Show transcribed image textConsider a parallel plate capacitor. It is hooked up to a 12 V battery, charged up and then the battery is disconnected. The capacitor has a capacitance of C = 1.0 F. What is the charge on the capacitor. How much energy is stored in the capacitor? A dielectric with dielectric constant k = 2.0 is then inserted in between the plates. What is the charge now? What is the voltage difference between the plates? What is the energy of the capacitor now? Describe where the energy went to or came from that makes up the difference from before. Explain what would have happened to the energy if the capacitor remained connected to the battery and the dielectric was inserted.