The original equation is undefined if the denominator = 0. So in this case it's undefined if , which as you demonstrated means it's undefined if . For what value(s) of x does ?
Started a new online course to try and get better at math, but the course has a few dead links and I'm missing some information. I have this question:
"For what values are the following undefined"
x^2 - 2x + 3
first I expand
x^2- 2x + 3
(x+1)(x+1) [or x+1^2]
Then I don't know what to do.
I've looked at the easier examples they give me and when they give an answer for an "undefined value" it is the x-intercepts/zeros of the function. Can someone explain to me what exactly they mean by "undefined values"
Right - you say the function is undefined for x = -1. To test this, try putting -1 in place of x in the denominator of the original equation - if the denominator turns out to be 0, then the function is undefined at that point.