duck paddling problem.
A duck has a mass of 2.6 kg.
As the duck paddles, a force of 0.07 N acts on it in a direction due east.
Also, the current of the water exerts a force of 0.23 N in a direction of 58° south of east. When these forces begin to act, the velocity of the duck is 0.11 m/s in a direction due east.
Find the magnitude and direction (relative to due east) of the displacement that the duck undergoes in 3.2 s while the forces are acting.
the magnitude displayed in meters and the direction in degrees, south of east
there are so many variables. please help me.
Not too many. Add the forces (vectorally) to get the net force, then divide by the mass to get the acceleration. Then it's just a 2-D motion problem in that direction. (Actually only a 1-D motion problem.... the component of the initial velocity perpendicular to the direction of the acceleration is constant, so there is little work to do with that.)
Originally Posted by rcmango
Okay, so if i'm doing this correctly,
i would add the forces of .07 N and .23 N together to get .30 N / 2.6kg
so the acceleration is .11538 ms^2
then now i would use .11538 as the acceleration in the x direction?
if i'm correct so far, whats next?