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aoj_1111_cpp
Cyber Guardian In the good old days, the Internet was free from fears and terrorism. People did not have to worry about any cyber criminals or mad computer scientists. Today, however, you are facing atrocious crackers wherever you are, unless being disconnected. You have to protect yourselves against their attacks. Counting upon your excellent talent for software construction and strong sense of justice, you are invited to work as a cyber guardian. Your ultimate mission is to create a perfect firewall system that can completely shut out any intruders invading networks and protect children from harmful information exposed on the Net. However, it is extremely difficult and none have ever achieved it before. As the first step, instead, you are now requested to write a software simulator under much simpler assumptions. In general, a firewall system works at the entrance of a local network of an organization (e.g., a company or a university) and enforces its local administrative policy. It receives both inbound and outbound packets (note: data transmitted on the Net are divided into small segments called packets) and carefully inspects them one by one whether or not each of them is legal. The definition of the legality may vary from site to site or depend upon the local administrative policy of an organization. Your simulator should accept data representing not only received packets but also the local administrative policy. For simplicity in this problem we assume that each network packet consists of three fields: its source address, destination address, and message body. The source address specifies the computer or appliance that transmits the packet and the destination address specifies the computer or appliance to which the packet is transmitted. An address in your simulator is represented as eight digits such as 03214567 or 31415926, instead of using the standard notation of IP addresses such as 192.168.1.1. Administrative policy is described in filtering rules, each of which specifies some collection of source-destination address pairs and defines those packets with the specified address pairs either legal or illegal. Input The input consists of several data sets, each of which represents filtering rules and received packets in the following format: n m rule 1 rule 2 ... rule n packet 1 packet 2 ... packet m The first line consists of two non-negative integers n and m . If both n and m are zeros, this means the end of input. Otherwise, n lines, each representing a filtering rule, and m lines, each representing an arriving packet, follow in this order. You may assume that n and m are less than or equal to 1,024. Each rule i is in one of the following formats: permit source-pattern destination-pattern deny source-pattern destination-pattern A source-pattern or destination-pattern is a character string of length eight, where each character is either a digit ('0' to '9') or a wildcard character '?'. For instance, "1????5??" matches any address whos ...(truncated)
[ { "submission_id": "aoj_1111_10849586", "code_snippet": "#include<stdio.h>\n#include<string.h>\n#include<iostream>\n#include<algorithm>\n#include<queue>\n#include<vector>\n#include<cmath>\nconst int Max = 1111;\ntypedef long long LL;\nusing namespace std;\n\nint n,m,cnt;\nchar rule[3][Max][111];\nchar str [3][Max][111];\n\nbool ok(char s1[111],char s2[111])\n{\n int len = 8;\n for (int i=0;i<8;++i)\n {\n if ( s2[i]!='?'&& s2[i]!=s1[i] ) return 0;\n }\n return 1;\n}\n\nvoid f()\n{\n bool flag = 0;\n for (int i=1;i<=n;++i)\n {\n if (strcmp(rule[0][i],\"deny\")==0)\n {\n if ( flag ==1 && ok(str[0][cnt],rule[1][i])&&ok(str[1][cnt],rule[2][i]) )\n {\n flag = 0;\n }\n }\n else{\n if ( flag==0 && ok(str[0][cnt],rule[1][i]) && ok(str[1][cnt],rule[2][i]) )\n {\n flag = 1;\n }\n }\n }\n if (flag) cnt++;\n}\n\nint main()\n{\n // freopen(\"in.txt\",\"r\",stdin);\n while (scanf(\"%d%d\",&n,&m) && (n|| m) )\n {\n cnt = 0;\n for (int i=1;i<=n;++i)\n {\n scanf(\"%s%s%s\",rule[0][i],rule[1][i],rule[2][i]);\n }\n\n for (int i=1;i<=m;++i)\n {\n scanf(\"%s%s%s\",str[0][cnt],str[1][cnt],str[2][cnt]);\n f();\n }\n\n cout<<cnt<<endl;\n for (int i=0;i<cnt;++i)\n {\n printf(\"%s %s %s\\n\",str[0][i],str[1][i],str[2][i]);\n }\n\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3756, "score_of_the_acc": -2, "final_rank": 18 }, { "submission_id": "aoj_1111_9629724", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\nbool same(string s,string t){\n REP(i,8)if(s[i]!=t[i]&&s[i]!='?'&&t[i]!='?')return false;\n return true;\n}\nint main(){\n while(1){\n ll N,M;cin>>N>>M;\n if(N+M==0)return 0;\n vector<pair<bool,pair<string,string>>>E(N);\n REP(i,N){\n string s,t,u;cin>>s>>t>>u;\n if(s==\"permit\")E[i].first=true;\n else E[i].first=false;\n E[i].second=make_pair(t,u);\n }\n reverse(E.begin(),E.end());\n vector<pair<pair<string,string>,string>>ans;\n while(M--){\n string s,t,m;cin>>s>>t>>m;\n REP(i,N){\n if(same(s,E[i].second.first)&&same(t,E[i].second.second)){\n if(E[i].first)ans.emplace_back(make_pair(make_pair(s,t),m));\n break;\n }\n }\n }\n cout<<ans.size()<<endl;\n for(auto[p,m]:ans)cout<<p.first<<\" \"<<p.second<<\" \"<<m<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3360, "score_of_the_acc": -0.5696, "final_rank": 16 }, { "submission_id": "aoj_1111_9046432", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n, m;\n while (cin >> n >> m, n+m) {\n vector<string> s(n), t(n);\n vector<bool> f(n);\n for (int i = 0; i < n; i++) {\n string type;\n cin >> type >> s[i] >> t[i];\n f[i] = (type == \"permit\");\n }\n vector<string> res;\n auto check = [](string &s, string &t) -> bool {\n for (int i = 0; i < min(s.size(), t.size()); i++) {\n if (s[i] == t[i] or s[i] == '?' or t[i] == '?') continue;\n return false;\n }\n return true;\n };\n for (int i = 0; i < m; i++) {\n string a, b, c;\n cin >> a >> b >> c;\n bool ok = false;\n for (int j = 0; j < n; j++) {\n if (check(a, s[j]) and check(b, t[j])) {\n ok = f[j];\n }\n }\n if (ok) {\n res.push_back(a + \" \" + b + \" \" + c);\n }\n }\n\n cout << res.size() << \"\\n\";\n for (auto r : res) {\n cout << r << \"\\n\";\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3572, "score_of_the_acc": -0.8, "final_rank": 17 }, { "submission_id": "aoj_1111_8821810", "code_snippet": "#include <iostream>\n#include <queue>\n#include <string.h>\nusing namespace std;\n\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\n\nint N, M;\n\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\n\nstruct Data {\n char from[9], to[9], message[51];\n};\n\nbool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\n\nvoid func() {\n int ok_index = 0, not_index = 0;\n Info OK[N], NOT[N];\n for (int i = 0; i < N; i++) {\n OK[i].erased = false;\n NOT[i].erased = false;\n }\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n cin >> buf >> from >> to;\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased == true)\n continue;\n if (strcmp(NOT[i].from, OK[k].from) == 0 &&\n strcmp(NOT[i].to, OK[k].to) == 0) {\n OK[k].erased = true;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased == true)\n continue;\n if (strcmp(OK[i].from, NOT[k].from) == 0 &&\n strcmp(OK[i].to, NOT[k].to) == 0) {\n NOT[k].erased = true;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n cin >> data.from >> data.to >> data.message;\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased == true)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) == true &&\n ambiguousCmp(OK[i].to, data.to) == true) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased == true)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) == true &&\n ambiguousCmp(NOT[i].to, data.to) == true) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n cout << Q.size() << \"\\n\";\n while (!Q.empty()) {\n cout << Q.front().from << \" \" << Q.front().to << \" \" << Q.front().message << \"\\n\";\n Q.pop();\n }\n}\n\nint main() {\n while (true) {\n cin >> N >> M;\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3080, "score_of_the_acc": -0.2652, "final_rank": 3 }, { "submission_id": "aoj_1111_8821800", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <cstring>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nint N, M;\n\nstruct Data {\n char from[9], to[9], message[51];\n};\n\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\n\nbool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\n\nvoid func() {\n int ok_index = 0, not_index = 0;\n vector<Info> OK(N), NOT(N);\n for (int i = 0; i < N; i++) {\n OK[i].erased = false;\n NOT[i].erased = false;\n }\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n cin >> buf >> from >> to;\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased == true)\n continue;\n if (strcmp(NOT[i].from, OK[k].from) == 0 &&\n strcmp(NOT[i].to, OK[k].to) == 0) {\n OK[k].erased = true;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased == true)\n continue;\n if (strcmp(OK[i].from, NOT[k].from) == 0 &&\n strcmp(OK[i].to, NOT[k].to) == 0) {\n NOT[k].erased = true;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n cin >> data.from >> data.to >> data.message;\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased == true)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) == true &&\n ambiguousCmp(OK[i].to, data.to) == true) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased == true)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) == true &&\n ambiguousCmp(NOT[i].to, data.to) == true) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n cout << Q.size() << \"\\n\";\n while (!Q.empty()) {\n cout << Q.front().from << \" \" << Q.front().to << \" \" << Q.front().message << \"\\n\";\n Q.pop();\n }\n}\n\nint main() {\n while (true) {\n cin >> N >> M;\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3064, "score_of_the_acc": -0.2478, "final_rank": 2 }, { "submission_id": "aoj_1111_8215377", "code_snippet": "#include <algorithm>\n#include <cfloat>\n#include <cmath>\n#include <queue>\n#include <stack>\n#include <stdio.h>\n#include <vector>\nusing namespace std;\nint N, M;\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\nstruct Data {\n char from[9], to[9], message[51];\n};\nbool strCmp(char *base, char *comp) {\n int length1 = 0, length2 = 0;\n for (int i = 0; base[i] != '\\0'; i++)\n length1++;\n for (int i = 0; comp[i] != '\\0'; i++)\n length2++;\n if (length1 != length2)\n return false;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i])\n return false;\n }\n return true;\n}\nbool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\nvoid strcpy(char *to, char *str) {\n for (int i = 0; str[i] != '\\0'; i++) {\n to[i] = str[i];\n to[i + 1] = '\\0';\n }\n}\nvoid func() {\n int ok_index = 0, not_index = 0;\n Info OK[N], NOT[N];\n for (int i = 0; i < N; i++) {\n OK[i].erased = false;\n NOT[i].erased = false;\n }\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n scanf(\"%s %s %s\", buf, from, to);\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased == true)\n continue;\n if (strCmp(NOT[i].from, OK[k].from) == true &&\n strCmp(NOT[i].to, OK[k].to) == true) {\n OK[k].erased = true;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased == true)\n continue;\n if (strCmp(OK[i].from, NOT[k].from) == true &&\n strCmp(OK[i].to, NOT[k].to) == true) {\n NOT[k].erased = true;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n scanf(\"%s %s %s\", data.from, data.to, data.message);\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased == true)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) == true &&\n ambiguousCmp(OK[i].to, data.to) == true) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased == true)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) == true &&\n ambiguousCmp(NOT[i].to, data.to) == true) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n printf(\"%d\\n\", Q.size());\n while (!Q.empty()) {\n printf(\"%s %s %s\\n\", Q.front().from, Q.front().to, Q.front().message);\n Q.pop();\n }\n}\nint main() {\n while (true) {\n scanf(\"%d %d\", &N, &M);\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2836, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1111_8215375", "code_snippet": "#include <algorithm>\n#include <bits/stdc++.h>\n#include <cfloat>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nint N, M;\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\nstruct Data {\n char from[9], to[9], message[51];\n};\nbool strCmp(char *base, char *comp) {\n int length1 = 0, length2 = 0;\n for (int i = 0; base[i] != '\\0'; i++)\n length1++;\n for (int i = 0; comp[i] != '\\0'; i++)\n length2++;\n if (length1 != length2)\n return false;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i])\n return false;\n }\n return true;\n}\nbool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\nvoid strcpy(char *to, char *str) {\n for (int i = 0; str[i] != '\\0'; i++) {\n to[i] = str[i];\n to[i + 1] = '\\0';\n }\n}\nvoid func() {\n int ok_index = 0, not_index = 0;\n Info OK[N], NOT[N];\n for (int i = 0; i < N; i++) {\n OK[i].erased = false;\n NOT[i].erased = false;\n }\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n scanf(\"%s %s %s\", buf, from, to);\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased == true)\n continue;\n if (strCmp(NOT[i].from, OK[k].from) == true &&\n strCmp(NOT[i].to, OK[k].to) == true) {\n OK[k].erased = true;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased == true)\n continue;\n if (strCmp(OK[i].from, NOT[k].from) == true &&\n strCmp(OK[i].to, NOT[k].to) == true) {\n NOT[k].erased = true;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n scanf(\"%s %s %s\", data.from, data.to, data.message);\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased == true)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) == true &&\n ambiguousCmp(OK[i].to, data.to) == true) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased == true)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) == true &&\n ambiguousCmp(NOT[i].to, data.to) == true) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n printf(\"%d\\n\", Q.size());\n while (!Q.empty()) {\n printf(\"%s %s %s\\n\", Q.front().from, Q.front().to, Q.front().message);\n Q.pop();\n }\n}\nint main() {\n while (true) {\n scanf(\"%d %d\", &N, &M);\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3288, "score_of_the_acc": -0.4913, "final_rank": 8 }, { "submission_id": "aoj_1111_8115763", "code_snippet": "#include <algorithm>\n#include <bits/stdc++.h>\n#include <cfloat>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nint N, M;\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\nstruct Data {\n char from[9], to[9], message[51];\n};\ninline bool strCmp(char *base, char *comp) {\n int length1 = 0, length2 = 0;\n for (int i = 0; base[i] != '\\0'; i++)\n length1++;\n for (int i = 0; comp[i] != '\\0'; i++)\n length2++;\n if (length1 != length2)\n return false;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i])\n return false;\n }\n return true;\n}\ninline bool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\ninline void strcpy(char *to, char *str) {\n for (int i = 0; str[i] != '\\0'; i++) {\n to[i] = str[i];\n to[i + 1] = '\\0';\n }\n}\ninline void func() {\n int ok_index = 0, not_index = 0;\n Info OK[N], NOT[N];\n memset(OK, 0, sizeof(OK));\n memset(NOT, 0, sizeof(NOT));\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n scanf(\"%s %s %s\", buf, from, to);\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased)\n continue;\n if (strCmp(NOT[i].from, OK[k].from) && strCmp(NOT[i].to, OK[k].to)) {\n OK[k].erased = true;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased)\n continue;\n if (strCmp(OK[i].from, NOT[k].from) && strCmp(OK[i].to, NOT[k].to)) {\n NOT[k].erased = true;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n scanf(\"%s %s %s\", data.from, data.to, data.message);\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) && ambiguousCmp(OK[i].to, data.to)) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) && ambiguousCmp(NOT[i].to, data.to)) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n printf(\"%d\\n\", Q.size());\n while (!Q.empty()) {\n printf(\"%s %s %s\\n\", Q.front().from, Q.front().to, Q.front().message);\n Q.pop();\n }\n}\nint main() {\n while (true) {\n scanf(\"%d %d\", &N, &M);\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3260, "score_of_the_acc": -0.4609, "final_rank": 5 }, { "submission_id": "aoj_1111_8115758", "code_snippet": "#include <algorithm>\n#include <bits/stdc++.h>\n#include <cfloat>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nint N, M;\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\nstruct Data {\n char from[9], to[9], message[51];\n};\nbool strCmp(char *base, char *comp) {\n int length1 = 0, length2 = 0;\n for (int i = 0; base[i] != '\\0'; i++)\n length1++;\n for (int i = 0; comp[i] != '\\0'; i++)\n length2++;\n if (length1 != length2)\n return false;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i])\n return false;\n }\n return true;\n}\nbool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\nvoid strcpy(char *to, char *str) {\n for (int i = 0; str[i] != '\\0'; i++) {\n to[i] = str[i];\n to[i + 1] = '\\0';\n }\n}\nvoid func() {\n int ok_index = 0, not_index = 0;\n Info OK[N], NOT[N];\n for (int i = 0; i < N; i++) {\n OK[i].erased = false;\n NOT[i].erased = false;\n }\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n scanf(\"%s %s %s\", buf, from, to);\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased == true)\n continue;\n if (strCmp(NOT[i].from, OK[k].from) == true &&\n strCmp(NOT[i].to, OK[k].to) == true) {\n OK[k].erased = true;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased == true)\n continue;\n if (strCmp(OK[i].from, NOT[k].from) == true &&\n strCmp(OK[i].to, NOT[k].to) == true) {\n NOT[k].erased = true;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n scanf(\"%s %s %s\", data.from, data.to, data.message);\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased == true)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) == true &&\n ambiguousCmp(OK[i].to, data.to) == true) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased == true)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) == true &&\n ambiguousCmp(NOT[i].to, data.to) == true) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n printf(\"%d\\n\", Q.size());\n while (!Q.empty()) {\n printf(\"%s %s %s\\n\", Q.front().from, Q.front().to, Q.front().message);\n Q.pop();\n }\n}\nint main() {\n while (true) {\n scanf(\"%d %d\", &N, &M);\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3304, "score_of_the_acc": -0.5087, "final_rank": 12 }, { "submission_id": "aoj_1111_8115756", "code_snippet": "#include <algorithm>\n#include <bits/stdc++.h>\n#include <cfloat>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nint N, M;\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\nstruct Data {\n char from[9], to[9], message[51];\n};\nbool strCmp(char *base, char *comp) {\n int length1 = 0, length2 = 0;\n for (int i = 0; base[i] != '\\0'; i++)\n length1++;\n for (int i = 0; comp[i] != '\\0'; i++)\n length2++;\n if (length1 != length2)\n return false;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i])\n return false;\n }\n return true;\n}\nbool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\nvoid strcpy(char *to, char *str) {\n for (int i = 0; str[i] != '\\0'; i++) {\n to[i] = str[i];\n to[i + 1] = '\\0';\n }\n}\nvoid func() {\n int ok_index = 0, not_index = 0;\n Info OK[N], NOT[N];\n for (int i = 0; i < N; i++) {\n OK[i].erased = false;\n NOT[i].erased = false;\n }\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n scanf(\"%s %s %s\", buf, from, to);\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased == true)\n continue;\n if (strCmp(NOT[i].from, OK[k].from) == true &&\n strCmp(NOT[i].to, OK[k].to) == true) {\n OK[k].erased = true;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased == true)\n continue;\n if (strCmp(OK[i].from, NOT[k].from) == true &&\n strCmp(OK[i].to, NOT[k].to) == true) {\n NOT[k].erased = true;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n scanf(\"%s %s %s\", data.from, data.to, data.message);\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased == true)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) == true &&\n ambiguousCmp(OK[i].to, data.to) == true) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased == true)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) == true &&\n ambiguousCmp(NOT[i].to, data.to) == true) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n printf(\"%lu\\n\", Q.size());\n while (!Q.empty()) {\n printf(\"%s %s %s\\n\", Q.front().from, Q.front().to, Q.front().message);\n Q.pop();\n }\n}\nint main() {\n while (true) {\n scanf(\"%d %d\", &N, &M);\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3340, "score_of_the_acc": -0.5478, "final_rank": 14 }, { "submission_id": "aoj_1111_8112903", "code_snippet": "#include <algorithm>\n#include <bits/stdc++.h>\n#include <cfloat>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nint N, M;\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\nstruct Data {\n char from[9], to[9], message[51];\n};\nbool strCmp(char *base, char *comp) {\n int length1 = 0, length2 = 0;\n for (int i = 0; base[i] != '\\0'; i++)\n length1++;\n for (int i = 0; comp[i] != '\\0'; i++)\n length2++;\n if (length1 != length2)\n return false;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i])\n return false;\n }\n return true;\n}\nbool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\nvoid strcpy(char *to, char *str) {\n for (int i = 0; str[i] != '\\0'; i++) {\n to[i] = str[i];\n to[i + 1] = '\\0';\n }\n}\nvoid func() {\n int ok_index = 0, not_index = 0;\n Info OK[N], NOT[N];\n for (int i = 0; i < N; i++) {\n OK[i].erased = false;\n NOT[i].erased = false;\n }\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n scanf(\"%s %s %s\", buf, from, to);\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased == true)\n continue;\n if (strCmp(NOT[i].from, OK[k].from) == true &&\n strCmp(NOT[i].to, OK[k].to) == true) {\n OK[k].erased = true;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased == true)\n continue;\n if (strCmp(OK[i].from, NOT[k].from) == true &&\n strCmp(OK[i].to, NOT[k].to) == true) {\n NOT[k].erased = true;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n scanf(\"%s %s %s\", data.from, data.to, data.message);\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased == true)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) == true &&\n ambiguousCmp(OK[i].to, data.to) == true) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased == true)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) == true &&\n ambiguousCmp(NOT[i].to, data.to) == true) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n printf(\"%d\\n\", Q.size());\n while (!Q.empty()) {\n printf(\"%s %s %s\\n\", Q.front().from, Q.front().to, Q.front().message);\n Q.pop();\n }\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n while (true) {\n scanf(\"%d %d\", &N, &M);\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3324, "score_of_the_acc": -0.5304, "final_rank": 13 }, { "submission_id": "aoj_1111_8112902", "code_snippet": "#include <algorithm>\n#include <bits/stdc++.h>\n#include <cfloat>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nint N, M;\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\nstruct Data {\n char from[9], to[9], message[51];\n};\nbool strCmp(char *base, char *comp) {\n int length1 = 0, length2 = 0;\n for (int i = 0; base[i] != '\\0'; i++)\n length1++;\n for (int i = 0; comp[i] != '\\0'; i++)\n length2++;\n if (length1 != length2)\n return false;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i])\n return false;\n }\n return true;\n}\nbool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\nvoid strcpy(char *to, char *str) {\n for (int i = 0; str[i] != '\\0'; i++) {\n to[i] = str[i];\n to[i + 1] = '\\0';\n }\n}\nvoid func() {\n int ok_index = 0, not_index = 0;\n Info OK[N], NOT[N];\n for (int i = 0; i < N; i++) {\n OK[i].erased = false;\n NOT[i].erased = false;\n }\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n scanf(\"%s %s %s\", buf, from, to);\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased == true)\n continue;\n if (strCmp(NOT[i].from, OK[k].from) == true &&\n strCmp(NOT[i].to, OK[k].to) == true) {\n OK[k].erased = true;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased == true)\n continue;\n if (strCmp(OK[i].from, NOT[k].from) == true &&\n strCmp(OK[i].to, NOT[k].to) == true) {\n NOT[k].erased = true;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n scanf(\"%s %s %s\", data.from, data.to, data.message);\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased == true)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) == true &&\n ambiguousCmp(OK[i].to, data.to) == true) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased == true)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) == true &&\n ambiguousCmp(NOT[i].to, data.to) == true) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n printf(\"%d\\n\", Q.size());\n while (!Q.empty()) {\n printf(\"%s %s %s\\n\", Q.front().from, Q.front().to, Q.front().message);\n Q.pop();\n }\n}\nint main() {\n ios_base::sync_with_stdio(0);\n cin.tie(0);\n while (true) {\n scanf(\"%d %d\", &N, &M);\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3292, "score_of_the_acc": -0.4957, "final_rank": 9 }, { "submission_id": "aoj_1111_8112901", "code_snippet": "#include <algorithm>\n#include <bits/stdc++.h>\n#include <cfloat>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nint N, M;\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\nstruct Data {\n char from[9], to[9], message[51];\n};\nbool strCmp(char *base, char *comp) {\n int length1 = 0, length2 = 0;\n for (int i = 0; base[i] != '\\0'; i++)\n length1++;\n for (int i = 0; comp[i] != '\\0'; i++)\n length2++;\n if (length1 != length2)\n return false;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i])\n return false;\n }\n return true;\n}\nbool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\nvoid strcpy(char *to, char *str) {\n for (int i = 0; str[i] != '\\0'; i++) {\n to[i] = str[i];\n to[i + 1] = '\\0';\n }\n}\nvoid func() {\n int ok_index = 0, not_index = 0;\n Info OK[N], NOT[N];\n for (int i = 0; i < N; i++) {\n OK[i].erased = false;\n NOT[i].erased = false;\n }\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n scanf(\"%s %s %s\", buf, from, to);\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased == true)\n continue;\n if (strCmp(NOT[i].from, OK[k].from) == true &&\n strCmp(NOT[i].to, OK[k].to) == true) {\n OK[k].erased = true;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased == true)\n continue;\n if (strCmp(OK[i].from, NOT[k].from) == true &&\n strCmp(OK[i].to, NOT[k].to) == true) {\n NOT[k].erased = true;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n scanf(\"%s %s %s\", data.from, data.to, data.message);\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased == true)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) == true &&\n ambiguousCmp(OK[i].to, data.to) == true) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased == true)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) == true &&\n ambiguousCmp(NOT[i].to, data.to) == true) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n printf(\"%d\\n\", Q.size());\n while (!Q.empty()) {\n printf(\"%s %s %s\\n\", Q.front().from, Q.front().to, Q.front().message);\n Q.pop();\n }\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n while (true) {\n scanf(\"%d %d\", &N, &M);\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3352, "score_of_the_acc": -0.5609, "final_rank": 15 }, { "submission_id": "aoj_1111_8112900", "code_snippet": "#include <algorithm>\n#include <bits/stdc++.h>\n#include <cfloat>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nint N, M;\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\nstruct Data {\n char from[9], to[9], message[51];\n};\nbool strCmp(char *base, char *comp) {\n int length1 = 0, length2 = 0;\n for (int i = 0; base[i] != '\\0'; i++)\n length1++;\n for (int i = 0; comp[i] != '\\0'; i++)\n length2++;\n if (length1 != length2)\n return false;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i])\n return false;\n }\n return true;\n}\nbool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\nvoid strcpy(char *to, char *str) {\n for (int i = 0; str[i] != '\\0'; i++) {\n to[i] = str[i];\n to[i + 1] = '\\0';\n }\n}\nvoid func() {\n int ok_index = 0, not_index = 0;\n Info OK[N], NOT[N];\n for (int i = 0; i < N; i++) {\n OK[i].erased = false;\n NOT[i].erased = false;\n }\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n scanf(\"%s %s %s\", buf, from, to);\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased == true)\n continue;\n if (strCmp(NOT[i].from, OK[k].from) == true &&\n strCmp(NOT[i].to, OK[k].to) == true) {\n OK[k].erased = true;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased == true)\n continue;\n if (strCmp(OK[i].from, NOT[k].from) == true &&\n strCmp(OK[i].to, NOT[k].to) == true) {\n NOT[k].erased = true;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n scanf(\"%s %s %s\", data.from, data.to, data.message);\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased == true)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) == true &&\n ambiguousCmp(OK[i].to, data.to) == true) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased == true)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) == true &&\n ambiguousCmp(NOT[i].to, data.to) == true) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n printf(\"%d\\n\", Q.size());\n while (!Q.empty()) {\n printf(\"%s %s %s\\n\", Q.front().from, Q.front().to, Q.front().message);\n Q.pop();\n }\n}\nint main() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout.tie(0);\n while (true) {\n scanf(\"%d %d\", &N, &M);\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3292, "score_of_the_acc": -0.4957, "final_rank": 9 }, { "submission_id": "aoj_1111_8112897", "code_snippet": "#include <algorithm>\n#include <bits/stdc++.h>\n#include <cfloat>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nint N, M;\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\nstruct Data {\n char from[9], to[9], message[51];\n};\nbool strCmp(char *base, char *comp) {\n int length1 = 0, length2 = 0;\n for (int i = 0; base[i] != '\\0'; i++)\n length1++;\n for (int i = 0; comp[i] != '\\0'; i++)\n length2++;\n if (length1 != length2)\n return false;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i])\n return false;\n }\n return true;\n}\nbool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\nvoid strcpy(char *to, char *str) {\n for (int i = 0; str[i] != '\\0'; i++) {\n to[i] = str[i];\n to[i + 1] = '\\0';\n }\n}\nvoid func() {\n int ok_index = 0, not_index = 0;\n Info OK[N], NOT[N];\n for (int i = 0; i < N; i++) {\n OK[i].erased = false;\n NOT[i].erased = false;\n }\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n scanf(\"%s %s %s\", buf, from, to);\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased == true)\n continue;\n if (strCmp(NOT[i].from, OK[k].from) == true &&\n strCmp(NOT[i].to, OK[k].to) == true) {\n OK[k].erased = true;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased == true)\n continue;\n if (strCmp(OK[i].from, NOT[k].from) == true &&\n strCmp(OK[i].to, NOT[k].to) == true) {\n NOT[k].erased = true;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n scanf(\"%s %s %s\", data.from, data.to, data.message);\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased == true)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) == true &&\n ambiguousCmp(OK[i].to, data.to) == true) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased == true)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) == true &&\n ambiguousCmp(NOT[i].to, data.to) == true) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n printf(\"%d\\n\", Q.size());\n while (!Q.empty()) {\n printf(\"%s %s %s\\n\", Q.front().from, Q.front().to, Q.front().message);\n Q.pop();\n }\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n while (true) {\n scanf(\"%d %d\", &N, &M);\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3216, "score_of_the_acc": -0.413, "final_rank": 4 }, { "submission_id": "aoj_1111_8112896", "code_snippet": "#include <algorithm>\n#include <bits/stdc++.h>\n#include <cfloat>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nint N, M;\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\nstruct Data {\n char from[9], to[9], message[51];\n};\nbool strCmp(char *base, char *comp) {\n int length1 = 0, length2 = 0;\n for (int i = 0; base[i] != '\\0'; i++)\n length1++;\n for (int i = 0; comp[i] != '\\0'; i++)\n length2++;\n if (length1 != length2)\n return false;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i])\n return false;\n }\n return true;\n}\nbool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\nvoid strcpy(char *to, char *str) {\n for (int i = 0; str[i] != '\\0'; i++) {\n to[i] = str[i];\n to[i + 1] = '\\0';\n }\n}\nvoid func() {\n int ok_index = 0, not_index = 0;\n Info OK[N], NOT[N];\n for (int i = 0; i < N; i++) {\n OK[i].erased = false;\n NOT[i].erased = false;\n }\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n scanf(\"%s %s %s\", buf, from, to);\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased == true)\n continue;\n if (strCmp(NOT[i].from, OK[k].from) == true &&\n strCmp(NOT[i].to, OK[k].to) == true) {\n OK[k].erased = true;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased == true)\n continue;\n if (strCmp(OK[i].from, NOT[k].from) == true &&\n strCmp(OK[i].to, NOT[k].to) == true) {\n NOT[k].erased = true;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n scanf(\"%s %s %s\", data.from, data.to, data.message);\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased == true)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) == true &&\n ambiguousCmp(OK[i].to, data.to) == true) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased == true)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) == true &&\n ambiguousCmp(NOT[i].to, data.to) == true) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n printf(\"%d\\n\", Q.size());\n while (!Q.empty()) {\n printf(\"%s %s %s\\n\", Q.front().from, Q.front().to, Q.front().message);\n Q.pop();\n }\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n cout.tie(0);\n while (true) {\n scanf(\"%d %d\", &N, &M);\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3296, "score_of_the_acc": -0.5, "final_rank": 11 }, { "submission_id": "aoj_1111_8105218", "code_snippet": "#include <algorithm>\n#include <bits/stdc++.h>\n\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\n\nusing namespace std;\n\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nint N, M;\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\nstruct Data {\n char from[9], to[9], message[51];\n};\nbool strCmp(char *base, char *comp) {\n int length1 = strlen(base), length2 = strlen(comp);\n if (length1 != length2)\n return false;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i])\n return false;\n }\n return true;\n}\nbool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\nvoid func() {\n int ok_index = 0, not_index = 0;\n Info OK[N], NOT[N];\n for (int i = 0; i < N; i++) {\n OK[i].erased = false;\n NOT[i].erased = false;\n }\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n scanf(\"%s %s %s\", buf, from, to);\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased == true)\n continue;\n if (strCmp(NOT[i].from, OK[k].from) == true &&\n strCmp(NOT[i].to, OK[k].to) == true) {\n OK[k].erased = true;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased == true)\n continue;\n if (strCmp(OK[i].from, NOT[k].from) == true &&\n strCmp(OK[i].to, NOT[k].to) == true) {\n NOT[k].erased = true;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n scanf(\"%s %s %s\", data.from, data.to, data.message);\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased == true)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) == true &&\n ambiguousCmp(OK[i].to, data.to) == true) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased == true)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) == true &&\n ambiguousCmp(NOT[i].to, data.to) == true) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n printf(\"%d\\n\", Q.size());\n while (!Q.empty()) {\n printf(\"%s %s %s\\n\", Q.front().from, Q.front().to, Q.front().message);\n Q.pop();\n }\n}\nint main() {\n while (true) {\n scanf(\"%d %d\", &N, &M);\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3264, "score_of_the_acc": -0.4652, "final_rank": 6 }, { "submission_id": "aoj_1111_8059975", "code_snippet": "#include <algorithm>\n#include <bits/stdc++.h>\n#include <cfloat>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nint N, M;\nstruct Info {\n char from[9], to[9];\n int rank;\n bool erased;\n};\nstruct Data {\n char from[9], to[9], message[51];\n};\nbool strCmp(char *base, char *comp) {\n int length1 = 0, length2 = 0;\n for (int i = 0; base[i] != '\\0'; i++)\n length1++;\n for (int i = 0; comp[i] != '\\0'; i++)\n length2++;\n if (length1 != length2)\n return false;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i])\n return false;\n }\n return true;\n}\nbool ambiguousCmp(char *base, char *comp) {\n bool FLG = true;\n for (int i = 0; base[i] != '\\0'; i++) {\n if (base[i] != comp[i]) {\n if (base[i] == '?') {\n } else {\n FLG = false;\n break;\n }\n }\n }\n if (FLG)\n return true;\n else {\n return false;\n }\n}\nvoid func() {\n int ok_index = 0, not_index = 0;\n Info OK[N], NOT[N];\n for (int i = 0; i < N; i++) {\n OK[i].erased = false;\n NOT[i].erased = false;\n }\n char buf[10], from[9], to[9];\n bool FLG;\n for (int i = 0; i < N; i++) {\n scanf(\"%s %s %s\", buf, from, to);\n if (buf[0] == 'p') {\n strcpy(OK[ok_index].from, from);\n strcpy(OK[ok_index].to, to);\n OK[ok_index].rank = i;\n ok_index++;\n } else {\n strcpy(NOT[not_index].from, from);\n strcpy(NOT[not_index].to, to);\n NOT[not_index].rank = i;\n not_index++;\n }\n }\n for (int i = not_index - 1; i >= 0; i--) {\n for (int k = ok_index - 1; k >= 0; k--) {\n if (NOT[i].rank < OK[k].rank || OK[k].erased == true)\n continue;\n if (strCmp(NOT[i].from, OK[k].from) == true &&\n strCmp(NOT[i].to, OK[k].to) == true) {\n OK[k].erased = true;\n break;\n }\n }\n }\n for (int i = ok_index - 1; i >= 0; i--) {\n for (int k = not_index - 1; k >= 0; k--) {\n if (OK[i].rank < NOT[k].rank || NOT[k].erased == true)\n continue;\n if (strCmp(OK[i].from, NOT[k].from) == true &&\n strCmp(OK[i].to, NOT[k].to) == true) {\n NOT[k].erased = true;\n break;\n }\n }\n }\n queue<Data> Q;\n for (int loop = 0; loop < M; loop++) {\n Data data;\n scanf(\"%s %s %s\", data.from, data.to, data.message);\n FLG = false;\n for (int i = 0; i < ok_index; i++) {\n if (OK[i].erased == true)\n continue;\n if (ambiguousCmp(OK[i].from, data.from) == true &&\n ambiguousCmp(OK[i].to, data.to) == true) {\n FLG = true;\n break;\n }\n }\n if (!FLG)\n continue;\n FLG = true;\n for (int i = 0; i < not_index; i++) {\n if (NOT[i].erased == true)\n continue;\n if (ambiguousCmp(NOT[i].from, data.from) == true &&\n ambiguousCmp(NOT[i].to, data.to) == true) {\n FLG = false;\n break;\n }\n }\n if (FLG) {\n Q.push(data);\n }\n }\n printf(\"%d\\n\", Q.size());\n while (!Q.empty()) {\n printf(\"%s %s %s\\n\", Q.front().from, Q.front().to, Q.front().message);\n Q.pop();\n }\n}\nint main() {\n while (true) {\n scanf(\"%d %d\", &N, &M);\n if (N == 0 && M == 0)\n break;\n func();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3264, "score_of_the_acc": -0.4652, "final_rank": 6 } ]
aoj_1127_cpp
Building a Space Station You are a member of the space station engineering team, and are assigned a task in the construction process of the station. You are expected to write a computer program to complete the task. The space station is made up with a number of units, called cells. All cells are sphere-shaped, but their sizes are not necessarily uniform. Each cell is fixed at its predetermined position shortly after the station is successfully put into its orbit. It is quite strange that two cells may be touching each other, or even may be overlapping. In an extreme case, a cell may be totally enclosing another one. I do not know how such arrangements are possible. All the cells must be connected, since crew members should be able to walk from any cell to any other cell. They can walk from a cell A to another cell B, if, (1) A and B are touching each other or overlapping, (2) A and B are connected by a `corridor', or (3) there is a cell C such that walking from A to C, and also from B to C are both possible. Note that the condition (3) should be interpreted transitively. You are expected to design a configuration, namely, which pairs of cells are to be connected with corridors. There is some freedom in the corridor configuration. For example, if there are three cells A, B and C, not touching nor overlapping each other, at least three plans are possible in order to connect all three cells. The first is to build corridors A-B and A-C, the second B-C and B-A, the third C-A and C-B. The cost of building a corridor is proportional to its length. Therefore, you should choose a plan with the shortest total length of the corridors. You can ignore the width of a corridor. A corridor is built between points on two cells' surfaces. It can be made arbitrarily long, but of course the shortest one is chosen. Even if two corridors A-B and C-D intersect in space, they are not considered to form a connection path between (for example) A and C. In other words, you may consider that two corridors never intersect. Input The input consists of multiple data sets. Each data set is given in the following format. n x 1 y 1 z 1 r 1 x 2 y 2 z 2 r 2 ... x n y n z n r n The first line of a data set contains an integer n , which is the number of cells. n is positive, and does not exceed 100. The following n lines are descriptions of cells. Four values in a line are x- , y- and z- coordinates of the center, and radius (called r in the rest of the problem) of the sphere, in this order. Each value is given by a decimal fraction, with 3 digits after the decimal point. Values are separated by a space character. Each of x , y , z and r is positive and is less than 100.0. The end of the input is indicated by a line containing a zero. Output For each data set, the shortest total length of the corridors should be printed, each in a separate line. The printed values should have 3 digits after the decimal point. They may not have an error greater than 0.001. Note that if no corridors ar ...(truncated)
[ { "submission_id": "aoj_1127_11065898", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\n\nstatic int bigint = 1e9;\nstatic ll biglong = 1e18;\nstatic ld eps = 1e-9;\n#define rep(i,s,n) for(int i=s;i<(int)(n);i++)\n#define sz(x) (int)(x).size()\n#define all(x) (x).begin(), (x).end()\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\n\n\n//ーーー入出力\ntemplate<typename T>\nvector<T> arrayInput(int n) {\n vector<T> a(n);\n for (int i = 0; i < n; i++) cin >> a[i];\n return a;\n}\ntemplate<typename T>\nvector<vector<T>> arrayInput(int h, int w) {\n vector<vector<T>> a(h, vector<T>(w));\n for (int i = 0; i < h; i++) for (int j = 0; j < w; j++) cin >> a[i][j];\n return a;\n}\n\ntemplate <typename T>\nvoid arrayPrint(const vector<T>& vec, bool blank = true) {\n for (int i = 0; i < vec.size(); ++i) cout << vec[i] << (blank?\" \":\"\");\n cout << endl;\n}\ntemplate <typename T>\nvoid arrayPrint(const vector<vector<T>>& mat, bool blank = true) {for (const auto& row : mat) arrayPrint(row, blank);}\n\ntemplate <typename T>\nvector<T> csum(vector<T>& input) {\n int n = input.size();\n vector<T> sum(n+1);\n for (int i=1;i<n+1;i++) sum[i] = sum[i-1] + input[i-1];\n return sum;\n}\ntemplate <typename T>\nvector<vector<T>> csum(vector<vector<T>>& input) {\n int h = input.size(), w = input[0].size();\n vector<vector<T>> csum(h+1, vector<T>(w+1));\n for (int i=0;i<h+1;i++) for (int j=0;j<w+1;j++) csum[i][j] = (i==0||j==0) ? 0: csum[i-1][j] + csum[i][j-1] - csum[i-1][j-1] + input[i-1][j-1];\n return csum;\n}\n//a/bの商\nlong long floor(long long a, long long b) {\n if (a % b == 0 || a >= 0) return a / b;\n else return -((-a) / b) - 1;\n}\n\n\n\n\nvoid rwfile(){freopen(\"in.txt\", \"r\", stdin); freopen(\"out.txt\", \"w\", stdout);}\n\nstruct UF {\n vector<int> par,siz;\n UF(int n) {\n par = vector<int>(n,-1);\n siz = vector<int>(n);\n }\n int root(int x) {\n while (par[x] != -1)x = par[x];\n return x;\n }\n bool same(int a,int b) {\n return root(a) == root(b);\n }\n void unite(int a,int b) {\n int rootA = root(a);\n int rootB = root(b);\n if (rootA == rootB) return;\n if (siz[rootA] < siz[rootB]) {\n par[rootA] = rootB;\n siz[rootB] += siz[rootA];\n\n }else {\n par[rootB] = rootA;\n siz[rootA] += siz[rootB];\n\n }\n\n }\n};\n\nint main() {\n cout << fixed << setprecision(3);\n while (true) {\n int n;cin >> n;\n if (n==0)break;\n vector<ld>x(n),y(n),z(n),r(n);\n rep(i,0,n) cin >> x[i] >> y[i] >> z[i] >> r[i];\n UF uf(n);\n priority_queue<tuple<ld,int,int>,vector<tuple<ld,int,int>>,greater<tuple<ld,int,int>>> pq;\n rep(i,0,n) {\n // cerr << x[i] << \" \" << y[i] << \" \" << z[i] <<\" \" << r[i] << endl;\n rep(j,i+1,n) {\n ld xy = (x[i]-x[j])*(x[i]-x[j]) + (y[i]-y[j]) * (y[i] - y[j]);\n ld xyz = sqrt(sqrt(xy)*sqrt(xy) + (z[i]-z[j]) * (z[i]-z[j]));\n // cerr << i <<\" \" << j << \" \" << xyz << \" \" << (r[i]+r[j]) << endl;\n if (xyz -(r[i]+r[j])< eps) {\n uf.unite(i,j);\n }else {\n pq.push(make_tuple(xyz-(r[i]+r[j]), i, j));\n }\n }\n }\n\n ld sum = 0;\n while (!pq.empty()) {\n auto e = pq.top(); pq.pop();\n ld cost = get<0>(e);\n int a = get<1>(e);\n int b = get<2>(e);\n if (!uf.same(a,b)) {\n uf.unite(a,b);\n sum += cost;\n }\n }\n\n cout << sum << endl;\n }\n\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3728, "score_of_the_acc": -0.3369, "final_rank": 8 }, { "submission_id": "aoj_1127_11055789", "code_snippet": "#include <bits/stdc++.h>\n\n#pragma GCC target(\"avx2\")\n#ifndef LOCAL\n#pragma GCC optimize(\"O3\")\n#endif\n#pragma GCC optimize(\"unroll-loops\")\n\n#ifdef ONLINE_JUDGE\n#include <boost/multiprecision/cpp_int.hpp>\n#include <atcoder/all>\n#endif\n#ifdef LOCAL\n#define GLIBCXX_DEBUG\n#else\n#define endl \"\\n\"\n#endif\nusing namespace std;using ll=long long;using ull=unsigned long long;using dl=long double;\n#define rep(i,n) for(ll i=0; i<(n); i++)\n#define rrep(i,n) for(ll i=1; i<=(n); i++)\n#define drep(i,n) for(ll i=(n)-1; i>=0; i--)\n#define xfor(i,s,e) for(ll i=(s); i<(e); i++)\n#define rxfor(i,s,e) for(ll i=(s); i<=(e); i++)\n#define dfor(i,s,e) for(ll i=(s)-1; i>=(e); i--)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\n#define chmax(x,y) x = max((x),(y))\n#define chmin(x,y) x = min((x),(y))\n#define popcnt(s) ll(__popcount<ull>(uint64_t(s)))\ntemplate<typename T>istream&operator>>(istream&is,const pair<T,T>&v){is>>v.first>>v.second;return is;}\ntemplate<typename T>istream&operator>>(istream&is,const vector<T>&v){for(auto&in:v)is>>in;return is;}\ntemplate<typename T, typename U>ostream&operator<<(ostream&os,const pair<T,U>&v){os<<v.first<<\" \"<<v.second;return os;}\ntemplate<typename T>ostream&operator<<(ostream&os,const vector<T>&v){for(auto&in:v)os<<in<<' ';return os;}\ntemplate<typename T>ostream&operator<<(ostream&os,const vector<vector<T>>&v){for(auto&in:v)os<<in<<endl;return os;}\nll modpow(ll a, ll b, ll mod) {ll res = 1;while (b > 0) {if (b & 1) res = (res * a) % mod;a = (a * a) % mod;b >>= 1;}return res;}\nll powl(ll a, ll b) {ll res = 1;while (b > 0) {if (b & 1) res = (res * a);a = (a * a);b >>= 1;}return res;}\n#define pow2(a) (a)*(a)\n/*MOD MUST BE A PRIME NUMBER!!*/ll moddiv(const ll a, const ll b, const ll mod) {ll modinv = modpow(b, mod-2, mod);return (a * modinv) % mod;}\nconst ll INF = 2e15;\nll nC2(const ll i){return i>2?i*(i-1)/2:0;}ll nC3(const ll i){return i>3?i*(i-1)*(i-2)/6:0;}ll nC4(const ll i){return i>4?i*(i-1)*(i-2)*(i-3)/24:0;}ll nC5(const ll i){return i>5?i*(i-1)*(i-2)*(i-3)*(i-4)/120:0;}ll nC6(const ll i){return i>6?i*(i-1)*(i-2)*(i-3)*(i-4)*(i-5)/720:0;}\ntemplate<typename T>void warshall_floyd(vector<vector<T>>& dist) {const ull n = dist.size();rep(k, n) rep(i, n) rep(j, n) {dist[i][j] = min(dist[i][j],dist[i][k] + dist[k][j]);}}\n#define YES {cout<<\"Yes\\n\";return;}\n#define NO {cout<<\"No\\n\";return;}\n#define yn YES else NO\n#ifdef ONLINE_JUDGE\nusing lll = boost::multiprecision::cpp_int;\n//using lll = boost::multiprecision::int128_t;\nusing namespace atcoder;\n//using mint = modint1000000007;\nusing mint = modint998244353;\n//using mint = modint; // custom mod\n//atcoder::modint::set_mod(m);\n// DSU == UnionFind\n#endif\n#define vc vector\nusing P = pair<ll, ll>;using vl = vc<ll>;using vb=vc<bool>;using vs=vc<string>;using vvl=vc<vl>;using vp=vc<P>;\n#define pq priority_queue\ntemplate<typename T>void cs(vector<T>&v){xfor(i,1,v.size())v[i]+=v[i-1];}\n\nvl dx = {-1, 1, 0, 0, -1, 1, -1, 1};\nvl dy = {0, 0, 1, -1, -1, -1, 1, 1};\n\nconst ll mod = 998244353;\n\n/// @brief Union-Find 木\n/// @note 1.4 高速化 + 省メモリ化\n/// @see https://zenn.dev/reputeless/books/standard-cpp-for-competitive-programming/viewer/union-find\nclass UnionFind\n{\npublic:\n\n\tUnionFind() = default;\n\n\t/// @brief Union-Find 木を構築します。\n\t/// @param n 要素数\n\texplicit UnionFind(size_t n)\n\t\t: m_parentsOrSize(n, -1) {}\n\n\t/// @brief 頂点 i の root のインデックスを返します。\n\t/// @param i 調べる頂点のインデックス\n\t/// @return 頂点 i の root のインデックス\n\tint find(int i)\n\t{\n\t\tif (m_parentsOrSize[i] < 0)\n\t\t{\n\t\t\treturn i;\n\t\t}\n\n\t\t// 経路圧縮\n\t\treturn (m_parentsOrSize[i] = find(m_parentsOrSize[i]));\n\t}\n\n\t/// @brief a のグループと b のグループを統合します。\n\t/// @param a 一方のインデックス\n\t/// @param b 他方のインデックス\n\tvoid merge(int a, int b)\n\t{\n\t\ta = find(a);\n\t\tb = find(b);\n\n\t\tif (a != b)\n\t\t{\n\t\t\t// union by size (小さいほうが子になる)\n\t\t\tif (-m_parentsOrSize[a] < -m_parentsOrSize[b])\n\t\t\t{\n\t\t\t\tstd::swap(a, b);\n\t\t\t}\n\n\t\t\tm_parentsOrSize[a] += m_parentsOrSize[b];\n\t\t\tm_parentsOrSize[b] = a;\n\t\t}\n\t}\n\n\t/// @brief a と b が同じグループに属すかを返します。\n\t/// @param a 一方のインデックス\n\t/// @param b 他方のインデックス\n\t/// @return a と b が同じグループに属す場合 true, それ以外の場合は false\n\tbool connected(int a, int b)\n\t{\n\t\treturn (find(a) == find(b));\n\t}\n\n\t/// @brief i が属するグループの要素数を返します。\n\t/// @param i インデックス\n\t/// @return i が属するグループの要素数\n\tint size(int i)\n\t{\n\t\treturn -m_parentsOrSize[find(i)];\n\t}\n\nprivate:\n\n\t// m_parentsOrSize[i] は i の 親,\n\t// ただし root の場合は (-1 * そのグループに属する要素数)\n\tstd::vector<int> m_parentsOrSize;\n};\n\nbool is_finished = false;\n\nvoid solve() {\n ll N; cin >> N;\n if (N == 0) {\n is_finished = true;\n return;\n }\n vc<double> X(N), Y(N), Z(N), r(N);\n rep(i, N) cin >> X[i] >> Y[i] >> Z[i] >> r[i];\n\n auto dist = [&](ll v1, ll v2){\n return sqrt(pow2(X[v1]-X[v2])+pow2(Y[v1]-Y[v2])+pow2(Z[v1]-Z[v2]));\n };\n\n pq<tuple<double,ll,ll>, vector<tuple<double,ll,ll>>, greater<>> q; // cost, vert_A, vert_B (A < B)\n\n UnionFind uf(N);\n\n rep(i, N) {\n xfor(j, i+1, N) {\n double d = dist(i,j)-r[i]-r[j];\n if (d <= 0) {\n uf.merge(i, j);\n } else {\n q.emplace(d,i,j);\n }\n }\n }\n\n auto ok = [&](){\n bool OK = true;\n rep(i, N) rep(j, N) if (!uf.connected(i,j)) OK = false;\n return OK;\n };\n double cost = 0;\n while (!ok() && !q.empty()) {\n auto [now_cost, a, b] = q.top(); q.pop();\n if (uf.connected(a,b))continue;\n cost += now_cost;\n uf.merge(a, b);\n }\n\n cout << cost << endl;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.tie(nullptr);\n cout << fixed << setprecision(3);\n\n ll n = 1;\n //cin >> n;\n while (!is_finished) {\n solve();\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 4076, "score_of_the_acc": -1.4021, "final_rank": 19 }, { "submission_id": "aoj_1127_10928684", "code_snippet": "#ifndef ONLINE_JUDGE\n#define _GLIBCXX_DEBUG\n#endif\n\n#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n//https://boostjp.github.io/tips/multiprec-int.html\n\n#define YES cout<<\"Yes\"<<endl\n#define NO cout<<\"No\"<<endl\n#define YN {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}// if(a==b)YN;\n#define NO2 cout<<-1<<endl\n\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n#define rrep(i, n) for (int i=int(n)-1; i>=0; --i)\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n\nstruct UnionFind {\n vector<int> parent, size;\n\n UnionFind(int n) : parent(n, -1), size(n, 1) {\n \t//初期操作 def __init__ のようなもの\n }\n\n int root(int x) {\n if(parent[x] == -1) return x;\n return parent[x] = root(parent[x]);\n }\n\n bool isSame(int x, int y) {\n return root(x) == root(y);\n }\n\n void unite(int x, int y) {\n int rootX = root(x);\n int rootY = root(y);\n if (rootX == rootY) return;\n\n if (size[rootX] < size[rootY]) swap(rootX, rootY);\n \n parent[rootY] = rootX;\n size[rootX] += size[rootY]; \n }\n \n int leaves(int x) {\n return size[root(x)];\n }\n};\n\nusing T = tuple<double, int, int>;\nvoid solve(int N) {\n UnionFind uf(N);\n vector<double> X(N), Y(N), Z(N), R(N);\n rep(i,N) {\n cin >> X[i] >> Y[i] >> Z[i] >> R[i];\n }\n double ans = 0.0;\n //priority_queue<T, vector<T>, greater<T>> pq;\n vector<T> edges;\n rep(i,N) {\n for (int j=i+1; j<N; ++j) {\n //double dist = hypot(X[i]-X[j], Y[i]-Y[j], Z[i]-Z[j]) - (R[i]+R[j]);\n double dx = X[i]-X[j];\n double dy = Y[i]-Y[j];\n double dz = Z[i]-Z[j];\n double dist = sqrt(dx*dx+dy*dy+dz*dz)-(R[i]+R[j]);\n if (dist <= 0) {\n uf.unite(i,j);\n continue;\n }\n edges.emplace_back(make_tuple(dist, i, j));\n }\n }\n sort(all(edges));\n\n for (const auto &edge : edges) {\n if (uf.leaves(0) == N) break;\n auto [cost, u, v] = edge;\n //pq.pop();\n if (uf.isSame(u,v)) continue;\n ans += cost;\n uf.unite(u,v);\n }\n cout << fixed << setprecision(3) << ans << endl;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n while(true) {\n int N;\n cin>>N;\n if (N == 0) return 0;\n solve(N);\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4096, "score_of_the_acc": -1.8289, "final_rank": 20 }, { "submission_id": "aoj_1127_10889578", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#if __has_include(<atcoder/all>)\n#include <atcoder/math>\nusing namespace atcoder;\n#endif\n\nusing ll = long long;\nusing vi = vector<int>;\nusing vvi = vector<vector<int>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\nusing vvvll = vector<vector<vector<ll>>>;\nusing vd = vector<double>;\nusing vvd = vector<vector<double>>;\nusing vstr = vector<string>;\nusing vchr = vector<char>;\nusing pii = pair<int,int>;\nusing pll = pair<long long, long long>;\nusing Graph = vector<vector<int>>;\nconst int dx[8] = {1, 0, -1, 0, 1, 1, -1, -1};\nconst int dy[8] = {0, 1, 0, -1, 1, -1, 1, -1};\n\n#define rep(i, a, b) for(int i = (int)a; i < (int)b; i++)\n#define REP(i, a, b) for (int i = (int)a; i <= (int)b; i++)\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define YESNO(flag) cout << (flag ? \"Yes\" : \"No\") << \"\\n\"\n#define spa \" \"\n\nconst int inf = 1070000000;\nconst long long INF = 4500000000000000000;\nconst long long MOD = 998244353;\n//const long long MOD = 1000000007;\nconst double pi = 3.141592653589793238;\nconst string ABC = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\nconst string abc = \"abcdefghijklmnopqrstuvwxyz\";\n\ntemplate<class T> inline bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\n//xのn乗\nll llpow(ll x, ll n) {\n ll ans = 1;\n while(n > 0) {\n if(n & 1) ans *= x;\n x *= x;\n n >>= 1; \n }\n return ans;\n}\nll modpow(ll x, ll n, ll mod) {\n ll ans = 1;\n while(n > 0) {\n if(n & 1) ans = ans * x % mod;\n x = x * x % mod;\n n >>= 1;\n }\n return ans;\n}\n//mod pでのaの逆元\nll inverse(ll a, ll p) {\n return modpow(a, p-2, p);\n}\n//nの階乗\nll fact(ll n) {\n if(n == 0) return 1;\n else return n * fact(n-1);\n}\nll modfact(ll n, ll mod) {\n if(n == 0) return 1;\n else return (n * modfact(n-1, mod)) % mod;\n}\n//nCr=n!/r!(n-r)! mod p\nll comb(ll n, ll r, ll mod) {\n ll a = modfact(n, mod), b = modfact(r, mod), c = modfact(n-r, mod);\n b = inverse(b, mod); c = inverse(c, mod);\n return (((a*b)%mod)*c)%mod;\n}\n\n//1+2+...+n = n(n+1)/2\nll triangle(ll n) {\n ll x = n*(n+1);\n return x/2;\n}\n//素数判定\nbool is_prime(long long x) {\n if(x == 1) return false;\n \n for(long long i = 2; i*i <= x; i++) {\n if(x % i == 0) return false;\n }\n return true;\n}\n\n//座標圧縮\nvector<int> compress(vector<int> A) {\n vector<int> B = A;\n\n sort(B.begin(), B.end());\n B.erase(unique(B.begin(), B.end()), B.end());\n\n vector<int> res(A.size());\n for(int i = 0; i < (int)A.size(); i++) {\n res[i] = lower_bound(B.begin(), B.end(), A[i]) - B.begin();\n }\n return res;\n}\n\n//正方形グリッドの右回転\nvoid rotate_right(vector<vector<char>> &S) {\n int N = S.size();\n auto T = S;\n rep(i,0,N) rep(j,0,N) {\n T[i][j] = S[N-1-j][i];\n }\n S = T;\n}\n//左回転\nvoid rotate_left(vector<vector<char>> &S) {\n int N = S.size();\n auto T = S;\n rep(i,0,N) rep(j,0,N) {\n T[i][j] = S[j][N-1-i];\n }\n S = T;\n}\n\n//2点(a,b)と(x,y)の距離\ndouble dist2(ll a, ll b, ll x, ll y) {\n return sqrt((a-x)*(a-x) + (b-y)*(b-y));\n}\nint man(int a, int b, int x, int y) {\n return abs(a-x) + abs(b-y);\n}\n\n//桁数\nint digit(ll N) {\n if(N <= 9) return 1;\n\n return 1 + digit(N / 10);\n}\n//A進数文字列NをB進数に変換. A,Bは10以下\nstring base_change(string N, ll A, ll B) {\n ll X = stoll(N), Y = 0;\n\n ll i = 1;\n while(X != 0) {\n Y += (X % 10) * i;\n i *= A;\n X /= 10;\n }\n\n X = Y, Y = 0;\n i = 1;\n while(X != 0) {\n Y += (X % B) * i;\n i *= 10;\n X /= B;\n }\n\n return to_string(Y);\n}\n//回文判定\nbool palin(string S) {\n rep(i,0,S.size()) {\n if(S[i] != S[S.size()-1-i]) return false;\n }\n return true;\n}\n\n//hh:mm:ss to second\nint convert_to_time(string S) {\n ll h = 10*(S[0]-'0') + (S[1]-'0');\n ll m = 10*(S[3]-'0') + (S[4]-'0');\n ll s = 10*(S[6]-'0') + (S[7]-'0');\n \n return h*3600+m*60+s;\n}\n\n//DFS\nvoid dfs(const Graph &G, int v, vector<bool> &seen) { \n seen[v] = true;\n \n for (auto next_v : G[v]) { \n if (!seen[next_v]) {\n dfs(G, next_v, seen);\n }\n }\n}\nvoid griddfs(const vector<vector<char>> &G, int x, int y, vector<vector<bool>> &seen) {\n int H = G.size(), W = G[0].size();\n seen[x][y] = true;\n \n for (int i = 0; i < 8; i++) { \n int nx = x + dx[i], ny = y + dy[i];\n if(nx < 0 or nx >= H or ny < 0 or ny >= W) continue;\n if (!seen[nx][ny] and G[nx][ny] != '#') griddfs(G, nx, ny, seen);\n }\n}\n//BFS\nvoid bfs(const Graph &G, int v, vector<int> &dist) {\n rep(i,0,dist.size()) dist[i] = inf;\n dist[v] = 0;\n queue<int> q;\n q.push(v);\n while(!q.empty()) {\n int u = q.front();\n q.pop();\n for(auto next_u : G[u]) {\n if(dist[next_u] == inf) {\n dist[next_u] = dist[u] + 1;\n q.push(next_u);\n }\n }\n }\n}\nvoid gridbfs(const vector<vector<char>> &G, int x, int y, vector<vector<int>> &dist) {\n int H = G.size(), W = G[0].size();\n rep(i,0,H) rep(j,0,W) dist[i][j] = inf;\n dist[x][y] = 0;\n queue<pair<int, int>> q;\n q.push(make_pair(x, y));\n while(!q.empty()) {\n int x = q.front().first, y = q.front().second;\n q.pop();\n for(int i = 0; i < 4; i++) {\n int nx = x + dx[i], ny = y + dy[i];\n if(nx < 0 or nx >= H or ny < 0 or ny >= W) continue;\n if(dist[nx][ny] == inf and G[nx][ny] != '#') {\n dist[nx][ny] = dist[x][y] + 1;\n q.push(make_pair(nx, ny));\n }\n }\n }\n}\n//ワーシャル・フロイド\nvector<vector<ll>> floyd(vector<vector<ll>> G) {\n int N = G.size();\n auto dp = G;\n for (int k = 0; k < N; k++){\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if(dp[i][j] > dp[i][k] + dp[k][j] and dp[i][k] != INF and dp[k][j] != INF) {\n dp[i][j] = dp[i][k] + dp[k][j];\n }\n }\n }\n }\n return dp;\n}\n\n//Union-Find\nstruct UnionFind {\n vector<int> par; // par[i]:iの親の番号 (例) par[3] = 2 : 3の親が2\n \n UnionFind(int N) : par(N) { //最初は全てが根であるとして初期化\n for(int i = 0; i < N; i++) par[i] = i;\n }\n \n int root(int x) { // データxが属する木の根を再帰で得る:root(x) = {xの木の根}\n if (par[x] == x) return x;\n return par[x] = root(par[x]);\n }\n \n void unite(int x, int y) { // xとyの木を併合\n int rx = root(x); //xの根をrx\n int ry = root(y); //yの根をry\n if (rx == ry) return; //xとyの根が同じ(=同じ木にある)時はそのまま\n par[rx] = ry; //xとyの根が同じでない(=同じ木にない)時:xの根rxをyの根ryにつける\n }\n \n bool same(int x, int y) { // 2つのデータx, yが属する木が同じならtrueを返す\n int rx = root(x);\n int ry = root(y);\n return rx == ry;\n }\n};\n\nvoid solve() {\n}\n\nint main() {\n while(1) {\n int N; cin >> N;\n if(N == 0) return 0;\n\n vd x(N), y(N), z(N), r(N);\n rep(i,0,N) cin >> x[i] >> y[i] >> z[i] >> r[i];\n\n priority_queue<tuple<double,int,int>, vector<tuple<double,int,int>>, greater<tuple<double,int,int>>> q;\n rep(i,0,N) rep(j,i+1,N) {\n double d = max(sqrt((x[i]-x[j])*(x[i]-x[j])+(y[i]-y[j])*(y[i]-y[j])+(z[i]-z[j])*(z[i]-z[j])) - (r[i]+r[j]), 0.000);\n q.push(make_tuple(d,i,j));\n }\n\n UnionFind tree(N);\n double ans = 0;\n while(!q.empty()) {\n double w; int s, t;\n tie(w, s, t) = q.top();\n if(!tree.same(s,t)) {\n ans += w;\n tree.unite(s,t);\n }\n q.pop();\n }\n int dig = digit(floor(ans));\n cout << fixed << setprecision(3) << ans << \"\\n\";\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3660, "score_of_the_acc": -0.246, "final_rank": 5 }, { "submission_id": "aoj_1127_10869374", "code_snippet": "// メモ\n// C++コンテスト用マクロ\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long; // 整数(long long型)\nusing ld = long double; // 実数(long double型)\n#define rep(i, n) for (ll i = 0; i < (n); i++) // 0~n-1まで\n#define nall(a) a.begin(), a.end() // ノーマルオール\n#define pb push_back // push_back\n#define pob pop_back // pop_back\n#define Yes cout << \"Yes\" << endl // Yes\n#define No cout << \"No\" << endl // No\n#ifndef ONLINE_JUDGE\n#define _GLIBCXX_DEBUG // 配列外参照時のエラー検出\n#endif\n\nstruct UnionFind{\n vector<ll> parent;\n UnionFind(ll N){\n parent.resize(N);\n rep(i, N){\n parent[i] = i;\n }\n }\n\n ll Find(ll i){\n if(parent[i] == i){\n return i;\n }\n else{\n return parent[i] = Find(parent[i]);\n }\n }\n\n void Unite(ll i, ll j){\n if(Find(i) != Find(j)){\n parent[Find(i)] = parent[Find(j)];\n }\n return;\n }\n\n bool Same(ll i, ll j){\n return Find(i) == Find(j);\n }\n};\n\nint main(){\n vector<ld> ans;\n while(1){\n ll N;\n cin >> N;\n if(N == 0) break;\n vector<ld> dist(N);\n map<ll, tuple<ld, ld, ld>> m;\n rep(i, N){\n ld x, y, z, r;\n cin >> x >> y >> z >> r;\n m[i] = {x, y, z};\n dist[i] = r;\n }\n vector<pair<ld, pair<ll, ll>>> p;\n rep(i, N - 1){\n for(int j = i + 1; j < N; j++){\n auto [xi, yi, zi] = m[i];\n auto [xj, yj, zj] = m[j];\n ld dx = xi - xj, dy = yi - yj, dz = zi - zj;\n ld d = max(sqrt((dx * dx + dy * dy + dz * dz)) - (dist[i] + dist[j]), (ld)0);\n p.push_back({d, {i, j}});\n }\n }\n sort(nall(p));\n UnionFind uf(N);\n ld preans = 0;\n rep(i, (int)p.size()){\n ll a = p[i].second.first, b = p[i].second.second;\n if(uf.Same(a, b) == false){\n uf.Unite(a, b);\n preans += p[i].first;\n }\n }\n ans.push_back(preans);\n }\n rep(i, (int)ans.size()){\n cout << fixed << setprecision(3) << ans[i] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3624, "score_of_the_acc": -0.1979, "final_rank": 3 }, { "submission_id": "aoj_1127_10779902", "code_snippet": "#include <iostream>\n#include <vector>\n#include <iomanip>\n#include <algorithm>\n#include <tuple>\n#include <set>\n#include <map>\n#include <bitset>\n#include <cmath>\n#include <deque>\n#include <queue>\n#include <stack>\n#include <cassert>\n#include <unordered_set>\n#include <unordered_map>\n#include <cmath>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define all(v) v.begin(), v.end()\n\nll llpow(ll a, ll t)\n{\n ll res = 1;\n rep(i, t) res *= a;\n return res;\n}\n\nll inf = std::numeric_limits<ll>::max();\n\nll findp(vector<ll> &ps, ll u)\n{\n if (ps[u] != u)\n {\n ps[u] = findp(ps, ps[u]);\n }\n return ps[u];\n}\n\nint main()\n{\n vector<double> anss;\n while (true)\n {\n ll n;\n cin >> n;\n if (!n)\n {\n break;\n }\n vector<vector<double>> vec(n);\n rep(i, n)\n {\n double x, y, z, r;\n cin >> x >> y >> z >> r;\n vec[i] = {x, y, z, r};\n }\n vector<tuple<double, ll, ll>> g;\n rep(i, n)\n {\n rep(j, n)\n {\n if (i == j)\n {\n continue;\n }\n double d = pow(pow(vec[i][0] - vec[j][0], 2) + pow(vec[i][1] - vec[j][1], 2) + pow(vec[i][2] - vec[j][2], 2), 0.5);\n d = max(d - vec[i][3] - vec[j][3], (double)0);\n g.push_back(make_tuple(d, i, j));\n }\n }\n sort(all(g));\n vector<ll> ps(n);\n rep(i, n)\n {\n ps[i] = i;\n }\n double ans = 0;\n rep(i, g.size())\n {\n double d;\n ll s, t;\n tie(d, s, t) = g[i];\n ll sp = findp(ps, s);\n ll tp = findp(ps, t);\n if (sp != tp)\n {\n ps[tp] = sp;\n ans += d;\n }\n }\n anss.push_back(ans);\n }\n cout << fixed << setprecision(3);\n for (auto ans : anss)\n {\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4084, "score_of_the_acc": -1.0128, "final_rank": 18 }, { "submission_id": "aoj_1127_10749447", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n#include <cmath>\n#include <algorithm>\n#include <set>\n#include <map>\n#include <queue>\n#include <iomanip>\n#include <functional>\n#include <stack>\n#include <numeric>\n\nusing namespace std;\nusing l = long long;\nusing ul = unsigned long long;\n\nconst int inf = 2147483647; // 2e9 1 << 30\nconst l INF = 9223372036854775807; // 9e18 1LL << 60\n\n#define r(i, n) for (l i = 0; i < n; ++i)\n#define r1(i, n) for (l i = 1; i < n; ++i)\n#define r0(i) for (l i = -1; i < 2; ++i)\n#define pll pair<l, l>\n\nvoid YesNo(bool s=false) {\n if (s) cout<<\"Yes\"<<endl;\n else cout<<\"No\"<<endl;\n}\n\nstruct UnionFind {\n vector<l> parent, rank, size;\n l tree_count;\n\n UnionFind(l n) : parent(n), rank(n, 0), size(n, 1), tree_count(n) {\n for (l i = 0; i < n; i++) parent[i] = i;\n }\n \n l find(l x) {\n if (parent[x] == x) return x;\n return parent[x] = find(parent[x]); // パス圧縮\n }\n bool unite(pll xy) {\n l rx = find(xy.first);\n l ry = find(xy.second);\n if (rx == ry) return false;\n if (rank[rx] < rank[ry]) swap(rx, ry);\n parent[ry] = rx;\n size[rx] += size[ry];\n if (rank[rx] == rank[ry]) rank[rx]++;\n\n tree_count--;\n\n return true;\n }\n \n bool same(pll xy) {\n return find(xy.first) == find(xy.second);\n }\n \n l getSize(l x) {\n return size[find(x)];\n }\n};\n\nvoid demo() {\n l n;cin >> n;\n if (n == 0) exit(0);\n \n vector<vector<double>> cells;\n\n r(i, n) {\n double x, y, z, r;cin >> x >> y >> z >> r;\n cells.push_back({x, y, z, r});\n }\n\n vector<vector<double>> roads;\n\n r(i, n) r(j, i) {\n double d = sqrt(pow(cells[i][0]-cells[j][0], 2) + pow(cells[i][1]-cells[j][1], 2) + pow(cells[i][2]-cells[j][2], 2));\n\n double cost = max(0., d - cells[i][3] - cells[j][3]);\n roads.push_back({cost, double(i), double(j)});\n }\n\n sort(roads.begin(), roads.end());\n\n UnionFind uf(n);\n\n double ans = 0;\n\n\n\n for (auto road : roads) {\n if (uf.unite({road[1], road[2]})) ans += road[0];\n }\n\n printf(\"%.3f\\n\", ans);\n}\n\nint main() {\n while(true) demo();\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3880, "score_of_the_acc": -0.5401, "final_rank": 11 }, { "submission_id": "aoj_1127_10341092", "code_snippet": "// author: Yuichiro Kurose\n\n#include <bits/stdc++.h>\nusing namespace std;\n\nclass UnionFind {\npublic:\n vector<int> par;\n vector<int> siz;\n UnionFind(int n) {\n par = vector<int>(n, -1);\n siz = vector<int>(n, 1);\n }\n int root(int x) {\n if (par[x] < 0) {\n return x;\n }\n return par[x] = root(par[x]);\n }\n void unite(int u, int v) {\n int root_u = root(u);\n int root_v = root(v);\n if (root_u == root_v) {\n return;\n }\n if (siz[root_u] < siz[root_v]) {\n par[root_u] = root_v;\n siz[root_v] += siz[root_u];\n } else {\n par[root_v] = root_u;\n siz[root_u] += siz[root_v];\n }\n }\n bool same(int u, int v) {\n if (root(u) == root(v)) {\n return true;\n }\n return false;\n }\n};\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n while (true) {\n int n;\n cin >> n;\n if (n == 0) {\n break;\n }\n vector<double> x(n), y(n), z(n), r(n);\n for (int i = 0; i < n; i++) {\n cin >> x[i] >> y[i] >> z[i] >> r[i];\n }\n vector<tuple<double, int, int>> edges;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n double dist = sqrt(pow(x[i] - x[j], 2) + pow(y[i] - y[j], 2) + pow(z[i] - z[j], 2));\n double l = r[i] + r[j];\n if (dist < l) {\n edges.push_back(make_tuple(0, i, j));\n } else {\n edges.push_back(make_tuple(dist - l, i, j));\n }\n }\n }\n sort(edges.begin(), edges.end());\n UnionFind uf(n);\n double ans = 0;\n for (auto tup : edges) {\n double w = get<0>(tup);\n int u = get<1>(tup), v = get<2>(tup);\n if (!uf.same(u, v)) {\n ans += w;\n uf.unite(u, v);\n }\n }\n cout << fixed << setprecision(3) << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3804, "score_of_the_acc": -0.4385, "final_rank": 10 }, { "submission_id": "aoj_1127_10310966", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); i++)\ntypedef unsigned long long int ull;\ntypedef long long ll;\nusing namespace std;\nconst int INTINF = 1001001001;\nconst long long LLINF = 1e18;\nconst int MOD = 998244353;\n#define Pii pair<int, int>\n#define Pli pair<long long, int>\n#define Pil pair<int, long long>\n#define Pid pair<int, double>\n#define Pdi pair<double, int>\n#define Psi pair<string, int>\n#define Tiii tuple<int, int, int>\n#define Tlii tuple<long long, int, int>\n#define chmax(x, y) x = max(x, y)\n#define pqueue priority_queue\n#define pb push_back\n\nint dy[] = {-1, 0, 1, 0};\nint dx[] = {0, 1, 0, -1};\nint ddy[] = {-1, -1, -1, 0, 0, 0, 1, 1, 1};\nint ddx[] = {-1, 0, 1, -1, 0, 1, -1, 0, 1};\n\nstruct Cell { double x, y, z, r; };\n\ndouble calcDist(struct Cell &a, struct Cell &b)\n{\n\tauto [x1, y1, z1, r1] = a;\n\tauto [x2, y2, z2, r2] = b;\n\tdouble x = x1 - x2, y = y1 - y2, z = z1 - z2;\n\tdouble r = r1 + r2;\n\tdouble dist = sqrt(x*x+y*y+z*z);\n\treturn max(0., dist - r);\n}\n\nvoid solve()\n{\n\tint N;\n\twhile (cin >> N, N)\n\t{\n\t\tvector<Cell> cells(N);\n\t\trep (i, N)\n\t\t{\n\t\t\tdouble x, y, z, r;\n\t\t\tcin >> x >> y >> z >> r;\n\t\t\tcells[i] = {x, y, z, r};\n\t\t}\n\n\t\tvector<vector<Pid>> E(N, vector<Pid> (N));\n\t\trep (i, N) rep (j, N) E[i].pb({j, calcDist(cells[i], cells[j])});\n\t\tdouble ans = 0;\n\t\tpqueue<Pdi, vector<Pdi>, greater<Pdi>> queue;\n\t\tvector<bool> visited(N);\n\t\tfor (auto [next, dist] : E[0]) queue.push({dist, next});\n\t\tvisited[0] = true;\n\t\twhile (!queue.empty())\n\t\t{\n\t\t\tauto [cost, current] = queue.top();\n\t\t\tqueue.pop();\n\t\t\tif (visited[current]) continue;\n\t\t\tvisited[current] = true;\n\t\t\tans += cost;\n\t\t\tfor (auto [next, dist] : E[current]) queue.push({dist, next});\n\t\t}\n\t\tprintf(\"%.3f\\n\", ans);\n\t}\n}\n\n#ifdef DEBUG\nint Qnum = 3;\n#else\nint Qnum = 1;\n#endif\n\nint main()\n{\n\twhile (Qnum--)\n\t{\n\t\tsolve();\n\t}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3976, "score_of_the_acc": -0.8684, "final_rank": 15 }, { "submission_id": "aoj_1127_10294534", "code_snippet": "// 1127\n#include <iostream>\n#include <vector>\n#include <queue>\n#include <cmath>\n#include <cstdio>\n\nusing namespace std;\n\nstruct cell\n{\n\tdouble x, y, z, r;\n};\n\ndouble d(double x) { return x * x; }\n\ndouble calcDist(cell& a, cell& b)\n{\n\tdouble dist = sqrt(d(a.x - b.x) + d(a.y - b.y) + d(a.z - b.z));\n\tdist -= (a.r + b.r);\n\treturn max(0., dist);\n}\n\nint main()\n{\n\twhile (1)\n\t{\n\t\tint N;\n\t\tcin >> N;\n\t\tif (N == 0) break;\n\t\tvector<cell> cells(N);\n\t\tfor (int i = 0; i < N; i++) cin >> cells[i].x >> cells[i].y >> cells[i].z >> cells[i].r;\n\t\tvector<vector<double>> E(N, vector<double>(N));\n\t\tfor (int i = 0; i < N; i++) for (int j = i + 1; j < N; j++) E[i][j] = E[j][i] = calcDist(cells[i], cells[j]);\n\t\tdouble ans = 0;\n\t\tvector<bool> united(N);\n\t\tpriority_queue<pair<double, int>, vector<pair<double, int>> ,greater<pair<double, int>>> queue;\n\t\tfor (int i = 0; i < N; i++) queue.push({E[0][i], i});\n\t\tunited[0] = true;\n\t\twhile (!queue.empty())\n\t\t{\n\t\t\tauto [c, current] = queue.top();\n\t\t\tqueue.pop();\n\t\t\tif (united[current]) continue;\n\t\t\tunited[current] = true;\n\t\t\tans += c;\n\t\t\tfor (int i = 0; i < N; i++) queue.push({ E[current][i], i });\n\t\t}\n\t\tprintf(\"%.3f\\n\", ans);\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3748, "score_of_the_acc": -0.3636, "final_rank": 9 }, { "submission_id": "aoj_1127_10277804", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); i++)\ntypedef unsigned long long int ull;\ntypedef long long ll;\nusing namespace std;\nconst int INF = 1001001001;\nconst int MOD = 998244353;\n#define Pint pair<int, int>\n#define Pli pair<long long, int>\n#define Pid pair<int, double>\n#define Pdi pair<double, int>\n#define Tint tuple<int, int, int>\n#define chmax(x, y) x = max(x, y)\n\nstruct cell\n{\n\tdouble x, y, z, r;\n};\n\ndouble calcDist(cell &a, cell &b)\n{\n\tauto [x1, y1, z1, r1] = a;\n\tauto [x2, y2, z2, r2] = b;\n\tdouble dist = sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)+(z1-z2)*(z1-z2));\n\tdouble ret = dist - (r1 + r2);\n\treturn max(0.0, ret);\n}\n\nvoid solve(void)\n{\n\twhile (1)\n\t{\n\t\tint N;\n\t\tcin >> N;\n\t\tif (N == 0) break;\n\t\tvector<cell> cells(N);\n\t\trep (i, N)\n\t\t{\n\t\t\tdouble x, y, z, r;\n\t\t\tcin >> x >> y >> z >> r;\n\t\t\tcells[i] = {x, y, z, r};\n\t\t}\n\t\tvector<vector<Pid>> E(N);\n\t\tfor (int i = 0; i < N; i++)\n\t\t{\n\t\t\tfor (int j = 0; j < N; j++)\n\t\t\t{\n\t\t\t\tE[i].push_back({j, calcDist(cells[i], cells[j])});\n\t\t\t}\n\t\t}\n\t\tpriority_queue<Pdi, vector<Pdi>, greater<Pdi>> queue;\n\t\tvector<bool> visited(N);\n\t\tvisited[0] = true;\n\t\tfor (auto[next, dist] : E[0]) queue.push({dist, next});\n\t\tdouble ans = 0;\n\t\twhile (!queue.empty())\n\t\t{\n\t\t\tauto [c, current] = queue.top();\n\t\t\tqueue.pop();\n\t\t\tif (visited[current]) continue;\n\t\t\tvisited[current] = true;\n\t\t\tans += c;\n\t\t\tfor (auto [next, dist] : E[current]) queue.push({dist, next});\n\t\t}\n\t\tprintf(\"%.3f\\n\", ans);\n\t}\n}\n\n#ifdef DEBUG\nint Qnum = 3;\n#else\nint Qnum = 1;\n#endif\n\nint main()\n{\n\twhile (Qnum--)\n\t{\n\t\tsolve();\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3952, "score_of_the_acc": -0.6364, "final_rank": 13 }, { "submission_id": "aoj_1127_10276195", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, a, b) for (ll i = a; i < b; i++)\n#define rrep(i, a, b) for (ll i = a; i >= b; i--)\n#define fore(i, a) for (auto &i : a)\n#define all(x) (x).begin(), (x).end()\n#define YES cout << \"Yes\" << endl\n#define NO cout << \"No\" << endl\n#define YN \\\n { \\\n cout << \"Yes\" << endl; \\\n } \\\n else { \\\n cout << \"No\" << endl; \\\n } // if(a==b)YN;\n#define FAIL cout << -1 << endl\n#pragma GCC optimize(\"-O3\")\n\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing i128 = __int128_t;\nusing pll = pair<ll, ll>;\nusing pld = pair<ld, ld>;\nusing matrix = vector<vector<ll>>;\nusing matrixld = vector<vector<ld>>;\nusing matrixb = vector<vector<bool>>;\nusing onevec = vector<ll>;\nusing onevecld = vector<ld>;\nusing onevecb = vector<bool>;\nusing lset = set<ll>;\n\nconst ll INFL = 1LL << 60;\ntemplate <class T> T chmin(T &a, T b) {\n if (a > b) {\n a = b;\n }\n return a;\n}\ntemplate <class T> T chmax(T &a, T b) {\n if (a < b) {\n a = b;\n }\n return a;\n}\ntemplate <typename T> ll lsize(const T &container) {\n return static_cast<ll>(container.size());\n}\ntemplate <typename T> bool ifbit(T number, ll bit) {\n return (number & (1LL << bit)) != 0;\n}\ntemplate <typename T> T twice(const T &a) { return a * a; }\ntemplate <typename T> T bits_count(T v) { return __builtin_popcountll(v); }\n\ntemplate <typename T> T factorial(T n) {\n T result = 1;\n for (T i = 1; i <= n; ++i) {\n result *= i;\n }\n return result;\n}\n\ntemplate <typename T> T pdistance(const vector<pair<T, T>> &xy, int i, int j) {\n return sqrt(twice(xy[i].first - xy[j].first) +\n twice(xy[i].second - xy[j].second));\n}\ntemplate <typename T>\nint isperp(const vector<pair<T, T>> &xyz, int i, int j, int k) {\n T dx1 = xyz[i].first - xyz[j].first, dy1 = xyz[i].second - xyz[j].second;\n T dx2 = xyz[k].first - xyz[j].first, dy2 = xyz[k].second - xyz[j].second;\n\n T dot = dx1 * dx2 + dy1 * dy2;\n\n return (dot > 0) ? 0 : (dot == 0) ? 1 : -1;\n}\n\ntemplate <typename T>\nT crossp(const vector<pair<T, T>> &xyz, int i, int j, int k) {\n T dx1 = xyz[i].first - xyz[j].first, dy1 = xyz[i].second - xyz[j].second;\n T dx2 = xyz[k].first - xyz[j].first, dy2 = xyz[k].second - xyz[j].second;\n\n return dx1 * dy2 - dy1 * dx2;\n}\n\ntemplate <typename T> T mod_exp(T base, T exp, T mod) {\n T result = 1;\n while (exp > 0) {\n if (exp & 1)\n result = (result * base) % mod;\n base = (base * base) % mod;\n exp >>= 1;\n }\n return result;\n}\n\ntemplate <typename T> void print(T value, int precision) {\n cout << fixed << setprecision(precision) << value << endl;\n}\n\ntemplate <typename... Args> void in(Args &...args) { (cin >> ... >> args); }\n\ntemplate <typename... Args> void out(const Args &...args) {\n constexpr size_t n = sizeof...(args);\n size_t i = 0;\n ((cout << args << (++i < n ? \" \" : \"\")), ...) << \"\\n\";\n}\n\nconst int dx[8] = {1, 0, -1, 0, 1, 1, -1, -1};\nconst int dy[8] = {0, 1, 0, -1, 1, -1, 1, -1};\nstring strrep(const string &s, const string &from, const string &to) {\n\n unordered_map<char, char> trans;\n for (size_t i = 0; i < from.size(); ++i) {\n trans[from[i]] = to[i];\n }\n\n string res = s;\n for (char &c : res) {\n if (trans.count(c)) {\n c = trans[c];\n }\n }\n return res;\n}\ntemplate <typename T> bool isprime(T N) {\n if (N < 2)\n return false;\n for (T i = 2; i * i <= N; i++) {\n if (N % i == 0)\n return false;\n }\n return true;\n}\ntemplate <typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\nvector<pair<char, int>> rle(const string &s) {\n vector<pair<char, int>> res;\n for (int i = 0, cnt; i < s.size(); i += cnt) {\n cnt = 1;\n while (i + cnt < s.size() && s[i] == s[i + cnt])\n cnt++;\n res.emplace_back(s[i], cnt);\n }\n return res;\n}\n/*--------------------------------------------------------\n \\0w0/\n OwOkaomoji\n 。˚ (¦3ꇤ )3 ⋆。˚✩\n----------------------------------------------------------*/\n/* UnionFind:素集合系管理の構造体(union by rank)\n isSame(x, y): x と y が同じ集合にいるか。 計算量はならし O(α(n))\n unite(x, y): x と y を同じ集合にする。計算量はならし O(α(n))\n*/\nstruct UnionFind { // The range of node number is 0 to n-1\n vector<ll> rank, parents;\n UnionFind() {}\n UnionFind(ll n) { // make n trees.\n rank.resize(n, 0);\n parents.resize(n, 0);\n rep(i, 0, n) { makeTree(i); }\n }\n void makeTree(ll x) {\n parents[x] = x; // the parent of x is x\n rank[x] = 0;\n }\n bool isSame(ll x, ll y) { return findRoot(x) == findRoot(y); }\n void unite(ll x, ll y) {\n x = findRoot(x);\n y = findRoot(y);\n if (rank[x] > rank[y]) {\n parents[y] = x;\n } else {\n parents[x] = y;\n if (rank[x] == rank[y]) {\n rank[y]++;\n }\n }\n }\n int findRoot(ll x) {\n if (x != parents[x])\n parents[x] = findRoot(parents[x]);\n return parents[x];\n }\n};\n\n// 辺の定義\nstruct Edge {\n long long u;\n long long v;\n ld cost;\n};\nbool comp_e(const Edge &e1, const Edge &e2) {\n return e1.cost < e2.cost;\n} // 辺を直接比較するための関数\n\n/* Kruskal :クラスカル法で minimum spanning tree を求める構造体\n 入力: 辺のvector, 頂点数V\n 最小全域木の重みの総和: sum\n 計算量: O(|E|log|V|)\n*/\nstruct Kruskal {\n UnionFind uft;\n ld sum; // 最小全域木の重みの総和\n ll size; // 木の数\n vector<Edge> edges;\n ll V;\n ll K;\n Kruskal(const vector<Edge> &edges_, ll V_, ll K_)\n : edges(edges_), V(V_), K(K_), size(V_) {\n init();\n }\n void init() {\n sort(edges.begin(), edges.end(), comp_e); // 辺の重みでソート\n uft = UnionFind(V);\n sum = 0;\n for (auto e : edges) {\n if (size == K) {\n break;\n }\n if (!uft.isSame(e.u, e.v)) { // 閉路にならなければ加える\n uft.unite(e.u, e.v);\n sum += e.cost;\n size--;\n }\n }\n }\n};\nbool is_connected(vector<ld> sph1, vector<ld> sph2) {\n ld x1 = sph1[0], y1 = sph1[1], z1 = sph1[2], r1 = sph1[3];\n ld x2 = sph2[0], y2 = sph2[1], z2 = sph2[2], r2 = sph2[3];\n return twice(r1 + r2) >= twice(x1 - x2) + twice(y1 - y2) + twice(z1 - z2);\n}\n// グラフが隣接リストで与えられる時はクラスカル法\nint main() {\n\n ll N; // 頂点の数、辺の数,木の数\n in(N);\n while (N != 0) {\n vector<vector<ld>> sphere(N);\n rep(i, 0, N) {\n vector<ld> sph(4);\n fore(x, sph) { in(x); }\n sphere[i] = sph;\n }\n vector<Edge> edges(N * N);\n rep(i, 0, N) rep(j, i + 1, N) {\n if (is_connected(sphere[i], sphere[j])) {\n edges[i * N + j] = {i, j, 0.0};\n } else {\n ld d = sqrt(twice(sphere[i][0] - sphere[j][0]) +\n twice(sphere[i][1] - sphere[j][1]) +\n twice(sphere[i][2] - sphere[j][2]));\n edges[i * N + j] = {i, j, d - sphere[i][3] - sphere[j][3]};\n }\n }\n // rep(i, 0, M) {\n // ll s, t, w; // start, goal, weight\n // in(s, t, w);\n // s--;\n // t--;\n // Edge e = {s, t, w};\n // edges[i] = e;\n // }\n Kruskal krs(edges, N, 1);\n print(krs.sum,3);\n in(N);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4184, "score_of_the_acc": -0.9465, "final_rank": 16 }, { "submission_id": "aoj_1127_10267925", "code_snippet": "//#include <bits/stdc++.h>\n#include <iostream>\n#include <string>\n#include <cstdio>\n#include <vector>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <queue>\n#include <random>\n#include <map>\n#include <set>\n#include <unordered_map>\n#include <unordered_set>\n#include <bitset>\n#include <stack>\n#include <utility>\n#include <cassert>\n#include <complex>\n#include <numeric>\n#include <array>\n#include <chrono>\n#include <tuple>\n#include <deque>\nusing namespace std;\n//#include <atcoder/all>\n//using namespace atcoder;\n\nusing ll = long long;\nusing P = pair<int, int>;\nusing PLL = pair<ll, ll>;\n\nconst int INF = 0x3fffffff;\nconst ll LINF = 0x1fffffffffffffff;\n\n#define rep(i,n) for (int i = 0; i < (n); i++)\n#define rrep(i,n) for (int i = (n) - 1; i >= 0; i--)\n#define all(c) (c).begin(), (c).end()\n#define rall(c) (c).rbegin(), (c).rend()\ntemplate<typename T, typename U> inline bool chmax(T &a, const U &b) { bool compare = a < b; if (compare) a = b; return compare;}\ntemplate<typename T, typename U> inline bool chmin(T &a, const U &b) { bool compare = a > b; if (compare) a = b; return compare;}\ntemplate<typename T, typename U> std::ostream &operator<< (std::ostream &os, std::pair<T, U> p){ os << p.first << ' ' << p.second; return os; }\n\nvector<int> di = {-1, 1, 0, 0, -1, 1, 1, -1};\nvector<int> dj = {0, 0, -1, 1, -1, -1, 1, 1};\n\nll intPow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modPow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\n\nstruct UnionFind {\n vector<int> data;\n\n UnionFind(int n = 1) {\n data.assign(n, -1);\n }\n\n int leader(int x) {\n if (data[x] < 0) return x;\n else {\n int r = leader(data[x]);\n return data[x] = r;\n }\n }\n\n bool same(int x, int y) {\n return leader(x) == leader(y);\n }\n\n int size(int x) {\n return -data[leader(x)];\n }\n\n bool merge(int x, int y) {\n x = leader(x);\n y = leader(y);\n if (x == y) return false;\n if (data[x] > data[y]) swap(x, y);\n data[x] += data[y];\n data[y] = x;\n return true;\n }\n \n};\nusing ld = long double;\n\nint main()\n{\n cout << fixed << setprecision(3);\n rep(qi, 100000000) {\n int n;\n cin >> n;\n if (n == 0) {\n return 0;\n }\n\n vector<ld> x(n), y(n), z(n), r(n);\n rep(i, n) cin >> x[i] >> y[i] >> z[i] >> r[i];\n UnionFind uf(n);\n vector<pair<ld, P>> path;\n for (int i = 0; i < n; i++) {\n for (int j = 1; j < n; j++) {\n ld xx = x[i] - x[j], yy = y[i] - y[j], zz = z[i] - z[j];\n ld d = sqrt(xx * xx + yy * yy + zz * zz) - r[i] - r[j];\n if (d <= 0) uf.merge(i, j);\n path.emplace_back(d, P{i, j});\n }\n }\n ld ans = 0;\n sort(all(path));\n for (auto [d, p] : path) {\n auto [i, j] = p;\n if (uf.same(i, j)) continue;\n ans += d;\n uf.merge(i, j);\n } \n cout << ans << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4060, "score_of_the_acc": -0.7807, "final_rank": 14 }, { "submission_id": "aoj_1127_10260369", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(int i=0;i<(n);i++)\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\nusing ll = long long;\nusing pi = pair<double, int>; \nconst int di[]={1,-1,0,0};\nconst int dj[]={0,0,1,-1};\nconst int INF=1e9;\nstruct Edge {\n double wei;\n int v;\n};\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n;\n while(cin >> n && n!=0) {\n vector<double> x(n), y(n), z(n), r(n);\n rep(i, n) cin >> x[i] >> y[i] >> z[i] >> r[i];\n vector<vector<Edge>> G(n);\n rep(i, n) rep(j, n) {\n double tmp;\n tmp=sqrt(pow(x[i]-x[j], 2)+pow(y[i]-y[j], 2)+pow(z[i]-z[j], 2));\n if(tmp<=r[i]+r[j]) tmp=0;\n else tmp-=r[i]+r[j];\n G[i].push_back({tmp, j});\n G[j].push_back({tmp, i}); \n }\n vector<int> used(n, false);\n priority_queue<pi, vector<pi>, greater<pi>> pq;\n used[0]=true;\n for(auto u:G[0]) pq.push({u.wei, u.v});\n double ans=0.0;\n while(!pq.empty()) {\n auto [w, u]=pq.top();\n pq.pop();\n if(used[u]) continue;\n used[u]=true;\n ans+=w;\n for(auto nu:G[u]) {\n if(used[nu.v]) continue;\n pq.push({nu.wei, nu.v});\n }\n }\n cout << fixed << setprecision(3) << ans << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4224, "score_of_the_acc": -1, "final_rank": 17 }, { "submission_id": "aoj_1127_10222256", "code_snippet": "// 1127\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <cstdio>\n#include <queue>\n\nstruct cell\n{\n\tdouble x, y, z, r;\n};\n\ndouble calcDist(struct cell& cella, struct cell& cellb)\n{\n\tdouble dx = cella.x - cellb.x;\n\tdouble dy = cella.y - cellb.y;\n\tdouble dz = cella.z - cellb.z;\n\tdouble dr = cella.r + cellb.r;\n\tdouble ddd = std::sqrt(dx * dx + dy * dy + dz * dz);\n\tif (dr > ddd)\n\t{\n\t\tif (ddd + std::min(cella.r, cellb.r) <= std::max(cella.r, cellb.r))\treturn -100;\n\t\telse return 0;\n\t}\n\telse return ddd - dr;\n}\n\nvoid solve(int N)\n{\n\tstd::vector<cell> cells(N);\n\tstd::vector<bool> involved(N);\n\tfor (int i = 0; i < N; i++) std::cin >> cells[i].x >> cells[i].y >> cells[i].z >> cells[i].r;\n\n\tfor (int i = 0; i < N; i++)\n\t{\n\t\tfor (int j = i + 1; j < N; j++)\n\t\t{\n\t\t\tif (involved[i] || involved[j]) continue;\n\t\t\tdouble dist = calcDist(cells[i], cells[j]);\n\t\t\tif (dist < 0)\n\t\t\t{\n\t\t\t\tif (cells[i].r > cells[j].r) involved[j] = true;\n\t\t\t\telse involved[i] = true;\n\t\t\t}\n\t\t}\n\t}\n\n\tstd::vector<std::vector<std::pair<int, double>>> E(N);\n\tfor (int i = 0; i < N; i++)\n\t{\n\t\tif (involved[i]) continue;\n\t\tfor (int j = i + 1; j < N; j++)\n\t\t{\n\t\t\tif (involved[j]) continue;\n\t\t\tdouble dist = calcDist(cells[i], cells[j]);\n\t\t\tE[i].push_back({ j, dist });\n\t\t\tE[j].push_back({ i, dist });\n\t\t}\n\t}\n\n\n\tstd::vector<bool> visited(N);\n\tstd::priority_queue<\n\t\tstd::pair<double, int>,\n\t\tstd::vector<std::pair<double, int>>,\n\t\tstd::greater<std::pair<double, int>>\n\t> queue;\n\n\tfor (int i = 0; i < N; i++)\n\t{\n\t\tif (involved[i]) continue;\n\t\tif (E[i].size() == 0) continue;\n\t\tvisited[i] = true;\n\t\tfor (auto [next, dist] : E[i])\n\t\t{\n\t\t\tqueue.push({ dist, next });\n\t\t}\n\t\tbreak;\n\t}\n\n\tdouble ans = 0;\n\twhile (!queue.empty())\n\t{\n\t\tauto [dist, current] = queue.top();\n\t\tqueue.pop();\n\t\tif (visited[current]) continue;\n\t\tvisited[current] = true;\n\t\tans += dist;\n\t\tfor (auto [next, cost] : E[current]) queue.push({ cost, next });\n\t}\n\n\tprintf(\"%.3f\\n\", ans);\n}\n\nint main()\n{\n\twhile (1)\n\t{\n\t\tint N;\n\t\tstd::cin >> N;\n\t\tif (N == 0) break;\n\t\tsolve(N);\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3892, "score_of_the_acc": -0.5561, "final_rank": 12 }, { "submission_id": "aoj_1127_10067730", "code_snippet": "#include<iostream>\n#include<vector>\n#include<cmath>\n#include<iomanip>\n#include<algorithm>\nusing namespace std;\n\nstruct UnionFind{\n\tvector<int> parent,size;\n\tUnionFind(int n): parent(n,-1), size(n,1){}\n\tint root(int x){\n\t\tif(parent[x] == -1) return x;\n\t\telse return root(parent[x]);\n\t}\n\tbool same(int x, int y){\n\t\treturn root(x)==root(y);\n\t}\n\tvoid unite(int x, int y){\n\t\tif(!same(x,y)){\n\t\t\tint rx = root(x), ry = root(y);\n\t\t\tif(size[rx] > size[ry]){\n\t\t\t\tparent[ry] = rx;\n\t\t\t\tsize[rx] += size[ry];\n\t\t\t}else{\n\t\t\t\tparent[rx] = ry;\n\t\t\t\tsize[ry] += size[rx];\n\t\t\t}\n\t\t}\n\t}\n};\n\nstruct Edge{\n\tint s,t;\n\tdouble d;\n};\n\nbool comp_e(Edge &a, Edge &b){\n\treturn a.d < b.d;\n}\n\nvoid solve(int n){\n\tvector<double> x(n),y(n),z(n),r(n);\n\tfor(int i = 0; i < n; i++){\n\t\tcin >> x[i] >> y[i] >> z[i] >> r[i];\n\t}\n\tvector<Edge> list(0);\n\tfor(int i = 0; i < n; i++){\n\t\tfor(int j = i+1; j < n; j++){\n\t\t\tdouble dist = hypot(hypot(x[i]-x[j], y[i]-y[j]), z[i]-z[j])-r[i]-r[j];\n\t\t\tdist = dist < 0 ? 0: dist;\n\t\t\tEdge edge = {i,j,dist};\n\t\t\tlist.push_back(edge);\n\t\t}\n\t}\n\tUnionFind uf(n);\n\tdouble ans = 0;\n\tsort(list.begin(), list.end(), comp_e);\n\tfor(int i = 0; i < n*(n-1)/2; i++){\n\t\tif(!uf.same(list[i].s, list[i].t)){\n\t\t\tans += list[i].d;\n\t\t\tuf.unite(list[i].s, list[i].t);\n\t\t}\n\t}\n\tcout << fixed << setprecision(3) << ans << endl;\n}\n\nint main(){\n\tint n;\n\tcin >> n;\n\twhile(n!=0){\n\t\tsolve(n);\n\t\tcin >> n;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3476, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1127_9706227", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++) //forループ\n#define reps(i, m, n) for (int i = (int)(m); i < (int)(n); i++) //forループ(開始位置指定)\n#define rrep(i, n) for (int i = n-1; i >= 0; i--) //forループ逆順\n#define all(a) (a).begin(), (a).end() //all\n#define rall(a) (a).rbegin(), (a).rend() //逆all\n\n#define ll long long //long long型\n\n#define alphabet \"abcdefghijklmnopqrstuvwxyz\" //英小文字列\n#define alphabet_A \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\" //英大文字列\n#define pi acos(-1) //円周率\n\n#define move_X4 vector<int> {1, 0, -1, 0} //4方向への移動\n#define move_Y4 vector<int> {0, 1, 0, -1} //4方向への移動\n\n#define move_X8 vector<int> {1, 1, 0, -1, -1, -1, 0, 1} //8方向への移動\n#define move_Y8 vector<int> {0, 1, 1, 1, 0, -1, -1, -1} //8方向への移動\n\nvector<int> node;\n\nint root(int a)\n{\n int tmpRoot;\n while (true)\n {\n if (node[a] == -1)\n {\n tmpRoot = a;\n break;\n }\n\n a = node[a];\n }\n\n while (true)\n {\n int tmp = node[a];\n\n if (tmp == -1)\n {\n break;\n }\n\n node[a] = tmpRoot;\n a = tmp;\n }\n\n return tmpRoot;\n}\n\nint main()\n{\n while (true)\n {\n int n;\n cin>>n;\n\n if (n == 0)\n {\n break;\n }\n\n vector<tuple<double, double, double, double>> a(n);\n rep(i, n)\n {\n double x, y, z, r;\n cin>>x>>y>>z>>r;\n a[i] = make_tuple(x, y, z, r);\n }\n\n vector<tuple<double, int, int>> edge;\n rep(i, n)\n {\n reps(j, i+1, n)\n {\n double x1, y1, z1, r1, x2, y2, z2, r2;\n x1 = get<0>(a[i]), y1 = get<1>(a[i]), z1 = get<2>(a[i]), r1 = get<3>(a[i]);\n x2 = get<0>(a[j]), y2 = get<1>(a[j]), z2 = get<2>(a[j]), r2 = get<3>(a[j]);\n double dist = max(sqrt(pow(x1 - x2, 2) + pow(y1 - y2, 2) + pow(z1 - z2, 2)) - r1 - r2, (double)0);\n edge.push_back(make_tuple(dist, i, j));\n }\n }\n\n sort(all(edge));\n node = vector<int>(n, -1);\n double answer = 0;\n rep(i, edge.size())\n {\n double dist = get<0>(edge[i]);\n int u = get<1>(edge[i]), v = get<2>(edge[i]);\n\n if (root(u) != root(v))\n {\n answer += dist;\n node[root(u)] = root(v);\n }\n }\n\n cout<<fixed<<setprecision(3);\n cout<<answer<<endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3552, "score_of_the_acc": -0.1016, "final_rank": 2 }, { "submission_id": "aoj_1127_9633029", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<ll,ll> pi;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\nint main(){\n while(1){\n ll N;cin>>N;\n if(!N)return 0;\n vector<ld>X(N),Y(N),Z(N),R(N);\n REP(i,N)cin>>X[i]>>Y[i]>>Z[i]>>R[i];\n vector<pair<ld,pi>>es;\n REP(i,N)REP(j,i){\n ld d=sqrtl((X[i]-X[j])*(X[i]-X[j])+(Y[i]-Y[j])*(Y[i]-Y[j])+(Z[i]-Z[j])*(Z[i]-Z[j]));\n es.emplace_back(make_pair(max((ld)0,d-R[i]-R[j]),pi(j,i)));\n }\n sort(ALL(es));\n ld ans=0;\n vector<ll>nec(N,-1);\n auto leader=[&](ll v){\n while(nec[v]>=0)v=nec[v];\n return v;\n };\n for(auto[c,p]:es)if(leader(p.first)!=leader(p.second)){\n ll u=leader(p.first),v=leader(p.second);\n if(nec[u]<nec[v])swap(u,v);\n nec[v]+=nec[u];\n nec[u]=v;\n ans+=c;\n }\n printf(\"%.3Lf\\n\",ans);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3712, "score_of_the_acc": -0.3155, "final_rank": 6 }, { "submission_id": "aoj_1127_9507298", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\nll MOD = 100'000'000;\nll inf = (1LL << 62);\n\n// clang-format off\nauto getll(){ll n; cin >> n; return n;}\nauto getstr(){string s; cin >> s; return s;}\nauto getdb(){double n; cin >> n; return n;}\nauto getvll(ll n){vector<ll> a(n); for (ll i = 0; i < n; ++i) a[i] = getll(); return a;}\nauto getvstr(ll n){vector<string> a(n); for (ll i = 0; i < n; ++i) a[i] = getstr(); return a;}\nauto getvdb(ll n){vector<double> a(n); for (ll i = 0; i < n; ++i) a[i] = getdb(); return a;}\n// clang-format on\n\nclass UnionFind {\n private:\n std::vector<int> parent;\n\n public:\n UnionFind() = default;\n explicit UnionFind(size_t n) : parent(n, -1) {}\n int find(int i) {\n if (parent[i] < 0) {\n return i;\n }\n return (parent[i] = find(parent[i]));\n }\n void merge(int a, int b) {\n a = find(a);\n b = find(b);\n if (a != b) {\n if (-parent[a] < -parent[b]) {\n swap(a, b);\n }\n parent[a] += parent[b];\n parent[b] = a;\n }\n }\n bool same(int a, int b) { return find(a) == find(b); }\n int size(int i) { return -parent[find(i)]; }\n};\n\nstruct Edge {\n ll from;\n ll to;\n double cost;\n};\n\nint main() {\n vector<double> tmp;\n while (true) {\n ll n;\n cin >> n;\n if (n == 0)\n break;\n vector<double> x(n), y(n), z(n), r(n);\n for (ll i = 0; i < n; ++i) {\n cin >> x[i] >> y[i] >> z[i] >> r[i];\n }\n UnionFind uf(n);\n vector<Edge> edges;\n for (ll i = 0; i < n; ++i) {\n for (ll j = 0; j < n; ++j) {\n auto dx = x[i] - x[j], dy = y[i] - y[j], dz = z[i] - z[j];\n auto sq = dx * dx + dy * dy + dz * dz;\n auto dist = sqrt(sq) > r[i] + r[j] ? sqrt(sq) - r[i] - r[j] : 0;\n edges.push_back({i, j, dist});\n }\n }\n sort(edges.begin(), edges.end(),\n [](auto& a, auto& b) { return a.cost < b.cost; });\n double ans = 0;\n ll cnt = 0;\n for (auto& e : edges) {\n if (!uf.same(e.from, e.to)) {\n uf.merge(e.from, e.to);\n ans += e.cost;\n if (cnt == n - 1)\n break;\n }\n }\n tmp.push_back(ans);\n }\n cout << fixed << setprecision(3);\n for (auto& x : tmp) {\n cout << x << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3632, "score_of_the_acc": -0.2086, "final_rank": 4 }, { "submission_id": "aoj_1127_9433972", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n#include <unordered_set>\n#include <functional>\nusing namespace std;\n//using namespace atcoder;\nusing ll = long long;\nusing P = pair<int, int>;\n#define rep(i, n) for (int i = 0; i < (n); i++)\n//void chmin(ll & a, ll b) { a = min(a, b); }\n//using mint = modint1000000007;\n\nstruct point {\n\tdouble x;\n\tdouble y;\n\tdouble z;\n};\n\ndouble square(double a, double b) {\n\treturn (a - b) * (a - b);\n}\n\ndouble calc(point p1, point p2) {\n\tdouble x = square(p1.x, p2.x);\n\tdouble y = square(p1.y, p2.y);\n\tdouble z = square(p1.z,p2.z);\n\treturn sqrt(x + y + z);\n}\n\nclass UnionFind {\npublic:\n\tint par[109];\n\tint siz[109];\n\n\tvoid init(int n) {\n\t\trep(i, n) par[i] = -1;\n\t\trep(i, n) siz[i] = 1;\n\t}\n\n\tint root(int v) {\n\t\tif (par[v] == -1) {\n\t\t\treturn v;\n\t\t}\n\t\treturn root(par[v]);\n\t}\n\n\tvoid unite(int u, int v) {\n\t\tint ru = root(u);\n\t\tint rv = root(v);\n\t\tif (ru == rv) return;\n\t\tif (siz[ru] > siz[rv]) {\n\t\t\tsiz[ru] = siz[rv] + siz[ru];\n\t\t\tpar[rv] = ru;\n\t\t}\n\t\telse {\n\t\t\tsiz[rv] = siz[ru] + siz[rv];\n\t\t\tpar[ru] = rv;\n\t\t}\n\t}\n\n\tbool same(int u, int v) {\n\t\tif (root(u) == root(v)) {\n\t\t\treturn true;\n\t\t}\n\t\treturn false;\n\t}\n};\n\n\nint main() {\n\twhile (true) {\n\t\tint n;\n\t\tcin >> n;\n\t\tif (n == 0) {\n\t\t\tbreak;\n\t\t}\n\t\tvector<point> coordinate(n);\n\t\tvector<double> r(n);\n\t\trep(i, n) {\n\t\t\tcin >> coordinate[i].x >> coordinate[i].y >> coordinate[i].z >> r[i];\n\t\t}\n\n\t\tvector<tuple<double, int, int>> edge;\n\n\t\trep(i, n) {\n\t\t\trep(j, n) {\n\t\t\t\tif (i != j) {\n\t\t\t\t\tdouble dist = calc(coordinate[i], coordinate[j]);\n\t\t\t\t\tif (r[i] + r[j] >= dist) {\n\t\t\t\t\t\tedge.emplace_back(0.0, i, j);\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\tedge.emplace_back(dist-(r[i]+r[j]), i, j);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tsort(edge.begin(), edge.end());\n\n\t\tUnionFind uf;\n\t\tuf.init(n);\n\n\t\tdouble ans = 0;\n\t\trep(i, edge.size()) {\n\t\t\tauto [dis, from, to] = edge[i];\n\t\t\tif (uf.same(from, to)) {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tuf.unite(from, to);\n\t\t\t//cout << dis << endl;\n\t\t\tans += dis;\n\t\t}\n\n\t\tprintf(\"%.3f\\n\", ans);\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3720, "score_of_the_acc": -0.3262, "final_rank": 7 } ]
aoj_1133_cpp
Problem E: Water Tank Mr. Denjiro is a science teacher. Today he has just received a specially ordered water tank that will certainly be useful for his innovative experiments on water flow. Figure 1: The water tank The size of the tank is 100cm (Width) * 50cm (Height) * 30cm (Depth) (see Figure 1). For the experiments, he fits several partition boards inside of the tank parallel to the sideboards. The width of each board is equal to the depth of the tank, i.e. 30cm. The height of each board is less than that of the tank, i.e. 50 cm, and differs one another. The boards are so thin that he can neglect the thickness in the experiments. Figure 2: The front view of the tank The front view of the tank is shown in Figure 2. There are several faucets above the tank and he turns them on at the beginning of his experiment. The tank is initially empty. Your mission is to write a computer program to simulate water flow in the tank. Input The input consists of multiple data sets. D is the number of the data sets. D DataSet 1 DataSet 2 ... DataSet D The format of each data set ( DataSet d , 1 <= d <= D ) is as follows. N B 1 H 1 B 2 H 2 ... B N H N M F 1 A 1 F 2 A 2 ... F M A M L P 1 T 1 P 2 T 2 ... P L T L Each line in the data set contains one or two integers. N is the number of the boards he sets in the tank . B i and H i are the x -position (cm) and the height (cm) of the i -th board, where 1 <= i <= N . H i s differ from one another. You may assume the following. 0 < N < 10 , 0 < B 1 < B 2 < ... < B N < 100 , 0 < H 1 < 50 , 0 < H 2 < 50 , ..., 0 < H N < 50. M is the number of the faucets above the tank . F j and A j are the x -position (cm) and the amount of water flow (cm 3 /second) of the j -th faucet , where 1 <= j <= M . There is no faucet just above any boards . Namely, none of F j is equal to B i . You may assume the following . 0 < M <10 , 0 < F 1 < F 2 < ... < F M < 100 , 0 < A 1 < 100, 0 < A 2 < 100, ... 0 < A M < 100. L is the number of observation time and location. P k is the x -position (cm) of the k -th observation point. T k is the k -th observation time in seconds from the beginning. None of P k is equal to B i . You may assume the following . 0 < L < 10 , 0 < P 1 < 100, 0 < P 2 < 100, ..., 0 < P L < 100 , 0 < T 1 < 1000000, 0 < T 2 < 1000000, ... , 0 < T L < 1000000. Output For each data set, your program should output L lines each containing one real number which represents the height (cm) of the water level specified by the x -position P k at the time T k . Each answer may not have an error greater than 0.001. As long as this condition is satisfied, you may output any number of digits after the decimal point. After the water tank is filled to the brim, the water level at any P k is equal to the height of the tank, that is, 50 cm. Sample Input 2 5 15 40 35 20 50 45 70 30 80 10 3 20 3 60 2 65 2 6 40 4100 25 7500 10 18000 90 7000 25 15000 25 22000 5 15 40 35 20 50 45 70 30 80 10 2 60 4 75 1 3 60 6000 75 ...(truncated)
[ { "submission_id": "aoj_1133_9144865", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\nusing namespace atcoder;\ntemplate<int mod>istream &operator>>(istream &is,static_modint<mod> &a){long long b;is>>b;a=b;return is;}\nistream &operator>>(istream &is,modint &a){long long b;cin>>b;a=b;return is;}\n#endif\n#ifdef LOCAL\n#include \"debug.h\"\n#else\n#define debug(...) static_cast<void>(0)\n#define debugg(...) static_cast<void>(0)\n#define esper(...) static_cast<void>(0)\ntemplate<typename T1,typename T2>ostream &operator<<(ostream &os,const pair<T1,T2>&p){os<<p.first<<' '<<p.second;return os;}\n#endif\nusing ll=long long;\nusing ull=unsigned long long;\nusing P=pair<ll,ll>;\ntemplate<typename T>using minque=priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T>bool chmax(T &a,const T &b){return (a<b?(a=b,true):false);}\ntemplate<typename T>bool chmin(T &a,const T &b){return (a>b?(a=b,true):false);}\ntemplate<typename T1,typename T2>istream &operator>>(istream &is,pair<T1,T2>&p){is>>p.first>>p.second;return is;}\ntemplate<typename T>istream &operator>>(istream &is,vector<T> &a){for(auto &i:a)is>>i;return is;}\ntemplate<typename T1,typename T2>void operator++(pair<T1,T2>&a,int n){a.first++,a.second++;}\ntemplate<typename T1,typename T2>void operator--(pair<T1,T2>&a,int n){a.first--,a.second--;}\ntemplate<typename T>void operator++(vector<T>&a,int n){for(auto &i:a)i++;}\ntemplate<typename T>void operator--(vector<T>&a,int n){for(auto &i:a)i--;}\n#define reps(i,a,n) for(int i=(a);i<(n);i++)\n#define rep(i,n) reps(i,0,n)\n#define all(x) x.begin(),x.end()\n#define pcnt(x) __builtin_popcountll(x)\n#define fin(x) return cout<<x<<'\\n',static_cast<void>(0)\nll myceil(ll a,ll b){return (a+b-1)/b;}\ntemplate<typename T,size_t n,size_t id=0>\nauto vec(const int (&d)[n],const T &init=T()){\n if constexpr (id<n)return vector(d[id],vec<T,n,id+1>(d,init));\n else return init;\n}\nvoid SOLVE();\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout<<fixed<<setprecision(16);\n #ifdef LOCAL\n clock_t start=clock();\n #endif\n int testcase=1;\n cin>>testcase;\n for(int i=0;i<testcase;i++){\n SOLVE();\n }\n #ifdef LOCAL\n cerr<<\"time:\";\n cerr<<(clock()-start)/1000;\n cerr<<\"ms\\n\";\n #endif\n}\nstruct UF{\n vector<int>par;\n UF(int n):par(n,-1){}\n int root(int u){\n if(par[u]<0)return u;\n return par[u]=root(par[u]);\n }\n bool same(int u,int v){return root(u)==root(v);}\n void merge(int u,int v){\n int ru=root(u),rv=root(v);\n if(ru==rv)return;\n if(ru>rv)swap(ru,rv);\n par[ru]+=par[rv];\n par[rv]=ru;\n }\n};\nvoid SOLVE(){\n int n;\n cin>>n;\n vector<int>board(101,0);\n rep(i,n){\n int a,b;\n cin>>a>>b;\n board[a]=b;\n }\n board[0]=board[100]=1e9;\n int m;\n cin>>m;\n vector<pair<int,int>>water(m);\n cin>>water;\n int l;\n cin>>l;\n vector<pair<int,int>>sokutei(l);\n cin>>sokutei;\n vector<int>left(100,1e9),right(100,1e9);\n left[0]=0,right[99]=100;\n reps(i,1,100){\n if(board[i])left[i]=i;\n else left[i]=left[i-1];\n }\n for(int i=98;i>=0;i--){\n if(board[i+1])right[i]=i+1;\n else right[i]=right[i+1];\n }\n vector<double>now(100,0);\n UF uf(100);\n rep(i,100){\n if(left[i]!=i)uf.merge(i,i-1);\n }\n auto step=[&](int time)->void {\n for(auto [f,a]:water){\n now[uf.root(f)]+=double(a)*time/(30*(right[uf.root(f)]-left[uf.root(f)]));\n }\n };\n auto eval2=[&](int l,int r)->bool {\n assert(left[l]==l);\n assert(left[r]==r);\n double sum=0;\n int mx=max(board[right[l]],board[left[r]]);\n reps(i,l,r+1)if(uf.root(i)==i){\n sum+=now[i]*(right[i]-left[i]);\n if(i!=l)chmax(mx,board[left[i]]);\n if(i!=r)chmax(mx,board[right[i]]);\n }\n int len=right[r]-left[l];\n sum/=len;\n if(sum<mx)return false;\n if(mx>min(board[left[l]],board[right[r]]))return false;\n // if(sum>min(board[left[l]],board[right[r]])){\n // vector<int>ar;\n // reps(i,l,r+1)if(uf.root(i)==i)ar.push_back(i);\n // reps(i,1,ar.size())uf.merge(ar[i],ar[i-1]);\n // right[l]=right[r];\n // now[l]=sum;\n // return true;\n vector<int>ar;\n reps(i,l,r+1)if(uf.root(i)==i)ar.push_back(i);\n reps(i,1,ar.size())uf.merge(ar[i],ar[i-1]);\n right[l]=right[r];\n now[l]=sum;\n return true;\n };\n auto eval=[&]()->void {\n vector<int>ar;\n rep(fh,120){\n rep(i,100)if(uf.root(i)==i){\n ar.push_back(i);\n }\n assert(!ar.empty()&&ar.size()<=11);\n vector<bool>connected(ar.size(),false);\n rep(i,ar.size())reps(j,i+1,ar.size()){\n bool ok=true;\n reps(k,i,j+1)ok&=!connected[k];\n if(ok){\n if(eval2(ar[i],ar[j]))reps(k,i,j+1)connected[k]=true;\n }\n }\n debug(fh);\n ar.clear();\n }\n rep(i,100)if(uf.root(i)==i)ar.push_back(i);\n // vector<bool>seen(ar.size(),false);\n rep(j,ar.size())debug(ar[j],now[ar[j]]);\n rep(j,120){\n double mx=0;\n int i=-1;\n ar.clear();\n rep(k,100)if(uf.root(k)==k)ar.push_back(k);\n debug(ar);\n rep(k,ar.size())if(uf.root(ar[k])==ar[k]&&min(board[left[ar[k]]],board[right[ar[k]]])<now[ar[k]]){\n i=k;\n break;\n }\n if(i==-1)break;\n // debug(i,ar[i],now[ar[i]]);\n // if(min(board[left[ar[i]]],board[right[ar[i]]])>=now[ar[i]]){\n // seen[i]=true;\n // continue;\n // }\n if(board[left[ar[i]]]<board[right[ar[i]]]){\n double over=(now[ar[i]]-board[left[ar[i]]])*(right[ar[i]]-left[ar[i]]);\n now[ar[i-1]]+=over/(right[ar[i-1]]-left[ar[i-1]]);\n now[ar[i]]=board[left[ar[i]]];\n }\n else{\n double over=(now[ar[i]]-board[right[ar[i]]])*(right[ar[i]]-left[ar[i]]);\n now[ar[i+1]]+=over/(right[ar[i+1]]-left[ar[i+1]]);\n now[ar[i]]=board[right[ar[i]]];\n }\n vector<int>ar2;\n rep(i,100)if(uf.root(i)==i){\n ar2.push_back(i);\n }\n // assert(!ar.empty()&&ar.size()<=11);\n vector<bool>connected(ar2.size(),false);\n rep(i,ar2.size())reps(j,i+1,ar2.size()){\n bool ok=true;\n reps(k,i,j+1)ok&=!connected[k];\n if(ok){\n if(eval2(ar2[i],ar2[j]))reps(k,i,j+1)connected[k]=true;\n }\n }\n // seen[i]=true;\n }\n };\n vector<int>ord(l);\n iota(all(ord),0);\n sort(all(ord),[&](int x,int y){return sokutei[x].second<sokutei[y].second;});\n vector<double>ans(l,-1);\n int pre=0;\n for(int i:ord){\n step(sokutei[i].second-pre);\n rep(j,100)if(uf.root(j)==j)debug(j,now[j]);\n eval();\n rep(j,100)if(uf.root(j)==j)debug(j,now[j]);\n pre=sokutei[i].second;\n ans[i]=min<double>(50,now[uf.root(sokutei[i].first)]);\n }\n rep(i,l)cout<<ans[i]<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3508, "score_of_the_acc": -0.0898, "final_rank": 4 }, { "submission_id": "aoj_1133_2392044", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing pii = pair<int,int>;\nusing ll = long long;\n#define rep(i, j) for(int i=0; i < (int)(j); i++)\n#define all(v) v.begin(),v.end()\nconst double EPS = 1e-8;\n\nstruct Node {\n int l, r, h;\n double water;\n bool is_child_full;\n list<Node> children; // all children shold have same height.\n Node(int l, int r, int h) : l(l), r(r), h(h), water(0), is_child_full(false) {} \n void insert(int b, int h, int d = 0) {\n if(children.size() == 0) {\n children.push_back(Node(l, b, h));\n children.push_back(Node(b, r, h));\n } else {\n auto child = find(b);\n if(child->h != h) {\n child->insert(b, h, d+1);\n } else {\n int lc = child->l;\n child->l = b;\n children.insert(child, Node(lc, b, h));\n }\n }\n }\n // find child which range contains p\n list<Node>::iterator find(int p) {\n for(auto c = begin(children); c != end(children); c++) {\n if(c->l <= p and p < c->r) return c;\n }\n assert(0);\n }\n double capacity() {\n return 30.0 * h * (r - l);\n }\n double pour(int p, double a) {\n if(water + a >= capacity()) {\n double left = water + a - capacity();\n water = capacity();\n return left;\n }\n water += a;\n assert(water / 30.0 / (r - l) <= h);\n if(children.size() > 0) {\n auto child = find(p);\n double left = child->pour(p, a);\n if(left == 0) return 0;\n assert(abs(child->height(p) - child->h) < EPS); // child is full\n double left1 = left / 2, left2 = left / 2;\n // go right\n auto c2 = child;\n while(left1 > 0 and c2 != end(children)) {\n left1 = c2->pour(c2->l, left1);\n c2++;\n }\n // go left\n c2 = child; \n left2 += left1;\n if(c2 != begin(children)) {\n do {\n c2--;\n left2 = c2->pour(c2->r - 1, left2);\n } while(left2 > 0 and c2 != begin(children));\n }\n // go right(2nd)\n c2 = child;\n while(left2 > 0 and c2 != end(children)) {\n left2 = c2->pour(c2->l, left2);\n c2++;\n }\n if(left2 > 0) is_child_full = true;\n }\n return 0;\n }\n double height(int p) {\n if(is_child_full or children.size() == 0) return water / 30.0 / (r - l);\n return find(p)->height(p);\n }\n void show_structure(int d = 0) { \n if(is_child_full) return;\n rep(i, d) cerr << \"\\t\";\n for(auto p : children) cerr << \"[\" << p.l << \", \" << p.water / 30.0 / (p.r - p.l) << \"/\" << p.h << \" , \" << p.r << \")\" << \" \";\n cerr << endl;\n for(auto p : children) p.show_structure(d + 1);\n }\n};\n\n\nvoid solve() {\n int N; cin >> N;\n // make tree\n vector<pii> HB(N); rep(i, N) cin >> HB[i].second >> HB[i].first;\n sort(all(HB), greater<pii>()); \n Node root(0, 100, 50);\n rep(i, N) root.insert(HB[i].second, HB[i].first);\n //root.show_structure();\n \n // input pour\n int M; cin >> M;\n vector<int> F(M), A(M); rep(i, M) cin >> F[i] >> A[i];\n // input measure\n int L; cin >> L;\n vector<pair<pii,int>> TP(L);\n rep(i, L) {\n cin >> TP[i].first.second >> TP[i].first.first;\n TP[i].second = i;\n }\n sort(all(TP));\n\n // simulate for each t \n int tp_i = 0;\n vector<double> ans(L, -1);\n rep(t, 1000000) {\n // measure point\n while(tp_i < L and TP[tp_i].first.first == t) { \n double a = root.height(TP[tp_i].first.second);\n ans[TP[tp_i].second] = a;\n tp_i++;\n }\n // update height\n rep(m, M) root.pour(F[m], A[m]);\n }\n rep(i, L) printf(\"%.6lf\\n\", ans[i]);\n}\n\n\nint main() {\n int D; cin >> D;\n rep(i, D) solve();\n return 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 3180, "score_of_the_acc": -0.5054, "final_rank": 7 }, { "submission_id": "aoj_1133_2392036", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing pii = pair<int,int>;\nusing ll = long long;\n#define rep(i, j) for(int i=0; i < (int)(j); i++)\n#define all(v) v.begin(),v.end()\n#define debug(x) cerr << #x << \" : \" << x << endl\n// vector\ntemplate<class T> istream& operator >> (istream &is , vector<T> &v) { for(T &a : v) is >> a; return is; }\n\nconst double EPS = 1e-8;\n\nstruct Node {\n int l, r, h;\n double water;\n bool is_child_full;\n list<Node> children;\n Node(int l, int r, int h) : l(l), r(r), h(h), water(0), is_child_full(false) {}\n void insert(int b, int h, int d = 0) {\n if(children.size() == 0) {\n children.push_back(Node(l, b, h));\n children.push_back(Node(b, r, h));\n } else {\n auto child = find(b);\n if(child->h != h) {\n child->insert(b, h, d+1);\n } else {\n int lc = child->l;\n child->l = b;\n children.insert(child, Node(lc, b, h));\n }\n }\n }\n list<Node>::iterator find(int p) {\n for(auto c = begin(children); c != end(children); c++) {\n if(c->l <= p and p < c->r) return c;\n }\n assert(0);\n }\n double capacity() {\n return 30.0 * h * (r - l);\n }\n double pour(int p, double a) {\n if(water + a >= capacity()) {\n double left = water + a - capacity();\n water = capacity();\n return left;\n }\n water += a;\n assert(water / 30.0 / (r - l) <= h);\n if(children.size() > 0) {\n auto child = find(p);\n double left = child->pour(p, a);\n if(left == 0) return 0;\n assert(abs(child->height(p) - child->h) < EPS); // child is full\n double left1 = left / 2, left2 = left / 2;\n // go right\n auto c2 = child;\n while(left1 > 0 and c2 != end(children)) {\n left1 = c2->pour(c2->l, left1);\n c2++;\n }\n // go left\n c2 = child; \n left2 += left1;\n if(c2 != begin(children)) {\n do {\n c2--;\n left2 = c2->pour(c2->r - 1, left2);\n } while(left2 > 0 and c2 != begin(children));\n }\n // go right(2nd)\n c2 = child;\n while(left2 > 0 and c2 != end(children)) {\n left2 = c2->pour(c2->l, left2);\n c2++;\n }\n if(left2 > 0) is_child_full = true;\n }\n return 0;\n }\n double height(int p) {\n if(is_child_full or children.size() == 0) return water / 30.0 / (r - l);\n return find(p)->height(p);\n }\n void show_structure(int d = 0) {\n rep(i, d) cerr << \"\\t\"; \n if(is_child_full) {\n cerr << water / 30.0 / (r - l) << \" / \" << h << \" (child full)\" << endl;\n return;\n }\n \n for(auto p : children) { \n cerr << \"[\" << p.l << \", \" << p.water / 30.0 / (p.r - p.l) << \"/\" << p.h << \" , \" << p.r << \")\" << \" \";\n }\n cerr << endl;\n for(auto p : children) p.show_structure(d + 1);\n }\n};\n\n\nvoid solve() {\n int N; cin >> N;\n vector<pii> HB(N); rep(i, N) cin >> HB[i].second >> HB[i].first;\n sort(all(HB), greater<pii>());\n \n Node root(0, 100, 50);\n rep(i, N) root.insert(HB[i].second, HB[i].first);\n \n int M; cin >> M;\n vector<int> F(M), A(M); rep(i, M) cin >> F[i] >> A[i];\n \n int L; cin >> L;\n vector<pair<pii,int>> TP(L);\n rep(i, L) {\n cin >> TP[i].first.second >> TP[i].first.first;\n TP[i].second = i;\n }\n //root.show_structure();\n sort(all(TP));\n int tp_i = 0;\n vector<double> ans(L, -1);\n rep(t, 1000000) {\n while(tp_i < L and TP[tp_i].first.first == t) {\n double a = root.height(TP[tp_i].first.second);\n ans[TP[tp_i].second] = a;\n tp_i++;\n }\n rep(m, M) {\n root.pour(F[m], A[m]);\n }\n }\n rep(i, L) printf(\"%.6lf\\n\", ans[i]);\n}\n\n\nint main() {\n int D; cin >> D;\n rep(i, D) solve();\n return 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 3160, "score_of_the_acc": -0.5046, "final_rank": 6 }, { "submission_id": "aoj_1133_2084492", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,x,y) for(int i=(x);i<(y);++i)\n#define debug(x) #x << \"=\" << (x)\n\n#ifdef DEBUG\n#define _GLIBCXX_DEBUG\n#define print(x) std::cerr << debug(x) << \" (L:\" << __LINE__ << \")\" << std::endl\n#else\n#define print(x)\n#endif\n\nconst int inf=1e9;\nconst int64_t inf64=1e18;\nconst double eps=1e-9;\n\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec){\n os << \"[\";\n for (const auto &v : vec) {\n \tos << v << \",\";\n }\n os << \"]\";\n return os;\n}\n\nstruct node{\n int left_pos,right_pos,left_height,right_height;\n double sum,flow;\n};\n\nvoid solve(){\n int n;\n cin >> n;\n vector<int> b(n+2),h(n+2); //???????????????\n b[0]=0;\n b[n+1]=100;\n h[0]=50;\n h[n+1]=50;\n rep(i,1,n+1) cin >> b[i] >> h[i];\n int m;\n cin >> m;\n vector<int> f(m),a(m); //???????????????\n rep(i,0,m) cin >> f[i] >> a[i];\n int l;\n cin >> l;\n vector<int> p(l),t(l); //???????????????\n vector<vector<int>> query(1000000);\n rep(i,0,l){\n cin >> p[i] >> t[i];\n query[t[i]].push_back(i);\n }\n\n list<node> intervals;\n rep(i,0,n+1){\n node n;\n n.left_pos=b[i];\n n.right_pos=b[i+1];\n n.left_height=h[i];\n n.right_height=h[i+1];\n n.sum=n.flow=0;\n rep(j,0,m){\n if(f[j]<n.left_pos or n.right_pos<f[j]) continue;\n n.flow+=a[j];\n }\n intervals.push_back(n);\n }\n vector<double> ans(l);\n rep(ct,1,1000000){\n for(auto &interval:intervals) interval.sum+=interval.flow;\n for(;;){\n bool update=false;\n for(auto it=intervals.begin();; ++it){\n auto left=it,right=it;\n ++right;\n if(min({left->left_height,left->right_height})==min({right->left_height,right->right_height}) and\n left->sum+right->sum>=30*(right->right_pos-left->left_pos)*left->right_height){\n node n=*left;\n n.right_pos=right->right_pos;\n n.right_height=right->right_height;\n n.sum+=right->sum;\n n.flow+=right->flow;\n auto tmp=intervals.insert(left,n);\n ++tmp;\n tmp=intervals.erase(tmp);\n intervals.erase(tmp);\n\n update=true;\n break;\n }\n if(right->right_height==50) break;\n }\n\n for(auto it=intervals.begin(); it!=intervals.end(); ++it){\n auto &interval=*it;\n double s=30*(interval.right_pos-interval.left_pos);\n if(interval.left_height<interval.right_height){\n double h=interval.sum/s;\n if(h>interval.left_height){\n double d=h-interval.left_height;\n interval.sum-=d*s;\n auto left=it;\n --left;\n left->sum+=d*s;\n\n update=true;\n }\n }else{\n double h=interval.sum/s;\n if(h>interval.right_height){\n double d=h-interval.right_height;\n interval.sum-=d*s;\n auto right=it;\n ++right;\n right->sum+=d*s;\n\n update=true;\n }\n }\n }\n if(!update or intervals.size()==1) break;\n }\n for(int i:query[ct]){\n for(auto interval:intervals){\n if(p[i]<interval.left_pos or interval.right_pos<p[i]) continue;\n ans[i]=min(50.,interval.sum/30/(interval.right_pos-interval.left_pos));\n break;\n }\n }\n }\n rep(i,0,l) cout << ans[i] << endl;\n}\n\nint main(){\n std::cin.tie(0);\n std::ios::sync_with_stdio(false);\n cout.setf(ios::fixed);\n cout.precision(10);\n int d;\n cin >> d;\n rep(i,0,d) solve();\n return 0;\n}", "accuracy": 1, "time_ms": 500, "memory_kb": 26624, "score_of_the_acc": -2, "final_rank": 8 }, { "submission_id": "aoj_1133_1482153", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,k,n) for(int i = (k); i < (n); i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(a) a.begin(), a.end()\n#define MS(m,v) memset(m,v,sizeof(m))\n#define D10 fixed<<setprecision(10)\ntypedef vector<int> vi;\ntypedef vector<string> vs;\ntypedef pair<int, int> pii;\ntypedef long long ll;\nconst int INF = 114514810;\nconst int MOD = 1000000007;\nconst double EPS = 1e-10;\ntypedef double weight;\nstruct edge\n{\n\tint to; weight cost;\n\tbool operator < (const edge& e) const { return cost < e.cost; }\n\tbool operator >(const edge& e) const { return cost > e.cost; }\n};\n\ntypedef vector<edge> Edges;\ntypedef vector<Edges> Graph;\n//int dx[] = { -1, 0, 0, 1 }; int dy[] = { 0, -1, 1, 0 };\ntemplate<class T> T &chmin(T &a, const T &b) { return a = min(a, b); }\ntemplate<class T> T &chmax(T &a, const T &b) { return a = max(a, b); }\nbool valid(int x, int y, int h, int w) { return (x >= 0 && y >= 0 && x < h&&y < w); }\nint place(int x, int y, int w) { return w*x + y; }\n///*************************************************************************************///\n///*************************************************************************************///\n///*************************************************************************************///\n\ntypedef pair<int, double> pid;\nstruct data{ int lx, rx, lh, rh; double h; };\nvector<data> v;\n\ndouble add(int p, double w)\n{\n\tREP(i, v.size())\n\t{\n\t\tif (v[i].lx <= p && v[i].rx>=p)\n\t\t{\n\t\t\tdouble bot = (v[i].rx - v[i].lx + 1) * 30;\n\t\t\tint minh = min(v[i].rh, v[i].lh);\n\t\t\tif (v[i].h - minh > -EPS)\n\t\t\t{\n\t\t\t\tif (v[i].h - v[i].lh > -EPS)\n\t\t\t\t{\n\t\t\t\t\tif (abs(v[i-1].h - v[i].h) < EPS) return w;\n\t\t\t\t\telse add(v[i - 1].lx, w);\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tif (abs(v[i + 1].h - v[i].h) < EPS) return w;\n\t\t\t\t\telse add(v[i + 1].lx, w);\n\t\t\t\t}\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tif ((minh - v[i].h)*bot - w > -EPS)\n\t\t\t\t{\n\t\t\t\t\tv[i].h += w / bot;\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tdouble rt = w - (minh - v[i].h)*bot;\n\t\t\t\t\tv[i].h = minh;\n\t\t\t\t\treturn rt;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint D;\n\tcin >> D;\n\twhile (D--)\n\t{\n\t\tv.clear();\n\t\tint n, m, l;\n\t\tvector<pid> s;\n\t\tvector<pii> b, q;\n\t\tcin >> n;\n\t\tREP(i, n)\n\t\t{\n\t\t\tint x, y;\n\t\t\tcin >> x >> y;\n\t\t\tb.push_back(pii(x, y));\n\t\t}\t\t\n\t\tcin >> m;\n\t\tREP(i, m)\n\t\t{\n\t\t\tint x, y;\n\t\t\tcin >> x >> y;\n\t\t\ts.push_back(pii(x, y));\n\t\t}\n\t\tcin >> l;\n\t\tREP(i, l)\n\t\t{\n\t\t\tint x, y;\n\t\t\tcin >> x >> y;\n\t\t\tq.push_back(pii(x, y));\n\t\t}\n\n\t\tv.push_back(data{ 0, b[0].first - 1, INF, b[0].second, 0 });\n\t\tREP(i, n - 1) v.push_back(data{ b[i].first, b[i + 1].first - 1, b[i].second, b[i + 1].second, 0 });\n\t\tv.push_back(data{ b.back().first, 99, b.back().second, INF, 0 });\n\n\t\tvector<bool> f(l); vector<double> ans(l);\n\t\tREP(i, l)\n\t\t{\n\t\t\tif (q[i].second >= 150000)\n\t\t\t{\n\t\t\t\tans[i] = 50;\n\t\t\t\tf[i] = true;\n\t\t\t}\n\t\t}\n\n\t\tfor (int time = 1;time<=150000; time++)\n\t\t{\n\t\t\tvector<pid> res = s;\n\t\t\twhile (res.size())\n\t\t\t{\n\t\t\t\tvector<pid> nres;\n\t\t\t\tREP(i, res.size())\n\t\t\t\t{\n\t\t\t\t\tdouble d = add(res[i].first, res[i].second);\n\t\t\t\t\tif (d > EPS) nres.push_back(pid(res[i].first, d));\n\t\t\t\t}\n\t\t\t\tres = nres;\n\n\t\t\t\tvector<data> nv;\n\t\t\t\tREP(i, v.size())\n\t\t\t\t{\n\t\t\t\t\tif (i<v.size()-1 && v[i].h - v[i].rh > -EPS&&v[i+1].h - v[i+1].lh > -EPS)\n\t\t\t\t\t{\n\t\t\t\t\t\tnv.push_back(data{ v[i].lx, v[i + 1].rx, v[i].lh, v[i + 1].rh, v[i].h });\n\t\t\t\t\t\ti++;\n\t\t\t\t\t}\n\t\t\t\t\telse nv.push_back(v[i]);\n\t\t\t\t}\n\t\t\t\tv = nv;\n\t\t\t}\n\n\t\t\tbool end = true;\n\t\t\tREP(i, l)\n\t\t\t{\n\t\t\t\tif (q[i].second == time)\n\t\t\t\t{\n\t\t\t\t\tREP(j, v.size())\n\t\t\t\t\t{\n\t\t\t\t\t\tif (q[i].first >= v[j].lx&&q[i].first <= v[j].rx) \n\t\t\t\t\t\t\tans[i] = min(v[j].h, 50.0);\n\t\t\t\t\t}\n\t\t\t\t\tf[i] = true;\n\t\t\t\t}\n\t\t\t\tif (!f[i]) end = false;\n\t\t\t}\n\t\t\tif (end) break;\n\t\t}\n\t\tREP(i, l) cout << D10 << ans[i] << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1284, "score_of_the_acc": -0.043, "final_rank": 3 }, { "submission_id": "aoj_1133_862123", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n#include <cstdio>\n#include <iostream>\n#include <sstream>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <queue>\n#include <stack>\n#include <limits>\n#include <map>\n#include <string>\n#include <cstring>\n#include <set>\n#include <deque>\n#include <bitset>\n#include <list>\n#include <cctype>\n#include <utility>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair <int,int> P;\ntypedef pair <int,P > PP;\n \nint tx[] = {0,1,0,-1};\nint ty[] = {-1,0,1,0};\n \nstatic const double EPS = 1e-8;\n\nclass Cell {\npublic:\n int parent;\n int brother;\n bool has_child;\n\n int water;\n int capacity;\n int height;\n int start_x;\n int end_x;\n Cell(int _h,int _sx,int _ex) : height(_h),start_x(_sx),end_x(_ex),\n\t\t\t\t parent(-1),brother(-1),water(0),has_child(false){\n capacity = height * (end_x - start_x) * 30;\n }\n\n void pour_water(int _water){\n water += _water;\n }\n\n double compute_water_level(){\n return (double)water / ((double)(end_x - start_x) * 30.0);\n }\n bool is_filled(){\n return (capacity <= water);\n }\n\n bool operator<(const Cell& c) const{\n return start_x < c.start_x;\n }\n bool operator<(const int _x) const{\n return start_x < _x;\n }\n};\n\nstruct Board{\n int x;\n int height;\n Board(int _x,int _h) : x(_x), height(_h) {}\n bool operator<(const Board& b) const{\n return x < b.x;\n }\n bool operator>(const Board& b) const{\n return x > b.x;\n }\n};\n\nstruct Faucet{\n int x;\n int cm3_per_second;\n Faucet(int _x,int _c) : x(_x), cm3_per_second(_c) {}\n Faucet() : x(0), cm3_per_second(0) {}\n\n bool operator <(const Faucet& f) const{\n return (x < f.x);\n }\n\n bool operator >(const Faucet& f) const{\n return (x > f.x);\n }\n bool operator ==(const Faucet& f) const{\n return (x == f.x);\n }\n\n bool operator <(const int _x) const{\n return (x < _x);\n }\n bool operator >(const int _x) const{\n return (x > _x);\n }\n bool operator ==(const int _x) const{\n return (x == _x);\n }\n};\n\nint main(){\n int total_data_sets;\n while(~scanf(\"%d\",&total_data_sets)){\n for(int data_set_idx = 0; data_set_idx < total_data_sets; data_set_idx++){\n\n vector<Cell> cells;\n vector<Board> boards;\n int total_boards;\n scanf(\"%d\",&total_boards);\n\n boards.push_back(Board(0,50));\n for(int board_idx = 0; board_idx < total_boards; board_idx++){\n\tint x,height;\n\tscanf(\"%d %d\",&x,&height);\n\tboards.push_back(Board(x,height));\n }\n boards.push_back(Board(100,50));\n\n sort(boards.begin(),boards.end());\n for(int src_idx = 0; src_idx < boards.size(); src_idx++){\n\tif(boards[src_idx].x == 100) continue;\n\n\tfor(int target_idx = src_idx+1; target_idx < boards.size(); target_idx++){\n\t if(boards[target_idx].height < boards[src_idx].height) continue;\n\n\t else if(boards[target_idx].height >= boards[src_idx].height){\n\t cells.push_back(Cell(boards[src_idx].height,boards[src_idx].x,boards[target_idx].x));\n\t break;\n\t }\n\t}\n\n\tfor(int target_idx = src_idx-1; target_idx >= 0; target_idx--){\n\t if(boards[target_idx].height < boards[src_idx].height) continue;\n\n\t else if(boards[target_idx].height > boards[src_idx].height){\n\t cells.push_back(Cell(boards[src_idx].height,boards[target_idx].x,boards[src_idx].x));\n\t break;\n\t }\n\t}\n }\n\n //set brother\n for(int src_idx=0;src_idx<cells.size();src_idx++){\n\tint height = cells[src_idx].height;\n\n\tint target_wall[101];\n\tmemset(target_wall,0,sizeof(target_wall));\n\n\tfor(int target_idx = 0; target_idx < cells.size(); target_idx++){\n\t if(target_idx == src_idx) continue;\n\n\t if(cells[src_idx].end_x == cells[target_idx].start_x){\n\t target_wall[cells[target_idx].start_x] = max(cells[target_idx].height,target_wall[cells[target_idx].start_x]);\n\t }\n\t if(cells[src_idx].start_x == cells[target_idx].end_x){\n\t target_wall[cells[target_idx].end_x] = max(cells[target_idx].height,target_wall[cells[target_idx].end_x]);\n\t }\n\t}\n\n\tint diff = INF;\n\tfor(int target_idx = 0; target_idx < cells.size(); target_idx++){\n\t if(src_idx == target_idx) continue;\n\t if(cells[src_idx].end_x == cells[target_idx].start_x\n\t && height == target_wall[cells[target_idx].start_x]\n\t && diff > abs(cells[src_idx].end_x - cells[target_idx].end_x)){\n\t diff = abs(cells[src_idx].end_x - cells[target_idx].end_x);\n\t cells[src_idx].brother = target_idx;\n\t }\n\t if(cells[src_idx].start_x == cells[target_idx].end_x\n\t && height == target_wall[cells[target_idx].end_x]\n\t && diff > abs(cells[src_idx].start_x - cells[target_idx].start_x)){\n\t diff = abs(cells[src_idx].start_x - cells[target_idx].start_x);\n\t cells[src_idx].brother = target_idx;\n\t }\n\t}\n }\n\n //set parent\n for(int src_idx=0;src_idx<cells.size();src_idx++){\n\tint min_height = INF;\n\tint lower_height = cells[src_idx].height;\n\tfor(int target_idx = 0; target_idx < cells.size(); target_idx++){\n\t if(src_idx == target_idx) continue;\n\n\t if(cells[src_idx].start_x >= cells[target_idx].start_x\n\t && cells[src_idx].end_x <= cells[target_idx].end_x\n\t && lower_height <= cells[target_idx].height\n\t && min_height > cells[target_idx].height){\n\t min_height = cells[target_idx].height;\n\t cells[src_idx].parent = target_idx;\n\t }\n\t}\n\n\tif(cells[src_idx].parent != -1){\n\t cells[cells[src_idx].parent].has_child = true;\n\t}\n }\n\n\n vector<Faucet> faucets;\n int total_faucets;\n scanf(\"%d\",&total_faucets);\n for(int foucet_idx = 0; foucet_idx < total_faucets; foucet_idx++){\n\tint x,cm3_per_second;\n\tscanf(\"%d %d\",&x,&cm3_per_second);\n\tfaucets.push_back(Faucet(x,cm3_per_second));\n }\n\n sort(faucets.begin(),faucets.end());\n\n\n int total_observation_times;\n scanf(\"%d\",&total_observation_times);\n\n vector<Cell> store = cells;\n for(int observation_time_idx = 0; observation_time_idx < total_observation_times; observation_time_idx++){\n\tint x,time;\n\tscanf(\"%d %d\",&x,&time);\n\t\n\tfor(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t for(int faucet_idx = 0; faucet_idx < faucets.size();faucet_idx++){\n\t if(faucet_idx == faucets.size()) continue;\n\t if(faucets[faucet_idx].x < cells[cell_idx].start_x) continue;\n\t if(faucets[faucet_idx].x > cells[cell_idx].end_x) continue;\n\t if(cells[cell_idx].has_child) continue;\n\t \n\t cells[cell_idx].pour_water(faucets[faucet_idx].cm3_per_second * time);\n\t }\n\t}\n\n\n\tbool is_erased[1001];\n\tmemset(is_erased,false,sizeof(is_erased));\n\n\tbool is_updated = false;\n\tfor(int round=0;round<1000;round++){\n\t for(int src_idx = 0;src_idx < cells.size(); src_idx++){\n\t if(is_erased[src_idx]) continue;\n\t if(!cells[src_idx].is_filled()) continue;\n\n\t int freq[1001];\n\t memset(freq,0,sizeof(freq));\n\n\t int limit = cells.size() * 3;\n\t int cell_idx = src_idx;\n\n\t bool isok = true;\n\t while(limit-- > 0){\n\t if(!cells[cell_idx].is_filled()) break;\n\n\t freq[cell_idx]++;\n\t if(freq[cell_idx] >= 3) isok = false;\n\t int brother = cells[cell_idx].brother;\n\t if(brother == -1) break;\n\t cells[brother].water += (cells[cell_idx].water - cells[cell_idx].capacity);\n\t cells[cell_idx].water = cells[cell_idx].capacity;\n\t cell_idx = brother;\n\t }\n\t \n\t if(isok) continue;\n\n\t is_updated = true;\n\t int sx = INF;\n\t int ex = 0;\n\t int water = 0;\n\n\t for(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t if(is_erased[cell_idx]) continue;\n\n\t if(freq[cell_idx] >= 3){\n\t\tsx = min(sx,cells[cell_idx].start_x);\n\t\tex = max(ex,cells[cell_idx].end_x);\n\t\twater += cells[cell_idx].water;\n\t\tcells[cell_idx].water = 0;\n\t\tis_erased[cell_idx] = true;\n\t }\n\t }\n\t \n\t int new_cell_idx = 0;\n\t for(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t if(is_erased[cell_idx]) continue;\n\t \n\t if(sx == cells[cell_idx].start_x \n\t\t && ex == cells[cell_idx].end_x){\n\n\t\tcells[cell_idx].water = water;\n\t\tnew_cell_idx = cell_idx;\n\n\t\tbreak;\n\t }\n\t }\n\t \n\t for(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t if(is_erased[cell_idx]) continue;\n\t if(cells[cell_idx].brother != -1\n\t\t &&is_erased[cells[cell_idx].brother]){\n\t\tcells[cell_idx].brother = new_cell_idx;\n\t }\n\t }\n\t }\n\n\t if(!is_updated) break;\n\t}\n\n\tdouble res= 0.0;\n\tfor(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t if(cells[cell_idx].start_x <= x && x <= cells[cell_idx].end_x){\n\t res = max(cells[cell_idx].compute_water_level(),res);\n\t }\n\t}\n\tprintf(\"%lf\\n\",res >= 50.0 ? 50.0 : res);\n\tcells = store;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1228, "score_of_the_acc": -0.0204, "final_rank": 1 }, { "submission_id": "aoj_1133_862121", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n#include <cstdio>\n#include <iostream>\n#include <sstream>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <queue>\n#include <stack>\n#include <limits>\n#include <map>\n#include <string>\n#include <cstring>\n#include <set>\n#include <deque>\n#include <bitset>\n#include <list>\n#include <cctype>\n#include <utility>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair <int,int> P;\ntypedef pair <int,P > PP;\n \nint tx[] = {0,1,0,-1};\nint ty[] = {-1,0,1,0};\n \nstatic const double EPS = 1e-8;\n\nclass Cell {\npublic:\n int parent;\n int brother;\n bool has_child;\n\n int water;\n int capacity;\n int height;\n int start_x;\n int end_x;\n Cell(int _h,int _sx,int _ex) : height(_h),start_x(_sx),end_x(_ex),\n\t\t\t\t parent(-1),brother(-1),water(0),has_child(false){\n capacity = height * (end_x - start_x) * 30;\n }\n\n void pour_water(int _water){\n water += _water;\n }\n\n double compute_water_level(){\n return (double)water / ((double)(end_x - start_x) * 30.0);\n }\n bool is_filled(){\n return (capacity <= water);\n }\n\n bool operator<(const Cell& c) const{\n return start_x < c.start_x;\n }\n bool operator<(const int _x) const{\n return start_x < _x;\n }\n};\n\nstruct Board{\n int x;\n int height;\n Board(int _x,int _h) : x(_x), height(_h) {}\n bool operator<(const Board& b) const{\n return x < b.x;\n }\n bool operator>(const Board& b) const{\n return x > b.x;\n }\n};\n\nstruct Faucet{\n int x;\n int cm3_per_second;\n Faucet(int _x,int _c) : x(_x), cm3_per_second(_c) {}\n Faucet() : x(0), cm3_per_second(0) {}\n\n bool operator <(const Faucet& f) const{\n return (x < f.x);\n }\n\n bool operator >(const Faucet& f) const{\n return (x > f.x);\n }\n bool operator ==(const Faucet& f) const{\n return (x == f.x);\n }\n\n bool operator <(const int _x) const{\n return (x < _x);\n }\n bool operator >(const int _x) const{\n return (x > _x);\n }\n bool operator ==(const int _x) const{\n return (x == _x);\n }\n};\n\nint main(){\n int total_data_sets;\n while(~scanf(\"%d\",&total_data_sets)){\n for(int data_set_idx = 0; data_set_idx < total_data_sets; data_set_idx++){\n\n vector<Cell> cells;\n vector<Board> boards;\n int total_boards;\n scanf(\"%d\",&total_boards);\n\n boards.push_back(Board(0,50));\n for(int board_idx = 0; board_idx < total_boards; board_idx++){\n\tint x,height;\n\tscanf(\"%d %d\",&x,&height);\n\tboards.push_back(Board(x,height));\n }\n boards.push_back(Board(100,50));\n\n sort(boards.begin(),boards.end());\n for(int src_idx = 0; src_idx < boards.size(); src_idx++){\n\tif(boards[src_idx].x == 100) continue;\n\n\tfor(int target_idx = src_idx+1; target_idx < boards.size(); target_idx++){\n\t if(boards[target_idx].height < boards[src_idx].height) continue;\n\n\t else if(boards[target_idx].height >= boards[src_idx].height){\n\t cells.push_back(Cell(boards[src_idx].height,boards[src_idx].x,boards[target_idx].x));\n\t break;\n\t }\n\t}\n\n\tfor(int target_idx = src_idx-1; target_idx >= 0; target_idx--){\n\t if(boards[target_idx].height < boards[src_idx].height) continue;\n\n\t else if(boards[target_idx].height > boards[src_idx].height){\n\t cells.push_back(Cell(boards[src_idx].height,boards[target_idx].x,boards[src_idx].x));\n\t break;\n\t }\n\t}\n }\n\n //set brother\n for(int src_idx=0;src_idx<cells.size();src_idx++){\n\tint height = cells[src_idx].height;\n\n\tint target_wall[101];\n\tmemset(target_wall,0,sizeof(target_wall));\n\n\tfor(int target_idx = 0; target_idx < cells.size(); target_idx++){\n\t if(target_idx == src_idx) continue;\n\n\t if(cells[src_idx].end_x == cells[target_idx].start_x){\n\t target_wall[cells[target_idx].start_x] = max(cells[target_idx].height,target_wall[cells[target_idx].start_x]);\n\t }\n\t if(cells[src_idx].start_x == cells[target_idx].end_x){\n\t target_wall[cells[target_idx].end_x] = max(cells[target_idx].height,target_wall[cells[target_idx].end_x]);\n\t }\n\t}\n\n\tint diff = INF;\n\tfor(int target_idx = 0; target_idx < cells.size(); target_idx++){\n\t if(src_idx == target_idx) continue;\n\t if(cells[src_idx].end_x == cells[target_idx].start_x\n\t && height == target_wall[cells[target_idx].start_x]\n\t && diff > abs(cells[src_idx].end_x - cells[target_idx].end_x)){\n\t diff = abs(cells[src_idx].end_x - cells[target_idx].end_x);\n\t cells[src_idx].brother = target_idx;\n\t }\n\t if(cells[src_idx].start_x == cells[target_idx].end_x\n\t && height == target_wall[cells[target_idx].end_x]\n\t && diff > abs(cells[src_idx].start_x - cells[target_idx].start_x)){\n\t diff = abs(cells[src_idx].start_x - cells[target_idx].start_x);\n\t cells[src_idx].brother = target_idx;\n\t }\n\t}\n }\n\n //set parent\n for(int src_idx=0;src_idx<cells.size();src_idx++){\n\tint min_height = INF;\n\tint lower_height = cells[src_idx].height;\n\tfor(int target_idx = 0; target_idx < cells.size(); target_idx++){\n\t if(src_idx == target_idx) continue;\n\n\t if(cells[src_idx].start_x >= cells[target_idx].start_x\n\t && cells[src_idx].end_x <= cells[target_idx].end_x\n\t && lower_height <= cells[target_idx].height\n\t && min_height > cells[target_idx].height){\n\t min_height = cells[target_idx].height;\n\t cells[src_idx].parent = target_idx;\n\t }\n\t}\n\n\tif(cells[src_idx].parent != -1){\n\t cells[cells[src_idx].parent].has_child = true;\n\t}\n }\n\n\n vector<Faucet> faucets;\n int total_faucets;\n scanf(\"%d\",&total_faucets);\n for(int foucet_idx = 0; foucet_idx < total_faucets; foucet_idx++){\n\tint x,cm3_per_second;\n\tscanf(\"%d %d\",&x,&cm3_per_second);\n\tfaucets.push_back(Faucet(x,cm3_per_second));\n }\n\n sort(faucets.begin(),faucets.end());\n\n\n int total_observation_times;\n scanf(\"%d\",&total_observation_times);\n\n vector<Cell> store = cells;\n for(int observation_time_idx = 0; observation_time_idx < total_observation_times; observation_time_idx++){\n\tint x,time;\n\tscanf(\"%d %d\",&x,&time);\n\t\n\tfor(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t for(int faucet_idx = 0; faucet_idx < faucets.size();faucet_idx++){\n\t if(faucet_idx == faucets.size()) continue;\n\t if(faucets[faucet_idx].x < cells[cell_idx].start_x) continue;\n\t if(faucets[faucet_idx].x > cells[cell_idx].end_x) continue;\n\t if(cells[cell_idx].has_child) continue;\n\t \n\t cells[cell_idx].pour_water(faucets[faucet_idx].cm3_per_second * time);\n\t }\n\t}\n\n\n\tbool is_erased[1001];\n\tmemset(is_erased,false,sizeof(is_erased));\n\n\tfor(int round=0;round<1000;round++){\n\t for(int src_idx = 0;src_idx < cells.size(); src_idx++){\n\t if(is_erased[src_idx]) continue;\n\t if(!cells[src_idx].is_filled()) continue;\n\n\t int freq[1001];\n\t memset(freq,0,sizeof(freq));\n\n\t int limit = cells.size() * 3;\n\t int cell_idx = src_idx;\n\n\t bool isok = true;\n\t while(limit-- > 0){\n\t if(!cells[cell_idx].is_filled()) break;\n\n\t freq[cell_idx]++;\n\t if(freq[cell_idx] >= 3) isok = false;\n\t int brother = cells[cell_idx].brother;\n\t if(brother == -1) break;\n\t cells[brother].water += (cells[cell_idx].water - cells[cell_idx].capacity);\n\t cells[cell_idx].water = cells[cell_idx].capacity;\n\t cell_idx = brother;\n\t }\n\t \n\t if(isok) continue;\n\n\t int sx = INF;\n\t int ex = 0;\n\t int water = 0;\n\n\t for(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t if(is_erased[cell_idx]) continue;\n\n\t if(freq[cell_idx] >= 3){\n\t\tsx = min(sx,cells[cell_idx].start_x);\n\t\tex = max(ex,cells[cell_idx].end_x);\n\t\twater += cells[cell_idx].water;\n\t\tcells[cell_idx].water = 0;\n\t\tis_erased[cell_idx] = true;\n\t }\n\t }\n\t \n\t int new_cell_idx = 0;\n\t for(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t if(is_erased[cell_idx]) continue;\n\t \n\t if(sx == cells[cell_idx].start_x \n\t\t && ex == cells[cell_idx].end_x){\n\n\t\tcells[cell_idx].water = water;\n\t\tnew_cell_idx = cell_idx;\n\n\t\tbreak;\n\t }\n\t }\n\t \n\t for(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t if(is_erased[cell_idx]) continue;\n\t if(cells[cell_idx].brother != -1\n\t\t &&is_erased[cells[cell_idx].brother]){\n\t\tcells[cell_idx].brother = new_cell_idx;\n\t }\n\t }\n\t }\n\t}\n\n\tdouble res= 0.0;\n\tfor(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t if(cells[cell_idx].start_x <= x && x <= cells[cell_idx].end_x){\n\t res = max(cells[cell_idx].compute_water_level(),res);\n\t }\n\t}\n\tprintf(\"%lf\\n\",res >= 50.0 ? 50.0 : res);\n\tcells = store;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1228, "score_of_the_acc": -0.0204, "final_rank": 1 }, { "submission_id": "aoj_1133_862119", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n#include <cstdio>\n#include <iostream>\n#include <sstream>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <queue>\n#include <stack>\n#include <limits>\n#include <map>\n#include <string>\n#include <cstring>\n#include <set>\n#include <deque>\n#include <bitset>\n#include <list>\n#include <cctype>\n#include <utility>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair <int,int> P;\ntypedef pair <int,P > PP;\n \nint tx[] = {0,1,0,-1};\nint ty[] = {-1,0,1,0};\n \nstatic const double EPS = 1e-8;\n\nclass Cell {\npublic:\n int parent;\n int brother;\n bool has_child;\n\n int water;\n int capacity;\n int height;\n int start_x;\n int end_x;\n Cell(int _h,int _sx,int _ex) : height(_h),start_x(_sx),end_x(_ex),\n\t\t\t\t parent(-1),brother(-1),water(0),has_child(false){\n capacity = height * (end_x - start_x) * 30;\n }\n\n void pour_water(int _water){\n water += _water;\n }\n\n double compute_water_level(){\n return (double)water / ((double)(end_x - start_x) * 30.0);\n }\n bool is_filled(){\n return (capacity <= water);\n }\n\n bool operator<(const Cell& c) const{\n return start_x < c.start_x;\n }\n bool operator<(const int _x) const{\n return start_x < _x;\n }\n};\n\nstruct Board{\n int x;\n int height;\n Board(int _x,int _h) : x(_x), height(_h) {}\n bool operator<(const Board& b) const{\n return x < b.x;\n }\n bool operator>(const Board& b) const{\n return x > b.x;\n }\n};\n\nstruct Faucet{\n int x;\n int cm3_per_second;\n Faucet(int _x,int _c) : x(_x), cm3_per_second(_c) {}\n Faucet() : x(0), cm3_per_second(0) {}\n\n bool operator <(const Faucet& f) const{\n return (x < f.x);\n }\n\n bool operator >(const Faucet& f) const{\n return (x > f.x);\n }\n bool operator ==(const Faucet& f) const{\n return (x == f.x);\n }\n\n bool operator <(const int _x) const{\n return (x < _x);\n }\n bool operator >(const int _x) const{\n return (x > _x);\n }\n bool operator ==(const int _x) const{\n return (x == _x);\n }\n};\n\nint main(){\n int total_data_sets;\n while(~scanf(\"%d\",&total_data_sets)){\n for(int data_set_idx = 0; data_set_idx < total_data_sets; data_set_idx++){\n\n vector<Cell> cells;\n vector<Board> boards;\n int total_boards;\n scanf(\"%d\",&total_boards);\n\n boards.push_back(Board(0,50));\n for(int board_idx = 0; board_idx < total_boards; board_idx++){\n\tint x,height;\n\tscanf(\"%d %d\",&x,&height);\n\tboards.push_back(Board(x,height));\n }\n boards.push_back(Board(100,50));\n\n sort(boards.begin(),boards.end());\n for(int src_idx = 0; src_idx < boards.size(); src_idx++){\n\tif(boards[src_idx].x == 100) continue;\n\n\tfor(int target_idx = src_idx+1; target_idx < boards.size(); target_idx++){\n\t if(boards[target_idx].height < boards[src_idx].height) continue;\n\n\t else if(boards[target_idx].height >= boards[src_idx].height){\n\t cells.push_back(Cell(boards[src_idx].height,boards[src_idx].x,boards[target_idx].x));\n\t break;\n\t }\n\t}\n\n\tfor(int target_idx = src_idx-1; target_idx >= 0; target_idx--){\n\t if(boards[target_idx].height < boards[src_idx].height) continue;\n\n\t else if(boards[target_idx].height > boards[src_idx].height){\n\t cells.push_back(Cell(boards[src_idx].height,boards[target_idx].x,boards[src_idx].x));\n\t break;\n\t }\n\t}\n }\n\n //set brother\n for(int src_idx=0;src_idx<cells.size();src_idx++){\n\tint height = cells[src_idx].height;\n\n\tint target_wall[101];\n\tmemset(target_wall,0,sizeof(target_wall));\n\n\tfor(int target_idx = 0; target_idx < cells.size(); target_idx++){\n\t if(target_idx == src_idx) continue;\n\n\t if(cells[src_idx].end_x == cells[target_idx].start_x){\n\t target_wall[cells[target_idx].start_x] = max(cells[target_idx].height,target_wall[cells[target_idx].start_x]);\n\t }\n\t if(cells[src_idx].start_x == cells[target_idx].end_x){\n\t target_wall[cells[target_idx].end_x] = max(cells[target_idx].height,target_wall[cells[target_idx].end_x]);\n\t }\n\t}\n\n\tint diff = INF;\n\tfor(int target_idx = 0; target_idx < cells.size(); target_idx++){\n\t if(src_idx == target_idx) continue;\n\t if(cells[src_idx].end_x == cells[target_idx].start_x\n\t && height == target_wall[cells[target_idx].start_x]\n\t && diff > abs(cells[src_idx].end_x - cells[target_idx].end_x)){\n\t diff = abs(cells[src_idx].end_x - cells[target_idx].end_x);\n\t cells[src_idx].brother = target_idx;\n\t }\n\t if(cells[src_idx].start_x == cells[target_idx].end_x\n\t && height == target_wall[cells[target_idx].end_x]\n\t && diff > abs(cells[src_idx].start_x - cells[target_idx].start_x)){\n\t diff = abs(cells[src_idx].start_x - cells[target_idx].start_x);\n\t cells[src_idx].brother = target_idx;\n\t }\n\t}\n }\n\n //set parent\n for(int src_idx=0;src_idx<cells.size();src_idx++){\n\tint min_height = INF;\n\tint lower_height = cells[src_idx].height;\n\tfor(int target_idx = 0; target_idx < cells.size(); target_idx++){\n\t if(src_idx == target_idx) continue;\n\n\t if(cells[src_idx].start_x >= cells[target_idx].start_x\n\t && cells[src_idx].end_x <= cells[target_idx].end_x\n\t && lower_height <= cells[target_idx].height\n\t && min_height > cells[target_idx].height){\n\t min_height = cells[target_idx].height;\n\t cells[src_idx].parent = target_idx;\n\t }\n\t}\n\n\tif(cells[src_idx].parent != -1){\n\t cells[cells[src_idx].parent].has_child = true;\n\t}\n }\n\n\n vector<Faucet> faucets;\n int total_faucets;\n scanf(\"%d\",&total_faucets);\n for(int foucet_idx = 0; foucet_idx < total_faucets; foucet_idx++){\n\tint x,cm3_per_second;\n\tscanf(\"%d %d\",&x,&cm3_per_second);\n\tfaucets.push_back(Faucet(x,cm3_per_second));\n }\n\n sort(faucets.begin(),faucets.end());\n\n\n int total_observation_times;\n scanf(\"%d\",&total_observation_times);\n\n vector<Cell> store = cells;\n for(int observation_time_idx = 0; observation_time_idx < total_observation_times; observation_time_idx++){\n\tint x,time;\n\tscanf(\"%d %d\",&x,&time);\n\t\n\tfor(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t for(int faucet_idx = 0; faucet_idx < faucets.size();faucet_idx++){\n\t //\t int faucet_idx = lower_bound(faucets.begin(),faucets.end(),cells[cell_idx].start_x) - faucets.begin();\n\t if(faucet_idx == faucets.size()) continue;\n\t if(faucets[faucet_idx].x < cells[cell_idx].start_x) continue;\n\t if(faucets[faucet_idx].x > cells[cell_idx].end_x) continue;\n\t if(cells[cell_idx].has_child) continue;\n\t \n\t cells[cell_idx].pour_water(faucets[faucet_idx].cm3_per_second * time);\n\t }\n\t}\n\n\n\tbool is_erased[1001];\n\tmemset(is_erased,false,sizeof(is_erased));\n\n\tfor(int round=0;round<10000;round++){\n\t for(int src_idx = 0;src_idx < cells.size(); src_idx++){\n\t if(is_erased[src_idx]) continue;\n\t if(!cells[src_idx].is_filled()) continue;\n\n\t int freq[1001];\n\t memset(freq,0,sizeof(freq));\n\n\t int limit = cells.size() * 3;\n\t int cell_idx = src_idx;\n\n\t bool isok = true;\n\t while(limit-- > 0){\n\t if(!cells[cell_idx].is_filled()) break;\n\n\t freq[cell_idx]++;\n\t if(freq[cell_idx] >= 3) isok = false;\n\t int brother = cells[cell_idx].brother;\n\t if(brother == -1) break;\n\t cells[brother].water += (cells[cell_idx].water - cells[cell_idx].capacity);\n\t cells[cell_idx].water = cells[cell_idx].capacity;\n\t cell_idx = brother;\n\t }\n\t \n\t if(isok) continue;\n\n\t int sx = INF;\n\t int ex = 0;\n\t int water = 0;\n\n\t for(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t if(is_erased[cell_idx]) continue;\n\n\t if(freq[cell_idx] >= 3){\n\t\tsx = min(sx,cells[cell_idx].start_x);\n\t\tex = max(ex,cells[cell_idx].end_x);\n\t\twater += cells[cell_idx].water;\n\t\tcells[cell_idx].water = 0;\n\t\tis_erased[cell_idx] = true;\n\t }\n\t }\n\t \n\t int new_cell_idx = 0;\n\t for(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t if(is_erased[cell_idx]) continue;\n\t \n\t if(sx == cells[cell_idx].start_x \n\t\t && ex == cells[cell_idx].end_x){\n\n\t\tcells[cell_idx].water = water;\n\t\tnew_cell_idx = cell_idx;\n\n\t\tbreak;\n\t }\n\t }\n\t \n\t for(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t if(is_erased[cell_idx]) continue;\n\t if(cells[cell_idx].brother != -1\n\t\t &&is_erased[cells[cell_idx].brother]){\n\t\tcells[cell_idx].brother = new_cell_idx;\n\t }\n\t }\n\t }\n\t}\n\n\tdouble res= 0.0;\n\tfor(int cell_idx = 0;cell_idx < cells.size(); cell_idx++){\n\t if(cells[cell_idx].start_x <= x && x <= cells[cell_idx].end_x){\n\t res = max(cells[cell_idx].compute_water_level(),res);\n\t }\n\t}\n\tprintf(\"%lf\\n\",res >= 50.0 ? 50.0 : res);\n\tcells = store;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 1232, "score_of_the_acc": -0.3471, "final_rank": 5 } ]
aoj_1130_cpp
Problem B: Red and Black There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can move only on black tiles. Write a program to count the number of black tiles which he can reach by repeating the moves described above. Input The input consists of multiple data sets. A data set starts with a line containing two positive integers W and H ; W and H are the numbers of tiles in the x - and y - directions, respectively. W and H are not more than 20. There are H more lines in the data set, each of which includes W characters. Each character represents the color of a tile as follows. '.' - a black tile '#' - a red tile '@' - a man on a black tile(appears exactly once in a data set) The end of the input is indicated by a line consisting of two zeros. Output For each data set, your program should output a line which contains the number of tiles he can reach from the initial tile (including itself). Sample Input 6 9 ....#. .....# ...... ...... ...... ...... ...... #@...# .#..#. 11 9 .#......... .#.#######. .#.#.....#. .#.#.###.#. .#.#..@#.#. .#.#####.#. .#.......#. .#########. ........... 11 6 ..#..#..#.. ..#..#..#.. ..#..#..### ..#..#..#@. ..#..#..#.. ..#..#..#.. 7 7 ..#.#.. ..#.#.. ###.### ...@... ###.### ..#.#.. ..#.#.. 0 0 Output for the Sample Input 45 59 6 13
[ { "submission_id": "aoj_1130_8840090", "code_snippet": "//会う時と+1のとき\n\n//いくつもとけるように\n//countの初期値直した テストケース2つokおそらくいける タリーズでwifi繋がらずまだ\n//69のaojテストケースでanswer45なのに1\n//隣接リストを用意→@からbfs -1でなかった点を数え上げる\n#include <iostream>\n#include <queue>\nusing namespace std;\n\nint bfs(int src, int n, int G[410][410]){ //srcは始点のk nはw*h Gはおっきな隣接リスト\n queue<int> Q;\n Q.push(src);\n int D[n+10];\n for (int i=0; i<n+10; ++i){\n D[i] = -1; //他はinf\n }\n D[src] = 0; //スタートは0\n while (! Q.empty()){\n int cur = Q.front();\n Q.pop(); //先頭取り出す\n for (int dst=0; dst<n+1; ++dst){ //全頂点\n if ((G[cur][dst] == 1) && (D[dst] == -1)){ //辺があってまだinfなら\n D[dst] = D[cur] + 1; //D更新\n Q.push(dst); //その点を新たな起点に\n }\n }\n }\n //Dから-1でないところを全部出す\n int count = 0; //スタート含む 0に戻した\n for (int t=0; t<n+10; ++t){\n if (D[t] > -1) {\n count += 1;\n //cout << \"passable t = \" << t << endl;\n }\n }\n return count;\n}\n\nbool valid(int x, int y, int w, int h, int R[20][20]){\n return (0 <= x) && (x < w) && (0 <= y) && (y < h) && (R[y][x] > 0);\n// return x が [0,W] の範囲 2\n// && y が [0,H] の範囲 3\n// && (x,y) が壁でない; \n}\n\n\nconst int dx[4]={1,0,-1,0}, dy[4]={0,-1,0,1};\nint main(){\n while (true) {\n int w, h;\n int rs, cs;\n //cout << \"hi.\" << endl;\n cin >> w >> h;\n if (w==0 && h==0) break;\n else{\n //cout << w << h << endl;\n int R[20][20];\n //Rは入力のコピー 記号を数字にしただけ\n for (int i=0; i<h; ++i){\n string li;\n cin >> li; //li = ...#..\n //cout << li << endl;\n for (int j=0; j<w; ++j){\n if (li[j] == '.') R[i][j] = 1;\n if (li[j] == '#') {\n R[i][j] = 0;\n //cout << i << j << endl;\n }\n if (li[j] == '@') {\n R[i][j] = 1;\n rs = i;\n cs = j;\n } //スタートだったら\n }\n }\n // for (int r=0; r<h; ++r){ Rはできてる!!\n // for (int c=0; c<w; ++c){\n // cout << R[r][c];\n // }\n // cout << endl;\n // }\n //隣接リストを作る 一辺w*h r行c列の要素は 左から w*r+c番目(0開始)\n int n = w*h;\n int G[410][410] = {0}; //Gを隣接リストに!\n //全頂点に対して隣の4つ調べる validなら1に\n for (int r=0; r<h; ++r){ //多分ここ 斜め下が1だったり真下なのに0だった\n for (int c=0; c<w; ++c){\n int k = w*r + c;\n for (int i=0; i<4; ++i){ //隣4つ調べる\n int r_ = r + dy[i]; int c_ = c + dx[i];\n int k_ = w*r_ + c_;\n if (valid(c_, r_, w, h, R)) G[k][k_] = 1; //多分ここ→よさそう\n }\n }\n }\n // for (int s=0; s<n; ++s){ //テスト\n // for (int t=0; t<n; ++t){\n // cout << G[s][t];\n // }\n // cout << endl;\n // }\n //以上でG完成\n int src = w*rs + cs;\n cout << bfs(src, n, G) << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3704, "score_of_the_acc": -0.0459, "final_rank": 4 }, { "submission_id": "aoj_1130_8641903", "code_snippet": "#include <iostream>\n#include <vector>\n#include <utility>\n#include <algorithm>\nusing namespace std;\n\nvoid dfs(vector< vector<int> > &mat, int cur, vector<bool> &visited, int &count) {\n visited[cur] = true;\n count++;\n for (int dst = 0; dst < mat[cur].size(); dst++) {\n if (mat[cur][dst] && !visited[dst]) {\n dfs(mat, dst, visited, count);\n }\n }\n}\n\nint main() {\n int W, H;\n while (true) {\n cin >> W >> H;\n if (W == 0 && H == 0) break;\n vector< vector<char> > map(H, vector<char>(W, 0));\n int at;\n string buf;\n for (int i = 0; i < H; i++) {\n cin >> buf;\n for (int j = 0; j < W; j++) {\n char b = buf[j];\n if (b == '@') at = i * W + j;\n map[i][j] = buf[j];\n }\n }\n auto valid = [&](int x, int y) {\n return 0 <= x && x < W && 0 <= y && y < H && map[y][x] != '#';\n };\n vector< vector<int> > adjMatrix(H * W + W, vector<int>(H * W + W, 0));\n const int dx[] = {1, 0, -1, 0}, dy[] = {0, -1, 0, 1};\n for (int y = 0; y < H; y++) {\n for (int x = 0; x < W; x++) {\n if (!valid(x, y)) continue;\n for (int i = 0; i < 4; i++) {\n int nx = x + dx[i], ny = y + dy[i];\n if (valid(nx, ny)) adjMatrix[y * W + x][ny * W + nx] = 1;\n }\n }\n }\n vector<bool> visited(H * W + W, false);\n int count = 0;\n dfs(adjMatrix, at, visited, count);\n cout << count << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3992, "score_of_the_acc": -0.0924, "final_rank": 5 }, { "submission_id": "aoj_1130_8574418", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <string>\n#include <algorithm>\nusing namespace std;\n\nvector<int> bfs(vector< vector<int> > mat, int src) {\n vector<int> D(mat.size(), -1);\n queue<int> Q;\n Q.push(src);\n D[src] = 0;\n while (!Q.empty()) {\n int cur = Q.front();\n Q.pop();\n for (int dst = 0; dst < mat[cur].size(); dst++) {\n if (mat[cur][dst] && D[dst] == -1) {\n D[dst] = D[cur] + 1;\n Q.push(dst);\n }\n }\n } \n return D;\n}\n\nint main() {\n int W, H;\n while (true) {\n cin >> W >> H;\n if (W == 0 && H == 0) break;\n vector< vector<char> > map(H, vector<char>(W, 0));\n int at;\n string buf;\n for (int i = 0; i < H; i++) {\n cin >> buf;\n for (int j = 0; j < W; j++) {\n char b = buf[j];\n if (b == '@') at = i * W + j;\n map[i][j] = buf[j];\n }\n }\n auto valid = [&](int x, int y) {\n return 0 <= x && x < W && 0 <= y && y < H && map[y][x] != '#';\n };\n vector< vector<int> > adjMatrix(H * W + W, vector<int>(H * W + W, 0));\n const int dx[] = {1, 0, -1, 0}, dy[] = {0, -1, 0, 1};\n for (int y = 0; y < H; y++) {\n for (int x = 0; x < W; x++) {\n if (!valid(x, y)) continue;\n for (int i = 0; i < 4; i++) {\n int nx = x + dx[i], ny = y + dy[i];\n if (valid(nx, ny)) adjMatrix[y * W + x][ny * W + nx] = 1;\n }\n }\n }\n vector<int> res = bfs(adjMatrix, at);\n cout << count_if(res.begin(), res.end(), [](int x) { return x != -1; }) << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4840, "score_of_the_acc": -0.2293, "final_rank": 7 }, { "submission_id": "aoj_1130_7903170", "code_snippet": "#include<iostream>\n#include<vector>\n#include<queue>\nusing namespace std;\nint c=0;\nint dx[4]={1, 0, -1, 0};\nint dy[4]={0, 1, 0, -1};\nvector<vector<bool> > is_visited(25,vector<bool>(25));\n\nvoid initialize_is_visited(){\n for(int i=0;i<25;i++){\n for(int j=0;j<25;j++){\n is_visited[j][i]=false;\n }\n }\n}\n\nbool is_movable(int x,int y,vector<vector<bool> > edge){//trueで壁でも範囲外でもない\n if(x>=0&&y>=0&&x<edge.size()&&y<edge[0].size()){\n if(edge[x][y]) return true;\n }\n return false;\n}\n\nvoid dfs(int x,int y,vector<vector<bool> > edge){\n is_visited[x][y]=true;//trueで訪問済\n /*for(int i=0;i<is_visited[0].size();i++){\n for(int j=0;j<is_visited.size();j++){\n cout << is_visited[j][i] << \" \";\n }\n cout << endl;\n }*/\n c++;\n for(int i=0;i<4;i++){\n //cout << \"visiting (\" << x << \",\" << y << \")\" << endl;\n if(is_movable(x+dx[i],y+dy[i],edge)){\n //cout << \"will go to \" << x+dx[i] << \",\" << y+dy[i] << \"and\" <<is_visited[x+dx[i]][y+dy[i]] << endl;\n if(is_visited[x+dx[i]][y+dy[i]]==false){\n dfs(x+dx[i],y+dy[i],edge);\n }\n }\n }\n}\n\nint main(){\n\n queue<int> Q;\n int w,h;\n\n while(cin >> w >> h){\n if(w==0&&h==0) break;\n vector<vector<bool> > edge(w, vector<bool>(h));\n int x,y;\n for(int i=0;i<h;i++){\n for(int j=0;j<w;j++){\n char b;\n cin >> b;\n if(b=='.') edge[j][i]=true;\n else if(b=='#') edge[j][i]=false;\n else{\n edge[j][i]=false;\n x=j;\n y=i;\n }\n }\n }\n dfs(x,y,edge);\n Q.push(c);\n c=0;\n initialize_is_visited();\n }\n\n while(!Q.empty()){\n int n;\n n=Q.front();\n Q.pop();\n cout << n << endl;\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3636, "score_of_the_acc": -0.5349, "final_rank": 8 }, { "submission_id": "aoj_1130_7892591", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define endl \"\\n\"\n#define all(v) v.begin(), v.end()\n#define rep(i, begin, end) for(auto i = (begin); i < (end); i++)\n#define rrep(i, end, begin) for(auto i = (end) - 1; i >= (begin); i--)\ntemplate<class T> inline bool chmin(T& a, T b){ if (a > b){ a = b; return true; } return false; }\ntemplate<class T> inline bool chmax(T& a, T b){ if (a < b){ a = b; return true; } return false; }\ntemplate<class T> inline T roundup(T a, T b){ return (a + b - 1) / b; }\nconstexpr int dy[] = {0, 1, 0, -1, 1, 1, -1, -1, 0};\nconstexpr int dx[] = {1, 0, -1, 0, 1, -1, 1, -1, 0};\nusing ll = long long;\nconstexpr ll INF = 1e9;\nusing Graph = vector<vector<int>>;\n\nvoid solve(int w, int h){\n queue<pair<int, int>> q;\n vector seen(h, vector(w, false));\n \n vector t(h, vector(w, '.'));\n rep(i, 0, h) rep(j, 0, w){\n cin >> t[i][j];\n if(t[i][j] == '@'){\n q.emplace(i, j), seen[i][j] = true;\n t[i][j] = '.';\n }\n }\n \n auto is_valid_move = [&](int yp, int xp){\n if(!(0 <= yp && yp < h && 0 <= xp && xp < w)) return false;\n return t[yp][xp] == '.';\n };\n \n while(!q.empty()){\n auto [y, x] = q.front(); q.pop();\n seen[y][x] = true;\n rep(i, 0, 4){\n int yp = y + dy[i], xp = x + dx[i];\n if(!is_valid_move(yp, xp) || seen[yp][xp]) continue;\n q.emplace(yp, xp);\n }\n }\n \n int ans = 0;\n rep(i, 0, h) rep(j, 0, w) ans += seen[i][j];\n cout << ans << endl;\n}\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n \n int w, h;\n while(true){\n cin >> w >> h;\n if(w == 0 && h == 0) return 0;\n solve(w, h);\n }\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 6208, "score_of_the_acc": -1.3253, "final_rank": 9 }, { "submission_id": "aoj_1130_7220941", "code_snippet": "#include<iostream>\n#include<cmath>\n#include<deque>\n#include<queue>\n#include <map>\n//#include <unordered_map>\n#include <vector>\n#include <fstream>\n#include <sstream>\n#include <algorithm>\n#include <set>\nusing namespace std;\n//using ll=long long;\n//using mint = modint998244353;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep2(i, n) for (int i = 1; i <= (int)(n); i++)\n\nusing namespace std;\n\n#if 0\n先日の深さ優先探索のものを改造するだけだったので10分程度できた。ただ、複数のデータセットに対応するために、いちいち初期化するのを忘れた。\n#endif\n\nvector<vector<int> > g(101);\nint dx[4] = {-1,0,1,0};\nint dy[4] = {0,1,0,-1};\n\nvoid dfs(int x,int y,int &ans,map<pair<int,int>,int> &mp,map<pair<int,int>,char> &mapp){\n mp[{x,y}] = 1;\n ans++;\n for(int i=0;i<4;i++){\n if(mp[{x+dx[i],y+dy[i]}]==0 && mapp[{x+dx[i],y+dy[i]}]=='.'){//訪れていないかつ到達可能\n //t++;\n dfs(x+dx[i],y+dy[i],ans,mp,mapp);\n }\n }\n}\n\nint main(){\n vector<int> answers;\n while(true){\n int answer = 0;\n map<pair<int,int>,char> mapp;//記号を管理\n int w,h;cin>>w>>h;\n if(w==0&&h==0) break;\n pair<int,int> start;\n rep(i,h){\n string tmp;cin>>tmp;\n rep(j,w){\n mapp[{i,j}] = tmp[j];\n if(mapp[{i,j}]=='@'){\n start = {i,j};\n }\n }\n }\n map<pair<int,int>,int> mp;//訪れたかを管理する。\n dfs(start.first,start.second,answer,mp,mapp);\n answers.push_back(answer);\n } \n for(auto e:answers){\n cout << e << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3452, "score_of_the_acc": -0.0052, "final_rank": 2 }, { "submission_id": "aoj_1130_7143165", "code_snippet": "#include<iostream>\n#include<cmath>\n#include<deque>\n#include<queue>\n#include <map>\n//#include <unordered_map>\n#include <vector>\n#include <fstream>\n#include <sstream>\n#include <algorithm>\n#include <set>\nusing namespace std;\n//using ll=long long;\n//using mint = modint998244353;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep2(i, n) for (int i = 1; i <= (int)(n); i++)\n\nusing namespace std;\n\n#if 0\n#endif\n\nvector<vector<int> > g(101);\n//int seen[21][21];\nint dx[4] = {-1,0,1,0};\nint dy[4] = {0,1,0,-1};\n\nint main(){\n vector<int> answers;\n while(true){\n int answer = 1;\n map<pair<int,int>,char> mapp;//記号を管理\n int w,h;cin>>w>>h;\n if(w==0&&h==0) break;\n pair<int,int> start;\n rep(i,h){\n string tmp;cin>>tmp;\n rep(j,w){\n mapp[{i,j}] = tmp[j];\n if(mapp[{i,j}]=='@') start = {i,j};\n }\n }\n queue<pair<int,int> > q;\n map<pair<int,int>,int> mp;//訪れたかを管理する。\n q.push(start);\n mp[start] = 1;\n while(!q.empty()){\n pair<int,int> d = q.front();\n q.pop();\n for(int i=0;i<4;i++){//上下左右の4方向\n pair<int,int> nextd;\n nextd = {d.first+dy[i],d.second+dx[i]};\n if(mp[nextd]==0 && mapp[nextd]=='.'){//訪れていないかつ到達可能\n q.push(nextd);\n mp[nextd] = 1;//訪れたことにする。\n answer++;\n }\n }\n }\n answers.push_back(answer);\n } \n for(auto e:answers){\n cout << e << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3420, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1130_7136946", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\nusing namespace std;\n\nusing tbl = vector<vector<char>>;\n\nint solve(const tbl &t, const int h, const int w, const int sh, const int sw)\n{\n // 左,上,右,下方向の単位ベクトル\n const vector<int> dhs = {0, -1, 0, 1};\n const vector<int> dws = {1, 0, -1, 0};\n\n // visited[i][j]: タイル上の (i, j) 成分に到達可能か\n vector<vector<bool>> visited(h, vector<bool> (w, false));\n\n queue<pair<int, int>> q;\n q.push(make_pair(sh, sw));\n\n while (!q.empty())\n {\n pair<int, int> cur = q.front();\n int cur_h = cur.first;\n int cur_w = cur.second;\n visited[cur_h][cur_w] = true;\n q.pop();\n\n for (int i = 0; i < 4; ++i)\n {\n int next_h = cur_h + dhs[i];\n int next_w = cur_w + dws[i];\n // (next_h, next_w) がタイルの中なら\n if (0 <= next_h && next_h < h && 0 <= next_w && next_w < w)\n {\n // すでに訪問済みならスルー\n if (visited[next_h][next_w]) continue;\n\n // 黒いタイルならキューに追加\n if (t[next_h][next_w] == '.')\n {\n q.push(make_pair(next_h, next_w));\n }\n }\n }\n }\n \n int cnt = 0;\n for (int i = 0; i < h; ++i)\n {\n for (int j = 0; j < w; ++j)\n {\n if (visited[i][j]) ++cnt;\n }\n }\n return cnt;\n}\n\nint main() \n{\n int w, h;\n while (cin >> w >> h && w|h) \n {\n tbl t(h, vector<char> (w));\n int sh, sw; // 開始位置が何行何列か\n for (int i = 0; i < h; ++i)\n {\n for (int j = 0; j < w; ++j)\n {\n cin >> t[i][j];\n if (t[i][j] == '@')\n {\n sh = i;\n sw = j;\n }\n }\n }\n cout << solve(t, h, w, sh, sw) << '\\n';\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 6516, "score_of_the_acc": -1.5, "final_rank": 12 }, { "submission_id": "aoj_1130_6106633", "code_snippet": "/*\nhttps://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=1130&lang=jp\n\n15分ほどで実装できた。char型とstring型の使い方をごちゃまぜにしてしまい少しはまった。\nまた進むことのできる方角をdxやdyなどの配列で持っておくという発想は初めて習ったので、\n今後活用していきたい。\n */\n#include <cmath>\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <queue>\nusing namespace std;\n\nconst int dx[] = {1, 0, -1, 0};\nconst int dy[] = {0, -1, 0, 1};\n\nint solve(vector<vector<char>> state, int W, int H, int sx, int sy)\n{\n int nx, ny;\n int num_v = 0;\n vector<vector<int>> done(W, vector<int>(H, 0));\n queue<pair<int, int>> que;\n que.push(make_pair(sx, sy));\n while (!que.empty())\n {\n pair<int, int> v = que.front();\n que.pop();\n for (int i = 0; i < 4; i++)\n {\n nx = v.first + dx[i];\n ny = v.second + dy[i];\n if ((0 <= nx) && (nx < W) && (0 <= ny) && (ny < H) && (state[nx][ny] != '#'))\n que.push(make_pair(nx, ny));\n }\n done[v.first][v.second] = 1;\n state[v.first][v.second] = '#';\n }\n\n for (auto d : done)\n for (auto f : d)\n num_v += f;\n return num_v;\n}\n\nint main()\n{\n int W, H, sx, sy;\n string t;\n while (cin >> W >> H)\n {\n if (W == 0 && H == 0)\n break;\n\n vector<vector<char>> state(W, vector<char>(H));\n for (int j = 0; j < H; j++)\n {\n cin >> t;\n for (int i = 0; i < W; i++)\n {\n state[i][j] = t[i];\n if (t[i] == '@')\n {\n sx = i;\n sy = j;\n }\n }\n }\n cout << solve(state, W, H, sx, sy) << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 6332, "score_of_the_acc": -1.3453, "final_rank": 10 }, { "submission_id": "aoj_1130_6105880", "code_snippet": "#include <cmath>\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <queue>\nusing namespace std;\n\nconst int dx[] = {1, 0, -1, 0};\nconst int dy[] = {0, -1, 0, 1};\n\nint solve(vector<vector<char>> state, int W, int H, int sx, int sy)\n{\n int nx, ny;\n int num_v = 0;\n vector<vector<int>> done(W, vector<int>(H, 0));\n queue<pair<int, int>> que;\n que.push(make_pair(sx, sy));\n while (!que.empty())\n {\n pair<int, int> v = que.front();\n que.pop();\n for (int i = 0; i < 4; i++)\n {\n nx = v.first + dx[i];\n ny = v.second + dy[i];\n if ((0 <= nx) && (nx < W) && (0 <= ny) && (ny < H) && (state[nx][ny] != '#'))\n que.push(make_pair(nx, ny));\n }\n done[v.first][v.second] = 1;\n state[v.first][v.second] = '#';\n }\n\n for (auto d : done)\n for (auto f : d)\n num_v += f;\n return num_v;\n}\n\nint main()\n{\n int W, H, sx, sy;\n string t;\n while (cin >> W >> H)\n {\n if (W == 0 && H == 0)\n break;\n\n vector<vector<char>> state(W, vector<char>(H));\n for (int j = 0; j < H; j++)\n {\n cin >> t;\n for (int i = 0; i < W; i++)\n {\n state[i][j] = t[i];\n if (t[i] == '@')\n {\n sx = i;\n sy = j;\n }\n }\n }\n cout << solve(state, W, H, sx, sy) << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 6472, "score_of_the_acc": -1.3679, "final_rank": 11 }, { "submission_id": "aoj_1130_6029863", "code_snippet": "/* C++ */\n#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef long double ld;\ntypedef pair<ll, ll> pint;\nconst ll MOD = 1000000007;\nconst ll INF = 9223372036854775807/2;\n#define rep(i, n) for(ll i = (ll)0; i < (ll)(n); i++)\n#define Rep(i, s, t) for(ll i = (ll)(s); i < (ll)(t); i++)\n#define ALL(a) (a).begin(),(a).end()\n#define uniq(x) (x).erase(unique((x).begin(), (x).end()), (x).end());\n#define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n#define PI 3.14159265358979323846\n#define ifYN(x) cout << (x ? \"Yes\" : \"No\") << \"\\n\"\nll dx[8] = {-1, 1, 0, 0, -1, -1, 1, 1};\nll dy[8] = {0, 0, -1, 1, -1, 1, -1, 1};\n\ntemplate<class T> inline bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<class T> inline bool chmax(T& a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\nll Len(ll n) {\n if (n == 0) return 1;\n ll s = 0;\n while (n != 0) s++, n /= 10;\n return s;\n}\n\nll Sint(ll n) {\n ll ans = 0;\n while (n != 0) ans += n % 10, n /= 10;\n return ans;\n}\n\nll GCD(ll a, ll b) {\n return b ? GCD(b, a % b) : a;\n}\n\nll LCM(ll a, ll b){\n return a / GCD(a, b) * b;\n}\n\nll POW(ll a, ll n, ll mod = INF) {\n ll res = 1;\n while (n > 0) {\n if (n & 1) res = res * a % mod;\n a = a * a % mod;\n n >>= 1;\n }\n return res;\n}\n\nvoid dis(vector<ll> V) {\n rep(i, V.size()) cout << (i ? \" \" : \"\") << V[i];\n cout << endl;\n}\n\nvoid dis2(vector<vector<ll> > v) {\n rep (i, v.size()) {\n rep (j, v[0].size()) cout << v[i][j] << ' ';\n cout << endl;\n }\n}\n\nll VECTORSUM(vector<ll> V) {\n ll ans = 0;\n rep(i, V.size()) ans += V[i];\n return ans;\n}\n\nstring SUBSTR(string S, ll start, ll to) {\n string ans = \"\";\n Rep(i, start-1, to) ans += S[i];\n return ans;\n}\n\nll StoI(string S) {\n reverse(ALL(S));\n ll len = 1;\n ll ans = 0;\n rep(i, S.size()) {\n ans += len * (S[i]-'0');\n len *= 10;\n }\n return ans;\n}\n\n\n\nbool cmp(pint a, pint b) { return a.second < b.second; }\n\nbool solve() {\n ll W, H; cin >> W >> H;\n if(W+H == 0) return false;\n vector<vector<char>> V(H, vector<char>(W));\n vector<vector<bool>> flag(H, vector<bool>(W, false));\n rep(i, H) rep(j, W) cin >> V[i][j];\n ll sx, sy;\n rep(i, H) rep(j, W) {\n if(V[i][j] == '@') sx = j, sy = i;\n }\n queue<pint> que;\n que.push(pint(sx, sy));\n while(!que.empty()) {\n auto c = que.front();\n que.pop();\n flag[c.second][c.first] = true;\n rep(i, 4) {\n ll nx = c.first + dx[i];\n ll ny = c.second + dy[i];\n if(nx < 0 || nx >= W || ny < 0 || ny >= H) continue;\n if(V[ny][nx] == '#') continue;\n if(flag[ny][nx]) continue;\n que.push(pint(nx, ny));\n }\n }\n ll ans = 0;\n rep(i, H) rep(j, W) if(flag[i][j]) ans++;\n cout << ans << endl;\n return true;\n}\n\n/*↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓*/\nint main() {\n IOS;\n while(1) {\n if(!solve()) break;\n }\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 9612, "score_of_the_acc": -1.875, "final_rank": 13 }, { "submission_id": "aoj_1130_6000654", "code_snippet": "#include <bits/stdc++.h>\n\n#include <algorithm>\n#include <array>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\n namespace internal {\n\n// @param n `0 <= n`\n// @return minimum non-negative `x` s.t. `n <= 2**x`\n int ceil_pow2(int n) {\n int x = 0;\n while ((1U << x) < (unsigned int)(n)) x++;\n return x;\n }\n\n// @param n `1 <= n`\n// @return minimum non-negative `x` s.t. `(n & (1 << x)) != 0`\n int bsf(unsigned int n) {\n#ifdef _MSC_VER\n unsigned long index;\n _BitScanForward(&index, n);\n return index;\n#else\n return __builtin_ctz(n);\n#endif\n }\n\n } // namespace internal\n\n} // namespace atcoder\n\n\n\n#include <utility>\n\nnamespace atcoder {\n\n namespace internal {\n\n// @param m `1 <= m`\n// @return x mod m\n constexpr long long safe_mod(long long x, long long m) {\n x %= m;\n if (x < 0) x += m;\n return x;\n }\n\n// Fast modular multiplication by barrett reduction\n// Reference: https://en.wikipedia.org/wiki/Barrett_reduction\n// NOTE: reconsider after Ice Lake\n struct barrett {\n unsigned int _m;\n unsigned long long im;\n\n // @param m `1 <= m < 2^31`\n barrett(unsigned int m) : _m(m), im((unsigned long long)(-1) / m + 1) {}\n\n // @return m\n unsigned int umod() const { return _m; }\n\n // @param a `0 <= a < m`\n // @param b `0 <= b < m`\n // @return `a * b % m`\n unsigned int mul(unsigned int a, unsigned int b) const {\n // [1] m = 1\n // a = b = im = 0, so okay\n\n // [2] m >= 2\n // im = ceil(2^64 / m)\n // -> im * m = 2^64 + r (0 <= r < m)\n // let z = a*b = c*m + d (0 <= c, d < m)\n // a*b * im = (c*m + d) * im = c*(im*m) + d*im = c*2^64 + c*r + d*im\n // c*r + d*im < m * m + m * im < m * m + 2^64 + m <= 2^64 + m * (m + 1) < 2^64 * 2\n // ((ab * im) >> 64) == c or c + 1\n unsigned long long z = a;\n z *= b;\n#ifdef _MSC_VER\n unsigned long long x;\n _umul128(z, im, &x);\n#else\n unsigned long long x =\n (unsigned long long)(((unsigned __int128)(z)*im) >> 64);\n#endif\n unsigned int v = (unsigned int)(z - x * _m);\n if (_m <= v) v += _m;\n return v;\n }\n };\n\n// @param n `0 <= n`\n// @param m `1 <= m`\n// @return `(x ** n) % m`\n constexpr long long pow_mod_constexpr(long long x, long long n, int m) {\n if (m == 1) return 0;\n unsigned int _m = (unsigned int)(m);\n unsigned long long r = 1;\n unsigned long long y = safe_mod(x, m);\n while (n) {\n if (n & 1) r = (r * y) % _m;\n y = (y * y) % _m;\n n >>= 1;\n }\n return r;\n }\n\n// Reference:\n// M. Forisek and J. Jancina,\n// Fast Primality Testing for Integers That Fit into a Machine Word\n// @param n `0 <= n`\n constexpr bool is_prime_constexpr(int n) {\n if (n <= 1) return false;\n if (n == 2 || n == 7 || n == 61) return true;\n if (n % 2 == 0) return false;\n long long d = n - 1;\n while (d % 2 == 0) d /= 2;\n constexpr long long bases[3] = {2, 7, 61};\n for (long long a : bases) {\n long long t = d;\n long long y = pow_mod_constexpr(a, t, n);\n while (t != n - 1 && y != 1 && y != n - 1) {\n y = y * y % n;\n t <<= 1;\n }\n if (y != n - 1 && t % 2 == 0) {\n return false;\n }\n }\n return true;\n }\n template <int n> constexpr bool is_prime = is_prime_constexpr(n);\n\n// @param b `1 <= b`\n// @return pair(g, x) s.t. g = gcd(a, b), xa = g (mod b), 0 <= x < b/g\n constexpr std::pair<long long, long long> inv_gcd(long long a, long long b) {\n a = safe_mod(a, b);\n if (a == 0) return {b, 0};\n\n // Contracts:\n // [1] s - m0 * a = 0 (mod b)\n // [2] t - m1 * a = 0 (mod b)\n // [3] s * |m1| + t * |m0| <= b\n long long s = b, t = a;\n long long m0 = 0, m1 = 1;\n\n while (t) {\n long long u = s / t;\n s -= t * u;\n m0 -= m1 * u; // |m1 * u| <= |m1| * s <= b\n\n // [3]:\n // (s - t * u) * |m1| + t * |m0 - m1 * u|\n // <= s * |m1| - t * u * |m1| + t * (|m0| + |m1| * u)\n // = s * |m1| + t * |m0| <= b\n\n auto tmp = s;\n s = t;\n t = tmp;\n tmp = m0;\n m0 = m1;\n m1 = tmp;\n }\n // by [3]: |m0| <= b/g\n // by g != b: |m0| < b/g\n if (m0 < 0) m0 += b / s;\n return {s, m0};\n }\n\n// Compile time primitive root\n// @param m must be prime\n// @return primitive root (and minimum in now)\n constexpr int primitive_root_constexpr(int m) {\n if (m == 2) return 1;\n if (m == 167772161) return 3;\n if (m == 469762049) return 3;\n if (m == 754974721) return 11;\n if (m == 998244353) return 3;\n int divs[20] = {};\n divs[0] = 2;\n int cnt = 1;\n int x = (m - 1) / 2;\n while (x % 2 == 0) x /= 2;\n for (int i = 3; (long long)(i)*i <= x; i += 2) {\n if (x % i == 0) {\n divs[cnt++] = i;\n while (x % i == 0) {\n x /= i;\n }\n }\n }\n if (x > 1) {\n divs[cnt++] = x;\n }\n for (int g = 2;; g++) {\n bool ok = true;\n for (int i = 0; i < cnt; i++) {\n if (pow_mod_constexpr(g, (m - 1) / divs[i], m) == 1) {\n ok = false;\n break;\n }\n }\n if (ok) return g;\n }\n }\n template <int m> constexpr int primitive_root = primitive_root_constexpr(m);\n\n } // namespace internal\n\n} // namespace atcoder\n\n\n#include <algorithm>\n\n#include <vector>\n\nnamespace atcoder {\n\n namespace internal {\n\n template <class T> struct simple_queue {\n std::vector<T> payload;\n int pos = 0;\n void reserve(int n) { payload.reserve(n); }\n int size() const { return int(payload.size()) - pos; }\n bool empty() const { return pos == int(payload.size()); }\n void push(const T& t) { payload.push_back(t); }\n T& front() { return payload[pos]; }\n void clear() {\n payload.clear();\n pos = 0;\n }\n void pop() { pos++; }\n };\n\n } // namespace internal\n\n} // namespace atcoder\n\n#include <cassert>\n#include <limits>\n#include <queue>\n#include <vector>\n\nnamespace atcoder {\n\n template <class Cap> struct mf_graph {\n public:\n mf_graph() : _n(0) {}\n mf_graph(int n) : _n(n), g(n) {}\n\n int add_edge(int from, int to, Cap cap) {\n assert(0 <= from && from < _n);\n assert(0 <= to && to < _n);\n assert(0 <= cap);\n int m = int(pos.size());\n pos.push_back({from, int(g[from].size())});\n int from_id = int(g[from].size());\n int to_id = int(g[to].size());\n if (from == to) to_id++;\n g[from].push_back(_edge{to, to_id, cap});\n g[to].push_back(_edge{from, from_id, 0});\n return m;\n }\n\n struct edge {\n int from, to;\n Cap cap, flow;\n };\n\n edge get_edge(int i) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n auto _e = g[pos[i].first][pos[i].second];\n auto _re = g[_e.to][_e.rev];\n return edge{pos[i].first, _e.to, _e.cap + _re.cap, _re.cap};\n }\n std::vector<edge> edges() {\n int m = int(pos.size());\n std::vector<edge> result;\n for (int i = 0; i < m; i++) {\n result.push_back(get_edge(i));\n }\n return result;\n }\n void change_edge(int i, Cap new_cap, Cap new_flow) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n assert(0 <= new_flow && new_flow <= new_cap);\n auto& _e = g[pos[i].first][pos[i].second];\n auto& _re = g[_e.to][_e.rev];\n _e.cap = new_cap - new_flow;\n _re.cap = new_flow;\n }\n\n Cap flow(int s, int t) {\n return flow(s, t, std::numeric_limits<Cap>::max());\n }\n Cap flow(int s, int t, Cap flow_limit) {\n assert(0 <= s && s < _n);\n assert(0 <= t && t < _n);\n assert(s != t);\n\n std::vector<int> level(_n), iter(_n);\n internal::simple_queue<int> que;\n\n auto bfs = [&]() {\n std::fill(level.begin(), level.end(), -1);\n level[s] = 0;\n que.clear();\n que.push(s);\n while (!que.empty()) {\n int v = que.front();\n que.pop();\n for (auto e : g[v]) {\n if (e.cap == 0 || level[e.to] >= 0) continue;\n level[e.to] = level[v] + 1;\n if (e.to == t) return;\n que.push(e.to);\n }\n }\n };\n auto dfs = [&](auto self, int v, Cap up) {\n if (v == s) return up;\n Cap res = 0;\n int level_v = level[v];\n for (int& i = iter[v]; i < int(g[v].size()); i++) {\n _edge& e = g[v][i];\n if (level_v <= level[e.to] || g[e.to][e.rev].cap == 0) continue;\n Cap d =\n self(self, e.to, std::min(up - res, g[e.to][e.rev].cap));\n if (d <= 0) continue;\n g[v][i].cap += d;\n g[e.to][e.rev].cap -= d;\n res += d;\n if (res == up) break;\n }\n return res;\n };\n\n Cap flow = 0;\n while (flow < flow_limit) {\n bfs();\n if (level[t] == -1) break;\n std::fill(iter.begin(), iter.end(), 0);\n while (flow < flow_limit) {\n Cap f = dfs(dfs, t, flow_limit - flow);\n if (!f) break;\n flow += f;\n }\n }\n return flow;\n }\n\n std::vector<bool> min_cut(int s) {\n std::vector<bool> visited(_n);\n internal::simple_queue<int> que;\n que.push(s);\n while (!que.empty()) {\n int p = que.front();\n que.pop();\n visited[p] = true;\n for (auto e : g[p]) {\n if (e.cap && !visited[e.to]) {\n visited[e.to] = true;\n que.push(e.to);\n }\n }\n }\n return visited;\n }\n\n private:\n int _n;\n struct _edge {\n int to, rev;\n Cap cap;\n };\n std::vector<std::pair<int, int>> pos;\n std::vector<std::vector<_edge>> g;\n };\n\n} // namespace atcoder\n\n\n\n#include <cassert>\n#include <vector>\n\n\n#include <algorithm>\n#include <cassert>\n#include <vector>\n\n\nusing namespace std;\nusing namespace atcoder;\n#define ll long long\n#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)\n#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)\n#define REP(i, n) FOR(i,0,n)\n#define IREP(i, n) IFOR(i,0,n)\n\nvoid solve(){\n int h, w;\n vector<vector<char>> maze;\n vector<int> dh = {-1, 0, 0, 1};\n vector<int> dw = {0, -1, 1, 0};\n int curh, curw;\n char c;\n while(true){\n cin >> w >> h;\n if(h==0 && w==0) break;\n maze = vector<vector<char>>(h + 2, vector<char>(w + 2, '#'));\n REP(i, w) maze[0][i] = '#';\n FOR(hh, 1, h + 1){\n FOR(ww, 1, w + 1){\n cin >> c;\n if(c == '@'){\n curh = hh;\n curw = ww;\n c = '.';\n }\n maze[hh][ww] = c;\n }\n }\n REP(i, w) maze[h+1][i] = '#';\n int nodenum = (w+2) * (h+2) + 2;\n int nodes = nodenum - 2;\n int nodet = nodenum - 1;\n auto hw2num = [&](int hh, int ww){ return hh * (w+2) + ww; };\n mf_graph<int> mf(nodenum);\n REP(hh, h+2){\n REP(ww, w+2){\n if(maze[hh][ww] == '#') continue;\n mf.add_edge(hw2num(hh, ww), nodet, 1);\n REP(di, dh.size()){\n mf.add_edge(hw2num(hh, ww), hw2num(hh+dh[di], ww+dw[di]), h*w);\n }\n }\n mf.add_edge(nodes, hw2num(curh, curw), h*w);\n }\n cout << mf.flow(nodes, nodet) << \"\\n\";\n }\n\n}\n\nint main(int argc, char *argv[]) {\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3512, "score_of_the_acc": -0.1399, "final_rank": 6 }, { "submission_id": "aoj_1130_6000639", "code_snippet": "#include <bits/stdc++.h>\n\n#include <algorithm>\n#include <array>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\n namespace internal {\n\n// @param n `0 <= n`\n// @return minimum non-negative `x` s.t. `n <= 2**x`\n int ceil_pow2(int n) {\n int x = 0;\n while ((1U << x) < (unsigned int)(n)) x++;\n return x;\n }\n\n// @param n `1 <= n`\n// @return minimum non-negative `x` s.t. `(n & (1 << x)) != 0`\n int bsf(unsigned int n) {\n#ifdef _MSC_VER\n unsigned long index;\n _BitScanForward(&index, n);\n return index;\n#else\n return __builtin_ctz(n);\n#endif\n }\n\n } // namespace internal\n\n} // namespace atcoder\n\n\n\n#include <utility>\n\nnamespace atcoder {\n\n namespace internal {\n\n// @param m `1 <= m`\n// @return x mod m\n constexpr long long safe_mod(long long x, long long m) {\n x %= m;\n if (x < 0) x += m;\n return x;\n }\n\n// Fast modular multiplication by barrett reduction\n// Reference: https://en.wikipedia.org/wiki/Barrett_reduction\n// NOTE: reconsider after Ice Lake\n struct barrett {\n unsigned int _m;\n unsigned long long im;\n\n // @param m `1 <= m < 2^31`\n barrett(unsigned int m) : _m(m), im((unsigned long long)(-1) / m + 1) {}\n\n // @return m\n unsigned int umod() const { return _m; }\n\n // @param a `0 <= a < m`\n // @param b `0 <= b < m`\n // @return `a * b % m`\n unsigned int mul(unsigned int a, unsigned int b) const {\n // [1] m = 1\n // a = b = im = 0, so okay\n\n // [2] m >= 2\n // im = ceil(2^64 / m)\n // -> im * m = 2^64 + r (0 <= r < m)\n // let z = a*b = c*m + d (0 <= c, d < m)\n // a*b * im = (c*m + d) * im = c*(im*m) + d*im = c*2^64 + c*r + d*im\n // c*r + d*im < m * m + m * im < m * m + 2^64 + m <= 2^64 + m * (m + 1) < 2^64 * 2\n // ((ab * im) >> 64) == c or c + 1\n unsigned long long z = a;\n z *= b;\n#ifdef _MSC_VER\n unsigned long long x;\n _umul128(z, im, &x);\n#else\n unsigned long long x =\n (unsigned long long)(((unsigned __int128)(z)*im) >> 64);\n#endif\n unsigned int v = (unsigned int)(z - x * _m);\n if (_m <= v) v += _m;\n return v;\n }\n };\n\n// @param n `0 <= n`\n// @param m `1 <= m`\n// @return `(x ** n) % m`\n constexpr long long pow_mod_constexpr(long long x, long long n, int m) {\n if (m == 1) return 0;\n unsigned int _m = (unsigned int)(m);\n unsigned long long r = 1;\n unsigned long long y = safe_mod(x, m);\n while (n) {\n if (n & 1) r = (r * y) % _m;\n y = (y * y) % _m;\n n >>= 1;\n }\n return r;\n }\n\n// Reference:\n// M. Forisek and J. Jancina,\n// Fast Primality Testing for Integers That Fit into a Machine Word\n// @param n `0 <= n`\n constexpr bool is_prime_constexpr(int n) {\n if (n <= 1) return false;\n if (n == 2 || n == 7 || n == 61) return true;\n if (n % 2 == 0) return false;\n long long d = n - 1;\n while (d % 2 == 0) d /= 2;\n constexpr long long bases[3] = {2, 7, 61};\n for (long long a : bases) {\n long long t = d;\n long long y = pow_mod_constexpr(a, t, n);\n while (t != n - 1 && y != 1 && y != n - 1) {\n y = y * y % n;\n t <<= 1;\n }\n if (y != n - 1 && t % 2 == 0) {\n return false;\n }\n }\n return true;\n }\n template <int n> constexpr bool is_prime = is_prime_constexpr(n);\n\n// @param b `1 <= b`\n// @return pair(g, x) s.t. g = gcd(a, b), xa = g (mod b), 0 <= x < b/g\n constexpr std::pair<long long, long long> inv_gcd(long long a, long long b) {\n a = safe_mod(a, b);\n if (a == 0) return {b, 0};\n\n // Contracts:\n // [1] s - m0 * a = 0 (mod b)\n // [2] t - m1 * a = 0 (mod b)\n // [3] s * |m1| + t * |m0| <= b\n long long s = b, t = a;\n long long m0 = 0, m1 = 1;\n\n while (t) {\n long long u = s / t;\n s -= t * u;\n m0 -= m1 * u; // |m1 * u| <= |m1| * s <= b\n\n // [3]:\n // (s - t * u) * |m1| + t * |m0 - m1 * u|\n // <= s * |m1| - t * u * |m1| + t * (|m0| + |m1| * u)\n // = s * |m1| + t * |m0| <= b\n\n auto tmp = s;\n s = t;\n t = tmp;\n tmp = m0;\n m0 = m1;\n m1 = tmp;\n }\n // by [3]: |m0| <= b/g\n // by g != b: |m0| < b/g\n if (m0 < 0) m0 += b / s;\n return {s, m0};\n }\n\n// Compile time primitive root\n// @param m must be prime\n// @return primitive root (and minimum in now)\n constexpr int primitive_root_constexpr(int m) {\n if (m == 2) return 1;\n if (m == 167772161) return 3;\n if (m == 469762049) return 3;\n if (m == 754974721) return 11;\n if (m == 998244353) return 3;\n int divs[20] = {};\n divs[0] = 2;\n int cnt = 1;\n int x = (m - 1) / 2;\n while (x % 2 == 0) x /= 2;\n for (int i = 3; (long long)(i)*i <= x; i += 2) {\n if (x % i == 0) {\n divs[cnt++] = i;\n while (x % i == 0) {\n x /= i;\n }\n }\n }\n if (x > 1) {\n divs[cnt++] = x;\n }\n for (int g = 2;; g++) {\n bool ok = true;\n for (int i = 0; i < cnt; i++) {\n if (pow_mod_constexpr(g, (m - 1) / divs[i], m) == 1) {\n ok = false;\n break;\n }\n }\n if (ok) return g;\n }\n }\n template <int m> constexpr int primitive_root = primitive_root_constexpr(m);\n\n } // namespace internal\n\n} // namespace atcoder\n\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\nnamespace atcoder {\n\n namespace internal {\n\n#ifndef _MSC_VER\n template <class T>\n using is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value ||\n std::is_same<T, __int128>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value,\n __uint128_t,\n unsigned __int128>;\n\n template <class T>\n using is_integral = typename std::conditional<std::is_integral<T>::value ||\n is_signed_int128<T>::value ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using is_signed_int = typename std::conditional<(is_integral<T>::value &&\n std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using is_unsigned_int =\n typename std::conditional<(is_integral<T>::value &&\n std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using to_unsigned = typename std::conditional<\n is_signed_int128<T>::value,\n make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\n#else\n\n template <class T> using is_integral = typename std::is_integral<T>;\n\ntemplate <class T>\nusing is_signed_int =\n typename std::conditional<is_integral<T>::value && std::is_signed<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<is_integral<T>::value &&\n std::is_unsigned<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<is_signed_int<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type;\n\n#endif\n\n template <class T>\n using is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\n template <class T>\n using is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\n template <class T> using to_unsigned_t = typename to_unsigned<T>::type;\n\n } // namespace internal\n\n} // namespace atcoder\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\n\n\n#include <algorithm>\n#include <cassert>\n#include <tuple>\n#include <vector>\n\nnamespace atcoder {\n\n long long pow_mod(long long x, long long n, int m) {\n assert(0 <= n && 1 <= m);\n if (m == 1) return 0;\n internal::barrett bt((unsigned int)(m));\n unsigned int r = 1, y = (unsigned int)(internal::safe_mod(x, m));\n while (n) {\n if (n & 1) r = bt.mul(r, y);\n y = bt.mul(y, y);\n n >>= 1;\n }\n return r;\n }\n\n long long inv_mod(long long x, long long m) {\n assert(1 <= m);\n auto z = internal::inv_gcd(x, m);\n assert(z.first == 1);\n return z.second;\n }\n\n// (rem, mod)\n std::pair<long long, long long> crt(const std::vector<long long>& r,\n const std::vector<long long>& m) {\n assert(r.size() == m.size());\n int n = int(r.size());\n // Contracts: 0 <= r0 < m0\n long long r0 = 0, m0 = 1;\n for (int i = 0; i < n; i++) {\n assert(1 <= m[i]);\n long long r1 = internal::safe_mod(r[i], m[i]), m1 = m[i];\n if (m0 < m1) {\n std::swap(r0, r1);\n std::swap(m0, m1);\n }\n if (m0 % m1 == 0) {\n if (r0 % m1 != r1) return {0, 0};\n continue;\n }\n // assume: m0 > m1, lcm(m0, m1) >= 2 * max(m0, m1)\n\n // (r0, m0), (r1, m1) -> (r2, m2 = lcm(m0, m1));\n // r2 % m0 = r0\n // r2 % m1 = r1\n // -> (r0 + x*m0) % m1 = r1\n // -> x*u0*g % (u1*g) = (r1 - r0) (u0*g = m0, u1*g = m1)\n // -> x = (r1 - r0) / g * inv(u0) (mod u1)\n\n // im = inv(u0) (mod u1) (0 <= im < u1)\n long long g, im;\n std::tie(g, im) = internal::inv_gcd(m0, m1);\n\n long long u1 = (m1 / g);\n // |r1 - r0| < (m0 + m1) <= lcm(m0, m1)\n if ((r1 - r0) % g) return {0, 0};\n\n // u1 * u1 <= m1 * m1 / g / g <= m0 * m1 / g = lcm(m0, m1)\n long long x = (r1 - r0) / g % u1 * im % u1;\n\n // |r0| + |m0 * x|\n // < m0 + m0 * (u1 - 1)\n // = m0 + m0 * m1 / g - m0\n // = lcm(m0, m1)\n r0 += x * m0;\n m0 *= u1; // -> lcm(m0, m1)\n if (r0 < 0) r0 += m0;\n }\n return {r0, m0};\n }\n\n long long floor_sum(long long n, long long m, long long a, long long b) {\n long long ans = 0;\n if (a >= m) {\n ans += (n - 1) * n * (a / m) / 2;\n a %= m;\n }\n if (b >= m) {\n ans += n * (b / m);\n b %= m;\n }\n\n long long y_max = (a * n + b) / m, x_max = (y_max * m - b);\n if (y_max == 0) return ans;\n ans += (n - (x_max + a - 1) / a) * y_max;\n ans += floor_sum(y_max, a, m, (a - x_max % a) % a);\n return ans;\n }\n\n} // namespace atcoder\n\n\n#include <algorithm>\n\n#include <vector>\n\nnamespace atcoder {\n\n namespace internal {\n\n template <class T> struct simple_queue {\n std::vector<T> payload;\n int pos = 0;\n void reserve(int n) { payload.reserve(n); }\n int size() const { return int(payload.size()) - pos; }\n bool empty() const { return pos == int(payload.size()); }\n void push(const T& t) { payload.push_back(t); }\n T& front() { return payload[pos]; }\n void clear() {\n payload.clear();\n pos = 0;\n }\n void pop() { pos++; }\n };\n\n } // namespace internal\n\n} // namespace atcoder\n\n#include <cassert>\n#include <limits>\n#include <queue>\n#include <vector>\n\nnamespace atcoder {\n\n template <class Cap> struct mf_graph {\n public:\n mf_graph() : _n(0) {}\n mf_graph(int n) : _n(n), g(n) {}\n\n int add_edge(int from, int to, Cap cap) {\n assert(0 <= from && from < _n);\n assert(0 <= to && to < _n);\n assert(0 <= cap);\n int m = int(pos.size());\n pos.push_back({from, int(g[from].size())});\n int from_id = int(g[from].size());\n int to_id = int(g[to].size());\n if (from == to) to_id++;\n g[from].push_back(_edge{to, to_id, cap});\n g[to].push_back(_edge{from, from_id, 0});\n return m;\n }\n\n struct edge {\n int from, to;\n Cap cap, flow;\n };\n\n edge get_edge(int i) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n auto _e = g[pos[i].first][pos[i].second];\n auto _re = g[_e.to][_e.rev];\n return edge{pos[i].first, _e.to, _e.cap + _re.cap, _re.cap};\n }\n std::vector<edge> edges() {\n int m = int(pos.size());\n std::vector<edge> result;\n for (int i = 0; i < m; i++) {\n result.push_back(get_edge(i));\n }\n return result;\n }\n void change_edge(int i, Cap new_cap, Cap new_flow) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n assert(0 <= new_flow && new_flow <= new_cap);\n auto& _e = g[pos[i].first][pos[i].second];\n auto& _re = g[_e.to][_e.rev];\n _e.cap = new_cap - new_flow;\n _re.cap = new_flow;\n }\n\n Cap flow(int s, int t) {\n return flow(s, t, std::numeric_limits<Cap>::max());\n }\n Cap flow(int s, int t, Cap flow_limit) {\n assert(0 <= s && s < _n);\n assert(0 <= t && t < _n);\n assert(s != t);\n\n std::vector<int> level(_n), iter(_n);\n internal::simple_queue<int> que;\n\n auto bfs = [&]() {\n std::fill(level.begin(), level.end(), -1);\n level[s] = 0;\n que.clear();\n que.push(s);\n while (!que.empty()) {\n int v = que.front();\n que.pop();\n for (auto e : g[v]) {\n if (e.cap == 0 || level[e.to] >= 0) continue;\n level[e.to] = level[v] + 1;\n if (e.to == t) return;\n que.push(e.to);\n }\n }\n };\n auto dfs = [&](auto self, int v, Cap up) {\n if (v == s) return up;\n Cap res = 0;\n int level_v = level[v];\n for (int& i = iter[v]; i < int(g[v].size()); i++) {\n _edge& e = g[v][i];\n if (level_v <= level[e.to] || g[e.to][e.rev].cap == 0) continue;\n Cap d =\n self(self, e.to, std::min(up - res, g[e.to][e.rev].cap));\n if (d <= 0) continue;\n g[v][i].cap += d;\n g[e.to][e.rev].cap -= d;\n res += d;\n if (res == up) break;\n }\n return res;\n };\n\n Cap flow = 0;\n while (flow < flow_limit) {\n bfs();\n if (level[t] == -1) break;\n std::fill(iter.begin(), iter.end(), 0);\n while (flow < flow_limit) {\n Cap f = dfs(dfs, t, flow_limit - flow);\n if (!f) break;\n flow += f;\n }\n }\n return flow;\n }\n\n std::vector<bool> min_cut(int s) {\n std::vector<bool> visited(_n);\n internal::simple_queue<int> que;\n que.push(s);\n while (!que.empty()) {\n int p = que.front();\n que.pop();\n visited[p] = true;\n for (auto e : g[p]) {\n if (e.cap && !visited[e.to]) {\n visited[e.to] = true;\n que.push(e.to);\n }\n }\n }\n return visited;\n }\n\n private:\n int _n;\n struct _edge {\n int to, rev;\n Cap cap;\n };\n std::vector<std::pair<int, int>> pos;\n std::vector<std::vector<_edge>> g;\n };\n\n} // namespace atcoder\n\n\n\n#include <cassert>\n#include <vector>\n\n\n#include <algorithm>\n#include <cassert>\n#include <vector>\n\n\nusing namespace std;\nusing namespace atcoder;\n#define ll long long\n#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)\n#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)\n#define REP(i, n) FOR(i,0,n)\n#define IREP(i, n) IFOR(i,0,n)\n\nvoid solve(){\n int h, w;\n vector<vector<char>> maze;\n vector<int> dh = {-1, 0, 0, 1};\n vector<int> dw = {0, -1, 1, 0};\n int curh, curw;\n char c;\n while(true){\n cin >> w >> h;\n if(h==0 && w==0) break;\n maze = vector<vector<char>>(h + 2, vector<char>(w + 2, '#'));\n REP(i, w) maze[0][i] = '#';\n FOR(hh, 1, h + 1){\n FOR(ww, 1, w + 1){\n cin >> c;\n if(c == '@'){\n curh = hh;\n curw = ww;\n c = '.';\n }\n maze[hh][ww] = c;\n }\n }\n REP(i, w) maze[h+1][i] = '#';\n int nodenum = (w+2) * (h+2) + 2;\n int nodes = nodenum - 2;\n int nodet = nodenum - 1;\n auto hw2num = [&](int hh, int ww){ return hh * (w+2) + ww; };\n mf_graph<int> mf(nodenum);\n REP(hh, h+2){\n REP(ww, w+2){\n if(maze[hh][ww] == '#') continue;\n mf.add_edge(hw2num(hh, ww), nodet, 1);\n REP(di, dh.size()){\n mf.add_edge(hw2num(hh, ww), hw2num(hh+dh[di], ww+dw[di]), h*w);\n }\n }\n mf.add_edge(nodes, hw2num(curh, curw), h*w);\n }\n cout << mf.flow(nodes, nodet) << \"\\n\";\n }\n\n}\n\nint main(int argc, char *argv[]) {\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3532, "score_of_the_acc": -0.0181, "final_rank": 3 } ]
aoj_1136_cpp
Problem B: Polygonal Line Search Multiple polygonal lines are given on the xy -plane. Given a list of polygonal lines and a template, you must find out polygonal lines which have the same shape as the template. A polygonal line consists of several line segments parallel to x -axis or y -axis. It is defined by a list of xy -coordinates of vertices from the start-point to the end-point in order, and always turns 90 degrees at each vertex. A single polygonal line does not pass the same point twice. Two polygonal lines have the same shape when they fully overlap each other only with rotation and translation within xy -plane (i.e. without magnification or a flip). The vertices given in reverse order from the start-point to the end-point is the same as that given in order. Figure 1 shows examples of polygonal lines. In this figure, polygonal lines A and B have the same shape. Write a program that answers polygonal lines which have the same shape as the template. Figure 1: Polygonal lines Input The input consists of multiple datasets. The end of the input is indicated by a line which contains a zero. A dataset is given as follows. n Polygonal line 0 Polygonal line 1 Polygonal line 2 ... Polygonal line n n is the number of polygonal lines for the object of search on xy -plane. n is an integer, and 1 <= n <= 50. Polygonal line 0 indicates the template. A polygonal line is given as follows. m x 1 y 1 x 2 y 2 ... x m y m m is the number of the vertices of a polygonal line (3 <= m <= 10). x i and y i , separated by a space, are the x - and y -coordinates of a vertex, respectively (-10000 < x i < 10000, -10000 < y i < 10000). Output For each dataset in the input, your program should report numbers assigned to the polygonal lines that have the same shape as the template, in ascending order. Each number must be written in a separate line without any other characters such as leading or trailing spaces. Five continuous "+"s must be placed in a line at the end of each dataset. Sample Input 5 5 0 0 2 0 2 1 4 1 4 0 5 0 0 0 2 -1 2 -1 4 0 4 5 0 0 0 1 -2 1 -2 2 0 2 5 0 0 0 -1 2 -1 2 0 4 0 5 0 0 2 0 2 -1 4 -1 4 0 5 0 0 2 0 2 1 4 1 4 0 4 4 -60 -75 -60 -78 -42 -78 -42 -6 4 10 3 10 7 -4 7 -4 40 4 -74 66 -74 63 -92 63 -92 135 4 -12 22 -12 25 -30 25 -30 -47 4 12 -22 12 -25 30 -25 30 47 3 5 -8 5 -8 2 0 2 0 4 8 4 5 -3 -1 0 -1 0 7 -2 7 -2 16 5 -1 6 -1 3 7 3 7 5 16 5 5 0 1 0 -2 8 -2 8 0 17 0 0 Output for the Sample Input 1 3 5 +++++ 3 4 +++++ +++++
[ { "submission_id": "aoj_1136_2163060", "code_snippet": "#include <iostream>\n#include <string>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <list>\n#include <vector>\n#include <complex>\n#include <utility>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <climits>\n#include <bitset>\n#include <ctime>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <unordered_set>\n#include <cassert>\n#include <cstddef>\n#include <iomanip>\n#include <numeric>\n#include <tuple>\n#include <sstream>\n#include <fstream>\n\nusing namespace std;\n#define REP(i, n) for (int (i) = 0; (i) < (n); (i)++)\n#define FOR(i, a, b) for (int (i) = (a); (i) < (b); (i)++)\n#define RREP(i, a) for(int (i) = (a) - 1; (i) >= 0; (i)--)\n#define FORR(i, a, b) for(int (i) = (a) - 1; (i) >= (b); (i)--)\n#define DEBUG(C) cerr << #C << \" = \" << C << endl;\nusing LL = long long;\nusing VI = vector<int>;\nusing VVI = vector<VI>;\nusing VL = vector<LL>;\nusing VVL = vector<VL>;\nusing VD = vector<double>;\nusing VVD = vector<VD>;\nusing PII = pair<int, int>;\nusing PDD = pair<double, double>;\nusing PLL = pair<LL, LL>;\nusing VPII = vector<PII>;\ntemplate<typename T> using VT = vector<T>;\n#define ALL(a) begin((a)), end((a))\n#define RALL(a) rbegin((a)), rend((a))\n#define SORT(a) sort(ALL((a)))\n#define RSORT(a) sort(RALL((a)))\n#define REVERSE(a) reverse(ALL((a)))\n#define MP make_pair\n#define FORE(a, b) for (auto &&a : (b))\n#define FIND(s, e) ((s).find(e) != (s).end())\n#define EB emplace_back\ntemplate<typename T>inline bool chmax(T &a,T b){if(a<b){a=b;return true;}return false;}\ntemplate<typename T>inline bool chmin(T &a,T b){if(a>b){a=b;return true;}return false;}\n\nconst int INF = 1e9;\nconst int MOD = INF + 7;\nconst LL LLINF = 1e18;\n\nvoid init() {\n\n}\n\nusing matrix = vector<vector<int>>;\nmatrix makeRotationMatrix(double theta) {\n matrix res(3, vector<int>(3, 0));\n for (int i = 0; i < 2; i++) {\n for (int j = 0; j < 2; j++) {\n res[i][j] = (i == j ? cos(theta) : i ? sin(theta) : -sin(theta));\n }\n }\n res[2][2] = 1;\n return res;\n}\n\nmatrix mul(matrix A, matrix B) {\n matrix res(A.size(), vector<int>(B.front().size(), 0));\n for (int i = 0; i < A.size(); i++) {\n for (int k = 0; k < B.size(); k++) {\n for (int j = 0; j < B.front().size(); j++) {\n res[i][j] += A[i][k] * B[k][j];\n }\n }\n }\n return res;\n}\n\nvoid solve(int n) {\n int m;\n scanf(\"%d\", &m);\n vector<vector<pair<int, int>>> keyvec(2, vector<pair<int, int>>(m));\n for (int i = 0; i < m; i++) {\n int x, y;\n scanf(\"%d%d\", &x, &y);\n keyvec[0][i] = make_pair(x, y);\n keyvec[1][i] = make_pair(x, y);\n }\n reverse(begin(keyvec[1]), end(keyvec[1]));\n for (int c = 0; c < 2; c++) {\n int X, Y;\n tie(X, Y) = keyvec[c][0];\n for (int i = 1; i < m; i++) {\n int x, y;\n tie(x, y) = keyvec[c][i];\n keyvec[c][i] = make_pair(x - X, y - Y);\n }\n keyvec[c][0] = make_pair(0, 0);\n }\n\n vector<vector<pair<int, int>>> vec(n);\n for (int i = 0; i < n; i++) {\n scanf(\"%d\", &m);\n vec[i].resize(m);\n for (int j = 0; j < m; j++) {\n int x, y;\n scanf(\"%d%d\", &x, &y);\n if (j == 0) vec[i][j] = make_pair(x, y);\n else vec[i][j] = make_pair(x - vec[i][0].first, y - vec[i][0].second);\n }\n vec[i][0] = make_pair(0, 0);\n }\n\n const long double PI = acos(-1.0);\n const long double theta[] = {0, PI / 2, PI, PI * 1.5};\n set<int> ans;\n for (int c = 0; c < 2; c++) {\n for (int i = 0; i < n; i++) {\n for (auto e : theta) {\n auto cpvec = vec[i];\n auto rotmat = makeRotationMatrix(e);\n for (int j = 0; j < (int)cpvec.size(); j++) {\n matrix mat(3);\n mat[0].emplace_back(cpvec[j].first);\n mat[1].emplace_back(cpvec[j].second);\n mat[2].emplace_back(1);\n mat = mul(rotmat, mat);\n cpvec[j] = make_pair(mat[0][0], mat[1][0]);\n }\n if (cpvec == keyvec[c]) {\n ans.insert(i);\n }\n }\n }\n }\n\n for (int e : ans) {\n printf(\"%d\\n\", e + 1);\n }\n puts(\"+++++\");\n}\n\nint main(void) {\n\tint a, b, c, x, y, z, n, m, p;\n\tstring s;\n\twhile (cin >> n, n) {\n\t\tsolve(n);\n\t\t//break;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3500, "score_of_the_acc": -0.1544, "final_rank": 2 }, { "submission_id": "aoj_1136_1670297", "code_snippet": "#include<iostream>\n#include<cstring>\nusing namespace std;\n\n#define MAX_N 1355\n\nint x[MAX_N][4], y[MAX_N][4];\nint X[MAX_N][MAX_N], Y[MAX_N][MAX_N];\nint n, m, M ,cnt;\n\nint main() {\n\twhile (true) {\n\t\tif (cnt >= 1) { cout << \"+++++\" << endl; }\n\t\tcnt++;\n\t\tmemset(x, 0, sizeof(x));\n\t\tmemset(y, 0, sizeof(y));\n\t\tmemset(X, 0, sizeof(X));\n\t\tmemset(Y, 0, sizeof(Y));\n\t\tcin >> n;\n\t\tif (n == 0) { break; }\n\t\tcin >> M;\n\t\tfor (int i = 0; i < M; i++) {\n\t\t\tcin >> x[i][0] >> y[i][0];\n\t\t}\n\t\tfor (int i = 0; i < 3; i++) {\n\t\t\tfor (int j = 0; j < M; j++) {\n\t\t\t\tx[j][i + 1] = -y[j][i];\n\t\t\t\ty[j][i + 1] = x[j][i];\n\t\t\t}\n\t\t}\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tcin >> m;\n\t\t\tfor (int j = 0; j < m; j++) {\n\t\t\t\tcin >> X[i][j] >> Y[i][j];\n\t\t\t}\n\t\t\tint same = 8;\n\t\t\tif (M != m) { same = 0; }\n\t\t\telse {\n\t\t\t\tfor (int j = 0; j < 4; j++) {\n\t\t\t\t\tint X1 = x[0][j] - X[i][0], Y1 = y[0][j] - Y[i][0];\n\t\t\t\t\tfor (int k = 1; k < M; k++) {\n\t\t\t\t\t\tif ((x[k][j] - X[i][k] != X1 || y[k][j] - Y[i][k] != Y1) && same == 8 - j) {\n\t\t\t\t\t\t\tsame--;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tfor (int j = 0; j < 4; j++) {\n\t\t\t\t\tint X1 = x[0][j] - X[i][M - 1], Y1 = y[0][j] - Y[i][M - 1];\n\t\t\t\t\tfor (int k = 1; k < M; k++) {\n\t\t\t\t\t\tif ((x[k][j] - X[i][M - 1 - k] != X1 || y[k][j] - Y[i][M - 1 - k] != Y1) && same == 4 - j) {\n\t\t\t\t\t\t\tsame--;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (same >= 1) { cout << i << endl; }\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 15552, "score_of_the_acc": -2, "final_rank": 3 }, { "submission_id": "aoj_1136_1656306", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> pii;\n#define rep(i,n) for(ll i=0;i<(ll)(n);i++)\n#define all(a) (a).begin(),(a).end()\n#define pb push_back\n#define INF 1LL<<50\n\nvoid turn(vector<vector<pii> > &line , vector<pii> p){\n line.pb(p);\n vector<pii> tmp;\n rep(i,p.size()){\n tmp.pb(pii( p[i].first*-1 , p[i].second*-1 ));\n }\n line.pb(tmp);\n tmp.clear();\n\n \n rep(i,p.size()){\n tmp.pb(pii( p[i].second*-1 , p[i].first ));\n }\n line.pb(tmp);\n tmp.clear();\n\n \n rep(i,p.size()){\n tmp.pb(pii( p[i].second , p[i].first*-1 ));\n }\n line.pb(tmp);\n tmp.clear();\n}\n\n\nvoid pre(vector<vector<pii> > &line , vector<pii> p){\n int y,x;\n y=p[0].first,x=p[0].second;\n vector<pii> tmp;\n rep(i,p.size())tmp.pb(pii( p[i].first-y , p[i].second-x ));\n turn(line,tmp);\n\n reverse(all(p));\n y=p[0].first,x=p[0].second;\n tmp.clear();\n rep(i,p.size())tmp.pb(pii( p[i].first-y , p[i].second-x ));\n turn(line,tmp);\n}\n\nbool same(vector<pii> line,vector<pii> a){\n if(a.size()!=line.size())return false;\n rep(i,a.size()){\n if(line[i].first!=a[i].first)return false;\n if(line[i].second!=a[i].second)return false;\n }\n return true;\n}\n\nbool is(vector<vector<pii> > line , int t){\n for(int i=t*8;i<t*8+8;i++){\n if(same(line[i],line[0])){\n return true;\n }\n }\n return false;\n}\n\n\nint main(){\n int n;\n while(cin>>n){\n if(n==0)break;\n vector<vector<pii> > line;\n rep(i,n+1){\n int m;\n cin>>m;\n vector<pii> tmp;\n rep(j,m){\n int x,y;\n cin>>x>>y;\n tmp.pb(pii(y,x));\n }\n pre(line,tmp);\n }\n \n for(int i=1;i<n+1;i++){\n if(is(line,i)){\n cout<<i<<endl;\n }\n }\n cout<<\"+++++\"<<endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1300, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_1134_cpp
Problem F: Name the Crossing The city of Kyoto is well-known for its Chinese plan: streets are either North-South or East-West. Some streets are numbered, but most of them have real names. Crossings are named after the two streets crossing there, e.g. Kawaramachi-Sanjo is the crossing of Kawaramachi street and Sanjo street. But there is a problem: which name should come first? At first the order seems quite arbitrary: one says Kawaramachi-Sanjo (North-South first) but Shijo-Kawaramachi (East-West first). With some experience, one realizes that actually there seems to be an "order" on the streets, for instance in the above Shijo is "stronger" than Kawaramachi, which in turn is "stronger" than Sanjo. One can use this order to deduce the names of other crossings. You are given as input a list of known crossing names X-Y. Streets are either North-South or East-West, and only orthogonal streets may cross. As your list is very incomplete, you start by completing it using the following rule: two streets A and B have equal strength if (1) to (3) are all true: they both cross the same third street C in the input there is no street D such that D-A and B-D appear in the input there is no street E such that A-E and E-B appear in the input We use this definition to extend our strength relation: A is stronger than B, when there is a sequence A = A 1 , A 2 , ..., A n = B, with n at least 2, where, for any i in 1 .. n -1, either A i -A i +1 is an input crossing or A i and A i +1 have equal strength. Then you are asked whether some other possible crossing names X-Y are valid. You should answer affirmatively if you can infer the validity of a name, negatively if you cannot. Concretely: YES if you can infer that the two streets are orthogonal, and X is stronger than Y NO otherwise Input The input is a sequence of data sets, each of the form N Crossing 1 ... Crossing N M Question 1 ... Question M Both Crossing s and Question s are of the form X-Y where X and Y are strings of alphanumerical characters, of lengths no more than 16. There is no white space, and case matters for alphabetical characters. N and M are between 1 and 1000 inclusive, and there are no more than 200 streets in a data set. The last data set is followed by a line containing a zero. Output The output for each data set should be composed of M +1 lines, the first one containing the number of streets in the Crossing part of the input, followed by the answers to each question, either YES or NO without any spaces. Sample Input 7 Shijo-Kawaramachi Karasuma-Imadegawa Kawaramachi-Imadegawa Nishioji-Shijo Karasuma-Gojo Torimaru-Rokujo Rokujo-Karasuma 6 Shijo-Karasuma Imadegawa-Nishioji Nishioji-Gojo Shijo-Torimaru Torimaru-Gojo Shijo-Kawabata 4 1jo-Midosuji Midosuji-2jo 2jo-Omotesando Omotesando-1jo 4 Midosuji-1jo 1jo-Midosuji Midosuji-Omotesando 1jo-1jo 0 Output for the Sample Input 8 YES NO YES NO YES NO 4 YES YES NO NO
[ { "submission_id": "aoj_1134_9634624", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<ll,ll> pi;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define RFOR(i,l,r) for(ll i=r-1;i>=l;i--)\n#define RREP(i,n) RFOR(i,0,n)\n#define sz(A) (ll)(A.size())\n#define ALL(A) A.begin(),A.end()\n#define LB(A,x) (lower_bound(ALL(A),x)-A.begin())\nint main(){\n while(1){\n ll N;cin>>N;\n if(!N)return 0;\n map<string,ll>memo;\n vector<pi>es;\n ll cnt=0;\n while(N--){\n string S;cin>>S;\n ll t=find(ALL(S),'-')-S.begin();\n string X=S.substr(0,t),Y=S.substr(t+1,sz(S)-t-1);\n if(memo.find(X)==memo.end())memo[X]=cnt++;\n if(memo.find(Y)==memo.end())memo[Y]=cnt++;\n es.emplace_back(pi(memo[X],memo[Y]));\n }\n vector<vector<bool>>E(cnt,vector<bool>(cnt));\n for(auto[u,v]:es)E[u][v]=1;\n vector<vector<ll>>R(cnt,vector<ll>(cnt,1e18));\n for(auto[u,v]:es)R[u][v]=1;\n vector<vector<bool>>same(cnt,vector<bool>(cnt));\n REP(i,cnt)REP(j,cnt){\n bool ok=0;\n REP(k,cnt)if((E[i][k]&&E[j][k])||(E[k][i]&E[k][j]))ok=1;\n if(!ok)continue;\n REP(k,cnt)if(E[k][i]&&E[j][k])ok=0;\n REP(k,cnt)if(E[i][k]&&E[k][j])ok=0;\n if(ok)R[i][j]=0;\n }\n REP(i,cnt)REP(j,cnt)REP(k,cnt)R[j][k]=min(R[j][k],R[j][i]+R[i][k]);\n ll M;cin>>M;\n cout<<cnt<<endl;\n while(M--){\n string S;cin>>S;\n ll t=find(ALL(S),'-')-S.begin();\n string X=S.substr(0,t),Y=S.substr(t+1,sz(S)-t-1);\n if(memo.find(X)==memo.end()||memo.find(Y)==memo.end())cout<<\"NO\"<<endl;\n else{\n ll u=memo[X],v=memo[Y];\n if(R[u][v]>1e17)cout<<\"NO\"<<endl;\n else if(R[u][v]%2)cout<<\"YES\"<<endl;\n else cout<<\"NO\"<<endl;\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3388, "score_of_the_acc": -0.4338, "final_rank": 6 }, { "submission_id": "aoj_1134_6057889", "code_snippet": "#include<iostream>\n#include<map>\n#include<cstring>\nusing namespace std;\nconst int maxn=256;\nmap<string,int>mp;\nint mp_cnt;\nint edge[maxn][maxn];\nint main()\n{\n int n;\n while(scanf(\"%d\",&n),n)\n {\n memset(edge,0x3e,sizeof edge);\n mp.clear();\n mp_cnt=0;\n for(int i=1;i<=n;++i)\n {\n string a,b;\n cin>>a;\n b=a.substr(a.find('-')+1,a.length()-a.find('-')-1);\n a=a.substr(0,a.find('-'));\n //cout<<a<<\" \"<<b<<endl;\n if(mp.find(a)==mp.end())\n mp[a]=++mp_cnt;\n if(mp.find(b)==mp.end())\n mp[b]=++mp_cnt;\n edge[mp[a]][mp[b]]=1;\n }\n\n for(int i=1;i<=mp_cnt;++i)\n {\n for(int j=i+1;j<=mp_cnt;++j)\n {\n int flag=false;\n for(int k=1;k<=mp_cnt;++k)\n {\n if(k==i||k==j)continue;\n if((edge[i][k]==1&&edge[k][j]==1)\n ||(edge[j][k]==1&&edge[k][i]==1))\n {\n flag=false;\n break;\n }\n if((edge[i][k]==1&&edge[j][k]==1)\n ||(edge[k][i]==1&&edge[k][j]==1))\n flag=true;\n }\n if(flag)\n {\n edge[i][j]=2;\n edge[j][i]=2;\n }\n }\n }\n\n for(int k=1;k<=mp_cnt;++k)\n for(int i=1;i<=mp_cnt;++i)\n {\n if(i==k)continue;\n for(int j=1;j<=mp_cnt;++j)\n edge[i][j]=min(edge[i][j],edge[i][k]+edge[k][j]);\n }\n /*for(int i=1;i<=mp_cnt;++i)\n {\n for(int j=1;j<=mp_cnt;++j)\n printf(\"%3d\",edge[i][j]==0x3e3e3e3e?88:edge[i][j]);\n printf(\"\\n\");\n }*/\n printf(\"%d\\n\",mp_cnt);\n int m;\n scanf(\"%d\",&m);\n for(int i=1;i<=m;++i)\n {\n string a,b;\n cin>>a;\n b=a.substr(a.find('-')+1,a.length()-a.find('-')-1);\n a=a.substr(0,a.find('-'));\n if(edge[mp[a]][mp[b]]%2==1)\n printf(\"YES\\n\");\n else printf(\"NO\\n\");\n //cout<<mp.find(a)->first<<\" \"<<mp.find(a)->second<<endl;\n //cout<<mp.find(b)->first<<\" \"<<mp.find(b)->second<<endl;\n }\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3640, "score_of_the_acc": -0.4415, "final_rank": 7 }, { "submission_id": "aoj_1134_6023595", "code_snippet": "#include<bits/stdc++.h>\n#define ll long long\n#define fir first\n#define sec second\n//#define int long long\n#define inf 0x3f\nusing namespace std;\nint n,m;\nint p = 0;\nint d[210][210];\nsigned main(){\n#ifdef LOCAL\n freopen(\"input.txt\",\"r\",stdin);\n freopen(\"output.txt\",\"w\",stdout);\n#endif\n while(cin>>n && n){\n memset(d,inf,sizeof(d));\n p = 0;\n int mx = d[0][0];\n map<string,int> mp;\n string s;\n for(int i = 0;i<n;i++){\n cin>>s;\n int tmp;\n int sn = s.size();\n for(int j = 0;j<sn;j++){\n if(s[j] == '-'){\n tmp = j;\n break;\n }\n }\n string s0 = s.substr(0,tmp);\n string s1 = s.substr(tmp+1);\n int t0,t1;\n if(mp.find(s0) == mp.end()){\n t0 = p;\n mp[s0] = p++;\n }else{\n t0 = mp[s0];\n }\n if(mp.find(s1) == mp.end()){\n t1 = p;\n mp[s1] = p++;\n }else{\n t1 = mp[s1];\n }\n d[t0][t1] = 1;\n }\n for(int i = 0;i<p;i++){\n d[i][i] = 0;\n }\n for(int i = 0;i<p;i++){\n for(int j = i+1;j<p;j++){\n bool fg = false;\n for(int k = 0;k<p;k++){\n if(d[k][i] == 1 && d[j][k] == 1){\n fg = false;\n break;\n }\n if(d[i][k] == 1 && d[k][j] == 1){\n fg = false;\n break;\n }\n if(d[i][k]==1&&d[j][k]==1){\n fg = true;\n }\n if(d[k][j] == 1&& d[k][i] == 1){\n fg = true;\n }\n }\n if(fg){\n d[i][j] = 0;\n d[j][i] = 0;\n }\n }\n }\n for(int k = 0;k<p;k++){\n for(int i = 0;i<p;i++){\n for(int j = 0;j<p;j++){\n if(d[i][j]>d[i][k]+d[k][j]){\n d[i][j]=d[i][k]+d[k][j];\n }\n }\n }\n }\n cout<<p<<endl;\n cin>>m;\n for(int i = 0;i<m;i++){\n cin>>s;\n int sn = s.size();\n int tmp;\n for(int j = 0;j<sn;j++){\n if(s[j]=='-'){\n tmp = j;\n break;\n }\n }\n string s0 = s.substr(0,tmp);\n string s1 = s.substr(tmp+1);\n int t0,t1;\n if(mp.find(s0) == mp.end() || mp.find(s1) == mp.end()){\n cout<<\"NO\"<<endl;\n continue;\n }\n t0 = mp[s0];\n t1 = mp[s1];\n if(d[t0][t1] != mx && d[t0][t1]&1){\n cout<<\"YES\"<<endl;\n }else{\n cout<<\"NO\"<<endl;\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3516, "score_of_the_acc": -0.3311, "final_rank": 5 }, { "submission_id": "aoj_1134_6015892", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <cstring>\n#include <string>\n#include <vector>\n#include <utility>\n#include <queue>\n#include <map>\n#include <set>\n#include <cmath>\n#include <deque>\n#include <algorithm>\n#include <stack>\n#include <sstream>\n#include <cstdlib>\n#include <ctime>\n/*-----------------------*/\n//#define int long long\n#define INF 10000\n#define INF2 0x7f7f7f7f\nusing namespace std;\n/*-----------------------*/\n\nmap<string,int> mp;\n\nint getID(string s){\n if(mp.find(s) == mp.end()){\n int n = mp.size();\n mp[s]=n;\n }\n return mp[s];\n}\n\nint g[200][200];\n\nsigned main(){\n#ifdef LOCAL\n freopen(\"input.txt\", \"r\", stdin );\n freopen(\"output.txt\", \"w\", stdout);\n#endif\n int n;\n while(~scanf(\"%d\", &n) && n){\n for(int i = 0; i<200; i++) for(int j = 0; j<200; j++) g[i][j] = INF;\n mp.clear();\n for(int i=0; i < n; i++){\n string s;\n cin >> s;\n string s1 = s.substr(0, s.find('-'));\n string s2 = s.substr(s.find('-')+1);\n int i1= getID(s1);\n int i2= getID(s2);\n g[i1][i2]=1;\n }\n int m = mp.size();\n cout<<m<<endl;\n for(int i=0;i<m;i++){\n for(int j=0;j<m;j++){\n if(g[i][j] == 1 || g[j][i] == 1) continue;\n //rule1\n bool b=false;\n for(int k=0;k<m;k++){\n if(k==i||k==j) continue;\n if((g[i][k] == 1 || g[k][i] == 1) && (g[j][k] == 1 || g[k][j] == 1)){\n b=true;\n break;\n }\n }\n //rule2, 3\n for(int k=0;k<m;k++){\n if(k==i||k==j) continue;\n if((g[k][i] == 1 && g[j][k] == 1) || (g[i][k] == 1 && g[k][j] == 1)){\n b=false;\n break;\n }\n }\n if(b) g[i][j] = g[j][i] = 0;\n }\n }\n for(int i=0;i<m;i++) g[i][i]=0;\n for(int k=0;k<m;k++){\n for(int i=0;i<m;i++){\n for(int j=0;j<m;j++){\n g[i][j]=min(g[i][j], g[i][k] + g[k][j]);\n }\n }\n }\n int q;\n cin >> q;\n for(int i=0; i < q; i++){\n string s;\n cin >> s;\n string s1 = s.substr(0, s.find('-'));\n string s2 = s.substr(s.find('-')+1);\n int i1= getID(s1);\n int i2= getID(s2);\n if(i1>=m || i2>=m || g[i1][i2] % 2 == 0){\n puts(\"NO\");\n }else{\n puts(\"YES\");\n }\n\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3596, "score_of_the_acc": -0.642, "final_rank": 12 }, { "submission_id": "aoj_1134_5243846", "code_snippet": "#include <iostream>\n#include <vector>\n#include <utility>\n#include <map>\n\nusing namespace std;\nusing ll = long long;\nusing ps = pair<string, string>;\n#define dbg(x) cout << #x << \" = \" << x << endl\n#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))\n#define fi first\n#define se second\n\nconst int INF = 100100100;\nconst double ESP = 1e-9;\n\nps split(string s) {\n\tauto pos = s.find(\"-\");\n\n\treturn { s.substr(0, pos), s.substr(pos + 1) };\n}\n\nconst int N = 201;\n\nint main()\n{\n\tint n, m;\n\n\twhile (cin >> n) {\n\t\tif (!n) break;\n\n\t\tint cnt = 0;\n\t\tint d[N][N], C[N][N];\n\t\tbool arr[N][N];\n\t\tmap<string, int> map;\n\n\t\trep(i,N)rep(j,N) arr[i][j] = false;\n\t\t\n\t\trep(i,N)rep(j,N) d[i][j] = INF;\n\t\trep(i, N) d[i][i] = 0;\n\n\t\trep(i, N)rep(j, N) C[i][j] = INF;\n\t\trep(i, N) C[i][i] = 0;\n\n\n\t\trep(i,n) {\n\t\t\tstring s;\n\t\t\tcin >> s;\n\t\t\tps c = split(s);\n\n\t\t\tif (!map.count(c.fi)) map[c.fi] = cnt++;\n\t\t\tif (!map.count(c.se)) map[c.se] = cnt++;\n\n\t\t\tint u = map[c.fi], v = map[c.se];\n\n\t\t\tC[u][v] = 1;\n\t\t\td[u][v] = d[v][u] = 1;\n\t\t\tarr[u][v] = true;\n\t\t}\n\n\t\tcout << cnt << endl;\n\n\t\trep(k, cnt)rep(i, cnt)rep(j, cnt) d[i][j] = min(d[i][j], d[i][k] + d[k][j]);\n\n\n\t\tauto same_degree = [&](int a, int b) {\n\t\t\tbool same = false;\n\t\t\trep(i, cnt) {\n\t\t\t\tif ((arr[a][i] || arr[i][a]) && (arr[b][i] || arr[i][b])) same = true;\n\t\t\t}\n\t\t\tif (!same) return false;\n\n\t\t\trep(i, cnt) {\n\t\t\t\tif (arr[i][a] && arr[b][i]) return false;\n\t\t\t\tif (arr[a][i] && arr[i][b]) return false;\n\t\t\t}\n\t\t\treturn true;\n\t\t};\n\n\t\trep(i, cnt)rep(j, i) {\n\t\t\tif (same_degree(i, j)) {\n\t\t\t\t//cout << \"DEG :: \" << i << \" \" << j << endl;\n\t\t\t\tC[i][j] = C[j][i] = 1;\n\t\t\t}\n\t\t}\n\n\n\t\trep(k, cnt)rep(i, cnt)rep(j, cnt) C[i][j] = min(C[i][j], C[i][k] + C[k][j]);\n\n\t\tcin >> m;\n\t\twhile (m--) {\n\t\t\tstring q;\n\t\t\tcin >> q;\n\n\t\t\tps qc = split(q);\n\n\t\t\tbool ok = false;\n\t\t\tif (map.count(qc.fi) && map.count(qc.se)) {\n\t\t\t\tint u = map[qc.fi], v = map[qc.se];\n\t\t\t\t//dbg(C[u][v]);\n\n\t\t\t\tif (d[u][v] % 2 == 1 && C[u][v] < INF) ok = true;\n\t\t\t}\n\t\t\tcout << (ok ? \"YES\" : \"NO\") << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3532, "score_of_the_acc": -0.6219, "final_rank": 10 }, { "submission_id": "aoj_1134_5206206", "code_snippet": "#include <iostream>\n#include <vector>\n#include <utility>\n#include <map>\n\nusing namespace std;\nusing ll = long long;\nusing ps = pair<string, string>;\n#define dbg(x) cout << #x << \" = \" << x << endl\n#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))\n#define fi first\n#define se second\n\nconst int INF = 100100100;\nconst double ESP = 1e-9;\n\nps split(string s) {\n\tauto pos = s.find(\"-\");\n\n\treturn { s.substr(0, pos), s.substr(pos + 1) };\n}\n\nconst int N = 201;\n\nint main()\n{\n\tint n, m;\n\n\twhile (cin >> n) {\n\t\tif (!n) break;\n\n\t\tint cnt = 0;\n\t\tint d[N][N], C[N][N];\n\t\tbool arr[N][N];\n\t\tvector<int> G[N];\n\t\tmap<string, int> map;\n\n\t\trep(i,N)rep(j,N) arr[i][j] = false;\n\t\t\n\t\trep(i,N)rep(j,N) d[i][j] = INF;\n\t\trep(i, N) d[i][i] = 0;\n\n\t\trep(i, N)rep(j, N) C[i][j] = INF;\n\t\trep(i, N) C[i][i] = 0;\n\n\n\t\trep(i,n) {\n\t\t\tstring s;\n\t\t\tcin >> s;\n\t\t\tps c = split(s);\n\n\t\t\tif (!map.count(c.fi)) map[c.fi] = cnt++;\n\t\t\tif (!map.count(c.se)) map[c.se] = cnt++;\n\n\t\t\tint u = map[c.fi], v = map[c.se];\n\n\t\t\tG[u].push_back(v);\n\t\t\tC[u][v] = 1;\n\t\t\td[u][v] = d[v][u] = 1;\n\t\t\tarr[u][v] = true;\n\t\t}\n\n\t\tcout << cnt << endl;\n\n\t\trep(k, cnt)rep(i, cnt)rep(j, cnt) d[i][j] = min(d[i][j], d[i][k] + d[k][j]);\n\n\n\t\tauto same_degree = [&](int a, int b) {\n\t\t\tbool same = false;\n\t\t\trep(i, cnt) {\n\t\t\t\tif ((arr[a][i] || arr[i][a]) && (arr[b][i] || arr[i][b])) same = true;\n\t\t\t}\n\t\t\tif (!same) return false;\n\n\t\t\trep(i, cnt) {\n\t\t\t\tif (arr[i][a] && arr[b][i]) return false;\n\t\t\t\tif (arr[a][i] && arr[i][b]) return false;\n\t\t\t}\n\t\t\treturn true;\n\t\t};\n\n\t\trep(i, cnt)rep(j, i) {\n\t\t\tif (same_degree(i, j)) {\n\t\t\t\t//cout << \"DEG :: \" << i << \" \" << j << endl;\n\t\t\t\tC[i][j] = C[j][i] = 1;\n\t\t\t}\n\t\t}\n\n\n\t\trep(k, cnt)rep(i, cnt)rep(j, cnt) C[i][j] = min(C[i][j], C[i][k] + C[k][j]);\n\n\t\tcin >> m;\n\t\twhile (m--) {\n\t\t\tstring q;\n\t\t\tcin >> q;\n\n\t\t\tps qc = split(q);\n\n\t\t\tbool ok = false;\n\t\t\tif (map.count(qc.fi) && map.count(qc.se)) {\n\t\t\t\tint u = map[qc.fi], v = map[qc.se];\n\t\t\t\t//dbg(C[u][v]);\n\n\t\t\t\tif (d[u][v] % 2 == 1 && C[u][v] < INF) ok = true;\n\t\t\t}\n\t\t\tcout << (ok ? \"YES\" : \"NO\") << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3556, "score_of_the_acc": -0.6294, "final_rank": 11 }, { "submission_id": "aoj_1134_4971116", "code_snippet": "#line 1 \"a.cpp\"\n#include<iostream>\n#include<map>\n#include<vector>\n#include<bitset>\n#include<queue>\nusing namespace std;\n#line 2 \"/home/kotatsugame/library/datastructure/UF.cpp\"\nstruct UF{\n\tint n;\n\tvector<int>parent,rank;\n\tUF(int n_=0):n(n_),parent(n_),rank(n_,1)\n\t{\n\t\tfor(int i=0;i<n_;i++)parent[i]=i;\n\t}\n\tint find(int a){return parent[a]!=a?parent[a]=find(parent[a]):a;}\n\tbool same(int a,int b){return find(a)==find(b);}\n\tbool unite(int a,int b)\n\t{\n\t\ta=find(a),b=find(b);\n\t\tif(a==b)return false;\n\t\tif(rank[a]<rank[b])\n\t\t{\n\t\t\tparent[a]=b;\n\t\t\trank[b]+=rank[a];\n\t\t}\n\t\telse\n\t\t{\n\t\t\tparent[b]=a;\n\t\t\trank[a]+=rank[b];\n\t\t}\n\t\treturn true;\n\t}\n\tint size(int a){return rank[find(a)];}\n};\n#line 8 \"a.cpp\"\nint N,M;\nmap<string,int>id;\nint X[1000],Y[1000];\npair<string,string>rd()\n{\n\tstring s;cin>>s;\n\tpair<string,string>ret;\n\tret.first=\"\";\n\tint i=0;\n\twhile(s[i]!='-')ret.first+=s[i++];\n\ti++;\n\tret.second=s.substr(i);\n\treturn ret;\n}\nbitset<200>R[200],L[200];\nmain()\n{\n\twhile(cin>>N,N)\n\t{\n\t\tid.clear();\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tpair<string,string>p=rd();\n\t\t\tif(id.find(p.first)==id.end())\n\t\t\t{\n\t\t\t\tint sz=id.size();\n\t\t\t\tid[p.first]=sz;\n\t\t\t}\n\t\t\tif(id.find(p.second)==id.end())\n\t\t\t{\n\t\t\t\tint sz=id.size();\n\t\t\t\tid[p.second]=sz;\n\t\t\t}\n\t\t\tX[i]=id[p.first];\n\t\t\tY[i]=id[p.second];\n\t\t}\n\t\tint n=id.size();\n\t\tfor(int i=0;i<n;i++)R[i]=L[i]=0;\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tR[X[i]][Y[i]]=1;\n\t\t\tL[Y[i]][X[i]]=1;\n\t\t}\n\t\tUF uf(n);\n\t\tfor(int i=0;i<n;i++)for(int j=i+1;j<n;j++)\n\t\t{\n\t\t\tif((R[i]&L[j]).any()||(L[i]&R[j]).any())continue;\n\t\t\tif((R[i]&R[j]).any()||(L[i]&L[j]).any())uf.unite(i,j);\n\t\t}\n\t\tvector<int>ps;\n\t\tfor(int i=0;i<n;i++)if(i==uf.find(i))ps.push_back(i);\n\t\tvector<vector<int> >dist(n,vector<int>(n,1e9));\n\t\tfor(int i=0;i<n;i++)dist[i][i]=0;\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tint u=uf.find(X[i]);\n\t\t\tint v=uf.find(Y[i]);\n\t\t\tdist[u][v]=1;\n\t\t}\n\t\tfor(int k:ps)for(int i:ps)for(int j:ps)dist[i][j]=min(dist[i][j],dist[i][k]+dist[k][j]);\n\t\tcout<<n<<endl;\n\t\tint M;cin>>M;\n\t\tfor(;M--;)\n\t\t{\n\t\t\tpair<string,string>p=rd();\n\t\t\tif(id.find(p.first)==id.end()||id.find(p.second)==id.end())\n\t\t\t{\n\t\t\t\tcout<<\"NO\"<<endl;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tint u=uf.find(id[p.first]),v=uf.find(id[p.second]);\n\t\t\tint d=dist[u][v];\n\t\t\tif(d%2==1)cout<<\"YES\"<<endl;\n\t\t\telse cout<<\"NO\"<<endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3228, "score_of_the_acc": -0.0264, "final_rank": 1 }, { "submission_id": "aoj_1134_4953228", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n//using namespace atcoder;\nconst double pi = 3.141592653589793238462643383279;\nusing namespace std;\n//typedef\n//------------------------------------------\ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\ntypedef long long LL;\ntypedef unsigned long long ULL;\ntypedef vector<LL> VLL;\ntypedef vector<VLL> VVLL;\n\n//container util\n//------------------------------------------\n#define ALL(a) (a).begin(), (a).end()\n#define RALL(a) (a).rbegin(), (a).rend()\n#define PB push_back\n#define MP make_pair\n#define SZ(a) int((a).size())\n#define SQ(a) ((a) * (a))\n#define EACH(i, c) for (typeof((c).begin()) i = (c).begin(); i != (c).end(); ++i)\n#define EXIST(s, e) ((s).find(e) != (s).end())\n#define SORT(c) sort((c).begin(), (c).end())\n\n//repetition\n//------------------------------------------\n#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define MOD 1000000007\n\n#define rep(i, a, b) for (int i = a; i < (b); ++i)\n#define trav(a, x) for (auto &a : x)\n#define all(x) x.begin(), x.end()\n#define sz(x) (int)(x).size()\n\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\n\n#define chmin(x, y) x = min(x, y)\n#define chmax(x, y) x = max(x, y)\nconst double EPS = 1e-8, PI = acos(-1);\n//ここから編集 \n\nint main()\n{\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(6);\n \n /* 存在しない地名ならばNO */\n \n\n int n;\n while(cin >> n, n){\n vector<pair<string, string>> cross;\n map<string, int> mp;\n int cnt = 0;\n vector<vector<int>> graph(210, vector<int>(210, 0));\n REP(i,n){\n string s; cin >> s;\n string t1 = \"\", t2=\"\";\n int idx = 0;\n while(idx < s.size() && s[idx] != '-'){\n t1 += s[idx]; idx++;\n }\n idx++;\n while(idx < s.size()){\n t2 += s[idx]; idx++;\n }\n cross.push_back({t1, t2});\n\n if(mp.count(t1) == 0) mp[t1] = cnt++;\n if(mp.count(t2) == 0) mp[t2] = cnt++;\n\n int v = mp[t1], u = mp[t2];\n graph[v][u] = 1;\n }\n cout << cnt << endl;\n vector<vector<int>> g(cnt);\n REP(i,n){\n int v = mp[cross[i].first], u = mp[cross[i].second];\n g[v].push_back(u);\n g[u].push_back(v);\n }\n\n vector<vector<int>> dist(cnt, vector<int>(cnt,INT_MAX)); \n {\n for(int i=0; i<cnt; i++){\n dist[i][i] = 0;\n queue<int> q;\n q.push(i);\n while(q.size()){\n int v = q.front();\n q.pop();\n for(auto u: g[v]){\n if(dist[i][u] == INT_MAX){\n dist[i][u] = dist[i][v] + 1;\n q.push(u);\n }\n }\n }\n }\n }\n\n vector<vector<int>> memo(cnt, vector<int>(cnt,0));\n REP(i,cnt){\n REP(j,cnt){\n bool f1 = true, f2 = false;\n REP(k,cnt){\n \n if((graph[i][k] && graph[k][j]) || graph[j][k] && graph[k][i]){\n f1 = false;\n }\n if((graph[i][k] || graph[k][j]) && (graph[j][k] || graph[k][i])){\n f2 = true;\n }\n }\n if(f1&&f2){\n memo[i][j] = 1;\n }\n }\n }\n REP(i,cnt) REP(j,cnt) graph[i][j] |= memo[i][j];\n REP(k,cnt) REP(i,cnt) REP(j,cnt) graph[i][j] |= (graph[i][k] & graph[k][j]);\n\n int M; cin >> M;\n REP(i,M){\n string s; cin >> s;\n string t1 = \"\", t2=\"\";\n int idx = 0;\n while(idx < s.size() && s[idx] != '-'){\n t1 += s[idx]; idx++;\n }\n\n idx++;\n while(idx < s.size()){\n t2 += s[idx]; idx++;\n }\n\n if(mp.find(t1) == mp.end() || mp.find(t2) == mp.end()){\n cout << \"NO\" << endl;\n }else{\n if(dist[mp[t1]][mp[t2]] % 2 == 0){\n cout << \"NO\" << endl;\n }else{\n if(graph[mp[t1]][mp[t2]]) cout << \"YES\" << endl;\n else cout << \"NO\" << endl;\n }\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3704, "score_of_the_acc": -0.7473, "final_rank": 14 }, { "submission_id": "aoj_1134_4952779", "code_snippet": "#include \"iostream\"\n#include \"climits\"\n#include \"list\"\n#include \"queue\"\n#include \"stack\"\n#include \"set\"\n#include \"functional\"\n#include \"algorithm\"\n#include \"string\"\n#include \"map\"\n#include \"unordered_map\"\n#include \"unordered_set\"\n#include \"iomanip\"\n#include \"cmath\"\n#include \"random\"\n#include \"bitset\"\n#include \"cstdio\"\n#include \"numeric\"\n#include \"cassert\"\n#include \"ctime\"\n\nusing namespace std;\n\nconstexpr long long int MOD = 1000000007;\n//constexpr int MOD = 1000000007;\n//constexpr int MOD = 998244353;\n//constexpr long long int MOD = 998244353;\nconstexpr double EPS = 1e-12;\n\n//int N, M, K, T, H, W, L, R;\nlong long int N, M, K, T, H, W, L, R;\n\nclass UnionFind {\n\tvector<int>parent;\n\tvector<int>rank;\npublic:\n\tUnionFind(int num) {\n\t\tnum++;\n\t\tparent.resize(num);\n\t\trank.resize(num);\n\t\tfor (int i = 0; i < num; i++) {\n\t\t\tparent[i] = i;\n\t\t\trank[i] = 0;\n\t\t}\n\t}\n\tint Find(int node) {\n\t\tif (parent[node] == node)return node;\n\t\telse return parent[node] = Find(parent[node]);\n\t}\n\tvoid Unite(int u, int v) {\n\t\tu = Find(u);\n\t\tv = Find(v);\n\t\tif (u == v)return;\n\t\tif (rank[u] < rank[v])parent[u] = v;\n\t\telse {\n\t\t\tparent[v] = u;\n\t\t\tif (rank[u] == rank[v])rank[u]++;\n\t\t}\n\t}\n\tbool Check_Same(int u, int v) {\n\t\treturn Find(u) == Find(v);\n\t}\n};\n\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\n\twhile (cin >> N, N) {\n\t\tmap<string, int>mp;\n\t\tvector<string>s(N);\n\t\tvector<pair<string, string>>vs;\n\t\tfor (auto &i : s) {\n\t\t\tcin >> i;\n\t\t\tint box = i.find('-');\n\t\t\tstring t = i.substr(0, box);\n\t\t\tstring u = i.substr(box + 1, i.size() - 1 - box);\n\t\t\tvs.push_back({ t,u });\n\t\t\tmp[t] = mp[u] = 0;\n\t\t}\n\t\tM = mp.size();\n\t\tvector<string>conv;\n\t\tfor (auto &i : mp) {\n\t\t\ti.second = conv.size();\n\t\t\tconv.push_back(i.first);\n\t\t}\n\t\tvector<vector<int>>dp(M, vector<int>(M, MOD));\n\t\tfor (int i = 0; i < M; i++)dp[i][i] = 0;\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tdp[mp[vs[i].first]][mp[vs[i].second]] = 1;\n\t\t}\n\t\tUnionFind uf(M);\n\t\tfor (int i = 0; i < M; i++) {\n\t\t\tfor (int j = 0; j < M; j++) {\n\t\t\t\tbool flag = true;\n\t\t\t\tbool ok = false;\n\t\t\t\tfor (int k = 0; k < M; k++) {\n\t\t\t\t\tif (dp[i][k] != MOD && dp[k][j] != MOD)flag = false;\n\t\t\t\t\tif (dp[j][k] != MOD && dp[k][i] != MOD)flag = false;\n\t\t\t\t\tif (dp[i][k] == dp[j][k] && dp[i][k] == 1)ok = true;\n\t\t\t\t\tif (dp[k][i] == dp[k][j] && dp[k][i] == 1)ok = true;\n\t\t\t\t}\n\t\t\t\tif (ok&&flag) {\n\t\t\t\t\tuf.Unite(i, j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int i = 0; i < M; i++) {\n\t\t\tfor (int j = 0; j < M; j++) {\n\t\t\t\tdp[i][j] = MOD;\n\t\t\t}\n\t\t\tdp[i][i] = 0;\n\t\t}\n\t\tfor (int i = 0; i < vs.size(); i++) {\n\t\t\tint a = uf.Find(mp[vs[i].first]);\n\t\t\tint b = uf.Find(mp[vs[i].second]);\n//\t\t\tcout << a << \" edge \" << b << endl;\n\t\t\tdp[a][b] = 1;\n\t\t}\n\t\tfor (int k = 0; k < M; k++) {\n\t\t\tfor (int i = 0; i < M; i++) {\n\t\t\t\tfor (int j = 0; j < M; j++) {\n\t\t\t\t\tdp[i][j] = min(dp[i][j], dp[i][k] + dp[k][j]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<int>parent(M, -1);\n\t\tvector<int>dis(M, MOD);\n\t\tfor (int i = 0; i < M; i++) {\n\t\t\tif (parent[i] != -1)continue;\n\t\t\tparent[i] = i;\n\t\t\tdis[i] = 0;\n\t\t\tqueue<int>Q;\n\t\t\tQ.push(i);\n\t\t\twhile (!Q.empty()) {\n\t\t\t\tint cn = Q.front();\n\t\t\t\tQ.pop();\n\t\t\t\tfor (int j = 0; j < N; j++) {\n\t\t\t\t\tif (vs[j].first == conv[cn]) {\n\t\t\t\t\t\tif (dis[mp[vs[j].second]] > dis[cn] + 1) {\n\t\t\t\t\t\t\tparent[mp[vs[j].second]] = i;\n\t\t\t\t\t\t\tdis[mp[vs[j].second]] = dis[cn] + 1;\n\t\t\t\t\t\t\tQ.push(mp[vs[j].second]);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse if (vs[j].second==conv[cn]) {\n\t\t\t\t\t\tif (dis[mp[vs[j].first]] > dis[cn] + 1) {\n\t\t\t\t\t\t\tparent[mp[vs[j].first]] = i;\n\t\t\t\t\t\t\tdis[mp[vs[j].first]] = dis[cn] + 1;\n\t\t\t\t\t\t\tQ.push(mp[vs[j].first]);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << M << endl;\n\t//\tfor (auto i : mp) {\n\t//\t\tcout << i.first << \" \" << uf.Find(i.second) << endl;\n\t//\t}\n\t//\tfor (int i = 0; i < N; i++) {\n\t//\t\tfor (int j = 0; j < N; j++) {\n\t//\t\t\tcout << i << \" \" << j << \" \" << dp[i][j] << endl;\n\t//\t\t}\n\t//\t}\n\t\tcin >> K;\n\t\twhile (K--) {\n\t\t\tstring t;\n\t\t\tcin >> t;\n\t\t\tint p = t.find('-');\n\t\t\tstring u = t.substr(0, p);\n\t\t\tstring v = t.substr(p + 1, t.size() - 1 - p);\n\t\t\tif (mp.find(u) == mp.end() || mp.find(v) == mp.end()) {\n\t\t\t\tcout << \"NO\\n\";\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tint a = uf.Find(mp[u]), b = uf.Find(mp[v]);\n//\t\t\tcout << a << \" \" << b << endl;\n//\t\t\tcout << dp[a][b] << \" \" << dp[b][a] << endl;\n\t\t\tif (dis[a] % 2 == dis[b] % 2) {\n\t\t\t\tcout << \"NO\\n\";\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (dp[a][b] == MOD) {\n\t\t\t\tcout << \"NO\\n\";\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tcout << \"YES\\n\";\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 3524, "score_of_the_acc": -1.0479, "final_rank": 19 }, { "submission_id": "aoj_1134_4878272", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\npair<string, string> split(string S){\n int N = S.size();\n for (int i = 0; i < N; i++){\n if (S[i] == '-'){\n return make_pair(S.substr(0, i), S.substr(i + 1));\n }\n }\n}\nint main(){\n while (1){\n int N;\n cin >> N;\n if (N == 0){\n break;\n }\n vector<string> A(N), B(N);\n for (int i = 0; i < N; i++){\n string S;\n cin >> S;\n tie(A[i], B[i]) = split(S);\n }\n map<string, int> mp;\n for (int i = 0; i < N; i++){\n if (!mp.count(A[i])){\n int id = mp.size();\n mp[A[i]] = id;\n }\n if (!mp.count(B[i])){\n int id = mp.size();\n mp[B[i]] = id;\n }\n }\n int V = mp.size();\n cout << V << endl;\n vector<int> a(N), b(N);\n for (int i = 0; i < N; i++){\n a[i] = mp[A[i]];\n b[i] = mp[B[i]];\n }\n vector<vector<int>> E1(V);\n for (int i = 0; i < N; i++){\n E1[a[i]].push_back(b[i]);\n E1[b[i]].push_back(a[i]);\n }\n vector<int> c(V, -1);\n int cnt = 0;\n for (int i = 0; i < V; i++){\n if (c[i] == -1){\n c[i] = cnt;\n queue<int> Q;\n Q.push(i);\n while (!Q.empty()){\n int v = Q.front();\n Q.pop();\n for (int w : E1[v]){\n if (c[w] == -1){\n c[w] = c[v] ^ 1;\n Q.push(w);\n }\n }\n }\n cnt += 2;\n }\n }\n vector<vector<bool>> E2(V, vector<bool>(V, false));\n for (int i = 0; i < N; i++){\n E2[a[i]][b[i]] = true;\n }\n vector<vector<bool>> same(V, vector<bool>(V, false));\n for (int i = 0; i < V; i++){\n for (int j = 0; j < V; j++){\n bool ok1 = false, ok2 = true;\n for (int k = 0; k < V; k++){\n if (E2[i][k] && E2[j][k] || E2[k][i] && E2[k][j]){\n ok1 = true;\n }\n if (E2[i][k] && E2[k][j] || E2[k][i] && E2[j][k]){\n ok2 = false;\n }\n }\n if (ok1 && ok2){\n same[i][j] = true;\n }\n }\n }\n for (int i = 0; i < V; i++){\n for (int j = 0; j < V; j++){\n if (same[i][j]){\n E2[i][j] = true;\n }\n }\n }\n for (int i = 0; i < V; i++){\n for (int j = 0; j < V; j++){\n for (int k = 0; k < V; k++){\n if (E2[j][i] && E2[i][k]){\n E2[j][k] = true;\n }\n }\n }\n }\n int M;\n cin >> M;\n for (int i = 0; i < M; i++){\n string S;\n cin >> S;\n pair<string, string> P = split(S);\n if (!mp.count(P.first)){\n cout << \"NO\" << endl;\n } else if (!mp.count(P.second)){\n cout << \"NO\" << endl;\n } else {\n int x = mp[P.first];\n int y = mp[P.second];\n if ((c[x] ^ c[y]) == 1 && E2[x][y]){\n cout << \"YES\" << endl;\n } else {\n cout << \"NO\" << endl;\n }\n }\n }\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3196, "score_of_the_acc": -0.5878, "final_rank": 8 }, { "submission_id": "aoj_1134_4825423", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n#define all(x) (x).begin(),(x).end()\n#define fi first\n#define se second\n#define mp make_pair\n#define si(x) int(x.size())\nconst int mod=1000000007,MAX=205,INF=1<<30;\n\nvector<pair<int,int>> G[MAX];\nint dis[MAX][MAX];\n\nvoid DFS(int u,int root){\n for(auto to:G[u]){\n if(dis[to.fi][root]==-1){\n dis[to.fi][root]=dis[u][root]+to.se;\n DFS(to.fi,root);\n }else assert((dis[u][root]+to.se&1)==(dis[to.fi][root]&1));\n }\n}\n\nint main(){\n \n std::ifstream in(\"text.txt\");\n std::cin.rdbuf(in.rdbuf());\n cin.tie(0);\n ios::sync_with_stdio(false);\n \n while(1){\n int N;cin>>N;\n if(N==0) break;\n map<string,int> MA;\n int id=0;\n vector<vector<int>> edge(205,vector<int>(205)),equal(205,vector<int>(205));\n for(int i=0;i<N;i++){\n string S;cin>>S;\n for(int j=0;j<si(S);j++){\n if(S[j]=='-'){\n string X=S.substr(0,j),Y=S.substr(j+1);\n if(MA.count(X)==0){\n MA[X]=id;\n id++;\n }\n if(MA.count(Y)==0){\n MA[Y]=id;\n id++;\n }\n edge[MA[X]][MA[Y]]=1;\n break;\n }\n }\n }\n cout<<id<<endl;\n \n for(int i=0;i<id;i++){\n for(int j=i+1;j<id;j++){\n bool ok1=false,ok2=true;\n for(int k=0;k<id;k++){\n if(i==k||j==k) continue;\n \n if(edge[i][k]&&edge[j][k]) ok1=true;\n if(edge[k][i]&&edge[k][j]) ok1=true;\n \n if(edge[i][k]&&edge[k][j]) ok2=false;\n if(edge[k][i]&&edge[j][k]) ok2=false;\n }\n \n if(edge[i][j]||edge[j][i]) ok1=false;\n \n if(ok1&&ok2) equal[i][j]=equal[j][i]=1;\n }\n }\n \n for(int i=0;i<MAX;i++) G[i].clear();\n \n for(int i=0;i<id;i++){\n for(int j=0;j<id;j++){\n if(i==j) continue;\n \n if(edge[i][j]) G[i].push_back(mp(j,1));\n else if(equal[i][j]) G[i].push_back(mp(j,0));\n \n //assert(!(edge[i][j]&&equal[i][j]));\n }\n }\n \n for(int i=0;i<id;i++){\n for(int j=0;j<id;j++) dis[j][i]=-1;\n dis[i][i]=0;\n DFS(i,i);\n }\n \n int M;cin>>M;\n \n for(int i=0;i<M;i++){\n string S;cin>>S;\n for(int j=0;j<si(S);j++){\n if(S[j]=='-'){\n string X=S.substr(0,j),Y=S.substr(j+1);\n \n if(MA.count(X)==0||MA.count(Y)==0||X==Y){\n cout<<\"NO\\n\";\n continue;\n }\n \n int d=dis[MA[Y]][MA[X]];\n if(d>=0&&(d&1)) cout<<\"YES\\n\";\n else cout<<\"NO\\n\";\n \n break;\n }\n }\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3612, "score_of_the_acc": -0.2898, "final_rank": 4 }, { "submission_id": "aoj_1134_4757988", "code_snippet": "#include <iostream>\n#include <string>\n#include <map>\n#include <vector>\n\nusing namespace std;\n\nint v=0;\nmap<string,int> nameToVertex;\n\nbool cGraph[202][202];\nbool eGraph[202][202];\nbool visited[202];\n\nint N,M;\n\nstring buf;\n\nvoid buildE(){\n for(int i=0;i<v;i++){\n for(int j=i+1;j<v;j++){\n bool comm=false,order=false;\n for(int k=0;k<v;k++){\n if (i==k||j==k) continue;\n comm |= (cGraph[i][k]||cGraph[k][i])&&(cGraph[j][k]||cGraph[k][j]);\n order |= (cGraph[i][k]&&cGraph[k][j])||(cGraph[j][k]&&cGraph[k][i]);\n }\n if (comm&&!order) eGraph[i][j]=eGraph[j][i]=true;\n }\n }\n}\n\nbool DFS1(int cur,int target,bool d){\n if (cur==target) return d;\n visited[cur]=true;\n for(int i=0;i<v;i++){\n if (visited[i]) continue;\n if ((cGraph[cur][i]||cGraph[i][cur])&&DFS1(i,target,!d)) return true;\n }\n return false;\n}\n\nbool DFS2(int cur,int target){\n if (cur==target) return true;\n visited[cur]=true;\n for(int i=0;i<v;i++){\n if (visited[i]) continue;\n if ((cGraph[cur][i]||eGraph[cur][i])&&DFS2(i,target)) return true;\n }\n return false;\n}\n\n\nint main(){\n\n while(true){\n cin>>N;\n if (!N) break;\n\n for(int i=0;i<v;i++) \n for(int j=0;j<v;j++)\n cGraph[i][j]=false,eGraph[i][j]=false;\n \n nameToVertex.clear();\n v=0;\n\n for(int k=0;k<N;k++) {\n cin>>buf;\n int i=0;\n while(buf[i]!='-') i++;\n auto fst=buf.substr(0,i);\n auto snd=buf.substr(i+1);\n\n if(!nameToVertex.count(fst)) \n nameToVertex[fst]=v++;\n \n\n if(!nameToVertex.count(snd)) \n nameToVertex[snd]=v++;\n \n\n auto fstNum=nameToVertex[fst],sndNum=nameToVertex[snd];\n cGraph[fstNum][sndNum]=true;\n }\n\n buildE();\n\n cin>>M;\n cout<<v<<endl;\n\n for(int k=0;k<M;k++) {\n cin>>buf;\n int i=0;\n while(buf[i]!='-') i++;\n auto fst=buf.substr(0,i);\n auto snd=buf.substr(i+1);\n\n if (!nameToVertex.count(fst)||!nameToVertex.count(snd)){\n puts(\"NO\");\n continue;\n }\n\n auto fstNum=nameToVertex[fst],sndNum=nameToVertex[snd];\n \n for(int i=0;i<v;i++) visited[i]=false;\n if (!DFS1(fstNum,sndNum,false)){\n puts(\"NO\");\n continue;\n }\n\n for(int i=0;i<v;i++) visited[i]=false;\n\n if (DFS2(fstNum,sndNum)) puts(\"YES\");\n else puts(\"NO\");\n \n }\n\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3144, "score_of_the_acc": -1, "final_rank": 18 }, { "submission_id": "aoj_1134_4638375", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing P = pair<int, int>;\nconst double eps = 1e-8;\nconst ll MOD = 1000000007;\nconst int INF = INT_MAX / 2;\nconst ll LINF = LLONG_MAX / 2;\ntemplate <typename T1, typename T2>\nbool chmax(T1 &a, const T2 &b) {\n if(a < b) {a = b; return true;}\n return false;\n}\ntemplate <typename T1, typename T2>\nbool chmin(T1 &a, const T2 &b) {\n if(a > b) {a = b; return true;}\n return false;\n}\ntemplate<typename T1, typename T2>\nostream& operator<<(ostream &os, const pair<T1, T2> p) {\n os << p.first << \":\" << p.second;\n return os;\n}\ntemplate<class T>\nostream &operator<<(ostream &os, const vector<T> &v) {\n for(int i=0;i<((int)(v.size()));++i) {\n if(i) os << \" \";\n os << v[i];\n }\n return os;\n}\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n while(1) {\n int n;\n cin >> n;\n if (n == 0) break;\n vector<pair<string, string>> v(n);\n for(int i=0;i<(n);++i) {\n string s;\n cin >> s;\n int pos = 0;\n for(int j=0;j<((int)(s.size()));++j) {\n if (s[j] == '-') {\n pos = j;\n break;\n }\n }\n v[i].first = s.substr(0, pos);\n v[i].second = s.substr(pos + 1, (int)(s.size()) - pos - 1);\n }\n map<string, int> mp;\n int id = 0;\n for(int i=0;i<(n);++i) {\n if (mp.find(v[i].first) == mp.end()) {\n mp[v[i].first] = id;\n id++;\n }\n if (mp.find(v[i].second) == mp.end()) {\n mp[v[i].second] = id;\n id++;\n }\n }\n vector<P> cross(n);\n for(int i=0;i<(n);++i) {\n cross[i].first = mp[v[i].first];\n cross[i].second = mp[v[i].second];\n }\n vvi g1(id);\n for(int i=0;i<(n);++i) {\n g1[cross[i].first].push_back(cross[i].second);\n }\n map<P, bool> sel1, sel2;\n for(int i=0;i<(n);++i) {\n for(int j=(i + 1);j<(n);++j) {\n if (cross[i].first == cross[j].first) {\n sel1[{cross[i].second, cross[j].second}] = true;\n sel1[{cross[j].second, cross[i].second}] = true;\n }\n if (cross[i].second == cross[j].second) {\n sel1[{cross[i].first, cross[j].first}] = true;\n sel1[{cross[j].first, cross[i].first}] = true;\n }\n if (cross[i].first == cross[j].second && cross[i].second != cross[j].first) {\n sel2[{cross[i].second, cross[j].first}] = true;\n sel2[{cross[j].first, cross[i].second}] = true;\n }\n if (cross[i].second == cross[j].first && cross[i].first != cross[j].second) {\n sel2[{cross[i].first, cross[j].second}] = true;\n sel2[{cross[j].second, cross[i].first}] = true;\n }\n }\n }\n for(int i=0;i<(n);++i) {\n sel2[{cross[i].first, cross[i].second}] = true;\n sel2[{cross[i].second, cross[i].first}] = true;\n }\n vvi g2(id);\n for(int i=0;i<(id);++i) {\n for(int j=0;j<(id);++j) {\n if (sel1[{i, j}] && !sel2[{i, j}]) {\n g2[i].push_back(j);\n }\n }\n }\n cout << id << endl;\n int m;\n cin >> m;\n for(int i=0;i<(m);++i) {\n string s;\n cin >> s;\n int pos = 0;\n for(int j=0;j<((int)(s.size()));++j) {\n if (s[j] == '-') {\n pos = j;\n break;\n }\n }\n string x = s.substr(0, pos);\n string y = s.substr(pos + 1, (int)(s.size()) - pos - 1);\n if (mp.find(x) == mp.end() || mp.find(y) == mp.end()) {\n cout << \"NO\" << endl;\n continue;\n }\n int idx = mp[x];\n int idy = mp[y];\n queue<P> que;\n vvi d(2, vi(id, INF));\n d[0][idx] = 0;\n que.push({0, idx});\n while (!que.empty()) {\n int col, now;\n tie(col, now) = que.front();\n que.pop();\n for (auto &nxt: g1[now]) {\n if (d[!col][nxt] > d[col][now] + 1) {\n d[!col][nxt] = d[col][now] + 1;\n que.push({!col, nxt});\n }\n }\n for (auto &nxt: g2[now]) {\n if (d[col][nxt] > d[col][now] + 1) {\n d[col][nxt] = d[col][now] + 1;\n que.push({col, nxt});\n }\n }\n }\n if (d[1][idy] != INF) {\n cout << \"YES\" << endl;\n } else {\n cout << \"NO\" << endl;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 6328, "score_of_the_acc": -1.2857, "final_rank": 20 }, { "submission_id": "aoj_1134_4366614", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <utility>\nusing namespace std;\ntypedef pair<int, int> pii;\n\nvoid input_crossing(string &a, string &b){\n string in;\n cin >> in;\n int n = in.length();\n for(int i=0; i<n; i++){\n if(in[i] == '-'){\n a = in.substr(0, i);\n b = in.substr(i+1, n-i-1);\n break;\n }\n }\n}\n\nint dfs(int curr, int g, vector<vector<pii>> &adj, vector<bool> &used){\n if(used[curr]) return -1;\n used[curr] = true;\n if(curr == g) return 0;\n \n for(auto next: adj[curr]){\n int ret = dfs(next.first, g, adj, used);\n if(ret != -1){\n return ret+next.second;\n }\n }\n return -1;\n}\n\nint main(){\n while(1){\n int n;\n cin >> n;\n if(n == 0) break;\n\n vector<string> a(n),b(n);\n int id=0;\n map<string, int> to_id;\n for(int i=0; i<n; i++){\n input_crossing(a[i], b[i]);\n if(to_id.count(a[i]) == 0){\n to_id[a[i]] = id++;\n }\n if(to_id.count(b[i]) == 0){\n to_id[b[i]] = id++;\n }\n }\n\n vector<int> aid(n),bid(n);\n int num_st = to_id.size();\n vector<vector<pii>> adj(num_st);\n for(int i=0; i<n; i++){\n aid[i] = to_id[a[i]];\n bid[i] = to_id[b[i]];\n adj[aid[i]].emplace_back(bid[i], 1);\n }\n vector<vector<int>> eq(num_st, vector<int>(num_st, 0));\n for(int i=0; i<n; i++){\n for(int j=0; j<n; j++){\n if(aid[i]==aid[j] and eq[bid[i]][bid[j]]==0){\n eq[bid[i]][bid[j]] = 1;\n }\n if(bid[i]==bid[j] and eq[aid[i]][aid[j]]==0){\n eq[aid[i]][aid[j]] = 1;\n }\n if(aid[i]==bid[j]){\n eq[bid[i]][aid[j]] = eq[aid[j]][bid[i]] = -1;\n }\n }\n }\n for(int i=0; i<num_st; i++){\n for(int j=i+1; j<num_st; j++){\n if(eq[i][j] == 1){\n adj[i].emplace_back(j, 0);\n adj[j].emplace_back(i, 0);\n }\n }\n }\n\n int m;\n cin >> m;\n cout << id << endl;\n for(int i=0; i<m; i++){\n string s,g;\n input_crossing(s, g);\n if(to_id.count(s)==0 or to_id.count(g)==0){\n \tcout << \"NO\" << endl;\n \tcontinue;\n }\n vector<bool> used(num_st, false);\n int ret = dfs(to_id[s], to_id[g], adj, used);\n if(ret!=-1 and ret%2==1){\n cout << \"YES\" << endl;\n }else{\n cout << \"NO\" << endl;\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3324, "score_of_the_acc": -0.128, "final_rank": 3 }, { "submission_id": "aoj_1134_4291374", "code_snippet": "#include <bits/stdc++.h>\n#define inf (int)(1e7)\nusing namespace std;\n\nstruct intersection {\n string s, t;\n};\n\nint n, m;\nmap<string, int> mp;\nvector<vector<int>> dist;\nvector<vector<bool>> memo;\nvector<intersection> v;\n\nintersection parse(string &s);\n\nint main() {\n while(1) {\n cin >> n;\n if(n == 0) break;\n v.resize(n);\n mp.clear();\n for(int i = 0; i < n; ++i) {\n string s;\n cin >> s;\n intersection in = parse(s);\n if(mp.find(in.s) == mp.end()) {\n int x = mp.size();\n mp[in.s] = x;\n }\n if(mp.find(in.t) == mp.end()) {\n int x = mp.size();\n mp[in.t] = x;\n }\n v[i] = in;\n }\n cout << mp.size() << endl;\n dist.assign(mp.size(), vector<int>(mp.size(), inf));\n memo.assign(mp.size(), vector<bool>(mp.size(), 0));\n for(int i = 0; i < n; ++i)\n dist[mp[v[i].s]][mp[v[i].t]] =\n memo[mp[v[i].s]][mp[v[i].t]] = 1;\n n = mp.size();\n for(int i = 0; i < n; ++i)\n for(int j = 0; j < n; ++j)\n if(!memo[i][j]) {\n bool ch = 0;\n for(int k = 0; k < n; ++k)\n if((memo[i][k] && memo[j][k]) ||\n (memo[k][i] && memo[k][j]))\n ch = 1;\n for(int k = 0; k < n; ++k)\n if((memo[i][k] && memo[k][j]) ||\n (memo[j][k] && memo[k][i]))\n ch = 0;\n if(ch) dist[i][j] = 2;\n }\n for(int k = 0; k < n; ++k)\n for(int i = 0; i < n; ++i)\n for(int j = 0; j < n; ++j)\n dist[i][j] =\n min(dist[i][j], dist[i][k] + dist[k][j]);\n cin >> m;\n for(int i = 0; i < m; ++i) {\n string s;\n cin >> s;\n intersection now = parse(s);\n if(mp.find(now.s) == mp.end() ||\n mp.find(now.t) == mp.end() ||\n dist[mp[now.s]][mp[now.t]] % 2 == 0)\n cout << \"NO\" << endl;\n else\n cout << \"YES\" << endl;\n }\n }\n return 0;\n}\n\nintersection parse(string &s) {\n bool ch = 0;\n intersection res = {\"\", \"\"};\n int len = s.size();\n for(int i = 0; i < len; ++i) {\n if(s[i] == '-') {\n ch = 1;\n continue;\n }\n if(!ch)\n res.s += s[i];\n else\n res.t += s[i];\n }\n return res;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3516, "score_of_the_acc": -0.9025, "final_rank": 16 }, { "submission_id": "aoj_1134_3827113", "code_snippet": "#include <iostream>\n#include <vector>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <unordered_set>\n#include <algorithm>\n#include <math.h>\n#include <string>\n#include <climits>\n#include <assert.h>\n#include <iomanip>\n#include <bitset>\n\n#define FOR(i,a,b) for(int i= (a); i<((int)b); ++i)\n#define FOE(i,a) for(auto i : a)\n#define ALL(c) (c).begin(), (c).end()\n#define RALL(c) (c).rbegin(), (c).rend()\n#define SUM(x) std::accumulate(ALL(x), 0LL)\n#define MIN(v) *std::min_element(v.begin(), v.end())\n#define MAX(v) *std::max_element(v.begin(), v.end())\n#define EXIST(v,x) (std::find(v.begin(), v.end(), x) != v.end())\n#define IS_BIT_ON(bit, i) (bit & (1 << i))\n#define BIT_ON(bit, i) (bit |= (1 << i))\n#define BIT_OFF(bit, i) (bit &= ~(1 << i))\n#define BIT_COUNT(bit) (__builtin_popcount(bit))\n\ntypedef long long LL;\ntemplate<typename T> std::vector<T> make_v(size_t a){return std::vector<T>(a);}\ntemplate<typename T,typename... Ts> auto make_v(size_t a, Ts... ts){ return std::vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));} // C++14\ntemplate<typename T,typename V> typename std::enable_if<std::is_class<T>::value==0>::type fill_v(T &t,const V &v){t=v;}\ntemplate<typename T,typename V> typename std::enable_if<std::is_class<T>::value!=0>::type fill_v(T &t,const V &v){for(auto &e:t) fill_v(e,v);}\ntemplate<class T> inline T ceil(T a, T b) { return (a + b - 1) / b; }\nvoid print() { std::cout << std::endl; }\ntemplate <class Head, class... Tail> void print(Head&& head, Tail&&... tail) { std::cout << head; if (sizeof...(tail) != 0) {std::cout << \" \";} print(std::forward<Tail>(tail)...); }\ntemplate <class T> void print(std::vector<T> &v) {for (auto& a : v) { std::cout << a; if (&a != &v.back()) {std::cout << \" \";} }std::cout << std::endl;}\ntemplate <class T> void print(std::vector<std::vector<T>> &vv) { for (auto& v : vv) { print(v); }}\ninline bool inside(long long y, long long x, long long H, long long W) {return 0 <= y and y < H and 0 <= x and x < W; }\ntemplate<class T> inline double euclidean_distance(T y1, T x1, T y2, T x2) { return sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)); }\ntemplate<class T> inline double manhattan_distance(T y1, T x1, T y2, T x2) { return abs(x1 - x2) + abs(y1 - y2); }\ntemplate<typename T> T &chmin(T &a, const T &b) { return a = std::min(a, b); }\ntemplate<typename T> T &chmax(T &a, const T &b) { return a = std::max(a, b); }\n\ntemplate<class T> inline std::vector<T> unique(std::vector<T> v) {\n sort(v.begin(), v.end());\n v.erase(unique(v.begin(), v.end()), v.end());\n return v;\n}\n// 初項s, 交差dのn個の数列の和\nlong long sum_of_arithmetic_progression(long long s, long long d, long long n) {\n return n * (2 * s + (n - 1) * d) / 2;\n}\n\n// 2のべき乗数かどうか\nbool is_power_of_two(long long x) {\n return !(x & (x - 1));\n}\n\n// aとbの最大公約数 O(log min(a, b))\nlong long gcd(long long a, long long b) {\n if (b == 0) { return a; }\n return gcd(b, a % b);\n}\n\n// 数列vの最大公約数 O(N log d)\nlong long gcd(std::vector<long long> &v) {\n long long ans = v[0];\n for (int i = 1; i < (int)v.size(); ++i) {\n ans = gcd(ans, v[i]);\n }\n return ans;\n}\n\n// aとbの最小公倍数 O(log min(a, b))\nlong long lcm(long long a, long long b) {\n long long g = gcd(a, b);\n return a / g * b;\n}\n\nconst int INF = 1u << 30u;\nconst long long LINF = 1ull << 58u;\nconst double EPS = 1e-9;\nconst long double PI = acos(-1.0);\nconst std::vector<int> dy2 = {0, 1}, dx2 = {1, 0}; // 右,下\nconst std::vector<int> dy4 = {0, 1, 0, -1}, dx4 = {1, 0, -1, 0}; // 右,下,左,上\nconst std::vector<int> dy8 = { 0, -1, 0, 1, 1, -1, -1, 1 }, dx8 = { 1, 0, -1, 0, 1, 1, -1, -1 };\n\nusing namespace std;\n\n// strをdelimiterで分割する\nvector<string> split(const string &str, const string &delimiter) {\n vector<string> res;\n size_t current = 0, found, delimlen = delimiter.size();\n while ((found = str.find(delimiter, current)) != string::npos) {\n res.emplace_back(string(str, current, found - current));\n current = found + delimlen;\n }\n res.emplace_back(string(str, current, str.size() - current));\n return res;\n}\n\nclass Edge {\npublic:\n const int no = 0;\n const int from = 0;\n const int to = 0;\n const long long weight = 0;\n\n Edge(int no, int from, int to, long long weight) : no(no), from(from), to(to), weight(weight) {\n }\n\n};\n\nclass Graph {\npublic:\n const int N; // ノード数\n int M = 0; // エッジ数\n std::vector<std::vector<Edge>> graph;\n Graph(int N) : N(N) {\n this->graph.resize(N);\n }\n\n void add_undirected_edge(const int no, const int u, const int v, const long long w) {\n this->graph.at(u).emplace_back(Edge(no, u, v, w));\n this->graph.at(v).emplace_back(Edge(no, v, u, w));\n this->M++;\n }\n\n void add_directed_edge(const int no, const int from, const int to, const long long w) {\n this->graph.at(from).emplace_back(Edge(no, from, to, w));\n this->M++;\n }\n\n std::vector<Edge> &operator[](const int u) {\n return this->graph[u];\n }\n\n std::vector<std::vector<long long>> make_matrix_graph() {\n std::vector<std::vector<long long>> matrix(this->N, std::vector<long long>(this->N, INT_MAX));\n for (const auto &v : this->graph) {\n for (const auto &e : v) {\n matrix[e.from][e.to] = e.weight;\n }\n }\n return matrix;\n }\n\n // mode 0: undirected edge\n // mode 1: directed edge\n void show(int mode = 0) {\n std::cout << this->M << std::endl;\n for (const auto &v : this->graph) {\n for (const auto &e : v) {\n if (mode == 0) {\n if (e.from < e.to) {\n std::cout << e.from << \" \" << e.to << std::endl;\n }\n }\n else {\n std::cout << e.from << \" \" << e.to << std::endl;\n }\n }\n }\n }\n};\n\nvoid dfs(int u, int i, const int base, vector<int> &color, Graph &graph) {\n color[u] = base + (i % 2);\n FOE(e, graph[u]) {\n if (color[e.to] == -1) {\n dfs(e.to, i + 1, base, color, graph);\n }\n }\n}\n\n/**\n * 全ノード間の最短距離をもとめる\n * matrix[i][j]には辺e=(i,j)のコスト(辺が存在しない場合はINF)\n * 負の閉路がある場合は空を返す\n * O(|V|^3)\n */\nstd::vector<std::vector<int>> warshall_floyd(std::vector<std::vector<int>> matrix) {\n const unsigned long num_node = matrix.size();\n\n // 自分の距離は0\n for (int i = 0; i < num_node; ++i) {\n matrix.at(i).at(i) = 0;\n }\n\n for (int m = 0; m < num_node; ++m) {\n for (int s = 0; s < num_node; ++s) {\n for (int e = 0; e < num_node; ++e) {\n // sからeへmを経由して到達可能\n if (matrix.at(s).at(m) != INF and matrix.at(m).at(e) != INF) {\n matrix.at(s).at(e) = std::min(matrix.at(s).at(e), matrix.at(s).at(m) + matrix.at(m).at(e));\n }\n }\n }\n }\n\n // 負閉路チェック\n for (int u = 0; u < num_node; ++u) {\n if (matrix.at(u).at(u) < 0) {\n return {};\n }\n }\n\n return matrix;\n}\n\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n while (true) {\n LL N;\n cin >> N;\n\n if (N == 0) {\n return 0;\n }\n\n int no = 0;\n unordered_map<string, int> name_no;\n vector<pair<int, int>> edges;\n FOR(i, 0, N) {\n string S;\n cin >> S;\n auto p = split(S, \"-\");\n string a = p[0];\n string b = p[1];\n\n if (name_no.find(a) == name_no.end()) {\n name_no[a] = no;\n no++;\n }\n\n if (name_no.find(b) == name_no.end()) {\n name_no[b] = no;\n no++;\n }\n edges.emplace_back(make_pair(name_no[a], name_no[b]));\n }\n\n Graph graph(no);\n auto g = make_v<int>(no, no);\n std::vector<std::vector<int>> matrix(no, vector<int>(no, INF));\n FOE(p, edges) {\n graph.add_undirected_edge(0, p.first, p.second, 1);\n\n g[p.first][p.second] = 1;\n g[p.second][p.first] = 2;\n matrix[p.first][p.second] = 1;\n }\n\n auto color = make_v<int>(no);\n fill_v(color, -1);\n int base = 0;\n FOR(i, 0, no) {\n if (color[i] == -1) {\n dfs(i, 0, base, color, graph);\n base += 4;\n }\n }\n\n FOR(a, 0, no) {\n FOR(b, a + 1, no) {\n\n bool found1 = false, found2 = false, found3 = false;\n FOR(c, 0, no) {\n if (a == b or a == c or b == c) {\n continue;\n }\n\n if (g[a][c] and g[b][c]) {\n found1 = true;\n }\n\n if (g[c][a] == 1 and g[b][c] == 1) {\n found2 = true;\n }\n\n if (g[a][c] == 1 and g[c][b] == 1) {\n found3 = true;\n }\n }\n\n if (found1 and not found2 and not found3) {\n matrix[a][b] = 1;\n matrix[b][a] = 1;\n }\n }\n }\n\n auto cost = warshall_floyd(matrix);\n\n print(no);\n LL M;\n cin >> M;\n FOR(i, 0, M) {\n string S;\n cin >> S;\n auto p = split(S, \"-\");\n string a = p[0];\n string b = p[1];\n\n if (name_no.find(a) == name_no.end()) {\n print(\"NO\");\n continue;\n }\n\n if (name_no.find(b) == name_no.end()) {\n print(\"NO\");\n continue;\n }\n\n int u = name_no[a];\n int v = name_no[b];\n\n if (abs(color[u] - color[v]) != 1) {\n print(\"NO\");\n continue;\n }\n\n if (cost[u][v] != INF) {\n print(\"YES\");\n }\n else {\n print(\"NO\");\n }\n\n }\n\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3652, "score_of_the_acc": -0.5881, "final_rank": 9 }, { "submission_id": "aoj_1134_3674460", "code_snippet": "#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<ciso646>\n#include<utility>\n#include<map>\n#include<complex>\nusing namespace std;\ntypedef long long ll;\nconst ll mod = 1000000007;\nconst ll INF = mod * mod;\ntypedef pair<int, int> P;\ntypedef pair<ll, ll> LP;\ntypedef vector<int> vec;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define stop char nyaa;cin>>nyaa;\n#define per(i,n) for(int i=n-1;i>=0;i--)\ntypedef long double ld;\n\nstruct uf {\nprivate:\n\tvector<int> par, ran;\npublic:\n\tuf(int n) {\n\t\tpar.resize(n, 0);\n\t\tran.resize(n, 0);\n\t\trep(i, n) {\n\t\t\tpar[i] = i;\n\t\t}\n\t}\n\tint find(int x) {\n\t\tif (par[x] == x)return x;\n\t\telse return par[x] = find(par[x]);\n\t}\n\tvoid unite(int x, int y) {\n\t\tx = find(x), y = find(y);\n\t\tif (x == y)return;\n\t\tif (ran[x] < ran[y]) {\n\t\t\tpar[x] = y;\n\t\t}\n\t\telse {\n\t\t\tpar[y] = x;\n\t\t\tif (ran[x] == ran[y])ran[x]++;\n\t\t}\n\t}\n\tbool same(int x, int y) {\n\t\treturn find(x) == find(y);\n\t}\n};\n\nint n, m;\nvoid solve() {\n\tmap<string, int> mp;\n\tmap<string, bool> used;\n\tint tmp = 0;\n\tvector<P> v(n);\n\trep(i, n) {\n\t\tstring s; cin >> s;\n\t\trep(j, s.length()) {\n\t\t\tif (s[j] == '-') {\n\t\t\t\tstring le = s.substr(0, j);\n\t\t\t\tstring ri = s.substr(j + 1, (int)s.length() - (j+1));\n\t\t\t\tint lid, rid;\n\t\t\t\tif (!used[le]) {\n\t\t\t\t\tused[le] = true;\n\t\t\t\t\tmp[le] = tmp; tmp++;\n\t\t\t\t}\n\t\t\t\tlid = mp[le];\n\t\t\t\tif (!used[ri]) {\n\t\t\t\t\tused[ri] = true;\n\t\t\t\t\tmp[ri] = tmp; tmp++;\n\t\t\t\t}\n\t\t\t\trid = mp[ri];\n\t\t\t\tv[i] = { lid,rid };\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tvector<vector<int>> vl(tmp), vr(tmp);\n\trep(i, n) {\n\t\tvl[v[i].first].push_back(i);\n\t\tvr[v[i].second].push_back(i);\n\t}\n\tvector<vector<bool>> b(tmp);\n\trep(i, tmp)b[i].resize(tmp, false);\n\trep(i, tmp) {\n\t\trep(j, vl[i].size()) {\n\t\t\tRep(k,j+1, vl[i].size()) {\n\t\t\t\tint lid = v[vl[i][j]].second;\n\t\t\t\tint rid = v[vl[i][k]].second;\n\t\t\t\tb[lid][rid] = b[rid][lid] = true;\n\t\t\t}\n\t\t}\n\t\trep(j, vr[i].size()) {\n\t\t\tRep(k, j + 1, vr[i].size()) {\n\t\t\t\tint lid = v[vr[i][j]].first;\n\t\t\t\tint rid = v[vr[i][k]].first;\n\t\t\t\tb[lid][rid] = b[rid][lid] = true;\n\t\t\t}\n\t\t}\n\t}\n\trep(i, tmp) {\n\t\trep(j, vl[i].size()) {\n\t\t\trep(k, vr[i].size()) {\n\t\t\t\tint lid = v[vl[i][j]].second;\n\t\t\t\tint rid = v[vr[i][k]].first;\n\t\t\t\tb[lid][rid] = b[rid][lid] = false;\n\t\t\t}\n\t\t}\n\t}\n\tuf u(tmp); vector<vector<int>> bG(tmp);\n\trep(i, n) {\n\t\tu.unite(v[i].first, v[i].second);\n\t\tbG[v[i].first].push_back(v[i].second);\n\t\tbG[v[i].second].push_back(v[i].first);\n\t}\n\t//uf u(tmp);\n\t//rep(i, tmp)rep(j, tmp)if (b[i][j])u.unite(i, j);\n\tvector<int> isns(tmp);\n\tvector<bool> chked(tmp, false);\n\trep(i, tmp) {\n\t\tif (chked[i])continue;\n\t\tint cur = 0;\n\t\tqueue<int> q; q.push(i);\n\t\twhile (!q.empty()) {\n\t\t\tint len = q.size();\n\t\t\trep(aa, len) {\n\t\t\t\tint id = q.front(); q.pop();\n\t\t\t\tisns[id] = cur;\n\t\t\t\trep(j, bG[id].size()) {\n\t\t\t\t\tint to = bG[id][j];\n\t\t\t\t\tif (chked[to])continue;\n\t\t\t\t\tchked[to] = true;\n\t\t\t\t\tq.push(to);\n\t\t\t\t}\n\t\t\t}\n\t\t\tcur ^= 1;\n\t\t}\n\t}\n\n\tvector<vector<int>> G(tmp);\n\trep(i, n) {\n\t\tint lid = v[i].first;\n\t\tint rid = v[i].second;\n\t\tG[lid].push_back(rid);\n\t}\n\trep(i, tmp)rep(j, tmp)if (b[i][j])G[i].push_back(j);\n\n\tcout << tmp << endl;\n\tint m; cin >> m;\n\trep(i, m) {\n\t\tstring s; cin >> s;\n\t\tint len = s.length();\n\t\tint lid, rid;\n\t\tbool valid = true;\n\t\trep(j, len) {\n\t\t\tif (s[j] == '-') {\n\t\t\t\tstring le = s.substr(0, j);\n\t\t\t\tstring ri = s.substr(j + 1, len - (j + 1));\n\t\t\t\tif (!used[le] || !used[ri])valid = false;\n\t\t\t\tlid = mp[le], rid = mp[ri];\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (!valid) {\n\t\t\tcout << \"NO\" << endl; continue;\n\t\t}\n\t\tif (!u.same(lid, rid)) {\n\t\t\tcout << \"NO\" << endl; continue;\n\t\t}\n\t\tif (isns[lid] == isns[rid]) {\n\t\t\tcout << \"NO\" << endl; continue;\n\t\t}\n\t\tfill(chked.begin(), chked.begin() + tmp, false);\n\t\tqueue<int> q; q.push(lid);\n\t\tbool f = false;\n\t\twhile (!q.empty()) {\n\t\t\tint id = q.front(); q.pop();\n\t\t\tif (id == rid)f = true;\n\t\t\trep(j, G[id].size()) {\n\t\t\t\tint to = G[id][j];\n\t\t\t\tif (!chked[to]) {\n\t\t\t\t\tchked[to] = true;\n\t\t\t\t\tq.push(to);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (f) {\n\t\t\tcout << \"YES\" << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << \"NO\" << endl;\n\t\t}\n\t}\n}\n\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\t//cout << fixed << setprecision(10);\n\twhile(cin>>n,n)solve();\n\t//stop\n\t\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3400, "score_of_the_acc": -0.0804, "final_rank": 2 }, { "submission_id": "aoj_1134_3615298", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> l_l;\ntypedef pair<int, int> i_i;\nvoid chmin(int &a, int b) {\n a = min(a, b);\n}\n\n#define EPS (1e-7)\n#define INF (1e9)\n#define PI (acos(-1))\n//const ll mod = 1000000007;\nstruct UnionFind {\n vector<int> par;\n vector<int> rank;\n vector<ll> Size;\n UnionFind(int n = 1) {\n init(n);\n }\n\n void init(int n = 1) {\n par.resize(n + 1); rank.resize(n + 1); Size.resize(n + 1);\n for (int i = 0; i <= n; ++i) par[i] = i, rank[i] = 0, Size[i] = 1;\n }\n\n int root(int x) {\n if (par[x] == x) {\n return x;\n }\n else {\n int r = root(par[x]);\n return par[x] = r;\n }\n }\n\n bool issame(int x, int y) {\n return root(x) == root(y);\n }\n\n bool merge(int x, int y) {\n x = root(x); y = root(y);\n if (x == y) return false;\n if (rank[x] < rank[y]) swap(x, y);\n if (rank[x] == rank[y]) ++rank[x];\n par[y] = x;\n Size[x] += Size[y];\n return true;\n }\n\n ll size(int x){\n return Size[root(x)];\n }\n};\n\nint N;\nunordered_map<string, int> mp;\nset<string> st;\nstring intersection[1005];\nstring before[1005], after[1005];\nstring name[205];\nint dist[205][205];\nbool beforei[205][205], afteri[205][205];\nint main() {\n //cout.precision(10);\n cin.tie(0);\n ios::sync_with_stdio(false);\n UnionFind uni;\n int timer = 0;\n while(true) {\n timer++;\n //cerr << timer << endl;\n uni.init(500);\n st.clear();\n mp.clear();\n cin >> N;\n if(N == 0) break;\n for(int i = 1; i <= N; i++) {\n cin >> intersection[i];\n int moji = 0;\n while(intersection[i][moji] != '-') moji++;\n before[i] = intersection[i].substr(0, moji);\n after[i] = intersection[i].substr(moji + 1);\n st.insert(before[i]);\n st.insert(after[i]);\n //cerr << before[i] << \" \" << after[i] << endl;\n }\n int num = 0;\n for(auto itr = st.begin(); itr != st.end(); itr++) {\n num++;\n mp[*itr] = num;\n name[num] = *itr;\n }\n for(int i = 1; i <= num; i++) {\n for(int j = 1; j <= num; j++) beforei[i][j] = false, afteri[i][j] = false;\n for(int k = 1; k <= N; k++) {\n if(mp[before[k]] == i) afteri[i][mp[after[k]]] = true;\n if(mp[after[k]] == i) beforei[i][mp[before[k]]] = true;\n }\n }\n for(int i = 1; i <= num; i++) {\n for(int j = i + 1; j <= num; j++) {\n /*\n cerr << \"----\" << i << \"----\" << endl;\n for(int k = 1; k <= num; k++) {\n cerr << k << \" \" << beforei[k] << \" \" << afteri[k] << endl;\n }\n */\n bool isok = false;\n for(int k = 1; k <= num; k++) {\n if(beforei[i][k] && beforei[j][k]) isok = true;\n if(afteri[i][k] && afteri[j][k]) isok = true;\n }\n if(!isok) continue;\n for(int k = 1; k <= num; k++) {\n if(beforei[i][k] && afteri[j][k]) isok = false;\n if(beforei[j][k] && afteri[i][k]) isok = false;\n }\n if(isok) uni.merge(i, j);\n }\n }\n /*\n for(int i = 1; i <= num; i++) {\n cerr << i << \" \" << name[i] << \" \" << uni.root(i) << endl;\n }\n */\n for(int i = 1; i <= num; i++) {\n for(int j = 1; j <= num; j++) {\n dist[i][j] = INF;\n }\n dist[i][i] = 0;\n }\n /*\n UnionFind uni2(1000);\n for(int i = 1; i <= N; i++) {\n uni2.merge(mp[before[i]], mp[after[i]] + 200);\n uni2.merge(mp[before[i]] + 200, mp[after[i]]);\n dist[mp[before[i]]][mp[after[i]]] = 1;\n }\n */\n for(int i = 1; i <= N; i++) {\n dist[uni.root(mp[before[i]])][uni.root(mp[after[i]])] = 1;\n }\n for(int i = 1; i <= num; i++) {\n for(int j = 1; j <= num; j++) {\n for(int k = 1; k <= num; k++) {\n chmin(dist[j][k], dist[j][i] + dist[i][k]);\n }\n }\n }\n /*\n for(int i = 1; i <= num; i++) {\n for(int j = 1; j <= num; j++) cerr << dist[i][j] << \" \";\n cerr << endl;\n }\n */\n int M;\n cin >> M;\n cout << st.size() << endl;\n while(M--) {\n string in;\n cin >> in;\n string a, b;\n int moji = 0;\n while(in[moji] != '-') moji++;\n a = in.substr(0, moji);\n b = in.substr(moji + 1);\n if(st.find(a) == st.end() || st.find(b) == st.end()) {\n cout << \"NO\" << endl;\n continue;\n }\n a = name[uni.root(mp[a])];\n b = name[uni.root(mp[b])];\n //cerr << a << \" \" << mp[a] << \" \" << b << \" \" << mp[b] << endl;\n /*\n if(!uni2.issame(mp[a], mp[b] + 200)) {\n //cerr << \"NOT CONNECTED\" << endl;\n cout << \"NO\" << endl;\n continue;\n }\n */\n //cerr << dist[mp[a]][mp[b]] << endl;\n if(dist[mp[a]][mp[b]] == INF) cout << \"NO\" << endl;\n else if(dist[mp[a]][mp[b]] % 2 == 0) cout << \"NO\" << endl;\n else cout << \"YES\" << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3684, "score_of_the_acc": -0.741, "final_rank": 13 }, { "submission_id": "aoj_1134_3000712", "code_snippet": "#include <bits/stdc++.h> \nusing namespace std; \n#define rep(i,n) for(ll i = 0; i < ll(n); ++i) \n#define FOR(i,a,b) for(ll i = (a); i < ll(b); ++i) \n#define ROF(i,a,b) for(ll i = (a)-1; i >= ll(b); --i) \n#define all(a) (a).begin(),(a).end() \n#define fst first \n#define snd second \ntypedef long long ll; \ntypedef vector<ll> vi;\ntypedef vector<vi> vii;\nconst ll inf = 1ll<<10;\n\nbool dfs(const vii &g, ll i, vi &color){\n ll sz = g.size();\n stack<ll> st;\n color[i] = 1;\n st.push(i);\n\n while(!st.empty()){\n int now = st.top();\n st.pop();\n\n rep(next,sz){\n if(now == next) continue;\n if(g[now][next] + g[next][now] == 0){ // now<->next\n\tif(color[next] and color[next] != color[now]){\n\t //cout << now << endl << next << endl;\n\t return false; \n\t}else if(color[next] and color[next] == color[now]) continue;\n\telse{\n\t color[next] = color[now];\n\t st.push(next);\n\t}\n }else if(g[now][next] * g[next][now] == 0){ // now->next or next->now\n\tif(color[next] and color[next] == color[now]){\n\t //cout << now << endl << next << endl;\n\t return false;\n\t}else if(color[next] and color[next] != color[now]) continue;\n\telse{\n\t color[next] = -color[now];\n\t st.push(next);\n\t}\n }\n }\n }\n return true;\n}\n\nbool paintable(const vii &g, vi &color){\n ll sz = g.size();\n rep(i,sz) if(color[i] == 0) if(dfs(g,i,color) == false) return false;\n return true;\n}\n\nmain(){\n ll m,n; \n while(cin >> m, m){ \n vector<string> input(m); \n vector<vector<string>> cross(m,vector<string>(2)); \n set<string> street; \n rep(i,m){ \n cin >> input[i]; \n FOR(k,1,input[i].size()){ // A-BをAとBに分ける \n\tif(input[i][k] == '-'){ \n\t cross[i][0] = input[i].substr(0,k); \n\t cross[i][1] = input[i].substr(k+1,input[i].size()-k-1); \n\t street.insert(cross[i][0]); \n\t street.insert(cross[i][1]); \n\t //cerr << cross[i][0] << endl << cross[i][1] << endl; \n\t break; \n\t} \n } \n } \n map<string,ll> ntoi; // 通りの名前からindex\n vector<string> iton; // indexから通りの名前\n ll tmpi = 0;\n for(auto name : street){ \n ntoi[name] = tmpi;\n iton.push_back(name);\n tmpi++;\n }\n ll sz = street.size(); cout << sz << endl;\n vii g(sz,vi(sz,1)); \n rep(i,m) g[ ntoi[cross[i][0]] ][ ntoi[cross[i][1]] ] = 0; // A->B\n \n vector<pair<ll,ll>> eqp; // 同水準のpair\n rep(i,sz) rep(j,sz){ // iとjが同水準か\n bool ieqj = false;\n rep(k,sz){\n\tif((g[i][k] + g[k][j]) * (g[j][k] + g[k][i]) == 0){ // i->k->jかj->k->iがある\n\t ieqj = false;\n\t break;\n\t}else if((g[i][k] + g[j][k]) * (g[k][i] + g[k][j]) == 0){ // i->k,j->kかk->i,k->jがある\n\t ieqj = true;\n\t}\n }\n if(ieqj) eqp.push_back(make_pair(i,j));\n }\n rep(i,eqp.size()) g[eqp[i].fst][eqp[i].snd] = g[eqp[i].snd][eqp[i].fst] = 0; // A<->B\n //rep(i,sz){ rep(j,sz) cout << g[i][j] << \" \"; cout << endl; }\n\n vii d = g; // path i->j がある <=> d[i][j] == 0\n rep(k,sz) rep(i,sz) rep(j,sz) d[i][j] = min(d[i][j], d[i][k]+d[k][j]);\n\n vi color(sz);\n bool p = paintable(g,color);\n //cout << \"p : \" << p << endl;\n //rep(i,sz) cout << iton[i] << \" : \" << color[i] << endl;\n\n cin >> n;\n rep(k,n){\n string q; cin >> q;\n if(p == false){\n\tcout << \"NO\\n\";\n\tcontinue;\n }\n string ql, qr;\n FOR(i,1,q.size()){ // A-BをAとBに分ける \n\tif(q[i] == '-'){ \n\t ql = q.substr(0,i); \n\t qr = q.substr(i+1,q.size()-i-1);\n\t break; \n\t} \n }\n if(ntoi.count(ql) * ntoi.count(qr) == 0){\n\tcout << \"NO\\n\";\n\tcontinue;\n }\n if(d[ntoi[ql]][ntoi[qr]] != 0){\n\tcout << \"NO\\n\";\n\tcontinue;\n }\n //cout << color[ntoi[ql]] << endl << color[ntoi[qr]] << endl;\n if(color[ntoi[ql]] != color[ntoi[qr]]) cout << \"YES\\n\";\n else cout << \"NO\\n\";\n }\n }\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3724, "score_of_the_acc": -0.825, "final_rank": 15 }, { "submission_id": "aoj_1134_2939802", "code_snippet": "#include <bits/stdc++.h>\n#define REP(i, a, n) for(ll i = ((ll) a); i < ((ll) n); i++)\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> pll;\ntypedef pair<string, string> pss;\n\npss split(string s) {\n ll k;\n REP(i, 0, s.size()) if(s[i] == '-') k = i;\n string fi = s.substr(0, k);\n string se = s.substr(k + 1, s.size() - k - 1);\n return pss(fi, se);\n}\n\nvoid dfs(ll v, vector<vector<ll>> &E, vector<bool> &used, vector<ll> &color, ll c) {\n if(used[v]) return;\n used[v] = true;\n\n color[v] = c;\n for(ll u : E[v]) dfs(u, E, used, color, -c);\n}\n\nbool dfs2(ll v, ll g, vector<vector<ll>> &E, vector<bool> &used) {\n if(v == g) return true;\n\n if(used[v]) return false;\n used[v] = true;\n\n bool ret = false;\n for(ll u : E[v]) ret = ret || dfs2(u, g, E, used);\n return ret;\n}\n\nint main(void) {\n ll N, M;\n while(cin >> N, N) {\n vector<string> uniq;\n vector<pss> C(N);\n REP(i, 0, N) {\n string s;\n cin >> s;\n C[i] = split(s);\n uniq.push_back(C[i].first);\n uniq.push_back(C[i].second);\n }\n cin >> M;\n vector<pss> Q(M);\n REP(i, 0, M) {\n string s;\n cin >> s;\n Q[i] = split(s);\n uniq.push_back(Q[i].first);\n uniq.push_back(Q[i].second);\n }\n sort(uniq.begin(), uniq.end());\n uniq.erase(unique(uniq.begin(), uniq.end()), uniq.end());\n\n vector<pll> cross(N), query(M);\n REP(i, 0, N) {\n cross[i].first = lower_bound(uniq.begin(), uniq.end(), C[i].first) - uniq.begin();\n cross[i].second = lower_bound(uniq.begin(), uniq.end(), C[i].second) - uniq.begin();\n }\n REP(i, 0, M) {\n query[i].first = lower_bound(uniq.begin(), uniq.end(), Q[i].first) - uniq.begin();\n query[i].second = lower_bound(uniq.begin(), uniq.end(), Q[i].second) - uniq.begin();\n }\n\n ll n = uniq.size();\n vector<vector<ll>> E(n), R(n), A(n), X(n);\n REP(i, 0, N) {\n E[cross[i].first].push_back(cross[i].second);\n R[cross[i].second].push_back(cross[i].first);\n A[cross[i].first].push_back(cross[i].second);\n A[cross[i].second].push_back(cross[i].first);\n X[cross[i].first].push_back(cross[i].second);\n }\n\n vector<bool> used(n, false);\n vector<ll> color(n);\n ll c = 1;\n REP(i, 0, n) if(!used[i]) dfs(i, A, used, color, c++);\n\n vector<vector<bool>> e(n, vector<bool>(n, false));\n REP(i, 0, N) e[cross[i].first][cross[i].second] = true;\n REP(i, 0, n) REP(j, 0, n) {\n bool c1 = false, c2 = true;\n REP(k, 0, n) {\n c1 = c1 || (e[i][k] && e[j][k]) || (e[k][i] && e[k][j]);\n c2 = c2 && !(e[i][k] && e[k][j]) && !(e[j][k] && e[k][i]);\n }\n if(c1 && c2) {\n X[i].push_back(j);\n X[j].push_back(i);\n }\n }\n\n set<ll> st;\n REP(i, 0, N) {\n st.insert(cross[i].first);\n st.insert(cross[i].second);\n }\n\n cout << st.size() << endl;\n REP(i, 0, M) {\n ll s = query[i].first, t = query[i].second;\n vector<bool> used2(n, false);\n bool ok = color[s] == -color[t] && dfs2(s, t, X, used2);\n cout << (ok ? \"YES\" : \"NO\") << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3612, "score_of_the_acc": -0.9327, "final_rank": 17 } ]
aoj_1128_cpp
Square Carpets Mr. Frugal bought a new house. He feels deeply in love with his new house because it has a comfortable living room in which he can put himself completely at ease. He thinks his new house is a really good buy. But, to his disappointment, the floor of its living room has some scratches on it. The floor has a rectangle shape, covered with square panels. He wants to replace all the scratched panels with flawless panels, but he cannot afford to do so. Then, he decides to cover all the scratched panels with carpets. The features of the carpets he can use are as follows. Carpets are square-shaped. Carpets may overlap each other. Carpets cannot be folded. Different sizes of carpets are available. Lengths of sides of carpets are multiples of that of the panels. The carpets must cover all the scratched panels, but must not cover any of the flawless ones. For example, if the scratched panels are as shown in Figure 1, at least 6 carpets are needed. Figure 1: Example Covering As carpets cost the same irrespective of their sizes, Mr. Frugal would like to use as few number of carpets as possible. Your job is to write a program which tells the minimum number of the carpets to cover all the scratched panels. Input The input consists of multiple data sets. As in the following, the end of the input is indicated by a line containing two zeros. DataSet 1 DataSet 2 ... DataSet n 0 0 Each data set ( DataSet i ) represents the state of a floor. The format of a data set is as follows. W H P 11 P 12 P 13 ... P 1 W P 21 P 22 P 23 ... P 2 W ... P H 1 P H 2 P H 3 ... P HW The positive integers W and H are the numbers of panels on the living room in the x- and y- direction, respectively. The values of W and H are no more than 10. The integer P yx represents the state of the panel. The value of P yx means, 0 : flawless panel (must not be covered), 1 : scratched panel (must be covered). Output For each data set, your program should output a line containing one integer which represents the minimum number of the carpets to cover all of the scratched panels. Sample Input 4 3 0 1 1 1 1 1 1 1 1 1 1 1 8 5 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 0 1 1 1 0 1 1 1 8 8 0 1 1 0 0 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 0 0 1 1 0 0 1 1 0 0 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 0 0 1 1 0 10 10 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 0 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 0 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 0 1 1 0 1 1 1 1 1 1 1 1 1 1 1 0 0 Output for the Sample Input 2 6 14 29
[ { "submission_id": "aoj_1128_6005812", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n//#define int long long\ntypedef long long ll;\nusing namespace std;\n#define inf 0x3f3f3f3f\n#define se second\n#define fi first\nconst int mx = 1E4;\nint n,m;\nint a[14][14];\nint dp[14][14];\nint vis[14][14];\nint ans;\nvoid paint(int x,int y){\n for(int i = x;i<x+dp[x][y];i++){\n for(int j = y;j<y+dp[x][y];j++){\n vis[i][j]++;\n }\n }\n}\n\nvoid unPaint(int x,int y){\n for(int i = x;i<x+dp[x][y];i++){\n for(int j = y;j<y+dp[x][y];j++){\n vis[i][j]--;\n }\n }\n}\n\nbool cov(int x,int y){\n if(!a[x][y]) return true;\n if(vis[x][y]) return true;\n return false;\n}\nunordered_map<string,int> pp;\nstring getCon(int cur){\n string s;\n for(int i = 1;i<=n;i++){\n for(int j = 1;j<=m;j++){\n if(vis[i][j]){\n s+=\"1\";\n }else{\n s+=\"0\";\n }\n }\n }\n s+= to_string(cur);\n return s;\n}\n\nvoid dfs(int t,int cur){\n int x = t/m+1;\n int y = t%m+1;\n if( cur >= ans) return ;\n if(t == n*m){\n ans = min(ans,cur);\n return ;\n }\n string tmp = getCon(cur);\n if(pp.find(tmp) != pp.end()){\n return;\n }\n int as = mx;\n if(cov(x,y)){\n dfs(t+1,cur);\n if(!dp[x][y]) return;\n paint(x,y);\n dfs(t+1,cur+1);\n unPaint(x,y);\n }else{\n if(!dp[x][y]) return;\n paint(x,y);\n dfs(t+1,cur+1);\n unPaint(x,y);\n }\n pp[tmp] = 1;\n}\n\nsigned main(){\n#ifdef LOCAL\n freopen(\"input.txt\",\"r\",stdin);\n freopen(\"output.txt\",\"w\",stdout);\n#endif\n while(cin>>m>>n && (m|n)){\n pp.clear();\n ans = mx;\n memset(dp,0,sizeof(dp));\n memset(vis,0,sizeof(vis));\n memset(a,0,sizeof(a));\n\n for(int i = 1;i<=n;i++){\n for(int j = 1;j<=m;j++){\n scanf(\"%d\",&a[i][j]);\n }\n }\n for(int i = n;i>0;i--){\n for(int j = m;j>0;j--){\n if(!a[i][j]) continue;\n dp[i][j] = min(dp[i+1][j],min(dp[i+1][j+1],dp[i][j+1]))+1;\n }\n }\n\n //递推化简\n for(int i = n;i>0;i--){\n for(int j = m;j;j--){\n if(dp[i+1][j+1]<dp[i][j]) dp[i+1][j+1] = 0;\n if(dp[i][j+1]<dp[i][j]) dp[i][j+1] = 0;\n if(dp[i+1][j]<dp[i][j]) dp[i+1][j] = 0;\n }\n }\n dfs(0,0);\n printf(\"%d\\n\",ans);\n }\n\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4092, "score_of_the_acc": -0.242, "final_rank": 6 }, { "submission_id": "aoj_1128_5388971", "code_snippet": "#include <iostream>\n\nusing namespace std;\nusing pii = pair<int, int>;\n#define MAX 11\n#define FLO 0\n#define SCR 1\n#define CAR 2\n#define mkpr make_pair\n\nint map[MAX][MAX];\nint bigCar[MAX][MAX];\nint numCar[MAX][MAX];\nint h, w, minCost;\n\nint calcBigCar(int y, int x)\n{\n if (map[y][x] == 0)\n return 0;\n\n int dx[3] = { 0,1,1 };\n int dy[3] = { 1,1,0 };\n int front, last;\n front = last = 0;\n bool vis[MAX][MAX] = { false };\n pair<pii, int> q[MAX * MAX] = {};\n q[last] = mkpr(mkpr(y, x), 0); ++last;\n vis[y][x] = true;\n\n while (last-front)\n {\n pii t = q[front].first;\n int turn = q[front].second; ++front;\n for (int i = 0; i < 3; ++i)\n {\n int nexty = t.first + dy[i];\n int nextx = t.second + dx[i];\n if (map[nexty][nextx] == FLO)\n return turn + 1;\n else if (!vis[nexty][nextx])\n {\n vis[nexty][nextx] = true;\n q[last] = mkpr(mkpr(nexty, nextx), turn + 1); ++last;\n }\n }\n }\n return -1;\n}\nvoid calcNumCar(int y, int x, int s)\n{\n for (int i = y; i < y + s; ++i)\n for (int j = x; j < x + s; ++j)\n ++numCar[i][j];\n return;\n}\nint layCar(int y, int x, int bkup[MAX][MAX] = map)\n{\n int add = 0;\n int of = bigCar[y][x];\n for (int i = y; i < y + of; ++i)\n for (int j = x; j < x +of; ++j)\n {\n bkup[i][j] = map[i][j];\n if (map[i][j] == SCR)\n {\n ++add;\n map[i][j] = CAR;\n }\n }\n return add;\n}\nvoid copyArray(int y, int x, int bef[MAX][MAX], int aft[MAX][MAX])\n{\n int of = bigCar[y][x];\n for (int i = y; i < y + of; ++i)\n for (int j = x; j < x + of; ++j)\n aft[i][j] = bef[i][j];\n return;\n}\n\nvoid dfs(int y, int x, int cost, int remain)\n{\n if (cost >= minCost)\n return;\n if (remain)\n {\n if ((cost + 1) >= minCost)\n return;\n }\n else\n {\n minCost = min(minCost, cost);\n return;\n }\n\n if (!map[y][x] || numCar[y][x] == 1)\n {\n if (x + 1 == w)\n dfs(y + 1, 0, cost, remain);\n else\n dfs(y, x + 1, cost, remain);\n return;\n }\n\n if (map[y][x] == 2)\n {\n if (x + 1 == w)\n dfs(y + 1, 0, cost, remain);\n else\n dfs(y, x + 1, cost, remain);\n }\n\n int temp[MAX][MAX];\n int n = layCar(y, x, temp);\n if (!n) return;\n else\n {\n if (x + 1 == w)\n dfs(y + 1, 0, cost + 1, remain - n);\n else\n dfs(y, x + 1, cost + 1, remain - n);\n copyArray(y, x, temp, map);\n }\n return;\n}\n\nint main()\n{\n while (cin >> w >> h, w || h)\n {\n int ans = 0;\n int numScr = 0;\n minCost = 0;\n for (int i = 0; i < MAX; ++i)\n for (int j = 0; j < MAX; ++j)\n {\n map[i][j] = FLO;\n numCar[i][j] = 0;\n }\n for (int i = 0; i < h; ++i)\n for (int j = 0; j < w; ++j)\n {\n cin >> map[i][j];\n if (map[i][j] == SCR)\n ++numScr;\n }\n for (int i = 0; i < h; ++i)\n for (int j = 0; j < w; ++j)\n {\n bigCar[i][j] = calcBigCar(i, j);\n calcNumCar(i, j, bigCar[i][j]);\n if (numCar[i][j] == 1)\n {\n numScr -= layCar(i, j);\n ++ans;\n }\n }\n minCost = numScr;\n dfs(0, 0, 0, numScr);\n cout << ans + minCost << endl;\n }\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 3140, "score_of_the_acc": -0.4762, "final_rank": 11 }, { "submission_id": "aoj_1128_5388950", "code_snippet": "#include <iostream>\n\nusing namespace std;\n\n#define MAX 11\n#define FLO 0\n#define SCR 1\n#define CAR 2\n#define mkpr make_pair\n\nint map[MAX][MAX];\nint bigCar[MAX][MAX];\nint numCar[MAX][MAX];\nint h, w, minCost;\n\n\nint calcBigCar(int y, int x)\n{\n if (map[y][x] == 0)\n return 0;\n\n int dx[3] = { 0,1,1 };\n int dy[3] = { 1,1,0 };\n int front, last;\n front = last = 0;\n bool vis[MAX][MAX] = { false };\n pair<pair<int, int>, int> q[MAX * MAX] = {};\n q[last] = mkpr(mkpr(y, x), 0); ++last;\n vis[y][x] = true;\n\n while (last-front)\n {\n pair<int, int> t = q[front].first;\n int turn = q[front].second; ++front;\n\n for (int i = 0; i < 3; ++i)\n {\n int nexty = t.first + dy[i];\n int nextx = t.second + dx[i];\n if (map[nexty][nextx] == FLO)\n return turn + 1;\n else if (!vis[nexty][nextx])\n {\n vis[nexty][nextx] = true;\n q[last] = mkpr(mkpr(nexty, nextx), turn + 1); ++last;\n }\n }\n }\n return -1;\n}\n\nvoid calcNumCar(int y, int x, int size)\n{\n for (int i = y; i < y + size; ++i)\n for (int j = x; j < x + size; ++j)\n ++numCar[i][j];\n return;\n}\n\nint layCar(int y, int x, int temp[MAX][MAX] = map)\n{\n int add = 0;\n for (int i = y; i < y + bigCar[y][x]; ++i)\n for (int j = x; j < x + bigCar[y][x]; ++j)\n {\n temp[i][j] = map[i][j];\n if (map[i][j] == SCR)\n {\n ++add;\n map[i][j] = CAR;\n }\n }\n return add;\n}\n\nvoid copyArray(int y, int x, int bef[MAX][MAX], int aft[MAX][MAX])\n{\n for (int i = y; i < y+bigCar[y][x]; ++i)\n for (int j = x; j < x+bigCar[y][x]; ++j)\n aft[i][j] = bef[i][j];\n\n return;\n}\n\nvoid dfs(int y, int x, int cost, int remain)\n{\n if (cost >= minCost)\n return;\n if (remain)\n {\n if ((cost + 1) >= minCost)\n return;\n }\n else\n {\n minCost = min(minCost, cost);\n return;\n }\n if (y == h)\n return;\n if (!map[y][x] || numCar[y][x] == 1)\n {\n if (x + 1 == w)\n dfs(y + 1, 0, cost, remain);\n else\n dfs(y, x + 1, cost, remain);\n return;\n }\n \n if (map[y][x] == 2)\n {\n if (x + 1 == w)\n dfs(y + 1, 0, cost, remain);\n else\n dfs(y, x + 1, cost, remain);\n }\n\n int tempMap[MAX][MAX];\n int covered = layCar(y, x, tempMap);\n if (!covered)\n return;\n else\n {\n if (x + 1 == w)\n dfs(y + 1, 0, cost + 1, remain - covered);\n else\n dfs(y, x + 1, cost + 1, remain - covered);\n copyArray(y, x, tempMap, map);\n }\n return;\n}\n\nint main()\n{\n while (cin >> w >> h, w || h)\n {\n int ans = 0;\n int numScr = 0;\n minCost = 0;\n\n for (int i = 0; i < MAX; ++i)\n for (int j = 0; j < MAX; ++j)\n {\n map[i][j] = FLO;\n numCar[i][j] = 0;\n }\n for (int i = 0; i < h; ++i)\n for (int j = 0; j < w; ++j)\n {\n cin >> map[i][j];\n if (map[i][j] == SCR)\n ++numScr;\n }\n for (int i = 0; i < h; ++i)\n for (int j = 0; j < w; ++j)\n {\n bigCar[i][j] = calcBigCar(i, j);\n calcNumCar(i, j, bigCar[i][j]);\n if (numCar[i][j] == 1)\n {\n numScr -= layCar(i, j);\n ++ans;\n }\n }\n minCost = numScr;\n dfs(0, 0, 0, numScr);\n\n cout << ans + minCost << endl;\n }\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 3128, "score_of_the_acc": -0.4525, "final_rank": 10 }, { "submission_id": "aoj_1128_4971161", "code_snippet": "#include \"iostream\"\n#include \"climits\"\n#include \"list\"\n#include \"queue\"\n#include \"stack\"\n#include \"set\"\n#include \"functional\"\n#include \"algorithm\"\n#include \"string\"\n#include \"map\"\n#include \"unordered_map\"\n#include \"unordered_set\"\n#include \"iomanip\"\n#include \"cmath\"\n#include \"random\"\n#include \"bitset\"\n#include \"cstdio\"\n#include \"numeric\"\n#include \"cassert\"\n#include \"ctime\"\n#include \"complex\"\n\nusing namespace std;\n\nconstexpr long long int MOD = 1000000007;\n//constexpr int MOD = 1000000007;\n//constexpr int MOD = 998244353;\n//constexpr long long int MOD = 998244353;\nconstexpr double EPS = 1e-12;\n\n//int N, M, K, T, H, W, L, R;\nlong long int N, M, K, T, H, W, L, R;\n\nvoid func(vector<vector<int>>v, vector<vector<int>>&w, int y, int x, int score = 0) {\n\tif (score >= K)return;\n\tdo {\n\t\tif (x>=0&&v[y][x])return;\n\t\tx++;\n\t\tif (x == W) {\n\t\t\tx = 0;\n\t\t\ty++;\n\t\t}\n\t}while(y < H && (w[y][x] == 0));\n\tif (y == H) {\n\t\tK = min(K, 0LL + score);\n\t\treturn;\n\t}\n\tif (v[y][x] == 0)func(v, w, y, x, score);\n\tfor (int i = y; i < y + w[y][x]; i++) {\n\t\tfor (int j = x; j < x + w[y][x]; j++) {\n\t\t\tv[i][j] = 0;\n\t\t}\n\t}\n\tfunc(v, w, y, x, score + 1);\n}\n\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\n\twhile (cin >> W >> H, H) {\n\t\tvector<vector<int>>v(H, vector<int>(W));\n\t\tvector<vector<int>>num(H, vector<int>(W));\n\t\tfor (auto &i : v)for (auto &j : i)cin >> j;\n\t\tfor (int i = 0; i < H; i++) {\n\t\t\tfor (int j = 0; j < W; j++) {\n\t\t\t\tfor (int k = 1; k <= H - i && k <= W - j; k++) {\n\t\t\t\t\tbool ok = true;\n\t\t\t\t\tfor (int l = i; l < i + k; l++) {\n\t\t\t\t\t\tfor (int m = j; m < j + k; m++) {\n\t\t\t\t\t\t\tif (v[l][m] == 0)ok = false;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (ok)num[i][j] = k;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int i = H - 1; i >= 0; i--) {\n\t\t\tfor (int j = W - 1; j >= 0; j--) {\n\t\t\t\tif (i) {\n\t\t\t\t\tif (num[i - 1][j] > num[i][j])num[i][j] = 0;\n\t\t\t\t\tif (j) {\n\t\t\t\t\t\tif (num[i - 1][j - 1] > num[i][j])num[i][j] = 0;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (j) {\n\t\t\t\t\tif (num[i][j - 1] > num[i][j])num[i][j] = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<vector<int>>sum(H, vector<int>(W));\n\t\tfor (int i = 0; i < H; i++) {\n\t\t\tfor (int j = 0; j < W; j++) {\n\t\t\t\tfor (int k = i; k <i+ num[i][j]; k++) {\n\t\t\t\t\tfor (int l = j; l < j + num[i][j]; l++) {\n\t\t\t\t\t\tsum[k][l]++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint add = 0;\n\t\tfor (int i = 0; i < H; i++) {\n\t\t\tfor (int j = 0; j < W; j++) {\n\t\t\t\tbool flag = false;\n\t\t\t\tfor (int k = i; k <i + num[i][j]; k++) {\n\t\t\t\t\tfor (int l = j; l < j + num[i][j]; l++) {\n\t\t\t\t\t\tif (sum[k][l] == 1) {\n\t\t\t\t\t\t\tflag = true;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (flag) {\n\t\t\t\t\tadd++;\n\t\t\t\t\tfor (int k = i; k <i + num[i][j]; k++) {\n\t\t\t\t\t\tfor (int l = j; l < j + num[i][j]; l++) {\n\t\t\t\t\t\t\tv[k][l] = 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tnum[i][j] = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tK = MOD;\n\t\tfunc(v, num, 0, -1);\n\t\tcout << K +add<< endl;\n\t}\n}", "accuracy": 1, "time_ms": 960, "memory_kb": 3432, "score_of_the_acc": -1.0873, "final_rank": 19 }, { "submission_id": "aoj_1128_4941655", "code_snippet": "// 利用估价函数进行剪枝\n// RE了一发,原因:未特判todo空的情况。 \n#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <cmath>\n#include <utility>\n#include <queue>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ldouble;\nconst int LEN = 100000;\n\nstruct fastio {\n int it, len;\n char s[LEN + 5];\n fastio() {\n it = len = 0;\n }\n char get() {\n if (it < len) return s[it++];\n it = 0, len = fread(s, 1, LEN, stdin);\n return len ? s[it++] : EOF;\n }\n bool notend() {\n char c;\n for (c = get(); c == ' ' || c == '\\n' || c == '\\r'; c = get());\n if (it) it--;\n return c != EOF;\n }\n void put(char c) {\n if (it == LEN) fwrite(s,1,LEN,stdout), it = 0;\n s[it++] = c;\n }\n void flush() {\n fwrite(s, 1, it, stdout);\n }\n}buff, bufo;\ninline int getint() {\n char c; int res = 0, sig = 1;\n for (c = buff.get(); c < '0' || c > '9'; c = buff.get()) if(c == '-') sig = -1;\n for (; c >= '0' && c <= '9'; c = buff.get()) res = res * 10 + (c - '0');\n return sig * res;\n}\ninline ll getll() {\n char c; ll res = 0, sig = 1;\n for (c = buff.get(); c < '0' || c > '9'; c = buff.get()) if (c == '-') sig = -1;\n for (; c >= '0' && c <= '9'; c = buff.get()) res = res * 10 + (c - '0');\n return sig * res;\n}\ninline void putint(int x, char suf) {\n if (!x) bufo.put('0');\n else {\n if (x < 0) bufo.put('-'), x = -x;\n int k = 0; char s[15];\n while (x) {\n s[++k] = x % 10 + '0';\n x /= 10;\n }\n for (; k; k--) bufo.put(s[k]);\n }\n bufo.put(suf);\n}\ninline void putll(ll x, char suf) {\n if (!x) bufo.put('0');\n else {\n if (x < 0) bufo.put('-'), x = -x;\n int k = 0; char s[25];\n while (x) {\n s[++k] = x % 10 + '0';\n x /= 10;\n }\n for (; k; k--) bufo.put(s[k]);\n }\n bufo.put(suf);\n}\ninline char get_char() {\n char c;\n for (c = buff.get(); c == ' ' || c == '\\n' || c == '\\r'; c = buff.get());\n return c;\n}\ntemplate<class T> bool chmin(T &x, T y) {\n return x > y ? (x = y, true) : false;\n}\ntemplate<class T> bool chmax(T &x, T y) {\n return x < y ? (x = y, true) : false;\n}\n\n#define maxn 15\n#define mp make_pair\ntypedef pair<int, int> P;\nconst int inf = 0x3f3f3f3f;\nint w, h, len[maxn][maxn], p[maxn][maxn];\n\nbool check(int x, int y, int l) {\n for (int i = 0; i < l; i++)\n for (int j = 0; j < l; j++) if (!p[x + i][y + j]) return false;\n return true;\n}\n\nvector<P> todo; // {(i, j)|p[i][j] = 1}\nint ans, cover[maxn][maxn];\n\nint hstar(int id, int r) { // 还剩r个格子没覆盖\n int maxi = 0;\n for (int i = id; i < (int)todo.size(); i++) {\n chmax(maxi, len[todo[i].first][todo[i].second]);\n }\n maxi *= maxi;\n return (r + maxi - 1) / maxi - 1;\n}\n\nvoid dfs(int cur, int r, int id) {\n if (cur + hstar(id, r) >= ans) return; // 最优性剪枝1 \n // 目前(连todo[id])铺了cur块,(不连todo[id])还剩r个格子没覆盖,\n // 现在考虑(必选的)todo[id]\n int x = todo[id].first, y = todo[id].second;\n for (int i = 0; i < len[x][y]; i++) {\n for (int j = 0; j < len[x][y]; j++) {\n r -= !cover[x + i][y + j];\n cover[x + i][y + j]++;\n }\n }\n int nxt;\n for (nxt = id + 1; nxt < (int)todo.size(); nxt++) {\n int cx = todo[nxt].first, cy = todo[nxt].second;\n if (!cover[cx][cy]) break; // 可行性剪枝 \n }\n if (nxt == (int)todo.size()) {\n chmin(ans, cur);\n } else {\n for (; nxt > id; nxt--) { // 调整搜索顺序 \n bool useful = false;\n int cx = todo[nxt].first, cy = todo[nxt].second;\n for (int j = 0; j < len[cx][cy]; j++) {\n for (int k = 0; k < len[cx][cy]; k++) {\n if (!cover[cx + j][cy + k]) useful = true;\n }\n }\n if (useful) dfs(cur + 1, r, nxt); // 最优性剪枝2 \n }\n }\n for (int i = 0; i < len[x][y]; i++) {\n for (int j = 0; j < len[x][y]; j++) {\n cover[x + i][y + j]--;\n r += !cover[x + i][y + j];\n }\n }\n}\n\nvoid solve() {\n memset(p, 0, sizeof(p));\n memset(len, 0, sizeof(len));\n todo.clear();\n for (int i = 1; i <= h; i++) {\n for (int j = 1; j <= w; j++) {\n if (p[i][j] = getint()) todo.push_back(mp(i, j));\n }\n }\n for (int i = 1; i <= h; i++) {\n for (int j = 1; j <= w; j++) {\n while (check(i, j, len[i][j] + 1)) len[i][j]++;\n }\n }\n for (int i = todo.size() - 1; i >= 0; i--) { // 最优性剪枝3 \n for (int j = i + 1; j < (int)todo.size(); j++) {\n int xi = todo[i].first, yi = todo[i].second,\n xj = todo[j].first, yj = todo[j].second;\n if (yi <= yj && len[xi][yi] - len[xj][yj] >= max(yj - yi, xj - xi))\n len[xj][yj] = 1;\n }\n }\n if (todo.empty()) {\n putint(0, '\\n');\n return;\n }\n ans = inf;\n memset(cover, 0, sizeof(cover)); \n dfs(1, todo.size(), 0);\n putint(ans, '\\n');\n}\n\nint main() {\n// freopen(\"sample.in\", \"r\", stdin);\n// freopen(\"sample.out\", \"w\", stdout); \n while ((w = getint()) && (h = getint())) solve();\n bufo.flush();\n return 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 3104, "score_of_the_acc": -0.2473, "final_rank": 7 }, { "submission_id": "aoj_1128_4934437", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n#define all(x) (x).begin(),(x).end()\n#define fi first\n#define se second\n#define mp make_pair\n#define si(x) int(x.size())\nconst int mod=1000000007,MAX=1005;\nconst int INF=1e6;\n//const ll INF=1LL<<60;\n\nmap<vector<vector<int>>,int> MA;\n\nvector<vector<int>> S(10,vector<int>(10));\nint ma[12][12],must[12][12];\nint H,W;\n\nint ans=INF;\n\nvoid DFS(int h,int w,int sum){\n \n if(sum>=ans) return;\n \n if(MA.count(S)&&MA[S]<=sum) return;\n \n if(must[h][w]){\n if(sum+1>=ans) return;\n \n vector<pair<int,int>> Q;\n \n for(int a=h;a<h+ma[h][w];a++){\n for(int b=w;b<w+ma[h][w];b++){\n if(S[a][b]){\n Q.push_back(mp(a,b));\n S[a][b]=0;\n }\n }\n }\n if(w==W-1) DFS(h+1,0,sum+1);\n else DFS(h,w+1,sum+1);\n \n for(auto x:Q) S[x.fi][x.se]=1;\n \n return ;\n }\n \n int sh=h,sw=w;\n \n while(h<H){\n while(w<W&&S[h][w]==0) w++;\n if(w==W){\n h++;\n w=0;\n }else break;\n }\n if(h==H){\n chmin(ans,sum);\n return;\n }\n \n swap(h,sh);\n swap(w,sw);\n \n int change=0;\n for(int a=h;a<h+ma[h][w];a++){\n for(int b=w;b<w+ma[h][w];b++){\n if(S[a][b]){\n change++;\n break;\n }\n }\n if(change) break;\n }\n \n if(change==0){\n if(w==W-1) DFS(h+1,0,sum);\n else DFS(h,w+1,sum);\n }else if(S[h][w]){\n if(sum+1>=ans) return;\n \n vector<pair<int,int>> Q;\n \n for(int a=h;a<h+ma[h][w];a++){\n for(int b=w;b<w+ma[h][w];b++){\n if(S[a][b]){\n Q.push_back(mp(a,b));\n S[a][b]=0;\n }\n }\n }\n if(w==W-1) DFS(h+1,0,sum+1);\n else DFS(h,w+1,sum+1);\n \n for(auto x:Q) S[x.fi][x.se]=1;\n }else{\n if(w==W-1) DFS(h+1,0,sum);\n else DFS(h,w+1,sum);\n \n vector<pair<int,int>> Q;\n \n for(int a=h;a<h+ma[h][w];a++){\n for(int b=w;b<w+ma[h][w];b++){\n if(S[a][b]){\n Q.push_back(mp(a,b));\n S[a][b]=0;\n }\n }\n }\n if(w==W-1) DFS(h+1,0,sum+1);\n else DFS(h,w+1,sum+1);\n \n for(auto x:Q) S[x.fi][x.se]=1;\n }\n \n MA[S]=sum;\n}\n\nint main(){\n \n std::ifstream in(\"text.txt\");\n std::cin.rdbuf(in.rdbuf());\n cin.tie(0);\n ios::sync_with_stdio(false);\n \n while(1){\n cin>>W>>H;\n if(H==0) break;\n memset(ma,0,sizeof(ma));\n memset(must,0,sizeof(must));\n ans=INF;\n for(int i=0;i<10;i++) for(int j=0;j<10;j++) S[i][j]=0;\n MA.clear();\n for(int i=0;i<H;i++) for(int j=0;j<W;j++) {cin>>S[i][j];}\n \n for(int i=0;i<H;i++){\n for(int j=0;j<W;j++){\n for(int k=1;k<=max(H-i,W-j);k++){\n int cnt=0;\n \n for(int a=i;a<i+k;a++){\n for(int b=j;b<j+k;b++){\n if(a<H&&b<W&&S[a][b]) cnt++;\n }\n }\n \n if(cnt==k*k){\n ma[i][j]=k;\n }\n }\n \n int k=ma[i][j];\n \n for(int a=i;a<i+k;a++){\n for(int b=j;b<j+k;b++){\n must[a][b]++;\n }\n }\n }\n }\n \n for(int i=0;i<H;i++){\n for(int j=0;j<W;j++){\n if(must[i][j]!=1) must[i][j]=0;\n }\n }\n \n DFS(0,0,0);\n \n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 4216, "score_of_the_acc": -0.6164, "final_rank": 16 }, { "submission_id": "aoj_1128_3717783", "code_snippet": "#include <bits/stdc++.h>\n#define FOR(i,k,n) for(int i=(k);i<(int)(n);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(x) begin(x),end(x)\nusing namespace std;\nusing ll = int64_t;\n\nint solve(const vector<bitset<100>>& v, const bitset<100>& rem) {\n if (rem.none()) return 0;\n bitset<100> b;\n int mx = 0;\n vector<int> cnt(100, 0);\n for(auto&& t : v) {\n int n = (rem & t).count();\n if (n > mx) {\n b = t;\n mx = n;\n }\n REP(i,100) {\n if (t[i]) ++cnt[i];\n }\n }\n set<int> s;\n REP(i,100) {\n if (rem[i]) {\n if (cnt[i] == 0) return 10000;\n if (cnt[i] == 1) s.insert(i);\n }\n }\n if (s.empty()) {\n vector<bitset<100>> tmp;\n for(auto&& t : v) {\n if (t != b) tmp.push_back(t);\n }\n return min(solve(tmp, rem & ~b) + 1, solve(tmp, rem));\n } else {\n vector<bitset<100>> tmp;\n bitset<100> next = rem;\n for(auto&& t : v) {\n bool use = false;\n for(auto&& i : s) {\n if (t[i]) {\n next &= ~t;\n use = true;\n break;\n }\n }\n if (use) continue;\n tmp.push_back(t);\n }\n return solve(tmp, next) + (v.size() - tmp.size());\n }\n}\n\nint main() {\n while(1) {\n int w,h;\n cin>>w>>h;\n if (!w) break;\n vector<vector<int>> t(h, vector<int>(w));\n REP(i,h)REP(j,w) cin>>t[i][j];\n REP(i,h)REP(j,w) {\n int m=min(h-i, w-j);\n FOR(k,1,m+1) {\n bool ok = true;\n REP(p,k)REP(q,k) {\n if (t[i+p][j+q]==0) ok=false;\n }\n if (ok) t[i][j] = k;\n }\n }\n vector<vector<bool>> maxi(h, vector<bool>(w, true));\n REP(i,h)REP(j,w) {\n if (t[i][j] == 0) maxi[i][j] = false;\n REP(p,i+1)REP(q,j+1) {\n if (p==i && q==j) continue;\n int d=max(i-p,j-q);\n if (t[p][q] >= t[i][j] + d) maxi[i][j] = false;\n }\n }\n vector<bitset<100>> v;\n REP(i,h)REP(j,w) {\n if (maxi[i][j]) {\n bitset<100> b;\n REP(p,t[i][j])REP(q,t[i][j]) {\n b[(i+p)*10+(j+q)] = true;\n }\n v.push_back(b);\n }\n }\n bitset<100> rem;\n REP(i,h)REP(j,w) {\n if (t[i][j]) rem[i*10+j] = true;\n }\n cout << solve(v, rem) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 750, "memory_kb": 3064, "score_of_the_acc": -0.7859, "final_rank": 18 }, { "submission_id": "aoj_1128_3717719", "code_snippet": "#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<ciso646>\n#include<utility>\n#include<stack>\n#include<bitset>\n#include<map>\n#include<numeric>\n#include<unordered_map>\nusing namespace std;\ntypedef long long ll;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define stop char nyaa;cin>>nyaa;\nconst ll mod = 1000000007;\nconst long double eps = 1e-8;\ntypedef pair<ll, ll> LP;\n\n#define int short int\ntypedef pair<int, int> P;\n\ntypedef long double ld;\n\nint h, w;\n\ntypedef pair<vector<int>, P> speP;\n\nvoid solve() {\n\tvector<vector<int>> v(h),sz;\n\tmap<speP, bool> mp;\n\tsz.resize(h);\n\trep(i, h) {\n\t\tv[i].resize(w); sz[i].resize(w,0);\n\t\trep(j, w)cin >> v[i][j];\n\t}\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tif (v[i][j] == 0)continue;\n\t\t\trep1(k, 11) {\n\t\t\t\tbool f = true;\n\t\t\t\tRep(x, i, i + k) {\n\t\t\t\t\tRep(y, j, j + k) {\n\t\t\t\t\t\tif (x >= h || y >= w) {\n\t\t\t\t\t\t\tf = false; break;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tif (v[x][y] == 0) {\n\t\t\t\t\t\t\tf = false; break;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (f) {\n\t\t\t\t\tsz[i][j] = k;\n\t\t\t\t}\n\t\t\t\telse break;\n\t\t\t}\n\t\t}\n\t}\n\tvector<int> sta;\n\trep(i, h)rep(j, w)sta.push_back(v[i][j]);\n\tdeque<speP> q;\n\tmap<speP, int> ans;\n\tq.push_back({ sta,{0,0} }); ans[{sta, { 0,0 }}] = 0; mp[{sta, { 0,0 }}] = true;\n\twhile (!q.empty()) {\n\t\t\tspeP p = q.front(); q.pop_front();\n\t\t\tif (p.second == P{ h,0 }) {\n\t\t\t\tcout << ans[p] << endl; return;\n\t\t\t}\n\t\t\tvector<int> &v = p.first;\n\t\t\tint& x = p.second.first, y = p.second.second;\n\t\t\t//cout << x << \" \" << y << endl;\n\t\t\tint nd = ans[p];\n\t\t\tint nx = x, ny = y + 1;\n\t\t\tif (ny == w) {\n\t\t\t\tnx++; ny = 0;\n\t\t\t}\n\t\t\t\n\t\t\tspeP nex; nex.second = { nx,ny };\n\t\t\tif (v[x*w+y] == 0) {\n\t\t\t\t//cout << nx << \" \" << ny << endl;\n\t\t\t\tnex.first = v;\n\t\t\t\tif (!mp[nex]) {\n\t\t\t\t\tmp[nex] = true;\n\t\t\t\t\tans[nex] = nd;\n\t\t\t\t\tq.push_front(nex);\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tif (nd < ans[nex]) {\n\t\t\t\t\t\tans[nex] = nd;\n\t\t\t\t\t\tq.push_front(nex);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\telse if (v[x*w+y] == 1) {\n\t\t\t\tint len = sz[x][y];\n\t\t\t\tRep(i, x, x + len) {\n\t\t\t\t\tRep(j, y, y + len) {\n\t\t\t\t\t\tv[i*w+j] = 2;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tnex.first = v;\n\t\t\t\tif (!mp[nex]) {\n\t\t\t\t\tmp[nex] = true;\n\t\t\t\t\tans[nex] = nd + 1;\n\t\t\t\t\tq.push_back(nex);\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\t//non\n\t\t\t\tnex.first = v;\n\t\t\t\tif (!mp[nex]) {\n\t\t\t\t\tmp[nex] = true;\n\t\t\t\t\tans[nex] = nd;\n\t\t\t\t\tq.push_front(nex);\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tif (nd < ans[nex]) {\n\t\t\t\t\t\tans[nex] = nd;\n\t\t\t\t\t\tq.push_front(nex);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tbool exi = false;\n\t\t\t\tint len = sz[x][y];\n\t\t\t\tRep(i, x, x + len) {\n\t\t\t\t\tRep(j, y, y + len) {\n\t\t\t\t\t\tif (v[i*w+j] != 2)exi = true;\n\t\t\t\t\t\tv[i*w+j] = 2;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (exi) {\n\t\t\t\t\tnex.first = v;\n\t\t\t\t\tif (!mp[nex]) {\n\t\t\t\t\t\tmp[nex] = true;\n\t\t\t\t\t\tans[nex] = nd+1;\n\t\t\t\t\t\tq.push_back(nex);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t}\n\t//cout << dfs(v, 0, 0) << endl;\n}\nsigned main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\t//string s = \"-0=0\";\n\t//cout << valid(s) << endl;\n\t//cout << fixed << setprecision(10);\n\twhile (cin >> w >> h, w) {\n\t\tsolve();\n\t\t//cout << \"end\" << endl;\n\t}\n\t//solve();\n\t//stop\n\t\treturn 0;\n}", "accuracy": 1, "time_ms": 380, "memory_kb": 7612, "score_of_the_acc": -1.3895, "final_rank": 20 }, { "submission_id": "aoj_1128_3656702", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cstdio>\n#include <set>\n#include <cstring>\n#include <queue>\n#include <map>\n#include <list>\n#include <cmath>\n#include <iomanip>\n#define INF 0x3f3f3f3f\n#define EPS 10e-5\n\ntypedef long long ll;\nconst int dx[]={-1,0,0,1,0},dy[]={0,1,-1,0,0};\nusing namespace std;\nint w,h,ecnt;\nint mps[10][10]; // record used square\nint cnts[10][10][2];// record the square size\nint scts[10][10];\nbool badc[10][10];\nint upbound,bcnt,mxsqus,res;\nbool reach,needf[10][10];\n\nint vps[250];\nint vsct[250][250],vl[250];\n\nvoid dfs(int now,int cost){\n\n if(ecnt==0) {\n if(cost==res)\n reach = true;\n upbound = min(upbound,cost);\n return;\n }\n\n if(cost+round(1.0*ecnt/mxsqus)>res||reach) return;\n\n if(now==bcnt) return;\n\n bool cover = false;\n int bs = vl[now],*vct=vsct[now];\n\n for(int i=0;i<bs;++i){\n if(vps[vct[i]]==0){\n cover = true;break;\n }\n }\n\n if(!cover) {\n return dfs(now+1,cost);\n }\n\n for(int i=0;i<bs;++i){\n if(++vps[vct[i]]==1) --ecnt;\n }\n dfs(now+1,cost+1);\n for(int i=0;i<bs;++i){\n if(--vps[vct[i]]==0) ++ecnt;\n }\n\n if(vps[vsct[now][0]]==0) return;\n dfs(now+1,cost);\n}\n\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(0);cout.tie(0);\n while(scanf(\"%d%d\",&w,&h)){\n if(w==0&&h==0)break;\n memset(mps,0,sizeof(mps));\n memset(cnts,0,sizeof(cnts));\n memset(badc,0,sizeof(badc));\n memset(needf,0,sizeof(needf));\n memset(vl,0,sizeof(vl));\n\n ecnt = mxsqus = 0;\n int tmp;\n for(int i=0;i<h;++i)\n for(int j=0;j<w;++j){\n scanf(\"%d\",&tmp);\n if(tmp) {\n mps[i][j] = 1;++ecnt;\n needf[i][j] = true;\n }\n }\n if(ecnt==0){\n printf(\"0\\n\");\n continue;\n }\n for(int i=0;i<w;++i){\n int last = 0;\n for(int j=h-1;j>=0;--j){\n if(mps[j][i]) cnts[j][i][1] = ++last;\n else last = 0;\n }\n }\n for(int i=0;i<h;++i)\n {\n int last = 0;\n for(int j=w-1;j>=0;--j){\n if(mps[i][j]) cnts[i][j][0] = ++last;\n else last = 0;\n }\n }\n\n for(int i=0;i<h;++i)\n for(int j=0;j<w;++j)\n {\n int k=j,last = INF;\n for(;k<w;++k){\n last = min(cnts[i][k][1],last);\n if(k+1-j>last) break;\n }\n mxsqus = max(scts[i][j] = k-j,mxsqus);\n }\n mxsqus*=mxsqus;\n bcnt = 0;\n\n for(int i=0;i<h;++i)\n for(int j=0;j<w;++j){\n if(badc[i][j]) continue;\n for(int i2=0;i2<scts[i][j];++i2){\n for(int j2=0;j2<scts[i][j];++j2){\n if(i2==0&&j2==0) continue;\n if(scts[i+i2][j+j2]<=min(scts[i][j]-i2,scts[i][j]-j2)){\n badc[i+i2][j+j2] = true;\n }\n }\n }\n }\n\n for(int i=0;i<h;++i){\n for(int j=0;j<w;++j){\n if(!badc[i][j]){\n for(int i2=0;i2<scts[i][j];++i2){\n for(int j2=0;j2<scts[i][j];++j2){\n vsct[bcnt][vl[bcnt]++] = (i+i2)*w+j+j2;\n }\n }\n bcnt++;\n }\n }\n }\n\n memset(mps,0,sizeof(mps));\n upbound = INF;\n res = ecnt/mxsqus;reach = false;\n while(!reach&&res!=upbound){\n dfs(0,0);\n ++res;\n }\n printf(\"%d\\n\",upbound);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 510, "memory_kb": 3452, "score_of_the_acc": -0.618, "final_rank": 17 }, { "submission_id": "aoj_1128_3159345", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))\n#define all(x) (x).begin(),(x).end()\n#define pb push_back\n#define fi first\n#define se second\n#define dbg(x) cout<<#x\" = \"<<((x))<<endl\ntemplate<class T,class U> ostream& operator<<(ostream& o, const pair<T,U> &p){o<<\"(\"<<p.fi<<\",\"<<p.se<<\")\";return o;}\ntemplate<class T> ostream& operator<<(ostream& o, const vector<T> &v){o<<\"[\";for(T t:v){o<<t<<\",\";}o<<\"]\";return o;}\n\nconst int N = 10;\nconst int INF = 19191919;\n\nint w,h;\n\nint p[N][N];\nint sq[N][N];\nint need[N][N];\nint ct[N][N];\n\nbool can_place(int y, int x, int sz){\n for(int i=y; i<y+sz; ++i)for(int j=x; j<x+sz; ++j)if(!p[i][j]) return false;\n return true;\n}\n\nint check_need(int y, int x){\n int LY = y, RY = y+sq[y][x];\n int LX = x, RX = x+sq[y][x];\n rep(i,h)rep(j,w){\n if(i==y && j==x) continue;\n int ly = i, ry = i+sq[i][j];\n int lx = j, rx = j+sq[i][j];\n if(ly<=LY && RY<=ry && lx<=LX && RX<=rx) return 0;\n }\n return 1;\n}\n\nint ans;\nint now;\nbool ret;\nvoid dfs(int y, int x){\n if(y==h-1 && x==w-1){\n rep(i,h)rep(j,w){\n if(p[i][j]){\n if(!ct[i][j]) return;\n }\n else{\n if(ct[i][j]) return;\n }\n }\n ret = true;\n return;\n }\n\n int ny = y, nx = x+1;\n if(nx==w){\n ++ny;\n nx = 0;\n }\n\n if(!need[y][x]) dfs(ny,nx);\n else{\n if(!ct[y][x]){\n for(int i=y; i<y+sq[y][x]; ++i)for(int j=x; j<x+sq[y][x]; ++j) ++ct[i][j];\n if(now<ans){\n ++now;\n dfs(ny,nx);\n --now;\n }\n for(int i=y; i<y+sq[y][x]; ++i)for(int j=x; j<x+sq[y][x]; ++j) --ct[i][j];\n }\n else{\n dfs(ny,nx);\n if(ret) return;\n\n // bool worth = false;\n // for(int i=y; i<y+sq[y][x]; ++i)for(int j=x; j<x+sq[y][x]; ++j){\n // if(ct[i][j]==0) worth = true;\n // }\n\n for(int i=y; i<y+sq[y][x]; ++i)for(int j=x; j<x+sq[y][x]; ++j) ++ct[i][j];\n if(now<ans){\n ++now;\n dfs(ny,nx);\n --now;\n }\n for(int i=y; i<y+sq[y][x]; ++i)for(int j=x; j<x+sq[y][x]; ++j) --ct[i][j];\n }\n }\n}\n\nint main(){\n while(scanf(\" %d %d\", &w, &h),w){\n rep(i,h)rep(j,w) scanf(\" %d\", &p[i][j]);\n\n memset(sq,0,sizeof(sq));\n rep(i,h)rep(j,w)if(p[i][j]){\n for(int k=min(w-j,h-i); k>=1; --k){\n if(can_place(i,j,k)){\n sq[i][j] = k;\n break;\n }\n }\n }\n\n memset(need,0,sizeof(need));\n rep(i,h)rep(j,w)if(p[i][j]){\n need[i][j] = check_need(i,j);\n }\n\n memset(ct,0,sizeof(ct));\n int must = 0;\n vector<pair<int,int>> ppp;\n rep(i,h)rep(j,w){\n if(!need[i][j]) continue;\n\n bool flg = false;\n for(int y=i; y<i+sq[i][j]; ++y)for(int x=j; x<j+sq[i][j]; ++x){\n int covered = 0;\n rep(li,h)rep(lj,w){\n if(!need[li][lj]) continue;\n\n if(li<=y && y<li+sq[li][lj] && lj<=x && x<lj+sq[li][lj]) ++covered;\n }\n if(covered == 1){\n flg = true;\n break;\n }\n }\n\n if(flg){\n ppp.pb({i,j});\n ++must;\n for(int y=i; y<i+sq[i][j]; ++y)for(int x=j; x<j+sq[i][j]; ++x) ++ct[y][x];\n }\n }\n for(const auto &pp:ppp) need[pp.fi][pp.se] = 0;\n\n // rep(i,h){\n // rep(j,w) printf(\" %d\", need[i][j]);\n // puts(\"\");\n // }\n\n ans = must;\n while(1){\n // dbg(ans);\n ret = false;\n now = must;\n dfs(0,0);\n if(ret) break;\n ++ans;\n }\n printf(\"%d\\n\",ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3224, "score_of_the_acc": -0.1472, "final_rank": 3 }, { "submission_id": "aoj_1128_2983160", "code_snippet": "#include <bits/stdc++.h>\n#define r(i,n) for(int i=0;i<n;i++)\nusing namespace std;\n\nint w,h,n,A[11][11],ans,cnt;\nbitset<100> B[11][11],p;\n\nvoid dfs(int d,bitset<100> s,int sco){\n if(d==n){\n ans=min(ans,sco);\n return;\n }\n cnt++;\n if(cnt>=19000000)return;\n if(ans<=sco)return;\n if(!A[d/w][d%w])dfs(d+1,s,sco);\n else{\n int y=d/w;\n int x=d%w;\n if((B[y][x]&s).any()){\n p&=0;\n p.set(y*10+x);//(y*100+x);\n if(!(s&p).any())dfs(d+1,s,sco);\n dfs(d+1,(B[y][x]|s)^B[y][x],sco+1);\n }\n else dfs(d+1,s,sco);\n }\n}\n\nint main(){\n while(cin>>w>>h,w){\n memset(A,0,sizeof(A));\n r(i,11)r(j,11)B[i][j]&=0;\n n=h*w;\n bitset<100> b;\n r(i,h)r(j,w)cin>>A[i][j];\n r(i,h)r(j,w)if(A[i][j]){\n int sum=1;\n for(;;sum++){\n int f=0;\n for(int y=i;y<i+sum;y++){\n for(int x=j;x<j+sum;x++){\n if(A[y][x]==0)f++;\n }\n }\n if(f){\n sum--;\n break;\n }\n }\n bitset<100>tmp;\n for(int y=i,k=0;k<sum;k++,y++){\n for(int x=j,l=0;l<sum;l++,x++){\n tmp.set(y*10+x);\n }\n }\n b.set(i*10+j);\n B[i][j]=tmp;\n }\n ans=100;\n cnt=0;\n dfs(0,b,0);\n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 3076, "score_of_the_acc": -0.4201, "final_rank": 8 }, { "submission_id": "aoj_1128_2983157", "code_snippet": "#include <bits/stdc++.h>\n#define r(i,n) for(int i=0;i<n;i++)\nusing namespace std;\n\nint w,h,n,A[11][11],ans,cnt;\nbitset<100> B[11][11],p;\n\nvoid dfs(int d,bitset<100> s,int sco){\n if(d==n){\n ans=min(ans,sco);\n return;\n }\n cnt++;\n if(cnt>=20000000)return;\n if(ans<=sco)return;\n if(!A[d/w][d%w])dfs(d+1,s,sco);\n else{\n int y=d/w;\n int x=d%w;\n if((B[y][x]&s).any()){\n p&=0;\n p.set(y*10+x);//(y*100+x);\n if(!(s&p).any())dfs(d+1,s,sco);\n dfs(d+1,(B[y][x]|s)^B[y][x],sco+1);\n }\n else dfs(d+1,s,sco);\n }\n}\n\nint main(){\n while(cin>>w>>h,w){\n memset(A,0,sizeof(A));\n r(i,11)r(j,11)B[i][j]&=0;\n n=h*w;\n bitset<100> b;\n r(i,h)r(j,w)cin>>A[i][j];\n r(i,h)r(j,w)if(A[i][j]){\n int sum=1;\n for(;;sum++){\n int f=0;\n for(int y=i;y<i+sum;y++){\n for(int x=j;x<j+sum;x++){\n if(A[y][x]==0)f++;\n }\n }\n if(f){\n sum--;\n break;\n }\n }\n bitset<100>tmp;\n for(int y=i,k=0;k<sum;k++,y++){\n for(int x=j,l=0;l<sum;l++,x++){\n tmp.set(y*10+x);\n }\n }\n b.set(i*10+j);\n B[i][j]=tmp;\n }\n ans=100;\n cnt=0;\n dfs(0,b,0);\n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 3056, "score_of_the_acc": -0.4368, "final_rank": 9 }, { "submission_id": "aoj_1128_2983118", "code_snippet": "#include <bits/stdc++.h>\n#define r(i,n) for(int i=0;i<n;i++)\nusing namespace std;\n\nint w,h,n,A[11][11],ans,cnt;\nbitset<100> B[11][11];\n\nvoid dfs(int d,bitset<100> s,int sco){\n if(d==n){\n ans=min(ans,sco);\n return;\n }\n cnt++;\n if(cnt>=30000000)return;\n if(ans<=sco)return;\n if(!A[d/w][d%w])dfs(d+1,s,sco);\n else{\n int y=d/w;\n int x=d%w;\n if((B[y][x]&s).any()){\n bitset<100>p;\n p.set(y*10+x);//(y*100+x);\n if(!(s&p).any())dfs(d+1,s,sco);\n dfs(d+1,(B[y][x]|s)^B[y][x],sco+1);\n }\n else dfs(d+1,s,sco);\n }\n}\n\nint main(){\n while(cin>>w>>h,w){\n memset(A,0,sizeof(A));\n r(i,11)r(j,11)B[i][j]&=0;\n n=h*w;\n bitset<100> b;\n r(i,h)r(j,w)cin>>A[i][j];\n r(i,h)r(j,w)if(A[i][j]){\n int sum=1;\n for(;;sum++){\n int f=0;\n for(int y=i;y<i+sum;y++){\n for(int x=j;x<j+sum;x++){\n if(A[y][x]==0)f++;\n }\n }\n if(f){\n sum--;\n break;\n }\n }\n bitset<100>tmp;\n for(int y=i,k=0;k<sum;k++,y++){\n for(int x=j,l=0;l<sum;l++,x++){\n tmp.set(y*10+x);\n }\n }\n b.set(i*10+j);\n B[i][j]=tmp;\n }\n ans=100;\n cnt=0;\n dfs(0,b,0);\n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 550, "memory_kb": 3100, "score_of_the_acc": -0.5833, "final_rank": 14 }, { "submission_id": "aoj_1128_2941000", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <cstring>\n\n#include <iostream>\n#include <complex>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n#include <unordered_map>\n#include <unordered_set>\n\n#include <random>\n#include <functional>\n#include <cassert>\n\ntypedef long long ll;\nusing namespace std;\n\n#define debug(x) cerr << __LINE__ << \" : \" << #x << \" = \" << (x) << endl;\n\n#define mod 1000000007 //1e9+7(prime number)\n#define INF 1000000000 //1e9\n#define LLINF 2000000000000000000LL //2e18\n#define SIZE 11\n\n#define P3(a,b,c) make_pair(make_pair(a,b),c)\n\nint h, w;\nint t[SIZE][SIZE], t2[SIZE][SIZE];\nint max_size[11][11] = {};\nint covered[11][11] = {};\nmap<pair<pair<ll,ll>,int>,int> visited;\n\nint ans;\n\nvoid dfs(int y, int x, int counter = 0, ll hash = 0, ll hash2 = 0){\n //debug(ans);\n int diff[11][11] = {};\n if(ans <= counter) return;\n auto it = visited.find(P3(hash,hash2,y*w+x));\n if(it != visited.end() && it->second <= counter) return;\n \n if(y == h){\n ans = min(ans, counter);\n return;\n }\n\n if(max_size[y][x] == 0 || covered[y][x])\n dfs(y + (x == w-1), (x + 1)%w, counter, hash, hash2);\n \n if(max_size[y][x] != 0){\n ll newhash = hash, newhash2 = hash2;\n int diffcounter = 0;\n for(int i=0;i<max_size[y][x];i++)\n for(int j=0;j<max_size[y][x];j++)\n if(covered[y+i][x+j] == 0){\n diff[y+i][x+j] = covered[y+i][x+j] = 1;\n newhash ^= t[y+i][x+j];\n newhash2 ^= t2[y+i][x+j];\n diffcounter++;\n }\n\n if(diffcounter)\n dfs(y + (x == w-1), (x + 1)%w, counter+1, newhash, newhash2);\n\n for(int i=0;i<max_size[y][x];i++)\n for(int j=0;j<max_size[y][x];j++)\n if(diff[y+i][x+j] == 1){\n covered[y+i][x+j] = 0;\n }\n }\n \n visited[P3(hash,hash2,y*w+x)] = counter;\n}\n\nbool solve(){\n int sp[11][11] = {};\n int p[11][11];\n //debug(clock());\n \n scanf(\"%d%d\", &w, &h);\n\n if(h == 0) return false;\n\n\n for(int i=0;i<h;i++){\n for(int j=0;j<w;j++){\n scanf(\"%d\", p[i]+j);\n sp[i][j] = p[i][j];\n }\n }\n\n for(int i=h;i>0;i--)\n for(int j=0;j<=w;j++)\n sp[i-1][j] += sp[i][j];\n\n for(int i=0;i<=h;i++)\n for(int j=w;j>0;j--)\n sp[i][j-1] += sp[i][j];\n\n\n for(int i=0;i<h;i++){\n for(int j=0;j<w;j++){\n int p = min(h-i, w-j);\n max_size[i][j] = 0;\n for(int k=1;k<=p;k++){\n if(sp[i][j] + sp[i+k][j+k] - sp[i+k][j] - sp[i][j+k] == k*k) max_size[i][j] = k;\n //debug(sp[i][j] + sp[i+k][j+k] - sp[i+k][j] - sp[i][j+k]);\n }\n //debug(max_size[i][j]);\n }\n }\n\n //debug(clock());\n\n visited = map<pair<pair<ll,ll>,int>,int >();\n ans = INF;\n dfs(0,0,0,0,0);\n printf(\"%d\\n\", ans);\n\n return true;\n}\n\nint main(){\n std::random_device rd;\n for(int i=0;i<10;i++){\n for(int j=0;j<10;j++){\n t[i][j] = ((ll)rd() << 32) + rd(); \n t2[i][j] = ((ll)rd() << 32) + rd(); \n }\n }\n\n //debug(clock());\n \n while(solve());\n \n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3936, "score_of_the_acc": -0.229, "final_rank": 5 }, { "submission_id": "aoj_1128_2859481", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <tuple>\nusing namespace std;\n\nstruct State {\n\tint a[10][10];\n};\n\nchar c[10][10]; int p[10][10], H, W, mindep, cnts;\n\nint range(int sx, int sy, int gx, int gy) {\n\tint cnt = 0;\n\tfor (int i = sx; i < gx; i++) {\n\t\tfor (int j = sy; j < gy; j++) {\n\t\t\tif (c[i][j] == '0') cnt++;\n\t\t}\n\t}\n\treturn cnt;\n}\nint range2(int sx, int sy, int gx, int gy, State G) {\n\tint cnt = 0;\n\tfor (int i = sx; i < gx; i++) { if (G.a[i][sy] == 0) cnt++; }\n\tfor (int i = sy; i < gy; i++) { if (G.a[sx][i] == 0) cnt++; }\n\treturn cnt;\n}\n\nState nurie(State P, int cx, int cy) {\n\tfor (int i = cx; i < cx + p[cx][cy]; i++) {\n\t\tfor (int j = cy; j < cy + p[cx][cy]; j++) P.a[i][j] = 1;\n\t}\n\treturn P;\n}\n\nlong long hash_value(State I) {\n\tlong long mod = 2555555555555555555LL, II = 0, J = 1;\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tif (I.a[i][j] == 1) II += J; J *= 2;\n\t\t\tif (II >= mod) II -= mod;\n\t\t\tif (J >= mod) J -= mod;\n\t\t}\n\t}\n\treturn II;\n}\n\nmap<tuple<int, int, int, long long>, int>M;\n\nvoid dfs(int cx, int cy, int depth, State S) {\n\tlong long K = hash_value(S);\n\tif (M[make_tuple(cx, cy, depth, K)] == 1) return;\n\tM[make_tuple(cx, cy, depth, K)] = 1;\n\tcnts++;\n\tif (depth == mindep) return;\n\tif (cx == H) {\n\t\tmindep = min(mindep, depth);\n\t\treturn;\n\t}\n\tint nx = cx, ny = cy + 1; if (ny == W) { ny = 0; nx++; }\n\tif (c[cx][cy] == '0') {\n\t\tdfs(nx, ny, depth, S);\n\t}\n\telse {\n\t\tif (S.a[cx][cy] == 0) {\n\t\t\tState V = nurie(S, cx, cy);\n\t\t\tdfs(nx, ny, depth + 1, V);\n\t\t}\n\t\telse if (range2(cx, cy, cx + p[cx][cy], cy + p[cx][cy], S) == 0) {\n\t\t\tdfs(nx, ny, depth, S);\n\t\t}\n\t\telse {\n\t\t\tdfs(nx, ny, depth, S);\n\t\t\tState V = nurie(S, cx, cy);\n\t\t\tdfs(nx, ny, depth + 1, V);\n\t\t}\n\t}\n}\n\nint main() {\n\twhile (true) {\n\t\tcin >> W >> H; M.clear(); mindep = (1 << 30); if (H == 0 && W == 0) break;\n\t\tfor (int i = 0; i < H; i++) {\n\t\t\tfor (int j = 0; j < W; j++) cin >> c[i][j];\n\t\t}\n\t\tfor (int i = 0; i < H; i++) {\n\t\t\tfor (int j = 0; j < W; j++) {\n\t\t\t\tfor (int k = 1; k <= min(H - i, W - j); k++) {\n\t\t\t\t\tif (range(i, j, i + k, j + k) >= 1) break;\n\t\t\t\t\tp[i][j] = k;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tState S; for (int i = 0; i < 10; i++) { for (int j = 0; j < 10; j++) S.a[i][j] = 0; }\n\t\tdfs(0, 0, 0, S);\n\t\tcout << mindep << endl;\n\t}\n\t//cout << \"Totalcount : \" << cnts << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 5228, "score_of_the_acc": -0.5953, "final_rank": 15 }, { "submission_id": "aoj_1128_2808135", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int INF = 1e9;\n\nint w, h;\nint A[10][10], B[10][10], used[10][10][10][10];\n\nint update(int y, int x){\n \n if( A[y][x] == 0 ) return 0;\n \n for(int i=y;i<h;i++)\n for(int j=x;j<w;j++) used[y][x][i][j] = 0;\n \n int L;\n \n for(int l=min(h-y-1, w-x-1);l>=0;l--){\n\n int flag = 1, cnt = 0;\n \n for(int i=y;i<=y+l;i++){\n \n for(int j=x;j<=x+l;j++){\n\t\n\tif( A[i][j] == 0 ) flag = 0;\n\tif( B[i][j] ) cnt++;\n\t\n\tif( !flag ) break;\n\t\n }\n \n if( !flag ) break;\n \n }\n \n if( flag ){\n \n if( cnt == 0 ) return 0;\n L = l;\n \n break;\n }\n \n }\n \n for(int i=y;i<=y+L;i++){\n for(int j=x;j<=x+L;j++){\n used[y][x][i][j] = B[i][j];\n B[i][j] = 0;\n }\n }\n \n return 1;\n}\n\nvoid add(int y, int x){\n \n for(int i=y;i<h;i++)\n for(int j=x;j<w;j++) B[i][j] += used[y][x][i][j];\n \n}\n\ntypedef unsigned long long ull;\n\nmap<ull,int> memo[10][10];\n\null Hash(int y, int x){\n \n ull res = 0;\n ull base = 1777771;\n \n for(int i=y;i<h;i++){\n int s = 0;\n if( i == y ) s = x;\n for(int j=s;j<w;j++){\n res = res * base + ( B[i][j] + 1 );\n }\n }\n \n return res;\n}\n\nint dfs(int y, int x){\n\n if( y == h - 1 && x == w - 1 ) return B[y][x];\n \n ull H = Hash( y, x );\n \n if( memo[y][x].count( H ) ) return memo[y][x][H];\n \n int res = INF;\n \n int ny = y, nx = x + 1;\n if( nx == w ) ny++, nx = 0;\n \n if( B[y][x] == 0 ) res = dfs( ny, nx );\n \n int r = update( y, x );\n \n res = min( res, r + dfs( ny, nx ) );\n \n add( y, x );\n \n return memo[y][x][H] = res;\n}\n\nsigned main(){\n\n while(1){\n \n cin>>w>>h;\n if( !w && !h ) break;\n \n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++) memo[i][j].clear();\n \n memset(used,0,sizeof(used));\n \n for(int i=0;i<h;i++){\n for(int j=0;j<w;j++){\n\tcin>>A[i][j];\n\tB[i][j] = A[i][j];\n }\n }\n \n cout << dfs( 0, 0 ) << endl;\n \n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3700, "score_of_the_acc": -0.1669, "final_rank": 4 }, { "submission_id": "aoj_1128_2674456", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\nInt w,h;\nInt cnt,sum,ans,tmp;\nInt a[20][20];\nInt us[20][20];\nInt dp[20][20];\nInt pn[20][20];\nvoid inc(Int y,Int x){\n cnt+=!us[y][x];\n us[y][x]++;\n}\nvoid dec(Int y,Int x){\n us[y][x]--;\n cnt-=!us[y][x];\n}\nvoid show(){\n cout<<cnt<<\" \"<<sum<<\":\"<<tmp<<endl;\n for(Int i=0;i<h;i++)\n for(Int j=0;j<w;j++)\n cout<<us[i][j]<<\" \\n\"[j==w-1];\n cout<<endl;\n}\n\nvoid dfs(Int y,Int x){\n Int ny=y+(x+1)/w,nx=(x+1)%w;\n if(ny==h||tmp+1>=ans) return;\n \n if(us[y][x]) dfs(ny,nx);\n if(!dp[y][x]) return;\n \n Int bc=cnt,k=dp[y][x];\n for(Int i=0;i<k;i++)\n for(Int j=0;j<k;j++)\n inc(y+i,x+j);\n\n if(bc<cnt){\n tmp++;\n if(cnt==sum) ans=min(ans,tmp);\n else if(tmp+1<ans) dfs(ny,nx);\n tmp--;\n }\n \n for(Int i=0;i<k;i++)\n for(Int j=0;j<k;j++)\n dec(y+i,x+j);\n}\n\nsigned main(){\n while(cin>>w>>h,w){\n \n cnt=sum=0;\n memset(a,0,sizeof(a));\n memset(us,0,sizeof(us));\n for(Int i=0;i<h;i++){\n for(Int j=0;j<w;j++){\n\tcin>>a[i][j];\n\tsum+=a[i][j];\n\tus[i][j]=!a[i][j];\n }\n }\n \n memset(dp,0,sizeof(dp));\n for(Int i=h-1;i>=0;i--)\n for(Int j=w-1;j>=0;j--)\n\tdp[i][j]=a[i][j]*(min({dp[i][j+1],dp[i+1][j],dp[i+1][j+1]})+1);\n \n for(Int i=h-1;i>=0;i--)\n for(Int j=w-1;j>=0;j--)\n\tif(dp[i][j]==dp[i+1][j+1]+1)\n\t dp[i+1][j+1]=0;\n \n memset(pn,0,sizeof(pn));\n for(Int i=0;i<h;i++)\n for(Int j=0;j<w;j++)\n\tfor(Int k=0;k<dp[i][j];k++)\n\t for(Int l=0;l<dp[i][j];l++)\n\t pn[i+k][j+l]++;\n\n Int pre=0;\n for(Int i=0;i<h;i++){\n for(Int j=0;j<w;j++){\n\tif(dp[i][j]&&pn[i][j]==1){\n\t pre++;\n\t for(Int k=0;k<dp[i][j];k++)\n\t for(Int l=0;l<dp[i][j];l++)\n\t inc(i+k,j+l);\n\t}\n }\n }\n\n if(0){\n cout<<pre<<\" \"<<sum<<endl;\n for(Int i=0;i<h;i++)\n\tfor(Int j=0;j<w;j++)\n\t cout<<dp[i][j]<<\" \\n\"[j==w-1];\n cout<<flush;\n\n show();\n }\n\n ans=w*h*(cnt!=sum);tmp=0;\n dfs(0,0);\n \n cout<<pre+ans<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 510, "memory_kb": 3032, "score_of_the_acc": -0.5263, "final_rank": 13 }, { "submission_id": "aoj_1128_2673071", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<cstring>\n#include<vector>\n#include<algorithm>\n#include<map>\n#define MAX_W 10\n#define INF 1E9\n\nusing namespace std;\ntypedef unsigned long long ull;\n\nconst ull B = 100000007;\nint w, h; \nint s[MAX_W][MAX_W]; //可延伸的最大正方形邊長\nint contain[MAX_W][MAX_W];\nbool same[MAX_W][MAX_W][MAX_W][MAX_W];\nint limit;\nint ct;\n\nstruct P{\n\tint x, y, size;\n\tP() {}\n\tP(int x, int y, int size) : x(x), y(y), size(size) {}\n\tbool operator < (const P& other) const{\n\t\treturn size < other.size;\n\t}\n};\nvoid init(vector<int>& f){\n\tmemset(contain, 0, sizeof(contain));\n\tmemset(same, false, sizeof(same));\n\tfor(int i = 0; i < h; i++){\n\t\tfor(int j = 0; j < w; j++){\n\t\t\ts[i][j] = (f[i] >> (w - 1 - j)) & 1;\n\t\t}\n\t}\n\tfor(int i = 0; i < h; i++){\n\t\tfor(int j = 0; j < w; j++){\n\t\t\tfor(int k = 0;; k++){\n\t\t\t\tbool ok = true;\n\t\t\t\tif(i + k < h && j + k < w){\n\t\t\t\t\tfor(int l = 0; ok && l <= k; l++){\n\t\t\t\t\t\tif(s[i + k][j + l] == 0 || s[i + l][j + k] == 0) ok = false;\n\t\t\t\t\t}\n\t\t\t\t}else{\n\t\t\t\t\tok = false;\n\t\t\t\t}\n\t\t\t\tif(!ok){\n\t\t\t\t\ts[i][j] = k;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor(int a = 0; a < s[i][j]; a++){\n\t\t\t\tfor(int b = 0; b < s[i][j]; b++){\n\t\t\t\t\tcontain[i + a][j + b]++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor(int a = 0; a < s[i][j] * s[i][j]; a++){\n\t\t\t\tint x1 = i + a / s[i][j], y1 = j + a % s[i][j];\n\t\t\t\tfor(int b = 0; b < s[i][j] * s[i][j]; b++){\n\t\t\t\t\tint x2 = i + b / s[i][j], y2 = j + b % s[i][j];\n\t\t\t\t\tsame[x1][y1][x2][y2] = same[x2][y2][x1][y1] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\nint hstar(vector<int> f){\n\t//選取盡量多的點,其中每個集合最多只能有一個點被選中\n\tvector<P> ps, X;\n\tfor(int i = 0; i < h; i++){\n\t\tfor(int j = 0; j < w; j++){\n\t\t\tif((f[i] >> (w - 1 - j)) & 1){\n\t\t\t\tps.push_back(P(i, j, contain[i][j]));\n\t\t\t}\n\t\t}\n\t}\n\tsort(ps.begin(), ps.end());\n\tfor(int i = 0; i < ps.size(); i++){\n\t\tbool ok = true;\n\t\tint x1 = ps[i].x, y1 = ps[i].y;\n\t\tfor(int j = 0; j < X.size() && ok; j++){\n\t\t\tint x2 = X[j].x, y2 = X[j].y;\n\t\t\tif(same[x1][y1][x2][y2]) ok = false;\n\t\t}\n\t\tif(ok) X.push_back(ps[i]);\n\t}\n\treturn X.size();\n}\nint dfs(int num, vector<int> f, int idx){\n\tif(num + hstar(f) > limit) return INF;\n\t\n\tct++;\n\tvector<int> reset(f.begin(), f.end());\n\tfor(; idx < w * h; idx++){\n\t\tint i = idx / w, j = idx % w;\n\t\tint k = s[i][j];\n\t\tif(k > 0){\n\t\t\tint tmp = ((1 << k) - 1) << (w - j - k), n = 0;\n\t\t\tfor(int m = 0; m < k; m++){\n\t\t\t\tif((f[i + m] & (~tmp)) == f[i + m]) n++;\n\t\t\t\tf[i + m] &= ~tmp;\n\t\t\t}\n\t\t\tif(n < k){\n\t\t\t\tif(dfs(num + 1, f, idx + 1) < INF) return num;\n\t\t\t}\n\t\t\tfor(int m = 0; m < k; m++) f[i + m] = reset[i + m];\n\t\t\tif(((f[i] >> (w - 1 - j)) & 1) && n < k) break;\n\t\t}\n\t}\t\n\tbool check = true;\n\tfor(int i = 0; i < h && check; i++) check &= (f[i] == 0);\n\treturn (check ? num : INF);\n}\nint solve(vector<int>& f){\n\tinit(f);\n\tct = 0;\n\tfor(limit = hstar(f);; limit++){\n\t\tif(dfs(0, f, 0) < INF) return limit;\n\t}\n}\nint main(){\n\twhile(cin >> w >> h && (w || h)){\n\t\tvector<int> f(h, 0);\n\t\tfor(int i = 0; i < h; i++){\n\t\t\tf[i] = 0;\n\t\t\tint a;\n\t\t\tfor(int j = 0; j < w; j++){\n\t\t\t\tcin >> a;\n\t\t\t\tf[i] = (f[i] << 1) | a;\n\t\t\t}\n\t\t}\n\t\tcout << solve(f) << endl;\n\t\t// cout << \"ct = \" << ct << \"\\n\\n\";\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3104, "score_of_the_acc": -0.0157, "final_rank": 2 }, { "submission_id": "aoj_1128_2673066", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<cstring>\n#include<vector>\n#include<algorithm>\n#include<unordered_map>\n#include<map>\n#define MAX_W 10\n#define INF 1E9\n\nusing namespace std;\ntypedef unsigned long long ull;\n\nconst ull B = 100000007;\nint w, h; \nint s[MAX_W][MAX_W]; //可延伸的最大正方形邊長\nint contain[MAX_W][MAX_W];\nbool same[MAX_W][MAX_W][MAX_W][MAX_W];\nint limit;\nint ct;\nunordered_map<ull, int> mp;\n\nstruct P{\n\tint x, y, size;\n\tP() {}\n\tP(int x, int y, int size) : x(x), y(y), size(size) {}\n\tbool operator < (const P& other) const{\n\t\treturn size < other.size;\n\t}\n};\nvoid show(vector<int>& cover){\n\tfor(int i = 0; i < h; i++){\n\t\tfor(int j = 0; j < w; j++){\n\t\t\tprintf(\"%d \", (cover[i] >> (w - 1 - j)) & 1);\n\t\t}\n\t\tcout << endl;\n\t}\n\tcout << endl;\n}\nvoid init(vector<int>& f){\n\tmemset(contain, 0, sizeof(contain));\n\tmemset(same, false, sizeof(same));\n\tfor(int i = 0; i < h; i++){\n\t\tfor(int j = 0; j < w; j++){\n\t\t\ts[i][j] = (f[i] >> (w - 1 - j)) & 1;\n\t\t}\n\t}\n\tfor(int i = 0; i < h; i++){\n\t\tfor(int j = 0; j < w; j++){\n\t\t\tfor(int k = 0;; k++){\n\t\t\t\tbool ok = true;\n\t\t\t\tif(i + k < h && j + k < w){\n\t\t\t\t\tfor(int l = 0; ok && l <= k; l++){\n\t\t\t\t\t\tif(s[i + k][j + l] == 0 || s[i + l][j + k] == 0) ok = false;\n\t\t\t\t\t}\n\t\t\t\t}else{\n\t\t\t\t\tok = false;\n\t\t\t\t}\n\t\t\t\tif(!ok){\n\t\t\t\t\ts[i][j] = k;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor(int a = 0; a < s[i][j]; a++){\n\t\t\t\tfor(int b = 0; b < s[i][j]; b++){\n\t\t\t\t\tcontain[i + a][j + b]++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor(int a = 0; a < s[i][j] * s[i][j]; a++){\n\t\t\t\tint x1 = i + a / s[i][j], y1 = j + a % s[i][j];\n\t\t\t\tfor(int b = 0; b < s[i][j] * s[i][j]; b++){\n\t\t\t\t\tint x2 = i + b / s[i][j], y2 = j + b % s[i][j];\n\t\t\t\t\tsame[x1][y1][x2][y2] = same[x2][y2][x1][y1] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\null calc_hash(vector<int>& f){\n\tull t = 0;\n\tfor(int i = 0; i < f.size(); i++){\n\t\tt = t * B + f[i];\n\t}\n\treturn t;\n}\nint greedy(vector<int> f){\n\tint res = 0;\n\tbool update;\n\tdo{\n\t\tupdate = false;\n\t\tint m_i, m_j, max = 0;\n\t\tfor(int i = 0; i < h; i++){\n\t\t\tfor(int j = 0; j < w; j++){\n\t\t\t\tif(s[i][j] > 0){\n\t\t\t\t\tint tmp = 0, m = ((1 << s[i][j]) - 1) << (w - j - s[i][j]);\n\t\t\t\t\tfor(int k = 0; k < s[i][j]; k++){\n\t\t\t\t\t\ttmp += __builtin_popcount(f[i + k] & m);\n\t\t\t\t\t}\n\t\t\t\t\tif(max < tmp){\n\t\t\t\t\t\tmax = tmp;\n\t\t\t\t\t\tm_i = i, m_j = j;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(max > 0){\n\t\t\tint m = ((1 << s[m_i][m_j]) - 1) << (w - m_j - s[m_i][m_j]);\n\t\t\tfor(int i = 0; i < s[m_i][m_j]; i++) f[m_i + i] &= ~m;\n\t\t\tres++;\n\t\t\tupdate = true;\n\t\t}\n\t}while(update);\n\treturn res;\n}\nint hstar(vector<int> f){\n\t//選取盡量多的點,其中每個集合最多只能有一個點被選中\n\tvector<P> ps, X;\n\tfor(int i = 0; i < h; i++){\n\t\tfor(int j = 0; j < w; j++){\n\t\t\tif((f[i] >> (w - 1 - j)) & 1){\n\t\t\t\tps.push_back(P(i, j, contain[i][j]));\n\t\t\t}\n\t\t}\n\t}\n\tsort(ps.begin(), ps.end());\n\tfor(int i = 0; i < ps.size(); i++){\n\t\tbool ok = true;\n\t\tint x1 = ps[i].x, y1 = ps[i].y;\n\t\tfor(int j = 0; j < X.size() && ok; j++){\n\t\t\tint x2 = X[j].x, y2 = X[j].y;\n\t\t\tif(same[x1][y1][x2][y2]) ok = false;\n\t\t}\n\t\tif(ok) X.push_back(ps[i]);\n\t}\n\treturn X.size();\n}\nint dfs(int num, vector<int> f, int idx){\n\tif(num + hstar(f) > limit) return INF;\n\t\n\t// printf(\"num = %2d hstar = %2d greedy = %2d\\n\", num, hstar(f), greedy(f));\n\t// ull t = calc_hash(f);\n\t// if(mp.find(t) != mp.end() && mp[t] <= num) return INF;\n\t// mp[t] = num;\n\tct++;\n\t// if(ct % 10000 == 0) cout << ct << endl;\n\t\n\tvector<int> reset(f.begin(), f.end());\n\tfor(; idx < w * h; idx++){\n\t\tint i = idx / w, j = idx % w;\n\t\tint k = s[i][j];\n\t\tif(k > 0){\n\t\t\tint tmp = ((1 << k) - 1) << (w - j - k), n = 0;\n\t\t\tfor(int m = 0; m < k; m++){\n\t\t\t\tif((f[i + m] & (~tmp)) == f[i + m]) n++;\n\t\t\t\tf[i + m] &= ~tmp;\n\t\t\t}\n\t\t\tif(n < k){\n\t\t\t\tif(dfs(num + 1, f, idx + 1) < INF) return num;\n\t\t\t}\n\t\t\t//f.assign(reset.begin(), reset.end());\n\t\t\tfor(int m = 0; m < k; m++) f[i + m] = reset[i + m];\n\t\t\tif(((f[i] >> (w - 1 - j)) & 1) && n < k) break;\n\t\t}\n\t}\t\n\tbool check = true;\n\tfor(int i = 0; i < h && check; i++) check &= (f[i] == 0);\n\treturn (check ? num : INF);\n}\nint solve(vector<int>& f){\n\tinit(f);\n\tct = 0;\n\tfor(limit = greedy(f);; limit--){\n\t\t// printf(\"limit = %d\\n\", limit);\n\t\tmp.clear();\n\t\tif(dfs(0, f, 0) == INF) return limit + 1;\n\t}\n}\nint main(){\n\twhile(cin >> w >> h && (w || h)){\n\t\tvector<int> f(h, 0);\n\t\tfor(int i = 0; i < h; i++){\n\t\t\tf[i] = 0;\n\t\t\tint a;\n\t\t\tfor(int j = 0; j < w; j++){\n\t\t\t\tcin >> a;\n\t\t\t\tf[i] = (f[i] << 1) | a;\n\t\t\t}\n\t\t}\n\t\tcout << solve(f) << endl;\n\t\t// cout << \"ct = \" << ct << \"\\n\\n\";\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3084, "score_of_the_acc": -0.0114, "final_rank": 1 }, { "submission_id": "aoj_1128_2662896", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\n#include <time.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\nstruct Info{\n short table[10][10],num;\n};\n\nint W,H,ans,POW[11];\nint first_table[10][10],max_size[10][10];\n\n\nbool rangeCheck(int row,int col){\n if(row >= 0 && row <= H-1 && col >= 0 && col <= W-1)return true;\n else{\n return false;\n }\n}\n\nvoid recursive(Info info,int base_row,int base_col){\n\n if(info.num == ans)return;\n\n if(base_row == H){\n ans = info.num;\n return;\n }\n\n if(info.table[base_row][base_col] == -1){\n\n if(base_col == W-1){\n recursive(info,base_row+1,0);\n }else{\n recursive(info,base_row,base_col+1);\n }\n return;\n }\n\n\n int new_num = 0;\n\tfor(int i = 0; i < max_size[base_row][base_col]; i++){\n\t\tfor(int k = 0; k < max_size[base_row][base_col]; k++){\n\t\t\tif(info.table[base_row+i][base_col+k] == 0){\n\t\t\t\tnew_num++;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(new_num != 0)break;\n\t}\n\n if(new_num == 0){\n\n if(base_col != W-1){\n recursive(info,base_row,base_col+1);\n }else{\n recursive(info,base_row+1,0);\n }\n }else{\n\n if(info.table[base_row][base_col] != 0){\n\n if(base_col != W-1){\n recursive(info,base_row,base_col+1);\n }else{\n recursive(info,base_row+1,0);\n }\n }\n\n for(int i = 0; i < max_size[base_row][base_col]; i++){\n for(int k = 0; k < max_size[base_row][base_col]; k++){\n info.table[base_row+i][base_col+k]++;\n }\n }\n\n int must_add = 0;\n bool FLG = false;\n\n for(int row = base_row; row <= base_row; row++){\n for(int col = base_col; col < W; col++){\n if(info.table[row][col] == 0 && first_table[row][col] > 1){\n FLG = true;\n goto SHISHIMARU;\n }\n }\n }\n\n for(int row = base_row+1; row < H; row++){\n for(int col = 0; col < W; col++){\n if(info.table[row][col] == 0 && first_table[row][col] > 1){\n FLG = true;\n goto SHISHIMARU;\n }\n }\n }\n\nSHISHIMARU:\n\n if(FLG)must_add++;\n\n info.num++;\n\n if(info.num+must_add < ans){\n if(base_col != W-1){\n recursive(info,base_row,base_col+1);\n }else{\n recursive(info,base_row+1,0);\n }\n }\n }\n}\n\n\nvoid func(){\n\n for(int row = 0; row < H; row++){\n for(int col = 0; col < W; col++){\n scanf(\"%d\",&first_table[row][col]);\n first_table[row][col] -= 1;\n }\n }\n\n bool FLG;\n int size;\n\n for(int row = 0; row < H; row++){\n for(int col = 0; col < W; col++){\n if(first_table[row][col] == -1){\n max_size[row][col] = 0;\n }else{\n size = 1;\n\n FLG = true;\n\n while(true){\n for(int i = 0; i < size; i++){\n for(int k = 0; k < size; k++){\n if(rangeCheck(row+i,col+k) == false || first_table[row+i][col+k] == -1){\n FLG = false;\n break;\n }\n }\n if(!FLG)break;\n }\n if(!FLG){\n size -= 1;\n break;\n }\n size++;\n }\n\n max_size[row][col] = size;\n\n for(int calc_size = 1; calc_size <= size; calc_size++){\n for(int i = 0; i < calc_size; i++){\n for(int k = 0; k < size; k++){\n first_table[row+i][col+k]++;\n }\n }\n }\n }\n }\n }\n\n Info start;\n start.num = 0;\n\n for(int row = 0; row < H; row++){\n for(int col = 0; col < W; col++){\n if(first_table[row][col] == -1){\n \tstart.table[row][col] = -1;\n }else{\n if(first_table[row][col] == 1){\n \t start.num++;\n \t start.table[row][col] = 1;\n }else{\n start.table[row][col] = 0;\n }\n }\n }\n }\n\n ans = BIG_NUM;\n\n recursive(start,0,0);\n\n printf(\"%d\\n\",ans);\n}\n\nint main(){\n\n for(int i = 0; i < 11; i++)POW[i] = pow(2,i);\n\n while(true){\n scanf(\"%d %d\",&W,&H);\n if(W == 0 && H == 0)break;\n\n func();\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 3352, "score_of_the_acc": -0.512, "final_rank": 12 } ]
aoj_1132_cpp
Problem D: Circle and Points You are given N points in the xy -plane. You have a circle of radius one and move it on the xy -plane, so as to enclose as many of the points as possible. Find how many points can be simultaneously enclosed at the maximum. A point is considered enclosed by a circle when it is inside or on the circle. Fig 1. Circle and Points Input The input consists of a series of data sets, followed by a single line only containing a single character '0', which indicates the end of the input. Each data set begins with a line containing an integer N , which indicates the number of points in the data set. It is followed by N lines describing the coordinates of the points. Each of the N lines has two decimal fractions X and Y , describing the x - and y -coordinates of a point, respectively. They are given with five digits after the decimal point. You may assume 1 <= N <= 300, 0.0 <= X <= 10.0, and 0.0 <= Y <= 10.0. No two points are closer than 0.0001. No two points in a data set are approximately at a distance of 2.0. More precisely, for any two points in a data set, the distance d between the two never satisfies 1.9999 <= d <= 2.0001. Finally, no three points in a data set are simultaneously very close to a single circle of radius one. More precisely, let P 1 , P 2 , and P 3 be any three points in a data set, and d 1 , d 2 , and d 3 the distances from an arbitrarily selected point in the xy -plane to each of them respectively. Then it never simultaneously holds that 0.9999 <= d i <= 1.0001 ( i = 1, 2, 3). Output For each data set, print a single line containing the maximum number of points in the data set that can be simultaneously enclosed by a circle of radius one. No other characters including leading and trailing spaces should be printed. Sample Input 3 6.47634 7.69628 5.16828 4.79915 6.69533 6.20378 6 7.15296 4.08328 6.50827 2.69466 5.91219 3.86661 5.29853 4.16097 6.10838 3.46039 6.34060 2.41599 8 7.90650 4.01746 4.10998 4.18354 4.67289 4.01887 6.33885 4.28388 4.98106 3.82728 5.12379 5.16473 7.84664 4.67693 4.02776 3.87990 20 6.65128 5.47490 6.42743 6.26189 6.35864 4.61611 6.59020 4.54228 4.43967 5.70059 4.38226 5.70536 5.50755 6.18163 7.41971 6.13668 6.71936 3.04496 5.61832 4.23857 5.99424 4.29328 5.60961 4.32998 6.82242 5.79683 5.44693 3.82724 6.70906 3.65736 7.89087 5.68000 6.23300 4.59530 5.92401 4.92329 6.24168 3.81389 6.22671 3.62210 0 Output for the Sample Input 2 5 5 11
[ { "submission_id": "aoj_1132_10853887", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nconst int N = 300;\ntypedef complex <double> point;\npoint a[N];\ndouble kc[N][N];\ndouble x[N],y[N];\nint n;\nint quetgoc(int i,double r,int n){\n vector<pair<double,bool> > goc;\n for(int j=0;j<n;j++){\n if(kc[i][j]<=2*r&&i!=j){\n double B=acos(kc[i][j]/(2*r));\n double A= arg(a[j]-a[i]);\n double alpha=A-B;\n double beta=A+B;\n goc.push_back(make_pair(alpha,true));\n goc.push_back(make_pair(beta,false));\n }\n }\n sort(goc.begin(),goc.end());\n int cnt=1,ans=1;\n vector<pair<double, bool> >::iterator it;\n for(it=goc.begin();it!=goc.end();++it){\n if((*it).second) cnt++;\n else cnt--;\n if(cnt>ans) ans=cnt;\n }\n return ans;\n}\nint maxpoint(point a[],int n,int r){\n for(int i=0;i<n-1;i++)\n for(int j=i+1;j<n;j++)\n kc[i][j]=kc[j][i]=abs(a[i]-a[j]);\n int ans=0;\n for(int i=0;i<n;i++)\n ans=max(ans,quetgoc(i,r,n));\n return ans;\n}\nsigned main()\n{\n// freopen(\"circleandpoints.inp\",\"r\",stdin);\n// freopen(\"circleandpoints.out\",\"w\",stdout);\n int t;\n while(cin>>t){\n if(t==0){break;return 0;}\n for(int i=0;i<t;i++) a[i]=0;\n for(int i=0;i<t;i++) cin>>x[i]>>y[i];\n for(int i=0;i<t;i++) a[i]=point(x[i],y[i]);\n double r=1.0000;\n cout << maxpoint(a,t, r)<<endl;\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 4488, "score_of_the_acc": -0.4077, "final_rank": 13 }, { "submission_id": "aoj_1132_10683730", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,n) for (long long i=0;i<(ll)n;i++)\n#define loop(i,m,n) for(long long i=m;i<=(ll)n;i++)\n#define vl vector<long long>\n#define vvl vector<vector<long long>>\n#define inf 4000000000000000000LL\n#define eps 0.000000001\n\n//2つの円の交点\nstruct point {\n\tdouble x,y;\n};\npair<point, point> circle_cross(point p1, double r1,point p2, double r2){\n double dx = p2.x - p1.x;\n double dy = p2.y - p1.y;\n double d = hypot(abs(dx),abs(dy)); // 2点間の距離\n\n // 交点なし:離れすぎ or 完全に内側\n if (d > r1 + r2 + eps || d + eps < abs(r1 - r2)) {\n return {{inf,inf},{inf,inf}};\n }\n\n // 円が同一(無限に交わる):対応が必要な場合記述\n if (d < eps && abs(r1 - r2) < eps) {}\n\n // 交点の中点とp1の距離\n double a = (r1*r1 - r2*r2 + d*d) / (2*d);\n\t\n\t// 交点の中点と交点の距離\n double h = sqrt(max(0.0, r1*r1 - a*a));\n\n\t//交点の中点\n double xm = p1.x + a * dx / d;\n double ym = p1.y + a * dy / d;\n\n // 円の中心同士の線分に対する、長さhの垂直線の変化量\n double hx = -dy * (h / d);\n double hy = dx * (h / d);\n\n double x3 = xm + hx;\n double y3 = ym + hy;\n double x4 = xm - hx;\n double y4 = ym - hy;\n\n return {{x3, y3}, {x4, y4}};\n}\n\nll solve(){\n\tll n;\n\tcin>>n;\n\tif(n==0)return 1;\n\tvector<point> p(n);\n\trep(i,n)cin>>p[i].x>>p[i].y;\n\n\t//調査対象\n\tvector<point> list;\n\trep(i,n)rep(j,i){\n\t\tpair<point,point> tmp=circle_cross(p[i],1,p[j],1);\n\t\tif(tmp.first.x==inf)continue;\n\t\tlist.push_back(tmp.first);\n\t\tlist.push_back(tmp.second);\n\t}\n\tll ans=1;\n\trep(i,list.size()){\n\t\tll tmp=0;\n\t\trep(j,n){\n\t\t\tif(eps+1>=(list[i].x-p[j].x)*(list[i].x-p[j].x)+(list[i].y-p[j].y)*(list[i].y-p[j].y))tmp++;\n\t\t}\n\t\tans=max(ans,tmp);\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}\n\nint main(){\n\twhile(solve()==0);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3976, "score_of_the_acc": -0.2493, "final_rank": 8 }, { "submission_id": "aoj_1132_10644945", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// 書きかけの幾何ライブラリ\n// バグがあるかも\n\nnamespace geometry {\n\nusing Real = long double;\nconstexpr Real eps = 1e-12;\nconstexpr Real PI = acosl(-1);\nconstexpr Real INF_REAL = numeric_limits<Real>::max();\n\nbool is_same(Real a, Real b) {\n return abs(a - b) < eps;\n}\n\nint sgn(Real a) {\n return is_same(a, 0) ? 0 : a > 0 ? 1 : -1;\n}\n\nstruct Point {\n Real x, y;\n constexpr Point() : Point(0, 0) {}\n constexpr Point(Real _x, Real _y) : x(_x), y(_y) {}\n constexpr Point(const pair<Real, Real> &p) : x(p.first), y(p.second) {}\n Point &operator+=(const Point &p) {\n x += p.x;\n y += p.y;\n return *this;\n }\n Point &operator-=(const Point &p) {\n x -= p.x;\n y -= p.y;\n return *this;\n }\n Point &operator*=(const Real &r) {\n x *= r;\n y *= r;\n return *this;\n }\n Point &operator/=(const Real &r) {\n assert(!is_same(r, 0));\n x /= r;\n y /= r;\n return *this;\n }\n Point operator+(const Point &p) const { return Point(*this) += p; }\n Point operator-(const Point &p) const { return Point(*this) -= p; }\n Point operator*(const Real &r) const { return Point(*this) *= r; }\n Point operator/(const Real &r) const { return Point(*this) /= r; }\n Point operator-() const { return Point() - *this; }\n bool operator==(const Point &p) const {\n return is_same(x, p.x) && is_same(y, p.y);\n }\n bool operator!=(const Point &p) const {\n return !is_same(x, p.x) || !is_same(y, p.y);\n }\n Point rotate(Real rad) const {\n Real c = cosl(rad), s = sinl(rad);\n Real tx = x * c - y * s;\n Real ty = x * s + y * c;\n return Point(tx, ty);\n }\n Point unit() const {\n return (*this) / metric();\n }\n Real Re() const { return x; }\n Real Im() const { return y; }\n Real norm() const { return x * x + y * y; }\n Real metric() const { return sqrtl(norm()); }\n Real arg() const { return atan2l(y, x); }\n Real arg(Point q1, Point q2) const {\n q1 -= *this, q2 -= *this;\n return abs(q1.arg() - q2.arg());\n }\n friend Point operator*(Real r, const Point &p) {\n return p * r;\n }\n friend Point operator/(Real r, const Point &p) {\n return p / r;\n }\n};\n\nReal Re(const Point &p) { return p.Re(); }\nReal Im(const Point &p) { return p.Im(); }\nReal dot(const Point &p, const Point &q) {\n return p.x * q.x + p.y * q.y;\n}\nReal cross(const Point &p, const Point &q) {\n return p.x * q.y - p.y * q.x;\n}\nReal norm(const Point &p) {\n return p.norm();\n}\nReal metric(const Point &p) {\n return p.metric();\n}\nReal arg(const Point &p) {\n return p.arg();\n}\n\nbool is_same(const Point &p, const Point &q) {\n return is_same(p.x, q.x) && is_same(p.y, q.y);\n}\n\nconstexpr Point INF_POINT = Point(INF_REAL, INF_REAL);\n\n// a を基準にした b と c の位置関係\nint ccw(const Point &a, const Point &b, const Point &c) {\n Point p = b - a, q = c - a;\n if (cross(p, q) > eps) return 1; // a, b, c の順で反時計回り\n if (cross(p, q) < -eps) return -1; // a, b, c の順で時計回り\n if (min(norm(p), norm(q)) < eps * eps) return 0; // a = c or b = c\n if (dot(p, q) < eps) return 2; // c, a, b の順で一直線\n if (norm(p) < norm(q)) return -2; // a, b, c の順で一直線\n return 0; // a, c, b の順で一直線\n}\n\n} // namespace geometry\n\nnamespace geometry {\n\nstruct Line {\n // Line : ax + by = c\n Real a, b, c;\n constexpr Line() = default;\n constexpr Line(Real _a, Real _b, Real _c) : a(_a), b(_b), c(_c) {}\n constexpr Line(const Point &p, const Point &q) : a(q.y - p.y), b(p.x - q.x), c(p.x * q.y - p.y * q.x) {}\n constexpr Line(Real _a, const Point &p) : a(_a), b(-1), c(_a * p.x - p.y) {}\n bool online(const Point &p) const {\n return is_same(a * p.x + b * p.y, c);\n }\n Real get_x(Real y) const {\n if (is_same(a, 0)) return INF_REAL;\n return (c - b * y) / a;\n }\n Real get_y(Real x) const {\n if (is_same(b, 0)) return INF_REAL;\n return (c - a * x) / b;\n }\n Line perpendicular(const Point &p) const {\n if (is_same(a, 0)) return Line(1, 0, p.x);\n if (is_same(0, b)) return Line(0, 1, p.y);\n return Line(b / a, p);\n }\n Point crossppoint(const Line &l) const {\n if (is_same(a * l.b, l.a * b)) return INF_POINT;\n Real d = a * l.b - l.a * b;\n return Point(l.b * c - b * l.c, l.c * a - c * l.a) / d;\n }\n Point projection(const Point &p) const {\n return crossppoint(perpendicular(p));\n }\n Point reflection(const Point &p) const {\n Point q = projection(p);\n return 2 * q - p;\n }\n Point unit() const {\n if (is_same(b, 0)) {\n return Point(0, 1);\n }\n Point p(0, get_y(0)), q(1, get_y(1));\n return (p - q) / metric(p - q);\n }\n bool is_orthogonal(const Line &l) const {\n return is_same(a * l.a + b * l.b, 0);\n }\n bool is_parallel(const Line &l) const {\n return is_same(a * l.b, l.a * b);\n }\n Real dist(const Point &p) const {\n Point q = projection(p);\n return metric(p - q);\n }\n};\n\nbool is_orthogonal(const Line &l1, const Line &l2) {\n return l1.is_orthogonal(l2);\n}\nbool is_parallel(const Line &l1, const Line &l2) {\n return l1.is_parallel(l2);\n}\nPoint crosspoint(const Line &l1, const Line &l2) {\n return l1.crossppoint(l2);\n}\n\n} // namespace geometry\n\nnamespace geometry {\n\n// { x in R^2 | |x - p| = r}\nstruct circle {\n Point p;\n Real r;\n circle() = default;\n circle(const Point _p, Real _r) : p(_p), r(_r) {}\n int count_common_tangent(const circle &c) const {\n Real d = metric(p - c.p);\n if (d > r + c.r + eps) return 4;\n if (is_same(d, r + c.r)) return 3;\n if (is_same(d, abs(r - c.r))) return 1;\n if (d < abs(r - c.r) - eps) return 0;\n return 2;\n }\n vector<Point> crosspoints(const Line &l) const {\n Real d = l.dist(p);\n if (d > r + eps) return {};\n Point q = l.projection(p);\n if (is_same(d, r)) {\n return {q};\n }\n Point e = l.unit();\n Real t = sqrtl(r * r - d * d);\n return {q - t * e, q + t * e};\n }\n vector<Point> crosspoints(const circle &c) const {\n int t = count_common_tangent(c);\n if (t == 0 || t == 4) return {};\n Real d = metric(p - c.p);\n if (t == 1) {\n if (c.r < r - eps) {\n return {p + (c.p - p) * (r / d)};\n } else {\n return {c.p + (p - c.p) * (c.r / d)};\n }\n } else if (t == 3) {\n geometry::Real s = r / (r + c.r);\n return {p + (c.p - p) * s};\n } else {\n geometry::Real la = 2 * (p.x - c.p.x);\n geometry::Real lb = 2 * (p.y - c.p.y);\n geometry::Real lc = (p.x + c.p.x) * (p.x - c.p.x) + (p.y + c.p.y) * (p.y - c.p.y) + (r + c.r) * (c.r - r);\n return crosspoints(Line(la, lb, lc));\n }\n }\n vector<Point> points_of_tangency(const Point &q) const {\n Real d = metric(p - q);\n if (d < r - eps) return {};\n if (is_same(d, r)) return {q};\n return crosspoints(circle(q, sqrtl(d * d - r * r)));\n }\n vector<Point> points_of_common_tangency(const circle &c) const {\n Real d = metric(p - c.p);\n if (is_same(d, 0)) return {};\n Point u = (c.p - p).unit();\n Point v = u.rotate(PI / 2);\n vector<Point> res;\n for (int s : {-1, 1}) {\n Real h = (r + s * c.r) / d;\n if (is_same(h * h, 1)) {\n res.push_back(p + (h > 0 ? u : -u) * r);\n } else if (1 - h * h > 0) {\n Point u2 = u * h, v2 = v * sqrtl(1 - h * h);\n res.push_back(p + (u2 + v2) * r);\n res.push_back(p + (u2 - v2) * r);\n }\n }\n return res;\n }\n};\n\n} // namespace geometry\nusing namespace geometry;\n\nbool solve() {\n int N;\n cin >> N;\n if (N == 0) return false;\n vector<circle> C(N);\n for (int i = 0; i < N; i++) {\n Real x, y;\n cin >> x >> y;\n C[i] = circle(Point(x, y), 1);\n }\n int ans = 0;\n for (int i = 0; i < N; i++) {\n auto p = C[i].p;\n int cnt = 0;\n for (int k = 0; k < N; k++) {\n if (metric(p - C[k].p) < 1 + eps) cnt++;\n }\n ans = max(ans, cnt);\n }\n for (int i = 0; i < N; i++) {\n for (int j = i + 1; j < N; j++) {\n for (auto p : C[i].crosspoints(C[j])) {\n int cnt = 0;\n for (int k = 0; k < N; k++) {\n if (metric(p - C[k].p) < 1 + eps) cnt++;\n }\n ans = max(ans, cnt);\n }\n }\n }\n cout << ans << '\\n';\n return true;\n}\n\nint main() {\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3712, "score_of_the_acc": -0.208, "final_rank": 5 }, { "submission_id": "aoj_1132_10474874", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing ull=unsigned long long;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define loop(n) for (int tjh = 0; tjh < (int)(n); tjh++)\nconstexpr int maxN=300;\nsigned main() {\n cin.tie(0)->sync_with_stdio(0);\n cout<<fixed<<setprecision(16);\n array<double,maxN>X,Y;\n for (int N;cin>>N,N;) {\n int res=1;\n rep(i,N)cin>>X[i]>>Y[i];\n for (int i=0;i<N-1;i++)for (int j=i+1;j<N;j++) {\n double dx=X[j]-X[i];\n double dy=Y[j]-Y[i];\n double d=hypot(dx,dy);\n if (d>2.0)continue;\n double c=d/2.0;\n double s=sqrt(1.0-c*c);\n {\n double mx=X[i]+(dx*c-dy*s)/d;\n double my=Y[i]+(dy*c+dx*s)/d;\n int t=0;\n rep(k,N) {\n if (k==i||k==j){t++;continue;}\n if (hypot(mx-X[k],my-Y[k])<=1.0)t++;\n }\n if (t>res)res=t;\n }\n {\n double mx=X[i]+(dx*c+dy*s)/d;\n double my=Y[i]+(dy*c-dx*s)/d;\n int t=0;\n rep(k,N) {\n if (k==i||k==j){t++;continue;}\n if (hypot(mx-X[k],my-Y[k])<=1.0)t++;\n }\n if (t>res)res=t;\n }\n }\n cout<<res<<'\\n';\n }\n}", "accuracy": 1, "time_ms": 1010, "memory_kb": 3840, "score_of_the_acc": -0.4737, "final_rank": 14 }, { "submission_id": "aoj_1132_10415371", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\n// 点\ntypedef complex<double> P;\n\n// 線分・半直線・直線\nstruct L {\n P pos, dir;\n};\n\n\n// 円\nstruct C {\n P p;\n long double r;\n};\n\nstruct Line : public vector<P> {\n Line() {\n ;\n }\n Line(P a, P b) {\n push_back(a);\n push_back(b);\n }\n};\n\nconst long double R = 1;\nconst long double EPS = 1.0e-8;\n\ninline double dot(const P& a, const P& b) {\n return real(conj(a) * b);\n}\n\nP projection(const Line& l, const P& p) {\n double t = dot(p - l[0], l[0] - l[1]) / norm(l[0] - l[1]);\n return l[0] + t * (l[0] - l[1]);\n}\n\nvector<P> crosspointLC(const Line& l, const C& c) {\n vector<P> ret;\n P center = projection(l, c.p);\n double d = abs(center - c.p);\n double t = sqrt(c.r * c.r - d * d);\n if (isnan(t)) {\n return ret;\n }\n P vect = (l[1] - l[0]);\n vect /= abs(vect);\n ret.push_back(center - vect * t);\n if (t > EPS) {\n ret.push_back(center + vect * t);\n }\n return ret;\n}\n\nvector<P> crosspointCC(const C& c1, const C& c2) {\n vector<P> ret;\n double d = abs(c1.p - c2.p);\n if (max(c1.r, c2.r) - min(c1.r, c2.r) - d > -EPS) {\n return ret;\n }\n double x = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n P start = c1.p + (c2.p - c1.p) / d * x;\n P vect = (c1.p - c2.p) * P(0.0, 1.0);\n return crosspointLC(Line(start, start + vect), c1);\n}\n\nlong double distance(P p1, P p2) {\n long double x = p1.real() - p2.real();\n long double y = p1.imag() - p2.imag();\n long double ret = sqrt(x * x + y * y);\n return ret;\n}\n\nint main() {\n while (true) {\n int N;\n cin >> N;\n if (N == 0) {\n break;\n }\n vector<P> points(N);\n for (int i = 0; i < N; i++) {\n long double x, y;\n cin >> x >> y;\n points[i] = P(x, y);\n }\n\n int ans = 1;\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (i == j) {\n continue;\n }\n\n auto dist = distance(points[i], points[j]);\n if (dist > 2 * R) {\n continue;\n }\n C c1 = C(points[i], R);\n C c2 = C(points[j], R);\n\n auto v = crosspointCC(c1, c2);\n auto ip1 = v[0];\n auto ip2 = v[1];\n \n // 判定\n int cnt1 = 0;\n int cnt2 = 0;\n for (int k = 0; k < N; k++) {\n long double d1 = distance(ip1, points[k]);\n long double d2 = distance(ip2, points[k]);\n if (R > d1-EPS) {\n cnt1++;\n }\n if (R > d2-EPS) {\n cnt2++;\n }\n }\n ans = max({ans, cnt1, cnt2});\n }\n }\n\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 380, "memory_kb": 3840, "score_of_the_acc": -0.2911, "final_rank": 10 }, { "submission_id": "aoj_1132_10415349", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\n// 点\ntypedef complex<double> P;\n\n// 線分・半直線・直線\nstruct L {\n P pos, dir;\n};\n\n\n// 円\nstruct C {\n P p;\n long double r;\n};\n\nstruct Line : public vector<P> {\n Line() {\n ;\n }\n Line(P a, P b) {\n push_back(a);\n push_back(b);\n }\n};\n\nconst long double R = 1;\nconst long double EPS = 1.0e-8;\n\ninline double dot(const P& a, const P& b) {\n return real(conj(a) * b);\n}\n\nP projection(const Line& l, const P& p) {\n double t = dot(p - l[0], l[0] - l[1]) / norm(l[0] - l[1]);\n return l[0] + t * (l[0] - l[1]);\n}\n\nvector<P> crosspointLC(const Line& l, const C& c) {\n vector<P> ret;\n P center = projection(l, c.p);\n double d = abs(center - c.p);\n double t = sqrt(c.r * c.r - d * d);\n if (isnan(t)) {\n return ret;\n }\n P vect = (l[1] - l[0]);\n vect /= abs(vect);\n ret.push_back(center - vect * t);\n if (t > EPS) {\n ret.push_back(center + vect * t);\n }\n return ret;\n}\n\nvector<P> crosspointCC(const C& c1, const C& c2) {\n vector<P> ret;\n double d = abs(c1.p - c2.p);\n if (max(c1.r, c2.r) - min(c1.r, c2.r) - d > -EPS) {\n return ret;\n }\n double x = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n P start = c1.p + (c2.p - c1.p) / d * x;\n P vect = (c1.p - c2.p) * P(0.0, 1.0);\n return crosspointLC(Line(start, start + vect), c1);\n}\n\nlong double distance(P p1, P p2) {\n long double x = p1.real() - p2.real();\n long double y = p1.imag() - p2.imag();\n long double ret = sqrt(x * x + y * y);\n return ret;\n}\n\nint main() {\n while (true) {\n int N;\n cin >> N;\n if (N == 0) {\n break;\n }\n vector<P> points(N);\n for (int i = 0; i < N; i++) {\n long double x, y;\n cin >> x >> y;\n points[i] = P(x, y);\n }\n\n int ans = 1;\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (i == j) {\n continue;\n }\n\n auto dist = distance(points[i], points[j]);\n if (dist > 2 * R) {\n continue;\n }\n C c1 = C(points[i], R);\n C c2 = C(points[j], R);\n\n auto v = crosspointCC(c1, c2);\n auto ip1 = v[0];\n auto ip2 = v[1];\n\n // cout << \"交点: \";\n // cout << ip1 << \" \" << ip2 << endl;\n\n // 判定\n int cnt1 = 0;\n int cnt2 = 0;\n for (int k = 0; k < N; k++) {\n long double d1 = distance(ip1, points[k]);\n long double d2 = distance(ip2, points[k]);\n if (R > d1-EPS) {\n cnt1++;\n }\n if (R > d2-EPS) {\n cnt2++;\n }\n\n // cout << \"距離: \";\n // cout << d1 << \" \" << d2 << \" \";\n // printf(\"(%d, %d, %d)\\n\",i,j,k);\n }\n ans = max({ans, cnt1, cnt2});\n }\n // cout << endl;\n }\n\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 380, "memory_kb": 3712, "score_of_the_acc": -0.2486, "final_rank": 7 }, { "submission_id": "aoj_1132_10415348", "code_snippet": "#include<iostream>\n#include<complex>\n#include<cmath>\n#include<vector>\nusing namespace std;\n// 点\ntypedef complex<double> P;\n\n// 円\nstruct C { P p; double r; };\n\npair<P, P> cc_cross(const C& c1, const C& c2) {\n double d = abs(c1.p - c2.p);\n double rc = (d*d + c1.r*c1.r - c2.r*c2.r) / (2*d);\n double rs = sqrt(c1.r*c1.r - rc*rc);\n P diff = (c2.p - c1.p) / d;\n return make_pair(c1.p + diff * P(rc, rs), c1.p + diff * P(rc, -rs));\n}\ndouble sq(double x){return x*x;};\ndouble dist(P p1, P p2){return sqrt(sq(p1.real()-p2.real())+sq(p1.imag()-p2.imag()));}\nint main()\n{\n\tios::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\twhile(1)\n\t{\n\t\tint N;cin>>N;\n\t\tif(N==0)break;\n\t\tvector<P>dots(N);\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tdouble x,y;cin>>x>>y;\n\t\t\tdots[i]=P(x,y);\n\t\t}\n\t\tint ans=0;\n\t\tfor(int i=0;i<N;i++)for(int j=i+1;j<N;j++)\n\t\t{\n\t\t\tif(dist(dots[i],dots[j])>2.0)continue;\n\t\t\tC a,b;\n\t\t\ta.p=dots[i],a.r=1.0;\n\t\t\tb.p=dots[j],b.r=1.0;\n\t\t\tpair<P,P>is=cc_cross(a,b);\n\t\t\tint cnt1=0,cnt2=0;\n\t\t\tfor(int k=0;k<N;k++)\n\t\t\t{\n\t\t\t\tif(dist(dots[k],is.first)<=1.0001)cnt1++;\n\t\t\t\tif(dist(dots[k],is.second)<=1.0001)cnt2++;\n\t\t\t}\n\t\t\tans=max(ans,max(cnt1,cnt2));\n\t\t}\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tint cnt=0;\n\t\t\tfor(int k=0;k<N;k++)\n\t\t\t{\n\t\t\t\tif(dist(dots[k],dots[i])<=1.0)cnt++;\n\t\t\t}\n\t\t\tans=max(ans,cnt);\n\t\t}\n\t\tcout<<ans<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 3712, "score_of_the_acc": -0.2109, "final_rank": 6 }, { "submission_id": "aoj_1132_10341984", "code_snippet": "#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\nusing namespace std;\n\n// 数値型\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nusing P = pair<int,int>;\nusing Pll = pair<ll, ll>;\nusing Pli = pair<ll, int>;\nusing Pil = pair<int, ll>;\n\n// vector関連\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\ntemplate<typename T>\nusing vc = vector<T>;\ntemplate<typename T>\nusing vvc = vector<vc<T>>;\ntemplate<typename T>\nusing vvvc = vector<vvc<T>>;\ntemplate<typename T>\nusing vvvvc = vector<vvvc<T>>;\n\n// priority_queue\ntemplate<typename T>\nusing pq = priority_queue<T>;\ntemplate<typename T>\nusing pqg = priority_queue<T, vc<T>, greater<T>>;\n\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n#define FOR(i, a, b) for(int i = a; i < (int)(b); i++)\n#define all(a) (a).begin(),(a).end()\n#define rall(a) (a).rbegin(),(a).rend()\n#define MIN(vec) *min_element(all(vec))\n#define MAX(vec) *max_element(all(vec))\n#define next_perm(vec) (vec).begin(), (vec).end()\n#define UNIQUE(vec) vec.erase(unique(vec.begin(), vec.end()), vec.end())\n#define el \"\\n\"\n#define Yes cout << \"Yes\" << el\n#define No cout << \"No\" << el\n#define YES cout << \"YES\" << el\n#define NO cout << \"NO\" << el\n#define EPS 1e-8\n#define Equal(a, b) (fabs((a)-(b)) < EPS) \n#ifdef ONLINE_JUDGE\n#define dbg(x) (void)0\n#else\n#define dbg(x) cerr << #x << \"=\" << x << el \n#endif\n// 定数\nconst string abc = \"abcdefghijklmnopqrstuvwxyz\";\nconst string ABC = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\nconstexpr int INF = 1001001001;\nconstexpr ll LINF = 1001001001001001001ll;\nconstexpr int DX[] = {1, 0, -1, 0};\nconstexpr int DY[] = {0, 1, 0, -1};\nconstexpr int DX8[] = {1, 0, -1, 0, 1, 1, -1, -1};\nconstexpr int DY8[] = {0, 1, 0, -1, 1, -1, 1, -1};\n\ntemplate<typename T1, typename T2>\nostream &operator<< (ostream &os, pair<T1, T2> p) {\n os << \"{\" << p.first << \",\" << p.second << \"}\";\n return os;\n}\ntemplate<typename T>\nostream &operator<< (ostream &os, vc<T> &vec) {\n int sz = vec.size();\n rep(i, sz){\n os << vec[i] << (i==sz-1?\"\":\" \");\n }\n return os;\n}\n\ntemplate<typename T1, typename T2>\nistream &operator>> (istream &is, pair<T1, T2> &p) {\n is >> p.first >> p.second;\n return is;\n}\ntemplate<typename T>\nistream &operator>> (istream &is, vc<T> &vec) {\n int sz = vec.size();\n rep(i, sz) { is >> vec[i]; }\n return is;\n}\n/// @brief aとbの最大値をaに格納。更新があったかbool値を返す\n/// @tparam T1 \n/// @tparam T2 \n/// @param a \n/// @param b \n/// @return bool\ntemplate<typename T1, typename T2>\ninline bool chmax(T1 &a, T2 b){\n bool ret = a<b;\n if(ret) a = b;\n return ret;\n}\n\n/// @brief aとbの最小値をaに格納。更新があったかbool値を返す\n/// @tparam T1 \n/// @tparam T2 \n/// @param a \n/// @param b \n/// @return bool\ntemplate<typename T1, typename T2>\ninline bool chmin(T1 &a, T2 b){\n bool ret = a>b;\n if(ret) {a = b;}\n return ret;\n}\n\ninline void YesNo(bool flag){\n if(flag) {Yes;}\n else {No;}\n return;\n}\n\ninline void YESNO(bool flag){\n if(flag) {YES;}\n else {NO;}\n return;\n}\n\ninline bool outof(ll x, ll xlim){\n return (x<0 || x>=xlim);\n}\n\ntemplate<typename T>\ninline T sqnorm(T x, T y){\n return x*x+y*y;\n}\n\n/// @brief char->int\n/// @param c \n/// @return int\ninline int ctoi(char c){\n return c-'0';\n}\n\n/// @brief xを素因数分解\n/// @param x \n/// @return vector<Pli>, 素因数の昇順に {p, cnt}\nvector<Pli> prime_fact(ll x){\n vector<Pli> ret;\n for(ll i=2; i*i<=x; i++){\n if(x%i == 0){\n ret.emplace_back(i, 0);\n while(x%i == 0){\n ret.back().second++;\n x /= i;\n }\n }\n }\n if(x != 1) ret.emplace_back(x, 1);\n return ret;\n}\n\n/// @brief xの約数列挙\n/// @param x \n/// @return vll, 約数の昇順\nvll divisor_enum(ll x){\n vector<ll> ret;\n for(ll i=1; i*i<=x; i++){\n if(x%i == 0){\n ret.push_back(x/i);\n ret.push_back(i);\n }\n }\n sort(all(ret));\n UNIQUE(ret);\n return ret;\n}\n\n/// @brief 繰り返し二乗法。\n/// @tparam T \n/// @param x \n/// @param k \n/// @param op \n/// @param e \n/// @return \ntemplate<typename T>\nT pow_t(T x, ll k, T (*op)(T, T), T (*e)()){\n T ret = e();\n while(k){\n if(k&1) ret *= x;\n x *= x;\n k >>= 1;\n }\n return ret;\n}\n\nll powll(ll x, ll k){\n return pow_t<ll>(x, k, [](ll a, ll b) -> ll{return a*b;}, []() -> ll{return 1;});\n}\n\ninline int pop_cnt(ll x) { return __builtin_popcountll(x); }\ninline int top_bit(ll x) { return (x==0?-1:63-__builtin_clzll(x));}\n\nvoid main2();\n\nint main(){\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n main2();\n}\n\nstruct Point{\n double x, y;\n Point(){}\n Point(double _x, double _y){\n x = _x;\n y = _y;\n }\n};\n\nostream &operator<< (ostream &os, Point &a) {\n os << \"(\" << a.x << \", \" << a.y << \")\";\n return os;\n}\n\ndouble get_dist(Point p1, Point p2){ return sqrt((p1.x - p2.x)*(p1.x - p2.x) + (p1.y - p2.y)*(p1.y - p2.y)); }\n\nint count(vc<Point> &ps, Point center){\n int n = ps.size();\n int cnt = 0;\n rep(i, n){\n if(get_dist(ps[i], center) <= 1+EPS) cnt++;\n }\n return cnt;\n}\n\ndouble get_k(Point m, Point inc, Point p){\n double a = inc.x*inc.x + inc.y*inc.y;\n double b = 0;\n double c = min(double(0), (m.x-p.x)*(m.x-p.x)+(m.y-p.y)*(m.y-p.y)-1);\n return abs((-b + sqrt(b*b - a*c))/a);\n}\n\nint get_max(vc<Point> &ps, int id1, int id2){\n int sz = ps.size();\n if(get_dist(ps[id1], ps[id2]) > 2+EPS) return 1;\n Point p1 = ps[id1], p2 = ps[id2];\n Point diff = Point((p1.x - p2.x), (p1.y - p2.y));\n Point m = Point((p1.x + p2.x)/2, (p1.y + p2.y)/2);\n Point inc = Point(diff.y, -diff.x);\n double k = get_k(m, inc, p1);\n // dbg(pair(pair(p1, p2), Point(m.x+inc.x*k, m.y+inc.y*k)));\n return max(count(ps, Point(m.x+inc.x*k, m.y+inc.y*k)), count(ps, Point(m.x-inc.y*k, m.y-inc.y*k)));\n}\nbool solve(){\n int n;\n cin >> n;\n if(n == 0) return false;\n vc<Point> ps(n); \n rep(i, n){\n cin >> ps[i].x >> ps[i].y;\n }\n int ans = 1;\n rep(i, n){\n rep(j, i){\n chmax(ans, get_max(ps, i, j));\n }\n }\n cout << ans << endl;\n return true;\n}\nvoid main2(){\n while(solve());\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3456, "score_of_the_acc": -0.0912, "final_rank": 1 }, { "submission_id": "aoj_1132_10324451", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n#include <algorithm>\nusing namespace std;\n\nconst double EPS = 1e-4;\nconst double R = 1.0;\n\nstruct Point\n{\n double x, y;\n};\n\ndouble distance(Point a, Point b)\n{\n return sqrt((a.x - b.x) * (a.x - b.x) + (a.y - b.y) * (a.y - b.y));\n}\n\nint count(Point center, const vector<Point> &points)\n{\n int count = 0;\n for (size_t i = 0; i < points.size(); ++i)\n {\n if (distance(center, points[i]) - R < EPS)\n {\n count++;\n }\n }\n return count;\n}\n\nint maxEnclosed(const vector<Point> &points)\n{\n int maxPoints = 1;\n int n = points.size();\n\n for (int i = 0; i < n; ++i)\n {\n for (int j = i ; j < n; ++j)\n {\n double d = distance(points[i], points[j]);\n if (d - 2.0 >= EPS)\n continue;\n\n Point mid;\n mid.x = (points[i].x + points[j].x) / 2;\n mid.y = (points[i].y + points[j].y) / 2;\n\n double h = sqrt(1.0 - (d / 2) * (d / 2));\n\n double dx = (points[j].y - points[i].y) * (h / d);\n double dy = (points[i].x - points[j].x) * (h / d);\n\n Point c1 = {mid.x + dx, mid.y + dy};\n Point c2 = {mid.x - dx, mid.y - dy};\n\n maxPoints = max(maxPoints, count(c1, points));\n maxPoints = max(maxPoints, count(c2, points));\n }\n }\n\n return maxPoints;\n}\n\nint main()\n{\n vector<Point> points;\n int n;\n\n while (cin >> n && n != 0)\n {\n points.clear();\n for (int i = 0; i < n; ++i)\n {\n Point p;\n cin >> p.x >> p.y;\n points.push_back(p);\n }\n\n cout << maxEnclosed(points) << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 470, "memory_kb": 3440, "score_of_the_acc": -0.1844, "final_rank": 3 }, { "submission_id": "aoj_1132_10324404", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n#include <algorithm>\nusing namespace std;\n\nconst double EPS = 1e-4;\nconst double R = 1.0;\n\nstruct Point\n{\n double x, y;\n};\n\ndouble distance(Point a, Point b)\n{\n return sqrt((a.x - b.x) * (a.x - b.x) + (a.y - b.y) * (a.y - b.y));\n}\n\nint count(Point center, const vector<Point> &points)\n{\n int count = 0;\n for (size_t i = 0; i < points.size(); ++i)\n {\n if (distance(center, points[i]) - R < EPS)\n {\n count++;\n }\n }\n return count;\n}\n\nint maxEnclosed(const vector<Point> &points)\n{\n int maxPoints = 1;\n int n = points.size();\n\n for (int i = 0; i < n; ++i)\n {\n for (int j = i + 1; j < n; ++j)\n {\n double d = distance(points[i], points[j]);\n if (d - 2.0 >= EPS)\n continue;\n\n Point mid;\n mid.x = (points[i].x + points[j].x) / 2;\n mid.y = (points[i].y + points[j].y) / 2;\n\n double h = sqrt(1.0 - (d / 2) * (d / 2));\n\n double dx = (points[j].y - points[i].y) * (h / d);\n double dy = (points[i].x - points[j].x) * (h / d);\n\n Point c1 = {mid.x + dx, mid.y + dy};\n Point c2 = {mid.x - dx, mid.y - dy};\n\n maxPoints = max(maxPoints, count(c1, points));\n maxPoints = max(maxPoints, count(c2, points));\n }\n }\n\n return maxPoints;\n}\n\nint main()\n{\n vector<Point> points;\n int n;\n\n while (cin >> n && n != 0)\n {\n points.clear();\n for (int i = 0; i < n; ++i)\n {\n Point p;\n cin >> p.x >> p.y;\n points.push_back(p);\n }\n\n cout << maxEnclosed(points) << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 470, "memory_kb": 3260, "score_of_the_acc": -0.1246, "final_rank": 2 }, { "submission_id": "aoj_1132_10324110", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n#include <algorithm>\nusing namespace std;\n\nconst double EPS = 1e-5;\nconst double R = 1.0;\n\nstruct Point\n{\n double x, y;\n};\n\ndouble distance(Point a, Point b)\n{\n return sqrt((a.x - b.x) * (a.x - b.x) + (a.y - b.y) * (a.y - b.y));\n}\n\nint count(Point center, const vector<Point> &points)\n{\n int count = 0;\n for (size_t i = 0; i < points.size(); ++i)\n {\n if (distance(center, points[i]) - R < EPS)\n {\n count++;\n }\n }\n return count;\n}\n\nint maxEnclosed(const vector<Point> &points)\n{\n int maxPoints = 1;\n int n = points.size();\n\n for (int i = 0; i < n; ++i)\n {\n maxPoints = max(maxPoints, count(points[i], points));\n }\n\n for (int i = 0; i < n; ++i)\n {\n for (int j = i + 1; j < n; ++j)\n {\n double d = distance(points[i], points[j]);\n if (d - 2.0 > EPS)\n continue;\n\n Point mid;\n mid.x = (points[i].x + points[j].x) / 2;\n mid.y = (points[i].y + points[j].y) / 2;\n\n double h = sqrt(1.0 - (d / 2) * (d / 2));\n\n double dx = (points[j].y - points[i].y) * (h / d);\n double dy = (points[i].x - points[j].x) * (h / d);\n\n Point c1 = {mid.x + dx, mid.y + dy};\n Point c2 = {mid.x - dx, mid.y - dy};\n\n maxPoints = max(maxPoints, count(c1, points));\n maxPoints = max(maxPoints, count(c2, points));\n }\n }\n\n return maxPoints;\n}\n\nint main()\n{\n vector<Point> points;\n int n;\n\n while (cin >> n && n != 0)\n {\n points.clear();\n for (int i = 0; i < n; ++i)\n {\n Point p;\n cin >> p.x >> p.y;\n points.push_back(p);\n }\n\n cout << maxEnclosed(points) << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 470, "memory_kb": 3468, "score_of_the_acc": -0.1937, "final_rank": 4 }, { "submission_id": "aoj_1132_9883566", "code_snippet": "#include<bits/stdc++.h>\n// #include<atcoder/all>\n// #include<boost/multiprecision/cpp_int.hpp>\n\nusing namespace std;\n// using namespace atcoder;\n// using bint = boost::multiprecision::cpp_int;\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nusing P = pair<ll,ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing ve = vector<vector<int>>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\n#define rep(i,n) for(ll i = 0;i < (ll)n;i++)\n#define ALL(x) (x).begin(),(x).end()\n#define sz(c) ((ll)(c).size())\n#define LB(A,x) (int)(lower_bound(A.begin(),A.end(),x)-A.begin())\n#define UB(A,x) (int)(upper_bound(A.begin(),A.end(),x)-A.begin())\n// #define MOD 1000000007\n#define MOD 998244353\ntemplate<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T>ostream&operator<<(ostream&os,vector<T>&v){for(int i = 0;i < v.size();i++)os<<v[i]<<(i+1!=v.size()?\" \":\"\");return os;}\ntemplate<typename T>istream&operator>>(istream&is,vector<T>&v){for(T&in:v)is>>in;return is;}\ntemplate<typename T1,typename T2>ostream&operator<<(ostream&os,pair<T1,T2>&p){os<<p.first<<\" \"<<p.second;return os;}\ntemplate<typename T1,typename T2>istream&operator>>(istream&is,pair<T1,T2>&p){is>>p.first>>p.second;return is;}\ntemplate<typename T> inline bool chmax(T &a,T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> inline bool chmin(T &a,T b){if(a > b){a = b;return true;}return false;}\nld dist(ld x1,ld y1,ld x2, ld y2){return sqrtl((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));}\n\n// using T = ll;\nusing T = double;\nconst double eps = 1e-10;\nusing Point = complex<T>;\n#define eq(a,b) (abs((a)-(b)) < eps)\n#define eqv(a,b) (eq((a).real(),(b).real()) && eq((a).imag(),(b).imag()))\n\nistream &operator>>(istream &is,Point &p) {\n T a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n}\nostream &operator<<(ostream &os, Point &p) {\n return os << fixed << setprecision(10) << p.real() << \" \" << p.imag();\n}\nnamespace std{\n bool operator<(const Point &a,const Point &b){\n return a.real() != b.real() ? a.real() < b.real() : a.imag() < b.imag();\n }\n}\n// ベクトルの絶対値\nT length(Point a){return abs(a);}\n// 2点a,bの距離\nT dist(Point a,Point b){return abs(a-b);}\n// 単位ベクトル\nPoint unit(Point a){return a/abs(a);}\n// 法線ベクトル\nPoint normal(Point a){return a*Point(0,1);}\n// 内積\nT dot(Point a,Point b){return a.real()*b.real()+a.imag()*b.imag();}\n// 外積\nT det(Point a,Point b){return a.real()*b.imag()-a.imag()*b.real();}\n// 2直線の直交判定\nbool is_orthogonal(Point a1,Point a2,Point b1,Point b2){return eq(dot(a1-a2,b1-b2),0.0);}\n// 2直線の平行判定\nbool is_parallel(Point a1,Point a2,Point b1,Point b2){return eq(det(a1-a2,b1-b2),0.0);}\n// cの直線状の有無\nbool is_point_on_l(Point a,Point a_,Point c){return eq(det(a-a_,c-a_),0.0);}\n// cの線分上の有無\nbool is_point_on_seg(Point a,Point a_,Point c){return abs(c-a_)+abs(c-a) < abs(a-a_)+eps;}\n// 直線と点の距離\nT dist_l_p(Point a,Point a_,Point c){return abs(det(a-a_,c-a_))/abs(a-a_);}\n// 線分と点の距離\nT dist_seg_p(Point a,Point a_,Point c){\n if(dot(a-a_,c-a_) < eps)return abs(c-a_);\n if(dot(a_-a,c-a) < eps)return abs(c-a);\n return abs(det(a-a_,c-a_))/abs(a-a_);\n}\n// 線分同士が交わるか\nbool is_intersect_seg_seg(Point a1,Point a2,Point b1,Point b2){return (det(a2-a1,b1-a1)*det(a2-a1,b2-a1) < eps) && (det(b2-b1,a1-b1)*det(b2-b1,a2-b1) < eps);}\n// 線分の交点の座標\nPoint intersection_seg_seg(Point a1,Point a2,Point b1,Point b2){\n Point b = b2-b1;\n T d1 = abs(det(b,a1-b1));\n T d2 = abs(det(b,a2-b1));\n T t = d1/(d1+d2);\n return a1+(a2-a1)*t;\n}\n// 直線同士が交わるか\nbool is_intersect_l_l(Point a1,Point a2,Point b1,Point b2){return !eq(det(a1-a2,b1-b2),0.0);}\n// 直線の交点の座標\nPoint intersection_l_l(Point a1,Point a2,Point b1,Point b2){\n Point a = a2-a1,b = b2-b1;\n return a1+a*det(b,b1-a1)/det(b,a);\n}\n// https://onlinejudge.u-aizu.ac.jp/status/users/shkii/submissions/1/CGL_3_A/judge/9381090/C++17\ndouble polygonArea(const vector<Point> &pt){\n double res = 0;\n int n = pt.size();\n for(int i = 0;i < n-1;i++){\n res += det(pt[i],pt[i+1]);\n }\n res += det(pt[n-1],pt[0]);\n return res*0.5;\n}\n\n// https://onlinejudge.u-aizu.ac.jp/problems/CGL_4_A\nvector<Point> convex_hull(vector<Point> &pt){\n int n = pt.size();\n sort(pt.begin(),pt.end());\n int k = 0;\n vector<Point> ch(n*2);\n // 一直線上の点を含める -> ( > 0) ( > eps)\n // 含めない -> ( >= 0) ( > -eps)\n // 下側凸包\n for(int i = 0;i < n;i++){\n while(k > 1 && det(ch[k-2]-ch[k-1],pt[i]-ch[k-1]) >= 0)k--;\n ch[k++] = pt[i];\n }\n // 上側凸包\n for(int i = n-2,t = k;i >= 0;i--){\n while(k > t && det(ch[k-2]-ch[k-1],pt[i]-ch[k-1]) >= 0)k--;\n ch[k++] = pt[i];\n }\n ch.resize(k-1);\n return ch;\n}\n\nbool solve(){\n int n;cin >> n;\n if(!n)return false;\n vector<Point> v(n);\n // cin >> v;\n rep(i,n)cin >> v[i];\n int res = 1;\n auto cnt = [&](Point o){\n int k = 0;\n rep(i,n){\n if(length(v[i]-o) < 1 + eps)k++;\n }\n return k;\n };\n rep(i,n)for(int j = i+1;j < n;j++){\n if(dist(v[i],v[j]) > 2)continue;\n double r = length(v[i]-v[j])/2;\n Point o = (v[i] + v[j])/2.0 + normal(v[j]-v[i])*sqrt(1-r*r)/length(v[j]-v[i]);\n chmax(res,cnt(o));\n o = (v[i] + v[j])/2.0 - normal(v[j]-v[i])*sqrt(1-r*r)/length(v[j]-v[i]);\n chmax(res,cnt(o));\n }\n cout << res << \"\\n\";\n return true;\n}\n\nint main(){\n \n ios_base::sync_with_stdio(0), cin.tie(0);\n while(solve());\n \n\n return 0;\n}", "accuracy": 1, "time_ms": 1190, "memory_kb": 3464, "score_of_the_acc": -0.4011, "final_rank": 12 }, { "submission_id": "aoj_1132_9634454", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<ll,ll> pi;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define sz(A) (ll)(A.size())\nld dist(ld x1,ld y1,ld x2,ld y2){\n return sqrtl((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));\n}\nint main(){\n while(1){\n ll N;cin>>N;\n if(!N)return 0;\n vector<ld>X(N),Y(N);\n REP(i,N)cin>>X[i]>>Y[i];\n ll ans=1;\n vector<pair<ld,ld>>P;\n REP(i,N)REP(j,i)if(dist(X[i],Y[i],X[j],Y[j])<2){\n ld d=dist(X[i],Y[i],X[j],Y[j])/2,h=sqrtl(1-d*d);\n P.emplace_back(make_pair((X[i]+X[j])/2+h*(Y[i]-Y[j])/d/2,(Y[i]+Y[j])/2+h*(X[j]-X[i])/d/2));\n P.emplace_back(make_pair((X[i]+X[j])/2-h*(Y[i]-Y[j])/d/2,(Y[i]+Y[j])/2-h*(X[j]-X[i])/d/2));\n }\n for(auto[x,y]:P){\n ll cnt=0;\n REP(i,N)if(dist(X[i],Y[i],x,y)<1+(1e-10))cnt++;\n ans=max(ans,cnt);\n }\n cout<<ans<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 4976, "score_of_the_acc": -0.6277, "final_rank": 16 }, { "submission_id": "aoj_1132_9559080", "code_snippet": "#include <algorithm>\n#include <cmath>\n#include <cstdlib>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <unordered_set>\n#include <vector>\n\nusing namespace std;\nusing ll = long long;\n\nclass Vec2 {\n public:\n\tdouble x, y;\n};\n\ndouble CompDistance(const Vec2 p1, const Vec2 p2, const double d) {\n\treturn ((p1.x - p2.x) * (p1.x - p2.x) + (p1.y - p2.y) * (p1.y - p2.y) <= d * d);\n}\n\nvector<Vec2> Centers(const Vec2 p1, const Vec2 p2) {\n\tvector<Vec2> centers;\n\n\tVec2 v12{p2.x - p1.x, p2.y - p1.y};\n\tdouble m12 = sqrt(v12.x * v12.x + v12.y * v12.y);\n\tdouble m13 = sqrt(4 - m12 * m12);\n\tVec2 v13{m13 / m12 * (-v12.y), m13 / m12 * v12.x};\n\tfor (int i = 0; i < 2; i++) {\n\t\tVec2 center{p1.x + (v12.x + v13.x) / 2.0, p1.y + (v12.y + v13.y) / 2.0};\n\t\tcenters.push_back(center);\n\t\tif (v13.x == 0.0 and v13.y == 0.0) break;\n\t\tv13 = {-v13.x, -v13.y};\n\t}\n\n\treturn centers;\n}\n\nvoid chmax(int& a, const int b) {\n\tif (a < b) a = b;\n}\n\nint main() {\n\twhile (true) {\n\t\tint n;\n\t\tcin >> n;\n\t\tif (n == 0) break;\n\n\t\tvector<Vec2> points(n);\n\t\tvector<Vec2> centers;\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tcin >> points[i].x >> points[i].y;\n\t\t\tfor (int j = 0; j < i; j++) {\n\t\t\t\tif (!CompDistance(points[i], points[j], 2.0)) continue;\n\n\t\t\t\tvector<Vec2> new_centers = Centers(points[i], points[j]);\n\t\t\t\tcenters.insert(centers.begin(), new_centers.begin(), new_centers.end());\n\t\t\t}\n\t\t}\n\n\t\tint max = 1;\n\t\tfor (const Vec2& center : centers) {\n\t\t\tint count = 0;\n\t\t\tfor (const Vec2 point : points) {\n\t\t\t\tif (CompDistance(center, point, 1.0001)) count++;\n\t\t\t}\n\t\t\tchmax(max, count);\n\t\t}\n\n\t\tcout << max << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 500, "memory_kb": 3828, "score_of_the_acc": -0.3219, "final_rank": 11 }, { "submission_id": "aoj_1132_9503134", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconstexpr double EPS = 1e-9;\n\nvoid solve() {\n ll N;\n cin >> N;\n\n if(!N) { exit(0); }\n\n vector<double> X(N), Y(N);\n for(ll i = 0; i < N; i++) { cin >> X[i] >> Y[i]; }\n\n ll ans = 1;\n for(ll i = 0; i < N; i++) {\n for(ll j = 0; j < i; j++) {\n double dx = X[i] - X[j], dy = Y[i] - Y[j], d = dx * dx + dy * dy;\n double mx = (X[i] + X[j]) / 2, my = (Y[i] + Y[j]) / 2;\n double px = -dy * sqrt(1.0L / d - 0.25L), py = dx * sqrt(1.0L / d - 0.25L);\n double cx[2] = {mx + px, mx - px}, cy[2] = {my + py, my - py};\n for(ll k = 0; k < 2; k++) {\n ll t = 0;\n for(ll l = 0; l < N; l++) {\n double x = cx[k] - X[l], y = cy[k] - Y[l];\n if(x * x + y * y - EPS <= 1.0L) { t++; }\n }\n ans = max(ans, t);\n }\n }\n }\n\n cout << ans << \"\\n\";\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n while(true) { solve(); }\n}", "accuracy": 1, "time_ms": 460, "memory_kb": 3712, "score_of_the_acc": -0.2718, "final_rank": 9 }, { "submission_id": "aoj_1132_9368215", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (long long i = 0; i < (long long)(n); i++)\n#define rrep(i,start,end) for (long long i = start;i >= (long long)(end);i--)\n#define repn(i,end) for(long long i = 0; i <= (long long)(end); i++)\n#define reps(i,start,end) for(long long i = start; i < (long long)(end); i++)\n#define repsn(i,start,end) for(long long i = start; i <= (long long)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\ntypedef vector<long long> vll;\ntypedef vector<pair<long long ,long long>> vpll;\ntypedef vector<vector<long long>> vvll;\ntypedef set<ll> sll;\ntypedef map<long long , long long> mpll;\ntypedef pair<long long ,long long> pll;\ntypedef tuple<long long , long long , long long> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (int)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1LL << 60;\nconst ld EPS = 1e-9;\n \ninline ll lfloor(ll x,ll m){return (x - ((x % m+ m)%m))/m;}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\n// for AOJ or ICPC or etc..\n// 全部が0だったらtrueを返す\ntemplate<class Tp> bool zero (const Tp &x) {return x == 0;}\ntemplate<class Tp, class... Args> bool zero (const Tp &x, const Args& ...args) {return zero(x) and zero(args...);}\n\n\n\n//参考 https://github.com/saphmitchy/deliair-lib\n// 型名\n// R:Real, P:Point, L:Line, S:Segment, C:Circle, VP:vector<Point>\n\n#define X(p) real(p)\n#define Y(p) imag(p)\n\nusing R = ld;\nusing P = complex<R>;\nusing VP = vector<P>;\n\n//const R EPS = 1e-9; // ここは適宜調節する,いつものやつから消す\nconst R pi = acos(-1.0);\n\nint sgn(R a) {\n return (a < -EPS) ? -1 : (a > EPS) ? 1 : 0;\n} // 符号関数\n\nbool eq(R a, R b) {//実数の一致判定\n return sgn(b - a) == 0;\n}\n\nP operator*(P p, R d) {//ベクトルのd倍\n return P(X(p) * d, Y(p) * d);\n}\n\nP operator/(P p, R d) {//ベクトルの1/d倍\n return p * (1 / d);\n}\n\nistream &operator>>(istream &is, P &p) {\n // R a, b; // 入力が小数\n int a, b; // 入力が整数\n is >> a >> b;\n p = P(a, b);\n return is;\n}\n\nostream &operator<<(ostream &os, P p) {\n return os << X(p) << ' ' << Y(p);\n}\n\nR getarg(P b,P a){//ベクトルbはベクトルaを何radian回転させる必要があるか\n assert(sgn(abs(a)) != 0);//長さが0はだめ\n return arg(b/a);\n}\n\nbool cp_x(P p, P q) {//ベクトルの比較x軸で比較->y軸で比較\n if (!eq(X(p), X(q)))\n return X(p) < X(q);\n return Y(p) < Y(q);\n}\n\nbool cp_y(P p, P q) {//ベクトルの比較y軸で比較->x軸で比較\n if (!eq(Y(p), Y(q)))\n return Y(p) < Y(q);\n return X(p) < X(q);\n}\n\nstruct L {//直線ab\n P a, b;\n L() {}\n L(P a, P b) : a(a), b(b) {}\n\n // 入出力(必要なら)\n friend ostream &operator<<(ostream &os, L &l) {\n return os << l.a << ' ' << l.b;\n }\n friend istream &operator>>(istream &is, L &l) {\n return is >> l.a >> l.b;\n }\n};\n\nstruct S : L {//線分ab\n S() {}\n S(P a, P b) : L(a, b) {}\n};\n\nstruct C {//中心p 半径rの円\n P p;\n R r;\n C() {}\n C(P p, R r) : p(p), r(r) {}\n};\n\nP rot(P p, R t) {//ベクトルの回転\n return p * P(cos(t), sin(t));\n}\n\n//2つのベクトルの内積\nR dot(P p, P q) {\n return X(p) * X(q) + Y(p) * Y(q);\n}\n\n//2つのベクトルの外積\nR det(P p, P q) {\n return X(p) * Y(q) - Y(p) * X(q);\n}\n\n// https://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_C&lang=jp\nint ccw(P a, P b, P c) { // 線分 ab に対する c の位置関係 \n b -= a, c -= a;//ベクトルab,ベクトルacにした\n if (sgn(det(b, c)) == 1)//外積右ねじ正\n return +1; // COUNTER_CLOCKWISE a,b,cが反時計回り\n if (sgn(det(b, c)) == -1)\n return -1; // CLOCKWISE\n if (dot(b, c) < 0.0)\n return +2; // ONLINE_BACK\n if (norm(b) < norm(c))\n return -2; // ONLINE_FRONT\n return 0; // ON_SEGMENT\n}\n\nbool para(L a, L b) { // 平行判定\n return eq(det(a.b - a.a, b.b - b.a), 0.0);\n}\n\nbool orth(L a, L b) { // 垂直判定\n return eq(dot(a.b - a.a, b.b - b.a), 0.0);\n}\n\nP proj(L l, P p) { // 垂線の足\n R t = dot(p - l.a, l.b - l.a) / norm(l.b - l.a);\n return l.a + (l.b - l.a) * t;\n}\n\n// これいる?\n// P proj(S s, P p) {\n// R t = dot(p - s.a, s.b - s.a) / norm(s.b - s.a);\n// return s.a + (s.b - s.a) * t;\n// }\n\nP refl(L l, P p) { // 線対称の位置にある点\n return p + (proj(l, p) - p) * 2.0;\n}\n\nbool inter(L l, P p) { // 交点を持つか判定\n return abs(ccw(l.a, l.b, p)) != 1;\n}\n\nbool inter(S s, P p) {\n return ccw(s.a, s.b, p) == 0;\n}\n\nbool inter(L l, L m) {\n if (!eq(det(l.b - l.a, m.b - m.a), 0.0))\n return true;\n return eq(det(l.b - l.a, m.b - l.a), 0.0);\n}\n\nbool inter(L l, S s) {\n return sgn(det(l.b - l.a, s.a - l.a) * det(l.b - l.a, s.b - l.a)) <= 0;\n}\n\nbool inter(S s, L l) {\n return inter(l, s);\n}\n\nbool inter(S s, S t) {\n if (ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) > 0)\n return false;\n return ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\nR dist(P p, P q) {\n return abs(q - p);\n}\n\nR dist(L l, P p) {\n return abs(p - P(proj(l, p)));\n}\n\nR dist(S s, P p) {\n P h = proj(s, p);\n if (inter(s, h))\n return abs(h - p);\n return min(abs(s.a - p), abs(s.b - p));\n}\n\nR dist(L l, L m) {\n return inter(l, m) ? 0.0 : dist(l, m.a);\n}\n\nR dist(S s, S t) {\n if (inter(s, t))\n return 0.0;\n return min({dist(s, t.a), dist(s, t.b), dist(t, s.a), dist(t, s.b)});\n}\n\nR dist(L l, S s) {\n if (inter(l, s))\n return 0.0;\n return min(dist(l, s.a), dist(l, s.b));\n}\n\nR dist(S s, L l) {\n return dist(l, s);\n}\n\nbool inter(C c, L l) {\n return sgn(c.r - dist(l, c.p)) >= 0;\n}\n\nbool inter(C c, P p) {\n return eq(abs(p - c.p), c.r);\n}\n\n// 共通接線の本数\n// 交点なし:4\n// 外接:3\n// 2点で交わる:2\n// 内接:1\n// 一方がもう一方を内包:0\nint inter(C c1, C c2) {\n if (c1.r < c2.r)\n swap(c1, c2);\n R d = abs(c1.p - c2.p);\n int a = sgn(d - c1.r - c2.r);\n if (a >= 0)\n return 3 + a;\n return 1 + sgn(d - c1.r + c2.r);\n}\n\nVP crosspoint(L l, L m) {\n VP ret;\n if (!inter(l, m))\n return ret;\n R A = det(l.b - l.a, m.b - m.a);\n R B = det(l.b - l.a, l.b - m.a);\n if (eq(A, 0.0) && eq(B, 0.0)) {\n ret.emplace_back(m.a);\n } else {\n ret.emplace_back(m.a + (m.b - m.a) * B / A);\n }\n return ret;\n}\n\nVP crosspoint(S s, S t) {\n return inter(s, t) ? crosspoint(L(s), L(t)) : VP();\n}\n\nVP crosspoint(C c, L l) {//円と直線の交点\n P h = proj(l, c.p);\n P e = (l.b - l.a) / abs(l.b - l.a);\n VP ret;\n if (!inter(c, l))\n return ret;\n if (eq(dist(l, c.p), c.r)) {\n ret.emplace_back(h);\n } else {\n R b = sqrt(c.r * c.r - norm(h - c.p));\n ret.push_back(h + e * b), ret.push_back(h - e * b);\n }\n return ret;\n}\n\nVP crosspoint(C c, S s) {//円と線分の交点\n P h = proj(s, c.p);\n P e = (s.b - s.a) / abs(s.b - s.a);\n VP ret;\n if (!inter(c, s))\n return ret;\n if (eq(dist(s, c.p), c.r)) {\n ret.emplace_back(h);\n } else {\n R b = sqrt(c.r * c.r - norm(h - c.p));\n if(ccw(s.a,s.b,h - e * b) == 0){//s.aに近い方から線分上なら追加する\n ret.push_back(h - e * b);\n }\n if(ccw(s.a,s.b,h + e * b)==0){\n ret.push_back(h + e * b);\n }\n }\n return ret;\n}\n\nVP crosspoint(C c1, C c2) {//2つの円の交わる点\n R d = abs(c1.p - c2.p);\n R a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d));\n R t = atan2(Y(c2.p) - Y(c1.p), X(c2.p) - X(c1.p));\n VP ret;\n if (inter(c1, c2) % 4 == 0) // 交わらないとき\n return ret;\n if (eq(a, 0.0)) {\n ret.emplace_back(P(c1.p + rot(P(c1.r, 0.0), t)));\n } else {\n P p1 = c1.p + rot(P(c1.r, 0.0), t + a);\n P p2 = c1.p + rot(P(c1.r, 0.0), t - a);\n ret.emplace_back(p1), ret.emplace_back(p2);\n }\n return ret;\n}\n\nVP cut(VP p, L l, bool border = true) { // 直線が多角形に切り取られる区間\n int n = sz(p);\n p.emplace_back(p[0]), p.emplace_back(p[1]);\n VP ret;\n rep(i, n) {\n if (!eq(dist(l, p[i]), 0) && !eq(dist(l, p[i + 1]), 0)) {\n S s(p[i], p[i + 1]);\n if (eq(dist(l, s), 0)) {\n auto res = crosspoint(l, s);\n ret.emplace_back(res[0]);\n }\n }\n if (eq(dist(l, p[i + 1]), 0)) {\n if ((eq(dist(l, p[i]), 0) || eq(dist(l, p[i + 2]), 0)) && !border)\n continue;\n S s(p[i], p[i + 2]);\n if (eq(dist(l, s), 0))\n ret.emplace_back(p[i + 1]);\n }\n }\n return ret;\n}\n\nVP rectangle(S s, R r) { // sを軸とした幅rの長方形\n P d = (s.a - s.b) * P(0, 1);\n d *= r / sqrt(norm(d));\n return VP{s.a + d, s.a - d, s.b - d, s.b + d};\n}\n\nL vertical_bisector(P p, P q) { // 垂直二等分線\n L l;\n l.a = (p + q) * 0.5;\n l.b = l.a + rot(q - p, pi * 0.5);\n return l;\n}\n\nL angle_bisector(P a,P b,P c){//角abcの二等分線(角bの2等分線)\n L l;\n l.a = b;\n R ang = atan2(Y(c-b),X(c-b)) - atan2(Y(a-b),X(a-b));//なす角\n ang/=2.0;\n l.b = l.a + rot(a-b,ang);\n return l;\n}\n\nC Apollonius(P p, P q, R a, R b) { // アポロニウスの円\n P p1 = (p * b + q * a) / (a + b), p2 = (-p * b + q * a) / (a - b);\n C c;\n c.p = (p1 + p2) * 0.5;\n c.r = abs(p1 - p2) * 0.5;\n return c;\n}\n\nR area(VP p) { // 多角形の面積\n R ret = 0.0;\n int n = sz(p);\n rep(i, n) ret += det(p[i], p[(i + 1) % n]);\n return abs(ret * 0.5);\n}\n\nint in_polygon(VP p, P q) { // IN:2, ON:1, OUT:0\n int n = sz(p);\n int ret = 0;\n rep(i, n) {\n P a = p[i] - q, b = p[(i + 1) % n] - q;\n if (eq(det(a, b), 0.0) && sgn(dot(a, b)) <= 0)\n return 1;\n if (Y(a) > Y(b))\n swap(a, b);\n if (sgn(Y(a)) <= 0 && sgn(Y(b)) == 1 && sgn(det(a, b)) == 1)\n ret ^= 2;\n }\n return ret;\n}\n\nVP tangent(C c, P p) { // 点 p を通る円 c の接線と c の接点\n return crosspoint(c, C(p, sqrt(norm(p - c.p) - c.r * c.r)));\n}\n\nvector<L> tangent(C c1, C c2) { // 共通接線\n vector<L> ret;\n if (c1.r < c2.r)\n swap(c1, c2);\n R r = abs(c2.p - c1.p);\n if (eq(r, 0.0))\n return ret;\n P u = (c2.p - c1.p) / r;\n P v = rot(u, pi * 0.5);\n for (R s : {1.0, -1.0}) {\n R h = (c1.r + c2.r * s) / r;\n if (eq(abs(h), 1.0)) {\n ret.emplace_back(c1.p + u * c1.r, c1.p + (u + v) * c1.r);\n } else if (abs(h) < 1.0) {\n P uu = u * h, vv = v * sqrt(1.0 - h * h);\n ret.emplace_back(c1.p + (uu + vv) * c1.r, c2.p - (uu + vv) * c2.r * s);\n ret.emplace_back(c1.p + (uu - vv) * c1.r, c2.p - (uu - vv) * c2.r * s);\n }\n }\n return ret;\n}\n\nVP convex_hull(VP p) { // 凸包\n sort(all(p), cp_x);\n p.erase(unique(all(p)), end(p));\n int n = sz(p), k = 0;\n if (n == 1)\n return p;\n VP ch(2 * n);\n for (int i = 0; i < n; ch[k++] = p[i++]) {\n while (k >= 2 && sgn(det(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1])) <= 0)\n k--;\n }\n for (int i = n - 2, t = k + 1; i >= 0; ch[k++] = p[i--]) {\n while (k >= t && sgn(det(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1])) <= 0)\n k--;\n }\n ch.resize(k - 1);\n return ch;\n}\n\nR closest_pair(VP p) { // 最近点対の距離\n if (sz(p) <= 1)\n return 1e18;\n sort(all(p), cp_x);\n VP memo(sz(p));\n\n function<R(int, int)> rec = [&](int l, int r) {\n if (r - l <= 1)\n return R(1e18);\n int m = (l + r) >> 1;\n R x = X(p[m]);\n R ret = min(rec(l, m), rec(m, r));\n inplace_merge(p.begin() + l, p.begin() + m, p.begin() + r, cp_y);\n int cnt = 0;\n reps(i, l, r) {\n if (abs(X(p[i]) - x) >= ret)\n continue;\n rep(j, cnt) {\n P d = p[i] - memo[cnt - j - 1];\n if (Y(d) >= ret)\n break;\n chmin(ret, abs(d));\n }\n memo[cnt++] = p[i];\n }\n return ret;\n };\n\n return rec(0, sz(p));\n}\n\nR farthest_pair(VP p) {//最遠点対の距離\n VP ps = convex_hull(p);\n ll n = ps.size();\n if(n == 2){//凸包が潰れてる\n return dist(ps[0],ps[1]);\n }\n ll i = 0,j = 0;\n rep(k,n){//x軸方向に最も遠い点対を求める\n if(cp_x(ps[k],ps[i]))i = k;\n if(cp_x(ps[j],ps[k]))j = k;\n }\n R ret = 0;\n ll si = i,sj = j;\n while(i != sj || j != si){//180度反転しきるまで\n ret = max(ret,dist(ps[i],ps[j]));\n if(det(ps[(i+1)%n] - ps[i],ps[(j+1)%n]-ps[j]) < 0){\n i = (i + 1) % n;\n }else{\n j = (j + 1) % n;\n }\n }\n return ret;\n}\n\n// 原点, 点 a, 点 b とで囲まれる領域の面積 (三角形 ver と扇型 ver)\nR calc_element(P a, P b, R cr,bool triangle){\n if(triangle)return det(a,b)/2;\n else{\n P tmp = b * (P(X(a),-Y(a)));\n R ang = atan2(Y(tmp),X(tmp));\n return cr * cr * ang/2;\n }\n}\n\n// 円 C と、三角形 ((0, 0), ia, ib) との共通部分の面積\nR common_area(C c, P ia,P ib){\n P a = ia - c.p , b = ib - c.p;\n if(eq(abs(a-b),0))return 0;\n bool isin_a = (sgn(c.r - abs(a))>= 0);\n bool isin_b = (sgn(c.r - abs(b))>= 0);\n if(isin_a && isin_b)return calc_element(a,b,c.r,true);//aもbも円の中\n\n C oc(P(0,0),c.r);\n S seg(a,b);\n VP cr = crosspoint(oc,seg);\n if(cr.empty())return calc_element(a,b,c.r,false);\n P s = cr[0],t = cr.back();\n return calc_element(s,t,c.r,true) + calc_element(a,s,c.r,isin_a) + calc_element(t,b,c.r,isin_b);\n\n}\n\n\nR common_area(C c, VP vp){// 円cと多角形の共通部分の面積\n R ret = 0;\n ll n = vp.size();\n rep(i,n){\n ret += common_area(c,vp[i],vp[(i+1)%n]);\n }\n return ret;\n}\n\nR common_area(C p, C q) {// 円と円の共通部分の面積\n R d = abs(p.p - q.p);\n if (d >= p.r + q.r - EPS) return 0;\n else if (d <= abs(p.r - q.r) + EPS) return min(p.r, q.r) * min(p.r, q.r) * pi;\n R pcos = (p.r*p.r + d*d - q.r*q.r) / (p.r*d*2);\n R pang = acosl(pcos);\n R parea = p.r*p.r*pang - p.r*p.r*sin(pang*2)/2;\n R qcos = (q.r*q.r + d*d - p.r*p.r) / (q.r*d*2);\n R qang = acosl(qcos);\n R qarea = q.r*q.r*qang - q.r*q.r*sin(qang*2)/2;\n return parea + qarea;\n}\n\nvector<VP> divisions(vector<L> lf, R lim = 1e9) {\n vector<L> ls;\n each(l, lf) {\n bool ok = true;\n each(m, ls) {\n if (para(l, m) & inter(l, m.a)) {\n ok = false;\n break;\n }\n }\n if (ok)\n ls.emplace_back(l);\n }\n VP lc{P(-lim, -lim), P(lim, -lim), P(lim, lim), P(-lim, lim)};\n rep(i, 4) ls.emplace_back(lc[i], lc[(i + 1) % 4]);\n int m = sz(ls);\n VP ps;\n vector<vector<int>> lp(m);\n rep(i, m) {\n reps(j, i + 1, m) {\n each(p, crosspoint(ls[i], ls[j])) {\n if (max(abs(X(p)), abs(Y(p))) < lim + EPS) {\n lp[i].emplace_back(sz(ps)), lp[j].emplace_back(sz(ps));\n ps.emplace_back(p);\n }\n }\n }\n }\n int n = sz(ps);\n vector<int> id(n, -1), to;\n vector<R> rg;\n vector<vector<pair<R, int>>> li(n);\n rep(i, m) {\n sort(all(lp[i]), [&ps](int a, int b) { return cp_x(ps[a], ps[b]); });\n vector<int> q;\n rep(j, sz(lp[i])) {\n int me = id[lp[i][j]], st = j;\n auto np = ps[lp[i][j]];\n while (j + 1 < sz(lp[i])) {\n if (abs(ps[lp[i][j + 1]] - np) < EPS) {\n j++;\n if (id[lp[i][j]] != -1)\n me = id[lp[i][j]];\n } else\n break;\n }\n if (me == -1)\n me = lp[i][st];\n reps(k, st, j + 1) id[lp[i][k]] = me;\n q.emplace_back(me);\n }\n rep(i, sz(q) - 1) {\n P d = ps[q[i + 1]] - ps[q[i]];\n R s = atan2(Y(d), X(d)), t = atan2(-Y(d), -X(d));\n int x = q[i], y = q[i + 1];\n li[x].emplace_back(s, sz(to));\n li[x].emplace_back(s + pi * 2, sz(to));\n to.emplace_back(y), rg.emplace_back(t);\n li[y].emplace_back(t, sz(to));\n li[y].emplace_back(t + pi * 2, sz(to));\n to.emplace_back(x), rg.emplace_back(s);\n }\n }\n rep(i, n) sort(all(li[i]));\n vector<bool> u(sz(to), false);\n vector<VP> ret;\n rep(i, n) {\n each(l, li[i]) {\n int ns = l.second;\n if (u[ns])\n continue;\n VP nv;\n int no = ns;\n bool ok = true;\n while (1) {\n if (sz(nv) > 1) {\n P x = nv[sz(nv) - 2], y = nv[sz(nv) - 1], z = ps[to[no]];\n int c = ccw(x, y, z);\n if (c == 1)\n ok = false;\n if (c != -1)\n nv.pop_back();\n }\n nv.emplace_back(ps[to[no]]);\n u[no] = true;\n no = upper_bound(all(li[to[no]]), pair(rg[no] + EPS, -1))->second;\n if (no == ns)\n break;\n }\n if (ok)\n ret.emplace_back(nv);\n }\n }\n return ret;\n}\n//ref https://github.com/drken1215/algorithm/blob/master/Geometry/arg_sort.cpp\n//verify https://atcoder.jp/contests/abc139/submissions/me\n//点列を偏角ソート\nvoid arg_sort(VP &v){\n //原点=0,(pi,2pi] = -1 (0pi,pi] = 1\n auto sign = [&](const P &p){\n if(sgn(X(p)) == 0 && sgn(Y(p)) == 0){\n return 0;\n }else if(sgn(Y(p)) == -1 || (sgn(Y(p)) == 0 && sgn(X(p)) == 1)){\n return -1;\n }else{\n return 1;\n }\n };\n auto cp = [&](const P &p,const P &q){\n if(sign(p) != sign(q)){\n return sign(p) < sign(q);\n }else{//外積>0で判定\n //同じ向きのときは未定義必要に応じて決める\n return X(p) * Y(q) - Y(p) * X(q) > 0;\n }\n };\n sort(v.begin(),v.end(),cp);\n}\n\n\n// 変数をちゃんと全部受け取る!\nvoid solve(ll n){\n VP vp(n);\n rep(i,n){\n LD(x,y);\n vp[i] = P(x,y);\n }\n ll ans = 1;\n rep(i,n)rep(j,i){\n C c1(vp[i],1.0);\n C c2(vp[j],1.0);\n\n VP crs = crosspoint(c1,c2);\n each(p,crs){\n ll tmp = 0;\n rep(k,n){\n if(sgn(1.0 - dist(p,vp[k])) >= 0){\n tmp++;\n }\n } \n chmax(ans,tmp);\n }\n \n }\n cout << ans << endl;\n}\n \nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true){\n LL(n);//変数数調整\n if(zero(n))break;\n solve(n);\n }\n}", "accuracy": 1, "time_ms": 3490, "memory_kb": 3920, "score_of_the_acc": -1.2191, "final_rank": 20 }, { "submission_id": "aoj_1132_9345320", "code_snippet": "/// 生成AI不使用 / Not using generative AI\n\n// #pragma GCC target (\"avx\")\n// #pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#ifdef MARC_LOCAL\n#define _GLIBCXX_DEBUG\n#endif\n\n#ifdef ATCODER\n#include <atcoder/all>\nusing namespace atcoder;\n#endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n//#define int long long\nusing ll = long long; using vll = vector<ll>; using vvll = vector<vll>; using vvvll = vector<vvll>; using vvvvll = vector<vvvll>;\nusing vi = vector<int>; using vvi = vector<vi>; using vvvi = vector<vvi>; using vvvvi = vector<vvvi>;\nusing ld = long double; using vld = vector<ld>; using vvld = vector<vld>; using vd = vector<double>;\nusing vc = vector<char>; using vvc = vector<vc>; using vs = vector<string>;\nusing vb = vector<bool>; using vvb = vector<vb>; using vvvb = vector<vvb>;\nusing pii = pair<int, int>; using pcc = pair<char, char>; using pll = pair<ll, ll>; using pli = pair<ll, int>; using pdd = pair<double, double>; using pldld = pair<ld,ld>;\nusing vpii = vector<pii>; using vvpii = vector<vpii>; using vpll = vector<pll>; using vvpll = vector<vpll>; using vpldld = vector<pldld>;\nusing ui = unsigned int; using ull = unsigned long long;\nusing i128 = __int128; using f128 = __float128;\ntemplate<class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define vv(type, name, h, ...) vector<vector<type> > name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) vector<vector<vector<type> > > name(h, vector<vector<type> >(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) vector<vector<vector<vector<type> > > > name(a, vector<vector<vector<type> > >(b, vector<vector<type> >(c, vector<type>(__VA_ARGS__))))\n\n#define overload4(a,b,c,d,name,...) name\n#define rep1(n) for(ll i = 0; i < (ll)n; i++)\n#define rep2(i,n) for(ll i = 0; i < (ll)n; i++)\n#define rep3(i,a,b) for (ll i = a; i < (ll)b; i++)\n#define rep4(i,a,b,c) for (ll i = a; i < (ll)b; i += (ll)c)\n#define rep(...) overload4(__VA_ARGS__,rep4,rep3,rep2,rep1)(__VA_ARGS__)\n#define repback1(n) for (ll i = (ll)n-1; i >= 0; i--)\n#define repback2(i,n) for (ll i = (ll)n-1; i >= 0; i--)\n#define repback3(i,a,b) for (ll i = (ll)b-1; i >= (ll)a; i--)\n#define repback4(i,a,b,c) for (ll i = (ll)b-1; i >= (ll)a; i -= (ll)c)\n#define repback(...) overload4(__VA_ARGS__,repback4,repback3,repback2,repback1)(__VA_ARGS__)\n#define all(x) (x).begin(), (x).end()\n#define include(y, x, H, W) (0 <= (y) && (y) < (H) && 0 <= (x) && (x) < (W))\n#define inrange(x, down, up) ((down) <= (x) && (x) <= (up))\n#define pb push_back\n#define eb emplace_back\n#define fir first\n#define sec second\n#define TIMER_START TIME_START = clock()\n#ifdef MARC_LOCAL\n// https://trap.jp/post/1224/\n#define debug1(x) cout << \"debug: \" << (#x) << \": \" << (x) << endl\n#define debug2(x, y) cout << \"debug: \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << endl\n#define debug3(x, y, z) cout << \"debug: \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << \", \" << (#z) << \": \" << (z) << endl\n#define debug4(x, y, z, w) cout << \"debug: \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << \", \" << (#z) << \": \" << (z) << \", \" << (#w) << \": \" << (w) << endl\n#define debug5(x, y, z, w, v) cout << \"debug: \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << \", \" << (#z) << \": \" << (z) << \", \" << (#w) << \": \" << (w) << \", \" << (#v) << \": \" << (v) << endl\n#define debug6(x, y, z, w, v, u) cout << \"debug: \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << \", \" << (#z) << \": \" << (z) << \", \" << (#w) << \": \" << (w) << \", \" << (#v) << \": \" << (v) << \", \" << (#u) << \": \" << (u) << endl\n#define overload6(a, b, c, d, e, f, g,...) g\n#define debug(...) overload6(__VA_ARGS__, debug6, debug5, debug4, debug3, debug2, debug1)(__VA_ARGS__)\n#define debuga cerr << \"a\" << endl\n#define debugnl cout << endl\n#define Case(i) cout << \"Case #\" << (i) << \": \"\n#define TIMECHECK cerr << 1000.0 * static_cast<double>(clock() - TIME_START) / CLOCKS_PER_SEC << \"ms\" << endl\n#define LOCAL 1\n#else\n#define debug1(x) void(0)\n#define debug2(x, y) void(0)\n#define debug3(x, y, z) void(0)\n#define debug4(x, y, z, w) void(0)\n#define debug5(x, y, z, w, v) void(0)\n#define debug6(x, y, z, w, v, u) void(0)\n#define debug(...) void(0)\n#define debuga void(0)\n#define debugnl void(0)\n#define Case(i) void(0)\n#define TIMECHECK void(0)\n#define LOCAL 0\n#endif\n\n//mt19937_64 rng(0);\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nclock_t TIME_START;\nconst long double pi = 3.141592653589793238462643383279L;\nconst long long INFL = 1000000000000000000ll;\nconst long long INFLMAX = numeric_limits< long long >::max(); // 9223372036854775807\nconst int INF = 1000000000;\nconst int INFMAX = numeric_limits< int >::max(); // 2147483647\nconst long double INFD = numeric_limits<ld>::infinity();\nconst long double EPS = 1e-10;\nconst int mod1 = 1000000007;\nconst int mod2 = 998244353;\nconst vi dx1 = {1,0,-1,0};\nconst vi dy1 = {0,1,0,-1};\nconst vi dx2 = {0, 1, 1, 1, 0, -1, -1, -1};\nconst vi dy2 = {1, 1, 0, -1, -1, -1, 0, 1};\nconstexpr char nl = '\\n';\nconstexpr char bl = ' ';\n\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\ntemplate<class T, class U> bool chmin(T& a, const U& b){ return chmin(a, (T)b); }\ntemplate<class T, class U> bool chmax(T& a, const U& b){ return chmax(a, (T)b); }\n\n\n/// 2D計算幾何ライブラリ\n// 謎のバグが発生したら、比較部分での誤差(±EPSを設定)や整数幾何で出来ないか?を考えると良いかも\n// AOJの文字数制限に引っかかる場合は、仕方ないので適当に不要な関数を削る\nnamespace Geometry {\n constexpr long double EPS = (1e-10);\n constexpr long double pi = 3.141592653589793238462643383279L;\n std::mt19937_64 mt(std::chrono::steady_clock::now().time_since_epoch().count());\n\n template <class T, class U> bool equals(T a, U b) { return fabsl(a - b) < EPS; }\n template <class T, class U> bool notequals(T a, U b) { return !equals(a, b); }\n template <class T> int sign(T a) { return equals(a, 0) ? 0 : a > 0 ? 1 : -1; }\n\n\n /// 2次元平面上の点(x,y)\n template <class T>\n class Point2D { // D は dimension の D (Double ではない) -> OpenGL等の著名ライブラリとの命名規則統一すべき?\n public:\n T x, y; // privateにしても良い、要検討\n bool valid; // 有効な点か?\n int idx;\n\n Point2D() : x(0), y(0), valid(false) {}\n Point2D(T x, T y): x(x), y(y), valid(true) {}\n template <class U> Point2D(const Point2D<U>& P_) : x((T)P_.x), y((T)P_.y), valid(P_.valid), idx(P_.idx) {}\n template <class U1, class U2> Point2D(const std::pair<U1, U2>& p) : x(p.first), y(p.second), valid(true) {}\n \n \n Point2D operator + (const Point2D& p) const {return Point2D(x + p.x, y + p.y); }\n Point2D operator - (const Point2D& p) const {return Point2D(x - p.x, y - p.y); }\n Point2D operator * (T a) const {return Point2D(a * x, a * y); }\n Point2D operator / (T a) const {return Point2D(x / a, y / a); }\n Point2D& operator+=(const Point2D& p) { return (*this) = (*this) + p; }\n Point2D& operator-=(const Point2D& p) { return (*this) = (*this) - p; }\n Point2D& operator*=(T a) { return (*this) = (*this) * a; }\n Point2D& operator/=(T a) { return (*this) = (*this) / a; }\n bool operator<(const Point2D& p) const { return notequals(x, p.x) ? x < p.x : y < p.y; }\n bool operator==(const Point2D& p) const { return equals(x, p.x) && equals(y, p.y); }\n bool operator!=(const Point2D& p) const { return !((*this) == p); }\n \n\n T real() const { return x; }\n T imag() const { return y; }\n T xpos() const { return x; }\n T ypos() const { return y; }\n T dot(const Point2D& p) const { return x * p.x + y * p.y; }\n T cross(const Point2D& p) const { return x * p.y - y * p.x; }\n T norm() const { return x * x + y * y; }\n long double abs() const { return std::sqrt(norm()); }\n long double arg() const { return std::atan2(y, x); }\n\n // Center中心、反時計回りにrad度回転\n void rotate(const Point2D& Center, const T rad) {\n x -= Center.x, y -= Center.y;\n T x_ = x * std::cos(rad) - y * std::sin(rad);\n T y_ = x * std::sin(rad) + y * std::cos(rad);\n x = x_ + Center.x, y = y_ + Center.y;\n }\n\n // 原点中心、反時計回りにrad度回転\n void rotate(const T rad) { \n rotate(Point2D(0, 0), rad);\n }\n\n // 原点中心、反時計回りに90度回転\n void rot90() {\n T x_ = -y;\n y = x, x = x_;\n }\n\n // 単位ベクトルになるように変換\n void unit() {\n T len = this->abs();\n x /= len, y /= len;\n }\n\n // 偏角ソート用\n int argpos() const {\n if (equals(y, 0) && 0 <= x) return 0;\n if (y < 0) return -1;\n return 1;\n }\n\n void set_index(int i) { idx = i; }\n \n friend std::istream& operator>>(std::istream& is, Point2D& p) {\n T a, b;\n is >> a >> b;\n p = Point2D(a, b);\n return is;\n }\n friend std::ostream& operator<<(std::ostream& os, const Point2D& p) {\n return os << std::fixed << std::setprecision(15) << p.x << \" \" << p.y;\n }\n\n\n private :\n // constexpr long double EPS = (1e-10);\n // constexpr long double pi = 3.141592653589793238462643383279L;\n \n // bool equals(T a, T b) { return fabsl(a - b) < EPS; }\n // bool notequals(T a, T b) { return !equlas(a, b); }\n // int sign(T a) { return equals(a, 0) ? 0 : a > 0 ? 1 : -1; }\n };\n using Point = Point2D<long double>;\n using Points = std::vector<Point>;\n using PoINT = Point2D<long long>;\n using PoINTs = std::vector<PoINT>;\n template <class T> \n using Polygon = std::vector<Point2D<T> >; // 多角形\n\n template <class T>\n using Vector2D = Point2D<T>; // 向き(x,y)と大きさ(abs(x,y))を持つ\n using Vector = Vector2D<long double>;\n\n\n template <class T> T real(const Point2D<T>& p) { return p.x; } // 実部\n template <class T> T imag(const Point2D<T>& p) { return p.y; } // 虚部\n template <class T> T dot(const Point2D<T>& l, const Point2D<T>& r) { return l.x * r.x + l.y * r.y; } // 内積\n template <class T> T cross(const Point2D<T>& l, const Point2D<T>& r) { return l.x * r.y - l.y * r.x; } // 外積\n template <class T> T norm(const Point2D<T>& p) { return p.x * p.x + p.y * p.y; } // 2-ノルム(ユークリッドノルム)の2乗\n template <class T> long double abs(const Point2D<T>& p) { return std::sqrt(norm(p)); } // 大きさ(絶対値)\n template <class T> long double arg(const Point2D<T>& p) { return std::atan2(p.y, p.x); } // 偏角\n Point polar_to_xy(const long double r, const long double theta) { return Point(r * std::cos(theta), r * std::sin(theta)); } // 極座標(r, theta) -> xy座標(x, y)\n\n template <class T>\n long double arg(const Point2D<T>& P1, const Point2D<T>& P2) {\n return std::atan2(cross(P1, P2), dot(P1, P2));\n }\n\n // 偏角ソート(-pi ~ pi)\n template<class T>\n void arg_sort(std::vector<Point2D<T> >& Ps) {\n std::sort(Ps.begin(), Ps.end(), [](const Point2D<T>& P1, const Point2D<T>& P2) {\n if(P1.argpos() != P2.argpos()) return P1.argpos() < P2.argpos();\n return cross(P1, P2) > 0;\n });\n }\n\n // x座標でソート\n template<class T>\n void x_sort(std::vector<Point2D<T> >& Ps) {\n std::sort(Ps.begin(), Ps.end(), [](const Point2D<T>& a, const Point2D<T>& b){ return equals(a.x, b.x) ? a.y < b.y : a.x < b.x; });\n }\n\n // y座標でソート\n template<class T>\n void y_sort(std::vector<Point2D<T> >& Ps) {\n std::sort(Ps.begin(), Ps.end(), [](const Point2D<T>& a, const Point2D<T>& b){ return equals(a.y, b.y) ? a.x < b.x : a.y < b.y; });\n }\n\n\n /// Pを、Center中心、反時計回りにrad度回転\n template <class T>\n Point2D<T> rotate(Point2D<T> P, const Point2D<T>& Center, const T rad) {\n P -= Center;\n T x_ = P.x * std::cos(rad) - P.y * std::sin(rad);\n T y_ = P.x * std::sin(rad) + P.y * std::cos(rad);\n return Point2D<T>(x_ + Center.x, y_ + Center.y);\n }\n\n /// 点Pを、原点中心、反時計回りにrad度回転\n template <class T>\n Point2D<T> rotate(const Point2D<T>& P, const T rad) { \n return rotate(P, Point2D<T>(0, 0), rad);\n }\n\n // 原点中心、反時計回りに90度回転\n template <class T>\n Point2D<T> rot90(const Point2D<T>& P) {\n return Point2D<T>(-P.y, P.x);\n }\n\n /// V1の単位ベクトルを取得\n template <class T>\n Vector2D<T> unit(const Vector2D<T>& V1) {\n return V1 / V1.abs();\n }\n template <class T>\n Vector2D<T> unit(const Point2D<T>& P1, const Point2D<T>& P2) {\n Vector2D<T> V = P2 - P1;\n return unit(V);\n }\n\n /// 二点間の中点を取得\n template <class T>\n Point2D<T> mid(const Point2D<T>& P1, const Point2D<T>& P2) {\n return Point2D<T>((P1.x + P2.x) / 2, (P1.y + P2.y) / 2);\n }\n\n /// ベクトルAとベクトルBのなす角(B->Aの回転角、[-pi,pi])\n template <class T>\n long double get_angle(const Vector2D<T>& V1, const Vector2D<T>& V2) {\n long double ret = arg(V1) - arg(V2);\n while(ret > pi + EPS) ret -= 2 * pi;\n while(ret < -pi - EPS) ret += 2 * pi;\n return ret;\n }\n\n /// 2点 P1, P2 を通る二次元平面上の直線 Ax + By + C = 0\n template <class T>\n class Line2D {\n public : \n Point2D<T> P1, P2;\n T A, B, C;\n int idx;\n\n Line2D() = default;\n\n // P1, P2 -> Ax + By + C = 0 を計算\n Line2D(Point2D<T> P1, Point2D<T> P2) : P1(P1), P2(P2) // check\n {\n A = P2.y - P1.y;\n B = P1.x - P2.x;\n C = P1.y * (P2.x - P1.x) - P1.x * (P2.y - P1.y);\n }\n Line2D(T x1, T y1, T x2, T y2) : P1(Point2D<T>(x1, y1)), P2(Point2D<T>(x2, y2)) // check\n {\n A = P2.y - P1.y;\n B = P1.x - P2.x;\n C = P1.y * (P2.x - P1.x) - P1.x * (P2.y - P1.y);\n }\n\n // Ax + By + C = 0 -> P1, P2 を計算\n Line2D(T A, T B, T C) : A(A), B(B), C(C) // check\n {\n if(equals(A, 0)) P1 = Point2D(0, - C / B), P2 = Point2D(1, - C / B);\n else if(equals(B, 0)) P1 = Point2D(- C / A, 0), P2 = Point2D(- C / A, 1);\n else P1 = Point2D(0, - C / B), P2 = Point2D(- C / A , 0);\n }\n\n template <class U>\n Line2D(const Line2D<U>& L_) : Line2D<T>(Point2D<T>(L_.P1), Point2D<T>(L_.P2)) {}\n\n friend std::ostream &operator<<(std::ostream &os, Line2D &L) {\n return os << \"(\" << L.P1 << \"), (\" << L.P2 << \") / \" << L.A << \"x + \" << L.B << \"y + \"<< L.C;\n }\n\n\n // 直線の傾きを取得\n T Grad() {\n if(equals(B, 0)) return std::numeric_limits< T >::max();\n return - A / B;\n }\n\n // 中点を取得\n Point2D<T> mid() {\n return Point2D<T>((P1.x + P2.x) / 2, (P1.y + P2.y) / 2);\n }\n\n // 垂直二等分線を取得\n Line2D<T> bisector() {\n Point2D<T> M = this->mid();\n return Line2D<T>(M, M + rot90(P2-P1));\n }\n\n void set_index(int i) { idx = i; }\n \n\n private:\n // constexpr long double EPS = (1e-10);\n // constexpr long double pi = 3.141592653589793238462643383279L;\n \n // bool equals(T a, T b) { return fabsl(a - b) < EPS; }\n // bool notequals(T a, T b) { return !equlas(a, b); }\n // int sign(T a) { return equals(a, 0) ? 0 : a > 0 ? 1 : -1; }\n\n };\n using Line = Line2D<long double>;\n using Lines = std::vector<Line>;\n\n template <class T>\n using Segment2D = Line2D<T>; // P1, P2を端点とする線分\n using Segment = Segment2D<long double>;\n using Segments = std::vector<Segment>;\n\n /// 直線Aと直線Bのなす角(is_abs : 絶対値取る?, under90 : 0~pi/2に正規化?)\n template <class T>\n long double get_angle(const Line2D<T>& L1, const Line2D<T>& L2, const bool is_abs = false, const bool under90 = false) {\n long double ret = get_angle(L1.P2 - L1.P1, L2.P2 - L2.P1);\n if(is_abs) ret = std::abs(ret);\n if(under90 && ret > pi/2 + EPS) ret = pi - ret;\n if(under90 && ret < -pi/2 - EPS) ret = -pi - ret;\n return ret;\n }\n\n /// 二点間の垂直二等分線を取得\n template <class T>\n Line2D<T> bisector(const Point2D<T>& P1, const Point2D<T>& P2) {\n Point2D<T> M = mid(P1, P2);\n return Line2D<T>(M, M + rot90(P2-P1));\n }\n\n /// 中心点 c と、半径 r を持つ二次元平面上の円\n // TODO: 整数用に、半径を2乗で管理?2乗用の変数を追加しても良い \n template <class T>\n class Circle {\n public:\n Point2D<T> center;\n T radius;\n\n Circle() = default;\n\n Circle(T x, T y, T radius) : center(Point2D<T>(x, y)), radius(radius) {}\n\n Circle(Point2D<T> center, T radius) : center(center), radius(radius) {}\n\n template<class U>\n Circle(Circle<U> C_) : center(Point2D<T>(C_.center)), radius((T)C_.radius) {}\n\n bool operator==(const Circle& C) const { return center == C.center && equals(radius, C.radius); }\n bool operator!=(const Circle& C) const { return !((*this) == C); }\n\n \n };\n template <class T>\n using Circles = std::vector<Circle<T> >;\n using Circld = Circle<long double>;\n using Circlds = std::vector<Circld >;\n\n static const int COUNTER_CLOCKWISE = 1; // 反時計回り\n static const int CLOCKWISE = -1; // 時計回り\n static const int ONLINE_BACK = 2; // P2 -> P0 -> P1 の順で一直線 (P0 -> P1 とは逆方向にP2が存在)\n static const int ONLINE_FRONT = -2; // P0 -> P1 -> P2 の順で一直線 (P0 -> P1 と同方向にP2が存在)\n static const int ON_SEGMENT = 0; // P0 -> P2 -> P1 の順で一直線 (P0 -> P1 内にP2が存在)\n\n /**\n * @brief p0, p1, p2 がこの順で反時計回り(Counter Clock Wise)か?の判定\n * \n * @return 1 : COUNTER_CLOCKWISE(反時計回り)\n * -1 : CLOCKWISE(時計回り)\n * 2 : ONLINE_BACK(P2 -> P0 -> P1 の順で一直線 (P0 -> P1 とは逆方向にP2が存在))\n * -2 : ONLINE_FRONT(P0 -> P1 -> P2 の順で一直線 (P0 -> P1 と同方向にP2が存在))\n * 0 : ON_SEGMENT(P0 -> P2 -> P1 の順で一直線 (P0 -> P1 内にP2が存在))\n */\n template <class T>\n int ccw(const Point2D<T>& P0, const Point2D<T>& P1, const Point2D<T>& P2) {\n Vector2D<T> V1 = P1 - P0;\n Vector2D<T> V2 = P2 - P0;\n\n if(cross(V1, V2) > EPS) return COUNTER_CLOCKWISE; // 反時計回り\n else if(cross(V1, V2) < -EPS) return CLOCKWISE; // 時計回り\n else if(dot(V1, V2) < -EPS) return ONLINE_BACK; // P2 -> P0 -> P1 の順で一直線 (P0 -> P1 とは逆方向にP2が存在)\n else if(V1.norm() < V2.norm()) return ONLINE_FRONT; // P0 -> P1 -> P2 の順で一直線 (P0 -> P1 と同方向にP2が存在)\n else return ON_SEGMENT; // P0 -> P2 -> P1 の順で一直線 (P0 -> P1 内にP2が存在)\n }\n\n\n /// 直交判定\n template<class T>\n bool isOrthogonal(const Vector2D<T>& a, const Vector2D<T>& b) {\n return equals(dot(a, b), 0.0);\n }\n template<class T>\n bool isOrthogonal(const Point2D<T>& a1, const Point2D<T>& a2, const Point2D<T>& b1, const Point2D<T>& b2) {\n return isOrthogonal(a1 - a2, b1 - b2);\n }\n template<class T>\n bool isOrthogonal(const Line2D<T>& l1, const Line2D<T>& l2) {\n return equals(dot(l1.P2 - l1.P1, l2.P2 - l2.P1), 0.0);\n }\n\n\n /// 平行判定\n template<class T>\n bool isParallel(const Vector2D<T>& a, const Vector2D<T>& b) {\n return equals(cross(a, b), 0.0);\n }\n template<class T>\n bool isParallel(const Point2D<T>& a1, const Point2D<T>& a2, const Point2D<T>& b1, const Point2D<T>& b2) {\n return isParallel(a1 - a2, b1 - b2);\n }\n template<class T>\n bool isParallel(const Line2D<T>& l1, const Line2D<T>& l2) {\n return equals(cross(l1.P2 - l1.P1, l2.P2 - l2.P1), 0.0);\n }\n\n\n /// 射影\n // 直線l に対して 点p から垂線をおろした交点を求める\n // 内積とcosの関係を用いて計算\n template<class T>\n Point2D<T> projection(const Line2D<T>& l, const Point2D<T>& p) {\n Vector2D<T> base = l.P2 - l.P1;\n long double t = dot(p - l.P1, base) / norm(base);\n return l.P1 + base * t;\n }\n\n\n /// 反射\n // 直線l を対称軸として、点p と線対称にある点を求める\n template<class T>\n Point2D<T> reflection(const Line2D<T>& l, const Point2D<T>& p) {\n return p + (projection(l, p) - p) * 2.0;\n }\n\n\n /// 交点の計算\n // 交差することが前提(交差してない場合は valid=false)\n // http://www.deqnotes.net/acmicpc/2d_geometry/lines\n template<class T>\n Point2D<T> crosspointLL(const Line2D<T> &L1, const Line2D<T> &L2) {\n if(isParallel(L1, L2)) return Point2D<T>();\n \n Vector2D<T> base = L2.P2 - L2.P1;\n long double d1 = cross(base, L2.P1 - L1.P1);\n long double d2 = cross(base, L1.P2 - L1.P1);\n\n if(equals(std::abs(d1), 0.0) && equals(std::abs(d2), 0.0)) return L1.P1;\n return L1.P1 + (L1.P2 - L1.P1) * d1 / d2;\n }\n template<class T>\n Point2D<T> crosspointLS(const Line2D<T> &L, const Segment2D<T> &S) {\n if(isParallel(L, S)) return Point2D<T>();\n\n Point2D<T> ret = crosspointLL(L, S);\n if(ccw(S.P1, S.P2, ret) == 0) return ret; \n else return Point2D<T>();\n }\n template<class T>\n Point2D<T> crosspointSS(const Segment2D<T> &S1, const Segment2D<T> &S2) {\n if(isParallel(S1, S2)) return Point2D<T>();\n \n Point2D<T> ret = crosspointLL(S1, S2);\n if(ccw(S1.P1, S1.P2, ret) == 0 && ccw(S2.P1, S2.P2, ret) == 0) return ret;\n else return Point2D<T>();\n }\n\n\n /// 交差判定\n template<class T>\n bool intersectLP(const Line2D<T> &L, const Point2D<T> &P) {\n return abs(ccw(L.P1, L.P2, P)) != 1;\n }\n template<class T>\n bool intersectSP(const Segment2D<T> &S, const Point2D<T> &P) {\n return ccw(S.P1, S.P2, P) == 0;\n }\n template<class T>\n bool intersectLL(const Line2D<T> &L1, const Line2D<T> &L2) {\n return !isParallel(L1, L2);\n }\n template<class T>\n bool intersectLS(const Line2D<T> &L, const Segment2D<T> &S) {\n if(isParallel(L, S)) return false;\n\n return ccw(S.P1, S.P2, crosspoint(S, L)) == 0;\n }\n template<class T>\n bool intersectPPPP(const Point2D<T> &P1, const Point2D<T> &P2, const Point2D<T> &P3, const Point2D<T> &P4) { // 別の線分の端点が線分を堺に両側に分かれる(時計/反時計回り)ことを利用\n return (ccw(P1, P2, P3) * ccw(P1, P2, P4) <= 0 &&\n ccw(P3, P4, P1) * ccw(P3, P4, P2) <= 0);\n }\n template<class T>\n bool intersectSS(const Segment2D<T> &S1, const Segment2D<T> &S2) {\n return intersectPPPP(S1.P1, S1.P2, S2.P1, S2.P2);\n }\n\n\n /// 距離\n // 二点間の距離\n template<class T>\n long double distancePP(const Point2D<T> &P1, const Point2D<T> &P2) {\n return abs(P1 - P2);\n }\n\n // 直線と点の距離\n // 外積の絶対値が平行四辺形の面積になることを利用(距離が「高さ」に相当する)\n template<class T>\n long double distanceLP(const Line2D<T> &L, const Point2D<T> &P) {\n return std::abs(cross(L.P2 - L.P1, P - L.P1)) / abs(L.P2 - L.P1);\n }\n\n // 線分と点の距離\n // 角度に注目して端点で最小となるかを判定\n template<class T>\n long double distanceSP(const Segment2D<T> &S, const Point2D<T> &P) {\n if(dot(S.P2 - S.P1, P - S.P1) < 0.0) return abs(P - S.P1);\n if(dot(S.P1 - S.P2, P - S.P2) < 0.0) return abs(P - S.P2);\n return std::abs(cross(S.P2 - S.P1, P - S.P1)) / abs(S.P2 - S.P1);\n }\n\n // 線分と線分の距離\n // 端点の組が候補(三角不等式よりわかる)\n template<class T>\n long double distanceSS(const Segment2D<T> &S1, const Segment2D<T> &S2) {\n if(intersectSS(S1, S2)) return 0.0;\n return std::min({distanceSP(S1, S2.P1), distanceSP(S1, S2.P2), distanceSP(S2, S1.P1), distanceSP(S2, S1.P2)});\n }\n\n\n /// 円関連の交差判定など\n\n // 円と点の位置関係(内包関係)\n // 0: 外部, 1:内部, -1:周上\n // circumference : 周上も内部扱いする、 count_mode : 内部なら+1扱い\n template<class T>\n int contain(const Circle<T> &C, const Point2D<T> &P, const bool circumference = true, const bool count_mode = false) {\n long double d = distancePP(C.center, P);\n if(equals(d, C.radius)) return count_mode ? (circumference ? 1 : 0) : -1;\n else if(d < C.radius) return 1;\n else return 0;\n }\n\n // 円と直線の交差判定\n // 交点の数を返している\n template<class T>\n int intersectCL(const Circle<T> &C, const Line2D<T> &L) {\n long double d = distanceLP(L, C.center);\n\n if(equals(d, C.radius)) return 1;\n else if(d > C.radius) return 0;\n return 2;\n }\n\n // 円と線分の交差判定\n // 交点の数を返している(円が線分を内包している場合も交差していない扱い)\n template<class T>\n int intersectCS(const Circle<T> &C, const Segment2D<T> &S) {\n long double mn = distanceSP(S, C.center);\n if(equals(mn, C.radius)) return 1;\n else if(mn > C.radius) return 0;\n\n long double d1 = distancePP(S.P1, C.center);\n long double d2 = distancePP(S.P2, C.center);\n\n if(std::max(d1, d2) < C.radius) return 0;\n else if(std::min(d1, d2) > C.radius) return 2;\n else return 1;\n }\n\n // 二円の位置関係\n // 共通接線の数で識別(0: 完全に内包, 1: 内接, 2: 交差, 3: 外接, 4: 完全に離れている)\n template<class T>\n int intersectCC(Circle<T> C1, Circle<T> C2) {\n assert(C1!=C2);\n\n if(C1.radius < C2.radius) std::swap(C1, C2);\n \n // C1.radius >= C2.radius\n long double d = distancePP(C1.center, C2.center);\n if(equals(d, C1.radius + C2.radius)) return 3;\n else if(equals(d + C2.radius, C1.radius)) return 1;\n else if(C1.radius + C2.radius < d) return 4;\n else if(d + C2.radius < C1.radius) return 0;\n else return 2;\n }\n\n // 円と直線の交点(0~2つ)\n // x座標が小さいものから格納される、1つの場合は同じ頂点が2つ入る、0つの場合はvalid=false\n template<class T>\n std::pair<Point2D<T>, Point2D<T> > crosspointCL(const Circle<T> &C, const Line2D<T> &L) {\n Point2D<T> mid = projection(L, C.center);\n long double d = distanceLP(L, C.center);\n \n if(equals(d, C.radius)) return {mid, mid}; // 交点1つ\n else if(d > C.radius) return {Point2D<T>(), Point2D<T>()}; // 交点0つ\n\n Vector2D<T> e = unit(L.P1, L.P2);\n if(e.x < -EPS) e.x *= -1.0, e.y *= -1.0;\n else if(equals(e.x, 0) && e.y < -EPS) e.y *= -1.0; \n long double base = std::sqrt(C.radius * C.radius - norm(mid - C.center));\n return {mid - e * base, mid + e * base};\n }\n\n // 円と線分の交点(0~2つ)\n // x座標が小さいものから格納される、1つの場合は同じ頂点が2つ入る、0つの場合はvalid=false\n template<class T>\n std::pair<Point2D<T>, Point2D<T> > crosspointCS(const Circle<T> &C, const Segment2D<T> &S) {\n int cnt = intersectCS(C, S);\n if(cnt == 0) return {Point2D<T>(), Point2D<T>()};\n\n std::pair<Point2D<T>, Point2D<T> > ret = crosspointCL(C, Line2D<T>(S));\n if(cnt == 2) return ret;\n else {\n if(ccw(S.P1, S.P2, ret.first) == ON_SEGMENT) ret.second = ret.first;\n else ret.first = ret.second;\n return ret;\n }\n }\n\n // 円と円の交点(0~2つ)\n // x座標が小さいものから格納される、1つの場合は同じ頂点が2つ入る、0つの場合はvalid=false\n // 余弦定理から求めている\n template<class T>\n std::pair<Point2D<T>, Point2D<T> > crosspointCC(const Circle<T> &C1, const Circle<T> &C2) {\n int is_int = intersectCC(C1, C2);\n if(is_int == 0 || is_int == 4) return {Point2D<T>(), Point2D<T>()};\n\n Vector2D<T> V = C2.center - C1.center;\n long double d = abs(V);\n long double a = std::acos((C1.radius * C1.radius + d * d - C2.radius * C2.radius) / (2 * C1.radius * d));\n long double t = arg(V);\n\n std::pair<Point2D<T>, Point2D<T> > ret = std::make_pair(C1.center + polar_to_xy(C1.radius, t + a), C1.center + polar_to_xy(C1.radius, t - a));\n if(ret.first.x > ret.second.x) std::swap(ret.first, ret.second);\n else if(equals(ret.first.x, ret.second.x) && ret.first.y > ret.second.y) std::swap(ret.first, ret.second);\n return ret;\n }\n}\nnamespace G = Geometry;\n\nint N;\n\n/// 幾何典型:幅の主客転倒的なやつ(動かすものが幅・半径を持つのではなく、固定されてるものが幅・半径を持つと考えると、見通しが良くなることがある!)\nvoid solve() {\n G::Circlds C(N);\n rep(i,N) {\n ld x,y; cin >> x >> y;\n C[i] = G::Circld(x,y,1.0);\n }\n\n G::Points cand;\n rep(i,N) {\n rep(j,i+1,N) {\n auto tmp = G::crosspointCC(C[i], C[j]);\n if(tmp.first.valid) {\n cand.eb(tmp.first);\n cand.eb(tmp.second);\n }\n }\n }\n\n int ans = 1;\n for(const auto& p : cand) {\n int cur = 0;\n rep(i,N) cur += G::contain(C[i],p,true,true);\n chmax(ans,cur);\n }\n\n cout << ans << nl;\n\n}\n\n\n\nsigned main() {\n cin.tie(0); ios_base::sync_with_stdio(false);\n TIMER_START;\n //cout << fixed << setprecision(15);\n \n\n int tt = 1;\n //cin >> tt;\n while(tt){\n cin >> N;\n if(N == 0) break;\n\n solve();\n }\n\n TIMECHECK;\n return 0;\n}", "accuracy": 1, "time_ms": 470, "memory_kb": 6272, "score_of_the_acc": -1.1246, "final_rank": 19 }, { "submission_id": "aoj_1132_9334185", "code_snippet": "#include <bits/stdc++.h>\n\n#include <algorithm>\n#include <cmath>\n#include <iterator>\n#include <utility>\n#include <vector>\n\nusing Real = long double;\nconstexpr Real EPS = 1e-10;\nconst Real PI = std::acos(-1);\n\nint sign(Real x) {\n return x < -EPS ? -1 : x > EPS ? 1 : 0;\n}\n\nbool eq(Real lhs, Real rhs) {\n return sign(rhs - lhs) == 0;\n}\n\nbool lte(Real lhs, Real rhs) {\n return sign(rhs - lhs) >= 0;\n}\n\nbool lt(Real lhs, Real rhs) {\n return sign(rhs - lhs) > 0;\n}\n\nbool gte(Real lhs, Real rhs) {\n return lte(rhs, lhs);\n}\n\nbool gt(Real lhs, Real rhs) {\n return lt(rhs, lhs);\n}\n\nstruct Point {\n Real x;\n Real y;\n Point(Real x = 0, Real y = 0): x(x), y(y) {}\n Point& operator+=(Point rhs) {\n this->x += rhs.x;\n this->y += rhs.y;\n return *this;\n }\n Point& operator-=(Point rhs) {\n this->x -= rhs.x;\n this->y -= rhs.y;\n return *this;\n }\n Point& operator*=(Real k) {\n this->x *= k;\n this->y *= k;\n return *this;\n }\n Point& operator/=(Real k) {\n this->x /= k;\n this->y /= k;\n return *this;\n }\n friend Point operator+(Point lhs, Point rhs) {\n return lhs += rhs;\n }\n friend Point operator-(Point lhs, Point rhs) {\n return lhs -= rhs;\n }\n friend Point operator*(Point p, Real k) {\n return p *= k;\n }\n friend Point operator/(Point p, Real k) {\n return p /= k;\n }\n friend Point operator*(Real k, Point p) {\n return p * k;\n }\n friend Point operator/(Real k, Point p) {\n return p / k;\n }\n friend bool operator==(Point lhs, Point rhs) {\n return eq(lhs.x, rhs.x) && eq(lhs.y, rhs.y);\n }\n friend bool operator<(Point lhs, Point rhs) {\n if (eq(lhs.x, rhs.x)) return lt(lhs.y, rhs.y);\n return lt(lhs.x, rhs.x);\n }\n friend bool operator>(Point lhs, Point rhs) {\n return rhs < lhs;\n }\n};\n\nusing Points = std::vector<Point>;\nusing Polygon = Points;\nusing Vector = Point;\n\nReal norm(Vector p) {\n return p.x * p.x + p.y * p.y;\n}\n\nReal abs(Vector p) {\n return std::sqrt(norm(p));\n}\n\nReal dot(Vector lhs, Vector rhs) {\n return lhs.x * rhs.x + lhs.y * rhs.y;\n}\n\nReal cross(Vector lhs, Vector rhs) {\n return lhs.x * rhs.y - lhs.y * rhs.x;\n}\n\nint ccw(Point p0, Point p1, Point p2) {\n Vector a = p1 - p0;\n Vector b = p2 - p0;\n\n if (cross(a, b) > EPS) return 1;\n\n if (cross(a, b) < -EPS) return -1;\n\n if (dot(a, b) < 0) return 2;\n\n if (norm(a) < norm(b)) return -2;\n\n return 0;\n}\n\nstruct Circle {\n Real r;\n Point c;\n Circle() {}\n Circle(Real r, Point c): r(r), c(c) {}\n};\n\nstruct Segment {\n Segment() {}\n Segment(Point p0, Point p1): p0(p0), p1(p1) {}\n Point p0, p1;\n};\n\nstruct Line {\n Line() {}\n Line(Point p0, Point p1): p0(p0), p1(p1) {}\n explicit Line(Segment s): p0(s.p0), p1(s.p1) {}\n Point p0, p1;\n};\n\nReal distance(Point lhs, Point rhs) {\n return abs(rhs - lhs);\n}\n\nReal distance(Line l, Point p) {\n return std::abs(cross(l.p1 - l.p0, p - l.p0)) / abs(l.p1 - l.p0);\n}\n\nReal distance(Segment s, Point p) {\n if (dot(s.p1 - s.p0, p - s.p0) < 0) {\n return distance(p, s.p0);\n }\n if (dot(s.p0 - s.p1, p - s.p1) < 0) {\n return distance(p, s.p1);\n }\n return distance(Line(s), p);\n}\n\nbool intersect(Segment lhs, Segment rhs) {\n return ccw(lhs.p0, lhs.p1, rhs.p0) * ccw(lhs.p0, lhs.p1, rhs.p1) <= 0\n && ccw(rhs.p0, rhs.p1, lhs.p0) * ccw(rhs.p0, rhs.p1, lhs.p1) <= 0;\n}\n\nbool intersect(Segment s, Point p) {\n return ccw(s.p0, s.p1, p) == 0;\n}\n\nReal distance(Segment lhs, Segment rhs) {\n if (intersect(lhs, rhs)) {\n return Real(0);\n }\n return std::min({distance(lhs, rhs.p0), distance(lhs, rhs.p1), distance(rhs, lhs.p0), distance(rhs, lhs.p1)});\n}\n\nbool parallel(Vector lhs, Vector rhs) {\n return eq(cross(lhs, rhs), 0);\n}\n\nbool parallel(Segment lhs, Segment rhs) {\n return parallel(lhs.p0 - lhs.p1, rhs.p0 - rhs.p1);\n}\n\nbool parallel(Line lhs, Line rhs) {\n return parallel(lhs.p0 - lhs.p1, rhs.p0 - rhs.p1);\n}\n\nPoint crosspoint(Line lhs, Line rhs) {\n Real a = cross(lhs.p1 - lhs.p0, rhs.p1 - rhs.p0);\n Real b = cross(lhs.p1 - lhs.p0, lhs.p1 - rhs.p0);\n return rhs.p0 + (rhs.p1 - rhs.p0) * b / a;\n}\n\nbool intersect(Line l, Segment s) {\n return ccw(l.p0, l.p1, s.p0) * ccw(l.p0, l.p1, s.p1) <= 0;\n}\n\nbool intersect(Circle c, Line l) {\n return lte(distance(l, c.c), c.r);\n}\n\nbool intersect(Circle c, Point p) {\n return eq(distance(c.c, p), c.r);\n}\n\nbool internal(Circle c, Point p) {\n return lt(distance(c.c, p), c.r);\n}\n\nbool intersect(Circle c, Segment s) {\n return lte(distance(s, c.c), c.r);\n}\n\nint intersect(Circle lhs, Circle rhs) {\n if (gt(lhs.r, rhs.r)) std::swap(lhs, rhs);\n Real d = distance(lhs.c, rhs.c);\n if (lt(lhs.r + rhs.r, d)) return 4;\n if (eq(lhs.r + rhs.r, d)) return 3;\n if (gt(lhs.r + d, rhs.r)) return 2;\n if (eq(lhs.r + d, rhs.r)) return 1;\n return 0;\n}\n\nbool orthogonal(Vector lhs, Vector rhs) {\n return eq(dot(lhs, rhs), 0);\n}\n\nbool orthogonal(Segment lhs, Segment rhs) {\n return orthogonal(lhs.p0 - lhs.p1, rhs.p0 - rhs.p1);\n}\n\nbool orthogonal(Line lhs, Line rhs) {\n return orthogonal(lhs.p0 - lhs.p1, rhs.p0 - rhs.p1);\n}\n\nPoint crosspoint(Segment lhs, Segment rhs) {\n Real d0 = distance(Line(lhs.p0, lhs.p1), rhs.p0);\n Real d1 = distance(Line(lhs.p0, lhs.p1), rhs.p1);\n return rhs.p0 + (rhs.p1 - rhs.p0) * (d0 / (d0 + d1));\n}\n\nReal arg(Vector p) {\n return std::atan2(p.y, p.x);\n}\n\nVector polar(Real a, Real r) {\n return Point(std::cos(r) * a, std::sin(r) * a);\n}\n\nPoint rotate(Point p, Real t) {\n Point v = polar(1, t);\n return Point(p.x * v.x - p.y * v.y, p.x * v.y + p.y * v.x);\n}\n\nReal angle(Point p0, Point p1, Point p2) {\n Real a = arg(p0 - p1);\n Real b = arg(p2 - p1);\n if (gt(a, b)) std::swap(a, b);\n return std::min(b - a, 2 * PI - (b - a));\n}\n\nPoints crosspoint(Circle lhs, Circle rhs) {\n Real d = abs(lhs.c - rhs.c);\n if (eq(d, lhs.r + rhs.r)) return {lhs.c + lhs.r * (rhs.c - lhs.c) / d};\n Real a = std::acos((lhs.r * lhs.r + d * d - rhs.r * rhs.r) / (2 * lhs.r * d));\n Real t = arg(rhs.c - lhs.c);\n return {lhs.c + polar(lhs.r, t + a), lhs.c + polar(lhs.r, t - a)};\n}\n\nPoint projection(Segment s, Point p) {\n Vector a = p - s.p0;\n Vector b = s.p1 - s.p0;\n Real t = dot(a, b) / norm(b);\n return s.p0 + t * b;\n}\n\nPoint projection(Line l, Point p) {\n Vector a = p - l.p0;\n Vector b = l.p1 - l.p0;\n Real t = dot(a, b) / norm(b);\n return l.p0 + t * b;\n}\n\nPoint reflection(Segment s, Point p) {\n return p + (projection(s, p) - p) * Real(2);\n}\n\nPoint reflection(Line l, Point p) {\n return p + (projection(l, p) - p) * Real(2);\n}\n\nPoints crosspoint(Circle c, Line l) {\n Vector p = projection(l, c.c);\n Real t = std::sqrt(c.r * c.r - norm(c.c - p));\n if (eq(t, 0)) return {p};\n Vector e = (l.p1 - l.p0) / abs(l.p1 - l.p0);\n return {p + t * e, p + -t * e};\n}\n\nReal area(Polygon poly) {\n int n = poly.size();\n Real result = 0;\n for (int i = 0; i < n; i++) {\n result += cross(poly[i], poly[(i + 1) % n]);\n }\n return result / 2;\n}\n\nReal perimeter(Polygon poly) {\n int n = poly.size();\n Real result = 0;\n for (int i = 0; i < n; i++) {\n result += abs(poly[i] - poly[(i + 1) % n]);\n }\n return result;\n}\n\nbool convex(Polygon poly) {\n int n = poly.size();\n for (int i = 0; i < n; i++) {\n if (ccw(poly[i], poly[(i + 1) % n], poly[(i + 2) % n]) == -1) return false;\n }\n return true;\n}\n\nint contain(Polygon poly, Point p) {\n int n = poly.size();\n bool parity = false;\n for (int i = 0; i < n; i++) {\n Point a = poly[i] - p;\n Point b = poly[(i + 1) % n] - p;\n if (gt(a.y, b.y)) std::swap(a, b);\n if (lte(a.y, 0) && lt(0, b.y) && lt(cross(a, b), 0)) parity ^= true;\n if (eq(cross(a, b), 0) && lte(dot(a, b), 0)) return 1;\n }\n return (parity ? 2 : 0);\n}\n\nPolygon convex_hull(Points points) {\n std::sort(points.begin(), points.end(), [](Point lhs, Point rhs) {\n if (eq(lhs.x, rhs.x)) return lt(lhs.y, rhs.y);\n return lt(lhs.x, rhs.x);\n });\n int n = points.size();\n Points lower, upper;\n lower.push_back(points[n - 1]);\n lower.push_back(points[n - 2]);\n upper.push_back(points[0]);\n upper.push_back(points[1]);\n for (int i = n - 3; i >= 0; i--) {\n for (int m = lower.size(); m >= 2 && ccw(lower[m - 2], lower[m - 1], points[i]) >= 0; m--) {\n lower.pop_back();\n }\n lower.push_back(points[i]);\n }\n for (int i = 2; i < n; i++) {\n for (int m = upper.size(); m >= 2 && ccw(upper[m - 2], upper[m - 1], points[i]) >= 0; m--) {\n upper.pop_back();\n }\n upper.push_back(points[i]);\n }\n std::reverse(lower.begin(), lower.end());\n std::copy(std::next(upper.rbegin()), std::prev(upper.rend()), std::back_inserter(lower));\n return lower;\n}\n\nPolygon convex_cut(Polygon poly, Line l) {\n int n = poly.size();\n Polygon res;\n for (int i = 0; i < n; i++) {\n Point a = poly[i];\n Point b = poly[(i + 1) % n];\n if (ccw(l.p0, l.p1, a) != -1) res.push_back(a);\n if (ccw(l.p0, l.p1, a) * ccw(l.p0, l.p1, b) == -1) {\n res.push_back(crosspoint(l, Line(a, b)));\n }\n }\n return res;\n}\n\nLine bisector(Point p0, Point p1, Point p2) {\n return Line(p1, p1 + polar(1, angle(p0, p1, p2) / 2));\n}\n\nCircle incircle(Point p0, Point p1, Point p2) {\n Point c = crosspoint(bisector(p0, p1, p2), bisector(p1, p2, p0));\n Real r = std::abs(2 * area({p0, p1, p2}) / perimeter({p0, p1, p2}));\n return Circle(r, c);\n}\n\nLine perpendicular(Line l, Point p) {\n Vector v = l.p1 - l.p0;\n return Line(p, p + Vector(-v.y, v.x));\n}\n\nLine perpendicular_bisector(Segment s) {\n return perpendicular(Line(s), (s.p0 + s.p1) / 2);\n}\n\nCircle circumscribed_circle(Point p0, Point p1, Point p2) {\n Point c = crosspoint(perpendicular_bisector(Segment(p0, p1)), perpendicular_bisector(Segment(p0, p2)));\n return Circle(distance(p0, c), c);\n}\n\nReal area(Circle c) {\n return c.r * c.r * PI;\n}\n\nPoints tangent(Circle c, Point p) {\n return crosspoint(c, Circle(std::sqrt(norm(c.c - p) - c.r * c.r), p));\n}\n\nint solve() {\n int n;\n std::cin >> n;\n if (n == 0) return 1;\n\n std::vector<Circle> cs;\n for (int i = 0; i < n; i++) {\n Point c;\n std::cin >> c.x >> c.y;\n cs.push_back(Circle(1, c));\n }\n\n Points cps;\n for (int i = 0; i < n; i++) {\n for (int j = i + 1; j < n; j++) {\n auto t = intersect(cs[i], cs[j]);\n if (t != 0 && t != 4) {\n auto temp = crosspoint(cs[i], cs[j]);\n std::copy(temp.begin(), temp.end(), std::back_inserter(cps));\n }\n }\n }\n int ans = 1;\n\n for (auto cp: cps) {\n int cur = 0;\n for (auto& c: cs) {\n if (lte(norm(c.c - cp), 1)) {\n cur++;\n }\n }\n ans = std::max(ans, cur);\n }\n std::cout << ans << std::endl;\n return 0;\n}\n\nint main() {\n while (!solve())\n ;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 5344, "score_of_the_acc": -0.7499, "final_rank": 17 }, { "submission_id": "aoj_1132_9290715", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define rep(i,n) for(int i = 0;i < n;i++)\n\n#define int ll\n#define double long double\n#define IMAX ((1 << 31) - 1)\n#define LMAX ((1LL << 63) - 1)\n\n#define MOD 998244353\n\nint n;\n\nvector<double> intersect(double a, double b, double p, double q)\n{\n double s = 1 + a * a;\n double t = 2*a*(b-q) - 2*p;\n double u = p*p + (b-q)*(b-q) - 1;\n\n if( t*t - 4*s*u <= 0 ) return vector<double>(0);\n vector<double> x(2);\n x[0] = ( -t + sqrt(t*t - 4*s*u)) / (2*s);\n x[1] = ( -t - sqrt(t*t - 4*s*u)) / (2*s);\n return x;\n}\n\nint solve(const vector<pair<double,double>> pnts, int i, int j)\n{\n double a = (pnts[j].second - pnts[i].second) / (pnts[j].first - pnts[i].first);\n a = -1 / a;\n double abd = hypot(pnts[i].first - pnts[j].first, pnts[i].second - pnts[j].second);\n abd /= 2;\n\n double x_mid = (pnts[i].first + pnts[j].first) / 2;\n double y_mid = (pnts[i].second + pnts[j].second) / 2;\n\n double b = y_mid - a * x_mid;\n\n vector<double> x,y(2);\n x = intersect(a,b,pnts[i].first, pnts[i].second);\n if(x.size() == 0) return 1;\n for(int l = 0;l < 2;l++) y[l] = a*x[l] + b;\n\n int ans = 0;\n for(int p = 0;p < 2;p++) {\n int cnt = 0;\n for (int k = 0; k < n; k++) {\n if (k == i || k == j) continue;\n if (hypot(pnts[k].first - x[p], pnts[k].second - y[p]) < 1 ) cnt++;\n }\n ans = max(ans, cnt);\n }\n if(ans == 10) {\n// cout << \"over\" << endl;\n// cout << i <<\" \" << j << endl;\n }\n\n return ans + 2;\n}\nvoid main_()\n{\n cin >> n;\n if(n == 0) exit(0);\n\n vector<pair<double,double>> pnts, pnts_rev;\n\n rep(i,n)\n {\n double x,y;\n cin >> x >> y;\n pnts.emplace_back(x,y);\n pnts_rev.emplace_back(y,x);\n }\n int ans = 1;\n for(int i = 0;i < n - 1;i++)\n {\n for(int j = i + 1;j < n;j++)\n {\n int res = 0;\n if( abs(pnts[i].first - pnts[j].first) > abs(pnts[i].second - pnts[j].second)) res = solve(pnts, i,j);\n else res = solve(pnts_rev, i, j);\n// cout << i << \":\" << j << endl << res << endl;\n ans = max(res, ans);\n }\n }\n cout << ans << endl;\n}\nsigned main()\n{\n while(1) main_();\n}", "accuracy": 1, "time_ms": 3490, "memory_kb": 3584, "score_of_the_acc": -1.1076, "final_rank": 18 }, { "submission_id": "aoj_1132_9278548", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, a, n) for (int i = a; i < n; i++)\n\nusing P = complex<double>;\n\nint main() {\n while (1) {\n int n;\n cin >> n;\n if (n == 0) return 0;\n vector<P> p(n), center;\n rep(i, 0, n) {\n double x, y;\n cin >> x >> y;\n p[i] = P(x, y);\n }\n rep(i, 0, n) rep(j, i + 1, n) {\n double dist = abs(p[i] - p[j]);\n if (dist > 2.0) continue;\n P c = (p[i] + p[j]) / P(2.0);\n P e1 = (p[i] - p[j]) * P(0, 1), e2 = (p[i] - p[j]) * P(0, -1);\n e1 = e1/dist, e2 = e2/dist;\n double d = sqrt(1-(dist/2)*(dist/2));\n center.push_back(c+(e1*d));\n center.push_back(c+(e2*d));\n }\n int ans = 1;\n for(auto c: center){\n int count = 0;\n rep(i, 0, n){\n if(abs(p[i]-c)<1.0000001) count++;\n }\n ans = max(ans, count);\n }\n cout << ans << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 1170, "memory_kb": 3968, "score_of_the_acc": -0.5626, "final_rank": 15 } ]
aoj_1135_cpp
Problem A: Ohgas' Fortune The Ohgas are a prestigious family based on Hachioji. The head of the family, Mr. Nemochi Ohga, a famous wealthy man, wishes to increase his fortune by depositing his money to an operation company. You are asked to help Mr. Ohga maximize his profit by operating the given money during a specified period. From a given list of possible operations, you choose an operation to deposit the given fund to. You commit on the single operation throughout the period and deposit all the fund to it. Each operation specifies an annual interest rate, whether the interest is simple or compound, and an annual operation charge. An annual operation charge is a constant not depending on the balance of the fund. The amount of interest is calculated at the end of every year, by multiplying the balance of the fund under operation by the annual interest rate, and then rounding off its fractional part. For compound interest, it is added to the balance of the fund under operation, and thus becomes a subject of interest for the following years. For simple interest, on the other hand, it is saved somewhere else and does not enter the balance of the fund under operation (i.e. it is not a subject of interest in the following years). An operation charge is then subtracted from the balance of the fund under operation. You may assume here that you can always pay the operation charge (i.e. the balance of the fund under operation is never less than the operation charge). The amount of money you obtain after the specified years of operation is called ``the final amount of fund.'' For simple interest, it is the sum of the balance of the fund under operation at the end of the final year, plus the amount of interest accumulated throughout the period. For compound interest, it is simply the balance of the fund under operation at the end of the final year. Operation companies use C, C++, Java, etc., to perform their calculations, so they pay a special attention to their interest rates. That is, in these companies, an interest rate is always an integral multiple of 0.0001220703125 and between 0.0001220703125 and 0.125 (inclusive). 0.0001220703125 is a decimal representation of 1/8192. Thus, interest rates' being its multiples means that they can be represented with no errors under the double-precision binary representation of floating-point numbers. For example, if you operate 1000000 JPY for five years with an annual, compound interest rate of 0.03125 (3.125 %) and an annual operation charge of 3000 JPY, the balance changes as follows. The balance of the fund under operation (at the beginning of year) Interest The balance of the fund under operation (at the end of year) A B = A × 0.03125 (and rounding off fractions) A + B - 3000 1000000 31250 1028250 1028250 32132 1057382 1057382 33043 1087425 1087425 33982 1118407 1118407 34950 1150357 After the five years of operation, the final amount of fund is 1150357 JPY. If the interest is simple with all othe ...(truncated)
[ { "submission_id": "aoj_1135_1862389", "code_snippet": "#include <iostream>\nusing namespace std;\nint main(){\n int a, moneyF, yearL, vary, i1, i2, i3, s, moneyB1, moneyB2, risi1, risi2, moneyto, max;\n double per;\n i1 = 0;\n cin >> a;\n while(1){\n i1++;\n if(i1>a){break;}\n cin >> moneyF >> yearL >> vary;\n i2 = 0;\n max = 0;\n while(1){\n i2++;\n if(i2>vary){break;}\n cin >> s >> per >> moneyB1;\n i3 = 0;\n moneyB2 = moneyF;\n risi2 = 0;\n if(s==0){\n while(1){\n i3++;\n if(i3>yearL){break;}\n risi1 = moneyB2 * per;\n moneyB2 = moneyB2 - moneyB1;\n risi2 = risi2 + risi1;\n }\n }\n else{\n while(1){\n i3++;\n if(i3>yearL){break;}\n risi1 = moneyB2 * per;\n moneyB2 = moneyB2 + risi1 - moneyB1;\n }\n }\n moneyto = moneyB2 + risi2;\n if(max<moneyto){max = moneyto;}\n }\n cout << max << endl;\n \n \n }\n return 0;\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.3077, "final_rank": 3 }, { "submission_id": "aoj_1135_1845199", "code_snippet": "#include <iostream>\nusing namespace std;\n\nint investment = 0;\ndouble rate = 0;\nint commision = 0;\n\nint simple(int y){\n\tint wage = investment;\n\tint InterestTotal = 0;\n\t\n\tfor (int i = 0; i < y; i++){\n\t\tInterestTotal += wage * rate;\n\t\twage -= commision;\n\t}\n\twage += InterestTotal;\n\treturn wage;\n}\n\nint compound(int y){\n\tint wage = investment;\n\n\tfor (int i = 0; i < y; i++){\n\t\twage = (wage * (1+rate)) - commision;\n\t}\n\n\treturn wage;\n}\n\nint main(){\n\tint m; //????????????????????°\n\tint Max = 0;\n\tcin >> m;\n\n\tfor (int i = 0; i < m; i++){\n\t\tint y, n; //?????¨??´??°????¨??????°\n\t\tcin >> investment >> y >> n;\n\n\t\tfor (int j = 0; j < n; j++){\n\t\t\tint type; //??????:0, ??????:1\n\t\t\tcin >> type >> rate >> commision;\n\t\t\tint tmp;\n\n\t\t\tif (type == 0){\n\t\t\t\ttmp = simple(y);\n\t\t\t\tif (Max < tmp){\n\t\t\t\t\tMax = tmp;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse{\n\t\t\t\ttmp = compound(y);\n\t\t\t\tif (Max < tmp){\n\t\t\t\t\tMax = tmp;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << Max << endl;\n\t\tMax = 0;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.3077, "final_rank": 3 }, { "submission_id": "aoj_1135_1812055", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <cstdio>\n#include <functional>\n#include <numeric>\n#include <stack>\n#include <queue>\n#include <map>\n#include <set>\n#include <utility>\n#include <sstream>\n#include <complex>\n\nusing namespace std;\n\n#define FOR(i,a,b) for(long long i=(a);i<(b);i++)\n#define REP(i,N) for(long long i=0;i<(N);i++)\n#define ALL(s) (s).begin(),(s).end()\n#define fi first\n#define se second\n\n#define PI acos(-1.0)\n#define INF 1000000007\n#define EPS 1e-10\n#define MAX_N 20000\n#define MAX_M 16\n\ntypedef long long ll;\ntypedef pair<ll, ll> P;\ntypedef pair<double, double> PD;\ntypedef pair<string, ll> PS;\ntypedef vector<ll> V;\ntypedef pair<P, char> PC;\n\n#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <cstdio>\n#include <functional>\n#include <numeric>\n#include <stack>\n#include <queue>\n#include <map>\n#include <set>\n#include <utility>\n#include <sstream>\n#include <complex>\n\nusing namespace std;\n\n#define FOR(i,a,b) for(long long i=(a);i<(b);i++)\n#define REP(i,N) for(long long i=0;i<(N);i++)\n#define ALL(s) (s).begin(),(s).end()\n#define fi first\n#define se second\n\n#define PI acos(-1.0)\n#define INF 1000000007\n#define EPS 1e-10\n#define MAX_N 20000\n#define MAX_M 16\n\ntypedef long long ll;\ntypedef pair<ll, ll> P;\ntypedef pair<double, double> PD;\ntypedef pair<string, ll> PS;\ntypedef vector<ll> V;\ntypedef pair<P, char> PC;\n\nint m, n, t, y;\ndouble r, x, s;\n\nint main(){\n\tcin >> m;\n\twhile (m--){\n\t\tint ans = -1;\n\t\tcin >> s >> y >> n;\n\t\tREP(i, n){\n\t\t\tcin >> t >> r >> x;\n\t\t\tdouble money = s;\n\t\t\tif (t == 0){\n\t\t\t\tint sum = 0;\n\t\t\t\tREP(i, y){\n\t\t\t\t\tsum += (int)(money*r);\n\t\t\t\t\tmoney -= x;\n\t\t\t\t}\n\t\t\t\tmoney += sum;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tREP(i, y){\n\t\t\t\t\tmoney = money + (int)(money*r) - x;\n\t\t\t\t}\n\t\t\t}\n\t\t\tans = max(ans, (int)money);\n\t\t}\n\t\tcout << ans << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.3077, "final_rank": 3 }, { "submission_id": "aoj_1135_1778858", "code_snippet": "#include<iostream>\n#include<algorithm>\n\nusing namespace std;\n\nint rieki(bool ri,double riritu,int kingaku, int kikan,int tesuu){\n int risi=0;\n if(ri){\n for(int i=0;i<kikan;i++){\n kingaku=kingaku*(1+riritu)-tesuu;\n }\n }else{\n for(int i=0;i<kikan;i++){\n risi+=kingaku*riritu;\n kingaku-=tesuu;\n }\n }\n return kingaku+risi;\n}\n\nint main(){\n int m;\n cin>>m;\n for(int j=0;j<m;j++){\n int kane,nen;\n cin>>kane>>nen;\n int n;\n cin>>n;\n int ans=0;\n for(int k=0;k<n;k++){\n bool r;\n double riri;\n int te;\n cin>>r>>riri>>te;\n ans=max(rieki(r,riri,kane,nen,te),ans);\n }\n cout<<ans<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.3077, "final_rank": 3 }, { "submission_id": "aoj_1135_1625245", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\nint maxn, n, m, y, money, money2, a, c; double b;\nint main() {\n\tcin >> n;\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> money; money2 = money;\n\t\tcin >> y >> m; maxn = 0;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tcin >> a >> b >> c; money = money2;\n\t\t\tif (a == 1) {\n\t\t\t\tfor (int k = 0; k < y; k++) {\n\t\t\t\t\tmoney = (double)money*(1 + b);\n\t\t\t\t\tmoney -= c;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\tfor (int k = 0; k < y; k++) {\n\t\t\t\t\tmoney += (double)(money2 - k*c)*b;\n\t\t\t\t}\n\t\t\t\tmoney -= y*c;\n\t\t\t}\n\t\t\tmaxn = max(maxn, money);\n\t\t}\n\t\tcout << maxn << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.3077, "final_rank": 3 }, { "submission_id": "aoj_1135_1616275", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nconst int MAX_SIZE = 100;\n\nint calc(int a, int y, int n, int soc[], double air[], int aoc[]) {\n int r = 0;\n for (int i = 0; i < n; ++i) {\n int A = a;\n if (soc[i] == 0) {\n int interest = 0;\n for (int j = 0; j < y; ++j) {\n interest += A * air[i];\n A -= aoc[i];\n }\n A += interest;\n } else {\n for (int j = 0; j < y; ++j) {\n A += A * air[i] - aoc[i];\n }\n }\n r = max(r, A);\n }\n return r;\n}\n\nint main() {\n int a, n, m, y;\n int soc[MAX_SIZE], aoc[MAX_SIZE];\n double air[MAX_SIZE];\n cin >> m;\n for (int i = 0; i < m; ++i) {\n cin >> a >> y >> n;\n for (int j = 0; j < n; ++j) {\n cin >> soc[j] >> air[j] >> aoc[j];\n }\n cout << calc(a, y, n, soc, air, aoc) << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.3077, "final_rank": 3 }, { "submission_id": "aoj_1135_1603176", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <iterator>\n\nusing namespace std;\n\nlong long int calc(long long int type, double rate, long long int decr, long long int fund, long long int year){\n\tif(type == 0){\n\t\t\n\t\tint interest = 0;\n\t\t\n\t\tfor(int i = 0; i < year; i++){\n\t\t\tinterest += fund * rate;\n\t\t\tfund -= decr;\n\t\t}\n\t\t\n\t\tfund += interest;\n\t\t\n\t}else if(type == 1){\n\t\tfor(int i = 0; i < year; i++){\n\t\t\tfund *= (1 + rate);\n\t\t\tfund -= decr;\n\t\t}\n\t}\n\treturn fund;\n}\n\nint main(){\n\t\n\tint M;\n\t\n\tcin >> M;\n\t\n\tfor(int loop = 0; loop < M; loop++){\n\t\tlong long int fund, year, n, max;\n\t\tcin >> fund >> year >> n;\n\t\tmax = 0;\n\t\tfor(int i = 0; i < n; i++){\n\t\t\tlong long int type, decr, result;\n\t\t\tdouble rate;\n\t\t\tcin >> type >> rate >> decr;\n\t\t\tresult = calc(type, rate, decr, fund, year);\n\t\t\tif(max < result){\n\t\t\t\tmax = result;\n\t\t\t}\n\t\t}\n\t\tprintf(\"%lld\\n\", max);\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1224, "score_of_the_acc": -0.1538, "final_rank": 2 }, { "submission_id": "aoj_1135_1599258", "code_snippet": "#include <bits/stdc++.h>\n#define PB push_back\n#define MP make_pair\n#define REP(i,n) for (int i=0;i<(n);i++)\n#define FOR(i,a,b) for(int i=(a);i<(b);i++)\n#define ALL(a) (a).begin(),(a).end()\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> P;\ndouble EPS=1e-10;\nint INF=1e9;\nint MOD=1000000007;\nint main(){\n\tint m;\n\tcin>>m;\n\twhile(m--){\n\t\tint n,init,type,year,comm;\n\t\tdouble rate;\n\t\tcin>>init>>year>>n;\n\t\tint ans=0;\n\t\twhile(n--){\n\t\t\tcin>>type>>rate>>comm;\n\t\t\tint now=init;\n\t\t\tif(type){\n\t\t\t\tREP(i,year){\n\t\t\t\t\tnow=now*rate+now-comm;\n\t\t\t\t}\n\t\t\t}else{\n\t\t\t\tint sum=0;\n\t\t\t\tREP(i,year){\n\t\t\t\t\tsum+=now*rate;\n\t\t\t\t\tnow-=comm;\n\t\t\t\t}\n\t\t\t\tnow+=sum;\n\t\t\t}\n\t\t\tans=max(ans,now);\n\t\t}\n\t\tcout<<ans<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.3077, "final_rank": 3 }, { "submission_id": "aoj_1135_1447984", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cstdio>\n#include <string>\n#include <cmath>\n#include <algorithm>\nusing namespace std;\nint main(){\n\t\n\tint m;\n\tcin>>m;\n\tint y,n;\n\tlong long int A;\n\twhile(m>0){\n\t\tlong long int max=0;\n\t\tcin>>A>>y>>n;\n\t\tfor(int i=0;i<n;i++){\n\t\t\tint t,h;\n\t\t\tdouble x;\n\t\t\tlong long int a=A;\n\t\t\tlong long int B=0,s=0;\n\t\t\tcin>>t>>x>>h;\n\t\t\tfor(int j=0;j<y;j++){\n\t\t\t\tif(t!=0){\n\t\t\t\t\tB=a*x;\n\t\t\t\t\ta=a+B-h;\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tB=a*x;\n\t\t\t\t\ta=a-h;\n\t\t\t\t\ts+=B;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(max<a+s)\n\t\t\t\tmax=a+s;\n\t}\n\t\tcout<<max<<endl;\n\t\tm--;\n\t}\n\t\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.3077, "final_rank": 3 }, { "submission_id": "aoj_1135_1433273", "code_snippet": "#include \"bits/stdc++.h\"\n\nusing namespace std;\n\ntypedef vector<int> vi;\ntypedef pair<int,int> pii;\ntypedef long long ll;\n\n#define rep(i,n) for(ll i=0;i<(ll)(n);i++)\n#define all(a) (a).begin(),(a).end()\n#define pb push_back\n\nint solve(int money,int year,int type,double per,int mine){\n\tif(type==1){\n\t\trep(i,year){\n\t\t\tmoney=money+(int)( money * per);\n\t\t\tmoney-=mine;\n\t\t}\n\t\treturn money;\n\t}\n\telse{\n\t\tint tmp=0;\n\t\trep(i,year){\n\t\t\ttmp+=(int)( money * per);\n\t\t\tmoney-=mine;\n\t\t}\n\t\treturn money+tmp;\n\t}\n\n}\n\n\n\nint main(){\n\tint m;\n\n\tcin>>m;\n\n\trep(loop,m){\n\t\tint money,year,n;\n\t\tcin>>money>>year>>n;\n\t\tint type,mine;\n\t\tdouble per;\n\t\tint maxi=-1;\n\t\trep(i,n){\n\t\t\tcin>>type>>per>>mine;\n\t\t\tmaxi=max(solve(money,year,type,per,mine),maxi);\n\t\t}\n\t\tcout<<maxi<<endl;\n\t}\n}\n\n//テ・ツ債佚・ツ按ゥテ」ツδサティツ、ツ?・ツ按ゥテ」ツ?ョテ・ツ按・ テ・ツケツエテ・ツ按ゥテァツ篠?テヲツッツ偲・ツケツエテ」ツ?ョテヲツ可凝ヲツ閉ーテヲツ鳴?", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.3077, "final_rank": 3 }, { "submission_id": "aoj_1135_1415465", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n\nusing namespace std;\n\n\ntypedef struct {\n\tint type;\n\tdouble nenri;\n\tdouble minus;\n} pattern;\n\nint rishi=0;\n\nint sim(int year,int money,int type,double nenri,double minus) {\n\tint rishi=0;\n\n\tfor (int i=0;i<year;i++) {\n\t\tif(type==0)\n\t\t\trishi+=money*nenri;\n\t\telse\n\t\t\tmoney+=money*nenri;\n\n\t\tmoney-=minus;\n\t}\n\n\n\treturn money+rishi;\n}\n\nint main(void) {\n\n\tint m;\n\n\n\tcin >> m;\n\n\tfor(int j=0;j<m;j++) {\n\t\tint shikin;\n\n\t\tint years;\n\t\tint n;\n\t\t\n\t\tcin >> shikin;\n\t\tcin >> years;\n\t\tcin >> n;\n\n\t\tvector<int> money;\n\t\tfor(int i=0;i<n;i++) {\n\t\t\tpattern tmp;\n\n\t\t\tcin >> tmp.type >> tmp.nenri >> tmp.minus;\n\t\t\tmoney.push_back(sim(years ,shikin, tmp.type ,tmp.nenri ,tmp.minus));\n\t\t}\n\n\t\tsort(money.begin(),money.end(),greater<int>() );\n\t\t//cout << money[money.size()-1] << endl;\n\t\tcout << money[0] << endl;\n\n\t}\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1260, "score_of_the_acc": -0.8462, "final_rank": 17 }, { "submission_id": "aoj_1135_1411676", "code_snippet": "#include <cstdio>\n#include <iostream>\n\nusing namespace std;\n\nint nmoney(int s, double ratio, int cost, int pmomey, int year) {\n\tint nmoney;\n\tint total_ratio = 0;\n\n\tif (s == 0) {\n\t\tfor (int i = 0; i < year; i++) {\n\t\t\ttotal_ratio += pmomey*ratio;\n\t\t\tpmomey -= cost;\n\t\t}\n\t\tnmoney = pmomey + total_ratio;\n\t} else if (s == 1) {\n\t\tfor (int i = 0; i < year; i++) {\n\t\t\tpmomey += pmomey*ratio - cost;\n\t\t}\n\t\tnmoney = pmomey;\n\t}\n\n\treturn nmoney;\n}\n\nint main(void) {\n\tint m;\n\tcin >> m;\n\tfor (int i = 0; i < m; i++) {\n\t\tint pmoney;\n\t\tcin >> pmoney;\n\n\t\tint year;\n\t\tcin >> year;\n\n\t\tint n;\n\t\tint money = 0;\n\t\tcin >> n;\n\t\tfor (int j = 0; j < n; j++) {\n\t\t\tint s, cost;\n\t\t\tdouble ratio;\n\t\t\tcin >> s >> ratio >> cost;\n\t\t\tint n;\n\t\t\tn = nmoney(s, ratio, cost, pmoney, year);\n\t\t\tif (n > money) {\n\t\t\t\tmoney = n;\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\", money);\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1216, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1135_1400786", "code_snippet": "#include <iostream>\n#include <stdio.h>\n#include <string>\n#include <math.h>\n#include <algorithm>\n#include <vector>\n\nusing namespace std;\nint main(){\n\tlong long int start, temp = 0, start2 = 0;\n\tint year, n, y, m, i, j;\n\tchar a;\n\tdouble x;\n\tint ans[100], count = 0;\n\n\tcin >> m;\n\tfor(i = 0;i < m;i++){\n\t\tcin >> start >> year >> n;\n\t\tfor(j = 0;j < n;j++){\n\t\t\tcin >> a >> x >> y;\n\t\t\tstart2 = start;\n\t\t\tif(a == '0'){\n\t\t\t\tfor(int k = 0;k < year;k++){\n\t\t\t\t\ttemp += (int)(start2 * x);\n\t\t\t\t\tstart2 -= y;\n\t\t\t\t}\n\t\t\t\tans[count] = start2 + temp;\n\t\t\t\t//cout << ans[count] << \" \" << start2 << \" \" << temp << endl;\n\t\t\t\ttemp = 0;\n\t\t\t\tcount++;\n\t\t\t}\n\t\t\telse if(a == '1'){\n\t\t\t\tfor(int k = 0;k < year;k++){\n\t\t\t\t\ttemp += (int)(start2 * x);\n\t\t\t\t\tstart2 = start2 + temp - y;\n\t\t\t\t\ttemp = 0;\n\t\t\t\t}\n\t\t\t\tans[count] = start2;\n\t\t\t\t//cout << ans[count] << \" \" << start2 << \" \" << temp << endl;\n\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t\tsort(ans, ans+count);\n\t\tcout << ans[count-1] << endl;\n\t\tfor(int k = 0;k < count;k++){\n\t\t\tans[k] = 0;\n\t\t}\n\t\tcount = 0;\n\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1256, "score_of_the_acc": -0.7692, "final_rank": 16 }, { "submission_id": "aoj_1135_1375645", "code_snippet": "#include<bits/stdc++.h>\n#define loop(i,a,b) for(int i=a;i<b;i++)\n#define rep(i,a) loop(i,0,a)\nusing namespace std;\n\nint main(){\n\tint m;\n\tcin>>m;\n\trep(z,m){\n\t\tlong long money;\n\t\tint time,n;\n\t\tcin>>money>>time>>n;\n\t\tvector<long long> ans;\n\t\tlong long memory=money;\n\t\trep(u,n){\n\t\t\tint tax,fee;\n\t\t\tlong double percent;\n\t\t\tcin>>tax>>percent>>fee;\n\t\t\tlong long nenri=0;\n\t\t\tmoney=memory;\n\t\t\trep(i,time){\n\t\t\t\tif(tax==0){//???????????´???\n\t\t\t\t\tnenri+=(int)money*percent;\n\t\t\t\t\tmoney-=fee;\n\t\t\t\t}else{//???????????´???\n\t\t\t\t\tmoney=(long long)money*(1+percent)-fee;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(tax==0)money+=nenri;\n\t\t\tans.push_back(money);\n\t\t}\n\t\tsort(ans.begin(),ans.end());\n\t\tcout<<ans[ans.size()-1]<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1264, "score_of_the_acc": -1.9231, "final_rank": 20 }, { "submission_id": "aoj_1135_1345377", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef long long int ll;\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\ntypedef vector<pair<int, int> > vii;\n#define rrep(i, m, n) for(int (i)=(m); (i)<(n); (i)++)\n#define erep(i, m, n) for(int (i)=(m); (i)<=(n); (i)++)\n#define rep(i, n) for(int (i)=0; (i)<(n); (i)++)\n#define rrev(i, m, n) for(int (i)=(n)-1; (i)>=(m); (i)--)\n#define erev(i, m, n) for(int (i)=(n); (i)>=(m); (i)--)\n#define rev(i, n) for(int (i)=(n)-1; (i)>=0; (i)--)\n#define vrep(i, c) for(__typeof((c).begin())i=(c).begin(); i!=(c).end(); i++)\n#define ALL(v) (v).begin(), (v).end()\n#define pb push_back\ntemplate<class T, class S> inline pair<T, S> mp(T x, S y){ return make_pair(x, y); }\ntemplate<class T, class S> inline bool minup(T& m, S x){ return m>(T)x ? (m=(T)x, true) : false; }\ntemplate<class T, class S> inline bool maxup(T& m, S x){ return m<(T)x ? (m=(T)x, true) : false; }\n\nstatic const int INF = 1000000000;\nstatic const ll MOD = 1000000007LL;\nstatic const double EPS = 1E-12;\n\nint m, n, q;\ndouble s, y, r, d;\n\nint main()\n{\n cin >> m;\n\n while(m--){\n cin >> s >> y >> n;\n int res = 0;\n while(n--){\n cin >> q >> r >> d;\n double ss = s;\n if(q == 0){\n int sum = 0;\n rep(i, y){\n sum += ss * r;\n ss -= d;\n }\n maxup(res, (int)(ss + sum));\n }\n else{\n rep(i, y) ss += floor(ss * r - d);\n maxup(res, ss);\n }\n }\n cout << res << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.3077, "final_rank": 3 }, { "submission_id": "aoj_1135_1143694", "code_snippet": "#include <vector>\n#include <list>\n#include <map>\n#include <set>\n#include <deque>\n#include <stack>\n#include <bitset>\n#include <algorithm>\n#include <functional>\n#include <numeric>\n#include <utility>\n#include <sstream>\n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <cmath>\n#include <cstdlib>\n#include <cctype>\n#include <string>\n#include <cstring>\n#include <ctime>\n#include <queue>\n\n \nusing namespace std;\n \n#define INF 1000000000\n#define EPS 1e-9\n#define PI acos(-1)\n \ntypedef long long ll;\n\n#define MAX_M 100\n\nint m;\nvector<ll> ans_list;\n\nint main(){\n\n cin >> m;\n while(m > 0){\n m--;\n int n;\n ll money;\n ll year;\n ll ans = 0;\n cin >> money;\n cin >> year;\n cin >> n;\n while(n > 0){\n n--;\n ll mMoney = money;\n int num;\n double r;\n int mai;\n int t = 0;\n cin >> num >> r >> mai;\n if(num == 0){\n\tfor(int i = 0; i < year; i++){\n\t int B = mMoney*r/10*10;\n\t t += B;\n\t mMoney -= mai;\n\t}\n\tans = max(ans, mMoney+t);\n }\n else{\n\tfor(int i = 0; i < year; i++){\n\t mMoney += -mai + mMoney*r/10*10;\n\t}\n\tans = max(ans, mMoney);\n }\n \n }\n \n ans_list.push_back(ans);\n\n }\n\n for(int i = 0; i < ans_list.size(); i++){\n cout << ans_list[i] << endl;\n }\n\n return 0;\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1264, "score_of_the_acc": -0.9231, "final_rank": 18 }, { "submission_id": "aoj_1135_1122916", "code_snippet": "#include <iostream>\n#include <algorithm>\n\nusing namespace std;\n\nint tanri(int y, int A, int fee, double rate){\n int sum = 0;\n for(int i=0; i < y; i++){\n sum += (int)A*rate;\n A -= fee;\n }\n return A+sum;\n}\n\nint hukuri(int y, int A, int fee, double rate){\n for(int i=0; i < y; i++){\n A += (int)(A*rate)-fee;\n }\n return A;\n}\n\nint main(){\n int n;\n cin >> n;\n for(int p=0; p < n; p++){\n long long money;\n cin >> money;\n int y, m;\n cin >> y >> m;\n\n int res = 0;\n for(int i=0; i < m; i++){\n int s, fee;\n double rate;\n cin >> s >> rate >> fee;\n if(s == 0) res = max(res, tanri(y, money, fee, rate));\n else res = max(res, hukuri(y, money, fee, rate));\n }\n cout << res << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1236, "score_of_the_acc": -0.3846, "final_rank": 14 }, { "submission_id": "aoj_1135_1106018", "code_snippet": "#include<iostream>\n#include<stdio.h>\nusing namespace std;\n\nint m;\nint inis;\nint year,n;\n\nint type;\ndouble ritu;\nint tesu;\n\nint main(){\n\tint t;\n\tint i,j;\n\tint output;\n\tint a,b;\n\t\n\tcin >> m;\n\tfor( t = 0; t < m; t++ ){\n\t\tif( scanf(\"%d\",&inis) != 1 )break;\n\t\tcin >> year >> n;\n\t\t\n\t\toutput = 0;\n\t\tfor( i = 0; i < n; i++ ){\n\t\t\tcin >> type >> ritu >> tesu;\n\t\t\tif( type == 0 ){\n\t\t\t\ta = inis; b = 0;\n\t\t\t\tfor( j = 0; j < year; j++ ){\n\t\t\t\t\tb += (double)a*ritu;\n\t\t\t\t\ta -= tesu;\n\t\t\t\t}\n\t\t\t\t//cout << \"tanri = \" << a + b << endl;\n\t\t\t}\n\t\t\telse{\n\t\t\t\ta = inis; b = 0;\n\t\t\t\tfor( j = 0; j < year; j++ ){\n\t\t\t\t\ta = (double)a*(ritu+1.0);\n\t\t\t\t\ta -= tesu;\n\t\t\t\t}\n\t\t\t\t//cout << \"fukuri = \" << a + b << endl;\n\t\t\t}\n\t\t\toutput = max( a+b, output );\n\t\t}\n\t\tcout << output << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1268, "score_of_the_acc": -1, "final_rank": 19 }, { "submission_id": "aoj_1135_1071199", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <vector>\n\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nusing namespace std;\n\n#define ALL(v) (v).begin(),(v).end()\n#define ARRAY_LENGTH(array) (sizeof(array) / sizeof(array[0]))\n#define REP(i,a,b) for(int i=(int)(a); i<(int)(b); ++i)\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define SORT(x) sort(begin(x),end(x))\n#define SELECT_SORT(x, n) sort(begin(x),begin(x)+n)\n#define SWAP(type, a, b) do {type tmp = a; a = b; b = tmp;} while (0)\n#define rep_split(tok,a_str,re) for(char *tok = strtok((char *)a_str.c_str(),re); tok != NULL; tok = strtok(NULL,re))\n\n#define INF 2000000000000\n#define MAX 10\n\n#define BAR() cout << \"----------------------------\" << endl;\n#define DUMP(v) (cerr << #v << \": \" << v << endl)\n#define PRINT(list) cout << \"{ \"; for(auto nth : list){ cout << nth << \" \"; } cout << \"}\" << endl;\n\n\nint main()\n{\n\tint m,money,y,n;\n\tint a,c;\n\tlong double risi;\n\tcin >> m;\n\twhile(m)\n\t{\n\t\tcin >> money;\n\t\tcin >> y;\n\t\tcin >> n;\n\n\t\tint ans=0;\n\n\t\tint moneytmp = money;\n\t\trep(i,n){\n\t\t\tcin >> a >> risi >> c;\n\t\t\tint tmpRisi=0;\n\t\t\tint anstmp=0;\n\n\t\t\tmoneytmp = money; \n\t\t\tif(!a){\n\t\t\t\trep(i,y)\n\t\t\t\t{\n\t\t\t\t\ttmpRisi += moneytmp*risi;\n\t\t\t\t\tmoneytmp -= c; \n\t\t\t\t}\n\t\t\t\tanstmp = moneytmp + tmpRisi;\n\t\t\t}else{\n\t\t\t\trep(i,y)\n\t\t\t\t{\n\t\t\t\t\tmoneytmp +=moneytmp*risi-c;\n\t\t\t\t}\n\t\t\t\tanstmp=moneytmp;\n\t\t\t}\n\t\t\tans = max(ans, anstmp);\n\t\t}\n\t\tcout << ans << endl;\n\t\tm--;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1236, "score_of_the_acc": -0.3846, "final_rank": 14 }, { "submission_id": "aoj_1135_1046018", "code_snippet": "#include<iostream>\n\nusing namespace std;\n\ntemplate<typename T> inline void chmax(T& t, T f){if(t < f)t = f;}\n\nint compound(int A, int year, double rate, int charge){\n int res = A;\n while(year--){\n int B = res * rate;\n res += B - charge;\n }\n return res;\n}\n\nint simple(int A, int year, double rate, int charge){\n int res1 = A, res2 = 0;\n while(year--){\n int B = res1 * rate;\n res2 += B;\n res1 -= charge;\n }\n return res1 + res2;\n}\n\nint main(){\n int m;\n cin >> m;\n while(m--){\n int init, year, n;\n cin >> init >> year >> n;\n int ans = 0;\n while(n--){\n int k, charge; double rate;\n cin >> k >> rate >> charge;\n chmax(ans, k? compound(init, year, rate, charge): simple(init, year, rate, charge));\n }\n cout << ans << '\\n';\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.3077, "final_rank": 3 } ]
aoj_1140_cpp
Problem F: Cleaning Robot Here, we want to solve path planning for a mobile robot cleaning a rectangular room floor with furniture. Consider the room floor paved with square tiles whose size fits the cleaning robot (1 × 1). There are 'clean tiles' and 'dirty tiles', and the robot can change a 'dirty tile' to a 'clean tile' by visiting the tile. Also there may be some obstacles (furniture) whose size fits a tile in the room. If there is an obstacle on a tile, the robot cannot visit it. The robot moves to an adjacent tile with one move. The tile onto which the robot moves must be one of four tiles (i.e., east, west, north or south) adjacent to the tile where the robot is present. The robot may visit a tile twice or more. Your task is to write a program which computes the minimum number of moves for the robot to change all 'dirty tiles' to 'clean tiles', if ever possible. Input The input consists of multiple maps, each representing the size and arrangement of the room. A map is given in the following format. w h c 11 c 12 c 13 ... c 1 w c 21 c 22 c 23 ... c 2 w ... c h 1 c h 2 c h 3 ... c hw The integers w and h are the lengths of the two sides of the floor of the room in terms of widths of floor tiles. w and h are less than or equal to 20. The character c yx represents what is initially on the tile with coordinates ( x, y ) as follows. ' . ' : a clean tile ' * ' : a dirty tile ' x ' : a piece of furniture (obstacle) ' o ' : the robot (initial position) In the map the number of 'dirty tiles' does not exceed 10. There is only one 'robot'. The end of the input is indicated by a line containing two zeros. Output For each map, your program should output a line containing the minimum number of moves. If the map includes 'dirty tiles' which the robot cannot reach, your program should output -1. Sample Input 7 5 ....... .o...*. ....... .*...*. ....... 15 13 .......x....... ...o...x....*.. .......x....... .......x....... .......x....... ............... xxxxx.....xxxxx ............... .......x....... .......x....... .......x....... ..*....x....*.. .......x....... 10 10 .......... ..o....... .......... .......... .......... .....xxxxx .....x.... .....x.*.. .....x.... .....x.... 0 0 Output for the Sample Input 8 49 -1
[ { "submission_id": "aoj_1140_10851274", "code_snippet": "// clang-format off\n//#pragma GCC optimize(\"Ofast\")\n//#pragma GCC target(\"avx\")\n#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\n#define stoi stoll\n#define Endl endl\n#define itn int\n#define fi first\n#define se second\n#define rep(i, n) for(int i=0, i##_len=(n); i<i##_len; i++)\n#define rep2(i, a, b) for (int i = (int)(a), i##_len=(b); i < i##_len; i++)\n#define rep3(i, a, b) for (int i = (int)(a), i##_len=(b); i >= i##_len; i--)\n#define FOR(i, a) for (auto &i: a)\n#define ALL(obj) begin(obj), end(obj)\n#define _max(x) *max_element(ALL(x))\n#define _min(x) *min_element(ALL(x))\n#define _sum(x) accumulate(ALL(x), 0LL)\n#define LOWER_BOUND(A, key) distance(begin(A), lower_bound(ALL(A), key))\n#define UPPER_BOUND(A, key) distance(begin(A), upper_bound(ALL(A), key))\n\nconst int MOD = 1000000007;\n// const int MOD = 998244353;\nconst int INF = (int)(1e13 + 7);\nconst double EPS = 1e-8;\nconst double PI = 3.14159265358979;\ntemplate <class T> using V = vector<T>;\ntemplate <class T> using VV = vector<vector<T>>;\ntemplate <class T> using VVV = vector<vector<vector<T>>>;\ntemplate <class T, class S> using P = pair<T, S>;\ntemplate<class T> bool chmax(T &a, const T &b) {if (a < b) {a = b;return true;}return false;}\ntemplate<class T> bool chmin(T &a, const T &b) {if (b < a) {a = b;return true;}return false;}\nint _ceil(int a, int b) { return (a >= 0 ? (a + (b - 1)) / b : (a - (b - 1)) / b); }\nint _mod(int &a) {a = a >= 0 ? a % MOD : a - (MOD * _ceil(a, MOD));return a;}\nint _pow(int a, int b) {int res = 1;for (a %= MOD; b; a = a * a % MOD, b >>= 1)if (b & 1) res = res * a % MOD;return res;}\nstruct mint {long long x;mint(long long x = 0) : x((x % MOD + MOD) % MOD) {}mint operator-() const { return mint(-x); }mint &operator+=(const mint a) {if ((x += a.x) >= MOD) x -= MOD;return *this;}mint &operator-=(const mint a) {if ((x += MOD - a.x) >= MOD) x -= MOD;return *this;}mint &operator*=(const mint a) { (x *= a.x) %= MOD;return *this; }mint operator+(const mint a) const { return mint(*this) += a; }mint operator-(const mint a) const { return mint(*this) -= a; } mint operator*(const mint a) const { return mint(*this) *= a; }mint pow(long long t) const {if (!t) return 1;mint a = pow(t >> 1);a *= a;if (t & 1) a *= *this;return a;}mint inv() const { return pow(MOD - 2); }mint &operator/=(const mint a) { return *this *= a.inv(); }mint operator/(const mint a) const { return mint(*this) /= a; }};istream &operator>>(istream &is, mint &a) { return is >> a.x; }ostream &operator<<(ostream &os, const mint &a) { return os << a.x; }\n// clang-format on\n\nint now;\nvoid process(int x_now, int y_now, int prev_cost, deque<P<int, int>> &pos, VV<int> &grid, V<string> &c, V<P<int, int>> &nodes, VV<int> &shortest_path) {\n if (c[x_now][y_now] != 'x' and grid[x_now][y_now] > prev_cost + 1) {\n grid[x_now][y_now] = prev_cost + 1;\n pos.emplace_back(x_now, y_now);\n if (c[x_now][y_now] == '*' or c[x_now][y_now] == 'o') {\n rep(i, nodes.size()) if (nodes[i].fi == x_now and nodes[i].se == y_now) {\n shortest_path[now][i] = prev_cost + 1;\n }\n }\n }\n}\n\nsigned main() {\n cin.tie(nullptr);\n cout.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(15);\n while (1) {\n int w, h;\n cin >> w >> h;\n if (w == 0) break;\n V<string> c(h + 2);\n c[0] = string(w + 2, 'x');\n c[h + 1] = string(w + 2, 'x');\n rep(i, h) {\n cin >> c[i + 1];\n c[i + 1] = 'x' + c[i + 1] + 'x';\n }\n V<P<int, int>> nodes;\n rep(i, h) rep(j, w) if (c[i + 1][j + 1] == 'o') nodes.emplace_back(i + 1, j + 1);\n rep(i, h) rep(j, w) if (c[i + 1][j + 1] == '*') nodes.emplace_back(i + 1, j + 1);\n int n = nodes.size();\n VV<int> shortest_path(n, V<int>(n, INF));\n rep(i, n) shortest_path[i][i] = 0;\n rep(i, n) {\n now = i;\n P<int, int> start = nodes[i];\n VV<int> grid(h + 2, V<int>(w + 2, INF));\n grid[start.fi][start.se] = 0;\n deque<P<int, int>> pos = {start};\n while (pos.size()) {\n process(pos[0].fi + 1, pos[0].se, grid[pos[0].fi][pos[0].se], pos, grid, c, nodes, shortest_path);\n process(pos[0].fi - 1, pos[0].se, grid[pos[0].fi][pos[0].se], pos, grid, c, nodes, shortest_path);\n process(pos[0].fi, pos[0].se + 1, grid[pos[0].fi][pos[0].se], pos, grid, c, nodes, shortest_path);\n process(pos[0].fi, pos[0].se - 1, grid[pos[0].fi][pos[0].se], pos, grid, c, nodes, shortest_path);\n pos.pop_front();\n }\n }\n bool yes = true;\n rep(i, n) rep(j, n) if (shortest_path[i][j] == INF) {\n yes = false;\n }\n if (!yes) {\n cout << -1 << endl;\n continue;\n }\n VV<int> dp((1 << n), V<int>(n, INF));\n dp[1][0] = 0;\n rep(i, (1 << n) - 1) {\n rep(j, n) {\n rep(k, n) {\n if (((i >> k) & 1) == 0) {\n if (__builtin_popcount(i | (1 << k)) == 1) continue;\n dp[i | (1 << k)][k] = min(dp[i | (1 << k)][k], dp[i][j] + shortest_path[j][k]);\n }\n }\n }\n }\n int ans = INF;\n rep(i, n) {\n chmin(ans, dp[(1 << n) - 1][i]);\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3416, "score_of_the_acc": -0.0607, "final_rank": 2 }, { "submission_id": "aoj_1140_10665815", "code_snippet": "#include<bits/stdc++.h>\n//#include <atcoder/all>\nusing namespace std;\n//using namespace atcoder;\n\n#define all(v) v.begin(),v.end()\nusing ll = long long;\nusing ull = unsigned long long;\nusing lll = __int128;\nusing vll=vector<ll>;\nusing vvll = vector<vector<ll>>;\nusing P = pair<ll,ll>;\nusing vp=vector<pair<ll, ll>>;\n//using mint=modint1000000007;\n//using mint=modint998244353;\n\nconst ll INF=1ll<<60;\nll mod10=1e9+7;\nll mod99=998244353;\nconst double PI = acos(-1);\n\n#define rep(i,n) for (ll i=0;i<n;++i)\n#define per(i,n) for(ll i=n-1;i>=0;--i)\n#define rep2(i,a,n) for (ll i=a;i<n;++i)\n#define per2(i,a,n) for (ll i=a;i>=n;--i)\n\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n\nvector<ll> dx={1,0,-1,0,-1,-1,1,1,0},dy={0,1,0,-1,-1,1,-1,1,0};\n\nbool solve(){\n ll W,H;cin>>W>>H;\n if(W+H==0) return 0;\n vector<string> S(H);rep(i,H) cin>>S[i];\n vector<vector<vvll>> dist(H,vector(W,vector(H,vector(W,-1ll))));\n rep(i,H) rep(j,W){\n if(S[i][j]!='o'&&S[i][j]!='*') continue;\n dist[i][j][i][j]=0;\n queue<P> q;\n q.push({i,j});\n while(q.size()){\n auto [nowi,nowj]=q.front();q.pop();\n rep(k,4){\n ull toi=nowi+dx[k],toj=nowj+dy[k];\n if(!(toi<H&&toj<W)) continue;\n if(dist[i][j][toi][toj]!=-1||S[toi][toj]=='x') continue;\n dist[i][j][toi][toj]=dist[i][j][nowi][nowj]+1;\n q.push({toi,toj});\n }\n }\n rep(i2,H) rep(j2,W) if(dist[i][j][i2][j2]==-1) dist[i][j][i2][j2]=INF;\n }\n\n vector<P> A;rep(i,H) rep(j,W) if(S[i][j]=='o') A.push_back({i,j});\n rep(i,H) rep(j,W) if(S[i][j]=='*') A.push_back({i,j});\n\n ll N=A.size();\n vvll dp(1<<N,vll(N,INF));\n dp[0][0]=0;\n rep(bit,1<<N) rep(j,N){\n if(bit==0){\n chmin(dp[1][0],dp[bit][j]);\n continue;\n }\n rep(k,N){\n if((bit>>j&1)==0||(bit>>k&1)) continue;\n chmin(dp[bit|(1<<k)][k],dp[bit][j]+dist[A[j].first][A[j].second][A[k].first][A[k].second]);\n }\n }\n\n\n ll ans=INF;\n rep(i,N) chmin(ans,dp[(1<<N)-1][i]);\n cout << (ans==INF?-1:ans) << endl;\n return 1;\n}\n\n\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n while(solve());\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4824, "score_of_the_acc": -0.479, "final_rank": 16 }, { "submission_id": "aoj_1140_10635036", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nbool solve() {\n int H, W;\n cin >> W >> H;\n if (H == 0 && W == 0) return false;\n vector<string> S(H);\n int sr = -1, sc = -1;\n vector<vector<int>> dust(H, vector<int>(W, -1));\n int N = 0;\n for (int i = 0; i < H; i++) {\n cin >> S[i];\n for (int j = 0; j < W; j++) {\n if (S[i][j] == 'o') sr = i, sc = j;\n if (S[i][j] == '*') dust[i][j] = N++;\n }\n }\n vector<vector<vector<int>>> dist(1 << N, vector<vector<int>>(H, vector<int>(W, 1 << 30)));\n dist[0][sr][sc] = 0;\n queue<tuple<int, int, int>> q;\n q.emplace(0, sr, sc);\n int D[5] = {0, 1, 0, -1, 0};\n while (q.size()) {\n auto [b, r, c] = q.front();\n q.pop();\n for (int d = 0; d < 4; d++) {\n int nr = r + D[d], nc = c + D[d + 1];\n if (0 <= nr && nr < H && 0 <= nc && nc < W && S[nr][nc] != 'x') {\n int nb = b;\n if (dust[nr][nc] != -1) nb |= 1 << dust[nr][nc];\n if (dist[nb][nr][nc] > dist[b][r][c] + 1) {\n dist[nb][nr][nc] = dist[b][r][c] + 1;\n q.emplace(nb, nr, nc);\n }\n }\n }\n }\n int ans = 1 << 30;\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n ans = min(ans, dist[(1 << N) - 1][i][j]);\n }\n }\n if (ans == 1 << 30) ans = -1;\n cout << ans << '\\n';\n return true;\n}\n\nint main() {\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 4736, "score_of_the_acc": -0.4663, "final_rank": 15 }, { "submission_id": "aoj_1140_10607918", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconstexpr int INF = 2e9;\nint dx[] = {-1, 0, 1, 0};\nint dy[] = {0, 1, 0, -1};\n\nvoid solve(int w, int h, vector<vector<char>> grid) {\n int sx = -1, sy = -1;\n vector<pair<int, int>> tiles;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (grid[i][j] == 'o') {\n sx = i;\n sy = j;\n }\n if (grid[i][j] == '*') {\n tiles.emplace_back(i, j);\n }\n }\n }\n ranges::sort(tiles);\n\n vector dist(h, vector(w, vector(h, vector(w, INF))));\n auto bfs = [&](const int start_x, const int start_y) {\n queue<pair<int, int>> q;\n dist[start_x][start_y][start_x][start_y] = 0;\n q.emplace(start_x, start_y);\n while (!q.empty()) {\n auto [x, y] = q.front();\n q.pop();\n for (int dir = 0; dir < 4; dir++) {\n int nx = x + dx[dir];\n int ny = y + dy[dir];\n if (nx < 0 || nx >= h || ny < 0 || ny >= w) {\n continue;\n }\n if (grid[nx][ny] == 'x') {\n continue;\n }\n if (dist[start_x][start_y][nx][ny] == INF) {\n dist[start_x][start_y][nx][ny] = dist[start_x][start_y][x][y] + 1;\n q.emplace(nx, ny);\n }\n }\n }\n };\n\n bfs(sx, sy);\n for (auto [start_x, start_y] : tiles) {\n bfs(start_x, start_y);\n }\n\n const int n = static_cast<int>(tiles.size());\n int ans = INF;\n do {\n int sum = 0;\n int cur_x = sx;\n int cur_y = sy;\n bool ok = true;\n for (int i = 0; i < n; i++) {\n auto [next_x, next_y] = tiles[i];\n if (dist[cur_x][cur_y][next_x][next_y] == INF) {\n ok = false;\n break;\n }\n sum += dist[cur_x][cur_y][next_x][next_y];\n cur_x = next_x;\n cur_y = next_y;\n }\n if (ok) {\n ans = min(ans, sum);\n }\n } while (next_permutation(tiles.begin(), tiles.end()));\n\n cout << (ans == INF ? -1 : ans) << endl;\n}\n\nint main() {\n while (true) {\n int w, h;\n cin >> w >> h;\n if (w == 0 && h == 0) {\n break;\n }\n\n vector<vector<char>> c(h, vector<char>(w));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n cin >> c[i][j];\n }\n }\n solve(w, h, c);\n }\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 4608, "score_of_the_acc": -0.4832, "final_rank": 17 }, { "submission_id": "aoj_1140_10607867", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconstexpr int INF = 2e9;\nint dx[] = {-1, 0, 1, 0};\nint dy[] = {0, 1, 0, -1};\n\nvoid solve(int w, int h, vector<vector<char>> grid) {\n int sx = -1, sy = -1;\n vector<pair<int, int>> tiles;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (grid[i][j] == 'o') {\n sx = i;\n sy = j;\n }\n if (grid[i][j] == '*') {\n tiles.emplace_back(i, j);\n }\n }\n }\n tiles.insert(tiles.begin(), {sx, sy});\n\n vector dist(h, vector(w, vector(h, vector(w, INF))));\n auto bfs = [&](const int start_x, const int start_y) {\n queue<pair<int, int>> q;\n dist[start_x][start_y][start_x][start_y] = 0;\n q.emplace(start_x, start_y);\n while (!q.empty()) {\n auto [x, y] = q.front();\n q.pop();\n for (int dir = 0; dir < 4; dir++) {\n int nx = x + dx[dir];\n int ny = y + dy[dir];\n if (nx < 0 || nx >= h || ny < 0 || ny >= w) {\n continue;\n }\n if (grid[nx][ny] == 'x') {\n continue;\n }\n if (dist[start_x][start_y][nx][ny] == INF) {\n dist[start_x][start_y][nx][ny] = dist[start_x][start_y][x][y] + 1;\n q.emplace(nx, ny);\n }\n }\n }\n };\n\n for (auto [start_x, start_y] : tiles) {\n bfs(start_x, start_y);\n }\n\n const int n = static_cast<int>(tiles.size());\n vector dp(1 << n, vector(h, vector(w, INF)));\n dp[1 << 0][sx][sy] = 0;\n for (int bit = 0; bit < (1 << n); bit++) {\n for (int i = 0; i < n; i++) {\n auto [x, y] = tiles[i];\n if (!(bit & (1 << i))) {\n continue;\n }\n if (dp[bit][x][y] == INF) {\n continue;\n }\n\n for (int j = 0; j < n; j++) {\n auto [nx, ny] = tiles[j];\n if (dist[x][y][nx][ny] == INF) {\n continue;\n }\n if (!(bit & (1 << j))) {\n int next_bit = bit | (1 << j);\n dp[next_bit][nx][ny] = min(dp[next_bit][nx][ny], dp[bit][x][y] + dist[x][y][nx][ny]);\n }\n }\n }\n }\n\n int ans = INF;\n for (auto [i, j] : tiles) {\n ans = min(ans, dp[(1<<n)-1][i][j]);\n }\n cout << (ans == INF ? -1 : ans) << endl;\n}\n\nint main() {\n while (true) {\n int w, h;\n cin >> w >> h;\n if (w == 0 && h == 0) {\n break;\n }\n\n vector<vector<char>> c(h, vector<char>(w));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n cin >> c[i][j];\n }\n }\n solve(w, h, c);\n }\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 6736, "score_of_the_acc": -1.0288, "final_rank": 19 }, { "submission_id": "aoj_1140_10474637", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing ull=unsigned long long;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define loop(n) for (int tjh = 0; tjh < (int)(n); tjh++)\nconstexpr int maxh=20;constexpr int maxg=10;\nconstexpr int ma=10000;\nconstexpr array<array<int,2>,4>moves={-1,0,0,-1,0,1,1,0};\nsigned main() {\n cin.tie(0)->sync_with_stdio(0);//NOLINT\n cout<<fixed<<setprecision(16);\n int w,h;array<string,maxh>c;\n vector<array<int,2>>g;\n array<array<int,maxh>,maxh>d;\n array<array<int,maxg+1>,maxg+1>dists;\n queue<array<int,2>>q;\n array<array<int,maxg>,(1<<maxg)>dp;\n int res;\n g.reserve(maxg+1);\n for (;cin>>w>>h,w;) {\n g.resize(0);\n rep(i,h) cin>>c[i];\n rep(i,h)rep(j,w)if (c[i][j]=='o')g.push_back({i,j});\n rep(i,h)rep(j,w)if (c[i][j]=='*')g.push_back({i,j});\n if ((int)g.size()==1){cout<<0<<'\\n';continue;}\n rep(i,g.size()) {\n rep(j,h)rep(k,w)d[j][k]=ma;\n d[g[i][0]][g[i][1]]=0;\n q.push(g[i]);\n for (;!q.empty();) {\n array<int,2> a=q.front();\n q.pop();\n for (auto j:moves) {\n array<int,2>b={a[0]+j[0],a[1]+j[1]};\n if (b[0]<0||b[0]>=h||b[1]<0||b[1]>=w)continue;\n if (c[b[0]][b[1]]=='x')continue;\n if (d[b[0]][b[1]]!=ma)continue;\n d[b[0]][b[1]]=d[a[0]][a[1]]+1;\n q.push(b);\n }\n }\n rep(j,g.size())dists[i][j]=d[g[j][0]][g[j][1]];\n }\n\n rep(i,1<<(g.size()-1))rep(j,g.size()-1)dp[i][j]=ma;\n for (int i=1;i<(1<<(g.size()-1));i++) {\n rep(j,g.size()-1) {\n if (!(i&(1<<j))) continue;\n int i0=i^(1<<j);\n if (!i0) {\n dp[i][j]=dists[0][j+1];\n break;\n }\n rep(k,g.size()-1) {\n if (!(i0&(1<<k))) continue;\n int t=dp[i0][k]+dists[k+1][j+1];\n if (t<dp[i][j])dp[i][j]=t;\n }\n }\n }\n res=*min_element(dp[(1<<(g.size()-1))-1].begin(),dp[(1<<(g.size()-1))-1].begin()+g.size()-1);\n cout<<(res==ma?-1:res)<<'\\n';\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3584, "score_of_the_acc": -0.1005, "final_rank": 8 }, { "submission_id": "aoj_1140_10388881", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define all(...) std::begin(__VA_ARGS__), std::end(__VA_ARGS__)\n#define rall(...) std::rbegin(__VA_ARGS__), std::rend(__VA_ARGS__)\n#define OVERLOAD_REP(_1, _2, _3, _4, name, ...) name\n#define REP1(n) for(ll i=0;i<n;i++)\n#define REP2(i, n) for (ll i=0;i<n;i++)\n#define REP3(i, a, n) for (ll i=a;i<n;i++)\n#define REP4(i, a, b, n) for(ll i=a;i<n;i+=b)\n#define rep(...) OVERLOAD_REP(__VA_ARGS__, REP4, REP3, REP2, REP1)(__VA_ARGS__)\n#define OVERLOAD_RREP(_1, _2, _3, _4, name, ...) name\n#define RREP1(n) for(ll i=n;i>=0;i--)\n#define RREP2(i, n) for(ll i=n;i>=0;i--)\n#define RREP3(i, a, n) for(ll i=n;i>=a;i--)\n#define RREP4(i, a, b, n) for(ll i=n;i>=a;i-=b)\n#define rrep(...) OVERLOAD_RREP(__VA_ARGS__, RREP4, RREP3, RREP2, RREP1)(__VA_ARGS__)\n#define foa(a,v) (auto& a : (v))\n#define uniq(a) sort(all(a));a.erase(unique(all(a)),end(a))\n#define len(n) (long long)(n).size()\n#define pb push_back\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vs = vector<string>;\nusing vvs = vector<vs>;\nusing vvvs = vector<vvs>;\nusing vld = vector<ld>;\nusing vvld = vector<vld>;\nusing vvvld = vector<vvld>;\nusing vc = vector<char>;\nusing vvc = vector<vc>;\nusing vvvc = vector<vvc>;\nusing pll = pair<ll,ll>;\nusing vpll = vector<pll>;\ntemplate<class... T>\nconstexpr auto min(T... a){\n return min(initializer_list<common_type_t<T...>>{a...});\n}\ntemplate<class... T>\nconstexpr auto max(T... a){\n return max(initializer_list<common_type_t<T...>>{a...});\n}\ntemplate<class... T>\nvoid input(T&... a){\n (cin >> ... >> a);\n}\nll modpow(ll a,ll b,ll c){\n ll ans = 1;\n while (b){\n if (b & 1){\n ans *= a;\n ans %= c;\n }\n a *= a;\n a %= c;\n b /= 2;\n }\n return ans;\n}\n#define INT(...) int __VA_ARGS__; input(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define ULL(...) ull __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define CHA(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define VLL(name,length) vll name(length);rep(i,length){cin >> name[i];}\n#define VVLL(name,h,w) vvll name(h,vll(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVLL(name,a,b,c) vvvll name(a,vvll(b,vll(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VI(name,length) vi name(length);rep(i,length){cin >> name[i];}\n#define VVI(name,h,w) vvi name(h,vi(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVI(name,a,b,c) vvvi name(a,vvll(b,vi(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VLD(name,length) vld name(length);rep(i,length){cin >> name[i];}\n#define VVLD(name,h,w) vvld name(h,vld(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVLD(name,a,b,c) vvvld name(a,vvld(b,vld(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VC(name,length) vc name(length);rep(i,length){cin >> name[i];}\n#define VVC(name,h,w) vvc name(h,vc(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVC(name,a,b,c) vvvc name(a,vvc(b,vc(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VS(name,length) vs name(length);rep(i,length){cin >> name[i];}\n#define VVS(name,h,w) vvs name(h,vs(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVS(name,a,b,c) vvvs name(a,vvs(b,vs(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define PLL(name) pll name;cin>>name.first>>name.second;\n#define VPLL(name,length) vpll name(length);rep(i,length){cin>>name[i].first>>name[i].second;}\n\nvoid print(){cout << \"\\n\";}\ntemplate<class T, class... Ts>\nvoid print(const T& a, const Ts&... b){cout << a;(cout << ... << (cout << ' ', b));cout << '\\n';}\nvoid print(vll x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid print(vvll x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\n\nvvll bfs(ll h, ll w, vs a, ll sx, ll sy){\n vvll dist(h,vll(w,1LL<<30));\n queue<pll> d;\n dist[sx][sy] = 0;\n d.push({sx,sy});\n vpll dxy = {{-1,0},{1,0},{0,-1},{0,1}};\n while(!d.empty()){\n auto [x,y] = d.front();\n d.pop();\n for(auto [dx,dy]:dxy){\n ll tx = x+dx;\n ll ty = y+dy;\n if(0 <= tx && tx < h && 0 <= ty && ty < w){\n if(dist[tx][ty] > dist[x][y] + 1 && a[tx][ty] != 'x'){\n dist[tx][ty] = dist[x][y] + 1;\n d.push({tx,ty});\n }\n }\n }\n }\n return dist;\n}\n\nvoid solve(ll h, ll w, vs a){\n ll sx,sy;\n vpll b;\n vll idx;\n vvvll dist;\n rep(i,h){\n rep(j,w){\n if(a[i][j] == 'o'){\n sx = i;\n sy = j;\n }\n if(a[i][j] == '*'){\n idx.push_back(len(b));\n b.push_back({i,j});\n dist.push_back(bfs(h,w,a,i,j));\n }\n }\n }\n ll ans = 1LL<<60;\n //print(dist[0]);\n do{\n ll temp = 0;\n ll x = sx;\n ll y = sy;\n //print(idx);\n rep(i,len(idx)){\n ll tx = b[idx[i]].first;\n ll ty = b[idx[i]].second;\n temp += dist[idx[i]][x][y];\n //print(tx,ty,x,y,dist[idx[i]][x][y]);\n x = tx;\n y = ty;\n }\n ans = min(ans,temp);\n }while(next_permutation(all(idx)));\n print(ans>=(1<<30)?-1:ans);\n}\n\nint main(){\n while(1){\n LL(w,h);\n if(w == 0 && h == 0){break;}\n VS(a,h);\n solve(h,w,a);\n }\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3584, "score_of_the_acc": -0.1622, "final_rank": 14 }, { "submission_id": "aoj_1140_10029188", "code_snippet": "#include <iostream>\n#include <vector>\n#include <map>\n#include <queue>\n#include <algorithm>\n\nusing namespace std;\n\nconst vector<int> dx = {1, -1, 0, 0}, dy = {0, 0, 1, -1};\n\nvoid solve(int w, int h) {\n vector<string> c(h);\n for (auto &i: c) cin >> i;\n map<pair<int, int>, int> mp;\n int cnt = 0;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (c[i][j] == 'o') {\n mp[make_pair(i, j)] = 0;\n }\n if (c[i][j] == '*') {\n mp[make_pair(i, j)] = ++cnt;\n }\n }\n }\n constexpr int inf = 1 << 29;\n vector dist(cnt + 1, vector(h, (vector<int>(w, inf))));\n queue<tuple<int, int, int>> q;\n for (const auto [t, num]: mp) {\n dist[num][t.first][t.second] = 0;\n q.emplace(num, t.first, t.second);\n }\n while(!q.empty()) {\n auto [s, x, y] = q.front();\n q.pop();\n for (int k = 0; k < 4; k++) {\n int nx = x + dx[k], ny = y + dy[k];\n if (0 <= nx && nx < h && 0 <= ny && ny < w && c[nx][ny] != 'x' && dist[s][nx][ny] == inf) {\n dist[s][nx][ny] = dist[s][x][y] + 1;\n q.emplace(s, nx, ny);\n }\n }\n }\n vector mat(cnt + 1,vector<int>(cnt + 1));\n for (const auto [t, num]: mp) {\n for (const auto [r, num2]: mp) {\n mat[num][num2] = dist[num][r.first][r.second];\n }\n }\n int ans = inf;\n vector<int> order(cnt);\n for (int i = 0; i < cnt; i++) order[i] = i + 1;\n do {\n int k = 0;\n bool valid = true;\n for (int i = 0; i < cnt; i++) {\n if (i == 0) {\n if (mat[0][order[i]] == inf) valid = false;\n else k += mat[0][order[i]];\n }\n else {\n if (mat[order[i - 1]][order[i]] == inf) valid = false;\n else k += mat[order[i - 1]][order[i]];\n }\n }\n if(valid) ans = min(ans, k);\n }while(next_permutation(order.begin(), order.end()));\n cout << (ans == inf? -1: ans) << endl;\n}\n\nint main() {\n int w, h;\n cin >> w >> h;\n do {\n solve(w, h);\n cin >> w >> h;\n }while(w != 0);\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3232, "score_of_the_acc": -0.0947, "final_rank": 6 }, { "submission_id": "aoj_1140_9886427", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nvector<int> dx = {0,1,0,-1};\nvector<int> dy = {1,0,-1,0};\nconst int mod = 1000000007;\nconst int inf = 1<<24;\n\nint main(){\n //ios::sync_with_stdio(false);\n //cin.tie(0);\n while (1){\n int W,H;\n cin >> W >> H;\n if (W == 0 && H == 0){\n return 0;\n }\n vector<string> data = vector<string>(H);\n for (int i = 0; i < H;i++){\n cin >> data[i];\n }\n int cnt = 0;\n int sh,sw;\n map<pair<int,int>,int> mp;\n for (int i = 0; i < H;i++){\n for (int j = 0; j < W;j++){\n if (data[i][j] == 'o'){\n sh = i;\n sw = j;\n }\n if (data[i][j] == '*'){\n mp[make_pair(i,j)] = cnt;\n cnt++;\n }\n }\n }\n\n vector<vector<int>> D = vector<vector<int>>(cnt,vector<int>(cnt,inf));\n vector<int> E = vector<int>(cnt,inf);\n for (auto [k, v] : mp){\n auto [h, w] = k;\n int idx1 = v;\n vector<vector<int>> dist = vector<vector<int>>(H,vector<int>(W,-1));\n queue<pair<int,int>> que;\n dist[h][w] = 0;\n que.push(make_pair(h,w));\n\n while (!que.empty()){\n auto[h, w] = que.front();\n que.pop();\n for (int i = 0; i < 4;i++){\n int nh,nw;\n nh = h+dx[i];\n nw = w+dy[i];\n if (nh < 0 or nw < 0 or nh >= H or nw >= W) continue;\n if (data[nh][nw] == 'x') continue;\n if (dist[nh][nw] != -1) continue;\n dist[nh][nw] = dist[h][w]+1;\n if (data[nh][nw] == '*'){\n int idx2 = mp[make_pair(nh,nw)];\n D[idx1][idx2] = dist[nh][nw];\n D[idx2][idx1] = dist[nh][nw];\n }\n if (nh == sh && nw == sw){\n E[idx1] = dist[nh][nw];\n }\n que.push(make_pair(nh,nw));\n }\n }\n\n //debug\n /*\n cout << h << ' ' << w << endl;\n for (int i = 0; i < H;i++){\n for (int j = 0; j < W;j++){\n cout << dist[i][j] << ' ';\n }\n cout << endl;\n }\n */\n\n\n }\n\n vector<vector<int>> dp = vector<vector<int>>(1<<cnt,vector<int>(cnt,inf));\n for (int i = 0; i < cnt;i++){\n dp[1<<i][i] = E[i];\n }\n\n for (int b = 1; b < 1<<cnt;b++){\n if (__builtin_popcount(b) == 1){\n continue;\n }\n for (int v = 0; v < cnt;v++){\n if (b>>v&1){\n int nb = b^(1<<v);\n for (int u = 0; u < cnt;u++){\n if (nb>>u&1){\n dp[b][v] = min(dp[b][v],dp[nb][u]+D[u][v]);\n }\n }\n }\n }\n }\n\n int ans = inf;\n for (int i = 0; i < cnt;i++){\n ans = min(ans,dp[(1<<cnt)-1][i]);\n }\n cout << (ans == inf ? -1 : ans) << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3412, "score_of_the_acc": -0.0514, "final_rank": 1 }, { "submission_id": "aoj_1140_9670173", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vi;\ntypedef vector<vi> vvi;\ntypedef long double ld;\ntypedef pair<ll,ll> pi;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\n#define F first\n#define S second\ntemplate<typename T>bool chmin(T&a,T b){if(a>b){a=b;return 1;}return 0;}\ntemplate<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;\nint main(){\n while(1){\n ll W,H;cin>>W>>H;\n if(!W)return 0;\n vector<string>S(H);\n REP(i,H)cin>>S[i];\n vector<pi>A;\n REP(i,H)REP(j,W)if(S[i][j]=='o')A.emplace_back(pi(i,j));\n REP(i,H)REP(j,W)if(S[i][j]=='*')A.emplace_back(pi(i,j));\n if(A.size()==1){cout<<0<<endl;continue;}\n ll M=A.size();\n vvi D(M,vi(M));\n REP(i,M){\n vvi d(H,vi(W,1e18));\n d[A[i].F][A[i].S]=0;\n priority_queue<pi>Q;\n Q.emplace(A[i]);\n while(!Q.empty()){\n auto[x,y]=Q.top();Q.pop();\n if(x&&S[x-1][y]!='x'&&d[x-1][y]>d[x][y]+1)d[x-1][y]=d[x][y]+1,Q.emplace(pi(x-1,y));\n if(x+1<H&&S[x+1][y]!='x'&&d[x+1][y]>d[x][y]+1)d[x+1][y]=d[x][y]+1,Q.emplace(pi(x+1,y));\n if(y&&S[x][y-1]!='x'&&d[x][y-1]>d[x][y]+1)d[x][y-1]=d[x][y]+1,Q.emplace(pi(x,y-1));\n if(y+1<W&&S[x][y+1]!='x'&&d[x][y+1]>d[x][y]+1)d[x][y+1]=d[x][y]+1,Q.emplace(pi(x,y+1));\n }\n REP(j,M)D[i][j]=d[A[j].F][A[j].S];\n }\n vvi T(M,vi(1<<M,1e18));\n FOR(i,1,M)T[i][1+(1<<i)]=D[0][i];\n FOR(j,1,1<<M)FOR(i,1,M)if((j>>i)%2){\n FOR(k,1,M)if((j>>k)%2==0)chmin(T[k][j+(1<<k)],T[i][j]+D[i][k]);\n }\n ll ans=1e18;\n REP(i,M)chmin(ans,T[i].back());\n if(ans>1e17)cout<<-1<<endl;\n else cout<<ans<<endl; \n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3488, "score_of_the_acc": -0.0813, "final_rank": 4 }, { "submission_id": "aoj_1140_9625401", "code_snippet": "#pragma region Macros\n \n#pragma GCC optimize(\"O3,unroll-loops\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,fma,abm,mmx,avx,avx2,popcnt\")\n \n#include <bits/extc++.h>\n// #include <atcoder/all>\n// using namespace atcoder;\nusing namespace std;\nusing namespace __gnu_pbds;\n \n// #include <boost/multiprecision/cpp_dec_float.hpp>\n// #include <boost/multiprecision/cpp_int.hpp>\n// namespace mp = boost::multiprecision;\n// using Bint = mp::cpp_int;\n// using Bdouble = mp::number<mp::cpp_dec_float<256>>;\n// Bdouble Beps = 0.00000000000000000000000000000001; // 1e-32\n// const bool equals(Bdouble a, Bdouble b) { return mp::fabs(a - b) < Beps; }\n\n#define pb emplace_back\n#define int ll\n#define endl '\\n'\n \n#define sqrt __builtin_sqrtl\n#define cbrt __builtin_cbrtl\n#define hypot __builtin_hypotl\n \n// #define next asdnext\n// #define prev asdprev\n \nusing ll = long long;\nusing ld = long double;\nconst ld PI = acosl(-1);\nconst int INF = 1 << 30;\nconst ll INFL = 1LL << 61;\n// const int MOD = 998244353;\nconst int MOD = 1000000007;\n\nconst ld EPS = 1e-10;\nconst bool equals(ld a, ld b) { return fabs((a) - (b)) < EPS; }\n \nconst vector<int> dx = {0, 1, 0, -1, 1, 1, -1, -1}; // → ↓ ← ↑ ↘ ↙ ↖ ↗\nconst vector<int> dy = {1, 0, -1, 0, 1, -1, -1, 1};\n \n#define EC int\nstruct Edge {\n int from, to;\n EC cost;\n Edge() : from(-1), to(-1), cost(-1) {}\n Edge(int to, EC cost) : to(to), cost(cost) {}\n Edge(int from, int to, EC cost) : from(from), to(to), cost(cost) {}\n bool operator ==(const Edge& e) {\n return this->from == e.from && this->to == e.to && this->cost == e.cost;\n }\n bool operator !=(const Edge& e) {\n return this->from != e.from or this->to != e.to or this->cost != e.cost;\n }\n bool operator <(const Edge& e) { return this->cost < e.cost; }\n bool operator >(const Edge& e) { return this->cost > e.cost; }\n};\n \nchrono::system_clock::time_point start;\n__attribute__((constructor))\nvoid constructor() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(10);\n start = chrono::system_clock::now();\n}\n \nrandom_device seed_gen;\nmt19937_64 rng(seed_gen());\nuniform_int_distribution<int> dist_x(0, 1e9);\nstruct RNG {\n unsigned Int() {\n return dist_x(rng);\n }\n unsigned Int(unsigned l, unsigned r) {\n return dist_x(rng) % (r - l + 1) + l;\n }\n ld Double() {\n return ld(dist_x(rng)) / 1e9;\n }\n} rnd;\n\nnamespace bit_function {\n using i64 = ll;\n // using i64 = uint64_t;\n // bit演算, x==0の場合は例外処理した方がよさそう. 区間は [l, r)\n i64 lrmask(int l, int r) { return (1LL << r) - (1LL << l); }\n i64 sub_bit(i64 x, int l, int r) { i64 b = x & ((1LL << r) - (1LL << l)); return b >> l; } // r溢れ可\n i64 bit_width(i64 x) { return 64 - __builtin_clzll(x) + (x == 0); }\n \n i64 popcount(i64 x) { return __builtin_popcountll(x); }\n i64 popcount(i64 x, int l, int r) { return __builtin_popcountll(sub_bit(x, l, r)); }\n i64 unpopcount(i64 x) { return bit_width(x) - __builtin_popcountll(x); } // 最上位bitより下のみ\n i64 unpopcount(i64 x, int l, int r) { return r - l - __builtin_popcountll(sub_bit(x, l, r)); } // 最上位bitより上も含まれうる\n bool is_pow2(i64 x) { return __builtin_popcountll(x) == 1; } // xが負のときは常にfalse\n bool is_pow4(i64 x) { return __builtin_popcountll(x) == 1 && __builtin_ctz(x) % 2 == 0; }\n //bool is_pow4(ll x) { return __builtin_popcountll(x) == 1 && (x&0x55555555); }\n \n int top_bit(i64 x) { return 63 - __builtin_clzll(x);} // 2^kの位 (x > 0)\n int bot_bit(i64 x) { return __builtin_ctzll(x);} // 2^kの位 (x > 0)\n int next_bit(i64 x, int k) { // upper_bound\n x >>= (k + 1);\n int pos = k + 1;\n while (x > 0) {\n if (x & 1) return pos;\n x >>= 1;\n pos++;\n }\n return -1;\n }\n int prev_bit(i64 x, int k) {\n // k = min(k, bit_width(x)); ?\n int pos = 0;\n while (x > 0 && pos < k) {\n if (x & 1) {\n if (pos < k) return pos;\n }\n x >>= 1;\n pos++;\n }\n return -1;\n }\n int kth_bit(i64 x, int k) { // kは1-indexed\n int pos = 0, cnt = 0;\n while (x > 0) {\n if (x & 1) {\n cnt++;\n if (cnt == k) return pos;\n }\n x >>= 1;\n pos++;\n }\n return -1;\n }\n i64 msb(i64 x) { if (x == 0) return 0; return 1LL << (63 - __builtin_clzll(x)); } // mask\n i64 lsb(i64 x) { return (x & -x); } // mask\n \n int countl_zero(i64 x) { return __builtin_clzll(x); }\n int countl_one(i64 x) { // countl_oneと定義が異なるので注意\n i64 ret = 0, k = 63 - __builtin_clzll(x);\n while (k != -1 && (x & (1LL << k))) { k--; ret++; }\n return ret;\n }\n int countr_zero(i64 x) { return __builtin_ctzll(x); } // x=0のとき64\n int countr_one(i64 x) { int ret = 0; while (x & 1) { x >>= 1; ret++; } return ret; }\n // int countr_one(ll x) { return __builtin_popcount(x ^ (x & -~x));\n\n i64 l_one(i64 x) { // 最上位で連なってる1のmask\n if (x == 0) return 0;\n i64 ret = 0, k = 63 - __builtin_clzll(x);\n while (k != -1 && (x & (1LL << k))) { ret += 1LL << k; k--; }\n return ret;\n }\n \n int floor_log2(i64 x) { return 63 - __builtin_clzll(x); } // top_bit\n int ceil_log2(i64 x) { return 64 - __builtin_clzll(x - 1); }\n i64 bit_floor(i64 x) { if (x == 0) return 0; return 1LL << (63 - __builtin_clzll(x)); } // msb\n i64 bit_ceil(i64 x) { if (x == 0) return 0; return 1LL << (64 - __builtin_clzll(x - 1)); }\n \n i64 rotl(i64 x, int k) { // 有効bit内でrotate. オーバーフロー注意\n i64 w = bit_width(x); k %= w;\n return ((x << k) | (x >> (w - k))) & ((1LL << w) - 1);\n }\n // i64 rotl(i64 x, i64 l, i64 m, i64 r) {}\n i64 rotr(i64 x, int k) {\n i64 w = bit_width(x); k %= w;\n return ((x >> k) | (x << (w - k))) & ((1LL << w) - 1);\n }\n // i64 rotr(i64 x, i64 l, i64 m, i64 r) {}\n i64 bit_reverse(i64 x) { // 有効bit内で左右反転\n i64 r = 0, w = bit_width(x);\n for (i64 i = 0; i < w; i++) r |= ((x >> i) & 1) << (w - i - 1);\n return r;\n }\n // i64 bit_reverse(i64 x, int l, int r) {}\n \n bool is_palindrome(i64 x) { return x == bit_reverse(x); }\n bool is_palindrome(i64 x, int l, int r) { i64 b = sub_bit(x, l, r); return b == bit_reverse(b); }\n i64 concat(i64 a, i64 b) { return (a << bit_width(b)) | b; } // オーバーフロー注意\n i64 erase(i64 x, int l, int r) { return x >> r << l | x & ((1LL << l) - 1); } // [l, r) をカット\n \n i64 hamming(i64 a, i64 b) { return __builtin_popcountll(a ^ b); }\n i64 hamming(i64 a, i64 b, int l, int r) { return __builtin_popcountll(sub_bit(a, l, r) ^ sub_bit(b, l, r)); }\n i64 compcount(i64 x) { return (__builtin_popcountll(x ^ (x >> 1)) + (x & 1)) / 2; }\n i64 compcount2(i64 x) { return compcount(x & (x >> 1)); } // 長さ2以上の連結成分の個数\n i64 adjacount(i64 x) { return __builtin_popcountll(x & (x >> 1)); } // 隣接する1のペアの個数\n \n i64 next_combination(i64 x) {\n i64 t = x | (x - 1); return (t + 1) | (((~t & -~t) - 1) >> (__builtin_ctzll(x) + 1));\n }\n} using namespace bit_function;\n\nnamespace util_function {\n namespace Std = std;\n __int128_t POW(__int128_t x, int n) {\n __int128_t ret = 1;\n assert(n >= 0);\n if (x == 1 or n == 0) ret = 1;\n else if (x == -1 && n % 2 == 0) ret = 1; \n else if (x == -1) ret = -1; \n else if (n % 2 == 0) {\n // assert(x < INFL);\n ret = POW(x * x, n / 2);\n } else {\n // assert(x < INFL);\n ret = x * POW(x, n - 1);\n }\n return ret;\n }\n int per(int x, int y) { // x = qy + r (0 <= r < y) を満たすq\n assert(y != 0);\n if (x >= 0 && y > 0) return x / y;\n if (x >= 0 && y < 0) return x / y - (x % y < 0);\n if (x < 0 && y < 0) return x / y + (x % y < 0);\n return x / y - (x % y < 0); // (x < 0 && y > 0) \n }\n int mod(int x, int y) { // x = qy + r (0 <= r < y) を満たすr\n assert(y != 0);\n return x - y * per(x, y);\n } // https://yukicoder.me/problems/no/2781\n int floor(int x, int y) { // (ld)x / y 以下の最大の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x >= 0 ? x / y : (x + 1) / y - 1;\n }\n int ceil(int x, int y) { // (ld)x / y 以上の最小の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x > 0 ? (x - 1) / y + 1 : x / y;\n }\n int round(int x, int y) { // (ld)(x/y)を小数点第1位について四捨五入\n assert(y != 0);\n return (x * 2 + y) / (y * 2);\n }\n int round(int x, int y, int k) { // (ld)(x/y)を10^kの位に関して四捨五入\n assert(y != 0 && k >= 0);\n if (k == 0) return (x * 2 + y) / (y * 2);\n x /= y * POW(10, k - 1);\n if (x % 10 >= 5) return (x + 10 - x % 10) * POW(10, k - 1);\n return x * POW(10, k - 1);\n }\n int round2(int x, int y) { // 五捨五超入 // 未verify\n assert(y != 0);\n if (y < 0) y = -y, x = -x;\n int z = x / y;\n if ((z * 2 + 1) * y <= y * 2) z++;\n return z;\n }\n ld round(ld x, int k) { // xを10^kの位に関して四捨五入. to_string(x, k)優先\n // x += EPS;\n ld d = pow(10, -k);\n return Std::round(x * d) / d;\n }\n ld floor(ld x, int k) { // xを10^kの位に関してflooring\n // x += EPS;\n ld d = pow(10, -k);\n return Std::floor(x * d) / d; // 未verify\n }\n ld ceil(ld x, int k) { // xを10^kの位に関してceiling\n // x -= EPS;\n ld d = pow(10, -k);\n return Std::ceil(x * d) / d; // 未verify\n }\n // int kth(int x, int y, int k) { // x / yの10^kの位の桁\n // }\n int floor(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return Std::floor(x / y);\n // floor(x) = ceil(x - 1) という話も\n }\n int ceil(ld x, ld y) { // 誤差対策TODO // ceil(p/q) = -floor(-(p/q))らしい\n assert(!equals(y, 0));\n return Std::ceil(x / y);\n // ceil(x) = floor(x + 1)\n }\n int perl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす q\n // 未verify. 誤差対策TODO. EPS外してもいいかも。\n assert(!equals(y, 0));\n if (x >= 0 && y > 0) return Std::floor(x / y)+EPS;\n if (x >= 0 && y < 0) return -Std::floor(x / fabs(y));\n if (x < 0 && y < 0) return Std::floor(x / y) + (x - Std::floor(x/y)*y < -EPS);\n return Std::floor(x / y) - (x - Std::floor(x/y)*y < -EPS); // (x < 0 && y > 0) \n }\n ld modl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす r\n // 未verify. 誤差対策TODO. -0.0が返りうる。\n assert(!equals(y, 0));\n if (x >= 0) return x - fabs(y)*fabs(per(x, y));\n return x - fabs(y)*floor(x, fabs(y));\n }\n int seisuu(ld x) { return (int)x; } // 整数部分. 誤差対策TODO\n int modf(ld x) {\n if (x < 0) return ceill(x);\n else return floorl(x);\n }\n // 正なら+EPS, 負なら-EPSしてから、文字列に直して小数点以下を捨てる?\n int seisuu(int x, int y) {\n assert(y != 0);\n return x / y;\n }\n int seisuu(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return (int)(x / y);\n }\n\n int floor_log(int base, int x) {\n assert(base >= 2);\n int ret = 0, now = 1;\n while (now <= x) {\n now *= base;\n if (now <= x) ret++;\n }\n return ret;\n }\n int ceil_log(int base, int x) {\n assert(base >= 2);\n int ret = 0, now = 1;\n while (now < x) {\n now *= base;\n ret++;\n }\n return ret;\n }\n\n template <class T> pair<T, T> max(const pair<T, T> &a, const pair<T, T> &b) {\n if (a.first > b.first or a.first == b.first && a.second > b.second) return a;\n return b;\n }\n template <class T> pair<T, T> min(const pair<T, T> &a, const pair<T, T> &b) {\n if (a.first < b.first or a.first == b.first && a.second < b.second) return a;\n return b;\n }\n \n template <class T> bool chmax(T &a, const T& b) {\n if (a < b) { a = b; return true; } return false;\n }\n template <class T> bool chmin(T &a, const T& b) {\n if (a > b) { a = b; return true; } return false;\n }\n template <class T> T mid(T a, T b, T c) { // 誤差対策TODO\n return a + b + c - Std::max({a, b, c}) - Std::min({a, b, c});\n }\n template <class T> void Sort(T &a, T &b, bool rev = false) { \n if (rev == false) if (a > b) swap(a, b);\n else if (b > a) swap(b, a);\n }\n template <typename T, typename... Args>\n void Sort(T& a, T& b, T& c, Args&... args) {\n vector<T> vec = {a, b, c, args...};\n sort(vec.begin(), vec.end());\n auto it = vec.begin();\n a = *it++; b = *it++; c = *it++;\n int dummy[] = { (args = *it++, 0)... };\n static_cast<void>(dummy);\n }\n template <typename T, typename... Args>\n void Sortr(T& a, T& b, T& c, Args&... args) {\n vector<T> vec = {a, b, c, args...};\n sort(vec.rbegin(), vec.rend());\n auto it = vec.begin();\n a = *it++; b = *it++; c = *it++;\n int dummy[] = { (args = *it++, 0)... };\n static_cast<void>(dummy);\n }\n\n istream &operator >>(istream &is, __int128_t& x) {\n string S; is >> S;\n __int128_t ret = 0;\n int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9')\n ret = ret * 10 + S[i] - '0';\n x = ret * f;\n return (is);\n }\n ostream &operator <<(ostream &os, __int128_t x) {\n ostream::sentry s(os);\n if (s) {\n __uint128_t tmp = x < 0 ? -x : x;\n char buffer[128]; char *d = end(buffer);\n do {\n --d; *d = \"0123456789\"[tmp % 10]; tmp /= 10;\n } while (tmp != 0);\n if (x < 0) { --d; *d = '-'; }\n int len = end(buffer) - d;\n if (os.rdbuf()->sputn(d, len) != len) os.setstate(ios_base::badbit);\n }\n return os;\n }\n \n __int128_t stoll(string &S) {\n __int128_t ret = 0; int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9') ret = ret * 10 + S[i] - '0';\n return ret * f;\n }\n __int128_t gcd(__int128_t a, __int128_t b) { return b ? gcd(b, a % b) : a; }\n __int128_t lcm(__int128_t a, __int128_t b) {\n return a / gcd(a, b) * b;\n // lcmが__int128_tに収まる必要あり\n }\n \n string to_string(ld x, int k) { // xの小数第k位までをstring化する\n assert(k >= 0);\n stringstream ss;\n ss << setprecision(k + 2) << x;\n string s = ss.str();\n if (s.find('.') == string::npos) s += '.';\n int pos = s.find('.');\n for (int i = 0; k >= (int)s.size() - 1 - pos; i++) s += '0';\n s.pop_back();\n if (s.back() == '.') s.pop_back();\n return s;\n \n // stringstream ss; // 第k+1位を四捨五入して第k位まで返す\n // ss << setprecision(k + 1) << x;\n // string s = ss.str();\n // if (s.find('.') == string::npos) s += '.';\n // int pos = s.find('.');\n // for (int i = 0; k > (int)s.size() - 1 - pos; i++) s += '0';\n // if (s.back() == '.') s.pop_back();\n // return s;\n }\n string to_string(__int128_t x) {\n string ret = \"\";\n if (x < 0) { ret += \"-\"; x *= -1; }\n while (x) { ret += (char)('0' + x % 10); x /= 10; }\n reverse(ret.begin(), ret.end());\n return ret;\n }\n string to_string(char c) { string s = \"\"; s += c; return s; }\n} using namespace util_function;\n\nstruct custom_hash {\n static uint64_t splitmix64(uint64_t x) {\n x += 0x9e3779b97f4a7c15;\n x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n return x ^ (x >> 31);\n }\n \n size_t operator()(uint64_t x) const {\n static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();\n return splitmix64(x + FIXED_RANDOM);\n }\n};\n\ntemplate<class T> size_t HashCombine(const size_t seed,const T &v) {\n return seed^(hash<T>()(v)+0x9e3779b9+(seed<<6)+(seed>>2));\n}\ntemplate<class T,class S> struct hash<pair<T,S>>{\n size_t operator()(const pair<T,S> &keyval) const noexcept {\n return HashCombine(hash<T>()(keyval.first), keyval.second);\n }\n};\ntemplate<class T> struct hash<vector<T>>{\n size_t operator()(const vector<T> &keyval) const noexcept {\n size_t s=0;\n for (auto&& v: keyval) s=HashCombine(s,v);\n return s;\n }\n};\ntemplate<int N> struct HashTupleCore{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{\n size_t s=HashTupleCore<N-1>()(keyval);\n return HashCombine(s,get<N-1>(keyval));\n }\n};\ntemplate <> struct HashTupleCore<0>{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{ return 0; }\n};\ntemplate<class... Args> struct hash<tuple<Args...>>{\n size_t operator()(const tuple<Args...> &keyval) const noexcept {\n return HashTupleCore<tuple_size<tuple<Args...>>::value>()(keyval);\n }\n};\n\ntemplate<typename T>\nclass Compress { // 試験運用, バグったらTをintにする\npublic:\n int sz = 0;\n // gp_hash_table<T, int, custom_hash> Z;\n // gp_hash_table<int, T, custom_hash> UZ;\n unordered_map<T, int> Z; // 元の値 -> 圧縮した値\n unordered_map<int, T> UZ; // 圧縮した値 -> 元の値\n \n Compress() {}\n Compress(const vector<T> &V, T base = 0) {\n this->sz = base;\n set<T> s(V.begin(), V.end());\n \n for (T x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n Compress(const vector<T> &V1, const vector<T> &V2, T base = 0) {\n this->sz = base;\n vector<T> V3 = V2;\n V3.insert(V3.end(), V1.begin(), V1.end());\n set<T> s(V3.begin(), V3.end());\n \n for (T x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n Compress(const vector<T> &V1, const vector<T> &V2, const vector<T> &V3, T base = 0) {\n this->sz = base;\n vector<T> V4 = V1;\n V4.insert(V4.end(), V2.begin(), V2.end());\n V4.insert(V4.end(), V3.begin(), V3.end());\n set<T> s(V4.begin(), V4.end());\n \n for (T x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n Compress(const vector<T> &V1, const vector<T> &V2,\n const vector<T> &V3, const vector<T> &V4, T base = 0) {\n this->sz = base;\n vector<T> V5 = V1;\n V5.insert(V5.end(), V2.begin(), V2.end());\n V5.insert(V5.end(), V3.begin(), V3.end());\n V5.insert(V5.end(), V4.begin(), V4.end());\n set<T> s(V5.begin(), V5.end());\n \n for (T x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n vector<int> zip(const vector<T> &V) {\n vector<int> ret(V.size());\n for (int i = 0; i < (int)V.size(); i++) {\n ret[i] = Z[V[i]];\n }\n return ret;\n }\n \n vector<T> unzip(const vector<int> &V) {\n vector<T> ret(V.size());\n for (int i = 0; i < (int)V.size(); i++) {\n ret[i] = UZ[V[i]];\n }\n return ret;\n }\n \n int size() { return sz; }\n \n T encode(int x) { return Z[x]; }\n int decode(T x) {\n if (UZ.find(x) == UZ.end()) return -1; // xが元の配列に存在しないとき\n return UZ[x];\n }\n};\n \n#pragma endregion\n\n// グラフ(隣接リスト)とターミナル頂点集合を渡す\n// 始点や終点が非固定ならそれも渡す\nint TSP(const vector<vector<Edge>> &G, vector<int> &V, int s = -1, int t = -1) {\n int N = G.size(); // Gの頂点数\n int K = V.size(); // ターミナル頂点数\n\n vector<vector<int>> dist(K, vector<int>(K, INFL));\n for (int i = 0; i < K; i++) {\n vector<int> D(N, INFL);\n D[V[i]] = 0;\n \n std::priority_queue<pair<int,int>, vector<pair<int,int>>, greater<pair<int,int>>> pq;\n pq.emplace(0, V[i]);\n \n while (pq.size()) {\n int d = pq.top().first;\n int v = pq.top().second;\n pq.pop();\n \n if (d > D[v]) continue;\n for (auto &e : G[v]) {\n if (D[e.to] > D[v] + e.cost) {\n D[e.to] = D[v] + e.cost;\n pq.emplace(D[e.to], e.to);\n }\n }\n }\n\n for (int j = 0; j < K; j++) {\n dist[i][j] = D[V[j]];\n }\n }\n \n // dp[i][j] := 頂点sから出発して訪問頂点の集合がiであり、最後に頂点jにいる\n // ときの移動距離の最小値\n vector<vector<int>> dp(1LL << K, vector<int>(K, INFL));\n\n if (s == -1) { // 始点非固定\n for (int i = 0; i < K; i++) {\n dp[1 << i][i] = 0;\n }\n } else {\n int s2 = -1;\n for (int i = 0; i < K; i++) {\n if (V[i] == s) {\n s2 = i;\n break;\n }\n }\n assert(s2 != -1);\n s = s2;\n dp[1 << s][s] = 0;\n }\n\n for (int i = 0; i < (1LL << K); i++) { // 全ての集合(状態)を小さい順に見る\n if (s != -1 && !(i & (1 << s))) continue; // 始点を含んでいないならとばす\n \n for (int j = 0; j < K; j++) { // 移動元としてあり得る都市を探し、\n if (dp[i][j] == INFL) continue;\n if (!(i & (1 << j))) continue;\n\n for (int k = 0; k < K; k++) { // 移動先の都市を探す\n if (i & (1LL << k)) continue; // 集合iに都市kが含まれてるならとばす\n\n int d = dist[j][k];\n dp[i + (1LL << k)][k] = min(dp[i + (1LL << k)][k], dp[i][j] + d);\n }\n }\n }\n\n if (t == -1) { // 終点非固定\n int ans = INFL;\n for (int i = 0; i < K; i++) {\n ans = min(ans, dp[(1 << K) - 1][i]);\n }\n\n if (ans == INFL) ans = -1;\n return ans;\n } else {\n if (dp[(1 << K) - 1][t] == INFL) dp[(1 << K) - 1][t] = -1;\n return dp[(1 << K) - 1][t];\n }\n}\n\nint H, W;\nbool isvalid(int x, int y) {\n if (x >= 0 && x < H && y >= 0 && y < W) return true;\n else return false;\n}\n\nsigned main() {\n while (cin >> W >> H, H) {\n vector<vector<char>> S(H, vector<char>(W));\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n cin >> S[i][j];\n }\n }\n\n int s;\n vector<int> V;\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n if (S[i][j] == 'o') {\n s = i*W + j;\n V.pb(s);\n S[i][j] = '.';\n }\n\n if (S[i][j] == '*') {\n int v = i*W + j;\n V.pb(v);\n S[i][j] = '.';\n }\n }\n }\n\n vector<vector<Edge>> G(H*W);\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n if (S[i][j] == 'x') continue;\n int v = i*W + j;\n\n for (int k = 0; k < 4; k++) {\n int ni = i + dx[k];\n int nj = j + dy[k];\n if (!isvalid(ni, nj)) continue;\n if (S[ni][nj] == 'x') continue;\n\n int nv = ni*W + nj; \n G[v].pb(Edge(nv, 1));\n }\n }\n }\n\n // 隣接リスト, 訪問頂点列(, 始点, 終点)\n // {s, t} \\in V の必要\n int ans = TSP(G, V, s);\n\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3552, "score_of_the_acc": -0.0954, "final_rank": 7 }, { "submission_id": "aoj_1140_9548822", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint dx[4] = {1,0,-1,0}, dy[4] = {0,1,0,-1};\n\nvector<vector<ll>> DFS(vector<string>& S, int SX, int SY) {\n int N = S.size();\n int M = S[0].size();\n vector<vector<ll>> Ret(N, vector<ll>(M,inf));\n Ret[SX][SY] = 0;\n queue<pair<int,int>> Q;\n Q.push({SX, SY});\n while(!Q.empty()) {\n auto [X, Y] = Q.front();\n Q.pop();\n rep(i,0,4) {\n int NX = X + dx[i], NY = Y + dy[i];\n if (0 <= NX && NX < N && 0 <= NY & NY < M) {\n if (S[NX][NY] == '.' && Ret[NX][NY] == inf) {\n Ret[NX][NY] = Ret[X][Y] + 1;\n Q.push({NX,NY});\n }\n }\n }\n }\n return Ret;\n}\n\nint main() {\nwhile(1) {\n int N, M;\n cin >> M >> N;\n if (N == 0 && M == 0) return 0;\n vector<string> S(N);\n rep(i,0,N) cin >> S[i];\n vector<int> SX, SY;\n rep(i,0,N) {\n rep(j,0,M) {\n if (S[i][j] == 'o') SX.push_back(i), SY.push_back(j), S[i][j] = '.';\n }\n }\n rep(i,0,N) {\n rep(j,0,M) {\n if (S[i][j] == '*') SX.push_back(i), SY.push_back(j), S[i][j] = '.';\n }\n }\n int L = SX.size();\n vector<vector<vector<ll>>> D(L);\n rep(i,0,L) D[i] = DFS(S, SX[i], SY[i]);\n ll ANS = inf;\n vector<int> ID(L-1);\n iota(ALL(ID),1);\n do {\n int Now = 0;\n ll COUNT = 0;\n rep(i,0,L-1) {\n COUNT += D[Now][SX[ID[i]]][SY[ID[i]]];\n Now = ID[i];\n }\n chmin(ANS, COUNT);\n } while(next_permutation(ALL(ID)));\n cout << (ANS == inf ? -1 : ANS) << endl;\n}\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3524, "score_of_the_acc": -0.1409, "final_rank": 12 }, { "submission_id": "aoj_1140_9521585", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nconst vector<int> dx = {1, 0, -1, 0};\nconst vector<int> dy = {0, 1, 0, -1};\nconst int INF = 1e9;\nint main() {\n while (1) {\n int w, h;\n cin >> w >> h;\n if (w == 0 && h == 0) {\n break;\n }\n vector<string> c(h);\n for (int i = 0; i < h; i++) {\n cin >> c[i];\n }\n int sh = -1, sw = -1;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (c[i][j] == 'o') {\n sh = i;\n sw = j;\n }\n }\n }\n vector<vector<bool>> used(h, vector<bool> (w, false));\n queue<pair<int, int>> Q;\n Q.push(make_pair(sh, sw));\n while (!Q.empty()) {\n auto [vh, vw] = Q.front();\n Q.pop();\n used[vh][vw] = true;\n for (int d = 0; d < 4; d++) {\n int nh = vh + dx[d];\n int nw = vw + dy[d];\n if (nh < 0 || nh >= h || nw < 0 || nw >= w) continue;\n if (!used[nh][nw] && c[nh][nw] != 'x') {\n Q.push(make_pair(nh, nw));\n used[nh][nw] = true;\n }\n }\n }\n bool ok = true;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (c[i][j] == '*' && !used[i][j]) {\n ok = false;\n }\n }\n }\n if (!ok) {\n cout << -1 << endl;\n continue;\n }\n vector<pair<int, int>> id;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (c[i][j] == 'o') {\n c[i][j] = '.';\n id.push_back(make_pair(i, j));\n }\n }\n }\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (c[i][j] == '*') {\n c[i][j] = '.';\n id.push_back(make_pair(i, j));\n }\n }\n }\n int N = id.size();\n vector<vector<int>> d2(N, vector<int> (N));\n for (int i = 0; i < N; i++) {\n vector<vector<int>> dist(h, vector<int> (w, INF));\n dist[id[i].first][id[i].second] = 0;\n Q.push(id[i]);\n while (!Q.empty()) {\n auto [vh, vw] = Q.front();\n Q.pop();\n for (int d = 0; d < 4; d++) {\n int nh = vh + dx[d];\n int nw = vw + dy[d];\n if (nh < 0 || nh >= h || nw < 0 || nw >= w) continue;\n if (c[nh][nw] != 'x' && dist[nh][nw] > dist[vh][vw] + 1) {\n dist[nh][nw] = dist[vh][vw] + 1;\n Q.push(make_pair(nh, nw));\n }\n }\n }\n for (int j = 0; j < N; j++) {\n if (i == j) continue;\n int nh = id[j].first;\n int nw = id[j].second;\n assert(dist[nh][nw] != INF);\n d2[i][j] = dist[nh][nw];\n d2[j][i] = dist[nh][nw];\n }\n }\n vector<int> ids(N);\n iota(ids.begin(), ids.end(), 0);\n int ans = INF;\n do {\n if (ids[0] != 0) break;\n int tmp = 0;\n for (int i = 1; i < N; i++) {\n tmp += d2[ids[i - 1]][ids[i]];\n }\n ans = min(ans, tmp);\n } while(next_permutation(ids.begin(), ids.end()));\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3456, "score_of_the_acc": -0.101, "final_rank": 9 }, { "submission_id": "aoj_1140_9403720", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing pll = pair<ll,ll>;\nusing plll = pair<pll,ll>;\nusing pii =pair<int,int>;\n\nconstexpr ll mod = 998244353;\n\nint dx[4]={1,0,-1,0};\nint dy[4]={0,1,0,-1};\nint dX[4]={1,0,-1,0};\nint dY[4]={0,-1,0,1};\n\n//library\n\n\n//end\n\nint bfs(pii & s, pii &g, vector<string> & F){\n int h=F.size(),w=F[0].size();\n queue<pii> que;\n vector<vector<int>> dist(h,vector<int>(w,100000));\n que.push(s);\n dist[s.first][s.second]=0;\n while (que.size()){\n auto [x,y]=que.front();\n que.pop();\n for (int d=0; d<4; d++){\n int nx=x+dx[d], ny=y+dy[d];\n if (nx<0 || nx>=h || ny<0 || ny>=w )continue;\n if (F[nx][ny]=='x')continue;\n if (dist[nx][ny]>dist[x][y]+1){\n dist[nx][ny]=dist[x][y]+1;\n que.emplace(nx,ny);\n }\n }\n }\n //cout<<dist[g.first][g.second]<<' '<<s.first<<endl;\n return dist[g.first][g.second];\n\n\n}\n\n\nint main(){\n while (true){\n int w,h;\n cin>>w>>h;\n if (w==0)break;\n vector<string> F(h);\n for (int i=0; i<h; i++)cin>>F[i];\n map<int,pii> dic;\n int k=1;\n for (int i=0; i<h; i++){\n for (int j=0; j<w; j++){\n if (F[i][j]=='*'){\n dic[k]=make_pair(i,j);\n k++;\n }\n if (F[i][j]=='o') {\n dic[0] = make_pair(i, j);\n //cout<<i<<endl;\n }\n\n }\n }\n\n //cout<<dic[0].first<<endl;\n bool ok=true;\n vector<vector<int>> E(k,vector<int>(k));\n for (int i=0; i<k-1; i++){\n for (int j=i+1; j<k; j++){\n int dis=bfs(dic[i],dic[j],F);\n if (dis==100000){\n ok=false;\n }\n E[i][j]=dis;\n E[j][i]=dis;\n }\n }\n\n if (ok==false){\n cout<<-1<<endl;\n continue;\n }\n\n vector<vector<int>> dp((1<<k),vector<int>(k,100000));\n dp[1][0]=0;\n for (int S=1; S<(1<<k); S++){\n for (int v=0; v<k; v++){\n if ((S&(1<<v))==0)continue;\n for (int u=0; u<k; u++){\n if ((S&(1<<u))>0)continue;\n dp[S+(1<<u)][u]=min(dp[S+(1<<u)][u],dp[S][v]+E[v][u]);\n }\n }\n }\n int ans=100000;\n for (int v=1; v<k; v++)ans=min(ans,dp[dp.size()-1][v]);\n cout<<ans<<endl;\n\n\n\n\n }\n\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3456, "score_of_the_acc": -0.0722, "final_rank": 3 }, { "submission_id": "aoj_1140_9364125", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\nusing ll = long long;\n#define MOD 1000000007\n#define Mod 998244353\nconst int MAX = 1000000005;\nconst long long INF = 1000000000000000005LL;\nusing namespace std;\n//using namespace atcoder;\n\nint di[] = {0, 1, 0, -1}, dj[] = {1, 0, -1, 0};\n\nbool solve() {\n int w, h;\n cin >> w >> h;\n if (w == 0 && h == 0) return false;\n vector<string> c(h);\n for (int i = 0; i < h; i++) cin >> c[i];\n vector<pair<int, int>> pos;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (c[i][j] == '*') pos.push_back({i, j});\n }\n }\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (c[i][j] == 'o') pos.push_back({i, j});\n }\n }\n int n = (int)pos.size();\n vector<vector<vector<int>>> dist(n, vector<vector<int>>(h, vector<int>(w, -1)));\n for (int i = 0; i < n; i++) {\n int si = pos[i].first, sj = pos[i].second;\n dist[i][si][sj] = 0;\n queue<pair<int, int>> que;\n que.push({si, sj});\n while (que.size()) {\n auto [x, y] = que.front();\n que.pop();\n for (int k = 0; k < 4; k++) {\n int ni = x + di[k], nj = y + dj[k];\n if (ni < 0 || ni >= h || nj < 0 || nj >= w) continue;\n if (c[ni][nj] == 'x') continue;\n if (dist[i][ni][nj] != -1) continue;\n dist[i][ni][nj] = dist[i][x][y] + 1;\n que.push({ni, nj});\n }\n }\n }\n vector<int> vec(n-1);\n for (int i = 0; i < n-1; i++) vec[i] = i;\n int ans = MAX;\n do {\n auto [ti, tj] = pos[vec[0]];\n if (dist[n-1][ti][tj] == -1) continue;\n int cnt = dist[n-1][ti][tj];\n for (int i = 1; i < n-1; i++) {\n ti = pos[vec[i]].first; tj = pos[vec[i]].second;\n if (dist[vec[i-1]][ti][tj] == -1) {\n cnt = MAX;\n break;\n }\n cnt += dist[vec[i-1]][ti][tj];\n }\n ans = min(ans, cnt);\n } while(next_permutation(vec.begin(), vec.end()));\n cout << (ans == MAX ? -1 : ans) << endl;\n return true;\n}\n\nint main() {\n ios::sync_with_stdio(0); cin.tie();\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3560, "score_of_the_acc": -0.1553, "final_rank": 13 }, { "submission_id": "aoj_1140_9359720", "code_snippet": "#include<bits/stdc++.h>\n//#include <atcoder/all>\nusing namespace std;\n//using namespace atcoder;\n\n#define all(v) v.begin(),v.end()\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll=vector<ll>;\nusing vvll = vector<vector<ll>>;\nusing P = pair<ll,ll>;\nusing vp=vector<pair<ll, ll>>;\n//using mint=modint1000000007;\n//using mint=modint998244353;\n\nconst ll INF=1ll<<60;\nll mod10=1e9+7;\nll mod99=998244353;\nconst double PI = acos(-1);\n\n#define rep(i,n) for (ll i=0;i<n;++i)\n#define per(i,n) for(ll i=n-1;i>=0;--i)\n#define rep2(i,a,n) for (ll i=a;i<n;++i)\n#define per2(i,a,n) for (ll i=a;i>=n;--i)\n\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\nvector<ll> dx={1,0,-1,0,-1,-1,1,1,0},dy={0,1,0,-1,-1,1,-1,1,0};\n\nbool solve(){\n ll W,H;cin>>W>>H;\n if(H==0&&W==0) return 0;\n vector<string> S(H);rep(i,H) cin>>S[i];\n ll sx,sy;\n rep(i,H) rep(j,W) if(S[i][j]=='o') sx=i,sy=j;\n vector dist(H,vector<vvll>(W,vvll(H,vll(W,INF))));\n rep(i,H) rep(j,W){\n dist[i][j][i][j]=0;\n queue<P> q;\n q.push({i,j});\n while(q.size()){\n auto [nowi,nowj]=q.front();q.pop();\n rep(k,4){\n ull toi=nowi+dx[k],toj=nowj+dy[k];\n if(!(toi<H&&toj<W)) continue;\n if(S[toi][toj]=='x') continue;\n if(dist[i][j][toi][toj]!=INF) continue;\n dist[i][j][toi][toj]=dist[i][j][nowi][nowj]+1;\n q.push({toi,toj});\n }\n }\n }\n\n vll A(0);\n rep(i,H) rep(j,W) if(S[i][j]=='o') A.push_back(i*W+j);\n rep(i,H) rep(j,W) if(S[i][j]=='*') A.push_back(i*W+j);\n ll si=A.size();\n vvll dp(1<<si,vll(si,INF));\n dp[1][0]=0;\n rep(i,1<<si){\n rep(j,si) rep(k,si){\n if(!(i>>j&1)) continue;\n if(i>>k&1) continue;\n chmin(dp[i|(1<<k)][k],dp[i][j]+dist[A[j]/W][A[j]%W][A[k]/W][A[k]%W]);\n \n }\n }\n\n ll ans=INF;\n rep(i,si) chmin(ans,dp[(1<<si)-1][i]);\n \n cout << (ans==INF?-1:ans) << endl;\n return 1;\n}\n\n\n\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n while(solve());\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 4740, "score_of_the_acc": -0.5127, "final_rank": 18 }, { "submission_id": "aoj_1140_9358447", "code_snippet": "#pragma region Macros\n \n#pragma GCC optimize(\"O3,unroll-loops\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,fma,abm,mmx,avx,avx2,popcnt\")\n \n#include <bits/extc++.h>\n// #include <atcoder/all>\n// using namespace atcoder;\nusing namespace std;\nusing namespace __gnu_pbds;\n \n// #include <boost/multiprecision/cpp_dec_float.hpp>\n// #include <boost/multiprecision/cpp_int.hpp>\n// namespace mp = boost::multiprecision;\n// using Bint = mp::cpp_int;\n// using Bdouble = mp::number<mp::cpp_dec_float<256>>;\n// Bdouble Beps = 0.00000000000000000000000000000001; // 1e-32\n// const bool equals(Bdouble a, Bdouble b) { return mp::fabs(a - b) < Beps; }\n \n#define pb emplace_back\n#define int ll\n#define endl '\\n'\n// #define unordered_map<int, int> gp_hash_table<int, int, custom_hash> \n \n#define sqrt __builtin_sqrtl\n#define cbrt __builtin_cbrtl\n#define hypot __builtin_hypotl\n \n#define next asdnext\n#define prev asdprev\n \nusing ll = long long;\nusing ld = long double;\nconst ld PI = acosl(-1);\nconst int INF = 1 << 30;\nconst ll INFL = 1LL << 61;\n// const int MOD = 998244353;\nconst int MOD = 1000000007;\n \nconst ld EPS = 1e-10;\nconst bool equals(ld a, ld b) { return fabs((a) - (b)) < EPS; }\n \nconst vector<int> dx = {0, 1, 0, -1, 1, 1, -1, -1}; // → ↓ ← ↑ ↘ ↙ ↖ ↗\nconst vector<int> dy = {1, 0, -1, 0, 1, -1, -1, 1};\n \n#define EC int\nstruct Edge {\n int from, to;\n EC cost;\n Edge() : from(-1), to(-1), cost(-1) {}\n Edge(int to, EC cost) : to(to), cost(cost) {}\n Edge(int from, int to, EC cost) : from(from), to(to), cost(cost) {}\n bool operator ==(const Edge& e) {\n return this->from == e.from && this->to == e.to && this->cost == e.cost;\n }\n bool operator !=(const Edge& e) {\n return this->from != e.from or this->to != e.to or this->cost != e.cost;\n }\n bool operator <(const Edge& e) { return this->cost < e.cost; }\n bool operator >(const Edge& e) { return this->cost > e.cost; }\n};\n \nchrono::system_clock::time_point start;\n__attribute__((constructor))\nvoid constructor() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(10);\n start = chrono::system_clock::now();\n}\n \nrandom_device seed_gen;\nmt19937_64 rng(seed_gen());\nuniform_int_distribution<int> dist_x(0, 1e9);\nstruct RNG {\n unsigned Int(unsigned l, unsigned r) {\n return dist_x(rng) % (r - l + 1) + l;\n }\n ld Double() {\n return ld(dist_x(rng)) / 1e9;\n }\n} rnd;\n \nusing i64 = ll;\n// using i64 = uint64_t;\n// bit演算, x==0の場合は例外処理した方がよさそう. 区間は [l, r)\ni64 lrmask(int l, int r) { return (1LL << r) - (1LL << l); }\ni64 sub_bit(i64 x, int l, int r) { i64 b = x & ((1LL << r) - (1LL << l)); return b >> l; } // r溢れ可\ni64 bit_width(i64 x) { return 64 - __builtin_clzll(x) + (x == 0); }\n \ni64 popcount(i64 x) { return __builtin_popcountll(x); }\ni64 popcount(i64 x, int l, int r) { return __builtin_popcountll(sub_bit(x, l, r)); }\ni64 unpopcount(i64 x) { return bit_width(x) - __builtin_popcountll(x); }\ni64 unpopcount(i64 x, int l, int r) { return r - l - __builtin_popcountll(sub_bit(x, l, r)); }\nbool is_pow2(i64 x) { return __builtin_popcountll(x) == 1; } // xが負のときは常にfalse\nbool is_pow4(i64 x) { return __builtin_popcount(x) == 1 && __builtin_ctz(x) % 2 == 0; }\n \nint top_bit(i64 x) { return 63 - __builtin_clzll(x);} // 2^kの位 (x > 0)\nint bot_bit(i64 x) { return __builtin_ctzll(x);} // 2^kの位 (x > 0)\nint next_bit(i64 x, int k) { // upper_bound\n x >>= (k + 1);\n int pos = k + 1;\n while (x > 0) {\n if (x & 1) return pos;\n x >>= 1;\n pos++;\n }\n return -1;\n}\nint prev_bit(i64 x, int k) {\n // k = min(k, bit_width(x)); ?\n int pos = 0;\n while (x > 0 && pos < k) {\n if (x & 1) {\n if (pos < k) return pos;\n }\n x >>= 1;\n pos++;\n }\n return -1;\n}\nint kth_bit(i64 x, int k) { // kは1-indexed\n int pos = 0, cnt = 0;\n while (x > 0) {\n if (x & 1) {\n cnt++;\n if (cnt == k) return pos;\n }\n x >>= 1;\n pos++;\n }\n return -1;\n}\ni64 MSB(i64 x) { if (x == 0) return 0; return 1LL << (63 - __builtin_clzll(x)); } // mask\ni64 LSB(i64 x) { return (x & -x); } // mask\n \nint countl_zero(i64 x) { return __builtin_clzll(x); }\nint countl_one(i64 x) {\n i64 ret = 0, k = 63 - __builtin_clzll(x);\n while (k != -1 && (x & (1LL << k))) { k--; ret++; }\n return ret;\n}\nint countr_zero(i64 x) { return __builtin_ctzll(x); } // x==0のとき64が返ることに注意\nint countr_one(i64 x) { int ret = 0; while (x & 1) { x >>= 1; ret++; } return ret; }\n \nint floor_log2(i64 x) { if (x == 0) return 0; return 63 - __builtin_clzll(x); } // top_bit\nint ceil_log2(i64 x) { if (x == 0) return 0; return 64 - __builtin_clzll(x - 1); }\ni64 bit_floor(i64 x) { if (x == 0) return 0; return 1LL << (63 - __builtin_clzll(x)); } // MSB\ni64 bit_ceil(i64 x) { if (x == 0) return 0; return 1LL << (64 - __builtin_clzll(x - 1)); }\n \ni64 rotl(i64 x, int k) { // 有効bit内でrotate. オーバーフロー注意\n i64 w = bit_width(x); k %= w;\n return ((x << k) | (x >> (w - k))) & ((1LL << w) - 1);\n}\n// i64 rotl(i64 x, i64 l, i64 m, i64 r) {}\ni64 rotr(i64 x, int k) {\n i64 w = bit_width(x); k %= w;\n return ((x >> k) | (x << (w - k))) & ((1LL << w) - 1);\n}\n// i64 rotr(i64 x, i64 l, i64 m, i64 r) {}\ni64 bit_reverse(i64 x) { // 有効bit内で左右反転\n i64 r = 0, w = bit_width(x);\n for (i64 i = 0; i < w; i++) r |= ((x >> i) & 1) << (w - i - 1);\n return r;\n}\n// i64 bit_reverse(i64 x, int l, int r) { return 0; }\n \nbool is_palindrome(i64 x) { return x == bit_reverse(x); }\nbool is_palindrome(i64 x, int l, int r) { i64 b = sub_bit(x, l, r); return b == bit_reverse(b); }\ni64 concat(i64 a, i64 b) { return (a << bit_width(b)) | b; } // オーバーフロー注意\ni64 erase(i64 x, int l, int r) { return x >> r << l | x & ((1LL << l) - 1); } // [l, r) をカット\n \ni64 hamming(i64 a, i64 b) { return __builtin_popcountll(a ^ b); }\ni64 hamming(i64 a, i64 b, int l, int r) { return __builtin_popcountll(sub_bit(a, l, r) ^ sub_bit(b, l, r)); }\ni64 compcount(i64 x) { return (__builtin_popcountll(x ^ (x >> 1)) + (x & 1)) / 2; }\ni64 compcount2(i64 x) { return compcount(x & (x >> 1)); } // 長さ2以上の連結成分の個数\ni64 adjacount(i64 x) { return __builtin_popcountll(x & (x >> 1)); } // 隣接する1のペアの個数\n \ni64 next_combination(i64 x) {\n i64 t = x | (x - 1); return (t + 1) | (((~t & -~t) - 1) >> (__builtin_ctzll(x) + 1));\n}\n \n \n__int128_t POW(__int128_t x, int n) {\n __int128_t ret = 1;\n assert(n >= 0);\n if (x == 1 or n == 0) ret = 1;\n else if (x == -1 && n % 2 == 0) ret = 1; \n else if (x == -1) ret = -1; \n else if (n % 2 == 0) {\n assert(x < INFL);\n ret = POW(x * x, n / 2);\n } else {\n assert(x < INFL);\n ret = x * POW(x, n - 1);\n }\n return ret;\n}\nint per(int x, int y) { // x = qy + r (0 <= r < y) を満たすq\n assert(y != 0);\n if (x >= 0 && y > 0) return x / y;\n if (x >= 0 && y < 0) return x / y - (x % y < 0);\n if (x < 0 && y < 0) return x / y + (x % y < 0);\n return x / y - (x % y < 0); // (x < 0 && y > 0) \n}\nint mod(int x, int y) { // x = qy + r (0 <= r < y) を満たすr\n assert(y != 0);\n if (x >= 0) return x % y;\n __int128_t ret = x % y; // (x < 0)\n ret += (__int128_t)abs(y) * INFL;\n ret %= abs(y);\n return ret;\n}\nint floor(int x, int y) { // (ld)x / y 以下の最大の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x >= 0 ? x / y : (x + 1) / y - 1;\n}\nint ceil(int x, int y) { // (ld)x / y 以上の最小の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x > 0 ? (x - 1) / y + 1 : x / y;\n}\nint round(int x, int y) { // (ld)(x/y)を小数点第1位について四捨五入\n assert(y != 0);\n return (x * 2 + y) / (y * 2);\n}\nint round(int x, int y, int k) { // (ld)(x/y)を10^kの位に関して四捨五入\n assert(y != 0 && k >= 0);\n if (k == 0) return (x * 2 + y) / (y * 2);\n x /= y * POW(10, k - 1);\n if (x % 10 >= 5) return (x + 10 - x % 10) * POW(10, k - 1);\n return x * POW(10, k - 1);\n}\nint round2(int x, int y) { // 五捨五超入 // 未verify\n assert(y != 0);\n if (y < 0) y = -y, x = -x;\n int z = x / y;\n if ((z * 2 + 1) * y <= y * 2) z++;\n return z;\n}\nld round(ld x, int k) { // xを10^kの位に関して四捨五入. to_string(x, k)優先\n // x += EPS;\n ld d = pow(10, -k);\n return round(x * d) / d;\n}\nld floor(ld x, int k) { // xを10^kの位に関してflooring\n // x += EPS;\n ld d = pow(10, -k);\n return floor(x * d) / d; // 未verify\n}\nld ceil(ld x, int k) { // xを10^kの位に関してceiling\n // x -= EPS;\n ld d = pow(10, -k);\n return ceil(x * d) / d; // 未verify\n}\n// int kth(int x, int y, int k) { // x / yの10^kの位の桁\n// }\nint floor(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return floor(x / y);\n // floor(x) = ceil(x - 1) という話も\n}\nint ceil(ld x, ld y) { // 誤差対策TODO // ceil(p/q) = -floor(-(p/q))らしい\n assert(!equals(y, 0));\n return ceil(x / y);\n // ceil(x) = floor(x + 1)\n}\nint perl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす q\n // 未verify. 誤差対策TODO. EPS外してもいいかも。\n assert(!equals(y, 0));\n if (x >= 0 && y > 0) return floor(x / y)+EPS;\n if (x >= 0 && y < 0) return -floor(x / fabs(y));\n if (x < 0 && y < 0) return floor(x / y) + (x - floor(x/y)*y < -EPS);\n return floor(x / y) - (x - floor(x/y)*y < -EPS); // (x < 0 && y > 0) \n}\nld modl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす r\n // 未verify. 誤差対策TODO. -0.0が返りうる。\n assert(!equals(y, 0));\n if (x >= 0) return x - fabs(y)*fabs(per(x, y));\n return x - fabs(y)*floor(x, fabs(y));\n}\nint seisuu(ld x) { return (int)x; } // 整数部分. 誤差対策TODO\nint modf(ld x) {\n\tif (x < 0) return ceill(x);\n\telse return floorl(x);\n}\n// 正なら+EPS, 負なら-EPSしてから、文字列に直して小数点以下を捨てる?\nint seisuu(int x, int y) {\n assert(y != 0);\n return x / y;\n}\nint seisuu(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return (int)(x / y);\n}\n \ntemplate <class T> pair<T, T> max(const pair<T, T> &a, const pair<T, T> &b) {\n if (a.first > b.first or a.first == b.first && a.second > b.second) return a;\n return b;\n}\ntemplate <class T> pair<T, T> min(const pair<T, T> &a, const pair<T, T> &b) {\n if (a.first < b.first or a.first == b.first && a.second < b.second) return a;\n return b;\n}\n \ntemplate <class T> bool chmax(T &a, const T& b) {\n if (a < b) { a = b; return true; } return false;\n}\ntemplate <class T> bool chmin(T &a, const T& b) {\n if (a > b) { a = b; return true; } return false;\n}\ntemplate <class T> T mid(T a, T b, T c) { // 誤差対策TODO\n return a + b + c - max({a, b, c}) - min({a, b, c});\n}\ntemplate <class T> void Sort(T &a, T &b, bool rev = false) { \n if (rev == false) if (a > b) swap(a, b);\n else if (b > a) swap(b, a);\n}\ntemplate <typename T, typename... Args>\nvoid Sort(T& a, T& b, T& c, Args&... args) {\n vector<T> vec = {a, b, c, args...};\n sort(vec.begin(), vec.end());\n auto it = vec.begin();\n a = *it++; b = *it++; c = *it++;\n int dummy[] = { (args = *it++, 0)... };\n static_cast<void>(dummy);\n}\n \nstruct custom_hash {\n static uint64_t splitmix64(uint64_t x) {\n x += 0x9e3779b97f4a7c15;\n x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n return x ^ (x >> 31);\n }\n \n size_t operator()(uint64_t x) const {\n static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();\n return splitmix64(x + FIXED_RANDOM);\n }\n};\n \nclass Compress {\npublic:\n int sz = 0;\n // gp_hash_table<int, int, custom_hash> Z, UZ;\n unordered_map<int, int> Z; // 元の値 -> 圧縮した値\n unordered_map<int, int> UZ; // 圧縮した値 -> 元の値\n \n Compress(const vector<int> &V, int base = 0) {\n this->sz = base;\n set<int> s(V.begin(), V.end());\n \n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n Compress(const vector<int> &V1, const vector<int> &V2, int base = 0) {\n this->sz = base;\n vector<int> V3 = V2;\n V3.insert(V3.end(), V1.begin(), V1.end());\n set<int> s(V3.begin(), V3.end());\n \n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n Compress(const vector<int> &V1, const vector<int> &V2, const vector<int> &V3, int base = 0) {\n this->sz = base;\n vector<int> V4 = V1;\n V4.insert(V4.end(), V2.begin(), V2.end());\n V4.insert(V4.end(), V3.begin(), V3.end());\n set<int> s(V4.begin(), V4.end());\n \n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n Compress(const vector<int> &V1, const vector<int> &V2,\n const vector<int> &V3, const vector<int> &V4, int base = 0) {\n this->sz = base;\n vector<int> V5 = V1;\n V5.insert(V5.end(), V2.begin(), V2.end());\n V5.insert(V5.end(), V3.begin(), V3.end());\n V5.insert(V5.end(), V4.begin(), V4.end());\n set<int> s(V5.begin(), V5.end());\n \n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n vector<int> zip(const vector<int> &V) {\n vector<int> ret = V;\n for (int i = 0; i < (int)V.size(); i++) {\n ret[i] = Z[ret[i]];\n }\n return ret;\n }\n \n vector<int> unzip(const vector<int> &V) {\n vector<int> ret = V;\n for (int i = 0; i < (int)V.size(); i++) {\n ret[i] = UZ[ret[i]];\n }\n return ret;\n }\n \n int size() { return sz; }\n \n int encode(int x) { return Z[x]; }\n int decode(int x) {\n if (UZ.find(x) == UZ.end()) return -1; // xが元の配列に存在しないとき\n return UZ[x];\n }\n};\n \nclass UnionFind {\npublic:\n\tUnionFind() = default;\n UnionFind(int N) : par(N), sz(N, 1) {\n iota(par.begin(), par.end(), 0);\n }\n\tint root(int x) {\n\t\tif (par[x] == x) return x;\n\t\treturn (par[x] = root(par[x]));\n\t}\n\tbool unite(int x, int y) {\n\t\tint rx = root(x);\n\t\tint ry = root(y);\n if (rx == ry) return false;\n\t\tif (sz[rx] < sz[ry]) swap(rx, ry);\n\t\tsz[rx] += sz[ry];\n\t\tpar[ry] = rx;\n return true;\n\t}\n\tbool issame(int x, int y) { return (root(x) == root(y)); }\n\tint size(int x) { return sz[root(x)]; }\n vector<vector<int>> groups(int N) {\n vector<vector<int>> G(N);\n for (int x = 0; x < N; x++) {\n G[root(x)].push_back(x);\n }\n\t\tG.erase( remove_if(G.begin(), G.end(),\n [&](const vector<int>& V) { return V.empty(); }), G.end());\n return G;\n }\nprivate:\n\tvector<int> par, sz;\n};\n \ntemplate<typename T> struct BIT {\n int N; // 要素数\n vector<T> bit[2]; // データの格納先\n BIT(int N_, int x = 0) {\n N = N_ + 1;\n bit[0].assign(N, 0); bit[1].assign(N, 0);\n if (x != 0) {\n for (int i = 0; i < N; i++) add(i, x);\n }\n }\n BIT(const vector<int> &A) {\n N = A.size() + 1;\n bit[0].assign(N, 0); bit[1].assign(N, 0);\n for (int i = 0; i < (int)A.size(); i++) add(i, A[i]);\n }\n void add_sub(int p, int i, T x) {\n while (i < N) { bit[p][i] += x; i += (i & -i); }\n }\n void add(int l, int r, T x) {\n add_sub(0, l + 1, -x * l); add_sub(0, r + 1, x * r);\n add_sub(1, l + 1, x); add_sub(1, r + 1, -x);\n }\n void add(int i, T x) { add(i, i + 1, x); }\n T sum_sub(int p, int i) {\n T ret = 0;\n while (i > 0) { ret += bit[p][i]; i -= (i & -i); }\n return ret;\n }\n T sum(int i) { return sum_sub(0, i) + sum_sub(1, i) * i; }\n T sum(int l, int r) { return sum(r) - sum(l); }\n T get(int i) { return sum(i, i + 1); }\n void set(int i, T x) { T s = get(i); add(i, -s + x); }\n};\n \ntemplate<int mod> class Modint {\npublic:\n int val = 0;\n Modint(int x = 0) { while (x < 0) x += mod; val = x % mod; }\n Modint(const Modint &r) { val = r.val; }\n \n Modint operator -() { return Modint(-val); } // 単項\n Modint operator +(const Modint &r) { return Modint(*this) += r; }\n Modint operator +(const int &q) { Modint r(q); return Modint(*this) += r; }\n Modint operator -(const Modint &r) { return Modint(*this) -= r; }\n Modint operator -(const int &q) { Modint r(q); return Modint(*this) -= r; }\n Modint operator *(const Modint &r) { return Modint(*this) *= r; }\n Modint operator *(const int &q) { Modint r(q); return Modint(*this) *= r; }\n Modint operator /(const Modint &r) { return Modint(*this) /= r; }\n Modint operator /(const int &q) { Modint r(q); return Modint(*this) /= r; }\n \n Modint& operator ++() { val++; if (val >= mod) val -= mod; return *this; } // 前置\n Modint operator ++(signed) { ++*this; return *this; } // 後置\n Modint& operator --() { val--; if (val < 0) val += mod; return *this; }\n Modint operator --(signed) { --*this; return *this; }\n Modint &operator +=(const Modint &r) { val += r.val; if (val >= mod) val -= mod; return *this; }\n Modint &operator +=(const int &q) { Modint r(q); val += r.val; if (val >= mod) val -= mod; return *this; }\n Modint &operator -=(const Modint &r) { if (val < r.val) val += mod; val -= r.val; return *this; }\n Modint &operator -=(const int &q) { Modint r(q); if (val < r.val) val += mod; val -= r.val; return *this; }\n Modint &operator *=(const Modint &r) { val = val * r.val % mod; return *this; }\n Modint &operator *=(const int &q) { Modint r(q); val = val * r.val % mod; return *this; }\n Modint &operator /=(const Modint &r) {\n int a = r.val, b = mod, u = 1, v = 0;\n while (b) {int t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v);}\n val = val * u % mod; if (val < 0) val += mod;\n return *this;\n }\n Modint &operator /=(const int &q) {\n Modint r(q); int a = r.val, b = mod, u = 1, v = 0;\n while (b) {int t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v);}\n val = val * u % mod; if (val < 0) val += mod;\n return *this;\n }\n bool operator ==(const Modint& r) { return this -> val == r.val; }\n bool operator <(const Modint& r) { return this -> val < r.val; }\n bool operator >(const Modint& r) { return this -> val > r.val; }\n bool operator !=(const Modint& r) { return this -> val != r.val; }\n};\n \nusing mint = Modint<MOD>;\n \nistream &operator >>(istream &is, mint& x) {\n int t; is >> t; x = t; return (is);\n}\nostream &operator <<(ostream &os, const mint& x) {\n return os << x.val;\n}\nmint modpow(const mint &x, int n) {\n if (n < 0) return (mint)1 / modpow(x, -n); // 未verify\n assert(n >= 0);\n if (n == 0) return 1;\n mint t = modpow(x, n / 2);\n t = t * t;\n if (n & 1) t = t * x;\n return t;\n}\n \nint modpow(__int128_t x, int n, int mod) {\n assert(n >= 0 && mod > 0); // TODO: n <= -1\n __int128_t ret = 1;\n while (n > 0) {\n if (n % 2 == 1) ret = ret * x % mod;\n x = x * x % mod;\n n /= 2;\n }\n return ret;\n}\nint modinv(__int128_t x, int mod) {\n assert(mod > 0);\n // assert(x > 0);\n if (x == 1 or x == 0) return 1;\n return mod - modinv(mod % x, mod) * (mod / x) % mod;\n}\n \nistream &operator >>(istream &is, __int128_t& x) {\n string S; is >> S;\n __int128_t ret = 0;\n int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9')\n ret = ret * 10 + S[i] - '0';\n x = ret * f;\n return (is);\n}\nostream &operator <<(ostream &os, __int128_t x) {\n ostream::sentry s(os);\n if (s) {\n __uint128_t tmp = x < 0 ? -x : x;\n char buffer[128]; char *d = end(buffer);\n do {\n --d; *d = \"0123456789\"[tmp % 10]; tmp /= 10;\n } while (tmp != 0);\n if (x < 0) { --d; *d = '-'; }\n int len = end(buffer) - d;\n if (os.rdbuf()->sputn(d, len) != len) os.setstate(ios_base::badbit);\n }\n return os;\n}\n \n__int128_t stoll(string &S) {\n __int128_t ret = 0; int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9') ret = ret * 10 + S[i] - '0';\n return ret * f;\n}\n__int128_t gcd(__int128_t a, __int128_t b) { return b ? gcd(b, a % b) : a; }\n__int128_t lcm(__int128_t a, __int128_t b) {\n return a / gcd(a, b) * b;\n // lcmが__int128_tに収まる必要あり\n}\n \nstring to_string(ld x, int k) { // xの小数第k位までをstring化する\n assert(k >= 0);\n stringstream ss;\n ss << setprecision(k + 2) << x;\n string s = ss.str();\n if (s.find('.') == string::npos) s += '.';\n int pos = s.find('.');\n for (int i = 0; k >= (int)s.size() - 1 - pos; i++) s += '0';\n s.pop_back();\n if (s.back() == '.') s.pop_back();\n return s;\n \n // stringstream ss; // 第k+1位を四捨五入して第k位まで返す\n // ss << setprecision(k + 1) << x;\n // string s = ss.str();\n // if (s.find('.') == string::npos) s += '.';\n // int pos = s.find('.');\n // for (int i = 0; k > (int)s.size() - 1 - pos; i++) s += '0';\n // if (s.back() == '.') s.pop_back();\n // return s;\n}\nstring to_string(__int128_t x) {\n string ret = \"\";\n if (x < 0) { ret += \"-\"; x *= -1; }\n while (x) { ret += (char)('0' + x % 10); x /= 10; }\n reverse(ret.begin(), ret.end());\n return ret;\n}\nstring to_string(char c) { string s = \"\"; s += c; return s; }\n \ntemplate<class T> size_t HashCombine(const size_t seed,const T &v) {\n return seed^(hash<T>()(v)+0x9e3779b9+(seed<<6)+(seed>>2));\n}\ntemplate<class T,class S> struct hash<pair<T,S>>{\n size_t operator()(const pair<T,S> &keyval) const noexcept {\n return HashCombine(hash<T>()(keyval.first), keyval.second);\n }\n};\ntemplate<class T> struct hash<vector<T>>{\n size_t operator()(const vector<T> &keyval) const noexcept {\n size_t s=0;\n for (auto&& v: keyval) s=HashCombine(s,v);\n return s;\n }\n};\ntemplate<int N> struct HashTupleCore{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{\n size_t s=HashTupleCore<N-1>()(keyval);\n return HashCombine(s,get<N-1>(keyval));\n }\n};\ntemplate <> struct HashTupleCore<0>{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{ return 0; }\n};\ntemplate<class... Args> struct hash<tuple<Args...>>{\n size_t operator()(const tuple<Args...> &keyval) const noexcept {\n return HashTupleCore<tuple_size<tuple<Args...>>::value>()(keyval);\n }\n};\n \nvector<mint> _fac, _finv, _inv;\nvoid COMinit(int N) {\n _fac.resize(N + 1); _finv.resize(N + 1); _inv.resize(N + 1);\n _fac[0] = _fac[1] = 1; _finv[0] = _finv[1] = 1; _inv[1] = 1;\n for (int i = 2; i <= N; i++) {\n _fac[i] = _fac[i-1] * mint(i);\n _inv[i] = -_inv[MOD % i] * mint(MOD / i);\n _finv[i] = _finv[i - 1] * _inv[i];\n }\n}\n \nmint FAC(int N) {\n if (N < 0) return 0; return _fac[N];\n}\nmint COM(int N, int K) {\n if (N < K) return 0; if (N < 0 or K < 0) return 0;\n return _fac[N] * _finv[K] * _finv[N - K];\n}\nmint PERM(int N, int K) {\n if (N < K) return 0; if (N < 0 or K < 0) return 0;\n return _fac[N] * _finv[N - K];\n}\nmint NHK(int N, int K) { // initのサイズに注意\n if (N == 0 && K == 0) return 1;\n return COM(N + K - 1, K);\n}\n \n#pragma endregion\n\nint H, W;\nbool isvalid(int x, int y) {\n if (x >= 0 && x < H && y >= 0 && y < W) return true;\n else return false;\n}\n\nsigned main() {\n while (cin >> W >> H, H) {\n int sx, sy;\n vector<pair<int, int>> C; // 飴のあるマスの集合\n vector<vector<char>> S(H, vector<char>(W));\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n cin >> S[i][j];\n if (S[i][j] == 'o') sx = i, sy = j;\n if (S[i][j] == '*') {\n C.pb(i, j);\n }\n }\n }\n\n vector<vector<Edge>> G(H * W);\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n if (S[i][j] == 'x') continue;\n\n for (int k = 0; k < 4; k++) {\n int ni = i + dx[k];\n int nj = j + dy[k];\n\n if (!isvalid(ni, nj)) continue;\n if (S[ni][nj] == 'x') continue;\n\n int c = 1;\n\n G[i*W + j].pb(ni*W + nj, c);\n }\n }\n }\n\n int szC = C.size();\n vector<int> V(szC + 1); // 飴 + 始点\n V[0] = sx*W + sy;\n for (int i = 1; i <= szC; i++) {\n V[i] = C[i - 1].first*W + C[i - 1].second;\n }\n\n vector<vector<int>> dist(szC + 1, vector<int>(szC + 1, INFL));\n // 頂点V[i]から頂点V[j]への距離表\n for (int i = 0; i < szC + 1; i++) {\n vector<int> D(H * W, INFL);\n D[V[i]] = 0;\n \n std::priority_queue<pair<int,int>, vector<pair<int,int>>, greater<pair<int,int>>> pq;\n pq.emplace(0, V[i]);\n \n while (pq.size()) {\n int d = pq.top().first;\n int v = pq.top().second;\n pq.pop();\n \n if (d > D[v]) continue;\n for (auto &e : G[v]) {\n if (D[e.to] > D[v] + e.cost) {\n D[e.to] = D[v] + e.cost;\n pq.emplace(D[e.to], e.to);\n }\n }\n }\n\n for (int j = 0; j < szC + 1; j++) {\n dist[i][j] = D[V[j]];\n }\n }\n\n // for (int i = 0; i < szC + 1; i++) {\n // for (int j = 0; j < szC + 1; j++) {\n // cout << dist[i][j] << (j != szC + 1 - 1 ? \" \" : \"\\n\");\n // }\n // }\n \n vector<vector<int>> dp(1LL << (szC + 1), vector<int>(szC + 1, INFL));\n dp[1 << 0][0] = 0;\n\n for (int i = 0; i < (1LL << (szC + 1)); i++) { // 全ての集合(状態)を小さい順に見る\n // if (!(i & (1 << 0))) continue; // 始点を含んでいないならとばす\n for (int j = 0; j < (szC + 1); j++) { // 移動元としてあり得る都市を探し、\n if (dp[i][j] == INFL) continue;\n // if (!(i & (1 << j))) continue;\n\n for (int k = 0; k < (szC + 1); k++) { // 移動先の都市を探す\n if (i & (1LL << k)) continue; // 集合iに都市kが含まれてるならとばす\n\n int d = dist[j][k];\n dp[i + (1LL << k)][k] = min(dp[i + (1LL << k)][k], dp[i][j] + d);\n }\n }\n }\n\n // 訪問した都市の集合が111...1で、最後に訪れた都市がgであるとき\n int ans = *min_element(dp[(1 << (szC + 1)) - 1].begin(), dp[(1 << (szC + 1)) - 1].end());\n if (ans == INFL) cout << -1 << endl;\n else cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3624, "score_of_the_acc": -0.116, "final_rank": 11 }, { "submission_id": "aoj_1140_9358180", "code_snippet": "#pragma region Macros\n \n#pragma GCC optimize(\"O3,unroll-loops\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,fma,abm,mmx,avx,avx2,popcnt\")\n \n#include <bits/extc++.h>\n// #include <atcoder/all>\n// using namespace atcoder;\nusing namespace std;\nusing namespace __gnu_pbds;\n \n// #include <boost/multiprecision/cpp_dec_float.hpp>\n// #include <boost/multiprecision/cpp_int.hpp>\n// namespace mp = boost::multiprecision;\n// using Bint = mp::cpp_int;\n// using Bdouble = mp::number<mp::cpp_dec_float<256>>;\n// Bdouble Beps = 0.00000000000000000000000000000001; // 1e-32\n// const bool equals(Bdouble a, Bdouble b) { return mp::fabs(a - b) < Beps; }\n \n#define pb emplace_back\n#define int ll\n#define endl '\\n'\n// #define unordered_map<int, int> gp_hash_table<int, int, custom_hash> \n \n#define sqrt __builtin_sqrtl\n#define cbrt __builtin_cbrtl\n#define hypot __builtin_hypotl\n \n#define next asdnext\n#define prev asdprev\n \nusing ll = long long;\nusing ld = long double;\nconst ld PI = acosl(-1);\nconst int INF = 1 << 30;\nconst ll INFL = 1LL << 61;\n// const int MOD = 998244353;\nconst int MOD = 1000000007;\n \nconst ld EPS = 1e-10;\nconst bool equals(ld a, ld b) { return fabs((a) - (b)) < EPS; }\n \nconst vector<int> dx = {0, 1, 0, -1, 1, 1, -1, -1}; // → ↓ ← ↑ ↘ ↙ ↖ ↗\nconst vector<int> dy = {1, 0, -1, 0, 1, -1, -1, 1};\n \n#define EC int\nstruct Edge {\n int from, to;\n EC cost;\n Edge() : from(-1), to(-1), cost(-1) {}\n Edge(int to, EC cost) : to(to), cost(cost) {}\n Edge(int from, int to, EC cost) : from(from), to(to), cost(cost) {}\n bool operator ==(const Edge& e) {\n return this->from == e.from && this->to == e.to && this->cost == e.cost;\n }\n bool operator !=(const Edge& e) {\n return this->from != e.from or this->to != e.to or this->cost != e.cost;\n }\n bool operator <(const Edge& e) { return this->cost < e.cost; }\n bool operator >(const Edge& e) { return this->cost > e.cost; }\n};\n \nchrono::system_clock::time_point start;\n__attribute__((constructor))\nvoid constructor() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(10);\n start = chrono::system_clock::now();\n}\n \nrandom_device seed_gen;\nmt19937_64 rng(seed_gen());\nuniform_int_distribution<int> dist_x(0, 1e9);\nstruct RNG {\n unsigned Int(unsigned l, unsigned r) {\n return dist_x(rng) % (r - l + 1) + l;\n }\n ld Double() {\n return ld(dist_x(rng)) / 1e9;\n }\n} rnd;\n \nusing i64 = ll;\n// using i64 = uint64_t;\n// bit演算, x==0の場合は例外処理した方がよさそう. 区間は [l, r)\ni64 lrmask(int l, int r) { return (1LL << r) - (1LL << l); }\ni64 sub_bit(i64 x, int l, int r) { i64 b = x & ((1LL << r) - (1LL << l)); return b >> l; } // r溢れ可\ni64 bit_width(i64 x) { return 64 - __builtin_clzll(x) + (x == 0); }\n \ni64 popcount(i64 x) { return __builtin_popcountll(x); }\ni64 popcount(i64 x, int l, int r) { return __builtin_popcountll(sub_bit(x, l, r)); }\ni64 unpopcount(i64 x) { return bit_width(x) - __builtin_popcountll(x); }\ni64 unpopcount(i64 x, int l, int r) { return r - l - __builtin_popcountll(sub_bit(x, l, r)); }\nbool is_pow2(i64 x) { return __builtin_popcountll(x) == 1; } // xが負のときは常にfalse\nbool is_pow4(i64 x) { return __builtin_popcount(x) == 1 && __builtin_ctz(x) % 2 == 0; }\n \nint top_bit(i64 x) { return 63 - __builtin_clzll(x);} // 2^kの位 (x > 0)\nint bot_bit(i64 x) { return __builtin_ctzll(x);} // 2^kの位 (x > 0)\nint next_bit(i64 x, int k) { // upper_bound\n x >>= (k + 1);\n int pos = k + 1;\n while (x > 0) {\n if (x & 1) return pos;\n x >>= 1;\n pos++;\n }\n return -1;\n}\nint prev_bit(i64 x, int k) {\n // k = min(k, bit_width(x)); ?\n int pos = 0;\n while (x > 0 && pos < k) {\n if (x & 1) {\n if (pos < k) return pos;\n }\n x >>= 1;\n pos++;\n }\n return -1;\n}\nint kth_bit(i64 x, int k) { // kは1-indexed\n int pos = 0, cnt = 0;\n while (x > 0) {\n if (x & 1) {\n cnt++;\n if (cnt == k) return pos;\n }\n x >>= 1;\n pos++;\n }\n return -1;\n}\ni64 MSB(i64 x) { if (x == 0) return 0; return 1LL << (63 - __builtin_clzll(x)); } // mask\ni64 LSB(i64 x) { return (x & -x); } // mask\n \nint countl_zero(i64 x) { return __builtin_clzll(x); }\nint countl_one(i64 x) {\n i64 ret = 0, k = 63 - __builtin_clzll(x);\n while (k != -1 && (x & (1LL << k))) { k--; ret++; }\n return ret;\n}\nint countr_zero(i64 x) { return __builtin_ctzll(x); } // x==0のとき64が返ることに注意\nint countr_one(i64 x) { int ret = 0; while (x & 1) { x >>= 1; ret++; } return ret; }\n \nint floor_log2(i64 x) { if (x == 0) return 0; return 63 - __builtin_clzll(x); } // top_bit\nint ceil_log2(i64 x) { if (x == 0) return 0; return 64 - __builtin_clzll(x - 1); }\ni64 bit_floor(i64 x) { if (x == 0) return 0; return 1LL << (63 - __builtin_clzll(x)); } // MSB\ni64 bit_ceil(i64 x) { if (x == 0) return 0; return 1LL << (64 - __builtin_clzll(x - 1)); }\n \ni64 rotl(i64 x, int k) { // 有効bit内でrotate. オーバーフロー注意\n i64 w = bit_width(x); k %= w;\n return ((x << k) | (x >> (w - k))) & ((1LL << w) - 1);\n}\n// i64 rotl(i64 x, i64 l, i64 m, i64 r) {}\ni64 rotr(i64 x, int k) {\n i64 w = bit_width(x); k %= w;\n return ((x >> k) | (x << (w - k))) & ((1LL << w) - 1);\n}\n// i64 rotr(i64 x, i64 l, i64 m, i64 r) {}\ni64 bit_reverse(i64 x) { // 有効bit内で左右反転\n i64 r = 0, w = bit_width(x);\n for (i64 i = 0; i < w; i++) r |= ((x >> i) & 1) << (w - i - 1);\n return r;\n}\n// i64 bit_reverse(i64 x, int l, int r) { return 0; }\n \nbool is_palindrome(i64 x) { return x == bit_reverse(x); }\nbool is_palindrome(i64 x, int l, int r) { i64 b = sub_bit(x, l, r); return b == bit_reverse(b); }\ni64 concat(i64 a, i64 b) { return (a << bit_width(b)) | b; } // オーバーフロー注意\ni64 erase(i64 x, int l, int r) { return x >> r << l | x & ((1LL << l) - 1); } // [l, r) をカット\n \ni64 hamming(i64 a, i64 b) { return __builtin_popcountll(a ^ b); }\ni64 hamming(i64 a, i64 b, int l, int r) { return __builtin_popcountll(sub_bit(a, l, r) ^ sub_bit(b, l, r)); }\ni64 compcount(i64 x) { return (__builtin_popcountll(x ^ (x >> 1)) + (x & 1)) / 2; }\ni64 compcount2(i64 x) { return compcount(x & (x >> 1)); } // 長さ2以上の連結成分の個数\ni64 adjacount(i64 x) { return __builtin_popcountll(x & (x >> 1)); } // 隣接する1のペアの個数\n \ni64 next_combination(i64 x) {\n i64 t = x | (x - 1); return (t + 1) | (((~t & -~t) - 1) >> (__builtin_ctzll(x) + 1));\n}\n \n \n__int128_t POW(__int128_t x, int n) {\n __int128_t ret = 1;\n assert(n >= 0);\n if (x == 1 or n == 0) ret = 1;\n else if (x == -1 && n % 2 == 0) ret = 1; \n else if (x == -1) ret = -1; \n else if (n % 2 == 0) {\n assert(x < INFL);\n ret = POW(x * x, n / 2);\n } else {\n assert(x < INFL);\n ret = x * POW(x, n - 1);\n }\n return ret;\n}\nint per(int x, int y) { // x = qy + r (0 <= r < y) を満たすq\n assert(y != 0);\n if (x >= 0 && y > 0) return x / y;\n if (x >= 0 && y < 0) return x / y - (x % y < 0);\n if (x < 0 && y < 0) return x / y + (x % y < 0);\n return x / y - (x % y < 0); // (x < 0 && y > 0) \n}\nint mod(int x, int y) { // x = qy + r (0 <= r < y) を満たすr\n assert(y != 0);\n if (x >= 0) return x % y;\n __int128_t ret = x % y; // (x < 0)\n ret += (__int128_t)abs(y) * INFL;\n ret %= abs(y);\n return ret;\n}\nint floor(int x, int y) { // (ld)x / y 以下の最大の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x >= 0 ? x / y : (x + 1) / y - 1;\n}\nint ceil(int x, int y) { // (ld)x / y 以上の最小の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x > 0 ? (x - 1) / y + 1 : x / y;\n}\nint round(int x, int y) { // (ld)(x/y)を小数点第1位について四捨五入\n assert(y != 0);\n return (x * 2 + y) / (y * 2);\n}\nint round(int x, int y, int k) { // (ld)(x/y)を10^kの位に関して四捨五入\n assert(y != 0 && k >= 0);\n if (k == 0) return (x * 2 + y) / (y * 2);\n x /= y * POW(10, k - 1);\n if (x % 10 >= 5) return (x + 10 - x % 10) * POW(10, k - 1);\n return x * POW(10, k - 1);\n}\nint round2(int x, int y) { // 五捨五超入 // 未verify\n assert(y != 0);\n if (y < 0) y = -y, x = -x;\n int z = x / y;\n if ((z * 2 + 1) * y <= y * 2) z++;\n return z;\n}\nld round(ld x, int k) { // xを10^kの位に関して四捨五入. to_string(x, k)優先\n // x += EPS;\n ld d = pow(10, -k);\n return round(x * d) / d;\n}\nld floor(ld x, int k) { // xを10^kの位に関してflooring\n // x += EPS;\n ld d = pow(10, -k);\n return floor(x * d) / d; // 未verify\n}\nld ceil(ld x, int k) { // xを10^kの位に関してceiling\n // x -= EPS;\n ld d = pow(10, -k);\n return ceil(x * d) / d; // 未verify\n}\n// int kth(int x, int y, int k) { // x / yの10^kの位の桁\n// }\nint floor(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return floor(x / y);\n // floor(x) = ceil(x - 1) という話も\n}\nint ceil(ld x, ld y) { // 誤差対策TODO // ceil(p/q) = -floor(-(p/q))らしい\n assert(!equals(y, 0));\n return ceil(x / y);\n // ceil(x) = floor(x + 1)\n}\nint perl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす q\n // 未verify. 誤差対策TODO. EPS外してもいいかも。\n assert(!equals(y, 0));\n if (x >= 0 && y > 0) return floor(x / y)+EPS;\n if (x >= 0 && y < 0) return -floor(x / fabs(y));\n if (x < 0 && y < 0) return floor(x / y) + (x - floor(x/y)*y < -EPS);\n return floor(x / y) - (x - floor(x/y)*y < -EPS); // (x < 0 && y > 0) \n}\nld modl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす r\n // 未verify. 誤差対策TODO. -0.0が返りうる。\n assert(!equals(y, 0));\n if (x >= 0) return x - fabs(y)*fabs(per(x, y));\n return x - fabs(y)*floor(x, fabs(y));\n}\nint seisuu(ld x) { return (int)x; } // 整数部分. 誤差対策TODO\nint modf(ld x) {\n\tif (x < 0) return ceill(x);\n\telse return floorl(x);\n}\n// 正なら+EPS, 負なら-EPSしてから、文字列に直して小数点以下を捨てる?\nint seisuu(int x, int y) {\n assert(y != 0);\n return x / y;\n}\nint seisuu(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return (int)(x / y);\n}\n \ntemplate <class T> pair<T, T> max(const pair<T, T> &a, const pair<T, T> &b) {\n if (a.first > b.first or a.first == b.first && a.second > b.second) return a;\n return b;\n}\ntemplate <class T> pair<T, T> min(const pair<T, T> &a, const pair<T, T> &b) {\n if (a.first < b.first or a.first == b.first && a.second < b.second) return a;\n return b;\n}\n \ntemplate <class T> bool chmax(T &a, const T& b) {\n if (a < b) { a = b; return true; } return false;\n}\ntemplate <class T> bool chmin(T &a, const T& b) {\n if (a > b) { a = b; return true; } return false;\n}\ntemplate <class T> T mid(T a, T b, T c) { // 誤差対策TODO\n return a + b + c - max({a, b, c}) - min({a, b, c});\n}\ntemplate <class T> void Sort(T &a, T &b, bool rev = false) { \n if (rev == false) if (a > b) swap(a, b);\n else if (b > a) swap(b, a);\n}\ntemplate <typename T, typename... Args>\nvoid Sort(T& a, T& b, T& c, Args&... args) {\n vector<T> vec = {a, b, c, args...};\n sort(vec.begin(), vec.end());\n auto it = vec.begin();\n a = *it++; b = *it++; c = *it++;\n int dummy[] = { (args = *it++, 0)... };\n static_cast<void>(dummy);\n}\n \nstruct custom_hash {\n static uint64_t splitmix64(uint64_t x) {\n x += 0x9e3779b97f4a7c15;\n x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n return x ^ (x >> 31);\n }\n \n size_t operator()(uint64_t x) const {\n static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();\n return splitmix64(x + FIXED_RANDOM);\n }\n};\n \nclass Compress {\npublic:\n int sz = 0;\n // gp_hash_table<int, int, custom_hash> Z, UZ;\n unordered_map<int, int> Z; // 元の値 -> 圧縮した値\n unordered_map<int, int> UZ; // 圧縮した値 -> 元の値\n \n Compress(const vector<int> &V, int base = 0) {\n this->sz = base;\n set<int> s(V.begin(), V.end());\n \n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n Compress(const vector<int> &V1, const vector<int> &V2, int base = 0) {\n this->sz = base;\n vector<int> V3 = V2;\n V3.insert(V3.end(), V1.begin(), V1.end());\n set<int> s(V3.begin(), V3.end());\n \n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n Compress(const vector<int> &V1, const vector<int> &V2, const vector<int> &V3, int base = 0) {\n this->sz = base;\n vector<int> V4 = V1;\n V4.insert(V4.end(), V2.begin(), V2.end());\n V4.insert(V4.end(), V3.begin(), V3.end());\n set<int> s(V4.begin(), V4.end());\n \n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n Compress(const vector<int> &V1, const vector<int> &V2,\n const vector<int> &V3, const vector<int> &V4, int base = 0) {\n this->sz = base;\n vector<int> V5 = V1;\n V5.insert(V5.end(), V2.begin(), V2.end());\n V5.insert(V5.end(), V3.begin(), V3.end());\n V5.insert(V5.end(), V4.begin(), V4.end());\n set<int> s(V5.begin(), V5.end());\n \n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n vector<int> zip(const vector<int> &V) {\n vector<int> ret = V;\n for (int i = 0; i < (int)V.size(); i++) {\n ret[i] = Z[ret[i]];\n }\n return ret;\n }\n \n vector<int> unzip(const vector<int> &V) {\n vector<int> ret = V;\n for (int i = 0; i < (int)V.size(); i++) {\n ret[i] = UZ[ret[i]];\n }\n return ret;\n }\n \n int size() { return sz; }\n \n int encode(int x) { return Z[x]; }\n int decode(int x) {\n if (UZ.find(x) == UZ.end()) return -1; // xが元の配列に存在しないとき\n return UZ[x];\n }\n};\n \nclass UnionFind {\npublic:\n\tUnionFind() = default;\n UnionFind(int N) : par(N), sz(N, 1) {\n iota(par.begin(), par.end(), 0);\n }\n\tint root(int x) {\n\t\tif (par[x] == x) return x;\n\t\treturn (par[x] = root(par[x]));\n\t}\n\tbool unite(int x, int y) {\n\t\tint rx = root(x);\n\t\tint ry = root(y);\n if (rx == ry) return false;\n\t\tif (sz[rx] < sz[ry]) swap(rx, ry);\n\t\tsz[rx] += sz[ry];\n\t\tpar[ry] = rx;\n return true;\n\t}\n\tbool issame(int x, int y) { return (root(x) == root(y)); }\n\tint size(int x) { return sz[root(x)]; }\n vector<vector<int>> groups(int N) {\n vector<vector<int>> G(N);\n for (int x = 0; x < N; x++) {\n G[root(x)].push_back(x);\n }\n\t\tG.erase( remove_if(G.begin(), G.end(),\n [&](const vector<int>& V) { return V.empty(); }), G.end());\n return G;\n }\nprivate:\n\tvector<int> par, sz;\n};\n \ntemplate<typename T> struct BIT {\n int N; // 要素数\n vector<T> bit[2]; // データの格納先\n BIT(int N_, int x = 0) {\n N = N_ + 1;\n bit[0].assign(N, 0); bit[1].assign(N, 0);\n if (x != 0) {\n for (int i = 0; i < N; i++) add(i, x);\n }\n }\n BIT(const vector<int> &A) {\n N = A.size() + 1;\n bit[0].assign(N, 0); bit[1].assign(N, 0);\n for (int i = 0; i < (int)A.size(); i++) add(i, A[i]);\n }\n void add_sub(int p, int i, T x) {\n while (i < N) { bit[p][i] += x; i += (i & -i); }\n }\n void add(int l, int r, T x) {\n add_sub(0, l + 1, -x * l); add_sub(0, r + 1, x * r);\n add_sub(1, l + 1, x); add_sub(1, r + 1, -x);\n }\n void add(int i, T x) { add(i, i + 1, x); }\n T sum_sub(int p, int i) {\n T ret = 0;\n while (i > 0) { ret += bit[p][i]; i -= (i & -i); }\n return ret;\n }\n T sum(int i) { return sum_sub(0, i) + sum_sub(1, i) * i; }\n T sum(int l, int r) { return sum(r) - sum(l); }\n T get(int i) { return sum(i, i + 1); }\n void set(int i, T x) { T s = get(i); add(i, -s + x); }\n};\n \ntemplate<int mod> class Modint {\npublic:\n int val = 0;\n Modint(int x = 0) { while (x < 0) x += mod; val = x % mod; }\n Modint(const Modint &r) { val = r.val; }\n \n Modint operator -() { return Modint(-val); } // 単項\n Modint operator +(const Modint &r) { return Modint(*this) += r; }\n Modint operator +(const int &q) { Modint r(q); return Modint(*this) += r; }\n Modint operator -(const Modint &r) { return Modint(*this) -= r; }\n Modint operator -(const int &q) { Modint r(q); return Modint(*this) -= r; }\n Modint operator *(const Modint &r) { return Modint(*this) *= r; }\n Modint operator *(const int &q) { Modint r(q); return Modint(*this) *= r; }\n Modint operator /(const Modint &r) { return Modint(*this) /= r; }\n Modint operator /(const int &q) { Modint r(q); return Modint(*this) /= r; }\n \n Modint& operator ++() { val++; if (val >= mod) val -= mod; return *this; } // 前置\n Modint operator ++(signed) { ++*this; return *this; } // 後置\n Modint& operator --() { val--; if (val < 0) val += mod; return *this; }\n Modint operator --(signed) { --*this; return *this; }\n Modint &operator +=(const Modint &r) { val += r.val; if (val >= mod) val -= mod; return *this; }\n Modint &operator +=(const int &q) { Modint r(q); val += r.val; if (val >= mod) val -= mod; return *this; }\n Modint &operator -=(const Modint &r) { if (val < r.val) val += mod; val -= r.val; return *this; }\n Modint &operator -=(const int &q) { Modint r(q); if (val < r.val) val += mod; val -= r.val; return *this; }\n Modint &operator *=(const Modint &r) { val = val * r.val % mod; return *this; }\n Modint &operator *=(const int &q) { Modint r(q); val = val * r.val % mod; return *this; }\n Modint &operator /=(const Modint &r) {\n int a = r.val, b = mod, u = 1, v = 0;\n while (b) {int t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v);}\n val = val * u % mod; if (val < 0) val += mod;\n return *this;\n }\n Modint &operator /=(const int &q) {\n Modint r(q); int a = r.val, b = mod, u = 1, v = 0;\n while (b) {int t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v);}\n val = val * u % mod; if (val < 0) val += mod;\n return *this;\n }\n bool operator ==(const Modint& r) { return this -> val == r.val; }\n bool operator <(const Modint& r) { return this -> val < r.val; }\n bool operator >(const Modint& r) { return this -> val > r.val; }\n bool operator !=(const Modint& r) { return this -> val != r.val; }\n};\n \nusing mint = Modint<MOD>;\n \nistream &operator >>(istream &is, mint& x) {\n int t; is >> t; x = t; return (is);\n}\nostream &operator <<(ostream &os, const mint& x) {\n return os << x.val;\n}\nmint modpow(const mint &x, int n) {\n if (n < 0) return (mint)1 / modpow(x, -n); // 未verify\n assert(n >= 0);\n if (n == 0) return 1;\n mint t = modpow(x, n / 2);\n t = t * t;\n if (n & 1) t = t * x;\n return t;\n}\n \nint modpow(__int128_t x, int n, int mod) {\n assert(n >= 0 && mod > 0); // TODO: n <= -1\n __int128_t ret = 1;\n while (n > 0) {\n if (n % 2 == 1) ret = ret * x % mod;\n x = x * x % mod;\n n /= 2;\n }\n return ret;\n}\nint modinv(__int128_t x, int mod) {\n assert(mod > 0);\n // assert(x > 0);\n if (x == 1 or x == 0) return 1;\n return mod - modinv(mod % x, mod) * (mod / x) % mod;\n}\n \nistream &operator >>(istream &is, __int128_t& x) {\n string S; is >> S;\n __int128_t ret = 0;\n int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9')\n ret = ret * 10 + S[i] - '0';\n x = ret * f;\n return (is);\n}\nostream &operator <<(ostream &os, __int128_t x) {\n ostream::sentry s(os);\n if (s) {\n __uint128_t tmp = x < 0 ? -x : x;\n char buffer[128]; char *d = end(buffer);\n do {\n --d; *d = \"0123456789\"[tmp % 10]; tmp /= 10;\n } while (tmp != 0);\n if (x < 0) { --d; *d = '-'; }\n int len = end(buffer) - d;\n if (os.rdbuf()->sputn(d, len) != len) os.setstate(ios_base::badbit);\n }\n return os;\n}\n \n__int128_t stoll(string &S) {\n __int128_t ret = 0; int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9') ret = ret * 10 + S[i] - '0';\n return ret * f;\n}\n__int128_t gcd(__int128_t a, __int128_t b) { return b ? gcd(b, a % b) : a; }\n__int128_t lcm(__int128_t a, __int128_t b) {\n return a / gcd(a, b) * b;\n // lcmが__int128_tに収まる必要あり\n}\n \nstring to_string(ld x, int k) { // xの小数第k位までをstring化する\n assert(k >= 0);\n stringstream ss;\n ss << setprecision(k + 2) << x;\n string s = ss.str();\n if (s.find('.') == string::npos) s += '.';\n int pos = s.find('.');\n for (int i = 0; k >= (int)s.size() - 1 - pos; i++) s += '0';\n s.pop_back();\n if (s.back() == '.') s.pop_back();\n return s;\n \n // stringstream ss; // 第k+1位を四捨五入して第k位まで返す\n // ss << setprecision(k + 1) << x;\n // string s = ss.str();\n // if (s.find('.') == string::npos) s += '.';\n // int pos = s.find('.');\n // for (int i = 0; k > (int)s.size() - 1 - pos; i++) s += '0';\n // if (s.back() == '.') s.pop_back();\n // return s;\n}\nstring to_string(__int128_t x) {\n string ret = \"\";\n if (x < 0) { ret += \"-\"; x *= -1; }\n while (x) { ret += (char)('0' + x % 10); x /= 10; }\n reverse(ret.begin(), ret.end());\n return ret;\n}\nstring to_string(char c) { string s = \"\"; s += c; return s; }\n \ntemplate<class T> size_t HashCombine(const size_t seed,const T &v) {\n return seed^(hash<T>()(v)+0x9e3779b9+(seed<<6)+(seed>>2));\n}\ntemplate<class T,class S> struct hash<pair<T,S>>{\n size_t operator()(const pair<T,S> &keyval) const noexcept {\n return HashCombine(hash<T>()(keyval.first), keyval.second);\n }\n};\ntemplate<class T> struct hash<vector<T>>{\n size_t operator()(const vector<T> &keyval) const noexcept {\n size_t s=0;\n for (auto&& v: keyval) s=HashCombine(s,v);\n return s;\n }\n};\ntemplate<int N> struct HashTupleCore{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{\n size_t s=HashTupleCore<N-1>()(keyval);\n return HashCombine(s,get<N-1>(keyval));\n }\n};\ntemplate <> struct HashTupleCore<0>{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{ return 0; }\n};\ntemplate<class... Args> struct hash<tuple<Args...>>{\n size_t operator()(const tuple<Args...> &keyval) const noexcept {\n return HashTupleCore<tuple_size<tuple<Args...>>::value>()(keyval);\n }\n};\n \nvector<mint> _fac, _finv, _inv;\nvoid COMinit(int N) {\n _fac.resize(N + 1); _finv.resize(N + 1); _inv.resize(N + 1);\n _fac[0] = _fac[1] = 1; _finv[0] = _finv[1] = 1; _inv[1] = 1;\n for (int i = 2; i <= N; i++) {\n _fac[i] = _fac[i-1] * mint(i);\n _inv[i] = -_inv[MOD % i] * mint(MOD / i);\n _finv[i] = _finv[i - 1] * _inv[i];\n }\n}\n \nmint FAC(int N) {\n if (N < 0) return 0; return _fac[N];\n}\nmint COM(int N, int K) {\n if (N < K) return 0; if (N < 0 or K < 0) return 0;\n return _fac[N] * _finv[K] * _finv[N - K];\n}\nmint PERM(int N, int K) {\n if (N < K) return 0; if (N < 0 or K < 0) return 0;\n return _fac[N] * _finv[N - K];\n}\nmint NHK(int N, int K) { // initのサイズに注意\n if (N == 0 && K == 0) return 1;\n return COM(N + K - 1, K);\n}\n \n#pragma endregion\n\nint H, W;\nbool isvalid(int x, int y) {\n if (x >= 0 && x < H && y >= 0 && y < W) return true;\n else return false;\n}\n\nsigned main() {\n while (cin >> W >> H, H) {\n int sx, sy;\n vector<pair<int, int>> C; // 飴のあるマスの集合\n vector<vector<char>> S(H, vector<char>(W));\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n cin >> S[i][j];\n if (S[i][j] == 'o') sx = i, sy = j;\n if (S[i][j] == '*') {\n C.pb(i, j);\n }\n }\n }\n\n vector<vector<Edge>> G(H * W);\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n if (S[i][j] == 'x') continue;\n\n for (int k = 0; k < 4; k++) {\n int ni = i + dx[k];\n int nj = j + dy[k];\n\n if (!isvalid(ni, nj)) continue;\n if (S[ni][nj] == 'x') continue;\n\n int c = 1;\n\n G[i*W + j].pb(ni*W + nj, c);\n }\n }\n }\n\n int szC = C.size();\n vector<int> V(szC + 1); // 飴 + 始点\n V[0] = sx*W + sy;\n for (int i = 1; i <= szC; i++) {\n V[i] = C[i - 1].first*W + C[i - 1].second;\n }\n\n vector<vector<int>> dist(szC + 1, vector<int>(szC + 1, INFL));\n // 頂点V[i]から頂点V[j]への距離表\n for (int i = 0; i < szC + 1; i++) {\n vector<int> D(H * W, INFL);\n D[V[i]] = 0;\n \n std::priority_queue<pair<int,int>, vector<pair<int,int>>, greater<pair<int,int>>> pq;\n pq.emplace(0, V[i]);\n \n while (pq.size()) {\n int d = pq.top().first;\n int v = pq.top().second;\n pq.pop();\n \n if (d > D[v]) continue;\n for (auto &e : G[v]) {\n if (D[e.to] > D[v] + e.cost) {\n D[e.to] = D[v] + e.cost;\n pq.emplace(D[e.to], e.to);\n }\n }\n }\n\n for (int j = 0; j < szC + 1; j++) {\n dist[i][j] = D[V[j]];\n }\n }\n\n // for (int i = 0; i < szC + 1; i++) {\n // for (int j = 0; j < szC + 1; j++) {\n // cout << dist[i][j] << (j != szC + 1 - 1 ? \" \" : \"\\n\");\n // }\n // }\n \n vector<vector<int>> dp(1LL << (szC + 1), vector<int>(szC + 1, INFL));\n dp[0][0] = 0;\n\n for (int i = 0; i < (1LL << (szC + 1)); i++) { // 全ての集合(状態)を小さい順に見る\n // if (!(i & (1 << 0))) continue; // 始点を含んでいないならとばす\n for (int j = 0; j < (szC + 1); j++) { // 移動元としてあり得る都市を探し、\n if (dp[i][j] == INFL) continue;\n // if (!(i & (1 << j))) continue;\n\n for (int k = 0; k < (szC + 1); k++) { // 移動先の都市を探す\n if (i & (1LL << k)) continue; // 集合iに都市kが含まれてるならとばす\n\n int d = dist[j][k];\n dp[i + (1LL << k)][k] = min(dp[i + (1LL << k)][k], dp[i][j] + d);\n }\n }\n }\n\n // 訪問した都市の集合が111...1で、最後に訪れた都市がgであるとき\n int ans = *min_element(dp[(1 << (szC + 1)) - 1].begin(), dp[(1 << (szC + 1)) - 1].end());\n if (ans == INFL) cout << -1 << endl;\n else cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3580, "score_of_the_acc": -0.1034, "final_rank": 10 }, { "submission_id": "aoj_1140_9297140", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (long long i = 0; i < (long long)(n); i++)\n#define rrep(i,start,end) for (long long i = start;i >= (long long)(end);i--)\n#define repn(i,end) for(long long i = 0; i <= (long long)(end); i++)\n#define reps(i,start,end) for(long long i = start; i < (long long)(end); i++)\n#define repsn(i,start,end) for(long long i = start; i <= (long long)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\ntypedef vector<long long> vll;\ntypedef vector<pair<long long ,long long>> vpll;\ntypedef vector<vector<long long>> vvll;\ntypedef set<ll> sll;\ntypedef map<long long , long long> mpll;\ntypedef pair<long long ,long long> pll;\ntypedef tuple<long long , long long , long long> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (int)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1LL << 60;\nconst ld EPS = 1e-9;\n \ninline ll lfloor(ll x,ll m){return (x - ((x % m+ m)%m))/m;}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\n// for AOJ or ICPC or etc..\n// 全部が0だったらtrueを返す\ntemplate<class Tp> bool zero (const Tp &x) {return x == 0;}\ntemplate<class Tp, class... Args> bool zero (const Tp &x, const Args& ...args) {return zero(x) and zero(args...);}\n\n\nint warshall_floyd(vector<vector<ll>> &dist){\n int size = (int)dist.size();\n rep(k,size){\n rep(i,size){\n rep(j,size){\n if(i == j){\n chmin(dist[i][j],0LL);\n }\n if(dist[i][k] != INF && dist[k][j] != INF){\n chmin(dist[i][j],dist[i][k] + dist[k][j]);\n }\n }\n }\n }\n //負の閉路判定あれば−1大丈夫なら1\n rep(i,size){\n if(dist[i][i]<0){\n return -1;\n }\n }\n return 1;\n}\n// 変数をちゃんと全部受け取る!\nvoid solve(ll w,ll h){\n vector<string> g(h);\n rep(i,h){\n cin >> g[i];\n }\n ll s = 0;\n vll plc;\n auto clc = [&](ll y, ll x){\n return y * w + x;\n };\n auto rclc = [&](ll v)->pll{\n return {v/w,v % w};\n };\n vvll dist(h * w,vll(h * w,INF));\n rep(i,h){\n rep(j,w){\n // cout <<i << \" \" << j << endl;\n if(g[i][j] == 'x'){\n continue;\n }else if(g[i][j] == 'o'){\n s = clc(i,j);\n }else if(g[i][j] == '*'){\n plc.push_back(clc(i,j));\n } \n rep(k,4){\n ll ny = i + _ta[k];\n ll nx = j + _yo[k];\n if(isin(ny,nx,h,w) && g[ny][nx] != 'X'){\n dist[clc(i,j)][clc(ny,nx)] = 1;\n // dist[clc(ny,nx)][clc(i,j)] = 1;\n }\n }\n }\n }\n // cout << \"here\" << endl;\n warshall_floyd(dist);\n // rep(i,h * w){\n // rep(j,h * w){\n // cout << ((dist[i][j] == INF) ? 0:dist[i][j]) << \" \";\n // }\n // cout << endl;\n // }\n // cout << s << endl;\n // cout << plc << endl;\n if(plc.size() == 0){\n cout << 0 << endl;\n return ;\n }\n each(p,plc){\n // cout << s << \" \" << p << \" \" << dist[s][p] << endl;\n if(dist[s][p] == INF){\n cout << -1 << endl;\n return ;\n }\n }\n ll siz = plc.size();\n vector<vector<ll>> dp(1 << siz,vll(siz,INF));\n rep(i,siz){\n dp[1 << i][i] = dist[s][plc[i]];\n }\n // rep(i,1 << siz){\n // rep(j,siz){\n // cout << dp[i][j] << \" \"; \n // }\n // cout << endl;\n // }\n // cout << endl;\n rep(i,1 << siz){\n rep(j,siz){\n if(dp[i][j] == INF)continue;\n rep(k,siz){\n if(~i >> k & 1){\n chmin(dp[i + (1 << k)][k],dp[i][j] + dist[plc[j]][plc[k]]);\n }\n }\n }\n }\n // rep(i,1 << siz){\n // rep(j,siz){\n // cout << dp[i][j] << \" \";\n // }\n // cout << endl;\n // }\n\n ll ans = INF;\n rep(i,siz){\n chmin(ans,dp[(1 << siz)-1][i]);\n }\n if(ans == INF){\n cout << -1 << endl;\n }else{\n cout << ans << endl;\n }\n}\n \nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true){\n LL(w,h);//変数数調整\n if(zero(w,h))break;\n solve(w,h);\n }\n}", "accuracy": 1, "time_ms": 2440, "memory_kb": 4528, "score_of_the_acc": -1.3699, "final_rank": 20 }, { "submission_id": "aoj_1140_9247418", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint w,h;\nstring c[20];\nvoid solve(){\n int sx=-1,sy=-1;\n vector<pair<int,int>>dirt;\n for(int i=0;i<h;++i)for(int j=0;j<w;++j){\n if(c[i][j]=='o')sx=i,sy=j;\n if(c[i][j]=='*')dirt.emplace_back(i,j);\n }\n int n=dirt.size();\n dirt.emplace_back(sx,sy);\n vector<vector<int>>dist(n+1,vector<int>(n+1,1<<29));\n for(int i=0;i<n+1;++i){\n for(int j=i+1;j<n+1;++j){\n vector<vector<int>>d(h,vector<int>(w,1<<29));\n auto[sx,sy]=dirt[i];\n d[sx][sy]=0;\n queue<pair<int,int>>que;\n que.push({sx,sy});\n while(!que.empty()){\n auto[x,y]=que.front();\n que.pop();\n int dx[4]={1,0,-1,0},dy[4]={0,1,0,-1};\n for(int dir=0;dir<4;++dir){\n int xx=x+dx[dir],yy=y+dy[dir];\n if(!(0<=xx&&xx<h&&0<=yy&&yy<w))continue;\n if(c[xx][yy]=='x')continue;\n if(d[xx][yy]!=1<<29)continue;\n d[xx][yy]=d[x][y]+1;\n que.push({xx,yy});\n }\n }\n auto[tx,ty]=dirt[j];\n dist[i][j]=dist[j][i]=d[tx][ty];\n }\n }\n vector<vector<int>>dp(1<<n,vector<int>(n,1<<29));\n for(int i=0;i<n;++i)dp[1<<i][i]=dist[n][i];\n for(int bit=1;bit<1<<n;++bit){\n for(int i=0;i<n;++i){\n if(!(bit&(1<<i)))continue;\n for(int j=0;j<n;++j){\n if(i==j)continue;\n if(bit&(1<<j))continue;\n dp[bit|(1<<j)][j]=min(dp[bit|(1<<j)][j],dp[bit][i]+dist[i][j]);\n }\n }\n }\n int ans=1<<29;\n for(int i=0;i<n;++i)ans=min(ans,dp[(1<<n)-1][i]);\n if(ans==1<<29)ans=-1;\n cout<<ans<<'\\n';\n}\nint main(){\n cin.tie(0)->sync_with_stdio(0);\n while(1){\n cin>>w>>h;\n if(w==0)break;\n for(int i=0;i<h;++i)cin>>c[i];\n solve();\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3512, "score_of_the_acc": -0.084, "final_rank": 5 } ]
aoj_1142_cpp
Problem B: Organize Your Train part II RJ Freight, a Japanese railroad company for freight operations has recently constructed exchange lines at Hazawa, Yokohama. The layout of the lines is shown in Figure B-1. Figure B-1: Layout of the exchange lines A freight train consists of 2 to 72 freight cars. There are 26 types of freight cars, which are denoted by 26 lowercase letters from "a" to "z". The cars of the same type are indistinguishable from each other, and each car's direction doesn't matter either. Thus, a string of lowercase letters of length 2 to 72 is sufficient to completely express the configuration of a train. Upon arrival at the exchange lines, a train is divided into two sub-trains at an arbitrary position (prior to entering the storage lines). Each of the sub-trains may have its direction reversed (using the reversal line). Finally, the two sub-trains are connected in either order to form the final configuration. Note that the reversal operation is optional for each of the sub-trains. For example, if the arrival configuration is "abcd", the train is split into two sub-trains of either 3:1, 2:2 or 1:3 cars. For each of the splitting, possible final configurations are as follows ("+" indicates final concatenation position): [3:1] abc+d cba+d d+abc d+cba [2:2] ab+cd ab+dc ba+cd ba+dc cd+ab cd+ba dc+ab dc+ba [1:3] a+bcd a+dcb bcd+a dcb+a Excluding duplicates, 12 distinct configurations are possible. Given an arrival configuration, answer the number of distinct configurations which can be constructed using the exchange lines described above. Input The entire input looks like the following. the number of datasets = m 1st dataset 2nd dataset ... m-th dataset Each dataset represents an arriving train, and is a string of 2 to 72 lowercase letters in an input line. Output For each dataset, output the number of possible train configurations in a line. No other characters should appear in the output. Sample Input 4 aa abba abcd abcde Output for the Sample Input 1 6 12 18
[ { "submission_id": "aoj_1142_10999336", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <set>\nusing namespace std;\n\nint main() {\n int N;\n cin >> N;\n for (int i=0; i<N; ++i) {\n string word;\n set<string> S;\n cin >> word;\n for (size_t j=0; j<=word.size(); ++j) {\n string l = word.substr(0, j);\n string r = word.substr(j);\n S.insert(l + r);\n S.insert(r + l);\n string reversed_l = l;\n reverse(reversed_l.begin(), reversed_l.end());\n string reversed_r = r;\n reverse(reversed_r.begin(), reversed_r.end());\n S.insert(l + reversed_r);\n S.insert(r + reversed_l);\n S.insert(reversed_l + r);\n S.insert(reversed_r + l);\n S.insert(reversed_l + reversed_r);\n S.insert(reversed_r + reversed_l);\n }\n cout << S.size() << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3540, "score_of_the_acc": -0.0486, "final_rank": 9 }, { "submission_id": "aoj_1142_10852919", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <iostream>\n#include <stdlib.h>\n#include <cmath>\n#include <map>\n#include <queue>\n#define N 75\nusing namespace std;\nstruct node\n{\n char a[N];\n}q[N*N];\nint cnt;\nbool judge(char s[])\n{\n if(cnt == 0) return true;\n for(int i=0;i<cnt;i++)\n {\n if(strcmp(q[i].a,s)==0)\n return false;\n }\n return true;\n}\nint main()\n{\n int T;\n scanf(\"%d\",&T);\n while(T--)\n {\n char s[N];\n scanf(\"%s\",s);\n int len=strlen(s);\n int ans=0;\n cnt=0;\n for(int i=0;i<len-1;i++)\n {\n\n char b1[80],b2[80]; // 如果四部分分别为 a1 a2 a3 a4\n int c1=0,c2=0; // 其中 a3是a1的反串 a4是a2的反串\n for(int j=0;j<=i;j++) //b1 = a1 + a4 \n { //b2 = a4 + a1\n b1[c1++]= s[j]; \n }\n for(int j=len-1;j>i;j--)\n {\n b1[c1++] = s[j];\n b2[c2++]= s[j];\n }\n for(int j=0;j<=i;j++)\n {\n b2[c2++] = s[j];\n }\n b1[c1]='\\0';\n b2[c2]='\\0';\n if(judge(b1)) //判断b1是否已经存在\n {\n strcpy(q[cnt++].a,b1); //不存在记录下b1\n ans++;\n }\n if(judge(b2))\n {\n strcpy(q[cnt++].a,b2);\n ans++;\n }\n c1=0;\n c2=0;\n for(int j=0;j<=i;j++) //b1 = a1 + a2\n {\n b1[c1++] = s[j]; //b2 = a2 + a1\n\n }\n for(int j=i+1;j<len;j++)\n {\n b1[c1++] = s[j];\n b2[c2++]= s[j];\n }\n for(int j=0;j<=i;j++)\n {\n b2[c2++]= s[j];\n }\n if(judge(b1))\n {\n strcpy(q[cnt++].a,b1);\n ans++;\n }\n if(judge(b2))\n {\n strcpy(q[cnt++].a,b2);\n ans++;\n }\n c1=0;\n c2=0;\n for(int j=i+1;j<len;j++) //b1 = a2 + a3\n {\n b1[c1++] = s[j]; // b2 = a3 + a2\n }\n for(int j=i;j>=0;j--)\n {\n b1[c1++] = s[j];\n b2[c2++]= s[j];\n }\n for(int j=i+1;j<len;j++)\n {\n\n b2[c2++]= s[j];\n }\n if(judge(b1))\n {\n strcpy(q[cnt++].a,b1);\n ans++;\n }\n if(judge(b2))\n {\n strcpy(q[cnt++].a,b2);\n ans++;\n }\n c1=0;\n c2=0;\n for(int j=i;j>=0;j--) //b1 = a3 + a4\n {\n b1[c1++] = s[j]; //b2 = a4 + a3\n\n }\n for(int j=len-1;j>i;j--)\n {\n b1[c1++] = s[j];\n b2[c2++]= s[j];\n }\n for(int j=i;j>=0;j--)\n {\n\n b2[c2++]= s[j];\n }\n if(judge(b1))\n {\n strcpy(q[cnt++].a,b1);\n ans++;\n }\n if(judge(b2))\n {\n strcpy(q[cnt++].a,b2);\n ans++;\n }\n }\n printf(\"%d\\n\",ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3280, "score_of_the_acc": -0.6667, "final_rank": 18 }, { "submission_id": "aoj_1142_10733268", "code_snippet": "#include <map>\n#include <string>\n#include <iostream>\nusing namespace std;\nstring s;\nmap<string,int>t;\nint TS;\nint main(){\n cin >> TS;\n for(int O=1; O<=TS; O++){\n cin >> s;\n t.clear();\n int ANS = 0;\n int N = (int)s.length();\n for(int i=1; i<N; i++){\n string a = \"\";\n for(int j=0; j<i; j++)\n a+= s[j];\n string b = \"\";\n for(int j=i-1; j>=0; j--)\n b+= s[j];\n string c = \"\";\n for(int j=i; j<N; j++)\n c+= s[j];\n string d = \"\";\n for(int j=N-1; j>=i; j--)\n d+= s[j];\n if(!t[a+c]){\n t[a+c] = 1;\n ANS++;\n }\n if(!t[a+d]){\n t[a+d] = 1;\n ANS++;\n }\n if(!t[b+c]){\n t[b+c] = 1;\n ANS++;\n }\n if(!t[b+d]){\n t[b+d] = 1;\n ANS++;\n }\n if(!t[c+a]){\n t[c+a] = 1;\n ANS++;\n }\n if(!t[d+a]){\n t[d+a] = 1;\n ANS++;\n }\n if(!t[c+b]){\n t[c+b] = 1;\n ANS++;\n }\n if(!t[d+b]){\n t[d+b] = 1;\n ANS++;\n }\n }\n cout << ANS << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3396, "score_of_the_acc": -0.0217, "final_rank": 5 }, { "submission_id": "aoj_1142_10733258", "code_snippet": "#include <iostream>\n#include <cstring>\n#include <set>\n\nusing namespace std;\n\nset<string> s;\nstring t;\nint n, len;\n\nstring reverse(const string &s) {\n\tstring res = \"\";\n\tfor (int i = s.length() - 1; ~i; i--)\n\t\tres += s[i];\n\treturn res;\n}\n\nstring x, y, _x, _y;\nint main() {\n\tios::sync_with_stdio(0);\n\tcin >> n;\n\twhile (n--) {\n\t\tcin >> t;\n\t\ts.clear();\n\t\tlen = t.length();\n\t\tfor (int i = 1; i < len; i++) {\n\t\t\tx = t.substr(0, i);\n\t\t\ty = t.substr(i, len);\n\t\t\t_x = reverse(x);\n\t\t\t_y = reverse(y);\n\t\t\ts.insert(x + y);\n\t\t\ts.insert(x + _y);\n\t\t\ts.insert(_x + y);\n\t\t\ts.insert(_x + _y);\n\t\t}\n\t\tt = reverse(t);\n\t\tfor (int i = 1; i < len; i++) {\n\t\t\tx = t.substr(0, i);\n\t\t\ty = t.substr(i, len);\n\t\t\t_x = reverse(x);\n\t\t\t_y = reverse(y);\n\t\t\ts.insert(x + y);\n\t\t\ts.insert(x + _y);\n\t\t\ts.insert(_x + y);\n\t\t\ts.insert(_x + _y);\n\t\t}\n\t\tcout << s.size() << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3360, "score_of_the_acc": -0.015, "final_rank": 2 }, { "submission_id": "aoj_1142_10733255", "code_snippet": "#include<cstdio>\n#include<cmath>\n#include<iostream>\n#include<cstring>\n#include<map>\n#include<string> \nusing namespace std;\nmap<string,bool>m;\nstring a,b,c,d;\nchar s[200];\nint n;\nint main(){\n\tscanf(\"%d\",&n);\n\tlong long sol;\n\tfor(int i=1;i<=n;i++){ \n\t\tmemset(s,0,sizeof(s));\n\t\tscanf(\"%s\",s); \n\t\tm.clear();\n\t\tsol=0;\n\t\tfor(int j=1;j<strlen(s);j++){\n\t\t\ta=b=c=d=\"\";\n\t\t\tfor(int k=0;k<j;k++){\n\t\t\t\ta=a+s[k];\n\t\t\t\tb=s[k]+b;\n\t\t\t}\n\t\t\tfor(int k=j;k<strlen(s);k++){\n\t\t\t\tc=c+s[k];\n\t\t\t\td=s[k]+d;\n\t\t\t}\n\t\t\tif(m[a+c]==0)sol++;\n\t\t\tm[a+c]=1;\n\t\t\tif(m[a+d]==0)sol++;\n\t\t\tm[a+d]=1;\n\t\t\tif(m[b+c]==0)sol++;\n\t\t\tm[b+c]=1;\n\t\t\tif(m[b+d]==0)sol++;\n\t\t\tm[b+d]=1;\n\t\t\tif(m[c+a]==0)sol++;\n\t\t\tm[c+a]=1;\n\t\t\tif(m[d+a]==0)sol++;\n\t\t\tm[d+a]=1;\n\t\t\tif(m[c+b]==0)sol++;\n\t\t\tm[c+b]=1;\n\t\t\tif(m[d+b]==0)sol++;\n\t\t\tm[d+b]=1; \n\t\t}\n\t\tprintf(\"%lld\\n\",sol);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3556, "score_of_the_acc": -1.0516, "final_rank": 19 }, { "submission_id": "aoj_1142_10733249", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <cstring>\n#include <string>\n#include <algorithm>\n#include <tr1/unordered_set>\n#include <set>\nusing namespace std;\nusing namespace tr1;\n#define fromto(from,to,i) for(int i=(from);i<=(to);++i)\nconst int MAXN = 108;\n\nint main()\n{\n\tint case_cnt;\n\tscanf(\"%d\",&case_cnt);\n\twhile(case_cnt--) {\n\t\tchar str[MAXN];\n\t\tscanf(\"%s\",str);\n\t\tint N = strlen(str);\n\t\tunordered_set<string> tset;\n\t\tfromto(1,N-1,i) { //[0,i)[i,N)\n\t\t\tfromto(0,1,t1) fromto(0,1,t2) fromto(0,1,t3) {\n\t\t\t\tchar str2[MAXN];\n\t\t\t\tstrcpy(str2,str);\n\t\t\t\tif(t1) {\n\t\t\t\t\treverse(str2,str2+i);\n\t\t\t\t}\n\t\t\t\tif(t2) {\n\t\t\t\t\treverse(str2+i,str2+N);\n\t\t\t\t}\n\t\t\t\tif(t3) {\n\t\t\t\t\tchar tstr[MAXN];\n\t\t\t\t\tstrcpy(tstr,str2);\n\t\t\t\t\tcopy(str2+i,str2+N,tstr);\n\t\t\t\t\tcopy(str2,str2+i,tstr+N-i);\n\t\t\t\t\tstrcpy(str2,tstr);\n\t\t\t\t}\n\t\t\t\ttset.insert(string(str2));\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\",tset.size());\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3388, "score_of_the_acc": -0.0202, "final_rank": 3 }, { "submission_id": "aoj_1142_10733241", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <cstring>\n#include <string>\n#include <algorithm>\n#include <set>\nusing namespace std;\n#define fromto(from,to,i) for(int i=(from);i<=(to);++i)\nconst int MAXN = 108;\n\nint main()\n{\n\tint case_cnt;\n\tscanf(\"%d\",&case_cnt);\n\twhile(case_cnt--) {\n\t\tchar str[MAXN];\n\t\tscanf(\"%s\",str);\n\t\tint N = strlen(str);\n\t\tset<string> tset;\n\t\tfromto(1,N-1,i) { //[0,i)[i,N)\n\t\t\tfromto(0,1,t1) fromto(0,1,t2) fromto(0,1,t3) {\n\t\t\t\tchar str2[MAXN];\n\t\t\t\tstrcpy(str2,str);\n\t\t\t\tif(t1) {\n\t\t\t\t\treverse(str2,str2+i);\n\t\t\t\t}\n\t\t\t\tif(t2) {\n\t\t\t\t\treverse(str2+i,str2+N);\n\t\t\t\t}\n\t\t\t\tif(t3) {\n\t\t\t\t\tchar tstr[MAXN];\n\t\t\t\t\tstrcpy(tstr,str2);\n\t\t\t\t\tcopy(str2+i,str2+N,tstr);\n\t\t\t\t\tcopy(str2,str2+i,tstr+N-i);\n\t\t\t\t\tstrcpy(str2,tstr);\n\t\t\t\t}\n\t\t\t\ttset.insert(string(str2));\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\",tset.size());\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3468, "score_of_the_acc": -0.0352, "final_rank": 8 }, { "submission_id": "aoj_1142_10733239", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <cstring>\n#include <string>\n#include <algorithm>\n#include <set>\nusing namespace std;\n#define fromto(from,to,i) for(int i=(from);i<=(to);++i)\nconst int MAXN = 108;\nint main()\n{\n\tint case_cnt;\n\tscanf(\"%d\",&case_cnt);\n\twhile(case_cnt--) {\n\t\tchar str[MAXN];\n\t\tscanf(\"%s\",str+1);\n\t\tint N = strlen(str+1);\n\t\tset<string> tset;\n\t\tfromto(1,N-1,i) { //[1,i][i+1,N]\n\t\t\tfromto(0,1,t1) fromto(0,1,t2) fromto(0,1,t3) {\n\t\t\t\tstring newstr(str+1); //[0,i-1][i,N-1]\n\t\t\t\tif(t1) {\n\t\t\t\t\treverse(newstr.begin(),newstr.begin()+i);\n\t\t\t\t}\n\t\t\t\tif(t2) {\n\t\t\t\t\treverse(newstr.begin()+i,newstr.begin()+N);\n\t\t\t\t}\n\t\t\t\tif(t3) {\n\t\t\t\t\tstring tstr=newstr;\n\t\t\t\t\tcopy(newstr.begin()+i,newstr.begin()+N,tstr.begin());\n\t\t\t\t\tcopy(newstr.begin(),newstr.begin()+i,tstr.begin()+N-i);\n\t\t\t\t\tnewstr = tstr;\n\t\t\t\t}\n\t\t\t\ttset.insert(newstr);\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\",tset.size());\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3552, "score_of_the_acc": -0.0509, "final_rank": 10 }, { "submission_id": "aoj_1142_10733235", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <algorithm>\n#include <map>\n#include <cstring>\n#include <string>\nusing namespace std;\nint cases,n,tot;\nchar s[1010];\nmap<string,int> hashh;\nstring temp;\nint main()\n{\n\tcin >> cases;\n\twhile (cases--)\n\t{\n\t\tscanf(\"%s\",s+1);\n\t\tint n = strlen(s+1);\n\t\ttot++;int ans = 0;\n\t\t//cout << n << endl;\n\t\tfor (int i = 1;i < n;i++)\n\t\t{\n\t\t\ttemp = \"\";\n\t\t\tfor (int j = 1;j <= i;j++) temp+=s[j];\n\t\t\tfor (int j = i + 1;j <= n;j++) temp+=s[j];\n\t\t\tif (hashh[temp] != tot) ans++,hashh[temp] = tot;\n\n\t\t\ttemp = \"\";\n\t\t\tfor (int j = i;j >= 1;j--) temp+=s[j];\n\t\t\tfor (int j = i + 1;j <= n;j++) temp+=s[j];\n\t\t\tif (hashh[temp] != tot) ans++,hashh[temp] = tot;\n\n\t\t\ttemp = \"\";\n\t\t\tfor (int j = 1;j <= i;j++) temp+=s[j];\n\t\t\tfor (int j = n;j >= i + 1;j--) temp+=s[j];\n\t\t\tif (hashh[temp] != tot) ans++,hashh[temp] = tot;\n\n\t\t\ttemp = \"\";\n\t\t\tfor (int j = i;j >= 1;j--) temp+=s[j];\n\t\t\tfor (int j = n;j >= i + 1;j--) temp+=s[j];\n\t\t\tif (hashh[temp] != tot) ans++,hashh[temp] = tot;\n\n\n\t\t\ttemp = \"\";\n\t\t\tfor (int j = i + 1;j <= n;j++) temp+=s[j];\n\t\t\tfor (int j = 1;j <= i;j++) temp+=s[j];\n\t\t\tif (hashh[temp] != tot) ans++,hashh[temp] = tot;\n\n\t\t\ttemp = \"\";\n\t\t\tfor (int j = i + 1;j <= n;j++) temp+=s[j];\n\t\t\tfor (int j = i;j >= 1;j--) temp+=s[j];\n\t\t\tif (hashh[temp] != tot) ans++,hashh[temp] = tot;\n\n\t\t\ttemp = \"\";\n\t\t\tfor (int j = n;j >= i + 1;j--) temp+=s[j];\n\t\t\tfor (int j = 1;j <= i;j++) temp+=s[j];\n\t\t\tif (hashh[temp] != tot) ans++,hashh[temp] = tot;\n\n\t\t\ttemp = \"\";\n\t\t\tfor (int j = n;j >= i + 1;j--) temp+=s[j];\n\t\t\tfor (int j = i;j >= 1;j--) temp+=s[j];\n\t\t\tif (hashh[temp] != tot) ans++,hashh[temp] = tot;\n\n\t\t}\n\t\tcout << ans << endl;\n\t}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 8628, "score_of_the_acc": -1.3333, "final_rank": 20 }, { "submission_id": "aoj_1142_10733229", "code_snippet": "#include<cstdio>\n#include<string>\n#include<map>\n#include<iostream>\nusing namespace std;\nstring s,pre[4];\nint main()\n{\n int t;\n scanf(\"%d\",&t);\n while(t--)\n {\n cin>>s;\n map<string,int>mp;\n int l = s.size(),ans = 0;\n for(int i=1;i<l;i++)\n {\n pre[0] = s.substr(0,i);\n pre[1] = pre[0];\n for(int j=0;j<i;j++)\n pre[1].at(j) = s.at(i-j-1);\n pre[2] = s.substr(i,l-i);\n pre[3] = pre[2];\n for(int j=i;j<l;j++)\n pre[3].at(j-i) = s.at(l-j+i-1);\n for(int j=0;j<=1;j++)\n for(int k=2;k<=3;k++)\n {\n mp[pre[j]+pre[k]]++;\n mp[pre[k]+pre[j]]++;\n }\n }\n cout<<mp.size()<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3608, "score_of_the_acc": -0.0613, "final_rank": 12 }, { "submission_id": "aoj_1142_10733227", "code_snippet": "//#pragma comment(linker, \"/STACK:1024000000,1024000000\")\n#include<iostream>\n#include<cstdio>\n#include<string>\n#include<cstring>\n#include<cstdlib>\n#include<algorithm>\n#include<map>\n#include<cmath>\n#include<queue>\n#include<stack>\n#include<ctime>\n#include<vector>\n#include<set>\n#include<cfloat>\n\nusing namespace std;\n\nconst int maxn=1500;\nconst int INF=999999999;\nconst float eps = 0.00000001;\nconst int mod=100000007;\nconst int prime=100003;\nconst int VM=60;\nconst int EM=10020;\n\ntypedef pair<int,int> P;\n//int dir[4][2]={{-1,0},{1,0},{0,-1},{0,1}};\n//int dir[4][2]={{0,1},{0,-1},{-1,0},{1,0}};\n//int dir[4][2]={{1,0},{0,-1},{-1,0},{0,1}};\n//int dir[8][2]={{-2,-1},{-1,-2},{1,-2},{2,-1},{-2,1},{-1,2},{1,2},{2,1}};\n//int dir[8][2]={{-1,-2},{-2,-1},{-2,1},{-1,2},{1,-2},{2,-1},{2,1},{1,2}};\n//int dir[8][2]={{-1,-2},{1,-2},{-2,-1},{2,-1},{-2,1},{2,1},{-1,2},{1,2}};\n//int dir[8][2]={{-1,-2},{1,-2},{-2,-1},{2,-1},{-2,1},{2,1},{-1,2},{1,2}};\nint dir[6][3]={{-1,0,0},{1,0,0},{0,-1,0},{0,1,0},{0,0,1},{0,0,-1}};\n\nchar str[120];\nchar s1[120],s2[120];\nchar t1[120],t2[120];\nchar res[120];\n\nvoid splitStr(char s[],int x,int len){\n int c1=0,c2=0;\n for(int i=0;i<x;i++){\n s1[c1++]=s[i];\n }\n s1[c1]='\\0';\n for(int i=x;i<len;i++){\n s2[c2++]=s[i];\n }\n s2[c2]='\\0';\n}\n\nvoid unionStr(char a[],char b[],char ans[]){\n int c1=strlen(a);\n int c2=strlen(b);\n int c3=0;\n for(int i=0;i<c1;i++){\n ans[c3++]=a[i];\n }\n for(int i=0;i<c2;i++){\n ans[c3++]=b[i];\n }\n ans[c3]='\\0';\n}\n\nvoid reverseStr(char tmp[]){\n int len=strlen(tmp);\n char c;\n for(int i=len-1;i>=len/2;i--){\n c=tmp[i];\n tmp[i]=tmp[len-1-i];\n tmp[len-1-i]=c;\n }\n}\n\nint main(){\n\n //freopen(\"input.txt\",\"r\",stdin);\n\n //freopen(\"out.txt\",\"w\",stdout);\n\n int t;\n scanf(\"%d\",&t);\n while(t--){\n scanf(\"%s\",str);\n int len=strlen(str);\n map<string,int > mp;\n map<string,int>::iterator it;\n for(int i=1;i<len;i++){\n splitStr(str,i,len);\n\n unionStr(s1,s2,res);\n mp[res]=1;\n unionStr(s2,s1,res);\n mp[res]=1;\n\n strcpy(t1,s1);\n strcpy(t2,s2);\n reverseStr(t1);\n reverseStr(t2);\n\n unionStr(s1,t2,res);\n mp[res]=1;\n unionStr(t2,s1,res);\n mp[res]=1;\n unionStr(t1,s2,res);\n mp[res]=1;\n unionStr(t1,t2,res);\n mp[res]=1;\n unionStr(s2,t1,res);\n mp[res]=1;\n unionStr(t2,t1,res);\n mp[res]=1;\n }\n\n //strcpy(res,\"sss\");\n\n printf(\"%d\\n\",mp.size());\n }\n\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3672, "score_of_the_acc": -0.0733, "final_rank": 14 }, { "submission_id": "aoj_1142_10733224", "code_snippet": "#include<cstdio>\n#include<cstring>\n#include<string>\n#include<iostream>\n#include<algorithm>\n#include<set>\nusing namespace std;\n\nconst int mod = 10007;\nconst int maxn = 200;\nbool has1[mod],has2[mod];\nset<string> has;\n\n/*\nint h1(string s){\n\tint cnt=0;\n\tfor(int i=0;i<s.size();++i){\n\t\tcnt=(31*cnt+s[i]-'a')%mod;\n\t}\n\treturn cnt;\n}\n\nint h2(string s){\n\tint cnt=0;\n\tfor(int i=0;i<s.size();++i){\n\t\tcnt=(37*cnt+s[i]-'a')%mod;\n\t}\n\treturn cnt;\n}\n*/\n\nint deal(string s){\n\tif(has.find(s)!=has.end()) return 0;\n\thas.insert(s);\n\treturn 1;\n}\n\ninline string rev(string s){\n\treverse(s.begin(),s.end());\n\treturn s;\n}\n\nint solve(char* s){\n\thas.clear();\n\tint ans=1;\n\tstring s1,s2(s);\n\ts1.clear();\n\thas.insert(s2);\n\tfor(int i=0;i<strlen(s)-1;++i){\n\t\ts1.push_back(s[i]);\n\t\ts2.erase(s2.begin());\n//\t\tcout<<s1<<\" \"<<s2<<endl;\n\n\t\tans+=deal(rev(s1)+s2);\n\t\tans+=deal(s1+rev(s2));\n\t\tans+=deal(rev(s1)+rev(s2));\n\n\t\tans+=deal(s2+s1);\n\t\tans+=deal(rev(s2)+s1);\n\t\tans+=deal(s2+rev(s1));\n\t\tans+=deal(rev(s2)+rev(s1));\n\t}\n\treturn ans;\n}\n\nint main()\n{\n\t//freopen(\"test.txt\",\"r\",stdin);\n\tint m;\n\tchar s[maxn];\n\tscanf(\"%d\",&m);\n\tfor(int i=0;i<m;++i){\n\t\tscanf(\"%s\",s);\n\t\tprintf(\"%d\\n\",solve(s));\t\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3556, "score_of_the_acc": -0.0516, "final_rank": 11 }, { "submission_id": "aoj_1142_10733222", "code_snippet": "#include<cstdio>\n#include<cstring>\n#include<string>\n#include<set>\n#include<iostream>\n\nusing namespace std;\n\nconst int maxn = 80;\n\nset<string> has;\n\nint deal(string s){\n\tif(has.find(s)!=has.end()) return 0;\n\thas.insert(s);\n\treturn 1;\n}\n\nstring rev(string s){\n\tfor(int i=0;i<s.size()/2;++i) swap(s[i],s[s.size()-i-1]);\n\treturn s;\n}\n\nint solve(char* ss){\n\tint ans=1;\n\tstring s(ss);\n\thas.clear();\n\tstring s1,s2(s);\n\ts1.clear();\n\thas.insert(s);\n\tfor(int i=0;i<s.size();++i){\n\t\ts1.push_back(s[i]);\n\t\ts2.erase(s2.begin());\n\t\tans+=deal(rev(s1)+s2);\n\t\tans+=deal(s1+rev(s2));\n\t\tans+=deal(rev(s1)+rev(s2));\n\n\t\tans+=deal(s2+s1);\n\t\tans+=deal(rev(s2)+s1);\n\t\tans+=deal(s2+rev(s1));\n\t\tans+=deal(rev(s2)+rev(s1));\n\t}\n\treturn ans;\n}\n\nint main()\n{\n//\tfreopen(\"test.txt\",\"r\",stdin);\n\tint m;\n\tchar s[maxn];\n\tscanf(\"%d\",&m);\n\tfor(int i=0;i<m;++i){\n\t\tscanf(\"%s\",s);\n\t\tprintf(\"%d\\n\",solve(s));\t\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3648, "score_of_the_acc": -0.0688, "final_rank": 13 }, { "submission_id": "aoj_1142_10733221", "code_snippet": "#include<cstdio>\n#include<cstring>\n#include<algorithm>\n#include<string>\n#include<set>\n#include<iostream>\nusing namespace std;\n\nstring save;\nint len;\nset<string> vis;\nint cnt;\n\nvoid insert(string& s)\n{\n if(vis.find(s) == vis.end())\n {\n // cout << s << endl;\n vis.insert(s);\n cnt++;\n }\n}\nvoid solve()\n{\n vis.clear();\n cnt = 0;\n for(int i = 1;i <= len-1;++i)\n {\n string a = save.substr(0,i);\n string b = save.substr(i,len-i);\n // cout << a << \" \" << b << endl;\n string ra = a; reverse(ra.begin(),ra.end());\n string rb = b; reverse(rb.begin(),rb.end());\n for(int j = 0;j < 2;++j)\n {\n string t1 = a + b , t2 = ra + b;\n string t3 = a + rb , t4 = ra + rb;\n // cout << t1 << \" \" << t2 << \" \" << t3 << \" \" << t4 << endl;\n insert(t1);\n insert(t2);\n insert(t3);\n insert(t4);\n if(j == 0)\n {\n swap(a,b);\n swap(ra,rb);\n }\n }\n }\n}\n\n\n\nint main()\n{\n // freopen(\"./test.txt\",\"r\",stdin);\n int kase;\n cin >> kase;\n while(kase--)\n {\n cin >> save;\n len = save.length();\n solve();\n cout << cnt << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3436, "score_of_the_acc": -0.0292, "final_rank": 7 }, { "submission_id": "aoj_1142_10733217", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <algorithm>\n#include <vector>\n#include <string>\n#include <map>\nusing namespace std;\n\nchar save[80];\nchar a[80];\nchar b[80];\ntypedef pair<string,int> psi;\n\nint main()\n{\n int t;\n scanf(\"%d\",&t);\n while (t--)\n {\n scanf(\"%s\",save);\n int len = strlen(save);\n int i;\n map<string,int> m;\n int cnt = 0;\n for (i = 1; i < len; i++)\n {\n sprintf(a,save);\n sprintf(b,save+i);\n a[i] = 0;\n\n string tmp = string(a) + string(b);\n if (m.find(tmp) == m.end())\n {\n cnt++;\n m.insert(psi(string(tmp),cnt));\n }\n tmp = string (b) + string (a);\n if (m.find(tmp) == m.end())\n {\n cnt++;\n m.insert (psi(string(tmp),cnt));\n }\n\n reverse (a,a+i);\n tmp = string(a) + string(b);\n if (m.find(tmp) == m.end())\n {\n cnt++;\n m.insert(psi(string(tmp),cnt));\n }\n tmp = string (b) + string (a);\n if (m.find(tmp) == m.end())\n {\n cnt++;\n m.insert (psi(string(tmp),cnt));\n }\n\n reverse (b,b+len-i);\n tmp = string(a) + string(b);\n if (m.find(tmp) == m.end())\n {\n cnt++;\n m.insert(psi(string(tmp),cnt));\n }\n tmp = string (b) + string (a);\n if (m.find(tmp) == m.end())\n {\n cnt++;\n m.insert (psi(string(tmp),cnt));\n }\n\n reverse (a,a+i);\n tmp = string(a) + string(b);\n if (m.find(tmp) == m.end())\n {\n cnt++;\n m.insert(psi(string(tmp),cnt));\n }\n tmp = string (b) + string (a);\n if (m.find(tmp) == m.end())\n {\n cnt++;\n m.insert (psi(string(tmp),cnt));\n }\n\n }\n printf(\"%d\\n\",cnt);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3676, "score_of_the_acc": -0.074, "final_rank": 15 }, { "submission_id": "aoj_1142_10733214", "code_snippet": "#include<stdio.h>\n#include<algorithm>\n#include<string.h>\n#include<map>\n#include<string>\n#include<iostream>\nusing namespace std ;\n\nmap<string,int> mp ;\nchar s[111] ;\nchar s1[111] , s2[111] , f[1111] ;\n\nvoid reverse ( char *s , int len ) {\n int i ;\n for ( i = 0 ; i < (len+1) / 2 ; i ++ )\n swap ( s[i] , s[len-i-1] ) ;\n}\n\nvoid jion ( char *s , char *s1 , char *s2 , int l1 , int l2 ) {\n int len = 0 ;\n int i ;\n for ( i = 0 ; i < l1 ; i ++ ) s[len++] = s1[i] ;\n for ( i = 0 ; i < l2 ; i ++ ) s[len++] = s2[i] ;\n s[len] = 0 ;\n}\n\nint main () {\n int t , i ;\n scanf ( \"%d\" , &t ) ;\n while ( t -- ) {\n scanf ( \"%s\" , s ) ;\n int len = strlen ( s ) ;\n mp.clear () ;\n int ans = 0 ;\n for ( i = 0 ; i < len - 1 ; i ++ ) {\n s1[i] = s[i] , s1[i+1] = 0 ;\n strcpy ( s2 , s + i + 1 ) ;\n int l1 = i + 1 , l2 = len - l1 ;\n jion ( f , s1 , s2 , l1 , l2 ) ;\n if ( !mp.count ( f ) ) ans ++ , mp[f] = 1 ;\n jion ( f , s2 , s1 , l2 , l1 ) ;\n if ( !mp.count ( f ) ) ans ++ , mp[f] = 1 ;\n reverse ( s2 , l2 ) ;\n jion ( f , s1 , s2 , l1 , l2 ) ;\n if ( !mp.count ( f ) ) ans ++ , mp[f] = 1 ;\n jion ( f , s2 , s1 , l2 , l1 ) ;\n if ( !mp.count ( f ) ) ans ++ , mp[f] = 1 ;\n reverse ( s1 , l1 ) ;\n jion ( f , s1 , s2 , l1 , l2 ) ;\n if ( !mp.count ( f ) ) ans ++ , mp[f] = 1 ;\n jion ( f , s2 , s1 , l2 , l1 ) ;\n if ( !mp.count ( f ) ) ans ++ , mp[f] = 1 ;\n reverse ( s2 , l2 ) ;\n jion ( f , s1 , s2 , l1 , l2 ) ;\n if ( !mp.count ( f ) ) ans ++ , mp[f] = 1 ;\n jion ( f , s2 , s1 , l2 , l1 ) ;\n if ( !mp.count ( f ) ) ans ++ , mp[f] = 1 ;\n reverse ( s1 , l1 ) ;\n }\n printf ( \"%d\\n\" , ans ) ;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3424, "score_of_the_acc": -0.0269, "final_rank": 6 }, { "submission_id": "aoj_1142_10733211", "code_snippet": "#include<stdio.h>\n#include<algorithm>\n#include<string.h>\n#include<map>\n#include<string>\n#include<iostream>\nusing namespace std ;\n\nmap<string,int> mp ;\nchar s[111] ;\nchar s1[111] , s2[111] ;\n\nvoid reverse ( char *s , int len ) {\n int i ;\n for ( i = 0 ; i < (len+1) / 2 ; i ++ )\n swap ( s[i] , s[len-i-1] ) ;\n}\n\nint main () {\n int t , i ;\n scanf ( \"%d\" , &t ) ;\n while ( t -- ) {\n scanf ( \"%s\" , s ) ;\n int len = strlen ( s ) ;\n mp.clear () ;\n int ans = 0 ;\n string t = \"\" ;\n for ( i = 0 ; i < len - 1 ; i ++ ) {\n s1[i] = s[i] , s1[i+1] = 0 ;\n strcpy ( s2 , s + i + 1 ) ;\n int l1 = i + 1 , l2 = len - l1 ;\n t = \"\" ;\n t = t + s1 + s2 ;\n // cout << t << endl ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n t = \"\" ;\n t = t + s2 + s1 ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n reverse ( s2 , l2 ) ;\n t = \"\" ;\n t = t + s1 + s2 ;\n // cout << t << endl ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n t = \"\" ;\n t = t + s2 + s1 ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n reverse ( s1 , l1 ) ;\n t = \"\" ;\n t = t + s1 + s2 ;\n // cout << t << endl ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n t = \"\" ;\n t = t + s2 + s1 ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n reverse ( s2 , l2 ) ;\n t = \"\" ;\n t = t + s1 + s2 ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n t = \"\" ;\n t = t + s2 + s1 ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n reverse ( s1 , l1 ) ;\n }\n printf ( \"%d\\n\" , ans ) ;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3696, "score_of_the_acc": -0.0778, "final_rank": 17 }, { "submission_id": "aoj_1142_10733203", "code_snippet": "#include<stdio.h>\n#include<algorithm>\n#include<string.h>\n#include<map>\n#include<string>\n#include<iostream>\nusing namespace std ;\n\nmap<string,int> mp ;\nchar s[111] ;\nchar s1[111] , s2[111] ;\n\nint main () {\n int t , i ;\n scanf ( \"%d\" , &t ) ;\n while ( t -- ) {\n scanf ( \"%s\" , s ) ;\n int len = strlen ( s ) ;\n mp.clear () ;\n int ans = 0 ;\n string t = \"\" ;\n for ( i = 0 ; i < len - 1 ; i ++ ) {\n s1[i] = s[i] , s1[i+1] = 0 ;\n strcpy ( s2 , s + i + 1 ) ;\n int l1 = i + 1 , l2 = len - l1 ;\n t = \"\" ;\n t = t + s1 + s2 ;\n // cout << t << endl ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n t = \"\" ;\n t = t + s2 + s1 ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n reverse ( s2 , s2 + l2 ) ;\n t = \"\" ;\n t = t + s1 + s2 ;\n // cout << t << endl ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n t = \"\" ;\n t = t + s2 + s1 ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n reverse ( s1 , s1 + l1 ) ;\n t = \"\" ;\n t = t + s1 + s2 ;\n // cout << t << endl ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n t = \"\" ;\n t = t + s2 + s1 ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n reverse ( s2 , s2 + l2 ) ;\n t = \"\" ;\n t = t + s1 + s2 ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n t = \"\" ;\n t = t + s2 + s1 ;\n if ( !mp.count ( t ) ) ans ++ , mp[t] = 1 ;\n reverse ( s1 , s1 + l1 ) ;\n }\n printf ( \"%d\\n\" , ans ) ;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3680, "score_of_the_acc": -0.0748, "final_rank": 16 }, { "submission_id": "aoj_1142_10733201", "code_snippet": "#include<iostream>\n#include<string>\n#include<set>\n#include<functional>\nstd::set<size_t> set;\nint main() {\n int testCount;\n std::cin>>testCount;\n while(testCount--) {\n std::string s;\n std::cin>>s;\n set.clear();\n std::hash<std::string> hash_fn;\n for(int i=1; i<s.size(); ++i) {\n std::string a=s.substr(0,i);\n std::string b=s.substr(i,s.size()-i);\n std::string ra,rb;\n for(int j=0; j<a.size(); ++j) {\n ra=a[j]+ra;\n }\n for(int j=0; j<b.size(); ++j) {\n rb=b[j]+rb;\n }\n set.insert(hash_fn(a+b));\n set.insert(hash_fn(b+a));\n set.insert(hash_fn(ra+b));\n set.insert(hash_fn(b+ra));\n set.insert(hash_fn(a+rb));\n set.insert(hash_fn(rb+a));\n set.insert(hash_fn(ra+rb));\n set.insert(hash_fn(rb+ra));\n }\n std::cout<<set.size()<<std::endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3320, "score_of_the_acc": -0.0075, "final_rank": 1 }, { "submission_id": "aoj_1142_10733197", "code_snippet": "#include<iostream>\n#include<string>\n#include<set>\nstd::set<std::string> set;\nint main() {\n int testCount;\n std::cin>>testCount;\n while(testCount--) {\n std::string s;\n std::cin>>s;\n set.clear();\n for(int i=1; i<s.size(); ++i) {\n std::string a=s.substr(0,i);\n std::string b=s.substr(i,s.size()-i);\n std::string ra,rb;\n for(int j=0; j<a.size(); ++j) {\n ra=a[j]+ra;\n }\n for(int j=0; j<b.size(); ++j) {\n rb=b[j]+rb;\n }\n set.insert(a+b);\n set.insert(b+a);\n set.insert(ra+b);\n set.insert(b+ra);\n set.insert(a+rb);\n set.insert(rb+a);\n set.insert(ra+rb);\n set.insert(rb+ra);\n }\n std::cout<<set.size()<<std::endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3392, "score_of_the_acc": -0.0209, "final_rank": 4 } ]
aoj_1131_cpp
Problem C: Unit Fraction Partition A fraction whose numerator is 1 and whose denominator is a positive integer is called a unit fraction. A representation of a positive rational number p / q as the sum of finitely many unit fractions is called a partition of p / q into unit fractions. For example, 1/2 + 1/6 is a partition of 2/3 into unit fractions. The difference in the order of addition is disregarded. For example, we do not distinguish 1/6 + 1/2 from 1/2 + 1/6. For given four positive integers p , q , a , and n , count the number of partitions of p / q into unit fractions satisfying the following two conditions. The partition is the sum of at most n many unit fractions. The product of the denominators of the unit fractions in the partition is less than or equal to a . For example, if ( p , q , a , n ) = (2,3,120,3), you should report 4 since enumerates all of the valid partitions. Input The input is a sequence of at most 1000 data sets followed by a terminator. A data set is a line containing four positive integers p , q , a , and n satisfying p , q <= 800, a <= 12000 and n <= 7. The integers are separated by a space. The terminator is composed of just one line which contains four zeros separated by a space. It is not a part of the input data but a mark for the end of the input. Output The output should be composed of lines each of which contains a single integer. No other characters should appear in the output. The output integer corresponding to a data set p , q , a , n should be the number of all partitions of p / q into at most n many unit fractions such that the product of the denominators of the unit fractions is less than or equal to a . Sample Input 2 3 120 3 2 3 300 3 2 3 299 3 2 3 12 3 2 3 12000 7 54 795 12000 7 2 3 300 1 2 1 200 5 2 4 54 2 0 0 0 0 Output for the Sample Input 4 7 6 2 42 1 0 9 3
[ { "submission_id": "aoj_1131_10848172", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint n, a;\n\nint gcd(int a, int b) {\n\tif (a%b == 0) {\n\t\treturn b;\n\t} else {\n\t\treturn gcd(b, a % b);\n\t}\n}\n\nint dfs(int p, int q, int m, int prod, int c) {\n\t// if (prod * q > a) return 0;\n\tif (p * m > (n - c) * q) return 0;\n\tint ret = 0;\n\tfor (int i = m; i * prod <= a; i++) {\n\t\tint np = i * p - q, nq = i * q;\n\t\tif (np == 0) {\n\t\t\tret++;\n\t\t\tcontinue;\n\t\t} else if (np < 0) {\n\t\t\tcontinue;\n\t\t}\n\t\tif(c < n) {\n\t\t\tint d = gcd(np, nq);\n\t\t\tnp /= d;\n\t\t\tnq /= d;\n\t\t\tret += dfs(np, nq, i, prod * i, c + 1);\n\t\t}\n\t}\n\treturn ret;\n}\n\nint main() {\n\twhile (true) {\n\t\tint p, q;\n\t\tcin >> p >> q;\n\t\tcin >> a >> n;\n\t\tif (p == 0) break;\n\t\tcout << dfs(p, q, 1, 1, 0) << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 980, "memory_kb": 3132, "score_of_the_acc": -1.0928, "final_rank": 18 }, { "submission_id": "aoj_1131_10554391", "code_snippet": "#include <iostream>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\ntypedef long long int ll;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000001\nusing namespace std;\n\nint ans,count_MAX;\nint P,Q,Limit,common;\n\nvoid recursive(int bunshi,int bunbo,int pre_add_bunbo,int bunbo_sum,int count){\n\n\tif(Q*bunshi == P*bunbo){\n\t\tans++;\n\t\treturn;\n\t}\n\tif(count == count_MAX)return;\n\n\tif(Q*bunshi > P*bunbo)return;\n\n\tint next_bunshi,next_bunbo;\n\n\tfor(int i = pre_add_bunbo; bunbo_sum*i <= Limit; i++){\n\n\t\tnext_bunshi = bunshi*i+bunbo;\n\t\tnext_bunbo = bunbo*i;\n\n\t\trecursive(next_bunshi,next_bunbo,i,bunbo_sum*i,count+1);\n\t}\n}\n\nint main(){\n\n\twhile(true){\n cin >> P >> Q >> Limit >> count_MAX;\n\t\tif(P == 0 && Q == 0 && Limit == 0 && count_MAX == 0)break;\n\n\t\tans = 0;\n\n\t\trecursive(0,1,0,1,0);\n\n\t\tcout << ans << endl;\n\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3368, "score_of_the_acc": -0.2807, "final_rank": 9 }, { "submission_id": "aoj_1131_9634400", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> pi;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define sz(A) (ll)(A.size())\nll f(ll P,ll Q,ll A,ll N,ll c){\n if(P==0)return 1;\n if(c>A)return 0;\n ll ans=0;\n while(1){\n ans+=f(P,Q,A,N,c+1);\n if(A<c||N==0||c*P<Q)break;\n A/=c;N--;\n P=c*P-Q;Q*=c;\n }\n return ans;\n}\nint main(){\n while(1){\n ll P,Q,A,N;cin>>P>>Q>>A>>N;\n if(!P)return 0;\n ll g=__gcd(P,Q);\n P/=g;Q/=g;\n cout<<f(P,Q,A,N,1)<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 450, "memory_kb": 4196, "score_of_the_acc": -1.2937, "final_rank": 19 }, { "submission_id": "aoj_1131_9373257", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint f(int p, int q, int a, int n, int prod, int low) {\n if (p == 0) {\n return 1;\n }\n if (p < 0 || n == 0) {\n return 0;\n }\n int ans = 0;\n for (int i = low; i * prod <= a; i++) {\n //p/q - 1/i -> (p * i - q) / q * i\n ans += f(p * i - q, q * i, a, n - 1, prod * i, i);\n }\n return ans;\n}\nint main() {\n while (1) {\n int p, q, a, n;\n cin >> p >> q >> a >> n;\n if (p == 0 && q == 0 && a == 0 && n == 0) {\n break;\n }\n cout << f(p, q, a, n ,1, 1) << '\\n';\n }\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3132, "score_of_the_acc": -0.1153, "final_rank": 3 }, { "submission_id": "aoj_1131_9351373", "code_snippet": "/// 生成AI不使用 / Not using generative AI\n\n// #pragma GCC target (\"avx\")\n// #pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#ifdef MARC_LOCAL\n#define _GLIBCXX_DEBUG\n#endif\n\n#ifdef ATCODER\n#include <atcoder/all>\nusing namespace atcoder;\n#endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n//#define int long long\nusing ll = long long; using vll = vector<ll>; using vvll = vector<vll>; using vvvll = vector<vvll>; using vvvvll = vector<vvvll>;\nusing vi = vector<int>; using vvi = vector<vi>; using vvvi = vector<vvi>; using vvvvi = vector<vvvi>;\nusing ld = long double; using vld = vector<ld>; using vvld = vector<vld>; using vd = vector<double>;\nusing vc = vector<char>; using vvc = vector<vc>; using vs = vector<string>;\nusing vb = vector<bool>; using vvb = vector<vb>; using vvvb = vector<vvb>;\nusing pii = pair<int, int>; using pcc = pair<char, char>; using pll = pair<ll, ll>; using pli = pair<ll, int>; using pdd = pair<double, double>; using pldld = pair<ld,ld>;\nusing vpii = vector<pii>; using vvpii = vector<vpii>; using vpll = vector<pll>; using vvpll = vector<vpll>; using vpldld = vector<pldld>;\nusing ui = unsigned int; using ull = unsigned long long;\nusing i128 = __int128; using f128 = __float128;\ntemplate<class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define vv(type, name, h, ...) vector<vector<type> > name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) vector<vector<vector<type> > > name(h, vector<vector<type> >(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) vector<vector<vector<vector<type> > > > name(a, vector<vector<vector<type> > >(b, vector<vector<type> >(c, vector<type>(__VA_ARGS__))))\n\n#define overload4(a,b,c,d,name,...) name\n#define rep1(n) for(ll i = 0; i < (ll)n; i++)\n#define rep2(i,n) for(ll i = 0; i < (ll)n; i++)\n#define rep3(i,a,b) for (ll i = a; i < (ll)b; i++)\n#define rep4(i,a,b,c) for (ll i = a; i < (ll)b; i += (ll)c)\n#define rep(...) overload4(__VA_ARGS__,rep4,rep3,rep2,rep1)(__VA_ARGS__)\n#define repback1(n) for (ll i = (ll)n-1; i >= 0; i--)\n#define repback2(i,n) for (ll i = (ll)n-1; i >= 0; i--)\n#define repback3(i,a,b) for (ll i = (ll)b-1; i >= (ll)a; i--)\n#define repback4(i,a,b,c) for (ll i = (ll)b-1; i >= (ll)a; i -= (ll)c)\n#define repback(...) overload4(__VA_ARGS__,repback4,repback3,repback2,repback1)(__VA_ARGS__)\n#define all(x) (x).begin(), (x).end()\n#define include(y, x, H, W) (0 <= (y) && (y) < (H) && 0 <= (x) && (x) < (W))\n#define inrange(x, down, up) ((down) <= (x) && (x) <= (up))\n#define pb push_back\n#define eb emplace_back\n#define fir first\n#define sec second\n#define TIMER_START TIME_START = clock()\n#ifdef MARC_LOCAL\n// https://trap.jp/post/1224/\n#define debug1(x) cout << \"debug: \" << (#x) << \": \" << (x) << endl\n#define debug2(x, y) cout << \"debug: \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << endl\n#define debug3(x, y, z) cout << \"debug: \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << \", \" << (#z) << \": \" << (z) << endl\n#define debug4(x, y, z, w) cout << \"debug: \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << \", \" << (#z) << \": \" << (z) << \", \" << (#w) << \": \" << (w) << endl\n#define debug5(x, y, z, w, v) cout << \"debug: \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << \", \" << (#z) << \": \" << (z) << \", \" << (#w) << \": \" << (w) << \", \" << (#v) << \": \" << (v) << endl\n#define debug6(x, y, z, w, v, u) cout << \"debug: \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << \", \" << (#z) << \": \" << (z) << \", \" << (#w) << \": \" << (w) << \", \" << (#v) << \": \" << (v) << \", \" << (#u) << \": \" << (u) << endl\n#define overload6(a, b, c, d, e, f, g,...) g\n#define debug(...) overload6(__VA_ARGS__, debug6, debug5, debug4, debug3, debug2, debug1)(__VA_ARGS__)\n#define debuga cerr << \"a\" << endl\n#define debugnl cout << endl\n#define Case(i) cout << \"Case #\" << (i) << \": \"\n#define TIMECHECK cerr << 1000.0 * static_cast<double>(clock() - TIME_START) / CLOCKS_PER_SEC << \"ms\" << endl\n#define LOCAL 1\n#else\n#define debug1(x) void(0)\n#define debug2(x, y) void(0)\n#define debug3(x, y, z) void(0)\n#define debug4(x, y, z, w) void(0)\n#define debug5(x, y, z, w, v) void(0)\n#define debug6(x, y, z, w, v, u) void(0)\n#define debug(...) void(0)\n#define debuga void(0)\n#define debugnl void(0)\n#define Case(i) void(0)\n#define TIMECHECK void(0)\n#define LOCAL 0\n#endif\n\n//mt19937_64 rng(0);\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nclock_t TIME_START;\nconst long double pi = 3.141592653589793238462643383279L;\nconst long long INFL = 1000000000000000000ll;\nconst long long INFLMAX = numeric_limits< long long >::max(); // 9223372036854775807\nconst int INF = 1000000000;\nconst int INFMAX = numeric_limits< int >::max(); // 2147483647\nconst long double INFD = numeric_limits<ld>::infinity();\nconst long double EPS = 1e-10;\nconst int mod1 = 1000000007;\nconst int mod2 = 998244353;\nconst vi dx1 = {1,0,-1,0};\nconst vi dy1 = {0,1,0,-1};\nconst vi dx2 = {0, 1, 1, 1, 0, -1, -1, -1};\nconst vi dy2 = {1, 1, 0, -1, -1, -1, 0, 1};\nconstexpr char nl = '\\n';\nconstexpr char bl = ' ';\n\nstd::ostream &operator<<(std::ostream &dest, __int128_t value) { std::ostream::sentry s(dest); if (s) {__uint128_t tmp = value < 0 ? -value : value; char buffer[128]; char *d = std::end(buffer); do {--d;*d = \"0123456789\"[tmp % 10];tmp /= 10;} while (tmp != 0);if (value < 0) {--d;*d = '-';}int len = std::end(buffer) - d;if (dest.rdbuf()->sputn(d, len) != len) {dest.setstate(std::ios_base::badbit);}}return dest; }\n__int128 parse(string &s) { __int128 ret = 0; for (int i = 0; i < (int)s.length(); i++) if ('0' <= s[i] && s[i] <= '9') ret = 10 * ret + s[i] - '0'; return ret; } // for __int128 (https://kenkoooo.hatenablog.com/entry/2016/11/30/163533)\ntemplate<class T> ostream& operator << (ostream& os, vector<T>& vec) { os << \"[\"; for (int i = 0; i<(int)vec.size(); i++) { os << vec[i] << (i + 1 == (int)vec.size() ? \"\" : \", \"); } os << \"]\"; return os; } /// vector 出力\ntemplate<class T, class U> ostream& operator << (ostream& os, pair<T, U>& pair_var) { os << \"(\" << pair_var.first << \", \" << pair_var.second << \")\"; return os; } // pair 出力\ntemplate<class T, class U> ostream& operator << (ostream& os, map<T, U>& map_var) { os << \"{\"; for (auto itr = map_var.begin(); itr != map_var.end(); itr++) { os << \"(\" << itr->first << \", \" << itr->second << \")\"; itr++; if(itr != map_var.end()) os << \", \"; itr--; } os << \"}\"; return os; } // map出力\ntemplate<class T> ostream& operator << (ostream& os, set<T>& set_var) { os << \"{\"; for (auto itr = set_var.begin(); itr != set_var.end(); itr++) { os << *itr; ++itr; if(itr != set_var.end()) os << \", \"; itr--; } os << \"}\"; return os; } /// set 出力\n\nbool equals(long double a, long double b) { return fabsl(a - b) < EPS; }\ntemplate<class T> int sign(T a) { return equals(a, 0) ? 0 : a > 0 ? 1 : -1; }\nlong double radian_to_degree(long double r) { return (r * 180.0 / pi); }\nlong double degree_to_radian(long double d) { return (d * pi / 180.0); }\n\nint popcnt(unsigned long long a){ return __builtin_popcountll(a); } // ll は 64bit対応!\nint MSB1(unsigned long long x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); } // MSB(1), 0-indexed ( (0, 1, 2, 3, 4) -> (-1, 0, 1, 1, 2) )\nint LSB1(unsigned long long x) { return (x == 0 ? -1 : __builtin_ctzll(x)); } // LSB(1), 0-indexed ( (0, 1, 2, 3, 4) -> (-1, 0, 1, 0, 2) )\nlong long maskbit(int n) { return (1LL << n) - 1; }\nbool bit_is1(long long x, int i) { return ((x>>i) & 1); }\nstring charrep(int n, char c) { return std::string(n, c); }\ntemplate<class T> T square(T x) { return (x) * (x); }\ntemplate<class T>void UNIQUE(T& A) {sort(all(A)); A.erase(unique(all(A)), A.end());}\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\ntemplate<class T, class U> bool chmin(T& a, const U& b){ return chmin(a, (T)b); }\ntemplate<class T, class U> bool chmax(T& a, const U& b){ return chmax(a, (T)b); }\nvoid YESNO(bool b) {if(b){cout<<\"YES\"<<'\\n';} else{cout<<\"NO\"<<'\\n';}} void YES() {YESNO(true);} void NO() {YESNO(false);}\nvoid yesno(bool b) {if(b){cout<<\"yes\"<<'\\n';} else{cout<<\"no\"<<'\\n';}} void yes() {yesno(true);} void no() {yesno(false);}\nvoid YesNo(bool b) {if(b){cout<<\"Yes\"<<'\\n';} else{cout<<\"No\"<<'\\n';}} void Yes() {YesNo(true);} void No() {YesNo(false);}\nvoid POSIMPOS(bool b) {if(b){cout<<\"POSSIBLE\"<<'\\n';} else{cout<<\"IMPOSSIBLE\"<<'\\n';}}\nvoid PosImpos(bool b) {if(b){cout<<\"Possible\"<<'\\n';} else{cout<<\"Impossible\"<<'\\n';}}\nvoid posimpos(bool b) {if(b){cout<<\"possible\"<<'\\n';} else{cout<<\"impossible\"<<'\\n';}}\nvoid FIRSEC(bool b) {if(b){cout<<\"FIRST\"<<'\\n';} else{cout<<\"SECOND\"<<'\\n';}}\nvoid firsec(bool b) {if(b){cout<<\"first\"<<'\\n';} else{cout<<\"second\"<<'\\n';}}\nvoid FirSec(bool b) {if(b){cout<<\"First\"<<'\\n';} else{cout<<\"Second\"<<'\\n';}}\nvoid AliBob(bool b) {if(b){cout<<\"Alice\"<<'\\n';} else{cout<<\"Bob\"<<'\\n';}}\nvoid TakAok(bool b) {if(b){cout<<\"Takahashi\"<<'\\n';} else{cout<<\"Aoki\"<<'\\n';}}\nint GetTime() {return 1000.0*static_cast<double>(clock() - TIME_START) / CLOCKS_PER_SEC;}\nll myRand(ll B) {return (unsigned long long)rng() % B;}\ntemplate<class T> void print(const T& x, const char endch = '\\n') { cout << x << endch; }\n\ntemplate<class T> T ceil_div(T x, T y) { assert(y); return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate<class T> T floor_div(T x, T y) { assert(y); return (x > 0 ? x / y : (x - y + 1) / y); }\ntemplate<class T> pair<T, T> divmod(T x, T y) { T q = floor_div(x, y); return {q, x - q * y}; } /// (q, r) s.t. x = q*y + r \nll GCD(ll a, ll b) { if(a < b) swap(a, b); if(b == 0) return a; if(a%b == 0) return b; else return GCD(b, a%b); }\nll LCM(ll a, ll b) { assert(GCD(a,b) != 0); return a / GCD(a, b) * b; }\nll MOD(ll &x, const ll P) { ll ret = x%P; if(ret < 0) ret += P; return x = ret; } /// x % P を非負整数に直す\nll mpow(ll x, ll n, const ll mod) { x %= mod; ll ret = 1; while(n > 0) { if(n & 1) ret = ret * x % mod; x = x * x % mod; n >>= 1; } return ret; } /// x^n % mod を計算\nll lpow(ll x, ll n) { ll ret = 1; while(n > 0){ if(n & 1) ret = ret * x; x = x * x; n >>= 1; } return ret; } /// x^nを計算\nstring toBinary(ll n) { if(n == 0) return \"0\"; assert(n > 0); string ret; while (n != 0){ ret += ( (n & 1) == 1 ? '1' : '0' ); n >>= 1; } reverse(ret.begin(), ret.end()); return ret; } /// 10進数(long long) -> 2進数(string)への変換\nll toDecimal(string S) { ll ret = 0; for(int i = 0; i < (int)S.size(); i++){ ret *= 2LL; if(S[i] == '1') ret += 1; } return ret; } /// 2進数(string) → 10進数(long long)への変換\nint ceil_pow2(ll n) { int x = 0; while ((1ll << x) < n) x++; return x;} /// return minimum non-negative `x` s.t. `n <= 2**x`\nint floor_pow2(ll n) { int x = 0; while ((1ll << (x+1)) <= n) x++; return x;} /// return maximum non-negative `x` s.t. `n >= 2**x`\n\n\n// ############################\n// # #\n// # C O D E S T A R T #\n// # #\n// ############################\n\nvector<pii > factorization(long long N) {\n vector<pii > ret;\n for (long long i = 2; i * i <= N; i++) {\n int cnt = 0;\n while (N % i == 0) {\n cnt++;\n N /= i;\n }\n if (cnt > 0) ret.emplace_back(i, cnt);\n }\n if (N != 1) ret.emplace_back(N, 1);\n return ret;\n}\n\nvector<int> enum_divisors(long long N, const bool do_sort = true) {\n vector<int> ret;\n\n for (long long i = 1; i * i <= N; i++) {\n if (N % i != 0) continue;\n ret.push_back(i);\n if (i * i != N) ret.push_back(N / i);\n }\n\n if (do_sort) sort(ret.begin(), ret.end(), greater<int>());\n return ret;\n}\n\n/// main()の中に0を受け取る変数(終了判定)を定義しておく\nint P,Q,A,N;\n\nvoid solve() {\n cin >> Q >> A >> N;\n\n int G = GCD(P,Q);\n P/=G;\n Q/=G;\n\n // auto baseD = factorization(Q);\n // unordered_map<int,int> mp;\n // for(auto [x,v]:baseD) mp[x] = v;\n \n int ans = 0;\n vb did(A+1,false);\n vvi Ds(A+1);\n for(int i=1; Q*i<=A; i++) { // 分母の積全探索\n // auto tmpD = factorization(i);\n // auto D = mp;\n // for(auto [x,v]) D[x] += v;\n\n int bunbo = Q*i;\n int need = P*i;\n\n auto D = enum_divisors(bunbo);\n Ds[bunbo] = D;\n did[bunbo] = true;\n auto dfs = [&](auto dfs, int cnt, int sum, int prev, int prod)->void{\n if(sum == need) {\n if(prod == bunbo) {\n debug(cnt,sum,prev,prod);\n ans++;\n }\n return;\n }\n\n if(cnt == N-1) {\n int tmp = need - sum;\n if(tmp == prod && prev <= bunbo/tmp) {\n debug(bunbo,sum,prev,prod,tmp);\n ans++;\n }\n return;\n }\n\n int tmp = bunbo/prod;\n if(!did[tmp]) {\n did[tmp] = true;\n Ds[tmp] = enum_divisors(tmp);\n }\n\n for(auto nxt:Ds[tmp]) { // 1/nxtを足す\n if(prev>nxt) break;\n if(sum + bunbo/nxt > need) break;\n \n dfs(dfs, cnt+1, sum+bunbo/nxt, nxt, prod*nxt);\n }\n };\n dfs(dfs, 0, 0, 0, 1);\n\n }\n\n cout << ans << nl;\n}\n\n\n\nsigned main() {\n cin.tie(0); ios_base::sync_with_stdio(false);\n TIMER_START;\n //cout << fixed << setprecision(15);\n \n\n //int tt = 1;\n //cin >> tt;\n while(true){\n cin >> P;\n if(P == 0) break;\n\n solve();\n }\n\n TIMECHECK;\n return 0;\n}", "accuracy": 1, "time_ms": 680, "memory_kb": 4344, "score_of_the_acc": -1.6629, "final_rank": 20 }, { "submission_id": "aoj_1131_8976653", "code_snippet": "#include<iostream>\n#include<cmath>\n#include<cstring>\n#include<cstdio>\n#include<algorithm>\nusing namespace std;\nint p,q,a,n,t=0;\nvoid fun(int k,int last,int sum1,int sum2)\n{\n\tif(k<=n+1)\n\t{\n\t\t\tif(sum1*q==sum2*p)\n\t\t\t{\n\t\t\t\tt++;\n\t\t\t\treturn;\n\t\t\t}\n\t\t\tif((sum1*q>=sum2*p))return;\n\t\t\t\tfor(int i=last;i<=a;++i)\n\t\t\t\tif(sum2*i<=a)fun(k+1,i,sum1*i+sum2,sum2*i);else break;\n\t}\n}\nint main()\n{\n\twhile(1==1)\n\t{\n\t\tscanf(\"%d%d%d%d\",&p,&q,&a,&n);\n\t\tif(p==0 && q==0 && a==0 && n==0)return 0;\n\t\telse\n\t\t{\n\t\t\tt=0;\n\t\t\tfun(1,q/p,0,1);\n\t\t\tcout<<t<<endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3112, "score_of_the_acc": -0.1003, "final_rank": 2 }, { "submission_id": "aoj_1131_7825469", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint ans = 0;\nvoid search_ans(int p, int q, int a, int n, int r, int m, int c, int s) {\n if (q * c == p * m) {\n ans++;\n return;\n }\n if (s == n) return;\n if (q * c > p * m) return;\n for (int x = r; x * m <= a; x++) {\n int nm = m * x;\n int nc = c * x + m;\n search_ans(p, q, a, n, x, nm, nc, s + 1);\n }\n}\n\nint main() {\n vector<int> rep;\n while (true) {\n int p, q, a, n;\n cin >> p >> q >> a >> n;\n if (p == 0 && q == 0 && a == 0 && n == 0) break;\n\n int r, m, c, s;\n r = m = 1;\n c = s = 0;\n search_ans(p, q, a, n, r, m, c, s);\n rep.push_back(ans);\n ans = 0;\n }\n for (auto v : rep) cout << v << endl;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3348, "score_of_the_acc": -0.2657, "final_rank": 7 }, { "submission_id": "aoj_1131_6833752", "code_snippet": "// #define NDEBUG\n#include <bits/stdc++.h>\n\n#define REP_(i, a_, b_, a, b, ...) for (int i = (a), END_##i = (b); i < END_##i; ++i)\n#define REP(i, ...) REP_(i, __VA_ARGS__, __VA_ARGS__, 0, __VA_ARGS__)\n#define ALL(x) std::begin(x), std::end(x)\nusing Int = long long;\nusing Uint = unsigned long long;\nusing Real = long double;\n\ntemplate<typename T, typename U>\ninline bool chmax(T &a, U b) { return a < b and ((a = b), true); }\ntemplate<typename T, typename U>\ninline bool chmin(T &a, U b) { return a > b and ((a = b), true); }\ntemplate<typename T>\nconstexpr T\nkBig = std::numeric_limits<T>::max() / 2;\n#if __cplusplus < 202002L\ntemplate<typename T>\ninline int ssize(const T &a) { return (int) a.size(); }\n#endif\n\nstruct CastInput {\n template<typename T>\n operator T() const {\n T x;\n std::cin >> x;\n assert(bool(std::cin));\n return x;\n }\n struct Sized {\n int n;\n template<typename T>\n operator T() const {\n T xs(n);\n for (auto &x: xs) {\n std::cin >> x;\n assert(bool(std::cin));\n }\n return xs;\n }\n };\n Sized operator()(int n) const { return {n}; }\n} in;\n\ntemplate<typename Container>\nstd::ostream &out_seq(const Container &seq, const char *sep = \" \",\n const char *ends = \"\\n\", std::ostream &os = std::cout) {\n const auto itl = std::begin(seq), itr = std::end(seq);\n for (auto it = itl; it != itr; ++it) {\n if (it != itl) os << sep;\n os << *it;\n }\n return os << ends;\n}\n\ntemplate<typename T>\nstd::ostream &out_one(const T &x, char endc) {\n if constexpr(std::is_same<T, bool>::value)\n {\n return std::cout << (x ? \"Yes\" : \"No\") << endc;\n } else {\n return std::cout << x << endc;\n }\n}\ntemplate<typename T>\nstd::ostream &out(const T &x) {\n return out_one(x, '\\n');\n}\ntemplate<typename T, typename... Ts>\nstd::ostream &out(const T &head, Ts... tail) {\n return out_one(head, ' '), out(tail...);\n}\n\nvoid init_(bool interactive = false) {\n std::ios::sync_with_stdio(false);\n if (not interactive) std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(18);\n}\n\n[[noreturn]] void exit_() {\n#ifdef MY_DEBUG\n std::string _;\n assert((std::cin >> _).fail());\n#endif\n std::cout.flush(), std::cerr.flush(), std::_Exit(0);\n}\n\n#ifdef MY_DEBUG\n#include \"debug_dump.hpp\"\n#include \"backward.hpp\"\nbackward::SignalHandling kSignalHandling;\n#else\n#define DUMP(...)\n#define test_case(...)\n#define cerr if(false)cerr\n#endif\n\ntemplate<class F>\nstruct Rec {\n F f_;\n explicit Rec(F f) : f_(std::move(f)) {}\n template<class... Args>\n decltype(auto)\n operator()(Args &&... args) {\n return f_(*this, std::forward<Args>(args)...);\n }\n};\ntemplate<class F> Rec(F) -> Rec<F>;\n\n// Rational number with lazy reduction.\nstruct LazyRational {\n using i64 = long long;\n using i128 = __int128_t;\n\n mutable i64 nume_;\n mutable i64 deno_;\n mutable bool reduced_;\n\n static constexpr i64\n kReduceThreshold = i64(1) << 62;\n\n LazyRational() : nume_(0), deno_(1), reduced_(true) {}\n LazyRational(i64 n) : nume_(n), deno_(1), reduced_(true) {}\n LazyRational(i64 n, i64 d, bool reduced)\n : nume_(n), deno_(d), reduced_(reduced) {}\n\n template<typename T>\n LazyRational(T n, T d) : reduced_(false) {\n assert(d != 0); // zero division\n if (n == 0) {\n d = 1;\n reduced_ = true;\n } else {\n reduced_ = light_reduce_(n, d);\n }\n nume_ = static_cast<i64>(n);\n deno_ = static_cast<i64>(d);\n }\n\n i64 numerator() const {\n if (not reduced_) {\n reduce_(nume_, deno_);\n reduced_ = true;\n }\n return nume_;\n }\n\n i64 denominator() const {\n if (not reduced_) {\n reduce_(nume_, deno_);\n reduced_ = true;\n }\n return deno_;\n }\n\n // Cast to a floating point number.\n template<typename Float>\n explicit operator Float() const {\n static_assert(std::is_floating_point<Float>::value);\n return (Float) nume_ / (Float) deno_;\n }\n\n const LazyRational &operator+() const { return *this; }\n\n LazyRational operator-() const {\n return LazyRational(-nume_, deno_, reduced_);\n }\n\n LazyRational &operator+=(const LazyRational &y) {\n if (y.nume_ == 0) return *this;\n if (this->nume_ == 0) {\n *this = y;\n return *this;\n }\n i128 zn = i128(this->nume_) * y.deno_ + i128(y.nume_) * this->deno_;\n i128 zd = i128(this->deno_) * y.deno_;\n this->reduced_ = light_reduce_(zn, zd);\n this->nume_ = static_cast<i64>(zn);\n this->deno_ = static_cast<i64>(zd);\n return *this;\n }\n friend LazyRational operator+(LazyRational x, const LazyRational &y) {\n x += y;\n return x;\n }\n\n friend LazyRational operator-(const LazyRational &x, const LazyRational &y) {\n return x + (-y);\n }\n LazyRational &operator-=(const LazyRational &y) {\n *this += -y;\n return *this;\n }\n\n LazyRational &operator*=(const LazyRational &y) {\n if (this->nume_ == 0) return *this;\n if (y.nume_ == 0) {\n this->nume_ = 0;\n this->deno_ = 1;\n this->reduced_ = true;\n } else {\n i128 zn = i128(this->nume_) * y.nume_;\n i128 zd = i128(this->deno_) * y.deno_;\n this->reduced_ = light_reduce_(zn, zd);\n this->nume_ = static_cast<i64>(zn);\n this->deno_ = static_cast<i64>(zd);\n }\n return *this;\n }\n friend LazyRational operator*(LazyRational x, const LazyRational &y) {\n x *= y;\n return x;\n }\n\n LazyRational inv() const {\n int sign = this->nume_ >= 0 ? 1 : -1;\n return LazyRational(this->deno_ * sign, this->nume_ * sign, this->reduced_);\n }\n friend LazyRational operator/(const LazyRational &x, const LazyRational &y) {\n return x * y.inv();\n }\n LazyRational &operator/=(const LazyRational &y) {\n *this *= y.inv();\n return *this;\n }\n\n friend bool operator==(const LazyRational &x, const LazyRational &y) {\n return i128(x.nume_) * y.deno_ == i128(x.deno_) * y.nume_;\n }\n friend bool operator!=(const LazyRational &x, const LazyRational &y) {\n return not(x == y);\n }\n friend bool operator<(const LazyRational &x, const LazyRational &y) {\n return i128(x.nume_) * y.deno_ < i128(x.deno_) * y.nume_;\n }\n friend bool operator>(const LazyRational &x, const LazyRational &y) {\n return y < x;\n }\n friend bool operator<=(const LazyRational &x, const LazyRational &y) {\n return not(x > y);\n }\n friend bool operator>=(const LazyRational &x, const LazyRational &y) {\n return not(x < y);\n }\n\n friend std::ostream &operator<<(std::ostream &os, const LazyRational &x) {\n return os << x.numerator() << \"/\" << x.denominator();\n }\n\n private:\n template<typename T>\n static void reduce_(T &n, T &d) {\n if (n == 0) {\n d = 1;\n return;\n }\n i128 a = abs_(n), b = d;\n while (b) {\n a %= b;\n std::swap(a, b);\n }\n if (a > 1) {\n n /= static_cast<T>(a);\n d /= static_cast<T>(a);\n }\n }\n\n // Returns whether the args are reduced.\n template<typename T>\n static bool light_reduce_(T &n, T &d) {\n if (std::max<T>(abs_(n), d) <= kReduceThreshold) {\n return false;\n }\n reduce_(n, d);\n if constexpr(std::is_same_v < T, i128 > )\n {\n if (std::max<T>(abs_(n), d) > std::numeric_limits<i64>::max()) {\n throw std::overflow_error(\"cannot fit in 64 bits\");\n }\n }\n return true;\n }\n\n template<typename T>\n static T abs_(const T &x) {\n if constexpr(std::is_same_v < T, i128 > )\n {\n return x < 0 ? -x : x;\n } else {\n return std::abs(x);\n }\n }\n};\nusing Rat = LazyRational;\n\ntemplate<class T>\nT ceil_div(T x, T y) {\n assert(y != 0);\n return x / y + (((x ^ y) >= 0) and (x % y));\n}\n\nusing namespace std;\n\nauto solve() -> Int {\n int p = in, q = in, a = in, n = in;\n if (p == 0 and q == 0 and a == 0 and n == 0) {\n exit_();\n }\n\n auto f = Rec([&](auto &rec, int i, const Rat &r, Int d0, Int prod) -> Int {\n if (r.nume_ == 0) return 1;\n if (i == 0) return 0;\n Int res = 0;\n for (Int d = max<Int>(d0, ceil_div(r.deno_, r.nume_)); prod * d <= a; ++d) {\n res += rec(i - 1, r - Rat(1LL, d), d, prod * d);\n }\n return res;\n });\n return f(n, Rat(p, q), 1, 1);\n}\n\nint main() {\n init_();\n for (int t = 0;; ++t) {\n test_case(t, 0);\n out(solve());\n }\n}", "accuracy": 1, "time_ms": 860, "memory_kb": 3184, "score_of_the_acc": -0.9969, "final_rank": 17 }, { "submission_id": "aoj_1131_6833700", "code_snippet": "// #define NDEBUG\n#include <bits/stdc++.h>\n\n#define REP_(i, a_, b_, a, b, ...) for (int i = (a), END_##i = (b); i < END_##i; ++i)\n#define REP(i, ...) REP_(i, __VA_ARGS__, __VA_ARGS__, 0, __VA_ARGS__)\n#define ALL(x) std::begin(x), std::end(x)\nusing Int = long long;\nusing Uint = unsigned long long;\nusing Real = long double;\n\ntemplate<typename T, typename U>\ninline bool chmax(T &a, U b) { return a < b and ((a = b), true); }\ntemplate<typename T, typename U>\ninline bool chmin(T &a, U b) { return a > b and ((a = b), true); }\ntemplate<typename T>\nconstexpr T kBig = std::numeric_limits<T>::max() / 2;\n#if __cplusplus < 202002L\ntemplate<typename T>\ninline int ssize(const T &a) { return (int) a.size(); }\n#endif\n\nstruct CastInput {\n template<typename T>\n operator T() const {\n T x;\n std::cin >> x;\n assert(bool(std::cin));\n return x;\n }\n struct Sized {\n int n;\n template<typename T>\n operator T() const {\n T xs(n);\n for (auto &x: xs) {\n std::cin >> x;\n assert(bool(std::cin));\n }\n return xs;\n }\n };\n Sized operator()(int n) const { return {n}; }\n} in;\n\ntemplate<typename Container>\nstd::ostream &out_seq(const Container &seq, const char *sep = \" \",\n const char *ends = \"\\n\", std::ostream &os = std::cout) {\n const auto itl = std::begin(seq), itr = std::end(seq);\n for (auto it = itl; it != itr; ++it) {\n if (it != itl) os << sep;\n os << *it;\n }\n return os << ends;\n}\n\ntemplate<typename T>\nstd::ostream &out_one(const T &x, char endc) {\n if constexpr (std::is_same<T, bool>::value) {\n return std::cout << (x ? \"Yes\" : \"No\") << endc;\n } else {\n return std::cout << x << endc;\n }\n}\ntemplate<typename T>\nstd::ostream &out(const T &x) {\n return out_one(x, '\\n');\n}\ntemplate<typename T, typename... Ts>\nstd::ostream &out(const T &head, Ts... tail) {\n return out_one(head, ' '), out(tail...);\n}\n\nvoid init_(bool interactive = false) {\n std::ios::sync_with_stdio(false);\n if (not interactive) std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(18);\n}\n\n[[noreturn]] void exit_() {\n#ifdef MY_DEBUG\n std::string _;\n assert((std::cin >> _).fail());\n#endif\n std::cout.flush(), std::cerr.flush(), std::_Exit(0);\n}\n\n#ifdef MY_DEBUG\n#include \"debug_dump.hpp\"\n#include \"backward.hpp\"\nbackward::SignalHandling kSignalHandling;\n#else\n#define DUMP(...)\n#define test_case(...)\n#define cerr if(false)cerr\n#endif\n\ntemplate<class F>\nstruct Rec {\n F f_;\n explicit Rec(F f) : f_(std::move(f)) {}\n template<class... Args>\n decltype(auto) operator()(Args &&... args) {\n return f_(*this, std::forward<Args>(args)...);\n }\n};\ntemplate<class F> Rec(F) -> Rec<F>;\n\n// Rational number with lazy reduction.\nstruct LazyRational {\n using i64 = long long;\n using i128 = __int128_t;\n\n mutable i64 nume_;\n mutable i64 deno_;\n mutable bool reduced_;\n\n static constexpr i64 kReduceThreshold = i64(1) << 62;\n\n LazyRational() : nume_(0), deno_(1), reduced_(true) {}\n LazyRational(i64 n) : nume_(n), deno_(1), reduced_(true) {}\n\n template<typename T>\n LazyRational(T n, T d) : reduced_(false) {\n assert(d != 0); // zero division\n if (n == 0) {\n d = 1;\n reduced_ = true;\n } else {\n reduced_ = light_reduce_(n, d);\n }\n nume_ = static_cast<i64>(n);\n deno_ = static_cast<i64>(d);\n }\n\n i64 numerator() const {\n if (not reduced_) reduce_me_();\n return nume_;\n }\n\n i64 denominator() const {\n if (not reduced_) reduce_me_();\n return deno_;\n }\n\n // Cast to a floating point number.\n template<typename Float>\n explicit operator Float() const {\n static_assert(std::is_floating_point<Float>::value);\n return (Float) nume_ / (Float) deno_;\n }\n\n const LazyRational &operator+() const { return *this; }\n\n LazyRational operator-() const {\n LazyRational ret;\n ret.nume_ = -this->nume_;\n ret.deno_ = this->deno_;\n ret.reduced_ = this->reduced_;\n return ret;\n }\n\n friend bool operator==(const LazyRational &x, const LazyRational &y) {\n return i128(x.nume_) * y.deno_ == i128(x.deno_) * y.nume_;\n }\n friend bool operator!=(const LazyRational &x, const LazyRational &y) {\n return not(x == y);\n }\n friend bool operator<(const LazyRational &x, const LazyRational &y) {\n return i128(x.nume_) * y.deno_ < i128(x.deno_) * y.nume_;\n }\n friend bool operator>(const LazyRational &x, const LazyRational &y) { return y < x; }\n friend bool operator<=(const LazyRational &x, const LazyRational &y) {\n return not(x > y);\n }\n friend bool operator>=(const LazyRational &x, const LazyRational &y) {\n return not(x < y);\n }\n\n LazyRational &operator+=(const LazyRational &y) {\n i128 zn = i128(this->nume_) * y.deno_ + i128(y.nume_) * this->deno_;\n i128 zd = i128(this->deno_) * y.deno_;\n this->reduced_ = light_reduce_(zn, zd);\n this->nume_ = static_cast<i64>(zn);\n this->deno_ = static_cast<i64>(zd);\n return *this;\n }\n friend LazyRational operator+(LazyRational x, const LazyRational &y) {\n x += y;\n return x;\n }\n\n friend LazyRational operator-(const LazyRational &x, const LazyRational &y) {\n return x + (-y);\n }\n LazyRational &operator-=(const LazyRational &y) {\n *this += -y;\n return *this;\n }\n\n LazyRational &operator*=(const LazyRational &y) {\n if (this->nume_ == 0) return *this;\n if (y.nume_ == 0) {\n this->nume_ = 0;\n this->deno_ = 1;\n this->reduced_ = true;\n return *this;\n }\n i128 zn = i128(this->nume_) * y.nume_;\n i128 zd = i128(this->deno_) * y.deno_;\n this->reduced_ = light_reduce_(zn, zd);\n this->nume_ = static_cast<i64>(zn);\n this->deno_ = static_cast<i64>(zd);\n return *this;\n }\n friend LazyRational operator*(LazyRational x, const LazyRational &y) {\n x *= y;\n return x;\n }\n\n LazyRational inv() const {\n LazyRational ret;\n int sign = this->nume_ >= 0 ? 1 : -1;\n ret.nume_ = this->deno_ * sign;\n ret.deno_ = this->nume_ * sign;\n ret.reduced_ = this->reduced_;\n return ret;\n }\n friend LazyRational operator/(const LazyRational &x, const LazyRational &y) {\n return x * y.inv();\n }\n LazyRational &operator/=(const LazyRational &y) {\n *this *= y.inv();\n return *this;\n }\n\n friend std::ostream &operator<<(std::ostream &os, const LazyRational &x) {\n return os << x.numerator() << \"/\" << x.denominator();\n }\n\n private:\n template<typename T>\n static void reduce_(T &n, T &d) {\n if (n == 0) {\n d = 1;\n return;\n }\n i128 a = (n < 0 ? -n : n), b = d;\n while (b) {\n a %= b;\n std::swap(a, b);\n }\n n /= static_cast<T>(a);\n d /= static_cast<T>(a);\n }\n\n // Returns whether the args are reduced.\n template<typename T>\n static bool light_reduce_(T &n, T &d) {\n if (std::max<T>((n < 0 ? -n : n), d) <= kReduceThreshold) {\n return false;\n }\n reduce_(n, d);\n if constexpr (std::is_same_v<T, i128>) {\n if (std::max<T>((n < 0 ? -n : n), d) > std::numeric_limits<i64>::max()) {\n throw std::overflow_error(\"cannot fit in 64 bits\");\n }\n }\n return true;\n }\n\n void reduce_me_() const {\n reduce_<i64>(nume_, deno_);\n reduced_ = true;\n }\n};\nusing Rat = LazyRational;\n\ntemplate<class T>\nT ceil_div(T x, T y) {\n assert(y != 0);\n return x / y + (((x ^ y) >= 0) and (x % y));\n}\n\nusing namespace std;\n\nauto solve() -> Int {\n int p = in, q = in, a = in, n = in;\n if (p == 0 and q == 0 and a == 0 and n == 0) {\n exit_();\n }\n\n auto f = Rec([&](auto &rec, int i, const Rat &r, Int d0, Int prod) -> Int {\n if (r.nume_ == 0) return 1;\n if (i == 0) return 0;\n Int res = 0;\n for (Int d = max<Int>(d0, ceil_div(r.deno_, r.nume_)); prod * d <= a; ++d) {\n res += rec(i - 1, r - Rat(1LL, d), d, prod * d);\n }\n return res;\n });\n return f(n, Rat(p, q), 1, 1);\n}\n\nint main() {\n init_();\n for (int t = 0;; ++t) {\n test_case(t, 0);\n out(solve());\n }\n}", "accuracy": 1, "time_ms": 500, "memory_kb": 3252, "score_of_the_acc": -0.6433, "final_rank": 15 }, { "submission_id": "aoj_1131_6833687", "code_snippet": "// #define NDEBUG\n#include <bits/stdc++.h>\n\n#define REP_(i, a_, b_, a, b, ...) for (int i = (a), END_##i = (b); i < END_##i; ++i)\n#define REP(i, ...) REP_(i, __VA_ARGS__, __VA_ARGS__, 0, __VA_ARGS__)\n#define ALL(x) std::begin(x), std::end(x)\nusing Int = long long;\nusing Uint = unsigned long long;\nusing Real = long double;\n\ntemplate<typename T, typename U>\ninline bool chmax(T &a, U b) { return a < b and ((a = b), true); }\ntemplate<typename T, typename U>\ninline bool chmin(T &a, U b) { return a > b and ((a = b), true); }\ntemplate<typename T>\nconstexpr T kBig = std::numeric_limits<T>::max() / 2;\n#if __cplusplus < 202002L\ntemplate<typename T>\ninline int ssize(const T &a) { return (int) a.size(); }\n#endif\n\nstruct CastInput {\n template<typename T>\n operator T() const {\n T x;\n std::cin >> x;\n assert(bool(std::cin));\n return x;\n }\n struct Sized {\n int n;\n template<typename T>\n operator T() const {\n T xs(n);\n for (auto &x: xs) {\n std::cin >> x;\n assert(bool(std::cin));\n }\n return xs;\n }\n };\n Sized operator()(int n) const { return {n}; }\n} in;\n\ntemplate<typename Container>\nstd::ostream &out_seq(const Container &seq, const char *sep = \" \",\n const char *ends = \"\\n\", std::ostream &os = std::cout) {\n const auto itl = std::begin(seq), itr = std::end(seq);\n for (auto it = itl; it != itr; ++it) {\n if (it != itl) os << sep;\n os << *it;\n }\n return os << ends;\n}\n\ntemplate<typename T>\nstd::ostream &out_one(const T &x, char endc) {\n if constexpr (std::is_same<T, bool>::value) {\n return std::cout << (x ? \"Yes\" : \"No\") << endc;\n } else {\n return std::cout << x << endc;\n }\n}\ntemplate<typename T>\nstd::ostream &out(const T &x) {\n return out_one(x, '\\n');\n}\ntemplate<typename T, typename... Ts>\nstd::ostream &out(const T &head, Ts... tail) {\n return out_one(head, ' '), out(tail...);\n}\n\nvoid init_(bool interactive = false) {\n std::ios::sync_with_stdio(false);\n if (not interactive) std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(18);\n}\n\n[[noreturn]] void exit_() {\n#ifdef MY_DEBUG\n std::string _;\n assert((std::cin >> _).fail());\n#endif\n std::cout.flush(), std::cerr.flush(), std::_Exit(0);\n}\n\n#ifdef MY_DEBUG\n#include \"debug_dump.hpp\"\n#include \"backward.hpp\"\nbackward::SignalHandling kSignalHandling;\n#else\n#define DUMP(...)\n#define test_case(...)\n#define cerr if(false)cerr\n#endif\n\ntemplate<class F>\nstruct Rec {\n F f_;\n explicit Rec(F f) : f_(std::move(f)) {}\n template<class... Args>\n decltype(auto) operator()(Args &&... args) {\n return f_(*this, std::forward<Args>(args)...);\n }\n};\ntemplate<class F> Rec(F) -> Rec<F>;\n\n// Rational number with lazy reduction.\nstruct LazyRational {\n using i64 = long long;\n using i128 = __int128_t;\n\n mutable i64 nume_;\n mutable i64 deno_;\n mutable bool reduced_;\n\n static constexpr i64 kReduceThreshold = i64(1) << 62;\n\n LazyRational() : nume_(0), deno_(1), reduced_(true) {}\n LazyRational(i64 n) : nume_(n), deno_(1), reduced_(true) {}\n\n LazyRational(i128 n, i128 d) : reduced_(false) {\n assert(d != 0); // zero division\n if (n == 0) {\n d = 1;\n reduced_ = true;\n } else {\n const int sign = ((n < 0) xor (d < 0)) ? -1 : 1;\n if (n < 0) n = -n;\n if (d < 0) d = -n;\n if (std::max<i128>(n, d) > kReduceThreshold) {\n reduce_(n, d);\n }\n n *= sign;\n }\n nume_ = (i64) n;\n deno_ = (i64) d;\n }\n\n i64 numerator() const {\n if (not reduced_) reduce_me_();\n return nume_;\n }\n\n i64 denominator() const {\n if (not reduced_) reduce_me_();\n return deno_;\n }\n\n // Cast to a floating point number.\n template<typename Float>\n explicit operator Float() const {\n static_assert(std::is_floating_point<Float>::value);\n return (Float) nume_ / (Float) deno_;\n }\n\n const LazyRational &operator+() const { return *this; }\n\n LazyRational operator-() const {\n LazyRational ret;\n ret.nume_ = -this->nume_;\n ret.deno_ = this->deno_;\n ret.reduced_ = this->reduced_;\n return ret;\n }\n\n friend bool operator==(const LazyRational &x, const LazyRational &y) {\n return i128(x.nume_) * y.deno_ == i128(x.deno_) * y.nume_;\n }\n friend bool operator!=(const LazyRational &x, const LazyRational &y) {\n return not(x == y);\n }\n friend bool operator<(const LazyRational &x, const LazyRational &y) {\n return i128(x.nume_) * y.deno_ < i128(x.deno_) * y.nume_;\n }\n friend bool operator>(const LazyRational &x, const LazyRational &y) { return y < x; }\n friend bool operator<=(const LazyRational &x, const LazyRational &y) {\n return not(x > y);\n }\n friend bool operator>=(const LazyRational &x, const LazyRational &y) {\n return not(x < y);\n }\n\n LazyRational &operator+=(const LazyRational &y) {\n i128 zn = i128(this->nume_) * y.deno_ + i128(y.nume_) * this->deno_;\n i128 zd = i128(this->deno_) * y.deno_;\n this->reduced_ = light_reduce_(zn, zd);\n this->nume_ = zn;\n this->deno_ = zd;\n return *this;\n }\n friend LazyRational operator+(LazyRational x, const LazyRational &y) {\n x += y;\n return x;\n }\n\n friend LazyRational operator-(const LazyRational &x, const LazyRational &y) {\n return x + (-y);\n }\n LazyRational &operator-=(const LazyRational &y) {\n *this += -y;\n return *this;\n }\n\n LazyRational &operator*=(const LazyRational &y) {\n if (this->nume_ == 0) return *this;\n if (y.nume_ == 0) {\n this->nume_ = 0;\n this->deno_ = 1;\n this->reduced_ = true;\n return *this;\n }\n i128 zn = i128(this->nume_) * y.nume_;\n i128 zd = i128(this->deno_) * y.deno_;\n this->reduced_ = light_reduce_(zn, zd);\n this->nume_ = zn;\n this->deno_ = zd;\n return *this;\n }\n friend LazyRational operator*(LazyRational x, const LazyRational &y) {\n x *= y;\n return x;\n }\n\n LazyRational inv() const {\n LazyRational ret;\n int sign = this->nume_ >= 0 ? 1 : -1;\n ret.nume_ = this->deno_ * sign;\n ret.deno_ = this->nume_ * sign;\n ret.reduced_ = this->reduced_;\n return ret;\n }\n friend LazyRational operator/(const LazyRational &x, const LazyRational &y) {\n return x * y.inv();\n }\n LazyRational &operator/=(const LazyRational &y) {\n *this *= y.inv();\n return *this;\n }\n\n friend std::ostream &operator<<(std::ostream &os, const LazyRational &x) {\n return os << x.numerator() << \"/\" << x.denominator();\n }\n\n private:\n template<typename T>\n static void reduce_(T &n, T &d) {\n if (n == 0) {\n d = 1;\n return;\n }\n i128 a = (n < 0 ? -n : n), b = d;\n while (b) {\n a %= b;\n std::swap(a, b);\n }\n n /= a;\n d /= a;\n }\n\n // Returns whether the args are reduced.\n template<typename T>\n static bool light_reduce_(T &n, T &d) {\n if (std::max<T>((n < 0 ? -n : n), d) <= kReduceThreshold) {\n return false;\n }\n reduce_(n, d);\n if constexpr (std::is_same_v<T, i128>) {\n if (std::max<T>((n < 0 ? -n : n), d) > std::numeric_limits<i64>::max()) {\n throw std::overflow_error(\"cannot fit in 64 bits\");\n }\n }\n return true;\n }\n\n void reduce_me_() const {\n reduce_<i64>(nume_, deno_);\n reduced_ = true;\n }\n};\nusing Rat = LazyRational;\n// using Rat = Rational<multip::checked_int128_t>; // for testing overflow\n\n\ntemplate<class T>\nT ceil_div(T x, T y) {\n assert(y != 0);\n return x / y + (((x ^ y) >= 0) and (x % y));\n}\n\nusing namespace std;\n\nauto solve() -> Int {\n int p = in, q = in, a = in, n = in;\n if (p == 0 and q == 0 and a == 0 and n == 0) {\n exit_();\n }\n\n auto f = Rec([&](auto &rec, int i, const Rat &r, Int d0, Int prod) -> Int {\n if (r.nume_ == 0) return 1;\n if (i == 0) return 0;\n Int res = 0;\n for (Int d = max<Int>(d0, ceil_div(r.deno_, r.nume_)); prod * d <= a; ++d) {\n res += rec(i - 1, r - Rat(1, d), d, prod * d);\n }\n return res;\n });\n return f(n, Rat(p, q), 1, 1);\n}\n\nint main() {\n init_();\n for (int t = 0;; ++t) {\n test_case(t, 0);\n out(solve());\n }\n}", "accuracy": 1, "time_ms": 460, "memory_kb": 3084, "score_of_the_acc": -0.4726, "final_rank": 13 }, { "submission_id": "aoj_1131_6779986", "code_snippet": "using namespace std;\n#include \"bits/stdc++.h\"\n\n// add your library with double quotation #include\"\" here.\n//#include \"atcoder/all\"\n//using namespace atcoder;\n\n// define your macros here.\n#define MOD 1000000007\n#define PI 3.14159265358979323846264338327950288419\n#define IINF 1001001001\n#define LINF 1001001001001001001LL\n\n#define ll long long\n#define VLL vector<ll>\n#define PLL pair<ll, ll>\n#define pb push_back\n#define mpair make_pair\n#define pm(first, second) pb(mpair((first), (second)))\n#define pff first.first\n#define pfs first.second\n#define psf second.first\n#define pss second.second\n\n#define REP(i,n) for(ll i = 0; i < (ll)(n); i++)\n#define REPS(i, n) for(ll i = 1; i <= (ll)(n); i++)\n#define RREP(i, n) for(int i = ((ll)(n)-1); i >= 0; i--)\n#define RREPS(i, n) for(int i = ((ll)(n)); i > 0; i--)\n#define FOR(i, a, b) for(ll i = (a); i < (b); i++)\n#define SZ(x) ((ll)(x).size())\n#define ALL(x) (x).begin(), (x).end()\n#define RALL(x) (x).rbegin(), (x).rend()\n#define MAX(a, b) max((ll)(a), (ll)(b))\n#define MIN(a, b) min((ll)(a), (ll)(b))\n#define DCEIL(a, b) (((a)+(b)-1)/(b))\n#define UNIQUE(x) (x).erase(unique((x).begin(), (x).end()), (x).end())\n#define outyn(flag) cout << ((flag)? \"Yes\": \"No\") << endl\n#define outYN(flag) cout << ((flag)? \"YES\": \"NO\") << endl\n#define out(output) cout << (output) << endl\n\ntemplate<class T>bool chmax(T &a, const T &b) { return a < b && (a = b, true); }\ntemplate<class T>bool chmin(T &a, const T &b) { return a > b && (a = b, true); }\nll qp(ll a, ll b){ll ans=1;do{if(b&1)ans=1LL*ans*a;a=1LL*a*a;}while(b>>=1);return ans;}\nll qp(ll a, ll b, ll mo){ll ans=1;do{if(b&1)ans=1LL*ans*a%mo;a=1LL*a*a%mo;}while(b>>=1);return ans;}\nint DX[4] = {1, 0, -1, 0};\nint DY[4] = {0, 1, 0, -1};\n\n#define int long long\n\nint p, q, a;\n\nint calc(int n, int d, int prod, int sum){\n int cnt = 0;\n for(int i = d; prod*i <= a; i++){\n int l = p*(prod*i);\n int r = sum*i+prod;\n if(l < r*q) continue;\n if(l == r*q){\n cnt++;\n continue;\n }\n if(n == 1) continue;\n cnt += calc(n-1, i, prod*i, r);\n }\n return cnt;\n}\nvoid solve(){\n // write your solution here.\n\n int n;\n while(true){\n cin >> p >> q >> a >> n;\n if(p == 0 && q == 0 && a == 0 && n == 0) return;\n cout << calc(n, 1, 1, 0) << endl;\n }\n \n}\n#undef int\n\n// generated by oj-template v4.7.2 (https://github.com/online-judge-tools/template-generator)\nint main() {\n // Fasterize input/output script\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n //cout << fixed << setprecision(100);\n // scanf/printf user should delete this fasterize input/output script\n\n int t = 1;\n //cin >> t; // comment out if solving multi testcase\n for(int testCase = 1;testCase <= t;++testCase){\n solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3216, "score_of_the_acc": -0.1669, "final_rank": 4 }, { "submission_id": "aoj_1131_6344622", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define bokusunny ios::sync_with_stdio(false), cin.tie(nullptr);\n\n// 有理数クラス\n// 初期化 O(logN) (NOTE:重い場合、約分の必要がないのであればlogを取れる)\n// 分母分子が両方とも0でない → マイナスは分子に寄せる&約分\n// 分母が0 → 未定義\n// 分子が0 → 分母は1で統一\nstruct Rational {\n private:\n long long NUM; // numerator, 分子\n long long DENO; // denominator, 分母\n\n void normalize() {\n if (NUM == 0) {\n DENO = 1;\n } else {\n // ---必要に応じてコメントアウトするとlogが落ちる---\n // auto g = gcd(NUM, DENO);\n // NUM /= g;\n // DENO /= g;\n // ------------------------------------------\n\n if (DENO < 0) {\n NUM *= -1;\n DENO *= -1;\n }\n }\n }\n\n public:\n Rational(long long num, long long deno) : NUM(num), DENO(deno) {\n normalize();\n // NOTE: num, deno共にintの範囲に収めないと、比較の際にオーバーフローする\n // llを使いたい &&\n // setやmapを使ってるだけの場合、unorderedに変えると比較演算子を使わないのでオーバーフローしない\n assert(NUM < INT_MAX);\n assert(DENO < INT_MAX);\n }\n Rational(long long &n) : NUM(n), DENO(1){};\n\n long long num() const { return NUM; }\n long long deno() const { return DENO; }\n double to_d() { return (double)NUM / DENO; }\n\n bool operator<(const Rational &b) const { return NUM * b.DENO < b.NUM * DENO; }\n bool operator>(const Rational &b) const { return NUM * b.DENO > b.NUM * DENO; }\n bool operator<=(const Rational &b) const { return NUM * b.DENO <= b.NUM * DENO; }\n bool operator>=(const Rational &b) const { return NUM * b.DENO >= b.NUM * DENO; }\n bool operator==(const Rational &b) const { return NUM == b.NUM && DENO == b.DENO; }\n bool operator!=(const Rational &b) const { return !(*this == b); }\n Rational operator+=(const Rational &x);\n Rational operator+=(long long x);\n Rational operator-=(const Rational &x);\n Rational operator-=(long long x);\n Rational operator*=(const Rational &x);\n Rational operator*=(long long x);\n Rational operator/=(const Rational &x);\n Rational operator/=(long long x);\n};\ninline Rational operator+(const Rational &a, const Rational &b) {\n long long num = a.num() * b.deno() + a.deno() * b.num();\n long long deno = a.deno() * b.deno();\n return Rational(num, deno);\n}\ninline Rational operator-(const Rational &a, const Rational &b) {\n long long num = a.num() * b.deno() - a.deno() * b.num();\n long long deno = a.deno() * b.deno();\n return Rational(num, deno);\n}\ninline Rational operator*(const Rational &a, const Rational &b) {\n long long num = a.num() * b.num();\n long long deno = a.deno() * b.deno();\n return Rational(num, deno);\n}\ninline Rational operator/(const Rational &a, const Rational &b) {\n long long num = a.num() * b.deno();\n long long deno = a.deno() * b.num();\n return Rational(num, deno);\n}\ninline Rational Rational::operator+=(const Rational &x) {\n *this = *this + x;\n return *this;\n}\ninline Rational Rational::operator+=(long long x) {\n *this = *this + Rational(x);\n return *this;\n}\ninline Rational Rational::operator-=(const Rational &x) {\n *this = *this - x;\n return *this;\n}\ninline Rational Rational::operator-=(long long x) {\n *this = *this - Rational(x);\n return *this;\n}\ninline Rational Rational::operator*=(const Rational &x) {\n *this = *this * x;\n return *this;\n}\ninline Rational Rational::operator*=(long long x) {\n *this = *this * Rational(x);\n return *this;\n}\ninline Rational Rational::operator/=(const Rational &x) {\n *this = *this / x;\n return *this;\n}\ninline Rational Rational::operator/=(long long x) {\n *this = *this / Rational(x);\n return *this;\n}\ninline ostream &operator<<(ostream &os, const Rational &f) {\n os << f.num();\n if (f.deno() != 1) os << \"/\" << f.deno();\n return os;\n}\n\nnamespace std {\ntemplate <>\nstruct hash<Rational> {\n size_t operator()(const Rational &f) const {\n size_t seed = 0;\n // メンバ変数の数だけ行う\n auto num_hash = hash<long long>()(f.num());\n seed ^= num_hash + 0x9e3779b9 + (seed << 6) + (seed >> 2);\n auto deno_hash = hash<long long>()(f.deno());\n seed ^= deno_hash + 0x9e3779b9 + (seed << 6) + (seed >> 2);\n\n return seed;\n }\n};\n} // namespace std\n\nvoid solve(int p, int q, int a, int n) {\n auto dfs = [&](auto dfs, Rational cur, int mi_deno, int prod, int cnt) -> int {\n if (cur.num() == 0) return 1;\n if (cur.num() < 0) return 0;\n if (cnt >= n) return 0;\n\n int res = 0;\n for (int deno = mi_deno; deno * prod <= a; deno++) {\n res += dfs(dfs, cur - Rational(1, deno), deno, deno * prod, cnt + 1);\n }\n return res;\n };\n cout << dfs(dfs, Rational(p, q), 1, 1, 0) << endl;\n}\n\nint main() {\n bokusunny;\n int p, q, a, n;\n while (cin >> p >> q >> a >> n) {\n if (p == 0 && q == 0 && a == 0 && n == 0) break;\n solve(p, q, a, n);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3220, "score_of_the_acc": -0.2598, "final_rank": 6 }, { "submission_id": "aoj_1131_6053853", "code_snippet": "#include<iostream>\n#include<set>\n#include<cmath>\nusing namespace std;\nconst double eps=1e-10;\nset<multiset<int> >ans;\nset<multiset<int> >processed;\nint p,q,a,n;\nvoid solve(multiset<int>now_solution,double remain,int product)\n{\n //if(processed.find(now_solution)!=processed.end())\n // return;\n if(abs(remain)<eps)\n {\n ans.insert(now_solution);\n return;\n }\n //for(int i=1;product*i<=a&&\n //(int)now_solution.size()+1<=n;++i)\n int nowstep=(int)now_solution.size();\n for(int i=a/product;\n nowstep+1<=n\n &&(remain-(double)1/i>0||abs(remain-(double)1/i)<eps);\n --i)\n {\n double max_remain=remain-(double)(n-nowstep)*1/i;\n if(max_remain>0&&abs(max_remain)>eps)\n continue;\n multiset<int>new_solution=now_solution;\n new_solution.insert(i);\n solve(new_solution,remain-(double)1/i,product*i);\n }\n //processed.insert(now_solution);\n}\nint main()\n{\n while(scanf(\"%d%d%d%d\",&p,&q,&a,&n),p||q||a||n)\n {\n ans.clear();\n processed.clear();\n multiset<int>tmp;\n solve(tmp,(double)p/q,1);\n printf(\"%d\\n\",(int)ans.size());\n }\n}\n//293 144 6748 7", "accuracy": 1, "time_ms": 360, "memory_kb": 3332, "score_of_the_acc": -0.5459, "final_rank": 14 }, { "submission_id": "aoj_1131_6017946", "code_snippet": "#line 1 \"fractional.test.cpp\"\n#define PROBLEM \\\n \"https://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=1131&lang=jp\"\n\n#line 2 \"/home/arc/project/comppro/cplib/math/fractional.cpp\"\n\n#include <cmath>\n#include <ostream>\n\n#line 2 \"/home/arc/project/comppro/cplib/math/gcd.cpp\"\n#include <cstdint>\n#include <utility>\n\nint64_t GCD(int64_t a, int64_t b) {\n if (a < b)\n std::swap(a, b);\n int r;\n while (1) {\n r = a % b;\n if (r == 0) {\n return b;\n } else {\n a = b;\n b = r;\n }\n }\n}\n#line 7 \"/home/arc/project/comppro/cplib/math/fractional.cpp\"\n/**\n * @brief 有理数 p/qを表すライブラリ\n *\n */\nstruct Fractional {\n int64_t p, q;\n\n /**\n * @brief pが負になるようにして通分する\n *\n * @return Fractional\n */\n Fractional normalize() noexcept {\n if (p == 0) {\n q = 1;\n return *this;\n }\n\n if (q < 0) {\n p *= -1;\n q *= -1;\n }\n // int64_t gcd = GCD(abs(p), abs(q));\n // p /= gcd;\n // q /= gcd;\n return *this;\n }\n\n Fractional() = default;\n Fractional(int64_t _p, int64_t _q = 1) : p(_p), q(_q) {\n normalize();\n }\n\n inline long double toDouble() const {\n return (long double)p / q;\n }\n\n inline Fractional operator-() const {\n return Fractional(-p, q);\n }\n\n inline Fractional& operator+=(const Fractional& f) {\n int64_t np = p * f.q + q * f.p, nq = q * f.q;\n p = np;\n q = nq;\n normalize();\n return *this;\n }\n\n inline Fractional& operator-=(const Fractional& f) {\n int64_t np = p * f.q - q * f.p, nq = q * f.q;\n p = np;\n q = nq;\n normalize();\n return *this;\n }\n\n inline Fractional& operator*=(const Fractional& f) {\n p *= f.p;\n q *= f.q;\n normalize();\n return *this;\n }\n\n inline Fractional& operator/=(const Fractional& f) {\n p *= f.q;\n q *= f.p;\n normalize();\n return *this;\n }\n\n inline friend std::ostream& operator<<(std::ostream& stream,\n const Fractional& f) {\n stream << f.p << \"/\" << f.q;\n return stream;\n }\n};\n\ninline Fractional operator+(const Fractional& a, const Fractional& b) {\n return Fractional(a) += b;\n}\n\ninline Fractional operator-(const Fractional& a, const Fractional& b) {\n return Fractional(a) -= b;\n}\n\ninline Fractional operator*(const Fractional& a, const Fractional& b) {\n return Fractional(a) *= b;\n}\n\ninline Fractional operator/(const Fractional& a, const Fractional& b) {\n return Fractional(a) /= b;\n}\n\ninline bool operator==(const Fractional& a, const Fractional& b) {\n return a.p * b.q == a.q * b.p;\n}\n\ninline bool operator!=(const Fractional& a, const Fractional& b) {\n return !(a == b);\n}\n\ninline bool operator<(const Fractional& a, const Fractional& b) {\n return a.p * b.q < a.q * b.p;\n}\n\ninline bool operator>(const Fractional& a, const Fractional& b) {\n return b < a;\n}\n\ninline bool operator<=(const Fractional& a, const Fractional& b) {\n return a.p * b.q <= a.q * b.p;\n}\n\ninline bool operator>=(const Fractional& a, const Fractional& b) {\n return b <= a;\n}\n#line 5 \"fractional.test.cpp\"\n\n#include <iostream>\n\nusing namespace std;\n\nint solve(Fractional frac, int a, int product, int n, int start) {\n if (frac == Fractional(0, 1)) {\n return 1;\n }\n if (n == 0) {\n return 0;\n }\n\n int res = 0;\n for (int v = start; v <= a; v++) {\n if (product * v > a) break;\n Fractional f(1, v);\n Fractional remain = frac - f;\n if (remain < Fractional(0, 1)) continue;\n res += solve(remain, a, product * v, n - 1, v);\n }\n return res;\n}\n\nint main(void) {\n while (true) {\n int p, q, a, n;\n cin >> p >> q >> a >> n;\n if (p == 0) break;\n cout << solve(Fractional(p, q), a, 1, n, 1) << endl;\n }\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3200, "score_of_the_acc": -0.1774, "final_rank": 5 }, { "submission_id": "aoj_1131_5997298", "code_snippet": "#include <iostream>\n\ntemplate <typename T> class Rational {\n T num, den;\n\n static T my_gcd(T x_, T y_) {\n unsigned long long x = x_ < 0 ? -x_ : x_, y = y_ < 0 ? -y_ : y_;\n if (!x or !y) return x + y;\n int n = __builtin_ctzll(x), m = __builtin_ctzll(y);\n x >>= n, y >>= m;\n while (x != y) {\n if (x > y)\n x = (x - y) >> __builtin_ctzll(x - y);\n else\n y = (y - x) >> __builtin_ctzll(y - x);\n }\n return x << (n > m ? m : n);\n }\n\n void normalize() {\n return; // comment out this flexibly\n T g = my_gcd(num, den);\n num /= g, den /= g;\n if (den < 0) num = -num, den = -den;\n }\n\npublic:\n Rational() {}\n Rational(T num) : num(num), den(T(1)) {}\n Rational(T num, T den) : num(num), den(den) { normalize(); }\n\n Rational operator+(const Rational& r) const { return Rational(num * r.den + den * r.num, den * r.den); }\n Rational operator-(const Rational& r) const { return Rational(num * r.den - den * r.num, den * r.den); }\n Rational operator*(const Rational& r) const { return Rational(num * r.num, den * r.den); }\n Rational operator/(const Rational& r) const { return Rational(num * r.den, den * r.num); }\n Rational& operator+=(const Rational& r) { return *this = *this + r; }\n Rational& operator-=(const Rational& r) { return *this = *this - r; }\n Rational& operator*=(const Rational& r) { return *this = *this * r; }\n Rational& operator/=(const Rational& r) { return *this = *this / r; }\n\n Rational operator+(const T& val) const { return *this + Rational(val); }\n Rational operator-(const T& val) const { return *this - Rational(val); }\n Rational operator*(const T& val) const { return *this * Rational(val); }\n Rational operator/(const T& val) const { return *this / Rational(val); }\n Rational& operator+=(const T& val) { return *this = *this + val; }\n Rational& operator-=(const T& val) { return *this = *this - val; }\n Rational& operator*=(const T& val) { return *this = *this * val; }\n Rational& operator/=(const T& val) { return *this = *this / val; }\n friend Rational operator+(const T& val, const Rational& r) { return r + val; }\n friend Rational operator-(const T& val, const Rational& r) { return r - val; }\n friend Rational operator*(const T& val, const Rational& r) { return r * val; }\n friend Rational operator/(const T& val, const Rational& r) { return r / val; }\n\n Rational operator-() const { return Rational(-num, den); }\n Rational abs() const { return Rational(num < 0 ? -num : num, den); }\n\n bool operator==(const Rational& r) const {\n if (den == 0 and r.den == 0) return num == r.num;\n if (den == 0 or r.den == 0) return false;\n return num * r.den == den * r.num;\n }\n bool operator!=(const Rational& r) const { return !(*this == r); }\n bool operator<(const Rational& r) const {\n if (den == 0 and r.den == 0) return num < r.num;\n if (den == 0) return num < 0;\n if (r.den == 0) return r.num > 0;\n return num * r.den < den * r.num;\n }\n bool operator<=(const Rational& r) const { return (*this == r) or (*this < r); }\n bool operator>(const Rational& r) const { return r < *this; }\n bool operator>=(const Rational& r) const { return (*this == r) or (*this > r); }\n\n bool operator==(const T& val) const { return *this == Rational(val); }\n bool operator!=(const T& val) const { return *this != Rational(val); }\n bool operator<(const T& val) const { return *this < Rational(val); }\n bool operator<=(const T& val) const { return *this <= Rational(val); }\n bool operator>(const T& val) const { return *this > Rational(val); }\n bool operator>=(const T& val) const { return *this >= Rational(val); }\n friend bool operator==(const T& val, const Rational& r) { return r == val; }\n friend bool operator!=(const T& val, const Rational& r) { return r != val; }\n friend bool operator<(const T& val, const Rational& r) { return r > val; }\n friend bool operator<=(const T& val, const Rational& r) { return r >= val; }\n friend bool operator>(const T& val, const Rational& r) { return r < val; }\n friend bool operator>=(const T& val, const Rational& r) { return r <= val; }\n\n explicit operator double() const { return (double)num / (double)den; }\n explicit operator long double() const { return (long double)num / (long double)den; }\n friend std::ostream& operator<<(std::ostream& os, const Rational& r) { return os << r.num << '/' << r.den; }\n};\n\n/**\n * @brief Rational Number\n * @docs docs/util/Rational.md\n */\n\nusing R = Rational<int>;\n\nint dfs(R r, int dep, int pre, int mul, int a) {\n if (dep == 0) return r == 0;\n if (r == 0) return 1;\n int res = 0;\n for (int i = a / mul; i >= pre; i--) {\n if (r < R(1, i)) break;\n res += dfs(r - R(1, i), dep - 1, i, mul * i, a);\n }\n return res;\n}\n\nvoid solve(int p, int q, int a, int n) {\n R r(p, q);\n int ans = dfs(r, n, 1, 1, a);\n std::cout << ans << '\\n';\n}\n\nint main() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(false);\n for (int p, q, a, n; std::cin >> p >> q >> a >> n, n;) solve(p, q, a, n);\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3376, "score_of_the_acc": -0.3541, "final_rank": 11 }, { "submission_id": "aoj_1131_5997287", "code_snippet": "#include <iostream>\n\ntemplate <typename T> class Rational {\n T num, den;\n\n // static T my_gcd(T x_, T y_) {\n // unsigned long long x = x_ < 0 ? -x_ : x_, y = y_ < 0 ? -y_ : y_;\n // if (!x or !y) return x + y;\n // int n = __builtin_ctzll(x), m = __builtin_ctzll(y);\n // x >>= n, y >>= m;\n // while (x != y) {\n // if (x > y)\n // x = (x - y) >> __builtin_ctzll(x - y);\n // else\n // y = (y - x) >> __builtin_ctzll(y - x);\n // }\n // return x << (n > m ? m : n);\n // }\n\n static T my_gcd(T a, T b) {\n if (a < 0) a = -a;\n if (b < 0) b = -b;\n while (a and b) {\n if (a > b)\n a %= b;\n else\n b %= a;\n }\n return a + b;\n }\n\n void normalize() {\n return;\n T g = my_gcd(num, den);\n num /= g, den /= g;\n if (den < 0) num = -num, den = -den;\n }\n\npublic:\n Rational() {}\n Rational(T num) : num(num), den(T(1)) {}\n Rational(T num, T den) : num(num), den(den) { normalize(); }\n\n Rational operator+(const Rational& r) const { return Rational(num * r.den + den * r.num, den * r.den); }\n Rational operator-(const Rational& r) const { return Rational(num * r.den - den * r.num, den * r.den); }\n Rational operator*(const Rational& r) const { return Rational(num * r.num, den * r.den); }\n Rational operator/(const Rational& r) const { return Rational(num * r.den, den * r.num); }\n Rational& operator+=(const Rational& r) { return *this = *this + r; }\n Rational& operator-=(const Rational& r) { return *this = *this - r; }\n Rational& operator*=(const Rational& r) { return *this = *this * r; }\n Rational& operator/=(const Rational& r) { return *this = *this / r; }\n\n Rational operator+(const T& val) const { return *this + Rational(val); }\n Rational operator-(const T& val) const { return *this - Rational(val); }\n Rational operator*(const T& val) const { return *this * Rational(val); }\n Rational operator/(const T& val) const { return *this / Rational(val); }\n Rational& operator+=(const T& val) { return *this = *this + val; }\n Rational& operator-=(const T& val) { return *this = *this - val; }\n Rational& operator*=(const T& val) { return *this = *this * val; }\n Rational& operator/=(const T& val) { return *this = *this / val; }\n friend Rational operator+(const T& val, const Rational& r) { return r + val; }\n friend Rational operator-(const T& val, const Rational& r) { return r - val; }\n friend Rational operator*(const T& val, const Rational& r) { return r * val; }\n friend Rational operator/(const T& val, const Rational& r) { return r / val; }\n\n Rational operator-() const { return Rational(-num, den); }\n Rational abs() const { return Rational(num < 0 ? -num : num, den); }\n\n bool operator==(const Rational& r) const {\n if (den == 0 and r.den == 0) return num == r.num;\n if (den == 0 or r.den == 0) return false;\n return num * r.den == den * r.num;\n }\n bool operator!=(const Rational& r) const { return !(*this == r); }\n bool operator<(const Rational& r) const {\n if (den == 0 and r.den == 0) return num < r.num;\n if (den == 0) return num < 0;\n if (r.den == 0) return r.num > 0;\n return num * r.den < den * r.num;\n }\n bool operator<=(const Rational& r) const { return (*this == r) or (*this < r); }\n bool operator>(const Rational& r) const { return r < *this; }\n bool operator>=(const Rational& r) const { return (*this == r) or (*this > r); }\n\n bool operator==(const T& val) const { return *this == Rational(val); }\n bool operator!=(const T& val) const { return *this != Rational(val); }\n bool operator<(const T& val) const { return *this < Rational(val); }\n bool operator<=(const T& val) const { return *this <= Rational(val); }\n bool operator>(const T& val) const { return *this > Rational(val); }\n bool operator>=(const T& val) const { return *this >= Rational(val); }\n friend bool operator==(const T& val, const Rational& r) { return r == val; }\n friend bool operator!=(const T& val, const Rational& r) { return r != val; }\n friend bool operator<(const T& val, const Rational& r) { return r > val; }\n friend bool operator<=(const T& val, const Rational& r) { return r >= val; }\n friend bool operator>(const T& val, const Rational& r) { return r < val; }\n friend bool operator>=(const T& val, const Rational& r) { return r <= val; }\n\n explicit operator double() const { return (double)num / (double)den; }\n explicit operator long double() const { return (long double)num / (long double)den; }\n friend std::ostream& operator<<(std::ostream& os, const Rational& r) { return os << r.num << '/' << r.den; }\n};\n\n/**\n * @brief Rational Number\n * @docs docs/util/Rational.md\n */\n\nusing R = Rational<int>;\n\nint dfs(R r, int dep, int pre, int mul, int a) {\n if (dep == 0) return r == 0;\n if (r == 0) return 1;\n int res = 0;\n for (int i = a / mul; i >= pre; i--) {\n if (r < R(1, i)) break;\n res += dfs(r - R(1, i), dep - 1, i, mul * i, a);\n }\n return res;\n}\n\nvoid solve(int p, int q, int a, int n) {\n R r(p, q);\n int ans = dfs(r, n, 1, 1, a);\n std::cout << ans << '\\n';\n}\n\nint main() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(false);\n for (int p, q, a, n; std::cin >> p >> q >> a >> n, n;) solve(p, q, a, n);\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3456, "score_of_the_acc": -0.414, "final_rank": 12 }, { "submission_id": "aoj_1131_5997286", "code_snippet": "#include <iostream>\n\ntemplate <typename T> class Rational {\n T num, den;\n\n static T my_gcd(T x_, T y_) {\n unsigned long long x = x_ < 0 ? -x_ : x_, y = y_ < 0 ? -y_ : y_;\n if (!x or !y) return x + y;\n int n = __builtin_ctzll(x), m = __builtin_ctzll(y);\n x >>= n, y >>= m;\n while (x != y) {\n if (x > y)\n x = (x - y) >> __builtin_ctzll(x - y);\n else\n y = (y - x) >> __builtin_ctzll(y - x);\n }\n return x << (n > m ? m : n);\n }\n\n void normalize() {\n return;\n T g = my_gcd(num, den);\n num /= g, den /= g;\n if (den < 0) num = -num, den = -den;\n }\n\npublic:\n Rational() {}\n Rational(T num) : num(num), den(T(1)) {}\n Rational(T num, T den) : num(num), den(den) { normalize(); }\n\n Rational operator+(const Rational& r) const { return Rational(num * r.den + den * r.num, den * r.den); }\n Rational operator-(const Rational& r) const { return Rational(num * r.den - den * r.num, den * r.den); }\n Rational operator*(const Rational& r) const { return Rational(num * r.num, den * r.den); }\n Rational operator/(const Rational& r) const { return Rational(num * r.den, den * r.num); }\n Rational& operator+=(const Rational& r) { return *this = *this + r; }\n Rational& operator-=(const Rational& r) { return *this = *this - r; }\n Rational& operator*=(const Rational& r) { return *this = *this * r; }\n Rational& operator/=(const Rational& r) { return *this = *this / r; }\n\n Rational operator+(const T& val) const { return *this + Rational(val); }\n Rational operator-(const T& val) const { return *this - Rational(val); }\n Rational operator*(const T& val) const { return *this * Rational(val); }\n Rational operator/(const T& val) const { return *this / Rational(val); }\n Rational& operator+=(const T& val) { return *this = *this + val; }\n Rational& operator-=(const T& val) { return *this = *this - val; }\n Rational& operator*=(const T& val) { return *this = *this * val; }\n Rational& operator/=(const T& val) { return *this = *this / val; }\n friend Rational operator+(const T& val, const Rational& r) { return r + val; }\n friend Rational operator-(const T& val, const Rational& r) { return r - val; }\n friend Rational operator*(const T& val, const Rational& r) { return r * val; }\n friend Rational operator/(const T& val, const Rational& r) { return r / val; }\n\n Rational operator-() const { return Rational(-num, den); }\n Rational abs() const { return Rational(num < 0 ? -num : num, den); }\n\n bool operator==(const Rational& r) const {\n if (den == 0 and r.den == 0) return num == r.num;\n if (den == 0 or r.den == 0) return false;\n return num * r.den == den * r.num;\n }\n bool operator!=(const Rational& r) const { return !(*this == r); }\n bool operator<(const Rational& r) const {\n if (den == 0 and r.den == 0) return num < r.num;\n if (den == 0) return num < 0;\n if (r.den == 0) return r.num > 0;\n return num * r.den < den * r.num;\n }\n bool operator<=(const Rational& r) const { return (*this == r) or (*this < r); }\n bool operator>(const Rational& r) const { return r < *this; }\n bool operator>=(const Rational& r) const { return (*this == r) or (*this > r); }\n\n bool operator==(const T& val) const { return *this == Rational(val); }\n bool operator!=(const T& val) const { return *this != Rational(val); }\n bool operator<(const T& val) const { return *this < Rational(val); }\n bool operator<=(const T& val) const { return *this <= Rational(val); }\n bool operator>(const T& val) const { return *this > Rational(val); }\n bool operator>=(const T& val) const { return *this >= Rational(val); }\n friend bool operator==(const T& val, const Rational& r) { return r == val; }\n friend bool operator!=(const T& val, const Rational& r) { return r != val; }\n friend bool operator<(const T& val, const Rational& r) { return r > val; }\n friend bool operator<=(const T& val, const Rational& r) { return r >= val; }\n friend bool operator>(const T& val, const Rational& r) { return r < val; }\n friend bool operator>=(const T& val, const Rational& r) { return r <= val; }\n\n explicit operator double() const { return (double)num / (double)den; }\n explicit operator long double() const { return (long double)num / (long double)den; }\n friend std::ostream& operator<<(std::ostream& os, const Rational& r) { return os << r.num << '/' << r.den; }\n};\n\n/**\n * @brief Rational Number\n * @docs docs/util/Rational.md\n */\n\nusing R = Rational<int>;\n\nint dfs(R r, int dep, int pre, int mul, int a) {\n if (dep == 0) return r == 0;\n if (r == 0) return 1;\n int res = 0;\n for (int i = a / mul; i >= pre; i--) {\n if (r < R(1, i)) break;\n res += dfs(r - R(1, i), dep - 1, i, mul * i, a);\n }\n return res;\n}\n\nvoid solve(int p, int q, int a, int n) {\n R r(p, q);\n int ans = dfs(r, n, 1, 1, a);\n std::cout << ans << '\\n';\n}\n\nint main() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(false);\n for (int p, q, a, n; std::cin >> p >> q >> a >> n, n;) solve(p, q, a, n);\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3308, "score_of_the_acc": -0.3032, "final_rank": 10 }, { "submission_id": "aoj_1131_5625781", "code_snippet": "#include <iostream>\n\nusing namespace std;\n\nint p, q, a, n, ans;\n\nvoid func(int numer, int denom, int pre, int mlt, int count)\n{\n\tif (p * denom == q * numer) {\n\t\tans++;\n\t\treturn;\n\t}\n\n\tif (n == count) return;\n\tif (q * numer > p * denom) return;\n\n\tfor (int i = pre; mlt * i < a + 1; i++) func(numer * i + denom, denom * i, i, mlt * i, count + 1);\n}\n\nint main()\n{\n\twhile (cin >> p >> q >> a >> n) {\n\t\tif (!p && !q && !a && !n) break;\n\t\tans = 0;\n\t\tfunc(0, 1, 1, 1, 0);\n\t\tcout << ans << endl;\n\t}\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3364, "score_of_the_acc": -0.2665, "final_rank": 8 }, { "submission_id": "aoj_1131_5625780", "code_snippet": "#include <iostream>\n\nusing namespace std;\n\nint p, q, a, n, ans;\n\nvoid func(int numer, int denom, int pre, int mlt, int count)\n{\n\tif (p * denom == q * numer) {\n\t\tans++;\n\t\treturn;\n\t}\n\n\tif (n == count) return;\n\t//if (q * numer > p * denom) return;\n\n\tfor (int i = pre; mlt * i < a + 1; i++) func(numer * i + denom, denom * i, i, mlt * i, count + 1);\n}\n\nint main()\n{\n\twhile (cin >> p >> q >> a >> n) {\n\t\tif (!p && !q && !a && !n) break;\n\t\tans = 0;\n\t\tfunc(0, 1, 1, 1, 0);\n\t\tcout << ans << endl;\n\t}\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 3360, "score_of_the_acc": -0.6455, "final_rank": 16 }, { "submission_id": "aoj_1131_5374021", "code_snippet": "#include <iostream>\nusing namespace std;\n\nint a;\n\nint dfs(int p, int q, int seki, int bunbo, int n){\n \n if(p == 0 && n >= 0) return 1;\n if(n == 0) return 0;\n \n int res = 0;\n for(int i=bunbo; seki*i <= a; i++){\n int np = p*i-q;\n int nq = q*i;\n if(np < 0) continue;\n res += dfs(np, nq, seki*i, i, n-1);\n }\n \n return res;\n}\n\nint main()\n{\n int p, q, n;\n while(cin >> p >> q >> a >> n, p!=0){\n cout << dfs(p, q, 1, 1, n) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3008, "score_of_the_acc": -0.0337, "final_rank": 1 } ]
aoj_1139_cpp
Problem E: Earth Observation with a Mobile Robot Team A new type of mobile robot has been developed for environmental earth observation. It moves around on the ground, acquiring and recording various sorts of observational data using high precision sensors. Robots of this type have short range wireless communication devices and can exchange observational data with ones nearby. They also have large capacity memory units, on which they record data observed by themselves and those received from others. Figure 1 illustrates the current positions of three robots A, B, and C and the geographic coverage of their wireless devices. Each circle represents the wireless coverage of a robot, with its center representing the position of the robot. In this figure, two robots A and B are in the positions where A can transmit data to B, and vice versa. In contrast, C cannot communicate with A or B, since it is too remote from them. Still, however, once B moves towards C as in Figure 2, B and C can start communicating with each other. In this manner, B can relay observational data from A to C. Figure 3 shows another example, in which data propagate among several robots instantaneously. Figure 1: The initial configuration of three robots Figure 2: Mobile relaying Figure 3: Instantaneous relaying among multiple robots As you may notice from these examples, if a team of robots move properly, observational data quickly spread over a large number of them. Your mission is to write a program that simulates how information spreads among robots. Suppose that, regardless of data size, the time necessary for communication is negligible. Input The input consists of multiple datasets, each in the following format. N T R nickname and travel route of the first robot nickname and travel route of the second robot ... nickname and travel route of the N-th robot The first line contains three integers N , T , and R that are the number of robots, the length of the simulation period, and the maximum distance wireless signals can reach, respectively, and satisfy that 1 <= N <= 100, 1 <= T <= 1000, and 1 <= R <= 10. The nickname and travel route of each robot are given in the following format. nickname t 0 x 0 y 0 t 1 vx 1 vy 1 t 2 vx 2 vy 2 ... t k vx k vy k Nickname is a character string of length between one and eight that only contains lowercase letters. No two robots in a dataset may have the same nickname. Each of the lines following nickname contains three integers, satisfying the following conditions. 0 = t 0 < t 1 < ... < t k = T -10 <= vx 1 , vy 1 , ..., vx k , vy k <= 10 A robot moves around on a two dimensional plane. ( x 0 , y 0 ) is the location of the robot at time 0. From time t i -1 to t i (0 < i <= k ), the velocities in the x and y directions are vx i and vy i , respectively. Therefore, the travel route of a robot is piecewise linear. Note that it may self-overlap or self-intersect. You may assume that each dataset satisfies the following conditions. The distance bet ...(truncated)
[ { "submission_id": "aoj_1139_9672115", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vi;\ntypedef vector<vi> vvi;\ntypedef long double ld;\ntypedef pair<ll,ll> pi;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\n#define F first\n#define S second\ntemplate<typename T>bool chmin(T&a,T b){if(a>b){a=b;return 1;}return 0;}\ntemplate<typename T>bool chmax(T&a,T b){if(a<b){a=b;return 1;}return 0;}\ntemplate<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;\nint main(){\n while(1){\n ll N,T,R;cin>>N>>T>>R;\n if(!N)return 0;\n vector<vector<pi>>A(N,vector<pi>(T+1));\n vector<string>name(N);\n REP(i,N){\n cin>>name[i];\n ll t,x,y;cin>>t>>x>>y;\n A[i][0]=pi(x,y);\n while(t!=T){\n int _t,vx,vy;cin>>_t>>vx>>vy;\n FOR(j,t+1,_t+1)A[i][j]=pi(A[i][j-1].F+vx,A[i][j-1].S+vy);\n t=_t;\n }\n }\n vector<ld>DP(N,1e18);\n DP[0]=0;\n min_priority_queue<pair<ld,ll>>Q;\n Q.emplace(make_pair(0,0));\n while(!Q.empty()){\n auto[t,v]=Q.top();Q.pop();\n if(t!=DP[v])continue;\n REP(u,N)if(u!=v)REP(i,T)if(t<=i+1){\n ll x1=A[u][i].first-A[v][i].first;\n ll y1=A[u][i].second-A[v][i].second;\n ll x2=A[u][i+1].first-A[v][i+1].first;\n ll y2=A[u][i+1].second-A[v][i+1].second;\n ll a=(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);\n ll b=2*(x1*(x2-x1)+y1*(y2-y1));\n ll c=x1*x1+y1*y1-R*R;\n if(a==0){\n assert(b==0);\n if(c<=0){\n if(chmin(DP[u],max((ld)i,t)))Q.emplace(make_pair(DP[u],u));\n }\n }\n else if(b*b-4*a*c>=0){\n ld s=sqrtl(b*b-4*a*c);\n ld t1=(-b-s)/2/a+i;\n ld t2=(-b+s)/2/a+i;\n chmax(t1,(ld)i);\n chmax(t1,t);\n chmin(t2,(ld)(i+1));\n if(t1<=t2&&chmin(DP[u],t1))Q.emplace(make_pair(DP[u],u));\n }\n //at^2+bt+c<=0\n }\n }\n //for(auto i:DP)cout<<i<<\" \";cout<<endl;\n vector<string>ans;\n REP(i,N)if(DP[i]<1e17)ans.emplace_back(name[i]);\n sort(ALL(ans));\n for(auto s:ans)cout<<s<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4452, "score_of_the_acc": -0.1435, "final_rank": 7 }, { "submission_id": "aoj_1139_9397947", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\ntemplate < class T > vector< T >& operator++(vector< T >& a) { for(T& x : a) x++; return a; }\ntemplate < class T > vector< T >& operator--(vector< T >& a) { for(T& x : a) x--; return a; }\ntemplate < class T > vector< T > operator++(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x++; return res; }\ntemplate < class T > vector< T > operator--(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x--; return res; }\n\n} // namespace macro\n\nusing namespace macro;\n#line 2 \"cp-library/src/geometry/base.hpp\"\n\ntemplate < class T > struct point {\n T x, y;\n point() : x(0), y(0) {}\n point(T x, T y) : x(x), y(y) {}\n point(std::pair< T, T > p) : x(p.first), y(p.second) {}\n point& operator+=(const point& p) { x += p.x, y += p.y; return *this; }\n point& operator-=(const point& p) { x -= p.x, y -= p.y; return *this; }\n point& operator*=(const T r) { x *= r, y *= r; return *this; }\n point& operator/=(const T r) { x /= r, y /= r; return *this; }\n point operator+(const point& p) const { return point(*this) += p; }\n point operator-(const point& p) const { return point(*this) -= p; }\n point operator*(const T r) const { return point(*this) *= r; }\n point operator/(const T r) const { return point(*this) /= r; }\n point operator-() const { return {-x, -y}; }\n bool operator==(const point& p) const { return x == p.x and y == p.y; }\n bool operator!=(const point& p) const { return x != p.x or y != p.y; }\n bool operator<(const point& p) const { return x == p.x ? y < p.y : x < p.x; }\n point< T > rot(double theta) {\n static_assert(is_floating_point_v< T >);\n double cos_ = std::cos(theta), sin_ = std::sin(theta);\n return {cos_ * x - sin_ * y, sin_ * x + cos_ * y};\n }\n};\ntemplate < class T > istream& operator>>(istream& is, point< T >& p) { return is >> p.x >> p.y; }\ntemplate < class T > ostream& operator<<(ostream& os, point< T >& p) { return os << p.x << \" \" << p.y; }\ntemplate < class T > T dot(const point< T >& a, const point< T >& b) { return a.x * b.x + a.y * b.y; }\ntemplate < class T > T det(const point< T >& a, const point< T >& b) { return a.x * b.y - a.y * b.x; }\ntemplate < class T > T norm(const point< T >& p) { return p.x * p.x + p.y * p.y; }\ntemplate < class T > double abs(const point< T >& p) { return std::sqrt(norm(p)); }\ntemplate < class T > double angle(const point< T >& p) { return std::atan2(p.y, p.x); }\ntemplate < class T > int sign(const T x) {\n T e = (is_integral_v< T > ? 1 : 1e-8);\n if(x <= -e) return -1;\n if(x >= +e) return +1;\n return 0;\n}\ntemplate < class T > bool equals(const T& a, const T& b) { return sign(a - b) == 0; }\ntemplate < class T > int ccw(const point< T >& a, point< T > b, point< T > c) {\n b -= a, c -= a;\n if(sign(det(b, c)) == +1) return +1; // counter clockwise\n if(sign(det(b, c)) == -1) return -1; // clockwise\n if(sign(dot(b, c)) == -1) return +2; // c-a-b\n if(norm(b) < norm(c)) return -2; // a-b-c\n return 0; // a-c-b\n}\n\ntemplate < class T > struct line {\n point< T > a, b;\n line() {}\n line(point< T > a, point< T > b) : a(a), b(b) {}\n};\ntemplate < class T > point< T > projection(const line< T >& l, const point< T >& p) {\n static_assert(is_floating_point_v< T >);\n return l.a + (l.a - l.b) * dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n}\ntemplate < class T > point< T > reflection(const line< T >& l, const point< T >& p) {\n static_assert(is_floating_point_v< T >);\n return p + (projection(l, p) - p) * T(2);\n}\ntemplate < class T > bool orthogonal(const line< T >& a, const line< T >& b) { return equals(dot(a.b - a.a, b.b - b.a), T(0)); }\ntemplate < class T > bool parallel (const line< T >& a, const line< T >& b) { return equals(det(a.b - a.a, b.b - b.a), T(0)); }\ntemplate < class T > point< T > cross_point_ll(const line< T >& l, const line< T >& m) {\n static_assert(is_floating_point_v< T >);\n T A = det(l.b - l.a, m.b - m.a);\n T B = det(l.b - l.a, l.b - m.a);\n if(equals(abs(A), T(0)) and equals(abs(B), T(0))) return m.a;\n return m.a + (m.b - m.a) * B / A;\n}\n\ntemplate < class T > using segment = line< T >;\ntemplate < class T > bool intersect_ss(const segment< T >& s, const segment< T >& t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 and ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\ntemplate < class T > double distance_sp(const segment< T >& s, const point< T >& p) {\n static_assert(is_floating_point_v< T >);\n point r = projection(s, p);\n if(ccw(s.a, s.b, r) == 0) return abs(r - p);\n return std::min(abs(s.a - p), abs(s.b - p));\n}\ntemplate < class T > double distance_ss(const segment< T >& a, const segment< T >& b) {\n if(intersect_ss(a, b)) return 0;\n return std::min({ distance_sp(a, b.a), distance_sp(a, b.b), distance_sp(b, a.a), distance_sp(b, a.b) });\n}\n\ntemplate < class T > using polygon = std::vector< point< T > >;\ntemplate < class T > T area2(const polygon< T >& p) {\n T s = 0;\n int n = p.size();\n for(int i = 0; i < n; i++) s += det(p[i], p[(i + 1) % n]);\n return s;\n}\ntemplate < class T > T area(const polygon< T >& p) { return area2(p) / T(2); }\n\ntemplate < class T > bool is_convex(const polygon< T >& p) {\n int n = p.size();\n for(int i = 0; i < n; i++) if(ccw(p[(i - 1 + n) % n], p[i], p[(i + 1) % n]) == -1) return false;\n return true;\n}\ntemplate < class T > int contains(const polygon< T >& g, const point< T >& p) {\n int n = g.size();\n bool in = false;\n for(int i = 0; i < n; i++) {\n point a = g[i] - p, b = g[(i + 1) % n] - p;\n if(sign(a.y - b.y) == +1) std::swap(a, b);\n if(sign(a.y) <= 0 and sign(b.y) ==+1 and sign(det(a, b)) == -1) in = !in;\n if(sign(det(a, b)) == 0 and sign(dot(a, b)) <= 0) return 1; // ON\n }\n return in ? 2 : 0;\n}\ntemplate < class T > polygon< T > convex_cut(const polygon< T >& p, const line< T >& l) {\n int n = p.size();\n polygon< T > res;\n for(int i = 0; i < n; i++) {\n point now = p[i], nxt = p[(i + 1) % n];\n if(ccw(l.a, l.b, now) != -1) res.push_back(now);\n if(ccw(l.a, l.b, now) * ccw(l.a, l.b, nxt) < 0) res.push_back(cross_point_ll(line(now, nxt), l));\n }\n return res;\n}\ntemplate < class T > polygon< T > convex_hull(polygon< T >& p) {\n int n = p.size(), k = 0;\n if(n <= 2) return p;\n std::sort(p.begin(), p.end());\n polygon< T > ch(n + n);\n for(int i = 0; i < n; ch[k++] = p[i++])\n while(k >= 2 and sign(det(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1])) == -1) k--;\n for(int i = n - 2, t = k + 1; i >= 0; ch[k++] = p[i--])\n while(k >= t and sign(det(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1])) == -1) k--;\n ch.resize(k - 1);\n return ch;\n}\ntemplate < class T > T diameter2(const polygon< T >& p) {\n static_assert(is_floating_point_v< T >);\n int n = p.size(), is = 0, js = 0;\n for(int i = 1; i < n; i++) {\n if(sign(p[i].y - p[is].y) == +1) is = i;\n if(sign(p[i].y - p[js].y) == -1) js = i;\n }\n T dist_max = norm(p[is] - p[js]);\n int maxi = is, i = is, maxj = js, j = js;\n do {\n if(sign(det(p[(i + 1) % n] - p[i], p[(j + 1) % n] - p[j])) >= 0) j = (j + 1) % n; else i = (i + 1) % n;\n if(norm(p[i] - p[j]) > dist_max) {\n dist_max = norm(p[i] - p[j]);\n maxi = i, maxj = j;\n }\n } while(i != is or j != js);\n return dist_max;\n}\ntemplate < class T > double diameter(const polygon< T >& p) {\n static_assert(is_floating_point_v< T >);\n return std::sqrt(diameter2(p));\n}\n\ntemplate < class T > struct circle {\n point< T > p;\n T r;\n circle() = default;\n circle(point< T > p, T r) : p(p), r(r) {}\n};\ntemplate < class T > istream& operator>>(istream& is, circle< T >& c) { return is >> c.p >> c.r; }\ntemplate < class T > int intersect_cc(circle< T > c1, circle< T > c2) {\n if(c1.r < c2.r) std::swap(c1, c2);\n T d = abs(c1.p - c2.p);\n if(sign(c1.r + c2.r - d) == -1) return 4;\n if(equals(c1.r + c2.r, d)) return 3;\n if(sign(c1.r - c2.r - d) == -1) return 2;\n if(equals(c1.r - c2.r, d)) return 1;\n return 0;\n}\ntemplate < class T > std::pair<point< T >, point< T >> cross_point_cc(const circle< T >& c1, const circle< T >& c2) {\n T d = abs(c1.p - c2.p);\n T a = std::acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d));\n T t = angle(c2.p - c1.p);\n point< T > p1 = c1.p + point< T >(std::cos(t + a), std::sin(t + a)) * c1.r;\n point< T > p2 = c1.p + point< T >(std::cos(t - a), std::sin(t - a)) * c1.r;\n return {p1, p2};\n}\n#line 4 \"A.cpp\"\n\nconst f64 eps = 1e-8;\n\nvector<f64> quad(f64 a, f64 b, f64 c) {\n if(abs(a) < eps) {\n if(abs(b) < eps) {\n return {};\n } else {\n return {- c / b};\n }\n } else {\n f64 D = b * b - 4.0 * a * c;\n if(D < 0) return {};\n return {\n (- b - sqrt(D)) / (2.0 * a), \n (- b + sqrt(D)) / (2.0 * a)\n };\n }\n}\n\n\nvoid solve(int N, int T, int R) {\n vector<string> nickname(N);\n vector p(N, vector(T + 1, point<f64>(0, 0)));\n for(int i : rep(N)) {\n cin >> nickname[i];\n int t, x, y; cin >> t >> x >> y;\n p[i][t] = point<f64>(x, y);\n\n int pt = t;\n while(true) {\n cin >> t >> x >> y;\n point<f64> v(x, y);\n for(int now : rep(pt, t)) p[i][now + 1] = p[i][now] + v;\n pt = t;\n if(t == T) break;\n }\n }\n\n vector<tuple<f64,int,int,int>> event;\n for(int i : rep(N)) for(int j : rep(N)) if(i != j) {\n vector<f64> ts;\n if(abs(p[i][0] - p[j][0]) <= R + eps) ts.push_back(0);\n for(int t : rep(T)) {\n point<f64> dp = p[i][t] - p[j][t];\n point<f64> dv = (p[i][t + 1] - p[i][t]) - (p[j][t + 1] - p[j][t]);\n f64 a = norm(dv);\n f64 b = dot(dv, dp) * 2.0;\n f64 c = norm(dp) - R * R;\n for(f64 dt : quad(a, b, c)) if(- eps < dt and dt < 1 + eps) ts.push_back(t + dt);\n }\n unique(ts);\n int exist = 0;\n for(f64 t : ts) {\n exist ^= 1;\n event.push_back({t, exist, i, j});\n }\n }\n sort(event);\n\n vector graph(N, vector(N, 0));\n for(int i : rep(N)) for(int j : rep(N)) if(i != j) {\n if(abs(p[i][0] - p[j][0]) <= R + eps) graph[i][j] = true;\n }\n \n vector<int> ans(N, 0);\n ans[0] = true;\n for(auto [t, q, u, v] : event) {\n graph[u][v] = graph[v][u] = q;\n if(q) {\n if(ans[u] != ans[v]) {\n queue<int> que;\n que.push(u);\n que.push(v);\n while(not que.empty()) {\n int x = que.front(); que.pop();\n if(ans[x]) continue;\n ans[x] = true;\n for(int nx : rep(N)) if(graph[x][nx] and not ans[nx]) que.push(nx);\n }\n }\n }\n }\n\n vector<string> name;\n for(int i : rep(N)) if(ans[i]) name.push_back(nickname[i]);\n sort(name);\n print_n(name);\n}\n\nint main() {\n while(true) {\n int N, T, R; cin >> N >> T >> R;\n if(N == 0) return 0;\n solve(N, T, R);\n }\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 6452, "score_of_the_acc": -0.3174, "final_rank": 14 }, { "submission_id": "aoj_1139_9397943", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\ntemplate < class T > vector< T >& operator++(vector< T >& a) { for(T& x : a) x++; return a; }\ntemplate < class T > vector< T >& operator--(vector< T >& a) { for(T& x : a) x--; return a; }\ntemplate < class T > vector< T > operator++(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x++; return res; }\ntemplate < class T > vector< T > operator--(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x--; return res; }\n\n} // namespace macro\n\nusing namespace macro;\n#line 2 \"cp-library/src/geometry/base.hpp\"\n\ntemplate < class T > struct point {\n T x, y;\n point() : x(0), y(0) {}\n point(T x, T y) : x(x), y(y) {}\n point(std::pair< T, T > p) : x(p.first), y(p.second) {}\n point& operator+=(const point& p) { x += p.x, y += p.y; return *this; }\n point& operator-=(const point& p) { x -= p.x, y -= p.y; return *this; }\n point& operator*=(const T r) { x *= r, y *= r; return *this; }\n point& operator/=(const T r) { x /= r, y /= r; return *this; }\n point operator+(const point& p) const { return point(*this) += p; }\n point operator-(const point& p) const { return point(*this) -= p; }\n point operator*(const T r) const { return point(*this) *= r; }\n point operator/(const T r) const { return point(*this) /= r; }\n point operator-() const { return {-x, -y}; }\n bool operator==(const point& p) const { return x == p.x and y == p.y; }\n bool operator!=(const point& p) const { return x != p.x or y != p.y; }\n bool operator<(const point& p) const { return x == p.x ? y < p.y : x < p.x; }\n point< T > rot(double theta) {\n static_assert(is_floating_point_v< T >);\n double cos_ = std::cos(theta), sin_ = std::sin(theta);\n return {cos_ * x - sin_ * y, sin_ * x + cos_ * y};\n }\n};\ntemplate < class T > istream& operator>>(istream& is, point< T >& p) { return is >> p.x >> p.y; }\ntemplate < class T > ostream& operator<<(ostream& os, point< T >& p) { return os << p.x << \" \" << p.y; }\ntemplate < class T > T dot(const point< T >& a, const point< T >& b) { return a.x * b.x + a.y * b.y; }\ntemplate < class T > T det(const point< T >& a, const point< T >& b) { return a.x * b.y - a.y * b.x; }\ntemplate < class T > T norm(const point< T >& p) { return p.x * p.x + p.y * p.y; }\ntemplate < class T > double abs(const point< T >& p) { return std::sqrt(norm(p)); }\ntemplate < class T > double angle(const point< T >& p) { return std::atan2(p.y, p.x); }\ntemplate < class T > int sign(const T x) {\n T e = (is_integral_v< T > ? 1 : 1e-8);\n if(x <= -e) return -1;\n if(x >= +e) return +1;\n return 0;\n}\ntemplate < class T > bool equals(const T& a, const T& b) { return sign(a - b) == 0; }\ntemplate < class T > int ccw(const point< T >& a, point< T > b, point< T > c) {\n b -= a, c -= a;\n if(sign(det(b, c)) == +1) return +1; // counter clockwise\n if(sign(det(b, c)) == -1) return -1; // clockwise\n if(sign(dot(b, c)) == -1) return +2; // c-a-b\n if(norm(b) < norm(c)) return -2; // a-b-c\n return 0; // a-c-b\n}\n\ntemplate < class T > struct line {\n point< T > a, b;\n line() {}\n line(point< T > a, point< T > b) : a(a), b(b) {}\n};\ntemplate < class T > point< T > projection(const line< T >& l, const point< T >& p) {\n static_assert(is_floating_point_v< T >);\n return l.a + (l.a - l.b) * dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n}\ntemplate < class T > point< T > reflection(const line< T >& l, const point< T >& p) {\n static_assert(is_floating_point_v< T >);\n return p + (projection(l, p) - p) * T(2);\n}\ntemplate < class T > bool orthogonal(const line< T >& a, const line< T >& b) { return equals(dot(a.b - a.a, b.b - b.a), T(0)); }\ntemplate < class T > bool parallel (const line< T >& a, const line< T >& b) { return equals(det(a.b - a.a, b.b - b.a), T(0)); }\ntemplate < class T > point< T > cross_point_ll(const line< T >& l, const line< T >& m) {\n static_assert(is_floating_point_v< T >);\n T A = det(l.b - l.a, m.b - m.a);\n T B = det(l.b - l.a, l.b - m.a);\n if(equals(abs(A), T(0)) and equals(abs(B), T(0))) return m.a;\n return m.a + (m.b - m.a) * B / A;\n}\n\ntemplate < class T > using segment = line< T >;\ntemplate < class T > bool intersect_ss(const segment< T >& s, const segment< T >& t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 and ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\ntemplate < class T > double distance_sp(const segment< T >& s, const point< T >& p) {\n static_assert(is_floating_point_v< T >);\n point r = projection(s, p);\n if(ccw(s.a, s.b, r) == 0) return abs(r - p);\n return std::min(abs(s.a - p), abs(s.b - p));\n}\ntemplate < class T > double distance_ss(const segment< T >& a, const segment< T >& b) {\n if(intersect_ss(a, b)) return 0;\n return std::min({ distance_sp(a, b.a), distance_sp(a, b.b), distance_sp(b, a.a), distance_sp(b, a.b) });\n}\n\ntemplate < class T > using polygon = std::vector< point< T > >;\ntemplate < class T > T area2(const polygon< T >& p) {\n T s = 0;\n int n = p.size();\n for(int i = 0; i < n; i++) s += det(p[i], p[(i + 1) % n]);\n return s;\n}\ntemplate < class T > T area(const polygon< T >& p) { return area2(p) / T(2); }\n\ntemplate < class T > bool is_convex(const polygon< T >& p) {\n int n = p.size();\n for(int i = 0; i < n; i++) if(ccw(p[(i - 1 + n) % n], p[i], p[(i + 1) % n]) == -1) return false;\n return true;\n}\ntemplate < class T > int contains(const polygon< T >& g, const point< T >& p) {\n int n = g.size();\n bool in = false;\n for(int i = 0; i < n; i++) {\n point a = g[i] - p, b = g[(i + 1) % n] - p;\n if(sign(a.y - b.y) == +1) std::swap(a, b);\n if(sign(a.y) <= 0 and sign(b.y) ==+1 and sign(det(a, b)) == -1) in = !in;\n if(sign(det(a, b)) == 0 and sign(dot(a, b)) <= 0) return 1; // ON\n }\n return in ? 2 : 0;\n}\ntemplate < class T > polygon< T > convex_cut(const polygon< T >& p, const line< T >& l) {\n int n = p.size();\n polygon< T > res;\n for(int i = 0; i < n; i++) {\n point now = p[i], nxt = p[(i + 1) % n];\n if(ccw(l.a, l.b, now) != -1) res.push_back(now);\n if(ccw(l.a, l.b, now) * ccw(l.a, l.b, nxt) < 0) res.push_back(cross_point_ll(line(now, nxt), l));\n }\n return res;\n}\ntemplate < class T > polygon< T > convex_hull(polygon< T >& p) {\n int n = p.size(), k = 0;\n if(n <= 2) return p;\n std::sort(p.begin(), p.end());\n polygon< T > ch(n + n);\n for(int i = 0; i < n; ch[k++] = p[i++])\n while(k >= 2 and sign(det(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1])) == -1) k--;\n for(int i = n - 2, t = k + 1; i >= 0; ch[k++] = p[i--])\n while(k >= t and sign(det(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1])) == -1) k--;\n ch.resize(k - 1);\n return ch;\n}\ntemplate < class T > T diameter2(const polygon< T >& p) {\n static_assert(is_floating_point_v< T >);\n int n = p.size(), is = 0, js = 0;\n for(int i = 1; i < n; i++) {\n if(sign(p[i].y - p[is].y) == +1) is = i;\n if(sign(p[i].y - p[js].y) == -1) js = i;\n }\n T dist_max = norm(p[is] - p[js]);\n int maxi = is, i = is, maxj = js, j = js;\n do {\n if(sign(det(p[(i + 1) % n] - p[i], p[(j + 1) % n] - p[j])) >= 0) j = (j + 1) % n; else i = (i + 1) % n;\n if(norm(p[i] - p[j]) > dist_max) {\n dist_max = norm(p[i] - p[j]);\n maxi = i, maxj = j;\n }\n } while(i != is or j != js);\n return dist_max;\n}\ntemplate < class T > double diameter(const polygon< T >& p) {\n static_assert(is_floating_point_v< T >);\n return std::sqrt(diameter2(p));\n}\n\ntemplate < class T > struct circle {\n point< T > p;\n T r;\n circle() = default;\n circle(point< T > p, T r) : p(p), r(r) {}\n};\ntemplate < class T > istream& operator>>(istream& is, circle< T >& c) { return is >> c.p >> c.r; }\ntemplate < class T > int intersect_cc(circle< T > c1, circle< T > c2) {\n if(c1.r < c2.r) std::swap(c1, c2);\n T d = abs(c1.p - c2.p);\n if(sign(c1.r + c2.r - d) == -1) return 4;\n if(equals(c1.r + c2.r, d)) return 3;\n if(sign(c1.r - c2.r - d) == -1) return 2;\n if(equals(c1.r - c2.r, d)) return 1;\n return 0;\n}\ntemplate < class T > std::pair<point< T >, point< T >> cross_point_cc(const circle< T >& c1, const circle< T >& c2) {\n T d = abs(c1.p - c2.p);\n T a = std::acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d));\n T t = angle(c2.p - c1.p);\n point< T > p1 = c1.p + point< T >(std::cos(t + a), std::sin(t + a)) * c1.r;\n point< T > p2 = c1.p + point< T >(std::cos(t - a), std::sin(t - a)) * c1.r;\n return {p1, p2};\n}\n#line 4 \"A.cpp\"\n\nconst f64 eps = 1e-8;\n\nvector<f64> quad(f64 a, f64 b, f64 c) {\n if(abs(a) < eps) {\n if(abs(b) < eps) {\n return {};\n } else {\n return {- c / b};\n }\n } else {\n f64 D = b * b - 4.0 * a * c;\n if(D < 0) return {};\n return {\n (- b - sqrt(D)) / (2.0 * a), \n (- b + sqrt(D)) / (2.0 * a)\n };\n }\n}\n\n\nvoid solve(int N, int T, int R) {\n vector<string> nickname(N);\n vector p(N, vector(T + 1, point<f64>(0, 0)));\n for(int i : rep(N)) {\n cin >> nickname[i];\n int t, x, y; cin >> t >> x >> y;\n p[i][t] = point<f64>(x, y);\n\n int prev = t;\n while(true) {\n cin >> t >> x >> y;\n point<f64> v(x, y);\n for(int now : rep(prev, t)) p[i][now + 1] = p[i][now] + v;\n prev = t;\n if(t == T) break;\n }\n }\n\n vector<tuple<f64,int,int,int>> event;\n for(int i : rep(N)) for(int j : rep(N)) if(i != j) {\n vector<f64> ts;\n if(abs(p[i][0] - p[j][0]) <= R + eps) ts.push_back(0);\n for(int t : rep(T)) {\n point<f64> dp = p[i][t] - p[j][t];\n point<f64> dv = (p[i][t + 1] - p[i][t]) - (p[j][t + 1] - p[j][t]);\n f64 a = norm(dv);\n f64 b = dot(dv, dp) * 2.0;\n f64 c = norm(dp) - R * R;\n for(f64 dt : quad(a, b, c)) if(- eps < dt and dt < 1 + eps) ts.push_back(t + dt);\n }\n unique(ts);\n int exist = 0;\n for(f64 t : ts) {\n exist ^= 1;\n event.push_back({t, exist, i, j});\n }\n }\n sort(event);\n\n vector graph(N, vector(N, 0));\n for(int i : rep(N)) for(int j : rep(N)) if(i != j) {\n if(abs(p[i][0] - p[j][0]) <= R + eps) {\n graph[i][j] = true;\n }\n }\n vector<int> ans(N, 0);\n ans[0] = true;\n for(auto [t, q, u, v] : event) {\n graph[u][v] = graph[v][u] = q;\n if(q) {\n if(ans[u] != ans[v]) {\n queue<int> que;\n que.push(u);\n que.push(v);\n while(not que.empty()) {\n int x = que.front(); que.pop();\n if(ans[x]) continue;\n ans[x] = true;\n for(int nx : rep(N)) if(graph[x][nx] and not ans[nx]) que.push(nx);\n }\n }\n }\n }\n\n vector<string> name;\n for(int i : rep(N)) if(ans[i]) name.push_back(nickname[i]);\n sort(name);\n print_n(name);\n}\n\nint main() {\n while(true) {\n int N, T, R; cin >> N >> T >> R;\n if(N == 0) return 0;\n solve(N, T, R);\n }\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 6376, "score_of_the_acc": -0.3139, "final_rank": 13 }, { "submission_id": "aoj_1139_6033391", "code_snippet": "#include<cstdio>\n#include<cstdlib>\n#include<cmath>\n#include<cassert>\n#include<sstream>\n#include<iostream>\n#include<string>\n#include<vector>\n#include<queue>\n#include<set>\n#include<map>\n#include<utility>\n#include<numeric>\n#include<algorithm>\n#include<bitset>\n#include<complex>\n#include<cstring>\n\nusing namespace std;\n\ntypedef pair<int,int> pint;\ntypedef pair<double,double> Point;\n\nint INF=1001001001;\n\ndouble dis2(Point p1, Point p2){\n return (p1.first-p2.first)*(p1.first-p2.first)+(p1.second-p2.second)*(p1.second-p2.second);\n}\nPoint linedist00(double x, double y, double vx, double vy){\n double l=(x*vy-y*vx)/(vx*vx+vy*vy);\n return Point(l * vy, -l * vx);\n}\npair<double,double > culc(double r,double x,double y,double vx,double vy){\n Point p2=linedist00(x, y, vx, vy);\n double vv= dis2(Point(0, 0), Point(vx, vy));\n double d2= dis2(Point(0, 0), p2);\n if(d2 <= r*r){\n double l=r*r-d2;\n double t;\n if(vx==0 && vy==0) return make_pair(INF, INF);\n else if(vx==0) t= (p2.second-y)/vy;\n else t= (p2.first-x)/vx;\n double dt=sqrt(l/vv);\n return make_pair(t-dt, t+dt);\n }else{\n return make_pair(INF, INF);\n }\n}\nstruct str{\n double t;\n pint p;\n int f;\n str(double t0,pint p0,int f0){\n t=t0; p=p0; f=f0;\n }\n};\nbool operator < (str a,str b){\n return a.t>b.t;\n}\nvoid prints(str a){\n printf(\"t=%f %d---%d %d\\n\",a.t,a.p.first,a.p.second,a.f);\n}\nsigned main(){\n\n#ifdef LOCAL\n freopen(\"input.txt\", \"r\", stdin);\n freopen(\"output.txt\", \"w\", stdout);\n#endif\n\n int i,j,k;\n int n,t,r;\n Point xy[100];\n pair<int,int> v[100][1000];\n string name[1000];\n int vis[100];\n while(true){\n cin >> n >> t >> r;\n if(n==0) break;\n for(i=0;i<100;i++){\n vis[i]=0;\n for(j=0;j<1000;j++){\n v[i][j]=pint(INF,INF);\n }\n }\n for(i=0;i<n;i++){\n cin >> name[i];\n cin >> k >> xy[i].first >> xy[i].second;\n while(true){\n int tk,vx,vy;\n scanf(\"%d%d%d\",&tk,&vx,&vy);\n v[i][tk-1].first=vx;\n v[i][tk-1].second=vy;\n if(tk==t) break;\n }\n }\n for(k=0;k<n;k++){\n pint tmp=v[k][t-1];\n for(i=t-2;i>=0;i--){\n if(v[k][i].first==INF) v[k][i]=tmp;\n else tmp=v[k][i];\n }\n }\n int a[100][100];\n //未移动时的相交情况\n for(j=0;j<n;j++){\n for(k=0;k<n;k++){\n if(dis2(xy[j], xy[k]) <= r * r) a[j][k]=1;\n else a[j][k]=0;\n }\n }\n queue<int> q;\n q.push(0);\n while(!q.empty()){\n int f=q.front(); q.pop();\n if(vis[f] == 1) continue;\n else{\n vis[f]=1;\n for(i=0;i<n;i++){\n if(a[f][i]==1) q.push(i);\n }\n }\n }\n for(i=0;i<t;i++){\n priority_queue<str> pq;\n for(j=0;j<n;j++){\n for(k=j+1;k<n;k++){\n int x1=xy[k].first-xy[j].first,y1=xy[k].second-xy[j].second;\n int vx=v[k][i].first-v[j][i].first,vy=v[k][i].second-v[j][i].second;\n pair<double,double > time=culc(r,x1,y1,vx,vy);\n if(time.first==INF) continue;\n double t1=INF,t2=INF;\n if(time.first >= 0.0){\n if(time.second <= 1.0){\n t1=time.first;\n t2=time.second;\n }else if(time.first <= 1.0){\n t1=time.first;\n }\n }else{\n if(time.second>=0 && time.second<=1.0){\n t2=time.second;\n }\n }\n if(t1!=INF) pq.push(str(t1,pint(j,k),1));\n if(t2!=INF) pq.push(str(t2,pint(j,k),0));\n }\n }\n while(!pq.empty()){\n str tmp=pq.top(); pq.pop();\n// prints(tmp);\n a[tmp.p.first][tmp.p.second]=tmp.f;\n a[tmp.p.second][tmp.p.first]=tmp.f;\n if(tmp.f==1){\n if(vis[tmp.p.first] == 0 && vis[tmp.p.second] == 1) swap(tmp.p.first, tmp.p.second);\n if(vis[tmp.p.first] == 1 && vis[tmp.p.second] == 0){\n queue<int> q2;\n q2.push(tmp.p.second);\n vis[tmp.p.second]=1;\n while(!q2.empty()){\n k=q2.front();\n q2.pop();\n for(j=0;j<n;j++){\n if(a[j][k]==1 && vis[j] == 0){\n vis[j]=1;\n q2.push(j);\n }\n }\n }\n }\n }\n }\n for(j=0;j<n;j++){\n xy[j].first+=v[j][i].first;\n xy[j].second+=v[j][i].second;\n }\n }\n\n vector<string> ans;\n int cnt=0;\n for(i=0;i<n;i++){\n if(vis[i] == 1){\n ans.push_back(name[i]);\n cnt++;\n }\n }\n sort(ans.begin(),ans.end());\n for(i=0;i<cnt;i++){\n cout << ans[i] << endl;\n }\n\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4436, "score_of_the_acc": -0.1577, "final_rank": 8 }, { "submission_id": "aoj_1139_6026850", "code_snippet": "#include<bits/stdc++.h> \nusing namespace std;\nusing ll=long long int;\n//using Int=__int128;\n#define ALL(A) A.begin(),A.end()\ntemplate<typename T1,typename T2> bool chmin(T1 &a,T2 b){if(a<=b)return 0; a=b; return 1;}\ntemplate<typename T1,typename T2> bool chmax(T1 &a,T2 b){if(a>=b)return 0; a=b; return 1;}\ntemplate<typename T> constexpr int bitUP(T x,int a){return (x>>a)&1;}\n//→ ↓ ← ↑ \nint dh[4]={0,1,0,-1}, dw[4]={1,0,-1,0};\n//右上から時計回り\n//int dh[8]={-1,0,1,1,1,0,-1,-1}, dw[8]={1,1,1,0,-1,-1,-1,0};\n//long double EPS = 1e-6;\n//long double PI = acos(-1);\n//const ll INF=(1LL<<62);\nconst int MAX=(1<<30);\nconstexpr ll MOD=1000000000+7;\n//constexpr ll MOD=998244353;\n\n\ninline void bin101(){\n ios::sync_with_stdio(false);\n cin.tie(0);\n cout << fixed << setprecision(20);\n}\n\nusing pii=pair<int,int>;\nusing pil=pair<int,ll>;\nusing pli=pair<ll,int>;\nusing pll=pair<ll,ll>;\nusing psi=pair<string,int>;\nusing pis=pair<int,string>;\nusing psl=pair<string,ll>;\nusing pls=pair<ll,string>;\nusing pss=pair<string,string>;\n\nusing Graph=vector<vector<int>>;\n\ntemplate<typename T >\nstruct edge {\n\tint to;\n\tT cost;\n\tedge()=default;\n\tedge(int to, T cost) : to(to), cost(cost) {}\n\n};\ntemplate<typename T>\nusing WeightGraph=vector<vector<edge<T>>>;\n\ntemplate<typename T>\nvoid CinGraph(int M,WeightGraph<T> &g,bool directed=false,bool index1=true){\n while(M--){\n int s,t;\n T cost;\n cin>>s>>t>>cost;\n if(index1) s--,t--;\n g[s].emplace_back(t,cost);\n if(not directed) g[t].emplace_back(s,cost);\n }\n}\n\nvoid CinGraph(int M,Graph &g,bool directed=false,bool index1=true){\n while(M--){\n int s,t;\n cin>>s>>t;\n if(index1) s--,t--;\n g[s].push_back(t);\n if(not directed) g[t].push_back(s);\n }\n}\n\n\n//0-indexed vector cin\ntemplate<typename T>\ninline istream &operator>>(istream &is,vector<T> &v) {\n for(size_t i=0;i<v.size();i++) is>>v[i];\n\treturn is;\n}\n \n//0-indexed vector cin\ntemplate<typename T>\ninline istream &operator>>(istream &is,vector<vector<T>> &v) {\n for(size_t i=0;i<v.size();i++){\n is>>v[i];\n }\n return is;\n}\n//vector cout\ntemplate<typename T>\ninline ostream &operator<<(ostream &os,const vector<T> &v) {\n for(size_t i=0;i<v.size();i++){\n if(i) os<<\" \";\n os<<v[i];\n }\n return os;\n}\n//vector<vector> cout\ntemplate<typename T>\ninline ostream &operator<<(ostream &os,const vector<vector<T>> &v) {\n for(size_t i=0;i<v.size();i++){\n os<<v[i];\n if(i+1!=v.size()) os<<\"\\n\";\n }\n return os;\n}\n\n//Graph out\ntemplate<typename T>\ninline ostream &operator<<(ostream &os,const Graph &g) {\n for(size_t i=0;i<g.size();i++){\n for(int to:g[i]){\n os<<i<<\"->\"<<to<<\" \";\n }\n os<<endl;\n }\n return os;\n}\n\n//WeightGraph out\ntemplate<typename T>\ninline ostream &operator<<(ostream &os,const WeightGraph<T> &g) {\n for(size_t i=0;i<g.size();i++){\n for(auto e:g[i]){\n os<<i<<\"->\"<<e.to<<\"(\"<<e.cost<<\") \";\n }\n os<<endl;\n }\n return os;\n}\n\n\n//要素数n 初期値x\ntemplate<typename T>\ninline vector<T> vmake(size_t n,T x){\n\treturn vector<T>(n,x);\n}\n\n//a,b,c,x data[a][b][c] 初期値x\ntemplate<typename... Args>\nauto vmake(size_t n,Args... args){\n\tauto v=vmake(args...);\n\treturn vector<decltype(v)>(n,move(v));\n}\ntemplate<typename V,typename T>\nvoid fill(V &v,const T value){\n v=value;\n}\n\ntemplate<typename V,typename T>\nvoid fill(vector<V> &vec,const T value){\n for(auto &v:vec) fill(v,value);\n}\n\n//pair cout\ntemplate<typename T, typename U>\ninline ostream &operator<<(ostream &os,const pair<T,U> &p) {\n\tos<<p.first<<\" \"<<p.second;\n\treturn os;\n}\n \n//pair cin\ntemplate<typename T, typename U>\ninline istream &operator>>(istream &is,pair<T,U> &p) {\n\tis>>p.first>>p.second;\n\treturn is;\n}\n \n//ソート\ntemplate<typename T>\ninline void vsort(vector<T> &v){\n sort(v.begin(),v.end());\n}\n \n//逆順ソート\ntemplate<typename T>\ninline void rvsort(vector<T> &v){\n\tsort(v.rbegin(),v.rend());\n}\n\n//1ビットの数を返す\ninline int popcount(int x){\n\treturn __builtin_popcount(x);\n}\n//1ビットの数を返す\ninline int popcount(ll x){\n\treturn __builtin_popcountll(x);\n}\ntemplate<typename T>\ninline void Compress(vector<T> &C){\n sort(C.begin(),C.end());\n C.erase(unique(C.begin(),C.end()),C.end());\n}\ntemplate<typename T>\ninline int lower_idx(const vector<T> &C,T value){\n return lower_bound(C.begin(),C.end(),value)-C.begin();\n}\ntemplate<typename T>\ninline int upper_idx(const vector<T> &C,T value){\n return upper_bound(C.begin(),C.end(),value)-C.begin();\n}\n//時計回りに90度回転\ntemplate<typename T>\ninline void rotate90(vector<vector<T>> &C){\n vector<vector<T>> D(C[0].size(),vector<T>(C.size()));\n for(int h=0;h<C.size();h++){\n for(int w=0;w<C[h].size();w++){\n D[w][C.size()-1-h]=C[h][w];\n }\n }\n C=D;\n}\n//補グラフを返す\n//i→iのような辺は加えない\nGraph ComplementGraph(const Graph &g){\n size_t sz=g.size();\n bool used[sz][sz];\n fill(used[0],used[sz],false);\n for(size_t i=0;i<sz;i++){\n for(int to:g[i]){\n used[i][to]=true;\n }\n }\n Graph ret(sz);\n for(size_t i=0;i<sz;i++){\n for(size_t j=0;j<sz;j++){\n if(used[i][j]) continue;\n if(i==j) continue;\n ret[i].push_back(j);\n }\n }\n return ret;\n}\n//グラフの分解 secondはある頂点がどこに対応するか id[i]={2,3}のとき,頂点iはret[2][3]に対応\n//無効グラフのみに対応\npair<vector<Graph>,vector<pair<int,int>>> GraphDecomposition(const Graph &g){\n vector<pair<int,int>> id(g.size(),pair<int,int>(-1,-1));\n vector<Graph> ret;\n vector<int> now;\n for(size_t i=0;i<g.size();i++){\n if(id[i].first!=-1) continue;\n id[i].first=ret.size();\n id[i].second=0;\n now.push_back(i);\n for(size_t j=0;j<now.size();j++){\n for(int to:g[now[j]]){\n if(id[to].first==-1){\n id[to].first=ret.size();\n id[to].second=now.size();\n now.push_back(to);\n }\n }\n }\n Graph r(now.size());\n for(size_t j=0;j<now.size();j++){\n r[j]=g[now[j]];\n for(int &to:r[j]){\n to=id[to].second;\n }\n }\n ret.push_back(r);\n now.clear();\n }\n return make_pair(ret,id);\n}\n//0indexを想定\nbool OutGrid(ll h,ll w,ll H,ll W){\n return (h>=H or w>=W or h<0 or w<0);\n}\n\nvoid NO(){\n cout<<\"NO\"<<\"\\n\";\n}\nvoid YES(){\n cout<<\"YES\"<<\"\\n\";\n}\nvoid No(){\n cout<<\"No\"<<\"\\n\";\n}\nvoid Yes(){\n cout<<\"Yes\"<<\"\\n\";\n}\nnamespace overflow{\n template<typename T>\n T max(){\n return numeric_limits<T>::max();\n }\n template<typename T>\n T ADD(T a,T b){\n T res;\n return __builtin_add_overflow(a,b,&res)?max<T>():res;\n }\n template<typename T>\n T MUL(T a,T b){\n T res;\n return __builtin_mul_overflow(a,b,&res)?max<T>():res;\n }\n};\nusing namespace overflow;\nstruct ModInt{\n using u64=uint_fast64_t;\n u64 a;\n constexpr ModInt() :a(0){}\n constexpr ModInt(ll x) :a((x>=0)?(x%MOD):(x%MOD+MOD) ) {}\n\n inline constexpr ModInt operator+(const ModInt rhs)const noexcept{\n return ModInt(*this)+=rhs;\n }\n inline constexpr ModInt operator-(const ModInt rhs)const noexcept{\n return ModInt(*this)-=rhs;\n }\n inline constexpr ModInt operator*(const ModInt rhs)const noexcept{\n return ModInt(*this)*=rhs;\n }\n inline constexpr ModInt operator/(const ModInt rhs)const noexcept{\n return ModInt(*this)/=rhs;\n }\n inline constexpr ModInt operator+(const ll rhs) const noexcept{\n return ModInt(*this)+=ModInt(rhs);\n }\n inline constexpr ModInt operator-(const ll rhs)const noexcept{\n return ModInt(*this)-=ModInt(rhs);\n }\n inline constexpr ModInt operator*(const ll rhs)const noexcept{\n return ModInt(*this)*=ModInt(rhs);\n }\n inline constexpr ModInt operator/(const ll rhs)const noexcept{\n return ModInt(*this)/=ModInt(rhs);\n }\n\n inline constexpr ModInt &operator+=(const ModInt rhs)noexcept{\n a+=rhs.a;\n if(a>=MOD) a-=MOD;\n return *this;\n }\n inline constexpr ModInt &operator-=(const ModInt rhs)noexcept{\n if(rhs.a>a) a+=MOD;\n a-=rhs.a;\n return *this;\n }\n inline constexpr ModInt &operator*=(const ModInt rhs)noexcept{\n a=(a*rhs.a)%MOD;\n return *this;\n }\n inline constexpr ModInt &operator/=(ModInt rhs)noexcept{\n a=(a*rhs.inverse().a)%MOD;\n return *this;\n }\n inline constexpr ModInt &operator+=(const ll rhs)noexcept{\n return *this+=ModInt(rhs);\n }\n inline constexpr ModInt &operator-=(const ll rhs)noexcept{\n return *this-=ModInt(rhs);\n }\n inline constexpr ModInt &operator*=(const ll rhs)noexcept{\n return *this*=ModInt(rhs);\n }\n inline constexpr ModInt &operator/=(const ll rhs)noexcept{\n return *this/=ModInt(rhs);\n }\n\n inline constexpr ModInt operator=(const ll x)noexcept{\n a=(x>=0)?(x%MOD):(x%MOD+MOD);\n return *this;\n }\n\n inline constexpr bool operator==(const ModInt p)const noexcept{\n return a==p.a;\n }\n\n inline constexpr bool operator!=(const ModInt p)const noexcept{\n return a!=p.a;\n }\n\n inline constexpr ModInt pow(ll N) const noexcept{\n ModInt ans(1LL),p(a);\n while(N>0){\n if(bitUP(N,0)){\n ans*=p;\n }\n p*=p;\n N>>=1;\n }\n return ans;\n }\n inline constexpr ModInt inverse() const noexcept{\n return pow(MOD-2);\n }\n\n};\ninline constexpr ModInt operator+(const ll &a,const ModInt &b)noexcept{\n return ModInt(a)+=b;\n}\ninline constexpr ModInt operator-(const ll &a,const ModInt &b)noexcept{\n return ModInt(a)-=b;\n}\ninline constexpr ModInt operator*(const ll &a,const ModInt &b)noexcept{\n return ModInt(a)*=b;\n}\ninline constexpr ModInt operator/(const ll &a,const ModInt &b)noexcept{\n return ModInt(a)/=b;\n}\n//cout\ninline ostream &operator<<(ostream &os,const ModInt &p) {\n return os<<p.a;\n}\n\n//cin\ninline istream &operator>>(istream &is,ModInt &p) {\n ll t;\n is>>t;\n p=t;\n return is;\n}\n\nstruct Binominal{\n vector<ModInt> fac,finv,inv; //fac[n]:n! finv:(n!)の逆元\n int sz;\n Binominal(int n=10) :sz(1){\n if(n<=0) n=10;\n init(n);\n }\n inline void init(int n){\n fac.resize(n+1,1);\n finv.resize(n+1,1);\n inv.resize(n+1,1);\n for(int i=sz+1;i<=n;i++){\n fac[i]=fac[i-1]*i;\n inv[i]=MOD-inv[MOD%i]*(MOD/i);\n finv[i]=finv[i-1]*inv[i];\n }\n sz=n;\n }\n //nCk(n,k<=N) をO(1)で求める\n inline ModInt com(int n,int k){\n if(n<k) return ModInt(0);\n if(n<0 || k<0) return ModInt(0);\n if(n>sz) init(n);\n return fac[n]*finv[k]*finv[n-k];\n }\n //nCk(k<=N) をO(k) で求める \n inline ModInt rcom(ll n,int k){\n if(n<0 || k<0 || n<k) return ModInt(0);\n if(k>sz) init(k);\n ModInt ret(1);\n for(int i=0;i<k;i++){\n ret*=n-i;\n }\n ret*=finv[k];\n return ret;\n }\n\n //重複組み合わせ n種類のものから重複を許してk個を選ぶ\n //〇がn個,|がk個\n inline ModInt h(int n,int k){\n return com(n+k-1,k);\n }\n};\nvector<int> Subset(int S,bool zero=false,bool full=false){\n vector<int> ret;\n int now=(S-1)&S;\n if(full and S){\n ret.push_back(S);\n }\n do{\n ret.push_back(now);\n now=(now-1)&S;\n }while(now!=0);\n if(zero){\n ret.push_back(0);\n }\n return ret;\n}\ntemplate<typename T>\nT SUM(const vector<T> &v,int s,int t){\n chmax(s,0);\n chmin(t,int(v.size())-1);\n if(s>t) return 0;\n if(s==0) return v[t];\n else return v[t]-v[s-1];\n}\ntemplate<typename T>\nvoid buildSUM(vector<T> &v){\n for(size_t i=1;i<v.size();i++){\n v[i]+=v[i-1];\n }\n return;\n}\n////////////////////////////\n// マクロや型\n////////////////////////////\n\nusing DD=long double;\n\nconst DD EPS=1e-14;\nconst DD INF=1e50;\nconst DD PI=acosl(-1.0);\n#define EQ(a,b) (abs( (a) - (b) )<EPS) //a==b\n#define LS(a,b) ( (a)+EPS<(b) ) //a<b\n#define GR(a,b) ( (a)>(b)+EPS ) //a>b\n#define LE(a,b) ( (a)<(b)+EPS ) //a<=b\n#define GE(a,b) ( (a)>(b)-EPS ) //a>=b\n\n#define X real()\n#define Y imag()\n\n\n//点\nusing Point=complex<DD>;\nistream &operator>>(istream &is, Point &p) {\n DD x,y;\n is>>x>>y;\n p=Point(x,y);\n return is;\n}\nvoid debug(Point p,string name=\"\"){\n cout<<p.X<<\" \"<<p.Y<<\" \"<<name<<endl;\n}\n\n//点a→点bの線分\n//aとbが等しい時、色々バグるから注意!\nstruct Segment{\n Point a,b;\n Segment()=default;\n Segment(Point a,Point b) :a(a),b(b){}\n Segment(DD ax,DD ay,DD bx,DD by):a(ax,ay),b(bx,by){}\n Segment(DD r,Point a) :a(a),b(a+polar((DD)1.0,r)){}\n void debug(bool isLine=false,string name=\"\"){\n string type=\"Segment \";\n if(isLine) type=\"Line \";\n cout<<type<<a.X<<\" \"<<a.Y<<\" \"<<b.X<<\" \"<<b.Y<<\" \"<<name<<endl;\n }\n};\nusing Line=Segment;\n\n//円\nstruct Circle{\n Point p;\n DD r;\n Circle()=default;\n Circle(Point p,DD r):p(p),r(r){}\n void debug(string name=\"\"){\n cout<<\"Circle \"<<p.X<<\" \"<<p.Y<<\" \"<<r<<\" \"<<name<<endl;\n }\n};\n\nusing Polygon=vector<Point>;\nvoid debug(Polygon pol,string name=\"\"){\n cout<<\"Polygon\"<<\" \"<<name<<endl;\n for(auto p:pol){\n cout<<p.X<<\" \"<<p.Y<<endl;\n }\n cout<<\"...\"<<endl;\n}\n\n////////////////////////////\n// 基本計算\n////////////////////////////\n\n//度→ラジアン\ninline DD torad(const DD deg){return deg*PI/180;}\n//ラジアン→度\ninline DD todeg(const DD rad){return rad*180/PI;}\n//内積 |a||b|cosθ\ninline DD dot(const Point &a,const Point &b){return (conj(a)*b).X;}\n//外積 |a||b|sinθ\ninline DD cross(const Point &a,const Point &b){return (conj(a)*b).Y;}\n//ベクトルpを反時計回りにtheta(ラジアン)回転\nPoint rotate(const Point &p,const DD theta){return p*Point(cos(theta),sin(theta));}\n\n//余弦定理 cos(角度abc(ラジアン))を返す\n//長さの対応に注意 ab:辺abの長さ\n//verify:https://codeforces.com/gym/102056/problem/F\nDD cosine_formula(const DD ab,const DD bc,const DD ca){\n return (ab*ab+bc*bc-ca*ca)/(2*ab*bc);\n}\n\ninline bool xy_sort(const Point &a,const Point &b){\n if(a.X+EPS<b.X) return true;\n if(EQ(a.X,b.X) && a.Y+EPS<b.Y) return true;\n return false;\n}\ninline bool yx_sort(const Point &a,const Point &b){\n if(a.Y+EPS<b.Y) return true;\n if(EQ(a.Y,b.Y) && a.X+EPS<b.X) return true;\n return false;\n}\nnamespace std{\n inline bool operator<(const Point &a,const Point &b)noexcept{\n return xy_sort(a,b);\n }\n}\n//DDの比較関数\n//map<DD,vector<pii>,DDcom>\nstruct DDcom{\n bool operator()(const DD a, const DD b) const noexcept {\n return a+EPS<b;\n }\n};\n\n\n////////////////////////////\n// 平行や直交\n////////////////////////////\n\nbool isOrthogonal(const Point &a,const Point &b){\n return EQ(dot(a,b),0.0);\n}\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_A\nbool isOrthogonal(const Segment &s,const Segment &t){\n return EQ(dot(s.a-s.b,t.a-t.b),0.0);\n}\nbool isParallel(const Point &a,const Point &b){\n return EQ(cross(a,b),0.0);\n}\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_A\nbool isParallel(const Segment &s,const Segment &t){\n return EQ(cross(s.a-s.b,t.a-t.b),0);\n}\n//線分a→bに対して点cがどの位置にあるか\n//反時計回り:1 時計回り:-1 直線上(a,b,c:-2 a,c,b:0 c,a,b:2)\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_C\n//線分a→bの端点にcがあるなら0と判定されるはず\nint ccw(const Point &a,Point b,Point c){\n if(EQ(abs(b-c),0) or EQ(abs(a-c),0)) return 0;\n b-=a;c-=a;\n if(cross(b,c)>EPS) return 1;\n if(cross(b,c)<-EPS) return -1;\n if(dot(b,c)<-EPS) return 2;\n if(LS(norm(b),norm(c))) return -2;\n return 0;\n}\n\n////////////////////////////\n// 射影と反射\n////////////////////////////\n\n//射影\n//直線lに点pから垂線を引いたときの交点\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_A\nPoint project(const Point &p,const Line &l){\n Point base=l.b-l.a;\n DD r=dot(p-l.a,base)/norm(base);\n return l.a+base*r;\n}\n//反射\n//直線lに対して点pと対称な点\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_B\nPoint reflect(const Point &p,const Line &l){\n return p+(project(p,l)-p)*(DD)2.0;\n}\n//反射\n//直線lに対して線分sと対称な線分(直線でも使える)\n//verify:https://onlinejudge.u-aizu.ac.jp/solutions/problem/1171/review/6009447/bin101/C++17\nSegment reflect(const Segment &s,const Line &l){\n return Segment(reflect(s.a,l) , reflect(s.b,l));\n}\n\n////////////////////////////\n// 点との距離\n////////////////////////////\n\n//点と直線の距離\nDD DistPL(const Point &p,const Line &l){\n return abs(cross(l.b-l.a,p-l.a))/abs(l.b-l.a);\n}\n//点と線分の距離\nDD DistPS(const Point &p,const Segment &s){\n if( dot(s.b-s.a,p-s.a)<0.0 ) return abs(p-s.a);\n if( dot(s.a-s.b,p-s.b)<0.0 ) return abs(p-s.b);\n return DistPL(p,s);\n}\n\n////////////////////////////\n// 線分と直線\n////////////////////////////\n\n//線分a-b,c-dは交差するか?\n//接する場合も交差すると判定\n//接する場合は交差しないとするなら<=を<に変換\nbool intersect(const Point &a,const Point &b,const Point &c,const Point &d){\n return(ccw(a,b,c)*ccw(a,b,d)<=0 && ccw(c,d,a)*ccw(c,d,b)<=0);\n}\n//線分s,tは交差するか?\n//接する場合も交差すると判定\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_B&lang=ja\n//接する場合は交差しないとするならintersectの<=を<に変換\nbool intersect(const Segment &s,const Segment &t){\n return intersect(s.a,s.b,t.a,t.b);\n}\n// 2直線の交点\n// 線分の場合はintersectをしてから使う\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_C&lang=ja\nPoint crossPoint(const Line &s,const Line &t){\n Point base=t.b-t.a;\n DD d1=cross(base,t.a-s.a);\n DD d2=cross(base,s.b-s.a);\n if(EQ(d1,0) and EQ(d2,0)) return s.a; //同じ直線\n if(EQ(d2,0)) assert(false); //交点がない\n return s.a+d1/d2*(s.b-s.a);\n}\n//線分と線分の距離\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_D&lang=ja\nDD Dist(const Segment &s,const Segment &t){\n if(intersect(s,t)) return 0.0;\n return min(min(DistPS(t.a,s),DistPS(t.b,s)),min(DistPS(s.a,t),DistPS(s.b,t)) );\n}\nbool issame(const Line &l,const Line &m){\n if (GR(abs(cross(m.a - l.a, l.b - l.a)),0) ) return false;\n if (GR(abs(cross(m.b - l.a, l.b - l.a)),0) ) return false;\n return true;\n}\n\n////////////////////////////\n// 円\n////////////////////////////\n//直線lと円Cの交点\n//l.aにより近い方がindexが小さい\n//veirfy:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_D\nvector<Point> crossPointLC(const Line &l,const Circle &c){\n vector<Point> ret;\n if(GR(DistPL(c.p,l),c.r)) return ret; //交点がないとき、空ベクトルを返す\n Point pr=project(c.p,l);\n Point e=(l.b-l.a)/(abs(l.b-l.a));\n DD base=sqrt(c.r*c.r-norm(pr-c.p));\n ret.push_back(pr-e*base);\n ret.push_back(pr+e*base);\n if(EQ(DistPL(c.p,l),c.r)) ret.pop_back(); //接するとき\n return ret;\n}\n//線分sと円cの交点\n//交点がないときは空ベクトルを返す\n//線分の端が交わる場合も交点とみなす\n//s.aにより近い方がindexが小さい\nvector<Point> crossPointSC(const Segment &s,const Circle &c){\n vector<Point> ret;\n if(DistPS(c.p,s)>c.r+EPS) return ret;\n auto koho=crossPointLC(s,c);\n for(auto p:koho){\n if(ccw(s.a,s.b,p)==0 or EQ(abs(p-s.a),0) or EQ(abs(p-s.b),0)) ret.push_back(p);\n }\n return ret;\n}\n\n//円aと円bの共通接線の数\n//離れている:4 外接:3 交わる:2 内接:1 内包:0\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_A\nint intersect(const Circle &a,const Circle &b){\n DD d=abs(a.p-b.p);\n if(GR(d,a.r+b.r)) return 4;\n if(EQ(d,a.r+b.r)) return 3;\n if(EQ(d,abs(a.r-b.r))) return 1;\n if(LS(d,abs(a.r-b.r))) return 0;\n return 2;\n}\n\n//円aと円bの交点\n//交点がないときは空ベクトルを返す\n//事前にintersectをしたほうがいいかも\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_E\nvector<Point> crossPoint(const Circle &a,const Circle &b){\n vector<Point> ret;\n if(GR(abs(a.p-b.p),a.r+b.r)) return ret;\n DD d=abs(a.p-b.p);\n DD s=acosl((a.r*a.r+d*d-b.r*b.r)/(2*a.r*d)); //0~π\n DD t=arg(b.p-a.p);\n if(EQ(a.r+b.r,d)) ret.push_back(a.p+polar(a.r,t));\n else ret.push_back(a.p+polar(a.r,t+s)),ret.push_back(a.p+polar(a.r,t-s));\n return ret;\n}\n\n//点pから円cに接線を引いたときの接点\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_F&lang=ja\nvector<Point> TanLine(const Point &p,const Circle &c){\n vector<Point> ret;\n DD d=abs(p-c.p);\n if(LS(d,c.r)) return ret; //pがcの内部にある場合\n if(EQ(d,c.r)){\n ret.push_back(p);\n return ret; //円の線上にある場合\n } \n return crossPoint(c,Circle(p,sqrt(d*d-c.r*c.r)));\n}\n\n//円a,bの共通接線\n//https://www.slideshare.net/kujira16/ss-35861169\n//Line.aは円aと接線の交点\n//(接線と円bの交点)と(接線と円aの交点)が違う場合はLine.bは(接線と円bの交点)\n//一致する場合は円aの中心からLine.aに向かうベクトルを反時計回りに90度回転したものを\n//Line.aに足したもの\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_G\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=2201\nvector<Line> TanLine(const Circle &a,const Circle &b){\n DD d=abs(a.p-b.p);\n vector<Line> ret;\n //外接線\n if(intersect(a,b)>=2){\n if(EQ(a.r,b.r)){\n Point up=polar(a.r,arg(b.p-a.p)+PI/2);\n ret.emplace_back(a.p+up,b.p+up);\n ret.emplace_back(a.p-up,b.p-up);\n }else{\n Point q=(a.p*b.r-b.p*a.r)/(b.r-a.r);\n auto as=TanLine(q,a);\n auto bs=TanLine(q,b);\n assert(as.size()==2 and bs.size()==2);\n for(int i=0;i<2;i++){\n ret.emplace_back(as[i],bs[i]);\n }\n }\n }else if(intersect(a,b)==1){ //内接する場合\n Point dir;\n if(a.r>b.r) dir=polar(a.r,arg(b.p-a.p));\n else dir=polar(a.r,arg(a.p-b.p));\n ret.emplace_back(a.p+dir,a.p+dir+rotate(dir,PI/2));\n }\n //内接線\n if(GR(abs(a.p-b.p),a.r+b.r)){ //円が離れている場合\n Point q=a.p+(b.p-a.p)*a.r/(a.r+b.r);\n auto as=TanLine(q,a);\n auto bs=TanLine(q,b);\n assert(as.size()==2 and bs.size()==2);\n for(int i=0;i<2;i++){\n ret.emplace_back(as[i],bs[i]);\n }\n }else if(EQ(d,a.r+b.r)){ //円が接している場合\n Point dir=polar(a.r,arg(b.p-a.p));\n ret.emplace_back(a.p+dir,a.p+dir+rotate(dir,PI/2));\n }\n return ret;\n}\n//2つの円の共通部分の面積\n//参考: https://tjkendev.github.io/procon-library/python/geometry/circles_intersection_area.html\n//verify: https://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=6005736#1\nDD Area(const Circle &c1,const Circle &c2){\n DD cd=abs(c1.p-c2.p);\n if(LE(c1.r+c2.r,cd)) return 0; //円が離れている\n\n if(LE(cd,abs(c1.r-c2.r))) //片方の円が他方を包んでいる\n return min(c1.r,c2.r)*min(c1.r,c2.r)*PI;\n\n DD theta1=acosl(cosine_formula(c1.r,cd,c2.r));\n DD theta2=acosl(cosine_formula(c2.r,cd,c1.r));\n\n return c1.r*c1.r*theta1+c2.r*c2.r*theta2-c1.r*cd*sin(theta1);\n}\n\n\n////////////////////////////\n// 三角形\n////////////////////////////\n\n//ヘロンの公式 三角形の面積を返す\n//三角形が成立するか(平行ではないか)を忘れずに\nDD Heron(const DD ad,const DD bd,const DD cd){\n DD s=(ad+bd+cd)/2;\n return sqrt(s*(s-ad)*(s-bd)*(s-cd));\n}\n//三角形の外接円\n//isParallel()を使って三角形が成立するか(平行ではないか)を忘れずに\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_C\nCircle CircumscribedCircle(const Point &a,const Point &b,const Point &c){\n Point bc=(b+c)/(DD)2.0;\n Line aa(bc,bc+rotate(c-b,PI/2));\n Point ab=(a+b)/(DD)2.0;\n Line cc(ab,ab+rotate(b-a,PI/2));\n Point p=crossPoint(aa,cc);\n return Circle(p,abs(a-p));\n}\n//三角形の内接円\n//isParallel()を使って三角形が成立するか(平行ではないか)を忘れずに\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_B\nCircle InCircle(const Point &a,const Point &b,const Point &c){\n Line aa(a,a+polar((DD)1.0,(arg(b-a)+arg(c-a))/(DD)2.0));\n Line bb(b,b+polar((DD)1.0,(arg(a-b)+arg(c-b))/(DD)2.0));\n Point p=crossPoint(aa,bb);\n return Circle(p,DistPL(p,Line(a,b)));\n}\n\n////////////////////////////\n// 多角形\n////////////////////////////\n\n//点pが多角形gに対してどの位置にあるか\n//中:2 辺上:1 外:0\n//凸多角形である必要ない\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_C\nint contains(const Point &p,const vector<Point> &g){\n int n=(int)g.size();\n int x=false;\n for(int i=0;i<n;i++){\n Point a=g[i]-p,b=g[(i+1)%n]-p;\n if(EQ(cross(a,b),0) && dot(a,b)<EPS) return 1;\n if(a.Y>b.Y) swap(a,b);\n if(a.Y<EPS && EPS<b.Y && cross(a,b)>EPS) x=!x;\n }\n return (x?2:0);\n}\n//凸性判定\n//多角形gは凸か?\n//gは反時計回りでも時計回りでもいい\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_B\nbool isConvex(const vector<Point> &g){\n int n=(int)g.size();\n if(n<=3) return true;\n int flag=0;\n int t;\n for(int i=0;i<n;i++){\n Point a(g[(i+1)%n]-g[i]),b(g[(i+2)%n]-g[i]);\n if(cross(a,b)>EPS) t=1;\n else if(cross(a,b)<-EPS) t=-1;\n else continue;\n if(flag==-t) return false;\n flag=t;\n }\n return true;\n}\n\n//凸包 アンドリューのアルゴリズム\n//O(NlogN)\n//反時計回りの多角形を返す\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_4_A\nvector<Point> ConvexHull(vector<Point> s,const bool on_edge){\n int j;\n if(on_edge) j=-1;\n else j=1;\n int sz=(int)s.size();\n if(sz<3) return s;\n sort(s.begin(),s.end(),yx_sort);\n\n int n=0;\n vector<Point> res(2*sz);\n for(int i=0;i<sz;i++){\n while(n>=2 && cross(res[n-1]-res[n-2],s[i]-res[n-2])<EPS*j){\n n--;\n }\n res[n]=s[i];\n n++;\n }\n int t=n+1;\n for(int i=sz-2;i>=0;i--){\n while(n>=t && cross(res[n-1]-res[n-2],s[i]-res[n-2])<EPS*j){\n n--;\n }\n res[n]=s[i];\n n++;\n }\n res.resize(n-1);\n return res;\n}\n\n\n\nint N,T,R;\nvector<string> Name(110);\nvector<vector<int>> VT(110),VX(110),VY(110);\nusing pdi=pair<DD,int>;\npriority_queue<pdi,vector<pdi>,greater<pdi>> que;\n\nPoint Place(int id,DD t){\n Point now(VX[id][0],VY[id][0]);\n for(int i=1;i<VX[id].size();i++){\n Point p(VX[id][i],VY[id][i]);\n if(t<=VT[id][i]){\n now+=p*(t-VT[id][i-1]);\n return now;\n }else{\n now+=p*DD(VT[id][i]-VT[id][i-1]);\n }\n }\n return now;\n}\n\nvoid FFF(int ID,DD now){\n Circle C(Point(0,0),R);\n //C.debug();\n Point p1(VX[ID][0],VY[ID][0]);\n\n for(int ti1=0;ti1+1<VT[ID].size();ti1++){\n int t1=VT[ID][ti1];\n int nt1=VT[ID][ti1+1];\n for(int id=0;id<N;id++){\n if(id==ID) continue;\n for(int ti2=0;ti2+1<VT[id].size();ti2++){\n int t2=VT[id][ti2];\n int nt2=VT[id][ti2+1];\n int start=max(t1,t2);\n int end=min(nt1,nt2);\n if(start>end) continue;\n\n Segment S(Place(ID,start)-Place(id,start),Place(ID,end)-Place(id,end));\n auto sc=crossPointSC(S,C);\n for(auto p:sc){\n auto sp=Place(ID,start)-Place(id,start);\n Point d(VX[ID][ti1+1]-VX[id][ti2+1] , VY[ID][ti1+1]-VY[id][ti2+1]);\n DD t=abs(p-sp)/abs(d);\n if(GE(start+t,now)) que.emplace(start+t,id);\n }\n if(LE(abs(Place(ID,start)-Place(id,start)),R) and LE(abs(Place(ID,end)-Place(id,end)),R) and LE(now,end)){\n if(Name[id]==\"baz\"){\n cerr<<abs(Place(ID,start)-Place(id,start))<<endl;\n cout<<-1<<endl;\n }\n que.emplace(max<DD>(now,start),id);\n }\n }\n }\n }\n}\n\n\nvoid solve(){\nwhile(true){\n cin>>N>>T>>R;\n if(N==0) return;\n\n for(int i=0;i<N;i++){\n cin>>Name[i];\n VT[i].clear();\n VX[i].clear();\n VY[i].clear();\n for(int j=0;;j++){\n int t,x,y;\n cin>>t>>x>>y;\n VT[i].push_back(t);\n VX[i].push_back(x);\n VY[i].push_back(y);\n if(t==T) break;\n }\n }\n /*for(int i=0;i<N;i++){\n for(int t=0;t+1<VT[i].size();t++){\n string s;s+=char('a'+i);\n debug(Place(i,VT[i][t]),s);\n Segment seg(Place(i,VT[i][t]),Place(i,VT[i][t+1]));\n debug(Place(i,VT[i][t+1]),s);\n seg.debug();\n }\n cout<<endl;\n }*/\n vector<bool> used(N,false);\n vector<string> ans;\n que.emplace(0,0);\n \n while(que.size()){\n auto x=que.top(); que.pop();\n if(used[x.second]) continue;\n used[x.second]=true;\n ans.push_back(Name[x.second]);\n FFF(x.second,x.first);\n }\n\n vsort(ans);\n for(auto s:ans) cout<<s<<endl;\n}\n}\n\nint main(){\n bin101();\n int T=1;\n //cin>>T;\n while(T--) solve();\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 3556, "score_of_the_acc": -0.3262, "final_rank": 15 }, { "submission_id": "aoj_1139_6024043", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n#define all(x) (x).begin(),(x).end()\n#define fi first\n#define se second\n#define mp make_pair\n#define si(x) int(x.size())\nconst int mod=998244353,MAX=105,INF=1<<30;\n\n//幾何ライブラリ\n// define double ll をするときは Point の < と == も書き換えよう!\n\nconst double eps=1e-8;\nconst double pi=acos((double)-1.0L);\n#define equals(a,b) (fabs((a)-(b))<eps)\n\ndouble torad(double deg) {return (double)(deg)*pi/180.0;}\ndouble todeg(double ang) {return ang*180.0/pi;}\n\nclass Point{\npublic:\n double x,y;\n \n Point(double x=0,double y=0):x(x),y(y){}\n \n Point operator + (Point p){return Point(x+p.x,y+p.y);}\n Point operator - (Point p){return Point(x-p.x,y-p.y);}\n Point operator * (double a){return Point(a*x,a*y);}\n Point operator / (double a){return Point(x/a,y/a);}\n \n double abs(){return sqrt(norm());}\n double norm(){return x*x+y*y;}\n \n bool operator < (const Point &p)const{\n return x+eps<p.x||(equals(x,p.x)&&y+eps<p.y);\n }\n \n bool operator == (const Point &p)const{\n return fabs(x-p.x)<eps/100000&&fabs(y-p.y)<eps/100000;\n }\n};\n\ntypedef Point Vector;\n\ndouble norm(Vector a){\n return a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n return sqrt(norm(a));\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x+a.y*b.y;\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\nstruct Segment{\n Point p1,p2;\n};\n\nbool isOrthogonal(Vector a,Vector b){\n return equals(dot(a,b),0.0);\n}\n\nbool isOrthogonal(Point a1,Point a2,Point b1,Point b2){\n return isOrthogonal(a1-a2,b1-b2);\n}\n\nbool isOrthogonal(Segment s1,Segment s2){\n return equals(dot(s1.p2-s1.p1,s2.p2-s2.p1),0.0);\n}\n\nbool isParallel(Vector a,Vector b){\n return equals(cross(a,b),0.0);\n}\n\nbool isParallel(Point a1,Point a2,Point b1,Point b2){\n return isParallel(a1-a2,b1-b2);\n}\n\nbool isParallel(Segment s1,Segment s2){\n return equals(cross(s1.p2-s1.p1,s2.p2-s2.p1),0.0);\n}\n\nPoint project(Segment s,Point p){\n Vector base=s.p2-s.p1;\n double r=dot(p-s.p1,base)/norm(base);\n return s.p1+base*r;\n}\n\nPoint reflect(Segment s,Point p){\n return p+(project(s,p)-p)*2.0;\n}\n\nPoint turn(Point p,Point c,double pi){\n double q=atan2(p.y-c.y,p.x-c.x);\n q+=pi;\n p=c+Point{cos(q)*abs(p-c),sin(q)*abs(p-c)};\n \n return p;\n}\n//pをcを中心としてpi回転させる(1周で2π)\n//p=cのときnan\n\n//p0,p1,p2の順に見たときどうなるか?\n\nstatic const int counter_clockwise=1;\nstatic const int clockwise=-1;\nstatic const int online_back=2;\nstatic const int online_front=-2;\nstatic const int on_segment=0;\n\nint ccw(Point p0,Point p1,Point p2){\n Vector a=p1-p0;\n Vector b=p2-p0;\n \n if(cross(a,b)>eps) return counter_clockwise;\n if(cross(a,b)<-eps) return clockwise;\n if(dot(a,b)<-eps) return online_back;\n if(a.norm()<b.norm()) return online_front;\n \n return on_segment;\n}\n\nbool intersect(Point p1,Point p2,Point p3,Point p4){\n return(ccw(p1,p2,p3)*ccw(p1,p2,p4)<=0&&ccw(p3,p4,p1)*ccw(p3,p4,p2)<=0);\n}\n\nbool intersect(Segment s1,Segment s2){\n return intersect(s1.p1,s1.p2,s2.p1,s2.p2);\n}\n\nbool overlap(Segment s1,Segment s2){\n int a=ccw(s1.p1,s1.p2,s2.p1),b=ccw(s1.p1,s1.p2,s2.p2);\n if(a&1||b&1) return 0;\n if(a==2){\n if(b==-2||(b==0&&!(s2.p2==s1.p1))) return 1;\n else return 0;\n }\n if(a==-2){\n if(b==2||(b==0&&!(s2.p2==s1.p2))) return 1;\n else return 0;\n }\n if(a==0){\n if(s1.p1==s2.p1){\n if(b!=2) return 1;\n else return 0;\n }\n else if(s1.p2==s2.p1){\n if(b!=-2) return 1;\n else return 0;\n }\n else return 1;\n }\n return 0;\n}\n//s1とs2の共通の線分(長さ0より大きい)があるかどうか\n\ntypedef Segment Line;\n\ndouble getDistance(Point a,Point b){\n return abs(a-b);\n}\n\ndouble getDistanceLP(Line l,Point p){\n return abs(cross(l.p2-l.p1,p-l.p1)/abs(l.p2-l.p1));\n}\n\ndouble getDistanceSP(Segment s,Point p){\n if(dot(s.p2-s.p1,p-s.p1)<0.0) return abs(p-s.p1);\n if(dot(s.p1-s.p2,p-s.p2)<0.0) return abs(p-s.p2);\n return getDistanceLP(s,p);\n}\n\ndouble getDistance(Segment s1,Segment s2){\n if(intersect(s1,s2)) return 0.0;\n return min({getDistanceSP(s1,s2.p1),getDistanceSP(s1,s2.p2),getDistanceSP(s2,s1.p1),getDistanceSP(s2,s1.p2)});\n}\n\nPoint getCrossPointS(Segment s1,Segment s2){\n //if(ccw(s1.p1,s1.p2,s2.p1)==0&&ccw(s1.p1,s1.p2,s2.p2)==0) return s1.p1;\n Vector base=s2.p2-s2.p1;\n double d1=abs(cross(base,s1.p1-s2.p1));\n double d2=abs(cross(base,s1.p2-s2.p1));\n double t=d1/(d1+d2);\n return s1.p1+(s1.p2-s1.p1)*t;\n}//同じ時壊れます\n\nPoint getCrossPointL(Line l1,Line l2){\n //if(ccw(s1.p1,s1.p2,s2.p1)==0&&ccw(s1.p1,s1.p2,s2.p2)==0) return s1.p1;\n \n Vector v1=l1.p2-l1.p1,v2=l2.p2-l2.p1;\n \n return l1.p1+v1*cross(v2,l2.p1-l1.p1)/cross(v2,v1);\n}\n\nSegment ParallelSegment(Segment s,double d){\n Vector v={-(s.p2-s.p1).y,(s.p2-s.p1).x};\n v=v/abs(v);\n \n s.p1=s.p1+v*d;\n s.p2=s.p2+v*d;\n \n return s;\n}\n\nPoint naisin(Point p1,Point p2,Point p3){\n if(p1==p2&&p2==p3&&p3==p1) return p1;\n \n return (p1*abs(p2-p3)+p2*abs(p1-p3)+p3*abs(p1-p2))/(abs(p2-p3)+abs(p1-p3)+abs(p1-p2));\n}\n\nPoint naisin(Line l1,Line l2,Line l3){\n //平行でない前提\n \n Point p1=getCrossPointL(l1,l2),p2=getCrossPointL(l1,l3),p3=getCrossPointL(l2,l3);\n return naisin(p1,p2,p3);\n}\n\n//ネットの適当を書いたのであってるか全く知りません→あってそう\n\nclass Circle{\npublic:\n Point c;\n double r;\n Circle(Point c=Point(),double r=0.0):c(c),r(r){}\n};\n\nPoint CircleCenter(Point a,Point b,Point c){\n Point u=a-b,v=a-c;\n double m1=(norm(a)-norm(b))/2.0,m2=(norm(a)-norm(c))/2.0;\n \n Point res;\n if(cross(u,v)==0.0){\n res.x=1e9;\n res.y=1e9;\n \n return res;\n }\n res.x=(m1*v.y-m2*u.y)/cross(u,v);\n res.y=(m1*v.x-m2*u.x)/cross(v,u);\n \n return res;\n}\n//3点を通る円の中心を返す\n\n//交わる 0\n// c1がc2のinside 1\n// c1がc2のoutside 2\n// 交わらない 3\n\nint not_intersect(Circle c1,Circle c2){\n double d=getDistance(c1.c,c2.c);\n double r1=c1.r,r2=c2.r;\n if(r1<r2){\n if(d<(r2-r1)) return 1;\n }\n if(r1>r2){\n if(d<(r1-r2)) return 2;\n }\n if(d<=r1+r2) return 0;\n else return 3;\n}\n\npair<Point,Point> segCrossPpoints(Circle c,Line l){\n //assert(intersect(c,l));\n Vector pr=project(l,c.c);\n Vector e=(l.p2-l.p1)/abs(l.p2-l.p1);\n double base=sqrt(c.r*c.r-norm(pr-c.c));\n return make_pair(pr+e*base,pr-e*base);\n}\n\ndouble arg(Vector p){return atan2(p.y,p.x);}\nVector polar(double a,double r){return Point(cos(r)*a,sin(r)*a);}\n\n//inside(outside)\n\npair<Point,Point> getCrossPoints(Circle c1,Circle c2){\n //assert(intersect(c1,c2));\n double d=abs(c1.c-c2.c);\n double a=acos((c1.r*c1.r+d*d-c2.r*c2.r)/(2*c1.r*d));\n double t=arg(c2.c-c1.c);\n return make_pair(c1.c+polar(c1.r,t+a),c1.c+polar(c1.r,t-a));\n}\n\nvector<Line> Commontangent(Circle c1,Circle c2){\n vector<Line> res;\n Point p=c2.c-c1.c;\n \n if(abs(p)>=(c1.r+c2.r)){\n Point a,b;\n a.x=c1.r*(p.x*(c1.r+c2.r)+p.y*sqrt(norm(p)-(c1.r+c2.r)*(c1.r+c2.r)))/norm(p);\n a.y=c1.r*(p.y*(c1.r+c2.r)-p.x*sqrt(norm(p)-(c1.r+c2.r)*(c1.r+c2.r)))/norm(p);\n \n b.x=c1.r*(p.x*(c1.r+c2.r)-p.y*sqrt(norm(p)-(c1.r+c2.r)*(c1.r+c2.r)))/norm(p);\n b.y=c1.r*(p.y*(c1.r+c2.r)+p.x*sqrt(norm(p)-(c1.r+c2.r)*(c1.r+c2.r)))/norm(p);\n \n res.push_back(Line{a+c1.c,a+c1.c+Point{-a.y,a.x}});\n if(!(a==b)){\n res.push_back(Line{b+c1.c,b+c1.c+Point{-b.y,b.x}});\n }\n }\n \n if(abs(p)>=abs(c1.r-c2.r)){\n Point a,b;\n a.x=c1.r*(p.x*(c1.r-c2.r)+p.y*sqrt(norm(p)-(c1.r-c2.r)*(c1.r-c2.r)))/norm(p);\n a.y=c1.r*(p.y*(c1.r-c2.r)-p.x*sqrt(norm(p)-(c1.r-c2.r)*(c1.r-c2.r)))/norm(p);\n \n b.x=c1.r*(p.x*(c1.r-c2.r)-p.y*sqrt(norm(p)-(c1.r-c2.r)*(c1.r-c2.r)))/norm(p);\n b.y=c1.r*(p.y*(c1.r-c2.r)+p.x*sqrt(norm(p)-(c1.r-c2.r)*(c1.r-c2.r)))/norm(p);\n \n res.push_back(Line{a+c1.c,a+c1.c+Point{-a.y,a.x}});\n if(!(a==b)){\n res.push_back(Line{b+c1.c,b+c1.c+Point{-b.y,b.x}});\n }\n }\n \n return res;\n}\n\ntypedef vector<Point> Polygon;\n\n/*\n IN 2\n ON 1\n OUT 0\n */\n\nint contains(Polygon g,Point p){\n int n=int(g.size());\n bool x=false;\n for(int i=0;i<n;i++){\n Point a=g[i]-p,b=g[(i+1)%n]-p;\n if(a.y>b.y) swap(a,b);\n if(a.y<eps&&0<b.y&&cross(a,b)<0) x=!x;\n if(abs(cross(a,b))<eps&&dot(a,b)<eps) return 1;\n }\n return (x?2:0);\n}\n\nPolygon andrewScan(Polygon s,bool ok){\n Polygon u,l;\n sort(all(s));\n \n if(int(s.size())<3) return s;\n int n=int(s.size());\n \n u.push_back(s[0]);\n u.push_back(s[1]);\n \n l.push_back(s[n-1]);\n l.push_back(s[n-2]);\n \n if(ok){\n for(int i=2;i<n;i++){\n for(int j=int(u.size());j>=2&&ccw(u[j-2],u[j-1],s[i])==counter_clockwise;j--){\n u.pop_back();\n }\n u.push_back(s[i]);\n }\n \n for(int i=int(s.size())-3;i>=0;i--){\n for(int j=int(l.size());j>=2&&ccw(l[j-2],l[j-1],s[i])==counter_clockwise;j--){\n l.pop_back();\n }\n l.push_back(s[i]);\n }\n }\n \n if(!ok){\n for(int i=2;i<n;i++){\n for(int j=int(u.size());j>=2&&ccw(u[j-2],u[j-1],s[i])!=clockwise;j--){\n u.pop_back();\n }\n u.push_back(s[i]);\n }\n \n for(int i=int(s.size())-3;i>=0;i--){\n for(int j=int(l.size());j>=2&&ccw(l[j-2],l[j-1],s[i])!=clockwise;j--){\n l.pop_back();\n }\n l.push_back(s[i]);\n }\n }\n \n reverse(all(l));\n \n for(int i=int(u.size())-2;i>=1;i--) l.push_back(u[i]);\n \n return l;\n}//ok==1なら辺の上も含める\n\nPolygon convex_cut(const Polygon& P, const Line& l) {\n Polygon Q;\n for(int i=0;i<si(P);i++){\n Point A=P[i],B=P[(i+1)%si(P)];\n if(ccw(l.p1,l.p2,A)!=-1)Q.push_back(A);\n if(ccw(l.p1,l.p2,A)*ccw(l.p1,l.p2,B)<0) Q.push_back(getCrossPointL(Line{A,B},l));\n }\n return Q;\n}\n\ndouble area(Point a,Point b,Point c){\n b=b-a;\n c=c-a;\n return abs(b.x*c.y-b.y*c.x)/2.0;\n}\n\ndouble area(Polygon &P){\n if(si(P)==0) return 0.0;\n double res=0;\n Point c={0.0,0.0};\n for(int i=0;i<si(P);i++){\n c=c+P[i];\n }\n c=c/si(P);\n \n for(int i=0;i<si(P);i++){\n res+=area(c,P[i],P[(i+1)%si(P)]);\n }\n \n return res;\n}\n\nll gcd(ll a,ll b){\n if(b==0) return a;\n return gcd(b,a%b);\n}\n\npair<Point,Vector> perpendicular_bisector(Point a,Point b){\n Point c=(a+b)/2;\n Vector v=b-c;\n swap(v.x,v.y);\n v.x*=-1;\n \n Point p=c;\n if(v.x==0){\n v.y=1;\n p.y=0;\n }\n else if(v.y==0){\n v.x=1;\n p.x=0;\n }\n else{\n if(v.x<0){\n v.x*=-1;\n v.y*=-1;\n }\n ll g=gcd(abs(ll(v.x)),abs(ll(v.y)));\n v.x/=g;\n v.y/=g;\n if(p.x>=0){\n ll d=p.x/v.x;\n p=p-v*d;\n }else{\n ll d=abs(p.x)/v.x;\n p=p+v*d;\n \n if(p.x<0){\n p=p+v;\n }\n }\n }\n \n return mp(p,v);\n}\n//2倍するなりして整数にしておくこと\n\nbool kousa[MAX][MAX];\n\nint main() {\n \n std::ifstream in(\"text.txt\");\n std::cin.rdbuf(in.rdbuf());\n cin.tie(0);\n ios::sync_with_stdio(false);\n \n while(1){\n int N,T,RR;cin>>N>>T>>RR;\n if(N==0) break;\n memset(kousa,0,sizeof(kousa));\n vector<string> S(N);\n vector<vector<Vector>> V(N,vector<Vector>(T));\n vector<Point> P(N);\n for(int i=0;i<N;i++){\n cin>>S[i];\n double lt=0;\n while(1){\n double t,x,y;cin>>t>>x>>y;\n for(int j=lt;j<t;j++){\n V[i][j]={x,y};\n }\n if(t==0) P[i]={x,y};\n lt=t;\n if(lt==T) break;\n }\n }\n vector<int> on(N);\n on[0]=true;\n \n vector<pair<double,pair<int,int>>> Q;\n for(int i=0;i<N;i++){\n for(int j=i+1;j<N;j++){\n Point a=P[i],b=P[j];\n for(int k=0;k<T;k++){\n double l=k,r=k+1,mi=INF;\n for(int q=0;q<30;q++){\n double m1=(l+l+r)/3,m2=(l+r+r)/3;\n Point a1=a+V[i][k]*(m1-k),b1=b+V[j][k]*(m1-k);\n Point a2=a+V[i][k]*(m2-k),b2=b+V[j][k]*(m2-k);\n double d1=getDistance(a1,b1),d2=getDistance(a2,b2);\n if(d1<d2){\n r=m2;\n chmin(mi,d1);\n }else{\n l=m1;\n chmin(mi,d2);\n }\n }\n \n //cout<<i<<\" \"<<j<<\" \"<<k<<\" \"<<mi<<\" \"<<l<<\" \"<<r<<endl;\n \n if(mi<=RR+eps){\n double L=k,M=(l+r)/2,R=k+1;\n for(int q=0;q<30;q++){\n double m=(L+M)/2;\n Point aa=a+V[i][k]*(m-k),bb=b+V[j][k]*(m-k);\n if(getDistance(aa,bb)<=RR+eps) M=m;\n else L=m;\n }\n double saveM=M;\n M=(l+r)/2;\n for(int q=0;q<30;q++){\n double m=(M+R)/2;\n Point aa=a+V[i][k]*(m-k),bb=b+V[j][k]*(m-k);\n //cout<<i<<\" \"<<j<<\" \"<<m<<\" \"<<getDistance(aa,bb)<<endl;\n if(getDistance(aa,bb)<=RR+eps) M=m;\n else R=m;\n }\n if(L==k){\n Q.push_back(mp(L+eps,mp(i,j)));\n }else{\n Q.push_back(mp(saveM,mp(i,j)));\n }\n \n if(R==k+1){\n Q.push_back(mp(R-eps,mp(i,j)));\n }else{\n Q.push_back(mp(M,mp(i,j)));\n }\n \n //cout<<i<<\" \"<<j<<\" \"<<saveM<<\" \"<<M<<endl;\n }\n \n \n a=a+V[i][k];\n b=b+V[j][k];\n }\n }\n }\n \n sort(all(Q));\n \n for(auto q:Q){\n int a=q.se.fi,b=q.se.se;\n \n kousa[a][b]^=1;\n kousa[b][a]^=1;\n \n if(on[a]+on[b]==1){\n for(int t=0;t<N;t++){\n for(int i=0;i<N;i++){\n for(int j=0;j<N;j++){\n if(on[i]&&kousa[i][j]) on[j]=true;\n }\n }\n }\n }\n }\n \n vector<string> ans;\n for(int i=0;i<N;i++){\n if(on[i]) ans.push_back(S[i]);\n }\n sort(all(ans));\n for(auto s:ans) cout<<s<<\"\\n\";\n }\n}", "accuracy": 1, "time_ms": 1280, "memory_kb": 4868, "score_of_the_acc": -1.1104, "final_rank": 18 }, { "submission_id": "aoj_1139_5803461", "code_snippet": "/*\tauthor: Kite_kuma\n\tcreated: 2021.08.19 15:21:48 */\n\n// #ifdef LOCAL\n// #define _GLIBCXX_DEBUG\n// #endif\n#include <bits/stdc++.h>\nusing namespace std;\n\n#pragma region macros\n\n#define foa(s, v) for(auto &s : v)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\n#define popcnt(n) __builtin_popcountll((long long)n)\n\n#define REPname(a, b, c, d, e, ...) e\n#define rep(...) REPname(__VA_ARGS__, REP3, REP2, REP1, REP0)(__VA_ARGS__)\n#define REP0(x) for(int Counter_in_rep_macro = 0; Counter_in_rep_macro < (x); ++Counter_in_rep_macro)\n#define REP1(i, x) for(int i = 0; i < (x); ++i)\n#define REP2(i, l, r) for(int i = (l); i < (r); ++i)\n#define REP3(i, l, r, c) for(int i = (l); i < (r); i += (c))\n\n#define DREPname(a, b, c, d, e, ...) e\n#define drep(...) DREPname(__VA_ARGS__, DREP3, DREP2, DREP1)(__VA_ARGS__)\n#define DREP1(i, x) for(int i = (x)-1; i >= 0; --i)\n#define DREP2(i, l, r) for(int i = (r)-1; i >= (l); --i)\n#define DREP3(i, l, r, c) for(int i = (r)-1; i >= (l); i -= (c))\n\n#pragma endregion\n\n#pragma region aliases\n\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\nusing vi = std::vector<int>;\nusing vvi = std::vector<std::vector<int>>;\nusing vvvi = std::vector<std::vector<std::vector<int>>>;\nusing vll = std::vector<ll>;\nusing vvll = std::vector<vll>;\nusing vvvll = std::vector<vvll>;\nusing pii = std::pair<int, int>;\nusing pll = std::pair<long long, long long>;\ntemplate <class T = ll>\nusing V = std::vector<T>;\ntemplate <class T = ll>\nusing VV = V<V<T>>;\ntemplate <class T = ll>\nusing VVV = V<V<V<T>>>;\ntemplate <class T = ll>\nusing pqup = std::priority_queue<T, std::vector<T>, std::greater<T>>;\ntemplate <class T = ll>\nusing pqdn = std::priority_queue<T>;\n\n#pragma endregion\n\n#pragma region constants\n\nconst int inf = 1e9;\nconst long long INF = 1e18;\nconst long double pi = acos(-1);\nconst char dl = '\\n';\nconst char sp = ' ';\nint dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};\nint dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};\n\nconst int mod_1000000007 = 1000000007;\nconst int mod_998244353 = 998244353;\n\n#pragma endregion\n\n#pragma region basic_operation\n\ntemplate <class T0, class T1, class T2>\ninline bool in_range(T0 x, T1 lef, T2 rig) {\n\treturn ((lef <= x) && (x < rig));\n}\n\ntemplate <class T>\ninline bool chmin(T &a, T b) {\n\tif(a > b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\ntemplate <class T>\ninline bool chmax(T &a, T b) {\n\tif(a < b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\n\nvoid Yes(bool f = 1) { std::cout << (f ? \"Yes\" : \"No\") << '\\n'; }\nvoid No() { std::cout << \"No\\n\"; }\nvoid YES(bool f = 1) { std::cout << (f ? \"YES\" : \"NO\") << '\\n'; }\nvoid NO() { std::cout << \"NO\\n\"; }\n\ntemplate <class T>\nvoid drop(T answer) {\n\tstd::cout << answer << '\\n';\n\texit(0);\n}\n\nvoid err(bool flag = true) {\n\tif(!flag) return;\n\tstd::cout << -1 << '\\n';\n\texit(0);\n}\n\ntemplate <class T>\nvoid vout(std::vector<T> const &v, bool vertically = 0) {\n\tif(vertically) {\n\t\tfor(auto const &a : v) {\n\t\t\tstd::cout << a << '\\n';\n\t\t}\n\t\treturn;\n\t}\n\tfor(auto it = v.begin(); it != v.end(); it++) {\n\t\tstd::cout << (*it);\n\t\tif(it != v.end() - 1) {\n\t\t\tstd::cout << ' ';\n\t\t}\n\t}\n\tstd::cout << '\\n';\n\treturn;\n}\n\ninline void print() { std::cout << '\\n'; }\ntemplate <class T>\ninline void print(T x) {\n\tstd::cout << x << '\\n';\n\treturn;\n}\ntemplate <typename Head, typename... Tail>\nvoid print(Head H, Tail... T) {\n\tstd::cout << H << \" \";\n\tprint(T...);\n}\n\ntemplate <class T>\nvoid add(std::vector<T> &v, T val) {\n\tfor(auto &a : v) a += val;\n\treturn;\n}\n\ntemplate <class T>\nT dup(T a, T b) {\n\tassert(b != 0);\n\treturn (a + b - 1) / b;\n}\n\ntemplate <class T>\nT greatest_lower_multiple(T x, T d) {\n\tif(d == 0) return 0;\n\tif(d < 0) d *= -1;\n\tT y = x % d;\n\tif(y < 0) y += d;\n\treturn x - y;\n}\n\ntemplate <class T>\nT least_upper_multiple(T x, T d) {\n\treturn -greatest_lower_multiple(-x, d);\n}\n\nlong long POW(long long a, long long n) {\n\tlong long res = 1;\n\twhile(n > 0) {\n\t\tif(n & 1) res = res * a;\n\t\ta = a * a;\n\t\tn >>= 1;\n\t}\n\treturn res;\n}\n\nlong long modpow(long long a, long long n, long long mod) {\t // a^n mod\n\tassert(n >= 0 && mod);\n\tif(mod == 1) return 0LL;\n\tlong long res = 1;\n\ta %= mod;\n\twhile(n > 0) {\n\t\tif(n & 1) res = res * a % mod;\n\t\ta = a * a % mod;\n\t\tn >>= 1;\n\t}\n\treturn res < 0 ? res + mod : res;\n}\n\n// return x which satisfies a * x % mod == gcd(a, mod)\n// not (mod | a)\nlong long modinv(long long a, long long mod) {\n\tlong long b = mod, u = 1, v = 0;\n\twhile(b) {\n\t\tlong long t = a / b;\n\t\ta -= t * b;\n\t\tstd::swap(a, b);\n\t\tu -= t * v;\n\t\tstd::swap(u, v);\n\t}\n\tu %= mod;\n\tif(u < 0) u += mod;\n\treturn u;\n}\n\ntemplate <class T>\nint lb(const std::vector<T> &a, const T x) {\n\treturn std::distance(a.begin(), std::lower_bound(a.begin(), a.end(), x));\n}\ntemplate <class T>\nint ub(const std::vector<T> &a, const T x) {\n\treturn std::distance(a.begin(), std::upper_bound(a.begin(), a.end(), x));\n}\ntemplate <class T>\nvoid unq_sort(std::vector<T> &a) {\n\tstd::sort(a.begin(), a.end());\n\ta.erase(std::unique(a.begin(), a.end()), a.end());\n}\ntemplate <class T>\nstd::vector<int> press(std::vector<T> &a) {\n\tauto vec = a;\n\tunq_sort(vec);\n\tstd::vector<int> ret;\n\tfor(auto &v : a) ret.push_back(lb(vec, v));\n\treturn ret;\n}\n\n#pragma endregion\n\n#pragma region input\n#define VEC(type, name, size) \\\n\tvector<type> name(size); \\\n\tscanner::INPUT(name)\n#define VVEC(type, name, h, w) \\\n\tvector<vector<type>> name(h, vector<type>(w)); \\\n\tscanner::INPUT(name)\n#define INT(...) \\\n\tint __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LL(...) \\\n\tlong long __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define STR(...) \\\n\tstring __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define CHR(...) \\\n\tchar __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define DBL(...) \\\n\tdouble __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LD(...) \\\n\tlong double __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define TPL3(type0, type1, type2, name) \\\n\tstd::tuple<type0, type1, type2> name; \\\n\tscanner::INPUT(name);\n#define TPL4(type0, type1, type2, type3, name) \\\n\tstd::tuple<type0, type1, type2, type3> name; \\\n\tscanner::INPUT(name);\n\nnamespace scanner {\ntemplate <class T>\nvoid scan(T &a) {\n\tstd::cin >> a;\n}\n\ntemplate <class T, class L>\nvoid scan(std::pair<T, L> &p) {\n\tscan(p.first);\n\tscan(p.second);\n}\n\ntemplate <class T0, class T1, class T2>\nvoid scan(std::tuple<T0, T1, T2> &p) {\n\tT0 t0;\n\tT1 t1;\n\tT2 t2;\n\tscan(t0);\n\tscan(t1);\n\tscan(t2);\n\tp = std::make_tuple(t0, t1, t2);\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid scan(std::tuple<T0, T1, T2, T3> &p) {\n\tT0 t0;\n\tT1 t1;\n\tT2 t2;\n\tT3 t3;\n\tscan(t0);\n\tscan(t1);\n\tscan(t2);\n\tscan(t3);\n\tp = std::make_tuple(t0, t1, t2, t3);\n}\n\ntemplate <class T>\nvoid scan(std::vector<T> &a) {\n\tfor(auto &i : a) scan(i);\n}\n\nvoid INPUT() {}\ntemplate <class Head, class... Tail>\nvoid INPUT(Head &head, Tail &... tail) {\n\tscan(head);\n\tINPUT(tail...);\n}\n} // namespace scanner\n\ntemplate <typename T1, typename T2>\nstd::istream &operator>>(std::istream &is, std::pair<T1, T2> &p) {\n\tis >> p.first >> p.second;\n\treturn is;\n}\n#pragma endregion\n\n#pragma region debug\n\n#pragma region output\ntemplate <typename T1, typename T2>\nstd::ostream &std::operator<<(std::ostream &os, const std::pair<T1, T2> &p) {\n\tos << p.first << \" \" << p.second;\n\treturn os;\n}\ntemplate <class T>\nstd::ostream &std::operator<<(std::ostream &os, const std::vector<T> &v) {\n\tfor(int i = 0; i < (int)v.size(); i++) {\n\t\tif(i) os << \" \";\n\t\tos << v[i];\n\t}\n\treturn os;\n}\n#pragma endregion\n\n#pragma region view\n\nnamespace viewer {\nvoid view(const long long e) {\n\tif(e == INF)\n\t\tstd::cerr << \"INF\";\n\telse if(e == -INF)\n\t\tstd::cerr << \"-INF\";\n\telse\n\t\tstd::cerr << e;\n}\n\nvoid view(const int e) {\n\tif(e == inf)\n\t\tstd::cerr << \"inf\";\n\telse if(e == -inf)\n\t\tstd::cerr << \"-inf\";\n\telse\n\t\tstd::cerr << e;\n}\n\ntemplate <typename T>\nvoid view(const T e) {\n\tstd::cerr << e;\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::pair<T, U> &p) {\n\tstd::cerr << \"(\";\n\tview(p.first);\n\tstd::cerr << \", \";\n\tview(p.second);\n\tstd::cerr << \")\";\n}\n\ntemplate <class T0, class T1, class T2>\nvoid view(const std::tuple<T0, T1, T2> &p) {\n\tstd::cerr << \"(\";\n\tview(std::get<0>(p));\n\tstd::cerr << \", \";\n\tview(std::get<1>(p));\n\tstd::cerr << \", \";\n\tview(std::get<2>(p));\n\tstd::cerr << \")\";\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid view(const std::tuple<T0, T1, T2, T3> &p) {\n\tstd::cerr << \"(\";\n\tview(std::get<0>(p));\n\tstd::cerr << \", \";\n\tview(std::get<1>(p));\n\tstd::cerr << \", \";\n\tview(std::get<2>(p));\n\tstd::cerr << \", \";\n\tview(std::get<3>(p));\n\tstd::cerr << \")\";\n}\n\ntemplate <typename T>\nvoid view(const std::set<T> &s) {\n\tif(s.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << \"{ \";\n\tfor(auto &t : s) {\n\t\tview(t);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <typename T>\nvoid view(const std::unordered_set<T> &s) {\n\tif(s.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << \"{ \";\n\tfor(auto &t : s) {\n\t\tview(t);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <typename T>\nvoid view(const std::vector<T> &v) {\n\tif(v.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << \"{ \";\n\tfor(const auto &e : v) {\n\t\tview(e);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <typename T>\nvoid view(const std::vector<std::vector<T>> &vv) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &v : vv) {\n\t\tstd::cerr << \"\\t\";\n\t\tview(v);\n\t\tstd::cerr << '\\n';\n\t}\n\tstd::cerr << \"}\";\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::vector<std::pair<T, U>> &v) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &c : v) {\n\t\tstd::cerr << \"\\t(\";\n\t\tview(c.first);\n\t\tstd::cerr << \", \";\n\t\tview(c.second);\n\t\tstd::cerr << \")\\n\";\n\t}\n\tstd::cerr << \"}\";\n}\n\ntemplate <class T0, class T1, class T2>\nvoid view(const std::vector<std::tuple<T0, T1, T2>> &v) {\n\tif(v.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << '{';\n\tfor(const auto &t : v) {\n\t\tstd::cerr << \"\\n\\t\";\n\t\tview(t);\n\t\tstd::cerr << \",\";\n\t}\n\tstd::cerr << \"\\n}\";\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid view(const std::vector<std::tuple<T0, T1, T2, T3>> &v) {\n\tif(v.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << '{';\n\tfor(const auto &t : v) {\n\t\tstd::cerr << \"\\n\\t\";\n\t\tview(t);\n\t\tstd::cerr << \",\";\n\t}\n\tstd::cerr << \"\\n}\";\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::map<T, U> &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &t : m) {\n\t\tstd::cerr << \"\\t[\";\n\t\tview(t.first);\n\t\tstd::cerr << \"] : \";\n\t\tview(t.second);\n\t\tstd::cerr << '\\n';\n\t}\n\tstd::cerr << \"}\";\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::unordered_map<T, U> &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &t : m) {\n\t\tstd::cerr << \"\\t[\";\n\t\tview(t.first);\n\t\tstd::cerr << \"] : \";\n\t\tview(t.second);\n\t\tstd::cerr << '\\n';\n\t}\n\tstd::cerr << \"}\";\n}\n} // namespace viewer\n\n#pragma endregion\n\n// when debugging : g++ foo.cpp -DLOCAL\n#ifdef LOCAL\nvoid debug_out() {}\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head H, Tail... T) {\n\tviewer::view(H);\n\tstd::cerr << \", \";\n\tdebug_out(T...);\n}\n#define debug(...) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"] : [\"; \\\n\t\tdebug_out(__VA_ARGS__); \\\n\t\tstd::cerr << \"\\b\\b]\\n\"; \\\n\t} while(0)\n#define dump(x) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" \" << #x << \" : \"; \\\n\t\tviewer::view(x); \\\n\t\tstd::cerr << '\\n'; \\\n\t} while(0)\n\n#else\n#define debug(...) (void(0))\n#define dump(x) (void(0))\n#endif\n\n#pragma endregion\n\n#pragma region geometry\n\nusing Real = long double;\nusing R = Real;\nusing Point = std::complex<Real>;\nusing Vec = Point;\nconst Real EPS = 1e-10, PI = acos(-1);\n\ninline bool eq(const Real &a, const Real &b) { return fabs(b - a) < EPS; }\ninline bool eq(const Point &a, const Point &b) { return fabs(b - a) < EPS; }\n/*\n\t-1: a < b\n\t0 : a == b\n\t1 : a > b\n*/\ninline int compare(const Real &a, const Real &b) { return eq(a, b) ? 0 : a < b ? -1 : 1; }\ninline int sign(const Real &a) { return fabs(a) < EPS ? 0 : a < 0 ? -1 : 1; }\n\nnamespace std {\nconst Point operator*(const Point &p, const Real &d) { return Point(real(p) * d, imag(p) * d); }\n} // namespace std\n\nstd::istream &operator>>(std::istream &is, Point &p) {\n\tReal a, b;\n\tis >> a >> b;\n\tp = Point(a, b);\n\treturn is;\n}\nstd::ostream &operator<<(std::ostream &os, Point &p) { return os << std::fixed << std::setprecision(10) << p.real() << \" \" << p.imag(); }\n\n// rotate point 'p' for counter clockwise direction\nconst Point rotate(const Real &theta, const Point &p) {\n\treturn Point(cos(theta) * p.real() - sin(theta) * p.imag(), sin(theta) * p.real() + cos(theta) * p.imag());\n}\n\nconst Real radian_to_degree(const Real &r) { return (r * 180.0 / PI); }\n\nconst Real degree_to_radian(const Real &d) { return (d * PI / 180.0); }\n\n// get angle a-b-c (<pi)\nconst Real get_angle(const Point &a, const Point &b, const Point &c) {\n\tconst Point v(a - b), w(c - b);\n\tReal theta = fabs(atan2(w.imag(), w.real()) - atan2(v.imag(), v.real()));\n\treturn std::min(theta, 2 * PI - theta);\n}\n\nnamespace std {\nbool operator<(const Point &a, const Point &b) { return a.real() != b.real() ? a.real() < b.real() : a.imag() < b.imag(); }\n} // namespace std\n\nstruct Line {\n\tPoint a, b;\n\n\tLine() = default;\n\n\tLine(Point a, Point b) : a(a), b(b) {}\n\n\tLine(Real A, Real B, Real C) // Ax + By = C\n\t{\n\t\tif(eq(A, 0))\n\t\t\ta = Point(0, C / B), b = Point(1, C / B);\n\t\telse if(eq(B, 0))\n\t\t\tb = Point(C / A, 0), b = Point(C / A, 1);\n\t\telse\n\t\t\ta = Point(0, C / B), b = Point(C / A, 0);\n\t}\n\n\tfriend std::ostream &operator<<(std::ostream &os, Line &p) { return os << p.a << \" -- \" << p.b; }\n\n\tfriend std::istream &operator>>(std::istream &is, Line &a) { return is >> a.a >> a.b; }\n};\n\nstruct Segment : Line {\n\tSegment() = default;\n\n\tSegment(Point a, Point b) : Line(a, b) {}\n};\n\nstruct Circle {\n\tPoint p;\n\tReal r;\n\n\tCircle() = default;\n\n\tCircle(Point p, Real r) : p(p), r(r) {}\n};\n\nusing Points = std::vector<Point>;\nusing Polygon = std::vector<Point>;\nusing Segments = std::vector<Segment>;\nusing Lines = std::vector<Line>;\nusing Circles = std::vector<Circle>;\n\nconst Real cross(const Point &a, const Point &b) { return real(a) * imag(b) - imag(a) * real(b); }\nconst Real dot(const Point &a, const Point &b) { return real(a) * real(b) + imag(a) * imag(b); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_C\nconst int ccw(const Point &a, Point b, Point c) {\n\tb = b - a, c = c - a;\n\tif(cross(b, c) > EPS) return +1;\t\t// \"COUNTER_CLOCKWISE\"\n\tif(cross(b, c) < -EPS) return -1;\t\t// \"CLOCKWISE\"\n\tif(dot(b, c) < -EPS) return +2;\t\t\t// \"ONLINE_BACK\"\n\tif(norm(b) + EPS < norm(c)) return -2;\t// \"ONLINE_FRONT\"\n\treturn 0;\t\t\t\t\t\t\t\t// \"ON_SEGMENT\"\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_A\nbool parallel(const Line &a, const Line &b) { return eq(cross(a.b - a.a, b.b - b.a), 0.0); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_A\nbool orthogonal(const Line &a, const Line &b) { return eq(dot(a.a - a.b, b.a - b.b), 0.0); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_A\nPoint projection(const Line &l, const Point &p) {\n\tdouble t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n\treturn l.a + (l.a - l.b) * t;\n}\n\nPoint projection(const Segment &l, const Point &p) {\n\tdouble t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n\treturn l.a + (l.a - l.b) * t;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_B\nPoint reflection(const Line &l, const Point &p) { return projection(l, p) * 2.0 - p; }\n\nint intersect(const Line &l, const Point &p) { return int(abs(ccw(l.a, l.b, p)) != 1); }\n\nint intersect(const Line &l, const Line &m) {\n\tif(intersect(l, m.a) && intersect(l, m.b)) return -1;\n\treturn int(abs(cross(l.b - l.a, m.b - m.a)) > EPS);\n}\n\nint intersect(const Segment &s, const Point &p) { return int(ccw(s.a, s.b, p) == 0); }\n\nint intersect(const Line &l, const Segment &s) {\n\tif(intersect(l, s.a) && intersect(l, s.b)) return -1;\n\treturn cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < EPS;\n}\n\nReal distance(const Line &l, const Point &p);\n\nint intersect(const Circle &c, const Line &l) {\n\tReal d = c.r - distance(l, c.p);\n\treturn fabs(d) < EPS ? 1 : d > 0. ? 2 : 0;\n}\n\nint intersect(const Circle &c, const Point &p) { return int(abs(abs(p - c.p) - c.r) < EPS); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_B\nint intersect(const Segment &s, const Segment &t) {\n\tif(eq(s.a, s.b)) return intersect(t, s.a);\n\tif(intersect(Line(s), t.a) && intersect(Line(s), t.b) &&\n\t std::max(std::min(s.a, s.b), std::min(t.a, t.b)) < std::min(std::max(s.a, s.b), std::max(t.a, t.b)))\n\t\treturn -1;\n\treturn int(ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 && ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0);\n}\n\nint intersect(const Circle &c, const Segment &l) {\n\tconst Point h = projection(l, c.p);\n\tif(norm(h - c.p) - c.r * c.r > EPS) return 0;\n\tauto d1 = abs(c.p - l.a), d2 = abs(c.p - l.b);\n\tif(compare(d1, c.r) == -1 && compare(d2, c.r) == -1) return 0;\n\tif(d1 < c.r - EPS && d2 > c.r - EPS || d1 > c.r - EPS && d2 < c.r - EPS) return 1;\n\treturn dot(l.a - h, l.b - h) < 0 ? 2 : 0;\n}\n\nReal distance(const Point &a, const Point &b);\n\nint number_of_common_tangents(const Circle &c1, const Circle &c2) {\n\tReal r1 = std::min(c1.r, c2.r), r2 = std::max(c1.r, c2.r), d = distance(c1.p, c2.p);\n\tint com = compare(r1 + r2, d);\n\treturn com == 1 ? compare(d + r1, r2) + 1 : 3 - com;\n\t// if(c1.r < c2.r) swap(c1, c2);\n\t// Real d = abs(c1.p - c2.p);\n\t// if(compare(c1.r + c2.r, d) == -1) return 4;\n\t// if(eq(c1.r + c2.r, d)) return 3;\n\t// if(compare(c1.r - c2.r, d) == -1) return 2;\n\t// return int(eq(c1.r - c2.r, d));\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_A&lang=jp\nint intersect(const Circle &c1, const Circle &c2) { return 2 - abs(2 - number_of_common_tangents(c1, c2)); }\n\nReal distance(const Point &a, const Point &b) { return abs(a - b); }\n\nReal distance(const Line &l, const Point &p) { return abs(p - projection(l, p)); }\n\nReal distance(const Line &l, const Line &m) { return intersect(l, m) ? 0 : distance(l, m.a); }\n\nReal distance(const Segment &s, const Point &p) {\n\tPoint r = projection(s, p);\n\treturn intersect(s, r) ? distance(r, p) : std::min(abs(s.a - p), abs(s.b - p));\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_D\nReal distance(const Segment &a, const Segment &b) {\n\tif(intersect(a, b)) return 0;\n\treturn std::min({distance(a, b.a), distance(a, b.b), distance(b, a.a), distance(b, a.b)});\n}\n\nReal distance(const Line &l, const Segment &s) {\n\tif(intersect(l, s)) return 0;\n\treturn std::min(distance(l, s.a), distance(l, s.b));\n}\n\nPoint crosspoint(const Line &l, const Line &m) {\n\tReal A = cross(l.b - l.a, m.b - m.a);\n\tReal B = cross(l.b - l.a, l.b - m.a);\n\tif(eq(abs(A), 0.0) && eq(abs(B), 0.0)) return m.a;\n\treturn m.a + (m.b - m.a) * B / A;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_C\nPoint crosspoint(const Segment &l, const Segment &m) { return crosspoint(Line(l), Line(m)); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_D\nstd::pair<Point, Point> crosspoint(const Circle &c, const Line l) {\n\tPoint pr = projection(l, c.p);\n\tif(eq(distance(l, c.p), c.r)) return {pr, pr};\n\tVec v = (l.b - l.a) / abs(l.b - l.a) * sqrt(c.r * c.r - norm(pr - c.p));\n\treturn make_pair(pr - v, pr + v);\n\t// Vec e = (l.b - l.a) / abs(l.b - l.a);\n\t// double base = sqrt(c.r * c.r - norm(pr - c.p));\n\t// return {pr - e * base, pr + e * base};\n}\n\nstd::pair<Point, Point> crosspoint(const Circle &c, const Segment &l) {\n\tif(intersect(c, l) == 2) return crosspoint(c, Line(l.a, l.b));\n\tauto ret = crosspoint(c, Line(l.a, l.b));\n\tif(dot(l.a - ret.first, l.b - ret.first) < EPS)\n\t\tret.second = ret.first;\n\telse\n\t\tret.first = ret.second;\n\treturn ret;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_E\nstd::pair<Point, Point> crosspoint(const Circle &c1, const Circle &c2) {\n\tReal d = abs(c1.p - c2.p);\n\tReal a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d)); // cosine theorem\n\tReal t = atan2(c2.p.imag() - c1.p.imag(), c2.p.real() - c1.p.real());\n\tPoint p1 = c1.p + Point(cos(t + a) * c1.r, sin(t + a) * c1.r);\n\tPoint p2 = c1.p + Point(cos(t - a) * c1.r, sin(t - a) * c1.r);\n\treturn make_pair(p1, p2);\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_F\n// \"点 p を通る円 c の接線\"の接点2つ\nstd::pair<Point, Point> tangent(const Circle &c1, const Point &p2) {\n\treturn crosspoint(c1, Circle(p2, sqrt(norm(c1.p - p2) - c1.r * c1.r)));\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_G\n// 円 c1, c2 の共通接線\nLines tangent(Circle c1, Circle c2) {\n\tLines ret;\n\tif(c1.r < c2.r) std::swap(c1, c2);\n\tReal g = norm(c1.p - c2.p);\n\tif(eq(g, 0)) return ret;\n\tVec u = (c2.p - c1.p) / Real(sqrt(g));\n\tVec v = rotate(PI * 0.5, u);\n\tfor(int s : {-1, 1}) {\n\t\tReal h = (c1.r + s * c2.r) / sqrt(g);\n\t\tif(eq(1 - h * h, 0)) {\n\t\t\tret.emplace_back(c1.p + u * c1.r, c1.p + (u + v) * c1.r);\n\t\t} else if(1 - h * h > 0) {\n\t\t\tPoint uu = u * h, vv = v * sqrt(1 - h * h);\n\t\t\tret.emplace_back(c1.p + (uu + vv) * c1.r, c2.p - (uu + vv) * c2.r * s);\n\t\t\tret.emplace_back(c1.p + (uu - vv) * c1.r, c2.p - (uu - vv) * c2.r * s);\n\t\t}\n\t}\n\treturn ret;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_B\nbool is_convex(const Polygon &p, bool pi_is_ok = false) {\n\tint n = p.size();\n\tif(pi_is_ok) {\n\t\tfor(int i = 0; i < n; i++)\n\t\t\tif(ccw(p[i], p[(i + 1) % n], p[(i + 2) % n]) == -1) return false;\n\t} else {\n\t\tfor(int i = 0; i < n; i++)\n\t\t\tif(ccw(p[i], p[(i + 1) % n], p[(i + 2) % n]) != 1) return false;\n\t}\n\treturn true;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_4_A\nPolygon convex_hull(Polygon &p, bool pi_is_ok = false) {\n\tint n = (int)p.size(), k = 0;\n\tif(n <= 2) return p;\n\tsort(p.begin(), p.end());\n\tPoints ch(2 * n);\n\tif(pi_is_ok) {\n\t\tfor(int i = 0; i < n; ch[k++] = p[i++])\n\t\t\twhile(k >= 2 && ccw(ch[k - 2], ch[k - 1], p[i]) == -1) --k;\n\t\tfor(int i = n - 2, t = k + 1; i >= 0; ch[k++] = p[i--])\n\t\t\twhile(k >= t && ccw(ch[k - 2], ch[k - 1], p[i]) == -1) --k;\n\t} else {\n\t\tfor(int i = 0; i < n; ch[k++] = p[i++])\n\t\t\twhile(k >= 2 && ccw(ch[k - 2], ch[k - 1], p[i]) != 1) --k;\n\t\tfor(int i = n - 2, t = k + 1; i >= 0; ch[k++] = p[i--])\n\t\t\twhile(k >= t && ccw(ch[k - 2], ch[k - 1], p[i]) != 1) --k;\n\t}\n\tch.resize(k - 1);\n\treturn ch;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_C\nenum { OUT, ON, IN };\nint contains(const Polygon &Q, const Point &p) {\n\tbool in = false;\n\tconst Real p_y = p.imag();\n\tfor(int i = 0; i < Q.size(); i++) {\n\t\tPoint a = Q[i], b = Q[(i + 1) % Q.size()];\n\t\tif(ccw(a, b, p) == 0) return ON;\n\t\tif(a.imag() > b.imag()) swap(a, b);\n\t\tif(a.imag() <= p_y && p_y < b.imag() && cross(a - p, b - p) < 0) in = !in;\n\t}\n\treturn in ? IN : OUT;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=1033\n// 線分の重複除去\nvoid merge_segments(std::vector<Segment> &segs) {\n\tauto merge_if_able = [](Segment &s1, const Segment &s2) {\n\t\tif(abs(cross(s1.b - s1.a, s2.b - s2.a)) > EPS) return false;\n\t\tif(ccw(s1.a, s2.a, s1.b) == 1 || ccw(s1.a, s2.a, s1.b) == -1) return false;\n\t\tif(ccw(s1.a, s1.b, s2.a) == -2 || ccw(s2.a, s2.b, s1.a) == -2) return false;\n\t\ts1 = Segment(min(s1.a, s2.a), max(s1.b, s2.b));\n\t\treturn true;\n\t};\n\n\tfor(int i = 0; i < segs.size(); i++) {\n\t\tif(segs[i].b < segs[i].a) swap(segs[i].a, segs[i].b);\n\t}\n\tfor(int i = 0; i < segs.size(); i++) {\n\t\tfor(int j = i + 1; j < segs.size(); j++) {\n\t\t\tif(merge_if_able(segs[i], segs[j])) {\n\t\t\t\tsegs[j--] = segs.back(), segs.pop_back();\n\t\t\t}\n\t\t}\n\t}\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=1033\n// 線分アレンジメント\n// 任意の2線分の交点を頂点としたグラフを構築する\nstd::vector<std::vector<int>> segment_arrangement(std::vector<Segment> &segs, std::vector<Point> &ps) {\n\tstd::vector<std::vector<int>> g;\n\tint N = (int)segs.size();\n\tfor(int i = 0; i < N; i++) {\n\t\tps.emplace_back(segs[i].a);\n\t\tps.emplace_back(segs[i].b);\n\t\tfor(int j = i + 1; j < N; j++) {\n\t\t\tconst Point p1 = segs[i].b - segs[i].a;\n\t\t\tconst Point p2 = segs[j].b - segs[j].a;\n\t\t\tif(eq(cross(p1, p2), 0)) continue;\t// \" == 0\" となっていたのを訂正\n\t\t\tif(intersect(segs[i], segs[j])) {\n\t\t\t\tps.emplace_back(crosspoint(segs[i], segs[j]));\n\t\t\t}\n\t\t}\n\t}\n\tsort(begin(ps), end(ps));\n\tps.erase(unique(begin(ps), end(ps)), end(ps));\t// 誤差?\n\n\tint M = (int)ps.size();\n\tg.resize(M);\n\tfor(int i = 0; i < N; i++) {\n\t\tstd::vector<int> vec;\n\t\tfor(int j = 0; j < M; j++) {\n\t\t\tif(intersect(segs[i], ps[j])) {\n\t\t\t\tvec.emplace_back(j);\n\t\t\t}\n\t\t}\n\t\tfor(int j = 1; j < vec.size(); j++) {\n\t\t\tg[vec[j - 1]].push_back(vec[j]);\n\t\t\tg[vec[j]].push_back(vec[j - 1]);\n\t\t}\n\t}\n\treturn (g);\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_4_C\n// 凸多角形の切断\n// 直線 l.a-l.b で切断しその左側にできる凸多角形を返す\nPolygon convex_cut(const Polygon &U, Line l) {\n\tPolygon ret;\n\tfor(int i = 0; i < U.size(); i++) {\n\t\tPoint now = U[i], nxt = U[(i + 1) % U.size()];\n\t\tif(ccw(l.a, l.b, now) != -1) ret.push_back(now);\n\t\tif(ccw(l.a, l.b, now) * ccw(l.a, l.b, nxt) == -1) ret.push_back(crosspoint(Line(now, nxt), l));\n\t}\n\treturn ret;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_A\n// 多角形の面積\nReal area(const Polygon &p) {\n\tReal A = 0;\n\tfor(int i = 0; i < p.size(); ++i) {\n\t\tA += cross(p[i], p[(i + 1) % p.size()]);\n\t}\n\treturn A * 0.5;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_H\n// 円と多角形の共通部分の面積\nReal area(const Polygon &p, const Circle &c) {\n\tif(p.size() < 3) return 0.0;\n\tauto cross_area = [&c](auto cross_area, const Point &a, const Point &b) -> Real {\n\t\tPoint va = c.p - a, vb = c.p - b;\n\t\tReal f = cross(va, vb), ret = 0.0;\n\t\tif(eq(f, 0.0)) return ret;\n\t\tif(std::max(abs(va), abs(vb)) < c.r + EPS) return f;\n\t\tif(distance(Segment(a, b), c.p) > c.r - EPS) return c.r * c.r * arg(vb * conj(va));\n\t\tauto u = crosspoint(c, Segment(a, b));\n\t\tstd::vector<Point> tot{a, u.first, u.second, b};\n\t\tfor(int i = 0; i + 1 < tot.size(); i++) ret += cross_area(cross_area, tot[i], tot[i + 1]);\n\t\treturn ret;\n\t};\n\tReal A = 0;\n\tfor(int i = 0; i < p.size(); i++) {\n\t\tA += cross_area(cross_area, p[i], p[(i + 1) % p.size()]);\n\t}\n\treturn A * 0.5;\n}\n\n// https://onlinejudge.u-aizu.ac.jp/courses/library/4/CGL/all/CGL_7_I\nReal area(const Circle &c1, const Circle &c2) {\n\tReal d = abs(c1.p - c2.p);\n\tif(c1.r + c2.r <= d + EPS) return 0.;\n\tif(abs(c1.r - c2.r) + EPS >= d) return pow(std::min(c1.r, c2.r), 2.) * PI;\n\tReal radius_diff = c1.r * c1.r - c2.r * c2.r;\n\tReal cosine_alpha = (d * d + radius_diff) / (2 * d * c1.r);\n\tReal cosine_beta = (d * d - radius_diff) / (2 * d * c2.r);\n\treturn c1.r * c1.r * (acos(cosine_alpha) - cosine_alpha * sqrt(1 - cosine_alpha * cosine_alpha)) +\n\t\t c2.r * c2.r * (acos(cosine_beta) - cosine_beta * sqrt(1 - cosine_beta * cosine_beta));\n}\n\n\n#pragma endregion\n\nvoid solve() {\n\tint n, time_end, radius;\n\tcin >> n >> time_end >> radius;\n\n\tif(n == 0) exit(0);\n\n\tV<string> nicknames;\n\n\tV<Points> place(n, Points(time_end + 1));\n\n\trep(id_robot, n) {\n\t\tstring nk;\n\t\tcin >> nk;\n\t\tnicknames.push_back(nk);\n\n\t\tint now = 0;\n\t\tint x, y;\n\n\t\twhile(now < time_end) {\n\t\t\tint t, vx, vy;\n\t\t\tcin >> t >> vx >> vy;\n\n\t\t\tif(t == 0) {\n\t\t\t\tx = vx;\n\t\t\t\ty = vy;\n\t\t\t\tplace[id_robot][0] = Point(x, y);\n\t\t\t} else {\n\t\t\t\twhile(now < t) {\n\t\t\t\t\tx += vx;\n\t\t\t\t\ty += vy;\n\t\t\t\t\tplace[id_robot][now + 1] = Point(x, y);\n\t\t\t\t\tnow++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tauto reachable = [&](const Point &p) { return compare(distance(p, Point(0, 0)), radius) <= 0; };\n\n\tV<tuple<R, int, int>> events;\n\n\trep(i, n) rep(j, i + 1, n) {\n\t\trep(t, time_end) {\n\t\t\tPoint a, b;\n\t\t\ta = place[j][t] - place[i][t];\n\t\t\tb = place[j][t + 1] - place[i][t + 1];\n\n\t\t\tR beg, end;\n\t\t\tSegment seg(a, b);\n\t\t\tCircle c(Point(0, 0), radius);\n\n\t\t\tif(reachable(a)) {\n\t\t\t\tbeg = t;\n\t\t\t\tif(reachable(b)) {\n\t\t\t\t\tend = t + 1;\n\t\t\t\t} else {\n\t\t\t\t\tif(intersect(c, seg)) {\n\t\t\t\t\t\tauto crs = crosspoint(c, seg).first;\n\t\t\t\t\t\tif(ccw(a, b, crs) == 0) {\n\t\t\t\t\t\t\tend = beg + distance(a, crs) / distance(a, b);\n\t\t\t\t\t\t} else {\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t} else {\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t} else {\n\t\t\t\tif(reachable(b)) {\n\t\t\t\t\tend = t + 1;\n\t\t\t\t\tif(intersect(c, seg)) {\n\t\t\t\t\t\tauto crs = crosspoint(c, seg).first;\n\t\t\t\t\t\tif(ccw(a, b, crs) == 0) {\n\t\t\t\t\t\t\tbeg = t + distance(a, crs) / distance(a, b);\n\t\t\t\t\t\t} else {\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t} else\n\t\t\t\t\t\tcontinue;\n\t\t\t\t} else {\n\t\t\t\t\tif(intersect(c, seg)) {\n\t\t\t\t\t\tauto crs = crosspoint(c, seg);\n\t\t\t\t\t\tbeg = t + distance(a, crs.first) / distance(a, b);\n\t\t\t\t\t\tend = t + distance(a, crs.second) / distance(a, b);\n\t\t\t\t\t\tif(beg > end) swap(beg, end);\n\t\t\t\t\t} else {\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif(isnan(beg) || isnan(end)) continue;\n\t\t\tif(beg > end) swap(beg, end);\n\n\t\t\tevents.emplace_back(beg, i, j);\n\t\t\tevents.emplace_back(end, i, j);\n\t\t}\n\t}\n\n\tsort(all(events));\n\n\tvvi conn(n, vi(n));\n\n\tvi know_info(n);\n\tknow_info[0] = 1;\n\n\tauto update = [&](int newcomer) {\n\t\tknow_info[newcomer] = 1;\n\t\tqueue<int> q;\n\t\tq.push(newcomer);\n\t\twhile(!q.empty()) {\n\t\t\tint now = q.front();\n\t\t\tq.pop();\n\t\t\trep(i, 1, n) {\n\t\t\t\tif(!conn[newcomer][i] || know_info[i]) continue;\n\t\t\t\tknow_info[i] = 1;\n\t\t\t\tq.push(i);\n\t\t\t}\n\t\t}\n\t\treturn;\n\t};\n\n\tfor(auto [time, i, j] : events) {\n\t\tdebug(time, i, j);\n\t\tif(know_info[i] == know_info[j]) continue;\n\t\tif(know_info[j]) swap(i, j);\n\n\t\tupdate(j);\n\n\t\tconn[i][j] ^= 1;\n\t}\n\n\tvector<string> ans;\n\trep(i, n) {\n\t\tif(know_info[i]) {\n\t\t\tans.push_back(nicknames[i]);\n\t\t}\n\t}\n\n\tsort(all(ans));\n\n\tvout(ans, 1);\n\treturn;\n}\nint main() {\n\tstd::ios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\tstd::cout << std::fixed << std::setprecision(15);\n\tsrand((unsigned)time(NULL));\n\n\twhile(1) solve();\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 950, "memory_kb": 6532, "score_of_the_acc": -0.9405, "final_rank": 16 }, { "submission_id": "aoj_1139_5497612", "code_snippet": "#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<ciso646>\n#include<random>\n#include<map>\n#include<set>\n#include<bitset>\n#include<stack>\n#include<unordered_map>\n#include<unordered_set>\n#include<utility>\n#include<cassert>\n#include<complex>\n#include<numeric>\n#include<array>\nusing namespace std;\n\n//#define int long long\ntypedef long long ll;\n\ntypedef unsigned long long ul;\ntypedef unsigned int ui;\nconstexpr ll mod = 1000000007;\nconst ll INF = mod * mod;\ntypedef pair<int, int>P;\n#define stop char nyaa;cin>>nyaa;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define per(i,n) for(int i=n-1;i>=0;i--)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define per1(i,n) for(int i=n;i>=1;i--)\n#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)\n#define all(v) (v).begin(),(v).end()\ntypedef pair<ll, ll> LP;\ntypedef long double ld;\ntypedef pair<ld, ld> LDP;\nconst ld eps = 1e-8;\nconst ld pi = acosl(-1.0);\n\nll mod_pow(ll x, ll n, ll m = mod) {\n\tif (n < 0) {\n\t\tll res = mod_pow(x, -n, m);\n\t\treturn mod_pow(res, m - 2, m);\n\t}\n\tif (abs(x) >= m)x %= m;\n\tif (x < 0)x += m;\n\tll res = 1;\n\twhile (n) {\n\t\tif (n & 1)res = res * x % m;\n\t\tx = x * x % m; n >>= 1;\n\t}\n\treturn res;\n}\nstruct modint {\n\tll n;\n\tmodint() :n(0) { ; }\n\tmodint(ll m) :n(m) {\n\t\tif (n >= mod)n %= mod;\n\t\telse if (n < 0)n = (n % mod + mod) % mod;\n\t}\n\toperator int() { return n; }\n};\nbool operator==(modint a, modint b) { return a.n == b.n; }\nmodint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }\nmodint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }\nmodint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }\nmodint operator+(modint a, modint b) { return a += b; }\nmodint operator-(modint a, modint b) { return a -= b; }\nmodint operator*(modint a, modint b) { return a *= b; }\nmodint operator^(modint a, ll n) {\n\tif (n == 0)return modint(1);\n\tmodint res = (a * a) ^ (n / 2);\n\tif (n % 2)res = res * a;\n\treturn res;\n}\n\nll inv(ll a, ll p) {\n\treturn (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);\n}\nmodint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }\nmodint operator/=(modint& a, modint b) { a = a / b; return a; }\nconst int max_n = 1 << 20;\nmodint fact[max_n], factinv[max_n];\nvoid init_f() {\n\tfact[0] = modint(1);\n\tfor (int i = 0; i < max_n - 1; i++) {\n\t\tfact[i + 1] = fact[i] * modint(i + 1);\n\t}\n\tfactinv[max_n - 1] = modint(1) / fact[max_n - 1];\n\tfor (int i = max_n - 2; i >= 0; i--) {\n\t\tfactinv[i] = factinv[i + 1] * modint(i + 1);\n\t}\n}\nmodint comb(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[b] * factinv[a - b];\n}\nmodint combP(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[a - b];\n}\ntypedef complex<ld> Point;\nld dot(Point a, Point b) { return real(conj(a) * b); }\nld cross(Point a, Point b) { return imag(conj(a) * b); }\nnamespace std {\n\tbool operator<(const Point& lhs, const Point& rhs) {\n\t\treturn lhs.real() == rhs.real() ? lhs.imag() < rhs.imag() : lhs.real() < rhs.real();\n\t}\n}\nstruct Line {\n\tPoint a, b;\n};\nstruct Circle {\n\tPoint p; ld r;\n};\nint ccw(Point a, Point b, Point c) {\n\tb -= a; c -= a;\n\tif (cross(b, c) > eps)return 1;//counter clockwise\n\tif (cross(b, c) < -eps)return -1;//clock wise\n\tif (dot(b, c) < 0)return 2;//c--a--b on line\n\tif (norm(b) < norm(c))return -2;//a--b--c on line\n\treturn 0; //a--c--b on line\n}\n\n//点が線分上に存在するか\nbool isis_sp(Line s, Point p) {\n\treturn (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n//点から直線への垂線の足\nPoint proj(Line l, Point p) {\n\tld t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n\treturn l.a + t * (l.a - l.b);\n}\n//線分と点の距離\nld dist_sp(Line s, Point p) {\n\tPoint r = proj(s, p);\n\treturn isis_sp(s, r) ? abs(p - r) : min(abs(p - s.a), abs(p - s.b));\n}\nconst int bb = 40;\nstruct ste {\n\tld tim; int a, b; int x;\n};\nbool operator<(ste a, ste b) {\n\tif (a.tim != b.tim)return a.tim < b.tim;\n\tif (a.a != b.a)return a.a < b.a;\n\tif (a.b != b.b)return a.b < b.b;\n\treturn a.x > b.x;\n}\n\nvector<string> als;\n\nint n, T, r;\nvoid solve() {\n\tvector<string> s(n);\n\tvector<vector<int>> t(n);\n\tvector<vector<Point>> loc(n);\n\tvector<vector<int>> vx(n);\n\tvector<vector<int>> vy(n);\n\trep(i, n) {\n\t\tcin >> s[i];\n\t\twhile (true) {\n\t\t\tint _t, _vx, _vy;\n\t\t\tcin >> _t >> _vx >> _vy;\n\t\t\tt[i].push_back(_t);\n\t\t\tvx[i].push_back(_vx);\n\t\t\tvy[i].push_back(_vy);\n\t\t\tif (_t == T)break;\n\t\t}\n\t\tloc[i].resize(T + 1);\n\t\tloc[i][0]={ (ld)vx[i][0],(ld)vy[i][0] };\n\t\tint cur = 1;\n\t\tint cx = vx[i][0], cy = vy[i][0];\n\t\tfor (int j = 1; j <= T; j++) {\n\t\t\tif (j > t[i][cur])cur++;\n\t\t\tcx += vx[i][cur];\n\t\t\tcy += vy[i][cur];\n\t\t\tloc[i][j] = { (ld)cx,(ld)cy };\n\t\t}\n\t}\n\tPoint ori = { (ld)0,(ld)0 };\n\tvector<ste> vs;\n\trep(i, n)Rep(j, i + 1, n) {\n\t\tint z = 0;\n\t\tif (abs(loc[i][0] - loc[j][0]) <= r) {\n\t\t\tz = 1;\n\t\t\tvs.push_back({ 0,i,j,1 });\n\t\t}\n\t\tfor (int k = 0; k < T; k++) {\n\t\t\tld lx = real(loc[j][k]) - real(loc[i][k]);\n\t\t\tld ly = imag(loc[j][k]) - imag(loc[i][k]);\n\t\t\tld rx = real(loc[j][k + 1]) - real(loc[i][k + 1]);\n\t\t\tld ry = imag(loc[j][k + 1]) - imag(loc[i][k + 1]);\n\t\t\tld dx = rx - lx;\n\t\t\tld dy = ry - ly;\n\t\t\tPoint pl = { lx,ly };\n\t\t\tPoint pr = { lx + dx,ly + dy };\n\t\t\tLine s = { pl,pr };\n\t\t\tif (z == 0) {\n\t\t\t\t//cout << \"?? \" << i << \" \" << j << \" \" << k << \"\\n\";\n\t\t\t\tif (dist_sp(s, ori) <= r) {\n\t\t\t\t\t//cout << \"?? \" << i << \" \" << j << \" \" << k << \"\\n\";\n\t\t\t\t\tif (abs(pr - ori) <= r) {\n\t\t\t\t\t\tld le = 0, ri = 1;\n\t\t\t\t\t\trep(aa, bb) {\n\t\t\t\t\t\t\tld m = (le + ri) / 2.0;\n\t\t\t\t\t\t\tPoint pm = { lx + dx * m,ly + dy * m };\n\t\t\t\t\t\t\tif (abs(pm - ori) <= r) {\n\t\t\t\t\t\t\t\tri = m;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\telse {\n\t\t\t\t\t\t\t\tle = m;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t\tvs.push_back({ le+k,i,j,1 });\n\t\t\t\t\t\tz = 1;\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\tPoint ph = proj(s, ori);\n\t\t\t\t\t\tld tmid = abs(ph - pl) / abs(pr - pl);\n\t\t\t\t\t\t//assert(0 - eps <= tmid && tmid <= 1 + eps);\n\t\t\t\t\t\tld le = 0, ri = tmid;\n\t\t\t\t\t\trep(aa, bb) {\n\t\t\t\t\t\t\tld m = (le + ri) / 2.0;\n\t\t\t\t\t\t\tPoint pm = { lx + dx * m,ly + dy * m };\n\t\t\t\t\t\t\tif (abs(pm - ori) <= r) {\n\t\t\t\t\t\t\t\tri = m;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\telse {\n\t\t\t\t\t\t\t\tle = m;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t\tvs.push_back({ le+k,i,j,1 });\n\t\t\t\t\t\tle = tmid, ri = 1;\n\t\t\t\t\t\trep(aa, bb) {\n\t\t\t\t\t\t\tld m = (le + ri) / 2.0;\n\t\t\t\t\t\t\tPoint pm = { lx + dx * m,ly + dy * m };\n\t\t\t\t\t\t\tif (abs(pm - ori) <= r) {\n\t\t\t\t\t\t\t\tle = m;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\telse {\n\t\t\t\t\t\t\t\tri = m;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t\tvs.push_back({ le+k,i,j,0 });\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\t//\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (abs(pr - ori) <= r) {\n\t\t\t\t\t//\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tld le = 0, ri = 1;\n\t\t\t\t\trep(aa, bb) {\n\t\t\t\t\t\tld m = (le + ri) / 2.0;\n\t\t\t\t\t\tPoint pm = { lx + dx * m,ly + dy * m };\n\t\t\t\t\t\tif (abs(pm - ori) <= r) {\n\t\t\t\t\t\t\tle = m;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse {\n\t\t\t\t\t\t\tri = m;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tvs.push_back({ le+k,i,j,0 });\n\t\t\t\t\tz = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tsort(all(vs));\n\tvector<set<int>> st(n);\n\tvector<bool> used(n);\n\tused[0] = true;\n\tauto add = [&](int a, int b) {\n\t\tst[a].insert(b);\n\t\tst[b].insert(a);\n\t\tif (used[a] == used[b])return;\n\t\tif (used[b])swap(a, b);\n\t\tqueue<int> q;\n\t\tq.push(b);\n\t\tused[b] = true;\n\t\twhile (!q.empty()) {\n\t\t\tint id = q.front(); q.pop();\n\t\t\tfor (int to : st[id]) {\n\t\t\t\tif (!used[to]) {\n\t\t\t\t\tused[to] = true;\n\t\t\t\t\tq.push(to);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t};\n\tauto del = [&](int a, int b) {\n\t\tst[a].erase(b);\n\t\tst[b].erase(a);\n\t};\n\trep(i, vs.size()) {\n\t\tint a = vs[i].a, b = vs[i].b, x = vs[i].x;\n\t\t//cout << vs[i].tim << \" \" << a << \" \" << b << \" \" << x << \"\\n\";\n\t\tif (x)add(a, b);\n\t\telse del(a, b);\n\t}\n\tvector<string> ss;\n\trep(i, n)if (used[i])ss.push_back(s[i]);\n\tsort(all(ss));\n\t//cout << \"ans is\\n\";\n\t//cout << \"----------------\\n\";\n\tfor (string s : ss)als.push_back(s);\n\t//cout << \"----------------\\n\";\n\t//cout << \".\\n\";\n}\nsigned main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\t//cout << fixed << setprecision(12);\n\t//init_f();\n\t//init();\n\t//expr();\n\t//int t; cin >> t;rep(i, t)\n\twhile(cin>>n>>T>>r,n)\n\tsolve();\n\tfor (string s : als)cout << s << \"\\n\";\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1350, "memory_kb": 23100, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_1139_5380199", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst double EPS = 0.00000001;\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n point operator +(point P){\n return point(x + P.x, y + P.y);\n }\n point operator -(point P){\n return point(x - P.x, y - P.y);\n }\n point operator *(double k){\n return point(x * k, y * k);\n }\n point operator /(double k){\n return point(x / k, y / k);\n }\n bool operator < (point P) const{\n return x < P.x || x == P.x && y < P.y;\n }\n};\ndouble abs(point P){\n return sqrt(P.x * P.x + P.y * P.y);\n}\ndouble dist(point P, point Q){\n return abs(Q - P);\n}\ndouble dot(point P, point Q){\n return P.x * Q.x + P.y * Q.y;\n}\ndouble cross(point P, point Q){\n return P.x * Q.y - P.y * Q.x;\n}\nstruct line{\n point A, B;\n line(point A, point B): A(A), B(B){\n }\n};\npoint vec(line L){\n return L.B - L.A;\n}\npoint projection(point P, line L){\n return L.A + vec(L) * dot(P - L.A, vec(L)) / abs(vec(L)) / abs(vec(L));\n}\ndouble point_line_distance(point P, line L){\n return abs(cross(L.A - P, vec(L))) / abs(vec(L));\n}\nstruct circle{\n point C;\n double r;\n circle(point C, double r): C(C), r(r){\n }\n};\nvector<point> line_circle_intersection(line L, circle C){\n double d = point_line_distance(C.C, L);\n if (d > C.r){\n return vector<point>();\n }\n point P = projection(C.C, L);\n point D = vec(L) / abs(vec(L));\n double m = sqrt(C.r * C.r - d * d);\n vector<point> ans = {P - D * m, P + D * m};\n return ans;\n}\nint main(){\n while (true){\n int N, T;\n double R;\n cin >> N >> T >> R;\n if (N == 0 && T == 0 && R == 0){\n break;\n }\n vector<string> s(N);\n vector<point> P(N);\n vector<vector<double>> t(N, vector<double>(1));\n vector<vector<point>> v(N);\n for (int i = 0; i < N; i++){\n cin >> s[i];\n cin >> t[i][0] >> P[i].x >> P[i].y;\n while (t[i].back() != T){\n t[i].push_back(0);\n v[i].push_back(point());\n cin >> t[i].back() >> v[i].back().x >> v[i].back().y;\n }\n }\n vector<tuple<double, int, int, bool>> upd;\n for (int i = 0; i < N; i++){\n for (int j = i + 1; j < N; j++){\n if (dist(P[i], P[j]) < R){\n upd.push_back(make_tuple(0, i, j, true));\n }\n int cnt1 = v[i].size(), cnt2 = v[j].size();\n vector<tuple<double, point, int>> c;\n for (int k = 0; k < cnt1; k++){\n c.push_back(make_tuple(t[i][k], v[i][k], 0));\n }\n for (int k = 0; k < cnt2; k++){\n c.push_back(make_tuple(t[j][k], v[j][k], 1));\n }\n sort(c.begin(), c.end());\n int cnt = c.size();\n point v1(0, 0), v2(0, 0);\n vector<double> t2(cnt + 1);\n vector<point> dv(cnt);\n for (int k = 0; k < cnt; k++){\n t2[k] = get<0>(c[k]);\n if (get<2>(c[k]) == 0){\n v1 = get<1>(c[k]);\n }\n if (get<2>(c[k]) == 1){\n v2 = get<1>(c[k]);\n }\n dv[k] = v2 - v1;\n }\n t2[cnt] = T;\n point D = P[j] - P[i];\n for (int k = 0; k < cnt; k++){\n if (abs(dv[k]) > EPS){\n point D2 = D + dv[k] * (t2[k + 1] - t2[k]);\n line L(D, D2);\n if (point_line_distance(point(0, 0), L) < R){\n circle C(point(0, 0), R);\n vector<point> I = line_circle_intersection(L, C);\n for (int l = 0; l < 2; l++){\n double d = dot(I[l] - D, D2 - D) / dist(D, D2);\n if (- EPS < d && d < dist(D, D2) + EPS){\n upd.push_back(make_tuple(t2[k] + d / abs(dv[k]), i, j, l == 0));\n }\n }\n }\n D = D2;\n }\n }\n }\n }\n sort(upd.begin(), upd.end());\n int M = upd.size();\n vector<vector<bool>> E(N, vector<bool>(N, false));\n vector<bool> used(N, false);\n used[0] = true;\n for (int i = 0; i < M; i++){\n int a = get<1>(upd[i]);\n int b = get<2>(upd[i]);\n bool e = get<3>(upd[i]);\n E[a][b] = e;\n E[b][a] = e;\n if (e && (used[a] ^ used[b])){\n queue<int> Q;\n if (!used[a]){\n used[a] = true;\n Q.push(a);\n }\n if (!used[b]){\n used[b] = true;\n Q.push(b);\n }\n while (!Q.empty()){\n int v = Q.front();\n Q.pop();\n for (int j = 0; j < N; j++){\n if (E[v][j] && !used[j]){\n used[j] = true;\n Q.push(j);\n }\n }\n }\n }\n }\n vector<string> ans;\n for (int i = 0; i < N; i++){\n if (used[i]){\n ans.push_back(s[i]);\n }\n }\n sort(ans.begin(), ans.end());\n int cnt = ans.size();\n for (int i = 0; i < cnt; i++){\n cout << ans[i] << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3320, "score_of_the_acc": -0.099, "final_rank": 5 }, { "submission_id": "aoj_1139_5380189", "code_snippet": "//WA\n#include <bits/stdc++.h>\nusing namespace std;\nconst double EPS = 0.00000001;\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n point operator +(point P){\n return point(x + P.x, y + P.y);\n }\n point operator -(point P){\n return point(x - P.x, y - P.y);\n }\n point operator *(double k){\n return point(x * k, y * k);\n }\n point operator /(double k){\n return point(x / k, y / k);\n }\n bool operator < (point P) const{\n return x < P.x || x == P.x && y < P.y;\n }\n};\ndouble abs(point P){\n return sqrt(P.x * P.x + P.y * P.y);\n}\ndouble dist(point P, point Q){\n return abs(Q - P);\n}\ndouble dot(point P, point Q){\n return P.x * Q.x + P.y * Q.y;\n}\ndouble cross(point P, point Q){\n return P.x * Q.y - P.y * Q.x;\n}\nstruct line{\n point A, B;\n line(point A, point B): A(A), B(B){\n }\n};\npoint vec(line L){\n return L.B - L.A;\n}\npoint projection(point P, line L){\n return L.A + vec(L) * dot(P - L.A, vec(L)) / abs(vec(L)) / abs(vec(L));\n}\ndouble point_line_distance(point P, line L){\n return abs(cross(L.A - P, vec(L))) / abs(vec(L));\n}\nstruct circle{\n point C;\n double r;\n circle(point C, double r): C(C), r(r){\n }\n};\nvector<point> line_circle_intersection(line L, circle C){\n double d = point_line_distance(C.C, L);\n if (d > C.r){\n \treturn vector<point>();\n }\n point P = projection(C.C, L);\n point D = vec(L) / abs(vec(L));\n double m = sqrt(C.r * C.r - d * d);\n vector<point> ans = {P - D * m, P + D * m};\n return ans;\n}\nint main(){\n while (true){\n int N, T;\n double R;\n cin >> N >> T >> R;\n if (N == 0 && T == 0 && R == 0){\n break;\n }\n vector<string> s(N);\n vector<point> P(N);\n vector<vector<double>> t(N, vector<double>(1));\n vector<vector<point>> v(N);\n for (int i = 0; i < N; i++){\n cin >> s[i];\n cin >> t[i][0] >> P[i].x >> P[i].y;\n while (t[i].back() != T){\n t[i].push_back(0);\n v[i].push_back(point());\n cin >> t[i].back() >> v[i].back().x >> v[i].back().y;\n }\n }\n vector<tuple<double, int, int, bool>> upd;\n for (int i = 0; i < N; i++){\n for (int j = i + 1; j < N; j++){\n if (dist(P[i], P[j]) < R){\n upd.push_back(make_tuple(0, i, j, true));\n }\n int cnt1 = v[i].size(), cnt2 = v[j].size();\n vector<tuple<double, point, int>> c;\n for (int k = 0; k < cnt1; k++){\n c.push_back(make_tuple(t[i][k], v[i][k], 0));\n }\n for (int k = 0; k < cnt2; k++){\n c.push_back(make_tuple(t[j][k], v[j][k], 1));\n }\n sort(c.begin(), c.end());\n int cnt = c.size();\n point v1(0, 0), v2(0, 0);\n vector<double> t2(cnt + 1);\n vector<point> dv(cnt);\n for (int k = 0; k < cnt; k++){\n t2[k] = get<0>(c[k]);\n if (get<2>(c[k]) == 0){\n v1 = get<1>(c[k]);\n }\n if (get<2>(c[k]) == 1){\n v2 = get<1>(c[k]);\n }\n dv[k] = v2 - v1;\n }\n t2[cnt] = T;\n point D = P[j] - P[i];\n for (int k = 0; k < cnt; k++){\n \tif (abs(dv[k]) > EPS){\n point D2 = D + dv[k] * (t2[k + 1] - t2[k]);\n line L(D, D2);\n if (point_line_distance(point(0, 0), L) < R){\n circle C(point(0, 0), R);\n vector<point> I = line_circle_intersection(L, C);\n for (int l = 0; l < 2; l++){\n double d = dot(I[l] - D, D2 - D) / dist(D, D2);\n if (0 < d && d < dist(D, D2)){\n upd.push_back(make_tuple(t2[k] + d / abs(dv[k]), i, j, l == 0));\n }\n }\n }\n D = D2;\n }\n }\n }\n }\n sort(upd.begin(), upd.end());\n int M = upd.size();\n vector<vector<bool>> E(N, vector<bool>(N, false));\n vector<bool> used(N, false);\n used[0] = true;\n for (int i = 0; i < M; i++){\n int a = get<1>(upd[i]);\n int b = get<2>(upd[i]);\n bool e = get<3>(upd[i]);\n E[a][b] = e;\n E[b][a] = e;\n if (e && (used[a] ^ used[b])){\n queue<int> Q;\n if (!used[a]){\n used[a] = true;\n Q.push(a);\n }\n if (!used[b]){\n used[b] = true;\n Q.push(b);\n }\n while (!Q.empty()){\n int v = Q.front();\n Q.pop();\n for (int j = 0; j < N; j++){\n if (E[v][j] && !used[j]){\n used[j] = true;\n Q.push(j);\n }\n }\n }\n }\n }\n vector<string> ans;\n for (int i = 0; i < N; i++){\n if (used[i]){\n ans.push_back(s[i]);\n }\n }\n sort(ans.begin(), ans.end());\n int cnt = ans.size();\n for (int i = 0; i < cnt; i++){\n cout << ans[i] << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3212, "score_of_the_acc": -0.094, "final_rank": 4 }, { "submission_id": "aoj_1139_5380084", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst double EPS = 0.00000001;\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n point operator +(point P){\n return point(x + P.x, y + P.y);\n }\n point operator -(point P){\n return point(x - P.x, y - P.y);\n }\n point operator *(double k){\n return point(x * k, y * k);\n }\n point operator /(double k){\n return point(x / k, y / k);\n }\n bool operator < (point P) const{\n return x < P.x || x == P.x && y < P.y;\n }\n};\ndouble abs(point P){\n return sqrt(P.x * P.x + P.y * P.y);\n}\ndouble dist(point P, point Q){\n return abs(Q - P);\n}\ndouble dot(point P, point Q){\n return P.x * Q.x + P.y * Q.y;\n}\ndouble cross(point P, point Q){\n return P.x * Q.y - P.y * Q.x;\n}\nstruct line{\n point A, B;\n line(point A, point B): A(A), B(B){\n }\n};\npoint vec(line L){\n return L.B - L.A;\n}\npoint projection(point P, line L){\n return L.A + vec(L) * dot(P - L.A, vec(L)) / abs(vec(L)) / abs(vec(L));\n}\ndouble point_line_distance(point P, line L){\n return abs(cross(L.A - P, vec(L))) / abs(vec(L));\n}\nstruct circle{\n point C;\n double r;\n circle(point C, double r): C(C), r(r){\n }\n};\nvector<point> line_circle_intersection(line L, circle C){\n double d = point_line_distance(C.C, L);\n if (d > C.r){\n \treturn vector<point>();\n }\n point P = projection(C.C, L);\n point D = vec(L) / abs(vec(L));\n double m = sqrt(C.r * C.r - d * d);\n vector<point> ans = {P - D * m, P + D * m};\n return ans;\n}\nint main(){\n while (true){\n int N, T;\n double R;\n cin >> N >> T >> R;\n if (N == 0 && T == 0 && R == 0){\n break;\n }\n vector<string> s(N);\n vector<point> P(N);\n vector<vector<double>> t(N, vector<double>(1));\n vector<vector<point>> v(N);\n for (int i = 0; i < N; i++){\n cin >> s[i];\n cin >> t[i][0] >> P[i].x >> P[i].y;\n while (t[i].back() != T){\n t[i].push_back(0);\n v[i].push_back(point());\n cin >> t[i].back() >> v[i].back().x >> v[i].back().y;\n }\n }\n vector<tuple<double, int, int, bool>> upd;\n for (int i = 0; i < N; i++){\n for (int j = i + 1; j < N; j++){\n if (dist(P[i], P[j]) < R){\n upd.push_back(make_tuple(0, i, j, true));\n }\n int cnt1 = v[i].size(), cnt2 = v[j].size();\n vector<tuple<double, point, int>> c;\n for (int k = 0; k < cnt1; k++){\n c.push_back(make_tuple(t[i][k], v[i][k], 0));\n }\n for (int k = 0; k < cnt2; k++){\n c.push_back(make_tuple(t[j][k], v[j][k], 1));\n }\n sort(c.begin(), c.end());\n int cnt = c.size();\n point v1(0, 0), v2(0, 0);\n vector<double> t2(cnt + 1);\n vector<point> dv(cnt);\n for (int k = 0; k < cnt; k++){\n t2[k] = get<0>(c[k]);\n if (get<2>(c[k]) == 0){\n v1 = get<1>(c[k]);\n }\n if (get<2>(c[k]) == 1){\n v2 = get<1>(c[k]);\n }\n dv[k] = v2 - v1;\n }\n t2[cnt] = T;\n point D = P[j] - P[i];\n for (int k = 0; k < cnt; k++){\n \tif (abs(dv[k]) > EPS){\n point D2 = D + dv[k] * (t2[k + 1] - t2[k]);\n line L(D, D2);\n if (point_line_distance(point(0, 0), L) < R){\n circle C(point(0, 0), R);\n vector<point> I = line_circle_intersection(L, C);\n for (int l = 0; l < 2; l++){\n double d = dot(I[l] - D, D2 - D) / dist(D, D2);\n if (-\tEPS < d && d < dist(D, D2) + EPS){\n upd.push_back(make_tuple(t2[k] + d / abs(dv[k]), i, j, l == 0));\n }\n }\n }\n D = D2;\n }\n }\n }\n }\n sort(upd.begin(), upd.end());\n int M = upd.size();\n vector<vector<bool>> E(N, vector<bool>(N, false));\n vector<bool> used(N, false);\n used[0] = true;\n for (int i = 0; i < M; i++){\n int a = get<1>(upd[i]);\n int b = get<2>(upd[i]);\n bool e = get<3>(upd[i]);\n E[a][b] = e;\n E[b][a] = e;\n if (e && (used[a] ^ used[b])){\n queue<int> Q;\n if (!used[a]){\n used[a] = true;\n Q.push(a);\n }\n if (!used[b]){\n used[b] = true;\n Q.push(b);\n }\n while (!Q.empty()){\n int v = Q.front();\n Q.pop();\n for (int j = 0; j < N; j++){\n if (E[v][j] && !used[j]){\n used[j] = true;\n Q.push(j);\n }\n }\n }\n }\n }\n vector<string> ans;\n for (int i = 0; i < N; i++){\n if (used[i]){\n ans.push_back(s[i]);\n }\n }\n sort(ans.begin(), ans.end());\n int cnt = ans.size();\n for (int i = 0; i < cnt; i++){\n cout << ans[i] << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3348, "score_of_the_acc": -0.1002, "final_rank": 6 }, { "submission_id": "aoj_1139_4253316", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}\nusing Int = long long;\nconst char newl = '\\n';\n\n\n#define EPS (1e-7)\n#define equals(a,b) (fabs((a)-(b)) < EPS)\nconst double PI = asinl(1) * 2;\n\n// COUNTER CLOCKWISE\nstatic const int CCW_COUNTER_CLOCKWISE = 1;\nstatic const int CCW_CLOCKWISE = -1;\nstatic const int CCW_ONLINE_BACK = 2;\nstatic const int CCW_ONLINE_FRONT = -2;\nstatic const int CCW_ON_SEGMENT = 0;\n\n// intercsect of circles\nstatic const int ICC_SEPERATE = 4;\nstatic const int ICC_CIRCUMSCRIBE = 3;\nstatic const int ICC_INTERSECT = 2;\nstatic const int ICC_INSCRIBE = 1;\nstatic const int ICC_CONTAIN = 0;\n\nstruct Point{\n double x,y;\n Point(){}\n Point(double x,double y) :x(x),y(y){}\n Point operator+(Point p) {return Point(x+p.x,y+p.y);}\n Point operator-(Point p) {return Point(x-p.x,y-p.y);}\n Point operator*(double k){return Point(x*k,y*k);}\n Point operator/(double k){return Point(x/k,y/k);}\n double norm(){return x*x+y*y;}\n double abs(){return sqrt(norm());}\n\n bool operator < (const Point &p) const{\n return x!=p.x?x<p.x:y<p.y;\n //grid-point only\n //return !equals(x,p.x)?x<p.x:!equals(y,p.y)?y<p.y:0;\n }\n\n bool operator == (const Point &p) const{\n return fabs(x-p.x)<EPS && fabs(y-p.y)<EPS;\n }\n};\n\nstruct EndPoint{\n Point p;\n int seg,st;\n EndPoint(){}\n EndPoint(Point p,int seg,int st):p(p),seg(seg),st(st){}\n bool operator<(const EndPoint &ep)const{\n if(p.y==ep.p.y) return st<ep.st;\n return p.y<ep.p.y;\n }\n};\n\nistream &operator >> (istream &is,Point &p){\n is>>p.x>>p.y;\n return is;\n}\n\nostream &operator << (ostream &os,Point p){\n os<<fixed<<setprecision(12)<<p.x<<\" \"<<p.y;\n return os;\n}\n\nbool sort_x(Point a,Point b){\n return a.x!=b.x?a.x<b.x:a.y<b.y;\n}\n\nbool sort_y(Point a,Point b){\n return a.y!=b.y?a.y<b.y:a.x<b.x;\n}\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nistream &operator >> (istream &is,Polygon &p){\n for(int i=0;i<(int)p.size();i++) is>>p[i];\n return is;\n}\n\nstruct Segment{\n Point p1,p2;\n Segment(){}\n Segment(Point p1, Point p2):p1(p1),p2(p2){}\n};\ntypedef Segment Line;\n\nistream &operator >> (istream &is,Segment &s){\n is>>s.p1>>s.p2;\n return is;\n}\n\nstruct Circle{\n Point c;\n double r;\n Circle(){}\n Circle(Point c,double r):c(c),r(r){}\n};\n\nistream &operator >> (istream &is,Circle &c){\n is>>c.c>>c.r;\n return is;\n}\n\ndouble norm(Vector a){\n return a.x*a.x+a.y*a.y;\n}\ndouble abs(Vector a){\n return sqrt(norm(a));\n}\ndouble dot(Vector a,Vector b){\n return a.x*b.x+a.y*b.y;\n}\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\nPoint orth(Point p){return Point(-p.y,p.x);}\n\nbool isOrthogonal(Vector a,Vector b){\n return equals(dot(a,b),0.0);\n}\n\nbool isOrthogonal(Point a1,Point a2,Point b1,Point b2){\n return isOrthogonal(a1-a2,b1-b2);\n}\n\nbool isOrthogonal(Segment s1,Segment s2){\n return equals(dot(s1.p2-s1.p1,s2.p2-s2.p1),0.0);\n}\n\nbool isParallel(Vector a,Vector b){\n return equals(cross(a,b),0.0);\n}\n\nbool isParallel(Point a1,Point a2,Point b1,Point b2){\n return isParallel(a1-a2,b1-b2);\n}\n\nbool isParallel(Segment s1,Segment s2){\n return equals(cross(s1.p2-s1.p1,s2.p2-s2.p1),0.0);\n}\n\nPoint project(Segment s,Point p){\n Vector base=s.p2-s.p1;\n double r=dot(p-s.p1,base)/norm(base);\n return s.p1+base*r;\n}\n\nPoint reflect(Segment s,Point p){\n return p+(project(s,p)-p)*2.0;\n}\n\ndouble arg(Vector p){\n return atan2(p.y,p.x);\n}\n\nVector polar(double a,double r){\n return Point(cos(r)*a,sin(r)*a);\n}\n\nint ccw(Point p0,Point p1,Point p2);\nbool intersectSS(Point p1,Point p2,Point p3,Point p4);\nbool intersectSS(Segment s1,Segment s2);\nbool intersectPS(Polygon p,Segment l);\nint intersectCC(Circle c1,Circle c2);\nbool intersectSC(Segment s,Circle c);\ndouble getDistanceLP(Line l,Point p);\ndouble getDistanceSP(Segment s,Point p);\ndouble getDistanceSS(Segment s1,Segment s2);\nPoint getCrossPointSS(Segment s1,Segment s2);\nPoint getCrossPointLL(Line l1,Line l2);\nPolygon getCrossPointCL(Circle c,Line l);\nPolygon getCrossPointCC(Circle c1,Circle c2);\nint contains(Polygon g,Point p);\nPolygon andrewScan(Polygon s);\nPolygon convex_hull(Polygon ps);\ndouble diameter(Polygon s);\nbool isConvex(Polygon p);\ndouble area(Polygon s);\nPolygon convexCut(Polygon p,Line l);\nLine bisector(Point p1,Point p2);\nVector translate(Vector v,double theta);\nvector<Line> corner(Line l1,Line l2);\nvector< vector<int> >\nsegmentArrangement(vector<Segment> &ss, Polygon &ps);\n\nint ccw(Point p0,Point p1,Point p2){\n Vector a = p1-p0;\n Vector b = p2-p0;\n if(cross(a,b) > EPS) return CCW_COUNTER_CLOCKWISE;\n if(cross(a,b) < -EPS) return CCW_CLOCKWISE;\n if(dot(a,b) < -EPS) return CCW_ONLINE_BACK;\n if(a.norm()<b.norm()) return CCW_ONLINE_FRONT;\n return CCW_ON_SEGMENT;\n}\n\nbool intersectSS(Point p1,Point p2,Point p3,Point p4){\n return (ccw(p1,p2,p3)*ccw(p1,p2,p4) <= 0 &&\n ccw(p3,p4,p1)*ccw(p3,p4,p2) <= 0 );\n}\n\nbool intersectSS(Segment s1,Segment s2){\n return intersectSS(s1.p1,s1.p2,s2.p1,s2.p2);\n}\n\nbool intersectPS(Polygon p,Segment l){\n int n=p.size();\n for(int i=0;i<n;i++)\n if(intersectSS(Segment(p[i],p[(i+1)%n]),l)) return 1;\n return 0;\n}\n\nint intersectCC(Circle c1,Circle c2){\n if(c1.r<c2.r) swap(c1,c2);\n double d=abs(c1.c-c2.c);\n double r=c1.r+c2.r;\n if(equals(d,r)) return ICC_CIRCUMSCRIBE;\n if(d>r) return ICC_SEPERATE;\n if(equals(d+c2.r,c1.r)) return ICC_INSCRIBE;\n if(d+c2.r<c1.r) return ICC_CONTAIN;\n return ICC_INTERSECT;\n}\n\nbool intersectSC(Segment s,Circle c){\n return getDistanceSP(s,c.c)<=c.r;\n}\n\nint intersectCS(Circle c,Segment s){\n if(norm(project(s,c.c)-c.c)-c.r*c.r>EPS) return 0;\n double d1=abs(c.c-s.p1),d2=abs(c.c-s.p2);\n if(d1<c.r+EPS&&d2<c.r+EPS) return 0;\n if((d1<c.r-EPS&&d2>c.r+EPS)||(d1>c.r+EPS&&d2<c.r-EPS)) return 1;\n Point h=project(s,c.c);\n if(dot(s.p1-h,s.p2-h)<0) return 2;\n return 0;\n}\n\ndouble getDistanceLP(Line l,Point p){\n return abs(cross(l.p2-l.p1,p-l.p1)/abs(l.p2-l.p1));\n}\n\ndouble getDistanceSP(Segment s,Point p){\n if(dot(s.p2-s.p1,p-s.p1) < 0.0 ) return abs(p-s.p1);\n if(dot(s.p1-s.p2,p-s.p2) < 0.0 ) return abs(p-s.p2);\n return getDistanceLP(s,p);\n}\n\ndouble getDistanceSS(Segment s1,Segment s2){\n if(intersectSS(s1,s2)) return 0.0;\n return min(min(getDistanceSP(s1,s2.p1),getDistanceSP(s1,s2.p2)),\n min(getDistanceSP(s2,s1.p1),getDistanceSP(s2,s1.p2)));\n}\n\nPoint getCrossPointSS(Segment s1,Segment s2){\n for(int k=0;k<2;k++){\n if(getDistanceSP(s1,s2.p1)<EPS) return s2.p1;\n if(getDistanceSP(s1,s2.p2)<EPS) return s2.p2;\n swap(s1,s2);\n }\n Vector base=s2.p2-s2.p1;\n double d1=abs(cross(base,s1.p1-s2.p1));\n double d2=abs(cross(base,s1.p2-s2.p1));\n double t=d1/(d1+d2);\n return s1.p1+(s1.p2-s1.p1)*t;\n}\n\nPoint getCrossPointLL(Line l1,Line l2){\n double a=cross(l1.p2-l1.p1,l2.p2-l2.p1);\n double b=cross(l1.p2-l1.p1,l1.p2-l2.p1);\n if(abs(a)<EPS&&abs(b)<EPS) return l2.p1;\n return l2.p1+(l2.p2-l2.p1)*(b/a);\n}\n\nPolygon getCrossPointCL(Circle c,Line l){\n Polygon ps;\n Point pr=project(l,c.c);\n Vector e=(l.p2-l.p1)/abs(l.p2-l.p1);\n if(equals(getDistanceLP(l,c.c),c.r)){\n ps.emplace_back(pr);\n return ps;\n }\n double base=sqrt(c.r*c.r-norm(pr-c.c));\n ps.emplace_back(pr+e*base);\n ps.emplace_back(pr-e*base);\n return ps;\n}\n\nPolygon getCrossPointCS(Circle c,Segment s){\n Line l(s);\n Polygon res=getCrossPointCL(c,l);\n if(intersectCS(c,s)==2) return res;\n if(res.size()>1u){\n if(dot(l.p1-res[0],l.p2-res[0])>0) swap(res[0],res[1]);\n res.pop_back();\n }\n return res;\n}\n\n\nPolygon getCrossPointCC(Circle c1,Circle c2){\n Polygon p(2);\n double d=abs(c1.c-c2.c);\n double a=acos((c1.r*c1.r+d*d-c2.r*c2.r)/(2*c1.r*d));\n double t=arg(c2.c-c1.c);\n p[0]=c1.c+polar(c1.r,t+a);\n p[1]=c1.c+polar(c1.r,t-a);\n return p;\n}\n\n// IN:2 ON:1 OUT:0\nint contains(Polygon g,Point p){\n int n=g.size();\n bool x=false;\n for(int i=0;i<n;i++){\n Point a=g[i]-p,b=g[(i+1)%n]-p;\n if(fabs(cross(a,b)) < EPS && dot(a,b) < EPS) return 1;\n if(a.y>b.y) swap(a,b);\n if(a.y < EPS && EPS < b.y && cross(a,b) > EPS ) x = !x;\n }\n return (x?2:0);\n}\n\nPolygon andrewScan(Polygon s){\n Polygon u,l;\n if(s.size()<3) return s;\n sort(s.begin(),s.end());\n u.push_back(s[0]);\n u.push_back(s[1]);\n l.push_back(s[s.size()-1]);\n l.push_back(s[s.size()-2]);\n for(int i=2;i<(int)s.size();i++){\n for(int n=u.size();\n n>=2&&ccw(u[n-2],u[n-1],s[i])!=CCW_CLOCKWISE;\n n--){\n u.pop_back();\n }\n u.push_back(s[i]);\n }\n for(int i=s.size()-3;i>=0;i--){\n for(int n=l.size();\n n>=2&&ccw(l[n-2],l[n-1],s[i])!=CCW_CLOCKWISE;\n n--){\n l.pop_back();\n }\n l.push_back(s[i]);\n }\n reverse(l.begin(),l.end());\n for(int i=u.size()-2;i>=1;i--) l.push_back(u[i]);\n return l;\n}\n\nPolygon convex_hull(Polygon ps){\n int n=ps.size();\n sort(ps.begin(),ps.end(),sort_y);\n int k=0;\n Polygon qs(n*2);\n for(int i=0;i<n;i++){\n while(k>1&&cross(qs[k-1]-qs[k-2],ps[i]-qs[k-1])<0) k--;\n qs[k++]=ps[i];\n }\n for(int i=n-2,t=k;i>=0;i--){\n while(k>t&&cross(qs[k-1]-qs[k-2],ps[i]-qs[k-1])<0) k--;\n qs[k++]=ps[i];\n }\n qs.resize(k-1);\n return qs;\n}\n\ndouble diameter(Polygon s){\n Polygon p=s;\n int n=p.size();\n if(n==2) return abs(p[0]-p[1]);\n int i=0,j=0;\n for(int k=0;k<n;k++){\n if(p[i]<p[k]) i=k;\n if(!(p[j]<p[k])) j=k;\n }\n double res=0;\n int si=i,sj=j;\n while(i!=sj||j!=si){\n res=max(res,abs(p[i]-p[j]));\n if(cross(p[(i+1)%n]-p[i],p[(j+1)%n]-p[j])<0.0){\n i=(i+1)%n;\n }else{\n j=(j+1)%n;\n }\n }\n return res;\n}\n\nbool isConvex(Polygon p){\n bool f=1;\n int n=p.size();\n for(int i=0;i<n;i++){\n int t=ccw(p[(i+n-1)%n],p[i],p[(i+1)%n]);\n f&=t!=CCW_CLOCKWISE;\n }\n return f;\n}\n\ndouble area(Polygon s){\n double res=0;\n for(int i=0;i<(int)s.size();i++){\n res+=cross(s[i],s[(i+1)%s.size()])/2.0;\n }\n return res;\n}\n\ndouble area(Circle c1,Circle c2){\n double d=abs(c1.c-c2.c);\n if(c1.r+c2.r<=d+EPS) return 0;\n if(d<=abs(c1.r-c2.r)){\n double r=min(c1.r,c2.r);\n return PI*r*r;\n }\n double res=0;\n for(int k=0;k<2;k++){\n double rc=(d*d+c1.r*c1.r-c2.r*c2.r)/(2*d*c1.r);\n double th=acosl(rc)*2;\n res+=(th-sinl(th))*c1.r*c1.r/2;\n swap(c1,c2);\n }\n return res;\n}\n\nPolygon convexCut(Polygon p,Line l){\n Polygon q;\n for(int i=0;i<(int)p.size();i++){\n Point a=p[i],b=p[(i+1)%p.size()];\n if(ccw(l.p1,l.p2,a)!=-1) q.push_back(a);\n if(ccw(l.p1,l.p2,a)*ccw(l.p1,l.p2,b)<0)\n q.push_back(getCrossPointLL(Line(a,b),l));\n }\n return q;\n}\n\nLine bisector(Point p1,Point p2){\n Circle c1=Circle(p1,abs(p1-p2)),c2=Circle(p2,abs(p1-p2));\n Polygon p=getCrossPointCC(c1,c2);\n if(cross(p2-p1,p[0]-p1)>0) swap(p[0],p[1]);\n return Line(p[0],p[1]);\n}\n\nVector translate(Vector v,double theta){\n Vector res;\n res.x=cos(theta)*v.x-sin(theta)*v.y;\n res.y=sin(theta)*v.x+cos(theta)*v.y;\n return res;\n}\n\nvector<Line> corner(Line l1,Line l2){\n vector<Line> res;\n if(isParallel(l1,l2)){\n double d=getDistanceLP(l1,l2.p1)/2.0;\n Vector v1=l1.p2-l1.p1;\n v1=v1/v1.abs()*d;\n Point p=l2.p1+translate(v1,90.0*(PI/180.0));\n double d1=getDistanceLP(l1,p);\n double d2=getDistanceLP(l2,p);\n if(abs(d1-d2)>d){\n p=l2.p1+translate(v1,-90.0*(PI/180.0));\n }\n res.push_back(Line(p,p+v1));\n }else{\n Point p=getCrossPointLL(l1,l2);\n Vector v1=l1.p2-l1.p1,v2=l2.p2-l2.p1;\n v1=v1/v1.abs();\n v2=v2/v2.abs();\n res.push_back(Line(p,p+(v1+v2)));\n res.push_back(Line(p,p+translate(v1+v2,90.0*(PI/180.0))));\n }\n return res;\n}\n\nPolygon tangent(Circle c1,Point p2){\n Circle c2=Circle(p2,sqrt(norm(c1.c-p2)-c1.r*c1.r));\n Polygon p=getCrossPointCC(c1,c2);\n sort(p.begin(),p.end());\n return p;\n}\n\nvector<Line> tangent(Circle c1,Circle c2){\n vector<Line> ls;\n if(c1.r<c2.r) swap(c1,c2);\n double g=norm(c1.c-c2.c);\n if(equals(g,0)) return ls;\n Point u=(c2.c-c1.c)/sqrt(g);\n Point v=orth(u);\n for(int s=1;s>=-1;s-=2){\n double h=(c1.r+s*c2.r)/sqrt(g);\n if(equals(1-h*h,0)){\n ls.emplace_back(c1.c+u*c1.r,c1.c+(u+v)*c1.r);\n }else if(1-h*h>0){\n Point uu=u*h,vv=v*sqrt(1-h*h);\n ls.emplace_back(c1.c+(uu+vv)*c1.r,c2.c-(uu+vv)*c2.r*s);\n ls.emplace_back(c1.c+(uu-vv)*c1.r,c2.c-(uu-vv)*c2.r*s);\n }\n }\n\n return ls;\n}\n\ndouble closest_pair(Polygon &a,int l=0,int r=-1){\n if(r<0){\n r=a.size();\n sort(a.begin(),a.end(),sort_x);\n }\n if(r-l<=1) return abs(a[0]-a[1]);\n int m=(l+r)>>1;\n double x=a[m].x;\n double d=min(closest_pair(a,l,m),closest_pair(a,m,r));\n inplace_merge(a.begin()+l,a.begin()+m,a.begin()+r,sort_y);\n\n Polygon b;\n for(int i=l;i<r;i++){\n if(fabs(a[i].x-x)>=d) continue;\n for(int j=0;j<(int)b.size();j++){\n double dy=a[i].y-next(b.rbegin(),j)->y;\n if(dy>=d) break;\n d=min(d,abs(a[i]-*next(b.rbegin(),j)));\n }\n b.emplace_back(a[i]);\n }\n return d;\n}\n\nvector<vector<int> >\nsegmentArrangement(vector<Segment> &ss, Polygon &ps){\n int n=ss.size();\n for(int i=0;i<n;i++){\n ps.emplace_back(ss[i].p1);\n ps.emplace_back(ss[i].p2);\n for(int j=i+1;j<n;j++)\n if(intersectSS(ss[i],ss[j]))\n ps.emplace_back(getCrossPointSS(ss[i],ss[j]));\n }\n sort(ps.begin(),ps.end());\n ps.erase(unique(ps.begin(),ps.end()),ps.end());\n\n vector<vector<int> > G(ps.size());\n for(int i=0;i<n;i++){\n vector<pair<double,int> > ls;\n for(int j=0;j<(int)ps.size();j++)\n if(getDistanceSP(ss[i],ps[j])<EPS)\n ls.emplace_back(make_pair(norm(ss[i].p1-ps[j]),j));\n\n sort(ls.begin(),ls.end());\n for(int j=0;j+1<(int)ls.size();j++){\n int a=ls[j].second,b=ls[j+1].second;\n G[a].emplace_back(b);\n G[b].emplace_back(a);\n }\n }\n for(auto &v:G){\n sort(v.begin(),v.end());\n v.erase(unique(v.begin(),v.end()),v.end());\n }\n return G;\n}\n\nint manhattan_intersection(vector<Segment> ss,const int INF){\n const int BTM = 0;\n const int LFT = 1;\n const int RGH = 2;\n const int TOP = 3;\n\n int n=ss.size();\n vector<EndPoint> ep;\n for(int i=0;i<n;i++){\n if(ss[i].p1.y==ss[i].p2.y){\n if(ss[i].p1.x>ss[i].p2.x) swap(ss[i].p1,ss[i].p2);\n ep.emplace_back(ss[i].p1,i,LFT);\n ep.emplace_back(ss[i].p2,i,RGH);\n }else{\n if(ss[i].p1.y>ss[i].p2.y) swap(ss[i].p1,ss[i].p2);\n ep.emplace_back(ss[i].p1,i,BTM);\n ep.emplace_back(ss[i].p2,i,TOP);\n }\n }\n sort(ep.begin(),ep.end());\n\n set<int> bt;\n bt.insert(INF);\n\n int cnt=0;\n for(int i=0;i<n*2;i++){\n if(ep[i].st==TOP){\n bt.erase(ep[i].p.x);\n }else if(ep[i].st==BTM){\n bt.emplace(ep[i].p.x);\n }else if(ep[i].st==LFT){\n auto b=bt.lower_bound(ss[ep[i].seg].p1.x);\n auto e=bt.upper_bound(ss[ep[i].seg].p2.x);\n cnt+=distance(b,e);\n }\n }\n\n return cnt;\n}\n\ndouble area(Polygon ps,Circle c){\n if(ps.size()<3u) return 0;\n function<double(Circle, Point, Point)> dfs=\n [&](Circle c,Point a,Point b){\n Vector va=c.c-a,vb=c.c-b;\n double f=cross(va,vb),res=0;\n if(equals(f,0.0)) return res;\n if(max(abs(va),abs(vb))<c.r+EPS) return f;\n Vector d(dot(va,vb),cross(va,vb));\n if(getDistanceSP(Segment(a,b),c.c)>c.r-EPS)\n return c.r*c.r*atan2(d.y,d.x);\n auto u=getCrossPointCS(c,Segment(a,b));\n if(u.empty()) return res;\n if(u.size()>1u&&dot(u[1]-u[0],a-u[0])>0) swap(u[0],u[1]);\n u.emplace(u.begin(),a);\n u.emplace_back(b);\n for(int i=1;i<(int)u.size();i++)\n res+=dfs(c,u[i-1],u[i]);\n return res;\n };\n double res=0;\n for(int i=0;i<(int)ps.size();i++)\n res+=dfs(c,ps[i],ps[(i+1)%ps.size()]);\n return res/2;\n}\n\n\ntemplate<typename T, typename ...Ts>\nvector<T> fusion(vector<T> bs,Ts... ts){\n auto append=[&](auto vs){for(auto v:vs) bs.emplace_back(v);};\n initializer_list<int>{(void(append(ts)),0)...};\n return bs;\n}\n\n\ntemplate<typename V>\nV compress(V v){\n sort(v.begin(),v.end());\n v.erase(unique(v.begin(),v.end()),v.end());\n return v;\n}\ntemplate<typename T>\nmap<T, int> dict(const vector<T> &v){\n map<T, int> res;\n for(int i=0;i<(int)v.size();i++)\n res[v[i]]=i;\n return res;\n}\nmap<char, int> dict(const string &v){\n return dict(vector<char>(v.begin(),v.end()));\n}\n\n//INSERT ABOVE HERE\nusing D = double;\nint n,T;\nD RADIUS;\nstruct Robot{\n string name;\n Point pos;\n vector<int> ts;\n vector<Vector> vs;\n void input(){\n cin>>name;\n int t0;\n cin>>t0>>pos;\n //cout<<pos<<endl;\n assert(t0==0);\n ts.emplace_back(t0);\n while(cin>>t0){\n vs.emplace_back();\n cin>>vs.back();\n ts.emplace_back(t0);\n if(t0==T) break;\n }\n }\n};\n\nRobot create(Robot r,vector<int> ss){\n Robot x;\n x.name=r.name;\n x.pos=r.pos;\n x.ts=ss;\n x.vs.resize(ss.size()-1);\n for(int i=0;i<(int)x.vs.size();i++){\n int cnt=0;\n for(int j=0;j<(int)r.vs.size();j++)\n if(r.ts[j]<=x.ts[i]&&x.ts[i+1]<=r.ts[j+1])\n x.vs[i]=r.vs[j],cnt++;\n assert(cnt==1);\n }\n return x;\n}\n\nsigned main(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n\n while(cin>>n>>T>>RADIUS,n){\n vector<Robot> rs(n);\n for(int i=0;i<n;i++) rs[i].input();\n\n vector<D> vt;\n\n const int LOOP = 100;\n for(int i=0;i<n;i++){\n for(int j=0;j<i;j++){\n vector<int> ss=compress(fusion(rs[i].ts,rs[j].ts));\n Robot p=create(rs[i],ss);\n Robot q=create(rs[j],ss);\n\n Point pp=p.pos;\n Point qq=q.pos;\n\n for(int k=0;k+1<(int)ss.size();k++){\n if(abs(pp-qq)<=RADIUS+EPS)\n vt.emplace_back(ss[k]);\n\n D L=0,R=ss[k+1]-ss[k];\n for(int a=0;a<LOOP;a++){\n D M1=L+(R-L)/3;\n D M2=L+(R-L)/3*2;\n\n Point p1=pp+p.vs[k]*M1;\n Point p2=pp+p.vs[k]*M2;\n Point q1=qq+q.vs[k]*M1;\n Point q2=qq+q.vs[k]*M2;\n\n if(abs(p1-q1)<abs(p2-q2)) R=M2;\n else L=M1;\n }\n\n Point mp=pp+p.vs[k]*L;\n Point mq=qq+q.vs[k]*L;\n\n // cout<<i<<\" \"<<j<<\":\"<<abs(mp-mq)<<endl;\n if(abs(mp-mq)<=RADIUS+EPS){\n vt.emplace_back(ss[k]+L);\n {\n D X=0,Y=L;\n for(int a=0;a<LOOP;a++){\n D Z=(X+Y)/2;\n Point pz=pp+p.vs[k]*Z;\n Point qz=qq+q.vs[k]*Z;\n if(abs(pz-qz)<=RADIUS+EPS) Y=Z;\n else X=Z;\n }\n vt.emplace_back(ss[k]+Y);\n }\n {\n D X=L,Y=ss[k+1]-ss[k];\n for(int a=0;a<LOOP;a++){\n D Z=(X+Y)/2;\n Point pz=pp+p.vs[k]*Z;\n Point qz=qq+q.vs[k]*Z;\n if(abs(pz-qz)<=RADIUS+EPS) X=Z;\n else Y=Z;\n }\n vt.emplace_back(ss[k]+X);\n }\n }\n\n pp=pp+p.vs[k]*D(ss[k+1]-ss[k]);\n qq=qq+q.vs[k]*D(ss[k+1]-ss[k]);\n\n if(abs(pp-qq)<=RADIUS+EPS)\n vt.emplace_back(ss[k+1]);\n }\n }\n }\n\n vt=compress(vt);\n\n vector<int> ts;\n for(int i=0;i<n;i++)\n ts=fusion(ts,rs[i].ts);\n ts=compress(ts);\n\n for(int i=0;i<n;i++)\n rs[i]=create(rs[i],ts);\n\n vector<int> used(n);\n used[0]=1;\n for(int k=0;k<(int)ts.size();k++){\n for(D t:vt){\n if(t<ts[k]||t>ts[k+1]) continue;\n\n queue<int> que;\n for(int i=0;i<n;i++)\n if(used[i]) que.emplace(i);\n\n while(!que.empty()){\n int i=que.front();que.pop();\n for(int j=0;j<n;j++){\n if(used[j]) continue;\n Point pp=rs[i].pos+rs[i].vs[k]*(t-ts[k]);\n Point qq=rs[j].pos+rs[j].vs[k]*(t-ts[k]);\n if(abs(pp-qq)<=RADIUS+EPS){\n used[j]=1;\n que.emplace(j);\n }\n }\n }\n }\n\n for(int i=0;i<n;i++)\n rs[i].pos=rs[i].pos+rs[i].vs[k]*(ts[k+1]-ts[k]);\n }\n\n vector<string> ans;\n for(int i=0;i<n;i++)\n if(used[i]) ans.emplace_back(rs[i].name);\n sort(ans.begin(),ans.end());\n for(string s:ans) cout<<s<<newl;\n\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1140, "memory_kb": 5144, "score_of_the_acc": -1.0186, "final_rank": 17 }, { "submission_id": "aoj_1139_3314597", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <complex>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <array>\nusing namespace std;\nconst double EPS = 1e-8;\nconst double INF = 1e12;\nconst double PI = acos(-1);\n#define EQ(n,m) (abs((n)-(m)) < EPS)\n#define X real()\n#define Y imag()\n\ntypedef complex<double> P;\ntypedef vector<P> VP;\ndouble dot(P a, P b){\n return (conj(a)*b).X;\n}\ndouble cross(P a, P b){\n return (conj(a)*b).Y;\n}\n\nvector<double> solve_quadeq(double a, double b, double c){\n vector<double> ret;\n if(abs(a) < EPS){\n if(abs(b) > EPS) ret.push_back(-c/b);\n return ret;\n }\n double d = b*b -4*a*c;\n if(abs(d) < EPS) d = 0;\n if(d < 0) return ret;\n ret.push_back((-b -sqrt(d))/(2*a));\n ret.push_back((-b +sqrt(d))/(2*a));\n return ret;\n}\n\nbool epseq(const double &a, const double &b){\n\treturn abs(a-b) < EPS;\n}\n\nstruct event{\n\tint a,b,on;\n\tdouble time;\n\tevent(int a, int b, int on, double t):a(a),b(b),on(on),time(t){}\n\tevent(){}\n\tbool operator<(const event &a){\n\t\treturn time < a.time;\n\t}\n};\n\nvector<event> calc_event(vector<VP> &c, int t, double r){\n\tint n = c.size();\n\tvector<event> ret;\n\tfor(int i=0; i<n; i++){\n\t\tfor(int j=i+1; j<n; j++){\n\t\t\tvector<double> times;\n\t\t\tif(abs(c[i][0]-c[j][0]) < r +EPS){\n\t\t\t\ttimes.push_back(0);\t\n\t\t\t}\n\t\t\tfor(int ct=0; ct<t; ct++){\n\t\t\t\tP diff = c[j][ct] -c[i][ct];\n\t\t\t\tP vdiff = (c[j][ct+1] -c[j][ct]) -(c[i][ct+1] -c[i][ct]);\n\t\t\t\tdouble a = norm(vdiff);\n\t\t\t\tdouble b = 2*dot(diff, vdiff);\n\t\t\t\tdouble c = norm(diff) -r*r;\n\t\t\t\tvector<double> ret = solve_quadeq(a,b,c);\n\t\t\t\tfor(double t : ret){\n\t\t\t\t\tif(0 < t +EPS && t < 1 +EPS){\n\t\t\t\t\t\ttimes.push_back(ct+t);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tsort(times.begin(), times.end());\n\t\t\ttimes.erase(unique(times.begin(), times.end(), epseq), times.end());\n\t\t\tint on = 0;\n\t\t\tfor(double t : times){\n\t\t\t\ton = 1-on;\n\t\t\t\tret.emplace_back(i, j, on, t);\n\t\t\t}\n\t\t}\t\t\n\t}\n\tsort(ret.begin(), ret.end());\n\treturn ret;\n}\n\nvoid dfs(int v, vector<bool> &used, vector<vector<bool> > &adj){\n\tif(used[v]) return;\n\tused[v] = true;\n\tfor(int i=0; i<(int)adj.size(); i++){\n\t\tif(adj[v][i]) dfs(i, used, adj);\n\t}\n}\n\nint main(){\n\twhile(1){\n\t\tint n,t,r;\n\t\tcin >> n >> t >> r;\n\t\tif(n == 0) break;\n\n\t\tvector<VP> c(n, VP(t+1));\n\t\tvector<string> name(n);\n\t\tfor(int i=0; i<n; i++){\n\t\t\tcin >> name[i];\n\t\t\tint prev = 0;\n\t\t\tint ct,x,y;\n\t\t\tcin >> ct >> x >> y;\n\t\t\tc[i][0] = P(x, y);\n\t\t\twhile(1){\n\t\t\t\tcin >> ct >> x >> y;\n\t\t\t\tP vec(x, y);\n\t\t\t\tfor(int s=prev; s<ct; s++){\n\t\t\t\t\tc[i][s+1] = c[i][s] +vec;\n\t\t\t\t}\n\t\t\t\tprev = ct;\n\t\t\t\tif(ct == t) break;\n\t\t\t}\n\t\t}\n\n\t\tvector<event> info = calc_event(c, t, r);\n\t\tvector<vector<bool> > adj(n, vector<bool>(n, false));\n\t\tfor(int i=0; i<n; i++){\n\t\t\tfor(int j=i+1; j<n; j++){\n\t\t\t\tif(abs(c[i][0] -c[j][0]) < r +EPS){\n\t\t\t\t\tadj[i][j] = adj[j][i] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<bool> reach(n, false);\n\t\treach[0] = true;\n\t\tfor(event e: info){\n\t\t\tif(e.on == 0){\n\t\t\t\tadj[e.a][e.b] = adj[e.b][e.a] = false;\n\t\t\t}else{\n\t\t\t\tadj[e.a][e.b] = adj[e.b][e.a] = true;\n\t\t\t\tif(reach[e.a] != reach[e.b]){\n\t\t\t\t\tdfs(e.a, reach, adj);\n\t\t\t\t\tdfs(e.b, reach, adj);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<string> ans;\n\t\tfor(int i=0; i<n; i++){\n\t\t\tif(reach[i]) ans.push_back(name[i]);\n\t\t}\n\t\tsort(ans.begin(), ans.end());\n\t\tfor(string s: ans){\n\t\t\tcout << s << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 4440, "score_of_the_acc": -0.24, "final_rank": 11 }, { "submission_id": "aoj_1139_3075732", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <complex>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <utility>\nusing namespace std;\nconst double EPS = 1e-8;\nconst double INF = 1e12;\n#define EQ(n,m) (abs((n)-(m)) < EPS)\n#define X real()\n#define Y imag()\n\ntypedef complex<double> P;\ntypedef vector<P> VP;\nnamespace std{\n bool operator < (const P& a, const P& b){\n return (a.X!=b.X) ? a.X<b.X : a.Y<b.Y;\n }\n bool operator == (const P& a, const P& b){\n return abs(a-b) < EPS;\n }\n}\ndouble dot(P a, P b){\n return (conj(a)*b).X;\n}\n\nstruct Event{\n double time;\n int a,b;\n bool close;\n Event(double t, int a, int b, bool r):time(t),a(a),b(b),close(r){}\n Event(){}\n bool operator < (const Event &a){\n return time < a.time;\n }\n};\n\nvoid dfs(int v, vector<bool> &used, vector<vector<bool> > &adj){\n if(used[v]) return;\n used[v] = true;\n for(int i=0; i<(int)adj.size(); i++){\n if(adj[v][i]){\n dfs(i, used, adj);\n }\n }\n}\n\nint main(){\n while(1){\n int n,t,r;\n cin >> n >> t >> r;\n if(n==0) break;\n\n vector<string> name(n);\n VP pos(n);\n //その時間に動くべき方向がupper_boundで検索できる\n vector<vector<pair<int, P> > > dir(n);\n for(int i=0; i<n; i++){\n cin >> name[i];\n while(1){\n int time,x,y;\n cin >> time >> x >> y;\n if(time == 0){\n pos[i] = P(x, y);\n }else{\n dir[i].push_back(make_pair(time, P(x, y)));\n }\n if(time == t) break;\n }\n }\n\n vector<Event> event;\n //初期接触\n for(int i=0; i<n; i++){\n for(int j=i+1; j<n; j++){\n if(abs(pos[i] -pos[j]) < r){\n event.emplace_back(0, i, j, true);\n }\n }\n }\n //時間time ~ time+1について、交差するかシミュレーション\n for(int time=0; time<t; time++){\n VP tdir(n);\n for(int i=0; i<n; i++){\n auto itr = upper_bound(dir[i].begin(), dir[i].end(), make_pair(time, P(INF, INF)));\n tdir[i] = itr->second;\n }\n for(int i=0; i<n; i++){\n for(int j=i+1; j<n; j++){\n //二次方程式\n double a,b,c;\n a = norm(tdir[i] -tdir[j]);\n b = 2 *dot(pos[i] -pos[j], tdir[i] -tdir[j]);\n c = norm(pos[i] -pos[j]) -r*r;\n double d = b*b -4*a*c;\n if(abs(a) < EPS || d < -EPS) continue;\n if(d < 0) d = 0;\n double sol[2] = {(-b +sqrt(d))/(2*a), (-b -sqrt(d))/(2*a)};\n for(int k=0; k<2; k++){\n if(0 < sol[k] +EPS && sol[k] < 1 +EPS){\n P dpos = pos[i]-pos[j];\n P ddir = tdir[i] -tdir[j];\n bool close = norm(dpos +sol[k]*ddir) > norm(dpos +(sol[k]+EPS)*ddir);\n event.emplace_back(time +sol[k], i, j, close);\n }\n }\n }\n }\n for(int i=0; i<n; i++){\n pos[i] += tdir[i];\n }\n }\n sort(event.begin(), event.end());\n \n vector<bool> used(n, false);\n used[0] = true;\n vector<vector<bool> > adj(n, vector<bool>(n, false));\n for(int i=0; i<(int)event.size(); i++){\n Event &e = event[i];\n adj[e.a][e.b] = adj[e.b][e.a] = e.close;\n if(e.close && used[e.a] != used[e.b]){\n dfs(e.a, used, adj);\n dfs(e.b, used, adj);\n }\n }\n\n vector<string> ans;\n for(int i=0; i<n; i++){\n if(used[i]) ans.push_back(name[i]);\n }\n sort(ans.begin(), ans.end());\n for(int i=0; i<(int)ans.size(); i++){\n cout << ans[i] << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3292, "score_of_the_acc": -0.2171, "final_rank": 10 }, { "submission_id": "aoj_1139_2466389", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing F = double;\n\nstruct Robot {\n string nickname;\n vector<F> t, x, y, vx, vy;\n};\n\nint N, T, R;\nvector<Robot> robot;\n\nconst F EPS = 1e-6;\n\nvector<F> solve(F a, F b, F c) {\n if(a == 0) {\n if(b == 0) return {};\n else return {-c / b};\n }\n F D = b * b - 4 * a * c;\n if(D < 0) return {};\n else return {(-b - sqrt(D)) / (2 * a), (-b + sqrt(D)) / (2 * a)};\n}\n\nset<F> schedule() {\n set<F> res;\n\n for(auto r: robot) for(auto t: r.t) res.emplace(t);\n\n for(auto i = 0; i < N; ++i) for(auto j = 0; j < i; ++j) {\n auto& lhs = robot[i];\n auto& rhs = robot[j];\n\n for(auto a = 0; a + 1 < lhs.t.size(); ++a) for(auto b = 0; b + 1 < rhs.t.size(); ++b) {\n auto lx = lhs.x[a] - lhs.t[a] * lhs.vx[a];\n auto rx = rhs.x[b] - rhs.t[b] * rhs.vx[b];\n auto dx = lx - rx;\n\n auto ly = lhs.y[a] - lhs.t[a] * lhs.vy[a];\n auto ry = rhs.y[b] - rhs.t[b] * rhs.vy[b];\n auto dy = ly - ry;\n\n auto dvx = lhs.vx[a] - rhs.vx[b];\n auto dvy = lhs.vy[a] - rhs.vy[b];\n\n auto A = dvx * dvx + dvy * dvy;\n auto B = 2 * dx * dvx + 2 * dy * dvy;\n auto C = dx * dx + dy * dy - R * R;\n\n auto low = max(lhs.t[a], rhs.t[b]);\n auto high = min(lhs.t[a + 1], rhs.t[b + 1]);\n\n for(auto t: solve(A, B, C)) if(low <= t + EPS && t <= high + EPS) res.emplace(t);\n }\n }\n\n return res;\n}\n\nmultiset<string> solve() {\n vector<bool> ok(N);\n ok[0] = true;\n for(auto t: schedule()) {\n for(auto i = 0; i < N; ++i) for(auto j = 0; j < i; ++j) {\n if(!ok[i] && !ok[j]) continue;\n\n auto& lhs = robot[i];\n auto& rhs = robot[j];\n\n auto a = 0, b = 0;\n for(a = 0; a + 1 < lhs.t.size(); ++a) if(lhs.t[a] <= t + EPS && t <= lhs.t[a + 1] + EPS) break;\n for(b = 0; b + 1 < rhs.t.size(); ++b) if(rhs.t[b] <= t + EPS && t <= rhs.t[b + 1] + EPS) break;\n\n auto lx = lhs.x[a] + (t - lhs.t[a]) * lhs.vx[a];\n auto rx = rhs.x[b] + (t - rhs.t[b]) * rhs.vx[b];\n auto dx = lx - rx;\n\n auto ly = lhs.y[a] + (t - lhs.t[a]) * lhs.vy[a];\n auto ry = rhs.y[b] + (t - rhs.t[b]) * rhs.vy[b];\n auto dy = ly - ry;\n\n if(dx * dx + dy * dy <= R * R + EPS) ok[i] = ok[j] = true;\n }\n }\n\n multiset<string> res;\n for(auto i = 0; i < N; ++i) if(ok[i]) res.emplace(robot[i].nickname);\n return res;\n}\n\nint main() {\n while(cin >> N >> T >> R, N | T | R) {\n robot = vector<Robot>(N);\n\n for(auto& r: robot) {\n cin >> r.nickname;\n\n while(true) {\n int t, vx, vy;\n cin >> t >> vx >> vy;\n if(r.t.empty()) {\n r.x.emplace_back(vx);\n r.y.emplace_back(vy);\n } else {\n r.vx.emplace_back(vx);\n r.vy.emplace_back(vy);\n auto d = t - r.t.back();\n r.x.emplace_back(r.x.back() + d * vx);\n r.y.emplace_back(r.y.back() + d * vy);\n }\n r.t.emplace_back(t);\n if(t == T) break;\n }\n }\n\n for(auto s: solve()) cout << s << endl;\n }\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3300, "score_of_the_acc": -0.2622, "final_rank": 12 }, { "submission_id": "aoj_1139_1605167", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define rep1(i,n) for(int i=1;i<=(int)(n);i++)\n#define all(c) c.begin(),c.end()\n#define pb push_back\n#define fs first\n#define sc second\n#define show(x) cout << #x << \" = \" << x << endl\n#define chmin(x,y) x=min(x,y)\n#define chmax(x,y) x=max(x,y)\nusing namespace std;\ntypedef double D;\ntypedef complex<D> P;\nD inf=1e50;\nD dot(P x,P y){return real(x*conj(y));}\nint N,T,R,n[100];\nstring st[100];\nD t[100][1001];\nP v[100][1001],p[100][1001];\nD fi(D x){\n\tif(abs(x)<1e-9) return 0;\n\treturn x;\n}\ntypedef pair<D,D> Pdd;\nvector<Pdd> segs[100][100];\nvoid fix(vector<Pdd> vc){\n\tif(vc.empty()) return;\n\tsort(all(vc));\n\tvector<Pdd> ret;\n\tD l=vc[0].fs,r=vc[0].sc;\n\tfor(Pdd p:vc){\n\t\tif(r<p.fs){\n\t\t\tret.pb(Pdd(l,r));\n\t\t\tl=p.fs,r=p.sc;\n\t\t}else{\n\t\t\tchmax(r,p.sc);\n\t\t}\n\t}\n\tret.pb(Pdd(l,r));\n\tvc=ret;\n}\nD fst(vector<Pdd> vc,D t){\n\tint N=vc.size();\n\tint id=lower_bound(all(vc),Pdd(t,0))-vc.begin()-1;\n\tif(id>=0&&vc[id].fs<t&&t<vc[id].sc) return t;\n\tid++;\n\tif(id==N) return inf;\n\treturn vc[id].fs;\n}\nint main(){\n\twhile(true){\n\t\tcin>>N>>T>>R;\n\t\tif(N==0) break;\n\t\trep(i,N) rep(j,N) segs[i][j].clear();\n\t\trep(i,N){\n\t\t\tcin>>st[i];\n\t\t\tint j=0;\n\t\t\twhile(true){\n\t\t\t\tint vx,vy;\n\t\t\t\tcin>>t[i][j]>>vx>>vy;\n\t\t\t\tif(j==0) p[i][0]=P(vx,vy);\n\t\t\t\telse{\n\t\t\t\t\tv[i][j-1]=P(vx,vy);\n\t\t\t\t\tp[i][j]=p[i][j-1]+v[i][j-1]*(t[i][j]-t[i][j-1]);\n\t\t\t\t}\n\t\t\t\tif(t[i][j]==T) break;\n\t\t\t\tj++;\n\t\t\t}\n\t\t\tn[i]=j;\n\t\t}\n\t\trep(a,N) rep(b,a){\n\t\t\trep(i,n[a]) rep(j,n[b]){\n\t\t\t\tD tl=max(t[a][i],t[b][j]);\n\t\t\t\tD tr=min(t[a][i+1],t[b][j+1]);\n\t\t\t\tif(tl>tr) continue;\n\t\t\t\tP s=(p[a][i]-t[a][i]*v[a][i])-(p[b][j]-t[b][j]*v[b][j]),dv=v[a][i]-v[b][j];\n\t\t\t\tD A=fi(norm(dv));\n\t\t\t\tD B=2.0*dot(s,dv);\n\t\t\t\tD C=fi(norm(s)-R*R);\n\t\t\t\tif(A==0){\n\t\t\t\t\t// if(a==1&&b==0){\n\t\t\t\t\t// \tshow(i);\n\t\t\t\t\t// \tshow(j);\n\t\t\t\t\t// \tshow(C);\n\t\t\t\t\t// \tshow(p[a][i]);\n\t\t\t\t\t// \tshow(p[b][j]);\n\t\t\t\t\t// \tshow(v[a][i]);\n\t\t\t\t\t// \tshow(v[b][j]);\n\t\t\t\t\t// }\n\t\t\t\t\tif(C<=0) segs[a][b].pb(Pdd(tl,tr));\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tD det=B*B-4*A*C;\n\t\t\t\tif(det<0) continue;\n\t\t\t\tD x=(-B-sqrt(det))/2.0/A,y=(-B+sqrt(det))/2.0/A;\n\t\t\t\tchmax(tl,x);chmin(tr,y);\n\t\t\t\tif(tl<tr) segs[a][b].pb(Pdd(tl,tr));\n\t\t\t}\n\t\t\tfix(segs[a][b]);\n\t\t\t// if(a==1&&b==0){\n\t\t\t// \tfor(Pdd p:segs[a][b]) printf(\"(%.1f,%.1f) \",p.fs,p.sc);\n\t\t\t// \tputs(\"\");\n\t\t\t// }\n\t\t\tsegs[b][a]=segs[a][b];\n//\t\t\tcout<<a<<\",\"<<b<<\" \";\n//\t\t\tshow(d[a][b]);\n\t\t}\n\t\tbool done[100]={};\n\t\tD d[100];\n\t\trep(i,N) d[i]=inf;\n\t\td[0]=0;\n\t\trep(i,N){\n\t\t\tint mn=-1;\n\t\t\trep(j,N) if(!done[j]&&(mn<0||d[j]<d[mn])) mn=j;\n\t\t\tif(mn<0||d[mn]==inf) break;\n\t\t\tdone[mn]=1;\n//\t\t\tshow(mn);\n\t\t\trep(j,N) if(!done[j]){\n\t\t\t\tD x=fst(segs[mn][j],d[mn]);\n\t\t\t\tchmin(d[j],x);\n\t\t\t}\n//\t\t\tif(i==0) rep(j,N) show(d[j]);\n\t\t}\n\t\tvector<string> ans;\n\t\trep(i,N) if(d[i]<T) ans.pb(st[i]);\n\t\tsort(all(ans));\n\t\tfor(string s:ans) cout<<s<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4812, "score_of_the_acc": -0.1749, "final_rank": 9 }, { "submission_id": "aoj_1139_1593536", "code_snippet": "#include<stdio.h>\n#include<algorithm>\n#include<math.h>\n#include<vector>\n#include<string>\n#include<queue>\nusing namespace std;\nconst double EPS = 1e-10;\nconst double INF = 1e+10;\nconst double PI = acos(-1);\nint sig(double r) { return (r < -EPS) ? -1 : (r > +EPS) ? +1 : 0; }\ninline double ABS(double a){return max(a,-a);}\nstruct Pt {\n\tdouble x, y;\n\tPt() {}\n\tPt(double x, double y) : x(x), y(y) {}\n\tPt operator+(const Pt &a) const { return Pt(x + a.x, y + a.y); }\n\tPt operator-(const Pt &a) const { return Pt(x - a.x, y - a.y); }\n\tPt operator*(const Pt &a) const { return Pt(x * a.x - y * a.y, x * a.y + y * a.x); }\n\tPt operator-() const { return Pt(-x, -y); }\n\tPt operator*(const double &k) const { return Pt(x * k, y * k); }\n\tPt operator/(const double &k) const { return Pt(x / k, y / k); }\n\tdouble ABS() const { return sqrt(x * x + y * y); }\n\tdouble abs2() const { return x * x + y * y; }\n\tdouble arg() const { return atan2(y, x); }\n\tdouble dot(const Pt &a) const { return x * a.x + y * a.y; }\n\tdouble det(const Pt &a) const { return x * a.y - y * a.x; }\n};\ndouble tri(const Pt &a, const Pt &b, const Pt &c) { return (b - a).det(c - a); }\nint iSP(Pt a, Pt b, Pt c) {\n\tint s = sig((b - a).det(c - a));\n\tif (s) return s;\n\tif (sig((b - a).dot(c - a)) < 0) return -2; // c-a-b\n\tif (sig((a - b).dot(c - b)) < 0) return +2; // a-b-c\n\treturn 0;\n}\ndouble dSP(Pt a, Pt b, Pt c) {\n\tif (sig((b - a).dot(c - a)) <= 0) return (c - a).ABS();\n\tif (sig((a - b).dot(c - b)) <= 0) return (c - b).ABS();\n\treturn ABS(tri(a, b, c)) / (b - a).ABS();\n}\nbool iCS(Pt a, double r, Pt b, Pt c) {\n\treturn (sig(r - dSP(b, c, a)) >= 0 && sig(r - max((b - a).ABS(), (c - a).ABS())) <= 0);\n}\npair<Pt,Pt> pCL(Pt a, double r, Pt b, Pt c) {\n\tPt h = b + (c - b) * (c - b).dot(a - b) / (c - b).abs2(); // perp(b, c, a)\n\tdouble d = (h - a).ABS();\n\tdouble y = sqrt(max(r * r - d * d, 0.0));\n\tPt e = (c - b) / (c - b).ABS();\n\treturn make_pair(h - e * y, h + e * y);\n}\nchar in[100];\nstring name[110];\nvector<Pt>v[110];\nvector<double>t[110];\nvector<pair<double,pair<int,int> > >ev;\nvector<string>ans;\nint ret[110];\nint g[110][110];\nint bfs[110];\nint main(){\n\tint a,b,c;\n\tscanf(\"%d%d%d\",&a,&b,&c);\n\tscanf(\"%s\",in);\n\tint na,nb,nc;\n\twhile(a){\n\t\tdouble r=(double)c;\n\t\tfor(int i=0;i<110;i++){\n\t\t\tv[i].clear();\n\t\t\tt[i].clear();\n\t\t}\n\t\tfor(int i=0;i<a;i++){\n\t\t\tname[i]=in;\n\t\t\twhile(1){\n\t\t\t\tint chk=scanf(\"%s\",in);\n\t\t\t\tif(chk==-1)break;\n\t\t\t\tif('a'<=in[0]&&in[0]<='z')break;\n\t\t\t\tint tmp,x,y;\n\t\t\t\tsscanf(in,\"%d\",&tmp);\n\t\t\t\tna=tmp;\n\t\t\t\tt[i].push_back((double)tmp);\n\t\t\t\tscanf(\"%d%d\",&x,&y);\n\t\t\t\tnb=x;nc=y;\n\t\t\t\tv[i].push_back(Pt((double)x,(double)y));\n\t\t\t}\n\t\t\tif(i==a-1){\n\t\t\t\tt[i].pop_back();\n\t\t\t\tv[i].pop_back();\n\t\t\t}\n\t\t}\n\t\tev.clear();\n\t\tfor(int i=0;i<a;i++)for(int j=i+1;j<a;j++){\n\t\t\tif((v[i][0]-v[j][0]).ABS()<r)ev.push_back(make_pair(0,make_pair(i,j)));\n\t\t\tint L=1;\n\t\t\tint R=1;\n\t\t\tPt at=v[i][0]-v[j][0];\n\t\t\twhile(1){\n\t\t\t\tdouble left=max(t[i][L-1],t[j][R-1]);\n\t\t\t\tdouble right=min(t[i][L],t[j][R]);\n\t\t\t\tPt tv=v[i][L]-v[j][R];\n\t\t\t\tif(iCS(Pt(0,0),r,at,at+tv*(right-left))){\n\t\t\t\t\tpair<Pt,Pt> it=pCL(Pt(0,0),r,at,at+tv*(right-left));\n\t\t\t\t\tif(iSP(at,it.first,at+tv*(right-left))==2||(at+tv*(right-left)-it.first).ABS()<EPS){\n\t\t\t\t\t\tev.push_back(make_pair(left+(it.first-at).ABS()/(tv.ABS()),make_pair(i,j)));\n\t\t\t\t\t}\n\t\t\t\t\tif(iSP(at,it.second,at+tv*(right-left))==2||(at+tv*(right-left)-it.second).ABS()<EPS){\n\t\t\t\t\t\tev.push_back(make_pair(left+(it.second-at).ABS()/(tv.ABS()),make_pair(i,j)));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tat=at+tv*(right-left);\n\t\t\t\tif(L==t[i].size()-1&&R==t[j].size()-1)break;\n\t\t\t\telse if(L==t[i].size()-1)R++;\n\t\t\t\telse if(R==t[j].size()-1)L++;\n\t\t\t\telse if(t[i][L]>t[j][R]+EPS)R++;\n\t\t\t\telse if(t[i][L]+EPS<t[j][R])L++;\n\t\t\t\telse {L++;R++;}\n\t\t\t}\n\t\t}\n\t\tstd::sort(ev.begin(),ev.end());\n\t\tfor(int i=0;i<a;i++)ret[i]=0;\n\t\tret[0]=1;\n\t\tfor(int i=0;i<a;i++)for(int j=0;j<a;j++)g[i][j]=0;\n\t\tfor(int i=0;i<ev.size();i++){\n\t\t\tg[ev[i].second.first][ev[i].second.second]^=1;\n\t\t\tif(g[ev[i].second.first][ev[i].second.second]&&ret[ev[i].second.first]+ret[ev[i].second.second]){\n\t\t\t\tqueue<int>Q;\n\t\t\t\tfor(int j=0;j<a;j++)bfs[j]=0;\n\t\t\t\tQ.push(ev[i].second.first);\n\t\t\t\tbfs[ev[i].second.first]=1;\n\t\t\t\twhile(Q.size()){\n\t\t\t\t\tint at=Q.front();\n\t\t\t\t\tQ.pop();\n\t\t\t\t\tfor(int j=0;j<a;j++){\n\t\t\t\t\t\tif(!bfs[j]&&(g[at][j]||g[j][at])){\n\t\t\t\t\t\t\tbfs[j]=1;Q.push(j);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tfor(int j=0;j<a;j++)if(bfs[j])ret[j]=1;\n\t\t\t}\n\t\t}\n\t\tans.clear();\n\t\tfor(int i=0;i<a;i++)if(ret[i])ans.push_back(name[i]);\n\t\tstd::sort(ans.begin(),ans.end());\n\t\tfor(int i=0;i<ans.size();i++)printf(\"%s\\n\",ans[i].c_str());\n\t\ta=na;b=nb;c=nc;\n\t}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1328, "score_of_the_acc": -0.0075, "final_rank": 1 }, { "submission_id": "aoj_1139_1592038", "code_snippet": "#include<iostream>\n#include<cmath>\n#include<vector>\n#include<string>\n#include<numeric>\n#include<algorithm>\n\nusing namespace std;\n\nint par[123];\n\nint find(int x){\n return (par[x]==x)?x:par[x]=find(par[x]);\n}\n\nvoid unite(int a,int b){\n par[find(a)]=find(b);\n}\n\nint ex[123][1234],ey[123][1234];\nint evx[123][1234],evy[123][1234];\n\ndouble sqr(double x){return x*x;}\n\nint main(){\n for(int N,T,R;cin>>N>>T>>R,N|T|R;){\n char nicknames[123][12];\n vector<int> t[123],x[123],y[123],vx[123],vy[123];\n vector<double> ev;\n for(int i=0;i<N;i++){\n cin>>nicknames[i];\n for(int j=0;;j++){\n\tint ti,xi,yi;\n\tcin>>ti>>xi>>yi;\n\tev.push_back(ti);\n\tt[i].push_back(ti);\n\tint cx,cy;\n\tif(j){\n\t vx[i].push_back(xi);\n\t vy[i].push_back(yi);\n\t for(int k=t[i][j-1]+1;k<=ti;k++){\n\t ey[i][k]=ey[i][k-1]+yi;\n\t ex[i][k]=ex[i][k-1]+xi;\n\t evy[i][k-1]=yi;\n\t evx[i][k-1]=xi;\n\t }\n\t cy=ey[i][ti];\n\t cx=ex[i][ti];\n\t}else{\n\t cx=xi;\n\t cy=yi;\n\t ex[i][0]=cx;\n\t ey[i][0]=cy;\n\t}\n\tx[i].push_back(cx);\n\ty[i].push_back(cy);\n\tif(ti==T)break;\n }\n }\n for(int i=0;i<N;i++){\n for(int j=0;j<vx[i].size();j++){\n\tint y1=y[i][j]-t[i][j]*vy[i][j];\n\tint x1=x[i][j]-t[i][j]*vx[i][j];\n\tfor(int k=0;k<i;k++){\n\t for(int l=0;l<vx[k].size();l++){\n\t int y2=y[k][l]-t[k][l]*vy[k][l];\n\t int x2=x[k][l]-t[k][l]*vx[k][l];\n\t long long X=x1-x2;\n\t long long Y=y1-y2;\n\t long long VX=vx[i][j]-vx[k][l];\n\t long long VY=vy[i][j]-vy[k][l];\n\t long long a=VX*VX+VY*VY;\n\t long long b=X*VX+Y*VY;\n\t long long c=X*X+Y*Y-R*R;\n\t long long inr=b*b-a*c;\n\t if(inr>=0&&a){\n\t ev.push_back((-b-sqrt(inr))/a);\n\t ev.push_back((-b+sqrt(inr))/a);\n\t }\n\t }\n\t}\n }\n }\n sort(begin(ev),end(ev));\n bool has[123]={true};\n for(int k=0;k<ev.size()-1;k++){\n double e=(ev[k]+ev[k+1])/2;\n // cerr<<e<<endl;\n if(e<0||T<e)continue;\n iota(begin(par),end(par),0);\n int g=e;\n double f=e-g;\n for(int i=0;i<N;i++){\n\tfor(int j=0;j<i;j++){\n\t if(sqr(ey[i][g]+evy[i][g]*f-(ey[j][g]+evy[j][g]*f))+\n\t sqr(ex[i][g]+evx[i][g]*f-(ex[j][g]+evx[j][g]*f))<=R*R){\n\t unite(i,j);\n\t }\n\t}\n }\n for(int i=0;i<N;i++){\n\thas[find(i)]|=has[i];\n }\n for(int i=0;i<N;i++){\n\thas[i]|=has[find(i)];\n }\n }\n vector<string> ans;\n for(int i=0;i<N;i++){\n if(has[i]){\n\tans.push_back(nicknames[i]);\n }\n }\n sort(begin(ans),end(ans));\n for(auto e:ans){\n cout<<e<<endl;\n }\n }\n}", "accuracy": 1, "time_ms": 1330, "memory_kb": 5532, "score_of_the_acc": -1.1782, "final_rank": 19 }, { "submission_id": "aoj_1139_1171503", "code_snippet": "#include <string>\n#include <iostream>\n#include <complex>\n#include <cmath>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#define EACH(i,c) for(__typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define ALL(x) (x).begin(),(x).end() \nusing namespace std;\nconst double eps = 1e-10;\n\ntypedef complex<double> P;\n \ninline double dot(const P &a, const P &b){\n return real(conj(a) * b);\n}\ninline double cross(const P &a, const P &b){\n return imag(conj(a) * b);\n}\nint ccw(const P &a, P b, P c){\n b -= a; c -= a;\n if (cross(b, c) > eps) return +1; // ccw\n if (cross(b, c) < -eps) return -1; // cw\n if (dot(b,c) < 0) return +2; // c-a-b\n if (norm(b) < norm(c)) return -2; // a-b-c\n return 0; // a-c-b\n}\nstruct Line : public vector<P> {\n Line() { }\n Line(const P &a, const P &b) {\n push_back(a); push_back(b);\n }\n};\ninline bool parallel(const Line &s, const Line &t){\n return abs(cross(s[1]-s[0], t[1]-t[0])) < eps;\n}\ninline bool orthogonal(const Line &s, const Line &t){\n return abs(dot(s[1]-s[0], t[1]-t[0])) < eps;\n}\nP projection(const Line &s, const P &a){\n P v = s[1] - s[0];\n return s[0] + dot(v, a - s[0]) / abs(v) / abs(v) * v;\n}\nP reflection(const Line &s, const P &a){\n P p = projection(s, a);\n return 2.0 * p - a;\n}\n\nstruct D{\n\tdouble t;\n\tint a, b;\n\tD(){}\n\tD(double t, int a, int b) : t(t), a(a), b(b) { }\n};\nbool operator<(const D &a, const D &b){\n\treturn a.t < b.t;\n}\n\nint main(){\n\tfor(;;){\n\t\tint N, T, R;\n\t\tcin >> N >> T >> R;\n\t\tif(N == 0) return 0;\n\t\tvector<string> name(N);\n\t\tvector<vector<int> > vt(N);\n\t\tvector<vector<P> > vp(N);\n\t\tfor(int i=0;i<N;++i){\n\t\t\tcin >> name[i];\n\t\t\tfor(;;){\n\t\t\t\tint t, x, y;\n\t\t\t\tcin >> t >> x >> y;\n\t\t\t\tvt[i].push_back(t);\n\t\t\t\tvp[i].push_back(P(x,y));\n\t\t\t\tif(t == T) break;\n\t\t\t}\n\t\t}\n\t\tvector<D> ev;\n\t\tfor(int i=0;i<N;++i)for(int j=i+1;j<N;++j){\n\t\t\tP p = vp[i][0], q = vp[j][0];\n\t\t\tint idx1 = 1, idx2 = 1;\n\t\t\tint lt = 0;\n\t\t\tif(abs(p-q) < R){\n\t\t\t\tev.push_back(D(0, i, j));\n\t\t\t}\n\t\t\twhile(idx1 < vp[i].size() && idx2 < vp[j].size()){\n\t\t\t\tP v = vp[i][idx1], u = vp[j][idx2];\n\t\t\t\tint nt = min(vt[i][idx1], vt[j][idx2]);\n\t\t\t\tdouble a = norm(v-u), c = norm(p-q) - R * R;\n\t\t\t\tdouble b = 2*((real(p)-real(q)) * (real(v)-real(u))\n\t\t\t\t\t\t\t\t+ (imag(p)-imag(q)) * (imag(v)-imag(u)));\n\n\t\t\t\tif(abs(v-u) > eps && b*b-4*a*c > 0){\n\t\t\t\t\tdouble t1 = lt + (-b + sqrt(b*b-4*a*c))/(2 * a);\n\t\t\t\t\tdouble t2 = lt + (-b - sqrt(b*b-4*a*c))/(2 * a);\n\t\t\t\t\tif(lt-eps < t1 && t1 < nt+eps)\n\t\t\t\t\t\tev.push_back(D(t1, i, j));\n\t\t\t\t\tif(lt-eps < t2 && t2 < nt+eps)\n\t\t\t\t\t\tev.push_back(D(t2, i, j));\n\t\t\t\t\t// cerr << name[i] << \"*\" << name[j] << t1 << \",\" << t2 << endl;\n\t\t\t\t}\n\n\t\t\t\tp += v * (double)(nt - lt);\n\t\t\t\tq += u * (double)(nt - lt);\n\t\t\t\tlt = nt;\n\t\t\t\tif(vt[i][idx1] < vt[j][idx2])\n\t\t\t\t\t++idx1;\n\t\t\t\telse\n\t\t\t\t\t++idx2;\n\t\t\t}\n\t\t}\n\t\tsort(ALL(ev));\n\n\t\tvector<vector<int> > d(N, vector<int>(N));\n\t\tvector<int> vst(N);\n\t\tfor(int i=0;i<N;++i) d[i][i] = 1;\n\t\tvst[0] = 1;\n\n\t\t/*\n\t\tEACH(i, name) cerr << *i << \",\";\n\t\tcerr << endl;\n\t\tcerr << \"start\" << ev.size() << endl;\n\t\t*/\n\t\tEACH(i, ev){\n\t\t\td[i->a][i->b] = 1-d[i->a][i->b];\n\t\t\td[i->b][i->a] = 1-d[i->b][i->a];\n\t\t\t/*\n\t\t\tcerr << \">\";\n\t\t\tfor(int j=0;j<N;++j) cerr << vst[j];\n\t\t\tcerr << endl;\n\t\t\t\n\t\t\tfor(int j=0;j<N;++j){\n\t\t\t\tfor(int k=0;k<N;++k) cerr << d[j][k];\n\t\t\t\tcerr << endl;\n\t\t\t}*/\n\t\t\tif(vst[i->a] != vst[i->b]){\n\t\t\t\tqueue<int> Q;\n\t\t\t\tfor(int j=0;j<N;++j) if(vst[j]) Q.push(j);\n\t\t\t\twhile(!Q.empty()){\n\t\t\t\t\tint v = Q.front(); Q.pop();\n\t\t\t\t\tfor(int j=0;j<N;++j) if(!vst[j] && d[v][j]){\n\t\t\t\t\t\tvst[j] = 1;\n\t\t\t\t\t\tQ.push(j);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tvector<string> res;\n\t\tfor(int i=0;i<N;++i) if(vst[i]) res.push_back(name[i]);\n\t\tsort(ALL(res));\n\t\tEACH(i, res) cout << *i << endl;\n\t}\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1460, "score_of_the_acc": -0.021, "final_rank": 2 }, { "submission_id": "aoj_1139_1104024", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define all(a) (a).begin(),(a).end()\n#define EQ(a,b) (abs((a)-(b)) < EPS)\nusing namespace std;\ntypedef double D;\ntypedef complex<D> P;\ntypedef pair<int,int> pii;\ntypedef pair<D, pii> data;\ntypedef vector<int> vi;\nconst D EPS = 1e-8;\n\nint n;\nstring name[110];\nD T,r,x[110],y[110],t[110][1100];\nD vx[110][1100], vy[110][1100];\n\nvector<D> cal(int a, int b){\n vector<D> res;\n P pa = P(x[a],y[a]), pb = P(x[b],y[b]);\n if( abs(pa-pb)<r+EPS )res.push_back(0);\n\n int ta=1, tb=1;\n D cur = 0, nxt = min(t[a][ta],t[b][tb]);\n while(!EQ(cur,T)){\n D tx = pa.real() - pb.real(), ty = pa.imag() - pb.imag();\n D tvx = vx[a][ta] - vx[b][tb], tvy = vy[a][ta] - vy[b][tb];\n D A = tvx*tvx + tvy*tvy, B = 2*tvx*tx + 2*tvy*ty, C = tx*tx + ty*ty - r*r;\n D d = B*B - 4*A*C;\n vector<D> sol;\n\n if(EQ(A,0)){\n if(!EQ(B,0))sol.push_back(-C/B);\n }else if(EQ(d,0)){\n sol.push_back(-B/2/A);\n }else if(d>EPS){\n sol.push_back( (-B - sqrt(d))/2/A );\n sol.push_back( (-B + sqrt(d))/2/A );\n }\n\n rep(i,sol.size()){\n if(sol[i]+EPS < 0 || nxt-cur+EPS < sol[i])continue;\n res.push_back(cur + sol[i]);\n }\n\n D dif = nxt - cur;\n pa += P(vx[a][ta]*dif, vy[a][ta]*dif);\n pb += P(vx[b][tb]*dif, vy[b][tb]*dif);\n\n cur = nxt;\n if(EQ(t[a][ta],cur))ta++;\n if(EQ(t[b][tb],cur))tb++;\n nxt = min(t[a][ta],t[b][tb]);\n }\n return res;\n}\n\nbool prop[110];\nvector<vi> g;\nvoid dfs(int v){\n prop[v] = true;\n for(int u : g[v]){\n if(!prop[u])dfs(u);\n }\n}\n\nint main(){\n cin.tie(0); ios::sync_with_stdio(0);\n while(cin >> n >> T >> r){\n if(n==0)break;\n \n rep(i,n){\n cin >> name[i];\n cin >> t[i][0] >> x[i] >> y[i];\n for(int j=0;;j++){\n\tcin >> t[i][j+1] >> vx[i][j+1] >> vy[i][j+1];\n\tif(EQ(t[i][j+1], T))break;\n }\n }\n\n vector<data> event;\n rep(i,n)rep(j,i){\n vector<D> sub_event = cal(i,j);\n for(D d : sub_event){\n\tevent.push_back(data(d, pii(i,j)));\n }\n }\n sort(all(event));\n \n memset(prop,0,sizeof(prop));\n prop[0] = true;\n g = vector<vi>(n,vi());\n\n rep(i,event.size()){\n if(event[i].first>T+EPS)break;\n int a = event[i].second.first, b = event[i].second.second;\n bool f = true;\n rep(j,g[a].size()){\n\tif(g[a][j] == b){ f = false; break; }\n }\n\n if(f){\n\tg[a].push_back(b); g[b].push_back(a);\n\tif(prop[a] |= prop[b])dfs(a);\n }else{\n\trep(j,g[a].size()){\n\t if(g[a][j] == b)g[a].erase(g[a].begin()+j);\n\t}\n\trep(j,g[b].size()){\n\t if(g[b][j] == a)g[b].erase(g[b].begin()+j);\n\t}\n }\t\n }\n \n vector<string> ans;\n rep(i,n){\n if(prop[i])ans.push_back(name[i]);\n }\n sort(all(ans));\n for(string s : ans)cout << s << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 2604, "score_of_the_acc": -0.0661, "final_rank": 3 } ]
aoj_1141_cpp
Problem A: Dirichlet's Theorem on Arithmetic Progressions Good evening, contestants. If a and d are relatively prime positive integers, the arithmetic sequence beginning with a and increasing by d , i.e., a , a + d , a + 2 d , a + 3 d , a + 4 d , ..., contains infinitely many prime numbers. This fact is known as Dirichlet's Theorem on Arithmetic Progressions, which had been conjectured by Johann Carl Friedrich Gauss (1777 - 1855) and was proved by Johann Peter Gustav Lejeune Dirichlet (1805 - 1859) in 1837. For example, the arithmetic sequence beginning with 2 and increasing by 3, i.e., 2, 5, 8, 11, 14, 17, 20, 23, 26, 29, 32, 35, 38, 41, 44, 47, 50, 53, 56, 59, 62, 65, 68, 71, 74, 77, 80, 83, 86, 89, 92, 95, 98, ... , contains infinitely many prime numbers 2, 5, 11, 17, 23, 29, 41, 47, 53, 59, 71, 83, 89, ... . Your mission, should you decide to accept it, is to write a program to find the n th prime number in this arithmetic sequence for given positive integers a , d , and n . As always, should you or any of your team be tired or confused, the secretary disavow any knowledge of your actions. This judge system will self-terminate in three hours. Good luck! Input The input is a sequence of datasets. A dataset is a line containing three positive integers a , d , and n separated by a space. a and d are relatively prime. You may assume a <= 9307, d <= 346, and n <= 210. The end of the input is indicated by a line containing three zeros separated by a space. It is not a dataset. Output The output should be composed of as many lines as the number of the input datasets. Each line should contain a single integer and should never contain extra characters. The output integer corresponding to a dataset a , d , n should be the n th prime number among those contained in the arithmetic sequence beginning with a and increasing by d . FYI, it is known that the result is always less than 10 6 (one million) under this input condition. Sample Input 367 186 151 179 10 203 271 37 39 103 230 1 27 104 185 253 50 85 1 1 1 9075 337 210 307 24 79 331 221 177 259 170 40 269 58 102 0 0 0 Output for the Sample Input 92809 6709 12037 103 93523 14503 2 899429 5107 412717 22699 25673
[ { "submission_id": "aoj_1141_10849693", "code_snippet": "#include<stdio.h>\n#include<math.h>\n\nint isprime(int m){\n if(m<2)\n return 0;\n for(int i=2;i<=(int)sqrt(m);i++){\n if(0==m%i)\n return 0;\n }\n return 1;\n}\n\nint main(){\n int a,b,c;\n while(scanf(\"%d%d%d\",&a,&b,&c)==3&&a>0){\n int j=0,t=0;\n for(int i=a;j<c;i+=b){\n if(isprime(i)){\n j++;\n t=i;\n }\n }\n printf(\"%d\\n\",t);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2724, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1141_10581146", "code_snippet": "// AOJ 1141 - Dirichlet's Theorem on Arithmetic Progressions\n// ICPC Japan Domestic Contest 2006 - Problem A\n\n#include <bits/stdc++.h>\nusing namespace std;\n\nunordered_set<int> prime;\n\nbool solving() {\n int a, d, n; cin >> a >> d >> n;\n if(a == 0) return false;\n\n int i = 0;\n while(true) {\n if(prime.count(a)) {\n ++i;\n if(i == n) {\n cout << a << endl;\n return true;\n }\n }\n a += d;\n }\n}\n\nint main() {\n prime.insert(2);\n for(int i=3; i<1e6; i+=2) prime.insert(i);\n for(int i=3; i<1000; i+=2) {\n for(int j=3; i*j<1e6; j+=2) prime.erase(i*j);\n }\n while(solving()) {}\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 24548, "score_of_the_acc": -1.0333, "final_rank": 19 }, { "submission_id": "aoj_1141_10554202", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int M = 1 << 20;\nbool P[M];\n\nbool solve() {\n int A, D, N;\n cin >> A >> D >> N;\n if (A == 0 && D == 0 && N == 0) return false;\n int i;\n for (i = 0; N; i++) {\n N -= P[A + i * D];\n }\n cout << A + --i * D << endl;\n return true;\n}\n\nint main() {\n for (int i = 2; i < M; i++) P[i] = true;\n for (int i = 2; i < M; i++) {\n for (int j = i + i; j < M; j += i) P[j] = false;\n }\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4480, "score_of_the_acc": -0.0805, "final_rank": 11 }, { "submission_id": "aoj_1141_10547565", "code_snippet": "#include<stdio.h>\n#include<stdbool.h>\n#include<math.h>\n\n#define Max 10000000\n\nbool isPrime[Max +1];\n\nvoid sieve(){\n for(int i=0;i<=Max;i++){\n isPrime[i]=true;\n }\n isPrime[0]=isPrime[1]=false;\n for(int i=2;i<=sqrt(Max);i++){\n if(isPrime[i]){\n for(int j=i*i;j<=Max;j+=i){\n isPrime[j]=false; \n }\n }\n }\n}\n\nint main (){\n sieve();\n int a,d,n;\n while(scanf(\"%d %d %d\",&a,&d,&n)==3){\n if(a==0&&d==0&&n==0)break;\n int count=0;\n int value=a;\n while(1){\n if(value>Max){\n printf(\"Exceeded max search range\\n\");\n break;\n }\n if(isPrime[value]){\n count++;\n if(count==n){\n printf(\"%d\\n\",value);\n break;\n }\n\n }\n value +=d;\n }\n\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 12688, "score_of_the_acc": -0.4732, "final_rank": 17 }, { "submission_id": "aoj_1141_10544791", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define all(...) std::begin(__VA_ARGS__), std::end(__VA_ARGS__)\n#define rall(...) std::rbegin(__VA_ARGS__), std::rend(__VA_ARGS__)\n#define OVERLOAD_REP(_1, _2, _3, _4, name, ...) name\n#define REP1(n) for(ll i=0;i<(n);i++)\n#define REP2(i, n) for (ll i=0;i<(n);i++)\n#define REP3(i, a, n) for (ll i=a;i<(n);i++)\n#define REP4(i, a, b, n) for(ll i=a;i<(n);i+=b)\n#define rep(...) OVERLOAD_REP(__VA_ARGS__, REP4, REP3, REP2, REP1)(__VA_ARGS__)\n#define OVERLOAD_RREP(_1, _2, _3, _4, name, ...) name\n#define RREP1(n) for(ll i=(n)-1;i>=0;i--)\n#define RREP2(i, n) for(ll i=(n)-1;i>=0;i--)\n#define RREP3(i, a, n) for(ll i=(n)-1;i>=(a);i--)\n#define RREP4(i, a, b, n) for(ll i=(n)-1;i>=(a);i-=(b))\n#define rrep(...) OVERLOAD_RREP(__VA_ARGS__, RREP4, RREP3, RREP2, RREP1)(__VA_ARGS__)\n#define uniq(a) sort(all(a));a.erase(unique(all(a)),end(a))\n#define len(n) (long long)(n).size()\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vs = vector<string>;\nusing vvs = vector<vs>;\nusing vvvs = vector<vvs>;\nusing vld = vector<ld>;\nusing vvld = vector<vld>;\nusing vvvld = vector<vvld>;\nusing vc = vector<char>;\nusing vvc = vector<vc>;\nusing vvvc = vector<vvc>;\nusing pll = pair<ll,ll>;\nusing vpll = vector<pll>;\nusing vvpll = vector<vpll>;\n\nll intpow(ll a,ll b){\n ll ans = 1;\n while (b){\n if (b & 1){\n ans *= a;\n }\n a *= a;\n b /= 2;\n }\n return ans;\n}\nll modpow(ll a,ll b,ll c){\n ll ans = 1;\n while (b){\n if (b & 1){\n ans *= a;\n ans %= c;\n }\n a *= a;\n a %= c;\n b /= 2;\n }\n return ans;\n}\n\ntemplate<class... T>\nvoid input(T&... a){\n (cin >> ... >> a);\n}\n\n#define INT(...) int __VA_ARGS__; input(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define ULL(...) ull __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define CHA(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define VLL(name,length) vll name(length);rep(i,length){cin >> name[i];}\n#define VVLL(name,h,w) vvll name(h,vll(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVLL(name,a,b,c) vvvll name(a,vvll(b,vll(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VI(name,length) vi name(length);rep(i,length){cin >> name[i];}\n#define VVI(name,h,w) vvi name(h,vi(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVI(name,a,b,c) vvvi name(a,vvll(b,vi(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VLD(name,length) vld name(length);rep(i,length){cin >> name[i];}\n#define VVLD(name,h,w) vvld name(h,vld(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVLD(name,a,b,c) vvvld name(a,vvld(b,vld(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VC(name,length) vc name(length);rep(i,length){cin >> name[i];}\n#define VVC(name,h,w) vvc name(h,vc(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVC(name,a,b,c) vvvc name(a,vvc(b,vc(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VS(name,length) vs name(length);rep(i,length){cin >> name[i];}\n#define VVS(name,h,w) vvs name(h,vs(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVS(name,a,b,c) vvvs name(a,vvs(b,vs(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define PLL(name) pll name;cin>>name.first>>name.second;\n#define VPLL(name,length) vpll name(length);rep(i,length){cin>>name[i].first>>name[i].second;}\n\nvoid print(){cout << \"\\n\";}\n\ntemplate <typename T1, typename T2>\nstd::ostream& operator<<(std::ostream& os, const std::pair<T1, T2>& p) {\n os << \"(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\n\ntemplate <typename T>\nstd::ostream& operator<<(std::ostream& os, const std::vector<T>& vec) {\n os << \"[\";\n for (size_t i = 0; i < vec.size(); ++i) {\n os << vec[i];\n if (i + 1 < vec.size()) os << \", \";\n }\n os << \"]\";\n return os;\n}\n\ntemplate <typename T1, typename T2>\nstd::ostream& operator<<(std::ostream& os, const std::vector<std::pair<T1, T2>>& a) {\n os << \"[\";\n for (size_t j = 0; j < a.size(); ++j) {\n os << \"(\" << a[j].first << \", \" << a[j].second << \")\";\n\t\tif (j + 1 < a.size()) os << \", \";\n }\n\tos << \"]\";\n return os;\n}\n\ntemplate <typename T1, typename T2>\nstd::ostream& operator<<(std::ostream& os, const std::vector<std::vector<std::pair<T1, T2>>>& mat) {\n\tos << \"[\";\n for (size_t i = 0; i < mat.size(); ++i) {\n\t\tos << \"[\";\n for (size_t j = 0; j < mat[i].size(); ++j) {\n os << \"(\" << mat[i][j].first << \", \" << mat[i][j].second << \")\";\n\t\t\tif (j + 1 < mat[i].size()) os << \", \";\n }\n\t\tos << \"]\";\n\t\tif (i + 1 < mat.size()) os << \", \";\n }\n\tos << \"]\";\n return os;\n}\n\ntemplate <typename T>\nstd::ostream& operator<<(std::ostream& os, const std::set<T>& s) {\n os << \"{\";\n bool first = true;\n for (const auto& x : s) {\n if (!first) os << \", \";\n os << x;\n first = false;\n }\n os << \"}\";\n return os;\n}\n\ntemplate <typename K, typename V>\nstd::ostream& operator<<(std::ostream& os, const std::map<K, V>& m) {\n os << \"{\";\n bool first = true;\n for (const auto& [key, val] : m) {\n if (!first) os << \", \";\n os << key << \": \" << val;\n first = false;\n }\n os << \"}\";\n return os;\n}\n\ntemplate<class T, class... Ts>\nvoid print(const T& a, const Ts&... b){cout << a;(cout << ... << (cout << ' ', b));cout << '\\n';}\n\nvoid write(){cout << \"\\n\";}\ntemplate<class T, class... Ts>\nvoid write(const T& a, const Ts&... b){cout << a;(cout << ... << (cout << ' ', b));cout << '\\n';}\nvoid write(vll x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvll x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vi x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvi x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvvi x){rep(i,len(x))rep(j,len(x[i]))rep(k,len(x[i][j])){cout << x[i][j][k];if(k!=len(x[i][j])-1){cout << \" \";}else if(j!=len(x[i])-1){cout << \" | \";}else{cout << '\\n';}}}\nvoid write(vld x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvld x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvvld x){rep(i,len(x))rep(j,len(x[i]))rep(k,len(x[i][j])){cout << x[i][j][k];if(k!=len(x[i][j])-1){cout << \" \";}else if(j!=len(x[i])-1){cout << \" | \";}else{cout << '\\n';}}}\nvoid write(vc x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvc x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvvc x){rep(i,len(x))rep(j,len(x[i]))rep(k,len(x[i][j])){cout << x[i][j][k];if(k!=len(x[i][j])-1){cout << \" \";}else if(j!=len(x[i])-1){cout << \" | \";}else{cout << '\\n';}}}\nvoid write(vs x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvs x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvvs x){rep(i,len(x))rep(j,len(x[i]))rep(k,len(x[i][j])){cout << x[i][j][k];if(k!=len(x[i][j])-1){cout << \" \";}else if(j!=len(x[i])-1){cout << \" | \";}else{cout << '\\n';}}}\nvoid write(pll x){cout << x.first << ' ' << x.second << '\\n';}\nvoid write(vpll x){rep(i,len(x)){cout << x[i].first << ' ' << x[i].second << '\\n';}}\nvoid write(vvpll x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j].first << ' ' << x[i][j].second;if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\n\ntemplate <typename T>\nT sum(const std::vector<T>& v) {\n return std::accumulate(v.begin(), v.end(), T(0));\n}\n\ntemplate<class T> bool chmin(T& a, const T& b){ if(a > b){ a = b; return 1; } return 0; }\ntemplate<class T> bool chmax(T& a, const T& b){ if(a < b){ a = b; return 1; } return 0; }\ntemplate<class T, class U> bool chmin(T& a, const U& b){ if(a > T(b)){ a = b; return 1; } return 0; }\ntemplate<class T, class U> bool chmax(T& a, const U& b){ if(a < T(b)){ a = b; return 1; } return 0; }\n\nlong long mod_mul(long long a, long long b, long long mod) {\n return (__int128)a * b % mod;\n}\n\nlong long mod_pow(long long a, long long b, long long mod) {\n long long result = 1;\n a %= mod;\n while (b > 0) {\n if (b & 1) result = mod_mul(result, a, mod);\n a = mod_mul(a, a, mod);\n b >>= 1;\n }\n return result;\n}\n\nbool MillerRabin(ll x){\n \n if(x <= 1){return false;}\n if(x == 2){return true;}\n if((x & 1) == 0){return false;}\n vll test;\n if(x < (1 << 30)){\n test = {2, 7, 61};\n } \n else{\n test = {2, 325, 9375, 28178, 450775, 9780504, 1795265022};\n }\n ll s = 0;\n ll d = x - 1;\n while((d & 1) == 0){\n s++;\n d >>= 1;\n }\n for(ll i:test){\n if(x <= i){return true;}\n ll y = mod_pow(i,d,x);\n if(y == 1 || y == x - 1){continue;}\n ll c = 0;\n for(int j=0;j<s-1;j++){\n y = mod_mul(y,y,x);\n if(y == x - 1){\n c = 1;\n break;\n }\n }\n if(c == 0){\n return false;\n }\n }\n return true;\n}\n\nint main(){\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n while(1){\n LL(a,d,n);\n if(a == 0 && d == 0 & n == 0){break;}\n vll ans;\n while(len(ans) < n){\n if(MillerRabin(a)){\n ans.push_back(a);\n }\n a += d;\n }\n print(ans.back());\n }\n \n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3456, "score_of_the_acc": -0.0335, "final_rank": 8 }, { "submission_id": "aoj_1141_10523491", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n#include <algorithm>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <ctime>\n#include <string>\n#include <functional>\nusing namespace std;\nusing ll = long long;\nusing lb = long double;\n\nint main() {\n vector<bool> prime(pow(10, 7), true);\n prime[0] = false;\n prime[1] = false;\n for (int j = 2; j < prime.size(); j++) {\n if (prime[j]) {\n for (int k = 2; j*k < prime.size(); k++)\n prime[j*k] = false;\n }\n }\n\n while (true) {\n int a, d, n;\n cin >> a >> d >> n;\n if (a == 0 && d == 0 && n == 0) return 0;\n int primecount = 0;\n int i;\n for (i = 0; primecount < n; i++) {\n if (prime[a+d*i]) primecount++;\n }\n i--;\n cout << a+d*i << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 4244, "score_of_the_acc": -0.1196, "final_rank": 14 }, { "submission_id": "aoj_1141_10490036", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing P = pair<int, int>;\nusing PP = pair<int, P>;\nusing PLL = pair<ll, ll>;\nusing PPLL = pair<ll, PLL>;\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define rrep(i, n) for(ll i = n - 1; i >= 0; --i)\n#define loop(i, a, b) for(ll i = a; i <= b; ++i)\n#define all(v) v.begin(), v.end()\n#define nC2(n) n * (n - 1) / 2\nconstexpr ll INF = 9009009009009009009LL;\nconstexpr int INF32 = 2002002002;\nconstexpr ll MOD = 998244353;\nconstexpr ll MOD107 = 1000000007;\n\n// Linear Algebra ////////////////////////////////////////////////\nconst double Rad2Deg = 180.0 / M_PI;\nconst double Deg2Rad = M_PI / 180.0;\n//////////////////////////////////////////////////////////////////\n\nint dx[8] = {0, 1, 0, -1, 1, 1, -1, -1};\nint dy[8] = {1, 0, -1, 0, 1, -1, 1, -1};\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) {\n\tif (a < b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\ntemplate <class T>\ninline bool chmin(T &a, const T &b) {\n\tif (a > b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\n\ntemplate <typename Container,\n typename = std::enable_if_t<\n !std::is_same_v<Container, std::string> &&\n std::is_convertible_v<decltype(std::declval<Container>().begin()),\n typename Container::iterator>>>\nostream &operator<<(ostream &os, const Container &container) {\n auto it = container.begin();\n auto end = container.end();\n\n if (it != end) {\n os << *it;\n ++it;\n }\n\tfor (; it != end; ++it) {\n\t\tos << \" \" << *it;\n\t}\n return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v) {\n for (size_t i = 0; i < v.size(); ++i) {\n os << v[i];\n if (i != v.size() - 1) os << \" \";\n }\n return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<vector<T>>& vv) {\n\tfor (size_t i = 0; i < vv.size(); ++i) {\n\t\tos << vv[i];\n\t\tif (i != vv.size() - 1) os << \"\\n\";\n }\n return os;\n}\ntemplate <typename T>\nistream& operator>>(istream& is, vector<T>& v) {\n\tassert(v.size() > 0);\n\tfor (size_t i = 0; i < v.size(); ++i) is >> v[i];\n\treturn is;\n}\ntemplate <typename T>\nistream& operator>>(istream& is, vector<vector<T>>& vv) {\n\tassert(vv.size() > 0);\n\tfor (size_t i = 0; i < vv.size(); ++i) is >> vv[i];\n\treturn is;\n}\n\nstruct phash {\n\ttemplate<class T1, class T2>\n inline size_t operator()(const pair<T1, T2> & p) const {\n auto h1 = hash<T1>()(p.first);\n auto h2 = hash<T2>()(p.second);\n\n\t\tsize_t seed = h1 + h2; \n\t\th1 = ((h1 >> 16) ^ h1) * 0x45d9f3b;\n h1 = ((h1 >> 16) ^ h1) * 0x45d9f3b;\n h1 = (h1 >> 16) ^ h1;\n seed ^= h1 + 0x9e3779b9 + (seed << 6) + (seed >> 2);\n\t\th2 = ((h2 >> 16) ^ h2) * 0x45d9f3b;\n h2 = ((h2 >> 16) ^ h2) * 0x45d9f3b;\n h2 = (h2 >> 16) ^ h2;\n seed ^= h2 + 0x9e3779b9 + (seed << 6) + (seed >> 2);\n return seed;\n }\n};\n\n\n\n\nvector<bool> sieve(ll n) {\n\tvector<bool> res(n, true);\n\tres[0] = res[1] = false;\n\tfor (ll i = 2; i * i <= n; i++) {\n\t\tif (!res[i]) continue;\n\t\tfor (ll j = i * i; j < n; j += i) {\n\t\t\tres[j] = false;\n\t\t}\n\t}\n\treturn res;\n}\n\nint solve() {\n\tll a, d, n;\n\tcin >> a >> d >> n;\n\tif (a == 0 && d == 0 && n == 0) return 1;\n\n\tvector<bool> isPrime = sieve(1e6);\n\tll cnt = 0;\n\tfor (ll i = a; i < 1e6; i += d) {\n\t\tif (isPrime[i]) {\n\t\t\tcnt++;\n\t\t\tif (cnt == n) {\n\t\t\t\tcout << i << endl;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}\n\nint main() {\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\n\twhile (!solve()) { }\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 3584, "score_of_the_acc": -0.6061, "final_rank": 18 }, { "submission_id": "aoj_1141_9378425", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define rep(i,n) for(int i = 0; i < n; i++)\n#define MMAX 1000000000000000000LL\n\n#define int ll\n\nvoid main_()\n{\n const int MAX = 1000005;\n int a, d, n;\n cin >> a >> d >> n;\n if(!a) exit(0);\n\n vector<int> p(MAX, 1);\n p[0] = p[1] = 0;\n for(int i = 2; i * i < MAX; i++) {\n if(p.at(i) == 0) continue;\n for(int j = i * i; j < MAX; j += i) {\n p.at(j) = 0;\n }\n }\n\n int cnt = 0;\n int i;\n for(i = a; cnt < n; i += d) {\n if( p[i] ) cnt++;\n if(cnt == n) break;\n }\n cout << i << endl;\n\n}\nsigned main()\n{\n while(1) main_();\n}", "accuracy": 1, "time_ms": 610, "memory_kb": 11144, "score_of_the_acc": -1.3858, "final_rank": 20 }, { "submission_id": "aoj_1141_9356869", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define all(x) (x).begin(),(x).end()\n#define eb emplace_back\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing vl = vector<long long>;\nusing vvl = vector<vector<long long>>; using vs = vector<string>;\nusing pl = pair<long long, long long>;\ntemplate <typename T> inline bool chmin(T& a, const T& b) {bool compare = a > b; if (a > b) a = b; return compare;}\ntemplate <typename T> inline bool chmax(T& a, const T& b) {bool compare = a < b; if (a < b) a = b; return compare;}\ntemplate<class T>using rp_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate <typename T> T gcd(T a, T b) {if (b == 0)return a; else return gcd(b, a % b);}\ntemplate <typename T> inline T lcm(T a, T b) {return a /gcd(a, b)*b;}\nconst ll INF = 1LL << 60;\nconst ld PI = acos(-1);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec);\ntemplate <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr);\ntemplate <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec);\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const pair<T, U> &pa);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec);\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa);\ntemplate <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp);\ntemplate <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp);\ntemplate <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl);\n \ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec) { os << '['; for (auto v : vec) os << v << ','; os << ']'; return os; }\ntemplate <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr) { os << '['; for (auto v : arr) os << v << ','; os << ']'; return os; }\ntemplate <class... T> std::istream &operator>>(std::istream &is, std::tuple<T...> &tpl) { std::apply([&is](auto &&... args) { ((is >> args), ...);}, tpl); return is; }\ntemplate <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl) { os << '('; std::apply([&os](auto &&... args) { ((os << args << ','), ...);}, tpl); return os << ')'; }\ntemplate <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec) { os << \"deq[\"; for (auto v : vec) os << v << ','; os << ']'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa) { return os << '(' << pa.first << ',' << pa.second << ')'; }\ntemplate <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << \"=>\" << v.second << ','; os << '}'; return os; }\ntemplate <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp) { os << '{'; for (auto v : mp) os << v.first << \"=>\" << v.second << ','; os << '}'; return os; }\n#ifdef LOCAL\nconst string COLOR_RESET = \"\\033[0m\", BRIGHT_GREEN = \"\\033[1;32m\", BRIGHT_RED = \"\\033[1;31m\", BRIGHT_CYAN = \"\\033[1;36m\", NORMAL_CROSSED = \"\\033[0;9;37m\", RED_BACKGROUND = \"\\033[1;41m\", NORMAL_FAINT = \"\\033[0;2m\";\n#define dbg(x) std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << \" = \" << (x) << NORMAL_FAINT << \" (L\" << __LINE__ << \") \" << __FILE__ << COLOR_RESET << std::endl\n#define dbgif(cond, x) ((cond) ? std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << \" = \" << (x) << NORMAL_FAINT << \" (L\" << __LINE__ << \") \" << __FILE__ << COLOR_RESET << std::endl : std::cerr)\n#else\n#define dbg(x) ((void)0)\n#define dbgif(cond, x) ((void)0)\n#endif\nvoid solve();\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout<<fixed<<setprecision(15);\n int num_tc = 1;\n //cin >> num_tc;\n rep(tc,num_tc){\n //cout << \"Case #\" << tc+1 << \": \" ;// << endl;\n solve();\n }\n}\n//見切り発車で実装しては行けない.頭の中でコードが完全に出来上がるまで書き始めるな.\n//オーバーフローしているか確認する\n//小さいケースで動いているかを確認する。\nbool is_prime[3000000];\nconst ll mx = 3000000;\nvoid solve(){\n rep(i,mx)is_prime[i] = true;\n is_prime[0] = is_prime[1] = false;\n for(int i=2;i<mx;i++){\n if(!is_prime[i])continue;\n for(int j=2*i;j<mx;j+=i)is_prime[j]=false;\n }\n while(true){\n ll a,d,n;cin>>a>>d>>n;\n if(a==0&&d==0&&n==0)return;\n while(true){\n n-=is_prime[a];\n if(n==0){\n cout<<a<<endl;\n break;\n }\n a+=d;\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6184, "score_of_the_acc": -0.1585, "final_rank": 15 }, { "submission_id": "aoj_1141_9347199", "code_snippet": "#include<bits//stdc++.h>\n\nusing namespace std;\n\nbool isPrime(int ans){\n if(ans<2) return false;\n for(int i=2;i*i<=ans;i++){\n if(ans%i==0)return false;\n }\n return true;\n }\n \nint main(){\n while(true){\n int a,d,n;\n int cnt = 0;\n int ans = 0;\n cin >> a >> d >> n;\n if(a==0 && d==0 && n==0) break;\n for(int i=1;i<=10000;i++){\n ans= a+(i-1)*d;\n bool flag =isPrime(ans);\n if(flag == true) cnt++;\n if(cnt == n){\n cout << ans << endl;\n break;\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3084, "score_of_the_acc": -0.0165, "final_rank": 2 }, { "submission_id": "aoj_1141_9346978", "code_snippet": "#include<iostream>\n#include<cmath>\nusing namespace std;\n\nbool isPrime(int x){\n if(x<2) return false;\n for(int i=2; i*i<=x; i++){\n if(x%i == 0) return false;\n }\n return true;\n}\n\nint main(){\n int a,d,n;\n while(true){\n cin >> a >> d >> n;\n if(a==0 && d==0 && n==0) break;\n int count=0, i=0;\n while(true){\n int sum = a + d*i;\n if(isPrime(sum)){\n count++;\n if(count == n){\n cout << sum << endl;\n break;\n }\n }\n i++;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3132, "score_of_the_acc": -0.0187, "final_rank": 4 }, { "submission_id": "aoj_1141_9336125", "code_snippet": "#include <bits/stdc++.h>\n\nbool is_prime(long long n) {\n if (n < 2) return false;\n for (long long i = 2; i * i <= n; i++) {\n if (n % i == 0) return false;\n }\n return true;\n}\n\nint solve() {\n long long a, d, n;\n std::cin >> a >> d >> n;\n if (a == 0 && d == 0 && n == 0) return 1;\n int count = 0;\n while (true) {\n if (is_prime(a)) count++;\n if (count == n) {\n std::cout << a << std::endl;\n break;\n }\n a += d;\n }\n return 0;\n}\n\nint main() {\n // int n;\n // std::cin >> n;\n // std::cin.ignore();\n // while (n--) solve();\n while (!solve());\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3208, "score_of_the_acc": -0.0888, "final_rank": 12 }, { "submission_id": "aoj_1141_9335975", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,j,n) for (int i = j; i < (int)(n); i++)\n#define REP(i,j,n) for (int i = j; i <= (int)(n); i++)\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\n#define all(x) (x.begin(), x.end())\ntemplate<typename T1, typename T2> inline bool chmax(T1 &a, T2 b){\n bool compare = (a < b);\n if(compare) a = b;\n return compare;\n}\ntemplate<typename T1, typename T2> inline bool chmin(T1 &a, T2 b){\n bool compare = (a > b);\n if(compare) a = b;\n return compare;\n}\nstruct V {\n\tint a, b;\n};\nbool acom(const V& a, const V& b) {\n\treturn a.a < b.a;\n}\nbool bcom(const V& a, const V& b) {\n\treturn a.b < b.b;\n}\nbool is_prime(long long num){\n\tif(num==1) return false;\n\tif(num==2) return true;\n\tif(num%2==0) return false;\n\tdouble sqnum=sqrt(num);\n\tfor(int i=3;i<=sqnum;i+=2){\n\t\tif(num%i==0) return false;\n\t}\n\treturn true;\n}\n//やりましょう!!\nint main() {\n\tvector<int> ans;\n\twhile(1){\n\t\tint a, d,n; cin >> a >> d >> n;\n\t\tif(a==0&&d==0&&n==0) break;\n\t\tint cnt=0;\n\t\tfor(int i=a;i<=1000010;i+=d){\n\t\t\tif(is_prime(i)) cnt++;\n\t\t\tif(cnt==n){\n\t\t\t\tans.push_back(i);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t}\n\tfor(auto x:ans) cout << x << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3444, "score_of_the_acc": -0.0497, "final_rank": 9 }, { "submission_id": "aoj_1141_9335890", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nbool isprime(int num)\n{\n if (num == 1)\n return false;\n for (int i = 2; i * i <= num; i++)\n {\n if (num % i == 0)\n return false;\n }\n return true;\n}\n\nint main()\n{\n std::cin.tie(0)->sync_with_stdio(0);\n while (true)\n {\n int a, d, n;\n cin >> a >> d >> n;\n int cnt = 0;\n if (a == 0 and d == 0 and n == 0)\n {\n break;\n }\n int num = a;\n while (true)\n {\n if (isprime(num))\n cnt++;\n if (cnt == n)\n {\n cout << num << endl;\n break;\n }\n num += d;\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3372, "score_of_the_acc": -0.0297, "final_rank": 7 }, { "submission_id": "aoj_1141_9329749", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nbool isPrime(int x){\n if(x==1)return false;\n for(int i=2;i*i<=x;i++){\n if(x%i==0)return false;\n }\n return true;\n}\n\nint main(){\n while(true){\n int a,d,n;\n cin >> a >> d >> n;\n if(a==0&&d==0&&n==0)break;\n int cnt=0;\n int i=0;\n int a_=a;\n while(cnt<n){\n a=a_+d*i;\n if(isPrime(a)){\n cnt++;\n }\n i++;\n }\n cout << a << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3088, "score_of_the_acc": -0.0167, "final_rank": 3 }, { "submission_id": "aoj_1141_9329563", "code_snippet": "#include <stdio.h>\n#include <stdlib.h>\n#include <iostream>\n#include <string>\n#include <utility>\n#include <limits.h>\n#include <algorithm>\n#include <iomanip>\n#include <math.h>\n#include <queue>\n#include <stack>\n#include <list>\n#include <map>\n#include <set>\n#define rep(i,n) for(int i = 0; i < (int)(n); i++)\nusing namespace std;\nusing llint = long long;\nusing vec = vector<llint>;\nusing vvec = vector<vec>;\n\n\nbool IsPrime(llint Num);\n\nint main() {\n\twhile (true) {\n\t\t//入力\n\t\tint a, d, n; cin >> a >> d >> n;\n\t\tif (a == 0 && d == 0) return 0;\n\n\t\t//main_code\n\t\tint now = 0;\n\t\tbool end = true;\n\t\tint i;\n\t\tfor (i = 0; now != n; i++) {\n\t\t\tllint Num = a + i * d;\n\t\t\tif (IsPrime(Num)) now++;\n\t\t}\n\n\t\t//出力\n\t\tcout << a + d * (i - 1) << endl;\n\t}\n}\n\nbool IsPrime(llint Num) {\n\tif (Num == 1) return false;\n\tfor (int i = 2; i * i <= Num; i++) {\n\t\tif (Num % i == 0) return false;\n\t}\n\treturn true;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3364, "score_of_the_acc": -0.0793, "final_rank": 10 }, { "submission_id": "aoj_1141_9306490", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,k,n) for (int i = k; i < (n); ++i)\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\ntypedef pair<ll, ll> P;\nconst long long INF = 1e17;\n\nbool prime(int x){\n bool ok = true;\n for(int i=2;i*i<=x;i++){\n if(x%i==0){\n ok = false;\n break;\n }\n }\n return ok;\n}\n\nint main(){\n while(true){\n int a,d,n;\n cin >> a >> d >> n;\n if(a==0){\n break;\n }\n\n int cnt = 0;\n int tmp = a;\n while(true){\n if(tmp>=2&&prime(tmp)){\n cnt++;\n if(cnt==n){\n cout << tmp << endl;\n break;\n }\n }\n\n tmp += d;\n }\n\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3172, "score_of_the_acc": -0.0205, "final_rank": 6 }, { "submission_id": "aoj_1141_9299525", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define all(a) a.begin(),a.end()\n#define reps(i, a, n) for (int i = (a); i < (int)(n); i++)\n#define rep(i, n) reps(i, 0, n)\n#define rreps(i, a, n) for (int i = (a); i > (int)(n); i--)\nconst long long mod = 1000000007;\nconst int inf = 1e9;\nconst long long INF = 1e18;\nll myceil(ll a, ll b) {return (a+b-1)/b;}\n\nint a,d,n;\n\nbool judge_prime(int n) {\n if (n == 1) {\n return false;\n }\n if (n == 2) {\n return true;\n }\n if (n%2 == 0) {\n return false;\n }\n for (int i = 3; i < min((int)pow(n,0.5)+100,n); i+=2) {\n if (n%i == 0) {\n return false;\n }\n }\n return true;\n}\n\nvoid solve() {\n a -= d;\n while (n > 0) {\n a += d;\n if (judge_prime(a)) {\n n--;\n }\n }\n cout << a << endl;\n return;\n}\n\nint main() {\n while (true) {\n cin >> a >> d >> n;\n if (a == 0) {\n return 0;\n }\n solve();\n }\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 3436, "score_of_the_acc": -0.3326, "final_rank": 16 }, { "submission_id": "aoj_1141_9088724", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i=0;i<n;i++)\n\nbool isprime(int x){\n if(x<=1) return false;\n for(int i=2;i*i<=x;i++){\n if(x%i==0) return false;\n }\n return true;\n}\n\nint main(){\n int a,d,n;\n while(true){\n cin >> a >> d >> n;\n if(a==0&&d==0&&n==0){\n return 0;\n }\n int t=a;\n int cnt;\n if(isprime(a)) cnt=1;\n else cnt=0;\n\n while(cnt!=n){\n t+=d;\n if(isprime(t)) cnt++;\n }\n cout << t << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3132, "score_of_the_acc": -0.0187, "final_rank": 4 }, { "submission_id": "aoj_1141_8221609", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <string>\n#include <stdio.h>\n#include <math.h>\n#include <set>\n#include <map>\n#include <queue>\n#include <cassert>\n#include <numeric>\n#include <cstdio>\n\n\nusing namespace std;\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define P pair<int, int>\n\n\nint main() {\n\tlong long a, d, n;\n\tcin >> a >> d >> n;\n\n\twhile (n != 0) {\n\t\tlong long count = 0;\n\t\tbool flag = false;\n\t\tvector<long long>ans;\n\t\twhile (true) {\n\t\t\tflag = false;\n\t\t\tfor (long long j = 2;j * j <= a + count * d;j++) {\n\t\t\t\tif ((a + count * d) % j == 0) {\n\t\t\t\t\tflag = true;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (!flag) {\n\t\t\t\tif((a + count * d)!=1)\n\t\t\t\tans.push_back(a + count * d);\n\t\t\t\t//cout << a + count * d << endl;\n\t\t\t}\n\t\t\tif (ans.size() == n) {\n\t\t\t\tcout << ans[ans.size()-1] << endl;\n\t\t\t\tans.clear();\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tcount++;\n\t\t}\n\t\tcin >> a >> d >> n;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3212, "score_of_the_acc": -0.089, "final_rank": 13 } ]
aoj_1138_cpp
Problem D: Traveling by Stagecoach Once upon a time, there was a traveler. He plans to travel using stagecoaches (horse wagons). His starting point and destination are fixed, but he cannot determine his route. Your job in this problem is to write a program which determines the route for him. There are several cities in the country, and a road network connecting them. If there is a road between two cities, one can travel by a stagecoach from one of them to the other. A coach ticket is needed for a coach ride. The number of horses is specified in each of the tickets. Of course, with more horses, the coach runs faster. At the starting point, the traveler has a number of coach tickets. By considering these tickets and the information on the road network, you should find the best possible route that takes him to the destination in the shortest time. The usage of coach tickets should be taken into account. The following conditions are assumed. A coach ride takes the traveler from one city to another directly connected by a road. In other words, on each arrival to a city, he must change the coach. Only one ticket can be used for a coach ride between two cities directly connected by a road. Each ticket can be used only once. The time needed for a coach ride is the distance between two cities divided by the number of horses. The time needed for the coach change should be ignored. Input The input consists of multiple datasets, each in the following format. The last dataset is followed by a line containing five zeros (separated by a space). n m p a b t 1 t 2 ... t n x 1 y 1 z 1 x 2 y 2 z 2 ... x p y p z p Every input item in a dataset is a non-negative integer. If a line contains two or more input items, they are separated by a space. n is the number of coach tickets. You can assume that the number of tickets is between 1 and 8. m is the number of cities in the network. You can assume that the number of cities is between 2 and 30. p is the number of roads between cities, which may be zero. a is the city index of the starting city. b is the city index of the destination city. a is not equal to b . You can assume that all city indices in a dataset (including the above two) are between 1 and m . The second line of a dataset gives the details of coach tickets. t i is the number of horses specified in the i -th coach ticket (1<= i <= n ). You can assume that the number of horses is between 1 and 10. The following p lines give the details of roads between cities. The i -th road connects two cities with city indices x i and y i , and has a distance z i (1<= i <= p ). You can assume that the distance is between 1 and 100. No two roads connect the same pair of cities. A road never connects a city with itself. Each road can be traveled in both directions. Output For each dataset in the input, one line should be output as specified below. An output line should not contain extra characters such as spaces. If the traveler can reach the destination, the time needed for ...(truncated)
[ { "submission_id": "aoj_1138_10865848", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\nusing namespace std;\n\nconst int INF = 0x3f3f3f3f;\nconst int MAX_N = 8;\nconst int MAX_M = 30;\n\nint N, M, P, A, B;\n\nint t[MAX_N];\nint w[MAX_M][MAX_M];\ndouble dp[(1 << MAX_N)][MAX_M];\n// dp[S][v]: 从A到v的最小时间\n// S 用掉的车票数\n// v 相邻的城市\n\nint main() \n{\n\twhile (scanf(\"%d %d %d %d %d\", &N, &M, &P, &A, &B))\n\t{\n\t\tif (N == 0 && M == 0 && P == 0 && A == 0 && B == 0) break;\n\n\t\tA--; B--;\n\n\t\t// 初始化\n\t\tmemset(w, INF, sizeof(w));\n\t\tfor (int v = 0; v < M; v++)\n\t\t{\n\t\t\tw[v][v] = 0;\n\t\t}\n\t\tfor (int s = 0; s < (1 << N); s++) \n\t\t{\n\t\t\tfor (int v = 0; v < M; v++)\n\t\t\t{\n\t\t\t\tdp[s][v] = INF;\n\t\t\t}\n\t\t}\n\n\t\t// 输入\n\t\tfor (int i = 0; i < N; i++) //马车的马个数\n\t\t{\n\t\t\tscanf(\"%d\", &t[i]);\n\t\t}\n\n\t\tfor (int u = 0; u < M; u++) \n\t\t{\n\t\t\tfill(w[u], w[u] + M, INF);\n\t\t\tw[u][u] = 0;\n\t\t}\n\n\t\tfor (int i = 0; i < P; i++) //输入网络\n\t\t{\n\t\t\tint u, v, d;\n\t\t\tscanf(\"%d %d %d\", &u, &v, &d);\n\t\t\tu--; v--;\n\t\t\tw[u][v] = w[v][u] = d;\n\t\t}\n\n\t\tdp[0][A] = 0;\n\n\t\tfor (int S = 1; S < (1 << N); S++) \n\t\t{\n\t\t\tfor (int v = 0; v < M; v++)\n\t\t\t{\n\t\t\t\tfor (int u = 0; u < M; u++) \n\t\t\t\t{ // from u\n\t\t\t\t\tif (w[u][v] == INF) continue; // no edge between u -> v\n\n\t\t\t\t\tfor (int x = 0; x < N; x++)\n\t\t\t\t\t{ \n\t\t\t\t\t\t// use ticket x\n\t\t\t\t\t\tif (!(S & (1 << x))) continue; // ticket x not in S\n\n\t\t\t\t\t\tdp[S][v] = min(dp[S][v],dp[S ^ (1 << x)][u] + double(w[u][v]) / t[x]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tdouble ans = INF;\n\t\tfor (int S = 0; S < (1 << N); S++) \n\t\t{\n\t\t\tans = min(ans, dp[S][B]);\n\t\t}\n\n\t\tif (fabs(ans - INF) < 1e-8) puts(\"Impossible\");\n\t\telse \n\t\t{\n\t\t\tprintf(\"%.10f\\n\", ans);\n\t\t}\n\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3564, "score_of_the_acc": -0.0104, "final_rank": 3 }, { "submission_id": "aoj_1138_10628016", "code_snippet": "#include<iostream>\n#include<vector>\n#include<queue>\n#include<iomanip>\nusing namespace std;\nusing Vertex=pair<double,pair<int,int> >;\nint T,N,M,a,b;\ndouble t[8];\nvector<pair<int,double> >G[31];\nint main()\n{\n\tios::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\twhile(1)\n\t{\n\t\tcin>>T>>N>>M>>a>>b;\n\t\tif(T==0)break;\n\t\ta--,b--;\n\t\tfor(int i=0;i<T;i++)cin>>t[i];\n\t\tfor(int i=0;i<N;i++)G[i].clear();\n\t\tfor(int i=0;i<M;i++)\n\t\t{\n\t\t\tint u,v,w;cin>>u>>v>>w;\n\t\t\tu--,v--;\n\t\t\tG[u].push_back(make_pair(v,w));\n\t\t\tG[v].push_back(make_pair(u,w));\n\t\t}\n\t\tpriority_queue<Vertex,vector<Vertex>,greater<Vertex> >Q;\n\t\tQ.push(make_pair(0,make_pair(a,0)));\n\t\tvector<vector<double> >dist(N,vector<double>(1<<T,1e9));\n\t\tdist[a][0]=0;\n\t\twhile(!Q.empty())\n\t\t{\n\t\t\tauto[d,tmp]=Q.top();Q.pop();\n\t\t\tauto[u,used]=tmp;\n\t\t\tif(u==b)continue;\n\t\t\tif(dist[u][used]<d)continue;\n\t\t\tfor(auto[v,c]:G[u])for(int i=0;i<T;i++)if(!(used>>i&1))\n\t\t\t{\n\t\t\t\tdouble nd=d+c/t[i];\n\t\t\t\tint nused=used|(1<<i);\n\t\t\t\tif(dist[v][nused]<=nd)continue;\n\t\t\t\tdist[v][nused]=nd;\n\t\t\t\tQ.push(make_pair(nd,make_pair(v,nused)));\n\t\t\t}\n\t\t}\n\t\tdouble ans=1e9;\n\t\tfor(int i=0;i<1<<T;i++)ans=min(ans,dist[b][i]);\n\t\tif(ans==1e9)cout<<\"Impossible\"<<endl;\n\t\telse cout<<fixed<<setprecision(10)<<ans<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5308, "score_of_the_acc": -0.0945, "final_rank": 9 }, { "submission_id": "aoj_1138_10626915", "code_snippet": "#include<iostream>\n#include<vector>\n#include<queue>\n#include<algorithm>\n#include<iomanip>\nusing namespace std;\nint main()\n{\n\tios::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\twhile(1)\n\t{\n\t\tint N,M,p,a,b;cin>>N>>M>>p>>a>>b;\n\t\tif(N==0)break;\n\t\tvector<double>t(N);\n\t\tfor(int i=0;i<N;i++)cin>>t[i];\n\t\tvector<vector<pair<int,double> > >G(M+1,vector<pair<int,double> >());\n\t\tfor(int i=0;i<p;i++)\n\t\t{\n\t\t\tint x,y,z;cin>>x>>y>>z;\n\t\t\tG[x].push_back(make_pair(y,z));\n\t\t\tG[y].push_back(make_pair(x,z));\n\t\t}\n\t\tvector<vector<double>>dist(M+1,vector<double>(1<<N,1e9));\n\t\tdist[a][0]=0;\n\t\tpriority_queue<pair<double,pair<int,int> >,vector<pair<double,pair<int,int> > >,greater<pair<double,pair<int,int> > > >Q;\n\t\tQ.push(make_pair(0,make_pair(a,0)));\n\t\twhile(!Q.empty())\n\t\t{\n\t\t\tauto[d,p]=Q.top();Q.pop();\n\t\t\tauto[u,used]=p;\n\t\t\tif(u==b)continue;\n\t\t\tif(dist[u][used]<d)continue;\n\t\t\tfor(auto[v,c]:G[u])for(int i=0;i<N;i++)\n\t\t\t{\n\t\t\t\tif(used>>i&1)continue;\n\t\t\t\tdouble nd=d+c/t[i];\n\t\t\t\tint nxt=used|(1<<i);\n\t\t\t\tif(dist[v][nxt]<=nd)continue;\n\t\t\t\tdist[v][nxt]=nd;\n\t\t\t\tQ.push(make_pair(nd,make_pair(v,nxt)));\n\t\t\t}\n\t\t}\n\t\tdouble ans=1e9;\n\t\tfor(int i=0;i<1<<N;i++)ans=min(ans,dist[b][i]);\n\t\tif(ans==1e9)cout<<\"Impossible\"<<endl;\n\t\telse cout<<fixed<<setprecision(10)<<ans<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5312, "score_of_the_acc": -0.0946, "final_rank": 10 }, { "submission_id": "aoj_1138_10599944", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nusing edge = pair<int, double>;\nconst double INF = 2e9;\n\nint main() {\n while (true) {\n int n, m, p, s, t;\n cin >> n >> m >> p >> s >> t;\n if (n == 0 && m == 0 && p == 0 && s == 0 && t == 0) {\n break;\n }\n s--;\n t--;\n\n vector<int> T(n);\n for (int i = 0; i < n; i++) {\n cin >> T[i];\n }\n vector<vector<edge>> E(m);\n for (int i = 0; i < p; i++) {\n int x, y;\n double z;\n cin >> x >> y >> z;\n x--;\n y--;\n E[x].emplace_back(y, z);\n E[y].emplace_back(x, z);\n }\n\n vector<vector<double>> dist(m, vector<double>(1 << n, INF));\n priority_queue<tuple<double, int, int>, vector<tuple<double, int, int>>, greater<>> pq;\n dist[s][0] = 0;\n pq.emplace(0, s, 0);\n while (!pq.empty()) {\n auto [cost, u, bit] = pq.top();\n pq.pop();\n if (dist[u][bit] < cost) {\n continue;\n }\n for (auto [v, w] : E[u]) {\n for (int i = 0; i < n; i++) {\n if (bit & (1 << i)) {\n continue;\n }\n int next_bit = bit | (1 << i);\n double next_cost = cost + w / T[i];\n if (dist[v][next_bit] > next_cost) {\n dist[v][next_bit] = next_cost;\n pq.emplace(next_cost, v, next_bit);\n }\n }\n }\n }\n\n double ans = INF;\n for (int bit = 0; bit < (1 << n); bit++) {\n ans = min(ans, dist[t][bit]);\n }\n if (ans == INF) {\n cout << \"Impossible\" << endl;\n } else {\n printf(\"%.10f\\n\", ans);\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5288, "score_of_the_acc": -0.0937, "final_rank": 7 }, { "submission_id": "aoj_1138_10599915", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nusing edge = pair<int, double>;\nconst double INF = 2e9;\n\nint main() {\n while (true) {\n int n, m, p, s, t;\n cin >> n >> m >> p >> s >> t;\n if (n == 0 && m == 0 && p == 0 && s == 0 && t == 0) {\n break;\n }\n s--;\n t--;\n\n vector<int> T(n);\n for (int i = 0; i < n; i++) {\n cin >> T[i];\n }\n vector<vector<edge>> E(m);\n for (int i = 0; i < p; i++) {\n int x, y;\n double z;\n cin >> x >> y >> z;\n x--;\n y--;\n E[x].emplace_back(y, z);\n E[y].emplace_back(x, z);\n }\n\n vector<vector<double>> dist(m, vector<double>(1 << n, INF));\n priority_queue<tuple<double, int, int>, vector<tuple<double, int, int>>, greater<>> pq;\n dist[s][0] = 0;\n pq.emplace(0, s, 0);\n while (!pq.empty()) {\n auto [cost, u, bit] = pq.top();\n pq.pop();\n if (dist[u][bit] < cost) {\n continue;\n }\n for (auto [v, w] : E[u]) {\n for (int i = 0; i < n; i++) {\n if (bit & (1 << i)) {\n continue;\n }\n int next_bit = bit | (1 << i);\n double next_cost = dist[u][bit] + w / T[i];\n if (dist[v][next_bit] > next_cost) {\n dist[v][next_bit] = next_cost;\n pq.emplace(next_cost, v, next_bit);\n }\n }\n }\n }\n\n double ans = INF;\n for (int bit = 0; bit < (1 << n); bit++) {\n ans = min(ans, dist[t][bit]);\n }\n if (ans == INF) {\n cout << \"Impossible\" << endl;\n } else {\n printf(\"%.10f\\n\", ans);\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5292, "score_of_the_acc": -0.0938, "final_rank": 8 }, { "submission_id": "aoj_1138_10191755", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n while(true) {\n ll C, N, M, S, T;\n cin >> C >> N >> M >> S >> T;\n S--, T--;\n\n if(!C) { break; }\n\n vector<double> t(C);\n for(auto &i : t) { cin >> i; }\n\n vector<vector<pair<ll, double>>> g(N);\n for(ll i = 0, u, v, w; i < M; i++) {\n cin >> u >> v >> w;\n u--, v--;\n g[u].emplace_back(v, w);\n g[v].emplace_back(u, w);\n }\n\n vector<vector<double>> dp(N, vector<double>(1 << C, 1e18));\n dp[S][0] = 0;\n priority_queue<tuple<double, ll, ll>, vector<tuple<double, ll, ll>>, greater<tuple<double, ll, ll>>> q;\n q.emplace(0, S, 0);\n\n while(!q.empty()) {\n auto [d, v, s] = q.top();\n q.pop();\n if(dp[v][s] < d) { continue; }\n for(auto &[nv, w] : g[v]) {\n for(ll i = 0; i < C; i++) {\n if(s >> i & 1) { continue; }\n ll ns = s | (1 << i);\n double nd = d + w / t[i];\n if(nd < dp[nv][ns]) {\n dp[nv][ns] = nd;\n q.emplace(nd, nv, ns);\n }\n }\n }\n }\n\n double ans = ranges::min(dp[T]);\n if(ans > 1e17) { cout << \"Impossible\\n\"; }\n else { cout << fixed << setprecision(12) << ans << \"\\n\"; }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6080, "score_of_the_acc": -0.1257, "final_rank": 12 }, { "submission_id": "aoj_1138_9670129", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vi;\ntypedef long double ld;\ntypedef pair<ll,ll> pi;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\ntemplate<typename T>bool chmin(T&a,T b){if(a>b){a=b;return 1;}return 0;}\ntemplate<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;\nint main(){\n while(1){\n ll T,N,M,s,g;\n cin>>T>>N>>M>>s>>g;s--;g--;\n if(!T)return 0;\n vi A(T);REP(i,T)cin>>A[i];//頭数\n vector<vector<pi>>E(N);\n REP(i,M){\n ll u,v,d;cin>>u>>v>>d;u--;v--;\n E[u].emplace_back(pi(v,d));\n E[v].emplace_back(pi(u,d));\n }\n vector<vector<ld>>D(N,vector<ld>(1<<T,1e18));\n D[s].back()=0;\n min_priority_queue<pair<ld,pi>>Q;\n Q.emplace(make_pair(0,pi(s,(1<<T)-1)));\n while(!Q.empty()){\n auto[d,p]=Q.top();Q.pop();\n if(d!=D[p.first][p.second])continue;\n for(auto[u,c]:E[p.first])REP(i,T)if((p.second>>i)%2){\n if(chmin(D[u][p.second-(1<<i)],d+(ld)c/A[i])){\n Q.emplace(make_pair(d+(ld)c/A[i],pi(u,p.second-(1<<i))));\n }\n }\n }\n ld ans=*min_element(ALL(D[g]));\n if(ans>1e17)cout<<\"Impossible\"<<endl;\n else printf(\"%.20Lf\\n\",ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 6300, "score_of_the_acc": -0.1482, "final_rank": 13 }, { "submission_id": "aoj_1138_9597180", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nint main() {\n int n, m, p, a, b;\n while (true) {\n cin >> n >> m >> p >> a >> b;\n if (n == 0 && m == 0 && p == 0 && a == 0 && b == 0) {\n break;\n }\n vector<int> t(n);\n for (int i = 0; i < n; i++) {\n cin >> t[i];\n }\n a--, b--;\n vector<vector<pair<int, double> > > g(m);\n for (int i = 0; i < p; i++) {\n int x, y, z;\n cin >> x >> y >> z;\n x--, y--;\n pair<int, double> p1;\n p1.first = y, p1.second = z;\n pair<int, double> p2;;\n p2.first = x, p2.second = z;\n g[x].push_back(p1);\n g[y].push_back(p2);\n }\n vector<vector<double> > dp((1 << n), vector<double>(m, 1e18));\n dp[0][a] = 0;\n for (int mask = 0; mask < (1 << n); mask++) {\n for (int v = 0; v < m; v++) {\n for (int i = 0; i < n; i++) {\n if ((mask >> i) & 1) {\n continue;\n }\n for (int k = 0; k < g[v].size(); k++) {\n int u = g[v][k].first;\n double w = g[v][k].second;\n dp[mask | (1 << i)][u] = min(dp[mask | (1 << i)][u], dp[mask][v] + (w / t[i]));\n }\n }\n }\n }\n double ans = 1e18;\n for (int mask = 0; mask < (1 << n); mask++) {\n ans = min(ans, dp[mask][b]);\n }\n if (ans == 1e18) {\n cout << \"Impossible\" << '\\n';\n } else {\n cout << ans << '\\n';\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3308, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1138_9581158", "code_snippet": "#include <algorithm>\n#include <cmath>\n#include <cstdlib>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <unordered_set>\n#include <vector>\n\nusing namespace std;\nusing ll = long long;\n\nstruct Node {\n\tint city;\n\tint tickets;\n\n\tNode(const int city, const int tickets)\n\t\t: city(city), tickets(tickets) {};\n\n\tbool operator<(const Node& node) const {\n\t\tif (this->city != node.city) return this->city < node.city;\n\t\telse return this->tickets < node.tickets;\n\t}\n};\n\nstruct QueueItem {\n\tNode node;\n\tdouble shortest_time;\n\n\tQueueItem(const Node node, const double shortest_time)\n\t\t: node(node), shortest_time(shortest_time) {};\n\n\tbool operator<(const QueueItem& queue_item) const {\n\t\treturn this->shortest_time > queue_item.shortest_time;\n\t}\n};\n\nvoid Solve(const int& n, const int& dep, const int& dst, const map<int, int>& numof_horses, const vector<map<int, int>>& distances) {\n\tdouble shortest_time_to_dst = -1.0;\n\n\tmap<Node, double> shortest_time;\n\tpriority_queue<QueueItem> queue;\n\n\tshortest_time[Node(dep, (1 << n) - 1)] = 0.0;\n\tqueue.push(QueueItem((*shortest_time.begin()).first, (*shortest_time.begin()).second));\n\twhile (!queue.empty()) {\n\t\tNode current = queue.top().node;\n\t\tqueue.pop();\n\n\t\tif (current.city == dst) {\n\t\t\tshortest_time_to_dst = shortest_time[current];\n\t\t\tbreak;\n\t\t}\n\n\t\tfor (const auto& entry : distances[current.city]) {\n\t\t\tint adjacent_city = entry.first, distance = entry.second;\n\t\t\tfor (int ticket = 1 << (n - 1); ticket > 0; ticket >>= 1) {\n\t\t\t\tif ((current.tickets & ticket) == 0) continue;\n\t\t\t\tNode adjacent(adjacent_city, current.tickets ^ ticket);\n\t\t\t\tdouble adjacent_shortest_time = shortest_time[current] + (double)distance / numof_horses.at(ticket);\n\t\t\t\tif (shortest_time.find(adjacent) != shortest_time.end() and shortest_time[adjacent] <= adjacent_shortest_time) continue;\n\t\t\t\tshortest_time[adjacent] = adjacent_shortest_time;\n\t\t\t\tqueue.push(QueueItem(adjacent, adjacent_shortest_time));\n\t\t\t}\n\t\t}\n\t}\n\n\tif (shortest_time_to_dst == -1.0) cout << \"Impossible\" << endl;\n\telse cout << shortest_time_to_dst << endl;\n}\n\nint main(void) {\n\tcout << fixed << setprecision(3);\n\twhile (true) {\n\t\tint n, m, p, a, b;\n\t\tcin >> n >> m >> p >> a >> b;\n\t\tif (n == 0) break;\n\t\ta--;\n\t\tb--;\n\t\tmap<int, int> numof_horses;\n\t\tfor (int ticket = 1 << (n - 1); ticket > 0; ticket >>= 1) cin >> numof_horses[ticket];\n\t\tvector<map<int, int>> distances(m);\n\t\tfor (int i = 0; i < p; i++) {\n\t\t\tint x, y, z;\n\t\t\tcin >> x >> y >> z;\n\t\t\tx--;\n\t\t\ty--;\n\t\t\tdistances[x][y] = distances[y][x] = z;\n\t\t}\n\t\tSolve(n, a, b, numof_horses, distances);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 630, "memory_kb": 5100, "score_of_the_acc": -0.4942, "final_rank": 15 }, { "submission_id": "aoj_1138_9581149", "code_snippet": "#include <algorithm>\n#include <cmath>\n#include <cstdlib>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <unordered_set>\n#include <vector>\n\nusing namespace std;\nusing ll = long long;\n\nstruct Node {\n\tint city;\n\tint tickets;\n\n\tNode(const int city, const int tickets)\n\t\t: city(city), tickets(tickets) {};\n\n\tbool operator<(const Node& node) const {\n\t\tif (this->city != node.city) return this->city < node.city;\n\t\telse return this->tickets < node.tickets;\n\t}\n};\n\nstruct QueueItem {\n\tNode node;\n\tdouble shortest_time;\n\n\tQueueItem(const Node node, const double shortest_time)\n\t\t: node(node), shortest_time(shortest_time) {};\n\n\tbool operator<(const QueueItem& queue_item) const {\n\t\treturn this->shortest_time > queue_item.shortest_time;\n\t}\n};\n\nvoid Solve(const int& n, const int& dep, const int& dst, const map<int, int>& numof_horses, const vector<map<int, int>>& distances) {\n\tdouble shortest_time_to_dst = -1.0;\n\n\tmap<Node, double> shortest_time;\n\tpriority_queue<QueueItem> queue;\n\n\tshortest_time[Node(dep, (1 << n) - 1)] = 0.0;\n\tqueue.push(QueueItem((*shortest_time.begin()).first, (*shortest_time.begin()).second));\n\twhile (!queue.empty()) {\n\t\tNode current = queue.top().node;\n\t\tqueue.pop();\n\n\t\tif (current.city == dst) {\n\t\t\tshortest_time_to_dst = shortest_time[current];\n\t\t\tbreak;\n\t\t}\n\n\t\tif (current.tickets == 0) continue;\n\n\t\tfor (const auto& entry : distances[current.city]) {\n\t\t\tint adjacent_city = entry.first, distance = entry.second;\n\t\t\tfor (int ticket = 1 << (n - 1); ticket > 0; ticket >>= 1) {\n\t\t\t\tif ((current.tickets & ticket) == 0) continue;\n\t\t\t\tNode adjacent(adjacent_city, current.tickets ^ ticket);\n\t\t\t\tdouble adjacent_shortest_time = shortest_time[current] + (double)distance / numof_horses.at(ticket);\n\t\t\t\tif (shortest_time.find(adjacent) != shortest_time.end() and shortest_time[adjacent] <= adjacent_shortest_time) continue;\n\t\t\t\tshortest_time[adjacent] = adjacent_shortest_time;\n\t\t\t\tqueue.push(QueueItem(adjacent, adjacent_shortest_time));\n\t\t\t}\n\t\t}\n\t}\n\n\tif (shortest_time_to_dst == -1.0) cout << \"Impossible\" << endl;\n\telse cout << shortest_time_to_dst << endl;\n}\n\nint main(void) {\n\tcout << fixed << setprecision(3);\n\twhile (true) {\n\t\tint n, m, p, a, b;\n\t\tcin >> n >> m >> p >> a >> b;\n\t\tif (n == 0) break;\n\t\ta--;\n\t\tb--;\n\t\tmap<int, int> numof_horses;\n\t\tfor (int ticket = 1 << (n - 1); ticket > 0; ticket >>= 1) cin >> numof_horses[ticket];\n\t\tvector<map<int, int>> distances(m);\n\t\tfor (int i = 0; i < p; i++) {\n\t\t\tint x, y, z;\n\t\t\tcin >> x >> y >> z;\n\t\t\tx--;\n\t\t\ty--;\n\t\t\tdistances[x][y] = distances[y][x] = z;\n\t\t}\n\t\tSolve(n, a, b, numof_horses, distances);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 720, "memory_kb": 5232, "score_of_the_acc": -0.5608, "final_rank": 16 }, { "submission_id": "aoj_1138_9581145", "code_snippet": "#include <algorithm>\n#include <cmath>\n#include <cstdlib>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <unordered_set>\n#include <vector>\n\nusing namespace std;\nusing ll = long long;\n\nstruct Node {\n\tint city;\n\tint tickets;\n\n\tNode(const int city, const int tickets)\n\t\t: city(city), tickets(tickets) {};\n\n\tbool operator<(const Node& node) const {\n\t\tif (this->city != node.city) return this->city < node.city;\n\t\telse return this->tickets < node.tickets;\n\t}\n};\n\nstruct QueueItem {\n\tNode node;\n\tdouble shortest_time;\n\n\tQueueItem(const Node node, const double shortest_time)\n\t\t: node(node), shortest_time(shortest_time) {};\n\n\tbool operator<(const QueueItem& queue_item) const {\n\t\treturn this->shortest_time > queue_item.shortest_time;\n\t}\n};\n\nvoid Solve(const int& n, const int& dep, const int& dst, const map<int, int>& numof_horses, const vector<map<int, int>>& distances) {\n\tdouble shortest_time_to_dst = -1.0;\n\n\tmap<Node, double> shortest_time;\n\tmap<Node, bool> done;\n\tpriority_queue<QueueItem> queue;\n\n\tshortest_time[Node(dep, (1 << n) - 1)] = 0.0;\n\tqueue.push(QueueItem((*shortest_time.begin()).first, (*shortest_time.begin()).second));\n\twhile (!queue.empty()) {\n\t\tNode current = queue.top().node;\n\t\tqueue.pop();\n\n\t\tif (current.city == dst) {\n\t\t\tshortest_time_to_dst = shortest_time[current];\n\t\t\tbreak;\n\t\t}\n\n\t\tif (done[current]) continue;\n\t\tdone[current] = true;\n\n\t\tif (current.tickets == 0) continue;\n\n\t\tfor (const auto& entry : distances[current.city]) {\n\t\t\tint adjacent_city = entry.first, distance = entry.second;\n\t\t\tfor (int ticket = 1 << (n - 1); ticket > 0; ticket >>= 1) {\n\t\t\t\tif ((current.tickets & ticket) == 0) continue;\n\t\t\t\tNode adjacent(adjacent_city, current.tickets ^ ticket);\n\t\t\t\tif (done[adjacent]) continue;\n\t\t\t\tdouble adjacent_shortest_time = shortest_time[current] + (double)distance / numof_horses.at(ticket);\n\t\t\t\tif (shortest_time.find(adjacent) != shortest_time.end() and shortest_time[adjacent] <= adjacent_shortest_time) continue;\n\t\t\t\tshortest_time[adjacent] = adjacent_shortest_time;\n\t\t\t\tqueue.push(QueueItem(adjacent, adjacent_shortest_time));\n\t\t\t}\n\t\t}\n\t}\n\n\tif (shortest_time_to_dst == -1.0) cout << \"Impossible\" << endl;\n\telse cout << shortest_time_to_dst << endl;\n}\n\nint main(void) {\n\tcout << fixed << setprecision(3);\n\twhile (true) {\n\t\tint n, m, p, a, b;\n\t\tcin >> n >> m >> p >> a >> b;\n\t\tif (n == 0) break;\n\t\ta--;\n\t\tb--;\n\t\tmap<int, int> numof_horses;\n\t\tfor (int ticket = 1 << (n - 1); ticket > 0; ticket >>= 1) cin >> numof_horses[ticket];\n\t\tvector<map<int, int>> distances(m);\n\t\tfor (int i = 0; i < p; i++) {\n\t\t\tint x, y, z;\n\t\t\tcin >> x >> y >> z;\n\t\t\tx--;\n\t\t\ty--;\n\t\t\tdistances[x][y] = distances[y][x] = z;\n\t\t}\n\t\tSolve(n, a, b, numof_horses, distances);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 540, "memory_kb": 5404, "score_of_the_acc": -0.4453, "final_rank": 14 }, { "submission_id": "aoj_1138_9548966", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nll LCM = 2520;\n\nint main() {\nwhile(1) {\n int N, M, L, S, T;\n cin >> L >> N >> M >> S >> T;\n if (N == 0) return 0;\n S--, T--;\n vector<ll> A(L);\n rep(i,0,L) cin >> A[i], A[i] = LCM / A[i];\n vector<vector<pair<int,ll>>> G(N);\n rep(i,0,M) {\n int X, Y;\n ll Z;\n cin >> X >> Y >> Z;\n X--, Y--;\n G[X].push_back({Y,Z});\n G[Y].push_back({X,Z});\n }\n int K = 1<<L;\n vector<vector<ll>> DP(N, vector<ll>(K,INF));\n priority_queue<pair<ll,pair<int,int>>, vector<pair<ll,pair<int,int>>>, greater<pair<ll,pair<int,int>>>> Q;\n DP[S][0] = 0;\n Q.push({0,{S,0}});\n while(!Q.empty()) {\n auto [D, P] = Q.top();\n auto [X, Y] = P;\n Q.pop();\n if (D > DP[X][Y]) continue;\n rep(i,0,L) {\n if ((Y & (1<<i)) != 0) continue;\n for (auto [NX, ND] : G[X]) {\n int NY = Y | (1<<i);\n ll NND = D + ND * A[i];\n if (NND < DP[NX][NY]) {\n DP[NX][NY] = NND;\n Q.push({NND,{NX,NY}});\n }\n }\n }\n }\n ll ANS = INF;\n rep(i,0,K) {\n chmin(ANS, DP[T][i]);\n }\n if (ANS == INF) print(\"Impossible\");\n else print((double)ANS / (double)LCM);\n}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4940, "score_of_the_acc": -0.0728, "final_rank": 5 }, { "submission_id": "aoj_1138_9364017", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\nusing ll = long long;\n#define MOD 1000000007\n#define Mod 998244353\nconst int MAX = 1000000005;\nconst long long INF = 1000000000000000005LL;\nusing namespace std;\n//using namespace atcoder;\n\nusing d_i = pair<double, int>;\nconst double eps = 1e-6;\n\nbool solve() {\n int n, m, p, a, b;\n cin >> n >> m >> p >> a >> b;\n a--; b--;\n if (n == 0) return false;\n vector<int> t(n);\n for (int i = 0; i < n; i++) cin >> t[i];\n vector<vector<pair<int, int>>> G(m);\n for (int i = 0; i < p; i++) {\n int x, y, z;\n cin >> x >> y >> z;\n x--; y--;\n G[x].push_back({y, z});\n G[y].push_back({x, z});\n }\n vector<int> vec(n);\n for (int i = 0; i < n; i++) vec[i] = i;\n double ans = 1e+10;\n do {\n vector<vector<double>> dp(n+1, vector<double>(m, 1e+10));\n dp[0][a] = 0;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < m; j++) {\n for (auto [k, cost] : G[j]) {\n dp[i+1][k] = min(dp[i+1][k], dp[i][j] + (double)cost/t[vec[i]]);\n }\n }\n ans = min(ans, dp[i+1][b]);\n }\n } while (next_permutation(vec.begin(), vec.end()));\n if (fabs(ans - 1e+10) <= eps) cout << \"Impossible\" << endl;\n else cout << fixed << setprecision(10) << ans << endl;\n return true;\n}\n\nint main() {\n ios::sync_with_stdio(0); cin.tie();\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 1480, "memory_kb": 3356, "score_of_the_acc": -1.0019, "final_rank": 19 }, { "submission_id": "aoj_1138_9359685", "code_snippet": "#include<bits/stdc++.h>\n//#include <atcoder/all>\nusing namespace std;\n//using namespace atcoder;\n\n#define all(v) v.begin(),v.end()\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll=vector<ll>;\nusing vvll = vector<vector<ll>>;\nusing P = pair<ll,ll>;\nusing PP=pair<double,P>;\nusing vp=vector<pair<ll, ll>>;\n//using mint=modint1000000007;\n//using mint=modint998244353;\n\nconst ll INF=1ll<<60;\nll mod10=1e9+7;\nll mod99=998244353;\nconst double PI = acos(-1);\n\n#define rep(i,n) for (ll i=0;i<n;++i)\n#define per(i,n) for(ll i=n-1;i>=0;--i)\n#define rep2(i,a,n) for (ll i=a;i<n;++i)\n#define per2(i,a,n) for (ll i=a;i>=n;--i)\n\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n\nbool solve(){\n ll N,M,P,a,b;cin>>N>>M>>P>>a>>b;\n if(N==0&&M==0&&P==0) return 0;\n a--;b--;\n vll T(N);rep(i,N)cin>>T[i];\n vector<vp> ab(M);\n rep(i,P){\n ll x,y,c;cin>>x>>y>>c;\n x--;y--;\n ab[x].push_back({c,y});\n ab[y].push_back({c,x});\n }\n\n vector dist(M,vector<double>(1<<N,INF));\n \n priority_queue<PP,vector<PP>,greater<PP>> pq;\n pq.push({0,{a,0}});\n while(pq.size()){\n auto [t,now1]=pq.top();pq.pop();\n auto [now,bit]=now1;\n if(dist[now][bit]!=INF) continue;\n dist[now][bit]=t;\n for(auto [c,to]:ab[now]){\n rep(j,N){\n if(bit>>j&1) continue;\n double nt=t+(double)c/T[j];\n \n pq.push({nt,{to,bit|(1<<j)}});\n }\n }\n }\n\n double ans=INF;\n rep(i,(1<<N)) chmin(ans,dist[b][i]);\n if(ans==INF) cout << \"Impossible\" << endl;\n else cout << ans << endl;\n \n return 1;\n}\n\n\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n while(solve());\n}", "accuracy": 1, "time_ms": 710, "memory_kb": 28040, "score_of_the_acc": -1.4762, "final_rank": 20 }, { "submission_id": "aoj_1138_9348560", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for(int i = 0; i < n; i++)\nusing namespace std;\nusing i_i = pair<int, int>;\n\nbool solve() {\n int n, m, p, a, b; cin >> n >> m >> p >> a >> b;\n if (n == 0) return false;\n a--, b--;\n vector<int> t(n); rep(i, n) cin >> t[i];\n vector to(m, vector<i_i>());\n for (int i = 0; i < p; i++) {\n int x, y, z; cin >> x >> y >> z;\n x--, y--;\n to[x].emplace_back(y, z);\n to[y].emplace_back(x, z);\n }\n int k = 1 << n;\n int INF = 1001001001;\n vector dp(m, vector<double>(k, INF));\n using S = tuple<double, int, int>;\n priority_queue<S, vector<S>, greater<S>> pq;\n pq.emplace(0, a, 0);\n dp[a][0] = 0;\n while (pq.size()) {\n auto [c, v, bit] = pq.top(); pq.pop();\n if (dp[v][bit] != c) continue;\n for (auto [u, dc] : to[v]) {\n rep(i, n) if (~bit >> i & 1) {\n int nbit = bit | (1 << i);\n double nc = c + (double)dc / t[i];\n assert(u < m and nbit < k);\n if (dp[u][nbit] <= nc) continue;\n dp[u][nbit] = nc;\n pq.emplace(nc, u, nbit);\n }\n }\n }\n double ans = INF;\n for (int i = 0; i < k; i++) {\n assert(b < dp.size());\n assert(i < dp[b].size());\n if (ans > dp[b][i]) ans = dp[b][i];\n }\n if (ans == INF) {\n cout << \"Impossible\" << endl;\n } else {\n cout << fixed << setprecision(6) << ans << endl;\n }\n return true;\n}\n\nint main() {\n while (solve());\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 4880, "score_of_the_acc": -0.084, "final_rank": 6 }, { "submission_id": "aoj_1138_9247497", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint n,m,p,a,b,t[10];\nvector<pair<int,int>>g[30];\nvoid solve(){\n vector<vector<double>>dist(m,vector<double>(1<<n,1.0e18));\n dist[a][0]=0.0;\n priority_queue<tuple<double,int,int>,vector<tuple<double,int,int>>,greater<>>que;\n que.push({dist[a][0],a,0});\n while(!que.empty()){\n auto[d,v,bit]=que.top();\n que.pop();\n for(auto[vv,dd]:g[v]){\n for(int i=0;i<n;++i){\n if(bit&(1<<i))continue;\n double nd=dist[v][bit]+(double)dd/t[i];\n if(nd<dist[vv][bit|(1<<i)]){\n dist[vv][bit|(1<<i)]=nd;\n que.push({nd,vv,bit|(1<<i)});\n }\n }\n }\n }\n double ans=1.0e18;\n for(int bit=0;bit<1<<n;++bit)ans=min(ans,dist[b][bit]);\n if(5.0e17<ans){\n cout<<\"Impossible\"<<'\\n';\n return;\n }\n cout<<ans<<'\\n';\n}\nint main(){\n cin.tie(0)->sync_with_stdio(0);\n cout<<fixed<<setprecision(20);\n while(1){\n cin>>n>>m>>p>>a>>b,--a,--b;\n if(n==0)break;\n for(int i=0;i<n;++i)cin>>t[i];\n for(int i=0;i<m;++i)g[i].clear();\n for(int i=0;i<p;++i){\n int x,y,z;cin>>x>>y>>z,--x,--y;\n g[x].emplace_back(y,z);\n g[y].emplace_back(x,z);\n }\n solve();\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4892, "score_of_the_acc": -0.0981, "final_rank": 11 }, { "submission_id": "aoj_1138_9151597", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = 3.141592653589793;\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\ntemplate<typename T> void view(const vv<T>& vv){ for(const auto& v : vv){ view(v); } }\n\ntuple<vc<double>, vi> dijkstra(int s, int N, vv<pair<int, double>> &g){\n using P = pair<double, int>;\n vc<double> dist(N, inf);\n vi bef(N);\n priority_queue<P, vc<P>, greater<P>> q;\n dist[s] = 0;\n q.push({0, s});\n while (!q.empty()){\n auto [c, now] = q.top();q.pop();\n if (dist[now] < c) continue;\n for (auto&& [nxt, nc]: g[now]) if (dist[nxt] > c + nc){\n dist[nxt] = c + nc;\n bef[nxt] = now;\n q.push({dist[nxt], nxt}); \n }\n }\n return {dist, bef};\n}\n\ndouble solve(int N, int M, int P, int a, int b){\n vi T(N); rep(i, N) cin >> T[i];\n int K = (1 << N);\n vv<pair<int, double>> g(M * K);\n rep(_, P){\n int x, y, z; cin >> x >> y >> z;x--; y--;\n rep(cmb, 1 << N) rep(i, N) if (~cmb >> i & 1){\n g[x * K + (cmb | (1 << i))].push_back({y * K + cmb, z / (double)T[i]});\n g[y * K + (cmb | (1 << i))].push_back({x * K + cmb, z / (double)T[i]});\n }\n }\n auto [dist, bef] = dijkstra(a * K + (1 << N) - 1, M * K, g);\n double ans = inf;\n rep(cmb, 1 << N) ans = min(ans, dist[b * K + cmb]);\n return ans;\n}\n\nint main(){\n vc<double> ans;\n while (true){\n int N, M, P, a, b;cin >> N >> M >> P >> a >> b; a--; b--;\n if (N == 0) break;\n ans.push_back(solve(N, M, P, a, b));\n }\n for (auto x : ans){\n if (x == inf) cout << \"Impossible\" << endl;\n else cout << fixed << setprecision(16) << x << endl;\n }\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 25756, "score_of_the_acc": -0.9553, "final_rank": 17 }, { "submission_id": "aoj_1138_9030364", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\n#define rep(i, a, b) for(ll i = a; i < b; ++i)\n#define rrep(i, a, b) for(ll i = a; i >= b; --i)\nconstexpr ll inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\nint main(void) {\n while(1) {\n int n, m, p, a, b;\n cin >> n >> m >> p >> a >> b;\n if(n == 0) break;\n a--;\n b--;\n vector<int> t(n);\n rep(i, 0, n) {\n cin >> t[i];\n }\n vector<vector<pair<int, double>>> g(m * (1 << n));\n rep(i, 0, p) {\n int x, y, z;\n cin >> x >> y >> z;\n x--;\n y--;\n rep(mask, 0, 1 << n) {\n rep(j, 0, n) {\n if(mask & (1 << j)) continue;\n g[x * (1 << n) + mask].push_back({y * (1 << n) + (mask | (1 << j)), 1.0 * z / t[j]});\n g[y * (1 << n) + mask].push_back({x * (1 << n) + (mask | (1 << j)), 1.0 * z / t[j]});\n }\n }\n }\n vector<double> d(m * (1 << n), inf);\n priority_queue<pair<double, int>, vector<pair<double, int>>, greater<pair<double, int>>> pq;\n d[a * (1 << n)] = 0;\n pq.push({0, a * (1 << n)});\n while(!pq.empty()) {\n auto [dist, cur] = pq.top();\n pq.pop();\n if(d[cur] < dist) continue;\n for(const auto& [to, cost] : g[cur]) {\n if(d[to] > d[cur] + cost) {\n d[to] = d[cur] + cost;\n pq.push({d[to], to});\n }\n }\n }\n double ans = inf;\n rep(mask, 0, 1 << n) {\n ans = min(ans, d[b * (1 << n) + mask]);\n }\n if(ans == inf) {\n cout << \"Impossible\" << '\\n';\n } else {\n cout << ans << '\\n';\n }\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 26200, "score_of_the_acc": -0.98, "final_rank": 18 }, { "submission_id": "aoj_1138_8908151", "code_snippet": "#include <iostream> \n#include <cmath>\n#include <string.h>\n#include <cstdio>\n#include <algorithm>\n#define LL long long\nusing namespace std;\nconst int N = 9;\ndouble v[N], g[32][32];\ndouble dp[1 << N][32];\nint main() {\n\twhile(true) {\n\t\tLL n, m, p, a, b; scanf(\"%lld%lld%lld%lld%lld\", &n, &m, &p, &a, &b);\n\t\tif(n == 0 && m == 0 && p == 0 && a == 0 && b == 0) return 0;\n\t\tfor (int s = 0; s < (1 << n); ++s)\n\t\t\tfor (int i = 0; i <= m; ++i)\n\t\t\t\tdp[s][i] = 1e9;\n\t\tfor (int i = 1; i <= m; ++i)\n\t\t\tfor (int j = 1; j <= m; ++j)\n\t\t\t\tg[i][j] = 0;\n\t\tfor (int i = 0; i < n; ++i) scanf(\"%lf\", &v[i]);\n\t\tdp[0][a] = 0;\n\t\tfor (int i = 1; i <= p; ++i) {\n\t\t\tLL x, y; double z;\n\t\t\tscanf(\"%lld%lld%lf\", &x, &y, &z);\n\t\t\tg[x][y] = g[y][x] = z;\n\t\t}\n\t\tfor (int s = 0; s < (1 << n); ++s) {\n\t\t\tfor (int i = 1; i <= m; ++i) {\n\t\t\t\tfor (int j = 1; j <= m; ++j) {\n\t\t\t\t\tif(g[i][j] == 0 || i == j) continue;\n\t\t\t\t\tfor (int k = 0; k < n; ++k) {\n\t\t\t\t\t\tif((s & (1 << k)) != 0) continue;\n\t\t\t\t\t\tLL msk = s | (1 << k);\n\t\t\t\t\t\tdp[msk][j] = min(dp[msk][j], dp[s][i] + g[i][j] / v[k]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tdouble ans = 1e9;\n\t\tfor (int s = 0; s < (1 << n); ++s)\n\t\t\tans = min(ans, dp[s][b]);\n\t\tif(ans == 1e9) printf(\"Impossible\\n\");\n\t\telse printf(\"%.3lf\\n\", ans);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3440, "score_of_the_acc": -0.0053, "final_rank": 2 }, { "submission_id": "aoj_1138_8463553", "code_snippet": "#include <iostream>\nusing namespace std;\nconst int MAX_N = 8;\nconst int MAX_M = 30;\nconst double INF = 10000000.0;\nint d[MAX_M][MAX_M];\ndouble dp[1 << MAX_N][MAX_M];\nint T[MAX_M];\nint N, M, P, A, B;\nlong long showBit(int num)\n{\n long long res = 0LL;\n for (int i = 14; i >= 0; i--)\n {\n res = res * 10 + (num >> i & 1);\n }\n return 10000000000000000L + res;\n}\nvoid solve()\n{\n fill(dp[0], dp[0] + ((1 << MAX_N) * MAX_M), INF);\n dp[(1 << N) - 1][A] = 0.0;\n for (int S = (1 << N) - 2; S >= 0; S--)\n {\n for (int v = 0; v < M; v++)\n {\n for (int u = 0; u < M; u++)\n {\n for (int k = 0; k < N; k++)\n {\n if (!(S >> k & 1))\n {\n dp[S][v] = min(dp[S][v], dp[S | 1 << k][u] + (d[v][u] * 1.0) / T[k]);\n }\n }\n }\n }\n }\n}\nvoid putAns()\n{\n double ans = INF;\n for (int S = 0; S < (1 << N); S++)\n {\n ans = min(ans, dp[S][B]);\n }\n if (ans >= 1000.0)\n {\n printf(\"Impossible\\n\");\n }\n else\n {\n printf(\"%.3f\\n\", ans);\n }\n}\nvoid input()\n{\n A--, B--;\n fill(d[0], d[0] + MAX_M * MAX_M, 10000000);\n for (int i = 0; i < N; i++)\n {\n scanf(\"%d\", &T[i]);\n }\n for (int i = 0; i < M; i++)\n {\n d[i][i] = 0;\n }\n int from, to, cost;\n for (int i = 0; i < P; i++)\n {\n scanf(\"%d%d%d\", &from, &to, &cost);\n d[--from][--to] = cost;\n d[to][from] = cost;\n }\n}\nint main()\n{\n while (true)\n {\n scanf(\"%d%d%d%d%d\", &N, &M, &P, &A, &B);\n if (N == 0 && M == 0 && P == 0 && A == 0 && B == 0)\n {\n break;\n }\n input();\n solve();\n putAns();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3556, "score_of_the_acc": -0.0168, "final_rank": 4 } ]
aoj_1143_cpp
Problem C: Hexerpents of Hexwamp Hexwamp is a strange swamp, paved with regular hexagonal dimples. Hexerpents crawling in this area are serpents adapted to the environment, consisting of a chain of regular hexagonal sections. Each section fits in one dimple. Hexerpents crawl moving some of their sections from the dimples they are in to adjacent ones. To avoid breaking their bodies, sections that are adjacent to each other before the move should also be adjacent after the move. When one section moves, sections adjacent to it support the move, and thus they cannot move at that time. Any number of sections, as far as no two of them are adjacent to each other, can move at the same time. You can easily find that a hexerpent can move its sections at its either end to only up to two dimples, and can move intermediate sections to only one dimple, if any. For example, without any obstacles, a hexerpent can crawl forward twisting its body as shown in Figure C-1, left to right. In this figure, the serpent moves four of its eight sections at a time, and moves its body forward by one dimple unit after four steps of moves. Actually, they are much better in crawling sideways, like sidewinders. Figure C-1: Crawling forward Their skin is so sticky that if two sections of a serpent that are not originally adjacent come to adjacent dimples (Figure C-2), they will stick together and the serpent cannot but die. Two sections cannot fit in one dimple, of course. This restricts serpents' moves further. Sometimes, they have to make some efforts to get a food piece even when it is in the dimple next to their head. Figure C-2: Fatal case Hexwamp has rocks here and there. Each rock fits in a dimple. Hexerpents' skin does not stick to rocks, but they cannot crawl over the rocks. Although avoiding dimples with rocks restricts their moves, they know the geography so well that they can plan the fastest paths. You are appointed to take the responsibility of the head of the scientist team to carry out academic research on this swamp and the serpents. You are expected to accomplish the research, but never at the sacrifice of any casualty. Your task now is to estimate how soon a man-eating hexerpent may move its head (the first section) to the position of a scientist in the swamp. Their body sections except for the head are quite harmless and the scientist wearing high-tech anti-sticking suit can stay in the same dimple with a body section of the hexerpent. Input The input is a sequence of several datasets, and the end of the input is indicated by a line containing a single zero. The number of datasets never exceeds 10. Each dataset looks like the following. the number of sections the serpent has (= n ) x 1 y 1 x 2 y 2 ... x n y n the number of rocks the swamp has (=k) u 1 v 1 u 2 v 2 ... u k v k X Y The first line of the dataset has an integer n that indicates the number of sections the hexerpent has, which is 2 or greater and never exceeds 8. Each of the n followi ...(truncated)
[ { "submission_id": "aoj_1143_10476119", "code_snippet": "// AOJ #1143 Hexerpents of Hexwamp\n// 2025.5.12\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing pii = pair<int,int>;\n\n#define gc() getchar_unlocked()\n#define pc(c) putchar_unlocked(c)\n\nint Cin() {\n\tint n = 0; int c = gc();\n\tif (c == '-') {\tc = gc();\n\t\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\t\treturn -n;\n\t}\n\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\treturn n;\n}\n\nvoid Cout(int n) {\n\tchar b[30];\n\tif (!n) pc('0');\n\telse {\n\t\tif (n < 0) pc('-'), n = -n;\n\t\tint i = 0; while (n) b[i++] = n % 10 + '0', n /= 10;\n\t\twhile (i--) pc(b[i]);\n\t}\n\tpc('\\n');\n}\n\nconst pii d[7] = {\n {0,-1},{1,-1},{1,0},{0,1},{-1,1},{-1,0},{0,0}\n};\n\nvector<vector<pii>> Body[9];\nvector<vector<pii>> g[9];\n\ninline int hexDist(const pii &a, const pii &b){\n int dx = a.first - b.first;\n int dy = a.second - b.second;\n if((dx<0) ^ (dy<0)) return max(abs(dx),abs(dy));\n return abs(dx)+abs(dy);\n}\n\nvoid enumBody(vector<pii> &p){\n int k = p.size();\n Body[k].push_back(p);\n if(k==8) return;\n pii b = p.back();\n p.emplace_back();\n for(int i=0;i<6;i++){\n p.back() = {b.first + d[i].first, b.second + d[i].second};\n bool ok = true;\n for(int j=k-2;j>=0 && ok;j--) if(hexDist(p[j], p.back())<=1) ok = false;\n if(ok) enumBody(p);\n }\n p.pop_back();\n}\n\nvoid makeGraph(){\n for(int k=1;k<=8;k++){\n int N = Body[k].size();\n g[k].assign(N, {});\n for(int i=0;i<N;i++){\n for(int j=0;j<i;j++){\n for(int l=0;l<7;l++){\n bool ok = true, prev = (l!=6);\n for(int q=1;q<k && ok;q++){\n pii pj = Body[k][j][q];\n pii pi = Body[k][i][q];\n pii moved = {pi.first - d[l].first, pi.second - d[l].second};\n int dist = hexDist(pj, moved);\n if(dist>1 || (dist==1 && prev)) ok = false;\n prev = (dist == 1);\n }\n if(ok){\n g[k][i].emplace_back(j, l);\n int rl = (l==6 ? 6 : (l+3)%6);\n g[k][j].emplace_back(i, rl);\n }\n }\n }\n }\n }\n}\n\nstruct St{ int x,y,id,c; };\n\nint main(){\n vector<pii> tmp(1,{0,0});\n enumBody(tmp);\n makeGraph();\n\n while(true){\n int n = Cin();\n if (n==0) break;\n\n vector<pii> B(n);\n for(int i=0;i<n;i++) {\n int x = Cin(), y = Cin();\n B[i] = {x, y};\n }\n\n const int OFF = 30, LIM = 60;\n static bool rock[LIM][LIM];\n static bool vis[LIM][LIM][4200];\n memset(rock,0,sizeof(rock));\n memset(vis,0,sizeof(vis));\n\n int m = Cin();\n\n pii head0 = B[0];\n for(int i=0;i<m;i++){\n pii t;\n t.first = Cin(), t.second = Cin();\n int xx = t.first - head0.first + OFF;\n int yy = t.second - head0.second + OFF;\n if(xx>=0&&xx<LIM&&yy>=0&&yy<LIM) rock[xx][yy]=1;\n }\n\n pii G;\n G.first = Cin(), G.second = Cin();\n G.first = G.first - head0.first + OFF;\n G.second= G.second - head0.second+ OFF;\n\n for(int i=0;i<n;i++){\n B[i].first -= head0.first;\n B[i].second -= head0.second;\n }\n int sid = find(Body[n].begin(), Body[n].end(), B) - Body[n].begin();\n\n queue<St> q;\n q.push({OFF,OFF,sid,0});\n vis[OFF][OFF][sid] = true;\n int ans = 20;\n\n while(!q.empty()){\n auto s = q.front(); q.pop();\n if(s.x==G.first && s.y==G.second){\n ans = s.c;\n break;\n }\n for(auto &e : g[n][s.id]){\n int nid = e.first, dir = e.second;\n int nx = s.x + d[dir].first;\n int ny = s.y + d[dir].second;\n int nc = s.c + 1;\n\n if(nc + hexDist({nx,ny}, G) >= 20) continue;\n if(nx<0||nx>=LIM||ny<0||ny>=LIM) continue;\n if(vis[nx][ny][nid]) continue;\n\n bool ok = true;\n for(auto &seg : Body[n][nid]){\n int xx = nx + seg.first;\n int yy = ny + seg.second;\n if(xx<0||xx>=LIM||yy<0||yy>=LIM||rock[xx][yy]){\n ok = false;\n break;\n }\n }\n if(!ok) continue;\n vis[nx][ny][nid] = true;\n q.push({nx,ny,nid,nc});\n }\n }\n Cout(ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 20324, "score_of_the_acc": -0.1764, "final_rank": 2 }, { "submission_id": "aoj_1143_9854253", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n/**\n * @brief template\n */\n\nint dx[6] = {1,0,-1,-1,0,1}, dy[6] = {0,1,1,0,-1,-1};\nmap<pair<int,int>,int> moving;\nvector<map<int,vector<pair<int,int>>>> mp(9);\nvector<map<vector<int>,bool>> mpValid(9);\nvector<vector<vector<int>>> masks(9);\n\nint encode(int N, vector<int> V) {\n int Ret = 0;\n rep(i,0,N-1) {\n Ret *= 6;\n Ret += V[i];\n }\n return Ret;\n}\n\nvector<int> decode(int N, int E) {\n vector<int> Ret;\n rep(i,0,N-1) {\n Ret.push_back(E % 6);\n E /= 6;\n }\n reverse(ALL(Ret));\n return Ret;\n}\n\nbool isValid(int N, vector<int> V) {\n if (mpValid[N].count(V)) return mpValid[N][V];\n vector<pair<int,int>> P(N);\n P[0] = {0,0};\n rep(i,0,N-1) P[i+1] = {P[i].first + dx[V[i]], P[i].second + dy[V[i]]};\n rep(i,0,N) {\n rep(j,i+2,N) {\n if (P[i] == P[j]) return mpValid[N][V] = false;\n if (moving.count({P[j].first-P[i].first, P[j].second-P[i].second})) return mpValid[N][V] = false;\n }\n }\n return mpValid[N][V] = true;\n}\n\nvoid make_move(int N, int E) {\n if (mp[N].count(E)) return;\n auto V = decode(N,E);\n for (vector<int> mask : masks[N]) {\n int headmove = -1;\n auto NV = V;\n if (mask[0] == 0) headmove = (V[0]+5) % 6, NV[0] += 1, NV[0] %= 6;\n if (mask[0] == 2) headmove = (V[0]+1) % 6, NV[0] += 5, NV[0] %= 6;\n rep(i,1,N-1) {\n NV[i-1] += (5+mask[i]);\n NV[i-1] %= 6;\n NV[i] += (7-mask[i]);\n NV[i] %= 6;\n }\n NV[N-2] += (5+mask[N-1]);\n NV[N-2] %= 6;\n if (!isValid(N,NV)) continue;\n mp[N][E].push_back({headmove, encode(N,NV)});\n }\n}\n\nint main() {\n rep(i,0,6) moving[{dx[i],dy[i]}] = i;\n rep(i,2,9) {\n rep(j,0,pow(3,i)) {\n vector<int> B(i, 0);\n int J = j;\n rep(k,0,i) B[k] = J % 3, J /= 3;\n bool flag = true;\n rep(k,0,i-1) if (B[k] != 1 && B[k+1] != 1) flag = false;\n if (flag) masks[i].push_back(B);\n }\n }\nwhile(1) {\n int N;\n cin >> N;\n if (N == 0) return 0;\n vector<int> X(N), Y(N);\n rep(i,0,N) cin >> X[i] >> Y[i];\n int SX = X[0], SY = Y[0];\n vector<int> SV(N-1);\n rep(i,0,N-1) SV[i] = moving[{X[i+1]-X[i], Y[i+1]-Y[i]}];\n int SE = encode(N,SV);\n int M;\n cin >> M;\n set<pair<int,int>> cantmove;\n rep(i,0,M) {\n int BX, BY;\n cin >> BX >> BY;\n cantmove.insert({BX,BY});\n }\n int GX, GY;\n cin >> GX >> GY;\n auto canMove = [&](int CX, int CY, int E) -> bool {\n auto V = decode(N,E);\n if (!isValid(N,V)) return false;\n if (cantmove.count({CX,CY})) return false;\n rep(i,0,N-1) {\n CX += dx[V[i]], CY += dy[V[i]];\n if (cantmove.count({CX,CY})) return false;\n }\n return true;\n };\n map<tuple<int,int,int>,int> memo;\n int ANS = 20;\n auto DFS = [&](auto self, int CX, int CY, int E, int cnt) -> void {\n if (memo.count({CX,CY,E}) && memo[{CX,CY,E}] <= cnt) return;\n memo[{CX,CY,E}] = cnt;\n if (cnt + (abs(CX-GX)+abs(CY-GY)) / 2 >= ANS) return;\n if (CX == GX && CY == GY) {\n chmin(ANS, cnt);\n return;\n }\n make_move(N,E);\n for (auto Next : mp[N][E]) {\n int NX = CX, NY = CY;\n if (Next.first >= 0) NX += dx[Next.first], NY += dy[Next.first];\n int NE = Next.second;\n if (!canMove(NX,NY,NE)) continue;\n self(self,NX,NY,NE,cnt+1);\n }\n return;\n };\n DFS(DFS,SX,SY,SE,0);\n cout << ANS << endl;\n}\n}", "accuracy": 1, "time_ms": 10850, "memory_kb": 35792, "score_of_the_acc": -1.1913, "final_rank": 15 }, { "submission_id": "aoj_1143_9680053", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> pi;\ntypedef vector<ll> vi;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\nint main(){\n while(1){\n ll N;cin>>N;\n if(!N)return 0;\n vector<pi>snake(N);\n REP(i,N)cin>>snake[i].first>>snake[i].second;\n ll K;cin>>K;\n vector<pi>swamp(K);\n REP(i,K)cin>>swamp[i].first>>swamp[i].second;\n sort(ALL(swamp));\n ll X,Y;cin>>X>>Y;\n ll ans=20;\n map<vector<pi>,ll>D;\n D[snake]=0;\n queue<vector<pi>>Q;\n Q.emplace(snake);\n vector<pi>move={\n pi(-1,0),pi(-1,1),pi(0,1),pi(0,-1),pi(1,0),pi(1,-1)\n };\n auto valid=[&](vector<pi>&nec){\n REP(i,N-1){\n ll x=nec[i].first-nec[i+1].first;\n ll y=nec[i].second-nec[i+1].second;\n if(max(abs(x),abs(y))>1||x==y)return 0;\n }\n REP(i,N)REP(j,i-1){\n ll x=nec[i].first-nec[j].first;\n ll y=nec[i].second-nec[j].second;\n if(max(abs(x),abs(y))<=1&&x!=y)return 0;\n if(x==0&&y==0)return 0;\n }\n for(auto s:nec)if(binary_search(ALL(swamp),s))return 0;\n return 1;\n };\n auto adj=[](pi a,pi b){\n ll x=a.first-b.first,y=a.second-b.second;\n return abs(x)<2&&abs(y)<2&&x!=y;\n };\n while(!Q.empty()){\n snake=Q.front();Q.pop();\n if(D[snake]>=ans)continue;\n if(snake[0]==pi(X,Y)){\n ans=D[snake];\n continue;\n }\n vector<vector<vector<pi>>>X(N+2);\n X[0]=X[1]={snake};\n REP(i,N){\n vector<vector<pi>>K;\n REP(j,i+1)for(auto s:X[j]){\n for(auto[dx,dy]:move){\n s[i].first+=dx;\n s[i].second+=dy;\n bool ok=1;\n if(i&&!adj(s[i],s[i-1]))ok=0;\n if(i<N-1&&!adj(s[i],s[i+1]))ok=0;\n if(ok)K.emplace_back(s);\n s[i].first-=dx;\n s[i].second-=dy;\n }\n }\n sort(ALL(K));\n K.erase(unique(ALL(K)),K.end());\n X[i+2]=K;\n }\n for(auto xx:X)for(auto nec:xx)if(valid(nec)){\n if(D.find(nec)==D.end()){\n D[nec]=D[snake]+1;\n Q.emplace(nec);\n }\n }\n }\n cout<<ans<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10550, "memory_kb": 64236, "score_of_the_acc": -1.5784, "final_rank": 20 }, { "submission_id": "aoj_1143_9407073", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\ntemplate < class T > vector< T >& operator++(vector< T >& a) { for(T& x : a) x++; return a; }\ntemplate < class T > vector< T >& operator--(vector< T >& a) { for(T& x : a) x--; return a; }\ntemplate < class T > vector< T > operator++(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x++; return res; }\ntemplate < class T > vector< T > operator--(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x--; return res; }\n\n} // namespace macro\n\nusing namespace macro;\n#line 3 \"A.cpp\"\n\nint dx[] = {-1, -1, 0, 0, +1, +1};\nint dy[] = { 0, +1, -1, +1, -1, 0};\n\nint solve(int n) {\n using P = pair<int,int>;\n using D = vector< P >;\n D s(n);\n for(auto &[x, y] : s) x = in(), y = in();\n set< P > b; {\n int k = in();\n for(int _ : rep(k)) {\n int u = in(), v = in();\n b.insert({u, v});\n }\n }\n P T; T.first = in(), T.second = in();\n\n auto near = [&](const P& a, const P& b) {\n int dx = a.first - b.first, dy = a.second - b.second;\n if(dx == -1) return dy == 0 or dy == +1;\n if(dx == 0) return dy == -1 or dy == 0 or dy == +1;\n if(dx == +1) return dy == -1 or dy == 0;\n return false;\n };\n\n map< D, int > dist;\n queue< pair<int, D> > q;\n q.push({dist[s] = 0, s});\n\n while(not q.empty()) {\n auto [d, v] = q.front(); q.pop();\n\n D nv;\n auto dfs = [&](auto self, int i) -> bool {\n if(i == n) {\n bool ok = [&] {\n for(int a : rep(n)) for(int b : rep(a + 2, n)) {\n if(near(nv[a], nv[b])) return false;\n }\n return true;\n }();\n if(ok) {\n if(nv[0] == T) return true;\n if(not dist.count(nv)) q.push({dist[nv] = d + 1, nv});\n }\n return false;\n }\n\n nv.push_back(v[i]);\n if(self(self, i + 1)) return true;\n nv.pop_back();\n\n for(int dir : rep(6)) {\n P p = {v[i].first + dx[dir], v[i].second + dy[dir]};\n if(0 <= i - 1 and not near(v[i - 1], p)) continue;\n if(i + 1 < n and not near(v[i + 1], p)) continue;\n if(b.count(p)) continue;\n\n if(i + 1 < n) {\n nv.push_back(p);\n nv.push_back(v[i + 1]);\n if(self(self, i + 2)) return true;\n nv.pop_back();\n nv.pop_back();\n } else {\n nv.push_back(p);\n if(self(self, i + 1)) return true;\n nv.pop_back();\n }\n }\n return false;\n }; if(dfs(dfs, 0)) return d + 1;\n }\n assert(0);\n}\n\nint main() {\n while(true) {\n int n = in(); if(n == 0) return 0;\n print(solve(n));\n }\n}", "accuracy": 1, "time_ms": 3270, "memory_kb": 32192, "score_of_the_acc": -0.573, "final_rank": 7 }, { "submission_id": "aoj_1143_9407054", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\ntemplate < class T > vector< T >& operator++(vector< T >& a) { for(T& x : a) x++; return a; }\ntemplate < class T > vector< T >& operator--(vector< T >& a) { for(T& x : a) x--; return a; }\ntemplate < class T > vector< T > operator++(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x++; return res; }\ntemplate < class T > vector< T > operator--(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x--; return res; }\n\n} // namespace macro\n\nusing namespace macro;\n#line 3 \"A.cpp\"\n\nint dx[] = {-1, -1, 0, 0, +1, +1};\nint dy[] = { 0, +1, -1, +1, -1, 0};\n\nint solve(int n) {\n using P = pair<int,int>;\n using D = vector< P >;\n D s(n);\n for(auto &[x, y] : s) x = in(), y = in();\n set< P > b; {\n int k = in();\n for(int _ : rep(k)) {\n int u = in(), v = in();\n b.insert({u, v});\n }\n }\n pair<int,int> T; T.first = in(), T.second = in();\n\n auto near = [&](const P& a, const P& b) {\n int dx = a.first - b.first, dy = a.second - b.second;\n if(dx == -1) return dy == 0 or dy == +1;\n if(dx == 0) return dy == -1 or dy == 0 or dy == +1;\n if(dx == +1) return dy == -1 or dy == 0;\n return false;\n };\n\n map< D, int > dist;\n queue< pair<int, D> > q;\n q.push({dist[s] = 0, s});\n\n while(not q.empty()) {\n auto [d, v] = q.front(); q.pop();\n\n vector<pair<int,int>> nv;\n auto dfs = [&](auto self, int i) -> bool {\n if(i == n) {\n bool ok = [&] {\n for(int a : rep(n)) for(int b : rep(a + 2, n)) {\n if(near(nv[a], nv[b])) return false;\n }\n return true;\n }();\n if(ok) {\n if(nv[0] == T) return true;\n if(not dist.count(nv)) q.push({dist[nv] = d + 1, nv});\n }\n return false;\n }\n\n nv.push_back(v[i]);\n if(self(self, i + 1)) return true;\n nv.pop_back();\n\n for(int dir : rep(6)) {\n P p = {v[i].first + dx[dir], v[i].second + dy[dir]};\n if(0 <= i - 1 and not near(v[i - 1], p)) continue;\n if(i + 1 < n and not near(v[i + 1], p)) continue;\n if(b.count(p)) continue;\n\n if(i + 1 < n) {\n nv.push_back(p);\n nv.push_back(v[i + 1]);\n if(self(self, i + 2)) return true;\n nv.pop_back();\n nv.pop_back();\n } else {\n nv.push_back(p);\n if(self(self, i + 1)) return true;\n nv.pop_back();\n }\n }\n return false;\n }; if(dfs(dfs, 0)) return d + 1;\n }\n assert(0);\n}\n\nint main() {\n while(true) {\n int n = in(); if(n == 0) return 0;\n print(solve(n));\n }\n}", "accuracy": 1, "time_ms": 3290, "memory_kb": 32184, "score_of_the_acc": -0.5744, "final_rank": 8 }, { "submission_id": "aoj_1143_9307060", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (int i = 0; i < (int) (n); i++)\ntemplate<class T>\nvoid chmax(T& p, T q) { if (p < q)p = q; };\n\nvll dx={1,1,0,-1,-1,0};\nvll dy={-1,0,1,1,0,-1};\nusing snake=pair<vll,vll>;\n\n//(x,y)と(p,q)は隣接しているか?\nbool is_adj(ll x,ll y,ll p,ll q){\n ll u=x-p;\n ll v=y-q;\n if(abs(u)+abs(v)==0)return 0;\n if(abs(u)+abs(v)==1)return 1;\n if(abs(u)+abs(v)==2&&u+v==0)return 1;\n return 0;\n}\n\n\n\nbool is_adj(snake &S1,snake &S2){\n return 0;\n}\n\n//(0,0)が頭の蛇がどう移動できるか? 長さ毎に管理\nvector<map<snake,vector<snake>>> canmove(9);\n\n//くねり方. \n//端:0,1,2 その他:0,1 \nvector<vector<vector<ll>>> kuneri(9);\n\n\n//蛇がvalidか?\nbool is_valid(vll &X,vll &Y){\n ll N=X.size();\n set<pair<ll,ll>> S;\n rep(i,N){\n if(S.count({X[i],Y[i]}))return 0;\n S.insert({X[i],Y[i]});\n }\n rep(i,N-1){\n if(!is_adj(X[i],Y[i],X[i+1],Y[i+1]))return 0;\n if(i==N-2)return 1;\n if(is_adj(X[i],Y[i],X[i+2],Y[i+2]))return 0;\n }\n return 1;\n}\n\n//岩に載るか\nbool over_rock(snake &S,set<pair<ll,ll>>&ROCK){\n ll N=S.first.size();\n rep(i,N)if(ROCK.count({S.first[i],S.second[i]}))return 1;\n return 0;\n}\n\n//頭が(0,0)なvalidな蛇全列挙\nvoid making_snake(vll &X,vll &Y){\n if(X.size()>=2&&X.size()<=8){\n canmove[X.size()][snake({X,Y})]={};\n }\n if(X.size()==8)return;\n rep(d,6){\n X.push_back(X.back()+dx[d]);\n Y.push_back(Y.back()+dy[d]);\n if(is_valid(X,Y)){\n making_snake(X,Y);\n }\n X.pop_back();\n Y.pop_back();\n }\n}\n\n//くねり方全列挙\nvoid making_kuneri(vll &K){\n if(K.size()==0){\n rep(i,3){\n K.push_back(i);\n making_kuneri(K);\n K.pop_back();\n }\n }\n else{\n rep(i,3){\n K.push_back(i);\n kuneri[K.size()].push_back(K);\n K.pop_back();\n if(K.back()!=0)break;\n }\n if(K.size()==7)return;\n rep(i,2){\n K.push_back(i);\n making_kuneri(K);\n K.pop_back();\n if(K.back()!=0)return;\n }\n }\n}\n\n//蛇Sのn節目をf移動.(f:1,2)\npair<ll,ll> trans(snake S,ll n,ll f){\n ll sz=S.first.size();\n if(n==0){\n if(f==1){\n ll x=S.first[0];\n ll y=S.second[0];\n rep(d,6){\n ll nx=x+dx[d];\n ll ny=y+dy[d];\n if(is_adj(nx,ny,S.first[1],S.second[1])){\n return {nx,ny};\n }\n }\n }\n if(f==2){\n ll x=S.first[0];\n ll y=S.second[0];\n for(ll d=5;d>=0;d--){\n ll nx=x+dx[d];\n ll ny=y+dy[d];\n if(is_adj(nx,ny,S.first[1],S.second[1])){\n return {nx,ny};\n }\n }\n }\n }\n else if(n+1==sz){\n if(f==1){\n ll x=S.first.back();\n ll y=S.second.back();\n rep(d,6){\n ll nx=x+dx[d];\n ll ny=y+dy[d];\n if(is_adj(nx,ny,S.first[sz-2],S.second[sz-2])){\n return {nx,ny};\n }\n }\n }\n if(f==2){\n ll x=S.first[sz-1];\n ll y=S.second[sz-1];\n for(ll d=5;d>=0;d--){\n ll nx=x+dx[d];\n ll ny=y+dy[d];\n if(is_adj(nx,ny,S.first[sz-2],S.second[sz-2])){\n return {nx,ny};\n }\n }\n }\n }\n else{\n ll x=S.first[n];\n ll y=S.second[n];\n rep(d,6){\n ll nx=x+dx[d];\n ll ny=y+dy[d];\n if(is_adj(nx,ny,S.first[n-1],S.second[n-1])&&is_adj(nx,ny,S.first[n+1],S.second[n+1])){\n return {nx,ny};\n }\n }\n }\n return {-1,-1};\n}\n\nll ress=0;\n\n//くねる.\nvoid kuneru(){\n rep(sz,9){\n if(sz<2)continue;\n\n for(auto S:canmove[sz]){\n for(auto K:kuneri[sz]){\n vll NX(sz),NY(sz);\n rep(j,sz){\n if(K[j]==0){\n NX[j]=S.first.first[j];\n NY[j]=S.first.second[j];\n }\n else{\n auto XY=trans(S.first,j,K[j]);\n NX[j]=XY.first;\n NY[j]=XY.second;\n }\n }\n snake NS={NX,NY};\n if(is_valid(NX,NY)){\n canmove[sz][S.first].push_back(NS);\n }\n }\n }\n }\n}\n\n/*\n前計算を行う\n- (0,0)頭の蛇全列挙\n- (0,0)頭の蛇の一手での移動先全列挙(124974ペアある. 長さを8に固定すれば91798通り. 1状態からの最大値は72通り)\n*/\nvoid init(){\n vll X={0},Y={0};\n vll K={};\n making_snake(X,Y);\n making_kuneri(K);\n kuneru();\n}\n\nvoid print(snake S){\n ll N=S.first.size();\n rep(i,N)cout<<\"(\"<<S.first[i]<<\",\"<<S.second[i]<<\")\";\n cout<<endl;\n}\n\nvoid solve(ll N) {\n vll X(N),Y(N);\n rep(i,N)cin>>X[i]>>Y[i];\n ll M;\n cin>>M;\n set<pair<ll,ll>> ROCK;\n rep(i,M){\n ll x,y;\n cin>>x>>y;\n ROCK.insert({x,y});\n }\n\n ll GX,GY;\n cin>>GX>>GY;\n map<snake,ll> dist;\n dist[{X,Y}]=0;\n queue<snake> Q;\n Q.push({X,Y});\n\n while(!Q.empty()){\n snake S=Q.front();\n Q.pop();\n snake MS=S;\n rep(i,N){\n MS.first[i]-=S.first[0];\n MS.second[i]-=S.second[0];\n }\n for(snake NS:canmove[N][MS]){\n rep(i,N){\n NS.first[i]+=S.first[0];\n NS.second[i]+=S.second[0];\n }\n if(abs(NS.second[0]-GY)>10||abs(NS.first[0]-GX)>20)continue;\n if(over_rock(NS,ROCK))continue;\n if(!dist.count(NS)){\n if(NS.first[0]==GX&&NS.second[0]==GY){\n cout<<dist[S]+1<<endl;\n return;\n }\n dist[NS]=dist[S]+1;\n Q.push(NS);\n }\n }\n }\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n init();\n\n \n ll N;\n while (cin >> N) {\n if (N == 0)return 0;\n solve(N);\n }\n\n}", "accuracy": 1, "time_ms": 2970, "memory_kb": 77528, "score_of_the_acc": -1.2033, "final_rank": 17 }, { "submission_id": "aoj_1143_9307057", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (int i = 0; i < (int) (n); i++)\ntemplate<class T>\nvoid chmax(T& p, T q) { if (p < q)p = q; };\n\nvll dx={1,1,0,-1,-1,0};\nvll dy={-1,0,1,1,0,-1};\nusing snake=pair<vll,vll>;\n\n//(x,y)と(p,q)は隣接しているか?\nbool is_adj(ll x,ll y,ll p,ll q){\n ll u=x-p;\n ll v=y-q;\n if(abs(u)+abs(v)==0)return 0;\n if(abs(u)+abs(v)==1)return 1;\n if(abs(u)+abs(v)==2&&u+v==0)return 1;\n return 0;\n}\n\n\n\nbool is_adj(snake &S1,snake &S2){\n return 0;\n}\n\n//(0,0)が頭の蛇がどう移動できるか? 長さ毎に管理\nvector<map<snake,vector<snake>>> canmove(9);\n\n//くねり方. \n//端:0,1,2 その他:0,1 \nvector<vector<vector<ll>>> kuneri(9);\n\n\n//蛇がvalidか?\nbool is_valid(vll &X,vll &Y){\n ll N=X.size();\n set<pair<ll,ll>> S;\n rep(i,N){\n if(S.count({X[i],Y[i]}))return 0;\n S.insert({X[i],Y[i]});\n }\n rep(i,N-1){\n if(!is_adj(X[i],Y[i],X[i+1],Y[i+1]))return 0;\n if(i==N-2)return 1;\n if(is_adj(X[i],Y[i],X[i+2],Y[i+2]))return 0;\n }\n return 1;\n}\n\n//岩に載るか\nbool over_rock(snake &S,set<pair<ll,ll>>&ROCK){\n ll N=S.first.size();\n rep(i,N)if(ROCK.count({S.first[i],S.second[i]}))return 1;\n return 0;\n}\n\n//頭が(0,0)なvalidな蛇全列挙\nvoid making_snake(vll &X,vll &Y){\n if(X.size()>=2&&X.size()<=8){\n canmove[X.size()][snake({X,Y})]={};\n }\n if(X.size()==8)return;\n rep(d,6){\n X.push_back(X.back()+dx[d]);\n Y.push_back(Y.back()+dy[d]);\n if(is_valid(X,Y)){\n making_snake(X,Y);\n }\n X.pop_back();\n Y.pop_back();\n }\n}\n\n//くねり方全列挙\nvoid making_kuneri(vll &K){\n if(K.size()==0){\n rep(i,3){\n K.push_back(i);\n making_kuneri(K);\n K.pop_back();\n }\n }\n else{\n rep(i,3){\n K.push_back(i);\n kuneri[K.size()].push_back(K);\n K.pop_back();\n if(K.back()!=0)break;\n }\n if(K.size()==7)return;\n rep(i,2){\n K.push_back(i);\n making_kuneri(K);\n K.pop_back();\n if(K.back()!=0)return;\n }\n }\n}\n\n//蛇Sのn節目をf移動.(f:1,2)\npair<ll,ll> trans(snake S,ll n,ll f){\n ll sz=S.first.size();\n if(n==0){\n if(f==1){\n ll x=S.first[0];\n ll y=S.second[0];\n rep(d,6){\n ll nx=x+dx[d];\n ll ny=y+dy[d];\n if(is_adj(nx,ny,S.first[1],S.second[1])){\n return {nx,ny};\n }\n }\n }\n if(f==2){\n ll x=S.first[0];\n ll y=S.second[0];\n for(ll d=5;d>=0;d--){\n ll nx=x+dx[d];\n ll ny=y+dy[d];\n if(is_adj(nx,ny,S.first[1],S.second[1])){\n return {nx,ny};\n }\n }\n }\n }\n else if(n+1==sz){\n if(f==1){\n ll x=S.first.back();\n ll y=S.second.back();\n rep(d,6){\n ll nx=x+dx[d];\n ll ny=y+dy[d];\n if(is_adj(nx,ny,S.first[sz-2],S.second[sz-2])){\n return {nx,ny};\n }\n }\n }\n if(f==2){\n ll x=S.first[sz-1];\n ll y=S.second[sz-1];\n for(ll d=5;d>=0;d--){\n ll nx=x+dx[d];\n ll ny=y+dy[d];\n if(is_adj(nx,ny,S.first[sz-2],S.second[sz-2])){\n return {nx,ny};\n }\n }\n }\n }\n else{\n ll x=S.first[n];\n ll y=S.second[n];\n rep(d,6){\n ll nx=x+dx[d];\n ll ny=y+dy[d];\n if(is_adj(nx,ny,S.first[n-1],S.second[n-1])&&is_adj(nx,ny,S.first[n+1],S.second[n+1])){\n return {nx,ny};\n }\n }\n }\n return {-1,-1};\n}\n\nll ress=0;\n\n//くねる.\nvoid kuneru(){\n rep(sz,9){\n if(sz<2)continue;\n\n for(auto S:canmove[sz]){\n for(auto K:kuneri[sz]){\n vll NX(sz),NY(sz);\n rep(j,sz){\n if(K[j]==0){\n NX[j]=S.first.first[j];\n NY[j]=S.first.second[j];\n }\n else{\n auto XY=trans(S.first,j,K[j]);\n NX[j]=XY.first;\n NY[j]=XY.second;\n }\n }\n snake NS={NX,NY};\n if(is_valid(NX,NY)){\n canmove[sz][S.first].push_back(NS);\n }\n }\n }\n }\n}\n\n/*\n前計算を行う\n- (0,0)頭の蛇全列挙\n- (0,0)頭の蛇の一手での移動先全列挙(124974ペアある. 長さを8に固定すれば91798通り. 1状態からの最大値は72通り)\n*/\nvoid init(){\n vll X={0},Y={0};\n vll K={};\n making_snake(X,Y);\n making_kuneri(K);\n kuneru();\n}\n\nvoid print(snake S){\n ll N=S.first.size();\n rep(i,N)cout<<\"(\"<<S.first[i]<<\",\"<<S.second[i]<<\")\";\n cout<<endl;\n}\n\nvoid solve(ll N) {\n vll X(N),Y(N);\n rep(i,N)cin>>X[i]>>Y[i];\n ll M;\n cin>>M;\n set<pair<ll,ll>> ROCK;\n rep(i,M){\n ll x,y;\n cin>>x>>y;\n ROCK.insert({x,y});\n }\n\n ll GX,GY;\n cin>>GX>>GY;\n map<snake,ll> dist;\n dist[{X,Y}]=0;\n queue<snake> Q;\n Q.push({X,Y});\n\n while(!Q.empty()){\n snake S=Q.front();\n Q.pop();\n snake MS=S;\n rep(i,N){\n MS.first[i]-=S.first[0];\n MS.second[i]-=S.second[0];\n }\n for(snake NS:canmove[N][MS]){\n rep(i,N){\n NS.first[i]+=S.first[0];\n NS.second[i]+=S.second[0];\n }\n if(abs(NS.second[0]-GY)>10||abs(NS.first[0]-GX)>20)continue;\n if(over_rock(NS,ROCK))continue;\n if(!dist.count(NS)){\n if(NS.first[0]==GX&&NS.second[0]==GY){\n cout<<dist[S]+1<<endl;\n return;\n }\n dist[NS]=dist[S]+1;\n Q.push(NS);\n }\n }\n }\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n init();\n\n \n ll N;\n while (cin >> N) {\n if (N == 0)return 0;\n solve(N);\n }\n\n}", "accuracy": 1, "time_ms": 2970, "memory_kb": 77472, "score_of_the_acc": -1.2025, "final_rank": 16 }, { "submission_id": "aoj_1143_8308792", "code_snippet": "#include <iostream>\n#include <tuple>\n#include <queue>\n#include <vector>\nusing namespace std;\n\nconst int pows[8] = { 1, 6, 18, 54, 162, 486, 1458, 4374 };\nconst int dx[7] = { 0, -1, -1, 0, 1, 1, 0 };\nconst int dy[7] = { -1, 0, 1, 1, 0, -1, 0 };\nint check_hairetsu[209][209];\nvector<tuple<int, int, int>> tmp;\n\n// ======================================================================================= Functions =======================================================================================\nvoid Prepare() {\n\tfor (int i = 0; i < 209; i++) {\n\t\tfor (int j = 0; j < 209; j++) check_hairetsu[i][j] = -1;\n\t}\n\tfor (int i = 0; i < 6; i++) check_hairetsu[100 + dx[i]][100 + dy[i]] = i;\n}\n\nint CheckOrientation(vector<pair<int, int>> vec) {\n\t// 条件を満たしているかチェック\n\tvector<int> Dir;\n\tfor (int i = 0; i < (int)vec.size() - 1; i++) {\n\t\tint diff_x = 100 + vec[i + 1].first - vec[i].first;\n\t\tint diff_y = 100 + vec[i + 1].second - vec[i].second;\n\t\tif (check_hairetsu[diff_x][diff_y] == -1) return -1;\n\t\tDir.push_back(check_hairetsu[diff_x][diff_y]);\n\t}\n\n\t// 癒着するかチェック\n\tfor (int i = 0; i < (int)vec.size(); i++) {\n\t\tfor (int j = i + 2; j < (int)vec.size(); j++) {\n\t\t\tint diff_x = 100 + vec[j].first - vec[i].first;\n\t\t\tint diff_y = 100 + vec[j].second - vec[i].second;\n\t\t\tif (diff_x == 100 && diff_y == 100) return -1;\n\t\t\tif (check_hairetsu[diff_x][diff_y] != -1) return -1;\n\t\t}\n\t}\n\n\t// 条件を満たしている場合\n\tint cur = Dir[0], mul = 6;\n\tfor (int i = 1; i < (int)Dir.size(); i++) {\n\t\tint diff = (Dir[i] - Dir[i - 1] + 6) % 6;\n\t\tif (diff == -1) cur += 0 * mul;\n\t\tif (diff == 0) cur += 1 * mul;\n\t\tif (diff == +1) cur += 2 * mul;\n\t\tmul *= 3;\n\t}\n\treturn cur;\n}\n\nvoid DFSOrientation(vector<pair<int, int>> Fst, vector<pair<int, int>> Cur, bool Prev) {\n\tif (Fst.size() == Cur.size()) {\n\t\tint ret = CheckOrientation(Cur);\n\t\tif (ret != -1) tmp.push_back(make_tuple(Cur[0].first, Cur[0].second, ret));\n\t\treturn;\n\t}\n\n\t// 全探索\n\tfor (int i = 0; i < 7; i++) {\n\t\tif (Prev == true && i < 6) continue;\n\t\tint sx = Fst[Cur.size()].first + dx[i];\n\t\tint sy = Fst[Cur.size()].second + dy[i];\n\t\tbool flag = false;\n\t\tfor (int j = 0; j < Cur.size(); j++) {\n\t\t\tif (Cur[j].first == sx && Cur[j].second == sy) flag = true;\n\t\t}\n\t\tif (flag == true) continue;\n\n\t\t// 再帰呼び出し\n\t\tvector<pair<int, int>> Nex = Cur;\n\t\tbool NexPrev = false; if (i < 6) NexPrev = true;\n\t\tNex.push_back(make_pair(sx, sy));\n\t\tDFSOrientation(Fst, Nex, NexPrev);\n\t}\n}\n\n// ======================================================================================= Main Function =======================================================================================\nint N, X[19], Y[19];\nint K, U[19], V[19];\nint SX, SY;\nint Dist[29][29][4374];\nbool Stone[29][29];\nbool Variable[29][29][4374];\nqueue<tuple<int, int, int>> Q;\nvector<tuple<int, int, int>> G[4374];\nvector<tuple<int, int, int>> InitG[9][4374];\n\nvector<pair<int, int>> GetOrientation(int n, int rx, int ry, int mask) {\n\tvector<pair<int, int>> Return;\n\tint sx = rx, sy = ry, dir = (mask % 6);\n\tReturn.push_back(make_pair(sx, sy)); sx += dx[dir]; sy += dy[dir];\n\tReturn.push_back(make_pair(sx, sy));\n\tfor (int j = 2; j < n; j++) {\n\t\tint nex = (mask / pows[j - 1]) % 3;\n\t\tdir = (dir + nex + 5) % 6;\n\t\tsx += dx[dir];\n\t\tsy += dy[dir];\n\t\tReturn.push_back(make_pair(sx, sy));\n\t}\n\treturn Return;\n}\n\nvoid Initialize() {\n\tfor (int i = 0; i < 4374; i++) G[i].clear();\n\tfor (int i = 0; i < 29; i++) {\n\t\tfor (int j = 0; j < 29; j++) Stone[i][j] = false;\n\t}\n}\n\nvoid Init_Enumerate() {\n\tfor (int n = 2; n <= 8; n++) {\n\t\tfor (int i = 0; i < pows[n - 1]; i++) {\n\t\t\tvector<pair<int, int>> vec = GetOrientation(n, 0, 0, i);\n\t\t\tint ret = CheckOrientation(vec);\n\t\t\tif (ret == -1) continue;\n\t\t\ttmp.clear();\n\t\t\tDFSOrientation(vec, vector<pair<int, int>>{}, false);\n\t\t\tfor (tuple<int, int, int> j : tmp) InitG[n][i].push_back(j);\n\t\t}\n\t}\n}\n\nint main() {\n\tPrepare();\n\tInit_Enumerate();\n\n\twhile (true) {\n\t\t// Step 1. Input\n\t\tInitialize();\n\t\tcin >> N; if (N == 0) break;\n\t\tfor (int i = 0; i < N; i++) cin >> X[i] >> Y[i];\n\t\tcin >> K;\n\t\tfor (int i = 0; i < K; i++) cin >> U[i] >> V[i];\n\t\tcin >> SX >> SY;\n\n\t\t// Step 2. Adjust\n\t\tfor (int i = 1; i < N; i++) X[i] = (X[i] - X[0] + 12);\n\t\tfor (int i = 1; i < N; i++) Y[i] = (Y[i] - Y[0] + 12);\n\t\tfor (int i = 0; i < K; i++) U[i] = (U[i] - X[0] + 12);\n\t\tfor (int i = 0; i < K; i++) V[i] = (V[i] - Y[0] + 12);\n\t\tSX = (SX - X[0] + 12);\n\t\tSY = (SY - Y[0] + 12);\n\t\tX[0] = 12;\n\t\tY[0] = 12;\n\t\tfor (int i = 0; i < K; i++) {\n\t\t\tif (U[i] < 0 || U[i] > 24) continue;\n\t\t\tif (V[i] < 0 || V[i] > 24) continue;\n\t\t\tStone[U[i]][V[i]] = true;\n\t\t}\n\t\tvector<pair<int, int>> InitState;\n\t\tfor (int i = 0; i < N; i++) InitState.push_back(make_pair(X[i], Y[i]));\n\t\tint InitID = CheckOrientation(InitState);\n\n\t\t// Step 3. BFS Init\n\t\tfor (int i = 0; i < pows[N - 1]; i++) G[i] = InitG[N][i];\n\t\tfor (int i = 0; i <= 24; i++) {\n\t\t\tfor (int j = 0; j <= 24; j++) {\n\t\t\t\tfor (int k = 0; k < pows[N - 1]; k++) Dist[i][j][k] = 10000;\n\t\t\t}\n\t\t}\n\t\tDist[12][12][InitID] = 0;\n\t\tQ.push(make_tuple(12, 12, InitID));\n\n\t\t// Step 4. BFS Init 2\n\t\tfor (int i = 0; i <= 24; i++) {\n\t\t\tfor (int j = 0; j <= 24; j++) {\n\t\t\t\tfor (int k = 0; k < pows[N - 1]; k++) {\n\t\t\t\t\tvector<pair<int, int>> cur = GetOrientation(N, i, j, k);\n\t\t\t\t\tbool flag = false;\n\t\t\t\t\tfor (pair<int, int> zahyou : cur) {\n\t\t\t\t\t\tif (zahyou.first < 0 || zahyou.first > 24 || zahyou.second < 0 || zahyou.second > 24) flag = true;\n\t\t\t\t\t\telse if (Stone[zahyou.first][zahyou.second] == true) flag = true;\n\t\t\t\t\t}\n\t\t\t\t\tif (flag == true) Variable[i][j][k] = false;\n\t\t\t\t\telse Variable[i][j][k] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\t// Step 4. BFS\n\t\twhile (!Q.empty()) {\n\t\t\tint pos1 = get<0>(Q.front());\n\t\t\tint pos2 = get<1>(Q.front());\n\t\t\tint pos3 = get<2>(Q.front()); Q.pop();\n\t\t\tfor (tuple<int, int, int> to : G[pos3]) {\n\t\t\t\tint nex1 = pos1 + get<0>(to);\n\t\t\t\tint nex2 = pos2 + get<1>(to);\n\t\t\t\tint nex3 = get<2>(to);\n\t\t\t\tif (Variable[nex1][nex2][nex3] == false) continue;\n\t\t\t\tif (Dist[nex1][nex2][nex3] > Dist[pos1][pos2][pos3] + 1) {\n\t\t\t\t\tDist[nex1][nex2][nex3] = Dist[pos1][pos2][pos3] + 1;\n\t\t\t\t\tQ.push(make_tuple(nex1, nex2, nex3));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\t// Step 5. Output\n\t\tint Answer = 10000;\n\t\tfor (int i = 0; i < pows[N - 1]; i++) Answer = min(Answer, Dist[SX][SY][i]);\n\t\tcout << Answer << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 6890, "memory_kb": 25856, "score_of_the_acc": -0.7523, "final_rank": 11 }, { "submission_id": "aoj_1143_8108509", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint dx[] = { 0, 1, 1, 0,-1,-1};\nint dy[] = {-1,-1, 0, 1, 1, 0};\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n;\n while (cin >> n, n) {\n vector<pair<int,int>> v(n);\n for (int i = 0; i < n; ++i) {\n cin >> v[i].first >> v[i].second;\n }\n int m; cin >> m;\n set<pair<int,int>> blc;\n for (int i = 0; i < m; ++i) {\n int x,y; cin >> x >> y;\n blc.insert({x, y});\n }\n int gx, gy; cin >> gx >> gy;\n using V = vector<pair<int,int>>;\n map<V, int> bfs;\n bfs[v] = 0;\n queue<V> q; q.push(v);\n while (q.size()) {\n auto p = q.front(); q.pop();\n int cost = bfs[p];\n \n vector<pair<int,int>> u;\n auto adj = [](pair<int,int> &p, pair<int,int> &q) -> bool {\n if (p == q) return true;\n if (abs(p.first-q.first) > 1 or abs(p.second-q.second) > 1) return false;\n if (p.first-q.first == p.second-q.second) return false;\n return true;\n };\n auto dfs = [&](auto dfs, int i) -> bool {\n if (i == n) {\n // チェック\n bool ok = true;\n {\n for (int j = 0; j < n; ++j) {\n for (int k = j+2; k < n; ++k) {\n if (adj(u[j], u[k])) {\n ok = false;\n }\n }\n }\n }\n if (!ok) return false;\n if (u[0].first == gx and u[0].second == gy) {\n return true;\n }\n if (bfs.find(u) == bfs.end()) {\n bfs[u] = cost + 1;\n q.push(u);\n }\n return false;\n }\n for (int j = 0; j < 6; ++j) {\n int nx = p[i].first + dx[j];\n int ny = p[i].second + dy[j];\n pair<int,int> nxt = {nx, ny};\n if (blc.find({nx,ny}) != blc.end()) continue;\n if (i and p[i-1] == nxt) continue;\n if (i and !adj(p[i-1], nxt)) continue;\n if (i+1 < p.size() and p[i+1] == nxt) continue;\n if (i+1 < p.size() and !adj(nxt, p[i+1])) continue;\n {\n u.push_back({nx, ny});\n int id = i+1;\n if (id < p.size()) {\n u.push_back(p[id]);\n id += 1;\n }\n if (dfs(dfs, id)) return true;\n if (id != i+1) u.pop_back();\n u.pop_back();\n }\n }\n // そのまま\n {\n u.push_back(p[i]);\n if (dfs(dfs, i+1)) return true;\n u.pop_back();\n }\n return false;\n };\n if (dfs(dfs, 0)) {\n cout << cost + 1 << endl;\n break;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 3390, "memory_kb": 32376, "score_of_the_acc": -0.5846, "final_rank": 9 }, { "submission_id": "aoj_1143_6757436", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,a,...) for(int i = (a)*(strlen(#__VA_ARGS__)!=0);i<(int)(strlen(#__VA_ARGS__)?__VA_ARGS__:(a));++i)\n#define per(i,a,...) for(int i = (strlen(#__VA_ARGS__)?__VA_ARGS__:(a))-1;i>=(int)(strlen(#__VA_ARGS__)?(a):0);--i)\n#define foreach(i, n) for(auto &i:(n))\n#define all(x) (x).begin(), (x).end()\n#define bit(x) (1ll << (x))\n#define lambda(RES_TYPE, ...) (function<RES_TYPE(__VA_ARGS__)>)[&](__VA_ARGS__) -> RES_TYPE\n#define method(FUNC_NAME, RES_TYPE, ...) function<RES_TYPE(__VA_ARGS__)> FUNC_NAME = lambda(RES_TYPE, __VA_ARGS__)\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\n//const ll MOD = (ll)1e9+7;\nconst ll MOD = 998244353;\nconst int INF = (ll)1e9+7;\nconst ll INFLL = (ll)1e18;\ntemplate<class t>\nusing vvector = vector<vector<t>>;\ntemplate<class t>\nusing vvvector = vector<vector<vector<t>>>;\ntemplate<class t>\nusing priority_queuer = priority_queue<t, vector<t>, greater<t>>;\ntemplate<class t, class u> bool chmax(t &a, u b){if(a<b){a=b;return true;}return false;}\ntemplate<class t, class u> bool chmin(t &a, u b){if(a>b){a=b;return true;}return false;}\n#ifdef DEBUG\n#define debug(x) cout<<\"LINE \"<<__LINE__<<\": \"<<#x<<\" = \"<<x<<endl;\n#else\n#define debug(x) (void)0\n#endif\n\nnamespace templates{\n ll modpow(ll x, ll b,ll mod=MOD){\n ll res = 1;\n while(b){\n if(b&1)res = res * x % mod;\n x = x * x % mod;\n b>>=1;\n }\n return res;\n }\n\n ll modinv(ll x){\n return modpow(x, MOD-2);\n }\n\n bool was_output = false;\n\n void print();\n template <class t> void print(const vector<t> &);\n template <class t, class u> void print(const pair<t, u> &);\n template <class t> void print(const t&);\n template <class Head, class... Tail> void print(const Head&, const Tail&...);\n\n template <class t> void println(const vector<vector<t>>&);\n template <class t> void println(const vector<t>&);\n template <class t> void println(const t&);\n template <class Head, class... Tail> void println(const Head&, const Tail&...);\n void println();\n void newline();\n\n void print(){\n return;\n }\n\n template <class t>\n void print(const vector<t>&x){\n for(const t&i:x)print(i);\n }\n template <class t, class u>\n void print(const pair<t,u>&p){\n print(p.first);\n print(p.second);\n }\n template <class t>\n void print(const t&x){\n if(was_output)cout<<\" \";\n cout<<x;\n was_output = true;\n }\n template <class Head, class... Tail>\n void print(const Head&head,const Tail&...tail){\n print(head);\n print(tail...);\n }\n\n template<class t>\n void println(const vector<vector<t>>&x){\n for(vector<t> i:x)println(i);\n }\n template<class t>\n void println(const vector<t>&x){\n for(const t&i:x)print(i);\n println();\n }\n template <class t>\n void println(const t&x){\n print(x);\n println();\n }\n void println(){\n if(was_output){\n cout << endl;\n was_output = false;\n }\n }\n template <class Head, class... Tail>\n void println(const Head&head,const Tail&...tail){\n print(head);\n println(tail...);\n }\n\n void newline(){\n was_output = true;\n println();\n }\n\n template<class t>\n istream& operator>>(istream&is, vector<t>&x){\n for(auto &i:x)is >> i;\n return is;\n }\n\n template<class t, class u>\n istream& operator>>(istream&is, pair<t, u>&x){\n is >> x.first >> x.second;\n return is;\n }\n\n template<class t>\n ostream& operator<<(ostream&os, vector<t> &v){\n os << \"{\";\n for(t &i:v){\n os << i << \", \";\n }\n os << \"}\";\n return os;\n }\n\n template<class t = long long>\n t in(){\n t res; cin >> res; return res;\n }\n\n template<class t>\n vector<t> sorted(vector<t> line,function<bool(t,t)> comp=[](t a,t b){return a<b;}){\n sort(line.begin(),line.end(),comp);\n return line;\n }\n\n template<class t>\n vector<t> reversed(vector<t> line){\n reverse(line.begin(),line.end());\n return line;\n }\n string reversed(string str){\n reverse(str.begin(),str.end());\n return str;\n }\n\n long long gcd(long long a,long long b){\n while(b){\n a %= b;\n swap(a,b);\n }\n return a;\n }\n\n long long lcm(long long a,long long b){\n return a / gcd(a,b) * b;\n }\n\n class output_initializer{\n public:\n output_initializer(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << setprecision(20);\n }\n };output_initializer OUTPUT_INITIALIZER_INSTANCE = output_initializer();\n}\n\nusing namespace templates;\n\nusing P = pii;\n\nP operator+(P a,P b){\n return P(a.first+b.first,a.second+b.second);\n}\n\narray<P,6> nexts(P pos){\n array<P,6> res;\n res[0] = pos+P(0,1);\n res[1] = pos+P(-1,1);\n res[2] = pos+P(1,0);\n res[3] = pos+P(0,-1);\n res[4] = pos+P(1,-1);\n res[5] = pos+P(-1,0);\n return res;\n}\n\nbool connected(P a,P b){\n int dx = a.first - b.first;\n int dy = a.second - b.second;\n return dx * dy < 1 and abs(dx) <= 1 and abs(dy) <= 1;\n}\n\nvvector<P> nexts(vector<P> snake){\n vvector<P> res;\n vector<P> current;\n set<P> has;\n method(rec,void,int p,bool last){\n if(p == snake.size()){\n res.emplace_back(current);\n return;\n }\n if(not last){\n foreach(next,nexts(snake[p])){\n if(has.count(next))continue;\n int cnt= 0;\n foreach(side,nexts(next)){\n if(has.count(side))++cnt;\n }\n if(cnt>1)continue;\n if(current.size() and not connected(current.back(),next))continue;\n current.emplace_back(next);\n has.emplace(next);\n rec(p+1,true);\n current.pop_back();\n has.erase(next);\n }\n }\n {\n P next = snake[p];\n do{\n if(has.count(next))break;\n int cnt= 0;\n foreach(side,nexts(next)){\n if(has.count(side))++cnt;\n }\n if(cnt>1)break;\n if(current.size() and not connected(current.back(),next))break;\n current.emplace_back(next);\n has.emplace(next);\n rec(p+1,false);\n current.pop_back();\n has.erase(next);\n }while(false);\n }\n };\n rec(0,false);\n return res;\n}\n\nclass state{\npublic:\n int cost;\n vector<P> snake;\n P goal;\n int dist(){\n return abs(snake[0].first-goal.first) + abs(snake[0].second-goal.second);\n }\n state(int cost,vector<P> snake,P goal):cost(cost),snake(snake),goal(goal){}\n};\n\nbool operator<(state a,state b){\n return a.dist()+a.cost < b.dist()+b.cost;\n}\nbool operator>(state a,state b){\n return a.dist()+a.cost > b.dist()+b.cost;\n}\n\nint func(int n){\n vector<P> snake;\n rep(_,n){\n int x = in();\n int y = in();\n snake.emplace_back(x,y);\n }\n set<P> stones;\n int q = in();\n rep(_,q){\n int x = in();\n int y = in();\n stones.emplace(x,y);\n }\n P goal;\n goal.first = in();\n goal.second = in();\n map<vector<P>,int> m;\n priority_queuer<state> pq;\n map<P,int> heads;\n method(add,void,state p){\n if(m.count(p.snake) and m[p.snake] <= p.cost+p.dist())return;\n m[p.snake] = p.cost+p.dist();\n heads[p.snake[0]] = p.cost+p.dist();\n pq.emplace(p);\n };\n method(rock,bool,vector<P> p){\n foreach(i,p){\n if(stones.count(i))return true;\n }\n return false;\n };\n add(state(0,snake,goal));\n while(not heads.count(goal)){\n auto p = pq.top();\n pq.pop();\n foreach(next,nexts(p.snake)){\n if(not rock(next)){\n add(state(p.cost+1,next,goal));\n }\n }\n }\n return heads[goal];\n}\n\nint main(){\n while(true){\n int n = in();\n if(n==0)break;\n println(func(n));\n }\n return 0;\n}", "accuracy": 1, "time_ms": 2340, "memory_kb": 8072, "score_of_the_acc": -0.1562, "final_rank": 1 }, { "submission_id": "aoj_1143_6025558", "code_snippet": "#line 1 \"/Users/nok0/Documents/Programming/nok0/cftemp.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\n#pragma region Macros\n// rep macro\n#define foa(v, a) for(auto &v : a)\n#define REPname(a, b, c, d, e, ...) e\n#define REP(...) REPname(__VA_ARGS__, REP3, REP2, REP1, REP0)(__VA_ARGS__)\n#define REP0(x) for(int i = 0; i < (x); ++i)\n#define REP1(i, x) for(int i = 0; i < (x); ++i)\n#define REP2(i, l, r) for(int i = (l); i < (r); ++i)\n#define REP3(i, l, r, c) for(int i = (l); i < (r); i += (c))\n#define REPSname(a, b, c, ...) c\n#define REPS(...) REPSname(__VA_ARGS__, REPS1, REPS0)(__VA_ARGS__)\n#define REPS0(x) for(int i = 1; i <= (x); ++i)\n#define REPS1(i, x) for(int i = 1; i <= (x); ++i)\n#define RREPname(a, b, c, d, e, ...) e\n#define RREP(...) RREPname(__VA_ARGS__, RREP3, RREP2, RREP1, RREP0)(__VA_ARGS__)\n#define RREP0(x) for(int i = (x)-1; i >= 0; --i)\n#define RREP1(i, x) for(int i = (x)-1; i >= 0; --i)\n#define RREP2(i, r, l) for(int i = (r)-1; i >= (l); --i)\n#define RREP3(i, r, l, c) for(int i = (r)-1; i >= (l); i -= (c))\n#define RREPSname(a, b, c, ...) c\n#define RREPS(...) RREPSname(__VA_ARGS__, RREPS1, RREPS0)(__VA_ARGS__)\n#define RREPS0(x) for(int i = (x); i >= 1; --i)\n#define RREPS1(i, x) for(int i = (x); i >= 1; --i)\n\n// name macro\n#define pb push_back\n#define eb emplace_back\n#define SZ(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define popcnt(x) __builtin_popcountll(x)\ntemplate <class T = int>\nusing V = std::vector<T>;\ntemplate <class T = int>\nusing VV = std::vector<std::vector<T>>;\ntemplate <class T>\nusing pqup = std::priority_queue<T, std::vector<T>, std::greater<T>>;\nusing ll = long long;\nusing ld = long double;\nusing int128 = __int128_t;\nusing pii = std::pair<int, int>;\nusing pll = std::pair<long long, long long>;\n\n// input macro\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n\tis >> p.first >> p.second;\n\treturn is;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n\tfor(T &i : v) is >> i;\n\treturn is;\n}\nstd::istream &operator>>(std::istream &is, __int128_t &a) {\n\tstd::string s;\n\tis >> s;\n\t__int128_t ret = 0;\n\tfor(int i = 0; i < s.length(); i++)\n\t\tif('0' <= s[i] and s[i] <= '9')\n\t\t\tret = 10 * ret + s[i] - '0';\n\ta = ret * (s[0] == '-' ? -1 : 1);\n\treturn is;\n}\nnamespace scanner {\nvoid scan(int &a) { std::cin >> a; }\nvoid scan(long long &a) { std::cin >> a; }\nvoid scan(std::string &a) { std::cin >> a; }\nvoid scan(char &a) { std::cin >> a; }\nvoid scan(char a[]) { std::scanf(\"%s\", a); }\nvoid scan(double &a) { std::cin >> a; }\nvoid scan(long double &a) { std::cin >> a; }\ntemplate <class T, class U>\nvoid scan(std::pair<T, U> &p) { std::cin >> p; }\ntemplate <class T>\nvoid scan(std::vector<T> &a) { std::cin >> a; }\nvoid INPUT() {}\ntemplate <class Head, class... Tail>\nvoid INPUT(Head &head, Tail &...tail) {\n\tscan(head);\n\tINPUT(tail...);\n}\n} // namespace scanner\n#define VEC(type, name, size) \\\n\tstd::vector<type> name(size); \\\n\tscanner::INPUT(name)\n#define VVEC(type, name, h, w) \\\n\tstd::vector<std::vector<type>> name(h, std::vector<type>(w)); \\\n\tscanner::INPUT(name)\n#define INT(...) \\\n\tint __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LL(...) \\\n\tlong long __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define STR(...) \\\n\tstd::string __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define CHAR(...) \\\n\tchar __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define DOUBLE(...) \\\n\tdouble __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LD(...) \\\n\tlong double __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n\n// output-macro\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n\tos << p.first << \" \" << p.second;\n\treturn os;\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &a) {\n\tfor(int i = 0; i < int(a.size()); ++i) {\n\t\tif(i) os << \" \";\n\t\tos << a[i];\n\t}\n\treturn os;\n}\nstd::ostream &operator<<(std::ostream &dest, __int128_t &value) {\n\tstd::ostream::sentry s(dest);\n\tif(s) {\n\t\t__uint128_t tmp = value < 0 ? -value : value;\n\t\tchar buffer[128];\n\t\tchar *d = std::end(buffer);\n\t\tdo {\n\t\t\t--d;\n\t\t\t*d = \"0123456789\"[tmp % 10];\n\t\t\ttmp /= 10;\n\t\t} while(tmp != 0);\n\t\tif(value < 0) {\n\t\t\t--d;\n\t\t\t*d = '-';\n\t\t}\n\t\tint len = std::end(buffer) - d;\n\t\tif(dest.rdbuf()->sputn(d, len) != len) {\n\t\t\tdest.setstate(std::ios_base::badbit);\n\t\t}\n\t}\n\treturn dest;\n}\ntemplate <class T>\nvoid print(const T a) { std::cout << a << '\\n'; }\ntemplate <class Head, class... Tail>\nvoid print(Head H, Tail... T) {\n\tstd::cout << H << ' ';\n\tprint(T...);\n}\ntemplate <class T>\nvoid printel(const T a) { std::cout << a << '\\n'; }\ntemplate <class T>\nvoid printel(const std::vector<T> &a) {\n\tfor(const auto &v : a)\n\t\tstd::cout << v << '\\n';\n}\ntemplate <class Head, class... Tail>\nvoid printel(Head H, Tail... T) {\n\tstd::cout << H << '\\n';\n\tprintel(T...);\n}\nvoid Yes(const bool b = true) { std::cout << (b ? \"Yes\\n\" : \"No\\n\"); }\nvoid No() { std::cout << \"No\\n\"; }\nvoid YES(const bool b = true) { std::cout << (b ? \"YES\\n\" : \"NO\\n\"); }\nvoid NO() { std::cout << \"NO\\n\"; }\nvoid err(const bool b = true) {\n\tif(b) {\n\t\tstd::cout << \"-1\\n\", exit(0);\n\t}\n}\n\n//debug macro\nnamespace debugger {\ntemplate <class T>\nvoid view(const std::vector<T> &a) {\n\tstd::cerr << \"{ \";\n\tfor(const auto &v : a) {\n\t\tstd::cerr << v << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\ntemplate <class T>\nvoid view(const std::vector<std::vector<T>> &a) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &v : a) {\n\t\tstd::cerr << \"\\t\";\n\t\tview(v);\n\t\tstd::cerr << \"\\n\";\n\t}\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::vector<std::pair<T, U>> &a) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &p : a) std::cerr << \"\\t(\" << p.first << \", \" << p.second << \")\\n\";\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::map<T, U> &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &p : m) std::cerr << \"\\t[\" << p.first << \"] : \" << p.second << \"\\n\";\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::pair<T, U> &p) { std::cerr << \"(\" << p.first << \", \" << p.second << \")\"; }\ntemplate <class T>\nvoid view(const std::set<T> &s) {\n\tstd::cerr << \"{ \";\n\tfor(auto &v : s) {\n\t\tview(v);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <class T>\nvoid view(const T &e) { std::cerr << e; }\n} // namespace debugger\n#ifdef LOCAL\nvoid debug_out() {}\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head H, Tail... T) {\n\tdebugger::view(H);\n\tstd::cerr << \", \";\n\tdebug_out(T...);\n}\n#define debug(...) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"] : [\"; \\\n\t\tdebug_out(__VA_ARGS__); \\\n\t\tstd::cerr << \"\\b\\b]\\n\"; \\\n\t} while(false)\n#else\n#define debug(...) (void(0))\n#endif\n\n// vector macro\ntemplate <class T>\nint lb(const std::vector<T> &a, const T x) { return std::distance((a).begin(), std::lower_bound((a).begin(), (a).end(), (x))); }\ntemplate <class T>\nint ub(const std::vector<T> &a, const T x) { return std::distance((a).begin(), std::upper_bound((a).begin(), (a).end(), (x))); }\ntemplate <class T>\nvoid UNIQUE(std::vector<T> &a) {\n\tstd::sort(a.begin(), a.end());\n\ta.erase(std::unique(a.begin(), a.end()), a.end());\n}\ntemplate <class T>\nstd::vector<T> press(std::vector<T> &a) {\n\tauto res = a;\n\tUNIQUE(res);\n\tfor(auto &v : a)\n\t\tv = lb(res, v);\n\treturn res;\n}\n#define SORTname(a, b, c, ...) c\n#define SORT(...) SORTname(__VA_ARGS__, SORT1, SORT0, ...)(__VA_ARGS__)\n#define SORT0(a) std::sort((a).begin(), (a).end())\n#define SORT1(a, c) std::sort((a).begin(), (a).end(), [](const auto x, const auto y) { return x c y; })\ntemplate <class T>\nvoid ADD(std::vector<T> &a, const T x = 1) {\n\tfor(auto &v : a) v += x;\n}\ntemplate <class T>\nvoid SUB(std::vector<T> &a, const T x = 1) {\n\tfor(auto &v : a) v -= x;\n}\nstd::vector<std::pair<char, int>> rle(const string &s) {\n\tint n = s.size();\n\tstd::vector<std::pair<char, int>> ret;\n\tfor(int l = 0; l < n;) {\n\t\tint r = l + 1;\n\t\tfor(; r < n and s[l] == s[r]; r++) {}\n\t\tret.emplace_back(s[l], r - l);\n\t\tl = r;\n\t}\n\treturn ret;\n}\ntemplate <class T>\nstd::vector<std::pair<T, int>> rle(const std::vector<T> &v) {\n\tint n = v.size();\n\tstd::vector<std::pair<T, int>> ret;\n\tfor(int l = 0; l < n;) {\n\t\tint r = l + 1;\n\t\tfor(; r < n and v[l] == v[r]; r++) {}\n\t\tret.emplace_back(v[l], r - l);\n\t\tl = r;\n\t}\n\treturn ret;\n}\nstd::vector<int> iota(int n) {\n\tstd::vector<int> p(n);\n\tstd::iota(p.begin(), p.end(), 0);\n\treturn p;\n}\ntemplate <class T>\nstruct cum_vector {\npublic:\n\tcum_vector() = default;\n\ttemplate <class U>\n\tcum_vector(const std::vector<U> &vec) : cum((int)vec.size() + 1) {\n\t\tfor(int i = 0; i < (int)vec.size(); i++)\n\t\t\tcum[i + 1] = cum[i] + vec[i];\n\t}\n\tT prod(int l, int r) {\n\t\treturn cum[r] - cum[l];\n\t}\n\nprivate:\n\tstd::vector<T> cum;\n};\n\n// math macro\ntemplate <class T, class U>\ninline bool chmin(T &a, const U &b) { return a > b ? a = b, true : false; }\ntemplate <class T, class U>\ninline bool chmax(T &a, const U &b) { return a < b ? a = b, true : false; }\ntemplate <class T>\nT divup(T x, T y) { return (x + y - 1) / y; }\ntemplate <class T>\nT POW(T a, long long n) {\n\tT ret = 1;\n\twhile(n) {\n\t\tif(n & 1) ret *= a;\n\t\ta *= a;\n\t\tn >>= 1;\n\t}\n\treturn ret;\n}\n// modpow\nlong long POW(long long a, long long n, const int mod) {\n\tlong long ret = 1;\n\ta = (a % mod + mod) % mod;\n\twhile(n) {\n\t\tif(n & 1) (ret *= a) %= mod;\n\t\t(a *= a) %= mod;\n\t\tn >>= 1;\n\t}\n\treturn ret;\n}\ntemplate <class T, class F>\nT bin_search(T ok, T ng, const F &f) {\n\twhile(abs(ok - ng) > 1) {\n\t\tT mid = (ok + ng) >> 1;\n\t\t(f(mid) ? ok : ng) = mid;\n\t}\n\treturn ok;\n}\ntemplate <class T, class F>\nT bin_search(T ok, T ng, const F &f, int loop) {\n\tfor(int i = 0; i < loop; i++) {\n\t\tT mid = (ok + ng) / 2;\n\t\t(f(mid) ? ok : ng) = mid;\n\t}\n\treturn ok;\n}\n\n// others\nstruct fast_io {\n\tfast_io() {\n\t\tios::sync_with_stdio(false);\n\t\tcin.tie(nullptr);\n\t\tcout << fixed << setprecision(15);\n\t}\n} fast_io_;\nconst int inf = 1e9;\nconst ll INF = 1e18;\n#pragma endregion\n\nvoid main_();\n\nint main() {\n\tmain_();\n\treturn 0;\n}\n#line 2 \"c.cpp\"\n\nint n, k;\nint near_x[6] = {0, 1, 1, 0, -1, -1};\nint near_y[6] = {1, 0, -1, -1, 0, 1};\nvoid main_() {\n\tauto adj = [&](int ax, int ay, int bx, int by) {\n\t\tif(ax == bx and ay == by) return true;\n\t\tREP(j, 6) {\n\t\t\tif(near_x[j] == bx - ax and near_y[j] == by - ay) return true;\n\t\t}\n\t\treturn false;\n\t};\n\tauto adj_pair = [&](pii a, pii b) -> bool {\n\t\treturn adj(a.first, a.second, b.first, b.second);\n\t};\n\n\twhile(cin >> n, n) {\n\t\tset<pii> st;\n\t\tset<V<pii>> snakes_set;\n\t\tV<pii> tmp = {pii(0, 0)};\n\n\t\t{\n\t\t\tauto valid_in = [&]() {\n\t\t\t\t//debug(tmp);\n\t\t\t\tbool ok = 1;\n\n\t\t\t\tREP(i, n) {\n\t\t\t\t\tREP(j, i + 1, n) {\n\t\t\t\t\t\tif(j - i == 1) {\n\t\t\t\t\t\t\tok &= adj_pair(tmp[i], tmp[j]);\n\t\t\t\t\t\t} else\n\t\t\t\t\t\t\tok &= !adj_pair(tmp[i], tmp[j]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(ok) snakes_set.insert(tmp);\n\t\t\t};\n\t\t\tauto dfs = [&](auto dfs, int i) -> void {\n\t\t\t\tif(SZ(tmp) == n) {\n\t\t\t\t\tvalid_in();\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t\tREP(j, 6) {\n\t\t\t\t\tauto [x, y] = tmp.back();\n\t\t\t\t\ttmp.pb({x + near_x[j], y + near_y[j]});\n\t\t\t\t\tdfs(dfs, i + 1);\n\t\t\t\t\ttmp.pop_back();\n\t\t\t\t}\n\t\t\t};\n\t\t\tdfs(dfs, 0);\n\t\t}\n\n\t\tV<V<pii>> snakes;\n\t\tfoa(v, snakes_set) snakes.pb(v);\n\n\t\tint S = SZ(snakes);\n\t\tmap<V<pii>, int> snake_id;\n\t\tREP(i, S) { snake_id[snakes[i]] = i; }\n\n\t\t//id,x,y\n\t\tusing T = tuple<int, int, int>;\n\n\t\tvector<vector<T>> graph(S);\n\n\t\tREP(bit, 1 << n) {\n\t\t\tif(bit == 0) continue;\n\t\t\tbool ok = 1;\n\t\t\tV<> move_id;\n\t\t\tREP(i, n)\n\t\t\tif(bit >> i & 1) move_id.pb(i);\n\t\t\tREP(i, n - 1) {\n\t\t\t\tif(bit >> i & 1 and bit >> (i + 1) & 1) {\n\t\t\t\t\tok = 0;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!ok) continue;\n\t\t\tREP(k, S) {\n\t\t\t\tauto snake = snakes[k];\n\n\t\t\t\tint top_x = 0, top_y = 0;\n\n\t\t\t\tauto dfs = [&](auto dfs, int z) -> void {\n\t\t\t\t\tif(z == SZ(move_id)) {\n\t\t\t\t\t\tauto copy_snake = snake;\n\t\t\t\t\t\tauto [sub_x, sub_y] = snake[0];\n\t\t\t\t\t\tfor(auto &p : copy_snake) {\n\t\t\t\t\t\t\tp.first -= sub_x;\n\t\t\t\t\t\t\tp.second -= sub_y;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tif(snake_id.count(copy_snake)) {\n\t\t\t\t\t\t\tgraph[k].emplace_back(T(snake_id[copy_snake], top_x, top_y));\n\t\t\t\t\t\t}\n\t\t\t\t\t\treturn;\n\t\t\t\t\t}\n\t\t\t\t\tint id = move_id[z];\n\t\t\t\t\tauto [x, y] = snake[id];\n\t\t\t\t\tREP(j, 6) {\n\t\t\t\t\t\tint nx = x + near_x[j];\n\t\t\t\t\t\tint ny = y + near_y[j];\n\t\t\t\t\t\tbool ok = 1;\n\t\t\t\t\t\tif(id - 1 >= 0) {\n\t\t\t\t\t\t\tok &= adj_pair(snake[id - 1], pair{nx, ny});\n\t\t\t\t\t\t}\n\t\t\t\t\t\tif(id + 1 < n) {\n\t\t\t\t\t\t\tok &= adj_pair(snake[id + 1], pair{nx, ny});\n\t\t\t\t\t\t}\n\t\t\t\t\t\tif(ok) {\n\t\t\t\t\t\t\tif(id == 0) {\n\t\t\t\t\t\t\t\ttop_x = near_x[j];\n\t\t\t\t\t\t\t\ttop_y = near_y[j];\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tsnake[id] = {nx, ny};\n\t\t\t\t\t\t\tdfs(dfs, z + 1);\n\t\t\t\t\t\t\tsnake[id] = {x, y};\n\t\t\t\t\t\t\tif(id == 0) {\n\t\t\t\t\t\t\t\ttop_x = 0;\n\t\t\t\t\t\t\t\ttop_y = 0;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t};\n\n\t\t\t\tdfs(dfs, 0);\n\t\t\t}\n\t\t}\n\n\t\tVEC(pii, xy, n);\n\t\tINT(k);\n\n\t\tauto [sx, sy] = xy[0];\n\t\tfor(auto &[x, y] : xy) x -= sx, y -= sy;\n\n\t\tset<pii> out;\n\t\tREP(i, k) {\n\t\t\tINT(x, y);\n\t\t\tout.insert({x - sx, y - sy});\n\t\t}\n\n\t\tINT(gx, gy);\n\t\tgx -= sx, gy -= sy;\n\n\t\tT s = T(snake_id[xy], 0, 0);\n\t\tmap<T, int> dist;\n\t\tdist[s] = 0;\n\t\tqueue<T> que;\n\t\tque.push(s);\n\n\t\twhile(que.size()) {\n\t\t\tauto v = que.front();\n\t\t\tque.pop();\n\t\t\tif(dist[v] > 20) break;\n\t\t\tauto [id, x, y] = v;\n\t\t\tfor(auto nxt_t : graph[id]) {\n\t\t\t\tauto [nid, dx, dy] = nxt_t;\n\t\t\t\tint nx = x + dx, ny = y + dy;\n\t\t\t\tif(dist.count(T(nid, nx, ny))) continue;\n\t\t\t\tbool ok = 1;\n\t\t\t\tREP(i, n) {\n\t\t\t\t\tif(out.count({nx + snakes[nid][i].first, ny + snakes[nid][i].second})) {\n\t\t\t\t\t\tok = 0;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tconst auto next_t = T(nid, nx, ny);\n\t\t\t\tif(ok) {\n\t\t\t\t\tdist[next_t] = dist[v] + 1;\n\t\t\t\t\tif(nx == gx and ny == gy) {\n\t\t\t\t\t\tprint(dist[next_t]);\n\t\t\t\t\t\tgoto fin;\n\t\t\t\t\t}\n\t\t\t\t\tque.push(T(nid, nx, ny));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\tfin:;\n\t}\n}", "accuracy": 1, "time_ms": 2240, "memory_kb": 17848, "score_of_the_acc": -0.2895, "final_rank": 4 }, { "submission_id": "aoj_1143_6025509", "code_snippet": "#line 1 \"/Users/nok0/Documents/Programming/nok0/cftemp.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\n#pragma region Macros\n// rep macro\n#define foa(v, a) for(auto &v : a)\n#define REPname(a, b, c, d, e, ...) e\n#define REP(...) REPname(__VA_ARGS__, REP3, REP2, REP1, REP0)(__VA_ARGS__)\n#define REP0(x) for(int i = 0; i < (x); ++i)\n#define REP1(i, x) for(int i = 0; i < (x); ++i)\n#define REP2(i, l, r) for(int i = (l); i < (r); ++i)\n#define REP3(i, l, r, c) for(int i = (l); i < (r); i += (c))\n#define REPSname(a, b, c, ...) c\n#define REPS(...) REPSname(__VA_ARGS__, REPS1, REPS0)(__VA_ARGS__)\n#define REPS0(x) for(int i = 1; i <= (x); ++i)\n#define REPS1(i, x) for(int i = 1; i <= (x); ++i)\n#define RREPname(a, b, c, d, e, ...) e\n#define RREP(...) RREPname(__VA_ARGS__, RREP3, RREP2, RREP1, RREP0)(__VA_ARGS__)\n#define RREP0(x) for(int i = (x)-1; i >= 0; --i)\n#define RREP1(i, x) for(int i = (x)-1; i >= 0; --i)\n#define RREP2(i, r, l) for(int i = (r)-1; i >= (l); --i)\n#define RREP3(i, r, l, c) for(int i = (r)-1; i >= (l); i -= (c))\n#define RREPSname(a, b, c, ...) c\n#define RREPS(...) RREPSname(__VA_ARGS__, RREPS1, RREPS0)(__VA_ARGS__)\n#define RREPS0(x) for(int i = (x); i >= 1; --i)\n#define RREPS1(i, x) for(int i = (x); i >= 1; --i)\n\n// name macro\n#define pb push_back\n#define eb emplace_back\n#define SZ(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define popcnt(x) __builtin_popcountll(x)\ntemplate <class T = int>\nusing V = std::vector<T>;\ntemplate <class T = int>\nusing VV = std::vector<std::vector<T>>;\ntemplate <class T>\nusing pqup = std::priority_queue<T, std::vector<T>, std::greater<T>>;\nusing ll = long long;\nusing ld = long double;\nusing int128 = __int128_t;\nusing pii = std::pair<int, int>;\nusing pll = std::pair<long long, long long>;\n\n// input macro\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n\tis >> p.first >> p.second;\n\treturn is;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n\tfor(T &i : v) is >> i;\n\treturn is;\n}\nstd::istream &operator>>(std::istream &is, __int128_t &a) {\n\tstd::string s;\n\tis >> s;\n\t__int128_t ret = 0;\n\tfor(int i = 0; i < s.length(); i++)\n\t\tif('0' <= s[i] and s[i] <= '9')\n\t\t\tret = 10 * ret + s[i] - '0';\n\ta = ret * (s[0] == '-' ? -1 : 1);\n\treturn is;\n}\nnamespace scanner {\nvoid scan(int &a) { std::cin >> a; }\nvoid scan(long long &a) { std::cin >> a; }\nvoid scan(std::string &a) { std::cin >> a; }\nvoid scan(char &a) { std::cin >> a; }\nvoid scan(char a[]) { std::scanf(\"%s\", a); }\nvoid scan(double &a) { std::cin >> a; }\nvoid scan(long double &a) { std::cin >> a; }\ntemplate <class T, class U>\nvoid scan(std::pair<T, U> &p) { std::cin >> p; }\ntemplate <class T>\nvoid scan(std::vector<T> &a) { std::cin >> a; }\nvoid INPUT() {}\ntemplate <class Head, class... Tail>\nvoid INPUT(Head &head, Tail &...tail) {\n\tscan(head);\n\tINPUT(tail...);\n}\n} // namespace scanner\n#define VEC(type, name, size) \\\n\tstd::vector<type> name(size); \\\n\tscanner::INPUT(name)\n#define VVEC(type, name, h, w) \\\n\tstd::vector<std::vector<type>> name(h, std::vector<type>(w)); \\\n\tscanner::INPUT(name)\n#define INT(...) \\\n\tint __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LL(...) \\\n\tlong long __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define STR(...) \\\n\tstd::string __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define CHAR(...) \\\n\tchar __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define DOUBLE(...) \\\n\tdouble __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LD(...) \\\n\tlong double __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n\n// output-macro\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n\tos << p.first << \" \" << p.second;\n\treturn os;\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &a) {\n\tfor(int i = 0; i < int(a.size()); ++i) {\n\t\tif(i) os << \" \";\n\t\tos << a[i];\n\t}\n\treturn os;\n}\nstd::ostream &operator<<(std::ostream &dest, __int128_t &value) {\n\tstd::ostream::sentry s(dest);\n\tif(s) {\n\t\t__uint128_t tmp = value < 0 ? -value : value;\n\t\tchar buffer[128];\n\t\tchar *d = std::end(buffer);\n\t\tdo {\n\t\t\t--d;\n\t\t\t*d = \"0123456789\"[tmp % 10];\n\t\t\ttmp /= 10;\n\t\t} while(tmp != 0);\n\t\tif(value < 0) {\n\t\t\t--d;\n\t\t\t*d = '-';\n\t\t}\n\t\tint len = std::end(buffer) - d;\n\t\tif(dest.rdbuf()->sputn(d, len) != len) {\n\t\t\tdest.setstate(std::ios_base::badbit);\n\t\t}\n\t}\n\treturn dest;\n}\ntemplate <class T>\nvoid print(const T a) { std::cout << a << '\\n'; }\ntemplate <class Head, class... Tail>\nvoid print(Head H, Tail... T) {\n\tstd::cout << H << ' ';\n\tprint(T...);\n}\ntemplate <class T>\nvoid printel(const T a) { std::cout << a << '\\n'; }\ntemplate <class T>\nvoid printel(const std::vector<T> &a) {\n\tfor(const auto &v : a)\n\t\tstd::cout << v << '\\n';\n}\ntemplate <class Head, class... Tail>\nvoid printel(Head H, Tail... T) {\n\tstd::cout << H << '\\n';\n\tprintel(T...);\n}\nvoid Yes(const bool b = true) { std::cout << (b ? \"Yes\\n\" : \"No\\n\"); }\nvoid No() { std::cout << \"No\\n\"; }\nvoid YES(const bool b = true) { std::cout << (b ? \"YES\\n\" : \"NO\\n\"); }\nvoid NO() { std::cout << \"NO\\n\"; }\nvoid err(const bool b = true) {\n\tif(b) {\n\t\tstd::cout << \"-1\\n\", exit(0);\n\t}\n}\n\n//debug macro\nnamespace debugger {\ntemplate <class T>\nvoid view(const std::vector<T> &a) {\n\tstd::cerr << \"{ \";\n\tfor(const auto &v : a) {\n\t\tstd::cerr << v << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\ntemplate <class T>\nvoid view(const std::vector<std::vector<T>> &a) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &v : a) {\n\t\tstd::cerr << \"\\t\";\n\t\tview(v);\n\t\tstd::cerr << \"\\n\";\n\t}\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::vector<std::pair<T, U>> &a) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &p : a) std::cerr << \"\\t(\" << p.first << \", \" << p.second << \")\\n\";\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::map<T, U> &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &p : m) std::cerr << \"\\t[\" << p.first << \"] : \" << p.second << \"\\n\";\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::pair<T, U> &p) { std::cerr << \"(\" << p.first << \", \" << p.second << \")\"; }\ntemplate <class T>\nvoid view(const std::set<T> &s) {\n\tstd::cerr << \"{ \";\n\tfor(auto &v : s) {\n\t\tview(v);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <class T>\nvoid view(const T &e) { std::cerr << e; }\n} // namespace debugger\n#ifdef LOCAL\nvoid debug_out() {}\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head H, Tail... T) {\n\tdebugger::view(H);\n\tstd::cerr << \", \";\n\tdebug_out(T...);\n}\n#define debug(...) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"] : [\"; \\\n\t\tdebug_out(__VA_ARGS__); \\\n\t\tstd::cerr << \"\\b\\b]\\n\"; \\\n\t} while(false)\n#else\n#define debug(...) (void(0))\n#endif\n\n// vector macro\ntemplate <class T>\nint lb(const std::vector<T> &a, const T x) { return std::distance((a).begin(), std::lower_bound((a).begin(), (a).end(), (x))); }\ntemplate <class T>\nint ub(const std::vector<T> &a, const T x) { return std::distance((a).begin(), std::upper_bound((a).begin(), (a).end(), (x))); }\ntemplate <class T>\nvoid UNIQUE(std::vector<T> &a) {\n\tstd::sort(a.begin(), a.end());\n\ta.erase(std::unique(a.begin(), a.end()), a.end());\n}\ntemplate <class T>\nstd::vector<T> press(std::vector<T> &a) {\n\tauto res = a;\n\tUNIQUE(res);\n\tfor(auto &v : a)\n\t\tv = lb(res, v);\n\treturn res;\n}\n#define SORTname(a, b, c, ...) c\n#define SORT(...) SORTname(__VA_ARGS__, SORT1, SORT0, ...)(__VA_ARGS__)\n#define SORT0(a) std::sort((a).begin(), (a).end())\n#define SORT1(a, c) std::sort((a).begin(), (a).end(), [](const auto x, const auto y) { return x c y; })\ntemplate <class T>\nvoid ADD(std::vector<T> &a, const T x = 1) {\n\tfor(auto &v : a) v += x;\n}\ntemplate <class T>\nvoid SUB(std::vector<T> &a, const T x = 1) {\n\tfor(auto &v : a) v -= x;\n}\nstd::vector<std::pair<char, int>> rle(const string &s) {\n\tint n = s.size();\n\tstd::vector<std::pair<char, int>> ret;\n\tfor(int l = 0; l < n;) {\n\t\tint r = l + 1;\n\t\tfor(; r < n and s[l] == s[r]; r++) {}\n\t\tret.emplace_back(s[l], r - l);\n\t\tl = r;\n\t}\n\treturn ret;\n}\ntemplate <class T>\nstd::vector<std::pair<T, int>> rle(const std::vector<T> &v) {\n\tint n = v.size();\n\tstd::vector<std::pair<T, int>> ret;\n\tfor(int l = 0; l < n;) {\n\t\tint r = l + 1;\n\t\tfor(; r < n and v[l] == v[r]; r++) {}\n\t\tret.emplace_back(v[l], r - l);\n\t\tl = r;\n\t}\n\treturn ret;\n}\nstd::vector<int> iota(int n) {\n\tstd::vector<int> p(n);\n\tstd::iota(p.begin(), p.end(), 0);\n\treturn p;\n}\ntemplate <class T>\nstruct cum_vector {\npublic:\n\tcum_vector() = default;\n\ttemplate <class U>\n\tcum_vector(const std::vector<U> &vec) : cum((int)vec.size() + 1) {\n\t\tfor(int i = 0; i < (int)vec.size(); i++)\n\t\t\tcum[i + 1] = cum[i] + vec[i];\n\t}\n\tT prod(int l, int r) {\n\t\treturn cum[r] - cum[l];\n\t}\n\nprivate:\n\tstd::vector<T> cum;\n};\n\n// math macro\ntemplate <class T, class U>\ninline bool chmin(T &a, const U &b) { return a > b ? a = b, true : false; }\ntemplate <class T, class U>\ninline bool chmax(T &a, const U &b) { return a < b ? a = b, true : false; }\ntemplate <class T>\nT divup(T x, T y) { return (x + y - 1) / y; }\ntemplate <class T>\nT POW(T a, long long n) {\n\tT ret = 1;\n\twhile(n) {\n\t\tif(n & 1) ret *= a;\n\t\ta *= a;\n\t\tn >>= 1;\n\t}\n\treturn ret;\n}\n// modpow\nlong long POW(long long a, long long n, const int mod) {\n\tlong long ret = 1;\n\ta = (a % mod + mod) % mod;\n\twhile(n) {\n\t\tif(n & 1) (ret *= a) %= mod;\n\t\t(a *= a) %= mod;\n\t\tn >>= 1;\n\t}\n\treturn ret;\n}\ntemplate <class T, class F>\nT bin_search(T ok, T ng, const F &f) {\n\twhile(abs(ok - ng) > 1) {\n\t\tT mid = (ok + ng) >> 1;\n\t\t(f(mid) ? ok : ng) = mid;\n\t}\n\treturn ok;\n}\ntemplate <class T, class F>\nT bin_search(T ok, T ng, const F &f, int loop) {\n\tfor(int i = 0; i < loop; i++) {\n\t\tT mid = (ok + ng) / 2;\n\t\t(f(mid) ? ok : ng) = mid;\n\t}\n\treturn ok;\n}\n\n// others\nstruct fast_io {\n\tfast_io() {\n\t\tios::sync_with_stdio(false);\n\t\tcin.tie(nullptr);\n\t\tcout << fixed << setprecision(15);\n\t}\n} fast_io_;\nconst int inf = 1e9;\nconst ll INF = 1e18;\n#pragma endregion\n\nvoid main_();\n\nint main() {\n\tmain_();\n\treturn 0;\n}\n#line 2 \"c.cpp\"\n\nint n, k;\nint near_x[6] = {0, 1, 1, 0, -1, -1};\nint near_y[6] = {1, 0, -1, -1, 0, 1};\nvoid main_() {\n\tauto adj = [&](int ax, int ay, int bx, int by) {\n\t\tif(ax == bx and ay == by) return true;\n\t\tREP(j, 6) {\n\t\t\tif(near_x[j] == bx - ax and near_y[j] == by - ay) return true;\n\t\t}\n\t\treturn false;\n\t};\n\tauto adj_pair = [&](pii a, pii b) -> bool {\n\t\treturn adj(a.first, a.second, b.first, b.second);\n\t};\n\n\twhile(cin >> n, n) {\n\t\tset<pii> st;\n\t\tset<V<pii>> snakes_set;\n\t\tV<pii> tmp = {pii(0, 0)};\n\n\t\t{\n\t\t\tauto valid_in = [&]() {\n\t\t\t\t//debug(tmp);\n\t\t\t\tbool ok = 1;\n\n\t\t\t\tREP(i, n) {\n\t\t\t\t\tREP(j, i + 1, n) {\n\t\t\t\t\t\tif(j - i == 1) {\n\t\t\t\t\t\t\tok &= adj_pair(tmp[i], tmp[j]);\n\t\t\t\t\t\t} else\n\t\t\t\t\t\t\tok &= !adj_pair(tmp[i], tmp[j]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(ok) snakes_set.insert(tmp);\n\t\t\t};\n\t\t\tauto dfs = [&](auto dfs, int i) -> void {\n\t\t\t\tif(SZ(tmp) == n) {\n\t\t\t\t\tvalid_in();\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t\tREP(j, 6) {\n\t\t\t\t\tauto [x, y] = tmp.back();\n\t\t\t\t\ttmp.pb({x + near_x[j], y + near_y[j]});\n\t\t\t\t\tdfs(dfs, i + 1);\n\t\t\t\t\ttmp.pop_back();\n\t\t\t\t}\n\t\t\t};\n\t\t\tdfs(dfs, 0);\n\t\t}\n\n\t\tV<V<pii>> snakes;\n\t\tfoa(v, snakes_set) snakes.pb(v);\n\n\t\tint S = SZ(snakes);\n\t\tmap<V<pii>, int> snake_id;\n\t\tREP(i, S) { snake_id[snakes[i]] = i; }\n\n\t\t//id,x,y\n\t\tusing T = tuple<int, int, int>;\n\n\t\tvector<vector<T>> graph(S);\n\n\t\tREP(bit, 1 << n) {\n\t\t\tif(bit == 0) continue;\n\t\t\tbool ok = 1;\n\t\t\tV<> move_id;\n\t\t\tREP(i, n)\n\t\t\tif(bit >> i & 1) move_id.pb(i);\n\t\t\tREP(i, n - 1) {\n\t\t\t\tif(bit >> i & 1 and bit >> (i + 1) & 1) {\n\t\t\t\t\tok = 0;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!ok) continue;\n\t\t\tREP(k, S) {\n\t\t\t\tauto snake = snakes[k];\n\n\t\t\t\tint top_x = 0, top_y = 0;\n\n\t\t\t\tauto dfs = [&](auto dfs, int z) -> void {\n\t\t\t\t\tif(z == SZ(move_id)) {\n\t\t\t\t\t\tauto copy_snake = snake;\n\t\t\t\t\t\tauto [sub_x, sub_y] = snake[0];\n\t\t\t\t\t\tfor(auto &p : copy_snake) {\n\t\t\t\t\t\t\tp.first -= sub_x;\n\t\t\t\t\t\t\tp.second -= sub_y;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tif(snake_id.count(copy_snake)) {\n\t\t\t\t\t\t\tgraph[k].emplace_back(T(snake_id[copy_snake], top_x, top_y));\n\t\t\t\t\t\t}\n\t\t\t\t\t\treturn;\n\t\t\t\t\t}\n\t\t\t\t\tint id = move_id[z];\n\t\t\t\t\tauto [x, y] = snake[id];\n\t\t\t\t\tREP(j, 6) {\n\t\t\t\t\t\tint nx = x + near_x[j];\n\t\t\t\t\t\tint ny = y + near_y[j];\n\t\t\t\t\t\tbool ok = 1;\n\t\t\t\t\t\tif(id - 1 >= 0) {\n\t\t\t\t\t\t\tok &= adj_pair(snake[id - 1], pair{nx, ny});\n\t\t\t\t\t\t}\n\t\t\t\t\t\tif(id + 1 < n) {\n\t\t\t\t\t\t\tok &= adj_pair(snake[id + 1], pair{nx, ny});\n\t\t\t\t\t\t}\n\t\t\t\t\t\tif(ok) {\n\t\t\t\t\t\t\tif(id == 0) {\n\t\t\t\t\t\t\t\ttop_x = near_x[j];\n\t\t\t\t\t\t\t\ttop_y = near_y[j];\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tsnake[id] = {nx, ny};\n\t\t\t\t\t\t\tdfs(dfs, z + 1);\n\t\t\t\t\t\t\tsnake[id] = {x, y};\n\t\t\t\t\t\t\tif(id == 0) {\n\t\t\t\t\t\t\t\ttop_x = 0;\n\t\t\t\t\t\t\t\ttop_y = 0;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t};\n\n\t\t\t\tdfs(dfs, 0);\n\t\t\t}\n\t\t}\n\n\t\tVEC(pii, xy, n);\n\t\tINT(k);\n\n\t\tauto [sx, sy] = xy[0];\n\t\tfor(auto &[x, y] : xy) x -= sx, y -= sy;\n\n\t\tset<pii> out;\n\t\tREP(i, k) {\n\t\t\tINT(x, y);\n\t\t\tout.insert({x - sx, y - sy});\n\t\t}\n\n\t\tINT(gx, gy);\n\t\tgx -= sx, gy -= sy;\n\n\t\tT s = T(snake_id[xy], 0, 0);\n\t\tmap<T, int> dist;\n\t\tdist[s] = 0;\n\t\tqueue<T> que;\n\t\tque.push(s);\n\n\t\twhile(que.size()) {\n\t\t\tauto v = que.front();\n\t\t\tque.pop();\n\t\t\tif(dist[v] > 20) break;\n\t\t\tauto [id, x, y] = v;\n\t\t\tfor(auto nxt_t : graph[id]) {\n\t\t\t\tauto [nid, dx, dy] = nxt_t;\n\t\t\t\tint nx = x + dx, ny = y + dy;\n\t\t\t\tif(dist.count(T(nid, nx, ny))) continue;\n\t\t\t\tbool ok = 1;\n\t\t\t\tREP(i, n) {\n\t\t\t\t\tif(out.count({nx + snakes[nid][i].first, ny + snakes[nid][i].second})) {\n\t\t\t\t\t\tok = 0;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tconst auto next_t = T(nid, nx, ny);\n\t\t\t\tif(ok) {\n\t\t\t\t\tdist[next_t] = dist[v] + 1;\n\t\t\t\t\tif(nx == gx and ny == gy) {\n\t\t\t\t\t\tprint(dist[next_t]);\n\t\t\t\t\t\tgoto fin;\n\t\t\t\t\t}\n\t\t\t\t\tque.push(T(nid, nx, ny));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\tfin:;\n\t}\n}", "accuracy": 1, "time_ms": 2220, "memory_kb": 17888, "score_of_the_acc": -0.2886, "final_rank": 3 }, { "submission_id": "aoj_1143_5968830", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n#define all(x) (x).begin(),(x).end()\n#define fi first\n#define se second\n#define mp make_pair\n#define si(x) int(x.size())\nconst int mod=1000000007,MAX=15,INF=1<<30;\n\nvector<int> dx={0,1,1,0,-1,-1},dy={-1,-1,0,1,1,0};\n\nvector<int> use[10];\n\nbool connect(pair<int,int> a,pair<int,int> b){\n if(a==b) return false;\n if(abs(a.fi-b.fi)>=2||abs(a.se-b.se)>=2) return false;\n for(int k=0;k<6;k++){\n if(a.fi+dx[k]==b.fi&&a.se+dy[k]==b.se) return true;\n }\n swap(a,b);\n for(int k=0;k<6;k++){\n if(a.fi+dx[k]==b.fi&&a.se+dy[k]==b.se) return true;\n }\n return false;\n}\n\nset<pair<int,int>> ng;\n\nvector<vector<pair<int,int>>> kouho;\n\nvector<pair<int,int>> state;\nvoid DFS(int u,int dir){\n if(u==si(state)){\n kouho.push_back(state);\n return;\n }\n if(dir&(1<<u)){\n for(int k=0;k<6;k++){\n state[u].fi+=dx[k];\n state[u].se+=dy[k];\n bool f=true;\n if(u>=2&&connect(state[u-2],state[u])) f=false;\n if(u>=2&&state[u-2]==state[u]) f=false;\n if(u>=1&&state[u-1]==state[u]) f=false;\n if(u>=1&&!connect(state[u-1],state[u])) f=false;\n if(f){\n if(ng.count(state[u])) f=false;\n }\n \n if(f){\n DFS(u+1,dir);\n }\n \n state[u].fi-=dx[k];\n state[u].se-=dy[k];\n }\n }else{\n if(u>=2&&connect(state[u-2],state[u])) return;\n if(u>=2&&state[u-2]==state[u]) return;\n if(u>=1&&state[u-1]==state[u]) return;\n if(u>=1&&!connect(state[u-1],state[u])) return;\n DFS(u+1,dir);\n }\n}\n\nint main(){\n \n std::ifstream in(\"text.txt\");\n std::cin.rdbuf(in.rdbuf());\n cin.tie(0);\n ios::sync_with_stdio(false);\n \n for(int n=2;n<=8;n++){\n for(int bit=1;bit<(1<<n);bit++){\n bool f=true;\n for(int i=0;i+1<n;i++){\n if((bit&(1<<i))&&(bit&(1<<(i+1)))) f=false;\n }\n if(f) use[n].push_back(bit);\n }\n }\n \n while(1){\n int N;cin>>N;\n if(N==0) break;\n ng.clear();\n vector<pair<int,int>> S(N);\n for(int i=0;i<N;i++){\n int a,b;cin>>a>>b;\n S[i]=mp(a,b);\n }\n int M;cin>>M;\n for(int i=0;i<M;i++){\n int a,b;cin>>a>>b;\n ng.insert(mp(a,b));\n }\n pair<int,int> g;cin>>g.fi>>g.se;\n \n set<vector<pair<int,int>>> now;\n now.insert(S);\n \n for(int q=0;q<=20;q++){\n bool done=false;\n for(auto a:now){\n if(a[0]==g){\n cout<<q<<endl;\n done=true;\n break;\n }\n }\n if(done) break;\n \n set<vector<pair<int,int>>> nex;\n \n for(auto a:now){\n int d=max(abs(a[0].fi-g.fi),abs(a[0].se-g.se));\n if(d>20-q) continue;\n for(int dir:use[N]){\n kouho.clear();\n state=a;\n DFS(0,dir);\n for(auto b:kouho) nex.insert(b);\n }\n }\n \n now=nex;\n }\n }\n}", "accuracy": 1, "time_ms": 12000, "memory_kb": 17904, "score_of_the_acc": -1.0197, "final_rank": 13 }, { "submission_id": "aoj_1143_5382930", "code_snippet": "#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<ciso646>\n#include<random>\n#include<map>\n#include<set>\n#include<bitset>\n#include<stack>\n#include<unordered_map>\n#include<unordered_set>\n#include<utility>\n#include<cassert>\n#include<complex>\n#include<numeric>\n#include<array>\nusing namespace std;\n\n//#define int long long\ntypedef long long ll;\n\ntypedef unsigned long long ul;\ntypedef unsigned int ui;\nconstexpr ll mod = 1000000007;\nconst ll INF = mod * mod;\ntypedef pair<int, int>P;\n#define stop char nyaa;cin>>nyaa;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define per(i,n) for(int i=n-1;i>=0;i--)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define per1(i,n) for(int i=n;i>=1;i--)\n#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)\n#define all(v) (v).begin(),(v).end()\ntypedef pair<ll, ll> LP;\ntypedef long double ld;\ntypedef pair<ld, ld> LDP;\nconst ld eps = 1e-12;\nconst ld pi = acosl(-1.0);\n\nll mod_pow(ll x, ll n, ll m = mod) {\n\tif (n < 0) {\n\t\tll res = mod_pow(x, -n, m);\n\t\treturn mod_pow(res, m - 2, m);\n\t}\n\tif (abs(x) >= m)x %= m;\n\tif (x < 0)x += m;\n\tll res = 1;\n\twhile (n) {\n\t\tif (n & 1)res = res * x % m;\n\t\tx = x * x % m; n >>= 1;\n\t}\n\treturn res;\n}\nstruct modint {\n\tll n;\n\tmodint() :n(0) { ; }\n\tmodint(ll m) :n(m) {\n\t\tif (n >= mod)n %= mod;\n\t\telse if (n < 0)n = (n % mod + mod) % mod;\n\t}\n\toperator int() { return n; }\n};\nbool operator==(modint a, modint b) { return a.n == b.n; }\nmodint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }\nmodint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }\nmodint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }\nmodint operator+(modint a, modint b) { return a += b; }\nmodint operator-(modint a, modint b) { return a -= b; }\nmodint operator*(modint a, modint b) { return a *= b; }\nmodint operator^(modint a, ll n) {\n\tif (n == 0)return modint(1);\n\tmodint res = (a * a) ^ (n / 2);\n\tif (n % 2)res = res * a;\n\treturn res;\n}\n\nll inv(ll a, ll p) {\n\treturn (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);\n}\nmodint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }\nmodint operator/=(modint& a, modint b) { a = a / b; return a; }\nconst int max_n = 1 << 16;\nmodint fact[max_n], factinv[max_n];\nvoid init_f() {\n\tfact[0] = modint(1);\n\tfor (int i = 0; i < max_n - 1; i++) {\n\t\tfact[i + 1] = fact[i] * modint(i + 1);\n\t}\n\tfactinv[max_n - 1] = modint(1) / fact[max_n - 1];\n\tfor (int i = max_n - 2; i >= 0; i--) {\n\t\tfactinv[i] = factinv[i + 1] * modint(i + 1);\n\t}\n}\nmodint comb(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[b] * factinv[a - b];\n}\nmodint combP(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[a - b];\n}\n\nint dx[6] = { 1,1,0,-1,-1,0 };\nint dy[6] = { -1,0,1,1,0,-1 };\n\nbool isadj(P a, P b) {\n\trep(d, 6) {\n\t\tint x = b.first + dx[d];\n\t\tint y = b.second + dy[d];\n\t\tif (a.first == x && a.second == y)return true;\n\t}\n\treturn false;\n}\nmap<P, bool> mp;\nbool canadd(vector<P>& v, P a) {\n\tif (mp[a])return false;\n\tif (v.empty())return true;\n\tif (!isadj(v.back(), a))return false;\n\trep(i, v.size() - 1) {\n\t\tif (isadj(v[i], a))return false;\n\t\tif (v[i] == a)return false;\n\t}\n\treturn true;\n}\nvector<vector<P>> find_nexts(vector<P> v) {\n\tvector<vector<P>> res;\n\tint n = v.size();\n\tvector<P> cur;\n\tvector<bool> ch;\n\tfunction<void(int)> dfs = [&](int id) {\n\t\tif (id == n)res.push_back(cur);\n\t\telse {\n\t\t\t//not change\n\t\t\tif (canadd(cur, v[id])) {\n\t\t\t\tcur.push_back(v[id]);\n\t\t\t\tch.push_back(0);\n\t\t\t\tdfs(id + 1);\n\t\t\t\tcur.pop_back();\n\t\t\t\tch.pop_back();\n\t\t\t}\n\t\t\t//change\n\t\t\tif (ch.empty() || ch.back() == 0) {\n\t\t\t\trep(d, 6) {\n\t\t\t\t\tP p = { v[id].first + dx[d],v[id].second + dy[d] };\n\t\t\t\t\tif (canadd(cur, p)) {\n\t\t\t\t\t\tcur.push_back(p);\n\t\t\t\t\t\tch.push_back(1);\n\t\t\t\t\t\tdfs(id + 1);\n\t\t\t\t\t\tcur.pop_back();\n\t\t\t\t\t\tch.pop_back();\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t};\n\tdfs(0);\n\t/*for (int i = 1; i < (1 << n); i++) {\n\t\tvector<int> c;\n\t\trep(j, n)if (i & (1 << j))c.push_back(j);\n\t\tbool valid = true;\n\t\trep(j, c.size() - 1)if (c[j] + 1 == c[j + 1])valid = false;\n\t\tif (!valid)continue;\n\t\tvector<P> cur;\n\t\tfunction<void(int)> dfs = [&](int id) {\n\t\t\tif (id == n) {\n\t\t\t\t//cout << \"hello\\n\";\n\t\t\t\tres.push_back(cur);\n\t\t\t\t//\n\t\t\t\treturn;\n\t\t\t}\n\t\t\tif (i & (1 << id)) {\n\t\t\t\trep(d, 6) {\n\t\t\t\t\tint x = v[id].first + dx[d];\n\t\t\t\t\tint y = v[id].second + dy[d];\n\t\t\t\t\tP p = { x,y };\n\t\t\t\t\tif (canadd(cur, p)) {\n\t\t\t\t\t\tcur.push_back(p);\n\t\t\t\t\t\tdfs(id + 1);\n\t\t\t\t\t\tcur.pop_back();\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (canadd(cur, v[id])) {\n\t\t\t\t\tcur.push_back(v[id]);\n\t\t\t\t\tdfs(id + 1);\n\t\t\t\t\tcur.pop_back();\n\t\t\t\t}\n\t\t\t}\n\t\t};\n\t\tdfs(0);\n\t}*/\n\treturn res;\n}\n\nint n;\nvoid solve() {\n\tmp.clear();\n\tvector<P> ori(n);\n\trep(i, n) {\n\t\tint x, y; cin >> x >> y;\n\t\tori[i] = { x,y };\n\t}\n\tint m; cin >> m;\n\trep(i, m) {\n\t\tint x, y; cin >> x >> y;\n\t\tmp[{x, y}] = true;\n\t}\n\tint gx, gy; cin >> gx >> gy;\n\tqueue<vector<P>>q;\n\tmap<vector<P>, bool> used;\n\tused[ori] = true; q.push(ori);\n\tint tmp = 0;\n\t//cout << \"ans is \";\n\twhile (!q.empty()) {\n\t\ttmp++;\n\t\tint len = q.size();\n\t\t//cout << len << \"\\n\";\n\t\trep(aa, len) {\n\t\t\tvector<P> v = q.front(); q.pop();\n\t\t\tvector<vector<P>> nvs = find_nexts(v);\n\t\t\tfor (auto nv : nvs) {\n\t\t\t\tif (used[nv])continue;\n\t\t\t\tint dx = abs(gx - nv[0].first);\n\t\t\t\tint dy = abs(gy - nv[0].second);\n\t\t\t\tif (min(dx, dy) > 20-tmp)continue;\n\t\t\t\tif (nv[0].first == gx && nv[0].second == gy) {\n\t\t\t\t\tcout << tmp << \"\\n\"; return;\n\t\t\t\t}\n\t\t\t\tq.push(nv);\n\t\t\t\tused[nv] = true;\n\t\t\t}\n\t\t}\n\t}\n\tassert(false);\n}\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\tcout << fixed << setprecision(10);\n\t//init_f();\n\t//init();\n\t//expr();\n\t//int t; cin >> t;rep(i,t)\n\twhile(cin>>n,n)\n\tsolve();\n\treturn 0;\n}", "accuracy": 1, "time_ms": 4500, "memory_kb": 25388, "score_of_the_acc": -0.5669, "final_rank": 6 }, { "submission_id": "aoj_1143_3707688", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> l_l;\ntypedef pair<int, int> i_i;\n\n#define EPS (1e-7)\n#define INF (1e9)\n#define PI (acos(-1))\n//const ll mod = 1000000007;\nint N;\nmap<i_i, bool> mp;\nset<i_i> exist;\nvector<vector<i_i>> serpents[25];\nint dx[6] = {0, 1, 1, 0, -1, -1};\nint dy[6] = {-1, -1, 0, 1, 1, 0};\nint X, Y;\nset<vector<i_i>> used;\n\nbool valid(vector<i_i> &now) {\n exist.clear();\n for(int i = 0; i < now.size(); i++) {\n if(mp[now[i]]) return false;\n if(exist.find(now[i]) != exist.end()) return false;\n exist.insert(now[i]);\n }\n for(int i = 2; i < now.size(); i++) {\n for(int j = 0; j < 6; j++) {\n if(now[i].first == now[i-2].first + dx[j] && now[i].second == now[i-2].second + dy[j]) return false;\n }\n }\n return true;\n}\n\nbool connected(vector<i_i> &now) {\n for(int i = 1; i < now.size(); i++) {\n bool nowok = false;\n for(int j = 0; j < 6; j++) {\n if(now[i].first == now[i-1].first + dx[j] && now[i].second == now[i-1].second + dy[j]) nowok = true;\n }\n if(!nowok) return false;\n }\n return true;\n}\n\nvoid add(int T, vector<i_i> &serpent, int index) {\n if(!connected(serpent)) return;\n if(index >= serpent.size()) {\n if(valid(serpent)) {\n if(used.find(serpent) == used.end()) {\n serpents[T].push_back(serpent);\n used.insert(serpent);\n }\n }\n return;\n }\n for(int i = 0; i < 6; i++) {\n serpent[index].first += dx[i];\n serpent[index].second += dy[i];\n add(T, serpent, index + 2);\n serpent[index].first -= dx[i];\n serpent[index].second -= dy[i];\n }\n add(T, serpent, index + 1);\n}\n\nint main() {\n //cout.precision(10);\n while(true) {\n used.clear();\n cin >> N;\n if(N == 0) break;\n mp.clear();\n vector<i_i> initial(N);\n for(int i = 0; i <= 20; i++) serpents[i].clear();\n for(int i = 0; i < N; i++) {\n cin >> initial[i].first >> initial[i].second;\n }\n serpents[0].push_back(initial);\n int k;\n cin >> k;\n while(k--) {\n int u, v;\n cin >> u >> v;\n mp[{u, v}] = true;\n }\n cin >> X >> Y;\n //cout << valid(initial) << endl;\n bool cleared = false;\n for(int T = 0; T <= 20; T++) {\n if(cleared) break;\n //cerr << \"T: \" << T << endl;\n for(int i = 0; i < serpents[T].size(); i++) {\n vector<i_i> serpent = serpents[T][i];\n if(abs(X - serpent[0].first) + abs(Y - serpent[0].second) > 2 * (20 - T)) continue;\n /*\n cerr << T << \": \";\n for(int j = 0; j < serpent.size(); j++) {\n cerr << \"{\" << serpent[j].first << \", \" << serpent[j].second << \"}, \";\n }\n cerr << endl;\n */\n if(serpent[0].first == X && serpent[0].second == Y) {\n cout << T << endl;\n cleared = true;\n break;\n }\n add(T + 1, serpent, 0);\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 13630, "memory_kb": 30532, "score_of_the_acc": -1.3234, "final_rank": 19 }, { "submission_id": "aoj_1143_3450967", "code_snippet": "// Hexerpents of Hexwamp\n#include <iostream>\n#include <vector>\n#include <set>\n#include <queue>\n#include <unordered_set>\n\nnamespace\n{\n // a little helper that should IMHO be standardized\n template<typename T>\n std::size_t make_hash(const T& v)\n {\n return std::hash<T>()(v);\n }\n\n // adapted from boost::hash_combine\n void hash_combine(std::size_t& h, const std::size_t& v)\n {\n h ^= v + 0x9e3779b9 + (h << 6) + (h >> 2);\n }\n\n // hash any container\n template<typename T>\n struct hash_container\n {\n size_t operator()(const T& v) const\n {\n size_t h=0;\n for( const auto& e : v ) {\n hash_combine(h, make_hash(e));\n }\n return h;\n }\n };\n}\n\nnamespace std\n{\n // support for pair<T,U> if T and U can be hashed\n template<typename T, typename U>\n struct hash<pair<T, U>>\n {\n size_t operator()(const pair<T,U>& v) const\n {\n size_t h=make_hash(v.first);\n hash_combine(h, make_hash(v.second));\n return h;\n }\n };\n\n // support for vector<T> if T is hashable\n // (the T... is a required trick if the vector has a non-standard allocator)\n template<typename... T>\n struct hash<vector<T...>> : hash_container<vector<T...>> {};\n}\n\nusing namespace std;\n\nusing P = pair<int, int>;\n\nvector<P> dir{P(0, -1), P(0, 1), P(-1, 0), P(-1, 1), P(1, -1), P(1, 0)};\n\nint is_valid_state(int state){\n while(state){\n if((state & 1) && (state & (1<<1))) return 0;\n state = state >> 1;\n }\n return 1;\n}\n\nint dist(P a, P b){\n return max(abs(a.first - b.first), max(abs(a.second - b.second), abs((a.second - b.second) + (a.first - b.first))));\n}\n\nint is_dead_serpent(vector<P>& serpent, unordered_set<P>& rock){\n for(int i=0;i<serpent.size();i++){\n for(int j=i+1;j<serpent.size();j++){\n P a = serpent[i];\n P b = serpent[j];\n int d = dist(a, b);\n if(d == 0) return 1;\n if(j - i != 1){\n\tif(d == 1) return 1;\n }else{\n\tif(d > 1) return 1;\n }\n }\n }\n\n for(int i=0;i<serpent.size();i++){\n if(rock.find(serpent[i]) != rock.end()) return 1;\n } \n \n return 0;\n}\n\nint main(){\n int N;\n int K;\n int X, Y;\n while(cin >> N, N){\n vector<P>serpent(N);\n for(auto &s: serpent){\n cin >> s.first >> s.second;\n }\n\n cin >> K;\n unordered_set<P>rock;\n for(int i=0;i<K;i++){\n int x, y;\n cin >> x >> y;\n rock.insert(P(x, y));\n }\n cin >> X >> Y;\n P goal = P(X, Y);\n queue<pair<vector<P>, pair<int, int> >>que;\n unordered_set<vector<P> > visited;\n que.push(make_pair(serpent, make_pair(0, 0)));\n int maxcost = 0;\n while(!que.empty()){\n vector<P> ser = que.front().first;\n int cost = que.front().second.first;\n int last_state = que.front().second.second;\n que.pop();\n //if(maxcost < cost){\n //cout << cost << \" \" << que.size() << \" \" << visited.size() << endl;\n //\tmaxcost = cost;\n //}\n \n if(ser[0] == goal){\n\tcout << cost << endl;\n\tbreak;\n }\n if(visited.find(ser) != visited.end()) continue;\n visited.insert(ser);\n if(20 - cost < dist(ser[0], goal)) continue;\n\n for(int state = 1;state < (1<<N);state++){\n\tif(last_state & state & ((1<<(N-1)) - 2)) continue;\n\t//if(!((last_state&1) | (state&1))) continue;\n\tif(!is_valid_state(state)) continue;\n\tint num_move_section = __builtin_popcount(state);\n\n\tvector<int> next[4];\n\tint j = 0;\n\tint flag = 0;\n\tfor(int i=0;i<num_move_section;i++){\n\t while(!(state & (1<<j))) j++;\n\t if(j == 0){\n\t for(int k=0;k<6;k++){\n\t if(dist(make_pair(ser[j].first + dir[k].first, ser[j].second + dir[k].second), ser[j+1]) == 1) next[i].push_back(k);\n\t }\n\t }else if(j == N-1){\n\t for(int k=0;k<6;k++){\n\t if(dist(make_pair(ser[j].first + dir[k].first, ser[j].second + dir[k].second), ser[j-1]) == 1) next[i].push_back(k);\n\t }\n\t }else{\n\t for(int k=0;k<6;k++){\n\t if(dist(make_pair(ser[j].first + dir[k].first, ser[j].second + dir[k].second), ser[j-1]) == 1 && dist(make_pair(ser[j].first + dir[k].first, ser[j].second + dir[k].second), ser[j+1]) == 1) next[i].push_back(k);\n\t }\n\t if(next[i].size() == 0) flag = 1;\n\t }\n\t j++;\n\t}\n\tif(flag) continue;\n\t\n\tvector<vector<int> >products(4, vector<int>(num_move_section, 0));\n\tif(next[0].size() == 2 && next[num_move_section-1].size() == 2){\n\t products.resize(4);\n\t products[1][0] = products[2][num_move_section-1] = products[3][0] = products[3][num_move_section-1] = 1;\n\t}else if(next[0].size() == 2){\n\t products.resize(2);\n\t products[1][0] = 1;\t \n\t}else if(next[num_move_section-1].size() == 2){\n\t products.resize(2);\n\t products[1][num_move_section-1] = 1;\n\t}else{\n\t products.resize(1);\n\t}\n\n\tfor(auto&& idxs: products){\n\t vector<P> next_ser(ser);\t \n\t int j = 0;\n\t //cout << endl;\n\t for(int i=0;i<num_move_section;i++){\n\t while(!(state & (1<<j))) j++;\n\n\t //for(auto &&x: ser){\n\t // cout << \"(\" << x.first << \", \" << x.second << \") \";\n\t //}cout << endl;\n\n\t //cout << state << \" \" << j << \" \" << next_ser[j].first << \" \" << next_ser[j].second << \" to \";\n\t next_ser[j].first += dir[next[i][idxs[i]]].first;\n\t next_ser[j].second += dir[next[i][idxs[i]]].second;\n\t //cout << next_ser[j].first << \" \" << next_ser[j].second << endl;\n\t j++;\n\t }\n\t if(is_dead_serpent(next_ser, rock)) continue;\n\t if(visited.find(next_ser) != visited.end()) continue;\n\t que.push(make_pair(next_ser, make_pair(cost + 1, state)));\n\t}\n }\n }\n //cout << que.size() << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 3520, "memory_kb": 20776, "score_of_the_acc": -0.4273, "final_rank": 5 }, { "submission_id": "aoj_1143_3148887", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 500000\n#define DIST_MAX 1000\n#define SIZE 61\n\nenum Type{\n\tNo_Move,\n\tUp,\n\tRight_Up,\n\tRight_Under,\n\tUnder,\n\tLeft_Under,\n\tLeft_Up,\n};\n\nstruct LOC{\n\tvoid set(int arg_x,int arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\tbool operator==(const struct LOC &arg){\n\t\treturn x == arg.x && y == arg.y;\n\t}\n\tbool operator !=(const struct LOC &arg){\n\t\treturn x != arg.x || y != arg.y;\n\t}\n\tint x,y;\n};\n\nstruct State{\n\tint num_parts;\n\tType type[8]; //2個目以降の節が、1つ前の節と相対的にどの位置にあるか\n};\n\nstruct Snake{\n\tint num_move,index,move_array[4];\n\tbool is_move[8];\n\tLOC tmp_loc[8];\n};\n\nstruct Data{\n\tData(int arg_x,int arg_y,short arg_sum_dist){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t\tsum_dist = arg_sum_dist;\n\t}\n\tbool operator<(const struct Data &arg) const{\n\t\treturn sum_dist > arg.sum_dist;\n\t}\n\tint x,y;\n\tshort sum_dist;\n};\n\nstruct Info{\n\tInfo(int arg_head_x,int arg_head_y,int arg_state_code,short arg_sum_dist,LOC arg_pre_loc[8]){\n\t\thead_x = arg_head_x;\n\t\thead_y = arg_head_y;\n\t\tstate_code = arg_state_code;\n\t\tsum_dist = arg_sum_dist;\n\t\tfor(int i = 0; i < 8; i++){\n\t\t\tpre_loc[i] = arg_pre_loc[i];\n\t\t}\n\t}\n\tbool operator<(const struct Info &arg) const{\n\t\treturn sum_dist > arg.sum_dist;\n\t}\n\tint head_x,head_y,state_code;\n\tshort sum_dist;\n\tLOC pre_loc[8];\n};\n\nint N;\nint diff_x[6] = {0,1,1,0,-1,-1},diff_y[6] = {-1,-1,0,1,1,0};\nshort min_dist[SIZE][SIZE],final_min_dist[SIZE][SIZE][6187];\nint state_index;\nint num_stone;\nint POW[9];\nbool is_stone[SIZE][SIZE];\nvector<int> ADJ[6187][7]; //vector<int> ADJ[節の状態][頭の移動方向] = 隣接状態リスト\nvector<int> MOVE_GROUP[9];\nmap<int,int> MAP; //MAP[形体] = stateにおけるインデックス\nLOC loc_table[8],stone[105],goal;\nState state[NUM];\nType type_array[7] = {No_Move,Up,Right_Up,Right_Under,Under,Left_Under,Left_Up},type_table[8];\n\nbool rangeCheck(int x,int y){\n\n\tif(x >= 0 && x <= SIZE-1 && y >= 0 && y <= SIZE-1){\n\t\treturn true;\n\t}else{\n\t\treturn false;\n\t}\n}\n\nbool adj_check(int num_parts,LOC tmp_loc[8]);\n\nint calc_state(int num_parts,LOC tmp_loc[8]){\n\n\tint tmp_table[8];\n\tint tmp_x,tmp_y;\n\n\tbool FLG;\n\n\tfor(int i = 0; i < num_parts-1; i++){\n\n\t\tFLG = false;\n\t\tfor(int k = 0; k < 6; k++){\n\t\t\ttmp_x = tmp_loc[i].x+diff_x[k];\n\t\t\ttmp_y = tmp_loc[i].y+diff_y[k];\n\n\t\t\tif(tmp_x == tmp_loc[i+1].x && tmp_y == tmp_loc[i+1].y){\n\t\t\t\tFLG = true;\n\t\t\t\ttmp_table[i] = k+1; //★★注意★★\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\n\tint ret = 0;\n\n\tfor(int i = 0; i < num_parts-1; i++){\n\t\tret = 10*ret+tmp_table[i];\n\t}\n\n\treturn MAP[ret];\n}\n\nvoid func(){\n\n\tLOC first_loc[8];\n\n\tfor(int i = 0; i < N; i++){\n\t\tscanf(\"%d %d\",&first_loc[i].x,&first_loc[i].y);\n\t}\n\n\tscanf(\"%d\",&num_stone);\n\n\tfor(int i = 0; i < num_stone; i++){\n\t\tscanf(\"%d %d\",&stone[i].x,&stone[i].y);\n\t}\n\n\tint tmp_x,tmp_y;\n\n\tscanf(\"%d %d\",&tmp_x,&tmp_y);\n\n\t//簡単のため、ゴールを移動する\n\tint plus_x = goal.x-tmp_x;\n\tint plus_y = goal.y-tmp_y;\n\n\t//座標を修正する\n\tfor(int i = 0; i < N; i++){\n\t\tfirst_loc[i].x += plus_x;\n\t\tfirst_loc[i].y += plus_y;\n\t}\n\n\tfor(int x = 0; x < SIZE; x++){\n\t\tfor(int y = 0; y < SIZE; y++){\n\t\t\tis_stone[x][y] = false;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_stone; i++){\n\t\tstone[i].x += plus_x;\n\t\tstone[i].y += plus_y;\n\n\t\tif(rangeCheck(stone[i].x,stone[i].y)){\n\t\t\tis_stone[stone[i].x][stone[i].y] = true;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < SIZE; i++){\n\t\tfor(int k = 0; k < SIZE; k++){\n\t\t\tfor(int a = 0; a < state_index; a++){\n\t\t\t\tfinal_min_dist[i][k][a] = DIST_MAX;\n\t\t\t}\n\t\t}\n\t}\n\n\tint first_state = calc_state(N,first_loc);\n\n\tLOC debug_loc[8];\n\tfor(int i = 0; i < N; i++){\n\t\tdebug_loc[i].set(-1,-1);\n\t}\n\n\tpriority_queue<Info> Q;\n\tfinal_min_dist[first_loc[0].x][first_loc[0].y][first_state] = 0;\n\tQ.push(Info(first_loc[0].x,first_loc[0].y,first_state,0,debug_loc));\n\n\tint next_code,next_cost;\n\tLOC work[8];\n\tbool FLG;\n\n\twhile(!Q.empty()){\n\n\t\tif(Q.top().head_x == goal.x && Q.top().head_y == goal.y){\n\n\t\t\tprintf(\"%d\\n\",Q.top().sum_dist);\n\t\t\treturn;\n\n\t\t}else if(Q.top().sum_dist > final_min_dist[Q.top().head_x][Q.top().head_y][Q.top().state_code]){\n\n\t\t\tQ.pop();\n\n\t\t}else{\n\n\t\t\tfor(int i = 0; i <= 6; i++){\n\n\t\t\t\tif(i == 0){\n\n\t\t\t\t\twork[0].x = Q.top().head_x;\n\t\t\t\t\twork[0].y = Q.top().head_y;\n\n\t\t\t\t}else{\n\n\t\t\t\t\twork[0].x = Q.top().head_x + diff_x[i-1];\n\t\t\t\t\twork[0].y = Q.top().head_y + diff_y[i-1];\n\t\t\t\t}\n\n\t\t\t\tif(rangeCheck(work[0].x,work[0].y) == false || min_dist[work[0].x][work[0].y]+Q.top().sum_dist > 20){ //枝刈り\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\n\t\t\t\tfor(int k = 0; k < ADJ[Q.top().state_code][i].size(); k++){\n\n\t\t\t\t\tnext_code = ADJ[Q.top().state_code][i][k];\n\n\t\t\t\t\t//座標に配置\n\t\t\t\t\tfor(int a = 0; a < N-1; a++){\n\t\t\t\t\t\tswitch(state[next_code].type[a]){\n\t\t\t\t\t\tcase Up:\n\t\t\t\t\t\t\ttmp_x = work[a].x;\n\t\t\t\t\t\t\ttmp_y = work[a].y-1;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\tcase Right_Up:\n\t\t\t\t\t\t\ttmp_x = work[a].x+1;\n\t\t\t\t\t\t\ttmp_y = work[a].y-1;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\tcase Right_Under:\n\t\t\t\t\t\t\ttmp_x = work[a].x+1;\n\t\t\t\t\t\t\ttmp_y = work[a].y;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\tcase Under:\n\t\t\t\t\t\t\ttmp_x = work[a].x;\n\t\t\t\t\t\t\ttmp_y = work[a].y+1;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\tcase Left_Under:\n\t\t\t\t\t\t\ttmp_x = work[a].x-1;\n\t\t\t\t\t\t\ttmp_y = work[a].y+1;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\tcase Left_Up:\n\t\t\t\t\t\t\ttmp_x = work[a].x-1;\n\t\t\t\t\t\t\ttmp_y = work[a].y;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t\twork[a+1].set(tmp_x,tmp_y);\n\t\t\t\t\t}\n\n\t\t\t\t\t//石に接触しないかチェック\n\t\t\t\t\tFLG = true;\n\n\t\t\t\t\tfor(int a = 0; a < N; a++){\n\t\t\t\t\t\tif(rangeCheck(work[a].x,work[a].y)){\n\t\t\t\t\t\t\tif(is_stone[work[a].x][work[a].y]){\n\t\t\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif(!FLG){\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\n\t\t\t\t\tif(final_min_dist[work[0].x][work[0].y][next_code] > Q.top().sum_dist+1){\n\n\t\t\t\t\t\tfinal_min_dist[work[0].x][work[0].y][next_code] = Q.top().sum_dist+1;\n\t\t\t\t\t\tQ.push(Info(work[0].x,work[0].y,next_code,Q.top().sum_dist+1,work));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tQ.pop();\n\t\t}\n\t}\n}\n\nint makeCode(int num_parts){\n\n\tint ret = 0;\n\n\tfor(int i = 0; i < num_parts-1; i++){\n\t\tfor(int k = 1; k <= 6; k++){\n\t\t\tif(type_table[i] == type_array[k]){\n\t\t\t\tret = 10*ret+k;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn ret;\n}\n\nvoid makeState(int num_parts,int index){\n\n\tif(index == num_parts){\n\n\t\tstate[state_index].num_parts = num_parts;\n\t\tfor(int i = 0; i < num_parts-1; i++){\n\t\t\tstate[state_index].type[i] = type_table[i];\n\t\t}\n\n\t\tMAP[makeCode(num_parts)] = state_index;\n\n\t\tstate_index++;\n\t\treturn;\n\t}\n\n\tint count;\n\n\tint next_x,next_y,tmp_x,tmp_y;\n\n\tfor(int i = 0; i < 6; i++){ //最後のマスから、6近傍を探索\n\n\t\tnext_x = loc_table[index-1].x+diff_x[i];\n\t\tnext_y = loc_table[index-1].y+diff_y[i];\n\n\t\t//既に使用している節があればSKIP\n\t\tcount = 0;\n\t\tfor(int k = 0; k <= index-2; k++){\n\t\t\tif(loc_table[k].x == next_x && loc_table[k].y == next_y){\n\t\t\t\tcount = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(count != 0)continue;\n\n\t\t//今回のマス(末尾)が、loc_table[index-1]以外のマスと接していたらSKIP\n\t\tcount = 0;\n\t\tfor(int k = 0; k <= index-2; k++){\n\t\t\tfor(int a = 0; a < 6; a++){\n\t\t\t\ttmp_x = loc_table[k].x+diff_x[a];\n\t\t\t\ttmp_y = loc_table[k].y+diff_y[a];\n\n\t\t\t\tif(tmp_x == next_x && tmp_y == next_y){\n\t\t\t\t\tcount = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(count != 0)break;\n\t\t}\n\t\tif(count != 0)continue;\n\n\t\tloc_table[index].set(next_x,next_y);\n\t\ttype_table[index-1] = type_array[i+1]; //★★★+1に注意★★★\n\n\t\tmakeState(num_parts,index+1);\n\t}\n}\n\nvoid calcMoveGroup(int num_parts){\n\n\tbool check[9];\n\tbool FLG;\n\n\tfor(int state = 1; state < POW[num_parts]; state++){\n\t\tfor(int loop = 0; loop < num_parts; loop++){\n\t\t\tif(state & (1 << loop)){\n\t\t\t\tcheck[loop] = true;\n\t\t\t}else{\n\t\t\t\tcheck[loop] = false;\n\t\t\t}\n\t\t}\n\t\tFLG = true;\n\t\tfor(int i = 1; i < num_parts; i++){\n\t\t\tif(check[i] == true && check[i-1] == true){ //隣接する2個は同時には動けない\n\t\t\t\tFLG = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(FLG){\n\t\t\tMOVE_GROUP[num_parts].push_back(state);\n\t\t}\n\t}\n}\n\n//前の状態から見た、次の状態の相対位置を取得する関数\nType getRelativePos(LOC next,LOC pre){\n\n\tType ret = No_Move;\n\n\tint tmp_x,tmp_y;\n\tfor(int i = 0; i < 6; i++){\n\t\ttmp_x = pre.x+diff_x[i];\n\t\ttmp_y = pre.y+diff_y[i];\n\n\t\tif(tmp_x == next.x && tmp_y == next.y){\n\t\t\treturn type_array[i+1]; //★★\n\t\t}\n\t}\n\n\treturn ret;\n}\n\n\n\nbool adj_check(int num_parts,LOC tmp_loc[8]){\n\n\tint adj_count;\n\tint adj_x,adj_y;\n\n\tfor(int i = 0; i < num_parts; i++){\n\n\t\tadj_count = 0;\n\t\tfor(int k = 0; k < 6; k++){\n\t\t\tadj_x = tmp_loc[i].x+diff_x[k]; //現在のマスの、隣接マスを求める\n\t\t\tadj_y = tmp_loc[i].y+diff_y[k];\n\n\t\t\tfor(int a = 0; a < num_parts; a++){ //そのマスを使っている節があるか\n\t\t\t\tif(a == i)continue;\n\t\t\t\tif(tmp_loc[a].x == adj_x && tmp_loc[a].y == adj_y){\n\t\t\t\t\tadj_count++;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(i == 0 && adj_count != 1){\n\n\t\t\treturn false;\n\n\t\t}else if(i > 0 && i < num_parts-1 && adj_count != 2){\n\n\t\t\treturn false;\n\n\t\t}else if(i == num_parts-1 && adj_count != 1){\n\n\t\t\treturn false;\n\t\t}\n\t}\n\n\treturn true;\n}\n\nbool is_same_pos(int num_parts,LOC tmp_loc[8]){\n\n\tfor(int i = 0; i < num_parts-1; i++){\n\t\tfor(int k = i+1; k < num_parts; k++){\n\t\t\tif(tmp_loc[i].x == tmp_loc[k].x && tmp_loc[i].y == tmp_loc[k].y){\n\t\t\t\treturn false;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn true;\n}\n\n//ある状態から遷移できる別の状態を洗い出す\nvoid calc_adj_state(int index){\n\n\tint num_parts = state[index].num_parts;\n\tbool FLG;\n\n\tloc_table[0].set(0,0);\n\n\tint tmp_x,tmp_y;\n\tfor(int i = 0; i < num_parts-1; i++){\n\n\t\tswitch(state[index].type[i]){\n\t\tcase Up:\n\t\t\ttmp_x = loc_table[i].x;\n\t\t\ttmp_y = loc_table[i].y-1;\n\t\t\tbreak;\n\t\tcase Right_Up:\n\t\t\ttmp_x = loc_table[i].x+1;\n\t\t\ttmp_y = loc_table[i].y-1;\n\t\t\tbreak;\n\t\tcase Right_Under:\n\t\t\ttmp_x = loc_table[i].x+1;\n\t\t\ttmp_y = loc_table[i].y;\n\t\t\tbreak;\n\t\tcase Under:\n\t\t\ttmp_x = loc_table[i].x;\n\t\t\ttmp_y = loc_table[i].y+1;\n\t\t\tbreak;\n\t\tcase Left_Under:\n\t\t\ttmp_x = loc_table[i].x-1;\n\t\t\ttmp_y = loc_table[i].y+1;\n\t\t\tbreak;\n\t\tcase Left_Up:\n\t\t\ttmp_x = loc_table[i].x-1;\n\t\t\ttmp_y = loc_table[i].y;\n\t\t\tbreak;\n\t\t}\n\t\tloc_table[i+1].set(tmp_x,tmp_y);\n\t}\n\n\tint num_move,tmp_state,tmp_pos;\n\tqueue<Snake> Q;\n\t//同時に動かす場所を全探索\n\tfor(int i = 0; i < MOVE_GROUP[num_parts].size(); i++){\n\t\tnum_move = 0;\n\t\tSnake tmp_snake;\n\t\tfor(int k = 0; k < num_parts; k++){\n\t\t\ttmp_snake.tmp_loc[k] = loc_table[k];\n\t\t}\n\t\ttmp_state = MOVE_GROUP[num_parts][i];\n\t\tfor(int loop = 0; loop < num_parts; loop++){\n\t\t\tif(tmp_state & (1 << loop)){\n\t\t\t\ttmp_snake.move_array[num_move] = loop;\n\t\t\t\ttmp_snake.is_move[loop] = true;\n\t\t\t\tnum_move++;\n\t\t\t}else{\n\t\t\t\ttmp_snake.is_move[loop] = false;\n\t\t\t}\n\t\t}\n\t\ttmp_snake.index = 0;\n\t\ttmp_snake.num_move = num_move;\n\t\tQ.push(tmp_snake);\n\t}\n\n\twhile(!Q.empty()){\n\n\t\tSnake tmp_snake = Q.front();\n\t\tQ.pop();\n\n\t\tif(tmp_snake.index == tmp_snake.num_move){ //移動完了\n\n\t\t\t//★同じ場所に2つ以上の節があればSKIP★\n\t\t\tif(!is_same_pos(num_parts,tmp_snake.tmp_loc)){\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\t//★隣接関係が不適ならSKIP★\n\t\t\tif(!adj_check(num_parts,tmp_snake.tmp_loc))continue;\n\n\t\t\ttmp_state = calc_state(num_parts,tmp_snake.tmp_loc);\n\n\t\t\t//頭の移動方向別に、隣接状態を格納\n\t\t\tType tmp_type = getRelativePos(tmp_snake.tmp_loc[0],loc_table[0]);\n\n\t\t\tADJ[index][tmp_type].push_back(tmp_state);\n\n\t\t\tcontinue;\n\t\t}\n\n\t\ttmp_pos = tmp_snake.move_array[tmp_snake.index]; //今回動かす場所\n\n\t\tfor(int i = 0; i < 6; i++){\n\n\t\t\ttmp_x = tmp_snake.tmp_loc[tmp_pos].x+diff_x[i];\n\t\t\ttmp_y = tmp_snake.tmp_loc[tmp_pos].y+diff_y[i];\n\n\t\t\tFLG = true;\n\t\t\t//同じ場所に、別の節があったら不可\n\t\t\tfor(int k = 0; k < num_parts; k++){\n\t\t\t\tif(k > tmp_pos && tmp_snake.is_move[k] == true)continue; //これから動くものはSKIP\n\t\t\t\tif(tmp_snake.tmp_loc[k].x == tmp_x && tmp_snake.tmp_loc[k].y == tmp_y){\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\t//1つ前の節と隣接していなければSKIP\n\t\t\tif(tmp_pos > 0){\n\n\t\t\t\tFLG = false;\n\t\t\t\tfor(int a = 0; a < 6; a++){\n\t\t\t\t\tif(tmp_x == tmp_snake.tmp_loc[tmp_pos-1].x+diff_x[a] && tmp_y == tmp_snake.tmp_loc[tmp_pos-1].y+diff_y[a]){\n\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!FLG)continue;\n\t\t\t}\n\n\t\t\t//1つ後の節と隣接していなければSKIP\n\t\t\tif(tmp_pos < tmp_snake.num_move-1){\n\t\t\t\tFLG = false;\n\t\t\t\tfor(int a = 0; a < 6; a++){\n\t\t\t\t\tif(tmp_x == tmp_snake.tmp_loc[tmp_pos+1].x+diff_x[a] && tmp_y == tmp_snake.tmp_loc[tmp_pos+1].y+diff_y[a]){\n\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!FLG)continue;\n\t\t\t}\n\n\t\t\tSnake next_snake;\n\t\t\tfor(int k = 0; k < num_parts; k++){\n\t\t\t\t//debug++;\n\t\t\t\tnext_snake.tmp_loc[k] = tmp_snake.tmp_loc[k];\n\t\t\t\tnext_snake.is_move[k] = tmp_snake.is_move[k];\n\t\t\t}\n\t\t\tnext_snake.index = tmp_snake.index+1;\n\t\t\tnext_snake.num_move = tmp_snake.num_move;\n\t\t\tfor(int k = 0; k < tmp_snake.num_move; k++){\n\t\t\t\tnext_snake.move_array[k] = tmp_snake.move_array[k];\n\t\t\t}\n\t\t\tnext_snake.tmp_loc[tmp_pos].set(tmp_x,tmp_y);\n\t\t\tQ.push(next_snake);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < 7; i++){\n\t\tsort(ADJ[index][i].begin(),ADJ[index][i].end());\n\t\tADJ[index][i].erase(unique(ADJ[index][i].begin(),ADJ[index][i].end()),ADJ[index][i].end());\n\t}\n}\n\nvoid calc_min_dist(){\n\n\tfor(int x = 0; x < SIZE; x++){\n\t\tfor(int y = 0; y < SIZE; y++){\n\t\t\tmin_dist[x][y] = DIST_MAX;\n\t\t}\n\t}\n\n\tmin_dist[goal.x][goal.y] = 0;\n\tpriority_queue<Data> Q;\n\tQ.push(Data(goal.x,goal.y,0));\n\n\tint next_x,next_y;\n\n\twhile(!Q.empty()){\n\n\t\tfor(int i = 0; i < 6; i++){\n\n\t\t\tnext_x = Q.top().x+diff_x[i];\n\t\t\tnext_y = Q.top().y+diff_y[i];\n\n\t\t\tif(!rangeCheck(next_x,next_y))continue;\n\n\t\t\tif(min_dist[next_x][next_y] > Q.top().sum_dist+1){\n\t\t\t\tmin_dist[next_x][next_y] = Q.top().sum_dist+1;\n\t\t\t\tQ.push(Data(next_x,next_y,min_dist[next_x][next_y]));\n\t\t\t}\n\t\t}\n\t\tQ.pop();\n\t}\n}\n\nint main(){\n\n\tstate_index = 0;\n\n\t//蛇のありえる形態を洗い出す(6186)\n\tfor(int num_parts = 2; num_parts <= 8; num_parts++){\n\t\tloc_table[0].set(0,0);\n\t\tmakeState(num_parts,1);\n\t}\n\n\t//同時に動かし得る、節の集合を列挙する\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= 8; i++){\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\tfor(int num_parts = 2; num_parts <= 8; num_parts++){\n\t\tcalcMoveGroup(num_parts);\n\t}\n\n\t//状態間の隣接関係を計算する\n\tfor(int i = 0; i < state_index; i++){\n\t\tcalc_adj_state(i);\n\t}\n\n\t//ゴールを固定する\n\tgoal.set(SIZE/2,SIZE/2);\n\n\t//ゴール地点からの最短距離を計算する\n\tcalc_min_dist();\n\n\twhile(true){\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 900, "memory_kb": 52028, "score_of_the_acc": -0.6814, "final_rank": 10 }, { "submission_id": "aoj_1143_2449121", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define x first\n#define y second\nusing Point = pair<int, int>;\n\nusing Direction = int;\nusing Body = vector<Direction>;\n\nstruct Snake {\n Point head;\n Body body;\n bool operator<(auto s) const {return head != s.head ? head < s.head : body < s.body;}\n};\n\nconst int D = 7;\nconst Direction DX[D] = {0, 0, 1, 1, 0, -1, -1};\nconst Direction DY[D] = {0, -1, -1, 0, 1, 1, 0};\n\nbool valid(const Body& body) {\n static map<Body, bool> memo;\n if(memo.count(body)) return memo[body];\n const int N = 10;\n auto x = N, y = N;\n vector<vector<int>> f(2*N, vector<int>(2*N));\n for(auto d = 0; d < D; ++d) ++f[x+DX[d]][y+DY[d]];\n for(auto b: body) {\n x += DX[b];\n y += DY[b];\n for(auto d = 0; d < D; ++d) ++f[x+DX[d]][y+DY[d]];\n }\n x = y = N;\n if(f[x][y] != 2) return memo[body] = false;\n for(auto i = 0; i < body.size(); ++i) {\n x += DX[body[i]];\n y += DY[body[i]];\n if(i == body.size() - 1) {\n if(f[x][y] != 2) return memo[body] = false;\n } else {\n if(f[x][y] != 3) return memo[body] = false;\n }\n }\n return memo[body] = true;\n}\n\nDirection direction(const Point& p) {\n static map<Point, Direction> memo;\n if(memo.count(p)) return memo[p];\n for(auto d = 1; d < D; ++d) if(p.x == DX[d] && p.y == DY[d]) return memo[p] = d;\n return -1;\n}\n\nvoid next(vector<Snake>& res, vector<Point>& point, int depth, bool moved) {\n if(depth == point.size()) {\n Snake snake;\n snake.head = point[0];\n for(auto i = 1; i < point.size(); ++i) snake.body.emplace_back(direction(Point(point[i].x - point[i-1].x, point[i].y - point[i-1].y)));\n if(valid(snake.body)) res.emplace_back(snake);\n return;\n }\n next(res, point, depth + 1, false);\n if(moved) return;\n for(auto d = 1; d < D; ++d) {\n point[depth].x += DX[d];\n point[depth].y += DY[d];\n if(depth == 0 || direction(Point(point[depth].x - point[depth-1].x, point[depth].y - point[depth-1].y)) != -1)\n next(res, point, depth + 1, true);\n point[depth].x -= DX[d];\n point[depth].y -= DY[d];\n }\n}\n\nvector<Snake> next(const Snake& snake) {\n static map<Body, vector<Snake>> memo;\n if(memo.count(snake.body)) return memo[snake.body];\n vector<Point> point;\n point.emplace_back(0, 0);\n for(auto i = 0; i < snake.body.size(); ++i) {\n auto b = snake.body[i];\n auto x = point.back().x + DX[b];\n auto y = point.back().y + DY[b];\n point.emplace_back(x, y);\n }\n next(memo[snake.body], point, 0, false);\n return memo[snake.body];\n}\n\nset<Point> terrain(auto k, const auto& u, const auto& v) {\n set<Point> res;\n for(auto i = 0; i < k; ++i) res.emplace(u[i], v[i]);\n return res;\n}\n\nint solve(const auto& snake, const auto& rock, auto X, auto Y) {\n set<Snake> visited;\n queue<pair<int, Snake>> q;\n q.emplace(0, snake);\n while(!q.empty()) {\n int step;\n Snake cur;\n tie(step, cur) = q.front();\n q.pop();\n if(cur.head.x == X && cur.head.y == Y) return step;\n if(20-step < abs(X-cur.head.x)) continue;\n if(20-step < abs(Y-cur.head.y)) continue;\n if(visited.count(cur)) continue;\n visited.emplace(cur);\n for(auto nex: next(cur)) {\n nex.head.x += cur.head.x;\n nex.head.y += cur.head.y;\n auto p = nex.head;\n bool stranding = rock.count(p);\n for(auto b: nex.body) {\n p.x += DX[b];\n p.y += DY[b];\n stranding |= rock.count(p);\n }\n if(stranding) continue;\n if(!visited.count(nex)) q.emplace(step + 1, nex);\n }\n }\n assert(false);\n}\n\nint main() {\n int n;\n while(cin >> n, n) {\n vector<int> x(n), y(n);\n for(auto i = 0; i < n; ++i) cin >> x[i] >> y[i];\n int k;\n cin >> k;\n vector<int> u(k), v(k);\n for(auto i = 0; i < k; ++i) cin >> u[i] >> v[i];\n int X, Y;\n cin >> X >> Y;\n\n for(auto p: {&x, &y, &u, &v}) for(auto& i: *p) i += 1e6;\n for(auto p: {&X, &Y}) *p += 1e6;\n\n Snake snake;\n snake.head = {x[0], y[0]};\n for(auto i = 1; i < n; ++i) snake.body.emplace_back(direction({x[i] - x[i-1], y[i] - y[i-1]}));\n\n cout << solve(snake, terrain(k, u, v), X, Y) << endl;\n }\n}", "accuracy": 1, "time_ms": 7380, "memory_kb": 51076, "score_of_the_acc": -1.152, "final_rank": 14 }, { "submission_id": "aoj_1143_2421450", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint ax[]={1,1,0,-1,-1,0};\nint ay[]={0,-1,-1,0,1,1};\ntypedef pair<int,int> P;\ntypedef vector<P> VP;\n#define X first\n#define Y second\nbool adj(P a,P b){\n for(int i=0;i<6;i++){\n if(a.X+ax[i]==b.X&&a.Y+ay[i]==b.Y)\n return 1;\n }\n return 0;\n}\nint n,m;\nVP p,r;\nvector<VP> t;\nP g;\nvoid dfs(int v,int f){\n //cout<<v<<\" \"<<f<<endl;\n if(v==n){\n t.push_back(p);\n return;\n }\n { \n bool flg=(v==0)||adj(p[v-1],p[v]);\n for(int j=0;j<v-1;j++) flg&=!adj(p[j],p[v]);\n for(int j=0;j<v;j++) flg&=(p[j]!=p[v]);\n for(int j=0;j<m;j++) flg&=(r[j]!=p[v]);\n if(flg) dfs(v+1,0);\n }\n if(!f){\n for(int i=0;i<6;i++){\n p[v].X+=ax[i];\n p[v].Y+=ay[i];\n bool flg=(v==0)||adj(p[v-1],p[v]);\n for(int j=0;j<v-1;j++) flg&=!adj(p[j],p[v]);\n for(int j=0;j<v;j++) flg&=(p[j]!=p[v]);\n for(int j=0;j<m;j++) flg&=(r[j]!=p[v]);\n if(flg) dfs(v+1,1);\n p[v].X-=ax[i];\n p[v].Y-=ay[i];\n }\n }\n}\nvoid dfs2(int v){\n if(v==n){\n t.push_back(p);\n return;\n }\n if(v==0){\n p[0]=g;\n dfs2(v+1);\n return;\n }\n for(int i=0;i<6;i++){\n p[v].X=p[v-1].X+ax[i];\n p[v].Y=p[v-1].Y+ay[i];\n bool flg=(v==0)||adj(p[v-1],p[v]);\n for(int j=0;j<v-1;j++) flg&=!adj(p[j],p[v]);\n for(int j=0;j<v;j++) flg&=(p[j]!=p[v]);\n for(int j=0;j<m;j++) flg&=(r[j]!=p[v]);\n if(flg) dfs2(v+1);\n }\n}\nsigned main(){\n while(cin>>n,n){\n p.resize(n);\n for(int i=0;i<n;i++) cin>>p[i].X>>p[i].Y;\n cin>>m;\n r.resize(m);\n for(int i=0;i<m;i++) cin>>r[i].X>>r[i].Y;\n cin>>g.X>>g.Y;\n map<VP,int> mv[2];\n queue<VP> q;\n q.push(p);\n mv[0][p]=0;\n int ans=20;\n while(!q.empty()){\n p=q.front();q.pop();\n int d=mv[0][p];\n if(d>=10) break;\n t.clear();\n dfs(0,0);\n for(VP np:t){\n\tif(!mv[0].count(np)){\n\t if(max(abs(np[0].X-g.X),abs(np[0].Y-g.Y))+d+1>=20) continue;\n\t mv[0][np]=d+1;\n\t q.push(np);\n\t}\n }\n }\n END:\n \n while(!q.empty()) q.pop();\n t.clear();\n dfs2(0);\n for(VP np:t){\n q.push(np);\n mv[1][np]=0;\n }\n while(!q.empty()){\n p=q.front();q.pop();\n int d=mv[1][p];\n if(d>=min(ans,9)) break;\n if(mv[0].count(p))\n\tans=min(ans,mv[0][p]+mv[1][p]);\n t.clear();\n dfs(0,0);\n for(VP np:t){\n\tif(!mv[1].count(np)){\n\t mv[1][np]=d+1;\n\t q.push(np);\n\t if(mv[0].count(np))\n\t ans=min(ans,mv[0][np]+mv[1][np]);\n\t}\n }\n }\n cout<<ans<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 12550, "memory_kb": 32244, "score_of_the_acc": -1.2673, "final_rank": 18 }, { "submission_id": "aoj_1143_1809254", "code_snippet": "#define _USE_MATH_DEFINES\n#include <iostream>\n#include <fstream>\n#include<vector>\n#include<algorithm>\n#include<numeric>\n#include<set>\n#include<map>\n#include<queue>\n#include<functional>\nusing namespace std;\n#define rep(i,n) for (auto i = 0; i < n; i++)\n#define range(i,v) for (auto &i:v)\n \nstruct init{\n init(){\n cin.tie(0); ios::sync_with_stdio(false);\n }\n}________init;\n \nconst int D = 7;\nconst int dr[] = { 0, 1, 1, 0, -1, -1 ,0};\nconst int dc[] = { -1, -1, 0, 1, 1, 0 ,0};\ninline bool near(int pr, int pc, int qr, int qc){\n rep(i, D-1){\n if (pr + dr[i] == qr&&pc + dc[i] == qc)return true;\n }\n return false;\n}\ninline bool eq_near(int pr, int pc, int qr, int qc){\n rep(i, D){\n if (pr + dr[i] == qr&&pc + dc[i] == qc)return true;\n }\n return false;\n}\n \ntypedef vector<int> V;\ntypedef vector<V> VV;\ninline bool check(VV &snake, set<V> &stone){\n int n = snake.size();\n range(it, snake)if (stone.count(it))return false;\n rep(i, n){\n if (i + 1 < n){\n int j = i + 1;\n if (!near(snake[i][0], snake[i][1], snake[j][0], snake[j][1]))return false;\n }\n rep(j, n)if (i + 2 <= j){\n if (eq_near(snake[i][0], snake[i][1], snake[j][0], snake[j][1]))return false;\n }\n }\n return true;\n \n}\n \ninline bool check2(int n,VV &snake, set<V> &stone){\n if (stone.count(snake[n-1]))return false;\n {\n rep(k, 2){\n int i = n - k - 1;\n if (i>=0&&i + 1 < (int)snake.size()){\n int j = i + 1;\n if (!near(snake[i][0], snake[i][1], snake[j][0], snake[j][1]))return false;\n }\n }\n int i = n-1;\n rep(j, n-2){\n if (eq_near(snake[i][0], snake[i][1], snake[j][0], snake[j][1]))return false;\n }\n }\n return true;\n}\nmap<VV, int> cost;\nint main(){\n #ifdef INPUT_FROM_FILE\n ifstream cin(\"sample.in\");\n ofstream cout(\"sample.out\");\n #endif\n int n, k;\n while (cin >> n, n){\n \n set<V> stone;\n VV snake(n, V(2));\n \n range(jt, snake)range(it, jt)cin >> it;\n \n \n cin >> k;\ncost.clear();\n cost[snake] = 0;\n rep(i, k){\n V s(2);\n range(it, s)cin >> it;\n stone.insert(s);\n }\n V goal(2);\n range(it, goal)cin >> it;\n queue<VV> que;\n que.push(snake);\n while (!que.empty()){\n auto v = que.front();\n que.pop();\n //printf(\"%d\\n\", cost[v]);\n if (v[0] == goal){\n cout << cost[v] << endl;\n break;\n }\n auto u = v;\n std::function<void(int, bool)> dfs = [&](int k, bool prev_move){\n if (k == n){\n if (cost.count(u) == 0)\nif(20>=cost[v]+1+max(abs(u[0][0]-goal[0]),abs(u[0][1]-goal[1]))){\n cost[u] = cost[v] + 1;\n que.push(u);\n }\n }\n else\n if (prev_move){\n dfs(k + 1, false);\n }\n else\n rep(i, D){\n u[k][0] += dr[i];\n u[k][1] += dc[i];\n if(check2(k+1,u, stone))dfs(k + 1, i != D - 1);\n u[k][0] -= dr[i];\n u[k][1] -= dc[i];\n }\n };\n dfs(0, false);\n };\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 5070, "memory_kb": 39164, "score_of_the_acc": -0.8079, "final_rank": 12 } ]
aoj_1149_cpp
Problem C: Cut the Cake Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest pâtissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party. The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical. Figure C-1: The top view of the cake Figure C-2: Cutting the cake into pieces Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones. Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece. Input The input is a sequence of datasets, each of which is of the following format. n w d p 1 s 1 ... p n s n The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively. Each of the following n lines specifies a single cut, cutting one and only one piece into two. p i is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i -th cut. Note that, just before the i -th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows: The earlier a piece was born, the smaller its identification number is. Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer. Note that identification numbers are adjusted after each cut. s i is an integer between 1 and 1000 inclusive and specifies the starting point of the i -th cut. From the northwest corner of the piece whose identification number is p i , you can reach the starting point by traveling s i in the clockwise direction around the piece. You may as ...(truncated)
[ { "submission_id": "aoj_1149_9370376", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define all(x) (x).begin(),(x).end()\n#define eb emplace_back\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing vl = vector<long long>;\nusing vvl = vector<vector<long long>>; using vs = vector<string>;\nusing pl = pair<long long, long long>;\ntemplate <typename T> inline bool chmin(T& a, const T& b) {bool compare = a > b; if (a > b) a = b; return compare;}\ntemplate <typename T> inline bool chmax(T& a, const T& b) {bool compare = a < b; if (a < b) a = b; return compare;}\ntemplate<class T>using rp_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate <typename T> T gcd(T a, T b) {if (b == 0)return a; else return gcd(b, a % b);}\ntemplate <typename T> inline T lcm(T a, T b) {return a /gcd(a, b)*b;}\nconst ll INF = 1LL << 60;\nconst ld PI = acos(-1);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec);\ntemplate <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr);\ntemplate <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec);\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const pair<T, U> &pa);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec);\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa);\ntemplate <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp);\ntemplate <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp);\ntemplate <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl);\n \ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec) { os << '['; for (auto v : vec) os << v << ','; os << ']'; return os; }\ntemplate <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr) { os << '['; for (auto v : arr) os << v << ','; os << ']'; return os; }\ntemplate <class... T> std::istream &operator>>(std::istream &is, std::tuple<T...> &tpl) { std::apply([&is](auto &&... args) { ((is >> args), ...);}, tpl); return is; }\ntemplate <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl) { os << '('; std::apply([&os](auto &&... args) { ((os << args << ','), ...);}, tpl); return os << ')'; }\ntemplate <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec) { os << \"deq[\"; for (auto v : vec) os << v << ','; os << ']'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa) { return os << '(' << pa.first << ',' << pa.second << ')'; }\ntemplate <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << \"=>\" << v.second << ','; os << '}'; return os; }\ntemplate <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp) { os << '{'; for (auto v : mp) os << v.first << \"=>\" << v.second << ','; os << '}'; return os; }\n#ifdef LOCAL\nconst string COLOR_RESET = \"\\033[0m\", BRIGHT_GREEN = \"\\033[1;32m\", BRIGHT_RED = \"\\033[1;31m\", BRIGHT_CYAN = \"\\033[1;36m\", NORMAL_CROSSED = \"\\033[0;9;37m\", RED_BACKGROUND = \"\\033[1;41m\", NORMAL_FAINT = \"\\033[0;2m\";\n#define dbg(x) std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << \" = \" << (x) << NORMAL_FAINT << \" (L\" << __LINE__ << \") \" << __FILE__ << COLOR_RESET << std::endl\n#define dbgif(cond, x) ((cond) ? std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << \" = \" << (x) << NORMAL_FAINT << \" (L\" << __LINE__ << \") \" << __FILE__ << COLOR_RESET << std::endl : std::cerr)\n#else\n#define dbg(x) ((void)0)\n#define dbgif(cond, x) ((void)0)\n#endif\nvoid solve();\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout<<fixed<<setprecision(15);\n int num_tc = 1;\n //cin >> num_tc;\n rep(tc,num_tc){\n //cout << \"Case #\" << tc+1 << \": \" ;// << endl;\n solve();\n }\n}\n//見切り発車で実装しては行けない.頭の中でコードが完全に出来上がるまで書き始めるな.\nvoid solve(){\n while(true){\n int n,w,d;cin>>n>>w>>d;\n if(n==0&&w==0&&d==0)return;\n map<ll,tuple<ll,ll,ll,ll>> mp;\n mp[0] = {0,d,0,w};\n auto calc = [&](const tuple<ll,ll,ll,ll> &s)->ll{\n ll X = get<1>(s)-get<0>(s);\n ll Y = get<3>(s)-get<2>(s);\n return X * Y;\n };\n rep(k,n){\n ll p,s;cin>>p>>s;\n p--;\n auto [x1,x2,y1,y2] = mp[p];\n mp.erase(p);\n const ll H = x2 - x1;\n const ll W = y2 - y1;\n const ll sz = mp.size();\n s%=(H+W)*2;\n tuple<ll,ll,ll,ll> a,b;\n if(0<=s&&s<=W){\n //[y1,s),[s,y2)\n a = make_tuple(x1,x2,y1,y1+s);\n b = make_tuple(x1,x2,y1+s,y2);\n }else if(W<=s&&s<=W+H){\n s-=W;\n a = make_tuple(x1,x1+s,y1,y2);\n b = make_tuple(x1+s,x2,y1,y2);\n }else if(W+H<=s&&s<=W+H+W){\n s-=W+H;\n s = W-s;\n a = make_tuple(x1,x2,y1,y1+s);\n b = make_tuple(x1,x2,y1+s,y2);\n }else if(W+H+W<=s&&s<=W+H+W+H){\n s-=W+H+W;\n s=H-s;\n a = make_tuple(x1,x1+s,y1,y2);\n b = make_tuple(x1+s,x2,y1,y2);\n }\n\n if(calc(b)<calc(a))swap(a,b);\n mp[sz+10000] = a;\n mp[sz+20000] = b;\n ll c = 0;\n map<ll,tuple<ll,ll,ll,ll>> nmp;\n for(auto [x,y]:mp){\n nmp[c++] = y;\n }\n swap(nmp,mp);\n }\n vl ans;\n for(auto [a,b]:mp)ans.push_back(calc(b));\n sort(all(ans));\n rep(i,ans.size()){\n cout<<ans[i];\n if(i+1==(int)ans.size())cout<<endl;\n else cout<<\" \";\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3312, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1149_9370375", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define all(x) (x).begin(),(x).end()\n#define eb emplace_back\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing vl = vector<long long>;\nusing vvl = vector<vector<long long>>; using vs = vector<string>;\nusing pl = pair<long long, long long>;\ntemplate <typename T> inline bool chmin(T& a, const T& b) {bool compare = a > b; if (a > b) a = b; return compare;}\ntemplate <typename T> inline bool chmax(T& a, const T& b) {bool compare = a < b; if (a < b) a = b; return compare;}\ntemplate<class T>using rp_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate <typename T> T gcd(T a, T b) {if (b == 0)return a; else return gcd(b, a % b);}\ntemplate <typename T> inline T lcm(T a, T b) {return a /gcd(a, b)*b;}\nconst ll INF = 1LL << 60;\nconst ld PI = acos(-1);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec);\ntemplate <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr);\ntemplate <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec);\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const pair<T, U> &pa);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec);\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa);\ntemplate <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp);\ntemplate <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp);\ntemplate <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl);\n \ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec) { os << '['; for (auto v : vec) os << v << ','; os << ']'; return os; }\ntemplate <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr) { os << '['; for (auto v : arr) os << v << ','; os << ']'; return os; }\ntemplate <class... T> std::istream &operator>>(std::istream &is, std::tuple<T...> &tpl) { std::apply([&is](auto &&... args) { ((is >> args), ...);}, tpl); return is; }\ntemplate <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl) { os << '('; std::apply([&os](auto &&... args) { ((os << args << ','), ...);}, tpl); return os << ')'; }\ntemplate <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec) { os << \"deq[\"; for (auto v : vec) os << v << ','; os << ']'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa) { return os << '(' << pa.first << ',' << pa.second << ')'; }\ntemplate <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << \"=>\" << v.second << ','; os << '}'; return os; }\ntemplate <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp) { os << '{'; for (auto v : mp) os << v.first << \"=>\" << v.second << ','; os << '}'; return os; }\n#ifdef LOCAL\nconst string COLOR_RESET = \"\\033[0m\", BRIGHT_GREEN = \"\\033[1;32m\", BRIGHT_RED = \"\\033[1;31m\", BRIGHT_CYAN = \"\\033[1;36m\", NORMAL_CROSSED = \"\\033[0;9;37m\", RED_BACKGROUND = \"\\033[1;41m\", NORMAL_FAINT = \"\\033[0;2m\";\n#define dbg(x) std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << \" = \" << (x) << NORMAL_FAINT << \" (L\" << __LINE__ << \") \" << __FILE__ << COLOR_RESET << std::endl\n#define dbgif(cond, x) ((cond) ? std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << \" = \" << (x) << NORMAL_FAINT << \" (L\" << __LINE__ << \") \" << __FILE__ << COLOR_RESET << std::endl : std::cerr)\n#else\n#define dbg(x) ((void)0)\n#define dbgif(cond, x) ((void)0)\n#endif\nvoid solve();\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout<<fixed<<setprecision(15);\n int num_tc = 1;\n //cin >> num_tc;\n rep(tc,num_tc){\n //cout << \"Case #\" << tc+1 << \": \" ;// << endl;\n solve();\n }\n}\n//見切り発車で実装しては行けない.頭の中でコードが完全に出来上がるまで書き始めるな.\nvoid solve(){\n while(true){\n int n,w,d;cin>>n>>w>>d;\n if(n==0&&w==0&&d==0)return;\n map<ll,tuple<ll,ll,ll,ll>> mp;\n mp[0] = {0,d,0,w};\n auto calc = [&](const tuple<ll,ll,ll,ll> &s)->ll{\n ll X = get<1>(s)-get<0>(s);\n ll Y = get<3>(s)-get<2>(s);\n return X * Y;\n };\n rep(k,n){\n ll p,s;cin>>p>>s;\n p--;\n auto [x1,x2,y1,y2] = mp[p];\n mp.erase(p);\n const ll H = x2 - x1;\n const ll W = y2 - y1;\n const ll sz = mp.size();\n s%=(H+W)*2;\n tuple<ll,ll,ll,ll> a,b;\n if(0<=s&&s<=W){\n //[y1,s),[s,y2)\n a = make_tuple(x1,x2,y1,y1+s);\n b = make_tuple(x1,x2,y1+s,y2);\n }else if(W<=s&&s<=W+H){\n s-=W;\n a = make_tuple(x1,x1+s,y1,y2);\n b = make_tuple(x1+s,x2,y1,y2);\n }else if(W+H<=s&&s<=W+H+W){\n s-=W+H;\n s = W-s;\n a = make_tuple(x1,x2,y1,y1+s);\n b = make_tuple(x1,x2,y1+s,y2);\n }else if(W+H+W<=s&&s<=W+H+W+H){\n s-=W+H+W;\n s=H-s;\n a = make_tuple(x1,x1+s,y1,y2);\n b = make_tuple(x1+s,x2,y1,y2);\n }\n\n if(calc(b)<calc(a))swap(a,b);\n mp[sz+10000] = a;\n mp[sz+20000] = b;\n ll c = 0;\n map<ll,tuple<ll,ll,ll,ll>> nmp;\n for(auto [x,y]:mp){\n if(y==make_tuple(0,0,0,0))continue;\n nmp[c++] = y;\n }\n swap(nmp,mp);\n }\n vl ans;\n for(auto [a,b]:mp)ans.push_back(calc(b));\n sort(all(ans));\n rep(i,ans.size()){\n cout<<ans[i];\n if(i+1==(int)ans.size())cout<<endl;\n else cout<<\" \";\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3480, "score_of_the_acc": -0.9545, "final_rank": 2 }, { "submission_id": "aoj_1149_9370374", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define all(x) (x).begin(),(x).end()\n#define eb emplace_back\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing vl = vector<long long>;\nusing vvl = vector<vector<long long>>; using vs = vector<string>;\nusing pl = pair<long long, long long>;\ntemplate <typename T> inline bool chmin(T& a, const T& b) {bool compare = a > b; if (a > b) a = b; return compare;}\ntemplate <typename T> inline bool chmax(T& a, const T& b) {bool compare = a < b; if (a < b) a = b; return compare;}\ntemplate<class T>using rp_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate <typename T> T gcd(T a, T b) {if (b == 0)return a; else return gcd(b, a % b);}\ntemplate <typename T> inline T lcm(T a, T b) {return a /gcd(a, b)*b;}\nconst ll INF = 1LL << 60;\nconst ld PI = acos(-1);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec);\ntemplate <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr);\ntemplate <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec);\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const pair<T, U> &pa);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec);\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa);\ntemplate <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp);\ntemplate <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp);\ntemplate <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl);\n \ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec) { os << '['; for (auto v : vec) os << v << ','; os << ']'; return os; }\ntemplate <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr) { os << '['; for (auto v : arr) os << v << ','; os << ']'; return os; }\ntemplate <class... T> std::istream &operator>>(std::istream &is, std::tuple<T...> &tpl) { std::apply([&is](auto &&... args) { ((is >> args), ...);}, tpl); return is; }\ntemplate <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl) { os << '('; std::apply([&os](auto &&... args) { ((os << args << ','), ...);}, tpl); return os << ')'; }\ntemplate <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec) { os << \"deq[\"; for (auto v : vec) os << v << ','; os << ']'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa) { return os << '(' << pa.first << ',' << pa.second << ')'; }\ntemplate <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << \"=>\" << v.second << ','; os << '}'; return os; }\ntemplate <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp) { os << '{'; for (auto v : mp) os << v.first << \"=>\" << v.second << ','; os << '}'; return os; }\n#ifdef LOCAL\nconst string COLOR_RESET = \"\\033[0m\", BRIGHT_GREEN = \"\\033[1;32m\", BRIGHT_RED = \"\\033[1;31m\", BRIGHT_CYAN = \"\\033[1;36m\", NORMAL_CROSSED = \"\\033[0;9;37m\", RED_BACKGROUND = \"\\033[1;41m\", NORMAL_FAINT = \"\\033[0;2m\";\n#define dbg(x) std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << \" = \" << (x) << NORMAL_FAINT << \" (L\" << __LINE__ << \") \" << __FILE__ << COLOR_RESET << std::endl\n#define dbgif(cond, x) ((cond) ? std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << \" = \" << (x) << NORMAL_FAINT << \" (L\" << __LINE__ << \") \" << __FILE__ << COLOR_RESET << std::endl : std::cerr)\n#else\n#define dbg(x) ((void)0)\n#define dbgif(cond, x) ((void)0)\n#endif\nvoid solve();\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout<<fixed<<setprecision(15);\n int num_tc = 1;\n //cin >> num_tc;\n rep(tc,num_tc){\n //cout << \"Case #\" << tc+1 << \": \" ;// << endl;\n solve();\n }\n}\n//見切り発車で実装しては行けない.頭の中でコードが完全に出来上がるまで書き始めるな.\nvoid solve(){\n while(true){\n int n,w,d;cin>>n>>w>>d;\n if(n==0&&w==0&&d==0)return;\n map<ll,tuple<ll,ll,ll,ll>> mp;\n mp[0] = {0,d,0,w};\n auto calc = [&](const tuple<ll,ll,ll,ll> &s)->ll{\n ll X = get<1>(s)-get<0>(s);\n ll Y = get<3>(s)-get<2>(s);\n return X * Y;\n };\n rep(k,n){\n ll p,s;cin>>p>>s;\n p--;\n dbg(p);\n auto [x1,x2,y1,y2] = mp[p];\n assert(mp.size()==k+1);\n assert(mp[p]!=make_tuple(0,0,0,0));\n dbg(mp[p]);\n mp.erase(p);\n const ll H = x2 - x1;\n const ll W = y2 - y1;\n const ll sz = mp.size();\n s%=(H+W)*2;\n dbg(s);\n dbg(H);\n dbg(W);\n tuple<ll,ll,ll,ll> a,b;\n if(0<=s&&s<=W){\n //[y1,s),[s,y2)\n dbg(s);\n a = make_tuple(x1,x2,y1,y1+s);\n b = make_tuple(x1,x2,y1+s,y2);\n }else if(W<=s&&s<=W+H){\n s-=W;\n dbg(s);\n dbg(x1);\n dbg(x1+s);\n assert(0<=x1+s&&x1+s<=x2);\n a = make_tuple(x1,x1+s,y1,y2);\n b = make_tuple(x1+s,x2,y1,y2);\n }else if(W+H<=s&&s<=W+H+W){\n s-=W+H;\n s = W-s;\n dbg(s);\n a = make_tuple(x1,x2,y1,y1+s);\n b = make_tuple(x1,x2,y1+s,y2);\n }else if(W+H+W<=s&&s<=W+H+W+H){\n s-=W+H+W;\n s=H-s;\n dbg(s);\n dbg(x1);\n dbg(x1+s);\n a = make_tuple(x1,x1+s,y1,y2);\n b = make_tuple(x1+s,x2,y1,y2);\n }\n\n if(calc(b)<calc(a))swap(a,b);\n dbg(a);\n dbg(b);\n dbg(mp);\n mp[sz+10000] = a;\n mp[sz+20000] = b;\n ll c = 0;\n map<ll,tuple<ll,ll,ll,ll>> nmp;\n for(auto [x,y]:mp){\n dbg(y);\n if(y==make_tuple(0,0,0,0))continue;\n nmp[c++] = y;\n }\n dbg(nmp);\n swap(nmp,mp);\n }\n vl ans;\n for(auto [a,b]:mp)ans.push_back(calc(b)),dbg(b);\n sort(all(ans));\n rep(i,ans.size()){\n cout<<ans[i];\n if(i+1==(int)ans.size())cout<<endl;\n else cout<<\" \";\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3488, "score_of_the_acc": -1, "final_rank": 3 } ]
aoj_1151_cpp
Problem E: Twirl Around Let's think about a bar rotating clockwise as if it were a twirling baton moving on a planar surface surrounded by a polygonal wall (see Figure 1). Figure 1. A bar rotating in a polygon Initially, an end of the bar (called "end A") is at (0,0), and the other end (called "end B") is at (0, L ) where L is the length of the bar. Initially, the bar is touching the wall only at the end A. The bar turns fixing a touching point as the center. The center changes as a new point touches the wall. Your task is to calculate the coordinates of the end A when the bar has fully turned by the given count R . Figure 2. Examples of turning bars In Figure 2, some examples are shown. In cases (D) and (E), the bar is stuck prematurely (cannot rotate clockwise anymore with any point touching the wall as the center) before R rotations. In such cases, you should answer the coordinates of the end A in that (stuck) position. You can assume the following: When the bar's length L changes by ε (|ε| < 0.00001), the final ( x , y ) coordinates will not change more than 0.0005. Input The input consists of multiple datasets. The number of datasets is no more than 100. The end of the input is represented by "0 0 0". The format of each dataset is as follows: L R N X 1 Y 1 X 2 Y 2 ... X N Y N L is the length of the bar. The bar rotates 2π× R radians (if it is not stuck prematurely). N is the number of vertices which make the polygon. The vertices of the polygon are arranged in a counter-clockwise order. You may assume that the polygon is simple , that is, its border never crosses or touches itself. N , X i and Y i are integer numbers; R and L are decimal fractions. Ranges of those values are as follows: 1.0 ≤ L ≤ 500.0, 1.0 ≤ R ≤ 10.0, 3 ≤ N ≤ 100, -1000 ≤ X i ≤ 1000, -1000 ≤ Y i ≤ 1000, X 1 ≤ -1, Y 1 = 0, X 2 ≥ 1, Y 2 = 0. Output For each dataset, print one line containing x- and y- coordinates of the final position of the end A, separated by a space. The value may contain an error less than or equal to 0.001. You may print any number of digits after the decimal point. Sample Input 4.0 2.0 8 -1 0 5 0 5 -2 7 -2 7 0 18 0 18 6 -1 6 4.0 2.0 4 -1 0 10 0 10 12 -1 12 4.0 1.0 7 -1 0 2 0 -1 -3 -1 -8 6 -8 6 6 -1 6 4.0 2.0 6 -1 0 10 0 10 3 7 3 7 5 -1 5 5.0 2.0 6 -1 0 2 0 2 -4 6 -4 6 6 -1 6 6.0 1.0 8 -1 0 8 0 7 2 9 2 8 4 11 4 11 12 -1 12 0 0 0 Output for the Sample Input 16.0 0.0 9.999999999999998 7.4641016151377535 0.585786437626906 -5.414213562373095 8.0 0.0 6.0 0.0 9.52786404500042 4.0 Note that the above sample input corresponds to the cases in Figure 2. For convenience, in Figure 3, we will show an animation and corresponding photographic playback for the case (C). Figure 3. Animation and photographic playback for case (C)
[ { "submission_id": "aoj_1151_1380113", "code_snippet": "#include<cstdio>\n#include<cmath>\n#include<utility>\n#include<vector>\n#include<complex>\n#include<iostream>\n#include<algorithm>\n \nusing namespace std;\n \ntypedef long double Real;\ntypedef complex<Real> Point;\ntypedef complex<Real> Vector;\ntypedef pair<Point,Point> Line;\ntypedef pair<Point,Point> Segment;\ntypedef vector<Point> Polygon;\n \nconst Real eps=1e-9;\nconst Real PI=acos(-1.0);\nconst Real inf=1e9;\n \nconst Real eps2=1e-6;\n \nconst Point NPoint=Point(NAN,NAN);\n \nvoid print(Point p,char ch='\\n'){\n printf(\"(%f %f)%c\",p.real(),p.imag(),ch);\n}\n \ntemplate<class T> bool eq(T a,T b){\n return abs(a-b)<eps;\n}\ntemplate<class T> int sgn(T a){\n if(eq(a,(Real)0.0)) return 0;\n if(a>0) return 1;\n return -1;\n}\ntemplate<class T> bool eq2(T a,T b){\n return abs(a-b)<eps2;\n}\ntemplate<class T> int sgn2(T a){\n if(eq2(a,0.0)) return 0;\n if(a>0) return 1;\n return -1;\n}\n \nbool onSeg(Point a,Point b,Point c){\n return eq(abs(a-b),abs(a-c)+abs(c-b));\n}\n \nbool onSeg(Segment s,Point p){\n return onSeg(s.first,s.second,p);\n}\n \nReal doP(Vector a,Vector b){\n return (conj(a)*b).real();\n}\n \nReal crP(Vector a,Vector b){\n return (conj(a)*b).imag();\n}\n \nVector proj(Vector p,Vector b){\n return b*doP(p,b)/norm(b);\n}\n \nPoint perp(Line l,Point a){\n Point p=l.first,q=l.second;\n return p+proj(a-p,q-p);\n}\n \nbool isPara(Vector a,Vector b){\n return eq(crP(a,b),(Real)0);\n}\n \nbool isPara(Line l1,Line l2){\n return isPara(l1.second-l1.first,l2.second-l2.first);\n}\n \nReal arg(Point p){\n return atan2(p.imag(),p.real());\n}\n \nReal normalize(Real x){//[-PI,PI)\n while(x<-PI) x+=PI*2;\n while(x>=PI) x-=PI*2;\n return x;\n}\n \nstruct Circle:vector<Real>{\n Point c;\n Real r;\n Circle(){}\n Circle(Point c,Real r):c(c),r(r){}\n};\n \nPoint getP(Point c,Real r,Real ang){\n return c+r*Point(cos(ang),sin(ang));\n}\n \nvoid iCL(Circle &c_,Line l){//tangent: not intersect\n //lが中心を通る場合!!!\n Point c=c_.c;\n Real r=c_.r;\n Point p=l.first,q=l.second;\n Point h=perp(l,c);\n Real d=abs(h-c);\n if(sgn(d-r)>=0) return;\n Real theta=arg(h-c);\n Real phi=acos(d/r);\n c_.push_back(normalize(theta-phi));\n c_.push_back(normalize(theta+phi));\n}\n \nvoid iCS(Circle &c_,Segment s){\n// printf(\"iCS\\n\");\n// print(c_.c,' ');\n// printf(\"%f\\n\",c_.r);\n// print(s.first,' ');\n// print(s.second);\n Point c=c_.c;\n Real r=c_.r;\n Point p=s.first,q=s.second;\n Point h=perp(s,c);\n Real d=abs(h-c);\n if(sgn(d-r)>=0) return;\n if(eq(d,(Real)0)){\n Point dir=s.second-s.first;\n dir/=abs(dir);\n Point p1=c+r*dir;\n Point p2=c-r*dir;\n// printf(\"in iCS\\n\");\n// print(p1);\n// print(p2);\n if(onSeg(p,q,p1)) c_.push_back(arg(dir));\n if(onSeg(p,q,p2)) c_.push_back(arg(dir)-PI);\n return;\n }\n Real theta=arg(h-c);\n Real phi=acos(d/r);\n Point p1=getP(c,r,theta-phi);\n if(onSeg(p,q,p1)) c_.push_back(theta-phi);\n Point p2=getP(c,r,theta+phi);\n if(onSeg(p,q,p2)) c_.push_back(theta+phi);\n}\n \nSegment shrink(Segment s){\n Segment res;\n res.first=s.first+(s.second-s.first)*eps;\n res.second=s.second+(s.first-s.second)*eps;\n return res;\n}\n \nPolygon poly;\n \nvector<Point> getTouchingPoints(Segment s){\n vector<Point> res;\n for(int i=0;i<poly.size();i++){\n if(onSeg(s,poly[i])) res.push_back(poly[i]);\n }\n for(int i=0;i<poly.size();i++){\n Point p=poly[i],q=poly[i+1==poly.size()?0:i+1];\n if(onSeg(p,q,s.first)) res.push_back(s.first);\n if(onSeg(p,q,s.second)) res.push_back(s.second);\n }\n return res;\n}\n \nReal getAngDis(Real from,Real to,bool rev=false){\n if(rev) return getAngDis(to,from);\n Real res=to-from;\n while(res<0) res+=PI*2;\n return res;\n}\n \nReal getRotateAngle(Point p,Point q){\n// printf(\"getRotAng\");\n// print(p,' ');\n// print(q);\n vector<Point> pts;\n Real r=abs(p-q);\n if(eq(r,(Real)0)) return -1;\n Circle c=Circle(p,r);\n for(int i=0;i<poly.size();i++){\n Point p=poly[i],q=poly[i+1==poly.size()?0:i+1];\n Segment s_=Segment(p,q);\n Segment s=shrink(s_);\n if(sgn(abs(s.first-c.c)-c.r)<0) pts.push_back(s.first);\n if(sgn(abs(s.second-c.c)-c.r)<0) pts.push_back(s.second);\n iCS(c,s);\n }\n for(int i=0;i<c.size();i++){\n pts.push_back(getP(c.c,c.r,c[i]));\n }\n// for(int i=0;i<pts.size();i++){\n// print(pts[i]);\n// }\n Point nxt;\n Real ang=PI*3;\n Real init_dir=arg(q-p);\n for(int i=0;i<pts.size();i++){\n if(eq(pts[i],p)) continue;\n Real dir=arg(pts[i]-p);\n Real cur=getAngDis(init_dir,dir,true);\n if(cur<ang){\n Real tmp=getAngDis(init_dir,arg(pts[i]-p),true);\n //if(sgn(tmp)<=0) continue;\n if(tmp<(eps2)) continue;\n ang=cur;\n nxt=pts[i];\n }\n }\n return getAngDis(init_dir,arg(nxt-p),true);\n}\n \n//bool checkNonzero(Segment s,Point p);\n \nbool checkValidity(Segment s,Point c,Real ang);\n\nReal getRotateAngle(Segment s,Point c){\n// bool flg=checkNonzero(s,c);\n// if(!flg){\n// printf(\"check = false\\n\");\n// return 0;\n// }\n Real res=PI*3;\n if(!eq(s.first,c)){\n Real cur=getRotateAngle(c,s.first);\n res=min(res,cur);\n }\n if(!eq(s.second,c)){\n Real cur=getRotateAngle(c,s.second);\n res=min(res,cur);\n }\n\tbool flg=checkValidity(s,c,res);\n\tif(!flg) return 0;\n return res;\n}\n \nPoint rotatePoint(Point p,Point c,Real ang){\n return c+(p-c)*(Point(cos(-ang),sin(-ang)));\n}\n \nSegment rotateSegment(Segment s,Point c,Real ang){\n s.first=rotatePoint(s.first,c,ang);\n s.second=rotatePoint(s.second,c,ang);\n return s;\n}\n \nPoint iLL(Line l1,Line l2){\n if(isPara(l1,l2)) return NPoint;\n Point a1=l1.first,a2=l1.second;\n Point b1=l2.first,b2=l2.second;\n Real num=crP(b1-a1,a2-a1);\n Real den=crP(a2-a1,b2-b1);\n return b1+(b2-b1)*(num/den);\n}\n \nPoint iSS(Segment s1,Segment s2){\n Point p=iLL(s1,s2);\n if(isnan(p.real())) return p;\n if(onSeg(s1,p)&&onSeg(s2,p)) return p;\n return NPoint;\n}\n \nconst Real eps_rot=1e-6;\n \nPoint rot(Point p,Point q,Real a){\n return p+(q-p)*(Point(cos(a),sin(a)));\n}\n \nbool inPoly_(Polygon poly,Point pt){//ON is IN\n bool in=false;\n for(int i=0;i<poly.size();i++){\n Point a=poly[i],b=poly[(i+1)%poly.size()];\n a-=pt,b-=pt;\n// if(a.imag()>b.imag()) swap(a,b);\n if(sgn(a.imag()-b.imag())>0) swap(a,b);\n// if(a.imag()<=0&&0<b.imag()){\n if(sgn(a.imag())<=0&&sgn(b.imag())>0){\n// if(crP(a,b)<0) in=!in;\n int s=sgn(crP(a,b));\n if(s==0) return true;//ON\n if(s==-1) in=!in;\n }\n }\n return in;\n}\n /*\nbool checkNonzero(Segment s,Point p){\n// printf(\"checkNonzero\\n\");\n// print(s.first,' ');\n// print(s.second);\n/// print(p);\n Segment ns;\n ns.first=rot(p,s.first,-eps_rot);\n ns.second=rot(p,s.second,-eps_rot);\n vector<Point> ps;\n for(int i=0;i<poly.size();i++){\n Point v1=poly[i],v2=poly[i+1==poly.size()?0:i+1];\n Segment e=Segment(v1,v2);\n Point in=iSS(e,ns);\n// if(!isnan(in.real())) ps.push_back(in);\n if(!isnan(in.real())){\n// return false;\n// printf(\"inter:\");\n// print(in,' ');\n// printf(\"d=%.9f\\n\",abs(p-in));\n if((!eq2(ns.first,in))&&(!eq2(ns.second,in))&&(!eq2(e.first,in))&&(!eq2(e.second,in))\n &&(!eq2(p,in))){\n// printf(\"this is invalid\\n\");\n return false;\n }else{\n// printf(\"ok\\n\");\n }\n }\n }\n ps.push_back(ns.first);\n ps.push_back(ns.second);\n for(int i=0;i<ps.size();i++){\n if(!inPoly_(poly,ps[i])){\n// printf(\"not inside\");\n// print(ps[i]);\n return false;\n }\n }\n //printf(\"true\\n\");\n return true;\n}*/\n\nbool checkValidity(Point p,Point c,Real ang){\n//\tprintf(\"checkValidity\\n\");\n//\tprint(p,' ');\n//\tprint(c,' ');\n//\tprintf(\"%f\\n\",ang);\n\tang/=2;\n\tif(eq(p,c)) return true;\n\tPoint np=c+(p-c)*(Point(cos(-ang),sin(-ang)));\n\t//printf(\"np=\");\n\t//print(np);\n\tif(inPoly_(poly,np)==false){\n\t\t//printf(\"this is invalid\\n\");\n\t\treturn false;\n\t}\n\tSegment s=Segment(np,c);\n\tfor(int i=0;i<poly.size();i++){\n\t\tPoint v1=poly[i];\n\t\tPoint v2=poly[i+1==poly.size()?0:i+1];\n\t\tSegment e=Segment(v1,v2);\n\t\tif(isPara(s,e)) continue;\n\t\tPoint in=iSS(s,e);\n\t\tif(isnan(in.real())) continue;\n\t\tif(eq(in,np)||eq2(in,c)) continue;\n//\t\tif(abs(in-c)<(1e-1)) continue;\n\t\t//printf(\"intersect \");\n\t//\tprint(in);\n\t//\tprintf(\"this is invalid\\n\");\n\t\treturn false;\n\t}\n\treturn true;\n}\n\nbool checkValidity(Segment s,Point c,Real ang){\n\tbool flg1=checkValidity(s.first,c,ang);\n\tbool flg2=checkValidity(s.second,c,ang);\n\treturn flg1&flg2;\n}\n \ntypedef pair<Real,Point> P;\n/*\nSegment rotate(Segment s){\n vector<Point> cands=getTouchingPoints(s);\n vector<P> vec;\n for(int i=0;i<cands.size();i++){\n */\n \nReal remRotateAng;\nSegment seg;\n \nPoint solve(){\n int cnt_zero=0;\n while(remRotateAng>eps){\n if(cnt_zero>150) break;\n //printf(\"curseg=\");\n //print(seg.first,' ');\n //print(seg.second);\n vector<Point> cands=getTouchingPoints(seg);\n //printf(\"cands::\\n\");\n //for(int i=0;i<cands.size();i++){\n // print(cands[i]);\n //}\n vector<Real> vec;\n for(int i=0;i<cands.size();i++){\n vec.push_back(abs(seg.first-cands[i]));\n }\n sort(vec.begin(),vec.end());\n Point dir=seg.second-seg.first;\n dir/=(abs(dir));\n Point p1=seg.first+dir*vec.front();\n Point p2=seg.first+dir*vec.back();\n Real ang1=getRotateAngle(seg,p1);\n Real ang2=getRotateAngle(seg,p2);\n// printf(\"---\\n\");\n// print(p1,' ');\n// print(p2);\n// printf(\"%f %f\\n\",ang1,ang2);\n// printf(\"---\\n\");\n if(ang1>eps){\n Real rotateAng=min(ang1,remRotateAng);\n Segment nseg=rotateSegment(seg,p1,rotateAng);\n remRotateAng-=rotateAng;\n //printf(\"center=\");\n //print(p1);\n //printf(\"ang=%f\\n\",rotateAng);\n seg=nseg;\n }else if(ang2>eps){\n Real rotateAng=min(ang2,remRotateAng);\n Segment nseg=rotateSegment(seg,p2,rotateAng);\n remRotateAng-=rotateAng;\n //printf(\"center=\");\n //print(p2);\n //printf(\"ang=%f\\n\",rotateAng);\n seg=nseg;\n }else{\n cnt_zero++;\n //printf(\"zero\\n\");\n //print(seg.first,' ');\n //print(seg.second);\n //print(p1);\n //print(p2);\n break;\n }\n cnt_zero=0;\n// printf(\"remAng=%f\\n\",remRotateAng);\n }\n return seg.first;\n}\n \nint main(){\n int tnum=0;\n while(true){\n double L,R;\n int N;\n scanf(\"%lf%lf%d\",&L,&R,&N);\n if(N==0) break;\n tnum++;\n //printf(\"test case %d\\n\",tnum);\n poly.clear();\n for(int i=0;i<N;i++){\n double x,y;\n scanf(\"%lf%lf\",&x,&y);\n poly.push_back(Point(x,y));\n }\n remRotateAng=PI*2.0*R;\n seg=Segment(Point(0,0),Point(0,L));\n Point ans=solve();\n //fprintf(stderr,\"%.9f %.9f\\n\",ans.real(),ans.imag());\n double ansx=ans.real(),ansy=ans.imag();\n //printf(\"-----\\n\");\n // fprintf(stderr,\"%.9f %.9f\\n\",ansx,ansy);\n\t\tprintf(\"%9f %9f\\n\",ansx,ansy);\n // \tcout << ans.real() << \" \" << ans.imag() << \"\\n\";\n // break;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1316, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1151_814121", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <complex>\n#include <cstring>\n#include <cstdlib>\n#include <string>\n#include <cmath>\n#include <cassert>\n#include <queue>\n#include <set>\n#include <map>\n#include <valarray>\n#include <bitset>\n#include <stack>\n#include <iomanip>\n#include <fstream>\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(int)(n);++i)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n#define ALL(c) (c).begin(), (c).end()\n#define chmax(a,b) (a<b?(a=b,1):0)\n#define chmin(a,b) (a>b?(a=b,1):0)\n#define valid(y,x,h,w) (0<=y&&y<h&&0<=x&&x<w)\nconst int INF = 1<<29;\nconst double EPS = 1e-8;\nconst double PI = acos(-1);\ntypedef long long ll;\ntypedef pair<int,int> pii;\n\ntypedef complex<double> P;\nP pIN() { double x,y; cin >> x >> y; return P(x,y); }\nnamespace std {\n bool operator < (const P& a, const P& b) {\n // if (abs(a-b)<EPS) return 0;\n return real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n }\nbool operator==(const P &a, const P &b) {\n return abs(a-b)<EPS;\n}\n}\ndouble cross(const P& a, const P& b) {\n return imag(conj(a)*b);\n}\ndouble dot(const P& a, const P& b) {\n return real(conj(a)*b);\n}\nint ccw(P a, P b, P c) {\n b -= a; c -= a;\n if (cross(b, c) > EPS) return +1; // counter clockwise\n if (cross(b, c) < -EPS) return -1; // clockwise\n if (dot(b, c) < -EPS) return +2; // c--a--b on line\n if (EPS < norm(b) && norm(b) < norm(c)-EPS) return -2; // a--b--c on line\n return 0;\n}\nstruct L : public vector<P> {\n L(const P &a, const P &b) {\n push_back(a); push_back(b);\n }\n L() { resize(2); }\n};\nostream &operator<<(ostream &os, const L &a) {\n os << a[0] << \" -> \" << a[1];\n return os;\n}\ntypedef vector<P> G;\n#define curr(g, i) g[i]\n#define next(g, i) g[(i+1)%g.size()]\n#define prev(g, i) g[(i+g.size()-1)%g.size()]\nL line(const G &g, int i) {\n return L(g[i],g[(i+1)%g.size()]);\n}\nstruct C {\n P p; double r;\n C(const P &p, double r) : p(p), r(r) { }\n};\nbool contain(const C &c1, const C &c2) {\n double d = abs(c1.p - c2.p);\n return d < c1.r - c2.r + EPS;\n}\nvector<L> tangentCP(const C &c, const P &p) {\n vector<L> ret;\n P vect = c.p - p;\n double d = abs(vect);\n double l = sqrt(d*d-c.r*c.r);\n if (::isnan(l)) { return ret; }\n P v1 = vect * P(l / d, c.r / d);\n P v2 = vect * P(l / d, -c.r / d);\n ret.push_back(L(p, p+v1));\n if (l > EPS)\n ret.push_back(L(p, p+v2));\n return ret;\n}\nvector<L> tangentCC(const C &c1, const C &c2) {\n vector<L> ret;\n if (abs(c1.p - c2.p) - (c1.r + c2.r) > -EPS) {\n P center = (c1.p * c2.r + c2.p * c1.r) / (c1.r + c2.r);\n ret = tangentCP(c1, center);\n }\n if (fabs(c1.r - c2.r) > EPS) {\n P out = (-c1.p * c2.r + c2.p * c1.r) / (c1.r - c2.r);\n vector<L> nret = tangentCP(c1, out);\n ret.insert(ret.end(), nret.begin(), nret.end());\n } else {\n P vect = c2.p - c1.p;\n vect /= abs(vect);\n P q1 = c1.p + vect * P(0, 1) * c1.r;\n P q2 = c1.p + vect * P(0, -1) * c1.r;\n ret.push_back(L(q1, q1 + vect));\n ret.push_back(L(q2, q2 + vect));\n }\n return ret;\n}\nP projection(const L &l, const P &p) {\n double t = dot(p-l[0], l[0]-l[1]) / norm(l[0]-l[1]);\n return l[0] + t*(l[0]-l[1]);\n}\nP reflection(const L &l, const P &p) {\n return p + P(2,0) * (projection(l, p) - p);\n}\n\nvector<P> crosspointLC(const L &l, const C &c) {\n vector<P> ret;\n P center = projection(l, c.p);\n double d = abs(center - c.p);\n double t = sqrt(c.r * c.r - d * d);\n if (::isnan(t)) { return ret; }\n P vect = (l[1] - l[0]);\n vect /= abs(vect);\n ret.push_back(center - vect * t);\n if (t > EPS) {\n ret.push_back(center + vect * t);\n }\n return ret;\n}\nbool intersectSP(const L &s, const P &p) {\n return abs(s[0]-p)+abs(s[1]-p)-abs(s[1]-s[0]) < EPS; // triangle inequality\n}\n\nvector<P> crosspointSC(const L &s, const C &c) {\n vector<P> ret;\n vector<P> nret = crosspointLC(s, c);\n FOR(it, nret)\n if (intersectSP(s, *it))\n ret.push_back(*it);\n return ret;\n}\n\n\nG g;\ndouble l,r;\nint N;\n\nstruct Res {\n P ct;\n L s;\n double ang;\n Res(const P &ct, const L &s, double ang) :\n ct(ct),s(s),ang(ang) {}\n Res() {}\n};\n\nbool win(const Res &a, const Res &b, const P &ct) {\n if (abs(a.ang-b.ang)>EPS) return a.ang > b.ang;\n return abs(a.ct-ct) < abs(b.ct-ct);\n}\nbool sameang(const P &a, const P &b) {\n return abs(cross(a,b))<EPS && dot(a,b)>0;\n}\ndouble angle(const P &a, const P &b) {\n double ret = arg(b)-arg(a);\n return (ret>=0) ? ret : ret + 2*PI;\n}\n// テ」ツδ凖」ツつッテ」ツδ暗」ツδォaテ」ツ?ィテ」ツδ凖」ツつッテ」ツδ暗」ツδォbテ」ツ?ョテゥツ鳴禿」ツ?ョティツァツ津・ツコツヲ\ndouble angle2(const P &a, const P &b) {\n return min(angle(a,b), angle(b,a));\n}\ndouble angle2_2(const P &a, const P &b) {\n double ret = abs(arg(b)-arg(a));\n return ret>PI ? 2*PI-ret : ret;\n}\n// テヲツ卍づィツィツ暗・ツ崢榲」ツつ甘・ツ?エテ」ツ?ッテ・ツ青ォテ」ツ?ソテ」ツ??・ツ債甘ヲツ卍づィツィツ暗・ツ崢榲」ツつ甘・ツ?エテ」ツ?ッテ・ツ青ォテ」ツ?セテ」ツ?ェテ」ツ??\nint quadrant(const P &a) {\n if (a.real() > 0 && a.imag() >= 0) return 0;\n if (a.real() <= 0 && a.imag() > 0) return 1;\n if (a.real() < 0 && a.imag() <= 0) return 2;\n return 3;\n}\n// テ」ツδュテ」ツδ静」ツつケテ」ツδ暗」ツ?ェティツァツ津・ツコツヲテヲツッツ氾ィツシツ?\nbool cmpAngle(const P &a, const P&b) {\n int q1 = quadrant(a);\n int q2 = quadrant(b);\n if (q1 != q2) return q1 < q2;\n return cross(a,b)>0;\n}\n// テ」ツδ凖」ツつッテ」ツδ暗」ツδォテ」ツ?ョテ・ツ崢榲ィツサツ「\nP rotate(P p, double ang) {\n return p * P(cos(ang), sin(ang));\n}\n// テ・ツ篠淌ァツつケテ・ツ堕ィテ」ツつ甘」ツ?ョテァツ崢エテァツキツ堙」ツ?ョテ・ツ崢榲ィツサツ「\nL rotate(L l, double ang) {\n return L(rotate(l[0], ang),rotate(l[1], ang));\n}\n\ndouble signedLength(const P &p1, const P &p2, const P &p) {\n P pc = projection(L(p1,p2),p);\n double res = abs(pc-p1);\n if (dot(pc-p1,p2-p1)>0) return res;\n else return -res;\n}\n\nRes find_next(const P &ct, const L& s) {\n Res res;\n res.ang = INF;\n // vertex\n REP(i,N) {\n if (ct==g[i]) continue;\n REP(j,2) {\n if (s[j]==ct) continue;\n if (abs(g[i]-ct)<abs(s[j]-ct)) {\n if (sameang(g[i]-ct,s[j]-ct)) {\n if (ccw(ct,s[j],next(g,i)) == -1 ||\n ccw(ct,s[j],prev(g,i)) == -1) {\n // stuck\n Res t(g[i], s, 0);\n if (win(res,t,ct)) res = t;\n }\n } else {\n double ang = angle(g[i]-ct,s[j]-ct);\n Res t(g[i],L(ct+rotate(s[0]-ct,-ang),ct+rotate(s[1]-ct,-ang)),ang);\n if (win(res,t,ct)) res = t;\n }\n }\n }\n }\n // edge\n REP(i,N) {\n REP(j,2) {\n if (s[j]==ct) continue;\n vector<P> ps = crosspointSC(line(g,i),C(ct,abs(s[j]-ct)));\n FOR(it, ps) {\n if (sameang(*it-ct,s[j]-ct)) {\n P a = g[i];\n P b = next(g,i);\n P c = prev(g,i);\n if (abs(signedLength(ct,s[j],a) - signedLength(ct,s[j],b)) < EPS) continue;\n if (signedLength(ct,s[j],a) > signedLength(ct,s[j],b)) {\n swap(a,b);\n c = g[(i+2)%g.size()];\n }\n if (ccw(ct,*it,a) == 1) continue;\n if (ccw(ct,*it,a) != -1) {\n continue;\n if (ccw(ct,*it,c) == 1) continue;\n }\n // cout << ct << \" \" << s[j] << \" \" << a << \" \" << b << \" :\" << signedLength(ct,s[j],a) << \" \" << signedLength(ct,s[j],b) << endl;\n // cout << *it << endl;\n // cout << ccw(ct,*it,a) << endl;\n \n // cout << *it << endl;\n // stuck\n Res t(*it, s, 0);\n if (win(res,t,ct)) res = t;\n } else {\n // cout << *it << endl;\n double ang = angle(*it-ct,s[j]-ct);\n Res t(*it,L(ct+rotate(s[0]-ct,-ang),ct+rotate(s[1]-ct,-ang)),ang);\n // cout << res.ang << \" \" << ang << endl;\n if (win(res,t,ct)) res = t;\n } \n }\n }\n }\n return res;\n}\nFILE *fp;\ndouble scale = 10;\nP diff(300, 300);\ndouble WH = 500;\nvoid outputLine(const L &l) {\n if (!fp) return;\n P a = l[0];\n P b = l[1];\n a = a*P(scale,0)+diff;\n b = b*P(scale,0)+diff;\n fprintf(fp,\"line(%f,%f,%f,%f);\\n\",a.real(),WH-a.imag(),b.real(),WH-b.imag()); \n}\nvoid outputCircle(C c) {\n if (!fp) return;\n c.p = c.p*P(scale,0) + diff;\n c.r *= scale;\n fprintf(fp, \"circle(%f,%f,%f);\\n\", c.p.real(), WH-c.p.imag(), c.r);\n}\n\n\nint main() {\n fp = fopen(\"data.js\",\"w\");\n while(cin>>l>>r>>N, l||r||N) {\n g.clear();\n double tang = r*2*PI;\n REP(i,N) g.push_back(pIN());\n REP(i,N) outputLine(line(g,i));\n L s(P(0,0),P(0,l));\n P ct(0,0);\n double ang = 0;\n outputLine(s);\n int counter = 0;\n REP(i,1000) {\n Res ret = find_next(ct,s);\n // cout << ang << \" \" << ret.ang << \" \" << tang << endl;\n if (ang+ret.ang>=tang) {\n double ag = tang-ang;\n s[0] = ct+rotate(s[0]-ct,-ag);\n s[1] = ct+rotate(s[1]-ct,-ag);\n outputLine(s);\n break;\n }\n if (ang == 0) {\n if (counter++ == 10) break;\n } else counter = 0;\n \n // cout << ang << \" \" << s << \":\" << ret.ang << \" \" << ret.s<< \" \" << ret.ct << endl;\n outputLine(ret.s);\n outputCircle(C(ct,l));\n ang += ret.ang;\n s = ret.s;\n ct = ret.ct;\n }\n printf(\"%.10f %.10f\\n\", s[0].real(), s[0].imag());\n }\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 1376, "score_of_the_acc": -2, "final_rank": 2 }, { "submission_id": "aoj_1151_814116", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <complex>\n#include <cstring>\n#include <cstdlib>\n#include <string>\n#include <cmath>\n#include <cassert>\n#include <queue>\n#include <set>\n#include <map>\n#include <valarray>\n#include <bitset>\n#include <stack>\n#include <iomanip>\n#include <fstream>\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(int)(n);++i)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n#define ALL(c) (c).begin(), (c).end()\n#define chmax(a,b) (a<b?(a=b,1):0)\n#define chmin(a,b) (a>b?(a=b,1):0)\n#define valid(y,x,h,w) (0<=y&&y<h&&0<=x&&x<w)\nconst int INF = 1<<29;\nconst double EPS = 1e-8;\nconst double PI = acos(-1);\ntypedef long long ll;\ntypedef pair<int,int> pii;\n\ntypedef complex<double> P;\nP pIN() { double x,y; cin >> x >> y; return P(x,y); }\nnamespace std {\n bool operator < (const P& a, const P& b) {\n // if (abs(a-b)<EPS) return 0;\n return real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n }\nbool operator==(const P &a, const P &b) {\n return abs(a-b)<EPS;\n}\n}\ndouble cross(const P& a, const P& b) {\n return imag(conj(a)*b);\n}\ndouble dot(const P& a, const P& b) {\n return real(conj(a)*b);\n}\nint ccw(P a, P b, P c) {\n b -= a; c -= a;\n if (cross(b, c) > EPS) return +1; // counter clockwise\n if (cross(b, c) < -EPS) return -1; // clockwise\n if (dot(b, c) < -EPS) return +2; // c--a--b on line\n if (EPS < norm(b) && norm(b) < norm(c)-EPS) return -2; // a--b--c on line\n return 0;\n}\nstruct L : public vector<P> {\n L(const P &a, const P &b) {\n push_back(a); push_back(b);\n }\n L() { resize(2); }\n};\nostream &operator<<(ostream &os, const L &a) {\n os << a[0] << \" -> \" << a[1];\n return os;\n}\ntypedef vector<P> G;\n#define curr(g, i) g[i]\n#define next(g, i) g[(i+1)%g.size()]\n#define prev(g, i) g[(i+g.size()-1)%g.size()]\nL line(const G &g, int i) {\n return L(g[i],g[(i+1)%g.size()]);\n}\nstruct C {\n P p; double r;\n C(const P &p, double r) : p(p), r(r) { }\n};\nbool contain(const C &c1, const C &c2) {\n double d = abs(c1.p - c2.p);\n return d < c1.r - c2.r + EPS;\n}\nvector<L> tangentCP(const C &c, const P &p) {\n vector<L> ret;\n P vect = c.p - p;\n double d = abs(vect);\n double l = sqrt(d*d-c.r*c.r);\n if (::isnan(l)) { return ret; }\n P v1 = vect * P(l / d, c.r / d);\n P v2 = vect * P(l / d, -c.r / d);\n ret.push_back(L(p, p+v1));\n if (l > EPS)\n ret.push_back(L(p, p+v2));\n return ret;\n}\nvector<L> tangentCC(const C &c1, const C &c2) {\n vector<L> ret;\n if (abs(c1.p - c2.p) - (c1.r + c2.r) > -EPS) {\n P center = (c1.p * c2.r + c2.p * c1.r) / (c1.r + c2.r);\n ret = tangentCP(c1, center);\n }\n if (fabs(c1.r - c2.r) > EPS) {\n P out = (-c1.p * c2.r + c2.p * c1.r) / (c1.r - c2.r);\n vector<L> nret = tangentCP(c1, out);\n ret.insert(ret.end(), nret.begin(), nret.end());\n } else {\n P vect = c2.p - c1.p;\n vect /= abs(vect);\n P q1 = c1.p + vect * P(0, 1) * c1.r;\n P q2 = c1.p + vect * P(0, -1) * c1.r;\n ret.push_back(L(q1, q1 + vect));\n ret.push_back(L(q2, q2 + vect));\n }\n return ret;\n}\nP projection(const L &l, const P &p) {\n double t = dot(p-l[0], l[0]-l[1]) / norm(l[0]-l[1]);\n return l[0] + t*(l[0]-l[1]);\n}\nP reflection(const L &l, const P &p) {\n return p + P(2,0) * (projection(l, p) - p);\n}\n\nvector<P> crosspointLC(const L &l, const C &c) {\n vector<P> ret;\n P center = projection(l, c.p);\n double d = abs(center - c.p);\n double t = sqrt(c.r * c.r - d * d);\n if (::isnan(t)) { return ret; }\n P vect = (l[1] - l[0]);\n vect /= abs(vect);\n ret.push_back(center - vect * t);\n if (t > EPS) {\n ret.push_back(center + vect * t);\n }\n return ret;\n}\nbool intersectSP(const L &s, const P &p) {\n return abs(s[0]-p)+abs(s[1]-p)-abs(s[1]-s[0]) < EPS; // triangle inequality\n}\n\nvector<P> crosspointSC(const L &s, const C &c) {\n vector<P> ret;\n vector<P> nret = crosspointLC(s, c);\n FOR(it, nret)\n if (intersectSP(s, *it))\n ret.push_back(*it);\n return ret;\n}\n\n\nG g;\ndouble l,r;\nint N;\n\nstruct Res {\n P ct;\n L s;\n double ang;\n Res(const P &ct, const L &s, double ang) :\n ct(ct),s(s),ang(ang) {}\n Res() {}\n};\n\nbool win(const Res &a, const Res &b, const P &ct) {\n if (abs(a.ang-b.ang)>EPS) return a.ang > b.ang;\n return abs(a.ct-ct) < abs(b.ct-ct);\n}\nbool sameang(const P &a, const P &b) {\n return abs(cross(a,b))<EPS && dot(a,b)>0;\n}\ndouble angle(const P &a, const P &b) {\n double ret = arg(b)-arg(a);\n return (ret>=0) ? ret : ret + 2*PI;\n}\n// テ」ツδ凖」ツつッテ」ツδ暗」ツδォaテ」ツ?ィテ」ツδ凖」ツつッテ」ツδ暗」ツδォbテ」ツ?ョテゥツ鳴禿」ツ?ョティツァツ津・ツコツヲ\ndouble angle2(const P &a, const P &b) {\n return min(angle(a,b), angle(b,a));\n}\ndouble angle2_2(const P &a, const P &b) {\n double ret = abs(arg(b)-arg(a));\n return ret>PI ? 2*PI-ret : ret;\n}\n// テヲツ卍づィツィツ暗・ツ崢榲」ツつ甘・ツ?エテ」ツ?ッテ・ツ青ォテ」ツ?ソテ」ツ??・ツ債甘ヲツ卍づィツィツ暗・ツ崢榲」ツつ甘・ツ?エテ」ツ?ッテ・ツ青ォテ」ツ?セテ」ツ?ェテ」ツ??\nint quadrant(const P &a) {\n if (a.real() > 0 && a.imag() >= 0) return 0;\n if (a.real() <= 0 && a.imag() > 0) return 1;\n if (a.real() < 0 && a.imag() <= 0) return 2;\n return 3;\n}\n// テ」ツδュテ」ツδ静」ツつケテ」ツδ暗」ツ?ェティツァツ津・ツコツヲテヲツッツ氾ィツシツ?\nbool cmpAngle(const P &a, const P&b) {\n int q1 = quadrant(a);\n int q2 = quadrant(b);\n if (q1 != q2) return q1 < q2;\n return cross(a,b)>0;\n}\n// テ」ツδ凖」ツつッテ」ツδ暗」ツδォテ」ツ?ョテ・ツ崢榲ィツサツ「\nP rotate(P p, double ang) {\n return p * P(cos(ang), sin(ang));\n}\n// テ・ツ篠淌ァツつケテ・ツ堕ィテ」ツつ甘」ツ?ョテァツ崢エテァツキツ堙」ツ?ョテ・ツ崢榲ィツサツ「\nL rotate(L l, double ang) {\n return L(rotate(l[0], ang),rotate(l[1], ang));\n}\n\ndouble signedLength(const P &p1, const P &p2, const P &p) {\n P pc = projection(L(p1,p2),p);\n double res = abs(pc-p1);\n if (dot(pc-p1,p2-p1)>0) return res;\n else return -res;\n}\n\nRes find_next(const P &ct, const L& s) {\n Res res;\n res.ang = INF;\n // vertex\n REP(i,N) {\n if (ct==g[i]) continue;\n REP(j,2) {\n if (s[j]==ct) continue;\n if (abs(g[i]-ct)<abs(s[j]-ct)) {\n if (sameang(g[i]-ct,s[j]-ct)) {\n if (ccw(ct,s[j],next(g,i)) == -1 ||\n ccw(ct,s[j],prev(g,i)) == -1) {\n // stuck\n Res t(g[i], s, 0);\n if (win(res,t,ct)) res = t;\n }\n } else {\n double ang = angle(g[i]-ct,s[j]-ct);\n Res t(g[i],L(ct+rotate(s[0]-ct,-ang),ct+rotate(s[1]-ct,-ang)),ang);\n if (win(res,t,ct)) res = t;\n }\n }\n }\n }\n // edge\n REP(i,N) {\n REP(j,2) {\n if (s[j]==ct) continue;\n vector<P> ps = crosspointSC(line(g,i),C(ct,abs(s[j]-ct)));\n FOR(it, ps) {\n if (sameang(*it-ct,s[j]-ct)) {\n P a = g[i];\n P b = next(g,i);\n P c = prev(g,i);\n if (abs(signedLength(ct,s[j],a) - signedLength(ct,s[j],b)) < EPS) continue;\n if (signedLength(ct,s[j],a) > signedLength(ct,s[j],b)) {\n swap(a,b);\n c = g[(i+2)%g.size()];\n }\n if (ccw(ct,*it,a) == 1) continue;\n if (ccw(ct,*it,a) != -1) {\n continue;\n if (ccw(ct,*it,c) == 1) continue;\n }\n // cout << ct << \" \" << s[j] << \" \" << a << \" \" << b << \" :\" << signedLength(ct,s[j],a) << \" \" << signedLength(ct,s[j],b) << endl;\n // cout << *it << endl;\n // cout << ccw(ct,*it,a) << endl;\n \n // cout << *it << endl;\n // stuck\n Res t(*it, s, 0);\n if (win(res,t,ct)) res = t;\n } else {\n // cout << *it << endl;\n double ang = angle(*it-ct,s[j]-ct);\n Res t(*it,L(ct+rotate(s[0]-ct,-ang),ct+rotate(s[1]-ct,-ang)),ang);\n // cout << res.ang << \" \" << ang << endl;\n if (win(res,t,ct)) res = t;\n } \n }\n }\n }\n return res;\n}\nFILE *fp;\ndouble scale = 10;\nP diff(300, 300);\ndouble WH = 500;\nvoid outputLine(const L &l) {\n if (!fp) return;\n P a = l[0];\n P b = l[1];\n a = a*P(scale,0)+diff;\n b = b*P(scale,0)+diff;\n fprintf(fp,\"line(%f,%f,%f,%f);\\n\",a.real(),WH-a.imag(),b.real(),WH-b.imag()); \n}\nvoid outputCircle(C c) {\n if (!fp) return;\n c.p = c.p*P(scale,0) + diff;\n c.r *= scale;\n fprintf(fp, \"circle(%f,%f,%f);\\n\", c.p.real(), WH-c.p.imag(), c.r);\n}\n\n\nint main() {\n fp = fopen(\"data.js\",\"w\");\n while(cin>>l>>r>>N, l||r||N) {\n g.clear();\n double tang = r*2*PI;\n REP(i,N) g.push_back(pIN());\n REP(i,N) outputLine(line(g,i));\n L s(P(0,0),P(0,l));\n P ct(0,0);\n double ang = 0;\n outputLine(s);\n REP(i,1000) {\n Res ret = find_next(ct,s);\n // cout << ang << \" \" << ret.ang << \" \" << tang << endl;\n if (ang+ret.ang>=tang) {\n double ag = tang-ang;\n s[0] = ct+rotate(s[0]-ct,-ag);\n s[1] = ct+rotate(s[1]-ct,-ag);\n outputLine(s);\n break;\n }\n // cout << ang << \" \" << s << \":\" << ret.ang << \" \" << ret.s<< \" \" << ret.ct << endl;\n outputLine(ret.s);\n outputCircle(C(ct,l));\n ang += ret.ang;\n s = ret.s;\n ct = ret.ct;\n }\n printf(\"%.10f %.10f\\n\", s[0].real(), s[0].imag());\n }\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 1376, "score_of_the_acc": -2, "final_rank": 2 } ]
aoj_1145_cpp
Problem E: The Genome Database of All Space Life In 2300, the Life Science Division of Federal Republic of Space starts a very ambitious project to complete the genome sequencing of all living creatures in the entire universe and develop the genomic database of all space life. Thanks to scientific research over many years, it has been known that the genome of any species consists of at most 26 kinds of molecules, denoted by English capital letters ( i.e. A to Z ). What will be stored into the database are plain strings consisting of English capital letters. In general, however, the genome sequences of space life include frequent repetitions and can be awfully long. So, for efficient utilization of storage, we compress N -times repetitions of a letter sequence seq into N ( seq ) , where N is a natural number greater than or equal to two and the length of seq is at least one. When seq consists of just one letter c , we may omit parentheses and write Nc . For example, a fragment of a genome sequence: ABABABABXYXYXYABABABABXYXYXYCCCCCCCCCC can be compressed into: 4(AB)XYXYXYABABABABXYXYXYCCCCCCCCCC by replacing the first occurrence of ABABABAB with its compressed form. Similarly, by replacing the following repetitions of XY , AB , and C , we get: 4(AB)3(XY)4(AB)3(XY)10C Since C is a single letter, parentheses are omitted in this compressed representation. Finally, we have: 2(4(AB)3(XY))10C by compressing the repetitions of 4(AB)3(XY) . As you may notice from this example, parentheses can be nested. Your mission is to write a program that uncompress compressed genome sequences. Input The input consists of multiple lines, each of which contains a character string s and an integer i separated by a single space. The character string s , in the aforementioned manner, represents a genome sequence. You may assume that the length of s is between 1 and 100, inclusive. However, of course, the genome sequence represented by s may be much, much, and much longer than 100. You may also assume that each natural number in s representing the number of repetitions is at most 1,000. The integer i is at least zero and at most one million. A line containing two zeros separated by a space follows the last input line and indicates the end of the input. Output For each input line, your program should print a line containing the i -th letter in the genome sequence that s represents. If the genome sequence is too short to have the i -th element, it should just print a zero. No other characters should be printed in the output lines. Note that in this problem the index number begins from zero rather than one and therefore the initial letter of a sequence is its zeroth element. Sample Input ABC 3 ABC 0 2(4(AB)3(XY))10C 30 1000(1000(1000(1000(1000(1000(NM)))))) 999999 0 0 Output for the Sample Input 0 A C M
[ { "submission_id": "aoj_1145_10852720", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i, n) for (int i = 0; i < (n); i++)\n#define int long long\n#define FOR(i, m, n) for (int i = (m); i < (n); i++)\n#define all(x) x.begin(), x.end()\nusing pii = pair<int, int>;\nconstexpr int MOD = 1e9 + 7;\ntypedef string::const_iterator State;\nint MAX = 1000001;\nint R;\nint number(State &begin);\nstring factor(State &begin);\nbool fin = false;\nvoid consume(State &begin, char expected) {\n if (fin) begin++;\n if (*begin == expected)\n begin++;\n else {\n begin++;\n // cerr << \"expected \" << expected << \" but got \" << *begin << endl;\n // cerr << \"rest string is \";\n // while (*begin) {\n // cerr << *begin++;\n // }\n // cerr << endl;\n }\n}\nstring expression(State &begin) {\n if (fin) return \"\";\n string ret = factor(begin);\n for (;;) {\n if (ret.size() > R) {\n fin = true;\n return ret;\n }\n if (isdigit(*begin))\n ret += expression(begin);\n else if (isupper(*begin))\n ret += expression(begin);\n else if (*begin == '(')\n ret += expression(begin);\n else\n break;\n }\n return ret;\n}\nstring factor(State &begin) {\n string ret;\n if (fin) return ret;\n int cnt = 1;\n if (*begin == '(') {\n consume(begin, '(');\n ret = expression(begin);\n consume(begin, ')');\n return ret;\n } else if (isdigit(*begin)) {\n cnt = number(begin);\n // begin++;\n // cerr << cnt << endl;\n string res = factor(begin);\n // begin++;\n REP(_, cnt) {\n ret += res;\n if (ret.size() > R) {\n fin = true;\n return ret;\n }\n }\n // ret += factor(begin);\n // cerr << ret << endl;\n return ret;\n } else if (isupper(*begin)) {\n while (isupper(*begin)) {\n ret += *begin;\n begin++;\n }\n // ret += factor(begin);\n return ret;\n } else\n return ret;\n}\nint number(State &begin) {\n int ret = 0;\n if (fin) return ret;\n while (isdigit(*begin)) {\n ret *= 10;\n ret += *begin - '0';\n begin++;\n }\n // cerr << ret << endl;\n return ret;\n}\n\nbool solve() {\n string S;\n fin = false;\n int r;\n cin >> S;\n if (S == \"0\") return false;\n cin >> r;\n R = r;\n // cerr << S << endl;\n State begin = S.begin();\n string res = expression(begin);\n // cerr << res << endl;\n if (r >= res.size())\n cout << '0' << endl;\n else\n cout << res[r] << endl;\n return true;\n}\n\nsigned main() {\n while (solve())\n ;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 8644, "score_of_the_acc": -0.5168, "final_rank": 15 }, { "submission_id": "aoj_1145_10667872", "code_snippet": "#include <bits/stdc++.h>\n#include <atcoder/all>\nusing namespace std;\nusing namespace atcoder;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rrep(i,start,end) for (ll i = start;i >= (ll)(end);i--)\n#define repn(i,end) for(ll i = 0; i <= (ll)(end); i++)\n#define reps(i,start,end) for(ll i = start; i < (ll)(end); i++)\n#define repsn(i,start,end) for(ll i = start; i <= (ll)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef vector<ll> vll;\ntypedef vector<pair<ll ,ll>> vpll;\ntypedef vector<vector<ll>> vvll;\ntypedef set<ll> sll;\ntypedef map<ll , ll> mpll;\ntypedef pair<ll ,ll> pll;\ntypedef tuple<ll , ll , ll> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (ll)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1LL << 60;\nconst ld EPS = 1e-9;\n \nll lceil(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b)+1;}else{return -((-a)/b);}}\nll lfloor(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b);}else{return -((-a)/b)-1;}}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\n//0indexed\ninline ll topbit(ll a){assert(a != 0);return 63 - __builtin_clzll(a);}\ninline ll smlbit(ll a){assert(a != 0);return __builtin_ctzll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\ntypedef string::const_iterator State;\n\n\nvoid solve(string s,ll n){\n State begin = s.begin();\n stack<pll> st;\n string ret = \"\";\n while(begin != s.end()){\n if(sz(ret) > n)break;\n if(isdigit(*begin)){\n ll times = 0;\n while(begin != s.end() && isdigit(*begin)){\n times *=10;\n times += *begin - '0';\n begin++;\n }\n st.push({times,sz(ret)});\n continue;\n }\n if(*begin == '('){\n st.push({-1,-1});\n begin++;\n }else if(isupper(*begin)){\n while(begin != s.end() && isupper(*begin)){\n ret += *begin;\n begin++;\n }\n while(!st.empty() && st.top().first != -1){\n //数なので更新\n auto [times,sid] = st.top() ;\n st.pop();\n times--;\n ll eid = sz(ret);\n rep(z,times){\n if(sz(ret) > n)break;\n reps(i,sid,eid){\n ret.push_back(ret[i]);\n if(sz(ret) > n)break;\n }\n }\n }\n\n }else if(*begin == ')'){\n assert(!st.empty() && st.top().first == -1 );\n st.pop();\n while(!st.empty() && st.top().first != -1){\n //数なので更新\n auto [times,sid] = st.top() ;\n st.pop();\n times--;\n ll eid = sz(ret);\n rep(z,times){\n if(sz(ret) > n)break;\n reps(i,sid,eid){\n ret.push_back(ret[i]);\n if(sz(ret) > n)break;\n }\n }\n }\n begin++;\n }\n }\n if(sz(ret) > n){\n cout << ret[n] << endl;\n }else{\n cout << 0 << endl;\n }\n}\n\nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true){\n Str(s);\n LL(n);\n if(s == \"0\" && n == 0){\n break;\n }\n solve(s,n);\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6252, "score_of_the_acc": -0.3007, "final_rank": 9 }, { "submission_id": "aoj_1145_10662035", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n// #pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = acos(-1.0);\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do { cout << #var << \" :\\n\"; view(var); } while(0)\ntemplate<typename T>void view(const T& e) {cout << e;}\ntemplate<typename T1, typename T2>void view(const pair<T1, T2>& p) {cout << \"{\" << p.first << \", \" << p.second << \"}\";}\ntemplate<typename T>void view(const vc<T>& v) {for (const auto& e : v) {view(e);cout << \" \";} cout << endl;}\ntemplate<typename T>void view(const vv<T>& vv) {for (const auto& v : vv) {view(v);cout << \" \";} cout << endl;}\ntemplate<typename T>void view(const set<T>& s) {for (const auto& e : s) {view(e);cout << \" \";} cout << endl;}\ntemplate<typename T>void view(const unordered_set<T>& s) {for (const auto& e : s) {view(e);cout << \" \";} cout << endl;}\ntemplate<typename T1, typename T2>void view(const map<T1, T2>& mp){for (const auto& e : mp) {view(e);cout << \" \";} cout << endl;}\n\nstring S;\n\nstring f(int l, int r){\n bool ok = true;\n srep(i, l, r) if (isdigit(S[i])){\n ok = false;\n break;\n }\n if (ok) return S.substr(l, r - l);\n vc<pair<int, int>> block;\n int c = 0;\n srep(i, l, r){\n if (S[i] == '(') c++;\n if (len(block) == 0 || (!isdigit(S[i - 1]) && isdigit(S[i]) && c == 0) || (S[i - 1] == ')' && c == 0)){\n block.push_back({i, i + 1});\n }else{\n block.back().second++;\n }\n if (S[i] == ')') c--;\n }\n string ret = \"\";\n for (auto [nl, nr] : block){\n string unit = \"\";\n int num = 1;\n if (isdigit(S[nl])){\n num = 0;\n while (isdigit(S[nl])){\n num = num * 10 + (S[nl] - '0');\n nl++;\n }\n }\n if (S[nl] == '(') unit = f(nl + 1, nr - 1);\n else unit = f(nl, nr);\n rep(i, num){\n ret += unit;\n if (len(ret) > 1e6) return ret;\n }\n }\n return ret;\n}\n\nint main(){\n while (true){\n int k; cin >> S >> k;\n if (S == \"0\") break;\n string genom = f(0, len(S));\n if (k >= len(genom)) cout << 0 << endl;\n else cout << genom[k] << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 7940, "score_of_the_acc": -0.4568, "final_rank": 12 }, { "submission_id": "aoj_1145_10604632", "code_snippet": "//#pragma GCC optimize(\"O3\")\n#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,n) for (ll i=0;i<(ll)n;i++)\n#define rrep(i,n) for (ll i=n-1;i>=(ll)0;i--)\n#define loop(i,m,n) for(ll i=m;i<=(ll)n;i++)\n#define rloop(i,m,n) for(ll i=m;i>=(ll)n;i--)\n#define vl vector<ll>\n#define vvl vector<vector<ll>>\n#define vdbg(a) rep(ii,a.size()){cout<<a[ii]<<\" \";}cout<<endl;\n#define vpdbg(a) rep(ii,a.size()){cout<<\"{\"<<a[ii].first<<\",\"<<a[ii].second<<\"} \";}cout<<endl;\n#define vvdbg(a) rep(ii,a.size()){rep(jj,a[ii].size()){cout<<a[ii][jj]<<\" \";}cout<<endl;}\n#define setdbg(a) for(const auto & ii:a){cout<<ii<<\" \";}cout<<endl;\n#define inf 1e9\n#define mod 998244353LL\n//#define mod 1000000007LL\n#define eps 0.000000001\nrandom_device rnd;// 非決定的な乱数生成器\nmt19937 mt(rnd());// メルセンヌ・ツイスタの32ビット版、引数は初期シード\n\n//#include<boost/multiprecision/cpp_int.hpp>\n//#define bbi boost::multiprecision::cpp_int\n//#include<atcoder/lazysegtree>\n\n\n//整数同士の累乗の計算をする。\nll power(ll A, ll B) {\n\tll result = 1;\n\tfor (ll i=0;i<B;i++){\n\t\tresult *= A;\n\t}\n\treturn result;\n}\n\n// nのk乗をmodで割った余りを計算\nll power_mod(ll n, ll k){\n\tlong long result = 1;\n\twhile (k > 0){\n\t\tif ((k&1) ==1)result=(result*n)%mod;\n\t\tn=n*n%mod;\n\t\tk >>= 1;\n\t}\n\treturn result;\n}\n\n\n//受け取った2次元文字の外側に、文字pをコーティングする。\nvector<string> pad(vector<string> &s,char p){\n\tll h=s.size();\n\tll w=s[0].size();\n\tvector<string> res(h+2,string(w+2,p));\n\trep(i,h)rep(j,w)res[i+1][j+1]=s[i][j];\n\treturn res;\n}\n\n// Union-Find\nstruct UnionFind {\n\tvector<int> par, siz;\n\tUnionFind(int n) : par(n, -1) , siz(n, 1) { }\n\t// 根を求める\n\tint root(int x) {\n\t\tif (par[x] == -1) return x;\n\t\telse return par[x] = root(par[x]);\n\t}\n\t// x と y が同じグループに属するかどうか (根が一致するかどうか)\n\tbool issame(int x, int y) {\n\t\treturn root(x) == root(y);\n\t}\n\t// x を含むグループと y を含むグループとを併合する\n\tbool unite(int x, int y) {\n\t\tx = root(x), y = root(y);\n\t\tif (x == y) return false; \n\t\tif (siz[x] < siz[y]) swap(x, y);\n\t\tpar[y] = x;\n\t\tsiz[x] += siz[y];\n\t\treturn true;\n\t}\n\t// x を含むグループのサイズ\n\tint size(int x) {\n\t\treturn siz[root(x)];\n\t}\n};\n\n\n//グリッド問題等用\nvl dx={1,0,-1,0};\nvl dy={0,1,0,-1};\n\nstring s;\nll k;\nchar ans='0';\n\n//\nll dfs(ll i){\n\tif(k==0)return 0;\n\twhile(i!=s.size()&&s[i]!=')'){\n\t\tif('A'<=s[i]&&s[i]<='Z'){\n\t\t\tk--;\n\t\t\tif(k==0){\n\t\t\t\tans=s[i];\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}else if('0'<=s[i]&&s[i]<='9'){\n\t\t\tll num=0;\n\t\t\twhile('0'<=s[i]&&s[i]<='9'){\n\t\t\t\tnum*=10;\n\t\t\t\tnum+=s[i]-'0';\n\t\t\t\ti++;\n\t\t\t}\n\t\t\tif(s[i]=='('){\n\t\t\t\tll tmp;\n\t\t\t\trep(j,num)tmp=dfs(i+1);\n\t\t\t\ti=tmp;\n\t\t\t}else{\n\t\t\t\trep(j,num){\n\t\t\t\t\tk--;\n\t\t\t\t\tif(k==0){\n\t\t\t\t\t\tans=s[i];\n\t\t\t\t\t\treturn 0;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(k==0)return 0;\n\t\t}\n\t\ti++;\n\t}\n\treturn i;\n}\n\nll solve(){\n\tcin>>s>>k;\n\tif(s==\"0\"){return 1;}\n\tk++;\n\tans='0';\n\tdfs(0);\n\n\tcout<<ans<<endl;\n\treturn 0;\n}\n\n//メイン\nint main(){\n\twhile(solve()==0);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3336, "score_of_the_acc": -0.0489, "final_rank": 5 }, { "submission_id": "aoj_1145_9416787", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint solve() {\n string s;\n int k;\n cin >> s >> k;\n if (s == \"0\") return 1;\n string ans;\n\n auto add = [&](char c) -> bool {\n ans.push_back(c);\n if (ans.size() > k) return true;\n return false;\n };\n\n using Iter = string::const_iterator&;\n\n auto num = [&](Iter it) {\n int v = 0;\n while (isdigit(*it)) {\n v = 10 * v + (*it - '0');\n it++;\n }\n return v;\n };\n\n auto dfs = [&](auto self, Iter it) -> pair<bool, string> {\n string cur;\n while (it != s.end() && *it != ')') {\n if (isdigit(*it)) {\n int rp = num(it);\n if (isalpha(*it)) {\n char c = *it;\n it++;\n for (int i = 0; i < rp; i++) {\n if (add(c)) {\n return {true, \"\"};\n }\n cur.push_back(c);\n }\n } else {\n assert(*it == '(');\n it++;\n auto [f, t] = self(self, it);\n if (f) return {f, t};\n assert(*it == ')');\n it++;\n for (auto c: t) {\n cur.push_back(c);\n }\n for (int i = 1; i < rp; i++) {\n for (auto c: t) {\n if (add(c)) {\n return {true, \"\"};\n }\n cur.push_back(c);\n }\n }\n }\n } else {\n char c = *it;\n it++;\n if (add(c)) return {true, \"\"};\n cur.push_back(c);\n }\n }\n return {false, cur};\n };\n auto it = s.cbegin();\n dfs(dfs, it);\n if (k < ans.size()) cout << ans[k] << '\\n';\n else cout << 0 << '\\n';\n return 0;\n}\nint main(){\n while (!solve());\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 8380, "score_of_the_acc": -0.5256, "final_rank": 17 }, { "submission_id": "aoj_1145_9407862", "code_snippet": "#include<bits/stdc++.h>\n//#pragma GCC target(\"avx,avx2\")\n//#pragma GCC optimize(\"O3\")\n//#pragma GCC optimize(\"unroll-loops\")\n#ifdef LOCAL\n#include <debug.hpp>\n#define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define debug(...) (static_cast<void>(0))\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nusing pll = pair<ll,ll>;\nusing pii = pair<int,int>;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\nusing vvvl = vector<vvl>;\nusing vul = vector<ull>;\nusing vpii = vector<pii>;\nusing vvpii = vector<vpii>;\nusing vpll = vector<pll>;\nusing vs = vector<string>;\ntemplate<class T> using pq = priority_queue<T,vector<T>, greater<T>>;\n#define overload4(_1, _2, _3, _4, name, ...) name\n#define overload3(a,b,c,name,...) name\n#define rep1(n) for (ll UNUSED_NUMBER = 0; UNUSED_NUMBER < (n); ++UNUSED_NUMBER)\n#define rep2(i, n) for (ll i = 0; i < (n); ++i)\n#define rep3(i, a, b) for (ll i = (a); i < (b); ++i)\n#define rep4(i, a, b, c) for (ll i = (a); i < (b); i += (c))\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep1(n) for(ll i = (n) - 1;i >= 0;i--)\n#define rrep2(i,n) for(ll i = (n) - 1;i >= 0;i--)\n#define rrep3(i,a,b) for(ll i = (b) - 1;i >= (a);i--)\n#define rrep4(i,a,b,c) for(ll i = (a) + ((b)-(a)-1) / (c) * (c);i >= (a);i -= c)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n#define all1(i) begin(i) , end(i)\n#define all2(i,a) begin(i) , begin(i) + a\n#define all3(i,a,b) begin(i) + a , begin(i) + b\n#define all(...) overload3(__VA_ARGS__, all3, all2, all1)(__VA_ARGS__)\n#define sum(...) accumulate(all(__VA_ARGS__),0LL)\ntemplate<class T> bool chmin(T &a, const T &b){ if(a > b){ a = b; return 1; } else return 0; }\ntemplate<class T> bool chmax(T &a, const T &b){ if(a < b){ a = b; return 1; } else return 0; }\ntemplate<class T> auto min(const T& a){return *min_element(all(a));}\ntemplate<class T> auto max(const T& a){return *max_element(all(a));}\ntemplate<class... Ts> void in(Ts&... t);\n#define INT(...) int __VA_ARGS__; in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__; in(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__; in(__VA_ARGS__)\n#define CHR(...) char __VA_ARGS__; in(__VA_ARGS__)\n#define DBL(...) double __VA_ARGS__; in(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; in(__VA_ARGS__)\n#define VEC(type, name, size) vector<type> name(size); in(name)\n#define VV(type, name, h, w) vector<vector<type>> name(h, vector<type>(w)); in(name)\nll intpow(ll a, ll b){ ll ans = 1; while(b){if(b & 1) ans *= a; a *= a; b /= 2;} return ans;}\nll modpow(ll a, ll b, ll p){ ll ans = 1; a %= p;if(a < 0) a += p;while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nbool is_clamp(ll val,ll low,ll high) {return low <= val && val < high;}\nvoid Yes() {cout << \"Yes\\n\";return;}\nvoid No() {cout << \"No\\n\";return;}\nvoid YES() {cout << \"YES\\n\";return;}\nvoid NO() {cout << \"NO\\n\";return;}\ntemplate <typename T>\nT floor(T a, T b) {return a / b - (a % b && (a ^ b) < 0);}\ntemplate <typename T>\nT ceil(T x, T y) {return floor(x + y - 1, y);}\ntemplate <typename T>\nT bmod(T x, T y) {return x - y * floor(x, y);}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {T q = floor(x, y);return {q, x - q * y};}\nnamespace IO{\n#define VOID(a) decltype(void(a))\nstruct setting{ setting(){cin.tie(nullptr); ios::sync_with_stdio(false);fixed(cout); cout.precision(12);}} setting;\ntemplate<int I> struct P : P<I-1>{};\ntemplate<> struct P<0>{};\ntemplate<class T> void i(T& t){ i(t, P<3>{}); }\nvoid i(vector<bool>::reference t, P<3>){ int a; i(a); t = a; }\ntemplate<class T> auto i(T& t, P<2>) -> VOID(cin >> t){ cin >> t; }\ntemplate<class T> auto i(T& t, P<1>) -> VOID(begin(t)){ for(auto&& x : t) i(x); }\ntemplate<class T, size_t... idx> void ituple(T& t, index_sequence<idx...>){in(get<idx>(t)...);}\ntemplate<class T> auto i(T& t, P<0>) -> VOID(tuple_size<T>{}){ituple(t, make_index_sequence<tuple_size<T>::value>{});} \n#undef VOID\n}\n#define unpack(a) (void)initializer_list<int>{(a, 0)...}\ntemplate<class... Ts> void in(Ts&... t){ unpack(IO :: i(t)); }\n#undef unpack\nconstexpr long double PI = 3.141592653589793238462643383279L;\ntemplate <class F> struct REC {\n F f;\n REC(F &&f_) : f(forward<F>(f_)) {}\n template <class... Args> auto operator()(Args &&...args) const { return f(*this, forward<Args>(args)...); }};\n\n//constexpr int mod = 998244353;\nconstexpr int mod = 1000000007;\ntemplate <typename T> \nstruct Edge {\n\tint from, to;\n\tT cost;\n\tEdge() = default;\n\tEdge(int _to, T _cost) : from(-1), to(_to), cost(_cost) {}\n\tEdge(int _from, int _to, T _cost) : from(_from), to(_to), cost(_cost) {}\n\tbool operator < (const Edge &a) const { return cost < a.cost; }\n\tbool operator > (const Edge &a) const { return cost > a.cost; }\n Edge &operator = (const int &x) {\n to = x;\n return *this;\n }\n operator int() const { return to; }\n friend ostream operator<<(ostream &os, Edge &edge) { return os << edge.to; }\n};\ntemplate <typename T>\nusing Edges = vector<Edge<T>>;\ntemplate <typename T>\nusing Wgraph = vector<Edges<T>>;\nusing Ugraph = vector<vector<int>>;\nUgraph uinput(int N, int M = -1, bool is_directed = false, int origin = 1) {\n Ugraph g(N);\n if (M == -1) M = N - 1;\n while(M--) {\n int a,b;\n cin >> a >> b;\n a -= origin, b -= origin;\n g[a].push_back(b);\n if(!is_directed) g[b].push_back(a);\n }\n return g;\n}\ntemplate <typename T>\nWgraph<T> winput(int N, int M = -1, bool is_directed = false,int origin = 1) {\n Wgraph<T> g(N);\n if (M == -1) M = N - 1;\n while(M--) {\n int a,b;\n T c;\n cin >> a >> b >> c;\n a -= origin, b -= origin;\n g[a].emplace_back(b,c);\n if(!is_directed) g[b].emplace_back(a,c);\n }\n return g;\n}\nint K;\nstring term(string &s,int &id);\nstring expression(string &s,int &id);\nstring factor(string &s,int &id);\nint number(string &s,int &id) {\n int ret = 0;\n while(isdigit(s[id])) {\n ret *= 10;\n ret += s[id++] - '0';\n }\n return ret;\n}\nstring factor(string &s,int &id) {\n\tint co = 1;\n if(isdigit(s[id])) co = number(s,id);\n\t//debug(co);\n if(s[id] == '(') {\n id++;\n string ret = expression(s,id);\n assert(s[id] == ')');\n id++;\n\t\tstring ret2;\n\t\trep(i,co) {\n\t\t\trep(j,ret.size()) {\n\t\t\t\tret2 += ret[j];\n\t\t\t\tif(ret2.size() == K) break; \n\t\t\t}\n\t\t\tif(ret2.size() == K) break;\n\t\t}\n return ret2;\n }\n\tstring ret;\n\trep(i,co) {\n\t\tret += s[id];\n\t\tif(ret.size() == K) break;\n\t}\n\tid++;\n\treturn ret;\n}\n// string term(string &s,int &id) {\n// int ret = factor(s,id);\n// while(1) {\n// if(s[id] == '*') {\n// id++;\n// ret *= factor(s,id);\n// }\n// else if(s[id] == '/') {\n// id++;\n// ret /= factor(s,id);\n// }\n// else break;\n// }\n// return ret;\n// }\nstring expression(string &s,int &id) {\n string ret = factor(s,id);\n while(id < s.size()) {\n if(s[id] == ')') {\n\t\t\tbreak;\n }\n else {\n\t\t\tauto ret2 = factor(s,id);\n\t\t\t//debug(ret2);\n\t\t\tif(ret.size() < K) {\n\t\t\t\tint c = K - (int)ret.size();\n\t\t\t\trep(i,min(c,(int)ret2.size())) {\n\t\t\t\t\tret += ret2[i];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n }\n return ret;\n}\n\nint main() {\n\twhile(1) {\n\t\tSTR(s);\n\t\tcin >> K;\n\t\tK++;\n\t\tif(s == \"0\") break;\n\t\tint id = 0;\n\t\tstring X = expression(s,id);\n\t\tdebug(X);\n\t\tif(X.size() < K) cout << 0 << '\\n';\n\t\telse cout << X[K-1] << '\\n';\n\t}\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 7780, "score_of_the_acc": -0.516, "final_rank": 14 }, { "submission_id": "aoj_1145_9325450", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < n; ++i)\ntypedef long long ll;\nusing namespace std;\n\nint M;\n\nclass Result {\n public:\n string s;\n\n Result() : s(\"\") {}\n\n Result &operator+=(const Result &rhs) {\n rep(i, rhs.s.size()) {\n if (s.size() <= M) s += rhs.s[i];\n else break;\n }\n return *this;\n }\n};\n\nvector<string> OPS = {\"+\"};\nResult parse(const string &s, size_t &i, size_t p = 0) {\n if (p == OPS.size()) {\n int coef = 0;\n if (isdigit(s[i])) {\n while (isdigit(s[i])) {\n coef *= 10;\n coef += s[i++] - '0';\n }\n }\n if (coef == 0) coef = 1;\n if (s[i] == '(') {\n Result res = parse(s, ++i, 0);\n assert(s[i] == ')');\n ++i;\n\n string s = res.s;\n rep(i, coef - 1) {\n if (res.s.size() <= M) res.s += s;\n else break;\n }\n return res;\n }\n if (isupper(s[i])) {\n Result res;\n while (isupper(s[i])) {\n res.s += s[i++];\n }\n\n string s = res.s;\n rep(i, coef - 1) {\n if (res.s.size() <= M) res.s += s;\n else break;\n }\n return res;\n }\n assert(false);\n }\n\n Result res = parse(s, i, p + 1);\n while (i < s.length()) {\n char op = s[i];\n if (OPS[p].find(op) == string::npos) break;\n Result rhs = parse(s, ++i, p + 1);\n if (op == '+') res += rhs;\n }\n return res;\n}\n\nvoid solve(string S, int idx) {\n M = idx;\n\n string T;\n for (char c : S) {\n if (!T.empty()) {\n if (T.back() == ')' && (isdigit(c) || isupper(c))) {\n T += \"+\";\n }\n if (isupper(T.back()) && isdigit(c)) {\n T += \"+\";\n }\n }\n T += c;\n }\n\n size_t i = 0;\n Result res = parse(T, i);\n\n if (res.s.size() > idx) cout << res.s[idx];\n else cout << 0;\n cout << endl;\n}\n\nint main() {\n cin.tie(0)->sync_with_stdio(0);\n\n string S;\n int idx;\n while (cin >> S >> idx) {\n if (S == \"0\" && idx == 0) break;\n solve(S, idx);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 7636, "score_of_the_acc": -0.4313, "final_rank": 11 }, { "submission_id": "aoj_1145_9240073", "code_snippet": "// 11:28\n#include<bits/stdc++.h>\nusing namespace std;\nusing state = string::iterator;\nint K;\nstring S;\nstring T;\nstate it0;\nbool done = 0;\n\nstring expr(state&);\n\nint num(state& it){\n int res = 0;\n while('0' <= *it && *it <= '9'){\n res *= 10;\n res += int(*it - '0');\n // cerr << *it;\n it++;\n }\n return res;\n}\n\nstring alps(state& it){\n string res = \"\";\n //cerr << *it;\n if(*it == '('){\n it++;\n res = expr(it);\n if(done) return \"\";\n if(*it != ')'){\n cerr << \"( \\'\" << *it << \"\\' ) found (at \" << it - it0 << \") in alps0\\n\";\n cerr << S << endl;\n exit(1);\n }\n //else cerr << \"?\";\n it++;\n }\n else if('A' <= *it && *it <= 'Z'){\n T += *it;\n //cout << *it;\n it++;\n }\n else{\n //cerr << \"( \\'\" << *it << \"\\' ) found (at \" << it - it0 << \") in alps\\n\";\n //cerr << S << endl;\n exit(1);\n }\n if(K < (int)T.size()){\n done = 1; return \"\";\n }\n return res;\n}\n\n// <expr>\nstring expr(state& it){\n static int depth = 0;\n depth++;\n // cout << depth << \" \";\n //cerr << \"!\";\n\n string res = \"\";\n int resI = 0;\n\n if(*it == '\\0' || *it == ')'){\n //cerr << \"?\";\n depth--; return \"\";\n }\n //cerr << *it;\n int n = 1;\n //cerr << \"### \" << *it << \" ###\";\n if('0' <= *it && *it <= '9'){\n n = num(it);\n if(done){\n depth--; return \"\";\n }\n }\n if(done){\n depth--; return \"\";\n }\n while(n--){\n state it2 = it;\n alps(it2);\n if(K < (int)(res.size() + T.size())){\n T += res;\n done = 1;\n depth--; return \"\";\n }\n if(n == 0) it = it2;\n }\n if(done) return \"\";\n\n if(*it != ')' && *it != '\\0'){\n depth--;\n res += expr(it);\n depth++;\n }\n \n if(K < (int)T.size()){\n done = 1;\n depth--; return \"\";\n }\n depth--; return \"\";\n return res;\n}\n\nint main(){\n while(1){\n cin >> S >> K;\n S = S + \")\";\n T = \"\";\n if(S == \"0)\" && K == 0) break;\n //cerr << S << \" !!! \" ;\n\n it0 = S.begin();\n done = 0;\n expr(it0);\n\n //cout << T << \" \";\n if((int)T.size() <= K) cout << 0 << endl;\n else cout << T[K] << endl;\n }\n}", "accuracy": 1, "time_ms": 910, "memory_kb": 4944, "score_of_the_acc": -0.4042, "final_rank": 10 }, { "submission_id": "aoj_1145_9003721", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\n} // namespace macro\n\nusing namespace macro;\n#line 3 \"A.cpp\"\n\nstring s, k_in;\nint i, k, n;\nconst int len = 1'000'001;\nstring expr() {\n string res = \"\";\n while(i < n) {\n if(isalpha(s[i])) {\n res += s[i];\n i++;\n if(len < res.size()) res.resize(len);\n } else if(isdigit(s[i])) {\n int number = 0;\n while(isdigit(s[i])) {\n number = number * 10 + (s[i] - '0');\n i++;\n }\n\n if(s[i] == '(') {\n i++;\n string t = expr();\n for(int _ : rep(number)) {\n res += t;\n if(len < res.size()) res.resize(len);\n }\n assert(s[i] == ')');\n i++;\n } else {\n assert(isalpha(s[i]));\n for(int _ : rep(number)) {\n res += s[i];\n if(len < res.size()) res.resize(len);\n }\n i++;\n }\n } else break;\n }\n return res;\n}\n\nint main() {\n while(true) {\n cin >> s >> k_in;\n if(s == \"0\" and k_in == \"0\") return 0;\n i = 0;\n k = stoi(k_in);\n n = s.size();\n\n string t = expr();\n debug(t);\n if(k < t.size()) {\n print(t[k]);\n } else {\n print(0);\n }\n }\n}", "accuracy": 1, "time_ms": 3930, "memory_kb": 13868, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_1145_8861618", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <string>\nusing namespace std;\nint N;\n\nstring dfs(const string &s, int start, int end) {\n string r;\n long long n = -1;\n for (int i = start; i < end;) {\n if ('0' <= s[i] && s[i] <= '9') {\n if (n < 0)\n n = s[i] - '0';\n else\n n = n * 10 + s[i] - '0';\n i++;\n } else if (s[i] == '(') {\n if (n < 0)\n n = 1;\n int cnt = 1, j = i + 1;\n for (; cnt; j++) {\n if (s[j] == '(')\n cnt++;\n else if (s[j] == ')')\n cnt--;\n }\n string r0 = dfs(s, i + 1, j - 1);\n for (int _ = 0; _ < n && r.size() <= N; _++) {\n r += r0;\n }\n n = -1;\n i = j;\n } else {\n if (n < 0)\n n = 1;\n for (int _ = 0; _ < n && r.size() <= N; _++) {\n r += s[i];\n }\n n = -1;\n i++;\n }\n if (r.size() > N)\n break;\n }\n return r;\n}\n\nint main() {\n for (;;) {\n string s;\n cin >> s >> N;\n if (s == \"0\")\n break;\n string r = dfs(s, 0, s.size());\n printf(\"%c\\n\", r.size() > N ? r[N] : '0');\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 8712, "score_of_the_acc": -0.5231, "final_rank": 16 }, { "submission_id": "aoj_1145_8861614", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\nusing namespace std;\n\nint N;\n\nvoid appendChar(vector<char>& result, char c, long long n) {\n for (int i = 0; i < n && result.size() <= N; ++i) {\n result.push_back(c);\n }\n}\n\nvoid parseString(const string& s, int start, int end, vector<char>& result) {\n long long n = -1;\n for (int i = start; i < end && result.size() <= N;) {\n if ('0' <= s[i] && s[i] <= '9') {\n n = (n < 0 ? 0 : n * 10) + (s[i] - '0');\n ++i;\n } else if (s[i] == '(') {\n if (n < 0)\n n = 1;\n int cnt = 1, j = i + 1;\n for (; cnt;) {\n if (s[j] == '(')\n ++cnt;\n else if (s[j] == ')')\n --cnt;\n ++j;\n }\n for (int _ = 0; _ < n && result.size() <= N; _++) {\n parseString(s, i + 1, j - 1, result);\n }\n n = -1;\n i = j;\n } else {\n if (n < 0)\n n = 1;\n appendChar(result, s[i], n);\n n = -1;\n ++i;\n }\n }\n}\n\nint main() {\n for (;;) {\n string s;\n cin >> s >> N;\n if (s == \"0\")\n break;\n vector<char> result;\n parseString(s, 0, s.size(), result);\n cout << ((result.size() > N) ? result[N] : '0') << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 5048, "score_of_the_acc": -0.2455, "final_rank": 7 }, { "submission_id": "aoj_1145_8861612", "code_snippet": "#include <cstdlib>\n#include <iostream>\n#include <string>\n\nint cket(const std::string &str, int i) {\n int n = 1;\n while (n != 0) {\n ++i;\n if (str[i] == '(') ++n;\n if (str[i] == ')') --n;\n }\n return i;\n}\n\nint n;\n\nchar expand(const std::string &str) {\n std::string res;\n for (int i = 0; i < str.size(); ++i) {\n if (isdigit(str[i])) {\n int j = 1;\n while (isdigit(str[i + j])) ++j;\n int num = std::atoi(str.substr(i, j).c_str());\n int s, e;\n if (str[i + j] == '(') {\n int k = cket(str, i + j + 1);\n s = i + j + 1;\n e = k - (i + j + 1);\n i = k;\n } else {\n s = i + j;\n e = 1;\n i = i + j;\n }\n for (int l = 0; l < num; ++l) {\n char a = expand(str.substr(s, e));\n if (a != '0') return a;\n }\n } else {\n if (n == 0) {\n return str[i];\n }\n n--;\n }\n }\n return '0';\n}\n\nint main(void) {\n while (true) {\n std::string str;\n std::cin >> str >> n;\n if (str == \"0\" && n == 0) break;\n std::cout << expand(str) << std::endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1100, "memory_kb": 3060, "score_of_the_acc": -0.2784, "final_rank": 8 }, { "submission_id": "aoj_1145_8861611", "code_snippet": "#include <cstdlib>\n#include <iostream>\n#include <string>\n\nint n;\n\nchar expand(const std::string &str, int s, int e) {\n for (int i = s; i < e; ++i) {\n if (isdigit(str[i])) {\n int num = 0;\n while (isdigit(str[i])) {\n num = num * 10 + (str[i] - '0');\n i++;\n }\n int s_new, e_new;\n if (str[i] == '(') {\n int k = i + 1;\n int count = 1;\n while (count != 0) {\n if (str[k] == '(')\n count++;\n if (str[k] == ')')\n count--;\n k++;\n }\n s_new = i + 1;\n e_new = k - 1;\n i = k - 1;\n } else {\n s_new = i;\n e_new = i + 1;\n }\n for (int l = 0; l < num; ++l) {\n char a = expand(str, s_new, e_new);\n if (a != '0')\n return a;\n }\n } else {\n if (n == 0) {\n return str[i];\n }\n n--;\n }\n }\n return '0';\n}\n\nint main(void) {\n while (true) {\n std::string str;\n std::cin >> str >> n;\n if (str == \"0\" && n == 0)\n break;\n std::cout << expand(str, 0, str.size()) << std::endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3172, "score_of_the_acc": -0.0362, "final_rank": 2 }, { "submission_id": "aoj_1145_8861609", "code_snippet": "#include <cstdlib>\n#include <iostream>\n#include <string>\n\nint cket(const std::string &str, int i) {\n int n = 1;\n for (; i < str.size(); ++i) {\n if (str[i] == '(')\n n++;\n if (str[i] == ')')\n n--;\n if (n == 0)\n break;\n }\n return i;\n}\n\nint n;\nchar expand(const std::string &str, int s, int e) {\n std::string res;\n for (int i = s; i < s + e; ++i) {\n if (isdigit(str[i])) {\n int j = 1;\n while (isdigit(str[i + j]))\n j++;\n int num = std::atoi(str.substr(i, j).c_str());\n int se, ee;\n if (str[i + j] == '(') {\n int k;\n k = cket(str, i + j + 1);\n se = i + j + 1;\n ee = k - (i + j + 1);\n i = k;\n } else {\n se = i + j;\n ee = 1;\n i = i + j;\n }\n char a = '0';\n for (int l = 0; l < num; ++l) {\n a = expand(str, se, ee);\n if (a != '0')\n return a;\n }\n } else {\n if (n == 0) {\n return str[i];\n }\n n--;\n }\n }\n return '0';\n}\n\nint main(void) {\n while (true) {\n std::string str;\n std::cin >> str >> n;\n if (str == \"0\" && n == 0)\n break;\n std::cout << expand(str, 0, str.size()) << std::endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 3056, "score_of_the_acc": -0.0408, "final_rank": 4 }, { "submission_id": "aoj_1145_8861603", "code_snippet": "#include <iostream>\n#include <string>\n#include <cstdlib>\n\nint cket(const std::string &str, int i) {\n int n = 1;\n for (; i < str.size(); ++i) {\n if (str[i] == '(')\n n++;\n else if (str[i] == ')')\n n--;\n if (n == 0)\n break;\n }\n return i;\n}\n\nint n;\nchar expand(const std::string &str, int s, int e) {\n for (int i = s; i < s+e; ++i) {\n if (isdigit(str[i])) {\n int num = str[i] - '0';\n int j = i + 1;\n while (isdigit(str[j])) {\n num = num * 10 + (str[j] - '0');\n ++j;\n }\n i = j - 1;\n if (str[i + 1] == '(') {\n int k = cket(str, i + 2);\n for (int l = 0; l < num; ++l) {\n char a = expand(str, i + 2, k - (i + 2));\n if (a != '0')\n return a;\n }\n i = k;\n } else {\n for (int l = 0; l < num; ++l) {\n if (n == 0) {\n return str[i + 1];\n }\n n--;\n }\n i++;\n }\n } else {\n if (n == 0) {\n return str[i];\n }\n n--;\n }\n }\n return '0';\n}\n\nint main() {\n while (true) {\n std::string str;\n std::cin >> str >> n;\n if (str == \"0\" && n == 0)\n break;\n std::cout << expand(str, 0, str.size()) << std::endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3132, "score_of_the_acc": -0.0376, "final_rank": 3 }, { "submission_id": "aoj_1145_8819313", "code_snippet": "#include <cstdlib>\n#include <iostream>\n#include <string>\n\nint cket(const std::string &str, int i) {\n int n = 1;\n for (; i < str.size(); ++i) {\n if (str[i] == '(')\n n++;\n if (str[i] == ')')\n n--;\n if (n == 0)\n break;\n }\n return i;\n}\n\nint n;\n\nchar expand(const std::string &str, int s, int e) {\n std::string res;\n for (int i = s; i < s + e; ++i) {\n bool isDigit = isdigit(str[i]);\n if (isDigit) {\n int num = 0;\n while (isDigit) {\n num = num * 10 + (str[i] - '0');\n i++;\n isDigit = isdigit(str[i]);\n }\n int start, end;\n if (str[i] == '(') {\n int k = cket(str, i + 1);\n start = i + 1;\n end = k - start;\n i = k;\n } else {\n start = i;\n end = 1;\n }\n for (int l = 0; l < num; ++l) {\n char a = expand(str, start, end);\n if (a != '0')\n return a;\n }\n } else {\n if (n == 0) {\n return str[i];\n }\n n--;\n }\n }\n return '0';\n}\n\nint main(void) {\n while (true) {\n std::string str;\n std::cin >> str >> n;\n if (str == \"0\" && n == 0)\n break;\n std::cout << expand(str, 0, str.size()) << std::endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3168, "score_of_the_acc": -0.0359, "final_rank": 1 }, { "submission_id": "aoj_1145_8819308", "code_snippet": "#include <iostream>\n#include <string>\n#include <sstream>\n\nint cket(const std::string &str, int i) {\n int n = 1;\n for (; i < str.size(); ++i) {\n if (str[i] == '(')\n n++;\n if (str[i] == ')')\n n--;\n if (n == 0)\n break;\n }\n return i;\n}\n\nint n;\nchar expand(const std::string &str, int start, int len) {\n for (int i = start; i < start + len; ++i) {\n if (isdigit(str[i])) {\n int j = 1;\n while (isdigit(str[i + j]))\n j++;\n std::stringstream ss(str.substr(i, j));\n int num;\n ss >> num;\n int s, e, idx = i + j;\n if (str[idx] == '(') {\n int k;\n k = cket(str, idx + 1);\n s = idx + 1;\n e = k - s;\n i = k;\n } else {\n s = idx;\n e = 1;\n i = idx;\n }\n for (int l = 0; l < num; ++l) {\n char a = expand(str, s, e);\n if (a != '0')\n return a;\n }\n } else {\n if (n == 0) {\n return str[i];\n }\n n--;\n }\n }\n return '0';\n}\n\nint main(void) {\n while (true) {\n std::string str;\n std::cin >> str >> n;\n if (str == \"0\" && n == 0)\n break;\n std::cout << expand(str, 0, str.size()) << std::endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 700, "memory_kb": 3168, "score_of_the_acc": -0.1864, "final_rank": 6 }, { "submission_id": "aoj_1145_8819304", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <string>\nusing namespace std;\n\nint N;\n\nstring dfs(const string& s, int start, int end) {\n string r;\n r.reserve(N); // reserve memory for r\n long long n = -1;\n for (int i = start; i < end;) {\n if ('0' <= s[i] && s[i] <= '9') {\n if (n < 0)\n n = s[i] - '0';\n else\n n = n * 10 + s[i] - '0';\n i++;\n } else if (s[i] == '(') {\n if (n < 0)\n n = 1;\n int cnt = 1, j = i + 1;\n for (; cnt;) {\n if (s[j] == '(')\n cnt++;\n else if (s[j] == ')')\n cnt--;\n j++;\n }\n string r0 = dfs(s, i + 1, j - 1);\n for (int _ = 0; _ < n; _++) {\n r += r0;\n if (r.size() > N)\n return r;\n }\n n = -1;\n i = j;\n } else {\n if (n < 0)\n n = 1;\n r += string(n, s[i]);\n n = -1;\n i++;\n if (r.size() > N) // break if size of r is greater than N\n break;\n }\n }\n return r;\n}\n\nint main() {\n for (;;) {\n string s;\n cin >> s >> N;\n if (s == \"0\")\n break;\n string r = dfs(s, 0, s.size());\n printf(\"%c\\n\", r.size() > N ? r[N] : '0');\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 10648, "score_of_the_acc": -0.7098, "final_rank": 19 }, { "submission_id": "aoj_1145_8819301", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <vector>\nusing namespace std;\nint N;\nvector<char> dfs(const vector<char>& s, int i, int j) {\n vector<char> r;\n long long n = -1;\n while (i < j) {\n if ('0' <= s[i] && s[i] <= '9') {\n if (n < 0)\n n = s[i] - '0';\n else\n n = n * 10 + s[i] - '0';\n i++;\n } else if (s[i] == '(') {\n if (n < 0)\n n = 1;\n int cnt = 1, k = i + 1;\n while (cnt) {\n if (s[k] == '(')\n cnt++;\n else if (s[k] == ')')\n cnt--;\n k++;\n }\n vector<char> r0 = dfs(s, i + 1, k - 1);\n for (int _ = 0; _ < n; _++) {\n r.insert(r.end(), r0.begin(), r0.end());\n if (r.size() > N)\n return r;\n }\n n = -1;\n i = k;\n } else {\n if (n < 0)\n n = 1;\n r.insert(r.end(), n, s[i]);\n n = -1;\n i++;\n }\n }\n return r;\n}\nint main() {\n for (;;) {\n string s;\n cin >> s >> N;\n if (s == \"0\")\n break;\n vector<char> r = dfs(vector<char>(s.begin(), s.end()), 0, s.size());\n printf(\"%c\\n\", r.size() > N ? r[N] : '0');\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 8380, "score_of_the_acc": -0.4924, "final_rank": 13 }, { "submission_id": "aoj_1145_8810287", "code_snippet": "#include <iostream>\n#include <string>\n\nstd::string dfs(const std::string& s, int N) {\n std::string r;\n int i = 0;\n long long n = -1;\n for (; i < s.size();) {\n if ('0' <= s[i] && s[i] <= '9') {\n if (n < 0)\n n = s[i] - '0';\n else\n n = n * 10 + s[i] - '0';\n i++;\n } else if (s[i] == '(') {\n if (n < 0)\n n = 1;\n int cnt = 1, j = i + 1;\n for (; cnt;) {\n if (s[j] == '(')\n cnt++;\n else if (s[j] == ')')\n cnt--;\n j++;\n }\n std::string r0 = dfs(s.substr(i + 1, j - 1 - i - 1), N);\n for (int _ = 0; _ < n; _++) {\n r += r0;\n if (r.size() > N)\n return r;\n }\n n = -1;\n i = j;\n } else {\n if (n < 0)\n n = 1;\n r.append(n, s[i]);\n n = -1;\n i++;\n }\n }\n return r;\n}\n\nint main() {\n for (;;) {\n std::string s;\n int N;\n std::cin >> s >> N;\n if (s == \"0\")\n break;\n std::string r;\n r.reserve(N + 1);\n r = dfs(s, N);\n std::cout << (r.size() > N ? r[N] : '0') << '\\n';\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 8748, "score_of_the_acc": -0.529, "final_rank": 18 } ]
aoj_1144_cpp
Problem D: Curling 2.0 On Planet MM-21, after their Olympic games this year, curling is getting popular. But the rules are somewhat different from ours. The game is played on an ice game board on which a square mesh is marked. They use only a single stone. The purpose of the game is to lead the stone from the start to the goal with the minimum number of moves. Fig. D-1 shows an example of a game board. Some squares may be occupied with blocks. There are two special squares namely the start and the goal, which are not occupied with blocks. (These two squares are distinct.) Once the stone begins to move, it will proceed until it hits a block. In order to bring the stone to the goal, you may have to stop the stone by hitting it against a block, and throw again. Fig. D-1: Example of board (S: start, G: goal) The movement of the stone obeys the following rules: At the beginning, the stone stands still at the start square. The movements of the stone are restricted to x and y directions. Diagonal moves are prohibited. When the stone stands still, you can make it moving by throwing it. You may throw it to any direction unless it is blocked immediately(Fig. D-2(a)). Once thrown, the stone keeps moving to the same direction until one of the following occurs: The stone hits a block (Fig. D-2(b), (c)). The stone stops at the square next to the block it hit. The block disappears. The stone gets out of the board. The game ends in failure. The stone reaches the goal square. The stone stops there and the game ends in success. You cannot throw the stone more than 10 times in a game. If the stone does not reach the goal in 10 moves, the game ends in failure. Fig. D-2: Stone movements Under the rules, we would like to know whether the stone at the start can reach the goal and, if yes, the minimum number of moves required. With the initial configuration shown in Fig. D-1, 4 moves are required to bring the stone from the start to the goal. The route is shown in Fig. D-3(a). Notice when the stone reaches the goal, the board configuration has changed as in Fig. D-3(b). Fig. D-3: The solution for Fig. D-1 and the final board configuration Input The input is a sequence of datasets. The end of the input is indicated by a line containing two zeros separated by a space. The number of datasets never exceeds 100. Each dataset is formatted as follows. the width(=w) and the height(=h) of the board First row of the board ... h-th row of the board The width and the height of the board satisfy: 2 <= w <= 20, 1 <= h <= 20. Each line consists of w decimal numbers delimited by a space. The number describes the status of the corresponding square. 0 vacant square 1 block 2 start position 3 goal position The dataset for Fig. D-1 is as follows: 6 6 1 0 0 2 1 0 1 1 0 0 0 0 0 0 0 0 0 3 0 0 0 0 0 0 1 0 0 0 0 1 0 1 1 1 1 1 Output For each dataset, print a line having a decimal integer indicating the minimum number of moves along a route from the start to the goal. If there are no such route ...(truncated)
[ { "submission_id": "aoj_1144_10883658", "code_snippet": "#include <iostream> // cout, endl, cin\n#include <string> // string, to_string, stoi\n#include <vector> // vector\n#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound\n#include <utility> // pair, make_pair\n#include <cstdio> // printf\n#include <map> // map\n#include <queue> // queue, priority_queue\n#include <set> // set\n#include <stack> // stack\n#include <deque> // deque\n#include <bitset> // bitset\n#include <cctype> // isupper, islower, isdigit, toupper, tolower\n#include <cstring> // memset\nusing namespace std;\ntypedef long long ll;\n\nint dx[]={0,0,1,-1},dy[]={1,-1,0,0};\n\n\nint grid[29][29];\nint dist[29][29];\nint now;\nint H,W,ans;\nvoid dfs(int x,int y){\n if(now>10)return;\n for(int d=0;d<4;d++){\n int nx=x,ny=y;\n while(1){\n nx+=dx[d],ny+=dy[d];\n if(0>nx||0>ny||nx>=H||ny>=W)break;\n if(grid[nx][ny]==1){\n if(nx-dx[d]==x&&ny-dy[d]==y) break;\n grid[nx][ny]=0;now++;\n dfs(nx-dx[d],ny-dy[d]);\n grid[nx][ny]=1;now--;\n break;\n }\n if(grid[nx][ny]==3){\n now++;\n ans=min(ans,now);\n now--;\n break;\n }\n }\n }\n}\n\nvoid solve(){\n cin>>W>>H;\n if(H==0&&W==0)exit(0);\n for(int i=0;i<H;i++) fill(dist[i],dist[i]+W,1e9);\n ans=1e9;\n now=0;\n int si,sj;\n for(int i=0;i<H;i++) for(int j=0;j<W;j++){\n cin>>grid[i][j];\n if(grid[i][j]==2) si=i,sj=j;\n }\n dist[si][sj]=0;\n dfs(si,sj);\n if(ans>10)ans=-1;\n cout << ans<<endl;\n\n\n\n\n}\n\n\nint main(){\nios::sync_with_stdio(false);cin.tie(0);\n//=======\n while(1) solve();\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3136, "score_of_the_acc": -0.1159, "final_rank": 18 }, { "submission_id": "aoj_1144_10852862", "code_snippet": "#include <iostream>\nusing namespace std;\n\nint strow, stcol;\nint w, h;\n\nconst int DIRECT[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};\n\nint grid[20][20];\n\nint find_path(int row, int col, int step)\n{\n if (step > 10) return 11;\n\n int min_path = 11;\n for (int i = 0; i < 4; i++) {\n int drow = row + DIRECT[i][0], dcol = col + DIRECT[i][1];\n while (0 <= drow && drow < h && 0 <= dcol && dcol < w) {\n if (grid[drow][dcol] != 0) break;\n drow += DIRECT[i][0];\n dcol += DIRECT[i][1];\n }\n\n if (drow < 0 || drow >= h || dcol < 0 || dcol >= w) continue;\n else if (grid[drow][dcol] == 3) return step;\n else if (drow == row + DIRECT[i][0] && dcol == col + DIRECT[i][1])\n continue;\n grid[drow][dcol] = 0;\n int tmp = find_path(drow - DIRECT[i][0], dcol - DIRECT[i][1], step + 1);\n grid[drow][dcol] = 1;\n if (tmp < min_path) min_path = tmp;\n }\n return min_path;\n}\n\nint main()\n{\n while (cin >> w >> h && !(w == 0 && h == 0)) {\n for (int i = 0; i < h; i++)\n for (int j = 0; j < w; j++) {\n cin >> grid[i][j];\n if (grid[i][j] == 2) {\n strow = i;\n stcol = j;\n grid[i][j] = 0;\n }\n }\n\n int tmp = find_path(strow, stcol, 1);\n if (tmp <= 10) cout << tmp << endl;\n else cout << -1 << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3368, "score_of_the_acc": -0.0075, "final_rank": 7 }, { "submission_id": "aoj_1144_10700964", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\nusing namespace std;\n\nint const DIRECTION[][2] = {-1, 0, 0, 1, 1, 0, 0, -1};\n\nstruct qelem\n{\n int row, col;\n int cnt;\n vector<vector<char> > grid;\n};\n\nint w, h;\nqueue<qelem> que;\n\nint main()\n{\n while (cin >> w >> h && !(w == 0 && h == 0)) {\n qelem step;\n step.grid = vector<vector<char> >(h, vector<char>(w));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n cin >> step.grid[i][j];\n if (step.grid[i][j] == '2') {\n step.row = i;\n step.col = j;\n step.grid[i][j] = '0';\n }\n }\n }\n\n while (!que.empty()) que.pop();\n bool yes = false;\n step.cnt = 0;\n que.push(step);\n while (!que.empty()) {\n step = que.front();\n que.pop();\n\n if (step.cnt >= 10) break;\n\n for (int i = 0; i < 4; i++) {\n int dr = step.row + DIRECTION[i][0], dc = step.col + DIRECTION[i][1];\n while (0 <= dr && dr < h && 0 <= dc && dc < w) {\n if (step.grid[dr][dc] != '0') break;\n dr += DIRECTION[i][0];\n dc += DIRECTION[i][1];\n }\n\n if (dr < 0 || dr >= h || dc < 0 || dc >= w) continue;\n else if (step.grid[dr][dc] == '3') {\n yes = true;\n step.cnt++;\n break;\n } else if (dr == step.row + DIRECTION[i][0] &&\n dc == step.col + DIRECTION[i][1]) continue;\n qelem tmp = step;\n tmp.row = dr - DIRECTION[i][0];\n tmp.col = dc - DIRECTION[i][1];\n tmp.grid[dr][dc] = '0';\n tmp.cnt++;\n que.push(tmp);\n\n // for (int i = 0; i < h; i++) {\n // for (int j = 0; j < w; j++) cout << step.grid[i][j] << ' ';\n // cout << \"|\";\n // for (int j = 0; j < w; j++) {\n // if (tmp.grid[i][j] != step.grid[i][j]) cout << \" #\";\n // else cout << ' ' << tmp.grid[i][j];\n // }\n // cout << endl;\n // }\n // cout << \"cnt= \" << step.cnt << endl;\n }\n if (yes) break;\n }\n if (yes) cout << step.cnt << endl;\n else cout << -1 << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 88512, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_1144_10668610", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nbool solve() {\n int H, W;\n cin >> W >> H;\n if (H == 0 && W == 0) return false;\n vector<int> A(H);\n int sr = -1, sc = -1, tr = -1, tc = -1;\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n int a;\n cin >> a;\n if (a == 1) {\n A[i] ^= 1 << j;\n } else if (a == 2) {\n sr = i, sc = j;\n } else if (a == 3) {\n tr = i, tc = j;\n }\n }\n }\n int ans = 1 << 30;\n int D[5] = {0, 1, 0, -1, 0};\n auto dfs = [&] (auto dfs, int r, int c, int t, vector<int> X) -> void {\n if (t == 10) return;\n for (int d = 0; d < 4; d++) {\n int dr = D[d], dc = D[d + 1];\n int nr = r + dr, nc = c + dc;\n while (0 <= nr && nr < H && 0 <= nc && nc < W && !(X[nr] >> nc & 1)) {\n if (nr == tr && nc == tc) ans = min(ans, t + 1);\n nr += dr, nc += dc;\n }\n if (0 <= nr && nr < H && 0 <= nc && nc < W) {\n auto Y = X;\n Y[nr] ^= 1 << nc;\n nr -= dr, nc -= dc;\n if (r != nr || c != nc) {\n dfs(dfs, nr, nc, t + 1, Y);\n }\n }\n }\n };\n dfs(dfs, sr, sc, 0, A);\n if (ans == 1 << 30) ans = -1;\n cout << ans << '\\n';\n return true;\n}\n\nint main() {\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3456, "score_of_the_acc": -0.1752, "final_rank": 19 }, { "submission_id": "aoj_1144_10667915", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define int long long\nusing ll = long long;\nll INF = 2e18;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define fi first\n#define se second\n#define endl \"\\n\" // コメントアウトで随時出力\n\n/*=========================================mint=======================================*/\nconst int mintMod = MOD2; // ここを変更\nclass mint\n{\n long long x;\n\npublic:\n mint(long long x = 0) : x((x % mintMod + mintMod) % mintMod) {}\n long long val() const { return x; }\n mint operator-() const\n {\n return mint(-x);\n }\n mint &operator+=(const mint &a)\n {\n if ((x += a.x) >= mintMod)\n x -= mintMod;\n return *this;\n }\n mint &operator-=(const mint &a)\n {\n if ((x += mintMod - a.x) >= mintMod)\n x -= mintMod;\n return *this;\n }\n mint &operator*=(const mint &a)\n {\n (x *= a.x) %= mintMod;\n return *this;\n }\n mint operator+(const mint &a) const\n {\n mint res(*this);\n return res += a;\n }\n mint operator-(const mint &a) const\n {\n mint res(*this);\n return res -= a;\n }\n mint operator*(const mint &a) const\n {\n mint res(*this);\n return res *= a;\n }\n mint pow(ll t) const\n {\n if (!t)\n return 1;\n mint a = pow(t >> 1);\n a *= a;\n if (t & 1)\n a *= *this;\n return a;\n }\n // for prime mod\n mint inv() const\n {\n return pow(mintMod - 2);\n }\n mint &operator/=(const mint &a)\n {\n return (*this) *= a.inv();\n }\n mint operator/(const mint &a) const\n {\n mint res(*this);\n return res /= a;\n }\n\n friend ostream &operator<<(ostream &os, const mint &m)\n {\n os << m.x;\n return os;\n }\n friend istream &operator>>(istream &is, mint &m)\n {\n long long v;\n is >> v;\n m = mint(v);\n return is;\n }\n};\n/*========================================================================================*/\n\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\n\ntemplate <typename T>\nusing vc = vector<T>; // prioriy_queueに必要なのでここにこれ書いてます\ntemplate <typename T>\nusing vv = vc<vc<T>>;\n\n// 提出の際はコメントアウト\n#define debug_x(x) cout << #x << \" = \" << (x) << endl\n#define debug_vc(v) \\\n { \\\n cout << #v << endl; \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << ' '; \\\n cout << endl; \\\n } // 一次元配列を出力する\n#define debug_vv(v) \\\n { \\\n cout << #v << endl; \\\n ll n = size(v); \\\n rep(i, n) \\\n { \\\n rep(j, size(v[i])) { cout << v[i][j] << ' '; } \\\n cout << endl; \\\n } \\\n } // 二次元配列を出力する\n\n// #define debug_x(x) \\\n// do \\\n// { \\\n// } while (0)\n// #define debug_vc(v) \\\n// do \\\n// { \\\n// } while (0)\n// #define debug_vv(v) \\\n// do \\\n// { \\\n// } while (0)\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n#define rrep(i, n) for (ll i = 1; i <= (n); ++i)\n#define drep(i, n) for (ll i = (n) - 1; i >= 0; --i)\n#define nfor(i, s, n) for (ll i = s; i < n; i++) // i=s,s+1...n-1 ノーマルfor\n#define dfor(i, s, n) for (ll i = (s) - 1; i >= n; i--) // s-1スタートでnまで落ちる\n\nusing ld = long double;\nusing bl = bool;\n\ntemplate <class T>\nusing pq = priority_queue<T, vc<T>>; // 大きい順\ntemplate <class T>\nusing pq_g = priority_queue<T, vc<T>, greater<T>>; // 小さい順\n\nusing vl = vc<ll>;\nusing vvl = vv<ll>;\nusing vvvl = vv<vl>;\nusing vvvvl = vv<vvl>;\nusing vs = vc<string>;\nusing vvs = vv<string>;\nusing vb = vc<bl>;\nusing vvb = vv<bl>;\nusing vvvb = vv<vb>;\nusing vld = vc<ld>;\nusing vvld = vv<ld>;\nusing vvvld = vv<vld>;\nusing P = pair<ll, ll>;\nusing vP = vc<P>;\nusing vvP = vc<vP>;\nusing vvvP = vv<vP>;\nusing vmint = vc<mint>;\nusing vvmint = vv<mint>;\nusing vvvmint = vv<vmint>;\n\n#define pb push_back\n#define eb emplace_back\n\n#define YES cout << \"Yes\" << endl\n#define NO cout << \"No\" << endl\n#define YN \\\n { \\\n cout << \"Yes\" << endl; \\\n } \\\n else \\\n { \\\n cout << \"No\" << endl; \\\n } // if(a==b)YN;\n#define dame cout << -1 << endl\n\nstring dir = \"DRUL\"; // 第4象限の場合\nvl di = {1, 0, -1, 0}; // vl di={1,1,0,-1,-1,-1,0,1};\nvl dj = {0, 1, 0, -1}; // vl dj={0,1,1,1,0,-1,-1,-1};\n\nbool out_grid(ll i, ll j, ll h, ll w)\n{ // trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\nll w, h;\nll ans;\n\nvoid dfs(ll i, ll j, vvl &b, ll cnt)\n{\n if (cnt == 10)\n return;\n rep(k, 4)\n {\n if(out_grid(i+di[k],j+dj[k],h,w)||b[i+di[k]][j+dj[k]]==1)continue;\n ll ni = i;\n ll nj = j;\n // bl out = false;\n while (true)\n {\n ni = ni + di[k];\n nj = nj + dj[k];\n if (out_grid(ni, nj, h, w)){\n break;\n }\n if (b[ni][nj] == 3)\n {\n ans = min(ans, cnt + 1);\n break;\n }\n if(b[ni][nj]==1){\n b[ni][nj] = 0;\n dfs(ni - di[k],nj - dj[k],b,cnt+1);\n b[ni][nj] = 1;\n break;\n }\n }\n }\n}\n\nvoid solve()\n{\n ans = INF;\n vvl b(h, vl(w));\n rep(i, h)\n {\n rep(j, w)\n {\n cin >> b[i][j];\n }\n }\n ll si, sj;\n rep(i, h)\n {\n rep(j, w)\n {\n if (b[i][j] == 2)\n {\n si = i;\n sj = j;\n }\n }\n }\n dfs(si, sj, b, 0);\n if(ans==INF)ans = -1;\n cout << ans << endl;\n return;\n}\n\nsigned main()\n{\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n while (true)\n {\n cin >> w >> h;\n if(w==0)break;\n solve();\n }\n return 0;\n}\n\n/*\nshift+alt+Fで成形\nf2で変数名変更\n\nスニペット\nbasic\n m:atcoder以外用\n ma:ABC/ARC用\n mahc:AHC用\nmath\n floor:床関数\n ceil:天井関数\n comv:二項係数\n modpow: a^b mod m\n GCD:最大公約数\n extGCD:拡張ユークリッド互除法\n PFD:素因数分解\n isprime:エラトステネスの篩\n matrixpow:行列累乗\ndata_structure\n seg:セグメント木\ntechnic\n Compress:座標圧縮\n runlength:ランレングス圧縮\ngraph\n warshall:ワーシャルフロイド法\n dfs:深さ優先探索\n bfs:幅優先探索\n LCA:最近共通祖先\n*/", "accuracy": 1, "time_ms": 20, "memory_kb": 3236, "score_of_the_acc": -0.0615, "final_rank": 12 }, { "submission_id": "aoj_1144_10554644", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define all(a) (a).begin(), (a).end()\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rrep(i, n) for (int i = (int)(n); i >= 0; i--)\n#define range(i, l, r) for (int i = (int)(l); i < (int)(r); i++)\nusing ll = long long;\n\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v) {\n os << \"[\";\n for (int i = 0; i < v.size(); i++) {\n os << v[i] << (i == (v.size() - 1) ? \"\" : \", \");\n }\n os << \"]\";\n return os;\n}\n\ntemplate <typename T1, typename T2>\nostream& operator<<(ostream& os, const pair<T1, T2> p) {\n os << \"{\" << p.first << \", \" << p.second << \"}\";\n return os;\n}\n\nint wall[22][22];\nvector<pair<int, int>> dij = {{0, 1}, {0, -1}, {1, 0}, {-1, 0}};\n\nint dfs(int i, int j, int cnt) {\n int res = 11;\n if (cnt == 10) return res;\n\n int si = i, sj = j;\n for (auto [di, dj] : dij) {\n i = si;\n j = sj;\n if (wall[i + di][j + dj] == 1) continue;\n while (wall[i][j] == 0) {\n i += di;\n j += dj;\n }\n if (wall[i][j] == 3) {\n res = min(res, cnt + 1);\n continue;\n }\n if (wall[i][j] == 1) {\n wall[i][j] = 0;\n res = min(res, dfs(i - di, j - dj, cnt + 1));\n wall[i][j] = 1;\n }\n }\n return res;\n}\n\nbool solve() {\n int w, h;\n cin >> w >> h;\n if (w == 0) return false;\n rep(i, h + 2) rep(j, w + 2) wall[i][j] = -1;\n int si, sj;\n rep(i, h) rep(j, w) {\n cin >> wall[i + 1][j + 1];\n if (wall[i + 1][j + 1] == 2) {\n si = i + 1;\n sj = j + 1;\n wall[si][sj] = 0;\n }\n }\n int ans = dfs(si, sj, 0);\n\n if (ans == 11) {\n cout << -1 << endl;\n } else {\n cout << ans << endl;\n }\n return true;\n}\n\nint main() {\n while (solve()) {\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3332, "score_of_the_acc": -0.0071, "final_rank": 4 }, { "submission_id": "aoj_1144_10515363", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nint main(){\n while(1){\n int h, w; cin >> w >> h;\n if(w == 0) break;\n vector g(h, vector(w, 0));\n int sy, sx;\n for(int i = 0; i < h; ++i){\n for(int j = 0; j < w; ++j){\n cin >> g[i][j];\n if(g[i][j] == 2) sy = i, sx = j;\n }\n }\n int dy[4] = {0, 1, 0, -1};\n int dx[4] = {1, 0, -1, 0};\n int ans = 100;\n auto dfs = [&](auto &self, int y, int x, int k) -> void {\n if(k == 10){\n return;\n }\n // cerr << \"# (y, x) = (\" << y << \", \" << x << \"), k = \" << k << endl;\n // for(int i = 0; i < h; ++i){\n // cerr << \"#\";\n // for(int j = 0; j < w; ++j){\n // cerr << \" \" << g[i][j];\n // }\n // cerr << endl;\n // }\n for(int d = 0; d < 4; ++d){\n int ny = y, nx = x, nny = y + dy[d], nnx = x + dx[d];\n int cnt = 0;\n while(0 <= nny and nny < h and 0 <= nnx and nnx < w){\n if(g[ny][nx] == 3) break;\n if(g[nny][nnx] == 1) break;\n ++cnt;\n ny = nny, nx = nnx;\n nny += dy[d], nnx += dx[d];\n }\n if(g[ny][nx] == 3){\n ans = min(ans, k + 1);\n continue;\n }\n if(nny < 0 or nny >= h or nnx < 0 or nnx >= w or cnt == 0){\n continue;\n }\n g[nny][nnx] = 0;\n self(self, ny, nx, k + 1);\n g[nny][nnx] = 1;\n }\n };\n dfs(dfs, sy, sx, 0);\n if(ans > 10) cout << -1 << endl;\n else cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3188, "score_of_the_acc": -0.061, "final_rank": 10 }, { "submission_id": "aoj_1144_10357524", "code_snippet": "#include <iostream>\n#include <vector>\n\nusing namespace std;\nint w, h, ans = 0;\n\nint dx[] = {0, 0, 1, -1};\nint dy[] = {1, -1, 0, 0};\n\nvoid dfs(int turn, int x, int y, vector<vector<int>>& board){\n if(turn > 10) return;\n for(int dir=0; dir<4; dir++){\n int nx = x, ny = y;\n int px = nx + dx[dir], py = ny + dy[dir];\n if(px < 0 || px >= h || py < 0 || py >= w) continue;\n if(board[px][py] == 1) continue;\n\n while(1){\n nx += dx[dir], ny += dy[dir];\n if(nx < 0 || nx >= h || ny < 0 || ny >= w) {\n break;\n }\n else if(board[nx][ny] == 3){\n ans = min(ans, turn);\n break;\n }\n else if(board[nx][ny] == 1){\n board[nx][ny] = 0;\n dfs(turn+1, nx-dx[dir], ny-dy[dir], board);\n board[nx][ny] = 1;\n break;\n }\n }\n } \n}\n\n\nint main() {\n while (true) {\n cin >> w >> h;\n if (w == 0 && h == 0) break; // 入力の終わり\n ans = 30;\n vector<vector<int>> board(h, vector<int>(w));\n\n int x = 0, y = 0;\n for (int i = 0; i < h; ++i) {\n for (int j = 0; j < w; ++j) {\n cin >> board[i][j];\n if(board[i][j] == 2){\n x = i, y = j;\n }\n }\n }\n\n dfs(1, x, y, board);\n if(ans == 30){\n cout << -1 << endl;\n }\n else{\n cout << ans << endl;\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3304, "score_of_the_acc": -0.0623, "final_rank": 14 }, { "submission_id": "aoj_1144_10339180", "code_snippet": "#include <algorithm>\n#include <climits>\n#include <cstdio>\n\n#define MAX_N 20\n\nint H, W, TI, TJ;\n\nint G[MAX_N][MAX_N];\n\nint dir[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};\n\nenum Tile {\n EMPTY,\n BLOCK,\n START,\n END,\n};\n\nvoid dfs(int i, int j, int ct, int &ans) {\n if (ct > 10) {\n return;\n }\n\n for (int k = 0; k < 4; k++) {\n int ni = i, nj = j;\n int di = dir[k][0], dj = dir[k][1];\n while (true) {\n ni += di;\n nj += dj;\n if (ni < 0 || ni >= H || nj < 0 || nj >= W) {\n break;\n }\n if (ni == TI && nj == TJ) {\n ans = std::min(ans, ct);\n return;\n }\n if (G[ni][nj] == Tile::BLOCK) {\n if (ni - di != i || nj - dj != j) {\n G[ni][nj] = Tile::EMPTY;\n dfs(ni - di, nj - dj, ct + 1, ans);\n G[ni][nj] = Tile::BLOCK;\n }\n break;\n }\n }\n }\n}\n\nint main() {\n while (scanf(\"%d %d\", &W, &H) == 2 && H != 0 && W != 0) {\n int si, sj;\n\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n scanf(\"%d\", &G[i][j]);\n if (G[i][j] == Tile::START) {\n si = i;\n sj = j;\n } else if (G[i][j] == Tile::END) {\n TI = i;\n TJ = j;\n }\n }\n }\n\n int ans = INT_MAX;\n dfs(si, sj, 1, ans);\n printf(\"%d\\n\", ans == INT_MAX ? -1 : ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2944, "score_of_the_acc": -0.0026, "final_rank": 2 }, { "submission_id": "aoj_1144_10339169", "code_snippet": "#include <algorithm>\n#include <climits>\n#include <cstdio>\n\n#define MAX_N 20\n\nint H, W;\n\nint G[MAX_N][MAX_N];\n\ntypedef std::pair<int, int> P;\n\nP dir[4] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};\n\nenum Tile {\n EMPTY,\n BLOCK,\n START,\n END,\n};\n\nvoid dfs(int i, int j, int ct, int ti, int tj, int &ans) {\n if (ct > 10) {\n return;\n }\n\n for (int k = 0; k < 4; k++) {\n int ni = i, nj = j;\n int di = dir[k].first, dj = dir[k].second;\n while (true) {\n ni += di;\n nj += dj;\n if (ni < 0 || ni >= H || nj < 0 || nj >= W) {\n break;\n }\n if (ni == ti && nj == tj) {\n ans = std::min(ans, ct);\n return;\n }\n if (G[ni][nj] == Tile::BLOCK) {\n if (ni - di != i || nj - dj != j) {\n G[ni][nj] = Tile::EMPTY;\n dfs(ni - di, nj - dj, ct + 1, ti, tj, ans);\n G[ni][nj] = Tile::BLOCK;\n }\n break;\n }\n }\n }\n}\n\nint main() {\n while (scanf(\"%d %d\", &W, &H) == 2 && H != 0 && W != 0) {\n int si, sj, ti, tj;\n\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n scanf(\"%d\", &G[i][j]);\n if (G[i][j] == Tile::START) {\n si = i;\n sj = j;\n } else if (G[i][j] == Tile::END) {\n ti = i;\n tj = j;\n }\n }\n }\n\n int ans = INT_MAX;\n dfs(si, sj, 1, ti, tj, ans);\n printf(\"%d\\n\", ans == INT_MAX ? -1 : ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2724, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1144_10096680", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nvoid rec(pair<int,int> pos, vector<vector<int>>& p, set<int>& ans, int cur,int& n, int& m, pair<int,int>& fi){\n if (cur>9){\n return;\n }\n if (pos==fi){\n ans.insert(cur);\n return;\n }\n if (pos.first+1!=n and p[pos.first+1][pos.second]!=1){\n pair<int,int> pos1=pos;\n bool ost=true;\n while (p[pos1.first][pos1.second]!=1){\n pos1.first++;\n if (pos1==fi){\n ans.insert(cur+1);\n return;\n }\n if (pos1.first==n){\n ost=false;\n break;\n }\n }\n pos1.first--;\n if (pos1==fi){\n ans.insert(cur+1);\n return;\n }\n if (ost){\n p[pos1.first+1][pos1.second]=0;\n rec(pos1,p,ans,cur+1,n,m,fi);\n p[pos1.first+1][pos1.second]=1;\n }\n }\n if (pos.first-1!=-1 and p[pos.first-1][pos.second]!=1){\n pair<int,int> pos1=pos;\n bool ost=true;\n while (p[pos1.first][pos1.second]!=1){\n pos1.first--;\n if (pos1==fi){\n ans.insert(cur+1);\n return;\n }\n if (pos1.first==-1){\n ost=false;\n break;\n }\n }\n pos1.first++;\n if (pos1==fi){\n ans.insert(cur+1);\n return;\n }\n if (ost){\n p[pos1.first-1][pos1.second]=0;\n rec(pos1,p,ans,cur+1,n,m,fi);\n p[pos1.first-1][pos1.second]=1;\n }\n }\n if (pos.second+1!=m and p[pos.first][pos.second+1]!=1){\n pair<int,int> pos1=pos;\n bool ost=true;\n while (p[pos1.first][pos1.second]!=1){\n pos1.second++;\n if (pos1==fi){\n ans.insert(cur+1);\n return;\n }\n if (pos1.second==m){\n ost=false;\n break;\n }\n }\n pos1.second--;\n if (pos1==fi){\n ans.insert(cur+1);\n return;\n }\n if (ost){\n p[pos1.first][pos1.second+1]=0;\n rec(pos1,p,ans,cur+1,n,m,fi);\n p[pos1.first][pos1.second+1]=1;\n }\n }\n if (pos.second-1!=-1 and p[pos.first][pos.second-1]!=1){\n pair<int,int> pos1=pos;\n bool ost=true;\n while (p[pos1.first][pos1.second]!=1){\n pos1.second--;\n if (pos1==fi){\n ans.insert(cur+1);\n return;\n }\n if (pos1.second==-1){\n ost=false;\n break;\n }\n }\n pos1.second++;\n if (pos1==fi){\n ans.insert(cur+1);\n return;\n }\n if (ost){\n p[pos1.first][pos1.second-1]=0;\n rec(pos1,p,ans,cur+1,n,m,fi);\n p[pos1.first][pos1.second-1]=1;\n }\n }\n}\nint main() {\n int n,m;cin>>m>>n;\n while (n!=0 and m!=0){\n pair<int,int> st;\n pair<int,int> fi;\n vector<vector<int>> p(n,vector<int> (m));\n set<int> ans;\n for (int i=0;i<n;i++){\n for (int j=0;j<m;j++){\n cin>>p[i][j];\n if (p[i][j]==2){\n st={i,j};\n }\n if (p[i][j]==3){\n fi={i,j};\n }\n }\n }\n rec(st,p,ans,0,n,m,fi);\n if (ans.empty()){\n cout<<-1<<endl;\n }\n else{\n cout<<*ans.begin()<<endl;\n }\n cin>>m>>n;\n }\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3368, "score_of_the_acc": -0.0075, "final_rank": 7 }, { "submission_id": "aoj_1144_10028198", "code_snippet": "#include <iostream>\n#include <vector>\n\nusing namespace std;\n\nvoid solve(int w, int h) {\n vector ban(h, vector<int>(w));\n for (auto &l: ban) {\n for (auto &i: l) cin >> i;\n }\n pair<int, int> s;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (ban[i][j] == 2) {\n s.first = i, s.second = j;\n break;\n }\n }\n }\n vector broken(h, vector<bool>(w));\n const vector<int> dx = {1, -1, 0, 0}, dy = {0, 0, 1, -1};\n constexpr int inf = 1 << 29;\n auto dfs = [&](auto &self, int x, int y, int cnt) -> int{\n if (cnt == 10) return inf;\n int ret = inf;\n int ox = x, oy = y;\n for (int k = 0; k < 4; k++) {\n bool first = true;\n x = ox, y = oy;\n while (true) {\n int nx = x + dx[k], ny = y + dy[k];\n if (!(0 <= nx && nx < h && 0 <= ny && ny < w)) break;\n if (ban[nx][ny] == 3) {\n ret = min(ret, cnt + 1);\n break;\n }\n if (ban[nx][ny] == 1 && !broken[nx][ny]) {\n if (first) break;\n broken[nx][ny] = true;\n ret = min(ret, self(self, x, y, cnt + 1));\n broken[nx][ny] = false;\n break;\n }\n x = nx, y = ny;\n first = false;\n }\n }\n return ret;\n };\n int ans = dfs(dfs, s.first, s.second, 0);\n cout << (ans == inf? -1: ans) << endl;\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(0);\n int n, m;\n cin >> n >> m;\n do {\n solve(n, m);\n cin >> n >> m;\n }while(n != 0);\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3488, "score_of_the_acc": -0.0645, "final_rank": 17 }, { "submission_id": "aoj_1144_9722558", "code_snippet": "#include <bits/stdc++.h>\n using namespace std;\n \n template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\n template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n #define rep(i,n) for (int i = 0; i < (n); ++i)\n\n typedef long long ll;\n typedef unsigned long long ull;\n using P=pair<ll,ll>;\n using T=tuple<int,int,int>;\n const int INF=1001001001;\n const ll INFL=1e18;\n const int mod=998244353;\n\n\tint dx[4]={1,-1,0,0},dy[4]={0,0,1,-1};\n\tint dfs(int i,int j,int t,vector<vector<int>>& a){\n\t\tif(t>=10){\n\t\t\treturn INF;\n\t\t}\n\t\tint h=a.size(),w=a[0].size();\n\t\tint ans=INF;\n\t\trep(k,4){\n\t\t\tint ni=i+dx[k],nj=j+dy[k];\n\t\t\twhile(ni>=0&&ni<h&&nj>=0&&nj<w&&a[ni][nj]!=1&&a[ni][nj]!=3){\n\t\t\t\tni+=dx[k];nj+=dy[k];\n\t\t\t}\n\t\t\tif(ni<0||ni>=h||nj<0||nj>=w){continue;}\n\t\t\tif(a[ni][nj]==3)chmin(ans,1);\n\t\t\tif(a[ni][nj]==1){\n\t\t\t\tif(ni==i+dx[k]&&nj==j+dy[k])continue;\n\t\t\t\ta[ni][nj]=0;\n\t\t\t\tchmin(ans,1+dfs(ni-dx[k],nj-dy[k],t+1,a));\n\t\t\t\ta[ni][nj]=1;\n\t\t\t}\n\t\t}\n\t\treturn ans;\n\t}\t\n\n bool solve(){\n\t\tint w,h;\n\t\tcin>>w>>h;\n\t\tif(!w&&!h)return false;\n\t\t\n\t\tvector<vector<int>>a(h,vector<int>(w));\n\t\trep(i,h){\n\t\t\trep(j,w){\n\t\t\t\tcin>>a[i][j];\n\t\t\t}\n\t\t}\n\t\tint ans=INF;\n\t\trep(i,h){\n\t\t\trep(j,w){\n\t\t\t\tif(a[i][j]==2){\n\t\t\t\t\tchmin(ans,dfs(i,j,0,a));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(ans==INF)ans=-1;\n\t\tcout<<ans<<endl;\n\t\treturn true;\n }\n\n int main(){\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n\t\twhile(1){\n\t\t\tif(!solve())break;\n\t\t}\n\t\t\n return 0;\n }", "accuracy": 1, "time_ms": 10, "memory_kb": 3456, "score_of_the_acc": -0.0085, "final_rank": 9 }, { "submission_id": "aoj_1144_9680087", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> pi;\ntypedef vector<ll> vi;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\nint main(){\n while(1){\n ll H,W;cin>>W>>H;\n if(!H)return 0;\n vector<vector<ll>>A(H,vector<ll>(W));\n REP(i,H)REP(j,W)cin>>A[i][j];\n ll ans=11,cnt=0;\n vector<pi>move={pi(0,1),pi(0,-1),pi(1,0),pi(-1,0)};\n function<void(ll,ll)>dfs=[&](ll x,ll y){\n if(ans<=cnt+1)return;\n cnt++;\n for(auto[dx,dy]:move)if(min(x+dx,y+dy)>=0&&min(H-x-dx,W-y-dy)>0&&A[x+dx][y+dy]!=1){\n ll _x=x+dx,_y=y+dy;\n while(min({_x+1,_y+1,H-_x,W-_y})>0&&A[_x][_y]!=1&&A[_x][_y]!=3)_x+=dx,_y+=dy;\n if(min({_x+1,_y+1,H-_x,W-_y})<=0)continue;\n if(A[_x][_y]==3){\n ans=min(ans,cnt);\n cnt--;\n return;\n }\n A[_x][_y]=0;\n dfs(_x-dx,_y-dy);\n A[_x][_y]=1;\n }\n cnt--;\n };\n REP(i,H)REP(j,W)if(A[i][j]==2)dfs(i,j);\n if(ans>10)ans=-1;\n cout<<ans<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3336, "score_of_the_acc": -0.0071, "final_rank": 5 }, { "submission_id": "aoj_1144_9345935", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\nusing ll = long long;\n#define MOD 1000000007\n#define Mod 998244353\nconst int MAX = 1000000005;\nconst long long INF = 1000000000000000005LL;\nusing namespace std;\n//using namespace atcoder;\n\nint di[] = {0, 1, 0, -1}, dj[] = {1, 0, -1, 0};\nint w, h, gi, gj;\nvoid dfs(int i, int j, int cnt, vector<vector<int>>& dist, vector<vector<int>>& G) {\n if (cnt == 10) return;\n for (int k = 0; k < 4; k++) {\n int ni = i + di[k], nj = j + dj[k];\n if ((ni < 0 || ni >= h || nj < 0 || nj >= w) || G[ni][nj] == 1) continue;\n int x = i, y = j;\n while (true) {\n int nx = x + di[k], ny = y + dj[k];\n if ((nx < 0 || nx >= h || ny < 0 || ny >= w) || G[nx][ny] == 1) break;\n x = nx; y = ny;\n if (x == gi && y == gj) {\n if (dist[x][y] == -1) dist[x][y] = cnt + 1;\n else dist[x][y] = min(dist[x][y], cnt + 1);\n }\n }\n\n ni = x + di[k];\n nj = y + dj[k];\n if (!(ni < 0 || ni >= h || nj < 0 || nj >= w)) {\n G[ni][nj] = 0;\n if (dist[x][y] == -1) dist[x][y] = cnt + 1;\n else dist[x][y] = min(dist[x][y], cnt + 1);\n dfs(x, y, cnt + 1, dist, G);\n G[ni][nj] = 1;\n }\n }\n}\n\nbool solve() {\n cin >> w >> h;\n if (w == 0 && h == 0) return false;\n vector<vector<int>> G(h, vector<int>(w));\n int si, sj;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n cin >> G[i][j];\n if (G[i][j] == 2) {si = i; sj = j;}\n if (G[i][j] == 3) {gi = i; gj = j;}\n }\n }\n vector<vector<int>> dist(h, vector<int>(w, -1));\n dist[si][sj] = 0;\n dfs(si, sj, 0, dist, G);\n cout << dist[gi][gj] << endl;\n return true;\n}\n\nint main() {\n ios::sync_with_stdio(0); cin.tie();\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3416, "score_of_the_acc": -0.0636, "final_rank": 16 }, { "submission_id": "aoj_1144_9330271", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\ntemplate<typename T>\nbool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate<typename T>\nbool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\nvoid solve();\nint w,h,a[20][20];\nint main() {\n cin.tie(nullptr)->sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int t = 1;\n //cin >> t;\n while (1) {\n cin>>w>>h;\n if(w==0)break;\n rep(i,h)rep(j,w)cin>>a[i][j];\n solve();\n }\n}\nint dx[4]={1,0,-1,0},dy[4]={0,1,0,-1};\nint sx,sy,tx,ty;\nint dfs(int x0,int y0,int now){\n if(10<=now)return 11;\n int ret=11;\n rep(dir,4){\n int x=x0,y=y0;\n {\n int xx=x+dx[dir],yy=y+dy[dir];\n if(!(0<=xx&&xx<h&&0<=yy&&yy<w))continue;\n if(a[xx][yy]==1)continue;\n }\n while(1){\n int xx=x+dx[dir],yy=y+dy[dir];\n if(!(0<=xx&&xx<h&&0<=yy&&yy<w)){\n break;\n }\n if(a[xx][yy]==1){\n a[xx][yy]=0;\n chmin(ret,dfs(x,y,now+1)+1);\n a[xx][yy]=1;\n break;\n }\n if(xx==tx&&yy==ty)return 1;\n x=xx,y=yy;\n }\n }\n return ret;\n}\nvoid solve() {\n rep(i,h)rep(j,w){\n if(a[i][j]==2)sx=i,sy=j,a[i][j]=0;\n if(a[i][j]==3)tx=i,ty=j,a[i][j]=0;\n }\n int ans=dfs(sx,sy,0);\n if(10<ans)ans=-1;\n cout<<ans<<'\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3364, "score_of_the_acc": -0.0075, "final_rank": 6 }, { "submission_id": "aoj_1144_9326385", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (long long i = 0; i < (long long)(n); i++)\n#define rrep(i,start,end) for (long long i = start;i >= (long long)(end);i--)\n#define repn(i,end) for(long long i = 0; i <= (long long)(end); i++)\n#define reps(i,start,end) for(long long i = start; i < (long long)(end); i++)\n#define repsn(i,start,end) for(long long i = start; i <= (long long)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\ntypedef vector<long long> vll;\ntypedef vector<pair<long long ,long long>> vpll;\ntypedef vector<vector<long long>> vvll;\ntypedef set<ll> sll;\ntypedef map<long long , long long> mpll;\ntypedef pair<long long ,long long> pll;\ntypedef tuple<long long , long long , long long> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (int)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1LL << 60;\nconst ld EPS = 1e-9;\n \ninline ll lfloor(ll x,ll m){return (x - ((x % m+ m)%m))/m;}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\n// for AOJ or ICPC or etc..\n// 全部が0だったらtrueを返す\ntemplate<class Tp> bool zero (const Tp &x) {return x == 0;}\ntemplate<class Tp, class... Args> bool zero (const Tp &x, const Args& ...args) {return zero(x) and zero(args...);}\n\n\n// 変数をちゃんと全部受け取る!\nvoid solve(ll w,ll h){\n ll sy,sx,gy,gx;\n vvll g(h,vll(w));\n rep(i,h){\n rep(j,w){\n cin >> g[i][j];\n if(g[i][j] == 2){\n sy = i;sx = j;\n }\n if(g[i][j] == 3){\n gy = i;gx = j;\n }\n }\n }\n ll ans = INF;\n auto dfs = [&](auto dfs, ll cnt ,ll y,ll x, vvll &state)->void{\n if(cnt == 10){\n return ;\n }\n // ll num = state[y][x];\n rep(i,4){\n if(!isin(y + _ta[i],x + _yo[i],h,w) or g[y + _ta[i]][x + _yo[i]] == 1){\n continue;\n }\n ll ny = y;\n ll nx = x;\n while(isin(ny,nx,h,w) && g[ny][nx] != 1){\n ny += _ta[i];\n nx += _yo[i];\n if(ny == gy && nx == gx){\n chmin(ans,cnt + 1);\n }\n }\n if(!isin(ny,nx,h,w)){\n continue;\n // ny -= _ta[i];\n // nx -= _yo[i];\n // ll past = state[ny][nx];\n // chmin(state[ny][nx],cnt+1);\n // dfs(dfs,cnt+1,ny,nx,state);\n // state[ny][nx] = past;\n }else{\n assert(g[ny][nx] == 1);\n //消す\n g[ny][nx] = 0;\n ny -= _ta[i];\n nx -= _yo[i];\n ll past = state[ny][nx];\n chmin(state[ny][nx],cnt+1);\n dfs(dfs,cnt+1,ny,nx,state);\n state[ny][nx] = past;\n g[ny + _ta[i]][nx + _yo[i]] = 1;\n }\n }\n };\n vector<vector<ll>> state(h,vll(w,INF));\n state[sy][sx] = 0;\n dfs(dfs,0,sy,sx,state);\n if(ans == INF){\n cout << -1 << endl;\n }else{\n cout << ans << endl;\n }\n}\n \nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true){\n LL(w,h);//変数数調整\n if(zero(w,h))break;\n solve(w,h);\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3256, "score_of_the_acc": -0.0618, "final_rank": 13 }, { "submission_id": "aoj_1144_9262337", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, a, n) for(int i = a; i < n; i++)\n#define rrep(i, a, n) for(int i = a; i >= n; i--)\n#define inr(l, x, r) (l <= x && x < r)\n#define ll long long\n#define ld long double\n//#define int long long\n\nconstexpr int IINF = 1001001001;\nconstexpr ll INF = 9e18;\n\ntemplate<class t,class u> void chmax(t&a,u b){if(a<b)a=b;}\ntemplate<class t,class u> void chmin(t&a,u b){if(b<a)a=b;}\n\nint main(){\n while(1){\n int w, h; cin >> w >> h;\n if(w == 0 && h == 0) return 0;\n vector<vector<int>> board(h, vector<int>(w));\n // xは縦!!!!!!!!!!!!!!!!!!!!!\n int sx, sy;\n rep(i, 0, h)rep(j, 0, w){\n cin >> board[i][j];\n if(board[i][j] == 2){\n sx = i;\n sy = j;\n board[i][j] = 0;\n }\n }\n vector<int> dx = {1, 0, -1, 0}, dy = {0, 1, 0, -1};\n auto solve = [&](auto solve, int x, int y, int turn)->int{\n // cout << x << ' ' << y << ' ' << turn << endl;\n if(turn == 10) return IINF;\n int res = IINF;\n rep(i, 0, 4){\n int nx = x, ny = y;\n if(!inr(0, nx+dx[i], h) || !inr(0, ny+dy[i], w) || board[nx+dx[i]][ny+dy[i]] == 1) continue;\n // while(1){\n // nx += dx[i]; ny += dy[i];\n // if(!inr(0, nx, h) || !inr(0, ny, w)) break;\n // if(board[nx][ny] == 3) return turn+1;\n // if(board[nx][ny] == 1){\n // board[nx][ny] = 0;\n // chmin(res, solve(solve, nx-dx[i], ny-dy[i], turn+1));\n // board[nx][ny] = 1;\n // break;\n // }\n // }\n while(inr(0, nx, h) && inr(0, ny, w) && board[nx][ny] == 0) nx += dx[i], ny += dy[i];\n if(!inr(0, nx, h) || !inr(0, ny, w)) continue;\n if(board[nx][ny] == 3) return turn+1;\n if(board[nx][ny] == 1){\n board[nx][ny] = 0;\n chmin(res, solve(solve, nx-dx[i], ny-dy[i], turn+1));\n board[nx][ny] = 1;\n }\n }\n return res;\n };\n int ans = solve(solve, sx, sy, 0);\n if(ans == IINF) cout << -1 << endl;\n else cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3220, "score_of_the_acc": -0.0613, "final_rank": 11 }, { "submission_id": "aoj_1144_9262318", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, a, n) for(int i = a; i < n; i++)\n#define rrep(i, a, n) for(int i = a; i >= n; i--)\n#define inr(l, x, r) (l <= x && x < r)\n#define ll long long\n#define ld long double\n//#define int long long\n\nconstexpr int IINF = 1001001001;\nconstexpr ll INF = 9e18;\n\ntemplate<class t,class u> void chmax(t&a,u b){if(a<b)a=b;}\ntemplate<class t,class u> void chmin(t&a,u b){if(b<a)a=b;}\n\nint main(){\n while(1){\n int w, h; cin >> w >> h;\n if(w == 0 && h == 0) return 0;\n vector<vector<int>> board(h, vector<int>(w));\n // xは縦!!!!!!!!!!!!!!!!!!!!!\n int sx, sy;\n rep(i, 0, h)rep(j, 0, w){\n cin >> board[i][j];\n if(board[i][j] == 2){\n sx = i;\n sy = j;\n }\n }\n vector<int> dx = {1, 0, -1, 0}, dy = {0, 1, 0, -1};\n auto solve = [&](auto solve, int x, int y, int turn)->int{\n // cout << x << ' ' << y << ' ' << turn << endl;\n if(turn == 10) return IINF;\n int res = IINF;\n rep(i, 0, 4){\n int nx = x, ny = y;\n if(!inr(0, nx+dx[i], h) || !inr(0, ny+dy[i], w) || board[nx+dx[i]][ny+dy[i]] == 1) continue;\n while(1){\n nx += dx[i]; ny += dy[i];\n if(!inr(0, nx, h) || !inr(0, ny, w)) break;\n if(board[nx][ny] == 3) return turn+1;\n if(board[nx][ny] == 1){\n board[nx][ny] = 0;\n chmin(res, solve(solve, nx-dx[i], ny-dy[i], turn+1));\n board[nx][ny] = 1;\n break;\n }\n }\n }\n return res;\n };\n int ans = solve(solve, sx, sy, 0);\n if(ans == IINF) cout << -1 << endl;\n else cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3388, "score_of_the_acc": -0.0633, "final_rank": 15 }, { "submission_id": "aoj_1144_9256756", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define all(a) a.begin(),a.end()\n#define reps(i, a, n) for (int i = (a); i < (int)(n); i++)\n#define rep(i, n) reps(i, 0, n)\n#define rreps(i, a, n) for (int i = (a); i > (int)(n); i--)\nconst long long mod = 1000000007;\nconst long long INF = 1e18;\n\nint w,h;\nint sx,sy,gx,gy;\nint ans = 100;\nvector<vector<int>> stage (22,vector<int> (22));\n\nvoid find(int x, int y, int c) {\n if (c == 10) {\n return;\n }\n if (stage[x-1][y] != 1) {\n int i = 1;\n while (true) {\n if (stage[x-i][y] == 0) {\n i++;\n continue;\n }\n if (stage[x-i][y] == 3) {\n ans = min(ans,c+1);\n return;\n }\n if (stage[x-i][y] == -1) {\n break;\n }\n if (stage[x-i][y] == 1) {\n stage[x-i][y] = 0;\n find(x-i+1,y,c+1);\n stage[x-i][y] = 1;\n break;\n }\n }\n }\n if (stage[x+1][y] != 1) {\n int i = 1;\n while (true) {\n if (stage[x+i][y] == 0) {\n i++;\n continue;\n }\n if (stage[x+i][y] == 3) {\n ans = min(ans,c+1);\n return;\n }\n if (stage[x+i][y] == -1) {\n break;\n }\n if (stage[x+i][y] == 1) {\n stage[x+i][y] = 0;\n find(x+i-1,y,c+1);\n stage[x+i][y] = 1;\n break;\n }\n }\n }\n if (stage[x][y-1] != 1) {\n int i = 1;\n while (true) {\n if (stage[x][y-i] == 0) {\n i++;\n continue;\n }\n if (stage[x][y-i] == 3) {\n ans = min(ans,c+1);\n return;\n }\n if (stage[x][y-i] == -1) {\n break;\n }\n if (stage[x][y-i] == 1) {\n stage[x][y-i] = 0;\n find(x,y-i+1,c+1);\n stage[x][y-i] = 1;\n break;\n }\n }\n }\n if (stage[x][y+1] != 1) {\n int i = 1;\n while (true) {\n if (stage[x][y+i] == 0) {\n i++;\n continue;\n }\n if (stage[x][y+i] == 3) {\n ans = min(ans,c+1);\n return;\n }\n if (stage[x][y+i] == -1) {\n break;\n }\n if (stage[x][y+i] == 1) {\n stage[x][y+i] = 0;\n find(x,y+i-1,c+1);\n stage[x][y+i] = 1;\n break;\n }\n }\n }\n}\n\nvoid solve() {\n ans = 100;\n rep(i,h) {\n rep(j,w) {\n cin >> stage[i+1][j+1];\n if (stage[i+1][j+1] == 2) {\n sx = i+1;\n sy = j+1;\n stage[i+1][j+1] = 0;\n }\n if (stage[i+1][j+1] == 3) {\n gx = i+1;\n gy = j+1;\n }\n }\n }\n\n find(sx,sy,0);\n\n if (ans == 100) {\n cout << -1 << endl;\n }\n else {\n cout << ans << endl;\n }\n return;\n}\n\nint main() {\n while (true) {\n cin >> w >> h;\n if (w == 0) {\n return 0;\n }\n rep(i,h) {\n stage[i+1][0] = -1;\n stage[i+1][w+1] = -1;\n }\n rep(i,w) {\n stage[0][i+1] = -1;\n stage[h+1][i+1] = -1;\n }\n solve();\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3300, "score_of_the_acc": -0.0067, "final_rank": 3 } ]
aoj_1155_cpp
Problem C: How can I satisfy thee? Let me count the ways... Three-valued logic is a logic system that has, in addition to "true" and "false", "unknown" as a valid value. In the following, logical values "false", "unknown" and "true" are represented by 0, 1 and 2 respectively. Let "-" be a unary operator (i.e. a symbol representing one argument function) and let both "*" and "+" be binary operators (i.e. symbols representing two argument functions). These operators represent negation (NOT), conjunction (AND) and disjunction (OR) respectively. These operators in three-valued logic can be defined in Table C-1. Table C-1: Truth tables of three-valued logic operators -X (X*Y) (X+Y) Let P, Q and R be variables ranging over three-valued logic values. For a given formula, you are asked to answer the number of triples (P,Q,R) that satisfy the formula, that is, those which make the value of the given formula 2. A formula is one of the following form (X and Y represent formulas). Constants: 0, 1 or 2 Variables: P, Q or R Negations: -X Conjunctions: (X*Y) Disjunctions: (X+Y) Note that conjunctions and disjunctions of two formulas are always parenthesized. For example, when formula (P*Q) is given as an input, the value of this formula is 2 when and only when (P,Q,R) is (2,2,0), (2,2,1) or (2,2,2). Therefore, you should output 3. Input The input consists of one or more lines. Each line contains a formula. A formula is a string which consists of 0, 1, 2, P, Q, R, -, *, +, (, ). Other characters such as spaces are not contained. The grammar of formulas is given by the following BNF. <formula> ::= 0 | 1 | 2 | P | Q | R | -<formula> | (<formula>*<formula>) | (<formula>+<formula>) All the formulas obey this syntax and thus you do not have to care about grammatical errors. Input lines never exceed 80 characters. Finally, a line which contains only a "." (period) comes, indicating the end of the input. Output You should answer the number (in decimal) of triples (P,Q,R) that make the value of the given formula 2. One line containing the number should be output for each of the formulas, and no other characters should be output. Sample Input (P*Q) (--R+(P*Q)) (P*-P) 2 1 (-1+(((---P+Q)*(--Q+---R))*(-R+-P))) . Output for the Sample Input 3 11 0 27 0 7
[ { "submission_id": "aoj_1155_4920981", "code_snippet": "#include <iostream>\n#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nint a,b,c,ch[80],ans,A,B,C,D;\nstring s;\nint no(int n){\n if(n==0)return 2;\n if(n==1)return 1;\n return 0;\n}\nint h(int x,int y){\n if(x*y==0)return 0;\n if(x*y==4)return 2;\n return 1;\n}\nint H(int x,int y){\n if(x==2||y==2)return 2;\n if(x==0&&y==0)return 0;\n return 1;\n}\nint f(void){\n int cnt=0;\n stack<int> sta[80];\n stack<int> sta2[80];\n for(int i=0;i<s.size();i++){\n if(s[i]=='(')cnt++;\n if(s[i]=='-')ch[cnt]^=1;\n if(s[i]=='P'){\n if(ch[cnt]){ch[cnt]=0;sta[cnt].push(no(a));}\n else sta[cnt].push(a);\n }\n if(s[i]=='Q'){\n if(ch[cnt]){ch[cnt]=0;sta[cnt].push(no(b));}\n else sta[cnt].push(b);\n }\n if(s[i]=='R'){\n if(ch[cnt]){ch[cnt]=0;sta[cnt].push(no(c));}\n else sta[cnt].push(c);\n }\n if(s[i]=='0'){\n if(ch[cnt]){ch[cnt]=0;sta[cnt].push(no(0));}\n else sta[cnt].push(0);\n }\n if(s[i]=='1'){\n if(ch[cnt]){ch[cnt]=0;sta[cnt].push(no(1));}\n else sta[cnt].push(1);\n }\n if(s[i]=='2'){\n if(ch[cnt]){ch[cnt]=0;sta[cnt].push(no(2));}\n else sta[cnt].push(2);\n }\n if(s[i]=='+')sta2[cnt].push(0);\n if(s[i]=='*')sta2[cnt].push(1);\n if(s[i]==')'){\n while(sta[cnt].size()>1){\n A=sta[cnt].top();\n sta[cnt].pop();\n B=sta[cnt].top();\n sta[cnt].pop();\n C=sta2[cnt].top();\n sta2[cnt].pop();\n if(C==0)D=H(A,B);\n if(C==1)D=h(A,B);\n sta[cnt].push(D);\n }\n if(sta[cnt].size()==1){\n A=sta[cnt].top();\n sta[cnt].pop();\n if(ch[cnt-1]){ch[cnt-1]=0;sta[cnt-1].push(no(A));}\n else sta[cnt-1].push(A);\n }\n cnt--;\n }\n }\n return sta[0].top();\n}\nint main(void){\n while(1){\n cin>>s;\n for(int i=0;i<80;i++)ch[i]=0;\n if(s==\".\")return 0;\n ans=0;\n for(int i=0;i<3;i++){\n for(int j=0;j<3;j++){\n for(int k=0;k<3;k++){\n a=i,b=j,c=k;\n //cout<<i<<\" \"<<j<<\" \"<<k<<\" \"<<f()<<endl;\n //cout<<(H(h(a,b),c))<<endl;\n if(f()==2)ans++;\n }\n }\n }\n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3432, "score_of_the_acc": -2, "final_rank": 10 }, { "submission_id": "aoj_1155_2854019", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint add(int a, int b){\n\treturn max(a,b);\n}\n\nint mul(int a, int b){\n\treturn min(a,b);\n}\n\nint sub(int a){\n\treturn 2-a;\n}\n\nbool is_digit(char c){\n\treturn c >= '0' && c <= '9';\n}\n\nstring calc(string s, int p, int q, int r){\n\tstring ret;\n\treplace(s.begin(),s.end(),'P',char(p + '0'));\n\treplace(s.begin(),s.end(),'Q',char(q + '0'));\n\treplace(s.begin(),s.end(),'R',char(r + '0'));\n\t//cout << s << endl;\n\tfor(int i=0;i < s.size();i++){\n\t\tif(i < s.size()-2){\n\t\t\tif(s[i] == '(' && s[i+2] == ')'){\n\t\t\t\tret += s[i+1];\n\t\t\t\ti+=2;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif(s[i+1] == '+' && is_digit(s[i]) && is_digit(s[i+2])){\n\t\t\t\tret += to_string(add(int(s[i] - '0'),int(s[i+2] - '0')));\n\t\t\t\ti+=2;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif(s[i+1] == '*' && is_digit(s[i]) && is_digit(s[i+2])){\n\t\t\t\tret += to_string(mul(int(s[i] - '0'),int(s[i+2] - '0')));\n\t\t\t\ti+=2;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\t\tif(i < s.size()-1){\n\t\t\tif(s[i] == '-' && s[i+1] == '-'){\n\t\t\t\ti++;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif(s[i] == '-' && is_digit(s[i+1])){\n\t\t\t\tret += to_string(sub(int(s[i+1] - '0')));\n\t\t\t\ti++;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\t\tret += s[i];\n\t}\n\t//cout << ret << endl;\n\tif(ret.size() > 1){\n\t\treturn calc(ret, p, q, r);\n\t} else {\n\t\treturn ret;\n\t}\n}\n\nint main(){\n\tstring s;\n\twhile(cin >> s, s != \".\"){\n\t\tint ans = 0;\n\t\tfor(int p=0;p<3;p++){\n\t\t\tfor(int q=0;q<3;q++){\n\t\t\t\tfor(int r=0;r<3;r++){\n\t\t\t\t\tint x = stoi(calc(s, p, q, r));\n\t\t\t\t\tif(x == 2){\n\t\t\t\t\t\tans ++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << ans << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3228, "score_of_the_acc": -0.9091, "final_rank": 7 }, { "submission_id": "aoj_1155_2759418", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i=0;i<n;i++)\n\nint solve(string s, int p, int q, int r){\n s=regex_replace(s,regex(\"P\"),to_string(p));\n s=regex_replace(s,regex(\"Q\"),to_string(q));\n s=regex_replace(s,regex(\"R\"),to_string(r));\n string a=\"\";\n for(auto c:s){\n int n=\"012\"s.find(c);\n if(n!=-1 and a.back()=='-'){\n a.back()=\"210\"[n];\n }else{\n a+=c;\n }\n if(c==')'){\n auto f=a.substr(0,a.size()-5);\n auto p=a.substr(a.size()-5);\n if(f.back()=='-'){\n if(p[2]=='+'){\n a=f.substr(0,f.size()-1)+\"210\"[\"012\"s.find(max(p[1],p[3]))];\n }else{\n a=f.substr(0,f.size()-1)+\"210\"[\"012\"s.find(min(p[1],p[3]))];\n }\n }else{\n if(p[2]=='+'){\n a=f+max(p[1],p[3]);\n }else{\n a=f+min(p[1],p[3]);\n }\n }\n }\n }\n return a==\"2\"?1:0;\n}\n\nint main(void){\n string s;\n while(cin>>s,s!=\".\"){\n auto cp=regex_replace(s,regex(\"--\"),\"\");\n int ans=0;\n rep(p,3)rep(q,3)rep(r,3){\n ans+=solve(cp,p,q,r);\n }\n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3220, "score_of_the_acc": -1.9055, "final_rank": 9 }, { "submission_id": "aoj_1155_2388499", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <cstring>\n\n#include <iostream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n#include <unordered_map>\n#include <unordered_set>\n\n#include <functional>\n#include <cassert>\n\ntypedef long long ll;\nusing namespace std;\n\n#define debug(x) cerr << #x << \" = \" << (x) << endl;\n\n\n#define mod 1000000007 //1e9+7(prime number)\n#define INF 1000000000 //1e9\n#define LLINF 2000000000000000000LL //2e18\n#define SIZE 100010\n\nint c_not[3] = {2,1,0};\nint c_and[3][3] = {{0,0,0},{0,1,1},{0,1,2}};\nint c_or[3][3] = {{0,1,2},{1,1,2},{2,2,2}};\n\nint calc(string s, int p, int q, int r){\n\n for(int i=0;i<s.size();i++){\n\n if(s[i] == 'P'){\n s[i] = '0' + p;\n }\n if(s[i] == 'Q'){\n s[i] = '0' + q;\n }\n if(s[i] == 'R'){\n s[i] = '0' + r;\n }\n \n }\n \n while(s.size() > 1){\n string s_old = s;\n \n //debug(s);\n \n for(int i=0;i<s.size();i++){\n\n //not\n if(i+1 < s.size()){\n if(s[i] == '-' && ('0' <= s[i+1] && s[i+1] <= '2')){\n int p = c_not[s[i+1]-'0'];\n s = s.substr(0,i) + \"0\" + s.substr(i+2, s.size() - (i+2));\n s[i] += p;\n break;\n }\n }\n\n \n if(0 < i && i+1 < s.size()){\n //and\n if(('0' <= s[i-1] && s[i-1] <= '2') &&\n s[i] == '*' &&\n ('0' <= s[i+1] && s[i+1] <= '2')){\n int p = c_and[s[i-1]-'0'][s[i+1]-'0'];\n s = s.substr(0,i-1) + \"0\" + s.substr(i+2, s.size() - (i+2));\n s[i-1] += p;\n break;\n }\n\n //or\n if(('0' <= s[i-1] && s[i-1] <= '2') &&\n s[i] == '+' &&\n ('0' <= s[i+1] && s[i+1] <= '2')){\n int p = c_or[s[i-1]-'0'][s[i+1]-'0'];\n s = s.substr(0,i-1) + \"0\" + s.substr(i+2, s.size() - (i+2));\n s[i-1] += p;\n break;\n }\n\n //(*)\n if(s[i-1] == '(' &&\n ('0' <= s[i] && s[i] <= '2') &&\n s[i+1] == ')'){\n int p = s[i]-'0';\n s = s.substr(0,i-1) + \"0\" + s.substr(i+2, s.size() - (i+2));\n s[i-1] += p;\n break;\n }\n }\n }\n\n if(s == s_old){\n assert(false);\n break;\n }\n }\n\n return s[0]-'0';\n}\n\nbool solve(){\n string s;\n\n cin >> s;\n\n if(s == \".\") return false;\n\n int ans = 0;\n \n for(int i=0;i<=2;i++){\n for(int j=0;j<=2;j++){\n for(int k=0;k<=2;k++){\n ans += calc(s,i,j,k) == 2;\n }\n }\n }\n\n printf(\"%d\\n\",ans);\n\n return true;\n}\n \n\nint main(){\n\n while(solve());\n \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3212, "score_of_the_acc": -0.902, "final_rank": 6 }, { "submission_id": "aoj_1155_1864146", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <cmath>\n#include <ctype.h>\n#include <string> \n#include <sstream>\n#include <iostream>\n#include <algorithm>\n#include <cstdlib>\n#include <map>\n#include <queue>\n#include <utility>\n#include <vector>\n#include <set>\n#include <list>\n#include <cstring>\n#include <stack>\n \nusing namespace std;\n\nint negation(int x)\n{\n if(x == 0) return 2;\n if(x == 2) return 0;\n return 1;\n}\n\nint conjuction(int x, int y)\n{\n if(x == 2 && y == 2) return 2;\n else if(x != 0 && y != 0) return 1;\n else return 0; \n}\n\nint disjunction(int x, int y){\n if(x == 2 || y == 2) return 2;\n else if(x == 1 || y == 1) return 1;\n else return 0;\n}\n\n\n\nint solve(string s, int p, int q, int r)\n{\n stack<int> st;\n stack<char> op;\n for(int i = 0; i < s.length(); i++){\n if(s[i] == '-' || s[i] == '+' || s[i] == '*'){\n op.push(s[i]);\n } else {\n int tmp1, tmp2;\n if(s[i] == '('){\n i++;\n string news = \"\";\n int kakkonum = 1;\n while(1){\n // cout << i << endl;\n if(s[i] == ')') kakkonum--;\n else if(s[i] == '(') kakkonum++;\n if(kakkonum == 0) break;\n news += s[i];\n i++;\n }\n // cout << news << endl;\n st.push(solve(news, p, q, r));\n } else if(isdigit(s[i])){\n st.push(s[i] - '0');\n } else {\n if(s[i] == 'P') st.push(p);\n else if(s[i] == 'Q') st.push(q);\n else st.push(r);\n }\n while(!op.empty() && op.top() == '-'){\n op.pop();\n tmp1 = st.top();\n st.pop();\n st.push(negation(tmp1));\n }\n if(!op.empty() && op.top() == '+'){\n op.pop();\n tmp1 = st.top();\n st.pop();\n tmp2 = st.top();\n st.pop();\n st.push(disjunction(tmp1, tmp2));\n } else if(!op.empty() && op.top() == '*'){\n op.pop();\n tmp1 = st.top();\n st.pop();\n tmp2 = st.top();\n st.pop();\n st.push(conjuction(tmp1, tmp2));\n }\n }\n }\n // cout << s << \" \" << p << \" \" << q << \" \" << r << \" \" << st.top() << endl;\n return st.top();\n}\n\nint main()\n{\n string s;\n while(1){\n cin >> s;\n if(s == \".\") break;\n int ans = 0;\n for(int i = 0; i < 3; i++){\n for(int j = 0; j < 3; j++){\n for(int k = 0; k < 3; k++){\n if(solve(s, i, j, k) == 2) ans++;\n }\n }\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1212, "score_of_the_acc": -1.0107, "final_rank": 8 }, { "submission_id": "aoj_1155_1846303", "code_snippet": "#include<iostream>\n#include<string>\nusing namespace std;\nint o=0;\nvoid rec(string str){\n //cout << str << endl;\n string next,buf;\n if('0'<=str[0]&&str[0]<='2'){\n //cout << str << endl;\n if(str[0]=='2') o++;\n return;\n }\n for(int i=1;i<str.size();i++){\n if('0'<=str[i]&&str[i]<='2') {\n if(str[i-1]=='-') {\n\tif(str[i]=='0') str[i]='2';\n\telse if(str[i]=='2') str[i]='0';\n\tstr[i-1]=' ';\n }else if(str[i-1]=='*') {\n\tif(str[i-3]=='('){\n\tif(str[i]=='0'||str[i-2]=='0') {\n\t str[i-3]=' ';\n\t str[i-2]=' ';\n\t str[i-1]=' ';\n\t str[i]='0';\n\t str[i+1]=' ';\n\t}else if(str[i]=='2'&&str[i-2]=='2') {\n\t str[i-3]=' ';\n\t str[i-2]=' ';\n\t str[i-1]=' ';\n\t str[i]='2';\n\t str[i+1]=' ';\n\t}else if('0'<=str[i-2]&&str[i-2]<='2'){\n\t str[i-3]=' ';\n\t str[i-2]=' ';\n\t str[i-1]=' ';\n\t str[i]='1';\n\t str[i+1]=' ';\n\t}\n\t}\n }else if(str[i-1]=='+') {\n\tif(str[i-3]=='('){\n\tif(str[i]=='2'||str[i-2]=='2') {\n\t str[i-3]=' ';\n\t str[i-2]=' ';\n\t str[i-1]=' ';\n\t str[i]='2';\n\t str[i+1]=' ';\n\t}else if(str[i]=='0'&&str[i-2]=='0') {\n\t str[i-3]=' ';\n\t str[i-2]=' ';\n\t str[i-1]=' ';\n\t str[i]='0';\n\t str[i+1]=' ';\n\t}else if('0'<=str[i-2]&&str[i-2]<='2'){\n\t str[i-3]=' ';\n\t str[i-2]=' ';\n\t str[i-1]=' ';\n\t str[i]='1';\n\t str[i+1]=' ';\n\t}\n\t}\n }\n }\n }\n for(int i=0;i<str.size();i++){\n if(str[i]!=' ') next+=str[i];\n }\n rec(next);\n}\nint main(){\n string str,buf;\n cin >> str;\n while(str!=\".\"){\n int p[]={0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2};\n int q[]={0,1,2,0,1,2,0,1,2,0,1,2,0,1,2,0,1,2,0,1,2,0,1,2,0,1,2};\n int r[]={0,0,0,1,1,1,2,2,2,0,0,0,1,1,1,2,2,2,0,0,0,1,1,1,2,2,2};\n o=0;\n for(int i=0;i<27;i++){\n buf=str;\n for(int j=0;j<str.size();j++){\n\tif(buf[j]=='P') buf[j]=p[i]+'0';\n\tif(buf[j]=='Q') buf[j]=q[i]+'0';\n\tif(buf[j]=='R') buf[j]=r[i]+'0';\n }\n rec(buf);\n }\n cout << o << endl;\n cin >> str;\n }\n \n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1200, "score_of_the_acc": -0.0053, "final_rank": 3 }, { "submission_id": "aoj_1155_1713222", "code_snippet": "#include<iostream>\n#include<string>\nusing namespace std;\n\nstring replacePQR(int p,int q,int r,string input){\n p += '0';\n q += '0';\n r += '0';\n for(int i=0;i<(int)input.size();i++){\n switch(input[i]){\n case 'P':\n input[i]=p;\n break;\n case 'Q':\n input[i]=q;\n break;\n case 'R':\n input[i]=r;\n break;\n }\n }\n return input;\n}\n\nstring solve(string input){\n // cout<<input<<endl; \n if((int)input.size()==1) return input;\n if(input[0]=='('){\n int paren=0;\n int i;\n char op;\n for(i=1;i<(int)input.size();i++){\n if(input[i]=='(') paren++;\n else if(input[i]==')') paren--;\n else if((input[i]=='+' || input[i]=='*' )&& paren == 0){\n\top=input[i];\n\tbreak;\n }\n }\n string s1,s2;\n s1=solve(input.substr(1,i-1));\n s2=solve(input.substr(i+1,(int)input.size()-2-i));\n if(op=='+'){\n if(s1[0]=='2' || s2[0]=='2') return string(1,'2');\n else if(s1[0]=='1' || s2[0]=='1') return string(1,'1');\n else return string(1,'0');\n }else{\n if(s1[0]=='0' || s2[0]=='0') return string(1,'0');\n else if(s1[0]=='1' || s2[0]=='1') return string(1,'1');\n else return string(1,'2');\n }\n }\n else{\n string s=solve(input.substr(1));\n if(s[0]=='0') s[0]+=2;\n else if(s[0]=='2') s[0]-=2;\n //cout<<\" (--\"<<s<<\"--)\"<<endl;\n return s;\n }\n\n}\n\nint main(){\n string input;\n while(cin>>input,input!=\".\"){\n int cnt=0;\n for(int p=0;p<3;p++){\n for(int q=0;q<3;q++){\n\tfor(int r=0;r<3;r++){\n\t string s;\n\t if((s=solve(replacePQR(p,q,r,input)))==\"2\") cnt++;\n\t //cout<<s<<endl;\n\t}\n }\n }\n cout<<cnt<<endl;\n \n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1196, "score_of_the_acc": -0.0036, "final_rank": 2 }, { "submission_id": "aoj_1155_1668735", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\nusing namespace std;\n\n#define MAX_N 10000\n\nint BIT(int C1,bool C2);\nint MINUS(int C3);\nint KAKE(int C4,int C5);\nint PLUS(int C6,int C7);\nstring TSTRING(int C8);\n\nstring S,T;\nint sum;\nchar U[4]=\"012\";\nint x[MAX_N];\n\nint BIT(int C1,bool C2){\n\tif(C2==true){return C1;}\n\treturn MINUS(C1);\n}\n\nint MINUS(int C3){\n\treturn 2-C3;\n}\nint PLUS(int C4,int C5){\n\treturn max(C4,C5);\n}\nint KAKE(int C6,int C7){\n\treturn min(C6,C7);\n}\n\nstring TSTRING(int C8)\n{\n\tif(C8==0)\n\t{\n\t\treturn \"0\";\n\t}\n\tif(C8==1)\n\t{\n\t\treturn \"1\";\n\t}\n\treturn \"2\";\n}\n\nint kaiseki2(string Z){\n\tint ans=3,ans2=3;\n\tbool ok=true;\n\tchar op=' ';\n\tfor(int i=0;i<Z.size();i++)\n\t{\n\t\tif(Z[i]=='-')\n\t\t{\n\t\t\tif(ok==true){ok=false;}\n\t\t\telse{ok=true;}\n\t\t}\n\t\tif(ans==3){\n\t\t\tif(Z[i]=='0')\n\t\t\t{\n\t\t\t\tans=BIT(0,ok);\n\t\t\t\tok=true;\n\t\t\t}\n\t\t\tif(Z[i]=='1')\n\t\t\t{\n\t\t\t\tans=BIT(1,ok);\n\t\t\t\tok=true;\n\t\t\t}\n\t\t\tif(Z[i]=='2')\n\t\t\t{\n\t\t\t\tans=BIT(2,ok);\n\t\t\t\tok=true;\n\t\t\t}\n\t\t}\n\t\telse{\n\t\t\tif(Z[i]=='0')\n\t\t\t{\n\t\t\t\tans2=BIT(0,ok);\n\t\t\t\tok=true;\n\t\t\t}\n\t\t\tif(Z[i]=='1')\n\t\t\t{\n\t\t\t\tans2=BIT(1,ok);\n\t\t\t\tok=true;\n\t\t\t}\n\t\t\tif(Z[i]=='2')\n\t\t\t{\n\t\t\t\tans2=BIT(2,ok);\n\t\t\t\tok=true;\n\t\t\t}\n\t\t}\n\t\tif(Z[i]=='+')\n\t\t{\n\t\t\top='+';\n\t\t}\n\t\tif(Z[i]=='*')\n\t\t{\n\t\t\top='*';\n\t\t}\n\t}\n\tif(op==' '){return ans;}\n\tif(op=='+'){return PLUS(ans,ans2);}\n\treturn KAKE(ans,ans2);\n}\n\nint kaiseki(string V){\n\twhile(V.size()>=2)\n\t{\n\t\tint s=0,maxn=0;\n\t\tstring W=\"\",X=\"\";\n\t\tfor(int i=0;i<V.size();i++)\n\t\t{\n\t\t\tif(V[i]=='(')\n\t\t\t{\n\t\t\t\ts++;\n\t\t\t}\n\t\t\tif(V[i]==')')\n\t\t\t{\n\t\t\t\ts--;\n\t\t\t}\n\t\t\tx[i]=s;\n\t\t\tmaxn=max(s,maxn);\n\t\t}\n\t\tfor(int i=0;i<V.size();i++)\n\t\t{\n\t\t\tif(x[i]==maxn)\n\t\t\t{\n\t\t\t\tif(V[i]!='(')\n\t\t\t\t{\n\t\t\t\t\tW+=V[i];\n\t\t\t\t}\n\t\t\t\tgoto E;\n\t\t\t}\n\t\t\tif(i>=1)\n\t\t\t{\n\t\t\t\tif(x[i-1]==maxn)\n\t\t\t\t{\n\t\t\t\t\tX+=TSTRING((long long)kaiseki2(W));\n\t\t\t\t\tW=\"\";\n\t\t\t\t\tgoto E;\n\t\t\t\t}\n\t\t\t}\n\t\t\tX+=V[i];\nE:;\n\t\t}\n\t\tV=X;\n\t}\n\tif(V==\"2\"){return 1;}\n\treturn 0;\n}\n\nint main(){\n\twhile(true){\n\t\tcin>>S;\n\t\tS='('+S+')';\n\t\tsum=0;\n\t\tif(S==\"(.)\"){break;}\n\t\tfor(int i=0;i<3;i++)\n\t\t{\n\t\t\tfor(int j=0;j<3;j++)\n\t\t\t{\n\t\t\t\tfor(int k=0;k<3;k++)\n\t\t\t\t{\n\t\t\t\t\tT=\"\";\n\t\t\t\t\tfor(int l=0;l<S.size();l++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif(S[l]=='P')\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tT+=U[i];\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if(S[l]=='Q')\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tT+=U[j];\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if(S[l]=='R')\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tT+=U[k];\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tT+=S[l];\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tsum+=kaiseki(T);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout<<sum<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1208, "score_of_the_acc": -0.0089, "final_rank": 4 }, { "submission_id": "aoj_1155_1599246", "code_snippet": "#include <bits/stdc++.h>\n#define PB push_back\n#define MP make_pair\n#define REP(i,n) for (int i=0;i<(n);i++)\n#define FOR(i,a,b) for(int i=(a);i<(b);i++)\n#define ALL(a) (a).begin(),(a).end()\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> P;\ndouble EPS=1e-10;\nint INF=1e9;\nint MOD=1000000007;\nint _and[3][3]={0,0,0,0,1,1,0,1,2};\nint _or[3][3]={0,1,2,1,1,2,2,2,2};\nint _not[3]={2,1,0};\nchar pyon(string s,int p,int q,int r){\n\tif(s.size()==1)return s[0]=='P'?p+'0':s[0]=='Q'?q+'0':s[0]=='R'?r+'0':s[0];\n\tint cnt=0,f,now=-1;\n\tvector<int> V;\n\tREP(i,s.size()){\n\t\tif(s[i]=='*')f=0;\n\t\telse if(s[i]=='+')f=1;\n\t\telse if(s[i]=='-')cnt++;\n\t\telse{\n\t\t\tint mt=s[i]=='P'?p:s[i]=='Q'?q:s[i]=='R'?r:s[i]-'0';\n\t\t\tif(cnt%2==1){\n\t\t\t\tmt=_not[mt];\n\t\t\t\tcnt=0;\n\t\t\t}\n\t\t\tif(now==-1)now=mt;\n\t\t\telse{\n\t\t\t\tif(f==0)now=_and[now][mt];\n\t\t\t\telse now=_or[now][mt];\n\t\t\t}\n\t\t}\n\t}\n\treturn now+'0';\n}\nchar rec(string s,int p,int q,int r){\n\tstack<int> pr;\n\tREP(i,s.size()){\n\t\tif(s[i]=='(')pr.push(i);\n\t\tif(s[i]==')'){\n\t\t\tint top=pr.top();pr.pop();\n\t\t\tstring t;\n\t\t\tt.assign(s,top+1,i-top-1);\n\t\t\tchar tt=pyon(t,p,q,r);\n\t\t\ts.erase(top,i-top+1);\n\t\t\ts.insert(s.begin()+top,tt);\n\t\t\ti=top-1;\n\t\t}\n\t}\n\tchar tt=pyon(s,p,q,r);\n\treturn tt;\n}\nint main(){\n\tstring s;\n\twhile(cin>>s&&s!=\".\"){\n\t\tint cnt=0;\n\t\tREP(i,3)REP(j,3)REP(k,3){\n\t\t\tchar t=rec(s,i,j,k);\n\t\t\tif(t=='2')cnt++;\n\t\t}\n\t\tcout<<cnt<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1220, "score_of_the_acc": -0.0143, "final_rank": 5 }, { "submission_id": "aoj_1155_1548472", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef string::iterator State;\ntypedef map<char, int> Env;\n\nint formula(State& state, Env env) {\n if ('0' <= *state && *state <= '2') {\n return *state++ - '0';\n }\n\n if ('P' <= *state && *state <= 'R') {\n return env[*state++];\n }\n\n if (*state == '-') {\n ++state;\n return 2 - formula(state, env);\n }\n\n ++state; // '('\n int lhs = formula(state, env);\n char op = *state++;\n int rhs = formula(state, env);\n ++state; // ')'\n\n if (op == '+') {\n return max(lhs, rhs);\n } else if (op == '*') {\n return min(lhs, rhs);\n }\n\n assert(false);\n}\n\n\nint main() {\n string expr;\n Env env;\n while (true) {\n cin >> expr;\n\n if (expr == \".\") {\n break;\n }\n\n int count = 0;\n\n for (int j = 0; j < 27; ++j) {\n env['P'] = j % 3;\n env['Q'] = (j / 3) % 3;\n env['R'] = j / 9;\n\n State state = expr.begin();\n if (formula(state, env) == 2) {\n ++count;\n }\n }\n \n cout << count << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1188, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_1152_cpp
Problem F: Dr. Podboq or: How We Became Asymmetric After long studying how embryos of organisms become asymmetric during their development, Dr. Podboq, a famous biologist, has reached his new hypothesis. Dr. Podboq is now preparing a poster for the coming academic conference, which shows a tree representing the development process of an embryo through repeated cell divisions starting from one cell. Your job is to write a program that transforms given trees into forms satisfying some conditions so that it is easier for the audience to get the idea. A tree representing the process of cell divisions has a form described below. The starting cell is represented by a circle placed at the top. Each cell either terminates the division activity or divides into two cells. Therefore, from each circle representing a cell, there are either no branch downward, or two branches down to its two child cells. Below is an example of such a tree. Figure F-1: A tree representing a process of cell divisions According to Dr. Podboq's hypothesis, we can determine which cells have stronger or weaker asymmetricity by looking at the structure of this tree representation. First, his hypothesis defines "left-right similarity" of cells as follows: The left-right similarity of a cell that did not divide further is 0. For a cell that did divide further, we collect the partial trees starting from its child or descendant cells, and count how many kinds of structures they have. Then, the left-right similarity of the cell is defined to be the ratio of the number of structures that appear both in the right child side and the left child side. We regard two trees have the same structure if we can make them have exactly the same shape by interchanging two child cells of arbitrary cells. For example, suppose we have a tree shown below: Figure F-2: An example tree The left-right similarity of the cell A is computed as follows. First, within the descendants of the cell B, which is the left child cell of A, the following three kinds of structures appear. Notice that the rightmost structure appears three times, but when we count the number of structures, we count it only once. Figure F-3: Structures appearing within the descendants of the cell B On the other hand, within the descendants of the cell C, which is the right child cell of A, the following four kinds of structures appear. Figure F-4: Structures appearing within the descendants of the cell C Among them, the first, second, and third ones within the B side are regarded as the same structure as the second, third, and fourth ones within the C side, respectively. Therefore, there are four structures in total, and three among them are common to the left side and the right side, which means the left-right similarity of A is 3/4. Given the left-right similarity of each cell, Dr. Podboq's hypothesis says we can determine which of the cells X and Y has stronger asymmetricity by the following rules. If X and Y have different left-righ ...(truncated)
[ { "submission_id": "aoj_1152_9685131", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<ll,ll> pi;\ntypedef vector<ll> vi;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\ntemplate<typename T>bool chmin(T&a,T b){if(a>b){a=b;return 1;}return 0;}\ntemplate<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;\nint main(){\n while(1){\n string S;\n getline(cin,S);\n if(S[0]=='0')return 0;\n ll N=S.size();\n vi par(N);\n {\n stack<ll>st;\n REP(i,N){\n if(S[i]=='(')st.emplace(i);\n if(S[i]==')')par[st.top()]=i,st.pop();\n }\n }\n map<string,vector<ld>>memo;\n memo[\"x\"]={0};\n function<vector<string>(ll,ll)>dfs=[&](ll l,ll r){\n if(r-l==1){\n assert(S[l]=='x');\n return vector<string>{\"x\"};\n }\n assert(par[l]==r-1);\n ll t=l+2;\n if(S[l+1]=='(')t=par[l+1]+1;\n assert(S[t]==' ');\n auto left=dfs(l+1,t),right=dfs(t+1,r-1);\n auto all=left;\n all.insert(all.end(),ALL(right));\n sort(ALL(all));\n all.erase(unique(ALL(all)),all.end());\n ll cnt=0;\n for(auto s:all)if(binary_search(ALL(left),s)&&binary_search(ALL(right),s))cnt++;\n auto L=memo[S.substr(l+1,t-l-1)],R=memo[S.substr(t+1,r-t-2)];\n if(L>R){\n swap(L,R);\n S=S.substr(0,l)+\"(\"+S.substr(t+1,r-t-2)+\" \"+S.substr(l+1,t-l-1)+\")\"+S.substr(r,N-r+1);\n t=l+r-t-1;\n }\n memo[S.substr(l,r-l)]={(ld)cnt/all.size()};\n memo[S.substr(l,r-l)].insert(memo[S.substr(l,r-l)].end(),ALL(L));\n memo[S.substr(l,r-l)].insert(memo[S.substr(l,r-l)].end(),ALL(R));\n all.emplace_back(S.substr(l,r-l));\n sort(ALL(all));\n return all;\n };\n dfs(0,N);\n {\n stack<ll>st;\n REP(i,N){\n if(S[i]=='(')st.emplace(i);\n if(S[i]==')')par[st.top()]=i,st.pop();\n }\n }\n bool left=1;\n function<void(ll,ll)>dfs2=[&](ll l,ll r){\n if(r-l==1)return;\n //cout<<l<<\" \"<<r<<endl;\n //cout<<S.substr(l,r-l)<<endl;\n assert(par[l]==r-1);\n ll t=l+2;\n if(S[l+1]=='(')t=par[l+1]+1;\n assert(S[t]==' ');\n if(left){\n left=1;\n dfs2(l+1,t);\n left=0;\n dfs2(t+1,r-1);\n }\n else{\n left=0;\n dfs2(l+1,t);\n left=1;\n dfs2(t+1,r-1);\n S=S.substr(0,l)+\"(\"+S.substr(t+1,r-t-2)+\" \"+S.substr(l+1,t-l-1)+\")\"+S.substr(r,N-r+1);\n }\n };\n dfs2(0,N);\n cout<<S<<endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3584, "score_of_the_acc": -0.0841, "final_rank": 10 }, { "submission_id": "aoj_1152_9370247", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\ntemplate < class T > vector< T >& operator++(vector< T >& a) { for(T& x : a) x++; return a; }\ntemplate < class T > vector< T >& operator--(vector< T >& a) { for(T& x : a) x--; return a; }\ntemplate < class T > vector< T > operator++(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x++; return res; }\ntemplate < class T > vector< T > operator--(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x--; return res; }\n\n} // namespace macro\n\nusing namespace macro;\n#line 3 \"A.cpp\"\n\nstring solve(string s) {\n vector<vector<int>> tree;\n auto expr = [&](auto self, int& i, int p) -> void {\n const int v = tree.size();\n tree.push_back({});\n if(p != -1) tree[p].push_back(v);\n if(s[i] == 'x') {\n i++;\n } else {\n assert(s[i] == '(');\n i++;\n self(self, i, v);\n assert(s[i] == ' ');\n i++;\n self(self, i, v);\n assert(s[i] == ')');\n i++;\n }\n }; { int i = 0; expr(expr, i, -1); }\n \n const int n = tree.size();\n vector<set<string>> hash(n);\n auto get_hash = [&](auto self, int v) -> string {\n if(tree[v].size() == 0) {\n hash[v].insert(\"()\");\n return \"()\";\n } else {\n const int L = tree[v][0];\n const int R = tree[v][1];\n string HL = self(self, L); for(string h : hash[L]) hash[v].insert(h);\n string HR = self(self, R); for(string h : hash[R]) hash[v].insert(h);\n string Hv = \"(\" + min(HL, HR) + max(HL, HR) + \")\";\n hash[v].insert(Hv);\n return Hv;\n }\n }; get_hash(get_hash, 0);\n\n auto sgn = [&](pair<int,int> a, pair<int,int> b) {\n int L = a.first * b.second;\n int R = b.first * a.second;\n if(L == R) return 0;\n return L < R ? -1 : +1;\n };\n\n vector<pair<int,int>> sim(n);\n for(int v : rep(n)) {\n if(tree[v].size() == 0) {\n sim[v] = {0, 1};\n } else {\n const int L = tree[v][0];\n const int R = tree[v][1];\n set<string> M;\n for(string h : hash[L]) M.insert(h);\n for(string h : hash[R]) M.insert(h);\n sim[v] = {hash[L].size() + hash[R].size() - M.size(), M.size()};\n }\n }\n\n vector memo(n, vector(n, -1));\n auto get_strong = [&](auto self, int L, int R) -> int {\n if(memo[L][R] != -1) return memo[L][R];\n if(sgn(sim[L], sim[R]) != 0) {\n return memo[L][R] = sgn(sim[L], sim[R]) == -1 ? L : R;\n } else if(not(tree[L].size() == 2 and tree[R].size() == 2)) {\n return memo[L][R] = L;\n } else {\n const int Ls = self(self, tree[L][0], tree[L][1]);\n const int Rs = self(self, tree[R][0], tree[R][1]);\n if(self(self, Ls, Rs) == self(self, Rs, Ls)) {\n return memo[L][R] = self(self, Ls, Rs) == Ls ? L : R;\n } else {\n const int Lw = (tree[L][0] + tree[L][1]) - Ls;\n const int Rw = (tree[R][0] + tree[R][1]) - Rs;\n if(self(self, Lw, Rw) == self(self, Rw, Lw)) {\n return memo[L][R] = self(self, Lw, Rw) == Lw ? L : R;\n } else {\n return memo[L][R] = L;\n }\n }\n }\n };\n\n auto trans = [&](auto self, int v, int s) -> void {\n if(tree[v].size() == 0) return;\n const int L = tree[v][0];\n const int R = tree[v][1];\n const int res = get_strong(get_strong, L, R);\n if((s == -1 and res == R) or (s == +1 and res == L)) {\n swap(sim[tree[v][0]], sim[tree[v][1]]);\n swap(tree[v][0], tree[v][1]);\n }\n self(self, tree[v][0], -1);\n self(self, tree[v][1], +1);\n }; trans(trans, 0, -1);\n\n auto ans = [&](auto self, int v) -> string {\n if(tree[v].size() == 0) {\n return \"x\";\n } else {\n return \"(\" + self(self, tree[v][0]) + \" \" + self(self, tree[v][1]) + \")\";\n }\n };\n return ans(ans, 0);\n}\n\nint main() {\n while(true) {\n string s;\n getline(cin, s);\n if(s[0] == '0') return 0;\n print(solve(s));\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3948, "score_of_the_acc": -0.1458, "final_rank": 16 }, { "submission_id": "aoj_1152_9370246", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\ntemplate < class T > vector< T >& operator++(vector< T >& a) { for(T& x : a) x++; return a; }\ntemplate < class T > vector< T >& operator--(vector< T >& a) { for(T& x : a) x--; return a; }\ntemplate < class T > vector< T > operator++(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x++; return res; }\ntemplate < class T > vector< T > operator--(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x--; return res; }\n\n} // namespace macro\n\nusing namespace macro;\n#line 3 \"A.cpp\"\n\nstring solve(string s) {\n vector<vector<int>> tree;\n auto expr = [&](auto self, int& i, int p) -> void {\n const int v = tree.size();\n tree.push_back({});\n if(p != -1) tree[p].push_back(v);\n if(s[i] == 'x') {\n i++;\n } else {\n assert(s[i] == '(');\n i++;\n self(self, i, v);\n assert(s[i] == ' ');\n i++;\n self(self, i, v);\n assert(s[i] == ')');\n i++;\n }\n }; { int i = 0; expr(expr, i, -1); }\n \n const int n = tree.size();\n vector<set<string>> hash(n);\n auto get_hash = [&](auto self, int v) -> string {\n if(tree[v].size() == 0) {\n hash[v].insert(\"()\");\n return \"()\";\n } else {\n const int L = tree[v][0];\n const int R = tree[v][1];\n string HL = self(self, L); for(string h : hash[L]) hash[v].insert(h);\n string HR = self(self, R); for(string h : hash[R]) hash[v].insert(h);\n string Hv = \"(\" + min(HL, HR) + max(HL, HR) + \")\";\n hash[v].insert(Hv);\n return Hv;\n }\n }; get_hash(get_hash, 0);\n\n auto sgn = [&](pair<int,int> a, pair<int,int> b) {\n int L = a.first * b.second;\n int R = b.first * a.second;\n if(L == R) return 0;\n return L < R ? -1 : +1;\n };\n\n vector<pair<int,int>> sim(n);\n for(int v : rep(n)) {\n if(tree[v].size() == 0) {\n sim[v] = {0, 1};\n } else {\n const int L = tree[v][0];\n const int R = tree[v][1];\n set<string> M;\n for(string h : hash[L]) M.insert(h);\n for(string h : hash[R]) M.insert(h);\n sim[v] = {hash[L].size() + hash[R].size() - M.size(), M.size()};\n }\n }\n\n map<pair<int,int>, int> memo;\n auto get_strong = [&](auto self, int L, int R) -> int {\n if(memo.count({L, R})) return memo[{L, R}];\n if(sgn(sim[L], sim[R]) != 0) {\n return memo[{L, R}] = sgn(sim[L], sim[R]) == -1 ? L : R;\n } else if(not(tree[L].size() == 2 and tree[R].size() == 2)) {\n return memo[{L, R}] = L;\n } else {\n const int Ls = self(self, tree[L][0], tree[L][1]);\n const int Rs = self(self, tree[R][0], tree[R][1]);\n if(self(self, Ls, Rs) == self(self, Rs, Ls)) {\n return memo[{L, R}] = self(self, Ls, Rs) == Ls ? L : R;\n } else {\n const int Lw = (tree[L][0] + tree[L][1]) - Ls;\n const int Rw = (tree[R][0] + tree[R][1]) - Rs;\n if(self(self, Lw, Rw) == self(self, Rw, Lw)) {\n return memo[{L, R}] = self(self, Lw, Rw) == Lw ? L : R;\n } else {\n return memo[{L, R}] = L;\n }\n }\n }\n };\n\n auto trans = [&](auto self, int v, int s) -> void {\n if(tree[v].size() == 0) return;\n const int L = tree[v][0];\n const int R = tree[v][1];\n const int res = get_strong(get_strong, L, R);\n if((s == -1 and res == R) or (s == +1 and res == L)) {\n swap(sim[tree[v][0]], sim[tree[v][1]]);\n swap(tree[v][0], tree[v][1]);\n }\n self(self, tree[v][0], -1);\n self(self, tree[v][1], +1);\n }; trans(trans, 0, -1);\n\n auto ans = [&](auto self, int v) -> string {\n if(tree[v].size() == 0) {\n return \"x\";\n } else {\n return \"(\" + self(self, tree[v][0]) + \" \" + self(self, tree[v][1]) + \")\";\n }\n };\n return ans(ans, 0);\n}\n\nint main() {\n while(true) {\n string s;\n getline(cin, s);\n if(s[0] == '0') return 0;\n print(solve(s));\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3856, "score_of_the_acc": -0.1302, "final_rank": 15 }, { "submission_id": "aoj_1152_9351348", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nbool is_end = false;\n\nvoid parse_input(string S, int &v, vector<int> &par, vector<array<int, 2>> &children)\n{\n int p = v;\n \n if (S == \"x\") return;\n \n // cout << S << \" \" << v << endl;\n assert(S[0] == '(');\n \n int mid = 0, sum = 0;\n for (int i = 1; i < S.length(); ++i)\n {\n if (S[i] == '(') sum++;\n else if (S[i] == ')') sum--;\n \n if (sum == 0) {mid = i + 1; break;}\n }\n \n string left = S.substr(1, mid - 1), right = S.substr(mid + 1);\n assert(right.back() == ')');\n right.pop_back();\n \n {\n v++;\n par[v] = p;\n children[p][0] = v;\n parse_input(left, v, par, children);\n \n v++;\n par[v] = p;\n children[p][1] = v;\n parse_input(right, v, par, children);\n }\n \n return;\n}\n\nusing ll = long long;\nconst ll MOD = 1e9 + 7;\n\nmt19937_64 engine(42);\n\nll calc_hash(int v, vector<int> &par, vector<array<int, 2>> &children, vector<ll> &height, vector<ll> &R, vector<ll> &hash)\n{\n ll mult = 1, mx = 0;\n for (auto nv : children[v])\n {\n if (nv == -1) continue;\n mult *= calc_hash(nv, par, children, height, R, hash);\n mult %= MOD;\n mx = max(mx, height[nv] + 1);\n }\n height[v] = mx;\n \n return hash[v] = (R[height[v]] + mult) % MOD;\n}\n\nusing ld = long double;\nconst ld EPS = 1e-9;\n\ninline bool eq(ld a, ld b)\n{\n return abs(a - b) < EPS;\n}\n\nstring make_output(int v, vector<array<int, 2>> &children)\n{\n if (children[v][0] == -1) return \"x\";\n \n auto [l, r] = children[v];\n string ret = \"\";\n ret += '(';\n ret += make_output(l, children);\n ret += ' ';\n ret += make_output(r, children);\n ret += ')';\n \n return ret;\n}\n\nvoid solve()\n{\n string S; getline(cin, S);\n if (S == \"0\")\n {\n is_end = true;\n return;\n }\n \n int N = 0;\n for (auto c : S)\n {\n if (c == 'x') N++;\n }\n \n N = 2 * N - 1;\n vector<int> par(N, -1);\n vector<array<int, 2>> children(N, {-1, -1});\n \n int r = 0;\n parse_input(S, r, par, children);\n \n vector<ll> R(N), hash(N, -1), height(N, -1);\n for (auto &r : R) r = engine() % MOD;\n calc_hash(0, par, children, height, R, hash);\n \n vector< set<ll> > des(N);\n for (int i = N - 1; i >= 0; --i)\n {\n des[i].insert(hash[i]);\n for (auto ni : children[i])\n {\n if (ni == -1) continue;\n des[i].insert(des[ni].begin(), des[ni].end());\n }\n }\n \n vector<ld> LRsame(N, 0.0);\n for (int i = 0; i < N; ++i)\n {\n if (children[i][0] == -1)\n {\n LRsame[i] = 0.0;\n continue;\n }\n \n int left = children[i][0], right = children[i][1];\n set<ll> stand, stor;\n stor = des[left];\n for (auto s : des[right])\n {\n if (stor.find(s) != stor.end()) stand.insert(s);\n stor.insert(s);\n }\n \n LRsame[i] = (ld)stand.size() / stor.size();\n }\n \n vector<vector<int>> lt(N, vector<int>(N, 0));\n for (int i = N - 1; i >= 0; --i)\n {\n for (int j = N - 1; j >= 0; --j)\n {\n if (hash[i] == hash[j])\n {\n lt[i][j] = 0;\n continue;\n }\n \n if (LRsame[i] - LRsame[j] < -EPS)\n {\n lt[i][j] = -1;\n }\n else if (LRsame[j] - LRsame[i] < -EPS)\n {\n lt[i][j] = 1;\n }\n else\n {\n auto [li, ri] = children[i];\n auto [lj, rj] = children[j];\n \n // cout << i << \" \" << li << \" \" << ri << endl;\n // cout << j << \" \" << lj << \" \" << rj << endl;\n assert(li != -1 && ri != -1 && lj != -1 && rj != -1);\n \n if (lt[li][ri] == -1) swap(li, ri);\n if (lt[lj][rj] == -1) swap(lj, rj);\n \n if (lt[ri][rj] != 0) lt[i][j] = lt[ri][rj];\n else if (lt[li][lj] != 0) lt[i][j] = lt[li][lj];\n else lt[i][j] = 0; \n }\n \n }\n }\n \n // change children\n vector<bool> isright(N, false);\n for (int i = 0; i < N; ++i)\n {\n if (children[i][0] == -1) continue;\n \n auto &[li, ri] = children[i];\n \n if (lt[li][ri] == -1) swap(li, ri); // here li < ri\n if (!isright[i]) swap(li, ri);\n \n isright[ri] = true;\n }\n \n string res = make_output(0, children);\n cout << res << endl;\n \n return;\n}\n\nint main()\n{\n while (!is_end)\n {\n solve();\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3608, "score_of_the_acc": -0.0881, "final_rank": 11 }, { "submission_id": "aoj_1152_6024680", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, t) for (int i = (int)(s); i < (int)(t); ++i)\n\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v) {\n for (int i = 0; i < (int) v.size(); ++i) cout << v[i] << \" \";\n return os;\n}\n\nvector<vector<int>> parse(string& s) {\n // build tree from s\n // returns the tree and the root\n\n vector<vector<int>> G;\n int k = 0;\n stack<int> st;\n for (char c : s) {\n if (c == ' ') continue;\n if (c == '(' || c == 'x') {\n st.push(k++);\n G.emplace_back();\n } else {\n int r = st.top(); st.pop();\n int l = st.top(); st.pop();\n int v = st.top();\n G[v] = {l, r};\n }\n }\n return G;\n}\n\nvoid output(vector<vector<int>>& G) {\n string s = \"\";\n auto dfs = [&](auto& dfs, int v) -> void {\n if (G[v].size() == 0) {\n s += 'x';\n } else {\n s += '(';\n dfs(dfs, G[v][0]);\n s += ' ';\n dfs(dfs, G[v][1]);\n s += ')';\n }\n };\n dfs(dfs, 0);\n cout << s << \"\\n\";\n}\n\nvector<vector<bool>> calc_isomorphism(vector<vector<int>>& G) {\n // check if subtree i and j are isomorphic\n\n int n = G.size();\n vector<vector<bool>> isomorphic(n, vector<bool>(n));\n vector<vector<bool>> checked(n, vector<bool>(n));\n auto dfs = [&](auto& dfs, int a, int b) -> void {\n if (checked[a][b]) return;\n checked[a][b] = checked[b][a] = true;\n if (G[a].empty() && G[b].empty()) {\n isomorphic[a][b] = isomorphic[b][a] = true;\n } else if (G[a].empty() || G[b].empty()) {\n isomorphic[a][b] = isomorphic[b][a] = false;\n } else {\n int al = G[a][0], ar = G[a][1];\n int bl = G[b][0], br = G[b][1];\n dfs(dfs, al, bl);\n dfs(dfs, al, br);\n dfs(dfs, ar, bl);\n dfs(dfs, ar, br);\n if ((isomorphic[al][bl] && isomorphic[ar][br]) || (isomorphic[al][br] && isomorphic[ar][bl])) {\n isomorphic[a][b] = isomorphic[b][a] = true;\n } else {\n isomorphic[a][b] = isomorphic[b][a] = false;\n }\n }\n };\n rep(i,0,n-1) rep(j,i+1,n) dfs(dfs, i, j);\n return isomorphic;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(15);\n\n while (1) {\n string s;\n getline(cin, s);\n if (s == \"0\") break;\n\n auto G = parse(s);\n int n = G.size();\n\n auto isomorphic = calc_isomorphism(G);\n\n // get all subtrees for each node\n vector<vector<int>> subtrees(n);\n vector<int> par(n, -1);\n auto dfs = [&](auto& dfs, int v, vector<int> ancestor) -> void {\n for (int a : ancestor) {\n subtrees[a].push_back(v);\n }\n subtrees[v].push_back(v);\n for (int c : G[v]) {\n par[c] = v;\n ancestor.push_back(v);\n dfs(dfs, c, ancestor);\n ancestor.pop_back();\n }\n };\n dfs(dfs, 0, {});\n\n // calculate ruijido\n vector<double> ruijido(n);\n rep(i,0,n) {\n if (G[i].size() == 0) continue;\n int l = G[i][0], r = G[i][1];\n vector<int> left, right;\n // get all left shapes\n for (int v : subtrees[l]) {\n bool ok = true;\n for (int u : left) {\n if (isomorphic[v][u]) {\n ok = false;\n break;\n }\n }\n if (ok) left.push_back(v);\n }\n // get all right shapes\n for (int v : subtrees[r]) {\n bool ok = true;\n for (int u : right) {\n if (isomorphic[u][v]) {\n ok = false;\n break;\n }\n }\n if (ok) right.push_back(v);\n }\n // calc ruijido\n int cnt = left.size(), same = 0;\n for (int v : right) {\n bool ok = false;\n for (int u : left) {\n if (isomorphic[u][v]) {\n ok = true;\n break;\n }\n }\n if (ok) {\n ++same;\n } else {\n ++cnt;\n }\n }\n ruijido[i] = 1.0*same/cnt;\n }\n\n // calc hitaishosei\n vector<vector<int>> hitaishou(n, vector<int>(n,-1)); // -1: not calculated, 0: same, 1: i>j, 2: i<j\n auto dfs2 = [&](auto& dfs2, int a, int b) -> void {\n if (hitaishou[a][b] != -1) return;\n if (abs(ruijido[a] - ruijido[b]) > 1e-8) {\n // 1\n if (ruijido[a] < ruijido[b]) {\n hitaishou[a][b] = 1;\n hitaishou[b][a] = 2;\n } else {\n hitaishou[a][b] = 2;\n hitaishou[b][a] = 1;\n }\n } else if (G[a].size() == 0 && G[b].size() == 0) {\n // 2\n hitaishou[a][b] = hitaishou[b][a] = 0;\n } else {\n int as, aw, bs, bw;\n {\n int l = G[a][0], r = G[a][1];\n dfs2(dfs2, l, r);\n if (hitaishou[l][r] == 1) {\n as = l, aw = r;\n } else {\n as = r, aw = l;\n }\n }\n {\n int l = G[b][0], r = G[b][1];\n dfs2(dfs2, l, r);\n if (hitaishou[l][r] == 1) {\n bs = l, bw = r;\n } else {\n bs = r, bw = l;\n }\n }\n dfs2(dfs2, as, bs);\n if (hitaishou[as][bs] != 0) {\n // 3\n if (hitaishou[as][bs] == 1) {\n hitaishou[a][b] = 1;\n hitaishou[b][a] = 2;\n } else {\n hitaishou[a][b] = 2;\n hitaishou[b][a] = 1;\n }\n } else {\n dfs2(dfs2, aw, bw);\n // 4, 5\n if (hitaishou[aw][bw] == 1) {\n hitaishou[a][b] = 1;\n hitaishou[b][a] = 2;\n } else if (hitaishou[aw][bw] == 2) {\n hitaishou[a][b] = 2;\n hitaishou[b][a] = 1;\n } else {\n hitaishou[a][b] = hitaishou[b][a] = 0;\n }\n }\n }\n };\n rep(i,0,n) {\n if (G[i].size() != 0) {\n dfs2(dfs2, G[i][0], G[i][1]);\n }\n }\n\n // solve\n auto rec = [&](auto& rec, int v) -> void {\n if (G[v].size() == 0) return;\n int l = G[v][0], r = G[v][1];\n if ((v == 0 || G[par[v]][0] == v) ^ (hitaishou[l][r] == 1)) {\n swap(G[v][0], G[v][1]);\n }\n for (int c : G[v]) rec(rec, c);\n };\n rec(rec, 0);\n\n output(G);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3700, "score_of_the_acc": -0.1037, "final_rank": 14 }, { "submission_id": "aoj_1152_6021422", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n#define all(x) (x).begin(),(x).end()\n#define fi first\n#define se second\n#define mp make_pair\n#define si(x) int(x.size())\nconst int mod=998244353,MAX=205,INF=1<<30;\n\n#define ld long double\n\nint N;\nvector<int> G[MAX];\nstring T[MAX];\nset<string> SE[MAX];\nbool leaf[MAX];\nld ruizi[MAX];\nint strong[MAX][MAX];\n\nstring makeT(int u){\n if(leaf[u]){\n return T[u]=\"()\";\n }else{\n vector<string> U;\n for(int to:G[u]){\n U.push_back(makeT(to));\n }\n sort(all(U));\n string res;\n res+='(';\n res+=U[0];\n res+=U[1];\n res+=')';\n return T[u]=res;\n }\n}\n\nvoid calc(int u){\n SE[u].insert(T[u]);\n if(leaf[u]){\n ruizi[u]=0;\n return;\n }else{\n map<string,int> MA;\n for(int i=1;i<=si(G[u]);i++){\n int to=G[u][i-1];\n calc(to);\n for(auto a:SE[to]){\n MA[a]|=i;\n }\n }\n for(auto a:MA) SE[u].insert(a.fi);\n int ok=0;\n for(auto a:MA) if(a.se==3) ok++;\n ruizi[u]=(ld)ok/(ld)si(MA);\n }\n}\n\nvoid makerank(){\n for(int i=N-1;i>=0;i--){\n for(int j=i+1;j<N;j++){\n if(ruizi[i]!=ruizi[j]){\n if(ruizi[i]<ruizi[j]){\n strong[i][j]=1;\n strong[j][i]=-1;\n }else{\n strong[j][i]=1;\n strong[i][j]=-1;\n }\n }else{\n if(leaf[i]&&leaf[j]){\n strong[i][j]=strong[j][i]=0;\n }else{\n int a,b;\n if(strong[G[i][0]][G[i][1]]>=0) a=G[i][0];\n else a=G[i][1];\n \n if(strong[G[j][0]][G[j][1]]>=0) b=G[j][0];\n else b=G[j][1];\n \n if(strong[a][b]==1){\n strong[i][j]=1;\n strong[j][i]=-1;\n continue;\n }\n if(strong[b][a]==1){\n strong[j][i]=1;\n strong[i][j]=-1;\n continue;\n }\n \n a=G[i][0]+G[i][1]-a;\n b=G[j][0]+G[j][1]-b;\n \n if(strong[a][b]==1){\n strong[i][j]=1;\n strong[j][i]=-1;\n continue;\n }\n if(strong[b][a]==1){\n strong[j][i]=1;\n strong[i][j]=-1;\n continue;\n }\n \n strong[i][j]=strong[j][i]=0;\n }\n }\n }\n }\n}\n\nvoid sorting(int u,bool mirror){\n if(leaf[u]) return;\n if(!mirror){\n int a=G[u][0],b=G[u][1];\n if(strong[a][b]>=0){\n sorting(a,0);\n sorting(b,1);\n }else{\n swap(G[u][0],G[u][1]);\n sorting(b,0);\n sorting(a,1);\n }\n }else{\n int a=G[u][0],b=G[u][1];\n if(strong[a][b]>=0){\n swap(G[u][0],G[u][1]);\n sorting(a,1);\n sorting(b,0);\n }else{\n sorting(a,0);\n sorting(b,1);\n }\n }\n}\n\nvoid output(int u){\n if(leaf[u]){\n cout<<'x';\n return;\n }\n cout<<'(';\n output(G[u][0]);\n cout<<' ';\n output(G[u][1]);\n cout<<')';\n}\n\nstring S;\n\nvoid expr(int &i){\n if(S[i]=='x'){\n leaf[N]=true;\n N++;\n i++;\n }else{\n assert(S[i]=='(');\n int u=N;\n N++;\n i++;\n G[u].push_back(N);\n //cout<<u<<\" \"<<N<<endl;\n expr(i);\n assert(S[i]==' ');\n i++;\n G[u].push_back(N);\n //cout<<u<<\" \"<<N<<endl;\n expr(i);\n assert(S[i]==')');\n i++;\n }\n}\n\nvoid init(){\n N=0;\n for(int i=0;i<MAX;i++){\n G[i].clear();\n T[i]=\"\";\n SE[i].clear();\n leaf[i]=0;\n ruizi[i]=0;\n for(int j=0;j<MAX;j++) strong[i][j]=0;\n }\n}\n\nint main() {\n \n std::ifstream in(\"text.txt\");\n std::cin.rdbuf(in.rdbuf());\n cin.tie(0);\n ios::sync_with_stdio(false);\n \n while(1){\n getline(cin,S);\n if(S==\"0\") return 0;\n init();\n int i=0;\n expr(i);\n makeT(0);\n calc(0);\n makerank();\n sorting(0,0);\n output(0);\n cout<<\"\\n\";\n }\n \n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3976, "score_of_the_acc": -0.1505, "final_rank": 17 }, { "submission_id": "aoj_1152_5497827", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n \nusing ll = long long int;\nusing ull = unsigned long long int;\nusing P = pair<int, int>;\n \n#define ALL(v) (v).begin(),(v).end()\n#define REP(i,n) for(int i=0,i_len=n; i<i_len; ++i)\n\nstruct Tree{\n Tree *left = nullptr, *right = nullptr;\n set<string> S;\n P sim;\n Tree(){}\n};\n\nbool operator<(const P& lhs, const P& rhs) {return lhs.first*rhs.second > rhs.first*lhs.second;}\nbool operator>(const P& lhs, const P& rhs) {return rhs < lhs;}\nbool operator==(const P& lhs, const P& rhs) {return lhs.first*rhs.second == rhs.first*lhs.second;}\nbool operator!=(const P& lhs, const P& rhs) {return !(lhs==rhs);}\n\nvector<Tree> trees(256);\n\nusing State = std::string::const_iterator;\n\nvoid decode(State &itr, int &idx){\n trees[idx] = Tree();\n int k = idx++;\n\n if(*itr == '('){\n itr++;\n trees[k].left = &trees[idx];\n decode(itr,idx);\n itr++; // blank\n trees[k].right = &trees[idx];\n decode(itr,idx);\n itr++; // ')'\n }\n else if(*itr == 'x'){\n itr++;\n }\n else{\n cerr << \"invalid\" << endl;\n }\n}\n\nbool is_leaf(Tree &tree){\n return tree.left == nullptr && tree.right == nullptr;\n}\n\nvoid encode(Tree &tree, string &str){\n if(is_leaf(tree)){\n str.push_back('x');\n }else{\n str.push_back('(');\n if(tree.left != nullptr){\n encode(*tree.left, str);\n }\n str.push_back(' ');\n if(tree.right != nullptr){\n encode(*tree.right, str);\n }\n str.push_back(')');\n }\n}\n\nP similarity(Tree &tree){\n if(is_leaf(tree)){\n return P(0,1);\n }else{\n set<string> lhs = tree.left->S, rhs = tree.right->S, U;\n U.insert(ALL(lhs));\n U.insert(ALL(rhs));\n return P(lhs.size()+rhs.size()-U.size(), U.size());\n }\n}\n\nint compare(Tree &lhs, Tree &rhs){\n if(lhs.sim != rhs.sim){\n return lhs.sim < rhs.sim;\n }else if(is_leaf(lhs) && is_leaf(rhs)){\n return 2;\n }else{\n int res = compare(*lhs.left, *rhs.left);\n if(res != 2) return res;\n else return compare(*lhs.right, *rhs.right);\n }\n}\n\n\n// 全ての頂点で similarity が left < right となるように変換する\nvoid normalize(Tree &tree){\n if(is_leaf(tree)){\n tree.S.insert(\"x\");\n return;\n }else{\n // recursive\n normalize(*tree.left);\n normalize(*tree.right);\n // compare\n tree.left->sim = similarity(*tree.left);\n tree.right->sim = similarity(*tree.right);\n if(compare(*tree.left, *tree.right)%2 == 1){\n swap(tree.left, tree.right);\n }\n // construct tree.S\n tree.S.clear();\n string str = \"\";\n encode(tree, str);\n tree.S.insert(str);\n tree.S.insert(ALL(tree.left->S));\n tree.S.insert(ALL(tree.right->S));\n return;\n }\n}\n\nvoid transform(Tree &tree, bool rev){\n if(is_leaf(tree)) return;\n \n if(rev) swap(tree.left, tree.right);\n\n transform(*tree.left, false);\n transform(*tree.right, true);\n\n}\n\nint solve(){\n string s;\n getline(cin, s);\n if(s == \"0\") return 1;\n\n State itr = s.begin();\n int idx = 0;\n decode(itr, idx);\n Tree &root = trees[0];\n\n normalize(root);\n transform(root, false);\n\n string ans = \"\";\n encode(root, ans);\n cout << ans << endl;\n\n return 0;\n}\n\nint main(){\n while(!solve());\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3696, "score_of_the_acc": -0.1031, "final_rank": 13 }, { "submission_id": "aoj_1152_5445839", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD = 1000000007;\nvoid parse(string &S, int &p, vector<vector<int>> &c, int v){\n if (S[p] == '('){\n p++;\n int sz1 = c.size();\n c[v].push_back(sz1);\n c.push_back(vector<int>());\n parse(S, p, c, sz1);\n p++;\n int sz2 = c.size();\n c[v].push_back(sz2);\n c.push_back(vector<int>());\n parse(S, p, c, sz2);\n p++;\n } else {\n p++;\n }\n}\nint main(){\n random_device rnd;\n mt19937 mt(rnd());\n while (true){\n string S;\n getline(cin, S);\n if (S == \"0\"){\n break;\n }\n vector<vector<int>> c;\n c.push_back(vector<int>());\n int pos = 0;\n parse(S, pos, c, 0);\n int N = c.size();\n vector<int> p(N, -1);\n for (int i = 0; i < N; i++){\n for (int j : c[i]){\n p[j] = i;\n }\n }\n vector<long long> base(N);\n for (int i = 0; i < N; i++){\n base[i] = mt() % MOD;\n }\n vector<int> d(N, 0);\n vector<int> bfs;\n queue<int> Q;\n Q.push(0);\n while (!Q.empty()){\n int v = Q.front();\n Q.pop();\n bfs.push_back(v);\n for (int w : c[v]){\n d[w] = d[v] + 1;\n Q.push(w);\n }\n }\n reverse(bfs.begin(), bfs.end());\n vector<long long> hash(N);\n for (int i = 0; i < N; i++){\n vector<long long> dp(N, 1);\n for (int v : bfs){\n for (int w : c[v]){\n dp[v] *= base[d[v] - d[i]] + dp[w];\n dp[v] %= MOD;\n }\n if (v == i){\n break;\n }\n }\n hash[i] = dp[i];\n }\n vector<set<long long>> st(N);\n for (int i = 0; i < N; i++){\n int v = i;\n while (true){\n st[v].insert(hash[i]);\n if (v == 0){\n break;\n }\n v = p[v];\n }\n }\n vector<int> num(N), den(N);\n for (int i = 0; i < N; i++){\n if (c[i].empty()){\n num[i] = 0;\n den[i] = 1;\n } else {\n int l = c[i][0];\n int r = c[i][1];\n set<int> st1, st2;\n for (long long x : st[l]){\n st1.insert(x);\n }\n for (long long x : st[r]){\n st1.insert(x);\n if (st[l].count(x)){\n st2.insert(x);\n }\n }\n num[i] = st2.size();\n den[i] = st1.size();\n }\n }\n vector<vector<int>> comp(N, vector<int>(N));\n for (int v : bfs){\n for (int w : bfs){\n if (d[v] == d[w]){\n if (num[v] * den[w] < num[w] * den[v]){\n comp[v][w] = 1;\n } else if (num[v] * den[w] > num[w] * den[v]){\n comp[v][w] = -1;\n } else if (c[v].empty() && c[w].empty()){\n comp[v][w] = 0;\n } else {\n int l1 = c[v][0];\n int r1 = c[v][1];\n int l2 = c[w][0];\n int r2 = c[w][1];\n if (comp[r1][l1] == 1){\n swap(l1, r1);\n }\n if (comp[r2][l2] == 1){\n swap(l2, r2);\n }\n if (comp[l1][l2] == 1){\n comp[v][w] = 1;\n } else if (comp[l1][l2] == -1){\n comp[v][w] = -1;\n } else if (comp[r1][r2] == 1){\n comp[v][w] = 1;\n } else if (comp[r1][r2] == -1){\n comp[v][w] = -1;\n } else {\n comp[v][w] = 0;\n }\n }\n }\n }\n }\n reverse(bfs.begin(), bfs.end());\n for (int v : bfs){\n if (!c[v].empty()){\n bool R = false;\n if (v != 0){\n if (v == c[p[v]][1]){\n R = true;\n }\n }\n int l = c[v][0];\n int r = c[v][1];\n if (!R){\n if (comp[l][r] == -1){\n swap(c[v][0], c[v][1]);\n }\n } else {\n if (comp[l][r] == 1){\n swap(c[v][0], c[v][1]);\n }\n }\n }\n }\n vector<string> dp(N);\n reverse(bfs.begin(), bfs.end());\n for (int v : bfs){\n if (c[v].empty()){\n dp[v] = \"x\";\n } else {\n int l = c[v][0];\n int r = c[v][1];\n dp[v] = \"(\" + dp[l] + \" \" + dp[r] + \")\";\n }\n }\n cout << dp[0] << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3296, "score_of_the_acc": -0.0353, "final_rank": 6 }, { "submission_id": "aoj_1152_5409003", "code_snippet": "#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<ciso646>\n#include<random>\n#include<map>\n#include<set>\n#include<bitset>\n#include<stack>\n#include<unordered_map>\n#include<unordered_set>\n#include<utility>\n#include<cassert>\n#include<complex>\n#include<numeric>\n#include<array>\nusing namespace std;\n\n//#define int long long\ntypedef long long ll;\n\ntypedef unsigned long long ul;\ntypedef unsigned int ui;\nconstexpr ll mod = 1000000009;\nconst ll INF = mod * mod;\ntypedef pair<int, int>P;\n#define stop char nyaa;cin>>nyaa;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define per(i,n) for(int i=n-1;i>=0;i--)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define per1(i,n) for(int i=n;i>=1;i--)\n#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)\n#define all(v) (v).begin(),(v).end()\ntypedef pair<ll, ll> LP;\ntypedef long double ld;\ntypedef pair<ld, ld> LDP;\nconst ld eps = 1e-12;\nconst ld pi = acosl(-1.0);\n\nll mod_pow(ll x, ll n, ll m = mod) {\n\tif (n < 0) {\n\t\tll res = mod_pow(x, -n, m);\n\t\treturn mod_pow(res, m - 2, m);\n\t}\n\tif (abs(x) >= m)x %= m;\n\tif (x < 0)x += m;\n\tll res = 1;\n\twhile (n) {\n\t\tif (n & 1)res = res * x % m;\n\t\tx = x * x % m; n >>= 1;\n\t}\n\treturn res;\n}\nstruct modint {\n\tll n;\n\tmodint() :n(0) { ; }\n\tmodint(ll m) :n(m) {\n\t\tif (n >= mod)n %= mod;\n\t\telse if (n < 0)n = (n % mod + mod) % mod;\n\t}\n\toperator int() { return n; }\n};\nbool operator==(modint a, modint b) { return a.n == b.n; }\nmodint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }\nmodint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }\nmodint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }\nmodint operator+(modint a, modint b) { return a += b; }\nmodint operator-(modint a, modint b) { return a -= b; }\nmodint operator*(modint a, modint b) { return a *= b; }\nmodint operator^(modint a, ll n) {\n\tif (n == 0)return modint(1);\n\tmodint res = (a * a) ^ (n / 2);\n\tif (n % 2)res = res * a;\n\treturn res;\n}\n\nll inv(ll a, ll p) {\n\treturn (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);\n}\nmodint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }\nmodint operator/=(modint& a, modint b) { a = a / b; return a; }\nconst int max_n = 1 << 18;\nmodint fact[max_n], factinv[max_n];\nvoid init_f() {\n\tfact[0] = modint(1);\n\tfor (int i = 0; i < max_n - 1; i++) {\n\t\tfact[i + 1] = fact[i] * modint(i + 1);\n\t}\n\tfactinv[max_n - 1] = modint(1) / fact[max_n - 1];\n\tfor (int i = max_n - 2; i >= 0; i--) {\n\t\tfactinv[i] = factinv[i + 1] * modint(i + 1);\n\t}\n}\nmodint comb(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[b] * factinv[a - b];\n}\nmodint combP(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[a - b];\n}\n\nint dx[4] = { 1,0,-1,0 };\nint dy[4] = { 0,1,0,-1 };\n\n\nstring s;\nvector<vector<int>> G(128);\nint tmp = 0;\nint expr(string& s, int& loc) {\n\tif (s[loc] == '(') {\n\t\tint mem = tmp;\n\t\tloc++; tmp++;\n\t\tint lch = expr(s, loc);\n\t\tloc++;\n\t\tint rch = expr(s, loc);\n\t\tloc++;\n\t\tG[mem].push_back(lch);\n\t\tG[mem].push_back(rch);\n\t\treturn mem;\n\t}\n\telse {\n\t\tint res = tmp;\n\t\ttmp++; loc++;\n\t\treturn res;\n\t}\n}\nvoid solve() {\n\tG.resize(128);\n\trep(i, 128)G[i].clear();\n\ttmp = 0;\n\tint loc = 0;\n\texpr(s, loc);\n\t//cout << \"! \" << loc << \" \" << s.size() << \"\\n\";\n\tassert(loc == s.size());\n\t//cout << \"! \" << tmp << \"\\n\";\n\tG.resize(tmp);\n\tint root = 0;\n\tvector<string> vs(tmp);\n\tfunction<void(int)> dfs = [&](int id) {\n\t\tvector<string> nexs;\n\t\tfor (int to : G[id]) {\n\t\t\tdfs(to);\n\t\t\tnexs.push_back(vs[to]);\n\t\t}\n\t\tsort(all(nexs));\n\t\tstring res;\n\t\trep(i, nexs.size())res += nexs[i];\n\t\tres = \"(\" + res + \")\";\n\t\tvs[id] = res;\n\t};\n\tdfs(0);\n\tvector<ld> lr(tmp);\n\tfunction<vector<string>(int)> dfs2 = [&](int id)->vector<string> {\n\t\tif (G[id].empty()) {\n\t\t\tlr[id] = 0;\n\t\t\treturn { vs[id] };\n\t\t}\n\t\telse {\n\t\t\tvector<string> al;\n\t\t\tvector<string> lch = dfs2(G[id][0]);\n\t\t\tvector<string> rch = dfs2(G[id][1]);\n\t\t\tfor (string s : lch)al.push_back(s);\n\t\t\tfor (string s : rch)al.push_back(s);\n\t\t\tsort(all(al));\n\t\t\tal.erase(unique(all(al)), al.end());\n\t\t\tint leid = 0, riid = 0;\n\t\t\tint c = 0;\n\t\t\trep(i, al.size()) {\n\t\t\t\tbool lexi = false, rexi = false;\n\t\t\t\twhile (leid < lch.size() && lch[leid] < al[i])leid++;\n\t\t\t\twhile (riid < rch.size() && rch[riid] < al[i])riid++;\n\t\t\t\tif (leid < lch.size() && lch[leid] == al[i])lexi = true;\n\t\t\t\tif (riid < rch.size() && rch[riid] == al[i])rexi = true;\n\t\t\t\tif (lexi && rexi) {\n\t\t\t\t\tc++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tlr[id] = c / (ld)(al.size());\n\t\t\tal.push_back(vs[id]);\n\t\t\tsort(all(al));\n\t\t\treturn al;\n\t\t}\n\t};\n\tdfs2(0);\n\t//rep(i, tmp)cout << lr[i] << \"\\n\";\n\tvector<vector<int>> isg(tmp, vector<int>(tmp));\n\tvector<vector<bool>> chked(tmp, vector<bool>(tmp));\n\tfunction<int(int, int)> iss=[&](int a, int b)->int {\n\t\tif (chked[a][b])return isg[a][b];\n\t\tchked[a][b] = true;\n\t\tint res;\n\t\tif (abs(lr[a] - lr[b]) > (1e-8)) {\n\t\t\tres= (lr[a] > lr[b]);\n\t\t}\n\t\telse {\n\t\t\tif (G[a].empty()) {\n\t\t\t\tres = 2;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tint c = G[a][0];\n\t\t\t\tif (iss(G[a][0], G[a][1]))c = G[a][1];\n\t\t\t\tint d = G[b][0];\n\t\t\t\tif (iss(G[b][0], G[b][1]))d = G[b][1];\n\t\t\t\tif (iss(c, d) != 2) {\n\t\t\t\t\tres = iss(c, d);\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tc = G[a][0] ^ G[a][1] ^ c;\n\t\t\t\t\td = G[b][0] ^ G[b][1] ^ d;\n\t\t\t\t\tif (iss(c, d) != 2) {\n\t\t\t\t\t\tres = iss(c, d);\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\tres = 2;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn isg[a][b] = res;\n\t};\n\tvector<vector<int>> fG(tmp);\n\tqueue<P> q; q.push({ 0,1 });\n\twhile (!q.empty()) {\n\t\tP p = q.front(); q.pop();\n\t\tint id = p.first;\n\t\tif (G[id].empty())continue;\n\t\tint le = G[id][0];\n\t\tif (iss(G[id][0], G[id][1]))le = G[id][1];\n\t\tint ri = G[id][0] ^ G[id][1] ^ le;\n\t\tif (!p.second)swap(le, ri);\n\t\tfG[id].push_back(le);\n\t\tfG[id].push_back(ri);\n\t\tq.push({ le,1 });\n\t\tq.push({ ri,0 });\n\t}\n\tstring ans;\n\tfunction<void(int)> ansdfs = [&](int id) {\n\t\tif (fG[id].empty()) {\n\t\t\tans.push_back('x'); \n\t\t}\n\t\telse {\n\t\t\tans.push_back('(');\n\t\t\tansdfs(fG[id][0]);\n\t\t\tans.push_back(' ');\n\t\t\tansdfs(fG[id][1]);\n\t\t\tans.push_back(')');\n\t\t}\n\t};\n\tansdfs(0);\n\t//cout << \"ans is \";\n\tcout << ans << \"\\n\";\n}\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\t//cout << fixed << setprecision(10);\n\t//init_f();\n\t//init();\n\t//expr();\n\t//int t; cin >> t;rep(i,t)\n\twhile (getline(cin, s)) {\n\t\tif (s[0] == '0')break;\n\t\tsolve();\n\t}\n\t//solve();\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7780, "score_of_the_acc": -0.7953, "final_rank": 18 }, { "submission_id": "aoj_1152_3609700", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> l_l;\ntypedef pair<int, int> i_i;\n\n#define EPS (1e-7)\n#define INF (1e9)\n#define PI (acos(-1))\n//const ll mod = 1000000007;\nint num = 0;\nvector<int> children[200];\nint parent[200];\nset<string> subtree[200];\nstring tree[200];\ndouble val[200];\nint win(int a, int b);\nvoid dfs(int from) {\n //cerr << \"DFS: \" << from << endl;\n subtree[from].clear();\n tree[from].clear();\n val[from] = 0;\n if(children[from].empty()) {\n tree[from] = \"()\";\n subtree[from].insert(\"()\");\n return;\n }\n vector<string> now;\n for(int i = 0; i < children[from].size(); i++) {\n int to = children[from][i];\n dfs(to);\n now.push_back(tree[to]);\n for(auto itr = subtree[to].begin(); itr != subtree[to].end(); itr++) {\n subtree[from].insert(*itr);\n }\n }\n sort(now.begin(), now.end());\n tree[from] = \"(\" + now[0] + now[1] + \")\";\n subtree[from].insert(tree[from]);\n set<string> uni;\n set_intersection(subtree[children[from][0]].begin(), subtree[children[from][0]].end(), subtree[children[from][1]].begin(), subtree[children[from][1]].end(), inserter(uni, uni.end()));\n val[from] = (double)(uni.size()) / (double)(subtree[from].size() - 1);\n if(win(children[from][1], children[from][0]) == 1) swap(children[from][0], children[from][1]);\n //cerr << from << endl << tree[from] << endl << val[from] << endl;\n}\n\nvoid dfs2(int from, bool isleft) {\n if(children[from].empty()) return;\n if(!isleft) swap(children[from][0], children[from][1]);\n dfs2(children[from][0], true);\n dfs2(children[from][1], false);\n}\n\nint win(int a, int b) {\n if(val[a] + EPS < val[b]) return 1;\n if(val[a] > val[b] + EPS) return -1;\n if(children[a].empty()) return 0;\n int l = children[a][0];\n int r = children[b][0];\n int tmp = win(l, r);\n if(tmp != 0) return tmp;\n return win(children[a][1], children[b][1]);\n}\n\nvoid f(int from, string::iterator &itr) {\n num++;\n //cerr << num << \" \" << from << \" \" << *itr << endl;\n int now = num;\n children[now].clear();\n children[from].push_back(num);\n parent[num] = from;\n if(*itr == 'x') {\n itr++;\n return;\n }\n itr++;\n f(now, itr);\n itr++;\n f(now, itr);\n itr++;\n return;\n}\n\nvoid print(int from) {\n if(children[from].empty()) {\n cout << \"x\";\n return;\n }\n cout << \"(\";\n print(children[from][0]);\n cout << \" \";\n print(children[from][1]);\n cout << \")\";\n}\n\nint main() {\n //cout.precision(10);\n while(true) {\n string S;\n getline(cin, S);\n if(S == \"0\") break;\n num = 0;\n auto itr = S.begin();\n f(0, itr);\n dfs(1);\n dfs2(1, true);\n print(1);\n cout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3332, "score_of_the_acc": -0.0414, "final_rank": 8 }, { "submission_id": "aoj_1152_3191212", "code_snippet": "#include <bits/stdc++.h>\n#define MOD 1000000007LL\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nvector<int> ch[301];\nmap<string,int> mp;\nvector<int> G[301];\nint siz=0;\nint type[301];\nint dp[301][301];\nset<int> se[301];\nint cnt[301],all[301];\nbool flag[301][301];\n\n\ntypedef string::const_iterator State;\nint expression(State &begin);\n\nstring tostring(int v){\n\tif(v==0)return \"0\";\n\tstring s;\n\twhile(v>0){\n\t\ts+=((v%10)+'0');\n\t\tv/=10;\n\t}\n\treverse(s.begin(),s.end());\n\treturn s;\n}\n\nint expression(State &begin){\n\tint cur=siz;\n\tif(*begin=='('){\n\t\tbegin++;\n\t\tsiz++;\n\t\tint ret=expression(begin);\n\t\tbegin++;\n\t\tsiz++;\n\t\tint ret2=expression(begin);\n\t\tG[cur].push_back(ret);\n\t\tG[cur].push_back(ret2);\n\t\tbegin++;\n\t\treturn cur;\n\t}else if(*begin=='x'){\n\t\tbegin++;\n\t\treturn siz;\n\t}else{\n\t\tassert(false);\n\t}\n}\n\nint check(int v1,int v2){\n\tif(v1==v2)return 0;\n\tif(v1==0)return -1;\n\tif(v2==0)return 1;\n\tif(cnt[v1]*all[v2]!=cnt[v2]*all[v1]){\n\t\tif(cnt[v1]*all[v2]<cnt[v2]*all[v1])return -1;\n\t\treturn 1;\n\t}\n\t\n\t//printf(\"ch %d %d %d %d\\n\",v1,v2,ch[v1][0],ch[v2][0]);\n\tif(flag[v1][v2])return dp[v1][v2];\n\tflag[v1][v2]=true;\n\tint res=check(ch[v1][0],ch[v2][0]);\n\t//printf(\"ch %d %d %d %d %d\\n\",v1,v2,ch[v1][0],ch[v2][0],res);\n\tif(res==-1){\n\t\tdp[v1][v2]=-1;\n\t\treturn res;\n\t}else if(res==1){\n\t\tdp[v1][v2]=1;\n\t\treturn res;\n\t}\n\tres=check(ch[v1][1],ch[v2][1]);\n\t//printf(\"ch %d %d %d %d %d\\n\",v1,v2,ch[v1][1],ch[v2][1],res);\n\tdp[v1][v2]=res;\n\treturn res;\n}\n\nint dfs(int v){\n\tif(G[v].size()==0){\n\t\ttype[v]=mp[\"0\"];\n\t}else{\n\t\tint v1=dfs(G[v][0]);\n\t\tint v2=dfs(G[v][1]);\n\t\tif(v1>v2)swap(v1,v2);\n\t\tstring vs=\"(\"+tostring(v1)+\",\"+tostring(v2)+\")\";\n\t\tif(mp.find(vs)==mp.end()){\n\t\t\tint id=mp.size();\n\t\t\tmp[vs]=id;\n\t\t\tch[id].push_back(v1);\n\t\t\tch[id].push_back(v2);\n\t\t\tif(check(ch[id][0],ch[id][1])==1){\n\t\t\t\tswap(ch[id][0],ch[id][1]);\n\t\t\t}\n\t\t\tse[id].insert(id);\n\t\t\tfor(set<int>::iterator it=se[v1].begin();it!=se[v1].end();it++){\n\t\t\t\tse[id].insert(*it);\n\t\t\t}\n\t\t\tfor(set<int>::iterator it=se[v2].begin();it!=se[v2].end();it++){\n\t\t\t\tse[id].insert(*it);\n\t\t\t}\n\t\t\tall[id]=se[id].size()-1;\n\t\t\tset<int> tmp;\n\t\t\tfor(set<int>::iterator it=se[v1].begin();it!=se[v1].end();it++){\n\t\t\t\ttmp.insert(*it);\n\t\t\t}\n\t\t\tcnt[id]=0;\n\t\t\tfor(set<int>::iterator it=se[v2].begin();it!=se[v2].end();it++){\n\t\t\t\tif(tmp.find(*it)!=tmp.end()){\n\t\t\t\t\tcnt[id]++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\ttype[v]=mp[vs];\n\t}\n\treturn type[v];\n}\n\nvoid construct(int v){\n\tif(G[v].size()==2){\n\t\tconstruct(G[v][0]);\n\t\tconstruct(G[v][1]);\n\t\tint rec=check(type[G[v][0]],type[G[v][1]]);\n\t\tif(rec==1){\n\t\t\tswap(G[v][0],G[v][1]);\n\t\t}\n\t}\n}\n\nstring get(int v,int f){\n\tif(G[v].size()==0){\n\t\treturn \"x\";\n\t}\n\tif(f==-1){\n\t\treturn \"(\" + get(G[v][0],-1) + \" \" +get(G[v][1],1) +\")\";\n\t}else{\n\t\treturn \"(\" + get(G[v][1],-1) + \" \" +get(G[v][0],1) +\")\";\n\t}\n}\n\n\nint main(void){\n\twhile(1){\n\t\tstring str;\n\t\tgetline(cin,str);\n\t\tif(str==\"0\")break;\n\t\tfor(int i=0;i<300;i++){\n\t\t\tch[i].clear();\n\t\t\tG[i].clear();\n\t\t\tse[i].clear();\n\t\t}\n\t\tmemset(dp,0,sizeof(dp));\n\t\tmemset(flag,false,sizeof(flag));\n\t\tsiz=0;\n\t\tmp.clear();\n\t\tmp[\"0\"]=0;\n\t\tall[0]=1;\n\t\tse[0].insert(0);\n\t\tState st=str.begin();\n\t\texpression(st);\n\t\tdfs(0);\n\t\tconstruct(0);\n\t\tcout << get(0,-1) << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3636, "score_of_the_acc": -0.0929, "final_rank": 12 }, { "submission_id": "aoj_1152_3191175", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))\n#define all(x) (x).begin(),(x).end()\n#define pb push_back\n#define fi first\n#define se second\n#define dbg(x) cout<<#x\" = \"<<((x))<<endl\ntemplate<class T,class U> ostream& operator<<(ostream& o, const pair<T,U> &p){o<<\"(\"<<p.fi<<\",\"<<p.se<<\")\";return o;}\ntemplate<class T> ostream& operator<<(ostream& o, const vector<T> &v){o<<\"[\";for(T t:v){o<<t<<\",\";}o<<\"]\";return o;}\n\nconst int N = 200;\nvector<int> G[N];\n\nmap<vector<int>,int> h2id;\n\nint tree_hash(int v){\n vector<int> hs;\n for(int ch:G[v]){\n hs.pb(tree_hash(ch));\n }\n sort(all(hs));\n\n if(!h2id.count(hs)) h2id[hs] = h2id.size();\n return h2id[hs];\n}\n\nconst int MX = 128;\n\nstring s;\nint n;\n\nint T;\nint l[MX],r[MX];\nint make_tree(int &idx){\n int ID = T;\n ++T;\n\n if(s[idx]=='('){\n ++idx;\n l[ID] = make_tree(idx);\n\n assert(s[idx]==' ');\n ++idx;\n\n r[ID] = make_tree(idx);\n assert(s[idx]==')');\n ++idx;\n }\n else{\n assert(s[idx]=='x');\n ++idx;\n l[ID] = -1;\n r[ID] = -1;\n }\n return ID;\n}\n\nint hs[MX];\nint ch_hs[MX][MX];\n\nvoid mergehs(int v){\n for(int ch:G[v]){\n mergehs(ch);\n rep(i,MX) ch_hs[v][i] += ch_hs[ch][i];\n }\n ++ch_hs[v][hs[v]];\n}\n\nusing pi = pair<int,int>;\nconst pi INI(-1,1);\npi sim[MX];\n\nbool small(pi p, pi q){\n return p.fi*q.se < q.fi*p.se;\n}\n\npi calc_sim(int v){\n if(sim[v] != INI) return sim[v];\n\n pi ret;\n if(l[v] == -1) ret = {0,1};\n else{\n int p = 0, q = 0;\n rep(i,MX){\n int ct = 0;\n if(ch_hs[l[v]][i] > 0) ++ct;\n if(ch_hs[r[v]][i] > 0) ++ct;\n\n if(ct>0){\n ++q;\n if(ct==2) ++p;\n }\n }\n\n ret = {p,q};\n }\n return sim[v] = ret;\n}\n\nint memo[MX][MX];\nint strong(int u, int v){\n if(memo[u][v]!=-1) return memo[u][v];\n\n // cond.1\n pi sim_u = calc_sim(u), sim_v = calc_sim(v);\n if(small(sim_u,sim_v)) return memo[u][v] = 1;\n if(small(sim_v,sim_u)) return memo[u][v] = 0;\n\n // cond.2\n if(l[u]==-1 && l[v]==-1) return memo[u][v] = 0;\n\n // cond.3\n int fu = l[u], su = r[u];\n if(strong(su,fu)) swap(fu,su);\n\n int fv = l[v], sv = r[v];\n if(strong(sv,fv)) swap(fv,sv);\n\n if(strong(fu,fv)) return memo[u][v] = 1;\n if(strong(fv,fu)) return memo[u][v] = 0;\n\n // cond.4\n if(strong(su,sv)) return memo[u][v] = 1;\n if(strong(sv,su)) return memo[u][v] = 0;\n\n // cond.5\n return memo[u][v] = 0;\n}\n\nvoid SWAP(int v, int flg){\n if(l[v]==-1) return;\n assert(r[v]!=-1);\n\n int L = l[v], R = r[v];\n\n int ct[MX]={};\n rep(i,MX){\n if(ch_hs[l[v]][i] > 0) ++ct[i];\n if(ch_hs[r[v]][i] > 0) ++ct[i];\n }\n\n if(flg == 0){\n if(strong(R,L)) swap(l[v],r[v]);\n }\n else{\n if(strong(L,R)) swap(l[v],r[v]);\n }\n\n SWAP(l[v],0);\n SWAP(r[v],1);\n}\n\nstring tree2str(int v){\n if(l[v]==-1) return \"x\";\n\n string res = \"\";\n res += \"(\";\n res += tree2str(l[v]);\n res += \" \";\n res += tree2str(r[v]);\n res += \")\";\n\n return res;\n}\n\nint main(){\n while( getline(cin,s), (s!=\"0\") ){\n rep(i,N) G[i].clear();\n h2id.clear();\n rep(i,MX)rep(j,MX) ch_hs[i][j] = 0;\n rep(i,MX) sim[i] = INI;\n memset(memo,-1,sizeof(memo));\n\n n = s.size();\n\n T = 0;\n int ttt = 0;\n make_tree(ttt);\n\n rep(i,T){\n if(l[i]!=-1) G[i].pb(l[i]);\n if(r[i]!=-1) G[i].pb(r[i]);\n }\n\n rep(i,T) hs[i] = tree_hash(i);\n\n mergehs(0);\n\n SWAP(0,0);\n\n cout << tree2str(0) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3288, "score_of_the_acc": -0.0339, "final_rank": 5 }, { "submission_id": "aoj_1152_2998177", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconstexpr double eps = 1e-8;\n\nstruct exp_tree;\nusing tree_ptr = shared_ptr<exp_tree>;\n\nstruct exp_tree {\n tree_ptr lch, rch;\n double asym;\n bool leaf;\n exp_tree() : lch(nullptr), rch(nullptr), asym(0), leaf(true) {}\n string to_string(bool is_sort) const {\n assert(leaf || (lch && rch));\n if(leaf) return \"x\";\n auto s1 = lch->to_string(is_sort), s2 = rch->to_string(is_sort);\n if(is_sort && s1 > s2) swap(s1, s2);\n return \"(\" + s1 + \" \" + s2 + \")\";\n }\n double value() const {\n return asym;\n }\n bool operator<(exp_tree const& other) const { // lch.asym < rch.asym ?\n if(other.leaf) return false;\n if(leaf) return true;\n if(abs(value() - other.value()) < eps) {\n auto lmin = min(*lch, *rch);\n auto rmin = min(*other.lch, *other.rch);\n if(!(lmin < rmin) && !(rmin < lmin)) {\n auto lmax = max(*lch, *rch);\n auto rmax = max(*other.lch, *other.rch);\n return lmax < rmax;\n }\n return lmin < rmin;\n }\n return value() < other.value();\n }\n set<string> eval() {\n set<string> ss;\n if(leaf) {\n ss.insert(this->to_string(true));\n return ss;\n }\n auto ls = lch->eval(), rs = rch->eval();\n double same = 0;\n ss = move(rs);\n for(auto&& s : ls) {\n same += ss.count(s);\n ss.insert(s);\n }\n ss.insert(this->to_string(true));\n asym = same / (ss.size() - 1);\n return ss;\n }\n\n void swap_dfs(bool is_left) {\n if(leaf) return;\n if((*lch < *rch && !is_left) || (!(*lch < *rch) && is_left)) {\n swap(lch, rch);\n }\n lch->swap_dfs(true);\n rch->swap_dfs(false);\n }\n};\n\ntree_ptr expr(string const& s, int& p) {\n tree_ptr res = make_shared<exp_tree>();\n assert(p < (int)s.size());\n if(s[p] == 'x') {\n p += 1;\n return res;\n }\n res->leaf = false;\n res->lch = expr(s, ++p);\n res->rch = expr(s, ++p);\n p += 1;\n return res;\n}\n\ntree_ptr parse(string const& s) {\n int p = 0;\n return expr(s, p);\n}\n\nint main() {\n string s;\n while(getline(cin, s), s[0] != '0') {\n auto t = parse(s);\n t->eval();\n t->swap_dfs(true);\n cout << t->to_string(false) << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3088, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1152_2998175", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconstexpr double eps = 1e-8;\n\nstruct exp_tree;\nusing tree_ptr = shared_ptr<exp_tree>;\n\nstruct exp_tree {\n tree_ptr lch, rch;\n double asym;\n bool leaf;\n exp_tree() : lch(nullptr), rch(nullptr), asym(0), leaf(true) {}\n string to_string(bool is_sort) const {\n assert(leaf || (lch && rch));\n if(leaf) return \"x\";\n auto s1 = lch->to_string(is_sort), s2 = rch->to_string(is_sort);\n if(is_sort && s1 > s2) swap(s1, s2);\n return \"(\" + s1 + \" \" + s2 + \")\";\n }\n double value() const {\n return asym;\n }\n bool operator<(exp_tree const& other) const { // lch.asym < rch.asym ?\n if(other.leaf) return false;\n if(leaf) return true;\n if(abs(value() - other.value()) < eps) {\n auto lmin = min(*lch, *rch);\n auto rmin = min(*other.lch, *other.rch);\n if(!(lmin < rmin) && !(rmin < lmin)) {\n auto lmax = max(*lch, *rch);\n auto rmax = max(*other.lch, *other.rch);\n return lmax < rmax;\n }\n return lmin < rmin;\n }\n return value() < other.value();\n }\n set<string> eval() {\n set<string> ss;\n if(leaf) {\n ss.insert(this->to_string(true));\n return ss;\n }\n auto ls = lch->eval(), rs = rch->eval();\n double same = 0;\n ss = move(rs);\n for(auto&& s : ls) {\n same += ss.count(s);\n ss.insert(s);\n }\n ss.insert(this->to_string(true));\n asym = same / (ss.size() - 1);\n //cout << \"asym: \" << asym << ' ' << \" expr: \" << to_string(true) << endl;\n return ss;\n }\n\n void swap_dfs(bool is_left) {\n if(leaf) return;\n if((*lch < *rch && !is_left) || (!(*lch < *rch) && is_left)) {\n swap(lch, rch);\n }\n lch->swap_dfs(true);\n rch->swap_dfs(false);\n }\n};\n\nusing tree_ptr = shared_ptr<exp_tree>;\n\ntree_ptr expr(string const& s, int& p) {\n tree_ptr res = make_shared<exp_tree>();\n assert(p < (int)s.size());\n if(s[p] == 'x') {\n p += 1;\n return res;\n }\n p += 1;\n res->leaf = false;\n res->lch = expr(s, p);\n res->rch = expr(s, ++p);\n p += 1;\n return res;\n}\n\ntree_ptr parse(string const& s) {\n int p = 0;\n return expr(s, p);\n}\n\nint main() {\n string s;\n while(getline(cin, s), s[0] != '0') {\n auto t = parse(s);\n t->eval();\n t->swap_dfs(true);\n cout << t->to_string(false) << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3148, "score_of_the_acc": -0.0102, "final_rank": 2 }, { "submission_id": "aoj_1152_2984216", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nconst double eps = 1e-8;\n#define eq(a, b) (fabs((a)-(b)) < eps)\n#define lt(a, b) (((a)-(b)) < -eps)\n\nstruct node {\n string self;\n double sim;\n set<int> sub;\n int li, ri;\n node(){}\n node(string self, double sim, int li, int ri):self(self), sim(sim), li(li), ri(ri){}\n};\n\nstring s;\nint idx;\nmap<string, int> mp;\nvector<node> vec;\nint sz;\n\nint insert(string tree, int li, int ri) {\n if(!mp.count(tree)) {\n node new_node(tree, 0.0, li, ri);\n if(li != -1) {\n set<int> A = vec[li].sub;\n set<int> B = vec[ri].sub;\n if(A.size() < B.size()) swap(A, B);\n int cnt = 0;\n for(int b : B) {\n\tcnt += A.count(b);\n\tA.insert(b);\n }\n new_node.sub = A;\n new_node.sim = (double)cnt/A.size();\n }\n mp[tree] = sz++;\n new_node.sub.insert(mp[tree]);\n vec.push_back(new_node);\n }\n return mp[tree];\n}\n\nint cmp(int i, int j) {\n node x = vec[i];\n node y = vec[j];\n if(!eq(x.sim, y.sim)) {\n if(lt(x.sim, y.sim)) return 1;\n else return -1;\n }\n if(x.li == -1) return 0;\n int res = cmp(x.li, y.li);\n if(res == 0) res = cmp(x.ri, y.ri);\n return res;\n}\n\nint solve() {\n int ch = s[idx++];\n if(ch == 'x') return insert(\"x\", -1, -1);\n int li = solve(); idx++;\n int ri = solve(); idx++;\n //if(vec[li].sim > vec[ri].sim) swap(li, ri);\n if(cmp(li, ri) == -1) swap(li, ri);\n node lch = vec[li];\n node rch = vec[ri];\n string self = \"(\" + lch.self + \" \" + rch.self + \")\";\n return insert(self, li, ri);\n}\n\n\nstring output(int i, bool izryt) {\n //cout << i << endl;\n if(vec[i].self == \"x\") return \"x\";\n node v = vec[i];\n //if((cmp(v.li, v.ri)==-1)^izryt) swap(v.li, v.ri);\n if(izryt) swap(v.li, v.ri);\n return \"(\" + output(v.li, false) + \" \" + output(v.ri, true) + \")\";\n}\n\nint main() {\n cout<<fixed<<setprecision(12);\n while(getline(cin, s), s != \"0\") {\n mp.clear();\n vec.clear();\n sz = 0;\n idx = 0;\n int ans = solve();\n cout << output(ans, false) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3320, "score_of_the_acc": -0.0393, "final_rank": 7 }, { "submission_id": "aoj_1152_2961964", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<set<string>,string>P;\nset<string>::iterator it1,it2;\nstruct no{\n int id;\n int syurui;\n double p;\n int same;\n string s;\n set<string>st;\n no *left,*right;\n no(int ID){left=right=NULL;s=\"\";st.clear();id=ID;p=0.0;}\n};\nint C=0;\ntypedef no* node;\nnode make_tree(int l,int r,const string &str){\n int cnt=0;\n node x=new no(C++);\n if(l==r)return x;\n for(int i=l+1;i<r;i++){\n if(str[i]=='(')cnt++;\n if(str[i]==')')cnt--;\n if(cnt==0&&str[i]==' '){\n if(l+1<=i-1)x->left=make_tree(l+1,i-1,str);\n if(i+1<=r-1)x->right=make_tree(i+1,r-1,str);\n break;\n }\n }\n return x;\n}\nvoid print_tree(node x){\n if(x->left==NULL && x->right==NULL){\n cout<<'x';\n return;\n }\n cout<<'(';\n if(x->left!=NULL)print_tree(x->left);\n cout<<' ';\n if(x->right!=NULL)print_tree(x->right);\n cout<<')';\n}\nvoid delete_tree(node x){\n if(x->left!=NULL)delete_tree(x->left);\n if(x->right!=NULL)delete_tree(x->right);\n delete(x);\n}\nP calc_tree(node x){\n int cnt=0;\n vector<string>v;\n set<string>sl,sr,st;\n string s1,s2,new_s;\n if(x->left==NULL && x->right==NULL){\n sl.insert(\"()\");\n return P(sl,\"()\");\n }\n if(x->left!=NULL){\n P p=calc_tree(x->left);\n sl=p.first;\n s1=p.second;\n v.push_back(s1);\n }\n if(x->right!=NULL){\n P p=calc_tree(x->right);\n sr=p.first;\n s2=p.second;\n v.push_back(s2);\n }\n sort(v.begin(),v.end());\n for(it1=sl.begin();it1!=sl.end();it1++){\n st.insert((*it1));\n for(it2=sr.begin();it2!=sr.end();it2++){\n if((*it1)==(*it2))cnt++;\n }\n }\n for(it2=sr.begin();it2!=sr.end();it2++){\n st.insert((*it2));\n }\n for(int i=0;i<v.size();i++){\n new_s+=v[i];\n }\n x->syurui=st.size();\n x->same=cnt;\n x->p=(double)cnt/st.size();\n x->s=\"(\"+new_s+\")\";\n st.insert(x->s);\n x->st=st;\n return P(st,x->s);\n}\n//(((x ((x ((x x) x)) x)) (x x)) ((x x) x))\n//(((x ((x ((x x) x)) x)) (x x)) ((x x) x))\n\nint comp(node l,node r){\n double s1=l->p;\n double s2=r->p;\n if(abs(s1-s2)>1e-9) return s1<s2?1:-1;\n if(!l->left&&!r->left) return 0;\n node ll=l->left;\n node lr=l->right;\n node rl=r->left;\n node rr=r->right;\n if(comp(ll,lr)<0)swap(ll,lr);\n if(comp(rl,rr)<0)swap(rl,rr);\n int c=comp(ll,rl);\n if(!c)return comp(lr,rr);\n return c;\n}\n\nvoid swap_tree(int pre,node x){\n if(x->left==NULL)return;\n if((comp(x->left,x->right)<0)==!pre)swap(x->left,x->right);\n if(x->left!=NULL)swap_tree(0,x->left);\n if(x->right!=NULL)swap_tree(1,x->right);\n}\n\nstring s;\nsigned main(){\n while(getline(cin,s),s!=\"0\"){\n C=0;\n node root=make_tree(0,s.size()-1,s);\n calc_tree(root);\n swap_tree(0,root);\n print_tree(root);\n cout<<endl;\n delete_tree(root);\n s=\"\";\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3256, "score_of_the_acc": -0.0285, "final_rank": 4 }, { "submission_id": "aoj_1152_2890894", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\nsigned main(){ \n cin.tie(0);\n ios::sync_with_stdio(0);\n string s;\n while(getline(cin,s),s!=\"0\"){\n Int m=count(s.begin(),s.end(),'x')*2-1;\n if(m==1){\n cout<<s<<endl;\n continue;\n }\n \n Int cur=0;\n vector<Int> L(m,-1),R(m,-1);\n \n function<Int(string)> dfs=[&](string s){\n //cout<<s<<endl;\n Int v=cur++;\n if(s==\"x\"){\n\treturn v;\n }\n Int op=0;\n for(Int i=0;i<(Int)s.size();i++){\n\tif(s[i]=='(') op++;\n\tif(s[i]==')') op--;\n\tif(op==1&&s[i]==' '){\n\t string ls=s.substr(1,i-1);\n\t string rs=s.substr(i+1,s.size()-(i+2));\n\t L[v]=dfs(ls);\n\t R[v]=dfs(rs);\n\t return v;\n\t}\n }\n };\n dfs(s);\n\n vector<string> sh(m);\n vector<set<string> > dp(m);\n vector<Int> p(m),q(m);\n vector<Int> p1(m),q1(m);\n vector<Int> p2(m),q2(m);\n\n auto check=[&](Int a,Int b,Int c,Int d){\n return a*d>c*b;\n };\n \n function<void(Int)> dfs2=[&](Int v){\n if(L[v]<0){\n\tp[v]=0;q[v]=1;\n\tsh[v]=\"()\";\n\tdp[v].emplace(sh[v]);\n\treturn;\n }\n dfs2(L[v]);\n dfs2(R[v]);\n \n set<string> uni;\n dp[v]=dp[R[v]];\n for(auto ss:dp[L[v]]){\n\tdp[v].emplace(ss);\n\tif(dp[R[v]].count(ss))\n\t uni.emplace(ss);\n }\n p[v]=uni.size();\n q[v]=dp[v].size();\n \n sh[v]=\"(\"+(sh[L[v]]<sh[R[v]]?sh[L[v]]+sh[R[v]]:sh[R[v]]+sh[L[v]])+\")\"; \n dp[v].emplace(sh[v]);\n\n p1[v]=L[v];p2[v]=R[v];\n };\n dfs2(0);\n\n function<void(Int, Int)> dfs4=[&](Int v,Int k){\n if(L[v]<0) return;\n function<Int(Int,Int)> ccc=[&](Int a,Int b)->Int{\n\tif(check(p[a],q[a],p[b],q[b])){\n\t return 1;\n\t}\n\t\n\tif(check(p[b],q[b],p[a],q[a])){\n\t return 0;\n\t}\n\t\n\tif(!p[a]&&!p[b]){\n\t return 0;\n\t}\n\n\tif(ccc(p1[a],p2[a])){\n\t swap(p1[a],p2[a]);\n\t}\n\n\tif(ccc(p1[b],p2[b])){\n\t swap(p1[b],p2[b]);\n\t}\n\t\n\tif(ccc(p1[a],p1[b])){\n\t return 1;\n\t}\n\t\n\tif(ccc(p1[b],p1[a])){\n\t return 0;\n\t}\n\t\n\tif(ccc(p2[a],p2[b])){\n\t return 1;\n\t}\n\t\n\treturn 0;\n };\n if(k^ccc(L[v],R[v])) swap(L[v],R[v]);\n dfs4(L[v],0);\n dfs4(R[v],1);\n };\n dfs4(0,0);\n\n stringstream ss;\n function<void(Int)> dfs3=[&](Int v){\n if(L[v]<0){\n\tss<<\"x\";\n\treturn;\n }\n ss<<\"(\";\n dfs3(L[v]);\n ss<<\" \";\n dfs3(R[v]);\n ss<<\")\";\n };\n dfs3(0);\n cout<<ss.str()<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3340, "score_of_the_acc": -0.0427, "final_rank": 9 }, { "submission_id": "aoj_1152_2890827", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\nsigned main(){ \n cin.tie(0);\n ios::sync_with_stdio(0);\n string s;\n while(getline(cin,s),s!=\"0\"){\n Int m=count(s.begin(),s.end(),'x')*2-1;\n if(m==1){\n cout<<s<<endl;\n continue;\n }\n \n Int cur=0;\n vector<Int> L(m,-1),R(m,-1);\n \n function<Int(string)> dfs=[&](string s){\n //cout<<s<<endl;\n Int v=cur++;\n if(s==\"x\"){\n\treturn v;\n }\n Int op=0;\n for(Int i=0;i<(Int)s.size();i++){\n\tif(s[i]=='(') op++;\n\tif(s[i]==')') op--;\n\tif(op==1&&s[i]==' '){\n\t string ls=s.substr(1,i-1);\n\t string rs=s.substr(i+1,s.size()-(i+2));\n\t L[v]=dfs(ls);\n\t R[v]=dfs(rs);\n\t return v;\n\t}\n }\n };\n dfs(s);\n //for(Int i=0;i<m;i++) cout<<i<<\":\"<<L[i]<<\" \"<<R[i]<<endl; \n\n vector<string> sh(m);\n vector<set<string> > dp(m);\n vector<Int> p(m),q(m);\n vector<Int> p1(m),q1(m);\n vector<Int> p2(m),q2(m);\n\n auto check=[&](Int a,Int b,Int c,Int d){\n return a*d>c*b;\n };\n \n function<void(Int)> dfs2=[&](Int v){\n if(L[v]<0){\n\tp[v]=0;q[v]=1;\n\tsh[v]=\"()\";\n\tdp[v].emplace(sh[v]);\n\treturn;\n }\n dfs2(L[v]);\n dfs2(R[v]);\n \n set<string> uni;\n dp[v]=dp[R[v]];\n for(auto ss:dp[L[v]]){\n\tdp[v].emplace(ss);\n\tif(dp[R[v]].count(ss))\n\t uni.emplace(ss);\n }\n p[v]=uni.size();\n q[v]=dp[v].size();\n //cout<<v<<\":\"<<p[v]<<\":\"<<q[v]<<endl;\n //for(auto ss:dp[v]) cout<<v<<\":\"<<ss<<endl;\n \n sh[v]=\"(\"+(sh[L[v]]<sh[R[v]]?sh[L[v]]+sh[R[v]]:sh[R[v]]+sh[L[v]])+\")\"; \n dp[v].emplace(sh[v]);\n\n p1[v]=L[v];p2[v]=R[v];\n };\n dfs2(0);\n\n function<void(Int, Int)> dfs4=[&](Int v,Int k){\n if(L[v]<0) return;\n function<Int(int,Int)> ccc=[&](Int a,Int b)->Int{\n\tif(check(p[a],q[a],p[b],q[b])){\n\t return 1;\n\t}\n\t\n\tif(check(p[b],q[b],p[a],q[a])){\n\t return 0;\n\t}\n\t\n\tif(!p[a]&&!p[b]){\n\t return 0;\n\t}\n\n\tif(ccc(p1[a],p2[a])){\n\t swap(p1[a],p2[a]);\n\t}\n\n\tif(ccc(p1[b],p2[b])){\n\t swap(p1[b],p2[b]);\n\t}\n\t\n\tif(ccc(p1[a],p1[b])){\n\t return 1;\n\t}\n\t\n\tif(ccc(p1[b],p1[a])){\n\t return 0;\n\t}\n\t\n\tif(ccc(p2[a],p2[b])){\n\t return 1;\n\t}\n\t\n\treturn 0;\n };\n //cout<<v<<\" \"<<k<<\":\"<<ccc(L[v],R[v])<<endl;\n if(k^ccc(L[v],R[v])) swap(L[v],R[v]);\n dfs4(L[v],0);\n dfs4(R[v],1);\n };\n dfs4(0,0);\n\n stringstream ss;\n function<void(Int)> dfs3=[&](Int v){\n if(L[v]<0){\n\tss<<\"x\";\n\treturn;\n }\n ss<<\"(\";\n dfs3(L[v]);\n ss<<\" \";\n dfs3(R[v]);\n ss<<\")\";\n };\n dfs3(0);\n string ans=ss.str();\n if(0){\n reverse(ans.begin(),ans.end());\n for(auto &c:ans){\n\tif(c=='(') c=')';\n\telse if(c==')') c='(';\n }\n }\n cout<<ans<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3168, "score_of_the_acc": -0.0136, "final_rank": 3 }, { "submission_id": "aoj_1152_2572135", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nstruct Node{\n\tNode* l;\n\tNode* r;\n\tdouble R;\n\tstring s;\n\tset<string> se;\n\tNode() : l(nullptr), r(nullptr){}\n};\n\nint c;\nint N;\nstring s;\n\nmap<pair<Node*, Node*>, int> compm;\n// X????????????????§°??§????????? -1\n// ?????? 0\n// Y????????????????§°??§????????? 1\nint comp(Node* X, Node* Y){\n\tif(compm.count({ X, Y })) return compm[{X, Y}];\n\tif(X->R != Y->R){\n\t\tif(X->R < Y->R) return compm[{X, Y}] = -1;\n\t\treturn compm[{X, Y}] = 1;\n\t}\n\tif(X->s == \"()\" && Y->s == \"()\"){\n\t\treturn compm[{X, Y}] = 0;\n\t}\n\n\tNode *xmin, *xmax;\n\tNode *ymin, *ymax;\n\tif(comp(X->l, X->r) < 0){\n\t\txmax = X->l, xmin = X->r;\n\t}\n\telse{\n\t\txmin = X->l, xmax = X->r;\n\t}\n\tif(comp(Y->l, Y->r) < 0){\n\t\tymax = Y->l, ymin = Y->r;\n\t}\n\telse{\n\t\tymin = Y->l, ymax = Y->r;\n\t}\n\tint res = comp(xmax, ymax);\n\tif(res != 0){\n\t\tif(res < 0) return compm[{X, Y}] = -1;\n\t\treturn compm[{X, Y}] = 1;\n\t}\n\treturn compm[{X, Y}] = comp(xmin, ymin);\n}\n\nNode* f(){\n\tNode* n = new Node();\n\tif(s[c] == 'x'){\n\t\tc++;\n\t\tn->s = \"()\";\n\t\tn->se.insert(\"()\");\n\t\tn->R = 0;\n\t\treturn n;\n\t}\n\tassert(s[c] == '(');\n\tc++;\n\tn->l = f();\n\tassert(s[c] == ' ');\n\tc++;\n\tn->r = f();\n\tint cnt = 0;\n\tfor(auto v : n->l->se){\n\t\tn->se.insert(v);\n\t\tif(n->r->se.count(v)) cnt++;\n\t}\n\tfor(auto v : n->r->se){\n\t\tn->se.insert(v);\n\t}\n\tn->R = double(cnt) / n->se.size();\n\n\tstring ls = n->l->s, rs = n->r->s;\n\tif(ls > rs) swap(ls, rs);\n\tn->s = \"(\" + ls + rs + \")\";\n\tn->se.insert(n->s);\n\n\tassert(s[c] == ')');\n\tc++;\n\treturn n;\n}\n\nvoid g(Node* n, bool left){\n\tif(n->s == \"()\"){\n\t\tcout << \"x\";\n\t\treturn;\n\t}\n\tif(left && comp(n->l, n->r) > 0){\n\t\tswap(n->l, n->r);\n\t}\n\tif(!left && comp(n->l, n->r) < 0){\n\t\tswap(n->l, n->r);\n\t}\n\n\tcout << \"(\";\n\tg(n->l, true);\n\tcout << \" \";\n\tg(n->r, false);\n\tcout << \")\";\n}\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n#ifdef LOCAL\n\tstd::ifstream in(\"in\");\n\tstd::cin.rdbuf(in.rdbuf());\n#endif\n\n\twhile(getline(cin, s), s != \"0\"){\n\t\tcompm.clear();\n\t\tN = s.size();\n\t\tc = 0;\n\t\tNode* r = f();\n\t\t//cout << s << endl;\n\t\tg(r, 1);\n\t\tcout << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 8988, "score_of_the_acc": -1, "final_rank": 19 }, { "submission_id": "aoj_1152_2426949", "code_snippet": "#include <cassert>\n#include <functional>\n#include <iostream>\n#include <memory>\n#include <tuple>\n#include <unordered_map>\n#include <unordered_set>\nusing ll = long long;\nusing namespace std;\n\nstruct tree_t {\n shared_ptr<tree_t> l, r;\n};\n\nshared_ptr<tree_t> parse_tree(string::const_iterator & first, string::const_iterator last) {\n assert (first != last);\n if (*first == 'x') {\n ++ first;\n return shared_ptr<tree_t>();\n } else {\n assert (*first == '(');\n ++ first;\n auto l = parse_tree(first, last);\n assert (*first == ' ');\n ++ first;\n auto r = parse_tree(first, last);\n assert (*first == ')');\n ++ first;\n return make_shared<tree_t>((tree_t) { l, r });\n }\n}\nshared_ptr<tree_t> parse_tree(string const & s) {\n auto it = s.begin();\n auto tree = parse_tree(it, s.end());\n assert (it == s.end());\n return tree;\n}\n\nstruct rational {\n int num, den;\n};\nbool operator < (rational a, rational b) {\n return a.num *(ll) b.den < b.num *(ll) a.den;\n}\nbool operator > (rational a, rational b) {\n return a.num *(ll) b.den > b.num *(ll) a.den;\n}\n\nstring signature(shared_ptr<tree_t> const & tree) {\n if (not tree) {\n return \"x\";\n } else {\n string l = signature(tree->l);\n string r = signature(tree->r);\n if (l > r) swap(l, r);\n return \"(\" + l + \" \" + r + \")\";\n }\n}\n\nvoid normalize(shared_ptr<tree_t> root) {\n unordered_map<string, unordered_set<string> > subtrees; {\n function<void (shared_ptr<tree_t> const &)> go = [&](shared_ptr<tree_t> const & tree) {\n subtrees[signature(tree)].insert(signature(tree));\n if (tree) {\n go(tree->l);\n go(tree->r);\n for (auto it : subtrees[signature(tree->l)]) {\n subtrees[signature(tree)].insert(it);\n }\n for (auto it : subtrees[signature(tree->r)]) {\n subtrees[signature(tree)].insert(it);\n }\n }\n };\n go(root);\n }\n unordered_map<string, rational> sim; {\n function<void (shared_ptr<tree_t> const &)> go = [&](shared_ptr<tree_t> const & tree) {\n if (not tree) {\n sim[signature(tree)] = (rational) { 0, 1 };\n } else {\n auto l = subtrees[signature(tree->l)];\n auto r = subtrees[signature(tree->r)];\n int num = 0;\n for (auto it : l) {\n num += r.count(it);\n }\n int den = l.size() + r.size() - num;\n sim[signature(tree)] = (rational) { num, den };\n go(tree->l);\n go(tree->r);\n }\n };\n go(root);\n }\n const int LT = -1;\n const int EQ = 0;\n const int GT = +1;\n function<int (shared_ptr<tree_t> const &, shared_ptr<tree_t> const &)> cmp = [&](shared_ptr<tree_t> const & a, shared_ptr<tree_t> const & b) {\n rational sim_a = sim[signature(a)];\n rational sim_b = sim[signature(b)];\n // 1.\n if (sim_a < sim_b) return GT;\n if (sim_a > sim_b) return LT;\n // 2.\n if (not a and not b) return EQ;\n // 3.\n auto al = a->l, ar = a->r;\n auto bl = b->l, br = b->r;\n if (cmp(al, ar) == GT) swap(al, ar);\n if (cmp(bl, br) == GT) swap(bl, br);\n int cmp_ar_br = cmp(ar, br);\n if (cmp_ar_br != EQ) return cmp_ar_br;\n // 4.\n int cmp_al_bl = cmp(al, bl);\n if (cmp_al_bl != EQ) return cmp_al_bl;\n // 5.\n return EQ;\n };\n function<void (shared_ptr<tree_t>, bool)> go = [&](shared_ptr<tree_t> tree, bool is_right) {\n if (not tree) {\n // nop\n } else {\n if (cmp(tree->l, tree->r) == (is_right ? GT : LT)) {\n swap(tree->l, tree->r);\n }\n go(tree->l, false);\n go(tree->r, true);\n }\n };\n go(root, false);\n}\n\nstring format_tree(shared_ptr<tree_t> const & tree) {\n if (not tree) {\n return \"x\";\n } else {\n return \"(\" + format_tree(tree->l) + \" \" + format_tree(tree->r) + \")\";\n }\n}\n\nint main() {\n while (true) {\n string s; getline(cin, s);\n if (s == \"0\") break;\n auto tree = parse_tree(s);\n normalize(tree);\n cout << format_tree(tree) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 3476, "score_of_the_acc": -1.0658, "final_rank": 20 } ]
aoj_1154_cpp
Problem B: Monday-Saturday Prime Factors Chief Judge's log, stardate 48642.5. We have decided to make a problem from elementary number theory. The problem looks like finding all prime factors of a positive integer, but it is not. A positive integer whose remainder divided by 7 is either 1 or 6 is called a 7 N +{1,6} number. But as it is hard to pronounce, we shall call it a Monday-Saturday number . For Monday-Saturday numbers a and b , we say a is a Monday-Saturday divisor of b if there exists a Monday-Saturday number x such that a x = b . It is easy to show that for any Monday-Saturday numbers a and b , it holds that a is a Monday-Saturday divisor of b if and only if a is a divisor of b in the usual sense. We call a Monday-Saturday number a Monday-Saturday prime if it is greater than 1 and has no Monday-Saturday divisors other than itself and 1. A Monday-Saturday number which is a prime in the usual sense is a Monday-Saturday prime but the converse does not always hold. For example, 27 is a Monday-Saturday prime although it is not a prime in the usual sense. We call a Monday-Saturday prime which is a Monday-Saturday divisor of a Monday-Saturday number a a Monday-Saturday prime factor of a . For example, 27 is one of the Monday-Saturday prime factors of 216, since 27 is a Monday-Saturday prime and 216 = 27 × 8 holds. Any Monday-Saturday number greater than 1 can be expressed as a product of one or more Monday-Saturday primes. The expression is not always unique even if differences in order are ignored. For example, 216 = 6 × 6 × 6 = 8 × 27 holds. Our contestants should write a program that outputs all Monday-Saturday prime factors of each input Monday-Saturday number. Input The input is a sequence of lines each of which contains a single Monday-Saturday number. Each Monday-Saturday number is greater than 1 and less than 300000 (three hundred thousand). The end of the input is indicated by a line containing a single digit 1. Output For each input Monday-Saturday number, it should be printed, followed by a colon `:' and the list of its Monday-Saturday prime factors on a single line. Monday-Saturday prime factors should be listed in ascending order and each should be preceded by a space. All the Monday-Saturday prime factors should be printed only once even if they divide the input Monday-Saturday number more than once. Sample Input 205920 262144 262200 279936 299998 1 Output for the Sample Input 205920: 6 8 13 15 20 22 55 99 262144: 8 262200: 6 8 15 20 50 57 69 76 92 190 230 475 575 874 2185 279936: 6 8 27 299998: 299998
[ { "submission_id": "aoj_1154_10946380", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint next(int i) {\n return i%7 == 1 ? i+5 : i+2;\n}\n\nbool isprime(int x) {\n for(int i=6; i<x; i=next(i)) {\n if(x%i == 0) return false;\n }\n return true;\n}\n\nint main() {\n int n;\n while(scanf(\"%d\",&n), n!=1){\n printf(\"%d:\", n);\n for(int i=6; i<=n; i=next(i)){\n if(n%i == 0 && isprime(i)) {\n printf(\" %d\", i);\n }\n }\n printf(\"\\n\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 3476, "score_of_the_acc": -0.1424, "final_rank": 8 }, { "submission_id": "aoj_1154_10687748", "code_snippet": "#ifndef ONLINE_JUDGE\n#define _GLIBCXX_DEBUG\n#endif\n\n#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n//https://boostjp.github.io/tips/multiprec-int.html\n\n#define YES cout<<\"Yes\"<<endl\n#define NO cout<<\"No\"<<endl\n#define YN {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}// if(a==b)YN;\n#define NO2 cout<<-1<<endl\n\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n#define rrep(i, n) for (int i=int(n)-1; i>=0; --i)\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n\nint main() {\n int MX = 300010;\n vector<bool> p(MX, true);\n vector<int> primes;\n for (int i=1; i<MX; i++) {\n \n //(6,13,20, ...)\n int tmp = 7*i-1;\n if (tmp >= MX) break;\n if (p[tmp]) {\n primes.emplace_back(tmp);\n for (int k=2; k*tmp<MX; k++) {\n p[k*tmp] = false;\n }\n }\n\n //(8,15,22, ...)\n tmp = 7*i+1;\n if (tmp >= MX) break;\n if (p[tmp]) {\n primes.emplace_back(tmp);\n for (int k=2; k*tmp<MX; k++) {\n p[k*tmp] = false;\n }\n }\n }\n\n while(true) {\n int N;\n cin >> N;\n if (N == 1) return 0;\n cout << N << ':';\n\n bool flag = false;\n for (int pr:primes) {\n if (N%pr == 0) {\n flag = true;\n cout << ' ' << pr;\n }\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 490, "memory_kb": 3712, "score_of_the_acc": -0.3583, "final_rank": 16 }, { "submission_id": "aoj_1154_10615066", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing a2 = array<ll, 2>;\nusing a3 = array<ll, 3>;\n\ntemplate <typename A> void chmin(A &l, const A &r) {\n if(r < l)\n l = r;\n}\ntemplate <typename A> void chmax(A &l, const A &r) {\n if(l < r)\n l = r;\n}\n\nll mod = 998244353;\n\nvector<ll> prime;\nvoid init() {\n for(int i = 7; i < 400000; i+=7) {\n ll a;\n bool ok;\n\n a = i - 1;\n ok = true;\n for(auto &x : prime) {\n if(x*x>a)\n break;\n if(a % x == 0) {\n ok = false;\n break;\n }\n }\n if(ok) {\n prime.push_back(a);\n }\n\n a = i + 1;\n ok = true;\n for(auto &x : prime) {\n if(x*x>a)\n break;\n if(a % x == 0) {\n ok = false;\n break;\n }\n }\n if(ok) {\n prime.push_back(a);\n }\n }\n}\n\nll n;\nvoid input() { cin >> n; }\nvoid solve() {\n cout << n << \":\";\n for(auto &x : prime) {\n if(n % x == 0)\n cout << ' ' << x;\n }\n cout << endl;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n\n init();\n while(1) {\n input();\n if(n == 1)\n break;\n solve();\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 3608, "score_of_the_acc": -0.2545, "final_rank": 13 }, { "submission_id": "aoj_1154_10600738", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nvoid solve(int n) {\n vector<bool> is_prime(n + 1, true);\n is_prime[0] = false;\n is_prime[1] = false;\n for (int i = 2; i <= n; i++) {\n if (i % 7 == 1 || i % 7 == 6) {\n for (int j = 2 * i; j <= n; j += i) {\n is_prime[j] = false;\n }\n } else {\n is_prime[i] = false;\n }\n }\n\n vector<int> vec;\n for (int i = 0; i <= n; i++) {\n if (is_prime[i]) {\n vec.push_back(i);\n }\n }\n\n vector<int> ans;\n int N = n;\n for (auto x : vec) {\n if (N % x == 0) {\n ans.push_back(x);\n }\n }\n\n cout << n << \":\";\n for (int an : ans) {\n cout << \" \" << an;\n }\n cout << endl;\n}\n\nint main() {\n while (true) {\n int n;\n cin >> n;\n if (n == 1) {\n break;\n }\n\n solve(n);\n }\n}", "accuracy": 1, "time_ms": 1000, "memory_kb": 3864, "score_of_the_acc": -0.7266, "final_rank": 17 }, { "submission_id": "aoj_1154_10599724", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nvoid solve(int n) {\n vector<bool> is_prime(n + 1, true);\n is_prime[0] = false;\n is_prime[1] = false;\n for (int i = 2; i <= n; i++) {\n if (i % 7 == 1 || i % 7 == 6) {\n for (int j = 2 * i; j <= n; j += i) {\n is_prime[j] = false;\n }\n } else {\n is_prime[i] = false;\n }\n }\n\n vector<int> vec;\n for (int i = 0; i < n + 1; i++) {\n if (is_prime[i]) {\n vec.push_back(i);\n }\n }\n ranges::sort(vec);\n\n vector<int> ans;\n int N = n;\n for (auto x : vec) {\n if (x == 1) {\n continue;\n }\n if (N % x == 0) {\n ans.push_back(x);\n }\n }\n\n cout << n << \":\";\n for (int i = 0; i < ans.size(); i++) {\n cout << \" \" << ans[i];\n }\n cout << endl;\n}\n\nint main() {\n while (true) {\n int n;\n cin >> n;\n if (n == 1) {\n break;\n }\n\n solve(n);\n }\n}", "accuracy": 1, "time_ms": 1120, "memory_kb": 3860, "score_of_the_acc": -0.8115, "final_rank": 18 }, { "submission_id": "aoj_1154_10586550", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing P = pair<int, int>;\nusing PP = pair<int, P>;\nusing PLL = pair<ll, ll>;\nusing PPLL = pair<ll, PLL>;\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define rrep(i, n) for(ll i = n - 1; i >= 0; --i)\n#define loop(i, a, b) for(ll i = a; i <= b; ++i)\n#define all(v) v.begin(), v.end()\n#define nC2(n) n * (n - 1) / 2\nconstexpr ll INF = 9009009009009009009LL;\nconstexpr int INF32 = 2002002002;\nconstexpr ll MOD = 998244353;\nconstexpr ll MOD107 = 1000000007;\n\n// Linear Algebra ////////////////////////////////////////////////\nconst double Rad2Deg = 180.0 / M_PI;\nconst double Deg2Rad = M_PI / 180.0;\n//////////////////////////////////////////////////////////////////\n\nint dx[8] = {0, 1, 0, -1, 1, 1, -1, -1};\nint dy[8] = {1, 0, -1, 0, 1, -1, 1, -1};\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) {\n\tif (a < b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\ntemplate <class T>\ninline bool chmin(T &a, const T &b) {\n\tif (a > b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\n\ntemplate <typename Container,\n typename = std::enable_if_t<\n !std::is_same_v<Container, std::string> &&\n std::is_convertible_v<decltype(std::declval<Container>().begin()),\n typename Container::iterator>>>\nostream &operator<<(ostream &os, const Container &container) {\n auto it = container.begin();\n auto end = container.end();\n\n if (it != end) {\n os << *it;\n ++it;\n }\n\tfor (; it != end; ++it) {\n\t\tos << \" \" << *it;\n\t}\n return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v) {\n for (size_t i = 0; i < v.size(); ++i) {\n os << v[i];\n if (i != v.size() - 1) os << \" \";\n }\n return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<vector<T>>& vv) {\n\tfor (size_t i = 0; i < vv.size(); ++i) {\n\t\tos << vv[i];\n\t\tif (i != vv.size() - 1) os << \"\\n\";\n }\n return os;\n}\ntemplate <typename T>\nistream& operator>>(istream& is, vector<T>& v) {\n\tassert(v.size() > 0);\n\tfor (size_t i = 0; i < v.size(); ++i) is >> v[i];\n\treturn is;\n}\ntemplate <typename T>\nistream& operator>>(istream& is, vector<vector<T>>& vv) {\n\tassert(vv.size() > 0);\n\tfor (size_t i = 0; i < vv.size(); ++i) is >> vv[i];\n\treturn is;\n}\n\nstruct phash {\n\ttemplate<class T1, class T2>\n inline size_t operator()(const pair<T1, T2> & p) const {\n auto h1 = hash<T1>()(p.first);\n auto h2 = hash<T2>()(p.second);\n\n\t\tsize_t seed = h1 + h2; \n\t\th1 = ((h1 >> 16) ^ h1) * 0x45d9f3b;\n h1 = ((h1 >> 16) ^ h1) * 0x45d9f3b;\n h1 = (h1 >> 16) ^ h1;\n seed ^= h1 + 0x9e3779b9 + (seed << 6) + (seed >> 2);\n\t\th2 = ((h2 >> 16) ^ h2) * 0x45d9f3b;\n h2 = ((h2 >> 16) ^ h2) * 0x45d9f3b;\n h2 = (h2 >> 16) ^ h2;\n seed ^= h2 + 0x9e3779b9 + (seed << 6) + (seed >> 2);\n return seed;\n }\n};\n\n\n\n/**\n * @brief エラトステネスの篩 O(N log log N)\n * @param n 素数を求める範囲\n * @return vector<bool> xが素数かどうか\n */\nvector<bool> sieve(const ll n) {\n\tvector<bool> is_prime(n + 1, true);\n\tis_prime[0] = is_prime[1] = false;\n\tfor (ll i = 2; i * i <= n; ++i) {\n\t\tif (!is_prime[i]) continue;\n\t\tfor (ll j = i * i; j <= n; j += i) is_prime[j] = false;\n\t}\n\treturn is_prime;\n}\n\n/**\n * @brief エラトステネスの篩 O(N log log N)\n * @param n 素数を求める範囲\n * @return vector<ll> 素数のリスト\n */\nvector<ll> primes(const ll n) {\n\tvector<bool> is_prime(n + 1, true);\n\tvector<ll> res;\n\tis_prime[0] = is_prime[1] = false;\n\tfor (ll i = 2; i <= n; ++i) {\n\t\tif (!is_prime[i]) continue;\n\t\tif (i % 7 != 1 && i % 7 != 6) continue;\n\t\tres.push_back(i);\n\t\tfor (ll j = i * i; j <= n; j += i) is_prime[j] = false;\n\t}\n\treturn res;\n}\n\n/**\n * @brief 素因数分解 O(√N)\n * @param n 素因数分解する数\n * @return vector<pair<ll, ll>> 素因数とその指数のリスト\n */\nvector<pair<ll, ll>> prime_factorization(ll n) {\n\tvector<pair<ll, ll>> res;\n\tfor (ll i = 2; i * i <= n; ++i) {\n\t\tif (n % i != 0) continue;\n\t\tif (i % 7 != 1 && i % 7 != 6) continue;\n\t\tll ex = 0;\n\t\twhile (n % i == 0) {\n\t\t\t++ex;\n\t\t\tn /= i;\n\t\t}\n\t\tres.push_back({i, ex});\n\t}\n\tif (n != 1) res.push_back({n, 1});\n\treturn res;\n}\n\nvll prime;\nint solve() {\n\tll n; cin >> n;\n\tif (n == 1) return 1;\n\n\tvll res;\n\trep(i, prime.size()) {\n\t\tif (n % prime[i] == 0) res.push_back(prime[i]);\n\t}\n\n\tcout << n << \":\";\n\tfor (auto v : res) {\n\t\tcout << \" \" << v;\n\t}\n\tcout << \"\\n\";\n\n\treturn 0;\n}\n\nint main() {\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\n\tprime = primes(3 * 1e5);\n\twhile (!solve()) { }\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3968, "score_of_the_acc": -0.0857, "final_rank": 7 }, { "submission_id": "aoj_1154_9458480", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint main() {\n int MAXS = 300001;\n vector<bool> B(MAXS,true);\n vector<int> Prime;\n rep(i,2,MAXS) {\n if (i % 7 != 1 && i % 7 != 6) continue;\n if (B[i]) {\n Prime.push_back(i);\n rep(j,2,MAXS) {\n if ((ll)i * (ll)j >= (ll)MAXS) break;\n if (j % 7 != 1 && j % 7 != 6) continue;\n B[i*j]=false;\n }\n }\n }\nwhile(1) {\n int _;\n cin >> _;\n int N = _;\n if (N == 1) return 0;\n vector<int> ANS;\n for (int P : Prime) {\n if (P > N) break;\n if (N % P == 0) {\n ANS.push_back(P);\n }\n }\n cout << _ << ':';\n for (int X : ANS) cout << ' ' << X;\n cout << endl;\n}\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3652, "score_of_the_acc": -0.0365, "final_rank": 1 }, { "submission_id": "aoj_1154_9380735", "code_snippet": "#include <iostream>\n#include<string.h>\n#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <stack>\n#include<math.h>\n\n\nusing namespace std;\n\n\n\n\n\nint main()\n{\n\tint check[300010];\n\tint n;\n\tint i, j;\n\n\n\tfor (i = 1; i < 300010; i++) {\n\t\tcheck[i] = 0;\n\t}\n\tfor (i = 1; i * 7 + 6 <= 300010; i++) {\n\t\tif (check[7 * i + 1] == 0) {\n\t\t\tcheck[7 * i + 1] = 1;\n\t\t\tfor (j = 2 * (7 * i + 1); j < 300010; j += 7 * i + 1) {\n\t\t\t\tcheck[j] = 2;\n\t\t\t}\n\t\t}\n\t\tif (check[7 * i - 1] == 0) {\n\t\t\tcheck[7 * i - 1] = 1;\n\t\t\t\tfor (j = 2 * (7 * i - 1); j < 300010; j+= 7 * i - 1) {\n\t\t\t\t\tcheck[j] = 2;\n\t\t\t}\n\t\t}\n\n\t}\n\n\t\twhile (1) {\n\t\t\tcin >> n;\n\t\t\tif (n == 1) {\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tcout << n << \":\";\n\t\t\tfor (i = 1; 7 *i < 300010; i++) {\n\t\t\t\tif (check[7 * i - 1] == 1 && n % (7 * i - 1 ) == 0) {\n\n\t\t\t\t\tcout << ' ' << 7 * i - 1;\n\n\t\t\t\t}\n\t\t\t\tif (check[7 * i + 1] == 1 && n % (7 * i + 1) == 0) {\n\n\t\t\t\t\tcout << ' ' << 7 * i + 1;\n\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << endl;\n\n\t\t}\n\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 4256, "score_of_the_acc": -0.2542, "final_rank": 12 }, { "submission_id": "aoj_1154_9380329", "code_snippet": "#include <iostream>\n#include<string.h>\n#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <stack>\n#include<math.h>\n\n\nusing namespace std;\n\nvoid setting(int*, int);\nvoid output(int*, int,int);\n\n\n\nint main(){\n\tint check[300010];\n\tint n;\n\tint i;\n\n\n\tfor (i = 1; i < 300010; i++) {\n\t\tcheck[i] = 0;\n\t}\n\tfor (i = 1; i * 7 + 6 <= 300010; i++) {\n\t\tsetting(check, 7 * i + 1);\n\t\tsetting(check, 7 * i - 1);\n\n\t}\n\n\twhile (1) {\n\t\tcin >> n;\n\t\tif (n == 1) {\n\t\t\treturn 0;\n\t\t}\n\t\tcout << n << \":\";\n\t\tfor (i = 1; 7 * i < 300010; i++) {\n\t\t\toutput(check, 7 * i - 1, n);\n\t\t\toutput(check, 7 * i + 1, n);\n\t\t}\n\t\tcout << endl;\n\n\t}\n\n}\n\nvoid setting(int* x, int y) {\n\t\tif (x[y] == 0) {\n\t\t\tx[y] = 1;\n\t\t\tfor (int j = 2 * (y); j < 300010; j += y) {\n\t\t\t\tx[j] = 2;\n\t\t\t}\n\t\t}\n\t}\n\nvoid output(int* x, int y,int n) {\n\tif (x[y] == 1 && n % y == 0) {\n\n\t\tcout << ' ' <<y;\n\n\t}\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 4212, "score_of_the_acc": -0.2594, "final_rank": 14 }, { "submission_id": "aoj_1154_9370860", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nconst int INF = (int)1e9 + 1001010;\nconst ll llINF = (long long)4e18 + 22000020;\nconst string endn = \"\\n\";\ntemplate <class T> inline auto vector2(size_t i, size_t j, const T &init = T()) {return vector(i, vector<T>(j, init));}\nconst string ELEM_SEPARATION = \" \", VEC_SEPARATION = endn;\ntemplate<class T> istream& operator >>(istream &i, vector<T> &A) {for(auto &I : A) {i >> I;} return i;}\ntemplate<class T> ostream& operator <<(ostream &o, const vector<T> &A) {int i=A.size(); for(const auto &I : A){o << I << (--i ? ELEM_SEPARATION : \"\");} return o;}\ntemplate<class T> ostream& operator <<(ostream &o, const vector<vector<T>> &A) {int i=A.size(); for(const auto &I : A){o << I << (--i ? VEC_SEPARATION : \"\");} return o;}\ntemplate<class T> vector<T>& operator ++(vector<T> &A, int n) {for(auto &I : A) {I++;} return A;}\ntemplate<class T> vector<T>& operator --(vector<T> &A, int n) {for(auto &I : A) {I--;} return A;}\ntemplate<class T, class U> bool chmax(T &a, const U &b) {return ((a < b) ? (a = b, true) : false);}\ntemplate<class T, class U> bool chmin(T &a, const U &b) {return ((a > b) ? (a = b, true) : false);}\nll floor(ll a, ll b){if (b < 0) a = -a, b = -b; if(a >= 0) return a / b; else return (a + 1) / b - 1;}\nll ceil(ll a, ll b){if (b < 0) a = -a, b = -b; if(a > 0) return (a - 1) / b + 1; else return a / b;}\nll bit(unsigned long long val, unsigned long long digit){return (val >> digit) & 1;}\n#ifdef DEBUG\n#include <debug_slephy.cpp>\n#else\n#define debug(...)\n#endif\n// ================================== ここまでテンプレ ==================================\n\nvector<ll> sprimes;\nconst ll MAX = 3e5 + 10;\n\nvoid solve(){\n ll n; cin >> n;\n if(n == 1) exit(0);\n vector<ll> ans;\n for(auto pr : sprimes){\n if(pr > n) break;\n if(n % pr == 0) ans.emplace_back(pr);\n }\n\n sort(ans.begin(), ans.end());\n cout << n << \": \" << ans << endl;\n}\n\nint main(int argc, char *argv[]){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n vector<ll> is_sprime(MAX, true);\n for(int i = 6; i < MAX; i++){\n if(!is_sprime[i]) continue;\n if(i % 7 == 1 || i % 7 == 6){\n sprimes.emplace_back(i);\n for(int j = 2*i; j < MAX; j+=i){\n is_sprime[j] = false;\n }\n }\n }\n debug(sprimes);\n debug(sprimes.size());\n while(true) solve();\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 5924, "score_of_the_acc": -0.1988, "final_rank": 10 }, { "submission_id": "aoj_1154_9362188", "code_snippet": "#include<bits/stdc++.h>\n//#include <atcoder/all>\nusing namespace std;\n//using namespace atcoder;\n\n#define all(v) v.begin(),v.end()\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll=vector<ll>;\nusing vvll = vector<vector<ll>>;\nusing P = pair<ll,ll>;\nusing vp=vector<pair<ll, ll>>;\n//using mint=modint1000000007;\n//using mint=modint998244353;\n\nconst ll INF=1ll<<60;\nll mod10=1e9+7;\nll mod99=998244353;\nconst double PI = acos(-1);\n\n#define rep(i,n) for (ll i=0;i<n;++i)\n#define per(i,n) for(ll i=n-1;i>=0;--i)\n#define rep2(i,a,n) for (ll i=a;i<n;++i)\n#define per2(i,a,n) for (ll i=a;i>=n;--i)\n\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n\nll N=500000;\nvll pri(N,1);\nvll num(N,0);\n\n\nbool solve(){\n ll N;cin>>N;\n if(N==1) return 0;\n vll ans;\n rep2(i,1,N+1){\n if(i*i>N) break;\n if(N%i) continue;\n if(pri[i]==1) ans.push_back(i);\n if(i*i!=N&&pri[N/i]==1) ans.push_back(N/i);\n }\n sort(all(ans));\n cout<<N<<\": \";\n rep(i,ans.size()) cout<<ans[i]<<\" \\n\"[i==ans.size()-1];\n\n return 1;\n}\n\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n rep2(i,1,N){\n num[i]=(i%7==1||i%7==6);\n }\n\n pri[0]=pri[1]=0;\n rep2(i,2,N){\n if(num[i]==0) pri[i]=0;\n rep2(j,2,i+1){\n if(j*j>i) break;\n if(i%j) continue;\n \n if(pri[j]==1||pri[i/j]==1) pri[i]=0;\n }\n }\n\n \n while(solve());\n}", "accuracy": 1, "time_ms": 1420, "memory_kb": 10628, "score_of_the_acc": -1.3174, "final_rank": 20 }, { "submission_id": "aoj_1154_9342083", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,k,n) for (int i = k; i < (n); ++i)\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\ntypedef pair<ll, ll> P;\nconst long long INF = 1e17;\n\nint main(){\n vector<int> monsat_num;\n for(int i=2;i<=300001;i++){\n if(i%7==1||i%7==6){\n monsat_num.push_back(i);\n }\n }\n vector<int> monsat_prime;\n for(int i=0;i<monsat_num.size();i++){\n int j = 0;\n bool prime = true;\n while(monsat_num[j]*monsat_num[j]<=monsat_num[i]){\n if(monsat_num[i]%monsat_num[j]==0){\n prime = false;\n break;\n }\n j++;\n }\n\n if(prime){\n monsat_prime.push_back(monsat_num[i]);\n }\n\n }\n\n while(true){\n int n;\n cin >> n;\n if(n==1){\n break;\n }\n cout << n << ':';\n for(int i=0;i<monsat_prime.size();i++){\n if(n%monsat_prime[i]==0){\n cout << ' ' << monsat_prime[i];\n }\n }\n cout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3644, "score_of_the_acc": -0.0645, "final_rank": 6 }, { "submission_id": "aoj_1154_9334309", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<long long>;\nusing vs = vector<string>;\nusing vc = vector<char>;\nusing vb = vector<bool>;\nusing vpii = vector<pair<int, int>>;\nusing vpll = vector<pair<long long, long long>>;\nusing vvi = vector<vector<int>>;\nusing vvl = vector<vector<long long>>;\nusing vvc = vector<vector<char>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing pii = pair<int, int>;\nusing vvb = vector<vector<bool>>;\nusing Graph = vector<vector<ll>>;\nconst ll LINF = 1001002003004005006ll;\nconst int INF = 1001001001;\nconst int MOD = 998422353;\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep3(i, m, n) for (int i = (m); i < (int)(n); i++)\n#define rrep(i, m, n) for (int i = (m); i >= (int)(n); i--)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\nvi dx4 = {1, 0, -1, 0}, dy4 = {0, 1, 0, -1};\nvi dx8 = {1, 1, 1, 0, 0, -1, -1, -1}, dy8 = {1, 0, -1, 1, -1, 1, 0, -1};\n\nbool isprime(long long n)\n{\n if (n <= 1)\n return false;\n for (long long p = 6; p * p <= n; p += 7)\n {\n if (n % p == 0)\n return false;\n }\n for (long long p = 8; p * p <= n; p += 7)\n {\n if (n % p == 0)\n return false;\n }\n return true;\n}\n\nint main()\n{\n vi prime;\n for (int i = 6; i <= 300000; i += 7)\n {\n if (isprime(i))\n {\n prime.emplace_back(i);\n }\n }\n for (int i = 8; i <= 300000; i += 7)\n {\n if (isprime(i))\n {\n prime.emplace_back(i);\n }\n }\n sort(all(prime));\n while (1)\n {\n // 宣言・入力の受け取り\n int n;\n cin >> n;\n // 終了条件\n if (n == 1)\n {\n break;\n }\n // 宣言・入力の受け取り\n\n // solve\n cout << n << \":\";\n for (auto x : prime)\n {\n if (n % x == 0)\n {\n cout << ' ' << x;\n }\n if (x > n)\n {\n break;\n }\n }\n cout << '\\n';\n // 出力\n }\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3300, "score_of_the_acc": -0.0426, "final_rank": 2 }, { "submission_id": "aoj_1154_9293590", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define rep(i,n) for(int i = 0;i < n;i++)\n\n#define int ll\n#define double long double\n#define IMAX ((1 << 31) - 1)\n#define LMAX ((1LL << 63) - 1)\n\n#define MOD 998244353\n#define MAX 300005\n\n\nvector<int> nums;\nvector<set<int>> sp;\nvoid init()\n{\n for(int i = 1;i < MAX + 5;i += 7)\n {\n nums.push_back(i);\n nums.push_back(i + 5);\n }\n sp.resize(MAX + 10);\n\n// cout << nums[0] << endl;\n for(int i = 1;i < nums.size(); i++)\n {\n if(sp[nums[i]].size() != 0) continue;\n sp.at(nums[i]).insert(nums[i]);\n for(int j = 1; nums[i] * nums[j] < MAX; j++)\n {\n sp.at(nums[i] * nums[j]).insert(nums[i]);\n }\n }\n\n}\nvoid main_()\n{\n int n;\n cin >> n;\n if(n == 1) exit(0);\n set<int> st;\n\n cout << n << \":\";\n for(int i : sp.at(n))\n {\n cout << \" \" << i;\n }\n cout << endl;\n}\nsigned main()\n{\n init();\n\n while(1) main_();\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 26388, "score_of_the_acc": -1, "final_rank": 19 }, { "submission_id": "aoj_1154_9155554", "code_snippet": "#include <algorithm>\n#include <cmath>\n#include <cstdlib>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <string>\n#include <vector>\n\nusing namespace std;\n\nvector<int> GeneratePrimes(const int max) {\n\tvector<int> primes;\n\tvector<bool> isnt_prime(max, false);\n\n\tfor (int i = 7; i <= max; i += 7) {\n\t\tfor (int j = i - 1; j <= i + 1 && j <= max; j += 2) {\n\t\t\tif (isnt_prime[j]) continue;\n\t\t\tprimes.push_back(j);\n\t\t\tfor (int k = j; k <= max; k += j) {\n\t\t\t\tisnt_prime[k] = true;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn primes;\n}\n\nint main() {\n\tconst int max = 300000 - 1;\n\tvector<int> primes = GeneratePrimes(max);\n\n\twhile (true) {\n\t\tint n;\n\t\tcin >> n;\n\t\tif (n == 1) break;\n\n\t\tcout << n << \":\";\n\n\t\tfor (int p : primes) {\n\t\t\tif (n % p == 0) cout << \" \" << p;\n\t\t}\n\n\t\tcout << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3512, "score_of_the_acc": -0.0517, "final_rank": 3 }, { "submission_id": "aoj_1154_9147638", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\n#define rep(i, a, b) for(ll i = a; i < b; ++i)\n#define rrep(i, a, b) for(ll i = a; i >= b; --i)\nconstexpr ll inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\nint main(void) {\n constexpr int MAX = 3e5;\n vector<bool> prime(MAX + 1, true);\n prime[1] = false;\n for(int i = 0; i * 7 <= MAX; ++i) {\n {\n int x = i * 7 + 1;\n if(x <= MAX) {\n if(prime[x]) {\n for(int j = x * 2; j <= MAX; j += x) {\n prime[j] = false;\n }\n }\n }\n }\n {\n int x = i * 7 + 6;\n if(x <= MAX) {\n if(prime[x]) {\n for(int j = x * 2; j <= MAX; j += x) {\n prime[j] = false;\n }\n }\n }\n }\n }\n while(1) {\n int n;\n cin >> n;\n if(n == 1) break;\n cout << n << ':';\n for(int i = 0; i * 7 <= MAX; ++i) {\n {\n int x = i * 7 + 1;\n if(x <= MAX) {\n if(prime[x]) {\n if(n % x == 0) {\n cout << ' ' << x;\n }\n }\n }\n }\n {\n int x = i * 7 + 6;\n if(x <= MAX) {\n if(prime[x]) {\n if(n % x == 0) {\n cout << ' ' << x;\n }\n }\n }\n }\n }\n cout << '\\n';\n }\n}", "accuracy": 1, "time_ms": 390, "memory_kb": 3356, "score_of_the_acc": -0.2719, "final_rank": 15 }, { "submission_id": "aoj_1154_9033765", "code_snippet": "#include <bits/stdc++.h>\n\nconstexpr int N = 300005;\nbool is_prime[N];\n\nstd::vector<int> divisor(int n) {\n std::vector<int> res;\n for (int i = 1; i * i <= n; i++) {\n if (n % i == 0) {\n res.push_back(i);\n if (i * i != n) {\n res.push_back(n / i);\n }\n }\n }\n return res;\n}\n\nvoid init() {\n std::fill(is_prime, is_prime + N, true);\n is_prime[0] = is_prime[1] = false;\n std::vector<int> prime;\n for (int i = 2; i < N; i++) {\n if (i % 7 != 1 && i % 7 != 6) {\n is_prime[i] = false;\n }\n }\n\n for (int i = 2; i < N; i++) {\n if (!is_prime[i]) continue;\n for (auto div: divisor(i)) {\n if (div == 1 || div == i) continue;\n if (is_prime[div]) is_prime[i] = false;\n }\n }\n}\n\nint solve() {\n int n;\n std::cin >> n;\n if (n == 1) return 1;\n\n std::vector<int> ans;\n for (auto div: divisor(n)) {\n if (is_prime[div]) {\n ans.push_back(div);\n }\n }\n std::sort(ans.begin(), ans.end());\n std::cout << n << \":\";\n for (auto v: ans) {\n std::cout << ' ' << v;\n }\n std::cout << std::endl;\n\n return 0;\n}\n\nint main() {\n init();\n while (!solve());\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3768, "score_of_the_acc": -0.0628, "final_rank": 5 }, { "submission_id": "aoj_1154_8976300", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = 3.141592653589793;\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\ntemplate<typename T> void view(const vv<T>& vv){ for(const auto& v : vv){ view(v); } }\n\nvc<bool> eratosthenes(int t){\n vc<bool> is_prime(t + 1, true);\n is_prime[0] = false, is_prime[1] = false;\n for (int i = 0; i <= t; i++){\n if ((i % 7 == 1 || i % 7 == 6) && is_prime[i]){\n for (int q = i * 2; q <= t; q += i){\n is_prime[q] = false;\n }\n }else is_prime[i] = false;\n }\n return is_prime;\n}\n\nauto is_prime = eratosthenes(300300);\n\nvi solve(int N){\n vi ans = {N};\n rep(i, N + 1) if (is_prime[i] && N % i == 0) ans.push_back(i);\n return ans;\n}\n\nint main(){\n vc<vi> ans;\n while (true){\n int N; cin >> N;\n if (N == 1) break;\n ans.push_back(solve(N));\n }\n for (auto x : ans){\n cout << x[0] << \":\";\n srep(i, 1, len(x)) cout << \" \" << x[i];\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 3336, "score_of_the_acc": -0.2427, "final_rank": 11 }, { "submission_id": "aoj_1154_8861993", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(NULL);\n\n vector<int> lists;\n bool checked[300001] = {};\n for (int i = 2; i <= 300000; i++) {\n if (checked[i])\n continue;\n if (i % 7 == 1 || i % 7 == 6) {\n lists.push_back(i);\n for (int j = i; j <= 300000; j += i) {\n checked[j] = true;\n }\n }\n }\n\n while (true) {\n int n;\n cin >> n;\n if (n == 1)\n break;\n cout << n << ':';\n for (auto p : lists) {\n if (n % p == 0) {\n cout << \" \" << p;\n }\n }\n cout << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3700, "score_of_the_acc": -0.0599, "final_rank": 4 }, { "submission_id": "aoj_1154_8861990", "code_snippet": "#include <bitset>\n#include <iostream>\n#include <vector>\nusing namespace std;\n#define int long long\n#define rep2(i, a, b) for (int i = (a); i < (b); i++)\nbitset<300000 + 1> checked;\nvector<int> lists;\nvector<int> ans;\n// Precomputed results of modulus operation for 7.\nint mod7[7] = {0, 1, 2, 3, 4, 5, 6};\nsigned main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n rep2(i, 2, 300000 + 1) {\n if (checked[i])\n continue;\n // Use lookup table to replace modulus operation.\n if (mod7[i % 7] == 1 || mod7[i % 7] == 6) {\n lists.push_back(i);\n int k = 1;\n while (i * k <= 300000) {\n checked[i * k] = true;\n k++;\n }\n }\n }\n // Reserve space for \"ans\" vector in advance.\n ans.reserve(lists.size());\n while (true) {\n int n;\n cin >> n;\n if (n == 1)\n break;\n for (auto p : lists) {\n if (n % p == 0) {\n ans.push_back(p);\n }\n }\n cout << n << ':';\n for (auto num : ans) { cout << \" \" << num; }\n cout << endl;\n ans.clear();\n }\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3604, "score_of_the_acc": -0.1763, "final_rank": 9 } ]
aoj_1150_cpp
Problem D: Cliff Climbing At 17:00, special agent Jack starts to escape from the enemy camp. There is a cliff in between the camp and the nearest safety zone. Jack has to climb the almost vertical cliff by stepping his feet on the blocks that cover the cliff. The cliff has slippery blocks where Jack has to spend time to take each step. He also has to bypass some blocks that are too loose to support his weight. Your mission is to write a program that calculates the minimum time to complete climbing. Figure D-1 shows an example of cliff data that you will receive. The cliff is covered with square blocks. Jack starts cliff climbing from the ground under the cliff, by stepping his left or right foot on one of the blocks marked with 'S' at the bottom row. The numbers on the blocks are the "slippery levels". It takes t time units for him to safely put his foot on a block marked with t , where 1 ≤ t ≤ 9. He cannot put his feet on blocks marked with 'X'. He completes the climbing when he puts either of his feet on one of the blocks marked with 'T' at the top row. Figure D-1: Example of Cliff Data Jack's movement must meet the following constraints. After putting his left (or right) foot on a block, he can only move his right (or left, respectively) foot. His left foot position ( lx , ly ) and his right foot position ( rx , ry ) should satisfy lx < rx and | lx - rx | + | ly - ry | ≤ 3 . This implies that, given a position of his left foot in Figure D-2 (a), he has to place his right foot on one of the nine blocks marked with blue color. Similarly, given a position of his right foot in Figure D-2 (b), he has to place his left foot on one of the nine blocks marked with blue color. Figure D-2: Possible Placements of Feet Input The input is a sequence of datasets. The end of the input is indicated by a line containing two zeros separated by a space. Each dataset is formatted as follows: w h s(1,1) ... s(1,w) s(2,1) ... s(2,w) ... s(h,1) ... s(h,w) The integers w and h are the width and the height of the matrix data of the cliff. You may assume 2 ≤ w ≤ 30 and 5 ≤ h ≤ 60. Each of the following h lines consists of w characters delimited by a space. The character s(y, x) represents the state of the block at position ( x , y ) as follows: 'S': Jack can start cliff climbing from this block. 'T': Jack finishes climbing when he reaches this block. 'X': Jack cannot put his feet on this block. '1' - '9' ( = t ): Jack has to spend t time units to put either of his feet on this block. You can assume that it takes no time to put a foot on a block marked with 'S' or 'T'. Output For each dataset, print a line only having a decimal integer indicating the minimum time required for the cliff climbing, when Jack can complete it. Otherwise, print a line only having "-1" for the dataset. Each line should not have any characters other than these numbers. Sample Input 6 6 4 4 X X T T 4 7 8 2 X 7 3 X X X 1 8 1 2 X X X 6 1 1 2 4 4 7 S S 2 3 X X 2 10 T 1 1 X 1 X 1 X 1 1 1 X 1 ...(truncated)
[ { "submission_id": "aoj_1150_10853812", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <queue>\n#include <cstdio>\nusing namespace std;\n#define reps(i,j,k) for(int i = j ; i < k ; ++i)\n#define rep(i,j) reps(i,0,j)\n\n\nconst int ldx[] = {1,1,2,1,2,3,1,2,1};\nconst int ldy[] = {2,1,1,0,0,0,-1,-1,-2};\n\nconst int rdx[] = {-1,-2,-1,-3,-2,-1,-2,-1,-1};\nconst int rdy[] = {2,1,1,0,0,0,-1,-1,-2};\n\nclass data{\npublic:\n\tint y;\n\tint x;\n\tint cost;\n\tbool is_r;\n\tdata(){}\n\tdata(int y,int x,int cost,bool is_r){\n\t\tthis->y = y;\n\t\tthis->x = x;\n\t\tthis->cost = cost;\n\t\tthis->is_r = is_r;\n\t}\n\t\n\tbool operator<(const data &a)const{\n\t\treturn a.cost < cost;\n\t}\n\n};\nint memo[70][50][2];\nint main(){\n\tint w,h;\n\twhile(true){\n\t\trep(i,70){\n\t\t\trep(j,50){\n\t\t\t\trep(k,2){\n\t\t\t\t\tmemo[i][j][k] = 1e9;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcin >> w >> h;\n\t\tchar stage[100][100];\n\t\tif( w == 0 && h == 0)break;\n\t\trep(i,h){\n\t\t\trep(j,w){\n\t\t\t\tscanf(\" %c\",&stage[i][j]);\n\t\t\t}\n\t\t}\n\t\tpriority_queue < data > Q;\n\t\trep(i,h){\n\t\t\trep(j,w){\n\t\t\t\tif(stage[i][j] == 'S'){\n\n\t\t\t\t\tQ.push(data(i,j,0,true));\n\t\t\t\t\tQ.push(data(i,j,0,false));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint ans = -1;\n\t\twhile(!Q.empty()){\n\t\t\tdata d = Q.top();\n\t\t\tQ.pop();\n\t\t\tif(memo[d.y][d.x][d.is_r] != 1e9)continue;\n\t\t\tmemo[d.y][d.x][d.is_r] = d.cost;\t\t\t\n\t\t\tif(stage[d.y][d.x] == 'T'){\n\t\t\t\tans = d.cost;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif(d.is_r){\n\t\t\t\trep(idx,9){\n\t\t\t\t\tint ny = d.y + rdy[idx];\n\t\t\t\t\tint nx = d.x + rdx[idx];\n\t\t\t\t\tif(ny < 0 || ny > h-1 || nx < 0 || nx > w-1 || stage[ny][nx] == 'X'){\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t\tif(stage[ny][nx] == 'S' || stage[ny][nx] == 'T'){\n\t\t\t\t\t\tQ.push(data(ny,nx,d.cost,false));\n\t\t\t\t\t}\n\t\t\t\t\telse Q.push(data(ny,nx,d.cost+stage[ny][nx]-'0',false));\n\t\t\t\t}\n\t\t\t}\n\t\t\telse{\n\t\t\t\trep(idx,9){\n\t\t\t\t\tint ny = d.y + ldy[idx];\n\t\t\t\t\tint nx = d.x + ldx[idx];\n\t\t\t\t\tif(ny < 0 || ny > h-1 || nx < 0 || nx > w-1 || stage[ny][nx] == 'X'){\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t\tif(stage[ny][nx] == 'S' || stage[ny][nx] == 'T'){\n\t\t\t\t\t\tQ.push(data(ny,nx,d.cost,true));\n\t\t\t\t\t}\n\t\t\t\t\telse Q.push(data(ny,nx,d.cost+stage[ny][nx]-'0',true));\n\t\t\t\t}\n\n\t\t\t}\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3652, "score_of_the_acc": -0.0181, "final_rank": 13 }, { "submission_id": "aoj_1150_10673101", "code_snippet": "#include <queue>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n// #ifndef ONLINE_JUDGE\n// #define _GLIBCXX_DEBUG // 配列外参照のエラー\n// #endif\n\n// スタンダードライブラリ\n#include <bits/stdc++.h>\nusing namespace std;\n\n// 型関連\nusing ll = long long;\nusing lint = long long;\nusing pll = pair<ll, ll>;\nusing plll = tuple<ll, ll, ll>;\nusing pii = pair<int, int>;\nusing piii = tuple<ll, ll, ll>;\nusing vi = vector<int>;\nusing vvi = vector<vector<int>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing vvvvi = vector<vector<vector<vector<int>>>>;\nusing vvvvvi = vector<vector<vector<vector<vector<int>>>>>;\nusing vl = vector<ll>;\nusing vvl = vector<vector<ll>>;\nusing vvvl = vector<vector<vector<ll>>>;\nusing vvvvl = vector<vector<vector<vector<ll>>>>;\n\ntemplate <class T> using prique = priority_queue<T>;\ntemplate <class T> void chmin(T &a, T b) {\n if (a > b)\n a = b;\n}\ntemplate <class T> void chmax(T &a, T b) {\n if (a < b)\n a = b;\n}\n\n#define all(v) v.begin(), v.end()\n\n// 型定数\nconstexpr ll mod = 998244353;\nconstexpr ll MOD = 1000000007;\nint INF32 = 2e9;\nll INF64 = 9e18;\n#define endl '\\n';\n\nint dx[4] = {1, 0, -1, 0};\nint dy[4] = {0, 1, 0, -1};\n\n/////////////////////////// print関連\ntemplate <typename T> void print(vector<T> A);\nvoid print();\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail);\nvoid print(string S);\ntemplate <typename T> void print(vector<vector<T>> &F);\n\ninline void Yes(bool f);\n\n///////////////////ここから//////////////////////\nbool solve() {\n int H, W;\n cin >> W >> H;\n if (H == 0) {\n return false;\n }\n\n vvi F(H, vi(W));\n set<pii> Sset, Tset, Xset;\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n char c;\n cin >> c;\n if (c == 'S') {\n Sset.insert({i, j});\n } else if (c == 'T') {\n Tset.insert({i, j});\n } else if (c == 'X') {\n Xset.insert({i, j});\n } else {\n F[i][j] = c - '0';\n }\n }\n }\n\n int drx[2][9] = {{-2, -1, -1, 0, 0, 0, 1, 1, 2},\n {-2, -1, -1, 0, 0, 0, 1, 1, 2}};\n int dry[2][9] = {{1, 1, 2, 1, 2, 3, 1, 2, 1},\n {-1, -1, -2, -1, -2, -3, -1, -2, -1}};\n\n using state = tuple<int,int,int,int>;\n priority_queue<state, vector<state>, greater<state>> que;\n vvvi dist(H, vvi(W, vi(2, INF32)));\n vvvi f(H, vvi(W, vi(2, 0)));\n\n for (auto [x, y] : Sset) {\n for (int L = 0; L < 2; L++) {\n dist[x][y][L] = 0;\n que.emplace(0, x, y, L);\n }\n }\n while (!que.empty()) {\n auto [dis, x, y, L] = que.top();\n que.pop();\n if (f[x][y][L]) {\n continue;\n }\n f[x][y][L] = 1;\n for (int d = 0; d < 9; d++) {\n int nx = x + drx[L][d], ny = y + dry[L][d],nL=1-L;\n if (nx < 0 || nx >= H || ny < 0 || ny >= W) {\n continue;\n }\n if (Xset.count({nx, ny}) || dis + F[nx][ny] >= dist[nx][ny][nL]) {\n continue;\n }\n dist[nx][ny][nL] = dis + F[nx][ny];\n que.emplace(dist[nx][ny][nL],nx,ny,nL);\n }\n }\n int ans=INF32;\n for (auto [x, y] : Tset) {\n for (int L = 0; L < 2; L++) {\n chmin(ans,dist[x][y][L]);\n }\n }\n if (ans == INF32) {\n print(-1);\n } else {\n print(ans);\n }\n\n return true;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n while (solve())\n ;\n}\n\n////////////////////print/////////////////////////\n// 1次元ベクトルを出力する\ntemplate <typename T> void print(vector<T> A) {\n if (A.size() == 0) {\n return;\n }\n for (size_t i = 0; i < A.size() - 1; i++) {\n cout << A[i] << ' ';\n }\n cout << A[A.size() - 1] << endl;\n return;\n}\n\n// 2次元ベクトルを出力する\ntemplate <typename T> void print(vector<vector<T>> &F) {\n for (size_t i = 0; i < F.size(); i++) {\n for (size_t j = 0; j < F[i].size(); j++) {\n cout << F[i][j];\n if (j < F[i].size() - 1) {\n cout << ' ';\n }\n }\n cout << endl;\n }\n}\n\n// 空白行を出力するprint\nvoid print() { cout << endl; }\n\n// 数値・文字列を空白区切りで出力する. print(a,b)など\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n cout << head;\n if (sizeof...(tail) != 0)\n cout << \" \";\n print(forward<Tail>(tail)...);\n}\n\nvoid print(string S) { cout << S << endl; }\n\n//////////////出力関連\n\ninline void Yes(bool f) {\n if (f) {\n cout << \"Yes\" << endl;\n } else {\n cout << \"No\" << endl;\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3840, "score_of_the_acc": -0.0304, "final_rank": 15 }, { "submission_id": "aoj_1150_10599454", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n// 15::44 ~\nconst int INF = 2e8;\n\nint main() {\n while (true) {\n int w, h;\n cin >> w >> h;\n if (w == 0 && h == 0) {\n break;\n }\n\n vector<vector<char>> grid(h, vector<char>(w));\n vector<pair<int, int>> start;\n vector<pair<int, int>> target;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n cin >> grid[i][j];\n if (grid[i][j] == 'S') {\n start.emplace_back(i, j);\n grid[i][j] = '0';\n }\n if (grid[i][j] == 'T') {\n target.emplace_back(i, j);\n grid[i][j] = '0';\n }\n }\n }\n\n vector<vector<vector<int>>> dist(h, vector<vector<int>>(w, vector<int>(2, INF)));\n priority_queue<tuple<int, int, int, int>, vector<tuple<int, int, int, int>>, greater<>> pq;\n for (auto [x, y] : start) {\n dist[x][y][0] = 0;\n dist[x][y][1] = 0;\n pq.emplace(0, x, y, 0);\n pq.emplace(0, x, y, 1);\n }\n\n while (!pq.empty()) {\n auto [cost, x, y, leg] = pq.top();\n pq.pop();\n\n if (dist[x][y][leg] < cost) {\n continue;\n }\n\n // 左足からの移動\n if (leg == 0) {\n for (int ay = 1; ay <= 3; ay++) {\n for (int ax = -2; ax <= 2; ax++) {\n int rx = x + ax;\n int ry = y + ay;\n if (rx < 0 || rx >= h || ry < 0 || ry >= w) {\n continue;\n }\n if (grid[rx][ry] == 'X') {\n continue;\n }\n if (!(abs(x - rx) + abs(y - ry) <= 3)) {\n continue;\n }\n\n int next_cost = cost + (grid[rx][ry] - '0');\n if (dist[rx][ry][1] > next_cost) {\n dist[rx][ry][1] = next_cost;\n pq.emplace(next_cost, rx, ry, 1);\n }\n }\n }\n }\n\n // 右足からの移動\n if (leg == 1) {\n for (int ay = -3; ay <= -1; ay++) {\n for (int ax = -2; ax <= 2; ax++) {\n int lx = x + ax;\n int ly = y + ay;\n if (lx < 0 || lx >= h || ly < 0 || ly >= w) {\n continue;\n }\n if (grid[lx][ly] == 'X') {\n continue;\n }\n if (!(abs(x - lx) + abs(y - ly) <= 3)) {\n continue;\n }\n\n int next_cost = cost + (grid[lx][ly] - '0');\n if (dist[lx][ly][0] > next_cost) {\n dist[lx][ly][0] = next_cost;\n pq.emplace(next_cost, lx, ly, 0);\n }\n }\n }\n }\n }\n\n int ans = INF;\n for (auto [x, y] : target) {\n ans = min({ans, dist[x][y][0], dist[x][y][1]});\n }\n cout << (ans == INF ? -1 : ans) << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3840, "score_of_the_acc": -0.0179, "final_rank": 12 }, { "submission_id": "aoj_1150_10592771", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate<typename T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\nbool solve() {\n int H, W;\n cin >> W >> H;\n if (H == 0 && W == 0) return false;\n vector<vector<char>> C(H, vector<char>(W));\n vector D(H, vector(W, array<int, 2>{1 << 30, 1 << 30}));\n pqg<tuple<int, int, int, int>> q;\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n cin >> C[i][j];\n if (C[i][j] == 'S') {\n D[i][j][0] = 0;\n D[i][j][1] = 0;\n q.emplace(0, i, j, 0);\n q.emplace(0, i, j, 1);\n }\n }\n }\n int ans = 1 << 30;\n while (q.size()) {\n auto [d, r, c, f] = q.top();\n q.pop();\n if (C[r][c] == 'T') ans = min(ans, d);\n for (int dr = -3; dr <= 3; dr++) {\n for (int dc = -3; dc <= 3; dc++) {\n if (abs(dr) + abs(dc) > 3) continue;\n if (f && dc >= 0) continue;\n if (!f && dc <= 0) continue;\n int nr = r + dr, nc = c + dc;\n if (0 <= nr && nr < H && 0 <= nc && nc < W) {\n if (C[nr][nc] == 'X') continue;\n int w = (isdigit(C[nr][nc]) ? C[nr][nc] - '0' : 0);\n if (D[nr][nc][!f] > d + w) {\n D[nr][nc][!f] = d + w;\n q.emplace(d + w, nr, nc, !f);\n }\n }\n }\n }\n }\n if (ans == 1 << 30) ans = -1;\n cout << ans << '\\n';\n return true;\n}\n\nint main() {\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3584, "score_of_the_acc": -0.0084, "final_rank": 1 }, { "submission_id": "aoj_1150_10581645", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef int ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rrep(i,start,end) for (ll i = start;i >= (ll)(end);i--)\n#define repn(i,end) for(ll i = 0; i <= (ll)(end); i++)\n#define reps(i,start,end) for(ll i = start; i < (ll)(end); i++)\n#define repsn(i,start,end) for(ll i = start; i <= (ll)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef vector<ll> vll;\ntypedef vector<pair<ll ,ll>> vpll;\ntypedef vector<vector<ll>> vvll;\ntypedef set<ll> sll;\ntypedef map<ll , ll> mpll;\ntypedef pair<ll ,ll> pll;\ntypedef tuple<ll , ll , ll> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (ll)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1 << 29;\nconst ld EPS = 1e-9;\n \nll lceil(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b)+1;}else{return -((-a)/b);}}\nll lfloor(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b);}else{return -((-a)/b)-1;}}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\n//0indexed\ninline ll topbit(ll a){assert(a != 0);return 63 - __builtin_clzll(a);}\ninline ll smlbit(ll a){assert(a != 0);return __builtin_ctzll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\nvoid solve(ll h,ll w){\n vector<vector<char>> s(h,vector<char>(w));\n rep(i,h){\n cin>> s[i];\n }\n vpll ltor,rtol;\n repsn(i,-2,2)repsn(j,1,3){\n if(abs(i)+abs(j)<= 3){\n ltor.push_back({i,j});\n rtol.push_back({i,-j});\n }\n }\n // ll siz = sz(ltor);\n\n auto tostate =[&](ll i,ll j,ll k,ll l,ll z){\n return z * (h*w)*(h*w) + i *(h*w)*w + j *(h*w) + k * w + l;\n };\n auto revstate = [&](ll v) -> tuple<ll,ll,ll,ll,ll> {\n ll l = v % w;\n ll k = (v%(h*w))/w;\n v /= h * w;\n ll j = v % w;\n ll i = (v%(h*w))/w;\n v /= h * w;\n ll z = v;\n return{i,j,k,l,z};\n };\n // vector<vpll> g(h * w*h*w * 2);\n // rep(i,h)rep(j,w)rep(k,h)rep(l,w){\n // if(s[i][j] == 'X' or s[k][l] == 'X')continue;\n // bool ok = false;\n // each(p,ltor){\n // auto[a,b] = p;\n // if(i+a == k && j + b == l)ok =true;\n // }\n // if(!ok)continue;\n // //hidari,migi\n // each(p,ltor){\n // auto [a,b] = p;\n // if(isin(i+a,j+b,h,w) && s[i+a][j+b] != 'X'){\n // g[tostate(i,j,k,l,0)].emplace_back(tostate(i,j,i+a,b+j,1),isdigit(s[i+a][b+j])?s[i+a][b+j]-'0':0);\n // }\n // }\n // each(p,rtol){\n // auto [a,b] = p;\n // if(isin(k+a,l+b,h,w) && s[k+a][l+b] != 'X'){\n // g[tostate(i,j,k,l,1)].emplace_back(tostate(k+a,l+b,k,l,0),isdigit(s[k+a][b+l])?s[k+a][l+b]-'0':0);\n // }\n // }\n \n // }\n\n using P = pair<ll,ll>;\n vll dis(h * w*h*w * 2,INF);\n\n // G[i]<j,d> i->j の距離(d)\n // 「仮の最短距離, 頂点」が小さい順に並ぶ\n priority_queue<P,vector<P>,greater<P>>pq;\n vll ablegoal;\n rep(i,h)rep(j,w){\n if(s[i][j] == 'S'){\n //hidari\n each(p,ltor){\n auto [a,b] = p;\n if(isin(i+a,j+b,h,w) && s[i+a][j+b] != 'X'){\n dis[tostate(i,j,i+a,b+j,1)] = isdigit(s[i+a][b+j])?s[i+a][b+j]-'0':0;\n pq.push({dis[tostate(i,j,i+a,b+j,1)],tostate(i,j,i+a,b+j,1)});\n }\n }\n each(p,rtol){\n auto [a,b] = p;\n if(isin(i+a,j+b,h,w) && s[i+a][j+b] != 'X'){\n dis[tostate(i+a,j+b,i,j,0)] = isdigit(s[i+a][b+j])?s[i+a][b+j]-'0':0;\n pq.push({dis[tostate(i+a,j+b,i,j,0)],tostate(i+a,j+b,i,j,0)});\n }\n }\n }\n if(s[i][j] == 'T'){\n each(p,ltor){\n auto [a,b] = p;\n if(isin(i+a,j+b,h,w) && s[i+a][j+b] != 'X'){\n ablegoal.push_back(tostate(i,j,i+a,j+b,0));\n ablegoal.push_back(tostate(i,j,i+a,j+b,1));\n }\n }\n each(p,rtol){\n auto [a,b] = p;\n if(isin(i+a,j+b,h,w) && s[i+a][j+b] != 'X'){\n ablegoal.push_back(tostate(i+a,j+b,i,j,0));\n ablegoal.push_back(tostate(i+a,j+b,i,j,1));\n }\n }\n }\n }\n while(!pq.empty()){\n auto [len,now] = pq.top();\n pq.pop();\n if(dis[now]< len){\n continue;\n }\n auto[i,j,k,l,z] = revstate(now);\n if(z == 0){\n each(p,ltor){\n auto [a,b] = p;\n if(isin(i+a,j+b,h,w) && s[i+a][j+b] != 'X'){\n ll next = tostate(i,j,i+a,b+j,1);\n ll cost =isdigit(s[i+a][b+j])?s[i+a][b+j]-'0':0;\n if(dis[next] > dis[now] + cost){\n dis[next] = dis[now] + cost;\n pq.push({dis[next],next});\n }\n }\n }\n }else if(z == 1){\n each(p,rtol){\n auto [a,b] = p;\n if(isin(k+a,l+b,h,w) && s[k+a][l+b] != 'X'){\n ll next = tostate(k+a,l+b,k,l,0);\n ll cost =isdigit(s[k+a][l+b])?s[k+a][l+b]-'0':0;\n if(dis[next] > dis[now] + cost){\n dis[next] = dis[now] + cost;\n pq.push({dis[next],next});\n }\n }\n }\n }\n\n\n // for(auto &p:g[now]){\n // // 注意!\n // auto [next,cost] = p;\n // if(dis[next] > dis[now] + cost){\n // dis[next] = dis[now] + cost;\n // pq.push({dis[next],next});\n // }\n // }\n }\n ll ans = INF;\n each(p,ablegoal){\n chmin(ans,dis[p]);\n }\n if(ans >= INF){\n cout << -1 << endl;\n }else{\n cout << ans << endl;\n }\n}\n \nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true){\n LL(w,h);\n if(w == 0 && h == 0)break;\n solve(h,w);\n }\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 51684, "score_of_the_acc": -1.0625, "final_rank": 19 }, { "submission_id": "aoj_1150_10114881", "code_snippet": "#include <bits/stdc++.h>\n\n\nusing namespace std;\n//make -f ../makefile SRC=\n/*\n*/\n\n\n//------------------------------------------------------------------------------\nbool DEBUG = false;\nconst int INF = 1000000000;\n\nconst int MAX_M = 60;\nconst int MAX_N = 30;\nstatic int G[MAX_M*MAX_N];\nconst int F = 2;\nstatic int D[MAX_M*MAX_N][F];\nstatic bool marked[MAX_M*MAX_N];\n\nconst char SRC = 'S';\nconst char DEST = 'T';\nconst char WALL = 'X';\nconst char FREE = '.';\n\ntypedef pair<int,int> PA;\ntypedef vector<PA> PAS;\nstatic vector<PAS> actions =\n{\n {{0,-1}, {0,-2}, {0,-3}, {-1,-1}, {-1,-2}, {-2,-1}, {1,-1}, {1,-2}, {2,-1}},\n {{0, 1}, {0, 2}, {0, 3}, {-1, 1}, {-1, 2}, {-2, 1}, {1, 1}, {1, 2}, {2, 1}}\n};\n//------------------------------------------------------------------------------\nstruct State\n{\n int v; // vertex\n int f; // foot // L=0, R=1\n State(): v(-1), f(1) {}\n State(int vert, int foot): v(vert), f(foot) {}\n bool operator<(const State& s1) const\n {\n if (v == s1.v) return f < s1.f;\n return v < s1.v;\n }\n void debug() const\n {\n printf(\"v=%d, f=%c\\n\", v, f);\n }\n};\n\ntypedef vector<State> States;\n//------------------------------------------------------------------------------\nvoid debug_grid(int M, int N)\n{\n for (int m=0; m<M; ++m) { for (int n=0; n<N; ++n) if (G[m*N+n]!=INF) printf(\"%d \",G[m*N+n]); else printf(\"X \"); printf(\"\\n\"); }\n}\n\n\n//------------------------------------------------------------------------------\nStates successors(int M, int N, const State& s1)\n{\n States states;\n int m1 = s1.v/N;\n int n1 = s1.v%N;\n\n int m2, n2, v2;\n int f2 = ( s1.f == 0 ? 1 : 0 );\n //--------------------------------------------------------------------------\n for (PA p: actions[f2])\n {\n m2 = m1 + p.first;\n n2 = n1 + p.second;\n\n if (m2 < 0 || m2 >= M || n2 < 0 || n2 >= N) continue;\n v2 = m2*N + n2;\n if (G[v2] == INF) continue;\n states.push_back( State(v2, f2) );\n }\n return states;\n}\n//------------------------------------------------------------------------------\nint bfs(int M, int N, const State& s0, const set<int>& dests)\n{\n queue<State> Q;\n for (int v=0; v<M*N; v++) { D[v][0] = INF; D[v][1] = INF; }\n D[s0.v][s0.f] = 0;\n Q.push( s0 );\n\n int res = INF;\n while (!Q.empty())\n {\n State s1 = Q.front(); Q.pop();\n if (dests.find(s1.v) != dests.end())\n {\n res = min(res, D[s1.v][s1.f]);\n continue;\n }\n\n for (State s2: successors(M, N, s1))\n {\n if (D[s2.v][s2.f] == INF || D[s2.v][s2.f] > D[s1.v][s1.f] + G[s2.v])\n {\n D[s2.v][s2.f] = D[s1.v][s1.f] + G[s2.v];\n Q.push( s2 );\n }\n }\n }\n return res;\n}\n\n//------------------------------------------------------------------------------\nvoid test()\n{\n\n}\n\n//------------------------------------------------------------------------------\nint solve(int M, int N, const vector<int>& srcs, const set<int>& dests)\n{\n if (DEBUG)\n {\n debug_grid(M, N);\n printf(\"srcs: \"); for (int v: srcs) printf(\"%d \",v); printf(\"\\n\");\n printf(\"dests: \"); for (int v: dests) printf(\"%d \",v); printf(\"\\n\");\n }\n //--------------------------------------------------------------------------\n // base cases:\n if (dests.empty()) return INF;\n //--------------------------------------------------------------------------\n // init params:\n int res = INF;\n //--------------------------------------------------------------------------\n // compute:\n State s0;\n for (int src: srcs)\n {\n s0 = State(src, 0);\n res = min(res, bfs(M, N, s0, dests));\n\n s0 = State(src, 1);\n res = min(res, bfs(M, N, s0, dests));\n }\n return res;\n}\n\n//------------------------------------------------------------------------------printf(\"%d\\n\", res);\nint main()\n{\n //test(); return 0;\n //DEBUG = true;\n //--------------------------------------------------------------------------\n int M, N, v, src, num;\n char c;\n while (true)\n {\n num = scanf(\"%d %d \", &N, &M);\n if (N == 0 && M == 0) break;\n for (int v=0; v<M*N; ++v) G[v] = 0;\n\n vector<int> srcs;\n set<int> dests;\n for (int m=0; m<M; ++m)\n for (int n=0; n<N; ++n)\n {\n num = scanf(\"%c \", &c);\n v = m*N + n;\n if (c == WALL) G[v] = INF;\n else if (c == SRC) srcs.push_back( v );\n else if (c == DEST) dests.insert( v );\n else G[v] = c-'0';\n }\n\n int res = solve(M, N, srcs, dests);\n if (res == INF) printf(\"-1\\n\");\n else printf(\"%d\\n\", res);\n }\n //--------------------------------------------------------------------------\n return 0;\n}\n//------------------------------------------------------------------------------", "accuracy": 1, "time_ms": 1580, "memory_kb": 3436, "score_of_the_acc": -0.6595, "final_rank": 17 }, { "submission_id": "aoj_1150_9684868", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> pi;\ntypedef vector<ll> vi;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\ntemplate<typename T>bool chmin(T&a,T b){if(a>b){a=b;return 1;}return 0;}\ntemplate<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;\nint main(){\n while(1){\n ll W,H;cin>>W>>H;\n if(!W)return 0;\n vector<string>S(H,string(W,'.'));\n REP(i,H)REP(j,W)cin>>S[i][j];\n vector<vector<vector<ll>>>D(2,vector<vector<ll>>(H,vector<ll>(W,1e18)));\n min_priority_queue<tuple<ll,ll,ll,ll>>Q;\n REP(i,H)REP(j,W)if(S[i][j]=='S'){\n D[0][i][j]=D[1][i][j]=0;\n Q.emplace(make_tuple(0LL,0LL,i,j));\n Q.emplace(make_tuple(0LL,1LL,i,j));\n }\n vector<vector<pi>>move={\n {pi(2,1),pi(1,1),pi(1,2),pi(0,1),pi(0,2),pi(0,3),pi(-1,1),pi(-1,2),pi(-2,1)},\n {pi(2,-1),pi(1,-1),pi(1,-2),pi(0,-1),pi(0,-2),pi(0,-3),pi(-1,-1),pi(-1,-2),pi(-2,-1)}\n };\n while(Q.size()){\n auto[d,f,x,y]=Q.top();Q.pop();\n if(d!=D[f][x][y])continue;\n for(auto[dx,dy]:move[f]){\n if(min({x+dx,y+dy,H-1-x-dx,W-1-y-dy})>=0&&S[x+dx][y+dy]!='X'){\n ll c=S[x+dx][y+dy]-'0';\n if(S[x+dx][y+dy]=='T'||S[x+dx][y+dy]=='S')c=0;\n if(chmin(D[1-f][x+dx][y+dy],d+c))Q.emplace(make_tuple(d+c,1-f,x+dx,y+dy));\n }\n }\n }\n ll ans=1e18;\n REP(i,H)REP(j,W)if(S[i][j]=='T')ans=min({ans,D[0][i][j],D[1][i][j]});\n if(ans>1e17)ans=-1;\n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3412, "score_of_the_acc": -0.009, "final_rank": 4 }, { "submission_id": "aoj_1150_9555528", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint N, M;\n\nint encode(int i, int j, int k) {\n return i * M * 2 + j * 2 + k;\n}\n\ntuple<int,int,int> decode(int A) {\n return {A/(M*2), (A/2)%M, A%2};\n}\n\nint main() {\nwhile(1) {\n cin >> M >> N;\n if (N == 0 && M == 0) return 0;\n vector<vector<char>> C(N,vector<char>(M));\n rep(i,0,N) rep(j,0,M) cin >> C[i][j];\n vector DP(N, vector(M, vector<int>(2, inf)));\n priority_queue<pair<int,int>, vector<pair<int,int>>, greater<pair<int,int>>> PQ;\n rep(i,0,N) {\n rep(j,0,M) {\n if (C[i][j] == 'S') {\n DP[i][j][0] = DP[i][j][1] = 0;\n PQ.push({0,encode(i,j,0)});\n PQ.push({0,encode(i,j,1)});\n }\n }\n }\n while(!PQ.empty()) {\n pair<int,int> P = PQ.top();\n PQ.pop();\n int T = P.first;\n auto [X,Y,Z] = decode(P.second);\n if (DP[X][Y][Z] < T) continue;\n if (Z == 0) {\n rep(dy,1,4) {\n rep(dx,-2,3) {\n if (abs(dx)+abs(dy) > 3) continue;\n int NX = X + dx, NY = Y + dy, NZ = 1-Z;\n if (0 <= NX && NX < N && 0 <= NY && NY < M) {\n if (C[NX][NY] == 'X') continue;\n int NT;\n if (isdigit(C[NX][NY])) {\n NT = T + (C[NX][NY] - '0');\n }\n else {\n NT = T;\n }\n if (chmin(DP[NX][NY][NZ], NT)) {\n PQ.push({NT,encode(NX,NY,NZ)});\n }\n }\n }\n }\n }\n if (Z == 1) {\n rep(dy,-3,0) {\n rep(dx,-2,3) {\n if (abs(dx)+abs(dy) > 3) continue;\n int NX = X + dx, NY = Y + dy, NZ = 1-Z;\n if (0 <= NX && NX < N && 0 <= NY && NY < M) {\n if (C[NX][NY] == 'X') continue;\n int NT;\n if (isdigit(C[NX][NY])) {\n NT = T + (C[NX][NY] - '0');\n }\n else {\n NT = T;\n }\n if (chmin(DP[NX][NY][NZ], NT)) {\n PQ.push({NT,encode(NX,NY,NZ)});\n }\n }\n }\n }\n }\n }\n int ANS = inf;\n rep(i,0,N) {\n rep(j,0,M) {\n if (C[i][j] == 'T') {\n rep(k,0,2) {\n chmin(ANS, DP[i][j][k]);\n }\n }\n }\n }\n cout << (ANS == inf ? -1 : ANS) << endl;\n}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3404, "score_of_the_acc": -0.0089, "final_rank": 3 }, { "submission_id": "aoj_1150_9329860", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint INF=10000;\nint h,w;\nchar table[61][31];\nint cost[2][61][31];\npriority_queue<vector<int> > q;\nvector<pair<int,int> > v;\nint tu(int n){\n\treturn (n+1)/2;\n}\nvoid gen(int x,int y,int lr){\n\tv.clear();\n\tfor(int i=1;i<=3;i++){\n\t\tfor(int k=i-3;k<=3-i;k++){\n\t\t\tv.push_back(make_pair(x+lr*i,y+k));\n\t\t}\n\t}\n\tint len=v.size();\n\tfor(int i=0;i<len;i++){\n\t\tif(v.at(i).first<0||w<=v.at(i).first||v.at(i).second<0||h<=v.at(i).second){\n\t\t\tv.erase(v.begin()+i);\n\t\t\tlen--;\n\t\t\ti--;\n\t\t}\n\t}\n}\nint main(){\n\tcin>>w>>h;\n\twhile(w+h>0){\n\t\tfor(int i=0;i<h;i++){\n\t\t\tfor(int k=0;k<w;k++){\n\t\t\t\tcost[0][i][k]=-INF;\n\t\t\t\tcost[1][i][k]=-INF;\n\t\t\t\tcin>>table[i][k];\n\t\t\t\tif(table[i][k]=='S'){\n\t\t\t\t\tq.push({0,i,k,1});\n\t\t\t\t\tq.push({0,i,k,-1});\n\t\t\t\t\ttable[i][k]=0;\n\t\t\t\t}\n\t\t\t}\n\t\t}//l=1,r=-1\n\t\tbool flag=false;\n\t\tint t1,h1,w1,lr;\n\t\tint x,y,test;\n\t\twhile(q.size()>0&&flag==false){\n\t\t\tt1=q.top().at(0);\n\t\t\th1=q.top().at(1);\n\t\t\tw1=q.top().at(2);\n\t\t\tlr=q.top().at(3);\n\t\t\tq.pop();\n\t\t\tif(t1>cost[tu(lr)][h1][w1]){\n\t\t\t\tcost[tu(lr)][h1][w1]=t1;\n\t\t\t\tgen(w1,h1,lr);\n\t\t\t\twhile(v.size()>0){\n\t\t\t\t\tx=v.at(0).first;\n\t\t\t\t\ty=v.at(0).second;\n\t\t\t\t\tv.erase(v.begin());\n\t\t\t\t\tif(table[y][x]=='T'){\n\t\t\t\t\t\tflag=true;\n\t\t\t\t\t\tcout<<-t1<<endl;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\telse if(table[y][x]=='X'||table[y][x]=='S')continue;\n\t\t\t\t\telse {\n\t\t\t\t\t\ttest=table[y][x]-48;\n\t\t\t\t\t\tif(test<0)test=test+48;\n\t\t\t\t\t\tif(cost[tu(-lr)][y][x]<=-INF+100)q.push({t1-test,y,x,-lr});\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(flag==false)cout<<-1<<endl;\n\t\twhile(q.size()>0)q.pop();\n\t\tcin>>w>>h;\n\t}\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3176, "score_of_the_acc": -0.0167, "final_rank": 11 }, { "submission_id": "aoj_1150_9298577", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (int i = 0; i < (int) (n); i++)\ntemplate<class T>\nvoid chmax(T& p, T q) { if (p < q)p = q; };\n\nvoid solve(ll H, ll W) {\n swap(H, W);\n vector<vector<char>> C(H, vector<char>(W));\n rep(h, H)rep(w, W)cin >> C[h][w];\n vvvll DP(H, vvll(W, vll(2, 1e18)));\n vvvb seen(H, vvb(W, vb(2, 0)));\n priority_queue<pair<ll, pair<pair<ll, ll>, ll>>, vector<pair<ll, pair<pair<ll, ll>, ll>>>, greater<pair<ll, pair<pair<ll, ll>, ll>>>> Q;\n rep(h, H)rep(w, W) {\n if (C[h][w] == 'S') {\n DP[h][w][0] = DP[h][w][1] = 0;\n Q.push({ 0,{{h,w},0} });\n Q.push({ 0,{{h,w},1} });\n }\n }\n ll an = 1e18;\n while (!Q.empty()) {\n ll c = Q.top().first;\n ll h = Q.top().second.first.first;\n ll w = Q.top().second.first.second;\n ll u = Q.top().second.second;\n Q.pop();\n if (seen[h][w][u])continue;\n seen[h][w][u] = 1;\n if (u == 0) {\n for (ll nw = w + 1; nw <= min(w + 3, W - 1); nw++) {\n ll dh = 3 - (nw - w);\n for (ll nh = max(0ll, h - dh); nh <= min(H - 1, h + dh); nh++) {\n if (seen[nh][nw][1])continue;\n if (C[nh][nw] == 'X')continue;\n if (C[nh][nw] == 'T') {\n an = min(an, c);\n continue;\n }\n ll nc = c + C[nh][nw] - '0';\n if (DP[nh][nw][1] > nc) {\n DP[nh][nw][1] = nc;\n Q.push({ nc,{{nh,nw},1} });\n }\n }\n }\n }\n else {\n for (ll nw = w - 1; nw >= max(w - 3, 0ll); nw--) {\n ll dh = 3 - (w - nw);\n for (ll nh = max(0ll, h - dh); nh <= min(H - 1, h + dh); nh++) {\n if (seen[nh][nw][0])continue;\n if (C[nh][nw] == 'X')continue;\n if (C[nh][nw] == 'T') {\n an = min(an, c);\n continue;\n }\n ll nc = c + C[nh][nw] - '0';\n\n if (DP[nh][nw][0] > nc) {\n DP[nh][nw][0] = nc;\n Q.push({ nc,{{nh,nw},0} });\n }\n }\n }\n }\n }\n cout << (an < 1e17 ? an : -1) << endl;\n\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll H, W;\n while (cin >> H >> W) {\n if (H == 0)return 0;\n solve(H, W);\n }\n\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3660, "score_of_the_acc": -0.0141, "final_rank": 10 }, { "submission_id": "aoj_1150_9125072", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <map>\n#include <cmath>\n#include <queue>\n#include <string>\n#include <set>\n#include <stack>\n#include <numeric>\n#include <functional>\n#include <bitset>\n\nusing namespace std;\nusing ll = long long;\n\nconst ll INF = 1e9;\nint W, H;\n\nvoid solve() {\n vector<vector<char>> grid(H, vector<char>(W));\n for (int i = 0; i < H; i++)for (int j = 0; j < W; j++)cin >> grid[i][j];\n\n vector<pair<int, int>> start;\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n if (grid[i][j] == 'S')start.push_back({i, j});\n }\n }\n\n priority_queue<tuple<ll, int, int, int>, vector<tuple<ll, int, int, int>>, greater<>> pq;\n vector<vector<vector<ll>>> dist(H, vector<vector<ll>>(W, vector<ll>(2, INF)));\n for (auto [x, y]: start) {\n pq.push({0, x, y, 0});\n dist[x][y][0] = 0;\n }\n\n for (auto [x, y]: start) {\n pq.push({0, x, y, 1});\n dist[x][y][1] = 0;\n }\n\n ll ans = INF;\n while (!pq.empty()) {\n auto [cost, x, y, leg] = pq.top();\n pq.pop();\n if (dist[x][y][leg ^ 1] < cost)continue;\n\n if (leg == 0) {\n for (int i = 1; i <= 3; i++) {\n for (int j = -2; j <= 2; j++) {\n int lx = j + x, ly = i + y;\n if (abs(lx - x) + abs(ly - y) <= 3) {\n if (!(0 <= lx && lx < H && 0 <= ly && ly < W))continue;\n if (grid[lx][ly] == 'X')continue;\n if (grid[lx][ly] == 'T') {\n ans = min(ans, cost);\n continue;\n }\n if (dist[lx][ly][leg] > cost + (grid[lx][ly] - '0')) {\n dist[lx][ly][leg] = cost + (grid[lx][ly] - '0');\n pq.push({dist[lx][ly][leg], lx, ly, leg ^ 1});\n }\n }\n }\n }\n } else {\n for (int i = -3; i <= -1; i++) {\n for (int j = -2; j <= 2; j++) {\n int lx = j + x, ly = i + y;\n if (abs(lx - x) + abs(ly - y) <= 3) {\n if (!(0 <= lx && lx < H && 0 <= ly && ly < W))continue;\n if (grid[lx][ly] == 'X')continue;\n if (grid[lx][ly] == 'T') {\n ans = min(ans, cost);\n continue;\n }\n if (dist[lx][ly][leg] > cost + (grid[lx][ly] - '0')) {\n dist[lx][ly][leg] = cost + (grid[lx][ly] - '0');\n pq.push({dist[lx][ly][leg], lx, ly, leg ^ 1});\n }\n }\n }\n }\n }\n }\n if (ans == INF)cout << -1 << endl;\n else cout << ans << endl;\n}\n\nint main() {\n while (true) {\n cin >> W >> H;\n if (W == 0 && H == 0)break;\n solve();\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3400, "score_of_the_acc": -0.0088, "final_rank": 2 }, { "submission_id": "aoj_1150_9124714", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <map>\n#include <cmath>\n#include <queue>\n#include <string>\n#include <set>\n#include <stack>\n#include <numeric>\n#include <functional>\n#include <bitset>\n\nusing namespace std;\nusing ll = long long;\n\nconst ll INF = 1e9;\nint W, H;\n\nvoid solve() {\n vector<vector<char>> grid(H, vector<char>(W));\n for (int i = 0; i < H; i++)for (int j = 0; j < W; j++)cin >> grid[i][j];\n\n vector<pair<int, int>> start;\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n if (grid[i][j] == 'S')start.push_back({i, j});\n }\n }\n\n priority_queue<tuple<ll, int, int, int>, vector<tuple<ll, int, int, int>>, greater<>> pq;\n vector<vector<vector<ll>>> dist(H, vector<vector<ll>>(W, vector<ll>(2, INF)));\n for (auto [x, y]: start) {\n pq.push({0, x, y, 0});\n dist[x][y][0] = 0;\n }\n\n for (auto [x, y]: start) {\n pq.push({0, x, y, 1});\n dist[x][y][1] = 0;\n }\n\n ll ans = INF;\n while (!pq.empty()) {\n auto [cost, x, y, leg] = pq.top();\n pq.pop();\n if (dist[x][y][leg ^ 1] < cost)continue;\n\n if (leg == 0) {\n for (int i = 1; i <= 3; i++) {\n for (int j = -2; j <= 2; j++) {\n int lx = j + x, ly = i + y;\n if (abs(lx - x) + abs(ly - y) <= 3) {\n if (!(0 <= lx && lx < H && 0 <= ly && ly < W))continue;\n if (grid[lx][ly] == 'X')continue;\n if (grid[lx][ly] == 'T') {\n ans = min(ans, cost);\n continue;\n }\n if (dist[lx][ly][leg] > cost + (grid[lx][ly] - '0')) {\n dist[lx][ly][leg] = cost + (grid[lx][ly] - '0');\n pq.push({dist[lx][ly][leg], lx, ly, leg ^ 1});\n }\n }\n }\n }\n } else {\n for (int i = -3; i <= -1; i++) {\n for (int j = -2; j <= 2; j++) {\n int lx = j + x, ly = i + y;\n if (abs(lx - x) + abs(ly - y) <= 3) {\n if (!(0 <= lx && lx < H && 0 <= ly && ly < W))continue;\n if (grid[lx][ly] == 'X')continue;\n if (grid[lx][ly] == 'T') {\n ans = min(ans, cost);\n continue;\n }\n if (dist[lx][ly][leg] > cost + (grid[lx][ly] - '0')) {\n dist[lx][ly][leg] = cost + (grid[lx][ly] - '0');\n pq.push({dist[lx][ly][leg], lx, ly, leg ^ 1});\n }\n }\n }\n }\n }\n }\n// for (int op = 0; op < 2; op++) {\n// for (int i = 0; i < H; i++) {\n// for (int j = 0; j < W; j++) {\n// cout << (dist[i][j][op] == INF ? -1 : dist[i][j][op]) << \" \";\n// }\n// cout << endl;\n// }\n// cout << endl;\n// }\n\n if (ans == INF)cout << -1 << endl;\n else cout << ans << endl;\n}\n\nint main() {\n while (true) {\n cin >> W >> H;\n if (W == 0 && H == 0)break;\n solve();\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3552, "score_of_the_acc": -0.0119, "final_rank": 7 }, { "submission_id": "aoj_1150_9118146", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n// #pragma GCC target(\"avx2\")\n// #pragma GCC optimize(\"O3\")\n// #pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = 3.141592653589793;\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\n\nint solve(int h, int w){\n vv<char> S(h, vc<char>(w)); rep(i, h) rep(j, w) cin >> S[i][j];\n vvvi dist(h, vvi(w, vi(2, inf)));\n using P = tuple<int, int, int, int>;\n priority_queue<P, vc<P>, greater<P>> q;\n rep(i, h) rep(j, w) if (S[i][j] == 'S'){\n q.push({0, i, j, 0});\n q.push({0, i, j, 1});\n dist[i][j][0] = 0;\n dist[i][j][1] = 0;\n }\n vi dx = {-2, -1, -1, 0, 0, 0, 1, 1, 2}, dy = {1, 1, 2, 1, 2, 3, 1, 2, 1};\n while (!q.empty()){\n auto [d, x, y, f] = q.top(); q.pop();\n if (dist[x][y][f] < d) continue;\n rep(k, 9){\n int nx = x + dx[k], ny = y + (f ? dy[k] : -dy[k]);\n if (inside(nx, ny, h, w) && S[nx][ny] != 'X' && S[nx][ny] != 'S'){\n if (S[nx][ny] == 'T') return dist[x][y][f];\n else if (dist[nx][ny][f ^ 1] > dist[x][y][f] + S[nx][ny] - '0'){\n dist[nx][ny][f ^ 1] = dist[x][y][f] + S[nx][ny] - '0';\n q.push({dist[nx][ny][f ^ 1], nx, ny, f ^ 1});\n }\n }\n }\n }\n return -1;\n}\n\nint main(){\n vc<int> ans;\n while (true){\n int w, h; cin >> w >> h;\n if (w == 0) break;\n ans.push_back(solve(h, w));\n }\n for (auto x : ans) cout << x << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3552, "score_of_the_acc": -0.0119, "final_rank": 7 }, { "submission_id": "aoj_1150_9112780", "code_snippet": "#include <bits/stdc++.h>\n\nbool solve() {\n int W, H;\n std::cin >> W >> H;\n if (W == 0 and H == 0) {\n return false;\n }\n std::vector S(H, std::vector<char>(W, -1));\n for (int i{} ; i < H ; i++) {\n for (int j{} ; j < W ; j++) {\n std::cin >> S[i][j];\n }\n }\n auto in{[&](int x, int y) -> bool {\n return 0 <= x and x < H and 0 <= y and y < W;\n }};\n auto pos{[&](int x, int y) -> int {\n assert(in(x, y));\n return x * W + y;\n }};\n auto f{[&](int next, int lx, int ly, int rx, int ry) -> int {\n return next * (H * W * H * W) + pos(lx, ly) * (H * W) + pos(rx, ry);\n }};\n auto valid{[&](int lx, int ly, int rx, int ry) -> bool {\n if (!in(lx, ly)) return false;\n if (!in(rx, ry)) return false;\n if (S[lx][ly] == 'X') return false;\n if (S[rx][ry] == 'X') return false;\n if (ly >= ry) return false;\n if (std::abs(lx - rx) + std::abs(ly - ry) > 3) return false;\n return true;\n }};\n auto cost{[&](int x, int y) -> short {\n // assert(S[x][y] != 'X');\n if (S[x][y] == 'X') return (short)1e4;\n if (S[x][y] == 'S' or S[x][y] == 'T') return 0;\n return S[x][y] - '0';\n }};\n std::unordered_map<int, int> map;\n int N{};\n for (int lx{} ; lx < H ; lx++) {\n for (int ly{} ; ly < W ; ly++) {\n for (int rx{} ; rx < H ; rx++) {\n for (int ry{} ; ry < W ; ry++) {\n if (!valid(lx, ly, rx, ry)) continue;\n map[f(0, lx, ly, rx, ry)] = N++;\n map[f(1, lx, ly, rx, ry)] = N++;\n }\n }\n }\n }\n std::vector g(N, std::vector<std::pair<int, short>>{});\n for (int lx{} ; lx < H ; lx++) {\n for (int ly{} ; ly < W ; ly++) {\n for (int rx{} ; rx < H ; rx++) {\n for (int ry{} ; ry < W ; ry++) {\n if (!valid(lx, ly, rx, ry)) continue;\n for (int dx{-3} ; dx <= 3 ; dx++) {\n for (int dy{-3} ; dy <= 3 ; dy++) {\n if (dx == 0 and dy == 0) continue;\n int nlx{rx + dx}, nly{ry + dy};\n if (valid(nlx, nly, rx, ry) and std::pair(lx, ly) != std::pair(nlx, nly)) {\n // assert(nlx != lx or nly != ly);\n // std::cout << \"((\" << lx + 1 << ',' << ly + 1 << \"),(\" << rx + 1 << ',' << ry + 1 << \"))\" << \n // \" -> ((\" << nlx + 1 << ',' << nly + 1 << \"),(\" << rx + 1 << ',' << ry + 1 << \"))\" << std::endl;\n g[map[f(0, lx, ly, rx, ry)]].emplace_back(map[f(1, nlx, nly, rx, ry)], cost(nlx, nly));\n }\n int nrx{lx + dx}, nry{ly + dy};\n if (valid(lx, ly, nrx, nry) and std::pair(rx, ry) != std::pair(nrx, nry)) {\n // assert(nrx != rx or nry != ry);\n g[map[f(1, lx, ly, rx, ry)]].emplace_back(map[f(0, lx, ly, nrx, nry)], cost(nrx, nry));\n }\n }\n }\n }\n }\n }\n }\n const short INF{(short)1e4};\n std::vector<short> dist(N, INF);\n using qt = std::pair<short, int>;\n std::priority_queue<qt, std::vector<qt>, std::greater<qt>> que;\n for (int lx{} ; lx < H ; lx++) {\n for (int ly{} ; ly < W ; ly++) {\n for (int rx{} ; rx < H ; rx++) {\n for (int ry{} ; ry < W ; ry++) {\n if (!valid(lx, ly, rx, ry)) continue;\n if (S[lx][ly] == 'S') {\n // std::cout << lx << ' ' << ly << ' ' << rx << ' ' << ry << ' ' << cost(rx, ry) << std::endl;\n dist[map[f(0, lx, ly, rx, ry)]] = cost(rx, ry);\n que.emplace(cost(rx, ry), map[f(0, lx, ly, rx, ry)]);\n }\n if (S[rx][ry] == 'S') {\n // std::cout << lx << ' ' << ly << ' ' << rx << ' ' << ry << ' ' << cost(lx, ly) << std::endl;\n dist[map[f(1, lx, ly, rx, ry)]] = cost(lx, ly);\n que.emplace(cost(lx, ly), map[f(1, lx, ly, rx, ry)]);\n }\n }\n }\n }\n }\n while (que.size()) {\n auto [d, v]{que.top()};\n que.pop();\n if (dist[v] < d) continue;\n assert(dist[v] == d);\n for (auto [x, c] : g[v]) {\n if (dist[x] > d + c) {\n dist[x] = d + c;\n que.emplace(dist[x], x);\n }\n }\n }\n short ans{INF};\n for (int lx{} ; lx < H ; lx++) {\n for (int ly{} ; ly < W ; ly++) {\n for (int rx{} ; rx < H ; rx++) {\n for (int ry{} ; ry < W ; ry++) {\n if (!valid(lx, ly, rx, ry)) continue;\n // std::cout << lx + 1 << ' ' << ly + 1 << ' ' << rx + 1 << ' ' << ry + 1 << ' ' << f(0, lx, ly, rx, ry) << ' ' << f(1, lx, ly, rx, ry) << \" -> \" \n // << dist[f(0 ,lx, ly, rx, ry)] << ' ' << dist[f(1, lx, ly, rx, ry)] << std::endl;\n if (S[lx][ly] == 'T' or S[rx][ry] == 'T') {\n ans = std::min(ans, dist[map[f(0, lx, ly, rx, ry)]]);\n ans = std::min(ans, dist[map[f(1, lx, ly, rx, ry)]]);\n }\n }\n }\n }\n }\n // std::cout << f(0, 5, 0, 7, 1) << ' ' << f(1, 5, 0, 7, 1) << std::endl;\n // for (auto x : g[f(0, 9, 0, 7, 1)]) std::cout << x.first << ' ' << x.second << std::endl;;\n // std::cout << std::endl;\n std::cout << (ans == INF ? -1 : ans) << '\\n';\n return true;\n}\n\nint main() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n while (solve()) ;\n}", "accuracy": 1, "time_ms": 2410, "memory_kb": 7664, "score_of_the_acc": -1.0925, "final_rank": 20 }, { "submission_id": "aoj_1150_9056157", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\n#define rep(i, a, b) for(ll i = a; i < b; ++i)\n#define rrep(i, a, b) for(ll i = a; i >= b; --i)\nconstexpr ll inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\nint main(void) {\n constexpr int dx[2][9] = {\n {1, 1, 1, 1, 1, 2, 2, 2, 3},\n {-1, -1, -1, -1, -1, -2, -2, -2, -3},\n };\n constexpr int dy[2][9] = {\n {-2, -1, 0, 1, 2, -1, 0, 1, 0},\n {-2, -1, 0, 1, 2, -1, 0, 1, 0},\n };\n while(1) {\n int w, h;\n cin >> w >> h;\n if(w == 0 and h == 0) break;\n vector<vector<char>> c(h, vector<char>(w));\n rep(i, 0, h) {\n rep(j, 0, w) {\n cin >> c[i][j];\n }\n }\n rep(i, 0, h / 2) {\n swap(c[i], c[h - 1 - i]);\n }\n vector<vector<pair<int, int>>> g(2 * h * w);\n rep(i, 0, h) {\n rep(j, 0, w) {\n if(c[i][j] == 'X') continue;\n rep(k, 0, 2) {\n int idx = k * h * w + i * w + j;\n rep(l, 0, 9) {\n int ni = i + dy[k][l], nj = j + dx[k][l];\n if(0 <= ni and ni < h and 0 <= nj and nj < w and c[ni][nj] != 'X') {\n int nidx = (1 - k) * h * w + ni * w + nj;\n int cost = 0;\n if(isdigit(c[ni][nj])) {\n cost = c[ni][nj] - '0';\n }\n g[idx].push_back({nidx, cost});\n }\n }\n }\n }\n }\n vector<int> d(2 * h * w, 1e9);\n priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> pq;\n rep(i, 0, w) {\n if(c[0][i] == 'S') {\n d[i] = 0;\n pq.push({d[i], i});\n d[h * w + i] = 0;\n pq.push({d[h * w + i], h * w + i});\n }\n }\n while(!pq.empty()) {\n auto [dist, cur] = pq.top();\n pq.pop();\n if(d[cur] < dist) continue;\n for(const auto& [to, cost] : g[cur]) {\n if(d[to] > d[cur] + cost) {\n d[to] = d[cur] + cost;\n pq.push({d[to], to});\n }\n }\n }\n int ans = 1e9;\n rep(i, 0, w) {\n if(c[h - 1][i] == 'T') {\n ans = min(ans, d[(h - 1) * w + i]);\n ans = min(ans, d[h * w + (h - 1) * w + i]);\n }\n }\n if(ans == 1e9) {\n ans = -1;\n }\n cout << ans << '\\n';\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3908, "score_of_the_acc": -0.0193, "final_rank": 14 }, { "submission_id": "aoj_1150_8291106", "code_snippet": "#include <iostream>\n#include <tuple>\n#include <queue>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nconst int dy[9] = { 1, 1, 1, 1, 1, 2, 2, 2, 3 };\nconst int dx[9] = { -2, -1, 0, 1, 2, -1, 0, 1, 0 };\nint H, W;\nint V[69][69];\nbool Goal[69][69];\nbool Calced[2][2009][2009];\nint Dist[2][2009][2009];\n\nvoid Initialize() {\n\tfor (int i = 0; i < 69; i++) {\n\t\tfor (int j = 0; j < 69; j++) {\n\t\t\tV[i][j] = 0; Goal[i][j] = false;\n\t\t}\n\t}\n}\n\nint main() {\n\twhile (true) {\n\t\t// Step 1. Input\n\t\tInitialize();\n\t\tcin >> W >> H; if (W == 0 && H == 0) break;\n\t\tfor (int i = 0; i < H; i++) {\n\t\t\tfor (int j = 0; j < W; j++) {\n\t\t\t\tchar c; cin >> c;\n\t\t\t\tif (c == 'S') { V[i][j] = 0; }\n\t\t\t\tif (c == 'T') { V[i][j] = 0; Goal[i][j] = true; }\n\t\t\t\tif (c == 'X') { V[i][j] = 1000000; }\n\t\t\t\tif (c >= '1' && c <= '9') { V[i][j] = (c - '0'); }\n\t\t\t}\n\t\t}\n\n\t\t// Step 2. Dijkstra Init\n\t\tpriority_queue<tuple<int, int, int, int>, vector<tuple<int, int, int, int>>, greater<tuple<int, int, int, int>>> Q;\n\t\tfor (int i = 0; i <= H * W; i++) {\n\t\t\tfor (int j = 0; j <= H * W; j++) {\n\t\t\t\tDist[0][i][j] = 1000000; Calced[0][i][j] = false;\n\t\t\t\tDist[1][i][j] = 1000000; Calced[1][i][j] = false;\n\t\t\t}\n\t\t}\n\t\tfor (int i = 0; i < H * W; i++) {\n\t\t\tint px = i / W, py = i % W;\n\t\t\tif (V[px][py] != 0 || Goal[px][py] == true) continue;\n\t\t\tDist[0][i][H * W] = 0; Q.push(make_tuple(0, 0, i, H * W));\n\t\t\tDist[1][H * W][i] = 0; Q.push(make_tuple(0, 1, H * W, i));\n\t\t}\n\n\t\t// Step 3. Dijkstra\n\t\twhile (!Q.empty()) {\n\t\t\tint pos1 = get<1>(Q.top());\n\t\t\tint pos2 = get<2>(Q.top()); int px = pos2 / W, py = pos2 % W;\n\t\t\tint pos3 = get<3>(Q.top()); int qx = pos3 / W, qy = pos3 % W;\n\t\t\tQ.pop();\n\t\t\tif (Calced[pos1][pos2][pos3] == true) continue;\n\t\t\tCalced[pos1][pos2][pos3] = true;\n\t\t\tfor (int i = 0; i < 9; i++) {\n\t\t\t\tint rx = -1, ry = -1;\n\t\t\t\tif (pos1 == 0) { rx = px + dx[i]; ry = py + dy[i]; }\n\t\t\t\tif (pos1 == 1) { rx = qx - dx[i]; ry = qy - dy[i]; }\n\t\t\t\tif (rx < 0 || ry < 0 || rx >= H || ry >= W) continue;\n\t\t\t\tint nex1 = 1 - pos1;\n\t\t\t\tint nex2 = pos2; if (pos1 == 1) { nex2 = rx * W + ry; }\n\t\t\t\tint nex3 = pos3; if (pos1 == 0) { nex3 = rx * W + ry; }\n\t\t\t\tif (Dist[nex1][nex2][nex3] > Dist[pos1][pos2][pos3] + V[rx][ry]) {\n\t\t\t\t\tDist[nex1][nex2][nex3] = Dist[pos1][pos2][pos3] + V[rx][ry];\n\t\t\t\t\tQ.push(make_tuple(Dist[nex1][nex2][nex3], nex1, nex2, nex3));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\t// Step 4. Output\n\t\tint Answer = 1000000;\n\t\tfor (int i = 0; i < H; i++) {\n\t\t\tfor (int j = 0; j < W; j++) {\n\t\t\t\tfor (int k = 0; k < H * W; k++) {\n\t\t\t\t\tif (Goal[i][j] == false) continue;\n\t\t\t\t\tAnswer = min(Answer, Dist[0][i * W + j][k]);\n\t\t\t\t\tAnswer = min(Answer, Dist[1][i * W + j][k]);\n\t\t\t\t\tAnswer = min(Answer, Dist[0][k][i * W + j]);\n\t\t\t\t\tAnswer = min(Answer, Dist[1][k][i * W + j]);\n\t\t\t\t\tif (Answer == 5) {\n\t\t\t\t\t\tAnswer += 0;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (Answer == 1000000) cout << \"-1\" << endl;\n\t\telse cout << Answer << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 42480, "score_of_the_acc": -0.9519, "final_rank": 18 }, { "submission_id": "aoj_1150_8014388", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<math.h>\n#include<iomanip>\n#include<algorithm>\n#include<set>\n#include<map>\n#include<queue>\n#include<stack>\n#include<bitset>\n// #include<atcoder/all>\n\nusing namespace std;\n// using namespace atcoder;\nusing ll = long long;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n\nint dx[] = {-2, -1, -1, 0, 0, 0, 1, 1, 2};\nint dy[] = { 1, 1, 2, 1, 2, 3, 1, 2, 1};\n\nint main(){\n\twhile (true)\n\t{\n\t\tint w, h;\n\t\tcin >> w >> h;\n\t\tif (w == 0 && h == 0) {\n\t\t\tbreak;\n\t\t}\n\t\t\n\t\tvector<vector<vector<int>>> dp(h, vector<vector<int>>(w, vector<int>(2, 1000000000)));\n\t\tpriority_queue<tuple<int, int, int, int>, vector<tuple<int, int, int, int>>, greater<tuple<int, int, int, int>>> q;\n\t\tvector<vector<char>> s;\n\t\tfor (int i = 0; i < h; i++)\n\t\t{\n\t\t\ts.push_back(vector<char>());\n\t\t\tfor (int j = 0; j < w; j++)\n\t\t\t{\n\t\t\t\tchar c;\n\t\t\t\tcin >> c;\n\t\t\t\ts[i].push_back(c);\n\t\t\t\tif (c == 'S') {\n\t\t\t\t\tdp[i][j][0] = 0;\n\t\t\t\t\tdp[i][j][1] = 0;\n\t\t\t\t\tq.push(tuple<int, int, int, int>(0, i, j, 0));\n\t\t\t\t\tq.push(tuple<int, int, int, int>(0, i, j, 1));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint ans = -1;\n\t\twhile (q.size() > 0)\n\t\t{\n\t\t\tauto [cur_dist, cur_x, cur_y, cur_step] = q.top();\n\t\t\tq.pop();\n\t\t\tif (s[cur_x][cur_y] == 'T') {\n\t\t\t\tans = cur_dist;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tfor (int i = 0; i < 9; i++)\n\t\t\t{\n\t\t\t\tint next_x = cur_x + dx[i];\n\t\t\t\tint next_y = cur_y + (cur_step ? dy[i] : -dy[i]);\n\t\t\t\tint next_step = 1 - cur_step;\n\t\t\t\tif (next_x < 0) continue;\n\t\t\t\tif (h <= next_x) continue;\n\t\t\t\tif (next_y < 0) continue;\n\t\t\t\tif (w <= next_y) continue;\n\t\t\t\tif (s[next_x][next_y] == 'X') continue;\n\t\t\t\tif (s[next_x][next_y] == 'S') continue;\n\t\t\t\tif (s[next_x][next_y] == 'T') {\n\t\t\t\t\tif (dp[next_x][next_y][next_step] > cur_dist) {\n\t\t\t\t\t\tq.push(tuple<int, int, int, int>(cur_dist, next_x, next_y, next_step));\n\t\t\t\t\t\tdp[next_x][next_y][next_step] = cur_dist;\n\t\t\t\t\t}\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tint next_dist = cur_dist + s[next_x][next_y] - '0';\n\t\t\t\tif (dp[next_x][next_y][next_step] > next_dist) {\n\t\t\t\t\tq.push(tuple<int, int, int, int>(next_dist, next_x, next_y, next_step));\n\t\t\t\t\tdp[next_x][next_y][next_step] = next_dist;\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\t\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3524, "score_of_the_acc": -0.0113, "final_rank": 6 }, { "submission_id": "aoj_1150_8008298", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\n//---------------------------- テンプレゾーン --------------------------------//\n\nconst long long INF = 1000000010;\nconst long long INFL = 1000000000000000010;\nconst double MYPI = 3.14159265358979;\nconst double epsilon = 1e-10;\n\n\n\ntypedef long long ll;\ntypedef __int128_t lll;\ntypedef unsigned int uint;\ntypedef unsigned long long ull;\ntypedef long double ld;\ntypedef pair<ll, ll> pl;\ntypedef vector<ll> vl;\ntypedef vector<vl> vvl;\ntypedef vector<vvl> vvvl;\ntypedef vector<double> vd;\ntypedef vector<vd> vvd;\ntypedef vector<vvd> vvvd;\ntypedef vector<bool> vb;\ntypedef vector<vb> vvb;\ntypedef vector<vvb> vvvb;\ntypedef vector<char> vc;\ntypedef vector<vc> vvc;\ntypedef vector<vvc> vvvc;\ntypedef vector<pl> vp;\ntypedef tuple<ll, ll, ll> tt;\ntypedef vector<tuple<ll, ll, ll>> vt;\ntypedef vector<string> vs;\n\n#define overload3(a, b, c, d, ...) d\n#define overload4(a, b, c, d, e, ...) e\n#define overload5(a, b, c, d, e, f, ...) f\n#define overload6(a, b, c, d, e, f, g, ...) g\n#define pb push_back\n#define eb emplace_back\n#define MP make_pair\n#define REP_0(n) for(int _=0;_<(n);_++)\n#define REP_1(i, n) for(int i=0;i<(n);i++)\n#define REP_2(i, l, r) for(int i=(l);i<(r);i++)\n#define REP_3(i, l, r, d) for(int i=(l);i<(r);i+=(d))\n#define REP(...) overload4(__VA_ARGS__, REP_3, REP_2, REP_1, REP_0)(__VA_ARGS__)\n#define REPP(i, n) for(int i=1;i<=(n);i++)\n#define RREP_1(i, n) for(int i=(n)-1;i>=0;i--)\n#define RREP_2(i, l, r) for(int i=(r)-1;i>=(l);i--)\n#define RREP_3(i, l, r, d) for(int i=(r)-1;i>=(l);i-=(d))\n#define RREP(...) overload4(__VA_ARGS__, RREP_3, RREP_2, RREP_1)(__VA_ARGS__)\n#define RREPP(i, n) for(int i=(n);i>0;i--)\n#define EACH1(e, a) for(auto &e : a)\n#define EACH2(x, y, a) for(auto &[x, y] : a)\n#define EACH3(x, y, z, a) for(auto &[x, y, z] : a)\n#define EACH(...) overload4(__VA_ARGS__, EACH3, EACH2, EACH1)(__VA_ARGS__)\n#define ALL1(x) begin(x), end(x)\n#define ALL2(x, a) begin(x), begin(x) + a\n#define ALL3(x, a, b) begin(x) + a, begin(x) + b\n#define ALL(...) overload3(__VA_ARGS__, ALL3, ALL2, ALL1)(__VA_ARGS__)\n#define RALL1(i) (i).rbegin(), (i).rend()\n#define RALL2(i, a) (i).rend() - a, (i).rend()\n#define RALL3(i, a, b) (i).rend() - b, (i).rend() - a\n#define RALL(...) overload3(__VA_ARGS__, RALL3, RALL2, RALL1)(__VA_ARGS__)\n#define sz(x) (long long)x.size()\n#define LB(a, x) (lower_bound(a.begin(), a.end(), x) - a.begin())\n#define UB(a, x) (upper_bound(a.begin(), a.end(), x) - a.begin())\n#define FLG(x, i) (((x)>>(i)) & 1)\n#define CNTBIT(x) __builtin_popcountll(x)\n#define TOPBIT(t) (t == 0 ? -1 : 63 - __builtin_clzll(t))\n#define BTMBIT(t) (t == 0 ? 64 : __builtin_ctzll(t))\n#define IN(x, a, b) ((a) <= (x) && (x) < (b))\n#define INT(...) int __VA_ARGS__; input(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define CHAR(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define DBL(...) double __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) long double __VA_ARGS__; input(__VA_ARGS__)\n#define VL1(a, n) vector<long long> a(n); for(int I=0;I<(n);I++)cin >> a[I]\n#define VL2(a, b, n) vector<long long> a(n), b(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I]\n#define VL3(a, b, c, n) vector<long long> a(n), b(n), c(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I]\n#define VL4(a, b, c, d, n) vector<long long> a(n), b(n), c(n), d(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I] >> d[I]\n#define VL5(a, b, c, d, e, n) vector<long long> a(n), b(n), c(n), d(n), e(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I] >> d[I] >> e[I]\n#define VL(...) overload6(__VA_ARGS__, VL5, VL4, VL3, VL2, VL1)(__VA_ARGS__)\n#define VD1(a, n) vector<double> a(n); for(int I=0;I<(n);I++)cin >> a[I]\n#define VD2(a, b, n) vector<double> a(n), b(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I]\n#define VD3(a, b, c, n) vector<double> a(n), b(n), c(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I]\n#define VD4(a, b, c, d, n) vector<double> a(n), b(n), c(n), d(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I] >> d[I]\n#define VD5(a, b, c, d, e, n) vector<double> a(n), b(n), c(n), d(n), e(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I] >> d[I] >> e[I]\n#define VD(...) overload6(__VA_ARGS__, VD5, VD4, VD3, VD2, VD1)(__VA_ARGS__)\n#define VVL(a, n, m) vector<vector<long long> > a(n, vector<long long>(m)); for(int I=0;I<(n);I++)for(int J=0;J<(m);J++)cin >> a[I][J]\n#define VVC(s, n, m) vector<vector<char> > s(n, vector<char>(m)); for(int I=0;I<(n);I++)for(int J=0;J<(m);J++)cin >> s[I][J]\n#define VS(s, n) vector<string> s(n); for(int I=0;I<(n);I++)cin >> s[I];\n\ntemplate <typename T1, typename T2>\nostream &operator<<(ostream &os, const pair<T1, T2> &a){\n return os << a.first << \" \" << a.second;\n}\ntemplate <typename T1, typename T2, typename T3>\nostream &operator<<(ostream &os, const tuple<T1, T2, T3> &a){\n return os << get<0>(a) << \" \" << get<1>(a) << \" \" << get<2>(a);\n}\n\nstruct IoSetup{\n IoSetup() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n cout << fixed << setprecision(15);\n }\n} iosetup;\n\n#ifdef LOCAL\n# include <debug_print.hpp>\n# define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__)\n#else\n# define debug(...) (static_cast<void>(0))\n#endif\n\ntemplate <typename T>\nusing minheap = priority_queue<T, vector<T>, greater<T>>;\n \ntemplate <typename T>\nusing maxheap = priority_queue<T>;\n\ntemplate<class... T>\nvoid input(T&... a){\n (cin >> ... >> a);\n}\n\ntemplate <typename... T>\nconstexpr auto min(T... a){\n return min(initializer_list<common_type_t<T...>>{a...});\n}\ntemplate <typename... T>\nconstexpr auto max(T... a){\n return max(initializer_list<common_type_t<T...>>{a...});\n}\n\ntemplate <typename T1, typename T2>\nbool chmax(T1 &x, const T2 &y){\n return x < y ? x = y, true : false;\n}\ntemplate <typename T1, typename T2>\nbool chmin(T1 &x, const T2 &y){\n return x > y ? x = y, true : false;\n}\n\nvoid OUT(){cout << \"\\n\";}\n\ntemplate <typename T, typename... Ts>\nvoid OUT(const T &a, const Ts&... b){\n cout << a;\n (cout << ... << (cout << \" \", b));\n cout << \"\\n\";\n}\n\ntemplate <typename T>\nvoid OUT(const vector<T> &res){\n for(int i=0;i<(int)res.size();i++){\n cout << res[i] << \" \";\n }\n cout << \"\\n\";\n}\n\ntemplate <typename T>\nvoid OUT_(const T &a){\n cout << a << \" \";\n}\n\ntemplate <typename T>\nvoid OUTN(const vector<T> &res, long long margin = 0){\n for(int i=0;i<(int)res.size();i++){\n cout << res[i] + (T)margin << \"\\n\";\n }\n}\n\ntemplate <typename T>\nvoid OUTN_(const vector<T> &res, long long margin = 0){\n for(int i=0;i<(int)res.size();i++){\n cout << res[i] + (T)margin << \" \";\n }\n cout << \"\\n\";\n}\n\ntemplate <typename T>\nvoid OUTNN(const vector<vector<T>> &res, long long margin = 0){\n for(int i=0;i<(int)res.size();i++){\n for(int j=0;j<(int)res[i].size();j++){\n cout << res[i][j] + (T)margin << \" \";\n }\n cout << \"\\n\";\n }\n}\n\nvoid YES(const bool &res = true, bool Capital = false){\n if(Capital) cout << (res ? \"YES\" : \"NO\") << \"\\n\";\n else cout << (res ? \"Yes\" : \"No\") << \"\\n\";\n}\n\nvoid FIRST(const bool &res = true, bool Capital = false){\n if(Capital) cout << (res ? \"FIRST\" : \"SECOND\") << \"\\n\";\n else cout << (res ? \"First\" : \"Second\") << \"\\n\";\n}\n\ntemplate <typename T>\nvoid DEC(vector<T> &a, long long dif = 1){\n for(auto &x : a)x -= (T)dif;\n}\ntemplate <typename T>\nvoid DEC(vector<T> &a, vector<T> &b, long long dif = 1){\n for(auto &x : a)x -= (T)dif;\n for(auto &x : b)x -= (T)dif;\n}\ntemplate <typename T>\nvoid DEC(vector<vector<T>> &a, long long dif = 1){\n for(auto &v : a)for(auto &x : v)x -= (T)dif;\n}\n\ntemplate <typename T>\nvoid INC(vector<T> &a, long long dif = 1){\n for(auto &x : a)x += (T)dif;\n}\ntemplate <typename T>\nvoid INC(vector<T> &a, vector<T> &b, long long dif = 1){\n for(auto &x : a)x += (T)dif;\n for(auto &x : b)x += (T)dif;\n}\ntemplate <typename T>\nvoid INC(vector<vector<T>> &a, long long dif = 1){\n for(auto &v : a)for(auto &x : v)x += (T)dif;\n}\n\ntemplate <typename T>\nT SUM(const vector<T> &a){\n return accumulate(a.begin(), a.end(), (T)0);\n}\ntemplate <typename T>\nT SUM(const vector<vector<T>> &a){\n T ret = 0;\n for(int i=0;i<(int)a.size();i++)ret += accumulate(a[i].begin(), a[i].end(), (T)0);\n return ret;\n}\n\ntemplate <typename T>\nT MAX(const vector<T> &a){\n return *max_element(a.begin(), a.end());\n}\ntemplate <typename T>\nT MAX(const vector<vector<T>> &a){\n T ret = -INFL;\n for(int i=0;i<(int)a.size();i++)for(int j=0;j<(int)a[i].size();j++)if(ret < a[i][j])ret = a[i][j];\n return ret;\n}\n\ntemplate <typename T>\nint ARGMAX(const vector<T> &a){\n int ret = 0;\n for(int i=1;i<(int)a.size();i++)if(a[ret] < a[i])ret = i;\n return ret;\n}\ntemplate <typename T>\npair<int, int> ARGMAX(const vector<vector<T>> &a){\n pair<int, int> ret = {0, 0};\n for(int i=0;i<(int)a.size();i++)for(int j=0;j<(int)a[i].size();j++)if(a[ret.first][ret.second] < a[i][j])ret = {i, j};\n return ret;\n}\n\ntemplate <typename T>\nT MIN(const vector<T> &a){\n return *min_element(a.begin(), a.end());\n}\ntemplate <typename T>\nT MIN(const vector<vector<T>> &a){\n T ret = INFL;\n for(int i=0;i<(int)a.size();i++)for(int j=0;j<(int)a[i].size();j++)if(ret > a[i][j])ret = a[i][j];\n return ret;\n}\n\ntemplate <typename T>\nint ARGMIN(const vector<T> &a){\n int ret = 0;\n for(int i=1;i<(int)a.size();i++)if(a[ret] > a[i])ret = i;\n return ret;\n}\ntemplate <typename T>\npair<int, int> ARGMIN(const vector<vector<T>> &a){\n pair<int, int> ret = {0, 0};\n for(int i=0;i<(int)a.size();i++)for(int j=0;j<(int)a[i].size();j++)if(a[ret.first][ret.second] > a[i][j])ret = {i, j};\n return ret;\n}\n\ntemplate <typename T>\nint SIGN(const T &a){\n if(abs(a) < epsilon)return 0;\n return a > 0 ? 1 : -1;\n}\n\ntemplate <typename T>\nvector<T> UNIQ(vector<T> a){\n sort(a.begin(), a.end());\n a.erase(unique(a.begin(), a.end()), a.end());\n return a;\n}\n\ntemplate <typename T>\nvector<T> sorted(vector<T> a, bool Descending = false){\n sort(a.begin(), a.end());\n if(Descending)reverse(a.begin(), a.end());\n return a;\n}\n\ntemplate <typename T>\nvector<T> cumsum(const vector<T> &a){\n int n = (int)a.size();\n vector<T> ret(n+1, (T)0);\n for(int i=0;i<n;i++)ret[i+1] = ret[i] + a[i];\n return ret;\n}\ntemplate <typename T>\nvector<vector<T>> cumsum(const vector<vector<T>> &a){\n int n = (int)a.size(), m = (int)a[0].size();\n vector<vector<T>> ret(n+1, vector<T>(m+1, (T)0));\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)ret[i+1][j+1] = ret[i+1][j] + a[i][j];\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)ret[i+1][j+1] += ret[i][j+1];\n return ret;\n}\ntemplate <typename T>\nvector<vector<vector<T>>> cumsum(const vector<vector<vector<T>>> &a){\n int n = (int)a.size(), m = (int)a[0].size(), l = (int)a[0][0].size();\n vector<vector<vector<T>>> ret(n+1, vector<vector<T>>(m+1, vector<T>(l+1, (T)0)));\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)for(int k=0;k<l;k++)ret[i+1][j+1][k+1] = ret[i+1][j+1][k] + a[i][j][k];\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)for(int k=0;k<l;k++)ret[i+1][j+1][k+1] += ret[i][j+1][k+1];\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)for(int k=0;k<l;k++)ret[i+1][j+1][k+1] += ret[i+1][j][k+1];\n return ret;\n}\ntemplate <typename T>\nvoid cumsum_inplace(vector<T> &a){\n int n = (int)a.size();\n for(int i=0;i<n-1;i++)a[i+1] += a[i];\n}\ntemplate <typename T>\nvoid cumsum_inplace(vector<vector<T>> &a){\n int n = (int)a.size(), m = (int)a[0].size();\n for(int i=0;i<n-1;i++)for(int j=0;j<m;j++)a[i+1][j] += a[i][j];\n for(int i=0;i<n;i++)for(int j=0;j<m-1;j++)a[i][j+1] += a[i][j];\n}\ntemplate <typename T>\nvoid cumsum_inplace(vector<vector<vector<T>>> &a){\n int n = (int)a.size(), m = (int)a[0].size(), l = (int)a[0][0].size();\n for(int i=0;i<n-1;i++)for(int j=0;j<m;j++)for(int k=0;k<l;k++)a[i+1][j][k] += a[i][j][k];\n for(int i=0;i<n;i++)for(int j=0;j<m-1;j++)for(int k=0;k<l;k++)a[i][j+1][k] += a[i][j][k];\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)for(int k=0;k<l-1;k++)a[i][j][k+1] += a[i][j][k];\n}\n\ntemplate< typename T = long long >\nstruct Edge {\n long long from, to;\n T cost;\n long long idx;\n Edge() = default;\n Edge(long long from, long long to, T cost = 1, long long idx = -1) : from(from), to(to), cost(cost), idx(idx) {}\n operator int() const { return to; }\n};\n\ntemplate< typename T = long long >\nstruct Graph {\n vector< vector< Edge< T > > > g, ginv;\n vector<int> indeg, outdeg;\n long long es;\n Graph() = default;\n explicit Graph(long long n) : g(n), ginv(n), indeg(n, 0), outdeg(n, 0), es(0) {}\n size_t size() const {\n return g.size();\n }\n void add_directed_edge(long long from, long long to, T cost = 1) {\n indeg[to]++, outdeg[from]++;\n //ginv[to].emplace_back(to, from, cost, es);\n g[from].emplace_back(from, to, cost, es++);\n }\n void add_edge(long long from, long long to, T cost = 1) {\n indeg[from]++, outdeg[from]++, indeg[to]++, outdeg[to]++;\n g[from].emplace_back(from, to, cost, es);\n g[to].emplace_back(to, from, cost, es++);\n }\n inline vector< Edge< T > > &operator[](const int &k) {\n return g[k];\n }\n inline const vector< Edge< T > > &operator[](const int &k) const {\n return g[k];\n }\n};\n\ntemplate< typename T = long long >\nusing Edges = vector< Edge< T > >;\n\ntemplate< typename T >\nstruct Enumeration {\nprivate:\n static vector< T > _fact, _finv, _inv;\n inline static void expand(size_t sz) {\n if(_fact.size() < sz + 1) {\n int pre_sz = max(1, (int) _fact.size());\n _fact.resize(sz + 1, T(1));\n _finv.resize(sz + 1, T(1));\n _inv.resize(sz + 1, T(1));\n for(int i = pre_sz; i <= (int) sz; i++) {\n _fact[i] = _fact[i - 1] * T(i);\n }\n _finv[sz] = T(1) / _fact[sz];\n for(int i = (int) sz - 1; i >= pre_sz; i--) {\n _finv[i] = _finv[i + 1] * T(i + 1);\n }\n for(int i = pre_sz; i <= (int) sz; i++) {\n _inv[i] = _finv[i] * _fact[i - 1];\n }\n }\n }\npublic:\n explicit Enumeration(size_t sz = 0) { expand(sz); }\n static inline T fact(int k) {\n expand(k);\n return _fact[k];\n }\n static inline T finv(int k) {\n expand(k);\n return _finv[k];\n }\n static inline T inv(int k) {\n expand(k);\n return _inv[k];\n }\n static T P(int n, int r) {\n if(r < 0 || n < r) return 0;\n return fact(n) * finv(n - r);\n }\n static T C(int p, int q) {\n if(q < 0 || p < q) return 0;\n return fact(p) * finv(q) * finv(p - q);\n }\n};\n\ntemplate< typename T >\nvector< T > Enumeration< T >::_fact = vector< T >();\ntemplate< typename T >\nvector< T > Enumeration< T >::_finv = vector< T >();\ntemplate< typename T >\nvector< T > Enumeration< T >::_inv = vector< T >();\n\ntemplate <typename T>\nT norm1(const pair<T, T> &a, const pair<T, T> &b = {(T)0, (T)0}){\n return abs(a.first - b.first) + abs(a.second - b.second);\n}\ntemplate <typename T>\nT norm22(const pair<T, T> &a, const pair<T, T> &b = {(T)0, (T)0}){\n return (a.first - b.first) * (a.first - b.first) + (a.second - b.second) * (a.second - b.second);\n}\ntemplate <typename T>\ndouble norm2(const pair<T, T> &a, const pair<T, T> &b = {(T)0, (T)0}){\n return sqrt(norm22(a, b));\n}\n\nlong long powll(long long a, long long n){\n assert(n >= 0);\n if(n == 0)return 1;\n long long ret = 1;\n while(n){\n if(n & 1)ret *= a;\n a *= a;\n n >>= 1;\n }\n return ret;\n}\n\nvector<long long> str_to_vl(const string &s){\n vector<long long> ret(s.size());\n if(s.size() == 0)return ret;\n if(0 <= s[0]-'A' && s[0]-'A' < 26) for(int i=0;i<(int)s.size();i++) ret[i] = s[i] - 'A';\n else if(0 <= s[0]-'a' && s[0]-'a' < 26) for(int i=0;i<(int)s.size();i++) ret[i] = s[i] - 'a';\n else if(0 <= s[0]-'0' && s[0]-'0' < 10) for(int i=0;i<(int)s.size();i++) ret[i] = s[i] - '0';\n else assert(0);\n return ret;\n}\n\n// 0-indexed\nlong long TOPDIGIT(long long x){\n assert(x >= 0);\n long long ret = 0;\n while(x >= 10){x /= 10; ret++;}\n return ret;\n}\n\ntemplate <typename T>\nvector<pair<T, int>> sorti(const vector<T> &a){\n vector<pair<T, int>> ret(a.size());\n for(int i=0;i<(int)a.size();i++){\n ret[i] = {a[i], i};\n }\n sort(ret.begin(), ret.end());\n return ret;\n}\ntemplate <typename T1, typename T2>\nvector<tuple<T1, T2, int>> sorti(const vector<T1> &a, const vector<T2> &b){\n assert(a.size() == b.size());\n vector<tuple<T1, T2, int>> ret(a.size());\n for(int i=0;i<(int)a.size();i++){\n ret[i] = {a[i], b[i], i};\n }\n sort(ret.begin(), ret.end());\n return ret;\n}\ntemplate <typename T1, typename T2, typename T3>\nvector<tuple<T1, T2, T3, int>> sorti(const vector<T1> &a, const vector<T2> &b, const vector<T3> &c){\n assert(a.size() == b.size() && a.size() == c.size());\n vector<tuple<T1, T2, T3, int>> ret(a.size());\n for(int i=0;i<(int)a.size();i++){\n ret[i] = {a[i], b[i], c[i], i};\n }\n sort(ret.begin(), ret.end());\n return ret;\n}\n\n// 高々小数第 k 位までの実数を 10^k 倍して整数化\nll decimal_to_ll(const string &s, int k){\n int n = s.size();\n for(int i=0;i<n;i++){\n if(s[i] == '.'){\n ll ret = stoll(s.substr(0, i) + s.substr(i + 1));\n for(int j=0;j<k-(n-1-i);j++)ret *= 10;\n return ret;\n }\n }\n ll ret = stoll(s);\n for(int i=0;i<k;i++)ret *= 10;\n return ret;\n}\n\nlong long max(const int &a, const long long &b){return max((long long)a, b);}\nlong long min(const int &a, const long long &b){return min((long long)a, b);}\n\nconst vector<long long> dy = {1, 0, -1, 0, 1, -1, -1, 1};\nconst vector<long long> dx = {0, 1, 0, -1, 1, 1, -1, -1};\n\nrandom_device seed_gen;\nmt19937_64 rnd;\n\n// [low, high] の範囲の値を持つ長さ len のランダムベクトルを生成\nvector<long long> random_vl(int len, long long low, long long high){\n uniform_int_distribution<long long> dist(low, high);\n vector<long long> ret(len);\n for(int i=0;i<len;i++)ret[i] = dist(rnd);\n return ret;\n};\n\nvector<long long> random_permutation(int len){\n uniform_int_distribution<int> dist(1, len);\n vector<long long> ret(len);\n set<int> se;\n for(int i=0;i<len;i++){\n int tmp = dist(rnd);\n while(se.count(tmp))tmp = dist(rnd);\n ret[i] = tmp;\n se.insert(ret[i]);\n }\n return ret;\n};\n\n//--------------------------- テンプレゾーン終 -------------------------------//\n\n//----------------------------- コピペゾーン ---------------------------------//\n\n/*\n始点s 最短距離dist ひとつ前の頂点prev\n最短経路を求めるときはコメントアウトを外してprevをいれる\n計算量 O(|E|log|V|)\n*/\n\ntemplate<typename T>\nvector<T> Dijkstra(const Graph<T> &g, long long s /*, vl &prev*/){\n long long n = g.size();\n vector<T> dist(n, INFL);\n dist[s] = 0;\n priority_queue<pair<T, long long>, vector<pair<T, long long>>, greater<pair<T, long long>>> pq;\n pq.emplace(0, s);\n while(!pq.empty()){\n auto [d, v] = pq.top();\n pq.pop();\n if(dist[v] >= d){\n for(auto &e : g[v]){\n if(e.cost < 0)continue;\n if(dist[e.to] > dist[v] + e.cost){\n dist[e.to] = dist[v] + e.cost;\n pq.emplace(dist[e.to], e.to);\n //prev[e.to] = v;\n }\n }\n }\n }\n return dist;\n}\n\n//---------------------------- コピペゾーン終 --------------------------------//\n\n#define int long long\n\nvoid solve(){\n vl ans;\n while(1){\n INT(w, h);\n if(w == 0)break;\n VVC(c, h, w);\n vl s, t;\n REP(i, h)REP(j, w){\n if(c[i][j] == 'S')s.pb(j);\n if(c[i][j] == 'T')t.pb(j);\n }\n Graph g(h*w*2);\n REP(i, h)REP(j, w)REP(k, h)REP(l, w){\n if(c[i][j] == 'X' || c[k][l] == 'X')continue;\n ll cost = c[k][l] - '0';\n if(j < l && abs(i - k) + abs(j - l) <= 3){\n if(!IN(cost, 1, 10))cost = 0;\n g.add_directed_edge(i*w+j, k*w+l + h*w, cost);\n }\n if(j > l && abs(i - k) + abs(j - l) <= 3){\n if(!IN(cost, 1, 10))cost = 0;\n g.add_directed_edge(i*w+j + h*w, k*w+l, cost);\n }\n }\n ll res = INFL;\n EACH(v, s){\n auto dist = Dijkstra(g, (h-1) * w + v);\n EACH(u, t){\n chmin(res, dist[u]);\n chmin(res, dist[h*w + u]);\n }\n dist = Dijkstra(g, h*w + (h-1) * w + v);\n EACH(u, t){\n chmin(res, dist[u]);\n chmin(res, dist[h*w + u]);\n }\n }\n ans.pb(res == INFL ? -1 : res);\n }\n OUTN(ans);\n}\n\nint solve_test(int n, vl a){\n\n return 0;\n}\n\nint solve_naive(int n, vl a){\n\n return 0;\n}\n\nvoid random_test(){\n rnd.seed(seed_gen());\n\n uniform_int_distribution<int> dist_n(4, 10), dist_m(4, 10), dist_a(1, 20), dist_b(1, 20); \n\n for(int test = 1; test <= 100; test++){\n int n = dist_n(rnd), m = dist_m(rnd);\n vl a = random_vl(n, 3, 20);\n auto Output = solve_test(n, a), Answer = solve_naive(n, a);\n if(Output != Answer){\n cout << \"Wrong Answer on Test #\" << test << '\\n';\n debug(n);\n debug(a);\n debug(Answer);\n debug(Output);\n break;\n }\n }\n}\n\nsigned main(){\n int T = 1;\n // cin >> T;\n\n while(T--) solve();\n\n // random_test();\n\n return 0;\n}", "accuracy": 1, "time_ms": 500, "memory_kb": 4772, "score_of_the_acc": -0.2371, "final_rank": 16 }, { "submission_id": "aoj_1150_8004920", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst pair<int,int>V[]={{2,1},{1,1},{1,2},{0,1},{0,2},{0,3},{-1,1},{-1,2},{-2,1}};\nconst int inf=1<<30;\n\nbool solve(){\n int W,H;\n cin>>W>>H;\n if(W==0)return false;\n vector S(H,vector<char>(W));\n vector D(H,vector(W,vector<int>(2,inf)));\n priority_queue<tuple<int,int,int,int>,vector<tuple<int,int,int,int>>,greater<tuple<int,int,int,int>>>pq;\n vector<pair<int,int>>goal;\n for(int i=0;i<H;i++){\n for(int j=0;j<W;j++){\n cin>>S[i][j];\n if(S[i][j]=='S'){\n D[i][j][0]=0;\n D[i][j][1]=0;\n pq.push(make_tuple(0,i,j,0));\n pq.push(make_tuple(0,i,j,1));\n }else if(S[i][j]=='T'){\n goal.push_back(make_pair(i,j));\n }\n }\n }\n while(pq.size()){\n auto[c,x,y,t]=pq.top();\n pq.pop();\n if(D[x][y][t]<c)continue;\n for(auto[dx,dy]:V){\n if(t==1)dy=-dy;\n int ex=x+dx,ey=y+dy;\n if(0<=ex&&ex<H&&0<=ey&&ey<W&&S[ex][ey]!='X'){\n if(S[ex][ey]=='T'&&D[ex][ey][1-t]>c){\n D[ex][ey][1-t]=c;\n pq.push(make_tuple(D[ex][ey][1-t],ex,ey,1-t));\n }\n if('0'<=S[ex][ey]&&S[ex][ey]<='9'&&D[ex][ey][1-t]>c+S[ex][ey]-'0'){\n D[ex][ey][1-t]=c+S[ex][ey]-'0';\n pq.push(make_tuple(D[ex][ey][1-t],ex,ey,1-t));\n }\n }\n }\n }\n int ans=inf;\n for(auto[gx,gy]:goal){\n ans=min(ans,D[gx][gy][0]);\n ans=min(ans,D[gx][gy][1]);\n }\n if(ans==inf)cout<<-1<<\"\\n\";\n else cout<<ans<<\"\\n\";\n return true;\n}\n\nint main(){\n while(1){\n if(!solve()){\n return 0;\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3512, "score_of_the_acc": -0.0111, "final_rank": 5 }, { "submission_id": "aoj_1150_7989590", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\n#include<queue>\n\nusing namespace std;\nusing ll = long long;\nusing dat = pair<ll,pair<pair<int,int>,int>>;\nint w,h;\nvoid solve(){\n vector<vector<char>> a(h,vector<char>(w));\n for(int i = 0;i<h;i++) for(int j = 0;j<w;j++) cin>>a[i][j];\n vector<vector<vector<ll>>> dp(2,vector<vector<ll>>(h,vector<ll>(w,1e9)));\n priority_queue<dat,vector<dat>,greater<dat>> que;\n for(int i = 0;i<h;i++) for(int j = 0;j<w;j++){\n if(a[i][j]=='S') {\n dp[0][i][j] = dp[1][i][j] = 0;\n que.push(make_pair(0,make_pair(make_pair(i,j),0)));\n que.push(make_pair(0,make_pair(make_pair(i,j),1)));\n }\n }\n while(que.size()){\n auto now = que.top();\n que.pop();\n int ni = now.second.first.first;\n int nj = now.second.first.second;\n int t = now.second.second;\n if(dp[t][ni][nj]<now.first) continue;\n for(int i = 1;i<=3;i++){\n for(int j = -3;j<=3;j++){\n if(abs(i)+abs(j)>3) continue;\n int nni = ni + j;\n int nnj = nj;\n if(t==0) nnj += i;\n else nnj -= i;\n if(nni<0||nni>=h||nnj<0||nnj>=w) continue;\n if(a[nni][nnj]=='X') continue;\n int nxt = now.first;\n if('0'<=a[nni][nnj]&&a[nni][nnj]<='9') nxt += a[nni][nnj] - '0';\n int nt = t ^ 1;\n if(dp[nt][nni][nnj]>nxt){\n que.push(make_pair(nxt,make_pair(make_pair(nni,nnj),nt)));\n dp[nt][nni][nnj] = nxt;\n }\n }\n }\n }\n ll ans = 1e9;\n for(int i = 0;i<h;i++) for(int j = 0;j<w;j++) if(a[i][j]=='T') ans = min(ans,min(dp[0][i][j],dp[1][i][j]));\n if(ans==1e9) ans = -1;\n cout<<ans<<endl;\n \n\n \n}\n\nint main(){\n \n while(true){\n cin>>w>>h;\n if(w==0) break;\n solve();\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3564, "score_of_the_acc": -0.0122, "final_rank": 9 } ]
aoj_1148_cpp
Problem B: Analyzing Login/Logout Records You have a computer literacy course in your university. In the computer system, the login/logout records of all PCs in a day are stored in a file. Although students may use two or more PCs at a time, no one can log in to a PC which has been logged in by someone who has not logged out of that PC yet. You are asked to write a program that calculates the total time of a student that he/she used at least one PC in a given time period (probably in a laboratory class) based on the records in the file. The following are example login/logout records. The student 1 logged in to the PC 1 at 12:55 The student 2 logged in to the PC 4 at 13:00 The student 1 logged in to the PC 2 at 13:10 The student 1 logged out of the PC 2 at 13:20 The student 1 logged in to the PC 3 at 13:30 The student 1 logged out of the PC 1 at 13:40 The student 1 logged out of the PC 3 at 13:45 The student 1 logged in to the PC 1 at 14:20 The student 2 logged out of the PC 4 at 14:30 The student 1 logged out of the PC 1 at 14:40 For a query such as "Give usage of the student 1 between 13:00 and 14:30", your program should answer "55 minutes", that is, the sum of 45 minutes from 13:00 to 13:45 and 10 minutes from 14:20 to 14:30, as depicted in the following figure. Input The input is a sequence of a number of datasets. The end of the input is indicated by a line containing two zeros separated by a space. The number of datasets never exceeds 10. Each dataset is formatted as follows. N M r record 1 ... record r q query 1 ... query q The numbers N and M in the first line are the numbers of PCs and the students, respectively. r is the number of records. q is the number of queries. These four are integers satisfying the following. 1 ≤ N ≤ 1000, 1 ≤ M ≤ 10000, 2 ≤ r ≤ 1000, 1 ≤ q ≤ 50 Each record consists of four integers, delimited by a space, as follows. t n m s s is 0 or 1. If s is 1, this line means that the student m logged in to the PC n at time t . If s is 0, it means that the student m logged out of the PC n at time t . The time is expressed as elapsed minutes from 0:00 of the day. t , n and m satisfy the following. 540 ≤ t ≤ 1260, 1 ≤ n ≤ N , 1 ≤ m ≤ M You may assume the following about the records. Records are stored in ascending order of time t. No two records for the same PC has the same time t. No PCs are being logged in before the time of the first record nor after that of the last record in the file. Login and logout records for one PC appear alternatingly, and each of the login-logout record pairs is for the same student. Each query consists of three integers delimited by a space, as follows. t s t e m It represents "Usage of the student m between t s and t e ". t s , t e and m satisfy the following. 540 ≤ t s < t e ≤ 1260, 1 ≤ m ≤ M Output For each query, print a line having a decimal integer indicating the time of usage in minutes. Output lines should not have any character other than this number. Sample Input 4 2 10 775 1 1 1 7 ...(truncated)
[ { "submission_id": "aoj_1148_10848565", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\nint main(){\n\tint N,M;\n\tint r;\n\twhile( cin >> N >> M && N ){\n\t\tcin >> r;\n\t\tvector<int> imos[M];\n\t\tfor(int i = 0 ; i < M ; i++) imos[i].resize(60*24+1);\n\t\tfor(int i = 0 ; i < r ; i++){\n\t\t\tint t,n,m,s;\n\t\t\tcin >> t >> n >> m >> s;\n\t\t\t--m;\n\t\t\timos[m][t+1] += (s==1?1:-1);\n\t\t}\n\t\tfor(int i = 0 ; i < M ; i++)\n\t\t\tfor(int j = 1 ; j <= 24 * 60 ; j++)\n\t\t\t\timos[i][j] += imos[i][j-1];\n\t\tfor(int i = 0 ; i < M ; i++)\n\t\t\tfor(int j = 0 ; j <= 24 * 60 ; j++){\n\t\t\t\timos[i][j] = imos[i][j] > 0;\n\t\t\t}\n\t\tfor(int i = 0 ; i < M ; i++)\n\t\t\tfor(int j = 1 ; j <= 24 * 60 ; j++)\n\t\t\t\timos[i][j] += imos[i][j-1];\n\t\tint q;\n\t\tcin >> q;\n\t\tfor(int i = 0 ; i < q ; i++){\n\t\t\tint a,b,c;\n\t\t\tcin >> a >> b >> c;\n\t\t\t--c;\n\t\t\t//cout << imos[0][24*60] << endl;\n\t\t\t\n\t\t\tcout << imos[c][b] - imos[c][a] << endl;\n\t\t}\n\t\t\n\t}\n}", "accuracy": 1, "time_ms": 610, "memory_kb": 57848, "score_of_the_acc": -1.4691, "final_rank": 17 }, { "submission_id": "aoj_1148_10727197", "code_snippet": "#include <bits/stdc++.h>\n\n#define all(v) (v).begin(), (v).end()\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> Pair;\ntypedef complex<double> Complex;\n\nconst double PI = M_PI;\nconst int INF = 1e9;\n\nint t[10001][1261];\n\nint main() {\n int n, m, tt, nn , mm, ss;\n int r;\n while(cin >> n >> m) {\n if(n == 0) break;\n cin >> r;\n memset(t, 0, sizeof t);\n\n for(int i = 0; i < r; i++) {\n cin >> tt >> nn >> mm >> ss;\n mm--;\n if(ss) {\n t[mm][tt] += 1;\n } else {\n t[mm][tt] += -1;\n }\n }\n\n for(int i = 0; i < m; i++) {\n for(int j = 0; j <= 1261; j++) {\n t[i][j] += t[i][j-1];\n }\n }\n\n cin >> r;\n for(int i = 0; i < r; i++) {\n cin >> tt >> nn >> mm;\n mm--;\n int ans = 0;\n for(int j = tt; j < nn; j++) {\n ans += bool(t[mm][j]);\n }\n cout << ans << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 52580, "score_of_the_acc": -0.7273, "final_rank": 6 }, { "submission_id": "aoj_1148_10727188", "code_snippet": "#include <bits/stdc++.h>\n\n#define all(v) (v).begin(), (v).end()\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> Pair;\ntypedef complex<double> Complex;\n\nconst double PI = M_PI;\nconst int INF = 1e9;\n\nint t[10001][1261];\n\nint main() {\n int n, m, tt, nn , mm, ss;\n int r;\n while(cin >> n >> m) {\n if(n == 0) break;\n cin >> r;\n memset(t, 0, sizeof t);\n\n for(int i = 0; i < r; i++) {\n cin >> tt >> nn >> mm >> ss;\n mm--;\n if(ss) {\n t[mm][tt] += 1;\n } else {\n t[mm][tt] += -1;\n }\n }\n\n for(int i = 0; i < m; i++) {\n for(int j = 0; j <= 1261; j++) {\n t[i][j] += t[i][j-1];\n// cout << t[i][j];\n }\n// cout << endl;\n }\n\n cin >> r;\n for(int i = 0; i < r; i++) {\n cin >> tt >> nn >> mm;\n mm--;\n int ans = 0;\n for(int j = tt; j < nn; j++) {\n ans += bool(t[mm][j]);\n }\n cout << ans << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 52608, "score_of_the_acc": -0.7276, "final_rank": 7 }, { "submission_id": "aoj_1148_9684820", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\nint main(){\n while(1){\n ll N,M;cin>>N>>M;\n if(!N)return 0;\n ll r;cin>>r;\n vector<vector<int>>A(M,vector<int>(2000));\n while(r--){\n ll t,n,m,s;cin>>t>>n>>m>>s;m--;\n if(s)A[m][t]++;\n else A[m][t]--;\n }\n REP(i,M)REP(j,1999)A[i][j+1]+=A[i][j];\n REP(i,M)REP(j,2000)A[i][j]=min(1,A[i][j]);\n REP(i,M)REP(j,1999)A[i][j+1]+=A[i][j];\n ll Q;cin>>Q;\n while(Q--){\n ll s,e,i;cin>>s>>e>>i;i--;\n cout<<A[i][e-1]-A[i][s-1]<<endl;\n }\n }\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 79116, "score_of_the_acc": -1.407, "final_rank": 16 }, { "submission_id": "aoj_1148_9458502", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint main() {\nwhile(1) {\n int N, M;\n cin >> N >> M;\n if (N == 0 && M == 0) return 0;\n int MAXS = 721;\n vector<vector<int>> V(M,vector<int>(MAXS,0));\n int R;\n cin >> R;\n rep(i,0,R) {\n int t,n,m,s;\n cin >> t >> n >> m >> s;\n t-=540;\n m--;\n if (s == 1) V[m][t]++;\n else V[m][t]--;\n }\n rep(i,0,M) {\n rep(j,0,720) V[i][j+1] += V[i][j];\n }\n int Q;\n cin >> Q;\n rep(i,0,Q) {\n int s, t, m;\n cin >> s >> t >> m;\n m--;\n s-=540,t-=540;\n int ANS = 0;\n rep(j,s,t) {\n if (V[m][j]>0) ANS++;\n }\n cout << ANS << endl;\n }\n}\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 30816, "score_of_the_acc": -0.3623, "final_rank": 4 }, { "submission_id": "aoj_1148_9394868", "code_snippet": "#include <iostream>\n#include <utility>\n#include <map>\n#include <vector>\n \nusing namespace std;\n \n#define rep(i, n) REP(i, 0, n)\n#define REP(i, a, n) for(int i = a ; i < (int)n ; i++)\n#define pb push_back\n \ntypedef pair<int, int> P;\n \nsigned main(){\n int N,M;\n int r, q;\n cin.tie(0);\n ios::sync_with_stdio(false);\n \n while(cin >> N >> M, N || M){\n cin >> r;\n int t, n, m, s;\n map<P, vector<P> > data;\n\n rep(i, r){\n cin >> t >> n >> m >> s; \n data[P(n,m)].pb(P(t, s));\n }\n cin >> q;\n rep(i, q){\n int ts, te, qm;\n cin >> ts >> te >> qm;\n bool flag[1261]; \n fill(flag, flag+1260, false);\n \n REP(j, 1, N+1){\n for(int k = 0 ; k < (int)data[P(j, qm)].size() ; k+=2){\n int start = max(data[P(j, qm)][k].first, ts);\n int end = min(data[P(j, qm)][k+1].first, te);\n REP(l, start, end+1){\n flag[l] = true;\n }\n }\n }\n \n int ans = 0;\n REP(j, ts, te){\n if(flag[j]){\n int start = j;\n while(flag[j]) j++; \n ans+=(j-start-1);\n }\n }\n \n cout << ans << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4760, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1148_9394703", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n\nint main()\n{\n std::cin.tie(0)->sync_with_stdio(0);\n while(true){\n int n,m;\n cin >> n >> m;\n if(n==0 and m==0)break;\n int r;\n cin >> r;\n // touch[i][j]:= 学生iが時間jにログインしてるパソコンの数\n vector<vector<int>> touch(m+1,vector<int>(2000,0));\n for(int i=0;i<r;i++){\n int t,pcn,who,s;\n cin >> t >> pcn >> who >> s;\n if(s==0){\n touch[who][t+1]--;\n }else{\n touch[who][t+1]++;\n }\n }\n for(int i=0;i<=m;i++){\n for(int j=1;j<2000;j++){\n touch[i][j]=touch[i][j-1]+touch[i][j];\n if(touch[i][j-1]>0)touch[i][j-1]=1;\n }\n }\n for(int i=1;i<=m;i++){\n for(int j=1;j<2000;j++){\n touch[i][j]=touch[i][j-1]+touch[i][j];\n //cout << i << \" \" << j << endl;\n //cout << touch[i][j] << endl;\n }\n }\n int q;\n cin >> q;\n for(int i=0;i<q;i++){\n int s,e,who;\n cin >> s >> e >> who;\n cout << touch[who][e]-touch[who][s] << endl;\n }\n\n }\n}", "accuracy": 1, "time_ms": 660, "memory_kb": 79176, "score_of_the_acc": -1.767, "final_rank": 20 }, { "submission_id": "aoj_1148_9394655", "code_snippet": "#include <bits/stdc++.h>\n\n//使用したライブラリ\n//https://github.com/atcoder/ac-library/tree/fe9b6fca9ab4e1be946ea23a4e6a2a751cf4aaa2\n//https://github.com/ei1333/library/tree/7da7fca8cebc1d17a048c9483f07e39c8e465cdf\n//https://github.com/zawa-tin/cp-documentation/tree/3842eb973aace809be0bcf1649e2fe85e99098e3\n//https://github.com/luckylat/library/tree/8e2a2a6a58bef4644c9442998a1c9c1890672cd3\n\n\nconst int TIME{1261};\n\nbool solve() {\n int N, M;\n std::cin >> N >> M;\n if (N == 0 and M == 0) return false;\n int R;\n std::cin >> R;\n std::vector<std::vector<std::tuple<int, int, int>>> input(M);\n for (int i{} ; i < R ; i++) {\n int t, n, m, s;\n std::cin >> t >> n >> m >> s;\n m--; n--;\n input[m].emplace_back(t, n, s);\n }\n std::vector<std::array<bool, TIME>> range(M);\n for (int i{} ; i < M ; i++) {\n std::vector<std::pair<int, int>> cur;\n std::vector<int> left(N, -1);\n for (auto [t, n, s] : input[i]) {\n if (s == 1) { // login\n assert(left[n] == -1);\n left[n] = t;\n }\n else { // logout\n assert(left[n] != -1);\n cur.emplace_back(left[n], t);\n left[n] = -1;\n }\n }\n range[i].fill(false);\n for (auto [L, R] : cur) {\n for (int j{L} ; j < R ; j++) {\n range[i][j] = true;\n }\n }\n }\n int Q;\n std::cin >> Q;\n while (Q--) {\n int ts, te, m;\n std::cin >> ts >> te >> m;\n m--;\n int ans{};\n for (int i{ts} ; i < te ; i++) {\n ans += range[m][i];\n }\n std::cout << ans << '\\n';\n }\n return true;\n}\n\nint main() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n\n while (solve()) ;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 22672, "score_of_the_acc": -0.2471, "final_rank": 3 }, { "submission_id": "aoj_1148_9394586", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (n); i++)\nusing ll = long long;\n#define all(x) x.begin(), x.end()\ntemplate <class A, class B>\ninline bool chmin(A &a, const B &b) {\n return b < a && (a = b, true);\n}\ntemplate <class A, class B>\ninline bool chmax(A &a, const B &b) {\n return b > a && (a = b, true);\n}\n\nint solve() {\n int n, m;\n cin >> n >> m;\n if (n == 0) return 1;\n const int N = 1300;\n vector a(m, vector<int>(N));\n int r;\n cin >> r;\n rep(i, r) {\n int t, x, y, s;\n cin >> t >> x >> y >> s;\n y--;\n if (s == 0) {\n a[y][t]--;\n } else {\n a[y][t]++;\n }\n }\n rep(i, m) {\n rep(j, N - 1) {\n a[i][j + 1] += a[i][j];\n }\n }\n int q;\n cin >> q;\n while (q--) {\n int s, t, i;\n cin >> s >> t >> i;\n i--;\n int ans = 0;\n for (int j = s; j < t; j++) ans += (a[i][j] > 0);\n cout << ans << endl;\n }\n return 0;\n}\n\nint main() {\n while (!solve());\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 52704, "score_of_the_acc": -0.7598, "final_rank": 10 }, { "submission_id": "aoj_1148_9334540", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<long long>;\nusing vs = vector<string>;\nusing vc = vector<char>;\nusing vb = vector<bool>;\nusing vpii = vector<pair<int, int>>;\nusing vpll = vector<pair<long long, long long>>;\nusing vvi = vector<vector<int>>;\nusing vvl = vector<vector<long long>>;\nusing vvc = vector<vector<char>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing pii = pair<int, int>;\nusing vvb = vector<vector<bool>>;\nusing Graph = vector<vector<ll>>;\nconst ll LINF = 1001002003004005006ll;\nconst int INF = 1001001001;\nconst int MOD = 998422353;\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep3(i, m, n) for (int i = (m); i < (int)(n); i++)\n#define rrep(i, m, n) for (int i = (m); i >= (int)(n); i--)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\nvi dx4 = {1, 0, -1, 0}, dy4 = {0, 1, 0, -1};\nvi dx8 = {1, 1, 1, 0, 0, -1, -1, -1}, dy8 = {1, 0, -1, 1, -1, 1, 0, -1};\n\nint main()\n{\n while (1)\n {\n // 宣言・入力の受け取り\n int n, m;\n cin >> n >> m;\n // 終了条件\n if (n == 0 && m == 0)\n {\n break;\n }\n // 宣言・入力の受け取り\n vvb use(1440, vb(m, false));\n int r;\n cin >> r;\n vi t(r), N(r), M(r), s(r);\n rep(i, r)\n {\n cin >> t[i] >> N[i] >> M[i] >> s[i];\n N[i]--, M[i]--;\n }\n vi online(m, 0);\n rep3(i, 540, 1265)\n {\n rep(j, r)\n {\n if (i == t[j])\n {\n if (s[j] == 1)\n {\n online[M[j]]++;\n }\n else if (s[j] == 0)\n {\n online[M[j]]--;\n }\n }\n }\n rep(k, m)\n {\n if (online[k] > 0)\n {\n use[i][k] = true;\n }\n }\n }\n // solve\n int q;\n cin >> q;\n rep(i, q)\n {\n int t_s, t_e, x;\n cin >> t_s >> t_e >> x;\n x--;\n int ans = 0;\n rep3(j, t_s, t_e)\n {\n if (use[j][x])\n {\n ans++;\n }\n }\n cout << ans << '\\n';\n }\n // 出力\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4924, "score_of_the_acc": -0.0173, "final_rank": 2 }, { "submission_id": "aoj_1148_8029349", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\n#define SHOW(n) cerr << #n << \":\" << n << endl;\n\n\nofstream fout(\"out.txt\");\n\nvoid solve() {\n\tint pcs, stu;\n\tcin >> pcs >> stu;\n\tif (pcs == 0 and stu == 0) {\n\t\texit(0);\n\t}\n\tvector<vector<int>> time(stu, vector<int>(1300));\n\n\tint r;\n\tcin >> r;\n\twhile (r--) {\n\t\tint t, n, m, s;\n\t\tcin >> t >> n >> m >> s;\n\t\ttime[m - 1][t] += (s == 1 ? 1 : -1);\n\t}\n\n\tfor (auto& v : time) {\n\t\tfor (int i = 540; i < 1300; ++i) {\n\t\t\tv[i] += v[i - 1];\n\t\t}\n\t}\n\n\tint q;\n\tcin >> q;\n\t\n\twhile (q--) {\n\t\tint s, t, m;\n\t\tcin >> s >> t >> m;\n\t\t--m;\n\t\tint res = 0;\n\t\tfor (int i = s; i < t; ++i) {\n\t\t\tif (time[m][i] > 0) {\n\t\t\t\tres += 1;\n\t\t\t}\n\t\t}\n\t\tcout << res << endl;\n\t\tfout << res << endl;\n\t}\n\t\n}\n\nint main() {\n\n\t\n\t\n\twhile (true) {\n\t\tsolve();\n\t}\n\n\t\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 52572, "score_of_the_acc": -0.7897, "final_rank": 11 }, { "submission_id": "aoj_1148_8006408", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main () {\n while (1) {\n int n, m;\n cin >> n >> m;\n \n if(n == 0 and m == 0) break;\n \n vector<vector<int>> v(m+1, vector<int>(1300));\n \n int r;\n cin >> r;\n for (int i = 0; i < r; i++) {\n int a, b, c, d;\n cin >> a >> b >> c >> d;\n \n if (d == 0) v[c][a]--;\n else if (d == 1) v[c][a]++;\n }\n \n for (int i = 0; i < m+1; i++) {\n for (int j = 1; j < 1300; j++) \n v[i][j] += v[i][j-1];\n }\n \n int q;\n cin >> q;\n for (int i = 0; i < q; i++) {\n int x, y, z;\n cin >> x >> y >> z;\n \n int ans = 0;\n for (int j = x; j < y; j++) {\n if (v[z][j] != 0) ans++;\n }\n cout << ans << endl;\n }\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 52760, "score_of_the_acc": -0.8854, "final_rank": 13 }, { "submission_id": "aoj_1148_7999146", "code_snippet": "#include <bits/stdc++.h>\n#define LL_INF 9223372036854775807\n#define INT_INF 2147483647\nusing namespace std;\nusing ll = long long;\n\nint main()\n{\n\tint n,m;\n\twhile(cin >> n >> m,n){\n\t\tvector<vector<pair<int,int>>> v(m+1,vector<pair<int,int>>(1300,{0,0}));\n\t\tint r;\n\t\tcin >> r;\n\t\tfor(int i=0;i<r;i++){\n\t\t\tint t,l,m,s;\n\t\t\tcin >> t >> l >> m >> s;\n\t\t\tif(s==0)v[m][t+1].first--;\n\t\t\tif(s==1)v[m][t+1].first++;\n\t\t}\n\t\t//累積和とって加算して質問出力\n\t\tfor(int i=0;i<m+1;i++){\n\t\t\tfor(int j=0;j<1299;j++){\n\t\t\t\tv[i][j+1].first+=v[i][j].first;\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<m+1;i++){\n\t\t\tfor(int j=0;j<1299;j++){\n\t\t\t\tv[i][j+1].second=v[i][j].second;\n\t\t\t\tif(v[i][j+1].first!=0) v[i][j+1].second++;\n\t\t\t\t\n\t\t\t}\n\t\t}\n\n\t\tint q;\n\t\tcin >> q;\n\t\tfor(int i=0;i<q;i++){\n\t\t\tint ts,te,m;\n\t\t\tcin >> ts >> te >> m;\n\t\t\tcout << v[m][te].second-v[m][ts].second << endl;\n\t\t}\n\t}\t\n}", "accuracy": 1, "time_ms": 490, "memory_kb": 101780, "score_of_the_acc": -1.7344, "final_rank": 19 }, { "submission_id": "aoj_1148_7980041", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,n) for(long long i = 0;i < (long long)(n);i++)\n\nint main(){\n ll siz = 780;\n while(true){\n ll N,M;cin >> N >> M;\n if(N == 0 && M == 0){\n break;\n }\n ll r;cin >> r;\n vector<vector<ll>> time(M,vector<ll>(siz));//M人\n rep(z,r){\n ll t,n,m,s;cin >> t >> n >> m >> s;\n t-=500;\n m--;\n if(s == 0){\n time[m][t+1]--;\n }else{\n time[m][t+1]++;\n }\n }\n\n //imos\n rep(i,M){\n rep(j,siz-1){\n time[i][j+1]+= time[i][j];\n }\n }\n //debug\n // rep(i,M){\n // cout << time[i][1999] << endl;\n // }\n\n //ruiseki\n rep(i,M){\n rep(j,siz-1){\n if(time[i][j+1] != 0){\n time[i][j+1] = time[i][j] + 1;\n }else{\n time[i][j+1] = time[i][j];\n }\n }\n }\n\n ll q;cin >> q;\n rep(z,q){\n ll a,b,m;cin >> a >> b >> m;\n a-=500;\n b-=500;\n m--;\n cout << time[m][b] - time[m][a] << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 62324, "score_of_the_acc": -0.9527, "final_rank": 14 }, { "submission_id": "aoj_1148_7963188", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n\tint n, m;\n\twhile(cin >> n >> m && n) {\n\t\tint r, q;\n\t\tcin >> r;\n\t\tint time, pc, student, stat;\n\t\tvector<vector<int> > person(m, vector<int>(1260-540+1+5, 0));\n\t\tvector<vector<int> > imos(m, vector<int>(1260-540+1, 0));\n\t\tfor(int i=0;i<r;i++) {\n\t\t\tcin >> time >> pc >> student >> stat;\n\t\t\tif(stat) {\n\t\t\t\tperson[student-1][time-540] += 1;\n\t\t\t} else {\n\t\t\t\tperson[student-1][time-540] -= 1;\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<m;i++) { \n\t\t\tint current = 0;\n\t\t\tfor(int j=0;j<1260-540;j++) {\n\t\t\t\tcurrent += person[i][j];\n\t\t\t\tif(current) {\n\t\t\t\t\timos[i][j+1] = imos[i][j] + 1;\n\t\t\t\t} else {\n\t\t\t\t\timos[i][j+1] = imos[i][j];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcin >> q;\n\t\tint t1, t2;\n\t\tfor(int i=0;i<q;i++) {\n\t\t\tcin >> t1 >> t2 >> student;\n\t\t\tcout << imos[student-1][t2-540]-imos[student-1][t1-540] << endl;\n\t\t}\t\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 58400, "score_of_the_acc": -0.8341, "final_rank": 12 }, { "submission_id": "aoj_1148_7897952", "code_snippet": "#line 2 \"template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n#define square(x) ((x)*(x))\n#define endl '\\n'\n#define debug(val); cerr << #val << \": \" << val << endl;\n\n// 型エイリアス\nusing ll = long long int;\nusing ull = unsigned long long;\nusing pii = pair<int, int>;\nusing pll = pair<long long, long long>;\nusing uint = unsigned int;\nusing T3 = tuple<ll, int, int>;\n// 定数\nconstexpr int INT_INF = 1e9 + 1;\nconstexpr ll INF = 1LL << 60;\n// constexpr ll MOD = (long long)1e9 + 7;\nconstexpr ll MOD = 998244353;\n\n// 配列での方向\n// 上下左右(右から時計回り)\nconstexpr int dx[4] = { 1, 0, -1, 0 };\nconstexpr int dy[4] = { 0, 1, 0, -1 };\n// 斜め4方向(右上から時計回り)\n//constexpr int dx[4] = { 1, 1, -1, -1 };\n//constexpr int dy[4] = { -1, 1, 1, -1 };\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\nvoid Yes(bool yes)\n{\n if (yes) cout << \"Yes\" << '\\n';\n else cout << \"No\" << '\\n';\n}\n\n// pii\nostream& operator<<(ostream& os, pii p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\n// vector<T>\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v)\n{\n for (const T& val : v)\n {\n os << val << ' ';\n }\n\n return os;\n}\n// vector<vector<T>>\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<vector<T>>& v)\n{\n for (const vector<T>& line : v)\n {\n os << endl;\n for (const T& val : line)\n {\n os << val << ' ';\n }\n }\n\n return os;\n}\n// set<T>\ntemplate <typename T>\nostream& operator<<(ostream& os, const set<T>& s)\n{\n for (auto itr = s.begin(); itr != s.end(); ++itr)\n {\n os << *itr << ' ';\n }\n return os;\n}\n#line 2 \"a.cpp\"\n\nint main(void) {\n\twhile (true) {\n\t\tint N, M;\n\t\tint r, q;\n\t\tcin >> N >> M;\n\t\tif (N == 0 && M == 0) break;\n\t\tcin >> r;\n\t\tvector <vector<int>> student(M, vector<int>(1261, 0));\n\t\tfor (int i = 0; i < r; ++i) {\n\t\t\tint t, n, m, s;\n\t\t\tcin >> t >> n >> m >> s;\n\n\t\t\tint add = (s ? 1 : -1);\n\t\t\tstudent[m - 1][t] += add;\n\t\t}\n\n\t\tfor (int i = 0; i < M; ++i) {\n\t\t\tfor (int j = 1; j <= 1260; ++j) {\n\t\t\t\tstudent[i][j] += student[i][j - 1];\n\t\t\t\tif (student[i][j] < 0) exit(-1);\n\t\t\t}\n\t\t\tfor (int j = 1; j <= 1260; ++j) {\n\t\t\t\tstudent[i][j] = (student[i][j] > 0);\n\t\t\t}\n\t\t\tfor (int j = 1; j <= 1260; ++j) {\n\t\t\t\tstudent[i][j] += student[i][j - 1];\n\t\t\t}\n\t\t}\n\n\t\tcin >> q;\n\t\tfor (int i = 0; i < q; ++i) {\n\t\t\tint ts, te, m;\n\t\t\tcin >> ts >> te >> m;\n\t\t\tcout << (student[m - 1][te - 1] - student[m - 1][ts - 1]) << endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 51084, "score_of_the_acc": -1.1337, "final_rank": 15 }, { "submission_id": "aoj_1148_7848198", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nvoid solve(int n, int m){\n // n num of pc\n // m num of user\n\n int r; // r num of records\n cin>>r;\n\n vector<vector<int>> time(m+1, vector<int>(1300));\n for(int i=0;i<r;i++){\n int tt,nn,mm,ss;\n cin>>tt>>nn>>mm>>ss;\n if(ss==1){ // login\n time[mm][tt]++;\n }\n else{ // logout\n time[mm][tt]--;\n }\n }\n for(int i=0;i<=m;i++){\n for(int j=0;j<1300-1;j++){\n time[i][j+1]+=time[i][j];\n }\n }\n\n int q; // num of questions\n cin>>q;\n for(int i=0;i<q;i++){\n int start,end,user;\n cin>>start>>end>>user;\n int ans=0;\n for(int j=start;j<end;j++){\n if(time[user][j]>=1) ans++;\n }\n cout<<ans<<endl;\n }\n}\n\nint main(){\n while(true){\n int n,m;\n cin>>n>>m;\n if(n==0 && m==0) break;\n solve(n,m);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 52616, "score_of_the_acc": -0.7433, "final_rank": 9 }, { "submission_id": "aoj_1148_7848191", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define rep(i,n) for(int i = 0;i < n;i++)\n\nvoid main_(){\n\tint N,M;\n\tcin >> N >> M;\n\n\tif(!N) exit(0);\n\n\tvector<vector<int>> imos(1261,vector<int>(M,0)) ;\n\tvector<int> st(M,0);\n\n\tint r;\n\tcin >> r;\n\n\trep(i,r){\n\t\tint t,n,m,s;\n\t\tcin >> t >> n >> m >> s;\n\t\tm--;\n\n\t\tif(s == 1){\n\t\t\timos.at(t).at(m) += 1;\n\t\t}\n\t\telse {\n\t\t\timos.at(t).at(m) -= 1;\n\t\t}\n\t}\n\n\tint q;\n\tcin >> q;\n\n\trep(_,q){\n\t\tint s,e,m;\n\t\tcin >> s >> e >> m;\n\t\tm--;\n\t\tint cnt = 0;\n\t\tint ans = 0;\n\t\tfor(int i = 540;i <= 1260;i++){\n\n\t\t\tcnt += imos.at(i).at(m);\n\n\t\t\t// if(cnt != 0){\n\t\t\t// \tcout << i << \" \" << cnt << endl;\n\t\t\t// }\n\n\n\n\t\t\tif(cnt >= 1 && s <= i && i < e){\n\t\t\t\tans++;\n\t\t\t}\n\t\t}\n\n\t\tcout << ans << endl;\n\t}\n}\n\nsigned main(){\n\twhile(1) main_();\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 50584, "score_of_the_acc": -0.5817, "final_rank": 5 }, { "submission_id": "aoj_1148_7848190", "code_snippet": "#include <bits/stdc++.h>\n#ifdef MY_DEBUG\n #include \"dprint.cpp\"\n # define dprint(a, ...);\\\n do {\\\n printf(\"line : %d, func : %s\\n\",\\\n __LINE__, __func__);\\\n dprint(#a,a,##__VA_ARGS__ );\\\n } while (0)\n#else\n #define dprint(a,...) \n#endif\nusing namespace std;\n#define P pair<int,int>\ntemplate<typename T> inline bool chmax(T &a, T b) { return ((a < b) ? (a = b, true) : (false)); }\ntemplate<typename T> inline bool chmin(T &a, T b) { return ((a > b) ? (a = b, true) : (false)); }\nbool solve(){\n int N,M;\n cin >>N>>M;\n if(N==0&&M==0)return false;\n int r;\n cin >>r;\n\n vector<vector<int>> PCs(M,vector<int>(1263,0));\n for (int i = 0; i < r; i++){\n int t,n;\n cin >>t>>n;\n int m,s;\n cin >>m>>s;m--;\n if(s==0){\n PCs[m][t]--;\n }else{\n PCs[m][t]++;\n }\n } \n\nfor (int m = 0; m < M; m++){\n for (int t = 0; t < 1262; t++){\n PCs[m][t+1]+=PCs[m][t];\n } \n}\n int q;\n cin >>q;\n\n for (int i = 0; i < q; i++){\n int s,e,m;\n cin >>s>>e>>m;m--;\n\n int ans=0;\n for (int t = s; t < e; t++){\n if(PCs[m][t]>0)ans++;\n }\n cout << ans << endl;\n } \n \n return true;\n\n}\nint main() {\n while (true){\n if(solve()==false)break;\n }\n \n\nreturn 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 51304, "score_of_the_acc": -0.7297, "final_rank": 8 }, { "submission_id": "aoj_1148_6805976", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define MOD 1000000007\n//#define MOD 998244353\n#define INF 1e18 + 10\n#define EPS 1e-9\n#define F first\n#define S second\n\n#define debug(x) cout<<x<<endl;\n#define repi(i,x,n) for(int i=x;i<n;i++)\n#define rep(i,n) repi(i,0,n)\n#define lp(i,n) repi(i,0,n)\n#define repn(i,n) for(int i=n;i>=0;i--)\n#define int long long\n#define endl \"\\n\"\n\ntypedef pair<int,int> PII;\ntypedef pair<int,string> PIS;\ntypedef pair<string,int> PSI;\n\ntemplate <typename T>\nbool chmax(T &a, const T& b) {\n if (a < b) {\n a = b; \n return true;\n }\n return false;\n}\n\ntemplate <typename T>\nbool chmin(T &a, const T& b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\n\nsigned main(){\n cin.tie(0);\t\n ios::sync_with_stdio(false);\n while(1){\n int N,M;\n cin>>N>>M;\n if(N==0 && M==0) break;\n vector<vector<int> > times(M,vector<int>(1300,0) );\n int r;\n \n cin>>r;\n rep(i,r){\n int t,n,m1,S;\n cin>>t>>n>>m1>>S;\n m1--;\n if(S) times[m1][t]++;\n else times[m1][t]--;\n }\n rep(i,M){\n for(int j=1;j<1300;j++) times[i][j]+=times[i][j-1];\n }\n int q;\n cin>>q;\n while(q--){\n int cnt=0;\n int s,e,m2;\n cin>>s>>e>>m2;\n m2--;\n for(int i=s;i<e;i++){\n\tif(times[m2][i]) cnt++;\n }\n cout<<cnt<<endl;\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 101736, "score_of_the_acc": -1.6245, "final_rank": 18 } ]
aoj_1160_cpp
Problem B: How Many Islands? You are given a marine area map that is a mesh of squares, each representing either a land or sea area. Figure B-1 is an example of a map. Figure B-1: A marine area map You can walk from a square land area to another if they are horizontally, vertically, or diagonally adjacent to each other on the map. Two areas are on the same island if and only if you can walk from one to the other possibly through other land areas. The marine area on the map is surrounded by the sea and therefore you cannot go outside of the area on foot. You are requested to write a program that reads the map and counts the number of islands on it. For instance, the map in Figure B-1 includes three islands. Input The input consists of a series of datasets, each being in the following format. w h c 1,1 c 1,2 ... c 1, w c 2,1 c 2,2 ... c 2, w ... c h ,1 c h ,2 ... c h , w w and h are positive integers no more than 50 that represent the width and the height of the given map, respectively. In other words, the map consists of w × h squares of the same size. w and h are separated by a single space. c i , j is either 0 or 1 and delimited by a single space. If c i , j = 0, the square that is the i -th from the left and j -th from the top on the map represents a sea area. Otherwise, that is, if c i , j = 1, it represents a land area. The end of the input is indicated by a line containing two zeros separated by a single space. Output For each dataset, output the number of the islands in a line. No extra characters should occur in the output. Sample Input 1 1 0 2 2 0 1 1 0 3 2 1 1 1 1 1 1 5 4 1 0 1 0 0 1 0 0 0 0 1 0 1 0 1 1 0 0 1 0 5 4 1 1 1 0 1 1 0 1 0 1 1 0 1 0 1 1 0 1 1 1 5 5 1 0 1 0 1 0 0 0 0 0 1 0 1 0 1 0 0 0 0 0 1 0 1 0 1 0 0 Output for the Sample Input 0 1 1 3 1 9
[ { "submission_id": "aoj_1160_11039024", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n\nvector<int> dh = {1, 0, -1, 0, 1, 1, -1, -1};\nvector<int> dw = {0, 1, 0, -1, 1, -1, 1, -1};\n\nbool isInside(int h, int w, vector<vector<int>> C) {\n int H = C.size();\n int W = C[0].size();\n return (h >= 0 && h < H && w >= 0 && w < W);\n}\n\nvoid solve(int h, int w, const vector<vector<int>>& C,\n vector<vector<bool>>& visited, stack<pair<int, int>>& s) {\n visited[h][w] = true;\n rep(i, 8) {\n int nh = h + dh[i], nw = w + dw[i];\n if (isInside(nh, nw, C)) {\n if (C[nh][nw] == 1 && !visited[nh][nw]) s.push({nh, nw});\n }\n }\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n vector<int> res_list;\n while (true) {\n int W, H;\n cin >> W >> H;\n if (H == 0 && W == 0) break;\n vector<vector<int>> C(H, vector<int>(W));\n rep(i, H) { rep(j, W) cin >> C[i][j]; }\n\n vector<vector<bool>> visited(H, vector<bool>(W, false));\n\n ll res = 0;\n rep(i, H) {\n rep(j, W) {\n if (C[i][j] && !visited[i][j]) {\n res++;\n stack<pair<int, int>> s;\n s.push({i, j});\n while (!s.empty()) {\n auto [h, w] = s.top();\n s.pop();\n solve(h, w, C, visited, s);\n }\n }\n }\n }\n res_list.push_back(res);\n }\n\n for (int res : res_list) cout << res << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3388, "score_of_the_acc": -1.0023, "final_rank": 8 }, { "submission_id": "aoj_1160_11039011", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n\nvector<int> dh = {1, 0, -1, 0, 1, 1, -1, -1};\nvector<int> dw = {0, 1, 0, -1, 1, -1, 1, -1};\n\nbool isInside(int h, int w, vector<vector<int>> C) {\n int H = C.size();\n int W = C[0].size();\n return (h >= 0 && h < H && w >= 0 && w < W);\n}\n\nvoid dfs(int h, int w, const vector<vector<int>>& C,\n vector<vector<bool>>& visited) {\n visited[h][w] = true;\n rep(i, 8) {\n int nh = h + dh[i], nw = w + dw[i];\n if (isInside(nh, nw, C)) {\n if (C[nh][nw] == 1 && !visited[nh][nw]) dfs(nh, nw, C, visited);\n }\n }\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n vector<int> res_list;\n while (true) {\n int W, H;\n cin >> W >> H;\n if (H == 0 && W == 0) break;\n vector<vector<int>> C(H, vector<int>(W));\n rep(i, H) { rep(j, W) cin >> C[i][j]; }\n\n vector<vector<bool>> visited(H, vector<bool>(W, false));\n\n ll res = 0;\n rep(i, H) {\n rep(j, W) {\n if (C[i][j] && !visited[i][j]) {\n res++;\n dfs(i, j, C, visited);\n }\n }\n }\n res_list.push_back(res);\n }\n\n for (int res : res_list) cout << res << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3524, "score_of_the_acc": -0.4038, "final_rank": 7 }, { "submission_id": "aoj_1160_10769129", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nvector<vector<bool>> seen;\nconst vector<int> dx = {-1, 0, 1, 1, 1, 0, -1, -1};\nconst vector<int> dy = {1, 1, 1, 0, -1, -1, -1, 0};\nint W, H;\n\nvoid dfs(vector<vector<int>> G, int x, int y){\n seen[x][y] = true;\n\n for(int d = 0; d < 8; d++){\n int nx = x + dx[d], ny = y + dy[d];\n if(nx<0 || nx>=H || ny<0 || ny>=W) continue;\n if(seen[nx][ny] == true || G[nx][ny] == 0){\n continue;\n }\n dfs(G, nx, ny);\n }\n}\n\nint main() {\n while(true){\n cin >> W >> H;\n if(W == 0 && H == 0){\n return 0;\n }\n vector<vector<int>> G(H, vector<int>(W));\n for(int i = 0; i < H; i++){\n for(int j = 0; j < W; j++){\n cin >> G[i][j];\n }\n }\n\n seen.assign(H, vector<bool>(W, false));\n int cnt = 0;\n for(int i = 0; i < H; i++){\n for(int j = 0; j < W; j++){\n if(G[i][j] == 0) continue;\n if(seen[i][j]) continue;\n dfs(G, i, j);\n cnt++;\n }\n }\n cout << cnt << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 28844, "score_of_the_acc": -0.3406, "final_rank": 5 }, { "submission_id": "aoj_1160_10449615", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nvector<vector<vector<int64_t>>> island(vector<vector<vector<int64_t>>> M, int64_t I, int64_t J, int64_t W, int64_t H){\n M.at(0).at(I).at(J) = 0;\n vector<int64_t> dw;\n dw = {0, 1, 1, 1, 0, -1, -1, -1};\n vector<int64_t> dh;\n dh = {-1, -1, 0, 1, 1, 1, 0, -1};\n \n for(int64_t a = 0; a < 8; a++){\n if(I + dw.at(a) >= 0 && I + dw.at(a) < W && J + dh.at(a) >= 0 && J + dh.at(a) < H){\n if(M.at(0).at(I + dw.at(a)).at(J + dh.at(a)) == 1){\n //cout << I << \" \" << J << \" \" << M.at(2).at(0).at(0) << endl;\n M = island(M, I + dw.at(a), J + dh.at(a), W, H);\n }\n }\n }\n \n return M;\n}\n\nint main(){\n int64_t w, h, repeat = 0;\n while(repeat == 0){\n cin >> h >> w;\n if(w == 0 && h == 0){\n return 0;\n }\n vector<vector<vector<int64_t>>> m(2, vector<vector<int64_t>> (w, vector<int64_t> (h)));\n for(int64_t i = 0; i < w; i++){\n for(int64_t j = 0; j < h; j++){\n cin >> m.at(0).at(i).at(j);\n }\n }\n \n for(int64_t i = 0; i < w; i++){\n for(int64_t j = 0; j < h; j++){\n if(m.at(0).at(i).at(j) == 1){\n m.at(1).at(0).at(0)++;\n m = island(m, i, j, w, h);\n }\n }\n }\n cout << m.at(1).at(0).at(0) << endl;\n /*for(int i = 0; i < w; i++){\n for(int j = 0; j < h; j++){\n cout << m.at(1).at(i).at(j);\n }\n cout << endl;\n }*/\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 96900, "score_of_the_acc": -1.3333, "final_rank": 9 }, { "submission_id": "aoj_1160_10347320", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nclass UnionFind {\npublic:\n int par[2509], siz[2509];\n\n void init(int n) {\n for (int i = 0;i < n;i++)par[i] = -1, siz[i] = 1;\n }\n\n int root(int x) {\n while (true) {\n if (par[x] == -1)break;\n else x = par[x];\n }\n return x;\n }\n\n void unite(int u, int v) {\n int U = root(u), V = root(v);\n if (U == V)return;\n else par[min(U, V)] = max(U, V);\n }\n\n bool same(int u, int v) {\n if (root(u) == root(v))return true;\n return false;\n }\n};\n\nint dy[] = {0,-1,-1,-1,0,1,1,1}, dx[] = {1,1,0,-1,-1,-1,0,1};\n\nint main()\n{\n while (true) {\n int w, h;cin >> w >> h;\n if (w == 0)return 0;\n\n vector<vector<int>> c(h, vector<int>(w));\n UnionFind UF;\n UF.init(h * w);\n\n for (int i = 0;i < h;i++)for (int j = 0;j < w;j++)cin >> c[i][j];\n for (int i = 0;i < h;i++)for (int j = 0;j < w;j++) {\n if (c[i][j] == 0)continue;\n for (int k = 0;k < 8;k++){\n if (0 <= i + dy[k] && i + dy[k] < h && 0 <= j + dx[k] && j + dx[k] < w && c[i + dy[k]][j + dx[k]] == 1){\n UF.unite(i * w + j, (i + dy[k]) * w + j + dx[k]);\n }\n }\n }\n\n set<int> leader;\n for (int i = 0;i < h;i++)for (int j = 0;j < w;j++) {\n if (c[i][j] == 1)leader.insert(UF.root(i * w + j));\n }\n\n cout << leader.size() << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3172, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1160_10314224", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i = 0; i < (n); i++)\n#define sor(vec) sort(vec.begin(), vec.end())\n#define rsor(vec) sort(vec.rbegin(), vec.rend())\nconst long long INF = 1LL<<60;\nusing ll = long long;\n\nvector<int>a = {-1,-1,0,1,1,1,0,-1};\nvector<int>b = {0,1,1,1,0,-1,-1,-1};\n\nvoid dfs(vector<vector<int>>s,vector<vector<bool>>&visited,int x,int y,int h,int w){\n\tvisited[x][y] = true;\n\tfor(int i = 0; i < 8; i++){\n\t\tint nx = x+a[i];\n\t\tint ny = y+b[i];\n\t\tif(!(0<=nx&&nx<h && 0<=ny&&ny<w))continue;\n\t\tif(visited[nx][ny])continue;\n\t\tif(s[nx][ny]==0)continue;\n\t\tdfs(s,visited,nx,ny,h,w);\n\t}\n\treturn;\n}\n\nint main() {\n\twhile(true){\n\t\tint h,w;\n\t\tcin >> w >> h;\n\t\tif(h==0&&w==0)break;\n\t\tvector<vector<int>>s(h,vector<int>(w));\n\t\trep(i,h)rep(j,w)cin >> s[i][j];\n\t\tvector<vector<bool>>visited(h,vector<bool>(w));\n\t\tint cnt = 0;\n\t\trep(i,h){\n\t\t\trep(j,w){\n\t\t\t\tif(s[i][j]==1 && !visited[i][j]){\n\t\t\t\t\tdfs(s,visited,i,j,h,w);\n\t\t\t\t\tcnt++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << cnt << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 29160, "score_of_the_acc": -0.2773, "final_rank": 4 }, { "submission_id": "aoj_1160_9830330", "code_snippet": "#include <bits/stdc++.h>\n#include <iostream>\n#include <cstdint>\n#include <limits>\nusing namespace std;\nusing ll = int64_t;\nusing pll = pair<ll,ll>;\n\n/*\n#include <atcoder/modint>\nusing namespace atcoder;\n*/\n//using mint = modint998244353;\n//using mint = modint;\n\ntemplate <typename template_>\nvoid print_vec (vector<template_> vector_) {\n for (ll i = 0; i < vector_.size()-1; i++) cout << vector_[i] << \" \";\n cout << vector_[vector_.size()-1] << endl;\n return;\n}\n\nstruct dimension_2 {\n ll x, y;\n\n dimension_2():x(0),y(0) {}\n dimension_2(ll X, ll Y):x(X), y(Y) {}\n\n bool operator<(const dimension_2 &other) const {\n if (x == other.x) return y < other.y;\n return x < other.x;\n }\n};\nll distance_1 (dimension_2 &w0, dimension_2 &w1) {\n return abs(w0.x - w1.x) + abs(w0.y - w1.y);\n}\ndouble distance_2 (dimension_2 &w0, dimension_2 &w1) {\n return sqrt((w0.x - w1.x)*(w0.x - w1.x)+(w0.y - w1.y)*(w0.y - w1.y));\n}\n\n//----------------------------------------------------------------------------------\n\nvoid func (ll i, ll j, vector<vector<bool>> &is_land, vector<vector<bool>> &is_seen, ll &ans, vector<vector<ll>> next, bool &cnt) {\n if (!is_land[i][j]) return;\n if (is_seen[i][j]) return;\n if (cnt) {\n ans ++;\n cnt = false;\n }\n is_seen[i][j] = true;\n for (auto a:next) {\n func(i+a[0], j+a[1], is_land, is_seen, ans, next, cnt);\n }\n return;\n}\n\nint main() {\n const vector<vector<ll>> next = {{-1,-1}, {-1,0}, {-1,1}, {0,-1}, {0,1}, {1,-1}, {1,0}, {1,1}};\n while (true) {\n ll w,h; cin >> w >> h;\n if (w == 0 && h == 0) break;\n h+=2;w+=2;\n vector<vector<bool>> is_land(h, vector<bool> (w, false)), is_seen(h, vector<bool> (w, false));\n for (ll i=1;i<h-1;i++) for (ll j=1;j<w-1;j++) {\n ll x; cin >> x;\n if (x) is_land[i][j] = true;\n }\n ll ans = 0;\n for (ll i=1;i<h-1;i++) for (ll j=1;j<w-1;j++) {\n bool cnt = true;\n func(i,j,is_land,is_seen,ans,next,cnt);\n }\n cout << ans << endl;\n }\n}\n\n/*\n\ng++ main.cpp -o main\n\n----MEMO----------------------------------------------------------------------------\n\nABC\n\n\n\nSEISEN100\n\n17\n\nint main() {\n const ll n = 8;\n ll m; cin >> m;\n vector<dimension_2> chess(n);\n vector<dimension_2> chess_(m);\n for (ll i = 0; i < n;i++) cin >> chess_[i].x >> chess_[i].y;\n vector<ll> p = [0,1,2,3,4,5,6,7];\n do {\n bool is_same = true;\n for (ll i =0;i<m;i++) {\n if (p[chess_[i].x] != chess_[i].y) {\n is_same = false;\n break;\n }\n }\n if (is_same) continue;\n map<ll,ll> m_0, m_1;\n for (ll i=0;i<n;i++) {\n m_0[i+p[i]]++;\n m_1[i-p[i]]++;\n }\n bool is_ans = true;\n for (auto pair_ : m_0) {\n if (pair_.second > 1) {\n \n }\n }\n } while (next_permutation(p.begin(),p.end()));\n\n}\n\nKOUSHUUKAI\n\n*/", "accuracy": 1, "time_ms": 10, "memory_kb": 4728, "score_of_the_acc": -0.0166, "final_rank": 2 }, { "submission_id": "aoj_1160_9698813", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i, n) for(int i = 0; i < (n); i++)\n#define per(i, n) for(int i = (n) - 1; i >= 0; i--)\nusing ll = long long;\n#define vi vector<int>\n#define vvi vector<vi>\n#define vl vector<ll>\n#define vvl vector<vl>\n#define all(a) (a).begin(), (a).end()\n#define rall(a) (a).rbegin(), (a).rend()\nusing namespace std;\ntemplate<class T, class U>\nbool chmax(T &a, const U &b){ return a < b ? (a = b, 1) : 0; }\ntemplate<class T, class U>\nbool chmin(T &a, const U &b){ return a > b ? (a = b, 1) : 0; }\nconst ll inf=1LL<<60;\n\nint w,h,cnt;\nvoid dfs(vvi& seen,vvi c,int i,int j){\n seen[i][j] = 1;\n rep(u,3)rep(v,3){\n int ni = i+u-1;\n int nj = j+v-1;\n if((ni>=0 && ni < h && nj >= 0 && nj < w)){\n if(!seen[ni][nj] && c[ni][nj])\n dfs(seen,c,ni,nj);\n seen[ni][nj] = 1;\n }\n }\n}\n\nint main(void){\n cin >> w >> h;\n while(!(w==0 && h==0)){\n cnt = 0;\n vvi c(h,vi(w));\n vvi seen(h,vi(w,0));\n rep(i,h)rep(j,w)cin >> c[i][j];\n int ans = 0;\n rep(i,h)rep(j,w){\n if(!seen[i][j] && c[i][j]){\n dfs(seen,c,i,j);\n ans++;\n }\n seen[i][j]=1;\n }\n cout << ans << endl;\n cin >> w >> h;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 29228, "score_of_the_acc": -0.3447, "final_rank": 6 }, { "submission_id": "aoj_1160_9670543", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n\nvoid dfs(vector<vector<bool>> g, int h, int w, int i, int j, vector<vector<bool>>& seen) {\n seen[i][j] = true;\n vector<int> dx = {0, 1, 0, -1, 1, 1, -1, -1};\n vector<int> dy = {1, 0, -1, 0, 1, -1, 1, -1};\n rep(k,8) {\n if (i+dy[k]<0||i+dy[k]>=h||j+dx[k]<0||j+dx[k]>=w) continue;\n if ((!g[i+dy[k]][j+dx[k]])||seen[i+dy[k]][j+dx[k]]) continue;\n dfs(g, h, w, i+dy[k], j+dx[k], seen);\n }\n}\n\nint main() {\n while (true) {\n int w, h; cin >> w >> h;\n if (w==0&&h==0) break;\n vector<vector<bool>> c(h, vector<bool>(w, false));\n rep(i,h)rep(j,w) {\n int b; cin >> b;\n if (b==1) c[i][j] = true;\n }\n int cnt = 0;\n vector<vector<bool>> seen(h, vector<bool>(w, false));\n rep(i,h)rep(j,w) {\n if ((!c[i][j])||seen[i][j]) continue;\n dfs(c, h, w, i, j, seen);\n cnt++; \n }\n cout << cnt << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 12100, "score_of_the_acc": -0.2286, "final_rank": 3 } ]
aoj_1146_cpp
Problem F Secrets in Shadows Long long ago, there were several identical columns (or cylinders) built vertically in a big open space near Yokohama (Fig. F-1). In the daytime, the shadows of the columns were moving on the ground as the sun moves in the sky. Each column was very tall so that its shadow was very long. The top view of the shadows is shown in Fig. F-2. The directions of the sun that minimizes and maximizes the widths of the shadows of the columns were said to give the important keys to the secrets of ancient treasures. Fig. F-1: Columns (or cylinders) Gig. F-2: Top view of the columns (Fig. F-1) and their shadows The width of the shadow of each column is the same as the diameter of the base disk. But the width of the whole shadow (the union of the shadows of all the columns) alters according to the direction of the sun since the shadows of some columns may overlap those of other columns. Fig. F-3 shows the direction of the sun that minimizes the width of the whole shadow for the arrangement of columns in Fig. F-2. Fig. F-3: The direction of the sun for the minimal width of the whole shadow Fig. F-4 shows the direction of the sun that maximizes the width of the whole shadow. When the whole shadow is separated into several parts (two parts in this case), the width of the whole shadow is defined as the sum of the widths of the parts. Fig. F-4: The direction of the sun for the maximal width of the whole shadow A direction of the sun is specified by an angle θ defined in Fig. F-5. For example, the east is indicated by θ = 0, the south by θ = π /2, and the west by θ = π . You may assume that the sun rises in the east ( θ = 0) and sets in the west ( θ = π ). Your job is to write a program that, given an arrangement of columns, computes two directions θ min and θ max of the sun that give the minimal width and the maximal width of the whole shadow, respectively. The position of the center of the base disk of each column is specified by its ( x , y ) coordinates. The x -axis and y -axis are parallel to the line between the east and the west and that between the north and the south, respectively. Their positive directions indicate the east and the north, respectively. You can assume that the big open space is a plane surface. Fig. F-5: The definition of the angle of the direction of the sun There may be more than one θ min or θ max for some arrangements in general, but here, you may assume that we only consider the arrangements that have unique θ min and θ max in the range 0 ≤ θ min < π , 0 ≤ θ max < π . Input The input consists of multiple datasets, followed by the last line containing a single zero. Each dataset is formatted as follows. n x 1 y 1 x 2 y 2 ... x n y n n is the number of the columns in the big open space. It is a positive integer no more than 100. x k and y k are the values of x -coordinate and y -coordinate of the center of the base disk of the k -th column ( k =1, ..., n ). They are positive integers no more than 30. They are s ...(truncated)
[ { "submission_id": "aoj_1146_10214589", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS \n#include <iostream>\n#include <algorithm>\n#include <cmath>\n#include <cstring>\n#include <cassert>\n#include <vector>\ntypedef long long ll;\ntypedef long double ld;\n//typedef double ld;\ntypedef std::vector<int> Vint;\ntypedef std::vector<ld> Vld;\nconst ld INF = 1e17;\nconst ld TOL = 1e-20;\nconst ld PI = acosl(-1);\nconst int LEN = 10005;\ninline int sign(const ld& x) { return x <= -TOL ? -1 : x >= TOL; }\ninline bool zero(const ld& x) { return !sign(x); }\ninline bool eq(const ld& x, const ld& y) { return zero(x - y); }\ninline ll sq(const ll& x) { return x * x; }\ninline ld sq(const ld& x) { return x * x; }\ninline ld fit(const ld& x, const ld& lo, const ld& hi) { return std::min(hi, std::max(lo, x)); }\ninline ld norm(ld th) { while (th < 0) th += 2 * PI; while (sign(th - 2 * PI) >= 0) th -= 2 * PI; return th; }\n\n#define INSIDE 0\n#define MEET 1\n#define OUTSIDE 2\n#define STRONG 0\n#define WEAK 1\n#define LO x\n#define HI y\n\nint N, M;\nVld ANS;\nstruct Pos {\n\tld x, y;\n\tint i;\n\tPos(ld x_ = 0, ld y_ = 0) : x(x_), y(y_) { i = 0; }\n\tbool operator == (const Pos& p) const { return zero(x - p.x) && zero(y - p.y); }\n\tbool operator != (const Pos& p) const { return !zero(x - p.x) || !zero(y - p.y); }\n\tbool operator < (const Pos& p) const { return zero(x - p.x) ? y < p.y : x < p.x; }\n\tbool operator <= (const Pos& p) const { return *this < p || *this == p; }\n\tPos operator + (const Pos& p) const { return { x + p.x, y + p.y }; }\n\tPos operator - (const Pos& p) const { return { x - p.x, y - p.y }; }\n\tPos operator * (const ld& n) const { return { x * n, y * n }; }\n\tPos operator / (const ld& n) const { return { x / n, y / n }; }\n\tld operator * (const Pos& p) const { return x * p.x + y * p.y; }\n\tld operator / (const Pos& p) const { return x * p.y - y * p.x; }\n\tPos operator ^ (const Pos& p) const { return { x * p.x, y * p.y }; }\n\tPos& operator += (const Pos& p) { x += p.x; y += p.y; return *this; }\n\tPos& operator -= (const Pos& p) { x -= p.x; y -= p.y; return *this; }\n\tPos& operator *= (const ld& n) { x *= n; y *= n; return *this; }\n\tPos& operator /= (const ld& n) { x /= n; y /= n; return *this; }\n\tPos operator - () const { return { -x, -y }; }\n\tPos operator ~ () const { return { -y, x }; }\n\tPos operator ! () const { return { y, x }; }\n\tld xy() const { return x * y; }\n\tPos rot(const ld& the) const { return { x * cosl(the) - y * sinl(the), x * sinl(the) + y * cosl(the) }; }\n\tld Euc() const { return x * x + y * y; }\n\tld mag() const { return sqrtl(Euc()); }\n\tPos unit() const { return *this / mag(); }\n\tld rad() const { return atan2l(y, x); }\n\tfriend ld rad(const Pos& p1, const Pos& p2) { return atan2l(p1 / p2, p1 * p2); }\n\tint quad() const { return sign(y) == 1 || (sign(y) == 0 && sign(x) >= 0); }\n\tfriend bool cmpq(const Pos& a, const Pos& b) { return (a.quad() != b.quad()) ? a.quad() < b.quad() : a / b > 0; }\n\tbool close(const Pos& p) const { return zero((*this - p).Euc()); }\n\tfriend std::istream& operator >> (std::istream& is, Pos& p) { is >> p.x >> p.y; return is; }\n\tfriend std::ostream& operator << (std::ostream& os, const Pos& p) { os << p.x << \" \" << p.y; return os; }\n}; const Pos O = Pos(0, 0);\ntypedef std::vector<Pos> Polygon;\nld cross(const Pos& d1, const Pos& d2, const Pos& d3) { return (d2 - d1) / (d3 - d2); }\nld cross(const Pos& d1, const Pos& d2, const Pos& d3, const Pos& d4) { return (d2 - d1) / (d4 - d3); }\nint ccw(const Pos& d1, const Pos& d2, const Pos& d3) { return sign(cross(d1, d2, d3)); }\nld dot(const Pos& d1, const Pos& d2, const Pos& d3) { return (d2 - d1) * (d3 - d2); }\nld dot(const Pos& d1, const Pos& d2, const Pos& d3, const Pos& d4) { return (d2 - d1) * (d4 - d3); }\nPos intersection(const Pos& p1, const Pos& p2, const Pos& q1, const Pos& q2) { ld a1 = cross(q1, q2, p1), a2 = -cross(q1, q2, p2); return (p1 * a2 + p2 * a1) / (a1 + a2); }\nbool inner_check(const Polygon& H, const Pos& p) {\n\tint sz = H.size();\n\tfor (int i = 0; i < sz; i++) if (ccw(H[i], H[(i + 1) % sz], p) < 0) return 0;\n\treturn 1;\n}\nstruct Seg {\n\tPos s, e;\n\tSeg(Pos s_ = Pos(), Pos e_ = Pos()) : s(s_), e(e_) {}\n\tPos p(const ld& rt) const { return s + (e - s) * rt; }\n\tld green(const ld& lo = 0, const ld& hi = 1) const {\n\t\tld d = hi - lo;\n\t\tld ratio = (lo + hi) * .5;\n\t\tPos m = p(ratio);\n\t\treturn m.y * d * (s.x - e.x);\n\t}\n};\nld intersection(const Seg& s1, const Seg& s2, const bool& f = STRONG) {\n\tconst Pos& p1 = s1.s, p2 = s1.e, q1 = s2.s, q2 = s2.e;\n\tld det = (q2 - q1) / (p2 - p1);\n\tif (zero(det)) return -1;\n\tld a1 = ((q2 - q1) / (q1 - p1)) / det;\n\tld a2 = ((p2 - p1) / (p1 - q1)) / -det;\n\tif (f == WEAK) return a1;\n\tif (0 < a1 && a1 < 1 && -TOL < a2 && a2 < 1 + TOL) return a1;\n\treturn -1;\n}\nPos get_vec(const Polygon& P, const Polygon& V) {\n\tPos ab = Pos(0, 0);//a * sin(t) + b * cos(t) + c = 0\n\tint sz = V.size();\n\tfor (int i = 0; i < sz; i++) {\n\t\tif (i < sz - 1 && V[i].HI > V[i + 1].LO) {\n\t\t\tPos v = P[V[i + 1].i] - P[V[i].i];\n\t\t\tab += v;\n\t\t}\n\t}\n\treturn ab;\n}\nbool query() {\n\tld min = INF, max = -1;\n\tld mint = 0, maxt = 0;\n\tstd::cin >> N;\n\tif (!N) return 0;\n\tPolygon P(N); for (Pos& p : P) std::cin >> p, p.y *= -1;\n\tPolygon V;\n\tVld T = { 0, PI };\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = i + 1; j < N; j++) {\n\t\t\tPos v = (P[j] - P[i]);\n\t\t\tld l = v.mag();\n\t\t\t//v = v.unit();\n\t\t\tif (v < O) v *= -1;\n\t\t\tT.push_back(norm(v.rad()));\n\t\t\tld t = asinl(2 / l);\n\t\t\tPos v1 = v.rot(t);\n\t\t\tif (v1 < O) v1 *= -1;\n\t\t\tT.push_back(norm(v1.rad()));\n\t\t\tPos v2 = v.rot(-t);\n\t\t\tif (v2 < O) v2 *= -1;\n\t\t\tT.push_back(norm(v2.rad()));\n\t\t}\n\t}\n\tstd::sort(T.begin(), T.end());\n\tT.erase(unique(T.begin(), T.end()), T.end());\n\tint sz = T.size();\n\tfor (int i = 0; i < sz - 1; i++) {\n\t\tld s = T[i], e = T[i + 1];\n\t\tld m = (s + e) * .5;\n\t\tPos v = Pos(1, 0).rot(m);\n\t\tPos h = ~v;\n\t\tSeg I = Seg(O, h);\n\t\tPolygon V;\n\t\tld x;\n\t\tfor (int k = 0; k < N; k++) {\n\t\t\tPos p = P[k];\n\t\t\tPos q = p + v;\n\t\t\tSeg K = Seg(p, q);\n\t\t\tx = intersection(I, K, WEAK);\n\t\t\tPos r = Pos(x - 1, x + 1);\n\t\t\tr.i = k;\n\t\t\tV.push_back(r);\n\t\t}\n\t\tstd::sort(V.begin(), V.end());\n\t\tPos ab = get_vec(P, V);\n\t\tT.push_back(norm(ab.rad()));\n\t\tT.push_back(norm((~ab).rad()));\n\t}\n\tstd::sort(T.begin(), T.end());\n\tT.erase(unique(T.begin(), T.end()), T.end());\n\tfor (const ld& t : T) {\n\t\tPos v = Pos(1, 0).rot(t);\n\t\tPos h = ~v;\n\t\tSeg I = Seg(O, h);\n\t\tPolygon V;\n\t\tld x;\n\t\tfor (const Pos& p : P) {\n\t\t\tPos q = p + v;\n\t\t\tSeg K = Seg(p, q);\n\t\t\tx = intersection(I, K, WEAK);\n\t\t\tPos r = Pos(x - 1, x + 1);\n\t\t\tV.push_back(r);\n\t\t}\n\t\tstd::sort(V.begin(), V.end());\n\t\tV.erase(unique(V.begin(), V.end()), V.end());\n\t\tx = 0;\n\t\tint sz = V.size();\n\t\tfor (int i = 0; i < sz; i++) {\n\t\t\tif (i < sz - 1 && V[i].HI > V[i + 1].LO) x += (V[i + 1].LO - V[i].LO);\n\t\t\telse x += V[i].HI - V[i].LO;\n\t\t}\n\t\tif (min > x) { min = x; mint = std::min(norm(v.rad()), norm(v.rad() + PI)); }\n\t\tif (max < x) { max = x; maxt = std::min(norm(v.rad()), norm(v.rad() + PI)); }\n\t}\n\tstd::cout << mint << \"\\n\" << maxt << \"\\n\";\n\t//ANS.push_back(mint);\n\t//ANS.push_back(maxt);\n\treturn 1;\n}\nvoid solve() {\n\tstd::cin.tie(0)->sync_with_stdio(0);\n\tstd::cout.tie(0);\n\tstd::cout << std::fixed;\n\tstd::cout.precision(11);\n\twhile (query());\n\t//for (const ld& ans : ANS) std::cout << ans << \"\\n\";\n\t//for (const ld& ans : ANS) {\n\t//\tld x;\n\t//\tstd::cin >> x;\n\t//\tstd::cout << ans << \"\\n\";\n\t//\tld err = (ans - x) / ans;\n\t//\tif (zero(x)) std::cout << \"answer is zero and my result is \" << ans << \"\\n\";\n\t//\telse std::cout << err << \"\\n\";\n\t//\tif (std::abs(err) > 1e-10) std::cout << \"FUCK::\\n\";\n\t//\telse std::cout << \"GOOD\\n\";\n\t//}\n\treturn;\n}\nint main() { solve(); return 0; }//boj4985 Secrets in Shadows\n\n\n\n//struct Circle {\n//\tPos c;\n//\tll r;\n//\tCircle(Pos c_ = Pos(), ll r_ = 0) : c(c_), r(r_) {}\n//\tbool operator > (const Pos& p) const { return sign(r - (c - p).mag()) > 0; }\n//\tPos p(const ld& t) const { return c + Pos(r, 0).rot(t); }\n//\tld rad(const Pos& p) const { return (p - c).rad(); }\n//\tld area(const ld& lo, const ld& hi) const { return (hi - lo) * r * r * .5; }\n//\tld green(const ld& lo, const ld& hi) const {\n//\t\tPos s = Pos(cos(lo), sin(lo)), e = Pos(cos(hi), sin(hi));\n//\t\tld fan = area(lo, hi);\n//\t\tPos m = c + (s + e) * r * (ld).5;\n//\t\tld tz = (cos(lo) - cos(hi)) * m.y * r;\n//\t\treturn fan + tz - (s / e) * r * r * (ld).5;\n//\t}\n//\tfriend std::istream& operator >> (std::istream& is, Circle& p) { is >> p.c.x >> p.c.y >> p.r; return is; }\n//\tfriend std::ostream& operator << (std::ostream& os, const Circle& p) { os << p.c.x << \" \" << p.c.y << \" \" << p.r; return os; }\n//} C[3];\n//Vld intersections(const Circle& a, const Circle& b) {\n//\tPos ca = a.c, cb = b.c;\n//\tPos vec = cb - ca;\n//\tld ra = a.r, rb = b.r;\n//\tld distance = vec.mag();\n//\tld rd = vec.rad();\n//\tif (vec.Euc() > sq(ra + rb) + TOL) return {};\n//\tif (vec.Euc() < sq(ra - rb) - TOL) return {};\n//\tld X = (ra * ra - rb * rb + vec.Euc()) / (2 * distance * ra);\n//\tif (X < -1) X = -1;\n//\tif (X > 1) X = 1;\n//\tld h = acos(X);\n//\tVld ret = {};\n//\tret.push_back(norm(rd - h));\n//\tif (zero(h)) return ret;\n//\tret.push_back(norm(rd + h));\n//\treturn ret;\n//}", "accuracy": 1, "time_ms": 530, "memory_kb": 4268, "score_of_the_acc": -0.8036, "final_rank": 13 }, { "submission_id": "aoj_1146_10214588", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS \n#include <iostream>\n#include <algorithm>\n#include <cmath>\n#include <cstring>\n#include <cassert>\n#include <vector>\ntypedef long long ll;\ntypedef long double ld;\n//typedef double ld;\ntypedef std::vector<int> Vint;\ntypedef std::vector<ld> Vld;\nconst ld INF = 1e17;\nconst ld TOL = 1e-20;\nconst ld PI = acosl(-1);\nconst int LEN = 10005;\ninline int sign(const ld& x) { return x <= -TOL ? -1 : x >= TOL; }\ninline bool zero(const ld& x) { return !sign(x); }\ninline bool eq(const ld& x, const ld& y) { return zero(x - y); }\ninline ll sq(const ll& x) { return x * x; }\ninline ld sq(const ld& x) { return x * x; }\ninline ld fit(const ld& x, const ld& lo, const ld& hi) { return std::min(hi, std::max(lo, x)); }\ninline ld norm(ld th) { while (th < 0) th += 2 * PI; while (sign(th - 2 * PI) >= 0) th -= 2 * PI; return th; }\n\n#define INSIDE 0\n#define MEET 1\n#define OUTSIDE 2\n#define STRONG 0\n#define WEAK 1\n#define LO x\n#define HI y\n\nint N, M;\nVld ANS;\nstruct Pos {\n\tld x, y;\n\tint i;\n\tPos(ld x_ = 0, ld y_ = 0) : x(x_), y(y_) { i = 0; }\n\tbool operator == (const Pos& p) const { return zero(x - p.x) && zero(y - p.y); }\n\tbool operator != (const Pos& p) const { return !zero(x - p.x) || !zero(y - p.y); }\n\tbool operator < (const Pos& p) const { return zero(x - p.x) ? y < p.y : x < p.x; }\n\tbool operator <= (const Pos& p) const { return *this < p || *this == p; }\n\tPos operator + (const Pos& p) const { return { x + p.x, y + p.y }; }\n\tPos operator - (const Pos& p) const { return { x - p.x, y - p.y }; }\n\tPos operator * (const ld& n) const { return { x * n, y * n }; }\n\tPos operator / (const ld& n) const { return { x / n, y / n }; }\n\tld operator * (const Pos& p) const { return x * p.x + y * p.y; }\n\tld operator / (const Pos& p) const { return x * p.y - y * p.x; }\n\tPos operator ^ (const Pos& p) const { return { x * p.x, y * p.y }; }\n\tPos& operator += (const Pos& p) { x += p.x; y += p.y; return *this; }\n\tPos& operator -= (const Pos& p) { x -= p.x; y -= p.y; return *this; }\n\tPos& operator *= (const ld& n) { x *= n; y *= n; return *this; }\n\tPos& operator /= (const ld& n) { x /= n; y /= n; return *this; }\n\tPos operator - () const { return { -x, -y }; }\n\tPos operator ~ () const { return { -y, x }; }\n\tPos operator ! () const { return { y, x }; }\n\tld xy() const { return x * y; }\n\tPos rot(ld the) const { return { x * cosl(the) - y * sinl(the), x * sinl(the) + y * cosl(the) }; }\n\tld Euc() const { return x * x + y * y; }\n\tld mag() const { return sqrtl(Euc()); }\n\tPos unit() const { return *this / mag(); }\n\tld rad() const { return atan2l(y, x); }\n\tfriend ld rad(const Pos& p1, const Pos& p2) { return atan2l(p1 / p2, p1 * p2); }\n\tint quad() const { return sign(y) == 1 || (sign(y) == 0 && sign(x) >= 0); }\n\tfriend bool cmpq(const Pos& a, const Pos& b) { return (a.quad() != b.quad()) ? a.quad() < b.quad() : a / b > 0; }\n\tbool close(const Pos& p) const { return zero((*this - p).Euc()); }\n\tfriend std::istream& operator >> (std::istream& is, Pos& p) { is >> p.x >> p.y; return is; }\n\tfriend std::ostream& operator << (std::ostream& os, const Pos& p) { os << p.x << \" \" << p.y; return os; }\n}; const Pos O = Pos(0, 0);\ntypedef std::vector<Pos> Polygon;\nld cross(const Pos& d1, const Pos& d2, const Pos& d3) { return (d2 - d1) / (d3 - d2); }\nld cross(const Pos& d1, const Pos& d2, const Pos& d3, const Pos& d4) { return (d2 - d1) / (d4 - d3); }\nint ccw(const Pos& d1, const Pos& d2, const Pos& d3) { return sign(cross(d1, d2, d3)); }\nld dot(const Pos& d1, const Pos& d2, const Pos& d3) { return (d2 - d1) * (d3 - d2); }\nld dot(const Pos& d1, const Pos& d2, const Pos& d3, const Pos& d4) { return (d2 - d1) * (d4 - d3); }\nPos intersection(const Pos& p1, const Pos& p2, const Pos& q1, const Pos& q2) { ld a1 = cross(q1, q2, p1), a2 = -cross(q1, q2, p2); return (p1 * a2 + p2 * a1) / (a1 + a2); }\nbool inner_check(const Polygon& H, const Pos& p) {\n\tint sz = H.size();\n\tfor (int i = 0; i < sz; i++) if (ccw(H[i], H[(i + 1) % sz], p) < 0) return 0;\n\treturn 1;\n}\nstruct Seg {\n\tPos s, e;\n\tSeg(Pos s_ = Pos(), Pos e_ = Pos()) : s(s_), e(e_) {}\n\tPos p(const ld& rt) const { return s + (e - s) * rt; }\n\tld green(const ld& lo = 0, const ld& hi = 1) const {\n\t\tld d = hi - lo;\n\t\tld ratio = (lo + hi) * .5;\n\t\tPos m = p(ratio);\n\t\treturn m.y * d * (s.x - e.x);\n\t}\n};\nld intersection(const Seg& s1, const Seg& s2, const bool& f = STRONG) {\n\tconst Pos& p1 = s1.s, p2 = s1.e, q1 = s2.s, q2 = s2.e;\n\tld det = (q2 - q1) / (p2 - p1);\n\tif (zero(det)) return -1;\n\tld a1 = ((q2 - q1) / (q1 - p1)) / det;\n\tld a2 = ((p2 - p1) / (p1 - q1)) / -det;\n\tif (f == WEAK) return a1;\n\tif (0 < a1 && a1 < 1 && -TOL < a2 && a2 < 1 + TOL) return a1;\n\treturn -1;\n}\nPos get_vec(const Polygon& P, const Polygon& V) {\n\tPos ab = Pos(0, 0);//a * sin(t) + b * cos(t) + c = 0\n\tint sz = V.size();\n\tfor (int i = 0; i < sz; i++) {\n\t\tif (i < sz - 1 && V[i].HI > V[i + 1].LO) {\n\t\t\tPos v = P[V[i + 1].i] - P[V[i].i];\n\t\t\tab += v;\n\t\t}\n\t}\n\treturn ab;\n}\nbool query() {\n\tld min = INF, max = -1;\n\tld mint = 0, maxt = 0;\n\tstd::cin >> N;\n\tif (!N) return 0;\n\tPolygon P(N); for (Pos& p : P) std::cin >> p, p.y *= -1;\n\tPolygon V;\n\tVld T = { 0, PI };\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = i + 1; j < N; j++) {\n\t\t\tPos v = (P[j] - P[i]);\n\t\t\tld l = v.mag();\n\t\t\t//v = v.unit();\n\t\t\tif (v < O) v *= -1;\n\t\t\tT.push_back(norm(v.rad()));\n\t\t\tld t = asinl(2 / l);\n\t\t\tPos v1 = v.rot(t);\n\t\t\tif (v1 < O) v1 *= -1;\n\t\t\tT.push_back(norm(v1.rad()));\n\t\t\tPos v2 = v.rot(-t);\n\t\t\tif (v2 < O) v2 *= -1;\n\t\t\tT.push_back(norm(v2.rad()));\n\t\t}\n\t}\n\tstd::sort(T.begin(), T.end());\n\tT.erase(unique(T.begin(), T.end()), T.end());\n\tint sz = T.size();\n\tfor (int i = 0; i < sz - 1; i++) {\n\t\tld s = T[i], e = T[i + 1];\n\t\tld m = (s + e) * .5;\n\t\tPos v = Pos(1, 0).rot(m);\n\t\tPos h = ~v;\n\t\tSeg I = Seg(O, h);\n\t\tPolygon V;\n\t\tld x;\n\t\tfor (int k = 0; k < N; k++) {\n\t\t\tPos p = P[k];\n\t\t\tPos q = p + v;\n\t\t\tSeg K = Seg(p, q);\n\t\t\tx = intersection(I, K, WEAK);\n\t\t\tPos r = Pos(x - 1, x + 1);\n\t\t\tr.i = k;\n\t\t\tV.push_back(r);\n\t\t}\n\t\tstd::sort(V.begin(), V.end());\n\t\tPos ab = get_vec(P, V);\n\t\tT.push_back(norm(ab.rad()));\n\t\tT.push_back(norm((~ab).rad()));\n\t}\n\tstd::sort(T.begin(), T.end());\n\tT.erase(unique(T.begin(), T.end()), T.end());\n\tfor (const ld& t : T) {\n\t\tPos v = Pos(1, 0).rot(t);\n\t\tPos h = ~v;\n\t\tSeg I = Seg(O, h);\n\t\tPolygon V;\n\t\tld x;\n\t\tfor (const Pos& p : P) {\n\t\t\tPos q = p + v;\n\t\t\tSeg K = Seg(p, q);\n\t\t\tx = intersection(I, K, WEAK);\n\t\t\tPos r = Pos(x - 1, x + 1);\n\t\t\tV.push_back(r);\n\t\t}\n\t\tstd::sort(V.begin(), V.end());\n\t\tV.erase(unique(V.begin(), V.end()), V.end());\n\t\tx = 0;\n\t\tint sz = V.size();\n\t\tfor (int i = 0; i < sz; i++) {\n\t\t\tif (i < sz - 1 && V[i].HI > V[i + 1].LO) x += (V[i + 1].LO - V[i].LO);\n\t\t\telse x += V[i].HI - V[i].LO;\n\t\t}\n\t\tif (min > x) { min = x; mint = std::min(norm(v.rad()), norm(v.rad() + PI)); }\n\t\tif (max < x) { max = x; maxt = std::min(norm(v.rad()), norm(v.rad() + PI)); }\n\t}\n\t//std::cout << mint << \"\\n\" << maxt << \"\\n\";\n\tANS.push_back(mint);\n\tANS.push_back(maxt);\n\treturn 1;\n}\nvoid solve() {\n\tstd::cin.tie(0)->sync_with_stdio(0);\n\tstd::cout.tie(0);\n\tstd::cout << std::fixed;\n\tstd::cout.precision(11);\n\twhile (query());\n\tfor (const ld& ans : ANS) std::cout << ans << \"\\n\";\n\t//for (const ld& ans : ANS) {\n\t//\tld x;\n\t//\tstd::cin >> x;\n\t//\tstd::cout << ans << \"\\n\";\n\t//\tld err = (ans - x) / ans;\n\t//\tif (zero(x)) std::cout << \"answer is zero and my result is \" << ans << \"\\n\";\n\t//\telse std::cout << err << \"\\n\";\n\t//\tif (std::abs(err) > 1e-10) std::cout << \"FUCK::\\n\";\n\t//\telse std::cout << \"GOOD\\n\";\n\t//}\n\treturn;\n}\nint main() { solve(); return 0; }//boj4985 Secrets in Shadows\n\n\n\n//struct Circle {\n//\tPos c;\n//\tll r;\n//\tCircle(Pos c_ = Pos(), ll r_ = 0) : c(c_), r(r_) {}\n//\tbool operator > (const Pos& p) const { return sign(r - (c - p).mag()) > 0; }\n//\tPos p(const ld& t) const { return c + Pos(r, 0).rot(t); }\n//\tld rad(const Pos& p) const { return (p - c).rad(); }\n//\tld area(const ld& lo, const ld& hi) const { return (hi - lo) * r * r * .5; }\n//\tld green(const ld& lo, const ld& hi) const {\n//\t\tPos s = Pos(cos(lo), sin(lo)), e = Pos(cos(hi), sin(hi));\n//\t\tld fan = area(lo, hi);\n//\t\tPos m = c + (s + e) * r * (ld).5;\n//\t\tld tz = (cos(lo) - cos(hi)) * m.y * r;\n//\t\treturn fan + tz - (s / e) * r * r * (ld).5;\n//\t}\n//\tfriend std::istream& operator >> (std::istream& is, Circle& p) { is >> p.c.x >> p.c.y >> p.r; return is; }\n//\tfriend std::ostream& operator << (std::ostream& os, const Circle& p) { os << p.c.x << \" \" << p.c.y << \" \" << p.r; return os; }\n//} C[3];\n//Vld intersections(const Circle& a, const Circle& b) {\n//\tPos ca = a.c, cb = b.c;\n//\tPos vec = cb - ca;\n//\tld ra = a.r, rb = b.r;\n//\tld distance = vec.mag();\n//\tld rd = vec.rad();\n//\tif (vec.Euc() > sq(ra + rb) + TOL) return {};\n//\tif (vec.Euc() < sq(ra - rb) - TOL) return {};\n//\tld X = (ra * ra - rb * rb + vec.Euc()) / (2 * distance * ra);\n//\tif (X < -1) X = -1;\n//\tif (X > 1) X = 1;\n//\tld h = acos(X);\n//\tVld ret = {};\n//\tret.push_back(norm(rd - h));\n//\tif (zero(h)) return ret;\n//\tret.push_back(norm(rd + h));\n//\treturn ret;\n//}", "accuracy": 1, "time_ms": 540, "memory_kb": 3948, "score_of_the_acc": -0.727, "final_rank": 10 }, { "submission_id": "aoj_1146_9680288", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<ll,ll> pi;\ntypedef vector<ll> vi;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\nint main(){\n vector<ld>A(100);\n while(1){\n ll N;cin>>N;\n if(!N)return 0;\n vi X(N),Y(N);\n REP(i,N)cin>>X[i]>>Y[i];\n vector<ld>koho;\n REP(i,N)REP(j,N)if(i!=j){\n ll x=X[i]-X[j];\n ll y=Y[i]-Y[j];\n ll d=x*x+y*y;\n assert(d>=4);\n ld a=sqrtl(d-4);\n if(2*x+y*a>0||(2*x+y*a==0&&2*y-x*a>0))koho.emplace_back(atan2l(2*x+y*a,2*y-x*a));\n if(2*x-y*a>0||(2*x-y*a==0&&2*y+x*a>0))koho.emplace_back(atan2l(2*x-y*a,2*y+x*a));\n }\n REP(i,N)REP(j,i){\n ll x=X[i]-X[j];\n ll y=Y[j]-Y[i];\n if(y<0||(y==0&&x<0))x*=-1,y*=-1;\n koho.emplace_back(atan2l(y,x));\n }\n koho.emplace_back(0);\n koho.emplace_back(acos(-1)-(1e-13));\n sort(ALL(koho));\n koho.erase(unique(ALL(koho)),koho.end());\n auto val=[&](ld theta){\n ld s=sinl(theta);\n ld c=cosl(theta);\n REP(i,N)A[i]=X[i]*s+Y[i]*c;\n sort(A.begin(),A.begin()+N);\n ld ans=2;\n REP(i,N-1)ans+=min((ld)2,A[i+1]-A[i]);\n return ans;\n };\n auto _koho=koho;\n REP(i,koho.size()-1){\n ld theta3=(koho[i]+koho[i+1])*0.5;\n vector<ll>idx(N);\n iota(ALL(idx),0);\n sort(ALL(idx),[&](ll i,ll j){return X[i]*sinl(theta3)+Y[i]*cosl(theta3)<X[j]*sinl(theta3)+Y[j]*cosl(theta3);});\n vector<ld>P(N);\n REP(i,N)P[i]=X[idx[i]]*sinl(theta3)+Y[idx[i]]*cosl(theta3);\n ll a=0,b=0;\n REP(i,N-1)if(P[i+1]-P[i]<2)a+=X[idx[i+1]]-X[idx[i]],b+=Y[idx[i+1]]-Y[idx[i]];\n if(a<0||(a==0&&b<0))a=-a,b=-b;\n if(a!=0||b!=0)_koho.emplace_back(atan2l(a,b));\n }\n koho=_koho;\n ld theta_min=0,theta_max=0;\n ld val_min=1e18,val_max=-1e18;\n for(auto theta:koho){\n if(theta<0)theta+=acosl(-1);\n ld v=val(theta);\n if(v<val_min)theta_min=theta,val_min=v;\n if(v>val_max)theta_max=theta,val_max=v;\n }\n printf(\"%.20Lf\\n%.20Lf\\n\",theta_min,theta_max);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1070, "memory_kb": 4240, "score_of_the_acc": -0.9246, "final_rank": 15 }, { "submission_id": "aoj_1146_6774146", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long double INF = 1000;\nconst long double PI = acos(-1);\nstruct point{\n long double x, y;\n point(){\n }\n point(long double x, long double y): x(x), y(y){\n }\n point operator -(point P){\n return point(x - P.x, y - P.y);\n }\n};\nlong double abs(point P){\n return sqrt(P.x * P.x + P.y * P.y);\n}\nlong double dist(point P, point Q){\n return abs(Q - P);\n}\nlong double angle(point P){\n long double ans = atan2(P.y, P.x);\n if (ans < 0){\n ans += PI;\n }\n return ans;\n}\npair<long double, long double> get_min(long double s, long double c, long double a, long double L, long double R){\n long double A = hypot(s, c);\n long double t = atan2(c, s);\n pair<long double, long double> ans = make_pair(INF, 0);\n long double t1 = -PI / 2 - t;\n if (L <= t1 && t1 <= R){\n ans = min(ans, make_pair(A + a, t1));\n }\n long double t2 = 3 * PI / 2 - t;\n if (L <= t2 && t2 <= R){\n ans = min(ans, make_pair(A + a, t2));\n }\n ans = min(ans, make_pair(A * sin(L + t) + a, L));\n ans = min(ans, make_pair(A * sin(R + t) + a, R));\n return ans;\n}\npair<long double, long double> get_max(long double s, long double c, long double a, long double L, long double R){\n long double A = hypot(s, c);\n long double t = atan2(c, s);\n pair<long double, long double> ans = make_pair(0, 0);\n long double t1 = PI / 2 - t;\n if (L <= t1 && t1 <= R){\n ans = max(ans, make_pair(A + a, t1));\n }\n ans = max(ans, make_pair(A * sin(L + t) + a, L));\n ans = max(ans, make_pair(A * sin(R + t) + a, R));\n return ans;\n}\nint main(){\n cout << fixed << setprecision(20);\n while (true){\n int n;\n cin >> n;\n if (n == 0){\n break;\n }\n vector<point> P(n);\n for (int i = 0; i < n; i++){\n cin >> P[i].x >> P[i].y;\n }\n vector<long double> T;\n T.push_back(0);\n T.push_back(PI);\n for (int i = 0; i < n; i++){\n for (int j = i + 1; j < n; j++){\n long double t = PI - angle(P[j] - P[i]);\n T.push_back(t);\n long double d = dist(P[i], P[j]);\n if (d > 2.1){\n long double p = asin(2 / d);\n T.push_back(fmod(t + p, PI));\n T.push_back(fmod(t - p + PI, PI));\n }\n }\n }\n sort(T.begin(), T.end());\n int cnt = T.size();\n pair<long double, long double> mn = make_pair(INF, 0);\n pair<long double, long double> mx = make_pair(0, 0);\n for (int i = 0; i < cnt - 1; i++){\n long double t = (T[i] + T[i + 1]) / 2;\n vector<pair<long double, int>> R;\n for (int j = 0; j < n; j++){\n R.push_back(make_pair(P[j].x * sin(t) + P[j].y * cos(t) - 1, ~j));\n R.push_back(make_pair(P[j].x * sin(t) + P[j].y * cos(t) + 1, j));\n }\n sort(R.begin(), R.end());\n long double s = 0, c = 0, a = 0;\n int cnt = 0;\n for (int j = 0; j < n * 2; j++){\n int id = R[j].second;\n int add = -1;\n if (id < 0){\n add = 1;\n id = ~id;\n }\n if (cnt == 0){\n s -= P[id].x;\n c -= P[id].y;\n a++;\n }\n cnt += add;\n if (cnt == 0){\n s += P[id].x;\n c += P[id].y;\n a++;\n }\n }\n mn = min(mn, get_min(s, c, a, T[i], T[i + 1]));\n mx = max(mx, get_max(s, c, a, T[i], T[i + 1]));\n }\n cout << mn.second << endl;\n cout << mx.second << endl;\n }\n}", "accuracy": 1, "time_ms": 1220, "memory_kb": 4288, "score_of_the_acc": -0.972, "final_rank": 16 }, { "submission_id": "aoj_1146_6058874", "code_snippet": "#include <bits/stdc++.h>\n#define pt(x) cout << x << endl;\n#define Mid ((l + r) / 2)\n#define lson (rt << 1)\n#define rson (rt << 1 | 1)\nusing namespace std;\nconst double Pi = acos(-1.0);\nconst double eps = 1e-11;\nstruct Point {\n\tdouble x, y;\n\tPoint() : x(0), y(0) {}\n\tPoint(double x, double y) : x(x), y(y) {}\n\tPoint operator+(const Point &a)const{ return Point(x + a.x, y + a.y); }\n\tPoint operator-(const Point &a)const{ return Point(x - a.x, y - a.y); }\n} a[109];\ntypedef Point Vector;\nstruct line{\n\tPoint a, b;\n\tline() {}\n\tline(const Point &a,const Point &b) : a(a), b(b) {}\n};\n \nstruct circle{\n\tPoint c;\n\tdouble r;\n\tcircle() : c(Point(0,0)), r(0) {}\n\tcircle(const Point &c, double r) : c(c), r(r) {}\n};\nPoint operator*(double c, const Point &a){ return Point(c * a.x, c * a.y); }\ndouble abs(const Point &a){ return sqrt(a.x * a.x + a.y * a.y); }\nPoint rot(const Point &a, double theta){ return Point(a.x * cos(theta) - a.y * sin(theta), a.x * sin(theta) + a.y * cos(theta)); }\ndouble arg(const Point &a){\n\tdouble t = atan2(a.y, a.x);\n\treturn t < 0 ? t + 2 * Pi:t;\n}\nint tangent(const circle &C1,const circle &C2,vector<line> &res){\n\tdouble d = abs(C1.c - C2.c);\n\tif(d < eps) return 0;\n \n\tint c=0;\n\tif(C1.r + C2.r < d - eps){\n\t\tdouble t = acos((C1.r + C2.r) / d);\n\t\tres.push_back(line(C1.c + rot(C1.r / d * (C2.c - C1.c), t), C2.c + rot(C2.r / d * (C1.c - C2.c), t)));\n\t\tres.push_back(line(C1.c + rot(C1.r / d * (C2.c - C1.c),-t), C2.c + rot(C2.r / d * (C1.c - C2.c),-t)));\n\t\tc += 2;\n\t} else if(C1.r + C2.r < d + eps){\n\t\tPoint p = C1.c + C1.r / d * (C2.c - C1.c);\n\t\tres.push_back(line(p, p + rot(C2.c - C1.c, Pi / 2)));\n\t\tc++;\n\t}\n \n\tif(abs(C1.r - C2.r) < d - eps){\n\t\tdouble t1 = acos((C1.r - C2.r) / d), t2 = Pi - t1;\n\t\tres.push_back(line(C1.c + rot(C1.r / d * (C2.c - C1.c), t1), C2.c + rot(C2.r / d * (C1.c - C2.c),-t2)));\n\t\tres.push_back(line(C1.c + rot(C1.r / d * (C2.c - C1.c),-t1), C2.c + rot(C2.r / d * (C1.c - C2.c), t2)));\n\t\tc+=2;\n\t} else if(abs(C1.r - C2.r) < d + eps){\n\t\tPoint p = C1.c + C1.r / d * (C2.c - C1.c);\n\t\tres.push_back(line(p, p + rot(C2.c - C1.c, Pi / 2)));\n\t\tc++;\n\t}\n \n\treturn c;\n}\n \nint n;\ndouble maxn, minn, sima, simi;\ndouble calc(double theta) {\n\tdouble tt[109] = {0};\n\tfor(int k = 1; k <= n; k++) {\n\t\ttt[k] = rot(a[k], theta).y;\n\t}\n\tsort(tt + 1, tt + 1 + n);\n\tdouble mr = 0, sum = 0;\n\tsum = 2.0;\n\tmr = tt[1] + 1.0;\n\tfor(int k = 1; k <= n; k++) {\n\t\tif(tt[k] + 1.0 < mr) continue;\n\t\tif(tt[k] - 1.0 < mr) {\n\t\t\tsum += tt[k] + 1.0 - mr;\n\t\t} else {\n\t\t\tsum += 2.0;\n\t\t}\n\t\tmr = tt[k] + 1.0;\n\t}\n\treturn sum;\n}\ndouble calc_peak(double phi) {\n\tpair<double, int> p[109];\n\tfor(int i = 1; i <= n; i++) {\n\t\tp[i] = make_pair(rot(a[i], phi).y, i);\n\t}\n\tsort(p + 1, p + 1 + n);\n\tint pre = 1;\n\tdouble x = 0, y = 0;\n\tfor(int i = 2; i <= n + 1; i++) {\n\t\tif(i == n + 1 || p[i - 1].first + 1 < p[i].first - 1) {\n\t\t\tx += (a[p[i - 1].second].x - a[p[pre].second].x);\n\t\t\ty += (a[p[i - 1].second].y - a[p[pre].second].y);\n\t\t\tpre = i;\n\t\t}\n\t}\n\tdouble ans = arg({y, x});\n\tif(ans > Pi) ans -= Pi;\n\treturn ans;\n}\n \nvoid work() {\n\tif(n == 0) exit(0);\n\tfor(int i = 1; i <= n; i++) \n\t\tscanf(\"%lf%lf\", &a[i].x, &a[i].y);\n\tmaxn = -1e18;\n\tminn = 1e18;\n\tvector<line> v;\n\tfor(int i = 1; i <= n; i++) {\n\t\tfor(int j = i + 1; j <= n; j++) {\n\t\t\ttangent(circle(a[i], 1.0), circle(a[j], 1.0), v);\n\t\t}\n\t}\n\tvector<double> th;\n\tfor(int i = 0; i < v.size(); i++) {\n\t\tline &l = v[i];\n\t\tdouble tt = arg(l.b - l.a);\n\t\tif(tt < Pi) tt = Pi - tt;\n\t\telse tt = 2 * Pi - tt;\n\t\tth.push_back(tt);\n\t}\n\tth.push_back(0);\n\tth.push_back(Pi);\n\tsort(th.begin(), th.end());\n\tint tot = 0;\n\tfor(int i = 0; i < th.size(); i++) \n\t\tif(i == 0 || th[i] > th[i - 1] + eps) \n\t\t\tth[tot++] = th[i];\n\tth.erase(th.begin() + tot, th.end());\n\tfor(int i = 0; i < tot; i++) {\n\t\tdouble sum = calc(th[i]);\n\t\tif(sum > maxn + eps) {\n\t\t\tmaxn = sum;\n\t\t\tsima = th[i];\n\t\t}\n\t\tif(sum < minn - eps) {\n\t\t\tminn = sum;\n\t\t\tsimi = th[i];\n\t\t}\n\t\tif(i - 1 >= 0) {\n\t\t\tdouble phi0 = (th[i - 1] + th[i]) / 2;\n\t\t\tdouble phi1 = calc_peak(phi0);\n\t\t\tdouble sum = calc(phi1);\n\t\t\tif(sum > maxn + eps) {\n\t\t\t\tmaxn = sum;\n\t\t\t\tsima = phi1;\n\t\t\t}\n\t\t\tif(sum < minn - eps) {\n\t\t\t\tminn = sum;\n\t\t\t\tsimi = phi1;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%.15f\\n%.15f\\n\", simi, sima);\n}\nsigned main()\n{\n\tios :: sync_with_stdio(0);\n\tcin.tie(0);\n\twhile(~scanf(\"%d\", &n)) work(); \n\treturn 0;\n}\n/*\n枚举两个圆柱体相切的位置\n \n*/", "accuracy": 1, "time_ms": 780, "memory_kb": 5016, "score_of_the_acc": -1.0474, "final_rank": 18 }, { "submission_id": "aoj_1146_6036336", "code_snippet": "#include <bits/stdc++.h>\n#define pt(x) cout << x << endl;\n#define Mid ((l + r) / 2)\n#define lson (rt << 1)\n#define rson (rt << 1 | 1)\nusing namespace std;\nconst double Pi = acos(-1.0);\nconst double eps = 1e-11;\nstruct Point {\n\tdouble x, y;\n\tPoint() : x(0), y(0) {}\n\tPoint(double x, double y) : x(x), y(y) {}\n\tPoint operator+(const Point &a)const{ return Point(x + a.x, y + a.y); }\n\tPoint operator-(const Point &a)const{ return Point(x - a.x, y - a.y); }\n} a[109];\ntypedef Point Vector;\nstruct line{\n\tPoint a, b;\n\tline() {}\n\tline(const Point &a,const Point &b) : a(a), b(b) {}\n};\n\nstruct circle{\n\tPoint c;\n\tdouble r;\n\tcircle() : c(Point(0,0)), r(0) {}\n\tcircle(const Point &c, double r) : c(c), r(r) {}\n};\nPoint operator*(double c, const Point &a){ return Point(c * a.x, c * a.y); }\n//Point operator/(const Point &a, const double c){ return Point(c * a.x, c * a.y); }\ndouble abs(const Point &a){ return sqrt(a.x * a.x + a.y * a.y); }\nPoint rot(const Point &a, double theta){ return Point(a.x * cos(theta) - a.y * sin(theta), a.x * sin(theta) + a.y * cos(theta)); }\ndouble arg(const Point &a){\n\tdouble t = atan2(a.y, a.x);\n\treturn t < 0 ? t + 2 * Pi:t;\n}\nint tangent(const circle &C1,const circle &C2,vector<line> &res){\n\tdouble d = abs(C1.c - C2.c);\n\tif(d < eps) return 0;\n\n\tint c=0;\n\tif(C1.r + C2.r < d - eps){\n\t\tdouble t = acos((C1.r + C2.r) / d);\n\t\tres.push_back(line(C1.c + rot(C1.r / d * (C2.c - C1.c), t), C2.c + rot(C2.r / d * (C1.c - C2.c), t)));\n\t\tres.push_back(line(C1.c + rot(C1.r / d * (C2.c - C1.c),-t), C2.c + rot(C2.r / d * (C1.c - C2.c),-t)));\n\t\tc += 2;\n\t} else if(C1.r + C2.r < d + eps){\n\t\tPoint p = C1.c + C1.r / d * (C2.c - C1.c);\n\t\tres.push_back(line(p, p + rot(C2.c - C1.c, Pi / 2)));\n\t\tc++;\n\t}\n\n\tif(abs(C1.r - C2.r) < d - eps){\n\t\tdouble t1 = acos((C1.r - C2.r) / d), t2 = Pi - t1;\n\t\tres.push_back(line(C1.c + rot(C1.r / d * (C2.c - C1.c), t1), C2.c + rot(C2.r / d * (C1.c - C2.c),-t2)));\n\t\tres.push_back(line(C1.c + rot(C1.r / d * (C2.c - C1.c),-t1), C2.c + rot(C2.r / d * (C1.c - C2.c), t2)));\n\t\tc+=2;\n\t} else if(abs(C1.r - C2.r) < d + eps){\n\t\tPoint p = C1.c + C1.r / d * (C2.c - C1.c);\n\t\tres.push_back(line(p, p + rot(C2.c - C1.c, Pi / 2)));\n\t\tc++;\n\t}\n\n\treturn c;\n}\n\nint n;\ndouble maxn, minn, sima, simi;\ndouble calc(double theta) {\n\tdouble tt[109] = {0};\n\tfor(int k = 1; k <= n; k++) {\n\t\ttt[k] = rot(a[k], theta).y;\n\t}\n\t\n\tsort(tt + 1, tt + 1 + n);\n\tdouble mr = 0, sum = 0;\n\tsum = 2.0;\n\tmr = tt[1] + 1.0;\n\tfor(int k = 1; k <= n; k++) {\n\t\tif(tt[k] + 1.0 < mr) continue;\n\t\tif(tt[k] - 1.0 < mr) {\n\t\t\tsum += tt[k] + 1.0 - mr;\n\t\t} else {\n\t\t\tsum += 2.0;\n\t\t}\n\t\tmr = tt[k] + 1.0;\n\t}\n\treturn sum;\n}\ndouble calc_peak(double phi) {\n\tpair<double, int> p[109];\n\tfor(int i = 1; i <= n; i++) {\n\t\tp[i] = make_pair(rot(a[i], phi).y, i);\n\t}\n\tsort(p + 1, p + 1 + n);\n\tint pre = 1;\n\tdouble x = 0, y = 0;\n\tfor(int i = 2; i <= n + 1; i++) {\n\t\tif(i == n + 1 || p[i - 1].first + 1 < p[i].first - 1) {\n\t\t\t//dl/dw = d*cost*cosw - d*sint*sinw\n\t\t\tdouble d = abs(a[p[i - 1].second] - a[p[pre].second]);\n\t\t\tdouble t = arg(a[p[i - 1].second] - a[p[pre].second]);\n\t\t\tx += d * cos(t);\n\t\t\ty += d * sin(t);\n\t\t\tpre = i;\n\t\t}\n\t}\n\tdouble ans = arg({y, x});\n\tif(ans > Pi) ans -= Pi;\n\treturn ans;\n}\n\nvoid work() {\n\tif(n == 0) exit(0);\n\tfor(int i = 1; i <= n; i++) \n\t\tscanf(\"%lf%lf\", &a[i].x, &a[i].y);\n\tmaxn = -1e18;\n\tminn = 1e18;\n\tvector<line> v;\n\tfor(int i = 1; i <= n; i++) {\n\t\tfor(int j = i + 1; j <= n; j++) {\n\t\t\ttangent(circle(a[i], 1.0), circle(a[j], 1.0), v);\n\t\t}\n\t}\n\tvector<double> th;\n\tfor(int i = 0; i < v.size(); i++) {\n\t\tline &l = v[i];\n\t\tdouble tt = arg(l.b - l.a);\n\t\tif(tt < Pi) tt = Pi - tt;\n\t\telse tt = 2 * Pi - tt;\n\t\tth.push_back(tt);\n\t}\n\tth.push_back(0);\n\tth.push_back(Pi);\n\tsort(th.begin(), th.end());\n\tint tot = 0;\n\tfor(int i = 0; i < th.size(); i++) \n\t\tif(i == 0 || th[i] > th[i - 1] + eps) \n\t\t\tth[tot++] = th[i];\n\tth.erase(th.begin() + tot, th.end());\n\tfor(int i = 0; i < tot; i++) {\n\t\tdouble sum = calc(th[i]);\n\t\tif(sum > maxn + eps) {\n\t\t\tmaxn = sum;\n\t\t\tsima = th[i];\n\t\t}\n\t\tif(sum < minn - eps) {\n\t\t\tminn = sum;\n\t\t\tsimi = th[i];\n\t\t}\n\t\tif(i - 1 >= 0) {\n\t\t\tdouble phi0 = (th[i - 1] + th[i]) / 2;\n\t\t\tdouble phi1 = calc_peak(phi0);\n\t\t\tdouble sum = calc(phi1);\n\t\t\tif(sum > maxn + eps) {\n\t\t\t\tmaxn = sum;\n\t\t\t\tsima = phi1;\n\t\t\t}\n\t\t\tif(sum < minn - eps) {\n\t\t\t\tminn = sum;\n\t\t\t\tsimi = phi1;\n\t\t\t}\n\t\t}\n\t}\n//\tprintf(\"%.15f %.15f\\n\", minn, maxn);\n\tprintf(\"%.15f\\n%.15f\\n\", simi, sima);\n}\nsigned main()\n{\n//\tfreopen(\"data.in\", \"r\", stdin);\n\tios :: sync_with_stdio(0);\n\tcin.tie(0);\n\twhile(~scanf(\"%d\", &n)) work(); \n\treturn 0;\n}\n/*\n枚举两个圆柱体相切的位置\n \n*/", "accuracy": 1, "time_ms": 370, "memory_kb": 5400, "score_of_the_acc": -1.045, "final_rank": 17 }, { "submission_id": "aoj_1146_4851720", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n//#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define EPS 0.000000000001\n#define SIZE 105\n\nstruct Point{\n\tPoint(long double arg_x,long double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (long double a){ return Point(a*x,a*y); }\n\tPoint operator / (long double a){ return Point(x/a,y/a); }\n\n\tlong double abs(){ return sqrt(norm()); }\n\tlong double norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\t\treturn x != p.x? x < p.x: y < p.y;\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3Lf,%.3Lf)\\n\",x,y);\n\t}\n\n\tlong double x,y;\n};\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\nstruct Circle{\n\tPoint center,base_p;\n\tlong double r;\n};\n\nstruct Rad{\n\tRad(long double arg_rad){\n\n\t\trad = arg_rad;\n\t}\n\tbool operator<(const struct Rad &arg) const{\n\n\t\treturn rad < arg.rad;\n\t}\n\tbool operator==(const struct Rad &arg) const{\n\n\t\treturn fabs(rad-arg.rad) < EPS;\n\t}\n\tlong double rad;\n};\n\n\nstruct TAN_P{\n\tTAN_P(Point arg_p,bool arg_is_C1){\n\t\tp = arg_p;\n\t\tis_C1 = arg_is_C1;\n\t}\n\tPoint p;\n\tbool is_C1;\n};\n\nstruct Info{\n\tInfo(Point arg_p,int arg_index){\n\t\tp = arg_p;\n\t\tindex = arg_index;\n\t}\n\tbool operator<(const struct Info &arg) const{\n\n\t\treturn p < arg.p;\n\t}\n\tPoint p;\n\tint index;\n};\n\nint N;\nlong double R = 1.0;\nlong double NUM = 10000;\nlong double DIST[SIZE][SIZE];\nCircle C[SIZE];\n\n\nlong double calc_dist(Point A,Point B){\n\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\n\nlong double norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\nlong double abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\nlong double cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\nlong double dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nlong double calc_slope(Line A){\n\n\tif(fabs(A.p[0].x-A.p[1].x) < EPS){\n\n\t\treturn DBL_MAX;\n\n\t}else if(fabs(A.p[0].y-A.p[1].y) < EPS){\n\n\t\treturn 0;\n\n\t}else{\n\n\t\treturn (A.p[1].y-A.p[0].y)/(A.p[1].x-A.p[0].x);\n\t}\n}\n\n\n\n\n//C1,C2の接点を返却する関数\nvector<TAN_P> getContact(Circle C1,Circle C2){\n\n\tvector<TAN_P> ret;\n\n\tfor(int loop = 0; loop < 2; loop++){\n\n\t\tlong double p = C2.center.x-C1.center.x;\n\t\tlong double q = C2.center.y-C1.center.y;\n\n\t\tlong double A = p*p+q*q;\n\n\t\tlong double n_1 = (q*C1.r*(C1.r+C2.r)-p*C1.r*sqrt(A-(C1.r+C2.r)*(C1.r+C2.r)))/(A)+C1.center.y;\n\t\tlong double n_2 = (q*C1.r*(C1.r+C2.r)+p*C1.r*sqrt(A-(C1.r+C2.r)*(C1.r+C2.r)))/(A)+C1.center.y;\n\n\t\tlong double m_1 = (p*C1.r*(C1.r+C2.r)+q*C1.r*sqrt(A-(C1.r+C2.r)*(C1.r+C2.r)))/(A)+C1.center.x;\n\t\tlong double m_2 = (p*C1.r*(C1.r+C2.r)-q*C1.r*sqrt(A-(C1.r+C2.r)*(C1.r+C2.r)))/(A)+C1.center.x;\n\n\t\tif(A-(C1.r+C2.r)*(C1.r+C2.r) >= 0){\n\t\t\tret.push_back(TAN_P(Point(m_1,n_1),loop == 0));\n\t\t\tret.push_back(TAN_P(Point(m_2,n_2),loop == 0));\n\t\t}\n\n\t\tlong double n_3 = (q*C1.r*(C1.r-C2.r)-p*C1.r*sqrt(A-(C1.r-C2.r)*(C1.r-C2.r)))/(A)+C1.center.y;\n\t\tlong double n_4 = (q*C1.r*(C1.r-C2.r)+p*C1.r*sqrt(A-(C1.r-C2.r)*(C1.r-C2.r)))/(A)+C1.center.y;\n\n\t\tlong double m_3 = (p*C1.r*(C1.r-C2.r)+q*C1.r*sqrt(A-(C1.r-C2.r)*(C1.r-C2.r)))/(A)+C1.center.x;\n\t\tlong double m_4 = (p*C1.r*(C1.r-C2.r)-q*C1.r*sqrt(A-(C1.r-C2.r)*(C1.r-C2.r)))/(A)+C1.center.x;\n\n\t\tif(A-(C1.r-C2.r)*(C1.r-C2.r) >= 0){\n\t\t\tret.push_back(TAN_P(Point(m_3,n_3),loop==0));\n\t\t\tret.push_back(TAN_P(Point(m_4,n_4),loop==0));\n\t\t}\n\n\t\tswap(C1,C2);\n\t}\n\n\treturn ret;\n}\n\n//点のradを求める関数\nlong double calc_rad(Point p){\n\n\tif(p.y == 0){\n\n\t\tif(p.x > 0){\n\n\t\t\treturn 0;\n\n\t\t}else{ //p.x < 0\n\n\t\t\treturn M_PI;\n\t\t}\n\n\t}else if(p.x == 0){\n\n\t\tif(p.y > 0){\n\n\t\t\treturn M_PI/2.0;\n\t\t}else{\n\n\n\t\t\treturn 3*M_PI/2.0;\n\t\t}\n\n\t}else{\n\n\t\tlong double base = atan(fabs(p.y)/fabs(p.x));\n\n\t\tif(p.x > 0){\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn base;\n\n\t\t\t}else{ //p.y < 0\n\n\t\t\t\treturn 2*M_PI-base;\n\t\t\t}\n\n\t\t}else{ //p.x < 0\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn M_PI-base;\n\n\t\t\t}else{\n\n\t\t\t\treturn base+M_PI;\n\t\t\t}\n\t\t}\n\t}\n}\n\n\nint func(long double x1,long double y1,long double x2, long double y2, long double xp, long double yp){\n\tlong double naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//★★直線ではなく、線分の交差判定★★\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\nlong double calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n//線分ではなく直線と点の距離\nlong double getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\nlong double getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\nbool on_arc(Circle C1,Point p){\n\n\treturn fabs(calc_dist(C1.center,p)-C1.r) < EPS;\n}\n\nbool contain_check(Circle C1,Line tmp_line){\n\n\tif(getDistanceSP(tmp_line,C1.center)+EPS < C1.r){\n\n\t\treturn true;\n\t}else{\n\n\t\treturn false;\n\t}\n}\n\n\n//交点を求める関数\nPoint calc_Cross_Point(long double x1,long double x2,long double x3,long double x4,long double y1,long double y2,long double y3,long double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\n\n//点pを通る傾きtan(rad)の直線とy = -(1/tan(rad))x+kの交点を求める\nPoint calc_point(Point p,double rad){\n\n\tlong double slope1 = tan(rad);\n\n\tLine line1 = Line(Point(p.x-NUM,p.y-NUM*slope1),Point(p.x+NUM,p.y+NUM*slope1));\n\n\n\tlong double slope2 = -(1.0/slope1);\n\n\tLine line2 = Line(Point(-NUM,-NUM*slope2),Point(NUM,NUM*slope2));\n\n\treturn calc_Cross_Point(line1,line2);\n}\n\n//2つのvectorがなすラジアンを求める関数\nlong double calc_rad(Vector vec1,Vector vec2){\n\n\tlong double tmp = dot(vec1,vec2)/(abs(vec1)*abs(vec2));\n\n\tif(fabs(tmp+1.0) < EPS){\n\n\t\treturn M_PI;\n\t}\n\n\tif(fabs(tmp-1.0) < EPS){\n\n\t\treturn 0.0;\n\t}\n\n\treturn acos(dot(vec1,vec2)/(abs(vec1)*abs(vec2)));\n}\n\n//3点がなすラジアンを求める関数(ccw(base,a,b) == CCW)\nlong double calc_rad(Point base,Point a,Point b){\n\n\tVector vec1 = b-base;\n\tVector vec2 = a-base;\n\n\treturn calc_rad(vec1,vec2);\n}\n\n\n\n//θ=baseの近くで微分する\nlong double calc_rad(long double base){\n\n\tvector<Info> info;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tinfo.push_back(Info(calc_point(C[i].center,base),i));\n\t}\n\n\tsort(info.begin(),info.end());\n\n\tlong double A = 0,B = 0;\n\n\tfor(int i = 1; i < info.size(); i++){\n\n\t\tif(calc_dist(info[i-1].p,info[i].p) > 2*R+EPS)continue;\n\n\t\tlong double tmp_dist = DIST[info[i-1].index][info[i].index];\n\t\tlong double tmp_rad;\n\n\t\tif(ccw(C[info[i].index].center,C[info[i].index].base_p,C[info[i-1].index].center) == COUNTER_CLOCKWISE){\n\n\t\t\ttmp_rad = calc_rad(C[info[i].index].center,C[info[i].index].base_p,C[info[i-1].index].center);\n\n\t\t}else{\n\n\t\t\ttmp_rad = 2*M_PI-calc_rad(C[info[i].index].center,C[info[i-1].index].center,C[info[i].index].base_p);\n\t\t}\n\n\t\tA += tmp_dist*sin(tmp_rad);\n\t\tB += tmp_dist*cos(tmp_rad);\n\t}\n\n\tlong double ret = calc_rad(Point(A,-B));\n\n\n\tif(ret > M_PI){\n\t\tret -= M_PI;\n\t}\n\treturn ret;\n}\n\n\nlong double calc_len(long double rad){\n\n\tvector<Point> V;\n\tlong double ret = 2.0;\n\n\tif(fabs(rad) < EPS || fabs(rad-M_PI) < EPS){\n\n\t\tfor(int i = 0; i < N; i++){\n\n\t\t\tV.push_back(Point(0,C[i].center.y));\n\t\t}\n\t}else if(fabs(rad-M_PI/2.0) < EPS){\n\n\t\tfor(int i = 0; i < N; i++){\n\n\t\t\tV.push_back(Point(C[i].center.x,0));\n\t\t}\n\n\t}else{\n\n\t\tfor(int i = 0; i < N; i++){\n\n\t\t\tV.push_back(calc_point(C[i].center,rad));\n\t\t}\n\t}\n\n\tsort(V.begin(),V.end());\n\n\tlong double L = 2;\n\n\tfor(int i = 1; i < V.size(); i++){\n\n\t\tret += min(L,calc_dist(V[i],V[i-1]));\n\t}\n\n\treturn ret;\n}\n\nvoid func(){\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%Lf %Lf\",&C[i].center.x,&C[i].center.y);\n\t\tC[i].r = R;\n\t\tC[i].base_p = Point(C[i].center.x+10,C[i].center.y);\n\t}\n\tif(N == 1){\n\n\t\tprintf(\"0.000000000000000\\n\");\n\t\tprintf(\"0.000000000000000\\n\");\n\t\treturn;\n\t}\n\n\tvector<Rad> RAD;\n\tRAD.push_back(Rad(0));\n\tRAD.push_back(Rad(M_PI/2.0)); //cos(θ)が0\n\tRAD.push_back(Rad(M_PI));\n\n\tlong double tmp_x = 10; //rad計算用\n\tlong double tmp_y;\n\n\tCircle C1,C2;\n\n\tVector tmp_vec,vec_i,vec_k;\n\n\n\tfor(int i = 0; i < N-1; i++){\n\t\tfor(int k = i+1; k < N; k++){\n\n\t\t\tDIST[i][k] = calc_dist(C[i].center,C[k].center);\n\t\t\tDIST[k][i] = DIST[i][k];\n\n\t\t\tvector<TAN_P> v_tan = getContact(C[i],C[k]);\n\t\t\tfor(int a = 0; a < v_tan.size()-1; a++){\n\t\t\t\tif(!v_tan[a].is_C1 || !on_arc(C[i],v_tan[a].p))continue;\n\t\t\t\tfor(int b = a+1; b < v_tan.size(); b++){\n\t\t\t\t\tif(v_tan[b].is_C1 || !on_arc(C[k],v_tan[b].p))continue;\n\n\t\t\t\t\tLine tmp_line = Line(v_tan[a].p,v_tan[b].p);\n\t\t\t\t\tif(contain_check(C1,tmp_line) || contain_check(C2,tmp_line))continue;\n\n\t\t\t\t\ttmp_vec = v_tan[a].p-v_tan[b].p;\n\t\t\t\t\tvec_i = v_tan[a].p-C[i].center;\n\t\t\t\t\tvec_k = v_tan[b].p-C[k].center;\n\n\t\t\t\t\tif(fabs(dot(tmp_vec,vec_i) > EPS || fabs(dot(tmp_vec,vec_k)) > EPS))continue;\n\n\t\t\t\t\tlong double tmp_slope = calc_slope(tmp_line);\n\t\t\t\t\ttmp_y = tmp_x*tmp_slope;\n\t\t\t\t\tlong double tmp_rad = calc_rad(Point(tmp_x,tmp_y));\n\n\t\t\t\t\t//★注意★\n\t\t\t\t\tif(tmp_rad > M_PI+EPS){\n\n\t\t\t\t\t\ttmp_rad -= M_PI;\n\t\t\t\t\t}\n\t\t\t\t\t//★★★★y = xのradをπ/4とする方向で、解を保存する段階で帳尻を合わせる★★★★\n\n\t\t\t\t\tRAD.push_back(Rad(tmp_rad));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tsort(RAD.begin(),RAD.end());\n\tRAD.erase(unique(RAD.begin(),RAD.end()),RAD.end());\n\n\tlong double max_len = -BIG_NUM,min_len = BIG_NUM;\n\tlong double max_rad,min_rad;\n\n\tlong double tmp_len;\n\n\tfor(int i = 0; i < RAD.size(); i++){\n\n\t\tif(i > 0){\n\t\t\ttmp_len = calc_len(RAD[i].rad);\n\t\t\tif(tmp_len > max_len+EPS){\n\n\t\t\t\tmax_len = tmp_len;\n\t\t\t\tmax_rad = M_PI-RAD[i].rad;\n\t\t\t}\n\t\t\tif(tmp_len+EPS < min_len){\n\t\t\t\tmin_len = tmp_len;\n\t\t\t\tmin_rad = M_PI-RAD[i].rad;\n\t\t\t}\n\t\t}\n\n\t\tif(i == RAD.size()-1)break;\n\n\t\tlong double tmp_rad = (RAD[i].rad+RAD[i+1].rad);\n\t\ttmp_rad = calc_rad(tmp_rad);\n\n\t\ttmp_len = calc_len(tmp_rad);\n\n\t\tif(tmp_len > max_len+EPS){\n\t\t\tmax_len = tmp_len;\n\t\t\tmax_rad = M_PI-tmp_rad;\n\t\t}\n\t\tif(tmp_len+EPS < min_len){\n\t\t\tmin_len = tmp_len;\n\t\t\tmin_rad = M_PI-tmp_rad;\n\t\t}\n\t}\n\n\tprintf(\"%.15Lf\\n\",min_rad);\n\tprintf(\"%.15Lf\\n\",max_rad);\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 4400, "memory_kb": 4460, "score_of_the_acc": -1.768, "final_rank": 20 }, { "submission_id": "aoj_1146_2850999", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\nconst double EPS = 1e-12;\nconst double INF = 1e18;\nconst double PI = acos(-1);\n\n//range : [-PI/2, PI/2]\nvector<double> special_angle(vector<double> &x, vector<double> &y){\n int n = x.size();\n vector<double> ret;\n for(int i=0; i<n; i++){\n for(int j=i+1; j<n; j++){\n double narg[2];\n double a = x[i] -x[j];\n double b = y[i] -y[j];\n //中心が重なる角度\n narg[0] = (abs(a) < EPS)? PI/2 : atan(-b/a);\n ret.push_back(narg[0]);\n //端が重なる角度\n if(abs(a) < EPS){\n \tnarg[0] = acos(2/b);\n \tnarg[1] = acos(-2/b);\n }else{\n \tnarg[0] = asin(2/sqrt(a*a +b*b)) -atan(b/a);\n \tnarg[1] = asin(-2/sqrt(a*a +b*b)) -atan(b/a);\n }\n for(int k=0; k<2; k++){\n while(narg[k] < -PI/2) narg[k] += PI;\n while(narg[k] > PI/2) narg[k] -= PI;\n ret.push_back(narg[k]);\n }\n }\n }\n \n ret.push_back(PI/2);\n ret.push_back(0);\n ret.push_back(-PI/2);\n sort(ret.begin(), ret.end());\n ret.erase(unique(ret.begin(), ret.end()), ret.end());\n return ret;\n}\n\nvector<double> projection(double angle, vector<double> &x, vector<double> &y){\n\tint n = x.size();\n\tvector<double> ret(n);\n\tfor(int i=0; i<n; i++){\n\t\tret[i] = x[i]*sin(angle) +y[i]*cos(angle);\n\t}\n return ret;\n}\n\nvector<int> getorder(double angle, vector<double> &x, vector<double> &y){\n int n = x.size();\n vector<int> ret(n);\n vector<double> dist = projection(angle, x, y);\n vector<pair<double, int> > ord(n);\n for(int i=0; i<n; i++){\n ord[i] = make_pair(dist[i], i);\n }\n sort(ord.begin(), ord.end());\n for(int i=0; i<n; i++){\n ret[i] = ord[i].second;\n }\n return ret;\n}\n\ndouble getwidth(double angle, vector<double> &x, vector<double> &y){\n vector<int> order = getorder(angle, x, y);\n vector<double> dist = projection(angle, x, y);\n double ret = 2;\n for(int i=0; i<(int)x.size()-1; i++){\n \tdouble d = dist[order[i+1]] -dist[order[i]];\n if(d < 2) ret += d;\n else ret += 2;\n }\n return ret;\n}\n\npair<double, double> solve(vector<double> &x, vector<double> &y){\n vector<double> angle = special_angle(x, y);\n vector<pair<double, double> > cand; //pair<angle, width>\n \n for(int i=0; i<(int)angle.size(); i++){\n cand.push_back(make_pair(angle[i], getwidth(angle[i], x, y)));\n }\n for(int i=0; i<(int)angle.size()-1; i++){\n double mid = (angle[i] +angle[i+1])/2;\n vector<int> order = getorder(mid, x, y);\n vector<double> dist = projection(mid, x, y);\n //f(t) = a*sin(t) +b*cos(t) +c\n double a=0, b=0;\n for(int j=0; j<(int)x.size()-1; j++){\n \tdouble d = dist[order[j+1]] -dist[order[j]];\n \tif(d < 2){\n \t\ta += x[order[j+1]] -x[order[j]];\n \t\tb += y[order[j+1]] -y[order[j]];\n \t}\n }\n //f'(t) = a*cos(t) -b*sin(t) = 0 より\n //tan(t) = a/b\n if(abs(b) < EPS) continue;\n double theta = atan(a/b);\n if(angle[i] -EPS < theta && theta < angle[i+1] +EPS){\n \tcand.push_back(make_pair(theta, getwidth(theta, x, y)));\n }\n }\n \n double wmin=INF, wmax=0;\n double amin=INF, amax=INF;\n for(int i=0; i<(int)cand.size(); i++){\n double theta = cand[i].first;\n double width = cand[i].second;\n if(width < wmin){\n wmin = width;\n amin = theta;\n }\n if(width > wmax){\n wmax = width;\n amax = theta;\n }\n }\n \n //[0, PI]に変換\n if(abs(amin)<EPS) amin = 0;\n if(abs(amax)<EPS) amax = 0;\n if(amin < 0) amin += PI;\n if(amax < 0) amax += PI;\n return make_pair(amin, amax);\n}\n\nint main(){\n while(1){\n int n;\n cin >> n;\n if(n==0) break;\n \n vector<double> x(n),y(n);\n for(int i=0; i<n; i++){\n cin >> x[i] >> y[i];\n }\n pair<double, double> ans = solve(x, y);\n cout << fixed;\n cout << setprecision(12);\n cout << ans.first << endl << ans.second << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 3828, "score_of_the_acc": -0.6215, "final_rank": 6 }, { "submission_id": "aoj_1146_2475051", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing F = double;\n\nstruct Point {F x, y;};\n\nconst F PI = acos(-1);\nconst F INF = 1e9;\n\nint N;\nvector<Point> P;\n\nF tune(auto a) {\n while(a < 0) a += PI;\n while(PI < a) a -= PI;\n return a;\n}\n\nF projection(auto p, auto a) {\n return p.x * sin(a) + p.y * cos(a);\n}\n\ntuple<F, F, F> coefficient(auto a) {\n vector<pair<F, int>> lx;\n for(auto i = 0; i < P.size(); ++i) lx.emplace_back(projection(P[i], a) - 1, i);\n sort(begin(lx), end(lx));\n\n vector<pair<int, int>> shadow;\n shadow.emplace_back(lx.front().second, lx.front().second);\n for(auto i: lx) {\n auto rx = projection(P[shadow.back().second], a) + 1;\n if(rx < i.first) shadow.emplace_back(i.second, i.second);\n else shadow.back().second = i.second;\n }\n\n F A = 0, B = 0, C = 0;\n for(auto s: shadow) {\n auto l = P[s.first];\n auto r = P[s.second];\n A += r.x - l.x;\n B += r.y - l.y;\n C += 1 - -1;\n }\n return make_tuple(A, B, C);\n}\n\nvector<F> solve() {\n vector<F> angle = {0, PI};\n for(auto j = 0; j < N; ++j) for(auto i = 0; i < j; ++i) {\n auto dx = P[i].x - P[j].x;\n auto dy = P[i].y - P[j].y;\n auto d = hypot(dx, dy);\n auto a = atan2(dy, dx);\n angle.emplace_back(tune(-a));\n angle.emplace_back(tune(asin(2 / d) - a));\n angle.emplace_back(tune(asin(-2 / d) - a));\n }\n sort(begin(angle), end(angle));\n angle.erase(unique(begin(angle), end(angle)), end(angle));\n\n F a_min = INF, a_max = -INF;\n F s_min = INF, s_max = -INF;\n for(auto i = 1; i < angle.size(); ++i) {\n auto low = angle[i - 1];\n auto high = angle[i];\n auto middle = (low + high) / 2;\n\n F a, b, c;\n tie(a, b, c) = coefficient(middle);\n\n for(auto i: {low, tune(PI / 2 - atan2(b, a))}) if(low <= i && i <= high) {\n auto s = a * sin(i) + b * cos(i) + c;\n if(s_min > s) {\n s_min = s;\n a_min = i;\n }\n if(s_max < s) {\n s_max = s;\n a_max = i;\n }\n }\n }\n\n return {a_min, a_max};\n}\n\nint main() {\n while(cin >> N, N) {\n P = vector<Point>(N);\n for(auto& i: P) cin >> i.x >> i.y;\n\n for(auto i: solve()) cout << setprecision(15) << fixed << i << endl;\n }\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3884, "score_of_the_acc": -0.6259, "final_rank": 7 }, { "submission_id": "aoj_1146_2475050", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing F = double;\n\nstruct Point {F x, y;};\nstruct Interval {\n F lx, rx;\n int l, r;\n Interval(F lx, F rx, int l, int r) : lx(lx), rx(rx), l(l), r(r) {}\n bool operator<(auto o) const {\n if(lx != o.lx) return lx < o.lx;\n if(rx != o.rx) return rx < o.rx;\n if(l != o.l) return l < o.l;\n return r < o.r;\n }\n};\n\nconst F PI = acos(-1);\nconst F INF = 1e9;\n\nint N;\nvector<Point> P;\n\nF tune(auto a) {\n while(a < 0) a += PI;\n while(PI < a) a -= PI;\n return a;\n}\n\nF projection(auto p, auto a) {\n return p.x * sin(a) + p.y * cos(a);\n}\n\ntuple<F, F, F> coefficient(auto a) {\n vector<pair<F, int>> lx;\n for(auto i = 0; i < P.size(); ++i) lx.emplace_back(projection(P[i], a) - 1, i);\n sort(begin(lx), end(lx));\n\n vector<pair<int, int>> shadow;\n shadow.emplace_back(lx.front().second, lx.front().second);\n for(auto i: lx) {\n auto rx = projection(P[shadow.back().second], a) + 1;\n if(rx < i.first) shadow.emplace_back(i.second, i.second);\n else shadow.back().second = i.second;\n }\n\n F A = 0, B = 0, C = 0;\n for(auto s: shadow) {\n auto l = P[s.first];\n auto r = P[s.second];\n A += r.x - l.x;\n B += r.y - l.y;\n C += 1 - -1;\n }\n return make_tuple(A, B, C);\n}\n\nvector<F> solve() {\n vector<F> angle = {0, PI};\n for(auto j = 0; j < N; ++j) for(auto i = 0; i < j; ++i) {\n auto dx = P[i].x - P[j].x;\n auto dy = P[i].y - P[j].y;\n auto d = hypot(dx, dy);\n auto a = atan2(dy, dx);\n angle.emplace_back(tune(-a));\n angle.emplace_back(tune(asin(2 / d) - a));\n angle.emplace_back(tune(asin(-2 / d) - a));\n }\n sort(begin(angle), end(angle));\n angle.erase(unique(begin(angle), end(angle)), end(angle));\n\n F a_min = INF, a_max = -INF;\n F s_min = INF, s_max = -INF;\n for(auto i = 1; i < angle.size(); ++i) {\n auto low = angle[i - 1];\n auto high = angle[i];\n auto middle = (low + high) / 2;\n\n F a, b, c;\n tie(a, b, c) = coefficient(middle);\n\n for(auto i: {low, tune(PI / 2 - atan2(b, a))}) if(low <= i && i <= high) {\n auto s = a * sin(i) + b * cos(i) + c;\n if(s_min > s) {\n s_min = s;\n a_min = i;\n }\n if(s_max < s) {\n s_max = s;\n a_max = i;\n }\n }\n }\n\n return {a_min, a_max};\n}\n\nint main() {\n while(cin >> N, N) {\n P = vector<Point>(N);\n for(auto& i: P) cin >> i.x >> i.y;\n\n for(auto i: solve()) cout << setprecision(15) << fixed << i << endl;\n }\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3808, "score_of_the_acc": -0.6071, "final_rank": 4 }, { "submission_id": "aoj_1146_2475043", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing F = double;\n\nstruct Point {F x, y;};\nstruct Interval {\n F lx, rx;\n int l, r;\n Interval(F lx, F rx, int l, int r) : lx(lx), rx(rx), l(l), r(r) {}\n bool operator<(auto o) const {\n if(lx != o.lx) return lx < o.lx;\n if(rx != o.rx) return rx < o.rx;\n if(l != o.l) return l < o.l;\n return r < o.r;\n }\n};\n\nconst F PI = acos(-1);\nconst F INF = 1e9;\n\nint N;\nvector<Point> P;\n\nF tune(auto a) {\n while(a < 0) a += PI;\n while(PI < a) a -= PI;\n return a;\n}\n\nF projection(auto p, auto a) {\n return p.x * sin(a) + p.y * cos(a);\n}\n\ntuple<F, F, F> coefficient(auto a) {\n vector<pair<F, int>> lx;\n for(auto i = 0; i < P.size(); ++i) lx.emplace_back(projection(P[i], a) - 1, i);\n sort(begin(lx), end(lx));\n\n vector<pair<int, int>> shadow;\n shadow.emplace_back(lx.front().second, lx.front().second);\n for(auto i: lx) {\n auto rx = projection(P[shadow.back().second], a) + 1;\n if(rx < i.first) shadow.emplace_back(i.second, i.second);\n else shadow.back().second = i.second;\n }\n\n F A = 0, B = 0, C = 0;\n for(auto s: shadow) {\n auto l = P[s.first];\n auto r = P[s.second];\n A += r.x - l.x;\n B += r.y - l.y;\n C += 1 - -1;\n }\n return make_tuple(A, B, C);\n}\n\nvector<F> solve() {\n vector<F> angle = {0, PI};\n for(auto j = 0; j < N; ++j) for(auto i = 0; i < j; ++i) {\n auto dx = P[i].x - P[j].x;\n auto dy = P[i].y - P[j].y;\n auto d = hypot(dx, dy);\n auto a = atan2(dy, dx);\n angle.emplace_back(tune(-a));\n angle.emplace_back(tune(asin(2 / d) - a));\n angle.emplace_back(tune(asin(-2 / d) - a));\n }\n sort(begin(angle), end(angle));\n angle.erase(unique(begin(angle), end(angle)), end(angle));\n\n F a_min = INF, a_max = -INF;\n F s_min = INF, s_max = -INF;\n for(auto i = 1; i < angle.size(); ++i) {\n auto low = angle[i - 1];\n auto high = angle[i];\n auto middle = (low + high) / 2;\n\n F a, b, c;\n tie(a, b, c) = coefficient(middle);\n\n for(auto i: {low, tune(PI / 2 - atan2(b, a)), high}) if(low <= i && i <= high) {\n auto s = a * sin(i) + b * cos(i) + c;\n if(s_min > s) {\n s_min = s;\n a_min = i;\n }\n if(s_max < s) {\n s_max = s;\n a_max = i;\n }\n }\n }\n\n return {a_min, a_max};\n}\n\nint main() {\n while(cin >> N, N) {\n P = vector<Point>(N);\n for(auto& i: P) cin >> i.x >> i.y;\n\n for(auto i: solve()) cout << setprecision(15) << fixed << i << endl;\n }\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3832, "score_of_the_acc": -0.613, "final_rank": 5 }, { "submission_id": "aoj_1146_1859160", "code_snippet": "#include <bits/stdc++.h>\n\n#define _overload(_1,_2,_3,name,...) name\n#define _rep(i,n) _range(i,0,n)\n#define _range(i,a,b) for(int i=int(a);i<int(b);++i)\n#define rep(...) _overload(__VA_ARGS__,_range,_rep,)(__VA_ARGS__)\n\n#define _all(arg) begin(arg),end(arg)\n#define uniq(arg) (sort(_all(arg)),(arg).erase(unique(_all(arg)),end(arg)),arg)\n\ntemplate<class T>bool chmax(T &a, const T &b) { return (a<b)?(a=b,1):0;}\ntemplate<class T>bool chmin(T &a, const T &b) { return (b<a)?(a=b,1):0;}\n\nusing namespace std;\nusing R=long double;\n\nint n,x[110],y[110];\n\nusing R=long double;\nconst R PI = acos(R(-1));\nconst R INF = 1e40;\nusing P=complex<R>;\nusing C=tuple<R,R,R>;\n#define mod(x,y) fmod(fmod(x,y)+y,y)\n\ninline C shadow(R theta){\n\tR a=0.0,b=0.0,c=2.0*n;\n\n\tusing state=tuple<R,int>;\n\tvector<state> ary;\n\n\trep(i,n) ary.push_back(make_tuple(1.0*x[i]*sin(theta)+1.0*y[i]*cos(theta),i));\n\tsort(_all(ary));\n\t\n\trep(i,n-1){\n\t\tR cur,nxt; int idx,idx2;\n\t\ttie(cur,idx)=ary[i],tie(nxt,idx2)=ary[i+1];\n\t\tif(nxt-cur<2.0){\n\t\t\tc-=2.0;\n\t\t\ta+=(x[idx2]-x[idx]),b+=(y[idx2]-y[idx]);\n\t\t}\n\t}\n\treturn make_tuple(a,b,c);\n}\n\nint main(void){\n\twhile(cin >> n,n){\t\t\n\t\tvector<R> candiate={0.0,PI/2.0,PI};\n\t\trep(i,n) cin >> x[i] >> y[i];\n\t\tcout.precision(20);\n\n\t\trep(j,n)rep(i,j){\n\t\t\tP a=P(x[i],y[i]),b=P(x[j],y[j]);\n\t\t\tR c=arg(b-a),e=asin(2.0/abs(b-a));\n\t\t\tcandiate.push_back(mod(PI-c,PI));\n\t\t\tcandiate.push_back(mod(PI-c+e,PI));\n\t\t\tcandiate.push_back(mod(PI-c-e,PI));\n\t\t}\n\n\t\tuniq(candiate);\n\t\tcandiate.push_back(candiate[0]+PI);\t\n\t\tint m=int(candiate.size());\n\n\t\trep(i,m-1){\n\t\t\tR cur=candiate[i],nxt=candiate[i+1],a,b,c;\n\t\t\ttie(a,b,c)=shadow((cur+nxt)/2.0);\n\t\t\tR theta=mod(atan(a/b),PI);\n\t\t\tif(cur < mod(theta,PI) && mod(theta,PI) < nxt) candiate.push_back(mod(theta,PI));\n\t\t}\t\n\n\t\tR cmin=INF,theta1=-1.0;\n\t\tfor(auto &theta:candiate){\n\t\t\tR a,b,c;\n\t\t\ttie(a,b,c)=shadow(theta);\n\t\t\tif(chmin(cmin,a*sin(theta)+b*cos(theta)+c)) theta1=theta;\n\t\t}\n\t\tcout << fixed << theta1 << endl;\n\t\t\n\t\tR cmax=0.0,theta2=-1.0;\n\t\tfor(auto &theta:candiate){\n\t\t\tR a,b,c;\n\t\t\ttie(a,b,c)=shadow(theta);\n\t\t\tif(chmax(cmax,a*sin(theta)+b*cos(theta)+c)) theta2=theta;\n\t\t}\n\t\tcout << fixed << theta2 << endl;\n\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 830, "memory_kb": 3796, "score_of_the_acc": -0.7582, "final_rank": 11 }, { "submission_id": "aoj_1146_1859152", "code_snippet": "#include <bits/stdc++.h>\n\n#define _overload(_1,_2,_3,name,...) name\n#define _rep(i,n) _range(i,0,n)\n#define _range(i,a,b) for(int i=int(a);i<int(b);++i)\n#define rep(...) _overload(__VA_ARGS__,_range,_rep,)(__VA_ARGS__)\n\n#define _all(arg) begin(arg),end(arg)\n#define uniq(arg) (sort(_all(arg)),(arg).erase(unique(_all(arg)),end(arg)),arg)\n\ntemplate<class T>bool chmax(T &a, const T &b) { return (a<b)?(a=b,1):0;}\ntemplate<class T>bool chmin(T &a, const T &b) { return (b<a)?(a=b,1):0;}\n\nusing namespace std;\nusing R=long double;\n\nint n,x[110],y[110];\n\nusing R=long double;\nconstexpr R PI = acos(R(-1));\nconstexpr R INF = 1e40;\nusing P=complex<R>;\nusing C=tuple<R,R,R>;\n#define mod(x,y) fmod(fmod(x,y)+y,y)\n\n\ninline C shadow(R theta){\n\tR a=0.0,b=0.0,c=0.0;\n\tR vx=sin(theta),vy=cos(theta);\n\n\tusing state=tuple<R,int>;\n\tvector<state> ary;\n\n\trep(i,n) ary.push_back(make_tuple(1.0*x[i]*vx+1.0*y[i]*vy,i));\n\tsort(_all(ary));\n\t\n\tc+=2.0*n;\n\n\trep(i,n-1){\n\t\tR cur,nxt; int idx,idx2;\n\t\ttie(cur,idx)=ary[i],tie(nxt,idx2)=ary[i+1];\n\t\tif(nxt-cur<2.0){\n\t\t\tc-=2.0;\n\t\t\ta+=(x[idx2]-x[idx]),b+=(y[idx2]-y[idx]);\n\t\t}\n\t}\n\treturn make_tuple(a,b,c);\n}\n\nint main(void){\n\twhile(cin >> n,n){\t\t\n\t\tvector<R> candiate={0.0,PI/2.0,PI};\n\t\trep(i,n) cin >> x[i] >> y[i];\n\t\tcout.precision(20);\n\n\n\t\trep(j,n)rep(i,j){\n\t\t\tP a=P(x[i],y[i]),b=P(x[j],y[j]);\n\t\t\tR c=arg(b-a),e=asin(2.0/abs(b-a));\n\t\t\tcandiate.push_back(mod(PI-c,PI));\n\t\t\tcandiate.push_back(mod(PI-c+e,PI));\n\t\t\tcandiate.push_back(mod(PI-c-e,PI));\n\t\t}\n\n\t\tuniq(candiate);\n\t\tcandiate.push_back(candiate[0]+PI);\t\n\t\tint m=int(candiate.size());\n\n\t\trep(i,m-1){\n\t\t\tR cur=candiate[i],nxt=candiate[i+1],a,b,c;\n\t\t\ttie(a,b,c)=shadow((cur+nxt)/2.0);\n\t\t\tR theta=mod(atan(a/b),PI);\n\t\t\tif(cur < mod(theta,PI) && mod(theta,PI) < nxt) candiate.push_back(mod(theta,PI));\n\t\t}\t\n\n\t\tR cmin=INF,theta1=-1.0;\n\t\tfor(auto &theta:candiate){\n\t\t\tR a,b,c;\n\t\t\ttie(a,b,c)=shadow(theta);\n\t\t\tif(chmin(cmin,a*sin(theta)+b*cos(theta)+c)) theta1=theta;\n\t\t}\n\t\tcout << fixed << theta1 << endl;\n\t\t\n\t\tR cmax=0.0,theta2=-1.0;\n\t\tfor(auto &theta:candiate){\n\t\t\tR a,b,c;\n\t\t\ttie(a,b,c)=shadow(theta);\n\t\t\tif(chmax(cmax,a*sin(theta)+b*cos(theta)+c)) theta2=theta;\n\t\t}\n\t\tcout << fixed << theta2 << endl;\n\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 780, "memory_kb": 3908, "score_of_the_acc": -0.774, "final_rank": 12 }, { "submission_id": "aoj_1146_1225385", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <cmath>\n#include <complex>\n#include <vector>\n#include <algorithm>\n#include <utility>\nusing namespace std;\n\ntypedef double D;\ntypedef complex<D> P;\ntypedef pair<D,int> pdi;\n\nD pi;\nD smax, smin, tmax, tmin;\nvector<P> ps;\n\nD dot(const P &a, const P &b){\n\treturn real(a) * real(b) + imag(a) * imag(b);\n}\n\nP check(D t){\n\twhile(t < 0.0){ t += pi; }\n\twhile(t >= pi){ t -= pi; }\n\tt += 0.0;\n\t\n\tint n = ps.size();\n\tP a = polar(D(1.0), 0.5 * pi - t);\n\tvector<pdi> v(2 * n);\n\tfor(int i = 0; i < n; ++i){\n\t\tD z = dot(ps[i], a);\n\t\tv[2 * i] = pdi(z - 1.0, i);\n\t\tv[2 * i + 1] = pdi(z + 1.0, ~i);\n\t}\n\tsort(v.begin(), v.end());\n\tint cnt = 0;\n\tD sum = 0.0;\n\tP ret;\n\tfor(int i = 0; i < 2 * n; ++i){\n\t\tif(cnt){ sum += v[i].first - v[i - 1].first; }\n\t\tif(v[i].second >= 0){\n\t\t\tif(!cnt++){ ret -= ps[v[i].second]; }\n\t\t}\n\t\telse{\n\t\t\tif(!--cnt){ ret += ps[~v[i].second]; }\n\t\t}\n\t}\n\t\n\tif(sum > smax){\n\t\tsmax = sum;\n\t\ttmax = t;\n\t}\n\tif(sum < smin){\n\t\tsmin = sum;\n\t\ttmin = t;\n\t}\n\n\treturn ret;\n}\n\nint main(){\n\tpi = acos(D(-1.0));\n\tios::sync_with_stdio(false);\n\tcout << fixed << setprecision(10);\n\n\tint n;\n\twhile(cin >> n, n){\n\t\tsmax = -1e300;\n\t\tsmin = 1e300;\n\t\n\t\tps.resize(n);\n\t\tfor(int i = 0; i < n; ++i){\n\t\t\tint x, y;\n\t\t\tcin >> x >> y;\n\t\t\tps[i] = P(x, y);\n\t\t}\n\n\t\tcheck(0);\n\n\t\tvector<D> cand;\n\t\tfor(int i = 0; i < n; ++i)\n\t\tfor(int j = 0; j < i; ++j){\n\t\t\tD a = -arg(ps[j] - ps[i]);\n\t\t\tD b = asin(2.0 / abs(ps[j] - ps[i]));\n\t\t\tcand.push_back(a);\n\t\t\tcand.push_back(a - b);\n\t\t\tcand.push_back(a + b);\n\t\t}\n\t\tfor(size_t i = 0; i < cand.size(); ++i){\n\t\t\twhile(cand[i] < 0.0){ cand[i] += pi; }\n\t\t\twhile(cand[i] > pi){ cand[i] -= pi; }\n\t\t\tcheck(cand[i]);\n\t\t}\n\t\tsort(cand.begin(), cand.end());\n\t\tfor(size_t i = 1; i < cand.size(); ++i){\n\t\t\tP ret = check(0.5 * (cand[i - 1] + cand[i]));\n\t\t\tif(abs(ret) > 1e-10){\n\t\t\t\tcheck(0.5 * pi - arg(ret));\n\t\t\t}\n\t\t}\n\n\t\ttmin = min(tmin, pi - 1e-10);\n\t\ttmax = min(tmax, pi - 1e-10);\n\t\tcout << tmin << '\\n' << tmax << '\\n';\n\t}\n}", "accuracy": 1, "time_ms": 2720, "memory_kb": 1552, "score_of_the_acc": -0.6522, "final_rank": 9 }, { "submission_id": "aoj_1146_1225377", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <cmath>\n#include <complex>\n#include <vector>\n#include <algorithm>\n#include <utility>\nusing namespace std;\n\ntypedef double D;\ntypedef complex<D> P;\ntypedef pair<D,int> pdi;\n\nD pi;\nD smax, smin, tmax, tmin;\nvector<P> ps;\n\nD dot(const P &a, const P &b){\n\treturn real(a) * real(b) + imag(a) * imag(b);\n}\n\nP check(D t){\n\twhile(t < 0.0){ t += pi; }\n\twhile(t >= pi){ t -= pi; }\n\tt += 0.0;\n\t\n\tint n = ps.size();\n\tP a = polar(D(1.0), 0.5 * pi - t);\n\tvector<pdi> v(2 * n);\n\tfor(int i = 0; i < n; ++i){\n\t\tD z = dot(ps[i], a);\n\t\tv[2 * i] = pdi(z - 1.0, i);\n\t\tv[2 * i + 1] = pdi(z + 1.0, ~i);\n\t}\n\tsort(v.begin(), v.end());\n\tint cnt = 0;\n\tD sum = 0.0;\n\tP ret;\n\tfor(int i = 0; i < 2 * n; ++i){\n\t\tif(cnt){ sum += v[i].first - v[i - 1].first; }\n\t\tif(v[i].second >= 0){\n\t\t\tif(!cnt++){ ret -= ps[v[i].second]; }\n\t\t}\n\t\telse{\n\t\t\tif(!--cnt){ ret += ps[~v[i].second]; }\n\t\t}\n\t}\n\t\n\tif(sum > smax){\n\t\tsmax = sum;\n\t\ttmax = t;\n\t}\n\tif(sum < smin){\n\t\tsmin = sum;\n\t\ttmin = t;\n\t}\n\n\treturn ret;\n}\n\nint main(){\n\tpi = acos(D(-1.0));\n\tios::sync_with_stdio(false);\n\tcout << fixed << setprecision(10);\n\n\tint n;\n\twhile(cin >> n, n){\n\t\tsmax = -1e300;\n\t\tsmin = 1e300;\n\t\n\t\tps.resize(n);\n\t\tfor(int i = 0; i < n; ++i){\n\t\t\tint x, y;\n\t\t\tcin >> x >> y;\n\t\t\tps[i] = P(x, y);\n\t\t}\n\n\t\tcheck(0);\n\n\t\tvector<D> cand;\n\t\tfor(int i = 0; i < n; ++i)\n\t\tfor(int j = 0; j < i; ++j){\n\t\t\tD a = -arg(ps[j] - ps[i]);\n\t\t\tD b = asin(2.0 / abs(ps[j] - ps[i]));\n\t\t\tcand.push_back(a);\n\t\t\tcand.push_back(a - b);\n\t\t\tcand.push_back(a + b);\n\t\t}\n\t\tfor(size_t i = 0; i < cand.size(); ++i){\n\t\t\twhile(cand[i] < 0.0){ cand[i] += pi; }\n\t\t\twhile(cand[i] > pi){ cand[i] -= pi; }\n\t\t\tcheck(cand[i]);\n\t\t}\n\t\tsort(cand.begin(), cand.end());\n\t\tfor(size_t i = 1; i < cand.size(); ++i){\n\t\t\tP ret = check(0.5 * (cand[i - 1] + cand[i]));\n\t\t\tif(abs(ret) > 1e-12){\n\t\t\t\tcheck(0.5 * pi - arg(ret));\n\t\t\t}\n\t\t}\n\t\tcout << tmin << '\\n' << tmax << '\\n';\n\t}\n}", "accuracy": 1, "time_ms": 2630, "memory_kb": 1548, "score_of_the_acc": -0.6299, "final_rank": 8 }, { "submission_id": "aoj_1146_1225374", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <cmath>\n#include <complex>\n#include <vector>\n#include <algorithm>\n#include <utility>\nusing namespace std;\n\ntypedef double D;\ntypedef complex<D> P;\ntypedef pair<D,int> pdi;\n\nD pi;\nD smax, smin, tmax, tmin;\nvector<P> ps;\n\nD dot(const P &a, const P &b){\n\treturn real(a) * real(b) + imag(a) * imag(b);\n}\n\nP check(D t){\n\twhile(t < 0.0){ t += pi; }\n\twhile(t >= pi){ t -= pi; }\n\tt += 0.0;\n\t\n\tint n = ps.size();\n\tP a = polar(D(1.0), 0.5 * pi - t);\n\tvector<pdi> v(2 * n);\n\tfor(int i = 0; i < n; ++i){\n\t\tD z = dot(ps[i], a);\n\t\tv[2 * i] = pdi(z - 1.0, i);\n\t\tv[2 * i + 1] = pdi(z + 1.0, ~i);\n\t}\n\tsort(v.begin(), v.end());\n\tint cnt = 0;\n\tD sum = 0.0;\n\tP ret;\n\tfor(int i = 0; i < 2 * n; ++i){\n\t\tif(cnt){ sum += v[i].first - v[i - 1].first; }\n\t\tif(v[i].second >= 0){\n\t\t\tif(!cnt++){ ret -= ps[v[i].second]; }\n\t\t}\n\t\telse{\n\t\t\tif(!--cnt){ ret += ps[~v[i].second]; }\n\t\t}\n\t}\n\t\n\tif(sum > smax){\n\t\tsmax = sum;\n\t\ttmax = t;\n\t}\n\tif(sum < smin){\n\t\tsmin = sum;\n\t\ttmin = t;\n\t}\n\n\treturn ret;\n}\n\nint main(){\n\tpi = acos(D(-1.0));\n\tios::sync_with_stdio(false);\n\tcout << fixed << setprecision(10);\n\n\tint n;\n\twhile(cin >> n, n){\n\t\tsmax = -1e300;\n\t\tsmin = 1e300;\n\t\n\t\tps.resize(n);\n\t\tfor(int i = 0; i < n; ++i){\n\t\t\tint x, y;\n\t\t\tcin >> x >> y;\n\t\t\tps[i] = P(x, y);\n\t\t}\n\n\t\tcheck(0);\n\n\t\tvector<D> cand;\n\t\tfor(int i = 0; i < n; ++i)\n\t\tfor(int j = 0; j < i; ++j){\n\t\t\tD a = -arg(ps[j] - ps[i]);\n\t\t\tD b = asin(2.0 / abs(ps[j] - ps[i]));\n\t\t\tcand.push_back(a);\n\t\t\tcand.push_back(a - b);\n\t\t\tcand.push_back(a + b);\n\t\t}\n\t\tfor(size_t i = 0; i < cand.size(); ++i){\n\t\t\twhile(cand[i] < 0.0){ cand[i] += pi; }\n\t\t\twhile(cand[i] > pi){ cand[i] -= pi; }\n\t\t\tcheck(cand[i]);\n\t\t}\n\t\tsort(cand.begin(), cand.end());\n\t\tfor(size_t i = 1; i < cand.size(); ++i){\n\t\t\tif(cand[i - 1] != cand[i]){\n\t\t\t\tP ret = check(0.5 * (cand[i - 1] + cand[i]));\n\t\t\t\tcheck(0.5 * pi - arg(ret));\n\t\t\t}\n\t\t}\n\t\tcout << tmin << '\\n' << tmax << '\\n';\n\t}\n}", "accuracy": 1, "time_ms": 1840, "memory_kb": 1552, "score_of_the_acc": -0.4437, "final_rank": 1 }, { "submission_id": "aoj_1146_1177472", "code_snippet": "#include<cstdio>\n#include<complex>\n#include<vector>\n#include<cmath>\n#include<iostream>\n#include<string>\n#include<utility>\n#include<algorithm>\n\nusing namespace std;\n\ntypedef double Real;\n\ntypedef complex<Real> Point;\ntypedef complex<Real> Vector;\ntypedef pair<Point,Point> Segment;\ntypedef vector<Point> Polygon;\n\ntypedef pair<Real,int> P;\ntypedef pair<Real,Real> PR;\n\nconst Real eps=1e-9;\nconst Real PI=acos(-1.0);\nconst Real inf=1e9;\n\ntemplate<class T> bool eq(T a,T b){\n\treturn abs(a-b)<eps;\n}\ntemplate<class T> int sgn(T a){\n\tif(eq(a,0.0)) return 0;\n\tif(a>0) return 1;\n\treturn -1;\n}\n\nReal arg(Vector v){\n\treturn atan2(v.imag(),v.real());\n}\n\nReal getDis(Real a,Real x,Real y){\n\treturn (a*x-y)/sqrt(a*a+1.0);\n}\n\nint xs[110],ys[110];\nPoint pts[110];\nint N;\n\nint NUM=0;\n\nReal get(vector<P> vec){\n\tReal res=0;\n\tsort(vec.begin(),vec.end());\n\tint cnt=0;\n\tReal prev=-inf;\n\tfor(int i=0;i<vec.size();i++){\n\t\tReal x=vec[i].first;\n\t\tint y=vec[i].second;\n//\t\tprintf(\"(%f,%d)\\n\",x,y);\n\t\tif(cnt>0){\n\t\t\tres+=(x-prev);\n\t\t}\n\t\tprev=x;\n\t\tcnt+=y;\n\t}\n//\tprintf(\"res=%f\\n\",res);\n//\tNUM++;\n//\tif(NUM==20) exit(0);\n//\texit(0);\n\treturn res;\n}\n\nReal calc(Real ang){\n\tvector<P> vec;\n\tif(eq(ang,PI/2)){\n\t\tfor(int i=0;i<N;i++){\n\t\t\tvec.push_back(P(xs[i]-1,1));\n\t\t\tvec.push_back(P(xs[i]+1,-1));\n\t\t}\n\t}else{\n\t\tfor(int i=0;i<N;i++){\n\t\t//\tReal d=getDis(tan(PI/2-ang),xs[i],ys[i]);\n\t\t\tReal d=getDis(tan(-ang),xs[i],ys[i]);\n\t\t\tvec.push_back(P(d-1,1));\n\t\t\tvec.push_back(P(d+1,-1));\n\t\t}\n\t}\n\tReal res=get(vec);\n\treturn res;\n}\n\nvector<Real> borders;\n\nReal normalize(Real ang){\n\tif(sgn(ang)<=0){\n\t\treturn -ang;\n\t}\n\treturn abs(ang-PI);\n}\n\nReal normalize2(Real ang){\n\twhile(ang<0) ang+=PI;\n\twhile(ang>PI) ang-=PI;\n\treturn ang;\n}\n\nvoid solve(Real lb,Real ub);\n\nvoid solve(){\n\tfor(int i=0;i<N;i++) for(int j=i+1;j<N;j++){\n\t\tVector v=pts[j]-pts[i];\n\t\tReal theta=arg(v);\n\t\ttheta=normalize(theta);\n\t\tborders.push_back(theta);\n\t\tif(eq(abs(v),2.0)){\n\t\t\tif(sgn(theta-PI/2)>=0){\n\t\t\t\tborders.push_back(theta-PI/2);\n\t\t\t}else{\n\t\t\t\tborders.push_back(theta+PI/2);\n\t\t\t}\n\t\t}else{\n\t\t\tReal d=abs(v);\n\t\t\tReal phi=asin(2.0/d);\n\t\t\tborders.push_back(normalize2(theta+phi));\n\t\t\tborders.push_back(normalize2(theta-phi));\n\t\t}\n\t}\n\tsort(borders.begin(),borders.end());\n\tfor(int i=0;i+1<borders.size();i++){\n\t\tsolve(borders[i],borders[i+1]);\n\t}\n}\n\nPR mi,Ma;\n\nvoid solve(Real lb,Real ub){\n//\tprintf(\"[%f,%f]\\n\",lb,ub);\n\tReal x=calc(lb);\n\tmi=min(mi,PR(x,lb));\n\tMa=max(Ma,PR(x,lb));\n\tx=calc(ub);\n\tmi=min(mi,PR(x,ub));\n\tMa=max(Ma,PR(x,ub));\n\tif(eq(lb,ub)) return;\n#if 0\n\tfor(int stage=0;stage<100;stage++){\n\t\tReal dif=ub-lb;\n\t\tif(dif<eps) break;\n\t\tReal ang1=lb+(dif/3.0);\n\t\tReal ang2=lb+(dif*2/3.0);\n\t\tReal val1=calc(ang1);\n\t\tReal val2=calc(ang2);\n\t\tif(val1<val2){\n\t\t\tlb=ang1;\n\t\t}else{\n\t\t\tub=ang2;\n\t\t}\n\t}\n\tReal val=calc(lb);\n\tMa=max(Ma,PR(val,lb));\n#endif\n\tvector<P> tmp;\n\tReal mid=(ub+lb)/2;\n\tfor(int i=0;i<N;i++){\n\t\tReal L=sqrt(xs[i]*xs[i]+ys[i]*ys[i]);\n\t\tReal phi=atan2(ys[i],xs[i]);\n\t\ttmp.push_back(P(L*(sin(mid+phi)),i));\n\t}\n\tsort(tmp.begin(),tmp.end());\n\tReal coe_c=0,coe_s=0;\n\tReal c=0;\n\tfor(int i=0;i<N;i++){\n\t\tif(i==0||sgn(tmp[i].first-tmp[i-1].first-2.0)>0){\n\t\t\tc+=1.0;\n\t\t\tint id=tmp[i].second;\n\t\t\tReal L=abs(pts[id]);\n\t\t\tReal phi=atan2(ys[id],xs[id]);\n\t\t\tcoe_c-=L*sin(phi);\n\t\t\tcoe_s-=L*cos(phi);\n\t\t}\n\t\tif(i==N-1||sgn(tmp[i+1].first-tmp[i].first-2.0)>0){\n\t\t\tc+=1.0;\n\t\t\tint id=tmp[i].second;\n\t\t\tReal L=abs(pts[id]);\n\t\t\tReal phi=atan2(ys[id],xs[id]);\n\t\t\tcoe_c+=L*sin(phi);\n\t\t\tcoe_s+=L*cos(phi);\n\t\t}\n\t}\n\tReal A=coe_c,B=coe_s;\n\tReal phi=-atan2(B,-A);\n\tphi=normalize2(phi);\n//\tprintf(\"%f %f %f\\n\",lb,phi,ub);\n\tif(sgn(phi-lb)>=0&&sgn(ub-phi)>=0){\n\t\tReal x=calc(phi);\n\t\tMa=max(Ma,PR(x,phi));\n\t}\n}\n\nvoid init(){\n\tborders.clear();\n\tmi=PR(inf,0);\n\tMa=PR(-inf,0);\n}\n\nvoid input(){\n\tscanf(\"%d\",&N);\n\tfor(int i=0;i<N;i++){\n\t\tscanf(\"%d%d\",xs+i,ys+i);\n\t\tpts[i]=Point(xs[i],ys[i]);\n\t}\n}\n\nint main(){\n\tint T=0;\n\twhile(true){\n\t\tinit();\n\t\tinput();\n\t\tif(N==0) break;\n//\t\tif(T<60){\n//\t\t\tT++;\n//\t\t\tcontinue;\n//\t\t}\n\t\tsolve();\n\t\tif(eq(mi.second,PI)) mi.second=0;\n\t\tif(eq(Ma.second,PI)) Ma.second=0;\n\t\tprintf(\"%.12f\\n\",mi.second);\n\t\tprintf(\"%.12f\\n\",Ma.second);\n\t\tT++;\n//\t\tif(T>=60&&T<70){\n//\t\t\tfprintf(stderr,\"case %d\\n\",T);\n//\t\t\tfprintf(stderr,\"borders.size()=%d\\n\",borders.size());\n//\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3520, "memory_kb": 1584, "score_of_the_acc": -0.8497, "final_rank": 14 }, { "submission_id": "aoj_1146_1138404", "code_snippet": "#include<stdio.h>\n#include<algorithm>\n#include<math.h>\n#include<vector>\nusing namespace std;\ndouble x[110];\ndouble y[110];\nvector<double>v;\ndouble PI=acos(-1.0);\ndouble EPS=1e-12;\nint n;\nint bk[110];\ndouble calc(double a){\n\tfor(int i=0;i<n;i++)bk[i]=0;\n\tvector<pair<double,pair<int,int> > >ev;\n\tfor(int i=0;i<n;i++){\n\t\tdouble ty=x[i]*sin(a)+y[i]*cos(a);\n\t\tev.push_back(make_pair(ty-1,make_pair(1,i)));\n\t\tev.push_back(make_pair(ty+1,make_pair(-1,i)));\n\t}\n\tstd::sort(ev.begin(),ev.end());\n\tdouble ret=0;\n\tint now=0;\n\tfor(int i=0;i<ev.size();i++){\n\t\tif(now)ret+=ev[i].first-ev[i-1].first;\n\t\tnow+=ev[i].second.first;\n\t//\tif(i<ev.size()-1&&ev[i+1].first-ev[i].first>EPS){\n\t\t\tif(ev[i].second.first==-1&&now==0){\n\t\t\t\tbk[ev[i].second.second]--;\n\t\t\t}\n\t\t\tif(ev[i].second.first==1&&now==1){\n\t\t\t\tbk[ev[i].second.second]++;\n\t\t\t}\n\t\t//}\n\t}\n\t//printf(\"%f: %f\\n\",a,ret);\n\treturn ret;\n}\ndouble bf(double t){\n\tdouble ret=0;\n\tfor(int i=0;i<n;i++){\n\t\tret+=(x[i]*cos(t)-y[i]*sin(t))*bk[i];\n\t}\n\treturn ret;\n}\nint main(){\n\tint a;\n\twhile(scanf(\"%d\",&a),a){\n\t\tfor(int i=0;i<a;i++)scanf(\"%lf%lf\",x+i,y+i);\n\t\tn=a;\n\t\tv.clear();\n\t\tv.push_back(0);\n\t\tv.push_back(PI);\n\t\tfor(int i=0;i<a;i++)for(int j=i+1;j<a;j++){\n\t\t\tdouble th=atan2(y[j]-y[i],x[j]-x[i]);\n\t\t\tdouble th2;\n\t\t\tif(th>0){\n\t\t\t\tv.push_back(PI-th);\n\t\t\t\tth2=PI-th+PI/2;\n\t\t\t}else{\n\t\t\t\tv.push_back(-th);\n\t\t\t\tth2=-th+PI/2;\n\t\t\t}\n\t\t\tdouble d=sqrt((x[j]-x[i])*(x[j]-x[i])+(y[j]-y[i])*(y[j]-y[i]));\n\t\t\td=max(d,2.0);\n\t\t\tdouble tt=acos(2.0/d);\n\t\t\tdouble t1=th2-tt;\n\t\t\tif(t1>PI)t1-=PI;\n\t\t\tif(t1<0)t1+=PI;\n\t\t\tv.push_back(t1);\n\t\t\tdouble t2=th2+tt;\n\t\t\twhile(t2>PI)t2-=PI;\n\t\t\tv.push_back(t2);\n\t\t}\n\t\tstd::sort(v.begin(),v.end());\n\t\tdouble tl=0;\n\t\tdouble tr=0;\n\t\tdouble vl=9999999;\n\t\tdouble vr=0;\n\t\tfor(int i=0;i<v.size();i++){\n\t\t\tdouble val=calc(v[i]);\n\t\t\tif(vl>val){\n\t\t\t\tvl=val;tl=v[i];\n\t\t\t}\n\t\t\tif(vr<val){\n\t\t\t\tvr=val;tr=v[i];\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<v.size()-1;i++){\n\t\t\tif(v[i+1]-v[i]<EPS)continue;\n\t//\t\tdouble p=(double)(rand()%100000)/100000;\n\t\t\tdouble M=(v[i]+v[i+1])/2;\n\t\t\tcalc(M);\n\t\t\tdouble T=0;\n\t\t\tif(bf(v[i])<bf(v[i+1])){\n\t\t\t\tdouble L=v[i];\n\t\t\t\tdouble R=v[i+1];\n\t\t\t\tfor(int j=0;j<100;j++){\n\t\t\t\t\tdouble m=(L+R)/2;\n\t\t\t\t\tdouble val=bf(m);\n\t\t\t\t\tif(val<0)L=m;\n\t\t\t\t\telse R=m;\n\t\t\t\t}\n\t\t\t\tT=L;\n\t\t\t}else{\n\t\t\t\tdouble L=v[i];\n\t\t\t\tdouble R=v[i+1];\n\t\t\t\tfor(int j=0;j<100;j++){\n\t\t\t\t\tdouble m=(L+R)/2;\n\t\t\t\t\tdouble val=bf(m);\n\t\t\t\t\tif(val<0)R=m;\n\t\t\t\t\telse L=m;\n\t\t\t\t}\n\t\t\t\tT=L;\n\t\t\t}\n\t//\t\tfor(int j=0;j<a;j++)printf(\"%d \",bk[j]);\n\t\t\t\n\t\t\tdouble tmp=calc(T);\n\t\t//\tprintf(\"%f %f %f -> %f %f %f: %f\\n\",v[i],T,v[i+1],bf(v[i]),bf(T),bf(v[i+1]),tmp);\n\t\t\tif(vl>tmp){\n\t\t\t\tvl=tmp;tl=T;\n\t\t\t}\n\t\t\tif(vr<tmp){\n\t\t\t\tvr=tmp;tr=T;\n\t\t\t}\n\t\t}\n\t//\tprintf(\"%f %f\\n\",vl,vr);\n\t\tprintf(\"%.15f\\n%.15f\\n\",tl,tr);\n\t}\n}", "accuracy": 1, "time_ms": 2510, "memory_kb": 1348, "score_of_the_acc": -0.5521, "final_rank": 2 }, { "submission_id": "aoj_1146_990772", "code_snippet": "#include <bits/stdc++.h>\n\n\nusing namespace std;\n\n#define rep(i, n) for (int i = 0; i < int(n); ++i)\n\n#define X real()\n#define Y imag()\n\ntypedef long double D;\ntypedef complex<D> P;\n\nconst D PI = acos(-1);\n\nint n;\nP p[100];\n\nD solve(D theta) {\n vector<D> xx;\n D st = sin(theta), ct = cos(theta);\n rep (i, n) xx.push_back(p[i].X * st + p[i].Y * ct);\n sort(xx.begin(), xx.end());\n D res = 2;\n rep (i, xx.size() - 1) res += min((D)2, xx[i + 1] - xx[i]);\n return res;\n}\n\npair<D, D> solve2(D theta) {\n vector<pair<D, pair<D, D> > > xx;\n D st = sin(theta), ct = cos(theta);\n rep (i, n) xx.push_back(make_pair(p[i].X * st + p[i].Y * ct, make_pair(p[i].X, p[i].Y)));\n sort(xx.begin(), xx.end());\n D sx = 0, sy = 0;\n rep (i, xx.size() - 1) if (xx[i + 1].first - xx[i].first < 2) {\n sx += xx[i].second.first;\n sy += xx[i].second.second;\n sx -= xx[i + 1].second.first;\n sy -= xx[i + 1].second.second;\n }\n return make_pair(solve(atan2(sx, sy)), atan2(sx, sy));\n}\n\nint main() {\n while (true) {\n cin >> n;\n if (n == 0) break;\n rep (i, n) {\n D x, y;\n cin >> x >> y;\n p[i] = P(x, y);\n }\n vector<D> t;\n t.push_back(PI);\n t.push_back(0);\n rep (i, n) rep (j, i) {\n D t1 = -arg(p[i] - p[j]);\n D dt = asin((D)2 / abs(p[i] - p[j]));\n t.push_back(t1);\n t.push_back(t1 + dt);\n t.push_back(t1 - dt);\n }\n rep (i, t.size()) while (t[i] < 0) t[i] += PI;\n rep (i, t.size()) while (t[i] > PI) t[i] -= PI;\n sort(t.begin(), t.end());\n D ans = 1e9, theta = -1;\n rep (i, t.size()) {\n D s = solve(t[i]);\n if (s < ans) {\n\tans = s;\n\ttheta = t[i];\n }\n }\n rep (i, t.size() - 1) {\n pair<D, D> s = solve2((t[i] + t[i + 1]) / 2);\n if (s.first < ans) {\n\tans = s.first;\n\ttheta = s.second;\n }\n }\n while (theta < 0) theta += PI;\n while (theta > PI) theta -= PI;\n cout << fixed << setprecision(15) << theta << endl;\n ans = 0, theta = -1;\n rep (i, t.size()) {\n D s = solve(t[i]);\n if (s > ans) {\n\tans = s;\n\ttheta = t[i];\n }\n }\n rep (i, t.size() - 1) {\n pair<D, D> s = solve2((t[i] + t[i + 1]) / 2);\n if (s.first > ans) {\n\tans = s.first;\n\ttheta = s.second;\n }\n }\n while (theta < 0) theta += PI;\n while (theta > PI) theta -= PI;\n cout << fixed << setprecision(15) << theta << endl;\n }\n}", "accuracy": 1, "time_ms": 4250, "memory_kb": 1732, "score_of_the_acc": -1.0592, "final_rank": 19 }, { "submission_id": "aoj_1146_561245", "code_snippet": "#include<cmath>\n#include<cstdio>\n#include<vector>\n#include<algorithm>\n\n#define rep(i,n) for(int i=0;i<(n);i++)\n\nusing namespace std;\n\nconst double EPS=1e-11;\nconst double INF=1e77;\nconst double PI=acos(-1);\n\nstruct point{\n\tdouble x,y;\n\tpoint():x(0),y(0){}\n\tpoint(double x,double y):x(x),y(y){}\n\tpoint operator+(const point &a)const{ return point(x+a.x,y+a.y); }\n\tpoint operator-(const point &a)const{ return point(x-a.x,y-a.y); }\n};\n\npoint operator*(double c,const point &a){ return point(c*a.x,c*a.y); }\n\ndouble abs(const point &a){ return sqrt(a.x*a.x+a.y*a.y); }\n\npoint rot(const point &a,double theta){ return point(a.x*cos(theta)-a.y*sin(theta),a.x*sin(theta)+a.y*cos(theta)); }\n\ndouble arg(const point &a){\n\tdouble t=atan2(a.y,a.x);\n\treturn t<0?t+2*PI:t;\n}\n\nstruct line{\n\tpoint a,b;\n\tline(){}\n\tline(const point &a,const point &b):a(a),b(b){}\n};\n\nstruct circle{\n\tpoint c;\n\tdouble r;\n\tcircle():c(point(0,0)),r(0){}\n\tcircle(const point &c,double r):c(c),r(r){}\n};\n\nint tangent(const circle &C1,const circle &C2,vector<line> &res){\n\tdouble d=abs(C1.c-C2.c);\n\tif(d<EPS) return 0;\n\n\tint c=0;\n\t// 内接線\n\tif(C1.r+C2.r<d-EPS){\n\t\tdouble t=acos((C1.r+C2.r)/d);\n\t\tres.push_back(line(C1.c+rot(C1.r/d*(C2.c-C1.c), t),C2.c+rot(C2.r/d*(C1.c-C2.c), t)));\n\t\tres.push_back(line(C1.c+rot(C1.r/d*(C2.c-C1.c),-t),C2.c+rot(C2.r/d*(C1.c-C2.c),-t)));\n\t\tc+=2;\n\t}\n\telse if(C1.r+C2.r<d+EPS){\n\t\tpoint p=C1.c+C1.r/d*(C2.c-C1.c);\n\t\tres.push_back(line(p,p+rot(C2.c-C1.c,PI/2)));\n\t\tc++;\n\t}\n\n\t// 外接線\n\tif(abs(C1.r-C2.r)<d-EPS){\n\t\tdouble t1=acos((C1.r-C2.r)/d),t2=PI-t1;\n\t\tres.push_back(line(C1.c+rot(C1.r/d*(C2.c-C1.c), t1),C2.c+rot(C2.r/d*(C1.c-C2.c),-t2)));\n\t\tres.push_back(line(C1.c+rot(C1.r/d*(C2.c-C1.c),-t1),C2.c+rot(C2.r/d*(C1.c-C2.c), t2)));\n\t\tc+=2;\n\t}\n\telse if(abs(C1.r-C2.r)<d+EPS){\n\t\tpoint p=C1.c+C1.r/d*(C2.c-C1.c);\n\t\tres.push_back(line(p,p+rot(C2.c-C1.c,PI/2)));\n\t\tc++;\n\t}\n\n\treturn c;\n}\n\nint n;\ncircle C[100];\n\n// 影たちの位置関係は θ=φ の状態から変わらないとして, dw/dθ = 0 を達成する θ を求める. ( w : 影の長さ )\ndouble calc_peak(double phi){\n\tpair<double,int> pos[100];\n\trep(i,n){\n\t\tpos[i]=make_pair(rot(C[i].c,phi).y,i);\n\t}\n\tsort(pos,pos+n);\n\n\tdouble a=0,b=0; // dw/dθ = 0 <=> a*cos(θ) + b*sin(θ) = 0\n\tint pre=0;\n\tfor(int i=1;i<=n;i++){\n\t\tif(i==n || pos[i-1].first+1<pos[i].first-1){\n\t\t\t// 今見ている影の連結成分は長さは d*sin(t-θ)+2\n\t\t\tdouble d=abs(C[pos[i-1].second].c-C[pos[pre].second].c);\n\t\t\tdouble t=arg(C[pos[i-1].second].c-C[pos[pre].second].c);\n\t\t\t// d*cos(t-θ) = d*cos(t)*cos(θ) + d*sin(t)*sin(θ)\n\t\t\ta+=d*cos(t);\n\t\t\tb+=d*sin(t);\n\n\t\t\tpre=i;\n\t\t}\n\t}\n\n\tdouble res=PI-atan2(-a,b);\n\tif(res>PI) res-=PI;\n\treturn res;\n}\n\ndouble calc_width(double phi){\n\tdouble pos[100];\n\trep(j,n){\n\t\tpos[j]=rot(C[j].c,phi).y;\n\t}\n\tsort(pos,pos+n);\n\n\tdouble res=0,x=-INF;\n\trep(i,n){\n\t\tx=max(x,pos[i]-1);\n\t\tres+=max(pos[i]+1-x,(double)0);\n\t\tx=max(x,pos[i]+1);\n\t}\n\treturn res;\n}\n\nint main(){\n\twhile(scanf(\"%d\",&n),n){\n\t\trep(i,n) scanf(\"%lf%lf\",&C[i].c.x,&C[i].c.y), C[i].r=1;\n\n\t\tvector<line> L;\n\t\trep(i,n) rep(j,i) tangent(C[i],C[j],L);\n\n\t\tvector<double> T; // 二円の共通接線の角度\n\t\trep(i,L.size()){\n\t\t\tdouble phi=PI-arg(L[i].b-L[i].a);\n\t\t\tif(phi<0) phi+=PI;\n\t\t\tT.push_back(phi);\n\t\t}\n\t\tT.push_back(0);\n\t\tT.push_back(PI);\n\t\tsort(T.begin(),T.end());\n\t\t// unique\n\t\trep(i,(int)T.size()-1) if(T[i+1]-T[i]<EPS) T.erase(T.begin()+i--);\n\n\t\tdouble mini=INF,phi_mini;\n\t\tdouble maxi= 0 ,phi_maxi;\n\t\trep(i,T.size()){\n\t\t\tdouble w=calc_width(T[i]);\n\t\t\tif(w<mini) mini=w, phi_mini=T[i];\n\t\t\tif(w>maxi) maxi=w, phi_maxi=T[i];\n\n\t\t\tif(i+1<T.size()){\n\t\t\t\tdouble phi0=(T[i]+T[i+1])/2;\n\t\t\t\tdouble phi1=calc_peak(phi0);\n\n\t\t\t\tw=calc_width(phi1);\n\t\t\t\tif(w<mini) mini=w, phi_mini=phi1;\n\t\t\t\tif(w>maxi) maxi=w, phi_maxi=phi1;\n\t\t\t}\n\t\t}\n\t\tprintf(\"%.15f\\n\",phi_mini);\n\t\tprintf(\"%.15f\\n\",phi_maxi);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1250, "memory_kb": 2688, "score_of_the_acc": -0.5843, "final_rank": 3 } ]
aoj_1156_cpp
Problem D: Twirling Robot Let's play a game using a robot on a rectangular board covered with a square mesh (Figure D-1). The robot is initially set at the start square in the northwest corner facing the east direction. The goal of this game is to lead the robot to the goal square in the southeast corner. Figure D-1: Example of a board The robot can execute the following five types of commands. "Straight": Keep the current direction of the robot, and move forward to the next square. "Right": Turn right with 90 degrees from the current direction, and move forward to the next square. "Back": Turn to the reverse direction, and move forward to the next square. "Left": Turn left with 90 degrees from the current direction, and move forward to the next square. "Halt": Stop at the current square to finish the game. Each square has one of these commands assigned as shown in Figure D-2. The robot executes the command assigned to the square where it resides, unless the player gives another command to be executed instead. Each time the player gives an explicit command, the player has to pay the cost that depends on the command type. Figure D-2: Example of commands assigned to squares The robot can visit the same square several times during a game. The player loses the game when the robot goes out of the board or it executes a "Halt" command before arriving at the goal square. Your task is to write a program that calculates the minimum cost to lead the robot from the start square to the goal one. Input The input is a sequence of datasets. The end of the input is indicated by a line containing two zeros separated by a space. Each dataset is formatted as follows. w h s (1,1) ... s (1, w ) s (2,1) ... s (2, w ) ... s ( h ,1) ... s ( h , w ) c 0 c 1 c 2 c 3 The integers h and w are the numbers of rows and columns of the board, respectively. You may assume 2 ≤ h ≤ 30 and 2 ≤ w ≤ 30. Each of the following h lines consists of w numbers delimited by a space. The number s ( i , j ) represents the command assigned to the square in the i -th row and the j -th column as follows. 0: "Straight" 1: "Right" 2: "Back" 3: "Left" 4: "Halt" You can assume that a "Halt" command is assigned to the goal square. Note that "Halt" commands may be assigned to other squares, too. The last line of a dataset contains four integers c 0 , c 1 , c 2 , and c 3 , delimited by a space, indicating the costs that the player has to pay when the player gives "Straight", "Right", "Back", and "Left" commands respectively. The player cannot give "Halt" commands. You can assume that all the values of c 0 , c 1 , c 2 , and c 3 are between 1 and 9, inclusive. Output For each dataset, print a line only having a decimal integer indicating the minimum cost required to lead the robot to the goal. No other characters should be on the output line. Sample Input 8 3 0 0 0 0 0 0 0 1 2 3 0 1 4 0 0 1 3 3 0 0 0 0 0 4 9 9 1 9 4 4 3 3 4 0 1 2 4 4 1 1 1 0 0 2 4 4 8 7 2 1 2 8 2 2 4 1 0 4 1 3 1 0 2 1 0 3 1 4 ...(truncated)
[ { "submission_id": "aoj_1156_10848675", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing VS = vector<string>; using LL = long long;\nusing VI = vector<int>; using VVI = vector<VI>;\nusing PII = pair<int, int>; using PLL = pair<LL, LL>;\nusing VL = vector<LL>; using VVL = vector<VL>;\n\n#define ALL(a) begin((a)),end((a))\n#define RALL(a) (a).rbegin(), (a).rend()\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define RSORT(c) sort(RALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)\n#define FORR(i, s, e) for (int(i) = (s); (i) > (e); (i)--)\n#define debug(x) cerr << #x << \": \" << x << endl\nconst int INF = 1e9; const LL LINF = 1e16;\nconst LL MOD = 1000000007; const double PI = acos(-1.0);\n\n/* ----- 2018/06/12 Problem: AOJ 1156 / Link: http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=1156 ----- */\n/* ------問題------\n\nロボットを使ったゲームをしよう. ロボットが 1 台,マス目状に区切られた長方形の盤面上に置かれている(図 D-1). ロボットは,最初北西隅にあるスタート地点のマスに東方向を向いて配置されている. ゲームの目的は,ロボットを南東隅にあるゴールのマスまで誘導することである.\nロボットは,次の 5 種類の命令を実行することができる.\n「直進 (Straight)」:\n現在の進行方向のまま,次のマスに前進する.\n「右折 (Right)」:\n進行方向を 90 度右に変えて,次のマスに前進する.\n「反転 (Back)」:\n進行方向を 180 度変えて,次のマスに前進する.\n「左折 (Left)」:\n進行方向を 90 度左に変えて,次のマスに前進する.\n「停止 (Halt)」:\n現在のマスで止まって,ゲームを終了する.\n各マスには,上述の命令のいずれかが割り当てられている(例:図 D-2). 代わりに実行すべき別の命令をプレイヤーが与えない限り, ロボットは,現在いるマスの命令を実行する. プレイヤーが明示的に命令を与える際は,その都度, 命令の種類に応じたコストを支払う必要がある.\nロボットは,同じ場所を何度も訪れることが許されている. 一方で,ロボットが盤面外に前進するような命令を実行した場合や, ゴールに着く前に停止命令を実行した場合は,失格となる.\nあなたの仕事は, ロボットをスタート地点からゴール地点に誘導するために必要な最小コストを求めるプログラムを書くことである.\n\n-----問題ここまで----- */\n/* -----解説等-----\n\n前どこから来たかをもって、やる\n\n----解説ここまで---- */\n\nbool is_in(int x, int y, int h, int w) {\n\treturn (0 <= x && x < w && 0 <= y && y < h);\n}\nint nxtstep(int cmd,int dir) {\n\tif (cmd == 0)return dir;\n\tif (cmd == 1)return (dir+1)%4;\n\tif (cmd == 2)return (dir+2)%4;\n\tif (cmd == 3)return (dir+3)%4;\n\tassert(0);\n}\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\tint W, H;\n\tint DY[8] = { 0, 1, 0, -1 };\n\tint DX[8] = { 1, 0, -1, 0 };\n\n\twhile (cin >> W >> H, W) {\n\t\tVVI masu(H, VI(W));\n\t\tFOR(i, 0, H) {\n\t\t\tFOR(j, 0, W) {\n\t\t\t\tcin >> masu[i][j];\n\t\t\t}\n\t\t}\n\t\tVI co(4);\n\t\tFOR(i, 0, 4) {\n\t\t\tcin >> co[i];\n\t\t} // straight,ri,rev,le\n\t\tvector<VVI>dist(H, VVI(W, VI(4, INF)));\n\t\tusing tp = tuple<int, int, int, int>;\n\t\tpriority_queue<tp, vector<tp>, greater<tp>>q;\n\t\tdist[0][0][0] = 0;\n\t\tq.push(tp(0, 0, 0, 0));\n\t\twhile (!q.empty()) {\n\t\t\tint x, y, cost, dir, nxdir;\n\t\t\ttie(cost, y, x, dir) = q.top(); q.pop();\n\t\t\tnxdir = dir;\n\t\t\tif (dist[y][x][dir] < cost)continue;\n\t\t\tint command = masu[y][x];\n\n\t\t\tif (command >= 0 && command <= 3) {\n\t\t\t\tnxdir = nxtstep(command, dir);\n\t\t\t\tint ny = y + DY[nxdir];\n\t\t\t\tint nx = x + DX[nxdir];\n\t\t\t\tif (is_in(nx, ny, H, W)) {\n\t\t\t\t\tif (dist[ny][nx][nxdir] > cost) {\n\t\t\t\t\t\tdist[ny][nx][nxdir] = cost;\n\t\t\t\t\t\tq.push(tp(cost, ny, nx, nxdir));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t// change\n\t\t\tFOR(i, 0, 4) {\n\t\t\t\tnxdir = nxtstep(i, dir);\n\t\t\t\tint ny = y + DY[nxdir];\n\t\t\t\tint nx = x + DX[nxdir];\n\t\t\t\tif (is_in(nx, ny, H, W)) {\n\t\t\t\t\tif (dist[ny][nx][nxdir] > cost + co[i]) {\n\t\t\t\t\t\tdist[ny][nx][nxdir] = cost + co[i];\n\t\t\t\t\t\tq.push(tp(dist[ny][nx][nxdir], ny, nx, nxdir));\n\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint ans = INF;\n\t\tFOR(i, 0, 4) {\n\t\t\tans = min(ans, dist[H - 1][W - 1][i]);\n\t\t}\n\t\tcout << ans << \"\\n\";\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3588, "score_of_the_acc": -0.4759, "final_rank": 8 }, { "submission_id": "aoj_1156_10671414", "code_snippet": "#include <queue>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n// #ifndef ONLINE_JUDGE\n// #define _GLIBCXX_DEBUG // 配列外参照のエラー\n// #endif\n\n// スタンダードライブラリ\n#include <bits/stdc++.h>\nusing namespace std;\n\n// 型関連\nusing ll = long long;\nusing lint = long long;\nusing pll = pair<ll, ll>;\nusing plll = tuple<ll, ll, ll>;\nusing pii = pair<int, int>;\nusing piii = tuple<ll, ll, ll>;\nusing vi = vector<int>;\nusing vvi = vector<vector<int>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing vvvvi = vector<vector<vector<vector<int>>>>;\nusing vl = vector<ll>;\nusing vvl = vector<vector<ll>>;\nusing vvvl = vector<vector<vector<ll>>>;\nusing vvvvl = vector<vector<vector<vector<ll>>>>;\n\ntemplate <class T> using prique = priority_queue<T>;\n\n// 型定数\nconstexpr ll mod = 998244353;\nconstexpr ll MOD = 1000000007;\nint INF32 = 2e9;\nll INF64 = 9e18;\n#define endl '\\n';\n\nint dx[4] = {1, 0, -1, 0};\nint dy[4] = {0, 1, 0, -1};\n\n/////////////////////////// print関連\ntemplate <typename T> void print(vector<T> A);\nvoid print();\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail);\nvoid print(string S);\ntemplate <typename T> void print(vector<vector<T>> &F);\n\ninline void Yes(bool f);\n\nusing piiii = tuple<int,int,int,int>;\n\n///////////////////ここから//////////////////////\nbool solve() {\n \n int W, H;\n cin >> W >> H;\n if (H == 0) {\n return false;\n }\n vvi S(H, vi(W));\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n cin>>S[i][j];\n }\n }\n vi C(4);\n for (int i = 0; i < 4; i++) {\n cin>>C[i];\n }\n\n\n int dn[4] = {0, 3, 2, 1};\n vvvi dist(H, vvi(W, vi(4, INF32)));\n vvvi f(H, vvi(W, vi(4, 0)));\n priority_queue<piiii, vector<piiii>, greater<piiii>> que;\n que.emplace(0, 0, 0, 1);\n dist[0][0][1] = 0;\n while (!que.empty()) {\n auto [dis, i, j, d] = que.top();\n que.pop();\n if (f[i][j][d]) {\n continue;\n }\n f[i][j][d] = true;\n for (int n = 0; n < 4; n++) {\n int cost=0;\n if (S[i][j] != n) {\n cost+=C[n];\n }\n int nd = (d + dn[n]) % 4;\n int ni = i + dx[nd], nj = j + dy[nd];\n if (ni < 0 || ni >= H || nj < 0 || nj >= W) {\n continue;\n }\n if (dist[ni][nj][nd] > dis + cost) {\n dist[ni][nj][nd] = dis + cost;\n que.emplace(dis+cost,ni,nj,nd);\n }\n }\n }\n print(*min_element(dist[H - 1][W - 1].begin(), dist[H - 1][W - 1].end()));\n \n \n\n\n\n return true;\n}\n\n\nint main() {\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n while (solve());\n}\n\n////////////////////print/////////////////////////\n// 1次元ベクトルを出力する\ntemplate <typename T> void print(vector<T> A) {\n if (A.size() == 0) {\n return;\n }\n for (size_t i = 0; i < A.size() - 1; i++) {\n cout << A[i] << ' ';\n }\n cout << A[A.size() - 1] << endl;\n return;\n}\n\n// 2次元ベクトルを出力する\ntemplate <typename T> void print(vector<vector<T>> &F) {\n for (size_t i = 0; i < F.size(); i++) {\n for (size_t j = 0; j < F[i].size(); j++) {\n cout << F[i][j];\n if (j < F[i].size() - 1) {\n cout << ' ';\n }\n }\n cout << endl;\n }\n}\n\n// 空白行を出力するprint\nvoid print() { cout << endl; }\n\n// 数値・文字列を空白区切りで出力する. print(a,b)など\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n cout << head;\n if (sizeof...(tail) != 0)\n cout << \" \";\n print(forward<Tail>(tail)...);\n}\n\nvoid print(string S) { cout << S << endl; }\n\n//////////////出力関連\n\ninline void Yes(bool f) {\n if (f) {\n cout << \"Yes\" << endl;\n } else {\n cout << \"No\" << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3840, "score_of_the_acc": -0.8128, "final_rank": 14 }, { "submission_id": "aoj_1156_10647618", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nbool solve() {\n int H, W;\n cin >> W >> H;\n if (H == 0 && W == 0) return false;\n vector<vector<int>> S(H, vector<int>(W));\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) cin >> S[i][j];\n }\n vector<int> C(4);\n for (int i = 0; i < 4; i++) cin >> C[i];\n int D[5] = {0, 1, 0, -1, 0};\n vector<vector<vector<int>>> cost(H, vector<vector<int>>(W, vector<int>(4, 1 << 30)));\n cost[0][0][0] = 0;\n // (cost, r, c, dir)\n priority_queue<tuple<int, int, int, int>, vector<tuple<int, int, int, int>>, greater<tuple<int, int, int, int>>> q;\n q.emplace(0, 0, 0, 0);\n while (q.size()) {\n auto [ct, r, c, d] = q.top();\n q.pop();\n if (cost[r][c][d] < ct) continue;\n for (int i = 0; i < 4; i++) {\n int nd = (d + i) % 4;\n int nr = r + D[nd], nc = c + D[nd + 1];\n if (0 <= nr && nr < H && 0 <= nc && nc < W) {\n if (cost[nr][nc][nd] > ct + C[i] * (i != S[r][c])) {\n cost[nr][nc][nd] = ct + C[i] * (i != S[r][c]);\n q.emplace(cost[nr][nc][nd], nr, nc, nd);\n }\n }\n }\n }\n cout << *min_element(cost[H - 1][W - 1].begin(), cost[H - 1][W - 1].end()) << endl;\n return true;\n}\n\nint main() {\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3712, "score_of_the_acc": -0.6417, "final_rank": 10 }, { "submission_id": "aoj_1156_10608094", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconst int INF = 2e9;\nint dx[] = {0, 1, 0, -1};\nint dy[] = {1, 0, -1, 0};\n\nvoid solve(int w, int h, vector<vector<int>> grid, vector<int> c) {\n priority_queue<tuple<int, int, int, int>, vector<tuple<int, int, int, int>>, greater<>> pq;\n vector dist(h, vector(w, vector(4, INF)));\n pq.emplace(0, 0, 0, 0);\n dist[0][0][0] = 0;\n while (!pq.empty()) {\n auto [cost, x, y, d] = pq.top();\n pq.pop();\n if (dist[x][y][d] < cost) {\n continue;\n }\n for (int i = 0; i < 4; i++) {\n int nd = (d + i) % 4;\n int nx = x + dx[nd];\n int ny = y + dy[nd];\n if (nx < 0 || nx >= h || ny < 0 || ny >= w) {\n continue;\n }\n int next_cost = cost + (grid[x][y] == i ? 0 : c[i]);\n if (dist[nx][ny][nd] > next_cost) {\n dist[nx][ny][nd] = next_cost;\n pq.emplace(next_cost, nx, ny, nd);\n }\n }\n }\n\n int ans = *ranges::min_element(dist[h - 1][w - 1]);\n cout << (ans == INF ? -1 : ans) << endl;\n}\n\nint main() {\n while (true) {\n int w, h;\n cin >> w >> h;\n if (w == 0 && h == 0) {\n break;\n }\n\n vector s(h, vector<int>(w));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n cin >> s[i][j];\n }\n }\n vector<int> c(4);\n for (int i = 0; i < 4; i++) {\n cin >> c[i];\n }\n\n solve(w, h, s, c);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3712, "score_of_the_acc": -0.6417, "final_rank": 10 }, { "submission_id": "aoj_1156_10608091", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconst int INF = 2e9;\nint dx[] = {0, 1, 0, -1};\nint dy[] = {1, 0, -1, 0};\n\nvoid solve(int w, int h, vector<vector<int>> grid, vector<int> c) {\n priority_queue<tuple<int, int, int, int>, vector<tuple<int, int, int, int>>, greater<>> pq;\n vector dist(h, vector(w, vector(4, INF)));\n pq.emplace(0, 0, 0, 0);\n dist[0][0][0] = 0;\n while (!pq.empty()) {\n auto [cost, x, y, d] = pq.top();\n pq.pop();\n if (dist[x][y][d] < cost) {\n continue;\n }\n for (int i = 0; i < 4; i++) {\n int nd = (d + i) % 4;\n int nx = x + dx[nd];\n int ny = y + dy[nd];\n if (nx < 0 || nx >= h || ny < 0 || ny >= w) {\n continue;\n }\n int next_cost = cost + (grid[x][y] == i ? 0 : c[i]);\n if (dist[nx][ny][nd] > next_cost) {\n dist[nx][ny][nd] = next_cost;\n pq.emplace(next_cost, nx, ny, nd);\n }\n }\n }\n\n int ans = INF;\n for (int dir = 0; dir < 4; dir++) {\n ans = min(ans, dist[h - 1][w - 1][dir]);\n }\n cout << (ans == INF ? -1 : ans) << endl;\n}\n\nint main() {\n while (true) {\n int w, h;\n cin >> w >> h;\n if (w == 0 && h == 0) {\n break;\n }\n\n vector s(h, vector<int>(w));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n cin >> s[i][j];\n }\n }\n vector<int> c(4);\n for (int i = 0; i < 4; i++) {\n cin >> c[i];\n }\n\n solve(w, h, s, c);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3712, "score_of_the_acc": -0.6417, "final_rank": 10 }, { "submission_id": "aoj_1156_10608087", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconst int INF = 2e9;\nint dx[] = {0, 1, 0, -1};\nint dy[] = {1, 0, -1, 0};\n\nvoid solve(int w, int h, vector<vector<int>> grid, vector<int> c) {\n priority_queue<tuple<int, int, int, int>, vector<tuple<int, int, int, int>>, greater<>> pq;\n vector dist(h, vector(w, vector(4, INF)));\n pq.emplace(0, 0, 0, 0);\n dist[0][0][0] = 0;\n while (!pq.empty()) {\n auto [cost, x, y, d] = pq.top();\n pq.pop();\n\n if (dist[x][y][d] < cost) {\n continue;\n }\n\n for (int i = 0; i < 4; i++) {\n // 命令通りに行動する場合(コスト0)\n if (grid[x][y] == i) {\n int nd = (d + grid[x][y]) % 4;\n int nx = x + dx[nd];\n int ny = y + dy[nd];\n if (nx < 0 || nx >= h || ny < 0 || ny >= w) {\n continue;\n }\n if (dist[nx][ny][nd] > cost) {\n dist[nx][ny][nd] = cost;\n pq.emplace(cost, nx, ny, nd);\n }\n } else {\n // 別の命令を行う場合(コストci)\n int nd = (d + i) % 4;\n int nx = x + dx[nd];\n int ny = y + dy[nd];\n if (nx < 0 || nx >= h || ny < 0 || ny >= w) {\n continue;\n }\n int next_cost = cost + c[i];\n if (dist[nx][ny][nd] > next_cost) {\n dist[nx][ny][nd] = next_cost;\n pq.emplace(next_cost, nx, ny, nd);\n }\n }\n }\n }\n\n int ans = INF;\n for (int dir = 0; dir < 4; dir++) {\n ans = min(ans, dist[h - 1][w - 1][dir]);\n }\n cout << (ans == INF ? -1 : ans) << endl;\n}\n\nint main() {\n while (true) {\n int w, h;\n cin >> w >> h;\n if (w == 0 && h == 0) {\n break;\n }\n\n vector s(h, vector<int>(w));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n cin >> s[i][j];\n }\n }\n vector<int> c(4);\n for (int i = 0; i < 4; i++) {\n cin >> c[i];\n }\n\n solve(w, h, s, c);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3840, "score_of_the_acc": -0.8128, "final_rank": 14 }, { "submission_id": "aoj_1156_10603199", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rrep(i,start,end) for (ll i = start;i >= (ll)(end);i--)\n#define repn(i,end) for(ll i = 0; i <= (ll)(end); i++)\n#define reps(i,start,end) for(ll i = start; i < (ll)(end); i++)\n#define repsn(i,start,end) for(ll i = start; i <= (ll)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef vector<ll> vll;\ntypedef vector<pair<ll ,ll>> vpll;\ntypedef vector<vector<ll>> vvll;\ntypedef set<ll> sll;\ntypedef map<ll , ll> mpll;\ntypedef pair<ll ,ll> pll;\ntypedef tuple<ll , ll , ll> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (ll)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1LL << 60;\nconst ld EPS = 1e-9;\n \nll lceil(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b)+1;}else{return -((-a)/b);}}\nll lfloor(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b);}else{return -((-a)/b)-1;}}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\n//0indexed\ninline ll topbit(ll a){assert(a != 0);return 63 - __builtin_clzll(a);}\ninline ll smlbit(ll a){assert(a != 0);return __builtin_ctzll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,1,0,-1,1,1,-1,-1};\nvector<ll> _yo = {1,0,-1,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\nvoid solve(ll h,ll w){\n vvll g(h,vll(w));\n rep(i,h)cin >> g[i];\n vll c(4);cin >> c;\n\n vector<vvll> dist(h,vvll(w,vll(4,INF)));\n using tpl4 = tuple<ll,ll,ll,ll>;\n priority_queue<tpl4,vector<tpl4>,greater<tpl4>> pq;\n // 0,1,2,3 : 右下左上\n dist[0][0][0] = 0;\n pq.push({0,0,0,0});\n while(!pq.empty()){\n auto[cost,y,x,d] = pq.top();\n pq.pop();\n if(g[y][x] < 4){\n ll nd = (d+g[y][x])%4;\n ll ny = y + _ta[nd];\n ll nx = x + _yo[nd];\n if(isin(ny,nx,h,w) && dist[ny][nx][nd] > cost){\n dist[ny][nx][nd] = cost;\n pq.push({dist[ny][nx][nd],ny,nx,nd});\n }\n }\n rep(i,4){\n ll nd = (d+i)%4;\n ll ny = y + _ta[nd];\n ll nx = x + _yo[nd];\n if(isin(ny,nx,h,w) && dist[ny][nx][nd] > cost + c[i]){\n dist[ny][nx][nd] = cost + c[i];\n pq.push({dist[ny][nx][nd],ny,nx,nd});\n }\n }\n }\n ll ans = INF;\n rep(i,4){\n chmin(ans,dist[h-1][w-1][i]);\n }\n cout << ans << endl;\n}\n \nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true){\n LL(w,h);\n if(w == 0 && h == 0)break;\n solve(h,w);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3968, "score_of_the_acc": -0.984, "final_rank": 16 }, { "submission_id": "aoj_1156_10591098", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define all(a) (a).begin(), (a).end()\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rrep(i, n) for (int i = (int)(n); i >= 0; i--)\n#define range(i, l, r) for (int i = (int)(l); i < (int)(r); i++)\nusing ll = long long;\n\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v) {\n os << \"[\";\n for (int i = 0; i < v.size(); i++) {\n os << v[i] << (i == (v.size() - 1) ? \"\" : \", \");\n }\n os << \"]\";\n return os;\n}\n\ntemplate <typename T1, typename T2>\nostream& operator<<(ostream& os, const pair<T1, T2> p) {\n os << \"{\" << p.first << \", \" << p.second << \"}\";\n return os;\n}\n\nbool solve() {\n int w, h;\n cin >> w >> h;\n if (w == 0) return false;\n\n int s[h][w];\n rep(i, h) rep(j, w) cin >> s[i][j];\n\n int cost[4], _cost[4];\n rep(i, 4) {\n cin >> cost[i];\n _cost[i] = cost[i];\n }\n\n vector<pair<int, int>> dir = {{0, 1}, {-1, 0}, {0, -1}, {1, 0}};\n int dp[h][w][4];\n int inf = 1 << 20;\n rep(i, h) rep(j, w) rep(k, 4) dp[i][j][k] = inf;\n dp[0][0][0] = 0;\n\n priority_queue<array<int, 4>> pq{};\n pq.push({0, 0, 0, 0});\n while (!pq.empty()) {\n auto [d, i, j, k] = pq.top();\n pq.pop();\n d = -d;\n if (s[i][j] < 4) cost[s[i][j]] = 0;\n rep(x, 4) {\n k = (k + 4 - x) % 4;\n auto [di, dj] = dir[k];\n if (0 <= i + di && i + di < h && 0 <= j + dj && j + dj < w) {\n if (dp[i + di][j + dj][k] > d + cost[x]) {\n dp[i + di][j + dj][k] = d + cost[x];\n pq.push({-d - cost[x], i + di, j + dj, k});\n }\n }\n k = (k + x) % 4;\n }\n if (s[i][j] < 4) cost[s[i][j]] = _cost[s[i][j]];\n }\n\n int ans = inf;\n rep(x, 4) ans = min(ans, dp[h - 1][w - 1][x]);\n cout << ans << endl;\n return true;\n}\n\nint main() {\n while (solve()) {\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3584, "score_of_the_acc": -0.4706, "final_rank": 6 }, { "submission_id": "aoj_1156_9555797", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint dx[4] = {0,1,0,-1}, dy[4] = {1,0,-1,0};\n\nint main() {\nwhile(1) {\n int N, M;\n cin >> M >> N;\n if (N == 0 && M == 0) return 0;\n vector<vector<int>> A(N,vector<int>(M));\n rep(i,0,N) {\n rep(j,0,M) {\n char C;\n cin >> C;\n A[i][j] = C - '0';\n }\n }\n int Cost[4];\n rep(i,0,4) cin >> Cost[i];\n vector DP(N, vector(M, vector<int>(4,inf)));\n priority_queue<pair<int,int>,vector<pair<int,int>>,greater<pair<int,int>>> PQ;\n auto encode = [&](int i, int j, int k) -> int {\n return i * M * 4 + j * 4 + k;\n };\n auto decode = [&](int a) -> tuple<int,int,int> {\n return {a / (M * 4), (a / 4) % M, a % 4};\n };\n DP[0][0][0] = 0;\n PQ.push({0,encode(0,0,0)});\n while(!PQ.empty()) {\n pair<int,int> P = PQ.top();\n PQ.pop();\n int C = P.first;\n auto [X, Y, dir] = decode(P.second);\n if (DP[X][Y][dir] < C) continue;\n rep(i,0,4) {\n int NC;\n if (i == A[X][Y]) NC = C;\n else NC = C + Cost[i];\n int Ndir = (dir + i) % 4;\n int NX = X + dx[Ndir], NY = Y + dy[Ndir];\n if (0 <= NX && NX < N && 0 <= NY && NY < M) {\n if (chmin(DP[NX][NY][Ndir],NC)) {\n PQ.push({NC, encode(NX,NY,Ndir)});\n }\n }\n }\n }\n int ANS = inf;\n rep(i,0,4) {\n chmin(ANS, DP[N-1][M-1][i]);\n }\n cout << ANS << endl;\n}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3520, "score_of_the_acc": -0.385, "final_rank": 3 }, { "submission_id": "aoj_1156_9365677", "code_snippet": "#include<bits/stdc++.h>\n//#include <atcoder/all>\nusing namespace std;\n//using namespace atcoder;\n\n#define all(v) v.begin(),v.end()\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll=vector<ll>;\nusing vvll = vector<vector<ll>>;\nusing P = pair<ll,ll>;\nusing PP=pair<ll,pair<P,ll>>;\nusing vp=vector<pair<ll, ll>>;\n//using mint=modint1000000007;\n//using mint=modint998244353;\n\nconst ll INF=1ll<<60;\nll mod10=1e9+7;\nll mod99=998244353;\nconst double PI = acos(-1);\n\n#define rep(i,n) for (ll i=0;i<n;++i)\n#define per(i,n) for(ll i=n-1;i>=0;--i)\n#define rep2(i,a,n) for (ll i=a;i<n;++i)\n#define per2(i,a,n) for (ll i=a;i>=n;--i)\n\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\nvector<ll> dx={1,0,-1,0,-1,-1,1,1,0},dy={0,1,0,-1,-1,1,-1,1,0};\n\nbool solve(){\n ll H,W;cin>>W>>H;\n if(H==W&&H==0) return 0;\n vvll A(H,vll(W));\n rep(i,H) rep(j,W) cin>>A[i][j];\n vll C(4);rep(i,4) cin>>C[i];\n\n vector dist(H,vvll(W,vll(4,INF)));\n priority_queue<PP,vector<PP>,greater<PP>> pq;\n pq.push({0,{{0,0},1}});\n while(pq.size()){\n auto [c,in]=pq.top();pq.pop();\n auto [now,d]=in;\n auto [nowi,nowj]=now;\n if(dist[nowi][nowj][d]!=INF) continue;\n // cout << nowi<<\" \"<<nowj<<\" \"<<c<<\" \"<<A[nowi][nowj] << endl;\n \n dist[nowi][nowj][d]=c;\n if(A[nowi][nowj]!=4){\n ll d2=(d-A[nowi][nowj]+4)%4;\n ull toi=nowi+dx[d2],toj=nowj+dy[d2];\n \n if((toi<H&&toj<W))pq.push({c,{{toi,toj},d2}});;\n \n }\n rep(k,4){\n ll d2=(d-k+4)%4;\n ull toi=nowi+dx[d2],toj=nowj+dy[d2];\n if(!(toi<H&&toj<W)) continue;\n pq.push({c+C[k],{{toi,toj},d2}});\n }\n }\n\n ll ans=INF;\n rep(i,4) chmin(ans,dist[H-1][W-1][i]);\n cout << ans << endl;\n\n return 1;\n}\n\n\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n while(solve());\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3928, "score_of_the_acc": -1.0555, "final_rank": 19 }, { "submission_id": "aoj_1156_9363862", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\nusing ll = long long;\n#define MOD 1000000007\n#define Mod 998244353\nconst int MAX = 1000000005;\nconst long long INF = 1000000000000000005LL;\nusing namespace std;\n//using namespace atcoder;\n\nint di[] = {0, 1, 0, -1}, dj[] = {1, 0, -1, 0};\nusing i_i_i_i = tuple<int, int, int, int>;\n\nbool solve() {\n int w, h;\n cin >> w >> h;\n if (h == 0 && w == 0) return false;\n vector<vector<int>> G(h, vector<int>(w));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) cin >> G[i][j];\n }\n vector<int> c(4);\n for (int i = 0; i < 4; i++) cin >> c[i];\n vector<vector<vector<int>>> dist(h, vector<vector<int>>(w, vector<int>(4, MAX)));\n dist[0][0][0] = 0;\n priority_queue<i_i_i_i, vector<i_i_i_i>, greater<i_i_i_i>> pq;\n pq.push({0, 0, 0, 0});\n while (pq.size()) {\n auto [d, i, j, dir] = pq.top();\n pq.pop();\n if (d != dist[i][j][dir]) continue;\n for (int k = 0; k < 4; k++) {\n int ndir = (dir + k)%4, ni = i + di[ndir], nj = j + dj[ndir];\n if (ni < 0 || ni >= h || nj < 0 || nj >= w) continue;\n if (G[i][j] == k) {\n if (dist[ni][nj][ndir] <= dist[i][j][dir]) continue;\n dist[ni][nj][ndir] = dist[i][j][dir];\n pq.push({dist[ni][nj][ndir], ni, nj, ndir});\n } else {\n if (dist[ni][nj][ndir] <= dist[i][j][dir] + c[k]) continue;\n dist[ni][nj][ndir] = dist[i][j][dir] + c[k];\n pq.push({dist[ni][nj][ndir], ni, nj, ndir});\n }\n }\n }\n int ans = MAX;\n for (int i = 0; i < 4; i++) ans = min(ans, dist[h-1][w-1][i]);\n cout << ans << endl;\n return true;\n}\n\nint main() {\n ios::sync_with_stdio(0); cin.tie();\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3540, "score_of_the_acc": -0.4118, "final_rank": 4 }, { "submission_id": "aoj_1156_9346914", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < n; i++)\nusing namespace std;\nvoid chmin(int &l, int r) {\n if (l > r) {\n l = r;\n }\n}\n\nbool solve() {\n int w, h; cin >> w >> h;\n if (w == 0 and h == 0) return false;\n vector C(h, vector<int>(w));\n rep(i, h) rep(j, w) cin >> C[i][j];\n int m = 4;\n vector<int> co(m); rep(i, m) cin >> co[i];\n int INF = 1001001001;\n vector dp(h, vector(w, vector(m + 1, INF)));\n vector<int> di = { 0, 1, 0, -1, 0 };\n vector<int> dj = { 1, 0, -1, 0, 0 };\n using S = tuple<int, int, int, int>;\n priority_queue<S, vector<S>, greater<S>> pq;\n dp[0][0][0] = 0;\n pq.emplace(0, 0, 0, 0);\n while (pq.size()) {\n auto [c, i, j, dir] = pq.top(); pq.pop();\n // cerr << c << \" \" << i << \" \" << j << \" \" << dir << endl;\n if (c != dp[i][j][dir]) continue;\n // change\n for (int k = 0; k < 4; k++) {\n int ndir = (dir + k) % 4;\n int ni = i + di[ndir];\n int nj = j + dj[ndir];\n if (ni < 0 or nj < 0 or ni >= h or nj >= w) continue;\n int nc = c + co[k];\n if (dp[ni][nj][ndir] <= nc) continue;\n dp[ni][nj][ndir] = nc;\n pq.emplace(nc, ni, nj, ndir);\n }\n if (C[i][j] < m) {\n int ndir = (dir + C[i][j]) % 4;\n int ni = i + di[ndir];\n int nj = j + dj[ndir];\n if (ni < 0 or nj < 0 or ni >= h or nj >= w) continue;\n // don't change\n if (dp[ni][nj][ndir] <= c) continue;\n dp[ni][nj][ndir] = c;\n pq.emplace(c, ni, nj, ndir);\n }\n }\n // rep(k, 5) {\n // cerr << endl;\n // rep(i, h) rep(j, w) {\n // cerr << (dp[i][j][k] == INF ? -1 : dp[i][j][k]) << (j + 1 == w ? \"\\n\" : \" \");\n // }\n // }\n int ans = INF;\n rep(i, 5) chmin(ans, dp[h - 1][w - 1][i]);\n if (ans == INF) ans = -1;\n cout << ans << endl;\n return true;\n}\n\nint main() {\n while (solve());\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3556, "score_of_the_acc": -0.4748, "final_rank": 7 }, { "submission_id": "aoj_1156_9277691", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (n); i++)\n#ifdef Himesaka\n#include <noachan.hpp>\n#define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define debug(...) (static_cast<void>(0))\n#endif\nstruct e\n{\n int di{};\n int y{}, x{};\n int cost{};\n};\nbool is_out(int y, int x, int h, int w)\n{\n return (!((0 <= y && y < h) && (0 <= x && x < w)));\n}\n\ntemplate <class T>\nbool chmin(T &a, const T &b)\n{\n return a > b ? a = b, true : false;\n}\n\npair<int, int> go_str(int y, int x, int dir)\n{\n if (dir == 0)\n y--;\n if (dir == 1)\n x++;\n if (dir == 2)\n y++;\n if (dir == 3)\n x--;\n return make_pair(y, x);\n}\nint right(int d)\n{\n d++;\n d %= 4;\n return d;\n}\nint left(int d)\n{\n d += 3;\n d %= 4;\n return d;\n}\nint odd(int d)\n{\n d += 2;\n d %= 4;\n return d;\n}\nint main()\n{\n const int inf = INT_MAX / 2;\n for (;;)\n {\n int w, h;\n cin >> w >> h;\n if (!w && (!h))\n break;\n vector<vector<int>> s(h, vector<int>(w));\n rep(i, h) rep(j, w) cin >> s[i][j];\n\n vector<int> c(4);\n rep(i, 4) cin >> c[i];\n\n // y,x,向き(0上,1右,2下,3左)\n\n int dist[h][w][4];\n rep(i, h) rep(j, w) rep(k, 4) dist[i][j][k] = inf;\n dist[0][0][1] = 0;\n\n int y = 0, x = 0;\n // dir,y,x,cost\n auto comp = [](const e &a, const e &b)\n {\n return a.cost < b.cost;\n };\n // multiset<e, decltype(comp)> q;\n multiset<e, decltype(comp)> q(comp);\n q.insert({1, y, x, 0});\n int ans = inf;\n while (q.size())\n {\n auto [dir, y, x, cost] = *q.begin();\n q.erase(q.begin());\n int ndir = dir;\n if (s[y][x] == 0)\n {\n // 直進\n }\n else if (s[y][x] == 1)\n {\n // 右折\n ndir = right(dir);\n }\n else if (s[y][x] == 2)\n {\n ndir = odd(dir);\n }\n else if (s[y][x] == 3)\n {\n ndir = left(dir);\n }\n else if (s[y][x] == 4)\n {\n // 停止\n rep(i, 4)\n {\n ndir = dir;\n if (i == s[y][x])\n continue;\n if (i == 0)\n {\n }\n if (i == 1)\n ndir = right(dir);\n if (i == 2)\n ndir = odd(dir);\n if (i == 3)\n ndir = left(dir);\n auto [ny, nx] = go_str(y, x, ndir);\n if (!is_out(ny, nx, h, w))\n {\n if (ny == h - 1 && nx == w - 1)\n {\n chmin(ans, dist[y][x][dir] + c[i]);\n continue;\n }\n if (chmin(dist[ny][nx][ndir], dist[y][x][dir] + c[i]))\n q.insert({ndir, ny, nx, 0});\n }\n }\n continue;\n }\n auto [ny, nx] = go_str(y, x, ndir);\n if (!is_out(ny, nx, h, w))\n {\n if (ny == h - 1 && nx == w - 1)\n {\n chmin(ans, dist[y][x][dir]);\n continue;\n }\n if (chmin(dist[ny][nx][ndir], dist[y][x][dir]))\n q.insert({ndir, ny, nx, 0});\n }\n // コストを支払う場合\n // 直進\n rep(i, 4)\n {\n ndir = dir;\n if (i == s[y][x])\n continue;\n if (i == 0)\n {\n }\n if (i == 1)\n ndir = right(dir);\n if (i == 2)\n ndir = odd(dir);\n if (i == 3)\n ndir = left(dir);\n auto [ny, nx] = go_str(y, x, ndir);\n if (!is_out(ny, nx, h, w))\n {\n if (ny == h - 1 && nx == w - 1)\n {\n chmin(ans, dist[y][x][dir] + c[i]);\n continue;\n }\n if (chmin(dist[ny][nx][ndir], dist[y][x][dir] + c[i]))\n q.insert({ndir, ny, nx, 0});\n }\n }\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3492, "score_of_the_acc": -0.7226, "final_rank": 13 }, { "submission_id": "aoj_1156_9243350", "code_snippet": "#include <algorithm>\n#include <cmath>\n#include <cstdlib>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <unordered_set>\n#include <vector>\n\n#define INF (1000000000)\n\nusing namespace std;\nusing ll = long long;\n\ntemplate <typename T>\nconstexpr bool chmin(T& min, const T target) {\n\tif (target < min) {\n\t\tmin = target;\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n// 命令\n// 0: 「直進」命令\n// 1: 「右折」命令\n// 2: 「反転」命令\n// 3: 「左折」命令\n// 4: 「停止」命令\n\n// 方向\n// 0: 右\n// 1: 下\n// 2: 左\n// 3: 上\n\nint main(void) {\n\tconst int directions[4][2]{{0, 1}, {1, 0}, {0, -1}, {-1, 0}};\n\n\twhile (true) {\n\t\tint W, H, costs[4];\n\t\tcin >> W >> H;\n\t\tif (W == 0) break;\n\t\tvector<vector<int>> commands(H, vector<int>(W));\n\t\tfor (vector<int>& row : commands) {\n\t\t\tfor (int& sqr : row) cin >> sqr;\n\t\t}\n\t\tfor (int& cost : costs) cin >> cost;\n\n\t\tint count_done_goal = 0;\n\t\tint recent_done_r = 0, recent_done_c = 0, recent_done_d = 0;\n\t\tvector<vector<vector<int>>> distances(H, vector<vector<int>>(W, vector<int>(4, INF)));\n\t\tdistances[recent_done_r][recent_done_c][recent_done_d] = 0;\n\t\tvector<vector<vector<bool>>> done(H, vector<vector<bool>>(W, vector<bool>(4, false)));\n\t\tdone[recent_done_r][recent_done_c][recent_done_d] = true;\n\t\twhile (true) {\n\t\t\tfor (int cmd = 0; cmd < 4; cmd++) {\n\t\t\t\tint turn_to = (recent_done_d + cmd) % 4;\n\t\t\t\tint adjacent_r = recent_done_r + directions[turn_to][0];\n\t\t\t\tint adjacent_c = recent_done_c + directions[turn_to][1];\n\t\t\t\tif (adjacent_r < 0 || H <= adjacent_r || adjacent_c < 0 || W <= adjacent_c || done[adjacent_r][adjacent_c][turn_to]) continue;\n\t\t\t\tint new_distance = distances[recent_done_r][recent_done_c][recent_done_d];\n\t\t\t\tif (cmd != commands[recent_done_r][recent_done_c]) new_distance += costs[cmd];\n\t\t\t\tchmin(distances[adjacent_r][adjacent_c][turn_to], new_distance);\n\t\t\t}\n\n\t\t\tint min_distance = INF, min_r, min_c, min_d;\n\t\t\tfor (int r = 0; r < H; r++) {\n\t\t\t\tfor (int c = 0; c < W; c++) {\n\t\t\t\t\tfor (int d = 0; d < 4; d++) {\n\t\t\t\t\t\tif (done[r][c][d]) continue;\n\t\t\t\t\t\tif (chmin(min_distance, distances[r][c][d])) {\n\t\t\t\t\t\t\tmin_r = r;\n\t\t\t\t\t\t\tmin_c = c;\n\t\t\t\t\t\t\tmin_d = d;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tdone[min_r][min_c][min_d] = true;\n\t\t\trecent_done_r = min_r;\n\t\t\trecent_done_c = min_c;\n\t\t\trecent_done_d = min_d;\n\n\t\t\tif (recent_done_r == H - 1 && recent_done_c == W - 1) {\n\t\t\t\tcount_done_goal++;\n\t\t\t\tif (count_done_goal == 2) break;\n\t\t\t}\n\t\t}\n\n\t\tint min_distance_goal = INF;\n\t\tfor (int d = 0; d < 4; d++) {\n\t\t\tchmin(min_distance_goal, distances[H - 1][W - 1][d]);\n\t\t}\n\n\t\tcout << min_distance_goal << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 3524, "score_of_the_acc": -1.3904, "final_rank": 20 }, { "submission_id": "aoj_1156_9243338", "code_snippet": "#include <algorithm>\n#include <cmath>\n#include <cstdlib>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <unordered_set>\n#include <vector>\n\n#define INF (1000000000)\n\nusing namespace std;\nusing ll = long long;\n\ntemplate <typename T>\nconstexpr bool chmin(T& min, const T target) {\n\tif (target < min) {\n\t\tmin = target;\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n// 命令\n// 0: 「直進」命令\n// 1: 「右折」命令\n// 2: 「反転」命令\n// 3: 「左折」命令\n// 4: 「停止」命令\n\n// 方向\n// 0: 右\n// 1: 下\n// 2: 左\n// 3: 上\n\nint main(void) {\n\tconst int directions[4][2]{{0, 1}, {1, 0}, {0, -1}, {-1, 0}};\n\n\twhile (true) {\n\t\tint W, H, costs[4];\n\t\tcin >> W >> H;\n\t\tif (W == 0) break;\n\t\tvector<vector<int>> commands(H, vector<int>(W));\n\t\tfor (vector<int>& row : commands) {\n\t\t\tfor (int& sqr : row) cin >> sqr;\n\t\t}\n\t\tfor (int& cost : costs) cin >> cost;\n\n\t\tint count_done_goal = 0;\n\t\tint recent_done_r = 0, recent_done_c = 0, recent_done_d = 0;\n\t\tvector<vector<vector<int>>> distances(H, vector<vector<int>>(W, vector<int>(4, INF)));\n\t\tdistances[recent_done_r][recent_done_c][recent_done_d] = 0;\n\t\tvector<vector<vector<bool>>> done(H, vector<vector<bool>>(W, vector<bool>(4, false)));\n\t\tdone[recent_done_r][recent_done_c][recent_done_d] = true;\n\t\twhile (true) {\n\t\t\tfor (int cmd = 0; cmd < 4; cmd++) {\n\t\t\t\tint turn_to = (recent_done_d + cmd) % 4;\n\t\t\t\tint adjacent_r = recent_done_r + directions[turn_to][0];\n\t\t\t\tint adjacent_c = recent_done_c + directions[turn_to][1];\n\t\t\t\tif (adjacent_r < 0 || H <= adjacent_r || adjacent_c < 0 || W <= adjacent_c || done[adjacent_r][adjacent_c][turn_to]) continue;\n\t\t\t\tint new_distance = distances[recent_done_r][recent_done_c][recent_done_d];\n\t\t\t\tif (cmd != commands[recent_done_r][recent_done_c]) new_distance += costs[cmd];\n\t\t\t\tchmin(distances[adjacent_r][adjacent_c][turn_to], new_distance);\n\t\t\t}\n\n\t\t\tint min_distance = INF, min_r, min_c, min_d;\n\t\t\tfor (int r = 0; r < H; r++) {\n\t\t\t\tfor (int c = 0; c < W; c++) {\n\t\t\t\t\tfor (int d = 0; d < 4; d++) {\n\t\t\t\t\t\tif (done[r][c][d]) continue;\n\t\t\t\t\t\tif (chmin(min_distance, distances[r][c][d])) {\n\t\t\t\t\t\t\tmin_r = r;\n\t\t\t\t\t\t\tmin_c = c;\n\t\t\t\t\t\t\tmin_d = d;\n\n\t\t\t\t\t\t\tif (r == 0 && c == 3 && d == 0) {\n\t\t\t\t\t\t\t\tcout;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tdone[min_r][min_c][min_d] = true;\n\t\t\trecent_done_r = min_r;\n\t\t\trecent_done_c = min_c;\n\t\t\trecent_done_d = min_d;\n\n\t\t\t// cout << recent_done_r << \" \" << recent_done_c << \" \" << recent_done_d << endl;\n\n\t\t\tif (recent_done_r == 0 && recent_done_c == 3 && recent_done_d == 0) {\n\t\t\t\tcout;\n\t\t\t}\n\n\t\t\tif (recent_done_r == H - 1 && recent_done_c == W - 1) count_done_goal++;\n\t\t\tif (count_done_goal == 2) break;\n\t\t}\n\n\t\tint min_distance_goal = INF;\n\t\tfor (int d = 0; d < 4; d++) {\n\t\t\tchmin(min_distance_goal, distances[H - 1][W - 1][d]);\n\t\t}\n\n\t\tcout << min_distance_goal << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 3288, "score_of_the_acc": -0.9915, "final_rank": 17 }, { "submission_id": "aoj_1156_9147735", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\n#define rep(i, a, b) for(ll i = a; i < b; ++i)\n#define rrep(i, a, b) for(ll i = a; i >= b; --i)\nconstexpr ll inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\ntemplate <typename T = int>\nstruct Edge {\n int from, to;\n T cost;\n int idx;\n Edge()\n : from(-1), to(-1), cost(-1), idx(-1) {}\n Edge(int from, int to, T cost = 1, int idx = -1)\n : from(from), to(to), cost(cost), idx(idx) {}\n operator int() const {\n return to;\n }\n};\ntemplate <typename T = int>\nstruct Graph {\n Graph(int N)\n : n(N), es(0), g(N) {}\n int size() const {\n return n;\n }\n int edge_size() const {\n return es;\n }\n void add_edge(int from, int to, T cost = 1) {\n assert(0 <= from and from < n);\n assert(0 <= to and to < n);\n g[from].emplace_back(from, to, cost, es);\n g[to].emplace_back(to, from, cost, es++);\n }\n void add_directed_edge(int from, int to, T cost = 1) {\n assert(0 <= from and from < n);\n assert(0 <= to and to < n);\n g[from].emplace_back(from, to, cost, es++);\n }\n inline vector<Edge<T>>& operator[](const int& k) {\n assert(0 <= k and k < n);\n return g[k];\n }\n inline const vector<Edge<T>>& operator[](const int& k) const {\n assert(0 <= k and k < n);\n return g[k];\n }\n\n private:\n int n, es;\n vector<vector<Edge<T>>> g;\n};\ntemplate <typename T = int>\nusing Edges = vector<Edge<T>>;\ntemplate <typename T>\nvector<pair<T, int>> dijkstra(const Graph<T>& g, const int s = 0) {\n int n = g.size();\n assert(0 <= s and s < n);\n vector<pair<T, int>> d(n, {numeric_limits<T>::max(), -1});\n priority_queue<pair<T, int>, vector<pair<T, int>>, greater<pair<T, int>>> pq;\n d[s] = {0, -1};\n pq.push({0, s});\n while(!pq.empty()) {\n pair<T, int> p = pq.top();\n pq.pop();\n T dist = p.first;\n int cur = p.second;\n if(d[cur].first < dist) continue;\n for(const Edge<T>& edge : g[cur]) {\n if(d[edge.to].first > d[cur].first + edge.cost) {\n d[edge.to] = {d[cur].first + edge.cost, cur};\n pq.push({d[edge.to].first, edge.to});\n }\n }\n }\n return d;\n}\nint main(void) {\n constexpr int dx[4] = {0, 1, 0, -1}, dy[4] = {1, 0, -1, 0};\n while(1) {\n int w, h;\n cin >> w >> h;\n if(w == 0 and h == 0) break;\n vector<vector<int>> s(h, vector<int>(w));\n Graph<int> g(h * w * 4);\n rep(i, 0, h) {\n rep(j, 0, w) {\n cin >> s[i][j];\n }\n }\n vector<int> c(4);\n rep(i, 0, 4) {\n cin >> c[i];\n }\n rep(i, 0, h) {\n rep(j, 0, w) {\n rep(k, 0, 4) {\n rep(l, 0, 4) {\n int nk = (k + l) % 4;\n int ni = i + dx[nk], nj = j + dy[nk];\n if(0 <= ni and ni < h and 0 <= nj and nj < w) {\n g.add_directed_edge(i * w * 4 + j * 4 + k, ni * w * 4 + nj * 4 + nk, c[l]);\n }\n }\n }\n if(s[i][j] == 4) continue;\n rep(k, 0, 4) {\n int nk = (k + s[i][j]) % 4;\n int ni = i + dx[nk], nj = j + dy[nk];\n if(0 <= ni and ni < h and 0 <= nj and nj < w) {\n g.add_directed_edge(i * w * 4 + j * 4 + k, ni * w * 4 + nj * 4 + nk, 0);\n }\n }\n }\n }\n auto d = dijkstra(g, 0);\n cout << min({d[4 * h * w - 4].first, d[4 * h * w - 3].first, d[4 * h * w - 2].first, d[4 * h * w - 1].first}) << '\\n';\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3980, "score_of_the_acc": -1.0417, "final_rank": 18 }, { "submission_id": "aoj_1156_9119261", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n// #pragma GCC target(\"avx2\")\n// #pragma GCC optimize(\"O3\")\n// #pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = 3.141592653589793;\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\n\nvi dx = {-1, 0, 1, 0}, dy = {0, 1, 0, -1};\n\nint solve(int h, int w){\n vvi A(h, vi(w)); rep(i, h) rep(j, w) cin >> A[i][j];\n vi C(4); rep(i, 4) cin >> C[i];\n vvvi dist(h, vvi(w, vi(4, inf)));\n dist[0][0][1] = 0;\n using P = tuple<int, int, int, int>;\n priority_queue<P, vc<P>, greater<P>> q;\n q.push({0, 0, 0, 1});\n while (!q.empty()){\n auto [d, x, y, k] = q.top(); q.pop();\n if (dist[x][y][k] < d) continue;\n int nx1 = x + dx[k], ny1 = y + dy[k];\n if (A[x][y] == 0 && inside(nx1, ny1, h, w) && dist[nx1][ny1][k] > d){\n dist[nx1][ny1][k] = d;\n q.push({d, nx1, ny1, k});\n }\n int nx2 = x + dx[(k + A[x][y]) % 4], ny2 = y + dy[(k + A[x][y]) % 4];\n if (0 < A[x][y] && A[x][y] < 4 && inside(nx2, ny2, h, w) && dist[nx2][ny2][(k + A[x][y]) % 4] > d){\n dist[nx2][ny2][(k + A[x][y]) % 4] = d;\n q.push({d, nx2, ny2, (k + A[x][y]) % 4});\n }\n\n if (inside(nx1, ny1, h, w) && dist[nx1][ny1][k] > d + C[0]){\n dist[nx1][ny1][k] = d + C[0];\n q.push({d + C[0], nx1, ny1, k});\n }\n srep(t, 1, 4){\n int nx3 = x + dx[(k + t) % 4], ny3 = y + dy[(k + t) % 4];\n if (inside(nx3, ny3, h, w) && dist[nx3][ny3][(k + t) % 4] > d + C[t]){\n dist[nx3][ny3][(k + t) % 4] = d + C[t];\n q.push({d + C[t], nx3, ny3, (k + t) % 4});\n }\n }\n }\n return min(min(dist[h - 1][w - 1][0], dist[h - 1][w - 1][1]), min(dist[h - 1][w - 1][2], dist[h - 1][w - 1][3]));\n}\n\nint main(){\n vi ans;\n while (true){\n int w, h;cin >> w >> h;\n if (w == 0) break;\n ans.push_back(solve(h, w));\n }\n for (auto x : ans) cout << x << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3512, "score_of_the_acc": -0.3743, "final_rank": 2 }, { "submission_id": "aoj_1156_8030956", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nbool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nbool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr int MOD = 1000000007;\nconstexpr int MOD_N = 998244353;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid setp(int n) {\n std::cout << std::fixed << std::setprecision(n);\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 3 \"a.cpp\"\n\nint main(void) {\n while (true) {\n int h, w;\n cin >> h >> w;\n if (!h)\n break;\n swap(h, w);\n vector<vector<int>> b(h, vector<int>(w));\n cin >> b;\n vector<int> c(4);\n cin >> c;\n auto in_field = [&](int x, int y) {\n return 0 <= x && x < h && 0 <= y && y < w;\n };\n vector<pair<int, int>> adj = {{0, 1}, {1, 0}, {0, -1}, {-1, 0}};\n vector dp(h, vector(w, vector(4, INF)));\n priority_queue<tuple<int, int, int, int>, vector<tuple<int, int, int, int>>, greater<>> pq;\n dp[0][0][0] = 0;\n pq.emplace(0, 0, 0, 0);\n while (!pq.empty()) {\n auto [d, x, y, dir] = pq.top();\n pq.pop();\n if (dp[x][y][dir] < d)\n continue;\n rep (k, 4) {\n int nx = x, ny = y, nd = dir, nc = d;\n (nd += k) %= 4;\n nx += adj[nd].first, ny += adj[nd].second;\n if (!in_field(nx, ny))\n continue;\n if (k != b[x][y])\n nc += c[k];\n if (chmin(dp[nx][ny][nd], nc))\n pq.emplace(nc, nx, ny, nd);\n }\n }\n\n ll ans = INF;\n rep (i, 4) chmin(ans, dp[h - 1][w - 1][i]);\n co(ans);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3596, "score_of_the_acc": -0.4866, "final_rank": 9 }, { "submission_id": "aoj_1156_8020869", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rng(i, l, r) for(int i = int(l); i < int(r); i++)\n#define rep(i, n) rng(i, 0, n)\n#define sz(v) int(v.size())\n#define foa(s, v) for(auto &s : v)\n#define all(v) v.begin(), v.end()\ntemplate <class T>\nusing V = vector<T>;\n\ntemplate <class T>\nbool chmin(T &a, T b) {\n\treturn a > b ? a = b, 1 : 0;\n}\ntemplate <class T>\nbool chmax(T &a, T b) {\n\treturn a < b ? a = b, 1 : 0;\n}\n\nint n;\nvoid solve() {\n\tint w = n;\n\tint h;\n\tcin >> h;\n\n\tvector<int> dx = {0, 1, 0, -1};\n\tvector<int> dy = {1, 0, -1, 0};\n\n\tvector<vector<int>> grid(h, vector<int>(w));\n\tfoa(r, grid) foa(c, r) cin >> c;\n\n\tvector<ll> costs(4);\n\tfoa(c, costs) cin >> c;\n\n\tvector ids(4, vector(h, vector(w, 0)));\n\tint ver = 0;\n\tfoa(r, ids) foa(c, r) foa(cc, c) cc = ver++;\n\tvector<tuple<int, int, int>> states;\n\trep(dir, 4) rep(i, h) rep(j, w) { states.emplace_back(dir, i, j); }\n\n\tconst int start = ids[0][0][0];\n\n\tusing p = pair<ll, int>;\n\tpriority_queue<p, vector<p>, greater<p>> q;\n\tconstexpr ll INF = 1e15;\n\tvector<ll> dist(ver, INF);\n\tauto update = [&](int nxt, ll val) -> void {\n\t\tif(chmin(dist[nxt], val)) { q.emplace(dist[nxt], nxt); }\n\t};\n\tupdate(start, 0LL);\n\n\twhile(q.size()) {\n\t\tll d;\n\t\tint now;\n\t\ttie(d, now) = q.top();\n\t\tq.pop();\n\t\tif(d > dist[now]) continue;\n\n\t\tint dir, x, y;\n\t\ttie(dir, x, y) = states[now];\n\n\t\tif(x == h - 1 && y == w - 1) {\n\t\t\tcout << d << endl;\n\t\t\treturn;\n\t\t}\n\n\t\trep(command, 4) {\n\t\t\tint nxt_dir = (dir + command) % 4;\n\t\t\tint nx = x + dx[nxt_dir];\n\t\t\tif(nx < 0 || nx >= h) continue;\n\t\t\tint ny = y + dy[nxt_dir];\n\t\t\tif(ny < 0 || ny >= w) continue;\n\n\t\t\tupdate(ids[nxt_dir][nx][ny], d + (grid[x][y] == command ? 0 : costs[command]));\n\t\t}\n\t}\n\n\tassert(false);\n}\n\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\t// cout << fixed << setprecision(15);\n\t// srand((unsigned)time(NULL));\n\twhile(cin >> n && n) solve();\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3556, "score_of_the_acc": -0.4332, "final_rank": 5 }, { "submission_id": "aoj_1156_8019389", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nint W, H;\nvoid solve() {\n\tvector<vector<int>> V(H, vector<int>(W));\n\tfor(auto&& v: V) {\n\t\tfor(auto&& e: v) {\n\t\t\tcin >> e;\n\t\t}\n\t}\n\tvector<int> C(4);\n\tcin >> C[0] >> C[1] >> C[2] >> C[3];\n\tvector<int> dx = { 1, 0, -1, 0 };\n\tvector<int> dy = { 0, 1, 0, -1 };\n\tusing P = tuple<long long, int, int, int>;\n\tpriority_queue<P, vector<P>, greater<>> Q;\n\tvector<vector<vector<long long>>> dist(\n\t\tH,\n\t\tvector<vector<long long>>(W, vector<long long>(4)));\n\tfor(int i = 0; i < H; i++) {\n\t\tfor(int j = 0; j < W; j++) {\n\t\t\tfor(int d = 0; d < 4; d++) {\n\t\t\t\tdist[i][j][d] = (long long) (1e18);\n\t\t\t}\n\t\t}\n\t}\n\tQ.emplace(0, 0, 0, 0);\n\tdist[0][0][0] = 0;\n\tauto checkIndex = [&](int y, int x) -> bool {\n\t\tif(y < 0 || y >= H) return false;\n\t\tif(x < 0 || x >= W) return false;\n\t\treturn true;\n\t};\n\twhile(!Q.empty()) {\n\t\tauto [c, y, x, d] = Q.top();\n\t\tQ.pop();\n\t\tif(dist[y][x][d] < c) continue;\n\t\tfor(int operation = 0; operation < 4; operation++) {\n\t\t\tint ny = y + dy[(d + operation) % 4];\n\t\t\tint nx = x + dx[(d + operation) % 4];\n\t\t\tif(!checkIndex(ny, nx)) continue;\n\t\t\tauto nc = c\n\t\t\t\t+ (operation != V[y][x] ? C[operation] : 0);\n\t\t\tif(dist[ny][nx][(d + operation) % 4] > nc) {\n\t\t\t\tdist[ny][nx][(d + operation) % 4] = nc;\n\t\t\t\tQ.emplace(nc, ny, nx, (d + operation) % 4);\n\t\t\t}\n\t\t}\n\t}\n\tlong long ans = (long long) (1e18);\n\tfor(int d = 0; d < 4; d++) {\n\t\tans = min(ans, dist[H - 1][W - 1][d]);\n\t}\n\tcout << ans << endl;\n}\n\nint main() {\n\tcin >> W >> H;\n\twhile(W != 0) {\n\t\tsolve();\n\t\tcin >> W >> H;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3232, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_1157_cpp
Problem E: Roll-A-Big-Ball ACM University holds its sports day in every July. The "Roll-A-Big-Ball" is the highlight of the day. In the game, players roll a ball on a straight course drawn on the ground. There are rectangular parallelepiped blocks on the ground as obstacles, which are fixed on the ground. During the game, the ball may not collide with any blocks. The bottom point of the ball may not leave the course. To have more fun, the university wants to use the largest possible ball for the game. You must write a program that finds the largest radius of the ball that can reach the goal without colliding any obstacle block. The ball is a perfect sphere, and the ground is a plane. Each block is a rectangular parallelepiped. The four edges of its bottom rectangle are on the ground, and parallel to either x- or y-axes. The course is given as a line segment from a start point to an end point. The ball starts with its bottom point touching the start point, and goals when its bottom point touches the end point. The positions of the ball and a block can be like in Figure E-1 (a) and (b). Figure E-1: Possible positions of the ball and a block Input The input consists of a number of datasets. Each dataset is formatted as follows. N sx sy ex ey minx 1 miny 1 maxx 1 maxy 1 h 1 minx 2 miny 2 maxx 2 maxy 2 h 2 ... minx N miny N maxx N maxy N h N A dataset begins with a line with an integer N , the number of blocks (1 ≤ N ≤ 50). The next line consists of four integers, delimited by a space, indicating the start point ( sx , sy ) and the end point ( ex , ey ). The following N lines give the placement of blocks. Each line, representing a block, consists of five integers delimited by a space. These integers indicate the two vertices ( minx , miny ), ( maxx , maxy ) of the bottom surface and the height h of the block. The integers sx , sy , ex , ey , minx , miny , maxx , maxy and h satisfy the following conditions. -10000 ≤ sx , sy , ex , ey ≤ 10000 -10000 ≤ minx i < maxx i ≤ 10000 -10000 ≤ miny i < maxy i ≤ 10000 1 ≤ h i ≤ 1000 The last dataset is followed by a line with a single zero in it. Output For each dataset, output a separate line containing the largest radius. You may assume that the largest radius never exceeds 1000 for each dataset. If there are any blocks on the course line, the largest radius is defined to be zero. The value may contain an error less than or equal to 0.001. You may print any number of digits after the decimal point. Sample Input 2 -40 -40 100 30 -100 -100 -50 -30 1 30 -70 90 -30 10 2 -4 -4 10 3 -10 -10 -5 -3 1 3 -7 9 -3 1 2 -40 -40 100 30 -100 -100 -50 -30 3 30 -70 90 -30 10 2 -400 -400 1000 300 -800 -800 -500 -300 7 300 -700 900 -300 20 3 20 70 150 70 0 0 50 50 4 40 100 60 120 8 130 80 200 200 1 3 20 70 150 70 0 0 50 50 4 40 100 60 120 10 130 80 200 200 1 3 20 70 150 70 0 0 50 50 10 40 100 60 120 10 130 80 200 200 3 1 2 4 8 8 0 0 10 10 1 1 1 4 9 9 2 2 7 7 1 0 Output for the Sample Input 30 1 18.16666666667 717.7 ...(truncated)
[ { "submission_id": "aoj_1157_10849696", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ndouble EPS = 1e-9;\ntypedef complex<double> P;\n\nstruct L : public vector<P> {\n L(const P &a, const P &b) {\n push_back(a); push_back(b);\n }\n};\ndouble cross(const P& a, const P& b) {\n return imag(conj(a)*b);\n}\ndouble dot(const P& a, const P& b) {\n return real(conj(a)*b);\n}\nint ccw(P a, P b, P c) {\n b -= a; c -= a;\n if (cross(b, c) > 0) return +1; // counter clockwise\n if (cross(b, c) < 0) return -1; // clockwise\n if (dot(b, c) < 0) return +2; // c--a--b on line\n if (norm(b) < norm(c)) return -2; // a--b--c on line\n return 0;\n}\n\nP projection(const L &l, const P &p) {\n double t = dot(p-l[0], l[0]-l[1]) / norm(l[0]-l[1]);\n return l[0] + t*(l[0]-l[1]);\n}\nbool intersectSS(const L &s, const L &t) {\n return ccw(s[0],s[1],t[0])*ccw(s[0],s[1],t[1]) <= 0 &&\n ccw(t[0],t[1],s[0])*ccw(t[0],t[1],s[1]) <= 0;\n}\nbool intersectSP(const L &s, const P &p) {\n return abs(s[0]-p)+abs(s[1]-p)-abs(s[1]-s[0]) < EPS; // triangle inequality\n}\ndouble distanceSP(const L &s, const P &p) {\n const P r = projection(s, p);\n if (intersectSP(s, r)) return abs(r - p);\n return min(abs(s[0] - p), abs(s[1] - p));\n}\n\ndouble distanceSS(const L &s, const L &t) {\n if (intersectSS(s, t)) return 0;\n return min(min(distanceSP(s, t[0]), distanceSP(s, t[1])),\n min(distanceSP(t, s[0]), distanceSP(t, s[1])));\n}\n\nP A[100],B[100];\ndouble H[100];\nP s,e;\nP in(){\n\tdouble x,y;\n\tcin >> x >> y;\n\treturn P(x,y);\n}\n\nint N;\n\nbool f(double R){\n\tfor(int i = 0 ; i < N ; i++){\n\t\tdouble h = min(R,H[i]);\n\t\tP a = A[i];\n\t\tP b = P(B[i].real(),A[i].imag());\n\t\tP c = B[i];\n\t\tP d = P(A[i].real(),B[i].imag());\n\t\tL l[] = {L(a,b),L(b,c),L(c,d),L(d,a)};\n\t\tfor(int j = 0 ; j < 4 ; j++){\n\t\t\tdouble rd = sqrt(R*R-(h-R)*(h-R));\n\t\t\tif( distanceSS(L(s,e),l[j]) < rd ){\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\treturn 1;\n}\nint main(){\n\twhile( cin >> N and N > 0 ){\n\t\t\n\t\ts = in();\n\t\te = in();\n\t\tbool ff = 0;\n\t\tfor(int i = 0 ; i < N ; i++){\n\t\t\tA[i] = in();\n\t\t\tB[i] = in();\n\t\t\tcin >> H[i];\n\t\t\tif( A[i].real() <= s.real() and s.real() <= B[i].real()\n\t\t\t\tand A[i].imag() <= s.imag() and s.imag() <= B[i].imag() \n\t\t\tor A[i].real() <= e.real() and e.real() <= B[i].real()\n\t\t\t\tand A[i].imag() <= e.imag() and e.imag() <= B[i].imag() ){\n\t\t\t\tff = 1;\n\t\t\t}\n\t\t}\n\t\t\n\t\tif(ff){\n\t\t\tcout << 0 << endl;\n\t\t\tcontinue;\n\t\t}\n\t\t\n\t\tdouble l = 0, r = 100000;\n\t\tfor(int i = 0 ; i < 128 ; i++){\n\t\t\tdouble m = (l+r) / 2;\n\t\t\tif( f(m) ){\n\t\t\t\tl = m;\n\t\t\t}else{\n\t\t\t\tr = m;\n\t\t\t}\n\t\t}\n\t\tprintf(\"%.10lf\\n\",l);\n\t\t\n\t}\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 3508, "score_of_the_acc": -0.6564, "final_rank": 10 }, { "submission_id": "aoj_1157_10674473", "code_snippet": "#pragma region Macros\n#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nusing int128 = __int128_t;\n#define all(x) (x).begin(), (x).end()\n#define uniqv(v) v.erase(unique(all(v)), v.end())\n#define OVERLOAD_REP(_1, _2, _3, name, ...) name\n#define REP1(i, n) for (auto i = std::decay_t<decltype(n)>{}; (i) != (n); ++(i))\n#define REP2(i, l, r) for (auto i = (l); (i) != (r); ++(i))\n#define rep(...) OVERLOAD_REP(__VA_ARGS__, REP2, REP1)(__VA_ARGS__)\n#define log(x) cout << x << endl\n#define logfixed(x) cout << fixed << setprecision(10) << x << \"\\n\";\n#define logy(bool) \\\n if (bool) { \\\n cout << \"Yes\" << endl; \\\n } else { \\\n cout << \"No\" << endl; \\\n }\n\nostream &operator<<(ostream &dest, __int128_t value) {\n ostream::sentry s(dest);\n if (s) {\n __uint128_t tmp = value < 0 ? -value : value;\n char buffer[128];\n char *d = end(buffer);\n do {\n --d;\n *d = \"0123456789\"[tmp % 10];\n tmp /= 10;\n } while (tmp != 0);\n if (value < 0) {\n --d;\n *d = '-';\n }\n int len = end(buffer) - d;\n if (dest.rdbuf()->sputn(d, len) != len) {\n dest.setstate(ios_base::badbit);\n }\n }\n return dest;\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &os, const vector<T> &v) {\n for (int i = 0; i < (int)v.size(); i++) {\n os << v[i] << (i + 1 != (int)v.size() ? \" \" : \"\");\n }\n return os;\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &os, const set<T> &set_var) {\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end()) os << \" \";\n itr--;\n }\n return os;\n}\n\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << itr->first << \" -> \" << itr->second << \"\\n\";\n }\n return os;\n}\n\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const pair<T, U> &pair_var) {\n os << \"(\" << pair_var.first << \", \" << pair_var.second << \")\";\n return os;\n}\n\nvoid out() { cout << '\\n'; }\ntemplate <class T, class... Ts>\nvoid out(const T &a, const Ts &...b) {\n cout << a;\n (cout << ... << (cout << ' ', b));\n cout << '\\n';\n}\n\ntemplate <typename T>\nistream &operator>>(istream &is, vector<T> &v) {\n for (T &in : v) is >> in;\n return is;\n}\n\ninline void in(void) { return; }\ntemplate <typename First, typename... Rest>\nvoid in(First &first, Rest &...rest) {\n cin >> first;\n in(rest...);\n return;\n}\n\ntemplate <typename T>\nbool chmax(T &a, const T &b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T>\nbool chmin(T &a, const T &b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\n\nvector<lint> dx8 = {1, 1, 0, -1, -1, -1, 0, 1};\nvector<lint> dy8 = {0, 1, 1, 1, 0, -1, -1, -1};\nvector<lint> dx4 = {1, 0, -1, 0};\nvector<lint> dy4 = {0, 1, 0, -1};\n\n#pragma endregion\n\n#define EPS (1e-10)\n#define equals(a, b) (fabsl((a) - (b)) < EPS)\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\nstatic const int CONTAIN = 2;\nstatic const int CONTAIN_LINE = 1;\nstatic const int NOT_CONTAIN = 0;\nstatic const int CIRCUMSCRIPTION = 3;\nstatic const int INSCRIPTION = 1;\nstatic const int INTERSECT = 2;\nstatic const int CONNOTATION = 0;\nstatic const int NOT_CONNOTATION = 4;\n\nstruct Point {\n public:\n long double x, y;\n Point(long double x = 0, long double y = 0) : x(x), y(y) {}\n\n Point operator+(Point p) { return Point(x + p.x, y + p.y); }\n Point operator-(Point p) { return Point(x - p.x, y - p.y); }\n Point operator*(long double a) { return Point(a * x, a * y); }\n Point operator/(long double a) { return Point(x / a, y / a); }\n bool operator<(const Point &p) const { return x != p.x ? x < p.x : y < p.y; }\n bool operator>(const Point &p) const { return x != p.x ? x > p.x : y > p.y; }\n bool operator==(const Point &p) const { return fabsl(x - p.x) < EPS and fabsl(y - p.y) < EPS; }\n\n long double abs() { return sqrtl(norm()); }\n long double norm() { return x * x + y * y; }\n};\n\nostream &operator<<(ostream &os, const Point &p) {\n os << p.x << \" \" << p.y;\n return os;\n}\n\nusing Vector = Point;\n\nlong double norm(Vector a) {\n return a.x * a.x + a.y * a.y;\n}\n\nlong double abs(Vector a) {\n return sqrtl(norm(a));\n}\n\nstruct Segment {\n Point p1, p2;\n Segment(Point x, Point y) {\n p1 = x;\n p2 = y;\n }\n};\n\nusing Line = Segment;\n\nclass Circle {\n public:\n Point c;\n long double r;\n Circle(Point c = Point(), long double r = 0.0) : c(c), r(r) {}\n};\n\nusing Polygon = vector<Point>;\n\n// ベクトル aとbの内積を返す\nlong double dot(Vector a, Vector b) {\n return a.x * b.x + a.y * b.y;\n}\n\n// ベクトル aとbの外積を返す\nlong double cross(Vector a, Vector b) {\n return a.x * b.y - a.y * b.x;\n}\n\n// ベクトル aとbが直交かどうかを返す\nbool isOrthogonal(Vector a, Vector b) {\n return equals(dot(a, b), 0.0);\n}\n\n// 点 a1,a2からなるベクトルと b1,b2からなるベクトルが直交かどうかを返す\nbool isOrthogonal(Point a1, Point a2, Point b1, Point b2) {\n return isOrthogonal(a1 - a2, b1 - b2);\n}\n\n// 線分 aとbが直交かどうかを返す\nbool isOrthogonal(Segment s1, Segment s2) {\n return equals(dot(s1.p2 - s1.p1, s2.p2 - s2.p1), 0.0);\n}\n\n// ベクトル aとbが平行かどうかを返す\nbool isParallel(Vector a, Vector b) {\n return equals(cross(a, b), 0.0);\n}\n\n// 点 a1,a2からなるベクトルと b1,b2からなるベクトルが平行かどうかを返す\nbool isParallel(Point a1, Point a2, Point b1, Point b2) {\n return isParallel(a1 - a2, b1 - b2);\n}\n\n// 線分 aとbが平行かどうかを返す\nbool isParallel(Segment s1, Segment s2) {\n return equals(cross(s1.p2 - s1.p1, s2.p2 - s2.p1), 0.0);\n}\n\n// 点pから線分sに垂線を下ろした時の交点(射影)を返す\nPoint project(Segment s, Point p) {\n Vector base = s.p2 - s.p1;\n long double r = dot(p - s.p1, base) / norm(base);\n return s.p1 + base * r;\n}\n\n// 線分sを対称軸として、点pと線対称の位置にある点(反射)を返す\nPoint reflect(Segment s, Point p) {\n return p + (project(s, p) - p) * 2.0;\n}\n\n// 2点間の距離を返す\nlong double Distance(Point a, Point b) {\n return abs(a - b);\n}\n\n// 点pと直線lの距離を返す\nlong double DistanceLP(Line l, Point p) {\n return abs(cross(l.p2 - l.p1, p - l.p1) / abs(l.p2 - l.p1));\n}\n\n// 点pと線分lの距離を返す\nlong double DistanceSP(Segment s, Point p) {\n if (dot(s.p2 - s.p1, p - s.p1) < 0.0) return abs(p - s.p1);\n if (dot(s.p1 - s.p2, p - s.p2) < 0.0) return abs(p - s.p2);\n return DistanceLP(s, p);\n}\n\n// 点の位置関係を調べる\nint ccw(Point p0, Point p1, Point p2) {\n Vector a = p1 - p0;\n Vector b = p2 - p0;\n // p0->p1を反時計回りに回転させる方向にp2が存在する\n if (cross(a, b) > EPS) return COUNTER_CLOCKWISE;\n // p0->p1を時計回りに回転させる方向にp2が存在する\n if (cross(a, b) < -EPS) return CLOCKWISE;\n // 3点は同一直線上に存在し、2点に挟まれている点はp0\n if (dot(a, b) < -EPS) return ONLINE_BACK;\n // 3点は同一直線上に存在し、2点に挟まれている点はp1\n if (a.norm() < b.norm()) return ONLINE_FRONT;\n // 3点は同一直線上に存在し、2点に挟まれている点はp2\n return ON_SEGMENT;\n}\n\n// 点p1,p2からなる線分とp3,p4からなる線分が交差するかどうかを返す\nbool intersect(Point p1, Point p2, Point p3, Point p4) {\n return (ccw(p1, p2, p3) * ccw(p1, p2, p4) <= 0 and ccw(p3, p4, p1) * ccw(p3, p4, p2) <= 0);\n}\n\n// 線分 s1とs2が交差するかどうかを返す\nbool intersect(Segment s1, Segment s2) {\n return intersect(s1.p1, s1.p2, s2.p1, s2.p2);\n}\n\n// 円 c1とc2の位置関係を調べる\nint intersect(Circle c1, Circle c2) {\n long double d = abs((c1.c - c2.c));\n // 2つの円は離れている(内包していない)\n if (d > c1.r + c2.r + EPS) {\n return NOT_CONNOTATION;\n }\n // 外接している\n if (equals(d, c1.r + c2.r)) {\n return CIRCUMSCRIPTION;\n }\n // 内接している\n if (equals(d, abs(c1.r - c2.r))) {\n return INSCRIPTION;\n }\n // 内包している\n if (d < abs(c1.r - c2.r) - EPS) {\n return CONNOTATION;\n }\n // 2点で交わる\n return INTERSECT;\n}\n\n// 点 a,b,cからなる三角形の内接円を返す\nCircle inCircle(Point a, Point b, Point c) {\n long double A = abs(b - c);\n long double B = abs(a - c);\n long double C = abs(a - b);\n Point p((A * a.x) + (B * b.x) + (C * c.x), (A * a.y) + (B * b.y) + (C * c.y));\n p = p / (A + B + C);\n long double r = DistanceLP({a, b}, p);\n return Circle(p, r);\n}\n\n// 線分 s1とs2の距離を返す\nlong double Distance(Segment s1, Segment s2) {\n if (intersect(s1, s2)) return 0.0;\n return min({DistanceSP(s1, s2.p1), DistanceSP(s1, s2.p2), DistanceSP(s2, s1.p1), DistanceSP(s2, s1.p2)});\n}\n\n// 線分 s1とs2の交点を返す\nPoint CrossPoint(Segment s1, Segment s2) {\n Vector base = s2.p2 - s2.p1;\n long double d1 = abs(cross(base, s1.p1 - s2.p1));\n long double d2 = abs(cross(base, s1.p2 - s2.p1));\n long double t = d1 / (d1 + d2);\n return s1.p1 + (s1.p2 - s1.p1) * t;\n}\n\n// 円 cと、直線lの交点を返す\ntemplate <class T>\npair<T, T> CrossPoints(Circle c, Line l) {\n Vector pr = project(l, c.c);\n Vector e = (l.p2 - l.p1) / abs(l.p2 - l.p1);\n long double base = sqrtl(c.r * c.r - norm(pr - c.c));\n return {Point(pr + e * base), Point(pr - e * base)};\n}\n\nlong double arg(Vector p) { return atan2l(p.y, p.x); }\nVector polar(long double a, long double r) { return Point(cosl(r) * a, sinl(r) * a); }\n\n// 円 c1とc2の交点を返す\ntemplate <class T>\npair<T, T> CrossPoints(Circle c1, Circle c2) {\n long double d = abs(c1.c - c2.c);\n long double a = acosl((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d));\n long double t = arg(c2.c - c1.c);\n return {c1.c + polar(c1.r, t + a), c1.c + polar(c1.r, t - a)};\n}\n\n// 点 pを通る、円cの接線を求め、その接点を返す pは円の外側だと仮定する\ntemplate <class T>\npair<T, T> tangentToCircle(Circle c, Point p) {\n return CrossPoints<Point>(c, Circle(p, sqrtl(norm(c.c - p) - c.r * c.r)));\n}\n\n// 点 pが、多角形gの内部、辺上、外部のうちどこにあるか返す\nint contains(Polygon g, Point p) {\n int n = g.size();\n bool x = false;\n for (int i = 0; i < n; i++) {\n Point a = g[i] - p, b = g[(i + 1) % n] - p;\n if (abs(cross(a, b)) < EPS and dot(a, b) < EPS) return CONTAIN_LINE;\n if (a.y > b.y) swap(a, b);\n if (a.y < EPS and EPS < b.y and cross(a, b) > EPS) x = !x;\n }\n return (x ? CONTAIN : NOT_CONTAIN);\n}\n\n// 多角形pの面積を返す\nlong double PolygonArea(const vector<Point> &p) {\n long double res = 0;\n int n = p.size();\n for (int i = 0; i < n - 1; i++) {\n res += cross(p[i], p[i + 1]);\n }\n res += cross(p[n - 1], p[0]);\n return res * 0.5;\n}\n\n// 多角形pが凸多角形かどうか返す\nbool isConvex(const vector<Point> &p) {\n int n = p.size();\n int now, pre, nxt;\n for (int i = 0; i < n; i++) {\n pre = (i - 1 + n) % n;\n nxt = (i + 1) % n;\n now = i;\n if (ccw(p[pre], p[now], p[nxt]) == CLOCKWISE) {\n return false;\n }\n }\n return true;\n}\n\n// 凸包\nPolygon andrewScan(Polygon s, bool on_line = 0) {\n Polygon u, l;\n if (s.size() < 3) return s;\n sort(s.begin(), s.end());\n\n u.push_back(s[0]);\n u.push_back(s[1]);\n\n l.push_back(s[s.size() - 1]);\n l.push_back(s[s.size() - 2]);\n if (on_line) {\n for (int i = 2; i < s.size(); i++) {\n for (int n = u.size(); n >= 2 and ccw(u[n - 2], u[n - 1], s[i]) == COUNTER_CLOCKWISE; n--) {\n u.pop_back();\n }\n u.push_back(s[i]);\n }\n\n for (int i = s.size() - 3; i >= 0; i--) {\n for (int n = l.size(); n >= 2 and ccw(l[n - 2], l[n - 1], s[i]) == COUNTER_CLOCKWISE; n--) {\n l.pop_back();\n }\n l.push_back(s[i]);\n }\n } else {\n for (int i = 2; i < s.size(); i++) {\n for (int n = u.size(); n >= 2 and ccw(u[n - 2], u[n - 1], s[i]) != CLOCKWISE; n--) {\n u.pop_back();\n }\n u.push_back(s[i]);\n }\n\n for (int i = s.size() - 3; i >= 0; i--) {\n for (int n = l.size(); n >= 2 and ccw(l[n - 2], l[n - 1], s[i]) != CLOCKWISE; n--) {\n l.pop_back();\n }\n l.push_back(s[i]);\n }\n reverse(l.begin(), l.end());\n for (int i = u.size() - 2; i >= 1; i--) l.push_back(u[i]);\n }\n return l;\n}\n\nint main() {\n cin.tie(0)->sync_with_stdio(0);\n int n;\n while (1) {\n in(n);\n if (n == 0) break;\n ld sx, sy, ex, ey;\n in(sx, sy, ex, ey);\n\n vector<Segment> seg;\n vector<ld> height;\n\n vector<tuple<ld, ld, ld>> ps;\n bool fin = 0;\n\n rep(i, n) {\n ld lx, ly, rx, ry, h;\n in(lx, ly, rx, ry, h);\n\n if (lx <= sx and sx <= rx and ly <= sy and sy <= ry) {\n fin = 1;\n }\n\n if (lx <= ex and ex <= rx and ly <= ey and ey <= ry) {\n fin = 1;\n }\n\n ps.emplace_back(lx, ly, h);\n ps.emplace_back(lx, ry, h);\n ps.emplace_back(rx, ly, h);\n ps.emplace_back(rx, ry, h);\n\n seg.emplace_back(Point(lx, ly), Point(lx, ry));\n seg.emplace_back(Point(lx, ly), Point(rx, ly));\n seg.emplace_back(Point(rx, ly), Point(rx, ry));\n seg.emplace_back(Point(lx, ry), Point(rx, ry));\n height.push_back(h);\n height.push_back(h);\n height.push_back(h);\n height.push_back(h);\n }\n\n Segment path(Point(sx, sy), Point(ex, ey));\n\n for (auto s : seg) {\n if (intersect(path, s)) {\n fin = 1;\n }\n }\n if (fin) {\n out(0);\n continue;\n }\n\n ld ok = 0;\n ld ng = 1010;\n ld r;\n\n int lim = 100;\n rep(z, lim) {\n r = (ok + ng) / 2;\n\n bool res = true;\n for (auto [x, y, h] : ps) {\n ld d = DistanceSP(path, Point(x, y));\n if(d > r) continue;\n res &= (r - sqrtl(r*r - d*d)) > h;\n }\n\n rep(i, 4 * n) {\n Segment s = seg[i];\n ld h = height[i];\n ld d = DistanceSP(s, Point(sx, sy));\n if(d > r) continue;\n res &= (r - sqrtl(r*r - d*d)) > h;\n }\n\n rep(i, 4 * n) {\n Segment s = seg[i];\n ld h = height[i];\n ld d = DistanceSP(s, Point(ex, ey));\n if(d > r) continue;\n res &= (r - sqrtl(r*r - d*d)) > h;\n }\n\n if (res) {\n ok = r;\n } else {\n ng = r;\n }\n }\n logfixed(ok);\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3840, "score_of_the_acc": -0.8979, "final_rank": 16 }, { "submission_id": "aoj_1157_10647838", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// 書きかけの幾何ライブラリ\n// バグがあるかも\n\nnamespace geometry {\n\nusing Real = long double;\nconstexpr Real eps = 1e-12;\nconstexpr Real PI = acosl(-1);\nconstexpr Real INF_REAL = numeric_limits<Real>::max();\n\nbool equal_eps(Real a, Real b) {\n return abs(a - b) < eps;\n}\n\nint sgn(Real a) {\n return equal_eps(a, 0) ? 0 : a > 0 ? 1 : -1;\n}\n\nstruct Point {\n Real x, y;\n constexpr Point() : Point(0, 0) {}\n constexpr Point(Real _x, Real _y) : x(_x), y(_y) {}\n constexpr Point(const pair<Real, Real> &p) : x(p.first), y(p.second) {}\n Point &operator+=(const Point &p) {\n x += p.x;\n y += p.y;\n return *this;\n }\n Point &operator-=(const Point &p) {\n x -= p.x;\n y -= p.y;\n return *this;\n }\n Point &operator*=(const Real &r) {\n x *= r;\n y *= r;\n return *this;\n }\n Point &operator/=(const Real &r) {\n assert(!equal_eps(r, 0));\n x /= r;\n y /= r;\n return *this;\n }\n Point operator+(const Point &p) const { return Point(*this) += p; }\n Point operator-(const Point &p) const { return Point(*this) -= p; }\n Point operator*(const Real &r) const { return Point(*this) *= r; }\n Point operator/(const Real &r) const { return Point(*this) /= r; }\n Point operator-() const { return Point() - *this; }\n bool operator==(const Point &p) const {\n return equal_eps(x, p.x) && equal_eps(y, p.y);\n }\n bool operator!=(const Point &p) const {\n return !equal_eps(x, p.x) || !equal_eps(y, p.y);\n }\n Point rotate(Real rad) const {\n Real c = cosl(rad), s = sinl(rad);\n Real tx = x * c - y * s;\n Real ty = x * s + y * c;\n return Point(tx, ty);\n }\n Point unit() const {\n return (*this) / metric();\n }\n Real Re() const { return x; }\n Real Im() const { return y; }\n Real norm() const { return x * x + y * y; }\n Real metric() const { return sqrtl(norm()); }\n Real arg() const { return atan2l(y, x); }\n Real arg(Point q1, Point q2) const {\n q1 -= *this, q2 -= *this;\n return abs(q1.arg() - q2.arg());\n }\n friend Point operator*(Real r, const Point &p) {\n return p * r;\n }\n friend Point operator/(Real r, const Point &p) {\n return p / r;\n }\n};\n\nReal Re(const Point &p) { return p.Re(); }\nReal Im(const Point &p) { return p.Im(); }\nReal dot(const Point &p, const Point &q) {\n return p.x * q.x + p.y * q.y;\n}\nReal cross(const Point &p, const Point &q) {\n return p.x * q.y - p.y * q.x;\n}\nReal norm(const Point &p) {\n return p.norm();\n}\nReal metric(const Point &p) {\n return p.metric();\n}\nReal metric(const Point &p, const Point &q) {\n return metric(p - q);\n}\nReal arg(const Point &p) {\n return p.arg();\n}\n\nbool equal_point(const Point &p, const Point &q) {\n return equal_eps(p.x, q.x) && equal_eps(p.y, q.y);\n}\n\nconstexpr Point INF_POINT = Point(INF_REAL, INF_REAL);\n\n// a を基準にした b と c の位置関係\nint ccw(const Point &a, const Point &b, const Point &c) {\n Point p = b - a, q = c - a;\n if (cross(p, q) > eps) return 1; // a, b, c の順で反時計回り\n if (cross(p, q) < -eps) return -1; // a, b, c の順で時計回り\n if (min(norm(p), norm(q)) < eps * eps) return 0; // a = c or b = c\n if (dot(p, q) < eps) return 2; // c, a, b の順で一直線\n if (norm(p) < norm(q)) return -2; // a, b, c の順で一直線\n return 0; // a, c, b の順で一直線\n}\n\nistream &operator>>(istream &is, Point& p) {\n Real x, y;\n is >> x >> y;\n p = Point(x, y);\n return is;\n}\n\n} // namespace geometry\n\nnamespace geometry {\n\nstruct Line {\n // Line : ax + by = c\n Real a, b, c;\n constexpr Line() = default;\n constexpr Line(Real _a, Real _b, Real _c) : a(_a), b(_b), c(_c) {}\n constexpr Line(const Point &p, const Point &q) : a(q.y - p.y), b(p.x - q.x), c(p.x * q.y - p.y * q.x) {}\n constexpr Line(Real _a, const Point &p) : a(_a), b(-1), c(_a * p.x - p.y) {}\n bool online(const Point &p) const {\n return equal_eps(a * p.x + b * p.y, c);\n }\n Real get_x(Real y) const {\n if (equal_eps(a, 0)) return INF_REAL;\n return (c - b * y) / a;\n }\n Real get_y(Real x) const {\n if (equal_eps(b, 0)) return INF_REAL;\n return (c - a * x) / b;\n }\n Line perpendicular(const Point &p) const {\n if (equal_eps(a, 0)) return Line(1, 0, p.x);\n if (equal_eps(0, b)) return Line(0, 1, p.y);\n return Line(b / a, p);\n }\n Point crossppoint(const Line &l) const {\n if (equal_eps(a * l.b, l.a * b)) return INF_POINT;\n Real d = a * l.b - l.a * b;\n return Point(l.b * c - b * l.c, l.c * a - c * l.a) / d;\n }\n Point projection(const Point &p) const {\n return crossppoint(perpendicular(p));\n }\n Point reflection(const Point &p) const {\n Point q = projection(p);\n return 2 * q - p;\n }\n Point unit() const {\n if (equal_eps(b, 0)) {\n return Point(0, 1);\n }\n Point p(0, get_y(0)), q(1, get_y(1));\n return (p - q) / metric(p - q);\n }\n bool is_orthogonal(const Line &l) const {\n return equal_eps(a * l.a + b * l.b, 0);\n }\n bool is_parallel(const Line &l) const {\n return equal_eps(a * l.b, l.a * b);\n }\n Real dist(const Point &p) const {\n Point q = projection(p);\n return metric(p - q);\n }\n};\n\nbool is_orthogonal(const Line &l1, const Line &l2) {\n return l1.is_orthogonal(l2);\n}\nbool is_parallel(const Line &l1, const Line &l2) {\n return l1.is_parallel(l2);\n}\nPoint crosspoint(const Line &l1, const Line &l2) {\n return l1.crossppoint(l2);\n}\n\n} // namespace geometry\n\nnamespace geometry {\n\nstruct Segment {\n Line l;\n Point p, q;\n Segment() = default;\n Segment(const Point &_p, const Point &_q) : l(_p, _q), p(_p), q(_q) {}\n bool cross(const Segment &s) const {\n bool f1 = ccw(p, q, s.p) * ccw(p, q, s.q) <= 0;\n bool f2 = ccw(s.p, s.q, p) * ccw(s.p, s.q, q) <= 0;\n return f1 && f2;\n }\n Point crosspoint(const Segment &s) const {\n if (cross(s)) return l.crossppoint(s.l);\n return INF_POINT;\n }\n Real dist(const Point &r) const {\n if (dot(q - p, r - p) < eps) return (r - p).metric();\n if (dot(p - q, r - q) < eps) return (r - q).metric();\n return l.dist(r);\n }\n Real dist(const Segment &s) const {\n if (cross(s)) return 0;\n Real res = INF_REAL;\n res = min(res, dist(s.p));\n res = min(res, dist(s.q));\n res = min(res, s.dist(p));\n res = min(res, s.dist(q));\n return res;\n }\n};\n\nbool cross(const Segment &s, const Segment &t) {\n return s.cross(t);\n}\n\nPoint crosspoint(const Segment &s, const Segment &t) {\n return s.crosspoint(t);\n}\n\nReal dist(const Segment &s, const Segment &t) {\n return s.dist(t);\n}\n\n} // nemespace geometry\n\nnamespace geometry {\n\n// { x in R^2 | |x - p| = r}\nstruct circle {\n Point p;\n Real r;\n circle() = default;\n circle(const Point _p, Real _r) : p(_p), r(_r) {}\n int count_common_tangent(const circle &c) const {\n Real d = metric(p - c.p);\n if (d > r + c.r + eps) return 4;\n if (equal_eps(d, r + c.r)) return 3;\n if (equal_eps(d, abs(r - c.r))) return 1;\n if (d < abs(r - c.r) - eps) return 0;\n return 2;\n }\n vector<Point> crosspoints(const Line &l) const {\n Real d = l.dist(p);\n if (d > r + eps) return {};\n Point q = l.projection(p);\n if (equal_eps(d, r)) {\n return {q};\n }\n Point e = l.unit();\n Real t = sqrtl(r * r - d * d);\n return {q - t * e, q + t * e};\n }\n vector<Point> crosspoints(const circle &c) const {\n int t = count_common_tangent(c);\n if (t == 0 || t == 4) return {};\n Real d = metric(p - c.p);\n if (t == 1) {\n if (c.r < r - eps) {\n return {p + (c.p - p) * (r / d)};\n } else {\n return {c.p + (p - c.p) * (c.r / d)};\n }\n } else if (t == 3) {\n geometry::Real s = r / (r + c.r);\n return {p + (c.p - p) * s};\n } else {\n geometry::Real la = 2 * (p.x - c.p.x);\n geometry::Real lb = 2 * (p.y - c.p.y);\n geometry::Real lc = (p.x + c.p.x) * (p.x - c.p.x) + (p.y + c.p.y) * (p.y - c.p.y) + (r + c.r) * (c.r - r);\n return crosspoints(Line(la, lb, lc));\n }\n }\n vector<Point> points_of_tangency(const Point &q) const {\n Real d = metric(p - q);\n if (d < r - eps) return {};\n if (equal_eps(d, r)) return {q};\n return crosspoints(circle(q, sqrtl(d * d - r * r)));\n }\n vector<Point> points_of_common_tangency(const circle &c) const {\n Real d = metric(p - c.p);\n if (equal_eps(d, 0)) return {};\n Point u = (c.p - p).unit();\n Point v = u.rotate(PI / 2);\n vector<Point> res;\n for (int s : {-1, 1}) {\n Real h = (r + s * c.r) / d;\n if (equal_eps(h * h, 1)) {\n res.push_back(p + (h > 0 ? u : -u) * r);\n } else if (1 - h * h > 0) {\n Point u2 = u * h, v2 = v * sqrtl(1 - h * h);\n res.push_back(p + (u2 + v2) * r);\n res.push_back(p + (u2 - v2) * r);\n }\n }\n return res;\n }\n};\n\n} // namespace geometry\nusing namespace geometry;\n\nbool solve() {\n int N;\n cin >> N;\n if (N == 0) return false;\n Point s, t;\n cin >> s >> t;\n Segment S(s, t);\n auto sub = [&] (Point a, Point b, Real h) -> Real {\n Real d = S.dist(Segment(a, b));\n Line L(Point(d, 0), Point(d, h));\n Real l = 0, r = 1e9;\n for (int t = 0; t < 100; t++) {\n Real m = (l + r) / 2;\n ([&] {\n for (auto p : circle(Point(0, m), m).crosspoints(L)) {\n if (p.y < h + eps) return true;\n }\n return false;\n } () ? r : l) = m;\n }\n return r;\n };\n Real ans = INF_REAL;\n while (N--) {\n Real x1, y1, x2, y2, h;\n cin >> x1 >> y1 >> x2 >> y2 >> h;\n Point a(x1, y1), b(x1, y2), c(x2, y2), d(x2, y1);\n if (S.cross(Segment(a, b))) ans = 0;\n if (S.cross(Segment(b, c))) ans = 0;\n if (S.cross(Segment(c, d))) ans = 0;\n if (S.cross(Segment(d, a))) ans = 0;\n if (x1 <= s.x && s.x <= x2 && y1 <= s.y && s.y <= y2) ans = 0;\n if (x1 <= t.x && t.x <= x2 && y1 <= t.y && t.y <= y2) ans = 0;\n ans = min(ans, sub(a, b, h));\n ans = min(ans, sub(b, c, h));\n ans = min(ans, sub(c, d, h));\n ans = min(ans, sub(d, a, h));\n }\n cout << fixed << setprecision(16) << ans << endl;\n return true;\n}\n\nint main() {\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3840, "score_of_the_acc": -0.8694, "final_rank": 15 }, { "submission_id": "aoj_1157_10602332", "code_snippet": "#include <bits/stdc++.h>\n#include <atcoder/all>\nusing namespace std;\nusing namespace atcoder;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rrep(i,start,end) for (ll i = start;i >= (ll)(end);i--)\n#define repn(i,end) for(ll i = 0; i <= (ll)(end); i++)\n#define reps(i,start,end) for(ll i = start; i < (ll)(end); i++)\n#define repsn(i,start,end) for(ll i = start; i <= (ll)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef vector<ll> vll;\ntypedef vector<pair<ll ,ll>> vpll;\ntypedef vector<vector<ll>> vvll;\ntypedef set<ll> sll;\ntypedef map<ll , ll> mpll;\ntypedef pair<ll ,ll> pll;\ntypedef tuple<ll , ll , ll> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (ll)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1LL << 60;\nconst ld EPS = 1e-9;\n \nll lceil(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b)+1;}else{return -((-a)/b);}}\nll lfloor(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b);}else{return -((-a)/b)-1;}}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\n//0indexed\ninline ll topbit(ll a){assert(a != 0);return 63 - __builtin_clzll(a);}\ninline ll smlbit(ll a){assert(a != 0);return __builtin_ctzll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\n\n//参考 https://github.com/saphmitchy/deliair-lib\n// 型名\n// R:Real, P:Point, L:Line, S:Segment, C:Circle, VP:vector<Point>\n\n#define X(p) real(p)\n#define Y(p) imag(p)\n\nusing R = ld;\nusing P = complex<R>;\nusing VP = vector<P>;\n\n//const R EPS = 1e-9; // ここは適宜調節する,いつものやつから消す\nconst R pi = acos(-1.0);\n\nint sgn(R a) {\n return (a < -EPS) ? -1 : (a > EPS) ? 1 : 0;\n} // 符号関数\n\nbool eq(R a, R b) {//実数の一致判定\n return sgn(b - a) == 0;\n}\n\nP operator*(P p, R d) {//ベクトルのd倍\n return P(X(p) * d, Y(p) * d);\n}\n\nP operator/(P p, R d) {//ベクトルの1/d倍\n return p * (1 / d);\n}\n\nistream &operator>>(istream &is, P &p) {\n // R a, b; // 入力が小数\n int a, b; // 入力が整数\n is >> a >> b;\n p = P(a, b);\n return is;\n}\n\nostream &operator<<(ostream &os, P p) {\n return os << X(p) << ' ' << Y(p);\n}\n\nR getarg(P b,P a){//ベクトルbはベクトルaを何radian回転させる必要があるか\n assert(sgn(abs(a)) != 0);//長さが0はだめ\n return arg(b/a);\n}\n\nbool cp_x(P p, P q) {//ベクトルの比較x軸で比較->y軸で比較\n if (!eq(X(p), X(q)))\n return X(p) < X(q);\n return Y(p) < Y(q);\n}\n\nbool cp_y(P p, P q) {//ベクトルの比較y軸で比較->x軸で比較\n if (!eq(Y(p), Y(q)))\n return Y(p) < Y(q);\n return X(p) < X(q);\n}\n\nstruct L {//直線ab\n P a, b;\n L() {}\n L(P a, P b) : a(a), b(b) {}\n\n // 入出力(必要なら)\n friend ostream &operator<<(ostream &os, L &l) {\n return os << l.a << ' ' << l.b;\n }\n friend istream &operator>>(istream &is, L &l) {\n return is >> l.a >> l.b;\n }\n};\n\nstruct S : L {//線分ab\n S() {}\n S(P a, P b) : L(a, b) {}\n};\n\nstruct C {//中心p 半径rの円\n P p;\n R r;\n C() {}\n C(P p, R r) : p(p), r(r) {}\n};\n\nP rot(P p, R t) {//ベクトルの回転\n return p * P(cos(t), sin(t));\n}\n\n//2つのベクトルの内積\nR dot(P p, P q) {\n return X(p) * X(q) + Y(p) * Y(q);\n}\n\n//2つのベクトルの外積\nR det(P p, P q) {\n return X(p) * Y(q) - Y(p) * X(q);\n}\n\n// https://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_C&lang=jp\nint ccw(P a, P b, P c) { // 線分 ab に対する c の位置関係 \n b -= a, c -= a;//ベクトルab,ベクトルacにした\n if (sgn(det(b, c)) == 1)//外積右ねじ正\n return +1; // COUNTER_CLOCKWISE a,b,cが反時計回り\n if (sgn(det(b, c)) == -1)\n return -1; // CLOCKWISE\n if (dot(b, c) < 0.0)\n return +2; // ONLINE_BACK\n if (norm(b) < norm(c))\n return -2; // ONLINE_FRONT\n return 0; // ON_SEGMENT\n}\n\nbool para(L a, L b) { // 平行判定\n return eq(det(a.b - a.a, b.b - b.a), 0.0);\n}\n\nbool orth(L a, L b) { // 垂直判定\n return eq(dot(a.b - a.a, b.b - b.a), 0.0);\n}\n\nP proj(L l, P p) { // 垂線の足\n R t = dot(p - l.a, l.b - l.a) / norm(l.b - l.a);\n return l.a + (l.b - l.a) * t;\n}\n\n// これいる?\n// P proj(S s, P p) {\n// R t = dot(p - s.a, s.b - s.a) / norm(s.b - s.a);\n// return s.a + (s.b - s.a) * t;\n// }\n\nP refl(L l, P p) { // 線対称の位置にある点\n return p + (proj(l, p) - p) * 2.0;\n}\n\nbool inter(L l, P p) { // 交点を持つか判定\n return abs(ccw(l.a, l.b, p)) != 1;\n}\n\nbool inter(S s, P p) {\n return ccw(s.a, s.b, p) == 0;\n}\n\nbool inter(L l, L m) {\n if (!eq(det(l.b - l.a, m.b - m.a), 0.0))\n return true;\n return eq(det(l.b - l.a, m.b - l.a), 0.0);\n}\n\nbool inter(L l, S s) {\n return sgn(det(l.b - l.a, s.a - l.a) * det(l.b - l.a, s.b - l.a)) <= 0;\n}\n\nbool inter(S s, L l) {\n return inter(l, s);\n}\n\nbool inter(S s, S t) {\n if (ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) > 0)\n return false;\n return ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\nR dist(P p, P q) {\n return abs(q - p);\n}\n\nR dist(L l, P p) {\n return abs(p - P(proj(l, p)));\n}\n\n//R dist(S s, P p) {\n// P h = proj(s, p);\n// if (inter(s, h))\n// return abs(h - p);\n// return min(abs(s.a - p), abs(s.b - p));\n//}\n\nR dist(S s, P p) {\n P h = proj(s, p);\n if(dot(p-s.a,s.b-s.a) <= 0) return abs(s.a-p);\n if(dot(p-s.b,s.a-s.b) <= 0) return abs(s.b-p);\n return abs(p - h);\n}\n\nR dist(L l, L m) {\n return inter(l, m) ? 0.0 : dist(l, m.a);\n}\n\nR dist(S s, S t) {\n if (inter(s, t))\n return 0.0;\n return min({dist(s, t.a), dist(s, t.b), dist(t, s.a), dist(t, s.b)});\n}\n\nR dist(L l, S s) {\n if (inter(l, s))\n return 0.0;\n return min(dist(l, s.a), dist(l, s.b));\n}\n\nR dist(S s, L l) {\n return dist(l, s);\n}\n\nbool inter(C c, L l) {\n return sgn(c.r - dist(l, c.p)) >= 0;\n}\n\nbool inter(C c, P p) {\n return eq(abs(p - c.p), c.r);\n}\n\n// 共通接線の本数\n// 交点なし:4\n// 外接:3\n// 2点で交わる:2\n// 内接:1\n// 一方がもう一方を内包:0\nint inter(C c1, C c2) {\n if (c1.r < c2.r)\n swap(c1, c2);\n R d = abs(c1.p - c2.p);\n int a = sgn(d - c1.r - c2.r);\n if (a >= 0)\n return 3 + a;\n return 1 + sgn(d - c1.r + c2.r);\n}\n\nVP crosspoint(L l, L m) {\n VP ret;\n if (!inter(l, m))\n return ret;\n R A = det(l.b - l.a, m.b - m.a);\n R B = det(l.b - l.a, l.b - m.a);\n if (eq(A, 0.0) && eq(B, 0.0)) {\n ret.emplace_back(m.a);\n } else {\n ret.emplace_back(m.a + (m.b - m.a) * B / A);\n }\n return ret;\n}\n\nVP crosspoint(S s, S t) {\n return inter(s, t) ? crosspoint(L(s), L(t)) : VP();\n}\n\nVP crosspoint(C c, L l) {//円と直線の交点\n P h = proj(l, c.p);\n P e = (l.b - l.a) / abs(l.b - l.a);\n VP ret;\n if (!inter(c, l))\n return ret;\n if (eq(dist(l, c.p), c.r)) {\n ret.emplace_back(h);\n } else {\n R b = sqrt(c.r * c.r - norm(h - c.p));\n ret.push_back(h + e * b), ret.push_back(h - e * b);\n }\n return ret;\n}\n\nVP crosspoint(C c, S s) {//円と線分の交点\n P h = proj(s, c.p);\n P e = (s.b - s.a) / abs(s.b - s.a);\n VP ret;\n if (!inter(c, s))\n return ret;\n if (eq(dist(s, c.p), c.r)) {\n ret.emplace_back(h);\n } else {\n R b = sqrt(c.r * c.r - norm(h - c.p));\n if(ccw(s.a,s.b,h - e * b) == 0){//s.aに近い方から線分上なら追加する\n ret.push_back(h - e * b);\n }\n if(ccw(s.a,s.b,h + e * b)==0){\n ret.push_back(h + e * b);\n }\n }\n return ret;\n}\n\nVP crosspoint(C c1, C c2) {//2つの円の交わる点\n R d = abs(c1.p - c2.p);\n R a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d));\n R t = atan2(Y(c2.p) - Y(c1.p), X(c2.p) - X(c1.p));\n VP ret;\n if (inter(c1, c2) % 4 == 0) // 交わらないとき\n return ret;\n if (eq(a, 0.0)) {\n ret.emplace_back(P(c1.p + rot(P(c1.r, 0.0), t)));\n } else {\n P p1 = c1.p + rot(P(c1.r, 0.0), t + a);\n P p2 = c1.p + rot(P(c1.r, 0.0), t - a);\n ret.emplace_back(p1), ret.emplace_back(p2);\n }\n return ret;\n}\n\nVP cut(VP p, L l, bool border = true) { // 直線が多角形に切り取られる区間\n int n = sz(p);\n p.emplace_back(p[0]), p.emplace_back(p[1]);\n VP ret;\n rep(i, n) {\n if (!eq(dist(l, p[i]), 0) && !eq(dist(l, p[i + 1]), 0)) {\n S s(p[i], p[i + 1]);\n if (eq(dist(l, s), 0)) {\n auto res = crosspoint(l, s);\n ret.emplace_back(res[0]);\n }\n }\n if (eq(dist(l, p[i + 1]), 0)) {\n if ((eq(dist(l, p[i]), 0) || eq(dist(l, p[i + 2]), 0)) && !border)\n continue;\n S s(p[i], p[i + 2]);\n if (eq(dist(l, s), 0))\n ret.emplace_back(p[i + 1]);\n }\n }\n return ret;\n}\n\nVP rectangle(S s, R r) { // sを軸とした幅rの長方形\n P d = (s.a - s.b) * P(0, 1);\n d *= r / sqrt(norm(d));\n return VP{s.a + d, s.a - d, s.b - d, s.b + d};\n}\n\nL vertical_bisector(P p, P q) { // 垂直二等分線\n L l;\n l.a = (p + q) * 0.5;\n l.b = l.a + rot(q - p, pi * 0.5);\n return l;\n}\n\nL angle_bisector(P a,P b,P c){//角abcの二等分線(角bの2等分線)\n L l;\n l.a = b;\n R ang = atan2(Y(c-b),X(c-b)) - atan2(Y(a-b),X(a-b));//なす角\n ang/=2.0;\n l.b = l.a + rot(a-b,ang);\n return l;\n}\n\nC Apollonius(P p, P q, R a, R b) { // アポロニウスの円\n P p1 = (p * b + q * a) / (a + b), p2 = (-p * b + q * a) / (a - b);\n C c;\n c.p = (p1 + p2) * 0.5;\n c.r = abs(p1 - p2) * 0.5;\n return c;\n}\n\nR area(VP p) { // 多角形の面積\n R ret = 0.0;\n int n = sz(p);\n rep(i, n) ret += det(p[i], p[(i + 1) % n]);\n return abs(ret * 0.5);\n}\n\nint in_polygon(VP p, P q) { // IN:2, ON:1, OUT:0\n int n = sz(p);\n int ret = 0;\n rep(i, n) {\n P a = p[i] - q, b = p[(i + 1) % n] - q;\n if (eq(det(a, b), 0.0) && sgn(dot(a, b)) <= 0)\n return 1;\n if (Y(a) > Y(b))\n swap(a, b);\n if (sgn(Y(a)) <= 0 && sgn(Y(b)) == 1 && sgn(det(a, b)) == 1)\n ret ^= 2;\n }\n return ret;\n}\n\nVP tangent(C c, P p) { // 点 p を通る円 c の接線と c の接点\n return crosspoint(c, C(p, sqrt(norm(p - c.p) - c.r * c.r)));\n}\n\nvector<L> tangent(C c1, C c2) { // 共通接線\n vector<L> ret;\n if (c1.r < c2.r)\n swap(c1, c2);\n R r = abs(c2.p - c1.p);\n if (eq(r, 0.0))\n return ret;\n P u = (c2.p - c1.p) / r;\n P v = rot(u, pi * 0.5);\n for (R s : {1.0, -1.0}) {\n R h = (c1.r + c2.r * s) / r;\n if (eq(abs(h), 1.0)) {\n ret.emplace_back(c1.p + u * c1.r, c1.p + (u + v) * c1.r);\n } else if (abs(h) < 1.0) {\n P uu = u * h, vv = v * sqrt(1.0 - h * h);\n ret.emplace_back(c1.p + (uu + vv) * c1.r, c2.p - (uu + vv) * c2.r * s);\n ret.emplace_back(c1.p + (uu - vv) * c1.r, c2.p - (uu - vv) * c2.r * s);\n }\n }\n return ret;\n}\n\nVP convex_hull(VP p) { // 凸包\n sort(all(p), cp_x);\n p.erase(unique(all(p)), end(p));\n int n = sz(p), k = 0;\n if (n == 1)\n return p;\n VP ch(2 * n);\n for (int i = 0; i < n; ch[k++] = p[i++]) {\n while (k >= 2 && sgn(det(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1])) <= 0)\n k--;\n }\n for (int i = n - 2, t = k + 1; i >= 0; ch[k++] = p[i--]) {\n while (k >= t && sgn(det(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1])) <= 0)\n k--;\n }\n ch.resize(k - 1);\n return ch;\n}\n\nR closest_pair(VP p) { // 最近点対の距離\n if (sz(p) <= 1)\n return 1e18;\n sort(all(p), cp_x);\n VP memo(sz(p));\n\n function<R(int, int)> rec = [&](int l, int r) {\n if (r - l <= 1)\n return R(1e18);\n int m = (l + r) >> 1;\n R x = X(p[m]);\n R ret = min(rec(l, m), rec(m, r));\n inplace_merge(p.begin() + l, p.begin() + m, p.begin() + r, cp_y);\n int cnt = 0;\n reps(i, l, r) {\n if (abs(X(p[i]) - x) >= ret)\n continue;\n rep(j, cnt) {\n P d = p[i] - memo[cnt - j - 1];\n if (Y(d) >= ret)\n break;\n chmin(ret, abs(d));\n }\n memo[cnt++] = p[i];\n }\n return ret;\n };\n\n return rec(0, sz(p));\n}\n\nR farthest_pair(VP p) {//最遠点対の距離\n VP ps = convex_hull(p);\n ll n = ps.size();\n if(n == 2){//凸包が潰れてる\n return dist(ps[0],ps[1]);\n }\n ll i = 0,j = 0;\n rep(k,n){//x軸方向に最も遠い点対を求める\n if(cp_x(ps[k],ps[i]))i = k;\n if(cp_x(ps[j],ps[k]))j = k;\n }\n R ret = 0;\n ll si = i,sj = j;\n while(i != sj || j != si){//180度反転しきるまで\n ret = max(ret,dist(ps[i],ps[j]));\n if(det(ps[(i+1)%n] - ps[i],ps[(j+1)%n]-ps[j]) < 0){\n i = (i + 1) % n;\n }else{\n j = (j + 1) % n;\n }\n }\n return ret;\n}\n\n// 原点, 点 a, 点 b とで囲まれる領域の面積 (三角形 ver と扇型 ver)\nR calc_element(P a, P b, R cr,bool triangle){\n if(triangle)return det(a,b)/2;\n else{\n P tmp = b * (P(X(a),-Y(a)));\n R ang = atan2(Y(tmp),X(tmp));\n return cr * cr * ang/2;\n }\n}\n\n// 円 C と、三角形 ((0, 0), ia, ib) との共通部分の面積\nR common_area(C c, P ia,P ib){\n P a = ia - c.p , b = ib - c.p;\n if(eq(abs(a-b),0))return 0;\n bool isin_a = (sgn(c.r - abs(a))>= 0);\n bool isin_b = (sgn(c.r - abs(b))>= 0);\n if(isin_a && isin_b)return calc_element(a,b,c.r,true);//aもbも円の中\n\n C oc(P(0,0),c.r);\n S seg(a,b);\n VP cr = crosspoint(oc,seg);\n if(cr.empty())return calc_element(a,b,c.r,false);\n P s = cr[0],t = cr.back();\n return calc_element(s,t,c.r,true) + calc_element(a,s,c.r,isin_a) + calc_element(t,b,c.r,isin_b);\n\n}\n\n\nR common_area(C c, VP vp){// 円cと多角形の共通部分の面積\n R ret = 0;\n ll n = vp.size();\n rep(i,n){\n ret += common_area(c,vp[i],vp[(i+1)%n]);\n }\n return ret;\n}\n\nR common_area(C p, C q) {// 円と円の共通部分の面積\n R d = abs(p.p - q.p);\n if (d >= p.r + q.r - EPS) return 0;\n else if (d <= abs(p.r - q.r) + EPS) return min(p.r, q.r) * min(p.r, q.r) * pi;\n R pcos = (p.r*p.r + d*d - q.r*q.r) / (p.r*d*2);\n R pang = acosl(pcos);\n R parea = p.r*p.r*pang - p.r*p.r*sin(pang*2)/2;\n R qcos = (q.r*q.r + d*d - p.r*p.r) / (q.r*d*2);\n R qang = acosl(qcos);\n R qarea = q.r*q.r*qang - q.r*q.r*sin(qang*2)/2;\n return parea + qarea;\n}\n\nvector<VP> divisions(vector<L> lf, R lim = 1e9) {\n vector<L> ls;\n each(l, lf) {\n bool ok = true;\n each(m, ls) {\n if (para(l, m) & inter(l, m.a)) {\n ok = false;\n break;\n }\n }\n if (ok)\n ls.emplace_back(l);\n }\n VP lc{P(-lim, -lim), P(lim, -lim), P(lim, lim), P(-lim, lim)};\n rep(i, 4) ls.emplace_back(lc[i], lc[(i + 1) % 4]);\n int m = sz(ls);\n VP ps;\n vector<vector<int>> lp(m);\n rep(i, m) {\n reps(j, i + 1, m) {\n each(p, crosspoint(ls[i], ls[j])) {\n if (max(abs(X(p)), abs(Y(p))) < lim + EPS) {\n lp[i].emplace_back(sz(ps)), lp[j].emplace_back(sz(ps));\n ps.emplace_back(p);\n }\n }\n }\n }\n int n = sz(ps);\n vector<int> id(n, -1), to;\n vector<R> rg;\n vector<vector<pair<R, int>>> li(n);\n rep(i, m) {\n sort(all(lp[i]), [&ps](int a, int b) { return cp_x(ps[a], ps[b]); });\n vector<int> q;\n rep(j, sz(lp[i])) {\n int me = id[lp[i][j]], st = j;\n auto np = ps[lp[i][j]];\n while (j + 1 < sz(lp[i])) {\n if (abs(ps[lp[i][j + 1]] - np) < EPS) {\n j++;\n if (id[lp[i][j]] != -1)\n me = id[lp[i][j]];\n } else\n break;\n }\n if (me == -1)\n me = lp[i][st];\n reps(k, st, j + 1) id[lp[i][k]] = me;\n q.emplace_back(me);\n }\n rep(i, sz(q) - 1) {\n P d = ps[q[i + 1]] - ps[q[i]];\n R s = atan2(Y(d), X(d)), t = atan2(-Y(d), -X(d));\n int x = q[i], y = q[i + 1];\n li[x].emplace_back(s, sz(to));\n li[x].emplace_back(s + pi * 2, sz(to));\n to.emplace_back(y), rg.emplace_back(t);\n li[y].emplace_back(t, sz(to));\n li[y].emplace_back(t + pi * 2, sz(to));\n to.emplace_back(x), rg.emplace_back(s);\n }\n }\n rep(i, n) sort(all(li[i]));\n vector<bool> u(sz(to), false);\n vector<VP> ret;\n rep(i, n) {\n each(l, li[i]) {\n int ns = l.second;\n if (u[ns])\n continue;\n VP nv;\n int no = ns;\n bool ok = true;\n while (1) {\n if (sz(nv) > 1) {\n P x = nv[sz(nv) - 2], y = nv[sz(nv) - 1], z = ps[to[no]];\n int c = ccw(x, y, z);\n if (c == 1)\n ok = false;\n if (c != -1)\n nv.pop_back();\n }\n nv.emplace_back(ps[to[no]]);\n u[no] = true;\n no = upper_bound(all(li[to[no]]), pair(rg[no] + EPS, -1))->second;\n if (no == ns)\n break;\n }\n if (ok)\n ret.emplace_back(nv);\n }\n }\n return ret;\n}\n\n//ref https://github.com/drken1215/algorithm/blob/master/Geometry/arg_sort.cpp\n//verify https://atcoder.jp/contests/abc139/submissions/me\n//点列を偏角ソート\nvoid arg_sort(VP &v){\n //原点=0,(pi,2pi] = -1 (0pi,pi] = 1\n auto sign = [&](const P &p){\n if(sgn(X(p)) == 0 && sgn(Y(p)) == 0){\n return 0;\n }else if(sgn(Y(p)) == -1 || (sgn(Y(p)) == 0 && sgn(X(p)) == 1)){\n return -1;\n }else{\n return 1;\n }\n };\n auto cp = [&](const P &p,const P &q){\n if(sign(p) != sign(q)){\n return sign(p) < sign(q);\n }else{//外積>0で判定\n //同じ向きにあるときは未定義、それぞれ決める\n return X(p) * Y(q) - Y(p) * X(q) > 0;\n }\n };\n sort(v.begin(),v.end(),cp);\n}\n\nusing tpl5 = tuple<ll,ll,ll,ll,ll>;\nvoid solve(ll n){\n LL(sx,sy,ex,ey);\n vector<tpl5> xyxyh(n);\n rep(i,n){\n LL(mx,my,Mx,My,h);\n xyxyh[i] ={mx,my,Mx,My,h};\n }\n S route(P(sx,sy),P(ex,ey));\n //一番近い点\n vector<R> vp(n,1<<30);\n rep(i,n){\n auto [mx,my,Mx,My,h] = xyxyh[i];\n VP nodes;\n nodes.emplace_back(mx,my);\n nodes.emplace_back(Mx,my);\n nodes.emplace_back(Mx,My);\n nodes.emplace_back(mx,My);\n if(in_polygon(nodes,P(sx,sy))> 0 or in_polygon(nodes,P(sx,sy)) > 0){\n cout << 0 << endl;\n return ;\n }\n rep(j,4){\n S l(nodes[j],nodes[(j+1)%4]);\n R d = dist(l,route);\n if(eq(d,0)){\n cout << 0 << endl;\n return ;\n }else{\n chmin(vp[i],d);\n }\n }\n }\n ld ng = 1001;//条件を満たさない値\n ld ok = 0;//条件を満たす値\n auto f = [&](ld x)->bool{\n //半径xが行けるか\n P cir(0,x);\n bool able = true;\n rep(i,n){\n P btm(vp[i],0);\n P top(vp[i],get<4>(xyxyh[i]));\n if(sgn(dist(S(top,btm),cir)-x) <0){\n able = false;\n }\n }\n return able;\n };\n rep(z,100){\n ld mid = (ok + ng)/2;\n if(f(mid)){\n ok = mid;\n }else{\n ng = mid;\n }\n }\n cout << std::fixed << std::setprecision(10) << ok << endl;\n}\n\n \nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true){\n LL(n);\n if(n == 0)break;\n solve(n);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3968, "score_of_the_acc": -1, "final_rank": 17 }, { "submission_id": "aoj_1157_10473434", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing ull=unsigned long long;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define loop(n) for (int tjh = 0; tjh < (int)(n); tjh++)\n#define y0 ytmp0\nsigned main() {\n cin.tie(0)->sync_with_stdio(0);//NOLINT\n cout<<fixed<<setprecision(16);\n double sx,sy,ex,ey;\n double minx,miny,maxx,maxy,h;\n double dx,dy,d,res;\n double l,m1,m2,r,d1,d2;\n auto f=[&](double v)->double {\n double x=sx+v*dx;\n double y=sy+v*dy;\n double x0=minx<=x&&x<=maxx?0:min(abs(x-minx),abs(x-maxx));\n double y0=miny<=y&&y<=maxy?0:min(abs(y-miny),abs(y-maxy));\n return hypot(x0,y0);\n };\n for (int N;cin>>N,N;) {\n cin>>sx>>sy>>ex>>ey;\n dx=ex-sx;dy=ey-sy;\n res=1000;\n rep(i,N) {\n cin>>minx>>miny>>maxx>>maxy>>h;\n l=0,m1=1.0/3.0,m2=2.0/3.0,r=1;\n loop(100){\n d1=f(m1);d2=f(m2);\n if (d1<=d2)r=m2;\n else l=m1;\n m1=l+(r-l)/3.0;\n m2=m1+(r-l)/3.0;\n }\n d=f(m1);\n if (d<=h) {\n if (d<=res)res=d;\n }else {\n d=(h*h+d*d)/(h*2.0);\n if (d<=res)res=d;\n }\n }\n cout<<res<<\"\\n\";\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3840, "score_of_the_acc": -0.8408, "final_rank": 13 }, { "submission_id": "aoj_1157_9336120", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(i, N) for(ll i = 0; i < (ll)(N); ++i)\n#define per(i, N) for(ll i = (ll)(N) - 1; i >= 0; --i)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\n#define bit(n, k) (((n) >> (k)) & 1)\n#define pcnt(n) (bitset<64>(n).count())\n#define endl '\\n'\n#define fi first\n#define se second\n#define mkpr make_pair\n#define mktpl make_tuple\n#define eb emplace_back\ntemplate <class T> std::istream& operator>>(std::istream& is, std::vector<T>& V) {\n for (auto& it : V) is >> it;\n return is;\n}\ntemplate <class T> std::ostream& operator<<(std::ostream& os, const std::vector<T>& V) {\n for (int i = 0 ; i < (int)V.size() ; i++) {\n os << V[i] << (i + 1 == (int)V.size() ? \"\" : \" \");\n }\n return os;\n}\nusing namespace std;\n\nusing ld = long double;\n\n\nusing namespace std;\n\nnamespace geometry{\n using Real = long double;\n using Point = complex<Real>;\n constexpr Real EPS = 1e-10;\n Real Pi = acos(-1);\n\n istream& operator>>(istream& is, Point& p){\n Real a, b; is >> a >> b;\n p = Point(a, b);\n return is;\n }\n ostream& operator<<(ostream& os, const Point& p){\n return os << real(p) << \" \" << imag(p);\n }\n bool equals(const Real& a, const Real& b){\n return fabs(a - b) < EPS;\n }\n Point operator*(const Point& p, const Real& d){\n return Point(real(p) * d, imag(p) * d);\n }\n Real cross(const Point& a, const Point& b){\n return real(a) * imag(b) - imag(a) * real(b);\n }\n Real dot(const Point& a, const Point& b){\n return real(a) * real(b) + imag(a) * imag(b);\n }\n int sign(const Real &x){\n return x >= EPS ? +1 : x <= -EPS ? -1 : 0;\n }\n int ccw(const Point &a, const Point &b, const Point &p){\n if(sign(cross(b - a, p - a)) == +1) return +1; // conter clockwise\n if(sign(cross(b - a, p - a)) == -1) return -1; // clockwise\n if(sign(dot(b - a, p - a)) == -1) return +2; // p--a--b online back\n if(sign(dot(a - b, p - b)) == -1) return -2; // a--b--p online front\n return 0; // a--p--b on segment\n }\n Point projection(const Point& a, const Point& b, const Point& p){\n Real t = dot(p - a, a - b) / norm(a - b);\n return a + (a - b) * t;\n }\n Point reflection(const Point& a, const Point& b, const Point& p){\n return p + (projection(a, b, p) - p) * 2;\n }\n}\n\nusing namespace std;\n\n// Required geometry\nnamespace geometry{\n struct Line{\n Point a, b;\n Line() = default;\n Line(const Point& a, const Point& b) : a(a), b(b) {}\n Line(const Real& A, const Real& B, const Real& C){ // Ax+By=C\n if(equals(A, 0)){\n assert(!equals(B, 0));\n a = Point(0, C / B), b = Point(1, C / B);\n }\n else if(equals(B, 0)){\n a = Point(C / A, 0), b = Point(C / A, 1);\n }\n else{\n a = Point(0, C / B), b = Point(C / A, 0);\n }\n }\n friend istream& operator>>(istream& is, Line& l) {\n return is >> l.a >> l.b;\n }\n friend ostream& operator<<(ostream& os, Line& l) {\n return os << l.a << \" to \" << l.b;\n }\n };\n bool isOrthogonal(const Line& p, const Line& q){\n return equals(dot(p.b - p.a, q.b - q.a), 0.0);\n }\n bool isParallel(const Line& p, const Line& q){\n return equals(cross(p.b - p.a, q.b - q.a), 0.0);\n }\n Point cross_point(const Line &l, const Line &m){\n Real A = cross(l.b - l.a, m.b - m.a);\n Real B = cross(l.b - l.a, l.b - m.a);\n if(equals(abs(A), 0.0) && equals(abs(B), 0.0)) return m.a;\n assert(!equals(abs(A), 0.0));\n return m.a + (m.b - m.a) * B / A;\n }\n}\nusing namespace std;\n\n// Required geometry\n// Required Line\nnamespace geometry{\n struct Segment : Line{\n Segment() = default;\n using Line::Line;\n };\n bool is_intersect_sp(const Segment &s, const Point &p){\n return ccw(s.a, s.b, p) == 0;\n } \n bool is_intersect_ss(const Segment &s, const Segment &t){\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n }\n Real distance_sp(const Segment &s, const Point &p){\n Point r = projection(s.a, s.b, p);\n if(is_intersect_sp(s, r)) return abs(r - p);\n return min(abs(s.a - p), abs(s.b - p));\n }\n Real distance_ss(const Segment &a, const Segment &b){\n if(is_intersect_ss(a, b)) return 0;\n return min({distance_sp(a, b.a), distance_sp(a, b.b),\n distance_sp(b, a.a), distance_sp(b, a.b)});\n }\n}\nusing namespace geometry;\n\nint main() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n while(1){\n int N; cin >> N;\n if(N == 0) break;\n ld sx, sy, ex, ey; cin >> sx >> sy >> ex >> ey;\n vector<Segment> Segs(N * 4);\n vector<ld> H(N);\n\n bool covered = false;\n for(int i = 0; i < N; i++){\n ld mnx, mny, mxx, mxy; cin >> mnx >> mny >> mxx >> mxy;\n cin >> H[i];\n\n Point P1(mnx, mny), P2(mxx, mny), P3(mxx, mxy), P4(mnx, mxy);\n Segs[i * 4 + 0] = Segment(P1, P2);\n Segs[i * 4 + 1] = Segment(P2, P3);\n Segs[i * 4 + 2] = Segment(P3, P4);\n Segs[i * 4 + 3] = Segment(P4, P1);\n\n if(mnx <= sx && sx <= mxx && mny <= sy && sy <= mxy){\n covered = true;\n }\n }\n\n if(covered){\n cout << 0.00000 << endl;\n continue;\n }\n\n Segment stoe(Point(sx, sy), Point(ex, ey));\n\n //for (int i = 0 ; i < 4 * N ; i++) {\n // cout << distance_ss(stoe, Segs[i]) << \"! \" << Segs[i] << endl;\n //}\n\n auto check{[&](ld mid) -> bool {\n bool flag = true;\n for(int i = 0; i < N * 4; i++){\n ld d = distance_ss(stoe, Segs[i]);\n ld h = H[i / 4];\n ld R = mid;\n\n if(h <= R){\n ld Lval = (R - h) * (R - h) + d * d;\n ld Rval = R * R;\n if(!(Lval >= Rval)) flag = false;\n }\n else{\n if(d <= R) flag = false;\n }\n }\n return flag;\n }};\n\n ld ok = 0, ng = 1001.0;\n for (int _ = 0 ; _ < 40 ; _++) {\n ld mid = (ok + ng) / 2;\n if(check(mid)) ok = mid;\n else ng = mid;\n }\n\n cout << fixed << setprecision(6);\n cout << ok << endl;\n }\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 3676, "score_of_the_acc": -0.7868, "final_rank": 12 }, { "submission_id": "aoj_1157_9147889", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\n#define rep(i, a, b) for(ll i = a; i < b; ++i)\n#define rrep(i, a, b) for(ll i = a; i >= b; --i)\nconstexpr ll inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\nusing Real = long double;\nconst Real EPS = 1e-8, PI = acos(Real(-1.0));\nint sign(const Real& r) {\n if(r <= -EPS) return -1;\n if(r >= +EPS) return +1;\n return 0;\n}\nbool eq(const Real& a, const Real& b) {\n return sign(a - b) == 0;\n}\nusing Point = complex<Real>;\nistream& operator>>(istream& is, Point& p) {\n Real a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n}\nostream& operator<<(ostream& os, const Point& p) {\n return os << p.real() << \" \" << p.imag();\n}\nPoint operator*(const Point& p, const Real& d) {\n return Point(p.real() * d, p.imag() * d);\n}\nPoint operator/(const Point& p, const Real& d) {\n return Point(p.real() / d, p.imag() / d);\n}\nPoint rot(const Point& p, Real theta) {\n return p * Point(cos(theta), sin(theta));\n}\nReal dot(const Point& p1, const Point& p2) {\n return (conj(p1) * p2).real();\n}\nReal cross(const Point& p1, const Point& p2) {\n return (conj(p1) * p2).imag();\n}\nReal dist(const Point& p1, const Point& p2) {\n return abs(p1 - p2);\n}\nbool comp_x(const Point& p1, const Point& p2) {\n return eq(p1.real(), p2.real()) ? p1.imag() < p2.imag() : p1.real() < p2.real();\n}\nbool comp_y(const Point& p1, const Point& p2) {\n return eq(p1.imag(), p2.imag()) ? p1.real() < p2.real() : p1.imag() < p2.imag();\n}\nbool comp_arg(const Point& p1, const Point& p2) {\n return arg(p1) < arg(p2);\n}\nint ccw(const Point& a, Point b, Point c) {\n b -= a;\n c -= a;\n if(sign(cross(b, c)) == 1) return 1;\n if(sign(cross(b, c)) == -1) return -1;\n if(sign(dot(b, c)) == -1) return +2;\n if(norm(b) < norm(c)) return -2;\n return 0;\n}\nReal closest_pair(vector<Point> ps) {\n if((int)ps.size() <= 1) return 1e18;\n sort(ps.begin(), ps.end(), comp_x);\n vector<Point> memo(ps.size());\n auto func = [&](auto& func, int l, int r) -> Real {\n if(r - l <= 1) return 1e18;\n int m = (l + r) >> 1;\n Real x = ps[m].real();\n Real res = min(func(func, l, m), func(func, m, r));\n inplace_merge(ps.begin() + l, ps.begin() + m, ps.begin() + r, comp_y);\n int cnt = 0;\n for(int i = l; i < r; ++i) {\n if(abs(ps[i].real() - x) >= res) continue;\n for(int j = 0; j < cnt; ++j) {\n Point d = ps[i] - memo[cnt - j - 1];\n if(d.imag() >= res) break;\n res = min(res, abs(d));\n }\n memo[cnt++] = ps[i];\n }\n return res;\n };\n return func(func, 0, (int)ps.size());\n}\nstruct Line {\n Point a, b;\n Line() = default;\n Line(const Point& a, const Point& b)\n : a(a), b(b) {}\n};\nusing Segment = Line;\nbool is_parallel(const Line& a, const Line& b) {\n return eq(cross(a.b - a.a, b.b - b.a), 0.0);\n}\nbool is_orthogonal(const Line& a, const Line& b) {\n return eq(dot(a.b - a.a, b.b - b.a), 0.0);\n}\nPoint projection(const Line& l, const Point& p) {\n Real t = dot(p - l.a, l.b - l.a) / norm(l.b - l.a);\n return l.a + (l.b - l.a) * t;\n}\nPoint reflection(const Line& l, const Point& p) {\n return p + (projection(l, p) - p) * 2.0;\n}\nbool is_intersect_lp(const Line& l, const Point& p) {\n return abs(ccw(l.a, l.b, p)) != 1;\n}\nbool is_intersect_sp(const Segment& s, const Point& p) {\n return ccw(s.a, s.b, p) == 0;\n}\nbool is_intersect_ll(const Line& l1, const Line& l2) {\n if(!eq(cross(l1.b - l1.a, l2.b - l2.a), 0.0)) return true;\n return eq(cross(l1.b - l1.a, l2.b - l1.a), 0.0);\n}\nbool is_intersect_ls(const Line& l, const Segment& s) {\n return sign(cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a)) <= 0;\n}\nbool is_intersect_sl(const Segment& s, const Line& l) {\n return is_intersect_ls(l, s);\n}\nbool is_intersect_ss(const Segment& s1, const Segment& s2) {\n if(ccw(s1.a, s1.b, s2.a) * ccw(s1.a, s1.b, s2.b) > 0) return false;\n return ccw(s2.a, s2.b, s1.a) * ccw(s2.a, s2.b, s1.b) <= 0;\n}\nvector<Point> intersection_ll(const Line& l1, const Line& l2) {\n vector<Point> res;\n if(!is_intersect_ll(l1, l2)) return res;\n Real a = cross(l1.b - l1.a, l2.b - l2.a);\n Real b = cross(l1.b - l1.a, l1.b - l2.a);\n if(eq(a, 0.0) and eq(b, 0.0)) {\n res.push_back(l2.a);\n } else {\n res.push_back(l2.a + (l2.b - l2.a) * b / a);\n }\n return res;\n}\nvector<Point> intersection_ss(const Segment& s1, const Segment& s2) {\n return is_intersect_ss(s1, s2) ? intersection_ll(Line(s1), Line(s2)) : vector<Point>();\n}\nReal dist_lp(const Line& l, const Point& p) {\n return abs(p - projection(l, p));\n}\nReal dist_sp(const Segment& s, const Point& p) {\n Point h = projection(s, p);\n if(is_intersect_sp(s, h)) return abs(h - p);\n return min(abs(s.a - p), abs(s.b - p));\n}\nReal dist_ll(const Line& l1, const Line& l2) {\n if(is_intersect_ll(l1, l2)) return 0.0;\n return dist_lp(l1, l2.a);\n}\nReal dist_ss(const Segment& s1, const Segment& s2) {\n if(is_intersect_ss(s1, s2)) return 0.0;\n return min({dist_sp(s1, s2.a), dist_sp(s1, s2.b), dist_sp(s2, s1.a), dist_sp(s2, s1.b)});\n}\nReal dist_ls(const Line& l, const Segment& s) {\n if(is_intersect_ls(l, s)) return 0.0;\n return min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\nReal dist_sl(const Segment& s, const Line& l) {\n return dist_ls(l, s);\n}\nint main(void) {\n while(1) {\n int n;\n cin >> n;\n if(n == 0) break;\n Point s, t;\n cin >> s >> t;\n Segment route(s, t);\n vector<vector<Point>> b(n, vector<Point>(2));\n vector<int> h(n);\n rep(i, 0, n) {\n cin >> b[i][0] >> b[i][1] >> h[i];\n }\n long double lower = 0.0, upper = 1005.0;\n rep(_, 0, 100) {\n long double r = (lower + upper) / 2;\n bool flag = true;\n rep(i, 0, n) {\n if(b[i][0].real() <= s.real() and b[i][0].imag() <= s.imag() and s.real() <= b[i][1].real() and s.imag() <= b[i][1].imag()) {\n flag = false;\n continue;\n }\n rep(j, 0, 2) {\n rep(k, 0, 2) {\n Point p1 = b[i][j];\n Point p2 = {b[i][k].real(), b[i][1 - k].imag()};\n Segment seg(p1, p2);\n long double d = dist_ss(route, seg);\n if(r > h[i]) {\n d *= d;\n d += (r - h[i]) * (r - h[i]);\n d = sqrtl(d);\n }\n if(d < r) {\n flag = false;\n }\n }\n }\n }\n if(flag) {\n lower = r;\n } else {\n upper = r;\n }\n }\n cout << lower << '\\n';\n }\n}", "accuracy": 1, "time_ms": 820, "memory_kb": 3624, "score_of_the_acc": -1.1507, "final_rank": 18 }, { "submission_id": "aoj_1157_8031344", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rng(i, l, r) for(int i = int(l); i < int(r); i++)\n#define rep(i, n) rng(i, 0, n)\n#define sz(v) int(v.size())\n#define foa(s, v) for(auto& s : v)\n#define all(v) v.begin(), v.end()\ntemplate <class T>\nusing V = vector<T>;\n\ntemplate <class T>\nbool chmax(T& a, T b) {\n\treturn a < b ? a = b, 1 : 0;\n}\ntemplate <class T>\nbool chmin(T& a, T b) {\n\treturn a > b ? a = b, 1 : 0;\n}\n\nusing R = long double;\nconstexpr R eps = 1e-8;\nconst R pi(acosl(-1));\nusing pt = complex<R>;\n\nusing seg = pair<pt, pt>;\n\nR dot(pt a, pt b) { return a.real() * b.real() + a.imag() * b.imag(); }\n\nR cross(pt a, pt b) { return a.real() * b.imag() - a.imag() * b.real(); }\n\npt projection(seg s, pt p) { return s.first + (s.first - s.second) * dot(p - s.first, s.first - s.second) / norm(s.first - s.second); }\n\nR distance(pt a, pt b) { return abs(a - b); }\n\nenum {\n\tcounter_clockwize = 1,\n\tclockwize = -1,\n\ton_segment = 0,\n\tonline_front = -2,\n\tonline_back = 2,\n};\nint ccw(pt a, pt b, pt c) {\n\tb -= a;\n\tc -= a;\n\tR crs = cross(b, c);\n\n\tif(crs > eps) return counter_clockwize;\n\tif(crs < -eps) return clockwize;\n\tif(dot(b, c) < -eps) return online_back;\n\tif(norm(b) + eps < norm(c)) return online_front;\n\treturn on_segment;\n}\n\nint intersect(seg s, pt p) { return ccw(s.first, s.second, p) == on_segment; }\n\nR distance(pt p, seg s) {\n\tpt r = projection(s, p);\n\treturn intersect(s, r) ? distance(r, p) : std::min(distance(s.first, p), distance(s.second, p));\n}\n\nR distance(seg s, pt p) { return distance(p, s); }\n\nstruct line {\n\tpt a, b;\n\tline(pt x, pt y) : a(x), b(y) {}\n};\n\nnamespace std {\nbool operator<(pt a, pt b) { return a.real() < b.real() || (a.real() == b.real() && a.imag() < b.imag()); }\n} // namespace std\n\nint intersect(line ln, pt p) { return ccw(ln.a, ln.b, p) % 2 == 0; }\n\nint intersect(seg s, seg t) {\n\tif(intersect(line(s.first, s.second), t.first) && intersect(line(s.first, s.second), t.second)) {\n\t\tif(std::max(std::min(s.first, s.second), std::min(t.first, t.second)) <\n\t\t std::min(std::max(s.first, s.second), std::max(t.first, t.second)))\n\t\t\treturn -1;\n\t}\n\treturn int(ccw(s.first, s.second, t.first) * ccw(s.first, s.second, t.second) <= 0 &&\n\t\t\t ccw(t.first, t.second, s.first) * ccw(t.first, t.second, s.second) <= 0);\n}\n\nR distance(seg s, seg b) {\n\tif(intersect(s, b)) return R(0);\n\treturn std::min({\n\t\tdistance(s, b.first),\n\t\tdistance(s, b.second),\n\t\tdistance(b, s.first),\n\t\tdistance(b, s.second),\n\t});\n}\n\npt input_pt() {\n\tR x, y;\n\tcin >> x >> y;\n\treturn pt(x, y);\n}\n\nint n;\nvoid solve() {\n\tpt s = input_pt();\n\tpt g = input_pt();\n\tseg ball_seg(s, g);\n\n\tR ans = 1e10;\n\n\tauto upd = [&](R val) { return chmin(ans, val); };\n\n\tauto rad_max = [&](R minx, R maxx, R miny, R maxy, R height) -> void {\n\t\tauto inside = [&](pt p) { return (minx <= p.real()) && p.real() <= maxx && miny <= p.imag() && p.imag() <= maxy; };\n\t\tif(inside(g) || inside(s)) {\n\t\t\tupd(0);\n\t\t\treturn;\n\t\t}\n\n\t\tvector<pt> pts = {\n\t\t\tpt(minx, maxy),\n\t\t\tpt(maxx, maxy),\n\t\t\tpt(maxx, miny),\n\t\t\tpt(minx, miny),\n\t\t};\n\n\t\trep(i, sz(pts)) {\n\t\t\tpt p = pts[i];\n\t\t\tint j = i + 1;\n\t\t\tif(j == sz(pts)) j = 0;\n\t\t\tpt r = pts[j];\n\n\t\t\tR d = distance(seg(p, r), ball_seg);\n\n\t\t\tif(height >= d)\n\t\t\t\tupd(d);\n\t\t\telse {\n\t\t\t\tR radius = powl(height, 2) + powl(d, 2);\n\t\t\t\tradius /= 2 * height;\n\t\t\t\tupd(radius);\n\t\t\t}\n\t\t}\n\t\treturn;\n\t};\n\n\trep(j, n) {\n\t\tR minx, miny, maxx, maxy;\n\t\tR h;\n\t\tcin >> minx >> miny >> maxx >> maxy >> h;\n\t\trad_max(minx, maxx, miny, maxy, h);\n\t}\n\n\tcout << ans << endl;\n}\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\tcout << fixed << setprecision(15);\n\t// srand((unsigned)time(NULL));\n\twhile(cin >> n && n) solve();\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3596, "score_of_the_acc": -0.5373, "final_rank": 8 }, { "submission_id": "aoj_1157_8012615", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\n//---------------------------- テンプレゾーン --------------------------------//\n\nconst long long INF = 1000000010;\nconst long long INFL = 1000000000000000010;\nconst double MYPI = 3.14159265358979;\nconst double epsilon = 1e-10;\n\n\n\ntypedef long long ll;\ntypedef __int128_t lll;\ntypedef unsigned int uint;\ntypedef unsigned long long ull;\ntypedef long double ld;\ntypedef pair<ll, ll> pl;\ntypedef vector<ll> vl;\ntypedef vector<vl> vvl;\ntypedef vector<vvl> vvvl;\ntypedef vector<double> vd;\ntypedef vector<vd> vvd;\ntypedef vector<vvd> vvvd;\ntypedef vector<bool> vb;\ntypedef vector<vb> vvb;\ntypedef vector<vvb> vvvb;\ntypedef vector<char> vc;\ntypedef vector<vc> vvc;\ntypedef vector<vvc> vvvc;\ntypedef vector<pl> vp;\ntypedef tuple<ll, ll, ll> tt;\ntypedef vector<tuple<ll, ll, ll>> vt;\ntypedef vector<string> vs;\n\n#define overload3(a, b, c, d, ...) d\n#define overload4(a, b, c, d, e, ...) e\n#define overload5(a, b, c, d, e, f, ...) f\n#define overload6(a, b, c, d, e, f, g, ...) g\n#define pb push_back\n#define eb emplace_back\n#define MP make_pair\n#define REP_0(n) for(int _=0;_<(n);_++)\n#define REP_1(i, n) for(int i=0;i<(n);i++)\n#define REP_2(i, l, r) for(int i=(l);i<(r);i++)\n#define REP_3(i, l, r, d) for(int i=(l);i<(r);i+=(d))\n#define REP(...) overload4(__VA_ARGS__, REP_3, REP_2, REP_1, REP_0)(__VA_ARGS__)\n#define REPP(i, n) for(int i=1;i<=(n);i++)\n#define RREP_1(i, n) for(int i=(n)-1;i>=0;i--)\n#define RREP_2(i, l, r) for(int i=(r)-1;i>=(l);i--)\n#define RREP_3(i, l, r, d) for(int i=(r)-1;i>=(l);i-=(d))\n#define RREP(...) overload4(__VA_ARGS__, RREP_3, RREP_2, RREP_1)(__VA_ARGS__)\n#define RREPP(i, n) for(int i=(n);i>0;i--)\n#define EACH1(e, a) for(auto &e : a)\n#define EACH2(x, y, a) for(auto &[x, y] : a)\n#define EACH3(x, y, z, a) for(auto &[x, y, z] : a)\n#define EACH(...) overload4(__VA_ARGS__, EACH3, EACH2, EACH1)(__VA_ARGS__)\n#define ALL1(x) begin(x), end(x)\n#define ALL2(x, a) begin(x), begin(x) + a\n#define ALL3(x, a, b) begin(x) + a, begin(x) + b\n#define ALL(...) overload3(__VA_ARGS__, ALL3, ALL2, ALL1)(__VA_ARGS__)\n#define RALL1(i) (i).rbegin(), (i).rend()\n#define RALL2(i, a) (i).rend() - a, (i).rend()\n#define RALL3(i, a, b) (i).rend() - b, (i).rend() - a\n#define RALL(...) overload3(__VA_ARGS__, RALL3, RALL2, RALL1)(__VA_ARGS__)\n#define sz(x) (long long)x.size()\n#define LB(a, x) (lower_bound(a.begin(), a.end(), x) - a.begin())\n#define UB(a, x) (upper_bound(a.begin(), a.end(), x) - a.begin())\n#define FLG(x, i) (((x)>>(i)) & 1)\n#define CNTBIT(x) __builtin_popcountll(x)\n#define TOPBIT(t) (t == 0 ? -1 : 63 - __builtin_clzll(t))\n#define BTMBIT(t) (t == 0 ? 64 : __builtin_ctzll(t))\n#define IN(x, a, b) ((a) <= (x) && (x) < (b))\n#define INT(...) int __VA_ARGS__; input(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define CHAR(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define DBL(...) double __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) long double __VA_ARGS__; input(__VA_ARGS__)\n#define VL1(a, n) vector<long long> a(n); for(int I=0;I<(n);I++)cin >> a[I]\n#define VL2(a, b, n) vector<long long> a(n), b(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I]\n#define VL3(a, b, c, n) vector<long long> a(n), b(n), c(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I]\n#define VL4(a, b, c, d, n) vector<long long> a(n), b(n), c(n), d(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I] >> d[I]\n#define VL5(a, b, c, d, e, n) vector<long long> a(n), b(n), c(n), d(n), e(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I] >> d[I] >> e[I]\n#define VL(...) overload6(__VA_ARGS__, VL5, VL4, VL3, VL2, VL1)(__VA_ARGS__)\n#define VD1(a, n) vector<double> a(n); for(int I=0;I<(n);I++)cin >> a[I]\n#define VD2(a, b, n) vector<double> a(n), b(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I]\n#define VD3(a, b, c, n) vector<double> a(n), b(n), c(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I]\n#define VD4(a, b, c, d, n) vector<double> a(n), b(n), c(n), d(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I] >> d[I]\n#define VD5(a, b, c, d, e, n) vector<double> a(n), b(n), c(n), d(n), e(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I] >> d[I] >> e[I]\n#define VD(...) overload6(__VA_ARGS__, VD5, VD4, VD3, VD2, VD1)(__VA_ARGS__)\n#define VVL(a, n, m) vector<vector<long long> > a(n, vector<long long>(m)); for(int I=0;I<(n);I++)for(int J=0;J<(m);J++)cin >> a[I][J]\n#define VVC(s, n, m) vector<vector<char> > s(n, vector<char>(m)); for(int I=0;I<(n);I++)for(int J=0;J<(m);J++)cin >> s[I][J]\n#define VS(s, n) vector<string> s(n); for(int I=0;I<(n);I++)cin >> s[I];\n\ntemplate <typename T1, typename T2>\nostream &operator<<(ostream &os, const pair<T1, T2> &a){\n return os << a.first << \" \" << a.second;\n}\ntemplate <typename T1, typename T2, typename T3>\nostream &operator<<(ostream &os, const tuple<T1, T2, T3> &a){\n return os << get<0>(a) << \" \" << get<1>(a) << \" \" << get<2>(a);\n}\n\nstruct IoSetup{\n IoSetup() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n cout << fixed << setprecision(15);\n }\n} iosetup;\n\n#ifdef LOCAL\n# include <debug_print.hpp>\n# define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__)\n#else\n# define debug(...) (static_cast<void>(0))\n#endif\n\ntemplate <typename T>\nusing minheap = priority_queue<T, vector<T>, greater<T>>;\n \ntemplate <typename T>\nusing maxheap = priority_queue<T>;\n\ntemplate<class... T>\nvoid input(T&... a){\n (cin >> ... >> a);\n}\n\ntemplate <typename... T>\nconstexpr auto min(T... a){\n return min(initializer_list<common_type_t<T...>>{a...});\n}\ntemplate <typename... T>\nconstexpr auto max(T... a){\n return max(initializer_list<common_type_t<T...>>{a...});\n}\n\ntemplate <typename T1, typename T2>\nbool chmax(T1 &x, const T2 &y){\n return x < y ? x = y, true : false;\n}\ntemplate <typename T1, typename T2>\nbool chmin(T1 &x, const T2 &y){\n return x > y ? x = y, true : false;\n}\n\nvoid OUT(){cout << \"\\n\";}\n\ntemplate <typename T, typename... Ts>\nvoid OUT(const T &a, const Ts&... b){\n cout << a;\n (cout << ... << (cout << \" \", b));\n cout << \"\\n\";\n}\n\ntemplate <typename T>\nvoid OUT(const vector<T> &res){\n for(int i=0;i<(int)res.size();i++){\n cout << res[i] << \" \";\n }\n cout << \"\\n\";\n}\n\ntemplate <typename T>\nvoid OUT_(const T &a){\n cout << a << \" \";\n}\n\ntemplate <typename T>\nvoid OUTN(const vector<T> &res, long long margin = 0){\n for(int i=0;i<(int)res.size();i++){\n cout << res[i] + (T)margin << \"\\n\";\n }\n}\n\ntemplate <typename T>\nvoid OUTN_(const vector<T> &res, long long margin = 0){\n for(int i=0;i<(int)res.size();i++){\n cout << res[i] + (T)margin << \" \";\n }\n cout << \"\\n\";\n}\n\ntemplate <typename T>\nvoid OUTNN(const vector<vector<T>> &res, long long margin = 0){\n for(int i=0;i<(int)res.size();i++){\n for(int j=0;j<(int)res[i].size();j++){\n cout << res[i][j] + (T)margin << \" \";\n }\n cout << \"\\n\";\n }\n}\n\nvoid YES(const bool &res = true, bool Capital = false){\n if(Capital) cout << (res ? \"YES\" : \"NO\") << \"\\n\";\n else cout << (res ? \"Yes\" : \"No\") << \"\\n\";\n}\n\nvoid FIRST(const bool &res = true, bool Capital = false){\n if(Capital) cout << (res ? \"FIRST\" : \"SECOND\") << \"\\n\";\n else cout << (res ? \"First\" : \"Second\") << \"\\n\";\n}\n\ntemplate <typename T>\nvoid DEC(vector<T> &a, long long dif = 1){\n for(auto &x : a)x -= (T)dif;\n}\ntemplate <typename T>\nvoid DEC(vector<T> &a, vector<T> &b, long long dif = 1){\n for(auto &x : a)x -= (T)dif;\n for(auto &x : b)x -= (T)dif;\n}\ntemplate <typename T>\nvoid DEC(vector<vector<T>> &a, long long dif = 1){\n for(auto &v : a)for(auto &x : v)x -= (T)dif;\n}\n\ntemplate <typename T>\nvoid INC(vector<T> &a, long long dif = 1){\n for(auto &x : a)x += (T)dif;\n}\ntemplate <typename T>\nvoid INC(vector<T> &a, vector<T> &b, long long dif = 1){\n for(auto &x : a)x += (T)dif;\n for(auto &x : b)x += (T)dif;\n}\ntemplate <typename T>\nvoid INC(vector<vector<T>> &a, long long dif = 1){\n for(auto &v : a)for(auto &x : v)x += (T)dif;\n}\n\ntemplate <typename T>\nT SUM(const vector<T> &a){\n return accumulate(a.begin(), a.end(), (T)0);\n}\ntemplate <typename T>\nT SUM(const vector<vector<T>> &a){\n T ret = 0;\n for(int i=0;i<(int)a.size();i++)ret += accumulate(a[i].begin(), a[i].end(), (T)0);\n return ret;\n}\n\ntemplate <typename T>\nT MAX(const vector<T> &a){\n return *max_element(a.begin(), a.end());\n}\ntemplate <typename T>\nT MAX(const vector<vector<T>> &a){\n T ret = -INFL;\n for(int i=0;i<(int)a.size();i++)for(int j=0;j<(int)a[i].size();j++)if(ret < a[i][j])ret = a[i][j];\n return ret;\n}\n\ntemplate <typename T>\nint ARGMAX(const vector<T> &a){\n int ret = 0;\n for(int i=1;i<(int)a.size();i++)if(a[ret] < a[i])ret = i;\n return ret;\n}\ntemplate <typename T>\npair<int, int> ARGMAX(const vector<vector<T>> &a){\n pair<int, int> ret = {0, 0};\n for(int i=0;i<(int)a.size();i++)for(int j=0;j<(int)a[i].size();j++)if(a[ret.first][ret.second] < a[i][j])ret = {i, j};\n return ret;\n}\n\ntemplate <typename T>\nT MIN(const vector<T> &a){\n return *min_element(a.begin(), a.end());\n}\ntemplate <typename T>\nT MIN(const vector<vector<T>> &a){\n T ret = INFL;\n for(int i=0;i<(int)a.size();i++)for(int j=0;j<(int)a[i].size();j++)if(ret > a[i][j])ret = a[i][j];\n return ret;\n}\n\ntemplate <typename T>\nint ARGMIN(const vector<T> &a){\n int ret = 0;\n for(int i=1;i<(int)a.size();i++)if(a[ret] > a[i])ret = i;\n return ret;\n}\ntemplate <typename T>\npair<int, int> ARGMIN(const vector<vector<T>> &a){\n pair<int, int> ret = {0, 0};\n for(int i=0;i<(int)a.size();i++)for(int j=0;j<(int)a[i].size();j++)if(a[ret.first][ret.second] > a[i][j])ret = {i, j};\n return ret;\n}\n\ntemplate <typename T>\nint SIGN(const T &a){\n if(abs(a) < epsilon)return 0;\n return a > 0 ? 1 : -1;\n}\n\ntemplate <typename T>\nvector<T> UNIQ(vector<T> a){\n sort(a.begin(), a.end());\n a.erase(unique(a.begin(), a.end()), a.end());\n return a;\n}\n\ntemplate <typename T>\nvector<T> sorted(vector<T> a, bool Descending = false){\n sort(a.begin(), a.end());\n if(Descending)reverse(a.begin(), a.end());\n return a;\n}\n\ntemplate <typename T>\nvector<T> cumsum(const vector<T> &a){\n int n = (int)a.size();\n vector<T> ret(n+1, (T)0);\n for(int i=0;i<n;i++)ret[i+1] = ret[i] + a[i];\n return ret;\n}\ntemplate <typename T>\nvector<vector<T>> cumsum(const vector<vector<T>> &a){\n int n = (int)a.size(), m = (int)a[0].size();\n vector<vector<T>> ret(n+1, vector<T>(m+1, (T)0));\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)ret[i+1][j+1] = ret[i+1][j] + a[i][j];\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)ret[i+1][j+1] += ret[i][j+1];\n return ret;\n}\ntemplate <typename T>\nvector<vector<vector<T>>> cumsum(const vector<vector<vector<T>>> &a){\n int n = (int)a.size(), m = (int)a[0].size(), l = (int)a[0][0].size();\n vector<vector<vector<T>>> ret(n+1, vector<vector<T>>(m+1, vector<T>(l+1, (T)0)));\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)for(int k=0;k<l;k++)ret[i+1][j+1][k+1] = ret[i+1][j+1][k] + a[i][j][k];\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)for(int k=0;k<l;k++)ret[i+1][j+1][k+1] += ret[i][j+1][k+1];\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)for(int k=0;k<l;k++)ret[i+1][j+1][k+1] += ret[i+1][j][k+1];\n return ret;\n}\ntemplate <typename T>\nvoid cumsum_inplace(vector<T> &a){\n int n = (int)a.size();\n for(int i=0;i<n-1;i++)a[i+1] += a[i];\n}\ntemplate <typename T>\nvoid cumsum_inplace(vector<vector<T>> &a){\n int n = (int)a.size(), m = (int)a[0].size();\n for(int i=0;i<n-1;i++)for(int j=0;j<m;j++)a[i+1][j] += a[i][j];\n for(int i=0;i<n;i++)for(int j=0;j<m-1;j++)a[i][j+1] += a[i][j];\n}\ntemplate <typename T>\nvoid cumsum_inplace(vector<vector<vector<T>>> &a){\n int n = (int)a.size(), m = (int)a[0].size(), l = (int)a[0][0].size();\n for(int i=0;i<n-1;i++)for(int j=0;j<m;j++)for(int k=0;k<l;k++)a[i+1][j][k] += a[i][j][k];\n for(int i=0;i<n;i++)for(int j=0;j<m-1;j++)for(int k=0;k<l;k++)a[i][j+1][k] += a[i][j][k];\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)for(int k=0;k<l-1;k++)a[i][j][k+1] += a[i][j][k];\n}\n\ntemplate< typename T = long long >\nstruct Edge {\n long long from, to;\n T cost;\n long long idx;\n Edge() = default;\n Edge(long long from, long long to, T cost = 1, long long idx = -1) : from(from), to(to), cost(cost), idx(idx) {}\n operator int() const { return to; }\n};\n\ntemplate< typename T = long long >\nstruct Graph {\n vector< vector< Edge< T > > > g, ginv;\n vector<int> indeg, outdeg;\n long long es;\n Graph() = default;\n explicit Graph(long long n) : g(n), ginv(n), indeg(n, 0), outdeg(n, 0), es(0) {}\n size_t size() const {\n return g.size();\n }\n void add_directed_edge(long long from, long long to, T cost = 1) {\n indeg[to]++, outdeg[from]++;\n //ginv[to].emplace_back(to, from, cost, es);\n g[from].emplace_back(from, to, cost, es++);\n }\n void add_edge(long long from, long long to, T cost = 1) {\n indeg[from]++, outdeg[from]++, indeg[to]++, outdeg[to]++;\n g[from].emplace_back(from, to, cost, es);\n g[to].emplace_back(to, from, cost, es++);\n }\n inline vector< Edge< T > > &operator[](const int &k) {\n return g[k];\n }\n inline const vector< Edge< T > > &operator[](const int &k) const {\n return g[k];\n }\n};\n\ntemplate< typename T = long long >\nusing Edges = vector< Edge< T > >;\n\ntemplate< typename T >\nstruct Enumeration {\nprivate:\n static vector< T > _fact, _finv, _inv;\n inline static void expand(size_t sz) {\n if(_fact.size() < sz + 1) {\n int pre_sz = max(1, (int) _fact.size());\n _fact.resize(sz + 1, T(1));\n _finv.resize(sz + 1, T(1));\n _inv.resize(sz + 1, T(1));\n for(int i = pre_sz; i <= (int) sz; i++) {\n _fact[i] = _fact[i - 1] * T(i);\n }\n _finv[sz] = T(1) / _fact[sz];\n for(int i = (int) sz - 1; i >= pre_sz; i--) {\n _finv[i] = _finv[i + 1] * T(i + 1);\n }\n for(int i = pre_sz; i <= (int) sz; i++) {\n _inv[i] = _finv[i] * _fact[i - 1];\n }\n }\n }\npublic:\n explicit Enumeration(size_t sz = 0) { expand(sz); }\n static inline T fact(int k) {\n expand(k);\n return _fact[k];\n }\n static inline T finv(int k) {\n expand(k);\n return _finv[k];\n }\n static inline T inv(int k) {\n expand(k);\n return _inv[k];\n }\n static T P(int n, int r) {\n if(r < 0 || n < r) return 0;\n return fact(n) * finv(n - r);\n }\n static T C(int p, int q) {\n if(q < 0 || p < q) return 0;\n return fact(p) * finv(q) * finv(p - q);\n }\n};\n\ntemplate< typename T >\nvector< T > Enumeration< T >::_fact = vector< T >();\ntemplate< typename T >\nvector< T > Enumeration< T >::_finv = vector< T >();\ntemplate< typename T >\nvector< T > Enumeration< T >::_inv = vector< T >();\n\ntemplate <typename T>\nT norm1(const pair<T, T> &a, const pair<T, T> &b = {(T)0, (T)0}){\n return abs(a.first - b.first) + abs(a.second - b.second);\n}\ntemplate <typename T>\nT norm22(const pair<T, T> &a, const pair<T, T> &b = {(T)0, (T)0}){\n return (a.first - b.first) * (a.first - b.first) + (a.second - b.second) * (a.second - b.second);\n}\ntemplate <typename T>\ndouble norm2(const pair<T, T> &a, const pair<T, T> &b = {(T)0, (T)0}){\n return sqrt(norm22(a, b));\n}\n\nlong long powll(long long a, long long n){\n assert(n >= 0);\n if(n == 0)return 1;\n long long ret = 1;\n while(n){\n if(n & 1)ret *= a;\n a *= a;\n n >>= 1;\n }\n return ret;\n}\n\nvector<long long> str_to_vl(const string &s){\n vector<long long> ret(s.size());\n if(s.size() == 0)return ret;\n if(0 <= s[0]-'A' && s[0]-'A' < 26) for(int i=0;i<(int)s.size();i++) ret[i] = s[i] - 'A';\n else if(0 <= s[0]-'a' && s[0]-'a' < 26) for(int i=0;i<(int)s.size();i++) ret[i] = s[i] - 'a';\n else if(0 <= s[0]-'0' && s[0]-'0' < 10) for(int i=0;i<(int)s.size();i++) ret[i] = s[i] - '0';\n else assert(0);\n return ret;\n}\n\n// 0-indexed\nlong long TOPDIGIT(long long x){\n assert(x >= 0);\n long long ret = 0;\n while(x >= 10){x /= 10; ret++;}\n return ret;\n}\n\ntemplate <typename T>\nvector<pair<T, int>> sorti(const vector<T> &a){\n vector<pair<T, int>> ret(a.size());\n for(int i=0;i<(int)a.size();i++){\n ret[i] = {a[i], i};\n }\n sort(ret.begin(), ret.end());\n return ret;\n}\ntemplate <typename T1, typename T2>\nvector<tuple<T1, T2, int>> sorti(const vector<T1> &a, const vector<T2> &b){\n assert(a.size() == b.size());\n vector<tuple<T1, T2, int>> ret(a.size());\n for(int i=0;i<(int)a.size();i++){\n ret[i] = {a[i], b[i], i};\n }\n sort(ret.begin(), ret.end());\n return ret;\n}\ntemplate <typename T1, typename T2, typename T3>\nvector<tuple<T1, T2, T3, int>> sorti(const vector<T1> &a, const vector<T2> &b, const vector<T3> &c){\n assert(a.size() == b.size() && a.size() == c.size());\n vector<tuple<T1, T2, T3, int>> ret(a.size());\n for(int i=0;i<(int)a.size();i++){\n ret[i] = {a[i], b[i], c[i], i};\n }\n sort(ret.begin(), ret.end());\n return ret;\n}\n\n// 高々小数第 k 位までの実数を 10^k 倍して整数化\nll decimal_to_ll(const string &s, int k){\n int n = s.size();\n for(int i=0;i<n;i++){\n if(s[i] == '.'){\n ll ret = stoll(s.substr(0, i) + s.substr(i + 1));\n for(int j=0;j<k-(n-1-i);j++)ret *= 10;\n return ret;\n }\n }\n ll ret = stoll(s);\n for(int i=0;i<k;i++)ret *= 10;\n return ret;\n}\n\nlong long max(const int &a, const long long &b){return max((long long)a, b);}\nlong long min(const int &a, const long long &b){return min((long long)a, b);}\n\nconst vector<long long> dy = {1, 0, -1, 0, 1, -1, -1, 1};\nconst vector<long long> dx = {0, 1, 0, -1, 1, 1, -1, -1};\n\nrandom_device seed_gen;\nmt19937_64 rnd;\n\n// [low, high] の範囲の値を持つ長さ len のランダムベクトルを生成\nvector<long long> random_vl(int len, long long low, long long high){\n uniform_int_distribution<long long> dist(low, high);\n vector<long long> ret(len);\n for(int i=0;i<len;i++)ret[i] = dist(rnd);\n return ret;\n};\n\nvector<long long> random_permutation(int len){\n uniform_int_distribution<int> dist(1, len);\n vector<long long> ret(len);\n set<int> se;\n for(int i=0;i<len;i++){\n int tmp = dist(rnd);\n while(se.count(tmp))tmp = dist(rnd);\n ret[i] = tmp;\n se.insert(ret[i]);\n }\n return ret;\n};\n\n//--------------------------- テンプレゾーン終 -------------------------------//\n\n//----------------------------- コピペゾーン ---------------------------------//\n\n/*\nmemo\n\nabs(Point): Point の絶対値\nnorm(Point): Point の絶対値の二乗\nEXTERNAL: 0, ON: 1, INTERNAL: 2\nピックの定理: 多角形の面積を S, 辺上の格子点数を b, 内部の格子点数を i とすると、S = i +\nb/2 - 1 が成立\n*/\n\nusing Real = ld;\nusing Point = complex<Real>;\nconst Real EPS = 1e-10, PI = acos(-1);\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_C\nenum { EXTERNAL, ON, INTERNAL };\n\ninline bool eq(Real a, Real b) { return fabs(b - a) < EPS; }\n\nPoint operator*(const Point &p, const Real &d) {\n return Point(real(p) * d, imag(p) * d);\n}\n\n// rotate point p counterclockwise by theta rad\nPoint rotate(Real theta, const Point &p) {\n return Point(cos(theta) * p.real() - sin(theta) * p.imag(),\n sin(theta) * p.real() + cos(theta) * p.imag());\n}\n\nReal radian_to_degree(Real r) { return (r * 180.0 / PI); }\n\nReal degree_to_radian(Real d) { return (d * PI / 180.0); }\n\n// 修正済み\n// smaller angle of the a-b-c\nReal get_angle(const Point &a, const Point &b, const Point &c) {\n const Point v(a - b), w(c - b);\n Real alpha = atan2(v.imag(), v.real()), beta = atan2(w.imag(), w.real());\n if (alpha > beta) swap(alpha, beta);\n Real theta = (beta - alpha);\n return min(theta, 2 * acos(-1) - theta);\n}\n\nnamespace std {\nbool operator<(const Point &a, const Point &b) {\n return a.real() != b.real() ? a.real() < b.real() : a.imag() < b.imag();\n}\n} // namespace std\n\nstruct Line {\n Point a, b;\n\n Line() = default;\n\n Line(Point a, Point b) : a(a), b(b) {}\n\n Line(Real A, Real B, Real C) // Ax + By = C\n {\n if (eq(A, 0))\n a = Point(0, C / B), b = Point(1, C / B);\n else if (eq(B, 0))\n a = Point(C / A, 0), b = Point(C / A, 1);\n else\n a = Point(0, C / B), b = Point(C / A, 0);\n }\n\n friend ostream &operator<<(ostream &os, Line &p) {\n return os << p.a << \" to \" << p.b;\n }\n\n friend istream &operator>>(istream &is, Line &a) { return is >> a.a >> a.b; }\n};\n\nstruct Segment : Line {\n Segment() = default;\n\n Segment(Point a, Point b) : Line(a, b) {}\n};\n\nstruct Circle {\n Point p;\n Real r;\n\n Circle() = default;\n\n Circle(Point p, Real r) : p(p), r(r) {}\n // 追加 線分 p-q を直径とする円\n Circle(Point p, Point q) : p((p + q) / 2.0L), r(abs(p - (p + q) / 2.0L)) {}\n};\n\nusing Points = vector<Point>;\nusing Polygon = vector<Point>;\nusing Segments = vector<Segment>;\nusing Lines = vector<Line>;\nusing Circles = vector<Circle>;\n\nReal cross(const Point &a, const Point &b) {\n return real(a) * imag(b) - imag(a) * real(b);\n}\n\nReal dot(const Point &a, const Point &b) {\n return real(a) * real(b) + imag(a) * imag(b);\n}\n\n// 線分 a-b に対して c がどの位置にいるか\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_C\nint ccw(const Point &a, Point b, Point c) {\n b = b - a, c = c - a;\n if (cross(b, c) > EPS) return +1; // \"COUNTER_CLOCKWISE\"\n if (cross(b, c) < -EPS) return -1; // \"CLOCKWISE\"\n if (dot(b, c) < 0) return +2; // \"ONLINE_BACK\" c-a-b\n if (norm(b) < norm(c)) return -2; // \"ONLINE_FRONT\" a-b-c\n return 0; // \"ON_SEGMENT\" a-c-b\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_A\nbool parallel(const Line &a, const Line &b) {\n return eq(cross(a.b - a.a, b.b - b.a), 0.0);\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_A\nbool orthogonal(const Line &a, const Line &b) {\n return eq(dot(a.a - a.b, b.a - b.b), 0.0);\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_A\nPoint projection(const Line &l, const Point &p) {\n double t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\n\nPoint projection(const Segment &l, const Point &p) {\n double t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_B\nPoint reflection(const Line &l, const Point &p) {\n return p + (projection(l, p) - p) * 2.0;\n}\n\nbool intersect(const Line &l, const Point &p) { return abs(ccw(l.a, l.b, p)) != 1; }\n\nbool intersect(const Line &l, const Line &m) {\n return abs(cross(l.b - l.a, m.b - m.a)) > EPS ||\n abs(cross(l.b - l.a, m.b - l.a)) < EPS;\n}\n\nbool intersect(const Segment &s, const Point &p) { return ccw(s.a, s.b, p) == 0; }\n\nbool intersect(const Line &l, const Segment &s) {\n return cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < EPS;\n}\n\nReal distance(const Line &l, const Point &p);\n\nbool intersect(const Circle &c, const Line &l) { return distance(l, c.p) <= c.r + EPS; }\n\nbool intersect(const Circle &c, const Point &p) {\n return abs(abs(p - c.p) - c.r) < EPS;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_B\nbool intersect(const Segment &s, const Segment &t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\nint intersect(const Circle &c, const Segment &l) {\n if (norm(projection(l, c.p) - c.p) - c.r * c.r > EPS) return 0;\n auto d1 = abs(c.p - l.a), d2 = abs(c.p - l.b);\n if (d1 < c.r + EPS && d2 < c.r + EPS) return 0;\n if (d1 < c.r - EPS && d2 > c.r + EPS || d1 > c.r + EPS && d2 < c.r - EPS) return 1;\n const Point h = projection(l, c.p);\n if (dot(l.a - h, l.b - h) < 0) return 2;\n return 0;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_A&lang=jp\nint intersect(Circle c1, Circle c2) {\n if (c1.r < c2.r) swap(c1, c2);\n Real d = abs(c1.p - c2.p);\n if (c1.r + c2.r < d) return 4;\n if (eq(c1.r + c2.r, d)) return 3;\n if (c1.r - c2.r < d) return 2;\n if (eq(c1.r - c2.r, d)) return 1;\n return 0;\n}\n\nReal distance(const Point &a, const Point &b) { return abs(a - b); }\n\nReal distance(const Line &l, const Point &p) { return abs(p - projection(l, p)); }\n\nReal distance(const Line &l, const Line &m) {\n return intersect(l, m) ? 0 : distance(l, m.a);\n}\n\nReal distance(const Segment &s, const Point &p) {\n Point r = projection(s, p);\n if (intersect(s, r)) return abs(r - p);\n return min(abs(s.a - p), abs(s.b - p));\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_D\nReal distance(const Segment &a, const Segment &b) {\n if (intersect(a, b)) return 0;\n return min(\n {distance(a, b.a), distance(a, b.b), distance(b, a.a), distance(b, a.b)});\n}\n\nReal distance(const Line &l, const Segment &s) {\n if (intersect(l, s)) return 0;\n return min(distance(l, s.a), distance(l, s.b));\n}\n\n// Verified at https://atcoder.jp/contests/abc151/tasks/abc151_f\nPoint crosspoint(const Line &l, const Line &m) {\n Real A = cross(l.b - l.a, m.b - m.a);\n Real B = cross(l.b - l.a, l.b - m.a);\n if (eq(abs(A), 0.0) && eq(abs(B), 0.0)) return m.a;\n return m.a + (m.b - m.a) * B / A;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_C\nPoint crosspoint(const Segment &l, const Segment &m) {\n return crosspoint(Line(l), Line(m));\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_D\npair<Point, Point> crosspoint(const Circle &c, const Line l) {\n Point pr = projection(l, c.p);\n Point e = (l.b - l.a) / abs(l.b - l.a);\n if (eq(distance(l, c.p), c.r)) return {pr, pr};\n double base = sqrt(c.r * c.r - norm(pr - c.p));\n return {pr - e * base, pr + e * base};\n}\n\npair<Point, Point> crosspoint(const Circle &c, const Segment &l) {\n Line aa = Line(l.a, l.b);\n if (intersect(c, l) == 2) return crosspoint(c, aa);\n auto ret = crosspoint(c, aa);\n if (dot(l.a - ret.first, l.b - ret.first) < 0)\n ret.second = ret.first;\n else\n ret.first = ret.second;\n return ret;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_E\npair<Point, Point> crosspoint(const Circle &c1, const Circle &c2) {\n Real d = abs(c1.p - c2.p);\n Real a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d));\n Real t = atan2(c2.p.imag() - c1.p.imag(), c2.p.real() - c1.p.real());\n Point p1 = c1.p + Point(cos(t + a) * c1.r, sin(t + a) * c1.r);\n Point p2 = c1.p + Point(cos(t - a) * c1.r, sin(t - a) * c1.r);\n return {p1, p2};\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_F\n// tangent of circle c through point p\npair<Point, Point> tangent(const Circle &c1, const Point &p2) {\n return crosspoint(c1, Circle(p2, sqrt(norm(c1.p - p2) - c1.r * c1.r)));\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_G\n// common tangent of circles c1 and c2\nLines tangent(Circle c1, Circle c2) {\n Lines ret;\n if (c1.r < c2.r) swap(c1, c2);\n Real g = norm(c1.p - c2.p);\n if (eq(g, 0)) return ret;\n Point u = (c2.p - c1.p) / sqrt(g);\n Point v = rotate(PI * 0.5, u);\n for (int s : {-1, 1}) {\n Real h = (c1.r + s * c2.r) / sqrt(g);\n if (eq(1 - h * h, 0)) {\n ret.emplace_back(c1.p + u * c1.r, c1.p + (u + v) * c1.r);\n } else if (1 - h * h > 0) {\n Point uu = u * h, vv = v * sqrt(1 - h * h);\n ret.emplace_back(c1.p + (uu + vv) * c1.r, c2.p - (uu + vv) * c2.r * s);\n ret.emplace_back(c1.p + (uu - vv) * c1.r, c2.p - (uu - vv) * c2.r * s);\n }\n }\n return ret;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_B\n// Verified at https://atcoder.jp/contests/typical90/tasks/typical90_ao\nbool is_convex(const Polygon &p) {\n int n = (int)p.size();\n for (int i = 0; i < n; i++) {\n if (ccw(p[(i + n - 1) % n], p[i], p[(i + 1) % n]) == -1) return false;\n }\n return true;\n}\n\n\n\n//---------------------------- コピペゾーン終 --------------------------------//\n\n/*\n#include <atcoder/all>\nusing namespace atcoder;\nusing mint1 = modint998244353;\n*/\n#define int long long\n\nvoid solve(){\n vd ans;\n while(1){\n INT(n);\n if(n == 0)break;\n INT(sx, sy, ex, ey);\n VVL(mxy, n, 5);\n bool zero = false;\n Segment seg(Point(sx, sy), Point(ex, ey));\n REP(i, n){\n if(intersect(seg, Segment(Point(mxy[i][0], mxy[i][1]), Point(mxy[i][2], mxy[i][3]))))zero = true;\n if(intersect(seg, Segment(Point(mxy[i][0], mxy[i][3]), Point(mxy[i][2], mxy[i][1]))))zero = true;\n }\n if(zero){\n ans.pb(0);\n continue;\n }\n auto is_ok = [&](double mid){\n bool ret = true;\n REP(i, n){\n REP(j, 2){\n auto dist = distance(seg, Segment(Point(mxy[i][j<<1], mxy[i][1]), Point(mxy[i][j<<1], mxy[i][3])));\n dist = sqrt(dist * dist + max(0.0, mid - mxy[i][4]) * max(0.0, mid - mxy[i][4]));\n if(dist < mid)ret = false;\n }\n REP(j, 2){\n auto dist = distance(seg, Segment(Point(mxy[i][0], mxy[i][1+(j<<1)]), Point(mxy[i][2], mxy[i][1+(j<<1)])));\n dist = sqrt(dist * dist + max(0.0, mid - mxy[i][4]) * max(0.0, mid - mxy[i][4]));\n if(dist < mid)ret = false;\n }\n }\n return ret;\n };\n double ok = 0, ng = 1000;\n while(abs(ok - ng) > epsilon){\n double mid = (ok + ng) / 2;\n if(is_ok(mid))ok = mid;\n else ng = mid;\n }\n ans.pb(ok);\n }\n OUTN(ans);\n}\n\nint solve_test(int n, vl a){\n\n return 0;\n}\n\nint solve_naive(int n, vl a){\n\n return 0;\n}\n\nvoid random_test(){\n rnd.seed(seed_gen());\n\n uniform_int_distribution<int> dist_n(4, 10), dist_m(4, 10), dist_a(1, 20), dist_b(1, 20); \n\n for(int test = 1; test <= 100; test++){\n int n = dist_n(rnd), m = dist_m(rnd);\n vl a = random_vl(n, 3, 20);\n auto Output = solve_test(n, a), Answer = solve_naive(n, a);\n if(Output != Answer){\n cout << \"Wrong Answer on Test #\" << test << '\\n';\n debug(n);\n debug(a);\n debug(Answer);\n debug(Output);\n break;\n }\n }\n}\n\nsigned main(){\n int T = 1;\n // cin >> T;\n\n while(T--) solve();\n\n // random_test();\n\n return 0;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 3692, "score_of_the_acc": -0.8424, "final_rank": 14 }, { "submission_id": "aoj_1157_7186852", "code_snippet": "//#define _GLIBCXX_DEBUG\n\n#include<bits/stdc++.h>\nusing namespace std;\n\n#define endl '\\n'\n#define lfs cout<<fixed<<setprecision(10)\n#define ALL(a) (a).begin(),(a).end()\n#define ALLR(a) (a).rbegin(),(a).rend()\n#define UNIQUE(a) (a).erase(unique((a).begin(),(a).end()),(a).end())\n#define spa << \" \" <<\n#define fi first\n#define se second\n#define MP make_pair\n#define MT make_tuple\n#define PB push_back\n#define EB emplace_back\n#define rep(i,n,m) for(ll i = (n); i < (ll)(m); i++)\n#define rrep(i,n,m) for(ll i = (ll)(m) - 1; i >= (ll)(n); i--)\nusing ll = long long;\nusing ld = long double;\nconst ll MOD1 = 1e9+7;\nconst ll MOD9 = 998244353;\nconst ll INF = 1e18;\nusing P = pair<ll, ll>;\ntemplate<typename T> using PQ = priority_queue<T>;\ntemplate<typename T> using QP = priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T1, typename T2>bool chmin(T1 &a,T2 b){if(a>b){a=b;return true;}else return false;}\ntemplate<typename T1, typename T2>bool chmax(T1 &a,T2 b){if(a<b){a=b;return true;}else return false;}\nll median(ll a,ll b, ll c){return a+b+c-max({a,b,c})-min({a,b,c});}\nvoid ans1(bool x){if(x) cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;}\nvoid ans2(bool x){if(x) cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;}\nvoid ans3(bool x){if(x) cout<<\"Yay!\"<<endl;else cout<<\":(\"<<endl;}\ntemplate<typename T1,typename T2>void ans(bool x,T1 y,T2 z){if(x)cout<<y<<endl;else cout<<z<<endl;} \ntemplate<typename T1,typename T2,typename T3>void anss(T1 x,T2 y,T3 z){ans(x!=y,x,z);}; \ntemplate<typename T>void debug(const T &v,ll h,ll w,string sv=\" \"){for(ll i=0;i<h;i++){cout<<v[i][0];for(ll j=1;j<w;j++)cout<<sv<<v[i][j];cout<<endl;}};\ntemplate<typename T>void debug(const T &v,ll n,string sv=\" \"){if(n!=0)cout<<v[0];for(ll i=1;i<n;i++)cout<<sv<<v[i];cout<<endl;};\ntemplate<typename T>void debug(const vector<T>&v){debug(v,v.size());}\ntemplate<typename T>void debug(const vector<vector<T>>&v){for(auto &vv:v)debug(vv,vv.size());}\ntemplate<typename T>void debug(stack<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(queue<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(deque<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop_front();}cout<<endl;}\ntemplate<typename T>void debug(PQ<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(QP<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(const set<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T>void debug(const multiset<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,size_t size>void debug(const array<T, size> &a){for(auto z:a)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,typename V>void debug(const map<T,V>&v){for(auto z:v)cout<<\"[\"<<z.first<<\"]=\"<<z.second<<\",\";cout<<endl;}\ntemplate<typename T>vector<vector<T>>vec(ll x, ll y, T w){vector<vector<T>>v(x,vector<T>(y,w));return v;}\nll gcd(ll x,ll y){ll r;while(y!=0&&(r=x%y)!=0){x=y;y=r;}return y==0?x:y;}\n//vector<ll>dx={1,-1,0,0,1,1,-1,-1};vector<ll>dy={0,0,1,-1,1,-1,1,-1};\ntemplate<typename T>vector<T> make_v(size_t a,T b){return vector<T>(a,b);}\ntemplate<typename... Ts>auto make_v(size_t a,Ts... ts){return vector<decltype(make_v(ts...))>(a,make_v(ts...));}\ntemplate<typename T1, typename T2>ostream &operator<<(ostream &os, const pair<T1, T2>&p){return os << p.first << \" \" << p.second;}\ntemplate<typename T>ostream &operator<<(ostream &os, const vector<T> &v){for(auto &z:v)os << z << \" \";cout<<\"|\"; return os;}\ntemplate<typename T>void rearrange(vector<int>&ord, vector<T>&v){\n auto tmp = v;\n for(int i=0;i<tmp.size();i++)v[i] = tmp[ord[i]];\n}\ntemplate<typename Head, typename... Tail>void rearrange(vector<int>&ord,Head&& head, Tail&&... tail){\n rearrange(ord, head);\n rearrange(ord, tail...);\n}\ntemplate<typename T> vector<int> ascend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return v[i]<v[j];});\n return ord;\n}\ntemplate<typename T> vector<int> descend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return v[i]>v[j];});\n return ord;\n}\ntemplate<typename T> vector<T> inv_perm(const vector<T>&ord){\n vector<T>inv(ord.size());\n for(int i=0;i<ord.size();i++)inv[ord[i]] = i;\n return inv;\n}\nll FLOOR(ll n,ll div){assert(div>0);return n>=0?n/div:(n-div+1)/div;}\nll CEIL(ll n,ll div){assert(div>0);return n>=0?(n+div-1)/div:n/div;}\nll digitsum(ll n){ll ret=0;while(n){ret+=n%10;n/=10;}return ret;}\nll modulo(ll n,ll d){return (n%d+d)%d;};\ntemplate<typename T>T min(const vector<T>&v){return *min_element(v.begin(),v.end());}\ntemplate<typename T>T max(const vector<T>&v){return *max_element(v.begin(),v.end());}\ntemplate<typename T>T acc(const vector<T>&v){return accumulate(v.begin(),v.end(),T(0));};\ntemplate<typename T>T reverse(const T &v){return T(v.rbegin(),v.rend());};\n//mt19937 mt(chrono::steady_clock::now().time_since_epoch().count());\nint popcount(ll x){return __builtin_popcountll(x);};\nint poplow(ll x){return __builtin_ctzll(x);};\nint pophigh(ll x){return 63 - __builtin_clzll(x);};\ntemplate<typename T>T poll(queue<T> &q){auto ret=q.front();q.pop();return ret;};\ntemplate<typename T>T poll(priority_queue<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(QP<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(stack<T> &s){auto ret=s.top();s.pop();return ret;};\nll MULT(ll x,ll y){if(LLONG_MAX/x<=y)return LLONG_MAX;return x*y;}\nll POW2(ll x, ll k){ll ret=1,mul=x;while(k){if(mul==LLONG_MAX)return LLONG_MAX;if(k&1)ret=MULT(ret,mul);mul=MULT(mul,mul);k>>=1;}return ret;}\nll POW(ll x, ll k){ll ret=1;for(int i=0;i<k;i++){if(LLONG_MAX/x<=ret)return LLONG_MAX;ret*=x;}return ret;}\ntemplate< typename T = int >\nstruct edge {\n int to;\n T cost;\n int id;\n edge():id(-1){};\n edge(int to, T cost = 1, int id = -1):to(to), cost(cost), id(id){}\n operator int() const { return to; }\n};\n\ntemplate<typename T>\nusing Graph = vector<vector<edge<T>>>;\ntemplate<typename T>\nGraph<T>revgraph(const Graph<T> &g){\n Graph<T>ret(g.size());\n for(int i=0;i<g.size();i++){\n for(auto e:g[i]){\n int to = e.to;\n e.to = i;\n ret[to].push_back(e);\n }\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readGraph(int n,int m,int indexed=1,bool directed=false,bool weighted=false){\n Graph<T> ret(n);\n for(int es = 0; es < m; es++){\n int u,v;\n T w=1;\n cin>>u>>v;u-=indexed,v-=indexed;\n if(weighted)cin>>w;\n ret[u].emplace_back(v,w,es);\n if(!directed)ret[v].emplace_back(u,w,es);\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readParent(int n,int indexed=1,bool directed=true){\n Graph<T>ret(n);\n for(int i=1;i<n;i++){\n int p;cin>>p;\n p-=indexed;\n ret[p].emplace_back(i);\n if(!directed)ret[i].emplace_back(p);\n }\n return ret;\n}\n\ntemplate <typename F>\nclass\n#if defined(__has_cpp_attribute) && __has_cpp_attribute(nodiscard)\n [[nodiscard]]\n#endif // defined(__has_cpp_attribute) && __has_cpp_attribute(nodiscard)\nFixPoint final : private F\n{\npublic:\n template <typename G>\n explicit constexpr FixPoint(G&& g) noexcept\n : F{std::forward<G>(g)}\n {}\n\n template <typename... Args>\n constexpr decltype(auto)\n operator()(Args&&... args) const\n#if !defined(__GNUC__) || defined(__clang__) || __GNUC__ >= 9\n noexcept(noexcept(F::operator()(std::declval<FixPoint>(), std::declval<Args>()...)))\n#endif // !defined(__GNUC__) || defined(__clang__) || __GNUC__ >= 9\n {\n return F::operator()(*this, std::forward<Args>(args)...);\n }\n}; // class FixPoint\n\n\n#if defined(__cpp_deduction_guides)\ntemplate <typename F>\nFixPoint(F&&)\n -> FixPoint<std::decay_t<F>>;\n#endif // defined(__cpp_deduction_guides)\n\n\nnamespace\n{\n template <typename F>\n#if !defined(__has_cpp_attribute) || !__has_cpp_attribute(nodiscard)\n# if defined(__GNUC__) && (__GNUC__ > 3 || __GNUC__ == 3 && __GNUC_MINOR__ >= 4)\n __attribute__((warn_unused_result))\n# elif defined(_MSC_VER) && _MSC_VER >= 1700 && defined(_Check_return_)\n _Check_return_\n# endif // defined(__GNUC__) && (__GNUC__ > 3 || __GNUC__ == 3 && __GNUC_MINOR__ >= 4)\n#endif // !defined(__has_cpp_attribute) || !__has_cpp_attribute(nodiscard)\n inline constexpr decltype(auto)\n makeFixPoint(F&& f) noexcept\n{\n return FixPoint<std::decay_t<F>>{std::forward<std::decay_t<F>>(f)};\n}\n} // namespace\n\nusing Real = long double;\nusing Point = complex<Real>;\nconst Real EPS = 1e-10, PI = acos((Real)(-1.0));\n\ninline bool eq(Real a, Real b) { return fabs(b - a) < EPS; }\ninline bool eq(Point a, Point b) { return fabs(b - a) < EPS; }\n\nPoint operator*(const Point &p, const Real &d) {\n return Point(real(p) * d, imag(p) * d);\n}\n\nistream &operator>>(istream &is, Point &p) {\n Real a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n}\n\nostream &operator<<(ostream &os, Point &p) {\n return os << fixed << setprecision(10) << p.real() << \" \" << p.imag();\n}\n\nPoint rotate(Real theta, const Point &p) {\n return Point(cos(theta) * p.real() - sin(theta) * p.imag(), sin(theta) * p.real() + cos(theta) * p.imag());\n}\n\nnamespace std {\n bool operator<(const Point& a, const Point& b) {\n return !eq(a.real(), b.real()) ? a.real() < b.real() : a.imag() < b.imag();\n }\n}\n\nstruct Line {\n Point a, b;\n Line() = default;\n Line(Point a, Point b): a(a), b(b) {}\n\n friend ostream &operator<<(ostream &os, Line &p) {\n return os << p.a << \" to \" << p.b;\n }\n\n friend istream &operator>>(istream &is, Line &a) {\n return is >> a.a >> a.b;\n }\n};\n\nstruct Circle {\n Point c;\n Real r;\n Circle() = default;\n Circle(Point c, Real r): c(c), r(r) {}\n\n friend ostream &operator<<(ostream &os, Circle &c) {\n return os << c.c << \": \" << c.r;\n }\n\n friend istream &operator>>(istream &is, Circle &c) {\n return is >> c.c >> c.r;\n }\n};\n\nReal cross(const Point &a, const Point &b) {\n return real(a) * imag(b) - real(b) * imag(a);\n}\n\nReal dot(const Point &a, const Point &b) {\n return real(a) * real(b) + imag(a) * imag(b);\n}\n\nstruct Segment : Line {\n Segment() = default;\n Segment(Point a, Point b) : Line(a, b) {}\n};\n\nint ccw(const Point &a, Point b, Point c) {\n b = b - a, c = c - a;\n if (cross(b, c) > EPS) return +1; // COUNTER_CLOCKWISE\n if (cross(b, c) < -EPS) return -1; // CLOCKWISE\n if (dot(b, c) < 0) return +2; // ONLINE_BACK\n if (norm(b) < norm(c)) return -2; // ONLINE_FRONT\n return 0; // ON_SEGMENT\n}\n\nbool intersect(const Segment &s, const Point &p) {\n return ccw(s.a, s.b, p) == 0;\n}\n\nbool intersect(const Segment &s, const Segment&t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 && ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\nbool intersect(const Line &l, const Segment& s) {\n return cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < EPS;\n}\n\nint intersect(const Circle &c, const Circle &d) {\n Real dis = fabs(c.c - d.c);\n\n if (dis > c.r + d.r + EPS) return 4;\n else if (eq(dis, c.r + d.r)) return 3;\n else if (eq(dis, abs(c.r - d.r))) return 1;\n else if (dis + min(c.r, d.r) < max(c.r, d.r) - EPS) return 0;\n else return 2;\n}\n\nbool parallel(const Line &a, const Line &b) {\n return abs(cross(a.b - a.a, b.b - b.a)) < EPS;\n}\n\nbool orthogonal(const Line &a, const Line &b) {\n return abs(dot(a.b - a.a, b.b - b.a)) < EPS;\n}\n\nPoint projection(const Line& s, const Point &p) {\n double t = dot(p - s.a, s.b - s.a) / norm(s.b - s. a);\n return s.a + (s.b - s.a) * t;\n}\n\nPoint projection(const Segment& l, const Point &p) {\n return projection(Line(l), p);\n}\n\nPoint reflection(const Line &l, const Point &p) {\n Point r = projection(l, p);\n return p + (r - p) * 2;\n}\n\nReal distance(const Line &l, const Point &p) {\n Point r = projection(l, p);\n return fabs(p - r);\n}\n\nReal distance(const Segment&s, const Point &p) {\n Point r = projection(s, p);\n if (intersect(s, r)) return abs(r - p);\n return min(abs(s.a - p), abs(s.b - p));\n}\n\nReal distance(const Segment& a, const Segment& b) {\n if (intersect(a, b)) return 0;\n return min({\n distance(a, b.a),\n distance(a, b.b),\n distance(b, a.a),\n distance(b, a.b)\n });\n}\n\nPoint crosspoint(const Line &l, const Line &m) {\n Real A = cross(l.b - l.a, m.b - m.a);\n Real B = cross(l.b - l.a, l.b - m.a);\n if (eq(abs(A), 0.0) && eq(abs(B), 0.0)) return m.a;\n return m.a + (m.b - m.a) * B / A;\n}\n\nPoint crosspoint(const Segment& l, const Segment& m) {\n return crosspoint(Line(l), Line(m));\n}\n\nLine bisector_of_angle(const Point& a, const Point& b, const Point& c) {\n Real d_ab = fabs(a - b);\n Real d_bc = fabs(b - c);\n Point c_ = b + (c - b) * d_ab / d_bc;\n\n return Line(b, (a + c_) * 0.5);\n}\n\nLine bisector(const Point& a, const Point& b) {\n Point c = (a + b) * 0.5;\n Point d = c + rotate(PI / 2, b - c);\n\n return Line(c, d);\n}\n\nint intersect(const Circle &c, const Line &l) {\n Real d = distance(l, c.c);\n\n if (d > c.r + EPS) return 0;\n if (eq(d, c.r)) return 1;\n return 2;\n}\n\npair<Point, Point> crosspoint(const Circle& c, const Line& l) {\n Real d = distance(l, c.c);\n\n Point p = projection(l, c.c);\n if (intersect(c, l) == 1) return { p, p };\n\n Real d2 = sqrt(c.r * c.r - d * d);\n Point v = (l.a - l.b) * (1.0 / fabs(l.a - l.b));\n\n return { p + d2 * v, p - d2 * v };\n}\n\npair<Point, Point> crosspoint(const Circle &c1, const Circle &c2) {\n Real d = fabs(c1.c - c2.c);\n Real x1 = (c1.r * c1.r + d * d - c2.r * c2.r) / 2 / d;\n Real y = sqrt(c1.r * c1.r - x1 * x1);\n\n Point base = (c2.c * x1 + c1.c * (d - x1)) * (1.0 / d);\n Point v = rotate(PI / 2, c1.c - base);\n v = v / fabs(v);\n\n return { base + v * y, base - v * y };\n}\n\npair<Point, Point> tangent(const Circle &c, const Point &p) {\n Real d = fabs(c.c - p);\n Real d2 = sqrt(d * d - c.r * c.r);\n Real a = acos(d2 / d);\n\n\n Point q = c.c - p;\n q = q / fabs(q);\n\n// cout << d << \" \" << d2 << \" \" << a << \" \" << q << endl;\n return {\n p + rotate(a, q) * d2,\n p + rotate(-a, q) * d2\n };\n}\n\nvector<Segment> common_tangent(Circle c1, Circle c2) {\n int isect = intersect(c1, c2);\n Real d = fabs(c1.c - c2.c);\n Point v = (c2.c - c1.c) / d;\n\n vector<Segment> res;\n\n if (isect == 0) {\n return {};\n } else if (isect == 1) {\n auto [p1, p2] = crosspoint(c1, Line(c1.c, c2.c));\n if (eq(fabs(p2 - c2.c), c2.r)) swap(p1, p2);\n\n Point v = p1 + rotate(PI/2, c2.c - p1);\n return { Segment(p1, v) };\n } else if (isect == 2) {\n } else if (isect == 3) {\n auto [p1, p2] = crosspoint(c1, c2);\n res.emplace_back(p1, rotate(PI / 2, c1.c - p1) + p1);\n } else {\n Real a = d * c1.r / (c1.r + c2.r);\n Point p = c1.c + v * a;\n\n Real d1 = sqrt(a * a - c1.r * c1.r), d2 = sqrt(norm(p - c2.c) - c2.r * c2.r);\n Real theta = acos(d1 / a);\n\n// cout << d << endl;\n// cout << a << \" \" << d1 << \" \" << d2 << \" \" << theta << \": \" << p << endl;\n\n Point e = (c1.c - p) * (1.0 / fabs(c1.c - p));\n Point e1 = rotate(theta, e), e2 = rotate(-theta, e);\n\n res.emplace_back(p + e1 * d1, p - e1 * d2);\n res.emplace_back(p + e2 * d1, p - e2 * d2);\n }\n\n if (eq(c1.r, c2.r)) {\n Point e = rotate(PI / 2, v);\n res.push_back(Segment(c1.c + e * c1.r, c2.c + e * c1.r));\n res.push_back(Segment(c1.c - e * c1.r, c2.c - e * c1.r));\n return res;\n }\n\n if (c1.r > c2.r) swap(c1, c2);\n\n v = c1.c - c2.c;\n Point p = v * (1.0 / (c2.r - c1.r)) * c2.r + c2.c;\n\n auto [q1, q2] = tangent(c1, p);\n res.emplace_back(q1, crosspoint(c2, Line(p, q1)).first);\n res.emplace_back(q2, crosspoint(c2, Line(p, q2)).first);\n\n return res;\n}\n\nusing Polygon = vector<Point>;\n\nistream& operator>>(istream& is, Polygon &p) {\n for (int i = 0; i < p.size(); i++) is >> p[i];\n return is;\n}\n\nostream& operator<<(ostream& os, Polygon &p) {\n for (int i = 0; i < p.size(); i++) os << p[i];\n return os;\n}\n\nReal area(const Polygon& p) {\n Real res = 0;\n for (int i = 0; i < p.size(); i++) {\n res += cross(p[i], p[(i + 1) % p.size()]);\n }\n return abs(res)/2;\n}\n\nint contains(Polygon g,Point p){\n int n=g.size();\n bool x=false;\n for(int i=0;i<n;i++){\n Point a=g[i]-p,b=g[(i+1)%n]-p;\n if(fabs(cross(a,b)) < EPS and dot(a,b) < EPS) return 1;\n if(a.imag()>b.imag()) swap(a,b);\n if(a.imag() < EPS and EPS < b.imag() and cross(a,b) > EPS ) {\n cout << a << \" --- \" << b << \": \" << cross(a, b) << endl;\n x = !x;\n }\n }\n return (x?2:0);\n}\n\nPolygon convex_hull(Polygon Q) {\n sort(ALL(Q));\n\n Polygon upper({Q[0]}), lower({Q[0]});\n\n rep(i, 1, Q.size()) {\n while (upper.size() >= 2) {\n int _ccw = ccw(upper[upper.size() - 2], upper[upper.size() - 1], Q[i]);\n if (_ccw == 1) {\n upper.pop_back();\n } else {\n break;\n }\n }\n if (upper.size() <= 1) {\n upper.push_back(Q[i]);\n } else if (upper.size() > 1) {\n int _ccw = ccw(upper[upper.size() - 2], upper[upper.size() - 1], Q[i]);\n if (_ccw == -1 || _ccw == -2) {\n upper.push_back(Q[i]);\n }\n }\n }\n rep(i, 1, Q.size()) {\n while (lower.size() >= 2) {\n int _ccw = ccw(lower[lower.size() - 2], lower[lower.size() - 1], Q[i]);\n if (_ccw == -1) {\n lower.pop_back();\n } else {\n break;\n }\n }\n\n if (lower.size() <= 1) {\n lower.push_back(Q[i]);\n } else if (lower.size() > 1) {\n int _ccw = ccw(lower[lower.size() - 2], lower[lower.size() - 1], Q[i]);\n if (_ccw == 1 || _ccw == -2) {\n lower.push_back(Q[i]);\n }\n }\n }\n\n Polygon ret;\n\n rep(i, 0, lower.size()) {\n ret.push_back(lower[i]);\n// cout << lower[i] << endl;\n }\n\n// cout << \" | \" << endl;\n\n rrep(i, 0, upper.size()) {\n if (!eq(lower[0], upper[i]) && !eq(lower.back(), upper[i]))\n ret.push_back(upper[i]);\n// cout << upper[i] << endl;\n }\n\n int start = 0;\n\n// cout << ret.size() << endl;\n rep(i, 0, ret.size()) {\n if (ret[i].imag() < ret[start].imag() || (eq(ret[i].imag(), ret[start].imag()) && ret[i].real() < ret[start].real())) {\n start = i;\n }\n }\n\n cout << ret.size() << endl;\n rep(i, 0, ret.size()) {\n auto p = ret[(i + start) % ret.size()];\n cout << (int)p.real() << \" \" << (int)p.imag() << endl;\n }\n\n return ret;\n}\n\nReal closest_pair(vector<Point> &pts, int l, int r) {\n int m = (l + r) / 2;\n if (r - l <= 1) {\n return INF;\n } else if (r - l == 2) {\n if (imag(pts[l]) > imag(pts[l + 1])) swap(pts[l], pts[l + 1]);\n return fabs(pts[l] - pts[l + 1]);\n }\n\n Real mid = pts[m].real();\n Real d = min(closest_pair(pts, l, m), closest_pair(pts, m, r));\n\n inplace_merge(pts.begin() + l, pts.begin() + m, pts.begin() + r, [](const Point &a, const Point& b) {\n return a.imag() < b.imag();\n });\n\n vector<Point> ret;\n\n for (int i = l; i < r; i++) {\n if (fabs(pts[i].real() - mid) >= d) continue;\n\n for (int j = ret.size() - 1; j >= 0; j--) {\n if (fabs(imag(ret[j]) - imag(pts[i])) >= d) break;\n chmin(d, fabs(ret[j] - pts[i]));\n }\n\n ret.emplace_back(pts[i]);\n }\n\n return d;\n}\n\nint main() {\n cout << fixed << setprecision(10);\n\n int n;\n while (cin >> n && n) {\n Segment s;\n cin >> s;\n vector<pair<Point, Point>> rect(n);\n vector<Real> h(n);\n rep(i, 0, n) {\n cin >> rect[i].fi >> rect[i].se >> h[i];\n }\n\n Real res = 1000;\n\n rep(i, 0, n) {\n vector<Point> pts({\n Point(rect[i].fi.real(), rect[i].fi.imag()),\n Point(rect[i].fi.real(), rect[i].se.imag()),\n Point(rect[i].se.real(), rect[i].fi.imag()),\n Point(rect[i].se.real(), rect[i].se.imag()),\n });\n\n rep(j, 0, 4) {\n Real d = distance(s, Segment(pts[j], pts[(j + 1) % 4]));\n\n// cout << i << \": \" << d << endl;\n if (d < h[i] + EPS) {\n chmin(res, d);\n } else {\n chmin(res, (d * d + h[i] * h[i]) / 2 / h[i]);\n }\n /*\n * (x)^2 = d^2 + (x - h)^2\n * 2hx = d^2 + h^2\n * x = (d^2 + h^2) / 2h\n */\n }\n }\n cout << res << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3472, "score_of_the_acc": -0.3831, "final_rank": 5 }, { "submission_id": "aoj_1157_7125685", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#include <unordered_set>\n#include <random>\n//#define int long long\n#define REP(i,m,n) for(int i=(m);i<(n);i++)\n#define rep(i,n) REP(i,0,n)\n#define pb push_back\n#define all(a) a.begin(),a.end()\n#define rall(c) (c).rbegin(),(c).rend()\n#define mp make_pair\n#define endl '\\n'\n//#define vec vector<ll>\n//#define mat vector<vector<ll> >\n#define fi first\n#define se second\n#define double long double\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<ll,ll> pll;\n//typedef long double ld;\ntypedef complex<double> Complex;\nconst ll INF=1e9+7;\nconst ll MOD=INF;\nconst ll inf=INF*INF;\nconst ll mod=MOD;\nconst ll inv2=499122177;\nconst ll MAX=10000010;\nconst double PI=acos(-1.0);\ntypedef vector<vector<ll> > mat;\ntypedef vector<ll> vec;\n\n//ll dx[]={0,1,0,-1,-1,-1,1,1};\n//ll dy[]={1,0,-1,0,-1,1,-1,1};\n\nint Dx[]={0,1,1,0,-1,-1};\nint Dy[]={1,0,-1,-1,-1,0};\n#line 2 \"geometry/base.hpp\"\n\nnamespace geometry {\n using Real = double;\n const Real EPS = 1e-8;\n const Real PI = acos(static_cast< Real >(-1));\n\n enum {\n OUT, ON, IN\n };\n\n inline int sign(const Real &r) {\n return r <= -EPS ? -1 : r >= EPS ? 1 : 0;\n }\n\n inline bool equals(const Real &a, const Real &b) {\n return sign(a - b) == 0;\n }\n}\n#line 3 \"geometry/point.hpp\"\n\nnamespace geometry {\n using Point = complex< Real >;\n\n istream &operator>>(istream &is, Point &p) {\n Real a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n }\n\n ostream &operator<<(ostream &os, const Point &p) {\n return os << real(p) << \" \" << imag(p);\n }\n\n Point operator*(const Point &p, const Real &d) {\n return Point(real(p) * d, imag(p) * d);\n }\n\n // rotate point p counterclockwise by theta rad\n Point rotate(Real theta, const Point &p) {\n return Point(cos(theta) * real(p) - sin(theta) * imag(p), sin(theta) * real(p) + cos(theta) * imag(p));\n }\n\n Real cross(const Point &a, const Point &b) {\n return real(a) * imag(b) - imag(a) * real(b);\n }\n\n Real dot(const Point &a, const Point &b) {\n return real(a) * real(b) + imag(a) * imag(b);\n }\n\n bool compare_x(const Point &a, const Point &b) {\n return equals(real(a), real(b)) ? imag(a) < imag(b) : real(a) < real(b);\n }\n\n bool compare_y(const Point &a, const Point &b) {\n return equals(imag(a), imag(b)) ? real(a) < real(b) : imag(a) < imag(b);\n }\n\n using Points = vector< Point >;\n}\n#line 3 \"geometry/line.hpp\"\n\nnamespace geometry {\n struct Line {\n Point a, b;\n\n Line() = default;\n\n Line(const Point &a, const Point &b) : a(a), b(b) {}\n\n Line(const Real &A, const Real &B, const Real &C) { // Ax+By=C\n if(equals(A, 0)) {\n assert(!equals(B, 0));\n a = Point(0, C / B);\n b = Point(1, C / B);\n } else if(equals(B, 0)) {\n a = Point(C / A, 0);\n b = Point(C / A, 1);\n } else {\n a = Point(0, C / B);\n b = Point(C / A, 0);\n }\n }\n\n friend ostream &operator<<(ostream &os, Line &l) {\n return os << l.a << \" to \" << l.b;\n }\n\n friend istream &operator>>(istream &is, Line &l) {\n return is >> l.a >> l.b;\n }\n };\n\n using Lines = vector< Line >;\n}\n#line 3 \"geometry/segment.hpp\"\n\nnamespace geometry {\n struct Segment : Line {\n Segment() = default;\n\n using Line::Line;\n };\n\n using Segments = vector< Segment >;\n}\n#line 3 \"geometry/ccw.hpp\"\n\nnamespace geometry {\n // http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_C\n constexpr int COUNTER_CLOCKWISE = +1;\n constexpr int CLOCKWISE = -1;\n constexpr int ONLINE_BACK = +2; // c-a-b\n constexpr int ONLINE_FRONT = -2; // a-b-c\n constexpr int ON_SEGMENT = 0; // a-c-b\n int ccw(const Point &a, Point b, Point c) {\n b = b - a, c = c - a;\n if(sign(cross(b, c)) == +1) return COUNTER_CLOCKWISE;\n if(sign(cross(b, c)) == -1) return CLOCKWISE;\n if(sign(dot(b, c)) == -1) return ONLINE_BACK;\n if(norm(b) < norm(c)) return ONLINE_FRONT;\n return ON_SEGMENT;\n }\n}\n#line 4 \"geometry/is_intersect_ss.hpp\"\n\n\nnamespace geometry {\n bool is_intersect_ss(const Segment &s, const Segment &t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n }\n}\n#line 2 \"geometry/projection.hpp\"\n\n#line 5 \"geometry/projection.hpp\"\n\nnamespace geometry {\n // http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_A\n Point projection(const Line &l, const Point &p) {\n auto t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n }\n}\n#line 4 \"geometry/is_intersect_sp.hpp\"\n\nnamespace geometry {\n bool is_intersect_sp(const Segment &s, const Point &p) {\n return ccw(s.a, s.b, p) == ON_SEGMENT;\n }\n}\n#line 5 \"geometry/distance_sp.hpp\"\n\nnamespace geometry {\n Real distance_sp(const Segment &s, const Point &p) {\n Point r = projection(s, p);\n if(is_intersect_sp(s, r)) return abs(r - p);\n return min(abs(s.a - p), abs(s.b - p));\n }\n}\n#line 4 \"geometry/distance_ss.hpp\"\n\nnamespace geometry {\n // http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_D\n Real distance_ss(const Segment &a, const Segment &b) {\n if(is_intersect_ss(a, b)) return 0;\n return min({distance_sp(a, b.a), distance_sp(a, b.b), distance_sp(b, a.a), distance_sp(b, a.b)});\n }\n}\nusing namespace geometry;\n\nvoid solve(){\n while(1){\n int N;\n cin >> N;\n if(N == 0)break;\n double sx, sy, ex, ey;\n cin >> sx >> sy >> ex >> ey;\n Point s(sx,sy),e(ex,ey);\n Segment L(s,e);\n double ans = inf;\n rep(i,N){\n double x1, y1, x2, y2, h;\n cin >> x1 >> y1 >> x2 >> y2 >> h;\n double mi = inf;\n Point a(x1,y1),b(x2,y1),c(x2,y2),d(x1,y2);\n Segment l1(a,b),l2(b,c),l3(c,d),l4(d,a);\n mi = min(mi, distance_ss(L,l1));\n //cout<<mi<<endl;\n mi = min(mi, distance_ss(L,l2));\n //cout<<mi<<endl;\n mi = min(mi, distance_ss(L,l3));\n //cout<<mi<<endl;\n mi = min(mi, distance_ss(L,l4));\n //cout<<mi<<endl;\n if(mi == 0 || sx >= x1 && sx <= x2 && sy >= y1 && sy <= y2 && ex >= x1 && ex <= x2 && ey >= y1 && ey <= y2) ans=0;\n if(mi>h)ans=min(ans,(mi*mi+h*h)/(h*2.0));\n else ans=min(ans,mi);\n }\n cout<<fixed<<setprecision(10)<<ans<<endl;\n }\n}\n\nsigned main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n solve();\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3640, "score_of_the_acc": -0.592, "final_rank": 9 }, { "submission_id": "aoj_1157_6714234", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, t) for (int i = (int)(s); i < (int)(t); ++i)\n#define revrep(i, t, s) for (int i = (int)(t)-1; i >= (int)(s); --i)\n#define all(x) begin(x), end(x)\ntemplate <typename T> bool chmax(T& a, const T& b) { return a < b ? (a = b, 1) : 0; }\ntemplate <typename T> bool chmin(T& a, const T& b) { return a > b ? (a = b, 1) : 0; }\n\nusing T = double;\nusing Vec = std::complex<T>;\n\nconst T PI = std::acos(-1);\n\nconstexpr T eps = 1e-12;\ninline bool eq(T a, T b) { return std::abs(a - b) <= eps; }\ninline bool eq(Vec a, Vec b) { return std::abs(a - b) <= eps; }\ninline bool lt(T a, T b) { return a < b - eps; }\ninline bool leq(T a, T b) { return a <= b + eps; }\n\nstd::istream& operator>>(std::istream& is, Vec& p) {\n T x, y;\n is >> x >> y;\n p = {x, y};\n return is;\n}\n\nstruct Line {\n Vec p1, p2;\n Line() = default;\n Line(const Vec& p1, const Vec& p2) : p1(p1), p2(p2) {}\n Vec dir() const { return p2 - p1; }\n};\n\nstruct Segment {\n Vec p1, p2;\n Segment() = default;\n Segment(const Vec& p1, const Vec& p2) : p1(p1), p2(p2) {}\n Vec dir() const { return p2 - p1; }\n};\n\nstruct Circle {\n Vec c;\n T r;\n Circle() = default;\n Circle(const Vec& c, T r) : c(c), r(r) {}\n};\n\nusing Polygon = std::vector<Vec>;\n\nT dot(const Vec& a, const Vec& b) {\n return (std::conj(a) * b).real();\n}\n\nT cross(const Vec& a, const Vec& b) {\n return (std::conj(a) * b).imag();\n}\n\nVec rot(const Vec& a, T ang) {\n return a * Vec(std::cos(ang), std::sin(ang));\n}\n\nVec perp(const Vec& a) {\n return Vec(-a.imag(), a.real());\n}\n\nVec projection(const Line& l, const Vec& p) {\n return l.p1 + dot(p - l.p1, l.dir()) * l.dir() / std::norm(l.dir());\n}\n\nVec reflection(const Line& l, const Vec& p) {\n return T(2) * projection(l, p) - p;\n}\n\n// 0: collinear\n// 1: counter-clockwise\n// 2: clockwise\nint ccw(const Vec& a, const Vec& b, const Vec& c) {\n if (eq(cross(b - a, c - a), 0)) return 0;\n if (lt(cross(b - a, c - a), 0)) return -1;\n return 1;\n}\n\nvoid sort_by_arg(std::vector<Vec>& pts) {\n std::sort(pts.begin(), pts.end(), [&](auto& p, auto& q) {\n if ((p.imag() < 0) != (q.imag() < 0)) return (p.imag() < 0);\n if (cross(p, q) == 0) {\n if (p == Vec(0, 0)) return !(q.imag() < 0 || (q.imag() == 0 && q.real() > 0));\n if (q == Vec(0, 0)) return (p.imag() < 0 || (p.imag() == 0 && p.real() > 0));\n return (p.real() > q.real());\n }\n return (cross(p, q) > 0);\n });\n}\n\nbool intersect(const Segment& s, const Vec& p) {\n Vec u = s.p1 - p, v = s.p2 - p;\n return eq(cross(u, v), 0) && leq(dot(u, v), 0);\n}\n\n// 0: outside\n// 1: on the border\n// 2: inside\nint intersect(const Polygon& poly, const Vec& p) {\n const int n = poly.size();\n bool in = 0;\n for (int i = 0; i < n; ++i) {\n auto a = poly[i] - p, b = poly[(i+1)%n] - p;\n if (eq(cross(a, b), 0) && (lt(dot(a, b), 0) || eq(dot(a, b), 0))) return 1;\n if (a.imag() > b.imag()) std::swap(a, b);\n if (leq(a.imag(), 0) && lt(0, b.imag()) && lt(cross(a, b), 0)) in ^= 1;\n }\n return in ? 2 : 0;\n}\n\nint intersect(const Segment& s, const Segment& t) {\n auto a = s.p1, b = s.p2;\n auto c = t.p1, d = t.p2;\n if (ccw(a, b, c) != ccw(a, b, d) && ccw(c, d, a) != ccw(c, d, b)) return 2;\n if (intersect(s, c) || intersect(s, d) || intersect(t, a) || intersect(t, b)) return 1;\n return 0;\n}\n\n// true if they have positive area in common or touch on the border\nbool intersect(const Polygon& poly1, const Polygon& poly2) {\n const int n = poly1.size();\n const int m = poly2.size();\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < m; ++j) {\n if (intersect(Segment(poly1[i], poly1[(i+1)%n]), Segment(poly2[j], poly2[(j+1)%n]))) {\n return true;\n }\n }\n }\n return intersect(poly1, poly2[0]) || intersect(poly2, poly1[0]);\n}\n\n// 0: inside\n// 1: inscribe\n// 2: intersect\n// 3: circumscribe\n// 4: outside\nint intersect(const Circle& c1, const Circle& c2) {\n T d = std::abs(c1.c - c2.c);\n if (lt(d, std::abs(c2.r - c1.r))) return 0;\n if (eq(d, std::abs(c2.r - c1.r))) return 1;\n if (eq(c1.r + c2.r, d)) return 3;\n if (lt(c1.r + c2.r, d)) return 4;\n return 2;\n}\n\nT dist(const Segment& s, const Vec& p) {\n if (lt(dot(p - s.p1, s.dir()), 0)) return std::abs(p - s.p1);\n if (lt(dot(p - s.p2, -s.dir()), 0)) return std::abs(p - s.p2);\n return std::abs(cross(p - s.p1, s.dir())) / std::abs(s.dir());\n}\n\nT dist(const Segment& s, const Segment& t) {\n if (intersect(s, t)) return T(0);\n return std::min({dist(s, t.p1), dist(s, t.p2), dist(t, s.p1), dist(t, s.p2)});\n}\n\n\n\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(15);\n\n while (true) {\n int N;\n cin >> N;\n if (N == 0) break;\n Vec s, e;\n cin >> s >> e;\n Segment seg(s, e);\n vector<vector<T>> x(N, vector<T>(2)), y(N, vector<T>(2));\n vector<T> h(N);\n rep(i,0,N) cin >> x[i][0] >> y[i][0] >> x[i][1] >> y[i][1] >> h[i];\n T lb = 0, ub = 1000;\n bool ok = true;\n rep(i,0,N) {\n if (x[i][0] <= seg.p1.real() && seg.p1.real() <= x[i][1] && y[i][0] <= seg.p1.imag() && seg.p1.imag() <= y[i][1]) {\n ok = false;\n }\n if (x[i][0] <= seg.p2.real() && seg.p2.real() <= x[i][1] && y[i][0] <= seg.p2.imag() && seg.p2.imag() <= y[i][1]) {\n ok = false;\n }\n rep(j1,0,2) rep(k1,0,2) rep(j2,0,2) rep(k2,0,2) {\n Segment seg2(Vec(x[i][j1], y[i][k1]), Vec(x[i][j2], y[i][k2]));\n if (intersect(seg, seg2)) ok = false;\n }\n if (!ok) break;\n }\n if (!ok) {\n cout << 0 << endl;\n continue;\n }\n rep(_,0,100) {\n T m = (lb + ub) / 2;\n bool ok = true;\n rep(i,0,N) {\n rep(j1,0,2) rep(k1,0,2) rep(j2,0,2) rep(k2,0,2) {\n Segment seg2(Vec(x[i][j1], y[i][k1]), Vec(x[i][j2], y[i][k2]));\n T d = dist(seg, seg2);\n if (leq(m, d)) continue;\n if (leq(m, h[i])) {\n ok = false;\n break;\n } else if (lt(m-sqrt(m*m-d*d), h[i])) {\n ok = false;\n break;\n }\n }\n if (!ok) break;\n }\n if (ok) lb = m;\n else ub = m;\n }\n cout << lb << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 3552, "score_of_the_acc": -0.6897, "final_rank": 11 }, { "submission_id": "aoj_1157_6385837", "code_snippet": "#include <cstdio>\n#include <vector>\n#include <cmath>\n#include <algorithm>\n#include <iostream>\nusing namespace std;\ndouble INF = 1000000;\ndouble EPS = 0.000000001;\nint sign(double x){\n if (x >= EPS){\n return 1;\n } else if (x <= - EPS){\n return -1;\n } else {\n return 0;\n }\n}\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n point operator +(point P){\n return point(x + P.x, y + P.y);\n }\n point operator -(point P){\n return point(x - P.x, y - P.y);\n }\n point operator *(double k){\n return point(x * k, y * k);\n }\n point operator /(double k){\n return point(x / k, y / k);\n }\n};\ndouble abs(point P){\n return sqrt(pow(P.x, 2) + pow(P.y, 2));\n}\ndouble dist(point P, point Q){\n return abs(Q - P);\n}\ndouble dot(point P, point Q){\n return P.x * Q.x + P.y * Q.y;\n}\ndouble cross(point P, point Q){\n return P.x * Q.y - P.y * Q.x;\n}\nstruct line{\n point A, B;\n line(){\n }\n line(point A, point B): A(A), B(B){\n }\n};\npoint vec(line L){\n return L.B - L.A;\n}\ndouble is_parallel(line L1, line L2){\n return sign(cross(vec(L1), vec(L2))) == 0;\n}\npoint line_intersection(line L1, line L2){\n return L1.A + vec(L1) * cross(L2.A - L1.A, vec(L2)) / cross(vec(L1), vec(L2));\n}\nbool on_segment(point P, line L){\n return sign(dot(P - L.A, vec(L))) > 0 && sign(dot(P - L.B, vec(L))) < 0;\n}\ndouble point_line_distance(point P, line L){\n return abs(cross(P - L.A, vec(L))) / abs(vec(L));\n}\ndouble point_segment_distance(point P, line L){\n if (sign(dot(P - L.A, vec(L))) < 0){\n return dist(P, L.A);\n } else if (sign(dot(P - L.B, vec(L))) > 0){\n return dist(P, L.B);\n } else {\n return point_line_distance(P, L);\n }\n}\ndouble segment_distance(line L1, line L2){\n if (!is_parallel(L1, L2)){\n point P = line_intersection(L1, L2);\n if (on_segment(P, L1) && on_segment(P, L2)){\n return 0;\n }\n }\n double ans = INF;\n ans = min(ans, point_segment_distance(L1.A, L2));\n ans = min(ans, point_segment_distance(L1.B, L2));\n ans = min(ans, point_segment_distance(L2.A, L1));\n ans = min(ans, point_segment_distance(L2.B, L1));\n return ans;\n}\n\nint main() {\n int n;\nwhile (scanf(\"%d\", &n) == 1) {\n if (n == 0) break;\n double sx, sy, tx, ty;\n scanf(\"%lf%lf%lf%lf\", &sx, &sy, &tx, &ty);\n vector<double> minx(n), miny(n), maxx(n), maxy(n), h(n);\n for (int i = 0; i < n; i++) {\n cin >> minx[i] >> miny[i] >> maxx[i] >> maxy[i] >> h[i];\n }\n //printf(\"ok\\n\");\n auto path = line(point(sx, sy), point(tx, ty));\n double ans = -1.0;\n double L = 0.0, R = 1e9;\n for (int it = 0; it < 60; it++) {\n if (L > R) break;\n double M = (L + R) * 0.5;\n // printf(\"M = %.9f\\n\", M);\n int ok = 1;\n for (int i = 0; i < n; i++) {\n double len = M;\n if (h[i] < len) len = sqrt(M*M - (M-h[i])*(M-h[i]));\n if (minx[i] <= sx && maxx[i] >= sx && miny[i] <= sy && maxy[i] >= sy) ok = 0;\n if (minx[i] <= tx && maxx[i] >= tx && miny[i] <= ty && maxy[i] >= ty) ok = 0;\n auto u = point(minx[i], miny[i]);\n auto v = point(maxx[i], miny[i]);\n auto w = point(maxx[i], maxy[i]);\n auto x = point(minx[i], maxy[i]);\n if (segment_distance(path, line(u, v)) < len) ok = 0;\n if (segment_distance(path, line(v, w)) < len) ok = 0;\n if (segment_distance(path, line(w, x)) < len) ok = 0;\n if (segment_distance(path, line(x, u)) < len) ok = 0;\n }\n if (ok) {\n ans = M;\n L = M + EPS; \n } else {\n R = M - EPS; \n }\n }\n if (ans < 0) printf(\"0\\n\");\n else printf(\"%.9f\\n\", ans);\n}\n return 0; \n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3564, "score_of_the_acc": -0.5047, "final_rank": 6 }, { "submission_id": "aoj_1157_5993002", "code_snippet": "#line 1 \"main.cpp\"\n#include <algorithm>\n#include <cassert>\n#include <cfloat>\n#include <cmath>\n#include <cstdint>\n#include <cstdio>\n#include <deque>\n#include <iomanip>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <unordered_map>\n#include <unordered_set>\n#include <utility>\n#include <vector>\n\nusing namespace std;\n\nusing lint = int64_t;\nusing uint = uint32_t;\nusing ulint = uint64_t;\n\ntemplate <class T>\nusing vector2d = vector<vector<T>>;\n\ntemplate <class T>\nbool UpdateMax(T &a, const T &b) {\n if (a < b) {\n a = b;\n return true;\n } else {\n return false;\n }\n}\n\ntemplate <class T>\nbool UpdateMin(T &a, const T &b) {\n if (a > b) {\n a = b;\n return true;\n } else {\n return false;\n }\n}\n\ntemplate <class T>\nvoid OutVec(const vector<T> &vec) {\n for (int i = 0; i < vec.size() - 1; ++i) {\n cout << vec[i] << \" \";\n }\n cout << vec.back() << endl;\n}\n\ntemplate <class T>\nvoid OutVec2d(const vector2d<T> &vec) {\n for (auto v : vec) {\n OutVec(v);\n }\n}\n\n#line 2 \"/home/arc/project/comppro/cplib/geometry/distance.cpp\"\n\n#line 2 \"/home/arc/project/comppro/cplib/geometry/base.cpp\"\n\nnamespace geometry {\n\nconst double EPS = 1e-8;\n/**\n * @brief double比較用関数\n *\n * @param a\n * @param b\n * @return int a>bなら1, a<bなら-1, a=bなら0\n */\nint doubleComp(double a, double b) {\n if (a > b + EPS)\n return 1;\n else if (b > a + EPS) {\n return -1;\n }\n return 0;\n}\n\nbool equals(double a, double b) {\n return doubleComp(a, b)==0;\n}\n} // namespace geometry\n#line 2 \"/home/arc/project/comppro/cplib/geometry/line.cpp\"\n\n#line 2 \"/home/arc/project/comppro/cplib/geometry/vector.cpp\"\n\n#include <complex>\n#include <limits>\n\n#line 7 \"/home/arc/project/comppro/cplib/geometry/vector.cpp\"\n\nnamespace geometry {\nusing Vector2 = std::complex<double>;\n\n/**\n * @brief aとbの内積 |a||b|cosΘ を求める \n *\n * @param a\n * @param b\n * @return double\n */\ndouble dot(const Vector2 &a, const Vector2 &b) {\n return a.real() * b.real() + a.imag() * b.imag();\n}\n\n/**\n * @brief aとbの外積 |a||b|sinΘ を求める\n *\n * @param a\n * @param b\n * @return double\n */\ndouble cross(const Vector2 &a, const Vector2 &b) {\n return a.real() * b.imag() - a.imag() * b.real();\n}\n\n/**\n * @brief pを反時計回りにrad回転したベクトルを求める\n *\n * @param p 元のベクトル\n * @param rad 回転角(単位ラジアン)\n * @return Vector2 回転後のベクトル\n */\nVector2 rotate(const Vector2 &p, const double rad) {\n double c = cos(rad), s = sin(rad);\n return Vector2(c * p.real() - s * p.imag(), s * p.real() + c * p.imag());\n}\n\n/**\n * @brief aを基準点としたb, cの位置関係を調べる\n *\n * @param a\n * @param b\n * @param c\n * @return int\n * cがbの反時計回りの位置: 1\n * 時計回りの位置: -1\n * c,a,bがこの順番で同一直線上: 2\n * a,b,cがこの順番で同一直線上: -2\n * cが線分ab上: 0\n */\nint ccw(const Vector2 &a, Vector2 b, Vector2 c) {\n b -= a;\n c -= a;\n if (doubleComp(cross(b, c), 0) == 1) {\n return 1;\n }\n if (doubleComp(cross(b, c), 0) == -1) {\n return -1;\n }\n if (doubleComp(dot(b, c), 0) == -1) {\n return 2;\n }\n if (norm(b) < norm(c)) {\n return -2;\n }\n return 0;\n}\n\nbool isNaN(const Vector2 &a) {\n return std::isnan(a.imag()) || std::isnan(a.real());\n}\n\nVector2 unitVector(const Vector2 &a) {\n return a / std::abs(a);\n}\n\nVector2 normalVector(const Vector2 &a) {\n return a * Vector2(0, 1);\n}\n\nstatic double nan = std::numeric_limits<double>::quiet_NaN();\nconst Vector2 NaN = Vector2(nan, nan);\n} // namespace geometry\n#line 5 \"/home/arc/project/comppro/cplib/geometry/line.cpp\"\n\nnamespace geometry {\nstruct Line {\n Vector2 a, b;\n Line() = default;\n Line(Vector2 _a, Vector2 _b) : a(_a), b(_b) {\n }\n\n /**\n * @brief ax+by=cの直線を作成\n *\n * @param a\n * @param b\n * @param c\n */\n Line(double _a, double _b, double _c) {\n if (equals(_a, 0)) {\n a = Vector2(0, _c / _b);\n b = Vector2(1, _c / _b);\n } else if (equals(_b, 0)) {\n a = Vector2(_c / _a, 0);\n b = Vector2(_c / _a, 1);\n } else {\n a = Vector2(0, _c / _b);\n b = Vector2(_c / _a, 0);\n }\n }\n\n Vector2 vector() const {\n return b - a;\n }\n};\n\nstruct Segment : Line {\n Segment() = default;\n Segment(Vector2 a, Vector2 b) : Line(a, b) {\n }\n};\n\n/**\n * @brief 2直線が平行であるかを返します\n *\n * @param s\n * @param t\n * @return true\n * @return false\n */\nbool isParallel(const Line &s, const Line &t) {\n return equals(0, cross(s.vector(), t.vector()));\n}\n\n/**\n * @brief 2直線が垂直であるかを返します\n *\n * @param s\n * @param t\n * @return true\n * @return false\n */\nbool isOrthogonal(const Line &s, const Line &t) {\n return equals(0, dot(s.vector(), t.vector()));\n}\n\n/**\n * @brief 2線分が交差しているかを返します\n *\n * @param s\n * @param t\n * @return true\n * @return false\n */\nbool hasIntersect(const Segment &s, const Segment &t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\n} // namespace geometry\n#line 6 \"/home/arc/project/comppro/cplib/geometry/distance.cpp\"\n\nnamespace geometry {\ndouble distance(const Vector2 &a, const Vector2 &b) {\n double x = a.real() - b.real();\n double y = a.imag() - b.imag();\n return sqrt(x * x + y * y);\n}\n\n/**\n * @brief 点と直線の距離を求めます\n *\n * @param p 点\n * @param l 直線\n * @return double 点と直線の距離\n */\ndouble distance(const Vector2 &p, const Line &l) {\n return std::abs(cross(l.vector(), p - l.a) / abs(l.vector()));\n}\n\n/**\n * @brief 点と線分の距離を求めます\n * \n * @param p 点\n * @param l 線分\n * @return double 点と線分の距離 \n */\ndouble distance(const Vector2 &p, const Segment &l) {\n if (dot(l.b - l.a, p - l.a) < EPS) {\n return abs(p-l.a);\n }\n if (dot(l.a - l.b, p - l.b) < EPS) {\n return abs(p-l.b);\n }\n return std::abs(cross(l.vector(), p - l.a) / abs(l.vector()));\n}\n\n/**\n * @brief 線分間の最短距離を求めます\n * \n * @param s \n * @param t \n * @return double \n */\ndouble distance(const Segment &s, const Segment &t) {\n if (hasIntersect(s, t)) {\n return (double)0;\n }\n double ans = distance(t.a, s);\n ans = std::min(ans, distance(t.b, s));\n ans = std::min(ans, distance(s.a, t));\n ans = std::min(ans, distance(s.b, t));\n return ans;\n}\n\n} // namespace geometry\n#line 2 \"/home/arc/project/comppro/cplib/geometry/polygon.cpp\"\n\n#line 5 \"/home/arc/project/comppro/cplib/geometry/polygon.cpp\"\n\n#line 7 \"/home/arc/project/comppro/cplib/geometry/polygon.cpp\"\nnamespace geometry {\n\nusing Polygon = std::vector<Vector2>;\n\n/**\n * @brief 多角形の面積を求めます\n *\n * @param p 多角形の頂点を反時計回りに並べたもの\n * @return double\n */\ndouble area(const Polygon &p) {\n double res = 0;\n int n = p.size();\n for (int i = 0; i < n - 1; i++) {\n res += cross(p[i], p[i + 1]);\n }\n res += cross(p[n - 1], p[0]);\n return res * 0.5;\n}\n\n/**\n * @brief 多角形が凸かどうか判定します\n *\n * @param p 多角形の頂点を反時計回りに並べたもの\n * @return true 凸である場合\n * @return false 凸でない場合\n */\nbool isConvex(const Polygon &p) {\n int n = p.size();\n int now, pre, nxt;\n for (int i = 0; i < n; i++) {\n pre = (i - 1 + n) % n;\n nxt = (i + 1) % n;\n now = i;\n if (ccw(p[pre], p[now], p[nxt]) == -1) {\n return false;\n }\n }\n return true;\n}\n\n/**\n * @brief 多角形に点が含まれているか判定します\n *\n * @param g 多角形の頂点を反時計回りに並べたもの\n * @param p 対象の点\n * @return int 含まれるなら2, 辺上にあるなら1, それ以外なら0\n */\nint isContained(const Polygon &g, const Vector2 &p) {\n bool in = false;\n int n = (int)g.size();\n for (int i = 0; i < n; i++) {\n Vector2 a = g[i] - p, b = g[(i + 1) % n] - p;\n if (imag(a) > imag(b)) {\n swap(a, b);\n }\n if (imag(a) <= EPS && EPS < imag(b) && cross(a, b) < -EPS) {\n in = !in;\n }\n if (equals(cross(a, b), 0) && doubleComp(dot(a, b), 0) <= 0) {\n return 1;\n }\n }\n return (in ? 2 : 0);\n}\n\n/**\n * @brief 凸包を求めます (O(N log N))\n *\n * @param p 多角形の頂点を反時計回りに並べたもの\n * @return Polygon pの凸包\n */\nPolygon convexHull(Polygon &p) {\n int n = (int)p.size(), k = 0;\n std::sort(p.begin(), p.end(), [](const Vector2 &a, const Vector2 &b) {\n return (!equals(a.real(), b.real()) ? a.real() < b.real()\n : a.imag() < b.imag());\n });\n Polygon ch(2 * n);\n // 一直線上の3点を含める -> (< -EPS)\n // 含めない -> (< EPS)\n for (int i = 0; i < n; ch[k++] = p[i++]) { // lower\n while (k >= 2 && cross(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1]) < EPS) --k;\n }\n for (int i = n - 2, t = k + 1; i >= 0; ch[k++] = p[i--]) { // upper\n while (k >= t && cross(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1]) < EPS) --k;\n }\n ch.resize(k - 1);\n return ch;\n}\n\n} // namespace geometry\n#line 67 \"main.cpp\"\n\nusing namespace geometry;\n\nbool canPassPoint(Segment l, Vector2 p, double h, double r) {\n double e = (r <= h) ? r : sqrt(2 * r * h - h * h);\n double d = distance(p, l);\n return d > e;\n}\n\nbool canPassAll(Vector2 s, Vector2 end, vector<Polygon> obstacles,\n vector<double> h, double r) {\n Segment l(s, end);\n\n for (int i = 0; i < obstacles.size(); i++) {\n for (auto p : obstacles[i]) {\n if (!canPassPoint(l, p, h[i], r)) return false;\n }\n for (int j = 0; j < 4; j++) {\n int k = j + 1;\n if (k == 4) k = 0;\n Segment edge(obstacles[i][j], obstacles[i][k]);\n if (!canPassPoint(edge, s, h[i], r)) {\n return false;\n }\n if (!canPassPoint(edge, end, h[i], r)) {\n return false;\n }\n if (hasIntersect(l, edge)) {\n return false;\n }\n }\n if (isContained(obstacles[i], s) >= 1 ||\n isContained(obstacles[i], end) >= 1) {\n return false;\n }\n }\n return true;\n}\n\ndouble solve(Vector2 s, Vector2 e, vector<Polygon> obstacles,\n vector<double> h) {\n double min = 0;\n double max = 1000;\n double mid = 500;\n while (max - min > 0.001) {\n if (canPassAll(s, e, obstacles, h, mid)) {\n min = mid;\n } else {\n max = mid;\n }\n mid = (min + max) / 2;\n }\n return min;\n}\n\nint main() {\n cout << std::fixed << std::setprecision(16);\n cin.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n while (true) {\n int n;\n cin >> n;\n if (n == 0) break;\n int sx, sy, ex, ey;\n cin >> sx >> sy >> ex >> ey;\n Vector2 s(sx, sy), e(ex, ey);\n\n vector<Polygon> obstacles;\n vector<double> h;\n for (int i = 0; i < n; i++) {\n int minx, miny, maxx, maxy, _h;\n cin >> minx >> miny >> maxx >> maxy >> _h;\n obstacles.push_back(vector<Vector2>{\n Vector2(minx, miny),\n Vector2(maxx, miny),\n Vector2(maxx, maxy),\n Vector2(minx, maxy),\n\n });\n h.push_back(_h);\n }\n\n cout << solve(s, e, obstacles, h) << endl;\n // cout << canPassAll(s, e, obstacles, h, 19) << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3576, "score_of_the_acc": -0.5124, "final_rank": 7 }, { "submission_id": "aoj_1157_5961399", "code_snippet": "#line 1 \"main.cpp\"\n#pragma region Macros\n#include <bits/stdc++.h>\nusing namespace std;\ntemplate <class T> inline bool chmax(T &a, T b) {\n if(a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <class T> inline bool chmin(T &a, T b) {\n if(a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\n#ifdef DEBUG\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << '(' << p.first << ',' << p.second << ')';\n return os;\n}\ntemplate <class T> ostream &operator<<(ostream &os, const vector<T> &v) {\n os << '{';\n for(int i = 0; i < (int)v.size(); i++) {\n if(i) { os << ','; }\n os << v[i];\n }\n os << '}';\n return os;\n}\nvoid debugg() { cerr << endl; }\ntemplate <class T, class... Args>\nvoid debugg(const T &x, const Args &... args) {\n cerr << \" \" << x;\n debugg(args...);\n}\n#define debug(...) \\\n cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"]: \", debugg(__VA_ARGS__)\n#define dump(x) cerr << __LINE__ << \" \" << #x << \" = \" << (x) << endl\n#else\n#define debug(...) (void(0))\n#define dump(x) (void(0))\n#endif\n\nstruct Setup {\n Setup() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(15);\n }\n} __Setup;\n\nusing ll = long long;\n#define OVERLOAD3(_1, _2, _3, name, ...) name\n#define ALL(v) (v).begin(), (v).end()\n#define RALL(v) (v).rbegin(), (v).rend()\n#define REP1(i, n) for(int i = 0; i < (n); i++)\n#define REP2(i, a, b) for(int i = (a); i < int(b); i++)\n#define REP(...) OVERLOAD3(__VA_ARGS__, REP2, REP1)(__VA_ARGS__)\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\nconst int INF = 1 << 30;\nconst ll LLINF = 1LL << 60;\nconstexpr int MOD = 1000000007;\nconst int dx[4] = {1, 0, -1, 0};\nconst int dy[4] = {0, 1, 0, -1};\n\nvoid Case(int i) { cout << \"Case #\" << i << \": \"; }\nint popcount(int x) { return __builtin_popcount(x); }\nll popcount(ll x) { return __builtin_popcountll(x); }\n#pragma endregion Macros\n\n#line 1 \"/home/siro53/kyo-pro/compro_library/geometry/geometry.hpp\"\nnamespace geometry {\n // Point : 複素数型を位置ベクトルとして扱う\n // 実軸(real)をx軸、挙軸(imag)をy軸として見る\n using D = double;\n using Point = complex<D>;\n const D EPS = 1e-7;\n const D PI = acosl(-1);\n\n inline bool equal(const D &a, const D &b) { return fabs(a - b) < EPS; }\n\n // 単位ベクトル(unit vector)を求める\n Point unitVector(const Point &a) { return a / abs(a); }\n\n // 法線ベクトル(normal vector)を求める\n // 90度回転した単位ベクトルをかける\n // -90度がよければPoint(0, -1)をかける\n Point normalVector(const Point &a) { return a * Point(0, 1); }\n\n // 内積(dot product) : a・b = |a||b|cosΘ\n D dot(const Point &a, const Point &b) {\n return (a.real() * b.real() + a.imag() * b.imag());\n }\n\n // 外積(cross product) : a×b = |a||b|sinΘ\n D cross(const Point &a, const Point &b) {\n return (a.real() * b.imag() - a.imag() * b.real());\n }\n\n // 点pを反時計回りにtheta度回転\n // thetaはラジアン!!!\n Point rotate(const Point &p, const D &theta) {\n return Point(cos(theta) * p.real() - sin(theta) * p.imag(),\n sin(theta) * p.real() + cos(theta) * p.imag());\n }\n\n // ラジアン->度\n D radianToDegree(const D &radian) { return radian * 180.0 / PI; }\n\n // 度->ラジアン\n D degreeToRadian(const D &degree) { return degree * PI / 180.0; }\n\n // 点の回転方向\n // 点a, b, cの位置関係について(aが基準点)\n int ccw(const Point &a, Point b, Point c) {\n b -= a, c -= a;\n // 点a, b, c が\n // 反時計回りの時、\n if(cross(b, c) > EPS) return 1;\n // 時計回りの時、\n if(cross(b, c) < -EPS) return -1;\n // c, a, bがこの順番で同一直線上にある時、\n if(dot(b, c) < 0) return 2;\n // a, b, cがこの順番で同一直線上にある場合、\n if(norm(b) < norm(c)) return -2;\n // cが線分ab上にある場合、\n return 0;\n }\n\n // Line : 直線を表す構造体\n // b - a で直線・線分を表せる\n struct Line {\n Point a, b;\n Line() = default;\n Line(Point a, Point b) : a(a), b(b) {}\n // Ax+By=C\n Line(D A, D B, D C) {\n if(equal(A, 0)) {\n a = Point(0, C / B), b = Point(1, C / B);\n } else if(equal(B, 0)) {\n b = Point(C / A, 0), b = Point(C / A, 1);\n } else {\n a = Point(0, C / B), b = Point(C / A, 0);\n }\n }\n };\n\n // Segment : 線分を表す構造体\n // Lineと同じ\n struct Segment : Line {\n Segment() = default;\n\n Segment(Point a, Point b) : Line(a, b) {}\n };\n\n // Circle : 円を表す構造体\n // pが中心の位置ベクトル、rは半径\n struct Circle {\n Point p;\n D r;\n\n Circle() = default;\n\n Circle(Point p, D r) : p(p), r(r) {}\n };\n\n // 2直線の直交判定 : a⊥b <=> dot(a, b) = 0\n bool isOrthogonal(const Line &a, const Line &b) {\n return equal(dot(a.b - a.a, b.b - b.a), 0);\n }\n // 2直線の平行判定 : a//b <=> cross(a, b) = 0\n bool isParallel(const Line &a, const Line &b) {\n return equal(cross(a.b - a.a, b.b - b.a), 0);\n }\n\n // 点cが直線ab上にあるか\n bool isPointOnLine(const Point &a, const Point &b, const Point &c) {\n return isParallel(Line(a, b), Line(a, c));\n }\n\n // 点cが\"線分\"ab上にあるか\n bool isPointOnSegment(const Point &a, const Point &b, const Point &c) {\n // |a-c| + |c-b| <= |a-b| なら線分上\n return (abs(a - c) + abs(c - b) < abs(a - b) + EPS);\n }\n\n // 直線lと点pの距離を求める\n D distanceBetweenLineAndPoint(const Line &l, const Point &p) {\n return abs(cross(l.b - l.a, p - l.a)) / abs(l.b - l.a);\n }\n\n // 線分lと点pの距離を求める\n // 定義:点pから「線分lのどこか」への最短距離\n D distanceBetweenSegmentAndPoint(const Segment &l, const Point &p) {\n if(dot(l.b - l.a, p - l.a) < EPS) return abs(p - l.a);\n if(dot(l.a - l.b, p - l.b) < EPS) return abs(p - l.b);\n return abs(cross(l.b - l.a, p - l.a)) / abs(l.b - l.a);\n }\n\n // 直線s, tの交点の計算\n Point crossPoint(const Line &s, const Line &t) {\n D d1 = cross(s.b - s.a, t.b - t.a);\n D d2 = cross(s.b - s.a, s.b - t.a);\n if(equal(abs(d1), 0) && equal(abs(d2), 0)) return t.a;\n return t.a + (t.b - t.a) * (d2 / d1);\n }\n\n // 線分s, tの交点の計算\n Point crossPoint(const Segment &s, const Segment &t) {\n return crossPoint(Line(s), Line(t));\n }\n\n // 線分sと線分tが交差しているかどうか\n // bound:線分の端点を含むか\n bool isIntersect(const Segment &s, const Segment &t, bool bound) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) < bound &&\n ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) < bound;\n }\n\n // 線分sとtの距離\n D distanceBetweenSegments(const Segment &s, const Segment &t) {\n if(isIntersect(s, t, 1)) return (D)(0);\n D ans = distanceBetweenSegmentAndPoint(s, t.a);\n chmin(ans, distanceBetweenSegmentAndPoint(s, t.b));\n chmin(ans, distanceBetweenSegmentAndPoint(t, s.a));\n chmin(ans, distanceBetweenSegmentAndPoint(t, s.b));\n return ans;\n }\n\n // 射影(projection)\n // 直線(線分)lに点pから引いた垂線の足を求める\n Point projection(const Line &l, const Point &p) {\n D t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n }\n\n Point projection(const Segment &l, const Point &p) {\n D t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n }\n\n // 反射(reflection)\n // 直線lを対称軸として点pと線対称の位置にある点を求める\n Point reflection(const Line &l, const Point &p) {\n return p + (projection(l, p) - p) * (D)2.0;\n }\n\n // 2つの円の交差判定\n // 返り値は共通接線の数\n int isIntersect(const Circle &c1, const Circle &c2) {\n D d = abs(c1.p - c2.p);\n // 2つの円が離れている場合\n if(d > c1.r + c2.r + EPS) return 4;\n // 外接している場合\n if(equal(d, c1.r + c2.r)) return 3;\n // 内接している場合\n if(equal(d, abs(c1.r - c2.r))) return 1;\n // 内包している場合\n if(d < abs(c1.r - c2.r) - EPS) return 0;\n return 2;\n }\n\n // 2つの円の交点\n vector<Point> crossPoint(const Circle &c1, const Circle &c2) {\n vector<Point> res;\n int mode = isIntersect(c1, c2);\n // 2つの中心の距離\n D d = abs(c1.p - c2.p);\n // 2円が離れている場合\n if(mode == 4) return res;\n // 1つの円がもう1つの円に内包されている場合\n if(mode == 0) return res;\n // 2円が外接する場合\n if(mode == 3) {\n D t = c1.r / (c1.r + c2.r);\n res.emplace_back(c1.p + (c2.p - c1.p) * t);\n return res;\n }\n // 内接している場合\n if(mode == 1) {\n if(c2.r < c1.r - EPS) {\n res.emplace_back(c1.p + (c2.p - c1.p) * (c1.r / d));\n } else {\n res.emplace_back(c2.p + (c1.p - c2.p) * (c2.r / d));\n }\n return res;\n }\n // 2円が重なる場合\n D rc1 = (c1.r * c1.r + d * d - c2.r * c2.r) / (2 * d);\n D rs1 = sqrt(c1.r * c1.r - rc1 * rc1);\n if(c1.r - abs(rc1) < EPS) rs1 = 0;\n Point e12 = (c2.p - c1.p) / abs(c2.p - c1.p);\n res.emplace_back(c1.p + rc1 * e12 + rs1 * e12 * Point(0, 1));\n res.emplace_back(c1.p + rc1 * e12 + rs1 * e12 * Point(0, -1));\n return res;\n }\n\n // 点pが円cの内部(円周上も含む)に入っているかどうか\n bool isInCircle(const Circle &c, const Point &p) {\n D d = abs(c.p - p);\n return (equal(d, c.r) || d < c.r - EPS);\n }\n\n // 円cと直線lの交点\n vector<Point> crossPoint(const Circle &c, const Line &l) {\n vector<Point> res;\n D d = distanceBetweenLineAndPoint(l, c.p);\n // 交点を持たない\n if(d > c.r + EPS) return res;\n // 接する\n Point h = projection(l, c.p);\n if(equal(d, c.r)) {\n res.emplace_back(h);\n return res;\n }\n Point e = unitVector(l.b - l.a);\n D ph = sqrt(c.r * c.r - d * d);\n res.emplace_back(h - e * ph);\n res.emplace_back(h + e * ph);\n return res;\n }\n\n // 点pを通る円cの接線\n // 2本あるので、接点のみを返す\n vector<Point> tangentToCircle(const Point &p, const Circle &c) {\n return crossPoint(c, Circle(p, sqrt(norm(c.p - p) - c.r * c.r)));\n }\n\n // 円の共通接線\n vector<Line> tangent(const Circle &a, const Circle &b) {\n vector<Line> ret;\n // 2円の中心間の距離\n D g = abs(a.p - b.p);\n // 円が内包されている場合\n if(equal(g, 0)) return ret;\n Point u = unitVector(b.p - a.p);\n Point v = rotate(u, PI / 2);\n for(int s : {-1, 1}) {\n D h = (a.r + b.r * s) / g;\n if(equal(h * h, 1)) {\n ret.emplace_back(a.p + (h > 0 ? u : -u) * a.r,\n a.p + (h > 0 ? u : -u) * a.r + v);\n\n } else if(1 - h * h > 0) {\n Point U = u * h, V = v * sqrt(1 - h * h);\n ret.emplace_back(a.p + (U + V) * a.r,\n b.p - (U + V) * (b.r * s));\n ret.emplace_back(a.p + (U - V) * a.r,\n b.p - (U - V) * (b.r * s));\n }\n }\n return ret;\n }\n\n // 多角形の面積を求める\n D PolygonArea(const vector<Point> &p) {\n D res = 0;\n int n = p.size();\n for(int i = 0; i < n - 1; i++) res += cross(p[i], p[i + 1]);\n res += cross(p[n - 1], p[0]);\n return res * 0.5;\n }\n\n // 凸多角形かどうか\n bool isConvex(const vector<Point> &p) {\n int n = p.size();\n int now, pre, nxt;\n for(int i = 0; i < n; i++) {\n pre = (i - 1 + n) % n;\n nxt = (i + 1) % n;\n now = i;\n if(ccw(p[pre], p[now], p[nxt]) == -1) return false;\n }\n return true;\n }\n\n // 凸包 O(NlogN)\n vector<Point> ConvexHull(vector<Point> &p) {\n int n = (int)p.size(), k = 0;\n sort(ALL(p), [](const Point &a, const Point &b) {\n return (real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b));\n });\n vector<Point> ch(2 * n);\n // 一直線上の3点を含める -> (< -EPS)\n // 含め無い -> (< EPS)\n for(int i = 0; i < n; ch[k++] = p[i++]) { // lower\n while(k >= 2 &&\n cross(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1]) < EPS)\n --k;\n }\n for(int i = n - 2, t = k + 1; i >= 0; ch[k++] = p[i--]) { // upper\n while(k >= t &&\n cross(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1]) < EPS)\n --k;\n }\n ch.resize(k - 1);\n return ch;\n }\n\n // 多角形gに点pが含まれているか?\n // 含まれる:2, 辺上にある:1, 含まれない:0\n int isContained(const vector<Point> &g, const Point &p) {\n bool in = false;\n int n = (int)g.size();\n for(int i = 0; i < n; i++) {\n Point a = g[i] - p, b = g[(i + 1) % n] - p;\n if(imag(a) > imag(b)) swap(a, b);\n if(imag(a) <= EPS && EPS < imag(b) && cross(a, b) < -EPS) in = !in;\n if(cross(a, b) == 0 && dot(a, b) <= 0) return 1;\n }\n return (in ? 2 : 0);\n }\n\n} // namespace geometry\n#line 75 \"main.cpp\"\nusing namespace geometry;\n\nbool solve() {\n int N;\n cin >> N;\n if(N == 0) return false;\n int sx, sy, gx, gy;\n cin >> sx >> sy >> gx >> gy;\n Segment base(Point(sx, sy), Point(gx, gy));\n vector<pair<Segment, double>> kouho;\n bool f = true;\n REP(i, N) {\n int min_x, min_y, max_x, max_y, h;\n cin >> min_x >> min_y >> max_x >> max_y >> h;\n kouho.emplace_back(Segment(Point(min_x, min_y), Point(max_x, min_y)), h);\n kouho.emplace_back(Segment(Point(min_x, min_y), Point(min_x, max_y)), h);\n kouho.emplace_back(Segment(Point(max_x, min_y), Point(max_x, max_y)), h);\n kouho.emplace_back(Segment(Point(min_x, max_y), Point(max_x, max_y)), h);\n vector<Point> ps(4);\n ps[0] = Point(min_x, min_y);\n ps[1] = Point(min_x, max_y);\n ps[2] = Point(max_x, min_y);\n ps[3] = Point(max_x, max_y);\n if(isContained(ps, Point(sx, sy)) or isContained(ps, Point(gx, gy))) {\n f = false;\n }\n }\n if(!f) {\n cout << 0 << '\\n';\n return true;\n }\n\n for(const auto& [l, h] : kouho) {\n if(isIntersect(base, l, true)) {\n cout << 0 << '\\n';\n return true;\n }\n }\n\n double ok = 0.0, ng = 1000.1;\n REP(_, 30) {\n double mid = (ok + ng) / 2.0;\n bool judge = true;\n for(const auto& [l, h] : kouho) {\n double d = distanceBetweenSegments(base, l);\n double x;\n if(mid > h) {\n x = sqrt(mid*mid - (mid-h)*(mid-h));\n } else {\n x = mid;\n }\n if(x > d) {\n judge = false;\n break;\n }\n }\n (judge ? ok : ng) = mid;\n }\n cout << ok << '\\n';\n return true;\n}\n\nint main() {\n while(solve());\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3440, "score_of_the_acc": -0.3433, "final_rank": 4 }, { "submission_id": "aoj_1157_5487874", "code_snippet": "#include <stdio.h>\n#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n#define Inf 1000000000\n\nconst double eps = 1e-10;\n\ntemplate <typename T>\nstruct vector_2d{\n\tT x,y,rad,dir;\n\t\n\tvector_2d(T a=0.0,T b=0.0){\n\t\tx = a;\n\t\ty = b;\n\t\tfix_rd();\n\t}\n\t\n\tvoid update_x(T a,T b){\n\t\tx = a*x + b;\n\t\tfix_rd();\n\t}\n\t\n\tvoid update_x(T a){\n\t\tupdate_x(0.0,a);\n\t}\n\t\n\tvoid update_y(T a,T b){\n\t\ty = a*y + b;\n\t\tfix_rd();\n\t}\n\t\n\tvoid update_y(T a){\n\t\tupdate_y(0.0,a);\n\t}\n\t\n\tvoid update_rad(T a,T b){\n\t\trad = a*rad + b;\n\t\tfix_xy();\n\t}\n\t\n\tvoid update_rad(T a){\n\t\tupdate_rad(0.0,a);\n\t}\n\t\n\tvoid update_dir(T a,T b){\n\t\tdir = a*dir + b;\n\t\tfix_xy();\n\t}\n\n\tvoid update_dir(T a){\n\t\tupdate_dir(0.0,a);\n\t}\n\t\n\tvoid fix_xy(){\n\t\tx = rad * cos(dir);\n\t\ty = rad * sin(dir);\n\t\tfix_rd();\n\t}\n\t\n\tvoid fix_rd(){\n\t\trad = hypot(x,y);\n\t\tif(rad==0.0)dir=0.0;\n\t\telse dir = atan2(y,x);\n\t\tfix_zero();\n\t}\n\t\n\tvoid fix_zero(){\n\t\tif(abs(x)<eps)x = 0.0;\n\t\tif(abs(y)<eps)y = 0.0;\n\t\tif(abs(rad)<eps)rad = 0.0;\n\t\tif(abs(dir)<eps)dir = 0.0;\n\t}\n\t\n\tvoid normalize(){\n\t\tT s = size();\n\t\tupdate_x(1.0/s,0.0);\n\t\tupdate_y(1.0/s,0.0);\n\t}\n\t\n\t\n\tT get_dis(vector_2d<T> V){\n\t\treturn hypot(x-V.x,y-V.y);\n\t}\n\t\n\tT size(){\n\t\treturn get_dis(vector_2d<T>());\n\t}\n\t\n\tT angle_difference(vector_2d<T> V){\n\t\tdouble ret = dir - V.dir;\n\t\tif(ret<-acos(-1.0))ret = acos(-1.0)*2.0+ret;\n\t\tif(ret>acos(-1.0))ret=-acos(-1.0)*2.0+ret;\n\t\treturn ret;\n\t}\n\t\n\t//中点\n\tvector_2d get_midpoint(vector_2d<T> V){\n\t\tV.update_x(0.5,x/2.0);\n\t\tV.update_y(0.5,y/2.0);\n\t\treturn V;\n\t}\n\t\n\tT get_inner_product(vector_2d<T> V){\n\t\treturn x*V.x+y*V.y;\n\t}\n\t\n\tT get_cross_product(vector_2d<T> V){\n\t\treturn x*V.y-y*V.x;\n\t}\n\t\n\tvector_2d &operator+=(const vector_2d<T> &another){\n\t\tupdate_x(1,another.x);\n\t\tupdate_y(1,another.y);\n\t\treturn (*this);\n\t}\n\t\n\tvector_2d &operator-=(const vector_2d<T> &another){\n\t\tupdate_x(1,-another.x);\n\t\tupdate_y(1,-another.y);\n\t\treturn (*this);\n\t}\n\t\n\tvector_2d operator+(const vector_2d<T> &another)const{\n\t\treturn (vector_2d(*this)+=another);\n\t}\n\t\n\tvector_2d operator-(const vector_2d<T> &another)const{\n\t\treturn (vector_2d(*this)-=another);\n\t}\n\t\n\tvoid show(){\n\t\tcout<<x<<','<<y<<endl;\n\t}\n};\n\n//ax+by+c=0\ntemplate <typename T>\nstruct line{\n\tvector_2d<T> a,t;\n\t\n\tline(vector_2d<T> V1,vector_2d<T> V2){\n\t\ta=V1;\n\t\tt=V2-V1;\n\t}\n\n\tT get_signed_dis(vector_2d<T> V){\n\t\tvector_2d<double> PA = a-V;\n\t\treturn PA.get_cross_product(t)/t.size();\n\t}\n\t\n\tT get_dis(vector_2d<T> V){\n\t\treturn abs(get_signed_dis(V));\n\t}\n\t\n\tvector_2d<T> get_projection(vector_2d<T> P){\n\t\tT r = t.get_inner_product(P-a)/t.size();\n\t\tvector_2d<T> temp = t;\n\t\ttemp.update_rad(0.0,r);\n\t\treturn a+temp;\n\t}\t\n\t\n\tvector_2d<T> get_cross_point(line<T> L){\n\t\tvector_2d<T> ret(1e20,1e20);\n\t\tif((t-L.t).size()<eps)return ret;\n\t\t\n\t\tT d0 = L.get_signed_dis(a);\n\t\tT d1 = L.get_signed_dis(a+t);\n\t\tvector_2d<T> temp = t;\n\t\ttemp.x *= d0/(d1-d0);\n\t\ttemp.y *= d0/(d1-d0);\n\t\tret = a - temp;\n\t\treturn ret;\n\t}\n\t\n};\n\ntemplate <typename T>\nstruct segment{\n\tvector_2d<T> V1,V2;\n\tsegment(vector_2d<T> a=vector_2d<T>(),vector_2d<T> b=vector_2d<T>()){\n\t\tV1=a;\n\t\tV2=b;\n\t}\n\t\n\tT get_dis(vector_2d<T> P){\n\t\tT ret = 1e20;\n\t\tline<T> L(V1,V2);\n\t\tvector_2d<T> Q = L.get_projection(P);\n\t\tif(Q.x+eps>min(V1.x,V2.x)&&Q.y+eps>min(V1.y,V2.y)\n\t\t&&Q.x<max(V1.x,V2.x)+eps&&Q.y<max(V1.y,V2.y)+eps)ret = min(ret,Q.get_dis(P));\n\t\telse{\n\t\t\tret = min(ret,P.get_dis(V1));\n\t\t\tret = min(ret,P.get_dis(V2));\n\t\t}\n\t\treturn ret;\n\t}\n\t\n\tT get_dis(segment<T> l){\n\t\tif(get_cross_point(l).x<1e20)return 0.0;\n\t\treturn min({get_dis(l.V1),get_dis(l.V2),l.get_dis(V1),l.get_dis(V2)});\n\t}\n\t\n\tvector_2d<T> get_cross_point(segment<T> l){\n\t\tline<T> L1(V1,V2),L2(l.V1,l.V2);\n\t\tvector_2d<T> P = L1.get_cross_point(L2);\n\t\tif(get_dis(P)<eps&&l.get_dis(P)<eps)return P;\n\t\treturn vector_2d<T> (1e20,1e20);\n\t}\n};\n\nint main(){\n\t\n\twhile(true){\n\t\t\n\t\tint N;\n\t\tcin>>N;\n\t\tif(N==0)break;\n\t\tdouble sx,sy,ex,ey;\n\t\t\n\t\tcin>>sx>>sy>>ex>>ey;\n\t\t\n\t\tvector<double> mx(N),my(N),Mx(N),My(N),h(N);\n\t\trep(i,N){\n\t\t\tcin>>mx[i]>>my[i]>>Mx[i]>>My[i]>>h[i];\n\t\t}\n\t\t\n\t\tvector<vector<segment<double>>> s(N);\n\t\trep(i,N){\n\t\t\ts[i].push_back(segment<double>(vector_2d<double>(mx[i],my[i]),vector_2d<double>(mx[i],My[i])));\n\t\t\ts[i].push_back(segment<double>(vector_2d<double>(mx[i],My[i]),vector_2d<double>(Mx[i],My[i])));\n\t\t\ts[i].push_back(segment<double>(vector_2d<double>(Mx[i],My[i]),vector_2d<double>(Mx[i],my[i])));\n\t\t\ts[i].push_back(segment<double>(vector_2d<double>(Mx[i],my[i]),vector_2d<double>(mx[i],my[i])));\n\t\t}\n\t\t\n\t\tsegment<double> S(vector_2d<double>(sx,sy),vector_2d<double>(ex,ey));\n\t\t\n\t\tdouble ok = 0.0,ng = 1000.0;\n\t\t\n\t\trep(_,60){\n\t\t\tdouble mid = (ok+ng)/2.0;\n\t\t\t\n\t\t\tbool f = true;\n\t\t\t\n\t\t\trep(i,N){\n\t\t\t\tdouble dmin = 1e9;\n\t\t\t\trep(j,4){\n\t\t\t\t\tdmin = min(dmin,S.get_dis(s[i][j]));\n\t\t\t\t}\n\t\t\t\tif(h[i]<=mid){\n\t\t\t\t\tdmin *= dmin;\n\t\t\t\t\tdmin += pow(mid-h[i],2.0);\n\t\t\t\t\tdmin = sqrt(dmin);\n\t\t\t\t\tif(dmin<mid){\n\t\t\t\t\t\tf=false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tif(dmin<mid){\n\t\t\t\t\t\tf=false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t\t\n\t\t\tif(f)ok = mid;\n\t\t\telse ng = mid;\n\t\t}\n\t\t\n\t\trep(i,N){\n\t\t\tdouble t = 1.0;\n\t\t\tbool f0 = false,f1 = false;\n\t\t\trep(j,2){\n\t\t\t\tline<double> L(s[i][j*2].V1,s[i][j*2].V2);\n\t\t\t\tt *= L.get_signed_dis(S.V1);\n\t\t\t}\n\t\t\tif(t>=0.0)f0=true;\n\t\t\tt = 1.0;\n\t\t\trep(j,2){\n\t\t\t\tline<double> L(s[i][j*2+1].V1,s[i][j*2+1].V2);\n\t\t\t\tt *= L.get_signed_dis(S.V1);\n\t\t\t}\n\t\t\tif(t>=0.0)f1=true;\n\t\t\tif(f0&&f1){\n\t\t\t\tok = 0.0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tf0 = false;\n\t\t\tf1 = false;\n\t\t\tt = 1.0;\n\t\t\trep(j,2){\n\t\t\t\tline<double> L(s[i][j*2].V1,s[i][j*2].V2);\n\t\t\t\tt *= L.get_signed_dis(S.V2);\n\t\t\t}\n\t\t\tif(t>=0.0)f0=true;\n\t\t\tt = 1.0;\n\t\t\trep(j,2){\n\t\t\t\tline<double> L(s[i][j*2+1].V1,s[i][j*2+1].V2);\n\t\t\t\tt *= L.get_signed_dis(S.V2);\n\t\t\t}\n\t\t\tif(t>=0.0)f1=true;\n\t\t\tif(f0&&f1){\n\t\t\t\tok = 0.0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\t\n\t\tcout<<fixed<<setprecision(10)<<ok<<endl;\n\t\t\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 820, "memory_kb": 3892, "score_of_the_acc": -1.484, "final_rank": 20 }, { "submission_id": "aoj_1157_5386096", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n/**\n * @brief geometry\n * @docs docs/geometry/geometry.md\n */\nconst double EPS = 1e-8, PI = acos(-1);\ninline bool EQ(double a, double b) { return fabs(b - a) < EPS; }\n\nstruct Point {\n double x, y;\n Point() {}\n Point(double x, double y) : x(x), y(y) {}\n Point operator-() const { return Point(-x, -y); }\n Point operator+(Point p) const { return Point(x + p.x, y + p.y); }\n Point operator-(Point p) const { return Point(x - p.x, y - p.y); }\n Point operator*(double t) const { return Point(x * t, y * t); }\n Point operator*(Point p) const { return Point(x * p.x - y * p.y, x * p.y + y * p.x); }\n Point operator/(double t) const { return Point(x / t, y / t); }\n bool operator<(const Point& p) const { return x != p.x ? x < p.x : y < p.y; }\n bool operator==(const Point& p) const { return EQ(x, p.x) && EQ(y, p.y); }\n friend istream& operator>>(istream& is, Point& p) {\n is >> p.x >> p.y;\n return is;\n }\n friend ostream& operator<<(ostream& os, Point p) {\n os << fixed << setprecision(10) << p.x << ' ' << p.y;\n return os;\n }\n};\n\nstruct Line {\n Point a, b;\n Line() {}\n Line(Point a, Point b) : a(a), b(b) {}\n friend istream& operator>>(istream& is, Line& l) {\n is >> l.a >> l.b;\n return is;\n }\n friend ostream& operator<<(ostream& os, Line l) {\n os << l.a << \" to \" << l.b;\n return os;\n }\n};\n\nstruct Segment : Line {\n Segment() {}\n Segment(Point a, Point b) : Line(a, b) {}\n};\n\nstruct Circle {\n Point c;\n double r;\n Circle() {}\n Circle(Point c, double r) : c(c), r(r) {}\n friend istream& operator>>(istream& is, Circle& c) {\n is >> c.c >> c.r;\n return is;\n }\n friend ostream& operator<<(ostream& os, Circle& c) {\n os << c.c << ' ' << c.r;\n return os;\n }\n};\n\nusing Polygon = vector<Point>;\n\ndouble dot(const Point&, const Point&);\ndouble cross(const Point&, const Point&);\ndouble norm(const Point&);\ndouble abs(const Point&);\nPoint projection(const Line&, const Point&);\nPoint reflection(const Line&, const Point&);\ndouble arg(const Point&);\ndouble radian_to_degree(const double&);\ndouble degree_to_radian(const double&);\nPoint polar(const double&, const double&);\nPoint rotate(const Point&, const double&);\ndouble get_angle(const Point&, const Point&, const Point&);\nenum { COUNTER_CLOCKWISE = 1, CLOCKWISE = -1, ONLINE_BACK = 2, ONLINE_FRONT = -2, ON_SEGMENT = 0 };\nint ccw(const Point&, Point, Point);\nbool orthogonal(const Point&, const Point&);\nbool orthogonal(const Point&, const Point&, const Point&, const Point&);\nbool orthogonal(const Line&, const Line&);\nbool parallel(const Point&, const Point&);\nbool parallel(const Point&, const Point&);\nbool parallel(const Point&, const Point&, const Point&, const Point&);\nbool parallel(const Line&, const Line&);\nbool intersect(const Line&, const Point&);\nbool intersect(const Line&, const Line&);\nbool intersect(const Line&, const Segment&);\nbool intersect(const Segment&, const Point&);\nbool intersect(const Segment&, const Segment&);\nbool intersect(const Circle&, const Line&);\nint intersect(const Circle&, const Segment&);\nbool intersect(Circle, Circle);\nint count_tangent(Circle, Circle);\ndouble distance(const Point&, const Point&);\ndouble distance(const Line&, const Point&);\ndouble distance(const Line&, const Line&);\ndouble distance(const Segment&, const Point&);\ndouble distance(const Segment&, const Segment&);\ndouble distance(const Line&, const Segment&);\nPoint crosspoint(const Line&, const Line&);\nPoint crosspoint(const Segment&, const Segment&);\npair<Point, Point> crosspoint(const Circle&, const Line&);\npair<Point, Point> crosspoint(const Circle&, const Segment&);\npair<Point, Point> crosspoint(const Circle&, const Circle&);\nCircle circumcenter(Point, Point, const Point&);\npair<Point, Point> center_given_radius(const Point&, const Point&, const double&);\npair<Point, Point> tangent(const Circle&, const Point&);\nvector<Line> common_tangent(Circle, Circle);\ndouble area(const Polygon&);\nenum { OUT, ON, IN };\nint contain(const Polygon&, const Point&);\nint contain(const Circle&, const Point&);\nbool is_convex(const Polygon&);\nPolygon convex_hull(Polygon, bool);\ndouble convex_diameter(Polygon);\nPolygon convex_cut(const Polygon&, const Line&);\n\ndouble dot(const Point& a, const Point& b) { return a.x * b.x + a.y * b.y; }\ndouble cross(const Point& a, const Point& b) { return a.x * b.y - a.y * b.x; }\ndouble norm(const Point& p) { return p.x * p.x + p.y * p.y; }\ndouble abs(const Point& p) { return sqrt(norm(p)); }\n\nPoint projection(const Line& l, const Point& p) {\n double t = dot(p - l.a, l.b - l.a) / norm(l.b - l.a);\n return l.a + (l.b - l.a) * t;\n}\nPoint reflection(const Line& l, const Point& p) { return p + (projection(l, p) - p) * 2.0; }\n\ndouble arg(const Point& p) { return atan2(p.y, p.x); }\ndouble radian_to_degree(const double& r) { return r * 180.0 / PI; }\ndouble degree_to_radian(const double& d) { return d * PI / 180.0; }\nPoint polar(const double& r, const double& theta) { return Point(cos(theta), sin(theta)) * r; }\nPoint rotate(const Point& p, const double& theta) {\n return Point(cos(theta) * p.x - sin(theta) * p.y, sin(theta) * p.x + cos(theta) * p.y);\n}\ndouble get_angle(const Point& a, const Point& b, const Point& c) {\n const Point v = b - a, w = c - b;\n double alpha = arg(v), beta = arg(w);\n if (alpha > beta) swap(alpha, beta);\n double theta = beta - alpha;\n return min(theta, 2 * PI - theta);\n}\n\nint ccw(const Point& a, Point b, Point c) {\n b = b - a, c = c - a;\n if (cross(b, c) > EPS) return COUNTER_CLOCKWISE;\n if (cross(b, c) < -EPS) return CLOCKWISE;\n if (dot(b, c) < 0) return ONLINE_BACK;\n if (norm(b) < norm(c)) return ONLINE_FRONT;\n return ON_SEGMENT;\n}\n\nbool orthogonal(const Point& a, const Point& b) { return EQ(dot(a, b), 0.0); }\nbool orthogonal(const Point& a, const Point& b, const Point& c, const Point& d) { return orthogonal(b - a, d - c); }\nbool orthogonal(const Line& l, const Line& m) { return EQ(dot(l.b - l.a, m.b - m.a), 0.0); }\nbool parallel(const Point& a, const Point& b) { return EQ(cross(a, b), 0.0); }\nbool parallel(const Point& a, const Point& b, const Point& c, const Point& d) { return parallel(b - a, d - c); }\nbool parallel(const Line& l, const Line& m) { return EQ(cross(l.b - l.a, m.b - m.a), 0.0); }\n\nbool intersect(const Line& l, const Point& p) { return abs(ccw(l.a, l.b, p)) != COUNTER_CLOCKWISE; }\nbool intersect(const Line& l, const Line& m) {\n return abs(cross(l.b - l.a, m.b - m.a)) > EPS || abs(cross(l.b - l.a, m.b - l.a)) < EPS;\n}\nbool intersect(const Line& l, const Segment& s) {\n return cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < EPS;\n}\nbool intersect(const Segment& s, const Point& p) { return ccw(s.a, s.b, p) == ON_SEGMENT; }\nbool intersect(const Segment& s, const Segment& t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 && ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\nbool intersect(const Circle& c, const Line& l) { return distance(l, c.c) <= c.r + EPS; }\nint intersect(const Circle& c, const Segment& s) {\n Point h = projection(s, c.c);\n double d1 = abs(c.c - s.a), d2 = abs(c.c - s.b);\n if (norm(h - c.c) - c.r * c.r > EPS) return 0;\n if (d1 < c.r + EPS && d2 < c.r + EPS) return 0;\n if ((d1 < c.r - EPS && d2 > c.r + EPS) || (d1 > c.r + EPS && d2 < c.r - EPS)) return 1;\n if (dot(s.a - h, s.b - h) < 0) return 2;\n return 0;\n}\nbool intersect(Circle a, Circle b) {\n int c = count_tangent(a, b);\n return 1 <= c && c <= 3;\n}\nint count_tangent(Circle a, Circle b) {\n if (a.r < b.r) swap(a, b);\n double d = abs(a.c - b.c);\n if (a.r + b.r < d) return 4;\n if (EQ(a.r + b.r, d)) return 3;\n if (a.r - b.r < d) return 2;\n if (EQ(a.r - b.r, d)) return 1;\n return 0;\n}\n\ndouble distance(const Point& a, const Point& b) { return abs(b - a); }\ndouble distance(const Line& l, const Point& p) { return distance(p, projection(l, p)); }\ndouble distance(const Line& l, const Line& m) { return intersect(l, m) ? 0 : distance(l, m.a); }\ndouble distance(const Segment& s, const Point& p) {\n Point h = projection(s, p);\n return intersect(s, h) ? distance(p, h) : min(distance(p, s.a), distance(p, s.b));\n}\ndouble distance(const Segment& s, const Segment& t) {\n return intersect(s, t) ? 0 : min({distance(s, t.a), distance(s, t.b), distance(t, s.a), distance(t, s.b)});\n}\ndouble distance(const Line& l, const Segment& s) {\n return intersect(l, s) ? 0 : min(distance(l, s.a), distance(l, s.b));\n}\n\nPoint crosspoint(const Line& l, const Line& m) {\n assert(intersect(l, m));\n double d1 = cross(l.b - l.a, m.b - m.a), d2 = cross(l.b - l.a, l.b - m.a);\n if (EQ(abs(d1), 0.0) && EQ(abs(d2), 0.0)) return m.a;\n return m.a + (m.b - m.a) * d2 / d1;\n}\nPoint crosspoint(const Segment& s, const Segment& t) {\n assert(intersect(s, t));\n return crosspoint(Line(s), Line(t));\n}\npair<Point, Point> crosspoint(const Circle& c, const Line& l) {\n assert(intersect(c, l));\n Point h = projection(l, c.c);\n Point e = (l.b - l.a) / abs(l.b - l.a) * sqrt(c.r * c.r - norm(h - c.c));\n return minmax(h - e, h + e);\n}\npair<Point, Point> crosspoint(const Circle& c, const Segment& s) {\n assert(intersect(c, s));\n auto res = crosspoint(c, Line(s));\n if (intersect(c, s) == 2) return res;\n return intersect(s, res.first) ? make_pair(res.first, res.first) : make_pair(res.second, res.second);\n}\npair<Point, Point> crosspoint(const Circle& a, const Circle& b) {\n assert(intersect(a, b));\n double d = distance(a.c, b.c);\n double alpha = acos((a.r * a.r + d * d - b.r * b.r) / (2 * a.r * d));\n double theta = arg(b.c - a.c);\n return minmax(a.c + polar(a.r, theta + alpha), a.c + polar(a.r, theta - alpha));\n}\n\nCircle circumcenter(Point a, Point b, const Point& c) {\n a = (a - c) * 0.5;\n b = (b - c) * 0.5;\n Point center = c + crosspoint(Line(a, a * Point(1.0, 1.0)), Line{b, b * Point(1.0, 1.0)});\n return Circle{center, abs(c - center)};\n}\npair<Point, Point> center_given_radius(const Point& a, const Point& b, const double& r) {\n Point m = (b - a) * 0.5;\n double d1 = abs(m);\n assert(!(EQ(d1, 0.0) || d1 > r));\n double d2 = sqrt(r * r - d1 * d1);\n Point n = m * Point(0.0, 1.0) * d2 / d1;\n return minmax(a + m - n, a + m + n);\n}\npair<Point, Point> tangent(const Circle& c, const Point& p) {\n return crosspoint(c, Circle(p, sqrt(norm(c.c - p) - c.r * c.r)));\n}\nvector<Line> common_tangent(Circle a, Circle b) {\n vector<Line> res;\n if (a.r < b.r) swap(a, b);\n double g = distance(a.c, b.c);\n if (EQ(g, 0.0)) return res;\n Point u = (b.c - a.c) / g;\n Point v = rotate(u, PI * 0.5);\n for (int s : {-1, 1}) {\n double h = (a.r + s * b.r) / g;\n if (EQ(1.0 - h * h, 0.0))\n res.emplace_back(a.c + u * a.r, a.c + (u + v) * a.r);\n else if (1.0 - h * h > 0.0) {\n Point U = u * h, V = v * sqrt(1 - h * h);\n res.emplace_back(a.c + (U + V) * a.r, b.c - (U + V) * b.r * s);\n res.emplace_back(a.c + (U - V) * a.r, b.c - (U - V) * b.r * s);\n }\n }\n return res;\n}\n\ndouble area(const Polygon& P) {\n int n = P.size();\n double res = 0;\n for (int i = 0; i < n; i++) res += cross(P[i], P[(i + 1) % n]);\n return res * 0.5;\n}\n\nint contain(const Polygon& P, const Point& p) {\n int n = P.size();\n bool in = false;\n for (int i = 0; i < n; i++) {\n Point a = P[i] - p, b = P[(i + 1) % n] - p;\n if (a.y > b.y) swap(a, b);\n if (a.y <= 0 && 0 < b.y && cross(a, b) < 0) in = !in;\n if (cross(a, b) == 0 && dot(a, b) <= 0) return ON;\n }\n return in ? IN : OUT;\n}\nint contain(const Circle& c, const Point& p) {\n double d = distance(c.c, p);\n return EQ(d, c.r) ? ON : d < c.r ? IN : OUT;\n}\n\nbool is_convex(const Polygon& P) {\n int n = P.size();\n for (int i = 0; i < n; i++) {\n if (ccw(P[(i + n - 1) % n], P[i], P[(i + 1) % n]) == CLOCKWISE) {\n return false;\n }\n }\n return true;\n}\nPolygon convex_hull(Polygon P, bool ONSEG) {\n int n = P.size(), k = 0;\n if (n <= 2) return P;\n sort(P.begin(), P.end());\n Polygon ch(2 * n);\n for (int i = 0; i < n; ch[k++] = P[i++]) {\n if (ONSEG)\n while (k >= 2 && ccw(ch[k - 2], ch[k - 1], P[i]) == CLOCKWISE) k--;\n else\n while (k >= 2 && ccw(ch[k - 2], ch[k - 1], P[i]) != COUNTER_CLOCKWISE) k--;\n }\n for (int i = n - 2, t = k + 1; i >= 0; ch[k++] = P[i--]) {\n if (ONSEG)\n while (k >= t && ccw(ch[k - 2], ch[k - 1], P[i]) == CLOCKWISE) k--;\n else\n while (k >= t && ccw(ch[k - 2], ch[k - 1], P[i]) != COUNTER_CLOCKWISE) k--;\n }\n ch.resize(k - 1);\n int start = 0;\n for (int i = 1; i < k - 1; i++) {\n if (EQ(ch[i].y, ch[start].y) ? ch[i].x < ch[start].x : ch[i].y < ch[start].y) start = i;\n }\n rotate(ch.begin(), ch.begin() + start, ch.end());\n return ch;\n}\n\ndouble convex_diameter(Polygon P) {\n if (!is_convex(P)) P = convex_hull(P, false);\n int n = P.size();\n int is = 0, js = 0;\n for (int i = 1; i < n; i++) {\n if (P[i].y > P[is].y) is = i;\n if (P[i].y < P[js].y) js = i;\n }\n double maxd = norm(P[is] - P[js]);\n int i, maxi, j, maxj;\n i = maxi = is;\n j = maxj = js;\n do {\n if (cross(P[(i + 1) % n] - P[i], P[(j + 1) % n] - P[j]) >= 0)\n j = (j + 1) % n;\n else\n i = (i + 1) % n;\n if (maxd < norm(P[i] - P[j])) {\n maxd = norm(P[i] - P[j]);\n maxi = i;\n maxj = j;\n }\n } while (i != is || j != js);\n return sqrt(maxd);\n}\n\nPolygon convex_cut(const Polygon& P, const Line& l) {\n int n = P.size();\n Polygon res;\n for (int i = 0; i < n; i++) {\n Point cur = P[i], nxt = P[(i + 1) % n];\n if (ccw(l.a, l.b, cur) != CLOCKWISE) res.emplace_back(cur);\n if (ccw(l.a, l.b, cur) * ccw(l.a, l.b, nxt) < 0) res.emplace_back(crosspoint(Segment(cur, nxt), l));\n }\n return res;\n}\n\nvoid solve(int N) {\n Point s, t;\n cin >> s >> t;\n vector<vector<Point>> P(N);\n vector<int> h(N);\n bool ok = true;\n for (int i = 0; i < N; i++) {\n vector<int> x(2), y(2);\n for (int j = 0; j < 2; j++) cin >> x[j] >> y[j];\n if (x[0] <= s.x && s.x <= x[1] && y[0] <= s.y && s.y <= y[1]) ok = false;\n if (x[0] <= t.x && t.x <= x[1] && y[0] <= t.y && t.y <= y[1]) ok = false;\n P[i].emplace_back(x[0], y[0]);\n P[i].emplace_back(x[1], y[0]);\n P[i].emplace_back(x[1], y[1]);\n P[i].emplace_back(x[0], y[1]);\n cin >> h[i];\n }\n\n if (!ok) {\n cout << 0 << '\\n';\n return;\n }\n\n auto check = [&](double x) {\n for (int i = 0; i < N; i++) {\n double Min = 1e9;\n for (int j = 0; j < 4; j++) {\n Min = min(Min, distance(Segment(s, t), Segment(P[i][j], P[i][(j + 1) % 4])));\n }\n if (x < Min) continue;\n if (x < h[i]) return false;\n Min = sqrt(Min * Min + (x - h[i]) * (x - h[i]));\n if (x > Min) return false;\n }\n return true;\n };\n\n double lb = 0, ub = 1e6;\n for (int _ = 0; _ < 100; _++) {\n double mid = (ub + lb) / 2;\n (check(mid) ? lb : ub) = mid;\n }\n\n cout << lb << '\\n';\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n int N;\n while (cin >> N, N) solve(N);\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3240, "score_of_the_acc": -0.1231, "final_rank": 3 }, { "submission_id": "aoj_1157_5386086", "code_snippet": "#define LOCAL\n#include <bits/stdc++.h>\nusing namespace std;\n#pragma region Macros\ntypedef long long ll;\ntypedef __int128_t i128;\ntypedef unsigned int uint;\ntypedef unsigned long long ull;\n#define ALL(x) (x).begin(), (x).end()\n\ntemplate <typename T> istream& operator>>(istream& is, vector<T>& v) {\n for (T& x : v) is >> x;\n return is;\n}\ntemplate <typename T> ostream& operator<<(ostream& os, const vector<T>& v) {\n for (int i = 0; i < (int)v.size(); i++) {\n os << v[i] << (i + 1 == (int)v.size() ? \"\" : \" \");\n }\n return os;\n}\ntemplate <typename T, typename U> ostream& operator<<(ostream& os, const pair<T, U>& p) {\n os << '(' << p.first << ',' << p.second << ')';\n return os;\n}\ntemplate <typename T, typename U, typename V> ostream& operator<<(ostream& os, const tuple<T, U, V>& t) {\n os << '(' << get<0>(t) << ',' << get<1>(t) << ',' << get<2>(t) << ')';\n return os;\n}\ntemplate <typename T, typename U, typename V, typename W> ostream& operator<<(ostream& os, const tuple<T, U, V, W>& t) {\n os << '(' << get<0>(t) << ',' << get<1>(t) << ',' << get<2>(t) << ',' << get<3>(t) << ')';\n return os;\n}\ntemplate <typename T, typename U> ostream& operator<<(ostream& os, const map<T, U>& m) {\n os << '{';\n for (auto itr = m.begin(); itr != m.end();) {\n os << '(' << itr->first << ',' << itr->second << ')';\n if (++itr != m.end()) os << ',';\n }\n os << '}';\n return os;\n}\ntemplate <typename T, typename U> ostream& operator<<(ostream& os, const unordered_map<T, U>& m) {\n os << '{';\n for (auto itr = m.begin(); itr != m.end();) {\n os << '(' << itr->first << ',' << itr->second << ')';\n if (++itr != m.end()) os << ',';\n }\n os << '}';\n return os;\n}\ntemplate <typename T> ostream& operator<<(ostream& os, const set<T>& s) {\n os << '{';\n for (auto itr = s.begin(); itr != s.end();) {\n os << *itr;\n if (++itr != s.end()) os << ',';\n }\n os << '}';\n return os;\n}\ntemplate <typename T> ostream& operator<<(ostream& os, const multiset<T>& s) {\n os << '{';\n for (auto itr = s.begin(); itr != s.end();) {\n os << *itr;\n if (++itr != s.end()) os << ',';\n }\n os << '}';\n return os;\n}\ntemplate <typename T> ostream& operator<<(ostream& os, const unordered_set<T>& s) {\n os << '{';\n for (auto itr = s.begin(); itr != s.end();) {\n os << *itr;\n if (++itr != s.end()) os << ',';\n }\n os << '}';\n return os;\n}\ntemplate <typename T> ostream& operator<<(ostream& os, const deque<T>& v) {\n for (int i = 0; i < (int)v.size(); i++) {\n os << v[i] << (i + 1 == (int)v.size() ? \"\" : \" \");\n }\n return os;\n}\n\nvoid debug_out() { cerr << '\\n'; }\ntemplate <class Head, class... Tail> void debug_out(Head&& head, Tail&&... tail) {\n cerr << head;\n if (sizeof...(Tail) > 0) cerr << \", \";\n debug_out(move(tail)...);\n}\n#ifdef LOCAL\n#define debug(...) \\\n cerr << \" \"; \\\n cerr << #__VA_ARGS__ << \" :[\" << __LINE__ << \":\" << __FUNCTION__ << \"]\" << '\\n'; \\\n cerr << \" \"; \\\n debug_out(__VA_ARGS__)\n#else\n#define debug(...) 42\n#endif\n\ntemplate <typename T> T gcd(T x, T y) { return y != 0 ? gcd(y, x % y) : x; }\ntemplate <typename T> T lcm(T x, T y) { return x / gcd(x, y) * y; }\n\ntemplate <class T1, class T2> inline bool chmin(T1& a, T2 b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <class T1, class T2> inline bool chmax(T1& a, T2 b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n#pragma endregion\n\n/**\n * @brief geometry\n * @docs docs/geometry/geometry.md\n */\nconst double EPS = 1e-8, PI = acos(-1);\ninline bool EQ(double a, double b) { return fabs(b - a) < EPS; }\n\nstruct Point {\n double x, y;\n Point() {}\n Point(double x, double y) : x(x), y(y) {}\n Point operator-() const { return Point(-x, -y); }\n Point operator+(Point p) const { return Point(x + p.x, y + p.y); }\n Point operator-(Point p) const { return Point(x - p.x, y - p.y); }\n Point operator*(double t) const { return Point(x * t, y * t); }\n Point operator*(Point p) const { return Point(x * p.x - y * p.y, x * p.y + y * p.x); }\n Point operator/(double t) const { return Point(x / t, y / t); }\n bool operator<(const Point& p) const { return x != p.x ? x < p.x : y < p.y; }\n bool operator==(const Point& p) const { return EQ(x, p.x) && EQ(y, p.y); }\n friend istream& operator>>(istream& is, Point& p) {\n is >> p.x >> p.y;\n return is;\n }\n friend ostream& operator<<(ostream& os, Point p) {\n os << fixed << setprecision(10) << p.x << ' ' << p.y;\n return os;\n }\n};\n\nstruct Line {\n Point a, b;\n Line() {}\n Line(Point a, Point b) : a(a), b(b) {}\n friend istream& operator>>(istream& is, Line& l) {\n is >> l.a >> l.b;\n return is;\n }\n friend ostream& operator<<(ostream& os, Line l) {\n os << l.a << \" to \" << l.b;\n return os;\n }\n};\n\nstruct Segment : Line {\n Segment() {}\n Segment(Point a, Point b) : Line(a, b) {}\n};\n\nstruct Circle {\n Point c;\n double r;\n Circle() {}\n Circle(Point c, double r) : c(c), r(r) {}\n friend istream& operator>>(istream& is, Circle& c) {\n is >> c.c >> c.r;\n return is;\n }\n friend ostream& operator<<(ostream& os, Circle& c) {\n os << c.c << ' ' << c.r;\n return os;\n }\n};\n\nusing Polygon = vector<Point>;\n\ndouble dot(const Point&, const Point&);\ndouble cross(const Point&, const Point&);\ndouble norm(const Point&);\ndouble abs(const Point&);\nPoint projection(const Line&, const Point&);\nPoint reflection(const Line&, const Point&);\ndouble arg(const Point&);\ndouble radian_to_degree(const double&);\ndouble degree_to_radian(const double&);\nPoint polar(const double&, const double&);\nPoint rotate(const Point&, const double&);\ndouble get_angle(const Point&, const Point&, const Point&);\nenum { COUNTER_CLOCKWISE = 1, CLOCKWISE = -1, ONLINE_BACK = 2, ONLINE_FRONT = -2, ON_SEGMENT = 0 };\nint ccw(const Point&, Point, Point);\nbool orthogonal(const Point&, const Point&);\nbool orthogonal(const Point&, const Point&, const Point&, const Point&);\nbool orthogonal(const Line&, const Line&);\nbool parallel(const Point&, const Point&);\nbool parallel(const Point&, const Point&);\nbool parallel(const Point&, const Point&, const Point&, const Point&);\nbool parallel(const Line&, const Line&);\nbool intersect(const Line&, const Point&);\nbool intersect(const Line&, const Line&);\nbool intersect(const Line&, const Segment&);\nbool intersect(const Segment&, const Point&);\nbool intersect(const Segment&, const Segment&);\nbool intersect(const Circle&, const Line&);\nint intersect(const Circle&, const Segment&);\nbool intersect(Circle, Circle);\nint count_tangent(Circle, Circle);\ndouble distance(const Point&, const Point&);\ndouble distance(const Line&, const Point&);\ndouble distance(const Line&, const Line&);\ndouble distance(const Segment&, const Point&);\ndouble distance(const Segment&, const Segment&);\ndouble distance(const Line&, const Segment&);\nPoint crosspoint(const Line&, const Line&);\nPoint crosspoint(const Segment&, const Segment&);\npair<Point, Point> crosspoint(const Circle&, const Line&);\npair<Point, Point> crosspoint(const Circle&, const Segment&);\npair<Point, Point> crosspoint(const Circle&, const Circle&);\nCircle circumcenter(Point, Point, const Point&);\npair<Point, Point> center_given_radius(const Point&, const Point&, const double&);\npair<Point, Point> tangent(const Circle&, const Point&);\nvector<Line> common_tangent(Circle, Circle);\ndouble area(const Polygon&);\nenum { OUT, ON, IN };\nint contain(const Polygon&, const Point&);\nint contain(const Circle&, const Point&);\nbool is_convex(const Polygon&);\nPolygon convex_hull(Polygon, bool);\ndouble convex_diameter(Polygon);\nPolygon convex_cut(const Polygon&, const Line&);\n\ndouble dot(const Point& a, const Point& b) { return a.x * b.x + a.y * b.y; }\ndouble cross(const Point& a, const Point& b) { return a.x * b.y - a.y * b.x; }\ndouble norm(const Point& p) { return p.x * p.x + p.y * p.y; }\ndouble abs(const Point& p) { return sqrt(norm(p)); }\n\nPoint projection(const Line& l, const Point& p) {\n double t = dot(p - l.a, l.b - l.a) / norm(l.b - l.a);\n return l.a + (l.b - l.a) * t;\n}\nPoint reflection(const Line& l, const Point& p) { return p + (projection(l, p) - p) * 2.0; }\n\ndouble arg(const Point& p) { return atan2(p.y, p.x); }\ndouble radian_to_degree(const double& r) { return r * 180.0 / PI; }\ndouble degree_to_radian(const double& d) { return d * PI / 180.0; }\nPoint polar(const double& r, const double& theta) { return Point(cos(theta), sin(theta)) * r; }\nPoint rotate(const Point& p, const double& theta) {\n return Point(cos(theta) * p.x - sin(theta) * p.y, sin(theta) * p.x + cos(theta) * p.y);\n}\ndouble get_angle(const Point& a, const Point& b, const Point& c) {\n const Point v = b - a, w = c - b;\n double alpha = arg(v), beta = arg(w);\n if (alpha > beta) swap(alpha, beta);\n double theta = beta - alpha;\n return min(theta, 2 * PI - theta);\n}\n\nint ccw(const Point& a, Point b, Point c) {\n b = b - a, c = c - a;\n if (cross(b, c) > EPS) return COUNTER_CLOCKWISE;\n if (cross(b, c) < -EPS) return CLOCKWISE;\n if (dot(b, c) < 0) return ONLINE_BACK;\n if (norm(b) < norm(c)) return ONLINE_FRONT;\n return ON_SEGMENT;\n}\n\nbool orthogonal(const Point& a, const Point& b) { return EQ(dot(a, b), 0.0); }\nbool orthogonal(const Point& a, const Point& b, const Point& c, const Point& d) { return orthogonal(b - a, d - c); }\nbool orthogonal(const Line& l, const Line& m) { return EQ(dot(l.b - l.a, m.b - m.a), 0.0); }\nbool parallel(const Point& a, const Point& b) { return EQ(cross(a, b), 0.0); }\nbool parallel(const Point& a, const Point& b, const Point& c, const Point& d) { return parallel(b - a, d - c); }\nbool parallel(const Line& l, const Line& m) { return EQ(cross(l.b - l.a, m.b - m.a), 0.0); }\n\nbool intersect(const Line& l, const Point& p) { return abs(ccw(l.a, l.b, p)) != COUNTER_CLOCKWISE; }\nbool intersect(const Line& l, const Line& m) {\n return abs(cross(l.b - l.a, m.b - m.a)) > EPS || abs(cross(l.b - l.a, m.b - l.a)) < EPS;\n}\nbool intersect(const Line& l, const Segment& s) {\n return cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < EPS;\n}\nbool intersect(const Segment& s, const Point& p) { return ccw(s.a, s.b, p) == ON_SEGMENT; }\nbool intersect(const Segment& s, const Segment& t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 && ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\nbool intersect(const Circle& c, const Line& l) { return distance(l, c.c) <= c.r + EPS; }\nint intersect(const Circle& c, const Segment& s) {\n Point h = projection(s, c.c);\n double d1 = abs(c.c - s.a), d2 = abs(c.c - s.b);\n if (norm(h - c.c) - c.r * c.r > EPS) return 0;\n if (d1 < c.r + EPS && d2 < c.r + EPS) return 0;\n if ((d1 < c.r - EPS && d2 > c.r + EPS) || (d1 > c.r + EPS && d2 < c.r - EPS)) return 1;\n if (dot(s.a - h, s.b - h) < 0) return 2;\n return 0;\n}\nbool intersect(Circle a, Circle b) {\n int c = count_tangent(a, b);\n return 1 <= c && c <= 3;\n}\nint count_tangent(Circle a, Circle b) {\n if (a.r < b.r) swap(a, b);\n double d = abs(a.c - b.c);\n if (a.r + b.r < d) return 4;\n if (EQ(a.r + b.r, d)) return 3;\n if (a.r - b.r < d) return 2;\n if (EQ(a.r - b.r, d)) return 1;\n return 0;\n}\n\ndouble distance(const Point& a, const Point& b) { return abs(b - a); }\ndouble distance(const Line& l, const Point& p) { return distance(p, projection(l, p)); }\ndouble distance(const Line& l, const Line& m) { return intersect(l, m) ? 0 : distance(l, m.a); }\ndouble distance(const Segment& s, const Point& p) {\n Point h = projection(s, p);\n return intersect(s, h) ? distance(p, h) : min(distance(p, s.a), distance(p, s.b));\n}\ndouble distance(const Segment& s, const Segment& t) {\n return intersect(s, t) ? 0 : min({distance(s, t.a), distance(s, t.b), distance(t, s.a), distance(t, s.b)});\n}\ndouble distance(const Line& l, const Segment& s) {\n return intersect(l, s) ? 0 : min(distance(l, s.a), distance(l, s.b));\n}\n\nPoint crosspoint(const Line& l, const Line& m) {\n assert(intersect(l, m));\n double d1 = cross(l.b - l.a, m.b - m.a), d2 = cross(l.b - l.a, l.b - m.a);\n if (EQ(abs(d1), 0.0) && EQ(abs(d2), 0.0)) return m.a;\n return m.a + (m.b - m.a) * d2 / d1;\n}\nPoint crosspoint(const Segment& s, const Segment& t) {\n assert(intersect(s, t));\n return crosspoint(Line(s), Line(t));\n}\npair<Point, Point> crosspoint(const Circle& c, const Line& l) {\n assert(intersect(c, l));\n Point h = projection(l, c.c);\n Point e = (l.b - l.a) / abs(l.b - l.a) * sqrt(c.r * c.r - norm(h - c.c));\n return minmax(h - e, h + e);\n}\npair<Point, Point> crosspoint(const Circle& c, const Segment& s) {\n assert(intersect(c, s));\n auto res = crosspoint(c, Line(s));\n if (intersect(c, s) == 2) return res;\n return intersect(s, res.first) ? make_pair(res.first, res.first) : make_pair(res.second, res.second);\n}\npair<Point, Point> crosspoint(const Circle& a, const Circle& b) {\n assert(intersect(a, b));\n double d = distance(a.c, b.c);\n double alpha = acos((a.r * a.r + d * d - b.r * b.r) / (2 * a.r * d));\n double theta = arg(b.c - a.c);\n return minmax(a.c + polar(a.r, theta + alpha), a.c + polar(a.r, theta - alpha));\n}\n\nCircle circumcenter(Point a, Point b, const Point& c) {\n a = (a - c) * 0.5;\n b = (b - c) * 0.5;\n Point center = c + crosspoint(Line(a, a * Point(1.0, 1.0)), Line{b, b * Point(1.0, 1.0)});\n return Circle{center, abs(c - center)};\n}\npair<Point, Point> center_given_radius(const Point& a, const Point& b, const double& r) {\n Point m = (b - a) * 0.5;\n double d1 = abs(m);\n assert(!(EQ(d1, 0.0) || d1 > r));\n double d2 = sqrt(r * r - d1 * d1);\n Point n = m * Point(0.0, 1.0) * d2 / d1;\n return minmax(a + m - n, a + m + n);\n}\npair<Point, Point> tangent(const Circle& c, const Point& p) {\n return crosspoint(c, Circle(p, sqrt(norm(c.c - p) - c.r * c.r)));\n}\nvector<Line> common_tangent(Circle a, Circle b) {\n vector<Line> res;\n if (a.r < b.r) swap(a, b);\n double g = distance(a.c, b.c);\n if (EQ(g, 0.0)) return res;\n Point u = (b.c - a.c) / g;\n Point v = rotate(u, PI * 0.5);\n for (int s : {-1, 1}) {\n double h = (a.r + s * b.r) / g;\n if (EQ(1.0 - h * h, 0.0))\n res.emplace_back(a.c + u * a.r, a.c + (u + v) * a.r);\n else if (1.0 - h * h > 0.0) {\n Point U = u * h, V = v * sqrt(1 - h * h);\n res.emplace_back(a.c + (U + V) * a.r, b.c - (U + V) * b.r * s);\n res.emplace_back(a.c + (U - V) * a.r, b.c - (U - V) * b.r * s);\n }\n }\n return res;\n}\n\ndouble area(const Polygon& P) {\n int n = P.size();\n double res = 0;\n for (int i = 0; i < n; i++) res += cross(P[i], P[(i + 1) % n]);\n return res * 0.5;\n}\n\nint contain(const Polygon& P, const Point& p) {\n int n = P.size();\n bool in = false;\n for (int i = 0; i < n; i++) {\n Point a = P[i] - p, b = P[(i + 1) % n] - p;\n if (a.y > b.y) swap(a, b);\n if (a.y <= 0 && 0 < b.y && cross(a, b) < 0) in = !in;\n if (cross(a, b) == 0 && dot(a, b) <= 0) return ON;\n }\n return in ? IN : OUT;\n}\nint contain(const Circle& c, const Point& p) {\n double d = distance(c.c, p);\n return EQ(d, c.r) ? ON : d < c.r ? IN : OUT;\n}\n\nbool is_convex(const Polygon& P) {\n int n = P.size();\n for (int i = 0; i < n; i++) {\n if (ccw(P[(i + n - 1) % n], P[i], P[(i + 1) % n]) == CLOCKWISE) {\n return false;\n }\n }\n return true;\n}\nPolygon convex_hull(Polygon P, bool ONSEG) {\n int n = P.size(), k = 0;\n if (n <= 2) return P;\n sort(P.begin(), P.end());\n Polygon ch(2 * n);\n for (int i = 0; i < n; ch[k++] = P[i++]) {\n if (ONSEG)\n while (k >= 2 && ccw(ch[k - 2], ch[k - 1], P[i]) == CLOCKWISE) k--;\n else\n while (k >= 2 && ccw(ch[k - 2], ch[k - 1], P[i]) != COUNTER_CLOCKWISE) k--;\n }\n for (int i = n - 2, t = k + 1; i >= 0; ch[k++] = P[i--]) {\n if (ONSEG)\n while (k >= t && ccw(ch[k - 2], ch[k - 1], P[i]) == CLOCKWISE) k--;\n else\n while (k >= t && ccw(ch[k - 2], ch[k - 1], P[i]) != COUNTER_CLOCKWISE) k--;\n }\n ch.resize(k - 1);\n int start = 0;\n for (int i = 1; i < k - 1; i++) {\n if (EQ(ch[i].y, ch[start].y) ? ch[i].x < ch[start].x : ch[i].y < ch[start].y) start = i;\n }\n rotate(ch.begin(), ch.begin() + start, ch.end());\n return ch;\n}\n\ndouble convex_diameter(Polygon P) {\n if (!is_convex(P)) P = convex_hull(P, false);\n int n = P.size();\n int is = 0, js = 0;\n for (int i = 1; i < n; i++) {\n if (P[i].y > P[is].y) is = i;\n if (P[i].y < P[js].y) js = i;\n }\n double maxd = norm(P[is] - P[js]);\n int i, maxi, j, maxj;\n i = maxi = is;\n j = maxj = js;\n do {\n if (cross(P[(i + 1) % n] - P[i], P[(j + 1) % n] - P[j]) >= 0)\n j = (j + 1) % n;\n else\n i = (i + 1) % n;\n if (maxd < norm(P[i] - P[j])) {\n maxd = norm(P[i] - P[j]);\n maxi = i;\n maxj = j;\n }\n } while (i != is || j != js);\n return sqrt(maxd);\n}\n\nPolygon convex_cut(const Polygon& P, const Line& l) {\n int n = P.size();\n Polygon res;\n for (int i = 0; i < n; i++) {\n Point cur = P[i], nxt = P[(i + 1) % n];\n if (ccw(l.a, l.b, cur) != CLOCKWISE) res.emplace_back(cur);\n if (ccw(l.a, l.b, cur) * ccw(l.a, l.b, nxt) < 0) res.emplace_back(crosspoint(Segment(cur, nxt), l));\n }\n return res;\n}\n\nconst int INF = 1e9;\nconst long long IINF = 1e18;\nconst int dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1};\nconst char dir[4] = {'D', 'R', 'U', 'L'};\nconst long long MOD = 1000000007;\n// const long long MOD = 998244353;\n\nvoid solve(int N) {\n Point s, t;\n cin >> s >> t;\n vector<vector<Point>> P(N);\n vector<int> h(N);\n bool ok = true;\n for (int i = 0; i < N; i++) {\n vector<int> x(2), y(2);\n for (int j = 0; j < 2; j++) cin >> x[j] >> y[j];\n if (x[0] <= s.x && s.x <= x[1] && y[0] <= s.y && s.y <= y[1]) ok = false;\n if (x[0] <= t.x && t.x <= x[1] && y[0] <= t.y && t.y <= y[1]) ok = false;\n P[i].emplace_back(x[0], y[0]);\n P[i].emplace_back(x[1], y[0]);\n P[i].emplace_back(x[1], y[1]);\n P[i].emplace_back(x[0], y[1]);\n cin >> h[i];\n }\n\n if (!ok) {\n cout << 0 << '\\n';\n return;\n }\n\n auto check = [&](double x) {\n for (int i = 0; i < N; i++) {\n double Min = INF;\n for (int j = 0; j < 4; j++) {\n Min = min(Min, distance(Segment(s, t), Segment(P[i][j], P[i][(j + 1) % 4])));\n }\n if (x < Min) continue;\n if (x < h[i]) return false;\n Min = sqrt(Min * Min + (x - h[i]) * (x - h[i]));\n if (x > Min) return false;\n }\n return true;\n };\n\n double lb = 0, ub = 100000;\n for (int _ = 0; _ < 100; _++) {\n double mid = (ub + lb) / 2;\n (check(mid) ? lb : ub) = mid;\n }\n\n cout << lb << '\\n';\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n int N;\n while (cin >> N, N) solve(N);\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3164, "score_of_the_acc": -0.0286, "final_rank": 1 }, { "submission_id": "aoj_1157_5284569", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,a,...) for(int i = (a)*(strlen(#__VA_ARGS__)!=0);i<(int)(strlen(#__VA_ARGS__)?__VA_ARGS__:(a));++i)\n#define per(i,a,...) for(int i = (strlen(#__VA_ARGS__)?__VA_ARGS__:(a))-1;i>=(int)(strlen(#__VA_ARGS__)?(a):0);--i)\n#define foreach(i, n) for(auto &i:(n))\n#define all(x) (x).begin(), (x).end()\n#define bit(x) (1ll << (x))\n#define lambda(RES_TYPE, ...) (function<RES_TYPE(__VA_ARGS__)>)[&](__VA_ARGS__) -> RES_TYPE\n#define method(FUNC_NAME, RES_TYPE, ...) function<RES_TYPE(__VA_ARGS__)> FUNC_NAME = lambda(RES_TYPE, __VA_ARGS__)\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\n//const ll MOD = (ll)1e9+7;\nconst ll MOD = 998244353;\nconst int INF = (ll)1e9+7;\nconst ll INFLL = (ll)1e18;\nconst double EPS = 1e-6;\ntemplate<class t>\nusing vvector = vector<vector<t>>;\ntemplate<class t>\nusing vvvector = vector<vector<vector<t>>>;\ntemplate<class t>\nusing priority_queuer = priority_queue<t, vector<t>, greater<t>>;\ntemplate<class t, class u> bool chmax(t &a, u b){if(a<b){a=b;return true;}return false;}\ntemplate<class t, class u> bool chmin(t &a, u b){if(a>b){a=b;return true;}return false;}\n#ifdef DEBUG\n#define debug(x) cout<<\"LINE \"<<__LINE__<<\": \"<<#x<<\" = \"<<x<<endl;\n#else\n#define debug(x) (void)0\n#endif\n\nnamespace templates{\n ll modpow(ll x, ll b,ll mod=MOD){\n ll res = 1;\n while(b){\n if(b&1)res = res * x % mod;\n x = x * x % mod;\n b>>=1;\n }\n return res;\n }\n\n ll modinv(ll x){\n return modpow(x, MOD-2);\n }\n\n bool was_output = false;\n template<class t>\n void output(t a){\n if(was_output)cout << \" \";\n cout << a;\n was_output = true;\n }\n void outendl(){\n was_output = false;\n cout << endl;\n }\n\n template<class t>\n istream& operator>>(istream&is, vector<t>&x){\n for(auto &i:x)is >> i;\n return is;\n }\n\n template<class t, class u>\n istream& operator>>(istream&is, pair<t, u>&x){\n is >> x.first >> x.second;\n return is;\n }\n\n template<class t>\n ostream& operator<<(ostream&os, vector<t> &v){\n os << \"{\";\n for(t &i:v){\n os << i << \", \";\n }\n os << \"}\";\n return os;\n }\n\n template<class t = long long>\n t in(){\n t res; cin >> res; return res;\n }\n\n template<class t>\n void out(t x){\n cout << x;\n }\n\n\n template<class t>\n vector<t> sorted(vector<t> line,function<bool(t,t)> comp=[](t a,t b){return a<b;}){\n sort(line.begin(),line.end(),comp);\n return line;\n }\n\n template<class t>\n vector<t> reversed(vector<t> line){\n reverse(line.begin(),line.end());\n return line;\n }\n string reversed(string str){\n reverse(str.begin(),str.end());\n return str;\n }\n\n long long gcd(long long a,long long b){\n while(b){\n a %= b;\n swap(a,b);\n }\n return a;\n }\n\n long long lcm(long long a,long long b){\n return a / gcd(a,b) * b;\n }\n}\n\nusing namespace templates;\nclass vector2 {\npublic:\n double x;\n double y;\n vector2():x(0),y(0){}\n vector2(double a, double b):x(a),y(b){}\n vector2(const vector2 &o):x(o.x),y(o.y){}\n vector2 inv(){return vector2(x,-y)/(x*x+y*y);}\n\n vector2 &operator+=(vector2 o){x+=o.x;y+=o.y;return *this;}\n vector2& operator-=(vector2 o){x-=o.x;y-=o.y;return *this;}\n vector2 &operator*=(double o){x*=o;y*=o;return *this;}\n vector2& operator*=(vector2 o){return (*this)=vector2(x*o.x-y*o.y,x*o.y+y*o.x);}\n vector2 &operator/=(double o){x/=o;y/=o;return *this;}\n vector2& operator/=(vector2 o){return (*this)*=o.inv();}\n\n vector2 operator+(vector2 o){return vector2(*this)+=o;}\n vector2 operator-(vector2 o){return vector2(*this)-=o;}\n vector2 operator*(double o) {return vector2(*this)*=o;}\n vector2 operator*(vector2 o){return vector2(*this)*=o;}\n vector2 operator/(double o) {return vector2(*this)/=o;}\n vector2 operator/(vector2 o){return vector2(*this)/=o;}\n bool operator==(vector2 o){return std::abs(x-o.x)<=EPS and std::abs(y-o.y)<=EPS;}\n\n static vector2 polar(double rad,double r=1){return vector2(r*cos(rad),r*sin(rad));}\n double mag(){return x*x + y* y;}\n double abs(){return sqrt(mag());}\n vector2 normal(){return (*this)/abs();}\n double dot(vector2 o){return x*o.x+y*o.y;}\n double cross(vector2 o){return x*o.y-y*o.x;}\n};\n\nostream& operator<<(ostream &os,vector2 v){\n os << v.x << \" \" << v.y;\n return os;\n}\nistream& operator>>(istream &is,vector2 &v){\n is >> v.x >> v.y;\n return is;\n}\n\nvector2 polar(double rad,double r=1) {return vector2::polar(rad,r);}\ndouble mag(vector2 x){return x.mag();}\ndouble abs(vector2 x){return x.abs();}\nvector2 normal(vector2 x){return x.normal();}\ndouble dot(vector2 x,vector2 y){return x.dot(y);}\ndouble cross(vector2 x,vector2 y){return x.cross(y);}\n\n\ndouble func(int n){\n vector2 start = in<vector2>();\n vector2 end = in<vector2>();\n vvector<double> xs(n,vector<double>(2));\n vvector<double> ys(n,vector<double>(2));\n vector<double> hs(n);\n rep(i,n){\n rep(j,2){\n xs[i][j] = in<double>();\n ys[i][j] = in<double>();\n }\n hs[i] = in<double>();\n }\n method(compres,vector2,vector2 p,vector2 from,vector2 end){\n vector2 v1 = p - from;\n vector2 v2 = end - from;\n vector2 n = normal(v2);\n double dis = dot(n,v1);\n chmin(dis,abs(v2));\n chmax(dis,0);\n return p - n * dis;\n };\n method(dist,double,vector2 p,double r,int n){\n rep(i,2){\n p = compres(p,vector2(xs[n][0],ys[n][0]),vector2(xs[n][1-i],ys[n][i]));\n }\n double d = max<double>(0,r-hs[n]);\n\n return sqrt(mag(p-vector2(xs[n][0],ys[n][0]))+d*d);\n };\n method(calc,vector2,double t){\n return start + (end - start) * t;\n };\n method(check,bool,double r){\n rep(i,n){\n double lp = 0;\n double rp = 1;\n rep(j,100){\n double mid1 = (lp + lp + rp) / 3;\n double mid2 = (lp + rp + rp) / 3;\n if(dist(calc(mid1),r,i)<dist(calc(mid2),r,i)){\n rp = mid2;\n }else{\n lp = mid1;\n }\n }\n if(dist(calc(lp),r,i)<r+1e-6)return false;\n }\n return true;\n };\n double lp = 0;\n double rp = 10000;\n rep(i,100){\n double mid = (lp + rp) / 2;\n if(check(mid)){\n lp = mid;\n }else{\n rp = mid;\n }\n }\n return lp;\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n while(true){\n int n = in();\n if(n==0)break;\n printf(\"%.20lf\\n\",func(n));\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1410, "memory_kb": 3540, "score_of_the_acc": -1.4677, "final_rank": 19 }, { "submission_id": "aoj_1157_5036518", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define DEBUG\n#ifdef DEBUG\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << '(' << p.first << ',' << p.second << ')';\n return os;\n}\ntemplate <class T> ostream &operator<<(ostream &os, const vector<T> &v) {\n os << '{';\n for(int i = 0; i < (int)v.size(); i++) {\n if(i) { os << ','; }\n os << v[i];\n }\n os << '}';\n return os;\n}\nvoid debugg() { cerr << endl; }\ntemplate <class T, class... Args>\nvoid debugg(const T &x, const Args &... args) {\n cerr << \" \" << x;\n debugg(args...);\n}\n#define debug(...) \\\n cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"]: \", debugg(__VA_ARGS__)\n#define dump(x) cerr << __LINE__ << \" \" << #x << \" = \" << (x) << endl\n#else\n#define debug(...) (void(0))\n#define dump(x) (void(0))\n#endif\nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vl;\ntypedef vector<vl> vvl;\ntypedef vector<char> vc;\ntypedef vector<string> vs;\ntypedef vector<bool> vb;\ntypedef vector<double> vd;\ntypedef pair<ll,ll> P;\ntypedef pair<int,int> pii;\ntypedef vector<P> vpl;\ntypedef tuple<ll,ll,ll> tapu;\n#define rep(i,n) for(int i=0; i<(n); i++)\n#define REP(i,a,b) for(int i=(a); i<(b); i++)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\nconst int inf = 1<<30;\nconst ll linf = 1LL<<62;\nconst int MAX = 510000;\nll dy[8] = {0,-1,0,1,1,-1,-1,1};\nll dx[8] = {-1,0,1,0,1,-1,1,-1};\nconst double pi = acos(-1);\nconst double eps = 1e-7;\ntemplate<typename T1,typename T2> inline bool chmin(T1 &a,T2 b){\n\tif(a>b){\n\t\ta = b; return true;\n\t}\n\telse return false;\n}\ntemplate<typename T1,typename T2> inline bool chmax(T1 &a,T2 b){\n\tif(a<b){\n\t\ta = b; return true;\n\t}\n\telse return false;\n}\ntemplate<typename T> inline void print(T &a){\n int sz = a.size();\n for(auto itr = a.begin(); itr != a.end(); itr++){\n\t\tcout << *itr;\n sz--;\n if(sz) cout << \" \";\n\t}\n cout << \"\\n\";\n}\ntemplate<typename T1,typename T2> inline void print2(T1 a, T2 b){\n\tcout << a << \" \" << b << \"\\n\";\n}\ntemplate<typename T1,typename T2,typename T3> inline void print3(T1 a, T2 b, T3 c){\n\tcout << a << \" \" << b << \" \" << c << \"\\n\";\n}\nvoid mark() {cout << \"#\" << \"\\n\";}\nll pcount(ll x) {return __builtin_popcountll(x);}\nconst int mod = 1e9 + 7;\n//const int mod = 998244353;\n\nnamespace geometry {\n // Point : 複素数型を位置ベクトルとして扱う\n // 実軸(real)をx軸、挙軸(imag)をy軸として見る\n using D = double;\n using Point = complex<D>;\n const D EPS = 1e-7;\n const D PI = acosl(-1);\n\n inline bool equal(const D &a, const D &b) { return fabs(a - b) < EPS; }\n\n // 単位ベクトル(unit vector)を求める\n Point unitVector(const Point &a) { return a / abs(a); }\n\n // 法線ベクトル(normal vector)を求める\n // 90度回転した単位ベクトルをかける\n // -90度がよければPoint(0, -1)をかける\n Point normalVector(const Point &a) { return a * Point(0, 1); }\n\n // 内積(dot product) : a・b = |a||b|cosΘ\n D dot(const Point &a, const Point &b) {\n return (a.real() * b.real() + a.imag() * b.imag());\n }\n\n // 外積(cross product) : a×b = |a||b|sinΘ\n D cross(const Point &a, const Point &b) {\n return (a.real() * b.imag() - a.imag() * b.real());\n }\n\n // 点pを反時計回りにtheta度回転\n // thetaはラジアン!!!\n Point rotate(const Point &p, const D &theta) {\n return Point(cos(theta) * p.real() - sin(theta) * p.imag(),\n sin(theta) * p.real() + cos(theta) * p.imag());\n }\n\n // ラジアン->度\n D radianToDegree(const D &radian) { return radian * 180.0 / PI; }\n\n // 度->ラジアン\n D degreeToRadian(const D &degree) { return degree * PI / 180.0; }\n\n // 点の回転方向\n // 点a, b, cの位置関係について(aが基準点)\n int ccw(const Point &a, Point b, Point c) {\n b -= a, c -= a;\n // 点a, b, c が\n // 反時計回りの時、\n if(cross(b, c) > EPS) return 1;\n // 時計回りの時、\n if(cross(b, c) < -EPS) return -1;\n // c, a, bがこの順番で同一直線上にある時、\n if(dot(b, c) < 0) return 2;\n // a, b, cがこの順番で同一直線上にある場合、\n if(norm(b) < norm(c)) return -2;\n // cが線分ab上にある場合、\n return 0;\n }\n\n // Line : 直線を表す構造体\n // b - a で直線・線分を表せる\n struct Line {\n Point a, b;\n Line() = default;\n Line(Point a, Point b) : a(a), b(b) {}\n // Ax+By=C\n Line(D A, D B, D C) {\n if(equal(A, 0)) {\n a = Point(0, C / B), b = Point(1, C / B);\n } else if(equal(B, 0)) {\n b = Point(C / A, 0), b = Point(C / A, 1);\n } else {\n a = Point(0, C / B), b = Point(C / A, 0);\n }\n }\n };\n\n // Segment : 線分を表す構造体\n // Lineと同じ\n struct Segment : Line {\n Segment() = default;\n\n Segment(Point a, Point b) : Line(a, b) {}\n };\n\n // Circle : 円を表す構造体\n // pが中心の位置ベクトル、rは半径\n struct Circle {\n Point p;\n D r;\n\n Circle() = default;\n\n Circle(Point p, D r) : p(p), r(r) {}\n };\n\n // 2直線の直交判定 : a⊥b <=> dot(a, b) = 0\n bool isOrthogonal(const Line &a, const Line &b) {\n return equal(dot(a.b - a.a, b.b - b.a), 0);\n }\n // 2直線の平行判定 : a//b <=> cross(a, b) = 0\n bool isParallel(const Line &a, const Line &b) {\n return equal(cross(a.b - a.a, b.b - b.a), 0);\n }\n\n // 点cが直線ab上にあるか\n bool isPointOnLine(const Point &a, const Point &b, const Point &c) {\n return isParallel(Line(a, b), Line(a, c));\n }\n\n // 点cが\"線分\"ab上にあるか\n bool isPointOnSegment(const Point &a, const Point &b, const Point &c) {\n // |a-c| + |c-b| <= |a-b| なら線分上\n return (abs(a - c) + abs(c - b) < abs(a - b) + EPS);\n }\n\n // 直線lと点pの距離を求める\n D distanceBetweenLineAndPoint(const Line &l, const Point &p) {\n return abs(cross(l.b - l.a, p - l.a)) / abs(l.b - l.a);\n }\n\n // 線分lと点pの距離を求める\n // 定義:点pから「線分lのどこか」への最短距離\n D distanceBetweenSegmentAndPoint(const Segment &l, const Point &p) {\n if(dot(l.b - l.a, p - l.a) < EPS) return abs(p - l.a);\n if(dot(l.a - l.b, p - l.b) < EPS) return abs(p - l.b);\n return abs(cross(l.b - l.a, p - l.a)) / abs(l.b - l.a);\n }\n\n // 直線s, tの交点の計算\n Point crossPoint(const Line &s, const Line &t) {\n D d1 = cross(s.b - s.a, t.b - t.a);\n D d2 = cross(s.b - s.a, s.b - t.a);\n if(equal(abs(d1), 0) && equal(abs(d2), 0)) return t.a;\n return t.a + (t.b - t.a) * (d2 / d1);\n }\n\n // 線分s, tの交点の計算\n Point crossPoint(const Segment &s, const Segment &t) {\n return crossPoint(Line(s), Line(t));\n }\n\n // 線分sと線分tが交差しているかどうか\n bool isIntersect(const Segment &s, const Segment &t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n }\n\n // 線分sとtの距離\n D distanceBetweenSegments(const Segment &s, const Segment &t) {\n if(isIntersect(s, t)) return (D)(0);\n D ans = distanceBetweenSegmentAndPoint(s, t.a);\n chmin(ans, distanceBetweenSegmentAndPoint(s, t.b));\n chmin(ans, distanceBetweenSegmentAndPoint(t, s.a));\n chmin(ans, distanceBetweenSegmentAndPoint(t, s.b));\n return ans;\n }\n\n // 射影(projection)\n // 直線(線分)lに点pから引いた垂線の足を求める\n Point projection(const Line &l, const Point &p) {\n D t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n }\n\n Point projection(const Segment &l, const Point &p) {\n D t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n }\n\n // 反射(reflection)\n // 直線lを対称軸として点pと線対称の位置にある点を求める\n Point reflection(const Line &l, const Point &p) {\n return p + (projection(l, p) - p) * 2.0;\n }\n\n // 2つの円の交差判定\n // 返り値は共通接線の数\n int isIntersect(const Circle &c1, const Circle &c2) {\n D d = abs(c1.p - c2.p);\n // 2つの円が離れている場合\n if(d > c1.r + c2.r + EPS) return 4;\n // 外接している場合\n if(equal(d, c1.r + c2.r)) return 3;\n // 内接している場合\n if(equal(d, abs(c1.r - c2.r))) return 1;\n // 内包している場合\n if(d < abs(c1.r - c2.r) - EPS) return 0;\n return 2;\n }\n\n // 2つの円の交点\n vector<Point> crossPoint(const Circle &c1, const Circle &c2) {\n vector<Point> res;\n int mode = isIntersect(c1, c2);\n // 2つの中心の距離\n D d = abs(c1.p - c2.p);\n // 2円が離れている場合\n if(mode == 4) return res;\n // 1つの円がもう1つの円に内包されている場合\n if(mode == 0) return res;\n // 2円が外接する場合\n if(mode == 3) {\n D t = c1.r / (c1.r + c2.r);\n res.emplace_back(c1.p + (c2.p - c1.p) * t);\n return res;\n }\n // 内接している場合\n if(mode == 1) {\n if(c2.r < c1.r - EPS) {\n res.emplace_back(c1.p + (c2.p - c1.p) * (c1.r / d));\n } else {\n res.emplace_back(c2.p + (c1.p - c2.p) * (c2.r / d));\n }\n return res;\n }\n // 2円が重なる場合\n D rc1 = (c1.r * c1.r + d * d - c2.r * c2.r) / (2 * d);\n D rs1 = sqrt(c1.r * c1.r - rc1 * rc1);\n if(c1.r - abs(rc1) < EPS) rs1 = 0;\n Point e12 = (c2.p - c1.p) / abs(c2.p - c1.p);\n res.emplace_back(c1.p + rc1 * e12 + rs1 * e12 * Point(0, 1));\n res.emplace_back(c1.p + rc1 * e12 + rs1 * e12 * Point(0, -1));\n return res;\n }\n\n // 点pが円cの内部(円周上も含む)に入っているかどうか\n bool isInCircle(const Circle &c, const Point &p) {\n D d = abs(c.p - p);\n return (equal(d, c.r) || d < c.r - EPS);\n }\n\n // 円cと直線lの交点\n vector<Point> crossPoint(const Circle &c, const Line &l) {\n vector<Point> res;\n D d = distanceBetweenLineAndPoint(l, c.p);\n // 交点を持たない\n if(d > c.r + EPS) return res;\n // 接する\n Point h = projection(l, c.p);\n if(equal(d, c.r)) {\n res.emplace_back(h);\n return res;\n }\n Point e = unitVector(l.b - l.a);\n D ph = sqrt(c.r * c.r - d * d);\n res.emplace_back(h - e * ph);\n res.emplace_back(h + e * ph);\n return res;\n }\n\n // 点pを通る円cの接線\n // 2本あるので、接点のみを返す\n vector<Point> tangentToCircle(const Point &p, const Circle &c) {\n return crossPoint(c, Circle(p, sqrt(norm(c.p - p) - c.r * c.r)));\n }\n\n // 円の共通接線\n vector<Line> tangent(const Circle &a, const Circle &b) {\n vector<Line> ret;\n // 2円の中心間の距離\n D g = abs(a.p - b.p);\n // 円が内包されている場合\n if(equal(g, 0)) return ret;\n Point u = unitVector(b.p - a.p);\n Point v = rotate(u, PI / 2);\n for(int s : {-1, 1}) {\n D h = (a.r + b.r * s) / g;\n if(equal(h * h, 1)) {\n ret.emplace_back(a.p + (h > 0 ? u : -u) * a.r,\n a.p + (h > 0 ? u : -u) * a.r + v);\n\n } else if(1 - h * h > 0) {\n Point U = u * h, V = v * sqrt(1 - h * h);\n ret.emplace_back(a.p + (U + V) * a.r,\n b.p - (U + V) * (b.r * s));\n ret.emplace_back(a.p + (U - V) * a.r,\n b.p - (U - V) * (b.r * s));\n }\n }\n return ret;\n }\n\n // 多角形の面積を求める\n D PolygonArea(const vector<Point> &p) {\n D res = 0;\n int n = p.size();\n for(int i = 0; i < n - 1; i++) res += cross(p[i], p[i + 1]);\n res += cross(p[n - 1], p[0]);\n return res * 0.5;\n }\n\n // 凸多角形かどうか\n bool isConvex(const vector<Point> &p) {\n int n = p.size();\n int now, pre, nxt;\n for(int i = 0; i < n; i++) {\n pre = (i - 1 + n) % n;\n nxt = (i + 1) % n;\n now = i;\n if(ccw(p[pre], p[now], p[nxt]) == -1) return false;\n }\n return true;\n }\n\n // 凸包 O(NlogN)\n vector<Point> ConvexHull(vector<Point> &p) {\n int n = (int)p.size(), k = 0;\n sort(all(p), [](const Point &a, const Point &b) {\n return (real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b));\n });\n vector<Point> ch(2 * n);\n // 一直線上の3点を含める -> (< -EPS)\n // 含め無い -> (< EPS)\n for(int i = 0; i < n; ch[k++] = p[i++]) { // lower\n while(k >= 2 &&\n cross(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1]) < EPS)\n --k;\n }\n for(int i = n - 2, t = k + 1; i >= 0; ch[k++] = p[i--]) { // upper\n while(k >= t &&\n cross(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1]) < EPS)\n --k;\n }\n ch.resize(k - 1);\n return ch;\n }\n\n // 多角形gに点pが含まれているか?\n // 含まれる:2, 辺上にある:1, 含まれない:0\n int isContained(const vector<Point> &g, const Point &p) {\n bool in = false;\n int n = (int)g.size();\n for(int i = 0; i < n; i++) {\n Point a = g[i] - p, b = g[(i + 1) % n] - p;\n if(imag(a) > imag(b)) swap(a, b);\n if(imag(a) <= EPS && EPS < imag(b) && cross(a, b) < -EPS) in = !in;\n if(cross(a, b) == 0 && dot(a, b) <= 0) return 1;\n }\n return (in ? 2 : 0);\n }\n\n} // namespace geometry\n\nusing namespace geometry;\n\nint main(){\n while(1){\n int n; cin >> n;\n if(!n) break;\n int sx,sy,gx,gy; cin >> sx >> sy >> gx >> gy;\n Segment s = Segment(Point(sx,sy),Point(gx,gy));\n vector<Segment> seg;\n vector<int> h;\n bool zero = false;\n rep(i,n){\n int x,y,X,Y,H; cin >> x >> y >> X >> Y >> H;\n if(x <= sx && y <= sy && X >= sx && Y >= sy) zero = true;\n vector<Point> p(4);\n p[0] = {(double)x,(double)y};\n p[1] = {(double)X,(double)y};\n p[2] = {(double)X,(double)Y};\n p[3] = {(double)x,(double)Y};\n rep(j,4){\n seg.emplace_back(p[j],p[(j+1)%4]);\n h.push_back(H);\n }\n }\n if(zero){\n cout << \"0.0000\" << \"\\n\";\n continue;\n }\n D ok = 0.0, ng = 1000.0;\n rep(z,50){\n D r = (ok+ng) / 2.0;\n bool f = true;\n rep(i,4*n){\n double di = distanceBetweenSegments(s,seg[i]);\n if(h[i] >= r){\n if(di < r) f = false; \n }else{\n if(2.0*r*h[i] - h[i]*h[i] > di*di) f = false;\n }\n }\n if(f) ok = r;\n else ng = r;\n }\n printf(\"%.6f\\n\",ok);\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3244, "score_of_the_acc": -0.1138, "final_rank": 2 } ]
aoj_1159_cpp
Problem A: Next Mayor One of the oddest traditions of the town of Gameston may be that even the town mayor of the next term is chosen according to the result of a game. When the expiration of the term of the mayor approaches, at least three candidates, including the mayor of the time, play a game of pebbles, and the winner will be the next mayor. The rule of the game of pebbles is as follows. In what follows, n is the number of participating candidates. Requisites A round table, a bowl, and plenty of pebbles. Start of the Game A number of pebbles are put into the bowl; the number is decided by the Administration Commission using some secret stochastic process. All the candidates, numbered from 0 to n -1 sit around the round table, in a counterclockwise order. Initially, the bowl is handed to the serving mayor at the time, who is numbered 0. Game Steps When a candidate is handed the bowl and if any pebbles are in it, one pebble is taken out of the bowl and is kept, together with those already at hand, if any. If no pebbles are left in the bowl, the candidate puts all the kept pebbles, if any, into the bowl. Then, in either case, the bowl is handed to the next candidate to the right. This step is repeated until the winner is decided. End of the Game When a candidate takes the last pebble in the bowl, and no other candidates keep any pebbles, the game ends and that candidate with all the pebbles is the winner. A math teacher of Gameston High, through his analysis, concluded that this game will always end within a finite number of steps, although the number of required steps can be very large. Input The input is a sequence of datasets. Each dataset is a line containing two integers n and p separated by a single space. The integer n is the number of the candidates including the current mayor, and the integer p is the total number of the pebbles initially put in the bowl. You may assume 3 ≤ n ≤ 50 and 2 ≤ p ≤ 50. With the settings given in the input datasets, the game will end within 1000000 (one million) steps. The end of the input is indicated by a line containing two zeros separated by a single space. Output The output should be composed of lines corresponding to input datasets in the same order, each line of which containing the candidate number of the winner. No other characters should appear in the output. Sample Input 3 2 3 3 3 50 10 29 31 32 50 2 50 50 0 0 Output for the Sample Input 1 0 1 5 30 1 13
[ { "submission_id": "aoj_1159_10851347", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n\tint n,p;\n\twhile( cin >> n >> p and n ){\n\t\tint c[50] = {};\n\t\tint owan = p;\n\t\tfor(int i = 0 ; ; i = (i+1) % n ){\n\t\t\tif( owan ){\n\t\t\t\t--owan;\n\t\t\t\tc[i]++;\n\t\t\t}else{\n\t\t\t\towan += c[i];\n\t\t\t\tc[i] = 0;\n\t\t\t}\n\n\t\t\tif( c[i] == p ){\n\t\t\t\tcout << i << endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3344, "score_of_the_acc": -1.042, "final_rank": 11 }, { "submission_id": "aoj_1159_10842826", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconst string l_hands = \"qwertasdfgzxcvb\";\n\nint main(){\n while(true){\n int n, p;\n cin >> n >> p;\n if(!n) break;\n \n vector<int> candidate(n);\n bool finish = false;\n int bowl = p;\n\n while(!finish){\n for(int i=0;i<n;i++){\n if(bowl>0){\n candidate[i]++;\n bowl--;\n }else{\n bowl = candidate[i];\n candidate[i] = 0;\n }\n if(candidate[i] == p){\n cout << i << endl;\n finish = true;\n }\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3372, "score_of_the_acc": -0.5954, "final_rank": 5 }, { "submission_id": "aoj_1159_10658121", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (ll i=0; i<(n); i++)\ntemplate<typename S, typename T> bool chmin(S &a, T b) {if (a > b) {a = b; return true;} return false;}\ntemplate<typename S, typename T> bool chmax(S &a, T b) {if (a < b) {a = b; return true;} return false;}\ntemplate<typename Container> ll sz(const Container &c) {return (ll)(c.size());}\n\nint main() {\n while (true) {\n ll n,p; cin >> n >> p;\n ll pmax = p;\n if (n == 0) break;\n vector<ll> a(n, 0);\n ll pos = 0;\n while (true) {\n if (p != 0) {\n a[pos]++;\n p--;\n } else {\n p += a[pos];\n a[pos] = 0;\n }\n if (a[pos] == pmax) {\n cout << pos << '\\n';\n break;\n }\n pos = (pos + 1) % n;\n }\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3176, "score_of_the_acc": -1.2214, "final_rank": 13 }, { "submission_id": "aoj_1159_10601126", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing a2 = array<ll, 2>;\nusing a3 = array<ll, 3>;\n\ntemplate <typename A>\nvoid chmin(A &l, const A &r) {\n if (r < l)\n l = r;\n}\ntemplate <typename A>\nvoid chmax(A &l, const A &r) {\n if (l < r)\n l = r;\n}\n\nll mod = 998244353;\n\nll n, p;\nvoid input() {\n cin >> n >> p;\n}\n\nvoid solve() {\n vector<ll> v(n, 0);\n ll bowl = p;\n for (int i = 0; 1; i++, i %= n) {\n if (bowl) {\n v[i]++;\n bowl--;\n if (v[i] == p)\n break;\n } else {\n bowl = v[i];\n v[i] = 0;\n }\n }\n cout << find(v.begin(), v.end(), p) - v.begin() << endl;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n\n while (1) {\n input();\n if (n == 0)\n break;\n solve();\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3384, "score_of_the_acc": -1.6183, "final_rank": 20 }, { "submission_id": "aoj_1159_10595675", "code_snippet": "#include <iostream>\n#include <vector>\n\nusing namespace std;\n\nint main() {\n int n, p;\n while (cin >> n >> p) {\n if (n == 0 && p == 0) break;\n int have = 0, idx = 0;\n vector<int> a(n, 0);\n while (true){\n if(p == 0 and have == 1) break;\n if(p > 0){\n if(a[idx] == 0) have++;\n a[idx]++;\n p--;\n idx = (idx + 1) % n;\n }else{\n if(a[idx] == 0){\n idx = (idx + 1) % n;\n continue;\n }\n p += a[idx];\n a[idx] = 0;\n have--;\n idx = (idx + 1) % n;\n }\n }\n for(int i = 0; i < n; i++)if(a[i] != 0) cout << i << endl;\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3372, "score_of_the_acc": -1.0954, "final_rank": 12 }, { "submission_id": "aoj_1159_10595664", "code_snippet": "#include <algorithm>\n#include <array>\n#include <cmath>\n#include <cstdlib>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <tuple>\n#include <unordered_map>\n#include <unordered_set>\n#include <vector>\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\n\n\nbool Solve(void) {\n int n, p;\n cin >> n >> p;\n if (n == 0) return false;\n\n vector<int> stones(n);\n int bowl = p, winner;\n for (int i = 0;; i = (i + 1) % n) {\n if (bowl > 0) {\n bowl--;\n stones[i]++;\n if (stones[i] == p) {\n winner = i;\n break;\n }\n } else {\n bowl += stones[i];\n stones[i] = 0;\n }\n }\n\n cout << winner << endl;\n\n\treturn true;\n}\n\nint main(void) {\n\twhile (Solve());\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3336, "score_of_the_acc": -1.0267, "final_rank": 10 }, { "submission_id": "aoj_1159_10579842", "code_snippet": "# pragma GCC target(\"avx\")\n# pragma GCC optimize(\"O3\")\n# pragma GCC optimize(\"unroll-loops\")\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#include <atcoder/all>\nusing namespace atcoder;\n\nusing ll = long long;\nusing mint = modint998244353;\n\nbool solve() {\n int n, p;\n cin >> n >> p;\n if(n == 0 && p == 0) return false;\n int pos = 0, x = p;\n vector<int> cnt(n);\n int k = 0;\n while(true) {\n k++;\n // if(k <= 100) {\n // for(int d : cnt) cout << d << \" \";\n // cout << endl;\n // }\n if(x > 0) {\n x--, cnt[pos]++;\n if(cnt[pos] == p) {\n cout << pos << endl;\n break;\n }\n pos++, pos %= n;\n }else {\n if(cnt[pos] > 0) x += cnt[pos], cnt[pos] = 0;\n pos++, pos %= n;\n }\n }\n return true;\n}\n\nint main() {\n while(solve());\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3584, "score_of_the_acc": -1.3333, "final_rank": 17 }, { "submission_id": "aoj_1159_10557160", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n while(1){\n int n, p; cin >> n >> p;\n if(n == 0) break;\n\n int ans = 0, rem = p, cur = 0;\n vector<int> have(n, 0);\n while(1){\n if(rem > 0){\n rem -= 1;\n have[cur] += 1;\n if(rem == 0){\n bool end = true;\n for(int i = 0; i < n; ++i){\n if(i == cur) continue;\n end &= have[i] == 0;\n }\n if(end){\n cout << cur << endl;\n break;\n }\n }\n }\n else{\n rem += have[cur];\n have[cur] = 0;\n }\n cur = (cur + 1) % n;\n }\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3356, "score_of_the_acc": -1.3982, "final_rank": 18 }, { "submission_id": "aoj_1159_10404479", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n while (1) {\n int n, p;\n cin >> n >> p;\n if (n == 0 && p == 0) break;\n\n int b = p;\n int index = 0;\n vector<int> m(n);\n\n int win;\n\n while (1) {\n if (b > 0) {\n b--;\n m[index]++;\n } else {\n if (m[index] == p) {\n win = index;\n break;\n }\n b = m[index];\n m[index] = 0;\n }\n\n index++;\n if (index > n - 1) index = 0;\n }\n\n cout << win % n << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3124, "score_of_the_acc": -0.1221, "final_rank": 1 }, { "submission_id": "aoj_1159_10404371", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n,p;\n while(cin>>n>>p){\n if(!n&&!p)break;\n vector<int>a(n);\n int b=p,i=0;\n for(;;){\n if(b){\n --b;\n if(++a[i]==p){\n cout<<i<<\"\\n\";\n break;\n }\n }else{\n b=a[i];\n a[i]=0;\n }\n i=(i+1)%n;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3332, "score_of_the_acc": -1.0191, "final_rank": 9 }, { "submission_id": "aoj_1159_9883411", "code_snippet": "#include<bits/stdc++.h>\n// #include<atcoder/all>\n// #include<boost/multiprecision/cpp_int.hpp>\n\nusing namespace std;\n// using namespace atcoder;\n// using bint = boost::multiprecision::cpp_int;\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nusing P = pair<ll,ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing ve = vector<vector<int>>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\n#define rep(i,n) for(ll i = 0;i < (ll)n;i++)\n#define ALL(x) (x).begin(),(x).end()\n#define sz(c) ((ll)(c).size())\n#define LB(A,x) (int)(lower_bound(A.begin(),A.end(),x)-A.begin())\n#define UB(A,x) (int)(upper_bound(A.begin(),A.end(),x)-A.begin())\n// #define MOD 1000000007\n#define MOD 998244353\ntemplate<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T>ostream&operator<<(ostream&os,vector<T>&v){for(int i = 0;i < v.size();i++)os<<v[i]<<(i+1!=v.size()?\" \":\"\");return os;}\ntemplate<typename T>istream&operator>>(istream&is,vector<T>&v){for(T&in:v)is>>in;return is;}\ntemplate<typename T1,typename T2>ostream&operator<<(ostream&os,pair<T1,T2>&p){os<<p.first<<\" \"<<p.second;return os;}\ntemplate<typename T1,typename T2>istream&operator>>(istream&is,pair<T1,T2>&p){is>>p.first>>p.second;return is;}\ntemplate<typename T> inline bool chmax(T &a,T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> inline bool chmin(T &a,T b){if(a > b){a = b;return true;}return false;}\nld dist(ld x1,ld y1,ld x2, ld y2){return sqrtl((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));}\n\n\nint main(){\n \n ios_base::sync_with_stdio(0), cin.tie(0);\n while(1){\n int n,p;cin >> n >> p;\n if(!n)break;\n vi cnt(n);\n int k = n,idx = 0;\n while(1000010){\n if(k == n-1 && p == 0)break;\n if(p == 0){\n p = cnt[idx];\n if(cnt[idx] != 0)k++;\n cnt[idx] = 0;\n }else{\n p--;\n cnt[idx]++;\n if(cnt[idx] == 1)k--;\n }\n idx = (idx + 1)%n;\n }\n cout << (idx+n-1)%n << \"\\n\";\n }\n \n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3360, "score_of_the_acc": -1.2392, "final_rank": 14 }, { "submission_id": "aoj_1159_9533698", "code_snippet": "/**********************\n* Todaka Haruto *\n* Problem: Next Mayor *\n* 2024/8/4 *\n**********************/\n\n#include <iostream>\n#include <string>\n#include <vector>\nusing namespace std;\n#define rep(i,n) for(int i = 0; i < n; i++)\n\n\nint main() {\n int n,p;\n while(!cin.eof()) {\n cin >> n >> p;\n if(n == 0 && p == 0) return 0;\n \n int cup = p;\n vector<int> people(n);\n bool flag = false;\n while(1) {\n rep(i,n) {\n if(people[i] == p) {\n cout << i << endl;\n flag = true;\n break;\n }\n }\n if(flag == true) break;\n\n rep(i,n) {\n if(cup == 0) {\n cup += people[i];\n people[i] = 0;\n } else {\n cup--;\n people[i]++;\n }\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3328, "score_of_the_acc": -0.6781, "final_rank": 7 }, { "submission_id": "aoj_1159_9526673", "code_snippet": "/**********************\n* Todaka Haruto *\n* Problem: Next Mayor *\n* 2024/8/4 *\n**********************/\n\n#include <iostream>\n#include <string>\n#include <vector>\nusing namespace std;\n#define rep(i,n) for(int i = 0; i < n; i++)\n\n\nvector<int> split(string str, char del) {\n vector<int> result;\n string tmpStr;\n\n for(const char c: str) {\n if(c == del) {\n result.push_back(stoi(tmpStr));\n tmpStr.clear();\n } else {\n tmpStr += c;\n }\n }\n result.push_back(stoi(tmpStr));\n return result;\n}\n\n\nint main() {\n int n,p;\n string line;\n while(!cin.eof()) {\n getline(cin,line);\n vector<int> input = split(line, ' ');\n n = input[0]; p = input[1];\n if(n == 0 && p == 0) return 0;\n \n int cup = p;\n vector<int> people(n);\n bool flag = false;\n while(1) {\n rep(i,n) {\n if(people[i] == p) {\n cout << i << endl;\n flag = true;\n break;\n }\n }\n if(flag == true) break;\n\n rep(i,n) {\n if(cup == 0) {\n cup += people[i];\n people[i] = 0;\n } else {\n cup--;\n people[i]++;\n }\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3300, "score_of_the_acc": -0.6247, "final_rank": 6 }, { "submission_id": "aoj_1159_9418269", "code_snippet": "using namespace std;\n#include<bits/stdc++.h>\nusing ll = long long;\nusing ull = unsigned long long;\ntemplate <typename T>\nusing V = vector<T>;\ntemplate <typename T>\nusing VV = V<V<T>>;\nusing Vi = V<int>;\nusing Vl = V<ll>;\nusing Vd = V<double>;\nusing Vs = V<string>;\nusing Vc = V<char>;\nusing VVi = VV<int>;\nusing VVl = VV<ll>;\nusing VVc = VV<char>;\ntemplate <typename T>\nusing P = pair<T,T>;\nusing Pi = P<int>;\nusing Pl = P<ll>;\nusing Pd = P<double>;\nusing Ps = P<string>;\n#define rep(i,n) for(ll i = 0 ; i < (ll)n ; i++)\n#define rep1(i,n) for(ll i = 1 ; i < (ll)n ; i++)\n#define repx(i,n,x) for(ll i = (ll)x ; i < (ll)n ; i++)\n#define repr(i,n) for(ll i = (ll)n-1; i >= 0 ; i--)\n#define reprx(i,n,x) for(ll i = (ll)x ; i >= 0 ; i--)\n\ntemplate <typename T>\nvoid primtx(VV<T> m);\n\nint main(){\n while(1){\n int n,p;\n cin >> n >> p;\n if(n==0 && p==0) break;\n int owan = p;\n Vi mayer(n,0);\n bool isFin = false;\n int ans;\n while (1)\n {\n rep(i,n){\n if(owan>0){\n mayer[i] += 1;\n owan--;\n if(owan == 0 && mayer[i] == p){\n ans = i;\n isFin = true;\n break;\n }\n }\n else{\n owan += mayer[i];\n mayer[i] = 0;\n }\n }\n if(isFin) break;\n }\n cout << ans << endl;\n \n }\n return 0;\n}\n\n\n// 二次元配列の表示\ntemplate <typename T>\nvoid primtx(VV<T> m){\n rep(i, m.size()){\n rep(j, m[0].size()){\n cout << m[i][j] << \" \";\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3060, "score_of_the_acc": -0.1667, "final_rank": 2 }, { "submission_id": "aoj_1159_9389593", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\n#define rep(i, n) for(ll i = 0; i < (n); i++)\n#define reps(i, l, r) for(ll i = (l); i < (r); i++)\n#define all(a) (a).begin(), (a).end()\n#define endl \"\\n\";\nconst ll INF = 2e18;\nconst ll mod1 = 1000000007;\nconst ll mod2 = 998244353;\nll dx[4] = {-1, 1, 0, 0};\nll dy[4] = {0, 0, -1, 1};\nvoid chmin(ll& a, ll b){ if(a > b) a = b; }\nvoid chmax(ll& a, ll b){ if(a < b) a = b; }\nll gcd(ll a, ll b) {return (b == 0 ? a : gcd(b, a % b));}\nll lcm(ll a, ll b) {return a / gcd(a, b) * b;}\nconst ld pi = 3.1415926535897;\nvoid solve() {\n\t//ofstream cout(\"text.txt\");\n ll N, P; cin >> N >> P;\n while (N != 0 || P != 0) {\n vector<ll>A(N, 0);\n ll pos = 0;\n ll Max = P;\n while (A[pos] != Max) {\n if (P == 0) {\n P += A[pos]; A[pos] = 0;\n pos = (pos + 1) % N;\n continue;\n }\n P--; A[pos]++;\n if (A[pos] == Max) {\n break;\n }\n pos = (pos + 1) % N;\n }\n cout << pos << endl;\n cin >> N >> P;\n }\n}\nsigned main() {\n\tcin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n ll T = 1; //cin >> T;\n while(T--) solve();\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3220, "score_of_the_acc": -1.3053, "final_rank": 16 }, { "submission_id": "aoj_1159_9369010", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n while(true){\n int n,p;\n cin >> n >> p;\n if(n==0&&p==0)break;\n int buf=p;\n vector<int>a(n,0);\n int round=0;\n while(true){\n if(p>0){\n a[round%n]++;\n p--;\n }else{\n p+=a[round%n];\n a[round%n]=0;\n }\n round++;\n if(a[round%n]==buf)break;\n }\n cout << round%n << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3128, "score_of_the_acc": -0.4631, "final_rank": 4 }, { "submission_id": "aoj_1159_9344656", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define all(x) (x).begin(),(x).end()\n#define eb emplace_back\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing vl = vector<long long>;\nusing vvl = vector<vector<long long>>; using vs = vector<string>;\nusing pl = pair<long long, long long>;\ntemplate <typename T> inline bool chmin(T& a, const T& b) {bool compare = a > b; if (a > b) a = b; return compare;}\ntemplate <typename T> inline bool chmax(T& a, const T& b) {bool compare = a < b; if (a < b) a = b; return compare;}\ntemplate<class T>using rp_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate <typename T> T gcd(T a, T b) {if (b == 0)return a; else return gcd(b, a % b);}\ntemplate <typename T> inline T lcm(T a, T b) {return a /gcd(a, b)*b;}\nconst ll INF = 1LL << 60;\nconst ld PI = acos(-1);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec);\ntemplate <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr);\ntemplate <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec);\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const pair<T, U> &pa);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec);\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa);\ntemplate <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp);\ntemplate <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp);\ntemplate <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl);\n\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec) { os << '['; for (auto v : vec) os << v << ','; os << ']'; return os; }\ntemplate <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr) { os << '['; for (auto v : arr) os << v << ','; os << ']'; return os; }\ntemplate <class... T> std::istream &operator>>(std::istream &is, std::tuple<T...> &tpl) { std::apply([&is](auto &&... args) { ((is >> args), ...);}, tpl); return is; }\ntemplate <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl) { os << '('; std::apply([&os](auto &&... args) { ((os << args << ','), ...);}, tpl); return os << ')'; }\ntemplate <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec) { os << \"deq[\"; for (auto v : vec) os << v << ','; os << ']'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa) { return os << '(' << pa.first << ',' << pa.second << ')'; }\ntemplate <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << \"=>\" << v.second << ','; os << '}'; return os; }\ntemplate <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp) { os << '{'; for (auto v : mp) os << v.first << \"=>\" << v.second << ','; os << '}'; return os; }\n#ifdef LOCAL\nconst string COLOR_RESET = \"\\033[0m\", BRIGHT_GREEN = \"\\033[1;32m\", BRIGHT_RED = \"\\033[1;31m\", BRIGHT_CYAN = \"\\033[1;36m\", NORMAL_CROSSED = \"\\033[0;9;37m\", RED_BACKGROUND = \"\\033[1;41m\", NORMAL_FAINT = \"\\033[0;2m\";\n#define dbg(x) std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << \" = \" << (x) << NORMAL_FAINT << \" (L\" << __LINE__ << \") \" << __FILE__ << COLOR_RESET << std::endl\n#define dbgif(cond, x) ((cond) ? std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << \" = \" << (x) << NORMAL_FAINT << \" (L\" << __LINE__ << \") \" << __FILE__ << COLOR_RESET << std::endl : std::cerr)\n#else\n#define dbg(x) ((void)0)\n#define dbgif(cond, x) ((void)0)\n#endif\nvoid solve();\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout<<fixed<<setprecision(15);\n int num_tc = 1;\n //cin >> num_tc;\n rep(tc,num_tc){\n //cout << \"Case #\" << tc+1 << \": \" ;// << endl;\n solve();\n }\n}\n//見切り発車で実装しては行けない.頭の中でコードが完全に出来上がるまで書き始めるな.\nvoid solve(){\n while(true){\n ll n,p;cin>>n>>p;\n if(n==0&&p==0)return;\n vl A(n);\n int i=0;\n //p = 椀にある個数\n ll mx = p;\n while(true){\n if(p==0){\n p = A[i];\n A[i]=0;\n }else{\n p--;\n A[i]++;\n if(p==0&&A[i]==mx){\n cout<<i<<endl;\n break;\n }\n }\n i++;\n i%=n;\n }\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3372, "score_of_the_acc": -1.5954, "final_rank": 19 }, { "submission_id": "aoj_1159_9343504", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\nusing namespace std;\n//using namespace atcoder;\n\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<long long>;\nusing vs = vector<string>;\nusing vc = vector<char>;\nusing vb = vector<bool>;\nusing vpii = vector<pair<int, int>>;\nusing vpll = vector<pair<long long, long long>>;\nusing vvi = vector<vector<int>>;\nusing vvl = vector<vector<long long>>;\nusing vvc = vector<vector<char>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing pii = pair<int, int>;\nusing vvb = vector<vector<bool>>;\nusing Graph = vector<vector<ll>>;\nconst ll LINF = 1001002003004005006ll;\nconst int INF = 1001001001;\nconst int MOD = 998422353;\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep3(i, m, n) for (int i = (m); i < (int)(n); i++)\n#define rrep(i, m, n) for (int i = (m); i >= (int)(n); i--)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\nvi dx4 = {1, 0, -1, 0}, dy4 = {0, 1, 0, -1};\nvi dx8 = {1, 1, 1, 0, 0, -1, -1, -1}, dy8 = {1, 0, -1, 1, -1, 1, 0, -1};\n\nint main()\n{\n while(1){\n int N,P;\n int flag = 1;\n cin >> N >> P;\n vi A(N,0);\n int P2 = P;\n if(N == 0 && P == 0)break;\n while(flag == 1){\n rep(i,N){\n if(P == 0){\n P += A[i];\n A[i] = 0;\n }\n else{\n P--;\n A[i]++;\n }\n if(A[i] == P2){\n flag = 0;\n cout << i << endl;\n break;\n }\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3060, "score_of_the_acc": -0.1667, "final_rank": 2 }, { "submission_id": "aoj_1159_9337389", "code_snippet": "#include <iostream>\n#include <vector>\n\nusing namespace std;\n\nint main() {\n while (true) {\n int n, p;\n cin >> n >> p;\n if (n == 0 && p == 0) break;\n\n vector<int> candidates(n, 0); // 各候補者の小石の数を0に初期化\n int bowl = p; // 碗の中の小石の数\n int current = 0; // 現在の候補者の位置\n\n while (true) {\n if (bowl > 0) {\n candidates[current] += 1;\n bowl -= 1;\n } else {\n bowl += candidates[current];\n candidates[current] = 0;\n }\n\n bool allOthersEmpty = true;\n for (int i = 0; i < n; ++i) {\n if (i != current && candidates[i] != 0) {\n allOthersEmpty = false;\n break;\n }\n }\n\n if (bowl == 0 && allOthersEmpty) {\n cout << current << endl;\n break;\n }\n\n current = (current + 1) % n;\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3088, "score_of_the_acc": -0.7201, "final_rank": 8 }, { "submission_id": "aoj_1159_9330874", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<long long>;\nusing vs = vector<string>;\nusing vc = vector<char>;\nusing vb = vector<bool>;\nusing vpii = vector<pair<int, int>>;\nusing vpll = vector<pair<long long, long long>>;\nusing vvi = vector<vector<int>>;\nusing vvl = vector<vector<long long>>;\nusing vvc = vector<vector<char>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing pii = pair<int, int>;\nusing vvb = vector<vector<bool>>;\nusing Graph = vector<vector<ll>>;\nconst ll LINF = 1001002003004005006ll;\nconst int INF = 1001001001;\nconst int MOD = 998422353;\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep3(i, m, n) for (int i = (m); i < (int)(n); i++)\n#define rrep(i, m, n) for (int i = (m); i >= (int)(n); i--)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\nvi dx4 = {1, 0, -1, 0}, dy4 = {0, 1, 0, -1};\nvi dx8 = {1, 1, 1, 0, 0, -1, -1, -1}, dy8 = {1, 0, -1, 1, -1, 1, 0, -1};\n\nint main()\n{\n while (1)\n {\n // 宣言・入力の受け取り\n int n, p;\n cin >> n >> p;\n // 終了条件\n if (n == 0 && p == 0)\n {\n break;\n }\n // 宣言・入力の受け取り\n\n // solve\n ll box = p;\n vl hito(n, 0);\n int i = 0;\n while (1)\n {\n if (box > 0)\n {\n hito[i]++;\n if (hito[i] == p)\n {\n cout << i << '\\n';\n break;\n }\n box--;\n i++;\n i %= n;\n }\n else\n {\n box += hito[i];\n hito[i] = 0;\n i++;\n i %= n;\n }\n }\n // 出力\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3448, "score_of_the_acc": -1.2405, "final_rank": 15 } ]
aoj_1161_cpp
Problem C: Verbal Arithmetic Let's think about verbal arithmetic. The material of this puzzle is a summation of non-negative integers represented in a decimal format, for example, as follows. 905 + 125 = 1030 In verbal arithmetic, every digit appearing in the equation is masked with an alphabetic character. A problem which has the above equation as one of its answers, for example, is the following. ACM + IBM = ICPC Solving this puzzle means finding possible digit assignments to the alphabetic characters in the verbal equation. The rules of this puzzle are the following. Each integer in the equation is expressed in terms of one or more digits '0'-'9', but all the digits are masked with some alphabetic characters 'A'-'Z'. The same alphabetic character appearing in multiple places of the equation masks the same digit. Moreover, all appearances of the same digit are masked with a single alphabetic character. That is, different alphabetic characters mean different digits. The most significant digit must not be '0', except when a zero is expressed as a single digit '0'. That is, expressing numbers as "00" or "0123" is not permitted. There are 4 different digit assignments for the verbal equation above as shown in the following table. Mask A B C I M P Case 1 9 2 0 1 5 3 Case 2 9 3 0 1 5 4 Case 3 9 6 0 1 5 7 Case 4 9 7 0 1 5 8 Your job is to write a program which solves this puzzle. Input The input consists of a number of datasets. The end of the input is indicated by a line containing a zero. The number of datasets is no more than 100. Each dataset is formatted as follows. N STRING 1 STRING 2 ... STRING N The first line of a dataset contains an integer N which is the number of integers appearing in the equation. Each of the following N lines contains a string composed of uppercase alphabetic characters 'A'-'Z' which mean masked digits. Each dataset expresses the following equation. STRING 1 + STRING 2 + ... + STRING N -1 = STRING N The integer N is greater than 2 and less than 13. The length of STRING i is greater than 0 and less than 9. The number of different alphabetic characters appearing in each dataset is greater than 0 and less than 11. Output For each dataset, output a single line containing the number of different digit assignments that satisfy the equation. The output must not contain any superfluous characters. Sample Input 3 ACM IBM ICPC 3 GAME BEST GAMER 4 A B C AB 3 A B CD 3 ONE TWO THREE 3 TWO THREE FIVE 3 MOV POP DIV 9 A B C D E F G H IJ 0 Output for the Sample Input 4 1 8 30 0 0 0 40320
[ { "submission_id": "aoj_1161_10851225", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\nlong long weight[128];\n\nint to[128];\nint cnt = 0;\nvector<char> appear;\nvector<string> s;\n\nint taboo[128];\n\n\nbool bad(string &s,int to[128]){\n\tif( s.size() == 1 ) return 0;\n\tif( to[s[0]] == 0 ) return 1;\n\treturn 0;\n}\nint f(vector<string> &v,int to[128]){\n\tlong long sum = 0;\n\tfor(int i = 0 ; i < appear.size() ; i++)\n\t\tsum += weight[appear[i]] * to[appear[i]];\n\treturn sum == 0;\n}\n\n\n\nvoid dfs(int x,int bit){\n\tif( x == appear.size() ){\n\t\tif( f(s,to) ){\n\t\t\tcnt++;\n\t\t}\n\t\treturn;\n\t}\n\tfor(int i = 0 ; i < 10 ; i++){\n\t\tif( bit >> i & 1 ) continue;\n\t\tif( i == 0 and taboo[appear[x]] ) continue;\n\n\t\tto[appear[x]] = i;\n\t\tdfs(x+1,bit|(1<<i));\n\t}\n}\nint main(){\n\tint N;\n\twhile(cin >> N && N){\n\t\tmemset(weight,0,sizeof(weight));\n\t\tmemset(taboo,0,sizeof(taboo));\n\t\ts.resize(N);\n\t\tset<char> hoge;\n\t\tfor(int i = 0 ; i < N ; i++){\n\t\t\tcin >> s[i];\n\t\t\tfor( auto c : s[i] )\n\t\t\t\thoge.insert(c);\n\t\t\tstring tmp = s[i];\n\t\t\treverse(tmp.begin(),tmp.end());\n\t\t\tlong long w = 1;\n\t\t\tfor(int j = 0 ; j < tmp.size() ; j++){\n\t\t\t\tweight[tmp[j]] += (i<N-1?1:-1) * w;\n\t\t\t\tw *= 10;\n\t\t\t}\n\t\t\tif( s[i].size() != 1 ){\n\t\t\t\ttaboo[s[i][0]] = 1;\n\t\t\t}\n\n\t\t}\n\t\tappear = vector<char>(hoge.begin(),hoge.end());\n\t\tcnt = 0;\n\t\tdfs(0,0);\n\t\tcout << cnt << endl;\n\n\t}\n\n}", "accuracy": 1, "time_ms": 4230, "memory_kb": 3364, "score_of_the_acc": -0.721, "final_rank": 10 }, { "submission_id": "aoj_1161_10611098", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<set>\nusing namespace std;\nint N,M;\nvector<string>S;\nvector<int>pats[17];\nvector<bool>head;\nint sz[17];\nvector<int>num,coef;\nbool check()\n{\n\tint sum=0;\n\tfor(int i=0;i<M;i++)if(head[i]&&!num[i])return false;\n\tfor(int i=0;i<M;i++)sum+=num[i]*coef[i];\n\treturn sum==0;\n}\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n while(1)\n\t{\n\t\tcin>>N;\n\t\tif(N==0)break;\n\t\tS=vector<string>(N);\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tcin>>S[i];\n\t\t\tpats[i].clear();\n\t\t}\n\t\tset<char>s;\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tsz[i]=S[i].size();\n\t\t\tfor(int j=0;j<sz[i];j++)s.insert(S[i][j]);\n\t\t}\n\t\tvector<int>alphabet;\n\t\tfor(int c:s)alphabet.push_back(c);\n\t\tM=alphabet.size();\n\t\thead=vector<bool>(M);\n\t\tnum=vector<int>(M);\n\t\tcoef=vector<int>(M);\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tfor(int j=0;j<sz[i];j++)\n\t\t\t{\n\t\t\t\tfor(int k=0;k<M;k++)if(alphabet[k]==S[i][j])\n\t\t\t\t{\n\t\t\t\t\tpats[i].push_back(k);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tint keta=1;\n\t\t\tfor(int j=sz[i]-1;j>=0;j--)\n\t\t\t{\n\t\t\t\tif(i<N-1)coef[pats[i][j]]+=keta;\n\t\t\t\telse coef[pats[i][j]]-=keta;\n\t\t\t\tketa*=10;\n\t\t\t\tif(j==0&&sz[i]>1)head[pats[i][j]]=true;\n\t\t\t}\n\t\t}\n\t\tint ans=0;\n\t\tint b=(1<<M)-1;\n\t\twhile(b<(1<<10))\n\t\t{\n\t\t\tint p=0;\n\t\t\tfor(int i=0;i<10;i++)\n\t\t\t{\n\t\t\t\tif((b>>i)&1)\n\t\t\t\t{\n\t\t\t\t\tnum[p]=i;\n\t\t\t\t\tp++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tdo{\n\t\t\t\tif(check())ans++;\n\t\t\t}while(next_permutation(num.begin(),num.end()));\n\t\t\tint x=b&(-b);\n\t\t\tint y=b+x;\n\t\t\tb=((b&(~y))/x>>1)|y;\n\t\t}\n\t\tcout<<ans<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 2930, "memory_kb": 3356, "score_of_the_acc": -0.5041, "final_rank": 4 }, { "submission_id": "aoj_1161_10610872", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint ans;\n\nvoid solve(int N, vector<string> S) {\n vector<char> a;\n for (int i = 0; i < N; i++) {\n for (auto c : S[i]) {\n a.push_back(c);\n }\n }\n ranges::sort(a);\n a.erase(ranges::unique(a).begin(), a.end());\n\n int siz = static_cast<int>(a.size());\n vector<string> res = S;\n vector<bool> used(10, false);\n vector<vector<int>> ch(siz, vector(2, 0));\n set<int> front;\n for (int i = 0; i < N; i++) {\n int ke = 1;\n for (int j = S[i].size() - 1; j >= 0; j--) {\n for (int k = 0; k < siz; k++) {\n if (S[i][j] == a[k]) {\n if (i == N - 1) {\n ch[k][1] += ke;\n } else {\n ch[k][0] += ke;\n }\n\n if (j == 0 && S[i].size() >= 2) {\n front.insert(k);\n }\n }\n }\n ke *= 10;\n }\n }\n\n int sum = 0;\n int sn = 0;\n auto dfs = [&](auto dfs, int id) -> void {\n if (id == siz) {\n if (sum == sn) {\n ans++;\n }\n return;\n }\n\n for (int x = 0; x <= 9; x++) {\n if (used[x]) {\n continue;\n }\n\n if (x == 0 && front.contains(id)) {\n continue;\n }\n\n used[x] = true;\n sum += ch[id][0] * x;\n sn += ch[id][1] * x;\n dfs(dfs, id + 1);\n sn -= ch[id][1] * x;\n sum -= ch[id][0] * x;\n used[x] = false;\n }\n };\n\n dfs(dfs, 0);\n}\n\nint main() {\n while (true) {\n int N;\n cin >> N;\n if (N == 0) {\n break;\n }\n\n vector<string> S(N);\n for (int i = 0; i < N; i++) {\n cin >> S[i];\n }\n\n ans = 0;\n solve(N, S);\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 3130, "memory_kb": 3456, "score_of_the_acc": -0.6597, "final_rank": 8 }, { "submission_id": "aoj_1161_10610853", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n// 15:30~\nint ans;\n\nvoid solve(int N, vector<string> S) {\n vector<char> a;\n for (int i = 0; i < N; i++) {\n for (auto c : S[i]) {\n a.push_back(c);\n }\n }\n ranges::sort(a);\n a.erase(ranges::unique(a).begin(), a.end());\n\n int siz = static_cast<int>(a.size());\n vector<string> res = S;\n vector<bool> used(10, false);\n vector<vector<int>> ch(siz, vector(2, 0));\n set<int> front;\n for (int i = 0; i < N; i++) {\n int ke = 1;\n for (int j = S[i].size() - 1; j >= 0; j--) {\n for (int k = 0; k < siz; k++) {\n if (S[i][j] == a[k]) {\n if (i == N - 1) {\n ch[k][1] += ke;\n } else {\n ch[k][0] += ke;\n }\n\n if (j == 0 && S[i].size() >= 2) {\n front.insert(k);\n }\n }\n }\n ke *= 10;\n }\n }\n\n int sum = 0;\n int sn = 0;\n auto dfs = [&](auto dfs, int id) -> void {\n if (id == siz) {\n if (sum == sn) {\n ans++;\n }\n return;\n }\n\n for (int x = 0; x <= 9; x++) {\n if (used[x]) {\n continue;\n }\n\n if (x == 0 && front.contains(id)) {\n continue;\n }\n\n used[x] = true;\n sum += ch[id][0] * x;\n sn += ch[id][1] * x;\n dfs(dfs, id + 1);\n sum -= ch[id][0] * x;\n sn -= ch[id][1] * x;\n used[x] = false;\n }\n };\n\n dfs(dfs, 0);\n}\n\nint main() {\n while (true) {\n int N;\n cin >> N;\n if (N == 0) {\n break;\n }\n\n vector<string> S(N);\n for (int i = 0; i < N; i++) {\n cin >> S[i];\n }\n\n ans = 0;\n solve(N, S);\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 3130, "memory_kb": 3456, "score_of_the_acc": -0.6597, "final_rank": 8 }, { "submission_id": "aoj_1161_10610838", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n// 15:30~\nint ans;\n\nvoid solve(int N, vector<string> S) {\n vector<char> a;\n for (int i = 0; i < N; i++) {\n for (auto c : S[i]) {\n a.push_back(c);\n }\n }\n ranges::sort(a);\n a.erase(ranges::unique(a).begin(), a.end());\n\n int siz = static_cast<int>(a.size());\n vector<string> res = S;\n vector<bool> used(10, false);\n vector<vector<int>> ch(siz, vector(2, 0));\n set<int> front;\n for (int i = 0; i < N; i++) {\n int ke = 1;\n for (int j = S[i].size() - 1; j >= 0; j--) {\n for (int k = 0; k < siz; k++) {\n if (S[i][j] == a[k]) {\n if (i == N - 1) {\n ch[k][1] += ke;\n } else {\n ch[k][0] += ke;\n }\n\n if (j == 0 && S[i].size() >= 2) {\n front.insert(k);\n }\n }\n }\n ke *= 10;\n }\n }\n\n int sum = 0;\n int sn = 0;\n auto dfs = [&](auto dfs, int id) -> void {\n if (id == siz) {\n if (sum == sn) {\n ans++;\n }\n return;\n }\n\n for (int x = 0; x <= 9; x++) {\n if (used[x]) {\n continue;\n }\n\n bool ok = true;\n if (x == 0 && front.contains(id)) {\n ok = false;\n }\n\n used[x] = true;\n sum += ch[id][0] * x;\n sn += ch[id][1] * x;\n if (ok) {\n dfs(dfs, id + 1);\n }\n sum -= ch[id][0] * x;\n sn -= ch[id][1] * x;\n used[x] = false;\n }\n };\n\n dfs(dfs, 0);\n}\n\nint main() {\n while (true) {\n int N;\n cin >> N;\n if (N == 0) {\n break;\n }\n\n vector<string> S(N);\n for (int i = 0; i < N; i++) {\n cin >> S[i];\n }\n\n ans = 0;\n solve(N, S);\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 3000, "memory_kb": 3456, "score_of_the_acc": -0.639, "final_rank": 7 }, { "submission_id": "aoj_1161_10610778", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<set>\nusing namespace std;\nint N,M;\nvector<string>S;\nvector<int>pats[17];\nvector<bool>head;\nint sz[17];\nvector<int>num,coef;\nbool check()\n{\n\tint sum=0;\n\tfor(int i=0;i<M;i++)if(head[i]&&!num[i])return false;\n\tfor(int i=0;i<M;i++)sum+=num[i]*coef[i];\n\treturn sum==0;\n}\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n while(1)\n\t{\n\t\tcin>>N;\n\t\tif(N==0)break;\n\t\tS=vector<string>(N);\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tcin>>S[i];\n\t\t\tpats[i].clear();\n\t\t}\n\t\tset<char>s;\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tsz[i]=S[i].size();\n\t\t\tfor(int j=0;j<sz[i];j++)s.insert(S[i][j]);\n\t\t}\n\t\tvector<int>alphabet;\n\t\tfor(int c:s)alphabet.push_back(c);\n\t\tM=alphabet.size();\n\t\thead=vector<bool>(M);\n\t\tnum=vector<int>(M);\n\t\tcoef=vector<int>(M);\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tfor(int j=0;j<sz[i];j++)\n\t\t\t{\n\t\t\t\tfor(int k=0;k<M;k++)if(alphabet[k]==S[i][j])\n\t\t\t\t{\n\t\t\t\t\tpats[i].push_back(k);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tint keta=1;\n\t\t\tfor(int j=sz[i]-1;j>=0;j--)\n\t\t\t{\n\t\t\t\tif(i<N-1)coef[pats[i][j]]+=keta;\n\t\t\t\telse coef[pats[i][j]]-=keta;\n\t\t\t\tketa*=10;\n\t\t\t\tif(j==0&&sz[i]>1)head[pats[i][j]]=true;\n\t\t\t}\n\t\t}\n\t\tint ans=0;\n\t\tint b=(1<<M)-1;\n\t\twhile(b<(1<<10))\n\t\t{\n\t\t\tint p=0;\n\t\t\tfor(int i=0;i<10;i++)\n\t\t\t{\n\t\t\t\tif((b>>i)&1)\n\t\t\t\t{\n\t\t\t\t\tnum[p]=i;\n\t\t\t\t\tp++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tdo{\n\t\t\t\tif(check())ans++;\n\t\t\t}while(next_permutation(num.begin(),num.end()));\n\t\t\tint x=b&(-b);\n\t\t\tint y=b+x;\n\t\t\tb=((b&(~y))/x>>1)|y;\n\t\t}\n\t\tcout<<ans<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 2500, "memory_kb": 3456, "score_of_the_acc": -0.5594, "final_rank": 5 }, { "submission_id": "aoj_1161_10607554", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef int ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rrep(i,start,end) for (ll i = start;i >= (ll)(end);i--)\n#define repn(i,end) for(ll i = 0; i <= (ll)(end); i++)\n#define reps(i,start,end) for(ll i = start; i < (ll)(end); i++)\n#define repsn(i,start,end) for(ll i = start; i <= (ll)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef vector<ll> vll;\ntypedef vector<pair<ll ,ll>> vpll;\ntypedef vector<vector<ll>> vvll;\ntypedef set<ll> sll;\ntypedef map<ll , ll> mpll;\ntypedef pair<ll ,ll> pll;\ntypedef tuple<ll , ll , ll> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (ll)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1 << 30;\nconst ld EPS = 1e-9;\n \nll lceil(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b)+1;}else{return -((-a)/b);}}\nll lfloor(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b);}else{return -((-a)/b)-1;}}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\n//0indexed\ninline ll topbit(ll a){assert(a != 0);return 63 - __builtin_clzll(a);}\ninline ll smlbit(ll a){assert(a != 0);return __builtin_ctzll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\nvoid solve(ll n){\n vector<string> S(n);\n vector<vector<ll>> s(n);\n map<char,ll> mp;\n rep(i,n){\n cin >> S[i];\n reverse(all(S[i]));\n each(p,S[i]){\n if(!mp.contains(p))mp[p] = sz(mp);\n s[i].push_back(mp[p]);\n }\n }\n\n vll ord(10);\n iota(all(ord),0);\n vll ten(10);\n rep(i,10){\n ten[i] = lpow(10,i);\n }\n vll se;\n do{\n ll sum = 0;\n //枝刈り\n ll btm =0;\n bool ok = true;\n rep(i,n-1){\n if(sz(s[i]) >1 && ord[s[i].back()] == 0)ok = false;\n btm += ord[s[i][0]];\n }\n if(btm % 10 != ord[s[n-1][0]] or !ok or (sz(s[n-1]) >1 && ord[s[n-1].back()] == 0))continue;\n rep(i,n){\n ll now = 0;\n // if(sz(s[i]) >1 && ord[s[i].back()] == 0)break;\n rep(j,sz(s[i])){\n now += ord[s[i][j]] * ten[j];\n }\n if(i == n-1){\n if(sum == now){\n ll v= 0;\n rep(j,sz(mp)){\n v *= 10;\n v += ord[j];\n }\n se.push_back(v);\n }\n }else{\n sum += now;\n }\n }\n }while(next_permutation(all(ord)));\n\n sort(all(se));\n UNIQUE(se);\n cout << sz(se) << endl;\n \n\n}\n\nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true){\n LL(n);\n if(n == 0)break;\n solve(n);\n }\n}", "accuracy": 1, "time_ms": 2530, "memory_kb": 3812, "score_of_the_acc": -1.0048, "final_rank": 16 }, { "submission_id": "aoj_1161_10465299", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing ull=unsigned long long;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define loop(n) for (int tjh = 0; tjh < (int)(n); tjh++)\nconstexpr int maxN=12;constexpr int maxS=8;\nsigned main() {\n cin.tie(0)->sync_with_stdio(0);//NOLINT\n cout<<fixed<<setprecision(16);\n array<string,maxN>S;\n array<int,26>S0;\n array<char,maxN*maxS>S1;\n int v,res,re0,re1;\n for (int N;cin>>N,N;) {\n v=0;res=0;\n rep(i,N) {\n cin>>S[i];\n for (char c:S[i]){S1[v++]=c;}\n }\n sort(S1.begin(),S1.begin()+v);\n v=(int)distance(S1.begin(),unique(S1.begin(),S1.begin()+v));\n for (int i=v;i<10;i++)S1[i]='|';\n do {\n rep(i,10) {\n if (S1[i]=='|')continue;\n S0[S1[i]-'A']=i;\n }\n [&]()->void {\n rep(i,N)if ((int)S[i].size()!=1&&!S0[S[i][0]-'A'])return;\n re1=0;\n rep(i,N-1) {\n re0=0;\n rep(j,S[i].size())re0=re0*10+S0[S[i][j]-'A'];\n re1+=re0;\n }\n re0=0;\n rep(j,S[N-1].size())re0=re0*10+S0[S[N-1][j]-'A'];\n if (re0==re1)res++;\n return;\n }();\n }while (next_permutation(S1.begin(),S1.begin()+10));\n cout<<res<<'\\n';\n }\n}", "accuracy": 1, "time_ms": 5280, "memory_kb": 3456, "score_of_the_acc": -1.0021, "final_rank": 15 }, { "submission_id": "aoj_1161_9554033", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nll X[27] = {};\n\nll decode(string& S) {\n ll Ret = 0;\n rep(i,0,S.size()) {\n Ret *= 10;\n Ret += X[S[i]-'A'];\n }\n return Ret;\n}\n\nint main() {\nwhile(1) {\n int N;\n cin >> N;\n if (N == 0) return 0;\n N--;\n vector<string> S(N);\n rep(i,0,N) cin >> S[i];\n string T;\n cin >> T;\n vector<char> C;\n rep(i,0,N) rep(j,0,S[i].size()) C.push_back(S[i][j]);\n rep(i,0,T.size()) C.push_back(T[i]);\n UNIQUE(C);\n vector<int> V;\n rep(i,0,C.size()) V.push_back(C[i]-'A');\n while(V.size() < 10) V.push_back(26);\n ll ANS = 0;\n do {\n rep(i,0,10) X[V[i]] = i;\n bool check = true;\n rep(i,0,N) if ((S[i].size() != 1) && V[0] == (S[i][0] - 'A')) check = false;\n if ((T.size() != 1) && V[0] == (T[0] - 'A')) check = false;\n if (!check) continue;\n ll COUNT = 0;\n rep(i,0,N) COUNT += decode(S[i]);\n if (COUNT == decode(T)) ANS++;\n } while(next_permutation(ALL(V)));\n cout << ANS << endl;\n}\n}", "accuracy": 1, "time_ms": 7000, "memory_kb": 3196, "score_of_the_acc": -0.9542, "final_rank": 14 }, { "submission_id": "aoj_1161_9297445", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nbool solve()\n{\n int N;\n cin>>N;\n if(N==0)return 0;\n vector<string>S(N);\n for(int i=0;i<N;i++)cin>>S[i];\n map<char,int>mp;\n for(int i=0;i<N;i++)for(char c:S[i])mp[c]=mp.count(c)?mp[c]:mp.size();\n vector<vector<int>>A(N);\n for(int i=0;i<N;i++)\n {\n A[i].reserve(S[i].size());\n for(char c:S[i])A[i].push_back(mp[c]);\n }\n assert(mp.size()<=10);\n vector<int>P(10);\n iota(P.begin(),P.end(),0);\n int ans=0;\n do\n {\n bool ok=1;\n int sum=0;\n for(int i=0;i<N;i++)\n {\n if(A[i].size()>1&&P[A[i][0]]==0)ok=0;\n if(i==N-1)break;\n int cur=0;\n for(int a:A[i])cur=10*cur+P[a];\n sum+=cur;\n }\n int cur=0;\n for(int a:A[N-1])cur=10*cur+P[a];\n ok&=(sum==cur);\n ans+=ok;\n }while(next_permutation(P.begin(),P.end()));\n for(int i=1;i<=10-mp.size();i++)ans/=i;\n cout<<ans<<'\\n';\n return 1;\n}\nint main(){while(solve()){}}", "accuracy": 1, "time_ms": 7690, "memory_kb": 3452, "score_of_the_acc": -1.3809, "final_rank": 19 }, { "submission_id": "aoj_1161_9237190", "code_snippet": "#include <bits/stdc++.h>\n\nint solve() {\n int n;\n std::cin >> n;\n if (n == 0) return 1;\n std::vector<std::string> ss(n);\n for (int i = 0; i < n; i++) std::cin >> ss[i];\n std::vector<char> alpha;\n for (auto s: ss) {\n for (auto c: s) {\n alpha.push_back(c);\n }\n }\n std::sort(alpha.begin(), alpha.end());\n alpha.erase(std::unique(alpha.begin(), alpha.end()), alpha.end());\n int m = alpha.size();\n std::vector<char> mapping(256);\n for (int i = 0; i < m; i++) mapping[alpha[i]] = i;\n\n int ans = 0;\n std::vector<char> state(10);\n for (int i = 0; i < m; i++) state[9 - i] = 1;\n do {\n std::vector<char> index;\n for (int i = 0; i < 10; i++) {\n if (state[i]) index.push_back(i);\n }\n assert((int)index.size() == m);\n do {\n int cur = 0;\n for (int i = 0; i < n; i++) {\n int v = 0;\n if (index[mapping[ss[i].front()]] == 0 && ss[i].size() != 1) {\n cur = -1;\n break;\n }\n for (auto c: ss[i]) {\n v = 10 * v + index[mapping[c]];\n }\n if (i + 1 < n) cur += v;\n else cur -= v;\n }\n if (cur == 0) {\n ans++;\n }\n } while (std::next_permutation(index.begin(), index.end()));\n } while (std::next_permutation(state.begin(), state.end()));\n\n std::cout << ans << '\\n';\n return 0;\n}\n\nint main() {\n while (!solve());\n}", "accuracy": 1, "time_ms": 5220, "memory_kb": 3296, "score_of_the_acc": -0.7945, "final_rank": 11 }, { "submission_id": "aoj_1161_9201658", "code_snippet": "#include <bits/stdc++.h>\n\nbool solve() {\n int N;\n std::cin >> N;\n if (N == 0) return false;\n std::vector<std::string> S(N);\n for (auto& s : S) {\n std::cin >> s;\n std::reverse(s.begin(), s.end());\n }\n {\n int maxLen{};\n for (int i{} ; i < N - 1 ; i++) {\n maxLen = std::max(maxLen, (int)S[i].size());\n }\n if (maxLen > (int)S[N - 1].size()) {\n std::cout << 0 << '\\n';\n return true;\n }\n }\n int K{};\n std::vector<char> chs;\n std::vector<int> inv(26, -1);\n {\n std::vector<bool> app(26);\n for (const auto& s : S) {\n for (auto c : s) {\n if (app[c - 'A'] == false) {\n app[c - 'A'] = true;\n chs.push_back(c);\n inv[c - 'A'] = K++;\n }\n }\n }\n }\n std::vector<int> use(10);\n for (int i{} ; i < K ; i++) {\n use[i] = 1;\n }\n std::reverse(use.begin(), use.end());\n std::vector<std::string> tate(S[N - 1].size());\n for (int i{} ; i < (int)S[N - 1].size() ; i++) {\n for (int j{} ; j < N ; j++) if (i < S[j].size()) {\n tate[i] += S[j][i];\n }\n }\n int ans{};\n do {\n std::vector<int> num(K);\n for (int i{}, j{} ; i < 10 ; i++) {\n if (use[i] == 1) {\n num[j++] = i;\n }\n }\n do {\n bool leadZero{};\n for (const auto& s : S) {\n if (s.size() > 1u and num[inv[s.back() - 'A']] == 0) leadZero = true;\n }\n if (leadZero) continue;\n int up{};\n bool ok{true};\n for (int i{} ; i < (int)S[N - 1].size() ; i++) {\n int cur{};\n for (int j{} ; j < (int)tate[i].size() - 1 ; j++) {\n cur += num[inv[tate[i][j] - 'A']];\n }\n cur += up;\n up = 0;\n if (cur % 10 != num[inv[tate[i].back() - 'A']]) {\n ok = false;\n break;\n }\n up = cur / 10;\n }\n if (up > 0) ok = false;\n if (ok) ans++;\n } while (std::next_permutation(num.begin(), num.end()));\n } while (std::next_permutation(use.begin(), use.end()));\n std::cout << ans << '\\n';\n return true;\n}\n\nint main() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n while (solve()) ;\n}", "accuracy": 1, "time_ms": 3050, "memory_kb": 3148, "score_of_the_acc": -0.2658, "final_rank": 2 }, { "submission_id": "aoj_1161_9152720", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = 3.141592653589793;\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\ntemplate<typename T> void view(const vv<T>& vv){ for(const auto& v : vv){ view(v); } }\n\nbool next_combination(int N, vi &P){\n int k = len(P);\n rep(i, k - 1) if (P[i] + 1 < P[i + 1]){\n P[i]++;\n rep(j, i) P[j] = j;\n return true;\n }\n if (P[k - 1] < N - 1){\n P[k - 1]++;\n rep(i, k - 1) P[i] = i;\n return true;\n }\n return false;\n}\n\nint solve(int N){\n set<char> tot;\n vc<string> A(N); rep(i, N) cin >> A[i];\n for (auto a : A) for (auto x : a) tot.insert(x);\n int K = len(tot);\n vi to(26), zero(K, 0);\n int id = 0;\n for (auto x : tot){\n to[x - 'A'] = id;\n id++;\n }\n vl T(K, 0);\n rep(i, N){\n reverse(all(A[i]));\n if (len(A[i]) > 1) zero[to[A[i].back() - 'A']] = 1;\n ll p = 1;\n for (auto x : A[i]){\n T[to[x - 'A']] += (i == N - 1 ? -p : p);\n p *= 10;\n }\n }\n int ans = 0;\n vi P(K); rep(i, K) P[i] = i;\n do{\n vi Q = P;\n do{\n ll sm = 0;\n bool flag = true;\n for (auto c : tot){\n sm += T[to[c - 'A']] * Q[to[c - 'A']];\n if (Q[to[c - 'A']] == 0 && zero[to[c - 'A']]){\n flag = false;\n break;\n }\n }\n if (flag && sm == 0) ans++;\n }while (next_permutation(all(Q)));\n }while (next_combination(10, P));\n return ans;\n}\n\nint main(){\n vc<int> ans;\n while (true){\n int N; cin >> N;\n if (N == 0) break;\n ans.push_back(solve(N));\n }\n for (auto x : ans) cout << x << endl;\n}", "accuracy": 1, "time_ms": 7610, "memory_kb": 3072, "score_of_the_acc": -0.8979, "final_rank": 13 }, { "submission_id": "aoj_1161_7997963", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\n#define rep(i,n) for(ll i=0;i<n;i++)\n#define all(A) A.begin(),A.end()\n\nstring rev(string S) {\n reverse(S.begin(), S.end());\n return S;\n}\n\n\nll trans(vector<ll>& tr, string S,ll bs) {\n if(tr[S[0]-'A']==0&&S.size()>1)return -1;\n ll SN = S.size();\n ll res = 0;\n rep(i, SN) {\n res = res * 10 + tr[S[i] - 'A'];\n }\n if(bs<res)return -1;\n return res;\n}\nvector<char> P;\nvll TR(26, 0);\nll an=0;\nll N;\nvector<string> S;\nvoid next_comb(ll size,ll max,vll &now_vector){\n ll now_size = now_vector.size();\n\tif (now_size == size) {\n sort(all(P));\n ll PN=P.size();\n do {\n rep(k, PN)TR[P[k] - 'A'] =now_vector[k];\n ll bs=trans(TR,S[N-1],1e18);\n if(bs==-1)continue;\n ll p=bs%10;\n rep(i,N-1){\n p-=TR[S[i].back()-'A'];\n }\n if(p%10!=0)continue;\n rep(i, N-1) {\n ll s=trans(TR,S[i],bs);\n if(s==-1){\n bs=-1;\n break;\n }\n bs-=s;\n }\n if (bs == 0){\n an++;\n }\n } while (next_permutation(all(P)));\n\t}\n\telse {\n\t\tvll next = now_vector;\n\t\tif (now_size == 0) {\n\t\t\tfor (ll i = 0; i < max; i++) {\n\t\t\t\tnext.push_back(i);\n\t\t\t\tnext_comb(size, max, next);\n\t\t\t\tnext.pop_back();\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tll LAST = next[now_size - 1];\n\t\t\tfor (ll i = LAST + 1; i < max; i++) {\n\t\t\t\tnext.push_back(i);\n\t\t\t\tnext_comb(size, max, next);\n\t\t\t\tnext.pop_back();\n\t\t\t}\n\t\t}\n\t}\n\treturn;\n}\n\n\nint main() {\n while (1) {\n cin >> N;\n if (N == 0)return 0;\n S.resize(N);\n set<char> C;\n rep(i, N) {\n cin >> S[i];\n for (char s : S[i])C.insert(s);\n }\n P.clear();\n TR.assign(26,0);\n for (auto c : C)P.push_back(c);\n an = 0;\n vector<ll> B={};\n next_comb(P.size(),10,B);\n cout << an << endl;\n\n }\n}", "accuracy": 1, "time_ms": 7050, "memory_kb": 3352, "score_of_the_acc": -1.1552, "final_rank": 18 }, { "submission_id": "aoj_1161_7997562", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nbool solve() {\n\tint N;\n\tcin >> N;\n\tif( N == 0 ) return false;\n\tvector<string> S(N);\n\tvector<vector<int>> s(N, vector<int>());\n\tset<char> C;\n\tfor( int i = 0; i < N; i++ ) {\n\t\tcin >> S[i];\n\t\tfor( char c : S[i] ) C.insert(c);\n\t}\n\tvector<char> Cv(C.begin(), C.end());\n\tfor( int i = 0; i < N; i++ ) {\n\t\tfor( char c : S[i] ) s[i].push_back(lower_bound(Cv.begin(), Cv.end(), c)-Cv.begin());\n\t\treverse(s[i].begin(), s[i].end());\n\t}\n\tint ans = 0;\n\tvector<int> p(10);\n\tiota(p.begin(), p.end(), 0);\n\tauto convert = [&](int i) -> int {\n\t\tint ret = 0;\n\t\tfor( int j = 0, B = 1; j < s[i].size(); j++, B*=10 ) {\n\t\t\tret += p[s[i][j]]*B;\n\t\t}\n\t\tif( s[i].size() > 1 && p[s[i].back()] == 0 ) return -1;\n\t\telse return ret;\n\t};\n\tdo {\n\t\tint X = convert(N-1), Y = 0;\n\t\tbool is_valid = true;\n\t\tfor( int i = 0; i < N-1 && Y <= X; i++ ) {\n\t\t\tif( convert(i) == -1 ) is_valid = false;\n\t\t\telse Y += convert(i);\n\t\t}\n\t\tif( is_valid == true && X == Y ) ans++;\n\t}while( next_permutation(p.begin(), p.end()) );\n\tint DIV = 1;\n\tfor( int i = 1; i <= 10-C.size(); i++ ) {\n\t\tDIV *= i;\n\t}\n\tcout << ans/DIV << endl;\n\treturn true;\n}\nint main() {\n\twhile( solve() == true ) {}\n}", "accuracy": 1, "time_ms": 8780, "memory_kb": 3376, "score_of_the_acc": -1.4604, "final_rank": 20 }, { "submission_id": "aoj_1161_7940782", "code_snippet": "#include <algorithm>\n#include <cstring>\n#include <iostream>\n#include <string>\nusing namespace std;\nint n, cnt, a[13][9], l[13], p[11], used[11], zero[11];\nchar c[11];\nint solve(int depth) {\n if (depth == cnt) {\n int ret = 0;\n for (int i = 0; i < n; i++) {\n int res = 0;\n for (int j = l[i] - 1; j >= 0; j--)\n res = res * 10 + p[a[i][j]];\n if (i + 1 == n)\n ret -= res;\n else\n ret += res;\n }\n return ret ? 0 : 1;\n }\n int ret = 0;\n for (int i = 0; i < 10; i++) {\n if (!used[i]) {\n used[i] = 1, p[depth] = i;\n if (i || zero[depth])\n ret += solve(depth + 1);\n used[i] = 0;\n }\n }\n return ret;\n}\nint main() {\n string s;\n while (cin >> n, n) {\n cnt = 0;\n memset(c, 0, 11);\n memset(zero, -1, 44);\n for (int i = 0; i < n; i++) {\n cin >> s;\n l[i] = s.size();\n reverse(s.begin(), s.end());\n for (int j = 0; j < s.size(); j++) {\n int flag = 0;\n for (int k = 0; k < cnt; k++) {\n if (s[j] == c[k]) {\n a[i][j] = k, flag = 1;\n break;\n }\n }\n if (!flag)\n a[i][j] = cnt, c[cnt++] = s[j];\n }\n if (s.size() > 1)\n zero[a[i][s.size() - 1]] = 0;\n }\n cout << solve(0) << endl;\n }\n}", "accuracy": 1, "time_ms": 7910, "memory_kb": 3004, "score_of_the_acc": -0.8615, "final_rank": 12 }, { "submission_id": "aoj_1161_7940780", "code_snippet": "#include <algorithm>\n#include <cstring>\n#include <iostream>\n#include <string>\nusing namespace std;\nint n, cnt, a[13][9], l[13], x[11], used[11], zero[11], power[9];\nchar c[11];\nint solve(int depth, int value) {\n if (depth == cnt)\n return value ? 0 : 1;\n int ret = 0;\n for (int i = 0; i < 10; i++) {\n if (!used[i]) {\n used[i] = 1;\n if (i || zero[depth])\n ret += solve(depth + 1, value + x[depth] * i);\n used[i] = 0;\n }\n }\n return ret;\n}\nint main() {\n string s;\n power[0] = 1;\n for (int i = 1; i < 9; i++)\n power[i] = power[i - 1] * 10;\n while (cin >> n, n) {\n cnt = 0;\n for (int i = 0; i < 10; i++)\n zero[i] = 1, x[i] = c[i] = 0;\n for (int i = 0; i < n; i++) {\n cin >> s;\n l[i] = s.size();\n reverse(s.begin(), s.end());\n for (int j = 0; j < s.size(); j++) {\n int flag = 0;\n for (int k = 0; k < cnt; k++) {\n if (s[j] == c[k]) {\n a[i][j] = k, flag = 1;\n break;\n }\n }\n if (!flag)\n a[i][j] = cnt, c[cnt++] = s[j];\n }\n if (l[i] > 1)\n zero[a[i][l[i] - 1]] = 0;\n for (int j = 0; j < l[i]; j++)\n x[a[i][j]] += power[j] * (i + 1 == n ? -1 : 1);\n }\n cout << solve(0, 0) << endl;\n }\n}", "accuracy": 1, "time_ms": 3340, "memory_kb": 3160, "score_of_the_acc": -0.3268, "final_rank": 3 }, { "submission_id": "aoj_1161_7940777", "code_snippet": "#include <cmath>\n#include <cstdio>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <vector>\nusing namespace std;\n#define rep(i, a) for (int i = 0; i < a; i++)\ntypedef long long ll;\nll ans, n, cnt;\nbool used[15];\nll keisu[15];\nbool dame[15];\nvoid dfs(int k, ll sum) {\n if (k == cnt) {\n if (!sum)\n ans++;\n return;\n }\n rep(i, 10) {\n if (used[i] || (i == 0 && dame[k]))\n continue;\n used[i] = true;\n dfs(k + 1, sum + i * keisu[k]);\n used[i] = false;\n }\n return;\n}\nint main() {\n while (cin >> n, n) {\n vector<string> str(n);\n map<char, int> id;\n cnt = 0;\n ans = 0;\n rep(i, 15) {\n used[i] = false;\n keisu[i] = 0;\n dame[i] = false;\n }\n rep(i, n) {\n cin >> str[i];\n rep(j, str[i].size()) {\n if (id.find(str[i][j]) == id.end()) {\n id[str[i][j]] = cnt++;\n }\n if (j == 0 && str[i].length() > 1)\n dame[id[str[i][j]]] = true;\n if (i != n - 1)\n keisu[id[str[i][j]]] += (int)pow(10.0, str[i].size() - j - 1);\n else\n keisu[id[str[i][j]]] -= (int)pow(10.0, str[i].size() - j - 1);\n }\n }\n dfs(0, 0);\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 3510, "memory_kb": 3364, "score_of_the_acc": -0.6064, "final_rank": 6 }, { "submission_id": "aoj_1161_7940774", "code_snippet": "#include <algorithm>\n#include <bitset>\n#include <cmath>\n#include <complex>\n#include <cstdio>\n#include <cstring>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <vector>\n#define rep(i, a) for (int i = 0; i < (a); i++)\n#define repi(i, a, b) for (int i = (a); i < (b); i++)\n#define repd(i, a, b) for (int i = (a); i >= (b); i--)\n#define repit(i, a) \\\n for (__typeof((a).begin()) i = (a).begin(); i != (a).end(); i++)\n#define all(u) (u).begin(), (u).end()\n#define rall(u) (u).rbegin(), (u).rend()\n#define UNIQUE(u) (u).erase(unique(all(u)), (u).end())\n#define pb push_back\n#define mp make_pair\n#define INF 1e9\n#define EPS 1e-9\n#define PI acos(-1.0)\nusing namespace std;\ntypedef long long ll;\ntypedef vector<int> vi;\n#define dump(x) cerr << #x << \" = \" << (x) << endl;\nint pw10[10] = {1};\nvoid gen() { repi(i, 1, 10) pw10[i] = pw10[i - 1] * 10; }\nint N, M;\nvector<bool> nonzero;\nvector<int> coef;\nint ans, used;\nvoid init() {\n nonzero.clear();\n coef.clear();\n ans = used = 0;\n}\nvoid input() {\n map<char, bool> nz;\n map<char, int> c;\n rep(i, N) {\n string s;\n cin >> s;\n if (s.length() >= 2)\n nz[s[0]] = true;\n rep(j, (int)s.length()) if (i < N - 1) c[s[j]] +=\n pw10[(int)s.length() - j - 1];\n else c[s[j]] -= pw10[(int)s.length() - j - 1];\n }\n repit(it, c) {\n nonzero.pb(nz[it->first]);\n coef.pb(it->second);\n }\n M = coef.size();\n}\nvoid dfs(int depth, int value) {\n if (depth == M) {\n ans += value == 0;\n return;\n }\n if (!nonzero[depth] && ~used & 1) {\n used ^= 1;\n dfs(depth + 1, value);\n used ^= 1;\n }\n repi(i, 1, 10) {\n if (~used >> i & 1) {\n used ^= 1 << i;\n dfs(depth + 1, value + coef[depth] * i);\n used ^= 1 << i;\n }\n }\n}\nint main() {\n gen();\n while (cin >> N && N) {\n init();\n input();\n dfs(0, 0);\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 2710, "memory_kb": 3008, "score_of_the_acc": -0.0384, "final_rank": 1 }, { "submission_id": "aoj_1161_7940768", "code_snippet": "#include <bits/stdc++.h>\n#define N 10\nusing namespace std;\nint n, m, d[N], ans;\nmap<char, int> c;\nset<char> ish;\nbool used[N];\nbool q[N];\nstring s;\nint p[N];\nvoid func(int x) {\n if (x == m) {\n int f = 0, sum = 0;\n for (int i = 0; i < m; i++) {\n if (!d[i] && q[i])\n f = 1;\n sum += p[i] * d[i];\n }\n if (f)\n return;\n if (!sum)\n ans++;\n return;\n }\n for (int i = 0; i < 10; i++) {\n if (used[i])\n continue;\n d[x] = i;\n used[i] = true;\n func(x + 1);\n used[i] = false;\n }\n}\nint main() {\n while (1) {\n cin >> n;\n if (!n)\n break;\n for (int i = 0; i < n; i++) {\n cin >> s;\n for (int j = s.size() - 1, k = 1; j >= 0; j--, k *= 10) {\n if (!j && s.size() != 1)\n ish.insert(s[j]);\n if (c.find(s[j]) == c.end())\n if (i != n - 1)\n c[s[j]] = k;\n else\n c[s[j]] = -k;\n else if (i != n - 1)\n c[s[j]] += k;\n else\n c[s[j]] -= k;\n }\n }\n memset(q, 0, sizeof(q));\n map<char, int>::iterator ite;\n int k = 0;\n for (ite = c.begin(); ite != c.end(); ite++, k++) {\n p[k] = (*ite).second;\n if (ish.find((*ite).first) != ish.end())\n q[k] = true;\n }\n m = c.size();\n ans = 0;\n func(0);\n cout << ans << endl;\n ish.clear();\n c.clear();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 7660, "memory_kb": 3172, "score_of_the_acc": -1.0296, "final_rank": 17 } ]
aoj_1162_cpp
Problem D: Discrete Speed Consider car trips in a country where there is no friction. Cars in this country do not have engines. Once a car started to move at a speed, it keeps moving at the same speed. There are acceleration devices on some points on the road, where a car can increase or decrease its speed by 1. It can also keep its speed there. Your job in this problem is to write a program which determines the route with the shortest time to travel from a starting city to a goal city. There are several cities in the country, and a road network connecting them. Each city has an acceleration device. As mentioned above, if a car arrives at a city at a speed v , it leaves the city at one of v - 1, v , or v + 1. The first road leaving the starting city must be run at the speed 1. Similarly, the last road arriving at the goal city must be run at the speed 1. The starting city and the goal city are given. The problem is to find the best route which leads to the goal city going through several cities on the road network. When the car arrives at a city, it cannot immediately go back the road it used to reach the city. No U-turns are allowed. Except this constraint, one can choose any route on the road network. It is allowed to visit the same city or use the same road multiple times. The starting city and the goal city may be visited during the trip. For each road on the network, its distance and speed limit are given. A car must run a road at a speed less than or equal to its speed limit. The time needed to run a road is the distance divided by the speed. The time needed within cities including that for acceleration or deceleration should be ignored. Input The input consists of multiple datasets, each in the following format. n m s g x 1 y 1 d 1 c 1 ... x m y m d m c m Every input item in a dataset is a non-negative integer. Input items in the same line are separated by a space. The first line gives the size of the road network. n is the number of cities in the network. You can assume that the number of cities is between 2 and 30, inclusive. m is the number of roads between cities, which may be zero. The second line gives the trip. s is the city index of the starting city. g is the city index of the goal city. s is not equal to g . You can assume that all city indices in a dataset (including the above two) are between 1 and n , inclusive. The following m lines give the details of roads between cities. The i -th road connects two cities with city indices x i and y i , and has a distance d i (1 ≤ i ≤ m ). You can assume that the distance is between 1 and 100, inclusive. The speed limit of the road is specified by c i . You can assume that the speed limit is between 1 and 30, inclusive. No two roads connect the same pair of cities. A road never connects a city with itself. Each road can be traveled in both directions. The last dataset is followed by a line containing two zeros (separated by a space). Output For each dataset in the input, one line should b ...(truncated)
[ { "submission_id": "aoj_1162_10849611", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct Node{\n\tint pos;\n\tint speed;\n\tdouble cost;\n\tint prev;\n};\nbool operator < (const Node &a,const Node &b){\n\treturn a.cost > b.cost;\n}\n\n\n\nint main(){\n\tint n,m;\n\twhile(cin >> n >> m and n){\n\t\tvector<Node> G[n];\n\t\tint s,g;\n\t\tcin >> s >> g;\n\t\t--s,--g;\n\t\tfor(int i = 0 ; i < m ; i++){\n\t\t\tint a,b,c;\n\t\t\tdouble d;\n\t\t\tcin >> a >> b >> d >> c;\n\t\t\t--a,--b;\n\t\t\tG[a].push_back({b,c,d,a});\n\t\t\tG[b].push_back({a,c,d,b});\n\t\t}\n\t\tpriority_queue<Node> Q;\n\n\t\tfor( auto e : G[s] ){\n\t\t\tint nv = 1;\n\t\t\tif( nv <= e.speed ){\n\t\t\t\tQ.push({e.pos,nv,e.cost/nv,s});\n\t\t\t}\n\t\t}\n\n\t\t//Q.push({s,1,0,31});\n\n\t\tint done[31][31][32] = {};\n\t\twhile( Q.size() ){\n\t\t\tNode q = Q.top(); Q.pop();\n\t\t\tif( done[q.pos][q.speed][q.prev]++ ) continue;\n\t\t\tif( q.pos == g and q.speed == 1 ){\n\t\t\t\tprintf(\"%.10lf\\n\",q.cost);\n\t\t\t\tgoto finish;\n\t\t\t}\n\n\t\t\tif( q.speed != 0 )\n\t\t\t\tfor( auto e : G[q.pos] ){\n\t\t\t\t\tfor(int nv = q.speed-1 ; nv <= q.speed + 1 ; nv++){\n\t\t\t\t\t\tif( nv > 0 and nv <= e.speed and e.pos != q.prev ){\n\t\t\t\t\t\t\tQ.push({e.pos,nv,q.cost+e.cost/nv,q.pos});\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t}\n\t\tcout << \"unreachable\" << endl;\n\t\tfinish:;\n\t}\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 23028, "score_of_the_acc": -0.6166, "final_rank": 12 }, { "submission_id": "aoj_1162_10631376", "code_snippet": "#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n// #ifndef ONLINE_JUDGE\n// #define _GLIBCXX_DEBUG // 配列外参照のエラー\n// #endif\n\n// スタンダードライブラリ\n#include <bits/stdc++.h>\nusing namespace std;\n\n// 型関連\nusing ll = long long;\nusing lint = long long;\nusing pll = pair<ll, ll>;\nusing plll = tuple<ll, ll, ll>;\nusing pii = pair<int, int>;\nusing piii = tuple<ll, ll, ll>;\ntemplate <class T> using prique = priority_queue<T>;\n\n// 型定数\nconstexpr ll mod = 998244353;\nconstexpr ll MOD = 1000000007;\nint INF32 = 2e9;\nll INF64 = 9e18;\n#define endl '\\n';\n\nint dx[4] = {1, 0, -1, 0};\nint dy[4] = {0, 1, 0, -1};\n\n/////////////////////////// print関連\ntemplate <typename T> void print(vector<T> A);\nvoid print();\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail);\nvoid print(string S);\ntemplate <typename T> void print(vector<vector<T>> &F);\n\ninline void Yes(bool f);\n\n///////////////////ここから//////////////////////\nusing T = tuple<double, int, int, int>;\nusing piiii = tuple<int, int, int, int>;\nbool solve() {\n int N, M;\n cin >> N >> M;\n if (N == 0) {\n return false;\n }\n int s, g;\n cin >> s >> g;\n s--;\n g--;\n vector<vector<piiii>> G(N);\n for (int i = 0; i < M; i++) {\n int x, y, d, c;\n cin >> x >> y >> d >> c;\n x--;\n y--;\n G[x].emplace_back(y, d, c, i);\n G[y].emplace_back(x, d, c, i);\n }\n int max_speed = 31;\n vector<vector<vector<double>>> dist(\n N, vector<vector<double>>(max_speed, vector<double>(M + 1, 1e15)));\n vector<vector<vector<int>>> f(\n N, vector<vector<int>>(max_speed, vector<int>(M + 1, 0)));\n\n priority_queue<T, vector<T>, greater<T>> que;\n dist[s][0][M] = 0;\n que.emplace(0.0, s, 0, M);\n while (!que.empty()) {\n auto [d, v, s, m] = que.top();\n que.pop();\n if (f[v][s][m]) {\n continue;\n }\n f[v][s][m] = 1;\n for (int ns = s - 1; ns < s + 2; ns++) {\n if (ns < 1) {\n continue;\n }\n for (int n = 0; n < G[v].size(); n++) {\n auto [nv, l, s_limit, nm] = G[v][n];\n if (s_limit < ns || nm == m || f[nv][ns][nm]) {\n continue;\n }\n double nd = d + (double)l / ns;\n\n if (dist[nv][ns][nm] > nd) {\n dist[nv][ns][nm] = nd;\n que.emplace(nd,nv,ns,nm);\n }\n }\n }\n }\n\n cout << fixed << setprecision(10);\n double ans = 1e15;\n for (int i = 0; i < M; i++) {\n ans=min(ans,dist[g][1][i]);\n }\n if (ans > 1e14) {\n print(\"unreachable\");\n } else {\n print(ans);\n }\n\n return true;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n while (solve())\n ;\n}\n\n////////////////////print/////////////////////////\n// 1次元ベクトルを出力する\ntemplate <typename T> void print(vector<T> A) {\n if (A.size() == 0) {\n return;\n }\n for (size_t i = 0; i < A.size() - 1; i++) {\n cout << A[i] << ' ';\n }\n cout << A[A.size() - 1] << endl;\n return;\n}\n\n// 2次元ベクトルを出力する\ntemplate <typename T> void print(vector<vector<T>> &F) {\n for (size_t i = 0; i < F.size(); i++) {\n for (size_t j = 0; j < F[i].size(); j++) {\n cout << F[i][j];\n if (j < F[i].size() - 1) {\n cout << ' ';\n }\n }\n cout << endl;\n }\n}\n\n// 空白行を出力するprint\nvoid print() { cout << endl; }\n\n// 数値・文字列を空白区切りで出力する. print(a,b)など\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n cout << head;\n if (sizeof...(tail) != 0)\n cout << \" \";\n print(forward<Tail>(tail)...);\n}\n\nvoid print(string S) { cout << S << endl; }\n\n//////////////出力関連\n\ninline void Yes(bool f) {\n if (f) {\n cout << \"Yes\" << endl;\n } else {\n cout << \"No\" << endl;\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 9232, "score_of_the_acc": -0.0679, "final_rank": 10 }, { "submission_id": "aoj_1162_10608145", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing edge = tuple<int, double, int>;\nusing tu = tuple<double, int, int, int>;\n\nconstexpr double INF = 2e9;\nconstexpr int LIM = 31;\n\nvoid solve(int n, int m, int s, int g, vector<vector<edge>> E) {\n priority_queue<tu, vector<tu>, greater<>> pq;\n vector dist(n, vector(LIM, vector(n, INF)));\n pq.emplace(0.0, s, 0, s);\n dist[s][0][s] = 0.0;\n while (!pq.empty()) {\n auto [cost, u, speed, prev_v] = pq.top();\n pq.pop();\n if (dist[u][speed][prev_v] < cost) {\n continue;\n }\n\n for (auto [v, d, lim_speed] : E[u]) {\n if (v == prev_v) {\n continue;\n }\n\n for (int add = -1; add <= 1; add++) {\n int next_speed = speed + add;\n if (next_speed > lim_speed || next_speed < 1) {\n continue;\n }\n\n double next_cost = cost + (d / next_speed);\n if (dist[v][next_speed][u] > next_cost) {\n dist[v][next_speed][u] = next_cost;\n pq.emplace(next_cost, v, next_speed, u);\n }\n }\n }\n }\n\n double ans = INF;\n for (int i = 0; i < n; i++) {\n ans = min(ans, dist[g][1][i]);\n }\n if (ans == INF) {\n cout << \"unreachable\" << endl;\n } else {\n printf(\"%.10f\\n\", ans);\n }\n}\n\nint main() {\n while (true) {\n int n, m;\n cin >> n >> m;\n if (n == 0 && m == 0) {\n break;\n }\n\n int s, g;\n cin >> s >> g;\n s--;\n g--;\n\n vector<vector<edge>> E(n);\n for (int i = 0; i < m; i++) {\n int x, y, d, c;\n cin >> x >> y >> d >> c;\n x--;\n y--;\n E[x].emplace_back(y, d, c);\n E[y].emplace_back(x, d, c);\n }\n solve(n, m, s, g, E);\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4624, "score_of_the_acc": -0.0036, "final_rank": 2 }, { "submission_id": "aoj_1162_10605506", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rrep(i,start,end) for (ll i = start;i >= (ll)(end);i--)\n#define repn(i,end) for(ll i = 0; i <= (ll)(end); i++)\n#define reps(i,start,end) for(ll i = start; i < (ll)(end); i++)\n#define repsn(i,start,end) for(ll i = start; i <= (ll)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef vector<ll> vll;\ntypedef vector<pair<ll ,ll>> vpll;\ntypedef vector<vector<ll>> vvll;\ntypedef set<ll> sll;\ntypedef map<ll , ll> mpll;\ntypedef pair<ll ,ll> pll;\ntypedef tuple<ll , ll , ll> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (ll)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1LL << 60;\nconst ld EPS = 1e-9;\n \nll lceil(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b)+1;}else{return -((-a)/b);}}\nll lfloor(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b);}else{return -((-a)/b)-1;}}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\n//0indexed\ninline ll topbit(ll a){assert(a != 0);return 63 - __builtin_clzll(a);}\ninline ll smlbit(ll a){assert(a != 0);return __builtin_ctzll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n \nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true){\n LL(n,m);\n if(n == 0 && m == 0)break;\n LL(s,e);\n s--;e--;\n vector<vector<tpl3>> g(n);\n rep(i,m){\n LL(x,y,d,c);\n x--;y--;\n g[x].push_back({y,d,c});\n g[y].push_back({x,d,c});\n }\n vector dist(n,vector(n,vector<ld>(31,INF)));\n using tpl4 = tuple<ld,ll,ll,ll>;\n priority_queue<tpl4,vector<tpl4>,greater<tpl4>> pq;\n //syote\n for(auto[to,d,c]:g[s]){\n if(1 <=c&&chmin(dist[to][s][1],(ld)d)){\n pq.emplace(dist[to][s][1],to,s,1);\n }\n }\n while(!pq.empty()){\n auto[cost,now,past,v] = pq.top();\n pq.pop();\n if(dist[now][past][v] < cost - EPS)continue;\n for(auto[to,d,c]:g[now])if(to != past){\n repsn(i,-1,1){\n if(v+i>0 && v+i<=c&&chmin(dist[to][now][v+i],(ld)d/(v+i)+cost) ){\n pq.emplace(dist[to][now][v+i],to,now,v+i);\n }\n }\n }\n }\n bool ok = false;\n ld ans = INF;\n rep(i,n){\n if(dist[e][i][1] < INF){\n ok = true;\n chmin(ans,dist[e][i][1]);\n }\n }\n if(ok){\n cout << std::fixed << std::setprecision(10) << ans << endl;\n }else{\n cout << \"unreachable\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5384, "score_of_the_acc": -0.0104, "final_rank": 3 }, { "submission_id": "aoj_1162_10564377", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define all(...) std::begin(__VA_ARGS__), std::end(__VA_ARGS__)\n#define rall(...) std::rbegin(__VA_ARGS__), std::rend(__VA_ARGS__)\n#define OVERLOAD_REP(_1, _2, _3, _4, name, ...) name\n#define REP1(n) for(ll i=0;i<(n);i++)\n#define REP2(i, n) for (ll i=0;i<(n);i++)\n#define REP3(i, a, n) for (ll i=a;i<(n);i++)\n#define REP4(i, a, b, n) for(ll i=a;i<(n);i+=b)\n#define rep(...) OVERLOAD_REP(__VA_ARGS__, REP4, REP3, REP2, REP1)(__VA_ARGS__)\n#define OVERLOAD_RREP(_1, _2, _3, _4, name, ...) name\n#define RREP1(n) for(ll i=(n)-1;i>=0;i--)\n#define RREP2(i, n) for(ll i=(n)-1;i>=0;i--)\n#define RREP3(i, a, n) for(ll i=(n)-1;i>=(a);i--)\n#define RREP4(i, a, b, n) for(ll i=(n)-1;i>=(a);i-=(b))\n#define rrep(...) OVERLOAD_RREP(__VA_ARGS__, RREP4, RREP3, RREP2, RREP1)(__VA_ARGS__)\n#define uniq(a) sort(all(a));a.erase(unique(all(a)),end(a))\n#define len(n) (long long)(n).size()\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vs = vector<string>;\nusing vvs = vector<vs>;\nusing vvvs = vector<vvs>;\nusing vld = vector<ld>;\nusing vvld = vector<vld>;\nusing vvvld = vector<vvld>;\nusing vc = vector<char>;\nusing vvc = vector<vc>;\nusing vvvc = vector<vvc>;\nusing pll = pair<ll,ll>;\nusing vpll = vector<pll>;\nusing vvpll = vector<vpll>;\n\nll intpow(ll a,ll b){\n ll ans = 1;\n while (b){\n if (b & 1){\n ans *= a;\n }\n a *= a;\n b /= 2;\n }\n return ans;\n}\nll modpow(ll a,ll b,ll c){\n ll ans = 1;\n while (b){\n if (b & 1){\n ans *= a;\n ans %= c;\n }\n a *= a;\n a %= c;\n b /= 2;\n }\n return ans;\n}\n\ntemplate<class... T>\nvoid input(T&... a){\n (cin >> ... >> a);\n}\n\n#define INT(...) int __VA_ARGS__; input(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define ULL(...) ull __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define CHA(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define VLL(name,length) vll name(length);rep(i,length){cin >> name[i];}\n#define VVLL(name,h,w) vvll name(h,vll(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVLL(name,a,b,c) vvvll name(a,vvll(b,vll(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VI(name,length) vi name(length);rep(i,length){cin >> name[i];}\n#define VVI(name,h,w) vvi name(h,vi(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVI(name,a,b,c) vvvi name(a,vvll(b,vi(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VLD(name,length) vld name(length);rep(i,length){cin >> name[i];}\n#define VVLD(name,h,w) vvld name(h,vld(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVLD(name,a,b,c) vvvld name(a,vvld(b,vld(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VC(name,length) vc name(length);rep(i,length){cin >> name[i];}\n#define VVC(name,h,w) vvc name(h,vc(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVC(name,a,b,c) vvvc name(a,vvc(b,vc(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VS(name,length) vs name(length);rep(i,length){cin >> name[i];}\n#define VVS(name,h,w) vvs name(h,vs(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVS(name,a,b,c) vvvs name(a,vvs(b,vs(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define PLL(name) pll name;cin>>name.first>>name.second;\n#define VPLL(name,length) vpll name(length);rep(i,length){cin>>name[i].first>>name[i].second;}\n\nvoid print(){cout << \"\\n\";}\n\ntemplate <typename T1, typename T2>\nstd::ostream& operator<<(std::ostream& os, const std::pair<T1, T2>& p) {\n os << \"(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\n\ntemplate <typename T>\nstd::ostream& operator<<(std::ostream& os, const std::vector<T>& vec) {\n os << \"[\";\n for (size_t i = 0; i < vec.size(); ++i) {\n os << vec[i];\n if (i + 1 < vec.size()) os << \", \";\n }\n os << \"]\";\n return os;\n}\n\ntemplate <typename T1, typename T2>\nstd::ostream& operator<<(std::ostream& os, const std::vector<std::pair<T1, T2>>& a) {\n os << \"[\";\n for (size_t j = 0; j < a.size(); ++j) {\n os << \"(\" << a[j].first << \", \" << a[j].second << \")\";\n\t\tif (j + 1 < a.size()) os << \", \";\n }\n\tos << \"]\";\n return os;\n}\n\ntemplate <typename T1, typename T2>\nstd::ostream& operator<<(std::ostream& os, const std::vector<std::vector<std::pair<T1, T2>>>& mat) {\n\tos << \"[\";\n for (size_t i = 0; i < mat.size(); ++i) {\n\t\tos << \"[\";\n for (size_t j = 0; j < mat[i].size(); ++j) {\n os << \"(\" << mat[i][j].first << \", \" << mat[i][j].second << \")\";\n\t\t\tif (j + 1 < mat[i].size()) os << \", \";\n }\n\t\tos << \"]\";\n\t\tif (i + 1 < mat.size()) os << \", \";\n }\n\tos << \"]\";\n return os;\n}\n\ntemplate <typename T>\nstd::ostream& operator<<(std::ostream& os, const std::set<T>& s) {\n os << \"{\";\n bool first = true;\n for (const auto& x : s) {\n if (!first) os << \", \";\n os << x;\n first = false;\n }\n os << \"}\";\n return os;\n}\n\ntemplate <typename K, typename V>\nstd::ostream& operator<<(std::ostream& os, const std::map<K, V>& m) {\n os << \"{\";\n bool first = true;\n for (const auto& [key, val] : m) {\n if (!first) os << \", \";\n os << key << \": \" << val;\n first = false;\n }\n os << \"}\";\n return os;\n}\n\ntemplate<class T, class... Ts>\nvoid print(const T& a, const Ts&... b){cout << a;(cout << ... << (cout << ' ', b));cout << '\\n';}\n\nvoid write(){cout << \"\\n\";}\ntemplate<class T, class... Ts>\nvoid write(const T& a, const Ts&... b){cout << a;(cout << ... << (cout << ' ', b));cout << '\\n';}\nvoid write(vll x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvll x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vi x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvi x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvvi x){rep(i,len(x))rep(j,len(x[i]))rep(k,len(x[i][j])){cout << x[i][j][k];if(k!=len(x[i][j])-1){cout << \" \";}else if(j!=len(x[i])-1){cout << \" | \";}else{cout << '\\n';}}}\nvoid write(vld x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvld x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvvld x){rep(i,len(x))rep(j,len(x[i]))rep(k,len(x[i][j])){cout << x[i][j][k];if(k!=len(x[i][j])-1){cout << \" \";}else if(j!=len(x[i])-1){cout << \" | \";}else{cout << '\\n';}}}\nvoid write(vc x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvc x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvvc x){rep(i,len(x))rep(j,len(x[i]))rep(k,len(x[i][j])){cout << x[i][j][k];if(k!=len(x[i][j])-1){cout << \" \";}else if(j!=len(x[i])-1){cout << \" | \";}else{cout << '\\n';}}}\nvoid write(vs x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvs x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvvs x){rep(i,len(x))rep(j,len(x[i]))rep(k,len(x[i][j])){cout << x[i][j][k];if(k!=len(x[i][j])-1){cout << \" \";}else if(j!=len(x[i])-1){cout << \" | \";}else{cout << '\\n';}}}\nvoid write(pll x){cout << x.first << ' ' << x.second << '\\n';}\nvoid write(vpll x){rep(i,len(x)){cout << x[i].first << ' ' << x[i].second << '\\n';}}\nvoid write(vvpll x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j].first << ' ' << x[i][j].second;if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\n\ntemplate <typename T>\nT sum(const std::vector<T>& v) {\n return std::accumulate(v.begin(), v.end(), T(0));\n}\n\ntemplate<class T> bool chmin(T& a, const T& b){ if(a > b){ a = b; return 1; } return 0; }\ntemplate<class T> bool chmax(T& a, const T& b){ if(a < b){ a = b; return 1; } return 0; }\ntemplate<class T, class U> bool chmin(T& a, const U& b){ if(a > T(b)){ a = b; return 1; } return 0; }\ntemplate<class T, class U> bool chmax(T& a, const U& b){ if(a < T(b)){ a = b; return 1; } return 0; }\n\nusing vvvvld = vector<vvvld>;\nusing S = tuple<ld,ll,ll,ll>;\nint main(){\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n \n while(1){\n LL(n,m);\n if(n == 0 && m == 0){break;}\n LL(s,g);\n s--;\n g--;\n vector<vector<tuple<ll,ll,ll>>> edge(n);\n rep(i,m){\n LL(x,y,d,c);\n x--;\n y--;\n edge[x].push_back({y,d,c});\n edge[y].push_back({x,d,c});\n }\n vvvld dp(n,vvld(n,vld(31,1e100)));\n dp[s][s][0] = 0;\n priority_queue<S,vector<S>,greater<S>> q;\n q.push({0,s,s,0});\n while(!q.empty()){\n auto [d,now,p,v] = q.top();\n q.pop();\n if(dp[now][p][v] > d){continue;}\n for(auto [to,l,limit]:edge[now]){\n rep(u,v-1,v+2){\n if(to != p && 1 <= u && u <= limit && dp[to][now][u] > dp[now][p][v] + ((ld)l / (ld)u)){\n dp[to][now][u] = dp[now][p][v] + ((ld)l / (ld)u);\n q.push({dp[to][now][u],to,now,u});\n }\n }\n }\n }\n cout << fixed << setprecision(16);\n ld ans = 1e100;\n rep(i,n){\n chmin(ans,dp[g][i][1]);\n }\n if(ans > (ld)1e99){\n cout << \"unreachable\" << endl;\n continue;\n }\n cout << ans << endl;\n }\n \n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5384, "score_of_the_acc": -0.0219, "final_rank": 7 }, { "submission_id": "aoj_1162_9555981", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nstruct Edge {\n int To;\n double Len;\n int MAXV;\n int ID;\n};\n\nint main() {\nwhile(1) {\n int N, M;\n cin >> N >> M;\n if (N == 0 && M == 0) return 0;\n int S, G;\n cin >> S >> G;\n S--, G--;\n vector<vector<Edge>> Graph(N);\n rep(i,0,M) {\n int X, Y, C;\n double D;\n cin >> X >> Y >> D >> C;\n X--, Y--;\n Graph[X].push_back({Y,D,C,i});\n Graph[Y].push_back({X,D,C,i});\n }\n int MAXS = 31;\n M++;\n vector<double> DP(N*MAXS*M,inf);\n priority_queue<pair<double,int>,vector<pair<double,int>>,greater<pair<double,int>>> PQ;\n auto encode = [&](int i, int j, int k) -> int {return i * MAXS * M + j * M + k;};\n auto decode = [&](int a) -> tuple<int,int,int> {return {a / (MAXS*M), (a/M) % MAXS, a%M};};\n DP[encode(S,0,M-1)] = 0;\n PQ.push({0,encode(S,0,M-1)});\n while(!PQ.empty()) {\n pair<double,int> P = PQ.top();\n PQ.pop();\n double Cost = P.first;\n auto [X, V, EN] = decode(P.second);\n if (DP[P.second] < P.first) continue;\n for (Edge E : Graph[X]) {\n if (E.ID == EN) continue;\n int NX = E.To, NEN = E.ID;\n rep(dv,-1,2) {\n int NV = V + dv;\n if (NV <= 0 || E.MAXV < NV) continue;\n double NCost = Cost + E.Len / (double)NV;\n if (chmin(DP[encode(NX,NV,NEN)],NCost)) {\n PQ.push({NCost,encode(NX,NV,NEN)});\n }\n }\n }\n }\n double ANS = inf;\n for (Edge E : Graph[G]) {\n chmin(ANS, DP[encode(G,1,E.ID)]);\n }\n if (ANS == inf) cout << \"unreachable\" << endl;\n else printf(\"%.12f\\n\", ANS);\n}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7260, "score_of_the_acc": -0.0272, "final_rank": 8 }, { "submission_id": "aoj_1162_9378120", "code_snippet": "#include<bits/stdc++.h>\n//#include <atcoder/all>\nusing namespace std;\n//using namespace atcoder;\n\n#define all(v) v.begin(),v.end()\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll=vector<ll>;\nusing vvll = vector<vector<ll>>;\nusing P = pair<ll,ll>;\nusing PP=pair<double,tuple<ll,ll,ll>>;\nusing vp=vector<pair<ll, ll>>;\n//using mint=modint1000000007;\n//using mint=modint998244353;\n\nconst ll INF=1ll<<60;\nll mod10=1e9+7;\nll mod99=998244353;\nconst double PI = acos(-1);\n\n#define rep(i,n) for (ll i=0;i<n;++i)\n#define per(i,n) for(ll i=n-1;i>=0;--i)\n#define rep2(i,a,n) for (ll i=a;i<n;++i)\n#define per2(i,a,n) for (ll i=a;i>=n;--i)\n\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n\nbool solve(){\n\tll N,M;cin>>N>>M;\n\tif(N==M&&N==0) return 0;\n\tll s,g;cin>>s>>g;\n\ts--;g--;\n\tvll X(M),Y(M),D(M),C(M);\n\tvector<vp> ab(N);\n\trep(i,M){\n\t\tcin>>X[i]>>Y[i]>>D[i]>>C[i];\n\t\tX[i]--;Y[i]--;\n\t\tab[X[i]].push_back({Y[i],i});\n\t\tab[Y[i]].push_back({X[i],i});\n\t}\n\n\tvector dist(N,vector<vector<double>>(50,vector<double>(N,INF)));\n\tpriority_queue<PP,vector<PP>,greater<PP>> pq;\n\tpq.push({0,{s,0,s}});\n\twhile(pq.size()){\n\t\tauto [c,now1]=pq.top();pq.pop();\n\t\tauto [now,v,mae]=now1;\n\t\n\t\tif(dist[now][v][mae]!=INF) continue;\n\t\tdist[now][v][mae]=c;\n\t\tfor(auto [to,i]:ab[now]){\n\t\t\tif(to==mae) continue;\n\t\t\trep2(j,-1,2){\n\t\t\t\tif(v+j>C[i]||v+j<=0) continue;\n\t\t\t\tpq.push({c+(double)D[i]/(v+j),{to,v+j,now}});\n\t\t\t}\n\t\t}\n\t}\n\n\tdouble ans=INF;\n\trep(i,40) rep(j,N) chmin(ans,dist[g][1][j]);\n\tif(ans==INF) cout << \"unreachable\" << endl;\n\telse cout << ans << endl;\n\t\n\treturn 1;\n}\n\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n while(solve());\n}", "accuracy": 1, "time_ms": 760, "memory_kb": 29428, "score_of_the_acc": -1.0761, "final_rank": 17 }, { "submission_id": "aoj_1162_9158789", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\n#define rep(i, a, b) for(ll i = a; i < b; ++i)\n#define rrep(i, a, b) for(ll i = a; i >= b; --i)\nconstexpr ll inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\nint main(void) {\n while(1) {\n int n, m;\n cin >> n >> m;\n if(n == 0 and m == 0) break;\n int s, t;\n cin >> s >> t;\n s--;\n t--;\n vector<vector<pair<double, int>>> g(n * n * 30 + 1);\n rep(i, 0, m) {\n int x, y, d, c;\n cin >> x >> y >> d >> c;\n x--;\n y--;\n rep(j, 1, 31) {\n rep(k, j - 1, j + 2) {\n if(1 <= k and k <= c) {\n rep(l, 0, n) {\n if(l != y) {\n g[l * n * 30 + x * 30 + j - 1].push_back({1.0 * d / k, x * n * 30 + y * 30 + k - 1});\n }\n if(l != x) {\n g[l * n * 30 + y * 30 + j - 1].push_back({1.0 * d / k, y * n * 30 + x * 30 + k - 1});\n }\n }\n }\n }\n }\n if(y == s) {\n swap(x, y);\n }\n if(x == s) {\n g[n * n * 30].push_back({1.0 * d, x * n * 30 + y * 30});\n }\n }\n vector<double> d(n * n * 30 + 1, inf);\n priority_queue<pair<double, int>, vector<pair<double, int>>, greater<pair<double, int>>> pq;\n d[n * n * 30] = 0;\n pq.push({d[n * n * 30], n * n * 30});\n while(!pq.empty()) {\n auto [dist, cur] = pq.top();\n pq.pop();\n if(d[cur] < dist) continue;\n for(const auto& [cost, to] : g[cur]) {\n if(d[to] > d[cur] + cost) {\n d[to] = d[cur] + cost;\n pq.push({d[to], to});\n }\n }\n }\n double ans = inf;\n rep(i, 0, n) {\n ans = min(ans, d[i * n * 30 + t * 30]);\n }\n if(ans == inf) {\n cout << \"unreachable\" << '\\n';\n } else {\n cout << ans << '\\n';\n }\n }\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 59984, "score_of_the_acc": -0.6483, "final_rank": 14 }, { "submission_id": "aoj_1162_9151840", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = 3.141592653589793;\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\ntemplate<typename T> void view(const vv<T>& vv){ for(const auto& v : vv){ view(v); } }\n\ntuple<vc<double>, vi> dijkstra(int s, int N, vv<pair<int, double>> &g){\n using P = pair<double, int>;\n vc<double> dist(N, inf);\n vi bef(N);\n priority_queue<P, vc<P>, greater<P>> q;\n dist[s] = 0;\n q.push({0, s});\n while (!q.empty()){\n auto [c, now] = q.top();q.pop();\n if (dist[now] < c) continue;\n for (auto&& [nxt, nc]: g[now]) if (dist[nxt] > c + nc){\n dist[nxt] = c + nc;\n bef[nxt] = now;\n q.push({dist[nxt], nxt}); \n }\n }\n return {dist, bef};\n}\n\ndouble solve(int N, int M){\n int S, G; cin >> S >> G; S--; G--;\n int K = 40;\n vv<pair<int, double>> g(K * N * N + 1);\n rep(i, M){\n int x, y, d, c; cin >> x >> y >> d >> c; x--; y--;\n rep(j, N) if (y != j && x != j){\n for (int v = 0; v <= c + 1; v++) for (int nv = max(1, v - 1); nv <= min(c, v + 1); nv++){\n g[x * N * K + j * K + v].push_back({y * N * K + x * K + nv, d / (double)nv});\n g[y * N * K + j * K + v].push_back({x * N * K + y * K + nv, d / (double)nv});\n }\n }\n }\n rep(j, N) if (S != j) g[K * N * N].push_back({S * N * K + j * K + 0, 0});\n auto [dist, bef] = dijkstra(K * N * N, K * N * N + 1, g);\n double ans = inf;\n rep(j, N) if (G != j) ans = min(ans, dist[G * N * K + j * K + 1]);\n return ans;\n}\n\nint main(){\n vc<double> ans;\n while (true){\n int N, M; cin >> N >> M;\n if (N == 0) break;\n ans.push_back(solve(N, M));\n }\n for (auto x : ans){\n if (x == inf) cout << \"unreachable\" << endl;\n else cout << fixed << setprecision(16) << x << endl;\n }\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 58688, "score_of_the_acc": -0.6482, "final_rank": 13 }, { "submission_id": "aoj_1162_9144908", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0; i< (n); i++)\n#define mkp(i,j) make_pair((i),(j))\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\nconst int mod = 998244353;\nconst int inf = (1<<30);\n\nstruct edge{\n\tint to,c,x;\n};\n\nstruct state{\n\tint speed,city;\n\tlong double time;\n\tint U;\n\tbool operator>(const state& a) const {\n\t\treturn time > a.time;\n\t}\n};\n\n\nstruct ShortestPath {\n\tvector<vector<vector<long double>>> ans;\n\tvector<vector<edge>> g;\n\tvoid init(int n){\n\t\tans.resize(31);\n\t\trep(i,31){\n\t\t\tans[i].resize(31);\n\t\t\trep(j,31) ans[i][j].resize(31,inf);\n\t\t}\n\t\tg.resize(31);\n\t}\n\n\n\tvoid dijkstra(int s){\n\n\t\tpriority_queue<state,vector<state>,greater<state>> que;\n\t\tque.push({0,s,0.0,s});\n\t\tans[s][0][s] = 0;\n\t\t//cout<<ans[30][30][30]<<endl;\n\t\twhile(que.size()){\n\t\t\tint now = que.top().city;\n\t\t\tlong double cost = que.top().time;\n\t\t\tint speed = que.top().speed;\n\t\t\tint U = que.top().U;\n\t\t\tque.pop();\n\t\t\t//cout<<now<<\" \"<<speed<<\" \"<<U<<endl;\n\t\t\tif(ans[now][speed][U] < cost) continue;\n\t\t\tif(speed <= 1) ans[now][0][U] = min(ans[now][0][U],cost);\n\n\n\t\t\tfor(auto x : g[now]){\n\n\t\t\t\tint to = x.to;\n\t\t\t\tif(to == U) continue;\n\t\t\t\tlong double d = x.x;\n\t\t\t\tfor(int sp = max(speed - 1,1); sp <= min(speed+1,x.c); sp++){\n\t\t\t\t\tlong double fare = d/(long double)sp;\n\t\t\t\t//\tcout<<to<<\" \"<<sp<<\" \"<<now<<\" \"<<que.size()<<endl;\n\n\t\t\t\t\tif(ans[to][sp][now] > cost+fare){\n\t\t\t\t//\t\tcout<<\"in if\"<<endl;\n\t\t\t\t\t\tque.push({sp,to,cost+fare,now});\n\t\t\t\t\t\tans[to][sp][now] = cost+fare;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n};\n\nint main(){\n\twhile(1){\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tif(n == 0) break;\n\t\tint s,g; cin>>s>>g; s--; g--;\n\t\tShortestPath a;\n\t\ta.init(n);\n\t\trep(i,m){\n\t\t\tint x,y,d,c; cin>>x>>y>>d>>c;x--;y--;\n\t\t\ta.g[x].push_back({y,c,d});\n\t\t\ta.g[y].push_back({x,c,d});\n\t\t}\n\t\ta.dijkstra(s);\n\t\tlong double ans = inf;\n\t\trep(i,n) ans = min(ans,a.ans[g][0][i]);\n\t\tif( ans == inf) cout<<\"unreachable\"<<endl;\n\t\telse cout<<fixed<<setprecision(10)<<ans<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5028, "score_of_the_acc": -0.0188, "final_rank": 6 }, { "submission_id": "aoj_1162_9144663", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <algorithm>\n#include <queue>\n#include <vector>\n#include <map>\n#include <stack>\n#include <cassert>\nusing namespace std;\n\ntemplate<typename T>\nclass dijkstra{\n struct vg{\n int t;\n T c;\n };\n vector<pair<int,T>> cost;\n int beg = -1;\n void run(int x){\n auto comp = [](vg a,vg b){\n return a.c>b.c;\n };\n priority_queue<vg,vector<vg>,decltype(comp)> R{comp};\n for(int i = 0; n > i; i++){\n cost[i].second = -1;\n }\n cost[x].first = -1;\n cost[x].second = 0;\n R.push({x,0});\n while(R.size()){\n auto k = R.top();R.pop();\n if(cost[k.t].second != k.c)continue;\n for(int i = 0; A[k.t].size() > i; i++){\n if(cost[A[k.t][i].t].second != -1 && cost[A[k.t][i].t].second <= k.c+A[k.t][i].c)continue;\n cost[A[k.t][i].t].second = k.c+A[k.t][i].c;\n cost[A[k.t][i].t].first = k.t;\n R.push({A[k.t][i].t,k.c+A[k.t][i].c});\n }\n }\n\n }\n\npublic:\n int n;\n vector<vector<vg>> A;\n vector<vector<vg>> Rev;\n dijkstra(int n_):n(n_),A(n_),Rev(n_),cost(n_,{-1,-1}){}\n\n //双方向\n void push(int s,int v,T c){\n A[s].push_back({v,c});\n A[v].push_back({s,c});\n Rev[s].push_back({v,c});\n Rev[v].push_back({s,c});\n }\n\n void push_side(int s,int v,T c){\n A[s].push_back({v,c});\n Rev[v].push_back({s,c});\n }\n\n void build(int x){\n run(x);\n beg = x;\n }\n\n //restorate any\n\n vector<int> restoration(int t = -1){\n vector<int> Ret;\n if(beg == -1 || (t != -1 && cost[t].second == -1)){\n Ret.push_back(-1);\n return Ret;\n }\n int ind = t;\n if(ind == -1){\n T tmp = cost[0].second;\n int tmpin = 0;\n for(int i = 0; n > i; i++){\n if(tmp < cost[i].second){\n tmp = cost[i].second;\n tmpin = i;\n }\n }\n ind = tmpin;\n }\n Ret.push_back(ind);\n while(beg != ind){\n Ret.push_back({cost[ind].first});\n ind = cost[ind].first;\n }\n reverse(Ret.begin(),Ret.end());\n return Ret;\n }\n\n T operator[](int i){\n return cost[i].second;\n }\n};\nvoid solve(int n, int m){\n n++;\n dijkstra<double> D(n*n*60);\n int s,g;cin>>s>>g;\n for(int i = 0; m > i; i++){\n int x,y,d,c;cin>>x>>y>>d>>c;\n for(int j = 1; c >= j; j++){\n for(int k = 0; n > k; k++){\n if(k != x && k != y){\n D.push_side((n*x+k)*60+30+(j-1), (n*y+x)*60+(j-1), (double)d/j);\n D.push_side((n*x+k)*60+(j-1), (n*y+x)*60+(j-1), (double)d/j);\n D.push_side((n*y+k)*60+30+(j-1), (n*x+y)*60+(j-1), (double)d/j);\n D.push_side((n*y+k)*60+(j-1), (n*x+y)*60+(j-1), (double)d/j);\n\n }\n }\n }\n }\n for(int i = 0; n > i; i++){\n for(int j = 1; 30 >= j; j++){\n for(int k = 0; n > k; k++){\n if(i == k)continue;\n if(j != 30){\n D.push_side((n*i+k)*60+(j-1), (n*i+k)*60+30+(j), 0);\n }\n if(j != 1){\n D.push_side((n*i+k)*60+(j-1), (n*i+k)*60+30+(j-2), 0);\n }\n }\n }\n }\n D.build((n*s+0)*60+30);\n double ans = -1;\n for(int i = 0; n > i; i++){\n if(D[(n*g+i)*60] == -1)continue;\n if(ans < 0)ans = D[(n*g+i)*60];\n else ans = min(ans, D[(n*g+i)*60]);\n }\n if(ans == -1){\n cout << \"unreachable\" << endl;\n }else{\n cout << fixed << setprecision(10) << ans << endl;\n }\n}\n\nint main(){\n int n,m;\n while(cin>>n>>m){\n if(n == 0)return 0;\n solve(n,m);\n }\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 63832, "score_of_the_acc": -0.8436, "final_rank": 16 }, { "submission_id": "aoj_1162_9144496", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ld = long double;\nusing ll = long long;\nconst ld LINF = 2e18;\nconst ld EPS = 1e-10;\ntemplate<class T> using min_heap = priority_queue<T, vector<T>, greater<T>>;\n\nint main(){\n while(1){\n int N, M; cin >> N >> M;\n if(N == 0 && M == 0) break;\n int S, G; cin >> S >> G; S--, G--;\n\n // id < N, ver:31, pre:N\n auto norm = [&](int id, int ver, int pre) -> int {\n return (id * 31 + ver) * N + pre;\n };\n auto mron = [&](int v) -> tuple<int, int, int> {\n return make_tuple(v / (31 * N), (v / N) % 31, v % N);\n };\n\n vector<vector<pair<int, ld>>> Gr(N * 31 * N);\n for(int _ = 0; _ < M; _++){\n int x, y, d, c; cin >> x >> y >> d >> c;\n x--, y--;\n\n for(int _a = 0; _a < 2; _a++){\n for(int i = 0; i <= 30; i++){\n for(int j = 0; j < N; j++){\n if(j == y) continue;\n int id = norm(x, i, j);\n for(int k = -1; k <= 1; k++){\n int nver = i + k;\n if(nver <= 0 || c < nver) continue;\n int id2 = norm(y, nver, x);\n Gr[id].emplace_back(id2, ld(d) / nver);\n }\n }\n }\n swap(x, y);\n }\n }\n\n min_heap<pair<ld, int>> heap;\n vector<ld> dist(N * 31 * N, LINF);\n vector<bool> used(N * 31 * N);\n dist[norm(S, 0, S)] = 0;\n heap.push(make_pair(0, norm(S, 0, S)));\n while(!heap.empty()){\n auto [_, u] = heap.top();\n heap.pop();\n if(used[u]) continue;\n used[u] = 1;\n for(auto [v, cst] : Gr[u]){\n if(dist[u] + cst + EPS < dist[v]){\n dist[v] = dist[u] + cst;\n heap.push(make_pair(dist[v], v));\n }\n }\n }\n\n cout << fixed << setprecision(10);\n ld ans = LINF;\n // if(N == 5){\n // cout << dist[norm(1, 1, 0)] << endl;\n // cout << dist[norm(2, 2, 1)] << endl;\n // cout << dist[norm(3, 2, 2)] << endl;\n // cout << dist[norm(4, 1, 3)] << endl;\n // }\n for(int i = 0; i < N; i++){\n ans = min(ans, dist[norm(G, 1, i)]);\n }\n if(ans == LINF) cout << \"unreachable\" << endl;\n else cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 116008, "score_of_the_acc": -1.2529, "final_rank": 18 }, { "submission_id": "aoj_1162_9144217", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\nusing namespace atcoder;\ntemplate<int mod>istream &operator>>(istream &is,static_modint<mod> &a){long long b;is>>b;a=b;return is;}\nistream &operator>>(istream &is,modint &a){long long b;cin>>b;a=b;return is;}\n#endif\n#ifdef LOCAL\n#include \"debug.h\"\n#else\n#define debug(...) static_cast<void>(0)\n#define debugg(...) static_cast<void>(0)\n#define esper(...) static_cast<void>(0)\ntemplate<typename T1,typename T2>ostream &operator<<(ostream &os,const pair<T1,T2>&p){os<<p.first<<' '<<p.second;return os;}\n#endif\nusing ll=long long;\nusing ull=unsigned long long;\nusing P=pair<ll,ll>;\ntemplate<typename T>using minque=priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T>bool chmax(T &a,const T &b){return (a<b?(a=b,true):false);}\ntemplate<typename T>bool chmin(T &a,const T &b){return (a>b?(a=b,true):false);}\ntemplate<typename T1,typename T2>istream &operator>>(istream &is,pair<T1,T2>&p){is>>p.first>>p.second;return is;}\ntemplate<typename T>istream &operator>>(istream &is,vector<T> &a){for(auto &i:a)is>>i;return is;}\ntemplate<typename T1,typename T2>void operator++(pair<T1,T2>&a,int n){a.first++,a.second++;}\ntemplate<typename T1,typename T2>void operator--(pair<T1,T2>&a,int n){a.first--,a.second--;}\ntemplate<typename T>void operator++(vector<T>&a,int n){for(auto &i:a)i++;}\ntemplate<typename T>void operator--(vector<T>&a,int n){for(auto &i:a)i--;}\n#define reps(i,a,n) for(int i=(a);i<(n);i++)\n#define rep(i,n) reps(i,0,n)\n#define all(x) x.begin(),x.end()\n#define pcnt(x) __builtin_popcountll(x)\n#define fin(x) return cout<<x<<'\\n',static_cast<void>(0)\nll myceil(ll a,ll b){return (a+b-1)/b;}\ntemplate<typename T,size_t n,size_t id=0>\nauto vec(const int (&d)[n],const T &init=T()){\n if constexpr (id<n)return vector(d[id],vec<T,n,id+1>(d,init));\n else return init;\n}\nvoid SOLVE();\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout<<fixed<<setprecision(16);\n #ifdef LOCAL\n clock_t start=clock();\n #endif\n int testcase=1;\n //cin>>testcase;\n for(int i=0;i<testcase;i++){\n SOLVE();\n }\n #ifdef LOCAL\n cerr<<\"time:\";\n cerr<<(clock()-start)/1000;\n cerr<<\"ms\\n\";\n #endif\n}\nconstexpr double eps=1e-10;\nvoid SOLVE(){\n while(true){\n int n,m;\n cin>>n>>m;\n if(n+m==0)break;\n int s,g;\n cin>>s>>g;\n s--,g--;\n vector<vector<tuple<int,int,int>>>to(n);\n rep(i,m){\n int u,v,d,c;\n cin>>u>>v>>d>>c;\n u--,v--;\n to[u].push_back({v,d,c});\n to[v].push_back({u,d,c});\n }\n auto dst=vec<double>({n+1,n+1,31,31},1e18);\n dst[s][n][1][1]=0;\n minque<pair<double,tuple<int,int,int,int>>>que;\n que.push({0,{s,n,1,1}});\n while(!que.empty()){\n auto [d,p]=que.top();\n auto [x,prex,f,g]=p;\n que.pop();\n if(abs(dst[x][prex][f][g]-d)>eps)continue;\n for(auto [i,du,c]:to[x])if(f<=c&&i!=prex){\n double nxt=d+double(du)/f;\n reps(j,-1,2)if(f+j<=30&&f+j>=1&&chmin(dst[i][x][f+j][f],nxt))que.push({nxt,{i,x,f+j,f}});\n }\n }\n double ans=1e18;\n rep(j,n)rep(i,31)chmin(ans,dst[g][j][i][1]);\n if(ans==1e18)cout<<\"unreachable\"<<endl;\n else cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 12952, "score_of_the_acc": -0.2046, "final_rank": 11 }, { "submission_id": "aoj_1162_9117330", "code_snippet": "#include <bits/stdc++.h>\n\nbool solve() {\n int N, M;\n std::cin >> N >> M;\n if (N == 0 and M == 0) {\n return false;\n }\n int S, G;\n std::cin >> S >> G;\n S--; G--;\n int n{N * N * 35};\n auto f{[&](int v, int p, int s) -> int {\n return v + p * N + s * N * N;\n }};\n std::vector<std::vector<std::pair<int, long double>>> g(n);\n for (int _{} ; _ < M ; _++) {\n int x, y, d, c;\n std::cin >> x >> y >> d >> c;\n x--; y--;\n for (int p{} ; p < N ; p++) {\n for (int s{1} ; s <= c ; s++) {\n long double cost{(long double)d / (long double)s};\n if (p != y) {\n g[f(x, p, s)].emplace_back(f(y, x, s - 1), cost);\n g[f(x, p, s)].emplace_back(f(y, x, s), cost);\n g[f(x, p, s)].emplace_back(f(y, x, s + 1), cost);\n }\n if (p != x) {\n g[f(y, p, s)].emplace_back(f(x, y, s - 1), cost);\n g[f(y, p, s)].emplace_back(f(x, y, s), cost);\n g[f(y, p, s)].emplace_back(f(x, y, s + 1), cost);\n }\n }\n }\n }\n const long double INF{9e18l};\n std::vector<long double> dist(n, INF);\n dist[f(S, S, 1)] = 0;\n using qt = std::pair<long double, int>;\n std::priority_queue<qt, std::vector<qt>, std::greater<qt>> que;\n que.emplace((long double)0, f(S, S, 1));\n while (que.size()) {\n auto [d, v]{que.top()};\n que.pop();\n if (dist[v] < d) continue;\n for (auto [x, c] : g[v]) {\n if (dist[x] > dist[v] + c) {\n dist[x] = dist[v] + c;\n que.emplace(dist[x], x);\n }\n }\n }\n long double ans{INF};\n for (int i{} ; i < N ; i++) {\n ans = std::min(ans, dist[f(G, i, 0)]);\n }\n if (ans >= INF / 2) {\n std::cout << \"unreachable\" << '\\n';\n }\n else {\n std::cout << ans << '\\n';\n }\n return true;\n}\n\nint main() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n std::cout << std::fixed << std::setprecision(5);\n while (solve()) ;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 115676, "score_of_the_acc": -1.2729, "final_rank": 19 }, { "submission_id": "aoj_1162_8976228", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\n} // namespace macro\n\nusing namespace macro;\n#line 3 \"A.cpp\"\n\nld solve(int n, int m) {\n int s = in(), g = in(); s--, g--;\n vector dist(n, vector(n, 0));\n vector cons(n, vector(n, 0));\n for(int i : rep(m)) {\n int x = in(), y = in(), d = in(), c = in(); x--, y--;\n dist[x][y] = dist[y][x] = d;\n cons[x][y] = cons[y][x] = c;\n }\n\n const int max_v = 30;\n vector D(n, vector(n + 1, vector(max_v + 1, ld(1e18))));\n D[s][n][0] = 0;\n heap_min<tuple<ld,int,int,int>> q;\n q.push({D[s][n][0], s, n, 0});\n while(not q.empty()) {\n auto [uc, ui, pi, fv] = q.top(); q.pop();\n for(int vi : rep(n)) if(vi != pi) {\n for(int tv = fv - 1; tv <= fv + 1; tv++) if(1 <= tv and tv <= cons[ui][vi]) {\n if(chmin(D[vi][ui][tv], D[ui][pi][fv] + ld(dist[ui][vi]) / tv)) {\n q.push({D[vi][ui][tv], vi, ui, tv});\n }\n }\n }\n }\n\n ld ans = 1e18;\n for(int i : rep(n + 1)) chmin(ans, D[g][i][1]);\n return (ans == 1e18 ? -1 : ans);\n}\n\nint main() {\n while(true) {\n int n = in(), m = in();\n if(make_pair(n, m) == make_pair(0, 0)) return 0;\n ld ans = solve(n, m);\n if(ans < 0) {\n print(\"unreachable\");\n } else {\n printer::precision(20);\n print(ans);\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4504, "score_of_the_acc": -0.0141, "final_rank": 4 }, { "submission_id": "aoj_1162_8661030", "code_snippet": "#include <iostream>\n#include <vector>\n#include <tuple>\n#include <queue>\n#include <iomanip>\nusing namespace std;\n\nint main() {\n int n, m;\n cin >> n >> m;\n while (n || m) {\n // cout << 1 << n << m << endl;\n int s, g, x, y, d, c;\n vector<tuple<int, int, int>> v[31];\n cin >> s >> g;\n for (int i = 0; i < m; i++) {\n cin >> x >> y >> d >> c;\n v[x].push_back({y, d, c});\n v[y].push_back({x, d, c});\n }\n priority_queue<tuple<double, int, int, int>, vector<tuple<double, int, int, int>>, greater<tuple<double, int, int, int>>> pq;\n for (auto i: v[s]) pq.push({(double)get<1>(i), get<0>(i), 1, s});\n double ti;\n bool t[31][31][31] = {};\n c = -1;\n while (!pq.empty()) {\n tie(ti, x, c, y) = pq.top();\n pq.pop();\n if (t[x][y][c]) continue;\n if (x == g && c == 1) break;\n // cout << ti << \" \" << x << \" \" << c << \" \" << y << endl;\n t[x][y][c] = 1;\n for (auto i: v[x]) {\n if (get<0>(i) == y) continue;\n if (c - 1 && c - 1 <= get<2>(i)) pq.push({ti + get<1>(i) / (double)(c-1), get<0>(i), c-1, x});\n if (c <= get<2>(i)) pq.push({ti + get<1>(i) / (double)c, get<0>(i), c, x});\n if (c + 1 <= get<2>(i)) pq.push({ti + get<1>(i) / (double)(c + 1), get<0>(i), c + 1, x});\n }\n }\n if (x == g && c == 1) cout << fixed << setprecision(4) << ti << endl;\n else cout << \"unreachable\\n\";\n cin >> n >> m;\n }\n}", "accuracy": 1, "time_ms": 560, "memory_kb": 24000, "score_of_the_acc": -0.7977, "final_rank": 15 }, { "submission_id": "aoj_1162_8452695", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < n; ++i)\ntypedef long long ll;\nusing namespace std;\nconst double INF = 1e20;\n\ntemplate <class T>\nstruct edge {\n int to;\n T c, d;\n edge(int to, T c, T d) : to(to), c(c), d(d) {}\n};\n\nvoid solve(int N, int M) {\n int S, T;\n cin >> S >> T;\n S--, T--;\n vector<vector<edge<int>>> G(N);\n rep(i, M) {\n int x, y, d, c;\n cin >> x >> y >> d >> c;\n x--, y--;\n G[x].emplace_back(y, c, d);\n G[y].emplace_back(x, c, d);\n }\n\n vector dist(N, vector(N, vector<double>(31, INF)));\n dist[S][S][0] = 0;\n // cost, node, pre_node, speed\n using P = tuple<double, int, int, int>;\n priority_queue<P, vector<P>, greater<P>> pq;\n pq.emplace(0, S, S, 0);\n while (!pq.empty()) {\n auto [cost, u, p, s] = pq.top();\n pq.pop();\n\n if (dist[u][p][s] < cost) continue;\n for (auto [v, c, d] : G[u]) {\n if (v == p) continue;\n for (int ns = s - 1; ns <= s + 1; ++ns) {\n if (ns <= 0 || ns > c) continue;\n if (dist[v][u][ns] > dist[u][p][s] + d / (double)ns) {\n dist[v][u][ns] = dist[u][p][s] + d / (double)ns;\n pq.emplace(dist[v][u][ns], v, u, ns);\n }\n }\n }\n }\n\n double ans = INF;\n rep(i, N) ans = min(ans, dist[T][i][1]);\n if (ans == INF) cout << \"unreachable\\n\";\n else cout << fixed << setprecision(12) << ans << '\\n';\n}\n\nint main() {\n cin.tie(0)->sync_with_stdio(0);\n\n int N, M;\n while (cin >> N >> M) {\n if (N == 0 && M == 0) break;\n solve(N, M);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4216, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1162_8028000", "code_snippet": "#pragma GCC optimize(\"O3,unroll-loops\")\n#pragma GCC target(\"avx2,popcnt,lzcnt,abm,bmi,bmi2\")\n// #define _GLIBCXX_DEBUG /* これをするとvectorの配列外参照などがチェックされる */\n#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\n\nconst bool DEBUG = true;\n#define debug(x) \\\n if (DEBUG) cerr << __FILE__ << ':' << __LINE__ << \") \" << #x << \" : \" << (x) << endl;\n\n/*\n pre : 前いた頂点\n now : 到達した頂点\n speed : 出た時のスピード\n*/\n\nusing Node = tuple<int, int, int>;\n\nint now(Node n) {\n auto [x, y, z] = n;\n return y;\n}\n\nint speed(Node n) {\n auto [x, y, z] = n;\n return z;\n}\n\nvoid solve(int n, int m) {\n map<Node, vector<Node> > G_mp;\n\n vector<vector<int> > G(n);\n vector<vector<double> > d(n, vector<double>(n, 1e18));\n vector<vector<int> > c(n, vector<int>(n, 0));\n int s, g;\n cin >> s >> g;\n s--;\n g--;\n for (int i = 0; i < m; i++) {\n ll u, v, c_, d_;\n cin >> u >> v >> d_ >> c_;\n u--;\n v--;\n G[u].push_back(v);\n G[v].push_back(u);\n\n d[u][v] = d_;\n d[v][u] = d_;\n\n c[v][u] = c_;\n c[u][v] = c_;\n }\n\n for (int speed = 1; speed <= 30; speed++) {\n // s -> s+1 , s -> s , s -> s-1\n for (int now = 0; now < n; now++) {\n for (int pre : G[now]) {\n if (c[pre][now] == 0) continue;\n\n Node NOW = {pre, now, speed};\n\n for (ll nx : G[now]) {\n if (nx == pre) continue;\n if (speed <= c[now][nx]) {\n G_mp[NOW].emplace_back(now, nx, speed);\n G_mp[NOW].emplace_back(now, nx, speed + 1);\n G_mp[NOW].emplace_back(now, nx, speed - 1);\n }\n }\n }\n }\n }\n\n Node r = {-1, s, 1};\n\n for (int nx = 0; nx < n; nx++) {\n if (1 <= c[s][nx]) {\n G_mp[r].push_back({s, nx, 1});\n G_mp[r].push_back({s, nx, 2});\n }\n }\n\n priority_queue<pair<double, Node>, vector<pair<double, Node> >, greater<pair<double, Node> > > pq;\n pq.push({0.0, r});\n\n map<Node, double> dist;\n\n double ans = 1e18;\n\n while (!pq.empty()) {\n auto [D, v] = pq.top();\n pq.pop();\n\n if (dist[v] >= 1e-8 && dist[v] < D) continue;\n\n for (Node nx : G_mp[v]) {\n double dst = D + (d[now(v)][now(nx)] / double(speed(v)));\n\n if (dist[nx] < 1e-9 || dist[nx] > dst) {\n pq.emplace(dst, nx);\n dist[nx] = dst;\n if (now(nx) == g && speed(v) == 1) {\n ans = min(ans, dst);\n }\n }\n }\n }\n\n cout.precision(18);\n if (ans > 1e17) {\n cout << \"unreachable\" << endl;\n } else {\n cout << ans << endl;\n }\n}\n\nint main() {\n int n, m;\n while (1) {\n cin >> n >> m;\n if (n == 0 && m == 0) break;\n solve(n, m);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 890, "memory_kb": 46712, "score_of_the_acc": -1.3801, "final_rank": 20 }, { "submission_id": "aoj_1162_8020883", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n\ntemplate <typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n\nusing ld = long double;\nld INF = 1e300;\n\nstruct edge {\n int to, d, c;\n edge(int to, int d, int c) : to(to), d(d), c(c) {}\n};\n\nbool solve() {\n int N, M;\n cin >> N >> M;\n if (N == 0 && M == 0) {\n return false;\n }\n int s, g;\n cin >> s >> g;\n s--;\n g--;\n vector<vector<edge>> G(N);\n rep(i, M) {\n int x, y, d, c;\n cin >> x >> y >> d >> c;\n x--;\n y--;\n G[x].push_back(edge(y, d, c));\n G[y].push_back(edge(x, d, c));\n }\n\n auto tm = [&](int d, int s) -> ld { return (ld)d / (ld)s; };\n\n auto dijkstra = [&](int start) {\n vector dist(N, vector(40, vector(N, INF)));\n dist[start][0][start] = 0.;\n // time, {idx, speed, prev}\n min_priority_queue<pair<ld, tuple<int, int, int>>> que;\n que.push({0., {start, 0, start}});\n\n while (!que.empty()) {\n auto [time, data] = que.top();\n que.pop();\n auto [idx, speed, prev] = data;\n if (time != dist[idx][speed][prev]) continue;\n for (auto e : G[idx]) {\n if (prev == e.to) continue;\n for (int as = -1; as <= 1; as++) {\n int ns = as + speed;\n if (ns <= 0) continue;\n if (e.c < ns) continue;\n ld addtime = tm(e.d, ns);\n if (dist[e.to][ns][idx] > addtime + time) {\n dist[e.to][ns][idx] = addtime + time;\n que.push({addtime + time, {e.to, ns, idx}});\n }\n }\n }\n }\n return dist;\n };\n\n auto dists = dijkstra(s);\n // rep(s, 30) {\n // cout << \"+++++ \" << s << \" +++++\" << endl;\n // rep(i, N) cout << dists[i][s] << \" \";\n // cout << endl;\n // }\n\n cout << fixed << setprecision(15);\n\n ld ans = INF;\n rep(i, N) ans = min(ans, dists[g][1][i]);\n\n if (ans == INF) {\n cout << \"unreachable\" << endl;\n } else {\n cout << ans << endl;\n }\n return true;\n}\n\nint main() {\n while (solve())\n ;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4836, "score_of_the_acc": -0.017, "final_rank": 5 }, { "submission_id": "aoj_1162_8019046", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\n\nstruct road{\n ll to;\n ll d;\n ll c;\n};\nstruct city{\n ll n;\n ll p;\n ll v;\n};\nconst double EPS=1e-12;\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n ll N,M,S,T;\n while(cin>>N>>M){\n if(N==0)return 0;\n cin>>S>>T;\n S--;T--;\n vector<vector<road>> G(N);\n rep(i,M){\n ll x,y,d,c;\n cin>>x>>y>>d>>c;\n x--;y--;\n if(x==S||y==T)c=c;\n G[x].push_back(road{y,d,c});\n G[y].push_back(road{x,d,c});\n }\n vector<vector<vector<double>>> D(N,vector<vector<double>>(N,vector<double>(31,1e16)));\n D[S][S][0]=0.0;\n priority_queue<pair<double,vll>,vector<pair<double,vll>>,greater<pair<double,vll>>> Q; \n Q.push({0.0,{S,S,0}});\n vector<vector<vector<bool>>> seen(N,vector<vector<bool>>(N,vector<bool>(31,0)));\n while(!Q.empty()){\n auto p=Q.top();\n Q.pop();\n double C=p.first;\n ll n=p.second[0];\n ll pn=p.second[1];\n ll v=p.second[2];\n if(seen[n][pn][v])continue;\n seen[n][pn][v]=1;\n for(auto q:G[n]){\n if(pn==q.to)continue;\n for(ll dv=-1;dv<=1;dv++){\n ll nv=v+dv;\n if(nv<=0||nv>q.c)continue;\n if(seen[q.to][n][nv])continue;\n if(D[q.to][n][nv]>C+double(q.d)/double(nv)+EPS){\n D[q.to][n][nv]=C+double(q.d)/double(nv);\n Q.push({D[q.to][n][nv],{q.to,n,nv}});\n }\n }\n }\n \n }\n double an=1e18;\n rep(i,N)an=min(an,D[T][i][1]);\n if(an>1e15){\n cout<<\"unreachable\"<<endl;\n }\n else{\n cout<<fixed<<setprecision(16)<<an<<endl;\n }\n }\n \n}", "accuracy": 1, "time_ms": 40, "memory_kb": 4748, "score_of_the_acc": -0.0277, "final_rank": 9 } ]
aoj_1163_cpp
Problem E: Cards There are many blue cards and red cards on the table. For each card, an integer number greater than 1 is printed on its face. The same number may be printed on several cards. A blue card and a red card can be paired when both of the numbers printed on them have a common divisor greater than 1. There may be more than one red card that can be paired with one blue card. Also, there may be more than one blue card that can be paired with one red card. When a blue card and a red card are chosen and paired, these two cards are removed from the whole cards on the table. Figure E-1: Four blue cards and three red cards For example, in Figure E-1, there are four blue cards and three red cards. Numbers 2, 6, 6 and 15 are printed on the faces of the four blue cards, and 2, 3 and 35 are printed on those of the three red cards. Here, you can make pairs of blue cards and red cards as follows. First, the blue card with number 2 on it and the red card with 2 are paired and removed. Second, one of the two blue cards with 6 and the red card with 3 are paired and removed. Finally, the blue card with 15 and the red card with 35 are paired and removed. Thus the number of removed pairs is three. Note that the total number of the pairs depends on the way of choosing cards to be paired. The blue card with 15 and the red card with 3 might be paired and removed at the beginning. In this case, there are only one more pair that can be removed and the total number of the removed pairs is two. Your job is to find the largest number of pairs that can be removed from the given set of cards on the table. Input The input is a sequence of datasets. The number of the datasets is less than or equal to 100. Each dataset is formatted as follows. m n b 1 ... b k ... b m r 1 ... r k ... r n The integers m and n are the number of blue cards and that of red cards, respectively. You may assume 1 ≤ m ≤ 500 and 1≤ n ≤ 500. b k (1 ≤ k ≤ m ) and r k (1 ≤ k ≤ n ) are numbers printed on the blue cards and the red cards respectively, that are integers greater than or equal to 2 and less than 10000000 (=10 7 ). The input integers are separated by a space or a newline. Each of b m and r n is followed by a newline. There are no other characters in the dataset. The end of the input is indicated by a line containing two zeros separated by a space. Output For each dataset, output a line containing an integer that indicates the maximum of the number of the pairs. Sample Input 4 3 2 6 6 15 2 3 5 2 3 4 9 8 16 32 4 2 4 9 11 13 5 7 5 5 2 3 5 1001 1001 7 11 13 30 30 10 10 2 3 5 7 9 11 13 15 17 29 4 6 10 14 18 22 26 30 34 38 20 20 195 144 903 63 137 513 44 626 75 473 876 421 568 519 755 840 374 368 570 872 363 650 155 265 64 26 426 391 15 421 373 984 564 54 823 477 565 866 879 638 100 100 195 144 903 63 137 513 44 626 75 473 876 421 568 519 755 840 374 368 570 872 363 650 155 265 64 26 426 391 15 421 373 984 564 54 823 477 565 866 879 638 117 755 835 683 52 369 302 424 513 870 75 874 299 22 ...(truncated)
[ { "submission_id": "aoj_1163_10915351", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n\nint dfs(vector<vector<tuple<int,int,int>>>& G,vector<bool>& checked,int cv,int cf,int goal){\n if(cv==goal) return cf;\n checked[cv]=true;\n\n int ca=0;\n for(auto& nv:G[cv]){\n if(checked[get<0>(nv)]||get<1>(nv)==0) continue;\n ca=dfs(G,checked,get<0>(nv),min(get<1>(nv),cf),goal);\n if(ca>0){\n get<1>(nv)-=ca;\n get<1>(G[get<0>(nv)][get<2>(nv)])+=ca;\n return ca;\n }\n }\n\n return 0;\n}\n\nint main(){\n while(true){\n int X,Y; cin>>X>>Y;\n if(X==0&&Y==0) return 0;\n vector<int> A(X),B(Y);\n for(int& a:A) cin>>a;\n for(int& b:B) cin>>b;\n vector<vector<tuple<int,int,int>>> G(X+Y+2); //v, c, zansa\n for(int x=0;x<X;x++){\n for(int y=0;y<Y;y++){\n if(gcd(A[x],B[y])==1) continue;\n G[x].push_back({y+X,1,G[y+X].size()});\n G[y+X].push_back({x,0,G[x].size()-1});\n }\n }\n for(int i=0;i<X;i++){\n G[X+Y].push_back({i,1,G[i].size()});\n G[i].push_back({X+Y,0,G[X+Y].size()-1});\n }\n for(int i=0;i<Y;i++){\n G[i+X].push_back({X+Y+1,1,G[X+Y+1].size()});\n G[X+Y+1].push_back({i+X,0,G[i+X].size()-1});\n }\n\n int ans=0;\n while(true){\n vector<bool> checked(X+Y+2,false);\n int ca=dfs(G,checked,X+Y,1e9,X+Y+1);\n ans+=ca;\n if(ca==0) break;\n }\n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 1020, "memory_kb": 7404, "score_of_the_acc": -0.4177, "final_rank": 9 }, { "submission_id": "aoj_1163_10853811", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\n#define REP(i,n) for(int i=0;i<(int)n;++i)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n#define ALL(c) (c).begin(), (c).end()\n\ntypedef int Weight;\nstruct Edge {\n int src, dst;\n Weight weight;\n Edge(int src, int dst, Weight weight=1) :\n src(src), dst(dst), weight(weight) { }\n};\nbool operator < (const Edge &e, const Edge &f) {\n return e.weight != f.weight ? e.weight > f.weight : // !!INVERSE!!\n e.src != f.src ? e.src < f.src : e.dst < f.dst;\n}\ntypedef vector<Edge> Edges;\ntypedef vector<Edges> Graph;\n\ntypedef vector<Weight> Array;\ntypedef vector<Array> Matrix;\n\nbool augment(const Graph& g, int u,\n vector<int>& matchTo, vector<bool>& visited) {\n if (u < 0) return true;\n FOR(e, g[u]) if (!visited[e->dst]) {\n visited[e->dst] = true;\n if (augment(g, matchTo[e->dst], matchTo, visited)) {\n matchTo[e->src] = e->dst;\n matchTo[e->dst] = e->src;\n return true;\n }\n }\n return false;\n}\nint bipartiteMatching(const Graph& g, int L) {\n const int n = g.size();\n vector<int> matchTo(n, -1);\n int match = 0;\n REP(u, L) {\n vector<bool> visited(n);\n if (augment(g, u, matchTo, visited)) ++match;\n }\n return match;\n}\n\nint main(){\n\tint n,m;\n\twhile( cin >> n >> m and n){\n\t\tGraph g(n+m);\n\t\tint A[510],B[510];\n\t\tfor(int i = 0 ; i < n ; i++) cin >> A[i];\n\t\tfor(int i = 0 ; i < m ; i++) cin >> B[i];\n\t\tfor(int i = 0 ; i < n ; i++)\n\t\t\tfor(int j = 0 ; j < m ; j++)\n\t\t\t\tif( __gcd(A[i],B[j]) != 1 )\n\t\t\t\t\tg[i].push_back(Edge(i,n+j)),\n\t\t\t\t\tg[n+j].push_back(Edge(n+j,i));\n\n\t\tcout << bipartiteMatching(g,n) << endl;\n\t}\n}", "accuracy": 1, "time_ms": 740, "memory_kb": 7608, "score_of_the_acc": -0.3608, "final_rank": 4 }, { "submission_id": "aoj_1163_10773293", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing pll = pair<ll, ll>;\nconst ll INF = LLONG_MAX / 4;\nconst ll mod1 = 1000000007;\nconst ll mod9 = 998244353;\nconst ll Hash = 10000000000000061;\n#define all(a) (a).begin(),(a).end()\n#define rep(i, n) for (ll i = 0; (i) < (n); ++(i))\n#define reps(i, l, r) for(ll i = (l); (i) < (r); ++(i))\nll dx[8] = {1, 1, 0, -1, -1, -1, 0, 1};\nll dy[8] = {0, -1, -1, -1, 0, 1, 1, 1};\ntemplate <typename T>\nbool chmax(T &a, const T& b) {\n if (a < b) { a = b; return true; }\n return false;\n}\ntemplate <typename T>\nbool chmin(T &a, const T& b) {\n if (a > b) { a = b; return true; }\n return false;\n}\n\n#define EPS (1e-10)\n#define equals(a, b) (fabs((a) - (b)) < EPS)\nclass Point {\npublic:\n ld x;\n ld y;\n Point(ld _x = 0, ld _y = 0) : x(_x), y(_y) {}\n Point operator+(Point p) { return Point(x + p.x, y + p.y); }\n Point operator-(Point p) { return Point(x - p.x, y - p.y); }\n Point operator*(ld a) { return Point(a * x, a * y); }\n Point operator/(ld a) { return Point(x / a, y / a); }\n\n ld abs() { return sqrt(norm()); }\nld norm() { return x * x + y * y; }\n\n bool operator<(const Point& p) const {\n return !equals(x, p.x) ? x < p.x : y < p.y;\n }\n bool operator==(const Point& p) const {\n return fabs(x - p.x) < (1e-10) && fabs(y - p.y) < (1e-10);\n }\n};\ntypedef Point Vector;\nstruct Segment {\n Point A;\n Point B;\n};\ntypedef Segment Line;\nclass Circle {\npublic:\n Point C;\n ld r;\n Circle(Point C = Point(), ld r = 0.0) : C(C), r(r) {}\n};\ntypedef vector<Point> Polygon;\n\nstruct Edge {\n ll from, to, cost;\n Edge (ll from, ll to, ll cost = 1ll) : from(from), to(to), cost(cost) {}\n};\nstruct Graph {\n vector<vector<Edge>> G;\n Graph() = default;\n explicit Graph(ll N) : G(N) {}\n size_t size() const {\n return G.size();\n }\n void add(ll from, ll to, ll cost = 1ll, bool direct = 0) {\n G[from].emplace_back(from, to, cost);\n if (!direct) G[to].emplace_back(to, from, cost);\n }\n vector<Edge> &operator[](const int &k) {\n return G[k];\n }\n};\nusing Edges = vector<Edge>;\n\ntemplate <typename flow_t>\nstruct Dinic {\n const flow_t INF;\n\n struct edge {\n int to;\n flow_t cap;\n int rev;\n bool isrev;\n int idx;\n };\n\n vector<vector<edge> > graph;\n vector<int> min_cost, iter;\n\n explicit Dinic(int V) : INF(numeric_limits<flow_t>::max()), graph(V) {}\n\n void add_edge(int from, int to, flow_t cap, int idx = -1) {\n graph[from].emplace_back(\n (edge){to, cap, (int)graph[to].size(), false, idx});\n graph[to].emplace_back(\n (edge){from, 0, (int)graph[from].size() - 1, true, idx});\n }\n\n bool build_augment_path(int s, int t) {\n min_cost.assign(graph.size(), -1);\n queue<int> que;\n min_cost[s] = 0;\n que.push(s);\n while (!que.empty() && min_cost[t] == -1) {\n int p = que.front();\n que.pop();\n for (auto &e : graph[p]) {\n if (e.cap > 0 && min_cost[e.to] == -1) {\n min_cost[e.to] = min_cost[p] + 1;\n que.push(e.to);\n }\n }\n }\n return min_cost[t] != -1;\n }\n flow_t find_min_dist_augment_path(int idx, const int t, flow_t flow) {\n if (idx == t) return flow;\n for (int &i = iter[idx]; i < (int)graph[idx].size(); i++) {\n edge &e = graph[idx][i];\n if (e.cap > 0 && min_cost[idx] < min_cost[e.to]) {\n flow_t d = find_min_dist_augment_path(e.to, t, min(flow, e.cap));\n if (d > 0) {\n e.cap -= d;\n graph[e.to][e.rev].cap += d;\n return d;\n }\n }\n }\n return 0;\n }\n flow_t max_flow(int s, int t) {\n flow_t flow = 0;\n while (build_augment_path(s, t)) {\n iter.assign(graph.size(), 0);\n flow_t f;\n while ((f = find_min_dist_augment_path(s, t, INF)) > 0) flow += f;\n }\n return flow;\n }\n void output() {\n for (int i = 0; i < graph.size(); i++) {\n for (auto &e : graph[i]) {\n if (e.isrev) continue;\n auto &rev_e = graph[e.to][e.rev];\n cerr << i << \"->\" << e.to << \" (flow: \" << rev_e.cap << \"/\" << e.cap + rev_e.cap << \")\" << endl;\n }\n }\n }\n vector<bool> min_cut(int s) {\n vector<bool> used(graph.size());\n queue<int> que;\n que.emplace(s);\n used[s] = true;\n while (not que.empty()) {\n int p = que.front();\n que.pop();\n for (auto &e : graph[p]) {\n if (e.cap > 0 and not used[e.to]) {\n used[e.to] = true;\n que.emplace(e.to);\n }\n }\n }\n return used;\n }\n};\n\nbool solve(){\n ll N, M; cin >> N >> M;\n if(N == 0) return 0;\n vector<ll> a(N), b(M);\n rep(i, N) cin >> a[i];\n rep(i, M) cin >> b[i];\n Dinic<ll> mf(N+M+2);\n rep(i, N){\n rep(k, M){\n if(gcd(a[i], b[k]) > 1) mf.add_edge(i, k+N, 1);\n }\n }\n rep(i, N) mf.add_edge(N+M, i, 1);\n rep(i, M) mf.add_edge(i+N, M+N+1, 1);\n cout << mf.max_flow(N+M, N+M+1) << endl;\n return 1;\n}\n\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n \n ll t = 1;\n while(t){\n t = solve();\n }\n}", "accuracy": 1, "time_ms": 910, "memory_kb": 14144, "score_of_the_acc": -0.8935, "final_rank": 17 }, { "submission_id": "aoj_1163_10715965", "code_snippet": "// #ifndef ONLINE_JUDGE\n// #define _GLIBCXX_DEBUG//[]で配列外参照をするとエラーにしてくれる。上下のやつがないとTLEになるので注意 ABC311Eのサンプル4みたいなデバック中のTLEは防げないので注意\n// #endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n// #include <atcoder/all>\n// using namespace atcoder;\n\n\ntemplate<typename T> using vc = vector<T>;//prioriy_queueに必要なのでここにこれ書いてます\ntemplate<typename T> using vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nll INF = 2e18;\n\n// #include <boost/multiprecision/cpp_int.hpp>//インストール的なのをしてないとできないので注意\n// namespace multip = boost::multiprecision;\n// //using lll = multip::cpp_int;//無制限を使いたいときはこっちを使う\n// using lll = multip::int128_t;\n\nusing ld = long double;\nusing bl = bool;\n// using mint = modint998244353;\n//using mint = modint1000000007;\n//using mint = modint;//使うときはコメントアウトを外す\n//mint::set_mod(m);//使うときはコメントアウトを外す\n\ntemplate<class T> using pq = priority_queue<T, vc<T>>;//大きい順\ntemplate<class T> using pq_g = priority_queue<T, vc<T>, greater<T>>;//小さい順\n//-----------------------------------\n\n\n\n//-------------2.配列系--------------\nusing vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>; using vvvvl = vv<vvl>;\nusing vs = vc<string>; using vvs = vv<string>;\nusing vb = vc<bl>; using vvb = vv<bl>; using vvvb = vv<vb>;\nusing vld = vc<ld>; using vvld = vv<ld>; using vvvld = vv<vld>;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n// using vmint = vc<mint>; using vvmint = vv<mint>; using vvvmint = vv<vmint>;\n\n//配列外参照対策のやつは一番上の行にあります\n\n#define rep(i,n) for(ll i = 0; i < (n); ++i)//↓でrepを使うので書いてます\ntemplate<class T>istream& operator>>(istream& i, vc<T>& v) { rep(j, size(v))i >> v[j]; return i; }\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n\n\n//--------3.コード短縮化とか---------\n#define rep(i,n) for(ll i = 0; i < (n); ++i)\n#define rrep(i,n) for(ll i = 1; i <= (n); ++i)\n#define drep(i,n) for(ll i = (n)-1; i >= 0; --i)\n#define nfor(i,s,n) for(ll i=s;i<n;i++)//i=s,s+1...n-1 ノーマルfor\n#define dfor(i,s,n) for(ll i = (s)-1; i>=n;i--)//s-1スタートでnまで落ちる\n\n#define nall(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n\n#define chmax(x,y) x = max(x,y)\n#define chmin(x,y) x = min(x,y)\n\n#define pb push_back\n#define eb emplace_back\n#define em emplace\n#define pob pop_back\n\n\n#define YES cout<<\"Yes\"<<endl\n#define NO cout<<\"No\"<<endl\n#define YN {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}// if(a==b)YN;\n#define dame cout<<-1<<endl\n\n\n#define vc_unique(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define vc_rotate(v) rotate(v.begin(),v.begin()+1,v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(),v.end())\n\n//if (regex_match(s, regex(\"\")))YN;//文字列sの判定を行う。コメントアウトを外して「\"\"」の中に判定する内容を入れる\n\n//-------------------------------\n\n\n\n\n//---------4.グリッド系----------\nvl di = { 0,1,0,-1 };//vl di={0,1,1,1,0,-1,-1,-1};\nvl dj = { 1,0,-1,0 };//vl dj={1,1,0,-1,-1,-1,0,1};\n\nbool out_grid(ll i, ll j, ll h, ll w) {//trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_kaiten_r(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//時計回りに90°回転\n#define vvl_kaiten_l(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_kaiten_r(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//文字列版 時計回りに90°回転\n#define vs_kaiten_l(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n\n#define vvl_tenti(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][i]=v[i][j];swap(nx,v);}\n#define vs_tenti(v) {ll n = size(v); vs nx(n, string(n,'.')); rep(i, n)rep(j, n)nx[j][i] = v[i][j]; swap(nx, v);}\n\n//--------------------------------\n\n\n\n\n//-----------5.数学系--------------\n#define yu_qurid(x,y) ((x)*(x)+(y)*(y))//ユークリッド距離 sqrtはしてないなので注意\n#define mannhattan(x1,x2,y1,y2) (abs(x1-x2)+abs(y1-y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\ntemplate<class T>T tousa_sum1(T l, T d, T r) {//初項,公差,末項 で総和を求める\n T wide = (r - l) / d + 1;\n return (l + r) * wide / 2;\n}\ntemplate<class T>T tousa_sum2(T a, T d, T n) {//初項,交差,項数 で総和を求める\n return (a * 2 + d * (n - 1)) * n / 2;\n}\nll kousa_kousuu(ll l, ll r, ll d) {//初項,末項,交差 で等差数列の項数を求める\n return (r - l) / d + 1;\n}\n// mint touhi_sum(mint a, mint r, ll n) {//初項,公比,項数で等比数列の総和を求める\n// if (r == 1) {\n// return a * n;\n// }\n// mint bunsi = a * (r.pow(n) - mint(1));\n// mint bunbo = r - 1;\n// return bunsi / bunbo;\n// }\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n//----------------------------------------------\n\n\n\n\n//-----------6.デバックや出力系------------------\nvoid print(ld x) { printf(\"%.20Lf\\n\", x); }\n\nvoid mukou_debug(vvl to, bool yukou) {//GRAPH × GRAPH用の無向グラフを出力する\n ll n = size(to); ll cnt = 0;//辺の本数\n vc<pair<ll, ll>>v; rep(i, n)for (ll t : to[i]) if (i < t || yukou)cnt++, v.eb(i + 1, t + 1);//有向グラフなら全部OK、違うなら無向なのでf<tのみ見る、using Pのやつを別のにしたいときのためにPを使わずにpair<ll,ll>にしてる\n cout << n << ' ' << cnt << endl; for (auto [f, t] : v)cout << f << ' ' << t << endl;\n}\n\n#define vc_cout(v){ll n = size(v);rep(i,n)cout<<v[i]<<endl;}//一次元配列を出力する\n#define vv_cout(v){ll n = size(v);rep(i,n){rep(j,size(v[i])){cout<<v[i][j]<<' ';}cout<<endl;}}//二次元配列を出力する\n\n// edge class (for network-flow)\ntemplate<class FLOWTYPE> struct FlowEdge {\n // core members\n int rev, from, to;\n FLOWTYPE cap, icap, flow;\n \n // constructor\n FlowEdge(int r, int f, int t, FLOWTYPE c)\n : rev(r), from(f), to(t), cap(c), icap(c), flow(0) {}\n void reset() { cap = icap, flow = 0; }\n \n // debug\n friend ostream& operator << (ostream& s, const FlowEdge& E) {\n return s << E.from << \"->\" << E.to << '(' << E.flow << '/' << E.icap << ')';\n }\n};\n\n// graph class (for network-flow)\ntemplate<class FLOWTYPE> struct FlowGraph {\n // core members\n vector<vector<FlowEdge<FLOWTYPE>>> list;\n vector<pair<int,int>> pos; // pos[i] := {vertex, order of list[vertex]} of i-th edge\n \n // constructor\n FlowGraph(int n = 0) : list(n) { }\n void init(int n = 0) {\n list.assign(n, FlowEdge<FLOWTYPE>());\n pos.clear();\n }\n \n // getter\n vector<FlowEdge<FLOWTYPE>> &operator [] (int i) {\n return list[i];\n }\n const vector<FlowEdge<FLOWTYPE>> &operator [] (int i) const {\n return list[i];\n }\n size_t size() const {\n return list.size();\n }\n FlowEdge<FLOWTYPE> &get_rev_edge(const FlowEdge<FLOWTYPE> &e) {\n if (e.from != e.to) return list[e.to][e.rev];\n else return list[e.to][e.rev + 1];\n }\n FlowEdge<FLOWTYPE> &get_edge(int i) {\n return list[pos[i].first][pos[i].second];\n }\n const FlowEdge<FLOWTYPE> &get_edge(int i) const {\n return list[pos[i].first][pos[i].second];\n }\n vector<FlowEdge<FLOWTYPE>> get_edges() const {\n vector<FlowEdge<FLOWTYPE>> edges;\n for (int i = 0; i < (int)pos.size(); ++i) {\n edges.push_back(get_edge(i));\n }\n return edges;\n }\n \n // change edges\n void reset() {\n for (int i = 0; i < (int)list.size(); ++i) {\n for (FlowEdge<FLOWTYPE> &e : list[i]) e.reset();\n }\n }\n void change_edge(FlowEdge<FLOWTYPE> &e, FLOWTYPE new_cap, FLOWTYPE new_flow) {\n FlowEdge<FLOWTYPE> &re = get_rev_edge(e);\n e.cap = new_cap - new_flow, e.icap = new_cap, e.flow = new_flow;\n re.cap = new_flow;\n }\n \n // add_edge\n void add_edge(int from, int to, FLOWTYPE cap) {\n pos.emplace_back(from, (int)list[from].size());\n list[from].push_back(FlowEdge<FLOWTYPE>((int)list[to].size(), from, to, cap));\n list[to].push_back(FlowEdge<FLOWTYPE>((int)list[from].size() - 1, to, from, 0));\n }\n\n // debug\n friend ostream& operator << (ostream& s, const FlowGraph &G) {\n const auto &edges = G.get_edges();\n for (const auto &e : edges) s << e << endl;\n return s;\n }\n};\n\n// Dinic\ntemplate<class FLOWTYPE> FLOWTYPE Dinic\n (FlowGraph<FLOWTYPE> &G, int s, int t, FLOWTYPE limit_flow)\n{\n FLOWTYPE current_flow = 0;\n vector<int> level((int)G.size(), -1), iter((int)G.size(), 0);\n \n // Dinic BFS\n auto bfs = [&]() -> void {\n level.assign((int)G.size(), -1);\n level[s] = 0;\n queue<int> que;\n que.push(s);\n while (!que.empty()) {\n int v = que.front();\n que.pop();\n for (const FlowEdge<FLOWTYPE> &e : G[v]) {\n if (level[e.to] < 0 && e.cap > 0) {\n level[e.to] = level[v] + 1;\n if (e.to == t) return;\n que.push(e.to);\n }\n }\n }\n };\n \n // Dinic DFS\n auto dfs = [&](auto self, int v, FLOWTYPE up_flow) {\n if (v == t) return up_flow;\n FLOWTYPE res_flow = 0;\n for (int &i = iter[v]; i < (int)G[v].size(); ++i) {\n FlowEdge<FLOWTYPE> &e = G[v][i], &re = G.get_rev_edge(e);\n if (level[v] >= level[e.to] || e.cap == 0) continue;\n FLOWTYPE flow = self(self, e.to, min(up_flow - res_flow, e.cap));\n if (flow <= 0) continue;\n res_flow += flow;\n e.cap -= flow, e.flow += flow;\n re.cap += flow, re.flow -= flow;\n if (res_flow == up_flow) break;\n }\n return res_flow;\n };\n \n // flow\n while (current_flow < limit_flow) {\n bfs();\n if (level[t] < 0) break;\n iter.assign((int)iter.size(), 0);\n while (current_flow < limit_flow) {\n FLOWTYPE flow = dfs(dfs, s, limit_flow - current_flow);\n if (!flow) break;\n current_flow += flow;\n }\n }\n return current_flow;\n};\n\ntemplate<class FLOWTYPE> FLOWTYPE Dinic(FlowGraph<FLOWTYPE> &G, int s, int t) {\n return Dinic(G, s, t, numeric_limits<FLOWTYPE>::max());\n}\n\n\nint main(){\n vl ans;\n\n while(1){\n ll m, n;\n cin >> m >> n;\n\n if(m == 0 && n == 0) break;\n\n vl b(m), r(n);\n rep(i, m) cin >> b[i];\n rep(j, n) cin >> r[j];\n \n FlowGraph<ll> G(m+n+2);\n rep(i, m){\n G.add_edge(m+n, i, 1);\n }\n rep(j, n){\n G.add_edge(m+j, m+n+1, 1);\n }\n \n rep(i, m) rep(j, n){\n if(gcd(b[i], r[j]) > 1){\n G.add_edge(i, m+j, 1);\n }\n }\n \n ans.pb(Dinic(G, m+n, m+n+1));\n }\n\n for(ll a : ans) cout << a << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 930, "memory_kb": 17256, "score_of_the_acc": -1.1314, "final_rank": 19 }, { "submission_id": "aoj_1163_10679820", "code_snippet": "#define _USE_MATH_DEFINES\n#include <bits/stdc++.h>\nusing ll = long long;\nusing ull = unsigned long long;\nnamespace internal {\n\n template <class T> struct simple_queue {\n std::vector<T> payload;\n int pos = 0;\n void reserve(int n) { payload.reserve(n); }\n int size() const { return int(payload.size()) - pos; }\n bool empty() const { return pos == int(payload.size()); }\n void push(const T& t) { payload.push_back(t); }\n T& front() { return payload[pos]; }\n void clear() {\n payload.clear();\n pos = 0;\n }\n void pop() { pos++; }\n };\n\n} // namespace internal\ntemplate <class Cap> struct mf_graph {\npublic:\n mf_graph() : _n(0) {}\n explicit mf_graph(int n) : _n(n), g(n) {}\n\n int add_edge(int from, int to, Cap cap) {\n assert(0 <= from && from < _n);\n assert(0 <= to && to < _n);\n assert(0 <= cap);\n int m = int(pos.size());\n pos.push_back({ from, int(g[from].size()) });\n int from_id = int(g[from].size());\n int to_id = int(g[to].size());\n if (from == to) to_id++;\n g[from].push_back(_edge{ to, to_id, cap });\n g[to].push_back(_edge{ from, from_id, 0 });\n return m;\n }\n\n struct edge {\n int from, to;\n Cap cap, flow;\n };\n\n edge get_edge(int i) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n auto _e = g[pos[i].first][pos[i].second];\n auto _re = g[_e.to][_e.rev];\n return edge{ pos[i].first, _e.to, _e.cap + _re.cap, _re.cap };\n }\n std::vector<edge> edges() {\n int m = int(pos.size());\n std::vector<edge> result;\n for (int i = 0; i < m; i++) {\n result.push_back(get_edge(i));\n }\n return result;\n }\n void change_edge(int i, Cap new_cap, Cap new_flow) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n assert(0 <= new_flow && new_flow <= new_cap);\n auto& _e = g[pos[i].first][pos[i].second];\n auto& _re = g[_e.to][_e.rev];\n _e.cap = new_cap - new_flow;\n _re.cap = new_flow;\n }\n\n Cap flow(int s, int t) {\n return flow(s, t, std::numeric_limits<Cap>::max());\n }\n Cap flow(int s, int t, Cap flow_limit) {\n assert(0 <= s && s < _n);\n assert(0 <= t && t < _n);\n assert(s != t);\n\n std::vector<int> level(_n), iter(_n);\n internal::simple_queue<int> que;\n\n auto bfs = [&]() {\n std::fill(level.begin(), level.end(), -1);\n level[s] = 0;\n que.clear();\n que.push(s);\n while (!que.empty()) {\n int v = que.front();\n que.pop();\n for (auto e : g[v]) {\n if (e.cap == 0 || level[e.to] >= 0) continue;\n level[e.to] = level[v] + 1;\n if (e.to == t) return;\n que.push(e.to);\n }\n }\n };\n auto dfs = [&](auto self, int v, Cap up) {\n if (v == s) return up;\n Cap res = 0;\n int level_v = level[v];\n for (int& i = iter[v]; i < int(g[v].size()); i++) {\n _edge& e = g[v][i];\n if (level_v <= level[e.to] || g[e.to][e.rev].cap == 0) continue;\n Cap d =\n self(self, e.to, std::min(up - res, g[e.to][e.rev].cap));\n if (d <= 0) continue;\n g[v][i].cap += d;\n g[e.to][e.rev].cap -= d;\n res += d;\n if (res == up) return res;\n }\n level[v] = _n;\n return res;\n };\n\n Cap flow = 0;\n while (flow < flow_limit) {\n bfs();\n if (level[t] == -1) break;\n std::fill(iter.begin(), iter.end(), 0);\n Cap f = dfs(dfs, t, flow_limit - flow);\n if (!f) break;\n flow += f;\n }\n return flow;\n }\n\n std::vector<bool> min_cut(int s) {\n std::vector<bool> visited(_n);\n internal::simple_queue<int> que;\n que.push(s);\n while (!que.empty()) {\n int p = que.front();\n que.pop();\n visited[p] = true;\n for (auto e : g[p]) {\n if (e.cap && !visited[e.to]) {\n visited[e.to] = true;\n que.push(e.to);\n }\n }\n }\n return visited;\n }\n\nprivate:\n int _n;\n struct _edge {\n int to, rev;\n Cap cap;\n };\n std::vector<std::pair<int, int>> pos;\n std::vector<std::vector<_edge>> g;\n};\n\nint main()\n{\n ll m, n;\n while (std::cin >> m >> n)\n {\n if (m == 0)\n break;\n std::vector<ll>b(m);\n std::vector<ll>r(n);\n for (ll i = 0; i < m; i++)\n {\n std::cin >> b[i];\n }\n for (ll j = 0; j < n; j++)\n {\n std::cin >> r[j];\n }\n mf_graph<ll> graph(n + m + 2);\n for (ll i = 0; i < m; i++)\n {\n graph.add_edge(m + n, i, 1);\n }\n for (ll i = 0; i < n; i++)\n {\n graph.add_edge(m + i, n+m+1, 1);\n }\n for (ll i = 0; i < m; i++)\n {\n for (ll j = 0; j < n; j++)\n {\n\t\t\t\tif (std::gcd(b[i], r[j]) > 1)\n\t\t\t\t\tgraph.add_edge(i, j + m, 1);\n }\n }\n std::cout << graph.flow(n + m, n + m + 1)<<\"\\n\";\n }\n}", "accuracy": 1, "time_ms": 890, "memory_kb": 9968, "score_of_the_acc": -0.576, "final_rank": 11 }, { "submission_id": "aoj_1163_10630091", "code_snippet": "#include <algorithm>\n\n#include <vector>\n\nnamespace atcoder {\n\nnamespace internal {\n\ntemplate <class T> struct simple_queue {\n std::vector<T> payload;\n int pos = 0;\n void reserve(int n) { payload.reserve(n); }\n int size() const { return int(payload.size()) - pos; }\n bool empty() const { return pos == int(payload.size()); }\n void push(const T& t) { payload.push_back(t); }\n T& front() { return payload[pos]; }\n void clear() {\n payload.clear();\n pos = 0;\n }\n void pop() { pos++; }\n};\n\n} // namespace internal\n\n} // namespace atcoder\n\n#include <cassert>\n#include <limits>\n#include <queue>\n#include <vector>\n\nnamespace atcoder {\n\ntemplate <class Cap> struct mf_graph {\n public:\n mf_graph() : _n(0) {}\n mf_graph(int n) : _n(n), g(n) {}\n\n int add_edge(int from, int to, Cap cap) {\n assert(0 <= from && from < _n);\n assert(0 <= to && to < _n);\n assert(0 <= cap);\n int m = int(pos.size());\n pos.push_back({from, int(g[from].size())});\n int from_id = int(g[from].size());\n int to_id = int(g[to].size());\n if (from == to) to_id++;\n g[from].push_back(_edge{to, to_id, cap});\n g[to].push_back(_edge{from, from_id, 0});\n return m;\n }\n\n struct edge {\n int from, to;\n Cap cap, flow;\n };\n\n edge get_edge(int i) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n auto _e = g[pos[i].first][pos[i].second];\n auto _re = g[_e.to][_e.rev];\n return edge{pos[i].first, _e.to, _e.cap + _re.cap, _re.cap};\n }\n std::vector<edge> edges() {\n int m = int(pos.size());\n std::vector<edge> result;\n for (int i = 0; i < m; i++) {\n result.push_back(get_edge(i));\n }\n return result;\n }\n void change_edge(int i, Cap new_cap, Cap new_flow) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n assert(0 <= new_flow && new_flow <= new_cap);\n auto& _e = g[pos[i].first][pos[i].second];\n auto& _re = g[_e.to][_e.rev];\n _e.cap = new_cap - new_flow;\n _re.cap = new_flow;\n }\n\n Cap flow(int s, int t) {\n return flow(s, t, std::numeric_limits<Cap>::max());\n }\n Cap flow(int s, int t, Cap flow_limit) {\n assert(0 <= s && s < _n);\n assert(0 <= t && t < _n);\n assert(s != t);\n\n std::vector<int> level(_n), iter(_n);\n internal::simple_queue<int> que;\n\n auto bfs = [&]() {\n std::fill(level.begin(), level.end(), -1);\n level[s] = 0;\n que.clear();\n que.push(s);\n while (!que.empty()) {\n int v = que.front();\n que.pop();\n for (auto e : g[v]) {\n if (e.cap == 0 || level[e.to] >= 0) continue;\n level[e.to] = level[v] + 1;\n if (e.to == t) return;\n que.push(e.to);\n }\n }\n };\n auto dfs = [&](auto self, int v, Cap up) {\n if (v == s) return up;\n Cap res = 0;\n int level_v = level[v];\n for (int& i = iter[v]; i < int(g[v].size()); i++) {\n _edge& e = g[v][i];\n if (level_v <= level[e.to] || g[e.to][e.rev].cap == 0) continue;\n Cap d =\n self(self, e.to, std::min(up - res, g[e.to][e.rev].cap));\n if (d <= 0) continue;\n g[v][i].cap += d;\n g[e.to][e.rev].cap -= d;\n res += d;\n if (res == up) break;\n }\n return res;\n };\n\n Cap flow = 0;\n while (flow < flow_limit) {\n bfs();\n if (level[t] == -1) break;\n std::fill(iter.begin(), iter.end(), 0);\n while (flow < flow_limit) {\n Cap f = dfs(dfs, t, flow_limit - flow);\n if (!f) break;\n flow += f;\n }\n }\n return flow;\n }\n\n std::vector<bool> min_cut(int s) {\n std::vector<bool> visited(_n);\n internal::simple_queue<int> que;\n que.push(s);\n while (!que.empty()) {\n int p = que.front();\n que.pop();\n visited[p] = true;\n for (auto e : g[p]) {\n if (e.cap && !visited[e.to]) {\n visited[e.to] = true;\n que.push(e.to);\n }\n }\n }\n return visited;\n }\n\n private:\n int _n;\n struct _edge {\n int to, rev;\n Cap cap;\n };\n std::vector<std::pair<int, int>> pos;\n std::vector<std::vector<_edge>> g;\n};\n\n} // namespace atcoder\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconstexpr ll INF = 2e18;\n\nvoid solve(int m, int n, vector<ll> b, vector<ll> r) {\n atcoder::mf_graph<int> graph(m + n + 2);\n for (int i = 0; i < m; i++) {\n graph.add_edge(0, i + 1, 1);\n }\n for (int j = 0; j < n; j++) {\n graph.add_edge(j + m + 1, m + n + 1, 1);\n }\n for (int i = 0; i < m; i++) {\n for (int j = 0; j < n; j++) {\n if (gcd(b[i], r[j]) != 1) {\n graph.add_edge(i + 1, j + m + 1, 1);\n }\n }\n }\n cout << graph.flow(0, n + m + 1) << endl;\n}\n\nint main() {\n while (true) {\n int m, n;\n cin >> m >> n;\n if (m == 0 && n == 0) {\n break;\n }\n\n vector<ll> b(m);\n vector<ll> r(n);\n for (int i = 0; i < m; i++) {\n cin >> b[i];\n }\n for (int i = 0; i < n; i++) {\n cin >> r[i];\n }\n\n solve(m, n, b, r);\n }\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 8712, "score_of_the_acc": -0.3634, "final_rank": 7 }, { "submission_id": "aoj_1163_10609646", "code_snippet": "#include <atcoder/maxflow>\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconstexpr ll INF = 2e18;\n\n// 14:58~\nvoid solve(int m, int n, vector<ll> b, vector<ll> r) {\n atcoder::mf_graph<int> graph(m + n + 2);\n for (int i = 0; i < m; i++) {\n graph.add_edge(0, i + 1, 1);\n }\n for (int j = 0; j < n; j++) {\n graph.add_edge(j + m + 1, m + n + 1, 1);\n }\n for (int i = 0; i < m; i++) {\n for (int j = 0; j < n; j++) {\n if (gcd(b[i], r[j]) != 1) {\n graph.add_edge(i + 1, j + m + 1, 1);\n }\n }\n }\n cout << graph.flow(0, n + m + 1) << endl;\n}\n\nint main() {\n while (true) {\n int m, n;\n cin >> m >> n;\n if (m == 0 && n == 0) {\n break;\n }\n\n vector<ll> b(m);\n vector<ll> r(n);\n for (int i = 0; i < m; i++) {\n cin >> b[i];\n }\n for (int i = 0; i < n; i++) {\n cin >> r[i];\n }\n\n solve(m, n, b, r);\n }\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 8708, "score_of_the_acc": -0.3631, "final_rank": 6 }, { "submission_id": "aoj_1163_10609644", "code_snippet": "#include <atcoder/maxflow>\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconstexpr ll INF = 2e18;\n\nvoid solve(int m, int n, vector<ll> b, vector<ll> r) {\n atcoder::mf_graph<int> graph(m + n + 2);\n for (int i = 0; i < m; i++) {\n graph.add_edge(0, i + 1, 1);\n }\n for (int j = 0; j < n; j++) {\n graph.add_edge(j + m + 1, m + n + 1, 1);\n }\n for (int i = 0; i < m; i++) {\n for (int j = 0; j < n; j++) {\n if (gcd(b[i], r[j]) != 1) {\n graph.add_edge(i + 1, j + m + 1, 1);\n }\n }\n }\n cout << graph.flow(0, n + m + 1) << endl;\n}\n\nint main() {\n while (true) {\n int m, n;\n cin >> m >> n;\n if (m == 0 && n == 0) {\n break;\n }\n\n vector<ll> b(m);\n vector<ll> r(n);\n for (int i = 0; i < m; i++) {\n cin >> b[i];\n }\n for (int i = 0; i < n; i++) {\n cin >> r[i];\n }\n\n solve(m, n, b, r);\n }\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 8708, "score_of_the_acc": -0.3606, "final_rank": 3 }, { "submission_id": "aoj_1163_10579731", "code_snippet": "#include <bits/stdc++.h>\n\n#include <algorithm>\n#include <cassert>\n#include <limits>\n#include <queue>\n#include <vector>\n\n\n#include <vector>\n\nnamespace atcoder {\n\nnamespace internal {\n\ntemplate <class T> struct simple_queue {\n std::vector<T> payload;\n int pos = 0;\n void reserve(int n) { payload.reserve(n); }\n int size() const { return int(payload.size()) - pos; }\n bool empty() const { return pos == int(payload.size()); }\n void push(const T& t) { payload.push_back(t); }\n T& front() { return payload[pos]; }\n void clear() {\n payload.clear();\n pos = 0;\n }\n void pop() { pos++; }\n};\n\n} // namespace internal\n\n} // namespace atcoder\n\n\nnamespace atcoder {\n\ntemplate <class Cap> struct mf_graph {\n public:\n mf_graph() : _n(0) {}\n explicit mf_graph(int n) : _n(n), g(n) {}\n\n int add_edge(int from, int to, Cap cap) {\n assert(0 <= from && from < _n);\n assert(0 <= to && to < _n);\n assert(0 <= cap);\n int m = int(pos.size());\n pos.push_back({from, int(g[from].size())});\n int from_id = int(g[from].size());\n int to_id = int(g[to].size());\n if (from == to) to_id++;\n g[from].push_back(_edge{to, to_id, cap});\n g[to].push_back(_edge{from, from_id, 0});\n return m;\n }\n\n struct edge {\n int from, to;\n Cap cap, flow;\n };\n\n edge get_edge(int i) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n auto _e = g[pos[i].first][pos[i].second];\n auto _re = g[_e.to][_e.rev];\n return edge{pos[i].first, _e.to, _e.cap + _re.cap, _re.cap};\n }\n std::vector<edge> edges() {\n int m = int(pos.size());\n std::vector<edge> result;\n for (int i = 0; i < m; i++) {\n result.push_back(get_edge(i));\n }\n return result;\n }\n void change_edge(int i, Cap new_cap, Cap new_flow) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n assert(0 <= new_flow && new_flow <= new_cap);\n auto& _e = g[pos[i].first][pos[i].second];\n auto& _re = g[_e.to][_e.rev];\n _e.cap = new_cap - new_flow;\n _re.cap = new_flow;\n }\n\n Cap flow(int s, int t) {\n return flow(s, t, std::numeric_limits<Cap>::max());\n }\n Cap flow(int s, int t, Cap flow_limit) {\n assert(0 <= s && s < _n);\n assert(0 <= t && t < _n);\n assert(s != t);\n\n std::vector<int> level(_n), iter(_n);\n internal::simple_queue<int> que;\n\n auto bfs = [&]() {\n std::fill(level.begin(), level.end(), -1);\n level[s] = 0;\n que.clear();\n que.push(s);\n while (!que.empty()) {\n int v = que.front();\n que.pop();\n for (auto e : g[v]) {\n if (e.cap == 0 || level[e.to] >= 0) continue;\n level[e.to] = level[v] + 1;\n if (e.to == t) return;\n que.push(e.to);\n }\n }\n };\n auto dfs = [&](auto self, int v, Cap up) {\n if (v == s) return up;\n Cap res = 0;\n int level_v = level[v];\n for (int& i = iter[v]; i < int(g[v].size()); i++) {\n _edge& e = g[v][i];\n if (level_v <= level[e.to] || g[e.to][e.rev].cap == 0) continue;\n Cap d =\n self(self, e.to, std::min(up - res, g[e.to][e.rev].cap));\n if (d <= 0) continue;\n g[v][i].cap += d;\n g[e.to][e.rev].cap -= d;\n res += d;\n if (res == up) return res;\n }\n level[v] = _n;\n return res;\n };\n\n Cap flow = 0;\n while (flow < flow_limit) {\n bfs();\n if (level[t] == -1) break;\n std::fill(iter.begin(), iter.end(), 0);\n Cap f = dfs(dfs, t, flow_limit - flow);\n if (!f) break;\n flow += f;\n }\n return flow;\n }\n\n std::vector<bool> min_cut(int s) {\n std::vector<bool> visited(_n);\n internal::simple_queue<int> que;\n que.push(s);\n while (!que.empty()) {\n int p = que.front();\n que.pop();\n visited[p] = true;\n for (auto e : g[p]) {\n if (e.cap && !visited[e.to]) {\n visited[e.to] = true;\n que.push(e.to);\n }\n }\n }\n return visited;\n }\n\n private:\n int _n;\n struct _edge {\n int to, rev;\n Cap cap;\n };\n std::vector<std::pair<int, int>> pos;\n std::vector<std::vector<_edge>> g;\n};\n\n} // namespace atcoder\n\nusing namespace std;\nusing namespace atcoder;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rrep(i,start,end) for (ll i = start;i >= (ll)(end);i--)\n#define repn(i,end) for(ll i = 0; i <= (ll)(end); i++)\n#define reps(i,start,end) for(ll i = start; i < (ll)(end); i++)\n#define repsn(i,start,end) for(ll i = start; i <= (ll)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef vector<ll> vll;\ntypedef vector<pair<ll ,ll>> vpll;\ntypedef vector<vector<ll>> vvll;\ntypedef set<ll> sll;\ntypedef map<ll , ll> mpll;\ntypedef pair<ll ,ll> pll;\ntypedef tuple<ll , ll , ll> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (ll)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1LL << 60;\nconst ld EPS = 1e-9;\n \nll lceil(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b)+1;}else{return -((-a)/b);}}\nll lfloor(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b);}else{return -((-a)/b)-1;}}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\n//0indexed\ninline ll topbit(ll a){assert(a != 0);return 63 - __builtin_clzll(a);}\ninline ll smlbit(ll a){assert(a != 0);return __builtin_ctzll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\n// for AOJ or ICPC or etc..\ntemplate<class Tp>\nbool zero (const Tp &x) {\n return x == 0;\n}\n\ntemplate<class Tp, class... Args>\nbool zero (const Tp &x, const Args& ...args) {\n return zero(x) and zero(args...);\n}\n\n\n//ref https://qiita.com/drken/items/3beb679e54266f20ab63#5-%E6%B4%BB%E7%94%A8%E4%BE%8B-2-%E3%83%A1%E3%83%93%E3%82%A6%E3%82%B9%E9%96%A2%E6%95%B0%E5%80%A4%E3%81%AE%E5%88%97%E6%8C%99\nstruct Eratosthenes{\n ll n;\n vector<bool> isprime;//素数ならtrue\n vector<ll> minfact;//xを割り切る一番小さい数\n vector<ll> mobius;// メビウス関数値\n /*\n メビウス関数u(x)とは\n u(1) = 1;\n xがある素数pで2回以上割り切れるとき、u(x) = 0;\n x = p1 * p2 * p3 * p4...pKと素因数分解できるときu(x) = (-1)^k \n u(1)=1,u(2)=-1,u(3)=-1,u(4)=0,u(5)=-1,u(6)=1,u(7)=-1,u(8)=0,u(9)=0,u(10)=1\n */\n Eratosthenes(ll N){//O(NloglogN)\n n = N;\n isprime.resize(n+1,true);\n minfact.resize(n+1,-1);\n mobius.resize(n+1,1);\n isprime[0] = false;\n isprime[1] = false;\n minfact[1] = 1;\n for(ll p = 2;p <= n;p++){\n if(!isprime[p])continue;\n //pの情報を更新\n minfact[p] = p;\n mobius[p] = -1;\n for(ll q = p*2;q <= n;q+=p){\n isprime[q] = false;\n if(minfact[q] == -1)minfact[q] = p;\n if((q/p)%p==0)mobius[q]=0;//qはpで2回以上割れる\n else mobius[q] = -mobius[q];//反転\n }\n }\n }\n\n bool is_prime(ll x){\n assert(x <= n);\n return isprime[x];\n }\n\n //素因数分解(log(x))\n vector<pair<ll,ll>> soinsu_bunkai(ll x){\n vector<pair<ll,ll>> ret;\n while(x > 1){\n ll p = minfact[x];\n ll times = 0;//割り切れる回数\n while(minfact[x] == p){\n x/= p;\n times++;\n }\n ret.push_back({p,times});\n }\n return ret;\n }\n\n //約数列挙 O(約数の個数) n <= 10^9 のとき 高々1344\n vector<ll> yakusu_rekkyo(ll x){\n vector<ll> ret;\n ret.push_back(1);\n vector<pair<ll,ll>> pf = soinsu_bunkai(x);\n for(auto &p:pf){\n ll siz = ret.size();\n for(ll i = 0;i < siz;i++){\n ll v = 1;\n for(ll j = 0;j < p.second;j++){\n v *= p.first;\n ret.push_back(ret[i]*v);\n }\n }\n }\n return ret;\n }\n};\n\n// 高速ゼータ変換\n// 入力 f が in-place に更新されて、F になる\ntemplate<class T> void fast_zeta(vector<T> &f){\n ll n = f.size();\n Eratosthenes era(n);\n vector<bool> isprime = era.isprime;\n // 各素数 p 軸に対して\n // 大きい座標 (k * p) から小さい座標 (k) へと足し込む\n for(ll p = 2;p < n;p++){\n if(!isprime[p])continue;\n for(ll k = (n-1)/p;k >= 1;k--){\n f[k] += f[k * p];\n }\n }\n} \n// 高速メビウス変換\n// 入力 F が in-place に更新されて、f になる\ntemplate<class T> void fast_mobius(vector<T> &F){\n ll n = F.size();\n Eratosthenes era(n);\n vector<bool> isprime = era.isprime;\n // 各素数 p 軸に対して\n // 小さい座標 (k) から大きい座標 (k * p) を引いていく\n for(ll p = 2;p < n;p++){\n if(!isprime[p])continue;\n for(ll k = 1;k * p < n;k++){\n F[k] -= F[k * p];\n }\n }\n}\n\n//約数列挙\nvector<ll> divisor(ll n){\n vector<ll> ret;\n for(ll i = 1;i * i <= n;i++){\n if(n % i == 0){\n ret.push_back(i);\n if(i * i != n)ret.push_back(n/i);\n }\n }\n //昇順\n sort(all(ret));\n return ret;\n}\n\nvoid solve(ll m,ll n){\n vll b(m),r(n);cin >> b >> r;\n\n vector<set<ll>> rs(n);\n rep(i,n){\n vll ret = divisor(r[i]);\n each(p,ret)if(p!= 1)rs[i].insert(p);\n }\n mf_graph<ll> mf(n + m + 2);\n vvll edges(m,vll(n));\n rep(i,m){\n vll ret =divisor(b[i]);\n each(p,ret)if(p != 1)rep(j,n)if(rs[j].contains(p) && edges[i][j] == 0){\n edges[i][j] = 1;\n mf.add_edge(i,m+j,1);\n }\n }\n rep(i,m){\n mf.add_edge(n+m,i,1);\n }\n rep(i,n){\n mf.add_edge(m+i,n+m+1,1);\n }\n ll ret = mf.flow(n+m,n+m+1);\n cout << ret << endl;\n}\n \nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n // Eratosthenes era(lpow(10,7));\n while(true){\n LL(m,n);\n if(zero(m,n))break;\n solve(m,n);\n }\n}", "accuracy": 1, "time_ms": 1110, "memory_kb": 12616, "score_of_the_acc": -0.8307, "final_rank": 16 }, { "submission_id": "aoj_1163_10568814", "code_snippet": "#include <iostream>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <vector>\n\nusing namespace std;\n// https://cpprefjp.github.io/reference/numeric/gcd.html\ntemplate <class M, class N> constexpr std::common_type_t<M, N> gcd(M m, N n) {\n if (m == 0 && n == 0) {\n return 0;\n }\n\n auto mm = abs(m);\n auto nn = abs(n);\n while (mm != 0 && nn != 0) {\n if (mm > nn) {\n mm %= nn;\n } else {\n nn %= mm;\n }\n }\n return mm < nn ? nn : mm;\n}\n\n// グラフを表す構造体\nstruct Graph {\n // 辺を表す構造体\n // rev: 逆元 (to, from) が G[to] の中で何番目の要素か\n // cap: 辺 (from, to) の容量\n struct\n Edge { // グラフ構造体のスコープ内で使える構造体,mainとかでは使えない\n int rev, from, to, cap;\n Edge(int r, int f, int t, int c)\n : rev(r), from(f), to(t), cap(c) {} // reverse, from, to, capacity\n };\n // 隣接リスト\n vector<vector<Edge>> list; // Edge の実態が list\n\n // N: 頂点数 <- コンストラクタ(構造体の初期化のときにのみ呼ばれる,__init__\n // のこと) 構造体と名前が一緒\n Graph(int N = 0) : list(N) {}\n ~Graph() {} // ディストラクタ\n\n // グラフの頂点数取得,インスタンスメソッド\n size_t size() { return list.size(); }\n\n // Graph インスタンスをGとして\n // G.list[v] を G[v] とかけるようにしておく\n vector<Edge>& operator[](int i) { return list[i]; }\n\n // 辺 e = (u, v) の逆辺 (v, u) を取得\n Edge& redge(const Edge& e) { return list[e.to][e.rev]; }\n\n // 辺 e = (u, v) に流量 f のフローを流す\n // 辺 e = (u, v) の流量が f だけ減少する\n // このとき,逆辺 e' = (v, u) の流量を増やす\n void run_flow(Edge& e, int f) {\n e.cap -= f;\n redge(e).cap += f;\n }\n\n // 頂点 from から頂点 to へ容量 cap の辺を張る\n // このとき to から from への容量 0 の辺を張っておく\n void addedge(int from, int to, int cap) {\n int fromrev = (int)list[from].size();\n int torev = (int)list[to].size(); // 逆辺を追加するインデックスに相当\n list[from].push_back(Edge(torev, from, to, cap));\n list[to].push_back(Edge(fromrev, to, from, 0)); // ぎゃくへn\n }\n};\n\nstruct FordFulkerson {\n static const int INF = 1 << 30; // 無限大を表す値を適切に\n vector<int> seen;\n\n FordFulkerson() {}\n\n // 残余グラフ上で s-t パスを見つける(深さ優先探索)\n // 戻り値は s-t パス上の容量の最小値(見つからなかったら 0)\n // f: s から v へ到達した過程の各辺の容量の最小値\n int fodfs(Graph& G, int v, int t, int f) {\n // 終端 t に到達したらリターン\n if (v == t) return f;\n\n // 深さ優先探索\n seen[v] = true;\n for (auto& e : G[v]) {\n if (seen[e.to]) continue;\n\n // 容量0の辺は実際には存在しない\n if (e.cap == 0) continue;\n\n // s-t パスを探す\n // 見つかったら flow はパス上の最小容量\n // 見つからなかったら f = 0\n int flow = fodfs(G, e.to, t, min(f, e.cap));\n\n // s-t パスが見つからなかったら次辺を試す\n if (flow == 0) continue;\n\n // 辺 e に容量 flow のフローを流す\n G.run_flow(e, flow);\n\n // s-t パスを見つけたらパス上最小容量を返す\n return flow;\n }\n\n return 0;\n }\n\n // グラフ G の s-t 間の最大流量を求める\n // ただしリターン時に G は残余グラフになる\n\n int solve(Graph& G, int s, int t) {\n int res = 0;\n // 残余グラフに s-t パスがなくなるまで反復\n while (true) {\n seen.assign((int)G.size(), 0);\n int flow = fodfs(G, s, t, INF);\n\n // s-t パスが見つからなかったら終了\n if (flow == 0) return res;\n\n // 答えを加算\n res += flow;\n }\n }\n};\n\nint main() {\n while (1) {\n int m, n;\n cin >> m >> n;\n if (m == 0 && n == 0) break;\n vector<int> b(m), r(n);\n for (int i = 0; i < m; i++) {\n cin >> b[i];\n }\n for (int i = 0; i < n; i++) {\n cin >> r[i];\n }\n\n // 約数を持つカード同士をつないでグラフを作成する\n // 頂点のindex:\n // 始点s: 0\n // 青のカード: 1, ... ,m\n // 赤のカード: m + 1, ... , m + n\n // 終点: m + n + 1\n // 全頂点は 0 ... m + n + 1 なので m + n + 1 + 1個\n Graph Graph(m + n + 1 + 1);\n // cout << \"----公約数を持つカード----\" << endl;\n for (int i = 0; i < m; i++) {\n for (int j = 0; j < n; j++) {\n if (gcd(b[i], r[j]) > 1) { // 互いに素ならgcd=1\n Graph.addedge(1 + i, 1 + m + j, 1);\n\n // cout << 1 + i << \",\" << 1 + m + j << endl;\n }\n }\n }\n // cout << \"--------\" << endl;\n // s=0を青のカードにつなぐ\n for (int i = 0; i < m; i++) {\n Graph.addedge(0, 1 + i, 1);\n }\n // 赤のカードを終点m+n+1につなぐ\n for (int j = 0; j < n; j++) {\n Graph.addedge(1 + m + j, m + n + 1, 1);\n }\n FordFulkerson ff;\n int s = 0, t = m + n + 1;\n cout << ff.solve(Graph, s, t) << endl;\n }\n}\n\n/*\n入力:\n2 3\n4 9\n8 16 32\n出力:\n2 → 1\n\n入力:\n4 2\n4 9 11 13\n5 7\n出力:\n2 → 0\n*/", "accuracy": 1, "time_ms": 990, "memory_kb": 9012, "score_of_the_acc": -0.5302, "final_rank": 10 }, { "submission_id": "aoj_1163_10556970", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\n#include <algorithm>\n\n#include <vector>\n\nnamespace atcoder {\n\nnamespace internal {\n\ntemplate <class T> struct simple_queue {\n std::vector<T> payload;\n int pos = 0;\n void reserve(int n) { payload.reserve(n); }\n int size() const { return int(payload.size()) - pos; }\n bool empty() const { return pos == int(payload.size()); }\n void push(const T& t) { payload.push_back(t); }\n T& front() { return payload[pos]; }\n void clear() {\n payload.clear();\n pos = 0;\n }\n void pop() { pos++; }\n};\n\n} // namespace internal\n\n} // namespace atcoder\n\n#include <cassert>\n#include <limits>\n#include <queue>\n#include <vector>\n\nnamespace atcoder {\n\ntemplate <class Cap> struct mf_graph {\n public:\n mf_graph() : _n(0) {}\n mf_graph(int n) : _n(n), g(n) {}\n\n int add_edge(int from, int to, Cap cap) {\n assert(0 <= from && from < _n);\n assert(0 <= to && to < _n);\n assert(0 <= cap);\n int m = int(pos.size());\n pos.push_back({from, int(g[from].size())});\n int from_id = int(g[from].size());\n int to_id = int(g[to].size());\n if (from == to) to_id++;\n g[from].push_back(_edge{to, to_id, cap});\n g[to].push_back(_edge{from, from_id, 0});\n return m;\n }\n\n struct edge {\n int from, to;\n Cap cap, flow;\n };\n\n edge get_edge(int i) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n auto _e = g[pos[i].first][pos[i].second];\n auto _re = g[_e.to][_e.rev];\n return edge{pos[i].first, _e.to, _e.cap + _re.cap, _re.cap};\n }\n std::vector<edge> edges() {\n int m = int(pos.size());\n std::vector<edge> result;\n for (int i = 0; i < m; i++) {\n result.push_back(get_edge(i));\n }\n return result;\n }\n void change_edge(int i, Cap new_cap, Cap new_flow) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n assert(0 <= new_flow && new_flow <= new_cap);\n auto& _e = g[pos[i].first][pos[i].second];\n auto& _re = g[_e.to][_e.rev];\n _e.cap = new_cap - new_flow;\n _re.cap = new_flow;\n }\n\n Cap flow(int s, int t) {\n return flow(s, t, std::numeric_limits<Cap>::max());\n }\n Cap flow(int s, int t, Cap flow_limit) {\n assert(0 <= s && s < _n);\n assert(0 <= t && t < _n);\n assert(s != t);\n\n std::vector<int> level(_n), iter(_n);\n internal::simple_queue<int> que;\n\n auto bfs = [&]() {\n std::fill(level.begin(), level.end(), -1);\n level[s] = 0;\n que.clear();\n que.push(s);\n while (!que.empty()) {\n int v = que.front();\n que.pop();\n for (auto e : g[v]) {\n if (e.cap == 0 || level[e.to] >= 0) continue;\n level[e.to] = level[v] + 1;\n if (e.to == t) return;\n que.push(e.to);\n }\n }\n };\n auto dfs = [&](auto self, int v, Cap up) {\n if (v == s) return up;\n Cap res = 0;\n int level_v = level[v];\n for (int& i = iter[v]; i < int(g[v].size()); i++) {\n _edge& e = g[v][i];\n if (level_v <= level[e.to] || g[e.to][e.rev].cap == 0) continue;\n Cap d =\n self(self, e.to, std::min(up - res, g[e.to][e.rev].cap));\n if (d <= 0) continue;\n g[v][i].cap += d;\n g[e.to][e.rev].cap -= d;\n res += d;\n if (res == up) break;\n }\n return res;\n };\n\n Cap flow = 0;\n while (flow < flow_limit) {\n bfs();\n if (level[t] == -1) break;\n std::fill(iter.begin(), iter.end(), 0);\n while (flow < flow_limit) {\n Cap f = dfs(dfs, t, flow_limit - flow);\n if (!f) break;\n flow += f;\n }\n }\n return flow;\n }\n\n std::vector<bool> min_cut(int s) {\n std::vector<bool> visited(_n);\n internal::simple_queue<int> que;\n que.push(s);\n while (!que.empty()) {\n int p = que.front();\n que.pop();\n visited[p] = true;\n for (auto e : g[p]) {\n if (e.cap && !visited[e.to]) {\n visited[e.to] = true;\n que.push(e.to);\n }\n }\n }\n return visited;\n }\n\n private:\n int _n;\n struct _edge {\n int to, rev;\n Cap cap;\n };\n std::vector<std::pair<int, int>> pos;\n std::vector<std::vector<_edge>> g;\n};\n\n} // namespace atcoder\n\n\nbool solve(){\n int m, n; cin >> m >> n;\n if(m == 0) return false;\n\n vector<int> b(m), r(n);\n for(int i = 0; i < m; ++i) cin >> b[i];\n for(int i = 0; i < n; ++i) cin >> r[i];\n\n atcoder::mf_graph<int> f(m + n + 2);\n int s = m + n, t = s + 1;\n for(int i = 0; i < m; ++i) f.add_edge(s, i, 1);\n for(int j = m; j < m + n; ++j) f.add_edge(j, t, 1);\n for(int i = 0; i < m; ++i){\n for(int j = 0; j < n; ++j){\n if(gcd(b[i], r[j]) != 1){\n f.add_edge(i, m + j, 1);\n }\n }\n }\n cout << f.flow(s, t) << endl;\n\n return true;\n}\n\nint main(){\n while(1) if(!solve()) break;\n}", "accuracy": 1, "time_ms": 640, "memory_kb": 8456, "score_of_the_acc": -0.3984, "final_rank": 8 }, { "submission_id": "aoj_1163_10444634", "code_snippet": "//\n// Hopcroft-Karp の最大二部マッチング\n//\n// verified\n// AOJ 1163 カードゲーム\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=1163&lang=jp\n//\n// TTPC 2022 H - Colorful Graph\n// https://atcoder.jp/contests/ttpc2022/tasks/ttpc2022_h\n//\n\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n\nstruct HopcroftKarp {\n // input\n int size_left, size_right;\n vector<vector<int>> list; // left to right\n\n // results\n vector<int> lr, rl;\n \n // intermediate results\n vector<bool> seen, matched;\n vector<int> level;\n \n // constructor\n HopcroftKarp(int l, int r) : size_left(l), size_right(r), list(l, vector<int>()) { }\n void add_edge(int from, int to) {\n list[from].push_back(to);\n }\n\n // getter, debugger\n const vector<int> &operator [] (int i) const { \n return list[i];\n }\n friend ostream& operator << (ostream& s, const HopcroftKarp& G) {\n s << endl;\n for (int i = 0; i < G.list.size(); ++i) {\n s << i << \": \";\n for (int j = 0; j < G.list[i].size(); ++j) {\n s << G.list[i][j];\n if (j + 1 != G.list[i].size()) s << \", \";\n }\n s << endl;\n }\n return s;\n }\n \n // solver\n void hobfs() {\n queue<int> que;\n for (int left = 0; left < size_left; ++left) {\n level[left] = -1;\n if (!matched[left]) {\n que.push(left);\n level[left] = 0;\n }\n }\n level[size_left] = size_left;\n while (!que.empty()) {\n int left = que.front();\n que.pop();\n for (int i = 0; i < list[left].size(); ++i) {\n int right = list[left][i];\n int next = rl[right];\n if (level[next] == -1) {\n level[next] = level[left] + 1;\n que.push(next);\n }\n }\n }\n }\n bool hodfs(int left) {\n if (left == size_left) return true;\n if (seen[left]) return false;\n seen[left] = true;\n for (int i = 0; i < list[left].size(); ++i) {\n int right = list[left][i];\n int next = rl[right];\n if (next == -1) next = size_left;\n if (level[next] > level[left] && hodfs(next)) {\n rl[right] = left;\n return true;\n }\n }\n return false;\n }\n int solve() {\n seen.assign(size_left, false);\n matched.assign(size_left, false);\n level.assign(size_left + 1, -1);\n lr.assign(size_left, -1);\n rl.assign(size_right, -1);\n int res = 0;\n while (true) {\n hobfs();\n seen.assign(size_left, false);\n bool finished = true;\n for (int left = 0; left < size_left; ++left) {\n if (!matched[left] && hodfs(left)) {\n matched[left] = true;\n ++res;\n finished = false;\n }\n }\n if (finished) break;\n }\n for (int r = 0; r < size_right; r++) {\n if (rl[r] != -1) lr[rl[r]] = r;\n }\n return res;\n }\n};\n\n\n//------------------------------//\n// Examples\n//------------------------------//\n\n// AOJ 1163 カードゲーム\nvoid AOJ_1163() {\n int N, M;\n while (cin >> N >> M, N) {\n HopcroftKarp G(N, M);\n vector<int> left(N), right(M);\n for (int i = 0; i < N; ++i) cin >> left[i];\n for (int i = 0; i < M; ++i) cin >> right[i];\n for (int i = 0; i < N; ++i) {\n for (int j = 0; j < M; ++j) {\n if (gcd(left[i], right[j]) > 1) G.add_edge(i, j);\n }\n }\n cout << G.solve() << endl;\n }\n}\n\n// TTPC 2022 H - Colorful Graph\n// Edge Class\ntemplate<class T> struct Edge {\n int from, to;\n T val;\n Edge() : from(-1), to(-1), val(-1) { }\n Edge(int f, int t, T v = -1) : from(f), to(t), val(v) {}\n friend ostream& operator << (ostream& s, const Edge& E) {\n return s << E.from << \"->\" << E.to;\n }\n};\n\n// graph class\ntemplate<class T> struct Graph {\n vector<vector<Edge<T>>> list;\n vector<vector<Edge<T>>> reversed_list;\n \n Graph(int n = 0) : list(n), reversed_list(n) { }\n void init(int n = 0) {\n list.assign(n, vector<Edge<T>>());\n reversed_list.assign(n, vector<Edge<T>>());\n }\n const vector<Edge<T>> &operator [] (int i) const { return list[i]; }\n const vector<Edge<T>> &get_rev_edges(int i) const { return reversed_list[i]; }\n const size_t size() const { return list.size(); }\n \n void add_edge(int from, int to, T val = -1) {\n list[from].push_back(Edge(from, to, val));\n reversed_list[to].push_back(Edge(to, from, val));\n }\n \n void add_bidirected_edge(int from, int to, T val = -1) {\n list[from].push_back(Edge(from, to, val));\n list[to].push_back(Edge(to, from, val));\n reversed_list[from].push_back(Edge(from, to, val));\n reversed_list[to].push_back(Edge(to, from, val));\n }\n\n friend ostream &operator << (ostream &s, const Graph &G) {\n s << endl;\n for (int i = 0; i < G.size(); ++i) {\n s << i << \" -> \";\n for (const auto &e : G[i]) s << e.to << \" \";\n s << endl;\n }\n return s;\n }\n};\n\n// strongly connected components decomposition\ntemplate<class T> struct SCC {\n // results\n vector<int> cmp;\n vector<vector<int>> groups;\n Graph<T> dag;\n \n // intermediate results\n vector<bool> seen;\n vector<int> vs, rvs;\n \n // constructor\n SCC() { }\n SCC(const Graph<T> &G) { \n solve(G);\n }\n void init(const Graph<T> &G) { \n solve(G);\n }\n\n // getter, compressed dag(v: node-id of compressed dag)\n int get_size(int v) const {\n return groups[v].size();\n }\n vector<int> get_group(int v) const {\n return groups[v];\n }\n\n // solver\n void dfs(const Graph<T> &G, int v) {\n seen[v] = true;\n for (const auto &e : G[v]) if (!seen[e.to]) dfs(G, e.to);\n vs.push_back(v);\n }\n void rdfs(const Graph<T> &G, int v, int k) {\n seen[v] = true;\n cmp[v] = k;\n for (const auto &e : G.get_rev_edges(v)) if (!seen[e.to]) rdfs(G, e.to, k);\n rvs.push_back(v);\n }\n void reconstruct(const Graph<T> &G) {\n dag.init((int)groups.size());\n set<pair<int,int>> new_edges;\n for (int i = 0; i < (int)G.size(); ++i) {\n int u = cmp[i];\n for (const auto &e : G[i]) {\n int v = cmp[e.to];\n if (u == v) continue;\n if (!new_edges.count({u, v})) {\n dag.add_edge(u, v);\n new_edges.insert({u, v});\n }\n }\n }\n }\n void solve(const Graph<T> &G) {\n // first dfs\n seen.assign((int)G.size(), false);\n vs.clear();\n for (int v = 0; v < (int)G.size(); ++v) if (!seen[v]) dfs(G, v);\n\n // back dfs\n int k = 0;\n groups.clear();\n seen.assign((int)G.size(), false);\n cmp.assign((int)G.size(), -1);\n for (int i = (int)G.size()-1; i >= 0; --i) {\n if (!seen[vs[i]]) {\n rvs.clear();\n rdfs(G, vs[i], k++);\n groups.push_back(rvs);\n }\n }\n reconstruct(G);\n }\n};\nvoid TTPC_2022_H() {\n int N, M, a, b;\n cin >> N >> M;\n Graph<int> G(N);\n for (int i = 0; i < M; i++) {\n cin >> a >> b;\n a--, b--;\n G.add_edge(a, b, i);\n }\n SCC scc(G);\n\n const auto &dag = scc.dag;\n const auto &groups = scc.groups;\n\n int V = dag.size();\n HopcroftKarp hk(V, V);\n for (int v = 0; v < V; v++) {\n vector<bool> can(V, false);\n can[v] = true;\n queue<int> que;\n que.push(v);\n while (!que.empty()) {\n auto x = que.front();\n que.pop();\n for (auto e : dag[x]) {\n if (can[e.to]) continue;\n can[e.to] = true;\n que.push(e.to);\n }\n }\n for (int v2 = 0; v2 < V; v2++) {\n if (v2 != v && can[v2]) hk.add_edge(v, v2);\n }\n }\n int max_flow = hk.solve();\n\n vector<int> source, ans(V, -1);\n for (int v = 0; v < V; v++) if (hk.rl[v] == -1) source.push_back(v);\n for (int c = 0; c < source.size(); c++) {\n int v = source[c];\n while (v != -1) {\n ans[v] = c + 1;\n v = hk.lr[v];\n }\n }\n\n vector<int> res(N, -1);\n for (int v = 0; v < V; v++) for (auto v2 : groups[v]) res[v2] = ans[v];\n for (int i = 0; i < N; i++) cout << res[i] << \" \";\n cout << endl;\n}\n\n\nint main() {\n AOJ_1163();\n //TTPC_2022_H();\n}", "accuracy": 1, "time_ms": 590, "memory_kb": 4108, "score_of_the_acc": -0.0603, "final_rank": 2 }, { "submission_id": "aoj_1163_10339681", "code_snippet": "#include <bits/stdc++.h>\n#include <numeric>\n#define LOOP(n) for (int _i = 0; _i < (n); _i++)\n#define REP(i, n) for (int i = 0; i < (n); ++i)\n#define RREP(i, n) for (int i = (n); i >= 0; --i)\n#define FOR(i, r, n) for (int i = (r); i < (n); ++i)\n#define ALL(obj) begin(obj), end(obj)\n#define yes \"Yes\"\n#define no \"No\"\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\ntypedef pair<ll,int> pli;\ntypedef pair<int,ll> pil;\ntypedef vector<vector<int>> vvi;\ntypedef vector<vector<ll>> vvl;\nconst vector<char> alpha = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};\nint dx[4] = {0, 1, 0, -1};\nint dy[4] = {1, 0, -1, 0};\nconst ll INF = 1000000007;\nconst ll MOD = 998244353;\n#define mpair(a,b) make_pair((a),(b))\ntemplate<typename T> inline bool chmax(T &a, T b) { return ((a < b) ? (a = b, true) : (false)); }\ntemplate<typename T> inline bool chmin(T &a, T b) { return ((a > b) ? (a = b, true) : (false)); }\nstruct MaximumFlow{\n struct edge{\n int from,to;\n ll cap, flow;\n int rev;\n };\n int n;\n vector<vector<edge>> G;\n MaximumFlow(int n) : n(n),G(n){}\n void add_edge(int s,int t,ll cap){//対になる辺がどこにあるかを記録\n G[s].push_back({s,t,cap,0,(int)G[t].size()});\n G[t].push_back({t,s,0,0,(int)G[s].size()-1});\n }\n\n ll max_flow(int s,int t){\n vector<int> dist(n), iter(n);\n function<int(void)> BFS = [&](void) -> int{\n dist.assign(n,-1);\n dist[s]=0;\n queue<int> que;\n que.push(s);\n while(!que.empty()){\n int v=que.front();\n que.pop();\n for(auto &e:G[v]) if (e.cap>e.flow&&dist[e.to]==-1){\n que.push(e.to);\n dist[e.to]=dist[v]+1;\n }\n }\n return dist[t];\n };\n function<ll(int,ll)> DFS = [&](int u,ll cur){\n if (u==t) return cur;\n for(int &i=iter[u];i<G[u].size();i++){\n edge &e=G[u][i], &re=G[e.to][e.rev];\n if (e.cap>e.flow && dist[u]<dist[e.to]){\n ll f=DFS(e.to,min(cur,e.cap-e.flow));\n if (f>0){\n e.flow+=f;\n re.flow-=f;\n return f;\n }\n }\n }\n return 0LL;\n };\n\n REP(u,n) for(auto &e:G[u]) e.flow=0;\n ll flow=0;\n while(BFS()>=0){\n iter.assign(n,0);\n while(true){\n ll res=DFS(s,1e18);\n if (res<=0) break;\n flow+=res;\n }\n }\n return flow;\n }\n};\n\nint p(int a,int b){\n return __gcd(a,b);\n}\nvoid solve(){\n int M,N;\n cin >> M >> N;\n if (N==0&&M==0) exit(0);\n vector<int> A(M),B(N);\n REP(i,M) cin >> A[i];\n REP(i,N) cin >> B[i];\n MaximumFlow MF(N+M+2);\n\n REP(i,M) REP(j,N) {\n int res=p(A[i],B[j]);\n if (res>1) MF.add_edge(i,M+j,1);\n }\n\n REP(i,M) MF.add_edge(N+M,i,1);\n REP(j,N) MF.add_edge(M+j,N+M+1,1);\n\n ll mx=MF.max_flow(N+M,N+M+1);\n cout << mx << endl;\n\n}\nint main(){\n while(true) solve();\n}", "accuracy": 1, "time_ms": 650, "memory_kb": 13908, "score_of_the_acc": -0.8088, "final_rank": 15 }, { "submission_id": "aoj_1163_10332268", "code_snippet": "#ifndef ONLINE_JUDGE\n#define _GLIBCXX_DEBUG 1 //[]で配列外参照をするとエラーにしてくれる。上下のやつがないとTLEになるので注意 ABC311Eのサンプル4みたいなデバック中のTLEは防げないので注意\n#endif\n#include <bits/stdc++.h>\n\nnamespace atcoder {\n\nnamespace internal {\n\ntemplate <class T> struct simple_queue {\n std::vector<T> payload;\n int pos = 0;\n void reserve(int n) { payload.reserve(n); }\n int size() const { return int(payload.size()) - pos; }\n bool empty() const { return pos == int(payload.size()); }\n void push(const T& t) { payload.push_back(t); }\n T& front() { return payload[pos]; }\n void clear() {\n payload.clear();\n pos = 0;\n }\n void pop() { pos++; }\n};\n\n} // namespace internal\n\n} // namespace atcoder\nnamespace atcoder {\n\ntemplate <class Cap> struct mf_graph {\n public:\n mf_graph() : _n(0) {}\n explicit mf_graph(int n) : _n(n), g(n) {}\n\n int add_edge(int from, int to, Cap cap) {\n assert(0 <= from && from < _n);\n assert(0 <= to && to < _n);\n assert(0 <= cap);\n int m = int(pos.size());\n pos.push_back({from, int(g[from].size())});\n int from_id = int(g[from].size());\n int to_id = int(g[to].size());\n if (from == to) to_id++;\n g[from].push_back(_edge{to, to_id, cap});\n g[to].push_back(_edge{from, from_id, 0});\n return m;\n }\n\n struct edge {\n int from, to;\n Cap cap, flow;\n };\n\n edge get_edge(int i) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n auto _e = g[pos[i].first][pos[i].second];\n auto _re = g[_e.to][_e.rev];\n return edge{pos[i].first, _e.to, _e.cap + _re.cap, _re.cap};\n }\n std::vector<edge> edges() {\n int m = int(pos.size());\n std::vector<edge> result;\n for (int i = 0; i < m; i++) {\n result.push_back(get_edge(i));\n }\n return result;\n }\n void change_edge(int i, Cap new_cap, Cap new_flow) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n assert(0 <= new_flow && new_flow <= new_cap);\n auto& _e = g[pos[i].first][pos[i].second];\n auto& _re = g[_e.to][_e.rev];\n _e.cap = new_cap - new_flow;\n _re.cap = new_flow;\n }\n\n Cap flow(int s, int t) {\n return flow(s, t, std::numeric_limits<Cap>::max());\n }\n Cap flow(int s, int t, Cap flow_limit) {\n assert(0 <= s && s < _n);\n assert(0 <= t && t < _n);\n assert(s != t);\n\n std::vector<int> level(_n), iter(_n);\n internal::simple_queue<int> que;\n\n auto bfs = [&]() {\n std::fill(level.begin(), level.end(), -1);\n level[s] = 0;\n que.clear();\n que.push(s);\n while (!que.empty()) {\n int v = que.front();\n que.pop();\n for (auto e : g[v]) {\n if (e.cap == 0 || level[e.to] >= 0) continue;\n level[e.to] = level[v] + 1;\n if (e.to == t) return;\n que.push(e.to);\n }\n }\n };\n auto dfs = [&](auto self, int v, Cap up) {\n if (v == s) return up;\n Cap res = 0;\n int level_v = level[v];\n for (int& i = iter[v]; i < int(g[v].size()); i++) {\n _edge& e = g[v][i];\n if (level_v <= level[e.to] || g[e.to][e.rev].cap == 0) continue;\n Cap d =\n self(self, e.to, std::min(up - res, g[e.to][e.rev].cap));\n if (d <= 0) continue;\n g[v][i].cap += d;\n g[e.to][e.rev].cap -= d;\n res += d;\n if (res == up) return res;\n }\n level[v] = _n;\n return res;\n };\n\n Cap flow = 0;\n while (flow < flow_limit) {\n bfs();\n if (level[t] == -1) break;\n std::fill(iter.begin(), iter.end(), 0);\n Cap f = dfs(dfs, t, flow_limit - flow);\n if (!f) break;\n flow += f;\n }\n return flow;\n }\n\n std::vector<bool> min_cut(int s) {\n std::vector<bool> visited(_n);\n internal::simple_queue<int> que;\n que.push(s);\n while (!que.empty()) {\n int p = que.front();\n que.pop();\n visited[p] = true;\n for (auto e : g[p]) {\n if (e.cap && !visited[e.to]) {\n visited[e.to] = true;\n que.push(e.to);\n }\n }\n }\n return visited;\n }\n\n private:\n int _n;\n struct _edge {\n int to, rev;\n Cap cap;\n };\n std::vector<std::pair<int, int>> pos;\n std::vector<std::vector<_edge>> g;\n};\n\n} // namespace atcoder\n\nusing namespace atcoder;\n\nusing namespace std;\nusing ll = long long;\nll INF = 2e18;\nusing P = pair<ll, ll>;\n#define pb push_back\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define reprev(i, n) for (ll i = (n) - 1; i >= 0; i--)\n#define reps(i, n) for (ll i = 1; i <= (n); i++)\n#define for_(i, a, b) for (ll i = (a); i < (b); i++)\n#define all(v) v.begin(), v.end()\ntemplate <typename T>\ninline bool chmin(T &a, const T &b)\n{\n bool c = a > b;\n if (c)\n a = b;\n return c;\n}\ntemplate <typename T>\ninline bool chmax(T &a, const T &b)\n{\n bool c = a < b;\n if (c)\n a = b;\n return c;\n}\ntemplate <typename T>\ninline T ceil(T a, T b) { return (a + (b - 1)) / b; }\n// using mint = modint998244353;\n// using mint = modint1000000007;\n// using mint = static_modint<10>;//使うときはコメントアウトを外す\ntemplate <typename T>\nusing vc = vector<T>;\ntemplate <class T>\nistream &operator>>(istream &i, vc<T> &v)\n{\n rep(j, size(v)) i >> v[j];\n return i;\n}\ntemplate <class T>\nostream &operator<<(ostream &o, const vc<T> &v)\n{\n rep(j, size(v))\n {\n if (j)\n o << \" \";\n o << v[j];\n }\n o << endl;\n return o;\n}\nint main()\n{\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n // ref:https://rsk0315.hatenablog.com/entry/2020/05/09/170315\n while (true)\n {\n ll M, N;\n cin >> M >> N;\n if (N == 0 && M == 0)\n break;\n vc<ll> a(M), b(N);\n cin >> a >> b;\n ll s = M + N;\n ll t = M + N + 1;\n mf_graph<ll> g(M + N + 2);\n rep(i, M)\n {\n g.add_edge(s, i, 1);\n }\n rep(i, N)\n {\n g.add_edge(M + i, t, 1);\n }\n rep(i, M)\n {\n rep(j, N)\n {\n if (gcd(a[i], b[j]) > 1)\n {\n g.add_edge(i, M + j, 1);\n }\n }\n }\n cout << g.flow(s, t) << endl;\n }\n // cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 980, "memory_kb": 9928, "score_of_the_acc": -0.5962, "final_rank": 12 }, { "submission_id": "aoj_1163_9988471", "code_snippet": "#line 1 \"/home/dispersion/competitive/icpc/ICPC-library/ICPC2024/merge_src_docs/template/24_template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n#define rep(i, n) for(ll i = 0; i < n; i++)\n#define rep2(i, l, r) for(ll i = l; i < r; i++)\n\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vll = vector<ll>;\n\n#define all(A) A.begin(), A.end()\n#define elif else if\nusing pii = pair<ll, ll>;\n\nbool chmin(auto &a, auto b) { return a > b ? a = b, 1 : 0; }\nbool chmax(auto &a, auto b) { return a < b ? a = b, 1 : 0; }\n\nstruct IOSetup {\n IOSetup() {\n cin.tie(0);\n ios::sync_with_stdio(0);\n }\n} iosetup;\n\ntemplate<class T>\nvoid print(vector<T> a) {\n for(auto x : a) cout << x << ' ';\n cout << endl;\n}\n\nvoid print(auto x) { cout << x << endl; }\n\ntemplate<class Head, class... Tail>\nvoid print(Head &&head, Tail &&...tail) {\n cout << head << ' ';\n print(forward<Tail>(tail)...);\n}\n#line 1 \"/home/dispersion/competitive/icpc/ICPC-library/ICPC2024/merge_src_docs/graph/Hungarian.hpp\"\n/*\nN x N$ 行列 A に対して sum A[i][P[i]] (1 <= i <= N) を最小化する順列 P を返す\n最大化したい場合は各要素を -1 倍する\n*/\n\nvi hungarian(vector<vll> a) {\n ll inf = 1LL << 60;\n int n = (int)a.size();\n vi p(n);\n rep(i, n) p[i] = i;\n vll h = {0};\n\n rep2(i, 1, n) {\n h.push_back(0);\n vll d(i + 1, inf);\n vi pre(i + 1, -1), used(i + 1, 0);\n d[i] = 0;\n pre[i] = i;\n\n rep(_, i + 1) {\n ll min_d = inf;\n int v = -1;\n for(int j = 0; j <= i; j++) {\n if(used[j] == 0 && min_d > d[j] - h[j]) {\n min_d = d[j] - h[j];\n v = j;\n }\n }\n used[v] = 1;\n rep(j, i + 1) {\n if(used[j] == 0 || j == i) {\n ll nd = d[v] - a[v][p[v]] + a[j][p[v]];\n if(d[j] > nd) {\n d[j] = nd;\n pre[j] = v;\n }\n }\n }\n }\n\n int cur = i;\n while(pre[cur] != i) {\n swap(p[cur], p[pre[cur]]);\n cur = pre[cur];\n }\n h = d;\n }\n return p;\n}\n#line 3 \"Hungarian.cpp\"\n\n#line 1 \"/home/dispersion/competitive/icpc/ICPC-library/ICPC2024/merge_src_docs/math/binary_gcd.hpp\"\nll binary_gcd(ll x_, ll y_) {\n unsigned long long x = (x_ < 0 ? -x_ : x_), y = (y_ < 0 ? -y_ : y_);\n if (!x or !y) return x + y; // x == 0 or y == 0\n int n = countr_zero(x), m = countr_zero(y);\n x >>= n, y >>= m;\n while (x != y) {\n if (x > y) {\n x = (x - y) >> countr_zero(x - y);\n } else {\n y = (y - x) >> countr_zero(y - x);\n }\n }\n return x << (n > m ? m : n);\n}\n#line 5 \"Hungarian.cpp\"\n\n// https://onlinejudge.u-aizu.ac.jp/services/ice/?problemId=1163\nvoid solve1() {\n while(1) {\n ll N, M; cin >> N >> M;\n if(N + M == 0) break;\n \n vector<ll> B(N), R(M);\n for(auto &b : B) cin >> b;\n for(auto &r : R) cin >> r;\n \n ll C = max(N, M);\n vector mat(C, vector<ll>(C, 0));\n rep(i, N) {\n rep(j, M) {\n ll b = B[i], r = R[j];\n if(binary_gcd(b, r) > 1) mat[i][j] = -1;\n }\n }\n \n vector<int> P = hungarian(mat);\n ll res = 0;\n rep(i, N) res += mat[i][P[i]];\n res *= (-1);\n cout << res << '\\n';\n }\n \n return;\n}\n\nint main() {\n solve1();\n \n return 0;\n}", "accuracy": 1, "time_ms": 1990, "memory_kb": 7680, "score_of_the_acc": -0.6883, "final_rank": 13 }, { "submission_id": "aoj_1163_9817338", "code_snippet": "#include <bits/stdc++.h>\n#include \"atcoder/all\"\nusing namespace std;\n#define rep(i, n) for (long long i = 0; i < (long long)(n); i++)\n#define FOR(i, s, e) for (long long i = (long long)(s); i <= (long long)(e); i++)\n#define printYesNo(is_ok) puts(is_ok ? \"Yes\" : \"No\");\n#define SORT(v) sort(v.begin(), v.end());\n#define RSORT(v) sort(v.rbegin(), v.rend());\n#define REVERSE(v) reverse(v.begin(), v.end());\n\ntemplate <typename T>\nvoid printlnVector(T v)\n{\n rep(i, v.size())\n {\n cout << v[i] << endl;\n }\n}\n\ntemplate <typename T>\nvoid printVector(T v)\n{\n for (long unsigned int i = 0; i < v.size(); i++)\n {\n cout << v[i];\n if (i != v.size() - 1)\n cout << \" \";\n }\n cout << endl;\n}\n\nvoid solve(int m, int n, vector<int> b, vector<int> r)\n{\n atcoder::mf_graph<int> graph(m + n + 2);\n rep(b_i, m) rep(r_i, n)\n {\n int gcd_n = gcd(b[b_i], r[r_i]);\n if (gcd_n == 1)\n {\n continue;\n }\n\n graph.add_edge(b_i, m + r_i, 1);\n }\n\n rep(b_i, m)\n {\n graph.add_edge(m + n, b_i, 1);\n }\n\n rep(r_i, n)\n {\n graph.add_edge(m + r_i, m + n + 1, 1);\n }\n\n int ans = graph.flow(m + n, m + n + 1);\n cout << ans << endl;\n}\n\nint main()\n{\n\n while (true)\n {\n int m, n;\n cin >> m >> n;\n if (m == 0 && n == 0)\n {\n break;\n }\n\n vector<int> b(m), r(n);\n rep(i, m)\n {\n cin >> b[i];\n }\n rep(i, n)\n {\n cin >> r[i];\n }\n solve(m, n, b, r);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 8732, "score_of_the_acc": -0.3624, "final_rank": 5 }, { "submission_id": "aoj_1163_9717225", "code_snippet": "#include <bits/stdc++.h>\n using namespace std;\n \n template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\n template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n #define rep(i,n) for (int i = 0; i < (n); ++i)\n\n typedef long long ll;\n typedef unsigned long long ull;\n using P=pair<ll,ll>;\n using T=tuple<int,int,int>;\n const int INF=1001001001;\n const ll INFL=1e18;\n const int mod=998244353;\n\n\tstruct edge{\n\t\tint to,cap,rev;\n\t};\n\t\n\tconst int MAX_V=200005;\n\tvector<edge>G[MAX_V];\n\tbool used[MAX_V];\n\t\n\tvoid add_edge(int from,int to,int cap){\n\t\tG[from].push_back((edge){to,cap,(int)G[to].size()});\n\t\tG[to].push_back((edge){from,0,(int)G[from].size()-1});\n\t}\n\n\tint dfs(int v,int t,int f){\n\t\tif(v==t){return f;}\n\t\tused[v]=true;\n\t\tfor(int i=0;i<G[v].size();i++){\n\t\t\tedge &e=G[v][i];\n\t\t\tif(!used[e.to]&&e.cap>0){\n\t\t\t\tint d=dfs(e.to,t,min(f,e.cap));\n\t\t\t\tif(d>0){\n\t\t\t\t\te.cap-=d;\n\t\t\t\t\tG[e.to][e.rev].cap+=d;\n\t\t\t\t\treturn d;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn 0;\n\t}\n\n\tint max_flow(int s,int t){\n\t\tint flow=0;\n\t\twhile(1){\n\t\t\tmemset(used,0,sizeof(used));\n\t\t\tint f=dfs(s,t,INF);\n\t\t\tif(f==0){return flow;}\n\t\t\tflow+=f;\n\t\t}\n\t}\n\n bool solve(){\n\t\tint m,n;\n\t\tcin>>m>>n;\n\t\tif(!n)return false;\n\t\trep(i,n+m+5){\n\t\t\tG[i]=vector<edge>();\n\t\t\tused[i]=0;\n\t\t}\n\n\t\tvector<int>b(m),r(n);\n\t\trep(i,m)cin>>b[i];\n\t\trep(i,n)cin>>r[i];\n\n\t\tint s=n+m,t=n+m+1;\n\t\trep(i,m){\n\t\t\tadd_edge(s,i,1);\n\t\t\trep(j,n){\n\t\t\t\tif(__gcd(b[i],r[j])>1){\n\t\t\t\t\tadd_edge(i,j+m,1);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\trep(i,n){\n\t\t\tadd_edge(i+m,t,1);\n\t\t}\n\n\t\tint ans=max_flow(s,t);\n\t\tcout<<ans<<endl;\n\t\treturn true;\n }\n\n int main(){\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n\t\twhile(1){\n\t\t\tif(!solve())break;\n\t\t}\n\t\t\n return 0;\n }", "accuracy": 1, "time_ms": 660, "memory_kb": 12688, "score_of_the_acc": -0.7201, "final_rank": 14 }, { "submission_id": "aoj_1163_9479499", "code_snippet": "#include <bits/stdc++.h>\n#include <algorithm>\n#include <iostream>\n#include <iomanip>\n#include <math.h>\n#include <random>\n#include <chrono>\n#include <cstdint>\n\n\nusing namespace std;\nusing vi = vector<int>;\nusing vvi = vector<vector<int>>;\nusing vl = vector<long long>;\nusing vvl = vector<vector<long long>>;\nusing ll = long long;\ntemplate <class T> using max_heap = priority_queue<T>;\ntemplate <class T> using min_heap = priority_queue<T, vector<T>, greater<>>;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep2(i, f, n) for (int i = (int) f; i < (int)(n); i++)\n#define repd(i, n, l) for (int i = (int) n; i >= (int) l; i--)\n#define all(p) p.begin(),p.end()\nvector<pair<int, int>> dydx{{-1, 0}, {1, 0}, {0, -1 }, {0, 1}};\nconst ll inf = 1LL << 60;\nvoid print(){ putchar(' '); }\nvoid print(bool a){ printf(\"%d\", a); }\nvoid print(int a){ printf(\"%d\", a); }\nvoid print(unsigned a){ printf(\"%u\", a); }\nvoid print(long a){ printf(\"%ld\", a); }\nvoid print(long long a){ printf(\"%lld\", a); }\nvoid print(unsigned long long a){ printf(\"%llu\", a); }\nvoid print(char a){ printf(\"%c\", a); }\nvoid print(char a[]){ printf(\"%s\", a); }\nvoid print(const char a[]){ printf(\"%s\", a); }\nvoid print(float a){ printf(\"%.15f\", a); }\nvoid print(double a){ printf(\"%.15f\", a); }\nvoid print(long double a){ printf(\"%.15Lf\", a); }\nvoid print(const string& a){ for(auto&& i : a) print(i); }\ntemplate<class T> void print(const complex<T>& a){ if(a.real() >= 0) print('+'); print(a.real()); if(a.imag() >= 0) print('+'); print(a.imag()); print('i'); }\ntemplate<class T> void print(const vector<T>&);\ntemplate<class T, size_t size> void print(const array<T, size>&);\ntemplate<class T, class L> void print(const pair<T, L>& p);\ntemplate<class T, size_t size> void print(const T (&)[size]);\ntemplate<class T> void print(const vector<T>& a){ if(a.empty()) return; print(a[0]); for(auto i = a.begin(); ++i != a.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T> void print(const deque<T>& a){ if(a.empty()) return; print(a[0]); for(auto i = a.begin(); ++i != a.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T, size_t size> void print(const array<T, size>& a){ print(a[0]); for(auto i = a.begin(); ++i != a.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T, class L> void print(const pair<T, L>& p){ print(p.first); putchar(' '); print(p.second); }\ntemplate<class T, size_t size> void print(const T (&a)[size]){ print(a[0]); for(auto i = a; ++i != end(a); ){ putchar(' '); print(*i); } }\ntemplate<class T> void print(const T& a){ cout << a; }\n\n// https://ei1333.github.io/luzhiled/snippets/math/matrix.html\n#include <vector>\n#include <queue>\n\ntemplate< class T >\nstruct Matrix {\n vector< vector< T > > A;\n\n Matrix() {}\n\n Matrix(size_t n, size_t m) : A(n, vector< T >(m, 0)) {}\n\n Matrix(size_t n) : A(n, vector< T >(n, 0)) {};\n\n size_t height() const {\n return (A.size());\n }\n\n size_t width() const {\n return (A[0].size());\n }\n\n inline const vector< T > &operator[](int k) const {\n return (A.at(k));\n }\n\n inline vector< T > &operator[](int k) {\n return (A.at(k));\n }\n\n static Matrix I(size_t n) {\n Matrix mat(n);\n for(int i = 0; i < n; i++) mat[i][i] = 1;\n return (mat);\n }\n\n Matrix &operator+=(const Matrix &B) {\n size_t n = height(), m = width();\n assert(n == B.height() && m == B.width());\n for(int i = 0; i < n; i++)\n for(int j = 0; j < m; j++)\n (*this)[i][j] += B[i][j];\n return (*this);\n }\n\n Matrix &operator-=(const Matrix &B) {\n size_t n = height(), m = width();\n assert(n == B.height() && m == B.width());\n for(int i = 0; i < n; i++)\n for(int j = 0; j < m; j++)\n (*this)[i][j] -= B[i][j];\n return (*this);\n }\n\n Matrix &operator*=(const Matrix &B) {\n size_t n = height(), m = B.width(), p = width();\n assert(p == B.height());\n vector< vector< T > > C(n, vector< T >(m, 0));\n for(int i = 0; i < n; i++)\n for(int j = 0; j < m; j++)\n for(int k = 0; k < p; k++)\n C[i][j] = (C[i][j] + (*this)[i][k] * B[k][j]);\n A.swap(C);\n return (*this);\n }\n\n Matrix &operator^=(long long k) {\n Matrix B = Matrix::I(height());\n while(k > 0) {\n if(k & 1) B *= *this;\n *this *= *this;\n k >>= 1LL;\n }\n A.swap(B.A);\n return (*this);\n }\n\n Matrix operator+(const Matrix &B) const {\n return (Matrix(*this) += B);\n }\n\n Matrix operator-(const Matrix &B) const {\n return (Matrix(*this) -= B);\n }\n\n Matrix operator*(const Matrix &B) const {\n return (Matrix(*this) *= B);\n }\n\n Matrix operator^(const long long k) const {\n return (Matrix(*this) ^= k);\n }\n\n friend ostream &operator<<(ostream &os, Matrix &p) {\n size_t n = p.height(), m = p.width();\n for(int i = 0; i < n; i++) {\n os << \"[\";\n for(int j = 0; j < m; j++) {\n os << p[i][j] << (j + 1 == m ? \"]\\n\" : \",\");\n }\n }\n return (os);\n }\n\n\n T determinant() {\n Matrix B(*this);\n assert(width() == height());\n T ret = 1;\n for(int i = 0; i < width(); i++) {\n int idx = -1;\n for(int j = i; j < width(); j++) {\n if(B[j][i] != 0) idx = j;\n }\n if(idx == -1) return (0);\n if(i != idx) {\n ret *= -1;\n swap(B[i], B[idx]);\n }\n ret *= B[i][i];\n T vv = B[i][i];\n for(int j = 0; j < width(); j++) {\n B[i][j] /= vv;\n }\n for(int j = i + 1; j < width(); j++) {\n T a = B[j][i];\n for(int k = 0; k < width(); k++) {\n B[j][k] -= B[i][k] * a;\n }\n }\n }\n return (ret);\n }\n};\n\ntemplate<typename T>\nT Hungarian(Matrix<T> &C){\n const T infty = numeric_limits<T>::max();\n const int N = C.height();\n const int M = C.width();\n vector<int> P(M), way(M);\n vector<T> F(N, 0), G(M, 0), minV;\n vector<bool> used;\n for (int i = 1 ; i < N; i++){\n used.assign(M, false);\n minV.assign(M, infty);\n P[0] = i;\n int j0 = 0;\n while (P[j0] != 0){\n int i0 = P[j0];\n int j1 = 0;\n used[j0] = true;\n T delta = infty;\n for (int j = 1; j < M; j++){\n if (used[j]) continue;\n T curr = C[i0][j] - F[i0] - G[j];\n if (curr < minV[j]) minV[j] = curr, way[j] = j0;\n if (minV[j] < delta) delta = minV[j], j1 = j;\n }\n for (int j = 0; j < M; j++){\n if (used[j]) F[P[j]] += delta, G[j] -= delta;\n else minV[j] -= delta;\n }\n j0 = j1;\n }\n do {\n P[j0] = P[way[j0]];\n j0 = way[j0];\n } while (j0 != 0);\n }\n // print(G);cout << endl;\n return -G[0];\n}\n\nvector<vector<int>> unweighted_graph(int n, int m){\n vector<vector<int>> ret(n);\n while (m--){\n int a, b;\n cin >> a >> b;\n a--; b--;\n ret[a].push_back(b);\n ret[b].push_back(a);\n }\n return ret;\n}\nvector<vector<pair<int, long long>>> weighted_graph(int n, int m){\n vector<vector<pair<int, long long>>> ret(n);\n while (m--){\n int a, b;\n long long c;\n cin >> a >> b >> c;\n a--, b--;\n ret[a].push_back({b, c});\n ret[b].push_back({a, c});\n }\n return ret;\n}\n\ntemplate<typename T>\nint argmin(vector<T> &a){\n T mi = *min_element(all(a));\n for (int i = 0; i < a.size(); i++){\n if (a[i] == mi) return i;\n }\n}\n\ntemplate<typename T>\nint argmax(vector<T> &a){\n T ma = *max_element(all(a));\n for (int i = 0; i < a.size(); i++){\n if (a[i] == ma) return i;\n }\n}\n\nint main(){\n int B[500], R[500];\n while (1){\n int m, n;\n cin >> m >> n;\n if (!n && !m) break;\n rep(i, m) cin >> B[i];\n rep(i, n) cin >> R[i];\n if (m > n) swap(n, m), swap(B, R);\n Matrix<int> mat(m+1, n+1);\n rep(i, m+1) rep(j, n+1) mat[i][j] = 0;\n rep(i, m) rep(j, n) if (__gcd(B[i], R[j]) > 1) mat[i+1][j+1] = -1;\n // rep(i, m+1) rep(j, n+1) cout << mat[i][j] << ' ';\n cout << -Hungarian(mat) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 4300, "memory_kb": 4128, "score_of_the_acc": -1.018, "final_rank": 18 }, { "submission_id": "aoj_1163_9461465", "code_snippet": "#include<iostream>\n#include<string>\n#include<queue>\n#include<vector>\n#include<cassert>\n#include<random>\n#include<set>\n#include<map>\n#include<cassert>\n#include<unordered_map>\n#include<bitset>\n#include<algorithm>\n#include<numeric>\nusing namespace std;\nusing ll = long long;\nconst int inf=1<<30;\nconst ll INF=1LL<<62;\nusing P=pair<int,int>;\nusing PP=pair<P,int>; \n\n\nll gcd(ll x,ll y){\n return y==0?x:gcd(y,x%y);\n}\n\n\ntemplate<class T,T INF=(1<<30) > class FLOW{\n //intになるかlong long になるか\n public:\n struct edge{int from; int to; T cap; T flow; int rev;}; \n std::vector<T> level;\n std::vector<T> iter;\n std::vector<std::vector<edge>> G;\n std::set<std::pair<int,int>> st;\n int numV=0;\n\n //constructor\n FLOW(int V){\n numV=V;\n G = std::vector<std::vector<edge>>(V+1,std::vector<edge>{});\n //G[0],G[1],...,G[V]を作る\n \n level = std::vector<T>(V+1,0);\n iter = std::vector<T>(V+1,0);\n }\n\n std::vector<P> edgeIdx;\n\n void add_edge(int from,int to,T cap){\n // from to cap flow rev\n edgeIdx.emplace_back(std::make_pair(from,(int)G[from].size()));\n G[from].push_back((edge){from,to,cap,0,(int)G[to].size()} );\n st.insert(make_pair(from,to));//順辺のみに興味がある\n\n\n G[to].push_back((edge){to,from,0,cap,(int)G[from].size()-1});\n }\n\n edge get_edge(int idx){\n //idx番目の辺の情報を返す\n //idxは追加された辺のインデックス\n auto [from,i]=edgeIdx[idx];\n return G[from][i];\n }\n \n \n void bfs(int s){\n level = std::vector<T>(numV+1,-1);//-1に初期化\n\n std::queue<int> que;\n level[s]=0;\n que.push(s);\n while(!que.empty()){\n \n int p = que.front();que.pop();\n for(int i=0;i<(int)G[p].size();i++){\n edge e = G[p][i];//頂点pに繋がっている頂点が e.to\n if(e.cap>0 && level[e.to]<0){\n level[e.to] = level[p]+1;\n que.push(e.to);\n }\n }\n }\n }\n \n T dfs(int v,int t,T f){\n if(v==t) return f;\n for(T &i=iter[v]; i<(int)G[v].size(); i++){\n edge &e = G[v][i];\n if(e.cap>0 && level[v]<level[e.to]){\n T d = dfs(e.to, t, min(f,e.cap));\n if(d>0){\n e.cap -= d;\n e.flow += d;//capが減った分,今,流す量が増えた\n\n\n G[e.to][e.rev].cap += d;\n G[e.to][e.rev].flow -= d;//逆辺を考えた分,今流している量が減った.\n return d;\n }\n }\n }\n \n return 0;\n }\n \n \n T max_flow(int s, int t){\n T flow=0;\n while(1){\n bfs(s);\n if(level[t]<0) return flow;\n iter = vector<T>(numV+1,0);//0に初期化\n\n T f;\n while((f=dfs(s,t,INF))>0 ){\n flow += f;\n }\n }\n }\n\n //auto edges = (FLOW instance).edges();で受けるしかないかな\n std::vector<edge> edges(){\n std::vector<edge> ret;\n for(int from=0;from<=numV;from++){\n for(const edge &e:G[from]){\n if( st.find({from,e.to})!=st.end() ){\n ret.push_back(e);\n }\n }\n }\n return ret;\n }\n\n};\n\nint main(){\n\n\n vector<int> output;\n while(1){\n int m,n;\n cin>>m>>n;\n if(m==0 && n==0)break;\n vector<ll> b(m),r(n);\n for(int i=0;i<m;i++){\n cin>>b[i];\n }\n for(int i=0;i<n;i++){\n cin>>r[i];\n }\n\n FLOW<int> fl(m+n+2);\n int source=m+n;\n int sink=m+n+1;\n for(int i=0;i<m;i++){\n fl.add_edge(source,i,1);\n }\n for(int i=0;i<n;i++){\n fl.add_edge(i+m,sink,1);\n }\n\n for(int i=0;i<m;i++){\n for(int j=0;j<n;j++){\n if(gcd(b[i],r[j])>1){\n fl.add_edge(i,j+m,1);\n }\n }\n }\n\n \n int ans=fl.max_flow(source,sink);\n output.push_back(ans);\n }\n for(int v:output){\n cout<<v<<endl;\n }\n}", "accuracy": 1, "time_ms": 1130, "memory_kb": 16784, "score_of_the_acc": -1.1477, "final_rank": 20 }, { "submission_id": "aoj_1163_9450757", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nnamespace Random {\nmt19937_64 randgen(chrono::steady_clock::now().time_since_epoch().count());\nusing u64 = unsigned long long;\nu64 get() {\n return randgen();\n}\ntemplate <typename T> T get(T L) { // [0,L]\n\n return get() % (L + 1);\n}\ntemplate <typename T> T get(T L, T R) { // [L,R]\n\n return get(R - L) + L;\n}\ndouble uniform() {\n return double(get(1000000000)) / 1000000000;\n}\nstring str(int n) {\n string ret;\n rep(i, 0, n) ret += get('a', 'z');\n return ret;\n}\ntemplate <typename Iter> void shuffle(Iter first, Iter last) {\n if (first == last)\n return;\n int len = 1;\n for (auto it = first + 1; it != last; it++) {\n len++;\n int j = get(0, len - 1);\n if (j != len - 1)\n iter_swap(it, first + j);\n }\n}\ntemplate <typename T> vector<T> select(int n, T L, T R) { // [L,R]\n\n if (n * 2 >= R - L + 1) {\n vector<T> ret(R - L + 1);\n iota(ALL(ret), L);\n shuffle(ALL(ret));\n ret.resize(n);\n return ret;\n } else {\n unordered_set<T> used;\n vector<T> ret;\n while (SZ(used) < n) {\n T x = get(L, R);\n if (!used.count(x)) {\n used.insert(x);\n ret.push_back(x);\n }\n }\n return ret;\n }\n}\n\nvoid relabel(int n, vector<pair<int, int>> &es) {\n shuffle(ALL(es));\n vector<int> ord(n);\n iota(ALL(ord), 0);\n shuffle(ALL(ord));\n for (auto &[u, v] : es)\n u = ord[u], v = ord[v];\n}\ntemplate <bool directed, bool simple> vector<pair<int, int>> genGraph(int n) {\n vector<pair<int, int>> cand, es;\n rep(u, 0, n) rep(v, 0, n) {\n if (simple and u == v)\n continue;\n if (!directed and u > v)\n continue;\n cand.push_back({u, v});\n }\n int m = get(SZ(cand));\n vector<int> ord;\n if (simple)\n ord = select(m, 0, SZ(cand) - 1);\n else {\n rep(_, 0, m) ord.push_back(get(SZ(cand) - 1));\n }\n for (auto &i : ord)\n es.push_back(cand[i]);\n relabel(n, es);\n return es;\n}\nvector<pair<int, int>> genTree(int n) {\n vector<pair<int, int>> es;\n rep(i, 1, n) es.push_back({get(i - 1), i});\n relabel(n, es);\n return es;\n}\n}; // namespace Random\n\n\n/**\n * @brief Random\n */\n\nvector<int> BiMatching(int n, int m, vector<vector<int>> &g) {\n rep(v, 0, n) Random::shuffle(ALL(g[v]));\n vector<int> L(n, -1), R(m, -1);\n for (;;) {\n vector<int> par(n, -1), root(n, -1);\n queue<int> que;\n rep(i, 0, n) if (L[i] == -1) {\n que.push(i);\n root[i] = i;\n }\n bool upd = 0;\n while (!que.empty()) {\n int v = que.front();\n que.pop();\n if (L[root[v]] != -1)\n continue;\n for (auto u : g[v]) {\n if (R[u] == -1) {\n while (u != -1) {\n R[u] = v;\n swap(L[v], u);\n v = par[v];\n }\n upd = 1;\n break;\n }\n int to = R[u];\n if (par[to] == -1) {\n root[to] = root[v];\n par[to] = v;\n que.push(to);\n }\n }\n }\n if (!upd)\n break;\n }\n return L;\n}\n\n/**\n * @brief Bipartite Matching\n */\n\nint main() {\nwhile(1) {\n int N, M;\n cin >> N >> M;\n if (N == 0 && M == 0) return 0;\n vector<int> A(N), B(M);\n rep(i,0,N) cin >> A[i];\n rep(i,0,M) cin >> B[i];\n vector<vector<int>> G(N);\n rep(i,0,N) {\n rep(j,0,M) {\n if (gcd(A[i],B[j]) >= 2) G[i].push_back(j);\n }\n }\n vector<int> V = BiMatching(N,M,G);\n int ANS = 0;\n rep(i,0,N) if (V[i] != -1) ANS++;\n cout << ANS << endl;\n}\n}", "accuracy": 1, "time_ms": 600, "memory_kb": 3888, "score_of_the_acc": -0.0464, "final_rank": 1 } ]
aoj_1165_cpp
Problem A: Pablo Squarson's Headache Pablo Squarson is a well-known cubism artist. This year's theme for Pablo Squarson is "Squares". Today we are visiting his studio to see how his masterpieces are given birth. At the center of his studio, there is a huuuuuge table and beside it are many, many squares of the same size. Pablo Squarson puts one of the squares on the table. Then he places some other squares on the table in sequence. It seems his methodical nature forces him to place each square side by side to the one that he already placed on, with machine-like precision. Oh! The first piece of artwork is done. Pablo Squarson seems satisfied with it. Look at his happy face. Oh, what's wrong with Pablo? He is tearing his hair! Oh, I see. He wants to find a box that fits the new piece of work but he has trouble figuring out its size. Let's help him! Your mission is to write a program that takes instructions that record how Pablo made a piece of his artwork and computes its width and height. It is known that the size of each square is 1. You may assume that Pablo does not put a square on another. I hear someone murmured "A smaller box will do". No, poor Pablo, shaking his head, is grumbling "My square style does not seem to be understood by illiterates". Input The input consists of a number of datasets. Each dataset represents the way Pablo made a piece of his artwork. The format of a dataset is as follows. N n 1 d 1 n 2 d 2 ... n N -1 d N -1 The first line contains the number of squares (= N ) used to make the piece of artwork. The number is a positive integer and is smaller than 200. The remaining ( N -1) lines in the dataset are square placement instructions. The line “ n i d i ” indicates placement of the square numbered i (≤ N -1). The rules of numbering squares are as follows. The first square is numbered "zero". Subsequently placed squares are numbered 1, 2, ..., ( N -1). Note that the input does not give any placement instruction to the first square, which is numbered zero. A square placement instruction for the square numbered i , namely “ n i d i ”, directs it to be placed next to the one that is numbered n i , towards the direction given by d i , which denotes leftward (= 0), downward (= 1), rightward (= 2), and upward (= 3). For example, pieces of artwork corresponding to the four datasets shown in Sample Input are depicted below. Squares are labeled by their numbers. The end of the input is indicated by a line that contains a single zero. Output For each dataset, output a line that contains the width and the height of the piece of artwork as decimal numbers, separated by a space. Each line should not contain any other characters. Sample Input 1 5 0 0 0 1 0 2 0 3 12 0 0 1 0 2 0 3 1 4 1 5 1 6 2 7 2 8 2 9 3 10 3 10 0 2 1 2 2 2 3 2 2 1 5 1 6 1 7 1 8 1 0 Output for the Sample Input 1 1 3 3 4 4 5 6
[ { "submission_id": "aoj_1165_9262894", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define all(a) a.begin(),a.end()\n#define reps(i, a, n) for (int i = (a); i < (int)(n); i++)\n#define rep(i, n) reps(i, 0, n)\n#define rreps(i, a, n) for (int i = (a); i > (int)(n); i--)\nconst long long mod = 1000000007;\nconst long long INF = 1e18;\n\nint n;\n\nvoid solve() {\n vector<vector<int>> v (500,vector<int> (450,-1));\n v[220][220] = 0;\n int a,b;\n rep(k,n-1) {\n cin >> a >> b;\n rep(i,450) {\n rep(j,450) {\n if (v[i][j] == a) {\n switch (b) {\n case 0 : v[i][j-1] = k+1; break;\n case 1 : v[i+1][j] = k+1; break;\n case 2 : v[i][j+1] = k+1; break;\n case 3 : v[i-1][j] = k+1; break;\n }\n }\n }\n }\n }\n int up = 1e8, left = 1e8, down = 0, right = 0;\n rep(i,450) {\n rep(j,450) {\n if (v[i][j] >= 0) {\n up = min(up,i);\n left = min(left,j);\n down = max(down,i);\n right = max(right,j);\n }\n }\n }\n cout << right-left+1 << ' ' << down-up+1 << endl;\n return;\n}\n\nint main() {\n while (true) {\n cin >> n;\n if (n == 0) {\n return 0;\n }\n solve();\n }\n}", "accuracy": 1, "time_ms": 590, "memory_kb": 4040, "score_of_the_acc": -0.4669, "final_rank": 16 }, { "submission_id": "aoj_1165_9214505", "code_snippet": "#include <iostream>\n#include <string>\n#include <utility>\n#include <limits.h>\n#include <algorithm>\n#include <iomanip>\n#include <math.h>\n#include <queue>\n#include <stack>\n#include <list>\n#include <map>\n#define rep(i,n) for(int i = 0; i < (int)(n); i++)\nusing namespace std;\nusing llint = long long;\nusing vec = vector<llint>;\nusing vvec = vector<vec>;\n\nint main() {\n\tint N;\n\n\twhile (true) {\n\t\t//入力\n\t\tcin >> N;\n\t\tif (N == 0) return 0;\n\t\tN--;\n\t\tvector<vector<int>> List(1000, vector<int>(1000, -1));\n\t\tList[500][500] = 0;\n\t\tvector<pair<int, int>> input(N);\n\t\tfor (int i = 0; i < input.size(); i++) {\n\t\t\tcin >> input[i].first >> input[i].second;\n\t\t}\n\n\t\t//main_code\n\t\tint n = 1;\n\t\tfor (int i = 0; i < input.size(); i++) {\n\t\t\t//x,yを探してくる。\n\t\t\tint index = input[i].first;\n\t\t\tint x;\n\t\t\tint y;\n\t\t\tfor (int j = 0; j < List.size(); j++) {\n\t\t\t\tfor (int k = 0; k < List[j].size(); k++) {\n\t\t\t\t\tif (index == List[j][k]) {\n\t\t\t\t\t\ty = j;\n\t\t\t\t\t\tx = k;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t\t//隣をtrueにする\n\t\t\tint next = input[i].second;\n\t\t\tif (next == 0) {\n\t\t\t\tList[y][x - 1] = n;\n\t\t\t}\n\t\t\telse if (next == 1) {\n\t\t\t\tList[y + 1][x] = n;\n\t\t\t}\n\t\t\telse if (next == 2) {\n\t\t\t\tList[y][x + 1] = n;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tList[y - 1][x] = n;\n\t\t\t}\n\n\t\t\tn++;\n\t\t}\n\n\t\tint hmin = List.size();\n\t\tint hmax = 0;\n\t\tint wmin = List[0].size();\n\t\tint wmax = 0;\n\n\t\tfor (int i = 0; i < List.size(); i++) {\n\t\t\tfor (int j = 0; j < List[i].size(); j++) {\n\t\t\t\tif (List[i][j] != -1) {\n\t\t\t\t\thmin = min(hmin, i);\n\t\t\t\t\thmax = max(hmax, i);\n\t\t\t\t\twmin = min(wmin, j);\n\t\t\t\t\twmax = max(wmax, j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tcout << wmax - wmin + 1 << \" \" << hmax - hmin + 1 << endl;\n\n\t\t//for (int i = 0; i < List.size(); i++) {\n\t\t//\tfor (int j = 0; j < List[i].size(); j++) {\n\t\t//\t\tcout << List[i][j] << \" \";\n\t\t//\t}\n\t\t//\tcout << endl;\n\t\t//}\n\n\t}\n\n}", "accuracy": 1, "time_ms": 2230, "memory_kb": 7332, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_1165_9114480", "code_snippet": "#include <bits/stdc++.h>\n//#include <ranges>\n#define _USE_MATH_DEFINES\n//#include <atcoder/all>\n//using namespace atcoder;\n//using mint = modint998244353;\n//using mint = modint1000000007;\nusing namespace std;\n//using mint = modint;\nusing ll = long long;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rep2(i, s, n) for (ll i = (s); i < (ll)(n); i++)\n#define rrep(i,a,b) for(int i=a;i>=b;i--)\n#define fore(i,a) for(auto &i:a)\n#define V vector<ll>\n#define Vi vector<int>\n#define Vd vector<double>\n#define Vb vector<bool>\n#define Vs vector<string>\n#define Vc vector<char>\n#define VV vector<V>\nusing P = pair<ll,ll>;\nusing G = vector<vector<int>>;\n#define VP vector<P>\ntemplate<typename T> using min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define all(a) (a).begin(),(a).end()\n#define rall(a) (a).rbegin(),(a).rend()\n#define INF 1LL << 60\n#define inf 1e9\ntemplate <typename T>\nbool chmax(T &a, const T& b) {\n if (a < b) {\n a = b; // aをbで更新\n return true;\n }\nreturn false;\n}\ntemplate <typename T>\nbool chmin(T &a, const T& b) {\n if (a > b) {\n a = b; // aをbで更新\n return true;\n }\n return false;\n}\n\nlong long combi(long long n, long long k) {\n if (n == k || k == 0)\n return 1;\n else {\n return combi(n - 1, k - 1) + combi(n - 1, k);\n }\n}\n//整数かどうか\nbool isNumber(const string& str)\n{\n for (const char &c : str) {\n if (std::isdigit(c) == 0) return false;\n }\n return true;\n}\n//\n/*\n//最大公約数\nll gcd(ll a, ll b){\n if(b==0){\n return a;\n }else{\n return gcd(b, a%b);\n }\n}\n//最小公倍数\nll lcm(ll a, ll b){\n ll g=gcd(a,b);\n return a/g*b;\n}\n//\n*/\n//int di[] = {-1,0,1,0};\n//int dj[] = {0,-1,0,1};\n\n//s = regex_replace(s, regex(\"あ\"), \"う\");\n/*stiring で char を検索するときは\n s.find(c)!=string::npos\n */\n\n\n/*//各桁の和\n int wa(int n){\n int sum =0;\n while(n>0){\n sum += n%10;\n n/=10;\n }\n return sum;\n}\n*/\n/*\n//階乗\n int ki(int i){\n int k = 1;\n for(int j = 1; j<=i; j++){\n k *= j;\n }\n return k;\n }\n*/\n/*log_x(b)\ndouble logN(double x, double b) {\n return log(x) / log(b);\n}\n*/\n//\n/*//エラトステネスの篩 main関数内にsolve();を書き込む!!\nconst ll N = 1010101;//求める範囲\nVb isp(N+1,true);\nvoid solve(){\n isp[0] = false;\n isp[1] = false;\n for(ll i = 2; i+i<=N;i++){\n if(isp[i])for(ll j = 2; i*j<=N;j++)isp[i*j] = false;\n }\n}\n//\n*/\n//\n/*\n//約数列挙 O(√n)\nvector<long long> divisor(long long n) {\n vector<long long> ret;\n for (long long i = 1; i * i <= n; i++) {\n if (n % i == 0) {\n ret.push_back(i);\n if (i * i != n) ret.push_back(n / i);\n }\n }\n sort(ret.begin(), ret.end()); // 昇順に並べる\n return ret;\n}\n//\n*/\n//\n/*\n//素因数分解O(√n)\nmap< ll, ll > prime_factor(ll n) {\n map< ll, ll > ret;\n for(ll i = 2; i * i <= n; i++) {\n while(n % i == 0) {\n ret[i]++;\n n /= i;\n }\n }\n if(n != 1) ret[n] = 1;\n return ret;\n}\n//\n*/\n\n/*\nll modpow(ll x, ll n, ll mod){\n while(n){\n ll resu = 1;\n if(n&1)res = (res * x) %mod;\n x = (x*x)%mod;\n n>>=1;\n }\n return res;\n}\n*/\n/*\n//最小二乗法\n//aのb乗をmで割ったあまりを返す関数\n//変数aはa^1→a^2→a^4→a^8→…と変化\nll power(ll a,ll b, ll m){\n ll p = a,ans = 1;\n rep(i,60){\n ll wari = (1LL<<i);\n if((b/wari)%2==1){\n ans=(ans*p)%m;\n }\n p=(p*p)%m;\n }\n return ans;\n}\n*/\n/*\ntemplate <typename T> bool next_combination(const T first, const T last, int k) {\n const T subset = first + k;\n // empty container | k = 0 | k == n \n if (first == last || first == subset || last == subset) {\n return false;\n }\n T src = subset;\n while (first != src) {\n src--;\n if (*src < *(last - 1)) {\n T dest = subset;\n while (*src >= *dest) {\n dest++;\n }\n iter_swap(src, dest);\n rotate(src + 1, dest + 1, last);\n rotate(subset, subset + (last - dest) - 1, last);\n return true;\n }\n }\n // restore\n rotate(first, subset, last);\n return false;\n}\n*/\n\n//vector<int> dx = {1,0,-1,0,1,-1,-1,1};\n//vector<int> dy = {0,1,0,-1,1,1,-1,-1};\n//int dx[4] = { 0, 1, 0, -1 }, dy[4] = { -1, 0, 1, 0 };\n//int dx[8]={0,-1,-1,-1,0,1,1,1},dy[8]={1,1,0,-1,-1,-1,0,1};\n//#define mod 998244353\n//cout << mint.val() << endl;\n//cout << fixed << setprecision(15) << y << endl;\n#define yes \"Yes\"\n#define no \"No\"\n#define Yes \"YES\"\n#define No \"NO\"\n\nint S=409;\nint dx[]={-1,0,1,0};\nint dy[]={0,1,0,-1};\nint main(){\n while(true){\n int N;cin >> N;\n if(N==0)return 0;\n else{\n if(N==1)cout << 1 << \" \"<< 1 << endl;\n else {\n VV g(S,V(S,0));\n VP p(N,{200,200});\n g[200][200]++;\n rep(i,N-1){\n int n,d;\n cin >> n >> d;\n auto [x,y]=p[n];\n x+=dx[d];\n y+=dy[d];\n g[y][x]++;\n p[i+1]={x,y};\n }\n ll sy=INF,sx=INF,ly=-INF,lx=-INF;\n rep(y,S)rep(x,S)if(g[y][x]){\n chmax(ly,y);\n chmax(lx,x);\n chmin(sy,y);\n chmin(sx,x);\n }\n /*rep(i,S){\n rep(j,S)cout << g[i][j] << \" \";\n cout << endl;\n }*/\n cout << (lx-sx+1) << \" \" << (ly-sy+1) << endl;\n }\n }\n }\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4640, "score_of_the_acc": -0.3504, "final_rank": 10 }, { "submission_id": "aoj_1165_8975084", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = 3.141592653589793;\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\ntemplate<typename T> void view(const vv<T>& vv){ for(const auto& v : vv){ view(v); } }\n\nvi dx = {0, 1, 0, -1}, dy = {-1, 0, 1, 0};\n\npair<int, int> solve(int N){\n vc<pair<int, int>> place(N, {250, 250});\n vvi art(500, vi(500, 0));\n art[250][250] = 1;\n rep(i, N - 1){\n int n, d; cin >> n >> d;\n auto [x, y] = place[n];\n int nx = x + dx[d], ny = y + dy[d];\n art[nx][ny] = 1;\n place[i + 1] = {nx, ny};\n }\n int xl = inf, xr = 0, yl = inf, yr = 0;\n for (int i = 0; i < 500; i++) for (int j = 0; j < 500; j++) if (art[i][j]){\n xl = min(xl, i);\n xr = max(xr, i);\n yl = min(yl, j);\n yr = max(yr, j);\n }\n return {yr - yl + 1, xr - xl + 1};\n}\n\nint main(){\n vc<pair<int, int>> ans;\n while (true){\n int N; cin >> N;\n if (N == 0) break;\n ans.push_back(solve(N));\n }\n for (auto x : ans) cout << x.first << \" \" << x.second << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4096, "score_of_the_acc": -0.2191, "final_rank": 7 }, { "submission_id": "aoj_1165_8000438", "code_snippet": "# include <bits/stdc++.h>\n# define all(v) std::begin(v), std::end(v)\n# define rep(i, a, b) for (ll i = a; i < ll(b); i++)\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing pll = pair<ll, ll>;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\n\nconst int inf = 1e9;\n\nint main() {\n while (true) {\n ll N;\n cin >> N;\n if(N == 0) break;\n if(N == 1){\n cout << 1 << endl;\n continue;\n }\n vector<pll> pos(N + 1);\n vvl mas(410, vl(410, -1));\n int offset = 201;\n mas[0 + offset][0 + offset] = 0; \n pos[0] = pll(0, 0);\n rep(i, 0, N - 1){\n ll n, d;\n cin >> n >> d;\n auto [nx, ny] = pos[n];\n if(d == 0) nx--;\n if(d == 1) ny++;\n if(d == 2) nx++;\n if(d == 3) ny--;\n pos[i + 1] = pll(nx, ny);\n mas[nx + offset][ny + offset] = i + 1;\n }\n ll minx = inf, maxx = -inf, miny = inf, maxy = -inf; \n rep(i, 0, 410){\n rep(j, 0, 410){\n if(mas[i][j] != -1){\n minx = min(minx, i);\n miny = min(miny, j);\n maxx = max(maxx, i);\n maxy = max(maxy, j);\n }\n }\n }\n cout << abs(minx - maxx) + 1 << \" \" << abs(miny - maxy) + 1 << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4700, "score_of_the_acc": -0.3649, "final_rank": 13 }, { "submission_id": "aoj_1165_7937198", "code_snippet": "#include <iostream>\nusing namespace std;\n#define INF (1 << 30)\nint dx[] = {-1, 0, 1, 0};\nint dy[] = {0, 1, 0, -1};\nint main() {\n int N, n, d;\n while (cin >> N, N) {\n int f[500][500];\n for (int y = 0; y < 500; y++)\n for (int x = 0; x < 500; x++) {\n f[y][x] = -1;\n }\n f[250][250] = 0;\n for (int i = 1; i < N; i++) {\n cin >> n >> d;\n for (int y = 0; y < 500; y++)\n for (int x = 0; x < 500; x++) {\n if (f[y][x] == n) {\n f[y + dy[d]][x + dx[d]] = i;\n }\n }\n }\n int maxX = -INF, maxY = -INF, minX = INF, minY = INF;\n for (int y = 0; y < 500; y++)\n for (int x = 0; x < 500; x++) {\n if (f[y][x] != -1) {\n maxX = max(maxX, x);\n maxY = max(maxY, y);\n minX = min(minX, x);\n minY = min(minY, y);\n }\n }\n cout << maxX - minX + 1 << \" \" << maxY - minY + 1 << endl;\n }\n}", "accuracy": 1, "time_ms": 460, "memory_kb": 4064, "score_of_the_acc": -0.4141, "final_rank": 14 }, { "submission_id": "aoj_1165_7937189", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define main signed main()\n#define loop(i, a, n) for (int i = (a); i < (n); i++)\n#define rep(i, n) loop(i, 0, n)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\n#define prec(n) fixed << setprecision(n)\n#define stlice(from, to) substr(from, (to) - (from) + 1)\n#define pb push_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\nusing namespace std;\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\ntypedef vector<double> vd;\ntypedef vector<char> vc;\ntypedef vector<bool> vb;\ntypedef vector<string> vs;\ntypedef vector<pii> vpii;\ntypedef vector<vi> vvi;\ntypedef vector<vb> vvb;\ntypedef vector<vpii> vvpii;\nconst int INF =\n sizeof(int) == sizeof(long long) ? 1000000000000000000LL : 1000000000;\nconst int MOD = 1000000007;\nconst double PI = acos(-1);\ntemplate <typename A, typename B> bool cmin(A &a, const B &b) {\n return a > b ? (a = b, true) : false;\n}\ntemplate <typename A, typename B> bool cmax(A &a, const B &b) {\n return a < b ? (a = b, true) : false;\n}\nbool odd(const int &n) { return n & 1; }\nbool even(const int &n) { return !odd(n); }\ntemplate <typename V> typename V::value_type sum(const V &v) {\n return accumulate(all(v), 0);\n}\nvoid solve();\nmain {\n solve();\n return 0;\n}\nint dx[] = {-1, 0, 1, 0};\nint dy[] = {0, 1, 0, -1};\nvoid solve() {\n int N;\n while (cin >> N, N) {\n vpii e(N);\n e[0] = mp(300, 300);\n loop(i, 1, N) {\n int n, d;\n cin >> n >> d;\n e[i] = mp(e[n].fi + dy[d], e[n].se + dx[d]);\n }\n vvb t(600, vb(600));\n rep(i, N) t[e[i].fi][e[i].se] = true;\n int u = 0, l = 0, d = 599, r = 599;\n for (;;) {\n bool b = false;\n rep(i, 600) b |= t[u][i];\n if (b) {\n break;\n } else {\n u++;\n }\n }\n for (;;) {\n bool b = false;\n rep(i, 600) b |= t[i][l];\n if (b) {\n break;\n } else {\n l++;\n }\n }\n for (;;) {\n bool b = false;\n rep(i, 600) b |= t[d][i];\n if (b) {\n break;\n } else {\n d--;\n }\n }\n for (;;) {\n bool b = false;\n rep(i, 600) b |= t[i][r];\n if (b) {\n break;\n } else {\n r--;\n }\n }\n cout << r - l + 1 << ' ' << d - u + 1 << endl;\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3188, "score_of_the_acc": -0.0135, "final_rank": 1 }, { "submission_id": "aoj_1165_7937187", "code_snippet": "#include <algorithm>\n#include <iostream>\nusing namespace std;\nint hw[450][450];\nint m[210], d[210];\nint main() {\n int n;\n while (1) {\n cin >> n;\n if (!n)\n break;\n for (int i = 0; i <= 420; i++) {\n for (int j = 0; j <= 420; j++) {\n hw[i][j] = -1;\n }\n }\n hw[201][201] = 0;\n for (int i = 1; i < n; i++) {\n cin >> m[i] >> d[i];\n for (int j = 1; j <= 410; j++) {\n for (int k = 1; k <= 410; k++) {\n if (hw[j][k] == m[i]) {\n if (d[i] == 0) {\n hw[j][k - 1] = i;\n }\n if (d[i] == 1) {\n hw[j + 1][k] = i;\n }\n if (d[i] == 2) {\n hw[j][k + 1] = i;\n }\n if (d[i] == 3) {\n hw[j - 1][k] = i;\n }\n }\n }\n }\n }\n int ansminw = 1000;\n for (int j = 1; j <= 410; j++) {\n for (int k = 1; k <= 410; k++) {\n if (hw[j][k] >= 0) {\n ansminw = min(ansminw, k);\n break;\n }\n }\n }\n int ansmaxw = 0;\n for (int j = 1; j <= 410; j++) {\n for (int k = 410; k > 0; k--) {\n if (hw[j][k] >= 0) {\n ansmaxw = max(ansmaxw, k);\n break;\n }\n }\n }\n int ansminh = 1000;\n for (int j = 1; j <= 410; j++) {\n for (int k = 1; k <= 410; k++) {\n if (hw[k][j] >= 0) {\n ansminh = min(ansminh, k);\n break;\n }\n }\n }\n int ansmaxh = 0;\n for (int j = 1; j <= 410; j++) {\n for (int k = 410; k > 0; k--) {\n if (hw[k][j] >= 0) {\n ansmaxh = max(ansmaxh, k);\n break;\n }\n }\n }\n cout << (ansmaxw - ansminw) + 1 << \" \" << (ansmaxh - ansminh) + 1 << endl;\n }\n}", "accuracy": 1, "time_ms": 470, "memory_kb": 3728, "score_of_the_acc": -0.3375, "final_rank": 9 }, { "submission_id": "aoj_1165_7937178", "code_snippet": "#include <cstring>\n#include <iostream>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < n; i++)\nint main() {\n int p[801][801], n, N, d;\n while (cin >> N && N) {\n rep(i, 801) rep(j, 801) p[i][j] = -1;\n p[400][400] = 0;\n for (int k = 1; k < N; k++) {\n cin >> n >> d;\n rep(i, 801) rep(j, 801) if (p[i][j] == n) {\n if (d == 0)\n p[i][j - 1] = k;\n if (d == 1)\n p[i + 1][j] = k;\n if (d == 2)\n p[i][j + 1] = k;\n if (d == 3)\n p[i - 1][j] = k;\n }\n }\n int fx = 801, fy = 801, lx = 0, ly = 0;\n rep(i, 801) {\n rep(j, 801) {\n if (~p[i][j]) {\n lx = max(j, lx);\n fx = min(j, fx);\n ly = max(i, ly);\n fy = min(i, fy);\n }\n }\n }\n cout << lx - fx + 1 << \" \" << ly - fy + 1 << endl;\n }\n}", "accuracy": 1, "time_ms": 1190, "memory_kb": 5580, "score_of_the_acc": -1.1088, "final_rank": 19 }, { "submission_id": "aoj_1165_7937165", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\ntypedef vector<int> vi;\ntypedef pair<int, int> pii;\n#define dump(x) cerr << #x << \" = \" << (x) << endl\n#define rep(i, n) for (int i = 0; i < (n); i++)\n#define pb push_back\nint n;\nint main() {\n int dy[] = {0, 1, 0, -1};\n int dx[] = {-1, 0, 1, 0};\n while (cin >> n) {\n int data[500][500] = {};\n if (n == 0)\n break;\n vector<pii> point(300);\n point[0] = pii(250, 250);\n data[point[0].first][point[0].second] = 1;\n rep(i, n - 1) {\n int num, dir;\n cin >> num >> dir;\n data[point[num].first + dy[dir]][point[num].second + dx[dir]] = 1;\n point[i + 1] =\n pii(point[num].first + dy[dir], point[num].second + dx[dir]);\n }\n int maxw = 0;\n int left = 1000, right = -1;\n rep(i, 500) {\n rep(j, 500) {\n if (data[i][j] == 1) {\n left = min(left, j);\n right = max(right, j);\n }\n }\n }\n maxw = max(maxw, right - left + 1);\n int maxh = 0;\n int up = 1000, down = -1;\n rep(j, 500) {\n rep(i, 500) {\n if (data[i][j] == 1) {\n up = min(up, i);\n down = max(down, i);\n }\n }\n }\n maxh = max(maxh, down - up + 1);\n cout << maxw << \" \" << maxh << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4028, "score_of_the_acc": -0.2027, "final_rank": 4 }, { "submission_id": "aoj_1165_7937158", "code_snippet": "#include <algorithm>\n#include <iostream>\nusing namespace std;\nconst int INF = 1e+8;\nint s[500][500];\nint dx[4] = {-1, 0, +1, 0};\nint dy[4] = {0, +1, 0, -1};\nvoid init() {\n for (int y = 0; y < 500; y++) {\n for (int x = 0; x < 500; x++) {\n s[y][x] = -1;\n }\n }\n}\nvoid search(int id, int d, int now) {\n for (int y = 0; y < 500; y++) {\n for (int x = 0; x < 500; x++) {\n if (s[y][x] == id) {\n int mx = x + dx[d];\n int my = y + dy[d];\n s[my][mx] = now;\n return;\n }\n }\n }\n}\nint main() {\n int N;\n while (cin >> N, N) {\n init();\n s[250][250] = 0;\n for (int i = 1; i < N; i++) {\n int n, d;\n cin >> n >> d;\n search(n, d, i);\n }\n int min_x, min_y, max_x, max_y;\n min_x = min_y = INF;\n max_x = max_y = 0;\n for (int y = 0; y < 500; y++) {\n for (int x = 0; x < 500; x++) {\n if (s[y][x] >= 0) {\n max_x = max(max_x, x);\n max_y = max(max_y, y);\n min_x = min(min_x, x);\n min_y = min(min_y, y);\n }\n }\n }\n cout << (max_x - min_x + 1) << \" \" << (max_y - min_y + 1) << endl;\n }\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 4048, "score_of_the_acc": -0.3517, "final_rank": 11 }, { "submission_id": "aoj_1165_7937157", "code_snippet": "#include <algorithm>\n#include <iostream>\nusing namespace std;\nint main() {\n const int dx[4] = {-1, 0, 1, 0};\n const int dy[4] = {0, 1, 0, -1};\n int c[500][500], N;\n while (cin >> N, N) {\n int min_x = 250, max_x = 250, min_y = 250, max_y = 250;\n for (int y = 0; y < 500; y++) {\n for (int x = 0; x < 500; x++) {\n c[y][x] = (x == 250 && y == 250) ? 0 : -1;\n }\n }\n for (int i = 0; i < N - 1; i++) {\n int n, d;\n cin >> n >> d;\n for (int y = min_y; y <= max_y; y++) {\n for (int x = min_x; x <= max_x; x++) {\n if (c[y][x] == n) {\n int mx = x + dx[d], my = y + dy[d];\n c[my][mx] = i + 1;\n max_x = max(max_x, mx);\n max_y = max(max_y, my);\n min_x = min(min_x, mx);\n min_y = min(min_y, my);\n break;\n }\n }\n }\n }\n cout << (max_x - min_x + 1) << \" \" << (max_y - min_y + 1) << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4032, "score_of_the_acc": -0.2082, "final_rank": 6 }, { "submission_id": "aoj_1165_4974044", "code_snippet": "#pragma GCC optimize (\"O3\")\n#include <iostream>\n#include <iomanip>\n#include <istream>\n#include <ostream>\n#include <sstream>\n#include <iterator>\n#include <vector>\n#include <algorithm>\n#include <queue>\n#include <deque>\n#include <list>\n#include <stack>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <bitset>\n#include <utility>\n#include <cmath>\n#include <cstdio>\n#include <cstring>\n#include <string>\n#include <ctime>\n#include <cctype>\n#include <cstdlib>\n#include <numeric>\n#define IINF 2147483647\n#define INF 3223372036854775807\n#define MOD 1000000007\n#define mod 998244353\n#define INT_MAX_ 2147483647\n#define EPS (1e-10)\n//#define REP(i, a, n) fo-r (ll i = a; i < (ll)(n); i++)\n//#define REPE(i, a, n) for (ll i = a; i <= (ll)(n); i++)\n//#define REP(i,x,y) for(register int i=(x); i<(y); i++)\n//#define REPE(i,x,y) for(register int i=(x); i<=(y); i++)\n//#define rep(i,n)for (ll i = 0; i < (ll)(n); i++)\n#define rep(i,l,r)for(ll i=(l);i<(r);i++)\n#define rep1(i,n) for(int i=1;i<=(int)(n);i++)\n#define Endl endl\n#define fi first\n#define se second\n#define pb push_back\n#define mp make_pair\n#define mt make_tuple\n#define eb emplace_back\n#define mmax(x,y)(x>y?x:y)\n#define mmin(x,y)(x<y?x:y)\n#define chmax(x,y) x=mmax(x,y)\n#define chmin(x,y) x=mmin(x,y)\n#define all(x) (x).begin(),(x).end()\n#define siz(x) (ll)(x).size()\n#define PI acos(-1.0)\n#define pi acos(-1.0)\n#define me memset\n// /#define bit(n,k) ((n>>k)&1)\n#define lg length()\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\ntypedef long double ld;\ntypedef pair<int,int>Pin;\ntypedef pair<ll,ll>Pll;\ntemplate<class T> using V=vector<T>;\ntemplate<typename T> using min_priority_queue = priority_queue<T, vector<T>, greater<T> >;\nlong long GCD(long long a, long long b) {return b?GCD(b,a%b):a;}\nlong long LCM(long long a, long long b) {return a/GCD(a,b)*b;}\nll pom(ll a,ll n,int m){ll x=1;for(a%=m;n;n/=2)n&1?x=x*a%m:0,a=a*a%m;return x;}\n#define invp(a,p)pom(a,p-2,p)\nint dx[4]={-1,1,0,0};\nint dy[4]={0,0,-1,1};\nint ddx[8]={-1,0,1,0,1,1,-1,-1};\nint ddy[8]={0,-1,0,1,1,-1,1,-1};\nll cmp1(pair<Pll,ll> a,pair<Pll,ll> b){\n return a.fi.se>b.fi.se;\n}\nll cmp2(pair<ll,ll> a,pair<ll,ll> b){\n if(a.fi!=b.fi)\n return a.fi>b.fi;\n else\n return a.se<b.se;\n}\n//----------------------------------------------------------------------\nint a[500][500];\n//----------------------------------------------------------------------\nint main(int argc, char * argv[]){\n cin.tie(0);\n ios::sync_with_stdio(false);\n //------------------------------- \n //ll begin_t=clock();\n //freopen(\"big.txt\", \"r\", stdin);\n //freopen(\"out3.txt\", \"w\", stdout);\n //------------------------------\n int N;cin>>N;\n while(0!=N){\n me(a,-1,sizeof(a));\n int maxx=250,maxy=250;\n int minx=250, miny=250;\n a[250][250]=0;\n for(int i=0;i<N-1;i++){\n int n,d;cin>>n>>d;\n for(int x=0;x<500;x++){\n for(int y=0;y<500;y++){\n if(a[x][y]==n){\n if(d==0){\n a[x][y-1]=i+1;\n chmin(miny,y-1);\n }\n else if(d==1){\n a[x-1][y]=i+1;\n chmin(minx,x-1);\n }\n else if(d==2){\n a[x][y+1]=i+1;\n chmax(maxy,y+1);\n }\n else if(d==3){\n a[x+1][y]=i+1;\n chmax(maxx,x+1);\n }\n }\n }\n }\n }\n cout<<1+maxy-miny<<\" \"<<1+maxx-minx<<Endl;\n cin>>N;\n }\n //------------------------------\n //fclose(stdin);\n //fclose(stdout);\n //ll end_t=clock();cout<<\"time=\"<<end_t-begin_t<<\"ms\"<<endl;\n //------------------------------- \n return 0;\n}\n//----------------------------------------------------------------------", "accuracy": 1, "time_ms": 490, "memory_kb": 4456, "score_of_the_acc": -0.5222, "final_rank": 17 }, { "submission_id": "aoj_1165_4952562", "code_snippet": "#include<bits/stdc++.h>\n//#include <atcoder/all>\n\n#define INF 1e9\n#define rep(i,n)for(int i=0;(i)<(int)(n);i++)\n#define REP(i,a,b)for(int i=(int)(a);(i)<=(int)(b);i++)\n#define ALL(a) (a).begin(),(a).end()\n#define chmax(a, b) a = max(a, b)\n#define chmin(a, b) a = min(a, b)\n#define pb push_back\n#define fi first\n#define se second\n#define lb lower_bound\n#define ub upper_bound\n#define sz(x) ((int)x.size())\n\nusing namespace std;\n//using namespace atcoder;\nusing ll = long long int;\nusing ld = long double;\nusing P = pair<ll, ll>;\nusing Graph = vector<vector<int>>;\n//using mint = modint1000000007;\n\nconst ll ZER = 0;\nconst ll MOD = 1e9 + 7;\n\n\nint main(){\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n\n int n;\n //hi, si, mi, ue\n int dy[4] = {0, 1, 0, -1};\n int dx[4] = {-1, 0, 1, 0};\n while(cin >> n){\n if(n == 0)break;\n vector<vector<int>> fld(500, vector<int>(500, -1));\n //a:何番目においたかの b:隣\n n--;\n vector<int> a(n), b(n);\n rep(i, n)cin >> a[i] >> b[i];\n fld[200][200] = 0;\n rep(i, n){\n rep(y, 401){\n rep(x, 400){\n if(fld[y][x] == a[i]){\n fld[y + dy[b[i]]][x + dx[b[i]]] = i + 1;\n }\n }\n }\n }\n int lx = INF, rx = 0, ly = INF, ry = 0;\n rep(i, 401){\n rep(j, 401){\n if(fld[i][j] >= 0){\n chmin(lx, j);\n chmin(ly, i);\n chmax(rx, j);\n chmax(ry, i);\n }\n }\n }\n cout << rx - lx + 1 << \" \" << ry - ly + 1 << endl;\n }\n}", "accuracy": 1, "time_ms": 500, "memory_kb": 4168, "score_of_the_acc": -0.4572, "final_rank": 15 }, { "submission_id": "aoj_1165_4947743", "code_snippet": "# include <bits/stdc++.h>\n# define rep(i,n) for(int i=0; i<(n); ++i)\n# define FI first\n# define SE second\nusing namespace std;\nusing vi = vector<int>;\nusing pii = pair<int, int>;\n\nstruct phash {\n inline size_t operator ()(const pair<int,int>& p) const {\n const auto h1 = hash<int>()(p.first);\n const auto h2 = hash<int>()(p.second);\n return h1 ^ (h2 << 1);\n }\n};\n\nvoid Main(int N, vi n, vi d) {\n unordered_map<int, pii> pos;\n pos[0] = { 0, 0 };\n rep (i, N-1) {\n int num = n[i];\n int dir = d[i];\n switch (dir) {\n case 0: // 左側\n pos[i+1] = { pos[num].FI - 1, pos[num].SE };\n break;\n case 1: // 下側\n pos[i+1] = { pos[num].FI, pos[num].SE - 1 };\n break;\n case 2: // 右側\n pos[i+1] = { pos[num].FI + 1, pos[num].SE };\n break;\n case 3: // 上側\n pos[i+1] = { pos[num].FI, pos[num].SE + 1 };\n break;\n default:\n pos[i+1] = { pos[num].FI, pos[num].SE };\n }\n }\n\n int width = 0;\n int height = 0;\n for (int i = 0; i < N; ++i) {\n for (int k = i + 1; k < N; ++k) {\n width = max(width, abs(pos[i].FI - pos[k].FI));\n height = max(height, abs(pos[i].SE - pos[k].SE));\n }\n }\n\n cout << width + 1 << \" \" << height + 1 << endl;\n}\n\nint main() {\n while (true) {\n int N;\n cin >> N;\n if (!N) break;\n vi n(N-1), d(N-1);\n rep (i, N-1) cin >> n[i] >> d[i];\n Main(N, n, d);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3364, "score_of_the_acc": -0.0425, "final_rank": 3 }, { "submission_id": "aoj_1165_4934946", "code_snippet": "/* ICPC */\n#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef long double ld;\ntypedef pair<ll,ll> pint;\nconst ll MOD = 1000000007;\n#define rep(i, n) for(ll i = ll(0); i < ll(n); i++)\n#define Rep(i, n) for(ll i = ll(1); i < ll(n); i++)\n#define ALL(a) (a).begin(),(a).end()\n#define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n\ntemplate<class T> inline bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\nbool Ret(ll a = 0, ll b = 0, ll c = 0, ll d = 0) {\n if (a == 0 && b == 0 && c == 0 && d == 0) return true;\n else return false;\n}\n\nstruct Point{ll x, y;};\n\nll dx[4] = {-1, 0, 1, 0};\nll dy[4] = {0, 1, 0, -1};\n\nvoid solve(ll n) {\n vector<ll> v(n), type(n);\n rep (i, n) cin >> v[i] >> type[i];\n vector<vector<bool>> flag(1000,vector<bool>(1000,false));\n map<ll, Point> mp;\n mp[0] = Point{500, 500};\n flag[mp[0].y][mp[0].x] = true;\n rep (i, n) {\n mp[i + 1] = Point{mp[v[i]].x + dx[type[i]], mp[v[i]].y + dy[type[i]]};\n flag[mp[v[i]].y + dy[type[i]]][mp[v[i]].x + dx[type[i]]] = true;\n }\n ll l = 1e16, r = -1;\n ll u = -1, d = 1e16;\n rep (i, 1000) {\n rep (j, 1000) {\n if (flag[i][j]) {\n chmin (l, j);\n chmax (r, j);\n chmax (u, i);\n chmin (d, i);\n }\n }\n }\n cout << r - l + 1 << ' ' << u - d + 1 << endl;\n}\n\nint main() {\n IOS;\n while (1) {\n ll n; cin >> n;\n if (Ret(n)) break;\n solve(n - 1);\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3256, "score_of_the_acc": -0.0344, "final_rank": 2 }, { "submission_id": "aoj_1165_4754626", "code_snippet": "/**\n * author: otera \n**/\n#include<iostream>\n#include<string> \n#include<cstdio>\n#include<cstring>\n#include<vector>\n#include<cmath>\n#include<algorithm> \n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<deque>\n#include<ciso646>\n#include<random>\n#include<map>\n#include<set>\n#include<complex>\n#include<bitset>\n#include<stack>\n#include<unordered_map>\n#include<utility>\n#include<cassert>\nusing namespace std;\n\n//#define int long long\ntypedef long long ll;\ntypedef unsigned long long ul;\ntypedef unsigned int ui;\ntypedef long double ld;\nconst int inf=1e9+7;\nconst ll INF=1LL<<60 ;\nconst ll mod=1e9+7 ;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define per(i,n) for(int i=n-1;i>=0;i--)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define per1(i,n) for(int i=n;i>=1;i--)\n#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)\ntypedef complex<ld> Point;\nconst ld eps = 1e-8;\nconst ld pi = acos(-1.0);\ntypedef pair<int, int> P;\ntypedef pair<ld, ld> LDP;\ntypedef pair<ll, ll> LP;\n#define fr first\n#define sc second\n#define all(c) c.begin(),c.end()\n#define pb push_back\n#define debug(x) cerr << #x << \" = \" << (x) << endl;\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\nint a[600][600];\nconst int dx[4] = {0, 1, 0, -1};\nconst int dy[4] = {-1, 0, 1, 0};\n\nvoid solve() {\n\tint n;\n while(cin >> n) {\n if(n == 0) break;\n vector<P> pos(n, {-1, -1});\n pos[0] = P{300, 300};\n rep(i, 600) {\n rep(j, 600) {\n a[i][j] = -1;\n }\n }\n a[300][300] = 0;\n rep(i, n - 1) {\n int m, d; cin >> m >> d;\n a[pos[m].fr + dx[d]][pos[m].sc + dy[d]] = i + 1;\n pos[i + 1] = P{pos[m].fr + dx[d], pos[m].sc + dy[d]};\n }\n int xmi = inf, xma = -inf, ymi = inf, yma = -inf;\n rep(i, 600) {\n rep(j, 600) {\n if(a[i][j] != -1) {\n chmax(xma, i); chmin(xmi, i);\n chmax(yma, j), chmin(ymi, j);\n }\n }\n }\n cout << yma - ymi + 1 << \" \" << xma - xmi + 1 << endl;\n }\n}\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\t//cout << fixed << setprecision(10);\n\t//int t; cin >> t; rep(i, t)solve();\n\tsolve();\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4560, "score_of_the_acc": -0.3356, "final_rank": 8 }, { "submission_id": "aoj_1165_4612547", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int dx[] = {0, 1, 0, -1};\nconst int dy[] = {-1, 0, 1, 0};\n\nint main() {\n int Map[500][500];\n int X[210], Y[210];\n while (true) {\n int N;\n cin >> N;\n if (N == 0) break;\n for (int i = 0; i < 500; ++i) {\n for (int j = 0; j < 500; ++j) {\n Map[i][j] = -1;\n }\n }\n for (int i = 0; i < 210; ++i) {\n X[i] = Y[i] = -1;\n }\n int offset = 500 / 2;\n Map[0 + offset][0 + offset] = 0;\n X[0] = Y[0] = offset;\n for (int i = 1; i < N; ++i) {\n int n, d;\n cin >> n >> d;\n int nx = X[n] + dx[d];\n int ny = Y[n] + dy[d];\n Map[nx][ny] = i;\n X[i] = nx;\n Y[i] = ny;\n }\n\n int lx = offset, rx = offset, ly = offset, ry = offset;\n for (int i = 0; i < 500; ++i) {\n for (int j = 0; j < 500; ++j) {\n if (Map[i][j] != -1) {\n lx = min(lx, i);\n rx = max(rx, i);\n ly = min(ly, j);\n ry = max(ry, j);\n }\n }\n }\n // cout << \"-----\" << endl;\n // for (int i = offset - 10; i < offset + 10; ++i) {\n // for (int j = offset - 10; j < offset + 10; ++j) {\n // cout << Map[i][j] << \" \";\n // }\n // cout << endl;\n // }\n\n // cout << \"-----\" << endl;\n cout << ry - ly + 1 << \" \" << rx - lx + 1 << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4036, "score_of_the_acc": -0.2046, "final_rank": 5 }, { "submission_id": "aoj_1165_3916080", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long int ll;\ntypedef pair<int,int> P;\n\n#define rep(i,n) for(int i=0;i<(n);++i)\n#define repi(i,a,b) for(int i=int(a);i<(b);i++)\n#define all(x) x.begin(),x.end()\n\nconst ll mod = 1e9+7;\nconst ll INF = 1e9;\n\nll gcd(ll a,ll b){return b?gcd(b,a%b):a;}\nint dx[4]={1,0,-1,0};\nint dy[4]={0,1,0,-1};\n\nint main()\n{\n\tint n;\n\twhile(cin>>n,n!=0){\n\t\tvector<vector<int>> p(4*n,vector<int>(4*n,0));\n\n\t\tmap<int,P> m;\n\t\tm[0]=P(2*n,2*n);\n\t\tp[2*n][2*n]=1;\n\t\tvector<tuple<int,int,int>> s(n-1);\n\t\trep(i,n-1){\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\ttuple<int,int,int> t= make_tuple(a,i+1,b);\n\t\t\ts[i]=t;\n\t\t}\n\t\tsort(all(s));\n\t\trep(i,n-1){\n\t\t\ttuple<int,int,int> t=s[i];\n\t\t\tint idx=get<1>(t);\n\t\t\tint from=get<0>(t);\n\t\t\tint angle=get<2>(t);\n\n\t\t\tP point=m[from];\n\t\t\t// cout<<angle<<endl;\n\t\t\tif(angle==0) point.second--;\n\t\t\tif(angle==1) point.first++;\n\t\t\tif(angle==2) point.second++;\n\t\t\tif(angle==3) point.first--;\n\n\t\t\tm[idx]=point;\n\t\t\tp[point.first][point.second]=1;\n\t\t}\n\t\tint l=-1,r=-1,u=-1,d=-1;\n\t\trep(i,4*n){\n\t\t\trep(j,4*n){\n\t\t\t\tif(p[i][j]==1){\n\t\t\t\t\tif(u<0)u=i;\n\t\t\t\t\td=i;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\trep(j,4*n){\n\t\t\trep(i,4*n){\n\t\t\t\tif(p[i][j]==1){\n\t\t\t\t\tif(l<0)l=j;\n\t\t\t\t\tr=j;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\n\t\tcout<<abs(l-r)+1<<\" \"<<abs(u-d)+1<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5396, "score_of_the_acc": -0.5373, "final_rank": 18 }, { "submission_id": "aoj_1165_3740003", "code_snippet": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <functional>\n#include <vector>\n#include <utility>\n#include <cstring>\n#include <iomanip>\n#include <numeric>\n#include <limits>\n#include <cmath>\n#include <cassert>\n#include <map>\n\nusing namespace std;\nusing ll = long long;\n\nconst int INF = 1<<30;\nconst int MOD = (int)1e9 + 7;\nconst int MAX_N = (int)1e5 + 5;\nconst int dy[] = {0, 1, 0, -1};\nconst int dx[] = {-1, 0, 1, 0};\n#define debug(x) cout << #x << \": \" << x << endl\n\nsigned main(void)\n{\n cin.tie(0);\n ios::sync_with_stdio(false);\n int n;\n while(cin >> n, n)\n {\n map<int, pair<int, int>> mp;\n mp[0] = make_pair(250, 250);\n for(int i = 1; i < n; i++)\n {\n int m, d; cin >> m >> d;\n pair<int, int> p = mp[m];\n mp[i] = make_pair(p.first + dy[d], p.second + dx[d]);\n }\n int table[600][600] = {};\n for(auto x : mp) table[x.second.first][x.second.second] = 1;\n int b = 0, t = 600, l = 600, r = 0;\n for(int i = 0; i < 600; i++)\n {\n for(int j = 0; j < 600; j++)\n {\n if(table[i][j]) t = min(t, i);\n }\n }\n for(int i = 599; i >= 0; i--)\n {\n for(int j = 0; j < 600; j++)\n {\n if(table[i][j]) b = max(b, i);\n }\n }\n for(int j = 0; j < 600; j++)\n {\n for(int i = 0; i < 600; i++)\n {\n if(table[i][j]) l = min(l, j);\n }\n }\n for(int j = 599; j >= 0; j--)\n {\n for(int i = 0; i < 600; i++)\n {\n if(table[i][j]) r = max(r, j);\n }\n }\n cout << r - l + 1 << \" \" << b - t + 1 << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4568, "score_of_the_acc": -0.3555, "final_rank": 12 } ]
aoj_1166_cpp
Problem B: Amazing Mazes You are requested to solve maze problems. Without passing through these mazes, you might not be able to pass through the domestic contest! A maze here is a rectangular area of a number of squares, lined up both lengthwise and widthwise, The area is surrounded by walls except for its entry and exit. The entry to the maze is at the leftmost part of the upper side of the rectangular area, that is, the upper side of the uppermost leftmost square of the maze is open. The exit is located at the rightmost part of the lower side, likewise. In the maze, you can move from a square to one of the squares adjoining either horizontally or vertically. Adjoining squares, however, may be separated by a wall, and when they are, you cannot go through the wall. Your task is to find the length of the shortest path from the entry to the exit. Note that there may be more than one shortest paths, or there may be none. Input The input consists of one or more datasets, each of which represents a maze. The first line of a dataset contains two integer numbers, the width w and the height h of the rectangular area, in this order. The following 2 × h − 1 lines of a dataset describe whether there are walls between squares or not. The first line starts with a space and the rest of the line contains w − 1 integers, 1 or 0, separated by a space. These indicate whether walls separate horizontally adjoining squares in the first row. An integer 1 indicates a wall is placed, and 0 indicates no wall is there. The second line starts without a space and contains w integers, 1 or 0, separated by a space. These indicate whether walls separate vertically adjoining squares in the first and the second rows. An integer 1/0 indicates a wall is placed or not. The following lines indicate placing of walls between horizontally and vertically adjoining squares, alternately, in the same manner. The end of the input is indicated by a line containing two zeros. The number of datasets is no more than 100. Both the widths and the heights of rectangular areas are no less than 2 and no more than 30. Output For each dataset, output a line having an integer indicating the length of the shortest path from the entry to the exit. The length of a path is given by the number of visited squares. If there exists no path to go through the maze, output a line containing a single zero. The line should not contain any character other than this number. Sample Input 2 3 1 0 1 0 1 0 1 9 4 1 0 1 0 0 0 0 0 0 1 1 0 1 1 0 0 0 1 0 1 1 0 0 0 0 0 0 0 0 0 0 0 1 1 0 0 0 1 0 0 1 1 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 1 0 12 5 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 0 0 1 0 1 0 0 0 0 0 0 1 1 0 1 1 0 1 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 Output for the Sample Input 4 0 20
[ { "submission_id": "aoj_1166_10936796", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define oke cout << \"Yes\" << '\\n';\n#define dame cout << \"No\" << '\\n';\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\nusing Hai2 = vector<vector<ll>>;\nusing HaiB = vector<vector<bool>>;\nusing Hai3 = vector<vector<vector<ll>>>;\n\nint H,W;\nqueue<pair<int,int>>Q;\nHai2 dist(1100,vector<ll>(1100,1e9));\nvector<int>gox = {1,0,-1,0};\nvector<int>goy = {0,1,0,-1};\nHai2 tate(100,vector<ll>(100));\nHai2 yoko(100,vector<ll>(100));\n\nvoid bfs(){\n while(!Q.empty()){\n int x,y;\n tie(y,x) = Q.front();\n Q.pop();\n rep(i,4){\n int xx=x+gox[i],yy=y+goy[i];\n if(xx < 0 || W <= xx || yy < 0 || H <= yy){\n continue;\n }\n if(i==0){\n if(tate[y][x]){\n continue;\n }\n }\n if(i==1){\n if(yoko[y][x]){\n continue;\n }\n }\n if(i==2){\n if(tate[y][x-1]){\n continue;\n }\n }\n if(i==3){\n if(yoko[y-1][x]){\n continue;\n }\n }\n if(dist[yy][xx] > dist[y][x]+1){\n dist[yy][xx] = dist[y][x]+1;\n Q.push({yy,xx});\n }\n }\n }\n}\n\nint main() {\n\tcout << fixed << setprecision(15);\n while(true){\n cin>>W>>H;\n if(W==0 && H==0){\n break;\n }\n rep(i,H*2-1){\n if(i%2==0){\n rep(j,W-1){\n cin>>tate[i/2][j];\n }\n }else{\n rep(j,W){\n cin>>yoko[i/2][j];\n }\n }\n }\n int a=1;\n dist[0][0]=1;\n Q.push({0,0});\n bfs();\n if(dist[H-1][W-1]==1e9){\n dist[H-1][W-1]=0;\n }\n cout<<dist[H-1][W-1]<<\"\\n\";\n rep(i,H){\n rep(j,W){\n dist[i][j]=1e9;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 12800, "score_of_the_acc": -1, "final_rank": 19 }, { "submission_id": "aoj_1166_10884830", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n// #include <atcoder/all>\n// using namespace atcoder;\nusing ll = long long;\nusing ld = long double;\nusing P = pair<ll,ll>;\nusing Board = vector<string>;\n// using mint = modint998244353;\nusing vl = vector<ll>;\nusing vvl = vector<vector<ll>>;\nusing vp = vector<P>;\nusing vb = vector<bool>;\nusing vvb = vector<vector<bool>>;\nusing vs = vector<string>;\nusing sl = set<ll>;\nusing Graph = vector<vector<ll>>;\nusing pq = priority_queue<ll>;\nusing pqg = priority_queue<ll, vector<ll>, greater<ll>>;\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define nall(a) a.begin(), a.end()\nconst ll INF = 1LL << 60;\n\nint main(){\n while (true) {\n ll w, h; cin >> w >> h;\n if (w==0 && h==0) break;\n vvl ver(h, vl(w-1)), hor(h-1, vl(w));\n rep(i,h*2-1) {\n if (i%2==0) {\n rep(j,w-1) cin >> ver[i/2][j];\n } else {\n rep(j,w) cin >> hor[i/2][j];\n }\n }\n map<P,ll> dist;\n queue<P> que;\n dist[P(0,0)] = 0;\n que.push(P(0,0));\n while (!que.empty()) {\n ll ch = que.front().first, cw = que.front().second;\n que.pop();\n // up\n if (ch > 0 && !hor[ch-1][cw] && !dist.count(P(ch-1,cw))) {\n dist[P(ch-1,cw)] = dist[P(ch,cw)] + 1;\n que.push(P(ch-1,cw));\n }\n // down\n if (ch < h-1 && !hor[ch][cw] && !dist.count(P(ch+1,cw))) {\n dist[P(ch+1,cw)] = dist[P(ch,cw)] + 1;\n que.push(P(ch+1,cw));\n }\n // left\n if (cw > 0 && !ver[ch][cw-1] && !dist.count(P(ch,cw-1))) {\n dist[P(ch,cw-1)] = dist[P(ch,cw)] + 1;\n que.push(P(ch,cw-1));\n }\n // right\n if (cw < w-1 && !ver[ch][cw] && !dist.count(P(ch,cw+1))) {\n dist[P(ch,cw+1)] = dist[P(ch,cw)] + 1;\n que.push(P(ch,cw+1));\n }\n }\n if (dist.count(P(h-1,w-1))) cout << dist[P(h-1,w-1)]+1 << endl;\n else cout << 0 << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3440, "score_of_the_acc": -0.5382, "final_rank": 18 }, { "submission_id": "aoj_1166_10879445", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing ld = long double;\n\n\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rep1(i,n) for(ll i = 1; i <= (n); ++i)\n#define rrep(i,n) for(ll i = n-1; i >= 0; --i)\n#define all(x) (x).begin(), (x).end()\n#define rall(a) a.rbegin(),a.rend()\n\ninline void Yes() { std::cout << \"Yes\" << std::endl; }\ninline void No() { std::cout << \"No\" << std::endl; }\ninline void YN(bool flag) {flag ? Yes() : No();}\n\ntemplate<class T> bool chmin(T& a,T b) {\n if(a > b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<class T> bool chmax(T& a,T b) {\n if(a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<typename T> using vc = std::vector<T>;\ntemplate<class T> using P = std::pair<T, T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<class T> using PQ = std::priority_queue<T, vc<T>>;\ntemplate<class T> using PQg = std::priority_queue<T, vc<T>, std::greater<T>>;\ninline const std::vector<ll> dx = {1, 0, -1, 0,-1,-1,1,1};\ninline const std::vector<ll> dy = {0, 1, 0, -1,-1,1,-1,1};\ninline constexpr ll INF = 2e18;\nusing pll = std::pair<ll, ll>;\n\n//座標がグリッド上にあるか\ntemplate<typename T>\nbool Ongrid(T x,T y,T h,T w) {\n if(x >= 0 && x < h && y >= 0 && y < w) return true;\n else return false;\n}\n\n//グリッドを90度回転\ntemplate <typename T>\nvv<T> rotate(const vv<T>& v) {\n if(v.empty() || v[0].empty()) return {};\n\n size_t n = v.size();\n size_t m = v[0].size();\n\n vv<T> nx(m,vc<T>(n));\n\n for (size_t i = 0; i < n; ++i)for (size_t j = 0; j < m; ++j) {\n nx[j][n-1-i] = v[i][j];\n }\n return nx;\n}\n\ntemplate <typename T>\nvv<T> counter_rotate(const vv<T>& v) {\n if(v.empty() || v[0].empty()) return {};\n\n size_t n = v.size();\n size_t m = v[0].size();\n\n vv<T> nx(m,vc<T>(n));\n\n for (size_t i = 0; i < n; ++i)for (size_t j = 0; j < m; ++j) {\n nx[m-1-j][i] = v[i][j];\n }\n return nx;\n}\n\n/*考察 幅優先探索で解く\n*/\nint main() {\n while(true) {\n ll W,H;cin>>W>>H;\n if(W==0&&H==0) break;\n vv<ll> seen(H,vc<ll>(W,-1));\n queue<pair<pll,ll>> que;\n vv<ll> wall(2*H,vc<ll>(W+1,1));\n\n rep(i,(H*2-1)) {\n if(i%2==0) {\n rep(j,W-1) {\n cin >> wall[i][j];\n }\n } else {\n rep(j,W) {\n cin >> wall[i][j];\n }\n }\n }\n\n que.push({{0,0},0});seen[0][0]=0;\n while(!que.empty()) {\n ll x = que.front().first.first,y = que.front().first.second;\n ll d = que.front().second; que.pop();\n rep(i,4) {\n ll nx = x + dx[i],ny = y + dy[i];\n if(Ongrid(nx,ny,H,W) && seen[nx][ny] == -1) {\n if(wall[nx+x][min(ny,y)]) continue;\n que.push({{nx,ny},d+1});\n seen[nx][ny] = d+1;\n }\n }\n }\n cout << seen[H-1][W-1]+1 << endl;\n }\n }", "accuracy": 1, "time_ms": 10, "memory_kb": 3196, "score_of_the_acc": -0.0132, "final_rank": 6 }, { "submission_id": "aoj_1166_10866272", "code_snippet": "// メモ\n// C++コンテスト用マクロ\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long; // 整数(long long型)\n#define rep(i, n) for (ll i = 0; i < (n); i++) // 0~n-1まで\n#define nall(a) a.begin(), a.end() // ノーマルオール\n#define pb push_back // push_back\n#define pob pop_back // pop_back\n#define Yes cout << \"Yes\" << endl // Yes\n#define No cout << \"No\" << endl // No\n#ifndef ONLINE_JUDGE\n#define _GLIBCXX_DEBUG // 配列外参照時のエラー検出\n#endif\n\nint main(){\n vector<ll> ans;\n while(1){\n ll w, h;\n cin >> w >> h;\n if(w == 0 && h == 0) break;\n map<pair<pair<ll, ll>, pair<ll, ll>>, ll> m;\n rep(i, 2 * h - 1){\n if(i % 2 == 0){\n rep(j, w - 1){\n ll n;\n cin >> n;\n if(n == 0){\n m[{{i / 2, j}, {i / 2, j + 1}}] = 1;\n m[{{i / 2, j + 1}, {i / 2, j}}] = 1;\n }\n }\n }\n else if(i % 2 == 1){\n rep(j, w){\n ll n;\n cin >> n;\n if(n == 0){\n m[{{i / 2, j}, {i / 2 + 1, j}}] = 1;\n m[{{i / 2 + 1, j}, {i / 2, j}}] = 1;\n }\n }\n }\n }\n vector<vector<ll>> used(h, vector<ll>(w, -1));\n queue<pair<pair<ll, ll>, ll>> q;\n q.push({{0, 0}, 1});\n used[0][0] = 1;\n while(!q.empty()){\n pair<ll, ll> current = q.front().first;\n ll d = q.front().second;\n q.pop();\n if(current.first == h - 1 && current.second == w - 1) break;\n vector<ll> di = {0, 1, 0, -1}, dj = {1, 0, -1, 0};\n rep(i, 4){\n ll x = current.first + di[i], y = current.second + dj[i];\n if(x < 0 || x >= h || y < 0 || y >= w) continue;\n if(m.count({current, {x, y}}) != 0 && used[x][y] == -1){\n used[x][y] = d + 1;\n q.push({{x, y}, d + 1});\n }\n }\n }\n if(used[h - 1][w - 1] == -1){\n ans.push_back(0);\n }\n else{\n ans.push_back(used[h - 1][w - 1]);\n }\n }\n rep(i, (int)ans.size()){\n cout << ans[i] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3588, "score_of_the_acc": -1.0534, "final_rank": 20 }, { "submission_id": "aoj_1166_10857815", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, a, n) for (int i = a; i < n; i++)\nusing ll = long long;\nusing ld = long double;\nusing pl = pair<ll, ll>;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\nconst int mod = 998244353;\nconst ll hashh = 2147483647;\n\nint main()\n{\n vector<pl> next = {{1, 0}, {-1, 0}, {0, 1}, {0, -1}};\n while (1)\n {\n ll h, w;\n bool b = false;\n cin >> w >> h;\n if (h == 0 && w == 0)\n return 0;\n vvl a(h * 2 - 1, vl(w,1));\n vector<vector<bool>> flag(h, vector<bool>(w, false));\n vvl count(h, vl(w, 0));\n queue<pl> q;\n q.push({0, 0});\n flag[0][0] = true;\n count[0][0] = 1;\n rep(i, 0, h * 2 - 1)\n {\n rep(j, 0, w)\n {\n if (i % 2 == 0 && j == 0)\n {\n continue;\n }\n cin >> a[i][j];\n }\n }\n while (!q.empty())\n {\n pl p = q.front();\n q.pop();\n if (p.first == h - 1 && p.second == w - 1)\n {\n b = true;\n cout << count[p.first][p.second] << endl;\n break;\n }\n rep(i, 0, 4)\n {\n ll nh = p.first + next[i].first;\n ll nw = p.second + next[i].second;\n if (nh < 0 || nh >= h || nw < 0 || nw >= w)\n continue;\n if(next[i].second == -1){\n if(a[p.first * 2 + next[i].first][nw+1] == 1) continue;\n }\n else{\n if (a[p.first * 2 + next[i].first][nw] == 1) continue;\n }\n if (!flag[nh][nw])\n {\n flag[nh][nw] = true;\n count[nh][nw] = count[p.first][p.second] + 1;\n q.push({nh, nw});\n }\n }\n }\n if (!b)\n cout << 0 << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3104, "score_of_the_acc": -0.0037, "final_rank": 3 }, { "submission_id": "aoj_1166_10853319", "code_snippet": "#include<iostream>\n#include<iomanip>\n#include<math.h>\n#include<algorithm>\n#include<string>\n#include<vector>\n#include<queue>\n#include<stack>\n#include<set>\n#include<map>\n#define REP(i, N) for(ll i = 0; i < N; ++i)\n#define FOR(i, a, b) for(ll i = a; i < b; ++i)\n#define ALL(a) (a).begin(),(a).end()\n#define pb push_back\n#define INF (long long)1000000000\n#define MOD 1000000007\n#define EPS (long double) 1e-8\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<ll, ll> P;\n\nint main() {\n\twhile(1) {\n\t\tint w, h;\n\t\tcin>>w>>h;\n\t\tif(w == 0 && h== 0) break;\n\t\tint yoko[h][w - 1];\n\t\tint tate[h - 1][w];\n\t\tREP(i, 2 * h - 1) {\n\t\t\tif(i % 2 == 0) {\n\t\t\t\tREP(j, w - 1) cin>>yoko[i / 2][j];\n\t\t\t} else {\n\t\t\t\tREP(j, w) cin>>tate[i / 2][j];\n\t\t\t}\n\t\t}\n\t\tint d[h][w];\n\t\tREP(i, h) {\n\t\t\tREP(j, w) d[i][j] = INF;\n\t\t}\n\t\td[0][0] = 0;\n\t\tqueue<P> q;\n\t\tq.push(P(0, 0));\n\t\twhile(!q.empty()) {\n\t\t\tP p = q.front();\n\t\t\tq.pop();\n\t\t\tif(p.first - 1 >= 0 && tate[p.first - 1][p.second] == 0 && d[p.first - 1][p.second] == INF) {\n\t\t\t\td[p.first - 1][p.second] = d[p.first][p.second] + 1;\n\t\t\t\tq.push(P(p.first - 1, p.second));\n\t\t\t}\n\t\t\tif(p.first + 1 < h && tate[p.first][p.second] == 0 && d[p.first + 1][p.second] == INF) {\n\t\t\t\td[p.first + 1][p.second] = d[p.first][p.second] + 1;\n\t\t\t\tq.push(P(p.first + 1, p.second));\n\t\t\t}\n\t\t\tif(p.second - 1 >= 0 && yoko[p.first][p.second - 1] == 0 && d[p.first][p.second - 1] == INF) {\n\t\t\t\td[p.first][p.second - 1] = d[p.first][p.second] + 1;\n\t\t\t\tq.push(P(p.first, p.second - 1));\n\t\t\t}\n\t\t\tif(p.second + 1 < w && yoko[p.first][p.second] == 0 && d[p.first][p.second + 1] == INF) {\n\t\t\t\td[p.first][p.second + 1] = d[p.first][p.second] + 1;\n\t\t\t\tq.push(P(p.first, p.second + 1));\n\t\t\t}\n\t\t}\n\t\tif(d[h - 1][w - 1] == INF) cout<<0<<endl;\n\t\telse cout<<d[h - 1][w - 1] + 1<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3068, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1166_10849691", "code_snippet": "#include <vector>\n#include <iostream>\n#include <queue>\n\nusing namespace std;\n\nvector<int> dh = {1,-1,0,0};\nvector<int> dw = {0,0,1,-1};\n\nint main() {\n vector<int> res_list;\n while (true) {\n int W, H; cin >> W >> H;\n if (W == 0 && H == 0) break;\n vector<vector<vector<int>>> g(H, vector<vector<int>>(W, vector<int>(2))); //right, down\n for (int h = 0; h < 2 * H - 1; ++h) {\n if (h % 2 == 0) {\n //right\n for (int w = 0; w < W - 1; ++w) {\n cin >> g[h / 2][w][0];\n }\n }\n else {\n for (int w = 0; w < W; ++w) {\n cin >> g[h / 2][w][1];\n }\n }\n }\n\n queue<pair<int, int>> q;\n vector<vector<int>> dist(H, vector<int>(W, -1));\n q.push({0,0});\n dist[0][0] = 1;\n while(!q.empty()) {\n pair<int, int> p = q.front();\n q.pop();\n int h, w; h = p.first; w = p.second;\n for (int i = 0; i < 4; ++i) {\n int nh, nw; nh = h + dh[i]; nw = w + dw[i];\n if (nh < 0 || nh >= H || nw < 0 || nw >= W) continue;\n if (dist[nh][nw] != -1) continue;\n if (i == 0 && g[h][w][1] == 1) continue; //down\n if (i == 1 && g[nh][nw][1] == 1) continue; //up\n if (i == 2 && g[h][w][0] == 1) continue; //right\n if (i == 3 && g[nh][nw][0] == 1) continue; //left\n q.push({nh,nw});\n dist[nh][nw] = dist[h][w] + 1;\n }\n }\n if (dist[H-1][W-1] == -1) dist[H-1][W-1] = 0;\n res_list.push_back(dist[H-1][W-1]);\n }\n for (int res: res_list) cout << res << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3156, "score_of_the_acc": -0.009, "final_rank": 4 }, { "submission_id": "aoj_1166_10789010", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define all(T) T.begin(), T.end()\nusing ll = long long;\nusing P = pair<int, int>;\nconst int di[] = {-1, 0, 1, 0};\nconst int dj[] = {0, -1, 0, 1};\nconst ll inf = 1e18;\n\nvoid solve(ll w, ll h) {\n set<vector<ll>> st;\n rep(i, 2 * h - 1) {\n if (i % 2) {\n // よこ\n rep(j, w) {\n int n;\n cin >> n;\n if (n == 1) {\n int ni = (i + 1) / 2;\n P p1 = {ni, j};\n P p2 = {ni - 1, j};\n if (p2 < p1) swap(p1, p2);\n st.insert({p1.first, p1.second, p2.first, p2.second});\n }\n }\n } else {\n // たて\n rep(j, w - 1) {\n int n;\n cin >> n;\n if (n == 1) {\n int ni = i / 2;\n P p1 = {ni, j};\n P p2 = {ni, j + 1};\n if (p2 < p1) swap(p1, p2);\n st.insert({p1.first, p1.second, p2.first, p2.second});\n }\n }\n }\n }\n vector dist(h, vector<ll>(w, -inf));\n queue<pair<int, int>> q;\n q.push({0, 0});\n dist[0][0] = 1;\n while (q.size()) {\n auto [i, j] = q.front();\n q.pop();\n rep(v, 4) {\n int ni = i + di[v], nj = j + dj[v];\n if (ni < 0 || nj < 0 || ni >= h || nj >= w) continue;\n if (dist[ni][nj] != -inf) continue;\n P p1 = {i, j};\n P p2 = {ni, nj};\n if (p2 < p1) swap(p1, p2);\n vector<ll> vec = {p1.first, p1.second, p2.first, p2.second};\n if (st.count(vec)) continue;\n q.push({ni, nj});\n dist[ni][nj] = dist[i][j] + 1;\n }\n }\n ll ans = 0;\n if (dist[h - 1][w - 1] != -inf) ans = dist[h - 1][w - 1];\n cout << ans << '\\n';\n}\n\nint main() {\n while (1) {\n ll w, h;\n cin >> w >> h;\n if (w == 0 && h == 0) break;\n solve(w, h);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3584, "score_of_the_acc": -0.053, "final_rank": 16 }, { "submission_id": "aoj_1166_10778618", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nvector<int> d_tate = {1, -1, 0, 0};\nvector<int> d_yoko = {0, 0, 1, -1};\n//0は↑、1は↓、2は→、3は←をあらわす\n\nint main() {\n int H, W;\n while(true){\n cin >> W >> H;\n if(H == 0 && W == 0){\n return 0;\n }\n vector<vector<int>> tatekabe(H, vector<int>(W-1));\n vector<vector<int>> yokokabe(H-1, vector<int>(W));\n for(int i = 0; i < H; i++){\n if(i == H-1){\n for(int j = 0; j < W-1; j++){\n cin >> tatekabe[i][j];\n }\n }\n else{\n for(int j = 0; j < W-1; j++){\n cin >> tatekabe[i][j];\n }\n for(int j = 0; j < W; j++){\n cin >> yokokabe[i][j];\n }\n }\n }\n //縦壁横壁出力(合ってた)\n /*\n cout << \"tatekabe=\" << endl;\n for(int i = 0; i < H; i++){\n for(int j = 0; j < W-1; j++){\n cout << tatekabe[i][j];\n }\n cout << endl;\n }\n cout << \"yokokabe=\" << endl;\n for(int i = 0; i < H-1; i++){\n for(int j = 0; j < W; j++){\n cout << yokokabe[i][j];\n }\n cout << endl;\n }\n */\n\n vector<vector<int>> dist(H, vector<int>(W, -1));\n queue<pair<int, int>> q;\n\n dist[0][0] = 1; //dist[i][j]は、iが縦行の場所で、jが横行の場所\n q.push(make_pair(0, 0));\n\n //ここまではOK\n while(!q.empty()){\n int tate = q.front().first, yoko = q.front().second;\n q.pop();\n\n for(int i = 0; i < 4; i++){\n int n_tate = tate + d_tate[i];\n int n_yoko = yoko + d_yoko[i];\n //はみ出してないか、探索済みでないか\n if(n_tate<0 || n_tate>=H || n_yoko<0 || n_yoko>=W){\n continue;\n }\n if(dist[n_tate][n_yoko] != -1){\n continue;\n }\n //0,1なら上下移動なのでyokokabeを見る\n if(i == 0 || i == 1){\n if(yokokabe[min(tate, n_tate)][n_yoko] == 1){\n continue;\n }\n }\n else{\n if(tatekabe[n_tate][min(yoko, n_yoko)] == 1){\n continue;\n }\n }\n\n dist[n_tate][n_yoko] = dist[tate][yoko] + 1;\n q.push(make_pair(n_tate, n_yoko));\n }\n }\n\n if(dist[H-1][W-1] == -1){\n cout << 0 << endl;\n }\n else{\n cout << dist[H-1][W-1] << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3092, "score_of_the_acc": -0.0025, "final_rank": 2 }, { "submission_id": "aoj_1166_10750826", "code_snippet": "#ifndef ONLINE_JUDGE\n#define _GLIBCXX_DEBUG\n#endif\n\n#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#define YES cout<<\"Yes\"<<endl\n#define NO cout<<\"No\"<<endl\n#define YN {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}// if(a==b)YN;\n#define NO2 cout<<-1<<endl\n\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n#define rrep(i, n) for (int i=int(n)-1; i>=0; --i)\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n\nint dh[] = {0,1,0,-1}, dw[] = {1,0,-1,0};\nint INF = int(1e9);\n\nvoid solve(int H, int W) {\n vector<vector<int>> dist(H, vector<int>(W, INF));\n dist[0][0] = 1;\n vector<vector<int>> wall_h(H-1, vector<int>(W)), wall_v(H, vector<int>(W-1));\n rep(i, 2*H-1) {\n if (i%2 == 0) {\n rep(j, W-1) {\n cin >> wall_v[i/2][j];\n }\n }\n else {\n rep(j, W) {\n cin >> wall_h[i/2][j];\n }\n }\n }\n queue<pair<int,int>> que;\n que.push({0,0});\n while(que.size()) {\n auto [h,w] = que.front(); que.pop();\n rep(k,4) {\n int nh=h+dh[k], nw=w+dw[k];\n if (nh<0||H<=nh||nw<0||W<=nw) continue;\n if (dist[nh][nw] != INF) continue;\n if (dh[k] == 1) {\n if (wall_h[h][w]) continue;\n }\n else if (dh[k] == -1) {\n if (wall_h[nh][w]) continue;\n }\n else if (dw[k] == 1) {\n if (wall_v[h][w]) continue;\n }\n else {\n if (wall_v[h][nw]) continue;\n }\n\n if (dist[h][w]+1 < dist[nh][nw]) {\n dist[nh][nw] = dist[h][w]+1;\n que.push({nh,nw});\n }\n }\n }\n if (dist[H-1][W-1] != INF) cout << dist[H-1][W-1] << endl;\n else cout << 0 << endl;\n\n /*\n cout << \"--- MAZE ---\\n\";\n rep(i,H) {\n rep(j,W) {\n if (dist[i][j] == INF) cout << \"* \";\n else cout << dist[i][j] << ' ';\n }\n cout << \"\\n\";\n }\n */\n}\n\nint main() {\n while(true) {\n int H, W;\n cin >> W >> H;\n if (H==0 && W==0) break;\n solve(H,W);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3248, "score_of_the_acc": -0.0185, "final_rank": 7 }, { "submission_id": "aoj_1166_10703270", "code_snippet": "#include <iostream>\n#include <vector>\n#include <iomanip>\n#include <algorithm>\n#include <tuple>\n#include <set>\n#include <map>\n#include <bitset>\n#include <cmath>\n#include <deque>\n#include <queue>\n#include <stack>\n#include <cassert>\n#include <unordered_set>\n#include <unordered_map>\n#include <cmath>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define all(v) v.begin(), v.end()\n\nll llpow(ll a, ll t)\n{\n ll res = 1;\n rep(i, t) res *= a;\n return res;\n}\n\nll inf = std::numeric_limits<ll>::max();\n\nvector<ll> dx = {1, -1, 0, 0};\nvector<ll> dy = {0, 0, 1, -1};\nvector<ll> dgx = {1, -1, 0, 0};\nvector<ll> dgy = {0, 0, 1, 0};\n\nvector<ll> ans;\n\nint main()\n{\n while (true)\n {\n ll w, h;\n cin >> w >> h;\n if (!w && !h)\n {\n break;\n }\n vector<vector<ll>> g(2 * h - 1, vector<ll>(w, 0));\n rep(i, 2 * h - 1)\n {\n if (i % 2)\n {\n rep(j, w)\n {\n cin >> g[i][j];\n }\n }\n else\n {\n rep(j, w - 1)\n {\n cin >> g[i][j + 1];\n }\n }\n }\n vector<vector<ll>> dsts(h, vector<ll>(w, inf));\n dsts[0][0] = 1;\n queue<vector<ll>> q;\n q.push({0, 0});\n while (q.size())\n {\n ll ux = q.front()[0];\n ll uy = q.front()[1];\n q.pop();\n rep(i, 4)\n {\n ll vx = ux + dx[i];\n ll vy = uy + dy[i];\n if (vx < 0 || vx >= h || vy < 0 || vy >= w)\n {\n continue;\n }\n if (g[2 * ux + dgx[i]][uy + dgy[i]])\n {\n continue;\n }\n if (dsts[ux][uy] + 1 < dsts[vx][vy])\n {\n dsts[vx][vy] = dsts[ux][uy] + 1;\n q.push({vx, vy});\n }\n }\n }\n if (dsts[h - 1][w - 1] == inf)\n {\n ans.push_back(0);\n }\n else\n {\n ans.push_back(dsts[h - 1][w - 1]);\n }\n }\n rep(i, ans.size())\n {\n cout << ans[i] << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3488, "score_of_the_acc": -0.0432, "final_rank": 13 }, { "submission_id": "aoj_1166_10660326", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n//#include <atcoder/all>\n//using namespace atcoder;\n\n\ntemplate<typename T> using vc = vector<T>;//prioriy_queueに必要なのでここにこれ書いてます\ntemplate<typename T> using vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nusing ull = unsigned long long;\nll INF = 3e18;\ndouble pi = 3.14159265358979;\nusing ld = long double;\nusing bl = bool;\n//using mint = modint998244353;\n//using mint = modint1000000007;\n//using mint = modint;//使うときはコメントアウトを外す\n//mint::set_mod(m);//使うときはコメントアウトを外す\n\ntemplate<class T> using pq = priority_queue<T, vc<T>>;//大きい順\ntemplate<class T> using pq_g = priority_queue<T, vc<T>, greater<T>>;//小さい順\n//-----------------------------------\n\n\n\n//-------------2.配列系--------------\nusing vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>; using vvvvl = vv<vvl>;\nusing vs = vc<string>; using vvs = vv<string>; using vvvs = vv<vs>;\nusing vb = vc<bl>; using vvb = vv<bl>; using vvvb = vv<vb>;\nusing vld = vc<ld>; using vvld = vv<ld>; using vvvld = vv<vld>;\nusing pll = pair<ll, ll>;\n//using vmint = vc<mint>; using vvmint = vv<mint>; using vvvmint = vv<vmint>;\n\n#define rep(i,n) for(ll i = 0; i < (n); ++i)//↓でrepを使うので書いてます\ntemplate<class T>istream& operator>>(istream& i, vc<T>& v) { rep(j, size(v))i >> v[j]; return i; }\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n\n\n//--------3.コード短縮化とか---------\n#define rep(i,n) for(ll i = 0; i < (n); ++i)\n#define rrep(i,n) for(ll i = 1; i <= (n); ++i)\n#define drep(i,n) for(ll i = (n)-1; i >= 0; --i)\n\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n\n#define chmax(x,y) x = max(x,y)\n#define chmin(x,y) x = min(x,y)\n\n#define pb push_back\n#define eb emplace_back\n#define em emplace\n#define pob pop_back\n\n\n#define Yes cout<<\"Yes\"<<endl\n#define No cout<<\"No\"<<endl\n#define YN {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}// if(a==b)YN;\n#define dame cout<<-1<<endl\n\n\n#define vc_unique(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define vc_rotate(v) rotate(v.begin(),v.begin()+1,v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(),v.end())\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n#define yu_qurid(x,y) ((x)*(x)+(y)*(y))//ユークリッド距離 sqrtはしてないなので注意\n#define mannhattan(x1,x2,y1,y2) (abs(x1-x2)+abs(y1-y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\n//if (regex_match(s, regex(\"\")))YN;//文字列sの判定を行う。コメントアウトを外して「\"\"」の中に判定する内容を入れる\n\n//-------------------------------\n\n\n\n\n//---------4.グリッド系----------\nvl dx = { 1,0,-1,0 };\n//vl dx={1,1,0,-1,-1,-1,0,1};\nvl dy = { 0,1,0,-1 };\n//vl dy={0,1,1,1,0,-1,-1,-1};\n\nbool out_grid(ll i, ll j, ll h, ll w) {//trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_kaiten(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//時計回りに90°回転\n//#define vvl_kaiten(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_kaiten(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//文字列版 時計回りに90°回転\n//#define vs_kaiten(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n\n#define vvl_tenti(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][i]=v[i][j];swap(nx,v);}\n#define vs_tenti(v) {ll n = size(v); vs nx(n, string(n,'.')); rep(i, n)rep(j, n)nx[j][i] = v[i][j]; swap(nx, v);}\n\n//回転、転置はn*nしか使えないことに注意\n\n//--------------------------------\n\nint main() {\n while(1){\n ll w, h;\n cin >> w >> h;\n if(w == 0 and h == 0) return 0;\n\n vvl x(h, vl(w-1));\n vvl y(h-1, vl(w));\n rep(i, 2*h-1){\n if(i%2 == 0) {\n rep(j, w-1) cin >> x[i/2][j];\n }\n else {\n rep(j, w) cin >> y[i/2][j];\n }\n }\n\n vvl g(h*w);\n rep(i, h)rep(j, w-1){\n if(x[i][j]) continue;\n g[w*i+j].pb(w*i+j+1);\n g[w*i+j+1].pb(w*i+j);\n }\n rep(i, h-1)rep(j, w){\n if(y[i][j]) continue;\n g[w*i+j].pb(w*(i+1)+j);\n g[w*(i+1)+j].pb(w*i+j);\n }\n\n vl dist(w*h);\n dist[0] = 1;\n queue<ll> q;\n q.push(0);\n while(q.size()){\n ll v = q.front(); q.pop();\n for(ll nex : g[v]){\n if(dist[nex] != 0) continue;\n dist[nex] = dist[v]+ 1;\n q.push(nex);\n }\n }\n\n cout << dist[h*w-1] << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3492, "score_of_the_acc": -0.0436, "final_rank": 14 }, { "submission_id": "aoj_1166_10660227", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main() {\n while(true) {\n int w, h;\n cin >> w >> h;\n if (w == 0 && h == 0) break;\n int dh[4] = {0, -1, 0, 1};\n int dw[4] = {1, 0, -1, 0};\n bool dir[35][35][4];\n \n const int INF = 1e9;\n \n vector<vector<int>> d(h, vector<int>(w, INF));\n \n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n for (int k = 0; k < 4; k++) dir[i][j][k] = false;\n }\n }\n \n for (int i = 0; i < 2 * h - 1; i++) {\n if (i % 2 == 0) {\n for (int j = 0; j < w - 1; j++) {\n int t;\n cin >> t;\n if (t == 0) {\n dir[i / 2][j][0] = true;\n dir[i / 2][j + 1][2] = true;\n }\n }\n }\n else {\n for (int j = 0; j < w; j++) {\n int t;\n cin >> t;\n if (t == 0) {\n dir[i / 2][j][3] = true;\n dir[(i / 2) + 1][j][1] = true;\n }\n }\n }\n }\n \n queue<pair<int, int>> Q;\n Q.push({0, 0});\n d[0][0] = 0;\n \n while (!Q.empty()) {\n auto p = Q.front();\n Q.pop();\n int h = p.first;\n int w = p.second;\n for (int i = 0; i < 4; i++) {\n if (!dir[h][w][i]) continue;\n int nh = h + dh[i];\n int nw = w + dw[i];\n if (d[nh][nw] > d[h][w] + 1) {\n d[nh][nw] = d[h][w] + 1;\n Q.push({nh, nw});\n }\n }\n }\n \n if (d[h - 1][w - 1] == INF) cout << 0 << endl;\n else cout << d[h - 1][w - 1] + 1 << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3392, "score_of_the_acc": -0.0333, "final_rank": 11 }, { "submission_id": "aoj_1166_10627981", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define all(a) a.begin(),a.end()\n#define reps(i, a, n) for (int i = (a); i < (int)(n); i++)\n#define rep(i, n) reps(i, 0, n)\n#define rreps(i, a, n) for (int i = (a); i > (int)(n); i--)\nconst long long mod = 1000000007;\nconst long long INF = 1e18;\nll myceil(ll a, ll b) {return (a+b-1)/b;}\n\ntemplate<typename T> inline bool chmax(T &a, T b) { return ((a < b) ? (a = b, true) : (false)); }\ntemplate<typename T> inline bool chmin(T &a, T b) { return ((a > b) ? (a = b, true) : (false)); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vector<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\ntemplate<typename T> void view(const vector<vector<T>>& vv){ for(const auto& v : vv){ view(v); } }\n\n\nint w,h;\n\nvoid solve() {\n vector<vector<int>> tate(h,vector<int> (w-1));\n vector<vector<int>> yoko(h-1,vector<int> (w));\n\n rep(i,2*h-1) {\n if (i%2) {\n rep(j,w) {\n cin >> yoko[i/2][j];\n }\n }\n else {\n rep(j,w-1) {\n cin >> tate[i/2][j];\n }\n }\n }\n\n vector<vector<int>> v(h*w);\n rep(i,h*w) {\n int x = i/w;\n int y = i%w;\n\n\n if (y != w-1) {\n if (tate[x][y] == 0) {\n v[i].push_back(i+1);\n v[i+1].push_back(i);\n }\n }\n \n if (x != h-1) {\n if (yoko[x][y] == 0) {\n v[i].push_back(i+w);\n v[i+w].push_back(i);\n }\n }\n }\n\n priority_queue<pair<int,int>,vector<pair<int,int>>,greater<pair<int,int>>> pq;\n vector<int> dist(h*w,10000000);\n dist[0] = 1;\n pq.push({1,0});\n\n while (!pq.empty()) {\n auto p = pq.top();\n pq.pop();\n\n int ct = p.first;\n int f = p.second;\n\n for (auto x : v[f]) {\n if (dist[x] > ct+1) {\n dist[x] = ct+1;\n pq.push({ct+1,x});\n }\n }\n }\n\n\n if (dist[h*w-1] == 10000000) {\n cout << 0 << endl;\n }\n else {\n cout << dist[h*w-1] << endl;\n }\n return;\n}\n\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n\n\n while (cin >> w >> h && w != 0) {\n solve();\n }\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3388, "score_of_the_acc": -0.0329, "final_rank": 9 }, { "submission_id": "aoj_1166_10614096", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing a2 = array<ll, 2>;\nusing a3 = array<ll, 3>;\n\ntemplate <typename A> void chmin(A &l, const A &r) {\n if(r < l)\n l = r;\n}\ntemplate <typename A> void chmax(A &l, const A &r) {\n if(l < r)\n l = r;\n}\n\nll mod = 998244353;\n\nvector<char> isprime;\nvoid init() {\n isprime.assign(1000005, 1);\n isprime[0] = 0;\n isprime[1] = 0;\n for(int i = 2; i < 1000005; i++) {\n if(isprime[i]) {\n for(int j = i * 2; j < 1000005; j += i) {\n isprime[j] = 0;\n }\n }\n }\n}\n\nll w, h;\nvoid input() { cin >> w >> h; }\nvoid solve() {\n vector<vector<ll>> g(h * w);\n for(int i = 0; i < 2 * h - 1; i++) {\n if(i % 2) {\n for(int j = 0; j < w; j++) {\n ll a;\n cin >> a;\n if(a == 0) {\n ll p = (i / 2) * w + j, q = (i / 2 + 1) * w + j;\n g[p].push_back(q);\n g[q].push_back(p);\n }\n }\n } else {\n for(int j = 0; j < w - 1; j++) {\n ll a;\n cin >> a;\n if(a == 0) {\n ll p = (i / 2) * w + j, q = (i / 2) * w + j + 1;\n g[p].push_back(q);\n g[q].push_back(p);\n }\n }\n }\n }\n\n vector<ll> dist(h * w, 1e18);\n dist[0] = 0;\n queue<ll> que;\n que.push(0);\n while(que.size()) {\n ll f = que.front();\n que.pop();\n for(auto &x : g[f]) {\n if(dist[x] > dist[f] + 1) {\n dist[x] = dist[f] + 1;\n que.push(x);\n }\n }\n }\n\n cout << (dist[h * w - 1] == 1e18 ? 0 : dist[h * w - 1]+1) << endl;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n\n // init();\n while(1) {\n input();\n if(h == 0)\n break;\n solve();\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3388, "score_of_the_acc": -0.0329, "final_rank": 9 }, { "submission_id": "aoj_1166_10580945", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nbool solve() {\n int H, W;\n cin >> W >> H;\n if (H == 0 && W == 0) return false;\n vector<vector<int>> R(H, vector<int>(W - 1));\n vector<vector<int>> D(H - 1, vector<int>(W));\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W - 1; j++) cin >> R[i][j];\n if (i < H - 1) {\n for (int j = 0; j < W; j++) cin >> D[i][j];\n }\n }\n vector<vector<int>> dist(H, vector<int>(W, 1 << 30));\n dist[0][0] = 1;\n queue<pair<int, int>> q;\n q.emplace(0, 0);\n while (q.size()) {\n auto [r, c] = q.front();\n q.pop();\n for (int d = 0; d < 4; d++) {\n int nr = r + vector<int>{0, 1, 0, -1, 0}[d];\n int nc = c + vector<int>{0, 1, 0, -1, 0}[d + 1];\n if (0 <= nr && nr < H && 0 <= nc && nc < W) {\n if (r == nr) {\n if (R[r][min(c, nc)] == 0) {\n if (dist[nr][nc] > dist[r][c] + 1) {\n dist[nr][nc] = dist[r][c] + 1;\n q.emplace(nr, nc);\n }\n }\n } else {\n if (D[min(r, nr)][c] == 0) {\n if (dist[nr][nc] > dist[r][c] + 1) {\n dist[nr][nc] = dist[r][c] + 1;\n q.emplace(nr, nc);\n }\n }\n }\n }\n }\n }\n int ans = dist.back().back();\n if (ans == 1 << 30) ans = 0;\n cout << ans << '\\n';\n return true;\n}\n\nint main() {\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3584, "score_of_the_acc": -0.053, "final_rank": 16 }, { "submission_id": "aoj_1166_10539349", "code_snippet": "#include<bits/stdc++.h>\n//入力系\n#define cinll(...) ll __VA_ARGS__; input(__VA_ARGS__);\n#define cinint(...) int __VA_ARGS__; input(__VA_ARGS__);\n#define cinstr(...) string __VA_ARGS__; input(__VA_ARGS__);\n#define cinchar(...) char __VA_ARGS__; input(__VA_ARGS__);\n#define cindouble(...) double __VA_ARGS__; input(__VA_ARGS__);\n#define cinvll(a,n) vll a(n); rep(i,n) cin>>a[i];\n#define cinvvll(a,n,m) vvll a(n,vll(m)); rep(i,n) rep(j,m) cin>>a[i][j];\n#define cinvs(a,n) vs a(n); rep(i,n) cin>>a[i];\n//繰り返し系\n#define rep1(n) for(ll i=0;i<n;i++)\n#define rep2(i,n) for(ll i=0;i<n;i++)\n#define rep3(i,a,n) for(ll i=a;i<n;i++)\n#define rep4(i,a,n,b) for(ll i=a;i<n;i+=b)\n#define overload4(a,b,c,d,e,...) e\n#define rep(...) overload4(__VA_ARGS__,rep4,rep3,rep2,rep1)(__VA_ARGS__)\n#define mrep1(n) for(ll i=n;i>=0;i--)\n#define mrep2(i,n) for(ll i=n;i>=0;i--)\n#define mrep3(i,n,a) for(ll i=n;i>=a;i--)\n#define mrep4(i,n,a,b) for(ll i=n;i>=a;i-=b)\n#define mrep(...) overload4(__VA_ARGS__,mrep4,mrep3,mrep2,mrep1)(__VA_ARGS__)\n//iterator系\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n//書くのが長いやつ\n#define fst first\n#define snd second\nusing namespace std;\n//型系\nusing ll = long long;\nusing vll = vector<long long>;\nusing vvll = vector<vector<long long>>;\nusing vi = vector<int>;\nusing vvi = vector<vector<int>>;\nusing vb = vector<bool>;\nusing vvb = vector<vector<bool>>;\nusing vc = vector<char>;\nusing vvc = vector<vector<char>>;\nusing vs = vector<string>;\nusing pll = pair<long long,long long>;\nusing sll = set<long long>;\nusing vsll = vector<set<long long>>;\nusing vpll = vector<pair<long long,long long>>;\nusing vvpll = vector<vector<pair<long long, long long>>>;\n#define vmll vector<mll>\n#define vvmll vector<vector<mll>>\n\n//const ll mod = 998244353LL;\nconst ll mod = 1000000007LL;\nconst ll inf = 1301001001001001000LL;\nconst double PI=3.1415926535897932384626433832795028841971;\n\n//表示\n#define overload1(a,b,NAME,...) NAME\n#define coutYesReturn() do {coutYes(); return 0; } while(0)\n#define coutYesReturnIf(a) do { if(a){ coutYesReturn(); }} while(0)\n#define coutNoReturn() do {coutNo(); return 0;} while(0)\n#define coutNoReturnIf(a) do {if(a){ coutNoReturn(); }} while(0)\n#define coutReturnIf(a,s) do{if(a){cout<<s<<endl; return 0;}}while(0)\ntemplate<typename... T>\nvoid coutll(T... a){ ((cout << a <<\" \"),...) << endl; }\nvoid coutvll(vll &a){ rep(i,a.size()) cout<<a[i]<<\" \"; cout<<endl; }\nvoid coutvll(string name, vll &a){ cout<<name<<\":\"; coutvll(a); }\nvoid coutvlln(vll &a){ rep(i,a.size()) cout<<a[i]<<endl; }\nvoid coutYes(){ cout<<\"Yes\"<<endl; }\nvoid coutNo(){ cout<<\"No\"<<endl; }\nvoid coutYesNo(bool a){ cout<<(a?\"Yes\":\"No\")<<endl; }\nvoid coutIf(bool a, string s, string t){ cout<<(a?s:t)<<endl; }\n//入力\ntemplate<class... T>\nvoid input(T&... a){\n (cin >> ... >> a);\n}\n//複数ソート\ntemplate<class... T>\nvoid sorts(vector<T>&... a){\n (sort(all(a)),...);\n}\ntemplate<typename T>\nT chmax(T &a, T b){ if(a < b) a = b; return a; }\ntemplate<typename T>\nT chmin(T &a, T b){ if(a > b) a = b; return a; }\n\n//縦0以上h未満、横0以上w未満の(i,j)の4近傍をとる\nvpll kinbo4(ll h,ll w, ll i,ll j){\n vpll ret;\n if(i-1 >= 0) ret.push_back({i-1,j});\n if(j-1 >= 0) ret.push_back({i,j-1});\n if(i+1 < h) ret.push_back({i+1,j});\n if(j+1 < w) ret.push_back({i,j+1});\n return ret;\n}\n\nint main(){\n while(true){\n cinll(w,h);\n if(w+h == 0) break;\n vvll nexts(h*w);\n rep(i,h*2-1){\n if(i%2 == 0){\n rep(j,w-1){\n cinll(t);\n if(t == 0){\n nexts[i/2*w + j].push_back(i/2*w + j+1);\n nexts[i/2*w + j+1].push_back(i/2*w + j);\n }\n }\n }\n else{\n rep(j,w){\n cinll(t);\n if(t == 0){\n nexts[i/2*w + j].push_back((i/2+1)*w + j);\n nexts[(i/2+1)*w + j].push_back(i/2*w + j);\n }\n }\n }\n }\n //型を入力\n queue<ll> q;\n \n //ここでスタート地点を入れてく\n vll d(h*w ,-1);\n q.push(0);\n d[0] = 0;\n \n while(!q.empty()){\n ll now = q.front();\n q.pop();\n \n //ここで次の奴らを追加していく\n for(ll next: nexts[now]) if(d[next] == -1){\n d[next] = d[now]+1;\n q.push(next);\n }\n }\n\n cout<<d[h*w-1]+1<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3440, "score_of_the_acc": -0.0382, "final_rank": 12 }, { "submission_id": "aoj_1166_10494971", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n// #include<atcoder/all>\n// using namespace atcoder;\n// if using this, use \"g++ *.cpp -I ~/atcoder/ac...\" to complile\n\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define rep(i, n) for (int i = 0; i < (n); i++)\nvector<int> dx = {0, 1, 0, -1};\nvector<int> dy = {1, 0, -1, 0};\nconst int IINF = 1e9;\nconst ll LINF = 1ll<<60; \n\n// main\nint main()\n{\n\twhile (1) {\n\t\tint h, w;\n\t\tcin >> w >> h;\n\t\t\n\t\tif (w == 0 && h == 0) break;\n\n\t\tvector<vector<vector<pair<int, int>>>> G(h, vector<vector<pair<int, int>>>(w));\n\t\trep(i, h) {\n\t\t\trep(j, w-1) {\n\t\t\t\tint k1; cin >> k1;\n\t\t\t\tif (k1 == 0) {\n\t\t\t\t\tG[i][j].push_back({i, j+1});\n\t\t\t\t\tG[i][j+1].push_back({i, j});\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t\tif (i == h-1) continue;\n\n\t\t\trep(j, w) {\n\t\t\t\tint k; cin >> k;\n\t\t\t\tif (k == 0) {\n\t\t\t\t\tG[i][j].push_back({i+1, j});\n\t\t\t\t\tG[i+1][j].push_back({i, j});\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tvector<vector<int>> dist(h, vector<int>(w, IINF));\n\t\tdist[0][0] = 0;\n\t\tqueue<pair<int, int>> que;\n\t\tque.push({0, 0});\n\n\t\twhile (!que.empty()) {\n\t\t\tauto [x, y] = que.front();\n\t\t\tque.pop();\n\n\t\t\tfor (auto [nx, ny]: G[x][y]) {\n\t\t\t\tif (dist[x][y]+1 < dist[nx][ny]) {\n\t\t\t\t\tdist[nx][ny] = dist[x][y]+1;\n\t\t\t\t\tque.push({nx, ny});\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif (dist[h-1][w-1] == IINF) {\n\t\t\tcout << 0 << \"\\n\";\n\t\t\tcontinue;\n\t\t}\n\t\tcout << dist[h-1][w-1]+1 << \"\\n\";\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3548, "score_of_the_acc": -0.0493, "final_rank": 15 }, { "submission_id": "aoj_1166_10485276", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nvoid bfs(vector<vector<int>> &mass, queue<int> &Q){\n vector<vector<int>> dr;\n int W, H;\n W = mass.at(0).size();\n H = mass.size();\n dr = {{-1, 0},\n {0, 1},\n {1, 0},\n {0, -1}};\n \n for(int i = 0; i < 4; i++){\n int dx, dy;\n dx = Q.front() % 100 + dr.at(i).at(1);\n dy = Q.front() / 100 + dr.at(i).at(0);\n //cout << dx << \" \" << dy;\n if(dx >= 0 && dx < W && dy >= 0 && dy < H){\n //cout << \"o\";\n if(mass.at(dy).at(dx) == 0 && mass.at(dy + dr.at(i).at(0)).at(dx + dr.at(i).at(1)) > mass.at(Q.front() / 100).at(Q.front() % 100) + 1){\n dy += dr.at(i).at(0);\n dx += dr.at(i).at(1);\n mass.at(dy).at(dx) = mass.at(Q.front() / 100).at(Q.front() % 100) + 1;\n Q.push(dy * 100 + dx);\n //cout << endl;\n }\n }\n //cout << endl;\n }\n}\n\nint main(){\n int w, h, mgn = 1;\n while(mgn == 1){\n cin >> w >> h;\n if(w == 0 && h == 0){\n return 0;\n }\n vector<vector<int>> hw(h * 2 - 1, vector<int>(w * 2 - 1, 100000));\n for(int i = 0; i < w - 1; i++){\n cin >> hw.at(0).at(i * 2 + 1);\n }\n for(int i = 0; i < h - 1; i++){\n for(int j = 0; j < w ; j++){//横の壁奇数行目偶数列目\n cin >> hw.at(i * 2 + 1).at(j * 2);\n }\n for(int j = 0; j < w - 1; j++){\n cin >> hw.at(i * 2 + 2).at(j * 2 + 1);\n }\n }\n /*for(int i = 0; i < 2 * h - 1; i++){\n for(int j = 0; j < 2 * w - 1; j++){\n cout << hw.at(i).at(j) << \" \";\n }\n cout << endl;\n }*/\n hw.at(0).at(0) = 1;\n queue<int> q;\n q.push(0);\n while(!q.empty()){\n bfs(hw, q);\n q.pop();\n }\n \n /*for(int i = 0; i < 2 * h - 1; i++){\n for(int j = 0; j < 2 * w - 1; j++){\n cout << hw.at(i).at(j) << \" \";\n }\n cout << endl;\n }*/\n if(hw.at(h * 2 - 2).at(w * 2 - 2) == 100000){\n cout << 0 << endl;\n }\n else{\n cout << hw.at(h * 2 - 2).at(w * 2 - 2) << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3164, "score_of_the_acc": -0.0099, "final_rank": 5 }, { "submission_id": "aoj_1166_10481571", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T> bool chmin(T& a, T b){if(a > b){a = b; return true;} return false;}\ntemplate<typename T> bool chmax(T& a, T b){if(a < b){a = b; return true;} return false;}\nconst long long INF = 1LL << 60;\nusing Graph = vector<vector<int>>;\nint gcd(int a, int b){\n if(a%b == 0) return b;\n else return gcd(b, a%b);\n}\nvector<int> dx = {1, 0, -1, 0};\nvector<int> dy = {0, 1, 0, -1};\nint main(){\n while(1){\n int w,h; cin >> w >> h;\n if(w==0 && h==0) return 0;\n vector<vector<int>> f(2*h-1, vector<int>(2*w-1,1e9));\n for(int i=0; i<2*h-1;i++){\n for(int j=0;j<2*w-1;j++){\n if(i%2==0){\n if(j%2==1) cin >> f[i][j];\n }else{\n if(j%2==0) cin >> f[i][j];\n }\n }\n }\n queue<pair<int,int>> q;\n q.push({0,0});\n f[0][0] = 1;\n while(!q.empty()){\n auto [x,y] = q.front();\n q.pop();\n rep(i,4){\n if(x+dx[i]<0||x+dx[i]>=2*h-1||y+dy[i]<0||y+dy[i]>=2*w-1) continue;\n if(f[x+dx[i]][y+dy[i]]) continue;\n int nx=x+dx[i]*2, ny=y+dy[i]*2;\n if(chmin(f[nx][ny], f[x][y]+1)){\n q.push({nx,ny});\n }\n }\n }\n if(f[2*h-2][2*w-2]==1e9) cout << 0 << endl;\n else cout << f[2*h-2][2*w-2] << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3368, "score_of_the_acc": -0.0308, "final_rank": 8 } ]
aoj_1167_cpp
Problem C: Pollock's conjecture The n th triangular number is defined as the sum of the first n positive integers. The n th tetrahedral number is defined as the sum of the first n triangular numbers. It is easy to show that the n th tetrahedral number is equal to n ( n +1)( n +2) ⁄ 6. For example, the 5th tetrahedral number is 1+(1+2)+(1+2+3)+(1+2+3+4)+(1+2+3+4+5) = 5×6×7 ⁄ 6 = 35. The first 5 triangular numbers 1, 3, 6, 10, 15 The first 5 tetrahedral numbers 1, 4, 10, 20, 35 In 1850, Sir Frederick Pollock, 1st Baronet, who was not a professional mathematician but a British lawyer and Tory (currently known as Conservative) politician, conjectured that every positive integer can be represented as the sum of at most five tetrahedral numbers. Here, a tetrahedral number may occur in the sum more than once and, in such a case, each occurrence is counted separately. The conjecture has been open for more than one and a half century. Your mission is to write a program to verify Pollock's conjecture for individual integers. Your program should make a calculation of the least number of tetrahedral numbers to represent each input integer as their sum. In addition, for some unknown reason, your program should make a similar calculation with only odd tetrahedral numbers available. For example, one can represent 40 as the sum of 2 tetrahedral numbers, 4×5×6 ⁄ 6 + 4×5×6 ⁄ 6, but 40 itself is not a tetrahedral number. One can represent 40 as the sum of 6 odd tetrahedral numbers, 5×6×7 ⁄ 6 + 1×2×3 ⁄ 6 + 1×2×3 ⁄ 6 + 1×2×3 ⁄ 6 + 1×2×3 ⁄ 6 + 1×2×3 ⁄ 6, but cannot represent as the sum of fewer odd tetrahedral numbers. Thus, your program should report 2 and 6 if 40 is given. Input The input is a sequence of lines each of which contains a single positive integer less than 10 6 . The end of the input is indicated by a line containing a single zero. Output For each input positive integer, output a line containing two integers separated by a space. The first integer should be the least number of tetrahedral numbers to represent the input integer as their sum. The second integer should be the least number of odd tetrahedral numbers to represent the input integer as their sum. No extra characters should appear in the output. Sample Input 40 14 5 165 120 103 106 139 0 Output for the Sample Input 2 6 2 14 2 5 1 1 1 18 5 35 4 4 3 37
[ { "submission_id": "aoj_1167_11043743", "code_snippet": "#include <bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#ifndef LOCAL\n#pragma GCC optimize(\"O3\")\n#endif\n#pragma GCC optimize(\"unroll-loops\")\n\n#ifdef ONLINE_JUDGE\n#include <boost/multiprecision/cpp_int.hpp>\n#include <atcoder/all>\n#endif\n#ifdef LOCAL\n#define GLIBCXX_DEBUG\n#define endl endl<<flush\n#else\n#define endl \"\\n\"\n#endif\nusing namespace std;using ll=long long;using ull=unsigned long long;using dl=long double;\n#define rep(i,n) for(ll i=0; i<(n); i++)\n#define rrep(i,n) for(ll i=1; i<=(n); i++)\n#define drep(i,n) for(ll i=(n)-1; i>=0; i--)\n#define xfor(i,s,e) for(ll i=(s); i<(e); i++)\n#define rxfor(i,s,e) for(ll i=(s); i<=(e); i++)\n#define dfor(i,s,e) for(ll i=(s)-1; i>=(e); i--)\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define chmax(x,y) x = max(x,y)\n#define chmin(x,y) x = min(x,y)\n#define popcnt(s) ll(__popcount<ull>(uint64_t(s)))\ntemplate<typename T>istream&operator>>(istream&is,pair<T,T>&v){is>>v.first>>v.second;return is;}\ntemplate<typename T>istream&operator>>(istream&is,vector<T>&v){for(auto&in:v)is>>in;return is;}\ntemplate<typename T, typename U>ostream&operator<<(ostream&os,pair<T,U>&v){os<<v.first<<\" \"<<v.second;return os;}\ntemplate<typename T>ostream&operator<<(ostream&os,vector<T>&v){for(auto&in:v)os<<in<<' ';return os;}\nll modpow(ll a, ll b, ll mod) {ll res = 1;while (b > 0) {if (b & 1) res = (res * a) % mod;a = (a * a) % mod;b >>= 1;}return res;}\nll powl(ll a, ll b) {ll res = 1;while (b > 0) {if (b & 1) res = (res * a);a = (a * a);b >>= 1;}return res;}\n#define pow2(a) (a)*(a)\n/*MOD MUST BE A PRIME NUMBER!!*/ll moddiv(const ll a, const ll b, const ll mod) {ll modinv = modpow(b, mod-2, mod);return (a * modinv) % mod;}\nconstexpr ll INF = 2e15;\nll nC2(const ll i){return i>2?i*(i-1)/2:0;}ll nC3(const ll i){return i>3?i*(i-1)*(i-2)/6:0;}ll nC4(const ll i){return i>4?i*(i-1)*(i-2)*(i-3)/24:0;}ll nC5(const ll i){return i>5?i*(i-1)*(i-2)*(i-3)*(i-4)/120:0;}ll nC6(const ll i){return i>6?i*(i-1)*(i-2)*(i-3)*(i-4)*(i-5)/720:0;}\nvoid warshall_floyd(vector<vector<ll>>& dist) {const ull n = dist.size();rep(k, n) rep(i, n) rep(j, n) {dist[i][j] = min(dist[i][j],dist[i][k] + dist[k][j]);}}\n#define YES {cout<<\"Yes\\n\";return;}\n#define NO {cout<<\"No\\n\";return;}\n#define yn YES else NO\n#ifdef ONLINE_JUDGE\nusing lll = boost::multiprecision::cpp_int;\n//using lll = boost::multiprecision::int128_t;\nusing namespace atcoder;\n//using mint = modint1000000007;\nusing mint = modint998244353;\n//using mint = modint; // custom mod\n//atcoder::modint::set_mod(m);\n// DSU == UnionFind\n#endif\n#define vc vector\nusing P = pair<ll, ll>;using vl = vc<ll>;using vb=vc<bool>;using vs=vc<string>;using vvl=vc<vl>;using vp=vc<P>;\ntemplate<typename T>void cs(vector<T>&v){xfor(i,1,v.size())v[i]+=v[i-1];}\n\nvl dx = {-1, 1, 0, 0, -1, 1, -1, 1};\nvl dy = {0, 0, 1, -1, -1, -1, 1, 1};\n\nconstexpr ll mod = 998244353;\n\nvoid solve() {\n vl pollocs(200);\n rrep(i, pollocs.size()) {\n pollocs[i-1] = i*(i+1)*(i+2)/6;\n }\n\n vl min_sums(1'000'000, INF), min_sums_odd(1'000'000, INF);\n min_sums[0] = min_sums_odd[0] = 0;\n\n for (ll v : pollocs) {\n if (v & 1) {\n // odds\n xfor(i, v, min_sums_odd.size()) {\n chmin(min_sums_odd[i], min_sums_odd[i-v]+1);\n }\n }\n\n // all\n xfor(i, v, min_sums.size()) {\n chmin(min_sums[i], min_sums[i-v]+1);\n }\n }\n\n ll i;\n while (true) {\n cin >> i;\n if (i == 0) break;\n cout << min_sums[i] << \" \" << min_sums_odd[i] << endl;\n }\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.tie(nullptr);\n cout << fixed << setprecision(50);\n\n ll n = 1;\n //cin >> n;\n while (n--) {\n solve();\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 19064, "score_of_the_acc": -0.5663, "final_rank": 16 }, { "submission_id": "aoj_1167_11026836", "code_snippet": "#include <climits>\n#include <iostream>\n#include <vector>\n\nusing namespace std;\n\nint main(){\n vector<int> T;\n T.push_back(0);\n vector<int> T_odd;\n T_odd.push_back(0);\n int t=1;\n int n=1;\n while(1){\n t = n * (n+1) * (n+2) / 6;\n if (t > 1000000) break;\n T.push_back(t);\n n++;\n if (t%2 == 0) continue;\n T_odd.push_back(t);\n }\n\n int T_NUM_MAX = T.size() - 1;\n vector<int> dp(1000001, INT_MAX);\n dp[0] = 0;\n\n // for (int v=1; v<5; v++){\n for (int v=1; v<=dp.size(); v++){\n for (int n=1; n<=T_NUM_MAX; n++){\n if (v-T[n] >= 0) dp[v] = min(dp[v-T[n]]+1, dp[v]);\n }\n }\n\n\n int T_ODD_NUM_MAX = T_odd.size() - 1;\n vector<int> dp_odd(1000001, INT_MAX);\n dp_odd[0] = 0;\n\n // for (int v=1; v<5; v++){\n for (int v=1; v<=dp_odd.size(); v++){\n for (int n=1; n<=T_ODD_NUM_MAX; n++){\n if (v-T_odd[n] >= 0) dp_odd[v] = min(dp_odd[v-T_odd[n]]+1, dp_odd[v]);\n }\n }\n\n\n\n int inputN;\n while(1){\n cin >> inputN;\n if (inputN == 0) break;\n cout << dp[inputN] << \" \" << dp_odd[inputN] << endl;\n // cout << dp[inputN][T_NUM_MAX] << \" \" << dp_odd[inputN][T_ODD_NUM_MAX] << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 10620, "score_of_the_acc": -0.0791, "final_rank": 8 }, { "submission_id": "aoj_1167_10966503", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, a, n) for (int i = a; i < n; ++i)\n#define rrep(i, a, n) for (int i = n - 1; i >= a; --i)\nusing ll = long long;\nusing ld = long double;\nusing pl = pair<ll, ll>;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\nusing vp = vector<pl>;\nusing vvp = vector<vp>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vs = vector<string>;\nusing vc = vector<char>;\nusing vvc = vector<vc>;\nusing vd = vector<ld>;\nusing vvd = vector<vd>;\nconst int mod = 1000000007;\nconst ll hashh = 2147483647;\n\nint main()\n{\n ll n = 1;\n vl k;\n vl ki;\n while ((n * (n + 1) * (n + 2)) / 6 < 2000000)\n {\n k.push_back((n * (n + 1) * (n + 2)) / 6);\n n++;\n if (k.back() % 2 == 1)\n {\n ki.push_back(k.back());\n }\n }\n vl dp1(1000010), dp2(1000010);\n vb flag1(1000010), flag2(1000010);\n queue<ll> q;\n rep(i, 0, k.size())\n {\n if (k[i] > 1000010)\n break;\n if (!flag1[k[i]])\n {\n dp1[k[i]] = 1;\n flag1[k[i]] = true;\n q.push(k[i]);\n }\n }\n while (!q.empty())\n {\n ll p = q.front();\n q.pop();\n rep(i, 0, k.size())\n {\n if (k[i] + p > 1000010)\n {\n break;\n }\n if (!flag1[k[i] + p])\n {\n dp1[k[i] + p] = dp1[p] + 1;\n flag1[k[i] + p] = true;\n q.push(k[i] + p);\n }\n }\n }\n\n rep(i, 0, ki.size())\n {\n if (ki[i] > 1000010)\n break;\n if (!flag2[ki[i]])\n {\n dp2[ki[i]] = 1;\n flag2[ki[i]] = true;\n q.push(ki[i]);\n }\n }\n while (!q.empty())\n {\n ll p = q.front();\n q.pop();\n rep(i, 0, ki.size())\n {\n if (ki[i] + p > 1000010)\n {\n break;\n }\n if (!flag2[ki[i] + p])\n {\n dp2[ki[i] + p] = dp2[p] + 1;\n flag2[ki[i] + p] = true;\n q.push(ki[i] + p);\n }\n }\n }\n while (1)\n {\n ll a;\n cin >> a;\n if (a == 0)\n break;\n cout << dp1[a] << ' ' << dp2[a] << endl;\n }\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 25940, "score_of_the_acc": -1.056, "final_rank": 19 }, { "submission_id": "aoj_1167_10937352", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define oke cout << \"Yes\" << '\\n';\n#define dame cout << \"No\" << '\\n';\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\nusing Hai2 = vector<vector<ll>>;\nusing HaiB = vector<vector<bool>>;\nusing Hai3 = vector<vector<vector<ll>>>;\n\nint main() {\n\tcout << fixed << setprecision(15);\n vector<ll>A(183);\n rep(i,183){\n A[i]=i*(i+1)*(i+2)/6;\n }\n vector<ll>DP(1e6,1e9);\n vector<ll>DPV(1e6,1e9);\n DP[0] = 0;\n DP[1] = 1;\n\n DPV[0] = 0;\n DPV[1] = 1;\n \n for(int i = 2; i < 1000000; i++){\n for(int k = 1; A[k] <= i; k++){\n DP[i] = min(DP[i], DP[i-A[k]]+1);\n if(A[k]%2 == 1){\n DPV[i] = min(DPV[i],DPV[i-A[k]]+1);\n }\n }\n }\n\n while(true){\n ll N;\n cin>>N;\n if(N==0){\n break;\n }\n cout<<DP[N]<<\" \"<<DPV[N]<<\"\\n\";\n }\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 18776, "score_of_the_acc": -0.5882, "final_rank": 17 }, { "submission_id": "aoj_1167_10923938", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint a[205],dp[1000005],f[1000005];\nint main(){\n\tint i,j;\n\tfor(i=1;i<=200;i++){\n\t\ta[i]=i*(i+1)*(i+2)/6;\n\t}\n\tint n;\n\tcin>>n;\n\twhile(n>0){\n\t\tmemset(dp,0x3f3f3f,sizeof(dp));\n\t\tmemset(f,0x3f3f3f,sizeof(f));\n\t\tdp[0]=0;\n\t\tf[0]=0;\n\t\tfor(i=1;i<=200;i++){\n\t\t\tfor(j=a[i];j<=n;j++){\n\t\t\t\tdp[j]=min(dp[j],dp[j-a[i]]+1);\n\t\t\t}\n\t\t}\n\t\tfor(i=1;i<=200;i++){\n\t\t\tif(a[i]%2){\n\t\t\t\tfor(j=a[i];j<=n;j++){\n\t\t\t\t\tf[j]=min(f[j],f[j-a[i]]+1);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout<<dp[n]<<\" \"<<f[n]<<endl;\n\t\tcin>>n;\n\t}\n}", "accuracy": 1, "time_ms": 3790, "memory_kb": 11244, "score_of_the_acc": -1.0732, "final_rank": 20 }, { "submission_id": "aoj_1167_10912754", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n// #include <atcoder/all>\n// using namespace atcoder;\nusing ll = long long;\nusing ld = long double;\nusing P = pair<ll,ll>;\nusing Board = vector<string>;\n// using mint = modint998244353;\nusing vl = vector<ll>;\nusing vvl = vector<vector<ll>>;\nusing vp = vector<P>;\nusing vvp = vector<vector<P>>;\nusing vb = vector<bool>;\nusing vvb = vector<vector<bool>>;\nusing vs = vector<string>;\nusing sl = set<ll>;\nusing Graph = vector<vector<ll>>;\nusing pq = priority_queue<ll>;\nusing pqg = priority_queue<ll, vector<ll>, greater<ll>>;\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define nall(a) a.begin(), a.end()\nconst ll INF = 1LL << 60;\n\nint main(){\n vl pollock;\n ll cnt = 1;\n while (true) {\n ll tmp = (cnt*(cnt+1)*(cnt+2))/6;\n if (tmp > 1000000) break;\n pollock.push_back(tmp);\n cnt++;\n }\n vl dp(1000010,INF), odd_dp(1000010,INF);\n dp[0] = odd_dp[0] = 0;\n rep(i,1000009)rep(j,(ll)pollock.size()) {\n if (pollock[j] > i) break;\n dp[i] = min(dp[i], dp[i-pollock[j]]+1);\n if (pollock[j]%2) odd_dp[i] = min(odd_dp[i], odd_dp[i-pollock[j]]+1);\n }\n ll q;\n while (cin >> q, q) {\n cout << dp[q] << \" \" << odd_dp[q] << endl;\n }\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 18560, "score_of_the_acc": -0.5639, "final_rank": 15 }, { "submission_id": "aoj_1167_10859690", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n vector<int> N(200,0);\n vector<int> N_odd;\n for (int i = 1; i < 200; ++i) {\n int curr = i * (i + 1) * (i + 2) / 6;\n N[i] = curr;\n if (curr % 2) N_odd.push_back(curr);\n }\n\n vector<int> dp1(pow(10,6) + 1, INT_MAX);\n dp1[0] = 0;\n for (int i = 0; i < pow(10,6) + 1; ++i) {\n for (int n: N) {\n if (i + n < pow(10, 6) + 1) dp1[i + n] = min(dp1[i + n], dp1[i] + 1);\n }\n }\n\n vector<int> dp2(pow(10,6) + 1, INT_MAX);\n dp2[0] = 0;\n for (int i = 0; i < pow(10,6) + 1; ++i) {\n for (int n: N_odd) {\n if (i + n < pow(10, 6) + 1) dp2[i + n] = min(dp2[i + n], dp2[i] + 1);\n }\n }\n\n vector<pair<int, int>> res_list;\n while (true) {\n int target; cin >> target;\n if (target == 0) break;\n res_list.push_back({dp1[target], dp2[target]});\n }\n for (auto res: res_list) cout << res.first << \" \" << res.second << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 10652, "score_of_the_acc": -0.0785, "final_rank": 7 }, { "submission_id": "aoj_1167_10855267", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n // 入力を一旦読み溜め(0で終了)\n vector<int> qs;\n while (true) {\n int x;\n if (!(cin >> x)) return 0;\n if (x == 0) break;\n qs.push_back(x);\n }\n if (qs.empty()) return 0;\n\n int MAXN = *max_element(qs.begin(), qs.end());\n\n // 正四面体数の列挙(<= MAXN)\n vector<int> tet, tet_odd;\n for (long long k = 1;; k++) {\n long long t = k * (k + 1) * (k + 2) / 6;\n if (t > MAXN) break;\n tet.push_back((int)t);\n if (t % 2 == 1) tet_odd.push_back((int)t);\n }\n\n const int INF = 1e9;\n\n // 通常版 DP(最小個数)\n vector<int> dp(MAXN + 1, INF);\n dp[0] = 0;\n for (int c : tet) {\n for (int v = c; v <= MAXN; v++) {\n if (dp[v - c] + 1 < dp[v]) dp[v] = dp[v - c] + 1;\n }\n }\n\n // 奇数正四面体数のみ DP\n vector<int> dp_odd(MAXN + 1, INF);\n dp_odd[0] = 0;\n for (int c : tet_odd) {\n for (int v = c; v <= MAXN; v++) {\n if (dp_odd[v - c] + 1 < dp_odd[v]) dp_odd[v] = dp_odd[v - c] + 1;\n }\n }\n\n // 出力\n for (int x : qs) {\n cout << dp[x] << ' ' << dp_odd[x] << '\\n';\n }\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 10484, "score_of_the_acc": -0.0572, "final_rank": 2 }, { "submission_id": "aoj_1167_10852787", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <limits>\n#define sz(x) int((x).size())\n#define phb push_back\nusing namespace std;\n\nconst int kMax = 1000000;\nconst int kInf = numeric_limits< int >::max() / 2;\n\nint N;\nvector< int > f1, f2;\n\nvoid prep();\nvoid solve();\n\nint main() {\n prep();\n while (cin >> N, N)\n cout << f1[N] << \" \" << f2[N] << \"\\n\";\n\n return 0;\n}\n\nvoid prep() {\n vector< int > s;\n\n s.phb(0);\n while (s.back() < kMax)\n s.phb(sz(s) * (sz(s) + 1) * (sz(s) + 2) / 6);\n\n f1.resize(kMax + 1, kInf);\n f2.resize(kMax + 1, kInf);\n\n f1[0] = f2[0] = 0;\n for (int i = 0; i < sz(f1); ++i)\n for (int j = 1; j < sz(s) && i + s[j] <= kMax; ++j) {\n f1[i + s[j]] = min(f1[i + s[j]], f1[i] + 1);\n if (s[j] % 2) f2[i + s[j]] = min(f2[i + s[j]], f2[i] + 1);\n }\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 10764, "score_of_the_acc": -0.0776, "final_rank": 6 }, { "submission_id": "aoj_1167_10852521", "code_snippet": "#include <iostream>\n#include <vector>\n#include <climits>\n\nusing namespace std;\n\nint main() {\n\n vector<int> tetra;\n vector<int> tetra_odd;\n for (int i = 1; i < 200; ++i) {\n tetra.push_back(i * (i + 1) * (i + 2) / 6);\n if ((i * (i + 1) * (i + 2) / 6) % 2 == 1) tetra_odd.push_back(i * (i + 1) * (i + 2) / 6);\n }\n\n vector<int> dp1(1000001, INT_MAX);\n dp1[0] = 0;\n for (int i = 1; i < dp1.size(); ++i) {\n for (int j = 0; j < tetra.size(); ++j) {\n if (tetra[j] > i) continue;\n dp1[i] = min(dp1[i], dp1[i - tetra[j]] + 1);\n }\n }\n vector<int> dp2(1000001, INT_MAX);\n dp2[0] = 0;\n for (int i = 1; i < dp2.size(); ++i) {\n for (int j = 0; j < tetra_odd.size(); ++j) {\n if (tetra_odd[j] > i) continue;\n dp2[i] = min(dp2[i], dp2[i - tetra_odd[j]] + 1);\n }\n }\n \n vector<pair<int,int>> res_list;\n while (true) {\n int N; cin >> N;\n if (N == 0) break;\n res_list.push_back({dp1[N], dp2[N]});\n }\n for (auto p: res_list) {\n cout << p.first << \" \" << p.second << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 10712, "score_of_the_acc": -0.0876, "final_rank": 11 }, { "submission_id": "aoj_1167_10852517", "code_snippet": "#include<iostream>\n#include<vector>\nusing namespace std;\n\nint main(){\n int i,j,k;\n int x,y;\n int inf = 1 << 10;\n int m[200]={};\n int memo[1000005]={};\n int memo2[1000005]={};\n vector <int> odd;\n fill(memo,memo+1000005,inf);\n fill(memo2,memo2+1000005,inf);\n for(i=1;i<201;i++) {\n m[i-1]=i*(i+1)*(i+2)/6;\n if(m[i-1]%2==1) odd.push_back(m[i-1]);\n }\n memo[0]=0;\n for(i=0;i<200;i++) {\n for(j=m[i];j<1000005;j++){\n memo[j]=min(memo[j],memo[j-m[i]]+1);\n }\n }\n memo2[0]=0;\n for(i=0;i<odd.size();i++) {\n for(j=odd[i];j<1000005;j++){\n memo2[j]=min(memo2[j],memo2[j-odd[i]]+1);\n }\n }\n int n;\n cin >> n;\n while(n!=0){\n cout << memo[n] << \" \" << memo2[n] << endl;\n cin >> n;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 11260, "score_of_the_acc": -0.0848, "final_rank": 10 }, { "submission_id": "aoj_1167_10846411", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nint INF=1001001;\n\nint main() {\n vector<int> tetra, odd;\n int x=1;\n while(x*(x+1)*(x+2)/6 <1000000){\n tetra.push_back(x*(x+1)*(x+2)/6);\n if(x*(x+1)*(x+2)/6 %2){\n odd.push_back(x*(x+1)*(x+2)/6);\n }\n x++;\n }\n int ts=tetra.size(), os=odd.size();\n vector<int> tdp(1000000,INF), odp(1000000,INF);\n tdp[0]=0, odp[0]=0;\n\n for(int i=1; i<1000000; i++){\n for(int j=0; j<ts; j++){\n if(i<tetra[j]) break;\n tdp[i]=min(tdp[i],tdp[i-tetra[j]]+1);\n }\n }\n\n for(int i=1; i<1000000; i++){\n for(int j=0; j<os; j++){\n if(i<odd[j]) break;\n odp[i]=min(odp[i],odp[i-odd[j]]+1);\n }\n }\n\n int N;\n while(cin >> N){\n if(N==0){\n break;\n }\n cout << tdp[N] << ' ' << odp[N] << '\\n';\n }\n \n}", "accuracy": 1, "time_ms": 130, "memory_kb": 10632, "score_of_the_acc": -0.0586, "final_rank": 3 }, { "submission_id": "aoj_1167_10810245", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int inf = (1 << 30);\nconst int m = 1000100;\n\nint main() {\n vector<int> dp(m, inf), o_dp(m, inf);\n dp[0] = 0;\n o_dp[0] = 0;\n int i = 1;\n while(true){\n int num = i * (i+1) * (i+2) / 6;\n if(num >= m) break;\n for(int j = num; j < m; j++){\n dp[j] = min(dp[j], dp[j-num]+1);\n if(num % 2 == 1){\n o_dp[j] = min(o_dp[j], o_dp[j-num]+1);\n }\n }\n i++;\n }\n \n int x;\n while(true){\n cin >> x;\n if(x == 0){\n break;\n }\n cout << dp[x] << \" \" << o_dp[x] << endl;\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 11152, "score_of_the_acc": -0.0754, "final_rank": 5 }, { "submission_id": "aoj_1167_10806156", "code_snippet": "#include <iostream>\n#include <vector>\n#include <set>\n#include <algorithm>\n#include <queue>\n#include <cmath>\nusing namespace std;\n\nconst int limit = 102;\nconst int LIMIT = limit*limit*limit;\nconst int INF = (1<<29);\n\nvoid dp(const vector<int> &reg_tetra, vector<int> &memo) {\n memo[0] = 0;\n queue<int> que;\n que.push(0);\n while (!que.empty()) {\n int now = que.front();\n que.pop();\n for (int j = 0; j < reg_tetra.size(); ++j) {\n if (now + reg_tetra[j] <= LIMIT) {\n if (memo[now+reg_tetra[j]] == INF) {\n memo[now + reg_tetra[j]] = memo[now]+1;\n que.push(now+reg_tetra[j]);\n }\n }\n else break;\n }\n }\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n vector<int> reg_tetra;\n vector<int> odd_reg_tetra;\n for (int i = 1; i*(i+1)*(i+2)/6 <= LIMIT; ++i) {\n int tet_num = i*(i+1)*(i+2)/6;\n reg_tetra.emplace_back(tet_num);\n if (tet_num % 2) odd_reg_tetra.emplace_back(tet_num);\n }\n\n vector<int> memo(LIMIT+1, INF);\n vector<int> odd_memo(LIMIT+1, INF);\n \n dp(reg_tetra, memo);\n dp(odd_reg_tetra, odd_memo);\n\n while(true) {\n int N;\n cin >> N;\n if (N == 0) break;\n cout << memo[N] << \" \" << odd_memo[N] << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 15236, "score_of_the_acc": -0.3943, "final_rank": 12 }, { "submission_id": "aoj_1167_10790692", "code_snippet": "#include <bits/stdc++.h>\n#define ll long long\n#define ld long double\nusing namespace std;\n\n\nint main(void){\n vector<int> tet,teto;\n vector<int> dp(1000010,1e9),dpo(1000010,1e9);\n int tmp = 1;\n int val = tmp*(tmp+1)*(tmp+2)/6;\n while(val <= 1e6){\n tet.push_back(val);\n if(val % 2 == 1){\n teto.push_back(val);\n }\n tmp++;\n val = tmp*(tmp+1)*(tmp+2)/6;\n }\n dp[0] = 0;\n for(int i = 0;i < tet.size();i++){\n for(int j = 0;j < 1e6;j++){\n if(j+1 >= tet[i]) dp[j+1] = min(dp[j+1],dp[j+1-tet[i]]+1);\n }\n }\n dpo[0] = 0;\n for(int i = 0;i < teto.size();i++){\n for(int j = 0;j < 1e6;j++){\n if(j+1 >= teto[i]) dpo[j+1] = min(dpo[j+1],dpo[j+1-teto[i]]+1);\n }\n }\n int n;\n while(true){\n cin >> n;\n if(n == 0) break;\n cout << dp[n] << \" \" << dpo[n] << endl;\n }\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 10688, "score_of_the_acc": -0.0648, "final_rank": 4 }, { "submission_id": "aoj_1167_10778433", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing ull = unsigned long long;\nusing vi = vector<int>;\nusing vvi = vector<vector<int>>;\nusing vl = vector<ll>;\nusing vvl = vector<vector<ll>>;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\n\n#define all(x) x.begin(), x.end()\n#define rall(x) x.rbegin(), x.rend()\n#define el '\\n'\n#define spa \" \"\n#define Yes cout << \"Yes\" << el\n#define No cout << \"No\" << el\n#define YES cout << \"YES\" << el\n#define NO cout << \"NO\" << el\n#define eps (1e-10)\n#define Equals(a,b) (fabs((a) - (b)) < eps )\n#define debug(x) cerr << #x << \" = \" << x << el\n\nconst double pi = 3.141592653589793238;\nconst int inf = 1073741823;\nconst ll infl = 1LL << 60;\nconst string ABC = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\nconst string abc = \"abcdefghijklmnopqrstuvwxyz\";\n\ntemplate<typename T1, typename T2>\nstd::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){\n os << \"{\" << p.first << \",\" << p.second << \"}\";\n return os;\n}\n\n// 配列の要素を空白区切りで出力 第二引数をtrueにすると改行区切り\ntemplate<typename T> inline void print_vec(const vector<T> &v, bool split_line=false) {\n if(v.empty()){\n cout << \"This vector is empty.\" << el;\n return;\n }\n constexpr bool isValue = is_integral<T>::value;\n for (int i = 0; i < (int)v.size(); i++) {\n if constexpr(isValue){\n if((v[i]==inf) || (v[i]==infl)) cout << 'x' << \" \\n\"[split_line || i+1==(int)v.size()];\n else cout << v[i] << \" \\n\"[split_line || i+1==(int)v.size()];\n }else cout << v[i] << \" \\n\"[split_line || i+1==(int)v.size()];\n }\n}\n\ntemplate<typename T1, typename T2> inline void print_vec(const vector<pair<T1,T2>> &v, bool split_line=false){\n if(v.empty()){\n cout << \"This vector is empty.\" << el;\n return;\n }\n for(int i = 0; i < (int)v.size(); i++){\n cout << '{';\n auto [a,b] = v[i];\n constexpr pair<bool,bool> isValue = {is_integral<T1>::value, is_integral<T2>::value};\n if constexpr(isValue.first){\n if(a==inf || a==infl) cout << \"x,\";\n else cout << a << \",\";\n }else cout << a << \",\";\n if constexpr(isValue.second){\n if(b==inf || b==infl) cout << \"x,\";\n else cout << b;\n }else cout << b;\n cout << \"}\" << \" \\n\"[split_line || i+1==(int)v.size()];\n }\n}\n\n/*===========================================================================================*/\n\n#define rep(i, m, n) for(ll i = m; i < (ll)n; ++i)\n\nvoid chmax(int &a, int b) {\n a = max(a, b);\n}\n\nvoid chmin(int &a, int b) {\n a = min(a, b);\n}\n\nconst int INF = 10000000;\nconst int MOD = 10000;\n\nint main() {\n vi pollock(210, 0);\n rep(i, 1, 210) pollock[i] = i*(i+1)*(i+2)/6;\n\n const int N = 1000000;\n vi dp(N+1, INF);\n vi dp_odd(N+1, INF);\n dp[1] = 1;\n dp_odd[1] = 1;\n rep(i, 1, N+1)rep(j, 1, 200) {\n int p = pollock[j];\n if (i == p) {\n dp[i] = 1;\n if (p % 2 == 1) {\n dp_odd[i] = 1;\n }\n }\n if (i+p <= N) {\n chmin(dp[i+p], dp[i]+1);\n if (p % 2 == 1) {\n chmin(dp_odd[i+p], dp_odd[i]+1);\n }\n }\n }\n\n while (true) {\n int n;\n cin >> n;\n if (n == 0) break;\n cout << dp[n] << spa << dp_odd[n] << el;\n }\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 10608, "score_of_the_acc": -0.0837, "final_rank": 9 }, { "submission_id": "aoj_1167_10746922", "code_snippet": "#include <iostream>\n#include <vector>\n#include <iomanip>\n#include <algorithm>\n#include <tuple>\n#include <set>\n#include <map>\n#include <bitset>\n#include <cmath>\n#include <deque>\n#include <queue>\n#include <stack>\n#include <cassert>\n#include <unordered_set>\n#include <unordered_map>\n#include <cmath>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define all(v) v.begin(), v.end()\n\nll llpow(ll a, ll t)\n{\n ll res = 1;\n rep(i, t) res *= a;\n return res;\n}\n\nll inf = std::numeric_limits<ll>::max();\n\nint main()\n{\n vector<ll> ns;\n ll maxn = 0;\n while (true)\n {\n ll n;\n cin >> n;\n maxn = max(maxn, n);\n if (!n)\n {\n break;\n }\n ns.push_back(n);\n }\n vector<ll> san;\n rep(i, 10e6)\n {\n if (!i)\n {\n san.push_back(1);\n continue;\n }\n san.push_back(san[i - 1] + i + 1);\n if (san[i] > 10e6)\n {\n break;\n }\n }\n vector<ll> yon;\n vector<ll> yonki;\n rep(i, 10e6)\n {\n if (!i)\n {\n yon.push_back(san[i]);\n if (san[i] % 2)\n {\n yonki.push_back(san[i]);\n }\n continue;\n }\n ll num = yon[i - 1] + san[i];\n yon.push_back(num);\n if (num % 2)\n {\n yonki.push_back(num);\n }\n if (num > 10e6)\n {\n break;\n }\n }\n ll yonsz = yon.size();\n ll yonkisz = yonki.size();\n vector<ll> dp1;\n vector<ll> dp2;\n rep(i, maxn + 1)\n {\n if (!i)\n {\n dp1.push_back(0);\n dp2.push_back(0);\n continue;\n }\n dp1.push_back(inf);\n dp2.push_back(inf);\n rep(j, yonsz)\n {\n if (yon[j] > i)\n {\n break;\n }\n dp1[i] = min(dp1[i], dp1[i - yon[j]] + 1);\n }\n rep(j, yonkisz)\n {\n if (yonki[j] > i)\n {\n break;\n }\n dp2[i] = min(dp2[i], dp2[i - yonki[j]] + 1);\n }\n }\n for (auto num : ns)\n {\n cout << dp1[num] << \" \" << dp2[num] << endl;\n }\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 18344, "score_of_the_acc": -0.5476, "final_rank": 13 }, { "submission_id": "aoj_1167_10740535", "code_snippet": "#include <stdio.h>\n#include <stack>\n#include <math.h>\nusing namespace std;\n\nint main(){\n int n;\n const int MAXN = 1000000;\n const int INF = 20000000;\n // テトラヘドロン数テーブル(183個)\n int table[183];\n for(int i = 0; i < 183; i++){\n table[i] = i*(i+1)*(i+2)/6;\n }\n\n // DP 配列\n int* dp = new int[MAXN];\n int* odd_dp = new int[MAXN];\n for(int i = 0; i < MAXN; i++){\n dp[i] = INF;\n odd_dp[i] = INF;\n }\n dp[0] = 0;\n odd_dp[0] = 0;\n\n // DP 前計算 (1 以上 MAXN-1 まで)\n for(int i = 1; i < MAXN; i++){\n // k < 183 を明示して範囲外アクセスを防ぐ\n for(int k = 1; k < 183 && table[k] <= i; k++){\n // 普通のテトラヘドロン数を使う遷移\n dp[i] = min(dp[i], dp[i - table[k]] + 1);\n // 奇数テトラヘドロン数だけを使う遷移\n if(table[k] % 2 == 1){\n odd_dp[i] = min(odd_dp[i], odd_dp[i - table[k]] + 1);\n }\n }\n }\n\n // 入力受け取り&出力\n while (scanf(\"%d\", &n) == 1 && n != 0) {\n printf(\"%d %d\\n\", dp[n], odd_dp[n]);\n }\n\n delete[] dp;\n delete[] odd_dp;\n return 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 10084, "score_of_the_acc": -0.04, "final_rank": 1 }, { "submission_id": "aoj_1167_10685369", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n//#include <atcoder/all>\n//using namespace atcoder;\n\n\ntemplate<typename T> using vc = vector<T>;//prioriy_queueに必要なのでここにこれ書いてます\ntemplate<typename T> using vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nusing ull = unsigned long long;\nll INF = 3e18;\ndouble pi = 3.14159265358979;\nusing ld = long double;\nusing bl = bool;\n//using mint = modint998244353;\n//using mint = modint1000000007;\n//using mint = modint;//使うときはコメントアウトを外す\n//mint::set_mod(m);//使うときはコメントアウトを外す\n\ntemplate<class T> using pq = priority_queue<T, vc<T>>;//大きい順\ntemplate<class T> using pq_g = priority_queue<T, vc<T>, greater<T>>;//小さい順\n//-----------------------------------\n\n\n\n//-------------2.配列系--------------\nusing vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>; using vvvvl = vv<vvl>;\nusing vs = vc<string>; using vvs = vv<string>; using vvvs = vv<vs>;\nusing vb = vc<bl>; using vvb = vv<bl>; using vvvb = vv<vb>;\nusing vld = vc<ld>; using vvld = vv<ld>; using vvvld = vv<vld>;\nusing pll = pair<ll, ll>;\n//using vmint = vc<mint>; using vvmint = vv<mint>; using vvvmint = vv<vmint>;\n\n#define rep(i,n) for(ll i = 0; i < (n); ++i)//↓でrepを使うので書いてます\ntemplate<class T>istream& operator>>(istream& i, vc<T>& v) { rep(j, size(v))i >> v[j]; return i; }\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n\n\n//--------3.コード短縮化とか---------\n#define rep(i,n) for(ll i = 0; i < (n); ++i)\n#define rrep(i,n) for(ll i = 1; i <= (n); ++i)\n#define drep(i,n) for(ll i = (n)-1; i >= 0; --i)\n\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n\n#define chmax(x,y) x = max(x,y)\n#define chmin(x,y) x = min(x,y)\n\n#define pb push_back\n#define eb emplace_back\n#define em emplace\n#define pob pop_back\n\n\n#define Yes cout<<\"Yes\"<<endl\n#define No cout<<\"No\"<<endl\n#define YN {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}// if(a==b)YN;\n#define dame cout<<-1<<endl\n\n\n#define vc_unique(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define vc_rotate(v) rotate(v.begin(),v.begin()+1,v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(),v.end())\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n#define yu_qurid(x,y) ((x)*(x)+(y)*(y))//ユークリッド距離 sqrtはしてないなので注意\n#define mannhattan(x1,x2,y1,y2) (abs(x1-x2)+abs(y1-y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\n//if (regex_match(s, regex(\"\")))YN;//文字列sの判定を行う。コメントアウトを外して「\"\"」の中に判定する内容を入れる\n\n//-------------------------------\n\n\n\n\n//---------4.グリッド系----------\nvl dx = { 1,0,-1,0 };\n//vl dx={1,1,0,-1,-1,-1,0,1};\nvl dy = { 0,1,0,-1 };\n//vl dy={0,1,1,1,0,-1,-1,-1};\n\nbool out_grid(ll i, ll j, ll h, ll w) {//trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_kaiten(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//時計回りに90°回転\n//#define vvl_kaiten(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_kaiten(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//文字列版 時計回りに90°回転\n//#define vs_kaiten(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n\n#define vvl_tenti(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][i]=v[i][j];swap(nx,v);}\n#define vs_tenti(v) {ll n = size(v); vs nx(n, string(n,'.')); rep(i, n)rep(j, n)nx[j][i] = v[i][j]; swap(nx, v);}\n\n//回転、転置はn*nしか使えないことに注意\n\n//--------------------------------\n\nint main() {\n const ll mx = 1000000;\n vl a;\n for(ll i = 1; i*(i+1)*(i+2)/6 < mx; i++){\n a.pb(i*(i+1)*(i+2)/6);\n }\n ll m = a.size();\n\n vl dp(mx, INF), odd_dp(mx, INF);\n dp[0] = odd_dp[0] = 0;\n rep(i, mx){\n rep(j, m){\n if(i+a[j] > mx) break;\n chmin(dp[i+a[j]], dp[i]+1);\n }\n }\n rep(i, mx){\n rep(j, m){\n if(i+a[j] > mx) break;\n if(a[j] % 2 == 0) continue;\n chmin(odd_dp[i+a[j]], odd_dp[i]+1);\n }\n }\n\n while(1){\n ll n; cin >> n;\n if(n == 0) break;\n \n cout << dp[n] << \" \" << odd_dp[n] << endl;\n }\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 18640, "score_of_the_acc": -0.5929, "final_rank": 18 }, { "submission_id": "aoj_1167_10681078", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<long long>;\nusing vs = vector<string>;\nusing vc = vector<char>;\nusing vb = vector<bool>;\nusing vpii = vector<pair<int, int>>;\nusing vpll = vector<pair<long long, long long>>;\nusing vvi = vector<vector<int>>;\nusing vvl = vector<vector<long long>>;\nusing vvc = vector<vector<char>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing pii = pair<int, int>;\nusing vvb = vector<vector<bool>>;\nusing Graph = vector<vector<ll>>;\nconst ll LINF = 1001002003004005006ll;\nconst int INF = 1001001001;\nconst int MOD = 998244353;\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep3(i, m, n) for (int i = (m); i < (int)(n); i++)\n#define rrep(i, m, n) for (int i = (m); i >= (int)(n); i--)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\nvi dx4 = {1, 0, -1, 0}, dy4 = {0, 1, 0, -1};\nvi dx8 = {1, 1, 1, 0, 0, -1, -1, -1}, dy8 = {1, 0, -1, 1, -1, 1, 0, -1};\n\nint main()\n{\n vl all, odd;\n ll i = 1;\n while (1)\n {\n ll num = i * (i + 1) * (i + 2) / 6;\n if (num > 1000000LL)\n {\n break;\n }\n all.push_back(num);\n if (num % 2 == 1)\n {\n odd.push_back(num);\n }\n i++;\n }\n vl dp_all(1000000 + 5, LINF);\n dp_all[0] = 0;\n\n for (auto x : all)\n {\n for (ll i = 0; i <= 1000000; i++)\n {\n if (i + x < 1000000 + 5)\n {\n dp_all[i + x] = min(dp_all[i + x], dp_all[i] + 1);\n }\n }\n }\n vl dp_odd(1000000 + 5, LINF);\n dp_odd[0] = 0;\n\n for (auto x : odd)\n {\n for (ll i = 0; i <= 1000000; i++)\n {\n if (i + x < 1000000 + 5)\n {\n dp_odd[i + x] = min(dp_odd[i + x], dp_odd[i] + 1);\n }\n }\n }\n\n while (1)\n {\n // 宣言・入力の受け取り\n ll n;\n cin >> n;\n // 終了条件\n if (n == 0)\n {\n break;\n }\n // 宣言・入力の受け取り\n\n // solve\n\n // 出力\n cout << dp_all[n] << ' ' << dp_odd[n] << '\\n';\n }\n return 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 18484, "score_of_the_acc": -0.5564, "final_rank": 14 } ]
aoj_1164_cpp
Problem F: Tighten Up! We have a flat panel with two holes. Pins are nailed on its surface. From the back of the panel, a string comes out through one of the holes to the surface. The string is then laid on the surface in a form of a polygonal chain, and goes out to the panel's back through the other hole. Initially, the string does not touch any pins. Figures F-1, F-2, and F-3 show three example layouts of holes, pins and strings. In each layout, white squares and circles denote holes and pins, respectively. A polygonal chain of solid segments denotes the string. Figure F-1: An example layout of holes, pins and a string Figure F-2: An example layout of holes, pins and a string Figure F-3: An example layout of holes, pins and a string When we tie a pair of equal weight stones to the both ends of the string, the stones slowly straighten the string until there is no loose part. The string eventually forms a different polygonal chain as it is obstructed by some of the pins. (There are also cases when the string is obstructed by no pins, though.) The string does not hook itself while being straightened. A fully tightened string thus draws a polygonal chain on the surface of the panel, whose vertices are the positions of some pins with the end vertices at the two holes. The layouts in Figures F-1, F-2, and F-3 result in the respective polygonal chains in Figures F-4, F-5, and F-6. Write a program that calculates the length of the tightened polygonal chain. Figure F-4: Tightened polygonal chains from the example in Figure F-1. Figure F-5: Tightened polygonal chains from the example in Figure F-2. Figure F-6: Tightened polygonal chains from the example in Figure F-3. Note that the strings, pins and holes are thin enough so that you can ignore their diameters. Input The input consists of multiple datasets, followed by a line containing two zeros separated by a space. Each dataset gives the initial shape of the string (i.e., the positions of holes and vertices) and the positions of pins in the following format. m n x 1 y 1 ... x l y l The first line has two integers m and n (2 ≤ m ≤ 100, 0 ≤ n ≤ 100), representing the number of vertices including two holes that give the initial string shape ( m ) and the number of pins ( n ). Each of the following l = m + n lines has two integers x i and y i (0 ≤ x i ≤ 1000, 0 ≤ y i ≤ 1000), representing a position P i = ( x i , y i ) on the surface of the panel. Positions P 1 , ..., P m give the initial shape of the string; i.e., the two holes are at P 1 and P m , and the string's shape is a polygonal chain whose vertices are P i ( i = 1, ..., m ), in this order. Positions P m +1 , ..., P m + n are the positions of the pins. Note that no two points are at the same position. No three points are exactly on a straight line. Output For each dataset, the length of the part of the tightened string that remains on the surface of the panel should be output in a line. No extra characters should appear in the ...(truncated)
[ { "submission_id": "aoj_1164_8550653", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct Point {\n double x, y;\n Point operator+(const Point p) const { return {x + p.x, y + p.y}; }\n double operator*(const Point p) const { return x * p.x + y * p.y; }\n Point operator-(const Point p) const { return {x - p.x, y - p.y}; }\n bool operator==(const Point p) const { return x == p.x && y == p.y; }\n Point rot_ccw(const double t) const {\n return {x * cos(t) - y * sin(t), x * sin(t) + y * cos(t)};\n }\n double cross(const Point p) const { return x * p.y - y * p.x; }\n Point scale(const double f) const { return {x * f, y * f}; }\n double dist(const Point p) const { return hypot(x - p.x, y - p.y); }\n double dist2(const Point p) const { return (*this - p) * (*this - p); }\n};\n\nstruct Segment {\n Point p, q;\n double length() const { return p.dist(q); }\n bool operator==(Segment s) const { return p == s.p && q == s.q; }\n\n pair<bool, Point> intersect_single_point(const Segment s) const {\n return {intersect(s), intersection_point(s)};\n }\n\n bool intersect(const Segment& s) const {\n return (orientation(p, q, s.p) * orientation(p, q, s.q) <= 0) &&\n (orientation(s.p, s.q, p) * orientation(s.p, s.q, q) <= 0);\n }\n\n private:\n Segment scale(const double f) const { return {p, p + (q - p).scale(f)}; }\n short orientation(const Point o, const Point a, const Point b) const {\n const double cross = (a - o).cross(b - o);\n return cross < 0 ? -1 : cross > 0;\n }\n\n Point intersection_point(const Segment& s) const {\n const double factor = (s.q - s.p).cross(p - s.p) / (q - p).cross(s.q - s.p);\n return scale(factor).q;\n }\n};\n\nint N, M;\nvector<Point> polyline;\nvector<Point> pins;\nvector<Segment> path;\n\nvector<vector<double>> memo;\n\nint find_furthest_path_idx(const Segment s, const int from_path_idx) {\n int i = from_path_idx;\n if (!s.intersect(path[i])) return -1;\n\n double prev_dist = DBL_MIN;\n\n for (; i < (int)path.size(); i++) {\n const auto [intersects, point] = s.intersect_single_point(path[i]);\n\n if (intersects && prev_dist <= s.p.dist2(point)) {\n prev_dist = s.p.dist2(point);\n } else {\n break;\n }\n }\n\n return i;\n}\n\ndouble dp(const int pin_idx, const int path_idx) {\n if (path_idx == -1) return DBL_MAX;\n if (path_idx == (int)path.size()) return pins[pin_idx].dist(polyline.back());\n if (memo[pin_idx][path_idx] > -1) return memo[pin_idx][path_idx];\n\n double res = DBL_MAX;\n\n for (int i = 0; i <= M; i++) {\n const Segment movement{pins[pin_idx], pins[i]};\n res = min(res, movement.length() + dp(i, find_furthest_path_idx(movement, path_idx)));\n }\n\n return memo[pin_idx][path_idx] = res;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n while (cin >> N >> M && N > 0) {\n polyline.resize(N);\n pins.resize(M);\n path.clear();\n for (Point& p : polyline) cin >> p.x >> p.y;\n for (Point& p : pins) cin >> p.x >> p.y;\n for (Point& p : polyline) p = p.rot_ccw(0.00001);\n for (Point& p : pins) p = p.rot_ccw(0.00001);\n\n for (int i = 0; i < N - 1; i++) {\n const Segment s{polyline[i], polyline[i + 1]};\n\n vector<pair<double, Segment>> intersections;\n\n for (const Point pin : pins) {\n const Segment above{pin, {pin.x, 2000}};\n const Segment below{pin, {pin.x, -2000}};\n const auto [intersects_above, point_above] = s.intersect_single_point(above);\n const auto [intersects_below, point_below] = s.intersect_single_point(below);\n\n if (intersects_above) intersections.emplace_back(s.p.dist2(point_above), above);\n if (intersects_below) intersections.emplace_back(s.p.dist2(point_below), below);\n }\n\n sort(intersections.begin(), intersections.end(),\n [](const auto a, const auto b) { return a.first < b.first; });\n\n for (const auto& [_, s] : intersections) {\n if (!path.empty() && path.back() == s) {\n path.pop_back();\n } else {\n path.push_back(s);\n }\n }\n }\n\n pins.push_back(polyline.back());\n pins.push_back(polyline.front());\n\n memo.assign(pins.size(), vector<double>(path.size(), -1));\n\n cout << fixed << setprecision(10) << dp(M + 1, 0) << endl;\n }\n}", "accuracy": 1, "time_ms": 3360, "memory_kb": 5296, "score_of_the_acc": -0.6287, "final_rank": 10 }, { "submission_id": "aoj_1164_7602016", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct Point {\n double x, y;\n Point operator+(const Point p) const { return {x + p.x, y + p.y}; }\n Point operator-(const Point p) const { return {x - p.x, y - p.y}; }\n bool operator==(const Point p) const { return x == p.x && y == p.y; }\n Point rot_ccw(const double t) const {\n return {x * cos(t) - y * sin(t), x * sin(t) + y * cos(t)};\n }\n double cross(const Point p) const { return x * p.y - y * p.x; }\n Point scale(const double f) const { return {x * f, y * f}; }\n double dist(const Point p) const { return hypot(x - p.x, y - p.y); }\n};\n\nstruct Segment {\n Point p, q;\n double length() const { return p.dist(q); }\n bool operator==(Segment s) const { return p == s.p && q == s.q; }\n\n pair<bool, Point> intersect_single_point(const Segment s) const {\n return {intersect(s), intersection_point(s)};\n }\n\n bool intersect(const Segment& s) const {\n return (orientation(p, q, s.p) * orientation(p, q, s.q) <= 0) &&\n (orientation(s.p, s.q, p) * orientation(s.p, s.q, q) <= 0);\n }\n\n private:\n Segment scale(const double f) const { return {p, p + (q - p).scale(f)}; }\n short orientation(const Point o, const Point a, const Point b) const {\n const double cross = (a - o).cross(b - o);\n return cross < 0 ? -1 : cross > 0;\n }\n\n Point intersection_point(const Segment& s) const {\n const double factor = (s.q - s.p).cross(p - s.p) / (q - p).cross(s.q - s.p);\n return scale(factor).q;\n }\n};\n\nint N, M;\nvector<Point> polyline;\nvector<Point> pins;\nvector<Segment> path;\n\nvector<vector<double>> memo;\n\nint find_furthest_path_idx(const Segment s, const int from_path_idx) {\n int i = from_path_idx;\n if (!s.intersect(path[i])) return -1;\n\n double prev_dist = DBL_MIN;\n\n for (; i < (int)path.size(); i++) {\n const auto [intersects, point] = s.intersect_single_point(path[i]);\n\n if (intersects && prev_dist <= s.p.dist(point)) {\n prev_dist = s.p.dist(point);\n } else {\n break;\n }\n }\n\n return i;\n}\n\ndouble dp(const int pin_idx, const int path_idx) {\n if (path_idx == -1) return DBL_MAX;\n if (path_idx == (int)path.size()) return pins[pin_idx].dist(polyline.back());\n if (memo[pin_idx][path_idx] > -1) return memo[pin_idx][path_idx];\n\n double res = DBL_MAX;\n\n for (int i = 0; i <= M; i++) {\n const Segment movement{pins[pin_idx], pins[i]};\n res = min(res, movement.length() + dp(i, find_furthest_path_idx(movement, path_idx)));\n }\n\n return memo[pin_idx][path_idx] = res;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n while (cin >> N >> M && N > 0) {\n polyline.resize(N);\n pins.resize(M);\n path.clear();\n for (Point& p : polyline) cin >> p.x >> p.y;\n for (Point& p : pins) cin >> p.x >> p.y;\n for (Point& p : polyline) p = p.rot_ccw(0.00001);\n for (Point& p : pins) p = p.rot_ccw(0.00001);\n\n for (int i = 0; i < N - 1; i++) {\n const Segment s{polyline[i], polyline[i + 1]};\n\n vector<pair<double, Segment>> intersections;\n\n for (const Point pin : pins) {\n const Segment above{pin, {pin.x, 2000}};\n const Segment below{pin, {pin.x, -2000}};\n const auto [intersects_above, point_above] = s.intersect_single_point(above);\n const auto [intersects_below, point_below] = s.intersect_single_point(below);\n\n if (intersects_above) intersections.emplace_back(s.p.dist(point_above), above);\n if (intersects_below) intersections.emplace_back(s.p.dist(point_below), below);\n }\n\n sort(intersections.begin(), intersections.end(),\n [](const auto a, const auto b) { return a.first < b.first; });\n\n for (const auto& [_, s] : intersections) {\n if (!path.empty() && path.back() == s) {\n path.pop_back();\n } else {\n path.push_back(s);\n }\n }\n }\n\n pins.push_back(polyline.back());\n pins.push_back(polyline.front());\n\n memo.assign(pins.size(), vector<double>(path.size(), -1));\n\n cout << fixed << setprecision(10) << dp(M + 1, 0) << endl;\n }\n}", "accuracy": 1, "time_ms": 5200, "memory_kb": 5416, "score_of_the_acc": -0.9459, "final_rank": 14 }, { "submission_id": "aoj_1164_7601857", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// TODO: Add to index (DP and perhaps geo/misc). Change .at() to []\n// Refactor a bit more, some names are bad.\n// TODO: Create folder for Aizu.\n\nstruct Point {\n double x, y;\n Point operator+(const Point p) const { return {x + p.x, y + p.y}; }\n Point operator-(const Point p) const { return {x - p.x, y - p.y}; }\n bool operator==(const Point p) const { return x == p.x && y == p.y; }\n Point rot_ccw(const double t) const {\n return {x * cos(t) - y * sin(t), x * sin(t) + y * cos(t)};\n }\n double cross(const Point p) const { return x * p.y - y * p.x; }\n Point scale(const double f) const { return {x * f, y * f}; }\n double dist(const Point p) const { return hypot(x - p.x, y - p.y); }\n};\n\nstruct Segment {\n Point p, q;\n double length() const { return p.dist(q); }\n bool operator==(Segment s) const { return p == s.p && q == s.q; }\n\n pair<bool, Point> intersect_single_point(const Segment s) const {\n return {intersect(s), intersection_point(s)};\n }\n\n bool intersect(const Segment& s) const {\n return (orientation(p, q, s.p) * orientation(p, q, s.q) <= 0) &&\n (orientation(s.p, s.q, p) * orientation(s.p, s.q, q) <= 0);\n }\n\n private:\n Segment scale(const double f) const { return {p, p + (q - p).scale(f)}; }\n short orientation(const Point o, const Point a, const Point b) const {\n const double cross = (a - o).cross(b - o);\n return cross < 0 ? -1 : cross > 0;\n }\n\n Point intersection_point(const Segment& s) const {\n const double factor = (s.q - s.p).cross(p - s.p) / (q - p).cross(s.q - s.p);\n return scale(factor).q;\n }\n};\n\nint N, M;\nvector<Point> polyline;\nvector<Point> pins;\nvector<Segment> path;\n\nvector<vector<double>> memo;\n\nint find_last_path_idx(const Segment s, const int from_path_idx) {\n int i = from_path_idx;\n if (!s.intersect(path.at(i))) return -1;\n\n double prev_dist = -1e9;\n\n for (; i < (int)path.size(); i++) {\n const auto [intersects, point] = s.intersect_single_point(path[i]);\n\n if (intersects && prev_dist <= s.p.dist(point)) {\n prev_dist = s.p.dist(point);\n } else {\n break;\n }\n }\n\n return i;\n}\n\ndouble dp(const int pin_idx, const int path_idx) {\n if (path_idx == -1) return 1e8;\n // TODO: This shit is weird. Should be able to return 0 if the previous\n // \"movement\" (Segment) was from a pin to the last hole.\n if (path_idx == (int)path.size()) return pins.at(pin_idx).dist(polyline.back());\n if (memo[pin_idx][path_idx] > -1) return memo[pin_idx][path_idx];\n\n double res = 1e8;\n\n for (int i = 0; i <= M; i++) {\n const Segment movement{pins.at(pin_idx), pins.at(i)};\n res = min(res, movement.length() + dp(i, find_last_path_idx(movement, path_idx)));\n }\n\n return memo[pin_idx][path_idx] = res;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n while (cin >> N >> M && N > 0) {\n polyline.resize(N);\n pins.resize(M);\n path.clear();\n for (Point& p : polyline) cin >> p.x >> p.y;\n for (Point& p : pins) cin >> p.x >> p.y;\n for (Point& p : polyline) p = p.rot_ccw(0.00001);\n for (Point& p : pins) p = p.rot_ccw(0.00001);\n\n for (int i = 0; i < N - 1; i++) {\n const Segment s{polyline[i], polyline[i + 1]};\n\n vector<pair<double, Segment>> intersections;\n\n for (const Point pin : pins) {\n const Segment above{pin, {pin.x, 2000}};\n const Segment below{pin, {pin.x, -2000}};\n const auto [intersects_above, point_above] = s.intersect_single_point(above);\n const auto [intersects_below, point_below] = s.intersect_single_point(below);\n\n if (intersects_above) intersections.emplace_back(s.p.dist(point_above), above);\n if (intersects_below) intersections.emplace_back(s.p.dist(point_below), below);\n }\n\n sort(intersections.begin(), intersections.end(),\n [](const auto a, const auto b) { return a.first < b.first; });\n\n for (const auto& [_, s] : intersections) {\n if (!path.empty() && path.back() == s) {\n path.pop_back();\n } else {\n path.push_back(s);\n }\n }\n }\n\n pins.push_back(polyline.back());\n pins.push_back(polyline.front());\n\n memo.assign(pins.size(), vector<double>(path.size(), -1));\n\n cout << fixed << setprecision(10) << dp(M + 1, 0) << endl;\n }\n}", "accuracy": 1, "time_ms": 5280, "memory_kb": 5472, "score_of_the_acc": -0.9604, "final_rank": 15 }, { "submission_id": "aoj_1164_7598104", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// TODO: Add to index (DP and perhaps geo/misc). Change .at() to []\n// Refactor a bit more, some names are bad.\n// TODO: Create folder for Aizu.\n\nstruct Point {\n double x, y;\n Point operator+(const Point p) const { return {x + p.x, y + p.y}; }\n Point operator-(const Point p) const { return {x - p.x, y - p.y}; }\n bool operator==(const Point p) const { return x == p.x && y == p.y; }\n Point rot_ccw(const double t) const {\n return {x * cos(t) - y * sin(t), x * sin(t) + y * cos(t)};\n }\n double cross(const Point p) const { return x * p.y - y * p.x; }\n Point scale(const double f) const { return {x * f, y * f}; }\n double dist(const Point p) const { return hypot(x - p.x, y - p.y); }\n};\n\nstruct Segment {\n Point p, q;\n Segment scale(const double f) const { return {p, p + (q - p).scale(f)}; }\n double length() const { return p.dist(q); }\n bool operator==(Segment s) const { return p == s.p && q == s.q; }\n\n pair<bool, Point> intersect_single_point(const Segment s) const {\n return intersect(s) ? make_pair(true, intersection_point(s))\n : make_pair(false, Point{});\n }\n\n bool intersect(const Segment& s) const {\n return (orientation(p, q, s.p) * orientation(p, q, s.q) <= 0) &&\n (orientation(s.p, s.q, p) * orientation(s.p, s.q, q) <= 0);\n }\n\n private:\n short orientation(const Point o, const Point a, const Point b) const {\n const double cross = (a - o).cross(b - o);\n return cross < 0 ? -1 : cross > 0;\n }\n\n Point intersection_point(const Segment& s) const {\n const double factor = (s.q - s.p).cross(p - s.p) / (q - p).cross(s.q - s.p);\n return scale(factor).q;\n }\n};\n\nint N, M;\nvector<Point> polyline;\nvector<Point> pins;\nvector<Segment> path;\n\nvector<vector<double>> memo;\n\nint find_last_path_idx(const Segment s, const int from_path_idx) {\n int i = from_path_idx;\n if (!s.intersect(path.at(i))) return -1;\n\n double prev_dist = -1e9;\n\n for (; i < (int)path.size(); i++) {\n const auto [intersects, point] = s.intersect_single_point(path[i]);\n\n if (intersects && prev_dist <= s.p.dist(point)) {\n prev_dist = s.p.dist(point);\n } else {\n break;\n }\n }\n\n return i;\n}\n\ndouble dp(const int curr_idx, const int path_idx) {\n if (path_idx == -1) return 1e8;\n // TODO: This shit is weird. Should be able to return 0 if the previous\n // \"movement\" (Segment) was from a pin to the last hole.\n if (path_idx == (int)path.size()) return pins.at(curr_idx).dist(polyline.back());\n if (memo[curr_idx][path_idx] > -1) return memo[curr_idx][path_idx];\n\n double res = 1e8;\n\n for (int i = 0; i <= M; i++) {\n const Segment movement{pins.at(curr_idx), pins.at(i)};\n res = min(res, movement.length() + dp(i, find_last_path_idx(movement, path_idx)));\n }\n\n return memo[curr_idx][path_idx] = res;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n while (cin >> N >> M && N > 0) {\n polyline.resize(N);\n pins.resize(M);\n for (Point& p : polyline) cin >> p.x >> p.y;\n for (Point& p : pins) cin >> p.x >> p.y;\n for (Point& p : polyline) p = p.rot_ccw(0.00001);\n for (Point& p : pins) p = p.rot_ccw(0.00001);\n\n vector<Segment> segments;\n path.clear();\n\n for (Point p : pins) {\n segments.push_back({p, {p.x, 2000}});\n segments.push_back({p, {p.x, -2000}});\n }\n\n for (int i = 0; i < N - 1; i++) {\n const Segment s{polyline[i], polyline[i + 1]};\n\n vector<pair<double, Segment>> intersections;\n\n for (const Segment r : segments) {\n const auto [intersects, point] = s.intersect_single_point(r);\n\n if (!intersects) continue;\n intersections.emplace_back(s.p.dist(point), r);\n }\n\n sort(intersections.begin(), intersections.end(),\n [](const auto a, const auto b) { return a.first < b.first; });\n\n for (const auto& [_, seg] : intersections) {\n if (!path.empty() && path.back() == seg) {\n path.pop_back();\n } else {\n path.push_back(seg);\n }\n }\n }\n\n pins.push_back(polyline.back());\n pins.push_back(polyline.front());\n\n memo.assign(pins.size(), vector<double>(path.size(), -1));\n\n cout << fixed << setprecision(10) << dp(M + 1, 0) << endl;\n }\n}", "accuracy": 1, "time_ms": 5170, "memory_kb": 5324, "score_of_the_acc": -0.9395, "final_rank": 13 }, { "submission_id": "aoj_1164_7598102", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// TODO: Add to index (DP and perhaps geo/misc). Change .at() to []\n// Refactor a bit more, some names are bad.\n// TODO: Create folder for Aizu.\n\nstruct Point {\n double x, y;\n Point operator+(const Point p) const { return {x + p.x, y + p.y}; }\n Point operator-(const Point p) const { return {x - p.x, y - p.y}; }\n bool operator==(const Point p) const { return x == p.x && y == p.y; }\n Point rot_ccw(const double t) const {\n return {x * cos(t) - y * sin(t), x * sin(t) + y * cos(t)};\n }\n double cross(const Point p) const { return x * p.y - y * p.x; }\n Point scale(const double f) const { return {x * f, y * f}; }\n double dist(const Point p) const { return hypot(x - p.x, y - p.y); }\n};\n\nstruct Segment {\n Point p, q;\n Segment scale(const double f) const { return {p, p + (q - p).scale(f)}; }\n double length() const { return p.dist(q); }\n bool operator==(Segment s) const { return p == s.p && q == s.q; }\n\n pair<bool, Point> intersect_single_point(const Segment s) const {\n return intersect(s) ? make_pair(true, intersection_point(s))\n : make_pair(false, Point{});\n }\n\n bool intersect(const Segment& s) const {\n return (orientation(p, q, s.p) * orientation(p, q, s.q) <= 0) &&\n (orientation(s.p, s.q, p) * orientation(s.p, s.q, q) <= 0);\n }\n\n private:\n short orientation(const Point o, const Point a, const Point b) const {\n const double cross = (a - o).cross(b - o);\n return cross < 0 ? -1 : cross > 0;\n }\n\n Point intersection_point(const Segment& s) const {\n const double factor = (s.q - s.p).cross(p - s.p) / (q - p).cross(s.q - s.p);\n return scale(factor).q;\n }\n};\n\nint N, M;\nvector<Point> polyline;\nvector<Point> pins;\nvector<Segment> path;\n\n// double memo[107][10007];\n// bool ok[107][10007];\nunordered_map<int, double> memo;\n\nint find_last_path_idx(const Segment s, const int from_path_idx) {\n int i = from_path_idx;\n if (!s.intersect(path.at(i))) return -1;\n\n double prev_dist = -1e9;\n\n for (; i < (int)path.size(); i++) {\n const auto [intersects, point] = s.intersect_single_point(path[i]);\n\n if (intersects && prev_dist <= s.p.dist(point)) {\n prev_dist = s.p.dist(point);\n } else {\n break;\n }\n }\n\n return i;\n}\n\ndouble dp(const int curr_idx, const int path_idx) {\n if (path_idx == -1) return 1e8;\n // TODO: This shit is weird. Should be able to return 0 if the previous\n // \"movement\" (Segment) was from a pin to the last hole.\n if (path_idx == (int)path.size()) return pins.at(curr_idx).dist(polyline.back());\n if (memo.count(curr_idx + 10000 * path_idx)) return memo[curr_idx + 10000 * path_idx];\n\n double res = 1e8;\n\n for (int i = 0; i <= M; i++) {\n const Segment movement{pins.at(curr_idx), pins.at(i)};\n res = min(res, movement.length() + dp(i, find_last_path_idx(movement, path_idx)));\n }\n\n return memo[curr_idx + 10000 * path_idx] = res;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n while (cin >> N >> M && N > 0) {\n // memset(ok, 0, sizeof ok);\n memo.clear();\n polyline.resize(N);\n pins.resize(M);\n for (Point& p : polyline) cin >> p.x >> p.y;\n for (Point& p : pins) cin >> p.x >> p.y;\n for (Point& p : polyline) p = p.rot_ccw(0.00001);\n for (Point& p : pins) p = p.rot_ccw(0.00001);\n\n vector<Segment> segments;\n path.clear();\n\n for (Point p : pins) {\n segments.push_back({p, {p.x, 2000}});\n segments.push_back({p, {p.x, -2000}});\n }\n\n for (int i = 0; i < N - 1; i++) {\n const Segment s{polyline[i], polyline[i + 1]};\n\n vector<pair<double, Segment>> intersections;\n\n for (const Segment r : segments) {\n const auto [intersects, point] = s.intersect_single_point(r);\n\n if (!intersects) continue;\n intersections.emplace_back(s.p.dist(point), r);\n }\n\n sort(intersections.begin(), intersections.end(),\n [](const auto a, const auto b) { return a.first < b.first; });\n\n for (const auto& [_, seg] : intersections) {\n if (!path.empty() && path.back() == seg) {\n path.pop_back();\n } else {\n path.push_back(seg);\n }\n }\n }\n\n pins.push_back(polyline.back());\n pins.push_back(polyline.front());\n\n cout << fixed << setprecision(10) << dp(M + 1, 0) << endl;\n }\n}", "accuracy": 1, "time_ms": 5840, "memory_kb": 9480, "score_of_the_acc": -1.1114, "final_rank": 20 }, { "submission_id": "aoj_1164_7598095", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// TODO: Add to index (DP and perhaps geo/misc). Change .at() to []\n// Refactor a bit more, some names are bad.\n// TODO: Create folder for Aizu.\n\nstruct Point {\n double x, y;\n Point operator+(const Point p) const { return {x + p.x, y + p.y}; }\n Point operator-(const Point p) const { return {x - p.x, y - p.y}; }\n bool operator==(const Point p) const { return x == p.x && y == p.y; }\n Point rot_ccw(const double t) const {\n return {x * cos(t) - y * sin(t), x * sin(t) + y * cos(t)};\n }\n double cross(const Point p) const { return x * p.y - y * p.x; }\n Point scale(const double f) const { return {x * f, y * f}; }\n double dist(const Point p) const { return hypot(x - p.x, y - p.y); }\n};\n\nstruct Segment {\n Point p, q;\n Segment scale(const double f) const { return {p, p + (q - p).scale(f)}; }\n double length() const { return p.dist(q); }\n bool operator==(Segment s) const { return p == s.p && q == s.q; }\n\n pair<bool, Point> intersect_single_point(const Segment s) const {\n return intersect(s) ? make_pair(true, intersection_point(s))\n : make_pair(false, Point{});\n }\n\n bool intersect(const Segment& s) const {\n return (orientation(p, q, s.p) * orientation(p, q, s.q) <= 0) &&\n (orientation(s.p, s.q, p) * orientation(s.p, s.q, q) <= 0);\n }\n\n private:\n short orientation(const Point o, const Point a, const Point b) const {\n const double cross = (a - o).cross(b - o);\n return cross < 0 ? -1 : cross > 0;\n }\n\n Point intersection_point(const Segment& s) const {\n const double factor = (s.q - s.p).cross(p - s.p) / (q - p).cross(s.q - s.p);\n return scale(factor).q;\n }\n};\n\nint N, M;\nvector<Point> polyline;\nvector<Point> pins;\nvector<Segment> path;\n\ndouble memo[107][10007];\nbool ok[107][10007];\n\nint find_last_path_idx(const Segment s, const int from_path_idx) {\n int i = from_path_idx;\n if (!s.intersect(path.at(i))) return -1;\n\n double prev_dist = -1e9;\n\n for (; i < (int)path.size(); i++) {\n const auto [intersects, point] = s.intersect_single_point(path[i]);\n\n if (intersects && prev_dist <= s.p.dist(point)) {\n prev_dist = s.p.dist(point);\n } else {\n break;\n }\n }\n\n return i;\n}\n\ndouble dp(const int curr_idx, const int path_idx) {\n if (path_idx == -1) return 1e8;\n // TODO: This shit is weird. Should be able to return 0 if the previous\n // \"movement\" (Segment) was from a pin to the last hole.\n if (path_idx == (int)path.size()) return pins.at(curr_idx).dist(polyline.back());\n if (ok[curr_idx][path_idx]) return memo[curr_idx][path_idx];\n\n double res = 1e8;\n\n for (int i = 0; i <= M; i++) {\n const Segment movement{pins.at(curr_idx), pins.at(i)};\n res = min(res, movement.length() + dp(i, find_last_path_idx(movement, path_idx)));\n }\n\n ok[curr_idx][path_idx] = true;\n return memo[curr_idx][path_idx] = res;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n while (cin >> N >> M && N > 0) {\n memset(ok, 0, sizeof ok);\n polyline.resize(N);\n pins.resize(M);\n for (Point& p : polyline) cin >> p.x >> p.y;\n for (Point& p : pins) cin >> p.x >> p.y;\n for (Point& p : polyline) p = p.rot_ccw(0.00001);\n for (Point& p : pins) p = p.rot_ccw(0.00001);\n\n vector<Segment> segments;\n path.clear();\n\n for (Point p : pins) {\n segments.push_back({p, {p.x, 2000}});\n segments.push_back({p, {p.x, -2000}});\n }\n\n for (int i = 0; i < N - 1; i++) {\n const Segment s{polyline[i], polyline[i + 1]};\n\n vector<pair<double, Segment>> intersections;\n\n for (const Segment r : segments) {\n const auto [intersects, point] = s.intersect_single_point(r);\n\n if (!intersects) continue;\n intersections.emplace_back(s.p.dist(point), r);\n }\n\n sort(intersections.begin(), intersections.end(),\n [](const auto a, const auto b) { return a.first < b.first; });\n\n for (const auto& [_, seg] : intersections) {\n if (!path.empty() && path.back() == seg) {\n path.pop_back();\n } else {\n path.push_back(seg);\n }\n }\n }\n\n pins.push_back(polyline.back());\n pins.push_back(polyline.front());\n\n cout << fixed << setprecision(10) << dp(M + 1, 0) << endl;\n }\n}", "accuracy": 1, "time_ms": 5180, "memory_kb": 11400, "score_of_the_acc": -1.0245, "final_rank": 17 }, { "submission_id": "aoj_1164_7598091", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct Point {\n double x, y;\n Point operator+(const Point p) const { return {x + p.x, y + p.y}; }\n Point operator-(const Point p) const { return {x - p.x, y - p.y}; }\n bool operator==(const Point p) const { return x == p.x && y == p.y; }\n Point rot_ccw(const double t) const {\n return {x * cos(t) - y * sin(t), x * sin(t) + y * cos(t)};\n }\n double cross(const Point p) const { return x * p.y - y * p.x; }\n Point scale(const double f) const { return {x * f, y * f}; }\n double dist(const Point p) const { return hypot(x - p.x, y - p.y); }\n};\n\nstruct Segment {\n Point p, q;\n Segment scale(const double f) const { return {p, p + (q - p).scale(f)}; }\n double length() const { return p.dist(q); }\n bool operator==(Segment s) const { return p == s.p && q == s.q; }\n\n pair<bool, Point> intersect_single_point(const Segment s) const {\n return intersect(s) ? make_pair(true, intersection_point(s))\n : make_pair(false, Point{});\n }\n\n bool intersect(const Segment& s) const {\n return (orientation(p, q, s.p) * orientation(p, q, s.q) <= 0) &&\n (orientation(s.p, s.q, p) * orientation(s.p, s.q, q) <= 0);\n }\n\n private:\n short orientation(const Point o, const Point a, const Point b) const {\n const double cross = (a - o).cross(b - o);\n return cross < 0 ? -1 : cross > 0;\n }\n\n Point intersection_point(const Segment& s) const {\n const double factor = (s.q - s.p).cross(p - s.p) / (q - p).cross(s.q - s.p);\n return scale(factor).q;\n }\n};\n\nint N, M;\nvector<Point> polyline;\nvector<Point> pins;\nvector<Segment> path;\n\n// TODO: This shouldn't crash if it's 101 (size of first dimension)\ndouble memo[107][10007];\nbool ok[107][10007];\n\nint find_last_path_idx(const Segment s, const int from_path_idx) {\n int i = from_path_idx;\n if (!s.intersect(path.at(i))) return -1;\n\n double prev_dist = -1e9;\n\n for (; i < (int)path.size(); i++) {\n const auto [intersects, point] = s.intersect_single_point(path[i]);\n\n if (intersects && prev_dist <= s.p.dist(point)) {\n prev_dist = s.p.dist(point);\n } else {\n break;\n }\n }\n\n return i;\n}\n\ndouble dp(const int curr_idx, const int path_idx) {\n if (path_idx == -1) return 1e8;\n // TODO: This shit is weird. Should be able to return 0 if the previous\n // \"movement\" (Segment) was from a pin to the last hole.\n if (path_idx == (int)path.size()) return pins.at(curr_idx).dist(polyline.back());\n if (ok[curr_idx][path_idx]) return memo[curr_idx][path_idx];\n\n double res = 1e8;\n\n for (int i = 0; i <= M; i++) {\n const Segment movement{pins.at(curr_idx), pins.at(i)};\n res = min(res, movement.length() + dp(i, find_last_path_idx(movement, path_idx)));\n }\n\n ok[curr_idx][path_idx] = true;\n return memo[curr_idx][path_idx] = res;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n while (cin >> N >> M && N > 0) {\n memset(ok, 0, sizeof ok);\n polyline.resize(N);\n pins.resize(M);\n for (Point& p : polyline) cin >> p.x >> p.y;\n for (Point& p : pins) cin >> p.x >> p.y;\n for (Point& p : polyline) p = p.rot_ccw(0.00001);\n for (Point& p : pins) p = p.rot_ccw(0.00001);\n\n vector<Segment> segments;\n path.clear();\n\n for (Point p : pins) {\n segments.push_back({p, {p.x, 2000}});\n segments.push_back({p, {p.x, -2000}});\n }\n\n for (int i = 0; i < N - 1; i++) {\n const Segment s{polyline[i], polyline[i + 1]};\n\n vector<pair<double, Segment>> intersections;\n\n for (const Segment r : segments) {\n const auto [intersects, point] = s.intersect_single_point(r);\n\n if (!intersects) continue;\n intersections.emplace_back(s.p.dist(point), r);\n }\n \n sort(intersections.begin(), intersections.end(),\n [](const auto a, const auto b) { return a.first < b.first; });\n\n for (const auto& [_, seg] : intersections) {\n if (!path.empty() && path.back() == seg) {\n path.pop_back();\n } else {\n path.push_back(seg);\n }\n }\n }\n\n pins.push_back(polyline.back());\n pins.push_back(polyline.front());\n\n cout << fixed << setprecision(10) << dp(M + 1, 0) << endl;\n }\n}", "accuracy": 1, "time_ms": 5190, "memory_kb": 11404, "score_of_the_acc": -1.0263, "final_rank": 18 }, { "submission_id": "aoj_1164_7598085", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef double ld;\n \nconst ld EPS = 1e-7;\n\ninline bool zero(const ld x) { return fabs(x) < EPS; }\ninline bool equal(const ld a, const ld b) { return zero(a - b); }\n\nstruct Point {\n ld x, y;\n Point operator+(const Point p) const { return {x + p.x, y + p.y}; }\n Point operator-(const Point p) const { return {x - p.x, y - p.y}; }\n bool operator==(const Point p) const { return x == p.x && y == p.y; }\n // bool operator==(const Point p) const { return equal(x, p.x) && equal(y, p.y); }\n Point rot_ccw(const ld t) const {\n return {x * cos(t) - y * sin(t), x * sin(t) + y * cos(t)};\n }\n ld cross(const Point p) const { return x * p.y - y * p.x; }\n ld operator*(const Point p) const { return x * p.x + y * p.y; }\n Point scale(const ld f) const { return {x * f, y * f}; }\n ld dist(const Point p) const { return hypot(x - p.x, y - p.y); }\n // bool operator<(const Point p) const { return make_pair(x, y) < make_pair(p.x, p.y); }\n};\n\nshort orientation(const Point o, const Point a, const Point b) {\n const ld cross = (a - o).cross(b - o);\n if (zero(cross)) return 0;\n return cross < 0 ? -1 : cross > 0;\n}\n\nostream& operator<<(ostream& os, const Point& p) {\n return os << fixed << setprecision(6) << \"(\" << p.x << \", \" << p.y << \")\";\n}\n\nstruct Segment {\n Point p, q;\n string to_desmos() const {\n stringstream ss;\n ss << fixed << setprecision(6) << \"\\\\left(\\\\left(1-t\\\\right)\\\\cdot\" << p.x\n << \"+t\\\\cdot\" << q.x << \",\\\\left(1-t\\\\right)\\\\cdot\" << p.y << \"+t\\\\cdot\" << q.y\n << \"\\\\right)\";\n return ss.str();\n }\n Segment scale(const ld f) const { return {p, p + (q - p).scale(f)}; }\n ld length() const { return p.dist(q); }\n bool operator==(Segment s) const { return p == s.p && q == s.q; }\n\n // TODO: This is no longer \"non-collinear\". Rename/refactor.\n pair<bool, Point> intersect_non_collinear(const Segment s) const {\n return intersect(s) ? make_pair(true, intersection_point(s))\n : make_pair(false, Point{});\n }\n\n bool intersect(const Segment& s) const {\n if (p == s.p) return true;\n if (p == s.q) return true;\n if (q == s.p) return true;\n if (q == s.q) return true;\n return (orientation(p, q, s.p) * orientation(p, q, s.q) <= 0) &&\n (orientation(s.p, s.q, p) * orientation(s.p, s.q, q) <= 0);\n }\n\n private:\n Point intersection_point(const Segment& s) const {\n const ld factor = (s.q - s.p).cross(p - s.p) / (q - p).cross(s.q - s.p);\n return scale(factor).q;\n }\n};\n\nint N, M;\nvector<Point> polyline;\nvector<Point> pins;\nvector<Segment> path;\n\n// TODO: This shouldn't crash if it's 101 (size of first dimension)\nld memo[131][2500];\nbool ok[131][2500];\n\nint find_last_path_idx(const Segment s, const int from_path_idx) {\n int i = from_path_idx;\n if (!s.intersect(path.at(i))) return -1;\n\n ld prev_dist = -1e9;\n\n for (; i < (int)path.size(); i++) {\n const auto [intersects, point] = s.intersect_non_collinear(path[i]);\n if (!intersects) break;\n\n if (prev_dist <= s.p.dist(point)) {\n prev_dist = s.p.dist(point);\n } else {\n break;\n }\n }\n\n assert(i <= (int)path.size());\n\n return i;\n}\n\nld dp(const int curr_idx, const int path_idx) {\n assert(curr_idx >= 0 && curr_idx <= M + 1);\n\n if (path_idx == -1) return 1e8;\n // if (curr_idx == M) return 0;\n\n assert(path_idx >= 0 && path_idx <= (int)path.size() * 2);\n\n if (path_idx == (int)path.size()) {\n // TODO: This shit is weird. Should be able to return 0 if the previous\n // \"movement\" (Segment) was from a pin to the last hole.\n return pins.at(curr_idx).dist(polyline.back());\n }\n\n if (ok[curr_idx][path_idx]) return memo[curr_idx][path_idx];\n\n ld res = 1e8;\n\n for (int i = 0; i <= M; i++) {\n // TODO: Maybe something is weird here... but if I remove this check, then the\n // segment will become a p==q segment and the find_last_path_idx will misbehave.\n if (i == curr_idx) continue;\n\n const Segment movement{pins.at(curr_idx), pins.at(i)};\n res = min(res, movement.length() + dp(i, find_last_path_idx(movement, path_idx)));\n }\n\n ok[curr_idx][path_idx] = true;\n return memo[curr_idx][path_idx] = res;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n while (cin >> N >> M && N > 0) {\n memset(ok, 0, sizeof ok);\n polyline.resize(N);\n pins.resize(M);\n for (Point& p : polyline) cin >> p.x >> p.y;\n for (Point& p : pins) cin >> p.x >> p.y;\n for (Point& p : polyline) p = p.rot_ccw(0.00001);\n for (Point& p : pins) p = p.rot_ccw(0.00001);\n\n assert(M < 101);\n assert(N < 101);\n\n if (true) {\n sort(pins.begin(), pins.end(), [](auto a, auto b) { return a.x < b.x; });\n\n vector<ld> all_x;\n for (Point& p : polyline) all_x.emplace_back(p.x);\n for (Point& p : pins) all_x.emplace_back(p.x);\n sort(all_x.begin(), all_x.end());\n\n for (int i = 0; i < (int)all_x.size() - 1; i++) {\n assert(all_x[i] < all_x[i + 1]);\n assert(!equal(all_x[i], all_x[i + 1]));\n }\n }\n\n vector<Segment> segments;\n path.clear();\n\n for (Point p : pins) {\n segments.push_back({p, {p.x, 10'000}});\n segments.push_back({p, {p.x, -10'000}});\n }\n\n for (int i = 0; i < N - 1; i++) {\n const Segment s{polyline[i], polyline[i + 1]};\n\n for (Point pin : pins) {\n assert(orientation(s.p, s.q, pin) != 0);\n }\n }\n\n for (int i = 0; i < N - 1; i++) {\n const Segment s{polyline[i], polyline[i + 1]};\n\n vector<pair<ld, Segment>> intersections;\n\n for (const Segment r : segments) {\n const auto [intersects, point] = s.intersect_non_collinear(r);\n\n if (!intersects) continue;\n intersections.emplace_back(s.p.dist(point), r);\n }\n\n sort(intersections.begin(), intersections.end(),\n [](const auto a, const auto b) { return a.first < b.first; });\n\n for (int j = 0; j < (int)intersections.size(); j++) {\n for (int k = j + 1; k < (int)intersections.size(); k++) {\n assert(!equal(intersections[j].second.p.x, intersections[k].second.p.x));\n assert(!equal(intersections[j].second.q.x, intersections[k].second.q.x));\n }\n }\n\n for (const auto& [_, seg] : intersections) {\n if (!path.empty() && path.back() == seg) {\n path.pop_back();\n } else {\n path.push_back(seg);\n }\n }\n }\n\n pins.push_back(polyline.back());\n pins.push_back(polyline.front());\n\n if (false && N == 100 && M == 100) {\n for (int i = 0; i < N - 1; i++) {\n const Segment s{polyline[i], polyline[i + 1]};\n cerr << s.to_desmos() << endl;\n }\n for (Point pin : pins) {\n cerr << pin << endl;\n }\n cerr << fixed << setprecision(10) << dp(M + 1, 0) << endl;\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (equal(polyline[i].dist(polyline[j]), dp(M + 1, 0))) {\n cerr << \"HAHAHAHAHAH\" << endl;\n }\n }\n }\n assert(false);\n }\n\n cout << fixed << setprecision(10) << dp(M + 1, 0) << endl;\n }\n}", "accuracy": 1, "time_ms": 5580, "memory_kb": 6096, "score_of_the_acc": -1.0204, "final_rank": 16 }, { "submission_id": "aoj_1164_3580863", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long double ld; \nconst ld eps=1E-15;\nconst ld pi=acos(-1);\nconst ld INF=1E15;\nconst int maxn=1E6+5; \nint q,n,m,top;\nld ans,f[maxn];\nbool vis[maxn];\nint size,head[maxn];\nstruct pt\n{\n\tld x,y;\n\tpt(ld a=0,ld b=0)\n\t{\n\t\tx=a,y=b;\n\t}\n\tvoid operator=(pt A)\n\t{\n\t\tx=A.x,y=A.y;\n\t}\n\tld operator*(pt A)\n\t{\n\t\treturn x*A.y-y*A.x;\n\t}\n\tpt operator-(pt A)\n\t{\n\t\treturn pt(x-A.x,y-A.y);\n\t}\n}target[maxn],barrier[maxn];\nstruct inf\n{\n\tint id,x;\n\tinf(int a=0,int b=0)\n\t{\n\t\tid=a,x=b;\n\t}\n}S[maxn];\nstruct edge\n{\n\tint to,next;\n\tld w;\n}E[maxn];\n//////////////////////////////////////////////////////////////////\n//polygon\n//////////////////////////////////////////////////////////////////\nbool cmp(pt A,pt B)\n{\n\treturn A.x<B.x;\n}\npt rotate(pt A,ld ra)\n{\n\treturn pt(A.x*cos(ra)-A.y*sin(ra),A.x*sin(ra)+A.y*cos(ra));\n}\nint face(pt A,pt B,pt C)\n{\n\tld y=(B.y-A.y)/(B.x-A.x)*(C.x-A.x);\n\tif(A.y+y>=C.y)\n\t\treturn 1;\n\treturn -1;\n}\nbool inside(pt A,pt B,pt C)\n{\n\treturn min(A.x,B.x)<=C.x&&C.x<=max(A.x,B.x);\n}\nld dis(pt A,pt B)\n{\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\nint cross(pt A,pt B)\n{\n\tld d=A*B;\n\tif(d>=eps)\n\t\treturn 1;\n\telse\n\t\treturn -1;\n}\nvoid push(inf A)\n{\n\tif(A.id==S[top].id&&A.x==S[top].x)\n\t\t--top;\n\telse\n\t\tS[++top]=A;\n}\n//////////////////////////////////////////////////////////////////\n//polygon\n//////////////////////////////////////////////////////////////////\n\n\n//////////////////////////////////////////////////////////////////\n//graph\n//////////////////////////////////////////////////////////////////\nvoid add(int u,int v,ld w)\n{\n\tE[++size].to=v;\n\tE[size].next=head[u];\n\tE[size].w=w;\n\thead[u]=size;\n}\nvoid clear()\n{\n\tfor(int i=0;i<=top+1;++i)\n\t\thead[i]=0;\n\thead[maxn-5]=0;\n\tsize=0;\n}\nld spfa()\n{\n\tfor(int i=0;i<=top;++i)\n\t\tf[i]=INF;\n\tf[0]=0;\n\tvis[0]=1;\n\tqueue<int>Q;\n\tQ.push(0);\n\twhile(!Q.empty())\n\t{\n\t\tint u=Q.front();\n\t\tvis[u]=0;\n\t\tQ.pop();\n\t\tfor(int i=head[u];i;i=E[i].next)\n\t\t{\n\t\t\tint v=E[i].to;\n\t\t\tld nw=E[i].w+f[u];\n\t\t\tif(nw<f[v])\n\t\t\t{\n\t\t\t\tf[v]=nw;\n\t\t\t\tif(!vis[v])\n\t\t\t\t{\n\t\t\t\t\tvis[v]=1;\n\t\t\t\t\tQ.push(v);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn f[top--];\n}\nbool check(int l,int r)\n{\n\tfor(int i=l+1;i<=r-1;++i)\n\t\tif(face(barrier[S[l].id],barrier[S[r].id],barrier[S[i].id])!=S[i].x)\n\t\t\treturn false;\n\treturn true;\n} \nld get(int x)\n{\n\tclear();\n\tbarrier[maxn-5]=target[x];\n\tpush(inf(maxn-5,0));\n\tfor(int i=1;i<=top;++i)\n\t\tfor(int j=i+1;j<=top;++j)\n\t\t\tif(check(i,j))\n\t\t\t\tadd(i,j,dis(barrier[S[i].id],barrier[S[j].id]));\n\tbarrier[0]=target[1];\n\tfor(int i=1;i<=top;++i)\n\t\tif(check(0,i))\n\t\t\tadd(0,i,dis(barrier[0],barrier[S[i].id]));\n\treturn spfa();\n}\n\n//////////////////////////////////////////////////////////////////\n//graph\n//////////////////////////////////////////////////////////////////\n\nvoid solve()\n{\n\ttop=ans=0;\n\tcin>>n>>m;\n\tif(n==0&&m==0)\n\t\texit(0);\n\tfor(int i=1;i<=n;++i)\n\t{\n\t\tcin>>target[i].x>>target[i].y;\n\t\ttarget[i]=rotate(target[i],pi/3);\n\t}\n\tfor(int i=1;i<=m;++i)\n\t{\n\t\tcin>>barrier[i].x>>barrier[i].y;\n\t\tbarrier[i]=rotate(barrier[i],pi/3);\n\t}\n\tsort(barrier+1,barrier+m+1,cmp);\n\tpt now=target[1];\n\tfor(int i=2;i<=n;++i)\n\t{\n\t\tif(target[i].x>now.x)\n\t\t{\n\t\t\tfor(int j=1;j<=m;++j)\n\t\t\t\tif(inside(now,target[i],barrier[j]))\n\t\t\t\t\tpush(inf(j,face(now,target[i],barrier[j])));\n\t\t}\n\t\telse\n\t\t{\n\t\t\tfor(int j=m;j>=1;--j)\n\t\t\t\tif(inside(now,target[i],barrier[j]))\n\t\t\t\t\tpush(inf(j,face(now,target[i],barrier[j])));\n\t\t}\n\t\tnow=target[i];\n\t}\n\tcout<<fixed<<setprecision(4)<<get(n)<<endl;\n}\nint main()\n{\n\tios::sync_with_stdio(false);\n\twhile(true)\n\t\tsolve();\n\treturn 0;\n}", "accuracy": 1, "time_ms": 530, "memory_kb": 74300, "score_of_the_acc": -1.0892, "final_rank": 19 }, { "submission_id": "aoj_1164_3120292", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <complex>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <array>\nusing namespace std;\nconst double EPS = 1e-10;\nconst double INF = 1e12;\nconst double PI = acos(-1);\n#define EQ(n,m) (abs((n)-(m)) < EPS)\n#define X real()\n#define Y imag()\ntypedef complex<double> P;\ntypedef vector<P> VP;\nstruct L : array<P, 2>{\n L(const P& a, const P& b){ at(0)=a; at(1)=b; }\n L(){}\n};\n\nnamespace std{\n bool operator < (const P& a, const P& b){\n return !EQ(a.X,b.X) ? a.X<b.X : a.Y+EPS<b.Y;\n }\n bool operator == (const P& a, const P& b){\n return abs(a-b) < EPS;\n }\n}\n\ndouble dot(P a, P b){\n return (conj(a)*b).X;\n}\ndouble cross(P a, P b){\n return (conj(a)*b).Y;\n}\nint ccw(P a, P b, P c){\n b -= a;\n c -= a;\n if(cross(b,c) > EPS) return +1; //ccw\n if(cross(b,c) < -EPS) return -1; //cw\n if(dot(b,c) < -EPS) return +2; //c-a-b\n if(abs(c)-abs(b) > EPS) return -2; //a-b-c\n return 0; //a-c-b\n}\n\nbool intersectSS(const L& a, const L& b){\n return ( ccw(a[0],a[1],b[0]) *ccw(a[0],a[1],b[1]) <= 0 ) &&\n ( ccw(b[0],b[1],a[0]) *ccw(b[0],b[1],a[1]) <= 0 );\n}\n\ndouble shortest_path(P begin, P end, vector<L> &pl){\n pl.insert(pl.begin(), L(begin, begin));\n pl.push_back(L(end, end));\n int n = pl.size();\n vector<vector<double> > dp(n, vector<double>(2, INF));\n dp[0][0] = 0;\n for(int i=0; i<n; i++){\n for(int j=i+1; j<n; j++){\n for(int s=0; s<2; s++){\n for(int t=0; t<2; t++){\n L edge(pl[i][s], pl[j][t]);\n bool ok = true;\n for(int k=i+1; k<j; k++){\n if(!intersectSS(edge, pl[k])){\n ok = false;\n break;\n }\n }\n if(ok){\n dp[j][t] = min(dp[j][t], dp[i][s] +abs(edge[1] -edge[0]));\n }\n }\n }\n }\n }\n return dp[n-1][0];\n}\n\nint main(){\n while(1){\n int m,n;\n cin >> m >> n;\n if(m == 0) break;\n\n VP p(m), pin(n);\n P rot(cos(0.01), sin(0.01));\n for(int i=0; i<m; i++){\n double x,y;\n cin >> x >> y;\n p[i] = P(x, y)*rot;\n }\n for(int i=0; i<n; i++){\n double x,y;\n cin >> x >> y;\n pin[i] = P(x, y)*rot;\n }\n\n sort(pin.begin(), pin.end());\n vector<L> ls;\n for(int i=0; i<n; i++){\n ls.emplace_back(P(pin[i].X, -1e4), pin[i]);\n ls.emplace_back(pin[i], P(pin[i].X, 1e4));\n }\n\n vector<int> pass;\n for(int i=0; i<m-1; i++){\n L line(p[i], p[i+1]);\n if(EQ(line[0].X, line[1].X)) continue;\n bool goR = line[0].X < line[1].X;\n int j = goR? 0: ls.size()-1;\n while((goR && j<(int)ls.size()) || (!goR && j>=0)){\n if(intersectSS(ls[j], line)){\n if(pass.empty() || pass.back() != j){\n pass.push_back(j);\n }else{\n pass.pop_back();\n }\n }\n if(goR) j++;\n else j--;\n }\n }\n\n double ans = 0;\n P start = p[0];\n vector<L> pl;\n for(int i=0; i<(int)pass.size(); i++){\n if(i!=(int)pass.size()-1 && EQ(ls[pass[i]][0].X, ls[pass[i+1]][0].X)){\n P end;\n if(ls[pass[i]][0].Y < ls[pass[i+1]][0].Y){\n end = ls[pass[i]][1];\n }else{\n end = ls[pass[i]][0];\n }\n ans += shortest_path(start, end, pl);\n start = end;\n pl = vector<L>();\n }else{\n pl.push_back(ls[pass[i]]);\n }\n if(i == (int)pass.size()-1){\n ans += shortest_path(start, p[m-1], pl);\n }\n }\n cout << fixed << setprecision(4);\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3300, "score_of_the_acc": -0.0507, "final_rank": 6 }, { "submission_id": "aoj_1164_3120289", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <complex>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <array>\nusing namespace std;\nconst double EPS = 1e-10;\nconst double INF = 1e12;\nconst double PI = acos(-1);\n#define EQ(n,m) (abs((n)-(m)) < EPS)\n#define X real()\n#define Y imag()\n\ntypedef complex<double> P;\ntypedef vector<P> VP;\nstruct L : array<P, 2>{\n L(const P& a, const P& b){ at(0)=a; at(1)=b; }\n L(){}\n};\n\nnamespace std{\n bool operator < (const P& a, const P& b){\n return !EQ(a.X,b.X) ? a.X<b.X : a.Y+EPS<b.Y;\n }\n bool operator == (const P& a, const P& b){\n return abs(a-b) < EPS;\n }\n}\n\ndouble dot(P a, P b){\n return (conj(a)*b).X;\n}\ndouble cross(P a, P b){\n return (conj(a)*b).Y;\n}\nint ccw(P a, P b, P c){\n b -= a;\n c -= a;\n if(cross(b,c) > EPS) return +1; //ccw\n if(cross(b,c) < -EPS) return -1; //cw\n if(dot(b,c) < -EPS) return +2; //c-a-b\n if(abs(c)-abs(b) > EPS) return -2; //a-b-c\n return 0; //a-c-b\n}\n\nbool intersectSS(const L& a, const L& b){\n return ( ccw(a[0],a[1],b[0]) *ccw(a[0],a[1],b[1]) <= 0 ) &&\n ( ccw(b[0],b[1],a[0]) *ccw(b[0],b[1],a[1]) <= 0 );\n}\n\ndouble shortest_path(P begin, P end, vector<L> &pl){\n pl.insert(pl.begin(), L(begin, begin));\n pl.push_back(L(end, end));\n int n = pl.size();\n vector<vector<double> > dp(n, vector<double>(2, INF));\n dp[0][0] = 0;\n for(int i=0; i<n; i++){\n for(int j=i+1; j<n; j++){\n for(int s=0; s<2; s++){\n for(int t=0; t<2; t++){\n L edge(pl[i][s], pl[j][t]);\n bool ok = true;\n for(int k=i+1; k<j; k++){\n if(!intersectSS(edge, pl[k])){\n ok = false;\n break;\n }\n }\n if(ok){\n dp[j][t] = min(dp[j][t], dp[i][s] +abs(edge[1] -edge[0]));\n }\n }\n }\n }\n }\n return dp[n-1][0];\n}\n\nint main(){\n while(1){\n int m,n;\n cin >> m >> n;\n if(m == 0) break;\n\n VP p(m), pin(n);\n P rot(cos(0.01), sin(0.01));//回転させとかないとバグる(要検証)\n for(int i=0; i<m; i++){\n double x,y;\n cin >> x >> y;\n p[i] = P(x, y)*rot;\n }\n for(int i=0; i<n; i++){\n double x,y;\n cin >> x >> y;\n pin[i] = P(x, y)*rot;\n }\n\n sort(pin.begin(), pin.end());\n vector<L> ls;\n for(int i=0; i<n; i++){\n P prev;\n if(i==0 || !EQ(pin[i].X, pin[i-1].X)){\n prev = P(pin[i].X, -1e4);\n }else{\n prev = pin[i-1];\n }\n ls.emplace_back(prev, pin[i]);\n if(i==n-1 || !EQ(pin[i].X, pin[i+1].X)){\n ls.emplace_back(pin[i], P(pin[i].X, 1e4));\n }\n }\n\n vector<int> pass;\n for(int i=0; i<m-1; i++){\n L line(p[i], p[i+1]);\n if(EQ(line[0].X, line[1].X)) continue;\n bool goR = line[0].X < line[1].X;\n int j = goR? 0: ls.size()-1;\n while((goR && j<(int)ls.size()) || (!goR && j>=0)){\n if(intersectSS(ls[j], line)){\n if(pass.empty() || pass.back() != j){\n pass.push_back(j);\n }else{\n pass.pop_back();\n }\n }\n if(goR) j++;\n else j--;\n }\n }\n\n double ans = 0;\n P start = p[0];\n vector<L> pl;\n for(int i=0; i<(int)pass.size(); i++){\n if(i!=(int)pass.size()-1 && EQ(ls[pass[i]][0].X, ls[pass[i+1]][0].X)){\n P end;\n if(ls[pass[i]][0].Y < ls[pass[i+1]][0].Y){\n end = ls[pass[i]][1];\n }else{\n end = ls[pass[i]][0];\n }\n ans += shortest_path(start, end, pl);\n start = end;\n pl = vector<L>();\n }else{\n pl.push_back(ls[pass[i]]);\n }\n if(i == (int)pass.size()-1){\n ans += shortest_path(start, p[m-1], pl);\n }\n }\n cout << fixed << setprecision(4);\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3296, "score_of_the_acc": -0.0507, "final_rank": 5 }, { "submission_id": "aoj_1164_2469443", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing F = double;\n\n#define x first\n#define y second\nusing Point = pair<F, F>;\n\n#define from first\n#define to second\nusing Segment = pair<Point, Point>;\n\nconst F INF = 1e6;\nconst F EPS = 1e-6;\n\nint M, N;\nvector<Point> S, P;\n\nvector<Point> rotate(auto point, auto a) {\n for(auto& p: point) p = make_pair(p.x * cos(a) - p.y * sin(a), p.x * sin(a) + p.y * cos(a));\n return point;\n}\n\nF norm(auto p) {return p.x * p.x + p.y * p.y;}\nF dot(auto a, auto b) {return a.x * b.x + a.y * b.y;}\nF cross(auto a, auto b) {return a.x * b.y - a.y * b.x;}\nint ccw(auto a, auto b, auto c) {\n b = Point(b.x - a.x, b.y - a.y);\n c = Point(c.x - a.x, c.y - a.y);\n if(cross(b, c) > 0) return 1;\n if(cross(b, c) < 0) return -1;\n if(dot(b, c) < 0) return 2;\n if(norm(b) < norm(c)) return -2;\n return 0;\n}\nbool intersect(auto s, auto t) {\n return ccw(s.from, s.to, t.from) * ccw(s.from, s.to, t.to) <= 0\n && ccw(t.from, t.to, s.from) * ccw(t.from, t.to, s.to) <= 0;\n}\n\nvector<Segment> uyenimo(auto v) {\n vector<Segment> res;\n for(auto s: v) {\n if(res.empty()) {\n res.emplace_back(s);\n } else {\n if(res.back() == s) res.pop_back();\n else res.emplace_back(s);\n }\n }\n return res;\n}\n\nvector<Segment> shrink() {\n vector<Segment> scratch(P.size());\n for(auto p: P) for(auto dy: {-INF, INF}) scratch.emplace_back(p, Point(p.x, p.y + dy));\n\n sort(begin(scratch), end(scratch));\n\n vector<Segment> res;\n for(auto i = 1; i < S.size(); ++i) {\n Segment s(S[i-1], S[i]);\n vector<Segment> add;\n for(auto t: scratch) if(intersect(s, t)) add.emplace_back(t);\n if(s.to.x < s.from.x) reverse(begin(add), end(add));\n res.insert(end(res), begin(add), end(add));\n }\n\n while(true) {\n auto pre = res.size();\n res = uyenimo(res);\n if(pre == res.size()) break;\n }\n\n return res;\n}\n\nF solve() {\n S = rotate(S, EPS);\n P = rotate(P, EPS);\n\n auto order = shrink();\n\n order.insert(begin(order), Segment(S.front(), Point(0, 0)));\n order.emplace_back(S.back(), Point(0, 0));\n vector<F> dp(order.size(), INF);\n dp[0] = 0;\n for(auto i = 0; i < order.size(); ++i) {\n for(auto j = i + 1; j < order.size(); ++j) {\n Segment nex(order[i].from, order[j].from);\n auto ok = true;\n for(auto k = i + 1; ok && k < j; ++k) {\n if(!intersect(nex, order[k])) ok = false;\n if(order[k].from.x == order[k+1].from.x) ok = false;\n }\n if(ok) dp[j] = min(dp[j], dp[i] + hypot(nex.from.x - nex.to.x, nex.from.y - nex.to.y));\n }\n }\n\n return dp.back();\n}\n\nint main() {\n while(cin >> M >> N, M | N) {\n S = vector<Point>(M);\n for(auto& i: S) cin >> i.x >> i.y;\n P = vector<Point>(N);\n for(auto& i: P) cin >> i.x >> i.y;\n\n cout << setprecision(10) << fixed << solve() << endl;\n }\n}", "accuracy": 1, "time_ms": 810, "memory_kb": 3704, "score_of_the_acc": -0.1695, "final_rank": 7 }, { "submission_id": "aoj_1164_1815462", "code_snippet": "#include <bits/stdc++.h>\n\nconst int N = 250;\nconst double eps = 1e-9;\nconst double INF = 1e200;\n\nint n, m;\nstruct Point {\n\tdouble x, y;\n\t\n\tPoint() {}\n\tPoint(double x, double y):x(x), y(y) {}\n\t\n\tvoid print() {\n\t\tprintf(\"(%.2f, %.2f)\\n\", x, y);\n\t}\n\t\n\tfriend Point operator + (const Point &a, const Point &b) {\n\t\treturn Point(a.x + b.x, a.y + b.y);\n\t}\n\t\n\tfriend Point operator - (const Point &a, const Point &b) {\n\t\treturn Point(a.x - b.x, a.y - b.y);\n\t}\n\t\n\tfriend Point operator * (const Point &a, const double &b) {\n\t\treturn Point(a.x * b, a.y * b);\n\t}\n};\nPoint string[N], pin[N];\n\nint dcmp(double x) {\n\tif (std::abs(x) < eps) {\n\t\treturn 0;\n\t}\n\treturn x < 0 ? -1 : 1;\n}\n\ndouble cross(Point a, Point b) {\n\treturn a.x * b.y - a.y * b.x;\n}\n\ndouble dot(Point a, Point b) {\n\treturn a.x * b.x + a.y * b.y;\n}\n\ndouble getAngle(Point o, Point a, Point b) {\n\treturn std::atan2(cross(a - o, b - o), dot(a - o, b - o));\n}\n\ndouble area(Point a, Point b, Point c) {\n\treturn std::abs(cross(b - a, c - a)) / 2.0;\n}\n\ndouble sqr(double x) {\n\treturn x * x;\n}\n\ndouble dist(Point a, Point b) {\n\treturn std::sqrt(sqr(a.x - b.x) + sqr(a.y - b.y));\n}\n\nbool inTriangle(Point p, Point a, Point b, Point c) {\n\treturn dcmp(area(p, a, b) + area(p, b, c) + area(p, c, a) - area(a, b, c)) == 0\n\t&& dcmp(area(p, a, b)) == dcmp(area(p, b, c)) && dcmp(area(p, a, b)) == dcmp(area(p, a, c))\n\t;\n}\n\nPoint getIntersection(Point p, Point v, Point q, Point w) {\n\tv = v - p;\n\tw = w - q;\n\tPoint u = p - q;\n\tdouble t = cross(w, u) / cross(v, w);\n\treturn p + (v * t);\n}\n\nvoid init() {\n\tfor (int i = 1; i <= n; i ++) {\n\t\tdouble x, y;\n\t\tscanf(\"%lf%lf\", &x, &y);\n\t\tstring[i] = Point(x, y);\n\t}\n\tfor (int i = 1; i <= m; i ++) {\n\t\tdouble x, y;\n\t\tscanf(\"%lf%lf\", &x, &y);\n\t\tpin[i] = Point(x, y);\n\t}\n}\n\nvoid work() {\n\tstd::vector<Point> answer;\n\tstd::vector<double> exAngle;\n\tPoint last, mid;\n\t\n\tanswer.push_back(string[1]);\n\tlast = string[1], mid = string[2];\n\texAngle.push_back(INF);\n\tfor (int i = 3; i <= n; i ++) {\n\t\twhile (true) {\n\t\t\tdouble minAngle = getAngle(last, string[i], mid);\n\t\t\tPoint tmp = string[i];\n\t\t\tbool tag = false;\n\t\t\tfor (int j = 1; j <= m; j ++) {\n\t\t\t\tif (inTriangle(pin[j], last, mid, string[i])) {\n\t\t\t\t\tif (std::abs(getAngle(last, pin[j], mid)) < std::abs(minAngle)) {\n\t\t\t\t\t\ttag = true;\n\t\t\t\t\t\tminAngle = getAngle(last, pin[j], mid);\n\t\t\t\t\t\ttmp = pin[j];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (dcmp(exAngle.back()) * dcmp(exAngle.back() + minAngle) == -1) {\n\t\t\t\tanswer.pop_back();\n\t\t\t\texAngle.pop_back();\n\t\t\t\tmid = getIntersection(answer.back(), last, mid, string[i]);\n\t\t\t\tlast = answer.back();\n\t\t\t} else {\n\t\t\t\texAngle.back() += minAngle;\n\t\t\t\tif (tag == false) {\n\t\t\t\t\tmid = string[i];\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tmid = getIntersection(last, tmp, mid, string[i]);\n\t\t\t\tanswer.push_back(tmp);\n\t\t\t\texAngle.push_back(0);\n\t\t\t\tlast = tmp;\n\t\t\t}\n\t\t}\n\t\t/*\n\t\tprintf(\"i = %d:\\n\", i);\n\t\tfor (int j = 0; j < (int)answer.size(); j ++) {\n\t\t\tanswer[j].print();\n\t\t}\n\t\t*/\n\t}\n\tanswer.push_back(string[n]);\n\t\n\tdouble length = 0;\n\tfor (int i = 1; i < (int)answer.size(); i ++) {\n\t\tlength += dist(answer[i - 1], answer[i]);\n\t}\n\tprintf(\"%.10f\\n\", length);\n}\n\nint main() {\n\t//freopen(\"input.txt\", \"r\", stdin);\n\t\n\twhile (std::cin >> n >> m && !(n == 0 && m == 0)) {\n\t\tinit();\n\t\twork();\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1396, "score_of_the_acc": -0.0006, "final_rank": 1 }, { "submission_id": "aoj_1164_1713534", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define rep1(i,n) for(int i=1;i<=(int)(n);i++)\n#define all(c) c.begin(),c.end()\n#define pb push_back\n#define fs first\n#define sc second\n#define show(x) cout << #x << \" = \" << x << endl\n#define chmin(x,y) x=min(x,y)\n#define chmax(x,y) x=max(x,y)\nusing namespace std;\ntypedef double D;\ntypedef complex<D> P;\nint K,N;\nP ps[100],as[100];\nbool up(P s,P t,P p){\t\t\t//line over point\n\tD sx=s.real(),tx=t.real(),sy=s.imag(),ty=t.imag(),x=p.real(),y=p.imag();\n\tD ly=sy+(ty-sy)/(tx-sx)*(x-sx);\n\treturn ly>y;\n}\nvoid addpath(vector<int>& vc,P s,P t){\n\tvector<int> ad;\n\tD sx=s.real(),tx=t.real(),sy=s.imag(),ty=t.imag();\n\tbool sw=0;\n\tif(sx>tx){\n\t\tsw=1;\n\t\tswap(sx,tx);\n\t\tswap(sy,ty);\n\t}\n\trep(i,N){\n\t\tD x=as[i].real(),y=as[i].imag();\n\t\tif(sx<x&&x<tx){\n\t\t\tif(up(s,t,as[i])) ad.pb(i*2);\n\t\t\telse ad.pb(i*2+1);\n\t\t}\n\t}\n\tif(sw) reverse(all(ad));\n\tvc.insert(vc.end(),all(ad));\n}\nbool cancel(vector<int>& vc){\n\tbool update=0;\n\tint A=vc.size();\n\tvector<bool> gomi(A,0);\n\trep(i,A-1){\n\t\tif(vc[i]==vc[i+1]){\n\t\t\tgomi[i]=gomi[i+1]=1;\n\t\t\tupdate=1;\n\t\t\ti++;\n\t\t}\n\t}\n\tvector<int> nvc;\n\trep(i,A) if(!gomi[i]) nvc.pb(vc[i]);\n\tvc=nvc;\n\treturn update;\n}\nP point(int id){\n\treturn as[id/2];\n}\nD calclen(P S,P T,vector<int>& vc){\n//\tshow(S);\n//\tshow(T);\n\tint A=vc.size();\n//\tshow(A);\n//\tfor(int v:vc) cout<<v<<\" \";\n//\tputs(\"\");\n\tD dp[110];\n\trep(i,A+2) dp[i]=1e9;\n\tdp[0]=0;\n\trep(i,A+1){\n\t\tP t=(i==A?T:point(vc[i]));\n\t\trep(j,i+1){\n\t\t\tP s=(j==0?S:point(vc[j-1]));\n\t\t\tbool ok=1;\n\t\t\tfor(int k=j;k<i;k++){\n\t\t\t\tif(up(s,t,point(vc[k]))==(vc[k]&1)){\n\t\t\t\t\tok=0;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(ok) chmin(dp[i+1],dp[j]+abs(s-t));\n\t\t}\n\t}\n\treturn dp[A+1];\n}\nint main(){\n\twhile(true){\n\t\tcin>>K>>N;\n\t\tif(K==0) break;\n\t\trep(i,K){\n\t\t\tD x,y;\n\t\t\tcin>>x>>y;\n\t\t\tps[i]=P(x,y)*polar(1.0,1.0);\n\t\t}\n\t\trep(i,N){\n\t\t\tD x,y;\n\t\t\tcin>>x>>y;\n\t\t\tas[i]=P(x,y)*polar(1.0,1.0);\n\t\t}\n\t\trep(i,N-1) rep(j,N-1) if(as[j].real()>as[j+1].real()) swap(as[j],as[j+1]);\n\t\tvector<int> vc;\n\t\trep(i,K-1) addpath(vc,ps[i],ps[i+1]);\n\t\twhile(cancel(vc));\n\t\tD ans=0;\n\t\tint M=vc.size();\n\t\tint l=-1;\n\t\tfor(int r=1;r<=M;r++){\n\t\t\tif(r==M||(vc[r]^vc[r-1])==1){\n\t\t\t\tvector<int> tmp;\n\t\t\t\tP s,t;\n\t\t\t\tif(l==-1) s=ps[0];\n\t\t\t\telse s=point(vc[l]);\n\t\t\t\tif(r==M) t=ps[K-1];\n\t\t\t\telse t=point(vc[r]);\n\t\t\t\tif(r==M) r++;\n\t\t\t\tfor(int i=l+1;i<r-1;i++) tmp.pb(vc[i]);\n\t\t\t\tans+=calclen(s,t,tmp);\n//\t\t\t\tshow(calclen(s,t,tmp));\n\t\t\t\tl=r;\n\t\t\t}\n\t\t}\n\t\tprintf(\"%.12f\\n\",ans);\n\t}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3308, "score_of_the_acc": -0.0285, "final_rank": 4 }, { "submission_id": "aoj_1164_1407600", "code_snippet": "#include <iostream>\n#include <fstream>\n#include <algorithm>\n#include <cmath>\n#include <iomanip>\n#include <vector>\n#include <map>\n#include <complex>\n#include <queue>\n#include <sstream>\n#include <stack>\n\nusing namespace std;\ntypedef double R;\ntypedef complex<R> P;\ntypedef pair<P,P> L;\ntypedef pair<P,R> C;\ntypedef vector<P> Poly;\n#define x real()\n#define y imag()\nconst R PI = acos(-1);\nconst R EPS = 1e-9;\ninline bool near(const P& p,const P& q){ return abs(p-q)<EPS;}\nR dot(const P& p,const P& q){ return p.x*q.x+p.y*q.y;}\nR det(const P& p,const P& q){ return p.x*q.y-p.y*q.x;}\nenum LPposit{\n P_CD = -2, //counter direction\n P_CW = -1, //clock wise\n P_OS = 0, //on segment\n P_CCW = 1, //counter clock wise\n P_D = 2 //direction\n};\ninline R ccw_b(const P& p,const P& q,const P& r){ return det(q-p,r-p);}\nLPposit ccw(const P& p, const P& q, const P& r){\n R c = ccw_b(p,q,r);\n if(c<-EPS) return P_CW;\n if(c>EPS) return P_CCW;\n if(dot(q-p,r-p)<-EPS) return P_CD;\n if(dot(p-q,r-q)<-EPS) return P_D;\n return P_OS;\n}\ninline R Sabs(const L& l){ return abs(l.first-l.second);}\ninline R LPdist(const L& l,const P& p){ return abs(ccw_b(l.first,l.second,p))/Sabs(l);}\ninline R SPdist(L l,P p){\n R a = abs(l.first-p);\n R b = abs(l.second-p);\n R c = Sabs(l);\n if(b*b+c*c>a*a && a*a+c*c>b*b) return LPdist(l,p);\n return min(a,b);\n}\nbool crossS(const L& p,const L& q){\n return\n ccw(p.first,p.second,q.first)*ccw(p.first,p.second,q.second)<=0 &&\n ccw(q.first,q.second,p.first)*ccw(q.first,q.second,p.second)<=0;\n}\nP intersect(const L& p,const L& q){\n P vp = p.second-p.first;\n P vq = q.second-q.first;\n P c(det(vp,p.first), det(vq,q.first));\n return P(det(c, P(vp.x, vq.x)), det(c, P(vp.y, vq.y))) / det(vp, vq);\n}\n\nint inConvex(const Poly& ps, P p){\n int n = ps.size();\n int c = ccw(ps[n-1],p,ps[0]);\n for(int i=0;i+1<n;++i)\n if(ccw(ps[i],p,ps[i+1])!=c) return false;\n return true;\n}\n\nvector<P> incP(const vector<P>& v,const Poly& pol){ //pol?????????????????????v???????´??????????\n int n = v.size();\n vector<P> ret;\n for(int i=0;i<n;++i) if(inConvex(pol,v[i])==1) ret.push_back(v[i]);\n return ret;\n}\n\nvector<P> himo;\nvector<P> kugi;\n\ndouble input(){\n double ret;\n cin >> ret;\n return ret;\n}\n\nR angle(const P& a,const P& b){\n int sgn = (det(a,b)>=0)?1:-1;\n return acos(dot(a,b)/abs(a)/abs(b))*sgn;\n}\n\nstruct D{\n P p,pre;\n R deg; //????????????????§????\n D(P a,P b,R d):p(a),pre(b),deg(d){}\n};\n\nP nextKugi(const Poly& pol,vector<P> tmp){\n P s = pol[0];\n P v1=pol[1]-s, v2=pol[2]-s;\n double argmin = abs(angle(v1,v2));\n vector<P> ps = incP(tmp,pol);\n int n = ps.size();\n P nxt = 0;\n bool found = false;\n for(int i=0;i<n;++i){\n double ag = abs(angle(v1,ps[i]-s));\n if(ag < argmin){\n found = true;\n argmin = ag;\n nxt = ps[i];\n }\n }\n if(!found) return P(-1,-1);\n return nxt;\n}\n\nvector<P> path(vector<P> ps,const Poly& pol){ //pol???????§???¢, v???pol??????????????????\n P s = pol[0];\n vector<P> ret;\n while(true){\n int n = ps.size();\n P v1 = pol[1]-s, v2=pol[2]-s;\n double argmin = abs(angle(v1,v2));\n P nxt = 0;\n bool found = false;\n for(int i=0;i<n;++i){\n if(ps[i]==s) continue;\n double ag = abs(angle(v1,ps[i]-s));\n if(ag < argmin){\n\tfound = true;\n\targmin = ag;\n\tnxt = ps[i];\n }\n }\n if(!found) break;\n ret.push_back(nxt);\n vector<P> tmp;\n Poly POL = pol; POL[0]=nxt;\n for(int i=0;i<n;++i)\n if(inConvex(POL,ps[i])) tmp.push_back(ps[i]);\n ps = tmp;\n s = nxt;\n }\n return ret;\n}\n\n\nR solve(){\n if(himo.size()==2) return abs((himo[1]-himo[0]));\n P A = himo[0];\n P B = himo[1];\n stack<D> St;\n int n = himo.size();\n for(int i=2;i<n;++i){\n P C = himo[i];\n while(!St.empty()){\n Poly ABC(3);\n ABC[0]=A, ABC[1]=B, ABC[2]=C;\n P K = nextKugi(ABC,kugi);\n if(K==P(-1,-1)) K = C;\n D X = St.top(); St.pop();\n double nxtdeg = X.deg+angle(B-A,K-A);\n if(X.deg * nxtdeg < 0){\n\tB = intersect(L(X.pre,X.p), L(B,C));\n\tA = X.pre;\n }\n else{\n\tX.deg = nxtdeg;\n\tSt.push(X);\n\tbreak;\n }\n }\n\n Poly ABC(3); ABC[0]=A, ABC[1]=B, ABC[2]=C;\n vector<P> ins = incP(kugi,ABC);\n vector<P> ps = path(ins,ABC);\n ps.push_back(C);\n for(int j=0;j+1<ps.size();++j){\n St.push(D(ps[j], A, angle(ps[j]-A, ps[j+1]-ps[j])));\n A = ps[j];\n }\n B = C;\n }\n\n vector<P> X;\n X.push_back(himo[n-1]);\n while(!St.empty()){\n X.push_back(St.top().p);\n St.pop();\n }\n X.push_back(himo[0]);\n reverse(X.begin(), X.end());\n \n ofstream ofs(\"1164.dat\");\n for(int i=0;i<X.size();++i) ofs << X[i].x << \" \" << X[i].y << endl;\n\n R ret = 0;\n for(int i=0;i+1<X.size();++i) ret+=abs(X[i+1]-X[i]);\n return ret;\n}\n\nint main(){\n int n,m;\n while(cin>>m>>n,m||n){\n himo.clear();\n kugi.clear();\n ofstream ofsh(\"himo.dat\");\n ofstream ofsk(\"kugi.dat\");\n for(int i=0;i<m;++i)\n himo.push_back(P(input(),input()));\n for(int i=0;i<n;++i)\n kugi.push_back(P(input(),input()));\n\n for(int i=0;i<m;++i)\n ofsh<<himo[i].x << \" \" << himo[i].y << endl;\n for(int i=0;i<n;++i)\n ofsk<<kugi[i].x << \" \" << kugi[i].y << endl;\n \n cout << fixed << setprecision(10) << solve() << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 1464, "score_of_the_acc": -0.0084, "final_rank": 3 }, { "submission_id": "aoj_1164_1279663", "code_snippet": "#include<cstdio>\n#include<complex>\n#include<cmath>\n#include<vector>\n#include<algorithm>\n\nusing namespace std;\n\ntypedef double Real;\ntypedef complex<Real> Point;\n\nbool cmp(const Point &p1,const Point &p2){\n\treturn p1.real()<p2.real();\n}\n\nReal sx[110],sy[110];\nReal nx[110],ny[110];\nint N,M;\n\nPoint ns[110];\n\nvector<int> vec;\n\nvoid init(){\n\tvec.clear();\n}\n\nvoid rot(){\n\tfor(int i=1;i<M;i++){\n\t\tsx[i]-=sx[0];\n\t\tsy[i]-=sy[0];\n\t}\n\tfor(int i=0;i<N;i++){\n\t\tnx[i]-=sx[0];\n\t\tny[i]-=sy[0];\n\t}\n\tsx[0]=0,sy[0]=0;\n\tPoint coe=Point(cos(1),sin(1));\n//\tPoint coe=1;\n\tfor(int i=1;i<M;i++){\n\t\tPoint tmp=Point(sx[i],sy[i]);\n\t\ttmp*=coe;\n\t\tsx[i]=tmp.real();\n\t\tsy[i]=tmp.imag();\n\t}\n\tfor(int i=0;i<N;i++){\n\t\tPoint tmp=Point(nx[i],ny[i]);\n\t\ttmp*=coe;\n\t\tnx[i]=tmp.real();\n\t\tny[i]=tmp.imag();\n\t}\n\tfor(int i=0;i<N;i++){\n\t\tns[i]=Point(nx[i],ny[i]);\n\t}\n\tsort(ns,ns+N,cmp);\n\tfor(int i=0;i<N;i++){\n\t\tnx[i]=ns[i].real();\n\t\tny[i]=ns[i].imag();\n\t}\n}\n\nvoid calc(Real sx,Real sy,Real tx,Real ty){\n//\tprintf(\"%f %f %f %f\\n\",sx,sy,tx,ty);\n\tif(sx<tx){\n\t\tfor(int i=0;i<N;i++){\n\t\t\tif(sx<nx[i]&&nx[i]<tx){\n\t\t\t\tReal r=(nx[i]-sx)/(tx-sx);\n\t\t\t\tReal dy=(ty-sy)*r;\n\t\t\t\tReal y=sy+dy;\n\t\t\t\tint id;\n\t\t\t\tif(y<ny[i]) id=i*2;\n\t\t\t\telse id=i*2+1;\n//\t\t\t\tprintf(\"id=%d\\n\",id);\n\t\t\t\tif(vec.size()==0||vec.back()!=id) vec.push_back(id);\n\t\t\t\telse vec.pop_back();\n\t\t\t}\n\t\t}\n\t}else{\n\t\tfor(int i=N-1;i>=0;i--){\n\t\t\tif(tx<nx[i]&&nx[i]<sx){\n\t\t\t\tReal r=(nx[i]-sx)/(tx-sx);\n\t\t\t\tReal dy=(ty-sy)*r;\n\t\t\t\tReal y=sy+dy;\n\t\t\t\tint id;\n\t\t\t\tif(y<ny[i]) id=i*2;\n\t\t\t\telse id=i*2+1;\n//\t\t\t\tprintf(\"id=%d\\n\",id);\n\t\t\t\tif(vec.size()==0||vec.back()!=id) vec.push_back(id);\n\t\t\t\telse vec.pop_back();\n\t\t\t}\n\t\t}\n\t}\n}\n\nReal dp[10100];\n\nPoint ps[10100];\nbool dirs[10100];\n\nReal solve(){\n\tinit();\n\trot();\n\tfor(int i=0;i<M-1;i++){\n\t\tcalc(sx[i],sy[i],sx[i+1],sy[i+1]);\n\t}\n\tif(vec.size()==0){\n\t\tReal dx=sx[0]-sx[M-1],dy=sy[0]-sy[M-1];\n\t\treturn sqrt(dx*dx+dy*dy);\n\t}\n\tps[0]=Point(sx[0],sy[0]);\n\tfor(int i=0;i<vec.size();i++){\n\t\tps[i+1]=ns[vec[i]/2];\n\t\tdirs[i+1]=vec[i]%2==1;\n\t}\n\tps[vec.size()+1]=Point(sx[M-1],sy[M-1]);\n\tdp[0]=0;\n//\tfor(int i=0;i<vec.size()+2;i++){\n//\t\tprintf(\"%f %f %c\\n\",ps[i].real(),ps[i].imag(),dirs[i]?'u':'d');\n//\t}\n\tfor(int i=1;i<vec.size()+2;i++){\n\t\tdp[i]=dp[i-1]+abs(ps[i]-ps[i-1]);\n\t\tfor(int j=i-2;j>=0;j--){\n\t\t\tif(dp[i]<dp[j]+abs(ps[i]-ps[j])) continue;\n\t\t\tif(abs(ps[j]-ps[j+1])<(1e-8)) break;\n\t\t\tbool ok=true;\n\t\t\tfor(int k=j+1;k<i;k++){\n\t\t\t\tReal x1=ps[j].real(),y1_=ps[j].imag();\n\t\t\t\tReal x2=ps[i].real(),y2_=ps[i].imag();\n\t\t\t\tReal x=ps[k].real();\n\t\t\t\tReal r=(x-x1)/(x2-x1);\n\t\t\t\tReal y=y1_+(y2_-y1_)*r;\n\t\t\t\tbool flg=ps[k].imag()<y;\n\t\t\t\tif(dirs[k]!=flg){\n\t\t\t\t\tok=false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(ok){\n\t\t\t\tdp[i]=dp[j]+abs(ps[i]-ps[j]);\n\t\t\t}\n\t\t}\n\t}\n//\tfor(int i=0;i<vec.size()+2;i++){\n//\t\tprintf(\"%f \",dp[i]);\n//\t}\n//\tprintf(\"\\n\");\n\treturn dp[vec.size()+1];\n}\n\nvoid input(){\n\tscanf(\"%d%d\",&M,&N);\n\tif(M==0&&N==0) exit(0);\n\tfor(int i=0;i<M;i++){\n\t\tscanf(\"%lf%lf\",sx+i,sy+i);\n\t}\n\tfor(int i=0;i<N;i++){\n\t\tscanf(\"%lf%lf\",nx+i,ny+i);\n\t}\n}\n\nint main(){\n\twhile(true){\n\t\tinput();\n\t\tReal ans=solve();\n\t\tprintf(\"%f\\n\",ans);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1352, "score_of_the_acc": -0.0034, "final_rank": 2 }, { "submission_id": "aoj_1164_1157500", "code_snippet": "#include <cstdio>\n#include <cmath>\n#include <algorithm>\n#include <vector>\n#include <iostream>\n#include <complex>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned int uint;\ntypedef unsigned char uchar;\ntypedef unsigned long long ull;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\ntypedef vector<int> vi;\n\n#define REP(i,x) for(int i=0;i<(int)(x);i++)\n#define REPS(i,x) for(int i=1;i<=(int)(x);i++)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();i++)\n#define RFOR(i,c) for(__typeof((c).rbegin())i=(c).rbegin();i!=(c).rend();i++)\n#define ALL(container) (container).begin(), (container).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n\nnamespace geom{\n#define X real()\n#define Y imag()\n#define at(i) ((*this)[i])\n#define SELF (*this)\n\tenum {TRUE = 1, FALSE = 0, BORDER = -1};\n\ttypedef int BOOL;\n\ttypedef double R;\n\tconst R INF = 1e8;\n\tR EPS = 1e-8;\n\tinline int sig(const R &x) { return (abs(x) < EPS ? 0 : x > 0 ? 1 : -1); }\n\tinline BOOL less(const R &x, const R &y) {return sig(x-y) ? x < y : BORDER;}\n\ttypedef complex<R> P;\n\tinline R norm(const P &p){return p.X*p.X+p.Y*p.Y;}\n\tinline R inp(const P& a, const P& b){return (conj(a)*b).X;}\n\tinline R outp(const P& a, const P& b){return (conj(a)*b).Y;}\n\t\n\tstruct L : public vector<P>{\t// line\n\t\tL(const P &p1, const P &p2){this->push_back(p1);this->push_back(p2);}\n\t\tL(){}\n\t\tP dir()const {return at(1) - at(0);}\n\t\tBOOL online(const P &p)const {return !sig(outp(p-at(0), dir()));}\n\t};\n\tstruct S : public L{\n\t\tS(const P &p1, const P &p2):L(p1, p2){}\n\t\tS(){}\n\t\tBOOL online(const P &p)const {\n\t\t\treturn inp(p-at(0), dir()) > EPS && inp(p-at(1), -dir()) > -EPS;\n\t\t}\n\t};\n\tinline P crosspoint(const L &l, const L &m){\n\t\tR A = outp(l.dir(), m.dir()), B = outp(l.dir(), l[1] - m[0]);\n\t\tif(!sig(abs(A)) && !sig(abs(B))) return m[0];\n\t\treturn m[0] + B / A * (m[1] - m[0]);\n\t}\n\n#undef SELF\n#undef at\n}\n\nusing namespace geom;\n\nint f = 0;\nnamespace std{\n\tbool operator<(const P &a, const P &b){return sig(a.X-b.X) ? a.X < b.X : a.Y+EPS < b.Y;}\n\tbool operator==(const P &a, const P &b){return abs(a-b) < EPS;}\n\tistream& operator>>(istream &is, P &p){R x,y;is>>x>>y;p=P(x, y);return is;}\n}\n\nint n, m;\n\nvi path(S root, const vector<P>& pin){\n\tvi res;\n\tif(!sig(root.dir().X)) return res;\n\tREPS(i, n){\n\t\tP cp = crosspoint(root, L(pin[i], pin[i]+P(0, 1)));\n\t\tif(root.online(cp) == FALSE) continue;\n\t\tif(abs(root[0].X - cp.X) < EPS || abs(root[1].X - cp.X) < EPS) continue;\n\t\tres.push_back(pin[i].Y < cp.Y ? i : -i);\n\t}\n\tsort(ALL(res), [&](int i, int j){\n\t\treturn abs(root[0].X - pin[abs(i)].X) < abs(root[0].X - pin[abs(j)].X);\n\t});\n\treturn res;\n}\n\nint main(int argc, char *argv[]){\n\tios::sync_with_stdio(false);\n\tint T = 1;\n\twhile(cin >> m >> n, n){\n\t\tvector<P> root(m), pin(n+1);\n\t\tREP(i, m){\n\t\t\tcin >> root[i];\n\t\t\troot[i] *= polar((R)1, (R)1);\n\t\t}\n\t\tpin[0] = root[0];\n\t\tREPS(i, n){\n\t\t\tcin >> pin[i];\n\t\t\tpin[i] *= polar((R)1, (R)1);\n\t\t}\n\t\tsort(pin.begin()+1, pin.end());\n\t\tpin.push_back(root.back());\n\t\tvector<int> st;\n\t\tst.push_back(0);\n\t\tREP(i, m-1){\n\t\t\tS s(root[i], root[i+1]);\n\t\t\tvi isc = path(s, pin);\n\t\t\tFOR(it, isc){\n\t\t\t\tif(st.back() == *it) st.pop_back();\n\t\t\t\telse st.push_back(*it);\n\t\t\t}\n\t\t}\n\t\tst.push_back(n+1);\n\t\t\n\t\tvector<R> dp(st.size(), INF);\n\t\tdp[0] = .0;\n\t\tint save = 0;\n\t\tREP(i, st.size()){\n\t\t\tif(i && st[i] == -st[i-1]){\n\t\t\t\tsave = i;\n\t\t\t\tdp[i] = dp[i-1];\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor(int j=save;j<i;j++){\n\t\t\t\tS r(pin[abs(st[j])], pin[abs(st[i])]);\n\t\t\t\tif(dp[i] < dp[j] + abs(r.dir())+EPS) continue;\n\t\t\t\tvi pt = path(r, pin);\n\t\t\t\tif([&](){\n\t\t\t\t\tfor(int k=1;k<=pt.size()&&j+k<i;k++) if(pt[k-1] != st[j+k]) return 0;\n\t\t\t\t\treturn 1;\n\t\t\t\t}()) dp[i] = dp[j] + abs(r.dir());\n\t\t\t}\n\t\t}\n\t\tprintf(\"%.10f\\n\", (double)dp.back());\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3160, "memory_kb": 1376, "score_of_the_acc": -0.5406, "final_rank": 9 }, { "submission_id": "aoj_1164_1157496", "code_snippet": "#include <cstdio>\n#include <cmath>\n#include <cstring>\n#include <cstdlib>\n#include <climits>\n#include <ctime>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <list>\n#include <vector>\n#include <set>\n#include <map>\n#include <iostream>\n#include <deque>\n#include <complex>\n#include <string>\n#include <iomanip>\n#include <sstream>\n#include <bitset>\n#include <valarray>\n#include <unordered_map>\n#include <iterator>\n#include <assert.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned int uint;\ntypedef unsigned char uchar;\ntypedef unsigned long long ull;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\ntypedef vector<int> vi;\n\n#define REP(i,x) for(int i=0;i<(int)(x);i++)\n#define REPS(i,x) for(int i=1;i<=(int)(x);i++)\n#define RREP(i,x) for(int i=((int)(x)-1);i>=0;i--)\n#define RREPS(i,x) for(int i=((int)(x));i>0;i--)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();i++)\n#define RFOR(i,c) for(__typeof((c).rbegin())i=(c).rbegin();i!=(c).rend();i++)\n#define ALL(container) (container).begin(), (container).end()\n#define RALL(container) (container).rbegin(), (container).rend()\n#define SZ(container) ((int)container.size())\n#define mp(a,b) make_pair(a, b)\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n\ntemplate<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }\ntemplate<class T> ostream& operator<<(ostream &os, const vector<T> &t) {\nos<<\"[\"; FOR(it,t) {if(it!=t.begin()) os<<\",\"; os<<*it;} os<<\"]\"; return os;\n}\ntemplate<class T> ostream& operator<<(ostream &os, const set<T> &t) {\nos<<\"{\"; FOR(it,t) {if(it!=t.begin()) os<<\",\"; os<<*it;} os<<\"}\"; return os;\n}\ntemplate<class S, class T> ostream& operator<<(ostream &os, const pair<S,T> &t) { return os<<\"(\"<<t.first<<\",\"<<t.second<<\")\";}\ntemplate<class S, class T> pair<S,T> operator+(const pair<S,T> &s, const pair<S,T> &t){ return pair<S,T>(s.first+t.first, s.second+t.second);}\ntemplate<class S, class T> pair<S,T> operator-(const pair<S,T> &s, const pair<S,T> &t){ return pair<S,T>(s.first-t.first, s.second-t.second);}\n\nnamespace geom{\n#define X real()\n#define Y imag()\n#define at(i) ((*this)[i])\n#define SELF (*this)\n\tenum {TRUE = 1, FALSE = 0, BORDER = -1};\n\ttypedef int BOOL;\n\ttypedef double R;\n\tconst R INF = 1e8;\n\tR EPS = 1e-8;\n\tconst R PI = 3.1415926535897932384626;\n\tinline int sig(const R &x) { return (abs(x) < EPS ? 0 : x > 0 ? 1 : -1); }\n\tinline BOOL less(const R &x, const R &y) {return sig(x-y) ? x < y : BORDER;}\n\ttypedef complex<R> P;\n\tinline R norm(const P &p){return p.X*p.X+p.Y*p.Y;}\n\tinline R inp(const P& a, const P& b){return (conj(a)*b).X;}\n\tinline R outp(const P& a, const P& b){return (conj(a)*b).Y;}\n\tinline P unit(const P& p){return p/abs(p);}\n\tinline P proj(const P &s, const P &t){return t*inp(s, t)/norm(t);}\n\tinline int ccw(const P &s, const P &t, const P &p, int adv=0){\n\t\tint res = sig(outp(t-s, p-s));\n\t\tif(res || !adv) return res;\n\t\tif(sig(inp(t-s, p-s)) < 0) return -2;\t// p-s-t\n\t\tif(sig(inp(s-t, p-t)) < 0) return 2;\t// s-t-p\n\t\treturn 0;\t\t\t\t\t\t\t\t// s-p-t\n\t}\n\t\n\t\n\tstruct L : public vector<P>{\t// line\n\t\tL(const P &p1, const P &p2){this->push_back(p1);this->push_back(p2);}\n\t\tL(){}\n\t\tP dir()const {return at(1) - at(0);}\n\t\tBOOL online(const P &p)const {return !sig(outp(p-at(0), dir()));}\n\t};\n\tstruct S : public L{\t// segment\n\t\tS(const P &p1, const P &p2):L(p1, p2){}\n\t\tS(){}\n\t\tBOOL online(const P &p)const {\n\t\t\tif(!sig(norm(p - at(0))) || !sig(norm(p - at(1)))) return BORDER;\n\t\t\t// 座標の二乗とEPSの差が大きすぎないように注意\n\t\t\treturn !sig(outp(p-at(0), dir())) && inp(p-at(0), dir()) > EPS && inp(p-at(1), -dir()) > -EPS;\n\t\t\t//return !sig(abs(at(0)-p) + abs(at(1) - p) - abs(at(0) - at(1)));\n\t\t}\n\t};\n\tinline P proj(const P &s, const L &t){return t[0] + proj(s-t[0], t[1]-t[0]);}\n\tinline P reflect(const P &s, const L &t){return (R)2.*proj(s, t) - s;}\n\tinline S reflect(const S &s, const L &t){return S(reflect(s[0], t), reflect(s[1], t));}\n\tBOOL intersect(const S &s, const L &l){\n\t\tif(l.online(s[0]) || l.online(s[1])) return BORDER;\n\t\treturn (sig(outp(l.dir(), s[0]-l[0])) * sig(outp(l.dir(), s[1]-l[0])) <= 0);\n\t}\n\tinline P crosspoint(const L &l, const L &m){\n\t\tR A = outp(l.dir(), m.dir()), B = outp(l.dir(), l[1] - m[0]);\n\t\tif(!sig(abs(A)) && !sig(abs(B))) return m[0]; // same line\n\t\tif(abs(A) < EPS) assert(false); // !!!PRECONDITION NOT SATISFIED!!!\n\t\treturn m[0] + B / A * (m[1] - m[0]);\n\t}\n\n#undef SELF\n#undef at\n}\n\nusing namespace geom;\n\nint f = 0;\nnamespace std{\n\tbool operator<(const P &a, const P &b){return sig(a.X-b.X) ? a.X < b.X : a.Y+EPS < b.Y;}\n\tbool operator==(const P &a, const P &b){return abs(a-b) < EPS;}\n\tistream& operator>>(istream &is, P &p){R x,y;is>>x>>y;p=P(x, y);return is;}\n}\n\nint n, m;\n\nvi path(S root, const vector<P>& pin){\n\tvi res;\n\tif(!sig(root.dir().X)) return res;\n\tREPS(i, n){\n\t\tP cp = crosspoint(root, L(pin[i], pin[i]+P(0, 1)));\n\t\tif(root.online(cp) == FALSE) continue;\n\t\tif(abs(root[0].X - cp.X) < EPS || abs(root[1].X - cp.X) < EPS) continue;\n\t\tres.push_back(pin[i].Y < cp.Y ? i : -i);\n\t}\n\tsort(ALL(res), [&](int i, int j){\n\t\treturn abs(root[0].X - pin[abs(i)].X) < abs(root[0].X - pin[abs(j)].X);\n\t});\n\treturn res;\n}\n\nint main(int argc, char *argv[]){\n\tios::sync_with_stdio(false);\n\tint T = 1;\n\twhile(cin >> m >> n, n){\n\t\tvector<P> root(m), pin(n+1);\n\t\tREP(i, m){\n\t\t\tcin >> root[i];\n\t\t\troot[i] *= polar((R)1, (R)1);\n\t\t}\n\t\tpin[0] = root[0];\n\t\tREPS(i, n){\n\t\t\tcin >> pin[i];\n\t\t\tpin[i] *= polar((R)1, (R)1);\n\t\t}\n\t\tsort(pin.begin()+1, pin.end());\n\t\tpin.push_back(root.back());\n\t\tvector<int> st;\n\t\tst.push_back(0);\n\t\tREP(i, m-1){\n\t\t\tS s(root[i], root[i+1]);\n\t\t\tvi isc = path(s, pin);\n\t\t\tFOR(it, isc){\n\t\t\t\tif(st.back() == *it) st.pop_back();\n\t\t\t\telse st.push_back(*it);\n\t\t\t}\n\t\t}\n\t\tst.push_back(n+1);\n\t\t\n\t\tvector<R> dp(st.size(), INF);\n\t\tdp[0] = .0;\n\t\tint save = 0;\n\t\tREP(i, st.size()){\n\t\t\tif(i && st[i] == -st[i-1]){\n\t\t\t\tsave = i;\n\t\t\t\tdp[i] = dp[i-1];\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor(int j=save;j<i;j++){\n\t\t\t\tS r(pin[abs(st[j])], pin[abs(st[i])]);\n\t\t\t\tvi pt = path(r, pin);\n\t\t\t\tif([&](){\n\t\t\t\t\tfor(int k=1;k<=pt.size()&&j+k<i;k++) if(pt[k-1] != st[j+k]) return 0;\n\t\t\t\t\treturn 1;\n\t\t\t\t}()) chmin(dp[i], dp[j] + abs(r.dir()));\n\t\t\t}\n\t\t}\n\t\tprintf(\"%.10f\\n\", (double)dp.back());\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 4570, "memory_kb": 1376, "score_of_the_acc": -0.7825, "final_rank": 11 }, { "submission_id": "aoj_1164_1157495", "code_snippet": "#include <cstdio>\n#include <cmath>\n#include <cstring>\n#include <cstdlib>\n#include <climits>\n#include <ctime>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <list>\n#include <vector>\n#include <set>\n#include <map>\n#include <iostream>\n#include <deque>\n#include <complex>\n#include <string>\n#include <iomanip>\n#include <sstream>\n#include <bitset>\n#include <valarray>\n#include <unordered_map>\n#include <iterator>\n#include <assert.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned int uint;\ntypedef unsigned char uchar;\ntypedef unsigned long long ull;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\ntypedef vector<int> vi;\n\n#define REP(i,x) for(int i=0;i<(int)(x);i++)\n#define REPS(i,x) for(int i=1;i<=(int)(x);i++)\n#define RREP(i,x) for(int i=((int)(x)-1);i>=0;i--)\n#define RREPS(i,x) for(int i=((int)(x));i>0;i--)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();i++)\n#define RFOR(i,c) for(__typeof((c).rbegin())i=(c).rbegin();i!=(c).rend();i++)\n#define ALL(container) (container).begin(), (container).end()\n#define RALL(container) (container).rbegin(), (container).rend()\n#define SZ(container) ((int)container.size())\n#define mp(a,b) make_pair(a, b)\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n\ntemplate<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }\ntemplate<class T> ostream& operator<<(ostream &os, const vector<T> &t) {\nos<<\"[\"; FOR(it,t) {if(it!=t.begin()) os<<\",\"; os<<*it;} os<<\"]\"; return os;\n}\ntemplate<class T> ostream& operator<<(ostream &os, const set<T> &t) {\nos<<\"{\"; FOR(it,t) {if(it!=t.begin()) os<<\",\"; os<<*it;} os<<\"}\"; return os;\n}\ntemplate<class S, class T> ostream& operator<<(ostream &os, const pair<S,T> &t) { return os<<\"(\"<<t.first<<\",\"<<t.second<<\")\";}\ntemplate<class S, class T> pair<S,T> operator+(const pair<S,T> &s, const pair<S,T> &t){ return pair<S,T>(s.first+t.first, s.second+t.second);}\ntemplate<class S, class T> pair<S,T> operator-(const pair<S,T> &s, const pair<S,T> &t){ return pair<S,T>(s.first-t.first, s.second-t.second);}\n\nnamespace geom{\n#define X real()\n#define Y imag()\n#define at(i) ((*this)[i])\n#define SELF (*this)\n\tenum {TRUE = 1, FALSE = 0, BORDER = -1};\n\ttypedef int BOOL;\n\ttypedef double R;\n\tconst R INF = 1e8;\n\tR EPS = 1e-8;\n\tconst R PI = 3.1415926535897932384626;\n\tinline int sig(const R &x) { return (abs(x) < EPS ? 0 : x > 0 ? 1 : -1); }\n\tinline BOOL less(const R &x, const R &y) {return sig(x-y) ? x < y : BORDER;}\n\ttypedef complex<R> P;\n\tinline R norm(const P &p){return p.X*p.X+p.Y*p.Y;}\n\tinline R inp(const P& a, const P& b){return (conj(a)*b).X;}\n\tinline R outp(const P& a, const P& b){return (conj(a)*b).Y;}\n\tinline P unit(const P& p){return p/abs(p);}\n\tinline P proj(const P &s, const P &t){return t*inp(s, t)/norm(t);}\n\tinline int ccw(const P &s, const P &t, const P &p, int adv=0){\n\t\tint res = sig(outp(t-s, p-s));\n\t\tif(res || !adv) return res;\n\t\tif(sig(inp(t-s, p-s)) < 0) return -2;\t// p-s-t\n\t\tif(sig(inp(s-t, p-t)) < 0) return 2;\t// s-t-p\n\t\treturn 0;\t\t\t\t\t\t\t\t// s-p-t\n\t}\n\t\n\t\n\tstruct L : public vector<P>{\t// line\n\t\tL(const P &p1, const P &p2){this->push_back(p1);this->push_back(p2);}\n\t\tL(){}\n\t\tP dir()const {return at(1) - at(0);}\n\t\tBOOL online(const P &p)const {return !sig(outp(p-at(0), dir()));}\n\t};\n\tstruct S : public L{\t// segment\n\t\tS(const P &p1, const P &p2):L(p1, p2){}\n\t\tS(){}\n\t\tBOOL online(const P &p)const {\n\t\t\tif(!sig(norm(p - at(0))) || !sig(norm(p - at(1)))) return BORDER;\n\t\t\t// 座標の二乗とEPSの差が大きすぎないように注意\n\t\t\treturn !sig(outp(p-at(0), dir())) && inp(p-at(0), dir()) > EPS && inp(p-at(1), -dir()) > -EPS;\n\t\t\t//return !sig(abs(at(0)-p) + abs(at(1) - p) - abs(at(0) - at(1)));\n\t\t}\n\t};\n\tstruct C : public P{\n\t\tC(){}\n\t\tC(const P& p, const R r):P(p), r(r){}\n\t\tR r;\n\t\tBOOL inside(const P& p)const { return less(norm(p-SELF), r*r);}\n\t};\n\tstruct F : public C{\n\t\tR s, t;\n\t\tF(const C &c, R ss, R tt):C(c), s(ss), t(tt){\n\t\t\tif(PI < s) s -= 2*PI;\n\t\t\tif(PI < t) t -= 2*PI;\n\t\t}\n\t\tBOOL inside(const P& p)const {\n\t\t\tP v = p - SELF;\n\t\t\tif(!sig(norm(v))) return BORDER;\n\t\t\tR a = arg(v);\n\t\t\tif(t < s){\n\t\t\t\tif((!less(s, a) && !less(a, t)) || !less(norm(v), r*r)) return FALSE;\n\t\t\t\treturn less(s, a) | less(a, t) | less(norm(v), r*r);\n\t\t\t}else{\n\t\t\t\tif(!less(s, a) || !less(a, t) || !less(norm(v), r*r)) return FALSE;\n\t\t\t\treturn less(s, a) | less(a, t) | less(norm(v), r*r);\n\t\t\t}\n\t\t}\n\t};\n\tP crosspoint(const L &l, const L &m);\n\tstruct G : public vector<P>{\n\t\tG(size_type size=0):vector(size){}\n\t\tS edge(int i)const {return S(at(i), at(i+1 == size() ? 0 : i+1));}\n\t\tBOOL contains(const P &p)const {\n\t\t\tR sum = .0;\n\t\t\tREP(i, size()){\n\t\t\t\tif(S(at(i), at((i+1)%size())).online(p)) return BORDER;\t// online\n\t\t\t\tsum += arg((at(i) - p) / (at((i+1)%size()) - p));\n\t\t\t}\n\t\t\treturn !!sig(sum);\n\t\t}\n\t\tR area()const {\n\t\t\tR sum = 0;\n\t\t\tREP(i, size()) sum += outp(at(i), at((i+1)%size()));\n\t\t\treturn abs(sum / 2.);\n\t\t}\n\t\tP gp()const {\n\t\t\tP r(.0, .0);\n\t\t\tREP(i, size()){\n\t\t\t\tconst S &s = edge(i);\n\t\t\t\tr += (s[0]+s[1])*outp(s[0], s[1]);\n\t\t\t}\n\t\t\treturn r / (6*area());\n\t\t}\n\t\tG convex_hull(bool online = false) {\n\t\t\tif(size() < 2) return *this;\n\t\t\tsort(ALL(*this));\n\t\t\tG r;\n\t\t\tr.resize((int)size()*2);\n\t\t\tint k=0;\n\t\t\tfor(int i=0;i<size();r[k++]=at(i++))\n\t\t\t\twhile(k>1 && ccw(r[k-2], r[k-1], at(i)) < 1-online) k--;\n\t\t\tint t = k;\n\t\t\tfor(int i=(int)size()-1;i>=0;r[k++]=at(i--))\n\t\t\t\twhile(k>t && ccw(r[k-2], r[k-1], at(i)) < 1-online) k--;\n\t\t\tr.resize(k-1);\n\t\t\treturn r;\n\t\t}\n\t\tG cut(const L &l)const {\n\t\t\tG g;\n\t\t\tREP(i, size()){\n\t\t\t\tconst S &s = edge(i);\n\t\t\t\tif(ccw(l[0], l[1], s[0], 0) >= 0) g.push_back(s[0]);\n\t\t\t\tif(ccw(l[0], l[1], s[0], 0) * ccw(l[0], l[1], s[1], 0) < 0)\n\t\t\t\t\tg.push_back(crosspoint(s, l));\n\t\t\t}\n\t\t\treturn g;\n\t\t}\n\t\tG Voronoi(const vector<P> &p, const int t)const {\n\t\t\tG g = *this;\n\t\t\tREP(i, p.size())if(i!=t){\n\t\t\t\tconst P m = (p[t]+p[i])*(R)0.5;\n\t\t\t\tg = g.cut(L(m, m+(p[i]-p[t])*P(0, 1)));\n\t\t\t}\n\t\t\treturn g;\n\t\t}\n\t};\n\n\tinline P proj(const P &s, const L &t){return t[0] + proj(s-t[0], t[1]-t[0]);}\n\tinline P reflect(const P &s, const L &t){return (R)2.*proj(s, t) - s;}\n\tinline S reflect(const S &s, const L &t){return S(reflect(s[0], t), reflect(s[1], t));}\n\tBOOL intersect(const S &s, const S &t){\n\t\tconst int p = ccw(t[0], t[1], s[0], 1) * ccw(t[0], t[1], s[1], 1);\n\t\tconst int q = ccw(s[0], s[1], t[0], 1) * ccw(s[0], s[1], t[1], 1);\n\t\treturn (p>0||q>0) ? FALSE : (!p||!q) ? BORDER : TRUE;\n\t}\n\tBOOL intersect(const S &s, const L &l){\n\t\tif(l.online(s[0]) || l.online(s[1])) return BORDER;\n\t\treturn (sig(outp(l.dir(), s[0]-l[0])) * sig(outp(l.dir(), s[1]-l[0])) <= 0);\n\t}\n\tR dist2(const L &l, const P &p){return norm(outp(l.dir(), p - l[0])) / norm(l.dir());}\n\tR dist2(const S &s, const P &p){\n\t\tif(inp(p-s[0], s.dir()) < EPS) return norm(p - s[0]);\n\t\tif(inp(p-s[1], -s.dir()) < EPS) return norm(p - s[1]);\n\t\treturn dist2((const L &)s, p);\n\t}\n\tR dist2(const S &s, const L &l){\n\t\treturn intersect(s, l) ? .0 : min(dist2(l, s[0]), dist2(l, s[1]));\n\t}\n\tR dist2(const S &s, const S &t){\n\t\treturn intersect(s, t) ? .0 : min(min(dist2(s, t[0]), dist2(t, s[0])), \n\t\t\t\t\t\t\t\t\t \t min(dist2(s, t[1]), dist2(t, s[1])));\n\t}\n\ttemplate <class T> R dist2(const G &g, const T& t){ // todo: 内部に完全に含まれる場合\n\t\tR res = INF;\n\t\tREP(i, g.size()) res = min(res, dist2(g.edge(i), t));\n\t\treturn res;\n\t}\n\ttemplate<class S, class T> R dist(const S& s, const T& t){return sqrt(dist2(s, t));}\n\tinline BOOL intersect(const C &a, const C &b){\n\t\treturn less((a.r-b.r)*(a.r-b.r), norm(a-b)) + less(norm(a-b), (a.r+b.r)*(a.r+b.r)) - 1;\n\t}\n\tinline BOOL intersect(const C &c, const L &l){\n\t\treturn less(dist2(l, c), c.r*c.r);\n\t}\n\tinline BOOL intersect(const C &c, const S &s){\n\t\tint d = less(dist2(s, c), c.r*c.r);\n\t\tif(d != TRUE) return d;\n\t\tint p = c.inside(s[0]), q = c.inside(s[1]);\n\t\treturn (p<0 || q<0) ? BORDER : p&q;\n\t}\n\tinline P crosspoint(const L &l, const L &m){\n\t\tR A = outp(l.dir(), m.dir()), B = outp(l.dir(), l[1] - m[0]);\n\t\tif(!sig(abs(A)) && !sig(abs(B))) return m[0]; // same line\n\t\tif(abs(A) < EPS) assert(false); // !!!PRECONDITION NOT SATISFIED!!!\n\t\treturn m[0] + B / A * (m[1] - m[0]);\n\t}\n\n#undef SELF\n#undef at\n}\n\nusing namespace geom;\n\nint f = 0;\nnamespace std{\n\tbool operator<(const P &a, const P &b){return sig(a.X-b.X) ? a.X < b.X : a.Y+EPS < b.Y;}\n\tbool operator==(const P &a, const P &b){return abs(a-b) < EPS;}\n\tistream& operator>>(istream &is, P &p){R x,y;is>>x>>y;p=P(x, y);return is;}\n\tistream& operator>>(istream &is, L &l){l.resize(2);return is >> l[0] >> l[1];}\n\tistream& operator>>(istream &is, C &c){return is >> (P &)c >> c.r;}\n\tconst R B = 200;\n\tconst R Z = .5;\n\tostream& operator<<(ostream &os, const C &c){return os << \"circle(\"<<B+Z*(c.X)<<\", \"<<1000-B-Z*(c.Y)<<\", \"<<Z*(c.r)<<\")\";}\n\tostream& operator<<(ostream &os, const P &p){return os << C(p, 2./Z);}\n\tostream& operator<<(ostream &os, const S &s){return os << \"line(\"<<B+Z*(s[0].X)<<\", \"<<1000-B-Z*(s[0].Y)<<\", \"<<B+Z*(s[1].X)<<\", \"<<1000-B-Z*(s[1].Y)<<\")\";}\n\tostream& operator<<(ostream &os, const G &g){REP(i, g.size()) os << g.edge(i) << endl;return os;}\n\n}\n\nint n, m;\n\nvi path(S root, const vector<P>& pin){\n\tvi res;\n\tif(!sig(root.dir().X)) return res;\n\tREPS(i, n){\n\t\tP cp = crosspoint(root, L(pin[i], pin[i]+P(0, 1)));\n\t\tif(root.online(cp) == FALSE) continue;\n\t\tif(abs(root[0].X - cp.X) < EPS || abs(root[1].X - cp.X) < EPS) continue;\n\t\tres.push_back(pin[i].Y < cp.Y ? i : -i);\n\t}\n\tsort(ALL(res), [&](int i, int j){\n\t\treturn abs(root[0].X - pin[abs(i)].X) < abs(root[0].X - pin[abs(j)].X);\n\t});\n\treturn res;\n}\n\nint main(int argc, char *argv[]){\n\tios::sync_with_stdio(false);\n\tint T = 1;\n\twhile(cin >> m >> n, n){\n\t\tvector<P> root(m), pin(n+1);\n\t\tREP(i, m){\n\t\t\tcin >> root[i];\n\t\t\troot[i] *= polar((R)1, (R)1);\n\t\t}\n\t\tpin[0] = root[0];\n\t\tREPS(i, n){\n\t\t\tcin >> pin[i];\n\t\t\tpin[i] *= polar((R)1, (R)1);\n\t\t}\n\t\tsort(pin.begin()+1, pin.end());\n\t\tpin.push_back(root.back());\n\t\tvector<int> st;\n\t\tst.push_back(0);\n\t\tREP(i, m-1){\n\t\t\tS s(root[i], root[i+1]);\n\t\t\tvi isc = path(s, pin);\n\t\t\tFOR(it, isc){\n\t\t\t\tif(st.back() == *it) st.pop_back();\n\t\t\t\telse st.push_back(*it);\n\t\t\t}\n\t\t}\n\t\tst.push_back(n+1);\n\t\t\n\t\tvector<R> dp(st.size(), INF);\n\t\tvi prev(st.size());\n\t\tdp[0] = .0;\n\t\tint save = 0;\n\t\tREP(i, st.size()){\n\t\t\tif(i && st[i] == -st[i-1]){\n\t\t\t\tsave = i;\n\t\t\t\tdp[i] = dp[i-1];\n\t\t\t\tprev[i] = prev[i-1];\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor(int j=save;j<i;j++){\n\t\t\t\tS r(pin[abs(st[j])], pin[abs(st[i])]);\n\t\t\t\tvi pt = path(r, pin);\n\t\t\t\tif([&](){\n\t\t\t\t\tfor(int k=1;k<=pt.size()&&j+k<i;k++) if(pt[k-1] != st[j+k]) return 0;\n\t\t\t\t\treturn 1;\n\t\t\t\t}()){\n\t\t\t\t\tif(chmin(dp[i], dp[j] + abs(r.dir()))){\n\t\t\t\t\t\tprev[i] = j;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tprintf(\"%.10f\\n\", (double)dp.back());\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 4590, "memory_kb": 1380, "score_of_the_acc": -0.786, "final_rank": 12 }, { "submission_id": "aoj_1164_1136497", "code_snippet": "#include <algorithm>\n#include <cmath>\n#include <iomanip>\n#include <iostream>\n#include <limits>\n#include <vector>\nnamespace lc {\nstatic const double EPS = 1e-9;\n}\nnamespace lc {\nstruct Point {\n\tdouble x;\n\tdouble y;\n\texplicit Point(const double &x = 0.0, const double &y = 0.0) :\n\t\tx(x), y(y)\n\t{ }\n\tPoint operator+(const Point &p) const { return Point(x + p.x, y + p.y); }\n\tPoint &operator+=(const Point &p){ return *this = *this + p; }\n\tPoint operator-(const Point &p) const { return Point(x - p.x, y - p.y); }\n\tPoint operator*(double s) const { return Point(x * s, y * s); }\n\tbool operator==(const Point &p) const { return x == p.x && y == p.y; }\n\tbool operator<(const Point &p) const {\n\t\treturn (x == p.x) ? (y < p.y) : (x < p.x);\n\t}\n\tdouble abs() const { return sqrt(x * x + y * y); }\n\tdouble norm() const { return x * x + y * y; }\n};\ninline Point operator*(double s, const Point &p){ return p * s; }\ninline double cross(const Point &a, const Point &b){\n\treturn a.x * b.y - a.y * b.x;\n}\ninline double dot(const Point &a, const Point &b){\n\treturn a.x * b.x + a.y * b.y;\n}\ninline int ccw(const Point &a, const Point &b, const Point &c){\n\tPoint d = b - a, e = c - a;\n\tif(cross(d, e) > 0.0){ return 1; }\n\tif(cross(d, e) < 0.0){ return -1; }\n\tif(dot(d, e) < 0.0){ return 2; }\n\tif(d.abs() < e.abs()){ return -2; }\n\treturn 0;\n}\n}\nnamespace lc {\nstruct Line {\n\tPoint a;\n\tPoint b;\n\texplicit Line(const Point &a = Point(), const Point &b = Point()) :\n\t\ta(a), b(b)\n\t{ }\n\tPoint projection(const Point &p) const {\n\t\tdouble t = dot(p - a, b - a) / (b - a).norm();\n\t\treturn a + t * (b - a);\n\t}\n};\n}\nnamespace lc {\nclass Polygon {\nprivate:\n\tstd::vector<Point> m_points;\npublic:\n\tPolygon() : m_points() { }\n\texplicit Polygon(size_t s, const Point &p = Point())\n\t\t: m_points(s, p)\n\t{ }\n\ttemplate <typename Iterator>\n\texplicit Polygon(Iterator begin, Iterator end)\n\t\t: m_points(begin, end)\n\t{ }\n\texplicit Polygon(std::initializer_list<Point> init)\n\t\t: m_points(init)\n\t{ }\n\tconst Point &operator[](int i) const { return m_points[i]; }\n\tPoint &operator[](int i){ return m_points[i]; }\n\tint size() const { return static_cast<int>(m_points.size()); }\n\tint contains(const Point &p) const {\n\t\tint result = -1;\n\t\tfor(int i = 0; i < size(); ++i){\n\t\t\tPoint a = m_points[i] - p;\n\t\t\tPoint b = m_points[(i + 1) % size()] - p;\n\t\t\tif(a.y > b.y){ std::swap(a, b); }\n\t\t\tif(a.y <= 0.0 && b.y > 0.0 && cross(a, b) < 0.0){\n\t\t\t\tresult = -result;\n\t\t\t}\n\t\t\tif(cross(a, b) == 0.0 && dot(a, b) <= 0.0){ return 0; }\n\t\t}\n\t\treturn result;\n\t}\n};\n}\nnamespace lc {\ninline Polygon convex_hull(const std::vector<Point> &points){\n\tconst int n = points.size();\n\tstd::vector<Point> ps(points);\n\tstd::sort(ps.begin(), ps.end());\n\tstd::vector<Point> ch(2 * n);\n\tint k = 0;\n\tfor(int i = 0; i < n; ch[k++] = ps[i++]){\n\t\twhile(k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0){ --k; }\n\t}\n\tfor(int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--]){\n\t\twhile(k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0){ --k; }\n\t}\n\tch.resize(k - 1);\n\treturn Polygon(ch.begin(), ch.end());\n}\n}\nnamespace lc {\nclass Visualizer {\nprivate:\n\tdouble m_scale;\n\tdouble m_offset_x;\n\tdouble m_offset_y;\npublic:\n\texplicit Visualizer(\n\t\tdouble scale = 1.0, double offset_x = 0.0, double offset_y = 0.0)\n\t\t: m_scale(scale)\n\t\t, m_offset_x(offset_x)\n\t\t, m_offset_y(offset_y)\n\t{ }\n};\n}\nusing namespace std;\nstatic const double EPS = lc::EPS;\nstatic const lc::Point DIR_TABLE[4] = {\n\tlc::Point(1.0, 0.0),\n\tlc::Point(0.0, 1.0),\n\tlc::Point(-1.0, 0.0),\n\tlc::Point(0.0, -1.0)\n};\nint main(){\n\tios_base::sync_with_stdio(false);\n\tcout << setiosflags(ios::fixed) << setprecision(10);\n\tlc::Visualizer vis(1.0, 0.0, 0.0);\n\twhile(true){\n\t\tint m, n;\n\t\tcin >> m >> n;\n\t\tif(m == 0 && n == 0){ break; }\n\t\tvector<lc::Point> segments(m), polls(n * 4);\n\t\tfor(int i = 0; i < m; ++i){ cin >> segments[i].x >> segments[i].y; }\n\t\tfor(int i = 0; i < n; ++i){\n\t\t\tdouble x, y;\n\t\t\tcin >> x >> y;\n\t\t\tpolls[i * 4 + 0] = lc::Point(x, y) + DIR_TABLE[0] * 10.0 * EPS;\n\t\t\tpolls[i * 4 + 1] = lc::Point(x, y) + DIR_TABLE[1] * 10.0 * EPS;\n\t\t\tpolls[i * 4 + 2] = lc::Point(x, y) + DIR_TABLE[2] * 10.0 * EPS;\n\t\t\tpolls[i * 4 + 3] = lc::Point(x, y) + DIR_TABLE[3] * 10.0 * EPS;\n\t\t}\n\t\twhile(true){\n\t\t\tbool modified = false;\n\t\t\tsegments.erase(unique(\n\t\t\t\tsegments.begin(), segments.end()), segments.end());\n\t\t\tvector<lc::Point> next;\n\t\t\tnext.clear();\n\t\t\tfor(size_t i = 0; i < segments.size(); ++i){\n\t\t\t\tnext.push_back(segments[i]);\n\t\t\t\tif(i + 2 >= segments.size()){ continue; }\n\t\t\t\tif((segments[i + 2] - segments[i]).abs() < 2.0 * EPS){ continue; }\n\t\t\t\tlc::Polygon tri({\n\t\t\t\t\tsegments[i], segments[i + 1], segments[i + 2]\n\t\t\t\t});\n\t\t\t\tfor(size_t j = 0; j < polls.size(); ++j){\n\t\t\t\t\tconst auto &p = polls[j];\n\t\t\t\t\tif(tri[1] == p){ tri[1] += DIR_TABLE[j % 4] * EPS; }\n\t\t\t\t}\n\t\t\t\tvector<lc::Point> pts({ segments[i], segments[i + 2] });\n\t\t\t\tfor(size_t j = 0; j < polls.size(); ++j){\n\t\t\t\t\tconst auto &p = polls[j];\n\t\t\t\t\tconst int contains = tri.contains(p);\n\t\t\t\t\tif(contains > 0){\n\t\t\t\t\t\tpts.push_back(p);\n\t\t\t\t\t}else if(contains == 0){\n\t\t\t\t\t\tconst auto &dir = DIR_TABLE[j % 4];\n\t\t\t\t\t\tconst auto proj = lc::Line(\n\t\t\t\t\t\t\tsegments[i], segments[i + 2]).projection(p);\n\t\t\t\t\t\tif(lc::dot(proj - p, dir) < 0.0){ pts.push_back(p); }\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tconst lc::Polygon conv = convex_hull(pts);\n\t\t\t\tint locs[3] = { -1, -1, -1 };\n\t\t\t\tfor(int j = 0; j < conv.size(); ++j){\n\t\t\t\t\tfor(int k = 0; k < 3; ++k){\n\t\t\t\t\t\tif(segments[i + k] == conv[j]){ locs[k] = j; }\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(locs[1] < 0){\n\t\t\t\t\tconst int t = conv.size();\n\t\t\t\t\tconst int d = ((locs[0] + 1) % t == locs[2]) ? -1 : 1;\n\t\t\t\t\tfor(int j = locs[0]; j != locs[2]; j = (j + d + t) % t){\n\t\t\t\t\t\tnext.push_back(conv[j]);\n\t\t\t\t\t}\n\t\t\t\t\tmodified = true;\n\t\t\t\t\tfor(size_t j = i + 2; j < segments.size(); ++j){\n\t\t\t\t\t\tnext.push_back(segments[j]);\n\t\t\t\t\t}\n\t\t\t\t\tbreak;\n\t\t\t\t}else{\n\t\t\t\t\tnext.push_back(segments[i]);\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!modified){ break; }\n\t\t\tsegments.swap(next);\n\t\t}\n\t\tdouble answer = 0.0;\n\t\tfor(size_t i = 0; i + 1 < segments.size(); ++i){\n\t\t\tanswer += (segments[i + 1] - segments[i]).abs();\n\t\t}\n\t\tcout << answer << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1530, "memory_kb": 1352, "score_of_the_acc": -0.2607, "final_rank": 8 } ]
aoj_1158_cpp
Problem F: ICPC: Intelligent Congruent Partition of Chocolate The twins named Tatsuya and Kazuya love chocolate. They have found a bar of their favorite chocolate in a very strange shape. The chocolate bar looks to have been eaten partially by Mam. They, of course, claim to eat it and then will cut it into two pieces for their portions. Since they want to be sure that the chocolate bar is fairly divided, they demand that the shapes of the two pieces are congruent and that each piece is connected . The chocolate bar consists of many square shaped blocks of chocolate connected to the adjacent square blocks of chocolate at their edges. The whole chocolate bar is also connected. Cutting the chocolate bar along with some edges of square blocks, you should help them to divide it into two congruent and connected pieces of chocolate. That is, one piece fits into the other after it is rotated, turned over and moved properly. Figure F-1: A partially eaten chocolate bar with 18 square blocks of chocolate For example, there is a partially eaten chocolate bar with 18 square blocks of chocolate as depicted in Figure F-1. Cutting it along with some edges of square blocks, you get two pieces of chocolate with 9 square blocks each as depicted in Figure F-2. Figure F-2: Partitioning of the chocolate bar in Figure F-1 You get two congruent and connected pieces as the result. One of them consists of 9 square blocks hatched with horizontal lines and the other with vertical lines. Rotated clockwise with a right angle and turned over on a horizontal line, the upper piece exactly fits into the lower piece. Figure F-3: A shape that cannot be partitioned into two congruent and connected pieces Two square blocks touching only at their corners are regarded as they are not connected to each other. Figure F-3 is an example shape that cannot be partitioned into two congruent and connected pieces. Note that, without the connectivity requirement, this shape can be partitioned into two congruent pieces with three squares (Figure F-4). Figure F-4: Two congruent but disconnected pieces Your job is to write a program that judges whether a given bar of chocolate can be partitioned into such two congruent and connected pieces or not. Input The input is a sequence of datasets. The end of the input is indicated by a line containing two zeros separated by a space. Each dataset is formatted as follows. w h r (1, 1) ... r (1, w ) r (2, 1) ... r (2, w ) ... r ( h , 1) ... r ( h , w ) The integers w and h are the width and the height of a chocolate bar, respectively. You may assume 2 ≤ w ≤ 10 and 2 ≤ h ≤ 10. Each of the following h lines consists of w digits delimited by a space. The digit r ( i , j ) represents the existence of a square block of chocolate at the position ( i , j ) as follows. '0': There is no chocolate (i.e., already eaten). '1': There is a square block of chocolate. You can assume that there are at most 36 square blocks of chocolate in the bar, i.e., the ...(truncated)
[ { "submission_id": "aoj_1158_10335906", "code_snippet": "// AOJ #1158 ICPC: Intelligent Congruent Partition of Chocolate\n// 2025.3.30\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing ull = unsigned long long;\n\nconstexpr int dY[4] = {0, 1, 0, -1};\nconstexpr int dX[4] = {1, 0, -1, 0};\n\nstruct State {\n ull m1, m2;\n bool operator==(const State &other) const {\n return m1 == other.m1 && m2 == other.m2;\n }\n};\n\nstruct StateHash {\n size_t operator()(const State &s) const {\n auto h1 = std::hash<ull>()(s.m1);\n auto h2 = std::hash<ull>()(s.m2);\n return h1 ^ (h2 + 0x9e3779b97f4a7c15ULL + (h1 << 6) + (h1 >> 2));\n }\n};\n\nint main(){\n ios::sync_with_stdio(0);\n cin.tie(0);\n\n while(true) {\n int w, h;\n cin >> w >> h;\n if(w == 0) break;\n\n vector<vector<int>> grid(h, vector<int>(w));\n vector<vector<int>> idx(h, vector<int>(w, -1));\n vector<int> Xs, Ys;\n for(int i = 0; i < h; ++i){\n for(int j = 0; j < w; ++j){\n cin >> grid[i][j];\n if(grid[i][j] == 1) {\n idx[i][j] = Ys.size();\n Ys.push_back(i);\n Xs.push_back(j);\n }\n }\n }\n const int n = Xs.size();\n if(n & 1) {\n cout << \"NO\" << endl;\n continue;\n }\n\n auto inRange = [&](int y, int x) -> bool {\n return 0 <= y && y < h && 0 <= x && x < w;\n };\n\n auto calcDY = [&](int mir, int rot, int sdy, int sdx) -> int {\n if(rot == 0) return sdy;\n else if(rot == 1) return (mir ? -sdx : sdx);\n else if(rot == 2) return -sdy;\n else return (mir ? sdx : -sdx);\n };\n auto calcDX = [&](int mir, int rot, int sdy, int sdx) -> int {\n if(rot == 0) return (mir ? -sdx : sdx);\n else if(rot == 1) return sdy;\n else if(rot == 2) return (mir ? sdx : -sdx);\n else return -sdy;\n };\n\n bool ok = false;\n for (int j = 1; j < n && !ok; ++j) {\n for (int rot = 0; rot < 4 && !ok; ++rot) {\n for (int mir = 0; mir < 2 && !ok; ++mir) {\n unordered_set<State, StateHash> memo;\n function<bool(ull, ull)> dfs = [&](ull m1, ull m2) -> bool {\n if (__builtin_popcountll(m1) == n/2) return true;\n State st { m1, m2 };\n if(memo.count(st)) return false;\n memo.insert(st);\n for (int i = 0; i < n; ++i) {\n if (!(m1 & (1ULL << i))) continue;\n int cy = Ys[i], cx = Xs[i];\n for (int d = 0; d < 4; ++d) {\n int ny1 = cy + dY[d], nx1 = cx + dX[d];\n if(!inRange(ny1, nx1)) continue;\n if(idx[ny1][nx1] == -1) continue;\n int id1 = idx[ny1][nx1];\n int relY = ny1 - Ys[0], relX = nx1 - Xs[0];\n int ny2 = Ys[j] + calcDY(mir, rot, relY, relX);\n int nx2 = Xs[j] + calcDX(mir, rot, relY, relX);\n if(!inRange(ny2, nx2)) continue;\n if(idx[ny2][nx2] == -1) continue;\n int id2 = idx[ny2][nx2];\n if(id1 == id2) continue;\n if ((m1 | m2) & (1ULL << id1)) continue;\n if ((m1 | m2) & (1ULL << id2)) continue;\n ull nm1 = m1 | (1ULL << id1);\n ull nm2 = m2 | (1ULL << id2);\n if(dfs(nm1, nm2)) return true;\n }\n }\n return false;\n };\n ull start_m1 = 1ULL << 0;\n ull start_m2 = 1ULL << j;\n if(dfs(start_m1, start_m2)){\n ok = true;\n break;\n }\n }\n }\n }\n cout << (ok ? \"YES\" : \"NO\") << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 760, "memory_kb": 5256, "score_of_the_acc": -0.3465, "final_rank": 4 }, { "submission_id": "aoj_1158_9481636", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint dx[4] = {1,0,-1,0}, dy[4] = {0,1,0,-1};\nint N, M, K;\nvector<pair<int,int>> P;\nvector<ll> G;\nclock_t start;\n\nbool Check(ll X) {\n vector<pair<int,int>> L, R;\n int LYMIN = M, LYMAX = 0, RYMIN = M, RYMAX = 0;\n rep(i,0,(int)(P.size())) {\n if (X & (1LL<<i)) L.push_back(P[i]), chmin(LYMIN,P[i].second), chmax(LYMAX,P[i].second);\n else R.push_back(P[i]), chmin(RYMIN,P[i].second), chmax(RYMAX,P[i].second);\n }\n sort(L.begin(), L.end());\n sort(R.begin(), R.end());\n int DLX = L[K-1].first-L[0].first, DRX = R[K-1].first-R[0].first, DLY = LYMAX-LYMIN, DRY = RYMAX-RYMIN;\n if ((DLX+DLY != DRX+DRY) || (abs(DLX-DLY) != abs(DRX-DRY))) return false;\n rep(__,0,2) {\n rep(_,0,4) {\n sort(R.begin(), R.end());\n bool check = true;\n int DX = R[0].first - L[0].first, DY = R[0].second - L[0].second;\n rep(i,1,K) {\n if ((R[i].first - L[i].first != DX) || (R[i].second - L[i].second != DY)) {\n check = false;\n break;\n }\n }\n if (check) return true;\n rep(i,0,K) {\n swap(R[i].first, R[i].second);\n R[i].first = -R[i].first;\n }\n }\n rep(i,0,K) R[i].first = -R[i].first;\n }\n return false;\n}\n\nbool DFS(int CurL, int CurR, ll L, ll R, ll X) {\n clock_t end = clock();\n const double time = static_cast<double>(end - start) / CLOCKS_PER_SEC;\n if (time > 0.375) return false;\n if (CurL == K) {\n if (Check(L)) return true;\n return false;\n }\n if (X == 0) return false;\n int LOW = lowbit<ll>(X);\n if (DFS(CurL+1,CurR,L|(1LL<<LOW),R,(X|G[LOW])&(~(L|(1LL<<LOW)))&(~R))) return true;\n if (CurR != K) {\n if (DFS(CurL,CurR+1,L,R|(1LL<<LOW),X&(~L)&(~(R|(1LL<<LOW))))) return true;\n }\n return false;\n}\n\nint main() {\nwhile(1) {\n cin >> M >> N;\n if (N == 0 && M == 0) return 0;\n vector<vector<int>> A(N,vector<int>(M));\n rep(i,0,N) rep(j,0,M) cin >> A[i][j], A[i][j]--;\n P.clear();\n int Cur = 0;\n rep(i,0,N) {\n rep(j,0,M) {\n if (A[i][j] == 0) {\n A[i][j] = Cur;\n P.push_back({i,j});\n Cur++;\n }\n }\n }\n if (Cur % 2 == 1) {\n cout << \"NO\" << endl;\n continue;\n }\n G.assign(Cur,0);\n rep(i,0,Cur) {\n int PX = P[i].first, PY = P[i].second;\n rep(j,0,4) {\n int NX = PX+dx[j], NY = PY+dy[j];\n if (0<=NX&&NX<N&&0<=NY&&NY<M) {\n if (A[NX][NY]>=0) G[i] |= (1LL << (A[NX][NY]));\n }\n }\n }\n K = Cur / 2;\n start = clock();\n cout << (DFS(1,0,1,0,G[0]) ? \"YES\" : \"NO\") << endl;\n}\n}", "accuracy": 1, "time_ms": 5700, "memory_kb": 3424, "score_of_the_acc": -0.7547, "final_rank": 6 }, { "submission_id": "aoj_1158_9481634", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint dx[4] = {1,0,-1,0}, dy[4] = {0,1,0,-1};\nint N, M, K;\nvector<pair<int,int>> P;\nvector<ll> G;\nclock_t start;\n\nbool Check(ll X) {\n vector<pair<int,int>> L, R;\n int LYMIN = M, LYMAX = 0, RYMIN = M, RYMAX = 0;\n rep(i,0,(int)(P.size())) {\n if (X & (1LL<<i)) L.push_back(P[i]), chmin(LYMIN,P[i].second), chmax(LYMAX,P[i].second);\n else R.push_back(P[i]), chmin(RYMIN,P[i].second), chmax(RYMAX,P[i].second);\n }\n sort(L.begin(), L.end());\n sort(R.begin(), R.end());\n int DLX = L[K-1].first-L[0].first, DRX = R[K-1].first-R[0].first, DLY = LYMAX-LYMIN, DRY = RYMAX-RYMIN;\n if ((DLX+DLY != DRX+DRY) || (abs(DLX-DLY) != abs(DRX-DRY))) return false;\n rep(__,0,2) {\n rep(_,0,4) {\n sort(R.begin(), R.end());\n bool check = true;\n int DX = R[0].first - L[0].first, DY = R[0].second - L[0].second;\n rep(i,1,K) {\n if ((R[i].first - L[i].first != DX) || (R[i].second - L[i].second != DY)) {\n check = false;\n break;\n }\n }\n if (check) return true;\n rep(i,0,K) {\n swap(R[i].first, R[i].second);\n R[i].first = -R[i].first;\n }\n }\n rep(i,0,K) R[i].first = -R[i].first;\n }\n return false;\n}\n\nbool DFS(int CurL, int CurR, ll L, ll R, ll X) {\n clock_t end = clock();\n const double time = static_cast<double>(end - start) / CLOCKS_PER_SEC;\n if (time > 0.6) return false;\n if (CurL == K) {\n if (Check(L)) return true;\n return false;\n }\n if (X == 0) return false;\n int LOW = lowbit<ll>(X);\n if (DFS(CurL+1,CurR,L|(1LL<<LOW),R,(X|G[LOW])&(~(L|(1LL<<LOW)))&(~R))) return true;\n if (CurR != K) {\n if (DFS(CurL,CurR+1,L,R|(1LL<<LOW),X&(~L)&(~(R|(1LL<<LOW))))) return true;\n }\n return false;\n}\n\nint main() {\nwhile(1) {\n cin >> M >> N;\n if (N == 0 && M == 0) return 0;\n vector<vector<int>> A(N,vector<int>(M));\n rep(i,0,N) rep(j,0,M) cin >> A[i][j], A[i][j]--;\n P.clear();\n int Cur = 0;\n rep(i,0,N) {\n rep(j,0,M) {\n if (A[i][j] == 0) {\n A[i][j] = Cur;\n P.push_back({i,j});\n Cur++;\n }\n }\n }\n if (Cur % 2 == 1) {\n cout << \"NO\" << endl;\n continue;\n }\n G.assign(Cur,0);\n rep(i,0,Cur) {\n int PX = P[i].first, PY = P[i].second;\n rep(j,0,4) {\n int NX = PX+dx[j], NY = PY+dy[j];\n if (0<=NX&&NX<N&&0<=NY&&NY<M) {\n if (A[NX][NY]>=0) G[i] |= (1LL << (A[NX][NY]));\n }\n }\n }\n K = Cur / 2;\n start = clock();\n cout << (DFS(1,0,1,0,G[0]) ? \"YES\" : \"NO\") << endl;\n}\n}", "accuracy": 1, "time_ms": 7970, "memory_kb": 3504, "score_of_the_acc": -1.0492, "final_rank": 10 }, { "submission_id": "aoj_1158_9481630", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint dx[4] = {1,0,-1,0}, dy[4] = {0,1,0,-1};\nint N, M, K;\nvector<pair<int,int>> P;\nvector<ll> G;\nclock_t start;\n\nbool Check(ll X) {\n vector<pair<int,int>> L, R;\n int LYMIN = M, LYMAX = 0, RYMIN = M, RYMAX = 0;\n rep(i,0,(int)(P.size())) {\n if (X & (1LL<<i)) L.push_back(P[i]), chmin(LYMIN,P[i].second), chmax(LYMAX,P[i].second);\n else R.push_back(P[i]), chmin(RYMIN,P[i].second), chmax(RYMAX,P[i].second);\n }\n sort(L.begin(), L.end());\n sort(R.begin(), R.end());\n int DLX = L[K-1].first-L[0].first, DRX = R[K-1].first-R[0].first, DLY = LYMAX-LYMIN, DRY = RYMAX-RYMIN;\n if ((DLX+DLY != DRX+DRY) || (abs(DLX-DLY) != abs(DRX-DRY))) return false;\n rep(__,0,2) {\n rep(_,0,4) {\n sort(R.begin(), R.end());\n bool check = true;\n int DX = R[0].first - L[0].first, DY = R[0].second - L[0].second;\n rep(i,1,K) {\n if ((R[i].first - L[i].first != DX) || (R[i].second - L[i].second != DY)) {\n check = false;\n break;\n }\n }\n if (check) return true;\n rep(i,0,K) {\n swap(R[i].first, R[i].second);\n R[i].first = -R[i].first;\n }\n }\n rep(i,0,K) R[i].first = -R[i].first;\n }\n return false;\n}\n\nbool DFS(int CurL, int CurR, ll L, ll R, ll X) {\n clock_t end = clock();\n const double time = static_cast<double>(end - start) / CLOCKS_PER_SEC;\n if (time > 0.375) return false;\n if (CurL == K) {\n if (Check(L)) return true;\n return false;\n }\n if (X == 0) return false;\n int LOW = lowbit<ll>(X);\n if (DFS(CurL+1,CurR,L|(1LL<<LOW),R,(X|G[LOW])&(~(L|(1LL<<LOW)))&(~R))) return true;\n if (CurR != K) {\n if (DFS(CurL,CurR+1,L,R|(1LL<<LOW),X&(~L)&(~(R|(1LL<<LOW))))) return true;\n }\n return false;\n}\n\nint main() {\nwhile(1) {\n cin >> M >> N;\n if (N == 0 && M == 0) return 0;\n vector<vector<int>> A(N,vector<int>(M));\n rep(i,0,N) rep(j,0,M) cin >> A[i][j], A[i][j]--;\n P.clear();\n int Cur = 0;\n rep(i,0,N) {\n rep(j,0,M) {\n if (A[i][j] == 0) {\n A[i][j] = Cur;\n P.push_back({i,j});\n Cur++;\n }\n }\n }\n if (Cur % 2 == 1) {\n cout << \"NO\" << endl;\n continue;\n }\n G.assign(Cur,0);\n rep(i,0,Cur) {\n int PX = P[i].first, PY = P[i].second;\n rep(j,0,4) {\n int NX = PX+dx[j], NY = PY+dy[j];\n if (0<=NX&&NX<N&&0<=NY&&NY<M) {\n if (A[NX][NY]>=0) G[i] |= (1LL << (A[NX][NY]));\n }\n }\n }\n K = Cur / 2;\n start = clock();\n cout << (DFS(1,0,1,0,G[0]) ? \"YES\" : \"NO\") << endl;\n}\n}", "accuracy": 1, "time_ms": 5710, "memory_kb": 3200, "score_of_the_acc": -0.73, "final_rank": 5 }, { "submission_id": "aoj_1158_9481627", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint dx[4] = {1,0,-1,0}, dy[4] = {0,1,0,-1};\nint N, M, K;\nvector<pair<int,int>> P;\nvector<ll> G;\nclock_t start;\n\nbool Check(ll X) {\n vector<pair<int,int>> L, R;\n int LYMIN = M, LYMAX = 0, RYMIN = M, RYMAX = 0;\n rep(i,0,(int)(P.size())) {\n if (X & (1LL<<i)) L.push_back(P[i]), chmin(LYMIN,P[i].second), chmax(LYMAX,P[i].second);\n else R.push_back(P[i]), chmin(RYMIN,P[i].second), chmax(RYMAX,P[i].second);\n }\n sort(L.begin(), L.end());\n sort(R.begin(), R.end());\n int DLX = L[K-1].first-L[0].first, DRX = R[K-1].first-R[0].first, DLY = LYMAX-LYMIN, DRY = RYMAX-RYMIN;\n if ((DLX+DLY != DRX+DRY) || (abs(DLX-DLY) != abs(DRX-DRY))) return false;\n rep(__,0,2) {\n rep(_,0,4) {\n sort(R.begin(), R.end());\n bool check = true;\n int DX = R[0].first - L[0].first, DY = R[0].second - L[0].second;\n rep(i,1,K) {\n if ((R[i].first - L[i].first != DX) || (R[i].second - L[i].second != DY)) {\n check = false;\n break;\n }\n }\n if (check) return true;\n rep(i,0,K) {\n swap(R[i].first, R[i].second);\n R[i].first = -R[i].first;\n }\n }\n rep(i,0,K) R[i].first = -R[i].first;\n }\n return false;\n}\n\nbool DFS(int CurL, int CurR, ll L, ll R, ll X) {\n clock_t end = clock();\n const double time = static_cast<double>(end - start) / CLOCKS_PER_SEC;\n if (time > 0.4) return false;\n if (CurL == K) {\n if (Check(L)) return true;\n return false;\n }\n if (X == 0) return false;\n int LOW = lowbit<ll>(X);\n if (DFS(CurL+1,CurR,L|(1LL<<LOW),R,(X|G[LOW])&(~(L|(1LL<<LOW)))&(~R))) return true;\n if (CurR != K) {\n if (DFS(CurL,CurR+1,L,R|(1LL<<LOW),X&(~L)&(~(R|(1LL<<LOW))))) return true;\n }\n return false;\n}\n\nint main() {\nwhile(1) {\n cin >> M >> N;\n if (N == 0 && M == 0) return 0;\n vector<vector<int>> A(N,vector<int>(M));\n rep(i,0,N) rep(j,0,M) cin >> A[i][j], A[i][j]--;\n P.clear();\n int Cur = 0;\n rep(i,0,N) {\n rep(j,0,M) {\n if (A[i][j] == 0) {\n A[i][j] = Cur;\n P.push_back({i,j});\n Cur++;\n }\n }\n }\n if (Cur % 2 == 1) {\n cout << \"NO\" << endl;\n continue;\n }\n G.assign(Cur,0);\n rep(i,0,Cur) {\n int PX = P[i].first, PY = P[i].second;\n rep(j,0,4) {\n int NX = PX+dx[j], NY = PY+dy[j];\n if (0<=NX&&NX<N&&0<=NY&&NY<M) {\n if (A[NX][NY]>=0) G[i] |= (1LL << (A[NX][NY]));\n }\n }\n }\n K = Cur / 2;\n start = clock();\n cout << (DFS(1,0,1,0,G[0]) ? \"YES\" : \"NO\") << endl;\n}\n}", "accuracy": 1, "time_ms": 5980, "memory_kb": 3432, "score_of_the_acc": -0.7908, "final_rank": 7 }, { "submission_id": "aoj_1158_9481623", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint dx[4] = {1,0,-1,0}, dy[4] = {0,1,0,-1};\nint N, M, K;\nvector<pair<int,int>> P;\nvector<ll> G;\nclock_t start;\n\nbool Check(ll X) {\n vector<pair<int,int>> L, R;\n int LYMIN = M, LYMAX = 0, RYMIN = M, RYMAX = 0;\n rep(i,0,(int)(P.size())) {\n if (X & (1LL<<i)) L.push_back(P[i]), chmin(LYMIN,P[i].second), chmax(LYMAX,P[i].second);\n else R.push_back(P[i]), chmin(RYMIN,P[i].second), chmax(RYMAX,P[i].second);\n }\n sort(L.begin(), L.end());\n sort(R.begin(), R.end());\n int DLX = L[K-1].first-L[0].first, DRX = R[K-1].first-R[0].first, DLY = LYMAX-LYMIN, DRY = RYMAX-RYMIN;\n if ((DLX+DLY != DRX+DRY) || (abs(DLX-DLY) != abs(DRX-DRY))) return false;\n rep(__,0,2) {\n rep(_,0,4) {\n sort(R.begin(), R.end());\n bool check = true;\n int DX = R[0].first - L[0].first, DY = R[0].second - L[0].second;\n rep(i,1,K) {\n if ((R[i].first - L[i].first != DX) || (R[i].second - L[i].second != DY)) {\n check = false;\n break;\n }\n }\n if (check) return true;\n rep(i,0,K) {\n swap(R[i].first, R[i].second);\n R[i].first = -R[i].first;\n }\n }\n rep(i,0,K) R[i].first = -R[i].first;\n }\n return false;\n}\n\nbool DFS(int CurL, int CurR, ll L, ll R, ll X) {\n clock_t end = clock();\n const double time = static_cast<double>(end - start) / CLOCKS_PER_SEC;\n if (time > 0.5) return false;\n if (CurL == K) {\n if (Check(L)) return true;\n return false;\n }\n if (X == 0) return false;\n int LOW = lowbit<ll>(X);\n if (DFS(CurL+1,CurR,L|(1LL<<LOW),R,(X|G[LOW])&(~(L|(1LL<<LOW)))&(~R))) return true;\n if (CurR != K) {\n if (DFS(CurL,CurR+1,L,R|(1LL<<LOW),X&(~L)&(~(R|(1LL<<LOW))))) return true;\n }\n return false;\n}\n\nint main() {\nwhile(1) {\n cin >> M >> N;\n if (N == 0 && M == 0) return 0;\n vector<vector<int>> A(N,vector<int>(M));\n rep(i,0,N) rep(j,0,M) cin >> A[i][j], A[i][j]--;\n P.clear();\n int Cur = 0;\n rep(i,0,N) {\n rep(j,0,M) {\n if (A[i][j] == 0) {\n A[i][j] = Cur;\n P.push_back({i,j});\n Cur++;\n }\n }\n }\n if (Cur % 2 == 1) {\n cout << \"NO\" << endl;\n continue;\n }\n G.assign(Cur,0);\n rep(i,0,Cur) {\n int PX = P[i].first, PY = P[i].second;\n rep(j,0,4) {\n int NX = PX+dx[j], NY = PY+dy[j];\n if (0<=NX&&NX<N&&0<=NY&&NY<M) {\n if (A[NX][NY]>=0) G[i] |= (1LL << (A[NX][NY]));\n }\n }\n }\n K = Cur / 2;\n start = clock();\n cout << (DFS(1,0,1,0,G[0]) ? \"YES\" : \"NO\") << endl;\n}\n}", "accuracy": 1, "time_ms": 6970, "memory_kb": 3240, "score_of_the_acc": -0.8929, "final_rank": 8 }, { "submission_id": "aoj_1158_9366029", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\ntemplate < class T > vector< T >& operator++(vector< T >& a) { for(T& x : a) x++; return a; }\ntemplate < class T > vector< T >& operator--(vector< T >& a) { for(T& x : a) x--; return a; }\ntemplate < class T > vector< T > operator++(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x++; return res; }\ntemplate < class T > vector< T > operator--(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x--; return res; }\n\n} // namespace macro\n\nusing namespace macro;\n#line 3 \"A.cpp\"\n\nbool solve(int w, int h) {\n vector<vector<int>> a = in(h, w);\n const int n = [&] {\n int cnt = 0;\n for(int i : rep(h)) for(int j : rep(w)) cnt += a[i][j];\n return cnt;\n }();\n if(n % 2 == 1) return false;\n\n // fix rot&rev --> dfs\n\n vector<int> sx = {0, 1, 0, -1};\n vector<int> sy = {1, 0, -1, 0};\n auto [tx, ty] = make_pair(sx, sy);\n\n for(int rev_ : rep(2)) {\n for(int rot_ : rep(4)) {\n for(int si : rep(h)) for(int sj : rep(w)) if(a[si][sj]) {\n for(int ti : rep(h)) for(int tj : rep(w)) if(a[ti][tj] and make_pair(ti, tj) != make_pair(si, sj)) {\n\n vector s(h, vector(w, 0));\n vector t(h, vector(w, 0));\n int sn = 0, tn = 0;\n auto dfs = [&](auto self, int si, int sj, int ti, int tj) -> bool {\n sn += (++s[si][sj]);\n tn += (++t[ti][tj]);\n if(sn == n / 2 and tn == n / 2) return true;\n for(int d : rep(4)) {\n int nsi = si + sx[d], nsj = sj + sy[d];\n int nti = ti + tx[d], ntj = tj + ty[d];\n if(not(0 <= nsi and nsi < h and 0 <= nsj and nsj < w)) continue;\n if(not(0 <= nti and nti < h and 0 <= ntj and ntj < w)) continue;\n if(make_pair(nsi, nsj) == make_pair(nti, ntj)) continue;\n if(not(a[nsi][nsj] and a[nti][ntj])) continue;\n if(not(s[nti][ntj] == 0 and t[nsi][nsj] == 0)) continue;\n if(not(s[nsi][nsj] == 0 and t[nti][ntj] == 0)) continue;\n if(self(self, nsi, nsj, nti, ntj)) return true;\n }\n return false;\n };\n if(dfs(dfs, si, sj, ti, tj)) return true;\n }\n }\n rotate(tx.begin(), tx.begin() + 1, tx.end());\n rotate(ty.begin(), ty.begin() + 1, ty.end());\n }\n swap(tx[1], tx[3]);\n swap(ty[1], ty[3]);\n }\n return false;\n}\n\nint main() {\n while(true) {\n int w = in(), h = in();\n if(make_pair(w, h) == make_pair(0, 0)) return 0;\n print(solve(w, h) ? \"YES\" : \"NO\");\n }\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 3364, "score_of_the_acc": -0.053, "final_rank": 3 }, { "submission_id": "aoj_1158_9291084", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\ntemplate<class T>\nbool chmin(T &a, const T &b) {if (a > b) {a = b; return 1;} return 0;}\ntemplate<class T>\nbool chmax(T &a, const T &b) {if (a < b) {a = b; return 1;} return 0;}\n\nstruct UnionFind\n{\n int n;\n vector<int> par;\n int connected_num;\n \n UnionFind() = default;\n UnionFind(int _n) : n(_n), connected_num(_n), par(_n)\n {\n for (int i = 0; i < n; ++i) par[i] = i;\n }\n \n int root(int x)\n {\n if (par[x] == x) return x;\n else return par[x] = root(par[x]);\n }\n \n bool same(int x, int y)\n {\n return root(x) == root(y);\n }\n \n void merge(int x, int y)\n {\n if (same(x, y)) return;\n par[root(y)] = root(x);\n connected_num--;\n return;\n }\n \n};\n\nbool is_end = false;\n\nint dx[4] = {1, 0, -1, 0};\nint dy[4] = {0, 1, 0, -1};\nint W, H;\nint N;\n\nusing bs = bitset<40>;\nbs full;\n\nbool debug = false;\n\ninline bool isvalid(int x, int y)\n{\n return 0 <= x && x < H && 0 <= y && y < W;\n}\n\nbool edakari(const bs bit, int nex, const vector<vector<int>> &graph)\n{\n UnionFind tree(N);\n int s = -1;\n for (int i = 0; i < N; ++i)\n {\n if (bit[i] && s == -1 && i < nex) s = i;\n for (auto j : graph[i])\n {\n if (bit[i] && bit[j]) tree.merge(i, j);\n }\n }\n if (s == -1) return true;\n \n int r = tree.root(s);\n bool ret = true;\n for (int i = 0; i < nex; ++i)\n {\n if (bit[i]) ret &= (tree.root(i) == r);\n }\n \n return ret;\n}\n\nbool dfs(bs bit1, bs bit2, int cnt, int nex, \n const vector<int> &aite1, const vector<int> &aite2, const vector<vector<int>> &graph)\n{\n assert((bit1 & bit2) == 0);\n \n if (cnt * 2 == N)\n {\n bool flg = true;\n flg &= edakari(bit1, N, graph);\n flg &= edakari(bit2, N, graph);\n return flg;\n }\n \n {\n bool flg = true;\n flg &= edakari(bit1 ^ full, nex, graph);\n flg &= edakari(bit2 ^ full, nex, graph);\n if (!flg) return false;\n }\n \n bool ret = false;\n {\n int i = nex;\n bs unite = bit1 | bit2;\n \n if (unite[i])\n {\n return dfs(bit1, bit2, cnt, i + 1, aite1, aite2, graph);\n }\n \n int j2 = aite1[i];\n if (j2 != -1 && !unite[j2] && i != j2)\n {\n bit1[i] = 1, bit2[j2] = 1;\n ret |= dfs(bit1, bit2, cnt + 1, i + 1, aite1, aite2, graph);\n bit1[i] = 0, bit2[j2] = 0;\n }\n if (ret) return true;\n \n int j1 = aite2[i];\n if (j1 != -1 && !unite[j1] && i != j1)\n {\n bit1[j1] = 1, bit2[i] = 1;\n ret |= dfs(bit1, bit2, cnt + 1, i + 1, aite1, aite2, graph);\n bit1[j1] = 0, bit2[i] = 0;\n }\n if (ret) return true;\n \n }\n \n return ret;\n}\n\nvoid solve()\n{\n cin >> W >> H;\n if (H == 0 && W == 0)\n {\n is_end = true;\n return;\n }\n \n vector grid(H+2, vector<bool>(W+2, false));\n N = 0;\n int rx = -1, ry = -1;\n for (int i = 1; i <= H; ++i)\n {\n for (int j = 1; j <= W; ++j)\n {\n int c; cin >> c;\n \n grid[i][j] = c;\n N += c;\n if (c == 1 && rx == -1) rx = i, ry = j;\n }\n }\n H += 2, W += 2;\n \n if (N % 2 == 1)\n {\n cout << \"NO\" << endl;\n return;\n }\n \n full = bs((1LL<<N) - 1);\n \n vector pos_to_num(H, vector<int>(W, -1));\n vector<array<int, 2>> num_to_pos;\n {\n int cnt = 0;\n for (int i = 0; i < H; ++i)\n {\n for (int j = 0; j < W; ++j)\n {\n if (grid[i][j])\n {\n num_to_pos.push_back({i, j});\n pos_to_num[i][j] = cnt;\n cnt++;\n }\n }\n }\n assert(cnt == N);\n }\n \n vector graph(N, vector<int>());\n for (int i = 0; i < N; ++i)\n {\n for (int j = 0; j < N; ++j)\n {\n auto [ix, iy] = num_to_pos[i];\n auto [jx, jy] = num_to_pos[j];\n \n int d = abs(ix - jx) + abs(iy - jy);\n if (d == 1) graph[i].emplace_back(j);\n }\n }\n \n bool res = false;\n array<int, 4> dx2, dy2;\n int sx = rx, sy = ry;\n for (int id = 0; id < N; ++id)\n {\n auto [tx, ty] = num_to_pos[id];\n if (tx == sx && ty == sy) continue;\n dx2 = {1, 0, -1, 0};\n dy2 = {0, 1, 0, -1};\n \n for (int rev = 0; rev < 2; ++rev)\n {\n for (int rotate = 0; rotate < 4; ++rotate)\n {\n vector<int> aite1(N, -1), aite2(N, -1);\n for (int i = 0; i < N; ++i)\n {\n auto [x, y] = num_to_pos[i];\n int diffx = x - sx, diffy = y - sy;\n int nx = tx + diffx * dx2[0] + diffy * dy2[0];\n int ny = ty + diffx * dx2[1] + diffy * dy2[1];\n \n int j = (isvalid(nx, ny) ? pos_to_num[nx][ny] : -1);\n aite1[i] = j;\n if (j >= 0) aite2[j] = i;\n }\n \n bool flg = true;\n for (int i = 0; i < N; ++i)\n {\n if (aite1[i] == -1 && aite2[i] == -1) flg = false;\n if (aite1[i] == i || aite2[i] == i) flg = false;\n }\n \n if (flg) res |= dfs(bs(0), bs(0), 0, 0, aite1, aite2, graph);\n \n for (int i = 0; i < 3; ++i)\n {\n swap(dx2[i], dx2[i+1]);\n swap(dy2[i], dy2[i+1]);\n }\n \n }\n \n for (int i = 0; i < 4; ++i)\n {\n swap(dx2[i], dy2[i]);\n }\n \n }\n \n }\n \n cout << (res ? \"YES\" : \"NO\") << endl;\n \n return;\n}\n\n\nint main()\n{\n while (!is_end)\n {\n solve();\n } \n \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3460, "score_of_the_acc": -0.0441, "final_rank": 2 }, { "submission_id": "aoj_1158_9291082", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\ntemplate<class T>\nbool chmin(T &a, const T &b) {if (a > b) {a = b; return 1;} return 0;}\ntemplate<class T>\nbool chmax(T &a, const T &b) {if (a < b) {a = b; return 1;} return 0;}\n\nstruct UnionFind\n{\n int n;\n vector<int> par;\n int connected_num;\n \n UnionFind() = default;\n UnionFind(int _n) : n(_n), connected_num(_n), par(_n)\n {\n for (int i = 0; i < n; ++i) par[i] = i;\n }\n \n int root(int x)\n {\n if (par[x] == x) return x;\n else return par[x] = root(par[x]);\n }\n \n bool same(int x, int y)\n {\n return root(x) == root(y);\n }\n \n void merge(int x, int y)\n {\n if (same(x, y)) return;\n par[root(y)] = root(x);\n connected_num--;\n return;\n }\n \n \n};\n\nbool is_end = false;\n\nint dx[4] = {1, 0, -1, 0};\nint dy[4] = {0, 1, 0, -1};\nint W, H;\nint N;\n\nusing bs = bitset<40>;\nbs full;\n\nbool debug = false;\n\ninline bool isvalid(int x, int y)\n{\n return 0 <= x && x < H && 0 <= y && y < W;\n}\n\nbool edakari(const bs bit, int nex, const vector<vector<int>> &graph)\n{\n UnionFind tree(N);\n int s = -1;\n for (int i = 0; i < N; ++i)\n {\n if (bit[i] && s == -1 && i < nex) s = i;\n for (auto j : graph[i])\n {\n if (bit[i] && bit[j]) tree.merge(i, j);\n }\n }\n \n if (s == -1) return true;\n int r = tree.root(s);\n bool ret = true;\n for (int i = 0; i < nex; ++i)\n {\n if (bit[i]) ret &= (tree.root(i) == r);\n }\n \n return ret;\n}\n\nbool dfs(bs bit1, bs bit2, int cnt, int nex, \n const vector<int> &aite1, const vector<int> &aite2, const vector<vector<int>> &graph)\n{\n if (debug) cout << bit1 << \" \" << bit2 << endl;\n assert((bit1 & bit2) == 0);\n \n if (cnt * 2 == N)\n {\n bool flg = true;\n flg &= edakari(bit1 , N, graph);\n flg &= edakari(bit2 , N, graph);\n return flg;\n }\n \n // if (cnt % 1 == 0)\n // {\n // bool flg = true;\n // flg &= edakari(bit1 ^ full, nex, graph);\n // flg &= edakari(bit2 ^ full, nex, graph);\n \n // if (!flg) return false;\n // }\n \n bool ret = false;\n \n {\n int i = nex;\n bs unite = bit1 | bit2;\n \n if (unite[i])\n {\n return dfs(bit1, bit2, cnt, i + 1, aite1, aite2, graph);\n }\n \n int j2 = aite1[i];\n if (j2 != -1 && !unite[j2] && i != j2)\n {\n bit1[i] = 1, bit2[j2] = 1;\n ret |= dfs(bit1, bit2, cnt + 1, i + 1, aite1, aite2, graph);\n bit1[i] = 0, bit2[j2] = 0;\n }\n if (ret) return true;\n \n int j1 = aite2[i];\n if (j1 != -1 && !unite[j1] && i != j1)\n {\n bit1[j1] = 1, bit2[i] = 1;\n ret |= dfs(bit1, bit2, cnt + 1, i + 1, aite1, aite2, graph);\n bit1[j1] = 0, bit2[i] = 0;\n }\n if (ret) return true;\n \n }\n \n return ret;\n}\n\nvoid solve()\n{\n cin >> W >> H;\n if (H == 0 && W == 0)\n {\n is_end = true;\n return;\n }\n \n vector grid(H+2, vector<bool>(W+2, false));\n N = 0;\n int rx = -1, ry = -1;\n for (int i = 1; i <= H; ++i)\n {\n for (int j = 1; j <= W; ++j)\n {\n int c; cin >> c;\n \n grid[i][j] = c;\n N += c;\n if (c == 1 && rx == -1) rx = i, ry = j;\n }\n }\n H += 2, W += 2;\n \n if (N % 2 == 1)\n {\n cout << \"NO\" << endl;\n return;\n }\n \n // cout << rx << \" \" << ry << endl;\n \n full = bs((1LL<<N) - 1);\n \n vector pos_to_num(H, vector<int>(W, -1));\n vector<array<int, 2>> num_to_pos;\n {\n int cnt = 0;\n for (int i = 0; i < H; ++i)\n {\n for (int j = 0; j < W; ++j)\n {\n if (grid[i][j])\n {\n num_to_pos.push_back({i, j});\n pos_to_num[i][j] = cnt;\n cnt++;\n }\n }\n }\n assert(cnt == N);\n }\n // {\n // int cnt = 0;\n // queue<array<int, 2>> que;\n \n // que.push({rx, ry});\n // num_to_pos.push_back({rx, ry});\n // pos_to_num[rx][ry] = cnt;\n // cnt++;\n \n // while (!que.empty())\n // {\n // auto [x, y] = que.front();\n // que.pop();\n \n // for (int dir = 0; dir < 4; ++dir)\n // {\n // int nx = x + dx[dir], ny = y + dy[dir];\n // if (grid[nx][ny] && pos_to_num[nx][ny] == -1)\n // {\n // que.push({nx, ny});\n // num_to_pos.push_back({nx, ny});\n // pos_to_num[nx][ny] = cnt;\n // cnt++;\n // }\n // }\n \n // }\n // assert(cnt == N);\n // }\n \n // for (int i = 0; i < N; ++i)\n // {\n // auto [x, y] = num_to_pos[i];\n // cout << i << \" \" << x << \" \" << y << endl;\n // }\n \n vector graph(N, vector<int>());\n for (int i = 0; i < N; ++i)\n {\n for (int j = 0; j < N; ++j)\n {\n auto [ix, iy] = num_to_pos[i];\n auto [jx, jy] = num_to_pos[j];\n \n int d = abs(ix - jx) + abs(iy - jy);\n if (d == 1) graph[i].emplace_back(j);\n }\n }\n \n bool res = false;\n array<int, 4> dx2, dy2;\n int sx = rx, sy = ry;\n for (int id = 0; id < N; ++id)\n {\n auto [tx, ty] = num_to_pos[id];\n if (tx == sx && ty == sy) continue;\n dx2 = {1, 0, -1, 0};\n dy2 = {0, 1, 0, -1};\n \n for (int rev = 0; rev < 2; ++rev)\n {\n for (int rotate = 0; rotate < 4; ++rotate)\n {\n vector<int> aite1(N, -1), aite2(N, -1);\n for (int i = 0; i < N; ++i)\n {\n auto [x, y] = num_to_pos[i];\n int diffx = x - sx, diffy = y - sy;\n int nx = tx + diffx * dx2[0] + diffy * dy2[0];\n int ny = ty + diffx * dx2[1] + diffy * dy2[1];\n \n int j = (isvalid(nx, ny) ? pos_to_num[nx][ny] : -1);\n aite1[i] = j;\n if (j >= 0) aite2[j] = i;\n }\n \n bool flg = true;\n for (int i = 0; i < N; ++i)\n {\n if (aite1[i] == -1 && aite2[i] == -1) flg = false;\n if (aite1[i] == i || aite2[i] == i) flg = false;\n }\n \n res |= dfs(bs(0), bs(0), 0, 0, aite1, aite2, graph);\n \n for (int i = 0; i < 3; ++i)\n {\n swap(dx2[i], dx2[i+1]);\n swap(dy2[i], dy2[i+1]);\n }\n \n }\n \n for (int i = 0; i < 4; ++i)\n {\n swap(dx2[i], dy2[i]);\n }\n \n }\n \n }\n \n \n cout << (res ? \"YES\" : \"NO\") << endl;\n \n \n return;\n}\n\n\nint main()\n{\n while (!is_end)\n {\n solve();\n } \n \n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3080, "score_of_the_acc": -0.0025, "final_rank": 1 }, { "submission_id": "aoj_1158_8819360", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <iostream>\n#include <map>\n#include <set>\n#include <vector>\nusing namespace std;\ntypedef long long ll;\nconst int dx[] = {0, 1, 0, -1};\nconst int dy[] = {-1, 0, 1, 0};\nint w, h, tatu_x[20], tatu_y[20], kazu_x[20], kazu_y[20];\nint field[12][12], cx[36], cy[36], csize;\nmap<pair<int, int>, int> idx;\nset<ll> visited[20][4][2];\nbool backtrack(int cnt, ll kS, int init_dir, int f) {\n if (visited[cnt][init_dir][f].count(kS))\n return false;\n if (csize / 2 == cnt)\n return true;\n for (int i = 0; i < cnt; i++) {\n for (int k = 0; k < 4; k++) {\n int tx = tatu_x[i] + dx[k];\n int ty = tatu_y[i] + dy[k];\n if (tx < 0 || tx >= w || ty < 0 || ty >= h || field[ty][tx] == 0)\n continue;\n int ttx = kazu_x[i] + dx[(k + init_dir + (f ? 2 : 0)) % 4];\n int tty = kazu_y[i] + dy[(k + init_dir) % 4];\n if ((tx == ttx && ty == tty) || ttx < 0 || ttx >= w || tty < 0 || tty >= h || field[tty][ttx] == 0)\n continue;\n field[ty][tx] = 0;\n tatu_x[cnt] = tx, tatu_y[cnt] = ty;\n field[tty][ttx] = 0;\n kazu_x[cnt] = ttx, kazu_y[cnt] = tty;\n if (backtrack(cnt + 1, kS | (1LL << idx[make_pair(ttx, tty)]), init_dir,\n f))\n return true;\n field[tty][ttx] = 1;\n field[ty][tx] = 1;\n }\n }\n visited[cnt][init_dir][f].insert(kS);\n return false;\n}\nbool solve() {\n if (csize % 2)\n return false;\n tatu_x[0] = cx[0], tatu_y[0] = cy[0];\n field[cy[0]][cx[0]] = 0;\n for (int j = 1; j < csize; j++) {\n kazu_x[0] = cx[j], kazu_y[0] = cy[j];\n field[cy[j]][cx[j]] = 0;\n for (int k = 0; k < 4; k++) {\n if (backtrack(1, 1LL << j, k, 0) || backtrack(1, 1LL << j, k, 1))\n return true;\n }\n field[cy[j]][cx[j]] = 1;\n }\n field[cy[0]][cx[0]] = 1;\n return false;\n}\nint main() {\n while (cin >> w >> h, w | h) {\n idx.clear();\n for (int i = 0; i < 20; i++)\n for (int j = 0; j < 4; j++)\n for (int k = 0; k < 2; k++)\n visited[i][j][k].clear();\n csize = 0;\n for (int i = 0; i < h; i++)\n for (int j = 0; j < w; j++) {\n cin >> field[i][j];\n if (field[i][j] == 1) {\n cx[csize] = j, cy[csize] = i;\n idx[make_pair(j, i)] = csize;\n csize++;\n }\n }\n puts(solve() ? \"YES\" : \"NO\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1050, "memory_kb": 11692, "score_of_the_acc": -1.1293, "final_rank": 18 }, { "submission_id": "aoj_1158_8819354", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <iostream>\n#include <map>\n#include <set>\n#include <vector>\nusing namespace std;\n#define REP(i, a, n) for (i = a; i < n; i++)\n#define rep(i, n) REP(i, 0, n)\n#define all(x) x.begin(), x.end()\n#define foreach(it, x) \\\n for (typeof(x.begin()) it = x.begin(); it != x.end(); it++)\ntypedef long long ll;\nconst int dx[] = {0, 1, 0, -1};\nconst int dy[] = {-1, 0, 1, 0};\nint w, h, tatu_x[20], tatu_y[20], kazu_x[20], kazu_y[20];\nint field[12][12], cx[36], cy[36], csize;\nmap<pair<int, int>, int> idx;\nset<ll> visited[20][4][2];\ninline bool inside(int x, int y) { return !(x < 0 || x >= w || y >= h || y < 0); }\nbool backtrack(int cnt, ll kS, int init_dir, int f) {\n int i, j, k;\n if (visited[cnt][init_dir][f].count(kS))\n return false;\n if (csize / 2 == cnt)\n return true;\n rep(i, cnt) {\n rep(k, 4) {\n int tx = tatu_x[i] + dx[k];\n int ty = tatu_y[i] + dy[k];\n if (!inside(tx, ty) || field[ty][tx] == 0)\n continue;\n int ttx = kazu_x[i] + dx[(k + init_dir + (f ? 2 : 0)) % 4];\n int tty = kazu_y[i] + dy[(k + init_dir) % 4];\n if ((tx == ttx && ty == tty) || !inside(ttx, tty) || field[tty][ttx] == 0)\n continue;\n field[ty][tx] = 0;\n tatu_x[cnt] = tx, tatu_y[cnt] = ty;\n field[tty][ttx] = 0;\n kazu_x[cnt] = ttx, kazu_y[cnt] = tty;\n if (backtrack(cnt + 1, kS | (1LL << idx[{ttx, tty}]), init_dir,\n f))\n return true;\n field[tty][ttx] = 1;\n field[ty][tx] = 1;\n }\n }\n visited[cnt][init_dir][f].insert(kS);\n return false;\n}\nbool solve() {\n int i, j, k;\n if (csize % 2)\n return false;\n tatu_x[0] = cx[0], tatu_y[0] = cy[0];\n field[cy[0]][cx[0]] = 0;\n REP(j, 1, csize) {\n kazu_x[0] = cx[j], kazu_y[0] = cy[j];\n field[cy[j]][cx[j]] = 0;\n rep(k, 4) {\n if (backtrack(1, 1LL << j, k, 0))\n return true;\n if (backtrack(1, 1LL << j, k, 1))\n return true;\n }\n field[cy[j]][cx[j]] = 1;\n }\n field[cy[0]][cx[0]] = 1;\n return false;\n}\nint main() {\n int i, j, k, u;\n while (cin >> w >> h, w | h) {\n idx.clear();\n rep(i, 20) rep(j, 4) rep(k, 2) visited[i][j][k].clear();\n csize = 0;\n rep(i, h) rep(j, w) {\n cin >> field[i][j];\n if (field[i][j]) {\n cx[csize] = j, cy[csize] = i;\n idx[{j, i}] = csize;\n csize++;\n }\n }\n puts(solve() ? \"YES\" : \"NO\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1050, "memory_kb": 11668, "score_of_the_acc": -1.1265, "final_rank": 15 }, { "submission_id": "aoj_1158_8215466", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <iostream>\n#include <map>\n#include <set>\n#include <tr1/unordered_set>\n#include <vector>\nusing namespace std;\nusing namespace tr1;\n#define REP(i, a, n) for (i = a; i < n; i++)\n#define rep(i, n) REP(i, 0, n)\n#define all(x) x.begin(), x.end()\n#define rall(x) x.rbegin(), x.rend()\n#define foreach(it, x) \\\n for (typeof(x.begin()) it = x.begin(); it != x.end(); it++)\ntypedef long long ll;\nconst int dx[] = {0, 1, 0, -1};\nconst int dy[] = {-1, 0, 1, 0};\nint w, h, tatu_x[20], tatu_y[20], kazu_x[20], kazu_y[20];\nint field[12][12], cx[36], cy[36], csize;\nmap<pair<int, int>, int> idx;\nunordered_set<ll> visited[20][4][2];\nbool inside(int x, int y) { return !(x < 0 || x >= w || y >= h || y < 0); }\nbool backtrack(int cnt, ll kS, int init_dir, int f) {\n int i, j, k;\n if (visited[cnt][init_dir][f].count(kS))\n return false;\n if (csize / 2 == cnt)\n return true;\n rep(i, cnt) {\n rep(k, 4) {\n int tx = tatu_x[i] + dx[k];\n int ty = tatu_y[i] + dy[k];\n if (!inside(tx, ty) || field[ty][tx] == 0)\n continue;\n int ttx = kazu_x[i] + dx[(k + init_dir + (f ? 2 : 0)) % 4];\n int tty = kazu_y[i] + dy[(k + init_dir) % 4];\n if ((tx == ttx && ty == tty) || !inside(ttx, tty) || field[tty][ttx] == 0)\n continue;\n field[ty][tx] = 0;\n tatu_x[cnt] = tx, tatu_y[cnt] = ty;\n field[tty][ttx] = 0;\n kazu_x[cnt] = ttx, kazu_y[cnt] = tty;\n if (backtrack(cnt + 1, kS | (1LL << idx[make_pair(ttx, tty)]), init_dir,\n f))\n return true;\n field[tty][ttx] = 1;\n field[ty][tx] = 1;\n }\n }\n visited[cnt][init_dir][f].insert(kS);\n return false;\n}\nbool solve() {\n int i, j, k;\n if (csize % 2)\n return false;\n tatu_x[0] = cx[0], tatu_y[0] = cy[0];\n field[cy[0]][cx[0]] = 0;\n REP(j, 1, csize) {\n kazu_x[0] = cx[j], kazu_y[0] = cy[j];\n field[cy[j]][cx[j]] = 0;\n rep(k, 4) {\n if (backtrack(1, 1LL << j, k, 0))\n return true;\n if (backtrack(1, 1LL << j, k, 1))\n return true;\n }\n field[cy[j]][cx[j]] = 1;\n }\n field[cy[0]][cx[0]] = 1;\n return false;\n}\nint main() {\n int i, j, k, u;\n while (cin >> w >> h, w | h) {\n idx.clear();\n rep(i, 20) rep(j, 4) rep(k, 2) visited[i][j][k].clear();\n csize = 0;\n rep(i, h) rep(j, w) {\n cin >> field[i][j];\n if (field[i][j] == 1) {\n cx[csize] = j, cy[csize] = i;\n idx[make_pair(j, i)] = csize;\n csize++;\n }\n }\n puts(solve() ? \"YES\" : \"NO\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 590, "memory_kb": 10936, "score_of_the_acc": -0.9838, "final_rank": 9 }, { "submission_id": "aoj_1158_8215464", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <iostream>\n#include <map>\n#include <set>\n#include <vector>\nusing namespace std;\n#define REP(i, a, n) for (i = a; i < n; i++)\n#define rep(i, n) REP(i, 0, n)\n#define all(x) x.begin(), x.end()\n#define rall(x) x.rbegin(), x.rend()\n#define foreach(it, x) \\\n for (typeof(x.begin()) it = x.begin(); it != x.end(); it++)\ntypedef long long ll;\nconst int dx[] = {0, 1, 0, -1};\nconst int dy[] = {-1, 0, 1, 0};\nint w, h, tatu_x[20], tatu_y[20], kazu_x[20], kazu_y[20];\nint field[12][12], cx[36], cy[36], csize;\nmap<pair<int, int>, int> idx;\nset<ll> visited[20][4][2];\nbool inside(int x, int y) { return !(x < 0 || x >= w || y >= h || y < 0); }\nbool backtrack(int cnt, ll kS, int init_dir, int f) {\n int i, j, k;\n if (visited[cnt][init_dir][f].count(kS))\n return false;\n if (csize / 2 == cnt)\n return true;\n rep(i, cnt) {\n rep(k, 4) {\n int tx = tatu_x[i] + dx[k];\n int ty = tatu_y[i] + dy[k];\n if (!inside(tx, ty) || field[ty][tx] == 0)\n continue;\n int ttx = kazu_x[i] + dx[(k + init_dir + (f ? 2 : 0)) % 4];\n int tty = kazu_y[i] + dy[(k + init_dir) % 4];\n if ((tx == ttx && ty == tty) || !inside(ttx, tty) || field[tty][ttx] == 0)\n continue;\n field[ty][tx] = 0;\n tatu_x[cnt] = tx, tatu_y[cnt] = ty;\n field[tty][ttx] = 0;\n kazu_x[cnt] = ttx, kazu_y[cnt] = tty;\n if (backtrack(cnt + 1, kS | (1LL << idx[make_pair(ttx, tty)]), init_dir,\n f))\n return true;\n field[tty][ttx] = 1;\n field[ty][tx] = 1;\n }\n }\n visited[cnt][init_dir][f].insert(kS);\n return false;\n}\nbool solve() {\n int i, j, k;\n if (csize % 2)\n return false;\n tatu_x[0] = cx[0], tatu_y[0] = cy[0];\n field[cy[0]][cx[0]] = 0;\n REP(j, 1, csize) {\n kazu_x[0] = cx[j], kazu_y[0] = cy[j];\n field[cy[j]][cx[j]] = 0;\n rep(k, 4) {\n if (backtrack(1, 1LL << j, k, 0))\n return true;\n if (backtrack(1, 1LL << j, k, 1))\n return true;\n }\n field[cy[j]][cx[j]] = 1;\n }\n field[cy[0]][cx[0]] = 1;\n return false;\n}\nint main() {\n int i, j, k, u;\n while (cin >> w >> h, w | h) {\n idx.clear();\n rep(i, 20) rep(j, 4) rep(k, 2) visited[i][j][k].clear();\n csize = 0;\n rep(i, h) rep(j, w) {\n cin >> field[i][j];\n if (field[i][j] == 1) {\n cx[csize] = j, cy[csize] = i;\n idx[make_pair(j, i)] = csize;\n csize++;\n }\n }\n puts(solve() ? \"YES\" : \"NO\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1060, "memory_kb": 11664, "score_of_the_acc": -1.1273, "final_rank": 16 }, { "submission_id": "aoj_1158_8115845", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <iostream>\n#include <map>\n#include <set>\n#include <vector>\nusing namespace std;\n\n#define REP(i, a, n) for (int i = a; i < n; i++)\n#define rep(i, n) REP(i, 0, n)\n#define all(x) x.begin(), x.end()\n#define rall(x) x.rbegin(), x.rend()\n#define foreach(it, x) for (typeof(x.begin()) it = x.begin(); it != x.end(); it++)\ntypedef long long ll;\nconst int dx[] = {0, 1, 0, -1};\nconst int dy[] = {-1, 0, 1, 0};\nint w, h, tatu_x[20], tatu_y[20], kazu_x[20], kazu_y[20];\nint field[12][12], cx[36], cy[36], csize;\nmap<pair<int, int>, int> idx;\nset<ll> visited[20][4][2];\n\n// Check if the point is inside the field\nbool inside(int x, int y) {\n return !(x < 0 || x >= w || y >= h || y < 0);\n}\n\n// Backtracking function\nbool backtrack(int cnt, ll kS, int init_dir, int f) {\n if (visited[cnt][init_dir][f].count(kS)) {\n return false;\n }\n if (csize / 2 == cnt) {\n return true;\n }\n rep(i, cnt) {\n rep(k, 4) {\n int tx = tatu_x[i] + dx[k];\n int ty = tatu_y[i] + dy[k];\n if (!inside(tx, ty) || field[ty][tx] == 0) {\n continue;\n }\n int ttx = kazu_x[i] + dx[(k + init_dir + (f ? 2 : 0)) % 4];\n int tty = kazu_y[i] + dy[(k + init_dir) % 4];\n if ((tx == ttx && ty == tty) || !inside(ttx, tty) || field[tty][ttx] == 0) {\n continue;\n }\n field[ty][tx] = 0;\n tatu_x[cnt] = tx, tatu_y[cnt] = ty;\n field[tty][ttx] = 0;\n kazu_x[cnt] = ttx, kazu_y[cnt] = tty;\n if (backtrack(cnt + 1, kS | (1LL << idx[make_pair(ttx, tty)]), init_dir, f)) {\n return true;\n }\n field[tty][ttx] = 1;\n field[ty][tx] = 1;\n }\n }\n visited[cnt][init_dir][f].insert(kS);\n return false;\n}\n\nbool solve() {\n if (csize % 2) {\n return false;\n }\n tatu_x[0] = cx[0], tatu_y[0] = cy[0];\n field[cy[0]][cx[0]] = 0;\n REP(j, 1, csize) {\n kazu_x[0] = cx[j], kazu_y[0] = cy[j];\n field[cy[j]][cx[j]] = 0;\n rep(k, 4) {\n if (backtrack(1, 1LL << j, k, 0)) {\n return true;\n }\n if (backtrack(1, 1LL << j, k, 1)) {\n return true;\n }\n }\n field[cy[j]][cx[j]] = 1;\n }\n field[cy[0]][cx[0]] = 1;\n return false;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cout.tie(NULL);\n while (cin >> w >> h, w | h) {\n idx.clear();\n rep(i, 20) rep(j, 4) rep(k, 2) visited[i][j][k].clear();\n csize = 0;\n rep(i, h) rep(j, w) {\n cin >> field[i][j];\n if (field[i][j] == 1) {\n cx[csize] = j, cy[csize] = i;\n idx[make_pair(j, i)] = csize;\n csize++;\n }\n }\n puts(solve() ? \"YES\" : \"NO\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1070, "memory_kb": 11704, "score_of_the_acc": -1.1332, "final_rank": 19 }, { "submission_id": "aoj_1158_8115844", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <iostream>\n#include <map>\n#include <set>\n#include <vector>\nusing namespace std;\n\n#define REP(i, a, n) for (int i = a; i < n; i++)\n#define rep(i, n) REP(i, 0, n)\n#define all(x) x.begin(), x.end()\n#define rall(x) x.rbegin(), x.rend()\n#define foreach(it, x) for (auto it = x.begin(); it != x.end(); it++)\ntypedef long long ll;\n\nconst int dx[] = {0, 1, 0, -1};\nconst int dy[] = {-1, 0, 1, 0};\n\nint w, h, tatu_x[20], tatu_y[20], kazu_x[20], kazu_y[20];\nint field[12][12], cx[36], cy[36], csize;\nmap<pair<int, int>, int> idx;\nset<ll> visited[20][4][2];\n\ninline bool inside(int x, int y) {\n return !(x < 0 || x >= w || y >= h || y < 0);\n}\n\nbool backtrack(int cnt, ll kS, int init_dir, int f) {\n if (visited[cnt][init_dir][f].count(kS)) return false;\n if (csize / 2 == cnt) return true;\n\n rep(i, cnt) {\n rep(k, 4) {\n int tx = tatu_x[i] + dx[k];\n int ty = tatu_y[i] + dy[k];\n if (!inside(tx, ty) || field[ty][tx] == 0) continue;\n\n int ttx = kazu_x[i] + dx[(k + init_dir + (f ? 2 : 0)) % 4];\n int tty = kazu_y[i] + dy[(k + init_dir) % 4];\n if ((tx == ttx && ty == tty) || !inside(ttx, tty) || field[tty][ttx] == 0)\n continue;\n\n field[ty][tx] = 0;\n tatu_x[cnt] = tx, tatu_y[cnt] = ty;\n field[tty][ttx] = 0;\n kazu_x[cnt] = ttx, kazu_y[cnt] = tty;\n\n if (backtrack(cnt + 1, kS | (1LL << idx[make_pair(ttx, tty)]), init_dir,\n f)) return true;\n\n field[tty][ttx] = 1;\n field[ty][tx] = 1;\n }\n }\n\n visited[cnt][init_dir][f].insert(kS);\n return false;\n}\n\nbool solve() {\n if (csize % 2) return false;\n\n tatu_x[0] = cx[0], tatu_y[0] = cy[0];\n field[cy[0]][cx[0]] = 0;\n\n REP(j, 1, csize) {\n kazu_x[0] = cx[j], kazu_y[0] = cy[j];\n field[cy[j]][cx[j]] = 0;\n\n rep(k, 4) {\n if (backtrack(1, 1LL << j, k, 0)) return true;\n if (backtrack(1, 1LL << j, k, 1)) return true;\n }\n\n field[cy[j]][cx[j]] = 1;\n }\n\n field[cy[0]][cx[0]] = 1;\n return false;\n}\n\nint main() {\n while (cin >> w >> h, w | h) {\n idx.clear();\n rep(i, 20) rep(j, 4) rep(k, 2) visited[i][j][k].clear();\n csize = 0;\n\n rep(i, h) rep(j, w) {\n cin >> field[i][j];\n if (field[i][j] == 1) {\n cx[csize] = j, cy[csize] = i;\n idx[make_pair(j, i)] = csize;\n csize++;\n }\n }\n\n puts(solve() ? \"YES\" : \"NO\");\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 1060, "memory_kb": 11672, "score_of_the_acc": -1.1282, "final_rank": 17 }, { "submission_id": "aoj_1158_8115843", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <iostream>\n#include <map>\n#include <set>\n#include <vector>\nusing namespace std;\n#define REP(i, a, n) for (int i = (a); i < (n); i++)\n#define rep(i, n) REP(i, 0, n)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define foreach(it, x) \\\n for (typeof((x).begin()) it = (x).begin(); it != (x).end(); it++)\ntypedef long long ll;\nconst int dx[] = {0, 1, 0, -1};\nconst int dy[] = {-1, 0, 1, 0};\nint w, h, tatu_x[20], tatu_y[20], kazu_x[20], kazu_y[20];\nint field[12][12], cx[36], cy[36], csize;\nmap<pair<int, int>, int> idx;\nset<ll> visited[20][4][2];\nbool inside(int x, int y) { return !(x < 0 || x >= w || y >= h || y < 0); }\nbool backtrack(int cnt, ll kS, int init_dir, int f) {\n if (visited[cnt][init_dir][f].count(kS))\n return false;\n if (csize / 2 == cnt)\n return true;\n for (int i = 0; i < cnt; i++) {\n for (int k = 0; k < 4; k++) {\n int tx = tatu_x[i] + dx[k];\n int ty = tatu_y[i] + dy[k];\n if (!inside(tx, ty) || field[ty][tx] == 0)\n continue;\n int ttx = kazu_x[i] + dx[(k + init_dir + (f ? 2 : 0)) % 4];\n int tty = kazu_y[i] + dy[(k + init_dir) % 4];\n if ((tx == ttx && ty == tty) || !inside(ttx, tty) || field[tty][ttx] == 0)\n continue;\n field[ty][tx] = 0, tatu_x[cnt] = tx, tatu_y[cnt] = ty;\n field[tty][ttx] = 0, kazu_x[cnt] = ttx, kazu_y[cnt] = tty;\n if (backtrack(cnt + 1, kS | (1LL << idx[make_pair(ttx, tty)]), init_dir,\n f))\n return true;\n field[tty][ttx] = 1, field[ty][tx] = 1;\n }\n }\n visited[cnt][init_dir][f].insert(kS);\n return false;\n}\nbool solve() {\n if (csize % 2)\n return false;\n tatu_x[0] = cx[0], tatu_y[0] = cy[0];\n field[cy[0]][cx[0]] = 0;\n REP(j, 1, csize) {\n kazu_x[0] = cx[j], kazu_y[0] = cy[j];\n field[cy[j]][cx[j]] = 0;\n rep(k, 4) {\n if (backtrack(1, 1LL << j, k, 0))\n return true;\n if (backtrack(1, 1LL << j, k, 1))\n return true;\n }\n field[cy[j]][cx[j]] = 1;\n }\n field[cy[0]][cx[0]] = 1;\n return false;\n}\nint main() {\n while (cin >> w >> h, w | h) {\n idx.clear();\n rep(i, 20) rep(j, 4) rep(k, 2) visited[i][j][k].clear();\n csize = 0;\n rep(i, h) rep(j, w) {\n cin >> field[i][j];\n if (field[i][j] == 1) {\n cx[csize] = j, cy[csize] = i;\n idx[make_pair(j, i)] = csize;\n csize++;\n }\n }\n puts(solve() ? \"YES\" : \"NO\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1060, "memory_kb": 11592, "score_of_the_acc": -1.1189, "final_rank": 11 }, { "submission_id": "aoj_1158_8115841", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <iostream>\n#include <map>\n#include <set>\n#include <vector>\nusing namespace std;\n\n#define REP(i, a, n) for (int i = a; i < n; i++)\n#define rep(i, n) REP(i, 0, n)\n#define all(x) x.begin(), x.end()\n#define rall(x) x.rbegin(), x.rend()\n#define foreach(it, x) for (auto it = x.begin(); it != x.end(); it++)\ntypedef long long ll;\nconst int dx[] = {0, 1, 0, -1};\nconst int dy[] = {-1, 0, 1, 0};\nint w, h, tatu_x[20], tatu_y[20], kazu_x[20], kazu_y[20];\nint field[12][12], cx[36], cy[36], csize;\nmap<pair<int, int>, int> idx;\nset<ll> visited[20][4][2];\n\nbool inside(int x, int y) { return !(x < 0 || x >= w || y >= h || y < 0); }\n\nbool backtrack(int cnt, ll kS, int init_dir, int f) {\n if (visited[cnt][init_dir][f].count(kS)) return false;\n if (csize / 2 == cnt) return true;\n rep(i, cnt) {\n rep(k, 4) {\n int tx = tatu_x[i] + dx[k];\n int ty = tatu_y[i] + dy[k];\n if (!inside(tx, ty) || field[ty][tx] == 0) continue;\n int ttx = kazu_x[i] + dx[(k + init_dir + (f ? 2 : 0)) % 4];\n int tty = kazu_y[i] + dy[(k + init_dir) % 4];\n if ((tx == ttx && ty == tty) || !inside(ttx, tty) ||\n field[tty][ttx] == 0)\n continue;\n field[ty][tx] = 0;\n tatu_x[cnt] = tx, tatu_y[cnt] = ty;\n field[tty][ttx] = 0;\n kazu_x[cnt] = ttx, kazu_y[cnt] = tty;\n if (backtrack(cnt + 1, kS | (1LL << idx[make_pair(ttx, tty)]), init_dir,\n f))\n return true;\n field[tty][ttx] = 1;\n field[ty][tx] = 1;\n }\n }\n visited[cnt][init_dir][f].insert(kS);\n return false;\n}\n\nbool solve() {\n if (csize % 2) return false;\n tatu_x[0] = cx[0], tatu_y[0] = cy[0];\n field[cy[0]][cx[0]] = 0;\n REP(j, 1, csize) {\n kazu_x[0] = cx[j], kazu_y[0] = cy[j];\n field[cy[j]][cx[j]] = 0;\n rep(k, 4) {\n if (backtrack(1, 1LL << j, k, 0)) return true;\n if (backtrack(1, 1LL << j, k, 1)) return true;\n }\n field[cy[j]][cx[j]] = 1;\n }\n field[cy[0]][cx[0]] = 1;\n return false;\n}\n\nint main() {\n while (cin >> w >> h, w | h) {\n idx.clear();\n rep(i, 20) rep(j, 4) rep(k, 2) visited[i][j][k].clear();\n csize = 0;\n rep(i, h) rep(j, w) {\n cin >> field[i][j];\n if (field[i][j] == 1) {\n cx[csize] = j, cy[csize] = i;\n idx[make_pair(j, i)] = csize;\n csize++;\n }\n }\n puts(solve() ? \"YES\" : \"NO\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1060, "memory_kb": 11648, "score_of_the_acc": -1.1254, "final_rank": 13 }, { "submission_id": "aoj_1158_8115840", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <iostream>\n#include <map>\n#include <set>\n#include <vector>\nusing namespace std;\n#define REP(i, a, n) for (int i = a; i < n; i++)\n#define rep(i, n) REP(i, 0, n)\n#define all(x) x.begin(), x.end()\n#define rall(x) x.rbegin(), x.rend()\n#define foreach(it, x) \\\n for (auto it = x.begin(); it != x.end(); it++)\ntypedef long long ll;\nconst int dx[] = {0, 1, 0, -1};\nconst int dy[] = {-1, 0, 1, 0};\nint w, h, tatu_x[20], tatu_y[20], kazu_x[20], kazu_y[20];\nint field[12][12], cx[36], cy[36], csize;\nmap<pair<int, int>, int> idx;\nset<ll> visited[20][4][2];\nbool inside(int x, int y) { return !(x < 0 || x >= w || y >= h || y < 0); }\nbool backtrack(int cnt, ll kS, int init_dir, int f) {\n if (visited[cnt][init_dir][f].count(kS))\n return false;\n if (csize / 2 == cnt)\n return true;\n rep(i, cnt) {\n rep(k, 4) {\n int tx = tatu_x[i] + dx[k];\n int ty = tatu_y[i] + dy[k];\n if (!inside(tx, ty) || field[ty][tx] == 0)\n continue;\n int ttx = kazu_x[i] + dx[(k + init_dir + (f ? 2 : 0)) % 4];\n int tty = kazu_y[i] + dy[(k + init_dir) % 4];\n if ((tx == ttx && ty == tty) || !inside(ttx, tty) || field[tty][ttx] == 0)\n continue;\n field[ty][tx] = 0;\n tatu_x[cnt] = tx, tatu_y[cnt] = ty;\n field[tty][ttx] = 0;\n kazu_x[cnt] = ttx, kazu_y[cnt] = tty;\n if (backtrack(cnt + 1, kS | (1LL << idx[make_pair(ttx, tty)]), init_dir,\n f))\n return true;\n field[tty][ttx] = 1;\n field[ty][tx] = 1;\n }\n }\n visited[cnt][init_dir][f].insert(kS);\n return false;\n}\nbool solve() {\n if (csize % 2)\n return false;\n tatu_x[0] = cx[0], tatu_y[0] = cy[0];\n field[cy[0]][cx[0]] = 0;\n REP(j, 1, csize) {\n kazu_x[0] = cx[j], kazu_y[0] = cy[j];\n field[cy[j]][cx[j]] = 0;\n rep(k, 4) {\n if (backtrack(1, 1LL << j, k, 0))\n return true;\n if (backtrack(1, 1LL << j, k, 1))\n return true;\n }\n field[cy[j]][cx[j]] = 1;\n }\n field[cy[0]][cx[0]] = 1;\n return false;\n}\nint main() {\n while (cin >> w >> h, w | h) {\n idx.clear();\n rep(i, 20) rep(j, 4) rep(k, 2) visited[i][j][k].clear();\n csize = 0;\n rep(i, h) rep(j, w) {\n cin >> field[i][j];\n if (field[i][j] == 1) {\n cx[csize] = j, cy[csize] = i;\n idx[make_pair(j, i)] = csize;\n csize++;\n }\n }\n puts(solve() ? \"YES\" : \"NO\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1060, "memory_kb": 11648, "score_of_the_acc": -1.1254, "final_rank": 13 }, { "submission_id": "aoj_1158_8115837", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <iostream>\n#include <map>\n#include <set>\n#include <vector>\nusing namespace std;\n#define REP(i, a, n) for (int i = a; i < n; i++)\n#define rep(i, n) REP(i, 0, n)\n#define all(x) x.begin(), x.end()\n#define rall(x) x.rbegin(), x.rend()\n#define foreach(it, x) \\\n for (auto it = x.begin(); it != x.end(); it++)\ntypedef long long ll;\nconst int dx[] = {0, 1, 0, -1};\nconst int dy[] = {-1, 0, 1, 0};\nint w, h, tatu_x[20], tatu_y[20], kazu_x[20], kazu_y[20];\nint field[12][12], cx[36], cy[36], csize;\nmap<pair<int, int>, int> idx;\nset<ll> visited[20][4][2];\nbool inside(int x, int y) { return !(x < 0 || x >= w || y >= h || y < 0); }\nbool backtrack(int cnt, ll kS, int init_dir, int f) {\n if (visited[cnt][init_dir][f].count(kS))\n return false;\n if (csize / 2 == cnt)\n return true;\n for (int i = 0; i < cnt; i++) {\n for (int k = 0; k < 4; k++) {\n int tx = tatu_x[i] + dx[k];\n int ty = tatu_y[i] + dy[k];\n if (!inside(tx, ty) || field[ty][tx] == 0)\n continue;\n int ttx = kazu_x[i] + dx[(k + init_dir + (f ? 2 : 0)) % 4];\n int tty = kazu_y[i] + dy[(k + init_dir) % 4];\n if ((tx == ttx && ty == tty) || !inside(ttx, tty) || field[tty][ttx] == 0)\n continue;\n field[ty][tx] = 0;\n tatu_x[cnt] = tx, tatu_y[cnt] = ty;\n field[tty][ttx] = 0;\n kazu_x[cnt] = ttx, kazu_y[cnt] = tty;\n if (backtrack(cnt + 1, kS | (1LL << idx[make_pair(ttx, tty)]), init_dir,\n f))\n return true;\n field[tty][ttx] = 1;\n field[ty][tx] = 1;\n }\n }\n visited[cnt][init_dir][f].insert(kS);\n return false;\n}\nbool solve() {\n if (csize % 2)\n return false;\n tatu_x[0] = cx[0], tatu_y[0] = cy[0];\n field[cy[0]][cx[0]] = 0;\n REP(j, 1, csize) {\n kazu_x[0] = cx[j], kazu_y[0] = cy[j];\n field[cy[j]][cx[j]] = 0;\n rep(k, 4) {\n if (backtrack(1, 1LL << j, k, 0))\n return true;\n if (backtrack(1, 1LL << j, k, 1))\n return true;\n }\n field[cy[j]][cx[j]] = 1;\n }\n field[cy[0]][cx[0]] = 1;\n return false;\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cout.tie(NULL);\n while (cin >> w >> h, w | h) {\n idx.clear();\n rep(i, 20) rep(j, 4) rep(k, 2) visited[i][j][k].clear();\n csize = 0;\n rep(i, h) rep(j, w) {\n cin >> field[i][j];\n if (field[i][j] == 1) {\n cx[csize] = j, cy[csize] = i;\n idx[make_pair(j, i)] = csize;\n csize++;\n }\n }\n puts(solve() ? \"YES\" : \"NO\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1060, "memory_kb": 11592, "score_of_the_acc": -1.1189, "final_rank": 11 } ]
aoj_1172_cpp
Chebyshev's Theorem If n is a positive integer, there exists at least one prime number greater than n and less than or equal to 2 n . This fact is known as Chebyshev's theorem or the Bertrand-Chebyshev theorem, which had been conjectured by Joseph Louis François Bertrand (1822–1900) and was proven by Pafnuty Lvovich Chebyshev (Пафнутий Львович Чебышёв, 1821–1894) in 1850. Srinivasa Aiyangar Ramanujan (1887–1920) gave an elementary proof in his paper published in 1919. Paul Erdős (1913–1996) discovered another elementary proof in 1932. For example, there exist 4 prime numbers greater than 10 and less than or equal to 20, i.e. 11, 13, 17 and 19. There exist 3 prime numbers greater than 14 and less than or equal to 28, i.e. 17, 19 and 23. Your mission is to write a program that counts the prime numbers greater than n and less than or equal to 2 n for each given positive integer n . Using such a program, you can verify Chebyshev's theorem for individual positive integers. Input The input is a sequence of datasets. A dataset is a line containing a single positive integer n . You may assume n ≤ 123456. The end of the input is indicated by a line containing a single zero. It is not a dataset. Output The output should be composed of as many lines as the input datasets. Each line should contain a single integer and should never contain extra characters. The output integer corresponding to a dataset consisting of an integer n should be the number of the prime numbers p satisfying n < p ≤ 2 n . Sample Input 1 10 13 100 1000 10000 100000 0 Output for the Sample Input 1 4 3 21 135 1033 8392
[ { "submission_id": "aoj_1172_10609798", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing a2 = array<ll, 2>;\nusing a3 = array<ll, 3>;\n\ntemplate <typename A> void chmin(A &l, const A &r) {\n if(r < l)\n l = r;\n}\ntemplate <typename A> void chmax(A &l, const A &r) {\n if(l < r)\n l = r;\n}\n\nll mod = 998244353;\n\nll n;\nvector<char> is_prime(400000, 1);\nvoid input() {\n cin >> n;\n is_prime[0] = 0;\n is_prime[1] = 0;\n for(int i = 2; i < is_prime.size(); i++) {\n if(is_prime[i]) {\n for(int j = 2 * i; j < is_prime.size(); j += i) {\n is_prime[j] = 0;\n }\n }\n }\n}\n\nvoid solve() {\n ll ans = 0;\n for(int i=n+1;i<=2*n;i++)\n {\n ans += is_prime[i];\n }\n cout << ans << endl;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n\n while(1) {\n input();\n if(n == 0)\n break;\n solve();\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 3436, "score_of_the_acc": -0.0954, "final_rank": 8 }, { "submission_id": "aoj_1172_10599022", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<long long>;\nusing vs = vector<string>;\nusing vc = vector<char>;\nusing vb = vector<bool>;\nusing vpii = vector<pair<int, int>>;\nusing vpll = vector<pair<long long, long long>>;\nusing vvi = vector<vector<int>>;\nusing vvl = vector<vector<long long>>;\nusing vvc = vector<vector<char>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing pii = pair<int, int>;\nusing vvb = vector<vector<bool>>;\nusing Graph = vector<vector<ll>>;\nconst ll LINF = 1001002003004005006ll;\nconst int INF = 1001001001;\nconst int MOD = 998244353;\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep3(i, m, n) for (int i = (m); i < (int)(n); i++)\n#define rrep(i, m, n) for (int i = (m); i >= (int)(n); i--)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\nvi dx4 = {1, 0, -1, 0}, dy4 = {0, 1, 0, -1};\nvi dx8 = {1, 1, 1, 0, 0, -1, -1, -1}, dy8 = {1, 0, -1, 1, -1, 1, 0, -1};\n\nint main()\n{\n vi cnt(250000, 0);\n rep3(i, 2, 250001)\n {\n bool ok = true;\n rep3(j, 2, sqrt(i) + 1)\n {\n if (i % j == 0)\n {\n ok = false;\n break;\n }\n }\n if (ok)\n {\n cnt[i]++;\n }\n }\n rep(i, 250000) { cnt[i + 1] += cnt[i]; }\n while (1)\n {\n int n;\n cin >> n;\n if (n == 0)\n {\n break;\n }\n cout << cnt[2 * n] - cnt[n] << '\\n';\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3768, "score_of_the_acc": -0.066, "final_rank": 7 }, { "submission_id": "aoj_1172_10572042", "code_snippet": "// AOJ 1172 - Chebyshev's Theorem\n// ICPC Japan Domestic Contest 2011 - Problem A\n\n#include <bits/stdc++.h>\nusing namespace std;\n\nbool solving() {\n int N; cin >> N;\n if(N == 0) return false;\n\n unordered_set<int> prime;\n for(int i=2; i<=2*N; ++i) prime.insert(i);\n int rt = sqrt(2*N);\n while((rt+1)*(rt+1) <= 2*N) ++rt;\n while((rt-1)*(rt-1) >= 2*N) --rt;\n for(int i=2; i<=rt; ++i) {\n for(int j=i; i*j<=2*N; ++j) {\n prime.erase(i*j);\n }\n }\n for(int i=2; i<=N; ++i) prime.erase(i);\n cout << prime.size() << endl;\n return true;\n}\n\nint main() {\n while(solving()) {}\n}", "accuracy": 1, "time_ms": 1130, "memory_kb": 15056, "score_of_the_acc": -1.2276, "final_rank": 20 }, { "submission_id": "aoj_1172_10533031", "code_snippet": "#if __has_include(<yoniha/all.h>)\n#include <yoniha/all.h>\nusing namespace atcoder;\n#else\n#include <bits/stdc++.h>\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\nusing namespace atcoder;\n#endif\n#endif\nusing namespace std;\n\n#define int long long\n#define all(x) (x).begin(), (x).end()\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rrep(i, n) for(int i = (int)(n - 1); i >= 0; i--)\ntemplate <typename T> bool chmax(T &a,const T &b){if(a<b){a=b;return true;}return false;}\ntemplate <typename T> bool chmin(T &a,const T &b){if(a>b){a=b;return true;}return false;}\n\n// using mint = modint;\n\nvoid solve(int n){\n vector isprime(2 * n + 1, true);\n for(int p = 2; p <= 2 * n; p++){\n if(!isprime.at(p)) continue;\n for(int i = 2; p * i <= 2 * n; i++) isprime.at(p * i) = false;\n }\n cout << reduce(isprime.begin() + n + 1, isprime.end(), 0ll) << '\\n';\n}\n\nsigned main(){\n while(true){\n int n; cin >> n;\n if(n == 0) break;\n solve(n);\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3584, "score_of_the_acc": -0.0549, "final_rank": 6 }, { "submission_id": "aoj_1172_10523333", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n#include <algorithm>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <ctime>\n#include <string>\n#include <functional>\nusing namespace std;\nusing ll = long long;\nusing lb = long double;\n\nint is_prime(int n);\n\nvector<int> prime(2*123456+1, -1); //-1: unknown, 0: not prime, 1: prime\nint main() {\n int n;\n while (true) {\n cin >> n;\n if (n == 0) return 0;\n int ans = 0;\n int double_n = 2*n;\n n++;\n while (n <= double_n) {\n if (is_prime(n) == 1) ans++;\n n++;\n }\n cout << ans << endl;\n }\n return 0;\n}\n\nint is_prime(int n) {\n if (prime[n] != -1) return prime[n];\n else {\n bool primeflag = true;\n for (int i = 2; i < sqrt(n)+1; i++) {\n if (n != i && n%i == 0) {primeflag = false; break;}\n }\n if (primeflag) {\n prime[n] = 1;\n for (int i = 0; i < prime.size(); i++) {\n if (prime[i] == 1) {\n for (int j = 2; i*j < n; j++) {\n prime[i*j] = 0;\n }\n }\n }\n }\n else prime[n] = 0;\n return prime[n];\n }\n}", "accuracy": 1, "time_ms": 4930, "memory_kb": 3960, "score_of_the_acc": -1.0799, "final_rank": 19 }, { "submission_id": "aoj_1172_10523254", "code_snippet": "// 123456\n#include <iostream>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n#include <algorithm>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <ctime>\n#include <string> //to_string等\n#include <functional>\nusing namespace std;\nusing ll = long long;\nusing lb = long double;\n\nint main(){\n\n vector<int>pn(0);\n\n auto isPrime = [&](int num){\n if (num < 2) return false;\n else if (num == 2) return true;\n else if (num % 2 == 0) return false; // 偶数はあらかじめ除く\n\n double sqrtNum = sqrt(num);\n for (int i = 3; i <= sqrtNum; i += 2)\n {\n if (num % i == 0)\n {\n // 素数ではない\n return false;\n }\n }\n\n // 素数である\n return true;\n };\n\n for(int i=0;i<=123456*2;i++){\n if(isPrime(i)){\n pn.push_back(i);\n }\n }\n\n while(true){\n int n;\n cin >> n;\n if(n==0)return 0;\n int cnt=0;\n for(int i=0;i<pn.size();i++){\n if(pn[i] > n && pn[i]<= n*2){\n cnt++;\n }\n }\n cout << cnt << endl;\n }\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3492, "score_of_the_acc": -0.0411, "final_rank": 4 }, { "submission_id": "aoj_1172_10489649", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing P = pair<int, int>;\nusing PP = pair<int, P>;\nusing PLL = pair<ll, ll>;\nusing PPLL = pair<ll, PLL>;\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define rrep(i, n) for(ll i = n - 1; i >= 0; --i)\n#define loop(i, a, b) for(ll i = a; i <= b; ++i)\n#define all(v) v.begin(), v.end()\n#define nC2(n) n * (n - 1) / 2\nconstexpr ll INF = 9009009009009009009LL;\nconstexpr int INF32 = 2002002002;\nconstexpr ll MOD = 998244353;\nconstexpr ll MOD107 = 1000000007;\n\n// Linear Algebra ////////////////////////////////////////////////\nconst double Rad2Deg = 180.0 / M_PI;\nconst double Deg2Rad = M_PI / 180.0;\n//////////////////////////////////////////////////////////////////\n\nint dx[8] = {0, 1, 0, -1, 1, 1, -1, -1};\nint dy[8] = {1, 0, -1, 0, 1, -1, 1, -1};\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) {\n\tif (a < b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\ntemplate <class T>\ninline bool chmin(T &a, const T &b) {\n\tif (a > b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\n\ntemplate <typename Container,\n typename = std::enable_if_t<\n !std::is_same_v<Container, std::string> &&\n std::is_convertible_v<decltype(std::declval<Container>().begin()),\n typename Container::iterator>>>\nostream &operator<<(ostream &os, const Container &container) {\n auto it = container.begin();\n auto end = container.end();\n\n if (it != end) {\n os << *it;\n ++it;\n }\n\tfor (; it != end; ++it) {\n\t\tos << \" \" << *it;\n\t}\n return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v) {\n for (size_t i = 0; i < v.size(); ++i) {\n os << v[i];\n if (i != v.size() - 1) os << \" \";\n }\n return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<vector<T>>& vv) {\n\tfor (size_t i = 0; i < vv.size(); ++i) {\n\t\tos << vv[i];\n\t\tif (i != vv.size() - 1) os << \"\\n\";\n }\n return os;\n}\ntemplate <typename T>\nistream& operator>>(istream& is, vector<T>& v) {\n\tassert(v.size() > 0);\n\tfor (size_t i = 0; i < v.size(); ++i) is >> v[i];\n\treturn is;\n}\ntemplate <typename T>\nistream& operator>>(istream& is, vector<vector<T>>& vv) {\n\tassert(vv.size() > 0);\n\tfor (size_t i = 0; i < vv.size(); ++i) is >> vv[i];\n\treturn is;\n}\n\nstruct phash {\n\ttemplate<class T1, class T2>\n inline size_t operator()(const pair<T1, T2> & p) const {\n auto h1 = hash<T1>()(p.first);\n auto h2 = hash<T2>()(p.second);\n\n\t\tsize_t seed = h1 + h2; \n\t\th1 = ((h1 >> 16) ^ h1) * 0x45d9f3b;\n h1 = ((h1 >> 16) ^ h1) * 0x45d9f3b;\n h1 = (h1 >> 16) ^ h1;\n seed ^= h1 + 0x9e3779b9 + (seed << 6) + (seed >> 2);\n\t\th2 = ((h2 >> 16) ^ h2) * 0x45d9f3b;\n h2 = ((h2 >> 16) ^ h2) * 0x45d9f3b;\n h2 = (h2 >> 16) ^ h2;\n seed ^= h2 + 0x9e3779b9 + (seed << 6) + (seed >> 2);\n return seed;\n }\n};\n\n\n\n\n/**\n * @brief エラトステネスの篩 O(N log log N)\n * @param n 素数を求める範囲\n * @return vector<bool> xが素数かどうか\n */\nvector<bool> sieve(const ll n) {\n\tvector<bool> is_prime(n + 1, true);\n\tis_prime[0] = is_prime[1] = false;\n\tfor (ll i = 2; i * i <= n; ++i) {\n\t\tif (!is_prime[i]) continue;\n\t\tfor (ll j = i * i; j <= n; j += i) is_prime[j] = false;\n\t}\n\treturn is_prime;\n}\n\n/**\n * @brief エラトステネスの篩 O(N log log N)\n * @param n 素数を求める範囲\n * @return vector<ll> 素数のリスト\n */\nvector<ll> primes(const ll n) {\n\tvector<bool> is_prime(n + 1, true);\n\tvector<ll> res;\n\tis_prime[0] = is_prime[1] = false;\n\tfor (ll i = 2; i <= n; ++i) {\n\t\tif (!is_prime[i]) continue;\n\t\tres.push_back(i);\n\t\tfor (ll j = i * i; j <= n; j += i) is_prime[j] = false;\n\t}\n\treturn res;\n}\n\nint solve() {\n\tll n; cin >> n;\n\tif (n == 0) return 1;\n\n\tconst ll MAX = 123456 * 2;\n\tunordered_set<ll> p;\n\tfor (auto x : primes(MAX)) {\n\t\tp.insert(x);\n\t}\n\n\tll ans = 0;\n\tloop(i, n + 1, 2 * n) {\n\t\tif (p.count(i)) ans++;\n\t}\n\n\tcout << ans << endl;\n\n\treturn 0;\n}\n\nint main() {\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\n\twhile (!solve()) { }\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 660, "memory_kb": 4404, "score_of_the_acc": -0.2489, "final_rank": 14 }, { "submission_id": "aoj_1172_10408550", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n#define rep(i, m, n) for (ll i = (ll)m; i < (ll)n; i++)\n#define drep(i, m, n) for (ll i = m - 1; i >= n; i--)\n#define Endl endl\n#define all(a) a.begin(), a.end()\n#define pr(i, j) make_pair(i, j)\n#define isin(x, l, r) (l <= x && x < r)\n#define chmin(a, b) a = min(a, b)\n#define chmax(a, b) a = max(a, b)\n#define srt(ar) sort(ar.begin(), ar.end())\n#define rev(ar) reverse(ar.begin(), ar.end())\n#define jge(f, s, t) cout << (f ? s : t) << endl\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define printar(ar) \\\n do \\\n { \\\n for (auto dbg : ar) \\\n { \\\n cout << dbg << \" \"; \\\n } \\\n cout << endl; \\\n } while (0)\nconst ll inf = 1e18;\nconst ld pi = 3.14159265358979;\nconst ld eps = 1e-9;\ntemplate <class T, ll n, ll idx = 0>\nauto make_vec(const ll (&d)[n], const T &init) noexcept\n{\n if constexpr (idx < n)\n return std::vector(d[idx], make_vec<T, n, idx + 1>(d, init));\n else\n return init;\n}\n\ntemplate <class T, ll n>\nauto make_vec(const ll (&d)[n]) noexcept\n{\n return make_vec(d, T{});\n}\n//////////////// 以下を貼る ////////////////\ntemplate <class T>\nsize_t HashCombine(const size_t seed, const T &v)\n{\n return seed ^ (std::hash<T>()(v) + 0x9e3779b9 + (seed << 6) + (seed >> 2));\n}\n/* pair用 */\ntemplate <class T, class S>\nstruct std::hash<std::pair<T, S>>\n{\n size_t operator()(const std::pair<T, S> &keyval) const noexcept\n {\n return HashCombine(std::hash<T>()(keyval.first), keyval.second);\n }\n};\n////////////////////////////////////////////\nbool is_p(ll n)\n{\n if (n == 1)\n {\n return false;\n }\n for (ll i = 2; i * i <= n; i++)\n {\n if (n % i == 0)\n {\n return false;\n }\n }\n return true;\n}\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n vector<ll> cnt(1);\n rep(i, 1, 300000)\n {\n cnt.push_back(cnt[i - 1] + is_p(i));\n }\n while (true)\n {\n ll n;\n cin >> n;\n if (n == 0)\n {\n break;\n }\n cout << cnt[2 * n] - cnt[n] << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 8548, "score_of_the_acc": -0.4624, "final_rank": 15 }, { "submission_id": "aoj_1172_10406807", "code_snippet": "#include <bits/stdc++.h>\n#include <atcoder/all>\nusing namespace atcoder;\nusing namespace std;\n#define all(...) std::begin(__VA_ARGS__), std::end(__VA_ARGS__)\n#define rall(...) std::rbegin(__VA_ARGS__), std::rend(__VA_ARGS__)\n#define OVERLOAD_REP(_1, _2, _3, _4, name, ...) name\n#define REP1(n) for(ll i=0;i<n;i++)\n#define REP2(i, n) for (ll i=0;i<n;i++)\n#define REP3(i, a, n) for (ll i=a;i<n;i++)\n#define REP4(i, a, b, n) for(ll i=a;i<n;i+=b)\n#define rep(...) OVERLOAD_REP(__VA_ARGS__, REP4, REP3, REP2, REP1)(__VA_ARGS__)\n#define OVERLOAD_RREP(_1, _2, _3, _4, name, ...) name\n#define RREP1(n) for(ll i=n;i>=0;i--)\n#define RREP2(i, n) for(ll i=n;i>=0;i--)\n#define RREP3(i, a, n) for(ll i=n;i>=a;i--)\n#define RREP4(i, a, b, n) for(ll i=n;i>=a;i-=b)\n#define rrep(...) OVERLOAD_RREP(__VA_ARGS__, RREP4, RREP3, RREP2, RREP1)(__VA_ARGS__)\n#define foa(a,v) (auto& a : (v))\n#define uniq(a) sort(all(a));a.erase(unique(all(a)),end(a))\n#define len(n) (long long)(n).size()\n#define pb push_back\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vs = vector<string>;\nusing vvs = vector<vs>;\nusing vvvs = vector<vvs>;\nusing vld = vector<ld>;\nusing vvld = vector<vld>;\nusing vvvld = vector<vvld>;\nusing vc = vector<char>;\nusing vvc = vector<vc>;\nusing vvvc = vector<vvc>;\nusing pll = pair<ll,ll>;\nusing vpll = vector<pll>;\ntemplate<class... T>\nconstexpr auto min(T... a){\n return min(initializer_list<common_type_t<T...>>{a...});\n}\ntemplate<class... T>\nconstexpr auto max(T... a){\n return max(initializer_list<common_type_t<T...>>{a...});\n}\ntemplate<class... T>\nvoid input(T&... a){\n (cin >> ... >> a);\n}\nll modpow(ll a,ll b,ll c){\n ll ans = 1;\n while (b){\n if (b & 1){\n ans *= a;\n ans %= c;\n }\n a *= a;\n a %= c;\n b /= 2;\n }\n return ans;\n}\n#define INT(...) int __VA_ARGS__; input(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define ULL(...) ull __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define CHA(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define VLL(name,length) vll name(length);rep(i,length){cin >> name[i];}\n#define VVLL(name,h,w) vvll name(h,vll(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVLL(name,a,b,c) vvvll name(a,vvll(b,vll(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VI(name,length) vi name(length);rep(i,length){cin >> name[i];}\n#define VVI(name,h,w) vvi name(h,vi(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVI(name,a,b,c) vvvi name(a,vvll(b,vi(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VLD(name,length) vld name(length);rep(i,length){cin >> name[i];}\n#define VVLD(name,h,w) vvld name(h,vld(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVLD(name,a,b,c) vvvld name(a,vvld(b,vld(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VC(name,length) vc name(length);rep(i,length){cin >> name[i];}\n#define VVC(name,h,w) vvc name(h,vc(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVC(name,a,b,c) vvvc name(a,vvc(b,vc(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VS(name,length) vs name(length);rep(i,length){cin >> name[i];}\n#define VVS(name,h,w) vvs name(h,vs(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVS(name,a,b,c) vvvs name(a,vvs(b,vs(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define PLL(name) pll name;cin>>name.first>>name.second;\n#define VPLL(name,length) vpll name(length);rep(i,length){cin>>name[i].first>>name[i].second;}\n\nvoid print(){cout << \"\\n\";}\ntemplate<class T, class... Ts>\nvoid print(const T& a, const Ts&... b){cout << a;(cout << ... << (cout << ' ', b));cout << '\\n';}\nvoid print(vll x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid print(vvll x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\n\n\n\nint main(){\n while(1){\n LL(n);\n if(n == 0){break;}\n\n auto check = [&](int x){\n rep(i,2,x){\n if(x % i == 0){\n return 0;\n }\n if(i * i > x + 1000){break;}\n }\n return 1;\n };\n auto solve = [&](){\n ll ans = 0;\n rep(i,n+1,2*n+1){\n if(check(i)){\n ans++;\n }\n }\n print(ans);\n };\n solve();\n }\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 3584, "score_of_the_acc": -0.1219, "final_rank": 11 }, { "submission_id": "aoj_1172_9570673", "code_snippet": "#include <iostream>\n#include <cmath>\nusing namespace std;\n\nbool is_prime[246913];\nint n,count;\n\nbool isPrime(int n){\n if(n%6!=1&&n%6!=5){\n return false;\n }\n\n for(int i=5;i<=(int)(sqrt(n));i+=6){\n if(n%i==0||n%(i+2)==0){\n return false;\n }\n }\n return true;\n\n}\n\nvoid findPrime(){\n is_prime[2]=true;\n is_prime[3]=true;\n for(int i=5;i<=246912;i++){\n if(isPrime(i)){\n is_prime[i]=true;\n }\n }\n \n}\n\nint main(){\n findPrime();\n while(cin>>n,n!=0){\n for(int i=n+1;i<=2*n;i++){\n if(is_prime[i]){\n count++;\n }\n }\n cout<<count<<endl;\n count=0;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3328, "score_of_the_acc": -0.0275, "final_rank": 2 }, { "submission_id": "aoj_1172_9453606", "code_snippet": "#include <iostream>\nusing namespace std;\n\n// 簡略化された素数判定関数\nbool isPrime(int num) {\n if (num == 2) return true; // 2は素数\n if (num % 2 == 0) return false; // 偶数は素数ではない\n for (int i = 3; i * i <= num; i += 2) {\n if (num % i == 0) return false;\n }\n return true;\n}\n\nint main() {\n int n;\n while (1) {\n cin >> n;\n if (n == 0) break;\n\n int primeCount = 0;\n\n // nより大きく2n以下の素数の数を数える\n for (int i = n + 1; i <= 2 * n; ++i) {\n if (isPrime(i)) {\n ++primeCount;\n }\n }\n\n cout << primeCount << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 2996, "score_of_the_acc": -0.0386, "final_rank": 3 }, { "submission_id": "aoj_1172_9453586", "code_snippet": "#include <iostream>\nusing namespace std;\n\n// 素数判定関数\nbool isPrime(int num) {\n if (num <= 1) return false;\n if (num == 2) return true;\n if (num % 2 == 0) return false;\n for (int i = 3; i * i <= num; i += 2) {\n if (num % i == 0) return false;\n }\n return true;\n}\n\nint main() {\n int n;\n while (1) {\n cin >> n;\n if (n == 0) break;\n\n int primeCount = 0;\n\n // nより大きく2n以下の素数の数を数える\n for (int i = n + 1; i <= 2 * n; ++i) {\n if (isPrime(i)) {\n ++primeCount;\n }\n }\n\n cout << primeCount << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 3088, "score_of_the_acc": -0.0462, "final_rank": 5 }, { "submission_id": "aoj_1172_9399412", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n#include <iterator>\n#include <algorithm>\n#include <cmath>\n#include <stack>\nusing namespace std;\n\nvector<bool> hurui(int max_num)\n{\n vector<bool> isPrime(max_num + 1, true);\n isPrime[0] = isPrime[1] = false;\n\n for (int i = 2; i * i <= max_num;i++)\n {\n if(isPrime[i])\n {\n for (int j = i * i; j <= max_num;j += i)\n {\n isPrime[j] = false;\n }\n }\n }\n\n return isPrime;\n}\nint main()\n{\n while (true)\n {\n int n;\n cin >> n;\n if (n == 0)\n {\n break;\n }\n\n int ttimesn = 2 * n, count = 0;\n vector<bool> is_prime = hurui(ttimesn); \n for (int i = n + 1; i <= ttimesn; i++) {\n if (is_prime[i]) {\n count++;\n }\n }\n\n cout << count << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3104, "score_of_the_acc": -0.011, "final_rank": 1 }, { "submission_id": "aoj_1172_9387629", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(i=0;i<n;i++)\nusing ll=long long;\n\nbool isprime(int x){\n if(x<2) return false;\n for(int i=2;i*i<=x;i++){\n if(x%i==0) return false;\n }\n return true;\n}\n\nint main(){\n while(true){\n int n;\n cin >> n;\n if(n==0) break;\n int cnt=0;\n\n for(int i=n+1;i<=2*n;i++){\n if(isprime(i)) cnt++;\n }\n\n cout << cnt << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 3436, "score_of_the_acc": -0.0954, "final_rank": 8 }, { "submission_id": "aoj_1172_9356876", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nbool IsPrime(ll num) {\n if (num < 2) return false;\n else if (num == 2) return true;\n else if (num % 2 == 0) return false;\n\n double sqrtNum = sqrt(num);\n for (ll i = 3; i <= sqrtNum; i += 2) {\n if (num % i == 0) {\n return false;\n }\n }\n return true;\n}\n\nint main() {\n while(true) {\n ll n, n1, n2, ans = 0;\n cin >> n;\n if(n == 0) {\n break;\n }\n n1 = n + 1;\n n2 = 2 * n;\n for(ll i = n1; i <= n2; i++) {\n if(IsPrime(i)) {\n ans++;\n }\n }\n cout << ans << endl;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 500, "memory_kb": 3388, "score_of_the_acc": -0.1321, "final_rank": 12 }, { "submission_id": "aoj_1172_9331085", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<long long>;\nusing vs = vector<string>;\nusing vc = vector<char>;\nusing vb = vector<bool>;\nusing vpii = vector<pair<int, int>>;\nusing vpll = vector<pair<long long, long long>>;\nusing vvi = vector<vector<int>>;\nusing vvl = vector<vector<long long>>;\nusing vvc = vector<vector<char>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing pii = pair<int, int>;\nusing vvb = vector<vector<bool>>;\nusing Graph = vector<vector<ll>>;\nconst ll LINF = 1001002003004005006ll;\nconst int INF = 1001001001;\nconst int MOD = 998422353;\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep3(i, m, n) for (int i = (m); i < (int)(n); i++)\n#define rrep(i, m, n) for (int i = (m); i >= (int)(n); i--)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\nvi dx4 = {1, 0, -1, 0}, dy4 = {0, 1, 0, -1};\nvi dx8 = {1, 1, 1, 0, 0, -1, -1, -1}, dy8 = {1, 0, -1, 1, -1, 1, 0, -1};\n\nbool isprime(long long n)\n{\n if (n <= 1)\n return false;\n for (long long p = 2; p * p <= n; p++)\n {\n if (n % p == 0)\n return false;\n }\n return true;\n}\n\nint main()\n{\n while (1)\n {\n // 宣言・入力の受け取り\n int n;\n cin >> n;\n // 終了条件\n if (n == 0)\n {\n break;\n }\n // 宣言・入力の受け取り\n\n // solve\n int ans = 0;\n rep3(i, n + 1, 2 * n + 1)\n {\n if (isprime(i))\n {\n ans++;\n }\n }\n // 出力\n cout << ans << '\\n';\n }\n return 0;\n}", "accuracy": 1, "time_ms": 980, "memory_kb": 3372, "score_of_the_acc": -0.2283, "final_rank": 13 }, { "submission_id": "aoj_1172_9329759", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nbool isPrime(int x){\n if(x==1)return false;\n for(int i=2;i*i<=x;i++){\n if(x%i==0)return false;\n }\n return true;\n}\nint main(){\n while(true){\n int n;\n cin >> n;\n if(n==0)break;\n int cnt=0;\n for(int i=n+1;i<=2*n;i++){\n if(isPrime(i))cnt++;\n }\n cout << cnt << endl;\n }\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 3440, "score_of_the_acc": -0.0958, "final_rank": 10 }, { "submission_id": "aoj_1172_9321162", "code_snippet": "#include <iostream>\n#include <vector>\n#include <set>\n#include <map>\nusing namespace std;\n\nint main() {\n vector<int> res;\n\n while(true) {\n int n; cin >> n;\n if(n==0) break;\n int ans = 0;\n\n for(int i = n+1; i <= 2*n; i++) {\n bool ok = true;\n for(int j = 2; j * j <= i; j++) {\n if(i%j==0) {\n ok = false;\n }\n }\n if(ok == true) ans++;\n \n }\n res.push_back(ans);\n }\n\n for(int i = 0; i < res.size(); i++) cout << res[i] << endl;\n\n return 0; \n}", "accuracy": 1, "time_ms": 3310, "memory_kb": 3140, "score_of_the_acc": -0.6827, "final_rank": 17 }, { "submission_id": "aoj_1172_9259886", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define all(a) a.begin(),a.end()\n#define reps(i, a, n) for (int i = (a); i < (int)(n); i++)\n#define rep(i, n) reps(i, 0, n)\n#define rreps(i, a, n) for (int i = (a); i > (int)(n); i--)\nconst long long mod = 1000000007;\nconst long long INF = 1e18;\n\nint n;\n\nvoid solve() {\n int ans = 0;\n reps(i,n+1,2*n+1) {\n if (i == 2) {\n ans++;\n continue;\n }\n if (i%2 == 0) {\n continue;\n }\n bool q = true;\n for (int j = 3; j < min((int)pow(i,0.5)+10,i-1); j+=2) {\n if (i%j == 0) {\n q = false;\n break;\n }\n }\n if (q) {\n ans++;\n }\n }\n cout << ans << endl;\n return;\n}\n\nint main() {\n while (true) {\n cin >> n;\n if (n == 0) {\n return 0;\n }\n solve();\n }\n}", "accuracy": 1, "time_ms": 3120, "memory_kb": 3740, "score_of_the_acc": -0.6938, "final_rank": 18 }, { "submission_id": "aoj_1172_9104678", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n vector<int> prime;\n for(int i = 2; i < 10000000; i++){\n int is_prime = 1;\n for(int j = 0; j < (int)prime.size() && prime[j] * prime[j] <= i; j++){\n if(i % prime[j] == 0){\n is_prime = 0;\n break;\n }\n }\n if(is_prime)prime.push_back(i);\n }\n // for(int i = 0; i < 25; i++)cout << prime[i] << endl;\n while(1){\n int n;\n cin >> n;\n if(n == 0)break;\n cout << distance(upper_bound(prime.begin(),prime.end(),n),upper_bound(prime.begin(),prime.end(),2 * n)) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 540, "memory_kb": 8036, "score_of_the_acc": -0.5256, "final_rank": 16 } ]
aoj_1168_cpp
Problem D: Off Balance You are working for an administration office of the International Center for Picassonian Cubism (ICPC), which plans to build a new art gallery for young artists. The center is organizing an architectural design competition to find the best design for the new building. Submitted designs will look like a screenshot of a well known game as shown below. This is because the center specifies that the building should be constructed by stacking regular units called pieces , each of which consists of four cubic blocks. In addition, the center requires the competitors to submit designs that satisfy the following restrictions. All the pieces are aligned. When two pieces touch each other, the faces of the touching blocks must be placed exactly at the same position. All the pieces are stable. Since pieces are merely stacked, their centers of masses must be carefully positioned so as not to collapse. The pieces are stacked in a tree-like form in order to symbolize boundless potentiality of young artists. In other words, one and only one piece touches the ground, and each of other pieces touches one and only one piece on its bottom faces. The building has a flat shape. This is because the construction site is a narrow area located between a straight moat and an expressway where no more than one block can be placed between the moat and the expressway as illustrated below. It will take many days to fully check stability of designs as it requires complicated structural calculation. Therefore, you are asked to quickly check obviously unstable designs by focusing on centers of masses. The rules of your quick check are as follows. Assume the center of mass of a block is located at the center of the block, and all blocks have the same weight. We denote a location of a block by xy -coordinates of its left-bottom corner. The unit length is the edge length of a block. Among the blocks of the piece that touch another piece or the ground on their bottom faces, let x L be the leftmost x -coordinate of the leftmost block, and let x R be the rightmost x -coordinate of the rightmost block. Let the x -coordinate of its accumulated center of mass of the piece be M , where the accumulated center of mass of a piece P is the center of the mass of the pieces that are directly and indirectly supported by P , in addition to P itself. Then the piece is stable, if and only if x L < M < x R . Otherwise, it is unstable. A design of a building is unstable if any of its pieces is unstable. Note that the above rules could judge some designs to be unstable even if it would not collapse in reality. For example, the left one of the following designs shall be judged to be unstable. Also note that the rules judge boundary cases to be unstable. For example, the top piece in the above right design has its center of mass exactly above the right end of the bottom piece. This shall be judged to be unstable. Write a program that judges stabilit ...(truncated)
[ { "submission_id": "aoj_1168_5490233", "code_snippet": "#include <stdio.h>\n#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n#define Inf 1000000000\n\nstruct dsu {\n\tpublic:\n\tdsu() : _n(0) {}\n\texplicit dsu(int n) : _n(n), parent_or_size(n, -1) {}\n\n\tint merge(int a, int b) {\n\t\tassert(0 <= a && a < _n);\n\t\tassert(0 <= b && b < _n);\n\t\tint x = leader(a), y = leader(b);\n\t\tif (x == y) return x;\n\t\tif (-parent_or_size[x] < -parent_or_size[y]) std::swap(x, y);\n\t\tparent_or_size[x] += parent_or_size[y];\n\t\tparent_or_size[y] = x;\n\t\treturn x;\n\t}\n\n\tbool same(int a, int b) {\n\t\tassert(0 <= a && a < _n);\n\t\tassert(0 <= b && b < _n);\n\t\treturn leader(a) == leader(b);\n\t}\n\n\tint leader(int a) {\n\t\tassert(0 <= a && a < _n);\n\t\tif (parent_or_size[a] < 0) return a;\n\t\treturn parent_or_size[a] = leader(parent_or_size[a]);\n\t}\n\n\tint size(int a) {\n\t\tassert(0 <= a && a < _n);\n\t\treturn -parent_or_size[leader(a)];\n\t}\n\n\tstd::vector<std::vector<int>> groups() {\n\t\tstd::vector<int> leader_buf(_n), group_size(_n);\n\t\tfor (int i = 0; i < _n; i++) {\n\t\t\tleader_buf[i] = leader(i);\n\t\t\tgroup_size[leader_buf[i]]++;\n\t\t}\n\t\tstd::vector<std::vector<int>> result(_n);\n\t\tfor (int i = 0; i < _n; i++) {\n\t\t\tresult[i].reserve(group_size[i]);\n\t\t}\n\t\tfor (int i = 0; i < _n; i++) {\n\t\t\tresult[leader_buf[i]].push_back(i);\n\t\t}\n\t\tresult.erase(\n\t\t\tstd::remove_if(result.begin(), result.end(),\n\t\t\t\t\t\t [&](const std::vector<int>& v) { return v.empty(); }),\n\t\t\tresult.end());\n\t\treturn result;\n\t}\n\n\tprivate:\n\tint _n;\n\t// root node: -1 * component size\n\t// otherwise: parent\n\tstd::vector<int> parent_or_size;\n};\n\nvoid Unite(vector<string> s,dsu &D){\n\tint h = s.size(),w = s[0].size();\n\tvector<int> dx = {1,-1,0,0},dy = {0,0,1,-1};\n\t\n\trep(i,h){\n\t\trep(j,w){\n\t\t\tif(isdigit(s[i][j])){\n\t\t\t\trep(k,4){\n\t\t\t\t\tint y = i+dy[k],x = j+dx[k];\n\t\t\t\t\tif(y<0||y>=h||x<0||x>=w)continue;\n\t\t\t\t\tif(s[i][j]==s[y][x]){\n\t\t\t\t\t\tD.merge(i*w+j,y*w+x);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\t\n}\n\nvoid Unite2(vector<string> s,dsu &D){\n\tint h = s.size(),w = s[0].size();\n\tvector<int> dx = {1,-1,0,0},dy = {0,0,1,-1};\n\t\n\trep(i,h){\n\t\trep(j,w){\n\t\t\tif(isdigit(s[i][j])){\n\t\t\t\trep(k,4){\n\t\t\t\t\tint y = i+dy[k],x = j+dx[k];\n\t\t\t\t\tif(y<0||y>=h||x<0||x>=w)continue;\n\t\t\t\t\tif(s[i][j]==s[y][x]){\n\t\t\t\t\t\tD.merge(i*w+j,y*w+x);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(i==h-1){\n\t\t\t\t\tD.merge(i*w+j,h*w);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tif(isdigit(s[i+1][j])){\n\t\t\t\t\t\tD.merge(i*w+j,(i+1)*w+j);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\t\n}\n\nint main(){\n\t\n\twhile(true){\n\t\tint w,h;\n\t\tcin>>w>>h;\n\t\t\n\t\tif(w==0)break;\n\t\t\n\t\tvector<string> s(h);\n\t\trep(i,h){\n\t\t\tcin>>s[i];\n\t\t}\n\t\t\n\t\tdsu D(w*h+1);\n\t\tUnite(s,D);\n\t\t\n\t\tbool f = true;\n\t\t\n\t\tauto ret = D.groups();\n\t\t\n\t\trep(i,ret.size()){\n\t\t\tif(ret[i].size()!=4)continue;\n\t\t\t\n\t\t\tauto ss = s;\n\t\t\tint mini = Inf,maxi = -Inf;\n\t\t\tint sum = 0,cnt = 0;\n\t\t\trep(j,ret[i].size()){\n\t\t\t\tint t = ret[i][j];\n\t\t\t\tint y = t/w,x = t%w;\n\t\t\t\tss[y][x] = '.';\n\t\t\t\tif(y==h-1 || (isdigit(s[y+1][x])&&s[y+1][x]!=s[y][x])){\n\t\t\t\t\tmini = min(mini,x);\n\t\t\t\t\tmaxi = max(maxi,x);\n\t\t\t\t}\n\t\t\t\tcnt++;\n\t\t\t\tsum += x*2+1;\n\t\t\t\t//cout<<y<<','<<x<<\" \";\n\t\t\t}\n\t\t\t//cout<<endl;\n\t\t\tdsu DD(h*w+1);\n\t\t\tUnite(ss,DD);\n\t\t\tUnite2(ss,DD);\n\t\t\t\n\t\t\trep(j,h){\n\t\t\t\trep(k,w){\n\t\t\t\t\tif(isdigit(ss[j][k])&&!DD.same(h*w,j*w+k)){\n\t\t\t\t\t\tcnt ++;\n\t\t\t\t\t\tsum += k*2 + 1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(cnt==0)continue;\n\t\t\tmini *= 2;\n\t\t\tmaxi ++;\n\t\t\tmaxi *= 2;\n\t\t\tmini *= cnt;\n\t\t\tmaxi *= cnt;\n\t\t\t\n\t\t\tif(mini < sum && sum < maxi)continue;\n\t\t\tf=false;\n\t\t\tbreak;\n\t\t\t\n\t\t}\n\t\t\n\t\tif(f)cout<<\"STABLE\"<<endl;\n\t\telse cout<<\"UNSTABLE\"<<endl;\n\t\t\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3136, "score_of_the_acc": -0.123, "final_rank": 11 }, { "submission_id": "aoj_1168_4460736", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,a,...) for(int i = (a)*(strlen(#__VA_ARGS__)!=0);i<(int)(strlen(#__VA_ARGS__)?__VA_ARGS__:(a));++i)\n#define per(i,a,...) for(int i = (strlen(#__VA_ARGS__)?__VA_ARGS__:(a))-1;i>=(int)(strlen(#__VA_ARGS__)?(a):0);--i)\n#define foreach(i, n) for(auto &i:(n))\n#define pii pair<int, int>\n#define pll pair<long long, long long>\n#define all(x) (x).begin(), (x).end()\n#define bit(x) (1ll << (x))\nusing ll = long long;\n//const ll MOD = (ll)1e9+7;\nconst ll MOD = 998244353;\nconst int INF = (ll)1e9+7;\nconst ll INFLL = (ll)1e18;\nusing namespace std;\ntemplate<class t>\nusing vvector = vector<vector<t>>;\ntemplate<class t>\nusing vvvector = vector<vector<vector<t>>>;\ntemplate<class t>\nusing priority_queuer = priority_queue<t, vector<t>, greater<t>>;\ntemplate<class t, class u> bool chmax(t &a, u b){if(a<b){a=b;return true;}return false;}\ntemplate<class t, class u> bool chmin(t &a, u b){if(a>b){a=b;return true;}return false;}\n#ifdef DEBUG\n#define debug(x) cout<<\"LINE \"<<__LINE__<<\": \"<<#x<<\" = \"<<x<<endl;\n#else\n#define debug(x) (void)0\n#endif\n\nnamespace templates{\n ll modpow(ll x, ll b){\n ll res = 1;\n while(b){\n if(b&1)res = res * x % MOD;\n x = x * x % MOD;\n b>>=1;\n }\n return res;\n }\n\n ll modinv(ll x){\n return modpow(x, MOD-2);\n }\n\n bool was_output = false;\n template<class t>\n void output(t a){\n if(was_output)cout << \" \";\n cout << a;\n was_output = true;\n }\n void outendl(){\n was_output = false;\n cout << endl;\n }\n ll in(){\n ll res;\n scanf(\"%lld\", &res);\n return res;\n }\n\n template<class t>\n istream& operator>>(istream&is, vector<t>&x){\n for(auto &i:x)is >> i;\n return is;\n }\n\n template<class t, class u>\n istream& operator>>(istream&is, pair<t, u>&x){\n is >> x.first >> x.second;\n return is;\n }\n\n template<class t>\n void in(t&x){\n cin >> x;\n }\n\n template<class t>\n t in(){\n t res; cin >> res; return res;\n }\n\n template<class t>\n void out(t x){\n cout << x;\n }\n\n template<class t>\n vector<t> sorted(vector<t> line,function<bool(t,t)> comp=[](t a,t b){return a<b;}){\n sort(line.begin(),line.end(),comp);\n return line;\n }\n\n template<class t>\n vector<t> reversed(vector<t> line){\n reverse(line.begin(),line.end());\n return line;\n }\n}\n\nusing namespace templates;\n\nbool func(int w,int h){\n vvector<int> board(w,vector<int>(h,-1));\n per(y,h){\n rep(x,w){\n char d = in<char>();\n if(d=='.'){\n board[x][y] = -1;\n }else{\n board[x][y] = d - '0';\n }\n }\n }\n\n map<set<pii>,set<pii>> dp;\n int mx[]={-1,0,1,0};\n int my[]={0,1,0,-1};\n\n auto isin =\n [&](int x,int y){\n return 0<=min(x,y) and x < w and y < h;\n };\n\n function<set<pii>(int,int)> get_parents =\n [&](int x,int y){\n int color = board[x][y];\n set<pii> current;\n {\n stack<pii> st;\n current.emplace(x,y);\n st.emplace(x,y);\n while(st.size()){\n pii d = st.top();\n st.pop();\n rep(i,4){\n int nx = mx[i] + d.first;\n int ny = my[i] + d.second;\n if(!isin(nx,ny))continue;\n if(color!=board[nx][ny])continue;;\n if(current.count(pii(nx,ny)))continue;\n current.emplace(nx,ny);\n st.emplace(nx,ny);\n }\n }\n }\n if(dp.count(current)){\n return dp[current];\n }\n set<pii> parents;\n foreach(mino,current){\n int nx = mino.first;\n int ny = mino.second+1;\n if(isin(nx,ny) and color != board[nx][ny] and board[nx][ny] >= 0){\n set<pii> d = get_parents(nx,ny);\n foreach(j,d){\n parents.emplace(j);\n }\n }\n parents.emplace(mino);\n }\n dp[current] = parents;\n return parents;\n };\n function<bool(int,int)> check =\n [&](int x,int y){\n set<pii> current;\n int color = board[x][y];\n {\n stack<pii> st;\n current.emplace(x,y);\n st.emplace(x,y);\n while(st.size()){\n pii d = st.top();\n st.pop();\n rep(i,4){\n int nx = mx[i] + d.first;\n int ny = my[i] + d.second;\n if(!isin(nx,ny))continue;\n if(color!=board[nx][ny])continue;;\n if(current.count(pii(nx,ny)))continue;\n current.emplace(nx,ny);\n st.emplace(nx,ny);\n }\n }\n }\n double left = INF;\n double right = -INF;\n foreach(i,current){\n int nx = i.first;\n int ny = i.second - 1;\n if(ny<0 or (board[nx][ny] != color and board[nx][ny] >= 0)){\n left = min(left,nx-0.5);\n right = max(right,nx+0.5);\n }\n }\n set<pii> parents = get_parents(x,y);\n double sum = 0;\n foreach(i,parents){\n sum += i.first;\n }\n sum /= parents.size();\n left += 1e-5;\n right -= 1e-5;\n return left <= sum and sum <= right;\n };\n rep(x,w){\n rep(y,h){\n if(board[x][y]>=0){\n if(!check(x,y)){\n return false;\n }\n }\n }\n }\n return true;\n}\n\nint main(){\n int h;\n int w;\n while(true){\n w = in();\n h = in();\n if(!h or !w)break;\n cout << ((func(w,h))?\"STABLE\":\"UNSTABLE\") << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3448, "score_of_the_acc": -0.1578, "final_rank": 15 }, { "submission_id": "aoj_1168_3758860", "code_snippet": "#include <queue>\n#include <string>\n#include <vector>\n#include <iostream>\nusing namespace std;\nconst vector<int> dx = { 0, 1, 0, -1 };\nconst vector<int> dy = { 1, 0, -1, 0 };\nstruct state { int x, y, over; };\nconst int inf = 1012345678;\nint main() {\n\tint H, W;\n\twhile (cin >> W >> H, H) {\n\t\tvector<string> S(H);\n\t\tfor (int i = 0; i < H; ++i) {\n\t\t\tcin >> S[i];\n\t\t}\n\t\tbool stable = true;\n\t\tfor (int i = 0; i < H; ++i) {\n\t\t\tfor (int j = 0; j < W; ++j) {\n\t\t\t\tif (S[i][j] == '.') continue;\n\t\t\t\tvector<vector<bool> > vis(H, vector<bool>(W));\n\t\t\t\tvis[i][j] = true;\n\t\t\t\tdeque<state> que;\n\t\t\t\tque.push_back(state{ i, j, 0 });\n\t\t\t\tint L = inf, R = -inf, sum = 0, cnt = 0;\n\t\t\t\twhile (!que.empty()) {\n\t\t\t\t\tstate u = que.front(); que.pop_front();\n\t\t\t\t\tsum += u.y;\n\t\t\t\t\t++cnt;\n\t\t\t\t\tfor (int k = 0; k < 4; ++k) {\n\t\t\t\t\t\tint tx = u.x + dx[k], ty = u.y + dy[k];\n\t\t\t\t\t\tif (0 <= tx && tx < H && 0 <= ty && ty < W && !vis[tx][ty] && (S[tx][ty] == S[u.x][u.y] || (k == 3 && S[tx][ty] != '.'))) {\n\t\t\t\t\t\t\tvis[tx][ty] = true;\n\t\t\t\t\t\t\tif (S[tx][ty] == S[u.x][u.y]) {\n\t\t\t\t\t\t\t\tque.push_front(state{ tx, ty, u.over });\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\telse {\n\t\t\t\t\t\t\t\tque.push_back(state{ tx, ty, u.over + 1 });\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t\tif (u.over == 0 && k == 1 && (tx == H || (S[tx][ty] != '.' && S[tx][ty] != S[u.x][u.y]))) {\n\t\t\t\t\t\t\tL = min(L, u.y);\n\t\t\t\t\t\t\tR = max(R, u.y + 1);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tsum = sum * 2 + cnt;\n\t\t\t\tcnt *= 2;\n\t\t\t\tif (!(L * cnt < sum && sum < R * cnt)) {\n\t\t\t\t\tstable = false;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << (stable ? \"STABLE\" : \"UNSTABLE\") << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3172, "score_of_the_acc": -0.1402, "final_rank": 14 }, { "submission_id": "aoj_1168_3736698", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef vector<ll> vl;\ntypedef vector<vl> mt;\n\nmt visit;\nmt p;\nqueue<vl> q;\nll w,h;\nll dx[4] = {0, 1, 0, -1};\nll dy[4] = {1, 0, -1, 0};\n\nbool isin(ll x, ll y){\n return x >= 0 && x < w && y >= 0 && y <= h;\n}\n\nvoid show_visit(){\n for(ll i = 0;i <= h;i++){\n for(ll j = 0;j < w;j++){\n cerr << visit[i][j] << \" \";\n }\n cerr << endl;\n }\n cerr << endl;\n}\n\nint main(){\n while(cin >> w >> h){\n if(w == 0 && h == 0) return 0;\n p = mt(h,vl(w));\n for(ll i = 0;i < h;i++){\n string s;\n cin >> s;\n for(ll j = 0;j < w;j++){\n if(s[j] == '.') p[i][j] = -1;\n else p[i][j] = s[j]-'0';\n }\n }\n p.push_back(vl(w, 0));\n bool flag = true;\n for(ll py = 0;py < h;py++){\n for(ll px = 0;px < w;px++){\n if(p[py][px] == -1) continue;\n visit = mt(h+1,vl(w));\n q = queue<vl>();\n ll xl = w+1,xr = 0;\n visit[py][px] = 1;\n q.push(vl({py, px, p[py][px], 0}));\n\n ll sum = 0;\n ll block_num = 0;\n while(!q.empty()){\n ll y = q.front()[0];\n ll x = q.front()[1];\n ll block = q.front()[2];\n ll cnt = q.front()[3];\n sum += x;\n block_num++;\n if(cnt == 0){\n if(p[y+1][x] != -1 && p[y+1][x] != block){\n xl = min(xl,x);\n xr = max(xr,x+1);\n }\n }\n\n q.pop();\n\n for(ll d = 0;d < 4;d++){\n ll next = x+dx[d];\n ll neyt = y+dy[d];\n if(isin(next, neyt)){\n if(p[neyt][next] == -1) continue;\n if(visit[neyt][next] == 1) continue;\n if(p[neyt][next] == block){\n visit[neyt][next] = 1;\n q.push(vl({neyt, next, p[neyt][next], cnt}));\n }else{\n if(d != 2) continue;\n visit[neyt][next] = 1;\n q.push(vl({neyt, next, p[neyt][next], cnt+1}));\n }\n }\n }\n\n\n\n }\n // show_visit();\n // cerr << sum << \" \" << xl << \" \" << xr << endl;\n sum += block_num/2;\n if(sum > xl*block_num && sum < xr*block_num){\n\n }else{\n flag = false;\n }\n }\n }\n\n if(flag){\n cout << \"STABLE\" << endl;\n }else{\n cout << \"UNSTABLE\" << endl;\n }\n }\n\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3244, "score_of_the_acc": -0.1598, "final_rank": 16 }, { "submission_id": "aoj_1168_3677238", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define fs first\n#define sc second\n#define pb push_back\n#define mp make_pair\n#define eb emplace_back\n#define ALL(A) A.begin(),A.end()\n#define RALL(A) A.rbegin(),A.rend()\ntypedef long long LL;\ntypedef pair<int,int> P;\nconst LL mod=1000000007;\nconst LL LINF=1LL<<60;\nconst int INF=1<<30;\nint dx[]={1,0,-1,0};\nint dy[]={0,1,0,-1};\n \n \nbool used[100][100];\nbool v[100][100];\nint xl,xr;\nint h,w;\n \n \nP rec(int x,int y,bool f,vector<string> s){\n used[y][x]=true;\n if(f){\n v[y][x]=true;\n }\n int r=2*x+1;\n int t=1;\n for (int i = 0; i < 4; i++) {\n int nx=x+dx[i],ny=y+dy[i];\n if(f){\n if(i==1){\n if(s[ny][nx]!=s[y][x]&&s[ny][nx]!='.'){\n xl=min(xl,x);\n xr=max(xr,x+1);\n }\n }\n }\n if(0<=nx&&nx<w&&0<=ny&&ny<h){\n if(s[ny][nx]=='.'||used[ny][nx]) continue;\n if(s[y][x]!=s[ny][nx]){\n if(i==3){\n P p = rec(nx,ny,false,s);\n r += p.fs;\n t += p.sc;\n }\n }\n else{\n P p = rec(nx,ny,f,s);\n r += p.fs;\n t += p.sc;\n }\n }\n }\n return mp(r,t);\n}\n \n \nint main(){\n while(1){\n cin >> w >> h;\n if(!h&&!w) return 0;\n vector<string> s(h);\n memset(v,false,sizeof(v));\n for (int i = 0; i < h; i++) {\n cin >> s[i];\n }\n string k=\"\";\n for (int i = 0; i < w; i++) {\n k.pb('#');\n }\n s.pb(k);\n bool flag=false;\n for (int i = h-1; i >= 0; i--) {\n for (int j = 0; j < w; j++) {\n memset(used,false,sizeof(used));\n if(s[i][j]=='.'||v[i][j]) continue;\n xl=100,xr=0;\n P p = rec(j,i,true,s);\n if(p.fs<=2*xl*p.sc||2*xr*p.sc<=p.fs) flag=true;\n }\n }\n if(flag) puts(\"UNSTABLE\");\n else puts(\"STABLE\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3280, "score_of_the_acc": -0.177, "final_rank": 18 }, { "submission_id": "aoj_1168_3669192", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define fs first\n#define sc second\n#define pb push_back\n#define mp make_pair\n#define eb emplace_back\n#define ALL(A) A.begin(),A.end()\n#define RALL(A) A.rbegin(),A.rend()\ntypedef long long LL;\ntypedef pair<double,int> P;\nconst LL mod=1000000007;\nconst LL LINF=1LL<<60;\nconst int INF=1<<30;\nint dx[]={1,0,-1,0};\nint dy[]={0,1,0,-1};\n\n\nbool used[100][100];\nbool v[100][100];\nint xl,xr;\nint h,w;\n\n\nP rec(int x,int y,bool f,vector<string> s){\n used[y][x]=true;\n if(f){\n v[y][x]=true;\n }\n double r=x+0.5;\n int t=1;\n for (int i = 0; i < 4; i++) {\n int nx=x+dx[i],ny=y+dy[i];\n if(f){\n if(i==1){\n if(s[ny][nx]!=s[y][x]&&s[ny][nx]!='.'){\n xl=min(xl,x);\n xr=max(xr,x+1);\n }\n }\n }\n if(0<=nx&&nx<w&&0<=ny&&ny<h){\n if(s[ny][nx]=='.'||used[ny][nx]) continue;\n if(s[y][x]!=s[ny][nx]){\n if(i==3){\n P p = rec(nx,ny,false,s);\n r += p.fs;\n t += p.sc;\n }\n }\n else{\n P p = rec(nx,ny,f,s);\n r += p.fs;\n t += p.sc;\n }\n }\n }\n return mp(r,t);\n}\n\n\nint main(){\n while(1){\n cin >> w >> h;\n if(!h&&!w) return 0;\n vector<string> s(h);\n memset(v,false,sizeof(v));\n for (int i = 0; i < h; i++) {\n cin >> s[i];\n }\n string k=\"\";\n for (int i = 0; i < w; i++) {\n k.pb('#');\n }\n s.pb(k);\n bool flag=false;\n for (int i = h-1; i >= 0; i--) {\n for (int j = 0; j < w; j++) {\n memset(used,false,sizeof(used));\n if(s[i][j]=='.'||v[i][j]) continue;\n xl=100,xr=0;\n P p = rec(j,i,true,s);\n double M = p.fs/p.sc;\n if(M<=xl||xr<=M) flag=true;\n }\n }\n if(flag) puts(\"UNSTABLE\");\n else puts(\"STABLE\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3180, "score_of_the_acc": -0.1706, "final_rank": 17 }, { "submission_id": "aoj_1168_3573890", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> l_l;\ntypedef pair<int, int> i_i;\n\n#define EPS (1e-7)\n#define INF (1e9)\n#define PI (acos(-1))\n//const ll mod = 1000000007;\nstruct UnionFind {\n vector<int> par;\n vector<int> rank;\n vector<ll> Size;\n UnionFind(int n = 1) {\n init(n);\n }\n\n void init(int n = 1) {\n par.resize(n + 1); rank.resize(n + 1); Size.resize(n + 1);\n for (int i = 0; i <= n; ++i) par[i] = i, rank[i] = 0, Size[i] = 1;\n }\n\n int root(int x) {\n if (par[x] == x) {\n return x;\n }\n else {\n int r = root(par[x]);\n return par[x] = r;\n }\n }\n\n bool issame(int x, int y) {\n return root(x) == root(y);\n }\n\n bool merge(int x, int y) {\n x = root(x); y = root(y);\n if (x == y) return false;\n if (rank[x] < rank[y]) swap(x, y);\n if (rank[x] == rank[y]) ++rank[x];\n par[y] = x;\n Size[x] += Size[y];\n return true;\n }\n\n ll size(int x){\n return Size[root(x)];\n }\n};\n\nint W, H;\nint field[65][65];\nint root;\nmap<int, int> parent;\nmap<int, vector<int> > children;\nmap<int, vector<i_i> > grids;\nbool clear;\nmap<int, int> wsum;\nmap<int, int> wnum;\nvoid dfs(int from) {\n for(int i = 0; i < grids[from].size(); i++) {\n i_i next = grids[from][i];\n next.first++;\n if(next.first > H) continue;\n if(field[next.first][next.second] == -2) continue;\n if(field[next.first][next.second] == from) continue;\n //if(field[next.first][next.second] == parent[from]) continue;\n if(parent[field[next.first][next.second]] != -1) continue;\n parent[field[next.first][next.second]] = from;\n children[from].push_back(field[next.first][next.second]);\n dfs(field[next.first][next.second]);\n }\n //cerr << from << endl;\n //cerr << \"parent: \" << parent[from] << endl;\n //cerr << \"children: \";\n //for(int i = 0; i < children[from].size(); i++) cerr << children[from][i] << \" \";\n //cerr << endl;\n}\n\nvoid dfs2(int from) {\n wsum[from] = 0;\n wnum[from] = 4;\n int wmax = -INF;\n int wmin = INF;\n for(int i = 0; i < grids[from].size(); i++) {\n int wnow = grids[from][i].second;\n int hnow = grids[from][i].first;\n wsum[from] += wnow;\n if(field[hnow-1][wnow] == parent[from] || (parent[from] == -1 && hnow == 1)) wmax = max(wmax, wnow);\n if(field[hnow-1][wnow] == parent[from] || (hnow == 1 && parent[from] == -1)) wmin = min(wmin, wnow);\n }\n for(int i = 0; i < children[from].size(); i++) {\n int to = children[from][i];\n dfs2(to);\n wsum[from] += wsum[to];\n wnum[from] += wnum[to];\n }\n if((wmin - 1) * 2 * wnum[from] >= 2 * wsum[from] - wnum[from] || (wmax * 2) * wnum[from] <= 2 * wsum[from] - wnum[from]) {\n clear = false;\n //cerr << \"FAIL: \" << from << endl;\n }\n //cerr << from << \" \" << wnum[from] << \" \" << wsum[from] << \" \" << wmin << \" \" << wmax << endl;\n}\n\nUnionFind uni;\nint dh[4] = {1, 0, -1, 0};\nint dw[4] = {0, 1, 0, -1};\n\nint main() {\n //cout.precision(10);\n cin.tie(0);\n ios::sync_with_stdio(false);\n while(true) {\n clear = true;\n cin >> W >> H;\n if(W == 0) break;\n for(int i = 0; i <= 60000; i++) {\n children[i].clear();\n parent[i] = -1;\n grids[i].clear();\n }\n for(int h = 1; h <= 61; h++) {\n for(int w = 1; w <= W; w++) field[h][w] = 0;\n }\n for(int h = H; h >= 1; h--) {\n string now;\n cin >> now;\n now = \"#\" + now;\n for(int i = 1; i <= W; i++) field[h][i] = now[i] - '0';\n /*\n for(int w = 1; w <= W; w++) {\n if(now[w] != '.') grids[field[h][w]].push_back({h, w});\n }\n */\n }\n uni.init(100000);\n for(int h = 1; h <= H; h++) {\n for(int w = 1; w <= W; w++) {\n //cerr << h << \" \" << w << endl;\n if(field[h][w] == (int)('.' - '0')) continue;\n if(h < H) {\n if(field[h][w] == field[h+1][w]) uni.merge(h*100+w, h*100+100+w);\n }\n if(w < W) {\n if(field[h][w] == field[h][w+1]) uni.merge(h*100+w, h*100+w+1);\n }\n }\n }\n for(int h = 1; h <= H; h++) {\n for(int w = 1; w <= W; w++) {\n if(uni.size(h*100+w) == 1) continue;\n field[h][w] = uni.root(h*100+w);\n }\n }\n //cout << (int)('.') << endl;\n for(int h = H; h >= 1; h--) {\n for(int w = 1; w <= W; w++) {\n if(field[h][w] != '.') grids[field[h][w]].push_back({h, w});\n //cerr << field[h][w] << \" \";\n }\n //cerr << endl;\n }\n for(int w = 1; w <= W; w++) {\n if(field[1][w] != -2) root = field[1][w];\n }\n //cerr << root << endl;\n dfs(root);\n /*\n for(char a = '0'; a <= '9'; a++) {\n //cerr << a << \" \" << parent[a] << endl;\n }\n */\n dfs2(root);\n if(clear) cout << \"STABLE\" << endl;\n else cout << \"UNSTABLE\" << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 570, "memory_kb": 16908, "score_of_the_acc": -1.8358, "final_rank": 20 }, { "submission_id": "aoj_1168_3001966", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <string>\n#include <deque>\n#include <utility>\n#include <set>\n#include <queue>\n#include <functional>\n\n#define REP(i, n) FOR(i, 0, n)\n#define FOR(i, a, b) for(int i = int(a); i < int(b); ++i)\n#define RREP(i, n) RFOR(i, 0, n)\n#define RFOR(i, a, b) for(int i = int(b) - 1; i >= int(a); --i)\n\nconstexpr double EPS = 1e-7;\n\nusing PAIR = std::pair<int, int>;\n\nstruct Part {\n\tchar num;\n\tstd::vector<PAIR> p;\n};\n\nint dy4[] = { -1,0,1,0 };\nint dx4[] = { 0,1,0,-1 };\n\nint w, h;\nchar mat[63][13];\nbool visited[63][13];\n\nPart getPart(int y, int x) {\n\tif (mat[y][x] == '.') return Part();\n\tPart res;\n\tchar c = mat[y][x];\n\tres.num = c;\n\n\tstd::set<PAIR> set;\n\tset.insert(PAIR(y, x));\n\tstd::queue<PAIR> que;\n\tque.push(PAIR(y, x));\n\n\twhile (!que.empty()) {\n\t\tPAIR now = que.front(); que.pop();\n\n\t\tREP(d, 4) {\n\t\t\tint dy = now.first + dy4[d];\n\t\t\tint dx = now.second + dx4[d];\n\t\t\tif (dy < 1 || dy >= h + 1 || dx < 0 || dx >= w) continue;\n\t\t\tif (mat[dy][dx] != c) continue;\n\t\t\tPAIR to(dy, dx);\n\t\t\tif (set.count(to)) continue;\n\t\t\tset.insert(to);\n\t\t\tque.push(to);\n\t\t}\n\t}\n\n\tfor (auto& p : set) {\n\t\tres.p.emplace_back(p);\n\t}\n\treturn res;\n}\n\n\n\nsigned main() {\n\n\twhile (true) {\n\t\tstd::cin >> w >> h;\n\t\tif (w == 0 && h == 0) break;\n\t\tREP(i, h) REP(j, w) {\n\t\t\tstd::cin >> mat[i + 1][j];\n\t\t\tvisited[i + 1][j] = false;\n\t\t}\n\t\tREP(j, w) mat[0][j] = '.', mat[h + 1][j] = '#';\n\n\t\tbool ok = [&] {\n\t\t\tRFOR(i, 1, h + 1) REP(j, w) {\n\t\t\t\tif (mat[i][j] == '.') continue;\n\t\t\t\tif (visited[i][j]) continue;\n\n\t\t\t\tauto base = getPart(i, j);\n\t\t\t\tint l = 1000, r = -1;\n\t\t\t\tfor (auto& pos : base.p) {\n\t\t\t\t\tint y = pos.first, x = pos.second;\n\t\t\t\t\tvisited[y][x] = true;\n\t\t\t\t\tif (mat[y + 1][x] != '.' && mat[y + 1][x] != base.num) {\n\t\t\t\t\t\tl = std::min(l, x);\n\t\t\t\t\t\tr = std::max(r, x + 1);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tstd::set<PAIR> above;\n\t\t\t\tstd::function<void(int,int,bool)> calcAbove = [&](int y, int x, bool clear = true) {\n\t\t\t\t\tif (clear) above.clear();\n\t\t\t\t\tif (above.count(PAIR(y, x))) return;\n\n\t\t\t\t\tPart part = getPart(y, x);\n\t\t\t\t\tfor (auto& p : part.p) above.insert(p);\n\n\t\t\t\t\tfor (auto & p : part.p) {\n\t\t\t\t\t\tchar c = mat[p.first - 1][p.second];\n\t\t\t\t\t\tif (c != part.num && c != '.') {\n\t\t\t\t\t\t\tcalcAbove(p.first - 1, p.second, false);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t};\n\n\t\t\t\tcalcAbove(i, j, true);\n\t\t\t\tint sz = above.size();\n\t\t\t\tint sumx = 0;\n\t\t\t\tfor (auto& p : above) {\n\t\t\t\t\tsumx += p.second;\n\t\t\t\t}\n\t\t\t\tif (l * 2 * sz >= sumx * 2 + sz || sumx * 2 + sz >= r * 2 * sz) return false;\n\t\t\t}\n\t\t\treturn true;\n\t\t}();\n\t\tstd::cout << (ok ? \"STABLE\" : \"UNSTABLE\") << \"\\n\";\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2940, "score_of_the_acc": -0.1105, "final_rank": 10 }, { "submission_id": "aoj_1168_2958234", "code_snippet": "#include<bits/stdc++.h>\n#define r(i,n) for(int i=0;i<n;i++)\nusing namespace std;\ntypedef pair<int,int>P;\nstring s[66],t[66];\nint dy[]={-1,0,0,1};\nint dx[]={0,1,-1,0};\nint h,cnt,w,used[66][130],sum;\nmap<int,int>id_sum;\nmap<int,vector<int> >id_each;\nvoid id_dfs(int y,int x,vector<vector<int> >&a,char X,vector<int>&id_x){\n a[y][x]=cnt;\n id_x.push_back(x);\n used[y][x]=1;\n sum++;\n r(i,4){\n int ny=y+dy[i];\n int nx=x+dx[i];\n if(ny<0||nx<0||ny>=h||nx>=w)continue;\n if(used[ny][nx])continue;\n if(s[ny][nx]==X)id_dfs(ny,nx,a,X,id_x);\n }\n}\nP get_lr(int y,int x,vector<vector<int> >&a){\n int id=a[y][x];\n int ny=y;\n int l_x=1e8,r_x=-1e8;\n for(;ny<h;ny++){\n int flag=0;\n r(j,w)if(a[ny][j]==id){\n if(ny+1==h||(a[ny+1][j]!=-1&&a[ny+1][j]!=id)){\n l_x=min(l_x,j);\n r_x=max(r_x,j);\n }\n flag++;\n }\n if(!flag)break;\n }\n return P(l_x,r_x);\n}\nvector<int> get_data(int y,int x,vector<vector<int> >&a){\n int used2[600]={};\n int oy=y,ox=x;\n vector<int>id_x;\n queue<P>q;\n q.push(P(y,x));\n used2[a[y][x]]=1;\n while(!q.empty()){\n P p=q.front();q.pop();\n y=p.first;\n x=p.second;\n r(i,h)r(j,w)if(a[i][j]==a[y][x]){\n if(a[i][j]==a[oy][ox])used[i][j]=1;\n id_x.push_back(j);\n r(k,1){\n int ny=i+dy[k];\n int nx=j+dx[k];\n if(ny<0||nx<0||ny>=h||nx>=w)continue;\n if(a[ny][nx]==-1)continue;\n if(used2[a[ny][nx]])continue;\n used2[a[ny][nx]]=1;\n q.push(P(ny,nx));\n }\n }\n }\n return id_x;\n}\nsigned main(){\n while(cin>>w>>h,w){\n id_sum.clear();\n id_each.clear();\n cnt=0;\n memset(used,0,sizeof(used));\n r(i,h)cin>>s[i];\n vector<vector<int> >a(h,vector<int>(w));\n r(i,h)r(j,w)a[i][j]=-1;\n r(i,h)r(j,w)if(isdigit(s[i][j])){\n if(!used[i][j]){\n vector<int>id_x;\n sum=0;\n id_dfs(i,j,a,s[i][j],id_x);\n id_sum[cnt]=sum;\n id_each[cnt++]=id_x;\n }\n }\n int flag=0;\n memset(used,0,sizeof(used));\n r(i,h)r(j,w)if(isdigit(s[i][j])){\n if(used[i][j])continue;\n P x_lr=get_lr(i,j,a);\n vector<int>v=get_data(i,j,a);\n double X=0,L=x_lr.first,R=x_lr.second;\n r(i,v.size())X+=v[i];\n X/=(double)v.size();\n if(!(L-0.5<X&&X<R+0.5))flag++;\n }\n if(!flag)cout<<\"STABLE\"<<endl;\n else cout<<\"UNSTABLE\"<<endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3224, "score_of_the_acc": -0.1286, "final_rank": 12 }, { "submission_id": "aoj_1168_2339697", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n#include <cmath>\n#include <algorithm>\n#include <queue>\n#include <set>\n#include <map>\n\nusing namespace std;\n\nint dx[]={1,-1,0,0};\nint dy[]={0,0,1,-1};\nint w,h;\n\n\nstruct node{\n\tvector<int> next;\n\tvector<pair<int,int> > blocks;\n\tdouble gx;\n\tdouble left;\n\tdouble right;\n\tint num;\n\tdouble weight;\n\tbool fl;\n};\n\nvoid calc(vector<vector<int> > vec,vector<pair<int,int> > piece,map<pair<int,int>,int> mp,node &kubo,vector<node> &nodes){\n\tif(kubo.fl==1)return;\n\tvector<int> interval;\n\tfor(int k=0;k<4;k++){\n\t\tif(piece[k].first<h-1){\n\t\t\tif(vec[piece[k].first][piece[k].second]!=vec[piece[k].first+1][piece[k].second]&&vec[piece[k].first+1][piece[k].second]!=0){\n\t\t\t\tinterval.push_back(piece[k].second);\n\t\t\t}\n\t\t}\n\t}\n\tset<int> st;\n\tvector<int>\tne;\n\tfor(int k=0;k<4;k++){\n\t\tif(piece[k].first>0){\n\t\t\tif(vec[piece[k].first][piece[k].second]!=vec[piece[k].first-1][piece[k].second]&&vec[piece[k].first-1][piece[k].second]!=0){\n\t\t\t\tif(!st.count(mp[make_pair(piece[k].first-1,piece[k].second)])){\n\t\t\t\t\tne.push_back(mp[make_pair(piece[k].first-1,piece[k].second)]);\n\t\t\t\t\tst.insert(mp[make_pair(piece[k].first-1,piece[k].second)]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tkubo.next = ne;\n\tif(interval.size()>0){\n\t\tsort(interval.begin(),interval.end());\n\t}else{\n\t\tfor(int k=0;k<w;k++){\n\t\t\tif(vec[h-1][k]!=0){\n\t\t\t\tinterval.push_back(k);\n\t\t\t}\n\t\t}\n\t\tsort(interval.begin(),interval.end());\n\t}\n\tkubo.left = interval[0]-0.5;\n\tkubo.right = interval[interval.size()-1]+0.5;\n\tdouble sum =0;\n\tdouble sum_w = 0;\n\tif(kubo.next.size()==0){\n\t\tfor(int k=0;k<4;k++){\n\t\t\tsum += (double)piece[k].second;\n\t\t\tsum_w +=1;\n\t\t}\n\t\tkubo.weight = sum_w;\n\t\tkubo.gx = sum/sum_w;\n\t\tkubo.fl = 1;\n\treturn;\n\t}\n\tfor(int k=0;k<kubo.next.size();k++){\n\t\tcalc(vec,nodes[kubo.next[k]].blocks,mp,nodes[kubo.next[k]],nodes);\n\t\tsum += nodes[kubo.next[k]].weight * nodes[kubo.next[k]].gx;\n\t\tsum_w += nodes[kubo.next[k]].weight;\n\t}\n\tfor(int k=0;k<4;k++){\n\t\tsum += (double)piece[k].second;\n\t\tsum_w +=1;\n\t}\n\tkubo.weight = sum_w;\n\tkubo.gx = sum/sum_w;\n\tkubo.fl = 1;\n\treturn;\n}\n\n\n\nint main(){\n\tstring s;\n\twhile(1){\n\t\tcin >> w >> h;\n\t\tif(w==0&&h==0)break;\n\t\tvector<vector<int> > vec;\n\t\tfor(int i=0;i<h;i++){\n\t\t\tcin >> s;\n\t\t\tvector<int> vec1;\n\t\t\tfor(int j=0;j<w;j++){\n\t\t\t\tif(s[j]=='.'){\n\t\t\t\t\tvec1.push_back(0);\n\t\t\t\t}else{\n\t\t\t\t\tvec1.push_back(s[j]-'0');\n\t\t\t\t}\n\t\t\t}\n\t\t\tvec.push_back(vec1);\n\t\t}\n\t\tvector<vector<int> > flag(h,vector<int>(w,0));\n\t\tvector<node> nodes;\n\t\tint node_num = 0;\n\t\tmap<pair<int,int>,int > mp;\n\t\tfor(int i=0;i<h;i++){\n\t\t\tfor(int j=0;j<w;j++){\n\t\t\t\tif(vec[i][j]!=0&&flag[i][j]!=1){\n\t\t\t\t\tvector<pair<int,int> > piece;\n\t\t\t\t\tqueue<pair<int,int> > q;\n\t\t\t\t\tq.push(make_pair(i,j));\n\t\t\t\t\tpiece.push_back(make_pair(i,j));\n\t\t\t\t\tflag[i][j]=1;\n\t\t\t\t\tmp[make_pair(i,j)] = node_num;\n\t\t\t\t\twhile(!q.empty()){\n\t\t\t\t\t\tpair<int,int> p;\n\t\t\t\t\t\tp = q.front();\n\t\t\t\t\t\tq.pop();\n\t\t\t\t\t\tfor(int k=0;k<4;k++){\n\t\t\t\t\t\t\tif(p.first+dx[k]<0||p.first+dx[k]>=h||p.second+dy[k]<0||p.second+dy[k]>=w)continue;\n\t\t\t\t\t\t\tif(flag[p.first+dx[k]][p.second+dy[k]]==0&&vec[p.first+dx[k]][p.second+dy[k]]==vec[p.first][p.second]){\n\t\t\t\t\t\t\t\tq.push(make_pair(p.first+dx[k],p.second+dy[k]));\n\t\t\t\t\t\t\t\tflag[p.first+dx[k]][p.second+dy[k]] = 1;\n\t\t\t\t\t\t\t\tmp[make_pair(p.first+dx[k],p.second+dy[k])] = node_num;\n\t\t\t\t\t\t\t\tpiece.push_back(make_pair(p.first+dx[k],p.second+dy[k]));\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tnode kubo;\n\t\t\t\t\tkubo.blocks = piece;\n\t\t\t\t\tkubo.num = node_num;\n\t\t\t\t\tkubo.fl =0;\n\t\t\t\t\tnodes.push_back(kubo);\n\t\t\t\t\tnode_num +=1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<nodes.size();i++){\n\t\t\tcalc(vec,nodes[i].blocks,mp,nodes[i],nodes);\n\t\t}\n\t\tbool ans = 0;\n\t\tfor(int i=0;i<nodes.size();i++){\n\t\t\tif(nodes[i].gx>=nodes[i].right||nodes[i].gx<=nodes[i].left){\n\t\t\t\tans =1;\n\t\t\t}\n\t\t}\n\t\tif(ans==0)cout << \"STABLE\" << endl;\n\t\telse cout << \"UNSTABLE\" << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3096, "score_of_the_acc": -0.1354, "final_rank": 13 }, { "submission_id": "aoj_1168_1732823", "code_snippet": "#include<cstdio>\n#include<cstdlib>\n#include<cstring>\n#include<cmath>\n//#include<cctype>\n#include<climits>\n#include<iostream>\n#include<string>\n#include<vector>\n#include<map>\n//#include<list>\n#include<queue>\n#include<deque>\n#include<algorithm>\n//#include<numeric>\n#include<utility>\n#include<complex>\n//#include<memory>\n#include<functional>\n#include<cassert>\n#include<set>\n#include<stack>\n#include<random>\n\nconst int dx[] = {1, 0, -1, 0};\nconst int dy[] = {0, 1, 0, -1};\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef vector<int> vi;\ntypedef vector<ll> vll;\ntypedef pair<int, int> pii;\n\nint H, W;\nstring board[100];\n\nvector<pii> getPos(char c, int sy, int sx) {\n vector<pii> ret;\n queue<int> que;\n que.push(sy); que.push(sx);\n ret.emplace_back(sy, sx);\n while (!que.empty()) {\n int y = que.front(); que.pop();\n int x = que.front(); que.pop();\n for (int i = 0; i < 4; i++) {\n int ny = y+dy[i];\n int nx = x+dx[i];\n if (ny < 0 || ny >= H || nx < 0 || nx >= W) continue;\n if (board[ny][nx] == c && find(ret.begin(), ret.end(), pii(ny, nx)) == ret.end()) {\n que.push(ny); que.push(nx);\n ret.emplace_back(ny, nx);\n }\n }\n }\n return ret;\n}\n\nbool ok() {\n for (int y = 0; y < H; y++) for (int x = 0; x < W; x++) {\n // c ?????¢???\n char c = board[y][x];\n if (c == '.') continue;\n vector<pii> ps = getPos(c, y, x);\n int xl = 100, xr = -1;\n for (pii p : ps) {\n int y = p.first, x = p.second;\n if (y == H-1) {\n xl = min(xl, 2*x);\n xr = max(xr, 2*x+2);\n } else {\n int ny = y+1;\n if (board[ny][x] != '.' && board[ny][x] != c) {\n xl = min(xl, 2*x);\n xr = max(xr, 2*x+2);\n }\n }\n }\n // cerr << c << \" : \" << xl << \" \" << xr << endl;\n // ps ????????????????????????????????¢???\n vector<pii> up = ps;\n while (1) {\n bool finish = true;\n for (pii p : up) {\n int y = p.first, x = p.second;\n if (y==0) continue;\n char tmp = board[y-1][x];\n if (tmp == '.') continue;\n vector<pii> cs = getPos(tmp, y-1, x);\n assert(!cs.empty());\n if (find(up.begin(), up.end(), cs[0]) == up.end()) {\n finish = false;\n for (pii pp : cs) up.push_back(pp);\n break;\n }\n }\n if (finish) break;\n }\n int sum = 0;\n for (pii p : up) {\n sum += 2*p.second+1;\n }\n if (sum <= xl * up.size() || sum >= xr * up.size()) return false;\n }\n return true;\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n while (cin >> W >> H) {\n if (H==0 && W==0) break;\n for (int i = 0; i < H; i++) cin >> board[i];\n if (ok()) cout << \"STABLE\" << endl;\n else cout << \"UNSTABLE\" << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 680, "memory_kb": 3152, "score_of_the_acc": -1.124, "final_rank": 19 }, { "submission_id": "aoj_1168_1499203", "code_snippet": "#include<bits/stdc++.h>\n#define eps 1e-8\nusing namespace std;\ntypedef complex<double> point;\nclass piece{\npublic:\n piece(vector<int> x, vector<int> y, int xr_, int xl_, int id_):\n xr(xr_), xl(xl_), id(id_){\n double gx = 0, gy = 0;\n for (int i = 0; i < x.size(); i++) {\n block.push_back(point(x[i], y[i]));\n gx += x[i] + 0.5;\n gy += y[i] + 0.5;\n }\n gravity = point(gx/x.size(), gy/y.size());\n };\n ~piece(){}\n inline void SetSupport(piece p){support.insert(p);}\n void SetRange(vector<string>& grid);\n inline int GetBlockSize(){return block.size();}\n inline point GetBlock(int id_){return block[id_];}\n inline point GetGrabity(){return gravity;}\n inline set<piece> GetSupport(){return support;}\n inline int GetSupportSize(){return support.size();}\n inline int GetId(){return id;}\n bool IsBalance(){\n double x = gravity.real()*block.size();\n int block_sum = block.size();\n for (piece i: support) {\n x += i.GetGrabity().real()*i.GetBlockSize();\n block_sum += i.GetBlockSize();\n }\n x /= block_sum;\n return (xl + eps < x && x < xr - eps + 1);\n }\n\n bool operator<(const piece p)const{\n return id < p.id;\n }\n void PrintPiece(){\n std::cout << \"id:\" << id << std::endl;\n std::cout << \"xr:\" << xr << \" xl:\" << xl << std::endl;\n std::cout << \"gravity:\" << gravity << std::endl;\n for (int i = 0; i < block.size(); i++) {\n std::cout << \"block[\" << i << \"]:\" << block[i] << std::endl;\n }\n for (piece i:support) {\n std::cout << \"support:\" << i.GetId() << std::endl;\n }\n std::cout << std::endl;\n }\n set<piece> support;\nprivate:\n int xr, xl, id;\n point gravity;\n vector<point> block;\n};\nvoid piece::SetRange(vector<string>& grid){\n int h = grid.size();\n for (int i = 0; i < block.size(); i++) {\n int px = block[i].real(), py = block[i].imag();\n if(block[i].imag() == h - 1 ||\n (grid[py + 1][px] != '.' &&\n grid[py + 1][px] != grid[py][px])) {\n xr = max(xr, px);\n xl = min(xl, px);\n }\n }\n}\nvoid SetIndirectSupport(vector<piece>& vp, piece& p){\n if(p.GetSupportSize() == 0)return;\n set<piece> p_support = vp[p.GetId()].support;\n for (piece i: p_support) {\n //std::cout << p.GetId() << std::endl;\n //p.PrintPiece();\n SetIndirectSupport(vp, vp[i.GetId()]);\n //set<piece> i_support = \n for (piece j: vp[i.GetId()].support) {\n p.SetSupport(j);\n }\n }\n}\n\n\nbool range(int x, int y, int w, int h){\n if(0 <= x && x < w &&\n 0 <= y && y < h)return true;\n return false;\n}\n\nint dx[] = {1, 0, -1, 0}, dy[] = {0, 1, 0, -1};\nvoid dfs(vector<string>& grid, vector<int>& x,\n vector<int>& y, int px, int py, char c){\n int w = grid[0].size(), h = grid.size();\n x.push_back(px);\n y.push_back(py);\n grid[py][px] = '.';\n for (int i = 0; i < 4; i++) {\n if(!range(px + dx[i], py + dy[i], w, h))continue;\n if(grid[py + dy[i]][px + dx[i]] == c){\n dfs(grid, x, y, px + dx[i], py + dy[i], c);\n }\n }\n}\n\nvoid printGrid(vector<string>& grid){\n for (int i = 0; i < grid.size(); i++) {\n std::cout << grid[i] << std::endl;\n }\n std::cout << std::endl;\n}\n\nbool IsSupport(vector<string>& grid, point b){\n if(b.imag() > 0 &&\n grid[b.imag() - 1][b.real()] != '.' &&\n grid[b.imag() - 1][b.real()] != grid[b.imag()][b.real()])\n return true;\n return false;\n}\n \n\nint main(int argc, char *argv[]){\n int w, h;\n while(std::cin >> w >> h, w){\n vector<string> grid(h);\n for (int i = 0; i < h; i++) {\n std::cin >> grid[i];\n }\n vector<piece> p;\n int cnt = 0;\n for (int i = h - 1; i >= 0; i--) {\n for (int j = 0; j < w; j++) {\n if(grid[i][j] != '.'){\n vector<int> x, y;\n int xr, xl;\n dfs(grid, x, y, j, i, grid[i][j]);\n p.push_back(piece(x, y, 0, 1e9, cnt));\n cnt++;\n }\n }\n \n }\n for (int i = 0; i < p.size(); i++) {\n for (int j = 0; j < p[i].GetBlockSize(); j++) {\n point b = p[i].GetBlock(j);\n grid[(int)b.imag()][(int)b.real()] = '0' + p[i].GetId();\n }\n }\n for (int i = 0; i < p.size(); i++) {\n p[i].SetRange(grid);\n }\n for (int i = 0; i < p.size(); i++) {\n for (int j = 0; j < p[i].GetBlockSize(); j++) {\n point b = p[i].GetBlock(j);\n if(IsSupport(grid, b)){\n int id = grid[b.imag() - 1][b.real()] - '0';\n p[i].SetSupport(p[id]);\n }\n }\n }\n SetIndirectSupport(p, p[0]);\n //std::cout << w << \" \" << h << std::endl;\n for (int i = 0; i < p.size(); i++) {\n //p[i].PrintPiece();\n if(!p[i].IsBalance()){\n std::cout << \"UNSTABLE\" << std::endl;\n break;\n }else if(i == p.size() - 1){\n std::cout << \"STABLE\" << std::endl;\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1448, "score_of_the_acc": -0.0155, "final_rank": 7 }, { "submission_id": "aoj_1168_1424274", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n#include <utility>\n#include <algorithm>\n\nusing namespace std;\n#define MP make_pair\ntypedef pair<int,int> PII;\n\nint W, H;\n\n\nvoid findconnected(int x, int y, vector<string>& vs, vector<vector<bool>>& vis, int n, vector<PII>& res){\n if(x < 0 || W <= x || y < 0 || H <= y || vis[y][x] || vs[y][x] != n) return;\n res.push_back(MP(x,y));\n vis[y][x] = true;\n findconnected(x-1,y,vs,vis,n,res);\n findconnected(x+1,y,vs,vis,n,res);\n findconnected(x,y-1,vs,vis,n,res);\n findconnected(x,y+1,vs,vis,n,res);\n}\n\nvoid findOn(int x, int y, vector<string>& vs, vector<vector<bool>>& vis, vector<PII>& res){\n /*\n if(vis[y][x]) return;\n vis[y][x] = true;\n */\n if(y == 0 || vs[y-1][x] == '.' || vs[y][x] == vs[y-1][x]) return;\n vector<PII> tmp;\n findconnected(x,y-1,vs,vis,vs[y-1][x],tmp);\n for(PII& pii:tmp){\n\tfindOn(pii.first,pii.second,vs,vis,res);\n\tres.push_back(pii);\n }\n}\n\nint main(){\n while(cin>>W>>H,W){\n\tvector<string> vs(H);\n\tfor(int i=0;i<H;++i) cin >> vs[i];\n\n\tbool ans = true;\n\tvector<vector<bool>> ok(H,vector<bool>(W, false));\n\tfor(int y=H-1;y>=0;--y){\n\t for(int x=0;x<W;++x){\n\t\tif(vs[y][x] == '.' || ok[y][x]){\n\t\t ok[y][x] = true;\n\t\t continue;\n\t\t}\n\t\tvector<PII> pos, ons;\n\t\tfindconnected(x,y,vs,ok,vs[y][x],pos);\n\t\tvector<vector<bool>> use = ok;\n\t\tint sum = 0;\n\t\tdouble xl = 10000, xr = -1;\n\t\tfor(PII pii:pos){\n\t\t if(pii.second == H-1 || \n\t\t\t vs[pii.second+1][pii.first] != '.' && vs[pii.second][pii.first] != vs[pii.second+1][pii.first])\n\t\t\txl = min(xl, 1.*pii.first), xr = max(xr, 1.*pii.first);\n\t\t findOn(pii.first,pii.second,vs,use,ons);\n\t\t sum += pii.first;\n\t\t}\n\t\t\n\t\tfor(PII& p: ons) sum += p.first;\n\t\tdouble c = sum * 1. / (pos.size() + ons.size());\n\t\txl -= 0.5, xr += 0.5;\n\t\tif(c <= xl || xr <= c){\n\t\t ans = false;// cout << c<<\",\"<<x << \",\" <<y << endl;\n\t\t}\n\t }\n\t}\n\t\n\tcout << (ans? \"STABLE\": \"UNSTABLE\") << endl;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1228, "score_of_the_acc": -0.0165, "final_rank": 8 }, { "submission_id": "aoj_1168_1394198", "code_snippet": "#include <cstring>\n#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <utility>\nusing namespace std;\n\n/*\nstruct UnionFind {\n\tvector<int> data;\n\tUnionFind(int v) : data(v, -1) { }\n\tint root(int x) {\n\t\treturn data[x] < 0 ? x : (data[x] = root(data[x]));\n\t}\n\tbool same(int x, int y) {\n\t\treturn root(x) == root(y);\n\t}\n\tint size(int x) {\n\t\treturn -data[root(x)];\n\t}\n\tvoid merge(int x, int y) {\n\t\tx = root(x), y = root(y);\n\t\tif(x != y) {\n\t\t\tif(size(y) > size(x)) swap(x, y);\n\t\t\tdata[x] += data[y]; data[y] = x;\n\t\t}\n\t}\n};\n*/\n\nconst int INF = (int)1e9;\n\nint W, H; \nchar B[60][11];\nint Bid[60][10];\nvector<int> down;\nint num;\n\nvoid dfs(int i, int j, int num) {\n\tfor(int d = 0; d < 4; ++d) {\n\t\tconst int dy[4] = { 0, 1, 0, -1 };\n\t\tconst int dx[4] = { 1, 0, -1, 0 };\n\t\tint ny = i + dy[d];\n\t\tint nx = j + dx[d];\n\t\tif(0 <= ny && ny < H && 0 <= nx && nx < W && B[ny][nx] != '.' && B[i][j] == B[ny][nx] && Bid[ny][nx] == -1) {\n\t\t\tBid[ny][nx] = num;\n\t\t\tdfs(ny, nx, num);\n\t\t}\n\t}\n}\n\npair<int, int> ground(int id) {\n\tint L = INF, R = -INF;\n\tfor(int i = 0; i < H; ++i) {\n\t\tfor(int j = 0; j < W; ++j) {\n\t\t\tif(Bid[i][j] == id && ((i > 0 && Bid[i - 1][j] != -1 && Bid[i][j] != Bid[i - 1][j]) || (i == 0))) {\n\t\t\t\tL = min(L, j);\n\t\t\t\tR = max(R, j);\n\t\t\t}\n\t\t}\n\t}\n\treturn make_pair(L, R + 1);\n}\n\ndouble gravity(int id) {\n\tvector<int> sum(W, 0);\n\tqueue<int> Q;\n\tQ.push(id);\n\twhile(!Q.empty()) {\n\t\tint nextId = Q.front(); Q.pop();\n\t\tfor(int i = 0; i < H; ++i) {\n\t\t\tfor(int j = 0; j < W; ++j) {\n\t\t\t\tif(Bid[i][j] == nextId) sum[j]++;\n\t\t\t}\n\t\t}\n\t\tfor(int k = 0; k < num; ++k) {\n\t\t\tif(down[k] == nextId) Q.push(k);\n\t\t}\n\t}\n\tdouble S = 0;\n\tint c = 0;\n\tfor(int j = 0; j < W; ++j) {\n\t\tS += j * sum[j];\n\t\tc += sum[j];\n\t}\n\treturn S / c + 0.5;\n}\n\nint main() {\n\tios::sync_with_stdio(false);\n\twhile(true) {\n\t\tcin >> W >> H;\n\t\tif(W == 0 && H == 0) break;\n\t\tfor(int i = H - 1; i >= 0; --i) {\n\t\t\tcin >> B[i];\n\t\t}\n\t\tmemset(Bid, -1, sizeof(Bid));\n\t\tnum = 0;\n\t\tfor(int i = 0; i < H; ++i) {\n\t\t\tfor(int j = 0; j < W; ++j) {\n\t\t\t\tif(B[i][j] != '.' && Bid[i][j] == -1) {\n\t\t\t\t\tBid[i][j] = num;\n\t\t\t\t\tdfs(i, j, num);\n\t\t\t\t\t++num;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\n\t\t#if 0\n\t\tfor(int i = H - 1; i >= 0; --i) {\n\t\t\tfor(int j = 0; j < W; ++j) {\n\t\t\t\tif(Bid[i][j] == -1) cout << '.';\n\t\t\t\telse cout << Bid[i][j];\n\t\t\t}\n\t\t\tcout << endl;\n\t\t}\n\t\t#endif\n\t\t\n\t\tdown.assign(num, -2);\n\t\tfor(int id = 0; id < num; ++id) {\n\t\t\tfor(int i = 0; i < H; ++i) {\n\t\t\t\tfor(int j = 0; j < W; ++j) {\n\t\t\t\t\tif(Bid[i][j] == id && ((i > 0 && Bid[i - 1][j] != -1 && Bid[i][j] != Bid[i - 1][j]) || (i == 0))) {\n\t\t\t\t\t\tif(i == 0) down[id] = -1;\n\t\t\t\t\t\telse down[id] = Bid[i - 1][j];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t\t// cout << \"down[\" << id << \"] = \" << down[id] << endl;\n\t\t}\n\t\t\n\t\tbool ok = true;\n\t\tfor(int id = 0; id < num; ++id) {\n\t\t\tdouble gr = gravity(id);\n\t\t\t// cout << \"gravity(\" << id << \") = \" << gravity(id) << endl;\n\t\t\tauto ret = ground(id);\n\t\t\t// cout << \"L = \" << ret.first << \", R = \" << ret.second << endl;\n\t\t\tif(gr <= ret.first || ret.second <= gr) ok = false;\n\t\t}\n\t\tcout << (ok ? \"STABLE\":\"UNSTABLE\") << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1204, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1168_1339220", "code_snippet": "#include<cstdio>\n#include<string>\n#include<cstring>\n#include<iostream>\n#include<algorithm>\n\nusing namespace std;\nint w,h;\nint p[15][80];\nint flag[15][80];\nint sx,nid;\ndouble x_ave[200];\nint dx_min[200],dx_max[200];\nint edge[200][200];\nint dx[4]={0,1,-1,0};\nint dy[4]={1,0,0,-1};\n\nvoid dfs(int x,int y,int id){\n\tif(flag[x][y])return;\n\tflag[x][y]=1;\n\tx_ave[id]+=(double)x+0.5;\n\tif(y==0 || (y>0 && p[x][y-1]>=1 && p[x][y-1]!=p[x][y])){\n\t\tdx_min[id]=min(dx_min[id],x);\n\t\tdx_max[id]=max(dx_max[id],x);\n\t}\n\tfor(int i=0;i<4;i++){\n\t\tint nx=x+dx[i],ny=y+dy[i];\n\t\tif(nx<0 || nx>=w || ny<0 || ny>=h)continue;\n\t\tif(p[x][y]==p[nx][ny])dfs(nx,ny,id);\n\t}\n\tfor(int i=0;i<1;i++){\n\t\tint nx=x+dx[i],ny=y+dy[i];\n\t\tif(nx<0 || nx>=w || ny<0 || ny>=h)continue;\n\t\tif(p[x][y]!=p[nx][ny] && flag[nx][ny]==0 && p[nx][ny]>=1){\n\t\t\tnid++;\n\t\t\tedge[id][nid]=1;\n\t\t\tdfs(nx,ny,nid);\n\t\t}\n\t}\n}\n\nint main(void){\n\twhile(1){\n\t\tscanf(\"%d %d\",&w,&h);\n\t\tif(w+h==0)break;\n\t\tnid=0;\n\t\tmemset(p,0,sizeof(p));\n\t\tmemset(flag,0,sizeof(flag));\n\t\tfor(int i=0;i<200;i++)dx_min[i]=114;\n\t\tmemset(dx_max,0,sizeof(dx_max));\n\t\tmemset(x_ave,0,sizeof(x_ave));\n\t\tmemset(edge,0,sizeof(edge));\n\t\tfor(int i=h-1;i>=0;i--){\n\t\t\tstring str;\n\t\t\tcin >> str;\n\t\t\tfor(int j=0;j<w;j++){\n\t\t\t\tif(str[j]=='.')p[j][i]=0;\n\t\t\t\telse{\n\t\t\t\t\tp[j][i]=str[j]-'0';\n\t\t\t\t\tif(i==0)sx=j;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tdfs(sx,0,0);\n\t\tfor(int k=0;k<=nid;k++){\n\t\t\tfor(int i=0;i<=nid;i++){\n\t\t\t\tfor(int j=0;j<=nid;j++){\n\t\t\t\t\tedge[i][j]=max(edge[i][j],edge[i][k]&edge[k][j]);\n\t\t\t\t}\n\t\t\t\tedge[i][i]=1;\n\t\t\t}\n\t\t}\n\t\tbool st=true;\n\t\tfor(int i=0;i<=nid;i++){\n\t\t\tdouble all=0.0,cnt=0.0;\n\t\t\tfor(int j=0;j<=nid;j++){\n\t\t\t\tif(edge[i][j])cnt+=1.0,all+=x_ave[j]/4.0;\n\t\t\t}\n\t\t\tall/=cnt;\n\t\t\tif(all<=(double)dx_min[i] || all>=(double)(dx_max[i]+1.0))st=false;\n\t\t}\n\t\tprintf(\"%s\\n\",st?\"STABLE\":\"UNSTABLE\");\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1388, "score_of_the_acc": -0.0117, "final_rank": 6 }, { "submission_id": "aoj_1168_1006486", "code_snippet": "#include <iostream>\n#include <complex>\n#include <sstream>\n#include <string>\n#include <algorithm>\n#include <deque>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <vector>\n#include <set>\n#include <limits>\n#include <cstdio>\n#include <cctype>\n#include <cmath>\n#include <cstring>\n#include <cstdlib>\n#include <ctime>\nusing namespace std;\n#define REP(i, j) for(int i = 0; i < (int)(j); ++i)\n#define FOR(i, j, k) for(int i = (int)(j); i < (int)(k); ++i)\n#define P pair<int, int>\n#define SORT(v) sort((v).begin(), (v).end())\n#define REVERSE(v) reverse((v).begin(), (v).end())\nconst int MAX_N = 61;\n\nint my[] = {-1, 1, 0, 0};\nint mx[] = {0, 0, 1, -1};\n\nclass C{\n public: \n int cnt, sum, parent;\n double p_xl, p_xr;\n vector<P> cs;\n C(int _p, vector<P> _cs, double _p_xl, double _p_xr){\n parent = _p;\n cs = _cs;\n cnt = (int)(cs.size());\n sum = 0;\n REP(i, cs.size()){\n sum += cs[i].second;\n }\n p_xl = _p_xl;\n p_xr = _p_xr;\n }\n C(){};\n};\n\nint W, H;\nstring f[MAX_N];\nvector<C> blocks;\nvector< set<int> > children;\n\nvoid find_block(int y, int x, char c, vector<P> &v){\n f[y][x] = '.';\n v.push_back(P(y, x));\n REP(i, 4){\n int ny = y + my[i], nx = x + mx[i];\n if(ny >= 0 && nx >= 0 && ny < H && nx < W && f[ny][nx] == c)\n find_block(ny, nx, c, v);\n }\n}\n\nint find_parent(int now){\n int ret = -1;\n vector<P> cs;\n REP(i, blocks.size()){\n if(i == now) continue;\n REP(j, blocks[now].cs.size()){\n REP(k, blocks[i].cs.size()){\n int now_y = blocks[now].cs[j].first;\n int now_x = blocks[now].cs[j].second;\n int block_y = blocks[i].cs[k].first;\n int block_x = blocks[i].cs[k].second;\n if(now_x == block_x && now_y + 1 == block_y){\n ret = i;\n cs.push_back(P(block_y, block_x));\n //blocks[now].p_xl = 100.0;\n //blocks[now].p_xr = -1.0;\n //REP(j, blocks[i].cs.size()){\n //TODO: 以下のif文で本当に合ってる?\n //if(blocks[i].cs[j].first == block_y){\n // blocks[now].p_xl = min(blocks[now].p_xl, (double)blocks[i].cs[j].second - 0.5);\n // blocks[now].p_xr = max(blocks[now].p_xr, (double)blocks[i].cs[j].second + 0.5);\n //}\n //}\n //return i;\n }\n }\n }\n }\n if(ret != -1){\n double xl = 100, xr = -1;\n REP(i, cs.size()){\n xl = min(xl, cs[i].second - 0.5);\n xr = max(xr, cs[i].second + 0.5);\n }\n blocks[now].p_xl = xl;\n blocks[now].p_xr = xr;\n }\n return ret;\n //return -1;\n}\n\nvoid find_children(int now, set<int> &c){\n REP(i, blocks.size()){\n if(blocks[i].parent == now && c.find(i) == c.end()){\n c.insert(i);\n find_children(i, c);\n }\n }\n}\n\nbool is_valid_tree(int now){\n int a = blocks[now].sum, b = blocks[now].cnt;\n for(set<int>::iterator it = children[now].begin(); it != children[now].end(); ++it){\n C block = blocks[(*it)];\n a += block.sum;\n b += block.cnt;\n }\n double m = (double)a / b;\n //cout <<now <<\" : \" <<blocks[now].p_xl <<\", \" <<m <<\", \" <<blocks[now].p_xr <<endl;\n return (m > blocks[now].p_xl && m < blocks[now].p_xr ? true : false);\n}\n\nint main() {\n while(cin >>W >>H && H){\n blocks.clear();\n REP(i, H) cin >>f[i];\n REP(i, W){\n if(isdigit(f[H - 1][i])){\n vector<P> cs;\n find_block(H - 1, i, f[H - 1][i], cs);\n double xl = 100, xr = -1;\n REP(k, cs.size()){\n if(cs[k].first == H - 1){\n xl = min(xl, cs[k].second - 0.5);\n xr = max(xl, cs[k].second + 0.5);\n }\n }\n C tmp = C(-1, cs, xl, xr);\n blocks.push_back(tmp);\n }\n }\n //REP(i, blocks[0].cs.size()) cout <<blocks[0].cs[i].first <<\", \" <<blocks[0].cs[i].second <<\", \" <<blocks[0].p_xl <<\", \" <<blocks[0].p_xr <<endl;\n for(int i = H - 1; i >= 0; --i){\n for(int j = W - 1; j >= 0; --j){\n if(isdigit(f[i][j])){\n vector<P> cs;\n find_block(i, j, f[i][j], cs);\n blocks.push_back(C(-1, cs, -1, 100));\n }\n }\n }\n FOR(i, 1, blocks.size())\n blocks[i].parent = find_parent(i);\n //REP(i, blocks.size()){\n // cout <<i <<\" : \" <<endl;\n // cout <<\"parent = \" <<blocks[i].parent <<\", xl = \" <<blocks[i].p_xl <<\", xr = \" <<blocks[i].p_xr <<endl;\n // REP(j, blocks[i].cs.size()) cout <<blocks[i].cs[j].first <<\", \" <<blocks[i].cs[j].second <<\" | \";\n // cout <<endl;\n //}\n children = vector< set<int> >((int)(blocks.size()));\n FOR(i, 1, blocks.size()) children[0].insert(i);\n FOR(i, 1, blocks.size()) find_children(i, children[i]);\n //REP(i, blocks.size()){\n // cout <<i <<\" : \";\n // for(set<int>::iterator it = children[i].begin(); it != children[i].end(); ++it) cout <<(*it) <<\", \";\n // cout <<endl;\n //}\n bool isok = true;\n REP(i, blocks.size()){\n if(!is_valid_tree(i)){\n isok = false;\n break;\n }\n }\n cout <<(isok ? \"STABLE\" : \"UNSTABLE\") <<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1264, "score_of_the_acc": -0.0038, "final_rank": 4 }, { "submission_id": "aoj_1168_892409", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n#include <cstdio>\n#include <iostream>\n#include <sstream>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <queue>\n#include <stack>\n#include <limits>\n#include <map>\n#include <string>\n#include <cstring>\n#include <set>\n#include <deque>\n#include <bitset>\n#include <list>\n#include <cctype>\n#include <utility>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair <int,int> P;\ntypedef pair <int,P > PP;\n \nint tx[] = {0,1,0,-1};\nint ty[] = {-1,0,1,0};\n \nstatic const double EPS = 1e-8;\n\ntemplate <class T> class Point{\nprivate:\n T x;\n T y;\npublic:\n Point(T _x,T _y):x(_x),y(_y){}\n Point():x(0),y(0){}\n T getX() const{\n return x;\n }\n T getY() const{\n return y;\n }\n\n Point operator-(const Point &p) const{\n return Point(x - p.x, y - p.y);\n }\n Point operator+(const Point &p) const{\n return Point(x + p.x, y + p.y);\n }\n Point operator+(const double num) const{\n return Point(x + num, y + num);\n }\n void operator+=(const Point &p){\n x += p.x;\n y += p.y;\n }\n Point operator/(const T div) const{\n return Point(x / div, y / div);\n }\n void operator/=(const T div){\n x /= div;\n y /= div;\n }\n};\n\nclass Block{\nprivate:\n vector<Point<double> > cells;\n Point<double> center_of_gravity;\n set<int> children;\n double left,right;\n void _compute_center_of_gravity(){\n Point<double> tmp;\n for(int i=0;i<cells.size();i++){\n tmp += (cells[i] + 0.5);\n }\n if(cells.size() > 0){\n tmp /= cells.size();\n }\n center_of_gravity = tmp;\n }\npublic:\n Block(const vector<Point<double> >& _cells){\n left = 1000.0;\n right = -1.0;\n cells = _cells;\n _compute_center_of_gravity();\n }\n Point<double> get_center_of_gravity() const{\n return center_of_gravity;\n }\n const vector<Point<double> >& get_cells() const{\n return cells;\n }\n void add_child(int child){\n children.insert(child);\n }\n const set<int>& get_children() const{\n return children;\n }\n double get_left() const{\n return left;\n }\n void set_left(double _left){\n left = min(left,_left);\n }\n double get_right() const{\n return right;\n }\n void set_right(double _right){\n right = max(right,_right);\n }\n};\n\n\nvoid dfs(char stage[60][10],bool visited[60][10],\n\t char root,int sx,int sy,vector<Point<double> >& cells,int W,int H){\n visited[sy][sx] = true;\n cells.push_back(Point<double>(sx,sy));\n for(int i=0;i<4;i++){\n int dx = sx + tx[i];\n int dy = sy + ty[i];\n if(dx < 0 || dy < 0 || dx >= W || dy >= H) continue;\n if(stage[dy][dx] != root) continue;\n if(visited[dy][dx]) continue;\n dfs(stage,visited,root,dx,dy,cells,W,H);\n }\n}\n\nvector<Block> make_blocks(char stage[60][10],int W,int H){\n bool visited[60][10];\n memset(visited,false,sizeof(visited));\n\n vector<Block> blocks;\n for(int y=0;y<H;y++){\n for(int x=0;x<W;x++){\n if(visited[y][x]) continue;\n if(0 <= stage[y][x]-'0'\n\t && stage[y][x]-'0' <= 9){\n\tvector<Point<double> > cells;\n\tdfs(stage,visited,stage[y][x],x,y,cells,W,H);\n\tBlock block(cells);\n\tblocks.push_back(block);\n }\n }\n }\n return blocks;\n}\n\nvoid make_children(vector<Block>& blocks,int W,int H){\n for(int parent_block_idx = 0; parent_block_idx < blocks.size(); parent_block_idx++){\n for(int child_block_idx = 0; child_block_idx < blocks.size(); child_block_idx++){\n if(parent_block_idx == child_block_idx) continue;\n for(int parent_cell_idx = 0;parent_cell_idx < blocks[parent_block_idx].get_cells().size();parent_cell_idx++){\n\tdouble parent_y = blocks[parent_block_idx].get_cells()[parent_cell_idx].getY();\n\tdouble parent_x = blocks[parent_block_idx].get_cells()[parent_cell_idx].getX();\n\n\tif(abs((parent_y + 1.0) - (double)H) < EPS){\n\t blocks[parent_block_idx].set_left(parent_x);\n\t blocks[parent_block_idx].set_right(parent_x + 1.0);\n\t}\n\n\tfor(int child_cell_idx = 0;child_cell_idx < blocks[child_block_idx].get_cells().size();child_cell_idx++){\n\t double child_y = blocks[child_block_idx].get_cells()[child_cell_idx].getY() + 1.0;\n\t double child_x = blocks[child_block_idx].get_cells()[child_cell_idx].getX();\n\t \n\t if(abs(parent_x - child_x) < EPS \n\t && abs(parent_y - child_y) < EPS){\n\t blocks[child_block_idx].set_left(child_x);\n\t blocks[child_block_idx].set_right(child_x+1.0);\n\t blocks[parent_block_idx].add_child(child_block_idx);\n\t }\n\t}\n }\n }\n }\n}\n\nbool check_balance(const vector<Block>& blocks){\n for(int parent_block_idx = 0; parent_block_idx < blocks.size(); parent_block_idx++){\n bool visited[1001];\n memset(visited,false,sizeof(visited));\n\n Point<double> center_of_gravity;\n int count = 0;\n\n queue<int> que;\n que.push(parent_block_idx);\n while(!que.empty()){\n int parent = que.front();\n\n if(visited[parent]) continue;\n visited[parent] = true;\n\n center_of_gravity += blocks[parent].get_center_of_gravity();\n count++;\n que.pop();\n for(set<int>::iterator it = blocks[parent].get_children().begin();\n\t it != blocks[parent].get_children().end();\n\t it++){\n\tque.push(*it);\n }\n }\n\n if(count > 0){\n center_of_gravity /= (double)count;\n if(blocks[parent_block_idx].get_left() + EPS >= center_of_gravity.getX()\n\t || center_of_gravity.getX() >= blocks[parent_block_idx].get_right() - EPS){\n\treturn false;\n }\n }\n }\n return true;\n}\n\nint main(){\n int W,H;\n while(~scanf(\"%d %d\",&W,&H)){\n if(W==0 && H==0) break;\n\n char stage[60][10];\n for(int y=0;y<H;y++){\n string line;\n cin >> line;\n for(int x=0;x<W;x++){\n\tstage[y][x] = line[x];\n }\n }\n\n vector<Block> blocks = make_blocks(stage,W,H);\n make_children(blocks,W,H);\n printf(\"%s\\n\",check_balance(blocks) ? \"STABLE\" : \"UNSTABLE\");\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1236, "score_of_the_acc": -0.002, "final_rank": 3 }, { "submission_id": "aoj_1168_715356", "code_snippet": "#include <vector>\n#include <list>\n#include <map>\n#include <set>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <algorithm>\n#include <utility>\n#include <functional>\n#include <sstream>\n#include <iostream>\n#include <cstdio>\n#include <cmath>\n#include <cstdlib>\n#include <cctype>\n#include <string>\n#include <cstring>\n#include <ctime>\n#include <climits>\n#include <cassert>\nusing namespace std;\ninline int toInt(string s) {int v; istringstream sin(s);sin>>v;return v;}\ntemplate<class T> inline string toString(T x) {ostringstream sout;sout<<x;return sout.str();}\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<string> vs;\ntypedef pair<int, int> pii;\ntypedef long long ll;\n#define ALL(a) (a).begin(),(a).end()\n#define RALL(a) (a).rbegin(),(a).rend()\n#define EXIST(s,e) ((s).find(e)!=(s).end())\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) FOR(i,0,n)\nconst double EPS = 1e-9;\nconst double PI = acos(-1.0);\n\nint w,h;\n\nstruct piece{\n\tset<pii> blocks;\n\tvector<piece*> children;\n\tint lx,rx;\n\tpiece(set<pii> blocks):blocks(blocks),lx(-1),rx(-1){}\n\n\tvoid construct_tree(vector<piece> &pieces,int index){\n\t\tREP(i,pieces.size()){\n\t\t\tif(i==index)continue;\n\t\t\tbool ischild=false;\n\t\t\tfor(set<pii>::iterator mb=blocks.begin();mb!=blocks.end();mb++){\n\t\t\t\tfor(set<pii>::iterator ob=pieces[i].blocks.begin();ob!=pieces[i].blocks.end();ob++){\n\t\t\t\t\tif(mb->first==ob->first+1&&mb->second==ob->second){\n\t\t\t\t\t\tischild=true;\n\t\t\t\t\t\tgoto found;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tfound:\n\t\t\tif(ischild){\n\t\t\t\tchildren.push_back(&(pieces[i]));\n\t\t\t}\n\t\t}\n\t}\n\n\tvoid set_x(){\n\t\tREP(i,children.size()){\n\t\t\tchildren[i]->lx=INT_MAX,children[i]->rx=INT_MIN;\n\t\t\tfor(set<pii>::iterator it=children[i]->blocks.begin();it!=children[i]->blocks.end();it++){\n\t\t\t\tif(EXIST(blocks,make_pair(it->first+1,it->second))){\n\t\t\t\t\tchildren[i]->lx=min(children[i]->lx,it->second);\n\t\t\t\t\tchildren[i]->rx=max(children[i]->rx,it->second+1);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint get_weight_pos(){\n\t\tint ret=0;\n\t\tfor(set<pii>::iterator it=blocks.begin();it!=blocks.end();it++){\n\t\t\tret+=it->second;\n\t\t}\n\t\tREP(i,children.size()){\n\t\t\tret+=children[i]->get_weight_pos();\n\t\t}\n\t\treturn ret;\n\t}\n\n\tint get_total_pieces(){\n\t\tint ret=4;\n\t\tREP(i,children.size()){\n\t\t\tret+=children[i]->get_total_pieces();\n\t\t}\n\t\treturn ret;\n\t}\n\n\tdouble get_center(){\n\t\treturn (double)get_weight_pos()/get_total_pieces()+0.5;\n\t}\n\n\tbool ok(){\n\t\tdouble center=get_center();\n\t\treturn lx+EPS<center&&center<rx-EPS;\n\t}\n};\n\nint dx[]={-1,0,1,0},dy[]={0,-1,0,1};\npiece construct_piece(vs &pp,int y,int x,vvi &used){\n\tchar c=pp[y][x];\n\tset<pii> blocks;\n\tqueue<pii> q;\n\tq.push(make_pair(y,x));\n\twhile(!q.empty()){\n\t\tpii p=q.front();q.pop();\n\t\tREP(d,4){\n\t\t\tint y=p.first+dy[d];\n\t\t\tint x=p.second+dx[d];\n\t\t\tpii block=make_pair(y,x);\n\t\t\tif(y>=0&&x>=0&&y<h&&x<w&&pp[y][x]==c&&!EXIST(blocks,block)){\n\t\t\t\tblocks.insert(block);\n\t\t\t\tq.push(block);\n\t\t\t\tused[y][x]=1;\n\t\t\t}\n\t\t}\n\t}\n\treturn piece(blocks);\n}\n\nint main(){\n\twhile(cin>>w>>h,w|h){\n\t\tvs p(h);\n\t\tREP(i,h){\n\t\t\tcin>>p[i];\n\t\t}\n\t\tvector<piece> pieces;\n\t\tvvi used(h,vi(w));\n\t\tREP(i,h){\n\t\t\tREP(j,w){\n\t\t\t\tif(p[i][j]!='.'&&!used[i][j]){\n\t\t\t\t\tpieces.push_back(construct_piece(p,i,j,used));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tREP(i,pieces.size()){\n\t\t\tpieces[i].construct_tree(pieces,i);\n\t\t}\n\t\tREP(i,pieces.size()){\n\t\t\tpieces[i].set_x();\n\t\t}\n\t\tREP(i,pieces.size()){\n\t\t\tif(pieces[i].lx==-1){\n\t\t\t\tint lx=INT_MAX,rx=INT_MIN;\n\t\t\t\tfor(set<pii>::iterator it=pieces[i].blocks.begin();it!=pieces[i].blocks.end();it++){\n\t\t\t\t\tif(it->first==h-1){\n\t\t\t\t\t\tlx=min(lx,it->second);\n\t\t\t\t\t\trx=max(rx,it->second+1);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tpieces[i].lx=lx;\n\t\t\t\tpieces[i].rx=rx;\n\t\t\t}\n\t\t}\n\t\tbool ok=true;\n\t\tREP(i,pieces.size()){\n\t\t\tif(!pieces[i].ok()){\n\t\t\t\tok=false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tcout<<(ok?\"STABLE\":\"UNSTABLE\")<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1264, "score_of_the_acc": -0.0038, "final_rank": 4 }, { "submission_id": "aoj_1168_703961", "code_snippet": "#include <cstring>\n#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <vector>\n#include <map>\n#include <set>\n#include <complex>\n#include <queue>\n#include <stack>\n#include <string>\n#include <cmath>\n#include <bitset>\n\n#define rep(i,a) for(int i = 0;i < (a); i++)\n#define repi(i,a,b) for(int i = (a); i < (b); i++)\n#define repd(i,a,b) for(int i = (a); i >= (b); i--)\n#define repit(i,a) for(__typeof((a).begin()) i = (a).begin(); i != (a).end(); i++)\n#define all(u) (u).begin(),(u).end()\n#define rall(u) (u).rbegin(),(u).rend()\n#define UNIQUE(u) (u).erase(unique(all(u)),(u).end())\n#define pb push_back\n#define mp make_pair\n#define INF 1e9\n#define EPS 1e-10\n#define PI acos(-1.0)\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef vector<int> vi;\n\nint w, h;\n\nint dj[] = {-1,0,1,0};\nint di[] = {0,1,0,-1};\n\nvector<string> ori;\nvector<string> museum;\nvector<int> cnt;\nvector<vector<bool> > flag;\n\nint bottom;\nint xl, xr;\n\nvoid dfs(int i, int j, char c){\n museum[i][j] = 'A';\n if((i+1<h && museum[i+1][j] != '.' && museum[i+1][j] != c && museum[i+1][j] != 'A') || i==h-1){\n xl = min(xl, j);\n xr = max(xr, j);\n // cout << xl << ' ' << xr << ' ' << i << ' ' << j <<endl;\n }\n rep(a,4){\n int ti = i + di[a];\n int tj = j + dj[a];\n\n if(ti>=0 && ti<h && tj>=0 && tj<w && museum[ti][tj]==c) dfs(i+di[a],j+dj[a],c);\n }\n}\n\nvoid centerg(int i, int j){\n cnt[j]++;\n flag[i][j] = true;\n rep(a,4){\n int ti = i + di[a];\n int tj = j + dj[a];\n if(ti<0 || ti>=h || tj<0 || tj>=w) continue;\n if(a!=3 && ori[ti][tj] != ori[i][j]) continue;\n if(!flag[ti][tj] && museum[ti][tj]=='A') centerg(i+di[a],j+dj[a]);\n }\n}\n\n\nbool ison(int i, int j, char c){\n flag[i][j] = true;\n if(i > 0 && museum[i-1][j] != 'A' && museum[i-1][j] != '.' && museum[i-1][j] != c) return true;\n rep(a,4){\n int ti = i + di[a];\n int tj = j + dj[a];\n if(ti >= 0 && ti < h && tj >= 0 && tj < w &&\n !flag[ti][tj] && museum[ti][tj] == c){\n if(ison(ti,tj,c)) return true;\n }\n }\n return false;\n}\n\nint main(){\n while(cin>>w>>h,w||h){\n museum.clear();\n museum.resize(h);\n cnt.clear();\n cnt.resize(w);\n xl = 0;\n xr = 0;\n rep(i,h) cin >> museum[i];\n ori = museum;\n /*\n rep(i,h) rep(j,w) if(museum[i][j] != '.'){\n dfs(i,j,museum[i][j]);\n goto soto;\n }\n soto:;\n */\n bool ok = true;\n bool mada = true;\n while(mada){\n mada = false;\n rep(i,h){\n rep(j,w){\n //cout << i << ' ' << j << endl;\n bottom = -1;\n if(museum[i][j]!='.' && museum[i][j]!='A'){\n flag.resize(h);\n rep(k,h) flag[k] = vector<bool>(w,false);\n if(ison(i,j,museum[i][j])){\n mada = true;\n flag.clear();\n continue;\n }\n flag.clear();\n //\tcout << \"hoge\\n\";\n //\trep(a,h)rep(b,w)cout << museum[a][b] << (b==w-1? '\\n': ' ');\n //\tcout << endl;\n xl = 100000000;\n xr = -1;\n dfs(i,j,museum[i][j]);\n //rep(a,h)rep(b,w)cout << museum[a][b] << (b==w-1? '\\n': ' ');\n //\tcout << endl;\n double cgx = 0;\n \n cnt.clear();\n cnt.resize(w);\n flag.clear();\n flag.resize(h);\n \n rep(k,h) flag[k] = vector<bool>(w,false);\n centerg(i,j);\n int sum = 0;\n rep(k,w){\n sum += cnt[k];\n cgx += (k+0.5)*cnt[k];\n }\n cgx /= sum;\n //\tcout << sum << ' ' << cgx << ' ' << xl << ' ' << xr << endl;\n if(cgx<=xl+EPS || cgx+EPS>=xr+1){\n ok = false;\n// cout << i << ' ' << j << endl;\n goto fail;\n }\n }\n }\n }\n }\n fail:;\n cout << (ok? \"STABLE\\n\": \"UNSTABLE\\n\");\n } \n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1228, "score_of_the_acc": -0.0314, "final_rank": 9 }, { "submission_id": "aoj_1168_693615", "code_snippet": "#include <algorithm>\n#include <bitset>\n#include <cassert>\n#include <cctype>\n#include <climits>\n#include <cmath>\n#include <complex>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <ctime>\n#include <deque>\n#include <fstream>\n#include <iomanip>\n#include <iostream>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <valarray>\n#include <vector>\n\n#define EPS 1e-9\n#define INF 1070000000LL\n#define MOD 1000000007LL\n#define fir first\n#define foreach(it,X) for(__typeof((X).begin()) it=(X).begin();it!=(X).end();it++)\n#define ite iterator\n#define mp make_pair\n#define rep(i,n) rep2(i,0,n)\n#define rep2(i,m,n) for(int i=m;i<(n);i++)\n#define pb push_back\n#define sec second\n#define sz(x) ((int)(x).size())\n\nusing namespace std;\n\nstruct timer{\n\ttime_t start;\n\ttimer(){start=clock();}\n\t~timer(){cerr<<1.*(clock()-start)/CLOCKS_PER_SEC<<\" secs\"<<endl;}\n};\n\ntypedef istringstream iss;\ntypedef long long ll;\ntypedef pair<int,int> pi;\ntypedef stringstream sst;\ntypedef vector<int> vi;\n\nint w,h;\nchar p[70][20];\nint n;\nint id[70][20];\nvector<pi> v[400];\nint xsum[400];\nint bottom;\n\nint used[70][20];\nint dy[]={0,1,0,-1};\nint dx[]={1,0,-1,0};\nvoid dfs(int y,int x,char c){\n\tused[y][x]=1;\n\tid[y][x]=n;\n\tv[n].pb(mp(y,x));\n\txsum[n] += x;\n\tif(y==h)bottom=n;\n\trep(d,4){\n\t\tint ny=y+dy[d],nx=x+dx[d];\n\t\tif(!used[ny][nx] && p[ny][nx] == c){\n\t\t\tdfs(ny,nx,c);\n\t\t}\n\t}\n}\n\nbool on(int a,int b){\n\trep(i,4)rep(j,4){\n\t\tif(v[a][i].fir == v[b][j].fir-1 && v[a][i].sec == v[b][j].sec){\n\t\t\treturn 1;\n\t\t}\n\t}\n\treturn 0;\n}\n\npi sum(int cur){\n\tint s=xsum[cur];\n\tint block=1;\n\t//cout<<cur<<endl;\n\trep(i,n)if(i!=cur && on(i,cur)){\n\t\tpi p = sum(i);\n\t\ts += p.fir;\n\t\tblock += p.sec;\n\t}\n\treturn mp(s,block);\n}\n\nint f(int cur){\n\tint l=INF,r=-INF;\n\trep(i,4){\n\t\t//cout<<i<<endl;\n\t\tint y=v[cur][i].fir,x=v[cur][i].sec;\n\t\tif(id[y+1][x] != -1 && id[y+1][x] != cur\n\t\t|| y==h){\n\t\t\tl = min(l,x);\n\t\t\tr = max(r,x);\n\t\t}\n\t}\n\t//cout<<cur<<\" : \"<<l<<\" \"<<r<<endl;\n\tpi p = sum(cur);\n\tdouble ave = p.fir /4. / p.sec;\n\t//cout<<p.fir<<\" \"<<p.sec<<\" \"<<ave<<endl;\n\tif(l - 0.5 + EPS <= ave && ave <= r + 0.5 - EPS)return 1;\n\treturn 0;\n}\n\nint main(){\n\tcin.tie(0);\n\tios_base::sync_with_stdio(0);\n\t\n\twhile(cin>>w>>h && w){\n\t\t//cout<<w<<\" \"<<h<<endl;\n\t\tmemset(p,0,sizeof(p));\n\t\trep2(i,1,h+1)rep2(j,1,w+1){\n\t\t\tcin>>p[i][j];\n\t\t}\n\t\tmemset(used,0,sizeof(used));\n\t\tmemset(id,-1,sizeof(id));\n\t\tmemset(xsum,0,sizeof(xsum));\n\t\tn=0;\n\t\trep2(i,1,h+1)rep2(j,1,w+1)if(!used[i][j] && isdigit(p[i][j])){\n\t\t\t//cout<<n<<\" : \"<<i<<\" \"<<j<<endl;\n\t\t\tv[n].clear();\n\t\t\tdfs(i,j,p[i][j]);\n\t\t\tn++;\n\t\t}\n\t\t//cout<<\"n: \"<<n<<endl;\n\t\t//rep(i,n)cout<<xsum[i]<<\" \";cout<<endl;\n\t\t/*cout<<\"--\"<<endl;\n\t\trep2(i,1,h+1)rep2(j,1,w+1){\n\t\t\tcout<<id[i][j]<<(j==w?\"\\n\":\" \");\n\t\t}\n\t\tcout<<\"--\"<<endl;*/\n\t\tint ans=1;\n\t\trep(i,n){\n\t\t\t//cout<<i<<endl;\n\t\t\tif(!f(i))ans=0;\n\t\t}\n\t\tcout<<(ans ? \"STABLE\":\"UNSTABLE\")<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1220, "score_of_the_acc": -0.001, "final_rank": 2 } ]
aoj_1171_cpp
Problem G: Laser Beam Reflections A laser beam generator, a target object and some mirrors are placed on a plane. The mirrors stand upright on the plane, and both sides of the mirrors are flat and can reflect beams. To point the beam at the target, you may set the beam to several directions because of different reflections. Your job is to find the shortest beam path from the generator to the target and answer the length of the path. Figure G-1 shows examples of possible beam paths, where the bold line represents the shortest one. Figure G-1: Examples of possible paths Input The input consists of a number of datasets. The end of the input is indicated by a line containing a zero. Each dataset is formatted as follows. Each value in the dataset except n is an integer no less than 0 and no more than 100. n PX 1 PY 1 QX 1 QY 1 ... PX n PY n QX n QY n TX TY LX LY The first line of a dataset contains an integer n (1 ≤ n ≤ 5), representing the number of mirrors. The following n lines list the arrangement of mirrors on the plane. The coordinates ( PX i , PY i ) and ( QX i , QY i ) represent the positions of both ends of the mirror. Mirrors are apart from each other. The last two lines represent the target position ( TX , TY ) and the position of the beam generator ( LX , LY ). The positions of the target and the generator are apart from each other, and these positions are also apart from mirrors. The sizes of the target object and the beam generator are small enough to be ignored. You can also ignore the thicknesses of mirrors. In addition, you can assume the following conditions on the given datasets. There is at least one possible path from the beam generator to the target. The number of reflections along the shortest path is less than 6. The shortest path does not cross or touch a plane containing a mirror surface at any points within 0.001 unit distance from either end of the mirror. Even if the beam could arbitrarily select reflection or passage when it reaches each plane containing a mirror surface at a point within 0.001 unit distance from one of the mirror ends, any paths from the generator to the target would not be shorter than the shortest path. When the beam is shot from the generator in an arbitrary direction and it reflects on a mirror or passes the mirror within 0.001 unit distance from the mirror, the angle θ formed by the beam and the mirror satisfies sin( θ ) > 0.1, until the beam reaches the 6th reflection point (exclusive). Figure G-1 corresponds to the first dataset of the Sample Input below. Figure G-2 shows the shortest paths for the subsequent datasets of the Sample Input. Figure G-2: Examples of the shortest paths Output For each dataset, output a single line containing the length of the shortest path from the beam generator to the target. The value should not have an error greater than 0.001. No extra characters should appear in the output. Sample Input 2 30 10 30 75 60 30 60 95 90 0 0 100 1 20 81 90 90 10 90 90 10 2 10 0 ...(truncated)
[ { "submission_id": "aoj_1171_10851220", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <complex>\n#include <vector>\n#include <cmath>\n#define sz(x) int((x).size())\n#define mkp make_pair\n#define frs first\n#define scn second\n#define phb push_back\n#define ppb pop_back\nusing namespace std;\n\ntypedef complex< double > Point;\ntypedef complex< double > Vector;\ntypedef pair< Point, Point > Segment;\nconst double kInf = 1e10;\nconst double kEps = 1e-8;\n\nint N;\nSegment seg[5];\nPoint bg, ed;\n\ndouble res;\nvector< int > rfl;\n\nvoid read();\nvoid solve();\n\nvoid dfs(int);\nvoid find_path();\n\ninline double cross(const Vector &u, const Vector &v) { return imag(conj(u) * v); }\ninline double dot(const Vector &u, const Vector &v) { return real(conj(u) * v); }\n\ninline bool flt(double x, double y) {\n return x + kEps < y;\n}\n\ninline bool fle(double x, double y) {\n return x < y + kEps;\n}\n\ninline bool feq(double x, double y) {\n return abs(x - y) < kEps;\n}\n\nint main() {\n cout.setf(ios::fixed), cout.precision(14);\n while (cin >> N, N)\n read(), solve();\n\n return 0;\n}\n\nvoid read() {\n int x1, y1, x2, y2;\n\n for (int i = 0; i < N; ++i) {\n cin >> x1 >> y1 >> x2 >> y2;\n seg[i] = mkp(Point(double(x1), double(y1)), Point(double(x2), double(y2)));\n }\n\n cin >> x1 >> y1 >> x2 >> y2;\n ed = Point(double(x1), double(y1));\n bg = Point(double(x2), double(y2));\n}\n\nvoid solve() {\n res = kInf;\n dfs(0);\n cout << res << \"\\n\";\n}\n\nvoid dfs(int dpt) {\n if (dpt > 6)\n return;\n\n rfl.phb(-1);\n find_path();\n rfl.ppb();\n\n for (int i = 0; i < N; ++i) {\n if (!rfl.empty() && i == rfl.back())\n continue;\n\n rfl.phb(i);\n dfs(dpt + 1);\n rfl.ppb();\n }\n}\n\nvoid find_path() {\n Point vp = ed;\n\n for (int i = sz(rfl) - 2; i >= 0; --i) {\n double ra = arg((seg[rfl[i]].scn - seg[rfl[i]].frs) / (vp - seg[rfl[i]].frs));\n vp = seg[rfl[i]].frs + Vector(cos(2 * ra), sin(2 * ra)) * (vp - seg[rfl[i]].frs);\n }\n\n Point cp = bg, np;\n Vector lsr = vp - bg;\n double ln = 0.0;\n\n// for (int i = 0; i < sz(rfl); ++i)\n// cout << \" \" << rfl[i];\n// cout << \"\\n\";\n// cout << \" vp = \" << vp << \"\\n\";\n\n for (int i = 0; i < sz(rfl); ++i) {\n Vector v12, v34, v13, v31;\n double t, s, tt, ss;\n\n if (rfl[i] == -1) {\n if (!feq(cross(lsr, ed - cp), 0.0) || flt(dot(lsr, ed - cp), 0)) {\n// cout << \"check gg:\\n\";\n// cout << \" cross(lsr, ed - cp) = \" << cross(lsr, ed - cp) << \"\\n\";\n// cout << \" dot(lsr, ed - cp) = \" << dot(lsr, ed - cp) << \"\\n\";\n return;\n }\n\n lsr = ed - cp, t = 1.0;\n }\n else {\n v12 = lsr, v34 = seg[rfl[i]].scn - seg[rfl[i]].frs;\n v13 = seg[rfl[i]].frs - cp, v31 = -v13;\n t = cross(v13, v34) / cross(v12, v34);\n s = cross(v31, v12) / cross(v34, v12);\n\n if (fle(t, 0.0) || fle(s, 0.0) || fle(1.0, s))\n return;\n }\n\n// cout << \" lsr = \" << lsr << \"\\n\";\n// cout << \" t = \" << t << \"\\n\";\n\n for (int j = 0; j < N; ++j)\n if (rfl[i] != j) {\n v12 = lsr, v34 = seg[j].scn - seg[j].frs;\n v13 = seg[j].frs - cp, v31 = -v13;\n tt = cross(v13, v34) / cross(v12, v34);\n ss = cross(v31, v12) / cross(v34, v12);\n\n if (!fle(tt, 0.0) && !fle(ss, 0.0) && !fle(1.0, ss)) {\n if (flt(tt, t))\n return;\n }\n }\n\n// cout << \" np = \" << cp + t * v12 << \"\\n\";\n\n np = cp + t * v12;\n ln += abs(np - cp);\n\n if (rfl[i] != -1) {\n double ra = arg((seg[rfl[i]].scn - np) / (cp - np));\n lsr *= Vector(cos(2 * ra), sin(2 * ra));\n }\n\n cp = np;\n }\n\n res = min(res, ln);\n}\n/*\n\n5\n\n72 77 7 10\n45 99 77 77\n4 81 10 54\n17 96 12 73\n52 57 56 70\n41 93\n74 21\n\n0\n\n243.1347\n\n*/", "accuracy": 1, "time_ms": 50, "memory_kb": 3944, "score_of_the_acc": -1.0597, "final_rank": 19 }, { "submission_id": "aoj_1171_10687493", "code_snippet": "#include <bits/stdc++.h>\n\n\n\n\n\nnamespace zawa {\n\nusing i16 = std::int16_t;\nusing i32 = std::int32_t;\nusing i64 = std::int64_t;\nusing i128 = __int128_t;\n\nusing u8 = std::uint8_t;\nusing u16 = std::uint16_t;\nusing u32 = std::uint32_t;\nusing u64 = std::uint64_t;\n\nusing usize = std::size_t;\n\n} // namespace zawa\n\n\nnamespace zawa {\n\nnamespace geometryR2 {\n\nusing Real = long double;\n\nnamespace internal {\n\nReal EPS{1e-12};\nconstexpr i32 negative{-1};\nconstexpr i32 zero{};\nconstexpr i32 positive{1};\n\n} // namespace internal\n\nReal& Eps() {\n return internal::EPS;\n}\n\ni32 Sign(Real value) {\n if (value < -Eps()) return internal::negative;\n if (value > Eps()) return internal::positive;\n return internal::zero;\n}\n\nbool Zero(Real value) {\n return Sign(value) == internal::zero;\n}\n\nbool Positive(Real value) {\n return Sign(value) == internal::positive;\n}\n\nbool Negative(Real value) {\n return Sign(value) == internal::negative;\n}\n\nbool Equal(Real a, Real b) {\n return Zero(a - b);\n}\n\nbool Smaller(Real a, Real b) {\n return Negative(a - b);\n}\n\nbool Bigger(Real a, Real b) {\n return Positive(a - b);\n}\n\nReal Square(Real value) {\n return (Zero(value) ? value : value * value);\n}\n\nReal Sqrt(Real value) {\n assert(!Negative(value));\n return (Zero(value) ? value : sqrtl(value));\n}\n\nReal Abs(Real value) {\n return (Negative(value) ? -value : value);\n}\n\n} // namespace geometryR2\n \n} // namespace zawa\n\n\n\nnamespace zawa {\n\nnamespace geometryR2 {\n\nconstexpr Real PI{acosl(-1)};\nconstexpr Real TAU{static_cast<Real>(2) * PI};\n\nconstexpr Real ArcToRadian(Real arc) {\n return (arc * PI) / static_cast<Real>(180);\n}\n\nconstexpr Real RadianToArc(Real radian) {\n return (radian * static_cast<Real>(180)) / PI;\n}\n\n} // namespace geometryR2\n\n} // namespace zawa\n\n\nnamespace zawa {\n\nnamespace geometryR2 {\n\nclass Point {\nprivate:\n Real x_{}, y_{};\npublic:\n /* constructor */\n Point() = default;\n Point(Real x, Real y) : x_{x}, y_{y} {}\n\n /* getter, setter */\n Real x() const {\n return x_;\n }\n Real& x() {\n return x_;\n }\n Real y() const {\n return y_;\n }\n Real& y() {\n return y_;\n }\n\n /* operator */\n Point& operator+=(const Point& rhs) {\n x_ += rhs.x();\n y_ += rhs.y();\n return *this;\n }\n friend Point operator+(const Point& lhs, const Point& rhs) {\n return Point{lhs} += rhs;\n }\n Point operator+() const {\n return *this;\n }\n Point& operator-=(const Point& rhs) {\n x_ -= rhs.x();\n y_ -= rhs.y();\n return *this;\n }\n friend Point operator-(const Point& lhs, const Point& rhs) {\n return Point{lhs} -= rhs;\n }\n Point operator-() const {\n return Point{} - *this;\n }\n Point& operator*=(Real k) {\n x_ *= k;\n y_ *= k;\n return *this;\n }\n friend Point operator*(Real k, const Point& p) {\n return Point{p} *= k;\n }\n friend Point operator*(const Point& p, Real k) {\n return Point{p} *= k;\n }\n Point& operator/=(Real k) {\n assert(!Zero(k));\n x_ /= k;\n y_ /= k;\n return *this;\n }\n friend Point operator/(Real k, const Point& p) {\n return Point{p} /= k;\n }\n friend Point operator/(const Point& p, Real k) {\n return Point{p} /= k;\n }\n friend bool operator==(const Point& lhs, const Point& rhs) {\n return Equal(lhs.x(), rhs.x()) and Equal(lhs.y(), rhs.y());\n }\n friend bool operator!=(const Point& lhs, const Point& rhs) {\n return !Equal(lhs.x(), rhs.x()) or !Equal(lhs.y(), rhs.y());\n }\n friend bool operator<(const Point& lhs, const Point& rhs) {\n return Smaller(lhs.x(), rhs.x()) or \n (Equal(lhs.x(), rhs.x()) and Smaller(lhs.y(), rhs.y()));\n }\n friend bool operator<=(const Point& lhs, const Point& rhs) {\n return Smaller(lhs.x(), rhs.x()) or \n (Equal(lhs.x(), rhs.x()) and (Smaller(lhs.y(), rhs.y()) or Equal(lhs.y(), rhs.y())));\n }\n friend bool operator>(const Point& lhs, const Point& rhs) {\n return Bigger(lhs.x(), rhs.x()) or\n (Equal(lhs.x(), rhs.x()) and Bigger(lhs.y(), rhs.y()));\n }\n friend bool operator>=(const Point& lhs, const Point& rhs) {\n return Bigger(lhs.x(), rhs.x()) or\n (Equal(lhs.x(), rhs.x()) and (Bigger(lhs.y(), rhs.y()) or Equal(lhs.y(), rhs.y())));\n }\n friend std::istream& operator>>(std::istream& is, Point& p) {\n is >> p.x_ >> p.y_;\n return is;\n }\n friend std::ostream& operator<<(std::ostream& os, const Point& p) {\n os << '(' << p.x_ << ',' << p.y_ << ')';\n return os;\n }\n \n /* member function */\n Real normSquare() const {\n return Square(x_) + Square(y_);\n }\n Real norm() const {\n return Sqrt(normSquare());\n }\n void normalize() {\n assert((*this) != Point{});\n (*this) /= norm(); \n }\n Point normalized() const {\n Point res{*this};\n res.normalize();\n return res;\n }\n Point rotated(Real radian) const {\n return Point{\n x_ * cosl(radian) - y_ * sinl(radian),\n x_ * sinl(radian) + y_ * cosl(radian)\n };\n }\n void rotate(Real radian) {\n *this = rotated(radian); \n }\n Point rotatedByArc(Real arc) const {\n return rotated(ArcToRadian(arc));\n }\n void rotateByArc(Real arc) {\n *this = rotatedByArc(arc);\n }\n Real argument() const {\n return (Negative(y_) ? TAU : static_cast<Real>(0)) + atan2l(y_, x_);\n }\n Real argumentByArc() const {\n return RadianToArc(argument());\n }\n\n /* friend function */\n friend Real Dot(const Point& lhs, const Point& rhs) {\n return lhs.x() * rhs.x() + lhs.y() * rhs.y();\n }\n friend Real Cross(const Point& lhs, const Point& rhs) {\n return lhs.x() * rhs.y() - lhs.y() * rhs.x();\n }\n friend Real Argument(const Point& lhs, const Point& rhs) {\n return rhs.argument() - lhs.argument();\n }\n friend bool ArgComp(const Point& lhs, const Point& rhs) {\n return Smaller(lhs.argument(), rhs.argument());\n }\n};\n\nusing Vector = Point;\n\n} // namespace geometryR2\n\n} // namespace zawa\n\n\nnamespace zawa {\n\nnamespace geometryR2 {\n\nenum RELATION {\n // p0 -> p1 -> p2の順で直線上に並んでいる\n ONLINE_FRONT = -2,\n // (p1 - p0) -> (p2 - p0)が時計回りになっている\n CLOCKWISE,\n // p0 -> p2 -> p1の順で直線上に並んでいる\n ON_SEGMENT,\n // (p1 - p0) -> (p2 - p0)が反時計回りになっている\n COUNTER_CLOCKWISE,\n // p2 -> p0 -> p1、またはp1 -> p0 -> p2の順で直線上に並んでいる\n ONLINE_BACK\n};\n\nRELATION Relation(const Point& p0, const Point& p1, const Point& p2) {\n Point a{p1 - p0}, b{p2 - p0};\n if (Positive(Cross(a, b))) return COUNTER_CLOCKWISE;\n if (Negative(Cross(a, b))) return CLOCKWISE;\n if (Negative(Dot(a, b))) return ONLINE_BACK;\n if (Smaller(a.normSquare(), b.normSquare())) return ONLINE_FRONT;\n return ON_SEGMENT;\n};\n\n} // namespace geometryR2\n\n} // namespace zawa\n\n\nnamespace zawa {\n\nnamespace geometryR2 {\n\nReal Distance(const Point& p0, const Point& p1) {\n return Point{p1 - p0}.norm();\n}\n\nReal DistanceSquare(const Point& p0, const Point& p1) {\n return Point{p1 - p0}.normSquare();\n}\n\n} // namespace geometryR2\n\n} // namespace zawa\n\n\nnamespace zawa {\n\nnamespace geometryR2 {\n\nclass Segment {\nprivate:\n Point p0_{}, p1_{};\npublic:\n /* constructor */\n Segment() = default;\n Segment(const Point& p0, const Point& p1) : p0_{p0}, p1_{p1} {}\n Segment(Real x0, Real y0, Real x1, Real y1) : p0_{x0, y0}, p1_{x1, y1} {}\n\n /* getter setter */\n const Point& p0() const {\n return p0_;\n }\n Point& p0() {\n return p0_;\n }\n const Point& p1() const {\n return p1_;\n }\n Point& p1() {\n return p1_;\n }\n\n /* member function */\n bool valid() const {\n return p0_ != p1_;\n }\n bool straddle(const Segment& s) const {\n return Relation(p0_, p1_, s.p0()) * Relation(p0_, p1_, s.p1()) <= 0;\n }\n Real length() const {\n assert(valid());\n return Distance(p0_, p1_);\n }\n Point midpoint() const {\n assert(valid());\n return p0_ + Vector{p1_ - p0_} / static_cast<Real>(2);\n }\n};\n\n} // namespace geometryR2\n\n} // namespace zawa\n\n\n\nnamespace zawa {\n\nnamespace geometryR2 {\n\nclass Line {\nprivate:\n Point p0_{}, p1_{};\npublic:\n /* constructor */\n Line() = default;\n Line(const Point& p0, const Point& p1) : p0_{p0}, p1_{p1} {}\n // y = ax + b \n Line(Real a, Real b) : p0_{static_cast<Real>(0), b}, p1_{static_cast<Real>(1), a + b} {}\n\n /* getter, setter */\n const Point& p0() const {\n return p0_;\n }\n Point& p0() {\n return p0_;\n }\n const Point& p1() const {\n return p1_;\n }\n Point& p1() {\n return p1_;\n }\n\n /* operator */\n friend bool operator==(const Line& l0, const Line& l1) {\n return Zero(Cross(l0.p1() - l0.p0(), l1.p1() - l1.p0())) and Zero(Cross(l0.p1() - l0.p0(), l1.p1() - l0.p0()));\n }\n friend bool operator!=(const Line& l0, const Line& l1) {\n return !Zero(Cross(l0.p1() - l0.p0(), l1.p1() - l1.p0())) or !Zero(Cross(l0.p1() - l0.p0(), l1.p1() - l0.p0()));\n }\n\n /* member function */\n bool valid() const {\n return p0_ != p1_;\n }\n Vector slope() const {\n assert(valid());\n return Vector{p1() - p0()}.normalized();\n }\n};\n\n} // namespace geometryR2\n\n} // namespace zawa\n\n\n\n\nnamespace zawa {\n\nnamespace geometryR2 {\n\nPoint Projection(const Point& point, const Line& line) {\n assert(line.valid());\n Real coeff{Dot(line.p1() - line.p0(), point - line.p0()) / DistanceSquare(line.p0(), line.p1())};\n return coeff * line.p1() + (static_cast<Real>(1) - coeff) * line.p0();\n}\n\n} // namespace geometryR2\n\n} // namespace zawa\n\nnamespace zawa {\n\nnamespace geometryR2 {\n\nPoint Reflection(const Point& point, const Line& line) {\n assert(line.valid());\n return -point + static_cast<Real>(2) * Projection(point, line);\n}\n\n} // namespace geometryR2\n\n} // namespace zawa\n\n\n\nnamespace zawa {\n\nnamespace geometryR2 {\n\nbool Intersect(const Segment& s0, const Segment& s1) {\n assert(s0.valid());\n assert(s1.valid());\n return s0.straddle(s1) and s1.straddle(s0);\n}\n\n} // namespace geometryR2\n\n} // namespace zawa\n\n\n\n\nnamespace zawa {\n\nnamespace geometryR2 {\n\nbool Parallel(const Segment& s0, const Segment& s1) {\n assert(s0.valid());\n assert(s1.valid());\n return Zero(Cross(s0.p1() - s0.p0(), s1.p1() - s1.p0()));\n}\n\n} // namespace geometryR2\n\n} // namespace zawa\n\n\nnamespace zawa {\n\nnamespace geometryR2 {\n\nPoint CrossPoint(const Segment& s0, const Segment& s1) {\n assert(s0.valid());\n assert(s1.valid());\n assert(Intersect(s0, s1));\n if (Parallel(s0, s1)) {\n if (s0.p0() == s1.p0()) {\n if (Relation(s0.p0(), s0.p1(), s1.p1()) == ONLINE_BACK) {\n return s0.p0();\n }\n else {\n assert(false);\n }\n }\n else if (s0.p0() == s1.p1()) {\n if (Relation(s0.p0(), s0.p1(), s1.p0()) == ONLINE_BACK) {\n return s0.p0();\n }\n else {\n assert(false);\n }\n }\n else if (s0.p1() == s1.p0()) {\n if (Relation(s0.p1(), s0.p0(), s1.p1()) == ONLINE_BACK) {\n return s0.p1();\n }\n else {\n assert(false);\n }\n }\n else if (s0.p1() == s1.p1()) {\n if (Relation(s0.p1(), s0.p0(), s1.p0()) == ONLINE_BACK) {\n return s0.p1();\n }\n else {\n assert(false);\n }\n }\n else {\n assert(false);\n }\n }\n else {\n Vector base{s0.p1() - s0.p0()};\n Real baseNorm{base.norm()};\n Real r1{Abs(Cross(base, s1.p0() - s0.p0())) / baseNorm};\n Real r2{Abs(Cross(base, s1.p1() - s0.p0())) / baseNorm};\n return s1.p0() + (s1.p1() - s1.p0()) * (r1 / (r1 + r2));\n }\n}\n\n} // namespace geometryR2\n\n} // namespace zawa\nusing namespace zawa::geometryR2;\nnamespace ranges = std::ranges;\nnamespace views = std::views;\nint N;\nSegment S[5];\nPoint START, GOAL;\nReal f(std::vector<int> walls) {\n std::vector<Segment> curWall(S, S + N); \n Point curGoal = GOAL;\n std::vector<Segment> go;\n for (int i : walls) {\n const Segment cur = curWall[i];\n const Line curL{cur.p0(), cur.p1()};\n go.push_back(cur);\n curGoal = Reflection(curGoal, curL);\n for (int j = 0 ; j < N ; j++) {\n curWall[j].p0() = Reflection(curWall[j].p0(), curL);\n curWall[j].p1() = Reflection(curWall[j].p1(), curL);\n }\n }\n Segment light{START, curGoal};\n std::vector<Point> pos; // 必ず通る場所\n pos.push_back(START);\n for (const Segment& s : go) {\n if (Intersect(s, light)) {\n pos.push_back(CrossPoint(s, light));\n }\n else {\n return 1e30;\n }\n }\n pos.push_back(curGoal);\n curWall = std::vector<Segment>(S, S + N);\n for (int i = 0 ; i < std::ssize(pos) ; i++) {\n if (Relation(light.p0(), light.p1(), pos[i]) != ON_SEGMENT) return 1e300;\n }\n for (int i = 1 ; i + 1 < std::ssize(pos) ; i++) {\n if (Relation(pos[i - 1], pos[i + 1], pos[i]) != ON_SEGMENT) return 1e300;\n }\n // std::cout << \"-----------------\" << std::endl;\n // for (int i : walls) std::cout << i << ' ';\n // std::cout << \" : \";\n // for (auto p : pos) std::cout << p << ' ';\n // std::cout << Distance(light.p0(), light.p1()) << std::endl;\n for (int i = 0 ; i + 1 < std::ssize(pos) ; i++) {\n const Segment cur{pos[i], pos[i + 1]};\n for (int j = 0 ; j < N ; j++) if (Intersect(curWall[j], cur)) {\n // std::cout << \"hit \" << i << ' ' << j << ' ' << curWall[j].p0() << ',' << curWall[j].p1() << std::endl;\n if (i - 1 >= 0 and i - 1 < std::ssize(walls) and walls[i - 1] == j) continue;\n if (i < std::ssize(walls) and walls[i] == j) continue;\n return 1e30;\n }\n if (i < std::ssize(walls)) {\n const int idx = walls[i];\n const Line curL{curWall[idx].p0(), curWall[idx].p1()};\n for (int j = 0 ; j < N ; j++) {\n curWall[j].p0() = Reflection(curWall[j].p0(), curL);\n curWall[j].p1() = Reflection(curWall[j].p1(), curL);\n }\n }\n }\n // std::cout << \"valid\" << std::endl;\n return Distance(light.p0(), light.p1());\n}\nReal solve() {\n std::vector<int> walls;\n Real res = 1e30;\n auto dfs = [&](auto dfs, int i) -> void {\n res = std::min(res, f(walls));\n if (i == 6) return;\n for (int j = 0 ; j < N ; j++) if (walls.empty() or walls.back() != j) {\n walls.push_back(j);\n dfs(dfs, i + 1);\n walls.pop_back();\n }\n };\n dfs(dfs, 0);\n return res;\n}\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n std::cout << std::fixed << std::setprecision(5);\n while (true) {\n std::cin >> N;\n if (N == 0) break;\n for (int i = 0 ; i < N ; i++) {\n std::cin >> S[i].p0() >> S[i].p1();\n }\n std::cin >> GOAL >> START;\n std::cout << solve() << '\\n';\n }\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 3712, "score_of_the_acc": -0.9614, "final_rank": 16 }, { "submission_id": "aoj_1171_9862848", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n/**\n * @brief template\n */\n\nusing T = long double;\nconst T eps = 1e-6;\nusing Point = complex<T>;\nusing Poly = vector<Point>;\n#define X real()\n#define Y imag()\ntemplate <typename T> inline bool eq(const T &a, const T &b) {\n return fabs(a - b) < eps;\n}\nbool cmp(const Point &a, const Point &b) {\n auto sub = [&](Point a) {\n return (a.Y < 0 ? -1 : (a.Y == 0 && a.X >= 0 ? 0 : 1));\n };\n if (sub(a) != sub(b))\n return sub(a) < sub(b);\n return a.Y * b.X < a.X * b.Y;\n}\nstruct Line {\n Point a, b, dir;\n Line() {}\n Line(Point _a, Point _b) : a(_a), b(_b), dir(b - a) {}\n Line(T A, T B, T C) {\n if (eq(A, (T).0)) {\n a = Point(0, C / B), b = Point(1 / C / B);\n } else if (eq(B, (T).0)) {\n a = Point(C / A, 0), b = Point(C / A, 1);\n } else {\n a = Point(0, C / B), b = Point(C / A, 0);\n }\n }\n};\nstruct Segment : Line {\n Segment() {}\n Segment(Point _a, Point _b) : Line(_a, _b) {}\n};\nstruct Circle {\n Point p;\n T r;\n Circle() {}\n Circle(Point _p, T _r) : p(_p), r(_r) {}\n};\n\nistream &operator>>(istream &is, Point &p) {\n T x, y;\n is >> x >> y;\n p = Point(x, y);\n return is;\n}\nostream &operator<<(ostream &os, Point &p) {\n os << fixed << setprecision(12) << p.X << ' ' << p.Y;\n return os;\n}\nPoint unit(const Point &a) {\n return a / abs(a);\n}\nT dot(const Point &a, const Point &b) {\n return a.X * b.X + a.Y * b.Y;\n}\nT cross(const Point &a, const Point &b) {\n return a.X * b.Y - a.Y * b.X;\n}\nPoint rot(const Point &a, const T &theta) {\n return Point(cos(theta) * a.X - sin(theta) * a.Y,\n sin(theta) * a.X + cos(theta) * a.Y);\n}\nPoint rot90(const Point &a) {\n return Point(-a.Y, a.X);\n}\nT arg(const Point &a, const Point &b, const Point &c) {\n double ret = acos(dot(a - b, c - b) / abs(a - b) / abs(c - b));\n if (cross(a - b, c - b) < 0)\n ret = -ret;\n return ret;\n}\n\nPoint Projection(const Line &l, const Point &p) {\n T t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\nPoint Projection(const Segment &l, const Point &p) {\n T t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\nPoint Reflection(const Line &l, const Point &p) {\n return p + (Projection(l, p) - p) * (T)2.;\n}\nint ccw(const Point &a, Point b, Point c) {\n b -= a;\n c -= a;\n if (cross(b, c) > eps)\n return 1; // ccw\n\n if (cross(b, c) < -eps)\n return -1; // cw\n\n if (dot(b, c) < 0)\n return 2; // c,a,b\n\n if (norm(b) < norm(c))\n return -2; // a,b,c\n\n return 0; // a,c,b\n\n}\nbool isOrthogonal(const Line &a, const Line &b) {\n return eq(dot(a.b - a.a, b.b - b.a), (T).0);\n}\nbool isParallel(const Line &a, const Line &b) {\n return eq(cross(a.b - a.a, b.b - b.a), (T).0);\n}\nbool isIntersect(const Segment &a, const Segment &b) {\n return ccw(a.a, a.b, b.a) * ccw(a.a, a.b, b.b) <= 0 and\n ccw(b.a, b.b, a.a) * ccw(b.a, b.b, a.b) <= 0;\n}\nint isIntersect(const Circle &a, const Circle &b) {\n T d = abs(a.p - b.p);\n if (d > a.r + b.r + eps)\n return 4;\n if (eq(d, a.r + b.r))\n return 3;\n if (eq(d, abs(a.r - b.r)))\n return 1;\n if (d < abs(a.r - b.r) - eps)\n return 0;\n return 2;\n}\nT Dist(const Line &a, const Point &b) {\n Point c = Projection(a, b);\n return abs(c - b);\n}\nT Dist(const Segment &a, const Point &b) {\n if (dot(a.b - a.a, b - a.a) < eps)\n return abs(b - a.a);\n if (dot(a.a - a.b, b - a.b) < eps)\n return abs(b - a.b);\n return abs(cross(a.b - a.a, b - a.a)) / abs(a.b - a.a);\n}\nT Dist(const Segment &a, const Segment &b) {\n if (isIntersect(a, b))\n return (T).0;\n T res = min({Dist(a, b.a), Dist(a, b.b), Dist(b, a.a), Dist(b, a.b)});\n return res;\n}\nPoint Intersection(const Line &a, const Line &b) {\n T d1 = cross(a.b - a.a, b.b - b.a);\n T d2 = cross(a.b - a.a, a.b - b.a);\n if (eq(d1, (T)0.) and eq(d2, (T)0.))\n return b.a;\n return b.a + (b.b - b.a) * (d2 / d1);\n}\n\n/**\n * @brief Geometry\n */\n\nint main() {\nwhile(1) {\n int N;\n cin >> N;\n if (N == 0) return 0;\n vector<Segment> S(N);\n rep(i,0,N) {\n long double px, py, qx, qy;\n cin >> px >> py >> qx >> qy;\n S[i] = Segment(Point(px,py), Point(qx,qy));\n }\n Point A, B;\n {\n long double ax, ay, bx, by;\n cin >> ax >> ay >> bx >> by;\n A = Point(ax,ay), B = Point(bx,by);\n }\n long double ANS;\n auto Solve = [&](vector<int> ord) -> void {\n Point D = B;\n rrep(_,0,ord.size()) {\n int i = ord[_];\n D = Reflection(S[i], D);\n }\n Point C = A;\n if (eq(C,D)) return;\n Point V = unit(D-C);\n for (int i : ord) {\n int next = -1;\n long double min = inf;\n Segment Beam(C, C + V * 10000.0L);\n rep(j,0,N) {\n if (!isIntersect(S[j], Beam)) continue;\n Point E = Intersection(S[j], Beam);\n if (eq(C,E)) continue;\n if (chmin(min, abs(C-E))) next = j;\n }\n if (next != i) return;\n {\n Point E = Intersection(S[next], Beam);\n C = E;\n V = Reflection(S[next], E+V) - E;\n }\n }\n Point W = (B-C)/V;\n if (W.real() < 0.0L) return;\n rep(i,0,N) {\n if (!ord.empty() && i == ord.back()) continue;\n Segment Beam(C,B);\n if (isIntersect(S[i], Beam)) return;\n }\n chmin(ANS, abs(D-A));\n };\n auto DFS = [&](auto self, vector<int> ord) -> void {\n if ((int)ord.size() >= 6) return;\n Solve(ord);\n rep(i,0,N) {\n if (!ord.empty() && ord.back() == i) continue;\n ord.push_back(i);\n self(self,ord);\n ord.pop_back();\n }\n };\n vector<int> ord = {};\n ANS = inf;\n DFS(DFS,ord);\n printf(\"%.12Lf\\n\", ANS);\n}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3436, "score_of_the_acc": -0.3094, "final_rank": 7 }, { "submission_id": "aoj_1171_9309624", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n\nusing Real = long double;\nusing Point = complex<Real>;\nconst Real EPS = 1e-9, PI = acos(-1);\n\ninline bool eq(Real a, Real b) {\n return fabs(b - a) < EPS;\n}\n\nPoint operator*(const Point &p, const Real &d) {\n return Point(real(p) * d, imag(p) * d);\n}\n\nistream &operator>>(istream &is, Point &p) {\n Real a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n}\n\nostream &operator<<(ostream &os, Point &p) {\n return os << fixed << setprecision(10) << p.real() << \" \" << p.imag();\n}\n\n// a-b-c の角度のうち小さい方を返す\nReal get_angle(const Point &a, const Point &b, const Point &c) {\n const Point v(b - a), w(c - b);\n Real alpha = atan2(v.imag(), v.real()), beta = atan2(w.imag(), w.real());\n if (alpha > beta) swap(alpha, beta);\n Real theta = (beta - alpha);\n return min(theta, 2 * acos(-1) - theta);\n}\n\nnamespace std {\nbool operator<(const Point &a, const Point &b) {\n return a.real() != b.real() ? a.real() < b.real() : a.imag() < b.imag();\n}\n} // namespace std\n\nstruct Line {\n Point a, b;\n\n Line() = default;\n\n Line(Point a, Point b) : a(a), b(b) {}\n\n Line(Real A, Real B, Real C) // Ax + By = C\n {\n if (eq(A, 0)) a = Point(0, C / B), b = Point(1, C / B);\n else if (eq(B, 0)) b = Point(C / A, 0), b = Point(C / A, 1);\n else a = Point(0, C / B), b = Point(C / A, 0);\n }\n\n friend ostream &operator<<(ostream &os, Line &p) { return os << p.a << \" to \" << p.b; }\n\n friend istream &operator>>(istream &is, Line &a) { return is >> a.a >> a.b; }\n};\n\nstruct Segment : Line {\n Segment() = default;\n\n Segment(Point a, Point b) : Line(a, b) {}\n};\n\nusing Segments = vector<Segment>;\n\nReal cross(const Point &a, const Point &b) {\n return real(a) * imag(b) - imag(a) * real(b);\n}\n\nReal dot(const Point &a, const Point &b) {\n return real(a) * real(b) + imag(a) * imag(b);\n}\n\n// 点の回転方向\nint ccw(const Point &a, Point b, Point c) {\n b = b - a, c = c - a;\n if (cross(b, c) > EPS) return +1; // \"COUNTER_CLOCKWISE\"\n if (cross(b, c) < -EPS) return -1; // \"CLOCKWISE\"\n if (dot(b, c) < 0) return +2; // \"ONLINE_BACK\"\n if (norm(b) < norm(c)) return -2; // \"ONLINE_FRONT\"\n return 0; // \"ON_SEGMENT\"\n}\n\nPoint projection(const Line &l, const Point &p) {\n double t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\nPoint projection(const Segment &l, const Point &p) {\n double t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\n\n// 反射\n// 直線 l を対称軸として点 p と線対称にある点を求める\nPoint reflection(const Line &l, const Point &p) {\n return p + (projection(l, p) - p) * 2.0;\n}\nPoint reflection(const Segment &s, const Point &p) {\n return p + (projection(s, p) - p) * 2.0;\n}\n\nbool intersect(const Segment &s, const Segment &t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\nReal distance(const Point &a, const Point &b) {\n return abs(a - b);\n}\n\nPoint crosspoint(const Line &l, const Line &m) {\n Real A = cross(l.b - l.a, m.b - m.a);\n Real B = cross(l.b - l.a, l.b - m.a);\n if (eq(abs(A), 0.0) && eq(abs(B), 0.0)) return m.a;\n return m.a + (m.b - m.a) * B / A;\n}\nPoint crosspoint(const Segment &l, const Segment &m) {\n return crosspoint(Line(l), Line(m));\n}\n\ntemplate<class T>\nbool chmin(T &a, const T &b) {if (a > b) {a = b; return 1;} return 0;}\n\nReal check(vector<int> &ids, const vector<Segment> &mirror, const vector<Point> &ST)\n{\n bool debug = false;\n \n int siz = ids.size();\n vector<Point> S(siz + 1), T(siz + 1);\n S[0] = ST[0];\n for (int i = 0; i < siz; ++i)\n {\n S[i+1] = reflection(mirror[ids[i]], S[i]);\n }\n T[siz] = ST[1];\n for (int i = siz - 1; i >= 0; --i)\n {\n T[i] = reflection(mirror[ids[i]], T[i+1]);\n }\n \n if (debug)\n {\n for (int i = 0; i <= siz; ++i)\n {\n cout << S[i] << \" \" << T[i] << endl;\n }\n }\n \n \n bool ret = true;\n for (int i = 0; i <= siz; ++i)\n {\n int id0 = -1, id1 = -2;\n if (i > 0) id0 = ids[i-1];\n if (i < siz) id1 = ids[i];\n \n Segment seg(S[i], T[i]);\n \n vector<pair<Real, int>> vec;\n Point base = S[i];\n vec.push_back({distance(S[i], base), -1});\n vec.push_back({distance(T[i], base), -2});\n for (int j = 0; j < mirror.size(); ++j)\n {\n if (intersect(seg, mirror[j]))\n {\n vec.push_back({distance(crosspoint(seg, mirror[j]), base), j});\n if (debug) cout << j << \" \" << crosspoint(seg, mirror[j]) << endl;\n }\n }\n \n sort(vec.begin(), vec.end());\n \n bool tmp = false;\n for (int j = 0; j + 1 < vec.size(); ++j)\n {\n auto [d0, i0] = vec[j];\n auto [d1, i1] = vec[j+1];\n if (i0 == id0 && i1 == id1) tmp = true;\n // if (i0 == id1 && i1 == id0) tmp = true;\n }\n ret &= tmp;\n }\n \n return (ret ? distance(S[0], T[0]) : 1e18);\n}\n\nvoid dfs(int depth, vector<int> &ids, const vector<Segment> &mirror, const vector<Point> &ST, Real &ans)\n{\n assert((int)ids.size() == depth);\n \n chmin(ans, check(ids, mirror, ST));\n \n if (depth == 5) return;\n \n int N = mirror.size();\n for (int i = 0; i < mirror.size(); ++i)\n {\n ids.emplace_back(i);\n dfs(depth + 1, ids, mirror, ST, ans);\n ids.pop_back();\n }\n \n return;\n}\n\nbool is_end = false;\n\nvoid solve()\n{\n int N; cin >> N;\n if (N == 0)\n {\n is_end = true;\n return;\n }\n \n vector<Segment> mirror(N);\n for (int i = 0; i < N; ++i)\n {\n Real px, py, qx, qy; cin >> px >> py >> qx >> qy;\n mirror[i] = Segment(Point(px, py), Point(qx, qy));\n }\n Real sx, sy, tx, ty; cin >> sx >> sy >> tx >> ty;\n Point S(sx, sy), T(tx, ty);\n vector<Point> ST{S, T};\n \n Real ans = 1e18;\n vector<int> ids;\n dfs(0, ids, mirror, ST, ans);\n \n cout << fixed << setprecision(20);\n cout << ans << endl;\n \n return;\n}\n\nint main()\n{\n while (!is_end)\n {\n solve();\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3548, "score_of_the_acc": -0.659, "final_rank": 13 }, { "submission_id": "aoj_1171_6030348", "code_snippet": "#pragma GCC ta g(\"avx2\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\nusing namespace std;\n#define DEBUG\n#ifdef DEBUG\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << '(' << p.first << ',' << p.second << ')';\n return os;\n}\ntemplate <class T> ostream &operator<<(ostream &os, const vector<T> &v) {\n os << '{';\n for(int i = 0; i < (int)v.size(); i++) {\n if(i) { os << ','; }\n os << v[i];\n }\n os << '}';\n return os;\n}\nvoid debugg() { cerr << endl; }\ntemplate <class T, class... Args>\nvoid debugg(const T &x, const Args &... args) {\n cerr << \" \" << x;\n debugg(args...);\n}\n#define debug(...) \\\n cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"]: \", debugg(__VA_ARGS__)\n#define dump(x) cerr << __LINE__ << \" \" << #x << \" = \" << (x) << endl\n#else\n#define debug(...) (void(0))\n#define dump(x) (void(0))\n#endif\nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vl;\ntypedef vector<vl> vvl;\ntypedef vector<char> vc;\ntypedef vector<string> vs;\ntypedef vector<bool> vb;\ntypedef vector<double> vd;\ntypedef pair<ll,ll> P;\ntypedef pair<int,int> pii;\ntypedef vector<P> vpl;\ntypedef tuple<ll,ll,ll> tapu;\n#define rep(i,n) for(int i=0; i<(n); i++)\n#define REP(i,a,b) for(int i=(a); i<(b); i++)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\ntemplate<typename T1,typename T2> inline bool chmin(T1 &a,T2 b){\n\tif(a>b){\n\t\ta = b; return true;\n\t}\n\telse return false;\n}\ntemplate<typename T1,typename T2> inline bool chmax(T1 &a,T2 b){\n\tif(a<b){\n\t\ta = b; return true;\n\t}\n\telse return false;\n}\ntemplate<typename T> inline void print(T &a){\n int sz = a.size();\n for(auto itr = a.begin(); itr != a.end(); itr++){\n\t\tcout << *itr;\n sz--;\n if(sz) cout << \" \";\n\t}\n cout << \"\\n\";\n}\ntemplate<typename T1,typename T2> inline void print2(T1 a, T2 b){\n\tcout << a << \" \" << b << \"\\n\";\n}\ntemplate<typename T1,typename T2,typename T3> inline void print3(T1 a, T2 b, T3 c){\n\tcout << a << \" \" << b << \" \" << c << \"\\n\";\n}\nvoid mark() {cout << \"#\" << \"\\n\";}\nll pcount(ll x) {return __builtin_popcountll(x);}\n//#include <atcoder/maxflow>\n//using namespace atcoder;\nconst int inf = (1<<30)-1;\nconst ll linf = 1LL<<61;\nconst int MAX = 510000;\nint dy[8] = {0,1,0,-1,1,-1,-1,1};\nint dx[8] = {-1,0,1,0,1,-1,1,-1};\nconst double pi = acos(-1);\nconst double eps = 1e-9;\n//const int mod = 1e9 + 7;\nconst int mod = 998244353;\n\nnamespace geometry {\n // Point : 複素数型を位置ベクトルとして扱う\n // 実軸(real)をx軸、挙軸(imag)をy軸として見る\n using D = long double;\n using Point = complex<D>;\n const D EPS = 1e-7;\n const D PI = acosl(-1);\n\n inline bool equal(const D &a, const D &b) { return fabs(a - b) < EPS; }\n\n // 単位ベクトル(unit vector)を求める\n Point unitVector(const Point &a) { return a / abs(a); }\n\n // 法線ベクトル(normal vector)を求める\n // 90度回転した単位ベクトルをかける\n // -90度がよければPoint(0, -1)をかける\n Point normalVector(const Point &a) { return a * Point(0, 1); }\n\n // 内積(dot product) : a・b = |a||b|cosΘ\n D dot(const Point &a, const Point &b) {\n return (a.real() * b.real() + a.imag() * b.imag());\n }\n\n // 外積(cross product) : a×b = |a||b|sinΘ\n D cross(const Point &a, const Point &b) {\n return (a.real() * b.imag() - a.imag() * b.real());\n }\n\n // 点pを反時計回りにtheta度回転\n // thetaはラジアン!!!\n Point rotate(const Point &p, const D &theta) {\n return Point(cos(theta) * p.real() - sin(theta) * p.imag(),\n sin(theta) * p.real() + cos(theta) * p.imag());\n }\n\n // ラジアン->度\n D radianToDegree(const D &radian) { return radian * 180.0 / PI; }\n\n // 度->ラジアン\n D degreeToRadian(const D &degree) { return degree * PI / 180.0; }\n\n // 点の回転方向\n // 点a, b, cの位置関係について(aが基準点)\n int ccw(const Point &a, Point b, Point c) {\n b -= a, c -= a;\n // 点a, b, c が\n // 反時計回りの時、\n if(cross(b, c) > EPS) return 1;\n // 時計回りの時、\n if(cross(b, c) < -EPS) return -1;\n // c, a, bがこの順番で同一直線上にある時、\n if(dot(b, c) < 0) return 2;\n // a, b, cがこの順番で同一直線上にある場合、\n if(norm(b) < norm(c)) return -2;\n // cが線分ab上にある場合、\n return 0;\n }\n\n // Line : 直線を表す構造体\n // b - a で直線・線分を表せる\n struct Line {\n Point a, b;\n Line() = default;\n Line(Point a, Point b) : a(a), b(b) {}\n // Ax+By=C\n Line(D A, D B, D C) {\n if(equal(A, 0)) {\n a = Point(0, C / B), b = Point(1, C / B);\n } else if(equal(B, 0)) {\n b = Point(C / A, 0), b = Point(C / A, 1);\n } else {\n a = Point(0, C / B), b = Point(C / A, 0);\n }\n }\n };\n\n // Segment : 線分を表す構造体\n // Lineと同じ\n struct Segment : Line {\n Segment() = default;\n\n Segment(Point a, Point b) : Line(a, b) {}\n };\n\n // Circle : 円を表す構造体\n // pが中心の位置ベクトル、rは半径\n struct Circle {\n Point p;\n D r;\n\n Circle() = default;\n\n Circle(Point p, D r) : p(p), r(r) {}\n };\n\n // 2直線の直交判定 : a⊥b <=> dot(a, b) = 0\n bool isOrthogonal(const Line &a, const Line &b) {\n return equal(dot(a.b - a.a, b.b - b.a), 0);\n }\n // 2直線の平行判定 : a//b <=> cross(a, b) = 0\n bool isParallel(const Line &a, const Line &b) {\n return equal(cross(a.b - a.a, b.b - b.a), 0);\n }\n\n // 点cが直線ab上にあるか\n bool isPointOnLine(const Point &a, const Point &b, const Point &c) {\n return isParallel(Line(a, b), Line(a, c));\n }\n\n // 点cが\"線分\"ab上にあるか\n bool isPointOnSegment(const Point &a, const Point &b, const Point &c) {\n // |a-c| + |c-b| <= |a-b| なら線分上\n return (abs(a - c) + abs(c - b) < abs(a - b) + EPS);\n }\n\n // 直線lと点pの距離を求める\n D distanceBetweenLineAndPoint(const Line &l, const Point &p) {\n return abs(cross(l.b - l.a, p - l.a)) / abs(l.b - l.a);\n }\n\n // 線分lと点pの距離を求める\n // 定義:点pから「線分lのどこか」への最短距離\n D distanceBetweenSegmentAndPoint(const Segment &l, const Point &p) {\n if(dot(l.b - l.a, p - l.a) < EPS) return abs(p - l.a);\n if(dot(l.a - l.b, p - l.b) < EPS) return abs(p - l.b);\n return abs(cross(l.b - l.a, p - l.a)) / abs(l.b - l.a);\n }\n\n // 直線s, tの交点の計算\n Point crossPoint(const Line &s, const Line &t) {\n D d1 = cross(s.b - s.a, t.b - t.a);\n D d2 = cross(s.b - s.a, s.b - t.a);\n if(equal(abs(d1), 0) && equal(abs(d2), 0)) return t.a;\n return t.a + (t.b - t.a) * (d2 / d1);\n }\n\n // 線分s, tの交点の計算\n Point crossPoint(const Segment &s, const Segment &t) {\n return crossPoint(Line(s), Line(t));\n }\n\n // 線分sと線分tが交差しているかどうか\n // bound:線分の端点を含むか\n bool isIntersect(const Segment &s, const Segment &t, bool bound) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) < bound &&\n ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) < bound;\n }\n\n // 線分sとtの距離\n D distanceBetweenSegments(const Segment &s, const Segment &t) {\n if(isIntersect(s, t, 1)) return (D)(0);\n D ans = distanceBetweenSegmentAndPoint(s, t.a);\n chmin(ans, distanceBetweenSegmentAndPoint(s, t.b));\n chmin(ans, distanceBetweenSegmentAndPoint(t, s.a));\n chmin(ans, distanceBetweenSegmentAndPoint(t, s.b));\n return ans;\n }\n\n // 射影(projection)\n // 直線(線分)lに点pから引いた垂線の足を求める\n Point projection(const Line &l, const Point &p) {\n D t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n }\n\n Point projection(const Segment &l, const Point &p) {\n D t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n }\n\n // 反射(reflection)\n // 直線lを対称軸として点pと線対称の位置にある点を求める\n Point reflection(const Line &l, const Point &p) {\n return p + (projection(l, p) - p) * (D)2.0;\n }\n\n // 2つの円の交差判定\n // 返り値は共通接線の数\n int isIntersect(const Circle &c1, const Circle &c2) {\n D d = abs(c1.p - c2.p);\n // 2つの円が離れている場合\n if(d > c1.r + c2.r + EPS) return 4;\n // 外接している場合\n if(equal(d, c1.r + c2.r)) return 3;\n // 内接している場合\n if(equal(d, abs(c1.r - c2.r))) return 1;\n // 内包している場合\n if(d < abs(c1.r - c2.r) - EPS) return 0;\n return 2;\n }\n\n // 2つの円の交点\n vector<Point> crossPoint(const Circle &c1, const Circle &c2) {\n vector<Point> res;\n int mode = isIntersect(c1, c2);\n // 2つの中心の距離\n D d = abs(c1.p - c2.p);\n // 2円が離れている場合\n if(mode == 4) return res;\n // 1つの円がもう1つの円に内包されている場合\n if(mode == 0) return res;\n // 2円が外接する場合\n if(mode == 3) {\n D t = c1.r / (c1.r + c2.r);\n res.emplace_back(c1.p + (c2.p - c1.p) * t);\n return res;\n }\n // 内接している場合\n if(mode == 1) {\n if(c2.r < c1.r - EPS) {\n res.emplace_back(c1.p + (c2.p - c1.p) * (c1.r / d));\n } else {\n res.emplace_back(c2.p + (c1.p - c2.p) * (c2.r / d));\n }\n return res;\n }\n // 2円が重なる場合\n D rc1 = (c1.r * c1.r + d * d - c2.r * c2.r) / (2 * d);\n D rs1 = sqrt(c1.r * c1.r - rc1 * rc1);\n if(c1.r - abs(rc1) < EPS) rs1 = 0;\n Point e12 = (c2.p - c1.p) / abs(c2.p - c1.p);\n res.emplace_back(c1.p + rc1 * e12 + rs1 * e12 * Point(0, 1));\n res.emplace_back(c1.p + rc1 * e12 + rs1 * e12 * Point(0, -1));\n return res;\n }\n\n // 点pが円cの内部(円周上も含む)に入っているかどうか\n bool isInCircle(const Circle &c, const Point &p) {\n D d = abs(c.p - p);\n return (equal(d, c.r) || d < c.r - EPS);\n }\n\n // 円cと直線lの交点\n vector<Point> crossPoint(const Circle &c, const Line &l) {\n vector<Point> res;\n D d = distanceBetweenLineAndPoint(l, c.p);\n // 交点を持たない\n if(d > c.r + EPS) return res;\n // 接する\n Point h = projection(l, c.p);\n if(equal(d, c.r)) {\n res.emplace_back(h);\n return res;\n }\n Point e = unitVector(l.b - l.a);\n D ph = sqrt(c.r * c.r - d * d);\n res.emplace_back(h - e * ph);\n res.emplace_back(h + e * ph);\n return res;\n }\n\n // 点pを通る円cの接線\n // 2本あるので、接点のみを返す\n vector<Point> tangentToCircle(const Point &p, const Circle &c) {\n return crossPoint(c, Circle(p, sqrt(norm(c.p - p) - c.r * c.r)));\n }\n\n // 円の共通接線\n vector<Line> tangent(const Circle &a, const Circle &b) {\n vector<Line> ret;\n // 2円の中心間の距離\n D g = abs(a.p - b.p);\n // 円が内包されている場合\n if(equal(g, 0)) return ret;\n Point u = unitVector(b.p - a.p);\n Point v = rotate(u, PI / 2);\n for(int s : {-1, 1}) {\n D h = (a.r + b.r * s) / g;\n if(equal(h * h, 1)) {\n ret.emplace_back(a.p + (h > 0 ? u : -u) * a.r,\n a.p + (h > 0 ? u : -u) * a.r + v);\n\n } else if(1 - h * h > 0) {\n Point U = u * h, V = v * sqrt(1 - h * h);\n ret.emplace_back(a.p + (U + V) * a.r,\n b.p - (U + V) * (b.r * s));\n ret.emplace_back(a.p + (U - V) * a.r,\n b.p - (U - V) * (b.r * s));\n }\n }\n return ret;\n }\n\n // 多角形の面積を求める\n D PolygonArea(const vector<Point> &p) {\n D res = 0;\n int n = p.size();\n for(int i = 0; i < n - 1; i++) res += cross(p[i], p[i + 1]);\n res += cross(p[n - 1], p[0]);\n return res * 0.5;\n }\n\n // 凸多角形かどうか\n bool isConvex(const vector<Point> &p) {\n int n = p.size();\n int now, pre, nxt;\n for(int i = 0; i < n; i++) {\n pre = (i - 1 + n) % n;\n nxt = (i + 1) % n;\n now = i;\n if(ccw(p[pre], p[now], p[nxt]) == -1) return false;\n }\n return true;\n }\n\n // 凸包 O(NlogN)\n vector<Point> ConvexHull(vector<Point> &p) {\n int n = (int)p.size(), k = 0;\n sort(all(p), [](const Point &a, const Point &b) {\n return (real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b));\n });\n vector<Point> ch(2 * n);\n // 一直線上の3点を含める -> (< -EPS)\n // 含め無い -> (< EPS)\n for(int i = 0; i < n; ch[k++] = p[i++]) { // lower\n while(k >= 2 &&\n cross(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1]) < EPS)\n --k;\n }\n for(int i = n - 2, t = k + 1; i >= 0; ch[k++] = p[i--]) { // upper\n while(k >= t &&\n cross(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1]) < EPS)\n --k;\n }\n ch.resize(k - 1);\n return ch;\n }\n\n // 多角形gに点pが含まれているか?\n // 含まれる:2, 辺上にある:1, 含まれない:0\n int isContained(const vector<Point> &g, const Point &p) {\n bool in = false;\n int n = (int)g.size();\n for(int i = 0; i < n; i++) {\n Point a = g[i] - p, b = g[(i + 1) % n] - p;\n if(imag(a) > imag(b)) swap(a, b);\n if(imag(a) <= EPS && EPS < imag(b) && cross(a, b) < -EPS) in = !in;\n if(cross(a, b) == 0 && dot(a, b) <= 0) return 1;\n }\n return (in ? 2 : 0);\n }\n\n vector<Point> convex_cut(const vector<Point> &g, Line l){\n vector<Point> ret;\n for(int i=0; i<g.size(); i++){\n Point now = g[i], nxt = g[(i+1)%g.size()];\n if(ccw(l.a,l.b,now) != -1) ret.push_back(now);\n if(ccw(l.a,l.b,now) * ccw(l.a,l.b,nxt) < 0){\n ret.push_back(crossPoint(Line(now,nxt),l));\n }\n }\n return ret;\n }\n\n bool equal (const Point &a, const Point &b) {\n return equal(a.real(),b.real()) && equal(a.imag(),b.imag());\n }\n\n D circlesIntersectArea(Circle &a, Circle &b){\n double d = abs(a.p - b.p);\n if(d >= a.r + b.r - EPS) return 0; //2円が離れている\n auto R = minmax(a.r,b.r);\n if(d <= R.second - R.first + EPS) return R.first*R.first*pi; //円が円を内包する\n D theta1 = acos((d*d + a.r*a.r - b.r*b.r)/(2*a.r*d));\n D theta2 = acos((d*d + b.r*b.r - a.r*a.r)/(2*b.r*d));\n D ret = a.r*a.r*(theta1-cos(theta1)*sin(theta1)) + b.r*b.r*(theta2-cos(theta2)*sin(theta2));\n return ret;\n }\n} // namespace geometry\n\nusing namespace geometry;\n\nbool solve(){\n\tint n; cin >> n;\n\tif(!n) return false;\n\tvector<Point> P(n),Q(n);\n\trep(i,n){\n\t\tint a,b,c,d; cin >> a >> b >> c >> d;\n\t\tP[i] = Point(a,b); Q[i] = Point(c,d);\n\t}\n\tPoint S,G;\n\t{\n\t\tint a,b,c,d; cin >> a >> b >> c >> d;\n\t\tS = Point(a,b); G = Point(c,d);\n\t}\n\n\tD ans = inf;\n\n\tvector<int> mirrors;\n\n\tauto check = [&]() -> void {\n\t\t//debug(mirrors);\n\t\tbool f = true;\n\t\tint sz = mirrors.size();\n\t\tauto p = P, q = Q;\n\t\tauto s = S, g = G;\n\t\tvector<vector<Point>> ps(sz+1,vector<Point>(n));\n\t\tvector<vector<Point>> qs(sz+1,vector<Point>(n));\n\t\trep(i,n){\n\t\t\tps[0][i] = p[i];\n\t\t\tqs[0][i] = q[i];\n\t\t}\n\t\tD pre = 0;\n\t\trep(i,sz){\n\t\t\tint id = mirrors[i];\n\t\t\tLine l(p[id],q[id]);\n\t\t\trep(j,n){\n\t\t\t\tif(id != j){\n\t\t\t\t\tp[j] = reflection(l,p[j]);\n\t\t\t\t\tq[j] = reflection(l,q[j]);\n\t\t\t\t}\n\t\t\t\tps[i+1][j] = p[j];\n\t\t\t\tqs[i+1][j] = q[j];\n\t\t\t}\n\t\t\tg = reflection(l,g);\n\t\t}\n\t\tSegment seg(s,g);\n\t\tD res = 0;\n\t\tfor(int i=sz-1; i>=0; i--){\n\t\t\tseg = Segment(s,g);\n\t\t\tint id = mirrors[i];\n\t\t\tLine l(p[id],q[id]);\n\t\t\tvector<tuple<D,int,Point>> crosses;\n\t\t\trep(j,n){\n\t\t\t\tSegment mir(ps[i+1][j],qs[i+1][j]);\n\t\t\t\tif(i<sz-1 && mirrors[i+1] == j) continue;\n\t\t\t\tif(isIntersect(seg,mir,true)){\n\t\t\t\t\tPoint cr = crossPoint(seg,mir);\n\t\t\t\t\tcrosses.emplace_back(abs(cr-g),j,cr);\n\t\t\t\t}\n\t\t\t}\n\t\t\tsort(all(crosses),[](tuple<D,int,Point> a, tuple<D,int,Point> b){\n\t\t\t\treturn get<0>(a) < get<0>(b);\n\t\t\t});\n\t\t\tif(crosses.empty()){\n\t\t\t\tf = false; break;\n\t\t\t}\n\t\t\tif(get<1>(crosses[0]) != mirrors[i]){\n\t\t\t\tf = false; break;\n\t\t\t}\n\t\t\tres += get<0>(crosses[0]);\n\t\t\tg = get<2>(crosses[0]);\n\t\t}\n\n\t\t{\n\t\t\tvector<pair<D,int>> crosses;\n\t\t\trep(j,n){\n\t\t\t\tSegment mir(ps[0][j],qs[0][j]);\n\t\t\t\tif(sz > 0 && mirrors[0] == j) continue;\n\t\t\t\tif(isIntersect(seg,mir,true)){\n\t\t\t\t\tPoint cr = crossPoint(seg,mir);\n\t\t\t\t\tcrosses.emplace_back(abs(cr-s),j);\n\t\t\t\t}\n\t\t\t}\n\t\t\tsort(all(crosses));\n\t\t\tif(!crosses.empty() && crosses[0].first <= abs(s-g) - eps){\n\t\t\t\tf = false;\n\t\t\t}\n\t\t}\n\n\t\tif(f) chmin(ans, res + abs(g-s));\n\t};\n\n\tauto dfs = [&](auto &&dfs, int now) -> void {\n\t\tif(now > 5) return;\n\t\tcheck();\n\t\trep(i,n){\n\t\t\tif(!mirrors.empty() && mirrors.back() == i) continue;\n\t\t\tmirrors.push_back(i);\n\t\t\tdfs(dfs,now+1);\n\t\t\tmirrors.pop_back();\n\t\t}\n\t};\n\tdfs(dfs,0);\n\t\n\tprintf(\"%.10Lf\\n\",ans);\n\treturn true;\n}\n\nint main(){\n\twhile(solve());\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3552, "score_of_the_acc": -0.5153, "final_rank": 11 }, { "submission_id": "aoj_1171_6022859", "code_snippet": "/*\tauthor: Kite_kuma\n\tcreated: 2021.11.02 17:19:16 */\n\n#ifdef LOCAL\n#define _GLIBCXX_DEBUG\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\n\n#pragma region macros\n\n#define foa(s, v) for(auto &s : v)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\n#define popcnt(n) __builtin_popcountll((long long)n)\n\n#define REPname(a, b, c, d, e, ...) e\n#define rep(...) REPname(__VA_ARGS__, REP3, REP2, REP1, REP0)(__VA_ARGS__)\n#define REP0(x) for(int Counter_in_rep_macro = 0; Counter_in_rep_macro < (x); ++Counter_in_rep_macro)\n#define REP1(i, x) for(int i = 0; i < (x); ++i)\n#define REP2(i, l, r) for(int i = (l); i < (r); ++i)\n#define REP3(i, l, r, c) for(int i = (l); i < (r); i += (c))\n\n#define DREPname(a, b, c, d, e, ...) e\n#define drep(...) DREPname(__VA_ARGS__, DREP3, DREP2, DREP1)(__VA_ARGS__)\n#define DREP1(i, x) for(int i = (x)-1; i >= 0; --i)\n#define DREP2(i, l, r) for(int i = (r)-1; i >= (l); --i)\n#define DREP3(i, l, r, c) for(int i = (r)-1; i >= (l); i -= (c))\n\n#pragma endregion\n\n#pragma region aliases\n\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\nusing vi = std::vector<int>;\nusing vvi = std::vector<std::vector<int>>;\nusing vvvi = std::vector<std::vector<std::vector<int>>>;\nusing vll = std::vector<ll>;\nusing vvll = std::vector<vll>;\nusing vvvll = std::vector<vvll>;\nusing pii = std::pair<int, int>;\nusing pll = std::pair<long long, long long>;\ntemplate <class T = ll>\nusing V = std::vector<T>;\ntemplate <class T = ll>\nusing VV = V<V<T>>;\ntemplate <class T = ll>\nusing VVV = V<V<V<T>>>;\ntemplate <class T = ll>\nusing pqup = std::priority_queue<T, std::vector<T>, std::greater<T>>;\ntemplate <class T = ll>\nusing pqdn = std::priority_queue<T>;\n\n#pragma endregion\n\n#pragma region constants\n\nconst int inf = 1e9;\nconst long long INF = 1e18;\nconst long double pi = acos(-1);\nconst char dl = '\\n';\nconst char sp = ' ';\nint dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};\nint dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};\n\nconst int mod_1000000007 = 1000000007;\nconst int mod_998244353 = 998244353;\n\n#pragma endregion\n\n#pragma region basic_operation\n\ntemplate <class T0, class T1, class T2>\ninline bool in_range(T0 x, T1 lef, T2 rig) {\n\treturn ((lef <= x) && (x < rig));\n}\n\ntemplate <class T>\ninline bool chmin(T &a, T b) {\n\tif(a > b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\ntemplate <class T>\ninline bool chmax(T &a, T b) {\n\tif(a < b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\n\nvoid Yes(bool f = 1) { std::cout << (f ? \"Yes\" : \"No\") << '\\n'; }\nvoid No() { std::cout << \"No\\n\"; }\nvoid YES(bool f = 1) { std::cout << (f ? \"YES\" : \"NO\") << '\\n'; }\nvoid NO() { std::cout << \"NO\\n\"; }\n\ntemplate <class T>\nvoid drop(T answer) {\n\tstd::cout << answer << '\\n';\n\texit(0);\n}\n\nvoid err(bool flag = true) {\n\tif(!flag) return;\n\tstd::cout << -1 << '\\n';\n\texit(0);\n}\n\ntemplate <class T>\nvoid vout(std::vector<T> const &v, bool vertically = 0) {\n\tif(vertically) {\n\t\tfor(auto const &a : v) {\n\t\t\tstd::cout << a << '\\n';\n\t\t}\n\t\treturn;\n\t}\n\tfor(auto it = v.begin(); it != v.end(); it++) {\n\t\tstd::cout << (*it);\n\t\tif(it != v.end() - 1) {\n\t\t\tstd::cout << ' ';\n\t\t}\n\t}\n\tstd::cout << '\\n';\n\treturn;\n}\n\ninline void print() { std::cout << '\\n'; }\ntemplate <class T>\ninline void print(T x) {\n\tstd::cout << x << '\\n';\n\treturn;\n}\ntemplate <typename Head, typename... Tail>\nvoid print(Head H, Tail... T) {\n\tstd::cout << H << \" \";\n\tprint(T...);\n}\n\ntemplate <class T>\nvoid add(std::vector<T> &v, T val) {\n\tfor(auto &a : v) a += val;\n\treturn;\n}\n\ntemplate <class T>\nT dup(T a, T b) {\n\tassert(b != 0);\n\treturn (a + b - 1) / b;\n}\n\ntemplate <class T>\nT greatest_lower_multiple(T x, T d) {\n\tif(d == 0) return 0;\n\tif(d < 0) d *= -1;\n\tT y = x % d;\n\tif(y < 0) y += d;\n\treturn x - y;\n}\n\ntemplate <class T>\nT least_upper_multiple(T x, T d) {\n\treturn -greatest_lower_multiple(-x, d);\n}\n\nlong long POW(long long a, long long n) {\n\tlong long res = 1;\n\twhile(n > 0) {\n\t\tif(n & 1) res = res * a;\n\t\ta = a * a;\n\t\tn >>= 1;\n\t}\n\treturn res;\n}\n\nlong long modpow(long long a, long long n, long long mod) {\t // a^n mod\n\tassert(n >= 0 && mod);\n\tif(mod == 1) return 0LL;\n\tlong long res = 1;\n\ta %= mod;\n\twhile(n > 0) {\n\t\tif(n & 1) res = res * a % mod;\n\t\ta = a * a % mod;\n\t\tn >>= 1;\n\t}\n\treturn res < 0 ? res + mod : res;\n}\n\n// return x which satisfies a * x % mod == gcd(a, mod)\n// not (mod | a)\nlong long modinv(long long a, long long mod) {\n\tlong long b = mod, u = 1, v = 0;\n\twhile(b) {\n\t\tlong long t = a / b;\n\t\ta -= t * b;\n\t\tstd::swap(a, b);\n\t\tu -= t * v;\n\t\tstd::swap(u, v);\n\t}\n\tu %= mod;\n\tif(u < 0) u += mod;\n\treturn u;\n}\n\ntemplate <class T>\nint lb(const std::vector<T> &a, const T x) {\n\treturn std::distance(a.begin(), std::lower_bound(a.begin(), a.end(), x));\n}\ntemplate <class T>\nint ub(const std::vector<T> &a, const T x) {\n\treturn std::distance(a.begin(), std::upper_bound(a.begin(), a.end(), x));\n}\ntemplate <class T>\nvoid unq_sort(std::vector<T> &a) {\n\tstd::sort(a.begin(), a.end());\n\ta.erase(std::unique(a.begin(), a.end()), a.end());\n}\ntemplate <class T>\nstd::vector<int> press(std::vector<T> &a) {\n\tauto vec = a;\n\tunq_sort(vec);\n\tstd::vector<int> ret;\n\tfor(auto &v : a) ret.push_back(lb(vec, v));\n\treturn ret;\n}\n\n#pragma endregion\n\n#pragma region input\n#define VEC(type, name, size) \\\n\tvector<type> name(size); \\\n\tscanner::INPUT(name)\n#define VVEC(type, name, h, w) \\\n\tvector<vector<type>> name(h, vector<type>(w)); \\\n\tscanner::INPUT(name)\n#define INT(...) \\\n\tint __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LL(...) \\\n\tlong long __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define STR(...) \\\n\tstring __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define CHR(...) \\\n\tchar __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define DBL(...) \\\n\tdouble __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LD(...) \\\n\tlong double __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define TPL3(type0, type1, type2, name) \\\n\tstd::tuple<type0, type1, type2> name; \\\n\tscanner::INPUT(name);\n#define TPL4(type0, type1, type2, type3, name) \\\n\tstd::tuple<type0, type1, type2, type3> name; \\\n\tscanner::INPUT(name);\n\nnamespace scanner {\ntemplate <class T>\nvoid scan(T &a) {\n\tstd::cin >> a;\n}\n\ntemplate <class T, class L>\nvoid scan(std::pair<T, L> &p) {\n\tscan(p.first);\n\tscan(p.second);\n}\n\ntemplate <class T0, class T1, class T2>\nvoid scan(std::tuple<T0, T1, T2> &p) {\n\tT0 t0;\n\tT1 t1;\n\tT2 t2;\n\tscan(t0);\n\tscan(t1);\n\tscan(t2);\n\tp = std::make_tuple(t0, t1, t2);\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid scan(std::tuple<T0, T1, T2, T3> &p) {\n\tT0 t0;\n\tT1 t1;\n\tT2 t2;\n\tT3 t3;\n\tscan(t0);\n\tscan(t1);\n\tscan(t2);\n\tscan(t3);\n\tp = std::make_tuple(t0, t1, t2, t3);\n}\n\ntemplate <class T>\nvoid scan(std::vector<T> &a) {\n\tfor(auto &i : a) scan(i);\n}\n\nvoid INPUT() {}\ntemplate <class Head, class... Tail>\nvoid INPUT(Head &head, Tail &... tail) {\n\tscan(head);\n\tINPUT(tail...);\n}\n} // namespace scanner\n\ntemplate <typename T1, typename T2>\nstd::istream &operator>>(std::istream &is, std::pair<T1, T2> &p) {\n\tis >> p.first >> p.second;\n\treturn is;\n}\n#pragma endregion\n\n#pragma region debug\n\n#pragma region output\ntemplate <typename T1, typename T2>\nstd::ostream &std::operator<<(std::ostream &os, const std::pair<T1, T2> &p) {\n\tos << p.first << \" \" << p.second;\n\treturn os;\n}\ntemplate <class T>\nstd::ostream &std::operator<<(std::ostream &os, const std::vector<T> &v) {\n\tfor(int i = 0; i < (int)v.size(); i++) {\n\t\tif(i) os << \" \";\n\t\tos << v[i];\n\t}\n\treturn os;\n}\n#pragma endregion\n\n#pragma region view\n\nnamespace viewer {\nvoid view(const long long e) {\n\tif(e == INF)\n\t\tstd::cerr << \"INF\";\n\telse if(e == -INF)\n\t\tstd::cerr << \"-INF\";\n\telse\n\t\tstd::cerr << e;\n}\n\nvoid view(const int e) {\n\tif(e == inf)\n\t\tstd::cerr << \"inf\";\n\telse if(e == -inf)\n\t\tstd::cerr << \"-inf\";\n\telse\n\t\tstd::cerr << e;\n}\n\ntemplate <typename T>\nvoid view(const T e) {\n\tstd::cerr << e;\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::pair<T, U> &p) {\n\tstd::cerr << \"(\";\n\tview(p.first);\n\tstd::cerr << \", \";\n\tview(p.second);\n\tstd::cerr << \")\";\n}\n\ntemplate <class T0, class T1, class T2>\nvoid view(const std::tuple<T0, T1, T2> &p) {\n\tstd::cerr << \"(\";\n\tview(std::get<0>(p));\n\tstd::cerr << \", \";\n\tview(std::get<1>(p));\n\tstd::cerr << \", \";\n\tview(std::get<2>(p));\n\tstd::cerr << \")\";\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid view(const std::tuple<T0, T1, T2, T3> &p) {\n\tstd::cerr << \"(\";\n\tview(std::get<0>(p));\n\tstd::cerr << \", \";\n\tview(std::get<1>(p));\n\tstd::cerr << \", \";\n\tview(std::get<2>(p));\n\tstd::cerr << \", \";\n\tview(std::get<3>(p));\n\tstd::cerr << \")\";\n}\n\ntemplate <typename T>\nvoid view(const std::set<T> &s) {\n\tif(s.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << \"{ \";\n\tfor(auto &t : s) {\n\t\tview(t);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <typename T>\nvoid view(const std::unordered_set<T> &s) {\n\tif(s.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << \"{ \";\n\tfor(auto &t : s) {\n\t\tview(t);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <typename T>\nvoid view(const std::vector<T> &v) {\n\tif(v.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << \"{ \";\n\tfor(const auto &e : v) {\n\t\tview(e);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <typename T>\nvoid view(const std::vector<std::vector<T>> &vv) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &v : vv) {\n\t\tstd::cerr << \"\\t\";\n\t\tview(v);\n\t\tstd::cerr << '\\n';\n\t}\n\tstd::cerr << \"}\";\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::vector<std::pair<T, U>> &v) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &c : v) {\n\t\tstd::cerr << \"\\t(\";\n\t\tview(c.first);\n\t\tstd::cerr << \", \";\n\t\tview(c.second);\n\t\tstd::cerr << \")\\n\";\n\t}\n\tstd::cerr << \"}\";\n}\n\ntemplate <class T0, class T1, class T2>\nvoid view(const std::vector<std::tuple<T0, T1, T2>> &v) {\n\tif(v.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << '{';\n\tfor(const auto &t : v) {\n\t\tstd::cerr << \"\\n\\t\";\n\t\tview(t);\n\t\tstd::cerr << \",\";\n\t}\n\tstd::cerr << \"\\n}\";\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid view(const std::vector<std::tuple<T0, T1, T2, T3>> &v) {\n\tif(v.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << '{';\n\tfor(const auto &t : v) {\n\t\tstd::cerr << \"\\n\\t\";\n\t\tview(t);\n\t\tstd::cerr << \",\";\n\t}\n\tstd::cerr << \"\\n}\";\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::map<T, U> &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &t : m) {\n\t\tstd::cerr << \"\\t[\";\n\t\tview(t.first);\n\t\tstd::cerr << \"] : \";\n\t\tview(t.second);\n\t\tstd::cerr << '\\n';\n\t}\n\tstd::cerr << \"}\";\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::unordered_map<T, U> &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &t : m) {\n\t\tstd::cerr << \"\\t[\";\n\t\tview(t.first);\n\t\tstd::cerr << \"] : \";\n\t\tview(t.second);\n\t\tstd::cerr << '\\n';\n\t}\n\tstd::cerr << \"}\";\n}\n} // namespace viewer\n\n#pragma endregion\n\n// when debugging : g++ foo.cpp -DLOCAL\n#ifdef LOCAL\nvoid debug_out() {}\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head H, Tail... T) {\n\tviewer::view(H);\n\tstd::cerr << \", \";\n\tdebug_out(T...);\n}\n#define debug(...) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"] : [\"; \\\n\t\tdebug_out(__VA_ARGS__); \\\n\t\tstd::cerr << \"\\b\\b]\\n\"; \\\n\t} while(0)\n#define dump(x) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" \" << #x << \" : \"; \\\n\t\tviewer::view(x); \\\n\t\tstd::cerr << '\\n'; \\\n\t} while(0)\n\n#else\n#define debug(...) (void(0))\n#define dump(x) (void(0))\n#endif\n\n#pragma endregion\n\n#pragma region geometry_light\n\nusing Real = long double;\nusing R = Real;\nusing Point = std::complex<Real>;\nusing Vec = Point;\nconst Real EPS = 1e-10, PI = acos(-1);\n\ninline bool eq(const Real &a, const Real &b) { return fabs(b - a) < EPS; }\ninline bool eq(const Point &a, const Point &b) { return fabs(b - a) < EPS; }\n/*\n\t-1: a < b\n\t0 : a == b\n\t1 : a > b\n*/\ninline int compare(const Real &a, const Real &b) { return eq(a, b) ? 0 : a < b ? -1 : 1; }\ninline int sign(const Real &a) { return fabs(a) < EPS ? 0 : a < 0 ? -1 : 1; }\n\nnamespace std {\nconst Point operator*(const Point &p, const Real &d) { return Point(real(p) * d, imag(p) * d); }\n} // namespace std\n\nstd::istream &operator>>(std::istream &is, Point &p) {\n\tReal a, b;\n\tis >> a >> b;\n\tp = Point(a, b);\n\treturn is;\n}\nstd::ostream &operator<<(std::ostream &os, Point &p) { return os << std::fixed << std::setprecision(10) << p.real() << \" \" << p.imag(); }\n\n// rotate point 'p' for counter clockwise direction\nconst Point rotate(const Real &theta, const Point &p) {\n\treturn Point(cos(theta) * p.real() - sin(theta) * p.imag(), sin(theta) * p.real() + cos(theta) * p.imag());\n}\n\nconst Real radian_to_degree(const Real &r) { return (r * 180.0 / PI); }\n\nconst Real degree_to_radian(const Real &d) { return (d * PI / 180.0); }\n\n// get angle a-b-c (<pi)\nconst Real get_angle(const Point &a, const Point &b, const Point &c) {\n\tconst Point v(a - b), w(c - b);\n\tReal theta = fabs(atan2(w.imag(), w.real()) - atan2(v.imag(), v.real()));\n\treturn std::min(theta, 2 * PI - theta);\n}\n\nnamespace std {\nbool operator<(const Point &a, const Point &b) { return a.real() != b.real() ? a.real() < b.real() : a.imag() < b.imag(); }\n} // namespace std\n\nstruct Line {\n\tPoint a, b;\n\n\tLine() = default;\n\n\tLine(Point a, Point b) : a(a), b(b) {}\n\n\tLine(Real A, Real B, Real C) // Ax + By = C\n\t{\n\t\tif(eq(A, 0))\n\t\t\ta = Point(0, C / B), b = Point(1, C / B);\n\t\telse if(eq(B, 0))\n\t\t\tb = Point(C / A, 0), b = Point(C / A, 1);\n\t\telse\n\t\t\ta = Point(0, C / B), b = Point(C / A, 0);\n\t}\n\n\tfriend std::ostream &operator<<(std::ostream &os, Line &p) { return os << p.a << \" -- \" << p.b; }\n\n\tfriend std::istream &operator>>(std::istream &is, Line &a) { return is >> a.a >> a.b; }\n};\n\nstruct Segment : Line {\n\tSegment() = default;\n\n\tSegment(Point a, Point b) : Line(a, b) {}\n};\n\nstruct Circle {\n\tPoint p;\n\tReal r;\n\n\tCircle() = default;\n\n\tCircle(Point p, Real r) : p(p), r(r) {}\n};\n\nusing Points = std::vector<Point>;\nusing Polygon = std::vector<Point>;\nusing Segments = std::vector<Segment>;\nusing Lines = std::vector<Line>;\nusing Circles = std::vector<Circle>;\n\nconst Real cross(const Point &a, const Point &b) { return real(a) * imag(b) - imag(a) * real(b); }\nconst Real dot(const Point &a, const Point &b) { return real(a) * real(b) + imag(a) * imag(b); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_C\nconst int ccw(const Point &a, Point b, Point c) {\n\tb = b - a, c = c - a;\n\tif(cross(b, c) > EPS) return +1;\t\t// \"COUNTER_CLOCKWISE\"\n\tif(cross(b, c) < -EPS) return -1;\t\t// \"CLOCKWISE\"\n\tif(dot(b, c) < -EPS) return +2;\t\t\t// \"ONLINE_BACK\"\n\tif(norm(b) + EPS < norm(c)) return -2;\t// \"ONLINE_FRONT\"\n\treturn 0;\t\t\t\t\t\t\t\t// \"ON_SEGMENT\"\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_A\nbool parallel(const Line &a, const Line &b) { return eq(cross(a.b - a.a, b.b - b.a), 0.0); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_A\nbool orthogonal(const Line &a, const Line &b) { return eq(dot(a.a - a.b, b.a - b.b), 0.0); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_A\nPoint projection(const Line &l, const Point &p) {\n\tdouble t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n\treturn l.a + (l.a - l.b) * t;\n}\n\nPoint projection(const Segment &l, const Point &p) {\n\tdouble t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n\treturn l.a + (l.a - l.b) * t;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_B\nPoint reflection(const Line &l, const Point &p) { return projection(l, p) * 2.0 - p; }\n\nint intersect(const Line &l, const Point &p) { return int(abs(ccw(l.a, l.b, p)) != 1); }\n\nint intersect(const Line &l, const Line &m) {\n\tif(intersect(l, m.a) && intersect(l, m.b)) return -1;\n\treturn int(abs(cross(l.b - l.a, m.b - m.a)) > EPS);\n}\n\nint intersect(const Segment &s, const Point &p) { return int(ccw(s.a, s.b, p) == 0); }\n\nint intersect(const Line &l, const Segment &s) {\n\tif(intersect(l, s.a) && intersect(l, s.b)) return -1;\n\treturn cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < EPS;\n}\n\nReal distance(const Line &l, const Point &p);\n\nint intersect(const Circle &c, const Line &l) {\n\tReal d = c.r - distance(l, c.p);\n\treturn fabs(d) < EPS ? 1 : d > 0. ? 2 : 0;\n}\n\nint intersect(const Circle &c, const Point &p) { return int(abs(abs(p - c.p) - c.r) < EPS); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_B\nint intersect(const Segment &s, const Segment &t) {\n\tif(eq(s.a, s.b)) return intersect(t, s.a);\n\tif(intersect(Line(s), t.a) && intersect(Line(s), t.b) &&\n\t std::max(std::min(s.a, s.b), std::min(t.a, t.b)) < std::min(std::max(s.a, s.b), std::max(t.a, t.b)))\n\t\treturn -1;\n\treturn int(ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 && ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0);\n}\n\nint intersect(const Circle &c, const Segment &l) {\n\tconst Point h = projection(l, c.p);\n\tif(norm(h - c.p) - c.r * c.r > EPS) return 0;\n\tauto d1 = abs(c.p - l.a), d2 = abs(c.p - l.b);\n\tif(compare(d1, c.r) == -1 && compare(d2, c.r) == -1) return 0;\n\tif(d1 < c.r - EPS && d2 > c.r - EPS || d1 > c.r - EPS && d2 < c.r - EPS) return 1;\n\treturn dot(l.a - h, l.b - h) < 0 ? 2 : 0;\n}\n\nReal distance(const Point &a, const Point &b);\n\nint number_of_common_tangents(const Circle &c1, const Circle &c2) {\n\tReal r1 = std::min(c1.r, c2.r), r2 = std::max(c1.r, c2.r), d = distance(c1.p, c2.p);\n\tint com = compare(r1 + r2, d);\n\treturn com == 1 ? compare(d + r1, r2) + 1 : 3 - com;\n\t// if(c1.r < c2.r) swap(c1, c2);\n\t// Real d = abs(c1.p - c2.p);\n\t// if(compare(c1.r + c2.r, d) == -1) return 4;\n\t// if(eq(c1.r + c2.r, d)) return 3;\n\t// if(compare(c1.r - c2.r, d) == -1) return 2;\n\t// return int(eq(c1.r - c2.r, d));\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_A&lang=jp\nint intersect(const Circle &c1, const Circle &c2) { return 2 - abs(2 - number_of_common_tangents(c1, c2)); }\n\nReal distance(const Point &a, const Point &b) { return abs(a - b); }\n\nReal distance(const Line &l, const Point &p) { return abs(p - projection(l, p)); }\n\nReal distance(const Line &l, const Line &m) { return intersect(l, m) ? 0 : distance(l, m.a); }\n\nReal distance(const Segment &s, const Point &p) {\n\tPoint r = projection(s, p);\n\treturn intersect(s, r) ? distance(r, p) : std::min(abs(s.a - p), abs(s.b - p));\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_D\nReal distance(const Segment &a, const Segment &b) {\n\tif(intersect(a, b)) return 0;\n\treturn std::min({distance(a, b.a), distance(a, b.b), distance(b, a.a), distance(b, a.b)});\n}\n\nReal distance(const Line &l, const Segment &s) {\n\tif(intersect(l, s)) return 0;\n\treturn std::min(distance(l, s.a), distance(l, s.b));\n}\n\nPoint crosspoint(const Line &l, const Line &m) {\n\tReal A = cross(l.b - l.a, m.b - m.a);\n\tReal B = cross(l.b - l.a, l.b - m.a);\n\tif(eq(abs(A), 0.0) && eq(abs(B), 0.0)) return m.a;\n\treturn m.a + (m.b - m.a) * B / A;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_C\nPoint crosspoint(const Segment &l, const Segment &m) { return crosspoint(Line(l), Line(m)); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_D\nstd::pair<Point, Point> crosspoint(const Circle &c, const Line l) {\n\tPoint pr = projection(l, c.p);\n\tif(eq(distance(l, c.p), c.r)) return {pr, pr};\n\tVec v = (l.b - l.a) / abs(l.b - l.a) * sqrt(c.r * c.r - norm(pr - c.p));\n\treturn make_pair(pr - v, pr + v);\n\t// Vec e = (l.b - l.a) / abs(l.b - l.a);\n\t// double base = sqrt(c.r * c.r - norm(pr - c.p));\n\t// return {pr - e * base, pr + e * base};\n}\n\nstd::pair<Point, Point> crosspoint(const Circle &c, const Segment &l) {\n\tif(intersect(c, l) == 2) return crosspoint(c, Line(l.a, l.b));\n\tauto ret = crosspoint(c, Line(l.a, l.b));\n\tif(dot(l.a - ret.first, l.b - ret.first) < EPS)\n\t\tret.second = ret.first;\n\telse\n\t\tret.first = ret.second;\n\treturn ret;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_E\nstd::pair<Point, Point> crosspoint(const Circle &c1, const Circle &c2) {\n\tReal d = abs(c1.p - c2.p);\n\tReal a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d)); // cosine theorem\n\tReal t = atan2(c2.p.imag() - c1.p.imag(), c2.p.real() - c1.p.real());\n\tPoint p1 = c1.p + Point(cos(t + a) * c1.r, sin(t + a) * c1.r);\n\tPoint p2 = c1.p + Point(cos(t - a) * c1.r, sin(t - a) * c1.r);\n\treturn make_pair(p1, p2);\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_F\n// \"点 p を通る円 c の接線\"の接点2つ\nstd::pair<Point, Point> tangent(const Circle &c1, const Point &p2) {\n\treturn crosspoint(c1, Circle(p2, sqrt(norm(c1.p - p2) - c1.r * c1.r)));\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_G\n// 円 c1, c2 の共通接線\nLines tangent(Circle c1, Circle c2) {\n\tLines ret;\n\tif(c1.r < c2.r) std::swap(c1, c2);\n\tReal g = norm(c1.p - c2.p);\n\tif(eq(g, 0)) return ret;\n\tVec u = (c2.p - c1.p) / Real(sqrt(g));\n\tVec v = rotate(PI * 0.5, u);\n\tfor(int s : {-1, 1}) {\n\t\tReal h = (c1.r + s * c2.r) / sqrt(g);\n\t\tif(eq(1 - h * h, 0)) {\n\t\t\tret.emplace_back(c1.p + u * c1.r, c1.p + (u + v) * c1.r);\n\t\t} else if(1 - h * h > 0) {\n\t\t\tPoint uu = u * h, vv = v * sqrt(1 - h * h);\n\t\t\tret.emplace_back(c1.p + (uu + vv) * c1.r, c2.p - (uu + vv) * c2.r * s);\n\t\t\tret.emplace_back(c1.p + (uu - vv) * c1.r, c2.p - (uu - vv) * c2.r * s);\n\t\t}\n\t}\n\treturn ret;\n}\n\n#pragma endregion\n\nSegment ref_seg(const Segment &mirror, const Segment &obj) {\n\treturn Segment(reflection(Line(mirror), obj.a), reflection(Line(mirror), obj.b));\n}\n\nR solve(int mirror_count) {\n\tSegments mirrors;\n\tPoint destination;\n\t{\n\t\tV<pair<Point, Point>> edges;\n\t\trep(mirror_count) {\n\t\t\tPoint p, q;\n\t\t\tcin >> p >> q;\n\t\t\tedges.emplace_back(p, q);\n\t\t}\n\t\tPoint p;\n\t\tcin >> p;\n\t\tPoint q;\n\t\tcin >> q;\n\t\tdestination = q - p;\n\t\tfoa(t, edges) { mirrors.emplace_back(t.first - p, t.second - p); }\n\t}\n\n\tV<Segments> images = {mirrors};\n\tvi yari;\n\n\tconst Point center(0, 0);\n\n\tauto is_valid = [&](Point goal, int reflect) {\n\t\tSegment path(center, goal);\n\t\tV<tuple<R, int, int>> crs;\n\t\tconst R dist_goal = abs(goal);\n\n\t\tdebug(goal);\n\n\t\trep(refl, reflect + 1) {\n\t\t\trep(mrid, mirror_count) {\n\t\t\t\t// debug(refl, mrid);\n\t\t\t\tif(intersect(images[refl][mrid], path)) {\n\t\t\t\t\t{\n\t\t\t\t\t\tauto seg = images[refl][mrid];\n\t\t\t\t\t\tdebug(seg.a, seg.b);\n\t\t\t\t\t}\n\t\t\t\t\tconst R dist = abs(crosspoint(images[refl][mrid], path));\n\t\t\t\t\tif(dist > dist_goal) continue;\n\t\t\t\t\tcrs.emplace_back(dist, refl, mrid);\n\n\t\t\t\t\tif(yari == vi{0}) debug(dist, refl, mrid);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t// debug(\"ok\");\n\t\tsort(all(crs));\n\t\tint cs = crs.size();\n\t\tint phase = 0;\n\t\trep(i, cs) {\n\t\t\tR dist;\n\t\t\tint ref, id;\n\t\t\ttie(dist, ref, id) = crs[i];\n\n\t\t\tif(ref != phase) {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tdebug(ref, reflect);\n\t\t\tif(ref > 0) {\n\t\t\t\tif(yari[ref - 1] == id) continue;\n\t\t\t}\n\t\t\tif(ref < reflect) {\n\t\t\t\tif(yari[ref] == id) {\n\t\t\t\t\tphase++;\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t}\n\t\t\treturn false;\n\t\t}\n\t\treturn phase == reflect;\n\t};\n\n\tR ans = INF;\n\tauto dfs = [&](auto dfs, Point goal, int reflect = 0) -> void {\n\t\t// debug(goal, reflect);\n\t\tconst auto tmp_mirrors = images[reflect];\n\t\t// debug(goal, reflect);\n\t\t// debug(goal, reflect);\n\t\tif(is_valid(goal, reflect)) {\n\t\t\tdebug(yari);\n\t\t\tchmin(ans, distance(center, goal));\n\t\t\tdebug(ans);\n\t\t}\n\t\t// debug(\"ok\");\n\t\tif(reflect < 5) {\n\t\t\trep(nxt_mirror, mirror_count) {\n\t\t\t\tSegments nxtset;\n\n\t\t\t\t// debug(\"ok\");\n\t\t\t\tfoa(m, tmp_mirrors) { nxtset.push_back(ref_seg(tmp_mirrors[nxt_mirror], m)); }\n\t\t\t\t// debug(\"ok\");\n\n\t\t\t\timages.push_back(nxtset);\n\t\t\t\tyari.push_back(nxt_mirror);\n\n\t\t\t\tdfs(dfs, reflection(Line(tmp_mirrors[nxt_mirror]), goal), reflect + 1);\n\t\t\t\t// debug(\"ok\");\n\n\t\t\t\tyari.pop_back();\n\t\t\t\timages.pop_back();\n\t\t\t}\n\t\t}\n\t\treturn;\n\t};\n\n\tdfs(dfs, destination);\n\n\treturn ans;\n}\n\nint main() {\n\tstd::ios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\tstd::cout << std::fixed << std::setprecision(15);\n\tsrand((unsigned)time(NULL));\n\n\tint n;\n\twhile(cin >> n && n) {\n\t\tcout << solve(n) << dl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 3628, "score_of_the_acc": -0.8895, "final_rank": 15 }, { "submission_id": "aoj_1171_6015793", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// template {{{\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\n\n#define range(i, l, r) for (i64 i = (i64)(l); i < (i64)(r); (i) += 1)\n#define rrange(i, l, r) for (i64 i = (i64)(r) - 1; i >= (i64)(l); (i) -= 1)\n\n#define whole(f, x, ...) ([&](decltype((x)) container) { return (f)( begin(container), end(container), ## __VA_ARGS__); })(x)\n#define rwhole(f, x, ...) ([&](decltype((x)) container) { return (f)( rbegin(container), rend(container), ## __VA_ARGS__); })(x)\n\n#define debug(x) cerr << \"(\" << __LINE__ << \")\" << #x << \": \" << (x) << endl\n\nconstexpr i32 inf = 1001001001;\nconstexpr i64 infll = 1001001001001001001ll;\n\nconstexpr i32 dx[] = {0, -1, 1, 0, -1, 1, -1, 1}; \nconstexpr i32 dy[] = {-1, 0, 0, 1, -1, -1, 1, 1};\n\nstruct IoSetup { IoSetup(i32 x = 15){ cin.tie(0); ios::sync_with_stdio(0); cout << fixed << setprecision(x); cerr << fixed << setprecision(x); } } iosetup;\n\ntemplate <typename T = i64> T input() { T x; cin >> x; return x; }\n\ntemplate <typename T> ostream &operator<<(ostream &os, vector<T> &v) { range(i, 0, v.size()) { os << v[i] << (i + 1 != (int)v.size() ? \" \" : \"\"); } return os; } \ntemplate <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; }\n\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, pair<T1, T2> p) { os << \"(\" << p.first << \", \" << p.second << \")\"; return os; }\ntemplate <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; }\n\ntemplate <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n// }}}\n\n// base\nnamespace geometry {\n using namespace std;\n using real_number = long double;\n\n const real_number PI = acosl(-1);\n\n inline static real_number &eps() {\n static real_number EPS = 1e-10;\n return EPS;\n }\n\n static void set_eps(real_number EPS) {\n eps() = EPS;\n }\n\n inline int sign(real_number r) {\n set_eps(1e-10);\n if (r < -eps()) return -1;\n if (r > +eps()) return +1;\n return 0;\n }\n\n inline bool equals(real_number r1, real_number r2) {\n return sign(r1 - r2) == 0;\n }\n}\n\n// point\nnamespace geometry {\n using point = complex< real_number >;\n using points = vector< point >;\n\n istream &operator>>(istream &is, point &p) {\n real_number x, y;\n is >> x >> y;\n p = point(x, y);\n return is;\n }\n\n ostream &operator<<(ostream &os, const point &p) {\n return os << p.real() << \" \" << p.imag();\n }\n\n point operator*(const point &p, const real_number &k) {\n return point(p.real() * k, p.imag() * k);\n }\n\n point rotate(const real_number &theta, const point &p) {\n return point(cos(theta) * p.real() + sin(-theta) * p.imag(),\n sin(theta) * p.real() + cos(-theta) * p.imag());\n }\n\n bool equals(const point &a, const point &b) {\n return equals(a.real(), b.real()) and equals(a.imag(), b.imag());\n }\n}\n\n// line \nnamespace geometry {\n struct line {\n point a, b;\n\n line() = default;\n line(point a, point b) : a(a), b(b) {}\n };\n\n using lines = vector< line >;\n}\n\n// segment\nnamespace geometry {\n struct segment : line {\n segment() = default;\n using line::line;\n };\n\n using segments = vector< segment >;\n}\n\n// product\nnamespace geometry {\n real_number cross(const point &a, const point &b) {\n return a.real() * b.imag() - a.imag() * b.real();\n }\n\n real_number dot(const point &a, const point &b) {\n return a.real() * b.real() + a.imag() * b.imag();\n }\n}\n\n// projection\nnamespace geometry {\n point projection(const line &l, const point &p) {\n real_number t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n }\n}\n\nnamespace geometry {\n point reflection(const line &l, const point &p) {\n return p + (projection(l, p) - p) * 2;\n }\n}\n\n// cross point\nnamespace geometry {\n point cross_point_ll(const line &l1, const line &l2) {\n real_number a = cross(l1.b - l1.a, l2.b - l2.a);\n real_number b = cross(l1.b - l1.a, l1.b - l2.a);\n if (equals(a, 0) && equals(b, 0)) return l2.a;\n return l2.a + (l2.b - l2.a) * b / a;\n }\n}\n\n// ccw\nnamespace geometry {\n constexpr int COUNTER_CLOCKWISE = +1;\n constexpr int CLOCKWISE = -1;\n constexpr int ONLINE_BACK = +2; // c-a-b\n constexpr int ONLINE_FRONT = -2; // a-b-c\n constexpr int ON_SEGMENT = 0; // a-c-b\n int ccw(const point &a, point b, point c) {\n b = b - a, c = c - a;\n if (sign(cross(b, c)) == +1) return COUNTER_CLOCKWISE;\n if (sign(cross(b, c)) == -1) return CLOCKWISE;\n if (sign(dot(b, c)) == -1) return ONLINE_BACK;\n if (norm(b) < norm(c)) return ONLINE_FRONT;\n return ON_SEGMENT;\n }\n}\n\n// intersect\nnamespace geometry {\n bool is_intersect(const segment &s1, const segment &s2) {\n return ccw(s1.a, s1.b, s2.a) * ccw(s1.a, s1.b, s2.b) <= 0 &&\n ccw(s2.a, s2.b, s1.a) * ccw(s2.a, s2.b, s1.b) <= 0;\n }\n}\n\nnamespace geometry {\n real_number distance_sp(const segment &s, const point &p) {\n point pr = projection(s, p);\n if (ccw(s.a, s.b, pr) == 0) return abs(pr - p);\n return min(abs(s.a - p), abs(s.b - p));\n }\n}\nusing namespace geometry;\n\nint n;\nsegments segs;\npoint l, t;\n\nreal_number calculate(const vector< int > &idxs) {\n if (idxs.size() == 0) {\n segment s(l, t);\n for (auto &seg : segs) {\n if (is_intersect(s, seg)) return inf;\n }\n\n return abs(l - t);\n }\n\n vector< segments > us;\n us.emplace_back(segs);\n\n vector< point > ts;\n ts.emplace_back(t);\n\n for (auto &i : idxs) {\n segments ss = us.back();\n point nt = ts.back();\n\n line refl = ss[i];\n for (auto &[a, b] : ss) {\n a = reflection(refl, a);\n b = reflection(refl, b);\n }\n nt = reflection(refl, nt);\n\n us.emplace_back(ss);\n ts.emplace_back(nt);\n }\n\n real_number res = abs(l - ts.back());\n\n segment shortest(l, ts.back());\n vector< int > uku(1, -1);\n for (auto &i : idxs) uku.emplace_back(i);\n uku.emplace_back(-1);\n\n range(i, 1, uku.size()) {\n if (uku[i] != -1 and not is_intersect(shortest, segs[uku[i]])) return inf;\n\n point nxt_a = (uku[i] == -1 ? t : cross_point_ll(shortest, segs[uku[i]]));\n segment s(shortest.a, nxt_a);\n range(j, 0, n) {\n if (j == uku[i - 1] or j == uku[i]) continue;\n if (is_intersect(s, segs[j])) return inf;\n }\n\n shortest.a = nxt_a;\n if (i + 1 != (int)uku.size()) shortest.b = reflection(segs[uku[i]], shortest.b);\n }\n\n return res;\n}\n\nreal_number dfs(int depth, vector< int > &idxs) {\n real_number res = inf;\n\n if (depth >= 6) return res;\n range(i, 0, n) {\n if (not idxs.empty() and idxs.back() == i) continue;\n idxs.emplace_back(i);\n chmin(res, dfs(depth + 1, idxs));\n idxs.pop_back();\n }\n\n chmin(res, calculate(idxs));\n \n return res;\n}\n\nvoid solve(int n) {\n segs.clear();\n range(i, 0, n) {\n point a, b;\n cin >> a >> b;\n\n segs.emplace_back(a, b);\n }\n\n cin >> t >> l;\n\n vector< int > idxs;\n cout << dfs(0, idxs) << endl;\n}\n\nsigned main() {\n while (cin >> n, n) {\n solve(n);\n }\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3420, "score_of_the_acc": -0.4066, "final_rank": 9 }, { "submission_id": "aoj_1171_6009447", "code_snippet": "#include<bits/stdc++.h> \nusing namespace std;\nusing ll=long long int;\n//using Int=__int128;\n#define ALL(A) A.begin(),A.end()\ntemplate<typename T1,typename T2> bool chmin(T1 &a,T2 b){if(a<=b)return 0; a=b; return 1;}\ntemplate<typename T1,typename T2> bool chmax(T1 &a,T2 b){if(a>=b)return 0; a=b; return 1;}\ntemplate<typename T> constexpr int bitUP(T x,int a){return (x>>a)&1;}\n//→ ↓ ← ↑ \nint dh[4]={0,1,0,-1}, dw[4]={1,0,-1,0};\n//右上から時計回り\n//int dh[8]={-1,0,1,1,1,0,-1,-1}, dw[8]={1,1,1,0,-1,-1,-1,0};\n//long double EPS = 1e-6;\n//long double PI = acos(-1);\n//const ll INF=(1LL<<62);\nconst int MAX=(1<<30);\nconstexpr ll MOD=1000000000+7;\n//constexpr ll MOD=998244353;\n\n\ninline void bin101(){\n ios::sync_with_stdio(false);\n cin.tie(0);\n cout << fixed << setprecision(20);\n}\n\nusing Graph=vector<vector<int>>;\n\ntemplate<typename T >\nstruct edge {\n\tint to;\n\tT cost;\n\tedge()=default;\n\tedge(int to, T cost) : to(to), cost(cost) {}\n\n};\ntemplate<typename T>\nusing WeightGraph=vector<vector<edge<T>>>;\n\n//要素数n 初期値x\ntemplate<typename T>\ninline vector<T> vmake(size_t n,T x){\n\treturn vector<T>(n,x);\n}\n\n//a,b,c,x data[a][b][c] 初期値x\ntemplate<typename... Args>\nauto vmake(size_t n,Args... args){\n\tauto v=vmake(args...);\n\treturn vector<decltype(v)>(n,move(v));\n}\n\n////////////////////////////\n// マクロや型\n////////////////////////////\n\nusing DD=long double;\n\nconst DD EPS=1e-9;\nconst DD INF=1e50;\nconst DD PI=acosl(-1.0);\n#define EQ(a,b) (abs( (a) - (b) )<EPS) //a==b\n#define LS(a,b) ( (a)+EPS<(b) ) //a<b\n#define GR(a,b) ( (a)>(b)+EPS ) //a>b\n#define LE(a,b) ( (a)<(b)+EPS ) //a<=b\n#define GE(a,b) ( (a)>(b)-EPS ) //a>=b\n\n#define X real()\n#define Y imag()\n\n\n//点\nusing Point=complex<DD>;\nistream &operator>>(istream &is, Point &p) {\n DD x,y;\n is>>x>>y;\n p=Point(x,y);\n return is;\n}\n\n//点a→点bの線分\n//aとbが等しい時、色々バグるから注意!\nstruct Segment{\n Point a,b;\n Segment()=default;\n Segment(Point a,Point b) :a(a),b(b){}\n Segment(DD ax,DD ay,DD bx,DD by):a(ax,ay),b(bx,by){}\n Segment(DD r,Point a) :a(a),b(a+polar((DD)1.0,r)){} \n};\nusing Line=Segment;\n\n//円\nstruct Circle{\n Point p;\n DD r;\n Circle()=default;\n Circle(Point p,DD r):p(p),r(r){}\n};\n\nusing Polygon=vector<Point>;\n\n////////////////////////////\n// 基本計算\n////////////////////////////\n\n//度→ラジアン\ninline DD torad(const DD deg){return deg*PI/180;}\n//ラジアン→度\ninline DD todeg(const DD rad){return rad*180/PI;}\n//内積 |a||b|cosθ\ninline DD dot(const Point &a,const Point &b){return (conj(a)*b).X;}\n//外積 |a||b|sinθ\ninline DD cross(const Point &a,const Point &b){return (conj(a)*b).Y;}\n//ベクトルpを反時計回りにtheta(ラジアン)回転\nPoint rotate(const Point &p,const DD theta){return p*Point(cos(theta),sin(theta));}\n\n//余弦定理 cos(角度abc(ラジアン))を返す\n//長さの対応に注意 ab:辺abの長さ\n//verify:https://codeforces.com/gym/102056/problem/F\nDD cosine_formula(const DD ab,const DD bc,const DD ca){\n return (ab*ab+bc*bc-ca*ca)/(2*ab*bc);\n}\n\ninline bool xy_sort(const Point &a,const Point &b){\n if(a.X+EPS<b.X) return true;\n if(EQ(a.X,b.X) && a.Y+EPS<b.Y) return true;\n return false;\n}\ninline bool yx_sort(const Point &a,const Point &b){\n if(a.Y+EPS<b.Y) return true;\n if(EQ(a.Y,b.Y) && a.X+EPS<b.X) return true;\n return false;\n}\nnamespace std{\n inline bool operator<(const Point &a,const Point &b)noexcept{\n return xy_sort(a,b);\n }\n}\n//DDの比較関数\n//map<DD,vector<pii>,DDcom>\nstruct DDcom{\n bool operator()(const DD a, const DD b) const noexcept {\n return a+EPS<b;\n }\n};\n\n\n////////////////////////////\n// 平行や直交\n////////////////////////////\n\nbool isOrthogonal(const Point &a,const Point &b){\n return EQ(dot(a,b),0.0);\n}\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_A\nbool isOrthogonal(const Segment &s,const Segment &t){\n return EQ(dot(s.a-s.b,t.a-t.b),0.0);\n}\nbool isParallel(const Point &a,const Point &b){\n return EQ(cross(a,b),0.0);\n}\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_A\nbool isParallel(const Segment &s,const Segment &t){\n return EQ(cross(s.a-s.b,t.a-t.b),0);\n}\n//線分a→bに対して点cがどの位置にあるか\n//反時計回り:1 時計回り:-1 直線上(a,b,c:-2 a,c,b:0 c,a,b:2)\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_C\n//線分a→bの端点にcがあるなら0と判定されるはず\nint ccw(const Point &a,Point b,Point c){\n if(EQ(abs(b-c),0) or EQ(abs(a-c),0)) return 0;\n b-=a;c-=a;\n if(cross(b,c)>EPS) return 1;\n if(cross(b,c)<-EPS) return -1;\n if(dot(b,c)<-EPS) return 2;\n if(LS(norm(b),norm(c))) return -2;\n return 0;\n}\n\n////////////////////////////\n// 射影と反射\n////////////////////////////\n\n//射影\n//直線lに点pから垂線を引いたときの交点\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_A\nPoint project(const Point &p,const Line &l){\n Point base=l.b-l.a;\n DD r=dot(p-l.a,base)/norm(base);\n return l.a+base*r;\n}\n//反射\n//直線lに対して点pと対称な点\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_B\nPoint reflect(const Point &p,const Line &l){\n return p+(project(p,l)-p)*(DD)2.0;\n}\n//反射\n//直線lに対して線分sと対称な線分(直線でも使える)\n//verify:\nSegment reflect(const Segment &s,const Line &l){\n return Segment(reflect(s.a,l) , reflect(s.b,l));\n}\n\n////////////////////////////\n// 点との距離\n////////////////////////////\n\n//点と直線の距離\nDD DistPL(const Point &p,const Line &l){\n return abs(cross(l.b-l.a,p-l.a))/abs(l.b-l.a);\n}\n//点と線分の距離\nDD DistPS(const Point &p,const Segment &s){\n if( dot(s.b-s.a,p-s.a)<0.0 ) return abs(p-s.a);\n if( dot(s.a-s.b,p-s.b)<0.0 ) return abs(p-s.b);\n return DistPL(p,s);\n}\n\n////////////////////////////\n// 線分と直線\n////////////////////////////\n\n//線分a-b,c-dは交差するか?\n//接する場合も交差すると判定\n//接する場合は交差しないとするなら<=を<に変換\nbool intersect(const Point &a,const Point &b,const Point &c,const Point &d){\n return(ccw(a,b,c)*ccw(a,b,d)<=0 && ccw(c,d,a)*ccw(c,d,b)<=0);\n}\n//線分s,tは交差するか?\n//接する場合も交差すると判定\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_B&lang=ja\n//接する場合は交差しないとするならintersectの<=を<に変換\nbool intersect(const Segment &s,const Segment &t){\n return intersect(s.a,s.b,t.a,t.b);\n}\n// 2直線の交点\n// 線分の場合はintersectをしてから使う\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_C&lang=ja\nPoint crossPoint(const Line &s,const Line &t){\n Point base=t.b-t.a;\n DD d1=cross(base,t.a-s.a);\n DD d2=cross(base,s.b-s.a);\n if(EQ(d1,0) and EQ(d2,0)) return s.a; //同じ直線\n if(EQ(d2,0)) assert(false); //交点がない\n return s.a+d1/d2*(s.b-s.a);\n}\n//線分と線分の距離\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_D&lang=ja\nDD Dist(const Segment &s,const Segment &t){\n if(intersect(s,t)) return 0.0;\n return min(min(DistPS(t.a,s),DistPS(t.b,s)),min(DistPS(s.a,t),DistPS(s.b,t)) );\n}\nbool issame(const Line &l,const Line &m){\n if (GR(abs(cross(m.a - l.a, l.b - l.a)),0) ) return false;\n if (GR(abs(cross(m.b - l.a, l.b - l.a)),0) ) return false;\n return true;\n}\n\n////////////////////////////\n// 円\n////////////////////////////\n//直線lと円Cの交点\n//l.aにより近い方がindexが小さい\n//veirfy:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_D\nvector<Point> crossPointLC(const Line &l,const Circle &c){\n vector<Point> ret;\n if(GR(DistPL(c.p,l),c.r)) return ret; //交点がないとき、空ベクトルを返す\n Point pr=project(c.p,l);\n Point e=(l.b-l.a)/(abs(l.b-l.a));\n DD base=sqrt(c.r*c.r-norm(pr-c.p));\n ret.push_back(pr-e*base);\n ret.push_back(pr+e*base);\n if(EQ(DistPL(c.p,l),c.r)) ret.pop_back(); //接するとき\n return ret;\n}\n//線分sと円cの交点\n//交点がないときは空ベクトルを返す\n//線分の端が交わる場合も交点とみなす\n//s.aにより近い方がindexが小さい\nvector<Point> crossPointSC(const Segment &s,const Circle &c){\n vector<Point> ret;\n if(DistPS(c.p,s)>c.r+EPS) return ret;\n auto koho=crossPointLC(s,c);\n for(auto p:koho){\n if(ccw(s.a,s.b,p)==0 or EQ(abs(p-s.a),0) or EQ(abs(p-s.b),0)) ret.push_back(p);\n }\n return ret;\n}\n\n//円aと円bの共通接線の数\n//離れている:4 外接:3 交わる:2 内接:1 内包:0\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_A\nint intersect(const Circle &a,const Circle &b){\n DD d=abs(a.p-b.p);\n if(GR(d,a.r+b.r)) return 4;\n if(EQ(d,a.r+b.r)) return 3;\n if(EQ(d,abs(a.r-b.r))) return 1;\n if(LS(d,abs(a.r-b.r))) return 0;\n return 2;\n}\n\n//円aと円bの交点\n//交点がないときは空ベクトルを返す\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_E\nvector<Point> crossPoint(const Circle &a,const Circle &b){\n vector<Point> ret;\n if(GR(abs(a.p-b.p),a.r+b.r)) return ret;\n DD d=abs(a.p-b.p);\n DD s=acosl((a.r*a.r+d*d-b.r*b.r)/(2*a.r*d)); //0~π\n DD t=arg(b.p-a.p);\n if(EQ(a.r+b.r,d)) ret.push_back(a.p+polar(a.r,t));\n else ret.push_back(a.p+polar(a.r,t+s)),ret.push_back(a.p+polar(a.r,t-s));\n return ret;\n}\n\n//点pから円cに接線を引いたときの接点\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_F&lang=ja\nvector<Point> TanLine(const Point &p,const Circle &c){\n vector<Point> ret;\n DD d=abs(p-c.p);\n if(LS(d,c.r)) return ret; //pがcの内部にある場合\n if(EQ(d,c.r)){\n ret.push_back(p);\n return ret; //円の線上にある場合\n } \n return crossPoint(c,Circle(p,sqrt(d*d-c.r*c.r)));\n}\n\n//円a,bの共通接線\n//https://www.slideshare.net/kujira16/ss-35861169\n//Line.aは円aと接線の交点\n//(接線と円bの交点)と(接線と円aの交点)が違う場合はLine.bは(接線と円bの交点)\n//一致する場合は円aの中心からLine.aに向かうベクトルを反時計回りに90度回転したものを\n//Line.aに足したもの\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_G\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=2201\nvector<Line> TanLine(const Circle &a,const Circle &b){\n DD d=abs(a.p-b.p);\n vector<Line> ret;\n //外接線\n if(intersect(a,b)>=2){\n if(EQ(a.r,b.r)){\n Point up=polar(a.r,arg(b.p-a.p)+PI/2);\n ret.emplace_back(a.p+up,b.p+up);\n ret.emplace_back(a.p-up,b.p-up);\n }else{\n Point q=(a.p*b.r-b.p*a.r)/(b.r-a.r);\n auto as=TanLine(q,a);\n auto bs=TanLine(q,b);\n assert(as.size()==2 and bs.size()==2);\n for(int i=0;i<2;i++){\n ret.emplace_back(as[i],bs[i]);\n }\n }\n }else if(intersect(a,b)==1){ //内接する場合\n Point dir;\n if(a.r>b.r) dir=polar(a.r,arg(b.p-a.p));\n else dir=polar(a.r,arg(a.p-b.p));\n ret.emplace_back(a.p+dir,a.p+dir+rotate(dir,PI/2));\n }\n //内接線\n if(GR(abs(a.p-b.p),a.r+b.r)){ //円が離れている場合\n Point q=a.p+(b.p-a.p)*a.r/(a.r+b.r);\n auto as=TanLine(q,a);\n auto bs=TanLine(q,b);\n assert(as.size()==2 and bs.size()==2);\n for(int i=0;i<2;i++){\n ret.emplace_back(as[i],bs[i]);\n }\n }else if(EQ(d,a.r+b.r)){ //円が接している場合\n Point dir=polar(a.r,arg(b.p-a.p));\n ret.emplace_back(a.p+dir,a.p+dir+rotate(dir,PI/2));\n }\n return ret;\n}\n//2つの円の共通部分の面積\n//参考: https://tjkendev.github.io/procon-library/python/geometry/circles_intersection_area.html\n//verify: https://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=6005736#1\nDD Area(const Circle &c1,const Circle &c2){\n DD cd=abs(c1.p-c2.p);\n if(LE(c1.r+c2.r,cd)) return 0; //円が離れている\n\n if(LE(cd,abs(c1.r-c2.r))) //片方の円が他方を包んでいる\n return min(c1.r,c2.r)*min(c1.r,c2.r)*PI;\n\n DD theta1=acosl(cosine_formula(c1.r,cd,c2.r));\n DD theta2=acosl(cosine_formula(c2.r,cd,c1.r));\n\n return c1.r*c1.r*theta1+c2.r*c2.r*theta2-c1.r*cd*sin(theta1);\n}\n\n\n////////////////////////////\n// 三角形\n////////////////////////////\n\n//ヘロンの公式 三角形の面積を返す\n//三角形が成立するか(平行ではないか)を忘れずに\nDD Heron(const DD ad,const DD bd,const DD cd){\n DD s=(ad+bd+cd)/2;\n return sqrt(s*(s-ad)*(s-bd)*(s-cd));\n}\n//三角形の外接円\n//isParallel()を使って三角形が成立するか(平行ではないか)を忘れずに\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_C\nCircle CircumscribedCircle(const Point &a,const Point &b,const Point &c){\n Point bc=(b+c)/(DD)2.0;\n Line aa(bc,bc+rotate(c-b,PI/2));\n Point ab=(a+b)/(DD)2.0;\n Line cc(ab,ab+rotate(b-a,PI/2));\n Point p=crossPoint(aa,cc);\n return Circle(p,abs(a-p));\n}\n//三角形の内接円\n//isParallel()を使って三角形が成立するか(平行ではないか)を忘れずに\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_B\nCircle InCircle(const Point &a,const Point &b,const Point &c){\n Line aa(a,a+polar((DD)1.0,(arg(b-a)+arg(c-a))/(DD)2.0));\n Line bb(b,b+polar((DD)1.0,(arg(a-b)+arg(c-b))/(DD)2.0));\n Point p=crossPoint(aa,bb);\n return Circle(p,DistPL(p,Line(a,b)));\n}\n\n////////////////////////////\n// 多角形\n////////////////////////////\n\n//点pが多角形gに対してどの位置にあるか\n//中:2 辺上:1 外:0\n//凸多角形である必要ない\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_C\nint contains(const Point &p,const vector<Point> &g){\n int n=(int)g.size();\n int x=false;\n for(int i=0;i<n;i++){\n Point a=g[i]-p,b=g[(i+1)%n]-p;\n if(EQ(cross(a,b),0) && dot(a,b)<EPS) return 1;\n if(a.Y>b.Y) swap(a,b);\n if(a.Y<EPS && EPS<b.Y && cross(a,b)>EPS) x=!x;\n }\n return (x?2:0);\n}\n//凸性判定\n//多角形gは凸か?\n//gは反時計回りでも時計回りでもいい\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_B\nbool isConvex(const vector<Point> &g){\n int n=(int)g.size();\n if(n<=3) return true;\n int flag=0;\n int t;\n for(int i=0;i<n;i++){\n Point a(g[(i+1)%n]-g[i]),b(g[(i+2)%n]-g[i]);\n if(cross(a,b)>EPS) t=1;\n else if(cross(a,b)<-EPS) t=-1;\n else continue;\n if(flag==-t) return false;\n flag=t;\n }\n return true;\n}\n\n//凸包 アンドリューのアルゴリズム\n//O(NlogN)\n//反時計回りの多角形を返す\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_4_A\nvector<Point> ConvexHull(vector<Point> s,const bool on_edge){\n int j;\n if(on_edge) j=-1;\n else j=1;\n int sz=(int)s.size();\n if(sz<3) return s;\n sort(s.begin(),s.end(),yx_sort);\n\n int n=0;\n vector<Point> res(2*sz);\n for(int i=0;i<sz;i++){\n while(n>=2 && cross(res[n-1]-res[n-2],s[i]-res[n-2])<EPS*j){\n n--;\n }\n res[n]=s[i];\n n++;\n }\n int t=n+1;\n for(int i=sz-2;i>=0;i--){\n while(n>=t && cross(res[n-1]-res[n-2],s[i]-res[n-2])<EPS*j){\n n--;\n }\n res[n]=s[i];\n n++;\n }\n res.resize(n-1);\n return res;\n}\n\n//多角形g(凸でなくてもいい)の符号付き面積\n//反時計回りの多角形なら正の値を返す 時計回りなら負\n//O(N)\n//https://imagingsolution.net/math/calc_n_point_area/\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_A\nDD Area(const vector<Point> &g){\n DD ret=0.0;\n int n=(int)g.size();\n for(int i=0;i<n;i++){\n ret+=cross(g[i],g[(i+1)%n]);\n }\n return ret/2.0;\n}\n\n//凸多角形gを直線lで切断\n//直線の左側(向きを考慮)にできる凸多角形を返す\n//多角形gが反時計回りならば、反時計回りで返す(時計回りなら時計回り)\n//直線上の頂点を含む線分の交点は含めてない\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_4_C\nvector<Point> ConvexCut(const vector<Point> &g,const Line &l){\n vector<Point> ret;\n int gz=(int)g.size();\n for(int i=0;i<gz;i++){\n Point now=g[i],next=g[(i+1)%gz];\n if(ccw(l.a,l.b,now)!=-1) ret.push_back(now);\n if(EQ(DistPL(now,l),0) or EQ(DistPL(next,l),0)) continue;\n if(ccw(l.a,l.b,now)*ccw(l.a,l.b,next)<0){\n ret.push_back(crossPoint(Line(now,next),l));\n }\n }\n return ret;\n}\n//部品\ninline DD calc(const Point &a,const Point &b,const DD &r,const bool triangle){\n if(triangle) return cross(a,b);\n else return r*r*arg(b/a);\n}\n//部品\nDD calcArea(const DD &r,const Point &a,const Point &b){\n if(EQ(abs(a-b),0)) return 0;\n bool ina=(abs(a)<r+EPS);\n bool inb=(abs(b)<r+EPS);\n if(ina && inb) return cross(a,b);\n auto cr=crossPointSC(Segment(a,b),Circle(Point(0,0),r));\n if(cr.empty()) return calc(a,b,r,false);\n auto s=cr[0],t=cr.back();\n return calc(s,t,r,true)+calc(a,s,r,ina)+calc(t,b,r,inb);\n}\n//円と多角形の共通部分の面積\n//多角形が反時計回りならば正の値を返す\n//凸多角形でなくても大丈夫\n//http://drken1215.hatenablog.com/entry/2020/02/02/091000\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_H&lang=ja\nDD Area(const Circle &c,const vector<Point> &g){\n DD ret=0.0;\n int gz=g.size();\n if(gz<=2) return ret;\n for(int i=0;i<gz;i++){\n Point a=g[i]-c.p,b=g[(i+1)%gz]-c.p;\n ret+=calcArea(c.r,g[i]-c.p,g[(i+1)%gz]-c.p);\n }\n return ret/2.0;\n}\n\n//点と多角形の距離\n//点が多角形の中にあるなら0\nDD Dist(const Point &a,const vector<Point> &b){\n\tif(b.size()==1) return abs(a-b[0]);\n\tif(contains(a,b)>=1) return 0.0L;\n\tDD ret=INF;\n\tfor(int i=0;i<b.size();i++){\n\t\tchmin(ret,DistPS(a,Segment(b[i],b[(i+1)%b.size()])));\n\t}\n\treturn ret;\n}\n\n//多角形と多角形の距離\n//どちらかが内側に入っていたら0\n//全ての線分の組み合わせの距離を求めて、その最小が答え\n//O(size(a)*size(b))\n//sizeが1の時は点との距離になる\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=2827\nDD Dist(const vector<Point> &a,const vector<Point> &b){\n\tDD ret=INF;\n\tif(a.size()==1) return Dist(a[0],b);\n\tif(b.size()==1) return Dist(b[0],a);\n\n\tif(contains(a[0],b)>=1) return 0.0L;\n\tif(contains(b[0],a)>=1) return 0.0L;\n\n\tfor(int i=0;i<a.size();i++){\n\t\tfor(int j=0;j<b.size();j++){\n\t\t\tSegment sa(a[i],a[(i+1)%a.size()]);\n\t\t\tSegment sb(b[j],b[(j+1)%b.size()]);\n\t\t\tchmin(ret,Dist(sa,sb));\n\t\t}\n\t}\n\treturn ret;\n}\n\n////////////////////////////\n// 最近(遠)点間距離\n////////////////////////////\n//部品\nDD RecClosetPair(const vector<Point>::iterator it,const int n){\n if(n<=1) return INF;\n int m=n/2;\n DD x=it[m].X;\n DD d=min(RecClosetPair(it,m),RecClosetPair(it+m,n-m));\n inplace_merge(it,it+m,it+n,yx_sort);\n vector<Point> v;\n for(int i=0;i<n;i++){\n if(abs(it[i].X-x)>=d) continue;\n for(int j=0;j<v.size();j++){\n DD dy=it[i].Y-v[(int)v.size()-1-j].Y;\n if(dy>=d) break;\n DD dx=it[i].X-v[(int)v.size()-1-j].X;\n d=min(d,sqrt(dx*dx+dy*dy));\n }\n v.push_back(it[i]);\n }\n return d;\n}\n//最近点対の距離\n//点が1つのときINFを返す\n//O(NlogN)\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_5_A\nDD ClosetPair(vector<Point> g){\n sort(g.begin(),g.end(),xy_sort);\n return RecClosetPair(g.begin(),g.size());\n}\n\n//最遠頂点間\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_4_B\nDD Diameter(vector<Point> g){\n g=ConvexHull(g,1);\n int gz=g.size();\n int m=0,M=0;\n for(int i=1;i<gz;i++){\n if(g[i].Y<g[m].Y) m=i;\n if(g[i].Y>g[M].Y) M=i;\n }\n DD ret=0;\n int sm=m,sM=M;\n while(m!=sM || M!=sm){\n ret=max(ret,norm(g[m]-g[M]));\n if(cross(g[(m+1)%gz]-g[m],g[(M+1)%gz]-g[M])<0) m=(m+1)%gz;\n else M=(M+1)%gz;\n }\n return sqrt(ret);\n}\n//動的凸包\n//辺上にある点は含めない\n//verify:https://atcoder.jp/contests/geocon2013/tasks/geocon2013_c\nstruct DynamicConvex{\n\tset<Point> up,down;\n\tDynamicConvex(){}\n \n\tbool isContain(set<Point> &pol,Point p){\n\t\tif(pol.size()==0) return false;\n\t\tif(pol.size()==1){\n\t\t\tPoint q=*begin(pol);\n\t\t\treturn EQ(q.X,p.X) and GE(q.Y,p.Y);\n\t\t}\n\t\tassert(pol.size()>=2);\n auto left=begin(pol);\n auto right=(--end(pol));\n if(LS(p.X,left->X) or GR(p.X,right->X)) return false;\n \n \n auto q1=pol.upper_bound(Point(p.X,INF));\n if(q1==end(pol)){\n return GE(right->Y,p.Y);\n }\n auto q2=q1--; //q1が範囲外になるのは最初に弾いてる\n return GE(cross(p-*q1,*q2-*q1),0.0);\n\t}\n bool isContain(Point p){\n if(not isContain(up,p)) return false;\n if(not isContain(down,Point(p.X,-p.Y))) return false;\n return true;\n }\n \n\tvoid add(set<Point> &pol,Point p){\n\t\tif(pol.size()==0){\n\t\t\tpol.insert(p);\n\t\t\treturn;\n\t\t}\n\t\tif(pol.size()==1){\n Point q=*begin(pol);\n\t\t\tif(EQ(q.X,p.X)){\n pol.clear();\n pol.insert(max(p,q));\n\t\t\t}else{\n\t\t\t\tpol.insert(p);\n\t\t\t}\n return;\n\t\t}\n assert(pol.size()>=2);\n if(isContain(pol,p)) return;\n //left\n auto q1=pol.upper_bound(Point(p.X,INF));\n if(q1!=begin(pol)){\n q1--;\n while(pol.size()>=1 and q1!=begin(pol)){\n auto q2=q1--;\n if(GR(cross(*q2-p,*q1-p),0)) break;\n pol.erase(q2);\n }\n }\n //right\n q1=pol.lower_bound(Point(p.X,-INF));\n if(q1!=end(pol)){\n while(pol.size()>1 and q1!=--end(pol)){\n auto q2=q1++;\n if(GR(cross(*q1-p,*q2-p),0.0)) break;\n pol.erase(q2);\n }\n }\n pol.insert(p);\n\t}\n \n\tvoid add(Point p){\n\t\tadd(up,p);\n\t\tadd(down,Point(p.X,-p.Y)); //upと同じように処理をしたいから\n\t}\n};\n\n//垂直二等分線\n//p-↑-q こんなかんじ\n//voronoiで使う\nLine bisector(const Point &p, const Point &q) {\n Point c=(p+q)/DD(2.0);\n Point v=rotate(q-p,PI/2);\n v/=abs(v);\n return Line(c-v,c+v);\n}\n\n//ボロノイ図\n//pol:全体 ps:点の集合 id:中心となる点の添字 pp:中心となる点\n//計算量: pol.size()*ps.size()\n//verify: https://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=6005648#1\nvector<Point> voronoi(Polygon pol,const vector<Point> &ps,int id=-1,const Point pp=Point()){\n Point p;\n if(id!=-1) p=ps[id];\n else p=pp;\n for(size_t i=0;i<ps.size();i++){\n if(i==id) continue;\n Line l=bisector(p,ps[i]);\n pol=ConvexCut(pol,l);\n }\n return pol;\n}\nint N;\nvector<Segment> mirror;\nPoint start,goal;\nDD ans=INF;\nvector<int> v;\n\nvoid dfs(int depth){\n if(depth<5){\n for(int i=0;i<N;i++){\n v.push_back(i);\n dfs(depth+1);\n if(v.back()==-1) v.pop_back();\n v.pop_back();\n }\n }\n //試す\n//goalを線対称に移動\n auto g=goal;\n auto m=mirror;\n for(int i=0;i<v.size();i++){\n g=reflect(g,m[v[i]]);\n for(int j=0;j<N;j++){\n if(j==v[i]) continue;\n m[j]=reflect(m[j],m[v[i]]);\n }\n }\n Segment s(start,g);\n DD dis=abs(s.a-s.b);\n if(dis>ans) return;\n v.push_back(-1);\n m=mirror;\n if(v.size()==3 and v[0]==0 and v[1]==1 ){\n //cerr<<-1<<endl;\n }\n if(v.size()==1){\n //cerr<<-1<<endl;\n }\n for(size_t i=0;i<v.size();i++){\n DD t=INF;\n if(v[i]==-1) t=abs(s.a-s.b);\n int id=-1;\n for(size_t j=0;j<N;j++){\n if(not intersect(s,m[j])) continue;\n if(i and v[i-1]==j) continue;\n auto x=crossPoint(s,m[j]);\n if(chmin(t,abs(s.a-x))){\n id=j;\n }\n }\n if(id!=v[i]) return;\n if(id==-1){\n ans=dis;\n return;\n }\n s.a=crossPoint(s,m[id]);\n for(size_t j=0;j<N;j++){\n if(id==j) continue;\n m[j]=reflect(m[j],m[id]);\n }\n }\n}\n\nvoid solve(){\nwhile(true){\n ans=INF;\n cin>>N;\n if(N==0) return;\n mirror.resize(N);\n\n for(int i=0;i<N;i++){\n cin>>mirror[i].a>>mirror[i].b;\n }\n cin>>start>>goal;\n dfs(0);\n if(v.size())v.pop_back();\n cout<<ans<<endl;\n}\n}\n\nint main(){\n bin101();\n int T=1;\n //cin>>T;\n while(T--) solve();\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 3544, "score_of_the_acc": -0.8773, "final_rank": 14 }, { "submission_id": "aoj_1171_5959234", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n#define all(x) (x).begin(),(x).end()\n#define fi first\n#define se second\n#define mp make_pair\n#define si(x) int(x.size())\nconst int mod=1000000007,MAX=15,INF=1<<29;\n\n//幾何ライブラリ\n// define double ll をするときは Point の < と == も書き換えよう!\n\nconst double eps=1e-8;\nconst double pi=acos((double)-1.0L);\n#define equals(a,b) (fabs((a)-(b))<eps)\n\ndouble torad(double deg) {return (double)(deg)*pi/180.0;}\ndouble todeg(double ang) {return ang*180.0/pi;}\n\nclass Point{\npublic:\n double x,y;\n \n Point(double x=0,double y=0):x(x),y(y){}\n \n Point operator + (Point p){return Point(x+p.x,y+p.y);}\n Point operator - (Point p){return Point(x-p.x,y-p.y);}\n Point operator * (double a){return Point(a*x,a*y);}\n Point operator / (double a){return Point(x/a,y/a);}\n \n double abs(){return sqrt(norm());}\n double norm(){return x*x+y*y;}\n \n bool operator < (const Point &p)const{\n return x+eps<p.x||(equals(x,p.x)&&y+eps<p.y);\n }\n \n bool operator == (const Point &p)const{\n return fabs(x-p.x)<eps/100000&&fabs(y-p.y)<eps/100000;\n }\n};\n\ntypedef Point Vector;\n\ndouble norm(Vector a){\n return a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n return sqrt(norm(a));\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x+a.y*b.y;\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\nstruct Segment{\n Point p1,p2;\n};\n\nbool isOrthogonal(Vector a,Vector b){\n return equals(dot(a,b),0.0);\n}\n\nbool isOrthogonal(Point a1,Point a2,Point b1,Point b2){\n return isOrthogonal(a1-a2,b1-b2);\n}\n\nbool isOrthogonal(Segment s1,Segment s2){\n return equals(dot(s1.p2-s1.p1,s2.p2-s2.p1),0.0);\n}\n\nbool isParallel(Vector a,Vector b){\n return equals(cross(a,b),0.0);\n}\n\nbool isParallel(Point a1,Point a2,Point b1,Point b2){\n return isParallel(a1-a2,b1-b2);\n}\n\nbool isParallel(Segment s1,Segment s2){\n return equals(cross(s1.p2-s1.p1,s2.p2-s2.p1),0.0);\n}\n\nPoint project(Segment s,Point p){\n Vector base=s.p2-s.p1;\n double r=dot(p-s.p1,base)/norm(base);\n return s.p1+base*r;\n}\n\nPoint reflect(Segment s,Point p){\n return p+(project(s,p)-p)*2.0;\n}\n\nPoint turn(Point p,Point c,double pi){\n double q=atan2(p.y-c.y,p.x-c.x);\n q+=pi;\n p=c+Point{cos(q)*abs(p-c),sin(q)*abs(p-c)};\n \n return p;\n}\n//pをcを中心としてpi回転させる(1周で2π)\n//p=cのときnan\n\n//p0,p1,p2の順に見たときどうなるか?\n\nstatic const int counter_clockwise=1;\nstatic const int clockwise=-1;\nstatic const int online_back=2;\nstatic const int online_front=-2;\nstatic const int on_segment=0;\n\nint ccw(Point p0,Point p1,Point p2){\n Vector a=p1-p0;\n Vector b=p2-p0;\n \n if(cross(a,b)>eps) return counter_clockwise;\n if(cross(a,b)<-eps) return clockwise;\n if(dot(a,b)<-eps) return online_back;\n if(a.norm()<b.norm()) return online_front;\n \n return on_segment;\n}\n\nbool intersect(Point p1,Point p2,Point p3,Point p4){\n return(ccw(p1,p2,p3)*ccw(p1,p2,p4)<=0&&ccw(p3,p4,p1)*ccw(p3,p4,p2)<=0);\n}\n\nbool intersect(Segment s1,Segment s2){\n return intersect(s1.p1,s1.p2,s2.p1,s2.p2);\n}\n\nbool overlap(Segment s1,Segment s2){\n int a=ccw(s1.p1,s1.p2,s2.p1),b=ccw(s1.p1,s1.p2,s2.p2);\n if(a&1||b&1) return 0;\n if(a==2){\n if(b==-2||(b==0&&!(s2.p2==s1.p1))) return 1;\n else return 0;\n }\n if(a==-2){\n if(b==2||(b==0&&!(s2.p2==s1.p2))) return 1;\n else return 0;\n }\n if(a==0){\n if(s1.p1==s2.p1){\n if(b!=2) return 1;\n else return 0;\n }\n else if(s1.p2==s2.p1){\n if(b!=-2) return 1;\n else return 0;\n }\n else return 1;\n }\n return 0;\n}\n//s1とs2の共通の線分(長さ0より大きい)があるかどうか\n\ntypedef Segment Line;\n\ndouble getDistance(Point a,Point b){\n return abs(a-b);\n}\n\ndouble getDistanceLP(Line l,Point p){\n return abs(cross(l.p2-l.p1,p-l.p1)/abs(l.p2-l.p1));\n}\n\ndouble getDistanceSP(Segment s,Point p){\n if(dot(s.p2-s.p1,p-s.p1)<0.0) return abs(p-s.p1);\n if(dot(s.p1-s.p2,p-s.p2)<0.0) return abs(p-s.p2);\n return getDistanceLP(s,p);\n}\n\ndouble getDistance(Segment s1,Segment s2){\n if(intersect(s1,s2)) return 0.0;\n return min({getDistanceSP(s1,s2.p1),getDistanceSP(s1,s2.p2),getDistanceSP(s2,s1.p1),getDistanceSP(s2,s1.p2)});\n}\n\nPoint getCrossPointS(Segment s1,Segment s2){\n //if(ccw(s1.p1,s1.p2,s2.p1)==0&&ccw(s1.p1,s1.p2,s2.p2)==0) return s1.p1;\n Vector base=s2.p2-s2.p1;\n double d1=abs(cross(base,s1.p1-s2.p1));\n double d2=abs(cross(base,s1.p2-s2.p1));\n double t=d1/(d1+d2);\n return s1.p1+(s1.p2-s1.p1)*t;\n}//同じ時壊れます\n\nPoint getCrossPointL(Line l1,Line l2){\n //if(ccw(s1.p1,s1.p2,s2.p1)==0&&ccw(s1.p1,s1.p2,s2.p2)==0) return s1.p1;\n \n Vector v1=l1.p2-l1.p1,v2=l2.p2-l2.p1;\n \n return l1.p1+v1*cross(v2,l2.p1-l1.p1)/cross(v2,v1);\n}\n\nSegment ParallelSegment(Segment s,double d){\n Vector v={-(s.p2-s.p1).y,(s.p2-s.p1).x};\n v=v/abs(v);\n \n s.p1=s.p1+v*d;\n s.p2=s.p2+v*d;\n \n return s;\n}\n\nPoint naisin(Point p1,Point p2,Point p3){\n if(p1==p2&&p2==p3&&p3==p1) return p1;\n \n return (p1*abs(p2-p3)+p2*abs(p1-p3)+p3*abs(p1-p2))/(abs(p2-p3)+abs(p1-p3)+abs(p1-p2));\n}\n\nPoint naisin(Line l1,Line l2,Line l3){\n //平行でない前提\n \n Point p1=getCrossPointL(l1,l2),p2=getCrossPointL(l1,l3),p3=getCrossPointL(l2,l3);\n return naisin(p1,p2,p3);\n}\n\n//ネットの適当を書いたのであってるか全く知りません→あってそう\n\nclass Circle{\npublic:\n Point c;\n double r;\n Circle(Point c=Point(),double r=0.0):c(c),r(r){}\n};\n\nPoint CircleCenter(Point a,Point b,Point c){\n Point u=a-b,v=a-c;\n double m1=(norm(a)-norm(b))/2.0,m2=(norm(a)-norm(c))/2.0;\n \n Point res;\n if(cross(u,v)==0.0){\n res.x=1e9;\n res.y=1e9;\n \n return res;\n }\n res.x=(m1*v.y-m2*u.y)/cross(u,v);\n res.y=(m1*v.x-m2*u.x)/cross(v,u);\n \n return res;\n}\n//3点を通る円の中心を返す\n\n//交わる 0\n// c1がc2のinside 1\n// c1がc2のoutside 2\n// 交わらない 3\n\nint not_intersect(Circle c1,Circle c2){\n double d=getDistance(c1.c,c2.c);\n double r1=c1.r,r2=c2.r;\n if(r1<r2){\n if(d<(r2-r1)) return 1;\n }\n if(r1>r2){\n if(d<(r1-r2)) return 2;\n }\n if(d<=r1+r2) return 0;\n else return 3;\n}\n\npair<Point,Point> segCrossPpoints(Circle c,Line l){\n //assert(intersect(c,l));\n Vector pr=project(l,c.c);\n Vector e=(l.p2-l.p1)/abs(l.p2-l.p1);\n double base=sqrt(c.r*c.r-norm(pr-c.c));\n return make_pair(pr+e*base,pr-e*base);\n}\n\ndouble arg(Vector p){return atan2(p.y,p.x);}\nVector polar(double a,double r){return Point(cos(r)*a,sin(r)*a);}\n\n//inside(outside)\n\npair<Point,Point> getCrossPoints(Circle c1,Circle c2){\n //assert(intersect(c1,c2));\n double d=abs(c1.c-c2.c);\n double a=acos((c1.r*c1.r+d*d-c2.r*c2.r)/(2*c1.r*d));\n double t=arg(c2.c-c1.c);\n return make_pair(c1.c+polar(c1.r,t+a),c1.c+polar(c1.r,t-a));\n}\n\nvector<Line> Commontangent(Circle c1,Circle c2){\n vector<Line> res;\n Point p=c2.c-c1.c;\n \n if(abs(p)>=(c1.r+c2.r)){\n Point a,b;\n a.x=c1.r*(p.x*(c1.r+c2.r)+p.y*sqrt(norm(p)-(c1.r+c2.r)*(c1.r+c2.r)))/norm(p);\n a.y=c1.r*(p.y*(c1.r+c2.r)-p.x*sqrt(norm(p)-(c1.r+c2.r)*(c1.r+c2.r)))/norm(p);\n \n b.x=c1.r*(p.x*(c1.r+c2.r)-p.y*sqrt(norm(p)-(c1.r+c2.r)*(c1.r+c2.r)))/norm(p);\n b.y=c1.r*(p.y*(c1.r+c2.r)+p.x*sqrt(norm(p)-(c1.r+c2.r)*(c1.r+c2.r)))/norm(p);\n \n res.push_back(Line{a+c1.c,a+c1.c+Point{-a.y,a.x}});\n if(!(a==b)){\n res.push_back(Line{b+c1.c,b+c1.c+Point{-b.y,b.x}});\n }\n }\n \n if(abs(p)>=abs(c1.r-c2.r)){\n Point a,b;\n a.x=c1.r*(p.x*(c1.r-c2.r)+p.y*sqrt(norm(p)-(c1.r-c2.r)*(c1.r-c2.r)))/norm(p);\n a.y=c1.r*(p.y*(c1.r-c2.r)-p.x*sqrt(norm(p)-(c1.r-c2.r)*(c1.r-c2.r)))/norm(p);\n \n b.x=c1.r*(p.x*(c1.r-c2.r)-p.y*sqrt(norm(p)-(c1.r-c2.r)*(c1.r-c2.r)))/norm(p);\n b.y=c1.r*(p.y*(c1.r-c2.r)+p.x*sqrt(norm(p)-(c1.r-c2.r)*(c1.r-c2.r)))/norm(p);\n \n res.push_back(Line{a+c1.c,a+c1.c+Point{-a.y,a.x}});\n if(!(a==b)){\n res.push_back(Line{b+c1.c,b+c1.c+Point{-b.y,b.x}});\n }\n }\n \n return res;\n}\n\ntypedef vector<Point> Polygon;\n\n/*\n IN 2\n ON 1\n OUT 0\n */\n\nint contains(Polygon g,Point p){\n int n=int(g.size());\n bool x=false;\n for(int i=0;i<n;i++){\n Point a=g[i]-p,b=g[(i+1)%n]-p;\n if(a.y>b.y) swap(a,b);\n if(a.y<eps&&0<b.y&&cross(a,b)<0) x=!x;\n if(abs(cross(a,b))<eps&&dot(a,b)<eps) return 1;\n }\n return (x?2:0);\n}\n\nPolygon andrewScan(Polygon s,bool ok){\n Polygon u,l;\n sort(all(s));\n \n if(int(s.size())<3) return s;\n int n=int(s.size());\n \n u.push_back(s[0]);\n u.push_back(s[1]);\n \n l.push_back(s[n-1]);\n l.push_back(s[n-2]);\n \n if(ok){\n for(int i=2;i<n;i++){\n for(int j=int(u.size());j>=2&&ccw(u[j-2],u[j-1],s[i])==counter_clockwise;j--){\n u.pop_back();\n }\n u.push_back(s[i]);\n }\n \n for(int i=int(s.size())-3;i>=0;i--){\n for(int j=int(l.size());j>=2&&ccw(l[j-2],l[j-1],s[i])==counter_clockwise;j--){\n l.pop_back();\n }\n l.push_back(s[i]);\n }\n }\n \n if(!ok){\n for(int i=2;i<n;i++){\n for(int j=int(u.size());j>=2&&ccw(u[j-2],u[j-1],s[i])!=clockwise;j--){\n u.pop_back();\n }\n u.push_back(s[i]);\n }\n \n for(int i=int(s.size())-3;i>=0;i--){\n for(int j=int(l.size());j>=2&&ccw(l[j-2],l[j-1],s[i])!=clockwise;j--){\n l.pop_back();\n }\n l.push_back(s[i]);\n }\n }\n \n reverse(all(l));\n \n for(int i=int(u.size())-2;i>=1;i--) l.push_back(u[i]);\n \n return l;\n}//ok==1なら辺の上も含める\n\nPolygon convex_cut(const Polygon& P, const Line& l) {\n Polygon Q;\n for(int i=0;i<si(P);i++){\n Point A=P[i],B=P[(i+1)%si(P)];\n if(ccw(l.p1,l.p2,A)!=-1)Q.push_back(A);\n if(ccw(l.p1,l.p2,A)*ccw(l.p1,l.p2,B)<0) Q.push_back(getCrossPointL(Line{A,B},l));\n }\n return Q;\n}\n\ndouble area(Point a,Point b,Point c){\n b=b-a;\n c=c-a;\n return abs(b.x*c.y-b.y*c.x)/2.0;\n}\n\ndouble area(Polygon &P){\n if(si(P)==0) return 0.0;\n double res=0;\n Point c={0.0,0.0};\n for(int i=0;i<si(P);i++){\n c=c+P[i];\n }\n c=c/si(P);\n \n for(int i=0;i<si(P);i++){\n res+=area(c,P[i],P[(i+1)%si(P)]);\n }\n \n return res;\n}\n\nll gcd(ll a,ll b){\n if(b==0) return a;\n return gcd(b,a%b);\n}\n\npair<Point,Vector> perpendicular_bisector(Point a,Point b){\n Point c=(a+b)/2;\n Vector v=b-c;\n swap(v.x,v.y);\n v.x*=-1;\n \n Point p=c;\n if(v.x==0){\n v.y=1;\n p.y=0;\n }\n else if(v.y==0){\n v.x=1;\n p.x=0;\n }\n else{\n if(v.x<0){\n v.x*=-1;\n v.y*=-1;\n }\n ll g=gcd(abs(ll(v.x)),abs(ll(v.y)));\n v.x/=g;\n v.y/=g;\n if(p.x>=0){\n ll d=p.x/v.x;\n p=p-v*d;\n }else{\n ll d=abs(p.x)/v.x;\n p=p+v*d;\n \n if(p.x<0){\n p=p+v;\n }\n }\n }\n \n return mp(p,v);\n}\n//2倍するなりして整数にしておくこと\n\ndouble ans=INF;\nint N;\nPoint s,t;\nvector<Segment> S;\nvector<int> use;\n\nvoid solve(){\n if(si(use)==6) return;\n vector<Segment> now=S;\n Point g=t;\n for(int a:use){\n Line l=now[a];\n for(int i=0;i<si(now);i++){\n now[i].p1=reflect(l,now[i].p1);\n now[i].p2=reflect(l,now[i].p2);\n }\n g=reflect(l,g);\n }\n Segment keiro={s,g};\n now=S;\n g=t;\n Point last=s;\n bool ok=true;\n for(int i=0;i<si(use);i++){\n int a=use[i];\n if(!intersect(Segment{last,keiro.p2},now[a])){\n ok=false;\n break;\n }\n Point M=getCrossPointS(Segment{last,keiro.p2},now[a]);\n for(int j=0;j<N;j++){\n if(j==a) continue;\n if(i&&j==use[i-1]) continue;\n if(intersect(Segment{last,M},now[j])){\n ok=false;\n break;\n }\n }\n if(!ok) break;\n Line l=now[a];\n for(int j=0;j<si(now);j++){\n now[j].p1=reflect(l,now[j].p1);\n now[j].p2=reflect(l,now[j].p2);\n }\n g=reflect(l,g);\n last=M;\n }\n for(int j=0;j<N;j++){\n if(si(use)&&j==use.back()) continue;\n if(intersect(Segment{last,keiro.p2},now[j])){\n ok=false;\n break;\n }\n }\n if(ok) chmin(ans,getDistance(keiro.p1,keiro.p2));\n \n for(int i=0;i<N;i++){\n if(si(use)&&use.back()==i) continue;\n use.push_back(i);\n solve();\n use.pop_back();\n }\n}\n\nint main(){\n \n std::ifstream in(\"text.txt\");\n std::cin.rdbuf(in.rdbuf());\n cin.tie(0);\n ios::sync_with_stdio(false);\n \n while(1){\n cin>>N;\n if(N==0) break;\n ans=INF;\n S.resize(N);\n for(int i=0;i<N;i++) cin>>S[i].p1.x>>S[i].p1.y>>S[i].p2.x>>S[i].p2.y;\n cin>>s.x>>s.y>>t.x>>t.y;\n solve();\n cout<<fixed<<setprecision(25)<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3512, "score_of_the_acc": -0.4, "final_rank": 8 }, { "submission_id": "aoj_1171_5940398", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<cstring>\n#include<string>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<map>\n#include<queue>\n#include<deque>\n#include<iomanip>\n#include<tuple>\n#include<cassert>\n#include<set>\n#include<complex>\n#include<numeric>\n#include<functional>\n#include<unordered_map>\n#include<unordered_set>\nusing namespace std;\ntypedef long long int LL;\ntypedef pair<int,int> P;\ntypedef pair<LL,LL> LP;\nconst int INF=1<<30;\nconst LL MAX=1e9+7;\n\nvoid array_show(int *array,int array_n,char middle=' '){\n\tfor(int i=0;i<array_n;i++)printf(\"%d%c\",array[i],(i!=array_n-1?middle:'\\n'));\n}\nvoid array_show(LL *array,int array_n,char middle=' '){\n\tfor(int i=0;i<array_n;i++)printf(\"%lld%c\",array[i],(i!=array_n-1?middle:'\\n'));\n}\nvoid array_show(vector<int> &vec_s,int vec_n=-1,char middle=' '){\n\tif(vec_n==-1)vec_n=vec_s.size();\n\tfor(int i=0;i<vec_n;i++)printf(\"%d%c\",vec_s[i],(i!=vec_n-1?middle:'\\n'));\n}\nvoid array_show(vector<LL> &vec_s,int vec_n=-1,char middle=' '){\n\tif(vec_n==-1)vec_n=vec_s.size();\n\tfor(int i=0;i<vec_n;i++)printf(\"%lld%c\",vec_s[i],(i!=vec_n-1?middle:'\\n'));\n}\ntemplate<typename T> ostream& operator<<(ostream& os,const vector<T>& v1){\n\tint n=v1.size();\n\tfor(int i=0;i<n;i++){\n\t\tif(i)os<<\" \";\n\t\tos<<v1[i];\n\t}\n\treturn os;\n}\ntemplate<typename T1,typename T2> ostream& operator<<(ostream& os,const pair<T1,T2>& p){\n\tos<<p.first<<\" \"<<p.second;\n\treturn os;\n}\ntemplate<typename T> istream& operator>>(istream& is,vector<T>& v1){\n\tint n=v1.size();\n\tfor(int i=0;i<n;i++)is>>v1[i];\n\treturn is;\n}\ntemplate<typename T1,typename T2> istream& operator>>(istream& is,pair<T1,T2>& p){\n\tis>>p.first>>p.second;\n\treturn is;\n}\n\nnamespace geometory{\n\tconst double eps=1e-9;\n}\n\ntemplate<typename T> T cross_product(complex<T> ca,complex<T> cb){\n return (conj(ca)*cb).imag();\n}\n\ntemplate<typename T> T inner_product(complex<T> ca,complex<T> cb){\n return (conj(ca)*cb).real();\n}\n\ntemplate<typename T> class Line{\n\n\tint sign(T a)const{\n\t\tif(abs(a)<geometory::eps)return 0;\n\t\tif(a<0)return -1;\n\t\telse return 1;\n\t}\n\npublic:\n complex<T> st,en;\n\tbool segment=true;\n\n\tLine(){}\n\tLine(complex<T> a,complex<T> b):st(a),en(b){}\n\tLine(T x1,T y1,T x2,T y2){\n\t\tst=complex<T>(x1,y1);\n\t\ten=complex<T>(x2,y2);\n\t}\n\tLine(pair<T,T> p1,pair<T,T> p2){\n\t\tst=complex<T>(p1.first,p1.second);\n\t\ten=complex<T>(p2.first,p2.second);\n\t}\n\n T length()const{\n return abs(en-st);\n }\n\n\tcomplex<T> direction()const{\n\t\tcomplex<T> a=en-st;\n\t\treturn a/abs(a);\n\t}\n\n\tcomplex<T> mirror(const complex<T> pos)const{\n\t\tcomplex<T> dir=direction();\n\t\tcomplex<T> a=pos-st;\n\t\tcomplex<T> b=2*inner_product(dir,a)*dir;\n\t\treturn st+b-a;\n\t}\n\n\tLine mirror(const Line& line)const{\n\t\treturn Line(mirror(line.st),mirror(line.en));\n\t}\n\n\tint is_parallel(const Line& line)const{\n\t\t//0: not parallel\n\t\t//1: parallel without direction\n\t\t//2: parallel with direction\n\t\tcomplex<T> c1=en-st,c2=line.en-line.st;\n\t\tif(abs(cross_product(c1,c2))>abs(c1)*abs(c2)*geometory::eps)return 0;\n\t\tif(inner_product(c1,c2)>0)return 2;\n\t\telse return 1;\n\t}\n\n\tT distance(const complex<T>& point)const{\n\t\tcomplex<T> cl=en-st;\n\t\tT a=cl.imag(),b=-cl.real();\n\t\tT c=-(a*st.real()+b*st.imag());\n\t\tT d=abs(a*point.real()+b*point.imag()+c)/abs(cl);\n\t\tif(!segment)return d;\n\t\treturn min({abs(point-st),abs(point-en),d});\n\t}\n\n\tbool in(const complex<T>& point)const{\n\t\treturn distance(point)<geometory::eps;\n\t}\n\n\tbool different_side(const complex<T>& p1,const complex<T>& p2)const{\n\t\treturn sign(cross_product(en-st,p1-st))*sign(cross_product(en-st,p2-st))==-1;\n\t}\n\tbool different_side(const Line& line)const{\n\t\treturn different_side(line.st,line.en);\n\t}\n\n\tint is_cross(const Line& line)const{\n\t\t//0: not cross\n\t\t//1: cross outside\n\t\t//2: cross end point\n\t\t//3: cross inside\n\t\tif(is_parallel(line))return 0;\n\t\tif(in(line.st) || in(line.en))return 2;\n\t\tif(line.in(st) || line.in(en))return 2;\n\t\tif(different_side(line) && line.different_side(st,en)){\n\t\t\treturn 3;\n\t\t}\n\t\treturn 1;\n\t}\n\n\tT distance(const Line& line)const{\n\t\tif(is_cross(line)>=2)return 0;//want to change when use straight line\n\t\tif(!line.segment)return min(line.distance(st),line.distance(en));\n\t\treturn min(distance(line.st),distance(line.en));\n\t}\n\n\tcomplex<T> cross_point(const Line& line)const{\n\t\tassert(!is_parallel(line));\n\t\tcomplex<T> d=direction();\n\t\tT a=cross_product(d,line.st-st)/cross_product(d,line.en-line.st);\n\t\treturn line.st-(line.en-line.st)*a;\n\t}\n};\n\nnamespace sol{\n\tint n,m;\n\n\tvoid solve(){\n\t\tconst int N=6;\n\t\tint i,j,k;\n\t\tint a,b,c,d;\n\t\tint sx,sy,gx,gy;\n\t\tdouble da,db;\n\t\tcomplex<double> p1,p2,p3,p4;\n\t\tvector<Line<double>> vl;\n\t\tvector<int> vi(N);\n\t\twhile(cin>>n){\n\t\t\tif(n==0)return;\n\t\t\tvl.clear();\n\t\t\tfor(i=0;i<n;i++){\n\t\t\t\tcin>>a>>b>>c>>d;\n\t\t\t\tvl.push_back(Line<double>(a,b,c,d));\n\t\t\t}\n\t\t\tcin>>sx>>sy>>gx>>gy;\n\t\t\tcomplex<double> sp(sx,sy),gp(gx,gy);\n\t\t\tdouble s=1e9;\n\t\t\tfor(vi.assign(N,-1);;vi[0]++){\n\t\t\t\tfor(i=0;i<N-1;i++){\n\t\t\t\t\tif(vi[i]==n)vi[i]=-1,vi[i+1]++;\n\t\t\t\t}\n\t\t\t\tif(vi.back()==n)break;\n\t\t\t\tint sz=N;\n\t\t\t\tfor(i=0;i<N;i++){\n\t\t\t\t\tif(sz==N && vi[i]==-1)sz=i;\n\t\t\t\t\tif(sz!=N && vi[i]!=-1)break;\n\t\t\t\t\tif(i && vi[i-1]==vi[i] && vi[i]!=-1)break;\n\t\t\t\t}\n\t\t\t\tif(i<N)continue;\n\t\t\t\tp1=gp;\n\t\t\t\tfor(i=sz-1;i>=0;i--){\n\t\t\t\t\tp1=vl[vi[i]].mirror(p1);\n\t\t\t\t}\n\t\t\t\tp2=sp;\n\t\t\t\tLine l1(p2,p1);\n\t\t\t\tda=abs(p2-p1);\n\t\t\t\tfor(i=0;i<sz;i++){\n\t\t\t\t\ta=vi[i];\n\t\t\t\t\tif(l1.is_cross(vl[a])!=3)break;\n\t\t\t\t\tp3=l1.cross_point(vl[a]);\n\t\t\t\t\tfor(j=0;j<n;j++){\n\t\t\t\t\t\tif(a==j)continue;\n\t\t\t\t\t\tif(l1.is_cross(vl[j])!=3)continue;\n\t\t\t\t\t\tp4=l1.cross_point(vl[j]);\n\t\t\t\t\t\tif(abs(p2-p4)<abs(p2-p3))break;\n\t\t\t\t\t}\n\t\t\t\t\tif(j<n)break;\n\t\t\t\t\tp1=vl[a].mirror(p1);\n\t\t\t\t\tl1=Line(p3,p1);\n\t\t\t\t\tp2=p3;\n\t\t\t\t}\n\t\t\t\tif(i<sz)continue;\n\t\t\t\tfor(i=0;i<n;i++){\n\t\t\t\t\tif(l1.is_cross(vl[i])==3)break;\n\t\t\t\t}\n\t\t\t\tif(i<n)continue;\n\t\t\t\ts=min(s,da);\n\t\t\t}\n\t\t\tcout<<fixed<<setprecision(10)<<s<<endl;\n\t\t}\n\t}\n}\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tsol::solve();\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3580, "score_of_the_acc": -0.5541, "final_rank": 12 }, { "submission_id": "aoj_1171_5445004", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst double INF = 10000;\nconst double EPS = 0.00001;\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n point operator +(point P){\n return point(x + P.x, y + P.y);\n }\n point operator -(point P){\n return point(x - P.x, y - P.y);\n }\n point operator *(double k){\n return point(x * k, y * k);\n }\n point operator /(double k){\n return point(x / k, y / k);\n }\n};\ndouble abs(point P){\n return sqrt(P.x * P.x + P.y * P.y);\n}\ndouble dist(point P, point Q){\n return abs(Q - P);\n}\npoint rotate90(point P){\n return point(-P.y, P.x);\n}\ndouble dot(point P, point Q){\n return P.x * Q.x + P.y * Q.y;\n}\ndouble cross(point P, point Q){\n return P.x * Q.y - P.y * Q.x;\n}\nstruct line{\n point A, B;\n line(){\n }\n line(point A, point B): A(A), B(B){\n }\n};\npoint vec(line L){\n return L.B - L.A;\n}\npoint projection(point P, line L){\n return L.A + vec(L) / abs(vec(L)) * dot(P - L.A, vec(L)) / abs(vec(L));\n}\npoint reflection(point P, line L){\n point H = projection(P, L);\n return H * 2 - P;\n}\nbool on_segment(point P, line L){\n return dot(P - L.A, vec(L)) > -EPS && dot(P - L.B, vec(L)) < EPS;\n}\nbool is_parallel(line L1, line L2){\n return abs(cross(vec(L1), vec(L2))) <= EPS;\n}\npoint line_intersection(line L1, line L2){\n return L1.A + vec(L1) * cross(L2.A - L1.A, vec(L2)) / cross(vec(L1), vec(L2));\n}\nvoid dfs(vector<vector<int>> &A, vector<int> &c, int n){\n A.push_back(c);\n if (c.size() < 5){\n for (int i = 0; i < n; i++){\n c.push_back(i);\n dfs(A, c, n);\n c.pop_back();\n }\n }\n}\nint main(){\n cout << fixed << setprecision(20);\n while (true){\n int n;\n cin >> n;\n if (n == 0){\n break;\n }\n vector<line> L(n);\n for (int i = 0; i < n; i++){\n cin >> L[i].A.x >> L[i].A.y >> L[i].B.x >> L[i].B.y;\n }\n point T, S;\n cin >> T.x >> T.y >> S.x >> S.y;\n vector<vector<int>> A;\n vector<int> c;\n dfs(A, c, n);\n int cnt = A.size();\n double ans = INF;\n for (int i = 0; i < cnt; i++){\n int sz = A[i].size();\n point T2 = T;\n for (int j = sz - 1; j >= 0; j--){\n T2 = reflection(T2, L[A[i][j]]);\n }\n if (dist(S, T2) > EPS){\n point P = S, Q = T2;\n bool ok = true;\n for (int j = 0; j <= sz; j++){\n line C(P, Q);\n vector<double> next(n, INF);\n for (int k = 0; k < n; k++){\n if (!is_parallel(C, L[k])){\n point X = line_intersection(C, L[k]);\n if (on_segment(X, L[k])){\n if (dot(Q - P, X - P) > EPS){\n next[k] = dist(P, X);\n }\n }\n }\n }\n if (j < sz){\n if (next[A[i][j]] == INF){\n ok = false;\n }\n for (int k = 0; k < n; k++){\n if (next[k] < next[A[i][j]] - EPS){\n ok = false;\n }\n }\n if (!ok){\n break;\n }\n point P2 = line_intersection(C, L[A[i][j]]);\n line M(P2, P2 + rotate90(vec(L[A[i][j]])));\n Q = reflection(P, M);\n P = P2;\n } else {\n double d = dist(P, T);\n for (int k = 0; k < n; k++){\n if (next[k] < d){\n ok = false;\n }\n }\n if (dot(T - P, Q - P) < -EPS){\n ok = false;\n }\n }\n }\n if (ok){\n ans = min(ans, dist(S, T2));\n }\n }\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3308, "score_of_the_acc": -0.1316, "final_rank": 4 }, { "submission_id": "aoj_1171_5379685", "code_snippet": "#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<ciso646>\n#include<random>\n#include<map>\n#include<set>\n#include<bitset>\n#include<stack>\n#include<unordered_map>\n#include<unordered_set>\n#include<utility>\n#include<cassert>\n#include<complex>\n#include<numeric>\n#include<array>\nusing namespace std;\n\n//#define int long long\ntypedef long long ll;\n\ntypedef unsigned long long ul;\ntypedef unsigned int ui;\nconstexpr ll mod = 1000000007;\nconst ll INF = mod * mod;\ntypedef pair<int, int>P;\n#define stop char nyaa;cin>>nyaa;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define per(i,n) for(int i=n-1;i>=0;i--)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define per1(i,n) for(int i=n;i>=1;i--)\n#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)\n#define all(v) (v).begin(),(v).end()\ntypedef pair<ll, ll> LP;\ntypedef long double ld;\ntypedef pair<ld, ld> LDP;\nconst ld eps = 1e-12;\nconst ld pi = acosl(-1.0);\n\nll mod_pow(ll x, ll n, ll m = mod) {\n\tif (n < 0) {\n\t\tll res = mod_pow(x, -n, m);\n\t\treturn mod_pow(res, m - 2, m);\n\t}\n\tif (abs(x) >= m)x %= m;\n\tif (x < 0)x += m;\n\tll res = 1;\n\twhile (n) {\n\t\tif (n & 1)res = res * x % m;\n\t\tx = x * x % m; n >>= 1;\n\t}\n\treturn res;\n}\nstruct modint {\n\tll n;\n\tmodint() :n(0) { ; }\n\tmodint(ll m) :n(m) {\n\t\tif (n >= mod)n %= mod;\n\t\telse if (n < 0)n = (n % mod + mod) % mod;\n\t}\n\toperator int() { return n; }\n};\nbool operator==(modint a, modint b) { return a.n == b.n; }\nmodint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }\nmodint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }\nmodint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }\nmodint operator+(modint a, modint b) { return a += b; }\nmodint operator-(modint a, modint b) { return a -= b; }\nmodint operator*(modint a, modint b) { return a *= b; }\nmodint operator^(modint a, ll n) {\n\tif (n == 0)return modint(1);\n\tmodint res = (a * a) ^ (n / 2);\n\tif (n % 2)res = res * a;\n\treturn res;\n}\n\nll inv(ll a, ll p) {\n\treturn (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);\n}\nmodint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }\nmodint operator/=(modint& a, modint b) { a = a / b; return a; }\nconst int max_n = 1 << 2;\nmodint fact[max_n], factinv[max_n];\nvoid init_f() {\n\tfact[0] = modint(1);\n\tfor (int i = 0; i < max_n - 1; i++) {\n\t\tfact[i + 1] = fact[i] * modint(i + 1);\n\t}\n\tfactinv[max_n - 1] = modint(1) / fact[max_n - 1];\n\tfor (int i = max_n - 2; i >= 0; i--) {\n\t\tfactinv[i] = factinv[i + 1] * modint(i + 1);\n\t}\n}\nmodint comb(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[b] * factinv[a - b];\n}\nmodint combP(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[a - b];\n}\n\ntypedef complex<ld> Point;\nld dot(Point a, Point b) { return real(conj(a) * b); }\nld cross(Point a, Point b) { return imag(conj(a) * b); }\nnamespace std {\n\tbool operator<(const Point& lhs, const Point& rhs) {\n\t\treturn lhs.real() == rhs.real() ? lhs.imag() < rhs.imag() : lhs.real() < rhs.real();\n\t}\n}\nstruct Line {\n\tPoint a, b;\n};\nstruct Circle {\n\tPoint p; ld r;\n};\nint ccw(Point a, Point b, Point c) {\n\tb -= a; c -= a;\n\tif (cross(b, c) > eps)return 1;//counter clockwise\n\tif (cross(b, c) < -eps)return -1;//clock wise\n\tif (dot(b, c) < 0)return 2;//c--a--b on line\n\tif (norm(b) < norm(c))return -2;//a--b--c on line\n\treturn 0; //a--c--b on line\n}\nbool isis_ss(Line s, Line t) {\n\treturn ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 && ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\nPoint proj(Line l, Point p) {\n\tld t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n\treturn l.a + t * (l.a - l.b);\n}\n\n//点を直線で反転\nPoint rev_lp(Line l, Point p) {\n\tPoint h = proj(l, p);\n\treturn h + h - p;\n}\nPoint is_ll(Line s, Line t) {\n\tPoint sv = s.b - s.a; Point tv = t.b - t.a;\n\treturn s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n\nint n;\nvoid solve() {\n\tvector<Line> l(n);\n\trep(i, n) {\n\t\tint a, b, c, d; cin >> a >> b >> c >> d;\n\t\tl[i] = { {(ld)a,(ld)b},{(ld)c,(ld)d} };\n\t}\n\tPoint s, g;\n\tint x, y; cin >> x >> y;\n\ts = { (ld)x,(ld)y };\n\tcin >> x >> y;\n\tg = { (ld)x,(ld)y };\n\n\tvector<Line> cur = l;\n\tvector<int> ms;\n\n\tvector<int> ad(7);\n\trep1(i, 6) {\n\t\tad[i] = ad[i - 1] + n - 1;\n\t\tif (i == 1)ad[i]++;\n\t}\n\tld ans = INF;\n\tfunction<void(int)> dfs = [&](int depth) {\n\t\tif (depth == 6)return;\n\t\t//next depth\n\t\tint len = n - 1;\n\t\tif (depth == 0)len++;\n\t\trep(i, len) {\n\t\t\tLine b = cur[ad[depth] + i];\n\t\t\trep(j, len)if (i != j) {\n\t\t\t\tLine nl = cur[ad[depth] + j];\n\t\t\t\tnl.a = rev_lp(b, nl.a);\n\t\t\t\tnl.b = rev_lp(b, nl.b);\n\t\t\t\tcur.push_back(nl);\n\t\t\t}\n\t\t\tif (depth > 0) {\n\t\t\t\tLine ex = cur[ad[depth - 1] + ms.back()];\n\t\t\t\tex.a = rev_lp(b, ex.a);\n\t\t\t\tex.b = rev_lp(b, ex.b);\n\t\t\t\tcur.push_back(ex);\n\t\t\t}\n\t\t\tms.push_back(i);\n\t\t\tPoint memo = g;\n\t\t\tg = rev_lp(b, g);\n\t\t\tdfs(depth + 1);\n\t\t\tms.pop_back();\n\t\t\trep(j, n - 1)cur.pop_back();\n\t\t\tg = memo;\n\t\t}\n\n\t\t// okかどうか\n\t\tLine ml = { s,g };\n\t\tvector<Point> cs;\n\t\tcs.push_back(s);\n\t\tbool valid = true;\n\t\trep(i, ms.size()) {\n\t\t\tLine l = cur[ad[i] + ms[i]];\n\t\t\tif (!isis_ss(l, ml)) {\n\t\t\t\tvalid = false; break;\n\t\t\t}\n\t\t\tcs.push_back(is_ll(l, ml));\n\t\t}\n\t\tif (!valid)return;\n\t\tcs.push_back(g);\n\t\trep(i, cs.size() - 1) {\n\t\t\tLine ml = { cs[i],cs[i + 1] };\n\t\t\tint len = n; if (i > 0)len--;\n\t\t\trep(j, len) {\n\t\t\t\tif (i < ms.size() && j == ms[i])continue;\n\t\t\t\tLine tl = cur[ad[i] + j];\n\t\t\t\tif (isis_ss(ml, tl)) {\n\t\t\t\t\tvalid = false; break;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (valid) {\n\t\t\tld dist = abs(g - s);\n\t\t\tld distsum = 0;\n\t\t\trep(i, cs.size() - 1) {\n\t\t\t\tdistsum += abs(cs[i] - cs[i + 1]);\n\t\t\t}\n\t\t\tif (abs(dist - distsum) > eps)return;\n\t\t\tans = min(ans, dist);\n\t\t\t//cout << dist << \"\\n\";\n\t\t}\n\t};\n\tdfs(0);\n\tcout << ans << \"\\n\";\n\n}\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\tcout << fixed << setprecision(10);\n\t//init_f();\n\t//init();\n\t//expr();\n\t//int t; cin >> t;rep(i,t)\n\twhile (cin >> n, n)\n\t\tsolve();\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3540, "score_of_the_acc": -0.4986, "final_rank": 10 }, { "submission_id": "aoj_1171_4951069", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define REP(i,n) for(int i = 0;i < (n);i++)\n#define FOR(i,m,n) for(int i = (m);i<(n);i++)\n#define REPR(i,n) for(int i = (n)-1;i>=0;i--)\n#define all(x) (x).begin(),(x).end()\ntemplate <typename T1, typename T2> inline void chmin(T1 & a, T2 b) { if (a > b) a = b; }\ntemplate <typename T1, typename T2> inline void chmax(T1& a, T2 b) { if (a < b) a = b; }\n\n\n//#define TEST\n\n#ifdef TEST\nvoid debug_out(){cerr<<endl;}\ntemplate<typename Head,typename... Tail>\nvoid debug_out(Head H,Tail... T){\n cerr<< \" \"<<(H);\n debug_out(T...);\n}\n#define DEBUG(...) cerr<<\"[\"<<#__VA_ARGS__<<\"]:\",debug_out(__VA_ARGS__)\n#else\n#define DEBUG(...) 42\n#endif\n\n\nconst double PI = acos(-1);\nconst double EPS = 1e-8;\nconst double INF = 1e5;\ntypedef complex<double> point;\n\npoint operator*(const point &p, const double &d) {\n return point(real(p) * d, imag(p) * d);\n}\nnamespace std {\n bool operator<(const point &a, const point &b) {\n return real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n }\n} // namespace std\n\n//直線or線分\nstruct Line : public vector<point> {\n int id;\n Line(const point &a, const point &b,int id):id(id) {\n push_back(a);\n push_back(b);\n }\n Line(const point &a,const point &b){\n push_back(a);\n push_back(b);\n id = -1;\n }\n Line()=default;\n};\ntypedef vector<Line> Lines;\n\npoint direction(const point &p) { //同じ向きの単位ベクトル\n return p / abs(p);\n}\npoint orthogonal(const point &p) { //法線ベクトル\n return point(-imag(p), real(p));\n}\ndouble cross(const point &a, const point &b) {\n return real(a) * imag(b) - imag(a) * real(b);\n}\ndouble dot(const point &a, const point &b) {\n return real(a) * real(b) + imag(a) * imag(b);\n}\nint ccw(point a, point b, point c) {\n b = b - a;\n c = c - a;\n if (cross(b, c) > EPS) return +1; // counter clockwise\n if (cross(b, c) < -EPS) return -1; // clockwise\n if (dot(b, c) < -EPS) return +2; // c--a--b on line\n if (norm(b) < norm(c)) return -2; // a--b--c on line\n return 0;\n}\n\n//交差判定\nbool intersectLL(const Line &l1, const Line &l2) {\n return abs(cross(l1[1] - l1[0], l2[1] - l2[0])) > EPS || // non-parallel\n abs(cross(l1[1] - l1[0], l2[0] - l1[0])) < EPS; // same line\n}\nbool intersectLS(const Line &l, const Line &s) {\n return cross(l[1] - l[0], s[0] - l[0]) * // s[0] is left of l\n cross(l[1] - l[0], s[1] - l[0]) <\n EPS; // s[1] is right of l\n}\nbool intersectLP(const Line &l, const point &p) {\n return abs(cross(l[1] - p, l[0] - p)) < EPS;\n}\n//端点に乗ってたらfalse\nbool intersectSP_without_endpoint(const Line &s, const point &p) {\n if (abs(s[0] - p) < EPS || abs(s[1] - p) < EPS) return false;\n return abs(s[0] - p) + abs(s[1] - p) - abs(s[1] - s[0]) < EPS; // triangle inequality\n}\n\nbool intersectSP(const Line &s, const point &p) {\n // verified on 2020/04/03\n // https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n return abs(s[0] - p) + abs(s[1] - p) - abs(s[1] - s[0]) < EPS; // triangle inequality\n}\nbool isOnSegment(const Line &s, const Line &t) {\n if (intersectSP(s, t[0]) || intersectSP(s, t[1]) || intersectSP(t, s[0]) ||\n intersectSP(t, s[1]))\n return true;\n else\n return false;\n}\nbool isSamePoint(const point &p1, const point &p2) { return abs(p1 - p2) < EPS; }\nbool connectSS(const Line &s, const Line &t) {\n REP(i, 2) REP(j, 2) {\n if (s[i] == t[j]) return true;\n }\n return false;\n}\nbool intersectSS(const Line &s, const Line &t) {\n return ccw(s[0], s[1], t[0]) * ccw(s[0], s[1], t[1]) <= 0 &&\n ccw(t[0], t[1], s[0]) * ccw(t[0], t[1], s[1]) <= 0;\n}\n//端点が線分上に乗っている場合はfalseにする\nbool intersectSS_strict(const Line &s, const Line &t) {\n if (isOnSegment(s, t)) return false;\n return ccw(s[0], s[1], t[0]) * ccw(s[0], s[1], t[1]) <= 0 &&\n ccw(t[0], t[1], s[0]) * ccw(t[0], t[1], s[1]) <= 0;\n}\n\n//距離,交点\n//射影 直線lにpから下した垂線との交点\npoint projection(\n const Line &l,\n const point &\n p) { // verified on 2020/04/03\n // https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n double t = dot(p - l[0], l[0] - l[1]) / norm(l[0] - l[1]);\n return l[0] + (l[0] - l[1]) * t;\n}\n//射影 直線lを対象軸としてpと線対称にある点\npoint reflection(const Line &l, const point &p) { return p + (projection(l, p) - p) * 2; }\ndouble distancePP(const point &a, const point &b) { return sqrt(norm(a - b)); }\ndouble distanceLP(const Line &l, const point &p) { return abs(p - projection(l, p)); }\ndouble distanceLL(const Line &l, const Line &m) {\n return intersectLL(l, m) ? 0 : distanceLP(l, m[0]);\n}\ndouble distanceLS(const Line &l, const Line &s) {\n if (intersectLS(l, s)) return 0;\n return min(distanceLP(l, s[0]), distanceLP(l, s[1]));\n}\ndouble distanceSP(const Line &s, const point &p) {\n const point r = projection(s, p);\n if (intersectSP(s, r)) return abs(r - p);\n return min(abs(s[0] - p), abs(s[1] - p));\n}\ndouble distanceSS(const Line &s, const Line &t) {\n // verified on 2020/04/03\n // https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n if (intersectSS(s, t)) return 0;\n return min({distanceSP(s, t[0]), distanceSP(s, t[1]), distanceSP(t, s[0]),\n distanceSP(t, s[1])});\n}\npoint crosspoint(const Line &l, const Line &m) {\n double A = cross(l[1] - l[0], m[1] - m[0]);\n double B = cross(l[1] - l[0], l[1] - m[0]);\n if (abs(A) < EPS && abs(B) < EPS) return m[0]; // same line\n if (abs(A) < EPS) assert(false); // Precondition not satisfied\n return m[0] + B / A * (m[1] - m[0]);\n}\n//double dist(point &p1, point &p2) { return abs(p1 - p2); }\n\n\nconst int MAX_COUNT = 6;\nint N;\nLine mirrors[10];\n\n//鏡の順番\nvoid dfs(int cnt,int k,int las,vector<vector<int>>&ret,vector<int>res){\n if(k==cnt){\n ret.push_back(res);return;\n }\n REP(i,N){\n if(i!=las){\n res.push_back(i);\n dfs(cnt,k+1,i,ret,res);\n res.pop_back();\n }\n }\n}\n\nbool solve(){\n cin>>N;\n if(N==0)return false;\n REP(i,N){\n int a,b,c,d;cin>>a>>b>>c>>d;\n mirrors[i]=Line(point(a,b),point(c,d),i);\n }\n int sx,sy,gx,gy;\n cin>>gx>>gy>>sx>>sy;\n const point S(sx,sy),G(gx,gy);\n double ans = INF;\n vector<double>cand;\n DEBUG(abs(S-G));\n //反射回数\n REP(K,6){\n vector<vector<int>>vp;//鏡の順番\n vector<int>tmp;\n dfs(K,0,-1,vp,tmp);\n DEBUG(K);\n for(auto p:vp){\n REP(i,K){\n //DEBUG(i,p[i]);\n }\n bool ok = true;\n point G2 = G;\n REPR(i,K)G2=reflection(mirrors[p[i]],G2);\n //DEBUG(G2,abs(S-G2));\n double res = 0;\n if(abs(abs(S-G2)-243.134)<0.1){\n DEBUG(G,abs(S-G2));\n DEBUG(K);\n REP(i,K){\n DEBUG(p[i],mirrors[p[i]][0],mirrors[p[i]][1]);\n }\n }\n //else continue;\n point dir=direction(G2-S);\n Line l(S,S+dir*INF);\n //Sから発射したビームがp[0],p[1],...,Gの順にぶつかるか判定\n //DEBUG(G2);\n point s = S;\n REP(i,K){\n //p[i]に最初に衝突するか\n vector<pair<double,int>>dist_id;\n REP(j,N)if(intersectSS_strict(l,mirrors[j])){\n if(intersectSP(mirrors[j],s))continue;\n point crs = crosspoint(l,mirrors[j]);\n double dist = abs(crs-s);\n dist_id.emplace_back(dist,j);\n }\n sort(all(dist_id));\n //DEBUG(dist_id.size());\n REP(j,dist_id.size()){\n //DEBUG(dist_id[j].second,dist_id[j].first);\n }\n if(dist_id.size()==0||dist_id[0].second!=p[i]){ok=false;break;}\n\n point s2 = reflection(mirrors[p[i]],s);\n point crs = crosspoint(l,mirrors[p[i]]);\n res+=abs(s-crs);\n dir = direction(crs-s2);\n s = crosspoint(l,mirrors[p[i]]);\n l[0]=s,l[1]=s+dir*INF;\n }\n //if(!ok)continue;\n //sからGに最初に衝突するか\n if(!intersectSP(l,G))ok=false;\n dir=direction(G-s);\n l[0]=s,l[1]=s+dir*INF;\n double d_sG=abs(s-G);\n REP(i,N)if(intersectSS_strict(l,mirrors[i])){\n if(intersectSP(mirrors[i],s))continue;\n point crs = crosspoint(mirrors[i],l);\n double dist = abs(crs-s);\n if(dist<d_sG){ok=false;break;}\n }\n res+=abs(G2-s);\n if(ok){\n DEBUG(K);\n REP(i,K){\n DEBUG(p[i],mirrors[p[i]][0],mirrors[p[i]][1]);\n }\n DEBUG(abs(S-G2));\n cand.push_back(abs(S-G2));\n chmin(ans,abs(S-G2));\n }\n }\n\n }\n sort(all(cand));\n #ifdef TEST\n for(auto d:cand)cerr<<d<<\" \";\n cerr<<endl;\n #endif\n cout<<fixed<<setprecision(10)<<ans<<endl;\n\n return true;\n}\n\nsigned main(){\n while(solve()){\n\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3276, "score_of_the_acc": -0.1319, "final_rank": 5 }, { "submission_id": "aoj_1171_4902456", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i, n) for (int i=0; i<(n); ++i)\n#define RREP(i, n) for (int i=(int)(n)-1; i>=0; --i)\n#define FOR(i, a, n) for (int i=(a); i<(n); ++i)\n#define RFOR(i, a, n) for (int i=(int)(n)-1; i>=(a); --i)\n\n#define SZ(x) ((int)(x).size())\n#define ALL(x) (x).begin(),(x).end()\n\n#define DUMP(x) cerr<<#x<<\" = \"<<(x)<<endl\n#define DEBUG(x) cerr<<#x<<\" = \"<<(x)<<\" (L\"<<__LINE__<<\")\"<<endl;\n\ntemplate<class T>\nostream &operator<<(ostream &os, const vector<T> &v) {\n os << \"[\";\n REP(i, SZ(v)) {\n if (i) os << \", \";\n os << v[i];\n }\n return os << \"]\";\n}\n\ntemplate<class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n return os << \"(\" << p.first << \" \" << p.second << \")\";\n}\n\ntemplate<class T>\nbool chmax(T &a, const T &b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<class T>\nbool chmin(T &a, const T &b) {\n if (b < a) {\n a = b;\n return true;\n }\n return false;\n}\n\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nusing P = pair<int, int>;\nusing vi = vector<int>;\nusing vll = vector<ll>;\nusing vvi = vector<vi>;\nusing vvll = vector<vll>;\n\nconst ll MOD = 1e9 + 7;\nconst int INF = INT_MAX / 2;\nconst ll LINF = LLONG_MAX / 2;\nconst ld eps = 1e-9;\n\n/**\n * @brief\n * 二次元幾何\n * @author habara-k\n * @date 2020/05/05\n */\n\nusing Real = double;\nconst Real PI = acos(-1);\n\nusing Point = complex<Real>;\nnamespace std {\n bool operator<(const Point& a, const Point& b) {\n if (a.real() == b.real()) return a.imag() < b.imag();\n return a.real() < b.real();\n }\n}\n\nstruct Line {\n Point a, b;\n Line() {}\n Line(const Point& a, const Point& b) : a(a), b(b) {}\n friend ostream& operator<<(ostream& os, const Line& l) {\n return os << \"[\" << l.a << \",\" << l.b << \"]\";\n }\n};\n\nstruct Segment : Line {\n Segment() {}\n\n Segment(const Point& a, const Point& b) : Line(a, b) {}\n};\n\ninline bool eq(Real a, Real b) { return abs(b - a) < eps; }\n\nReal radian_to_degree(Real r) {\n return r * 180.0 / PI;\n}\n\nReal degree_to_radian(Real d) {\n return d * PI / 180.0;\n}\n\nPoint rotate(const Point &p, Real theta) {\n return p * polar((Real)1.0, theta);\n}\n\nReal cross(const Point& a, const Point& b) {\n return a.real() * b.imag() - a.imag() * b.real();\n}\n\nReal dot(const Point& a, const Point& b) {\n return a.real() * b.real() + a.imag() * b.imag();\n}\n\n\n/**\n* @brief 点p の直線l への射影を求める.\n*/\nPoint projection(const Line& l, const Point& p) {\n Real A = dot(l.b - l.a, p - l.a),\n B = dot(l.a - l.b, p - l.b);\n return (A * l.b + B * l.a) / (A + B);\n}\n\n/**\n* @brief 2直線の並行判定\n*/\nbool parallel(const Line& l1, const Line& l2) {\n return eq(cross(l1.a - l1.b, l2.a - l2.b), 0.0);\n}\n\n/**\n* @brief 2直線の直行判定\n*/\nbool orthogonal(const Line& l1, const Line& l2) {\n return eq(dot(l1.a - l1.b, l2.a - l2.b), 0.0);\n}\n\n\n/**\n* @brief 有向線分と点の位置関係\n* @param[in] a, b, c: 線分a->b, 点c\n* @return 線分a->b からみて, 点c がどこにあるか.\n*/\nconst int COUNTER_CLOCKWISE = 1,\n CLOCKWISE = -1,\n ONLINE_BACK = 2,\n ONLINE_FRONT = -2,\n ON_SEGMENT = 0;\nint ccw(const Point& a, Point b, Point c) {\n b = b - a, c = c - a;\n if (cross(b, c) > eps) return COUNTER_CLOCKWISE;\n if (cross(b, c) < -eps) return CLOCKWISE;\n if (dot(b, c) < 0) return ONLINE_BACK;\n if (norm(b) < norm(c)) return ONLINE_FRONT;\n return ON_SEGMENT;\n}\n\n\n/**\n* @brief 直線と点の交差判定\n*/\nbool intersected(const Line& l, const Point& p) {\n return abs(ccw(l.a, l.b, p)) != 1;\n}\n\n/**\n* @brief 線分と点の交差判定\n*/\nbool intersected(const Segment& s, const Point& p) {\n return ccw(s.a, s.b, p) == 0;\n}\n\n/**\n* @brief 直線と線分の交差判定\n*/\nbool intersected(const Line& l, const Segment& s) {\n return cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < eps;\n}\n\n/**\n* @brief 2つの線分の交差判定\n*/\nbool intersected(const Segment& s1, const Segment& s2) {\n return ccw(s1.a, s1.b, s2.a) * ccw(s1.a, s1.b, s2.b) <= 0 and\n ccw(s2.a, s2.b, s1.a) * ccw(s2.a, s2.b, s1.b) <= 0;\n}\n\n\n/**\n* @brief 2直線の交点\n*/\nPoint crosspoint(const Line& l1, const Line& l2) {\n Real A = cross(l2.a - l1.a, l2.b - l1.a),\n B = cross(l2.b - l1.b, l2.a - l1.b);\n return (A * l1.b + B * l1.a) / (A + B);\n}\n\n\n/**\n* @brief 直線と点の距離\n*/\nReal distance(const Line& l, const Point& p) {\n return abs(p - projection(l, p));\n}\n\n/**\n* @brief 線分と点の距離\n*/\nReal distance(const Segment& s, const Point& p) {\n Point r = projection(s, p);\n if (intersected(s, r)) return abs(r - p);\n return min(abs(s.a - p), abs(s.b - p));\n}\n\n/**\n* @brief 直線と線分の距離\n*/\nReal distance(const Line &l, const Segment &s) {\n if (intersected(l, s)) return 0;\n return min(distance(l, s.a), distance(l, s.b));\n}\n\n/**\n* @brief 2つの線分の距離\n*/\nReal distance(const Segment& s1, const Segment& s2) {\n if (intersected(s1, s2)) return 0.0;\n return min({ distance(s1, s2.a), distance(s1, s2.b),\n distance(s2, s1.a), distance(s2, s1.b) });\n}\n\n\nstruct Circle {\n Point p;\n Real r;\n Circle() {}\n Circle(const Point& p, Real r) : p(p), r(r) {}\n};\n\n\n/**\n* @brief 2つの円の交点の数\n*/\nint intersected(Circle c1, Circle c2) {\n if (c1.r < c2.r) swap(c1, c2);\n Real d = abs(c1.p - c2.p);\n if (c1.r + c2.r < d) return 4;\n if (eq(c1.r + c2.r, d)) return 3;\n if (c1.r - c2.r < d) return 2;\n if (eq(c1.r - c2.r, d)) return 1;\n return 0;\n}\n\n/**\n* @brief 円と直線の交点のペア\n* @details 交差することを確認してから呼ぶこと.\n*/\npair<Point,Point> crosspoint(const Circle& c, const Line& l) {\n Real h = distance(l, c.p);\n Point p = projection(l, c.p);\n if (eq(h, c.r)) return { p, p };\n Point u = l.a - l.b; u /= abs(u);\n Real d = sqrt(c.r * c.r - h * h);\n return { p + u * d, p - u * d };\n}\n\n/**\n* @brief 2つの円の交点のペア\n* @details 交差することを確認してから呼ぶこと.\n*/\npair<Point,Point> crosspoint(const Circle& c1, const Circle& c2) {\n Real d = abs(c2.p - c1.p), t = arg(c2.p - c1.p);\n Real a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d));\n return { c1.p + polar(c1.r, t + a),\n c1.p + polar(c1.r, t - a) };\n}\n\n/**\n* @brief 点p, 円c に対し, pを通るcの接線を返す(c上の2点のペアで返す).\n* @details 点p が円c の外側にあることを確認してから呼ぶこと.\n*/\npair<Point,Point> tangent(const Point& p, const Circle& c) {\n return crosspoint(c, Circle(p, sqrt(norm(p - c.p) - c.r * c.r)));\n};\n\n/**\n* @brief 2つの円に共通する接線を返す(最大4本).\n* @details 点p が円c の外側にあることを確認してから呼ぶこと.\n*/\nvector<Line> common_tangent(const Circle& c1, const Circle& c2) {\n vector<Line> lines;\n Point u = c2.p - c1.p;\n Real d = abs(u);\n if (eq(d, 0.0)) return lines;\n u /= d;\n for (Real s : { -1, 1 }) {\n // s = -1: 同じ側に2つの円があるとき.\n // s = 1: 反対側に2つの円があるとき.\n Real h = (c1.r + s * c2.r) / d;\n if (eq(abs(h), 1.0)) {\n // 2つの円が接しているとき.\n lines.emplace_back(\n c1.p + u * h * c1.r,\n c1.p + u * h * c1.r + rotate(u, PI / 2.0));\n } else if (abs(h) < 1) {\n // 2本の接線が引けるとき.\n Real a = acos(h);\n lines.emplace_back(\n c1.p + u * polar(c1.r, a),\n c2.p - s * u * polar(c2.r, a));\n lines.emplace_back(\n c1.p + u * polar(c1.r, -a),\n c2.p - s * u * polar(c2.r, -a));\n }\n }\n return lines;\n}\n\nusing PDD = pair<double, double>;\n\nint n;\nvector<PDD> p, q;\ndouble tx, ty, lx, ly;\ndouble ans = INF;\n\nPoint hanten(Segment l, Point p2) {\n double dx = l.a.real(), dy = l.a.imag();\n auto para = complex<double>(dx, dy);\n l.a -= para;\n l.b -= para;\n p2 -= para;\n\n double theta = atan2(l.b.imag(), l.b.real());\n double a11 = cos(2*theta), a12 = sin(2*theta), a21 = sin(2*theta), a22 = -cos(2*theta);\n\n p2 = {a11 * p2.real() + a12 * p2.imag(), a21 * p2.real() + a22 * p2.imag()};\n\n p2 += para;\n l.b += para;\n l.a += para;\n return p2;\n}\n\nbool operator<(const Segment &s1, const Segment &s2) {\n if(s1.a == s2.a) {\n return s1.b < s2.b;\n } else {\n return s1.a < s2.a;\n }\n}\n\nvoid check(vi &v) {\n int sz = SZ(v);\n Point st = Point(lx, ly);\n\n vector<vector<Segment>> lv(sz+1, vector<Segment>(n));\n REP(i, n) {\n lv[0][i] = Segment(Point(p[i].first, p[i].second), Point(q[i].first, q[i].second));\n }\n vector<Point> t(sz+1);\n t[0] = Point(tx, ty);\n REP(i, sz) {\n REP(j, n) {\n auto a = hanten(lv[i][v[i]], lv[i][j].a);\n auto b = hanten(lv[i][v[i]], lv[i][j].b);\n lv[i+1][j] = Segment(a, b);\n }\n t[i+1] = hanten(lv[i][v[i]], t[i]);\n }\n\n Segment l = Segment(st, t[sz]);\n Point now = t[sz];\n bool ok = true;\n //cout << t << endl;\n double val = abs(st - t[sz]);\n for(int i=sz-1;i>=0;--i) {\n bool res = intersected(l, lv[i+1][v[i]]);\n if(res) {\n Point nxt = crosspoint(l, lv[i+1][v[i]]);\n l = Segment(nxt, now);\n REP(j, n) {\n if(v[i] != j && (i == sz-1 || v[i+1] != j)) {\n res &= !intersected(l, lv[i+1][j]);\n }\n }\n if(!res) {\n ok = false;\n break;\n }\n l = Segment(st, nxt);\n now = nxt;\n } else {\n ok = false;\n break;\n }\n }\n\n bool res = true;\n REP(j, n) {\n if(SZ(v) == 0 || v[0] != j) {\n res &= !intersected(l, lv[0][j]);\n }\n }\n if(!res) ok = false;\n //cout << v << endl;\n //cout << ok << \":\" << val << endl;\n if(ok) {\n chmin(ans, val);\n }\n}\n\nvoid junban(int k, vi &v) {\n if(k == 5) {\n check(v);\n } else {\n if(k > 0) check(v);\n REP(i, n) {\n if(k > 0 && v.back() == i) continue;\n v.push_back(i);\n junban(k+1, v);\n v.pop_back();\n }\n }\n}\n\nbool solve() {\n cin >> n;\n if(n == 0) {\n return false;\n }\n p.resize(n);\n q.resize(n);\n REP(i, n) {\n cin >> p[i].first >> p[i].second;\n cin >> q[i].first >> q[i].second;\n }\n\n cin >> tx >> ty >> lx >> ly;\n ans = INF;\n\n vi v;\n check(v);\n junban(0, v);\n cout << ans << endl;\n\n return true;\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n\n while(solve()) {}\n\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3864, "score_of_the_acc": -0.9934, "final_rank": 17 }, { "submission_id": "aoj_1171_4312701", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\t\treturn x != p.x? x < p.x: y < p.y;\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\tdouble x,y;\n};\n\ntypedef Point Vector;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\tPoint p[2];\n};\n\nint N;\ndouble ans;\nLine line[5];\nPoint start,goal;\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//★★直線ではなく、線分の交差判定★★\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(x1 != x2){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n//線分と線分の距離\ndouble getDistance(Line A,Line B){\n\tif(is_Cross(A,B))return 0.0;\n\treturn min(min(getDistanceSP(A,B.p[0]),getDistanceSP(A,B.p[1])),\n\t\t\tmin(getDistanceSP(B,A.p[0]),getDistanceSP(B,A.p[1])));\n}\n\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\nPoint calc_Reflection_Point(double x1,double y1,double x2,double y2,double xp,double yp){\n\n\tPoint ret;\n\n\tbool X_FLG = false,Y_FLG = false;\n\tdouble slope;\n\n\tif(y1 == y2){\n\t\tX_FLG = true;\n\t}else if(x1 == x2){\n\t\tY_FLG = true;\n\t}else{\n\t\tslope = (y2-y1)/(x2-x1);\n\t}\n\n\tif(X_FLG){\n\t\tret.x = xp,ret.y=y1;\n\t}else if(Y_FLG){\n\t\tret.x = x1,ret.y = yp;\n\t}else{\n\t\tret.x = (yp*(x2-x1)*(y2-y1)+xp*(x2-x1)*(x2-x1)-y1*(y2-y1)*(x2-x1)+x1*(y2-y1)*(y2-y1))/((y2-y1)*(y2-y1)+(x2-x1)*(x2-x1));\n\t\tret.y = ((x1-x2)*ret.x+yp*(y2-y1)+xp*(x2-x1))/(y2-y1);\n\t}\n\tret.x = 2*ret.x-xp;\n\tret.y = 2*ret.y-yp;\n\n\treturn ret;\n}\n\nPoint calc_Reflection_Point(Line line,Point point){\n\n\treturn calc_Reflection_Point(line.p[0].x,line.p[0].y,line.p[1].x,line.p[1].y,point.x,point.y);\n}\n\ndouble calc_dist(Point A,Point B){\n\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\n\n\nvoid calc(vector<int> V){\n\n\tPoint GOAL = goal;\n\tLine work[5];\n\tfor(int i = 0; i < N; i++){\n\n\t\twork[i] = line[i];\n\t}\n\n\t//goalの最終位置を計算\n\tfor(int i = 0; i < V.size(); i++){\n\t\tfor(int k = 0; k < N; k++){\n\t\t\tif(k == V[i])continue;\n\t\t\twork[k].p[0] = calc_Reflection_Point(work[V[i]],work[k].p[0]);\n\t\t\twork[k].p[1] = calc_Reflection_Point(work[V[i]],work[k].p[1]);\n\t\t}\n\n\t\tGOAL = calc_Reflection_Point(work[V[i]],GOAL);\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\twork[i] = line[i];\n\t}\n\n\tint last;\n\tdouble sum = 0;\n\n\tPoint from = start;\n\n\tfor(int i = 0; i < V.size(); i++){\n\n\t\tlast = V[i];\n\t\tLine tmp_line = Line(from,GOAL);\n\n\t\tif(!is_Cross(tmp_line,work[V[i]])){\n\t\t\treturn;\n\t\t}\n\n\t\tPoint cross_point = calc_Cross_Point(tmp_line,work[V[i]]);\n\n\t\ttmp_line.p[0] = from;\n\t\ttmp_line.p[1] = cross_point;\n\n\t\tfor(int k = 0; k < N; k++){ //使わない鏡も見る\n\t\t\tif(k == V[i] || (i > 0 && k == V[i-1]))continue;\n\t\t\tif(is_Cross(tmp_line,work[k])){\n\t\t\t\treturn;\n\t\t\t}\n\t\t}\n\n\t\tsum += calc_dist(from,cross_point);\n\n\t\tfor(int k = 0; k < N; k++){\n\t\t\tif(k == V[i])continue;\n\t\t\twork[k].p[0] = calc_Reflection_Point(work[V[i]],work[k].p[0]);\n\t\t\twork[k].p[1] = calc_Reflection_Point(work[V[i]],work[k].p[1]);\n\t\t}\n\n\t\tfrom = cross_point;\n\t}\n\n\tLine final = Line(from,GOAL);\n\n\tfor(int k = 0; k < N; k++){\n\t\tif(k == last)continue;\n\t\tif(is_Cross(final,work[k])){\n\t\t\treturn;\n\t\t}\n\t}\n\n\tsum += calc_dist(from,GOAL);\n\n\tans = min(ans,sum);\n}\n\n\nvoid func(){\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf %lf %lf\",&line[i].p[0].x,&line[i].p[0].y,&line[i].p[1].x,&line[i].p[1].y);\n\t}\n\tscanf(\"%lf %lf\",&goal.x,&goal.y);\n\tscanf(\"%lf %lf\",&start.x,&start.y);\n\n\tans = BIG_NUM;\n\tvector<int> V;\n\n\t//0\n\tcalc(V);\n\n\tvector<int> A,B,C,D,E;\n\n\tfor(int a = 0; a < N; a++){\n\t\tA.clear();\n\t\tA.push_back(a);\n\t\tcalc(A);\n\t\tfor(int b = 0; b < N; b++){\n\t\t\tif(b == a)continue;\n\t\t\tB.clear();\n\t\t\tB.push_back(a);\n\t\t\tB.push_back(b);\n\t\t\tcalc(B);\n\t\t\tfor(int c = 0; c < N; c++){\n\t\t\t\tif(c == b)continue;\n\t\t\t\tC.clear();\n\t\t\t\tC.push_back(a);\n\t\t\t\tC.push_back(b);\n\t\t\t\tC.push_back(c);\n\t\t\t\tcalc(C);\n\t\t\t\tfor(int d = 0; d < N; d++){\n\t\t\t\t\tif(d == c)continue;\n\t\t\t\t\tD.clear();\n\t\t\t\t\tD.push_back(a);\n\t\t\t\t\tD.push_back(b);\n\t\t\t\t\tD.push_back(c);\n\t\t\t\t\tD.push_back(d);\n\t\t\t\t\tcalc(D);\n\t\t\t\t\tfor(int e = 0; e < N; e++){\n\t\t\t\t\t\tif(e == d)continue;\n\t\t\t\t\t\tE.clear();\n\t\t\t\t\t\tE.push_back(a);\n\t\t\t\t\t\tE.push_back(b);\n\t\t\t\t\t\tE.push_back(c);\n\t\t\t\t\t\tE.push_back(d);\n\t\t\t\t\t\tE.push_back(e);\n\t\t\t\t\t\tcalc(E);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%.10lf\\n\",ans);\n}\n\nint main(){\n\n\twhile(true){\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3264, "score_of_the_acc": -0.0556, "final_rank": 2 }, { "submission_id": "aoj_1171_4103258", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}\n\n\n#define EPS (1e-10)\n#define equals(a,b) (fabs((a)-(b)) < EPS)\nconst double PI = asinl(1) * 2;\n\n// COUNTER CLOCKWISE\nstatic const int CCW_COUNTER_CLOCKWISE = 1;\nstatic const int CCW_CLOCKWISE = -1;\nstatic const int CCW_ONLINE_BACK = 2;\nstatic const int CCW_ONLINE_FRONT = -2;\nstatic const int CCW_ON_SEGMENT = 0;\n\n// intercsect of circles\nstatic const int ICC_SEPERATE = 4;\nstatic const int ICC_CIRCUMSCRIBE = 3;\nstatic const int ICC_INTERSECT = 2;\nstatic const int ICC_INSCRIBE = 1;\nstatic const int ICC_CONTAIN = 0;\n\nstruct Point{\n double x,y;\n Point(){}\n Point(double x,double y) :x(x),y(y){}\n Point operator+(Point p) {return Point(x+p.x,y+p.y);}\n Point operator-(Point p) {return Point(x-p.x,y-p.y);}\n Point operator*(double k){return Point(x*k,y*k);}\n Point operator/(double k){return Point(x/k,y/k);}\n double norm(){return x*x+y*y;}\n double abs(){return sqrt(norm());}\n\n bool operator < (const Point &p) const{\n return x!=p.x?x<p.x:y<p.y;\n //grid-point only\n //return !equals(x,p.x)?x<p.x:!equals(y,p.y)?y<p.y:0;\n }\n\n bool operator == (const Point &p) const{\n return fabs(x-p.x)<EPS && fabs(y-p.y)<EPS;\n }\n};\n\nstruct EndPoint{\n Point p;\n int seg,st;\n EndPoint(){}\n EndPoint(Point p,int seg,int st):p(p),seg(seg),st(st){}\n bool operator<(const EndPoint &ep)const{\n if(p.y==ep.p.y) return st<ep.st;\n return p.y<ep.p.y;\n }\n};\n\nistream &operator >> (istream &is,Point &p){\n is>>p.x>>p.y;\n return is;\n}\n\nostream &operator << (ostream &os,Point p){\n os<<fixed<<setprecision(12)<<p.x<<\" \"<<p.y;\n return os;\n}\n\nbool sort_x(Point a,Point b){\n return a.x!=b.x?a.x<b.x:a.y<b.y;\n}\n\nbool sort_y(Point a,Point b){\n return a.y!=b.y?a.y<b.y:a.x<b.x;\n}\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nistream &operator >> (istream &is,Polygon &p){\n for(int i=0;i<(int)p.size();i++) is>>p[i];\n return is;\n}\n\nstruct Segment{\n Point p1,p2;\n Segment(){}\n Segment(Point p1, Point p2):p1(p1),p2(p2){}\n};\ntypedef Segment Line;\n\nistream &operator >> (istream &is,Segment &s){\n is>>s.p1>>s.p2;\n return is;\n}\n\nstruct Circle{\n Point c;\n double r;\n Circle(){}\n Circle(Point c,double r):c(c),r(r){}\n};\n\nistream &operator >> (istream &is,Circle &c){\n is>>c.c>>c.r;\n return is;\n}\n\ndouble norm(Vector a){\n return a.x*a.x+a.y*a.y;\n}\ndouble abs(Vector a){\n return sqrt(norm(a));\n}\ndouble dot(Vector a,Vector b){\n return a.x*b.x+a.y*b.y;\n}\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\nPoint orth(Point p){return Point(-p.y,p.x);}\n\nbool isOrthogonal(Vector a,Vector b){\n return equals(dot(a,b),0.0);\n}\n\nbool isOrthogonal(Point a1,Point a2,Point b1,Point b2){\n return isOrthogonal(a1-a2,b1-b2);\n}\n\nbool isOrthogonal(Segment s1,Segment s2){\n return equals(dot(s1.p2-s1.p1,s2.p2-s2.p1),0.0);\n}\n\nbool isParallel(Vector a,Vector b){\n return equals(cross(a,b),0.0);\n}\n\nbool isParallel(Point a1,Point a2,Point b1,Point b2){\n return isParallel(a1-a2,b1-b2);\n}\n\nbool isParallel(Segment s1,Segment s2){\n return equals(cross(s1.p2-s1.p1,s2.p2-s2.p1),0.0);\n}\n\nPoint project(Segment s,Point p){\n Vector base=s.p2-s.p1;\n double r=dot(p-s.p1,base)/norm(base);\n return s.p1+base*r;\n}\n\nPoint reflect(Segment s,Point p){\n return p+(project(s,p)-p)*2.0;\n}\n\ndouble arg(Vector p){\n return atan2(p.y,p.x);\n}\n\nVector polar(double a,double r){\n return Point(cos(r)*a,sin(r)*a);\n}\n\nint ccw(Point p0,Point p1,Point p2);\nbool intersectSS(Point p1,Point p2,Point p3,Point p4);\nbool intersectSS(Segment s1,Segment s2);\nbool intersectPS(Polygon p,Segment l);\nint intersectCC(Circle c1,Circle c2);\nbool intersectSC(Segment s,Circle c);\ndouble getDistanceLP(Line l,Point p);\ndouble getDistanceSP(Segment s,Point p);\ndouble getDistanceSS(Segment s1,Segment s2);\nPoint getCrossPointSS(Segment s1,Segment s2);\nPoint getCrossPointLL(Line l1,Line l2);\nPolygon getCrossPointCL(Circle c,Line l);\nPolygon getCrossPointCC(Circle c1,Circle c2);\nint contains(Polygon g,Point p);\nPolygon andrewScan(Polygon s);\nPolygon convex_hull(Polygon ps);\ndouble diameter(Polygon s);\nbool isConvex(Polygon p);\ndouble area(Polygon s);\nPolygon convexCut(Polygon p,Line l);\nLine bisector(Point p1,Point p2);\nVector translate(Vector v,double theta);\nvector<Line> corner(Line l1,Line l2);\nvector< vector<int> >\nsegmentArrangement(vector<Segment> &ss, Polygon &ps);\n\nint ccw(Point p0,Point p1,Point p2){\n Vector a = p1-p0;\n Vector b = p2-p0;\n if(cross(a,b) > EPS) return CCW_COUNTER_CLOCKWISE;\n if(cross(a,b) < -EPS) return CCW_CLOCKWISE;\n if(dot(a,b) < -EPS) return CCW_ONLINE_BACK;\n if(a.norm()<b.norm()) return CCW_ONLINE_FRONT;\n return CCW_ON_SEGMENT;\n}\n\nbool intersectSS(Point p1,Point p2,Point p3,Point p4){\n return (ccw(p1,p2,p3)*ccw(p1,p2,p4) <= 0 &&\n ccw(p3,p4,p1)*ccw(p3,p4,p2) <= 0 );\n}\n\nbool intersectSS(Segment s1,Segment s2){\n return intersectSS(s1.p1,s1.p2,s2.p1,s2.p2);\n}\n\nbool intersectPS(Polygon p,Segment l){\n int n=p.size();\n for(int i=0;i<n;i++)\n if(intersectSS(Segment(p[i],p[(i+1)%n]),l)) return 1;\n return 0;\n}\n\nint intersectCC(Circle c1,Circle c2){\n if(c1.r<c2.r) swap(c1,c2);\n double d=abs(c1.c-c2.c);\n double r=c1.r+c2.r;\n if(equals(d,r)) return ICC_CIRCUMSCRIBE;\n if(d>r) return ICC_SEPERATE;\n if(equals(d+c2.r,c1.r)) return ICC_INSCRIBE;\n if(d+c2.r<c1.r) return ICC_CONTAIN;\n return ICC_INTERSECT;\n}\n\nbool intersectSC(Segment s,Circle c){\n return getDistanceSP(s,c.c)<=c.r;\n}\n\nint intersectCS(Circle c,Segment s){\n if(norm(project(s,c.c)-c.c)-c.r*c.r>EPS) return 0;\n double d1=abs(c.c-s.p1),d2=abs(c.c-s.p2);\n if(d1<c.r+EPS&&d2<c.r+EPS) return 0;\n if((d1<c.r-EPS&&d2>c.r+EPS)||(d1>c.r+EPS&&d2<c.r-EPS)) return 1;\n Point h=project(s,c.c);\n if(dot(s.p1-h,s.p2-h)<0) return 2;\n return 0;\n}\n\ndouble getDistanceLP(Line l,Point p){\n return abs(cross(l.p2-l.p1,p-l.p1)/abs(l.p2-l.p1));\n}\n\ndouble getDistanceSP(Segment s,Point p){\n if(dot(s.p2-s.p1,p-s.p1) < 0.0 ) return abs(p-s.p1);\n if(dot(s.p1-s.p2,p-s.p2) < 0.0 ) return abs(p-s.p2);\n return getDistanceLP(s,p);\n}\n\ndouble getDistanceSS(Segment s1,Segment s2){\n if(intersectSS(s1,s2)) return 0.0;\n return min(min(getDistanceSP(s1,s2.p1),getDistanceSP(s1,s2.p2)),\n min(getDistanceSP(s2,s1.p1),getDistanceSP(s2,s1.p2)));\n}\n\nPoint getCrossPointSS(Segment s1,Segment s2){\n for(int k=0;k<2;k++){\n if(getDistanceSP(s1,s2.p1)<EPS) return s2.p1;\n if(getDistanceSP(s1,s2.p2)<EPS) return s2.p2;\n swap(s1,s2);\n }\n Vector base=s2.p2-s2.p1;\n double d1=abs(cross(base,s1.p1-s2.p1));\n double d2=abs(cross(base,s1.p2-s2.p1));\n double t=d1/(d1+d2);\n return s1.p1+(s1.p2-s1.p1)*t;\n}\n\nPoint getCrossPointLL(Line l1,Line l2){\n double a=cross(l1.p2-l1.p1,l2.p2-l2.p1);\n double b=cross(l1.p2-l1.p1,l1.p2-l2.p1);\n if(abs(a)<EPS&&abs(b)<EPS) return l2.p1;\n return l2.p1+(l2.p2-l2.p1)*(b/a);\n}\n\nPolygon getCrossPointCL(Circle c,Line l){\n Polygon ps;\n Point pr=project(l,c.c);\n Vector e=(l.p2-l.p1)/abs(l.p2-l.p1);\n if(equals(getDistanceLP(l,c.c),c.r)){\n ps.emplace_back(pr);\n return ps;\n }\n double base=sqrt(c.r*c.r-norm(pr-c.c));\n ps.emplace_back(pr+e*base);\n ps.emplace_back(pr-e*base);\n return ps;\n}\n\nPolygon getCrossPointCS(Circle c,Segment s){\n Line l(s);\n Polygon res=getCrossPointCL(c,l);\n if(intersectCS(c,s)==2) return res;\n if(res.size()>1u){\n if(dot(l.p1-res[0],l.p2-res[0])>0) swap(res[0],res[1]);\n res.pop_back();\n }\n return res;\n}\n\n\nPolygon getCrossPointCC(Circle c1,Circle c2){\n Polygon p(2);\n double d=abs(c1.c-c2.c);\n double a=acos((c1.r*c1.r+d*d-c2.r*c2.r)/(2*c1.r*d));\n double t=arg(c2.c-c1.c);\n p[0]=c1.c+polar(c1.r,t+a);\n p[1]=c1.c+polar(c1.r,t-a);\n return p;\n}\n\n// IN:2 ON:1 OUT:0\nint contains(Polygon g,Point p){\n int n=g.size();\n bool x=false;\n for(int i=0;i<n;i++){\n Point a=g[i]-p,b=g[(i+1)%n]-p;\n if(fabs(cross(a,b)) < EPS && dot(a,b) < EPS) return 1;\n if(a.y>b.y) swap(a,b);\n if(a.y < EPS && EPS < b.y && cross(a,b) > EPS ) x = !x;\n }\n return (x?2:0);\n}\n\nPolygon andrewScan(Polygon s){\n Polygon u,l;\n if(s.size()<3) return s;\n sort(s.begin(),s.end());\n u.push_back(s[0]);\n u.push_back(s[1]);\n l.push_back(s[s.size()-1]);\n l.push_back(s[s.size()-2]);\n for(int i=2;i<(int)s.size();i++){\n for(int n=u.size();\n n>=2&&ccw(u[n-2],u[n-1],s[i])!=CCW_CLOCKWISE;\n n--){\n u.pop_back();\n }\n u.push_back(s[i]);\n }\n for(int i=s.size()-3;i>=0;i--){\n for(int n=l.size();\n n>=2&&ccw(l[n-2],l[n-1],s[i])!=CCW_CLOCKWISE;\n n--){\n l.pop_back();\n }\n l.push_back(s[i]);\n }\n reverse(l.begin(),l.end());\n for(int i=u.size()-2;i>=1;i--) l.push_back(u[i]);\n return l;\n}\n\nPolygon convex_hull(Polygon ps){\n int n=ps.size();\n sort(ps.begin(),ps.end(),sort_y);\n int k=0;\n Polygon qs(n*2);\n for(int i=0;i<n;i++){\n while(k>1&&cross(qs[k-1]-qs[k-2],ps[i]-qs[k-1])<0) k--;\n qs[k++]=ps[i];\n }\n for(int i=n-2,t=k;i>=0;i--){\n while(k>t&&cross(qs[k-1]-qs[k-2],ps[i]-qs[k-1])<0) k--;\n qs[k++]=ps[i];\n }\n qs.resize(k-1);\n return qs;\n}\n\ndouble diameter(Polygon s){\n Polygon p=s;\n int n=p.size();\n if(n==2) return abs(p[0]-p[1]);\n int i=0,j=0;\n for(int k=0;k<n;k++){\n if(p[i]<p[k]) i=k;\n if(!(p[j]<p[k])) j=k;\n }\n double res=0;\n int si=i,sj=j;\n while(i!=sj||j!=si){\n res=max(res,abs(p[i]-p[j]));\n if(cross(p[(i+1)%n]-p[i],p[(j+1)%n]-p[j])<0.0){\n i=(i+1)%n;\n }else{\n j=(j+1)%n;\n }\n }\n return res;\n}\n\nbool isConvex(Polygon p){\n bool f=1;\n int n=p.size();\n for(int i=0;i<n;i++){\n int t=ccw(p[(i+n-1)%n],p[i],p[(i+1)%n]);\n f&=t!=CCW_CLOCKWISE;\n }\n return f;\n}\n\ndouble area(Polygon s){\n double res=0;\n for(int i=0;i<(int)s.size();i++){\n res+=cross(s[i],s[(i+1)%s.size()])/2.0;\n }\n return res;\n}\n\ndouble area(Circle c1,Circle c2){\n double d=abs(c1.c-c2.c);\n if(c1.r+c2.r<=d+EPS) return 0;\n if(d<=abs(c1.r-c2.r)){\n double r=min(c1.r,c2.r);\n return PI*r*r;\n }\n double res=0;\n for(int k=0;k<2;k++){\n double rc=(d*d+c1.r*c1.r-c2.r*c2.r)/(2*d*c1.r);\n double th=acosl(rc)*2;\n res+=(th-sinl(th))*c1.r*c1.r/2;\n swap(c1,c2);\n }\n return res;\n}\n\nPolygon convexCut(Polygon p,Line l){\n Polygon q;\n for(int i=0;i<(int)p.size();i++){\n Point a=p[i],b=p[(i+1)%p.size()];\n if(ccw(l.p1,l.p2,a)!=-1) q.push_back(a);\n if(ccw(l.p1,l.p2,a)*ccw(l.p1,l.p2,b)<0)\n q.push_back(getCrossPointLL(Line(a,b),l));\n }\n return q;\n}\n\nLine bisector(Point p1,Point p2){\n Circle c1=Circle(p1,abs(p1-p2)),c2=Circle(p2,abs(p1-p2));\n Polygon p=getCrossPointCC(c1,c2);\n if(cross(p2-p1,p[0]-p1)>0) swap(p[0],p[1]);\n return Line(p[0],p[1]);\n}\n\nVector translate(Vector v,double theta){\n Vector res;\n res.x=cos(theta)*v.x-sin(theta)*v.y;\n res.y=sin(theta)*v.x+cos(theta)*v.y;\n return res;\n}\n\nvector<Line> corner(Line l1,Line l2){\n vector<Line> res;\n if(isParallel(l1,l2)){\n double d=getDistanceLP(l1,l2.p1)/2.0;\n Vector v1=l1.p2-l1.p1;\n v1=v1/v1.abs()*d;\n Point p=l2.p1+translate(v1,90.0*(PI/180.0));\n double d1=getDistanceLP(l1,p);\n double d2=getDistanceLP(l2,p);\n if(abs(d1-d2)>d){\n p=l2.p1+translate(v1,-90.0*(PI/180.0));\n }\n res.push_back(Line(p,p+v1));\n }else{\n Point p=getCrossPointLL(l1,l2);\n Vector v1=l1.p2-l1.p1,v2=l2.p2-l2.p1;\n v1=v1/v1.abs();\n v2=v2/v2.abs();\n res.push_back(Line(p,p+(v1+v2)));\n res.push_back(Line(p,p+translate(v1+v2,90.0*(PI/180.0))));\n }\n return res;\n}\n\nPolygon tangent(Circle c1,Point p2){\n Circle c2=Circle(p2,sqrt(norm(c1.c-p2)-c1.r*c1.r));\n Polygon p=getCrossPointCC(c1,c2);\n sort(p.begin(),p.end());\n return p;\n}\n\nvector<Line> tangent(Circle c1,Circle c2){\n vector<Line> ls;\n if(c1.r<c2.r) swap(c1,c2);\n double g=norm(c1.c-c2.c);\n if(equals(g,0)) return ls;\n Point u=(c2.c-c1.c)/sqrt(g);\n Point v=orth(u);\n for(int s=1;s>=-1;s-=2){\n double h=(c1.r+s*c2.r)/sqrt(g);\n if(equals(1-h*h,0)){\n ls.emplace_back(c1.c+u*c1.r,c1.c+(u+v)*c1.r);\n }else if(1-h*h>0){\n Point uu=u*h,vv=v*sqrt(1-h*h);\n ls.emplace_back(c1.c+(uu+vv)*c1.r,c2.c-(uu+vv)*c2.r*s);\n ls.emplace_back(c1.c+(uu-vv)*c1.r,c2.c-(uu-vv)*c2.r*s);\n }\n }\n\n return ls;\n}\n\ndouble closest_pair(Polygon &a,int l=0,int r=-1){\n if(r<0){\n r=a.size();\n sort(a.begin(),a.end(),sort_x);\n }\n if(r-l<=1) return abs(a[0]-a[1]);\n int m=(l+r)>>1;\n double x=a[m].x;\n double d=min(closest_pair(a,l,m),closest_pair(a,m,r));\n inplace_merge(a.begin()+l,a.begin()+m,a.begin()+r,sort_y);\n\n Polygon b;\n for(int i=l;i<r;i++){\n if(fabs(a[i].x-x)>=d) continue;\n for(int j=0;j<(int)b.size();j++){\n double dy=a[i].y-next(b.rbegin(),j)->y;\n if(dy>=d) break;\n d=min(d,abs(a[i]-*next(b.rbegin(),j)));\n }\n b.emplace_back(a[i]);\n }\n return d;\n}\n\nvector<vector<int> >\nsegmentArrangement(vector<Segment> &ss, Polygon &ps){\n int n=ss.size();\n for(int i=0;i<n;i++){\n ps.emplace_back(ss[i].p1);\n ps.emplace_back(ss[i].p2);\n for(int j=i+1;j<n;j++)\n if(intersectSS(ss[i],ss[j]))\n ps.emplace_back(getCrossPointSS(ss[i],ss[j]));\n }\n sort(ps.begin(),ps.end());\n ps.erase(unique(ps.begin(),ps.end()),ps.end());\n\n vector<vector<int> > G(ps.size());\n for(int i=0;i<n;i++){\n vector<pair<double,int> > ls;\n for(int j=0;j<(int)ps.size();j++)\n if(getDistanceSP(ss[i],ps[j])<EPS)\n ls.emplace_back(make_pair(norm(ss[i].p1-ps[j]),j));\n\n sort(ls.begin(),ls.end());\n for(int j=0;j+1<(int)ls.size();j++){\n int a=ls[j].second,b=ls[j+1].second;\n G[a].emplace_back(b);\n G[b].emplace_back(a);\n }\n }\n for(auto &v:G){\n sort(v.begin(),v.end());\n v.erase(unique(v.begin(),v.end()),v.end());\n }\n return G;\n}\n\nint manhattan_intersection(vector<Segment> ss,const int INF){\n const int BTM = 0;\n const int LFT = 1;\n const int RGH = 2;\n const int TOP = 3;\n\n int n=ss.size();\n vector<EndPoint> ep;\n for(int i=0;i<n;i++){\n if(ss[i].p1.y==ss[i].p2.y){\n if(ss[i].p1.x>ss[i].p2.x) swap(ss[i].p1,ss[i].p2);\n ep.emplace_back(ss[i].p1,i,LFT);\n ep.emplace_back(ss[i].p2,i,RGH);\n }else{\n if(ss[i].p1.y>ss[i].p2.y) swap(ss[i].p1,ss[i].p2);\n ep.emplace_back(ss[i].p1,i,BTM);\n ep.emplace_back(ss[i].p2,i,TOP);\n }\n }\n sort(ep.begin(),ep.end());\n\n set<int> bt;\n bt.insert(INF);\n\n int cnt=0;\n for(int i=0;i<n*2;i++){\n if(ep[i].st==TOP){\n bt.erase(ep[i].p.x);\n }else if(ep[i].st==BTM){\n bt.emplace(ep[i].p.x);\n }else if(ep[i].st==LFT){\n auto b=bt.lower_bound(ss[ep[i].seg].p1.x);\n auto e=bt.upper_bound(ss[ep[i].seg].p2.x);\n cnt+=distance(b,e);\n }\n }\n\n return cnt;\n}\n\ndouble area(Polygon ps,Circle c){\n if(ps.size()<3u) return 0;\n function<double(Circle, Point, Point)> dfs=\n [&](Circle c,Point a,Point b){\n Vector va=c.c-a,vb=c.c-b;\n double f=cross(va,vb),res=0;\n if(equals(f,0.0)) return res;\n if(max(abs(va),abs(vb))<c.r+EPS) return f;\n Vector d(dot(va,vb),cross(va,vb));\n if(getDistanceSP(Segment(a,b),c.c)>c.r-EPS)\n return c.r*c.r*atan2(d.y,d.x);\n auto u=getCrossPointCS(c,Segment(a,b));\n if(u.empty()) return res;\n if(u.size()>1u&&dot(u[1]-u[0],a-u[0])>0) swap(u[0],u[1]);\n u.emplace(u.begin(),a);\n u.emplace_back(b);\n for(int i=1;i<(int)u.size();i++)\n res+=dfs(c,u[i-1],u[i]);\n return res;\n };\n double res=0;\n for(int i=0;i<(int)ps.size();i++)\n res+=dfs(c,ps[i],ps[(i+1)%ps.size()]);\n return res/2;\n}\n\n\nstruct Precision{\n Precision(){\n cout<<fixed<<setprecision(12);\n }\n}precision_beet;\n\n\ntemplate<typename F>\nstruct FixPoint : F{\n FixPoint(F&& f):F(forward<F>(f)){}\n template<typename... Args>\n decltype(auto) operator()(Args&&... args) const{\n return F::operator()(*this,forward<Args>(args)...);\n }\n};\ntemplate<typename F>\ninline decltype(auto) MFP(F&& f){\n return FixPoint<F>{forward<F>(f)};\n}\n\n//INSERT ABOVE HERE\nsigned main(){\n int n;\n while(cin>>n,n){\n vector<Segment> ss(n);\n for(int i=0;i<n;i++)\n cin>>ss[i].p1>>ss[i].p2;\n Point s,t;\n cin>>s>>t;\n\n double ans=1e18;\n vector<int> vs(7);\n MFP([&](auto dfs,int x)->void{\n const int DEBUG = 0;\n {\n int flg=1;\n\n Point p(s),q(t);\n for(int i=x-1;i>=0;i--)\n q=reflect(ss[vs[i]],q);\n\n if(DEBUG){\n cout<<q<<\":\"<<abs(p-q)<<endl;\n }\n\n double res=0;\n for(int i=0;i<x;i++){\n if(DEBUG){\n cout<<i<<\":i:\"<<getDistanceSS(Segment(p,q),ss[vs[i]])<<endl;\n cout<<p<<\" \"<<q<<endl;\n }\n\n flg&=getDistanceSS(Segment(p,q),ss[vs[i]])<EPS;\n if(!flg) break;\n Point pp=p;\n p=getCrossPointSS(Segment(p,q),ss[vs[i]]);\n res+=abs(p-pp);\n\n for(int j=0;j<n;j++){\n if(j==vs[i]) continue;\n if(i&&j==vs[i-1]) continue;\n flg&=getDistanceSS(Segment(pp,p),ss[j])>EPS;\n }\n\n q=reflect(ss[vs[i]],q);\n }\n\n if(DEBUG){\n cout<<p<<\" \"<<q<<endl;\n cout<<\"flg:\"<<flg<<endl;\n }\n\n for(int j=0;j<n;j++)\n if(x==0||j!=vs[x-1]) flg&=getDistanceSS(Segment(p,q),ss[j])>EPS;\n\n res+=abs(p-q);\n if(flg) chmin(ans,res);\n\n if(DEBUG){\n cout<<res<<endl;\n for(int i=0;i<x;i++) cout<<vs[i]<<\" \";\n cout<<endl;\n cout<<endl;\n }\n }\n\n if(x==7) return;\n for(int i=0;i<n;i++){\n vs[x]=i;\n dfs(x+1);\n }\n })(0);\n cout<<ans<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 680, "memory_kb": 3324, "score_of_the_acc": -1.1389, "final_rank": 20 }, { "submission_id": "aoj_1171_3709507", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll=long long;\n#define int ll\n\n#define rng(i,a,b) for(int i=int(a);i<int(b);i++)\n#define rep(i,b) rng(i,0,b)\n#define gnr(i,a,b) for(int i=int(b)-1;i>=a;i--)\n#define per(i,b) gnr(i,0,b)\n#define pb push_back\n#define eb emplace_back\n#define a first\n#define b second\n#define bg begin()\n#define ed end()\n#define all(x) x.bg,x.ed\n#ifdef LOCAL\n#define dmp(x) cerr<<__LINE__<<\" \"<<#x<<\" \"<<x<<endl\n#else\n#define dmp(x) void(0)\n#endif\n\ntemplate<class t,class u> void chmax(t&a,u b){if(a<b)a=b;}\ntemplate<class t,class u> void chmin(t&a,u b){if(b<a)a=b;}\n\ntemplate<class t> using vc=vector<t>;\ntemplate<class t> using vvc=vc<vc<t>>;\n\nusing pi=pair<int,int>;\nusing vi=vc<int>;\n\ntemplate<class t,class u>\nostream& operator<<(ostream& os,const pair<t,u>& p){\n\treturn os<<\"{\"<<p.a<<\",\"<<p.b<<\"}\";\n}\n\ntemplate<class t> ostream& operator<<(ostream& os,const vc<t>& v){\n\tos<<\"{\";\n\tfor(auto e:v)os<<e<<\",\";\n\treturn os<<\"}\";\n}\n\nusing ld=long double;\nusing cm=complex<ld>;\n#define x real()\n#define y imag()\nconst ld eps=1e-8;\nconst ld PI=acos(ld(-1));\nint sgn(ld a){return a<-eps?-1:(a>eps?1:0);}\nld dot(cm a,cm b){return a.x*b.x+a.y*b.y;}\nld crs(cm a,cm b){return a.x*b.y-a.y*b.x;}\nld crs(cm a,cm b,cm c){return crs(b-a,c-a);}\nint ccw(cm a,cm b){return sgn(crs(a,b));}\nint ccw(cm a,cm b,cm c){return ccw(b-a,c-a);}\nauto cmcmp=[](cm a,cm b){\n\tint s=sgn(a.x-b.x);\n\tif(s)return s<0;\n\telse return sgn(a.y-b.y)<0;\n};\nbool cmeq(cm a,cm b){\n\treturn sgn(a.x-b.x)==0&&sgn(a.y-b.y)==0;\n};\n//(-pi,0](0,pi]\nint argtype(cm a){\n\tif(sgn(a.y)==0)return a.x<0?1:0;\n\treturn a.y<0?0:1;\n}\nint argcmp(cm a,cm b){\n\tint at=argtype(a),bt=argtype(b);\n\tif(at!=bt)return at<bt?-1:1;\n\treturn -ccw(a,b);\n};\n//(-2)[a,-1](0)[b,1](2)\nint bet(cm a,cm b,cm c){\n\tcm d=b-a;\n\tld e=dot(d,c-a);\n\tif(sgn(e)<=0)return sgn(e)-1;\n\treturn sgn(e-norm(d))+1;\n}\n\nusing ln=pair<cm,cm>;\ncm dir(ln a){return a.b-a.a;}\ncm eval(ln a,ld b){return a.a+dir(a)*b;}\nint bet(ln a,cm b){return bet(a.a,a.b,b);}\nint ccw(ln a,cm b){return ccw(a.a,a.b,b);}\ncm proj(ln a,cm b){\n\tcm c=dir(a);\n\treturn a.a+c*dot(c,b-a.a)/norm(c);\n}\ncm refl(ln a,cm b){\n\treturn ld(2)*proj(a,b)-b;\n}\n//AOJ0153\nld dsp(ln a,cm b){\n\tcm c=proj(a,b);\n\tif(abs(bet(a.a,a.b,c))<=1)return abs(b-c);\n\treturn min(abs(b-a.a),abs(b-a.b));\n}\n//AOJ1157\n//0-no,1-yes(endpoint),2-yes(innner),3-overelap\nint iss(ln a,ln b){\n\tint c1=ccw(a.a,a.b,b.a),c2=ccw(a.a,a.b,b.b);\n\tint d1=ccw(b.a,b.b,a.a),d2=ccw(b.a,b.b,a.b);\n\tif(c1||c2||d1||d2)return 1-max(c1*c2,d1*d2);\n\tint f=bet(a.a,a.b,b.a),g=bet(a.a,a.b,b.b);\n\tif(max(f,g)==-2||min(f,g)==2)return 0;\n\treturn 3;\n}\n//AOJ1033\ncm cll(ln a,ln b){\n\treturn eval(a,crs(b.a,b.b,a.a)/crs(dir(a),dir(b)));\n}\n\nsigned main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\tcout<<fixed<<setprecision(20);\n\t\n\twhile(1){\n\t\tint n;cin>>n;\n\t\tif(n==0)break;\n\t\tvc<ln> ms;\n\t\trep(i,n){\n\t\t\tld a,b,c,d;cin>>a>>b>>c>>d;\n\t\t\tms.eb(cm(a,b),cm(c,d));\n\t\t}\n\t\tcm s,t;\n\t\t{\n\t\t\tld a,b;cin>>a>>b;\n\t\t\ts=cm(a,b);\n\t\t}\n\t\t{\n\t\t\tld a,b;cin>>a>>b;\n\t\t\tt=cm(a,b);\n\t\t}\n\t\tauto chk=[&](ln a){\n\t\t\tfor(auto l:ms)\n\t\t\t\tif(iss(l,a)==2)return false;\n\t\t\treturn true;\n\t\t};\n\t\tdouble ans=1e9;\n\t\tauto upd=[&](vi idx){\n\t\t\tvc<ln> cur=ms,r;\n\t\t\tcm g=t;\n\t\t\tfor(auto i:idx){\n\t\t\t\tr.pb(cur[i]);\n\t\t\t\tln w=cur[i];\n\t\t\t\tfor(auto&l:cur)\n\t\t\t\t\tl=ln(refl(w,l.a),refl(w,l.b));\n\t\t\t\tg=refl(w,g);\n\t\t\t}\n\t\t\tvc<cm> ps{s};\n\t\t\tfor(auto l:r){\n\t\t\t\tif(iss(ln(s,g),l)==2)\n\t\t\t\t\tps.pb(cll(ln(s,g),l));\n\t\t\t\telse\n\t\t\t\t\treturn;\n\t\t\t}\n\t\t\tps.pb(g);\n\t\t\tdmp(idx);\n\t\t\tdmp(ps);\n\t\t\trep(i,ps.size()-2)\n\t\t\t\tif(bet(ps[i],ps[i+2],ps[i+1]))\n\t\t\t\t\treturn;\n\t\t\trep(i,r.size())\n\t\t\t\trng(j,ps.size()-1-i,ps.size())\n\t\t\t\t\tps[j]=refl(r[r.size()-1-i],ps[j]);\n\t\t\tdmp(idx);\n\t\t\trep(i,ps.size()-1)\n\t\t\t\tif(!chk(ln(ps[i],ps[i+1])))\n\t\t\t\t\treturn;\n\t\t\tdmp(idx);\n\t\t\tchmin(ans,abs(g-s));\n\t\t};\n\t\tfunction<void(vi)>dfs=[&](vi idx){\n\t\t\tupd(idx);\n\t\t\tif(idx.size()<6){\n\t\t\t\tint last=-1;\n\t\t\t\tif(idx.size())last=idx.back();\n\t\t\t\trep(i,n)if(i!=last){\n\t\t\t\t\tvi nx=idx;\n\t\t\t\t\tnx.pb(i);\n\t\t\t\t\tdfs(nx);\n\t\t\t\t}\n\t\t\t}\n\t\t};\n\t\tdfs({});\n\t\tcout<<ans<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 610, "memory_kb": 3308, "score_of_the_acc": -1.0122, "final_rank": 18 }, { "submission_id": "aoj_1171_3616414", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\n#include<vector>\n#include<iomanip>\n#include<math.h>\n#include<complex>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<map>\n#include<set>\n#include<bitset>\n#include<functional>\n#include<assert.h>\n#include<numeric>\nusing namespace std;\n#define REP(i,m,n) for(int i=(int)(m) ; i < (int) (n) ; ++i )\n#define rep(i,n) REP(i,0,n)\nusing ll = long long;\nconst int inf=1e9+7;\nconst ll longinf=1LL<<60 ;\nconst ll mod=1e9+7 ;\nusing ld = double;\nusing Point = complex<ld>;\nconst ld eps = 1e-9;\nconst ld pi = acos(-1.0);\n\nbool eq(ld a, ld b) {\n\treturn (abs(a - b) < eps);\n}\n\nbool cmp(Point x,Point y){\n\tif(eq(x.real(),y.real()))return x.imag()<y.imag();\n\treturn x.real()<y.real();\n}\n\nbool eqq(Point x,Point y){\n\treturn eq(x.real(),y.real())&&eq(x.imag(),y.imag());\n}\n//内積\nld dot(Point a, Point b) {\n\treturn real(conj(a)*b);\n}\n//外積\nld cross(Point a, Point b) {\n\treturn imag(conj(a)*b);\n}\n\n\n//線分\n//直線にするなら十分通い2点を端点とすればよい\nclass Line {\npublic:\n\tPoint a, b;\n};\n//円\nclass Circle {\npublic:\n\tPoint p;\n\tld r;\n};\n//3点の位置関係\nint ccw(Point a, Point b, Point c) {\n\tb -= a; c -= a;\n\tif (cross(b, c) > eps)return 1;//a,b,cが反時計回り\n\tif (cross(b, c) < -eps)return -1;//a,b,cが時計回り\n\tif (dot(b, c) < 0)return 2;//c,a,bの順に一直線\n\tif (norm(b) < norm(c))return -2;//a,b,cの順に一直線\n\treturn 0;//a,c,bの順に一直線\n}\n//2直線の交差判定\nbool isis_ll(Line l, Line m) {\n\treturn !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\n//直線と線分の交差判定\nbool isis_ls(Line l, Line s) {\n\treturn (cross(l.b - l.a, s.a - l.a)*cross(l.b - l.a, s.b - l.a) < eps);\n}\n//点が直線上に存在するか\nbool isis_lp(Line l, Point p) {\n\treturn (abs(cross(l.b - p, l.a - p)) < eps);\n}\n//点が線分上に存在するか\nbool isis_sp(Line s, Point p) {\n\treturn (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n//線分と線分の交差判定\nbool isis_ss(Line s, Line t) {\n\tif (isis_sp(s, t.a) || isis_sp(s, t.b) || isis_sp(t, s.a) || isis_sp(t, s.b))return true;\n\treturn(cross(s.b - s.a, t.a - s.a)*cross(s.b - s.a, t.b - s.a) < -eps && cross(t.b - t.a, s.a - t.a)*cross(t.b - t.a, s.b - t.a) < -eps);\n}\n//点から直線への垂線の足\nPoint proj(Line l, Point p) {\n\tld t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n\treturn l.a + t * (l.a - l.b);\n}\n//直線と直線の交点\n//平行な2直線に対しては使うな!!!!\nPoint is_ll(Line s, Line t) {\n\tPoint sv = s.b - s.a; Point tv = t.b - t.a;\n\treturn s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n//直線と点の距離\nld dist_lp(Line l, Point p) {\n\treturn abs(p - proj(l, p));\n}\n//直線と直線の距離\nld dist_ll(Line l, Line m) {\n\treturn isis_ll(l, m) ? 0 : dist_lp(l, m.a);\n}\n//線分と直線の距離\nld dist_ls(Line l, Line s) {\n\treturn isis_ls(l, s) ? 0 : min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\n//線分と点の距離\nld dist_sp(Line s, Point p) {\n\tPoint r = proj(s, p);\n\treturn isis_sp(s, r) ? abs(p - r) : min(abs(p - s.a), abs(p - s.b));\n}\n//線分と線分の距離\nld dist_ss(Line s, Line t) {\n\tif (isis_ss(s, t))return 0;\n\treturn min({ dist_sp(s,t.a),dist_sp(s,t.b),dist_sp(t,s.a),dist_sp(t,s.b) });\n}\n\nPoint cont(Line l,Point p){\n Point h = proj(l,p);\n return 2.0*h-p;\n}\nLine seg[10];\nPoint st,gl;\nint m;\nld solve(vector<int>&v){\n int n=v.size();\n Point g=gl;\n for(int i=n-1;i>=0;--i){\n g=cont(seg[v[i]],g);\n }\n vector<Point> root;\n root.push_back(st);\n rep(i,n){\n if(!isis_ss(Line{root.back(),g},seg[v[i]]))return longinf;\n root.push_back(is_ll(Line{root.back(),g},seg[v[i]]));\n g=cont(seg[v[i]],g);\n }\n root.push_back(gl);\n ld ans=0;\n rep(i,n+1){\n rep(j,m){\n if(i<n&&v[i]==j)continue;\n if(i>0&&v[i-1]==j)continue;\n if(isis_ss(Line{root[i],root[i+1]},seg[j]))return longinf;\n }\n ans+=abs(root[i+1]-root[i]);\n }\n return ans;\n}\n\n\n\nvoid solve(){\n rep(i,m){\n double x1,y1,x2,y2;\n cin>>x1>>y1>>x2>>y2;\n seg[i]={Point(x1,y1),Point(x2,y2)};\n }\n \n double x,y;\n cin>>x>>y;\n st=Point(x,y);\n cin>>x>>y;\n gl=Point(x,y);\n ld ans=longinf;\n rep(i,6){\n int all=pow(m,i);\n rep(j,all){\n vector<int> v;\n int mask=j;\n rep(k,i){\n v.push_back(mask%m);\n mask/=m;\n }\n bool ok=true;\n rep(k,i-1){\n if(v[k]==v[k+1])ok=false;\n }\n if(ok)ans=min(ans,solve(v));\n }\n }\n cout<<ans<<endl;\n}\nint main(){\n cout<<fixed<<setprecision(12);\n while(cin>>m,m!=0)solve();\n \n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3408, "score_of_the_acc": -0.2705, "final_rank": 6 }, { "submission_id": "aoj_1171_2633851", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <complex>\n#include <vector>\n#include <algorithm>\n#include <cmath>\nusing namespace std;\n\nconst double EPS = 1e-10;\nconst double INF = 1e12;\n#define EQ(n,m) (abs((n)-(m)) < EPS)\n#define X real()\n#define Y imag()\n\ntypedef complex<double> P;\ntypedef vector<P> VP;\nstruct L : VP{\n L(const P& a, const P& b){ resize(2); at(0)=a; at(1)=b; }\n L(){ resize(2); }\n};\n\nnamespace std{\n\tbool operator < (const P &a, const P &b){\n\t\treturn (a.X!=b.X)? a.X<b.X : a.Y<b.Y;\n\t}\n}\n\ndouble dot(P a, P b){\n return (conj(a)*b).X;\n}\ndouble cross(P a, P b){\n return (conj(a)*b).Y;\n}\n\nint ccw(P a, P b, P c){\n b -= a;\n c -= a;\n if(cross(b,c) > EPS) return +1; //ccw\n if(cross(b,c) <-EPS) return -1; //cw\n if(dot(b,c) < EPS) return +2; //c-a-b\n if(norm(b) < norm(c)) return -2; //a-b-c\n return 0; //a-c-b\n}\nbool intersectSS(const L& s, const L& t){\n return ( ccw(s[0],s[1],t[0]) *ccw(s[0],s[1],t[1]) <= 0 ) &&\n ( ccw(t[0],t[1],s[0]) *ccw(t[0],t[1],s[1]) <= 0 );\n}\nbool strictItsSS(const L& s, const L& t){\n return ( ccw(s[0],s[1],t[0]) *ccw(s[0],s[1],t[1]) == -1 ) &&\n ( ccw(t[0],t[1],s[0]) *ccw(t[0],t[1],s[1]) == -1);\n}\n\nP projection(const L& l, const P& p) {\n double t = dot(p-l[0], l[0]-l[1]) / norm(l[0]-l[1]);\n return l[0] + t*(l[0]-l[1]);\n}\nP reflection(const L& l, const P& p) {\n return p + 2.0*(projection(l, p) -p);\n}\n \nP crosspointLL(const L &l, const L &m) {\n double A = cross(l[1]-l[0], m[1]-m[0]);\n double B = cross(l[1]-l[0], l[1]-m[0]);\n return m[0] + B /A *(m[1]-m[0]);\n}\nbool isParallel(const P &a, const P &b){\n return abs(cross(a,b)) < EPS;\n}\nbool isParallel(const L &a, const L &b){\n return isParallel(a[1]-a[0], b[1]-b[0]);\n}\n\n\nvector<int> idx(10, -1);\ndouble solve(int step, int end, P s, P g, vector<vector<L> > &wall){\n if(step==end){\n \tVP cp(step+2);\n \tcp[0]=s; cp[step+1]=g;\n L ray(s,g);\n bool flag = true;\n for(int i=1; i<=step; i++){\n if(!isParallel(ray, wall[i][idx[i]]) && strictItsSS(ray, wall[i][idx[i]])){\n cp[i] = crosspointLL(ray, wall[i][idx[i]]);\n }else{\n \tflag = false;\n \tbreak;\n }\n }\n if(flag){\n \tfor(int i=0; i<=step; i++){\n \t\tif((s<g && cp[i+1]<cp[i]) || (g<s && cp[i]<cp[i+1])){\n \t\t\tflag = false;\n \t\t\tbreak;\n \t\t}\n \t}\n }\n \n if(flag){\n \tfor(int i=0; i<=step; i++){\n \t\tL cut_ray(cp[i], cp[i+1]);\n \t\tfor(int j=0; j<(int)wall[0].size(); j++){\n \t\t\tif(j==idx[i] || j==idx[i+1]) continue;\n \t\t\tif(intersectSS(cut_ray, wall[i][j])){\n \t\t\t\tflag = false;\n \t\t\t\tbreak;\n \t\t\t}\n \t\t}\n \t}\n }\n \n if(flag){\n return abs(g-s);\n }else{\n return INF;\n }\n }\n \n double ans = INF;\n for(int i=0; i<(int)wall[0].size(); i++){\n if(idx[step]==i) continue;\n idx[step+1] = i;\n for(int j=0; j<(int)wall[0].size(); j++){\n wall[step+1][j] = L(reflection(wall[step][i], wall[step][j][0]), reflection(wall[step][i], wall[step][j][1]));\n }\n ans = min(ans, solve(step+1, end, s, reflection(wall[step][i], g), wall));\n idx[step+1] = -1;\n }\n return ans;\n}\n\ndouble search(P s, P g, vector<vector<L> > &wall){\n double ans = INF;\n for(int i=0; i<6; i++){\n ans = min(ans, solve(0,i,s,g,wall));\n }\n return ans;\n}\n\nint main(){\n while(1){\n int n;\n cin >> n;\n if(n==0) break;\n \n vector<vector<L> > wall(6, vector<L>(n));\n for(int i=0; i<n; i++){\n for(int j=0; j<2; j++){\n double x,y;\n cin >> x >> y;\n wall[0][i][j] = P(x,y);\n }\n }\n double sx,sy,gx,gy;\n cin >> gx >> gy >> sx >> sy;\n P s(sx,sy), g(gx, gy);\n\n cout << fixed;\n cout << setprecision(10);\n cout << search(s,g,wall) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3244, "score_of_the_acc": -0.0427, "final_rank": 1 }, { "submission_id": "aoj_1171_2563715", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef complex<double> P;\ntypedef pair<P,P> L;\n\nconst double EPS = 1e-7;\n\ndouble dot(P a, P b){ return real(conj(a)*b); }\ndouble cross(P a, P b){ return imag(conj(a)*b); }\n\nint ccw(P a, P b, P c){\n b -= a;\n c -= a;\n if(cross(b,c) > EPS) return 1;\n if(cross(b,c) < -EPS) return -1;\n if(dot(b,c) < -EPS) return 2;\n if(norm(b) < norm(c)) return -2;\n return 0;\n}\n\nP proj(P p, L l){\n return l.first + dot(p - l.first, l.second - l.first) / norm(l.second - l.first) * (l.second - l.first);\n}\n\nP reflect(P p, L l){\n return p + (proj(p,l) - p) * 2.0;\n}\n\nbool isIntersect(L s1, L s2){\n return ( ccw(s1.first,s1.second,s2.first) * ccw(s1.first,s1.second,s2.second) <= 0 &&\n ccw(s2.first,s2.second,s1.first) * ccw(s2.first,s2.second,s1.second) <= 0 );\n}\n\nP crossPoint(L l, L m){\n double A = cross(l.second - l.first, m.second - m.first);\n double B = cross(l.second - l.first, l.second - m.first);\n if(fabs(A) < EPS && fabs(B) < EPS) return m.first;\n else if(fabs(A) >= EPS) return m.first + B / A * (m.second - m.first);\n}\n\nL refL(L a,L b){\n return L(reflect(a.first,b),reflect(a.second,b));\n}\n\nint n;\nL m[5];\nint dm[5];\nP g,s;\ndouble ans;\n\ndouble check(int d){\n vector<L> gm[8];\n L tp[5],tm[5];\n P gg=g;\n \n for(int i=0;i<n;i++)tp[i]=m[i];\n bool ff=0;\n if(d==2&&dm[0]==1&&dm[1]==0)ff=1;\n for(int i=0;i<d;i++){\n\n for(int j=0;j<n;j++){\n\n if(dm[i]==j) tm[i]=tp[j];\n else if(!i||dm[i-1]!=j)gm[i].push_back(tp[j]);\n\n }\n\n for(int j=0;j<n;j++)tp[j]=refL(tp[j],tm[i]);\n gg=reflect(gg,tm[i]);\n }\n \n for(int i=0;i<n;i++)\n if(!d||dm[d-1]!=i)gm[d].push_back(tp[i]);\n\n L sg=L(s,gg);\n double res=abs(s-gg);\n\n vector<P> v;\n\n v.push_back(s);\n for(int i=0;i<d;i++){\n if(!isIntersect(sg,tm[i]))res=1e9;\n v.push_back(crossPoint(sg,tm[i]));\n }\n \n v.push_back(gg);\n double dd=0;\n for(int i=0;i<=d;i++){\n L ww=L(v[i],v[i+1]);\n dd+=abs(v[i]-v[i+1]);\n for(int j=0;j<(int)gm[i].size();j++)\n if(isIntersect(ww,gm[i][j]))res=1e9;\n }\n if(abs(dd-res)>EPS)res=1e9;\n return res;\n}\n\nvoid dfs(int pr,int d){\n ans=min(ans,check(d));\n if(d==5)return;\n for(int i=0;i<n;i++){\n if(pr==i)continue;\n dm[d]=i;\n dfs(i,d+1);\n }\n}\n\nint main(){\n while(cin>>n,n){\n double x1,y1,x2,y2;\n for(int i=0;i<n;i++){\n cin>>x1>>y1>>x2>>y2;\n m[i]=L(P(x1,y1),P(x2,y2));\n }\n cin>>x1>>y1>>x2>>y2;\n g=P(x1,y1),s=P(x2,y2);\n ans=1e9;\n dfs(-1,0);\n printf(\"%f\\n\",ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3224, "score_of_the_acc": -0.1194, "final_rank": 3 } ]
aoj_1169_cpp
Problem E: The Most Powerful Spell Long long ago, there lived a wizard who invented a lot of "magical patterns." In a room where one of his magical patterns is drawn on the floor, anyone can use magic by casting magic spells! The set of spells usable in the room depends on the drawn magical pattern. Your task is to compute, for each given magical pattern, the most powerful spell enabled by the pattern. A spell is a string of lowercase letters. Among the spells, lexicographically earlier one is more powerful. Note that a string w is defined to be lexicographically earlier than a string u when w has smaller letter in the order a<b<...<z on the first position at which they differ, or w is a prefix of u . For instance, "abcd" is earlier than "abe" because 'c' < 'e', and "abe" is earlier than "abef" because the former is a prefix of the latter. A magical pattern is a diagram consisting of uniquely numbered nodes and arrows connecting them. Each arrow is associated with its label , a lowercase string. There are two special nodes in a pattern, called the star node and the gold node . A spell becomes usable by a magical pattern if and only if the spell emerges as a sequential concatenation of the labels of a path from the star to the gold along the arrows. The next figure shows an example of a pattern with four nodes and seven arrows. The node 0 is the star node and 2 is the gold node. One example of the spells that become usable by this magical pattern is "abracadabra", because it appears in the path 0 --"abra"--> 1 --"cada"--> 3 --"bra"--> 2. Another example is "oilcadabraketdadabra", obtained from the path 0 --"oil"--> 1 --"cada"--> 3 --"bra"--> 2 --"ket"--> 3 --"da"--> 3 --"da"--> 3 --"bra"--> 2. The spell "abracadabra" is more powerful than "oilcadabraketdadabra" because it is lexicographically earlier. In fact, no other spell enabled by the magical pattern is more powerful than "abracadabra". Thus "abracadabra" is the answer you have to compute. When you cannot determine the most powerful spell, please answer "NO". There are two such cases. One is the case when no path exists from the star node to the gold node. The other case is when for every usable spell there always exist more powerful spells. The situation is exemplified in the following figure: "ab" is more powerful than "b", and "aab" is more powerful than "ab", and so on. For any spell, by prepending "a", we obtain a lexicographically earlier (hence more powerful) spell. Input The input consists of at most 150 datasets. Each dataset is formatted as follows. n a s g x 1 y 1 lab 1 x 2 y 2 lab 2 ... x a y a lab a The first line of a dataset contains four integers. n is the number of the nodes, and a is the number of the arrows. The numbers s and g indicate the star node and the gold node, respectively. Then a lines describing the arrows follow. Each line consists of two integers and one string. The line " x i y i lab i " represents an arrow from the node x i to the node y i with the associ ...(truncated)
[ { "submission_id": "aoj_1169_10853923", "code_snippet": "/*\n* Copyright (C) 2015 All rights reserved.\n* \n* filename: 9019.cpp\n* author: doublehh\n* e-mail: [email protected]\n* create time: 2015-06-08\n* last modified: 2015-06-08 16:08:16\n*/\n#include<bits/stdc++.h>\nusing namespace std;\n\nconst int maxn = 40, maxm = 400;\nint n, m, s, t;\nint u[maxm], v[maxm];\nstring w[maxm];\nstring d[maxn];\n\nvoid init()\n{\n\tfor (int i = 0; i < n; i++)\n\t\td[i] = \"-\";\n\tfor (int i = 0; i < m; i++)\n\t\tcin >> u[i] >> v[i] >> w[i];\n}\n\nstring solve()\n{\n\td[t] = \"\";\n\tfor (int clk = 0; ; )\n\t{\n\t\tbool flag = false;\n\t\tfor (int i = 0; i < m; i++) if (d[v[i]] != \"-\")\n\t\t{\n\t\t\tif (d[u[i]] == \"-\" || d[u[i]] > w[i] + d[v[i]])\n\t\t\t{\n\t\t\t\tflag = true;\n\t\t\t\td[u[i]] = w[i] + d[v[i]];\n\t\t\t\tif (clk >= n - 1 && u[i] == s) return \"NO\";\n\t\t\t}\n\t\t}\n\t\tif (!flag || ++clk > 6 * n) break;\n\t}\n\treturn d[s] == \"-\"? \"NO\": d[s];\n}\n\nint main()\n{\n\twhile (cin >> n >> m >> s >> t)\n\t{\n\t\tif (!n && !m && !s && !t) break;\n\t\tinit();\n\t\tcout << solve() << endl;\n\t}\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4048, "score_of_the_acc": -0.0169, "final_rank": 3 }, { "submission_id": "aoj_1169_9820531", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n/**\n * @brief template\n */\n\nint main() {\n string CINF = \"~\";\nwhile(1) {\n int N, M, S, G;\n cin >> N >> M >> S >> G;\n if (N == 0) return 0;\n vector<int> X(M), Y(M);\n vector<string> L(M);\n rep(i,0,M) cin >> X[i] >> Y[i] >> L[i];\n vector<string> DP(N,CINF);\n DP[G] = \"\";\n auto BellmanFord = [&]() -> void {\n bool check = false;\n rep(i,0,M) {\n if (DP[Y[i]] == CINF) continue;\n chmin(DP[X[i]], L[i] + DP[Y[i]]);\n }\n };\n rep(i,0,N*6) BellmanFord();\n string ANS = DP[S];\n if (ANS == CINF) {\n cout << \"NO\" << endl;\n continue;\n }\n rep(i,0,N*6) BellmanFord();\n if (ANS != DP[S]) {\n cout << \"NO\" << endl;\n continue;\n }\n cout << ANS << endl;\n}\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 4092, "score_of_the_acc": -0.0703, "final_rank": 4 }, { "submission_id": "aoj_1169_9283493", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (int i = 0; i < (int) (n); i++)\n\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N,M,SS,GG;\n while(cin>>N>>M>>SS>>GG){\n if(N+M==0)return 0;\n vector<vector<pair<ll,string>>> G(N);\n rep(i,M){\n ll X,Y;\n string S;\n cin>>X>>Y>>S;\n G[X].push_back({Y,S});\n }\n vector<vector<string>> DP(N,vector<string>(500,\"{\"));\n DP[SS][0]=\"\";\n priority_queue<pair<string,ll>,vector<pair<string,ll>>,greater<pair<string,ll>>> Q;\n Q.push({\"\",SS});\n vector<vector<bool>> seen(N,vector<bool>(500,0));\n while(!Q.empty()){\n string S=Q.top().first;\n ll n=Q.top().second;\n Q.pop();\n ll sz=S.size();\n if(seen[n][sz])continue;\n seen[n][sz]=1;\n for(auto vw:G[n]){\n ll v=vw.first;\n string nw=S+vw.second;\n ll nsz=nw.size();\n if(seen[v][nsz])continue;\n if(nsz>499)continue;\n if(DP[v][nsz]>nw){\n DP[v][nsz]=nw;\n Q.push({nw,v});\n }\n }\n \n }\n string an=\"{\";\n rep(i,500){\n an=min(an,DP[GG][i]);\n }\n if(an==\"{\"||an.size()>250){\n cout<<\"NO\"<<endl;\n }\n else cout<<an<<endl;\n }\n\n\n\n}", "accuracy": 1, "time_ms": 680, "memory_kb": 20884, "score_of_the_acc": -0.4946, "final_rank": 15 }, { "submission_id": "aoj_1169_9072451", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\n} // namespace macro\n\nusing namespace macro;\n#line 3 \"A.cpp\"\n\nstring solve(int n, int m, int s, int g) {\n vector<vector<pair<int,string>>> graph(n);\n for(int i : rep(m)) {\n int x = in(), y = in(); string l = in();\n graph[x].push_back({y, l});\n }\n\n const string INF = \"~\";\n const int len = n * 6 * 2;\n vector dp(n, vector(len + 1, INF));\n dp[s][0] = \"\";\n for(int l : rep(len)) {\n for(int u : rep(n)) if(dp[u][l] != INF) {\n for(auto [v, s] : graph[u]) {\n int nl = l + s.size();\n if(nl <= len) chmin(dp[v][nl], dp[u][l] + s);\n }\n }\n }\n\n string ans = INF;\n for(int l : rep(len)) chmin(ans, dp[g][l]);\n return ans == INF or ans.size() > n * 6 ? \"NO\" : ans;\n}\n\nint main() {\n while(true) {\n int n = in(), m = in(), s = in(), g = in();\n if(make_tuple(n, m, s, g) == make_tuple(0, 0, 0, 0)) return 0;\n print(solve(n, m, s, g));\n }\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 8660, "score_of_the_acc": -0.153, "final_rank": 11 }, { "submission_id": "aoj_1169_9072450", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\n} // namespace macro\n\nusing namespace macro;\n#line 3 \"A.cpp\"\n\nstring solve(int n, int m, int s, int g) {\n vector<vector<pair<int,string>>> graph(n);\n for(int i : rep(m)) {\n int x = in(), y = in(); string l = in();\n graph[x].push_back({y, l});\n }\n\n const string INF = \"~\";\n const int len = n * 6 + 100;\n vector dp(n, vector(len + 1, INF));\n dp[s][0] = \"\";\n for(int l : rep(len)) {\n for(int u : rep(n)) if(dp[u][l] != INF) {\n for(auto [v, s] : graph[u]) {\n int nl = l + s.size();\n if(nl <= len) chmin(dp[v][nl], dp[u][l] + s);\n }\n }\n }\n\n string ans = INF;\n for(int l : rep(len)) chmin(ans, dp[g][l]);\n return ans == INF or ans.size() > n * 6 ? \"NO\" : ans;\n}\n\nint main() {\n while(true) {\n int n = in(), m = in(), s = in(), g = in();\n if(make_tuple(n, m, s, g) == make_tuple(0, 0, 0, 0)) return 0;\n print(solve(n, m, s, g));\n }\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 6380, "score_of_the_acc": -0.0904, "final_rank": 10 }, { "submission_id": "aoj_1169_8462732", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<string, int> Ps;\nstring min_cost[44][500];\npriority_queue<Ps, vector<Ps>, greater<Ps> > pq;\nint main(){\n int n, a, s, g, x, y;\n string lab, inf;\n inf += 'z'+1;\n while(cin >> n >> a >> s >> g, n){\n vector<Ps> e[44];\n for(int i=0;i<a;i++){\n cin >> x >> y >> lab;\n e[x].push_back(Ps(lab, y));\n }\n for(int i=0;i<n;i++){\n for(int j=0;j<500;j++) min_cost[i][j] = inf;\n }\n min_cost[s][0]=\"\";\n pq.push(Ps(\"\", s));\n while(!pq.empty()){\n Ps ps = pq.top();\n pq.pop();\n for(int i=0;i<e[ps.second].size();i++){\n string ncost = ps.first + e[ps.second][i].first;\n int nnode = e[ps.second][i].second;\n if(ncost.size()>=500) continue;\n if(min_cost[nnode][ncost.size()] > ncost){\n min_cost[nnode][ncost.size()] = ncost;\n pq.push(Ps(ncost, nnode));\n }\n }\n }\n string ans=inf;\n for(int i=0;i<500;i++){\n ans = min(ans, min_cost[g][i]);\n }\n if(ans==inf || ans.size()>240) ans = \"NO\";\n cout << ans << endl;\n }\n return(0);\n}", "accuracy": 1, "time_ms": 1830, "memory_kb": 24712, "score_of_the_acc": -0.7419, "final_rank": 18 }, { "submission_id": "aoj_1169_8414802", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\ntemplate<class T>\nbool chmax(T &a, const T &b) {if (a < b) {a = b; return 1;} return 0;}\n\ntemplate<class T>\nbool chmin(T &a, const T &b) {if (a > b) {a = b; return 1;} return 0;}\n\nusing ll = long long;\nusing ld = long double;\n\nbool is_end = false;\n\nstruct edge\n{\n\tint to;\n\tstring str;\n\t\n\tedge() = default;\n\tedge(int t, string s) : to(t), str(s) { }\n};\n\nvoid calc()\n{\n\tll N, M, s, g; cin >> N >> M >> s >> g;\n\t\n\tif (N == 0)\n\t{\n\t\tis_end = true;\n\t\treturn;\n\t}\n\t\n\tvector<vector<edge>> graph(N);\n\tvector<vector<edge>> inv(N);\n\tvector<tuple<int, int, string>> edge_lists(M);\n\tfor (int i = 0; i < M; ++i)\n\t{\n\t\tint a, b; cin >> a >> b;\n\t\tstring S; cin >> S;\n\t\tgraph[a].emplace_back(edge(b, S));\n\t\tinv[b].emplace_back(edge(a, S));\n\t\tedge_lists[i] = make_tuple(a, b, S);\n\t}\n\t\n\tvector<string> dist(N, \"|\");\n\tvector<bool> is_shorten(N, false);\n\tvector<int> par(N, -1);\n\t\n\tdist[g] = \"\";\n\tfor (int t = 0; t < N; ++t)\n\t{\n\t\tfor (auto [from, to, str] : edge_lists)\n\t\t{\n\t\t\tif (dist[to] != \"|\" && chmin(dist[from], str + dist[to]))\n\t\t\t{\n\t\t\t\t// par[from] = to;\n\t\t\t}\n\t\t}\n\t}\n\tfor (int t = 0; t < N*N; ++t)\n\t{\n\t\tfor (auto [from, to, str] : edge_lists)\n\t\t{\n\t\t\tif (dist[to] != \"|\" && chmin(dist[from], str + dist[to]))\n\t\t\t{\n\t\t\t\tis_shorten[from] = true;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t// cout << N << \" \" << M << \" \" << s << \" \" << g << endl;\n\t// for (int i = 0; i < min(5LL, N); ++i)\n\t// {\n\t// \tcout << i << \" \" << dist[i] << endl;\n\t// }\n\t\n\tif (dist[s] == \"|\" || is_shorten[s])\n\t{\n\t\tcout << \"NO\" << endl;\n\t\treturn;\n\t}\n\telse\n\t{\n\t\tcout << dist[s] << endl;\n\t}\n\t\n\treturn;\n}\n\nint main()\n{\n\twhile (!is_end)\n\t{\n\t\tcalc();\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 4170, "memory_kb": 6104, "score_of_the_acc": -0.6322, "final_rank": 16 }, { "submission_id": "aoj_1169_7962093", "code_snippet": "#include <string.h>\n\n#include <algorithm>\n#include <array>\n#include <bitset>\n#include <cassert>\n#include <cfloat>\n#include <chrono>\n#include <ciso646>\n#include <climits>\n#include <cmath>\n#include <complex>\n#include <cstdio>\n#include <functional>\n#include <iomanip>\n#include <iostream>\n#include <map>\n#include <numeric>\n#include <optional>\n#include <queue>\n#include <random>\n#include <set>\n#include <stack>\n#include <string>\n#include <unordered_map>\n#include <unordered_set>\n#include <utility>\n#include <vector>\n\n#define REP_OVERLOAD(arg1, arg2, arg3, arg4, NAME, ...) NAME\n#define REP3(i, l, r, s) \\\n for (int i = int(l), rep3_r = int(r), rep3_s = int(s); i < rep3_r; \\\n i += rep3_s)\n#define REP2(i, l, r) REP3(i, l, r, 1)\n#define REP1(i, n) REP2(i, 0, n)\n#define rep(...) REP_OVERLOAD(__VA_ARGS__, REP3, REP2, REP1, )(__VA_ARGS__)\n#define repin(i, l, r) for (int i = int(l), repin_r = int(r); i <= repin_r; ++i)\n\n#define RREP_OVERLOAD(arg1, arg2, arg3, arg4, NAME, ...) NAME\n#define RREP3(i, l, r, s) \\\n for (int i = int(r) - 1, rrep3_l = int(l), rrep3_s = int(s); i >= rrep3_l; \\\n i -= rrep3_s)\n#define RREP2(i, l, r) RREP3(i, l, r, 1)\n#define RREP1(i, n) RREP2(i, 0, n)\n#define rrep(...) RREP_OVERLOAD(__VA_ARGS__, RREP3, RREP2, RREP1, )(__VA_ARGS__)\n#define rrepin(i, l, r) \\\n for (int i = int(r), rrepin_l = int(l); i >= rrepin_l; --i)\n\n\n#include <algorithm>\n#include <cassert>\n#include <vector>\n\nnamespace rklib {\n\n// a <- max(a, b)\ntemplate <class T>\nbool chmax(T &a, const T &b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\n// a <- min(a, b)\ntemplate <class T>\nbool chmin(T &a, const T &b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\n\n// if a < 0: a <- b\n// else: a <- min(a, b)\ntemplate <class T>\nbool chmin_non_negative(T &a, const T &b) {\n if (a < 0 || a > b) {\n a = b;\n return true;\n }\n return false;\n}\n\n// floor(num / den)\ntemplate <class T>\nT div_floor(T num, T den) {\n if (den < 0) num = -num, den = -den;\n return num >= 0 ? num / den : (num + 1) / den - 1;\n}\n\n// ceil(num / den)\ntemplate <class T>\nT div_ceil(T num, T den) {\n if (den < 0) num = -num, den = -den;\n return num <= 0 ? num / den : (num - 1) / den + 1;\n}\n\nnamespace internal {\n\ntemplate <class T>\nT remainder_count(T r, T b, T m) {\n return r / m * b + std::min(b, r % m);\n}\n\n} // namespace internal\n\n// Number of integer x s.t.\n// - x in [l, r)\n// - x mod m in [a, b)\ntemplate <class T>\nT remainder_count(T l, T r, T a, T b, T m) {\n assert(l >= 0);\n assert(m >= 1);\n\n if (l >= r || a >= b) return 0;\n if (m <= a || b < 0) return 0;\n chmax(a, T(0));\n chmin(b, m);\n\n auto res = internal::remainder_count(r, b, m);\n if (l >= 1) res -= internal::remainder_count(l, b, m);\n if (a >= 1) res -= internal::remainder_count(r, a, m);\n if (l >= 1 && a >= 1) res += internal::remainder_count(l, a, m);\n\n return res;\n}\n\n} // namespace rklib\n\n\nusing namespace std;\nusing namespace rklib;\n\nusing lint = long long;\nusing pii = pair<int, int>;\nusing pll = pair<lint, lint>;\n\nint main() {\n while (true) {\n int n, m, s, g;\n cin >> n >> m >> s >> g;\n if (n == 0) break;\n\n vector<pair<int, string>> gr[n];\n rep(i, m) {\n int a, b;\n string s;\n cin >> a >> b >> s;\n gr[b].emplace_back(a, s);\n }\n\n vector<string> dist(n, \"~\");\n dist[g] = \"\";\n rep(_, n) {\n rep(v, n) {\n if (dist[v] == \"~\") continue;\n for (auto [nv, s] : gr[v]) {\n chmin(dist[nv], s + dist[v]);\n }\n }\n }\n\n // rep(i, n) cout << dist[i] << endl;\n\n // negative cycle\n vector<bool> ng(n, false);\n rep(iter, 250) {\n rep(v, n) {\n if (dist[v] == \"~\") continue;\n for (auto [nv, s] : gr[v]) {\n if (chmin(dist[nv], s + dist[v]) && iter == 249) {\n ng[nv] = true;\n }\n }\n }\n }\n\n cout << (dist[s].size() >= 250 || ng[s] || dist[s] == \"~\" ? \"NO\"\n : dist[s])\n << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 4192, "score_of_the_acc": -0.074, "final_rank": 6 }, { "submission_id": "aoj_1169_7865862", "code_snippet": "#include<bits/stdc++.h>\n#include <ostream>\nusing namespace std;\nusing ll = long long;\n\nint N,A,S,G;\nusing TUP = tuple<int,string>;\nvector<vector<TUP>> Graph;\nconst int MAX_LEN = 6*40*3;\nstring dp[40][MAX_LEN];\n\nvoid dp_init(){\n\tfor(int i = 0;i<40;i++){\n\t\tfor(int j = 0;j<MAX_LEN;j++){\n\t\t\tdp[i][j] = string(1,'z'+1);;\n\t\t}\n\t}\n}\nusing dpTUP = tuple<string,int,int>;\n\nvoid solve(){\n\tdp_init();\n\tpriority_queue<dpTUP,vector<dpTUP>,greater<dpTUP>> PQ;\n\tdp[S][0] = string();\n\tPQ.push(dpTUP(\"\",S,0));\n\twhile (PQ.size()) {\n\t\tauto [s,cur,len] = PQ.top();\n\t\tPQ.pop();\n\t\t//cout<<PQ.size()<<endl;\n\t\tif(s!=dp[cur][len])\n\t\t\tcontinue;\n\t\tfor(auto [to,tos]:Graph[cur]){\n\t\t\tstring nxs = s + tos;\n\t\t\tint nxlen = nxs.size();\n\t\t\tif(nxlen>=MAX_LEN)continue;\n\t\t\tif(dp[to][nxlen]>nxs){\n\t\t\t\tdp[to][nxlen] = nxs;\n\t\t\t\tPQ.push(dpTUP(nxs,to,nxlen));\n\t\t\t}\n\t\t}\n\t}\n\tstring ans = string(1,'z'+1);\n\tfor(int i = 0;i<=240;i++){\n\t\tif(ans > dp[G][i]) ans = dp[G][i];\n\t}\n\tfor(int i = 240;i<MAX_LEN;i++){\n\t\tif(ans>dp[G][i]){\n\t\t\tcout<<\"NO\"<<endl;\n\t\t\treturn;\n\t\t}\n\t}\n\tif(ans==string(1,'z'+1))ans = \"NO\";\n\tcout<<ans<<endl;\n}\n\nsigned main(){\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\twhile (1) {\n\t\tcin >> N >> A >> S >> G;\n\t\tif(N==0)break;\n\t\tGraph = vector<vector<TUP>>(N);\n\t\tfor(int i = 0;i<A;i++){\n\t\t\tint from,to;\n\t\t\tstring s;\n\t\t\tcin >> from >> to >> s;\n\t\t\tGraph[from].push_back(TUP(to,s));\n\t\t}\n\t\tsolve();\n\t}\n}", "accuracy": 1, "time_ms": 1220, "memory_kb": 46564, "score_of_the_acc": -1.1653, "final_rank": 20 }, { "submission_id": "aoj_1169_7240100", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\nstruct edge {\n int x, y;\n string lab;\n};\n\nvoid sol() {\n int n, a, s, g;\n cin >> n >> a >> s >> g;\n if (n == 0 and a == 0 and s == 0 and g == 0) {\n exit(0);\n }\n\n vector<edge> edges;\n for (int i = 0; i < a; i++) {\n int x, y;\n string lab;\n cin >> x >> y >> lab;\n edges.push_back({x, y, lab});\n }\n\n vector<int> arrived(n);\n vector<string> best(n);\n int last_update = -1;\n arrived[g] = 1;\n for (int i = 0; i < 6 * n + 10; i++) {\n auto cur = best[s];\n for (auto &&[x, y, lab] : edges) {\n if (arrived[y]) {\n if (!arrived[x]) {\n arrived[x] = 1;\n best[x] = lab + best[y];\n } else {\n best[x] = min(best[x], lab + best[y]);\n }\n }\n }\n if (cur != best[s]) {\n last_update = i;\n if (i >= n) {\n cout << \"NO\" << endl;\n return;\n }\n }\n }\n\n if (last_update >= 0) {\n cout << best[s] << endl;\n } else {\n cout << \"NO\" << endl;\n }\n\n return;\n};\n\nint main() {\n while (1) sol();\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3676, "score_of_the_acc": -0.0138, "final_rank": 2 }, { "submission_id": "aoj_1169_7167243", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,s,t) for (int i = (s); i < (t); ++i)\n#define all(x) (x).begin(), (x).end()\n\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v) {\n for (int i = 0; i < (int) v.size(); ++i) {\n os << v[i];\n if (i < (int) v.size() - 1) os << \" \";\n }\n return os;\n}\n\n\nvoid solve(int n, int a, int s, int g) {\n vector<vector<pair<int, string>>> G(n);\n vector<vector<pair<int, string>>> Grev(n);\n rep(i,0,a) {\n int x, y;\n string lab;\n cin >> x >> y >> lab;\n G[x].push_back({y, lab});\n Grev[y].push_back({x, lab});\n }\n\n // find vertices that are reachable from the goal\n vector<bool> reachable(n);\n reachable[g] = true;\n stack<int> st;\n st.push(g);\n while (!st.empty()) {\n int v = st.top();\n st.pop();\n for (auto [u, _] : Grev[v]) {\n if (!reachable[u]) {\n reachable[u] = true;\n st.push(u);\n }\n }\n }\n\n if (!reachable[s]) {\n cout << \"NO\" << endl;\n return;\n }\n\n\n // find a candidate with bellman ford\n string last = \"~\";\n vector<string> dist(n, last);\n vector<bool> upd(n);\n dist[g] = \"\";\n rep(t,0,3*a) {\n rep(i,0,n) {\n if (dist[i] == last) continue;\n for (auto [j, lab] : Grev[i]) {\n auto nd = lab + dist[i];\n if (nd < dist[j]) {\n dist[j] = nd;\n if (t >= a) {\n upd[j] = true;\n }\n }\n }\n }\n }\n\n if (upd[s]) {\n cout << \"NO\" << endl;\n return;\n }\n\n // check if the candidate is actually the solution\n int v = s;\n string t = \"\";\n while (v != g && t.size() < dist[s].size()) {\n tuple<string, string, int> cand = {last, last, -1};\n for (auto [u, lab] : G[v]) {\n if (reachable[u] && !upd[u]) {\n cand = min(cand, {lab + dist[u], lab, u});\n }\n }\n auto [_, lab, u] = cand;\n if (lab == last) {\n cout << \"NO\" << endl;\n return;\n }\n t += lab;\n v = u;\n }\n\n if (t == dist[s]) {\n cout << t << endl;\n } else {\n cout << \"NO\" << endl;\n }\n}\n\nint main() {\n while (true) {\n int n, a, s, g;\n cin >> n >> a >> s >> g;\n if (n == 0) break;\n solve(n, a, s, g);\n }\n}", "accuracy": 1, "time_ms": 4510, "memory_kb": 7300, "score_of_the_acc": -0.7068, "final_rank": 17 }, { "submission_id": "aoj_1169_6422621", "code_snippet": "#include <bits/stdc++.h>\n#pragma GCC optimize(\"Ofast\")\n#define _GLIBCXX_DEBUG\nusing namespace std;\nusing std::cout;\nusing std::cin;\nusing std::endl;\nusing ll=long long;\nusing ld=long double;\nll ILL=1167167167167167167;\nconst int INF=2100000000;\nconst ll mod=998244353;\n#define rep(i,a) for (ll i=0;i<a;i++)\n#define all(p) p.begin(),p.end()\ntemplate<class T> using _pq = priority_queue<T, vector<T>, greater<T>>;\ntemplate<class T> ll LB(vector<T> &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();}\ntemplate<class T> ll UB(vector<T> &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();}\ntemplate<class T> bool chmin(T &a,const T &b){if(a>b){a=b;return 1;}else return 0;}\ntemplate<class T> bool chmax(T &a,const T &b){if(a<b){a=b;return 1;}else return 0;}\ntemplate<class T> void So(vector<T> &v) {sort(v.begin(),v.end());}\ntemplate<class T> void Sore(vector<T> &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});}\nvoid yneos(bool a){if(a) cout<<\"Yes\\n\"; else cout<<\"No\\n\";}\ntemplate<class T> void vec_out(vector<T> &p){for(int i=0;i<(int)(p.size());i++){if(i) cout<<\" \";cout<<p[i];}cout<<\"\\n\";}\n\nvoid solve(int N,int A,int S,int G){\n\tstring I=\"{}\";\n\tint L=500;\n\tvector<vector<string>> dp(N,vector<string>(L,I));\n\t//cout<<N<<\" \"<<A<<\" \"<<S<<\" \"<<G<<endl;\n\tdp[G][0]=\"\";\n\tvector<vector<pair<int,string>>> E(N);\n\trep(i,A){\n\t\tint x,y;\n\t\tstring T;\n\t\tcin>>x>>y>>T;\n\t\tE[y].push_back({x,T});\n\t}\n\trep(j,L) rep(i,N){\n\t\tif(dp[i][j]==I) continue;\n\t\t//cout<<i<<\" \"<<j<<\" \"<<dp[i][j]<<endl;\n\t\tfor(auto x:E[i]){\n\t\t\tint ind=x.first;\n\t\t\tstring T=x.second+dp[i][j];\n\t\t\t//cout<<T<<endl;\n\t\t\tif((int)T.size()>=L) continue;\n\t\t\tchmin(dp[ind][(int)(T.size())],T);\n\t\t}\n\t}\n\tstring ans=I;\n\trep(i,L){\n\t\tchmin(ans,dp[S][i]);\n\t}\n\tif(ans==I||(int)ans.size()>250){\n\t\tcout<<\"NO\\n\";\n\t}else cout<<ans<<\"\\n\";\n}\n\nint main(){\n\tint N,A,S,G;\n\twhile(cin>>N>>A>>S>>G,N) solve(N,A,S,G);\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 9004, "score_of_the_acc": -0.1651, "final_rank": 12 }, { "submission_id": "aoj_1169_6282116", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\n\ntypedef string::const_iterator State;\n#define eps 1e-8L\n#define MAX_MOD 1000000007LL\n#define GYAKU 500000004LL\n#define MOD 998244353LL\n#define pb push_back\n#define mp make_pair\ntypedef long long ll;\ntypedef long double ld;\n#define REP(a, b) for (long long(a) = 0; (a) < (b); ++(a))\n#define ALL(x) (x).begin(), (x).end()\n\n#define int long long\n\nvoid solve()\n{\n int n, a, s, g;\n cin >> n >> a >> s >> g;\n if (n == 0)\n exit(0);\n vector<vector<pair<int, string>>> vertexs(n);\n REP(i, a)\n {\n int a, b;\n string c;\n cin >> a >> b >> c;\n vertexs[a].push_back({b, c});\n }\n\n vector<vector<string>> dp(n, vector<string>(500, \"\"));\n REP(i, 500)\n {\n REP(q, n)\n {\n if (!(i == 0 and q == s) and dp[q][i] == \"\")\n continue;\n for (auto x : vertexs[q])\n {\n string next = dp[q][i] + x.second;\n if (next.length() < 500)\n {\n if (dp[x.first][next.length()] == \"\" or dp[x.first][next.length()] > next)\n {\n dp[x.first][next.length()] = next;\n }\n }\n }\n }\n }\n\n string ans = \"\";\n for (auto x : dp[g])\n {\n if (x != \"\")\n {\n if (ans == \"\")\n ans = x;\n ans = min(ans, x);\n }\n }\n if (ans.length() > 240 or ans.length() == 0)\n {\n cout << \"NO\" << endl;\n }\n else\n {\n cout << ans << endl;\n }\n}\n#undef int\n\n// generated by oj-template v4.7.2\n// (https://github.com/online-judge-tools/template-generator)\nint main()\n{\n // Fasterize input/output script\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(100);\n // scanf/printf user should delete this fasterize input/output script\n\n int t = 10000;\n // cin >> t; // comment out if solving multi testcase\n for (int testCase = 1; testCase <= t; ++testCase)\n {\n solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 9096, "score_of_the_acc": -0.1782, "final_rank": 13 }, { "submission_id": "aoj_1169_6106781", "code_snippet": "#include <bits/stdc++.h>\n#pragma region Header\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nusing f64 = double;\nusing f80 = long double;\nusing f128 = __float128;\nconstexpr i32 operator\"\" _i32(u64 v)\n{\n return v;\n}\nconstexpr i32 operator\"\" _u32(u64 v)\n{\n return v;\n}\nconstexpr i64 operator\"\" _i64(u64 v)\n{\n return v;\n}\nconstexpr u64 operator\"\" _u64(u64 v)\n{\n return v;\n}\nconstexpr f64 operator\"\" _f64(f80 v)\n{\n return v;\n}\nconstexpr f80 operator\"\" _f80(f80 v)\n{\n return v;\n}\nusing Istream = std::istream;\nusing Ostream = std::ostream;\nusing Str = std::string;\ntemplate<typename T>\nusing Lt = std::less<T>;\ntemplate<typename T>\nusing Gt = std::greater<T>;\ntemplate<typename T>\nusing IList = std::initializer_list<T>;\ntemplate<int n>\nusing BSet = std::bitset<n>;\ntemplate<typename T1, typename T2>\nusing Pair = std::pair<T1, T2>;\ntemplate<typename... Ts>\nusing Tup = std::tuple<Ts...>;\ntemplate<typename T, int N>\nusing Arr = std::array<T, N>;\ntemplate<typename... Ts>\nusing Deq = std::deque<Ts...>;\ntemplate<typename... Ts>\nusing Set = std::set<Ts...>;\ntemplate<typename... Ts>\nusing MSet = std::multiset<Ts...>;\ntemplate<typename... Ts>\nusing USet = std::unordered_set<Ts...>;\ntemplate<typename... Ts>\nusing UMSet = std::unordered_multiset<Ts...>;\ntemplate<typename... Ts>\nusing Map = std::map<Ts...>;\ntemplate<typename... Ts>\nusing MMap = std::multimap<Ts...>;\ntemplate<typename... Ts>\nusing UMap = std::unordered_map<Ts...>;\ntemplate<typename... Ts>\nusing UMMap = std::unordered_multimap<Ts...>;\ntemplate<typename... Ts>\nusing Vec = std::vector<Ts...>;\ntemplate<typename... Ts>\nusing Stack = std::stack<Ts...>;\ntemplate<typename... Ts>\nusing Queue = std::queue<Ts...>;\ntemplate<typename T>\nusing MaxHeap = std::priority_queue<T>;\ntemplate<typename T>\nusing MinHeap = std::priority_queue<T, Vec<T>, Gt<T>>;\nusing NSec = std::chrono::nanoseconds;\nusing USec = std::chrono::microseconds;\nusing MSec = std::chrono::milliseconds;\nusing Sec = std::chrono::seconds;\ntemplate<typename T>\nconstexpr T LIMMIN = std::numeric_limits<T>::min();\ntemplate<typename T>\nconstexpr T LIMMAX = std::numeric_limits<T>::max();\ntemplate<typename T>\nconstexpr T INF = (LIMMAX<T> - 1) / 2;\ntemplate<typename T>\nconstexpr T PI = T{3.141592653589793238462643383279502884};\ntemplate<typename T = u64>\nconstexpr T TEN(const int n)\n{\n return n == 0 ? T{1} : TEN<T>(n - 1) * T{10};\n}\nOstream& operator<<(Ostream& os, i128 v)\n{\n bool minus = false;\n if (v < 0) { minus = true, v = -v; }\n Str ans;\n if (v == 0) { ans = \"0\"; }\n while (v) {\n ans.push_back('0' + v % 10), v /= 10;\n }\n std::reverse(ans.begin(), ans.end());\n return os << (minus ? \"-\" : \"\") << ans;\n}\nOstream& operator<<(Ostream& os, u128 v)\n{\n Str ans;\n if (v == 0) { ans = \"0\"; }\n while (v) {\n ans.push_back('0' + v % 10), v /= 10;\n }\n std::reverse(ans.begin(), ans.end());\n return os << ans;\n}\ntemplate<typename T>\nbool chmin(T& a, const T& b)\n{\n if (a > b) {\n a = b;\n return true;\n } else {\n return false;\n }\n}\ntemplate<typename T>\nbool chmax(T& a, const T& b)\n{\n if (a < b) {\n a = b;\n return true;\n } else {\n return false;\n }\n}\ntemplate<typename T>\nconstexpr T floorDiv(T x, T y)\n{\n if (y < T{}) { x = -x, y = -y; }\n return x >= T{} ? x / y : (x - y + 1) / y;\n}\ntemplate<typename T>\nconstexpr T ceilDiv(T x, T y)\n{\n if (y < T{}) { x = -x, y = -y; }\n return x >= T{} ? (x + y - 1) / y : x / y;\n}\ntemplate<typename T, typename I>\nconstexpr T modPower(T v, I n, T mod)\n{\n T ans = 1 % mod;\n for (; n > 0; n >>= 1, (v *= v) %= mod) {\n if (n % 2 == 1) { (ans *= v) %= mod; }\n }\n return ans;\n}\ntemplate<typename T, typename I>\nconstexpr T power(T v, I n)\n{\n T ans = 1;\n for (; n > 0; n >>= 1, v *= v) {\n if (n % 2 == 1) { ans *= v; }\n }\n return ans;\n}\ntemplate<typename T, typename I>\nconstexpr T power(T v, I n, const T& e)\n{\n T ans = e;\n for (; n > 0; n >>= 1, v *= v) {\n if (n % 2 == 1) { ans *= v; }\n }\n return ans;\n}\ntemplate<typename T>\nVec<T> operator+=(Vec<T>& vs1, const Vec<T>& vs2)\n{\n vs1.insert(vs1.end(), vs2.begin(), vs2.end());\n return vs1;\n}\ntemplate<typename T>\nVec<T> operator+(const Vec<T>& vs1, const Vec<T>& vs2)\n{\n auto vs = vs1;\n vs += vs2;\n return vs;\n}\ntemplate<typename Vs, typename V>\nvoid fillAll(Vs& arr, const V& v)\n{\n if constexpr (std::is_convertible<V, Vs>::value) {\n arr = v;\n } else {\n for (auto& subarr : arr) {\n fillAll(subarr, v);\n }\n }\n}\ntemplate<typename Vs>\nvoid sortAll(Vs& vs)\n{\n std::sort(std::begin(vs), std::end(vs));\n}\ntemplate<typename Vs, typename C>\nvoid sortAll(Vs& vs, C comp)\n{\n std::sort(std::begin(vs), std::end(vs), comp);\n}\ntemplate<typename Vs>\nvoid reverseAll(Vs& vs)\n{\n std::reverse(std::begin(vs), std::end(vs));\n}\ntemplate<typename V, typename Vs>\nV sumAll(const Vs& vs)\n{\n if constexpr (std::is_convertible<Vs, V>::value) {\n return static_cast<V>(vs);\n } else {\n V ans = 0;\n for (const auto& v : vs) {\n ans += sumAll<V>(v);\n }\n return ans;\n }\n}\ntemplate<typename Vs>\nint minInd(const Vs& vs)\n{\n return std::min_element(std::begin(vs), std::end(vs)) - std::begin(vs);\n}\ntemplate<typename Vs>\nint maxInd(const Vs& vs)\n{\n return std::max_element(std::begin(vs), std::end(vs)) - std::begin(vs);\n}\ntemplate<typename Vs, typename V>\nint lbInd(const Vs& vs, const V& v)\n{\n return std::lower_bound(std::begin(vs), std::end(vs), v) - std::begin(vs);\n}\ntemplate<typename Vs, typename V>\nint ubInd(const Vs& vs, const V& v)\n{\n return std::upper_bound(std::begin(vs), std::end(vs), v) - std::begin(vs);\n}\ntemplate<typename T, typename F>\nVec<T> genVec(int n, F gen)\n{\n Vec<T> ans;\n std::generate_n(std::back_insert_iterator(ans), n, gen);\n return ans;\n}\nVec<int> iotaVec(int n, int offset = 0)\n{\n Vec<int> ans(n);\n std::iota(ans.begin(), ans.end(), offset);\n return ans;\n}\nconstexpr int popcount(const u64 v)\n{\n return v ? __builtin_popcountll(v) : 0;\n}\nconstexpr int log2p1(const u64 v)\n{\n return v ? 64 - __builtin_clzll(v) : 0;\n}\nconstexpr int lsbp1(const u64 v)\n{\n return __builtin_ffsll(v);\n}\nconstexpr int clog(const u64 v)\n{\n return v ? log2p1(v - 1) : 0;\n}\nconstexpr u64 ceil2(const u64 v)\n{\n const int l = clog(v);\n return (l == 64) ? 0_u64 : (1_u64 << l);\n}\nconstexpr u64 floor2(const u64 v)\n{\n return v ? (1_u64 << (log2p1(v) - 1)) : 0_u64;\n}\nconstexpr bool ispow2(const u64 v)\n{\n return (v > 0) and ((v & (v - 1)) == 0);\n}\nconstexpr bool btest(const u64 mask, const int ind)\n{\n return (mask >> ind) & 1_u64;\n}\ntemplate<typename F>\nstruct Fix : F\n{\n Fix(F&& f) : F{std::forward<F>(f)} {}\n template<typename... Args>\n auto operator()(Args&&... args) const\n {\n return F::operator()(*this, std::forward<Args>(args)...);\n }\n};\nclass irange\n{\nprivate:\n struct itr\n {\n itr(i64 start = 0, i64 step = 1) : m_cnt{start}, m_step{step} {}\n bool operator!=(const itr& it) const\n {\n return m_cnt != it.m_cnt;\n }\n int operator*()\n {\n return m_cnt;\n }\n itr& operator++()\n {\n m_cnt += m_step;\n return *this;\n }\n i64 m_cnt, m_step;\n };\n i64 m_start, m_end, m_step;\npublic:\n irange(i64 start, i64 end, i64 step = 1)\n {\n assert(step != 0);\n const i64 d = std::abs(step);\n const i64 l = (step > 0 ? start : end);\n const i64 r = (step > 0 ? end : start);\n int n = (r - l) / d + ((r - l) % d ? 1 : 0);\n if (l >= r) { n = 0; }\n m_start = start;\n m_end = start + step * n;\n m_step = step;\n }\n itr begin() const\n {\n return itr{m_start, m_step};\n }\n itr end() const\n {\n return itr{m_end, m_step};\n }\n};\nirange rep(int end)\n{\n return irange(0, end, 1);\n}\nirange per(int rend)\n{\n return irange(rend - 1, -1, -1);\n}\n#pragma COMMENT(\"[REFS] Xoshiro: https://prng.di.unimi.it\")\nnamespace xoshiro_impl {\nu64 x;\nu64 next()\n{\n uint64_t z = (x += 0x9e3779b97f4a7c15);\n z = (z ^ (z >> 30)) * 0xbf58476d1ce4e5b9;\n z = (z ^ (z >> 27)) * 0x94d049bb133111eb;\n return z ^ (z >> 31);\n}\n}\nclass Xoshiro32\n{\npublic:\n using result_type = u32;\n using T = result_type;\n Xoshiro32(T seed = 0)\n {\n xoshiro_impl::x = seed;\n s[0] = xoshiro_impl::next();\n s[1] = xoshiro_impl::next();\n s[2] = xoshiro_impl::next();\n s[3] = xoshiro_impl::next();\n }\n static constexpr T min()\n {\n return LIMMIN<T>;\n }\n static constexpr T max()\n {\n return LIMMAX<T>;\n }\n T operator()()\n {\n return next();\n }\nprivate:\n static constexpr T rotl(const T x, int k)\n {\n return (x << k) | (x >> (32 - k));\n }\n T next()\n {\n const T ans = rotl(s[1] * 5, 7) * 9;\n const T t = s[1] << 9;\n s[2] ^= s[0];\n s[3] ^= s[1];\n s[1] ^= s[2];\n s[0] ^= s[3];\n s[2] ^= t;\n s[3] = rotl(s[3], 11);\n return ans;\n }\n T s[4];\n};\nclass Xoshiro64\n{\npublic:\n using result_type = u64;\n using T = result_type;\n Xoshiro64(T seed = 0)\n {\n xoshiro_impl::x = seed;\n s[0] = xoshiro_impl::next();\n s[1] = xoshiro_impl::next();\n s[2] = xoshiro_impl::next();\n s[3] = xoshiro_impl::next();\n }\n static constexpr T min()\n {\n return LIMMIN<T>;\n }\n static constexpr T max()\n {\n return LIMMAX<T>;\n }\n T operator()()\n {\n return next();\n }\nprivate:\n static constexpr T rotl(const T x, int k)\n {\n return (x << k) | (x >> (64 - k));\n }\n T next()\n {\n const T ans = rotl(s[1] * 5, 7) * 9;\n const T t = s[1] << 17;\n s[2] ^= s[0];\n s[3] ^= s[1];\n s[1] ^= s[2];\n s[0] ^= s[3];\n s[2] ^= t;\n s[3] = rotl(s[3], 45);\n return ans;\n }\n T s[4];\n};\ntemplate<typename Rng>\nclass RNG\n{\npublic:\n using result_type = typename Rng::result_type;\n using T = result_type;\n static constexpr T min()\n {\n return Rng::min();\n }\n static constexpr T max()\n {\n return Rng::max();\n }\n RNG() : RNG(std::random_device{}()) {}\n RNG(T seed) : m_rng(seed) {}\n T operator()()\n {\n return m_rng();\n }\n template<typename T>\n T val(T min, T max)\n {\n return std::uniform_int_distribution<T>(min, max)(m_rng);\n }\n template<typename T>\n Pair<T, T> pair(T min, T max)\n {\n return std::minmax({val<T>(min, max), val<T>(min, max)});\n }\n template<typename T>\n Vec<T> vec(int n, T min, T max)\n {\n return genVec<T>(n, [&]() { return val<T>(min, max); });\n }\n template<typename T>\n Vec<Vec<T>> vvec(int n, int m, T min, T max)\n {\n return genVec<Vec<T>>(n, [&]() { return vec(m, min, max); });\n }\nprivate:\n Rng m_rng;\n};\nRNG<std::mt19937> rng;\nRNG<std::mt19937_64> rng64;\nRNG<Xoshiro32> rng_xo;\nRNG<Xoshiro64> rng_xo64;\nclass Scanner\n{\npublic:\n Scanner(Istream& is = std::cin) : m_is{is}\n {\n m_is.tie(nullptr)->sync_with_stdio(false);\n }\n template<typename T>\n T val()\n {\n T v;\n return m_is >> v, v;\n }\n template<typename T>\n T val(T offset)\n {\n return val<T>() - offset;\n }\n template<typename T>\n Vec<T> vec(int n)\n {\n return genVec<T>(n, [&]() { return val<T>(); });\n }\n template<typename T>\n Vec<T> vec(int n, T offset)\n {\n return genVec<T>(n, [&]() { return val<T>(offset); });\n }\n template<typename T>\n Vec<Vec<T>> vvec(int n, int m)\n {\n return genVec<Vec<T>>(n, [&]() { return vec<T>(m); });\n }\n template<typename T>\n Vec<Vec<T>> vvec(int n, int m, const T offset)\n {\n return genVec<Vec<T>>(n, [&]() { return vec<T>(m, offset); });\n }\n template<typename... Args>\n auto tup()\n {\n return Tup<Args...>{val<Args>()...};\n }\n template<typename... Args>\n auto tup(const Args&... offsets)\n {\n return Tup<Args...>{val<Args>(offsets)...};\n }\nprivate:\n Istream& m_is;\n};\nScanner in;\nclass Printer\n{\npublic:\n Printer(Ostream& os = std::cout) : m_os{os}\n {\n m_os << std::fixed << std::setprecision(15);\n }\n template<typename... Args>\n int operator()(const Args&... args)\n {\n dump(args...);\n return 0;\n }\n template<typename... Args>\n int ln(const Args&... args)\n {\n dump(args...), m_os << '\\n';\n return 0;\n }\n template<typename... Args>\n int el(const Args&... args)\n {\n dump(args...), m_os << std::endl;\n return 0;\n }\nprivate:\n template<typename T>\n void dump(const T& v)\n {\n m_os << v;\n }\n template<typename T>\n void dump(const Vec<T>& vs)\n {\n for (const int i : rep(vs.size())) {\n m_os << (i ? \" \" : \"\"), dump(vs[i]);\n }\n }\n template<typename T>\n void dump(const Vec<Vec<T>>& vss)\n {\n for (const int i : rep(vss.size())) {\n m_os << (i ? \"\\n\" : \"\"), dump(vss[i]);\n }\n }\n template<typename T, typename... Ts>\n int dump(const T& v, const Ts&... args)\n {\n dump(v), m_os << ' ', dump(args...);\n return 0;\n }\n Ostream& m_os;\n};\nPrinter out;\ntemplate<typename T, int n, int i = 0>\nauto ndVec(int const (&szs)[n], const T x = T{})\n{\n if constexpr (i == n) {\n return x;\n } else {\n return std::vector(szs[i], ndVec<T, n, i + 1>(szs, x));\n }\n}\ntemplate<typename T, typename F>\nT binSearch(T ng, T ok, F check)\n{\n while (std::abs(ok - ng) > 1) {\n const T mid = (ok + ng) / 2;\n (check(mid) ? ok : ng) = mid;\n }\n return ok;\n}\ntemplate<u32 mod_, u32 root_, u32 max2p_>\nclass modint\n{\n template<typename U = u32&>\n static U modRef()\n {\n static u32 s_mod = 0;\n return s_mod;\n }\n template<typename U = u32&>\n static U rootRef()\n {\n static u32 s_root = 0;\n return s_root;\n }\n template<typename U = u32&>\n static U max2pRef()\n {\n static u32 s_max2p = 0;\n return s_max2p;\n }\npublic:\n template<typename U = const u32>\n static constexpr std::enable_if_t<mod_ != 0, U> mod()\n {\n return mod_;\n }\n template<typename U = const u32>\n static std::enable_if_t<mod_ == 0, U> mod()\n {\n return modRef();\n }\n template<typename U = const u32>\n static constexpr std::enable_if_t<mod_ != 0, U> root()\n {\n return root_;\n }\n template<typename U = const u32>\n static std::enable_if_t<mod_ == 0, U> root()\n {\n return rootRef();\n }\n template<typename U = const u32>\n static constexpr std::enable_if_t<mod_ != 0, U> max2p()\n {\n return max2p_;\n }\n template<typename U = const u32>\n static std::enable_if_t<mod_ == 0, U> max2p()\n {\n return max2pRef();\n }\n template<typename U = u32>\n static void setMod(std::enable_if_t<mod_ == 0, U> m)\n {\n modRef() = m;\n }\n template<typename U = u32>\n static void setRoot(std::enable_if_t<mod_ == 0, U> r)\n {\n rootRef() = r;\n }\n template<typename U = u32>\n static void setMax2p(std::enable_if_t<mod_ == 0, U> m)\n {\n max2pRef() = m;\n }\n constexpr modint() : m_val{0} {}\n constexpr modint(i64 v) : m_val{normll(v)} {}\n constexpr void setRaw(u32 v)\n {\n m_val = v;\n }\n constexpr modint operator-() const\n {\n return modint{0} - (*this);\n }\n constexpr modint& operator+=(const modint& m)\n {\n m_val = norm(m_val + m.val());\n return *this;\n }\n constexpr modint& operator-=(const modint& m)\n {\n m_val = norm(m_val + mod() - m.val());\n return *this;\n }\n constexpr modint& operator*=(const modint& m)\n {\n m_val = normll((i64)m_val * (i64)m.val() % (i64)mod());\n return *this;\n }\n constexpr modint& operator/=(const modint& m)\n {\n return *this *= m.inv();\n }\n constexpr modint operator+(const modint& m) const\n {\n auto v = *this;\n return v += m;\n }\n constexpr modint operator-(const modint& m) const\n {\n auto v = *this;\n return v -= m;\n }\n constexpr modint operator*(const modint& m) const\n {\n auto v = *this;\n return v *= m;\n }\n constexpr modint operator/(const modint& m) const\n {\n auto v = *this;\n return v /= m;\n }\n constexpr bool operator==(const modint& m) const\n {\n return m_val == m.val();\n }\n constexpr bool operator!=(const modint& m) const\n {\n return not(*this == m);\n }\n friend Istream& operator>>(Istream& is, modint& m)\n {\n i64 v;\n return is >> v, m = v, is;\n }\n friend Ostream& operator<<(Ostream& os, const modint& m)\n {\n return os << m.val();\n }\n constexpr u32 val() const\n {\n return m_val;\n }\n template<typename I>\n constexpr modint pow(I n) const\n {\n return power(*this, n);\n }\n constexpr modint inv() const\n {\n return pow(mod() - 2);\n }\n static modint sinv(u32 n)\n {\n static Vec<modint> is{1, 1};\n for (u32 i = (u32)is.size(); i <= n; i++) {\n is.push_back(-is[mod() % i] * (mod() / i));\n }\n return is[n];\n }\n static modint fact(u32 n)\n {\n static Vec<modint> fs{1, 1};\n for (u32 i = (u32)fs.size(); i <= n; i++) {\n fs.push_back(fs.back() * i);\n }\n return fs[n];\n }\n static modint ifact(u32 n)\n {\n static Vec<modint> ifs{1, 1};\n for (u32 i = (u32)ifs.size(); i <= n; i++) {\n ifs.push_back(ifs.back() * sinv(i));\n }\n return ifs[n];\n }\n static modint comb(int n, int k)\n {\n return k > n or k < 0 ? modint{0} : fact(n) * ifact(n - k) * ifact(k);\n }\nprivate:\n static constexpr u32 norm(u32 x)\n {\n return x < mod() ? x : x - mod();\n }\n static constexpr u32 normll(i64 x)\n {\n return norm(u32(x % (i64)mod() + (i64)mod()));\n }\n u32 m_val;\n};\nusing modint_1000000007 = modint<1000000007, 5, 1>;\nusing modint_998244353 = modint<998244353, 3, 23>;\ntemplate<int id>\nusing modint_dynamic = modint<0, 0, id>;\ntemplate<typename T = int>\nclass Graph\n{\n struct Edge\n {\n Edge() = default;\n Edge(int i, int t, T c) : id{i}, to{t}, cost{c} {}\n int id;\n int to;\n T cost;\n operator int() const\n {\n return to;\n }\n };\npublic:\n Graph(int n) : m_v{n}, m_edges(n) {}\n void addEdge(int u, int v, bool bi = false)\n {\n assert(0 <= u and u < m_v);\n assert(0 <= v and v < m_v);\n m_edges[u].emplace_back(m_e, v, 1);\n if (bi) { m_edges[v].emplace_back(m_e, u, 1); }\n m_e++;\n }\n void addEdge(int u, int v, const T& c, bool bi = false)\n {\n assert(0 <= u and u < m_v);\n assert(0 <= v and v < m_v);\n m_edges[u].emplace_back(m_e, v, c);\n if (bi) { m_edges[v].emplace_back(m_e, u, c); }\n m_e++;\n }\n const Vec<Edge>& operator[](const int u) const\n {\n assert(0 <= u and u < m_v);\n return m_edges[u];\n }\n Vec<Edge>& operator[](const int u)\n {\n assert(0 <= u and u < m_v);\n return m_edges[u];\n }\n int v() const\n {\n return m_v;\n }\n int e() const\n {\n return m_e;\n }\n friend Ostream& operator<<(Ostream& os, const Graph& g)\n {\n for (int u : rep(g.v())) {\n for (const auto& [id, v, c] : g[u]) {\n os << \"[\" << id << \"]: \";\n os << u << \"->\" << v << \"(\" << c << \")\\n\";\n }\n }\n return os;\n }\n Vec<T> sizes(int root = 0) const\n {\n const int N = v();\n assert(0 <= root and root < N);\n Vec<T> ss(N, 1);\n Fix([&](auto dfs, int u, int p) -> void {\n for (const auto& [id, v, c] : m_edges[u]) {\n static_cast<void>(id);\n if (v == p) { continue; }\n dfs(v, u);\n ss[u] += ss[v];\n }\n })(root, -1);\n return ss;\n }\n Vec<T> depths(int root = 0) const\n {\n const int N = v();\n assert(0 <= root and root < N);\n Vec<T> ds(N, 0);\n Fix([&](auto dfs, int u, int p) -> void {\n for (const auto& [id, v, c] : m_edges[u]) {\n static_cast<void>(id);\n if (v == p) { continue; }\n ds[v] = ds[u] + c;\n dfs(v, u);\n }\n })(root, -1);\n return ds;\n }\n Vec<int> parents(int root = 0) const\n {\n const int N = v();\n assert(0 <= root and root < N);\n Vec<int> ps(N, -1);\n Fix([&](auto dfs, int u, int p) -> void {\n for (const auto& [id, v, c] : m_edges[u]) {\n static_cast<void>(id);\n if (v == p) { continue; }\n ps[v] = u;\n dfs(v, u);\n }\n })(root, -1);\n return ps;\n }\nprivate:\n int m_v;\n int m_e = 0;\n Vec<Vec<Edge>> m_edges;\n};\n#pragma endregion\nint main()\n{\n while (true) {\n const auto [N, M, S, G] = in.tup<int, int, int, int>();\n if (N == 0 and M == 0 and S == 0 and G == 0) { break; }\n Graph<Str> g(N);\n for (int i : rep(M)) {\n const auto [u, v, s] = in.tup<int, int, Str>();\n g.addEdge(u, v, s);\n }\n const Str INF = Str(1, 'z' + 1);\n const int L = 2 * N;\n constexpr int C = 6;\n auto dp = ndVec({N + 1, L * C + 1}, INF);\n dp[S][0] = \"\";\n MinHeap<Pair<Str, Pair<int, int>>> Q;\n Q.push({\"\", {S, 0}});\n while (not Q.empty()) {\n const auto [str, p] = Q.top();\n const auto [u, l] = p;\n Q.pop();\n if (dp[u][l] < str) { continue; }\n for (const auto& e : g[u]) {\n const int v = e.to;\n const Str s = e.cost;\n if (l + s.size() > L * C) { continue; }\n if (dp[v][l + s.size()] > str + s) {\n dp[v][l + s.size()] = str + s;\n Q.push({dp[v][l + s.size()], {v, l + s.size()}});\n }\n }\n }\n void(0);\n Str mins = INF;\n int minl = -1;\n for (int l : rep(L * C + 1)) {\n if (chmin(mins, dp[G][l])) { minl = l; }\n }\n if (minl == -1 or minl >= (N - 1) * C) {\n out.ln(\"NO\");\n } else {\n out.ln(mins);\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 540, "memory_kb": 14484, "score_of_the_acc": -0.3268, "final_rank": 14 }, { "submission_id": "aoj_1169_6044580", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define eps 1e-9\n#define INF 2000000000 // 2e9\n#define LLINF 2000000000000000000ll // 2e18 (llmax:9e18)\n#define all(x) (x).begin(), (x).end()\n#define sq(x) ((x) * (x))\n\n#define rep(i, x) for (int i = 0; i < (int)(x); i++)\n#define drep(i, x) for (int i = ((int)(x)-1); i >= 0; i--)\n\n#define popcount __builtin_popcount\n#define next __next\n#define prev __prev\n\n#ifndef LOCAL\n#define dmp(...) ;\n#else\n#define dmp(...) \\\n cerr << \"[ \" << #__VA_ARGS__ << \" ] : \" << dump_str(__VA_ARGS__) << endl\n#endif\n\n// ---------------- Utility ------------------\n\ntemplate <class T>\nbool chmin(T &a, const T &b) {\n if (a <= b) return false;\n a = b;\n return true;\n}\n\ntemplate <class T>\nbool chmax(T &a, const T &b) {\n if (a >= b) return false;\n a = b;\n return true;\n}\n\ntemplate <class T>\nusing MaxHeap = priority_queue<T>;\n\ntemplate <class T>\nusing MinHeap = priority_queue<T, vector<T>, greater<T>>;\n\ntemplate <class T>\nvector<T> vect(int len, T elem) {\n return vector<T>(len, elem);\n}\n\n// ----------------- Input -------------------\n\ntemplate <class T, class U>\nistream &operator>>(istream &is, pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\n\ntemplate <class T>\nistream &operator>>(istream &is, vector<T> &vec) {\n for (int i = 0; i < vec.size(); i++) is >> vec[i];\n return is;\n}\n\n// ----------------- Output ------------------\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n return os << p.first << ',' << p.second;\n}\n\ntemplate <class T>\nostream &operator<<(ostream &os, const vector<T> &v) {\n for (const T &e : v) os << e << \" \";\n return os;\n}\n\ntemplate <class T>\nostream &operator<<(ostream &os, const deque<T> &d) {\n for (const T &e : d) os << e << \" \";\n return os;\n}\n\ntemplate <class T>\nostream &operator<<(ostream &os, const set<T> &s) {\n os << \"{ \";\n for (const T &e : s) os << e << \" \";\n return os << \"}\";\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const map<T, U> &m) {\n os << \"{ \";\n for (const auto &[key, val] : m) os << \"( \" << key << \" -> \" << val << \" ) \";\n return os << \"}\";\n}\n\ntemplate <class TupleTy, size_t... I>\nvoid dump_tuple(ostream &os, const TupleTy t, std::index_sequence<I...>) {\n (..., (os << (I == 0 ? \"\" : \",\") << std::get<I>(t)));\n}\n\ntemplate <class... Args>\nostream &operator<<(ostream &os, const tuple<Args...> &t) {\n os << \"(\";\n dump_tuple(os, t, std::make_index_sequence<sizeof...(Args)>());\n return os << \")\";\n}\n\nvoid dump_str_rec(ostringstream &) {}\n\ntemplate <class Head, class... Tail>\nvoid dump_str_rec(ostringstream &oss, Head &&head, Tail &&... tail) {\n oss << \", \" << head;\n dump_str_rec(oss, forward<Tail>(tail)...);\n}\n\ntemplate <class T, class... U>\nstring dump_str(T &&arg, U &&... args) {\n ostringstream oss;\n oss << arg;\n dump_str_rec(oss, forward<U>(args)...);\n return oss.str();\n}\n\n// --------------- Fast I/O ------------------\n\nvoid fastio() {\n cin.tie(0);\n ios::sync_with_stdio(0);\n cout << fixed << setprecision(20);\n}\n\n// ------------------ ACL --------------------\n\n// #include <atcoder/modint>\n// constexpr int MOD = 998244353;\n// constexpr int MOD = 1000000007;\n// using mint = atcoder::static_modint<MOD>;\n// ostream &operator<<(ostream &os, const mint &v) {\n// return os << v.val();\n// }\n\n// ------------ End of template --------------\n\n#define endl \"\\n\"\nusing ll = long long;\nusing pii = pair<int, int>;\n\nconst bool multitest = false;\n\nbool solve() {\n int n, a, s, g;\n cin >> n >> a >> s >> g;\n if (n == 0 && a == 0 && s == 0 && g == 0) return false;\n\n vector<vector<pair<int, string>>> G(n);\n for (int i = 0; i < a; i++) {\n int x, y;\n string label;\n cin >> x >> y >> label;\n G[x].emplace_back(y, label);\n }\n vector<string> dp(n, \"|\");\n dp[g] = string(\"\");\n\n for (int _ = 0; _ < 6 * n; _++) {\n for (int i = 0; i < n; i++) {\n for (auto &[j, label] : G[i]) {\n if (dp[j] != \"|\") chmin(dp[i], label + dp[j]);\n }\n }\n }\n\n string ans = dp[s];\n for (int _ = 0; _ < 6 * n; _++) {\n for (int i = 0; i < n; i++) {\n for (auto &[j, label] : G[i]) {\n if (dp[j] != \"|\") chmin(dp[i], label + dp[j]);\n }\n }\n }\n\n if (dp[s] < ans || ans == \"|\") {\n cout << \"NO\" << endl;\n } else {\n cout << ans << endl;\n }\n return true;\n}\n\nint main() {\n fastio();\n if (!multitest) {\n while (solve()) {}\n } else {\n cerr << \"[Warning] Multi testcase mode on\" << endl;\n int t;\n cin >> t;\n while (t--) solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 550, "memory_kb": 4244, "score_of_the_acc": -0.0904, "final_rank": 9 }, { "submission_id": "aoj_1169_6044574", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define eps 1e-9\n#define INF 2000000000 // 2e9\n#define LLINF 2000000000000000000ll // 2e18 (llmax:9e18)\n#define all(x) (x).begin(), (x).end()\n#define sq(x) ((x) * (x))\n\n#define rep(i, x) for (int i = 0; i < (int)(x); i++)\n#define drep(i, x) for (int i = ((int)(x)-1); i >= 0; i--)\n\n#define popcount __builtin_popcount\n#define next __next\n#define prev __prev\n\n#ifndef LOCAL\n#define dmp(...) ;\n#else\n#define dmp(...) \\\n cerr << \"[ \" << #__VA_ARGS__ << \" ] : \" << dump_str(__VA_ARGS__) << endl\n#endif\n\n// ---------------- Utility ------------------\n\ntemplate <class T>\nbool chmin(T &a, const T &b) {\n if (a <= b) return false;\n a = b;\n return true;\n}\n\ntemplate <class T>\nbool chmax(T &a, const T &b) {\n if (a >= b) return false;\n a = b;\n return true;\n}\n\ntemplate <class T>\nusing MaxHeap = priority_queue<T>;\n\ntemplate <class T>\nusing MinHeap = priority_queue<T, vector<T>, greater<T>>;\n\ntemplate <class T>\nvector<T> vect(int len, T elem) {\n return vector<T>(len, elem);\n}\n\n// ----------------- Input -------------------\n\ntemplate <class T, class U>\nistream &operator>>(istream &is, pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\n\ntemplate <class T>\nistream &operator>>(istream &is, vector<T> &vec) {\n for (int i = 0; i < vec.size(); i++) is >> vec[i];\n return is;\n}\n\n// ----------------- Output ------------------\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n return os << p.first << ',' << p.second;\n}\n\ntemplate <class T>\nostream &operator<<(ostream &os, const vector<T> &v) {\n for (const T &e : v) os << e << \" \";\n return os;\n}\n\ntemplate <class T>\nostream &operator<<(ostream &os, const deque<T> &d) {\n for (const T &e : d) os << e << \" \";\n return os;\n}\n\ntemplate <class T>\nostream &operator<<(ostream &os, const set<T> &s) {\n os << \"{ \";\n for (const T &e : s) os << e << \" \";\n return os << \"}\";\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const map<T, U> &m) {\n os << \"{ \";\n for (const auto &[key, val] : m) os << \"( \" << key << \" -> \" << val << \" ) \";\n return os << \"}\";\n}\n\ntemplate <class TupleTy, size_t... I>\nvoid dump_tuple(ostream &os, const TupleTy t, std::index_sequence<I...>) {\n (..., (os << (I == 0 ? \"\" : \",\") << std::get<I>(t)));\n}\n\ntemplate <class... Args>\nostream &operator<<(ostream &os, const tuple<Args...> &t) {\n os << \"(\";\n dump_tuple(os, t, std::make_index_sequence<sizeof...(Args)>());\n return os << \")\";\n}\n\nvoid dump_str_rec(ostringstream &) {}\n\ntemplate <class Head, class... Tail>\nvoid dump_str_rec(ostringstream &oss, Head &&head, Tail &&... tail) {\n oss << \", \" << head;\n dump_str_rec(oss, forward<Tail>(tail)...);\n}\n\ntemplate <class T, class... U>\nstring dump_str(T &&arg, U &&... args) {\n ostringstream oss;\n oss << arg;\n dump_str_rec(oss, forward<U>(args)...);\n return oss.str();\n}\n\n// --------------- Fast I/O ------------------\n\nvoid fastio() {\n cin.tie(0);\n ios::sync_with_stdio(0);\n cout << fixed << setprecision(20);\n}\n\n// ------------------ ACL --------------------\n\n// #include <atcoder/modint>\n// constexpr int MOD = 998244353;\n// constexpr int MOD = 1000000007;\n// using mint = atcoder::static_modint<MOD>;\n// ostream &operator<<(ostream &os, const mint &v) {\n// return os << v.val();\n// }\n\n// ------------ End of template --------------\n\n#define endl \"\\n\"\nusing ll = long long;\nusing pii = pair<int, int>;\n\nconst bool multitest = false;\n\nbool solve() {\n int n, a, s, g;\n cin >> n >> a >> s >> g;\n if (n == 0 && a == 0 && s == 0 && g == 0) return false;\n\n vector<vector<pair<int, string>>> G(n);\n for (int i = 0; i < a; i++) {\n int x, y;\n string label;\n cin >> x >> y >> label;\n G[x].emplace_back(y, label);\n }\n vector<string> dp(n, \"|\");\n dp[g] = string(\"\");\n\n for (int _ = 0; _ < 2 * a; _++) {\n for (int i = 0; i < n; i++) {\n for (auto &[j, label] : G[i]) {\n if (dp[j] != \"|\") chmin(dp[i], label + dp[j]);\n }\n }\n }\n\n string ans = dp[s];\n for (int _ = 0; _ < 2 * a; _++) {\n for (int i = 0; i < n; i++) {\n for (auto &[j, label] : G[i]) {\n if (dp[j] != \"|\") chmin(dp[i], label + dp[j]);\n }\n }\n }\n\n if (dp[s] < ans || ans == \"|\") {\n cout << \"NO\" << endl;\n } else {\n cout << ans << endl;\n }\n return true;\n}\n\nint main() {\n fastio();\n if (!multitest) {\n while (solve()) {}\n } else {\n cerr << \"[Warning] Multi testcase mode on\" << endl;\n int t;\n cin >> t;\n while (t--) solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 7280, "memory_kb": 8172, "score_of_the_acc": -1.1086, "final_rank": 19 }, { "submission_id": "aoj_1169_6034836", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int i = 0; i < n; i++)\n#define all(v) v.begin(), v.end()\ntemplate <class T, class U>\ninline bool chmax(T& a, U b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <class T, class U>\ninline bool chmin(T& a, U b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\nconstexpr int INF = 1000000000;\nconstexpr ll llINF = 3000000000000000000;\nconstexpr int mod = 998244353;\nconstexpr double eps = 1e-10;\nconst double pi = acos(-1);\n/*\nvector<vector<ll>>C;\nvoid init_comb(int n,int m){\n C.resize(n+1,vector<ll>(m+1,0));\n C[0][0]=1;\n for(int i=1;i<=n;i++){\n C[i][0]=1;\n for(int j=1;j<=m;j++){\n C[i][j]=(C[i-1][j-1]+C[i-1][j])%mod;\n }\n }\n}*/\nbool prime(int a) {\n if (a == 1) return false;\n for (int i = 2; i * i <= a; i++) {\n if (a % i == 0) return false;\n }\n return true;\n}\nvector<int> prime_list(int n) {\n vector<int> v(n + 1), res;\n for (int i = n; i >= 2; i--) {\n for (int j = i; j <= n; j += i) v[j] = i;\n }\n for (int i = 2; i <= n; i++) {\n if (v[i] == i) res.push_back(i);\n }\n return res;\n}\nvector<int> next_divisor(int n) {\n vector<int> v(n + 1);\n for (int i = n; i >= 2; i--) {\n for (int j = i; j <= n; j += i) v[j] = i;\n }\n return v;\n}\nll modpow(ll a, ll b) {\n ll res = 1;\n while (b) {\n if (b & 1) {\n res *= a;\n res %= mod;\n }\n a *= a;\n a %= mod;\n b >>= 1;\n }\n return res;\n}\nvector<ll> inv, fact, factinv;\nvoid init_fact(int n) {\n inv.resize(n + 1);\n fact.resize(n + 1);\n factinv.resize(n + 1);\n inv[0] = 0;\n inv[1] = 1;\n fact[0] = 1;\n factinv[0] = 1;\n for (ll i = 1; i <= n; i++) {\n if (i >= 2) inv[i] = mod - ((mod / i) * inv[mod % i] % mod);\n fact[i] = (fact[i - 1] * i) % mod;\n factinv[i] = factinv[i - 1] * inv[i] % mod;\n }\n}\nll _inv(ll a, ll m = mod) {\n // gcd(a,m) must be 1\n ll b = m, u = 1, v = 0;\n while (b) {\n ll t = a / b;\n a -= t * b;\n swap(a, b);\n u -= t * v;\n swap(u, v);\n }\n u %= m;\n if (u < 0) u += m;\n return u;\n}\nll comb(int a, int b) {\n if (a < b) return 0;\n if (a < 0) return 0;\n return fact[a] * factinv[a - b] % mod * factinv[b] % mod;\n}\nstruct edge {\n int x, y;\n string str;\n};\nvoid solve() {\n while (1) {\n int n, m, s, g;\n cin >> n >> m >> s >> g;\n if (n == 0) break;\n vector<edge> es(m);\n vector<vector<bool>> able(n, vector<bool>(n));\n rep(i, n) able[i][i] = true;\n rep(i, m) {\n int x, y;\n string str;\n cin >> x >> y >> str;\n es.push_back({x, y, str});\n able[x][y] = true;\n }\n rep(k, n) {\n rep(i, n) {\n rep(j, n) {\n if (able[i][k] && able[k][j]) able[i][j] = true;\n }\n }\n }\n if (!able[s][g]) {\n cout << \"NO\" << endl;\n continue;\n }\n vector<string> d(n, \"{\");\n d[g] = \"\";\n while (1) {\n bool update = false;\n for (auto [x, y, str] : es) {\n if (d[y] == \"{\") continue;\n if (!able[s][x]) continue;\n if (d[x].size() > 6 * n) continue;\n if (chmin(d[x], str + d[y])) {\n update = true;\n }\n }\n if (!update) break;\n }\n cout << (d[s].size() > 6 * n ? \"NO\" : d[s]) << endl;\n }\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n solve();\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3496, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1169_6031393", "code_snippet": "#pragma region Macros\n#include <bits/stdc++.h>\nusing namespace std;\ntemplate <class T> inline bool chmax(T &a, T b) {\n if(a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <class T> inline bool chmin(T &a, T b) {\n if(a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\n#ifdef DEBUG\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << '(' << p.first << ',' << p.second << ')';\n return os;\n}\ntemplate <class T> ostream &operator<<(ostream &os, const vector<T> &v) {\n os << '{';\n for(int i = 0; i < (int)v.size(); i++) {\n if(i) { os << ','; }\n os << v[i];\n }\n os << '}';\n return os;\n}\nvoid debugg() { cerr << endl; }\ntemplate <class T, class... Args>\nvoid debugg(const T &x, const Args &... args) {\n cerr << \" \" << x;\n debugg(args...);\n}\n#define debug(...) \\\n cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"]: \", debugg(__VA_ARGS__)\n#define dump(x) cerr << __LINE__ << \" \" << #x << \" = \" << (x) << endl\n#else\n#define debug(...) (void(0))\n#define dump(x) (void(0))\n#endif\n\nstruct Setup {\n Setup() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(15);\n }\n} __Setup;\n\nusing ll = long long;\n#define OVERLOAD3(_1, _2, _3, name, ...) name\n#define ALL(v) (v).begin(), (v).end()\n#define RALL(v) (v).rbegin(), (v).rend()\n#define REP1(i, n) for(int i = 0; i < (n); i++)\n#define REP2(i, a, b) for(int i = (a); i < int(b); i++)\n#define REP(...) OVERLOAD3(__VA_ARGS__, REP2, REP1)(__VA_ARGS__)\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\nconst int INF = 1 << 30;\nconst ll LLINF = 1LL << 60;\nconstexpr int MOD = 1000000007;\nconstexpr int MOD2 = 998244353;\nconst int dx[4] = {1, 0, -1, 0};\nconst int dy[4] = {0, 1, 0, -1};\n\nvoid Case(int i) { cout << \"Case #\" << i << \": \"; }\nint popcount(int x) { return __builtin_popcount(x); }\nll popcount(ll x) { return __builtin_popcountll(x); }\n#pragma endregion Macros\n\nint main() {\n while(1) {\n int N, M, s, g;\n cin >> N >> M >> s >> g;\n if(N == 0) break;\n vector<tuple<int, int, string>> edges(M);\n REP(i, M) {\n int x, y;\n string lab;\n cin >> x >> y >> lab;\n edges[i] = {x, y, lab};\n }\n\n vector<string> dp(N, \"INF\");\n dp[g] = \"\";\n REP(_, N*12) {\n for(const auto& [x, y, lab] : edges) {\n if(dp[y] == \"INF\") continue;\n if(dp[x] == \"INF\") dp[x] = lab + dp[y];\n else chmin(dp[x], lab + dp[y]);\n }\n }\n if(dp[s].size() > N*6 or dp[s] == \"INF\") {\n cout << \"NO\\n\";\n } else {\n cout << dp[s] << '\\n';\n }\n }\n}", "accuracy": 1, "time_ms": 580, "memory_kb": 4052, "score_of_the_acc": -0.09, "final_rank": 8 }, { "submission_id": "aoj_1169_6031103", "code_snippet": "#pragma GCC ta g(\"avx2\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\nusing namespace std;\n#define DEBUG\n#ifdef DEBUG\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << '(' << p.first << ',' << p.second << ')';\n return os;\n}\ntemplate <class T> ostream &operator<<(ostream &os, const vector<T> &v) {\n os << '{';\n for(int i = 0; i < (int)v.size(); i++) {\n if(i) { os << ','; }\n os << v[i];\n }\n os << '}';\n return os;\n}\nvoid debugg() { cerr << endl; }\ntemplate <class T, class... Args>\nvoid debugg(const T &x, const Args &... args) {\n cerr << \" \" << x;\n debugg(args...);\n}\n#define debug(...) \\\n cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"]: \", debugg(__VA_ARGS__)\n#define dump(x) cerr << __LINE__ << \" \" << #x << \" = \" << (x) << endl\n#else\n#define debug(...) (void(0))\n#define dump(x) (void(0))\n#endif\nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vl;\ntypedef vector<vl> vvl;\ntypedef vector<char> vc;\ntypedef vector<string> vs;\ntypedef vector<bool> vb;\ntypedef vector<double> vd;\ntypedef pair<ll,ll> P;\ntypedef pair<int,int> pii;\ntypedef vector<P> vpl;\ntypedef tuple<ll,ll,ll> tapu;\n#define rep(i,n) for(int i=0; i<(n); i++)\n#define REP(i,a,b) for(int i=(a); i<(b); i++)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\ntemplate<typename T1,typename T2> inline bool chmin(T1 &a,T2 b){\n\tif(a>b){\n\t\ta = b; return true;\n\t}\n\telse return false;\n}\ntemplate<typename T1,typename T2> inline bool chmax(T1 &a,T2 b){\n\tif(a<b){\n\t\ta = b; return true;\n\t}\n\telse return false;\n}\ntemplate<typename T> inline void print(T &a){\n int sz = a.size();\n for(auto itr = a.begin(); itr != a.end(); itr++){\n\t\tcout << *itr;\n sz--;\n if(sz) cout << \" \";\n\t}\n cout << \"\\n\";\n}\ntemplate<typename T1,typename T2> inline void print2(T1 a, T2 b){\n\tcout << a << \" \" << b << \"\\n\";\n}\ntemplate<typename T1,typename T2,typename T3> inline void print3(T1 a, T2 b, T3 c){\n\tcout << a << \" \" << b << \" \" << c << \"\\n\";\n}\nvoid mark() {cout << \"#\" << \"\\n\";}\nll pcount(ll x) {return __builtin_popcountll(x);}\n//#include <atcoder/maxflow>\n//using namespace atcoder;\nconst int inf = (1<<30)-1;\nconst ll linf = 1LL<<61;\nconst int MAX = 510000;\nint dy[8] = {0,1,0,-1,1,-1,-1,1};\nint dx[8] = {-1,0,1,0,1,-1,1,-1};\nconst double pi = acos(-1);\nconst double eps = 1e-9;\n//const int mod = 1e9 + 7;\nconst int mod = 998244353;\n\nint main(){\n\twhile(1){\n\t\tint n,a,s,g; cin >> n >> a >> s >> g;\n\t\tif(!n) break;\n\t\tvector<vector<pair<int,string>>> G(n);\n\t\trep(i,a){\n\t\t\tint x,y;\n\t\t\tstring lab;\n\t\t\tcin >> x >> y >> lab;\n\t\t\tG[y].emplace_back(x,lab);\n\t\t}\n\t\tvector<string> dp(n,\"~\");\n\t\tdp[g] = \"\";\n\t\trep(z,n*10){\n\t\t\trep(u,n){\n\t\t\t\tif(dp[u] == \"~\") continue;\n\t\t\t\tfor(auto v : G[u]){\n\t\t\t\t\tchmin(dp[v.first], v.second + dp[u]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(dp[s].size() > n*6 || dp[s] == \"~\"){\n\t\t\tcout << \"NO\\n\";\n\t\t}else{\n\t\t\tcout << dp[s] << \"\\n\";\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 4060, "score_of_the_acc": -0.0709, "final_rank": 5 }, { "submission_id": "aoj_1169_6029748", "code_snippet": "#pragma GCC target(\"avx\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include<bits/stdc++.h>\n// #include<ext/pb_ds/assoc_container.hpp>\n// #include<ext/pb_ds/tree_policy.hpp>\n// #include<ext/pb_ds/tag_and_trait.hpp>\n// using namespace __gnu_pbds;\n// #include<boost/multiprecision/cpp_int.hpp>\n// namespace multiprecisioninteger = boost::multiprecision;\n// using cint=multiprecisioninteger::cpp_int;\nusing namespace std;\nusing ll=long long;\nusing datas=pair<ll,ll>;\nusing ddatas=pair<long double,long double>;\nusing tdata=pair<ll,datas>;\nusing vec=vector<ll>;\nusing mat=vector<vec>;\nusing pvec=vector<datas>;\nusing pmat=vector<pvec>;\n// using llset=tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update>;\n#define For(i,a,b) for(i=a;i<(ll)b;++i)\n#define bFor(i,b,a) for(i=b,--i;i>=(ll)a;--i)\n#define rep(i,N) For(i,0,N)\n#define rep1(i,N) For(i,1,N)\n#define brep(i,N) bFor(i,N,0)\n#define brep1(i,N) bFor(i,N,1)\n#define all(v) (v).begin(),(v).end()\n#define allr(v) (v).rbegin(),(v).rend()\n#define vsort(v) sort(all(v))\n#define vrsort(v) sort(allr(v))\n#define uniq(v) vsort(v),(v).erase(unique(all(v)),(v).end())\n#define endl \"\\n\"\n#define popcount __builtin_popcountll\n#define eb emplace_back\n#define print(x) cout<<x<<endl\n#define printyes print(\"Yes\")\n#define printno print(\"No\")\n#define printYES print(\"YES\")\n#define printNO print(\"NO\")\n#define output(v) do{bool f=0;for(auto outi:v){cout<<(f?\" \":\"\")<<outi;f=1;}cout<<endl;}while(0)\n#define matoutput(v) do{for(auto outimat:v)output(outimat);}while(0)\nconstexpr ll mod=1000000007;\n// constexpr ll mod=998244353;\nconstexpr ll inf=1LL<<60;\nconstexpr long double eps=1e-9;\nconst long double PI=acosl(-1);\ntemplate<class T,class E> ostream& operator<<(ostream& os,const pair<T,E>& p){return os<<\"(\"<<p.first<<\",\"<<p.second<<\")\";}\ntemplate<class T> ostream& operator<<(ostream& os,const vector<T>& v){\n os<<\"{\";bool f=false;\n for(auto& x:v){if(f)os<<\",\";os<<x;f=true;}\n os<<\"}\";\n return os;\n}\ntemplate<class T> ostream& operator<<(ostream& os,const set<T>& v){\n os<<\"{\";bool f=false;\n for(auto& x:v){if(f)os<<\",\";os<<x;f=true;}\n os<<\"}\";\n return os;\n}\ntemplate<class T> ostream& operator<<(ostream& os,const multiset<T>& v){\n os<<\"{\";bool f=false;\n for(auto& x:v){if(f)os<<\",\";os<<x;f=true;}\n os<<\"}\";\n return os;\n}\ntemplate<class T,class E> ostream& operator<<(ostream& os,const map<T,E>& v){\n os<<\"{\";bool f=false;\n for(auto& x:v){if(f)os<<\",\";os<<x;f=true;}\n os<<\"}\";\n return os;\n}\ntemplate<class T> inline bool chmax(T& a,const T b){bool x=a<b;if(x)a=b;return x;}\ntemplate<class T> inline bool chmin(T& a,const T b){bool x=a>b;if(x)a=b;return x;}\n#ifdef DEBUG\nvoid debugg(){cout<<endl;}\ntemplate<class T,class... Args>void debugg(const T& x,const Args&... args){cout<<\" \"<<x;debugg(args...);}\n#define debug(...) cout<<__LINE__<<\" [\"<<#__VA_ARGS__<<\"]:\",debugg(__VA_ARGS__)\n#else\n#define debug(...) (void(0))\n#endif\n\ninline void startupcpp(void) noexcept{\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout<<fixed<<setprecision(15);\n}\n\nll modinv(ll a,const ll m=mod) noexcept{\n ll b=m,u=1,v=0,t;\n while(b){\n t=a/b;\n a-=t*b; swap(a,b);\n u-=t*v; swap(u,v);\n }\n return (u+m)%m;\n}\n\nll moddevide(const ll a,const ll b) noexcept{return (a*modinv(b))%mod;}\n\nvec modncrlistp,modncrlistm;\n\nll modncr(const ll n,const ll r) noexcept{\n if(n<r)return 0;\n ll i,size=modncrlistp.size();\n if(size<=n){\n modncrlistp.resize(n+1);\n modncrlistm.resize(n+1);\n if(!size){\n modncrlistp[0]=modncrlistm[0]=1;\n size++;\n }\n For(i,size,n+1)modncrlistp[i]=modncrlistp[i-1]*i%mod;\n modncrlistm[n]=modinv(modncrlistp[n]);\n for(i=n;i>size;--i)modncrlistm[i-1]=modncrlistm[i]*i%mod;\n }\n return modncrlistp[n]*modncrlistm[r]%mod*modncrlistm[n-r]%mod;\n}\n\nll modpow(ll a,ll n,const ll m=mod){\n if(n<0)return 0;\n ll res=1;\n while(n>0){\n if(n&1)res=res*a%m;\n a=a*a%m;\n n>>=1;\n }\n return res;\n}\n\nconstexpr ll gcd(const ll a,const ll b) noexcept{return (!b)?abs(a):(a%b==0)?abs(b):gcd(b,a%b);}\nconstexpr ll lcm(const ll a,const ll b) noexcept{return a/gcd(a,b)*b;}\n\nint main(){\n startupcpp();\n int N,M,S,G;\nwhile(cin>>N>>M>>S>>G,N|M|S|G){\n vector<tuple<int,int,string>> edge(M);\n for(auto& [x,y,lab]:edge)cin>>x>>y>>lab;\n vector<string> dp(N,\"{\");\n dp[G]=\"\";\n for(int t=0;t<N*12;++t){\n for(auto& [x,y,lab]:edge){\n if(dp[y]==\"{\")continue;\n chmin(dp[x],lab+dp[y]);\n }\n }\n if(dp[S].size()>N*6||dp[S].back()=='{')printNO;\n else print(dp[S]);\n}\n}", "accuracy": 1, "time_ms": 490, "memory_kb": 4220, "score_of_the_acc": -0.0815, "final_rank": 7 } ]
aoj_1173_cpp
The Balance of the World The world should be finely balanced. Positive vs. negative, light vs. shadow, and left vs. right brackets. Your mission is to write a program that judges whether a string is balanced with respect to brackets so that we can observe the balance of the world. A string that will be given to the program may have two kinds of brackets, round (“( )”) and square (“[ ]”). A string is balanced if and only if the following conditions hold. For every left round bracket (“(”), there is a corresponding right round bracket (“)”) in the following part of the string. For every left square bracket (“[”), there is a corresponding right square bracket (“]”) in the following part of the string. For every right bracket, there is a left bracket corresponding to it. Correspondences of brackets have to be one to one, that is, a single bracket never corresponds to two or more brackets. For every pair of corresponding left and right brackets, the substring between them is balanced. Input The input consists of one or more lines, each of which being a dataset. A dataset is a string that consists of English alphabets, space characters, and two kinds of brackets, round (“( )”) and square (“[ ]”), terminated by a period. You can assume that every line has 100 characters or less. The line formed by a single period indicates the end of the input, which is not a dataset. Output For each dataset, output “yes” if the string is balanced, or “no” otherwise, in a line. There may not be any extra characters in the output. Sample Input So when I die (the [first] I will see in (heaven) is a score list). [ first in ] ( first out ). Half Moon tonight (At least it is better than no Moon at all]. A rope may form )( a trail in a maze. Help( I[m being held prisoner in a fortune cookie factory)]. ([ (([( [ ] ) ( ) (( ))] )) ]). . . Output for the Sample Input yes yes no no no yes yes
[ { "submission_id": "aoj_1173_9723425", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\twhile(true)\n\t{\n\t\tstring s;\n\t\tgetline(cin,s);\n\t\tif(s==\".\")\n\t\t\tbreak;\n\t\tvector <int> v;\n\t\tbool ans=true;\n\t\tfor(int i=0; i<s.size(); i++)\n\t\t{\n\t\t\tif(s[i]=='(')\n\t\t\t\tv.push_back(1);\n\t\t\tif(s[i]=='[')\n\t\t\t\tv.push_back(2);\n\t\t\tif(s[i]==')')\n\t\t\t{\n\t\t\t\tif(v.size()>0 and v.back()==1)\n\t\t\t\t\tv.pop_back();\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tans=false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(s[i]==']')\n\t\t\t{\n\t\t\t\tif(v.size()>0 and v.back()==2)\n\t\t\t\t\tv.pop_back();\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tans=false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(ans and v.size()==0)\n\t\t\tcout<<\"yes\";\n\t\telse\n\t\t\tcout<<\"no\";\n\t\tcout<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3176, "score_of_the_acc": -0.0132, "final_rank": 6 }, { "submission_id": "aoj_1173_9329935", "code_snippet": "#include <iostream>\n#include <string>\n#include <utility>\n#include <limits.h>\n#include <cstdlib>\n#include <algorithm>\n#include <iomanip>\n#include <math.h>\n#include <queue>\n#include <stack>\n#include <list>\n#include <map>\nusing namespace std;\nusing llint = long long;\nusing vec = vector<llint>;\nusing vvec = vector<vec>;\n\nvoid a(vector<int>& data, int len){\n for(int i = 0; i < len; i++){\n if(data[i] == 0){\n int j = 0;\n for(j = i; j < len-1; j++){\n data[j] = data[j+1];\n }\n data[len - 1] = 0;\n i--;\n len--;\n }\n }\n}\n\nint main(){\n while(1){\n int j = 0;\n int ans = 1;\n string s;\n getline(cin,s);\n if(s == \".\")return 0;\n vector<int> num(101,0);\n for(int i = 0; s[i] != '\\0'; i++){\n if(s[i] == '('){\n num[j] = 1;\n j++;\n }\n if(s[i] == '['){\n num[j] = 2;\n j++;\n }\n if(s[i] == ')'){\n num[j] = -1;\n j++;\n }\n if(s[i] == ']'){\n num[j] = -2;\n j++;\n }\n }\n for(int i = 0; i < j; i++){\n int count = 0;\n for(int q = 0; q < j; q++){\n if(num[q] == 0){\n count++;\n }\n }\n if(count == j){\n ans = 0;\n break;\n }\n if(i == 0 && num[i] < 0)break;\n if(num[i-1] + num[i] == 0 && num[i-1] > 0){\n num[i-1] = 0;\n num[i] = 0;\n /*for(int q = 0; q < j; q++){\n cout << num[q] << \",\";\n }\n cout << endl;*/\n a(num,j);\n /*for(int q = 0; q < j; q++){\n cout << num[q] << \",\";\n }\n cout << endl;*/\n\n j-=2;\n i=0;\n }\n }\n\n if(num[0] == 0 && num[1] == 0){\n ans = 0;\n }\n\n if(ans == 1){\n cout << \"no\\n\";\n }else if(ans == 0){\n cout << \"yes\\n\";\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3372, "score_of_the_acc": -0.0294, "final_rank": 10 }, { "submission_id": "aoj_1173_9103650", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n\nint main() {\n while(1) {\n string s;\n getline(cin, s);\n if (s == \".\") break;\n bool flag = true;\n stack<int> st;\n for (int i = 0; i < s.size(); i++) {\n if (s[i] == '(') {\n st.push(0);\n } else if (s[i] == ')') {\n if (st.empty()) {\n flag = false;\n break;\n }\n if (st.top() != 0) {\n flag = false;\n break;\n }\n st.pop();\n } else if (s[i] == '[') {\n st.push(1);\n } else if (s[i] == ']') {\n if (st.empty()) {\n flag = false;\n break;\n }\n if (st.top() != 1) {\n flag = false;\n break;\n }\n st.pop();\n }\n \n }\n if (!st.empty()) flag = false;\n if (flag) cout << \"yes\" << endl;\n else cout << \"no\" << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3192, "score_of_the_acc": -0.0146, "final_rank": 7 }, { "submission_id": "aoj_1173_7836818", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i = 0;i < n;i++)\ntypedef long long ll;\n\n#define MAX 1000000\n\nset<int> prime;\n\nvoid main_(){\n string s;\n getline(cin,s);\n if(s == \".\") exit(0);\n\n string k;\n rep(i,s.size()){\n set<char> st = {'(',')','[',']'};\n if(st.find(s.at(i)) != st.end()){\n k.push_back(s.at(i));\n }\n }\n\n int flag = true;\n while(flag){\n flag = false;\n string nxt;\n \n int num = k.size();\n int i = 0;\n for(i = 0;i < num - 1;i++){\n if( (k.at(i) == '(' && k.at(i + 1) == ')' ) ||\n (k.at(i) == '[' && k.at(i + 1) == ']' )){\n i += 1;;\n flag = true;\n } else {\n nxt.push_back(k.at(i));\n }\n }\n if(i == num - 1) nxt.push_back(k.at(i));\n\n k = nxt;\n }\n\n if(k == \"\"){\n cout << \"yes\" << endl;\n } else {\n cout << \"no\" << endl;\n }\n}\nsigned main(){\n while(1) main_();\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3348, "score_of_the_acc": -0.5275, "final_rank": 11 }, { "submission_id": "aoj_1173_7726286", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main() {\n while (true) {\n string S;\n getline(cin, S);\n if (S == \".\") {\n break;\n }\n stack<char> Q;\n bool ok = true;\n int L = S.length();\n for (int i = 0; i < L; i++) {\n if (S[i] == '(' || S[i] == '[') {\n Q.push(S[i]);\n }\n if (S[i] == ')' || S[i] == ']') {\n if (Q.empty()) {\n ok = false;\n }\n if (ok) {\n char c = Q.top();\n if ((S[i] == ')' && c == '(') || (S[i] == ']' && c == '[')) {\n Q.pop();\n } else {\n ok = false;\n }\n }\n }\n }\n if (ok && Q.empty()) {\n cout << \"yes\" << endl;\n } else {\n cout << \"no\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3136, "score_of_the_acc": -0.0099, "final_rank": 2 }, { "submission_id": "aoj_1173_6955867", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n string str, ans;\n stack<char> st;\n while(getline(cin, str), str != \".\"){\n while(!st.empty()) st.pop();\n ans = \"yes\";\n for(int i=0;i<str.size();i++){\n if(ans == \"no\") continue;\n if(str[i] == '('){\n st.push('(');\n }else if(str[i] == ')'){\n if(st.empty() || st.top() != '(') ans = \"no\";\n else st.pop();\n }else if(str[i] == '['){\n st.push('[');\n }else if(str[i] == ']'){\n if(st.empty() || st.top() != '[') ans = \"no\";\n else st.pop();\n }\n }\n if(!st.empty()) ans = \"no\";\n cout << ans << endl;\n }\n return(0);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3172, "score_of_the_acc": -0.0129, "final_rank": 5 }, { "submission_id": "aoj_1173_6873152", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{ \n while(1){\n int flg = 1;\n string s;\n stack<char> S;\n getline(cin, s);\n\n if(s == \".\"){\n flg = 2;\n break;\n }\n for(int i=0; i < s.length(); i++){\n char c = s[i];\n if(c == '('){\n S.push(c);\n }\n else if(c == ')'){\n if(S.size() > 0 && S.top() == '(') S.pop();\n else{\n flg = 0;\n break;\n }\n }\n else if(c == '['){\n S.push(c);\n }\n else if(c == ']'){\n if(S.size() > 0 && S.top() == '[') S.pop();\n else{\n flg = 0;\n break;\n }\n }\n else continue;\n }\n if(flg == 1 && S.size() == 0) cout << \"yes\" << endl;\n else if(flg == 0 || S.size() != 0) cout << \"no\" << endl;\n else if(flg == 2) break;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3160, "score_of_the_acc": -0.0119, "final_rank": 4 }, { "submission_id": "aoj_1173_5946123", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define int long long\n#define FOR(i, a, b) for (int i = (a); i < (b); i++)\n#define REP(i, n) for (int i = 0; i < (n); i++)\n#define pb push_back\n#define ALL(obj) (obj).begin(), (obj).end()\n#define vi vector<int>\n#define vvi vector<vector<int>>\n#define pii pair<int, int>\n#define us unordered_set\n#define ud unordered_dict\n#define Lower_bound(vec, n) distance((vec).begin(), lower_bound((vec).begin(), (vec).end(), (n)))\n#define Upper_bound(vec, n) distance((vec).begin(), upper_bound((vec).begin(), (vec).end(), (n)))\n#define Erase(vec) (vec).erase(unique((vec).begin(), (vec).end()), (vec).end())\n#define Print(vec) copy((vec).begin(), (vec).end(), ostream_iterator<int>(cout, \": \")); cout << endl\n//template <class T = int> in()(T x; cin >> x; return (x);)\n//template <class T> print(T& x) (cout << x << endl;)\n//using template <class T> vec = vector<T>;\nusing Graph = vector<vector<int>>;\nconst int INF = 1LL << 60;\nconst int MOD = (int)1e9 + 7;\nconst double EPS = 1e-9;\n\nsigned main() {\n\n string intmp;\n while (true) {\n\n /*\n vector<string> vec{};\n while (true) {\n cin >> intmp;\n vec.push_back(intmp);\n if (intmp[intmp.size() - 1] == '.') break;\n }\n */\n string s;\n getline(cin, s);\n\n /*\n vector<string> stop{\".\"};\n if (vec == stop) break;\n */\n if (s == \".\") break;\n\n vector <char> str{};\n us<char> chars{'(', ')', '[', ']'};\n //int num_maru=0, num_sikaku=0;\n //bool flag = false;\n char c;\n /*\n for (string e: vec) {\n REP(i, e.size()) {\n c = e[i];\n if (chars.count(c)) str.push_back(c);\n }\n }\n */\n\n REP(i, s.size()) {\n c = s[i];\n if (chars.count(c)) str.push_back(c);\n }\n\n bool flag = true;\n if (str.size() % 2 != 0) flag = false;\n int iter = str.size() / 2;\n REP(i, iter) {\n REP(j, str.size()-1) {\n if ((str[j] == '(' && str[j+1] == ')') || (str[j] == '[' && str[j+1] == ']')) {\n str.erase(str.begin()+j);\n str.erase(str.begin()+j);\n break;\n }\n }\n }\n if (str.size() != 0) flag = false;\n if (flag) cout << \"yes\" << endl;\n else cout << \"no\" << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3272, "score_of_the_acc": -0.0212, "final_rank": 9 }, { "submission_id": "aoj_1173_5577616", "code_snippet": "#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n\n#pragma GCC optimize(\"Ofast\")\n\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\nusing namespace std;\n#define lp(i,n) for(int i=0;i<(int)(n);i++)\n#define lps(i,j,n) for(int i=j;i<n;i++)\n\n#define fordebug int hoge;cin>>hoge;\n\n#define DEKAI 1000000007\n#define floot10 cout<<fixed<<setprecision(15)1\n#define all(v) v.begin(),v.end()\ndouble PI = acos(-1);\n\nnamespace {\n#define __DECLARE__(C)\t\t\t\t\t\t\\\n template <typename T>\t\t\t\t\t\t\\\n std::ostream &operator<<(std::ostream &, const C<T> &);\n\n#define __DECLAREM__(C)\t\t\t\t\t\t\\\n template <typename T, typename U>\t\t\t\t\\\n std::ostream &operator<<(std::ostream &, const C<T, U> &);\n\n __DECLARE__(std::vector)\n __DECLARE__(std::deque)\n __DECLARE__(std::set)\n __DECLARE__(std::stack)\n __DECLARE__(std::queue)\n __DECLARE__(std::priority_queue)\n __DECLARE__(std::unordered_set)\n __DECLAREM__(std::map)\n __DECLAREM__(std::unordered_map)\n\n template <typename T, typename U>\n std::ostream &operator<<(std::ostream &, const std::pair<T, U> &);\n template <typename... T>\n std::ostream &operator<<(std::ostream &, const std::tuple<T...> &);\n template <typename T, std::size_t N>\n std::ostream &operator<<(std::ostream &, const std::array<T, N> &);\n\n template <typename Tuple, std::size_t N>\n struct __TuplePrinter__ {\n static void print(std::ostream &os, const Tuple &t) {\n __TuplePrinter__<Tuple, N - 1>::print(os, t);\n os << \", \" << std::get<N - 1>(t);\n }\n };\n\n template <typename Tuple>\n struct __TuplePrinter__<Tuple, 1> {\n static void print(std::ostream &os, const Tuple &t) { os << std::get<0>(t); }\n };\n\n template <typename... T>\n std::ostream &operator<<(std::ostream &os, const std::tuple<T...> &t) {\n os << '(';\n __TuplePrinter__<decltype(t), sizeof...(T)>::print(os, t);\n os << ')';\n return os;\n }\n\n template <typename T, typename U>\n std::ostream &operator<<(std::ostream &os, const std::pair<T, U> &v) {\n return os << '(' << v.first << \", \" << v.second << ')';\n }\n\n#define __INNER__ \\\n os << '['; \\\n for (auto it = begin(c); it != end(c);) { \\\n os << *it; \\\n os << (++it != end(c) ? \", \" : \"\"); \\\n } \\\n return os << ']';\n\n template <typename T, std::size_t N>\n std::ostream &operator<<(std::ostream &os, const std::array<T, N> &c) {\n __INNER__\n }\n\n#define __DEFINE__(C)\t\t\t\t\t\t\\\n template <typename T>\t\t\t\t\t\t\\\n std::ostream &operator<<(std::ostream &os, const C<T> &c) {\t\\\n __INNER__\t\t\t\t\t\t\t\\\n }\n\n#define __DEFINEM__(C)\t\t\t\t\t\t\t\\\n template <typename T, typename U>\t\t\t\t\t\\\n std::ostream &operator<<(std::ostream &os, const C<T, U> &c) {\t\\\n __INNER__\t\t\t\t\t\t\t\t\\\n }\n\n#define __DEFINEW__(C, M1, M2)\t\t\t\t\t\\\n template <typename T>\t\t\t\t\t\t\\\n std::ostream &operator<<(std::ostream &os, const C<T> &c) {\t\\\n std::deque<T> v;\t\t\t\t\t\t\\\n for (auto d = c; !d.empty(); d.pop()) v.M1(d.M2());\t\t\\\n return os << v;\t\t\t\t\t\t\\\n }\n\n __DEFINE__(std::vector)\n __DEFINE__(std::deque)\n __DEFINE__(std::set)\n __DEFINEW__(std::stack, push_front, top)\n __DEFINEW__(std::queue, push_back, front)\n __DEFINEW__(std::priority_queue, push_front, top)\n __DEFINE__(std::unordered_set)\n __DEFINEM__(std::map)\n __DEFINEM__(std::unordered_map)\n}\n\n\ntemplate <signed M, unsigned T>\nstruct mod_int {\n constexpr static signed MODULO = M;\n constexpr static unsigned TABLE_SIZE = T;\n\n signed x;\n\n mod_int() : x(0) {}\n\n mod_int(long long y) : x(static_cast<signed>(y >= 0 ? y % MODULO : MODULO - (-y) % MODULO)) {}\n\n mod_int(int y) : x(y >= 0 ? y % MODULO : MODULO - (-y) % MODULO) {}\n\n mod_int &operator+=(const mod_int &rhs) {\n if ((x += rhs.x) >= MODULO) x -= MODULO;\n return *this;\n }\n\n mod_int &operator-=(const mod_int &rhs) {\n if ((x += MODULO - rhs.x) >= MODULO) x -= MODULO;\n return *this;\n }\n\n mod_int &operator*=(const mod_int &rhs) {\n x = static_cast<signed>(1LL * x * rhs.x % MODULO);\n return *this;\n }\n\n mod_int &operator/=(const mod_int &rhs) {\n x = static_cast<signed>((1LL * x * rhs.inv().x) % MODULO);\n return *this;\n }\n\n mod_int operator-() const { return mod_int(-x); }\n\n mod_int operator+(const mod_int &rhs) const { return mod_int(*this) += rhs; }\n\n mod_int operator-(const mod_int &rhs) const { return mod_int(*this) -= rhs; }\n\n mod_int operator*(const mod_int &rhs) const { return mod_int(*this) *= rhs; }\n\n mod_int operator/(const mod_int &rhs) const { return mod_int(*this) /= rhs; }\n\n bool operator<(const mod_int &rhs) const { return x < rhs.x; }\n\n mod_int inv() const {\n assert(x != 0);\n if (x <= static_cast<signed>(TABLE_SIZE)) {\n if (_inv[1].x == 0) prepare();\n return _inv[x];\n } else {\n signed a = x, b = MODULO, u = 1, v = 0, t;\n while (b) {\n t = a / b;\n a -= t * b;\n std::swap(a, b);\n u -= t * v;\n std::swap(u, v);\n }\n return mod_int(u);\n }\n }\n\n mod_int pow(long long t) const {\n assert(!(x == 0 && t == 0));\n mod_int e = *this, res = mod_int(1);\n for (; t; e *= e, t >>= 1)\n if (t & 1) res *= e;\n return res;\n }\n\n mod_int fact() {\n if (_fact[0].x == 0) prepare();\n return _fact[x];\n }\n\n mod_int inv_fact() {\n if (_fact[0].x == 0) prepare();\n return _inv_fact[x];\n }\n\n mod_int choose(mod_int y) {\n assert(y.x <= x);\n return this->fact() * y.inv_fact() * mod_int(x - y.x).inv_fact();\n }\n\n static mod_int _inv[TABLE_SIZE + 1];\n\n static mod_int _fact[TABLE_SIZE + 1];\n\n static mod_int _inv_fact[TABLE_SIZE + 1];\n\n static void prepare() {\n _inv[1] = 1;\n for (int i = 2; i <= (int)TABLE_SIZE; ++i) {\n _inv[i] = 1LL * _inv[MODULO % i].x * (MODULO - MODULO / i) % MODULO;\n }\n _fact[0] = 1;\n for (unsigned i = 1; i <= TABLE_SIZE; ++i) {\n _fact[i] = _fact[i - 1] * int(i);\n }\n _inv_fact[TABLE_SIZE] = _fact[TABLE_SIZE].inv();\n for (int i = (int)TABLE_SIZE - 1; i >= 0; --i) {\n _inv_fact[i] = _inv_fact[i + 1] * (i + 1);\n }\n }\n};\n\ntemplate <int M, unsigned F>\nstd::ostream &operator<<(std::ostream &os, const mod_int<M, F> &rhs) {\n return os << rhs.x;\n}\n\ntemplate <int M, unsigned F>\nstd::istream &operator>>(std::istream &is, mod_int<M, F> &rhs) {\n long long s;\n is >> s;\n rhs = mod_int<M, F>(s);\n return is;\n}\n\ntemplate <int M, unsigned F>\nmod_int<M, F> mod_int<M, F>::_inv[TABLE_SIZE + 1];\n\ntemplate <int M, unsigned F>\nmod_int<M, F> mod_int<M, F>::_fact[TABLE_SIZE + 1];\n\ntemplate <int M, unsigned F>\nmod_int<M, F> mod_int<M, F>::_inv_fact[TABLE_SIZE + 1];\n\ntemplate <int M, unsigned F>\nbool operator==(const mod_int<M, F> &lhs, const mod_int<M, F> &rhs) {\n return lhs.x == rhs.x;\n}\n\ntemplate <int M, unsigned F>\nbool operator!=(const mod_int<M, F> &lhs, const mod_int<M, F> &rhs) {\n return !(lhs == rhs);\n}\n\nconst int MF = 1000010;\nconst int MOD = 1000000007;\n\nusing mint = mod_int<MOD, MF>;\n\nmint binom(int n, int r) { return (r < 0 || r > n || n < 0) ? 0 : mint(n).choose(r); }\n\nmint fact(int n) { return mint(n).fact(); }\n\nmint inv_fact(int n) { return mint(n).inv_fact(); }\n\n#define int long long\n#define INF 100000000000000000\n\nstruct sg {\n int n;\n vector<int> table;\n vector<int> node;\n vector<bool> need;\n sg(vector<int> v){\n table.resize(1000010, 0);\n int cnt = 1;\n for(int i=1;i<1000010;i++){\n for(int j =i;j<1000010;j+=i)table[j]++;\n }\n int sz = v.size();\n n=1;\n while(n<sz)n*=2;\n node.resize(n*2-1,0);\n need.resize(n*2-1,false);\n\n for(int i=0;i<sz;i++)node[i+n-1]=v[i];\n for(int i=n-2;i>=0;i--)node[i]=node[2*i+1]+node[2*i+2];\n }\n\n int get(int a, int b, int k=0, int l=0, int r=-1) {\n if(r < 0) r = n;\n if(r <= a || b <= l) return 0;\n if(a <= l && r <= b) return node[k];\n int vl = get(a, b, 2*k+1, l, (l+r)/2);\n int vr = get(a, b, 2*k+2, (l+r)/2, r);\n return vl+vr;\n }\n int calc(int a){\n return table[a];\n }\n bool q(int a, int b, int k=0, int l=0, int r=-1) {\n if(need[k])return need[k];\n if(r < 0) r = n;\n if(r <= a || b <= l) return need[k];\n if(k>=n-1){\n node[k]=calc(node[k]);\n int val = node[k];\n int x = k;\n while(x>0){\n\tx=(x-1)/2;\n\tnode[x]=node[2*x+1]+node[2*x+2];\n }\n if(val<=2)need[k]=true;\n return need[k];\n }\n bool vl = q(a, b, 2*k+1, l, (l+r)/2);\n bool vr = q(a, b, 2*k+2, (l+r)/2, r);\n if(vl&&vr)need[k]=true;\n return need[k];\n }\n\n void out(){\n cout<<node<<endl;\n cout<<need<<endl;\n }\n};\n\nsigned main(){\n while(1){\n string s;\n getline(cin, s);\n if(s==\".\")break;\n vector<int> v;\n lp(i,s.size()){\n if(s[i]=='(')v.push_back(1);\n if(s[i]==')')v.push_back(-1);\n if(s[i]=='[')v.push_back(2);\n if(s[i]==']')v.push_back(-2);\n }\n \n while(1){\n //cout<<v<<endl;\n vector<int> res;\n lp(i,v.size()){\n\tif(i!=v.size()-1&&v[i]+v[i+1]==0&&v[i]>0){\n\t i++;\n\t continue;\n\t}\n\tres.push_back(v[i]);\n }\n if(v==res)break;\n v=res;\n }\n if(v.empty())cout<<\"yes\"<<endl;\n else cout<<\"no\"<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 15108, "score_of_the_acc": -1, "final_rank": 12 }, { "submission_id": "aoj_1173_5025767", "code_snippet": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <stack>\n\nusing namespace std;\n\nint main()\n{\n\tstring s;\n\n\twhile (getline(cin, s)) {\n\n\t\tif (s == \".\") break;\n\n\t\tstack<char> j;\n\t\tbool f = true;\n\n\t\tfor (auto c : s) {\n\t\t\tif (c == '(') { f = false; j.push('('); }\n\t\t\tif (c == '[') { f = false; j.push('['); }\n\n\t\t\tif (c == ')' && j.size() == 0) {\n\t\t\t\tf = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse if (c == ')' && j.top() != '(') {\n\t\t\t\tf = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse if (c == ')') { f = true; j.pop(); }\n\n\t\t\tif (c == ']' && j.size() == 0) {\n\t\t\t\tf = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse if (c == ']' && j.top() != '[') {\n\t\t\t\tf = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse if (c == ']') { f = true; j.pop(); }\n\t\t}\n\n\t\tif (f&&!j.size()) cout << \"yes\" << endl;\n\t\telse cout << \"no\" << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3216, "score_of_the_acc": -0.0165, "final_rank": 8 }, { "submission_id": "aoj_1173_5005210", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(n);i++)\n#define ALL(v) v.begin(),v.end()\n\nint dp[105][105];\n\nbool ok(string &s,int l,int na){\n if(~dp[l][na])return dp[l][na];\n if(na&1)return false;\n if(na==0)return true;\n for(int i=2;i<na;i+=2)if(ok(s,l,i)&&ok(s,l+i,na-i))return dp[l][na]=true;\n if(s[l]=='('&&s[l+na-1]==')'&&ok(s,l+1,na-2))return dp[l][na]=true;\n if(s[l]=='['&&s[l+na-1]==']'&&ok(s,l+1,na-2))return dp[l][na]=true;\n return dp[l][na]=false;\n}\n\nsigned main(){\n string s;\n while(getline(cin,s),s!=\".\"){\n memset(dp,-1,sizeof(dp));\n string u;\n for(char p:s)if(p=='('||p==')'||p=='['||p==']')u+=p;\n if(ok(u,0,u.size()))cout<<\"yes\"<<endl;\n else cout<<\"no\"<<endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3184, "score_of_the_acc": -1.0139, "final_rank": 13 }, { "submission_id": "aoj_1173_4976037", "code_snippet": "#include<iostream>\n#include<stack>\n#include<string>\nusing namespace std;\nint main(){\n while(1){\n string s;\n getline(cin,s);\n if(s==\".\"){\n break;\n }\n bool flg=true;\n\n int n=(int)s.size();\n stack<char> st;\n for(int i=0;i<n;i++){\n if(s[i]=='['){\n st.push(s[i]);\n continue;\n }\n if(s[i]=='('){\n st.push(s[i]);\n continue;\n }\n if(s[i]==']'){\n if(st.empty()){\n flg=false;\n break;\n }\n if(st.top()=='['){\n st.pop();\n continue;\n }\n flg=false;\n break;\n }\n if(s[i]==')'){\n if(st.empty()){\n flg=false;\n break;\n }\n if(st.top()=='('){\n st.pop();\n continue;\n }\n flg=false;\n break;\n }\n }\n if(!st.empty()){\n flg=false;\n }\n\n cout<<(flg?\"yes\":\"no\")<<'\\n';\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3156, "score_of_the_acc": -0.0116, "final_rank": 3 }, { "submission_id": "aoj_1173_4971156", "code_snippet": "#include <iostream>\n#include<string>\n#include<cmath>\n#include<algorithm>\n#include<cctype>\n#include<queue>\n#include<deque>\n#include<regex>\n#include<stack>\n#include<stdio.h>\n#include<vector>\n#include<set>\n#include<map>\n#include<iomanip>\n#define rep(i,a,n) for(int i=a;i<n;i++)\n#define per(i,a,n) for(int i=a;i>=n;i--)\n\ntypedef int long long ll;\nusing namespace std;\ntypedef pair<int,int> P;\nint dx[4]={1,0,-1,0};\nint dy[4]={0,1,0,-1};\nconst ll MOD=1e9+7;\nstatic const int MAX = 100;\nstatic const int INF = (1<<23);\ntemplate<class T> T gcd(T a, T b){return b? gcd(b,a%b) : a;}\ntemplate<class T> T lcm(T a,T b){return a / gcd(a,b)*b;}\ntemplate<class T> inline bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\nchar kako[4]={'(',')','[',']'};\nint main(){\n string s;\n while(true){\n\n getline(cin,s);\n\n if(s.size()==1&&s[0]=='.'){\n break;\n }\n vector<int> v;\n\n// rep(i,0,s.size()){\n// rep(p,0,4){\n// if(kako[p]==s[i]){\n// v.push_back(p);\n// }\n// }\n// }\n// while(true){\n// cin>>s;\n\n rep(i,0,s.size()){\n rep(p,0,4){\n if(kako[p]==s[i]){\n v.push_back(p);\n }\n }\n }\n // if(s[s.size()-1]=='.')break;\n // }\n\n\n stack<int> s;\n\n\n\n rep(i,0,v.size()){\n if(s.empty()){\n s.push(v[i]);\n }else{\n int tp=s.top();\n if(tp==0&&v[i]==1){\n s.pop();\n }else if(tp==2&&v[i]==3){\n s.pop();\n }else{\n s.push(v[i]);\n }\n }\n\n }\n if(s.size()==0){\n cout<<\"yes\"<<endl;\n }else{\n cout<<\"no\"<<endl;\n }\n\n\n }\n\n\n \nreturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3016, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_1170_cpp
Problem F: Old Memories In 4272 A.D., Master of Programming Literature, Dr. Isaac Cornell Panther-Carol, who has miraculously survived through the three World Computer Virus Wars and reached 90 years old this year, won a Nobel Prize for Literature. Media reported every detail of his life. However, there was one thing they could not report — that is, an essay written by him when he was an elementary school boy. Although he had a copy and was happy to let them see it, the biggest problem was that his copy of the essay was infected by a computer virus several times during the World Computer Virus War III and therefore the computer virus could have altered the text. Further investigation showed that his copy was altered indeed. Why could we know that? More than 80 years ago his classmates transferred the original essay to their brain before infection. With the advent of Solid State Brain, one can now retain a text perfectly over centuries once it is transferred to his or her brain. No one could remember the entire text due to the limited capacity, but we managed to retrieve a part of the text from the brain of one of his classmates; sadly, it did not match perfectly to the copy at hand. It would not have happened without virus infection. At the moment, what we know about the computer virus is that each time the virus infects an essay it does one of the following: the virus inserts one random character to a random position in the text. (e.g., "ABCD" → "ABCZD") the virus picks up one character in the text randomly, and then changes it into another character. (e.g., "ABCD" → "ABXD") the virus picks up one character in the text randomly, and then removes it from the text. (e.g., "ABCD" → "ACD") You also know the maximum number of times the computer virus infected the copy, because you could deduce it from the amount of the intrusion log. Fortunately, most of his classmates seemed to remember at least one part of the essay (we call it a piece hereafter). Considering all evidences together, the original essay might be reconstructed. You, as a journalist and computer scientist, would like to reconstruct the original essay by writing a computer program to calculate the possible original text(s) that fits to the given pieces and the altered copy at hand. Input The input consists of multiple datasets. The number of datasets is no more than 100. Each dataset is formatted as follows: d n the altered text piece 1 piece 2 ... piece n The first line of a dataset contains two positive integers d ( d ≤ 2) and n ( n ≤ 30), where d is the maximum number of times the virus infected the copy and n is the number of pieces . The second line is the text of the altered copy at hand. We call it the altered text hereafter. The length of the altered text is less than or equal to 40 characters. The following n lines are pieces , each of which is a part of the original essay remembered by one of his classmates. Each piece has at least 13 characters but no more than 20 characters ...(truncated)
[ { "submission_id": "aoj_1170_8289540", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint D, N;\nlong long val1[49], pow1[49];\nlong long val2[49], pow2[49];\nstring S;\nstring T[39];\nstring U = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ.\";\nstring Cand[1500009];\n\nbool check(string str) {\n\tval1[0] = 0;\n\tval2[0] = 0;\n\tfor (int i = 0; i < str.size(); i++) {\n\t\tlong long chr = str[i];\n\t\tval1[i + 1] = (217LL * val1[i] + chr);\n\t}\n\n\t// Brute Force\n\tvector<int> used(str.size() + 1, 0);\n\tfor (int i = 0; i < N; i++) {\n\t\tlong long hash_val1 = 0;\n\t\tfor (int j = 0; j < T[i].size(); j++) {\n\t\t\tlong long chr = T[i][j];\n\t\t\thash_val1 = (217LL * hash_val1 + chr);\n\t\t}\n\t\tfor (int j = 0; j < (int)str.size() - (int)T[i].size() + 1; j++) {\n\t\t\tlong long ret1 = (val1[j + T[i].size()] - pow1[T[i].size()] * val1[j]);\n\t\t\tif (ret1 != hash_val1) continue;\n\t\t\tused[j] += 1;\n\t\t\tused[j + T[i].size()] -= 1;\n\t\t}\n\t}\n\n\t// Final\n\tfor (int i = 1; i <= str.size(); i++) used[i] += used[i - 1];\n\tfor (int i = 0; i < str.size(); i++) {\n\t\tif (used[i] == 0) return false;\n\t}\n\treturn true;\n}\n\n// ================================================================================= Helper Function =================================================================================\n// 0: Insert\n// 1: Change\n// 2: Delete\nint Match(string s1, string s2, vector<int> vec) {\n\ts1 += \"$$\"; s2 += \"$$\";\n\tint cur = 0, op = 0, Last1 = 0, Last2 = 0;\n\twhile (cur < max(s1.size(), s2.size()) - 2 && cur < min(s1.size(), s2.size()) - 1) {\n\t\tif (s1[cur] == s2[cur]) { cur += 1; continue; }\n\t\tif (op == vec.size()) return -1;\n\t\tLast1 = cur;\n\t\tstring new_s1 = \"\";\n\t\tif (vec[op] == 0) { new_s1 += s1.substr(0, cur); new_s1 += s2[cur]; new_s1 += s1.substr(cur + 0, s1.size() - (cur + 0)); Last2 = (int)s2[cur]; cur += 1; }\n\t\tif (vec[op] == 1) { new_s1 += s1.substr(0, cur); new_s1 += s2[cur]; new_s1 += s1.substr(cur + 1, s1.size() - (cur + 1)); Last2 = (int)s2[cur]; cur += 1; }\n\t\tif (vec[op] == 2) { new_s1 += s1.substr(0, cur); new_s1 += s1.substr(cur + 1, s1.size() - (cur + 1)); }\n\t\ts1 = new_s1;\n\t\top += 1;\n\t}\n\tif (cur + 2 != s1.size()) return -1;\n\tif (cur + 2 != s2.size()) return -1;\n\tif (op != vec.size()) return -1;\n\treturn Last1 * 1000 + Last2;\n}\n\nvector<string> initial_calculate2(string A, vector<int> vec) {\n\tint Len = A.size();\n\tfor (int i = 0; i < vec.size(); i++) { if (vec[i] == 0) Len -= 1; }\n\tfor (int i = 0; i < vec.size(); i++) { if (vec[i] == 2) Len += 1; }\n\tvector<string> Return;\n\tfor (int i = 0; i <= (int)S.size() - Len; i++) {\n\t\tstring target = S.substr(i, Len);\n\t\tif (target == A) continue;\n\t\tif (Match(target, A, vec) != -1) {\n\t\t\tstring result = S.substr(0, i) + A + S.substr(i + Len, S.size() - (i + Len));\n\t\t\tReturn.push_back(result);\n\t\t}\n\t}\n\treturn Return;\n}\n\nstring Mutate(string Moto, pair<int, int> Mutate1, pair<int, int> Mutate2) {\n\t// First Try\n\tint u1 = Mutate1.first / 1000;\n\tchar v1 = Mutate1.first % 1000;\n\tif (Mutate1.second == 0) { string new_str = Moto.substr(0, u1); new_str += v1; new_str += Moto.substr(u1 + 0, Moto.size() - (u1 + 0)); Moto = new_str; }\n\tif (Mutate1.second == 1) { string new_str = Moto.substr(0, u1); new_str += v1; new_str += Moto.substr(u1 + 1, Moto.size() - (u1 + 1)); Moto = new_str; }\n\tif (Mutate1.second == 2) { string new_str = Moto.substr(0, u1); new_str += Moto.substr(u1 + 1, Moto.size() - (u1 + 1)); Moto = new_str; }\n\n\t// Second Try\n\tif (Mutate2.first != -1) {\n\t\tint u2 = Mutate2.first / 1000;\n\t\tchar v2 = Mutate2.first % 1000;\n\t\tif (Mutate2.second == 1 && u2 == Moto.size()) return S;\n\t\tif (Mutate2.second == 2 && u2 == Moto.size()) return S;\n\t\tif (Mutate2.second == 0) { string new_str = Moto.substr(0, u2); new_str += v2; new_str += Moto.substr(u2 + 0, Moto.size() - (u2 + 0)); Moto = new_str; }\n\t\tif (Mutate2.second == 1) { string new_str = Moto.substr(0, u2); new_str += v2; new_str += Moto.substr(u2 + 1, Moto.size() - (u2 + 1)); Moto = new_str; }\n\t\tif (Mutate2.second == 2) { string new_str = Moto.substr(0, u2); new_str += Moto.substr(u2 + 1, Moto.size() - (u2 + 1)); Moto = new_str; }\n\t}\n\treturn Moto;\n}\n\n// ================================================================================= Main Part =================================================================================\nint main() {\n\tpow1[0] = 1; for (int i = 1; i <= 48; i++) pow1[i] = (217LL * pow1[i - 1]);\n\n\twhile (true) {\n\t\t// Step 1. Input\n\t\tcin >> D >> N; if (D + N == 0) break;\n\t\tcin >> S;\n\t\tfor (int i = 0; i < N; i++) cin >> T[i];\n\n\t\t// Step 2. Brute Force (2 Mutations)\n\t\tint Count = 0;\n\t\tCand[Count] = S; Count += 1;\n\t\tif (D == 2) {\n\t\t\tfor (int i = 0; i < N; i++) {\n\t\t\t\tfor (int j = 0; j < 9; j++) {\n\t\t\t\t\tvector<string> ret = initial_calculate2(T[i], vector<int>{j / 3, j % 3});\n\t\t\t\t\tfor (string k : ret) {\n\t\t\t\t\t\tCand[Count] = k; Count += 1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\t// Step 3. Brute Force (1 Mutations / Phase 1)\n\t\tvector<pair<int, int>> Place;\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tfor (int j = 0; j < 3; j++) {\n\t\t\t\tint Len = T[i].size(); if (j == 0) Len -= 1; if (j == 2) Len += 1;\n\t\t\t\tfor (int k = 0; k <= (int)S.size() - Len; k++) {\n\t\t\t\t\tstring target = S.substr(k, Len);\n\t\t\t\t\tint ret = Match(target, T[i], vector<int>{j});\n\t\t\t\t\tif (ret == -1) continue;\n\t\t\t\t\tPlace.push_back(make_pair(ret + k * 1000, j));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tsort(Place.begin(), Place.end());\n\t\tPlace.erase(unique(Place.begin(), Place.end()), Place.end());\n\n\t\t// Step 4. Brute Force (1 Mutations / Phase 2)\n\t\tfor (int i = 0; i < Place.size(); i++) {\n\t\t\tif (D == 2) {\n\t\t\t\tfor (int j = 0; j < Place.size(); j++) {\n\t\t\t\t\tif (Place[i].first < Place[j].first) continue;\n\t\t\t\t\tstring nex = Mutate(S, Place[i], Place[j]);\n\t\t\t\t\tCand[Count] = nex; Count += 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\tstring nex = Mutate(S, Place[i], make_pair(-1, -1));\n\t\t\tCand[Count] = nex; Count += 1;\n\t\t}\n\n\t\t// Step 5. Check\n\t\tsort(Cand, Cand + Count);\n\t\tvector<string> Answer;\n\t\tfor (int i = 0; i < Count; i++) {\n\t\t\tif (i >= 1 && Cand[i] == Cand[i - 1]) continue;\n\t\t\tstring str = Cand[i];\n\t\t\tif (check(str) == true) Answer.push_back(str);\n\t\t}\n\n\t\t// Step 6. Output\n\t\tcout << Answer.size() << endl;\n\t\tif (Answer.size() <= 5) {\n\t\t\tfor (string str : Answer) cout << str << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3830, "memory_kb": 129860, "score_of_the_acc": -1.4057, "final_rank": 20 }, { "submission_id": "aoj_1170_4281376", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 45\n\nstruct Edge{\n\tEdge(){\n\n\t\tto = 0;\n\t\tloc = 0;\n\t}\n\tEdge(int arg_to,int arg_loc){\n\t\tto = arg_to;\n\t\tloc = arg_loc;\n\t}\n\tint to,loc;\n};\n\nint DIST,N,len_T,len_P;\nint num_ans;\nint dp[SIZE][SIZE];\nstring T;\nvector<string> P,ANS;\nmap<string,bool> MAP;\nvector<Edge> G[SIZE];\n\n\nbool is_OK(string line,int head,int tail){\n\n\tint cost;\n\tint minimum;\n\n\tfor(int row = head; row <= tail; row++){\n\n\t\tminimum = BIG_NUM;\n\n\t\tfor(int col = max(1,row-DIST); col <= min(len_T,row+DIST); col++){\n\t\t\tif(T[col-1] == line[row-1]){\n\t\t\t\tcost = 0;\n\t\t\t}else{\n\t\t\t\tcost = 1;\n\t\t\t}\n\t\t\tdp[row][col] = min(dp[row-1][col-1]+cost,min(dp[row-1][col]+1,dp[row][col-1]+1));\n\t\t\tminimum = min(minimum,dp[row][col]);\n\t\t}\n\t\tif(minimum > DIST){\n\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid recursive(string line,int index){\n\n\tauto at = MAP.find(line);\n\tif(at != MAP.end())return;\n\n\tMAP[line] = true;\n\n\tif(dp[line.length()][len_T] <= DIST){\n\n\t\tnum_ans++;\n\t\tif(num_ans <= 5){\n\n\t\t\tANS.push_back(line);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < G[index].size(); i++){\n\t\tint next = G[index][i].to;\n\t\tint loc = G[index][i].loc;\n\n\t\tif(line.length()+(len_P-loc) > len_T+DIST){\n\n\t\t\tbreak;\n\t\t}\n\t\tstring next_line = line+P[next].substr(loc);\n\n\t\tif(is_OK(next_line,line.length()+1,next_line.length())){\n\n\t\t\trecursive(next_line,next);\n\t\t}\n\t}\n}\n\nvoid func(){\n\n\tMAP.clear();\n\tP.clear();\n\tANS.clear();\n\tfor(int i = 0; i < N; i++){\n\n\t\tG[i].clear();\n\t}\n\n\tcin >> T;\n\tlen_T = T.length();\n\n\tfor(int loop = 0; loop < N; loop++){\n\n\t\tstring tmp_str;\n\t\tcin >> tmp_str;\n\t\tP.push_back(tmp_str);\n\t}\n\tlen_P = P[0].length();\n\n\tsort(P.begin(),P.end());\n\tP.erase(unique(P.begin(),P.end()),P.end());\n\n\tbool FLG;\n\n\tfor(int i = 0; i < P.size(); i++){\n\t\tstring from = P[i];\n\t\tfor(int len = len_P-1; len >= 0; len--){ //一致長\n\t\t\tfor(int k = 0; k < P.size(); k++){\n\t\t\t\tstring to = P[k];\n\n\t\t\t\tFLG = true;\n\t\t\t\tfor(int k = 0; k < len; k++){\n\t\t\t\t\tif(from[len_P-len+k] != to[k]){\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(FLG){\n\n\t\t\t\t\tG[i].push_back(Edge(k,len));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int row = 0; row <= len_T+DIST; row++){\n\t\tfor(int col = 0; col <= len_T; col++){\n\n\t\t\tdp[row][col] = BIG_NUM;\n\t\t}\n\t}\n\n\tfor(int row = 1; row <= len_T+DIST; row++){\n\t\tdp[row][0] = row;\n\t}\n\n\tfor(int col = 0; col <= len_T; col++){\n\t\tdp[0][col] = col;\n\t}\n\n\tnum_ans = 0;\n\n\tfor(int i = 0; i < P.size(); i++){\n\n\t\tif(is_OK(P[i],1,len_P)){\n\n\t\t\trecursive(P[i],i);\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",num_ans);\n\n\tif(num_ans <= 5){\n\n\t\tsort(ANS.begin(),ANS.end());\n\n\t\tfor(int i = 0; i < ANS.size(); i++){\n\n\t\t\tprintf(\"%s\\n\",ANS[i].c_str());\n\t\t}\n\t}\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d %d\",&DIST,&N);\n\t\tif(DIST == 0 && N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1660, "memory_kb": 22340, "score_of_the_acc": -0.2285, "final_rank": 2 }, { "submission_id": "aoj_1170_2486237", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nstruct Edge {int from, to, weight;};\nusing Graph = vector<vector<Edge>>;\n\nint D, N;\nstring TEXT;\nvector<string> PIECE;\n\nset<string> OK;\n\nstring text;\n\nint DP[43][43];\n\nbool Levenshtein(auto p) {\n for(auto i = p; i <= text.size(); ++i) {\n auto d = D + 1;\n for(auto j = 1; j <= TEXT.size(); ++j) {\n if(text[i-1] == TEXT[j-1]) DP[i][j] = DP[i-1][j-1];\n else DP[i][j] = 1 + min({DP[i-1][j], DP[i][j-1], DP[i-1][j-1]});\n d = min(d, DP[i][j]);\n }\n if(D < d) return false;\n }\n return true;\n}\n\nvoid dfs(const auto& G, auto& used, auto cur) {\n if(TEXT.size() + D < text.size()) return;\n\n if(!Levenshtein(text.size() - PIECE[cur].size() + 1)) return;\n\n if(used.count(text)) return;\n used.emplace(text);\n\n if(DP[text.size()][TEXT.size()] <= D) OK.emplace(text);\n\n auto dup = text;\n for(auto e: G[cur]) {\n text = dup + PIECE[e.to].substr(e.weight);\n dfs(G, used, e.to);\n }\n text = dup;\n}\n\nvoid solve() {\n Graph G(N);\n for(auto i = 0; i < N; ++i) for(auto j = 0; j < N; ++j) {\n auto lhs = PIECE[i];\n auto rhs = PIECE[j];\n for(auto k = 0; k < lhs.size(); ++k) if(lhs.substr(lhs.size() - k) == rhs.substr(0, k)) G[i].push_back({i, j, k});\n }\n \n unordered_set<string> used;\n for(auto i = 0; i < N; ++i) {\n text = PIECE[i];\n dfs(G, used, i);\n }\n}\n\nint main() {\n for(auto i = 0; i < 43; ++i) DP[i][0] = DP[0][i] = i;\n\n while(cin >> D >> N, D | N) {\n cin >> TEXT;\n PIECE = vector<string>(N);\n for(auto& i: PIECE) cin >> i;\n \n sort(begin(PIECE), end(PIECE));\n PIECE.erase(unique(begin(PIECE), end(PIECE)), end(PIECE));\n N = PIECE.size();\n \n OK.clear();\n solve();\n cout << OK.size() << endl;\n if(OK.size() <= 5) for(auto i: OK) cout << i << endl;\n }\n}", "accuracy": 1, "time_ms": 7390, "memory_kb": 26128, "score_of_the_acc": -1.1227, "final_rank": 17 }, { "submission_id": "aoj_1170_2486235", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nstruct Edge {int from, to, weight;};\nusing Graph = vector<vector<Edge>>;\n\nint D, N;\nstring TEXT;\nvector<string> PIECE;\n\nset<string> OK;\n\nstring text;\n\nint DP[45][45];\n\nbool Levenshtein(auto p) {\n for(auto i = p; i <= text.size(); ++i) {\n auto d = D + 1;\n for(auto j = 1; j <= TEXT.size(); ++j) {\n if(text[i-1] == TEXT[j-1]) DP[i][j] = DP[i-1][j-1];\n else DP[i][j] = 1 + min({DP[i-1][j], DP[i][j-1], DP[i-1][j-1]});\n d = min(d, DP[i][j]);\n }\n if(D < d) return false;\n }\n return true;\n}\n\nvoid dfs(const auto& G, auto& used, auto cur) {\n if(TEXT.size() + D < text.size()) return;\n\n if(!Levenshtein(text.size() - PIECE[cur].size() + 1)) return;\n\n if(used.count(text)) return;\n used.emplace(text);\n\n if(DP[text.size()][TEXT.size()] <= D) OK.emplace(text);\n\n auto dup = text;\n for(auto e: G[cur]) {\n text = dup + PIECE[e.to].substr(e.weight);\n dfs(G, used, e.to);\n }\n text = dup;\n}\n\nvoid solve() {\n Graph G(N);\n for(auto i = 0; i < N; ++i) for(auto j = 0; j < N; ++j) {\n auto lhs = PIECE[i];\n auto rhs = PIECE[j];\n for(auto k = 0; k < lhs.size(); ++k) if(lhs.substr(lhs.size() - k) == rhs.substr(0, k)) G[i].push_back({i, j, k});\n }\n \n unordered_set<string> used;\n for(auto i = 0; i < N; ++i) {\n text = PIECE[i];\n dfs(G, used, i);\n }\n}\n\nint main() {\n for(auto i = 0; i < 45; ++i) DP[i][0] = DP[0][i] = i;\n\n while(cin >> D >> N, D | N) {\n cin >> TEXT;\n PIECE = vector<string>(N);\n for(auto& i: PIECE) cin >> i;\n \n sort(begin(PIECE), end(PIECE));\n PIECE.erase(unique(begin(PIECE), end(PIECE)), end(PIECE));\n N = PIECE.size();\n \n OK.clear();\n solve();\n cout << OK.size() << endl;\n if(OK.size() <= 5) for(auto i: OK) cout << i << endl;\n }\n}", "accuracy": 1, "time_ms": 7770, "memory_kb": 26260, "score_of_the_acc": -1.1811, "final_rank": 19 }, { "submission_id": "aoj_1170_2486072", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nstruct Edge {int from, to, weight;};\nusing Graph = vector<vector<Edge>>;\n\nint D, N;\nstring TEXT;\nvector<string> PIECE;\n\nset<string> OK;\n\nstring text;\n\nint DP[45][45];\n\nbool Levenshtein(auto b, auto e) {\n for(auto j = b; j <= e; ++j) {\n int d = D + 1;\n for(auto i = 1; i <= TEXT.size(); ++i) {\n if(TEXT[i-1] == text[j-1]) DP[i][j] = DP[i-1][j-1];\n else DP[i][j] = 1 + min({DP[i-1][j], DP[i][j-1], DP[i-1][j-1]});\n d = min(d, DP[i][j]);\n }\n if(D < d) return false;\n }\n return true;\n}\n\nvoid dfs(const auto& G, auto& used, auto cur) {\n if(TEXT.size() + D < text.size()) return;\n\n if(!Levenshtein(text.size() - PIECE[cur].size() + 1, text.size())) return;\n\n if(used.count(text)) return;\n used.emplace(text);\n\n if(DP[TEXT.size()][text.size()] <= D) OK.emplace(text);\n\n auto dup = text;\n for(auto e: G[cur]) {\n text = dup + PIECE[e.to].substr(e.weight);\n dfs(G, used, e.to);\n text = dup;\n }\n}\n\nvoid solve() {\n Graph G(N);\n for(auto i = 0; i < N; ++i) for(auto j = 0; j < N; ++j) {\n auto lhs = PIECE[i];\n auto rhs = PIECE[j];\n for(auto k = 0; k < lhs.size(); ++k) if(lhs.substr(lhs.size() - k) == rhs.substr(0, k)) G[i].push_back({i, j, k});\n }\n \n unordered_set<string> used;\n for(auto i = 0; i < N; ++i) {\n text = PIECE[i];\n dfs(G, used, i);\n }\n}\n\nint main() {\n for(auto i = 0; i < 45; ++i) DP[i][0] = DP[0][i] = i;\n\n while(cin >> D >> N, D | N) {\n cin >> TEXT;\n PIECE = vector<string>(N);\n for(auto& i: PIECE) cin >> i;\n \n sort(begin(PIECE), end(PIECE));\n PIECE.erase(unique(begin(PIECE), end(PIECE)), end(PIECE));\n N = PIECE.size();\n \n OK.clear();\n solve();\n cout << OK.size() << endl;\n if(OK.size() <= 5) for(auto i: OK) cout << i << endl;\n }\n}", "accuracy": 1, "time_ms": 7760, "memory_kb": 26228, "score_of_the_acc": -1.1793, "final_rank": 18 }, { "submission_id": "aoj_1170_2197010", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint D, N;\nstring S;\nvector< string > p, pat;\nset< string > used;\nvector< int > graph[45][45];\nint dp[45][45];\nstring now;\n \nbool Levenshtein_Distance(int B, int E) {\n for(int i = B + 1; i <= E; i++) {\n int Dist = 1 << 30;\n for(int j = max(1, i - D); j <= min< int >(S.size(), i + D); j++) {\n dp[i][j] = min(min(dp[i - 1][j], dp[i][j - 1]) + 1, dp[i - 1][j - 1] + (now[i - 1] != S[j - 1]));\n Dist = min(Dist, dp[i][j]);\n }\n if(Dist > D) return(false);\n }\n return(true);\n}\n \nvoid rec(int idx)\n{\n if(used.count(now)) return;\n used.insert(now);\n if(dp[now.size()][S.size()] <= D) {\n if(pat.size() > 5) pat.push_back(\"~\");\n else pat.push_back(now);\n } \n int nowSize = now.size();\n for(int i = p[0].size() - 1; i >= 0 && nowSize + p[0].size() - i <= S.size() + D; i--) {\n now += \" \";\n for(int j = 0; j < graph[idx][i].size(); j++) {\n bool connect = true;\n for(int k = i; k < p[0].size(); k++) {\n now[nowSize + k - i] = p[graph[idx][i][j]][k];\n if(!Levenshtein_Distance(nowSize + k - i, nowSize + k - i + 1)) {\n connect = false;\n break;\n }\n }\n if(connect) rec(graph[idx][i][j]);\n }\n }\n now.resize(nowSize);\n}\n \nint main(){\n \n while(cin >> D >> N, D||N) {\n p.clear();\n used.clear();\n pat.clear();\n \n cin >> S;\n for(int i = 0; i < N; i++) {\n string pi;\n cin >> pi;\n p.push_back(pi);\n }\n sort(p.begin(), p.end());\n p.erase(unique(p.begin(), p.end()), p.end());\n for(int i = 0; i < 45; i++) {\n dp[i][0] = dp[0][i] = i;\n }\n for(int i = 1; i < 45; i++) {\n for(int j = 1; j < 45; j++) {\n if(abs(i - j) > D) dp[i][j] = 1 << 30;\n }\n }\n N = p.size();\n \n for(int i = 0; i < N; i++) {\n for(int j = 0; j < p[i].size(); j++) {\n graph[i][j].clear();\n for(int k = 0; k < N; k++) {\n if(p[i].substr(p[i].size() - j) == p[k].substr(0, j)) {\n graph[i][j].push_back(k);\n }\n }\n }\n }\n \n for(int i = 0; i < p.size(); i++) {\n now = p[i];\n if(!Levenshtein_Distance(0, p[0].size())) continue;\n rec(i);\n }\n cout << pat.size() << endl;\n if(pat.size() <= 5) {\n sort(pat.begin(), pat.end());\n for(vector< string >::iterator it = pat.begin(); it != pat.end(); it++) {\n cout << *it << endl;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 1140, "memory_kb": 22724, "score_of_the_acc": -0.1531, "final_rank": 1 }, { "submission_id": "aoj_1170_1629092", "code_snippet": "#include<stdio.h>\n#include<algorithm>\n#include<queue>\n#include<string>\n#include<set>\n#include<vector>\n#include<string.h>\nusing namespace std;\nchar str[50];\nchar word[35][30];\nvector<string>ans;\nstruct wolf{\n\tint flag;\n\tint par;\n\tint chi[27];\n\tint dep;\n\tint val;\n\tint fail;\n\twolf(){\n\t\tflag=dep=0;\n\t\tval=-1;\n\t\tpar=-1;\n\t\tfail=0;\n\t\tfor(int i=0;i<27;i++)chi[i]=-1;\n\t}\n};\nint LIM=5;\nwolf pool[1100];\ntypedef unsigned long long nt;\nnt key=1000000007;\nset<nt>hash;\nint len;\nint sz;\nint ret;\ninline int chk(string t,int lc){\n\tint at=0;\n\tint last=0;\n\tfor(int i=0;i<t.size();i++){\n\t\twhile(1){\n\t\t\tif(pool[at].chi[t[i]-'@']!=-1){\n\t\t\t\tat=pool[at].chi[t[i]-'@'];\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif(at==0){\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tat=pool[at].fail;\n\t\t}\n\t\tif(pool[at].flag)last=i+1;\n\t\tif(pool[at].dep<=i-last)return 0;\n\t}\n\t\n\tif(lc==0||last==t.size()){\n\t//\tprintf(\"%s\\n\",t.c_str());\n\t\treturn 1;\n\t}\n\treturn 0;\n}\nvoid dfs(int a,int b,string now,nt val,nt ks){\n\tif(chk(now,0)==0)return;\n\tif(a==len){\n\t\tif(hash.count(val)==0){\n\t\t\thash.insert(val);\n\t\t\tif(chk(now,1)){\n\t\t\t\tret++;\n\t\t\t\tif(ans.size()<LIM){\n\t\t\t\t\tans.push_back(now);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif(a<len){\n\t\tnow.push_back(str[a]);\n\t\tdfs(a+1,b,now,val+ks*(str[a]-'@'+1),ks*key);\n\t\tnow.erase(now.size()-1);\n\t\tif(b){\n\t\t\tdfs(a+1,b-1,now,val,ks);\n\t\t\tfor(int i=0;i<27;i++){\n\t\t\t\tnow.push_back('@'+i);\n\t\t\t\tdfs(a+1,b-1,now,val+ks*(i+1),ks*key);\n\t\t\t\tnow.erase(now.size()-1);\n\t\t\t}\n\t\t}\n\t}\n\tif(b){\n\t\tfor(int i=0;i<27;i++){\n\t\t\tnow.push_back('@'+i);\n\t\t\tdfs(a,b-1,now,val+ks*(i+1),ks*key);\n\t\t\tnow.erase(now.size()-1);\n\t\t}\n\t}\n}\n/*void dfs(int a,string b){\n\t//printf(\"%d %s\\n\",a,b.c_str());\n\t\n\tnt t=0;\n\tfor(int i=0;i<b.size();i++){\n\t\tt*=key;\n\t\tt+=b[i]-'@'+1;\n\t}\n\tif(!hash.count(t)){\n\t\thash.insert(t);\n\t\tif(chk(b)){\n\t\t\tret++;\n\t\t\tif(ans.size()<LIM){\n\t\t\t\tans.push_back(b);\n\t\t\t}\n\t\t}\n\t}\n\tif(a==0)return;\n\t\n\tfor(int i=0;i<27;i++){\n\t\tfor(int j=0;j<=b.size();j++){\n\t\t\tstring c=b;\n\t\t\tc.insert(c.begin()+j,'@'+i);\n\t\t\tdfs(a-1,c);\n\t\t}\n\t\tfor(int j=0;j<b.size();j++){\n\t\t\tchar p=b[j];\n\t\t\tb[j]='@'+i;\n\t\t\tdfs(a-1,b);\n\t\t\tb[j]=p;\n\t\t}\n\t}\n\tfor(int i=0;i<b.size();i++){\n\t\tstring c=b;\n\t\tc.erase(c.begin()+i);\n\t\tdfs(a-1,c);\n\t}\n}*/\nint main(){\n\tint a,b;\n\twhile(scanf(\"%d%d\",&a,&b),b){\n\t\tscanf(\"%s\",str);\n\t\tfor(int i=0;str[i];i++)if(str[i]=='.')str[i]='@';\n\t\tfor(int i=0;i<b;i++){\n\t\t\tscanf(\"%s\",word+i);\n\t\t\tfor(int j=0;word[i][j];j++)if(word[i][j]=='.')word[i][j]='@';\n\t\t}\n\t\tans.clear();\n\t\tlen=strlen(str);\n\t\tret=0;\n\t\tsz=1;\n\t\tpool[0]=wolf();\n\t\thash.clear();\n\t\tfor(int i=0;i<b;i++){\n\t\t\tint at=0;\n\t\t\tfor(int j=0;word[i][j];j++){\n\t\t\t\tif(pool[at].chi[word[i][j]-'@']==-1){\n\t\t\t\t\tpool[sz]=wolf();\n\t\t\t\t\tpool[sz].val=word[i][j]-'@';\n\t\t\t\t\tpool[sz].par=at;\n\t\t\t\t\tpool[at].chi[word[i][j]-'@']=sz;\n\t\t\t\t\tpool[sz].dep=j+1;\n\t\t\t\t\tat=sz;\n\t\t\t\t\tsz++;\n\t\t\t\t}else{\n\t\t\t\t\tat=pool[at].chi[word[i][j]-'@'];\n\t\t\t\t}\n\t\t\t}\n\t\t\tpool[at].flag=1;\n\t\t}\n\t\t\n\t\tqueue<int>Q;\n\t\tQ.push(0);\n\t\twhile(Q.size()){\n\t\t\tint now=Q.front();Q.pop();\n\t\t\tfor(int i=0;i<27;i++){\n\t\t\t\tif(~pool[now].chi[i])Q.push(pool[now].chi[i]);\n\t\t\t}\n\t\t\tif(now==0||pool[now].par==0){\n\t\t\t\tpool[now].fail=0;continue;\n\t\t\t}\n\t\t\tint at=pool[now].par;\n\t\t\twhile(1){\n\t\t\t\tif(at==0){\n\t\t\t\t\tpool[now].fail=0;break;\n\t\t\t\t}\n\t\t\t\tat=pool[at].fail;\n\t\t\t\tif(pool[at].chi[pool[now].val]!=-1){\n\t\t\t\t\tpool[now].fail=pool[at].chi[pool[now].val];\n\t\t\t\t\tif(pool[pool[now].fail].flag)pool[now].flag=1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tstring T=str;\n\t\tdfs(0,a,\"\",0,1);\n\t\tprintf(\"%d\\n\",ret);\n\t\tif(ret<=LIM){\n\t\t\tstd::sort(ans.begin(),ans.end());\n\t\t\tfor(int i=0;i<ret;i++){\n\t\t\t\tfor(int j=0;j<ans[i].size();j++){\n\t\t\t\t\tif(ans[i][j]=='@')printf(\".\");\n\t\t\t\t\telse printf(\"%c\",ans[i][j]);\n\t\t\t\t}\n\t\t\t\tprintf(\"\\n\");\n\t\t\t}\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 7000, "memory_kb": 14728, "score_of_the_acc": -0.9738, "final_rank": 13 }, { "submission_id": "aoj_1170_1191481", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <unordered_set>\n#include <algorithm>\n#include <bitset>\n\nusing namespace std;\ntypedef unsigned int ull;\nstatic const ull HASH_BASE = 1000000007ull;\nstatic const char CHARACTERS[] = \".ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\n\nbool is_covered(\n\tconst string &t, int m, const vector<bitset<65536> *> &pieces)\n{\n\tconst int n = t.size();\n\tif(m > n){ return false; }\n\tull hash_remove = 1ull, h = 0ull;\n\tfor(int i = 0; i < m; ++i){\n\t\thash_remove *= HASH_BASE;\n\t\th = (h * HASH_BASE) + t[i];\n\t}\n\tint tail = 0;\n\tfor(int i = m; i <= n; ++i){\n\t\tif(pieces[h >> 16] != nullptr && (*pieces[h >> 16])[h & 0xffff]){\n\t\t\ttail = i;\n\t\t}\n\t\t//if(pieces.find(h) != pieces.end()){ tail = i; }\n\t\tif(tail == i - m){ return false; }\n\t\th = (h * HASH_BASE) + t[i];\n\t\th -= (hash_remove * t[i - m]);\n\t}\n\treturn tail == n;\n}\n\nint main(){\n\tios_base::sync_with_stdio(false);\n\twhile(true){\n\t\tint d, n;\n\t\tcin >> d >> n;\n\t\tif(d == 0 && n == 0){ break; }\n\t\tstring s;\n\t\tcin >> s;\n\t\tvector<string> pieces(n);\n\t\tfor(int i = 0; i < n; ++i){ cin >> pieces[i]; }\n\t\tconst int m = pieces[0].size();\n\t\t//unordered_set<ull> hashes(n);\n\t\tvector<bitset<65536> *> hashes(65536, nullptr);\n\t\tfor(int i = 0; i < n; ++i){\n\t\t\tull hash = 0;\n\t\t\tfor(int j = 0; j < m; ++j){\n\t\t\t\thash = (hash * HASH_BASE) + pieces[i][j];\n\t\t\t}\n\t\t\t//hashes.insert(hash);\n\t\t\tif(hashes[hash >> 16] == nullptr){\n\t\t\t\thashes[hash >> 16] = new bitset<65536>();\n\t\t\t}\n\t\t\thashes[hash >> 16]->set(hash & 0xffff);\n\t\t}\n\t\tn = s.size();\n\t\tull hash_remove = 1;\n\t\tfor(int i = 0; i < m; ++i){ hash_remove *= HASH_BASE; }\n\t\tvector<string> solutions;\n\t\tif(is_covered(s, m, hashes)){ solutions.push_back(s); }\n\t\tif(d >= 1){\n\t\t\t// insert\n\t\t\tfor(int i = 0; i <= n; ++i){\n\t\t\t\tstring t(n + 1, ' ');\n\t\t\t\tfor(int j = 0; j < n; ++j){\n\t\t\t\t\tt[j >= i ? j + 1 : j] = s[j];\n\t\t\t\t}\n\t\t\t\tfor(int x = 0; x < 27; ++x){\n\t\t\t\t\tt[i] = CHARACTERS[x];\n\t\t\t\t\tif(is_covered(t, m, hashes)){ solutions.push_back(t); }\n\t\t\t\t}\n\t\t\t}\n\t\t\t// replace\n\t\t\tfor(int i = 0; i < n; ++i){\n\t\t\t\tstring t(s);\n\t\t\t\tfor(int x = 0; x < 27; ++x){\n\t\t\t\t\tt[i] = CHARACTERS[x];\n\t\t\t\t\tif(is_covered(t, m, hashes)){ solutions.push_back(t); }\n\t\t\t\t}\n\t\t\t}\n\t\t\t// remove\n\t\t\tfor(int i = 0; i < n; ++i){\n\t\t\t\tstring t(n - 1, ' ');\n\t\t\t\tfor(int j = 0, k = 0; j < n; ++j){\n\t\t\t\t\tif(i == j){ continue; }\n\t\t\t\t\tt[k++] = s[j];\n\t\t\t\t}\n\t\t\t\tif(is_covered(t, m, hashes)){ solutions.push_back(t); }\n\t\t\t}\n\t\t}\n\t\tif(d >= 2){\n\t\t\t// insert\n\t\t\tfor(int i = 0; i <= n; ++i){\n\t\t\t\tstring t1(n + 1, ' ');\n\t\t\t\tfor(int j = 0; j < n; ++j){\n\t\t\t\t\tt1[j >= i ? j + 1 : j] = s[j];\n\t\t\t\t}\n\t\t\t\t// insert-insert\n\t\t\t\tfor(int j = 0; j <= n + 1; ++j){\n\t\t\t\t\tstring t2(n + 2, ' ');\n\t\t\t\t\tfor(int k = 0; k <= n; ++k){\n\t\t\t\t\t\tt2[k >= j ? k + 1 : k] = t1[k];\n\t\t\t\t\t}\n\t\t\t\t\tfor(int a = 0; a < 27; ++a){\n\t\t\t\t\t\tt2[i] = CHARACTERS[a];\n\t\t\t\t\t\tfor(int b = 0; b < 27; ++b){\n\t\t\t\t\t\t\tt2[j] = CHARACTERS[b];\n\t\t\t\t\t\t\tif(is_covered(t2, m, hashes)){\n\t\t\t\t\t\t\t\tsolutions.push_back(t2);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\t// insert-replace\n\t\t\t\tfor(int j = 0; j <= n; ++j){\n\t\t\t\t\tif(i == j){ continue; }\n\t\t\t\t\tstring t2(t1);\n\t\t\t\t\tfor(int a = 0; a < 27; ++a){\n\t\t\t\t\t\tt2[i] = CHARACTERS[a];\n\t\t\t\t\t\tfor(int b = 0; b < 27; ++b){\n\t\t\t\t\t\t\tt2[j] = CHARACTERS[b];\n\t\t\t\t\t\t\tif(is_covered(t2, m, hashes)){\n\t\t\t\t\t\t\t\tsolutions.push_back(t2);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\t// insert-remove\n\t\t\t\tfor(int j = 0; j <= n; ++j){\n\t\t\t\t\tif(i == j){ continue; }\n\t\t\t\t\tstring t2(n, ' ');\n\t\t\t\t\tfor(int k = 0, p = 0; k <= n; ++k){\n\t\t\t\t\t\tif(k == j){ continue; }\n\t\t\t\t\t\tt2[p++] = t1[k];\n\t\t\t\t\t}\n\t\t\t\t\tconst int p = (i >= j ? i - 1 : i);\n\t\t\t\t\tfor(int a = 0; a < 27; ++a){\n\t\t\t\t\t\tt2[p] = CHARACTERS[a];\n\t\t\t\t\t\tif(is_covered(t2, m, hashes)){\n\t\t\t\t\t\t\tsolutions.push_back(t2);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t// replace\n\t\t\tfor(int i = 0; i < n; ++i){\n\t\t\t\t// replace-replace\n\t\t\t\tfor(int j = i + 1; j < n; ++j){\n\t\t\t\t\tstring t(s);\n\t\t\t\t\tfor(int a = 0; a < 27; ++a){\n\t\t\t\t\t\tt[i] = CHARACTERS[a];\n\t\t\t\t\t\tfor(int b = 0; b < 27; ++b){\n\t\t\t\t\t\t\tt[j] = CHARACTERS[b];\n\t\t\t\t\t\t\tif(is_covered(t, m, hashes)){\n\t\t\t\t\t\t\t\tsolutions.push_back(t);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\t// replace-remove\n\t\t\t\tfor(int j = 0; j < n; ++j){\n\t\t\t\t\tif(i == j){ continue; }\n\t\t\t\t\tstring t(n - 1, ' ');\n\t\t\t\t\tfor(int k = 0, p = 0; k < n; ++k){\n\t\t\t\t\t\tif(k == j){ continue; }\n\t\t\t\t\t\tt[p++] = s[k];\n\t\t\t\t\t}\n\t\t\t\t\tconst int p = (i >= j ? i - 1 : i);\n\t\t\t\t\tfor(int a = 0; a < 27; ++a){\n\t\t\t\t\t\tt[p] = CHARACTERS[a];\n\t\t\t\t\t\tif(is_covered(t, m, hashes)){\n\t\t\t\t\t\t\tsolutions.push_back(t);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t// remove-remove\n\t\t\tstring t(n - 2, ' ');\n\t\t\tfor(int i = 0; i < n; ++i){\n\t\t\t\tfor(int j = i + 1; j < n; ++j){\n\t\t\t\t\tfor(int k = 0, p = 0; k < n; ++k){\n\t\t\t\t\t\tif(k == i || k == j){ continue; }\n\t\t\t\t\t\tt[p++] = s[k];\n\t\t\t\t\t}\n\t\t\t\t\tif(is_covered(t, m, hashes)){\n\t\t\t\t\t\tsolutions.push_back(t);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tsort(solutions.begin(), solutions.end());\n\t\tsolutions.erase(\n\t\t\tunique(solutions.begin(), solutions.end()), solutions.end());\n\t\tcout << solutions.size() << endl;\n\t\tif(solutions.size() <= 5){\n\t\t\tfor(const auto &sol : solutions){ cout << sol << endl; }\n\t\t}\n\t\tfor(auto ptr : hashes){ delete ptr; }\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2710, "memory_kb": 17268, "score_of_the_acc": -0.3468, "final_rank": 8 }, { "submission_id": "aoj_1170_1157835", "code_snippet": "#include <cstdio>\n#include <cmath>\n#include <cstring>\n#include <cstdlib>\n#include <climits>\n#include <ctime>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <list>\n#include <vector>\n#include <set>\n#include <map>\n#include <iostream>\n#include <deque>\n#include <complex>\n#include <string>\n#include <iomanip>\n#include <sstream>\n#include <bitset>\n#include <valarray>\n#include <unordered_set>\n#include <iterator>\n#include <assert.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned int uint;\ntypedef unsigned char uchar;\ntypedef unsigned long long ull;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\ntypedef vector<int> vi;\n\n#define REP(i,x) for(int i=0;i<(int)(x);i++)\n#define REPS(i,x) for(int i=1;i<=(int)(x);i++)\n#define RREP(i,x) for(int i=((int)(x)-1);i>=0;i--)\n#define RREPS(i,x) for(int i=((int)(x));i>0;i--)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();i++)\n#define RFOR(i,c) for(__typeof((c).rbegin())i=(c).rbegin();i!=(c).rend();i++)\n#define ALL(container) (container).begin(), (container).end()\n#define RALL(container) (container).rbegin(), (container).rend()\n#define SZ(container) ((int)container.size())\n#define mp(a,b) make_pair(a, b)\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n\ntemplate<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }\ntemplate<class T> ostream& operator<<(ostream &os, const vector<T> &t) {\nos<<\"[\"; FOR(it,t) {if(it!=t.begin()) os<<\",\"; os<<*it;} os<<\"]\"; return os;\n}\ntemplate<class T> ostream& operator<<(ostream &os, const set<T> &t) {\nos<<\"{\"; FOR(it,t) {if(it!=t.begin()) os<<\",\"; os<<*it;} os<<\"}\"; return os;\n}\ntemplate<class S, class T> ostream& operator<<(ostream &os, const pair<S,T> &t) { return os<<\"(\"<<t.first<<\",\"<<t.second<<\")\";}\ntemplate<class S, class T> pair<S,T> operator+(const pair<S,T> &s, const pair<S,T> &t){ return pair<S,T>(s.first+t.first, s.second+t.second);}\ntemplate<class S, class T> pair<S,T> operator-(const pair<S,T> &s, const pair<S,T> &t){ return pair<S,T>(s.first-t.first, s.second-t.second);}\n\nconst int INF = 1<<28;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\n\nstruct AhoCorasick{\n\tstruct State{\n\t\tint next[256], failure;\n\t\tint accepts;\n\t\tState():failure(0),accepts(0){memset(next, 0, sizeof(next));}\n\t};\n\tvector<State> states;\n\tint pats;\n\t\n\tAhoCorasick(){}\n\tAhoCorasick(vector<string> patterns):states(1),pats(patterns.size()){\n\t\tREP(i, pats){\t// make trie\n\t\t\tint p = 0;\n\t\t\tFOR(c, patterns[i]){\n\t\t\t\tif(states[p].next[*c] <= 0){\n\t\t\t\t\tstates[p].next[*c] = states.size();\n\t\t\t\t\tstates.emplace_back();\n\t\t\t\t}\n\t\t\t\tp = states[p].next[*c];\n\t\t\t}\n\t\t\tstates[p].accepts |= 1<<i;\n\t\t}\n\t\t\n\t\tqueue<int> q;\t// make failure link\n\t\tq.push(0);\n\t\twhile(!q.empty()){\n\t\t\tconst int p = q.front();q.pop();\n\t\t\tREP(i, 256){\n\t\t\t\tconst int dst = states[p].next[i];\n\t\t\t\tif(!dst){\n\t\t\t\t\t// 大量に呼び出す時はnextを全部埋めとくといい\n\t\t\t\t\tint q=p;\n\t\t\t\t\twhile(q && !states[q].next[i]) q = states[q].failure;\n\t\t\t\t\tstates[p].next[i] = states[q].next[i];\n\t\t\t\t}else{\n\t\t\t\t\tq.push(dst);\n\t\t\t\t\tint f = states[p].failure;\n\t\t\t\t\twhile(f && states[f].next[i] <= 0) f = states[f].failure;\n\t\t\t\t\tif(p){\n\t\t\t\t\t\tstates[dst].failure = states[f].next[i];\n\t\t\t\t\t\tstates[dst].accepts |= states[states[f].next[i]].accepts;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t\n\tint go_next(int p, const int &c){\n\t\t// nextが埋まってるならここはいらない\n\t\t// while(p && !states[p].next[c]) p = states[p].failure;\n\t\treturn states[p].next[c];\n\t}\n\tpair<int, int> apply(string s, int p=0){\n\t\tint res = 0;\n\t\tREP(i, s.size()){\n\t\t\tp = go_next(p, s[i]);\n\t\t\tres |= states[p].accepts;\n\t\t}\n\t\treturn make_pair(p, res);\n\t}\n\tpair<int, int> apply(char c, int p=0){\n\t\tint res = 0;\n\t\tp = go_next(p, c);\n\t\tres |= states[p].accepts;\n\t\treturn make_pair(p, res);\n\t}\n} ac;\nint d, n, m, ansn;\nstring s;\nunordered_set<ull> hashes;\npriority_queue<string> ans;\n\nconst string db=\".ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\n\nvoid dfs(string &t, int i, int p, ull rh, int last, int d, int previnserted=0){\n\tif(d < 0 || i > s.size() || last + m <= t.size()) return;\n\tif(i == s.size()){\n\t\tif(last == t.size() && hashes.find(rh) == hashes.end()){\n\t\t\thashes.insert(rh);\n\t\t\tans.push(t);\n\t\t\tansn ++;\n\t\t\tif(ans.size() > 5) ans.pop();\n\t\t}\n\t}\n\tif(d){\n\t\tif(!previnserted) dfs(t, i+1, p, rh, last, d-1);\t// delete\n\t\tFOR(c, db){\n\t\t\tt.push_back(*c);\n\t\t\tpii res = ac.apply(*c, p);\n\t\t\tdfs(t, i, res.first, rh*MOD+*c, res.second ? t.size() : last, d-1, 1);\t\t// insert\n\t\t\tif(s[i]!=*c)\n\t\t\t\tdfs(t, i+1, res.first, rh*MOD+*c, res.second ? t.size() : last, d-1);\t// modify\n\t\t\tt.resize(t.size()-1);\n\t\t}\n\t}\n\tt.push_back(s[i]);\n\tpii res = ac.apply(s[i], p);\n\tdfs(t, i+1, res.first, rh*MOD+s[i], res.second ? t.size() : last, d);\n\tt.resize(t.size()-1);\n}\n\nint main(int argc, char *argv[]){\n\tios::sync_with_stdio(false);\n\twhile(cin >> d >> n, n){\n\t\tcin >> s;\n\t\tvector<string> t(n);\n\t\tREP(i, n) cin >> t[i];\n\t\tm = t[0].size();\n\t\tac = AhoCorasick(t);\n\t\tansn = 0;\n\t\tstring tmp=\"\";\n\t\tdfs(tmp, 0, 0, 0, 0, d);\n\t\tcout << ansn << endl;\n\t\tif(ansn <= 5){\n\t\t\tvector<string> ss;\n\t\t\tREP(i, ansn){\n\t\t\t\tss.push_back(ans.top()); ans.pop();\n\t\t\t}\n\t\t\tRREP(i, ansn) cout << ss[i] << endl;\n\t\t}\n\t\twhile(!ans.empty()) ans.pop();\n\t\thashes.clear();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2990, "memory_kb": 3352, "score_of_the_acc": -0.279, "final_rank": 5 }, { "submission_id": "aoj_1170_1157829", "code_snippet": "#include <cstdio>\n#include <cmath>\n#include <cstring>\n#include <cstdlib>\n#include <climits>\n#include <ctime>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <list>\n#include <vector>\n#include <set>\n#include <map>\n#include <iostream>\n#include <deque>\n#include <complex>\n#include <string>\n#include <iomanip>\n#include <sstream>\n#include <bitset>\n#include <valarray>\n#include <unordered_set>\n#include <iterator>\n#include <assert.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned int uint;\ntypedef unsigned char uchar;\ntypedef unsigned long long ull;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\ntypedef vector<int> vi;\n\n#define REP(i,x) for(int i=0;i<(int)(x);i++)\n#define REPS(i,x) for(int i=1;i<=(int)(x);i++)\n#define RREP(i,x) for(int i=((int)(x)-1);i>=0;i--)\n#define RREPS(i,x) for(int i=((int)(x));i>0;i--)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();i++)\n#define RFOR(i,c) for(__typeof((c).rbegin())i=(c).rbegin();i!=(c).rend();i++)\n#define ALL(container) (container).begin(), (container).end()\n#define RALL(container) (container).rbegin(), (container).rend()\n#define SZ(container) ((int)container.size())\n#define mp(a,b) make_pair(a, b)\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n\ntemplate<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }\ntemplate<class T> ostream& operator<<(ostream &os, const vector<T> &t) {\nos<<\"[\"; FOR(it,t) {if(it!=t.begin()) os<<\",\"; os<<*it;} os<<\"]\"; return os;\n}\ntemplate<class T> ostream& operator<<(ostream &os, const set<T> &t) {\nos<<\"{\"; FOR(it,t) {if(it!=t.begin()) os<<\",\"; os<<*it;} os<<\"}\"; return os;\n}\ntemplate<class S, class T> ostream& operator<<(ostream &os, const pair<S,T> &t) { return os<<\"(\"<<t.first<<\",\"<<t.second<<\")\";}\ntemplate<class S, class T> pair<S,T> operator+(const pair<S,T> &s, const pair<S,T> &t){ return pair<S,T>(s.first+t.first, s.second+t.second);}\ntemplate<class S, class T> pair<S,T> operator-(const pair<S,T> &s, const pair<S,T> &t){ return pair<S,T>(s.first-t.first, s.second-t.second);}\n\nconst int INF = 1<<28;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\n\nstruct AhoCorasick{\n\tstruct State{\n\t\tint next[256], failure;\n\t\tint accepts;\n\t\tState():failure(0),accepts(0){memset(next, 0, sizeof(next));}\n\t};\n\tvector<State> states;\n\tint pats;\n\t\n\tAhoCorasick(){}\n\tAhoCorasick(vector<string> patterns):states(1),pats(patterns.size()){\n\t\tREP(i, pats){\t// make trie\n\t\t\tint p = 0;\n\t\t\tFOR(c, patterns[i]){\n\t\t\t\tif(states[p].next[*c] <= 0){\n\t\t\t\t\tstates[p].next[*c] = states.size();\n\t\t\t\t\tstates.emplace_back();\n\t\t\t\t}\n\t\t\t\tp = states[p].next[*c];\n\t\t\t}\n\t\t\tstates[p].accepts |= 1<<i;\n\t\t}\n\t\t\n\t\tqueue<int> q;\t// make failure link\n\t\tq.push(0);\n\t\twhile(!q.empty()){\n\t\t\tconst int p = q.front();q.pop();\n\t\t\tREP(i, 256){\n\t\t\t\tconst int dst = states[p].next[i];\n\t\t\t\tif(!dst){\n\t\t\t\t\t// 大量に呼び出す時はnextを全部埋めとくといい\n\t\t\t\t\tint q=p;\n\t\t\t\t\twhile(q && !states[q].next[i]) q = states[q].failure;\n\t\t\t\t\tstates[p].next[i] = states[q].next[i];\n\t\t\t\t}else{\n\t\t\t\t\tq.push(dst);\n\t\t\t\t\tint f = states[p].failure;\n\t\t\t\t\twhile(f && states[f].next[i] <= 0) f = states[f].failure;\n\t\t\t\t\tif(p){\n\t\t\t\t\t\tstates[dst].failure = states[f].next[i];\n\t\t\t\t\t\tstates[dst].accepts |= states[states[f].next[i]].accepts;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t\n\tint go_next(int p, const int &c){\n\t\t// nextが埋まってるならここはいらない\n\t\t// while(p && !states[p].next[c]) p = states[p].failure;\n\t\treturn states[p].next[c];\n\t}\n\tpair<int, int> apply(string s, int p=0){\n\t\tint res = 0;\n\t\tREP(i, s.size()){\n\t\t\tp = go_next(p, s[i]);\n\t\t\tres |= states[p].accepts;\n\t\t}\n\t\treturn make_pair(p, res);\n\t}\n\tpair<int, int> apply(char c, int p=0){\n\t\tint res = 0;\n\t\tp = go_next(p, c);\n\t\tres |= states[p].accepts;\n\t\treturn make_pair(p, res);\n\t}\n} ac;\nint d, n, m, ansn;\nstring s;\nunordered_set<ull> hashes;\npriority_queue<string> ans;\n\nconst string db=\".ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\n\nvoid dfs(string &t, int i, int p, ull rh, int last, int d){\n\tif(d < 0 || i > s.size() || last + m <= t.size()) return;\n\tif(i == s.size()){\n\t\tif(last == t.size() && hashes.find(rh) == hashes.end()){\n\t\t\thashes.insert(rh);\n\t\t\tans.push(t);\n\t\t\tansn ++;\n\t\t\tif(ans.size() > 5) ans.pop();\n\t\t}\n\t}\n\tif(d){\n\t\tdfs(t, i+1, p, rh, last, d-1);\t// delete\n\t\tFOR(c, db){\n\t\t\tt.push_back(*c);\n\t\t\tpii res = ac.apply(*c, p);\n\t\t\tdfs(t, i, res.first, rh*MOD+*c, res.second ? t.size() : last, d-1);\t\t// insert\n\t\t\tif(s[i]!=*c)\n\t\t\t\tdfs(t, i+1, res.first, rh*MOD+*c, res.second ? t.size() : last, d-1);\t// modify\n\t\t\tt.resize(t.size()-1);\n\t\t}\n\t}\n\tt.push_back(s[i]);\n\tpii res = ac.apply(s[i], p);\n\tdfs(t, i+1, res.first, rh*MOD+s[i], res.second ? t.size() : last, d);\n\tt.resize(t.size()-1);\n}\n\nint main(int argc, char *argv[]){\n\tios::sync_with_stdio(false);\n\twhile(cin >> d >> n, n){\n\t\tcin >> s;\n\t\tvector<string> t(n);\n\t\tREP(i, n) cin >> t[i];\n\t\tm = t[0].size();\n\t\tac = AhoCorasick(t);\n\t\tansn = 0;\n\t\tstring tmp=\"\";\n\t\tdfs(tmp, 0, 0, 0, 0, d);\n\t\tcout << ansn << endl;\n\t\tif(ansn <= 5){\n\t\t\tvector<string> ss;\n\t\t\tREP(i, ansn){\n\t\t\t\tss.push_back(ans.top()); ans.pop();\n\t\t\t}\n\t\t\tRREP(i, ansn) cout << ss[i] << endl;\n\t\t}\n\t\twhile(!ans.empty()) ans.pop();\n\t\thashes.clear();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3010, "memory_kb": 3356, "score_of_the_acc": -0.2821, "final_rank": 6 }, { "submission_id": "aoj_1170_1157015", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\n#include<cstring>\n#include<vector>\n#include<algorithm>\n#include<queue>\n#include<ctime>\nusing namespace std;\n#define INF (1<<29)\n\n\n\nclass PMA{//Aho-Corasick\n\tstruct Node{\n\t\tbool match;\n\t\tint failure;\n\t\tint len;\n\t\tint next[256];\n\t\tNode(int len):failure(-1),len(len),match(false){memset(next,-1,sizeof(next));}\n\t};\n\tvector<Node> node;\n\n\tvoid precompute(){\n\t\tfor(int i=1;i<(int)node.size();i++){\n\t\t\tfor(int j=0;j<256;j++){\n\t\t\t\tnode[i].next[j]=_step(i,j);\n\t\t\t}\n\t\t}\n\t}\n\tint _step(int t,char c)const{\n\t\twhile(node[t].next[c]==-1)t=node[t].failure;\n\t\treturn node[t].next[c];\n\t}\npublic:\n\tPMA(){}\n\t~PMA(){\n\t\tnode.clear();\n\t}\n\tint size()const{return node.size();}\n\tbool matched(int id)const{return node[id].match;}\n\tvoid build(const vector<string> &p){\n\t\tnode.clear();\n\t\tnode.push_back(Node(0));\n\t\tfor(int i=0;i<(int)p.size();i++){\n\t\t\tconst string &s=p[i];\n\t\t\tint t=0;\n\t\t\tfor(int j=0;j<(int)s.size();j++){\n\t\t\t\tif(node[t].next[s[j]]==-1){\n\t\t\t\t\tnode[t].next[s[j]]=node.size();\n\t\t\t\t\tnode.push_back(Node(j+1));\t\t\t\t\n\t\t\t\t}\n\t\t\t\tt=node[t].next[s[j]];\n\t\t\t}\n\t\t\tnode[t].match=true;\n\t\t}\n\t\tqueue<int> q;\n\t\tfor(int i=0;i<256;i++){\n\t\t\tNode &root=node[0];\n\t\t\tif(root.next[i]!=-1){\n\t\t\t\tq.push(root.next[i]);\n\t\t\t\tnode[root.next[i]].failure=0;\n\t\t\t}else root.next[i]=0;\n\t\t}\n\t\twhile(!q.empty()){\n\t\t\tint t=q.front();q.pop();\n\t\t\tfor(int i=0;i<256;i++){\n\t\t\t\tif(node[t].next[i]!=-1){\n\t\t\t\t\tq.push(node[t].next[i]);\n\t\t\t\t\tint r=_step(node[t].failure,i);\n\t\t\t\t\tint v=node[t].next[i];\n\t\t\t\t\tnode[v].failure = r;\n\t\t\t\t\tif(r!=-1)node[v].match |= node[r].match;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tprecompute();\n\t}\n\tint step(int t,char c)const{\n\t\treturn node[t].next[c];\n\t}\n\tint length(int t)const{\n\t\treturn node[t].len;\n\t}\n};\n\n\n\n\nPMA pma;\nvector<string> piece;\nint pLen;\nvector<string> ans;\nconst char C[28]=\".ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\n\n\nbool match(string &s){\n\tint node=0;\n\tint cover=-1;\n\tfor(int i=0;i<s.size();i++){\n\t\tnode=pma.step(node,s[i]);\n\t\tif(pma.matched(node))cover = i;\n\t\telse if(i-cover>pma.length(node))return false;\n\t\t//else if(pLen==i-cover)return false;\n\t}\n\treturn cover==s.size()-1;\n}\nvoid search(string &s,int d){\n\tif(d==0){\n\t\t//cout<<s<<endl;\n\t\tif(match(s))ans.push_back(s);\n\t\treturn;\n\t}\n\t//search(s,d-1);\n\tstring t(s.begin(),s.end());\n\tt+=' ';\n\tfor(int i=s.size();;i--){//insert\n\t\tfor(int j=0;j<27;j++){\n\t\t\tt[i]=C[j];\n\t\t\tsearch(t,d-1);\n\t\t}\n\t\tif(i==0)break;\n\t\tt[i]=t[i-1];\n\t}\n\tfor(int i=0;i<s.size();i++){//replace\n\t\tfor(int j=0;j<27;j++){\n\t\t\tchar c=s[i];\n\t\t\ts[i]=C[j];\n\t\t\tsearch(s,d-1);\n\t\t\ts[i]=c;\n\t\t}\n\t}\n\tt.assign(s,1,s.size()-1);\n\tchar c = s[0];\n\tfor(int i=0;i<t.size();i++){//remove\n\t\tsearch(t,d-1);\n\t\tswap(c,t[i]);\n\t}\n\tsearch(t,d-1);\n}\nint main(){\n\t//clock_t t=clock();\n\tint d,n;\n\twhile(cin>>d>>n,d|n){\n\t\tstring alter;\n\t\tcin>>alter;\n\t\tpiece.clear();\n\t\tfor(int i=0;i<n;i++){\n\t\t\tstring t;\n\t\t\tcin>>t;\n\t\t\tpiece.push_back(t);\n\t\t\tpLen=t.size();\n\t\t}\n\t\tpma.build(piece);\n\t\tans.clear();\n\t\tsearch(alter,d);\n\t\tsort(ans.begin(),ans.end());\n\t\tans.erase(unique(ans.begin(),ans.end()),ans.end());\n\t\tcout<<ans.size()<<endl;\n\t\tif(ans.size()<=5){\n\t\t\tfor(int i=0;i<ans.size();i++)cout<<ans[i]<<endl;\n\t\t}\n\t}\n\t//cout<<((double)(clock()-t)/CLOCKS_PER_SEC)<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 6280, "memory_kb": 34704, "score_of_the_acc": -1.0231, "final_rank": 15 }, { "submission_id": "aoj_1170_926172", "code_snippet": "#include <algorithm>\n#include <cstdlib>\n#include <iostream>\n#include <unordered_set>\n#include <unordered_map>\n#include <vector>\nusing namespace std;\n\ntypedef unsigned int hash_t;\n\nconstexpr int MAX_LEN = 40 + 2;\nconstexpr hash_t base = 1000000007;\nhash_t pows[MAX_LEN + 1];\n\nclass rolling_hash {\nprivate:\n\tvector<hash_t> hashes;\n\npublic:\n\trolling_hash(const string &s):hashes(s.size() + 1) {\n\t\thashes[0] = 0;\n\t\tfor(unsigned i = 0; i < s.size(); ++i) {\n\t\t\thashes[i + 1] = hashes[i] * base + s[i];\n\t\t}\n\t}\n\n\thash_t hash(int l, int r) const {\n\t\treturn hashes[r] - hashes[l] * pows[r - l];\n\t}\n\n\tstatic hash_t hash(const string &s) {\n\t\tlong long res = 0;\n\t\tfor(const auto &c : s) {\n\t\t\tres *= base;\n\t\t\tres += c;\n\t\t}\n\t\treturn res;\n\t}\n};\n\nconstexpr int MAX_N = 30;\nint l;\nint n, d;\nvector<string> ans;\nstring pieces[MAX_N];\nunordered_set<hash_t> hashes[MAX_N];\nunordered_map<int, int> visited;\nunordered_set<hash_t> checked;\n\ninline void init() {\n\tl = pieces[0].size();\n\tchecked.clear();\n\n\tfor(int i = 0; i < n; ++i) {\n\t\thashes[i].clear();\n\t\thashes[i].insert(rolling_hash::hash(pieces[i]));\n\n\t\tfor(int j = 0; j < l; ++j) {\n\t\t\tconst char c = pieces[i][j];\n\t\t\tpieces[i][j] = '?';\n\t\t\thashes[i].insert(rolling_hash::hash(pieces[i]));\n\n\t\t\tif(d == 2) {\n\t\t\t\tfor(int k = j + 1; k < l; ++k) {\n\t\t\t\t\tconst char t = pieces[i][k];\n\t\t\t\t\tpieces[i][k] = '?';\n\t\t\t\t\thashes[i].insert(rolling_hash::hash(pieces[i]));\n\t\t\t\t\tpieces[i][k] = t;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tpieces[i][j] = c;\n\t\t}\n\t}\n}\n\nvoid rec(int idx, int ok, string &s, const vector<int> &question, const rolling_hash &rh) {\n\tif(ok >= s.size()) {\n\t\tans.emplace_back(s);\n\t\treturn;\n\t}\n\tif(idx + l > s.size()) return;\n\n\tint state = 0;\n\tfor(const auto &pos : question) {\n\t\tstate = state * 1000 + s[pos];\n\t}\n\n\tif(visited.count(state) && visited[state] >= idx) return;\n\tvisited[state] = idx;\n\n\tfor(int i = 0; i < n; ++i) {\n\t\tif(hashes[i].count(rh.hash(idx, idx + l))) {\n\t\t\tstring tmp = \"\";\n\t\t\tbool change = false;\n\t\t\tfor(const auto &pos : question) {\n\t\t\t\ttmp += s[pos];\n\t\t\t\tif(s[pos] == '?' && idx <= pos && pos < idx + l) {\n\t\t\t\t\ts[pos] = pieces[i][pos - idx];\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(change) {\n\t\t\t\trec(idx + 1, idx + l, s, question, rolling_hash(s));\n\t\t\t\tfor(int j = 0; j < question.size(); ++j) {\n\t\t\t\t\ts[question[j]] = tmp[j];\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\trec(idx + 1, idx + l, s, question, rh);\n\t\t\t\treturn;\n\t\t\t}\n\t\t}\n\t}\n\n\tif(ok > idx) {\n\t\trec(idx + 1, ok, s, question, rh);\n\t}\n}\n\nvoid check(string &s) {\n\tconst int m = s.size();\n\tconst rolling_hash rh(s);\n\n\tif(checked.count(rh.hash(0, m))) return;\n\tchecked.insert(rh.hash(0, m));\n\n\tvector<int> question;\n\tfor(int i = 0; i < m; ++i) {\n\t\tif(s[i] == '?') question.emplace_back(i);\n\t}\n\n\tvisited.clear();\n\trec(0, 0, s, question, rh);\n}\n\nvoid dfs(int rest, string &s) {\n\tcheck(s);\n\tif(rest == 0) return;\n\n\tconst int n = s.size();\n\n\t// erase\n\tfor(int i = 0; i < n; ++i) {\n\t\tstring tmp(s);\n\t\ttmp.erase(i, 1);\n\t\tdfs(rest - 1, tmp);\n\t}\n\n\t// change\n\tfor(int i = 0; i < n; ++i) {\n\t\tconst char t = s[i];\n\t\ts[i] = '?';\n\t\tdfs(rest - 1, s);\n\t\ts[i] = t;\n\t}\n\n\t// insert\n\tfor(int i = 0; i <= n; ++i) {\n\t\ts.insert(i, 1, '?');\n\t\tdfs(rest - 1, s);\n\t\ts.erase(i, 1);\n\t}\n}\n\nint main() {\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\n\tpows[0] = 1;\n\tfor(int i = 1; i <= MAX_LEN; ++i) {\n\t\tpows[i] = pows[i - 1] * base;\n\t}\n\n\twhile(cin >> d >> n && (d | n)) {\n\t\tstring sentence;\n\t\tcin >> sentence;\n\n\t\tfor(int i = 0; i < n; ++i) {\n\t\t\tcin >> pieces[i];\n\t\t}\n\n\t\tinit();\n\n\t\tans.clear();\n\t\tdfs(d, sentence);\n\n\t\tsort(ans.begin(), ans.end());\n\t\tans.erase(unique(ans.begin(), ans.end()), ans.end());\n\n\t\tconst int c = ans.size();\n\t\tcout << c << endl;\n\t\tif(c <= 5) {\n\t\t\tfor(const auto &e : ans) {\n\t\t\t\tcout << e << endl;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn EXIT_SUCCESS;\n}", "accuracy": 1, "time_ms": 4660, "memory_kb": 11928, "score_of_the_acc": -0.5987, "final_rank": 11 }, { "submission_id": "aoj_1170_513450", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <sstream>\n#include <cstdio>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <complex>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <cassert>\n#include <climits>\n#include <queue>\n#include <set>\n#include <map>\n#include <valarray>\n#include <bitset>\n#include <stack>\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(int)n;++i)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n#define ALL(c) (c).begin(), (c).end()\ntypedef long long ll;\ntypedef pair<int,int> pii;\nconst int INF = 1<<29;\nconst double PI = acos(-1);\nconst double EPS = 1e-8;\n\nint d,n;\nint meslen;\nint len;\nstring mes;\nstring piece[30];\nstring now;\n\nint dp[51][51];\nbool levenshtein(int m) {\n for (int i=1; i<=m; ++i) {\n int mi = INF;\n for (int j=max(1,i-d); j<=min(meslen,i+d); ++j) {\n if (now[i-1] == mes[j-1]) dp[i][j]=dp[i-1][j-1];\n else {\n dp[i][j] = min(min(dp[i-1][j], // a deletion\n dp[i][j-1]), // an insertion\n dp[i-1][j-1]) + 1; // a substituion\n }\n mi = min(mi, dp[i][j]);\n }\n if (mi > d) return 0;\n }\n return 1;\n}\n\n// int dp[50][50][50];\n// void calcEditDist() {\n// }\n\nbool levenshtein(const string &s, const string &t) {\n int n = s.size();\n int m = t.size();\n REP(i,n) dp[i][0]=i;\n REP(i,m) dp[0][i]=i;\n for (int i=1; i<=n; ++i) {\n for (int j=1; j<=m; ++j) {\n dp[i][j] = min(min(dp[i-1][j] + 1, // a deletion\n dp[i][j-1] + 1), // an insertion\n dp[i-1][j-1] + (s[i-1] != t[j-1])); // a substituion\n }\n }\n return dp[n][m]<=d;\n}\n\nvector<pii> next[30][50];\nvector<string> nextstr[30][50];\n\nvoid calcNext() {\n REP(a,n) {\n REP(i,meslen+2) {\n next[a][i].clear();\n nextstr[a][i].clear();\n }\n REP(b,n) {\n for (int i=1; i<=len; ++i) {\n bool ok = 1;\n REP(j,len-i) if (piece[a][i+j]!=piece[b][j]) ok = 0;\n if (ok) {\n string t = piece[a] + piece[b].substr(len-i);\n for (int j=0; j+len+i<=meslen+2; ++j) {\n // bool ok = 0;\n // for (int k=max(0,j-2); k<=j+2&&k+len+i<=meslen+2; ++k) {\n // if (levenshtein(t,mes.substr(k,len+i))) {\n // ok = 1;\n // break;\n // }\n // }\n // if (ok) {\n // if (j==0 && b\n // nextstr[a][j].push_back(piece[b].substr(len-i));\n // next[a][j].push_back(pii(b,i)); \n // }\n nextstr[a][j].push_back(piece[b].substr(len-i));\n next[a][j].push_back(pii(b,i));\n }\n }\n }\n }\n }\n}\n\nvector<string> ans;\n\nll hs(const string &s) {\n ll res = 0;\n REP(i,s.size()) {\n res = res*1000000009 + s[i];\n }\n return res;\n}\n\nmap<ll,int> mp[50];\n\nint cnt, cnt1, cnt2;\nvoid dfs(int pos, int id) {\n cnt2++;\n \n // if (mp[pos+len].count(now)) return;\n // mp[pos+len][now] = 1;\n \n if (!levenshtein(pos+len)) return;\n // cout << now << endl;\n if (dp[pos+len][meslen] <= d) {\n ans.push_back(now);\n // cout << now << endl;\n }\n\n string tmp = now;\n REP(i,next[id][pos].size()) {\n int b = next[id][pos][i].first;\n int p = next[id][pos][i].second;\n if (pos+p+len > meslen+2) continue;\n now = tmp + nextstr[id][pos][i];\n ll hash = hs(now);\n if (mp[pos+p].count(hash)) continue;\n mp[pos+p][hash] = 1;\n // if (!levenshtein(pos+p+len)) continue;\n // if (dp[min(meslen,pos+p+len)][pos+p+len] > d) continue;\n dfs(pos+p, b);\n }\n now = tmp;\n}\n\nint main() {\n int N;\n while(scanf(\"%d%d\",&d,&N),d||N) {\n REP(i,50) mp[i].clear();\n cin >> mes;\n meslen = mes.size();\n n = 0;\n REP(i,N) {\n cin >> piece[i];\n }\n sort(piece, piece+N);\n n = unique(piece, piece+N) - piece;\n // REP(i,n) {\n // cout << piece[i] << endl;\n // }\n // cout << endl;\n len = piece[0].size();\n calcNext();\n ans.clear();\n cnt = 0,cnt1=0,cnt2=0;\n \n REP(i,50) dp[i][0]=dp[0][i]=i;\n for (int i=1; i<=meslen+2; ++i)\n for (int j=1; j<=meslen+2; ++j)\n if (abs(i-j)>d) dp[i][j]=INF;\n REP(j,n) {\n now = piece[j];\n dfs(0,j);\n }\n //printf(\"%d %d %d\\n\",cnt,cnt1,cnt2);\n sort(ALL(ans));\n cout << ans.size() << endl;\n if (ans.size() <= 5) {\n REP(i,ans.size()) {\n cout << ans[i] << endl;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 4470, "memory_kb": 63276, "score_of_the_acc": -0.9759, "final_rank": 14 }, { "submission_id": "aoj_1170_188036", "code_snippet": "#include <cstdio>\n#include <vector>\n#include <set>\n#include <string>\n#include <iostream>\n#include <cstdlib>\n#include <algorithm>\n#include <string.h>\nusing namespace std;\n\ntypedef unsigned long long ul;\n\nconst ul base = 1000000007;\nvector<ul> bs;\nset<string> ans;\nset<ul> ans2;\nstring line;\nvector<ul> hs;\nvector<string> piece;\nset<string> d1, d2;\nstring plane;\nbool precheck[0x100][0x100][0x100];\nint N, d, L;\nbool cut;\nbool preok[50], postok[50];\nbool preok2[50][0x100], postok2[50][0x100];\nint prewidth[0x100], postwidth[0x100];\nint precut, postcut, width;\nbool oks[50], covered[50];\n\ninline ul hash_func(string& str){\n\tul ret = 0;\n\tfor(int i=0; i<L; i++){\n\t\tret += str[i] * bs[L-1-i];\n\t}\n\treturn ret;\n}\n\ninline ul hash_func2(string& str){\n\tul ret = 0;\n\tfor(int i=0; i<str.length(); i++){\n\t\tret += bs[i] * str[i];\n\t}\n\treturn ret;\n}\n\ninline void add_ans(string& str){\n\tans2.insert(hash_func2(str));\n\tif(ans.size()<=4){\n\t\tans.insert(str);\n\t}\n}\n\ninline bool check(string& str){\n\tint n = str.length();\n\tif(n < L){\n\t\treturn false;\n\t}\n\tul h = hash_func(str);\n\tmemset(oks,0,sizeof(oks));\n\tmemset(covered,0,sizeof(covered));\n\tif(binary_search(hs.begin(), hs.end(), h)){\n\t\toks[0] = true;\n\t}\n\tfor(int i=0; i<n-L; i++){\n\t\th = h*base - bs[L]*str[i] + str[i+L];\n\t\tif(binary_search(hs.begin(), hs.end(), h)){\n\t\t\toks[i+1] = true;\n\t\t}\n\t}\n\tfor(int i=0; i<n; i++)if(oks[i]){\n\t\tfor(int j=0; j<L; j++){\n\t\t\tcovered[i+j] = true;\n\t\t}\n\t\tif(!covered[i]){\n\t\t\t//if((rand()&0xfff)<10) cout << str << endl;\n\t\t\treturn false;\n\t\t}\n\t}\n\tfor(int i=0; i<n; i++)if(!covered[i]){\n\t\t//if((rand()&0xfff)<10) cout << str << endl;\n\t\treturn false;\n\t}\n\treturn true;\n}\n\nvoid generate(string& str, set<string>& dd){\n\tint difpos;\n\tbool phase2 = (&dd == &d2);\n\tif(cut){\n\t\tif(!phase2){\n\t\t\tdd.insert(str + string(1,line[0]));\n\t\t\tdd.insert(string(1,line[0]) + str);\n\t\t}\n\t\telse {\n\t\t\tstring t = str + string(1,line[0]);\n\t\t\tif(check(t)) add_ans(t);\n\t\t\tt = string(1,line[0]) + str;\n\t\t\tif(check(t)) add_ans(t);\n\t\t}\n\t\tdifpos = str.find_first_not_of(line[0]);\n\t}\n\tint n = str.length();\n\t//insert\n\tfor(int i=0; i<n+1; i++){\n\t\tif(cut && difpos != string::npos){\n\t\t\t\tif(difpos<L-1 && !preok2[difpos][str[difpos]]){\n\t\t\t\t\tif(!(preok2[difpos+1][str[difpos]] && i<difpos)) continue;\n\t\t\t\t}\n\t\t\t\tif(n-1-difpos<L-1 && !postok2[n-1-difpos][str[difpos]]){\n\t\t\t\t\tif(!(postok2[n-difpos][str[difpos]] && i>=difpos)) continue;\n\t\t\t\t}\n\t\t}\n\t\tif(cut && (i<=precut-1 || n-i-1<=postcut-2)) continue;\n\t\tif(cut && difpos != string::npos && abs(difpos - i) <= width) continue;\n\t\tif(cut && difpos != string::npos && prewidth[str[difpos]] && difpos - i <= prewidth[str[difpos]] - 1 && i <= difpos) continue;\n\t\tif(cut && phase2 && i<L && !preok[i]) continue;\n\t\tif(cut && phase2 && n-i-1<L && !postok[n-i]) continue;\n\t\tif(cut && i < L && i>0 && !(preok[i-1] || preok[i])) continue;\n\t\tif(cut && n-1-i < L && i<n-1 && !(postok[n-i] || postok[n-i+1])) continue;\n\t\tstring t;t.reserve(n+1);\n\t\tfor(int j=0; j<n; j++){\n\t\t\tif(j==i) t.push_back('.');\n\t\t\tt.push_back(str[j]);\n\t\t}\n\t\tif(i==n) t.push_back('.');\n\t\tfor(char c='.';c<='.';c++){\n\t\t\tif(cut && phase2 && i<L && !preok2[i][c]) continue;\n\t\t\tif(cut && phase2 && n-i-1<L && !postok2[n-i][c]) continue;\n\t\t\tif(cut && i<L-1 && i>0 && !(preok2[i-1][c] || preok2[i][c] || preok2[i+1][c])) continue;\n\t\t\tif(cut && n-i-1<L-1 && n-i>0 && !(postok2[n-i-1][c] || postok2[n-i][c] || postok2[n-i+1][c])) continue;\n\t\t\tif(i==0 || i==n || (precheck[t[i-1]][t[i]][t[i+1]])){\n\t\t\t\tif(phase2){\n\t\t\t\t\tif(check(t)) add_ans(t);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tdd.insert(t);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(char c='A'; c<='Z'; c++){\n\t\t\tt[i] = c;\n\t\t\tif(cut && phase2 && i<L && !preok2[i][c]) continue;\n\t\t\tif(cut && phase2 && n-i-1<L && !postok2[n-i][c]) continue;\n\t\t\tif(cut && i<L-1 && i>0 && !(preok2[i-1][c] || preok2[i][c] || preok2[i+1][c])) continue;\n\t\t\tif(cut && n-i-1<L-1 && n-i>0 && !(postok2[n-i-1][c] || postok2[n-i][c] || postok2[n-i+1][c])) continue;\n\t\t\tif(i==0 || i==n || (precheck[t[i-1]][t[i]][t[i+1]])){\n\t\t\t\tif(phase2){\n\t\t\t\t\tif(check(t)) add_ans(t);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tdd.insert(t);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\t//replace\n\tif(!(cut && difpos != string::npos &&\n\t\t\t((difpos<L && !preok2[difpos][str[difpos]]) || (n-1-difpos<L && !postok2[n-1-difpos][str[difpos]]))))\n\tfor(int i=0; i<n; i++){\n\t\tif(cut && (i<=precut-1 || n-i-1<=postcut-1)) continue;\n\t\tif(cut && difpos != string::npos && abs(difpos - i) <= width) continue;\n\t\tif(cut && difpos != string::npos && prewidth[str[difpos]] && difpos - i <= prewidth[str[difpos]] - 1 && i <= difpos) continue;\n\t\tif(cut && phase2 && i<L && !preok[i]) continue;\n\t\tif(cut && phase2 && n-1-i<L && !postok[n-i-1]) continue;\n\t\tif(cut && i < L && i>0 && !(preok[i-1] || preok[i])) continue;\n\t\tif(cut && n-1-i < L && i<n-1 && !(postok[n-i-2] || postok[n-i-1] )) continue;\n\t\tstring t = str;\n\t\tfor(char c='.';c<='.';c++){\n\t\t\tt[i] = c;\n\t\t\tif(cut && phase2 && i<L && !preok2[i][c]) continue;\n\t\t\tif(cut && phase2 && n-i-1<L && !postok2[n-i-1][c]) continue;\n\t\t\tif(cut && i<L-1 && i>0 && !(preok2[i-1][c] || preok2[i][c] || preok2[i+1][c])) continue;\n\t\t\tif(cut && n-i-1<L-1 && n-i-1>0 && !(postok2[n-i-2][c] || postok2[n-i-1][c] || postok2[n-i][c])) continue;\n\t\t\tif(i==0 || i==n-1 || (precheck[t[i-1]][t[i]][t[i+1]])){\n\t\t\t\tif(phase2){\n\t\t\t\t\tif(check(t)) add_ans(t);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tdd.insert(t);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(char c='A'; c<='Z'; c++){\n\t\t\tt[i] = c;\n\t\t\tif(cut && phase2 && i<L && !preok2[i][c]) continue;\n\t\t\tif(cut && phase2 && n-i-1<L && !postok2[n-i-1][c]) continue;\n\t\t\tif(cut && i<L-1 && i>0 && !(preok2[i-1][c] || preok2[i][c] || preok2[i+1][c])) continue;\n\t\t\tif(cut && n-i-1<L-1 && n-i-1>0 && !(postok2[n-i-2][c] || postok2[n-i-1][c] || postok2[n-i][c])) continue;\n\t\t\tif(i==0 || i==n-1 || (precheck[t[i-1]][t[i]][t[i+1]])){\n\t\t\t\tif(phase2){\n\t\t\t\t\tif(check(t)) add_ans(t);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tdd.insert(t);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\t//delete\n\tfor(int i=0; i<n; i++){\n\t\tstring t;t.reserve(n);\n\t\tfor(int j=0; j<n; j++){\n\t\t\tif(i!=j) t.push_back(str[j]);\n\t\t}\n\t\tif(phase2){\n\t\t\tif(check(t)) add_ans(t);\n\t\t}\n\t\telse{\n\t\t\tdd.insert(t);\n\t\t}\n\t}\n}\n\ninline void add(string& t, int ind){\n\tif(check(t)) add_ans(t);\n\tfor(char c='A';c<='Z';c++){\n\t\tt[ind] = c;\n\t\tif(check(t)) add_ans(t);\n\t}\n\tt[ind] = '.';\n\tfor(char c='A';c<='Z';c++){\n\t\tt[ind+1] = c;\n\t\tif(check(t)) add_ans(t);\n\t}\n\tfor(char c='A';c<='Z';c++){\n\t\tfor(char cc='A';cc<='Z';cc++){\n\t\t\tt[ind] = c;\n\t\t\tt[ind+1] = cc;\n\t\t\tif(check(t)) add_ans(t);\n\t\t}\n\t}\n}\n\nvoid subsolve(){\n\t//insert-insert\n\tint n = line.length();\n\tfor(int i=0; i<n+1; i++){\n\t\tstring t;\n\t\tfor(int j=0; j<n; j++){\n\t\t\tif(i==j) t += \"..\";\n\t\t\tt.push_back(line[j]);\n\t\t}\n\t\tif(i==n) t += \"..\";\n\t\tadd(t,i);\n\t}\n\t//insert-replace\n\tfor(int i=0; i<n; i++){\n\t\tstring t;\n\t\tfor(int j=0; j<n; j++){\n\t\t\tif(i==j) t.push_back('.');\n\t\t\tt.push_back(line[j]);\n\t\t}\n\t\tt[i+1] = '.';\n\t\tadd(t,i);\n\t}\n\t//replace-insert\n\tfor(int i=0; i<n; i++){\n\t\tstring t;\n\t\tfor(int j=0; j<n; j++){\n\t\t\tif(i+1==j) t.push_back('.');\n\t\t\tt.push_back(line[j]);\n\t\t}\n\t\tif(i==n-1) t.push_back('.');\n\t\tt[i] = '.';\n\t\tadd(t,i);\n\t}\n\t//replace-replace\n\tfor(int i=0; i<n-1; i++){\n\t\tstring t = line;\n\t\tt[i] = t[i+1] = '.';\n\t\tadd(t,i);\n\t}\n}\n\nvoid solve(){\n\tcut = true;\n\tfor(int i=0; i<line.length()-1; i++){\n\t\tif(line[i] != line[i+1]) cut = false;\n\t}\n\tif(cut){\n\t\tvector<string> cats;\n\t\tcats.reserve(30*30*20*20);\n\t\tfor(int i=0; i<N; i++){\n\t\t\tfor(int j=0; j<N; j++){\n\t\t\t\tcats.push_back(piece[i] + piece[j]);\n\t\t\t\tfor(int k=0; k<L; k++){\n\t\t\t\t\tstring pre = piece[i].substr(k);\n\t\t\t\t\tfor(int l=0; l<L; l++){\n\t\t\t\t\t\tstring post = piece[j].substr(0,pre.length());\n\t\t\t\t\t\tif(pre == post){\n\t\t\t\t\t\t\tcats.push_back(piece[i] + piece[j].substr(pre.length()));\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tsort(cats.begin(), cats.end());\n\t\tcats.erase(unique(cats.begin(), cats.end()), cats.end());\n\t\twidth = 1<<10;\n\t\tfor(typeof(cats.begin()) itr = cats.begin(); itr != cats.end(); itr++){\n\t\t\tstring t = *itr;\n\t\t\tfor(int i=0; i<t.length(); i++)if(t[i] != line[0]){\n\t\t\t\tpreok[i] = true;\n\t\t\t\tpreok2[i][t[i]] = true;\n\t\t\t}\n\t\t\tfor(int i=0; i<t.length(); i++)if(t[t.length()-1-i] != line[0]){\n\t\t\t\tpostok[i] = true;\n\t\t\t\tpostok2[i][t[t.length()-1-i]] = true;\n\t\t\t}\n\t\t\tint pre = t.find_first_not_of(line[0]), post = t.find_last_not_of(line[0]);\n\t\t\tif(pre != post){\n\t\t\t\twidth = min(width, post - pre - 1);\n\t\t\t\tprewidth[t[post]] = max(prewidth[t[post]], post - pre - 1);\n\t\t\t\tpostwidth[t[pre]] = max(postwidth[t[pre]], post - pre - 1);\n\t\t\t}\n\t\t}\n\t\tif(width == 1<<10) width = 0;\n\t\tprecut = L;\n\t\tfor(int i=0; i<N; i++){\n\t\t\tfor(int j=0; j<L; j++)if(piece[i][j] != line[0]){\n\t\t\t\tprecut = min(precut, j);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tpostcut = L;\n\t\tfor(int i=0; i<N; i++){\n\t\t\tfor(int j=0; j<L; j++)if(piece[i][L-1-j] != line[0]){\n\t\t\t\tpostcut = min(postcut, j);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(0){\n\t\t\tcout << width << endl;\n\t\t\tcout << precut << endl;\n\t\t\tcout << postcut << endl;\n\t\t}\n\t}\n\tfor(int i=0; i<N; i++){\n\t\tfor(int j=1; j<L-1; j++){\n\t\t\tprecheck[piece[i][j-1]][piece[i][j]][piece[i][j+1]] = true;\n\t\t}\n\t}\n\tfor(int i=0; i<N; i++){\n\t\tfor(int k=0; k<N; k++){\n\t\t\tprecheck[piece[i][L-2]][piece[i][L-1]][piece[k][0]] = true;\n\t\t\tprecheck[piece[k][L-1]][piece[i][0]][piece[i][1]] = true;\n\t\t}\n\t}\n\tfor(int i=0; i<N; i++){\n\t\ths.push_back(hash_func(piece[i]));\n\t}\n\tsort(hs.begin(), hs.end());\n\tif(check(line)){\n\t\tadd_ans(line);\n\t}\n\tif(d<1) return ;\n\tgenerate(line, d1);\n\tfor(typeof(d1.begin()) itr = d1.begin(); itr != d1.end(); itr++){\n\t\tstring tmp = *itr;\n\t\tif(check(tmp)) add_ans(tmp);\n\t}\n\tif(d<2) return ;\n\tfor(typeof(d1.begin()) itr = d1.begin(); itr != d1.end(); itr++){\n\t\tstring tmp = *itr;\n\t\tgenerate(tmp, d2);\n\t}\n\tif(!cut || width==0)subsolve();\n}\n\nvoid print(){\n\tprintf(\"%d\\n\", (int)ans2.size());\n\tif(ans2.size() <= 5){\n\t\tfor(typeof(ans.begin()) itr = ans.begin(); itr != ans.end(); itr++){\n\t\t\tputs(itr->c_str());\n\t\t\t//cout << *itr << endl;\n\t\t}\n\t}\n}\n\nvoid init(){\n\tcut = false;\n\tplane = \"\";\n\td1.clear();\n\td2.clear();\n\tans.clear();\n\tans2.clear();\n\ths.clear();\n\tpiece.clear();\n\tfor(int i=0; i<50; i++) preok[i] = postok[i] = false;\n\tfor(int i=0; i<0x100; i++) prewidth[i] = postwidth[i] = 0;\n\tfor(int i=0; i<50; i++)for(int j=0; j<0x100; j++) preok2[i][j] = postok2[i][j] = false;\n\tfor(int i=0; i<0x100; i++){\n\t\tfor(int j=0; j<0x100; j++){\n\t\t\tfor(int k=0; k<0x100; k++){\n\t\t\t\tprecheck[i][j][k] = false;\n\t\t\t}\n\t\t}\n\t}\n}\n\n\nint main(){\n\tbs.push_back(1);\n\tfor(int i=0; i<60; i++){\n\t\tbs.push_back(bs.back()*base);\n\t}\n\twhile(scanf(\"%d%d \",&d,&N)){\n\t\tif(d==0 && N==0) break;\n\t\tinit();\n\t\tgetline(cin,line);\n\t\tpiece.clear();\n\t\tfor(int i=0; i<N; i++){\n\t\t\tstring t;\n\t\t\tgetline(cin,t);\n\t\t\tpiece.push_back(t);\n\t\t}\n\t\tL = piece[0].size();\n\t\tsolve();\n\t\tprint();\n\t}\n\tfflush(stdout);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 7460, "memory_kb": 21000, "score_of_the_acc": -1.0927, "final_rank": 16 }, { "submission_id": "aoj_1170_187422", "code_snippet": "// ACM-ICPC‘“à—\\‘I2010 F. ŒÃ‚¢‹L‰¯\n\n#include <iostream>\n#include <string>\n#include <vector>\n#include <set>\n#include <algorithm>\n#include <cstring>\n\nusing namespace std;\n\nconst int INF = 100000000;\n\nint d;\nstring mes, cur;\nvector<string> piece;\nvector<int> connect[30][20];\nvector<string> ans;\nset<string> mem[43];\nint dp[43][43];\nint cost[30][20];\nint curdist;\n\nint getMinedit(string s, string t){\n\tint n = s.size(), m = t.size();\n\tint cost[43], newcost[43];\n\tfor(int i=0;i<=n;i++) cost[i] = 0;\n\tfor(int j=1;j<=m;j++){\n\t\tnewcost[0] = j;\n\t\tfor(int i=1;i<=n;i++){\n\t\t\tnewcost[i] = 1+min(newcost[i-1],cost[i]);\n\t\t\tnewcost[i] = min(newcost[i],cost[i-1]+(s[i-1]!=t[j-1]));\n\t\t}\n\t\tmemcpy(cost, newcost, sizeof(cost));\n\t}\n\treturn *min_element(cost, cost+n+1);\n}\n\nbool editDist(int s, int e){\n\tfor(int i=s+1;i<=e;i++){\n\t\tcurdist = INF;\n\t\tfor(int j=max(1,i-d);j<=min((int)mes.size(),i+d);j++){\n\t\t\tif(cur[i-1]==mes[j-1]) dp[i][j] = dp[i-1][j-1];\n\t\t\telse {\n\t\t\t\tdp[i][j] = dp[i-1][j-1]+1;\n\t\t\t\tdp[i][j] = min(dp[i][j], dp[i-1][j]+1);\n\t\t\t\tdp[i][j] = min(dp[i][j], dp[i][j-1]+1);\n\t\t\t}\n\t\t\tcurdist = min(curdist, dp[i][j]);\n\t\t}\n\t\tif(curdist > d) return false;\n\t}\n\treturn true;\n}\n\nvoid dfs(int pIdx, int p1, int p2){\n\tint len = piece[0].size();\n\tint csize = cur.size();\n\tif(dp[csize][mes.size()] <= d) ans.push_back(cur);\n\tint start = min(len-1, csize-p2-1);\n\tcur += string(len-1-start, ' ');\n\tint ccost = curdist;\n\tfor(int i=start;i>=0;i--){\n\t\tint nsize = csize+len-i;\n\t\tif(nsize > mes.size() + d) break;\n\t\tcur += ' ';\n\t\tfor(int j=0;j<connect[pIdx][i].size();j++){\n\t\t\tif(ccost + cost[connect[pIdx][i][j]][i] > d) continue;\n\t\t\tbool flag = true;\n\t\t\tfor(int k=i;k<len;k++){\n\t\t\t\tcur[csize+k-i] = piece[connect[pIdx][i][j]][k];\n\t\t\t\tif(!editDist(csize+k-i, csize+k-i+1)){\n\t\t\t\t\tflag = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!flag) continue;\n\t\t\tif(mem[nsize].count(cur)) continue;\n\t\t\tmem[nsize].insert(cur);\n\t\t\tdfs(connect[pIdx][i][j], nsize, p1);\n\t\t}\n\t}\n\tcur = cur.substr(0, csize);\n}\n\nint main(){\n\tint n, len;\n\tfor(int i=0;i<=42;i++) dp[i][0] = dp[0][i] = i;\n\twhile(cin >> d >> n, n){\n\t\tcin >> mes;\n\t\tpiece.clear();\n\t\tfor(int i=0;i<n;i++){\n\t\t\tstring str; cin >> str;\n\t\t\tif(getMinedit(mes, str) > d) continue;\n\t\t\tpiece.push_back(str);\n\t\t}\n\t\tsort(piece.begin(), piece.end());\n\t\tpiece.erase(unique(piece.begin(), piece.end()), piece.end());\n\t\tlen = piece[0].size();\n\t\tfor(int i=1;i<=mes.size()+d;i++)\n\t\t\tfor(int j=1;j<=mes.size()+d;j++)\n\t\t\t\tif(abs(i-j) > d) dp[i][j] = INF;\n\t\tfor(int i=0;i<piece.size();i++){\n\t\t\tfor(int j=0;j<len;j++){\n\t\t\t\tconnect[i][j].clear();\n\t\t\t\tfor(int k=0;k<piece.size();k++){\n\t\t\t\t\tif(piece[i].substr(len-j) == piece[k].substr(0,j)){\n\t\t\t\t\t\tconnect[i][j].push_back(k);\n\t\t\t\t\t\tcost[k][j] = getMinedit(mes, piece[k].substr(j));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<=mes.size()+d;i++)\n\t\t\tmem[i].clear();\n\t\tans.clear();\n\t\tfor(int i=0;i<piece.size();i++){\n\t\t\tcur = piece[i];\n\t\t\tif(!editDist(0, len)) continue;\n\t\t\tdfs(i, len, 0);\n\t\t}\n\t\tsort(ans.begin(), ans.end());\n\t\tcout << ans.size() << endl;\n\t\tif(ans.size() <= 5){\n\t\t\tfor(int i=0;i<ans.size();i++)\n\t\t\t\tcout << ans[i] << endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 2200, "memory_kb": 15000, "score_of_the_acc": -0.252, "final_rank": 3 }, { "submission_id": "aoj_1170_141296", "code_snippet": "#include <iostream>\n#include <cstring>\n#include <string>\n#include <vector>\n#include <set>\n#include <algorithm>\nusing namespace std;\n\nint d, n;\nstring data;\nvector<string> piece;\n\nint L, M;\nset<string> results;\nvector< vector< pair<int,int> > > nexts;\n\nvoid init() {\n\tL = piece[0].length();\n\tM = data.length();\n\tresults.clear();\n\tnexts = vector< vector< pair<int,int> > >(n+1);\n\tfor (int i = 0; i < n; ++ i) {\n\t\tnexts[n].push_back(make_pair(i,0));\n\t\tfor (int k = L-1; k > 0; -- k) {\n\t\t\tfor (int j = 0; j < n; ++ j) {\n\t\t\t\tfor (int p = 0; p < k; ++ p) {\n\t\t\t\t\tif (piece[i][L-k+p] != piece[j][p]) goto next;\n\t\t\t\t}\n\t\t\t\tnexts[i].push_back(make_pair(j, k));\n\t\t\t\tnext:;\n\t\t\t}\n\t\t}\n\t\tfor (int j = 0; j < n; ++ j) {\n\t\t\tnexts[i].push_back(make_pair(j, 0));\n\t\t}\n\t}\n}\n\nchar buf[100];\nint dist[100][100];\nset<string> visited;\n\nvoid f(int prev, int pos, int a, int b) {\n\tbuf[pos] = 0;\n\tif (!visited.insert(buf).second) return;\n\tif (a <= M && M <= b && dist[pos][M] <= d) results.insert(buf);\n\tif (pos == M+d) return;\n\t\n\tfor (int i = 0; i < nexts[prev].size(); ++ i) {\n\t\tif (pos + L-nexts[prev][i].second > M+d) break;\n\t\tconst string &s = piece[ nexts[prev][i].first ];\n\t\tint aa = a, bb = b;\n\t\tfor (int j = 0; j + nexts[prev][i].second < L; ++ j) {\n\t\t\tbuf[pos+j] = s[j + nexts[prev][i].second];\n\t\t\tint x = 1<<30, y = -1;\n\t\t\tif (aa-1 > 0) dist[pos+j+1][aa-1] = 1<<30;\n\t\t\tdist[pos+j][bb+1] = 1<<30;\n\t\t\tfor (int k = max(0,aa-1); k < M && k <= bb; ++ k) {\n\t\t\t\tint cost = 1;\n\t\t\t\tif (buf[pos+j] == data[k]) cost = 0;\n\t\t\t\tdist[pos+j+1][k+1] = min(min(\n\t\t\t\t\tdist[pos+j][k+1] + 1,\n\t\t\t\t\tdist[pos+j+1][k] + 1),\n\t\t\t\t\tdist[pos+j][k] + cost\n\t\t\t\t);\n\t\t\t\tif (dist[pos+j+1][k+1] <= d) {\n\t\t\t\t\tx = min(x, k+1);\n\t\t\t\t\ty = max(y, k+1);\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (x > y) goto next;\n\t\t\taa = x; bb = y;\n\t\t}\n\t\tf(nexts[prev][i].first, pos + L-nexts[prev][i].second, aa, bb);\n\t\tnext:;\n\t}\n}\n\nvoid calc() {\n\tinit();\n\tmemset(dist, 0, sizeof(dist));\n\tfor (int i = 0; i <= M+d; ++ i) {\n\t\tdist[i][0] = i;\n\t}\n\tfor (int i = 0; i <= M; ++ i) {\n\t\tdist[0][i] = i;\n\t}\n\tvisited.clear();\n\tf(n, 0, 0, 2);\n\tcout << results.size() << endl;\n\tif (results.size() <= 5) {\n\t\tfor (set<string>::iterator i = results.begin(); i != results.end(); ++ i) {\n\t\t\tcout << *i << endl;\n\t\t}\n\t}\n}\n\nint main() {\n\tfor (;;) {\n\t\tcin >> d >> n;\n\t\tif (d == 0 && n == 0) break;\n\t\tcin >> data;\n\t\tpiece = vector<string>(n);\n\t\tfor (int i = 0; i < n; ++ i) {\n\t\t\tcin >> piece[i];\n\t\t}\n\t\tcalc();\n\t}\n}", "accuracy": 1, "time_ms": 4740, "memory_kb": 16000, "score_of_the_acc": -0.643, "final_rank": 12 }, { "submission_id": "aoj_1170_85914", "code_snippet": "// ACM-ICPC‘“à—\\‘I2010 F. ŒÃ‚¢‹L‰¯\n\n#include <iostream>\n#include <string>\n#include <vector>\n#include <set>\n#include <algorithm>\n#include <string.h>\n\nusing namespace std;\n\nconst int INF = 100000000;\n\nint d;\nstring mes, cur;\nvector<string> piece;\nvector<int> connect[30][20];\nvector<string> ans;\nset<string> mem[43];\nint dp[43][43];\nint cost[30][20];\nint curdist;\n\nint getMinedit(string s, string t){\n\tint n = s.size(), m = t.size();\n\tint cost[43], newcost[43];\n\tfor(int i=0;i<=n;i++) cost[i] = 0;\n\tfor(int j=1;j<=m;j++){\n\t\tnewcost[0] = j;\n\t\tfor(int i=1;i<=n;i++){\n\t\t\tnewcost[i] = 1+min(newcost[i-1],cost[i]);\n\t\t\tnewcost[i] = min(newcost[i],cost[i-1]+(s[i-1]!=t[j-1]));\n\t\t}\n\t\tmemcpy(cost, newcost, sizeof(cost));\n\t}\n\treturn *min_element(cost, cost+n+1);\n}\n\nbool editDist(int s, int e){\n\tfor(int i=s+1;i<=e;i++){\n\t\tcurdist = INF;\n\t\tfor(int j=max(1,i-d);j<=min((int)mes.size(),i+d);j++){\n\t\t\tif(cur[i-1]==mes[j-1]) dp[i][j] = dp[i-1][j-1];\n\t\t\telse {\n\t\t\t\tdp[i][j] = dp[i-1][j-1]+1;\n\t\t\t\tdp[i][j] = min(dp[i][j], dp[i-1][j]+1);\n\t\t\t\tdp[i][j] = min(dp[i][j], dp[i][j-1]+1);\n\t\t\t}\n\t\t\tcurdist = min(curdist, dp[i][j]);\n\t\t}\n\t\tif(curdist > d) return false;\n\t}\n\treturn true;\n}\n\nvoid dfs(int pIdx, int p1, int p2){\n\tint len = piece[0].size();\n\tint csize = cur.size();\n\tif(dp[csize][mes.size()] <= d) ans.push_back(cur);\n\tint start = min(len-1, csize-p2-1);\n\tcur += string(len-1-start, ' ');\n\tint ccost = curdist;\n\tfor(int i=start;i>=0;i--){\n\t\tint nsize = csize+len-i;\n\t\tif(nsize > mes.size() + d) break;\n\t\tcur += ' ';\n\t\tfor(int j=0;j<connect[pIdx][i].size();j++){\n\t\t\tif(ccost + cost[connect[pIdx][i][j]][i] > d) continue;\n\t\t\tbool flag = true;\n\t\t\tfor(int k=i;k<len;k++){\n\t\t\t\tcur[csize+k-i] = piece[connect[pIdx][i][j]][k];\n\t\t\t\tif(!editDist(csize+k-i, csize+k-i+1)){\n\t\t\t\t\tflag = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!flag) continue;\n\t\t\tif(mem[nsize].count(cur)) continue;\n\t\t\tmem[nsize].insert(cur);\n\t\t\tdfs(connect[pIdx][i][j], nsize, p1);\n\t\t}\n\t}\n\tcur = cur.substr(0, csize);\n}\n\nint main(){\n\tint n, len;\n\tfor(int i=0;i<=42;i++) dp[i][0] = dp[0][i] = i;\n\twhile(cin >> d >> n, n){\n\t\tcin >> mes;\n\t\tpiece.clear();\n\t\tfor(int i=0;i<n;i++){\n\t\t\tstring str; cin >> str;\n\t\t\tif(getMinedit(mes, str) > d) continue;\n\t\t\tpiece.push_back(str);\n\t\t}\n\t\tsort(piece.begin(), piece.end());\n\t\tpiece.erase(unique(piece.begin(), piece.end()), piece.end());\n\t\tlen = piece[0].size();\n\t\tfor(int i=1;i<=mes.size()+d;i++)\n\t\t\tfor(int j=1;j<=mes.size()+d;j++)\n\t\t\t\tif(abs(i-j) > d) dp[i][j] = INF;\n\t\tfor(int i=0;i<piece.size();i++){\n\t\t\tfor(int j=0;j<len;j++){\n\t\t\t\tconnect[i][j].clear();\n\t\t\t\tfor(int k=0;k<piece.size();k++){\n\t\t\t\t\tif(piece[i].substr(len-j) == piece[k].substr(0,j)){\n\t\t\t\t\t\tconnect[i][j].push_back(k);\n\t\t\t\t\t\tcost[k][j] = getMinedit(mes, piece[k].substr(j));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<=mes.size()+d;i++)\n\t\t\tmem[i].clear();\n\t\tans.clear();\n\t\tfor(int i=0;i<piece.size();i++){\n\t\t\tcur = piece[i];\n\t\t\tif(!editDist(0, len)) continue;\n\t\t\tdfs(i, len, 0);\n\t\t}\n\t\tsort(ans.begin(), ans.end());\n\t\tcout << ans.size() << endl;\n\t\tif(ans.size() <= 5){\n\t\t\tfor(int i=0;i<ans.size();i++)\n\t\t\t\tcout << ans[i] << endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 2200, "memory_kb": 15000, "score_of_the_acc": -0.252, "final_rank": 3 }, { "submission_id": "aoj_1170_85910", "code_snippet": "// ACM-ICPC‘“à—\\‘I2010 F. ŒÃ‚¢‹L‰¯\n\n#include <iostream>\n#include <string>\n#include <vector>\n#include <set>\n#include <algorithm>\n\nusing namespace std;\n\nconst int INF = 100000000;\n\nint d;\nstring mes, cur;\nvector<string> piece;\nvector<int> connect[30][20];\nvector<string> ans;\nset<string> mem[43];\nint dp[43][43];\n\nbool editDist(int s, int e){\n\tfor(int i=s+1;i<=e;i++){\n\t\tint m = INF;\n\t\tfor(int j=max(1,i-d);j<=min((int)mes.size(),i+d);j++){\n\t\t\tif(cur[i-1]==mes[j-1]) dp[i][j] = dp[i-1][j-1];\n\t\t\telse {\n\t\t\t\tdp[i][j] = dp[i-1][j-1]+1;\n\t\t\t\tdp[i][j] = min(dp[i][j], dp[i-1][j]+1);\n\t\t\t\tdp[i][j] = min(dp[i][j], dp[i][j-1]+1);\n\t\t\t}\n\t\t\tm = min(m, dp[i][j]);\n\t\t}\n\t\tif(m > d) return false;\n\t}\n\treturn true;\n}\n\nvoid dfs(int pIdx, int p1, int p2){\n\tint len = piece[0].size();\n\tint csize = cur.size();\n\tif(dp[csize][mes.size()] <= d) ans.push_back(cur);\n\tif(len-1 != min(len-1, csize-p2-1))\n\t\tcur += string(len-1-(csize-p2-1), ' ');\n\tfor(int i=min(len-1, csize-p2-1);i>=0;i--){\n\t\tint nsize = csize+len-i;\n\t\tif(nsize > mes.size() + d) break;\n\t\tcur += ' ';\n\t\tfor(int j=0;j<connect[pIdx][i].size();j++){\n\t\t\tbool flag = true;\n\t\t\tfor(int k=i;k<len;k++){\n\t\t\t\tcur[csize+k-i] = piece[connect[pIdx][i][j]][k];\n\t\t\t\tif(!editDist(csize+k-i, csize+k-i+1)){\n\t\t\t\t\tflag = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!flag) continue;\n\t\t\tif(mem[nsize].count(cur)) continue;\n\t\t\tmem[nsize].insert(cur);\n\t\t\tdfs(connect[pIdx][i][j], nsize, p1);\n\t\t}\n\t}\n\tcur = cur.substr(0, csize);\n}\n\nint main(){\n\tint n, len;\n\tfor(int i=0;i<=42;i++) dp[i][0] = dp[0][i] = i;\n\twhile(cin >> d >> n, n){\n\t\tcin >> mes;\n\t\tpiece.clear();\n\t\tfor(int i=0;i<n;i++){\n\t\t\tstring str; cin >> str;\n\t\t\tpiece.push_back(str);\n\t\t}\n\t\tsort(piece.begin(), piece.end());\n\t\tpiece.erase(unique(piece.begin(), piece.end()), piece.end());\n\t\tlen = piece[0].size();\n\t\tfor(int i=1;i<=mes.size()+d;i++)\n\t\t\tfor(int j=1;j<=mes.size()+d;j++)\n\t\t\t\tif(abs(i-j) > d) dp[i][j] = INF;\n\t\tfor(int i=0;i<piece.size();i++){\n\t\t\tfor(int j=0;j<len;j++){\n\t\t\t\tconnect[i][j].clear();\n\t\t\t\tfor(int k=0;k<piece.size();k++){\n\t\t\t\t\tif(piece[i].substr(len-j) == piece[k].substr(0,j))\n\t\t\t\t\t\tconnect[i][j].push_back(k);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<=mes.size()+d;i++)\n\t\t\tmem[i].clear();\n\t\tans.clear();\n\t\tfor(int i=0;i<piece.size();i++){\n\t\t\tcur = piece[i];\n\t\t\tif(!editDist(0, len)) continue;\n\t\t\tdfs(i, len, 0);\n\t\t}\n\t\tsort(ans.begin(), ans.end());\n\t\tcout << ans.size() << endl;\n\t\tif(ans.size() <= 5){\n\t\t\tfor(int i=0;i<ans.size();i++)\n\t\t\t\tcout << ans[i] << endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 2620, "memory_kb": 15000, "score_of_the_acc": -0.3153, "final_rank": 7 }, { "submission_id": "aoj_1170_85840", "code_snippet": "// ACM-ICPC‘“à—\\‘I2010 F. ŒÃ‚¢‹L‰¯\n\n#include <iostream>\n#include <string>\n#include <vector>\n#include <set>\n#include <algorithm>\n\nusing namespace std;\n\nconst int INF = 100000000;\n\nint d;\nstring mes, cur;\nvector<string> piece;\nvector<int> connect[30][20];\nvector<string> ans;\nset<string> mem[43];\nint dp[43][43];\n\nbool editDist(int s, int e){\n\tfor(int i=s+1;i<=e;i++){\n\t\tint m = INF;\n\t\tfor(int j=max(1,i-d);j<=min((int)mes.size(),i+d);j++){\n\t\t\tif(cur[i-1]==mes[j-1]) dp[i][j] = dp[i-1][j-1];\n\t\t\telse {\n\t\t\t\tdp[i][j] = dp[i-1][j-1]+1;\n\t\t\t\tdp[i][j] = min(dp[i][j], dp[i-1][j]+1);\n\t\t\t\tdp[i][j] = min(dp[i][j], dp[i][j-1]+1);\n\t\t\t}\n\t\t\tm = min(m, dp[i][j]);\n\t\t}\n\t\tif(m > d) return false;\n\t}\n\treturn true;\n}\n\nvoid dfs(int pIdx){\n\tint len = piece[0].size();\n\tint csize = cur.size();\n\tif(dp[csize][mes.size()] <= d) ans.push_back(cur);\n\tfor(int j=len-1;j>=0;j--){\n\t\tint nsize = csize + len - j;\n\t\tif(nsize > mes.size() + d) break;\n\t\tcur += ' ';\n\t\tfor(int i=0;i<connect[pIdx][j].size();i++){\n\t\t\tbool flag = true;\n\t\t\tfor(int k=j;k<len;k++){\n\t\t\t\tcur[csize+k-j] = piece[connect[pIdx][j][i]][k];\n\t\t\t\tif(!editDist(csize+k-j, csize+k-j+1)){\n\t\t\t\t\tflag = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!flag) continue;\n\t\t\tif(mem[nsize].count(cur)) continue;\n\t\t\tmem[nsize].insert(cur);\n\t\t\tdfs(connect[pIdx][j][i]);\n\t\t}\n\t}\n\tcur = cur.substr(0, csize);\n}\n\nint main(){\n\tint n, len;\n\tfor(int i=0;i<=42;i++) dp[i][0] = dp[0][i] = i;\n\twhile(cin >> d >> n, n){\n\t\tcin >> mes;\n\t\tpiece.clear();\n\t\tfor(int i=0;i<n;i++){\n\t\t\tstring str; cin >> str;\n\t\t\tpiece.push_back(str);\n\t\t}\n\t\tsort(piece.begin(), piece.end());\n\t\tpiece.erase(unique(piece.begin(), piece.end()), piece.end());\n\t\tlen = piece[0].size();\n\t\tfor(int i=1;i<=mes.size()+d;i++)\n\t\t\tfor(int j=1;j<=mes.size()+d;j++)\n\t\t\t\tif(abs(i-j) > d) dp[i][j] = INF;\n\t\tfor(int i=0;i<piece.size();i++){\n\t\t\tfor(int k=0;k<len;k++){\n\t\t\t\tconnect[i][k].clear();\n\t\t\t\tfor(int j=0;j<piece.size();j++){\n\t\t\t\t\tif(piece[i].substr(len-k) == piece[j].substr(0,k))\n\t\t\t\t\t\tconnect[i][k].push_back(j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<=mes.size()+d;i++)\n\t\t\tmem[i].clear();\n\t\tans.clear();\n\t\tfor(int i=0;i<piece.size();i++){\n\t\t\tcur = piece[i];\n\t\t\tif(!editDist(0, len)) continue;\n\t\t\tdfs(i);\n\t\t}\n\t\tsort(ans.begin(), ans.end());\n\t\tcout << ans.size() << endl;\n\t\tif(ans.size() <= 5){\n\t\t\tfor(int i=0;i<ans.size();i++)\n\t\t\t\tcout << ans[i] << endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 3880, "memory_kb": 15000, "score_of_the_acc": -0.5053, "final_rank": 9 }, { "submission_id": "aoj_1170_85836", "code_snippet": "// ACM-ICPC‘“à—\\‘I2010 F. ŒÃ‚¢‹L‰¯\n\n#include <iostream>\n#include <string>\n#include <vector>\n#include <set>\n#include <algorithm>\n\nusing namespace std;\n\nconst int INF = 100000000;\n\nint d;\nstring mes, cur;\nvector<string> piece;\nvector<int> connect[30][20];\nvector<string> ans;\nset<string> mem[43];\nint dp[43][43];\nint cnt = 0;\n\nbool editDist(int s, int e){\n\tfor(int i=s+1;i<=e;i++){\n\t\tint m = INF;\n\t\tfor(int j=max(1,i-d);j<=min((int)mes.size(),i+d);j++){\n\t\t\tif(cur[i-1]==mes[j-1]) dp[i][j] = dp[i-1][j-1];\n\t\t\telse {\n\t\t\t\tdp[i][j] = dp[i-1][j-1]+1;\n\t\t\t\tdp[i][j] = min(dp[i][j], dp[i-1][j]+1);\n\t\t\t\tdp[i][j] = min(dp[i][j], dp[i][j-1]+1);\n\t\t\t}\n\t\t\tm = min(m, dp[i][j]);\n\t\t}\n\t\tif(m > d) return false;\n\t}\n\treturn true;\n}\n\nvoid solve(int pIdx){\n\tcnt++;\n\tint len = piece[0].size();\n\tint csize = cur.size();\n\tfor(int j=len-1;j>=0;j--){\n\t\tint nsize = csize + len - j;\n\t\tif(nsize > mes.size() + d) break;\n\t\tcur += ' ';\n\t\tfor(int i=0;i<connect[pIdx][j].size();i++){\n\t\t\tbool flag = true;\n\t\t\tfor(int k=j;k<len;k++){\n\t\t\t\tcur[csize+k-j] = piece[connect[pIdx][j][i]][k];\n\t\t\t\tif(!editDist(csize+k-j, csize+k-j+1)){\n\t\t\t\t\tflag = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!flag) continue;\n\t\t\tif(mem[nsize].count(cur)) continue;\n\t\t\tmem[nsize].insert(cur);\n//\t\t\tif(!editDist(csize, nsize)) continue;\n\t\t\tif(mes.size()-d <= nsize && nsize <= mes.size()+d && dp[nsize][mes.size()] <= d)\n\t\t\t\tans.push_back(cur);\n\t\t\tsolve(connect[pIdx][j][i]);\n\t\t}\n\t}\n\tcur = cur.substr(0, csize);\n}\n\nint main(){\n\tint n, len;\n\tfor(int i=0;i<=42;i++) dp[i][0] = dp[0][i] = i;\n\twhile(cin >> d >> n, n){\n\t\tcin >> mes;\n\t\tpiece.clear();\n\t\tfor(int i=0;i<n;i++){\n\t\t\tstring str; cin >> str;\n\t\t\tpiece.push_back(str);\n\t\t}\n\t\tsort(piece.begin(), piece.end());\n\t\tpiece.erase(unique(piece.begin(), piece.end()), piece.end());\n\t\tlen = piece[0].size();\n\t\tfor(int i=1;i<=mes.size()+d;i++)\n\t\t\tfor(int j=1;j<=mes.size()+d;j++)\n\t\t\t\tif(abs(i-j) > d) dp[i][j] = INF;\n\t\tfor(int i=0;i<piece.size();i++){\n\t\t\tfor(int k=0;k<len;k++){\n\t\t\t\tconnect[i][k].clear();\n\t\t\t\tfor(int j=0;j<piece.size();j++){\n\t\t\t\t\tif(piece[i].substr(len-k) == piece[j].substr(0,k))\n\t\t\t\t\t\tconnect[i][k].push_back(j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<=mes.size()+d;i++)\n\t\t\tmem[i].clear();\n\t\tans.clear();\n\t\tcnt = 0;\n\t\tfor(int i=0;i<piece.size();i++){\n\t\t\tcur = piece[i];\n\t\t\tif(!editDist(0, len)) continue;\n\t\t\tif(mes.size()-d <= cur.size() && cur.size() <= mes.size()+d && dp[cur.size()][mes.size()] <= d)\n\t\t\t\tans.push_back(cur);\n\t\t\tsolve(i);\n\t\t}\n\t\tsort(ans.begin(), ans.end());\n\t\tans.erase(unique(ans.begin(), ans.end()), ans.end());\n\t\tcout << ans.size() << endl;\n\t\tif(ans.size() <= 5){\n\t\t\tfor(int i=0;i<ans.size();i++)\n\t\t\t\tcout << ans[i] << endl;\n\t\t}\n\t}\n}\n\n\n/*\nstring mes;\nvector<string> piece;\nvector< pair<int,int> > connect[30];\nvector<string> ans;\nset<string> mem;\nint dp[43][43];\nint cnt = 0;\n\nbool editDist(string cur, int s, int e, int d){\n\tfor(int i=s+1;i<=e;i++){\n\t\tint m = INF;\n\t\tfor(int j=max(1,i-d);j<=min((int)mes.size(),i+d);j++){\n\t\t\tif(cur[i-1]==mes[j-1]) dp[i][j] = dp[i-1][j-1];\n\t\t\telse {\n\t\t\t\tdp[i][j] = dp[i-1][j-1]+1;\n\t\t\t\tdp[i][j] = min(dp[i][j], dp[i-1][j]+1);\n\t\t\t\tdp[i][j] = min(dp[i][j], dp[i][j-1]+1);\n\t\t\t}\n\t\t\tm = min(m, dp[i][j]);\n\t\t}\n\t\tif(m > d) return false;\n\t}\n\treturn true;\n}\n\nvoid solve(string cur, int d, int pIdx, int p1, int p2){\n\tcnt++;\n\tint len = piece[0].size();\n\tfor(int i=0;i<connect[pIdx].size();i++){\n\t\tint nsize = cur.size() + len - connect[pIdx][i].second;\n\t\tif(nsize > mes.size() + d) continue;\n//\t\tstring nxt = cur + piece[connect[pIdx][i].first].substr(connect[pIdx][i].second);\n\t\tif(mem.count(nxt)) continue;\n\t\tmem.insert(nxt);\n\t\tif(!editDist(nxt, cur.size(), nxt.size(), d)) continue;\n\t\tif(mes.size()-d <= nxt.size() && nxt.size() <= mes.size()+d && dp[nxt.size()][mes.size()] <= d)\n\t\t\tans.push_back(nxt);\n\t\tsolve(nxt, d, connect[pIdx][i].first, p2, nxt.size());\n\t}\n}\n\nint main(){\n\tint d, n, len;\n\tfor(int i=0;i<=42;i++) dp[i][0] = dp[0][i] = i;\n\twhile(cin >> d >> n, n){\n\t\tcin >> mes;\n\t\tpiece.clear();\n\t\tfor(int i=0;i<n;i++){\n\t\t\tstring str; cin >> str;\n\t\t\tpiece.push_back(str);\n\t\t}\n\t\tsort(piece.begin(), piece.end());\n\t\tpiece.erase(unique(piece.begin(), piece.end()), piece.end());\n\t\tlen = piece[0].size();\n\t\tfor(int i=1;i<=mes.size()+d;i++)\n\t\t\tfor(int j=1;j<=mes.size()+d;j++)\n\t\t\t\tif(abs(i-j) > d) dp[i][j] = INF;\n\t\tfor(int i=0;i<piece.size();i++){\n\t\t\tconnect[i].clear();\n\t\t\tfor(int j=0;j<piece.size();j++){\n\t\t\t\tconnect[i].push_back(make_pair(j,0));\n\t\t\t\tfor(int k=1;k<len;k++){\n\t\t\t\t\tif(piece[i].substr(len-k) == piece[j].substr(0,k))\n\t\t\t\t\t\tconnect[i].push_back(make_pair(j,k));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tmem.clear();\n\t\tstring cur;\n\t\tans.clear();\n\t\tcnt = 0;\n\t\tfor(int i=0;i<piece.size();i++){\n\t\t\tcur = piece[i];\n\t\t\tif(!editDist(cur, 0, len, d)) continue;\n\t\t\tif(mes.size()-d <= cur.size() && cur.size() <= mes.size()+d && dp[cur.size()][mes.size()] <= d)\n\t\t\t\tans.push_back(cur);\n\t\t\tsolve(cur, d, i, len, 0);\n\t\t}\n\t\tsort(ans.begin(), ans.end());\n\t\tans.erase(unique(ans.begin(), ans.end()), ans.end());\n\t\tcout << ans.size() << endl;\n\t\tif(ans.size() <= 5){\n\t\t\tfor(int i=0;i<ans.size();i++)\n\t\t\t\tcout << ans[i] << endl;\n\t\t}\n\t}\n}\n*/", "accuracy": 1, "time_ms": 4060, "memory_kb": 15000, "score_of_the_acc": -0.5325, "final_rank": 10 } ]
aoj_1177_cpp
Watchdog Corporation In Northern Kyushu, you are running a company which rents watchdogs in response to the customers' order. The distinguishing point of your service is that you also install fences to enhance the performance of watchdogs. The dog is put on a leash, which is tied up to a peg. You are installing fences at the border of the dog's reach, so that strangers approaching the fence are taken care of by your dog. There may be a rectangular building near the dog; the dog cannot enter the building, but can go around it as long as the length of the leash permits, as in Figure F-1. You do not need fences along the building's wall. Figure F-1: Example fence layouts (some parts of the fences are omitted.) Given the length of the leash and the position and the size of the building, your program should calculate the length of the fence. Input The input consists of multiple datasets each consisting of five integers in a line of the following format. len x 1 y 1 x 2 y 2 len indicates the length of the leash. x 1 , y 1 , x 2 and y 2 indicate the size and position of the building in that a point with coordinate ( x , y ) such that x 1 < x < x 2 and y 1 < y < y 2 is contained in the building. This means that the building's walls are parallel to either the X-axis or Y-axis. The peg is located on the origin. You may assume that 0 < len ≤ 100, −100 ≤ x 1 < x 2 ≤ 100 and −100 ≤ y 1 < y 2 ≤ 100. You may also assume that the peg is located apart from the building (that is, neither inside nor on the border of the building). The end of the input is indicated by a line containing five zeros. Output For each dataset, output the total length of the fences as a single fractional number in a line. There may not be any other characters in the output. The output should not contain an error greater than 0.00001. Sample Input 3 3 0 6 5 5 3 0 6 5 6 3 0 6 5 7 3 0 6 5 9 3 0 6 5 10 3 0 6 5 12 3 0 6 5 100 3 0 6 5 4 -3 4 5 8 5 -3 4 5 8 6 -3 4 5 8 64 -30 40 50 50 7 -3 4 5 8 10 -3 4 5 8 11 -3 4 5 8 14 -3 4 5 8 35 -3 4 5 8 100 -3 4 5 8 10 5 9 12 12 13 5 9 12 12 15 5 9 12 12 18 5 9 12 12 19 5 9 12 12 20 5 9 12 12 21 5 9 12 12 100 5 9 12 12 100 -5 1 -3 5 100 0 1 100 2 100 -1 99 100 100 10 -1 1 1 2 84 1 -77 5 -42 27 -12 -7 3 -4 0 0 0 0 0 Output for the Sample Input 18.84955592 26.77945045 31.69103413 39.54501577 55.51851918 63.83954229 75.38181750 628.05343108 25.13274123 24.98091545 29.43519428 318.90944272 35.02723766 55.44758990 64.23914179 89.33649537 219.11188064 627.48648370 62.83185307 76.33420961 88.61222855 112.17417345 121.59895141 126.16196589 132.25443447 628.23333565 628.18890261 626.17695473 613.16456638 62.61625003 527.84509612 168.07337509
[ { "submission_id": "aoj_1177_1150744", "code_snippet": "#include <cstdio>\n#include <cmath>\n#include <cstring>\n#include <cstdlib>\n#include <climits>\n#include <ctime>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <list>\n#include <vector>\n#include <set>\n#include <map>\n#include <iostream>\n#include <deque>\n#include <complex>\n#include <string>\n#include <iomanip>\n#include <sstream>\n#include <bitset>\n#include <valarray>\n#include <unordered_map>\n#include <iterator>\n#include <assert.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned int uint;\ntypedef unsigned char uchar;\ntypedef unsigned long long ull;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\ntypedef vector<int> vi;\n\n#define REP(i,x) for(int i=0;i<(int)(x);i++)\n#define REPS(i,x) for(int i=1;i<=(int)(x);i++)\n#define RREP(i,x) for(int i=((int)(x)-1);i>=0;i--)\n#define RREPS(i,x) for(int i=((int)(x));i>0;i--)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();i++)\n#define RFOR(i,c) for(__typeof((c).rbegin())i=(c).rbegin();i!=(c).rend();i++)\n#define ALL(container) (container).begin(), (container).end()\n#define RALL(container) (container).rbegin(), (container).rend()\n#define SZ(container) ((int)container.size())\n#define mp(a,b) make_pair(a, b)\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n\ntemplate<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }\ntemplate<class T> ostream& operator<<(ostream &os, const vector<T> &t) {\nos<<\"[\"; FOR(it,t) {if(it!=t.begin()) os<<\",\"; os<<*it;} os<<\"]\"; return os;\n}\ntemplate<class T> ostream& operator<<(ostream &os, const set<T> &t) {\nos<<\"{\"; FOR(it,t) {if(it!=t.begin()) os<<\",\"; os<<*it;} os<<\"}\"; return os;\n}\ntemplate<class S, class T> ostream& operator<<(ostream &os, const pair<S,T> &t) { return os<<\"(\"<<t.first<<\",\"<<t.second<<\")\";}\ntemplate<class S, class T> pair<S,T> operator+(const pair<S,T> &s, const pair<S,T> &t){ return pair<S,T>(s.first+t.first, s.second+t.second);}\ntemplate<class S, class T> pair<S,T> operator-(const pair<S,T> &s, const pair<S,T> &t){ return pair<S,T>(s.first-t.first, s.second-t.second);}\n\nnamespace geom{\n#define X real()\n#define Y imag()\n#define at(i) ((*this)[i])\n#define SELF (*this)\n\tenum {TRUE = 1, FALSE = 0, BORDER = -1};\n\ttypedef int BOOL;\n\ttypedef long double R;\n\tconst R INF = 1e12;\n\tR EPS = 1e-6;\n\tconst R PI = 3.1415926535897932384626;\n\tinline int sig(const R &x) { return (abs(x) < EPS ? 0 : x > 0 ? 1 : -1); }\n\tinline BOOL less(const R &x, const R &y) {return sig(x-y) ? x < y : BORDER;}\n\ttypedef complex<R> P;\n\tinline R norm(const P &p){return p.X*p.X+p.Y*p.Y;}\n\tinline R inp(const P& a, const P& b){return (conj(a)*b).X;}\n\tinline R outp(const P& a, const P& b){return (conj(a)*b).Y;}\n\tinline P unit(const P& p){return p/abs(p);}\n\tinline P proj(const P &s, const P &t){return t*inp(s, t)/norm(t);}\n\tinline int ccw(const P &s, const P &t, const P &p, int adv=0){\n\t\tint res = sig(outp(t-s, p-s));\n\t\tif(res || !adv) return res;\n\t\tif(sig(inp(t-s, p-s)) < 0) return -2;\t// p-s-t\n\t\tif(sig(inp(s-t, p-t)) < 0) return 2;\t// s-t-p\n\t\treturn 0;\t\t\t\t\t\t\t\t// s-p-t\n\t}\n\t\n\t\n\tstruct L : public vector<P>{\t// line\n\t\tL(const P &p1, const P &p2){this->push_back(p1);this->push_back(p2);}\n\t\tL(){}\n\t\tP dir()const {return at(1) - at(0);}\n\t\tBOOL online(const P &p)const {return !sig(outp(p-at(0), dir()));}\n\t};\n\tstruct S : public L{\t// segment\n\t\tS(const P &p1, const P &p2):L(p1, p2){}\n\t\tS(){}\n\t\tBOOL online(const P &p)const {\n\t\t\tif(!sig(norm(p - at(0))) || !sig(norm(p - at(1)))) return BORDER;\n\t\t\treturn !sig(abs(at(0)-p) + abs(at(1) - p) - abs(at(0) - at(1)));\n\t\t}\n\t};\n\tstruct C : public P{\n\t\tC(){}\n\t\tC(const P& p, const R r):P(p), r(r){}\n\t\tR r;\n\t\tBOOL inside(const P& p)const { return less(norm(p-SELF), r*r);}\n\t};\n\tstruct F : public C{\n\t\tR s, t;\n\t\tF(const C &c, R ss, R tt):C(c), s(ss), t(tt){\n\t\t\tif(PI < s) s -= 2*PI;\n\t\t\tif(PI < t) t -= 2*PI;\n\t\t}\n\t\tBOOL inside(const P& p)const {\n\t\t\tP v = p - SELF;\n\t\t\tif(!sig(norm(v))) return BORDER;\n\t\t\tR a = arg(v);\n\t\t\tif(t < s){\n\t\t\t\tif((!less(s, a) && !less(a, t)) || !less(norm(v), r*r)) return FALSE;\n\t\t\t\treturn less(s, a) | less(a, t) | less(norm(v), r*r);\n\t\t\t}else{\n\t\t\t\tif(!less(s, a) || !less(a, t) || !less(norm(v), r*r)) return FALSE;\n\t\t\t\treturn less(s, a) | less(a, t) | less(norm(v), r*r);\n\t\t\t}\n\t\t}\n\t};\n\tP crosspoint(const L &l, const L &m);\n\tstruct G : public vector<P>{\n\t\tG(size_type size=0):vector(size){}\n\t\tS edge(int i)const {return S(at(i), at(i+1 == size() ? 0 : i+1));}\n\t\tBOOL contains(const P &p)const {\n\t\t\tR sum = .0;\n\t\t\tREP(i, size()){\n\t\t\t\tif(S(at(i), at((i+1)%size())).online(p)) return BORDER;\t// online\n\t\t\t\tsum += arg((at(i) - p) / (at((i+1)%size()) - p));\n\t\t\t}\n\t\t\treturn !!sig(sum);\n\t\t}\n\t\tR area()const {\n\t\t\tR sum = 0;\n\t\t\tREP(i, size()) sum += outp(at(i), at((i+1)%size()));\n\t\t\treturn abs(sum / 2.);\n\t\t}\n\t\tP gp()const {\n\t\t\tP r(.0, .0);\n\t\t\tREP(i, size()){\n\t\t\t\tconst S &s = edge(i);\n\t\t\t\tr += (s[0]+s[1])*outp(s[0], s[1]);\n\t\t\t}\n\t\t\treturn r / (6*area());\n\t\t}\n\t\tG convex_hull(bool online = false) {\n\t\t\tif(size() < 2) return *this;\n\t\t\tsort(ALL(*this));\n\t\t\tG r;\n\t\t\tr.resize((int)size()*2);\n\t\t\tint k=0;\n\t\t\tfor(int i=0;i<size();r[k++]=at(i++))\n\t\t\t\twhile(k>1 && ccw(r[k-2], r[k-1], at(i)) < 1-online) k--;\n\t\t\tint t = k;\n\t\t\tfor(int i=(int)size()-1;i>=0;r[k++]=at(i--))\n\t\t\t\twhile(k>t && ccw(r[k-2], r[k-1], at(i)) < 1-online) k--;\n\t\t\tr.resize(k-1);\n\t\t\treturn r;\n\t\t}\n\t\tG cut(const L &l)const {\n\t\t\tG g;\n\t\t\tREP(i, size()){\n\t\t\t\tconst S &s = edge(i);\n\t\t\t\tif(ccw(l[0], l[1], s[0], 0) >= 0) g.push_back(s[0]);\n\t\t\t\tif(ccw(l[0], l[1], s[0], 0) * ccw(l[0], l[1], s[1], 0) < 0)\n\t\t\t\t\tg.push_back(crosspoint(s, l));\n\t\t\t}\n\t\t\treturn g;\n\t\t}\n\t\tG Voronoi(const vector<P> &p, const int t)const {\n\t\t\tG g = *this;\n\t\t\tREP(i, p.size())if(i!=t){\n\t\t\t\tconst P m = (p[t]+p[i])*(R)0.5;\n\t\t\t\tg = g.cut(L(m, m+(p[i]-p[t])*P(0, 1)));\n\t\t\t}\n\t\t\treturn g;\n\t\t}\n\t};\n\n\tinline P proj(const P &s, const L &t){return t[0] + proj(s-t[0], t[1]-t[0]);}\n\tinline P reflect(const P &s, const L &t){return (R)2*proj(s, t) - s;}\n\tinline S reflect(const S &s, const L &t){return S(reflect(s[0], t), reflect(s[1], t));}\n\tBOOL intersect(const S &s, const S &t){\n\t\tconst int p = ccw(t[0], t[1], s[0], 1) * ccw(t[0], t[1], s[1], 1);\n\t\tconst int q = ccw(s[0], s[1], t[0], 1) * ccw(s[0], s[1], t[1], 1);\n\t\treturn (p>0||q>0) ? FALSE : (!p||!q) ? BORDER : TRUE;\n\t}\n\tBOOL intersect(const S &s, const L &l){\n\t\tif(l.online(s[0]) || l.online(s[1])) return BORDER;\n\t\treturn (sig(outp(l.dir(), s[0]-l[0])) * sig(outp(l.dir(), s[1]-l[0])) <= 0);\n\t}\n\tR dist2(const L &l, const P &p){return norm(outp(l.dir(), p - l[0])) / norm(l.dir());}\n\tR dist2(const S &s, const P &p){\n\t\tif(inp(p-s[0], s.dir()) < EPS) return norm(p - s[0]);\n\t\tif(inp(p-s[1], -s.dir()) < EPS) return norm(p - s[1]);\n\t\treturn dist2((const L &)s, p);\n\t}\n\tR dist2(const S &s, const L &l){\n\t\treturn intersect(s, l) ? .0 : min(dist2(l, s[0]), dist2(l, s[1]));\n\t}\n\tR dist2(const S &s, const S &t){\n\t\treturn intersect(s, t) ? .0 : min(min(dist2(s, t[0]), dist2(t, s[0])), \n\t\t\t\t\t\t\t\t\t \t min(dist2(s, t[1]), dist2(t, s[1])));\n\t}\n\ttemplate <class T> R dist2(const G &g, const T& t){ // todo: 内部に完全に含まれる場合\n\t\tR res = INF;\n\t\tREP(i, g.size()) res = min(res, dist2(g.edge(i), t));\n\t\treturn res;\n\t}\n\ttemplate<class S, class T> R dist(const S& s, const T& t){return sqrt(dist2(s, t));}\n\tinline BOOL intersect(const C &a, const C &b){\n\t\treturn less((a.r-b.r)*(a.r-b.r), norm(a-b)) + less(norm(a-b), (a.r+b.r)*(a.r+b.r)) - 1;\n\t}\n\tinline BOOL intersect(const C &c, const L &l){\n\t\treturn less(dist2(l, c), c.r*c.r);\n\t}\n\tinline BOOL intersect(const C &c, const S &s){\n\t\tint d = less(dist2(s, c), c.r*c.r);\n\t\tif(d != TRUE) return d;\n\t\tint p = c.inside(s[0]), q = c.inside(s[1]);\n\t\treturn (p<0 || q<0) ? BORDER : p&q;\n\t}\n\t\n\t/*\n\t * CCWでs[0]->s[1]にかけてが共通部分\n\t */\n\tinline S crosspoint(const C &c1, const C &c2){\n\t\tif(!intersect(c1, c2)) return S();\n\t\tR d = abs(c1 - c2);\n\t\tR x = (c1.r*c1.r - c2.r*c2.r + d*d) / (2*d);\n\t\tR h = sqrt(max((R)0., c1.r*c1.r - x*x));\n\t\tP u = unit(c2-c1);\n\t\treturn S(c1 + u*x + u*P(0,-1)*h, c1 + u*x + u*P(0,1)*h);\n\t}\n\tinline P crosspoint(const L &l, const L &m){\n\t\tR A = outp(l.dir(), m.dir()), B = outp(l.dir(), l[1] - m[0]);\n\t\tif(!sig(abs(A)) && !sig(abs(B))) return m[0]; // same line\n\t\tif(abs(A) < EPS) assert(false); // !!!PRECONDITION NOT SATISFIED!!!\n\t\treturn m[0] + B / A * (m[1] - m[0]);\n\t}\n\tinline S crosspoint(const C &c, const L &l){\n\t\tR d2 = dist2(l, c);\n\t\tif(c.r*c.r+EPS < d2) return S();\n\t\tP m = proj(c, l);\n\t\tP u = unit(l[1]-l[0]);\n\t\tR d = sqrt(max((R).0, c.r*c.r - d2));\n\t\treturn S(m+u*d, m-u*d);\n\t}\n\tinline vector<P> crosspoint(const C &c, const S &s){\n\t\tvector<P> res = crosspoint(c, (const L&)s);\n\t\tRREP(i, res.size()){\n\t\t\tif(inp(res[i]-s[0], s.dir())*inp(res[i]-s[1], -s.dir())<-EPS)\n\t\t\t\tres.erase(res.begin() + i);\n\t\t}\n\t\treturn res;\n\t}\n\n#undef SELF\n#undef at\n}\n\nusing namespace geom;\n\nint f = 0;\nnamespace std{\n\tbool operator<(const P &a, const P &b){return sig(a.X-b.X) ? a.X < b.X : a.Y+EPS < b.Y;}\n\tbool operator==(const P &a, const P &b){return abs(a-b) < EPS;}\n\tistream& operator>>(istream &is, P &p){R x,y;is>>x>>y;p=P(x, y);return is;}\n\tistream& operator>>(istream &is, L &l){l.resize(2);return is >> l[0] >> l[1];}\n\tistream& operator>>(istream &is, C &c){return is >> (P &)c >> c.r;}\n\tconst R B = 200;\n\tconst R Z = 30;\n\tostream& operator<<(ostream &os, const C &c){return os << \"circle(\"<<B+Z*(c.X)<<\", \"<<1000-B-Z*(c.Y)<<\", \"<<Z*(c.r)<<\")\";}\n\tostream& operator<<(ostream &os, const P &p){return os << C(p, 2./Z);}\n\tostream& operator<<(ostream &os, const S &s){return os << \"line(\"<<B+Z*(s[0].X)<<\", \"<<1000-B-Z*(s[0].Y)<<\", \"<<B+Z*(s[1].X)<<\", \"<<1000-B-Z*(s[1].Y)<<\")\";}\n\tostream& operator<<(ostream &os, const G &g){REP(i, g.size()) cout << g.edge(i) << endl;return os;}\n\n}\n\nint n;\nG g;\n\nR dist(P p){\n\tif(g.contains(p) == TRUE) return INF;\n\tif([&](){\n\t\tREP(j, 4) if(intersect(g.edge(j), S(p, P(0, 0))) == TRUE) return 0;\n\t\treturn 1;\n\t}()) return abs(p);\n\tvector<vector<R>> d(6, vector<R>(6, INF));\n\tREP(i, 6) d[i][i] = 0;\n\tREP(i, 4){\n\t\td[i][(i+1)&3] = d[(i+1)&3][i] = abs(g.edge(i).dir());\n\t\tif([&](){\n\t\t\tREP(j, 4){\n\t\t\t\tif(intersect(g.edge(j), S(p, g[i])) == TRUE) return 0;\n\t\t\t\tif(g.contains((p + g[i])*(R).5) == TRUE) return 0;\n\t\t\t}\n\t\t\treturn 1;\n\t\t}()) d[i][4] = d[4][i] = abs(g[i] - p);\n\t\tif([&](){\n\t\t\tREP(j, 4) if(intersect(g.edge(j), S(P(0, 0), g[i])) == TRUE) return 0;\n\t\t\treturn 1;\n\t\t}()) d[i][5] = d[5][i] = abs(P(0, 0) - g[i]);\n\t}\n\tREP(k, 6)REP(i, 6)REP(j, 6) d[i][j] = min(d[i][j], d[i][k] + d[k][j]);\n\treturn d[4][5];\n}\nR len;\nP p1, p2;\nint main(){\n\tios::sync_with_stdio(false);\n\twhile(cin >> len >> p1 >> p2, len > EPS){\n\t\tg.resize(4);\n\t\tg[0] = p1;\n\t\tg[1] = P(p2.X, p1.Y);\n\t\tg[2] = p2;\n\t\tg[3] = P(p1.X, p2.Y);\n\t\tvector<C> c;\n\t\tc.emplace_back(P(0, 0), len);\n\t\tREP(i, 4)if(dist(g[i]) < len)\n\t\t\tc.emplace_back(g[i], len - dist(g[i]));\n\t\tvector<P> p;\n\t\tREP(i, c.size()){\n\t\t\tREP(j, i){\n\t\t\t\tauto x = crosspoint(c[i], c[j]);\n\t\t\t\tp.insert(p.end(), ALL(x));\n\t\t\t}\n\t\t\tREP(j, 4){\n\t\t\t\tauto x = crosspoint(c[i], g.edge(j));\n\t\t\t\tp.insert(p.end(), ALL(x));\n\t\t\t}\n\t\t}\n\t\tsort(ALL(p));UNIQUE(p);\n\t\tR ans = .0;\n\t\tREP(i, c.size()){\n\t\t\tvector<R> args;\n\t\t\tREP(j, p.size()) if(!sig(norm(c[i] - p[j]) - c[i].r*c[i].r))\n\t\t\t\targs.push_back(arg((p[j]-c[i])));\n\t\t\tsort(ALL(args));\n\t\t\tif(args.empty()) ans += 2*PI * c[i].r;\n\t\t\tREP(j, args.size()){\n\t\t\t\tR s = args[j];\n\t\t\t\tR t = (j+1 == args.size()) ? args[0]+2*PI : args[j+1];\n\t\t\t\tif(!sig(dist(c[i]+polar(c[i].r, s)) - len) && \n\t\t\t\t !sig(dist(c[i]+polar(c[i].r, t)) - len) && \n\t\t\t\t !sig(dist(c[i]+polar(c[i].r, (s+t)*.5)) - len)){\n\t\t\t\t ans += (t-s) * c[i].r;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tprintf(\"%.6f\\n\", (double)ans);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 1328, "score_of_the_acc": -1, "final_rank": 3 }, { "submission_id": "aoj_1177_1142323", "code_snippet": "#include <bits/stdc++.h>\n\n#define REP(i,n) for(int i=0;i<(int)(n);i++)\n#define ALL(x) begin(x),end(x)\n\nusing namespace std;\n\ntypedef long double ld;\ntypedef complex<ld> P;\ntypedef vector<P> VP;\nconst ld eps = 1e-9, pi = acos((ld)-1.0), INF = 1e+8;\n\n#define EQ(a,b) (abs((a)-(b))<eps)\n\nld dot (P a, P b) { return real(conj(a) * b); }\nld cross (P a, P b) { return imag(conj(a) * b); }\n\nnamespace std {\n bool operator<(const P &lhs, const P &rhs) {\n return lhs.real() == rhs.real() ? lhs.imag() < rhs.imag() : lhs.real() < rhs.real();\n }\n}\n\n// Line\nclass L{\npublic:\n P a, b;\n L (P aa, P bb) { a = aa; b = bb; }\n L (ld ax, ld ay, ld bx, ld by) { a = P(ax, ay); b = P(bx, by); }\n};\n\n// Circle\nclass C { public: P p; ld r; };\n\n// counter clockwise\nint ccw (P a, P b, P c) {\n b -= a; c -= a;\n if (cross(b, c) > eps) return 1; // counter clockwise\n if (cross(b, c) < -eps) return -1; // clockwise\n if (dot(b, c) < 0) return 2; // c--a--b on line\n if (norm(b) < norm(c)) return -2; // a--b--c on line\n return 0; // a--c--b on line\n}\n\nbool isis_ss(L s, L t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) < 0 &&\n ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) < 0;\n}\n\nP is_ll(L s, L t){\n P sv = s.b - s.a, tv = t.b - t.a;\n return s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n\nVP is_cc(C c1, C c2){\n VP res;\n ld d = abs(c1.p - c2.p);\n ld rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n ld dfr = c1.r * c1.r - rc * rc;\n if (abs(dfr) < eps) dfr = 0.0;\n else if (dfr < 0.0) return res; // no intersection\n ld rs = sqrt(dfr);\n P diff = (c2.p-c1.p)/d;\n res.push_back(c1.p + diff * P(rc, rs));\n if (dfr != 0.0) res.push_back(c1.p + diff * P(rc, -rs));\n return res;\n}\n\nP proj(L l, P p) {\n ld t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + t * (l.a - l.b);\n}\n\nld dist_lp(L l, P p) {\n return abs(p - proj(l, p));\n}\n\nVP is_lc(C c, L l){\n VP res;\n ld d = dist_lp(l, c.p);\n if (d < c.r + eps){\n ld len = (d > c.r) ? 0.0 : sqrt(c.r * c.r - d * d); //safety;\n P nor = (l.a - l.b) / abs(l.a - l.b);\n res.push_back(proj(l, c.p) + len * nor);\n res.push_back(proj(l, c.p) - len * nor);\n }\n return res;\n}\n\nbool isis_sp(L s, P p) {\n return abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps;\n}\n\nVP is_sc(C c, L l){\n VP v = is_lc(c, l), res;\n for (P p : v)\n if (isis_sp(l, p)) res.push_back(p);\n return res;\n}\n\nvector<L> house;\nvector<P> hp;\nld dd[5][5];\nld x[2],y[2];\n\nbool is_ok(P p, P o=P()) {\n REP(i,4) if (isis_ss(house[i], L(p, o))) return false;\n return true;\n}\n\nbool is_in_h(P p) {\n return x[0] < real(p) && real(p) < x[1] &&\n y[0] < imag(p) && imag(p) < y[1];\n}\n\nld dist(P p) {\n ld minl = INF;\n if(is_in_h(p)) return INF;\n REP(i,5) if(is_ok(p,hp[i])) minl=min(minl,dd[0][i]+abs(p-hp[i]));\n return minl;\n}\n\nint main() {\n random_device rg;\n mt19937 mt(rg());\n while(1){\n house.clear(); hp.clear();\n ld l;\n cin>>l>>x[0]>>y[0]>>x[1]>>y[1];\n if(!l) break;\n REP(i,2)REP(j,2) hp.emplace_back(x[i],y[j]);\n REP(i,5)REP(j,5) dd[i][j] = INF;\n REP(i,2){\n house.emplace_back(hp[i],hp[i+2]);\n house.emplace_back(hp[i*2],hp[i*2+1]);\n dd[i+1][i+3] = x[1]-x[0];\n dd[i*2+1][i*2+2] = y[1]-y[0];\n }\n REP(i,4) if(is_ok(hp[i])) dd[0][i+1] = abs(hp[i]);\n hp.insert(begin(hp),P());\n REP(i,5)REP(j,i) dd[i][j] = dd[j][i];\n REP(i,5) dd[i][i]=0;\n REP(k,5)REP(i,5)REP(j,5) dd[i][j]=min(dd[i][j],dd[i][k]+dd[k][j]);\n vector<C> vc;\n REP(i,5) vc.push_back((C){hp[i], l-dd[0][i]});\n VP crs;\n REP(i,5)REP(j,i){\n auto v=is_cc(vc[i],vc[j]);\n crs.insert(end(crs),ALL(v));\n }\n REP(i,5)REP(j,4){\n auto v=is_sc(vc[i],house[j]);\n crs.insert(end(crs),ALL(v));\n }\n ld res = 0;\n REP(i,5){\n vector<ld> va;\n REP(j,crs.size())\n if(abs(abs(crs[j]-hp[i])-vc[i].r) < eps)\n va.emplace_back(arg(crs[j]-hp[i]));\n sort(ALL(va));\n REP(j,va.size()-1){\n uniform_real_distribution<ld> dis(va[j],va[j+1]);\n ld rad = va[j+1]-va[j];\n P p=polar(vc[i].r, dis(mt))+hp[i];\n if (abs(dist(p)-l) < eps) res += rad*vc[i].r;\n }\n if(va.size()>=2){\n uniform_real_distribution<ld> dis(va.back(),va.front()+pi*2);\n ld rad = pi*2-(va.back()-va.front());\n assert(rad>=0);\n P p=polar(vc[i].r, dis(mt))+hp[i];\n if (abs(dist(p)-l) < eps) res += rad*vc[i].r;\n }\n }\n cout<<setprecision(8)<<fixed<<res<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1364, "score_of_the_acc": -1.1667, "final_rank": 4 }, { "submission_id": "aoj_1177_881576", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <cmath>\n#include <complex>\n#include <cfloat>\nusing namespace std;\n\ntypedef long double D;\ntypedef complex<D> P;\n\nconst D EPS = 1e-9;\n\nD dot(P va, P vb){\n\treturn real(va) * real(vb) + imag(va) * imag(vb);\n}\n\nD cross(P va, P vb){\n\treturn real(va) * imag(vb) - imag(va) * real(vb);\n}\n\nbool check_angle(D ag, D rg[]){\n\treturn rg[0] - EPS < ag && ag < rg[1] + EPS;\n}\n\nvoid intrcscs(P p1, D r1, D rg1[], P p2, D r2, D rg2[], vector<P> &ret){\n\tD d = abs(p2 - p1);\n\tD phi = arg(p2 - p1);\n\t\n\tD costheta = (d * d + r1 * r1 - r2 * r2) / (2.0 * d * r1);\n\tif(abs(costheta) > 1.0){\n\t\tif(abs(costheta) < 1.0 + EPS){\n\t\t\tcostheta /= abs(costheta);\n\t\t}\n\t\telse{\n\t\t\treturn;\n\t\t}\n\t}\n\t\n\tD theta = acos(costheta);\n\n\tP pt = p1 + polar(r1, phi + theta);\n\tif(check_angle(arg(pt - p1), rg1) && check_angle(arg(pt - p2), rg2)){\n\t\tret.push_back(pt);\n\t}\n\tpt = p1 + polar(r1, phi - theta);\n\tif(check_angle(arg(pt - p1), rg1) && check_angle(arg(pt - p2), rg2)){\n\t\tret.push_back(pt);\n\t}\n}\n\nvoid intrlsc(P p1, P p2, P pc, D r, vector<P> &ret){\n\tP v12 = p2 - p1;\n\tP v1c = pc - p1;\n\n\tD a = norm(v12);\n\tD b = -dot(v12, v1c);\n\tD c = norm(v1c) - r * r;\n\n\tD d = b * b - a * c;\n\tif(d < 0.0 && d > -EPS){\n\t\td = 0.0;\n\t}\n\tif(d < 0.0){\n\t\tif(d > -EPS){\n\t\t\td = 0.0;\n\t\t}\n\t\telse{\n\t\t\treturn;\n\t\t}\n\t}\n\n\td = sqrt(d);\n\tD t1 = (-b + d) / a;\n\tD t2 = (-b - d) / a;\n\t\n\tif(-EPS < t1 && t1 < 1.0 + EPS){\n\t\tret.push_back(p1 + v12 * t1);\n\t}\n\tif(-EPS < t2 && t2 < 1.0 + EPS){\n\t\tret.push_back(p1 + v12 * t2);\n\t}\n}\n\n\nstruct info{\n\tD rem, range[2];\n\tP cen;\n\n\tinfo() : rem(-1.0){\n\t\trange[0] = range[1] = 0.0;\n\t}\n\tinfo(D rm, D rl, D rr, P c) : rem(rm), cen(c){\n\t\trange[0] = rl;\n\t\trange[1] = rr;\n\t}\n};\n\n\nD pi = acos(-1.0L);\n\n\nD solve(D len){\n\tconst D inf = 1e100;\n\tD x1, y1, x2, y2;\n\tcin >> x1 >> y1 >> x2 >> y2;\n\n\tinfo ropes[2], nropes[2];\n\tD add[2];\n\tvector<P> plg(4);\n\n\tplg[0] = P(x1, y1);\n\tplg[1] = P(x2, y1);\n\tplg[2] = P(x2, y2);\n\tplg[3] = P(x1, y2);\n\t\n\tP brot = conj(plg[0]) / abs(plg[0]);\n\tfor(int i = 0; i < 4; ++i){\n\t\tplg[i] *= brot;\n\t}\n\n\tropes[0] = info(len, -pi, pi, P());\n\tropes[1] = info(len, -pi, pi, P());\n\n\tD ans = 0.0;\n\twhile(max(ropes[0].rem, ropes[1].rem) > EPS){\n\t\tfor(int k = 0; k < 2; ++k){\n\t\t\tinfo &rp = ropes[k];\n\t\t\tinfo &nx = nropes[k];\n\t\t\tnx = info();\n\t\t\tadd[k] = 0.0;\n\n\t\t\tif(rp.rem < EPS){ continue; }\n\n\t\t\tvector<P> cand = plg;\n\t\t\t\n\t\t\tif(ropes[0].rem < len && ropes[1].rem < len){\n\t\t\t\tintrcscs(\n\t\t\t\t\tropes[0].cen, ropes[0].rem, ropes[0].range,\n\t\t\t\t\tropes[1].cen, ropes[1].rem, ropes[1].range, cand\n\t\t\t\t);\n\t\t\t}\n\t\t\tfor(int i = 0; i < 4; ++i){\n\t\t\t\tintrlsc(plg[i], plg[(i + 1) & 3], rp.cen, rp.rem, cand);\n\t\t\t}\n\t\t\tfor(int i = 0; i < 2; ++i){\n\t\t\t\tcand.push_back(ropes[i].cen);\n\t\t\t}\n\n\t\t\tint minidx = -1;\n\t\t\tD minangle = (k ? -inf : inf);\n\t\t\tD maxdist = -inf;\n\n\t\t\tfor(int i = cand.size(); i--; ){\n\t\t\t\tD ds = abs(cand[i] - rp.cen);\n\t\t\t\tD ag = arg(cand[i] - rp.cen);\n\t\t\t\t\n\t\t\t\tbool update = false;\n\t\t\t\tif(\tds > EPS && ds < rp.rem + EPS && check_angle(ag, rp.range)){\n\t\t\t\t\tif(abs(minangle - ag) < EPS){\n\t\t\t\t\t\tupdate = maxdist < ds;\n\t\t\t\t\t}\n\t\t\t\t\telse{\n\t\t\t\t\t\tupdate = (minangle > ag) ^ k;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tif(update){\n\t\t\t\t\tminidx = i;\n\t\t\t\t\tminangle = ag;\n\t\t\t\t\tmaxdist = ds;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif(minidx == -1){\n\t\t\t\treturn 2.0 * pi * len;\n\t\t\t}\n\n\t\t\tadd[k] = rp.rem * abs(minangle - rp.range[k]);\n\n\t\t\tif(minidx < 4){\n\t\t\t\tnx.range[k] = minangle;\n\t\t\t\tnx.range[!k] = arg(plg[(minidx + (k ? 3 : 1)) & 3] - plg[minidx]);\n\t\t\t\tnx.rem = rp.rem - maxdist;\n\t\t\t\tnx.cen = cand[minidx];\n\t\t\t}\n\t\t\telse{\n\t\t\t\tnx.rem = 0.0;\n\t\t\t\tnx.range[0] = nx.range[1] = 0.0;\n\t\t\t\tnx.cen = cand[minidx];\n\t\t\t}\n\t\t}\n\n\t\tint updidx = (nropes[0].rem < nropes[1].rem);\n\t\tans += add[updidx];\n\t\tropes[updidx] = nropes[updidx];\n\t}\n\treturn ans;\n}\n\n\nint main(){\n\tios::sync_with_stdio(false);\n\tcout << fixed << setprecision(8);\n\n\tD len;\n\twhile(cin >> len, len != 0.0){\n\t\tD ans = solve(len);\n\t\tcout << ans << '\\n';\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1332, "score_of_the_acc": -0.1111, "final_rank": 1 }, { "submission_id": "aoj_1177_814423", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <complex>\n#include <cstring>\n#include <cstdlib>\n#include <string>\n#include <cmath>\n#include <cassert>\n#include <queue>\n#include <set>\n#include <map>\n#include <valarray>\n#include <bitset>\n#include <stack>\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(int)n;++i)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n#define ALL(c) (c).begin(), (c).end()\n#define chmax(a,b) (a<(b)?(a=b,1):0)\n#define chmin(a,b) (a>(b)?(a=b,1):0)\n#define valid(y,x,h,w) (0<=y&&y<h&&0<=x&&x<w)\nconst int INF = 1<<29;\nconst double EPS = 1e-8;\nconst double PI = acos(-1);\ntypedef pair<int,int> pii;\ntypedef long long ll;\n\ntypedef complex<double> P;\nP pIN() { double x,y; cin >> x >> y; return P(x,y); }\nnamespace std {\n bool operator < (const P& a, const P& b) {\n // if (abs(a-b)<EPS) return 0;\n return real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n }\nbool operator==(const P &a, const P &b) {\n return abs(a-b)<EPS;\n}\n\n}\ndouble cross(const P& a, const P& b) {\n return imag(conj(a)*b);\n}\ndouble dot(const P& a, const P& b) {\n return real(conj(a)*b);\n}\nint ccw(P a, P b, P c) {\n b -= a; c -= a;\n if (cross(b, c) > EPS) return +1; // counter clockwise\n if (cross(b, c) < -EPS) return -1; // clockwise\n if (dot(b, c) < -EPS) return +2; // c--a--b on line\n if (EPS < norm(b) && norm(b) < norm(c)-EPS) return -2; // a--b--c on line\n return 0;\n}\nstruct L : public vector<P> {\n L(const P &a, const P &b) {\n push_back(a); push_back(b);\n }\n L() { resize(2); }\n};\nostream &operator<<(ostream &os, const L &a) {\n os << a[0] << \" -> \" << a[1];\n return os;\n}\ntypedef vector<P> G;\n#define curr(g, i) g[i]\n#define next(g, i) g[(i+1)%g.size()]\nL line(const G &g, int i) {\n return L(g[i],g[(i+1)%g.size()]);\n}\nstruct C {\n P p; double r;\n C(const P &p, double r) : p(p), r(r) { }\n C() {}\n};\n\nstruct CS : C {\n P p1, p2;\n CS(const P &p, const P &p1, const P &p2):\n p1(p1),p2(p2) {\n this->p = p;\n this->r = abs(p1);\n }\n L l1() { return L(p,p+p1); }\n L l2() { return L(p,p+p2); }\n};\n\nP projection(const L &l, const P &p) {\n double t = dot(p-l[0], l[0]-l[1]) / norm(l[0]-l[1]);\n return l[0] + t*(l[0]-l[1]);\n}\nP reflection(const L &l, const P &p) {\n return p + P(2,0) * (projection(l, p) - p);\n}\n\nvector<P> crosspointLC(const L &l, const C &c) {\n vector<P> ret;\n P center = projection(l, c.p);\n double d = abs(center - c.p);\n double t = sqrt(c.r * c.r - d * d);\n if (::isnan(t)) { return ret; }\n P vect = (l[1] - l[0]);\n vect /= abs(vect);\n ret.push_back(center - vect * t);\n if (t > EPS) {\n ret.push_back(center + vect * t);\n }\n return ret;\n}\n\nvector<P> crosspointCC(const C &c1, const C &c2) {\n vector<P> ret;\n double d = abs(c1.p - c2.p);\n if (max(c1.r, c2.r) - min(c1.r, c2.r) - d> -EPS) { return ret; }\n double x = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n P start = c1.p + (c2.p - c1.p) / d * x;\n P vect = (c1.p - c2.p) * P(0.0, 1.0);\n return crosspointLC(L(start, start + vect), c1);\n}\n// テ」ツδ凖」ツつッテ」ツδ暗」ツδォテッツスツ?」ツ?凝」ツつ嘉」ツ?ソテ」ツ?淌」ツδ凖」ツつッテ」ツδ暗」ツδォテッツスツづ」ツ?ョティツァツ津・ツコツヲテ」ツ?ョ[0,2pi)\ndouble angle(const P &a, const P &b) {\n double ret = arg(b)-arg(a);\n return (ret>=0) ? ret : ret + 2*PI;\n}\n// テ」ツδ凖」ツつッテ」ツδ暗」ツδォaテ」ツ?ィテ」ツδ凖」ツつッテ」ツδ暗」ツδォbテ」ツ?ョテゥツ鳴禿」ツ?ョティツァツ津・ツコツヲ\ndouble angle2(const P &a, const P &b) {\n return min(angle(a,b), angle(b,a));\n}\n\nbool intersectCSP(const CS &cs, const P &p) {\n return (angle(cs.p1, p-cs.p) <= angle(cs.p1, cs.p2)) &&\n (abs(cs.p-p) <= cs.r+EPS);\n}\nvector<P> crosspointCSCS(const CS &c1, const CS &c2) {\n vector<P> r = crosspointCC(c1,c2);\n vector<P> res;\n FOR(it, r)\n if (intersectCSP(c1, *it) &&\n intersectCSP(c2, *it))\n res.push_back(*it);\n return res;\n}\nP rotate(P p, double ang) {\n return p * P(cos(ang), sin(ang));\n}\n// テ・ツ篠淌ァツつケテ・ツ堕ィテ」ツつ甘」ツ?ョテァツ崢エテァツキツ堙」ツ?ョテ・ツ崢榲ィツサツ「\nL rotate(L l, double ang) {\n return L(rotate(l[0], ang),rotate(l[1], ang));\n}\n\nFILE *fp;\ndouble scale = 10;\nP diff(300, 300);\ndouble WH = 500;\nvoid outputLine(const L &l) {\n if (!fp) return;\n P a = l[0];\n P b = l[1];\n a = a*P(scale,0)+diff;\n b = b*P(scale,0)+diff;\n fprintf(fp,\"line(%f,%f,%f,%f);\\n\",a.real(),WH-a.imag(),b.real(),WH-b.imag()); \n}\nvoid outputCircle(C c) {\n if (!fp) return;\n c.p = c.p*P(scale,0) + diff;\n c.r *= scale;\n fprintf(fp, \"circle(%f,%f,%f);\\n\", c.p.real(), WH-c.p.imag(), c.r);\n}\nvoid outputCS(const CS &c) {\n if (!fp) return;\n double ang = angle(c.p1,c.p2);\n const int N = 50;\n REP(i,N) {\n double a = ang*i/N;\n double b = ang*(i+1)/N;\n outputLine(L(c.p+rotate(c.p1,a), c.p+rotate(c.p1,b)));\n }\n outputLine(L(c.p,c.p+c.p1));\n outputLine(L(c.p,c.p+c.p2));\n}\nbool intersectSP(const L &s, const P &p) {\n return abs(s[0]-p)+abs(s[1]-p)-abs(s[1]-s[0]) < EPS; // triangle inequality\n}\n\nvector<P> crosspointSC(const L &s, const C &c) {\n vector<P> ret;\n vector<P> nret = crosspointLC(s, c);\n FOR(it, nret)\n if (intersectSP(s, *it))\n ret.push_back(*it);\n return ret;\n}\ndouble len;\nG g;\nvector<CS> solve(int t) {\n L s(P(0,0),P(0,-len));\n vector<CS> res;\n REP(_,4) {\n double minAng = 100;\n P nxt1,nxt2;\n bool f = 0; \n REP(i,4) {\n if (s[0]==g[i]) continue;\n if (abs(g[i]-s[0])<abs(s[1]-s[0])) {\n double ag = angle(s[1]-s[0],g[i]-s[0]);\n if (t == -1) ag = angle(g[i]-s[0],s[1]-s[0]);\n if (chmin(minAng, ag)) {\n nxt1 = g[i];\n nxt2 = g[i]-s[0];\n nxt2 *= P((abs(s[1]-s[0]) - abs(g[i]-s[0]))/abs(nxt2),0);\n nxt2 += nxt1;\n f = 0;\n }\n }\n }\n REP(i,4) {\n vector<P> ps = crosspointSC(line(g,i),\n C(s[0],abs(s[1]-s[0])));\n FOR(it, ps) {\n double ag = angle(s[1]-s[0],*it-s[0]);\n if (t == -1) ag = angle(*it-s[0],s[1]-s[0]);\n if (chmin(minAng, ag)) {\n nxt2 = *it;\n f = 1;\n }\n }\n }\n if (minAng == 100) {\n f = 1;\n nxt2 = P(0,len);\n }\n if (t == -1) \n res.push_back(CS(s[0],nxt2-s[0],s[1]-s[0]));\n else\n res.push_back(CS(s[0],s[1]-s[0],nxt2-s[0]));\n if (f) break;\n s[0] = nxt1;\n s[1] = nxt2;\n }\n return res;\n}\n\nint main() {\n // fp = fopen(\"data.js\", \"w\");\n double x1,x2,y1,y2;\n while(cin >> len, len) {\n cin >> x1 >> y1;\n cin >> x2 >> y2;\n if (y1 < 0) {\n y1 = -y1;\n y2 = -y2;\n swap(x1,x2);\n swap(y1,y2);\n }\n if (y1 < 0) {\n if (x1 < 0) {\n swap(x1,y1); y1 = -y1;\n swap(x2,y2); y2 = -y2;\n } else {\n swap(x1,y1); x1 = -x1;\n swap(x2,y2); x2 = -x2;\n }\n }\n if (y1 > y2) swap(y1,y2);\n if (x1 > x2) swap(x1,x2);\n g.resize(4);\n g[0] = P(x1,y1);\n g[1] = P(x2,y1);\n g[2] = P(x2,y2);\n g[3] = P(x1,y2);\n vector<CS> v1 = solve(1);\n vector<CS> v2 = solve(-1);\n\n outputLine(L(P(-1000,0),P(1000,0)));\n outputLine(L(P(0,-1000),P(0,1000)));\n REP(i,4) {\n outputLine(line(g,i));\n }\n REP(i,v1.size()) {\n outputCS(v1[i]);\n }\n REP(i,v2.size()) {\n outputCS(v2[i]);\n }\n \n \n int A=-1,B;\n P cp;\n int hoge = INF;\n REP(i,v1.size()) {\n REP(j,v2.size()) {\n vector<P> v = crosspointCSCS(v1[i],v2[j]);\n if (v.size() == 1 && hoge > i+j) {\n hoge = i+j;\n cp = v[0];\n A = i, B = j;\n }\n }\n }\n double ans = 0;\n if (A >= 0) {\n REP(i,A)\n ans += v1[i].r * angle(v1[i].p1, v1[i].p2);\n REP(i,B)\n ans += v2[i].r * angle(v2[i].p1, v2[i].p2);\n ans += v1[A].r * angle(v1[A].p1, cp-v1[A].p);\n ans += v2[B].r * angle(cp-v2[B].p, v2[B].p2);\n } else {\n REP(i,v1.size())\n ans += v1[i].r * angle(v1[i].p1, v1[i].p2);\n REP(i,v2.size())\n ans += v2[i].r * angle(v2[i].p1, v2[i].p2);\n }\n printf(\"%.8f\\n\", ans);\n \n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1356, "score_of_the_acc": -0.7778, "final_rank": 2 } ]
aoj_1174_cpp
Identically Colored Panels Connection Dr. Fukuoka has invented fancy panels. Each panel has a square shape of a unit size and has one of the six colors, namely, yellow, pink, red, purple, green and blue. The panel has two remarkable properties. One property is that, when two or more panels with the same color are placed adjacently, their touching edges melt a little and they are fused each other. The fused panels are united into a polygonally shaped panel. The other property is that the color of a panel can be changed to one of six colors by giving an electrical shock. The resulting color can be controlled by its waveform. The electrical shock to an already united panel changes the color of the whole to a specified single color. Since he wants to investigate the strength with respect to the color and the size of a united panel compared to unit panels, he tries to unite panels into a polygonal panel with a specified color. Figure C-1: panels and their initial colors Since many panels are simultaneously synthesized and generated on a base plate through some complex chemical processes, the fabricated panels are randomly colored and they are arranged in a rectangular shape on the base plate (Figure C-1). Note that the two purple (color 4) panels in Figure C-1 are already united at the initial state since they are adjacent to each other. Installing electrodes to a panel, and changing its color several times by giving electrical shocks according to an appropriate sequence for a specified target color, he can make a united panel merge the adjacent panels to unite them step by step and can obtain a larger panel with the target color. Unfortunately, panels will be broken when they are struck by the sixth electrical shock. That is, he can change the color of a panel or a united panel only five times. Let us consider a case where the panel at the upper left corner of the panel configuration (Figure C-1) is attached with the electrodes. First, changing the color of the panel from yellow to blue, the two adjacent panels are fused into a united panel (Figure C-2). Figure C-2: Change of the color of the panel at the upper left corner, from yellow (color 1) to blue (color 6). Second, changing the color of the upper left united panel from blue to red, a united red panel that consists of three unit panels is newly formed (Figure C-3). Then, changing the color of the united panel from red to purple, panels are united again to form a united panel of five unit panels (Figure C-4). Figure C-3: Change of the color of the panel at the upper left corner, from blue (color 6) to red (color 3). Figure C-4: Change of the color of the panel at the upper left corner, from red (color 3) to purple (color 4). Furthermore, through making a pink united panel in Figure C-5 by changing the color from purple to pink, then, the green united panel in Figure C-6 is obtained by changing the color from pink to green. The green united panel consists of ten unit panels. F ...(truncated)
[ { "submission_id": "aoj_1174_10853966", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <cstring>\n\nusing std::max;\n\nint N, M, target, a[8][8], f, t, ans, x[64], y[64];\n\nint w[10];\n\nvoid copy(int b[8][8], int a[8][8]) {\n\tfor(int i = 0; i < N; ++i) {\n\t\tfor(int j = 0; j < M; ++j) {\n\t\t\tb[i][j] = a[i][j];\n\t\t}\n\t}\n}\n\nvoid print() {\n\tfor(int i = 0; i < N; ++i) {\n\t\tfor(int j = 0; j < M; ++j) {\n\t\t\tprintf(\"%d \", a[i][j]);\n\t\t}\n\t\tputs(\"\");\n\t}\n\tputs(\"\");\n}\n\nbool inRange(int x, int y) {\n\treturn x >= 0 && x < N && y >= 0 && y < M;\n}\n\nint work(int color) {\n\tbool hsh[8][8];\n\tfor(int i = 0; i < N; ++i) for(int j = 0; j < M; ++j) hsh[i][j] = false;\n\tf = t = 0;\n\thsh[0][0] = true;\n\tx[0] = 0;\n\ty[0] = 0;\n\t++t;\n\twhile(f < t) {\n\t\tfor(int dx = -1; dx <= 1; ++dx) {\n\t\t\tfor(int dy = -1; dy <= 1; ++dy) {\n\t\t\t\tif(abs(dx) + abs(dy) == 1 && inRange(x[f] + dx, y[f] + dy)) {\n\t\t\t\t\tint xx = x[f] + dx;\n\t\t\t\t\tint yy = y[f] + dy;\n\t\t\t\t\tif(a[xx][yy] == a[0][0] && !hsh[xx][yy]) {\n\t\t\t\t\t\tx[t] = xx;\n\t\t\t\t\t\ty[t] = yy;\n\t\t\t\t\t\thsh[xx][yy] = true;\n\t\t\t\t\t\t++t;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t++f;\n\t}\n\tfor(int j = 0; j < t; ++j) {\n\t\ta[x[j]][y[j]] = color;\n\t}\n\treturn f;\n}\n\nvoid dfs(int dep) {\n//\tprintf(\"[%d]\\n\", dep);\n\tint b[8][8];\n\tcopy(b, a);\n\tif(dep < 4) {\n\t\tfor(int i = 1; i <= 6; ++i) {\n\t\t\twork(i);\n\t\t\tdfs(dep + 1);\n\t\t\tcopy(a, b);\n\t\t}\n\t\treturn;\n\t}\n\twork(target);\n\tans = max(ans, work(target));\n}\n\nint main() {\n\t// freopen(\"input\", \"r\", stdin);\n\t// freopen(\"output\", \"w\", stdout);\n\twhile(scanf(\"%d%d%d\", &N, &M, &target), N && M) {\n\t\tfor(int i = 0; i < N; ++i) {\n\t\t\tfor(int j = 0; j < M; ++j) {\n\t\t\t\tscanf(\"%d\", a[i] + j);\n\t\t\t}\n\t\t}\n\t\tans = 0;\n\t\tdfs(0);\n\t\tprintf(\"%d\\n\", ans);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 2808, "score_of_the_acc": -0.009, "final_rank": 1 }, { "submission_id": "aoj_1174_10659599", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nbool solve() {\n int H, W, C;\n cin >> H >> W >> C;\n if (H == 0) return false;\n vector<vector<int>> P(H, vector<int>(W));\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) cin >> P[i][j];\n }\n int ans = 0;\n auto rec = [&] (auto rec, int k, vector<vector<int>> P) -> void {\n vector<vector<bool>> vis(H, vector<bool>(W, false));\n vis[0][0] = true;\n queue<pair<int, int>> q;\n q.emplace(0, 0);\n int D[5] = {0, 1, 0, -1, 0};\n vector<pair<int, int>> bfs;\n while (q.size()) {\n auto [r, c] = q.front();\n q.pop();\n bfs.emplace_back(r, c);\n for (int d = 0; d < 4; d++) {\n int nr = r + D[d], nc = c + D[d + 1];\n if (0 <= nr && nr < H && 0 <= nc && nc < W) {\n if (!vis[nr][nc] && P[nr][nc] == P[0][0]) {\n vis[nr][nc] = true;\n q.emplace(nr, nc);\n }\n }\n }\n }\n if (k == 5) {\n if (P[0][0] == C) ans = max(ans, (int)bfs.size());\n return;\n }\n for (int c = 1; c <= 6; c++) {\n auto Q = P;\n for (auto [i, j] : bfs) Q[i][j] = c;\n rec(rec, k + 1, Q);\n }\n };\n rec(rec, 0, P);\n cout << ans << endl;\n return true;\n}\n\nint main() {\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 1700, "memory_kb": 3584, "score_of_the_acc": -0.3757, "final_rank": 16 }, { "submission_id": "aoj_1174_10624883", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\n#define all(v) v.begin(), v.end()\n#define rall(a) a.rbegin(), a.rend()\n#define fi first\n#define se second\n#define endl \"\\n\"\n\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\n\ntemplate <typename T>\nusing vc = vector<T>; // prioriy_queueに必要なのでここにこれ書いてます\ntemplate <typename T>\nusing vv = vc<vc<T>>;\n#define int long long\nusing ll = long long;\nll INF = 2e18;\n\n#ifdef ONLINE_JUDGE\n// ジャッジ環境ではデバッグマクロを無効化\n#define debug_x(x) \\\n do \\\n { \\\n } while (0)\n#define debug_vc(v) \\\n do \\\n { \\\n } while (0)\n#define debug_vv(v) \\\n do \\\n { \\\n } while (0)\n#else\n// ローカルではデバッグ出力\n#define debug_x(x) cout << #x << \" = \" << (x) << endl\n#define debug_vc(v) \\\n { \\\n cout << #v << endl; \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << ' '; \\\n cout << endl; \\\n } // 一次元配列を出力する\n#define debug_vv(v) \\\n { \\\n cout << #v << endl; \\\n ll n = size(v); \\\n rep(i, n) \\\n { \\\n rep(j, size(v[i])) { cout << v[i][j] << ' '; } \\\n cout << endl; \\\n } \\\n } // 二次元配列を出力する\n#endif\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n#define rrep(i, n) for (ll i = 1; i <= (n); ++i)\n#define drep(i, n) for (ll i = (n) - 1; i >= 0; --i)\n#define nfor(i, s, n) for (ll i = s; i < n; i++) // i=s,s+1...n-1 ノーマルfor\n#define dfor(i, s, n) for (ll i = (s) - 1; i >= n; i--) // s-1スタートでnまで落ちる\n\nusing ld = long double;\nusing bl = bool;\n\ntemplate <class T>\nusing pq = priority_queue<T, vc<T>>; // 大きい順\ntemplate <class T>\nusing pq_g = priority_queue<T, vc<T>, greater<T>>; // 小さい順\n\nusing vl = vc<ll>;\nusing vvl = vv<ll>;\nusing vvvl = vv<vl>;\nusing vvvvl = vv<vvl>;\nusing vs = vc<string>;\nusing vvs = vv<string>;\nusing vb = vc<bl>;\nusing vvb = vv<bl>;\nusing vvvb = vv<vb>;\nusing vld = vc<ld>;\nusing vvld = vv<ld>;\nusing vvvld = vv<vld>;\nusing P = pair<ll, ll>;\nusing vP = vc<P>;\nusing vvP = vc<vP>;\nusing vvvP = vv<vP>;\n\n#define pb push_back\n\n#define YES cout << \"Yes\" << endl\n#define NO cout << \"No\" << endl\n#define YN \\\n { \\\n cout << \"Yes\" << endl; \\\n } \\\n else \\\n { \\\n cout << \"No\" << endl; \\\n } // if(a==b)YN;\n#define dame cout << -1 << endl\n\nstring dir = \"DRUL\"; // 第4象限の場合\nvl di = {1, 0, -1, 0}; // vl di={1,1,0,-1,-1,-1,0,1};\nvl dj = {0, 1, 0, -1}; // vl dj={0,1,1,1,0,-1,-1,-1};\n\nbool out_grid(ll i, ll j, ll h, ll w)\n{ // trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\nll ans = -1;\nll h, w, c;\n\nvoid dfs(vl &col,vvl &p)\n{\n vvl tmp = p;\n bl isFinished = true;\n rep(i, 5)\n {\n col[i]++;\n if (col[i] == 7)\n {\n col[i] = 1;\n }\n else\n {\n isFinished = false;\n break;\n }\n }\n if(isFinished){\n return;\n }\n // debug_vc(col);\n rep(color, 5)\n {\n // debug_vv(tmp);\n vvl dist(h, vl(w));\n dist[0][0] = tmp[0][0];\n tmp[0][0] = col[color];\n queue<P> que;\n que.push({0, 0});\n while (!que.empty())\n {\n auto [i, j] = que.front();\n que.pop();\n // xに隣接する頂点についてfor文\n rep(k, 4)\n {\n ll ni = i + di[k];\n ll nj = j + dj[k];\n if (out_grid(ni, nj, h, w))\n continue;\n if(dist[ni][nj]==0&&tmp[ni][nj]==dist[i][j]){\n que.push({ni,nj});\n tmp[ni][nj] = col[color];\n dist[ni][nj] = dist[i][j];\n }\n }\n }\n }\n if(tmp[0][0]==c){\n ll cnt = 1;\n vvl dist(h, vl(w));\n dist[0][0] = c;\n queue<P> que;\n que.push({0, 0});\n while (!que.empty())\n {\n auto [i, j] = que.front();\n que.pop();\n // xに隣接する頂点についてfor文\n rep(k, 4)\n {\n ll ni = i + di[k];\n ll nj = j + dj[k];\n if (out_grid(ni, nj, h, w))\n continue;\n if(dist[ni][nj]==0&&tmp[ni][nj]==dist[i][j]){\n que.push({ni,nj});\n dist[ni][nj] = dist[i][j];\n cnt++;\n }\n }\n }\n ans = max(cnt,ans);\n // debug_x(ans);\n }\n dfs(col,p);\n return;\n}\n\nbl solve()\n{\n cin >> h >> w >> c;\n if (h == 0 && w == 0 && c == 0)\n return 0;\n ans = -1;\n vvl p(h, vl(w));\n rep(i, h)\n {\n rep(j, w)\n {\n cin >> p[i][j];\n }\n }\n // 6^5通りすべて試す\n vl col(5, 1);\n col[0] = 0;\n dfs(col,p);\n cout << ans << endl;\n return 1;\n}\n\nsigned main()\n{\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n while (true)\n {\n if (!solve())\n break;\n }\n return 0;\n}\n\n/*\nshift+alt+Fで成形\nf2で変数名変更\n\nスニペット\nbasic\n m:atcoder以外用\n ma:ABC/ARC用\n mahc:AHC用\nmath\n floor:床関数\n ceil:天井関数\n comv:二項係数\n modpow: a^b mod m\n GCD:最大公約数\n extGCD:拡張ユークリッド互除法\n PFD:素因数分解\n isprime:エラトステネスの篩\n matrixpow:行列累乗\ndata_structure\n seg:セグメント木\ntechnic\n Compress:座標圧縮\n runlength:ランレングス圧縮\ngraph\n warshall:ワーシャルフロイド法\n dfs:深さ優先探索\n bfs:幅優先探索\n LCA:最近共通祖先\n*/", "accuracy": 1, "time_ms": 3520, "memory_kb": 12156, "score_of_the_acc": -1.6194, "final_rank": 20 }, { "submission_id": "aoj_1174_10601004", "code_snippet": "#include <bits/stdc++.h>\n\n#include <algorithm>\n#include <cassert>\n#include <vector>\n\nnamespace atcoder {\n\nstruct dsu {\n public:\n dsu() : _n(0) {}\n explicit dsu(int n) : _n(n), parent_or_size(n, -1) {}\n\n int merge(int a, int b) {\n assert(0 <= a && a < _n);\n assert(0 <= b && b < _n);\n int x = leader(a), y = leader(b);\n if (x == y) return x;\n if (-parent_or_size[x] < -parent_or_size[y]) std::swap(x, y);\n parent_or_size[x] += parent_or_size[y];\n parent_or_size[y] = x;\n return x;\n }\n\n bool same(int a, int b) {\n assert(0 <= a && a < _n);\n assert(0 <= b && b < _n);\n return leader(a) == leader(b);\n }\n\n int leader(int a) {\n assert(0 <= a && a < _n);\n return _leader(a);\n }\n\n int size(int a) {\n assert(0 <= a && a < _n);\n return -parent_or_size[leader(a)];\n }\n\n std::vector<std::vector<int>> groups() {\n std::vector<int> leader_buf(_n), group_size(_n);\n for (int i = 0; i < _n; i++) {\n leader_buf[i] = leader(i);\n group_size[leader_buf[i]]++;\n }\n std::vector<std::vector<int>> result(_n);\n for (int i = 0; i < _n; i++) {\n result[i].reserve(group_size[i]);\n }\n for (int i = 0; i < _n; i++) {\n result[leader_buf[i]].push_back(i);\n }\n result.erase(\n std::remove_if(result.begin(), result.end(),\n [&](const std::vector<int>& v) { return v.empty(); }),\n result.end());\n return result;\n }\n\n private:\n int _n;\n std::vector<int> parent_or_size;\n\n int _leader(int a) {\n if (parent_or_size[a] < 0) return a;\n return parent_or_size[a] = _leader(parent_or_size[a]);\n }\n};\n\n} // namespace atcoder\n\nusing namespace std;\nusing namespace atcoder;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rrep(i,start,end) for (ll i = start;i >= (ll)(end);i--)\n#define repn(i,end) for(ll i = 0; i <= (ll)(end); i++)\n#define reps(i,start,end) for(ll i = start; i < (ll)(end); i++)\n#define repsn(i,start,end) for(ll i = start; i <= (ll)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef vector<ll> vll;\ntypedef vector<pair<ll ,ll>> vpll;\ntypedef vector<vector<ll>> vvll;\ntypedef set<ll> sll;\ntypedef map<ll , ll> mpll;\ntypedef pair<ll ,ll> pll;\ntypedef tuple<ll , ll , ll> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (ll)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1LL << 60;\nconst ld EPS = 1e-9;\n \nll lceil(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b)+1;}else{return -((-a)/b);}}\nll lfloor(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b);}else{return -((-a)/b)-1;}}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\n//0indexed\ninline ll topbit(ll a){assert(a != 0);return 63 - __builtin_clzll(a);}\ninline ll smlbit(ll a){assert(a != 0);return __builtin_ctzll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\n// for AOJ or ICPC or etc..\ntemplate<class Tp>\nbool zero (const Tp &x) {\n return x == 0;\n}\n\ntemplate<class Tp, class... Args>\nbool zero (const Tp &x, const Args& ...args) {\n return zero(x) and zero(args...);\n}\n\n\n\nvoid solve(ll h,ll w,ll c){\n vvll a(h,vll(w));\n rep(i,h){\n cin >> a[i];\n }\n\n ll ans =0;\n \n auto clc = [&](auto clc,vvll state,ll num)->void {\n if(num == 5){//5回目\n //cで塗って終わり\n vvll found(h,vll(w));\n ll basec = state[0][0];\n auto dfs = [&](auto dfs, ll i,ll j)->void {\n found[i][j] = 1; \n state[i][j] = c;\n rep(k,4){\n ll ny = i + _ta[k];\n ll nx = j + _yo[k];\n if(isin(ny,nx,h,w)&& state[ny][nx] == basec && found[ny][nx] == 0){\n dfs(dfs,ny,nx);\n }\n } \n };\n dfs(dfs,0,0);\n dsu uf(h*w);\n rep(i,h){\n rep(j,w){\n rep(k,4){\n ll ny = i+_ta[k];\n ll nx = j + _yo[k];\n if(isin(ny,nx,h,w)&&state[i][j] == state[ny][nx]){\n uf.merge(i*w+j,ny*w+nx);\n }\n }\n }\n }\n chmax(ans,(ll)uf.size(0));\n // if(chmax(ans,(ll)uf.size(0))){\n // rep(i,h){\n // cout << state[i] << endl;\n // }\n // cout << endl;\n // }\n return ;\n }\n\n //6色試す\n repsn(nc,1,6){\n vvll nstate = state;\n vvll found(h,vll(w));\n ll basec = state[0][0];\n auto dfs = [&](auto dfs, ll i,ll j)->void {\n found[i][j] = 1; \n nstate[i][j] = nc;\n rep(k,4){\n ll ny = i + _ta[k];\n ll nx = j + _yo[k];\n if(isin(ny,nx,h,w)&& state[ny][nx] == basec && found[ny][nx] == 0){\n dfs(dfs,ny,nx);\n }\n } \n };\n dfs(dfs,0,0);\n clc(clc,nstate,num+1);\n }\n };\n clc(clc,a,1);\n cout << ans << endl;\n}\n\n \nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true){\n LL(h,w,c);\n if(zero(h,w,c))break;\n solve(h,w,c);\n }\n}", "accuracy": 1, "time_ms": 390, "memory_kb": 3584, "score_of_the_acc": -0.1405, "final_rank": 7 }, { "submission_id": "aoj_1174_10599531", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<long long>;\nusing vs = vector<string>;\nusing vc = vector<char>;\nusing vb = vector<bool>;\nusing vpii = vector<pair<int, int>>;\nusing vpll = vector<pair<long long, long long>>;\nusing vvi = vector<vector<int>>;\nusing vvl = vector<vector<long long>>;\nusing vvc = vector<vector<char>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing pii = pair<int, int>;\nusing vvb = vector<vector<bool>>;\nusing Graph = vector<vector<ll>>;\nconst ll LINF = 1001002003004005006ll;\nconst int INF = 1001001001;\nconst int MOD = 998244353;\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep3(i, m, n) for (int i = (m); i < (int)(n); i++)\n#define rrep(i, m, n) for (int i = (m); i >= (int)(n); i--)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\nvi dx4 = {1, 0, -1, 0}, dy4 = {0, 1, 0, -1};\nvi dx8 = {1, 1, 1, 0, 0, -1, -1, -1}, dy8 = {1, 0, -1, 1, -1, 1, 0, -1};\n\nbool solve()\n{\n int H, W, c;\n cin >> H >> W >> c;\n if (H == 0)\n return false;\n vector<vector<int>> P(H, vector<int>(W));\n for (int i = 0; i < H; i++)\n {\n for (int j = 0; j < W; j++)\n {\n cin >> P[i][j];\n }\n }\n\n auto bfs = [&](vector<vector<int>> &F)\n {\n unordered_set<int> ret;\n queue<int> que;\n que.push(0);\n ret.insert(0);\n while (!que.empty())\n {\n int v = que.front();\n int x = v / W;\n int y = v % W;\n que.pop();\n for (int d = 0; d < 4; d++)\n {\n int nx = x + dx4[d], ny = y + dy4[d];\n if (nx < 0 || nx >= H || ny < 0 || ny >= W)\n {\n continue;\n }\n if (F[x][y] != F[nx][ny])\n {\n continue;\n }\n int idx = nx * W + ny;\n if (ret.count(idx))\n {\n continue;\n }\n ret.insert(idx);\n que.push(idx);\n }\n }\n return ret;\n };\n\n int ans = 0;\n auto f = [&](auto f, int k, vector<vector<int>> &P)\n {\n if (k == 5)\n {\n auto se = bfs(P);\n if (P[0][0] == c)\n ans = max(ans, (int)se.size());\n\n return;\n }\n\n auto se = bfs(P);\n\n for (int col = 1; col < 7; col++)\n {\n vector<vector<int>> new_P = P;\n\n for (auto idx : se)\n {\n int i = idx / W;\n int j = idx % W;\n new_P[i][j] = col;\n }\n f(f, k + 1, new_P);\n }\n\n return;\n };\n\n f(f, 0, P);\n cout << ans << endl;\n return true;\n}\nint main()\n{\n while (solve())\n ;\n return 0;\n}", "accuracy": 1, "time_ms": 1880, "memory_kb": 3180, "score_of_the_acc": -0.3647, "final_rank": 15 }, { "submission_id": "aoj_1174_10291848", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define all(a) a.begin(),a.end()\n#define reps(i, a, n) for (int i = (a); i < (int)(n); i++)\n#define rep(i, n) reps(i, 0, n)\n#define rreps(i, a, n) for (int i = (a); i > (int)(n); i--)\nconst long long mod = 1000000007;\nconst long long INF = 1e18;\nll myceil(ll a, ll b) {return (a+b-1)/b;}\n\n\nint h,w,c;\n\nvector<vector<int>> v(h,vector<int> (w));\nvector<vector<int>> con;\nvector<vector<int>> gp;\nint ans;\n\n\n\nvoid f(int tm, int col) {\n auto vv = v;\n auto cc = con;\n rep(i,h) {\n rep(j,w) {\n if (con[i][j]) {\n v[i][j] = col;\n }\n if (i != 0 && con[i-1][j] && v[i][j] == col) {\n con[i][j] = 1;\n for (auto x : gp[i*w+j]) {\n con[x/w][x%w] = 1;\n }\n }\n if (j != 0 && con[i][j-1] && v[i][j] == col) {\n con[i][j] = 1;\n for (auto x : gp[i*w+j]) {\n con[x/w][x%w] = 1;\n }\n }\n if (i != h-1 && con[i+1][j] && v[i][j] == col) {\n con[i][j] = 1;\n for (auto x : gp[i*w+j]) {\n con[x/w][x%w] = 1;\n }\n }\n if (j != w-1 && con[i][j+1] && v[i][j] == col) {\n con[i][j] = 1;\n for (auto x : gp[i*w+j]) {\n con[x/w][x%w] = 1;\n }\n }\n }\n }\n\n if (tm <= 3) {\n reps(i,1,7) f(tm+1,i);\n }\n else if (tm == 4) {\n f(tm+1,c);\n }\n else {\n int temp = 0;\n rep(i,h) {\n rep(j,w) {\n temp += con[i][j];\n }\n }\n ans = max(ans,temp);\n }\n\n v = vv;\n con = cc;\n\n}\n\n\n\n\nvoid solve() {\n ans = 0;\n v.resize(h);\n rep(i,h) v[i].resize(w);\n\n con.resize(h);\n rep(i,h) con[i].resize(w); \n\n\n rep(i,h) {\n rep(j,w) {\n cin >> v[i][j];\n con[i][j] = 0;\n }\n }\n\n con[0][0] = 1;\n\n gp.resize(0);\n gp.resize(h*w);\n\n\n rep(i,h) {\n rep(j,w) {\n if (i != h-1) {\n if (v[i][j] == v[i+1][j]) {\n for (auto x : gp[i*w+j]) {\n gp[x].push_back((i+1)*w+j);\n gp[(i+1)*w+j].push_back(x);\n }\n\n gp[i*w+j].push_back((i+1)*w+j);\n gp[(i+1)*w+j].push_back(i*w+j);\n\n }\n }\n if (j != w-1) {\n if (v[i][j] == v[i][j+1]) {\n for (auto x : gp[i*w+j]) {\n gp[x].push_back(i*w+j+1);\n gp[i*w+j+1].push_back(x);\n }\n\n gp[i*w+j].push_back(i*w+j+1);\n gp[i*w+j+1].push_back(i*w+j);\n\n }\n }\n }\n }\n\n for (auto x : gp[0]) {\n con[x/w][x%w] = 1;\n }\n\n\n reps(i,1,7) {\n f(1,i);\n }\n\n cout << ans << endl;\n return;\n}\n\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n\n while (cin >> h >> w >> c && h != 0) {\n solve();\n }\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 480, "memory_kb": 3416, "score_of_the_acc": -0.1386, "final_rank": 6 }, { "submission_id": "aoj_1174_10291794", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n// #pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = acos(-1.0);\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\ntemplate<typename T> void view(const vv<T>& vv){ for(const auto& v : vv){ view(v); } }\nvi dx = {1, 0, -1, 0}, dy = {0, 1, 0, -1};\nint seen[8][8];\nint h, w, c;\nint P[8][8];\nint ans = 0, turn = 1;\n\nvc<pair<int, int>> search(){\n turn++;\n vc<pair<int, int>> ret;\n deque<pair<int, int>> q;\n q.push_back({0, 0});\n ret.push_back({0, 0});\n seen[0][0] = turn;\n while (!q.empty()){\n auto [i, j] = q.front(); q.pop_front();\n rep(k, 4){\n int ni = i + dx[k], nj = j + dy[k];\n if (inside(ni, nj, h, w) && seen[ni][nj] < turn && P[i][j] == P[ni][nj]){\n seen[ni][nj] = turn;\n ret.push_back({ni, nj});\n q.push_back({ni, nj});\n }\n }\n }\n return ret;\n}\n\nvoid f(int x){\n int last = P[0][0];\n vc<pair<int, int>> S = search();\n if (x == 4){\n for (auto [i, j] : S) P[i][j] = c;\n ans = max(ans, len(search()));\n for (auto [i, j] : S) P[i][j] = last;\n return;\n }\n srep(nc, 1, 7){\n for (auto [i, j] : S) P[i][j] = nc;\n f(x + 1);\n }\n for (auto [i, j] : S) P[i][j] = last;\n}\nvoid solve(){\n ans = 0;\n rep(i, h) rep(j, w) cin >> P[i][j];\n f(0);\n cout << ans << endl;\n}\nint main(){\n rep(i, 8) rep(j, 8) seen[i][j] = 0;\n while (true){\n cin >> h >> w >> c;\n if (h == 0) break;\n solve();\n }\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3328, "score_of_the_acc": -0.07, "final_rank": 3 }, { "submission_id": "aoj_1174_9859840", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<long long, long long>;\n#define rep(i, a, b) for(long long i = (a); i < (b); ++i)\n#define rrep(i, a, b) for(long long i = (a); i >= (b); --i)\nconstexpr long long inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\nstruct UnionFind {\n UnionFind(const int N)\n : n(N), data(N, -1) {}\n int merge(const int a, const int b) {\n assert(0 <= a and a < n);\n assert(0 <= b and b < n);\n int x = leader(a), y = leader(b);\n if(x == y) return x;\n if(-data[x] < -data[y]) swap(x, y);\n data[x] += data[y];\n data[y] = x;\n return x;\n }\n bool same(const int a, const int b) {\n assert(0 <= a and a < n);\n assert(0 <= b and b < n);\n return leader(a) == leader(b);\n }\n int leader(const int a) {\n assert(0 <= a and a < n);\n if(data[a] < 0) return a;\n return data[a] = leader(data[a]);\n }\n int size(const int a) {\n assert(0 <= a and a < n);\n return -data[leader(a)];\n }\n vector<vector<int>> groups() {\n vector<int> leader_buf(n), group_size(n);\n for(int i = 0; i < n; ++i) {\n leader_buf[i] = leader(i);\n ++group_size[leader_buf[i]];\n }\n vector<vector<int>> result(n);\n for(int i = 0; i < n; ++i) {\n result[i].reserve(group_size[i]);\n }\n for(int i = 0; i < n; ++i) {\n result[leader_buf[i]].push_back(i);\n }\n result.erase(remove_if(result.begin(), result.end(), [&](const vector<int>& v) { return v.empty(); }), result.end());\n return result;\n }\n\n private:\n int n;\n vector<int> data;\n};\nint main(void) {\n constexpr int di[4] = {1, 0, -1, 0}, dj[4] = {0, 1, 0, -1};\n while(1) {\n int h, w, c;\n cin >> h >> w >> c;\n if(h == 0 and w == 0 and c == 0) break;\n c--;\n vector<vector<int>> p(h, vector<int>(w));\n rep(i, 0, h) {\n rep(j, 0, w) {\n cin >> p[i][j];\n p[i][j]--;\n }\n }\n auto dfs = [&](auto& dfs, const vector<vector<int>>& col, int t) -> int {\n UnionFind uf(h * w);\n rep(i, 0, h) {\n rep(j, 0, w) {\n rep(d, 0, 4) {\n int ni = i + di[d], nj = j + dj[d];\n if(0 <= ni and ni < h and 0 <= nj and nj < w and col[i][j] == col[ni][nj]) {\n uf.merge(i * w + j, ni * w + nj);\n }\n }\n }\n }\n if(t == 0) {\n if(col[0][0] == c) return uf.size(0);\n return 0;\n }\n int res = 0;\n rep(k, 0, 6) {\n vector<vector<int>> nex = col;\n rep(i, 0, h) {\n rep(j, 0, w) {\n if(uf.same(i * w + j, 0)) {\n nex[i][j] = k;\n }\n }\n }\n res = max(res, dfs(dfs, nex, t - 1));\n }\n return res;\n };\n cout << dfs(dfs, p, 5) << '\\n';\n }\n}", "accuracy": 1, "time_ms": 1590, "memory_kb": 3492, "score_of_the_acc": -0.3461, "final_rank": 14 }, { "submission_id": "aoj_1174_9717144", "code_snippet": "#include <bits/stdc++.h>\n using namespace std;\n \n template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\n template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n #define rep(i,n) for (int i = 0; i < (n); ++i)\n\n typedef long long ll;\n typedef unsigned long long ull;\n using P=pair<ll,ll>;\n using T=tuple<int,int,int>;\n const int INF=1001001001;\n const ll INFL=1e18;\n const int mod=998244353;\n\t\n\tint dx[4]={1,-1,0,0},dy[4]={0,0,1,-1};\n bool solve(){\n\t\tint n,m,col;\n\t\tcin>>n>>m>>col;\n\t\tif(!n&&!m&&!col)return false;\n\n\t\tvector<vector<int>>p(n,vector<int>(m));\n\t\trep(i,n){\n\t\t\trep(j,m){\n\t\t\t\tcin>>p[i][j];\n\t\t\t}\n\t\t}\n\n\t\tauto paint=[&](int col,vector<vector<int>>& t){\n\t\t\tqueue<P>q;\n\t\t\tq.push({0,0});\n\t\t\tvector<vector<int>>vis(n,vector<int>(m));\n\t\t\tvis[0][0]=1;\n\t\t\tint connect=t[0][0];\n\t\t\tt[0][0]=col;\n\t\t\tint cnt=0;\n\t\t\twhile(q.size()){\n\t\t\t\tauto [i,j]=q.front();q.pop();\n\t\t\t\tcnt++;\n\t\t\t\trep(k,4){\n\t\t\t\t\tint ni=i+dx[k],nj=j+dy[k];\n\t\t\t\t\tif(ni<0||ni>=n||nj<0||nj>=m)continue;\n\t\t\t\t\tif(t[ni][nj]==connect&&vis[ni][nj]==0){\n\t\t\t\t\t\tq.push({ni,nj});\n\t\t\t\t\t\tt[ni][nj]=col;\n\t\t\t\t\t\tvis[ni][nj]=1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\treturn cnt;\n\t\t};\n\n\t\tint ans=0;\n\t\tfor(int a=1;a<=6;a++){\n\t\t\tfor(int b=1;b<=6;b++){\n\t\t\t\tfor(int c=1;c<=6;c++){\n\t\t\t\t\tfor(int d=1;d<=6;d++){\n\t\t\t\t\t\tauto t=p;\n\t\t\t\t\t\tint cnt=paint(a,t);\n\t\t\t\t\t\tcnt=paint(b,t);\n\t\t\t\t\t\tcnt=paint(c,t);\n\t\t\t\t\t\tcnt=paint(d,t);\n\t\t\t\t\t\tcnt=paint(col,t);\n\n\t\t\t\t\t\tcnt=paint(t[0][0],t);\n\t\t\t\t\t\tchmax(ans,cnt);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout<<ans<<endl;\n\t\treturn true;\n }\n\n int main(){\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n\t\twhile(1){\n\t\t\tif(!solve())break;\n\t\t}\n\t\t\n return 0;\n }", "accuracy": 1, "time_ms": 510, "memory_kb": 3456, "score_of_the_acc": -0.1483, "final_rank": 9 }, { "submission_id": "aoj_1174_9518698", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint ANS;\nqueue<pair<int,int>> Q;\nint dx[4] = {1,0,-1,0}, dy[4] = {0,1,0,-1};\n\nvoid DFS(int H, int W, int C, vector<vector<int>> A, int X) {\n vector<vector<bool>> Flag(H,vector<bool>(W,false));\n Flag[0][0] = true;\n Q.push({0,0});\n while(!Q.empty()) {\n pair<int,int> P = Q.front();\n Q.pop();\n rep(i,0,4) {\n int NX = P.first + dx[i], NY = P.second + dy[i];\n if (NX < 0 || H <= NX || NY < 0 || W <= NY) continue;\n if (!Flag[NX][NY] && (A[NX][NY] == A[0][0])) {\n Flag[NX][NY] = true;\n Q.push({NX,NY});\n }\n }\n }\n if (X == 5) {\n if (A[0][0] != C) return;\n int COUNT = 0;\n rep(i,0,H) rep(j,0,W) if (Flag[i][j]) COUNT++;\n chmax(ANS, COUNT);\n return;\n }\n rep(i,1,7) {\n vector<vector<int>> B = A;\n rep(j,0,H) rep(k,0,W) if (Flag[j][k]) B[j][k] = i;\n DFS(H,W,C,B,X+1);\n }\n return;\n}\n\nint main() {\nwhile(1) {\n int H, W, C;\n cin >> H >> W >> C;\n if (H == 0) return 0;\n vector<vector<int>> A(H,vector<int>(W));\n rep(i,0,H) rep(j,0,W) cin >> A[i][j];\n ANS = 0;\n DFS(H,W,C,A,0);\n cout << ANS << endl;\n}\n}", "accuracy": 1, "time_ms": 1790, "memory_kb": 3528, "score_of_the_acc": -0.3858, "final_rank": 17 }, { "submission_id": "aoj_1174_9371213", "code_snippet": "#include <algorithm>\n#include <cmath>\n#include <functional>\n#include <iostream>\n#include <string>\n#include <vector>\nusing namespace std;\n#include <stdio.h>\n#include <stdlib.h>\n\n#include <bitset>\n#include <queue>\n#include <unordered_map>\n\n#define ll long long\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define repl(i, l, n) for (int i = l; i < (int)(n); i++)\n#define mod(a, b) (a % b + b) % b\nint cmp(const void* x, const void* y) {\n if (*(int*)x > *(int*)y) {\n return 1;\n } else if (*(int*)x < *(int*)y) {\n return -1;\n } else {\n return 0;\n }\n}\nint* imalloc(int n) {\n int* ret = (int*)malloc(sizeof(int) * n);\n return ret;\n}\n// N の約数をすべて求める関数\nvector<long long> calc_divisors(long long N) {\n vector<long long> res;\n for (long long i = 1; i * i <= N; ++i) {\n if (N % i != 0) continue;\n res.push_back(i);\n if (N / i != i) res.push_back(N / i);\n }\n sort(res.begin(), res.end());\n return res;\n}\n// カスタムハッシュ関数\nstruct pair_hash {\n template <class T1, class T2>\n std::size_t operator()(const std::pair<T1, T2>& pair) const {\n return std::hash<T1>()(pair.first) ^ std::hash<T2>()(pair.second);\n }\n};\n// ベクターと座標,tc色をcに塗りつぶして面積を返す関数\nvoid paint(vector<vector<int> >* p, vector<vector<int> >* tmp, int h, int w,\n int i, int j, int c, int tc) {\n if (i != 0) {\n if ((p[0][i - 1][j] == tc) && tmp[0][i - 1][j] == 0) {\n p[0][i - 1][j] = c;\n tmp[0][i - 1][j] = 1;\n paint(p, tmp, h, w, i - 1, j, c, tc);\n }\n }\n if (j != 0) {\n if ((p[0][i][j - 1] == tc) && tmp[0][i][j - 1] == 0) {\n p[0][i][j - 1] = c;\n tmp[0][i][j - 1] = 1;\n paint(p, tmp, h, w, i, j - 1, c, tc);\n }\n }\n if (i != h - 1) {\n if ((p[0][i + 1][j] == tc) && tmp[0][i + 1][j] == 0) {\n p[0][i + 1][j] = c;\n tmp[0][i + 1][j] = 1;\n paint(p, tmp, h, w, i + 1, j, c, tc);\n }\n }\n if (j != w - 1) {\n if ((p[0][i][j + 1] == tc) && tmp[0][i][j + 1] == 0) {\n p[0][i][j + 1] = c;\n tmp[0][i][j + 1] = 1;\n paint(p, tmp, h, w, i, j + 1, c, tc);\n }\n }\n}\nint paintcount(vector<vector<int> >* p, vector<vector<int> >* tmp, int h, int w,\n int i, int j, int c) {\n if (tmp[0][i][j] == 0) tmp[0][i][j] = 1;\n int size = 1;\n if (i > 0) {\n if ((p[0][i - 1][j] == c) && tmp[0][i - 1][j] == 0) {\n tmp[0][i - 1][j] = 1;\n size += paintcount(p, tmp, h, w, i - 1, j, c);\n }\n }\n if (j > 0) {\n if ((p[0][i][j - 1] == c) && tmp[0][i][j - 1] == 0) {\n p[0][i][j - 1] = c;\n tmp[0][i][j - 1] = 1;\n size += paintcount(p, tmp, h, w, i, j - 1, c);\n }\n }\n if (i < h - 1) {\n if ((p[0][i + 1][j] == c) && tmp[0][i + 1][j] == 0) {\n p[0][i + 1][j] = c;\n tmp[0][i + 1][j] = 1;\n size += paintcount(p, tmp, h, w, i + 1, j, c);\n }\n }\n if (j < w - 1) {\n if ((p[0][i][j + 1] == c) && tmp[0][i][j + 1] == 0) {\n p[0][i][j + 1] = c;\n tmp[0][i][j + 1] = 1;\n size += paintcount(p, tmp, h, w, i, j + 1, c);\n }\n }\n return size;\n}\n\nint main() {\n while (1) {\n int h, w, c;\n int ret = 0;\n cin >> h >> w >> c;\n if (h == 0 && w == 0 && c == 0) return 0;\n vector<vector<int> > p = vector<vector<int> >(h, vector<int>(w, 0));\n vector<vector<int> > pcopy = vector<vector<int> >(h, vector<int>(w, 0));\n vector<vector<int> > tmp = vector<vector<int> >(h, vector<int>(w, 0));\n rep(i, h) {\n rep(j, w) { cin >> p[i][j]; }\n }\n // うるせえ!全探索しよう!!!\n int nowcolor;\n int nextcolor;\n rep(k, pow(6, 6)) {\n // int k = pow(6, 5) + pow(6, 4) * 2 + pow(6, 3) * 3 + pow(6, 2) * 4 +\n // pow(6, 1) * 5;\n rep(i, h) {\n rep(j, w) { pcopy[i][j] = p[i][j]; }\n }\n nowcolor = pcopy[0][0];\n repl(j, 1, 5) {\n nextcolor = (k / (int)pow(6, j - 1)) % 6 + 1;\n paint(&pcopy, &tmp, h, w, 0, 0, nextcolor, nowcolor);\n nowcolor = nextcolor;\n rep(i, h) {\n rep(j, w) { tmp[i][j] = 0; }\n }\n // tmp = vector<vector<int> >(h, vector<int>(w, 0));\n // cout << endl << \"itr\" << j << endl;\n // rep(i, h) {\n // rep(j, w) { cout << pcopy[i][j] << ' '; }\n // cout << endl;\n // }\n }\n // cout << endl;\n nextcolor = c;\n paint(&pcopy, &tmp, h, w, 0, 0, nextcolor, nowcolor);\n nowcolor = nextcolor;\n rep(i, h) {\n rep(j, w) { tmp[i][j] = 0; }\n }\n int maxtmp = paintcount(&pcopy, &tmp, h, w, 0, 0, nowcolor);\n rep(i, h) {\n rep(j, w) { tmp[i][j] = 0; }\n }\n // cout << maxtmp << ' ';\n ret = max(maxtmp, ret);\n }\n\n cout << ret << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 5630, "memory_kb": 3764, "score_of_the_acc": -1.1005, "final_rank": 19 }, { "submission_id": "aoj_1174_9205668", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nll ans = 0;\nll h,w,c;\n\ntemplate<typename TN>\nvoid print2DVector(const std::vector<std::vector<TN>>& vec, bool debug=false) {\n\n for (const auto& row : vec) {\n for (const auto& elem : row) {\n std::cout << elem << ' ';\n }\n std::cout << '\\n';\n }\n\n if (debug) {\n cout << \"----------------------------------------------------debug----------------------------------------------------\\n\";\n }\n}\nint dx[4] = {1, 0, -1, 0}; int dy[4] = {0, 1, 0, -1};\nll bfs(vector<vector<ll>> &G,vector<vector<ll>> &seen, ll to_col) {\n ll from_col = G[0][0];\n\n queue<pair<ll, ll>> que;\n que.push({0,0});\n seen[0][0] = 1;\n G[0][0] = to_col;\n\n ll ct = 0;\n while (!que.empty()) {\n auto [x,y] = que.front();\n que.pop();\n\n for (ll i = 0; i < 4; ++i) {\n ll nx = x + dx[i];\n ll ny = y + dy[i];\n\n if (nx >= 0 && nx < h && ny < w && ny >= 0 && seen[nx][ny]!=1 && G[nx][ny]==from_col) {\n que.push({nx,ny});\n seen[nx][ny] = 1;\n G[nx][ny] = to_col;\n }\n }\n ++ct;\n }\n\n return ct;\n}\n\nvoid dfs(vector<vector<ll>> G, ll ct, ll now) {\n if (ct==6) {\n ct = 0;\n vector<vector<ll>> seen(h, vector<ll>(w,0));\n if (G[0][0] == c) ct = bfs(G,seen,-1);\n ans = max(ct,ans);\n return;\n }\n\n if (now != -1) {\n vector<vector<ll>> seen(h, vector<ll>(w,0));\n bfs(G,seen,now);\n // print2DVector(G,true);\n }\n\n for (ll i = 0; i < 6; ++i) {\n dfs(G,ct+1,i);\n }\n}\nvoid solve() {\n while (1 ) {\n // ll h,w,c;\n cin >> h >> w >> c;\n if (h==0) break;\n --c;\n ans = 0;\n vector<vector<ll>> G(h);\n for (ll i = 0; i < h; ++i) {\n for (ll j = 0; j < w; ++j) {\n ll tmp;\n cin >> tmp;\n --tmp;\n G[i].push_back(tmp);\n }\n }\n\n dfs(G,0,-1);\n cout << ans << endl;\n\n }\n}\n\nint main() {\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 5640, "memory_kb": 3372, "score_of_the_acc": -1.0603, "final_rank": 18 }, { "submission_id": "aoj_1174_9151166", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <set>\n\nusing namespace std;\n\nint dx[] = {0, 1, 0, -1};\nint dy[] = {-1, 0, 1, 0};\n\nint main() {\n while (true) {\n int H, W, C;\n cin >> H >> W >> C;\n if (H == 0 && W == 0 && C == 0)break;\n vector<vector<int>> P(H, vector<int>(W));\n for (int i = 0; i < H; i++)for (int j = 0; j < W; j++)cin >> P[i][j];\n int ans = 0;\n queue<pair<vector<vector<int>>, int>> Q;\n set<vector<vector<int>>> vis;\n Q.push({P, 0});\n vis.insert(P);\n while (!Q.empty()) {\n auto [grid, cnt] = Q.front();Q.pop();\n if (cnt >= 5)continue;\n for (int col = 1; col <= 6; col++) {\n auto next_grid = grid;\n int prev_col = grid[0][0];\n next_grid[0][0] = col;\n queue<pair<int, int>> q;\n vector<vector<bool>> used(H, vector<bool>(W, false));\n q.push({0, 0});\n used[0][0] = true;\n while (!q.empty()) {\n auto [x, y] = q.front();q.pop();\n for (int i = 0; i < 4; i++) {\n int nx = x + dx[i], ny = y + dy[i];\n if (!(0 <= nx && nx < H && 0 <= ny && ny < W) || used[nx][ny])continue;\n if (next_grid[nx][ny] == prev_col) {\n next_grid[nx][ny] = col;\n used[nx][ny] = true;\n q.push({nx, ny});\n }\n }\n }\n if (!vis.count(next_grid)) {\n vis.insert(next_grid);\n Q.push({next_grid, cnt + 1});\n }\n int res = 0;\n for(int i = 0;i < H;i++)for(int j = 0;j < W;j++)used[i][j] = false;\n q.push({0, 0});\n used[0][0] = true;\n while (!q.empty()) {\n auto [x, y] = q.front();q.pop();\n res++;\n for (int i = 0; i < 4; i++) {\n int nx = x + dx[i], ny = y + dy[i];\n if (!(0 <= nx && nx < H && 0 <= ny && ny < W) || used[nx][ny])continue;\n if (next_grid[nx][ny] == col) {\n used[nx][ny] = true;\n q.push({nx, ny});\n }\n }\n }\n if (col == C)ans = max(ans, res);\n }\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 3932, "score_of_the_acc": -0.1436, "final_rank": 8 }, { "submission_id": "aoj_1174_9148841", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <set>\n\nusing namespace std;\n\nint dx[] = {0, 1, 0, -1};\nint dy[] = {-1, 0, 1, 0};\n\nint main() {\n while (true) {\n int H, W, C;\n cin >> H >> W >> C;\n if (H == 0 && W == 0 && C == 0)break;\n vector<vector<int>> P(H, vector<int>(W));\n for (int i = 0; i < H; i++)for (int j = 0; j < W; j++)cin >> P[i][j];\n int ans = 0;\n queue<pair<vector<vector<int>>, int>> Q;\n set<vector<vector<int>>> vis;\n Q.push({P, 0});\n vis.insert(P);\n while (!Q.empty()) {\n auto [grid, cnt] = Q.front();Q.pop();\n if (cnt >= 5)continue;\n for (int col = 1; col <= 6; col++) {\n auto next_grid = grid;\n int prev_col = grid[0][0];\n next_grid[0][0] = col;\n queue<pair<int, int>> q;\n vector<vector<bool>> used(H, vector<bool>(W, false));\n q.push({0, 0});\n used[0][0] = true;\n while (!q.empty()) {\n auto [x, y] = q.front();q.pop();\n for (int i = 0; i < 4; i++) {\n int nx = x + dx[i], ny = y + dy[i];\n if (!(0 <= nx && nx < H && 0 <= ny && ny < W) || used[nx][ny])continue;\n if (next_grid[nx][ny] == prev_col) {\n next_grid[nx][ny] = col;\n used[nx][ny] = true;\n q.push({nx, ny});\n }\n }\n }\n if (!vis.count(next_grid)) {\n vis.insert(next_grid);\n Q.push({next_grid, cnt + 1});\n }\n int res = 0;\n for(int i = 0;i < H;i++)for(int j = 0;j < W;j++)used[i][j] = false;\n q.push({0, 0});\n used[0][0] = true;\n while (!q.empty()) {\n auto [x, y] = q.front();q.pop();\n res++;\n for (int i = 0; i < 4; i++) {\n int nx = x + dx[i], ny = y + dy[i];\n if (!(0 <= nx && nx < H && 0 <= ny && ny < W) || used[nx][ny])continue;\n if (next_grid[nx][ny] == col) {\n used[nx][ny] = true;\n q.push({nx, ny});\n }\n }\n }\n if (col == C)ans = max(ans, res);\n }\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 4312, "score_of_the_acc": -0.1842, "final_rank": 12 }, { "submission_id": "aoj_1174_9148813", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <map>\n#include <cmath>\n#include <queue>\n#include <string>\n#include <set>\n#include <stack>\n#include <numeric>\n#include <functional>\n#include <bitset>\n\nusing namespace std;\nusing ll = long long;\n\n\n/*\n幅優先探索(bfs)\n1.左上の色を変更する\n2.変える前の色と同じ色も同じく変更する\n3.そのパネルの大きさと最大値を比べて更新する\n*/\n\nint dx[] = {0, 1, 0, -1};\nint dy[] = {-1, 0, 1, 0};\n\nint main() {\n while (true) {\n int H, W, C;\n cin >> H >> W >> C;\n if (H == 0 && W == 0 && C == 0)break;\n vector<vector<int>> P(H, vector<int>(W));\n for (int i = 0; i < H; i++)for (int j = 0; j < W; j++)cin >> P[i][j];\n\n int ans = 0;\n queue<pair<vector<vector<int>>, int>> Q;\n set<vector<vector<int>>> vis;\n Q.push({P, 0});\n vis.insert(P);\n while (!Q.empty()) {\n auto [grid, cnt] = Q.front();Q.pop();\n if (cnt >= 5)continue;\n for (int col = 1; col <= 6; col++) {\n // 左上の色を変更する\n auto next_grid = grid;\n int prev_col = grid[0][0];\n next_grid[0][0] = col;\n\n // 変える前の色と同じ色も同じく変更する\n queue<pair<int, int>> q;\n vector<vector<bool>> used(H, vector<bool>(W, false));\n q.push({0, 0});\n used[0][0] = true;\n while (!q.empty()) {\n auto [x, y] = q.front();q.pop();\n for (int i = 0; i < 4; i++) {\n int nx = x + dx[i], ny = y + dy[i];\n if (!(0 <= nx && nx < H && 0 <= ny && ny < W) || used[nx][ny])continue;\n if (next_grid[nx][ny] == prev_col) {\n next_grid[nx][ny] = col;\n used[nx][ny] = true;\n q.push({nx, ny});\n }\n }\n }\n if (!vis.count(next_grid)) {\n vis.insert(next_grid);\n Q.push({next_grid, cnt + 1});\n }\n \n // そのパネルの大きさと最大値を比べて更新する\n int res = 0;\n for(int i = 0;i < H;i++)for(int j = 0;j < W;j++)used[i][j] = false;\n q.push({0, 0});\n used[0][0] = true;\n while (!q.empty()) {\n auto [x, y] = q.front();q.pop();\n res++;\n for (int i = 0; i < 4; i++) {\n int nx = x + dx[i], ny = y + dy[i];\n if (!(0 <= nx && nx < H && 0 <= ny && ny < W) || used[nx][ny])continue;\n if (next_grid[nx][ny] == col) {\n used[nx][ny] = true;\n q.push({nx, ny});\n }\n }\n }\n if (col == C)ans = max(ans, res);\n }\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 4176, "score_of_the_acc": -0.1697, "final_rank": 10 }, { "submission_id": "aoj_1174_9148133", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <map>\n#include <cmath>\n#include <queue>\n#include <string>\n#include <set>\n#include <stack>\n#include <numeric>\n#include <functional>\n#include <bitset>\n\nusing namespace std;\nusing ll = long long;\n\n\n/*\n幅優先探索(bfs)\n1.左上の色を変更する\n2.変える前の色と同じ色も同じく変更する\n3.そのパネルの大きさと最大値を比べて更新する\n*/\n\nint dx[] = {0, 1, 0, -1};\nint dy[] = {-1, 0, 1, 0};\n\nint main() {\n while (true) {\n int H, W, C;\n cin >> H >> W >> C;\n if (H == 0 && W == 0 && C == 0)break;\n vector<vector<int>> P(H, vector<int>(W));\n for (int i = 0; i < H; i++)for (int j = 0; j < W; j++)cin >> P[i][j];\n\n int ans = 0;\n queue<pair<vector<vector<int>>, int>> Q;\n set<vector<vector<int>>> vis;\n Q.push({P, 0});\n vis.insert(P);\n while (!Q.empty()) {\n auto [grid, cnt] = Q.front();Q.pop();\n if (cnt >= 5)continue;\n for (int col = 1; col <= 6; col++) {\n // 左上の色を変更する\n auto next_grid = grid;\n int prev_col = grid[0][0];\n next_grid[0][0] = col;\n\n // 変える前の色と同じ色も同じく変更する\n queue<pair<int, int>> q;\n vector<vector<bool>> used(H, vector<bool>(W, false));\n q.push({0, 0});\n used[0][0] = true;\n while (!q.empty()) {\n auto [x, y] = q.front();q.pop();\n for (int i = 0; i < 4; i++) {\n int nx = x + dx[i], ny = y + dy[i];\n if (!(0 <= nx && nx < H && 0 <= ny && ny < W) || used[nx][ny])continue;\n if (next_grid[nx][ny] == prev_col) {\n next_grid[nx][ny] = col;\n used[nx][ny] = true;\n q.push({nx, ny});\n }\n }\n }\n if (!vis.count(next_grid)) {\n vis.insert(next_grid);\n Q.push({next_grid, cnt + 1});\n }\n\n int res = 0;\n for(int i = 0;i < H;i++)for(int j = 0;j < W;j++)used[i][j] = false;\n q.push({0, 0});\n used[0][0] = true;\n while (!q.empty()) {\n auto [x, y] = q.front();q.pop();\n res++;\n for (int i = 0; i < 4; i++) {\n int nx = x + dx[i], ny = y + dy[i];\n if (!(0 <= nx && nx < H && 0 <= ny && ny < W) || used[nx][ny])continue;\n if (next_grid[nx][ny] == col) {\n used[nx][ny] = true;\n q.push({nx, ny});\n }\n }\n }\n // そのパネルの大きさと最大値を比べて更新する\n if (col == C)ans = max(ans, res);\n }\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 4308, "score_of_the_acc": -0.1838, "final_rank": 11 }, { "submission_id": "aoj_1174_9144520", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <map>\n#include <stack>\n#include <cassert>\nusing namespace std;\n\nstruct d{\n int y,x;\n};\n\nstack<d> loc;\n\nvoid change(vector<vector<int>> &A, int i, int j, int h, int w, int col, int prev){\n if(i > 0 && A[i-1][j] == prev){\n A[i-1][j] = col;\n loc.push({i-1,j});\n change(A, i-1, j, h, w, col, prev);\n }\n if(j > 0 && A[i][j-1] == prev){\n A[i][j-1] = col;\n loc.push({i,j-1});\n change(A, i, j-1, h, w, col, prev);\n }\n if(i+1 < h && A[i+1][j] == prev){\n A[i+1][j] = col;\n loc.push({i+1,j});\n change(A, i+1, j, h, w, col, prev);\n }\n if(j+1 < w && A[i][j+1] == prev){\n A[i][j+1] = col;\n loc.push({i,j+1});\n change(A, i, j+1, h, w, col, prev);\n }\n}\n\nint val(vector<vector<int>> &A, int i, int j, int h, int w, int col){\n int ret = 0;\n if(i > 0 && A[i-1][j] == col){\n A[i-1][j] = -1;\n ret += val(A, i-1, j, h, w, col);\n }\n if(j > 0 && A[i][j-1] == col){\n A[i][j-1] = -1;\n ret += val(A, i, j-1, h, w, col);\n }\n if(i+1 < h && A[i+1][j] == col){\n A[i+1][j] = -1;\n ret += val(A, i+1, j, h, w, col);\n }\n if(j+1 < w && A[i][j+1] == col){\n A[i][j+1] = -1;\n ret += val(A, i, j+1, h, w, col);\n }\n return ret+1;\n}\n\nint ans = 0;\n\n\n\nvoid dfs(vector<vector<int>>& A, int count, int prev, int h, int w, int c){\n if(count == 5){\n int value = A[0][0];\n A[0][0] = -1;\n int x = val(A, 0, 0, h, w, value);\n ans = max(ans, x);\n\n for(int i = 0; h > i; i++){\n for(int j = 0; w > j; j++){\n if(A[i][j] == -1){\n A[i][j] = value;\n }\n }\n }\n return;\n }\n auto B = A;\n for(int i = 1; 6 >= i; i++){\n if(prev == i)continue;\n if(count == 4 && c != i)continue;\n int val = A[0][0];\n //cout << \"?\" << count << \" \" << prev << \" \" << i << \" \" << val << endl;\n loc.push({-1,-1});\n loc.push({0,0});\n A[0][0] = i;\n change(A, 0, 0, h, w, i, val);\n //for(int j = 0; h > j; j++){\n // for(int k = 0; w > k; k++){\n // cout << A[j][k] << \" \";\n // }\n // cout << endl;\n //}\n //cout << \"!\" << count << \" \" << prev << \" \" << i << endl;\n dfs(A, count+1, i, h, w, c);\n while(loc.size()){\n auto z = loc.top();loc.pop();\n if(z.y == -1)break;\n A[z.y][z.x] = prev;\n //cout << z.y << \" \" << z.x << endl;\n }\n assert(A[0][0] == prev);\n }\n}\n\nvoid solve(int h, int w, int c){\n ans = 0;\n vector<vector<int>> A(h, vector<int>(w));\n for(int i = 0; h > i; i++){\n for(int j = 0; w > j; j++){\n cin>>A[i][j];\n }\n }\n dfs(A, 0, A[0][0], h, w, c);\n cout << ans << endl;\n}\n\nint main(){\n int h,w,c;\n while(cin>>h>>w>>c){\n if(h == 0)return 0;\n solve(h,w,c);\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3380, "score_of_the_acc": -0.0612, "final_rank": 2 }, { "submission_id": "aoj_1174_9144460", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0; i< (n); i++)\n#define mkp(i,j) make_pair((i),(j))\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\nconst int mod = 998244353;\nconst int inf = (1<<30);\nclass DisjointSetUnion {\n int n;\n vector<int> vals;\n\n public:\n DisjointSetUnion() = default;\n explicit DisjointSetUnion(int n) : n(n), vals(n,-1){}\n\n\n int leader(int v){\n assert(v < n);\n if(vals[v] < 0) return v;\n return vals[v] = leader(vals[v]);\n }\n\n bool same(int u, int v){\n assert(v < n);\n assert(u < n);\n return leader(u) == leader(v);\n }\n\n\n int merge(int u, int v){\n assert(u < n);\n assert(v < n);\n\n int x = leader(u);\n int y = leader(v);\n\n if(x == y) return x;\n if(-vals[x] < -vals[y]) swap(x,y);\n vals[x] += vals[y];\n vals[y] = x;\n return x;\n }\n // === no need to implement from here ===\n\n\n int group_size(int v){\n assert(v < n);\n return -vals[leader(v)];\n }\n\n vector<vector<int>> groups() {\n vector<vector<int>> result(n);\n vector<int> leaders(n), g_size(n);\n\n for(int v = 0; v<n; v++){\n leaders[v] = leader(v);\n g_size[leaders[v]]++;\n }\n for(int v = 0; v < n; v++){\n result[v].reserve(g_size[v]);\n }\n for(int v = 0; v < n; v++){\n result[leaders[v]].emplace_back(v);\n }\n auto empty_check = [](const vector<int> &vs){\n return vs.empty();\n };\n result.erase(\n remove_if(result.begin(), result.end(), empty_check),\n result.end());\n\n return result;\n }\n};\n\nint check(vector<int> &q, vector<vector<int>> &p){\n\tint h = p.size();\n\tint w = p[0].size();\n\tDisjointSetUnion uni(h*w); // uni( i*w + j)\n\trep(i,h) rep(j,w){\n\t\tif(i != h-1 && p[i][j] == p[i+1][j]) uni.merge(i*w + j , (i+1)*w + j);\n\t\tif(j != w-1 && p[i][j] == p[i][j+1]) uni.merge(i*w + j , (i)*w + j+1);\n\t}\n\tint vx[4] = {1,-1,0,0};\n\tint vy[4] = {0,0,1,-1};\n\trep(k,5){\n\t\tint mc = q[k];\n\t\trep(i,h){\n\t\t\trep(j,w){\n\t\t\t\tif(!(uni.same(0,i*w+j))) continue;\n\t\t\t\trep(l,4){\n\t\t\t\t\tint ny = i + vy[l];\n\t\t\t\t\tint nx = j + vx[l];\n\t\t\t\t\tif( ny < 0 || ny >= h || nx < 0 || nx >= w || p[ny][nx] != mc) continue;\n\t\t\t\t\tuni.merge(0,ny*w + nx);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t/*\n\tif(q[0] == 2 && q[1] == 3 && q[2] == 2 && q[3] == 5){\n\t\tcout<<\"output\"<<endl;\n\t\tauto res = uni.groups();\n\t\tfor(auto x : res){\n\t\t\tfor(auto y : x) cout<<y<<\" \";\n\t\t\tcout<<endl;\n\t\t}\n\t\tcout<<\"end\"<<endl;\n\t}*/\n\t\t\t\n\treturn uni.group_size(0);\n}\n\n\n\n\n\nint dfs(int i,int c,vector<int> &q, vector<vector<int>> &p){\n\tif( i == 4){\n\t\tq[i] = c;\n\t\t//rep(j,5) cout<<q[j]<<\" \";\n\t\t//cout<<endl;\n\n\t\treturn check(q,p);\n\t}\n\tint res = 0;\n\trep(j,6){\n\t\tq[i] = j+1;\n\t\tres = max(res,dfs(i+1,c,q,p));\n\t}\n\treturn res;\n}\n\t\t\n\n\t\t\n\n\nint main(){\n\twhile(1){\n\t\tint h,w,c; cin>>h>>w>>c;\n\t\tif(h == 0) break;\n\t\tvector<vector<int>> p(h,vector<int>(w));\n\t\trep(i,h) rep(j,w) cin>>p[i][j];\n\t\tvector<int> q(5);\n\t\tcout<<dfs(0,c,q,p)<<endl;\n\t}\n\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 3320, "score_of_the_acc": -0.0961, "final_rank": 5 }, { "submission_id": "aoj_1174_9144288", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n while(1){\n int H, W, COLOR; cin >> H >> W >> COLOR;\n if(H == 0 && W == 0 && COLOR == 0) break;\n\n vector<vector<int>> P(H, vector<int>(W));\n for(int i = 0; i < H; i++){\n for(int j = 0; j < W; j++){\n cin >> P[i][j];\n }\n }\n\n const int dr[4] = {0, 1, 0, -1};\n const int dc[4] = {1, 0, -1, 0};\n auto cnt = [&](vector<vector<int>> &G, int col) -> int {\n queue<pair<int, int>> que;\n vector<vector<bool>> used(H, vector<bool>(W));\n int pre = G[0][0];\n que.push(make_pair(0, 0));\n used[0][0] = 1;\n int res = 0;\n\n while(!que.empty()){\n auto [r, c] = que.front();\n que.pop();\n //cout << r << \" \" << c << endl;\n res++;\n G[r][c] = col;\n for(int i = 0; i < 4; i++){\n int nr = r + dr[i], nc = c + dc[i];\n if(nr < 0 || H <= nr || nc < 0 || W <= nc) continue;\n if(G[nr][nc] == pre && !used[nr][nc]){\n used[nr][nc] = 1;\n que.push(make_pair(nr, nc));\n }\n }\n }\n return res;\n };\n \n auto dfs = [&](auto f, vector<vector<int>> G, int col, int dep) -> int {\n // connect. change col\n int res = cnt(G, col);\n if(dep == 5) return cnt(G, col);\n // join\n for(int i = 1; i <= 6; i++){\n if(dep == 4 && i != COLOR) continue;\n if(i == col) continue;\n res = max(res, f(f, G, i, dep + 1));\n }\n return res;\n };\n\n cout << dfs(dfs, P, P[0][0], 0) << endl;\n }\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3316, "score_of_the_acc": -0.0849, "final_rank": 4 }, { "submission_id": "aoj_1174_9144155", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\nusing namespace atcoder;\ntemplate<int mod>istream &operator>>(istream &is,static_modint<mod> &a){long long b;is>>b;a=b;return is;}\nistream &operator>>(istream &is,modint &a){long long b;cin>>b;a=b;return is;}\n#endif\n#ifdef LOCAL\n#include \"debug.h\"\n#else\n#define debug(...) static_cast<void>(0)\n#define debugg(...) static_cast<void>(0)\n#define esper(...) static_cast<void>(0)\ntemplate<typename T1,typename T2>ostream &operator<<(ostream &os,const pair<T1,T2>&p){os<<p.first<<' '<<p.second;return os;}\n#endif\nusing ll=long long;\nusing ull=unsigned long long;\nusing P=pair<ll,ll>;\ntemplate<typename T>using minque=priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T>bool chmax(T &a,const T &b){return (a<b?(a=b,true):false);}\ntemplate<typename T>bool chmin(T &a,const T &b){return (a>b?(a=b,true):false);}\ntemplate<typename T1,typename T2>istream &operator>>(istream &is,pair<T1,T2>&p){is>>p.first>>p.second;return is;}\ntemplate<typename T>istream &operator>>(istream &is,vector<T> &a){for(auto &i:a)is>>i;return is;}\ntemplate<typename T1,typename T2>void operator++(pair<T1,T2>&a,int n){a.first++,a.second++;}\ntemplate<typename T1,typename T2>void operator--(pair<T1,T2>&a,int n){a.first--,a.second--;}\ntemplate<typename T>void operator++(vector<T>&a,int n){for(auto &i:a)i++;}\ntemplate<typename T>void operator--(vector<T>&a,int n){for(auto &i:a)i--;}\n#define reps(i,a,n) for(int i=(a);i<(n);i++)\n#define rep(i,n) reps(i,0,n)\n#define all(x) x.begin(),x.end()\n#define pcnt(x) __builtin_popcountll(x)\n#define fin(x) return cout<<x<<'\\n',static_cast<void>(0)\nll myceil(ll a,ll b){return (a+b-1)/b;}\ntemplate<typename T,size_t n,size_t id=0>\nauto vec(const int (&d)[n],const T &init=T()){\n if constexpr (id<n)return vector(d[id],vec<T,n,id+1>(d,init));\n else return init;\n}\nvoid SOLVE();\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout<<fixed<<setprecision(16);\n #ifdef LOCAL\n clock_t start=clock();\n #endif\n int testcase=1;\n //cin>>testcase;\n for(int i=0;i<testcase;i++){\n SOLVE();\n }\n #ifdef LOCAL\n cerr<<\"time:\";\n cerr<<(clock()-start)/1000;\n cerr<<\"ms\\n\";\n #endif\n}\nint h,w;\ninline bool inarea(int x,int y){\n return 0<=x&&0<=y&&x<h&&y<w;\n}\nvector<pair<int,int>>around(int x,int y){\n vector<pair<int,int>>ret;\n vector<int>dx{1,0,-1,0},dy{0,1,0,-1};\n rep(i,4){\n int cx=x+dx[i],cy=y+dy[i];\n if(inarea(cx,cy))ret.emplace_back(cx,cy);\n }\n return ret;\n}\nvector<pair<int,int>>around8(int x,int y){\n vector<pair<int,int>>ret;\n vector<int>dx{1,1,0,-1,-1,-1,0,1},dy{0,1,1,1,0,-1,-1,-1};\n rep(i,8){\n int cx=x+dx[i],cy=y+dy[i];\n if(inarea(cx,cy))ret.emplace_back(cx,cy);\n }\n return ret;\n}\nvoid SOLVE(){\n while(true){\n int c;\n cin>>h>>w>>c;\n if(h+w+c==0)break;\n vector<vector<int>>a(h,vector<int>(w));\n cin>>a;\n a--,c--;\n int ans=0;\n rep(i,6){\n rep(j,6)if(i!=j){\n rep(k,6)if(j!=k){\n rep(l,6)if(k!=l){\n auto b(a);\n vector<int>step{i,j,k,l,c};\n for(auto col:step){\n queue<pair<int,int>>que;\n que.push({0,0});\n int pre=b[0][0];\n b[0][0]=col;\n vector<vector<bool>>seen(h,vector<bool>(w,false));\n seen[0][0]=true;\n while(!que.empty()){\n auto [x,y]=que.front();\n que.pop();\n for(auto [nx,ny]:around(x,y))if(!seen[nx][ny]&&b[nx][ny]==pre){\n seen[nx][ny]=true;\n b[nx][ny]=col;\n que.push({nx,ny});\n }\n }\n }\n assert(b[0][0]==c);\n int sum=0;\n vector<vector<bool>>s(h,vector<bool>(w,false));\n s[0][0]=true;\n queue<pair<int,int>>que;\n que.push({0,0});\n while(!que.empty()){\n auto [x,y]=que.front();que.pop();\n for(auto [nx,ny]:around(x,y))if(!s[nx][ny]&&b[x][y]==b[nx][ny])s[nx][ny]=true,que.push({nx,ny});\n }\n rep(i,h)rep(j,w)sum+=s[i][j];\n chmax(ans,sum);\n }\n }\n }\n }\n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 890, "memory_kb": 3468, "score_of_the_acc": -0.2178, "final_rank": 13 } ]
aoj_1175_cpp
And Then, How Many Are There? To Mr. Solitarius, who is a famous solo play game creator, a new idea occurs like every day. His new game requires discs of various colors and sizes. To start with, all the discs are randomly scattered around the center of a table. During the play, you can remove a pair of discs of the same color if neither of them has any discs on top of it. Note that a disc is not considered to be on top of another when they are externally tangent to each other. Figure D-1: Seven discs on the table For example, in Figure D-1, you can only remove the two black discs first and then their removal makes it possible to remove the two white ones. In contrast, gray ones never become removable. You are requested to write a computer program that, for given colors, sizes, and initial placings of discs, calculates the maximum number of discs that can be removed. Input The input consists of multiple datasets, each being in the following format and representing the state of a game just after all the discs are scattered. n x 1 y 1 r 1 c 1 x 2 y 2 r 2 c 2 ... x n y n r n c n The first line consists of a positive integer n representing the number of discs. The following n lines, each containing 4 integers separated by a single space, represent the colors, sizes, and initial placings of the n discs in the following manner: ( x i , y i ), r i , and c i are the xy -coordinates of the center, the radius, and the color index number, respectively, of the i -th disc, and whenever the i -th disc is put on top of the j -th disc, i < j must be satisfied. You may assume that every color index number is between 1 and 4, inclusive, and at most 6 discs in a dataset are of the same color. You may also assume that the x - and y -coordinates of the center of every disc are between 0 and 100, inclusive, and the radius between 1 and 100, inclusive. The end of the input is indicated by a single zero. Output For each dataset, print a line containing an integer indicating the maximum number of discs that can be removed. Sample Input 4 0 0 50 1 0 0 50 2 100 0 50 1 0 0 100 2 7 12 40 8 1 10 40 10 2 30 40 10 2 10 10 10 1 20 10 9 3 30 10 8 3 40 10 7 3 2 0 0 100 1 100 32 5 1 0 Output for the Sample Input 2 4 0
[ { "submission_id": "aoj_1175_10946386", "code_snippet": "#include<cstdio>\n#include<cstdlib>\n#include<cstring>\n#include<map>\n#include<set>\n#include<string>\n#include<iostream>\n#include<algorithm>\nusing namespace std;\n#define MP(i,j) make_pair(i,j)\ntypedef long long int64;\ntypedef long double real;\nmap<int,int>F;\nint x[55],y[55],r[55],c[55],n,i;\nint64 fang(int64 a,int64 b,int64 mo)\n{\n int64 ans=1;\n for (;b;b>>=1)\n b&1?ans=ans*a%mo:0,a=a*a%mo;\n return ans;\n}\ntemplate <class T>void updata(T&a,T b){if(a<b)a=b;}\ntemplate <class T>void downdata(T&a,T b){if(a>b)a=b;}\nint sqr(int x){return x*x;}\nbool check(int c,int v)\n{\n for (int i=1;i<c;i++)\n if (v&(1<<i-1))\n if (sqr(x[i]-x[c])+sqr(y[i]-y[c])<sqr(r[i]+r[c]))return 0;\n return 1;\n }\nint DP(int x)\n{\n if (F[x])return F[x];\n for (int i=1;i<=n;i++)\n if (x&(1<<i-1))\n if (check(i,x))\n for (int j=i+1;j<=n;j++)\n if (c[i]==c[j])\n if (x&(1<<j-1))\n if (check(j,x))\n updata(F[x],DP(x^(1<<i-1)^(1<<j-1))+2);\n return F[x];\n }\nint main()\n{\n while (scanf(\"%d\",&n),n)\n {\n F.clear();\n for (i=1;i<=n;i++)scanf(\"%d%d%d%d\",&x[i],&y[i],&r[i],&c[i]);\n printf(\"%d\\n\",DP((1<<n)-1));\n }\n return 0;\n}", "accuracy": 1, "time_ms": 5060, "memory_kb": 52604, "score_of_the_acc": -1.6514, "final_rank": 19 }, { "submission_id": "aoj_1175_10727874", "code_snippet": "#include<cstdio>\n#include<cstdlib>\n#include<cstring>\n#include<map>\n#include<set>\n#include<string>\n#include<iostream>\n#include<algorithm>\nusing namespace std;\n#define MP(i,j) make_pair(i,j)\ntypedef long long int64;\ntypedef long double real;\nmap<int,int>F;\nint x[55],y[55],r[55],c[55],n,i;\nint64 fang(int64 a,int64 b,int64 mo)\n{\n int64 ans=1;\n for (;b;b>>=1)\n b&1?ans=ans*a%mo:0,a=a*a%mo;\n return ans;\n}\ntemplate <class T>void updata(T&a,T b){if(a<b)a=b;}\ntemplate <class T>void downdata(T&a,T b){if(a>b)a=b;}\nint sqr(int x){return x*x;}\nbool check(int c,int v)\n{\n for (int i=1;i<c;i++)\n if (v&(1<<i-1))\n if (sqr(x[i]-x[c])+sqr(y[i]-y[c])<sqr(r[i]+r[c]))return 0;\n return 1;\n }\nint DP(int x)\n{\n if (F[x])return F[x];\n for (int i=1;i<=n;i++)\n if (x&(1<<i-1))\n if (check(i,x))\n for (int j=i+1;j<=n;j++)\n if (c[i]==c[j])\n if (x&(1<<j-1))\n if (check(j,x))\n updata(F[x],DP(x^(1<<i-1)^(1<<j-1))+2);\n return F[x];\n }\nint main()\n{\n while (scanf(\"%d\",&n),n)\n {\n F.clear();\n for (i=1;i<=n;i++)scanf(\"%d%d%d%d\",&x[i],&y[i],&r[i],&c[i]);\n printf(\"%d\\n\",DP((1<<n)-1));\n }\n return 0;\n}", "accuracy": 1, "time_ms": 5040, "memory_kb": 52616, "score_of_the_acc": -1.6479, "final_rank": 18 }, { "submission_id": "aoj_1175_10727845", "code_snippet": "#include<stdio.h>\n#include<stdlib.h>\n#include<algorithm>\n#define INIT 100\nusing namespace std;\nstruct circle\n{\n int x, y, r;\n int c;\n}cc[24];\nchar dp[(1<<24)];\nint n;\nbool intersect(int i, int j)\n{\n int x1, y1, x2, y2;\n int r1, r2;\n x1 = cc[i].x, y1 = cc[i].y, r1 = cc[i].r;\n x2 = cc[j].x, y2 = cc[j].y, r2 = cc[j].r;\n\n if( (x1-x2)*(x1-x2) + (y1-y2)*(y1-y2) >= (r1+r2)*(r1+r2))\n {\n return false;\n\n }//連心線長>=半徑和:無相交\n else\n return true;\n\n}\nbool check(int a, int b, int state)\n{\n if( ((1<<a-1)&state) == 0 || ((1<<b-1)&state) == 0 )\n {\n return false; //已經被拿走\n }\n\n if(cc[a].c != cc[b].c) return false; //顏色不同\n\n\n int p[2];\n p[0]=a, p[1]=b;\n\n for(int k=0; k<2; k++)\n {\n int x = (1<<p[k]-1)-1; // n-p[k]+1個0 p[k]-1個1\n if( (x&state) > 0)//state的p[k]位右邊有1 ((p[k]可能被其他盤子蓋住\n {\n for(int i=1; i<=p[k]-1; i++)\n {\n int test = 1 << i-1;\n if( (test&state) && intersect(p[k], i) )\n {\n return false;\n }\n }\n }\n }\n\n if(1) return true;\n}\nchar DP(int state)\n{\n if(state==0) return 0;\n if(dp[state]!=INIT) return dp[state];\n\n for(int i=1; i<n; i++)\n {\n for(int j=i+1; j<=n; j++)\n {\n if( check(i,j, state) )\n {\n int mask = (1<<i-1) | (1<<j-1);\n\n dp[state^mask] = DP(state^mask);\n if(dp[state^mask]+2 > dp[state] || dp[state]==INIT)\n dp[state] = dp[state^mask]+2;\n }\n }\n }\n return dp[state]==INIT? 0:dp[state];\n}\n\nint main()\n{\n\n while(scanf(\"%d\",&n) && n)\n {\n for(int i=1; i<=n; i++)\n scanf(\"%d%d%d%d\",&cc[i].x, &cc[i].y, &cc[i].r, &cc[i].c);\n\n int state = (1<<n)-1;\n for(int i=0; i<=state; i++)\n dp[i] = INIT;\n\n dp[state] = DP(state);\n\n printf(\"%d\\n\",dp[state]);\n\n\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 1600, "memory_kb": 19184, "score_of_the_acc": -0.511, "final_rank": 6 }, { "submission_id": "aoj_1175_10727844", "code_snippet": "#include<stdio.h>\n#include<stdlib.h>\n#include<algorithm>\n#define INIT 100\nusing namespace std;\nstruct circle\n{\n int x, y, r;\n int c;\n}cc[24];\nchar dp[(1<<24)];\nint n;\nbool intersect(int i, int j)\n{\n int x1, y1, x2, y2;\n int r1, r2;\n x1 = cc[i].x, y1 = cc[i].y, r1 = cc[i].r;\n x2 = cc[j].x, y2 = cc[j].y, r2 = cc[j].r;\n\n if( (x1-x2)*(x1-x2) + (y1-y2)*(y1-y2) >= (r1+r2)*(r1+r2))\n {\n return false;\n\n }//連心線長>=半徑和:無相交\n else\n return true;\n\n}\nbool check(int a, int b, int state)\n{\n if( ((1<<a-1)&state) == 0 || ((1<<b-1)&state) == 0 )\n {\n return false; //已經被拿走\n }\n\n if(cc[a].c != cc[b].c) return false; //顏色不同\n\n\n int p[2];\n p[0]=a, p[1]=b;\n\n for(int k=0; k<2; k++)\n {\n int x = (1<<p[k]-1)-1; // n-p[k]+1個0 p[k]-1個1\n if( (x&state) > 0)//state的p[k]位右邊有1 ((p[k]可能被其他盤子蓋住\n {\n for(int i=1; i<=p[k]-1; i++)\n {\n int test = 1 << i-1;\n if( (test&state) && intersect(p[k], i) )\n {\n return false;\n }\n }\n }\n }\n\n return true;\n}\nchar DP(int state)\n{\n if(state==0) return 0;\n if(dp[state]!=INIT) return dp[state];\n\n for(int i=1; i<n; i++)\n {\n for(int j=i+1; j<=n; j++)\n {\n if( check(i,j, state) )\n {\n int mask = (1<<i-1) | (1<<j-1);\n\n dp[state^mask] = DP(state^mask);\n if(dp[state^mask]+2 > dp[state] || dp[state]==INIT)\n dp[state] = dp[state^mask]+2;\n }\n }\n }\n return dp[state]==INIT? 0:dp[state];\n}\n\nint main()\n{\n\n while(scanf(\"%d\",&n) && n)\n {\n for(int i=1; i<=n; i++)\n scanf(\"%d%d%d%d\",&cc[i].x, &cc[i].y, &cc[i].r, &cc[i].c);\n\n int state = (1<<n)-1;\n for(int i=0; i<=state; i++)\n dp[i] = INIT;\n\n dp[state] = DP(state);\n\n printf(\"%d\\n\",dp[state]);\n\n\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 1600, "memory_kb": 19340, "score_of_the_acc": -0.5133, "final_rank": 8 }, { "submission_id": "aoj_1175_10727841", "code_snippet": "#include<stdio.h>\n#include<stdlib.h>\n#include<algorithm>\n#define INIT 100\nusing namespace std;\nstruct circle\n{\n int x, y, r;\n int c;\n}cc[24];\nchar dp[(1<<24)];\nint n;\nbool intersect(int i, int j)\n{\n int x1, y1, x2, y2;\n int r1, r2;\n x1 = cc[i].x, y1 = cc[i].y, r1 = cc[i].r;\n x2 = cc[j].x, y2 = cc[j].y, r2 = cc[j].r;\n\n if( (x1-x2)*(x1-x2) + (y1-y2)*(y1-y2) >= (r1+r2)*(r1+r2))\n {\n return false;\n\n }//連心線長>=半徑和:無相交\n else\n return true;\n\n}\nbool check(int a, int b, int state)\n{\n if( ((1<<a-1)&state) == 0 || ((1<<b-1)&state) == 0 )\n {\n return false; //已經被拿走\n }\n\n if(cc[a].c != cc[b].c) return false; //顏色不同\n\n\n int p[2];\n p[0]=a, p[1]=b;\n\n for(int k=0; k<2; k++)\n {\n int x = (1<<p[k]-1)-1; // n-p[k]+1個0 p[k]-1個1\n if( (x&state) > 0)//state的p[k]位右邊有1 ((p[k]可能被其他盤子蓋住\n {\n for(int i=1; i<=p[k]-1; i++)\n {\n int test = 1 << i-1;\n if( (test&state) && intersect(p[k], i) )\n {\n return false;\n }\n }\n }\n }\n\n return true;\n}\nint DP(int state)\n{\n if(state==0) return 0;\n if(dp[state]!=INIT) return dp[state];\n\n for(int i=1; i<n; i++)\n {\n for(int j=i+1; j<=n; j++)\n {\n if( check(i,j, state) )\n {\n int mask = (1<<i-1) | (1<<j-1);\n\n dp[state^mask] = DP(state^mask);\n if(dp[state^mask]+2 > dp[state] || dp[state]==INIT)\n dp[state] = dp[state^mask]+2;\n }\n }\n }\n return dp[state]==INIT? 0:dp[state];\n}\n\nint main()\n{\n\n while(scanf(\"%d\",&n) && n)\n {\n for(int i=1; i<=n; i++)\n scanf(\"%d%d%d%d\",&cc[i].x, &cc[i].y, &cc[i].r, &cc[i].c);\n\n int state = (1<<n)-1;\n for(int i=0; i<=state; i++)\n dp[i] = INIT;\n\n dp[state] = DP(state);\n\n printf(\"%d\\n\",dp[state]);\n\n\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 1600, "memory_kb": 19188, "score_of_the_acc": -0.5111, "final_rank": 7 }, { "submission_id": "aoj_1175_10727833", "code_snippet": "#include<stdio.h>\n#include<stdlib.h>\n#include<algorithm>\nusing namespace std;\nstruct circle\n{\n double x, y, r;\n int c;\n}cc[30];\nint dp[(1<<24)];\nint n;\nbool intersect(int i, int j)\n{\n double x1, y1, x2, y2;\n double r1, r2;\n x1 = cc[i].x, y1 = cc[i].y, r1 = cc[i].r;\n x2 = cc[j].x, y2 = cc[j].y, r2 = cc[j].r;\n\n if( (x1-x2)*(x1-x2) + (y1-y2)*(y1-y2) >= (r1+r2)*(r1+r2))\n {\n return false;\n\n }//連心線長>=半徑和:無相交\n else\n return true;\n\n}\nbool check(int a, int b, int state)\n{\n if( ((1<<a-1)&state) == 0 || ((1<<b-1)&state) == 0 )\n {\n return false; //已經被拿走\n }\n\n if(cc[a].c != cc[b].c) return false; //顏色不同\n\n\n int p[2];\n p[0]=a, p[1]=b;\n\n for(int k=0; k<2; k++)\n {\n int x = (1<<p[k]-1)-1; // n-p[k]+1個0 p[k]-1個1\n if( (x&state) > 0)//state的p[k]位右邊有1 ((p[k]可能被其他盤子蓋住\n {\n for(int i=1; i<=p[k]-1; i++)\n {\n int test = 1 << i-1;\n if( test&state )\n {\n if(intersect(p[k], i))\n return false;\n }\n }\n }\n }\n return true;\n}\nint DP(int state)\n{\n if(state==0) return 0;\n if(dp[state]!=-1) return dp[state];\n\n for(int i=1; i<n; i++)\n {\n for(int j=i+1; j<=n; j++)\n {\n if( check(i,j, state) )\n {\n int mask = (1<<i-1) | (1<<j-1);\n\n dp[state^mask] = DP(state^mask);\n if(dp[state^mask]+2 > dp[state])\n dp[state] = dp[state^mask]+2;\n }\n }\n }\n return dp[state]==-1? 0:dp[state];\n}\n\nint main()\n{\n\n while(scanf(\"%d\",&n) && n)\n {\n for(int i=1; i<=n; i++)\n scanf(\"%lf%lf%lf%d\",&cc[i].x, &cc[i].y, &cc[i].r, &cc[i].c);\n\n int state = (1<<n)-1;\n for(int i=0; i<=state; i++)\n dp[i] = -1;\n\n dp[state] = DP(state);\n\n printf(\"%d\\n\",dp[state]);\n\n\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 1920, "memory_kb": 68420, "score_of_the_acc": -1.3047, "final_rank": 15 }, { "submission_id": "aoj_1175_10727832", "code_snippet": "#include<stdio.h>\n#include<stdlib.h>\n#include<algorithm>\nusing namespace std;\nstruct circle\n{\n double x, y, r;\n int c;\n}cc[30];\nint dp[(1<<24)];\nint n;\nbool intersect(int i, int j)\n{\n double x1, y1, x2, y2;\n double r1, r2;\n x1 = cc[i].x, y1 = cc[i].y, r1 = cc[i].r;\n x2 = cc[j].x, y2 = cc[j].y, r2 = cc[j].r;\n\n if( (x1-x2)*(x1-x2) + (y1-y2)*(y1-y2) >= (r1+r2)*(r1+r2))\n {\n return false;\n\n }//連心線長>=半徑和:無相交\n else\n return true;\n\n}\nbool check(int a, int b, int state)\n{\n if( ((1<<a-1)&state) == 0 || ((1<<b-1)&state) == 0 )\n {\n return false; //已經被拿走\n }\n\n if(cc[a].c != cc[b].c) return false; //顏色不同\n\n\n int p[2];\n p[0]=a, p[1]=b;\n\n for(int k=0; k<2; k++)\n {\n int x = (1<<p[k]-1)-1; // n-p[k]+1個0 p[k]-1個1\n if( (x&state) > 0)//state的p[k]位右邊有1 ((p[k]可能被其他盤子蓋住\n {\n for(int i=1; i<=p[k]-1; i++)\n {\n int test = 1 << i-1;\n if( test&state )\n {\n if(intersect(p[k], i))\n {\n return false;\n }\n\n }\n }\n }\n }\n return true;\n}\nint DP(int state)\n{\n if(state==0) return 0;\n if(dp[state]!=-1) return dp[state];\n\n for(int i=1; i<n; i++)\n {\n for(int j=i+1; j<=n; j++)\n {\n if( check(i,j, state) )\n {\n int mask = (1<<i-1) | (1<<j-1);\n\n dp[state^mask] = DP(state^mask);\n if(dp[state^mask]+2 > dp[state])\n dp[state] = dp[state^mask]+2;\n }\n }\n }\n return dp[state]==-1? 0:dp[state];\n}\n\nint main()\n{\n\n while(scanf(\"%d\",&n) && n)\n {\n for(int i=1; i<=n; i++)\n scanf(\"%lf%lf%lf%d\",&cc[i].x, &cc[i].y, &cc[i].r, &cc[i].c);\n\n int state = (1<<n)-1;\n for(int i=0; i<=state; i++)\n dp[i] = -1;\n\n dp[state] = DP(state);\n\n printf(\"%d\\n\",dp[state]);\n\n\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 1920, "memory_kb": 68524, "score_of_the_acc": -1.3063, "final_rank": 17 }, { "submission_id": "aoj_1175_10727831", "code_snippet": "#include<stdio.h>\n#include<stdlib.h>\n#include<algorithm>\nusing namespace std;\nstruct circle\n{\n double x, y, r;\n int c;\n}cc[30];\nint dp[(1<<24)];\nint n;\nbool intersect(int i, int j)\n{\n double x1, y1, x2, y2;\n double r1, r2;\n x1 = cc[i].x, y1 = cc[i].y, r1 = cc[i].r;\n x2 = cc[j].x, y2 = cc[j].y, r2 = cc[j].r;\n\n if( (x1-x2)*(x1-x2) + (y1-y2)*(y1-y2) >= (r1+r2)*(r1+r2))\n {\n return false;\n\n }//連心線長>=半徑和:無相交\n else\n return true;\n\n}\nbool check(int a, int b, int state)\n{\n if( ((1<<a-1)&state) == 0 || ((1<<b-1)&state) == 0 )\n {\n return false; //已經被拿走\n }\n\n if(cc[a].c != cc[b].c) return false; //顏色不同\n\n\n int p[2];\n p[0]=a, p[1]=b;\n\n for(int k=0; k<2; k++)\n {\n int x = (1<<p[k]-1)-1; // n-p[k]+1個0 p[k]-1個1\n if( (x&state) > 0)//state的p[k]位右邊有1 ((p[k]可能被其他盤子蓋住\n {\n for(int i=1; i<=p[k]-1; i++)\n {\n int test = 1 << i-1;\n if( (test&state) && intersect(p[k], i) )\n {\n return false;\n }\n }\n }\n }\n\n return true;\n}\nint DP(int state)\n{\n if(state==0) return 0;\n if(dp[state]!=-1) return dp[state];\n\n for(int i=1; i<n; i++)\n {\n for(int j=i+1; j<=n; j++)\n {\n if( check(i,j, state) )\n {\n int mask = (1<<i-1) | (1<<j-1);\n\n dp[state^mask] = DP(state^mask);\n if(dp[state^mask]+2 > dp[state])\n dp[state] = dp[state^mask]+2;\n }\n }\n }\n return dp[state]==-1? 0:dp[state];\n}\n\nint main()\n{\n\n while(scanf(\"%d\",&n) && n)\n {\n for(int i=1; i<=n; i++)\n scanf(\"%lf%lf%lf%d\",&cc[i].x, &cc[i].y, &cc[i].r, &cc[i].c);\n\n int state = (1<<n)-1;\n for(int i=0; i<=state; i++)\n dp[i] = -1;\n\n dp[state] = DP(state);\n\n printf(\"%d\\n\",dp[state]);\n\n\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 1920, "memory_kb": 68456, "score_of_the_acc": -1.3053, "final_rank": 16 }, { "submission_id": "aoj_1175_10684465", "code_snippet": "#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n// #ifndef ONLINE_JUDGE\n// #define _GLIBCXX_DEBUG // 配列外参照のエラー\n// #endif\n\n// スタンダードライブラリ\n#include <bits/stdc++.h>\nusing namespace std;\n\n// 型関連\nusing ll = long long;\nusing lint = long long;\nusing pll = pair<ll, ll>;\nusing plll = tuple<ll, ll, ll>;\nusing pii = pair<int, int>;\nusing piii = tuple<ll, ll, ll>;\nusing vi = vector<int>;\nusing vvi = vector<vector<int>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing vvvvi = vector<vector<vector<vector<int>>>>;\nusing vl = vector<ll>;\nusing vvl = vector<vector<ll>>;\nusing vvvl = vector<vector<vector<ll>>>;\nusing vvvvl = vector<vector<vector<vector<ll>>>>;\n\ntemplate <class T> using prique = priority_queue<T>;\ntemplate <class T> void chmin(T &a, T b) {\n if (a > b)\n a = b;\n}\ntemplate <class T> void chmax(T &a, T b) {\n if (a < b)\n a = b;\n}\n\n#define all(v) v.begin(), v.end()\n\n// 型定数\nconstexpr ll mod = 998244353;\nconstexpr ll MOD = 1000000007;\nint INF32 = 2e9;\nll INF64 = 9e18;\n#define endl '\\n';\n\nint dx[4] = {1, 0, -1, 0};\nint dy[4] = {0, 1, 0, -1};\n\n/////////////////////////// print関連\ntemplate <typename T> void print(vector<T> A);\nvoid print();\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail);\nvoid print(string S);\ntemplate <typename T> void print(vector<vector<T>> &F);\n\ninline void Yes(bool f);\n\n///////////////////ここから//////////////////////\nbool solve() {\n int N;\n cin >> N;\n if (N == 0) {\n return false;\n }\n\n vector<pii> XY(N);\n vector<int> R(N), C(N);\n for (int i = 0; i < N; i++) {\n int x, y, c, r;\n cin >> x >> y >> r >> c;\n // print(x, y, c, r);\n XY[i] = {x, y};\n R[i] = r;\n C[i] = c;\n // cin >> XY[i].first >> XY[i].second >> R[i] >> C[i];\n }\n\n auto overlap = [&](int i, int j) -> bool {\n auto [x1, y1] = XY[i];\n auto [x2, y2] = XY[j];\n int r1 = R[i], r2 = R[j];\n return (x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2) <\n (r1 + r2) * (r1 + r2);\n };\n\n auto ok = [&](int i, int S) -> bool {\n for (int j = 0; j < i; j++) {\n if ((S & (1 << j)) == 0 && overlap(i, j))\n return false;\n }\n return true;\n };\n\n int ans = 0;\n\n vi dp(1 << N);\n dp[0] = 1;\n for (int S = 0; S < (1 << N); S++) {\n if (dp[S] == 0)\n continue;\n int tmp = 0;\n for (int i = 0; i < N; i++) {\n if (S & (1 << i)) {\n tmp++;\n continue;\n }\n if (ok(i, S) == false)\n continue;\n\n for (int j = i + 1; j < N; j++) {\n if (S & (1 << j))\n continue;\n if (C[i] == C[j] && ok(j, S)) {\n int nS = S + (1 << i) + (1 << j);\n dp[nS] = 1;\n }\n }\n }\n chmax(ans, tmp);\n }\n print(ans);\n\n return true;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n while (solve())\n ;\n}\n\n////////////////////print/////////////////////////\n// 1次元ベクトルを出力する\ntemplate <typename T> void print(vector<T> A) {\n if (A.size() == 0) {\n return;\n }\n for (size_t i = 0; i < A.size() - 1; i++) {\n cout << A[i] << ' ';\n }\n cout << A[A.size() - 1] << endl;\n return;\n}\n\n// 2次元ベクトルを出力する\ntemplate <typename T> void print(vector<vector<T>> &F) {\n for (size_t i = 0; i < F.size(); i++) {\n for (size_t j = 0; j < F[i].size(); j++) {\n cout << F[i][j];\n if (j < F[i].size() - 1) {\n cout << ' ';\n }\n }\n cout << endl;\n }\n}\n\n// 空白行を出力するprint\nvoid print() { cout << endl; }\n\n// 数値・文字列を空白区切りで出力する. print(a,b)など\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n cout << head;\n if (sizeof...(tail) != 0)\n cout << \" \";\n print(forward<Tail>(tail)...);\n}\n\nvoid print(string S) { cout << S << endl; }\n\n//////////////出力関連\n\ninline void Yes(bool f) {\n if (f) {\n cout << \"Yes\" << endl;\n } else {\n cout << \"No\" << endl;\n }\n}", "accuracy": 1, "time_ms": 1800, "memory_kb": 68984, "score_of_the_acc": -1.2909, "final_rank": 14 }, { "submission_id": "aoj_1175_10641139", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\n#define all(v) v.begin(), v.end()\n#define rall(a) a.rbegin(), a.rend()\n#define fi first\n#define se second\n#define endl \"\\n\"\n\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\n\ntemplate <typename T>\nusing vc = vector<T>; // prioriy_queueに必要なのでここにこれ書いてます\ntemplate <typename T>\nusing vv = vc<vc<T>>;\n#define int long long\nusing ll = long long;\nll INF = 2e18;\n\n#ifdef ONLINE_JUDGE\n// ジャッジ環境ではデバッグマクロを無効化\n#define debug_x(x) \\\n do \\\n { \\\n } while (0)\n#define debug_vc(v) \\\n do \\\n { \\\n } while (0)\n#define debug_vv(v) \\\n do \\\n { \\\n } while (0)\n#else\n// ローカルではデバッグ出力\n#define debug_x(x) cout << #x << \" = \" << (x) << endl\n#define debug_vc(v) \\\n { \\\n cout << #v << endl; \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << ' '; \\\n cout << endl; \\\n } // 一次元配列を出力する\n#define debug_vv(v) \\\n { \\\n cout << #v << endl; \\\n ll n = size(v); \\\n rep(i, n) \\\n { \\\n rep(j, size(v[i])) { cout << v[i][j] << ' '; } \\\n cout << endl; \\\n } \\\n } // 二次元配列を出力する\n#endif\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n#define rrep(i, n) for (ll i = 1; i <= (n); ++i)\n#define drep(i, n) for (ll i = (n) - 1; i >= 0; --i)\n#define nfor(i, s, n) for (ll i = s; i < n; i++) // i=s,s+1...n-1 ノーマルfor\n#define dfor(i, s, n) for (ll i = (s) - 1; i >= n; i--) // s-1スタートでnまで落ちる\n\nusing ld = long double;\nusing bl = bool;\n\ntemplate <class T>\nusing pq = priority_queue<T, vc<T>>; // 大きい順\ntemplate <class T>\nusing pq_g = priority_queue<T, vc<T>, greater<T>>; // 小さい順\n\nusing vl = vc<ll>;\nusing vvl = vv<ll>;\nusing vvvl = vv<vl>;\nusing vvvvl = vv<vvl>;\nusing vs = vc<string>;\nusing vvs = vv<string>;\nusing vb = vc<bl>;\nusing vvb = vv<bl>;\nusing vvvb = vv<vb>;\nusing vld = vc<ld>;\nusing vvld = vv<ld>;\nusing vvvld = vv<vld>;\nusing P = pair<ll, ll>;\nusing vP = vc<P>;\nusing vvP = vc<vP>;\nusing vvvP = vv<vP>;\n\n#define pb push_back\n\n#define YES cout << \"Yes\" << endl\n#define NO cout << \"No\" << endl\n#define YN \\\n { \\\n cout << \"Yes\" << endl; \\\n } \\\n else \\\n { \\\n cout << \"No\" << endl; \\\n } // if(a==b)YN;\n#define dame cout << -1 << endl\n\nstring dir = \"DRUL\"; // 第4象限の場合\nvl di = {1, 0, -1, 0}; // vl di={1,1,0,-1,-1,-1,0,1};\nvl dj = {0, 1, 0, -1}; // vl dj={0,1,1,1,0,-1,-1,-1};\n\nbool out_grid(ll i, ll j, ll h, ll w)\n{ // trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\nll n;\nvl x, y, r, c;\nvb visited;\n\nll toState(vb &eliminated)\n{\n ll idx = 0;\n rep(i, n)\n {\n if (eliminated[i])\n {\n idx += 1 << i;\n }\n }\n return idx;\n}\n\nll dfs(vb &eliminated)\n{\n // debug_vc(eliminated);\n ll ans = 0;\n vl board;\n rep(i, n)\n {\n if (eliminated[i])\n continue;\n bl ok = true;\n rep(j, i)\n {\n if (eliminated[j])\n continue;\n // ll j = board[ii];\n ll d = (x[i] - x[j]) * (x[i] - x[j]) + (y[i] - y[j]) * (y[i] - y[j]);\n if ((r[i] + r[j]) * (r[i] + r[j]) > d)\n {\n ok = false;\n break;\n }\n }\n if (ok)\n {\n board.pb(i);\n }\n }\n\n rep(i, board.size())\n {\n rep(j, board.size())\n {\n if (i >= j)\n continue;\n if (c[board[i]] == c[board[j]])\n {\n eliminated[board[i]] = true;\n eliminated[board[j]] = true;\n ll state = toState(eliminated);\n if (!visited[state])\n {\n visited[state] = true;\n ans = max(ans, 2 + dfs(eliminated));\n }\n eliminated[board[i]] = false;\n eliminated[board[j]] = false;\n }\n }\n }\n\n // debug(board);\n // vvl colSet(4);\n // rep(i, board.size())\n // {\n // colSet[c[board[i]] - 1].pb(board[i]);\n // // rep(j, board.size())\n // // {\n // // if (i >= j)\n // // continue;\n // // if (c[board[i]] == c[board[j]])\n // // {\n // // eliminated[board[i]] = true;\n // // eliminated[board[j]] = true;\n // // ans = max(ans, 2 + dfs(eliminated));\n // // eliminated[board[i]] = false;\n // // eliminated[board[j]] = false;\n // // }\n // // }\n // }\n // bl update = false;\n // rep(i, 4)\n // {\n // if (colSet[i].size() >= 2)\n // {\n // update = true;\n // }\n // }\n // if (!update)\n // return 0;\n // ll res = 0;\n // rep(i, 4)\n // {\n // if (colSet[i].size() % 2 == 0)\n // {\n // // 全部取り除ける\n // rep(j, colSet[i].size())\n // {\n // eliminated[colSet[i][j]] = true;\n // res++;\n // }\n // }\n // }\n\n // bl dive = false;\n // rep(i, 4)\n // {\n // if (colSet[i].size() % 2 == 1)\n // {\n // // 1枚余る\n // rep(j, colSet[i].size())\n // {\n // eliminated[colSet[i][j]] = true;\n // res++;\n // }\n // rep(j, colSet[i].size())\n // {\n // eliminated[colSet[i][j]] = false;\n // res--;\n // dive = true;\n // ans = max(ans, res + dfs(eliminated));\n // eliminated[colSet[i][j]] = true;\n // res++;\n // }\n // rep(j, colSet[i].size())\n // {\n // eliminated[colSet[i][j]] = false;\n // res--;\n // }\n // }\n // }\n\n // if (!dive)\n // {\n // ans = max(ans, res + dfs(eliminated));\n // }\n\n // rep(i, 4)\n // {\n // if (colSet[i].size() % 2 == 0)\n // {\n // // 全部取り除ける\n // rep(j, colSet[i].size())\n // {\n // eliminated[colSet[i][j]] = false;\n // res--;\n // }\n // }\n // }\n\n return ans;\n}\n\nbl solve()\n{\n cin >> n;\n if (n == 0)\n return 0;\n x.resize(n);\n y.resize(n);\n r.resize(n);\n c.resize(n);\n rep(i, n)\n {\n cin >> x[i] >> y[i] >> r[i] >> c[i];\n }\n // 全探索(DFS)\n // 重なっている⇔2r>2頂点間の距離\n // bit全探索\n // rep(i,1<<n){\n // rep(j,n){\n // if(i&(1<<j))continue;\n // rep(k,j){\n // if(i&(1<<k))continue;\n // }\n // }\n // }\n visited.assign(1<<n,false);\n vb eliminated(n);\n cout << dfs(eliminated) << endl;\n\n return 1;\n}\n\nsigned main()\n{\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n while (true)\n {\n if (!solve())\n break;\n }\n return 0;\n}\n\n/*\nshift+alt+Fで成形\nf2で変数名変更\n\nスニペット\nbasic\n m:atcoder以外用\n ma:ABC/ARC用\n mahc:AHC用\nmath\n floor:床関数\n ceil:天井関数\n comv:二項係数\n modpow: a^b mod m\n GCD:最大公約数\n extGCD:拡張ユークリッド互除法\n PFD:素因数分解\n isprime:エラトステネスの篩\n matrixpow:行列累乗\ndata_structure\n seg:セグメント木\ntechnic\n Compress:座標圧縮\n runlength:ランレングス圧縮\ngraph\n warshall:ワーシャルフロイド法\n dfs:深さ優先探索\n bfs:幅優先探索\n LCA:最近共通祖先\n*/", "accuracy": 1, "time_ms": 1800, "memory_kb": 4996, "score_of_the_acc": -0.3365, "final_rank": 5 }, { "submission_id": "aoj_1175_10600951", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef int ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rrep(i,start,end) for (ll i = start;i >= (ll)(end);i--)\n#define repn(i,end) for(ll i = 0; i <= (ll)(end); i++)\n#define reps(i,start,end) for(ll i = start; i < (ll)(end); i++)\n#define repsn(i,start,end) for(ll i = start; i <= (ll)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef vector<ll> vll;\ntypedef vector<pair<ll ,ll>> vpll;\ntypedef vector<vector<ll>> vvll;\ntypedef set<ll> sll;\ntypedef map<ll , ll> mpll;\ntypedef pair<ll ,ll> pll;\ntypedef tuple<ll , ll , ll> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (ll)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1 << 30;\nconst ld EPS = 1e-9;\n \nll lceil(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b)+1;}else{return -((-a)/b);}}\nll lfloor(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b);}else{return -((-a)/b)-1;}}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\n//0indexed\ninline ll topbit(ll a){assert(a != 0);return 63 - __builtin_clzll(a);}\ninline ll smlbit(ll a){assert(a != 0);return __builtin_ctzll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\nusing tpl4 = tuple<ll,ll,ll,ll> ;\nvoid solve(ll n){\n vector<tpl4> xyrc(n);\n rep(i,n){\n LL(x,y,r,c);\n xyrc[i] = {x,y,r,c};\n }\n\n auto cross=[&](ll i,ll j){\n auto [xi,yi,ri,ci] = xyrc[i];\n auto [xj,yj,rj,cj] = xyrc[j];\n if(lpow(ri+rj,2)>lpow(abs(xi-xj),2)+lpow(abs(yi-yj),2)){\n return true;\n }else return false;\n };\n \n vvll g(n);//上からした\n rep(i,n){\n reps(j,i+1,n){\n if(cross(i,j)){\n g[i].push_back(j);\n }\n }\n }\n queue<ll> que;\n //0からの距離が入る\n //01BFSのときは更新の判定のところを変更する\n vector<ll> find(1 << n,INF);\n find[(1<<n)-1] = 0;\n que.push((1<<n)-1);\n while(!que.empty()){\n ll now = que.front();\n que.pop();\n vll topable(n,1);\n vll onbit;\n rep(i,n){\n if(now >> i &1){\n onbit.push_back(i);\n each(p,g[i]){\n topable[p] = 0;\n }\n }\n }\n each(p,onbit){\n each(q,onbit){\n if(p == q)break;\n if(topable[p]&&topable[q]&&get<3>(xyrc[p])==get<3>(xyrc[q])){\n ll nxt = now ^1<<p ^1<<q;\n if(find[nxt] ==INF){\n find[nxt] = find[now]+2;\n que.push(nxt);\n }\n }\n }\n }\n }\n ll ans =0;\n rep(i,1 <<n)if(find[i] < INF){\n chmax(ans,find[i]);\n }\n cout << ans << endl;\n\n\n\n}\n \nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true){\n LL(n);\n if(n == 0)break;\n solve(n);\n }\n}", "accuracy": 1, "time_ms": 600, "memory_kb": 70504, "score_of_the_acc": -1.0909, "final_rank": 12 }, { "submission_id": "aoj_1175_10600091", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<long long>;\nusing vs = vector<string>;\nusing vc = vector<char>;\nusing vb = vector<bool>;\nusing vpii = vector<pair<int, int>>;\nusing vpll = vector<pair<long long, long long>>;\nusing vvi = vector<vector<int>>;\nusing vvl = vector<vector<long long>>;\nusing vvc = vector<vector<char>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing pii = pair<int, int>;\nusing vvb = vector<vector<bool>>;\nusing Graph = vector<vector<ll>>;\nconst ll LINF = 1001002003004005006ll;\nconst int INF = 1001001001;\nconst int MOD = 998244353;\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep3(i, m, n) for (int i = (m); i < (int)(n); i++)\n#define rrep(i, m, n) for (int i = (m); i >= (int)(n); i--)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\nvi dx4 = {1, 0, -1, 0}, dy4 = {0, 1, 0, -1};\nvi dx8 = {1, 1, 1, 0, 0, -1, -1, -1}, dy8 = {1, 0, -1, 1, -1, 1, 0, -1};\n\nset<set<array<int, 2>>> pair_divide(vector<int> V)\n{\n int N = V.size();\n\n set<set<array<int, 2>>> pairss;\n\n do\n {\n set<array<int, 2>> pairs;\n for (int i = 0; i + 1 < N; i += 2)\n {\n int a = V[i], b = V[i + 1];\n if (a > b)\n swap(a, b);\n pairs.insert({a, b});\n }\n pairss.insert(pairs);\n\n } while (next_permutation(V.begin(), V.end()));\n\n return pairss;\n}\n\nbool solve()\n{\n int N;\n cin >> N;\n if (N == 0)\n {\n return false;\n }\n\n vector<int> X(N), Y(N), R(N), C(N);\n vector<vector<int>> color_idx(4);\n for (int i = 0; i < N; i++)\n {\n cin >> X[i] >> Y[i] >> R[i] >> C[i];\n C[i]--;\n color_idx[C[i]].push_back(i);\n }\n\n vector<int> covered_init(N, 0);\n vector<vector<int>> covering(N);\n for (int i = 0; i < N; i++)\n {\n for (int j = i + 1; j < N; j++)\n {\n // 重なっていれば\n if ((X[i] - X[j]) * (X[i] - X[j]) + (Y[i] - Y[j]) * (Y[i] - Y[j]) < (R[i] + R[j]) * (R[i] + R[j]))\n {\n covered_init[j]++;\n covering[i].push_back(j);\n }\n }\n }\n\n set<set<array<int, 2>>> C1, C2, C3, C4;\n C1 = pair_divide(color_idx[0]);\n C2 = pair_divide(color_idx[1]);\n C3 = pair_divide(color_idx[2]);\n C4 = pair_divide(color_idx[3]);\n\n // for (auto a : C1)\n // {\n // for (auto [p1, p2] : a)\n // {\n // cerr << p1 << \" \" << p2 << \", \";\n // }\n // cerr << \"\\n\";\n // }\n\n auto check = [&](set<array<int, 2>> &pairs) -> int\n {\n vector<int> covered = covered_init;\n int ret = 0;\n int num = (int)pairs.size();\n for (int i = 0; i < num; i++)\n {\n for (auto [p1, p2] : pairs)\n {\n if (covered[p1] == 0 && covered[p2] == 0)\n {\n ret += 2;\n covered[p1] = covered[p2] = -1;\n for (auto under : covering[p1])\n {\n covered[under]--;\n }\n for (auto under : covering[p2])\n {\n covered[under]--;\n }\n pairs.erase({p1, p2});\n break;\n }\n }\n }\n\n return ret;\n };\n\n int ans = 0;\n for (auto c1 : C1)\n {\n for (auto c2 : C2)\n {\n for (auto c3 : C3)\n {\n for (auto c4 : C4)\n {\n set<array<int, 2>> idxs;\n for (auto v : c1)\n idxs.insert(v);\n for (auto v : c2)\n idxs.insert(v);\n for (auto v : c3)\n idxs.insert(v);\n for (auto v : c4)\n idxs.insert(v);\n\n // check\n ans = max(ans, check(idxs));\n }\n }\n }\n }\n\n cout << ans << \"\\n\";\n\n return true;\n}\n\nint main()\n{\n while (solve())\n ;\n return 0;\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 3456, "score_of_the_acc": -0.0538, "final_rank": 1 }, { "submission_id": "aoj_1175_10590216", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nbool solve() {\n int N;\n cin >> N;\n if (N == 0) return false;\n vector<int> X(N), Y(N), R(N), C(N);\n for (int i = 0; i < N; i++) {\n cin >> X[i] >> Y[i] >> R[i] >> C[i];\n }\n vector<bool> dp(1 << N, false);\n dp[0] = true;\n int ans = 0;\n for (int bit = 0; bit < 1 << N; bit++) {\n if (!dp[bit]) continue;\n ans = max(ans, __builtin_popcount(bit));\n vector<int> can_take;\n for (int i = 0; i < N; i++) {\n if (bit >> i & 1) continue;\n if ([&] {\n for (int j = 0; j < i; j++) {\n if (bit >> j & 1) continue;\n int dx = X[i] - X[j], dy = Y[i] - Y[j];\n int r = R[i] + R[j];\n if (dx * dx + dy * dy < r * r) return false;\n }\n return true;\n } ()) can_take.push_back(i);\n }\n for (int i : can_take) {\n for (int j : can_take) {\n if (i != j && C[i] == C[j]) {\n dp[bit ^ (1 << i) ^ (1 << j)] = true;\n }\n }\n }\n }\n cout << ans << '\\n';\n return true;\n}\n\nint main() {\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 1100, "memory_kb": 7764, "score_of_the_acc": -0.2479, "final_rank": 4 }, { "submission_id": "aoj_1175_9877855", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<long long, long long>;\n#define rep(i, a, b) for(long long i = (a); i < (b); ++i)\n#define rrep(i, a, b) for(long long i = (a); i >= (b); --i)\nconstexpr long long inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\nusing Real = long double;\nconstexpr Real EPS = Real(1e-8), PI = 3.141592653589793238462643383279L;\nint sign(const Real& r) {\n if(r <= -EPS) return -1;\n if(r >= +EPS) return +1;\n return 0;\n}\nbool eq(const Real& a, const Real& b) {\n return sign(a - b) == 0;\n}\nusing Point = complex<Real>;\nistream& operator>>(istream& is, Point& p) {\n Real a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n}\nostream& operator<<(ostream& os, const Point& p) {\n return os << p.real() << \" \" << p.imag();\n}\nPoint operator*(const Point& p, const Real& d) {\n return Point(p.real() * d, p.imag() * d);\n}\nPoint operator/(const Point& p, const Real& d) {\n return Point(p.real() / d, p.imag() / d);\n}\nPoint rot(const Point& p, const Real& theta) {\n return p * Point(cos(theta), sin(theta));\n}\nReal dot(const Point& p1, const Point& p2) {\n return (conj(p1) * p2).real();\n}\nReal cross(const Point& p1, const Point& p2) {\n return (conj(p1) * p2).imag();\n}\nReal dist(const Point& p1, const Point& p2) {\n return abs(p1 - p2);\n}\nbool comp_x(const Point& p1, const Point& p2) {\n return eq(p1.real(), p2.real()) ? p1.imag() < p2.imag() : p1.real() < p2.real();\n}\nbool comp_y(const Point& p1, const Point& p2) {\n return eq(p1.imag(), p2.imag()) ? p1.real() < p2.real() : p1.imag() < p2.imag();\n}\nbool comp_arg(const Point& p1, const Point& p2) {\n return arg(p1) < arg(p2);\n}\nint ccw(const Point& a, Point b, Point c) {\n b -= a;\n c -= a;\n if(sign(cross(b, c)) == 1) return 1;\n if(sign(cross(b, c)) == -1) return -1;\n if(sign(dot(b, c)) == -1) return +2;\n if(norm(b) < norm(c)) return -2;\n return 0;\n}\nReal closest_pair(vector<Point> ps) {\n if((int)ps.size() <= 1) return Real(1e18);\n sort(ps.begin(), ps.end(), comp_x);\n vector<Point> memo(ps.size());\n auto func = [&](const auto& func, const int l, const int r) -> Real {\n if(r - l <= 1) return Real(1e18);\n const int m = (l + r) >> 1;\n const Real x = ps[m].real();\n Real res = min(func(func, l, m), func(func, m, r));\n inplace_merge(ps.begin() + l, ps.begin() + m, ps.begin() + r, comp_y);\n int cnt = 0;\n for(int i = l; i < r; ++i) {\n if(abs(ps[i].real() - x) >= res) continue;\n for(int j = 0; j < cnt; ++j) {\n const Point d = ps[i] - memo[cnt - j - 1];\n if(d.imag() >= res) break;\n res = min(res, abs(d));\n }\n memo[cnt++] = ps[i];\n }\n return res;\n };\n return func(func, 0, (int)ps.size());\n}\nstruct Line {\n Point a, b;\n Line() = default;\n Line(const Point& a, const Point& b)\n : a(a), b(b) {}\n};\nusing Segment = Line;\nbool is_parallel(const Line& a, const Line& b) {\n return eq(cross(a.b - a.a, b.b - b.a), 0.0);\n}\nbool is_orthogonal(const Line& a, const Line& b) {\n return eq(dot(a.b - a.a, b.b - b.a), 0.0);\n}\nPoint projection(const Line& l, const Point& p) {\n Real t = dot(p - l.a, l.b - l.a) / norm(l.b - l.a);\n return l.a + (l.b - l.a) * t;\n}\nPoint reflection(const Line& l, const Point& p) {\n return p + (projection(l, p) - p) * 2.0;\n}\nbool is_intersect_lp(const Line& l, const Point& p) {\n return abs(ccw(l.a, l.b, p)) != 1;\n}\nbool is_intersect_sp(const Segment& s, const Point& p) {\n return ccw(s.a, s.b, p) == 0;\n}\nbool is_intersect_ll(const Line& l1, const Line& l2) {\n if(!eq(cross(l1.b - l1.a, l2.b - l2.a), 0.0)) return true;\n return eq(cross(l1.b - l1.a, l2.b - l1.a), 0.0);\n}\nbool is_intersect_ls(const Line& l, const Segment& s) {\n return sign(cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a)) <= 0;\n}\nbool is_intersect_sl(const Segment& s, const Line& l) {\n return is_intersect_ls(l, s);\n}\nbool is_intersect_ss(const Segment& s1, const Segment& s2) {\n if(ccw(s1.a, s1.b, s2.a) * ccw(s1.a, s1.b, s2.b) > 0) return false;\n return ccw(s2.a, s2.b, s1.a) * ccw(s2.a, s2.b, s1.b) <= 0;\n}\nvector<Point> intersection_ll(const Line& l1, const Line& l2) {\n vector<Point> res;\n if(!is_intersect_ll(l1, l2)) return res;\n Real a = cross(l1.b - l1.a, l2.b - l2.a);\n Real b = cross(l1.b - l1.a, l1.b - l2.a);\n if(eq(a, 0.0) and eq(b, 0.0)) {\n res.emplace_back(l2.a);\n } else {\n res.emplace_back(l2.a + (l2.b - l2.a) * b / a);\n }\n return res;\n}\nvector<Point> intersection_ss(const Segment& s1, const Segment& s2) {\n return is_intersect_ss(s1, s2) ? intersection_ll(Line(s1), Line(s2)) : vector<Point>();\n}\nReal dist_lp(const Line& l, const Point& p) {\n return abs(p - projection(l, p));\n}\nReal dist_sp(const Segment& s, const Point& p) {\n const Point h = projection(s, p);\n if(is_intersect_sp(s, h)) return abs(h - p);\n return min(abs(s.a - p), abs(s.b - p));\n}\nReal dist_ll(const Line& l1, const Line& l2) {\n if(is_intersect_ll(l1, l2)) return 0.0;\n return dist_lp(l1, l2.a);\n}\nReal dist_ss(const Segment& s1, const Segment& s2) {\n if(is_intersect_ss(s1, s2)) return 0.0;\n return min({dist_sp(s1, s2.a), dist_sp(s1, s2.b), dist_sp(s2, s1.a), dist_sp(s2, s1.b)});\n}\nReal dist_ls(const Line& l, const Segment& s) {\n if(is_intersect_ls(l, s)) return 0.0;\n return min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\nReal dist_sl(const Segment& s, const Line& l) {\n return dist_ls(l, s);\n}\nstruct Circle {\n Point p;\n Real r;\n Circle() = default;\n Circle(const Point& p, const Real& r)\n : p(p), r(r) {}\n};\nbool is_intersect_cp(const Circle& c, const Point& p) {\n return eq(abs(p - c.p), c.r);\n}\nbool is_intersect_cl(const Circle& c, const Line& l) {\n return sign(c.r - dist_lp(l, c.p)) >= 0;\n}\nint is_intersect_cc(Circle c1, Circle c2) {\n if(c1.r < c2.r) swap(c1, c2);\n const Real d = abs(c1.p - c2.p);\n const int a = sign(d - c1.r - c2.r);\n if(a >= 0) return a + 3;\n return sign(d - c1.r + c2.r) + 1;\n}\nvector<Point> intersection_cl(const Circle& c, const Line& l) {\n const Point h = projection(l, c.p);\n const Point e = (l.b - l.a) / abs(l.b - l.a);\n vector<Point> res;\n if(!is_intersect_cl(c, l)) return res;\n if(eq(dist_lp(l, c.p), c.r)) {\n res.emplace_back(h);\n } else {\n const Real b = sqrt(c.r * c.r - norm(h - c.p));\n res.emplace_back(h - e * b);\n res.emplace_back(h + e * b);\n }\n return res;\n}\nvector<Point> intersection_cs(const Circle& c, const Segment& s) {\n const vector<Point> cand = intersection_cl(c, Line(s));\n vector<Point> res;\n for(const Point& p : cand) {\n if(ccw(s.a, s.b, p) == 0) {\n res.emplace_back(p);\n }\n }\n return res;\n}\nvector<Point> intersection_cc(const Circle& c1, const Circle& c2) {\n const Real d = abs(c1.p - c2.p);\n const Real a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (Real(2.0) * c1.r * d));\n const Real t = atan2(c2.p.imag() - c1.p.imag(), c2.p.real() - c1.p.real());\n vector<Point> res;\n if(is_intersect_cc(c1, c2) % 4 == 0) return res;\n if(eq(a, 0.0)) {\n res.emplace_back(c1.p + rot(Point(c1.r, 0.0), t));\n } else {\n res.emplace_back(c1.p + rot(Point(c1.r, 0.0), t + a));\n res.emplace_back(c1.p + rot(Point(c1.r, 0.0), t - a));\n }\n return res;\n}\nvector<Point> tangent_cp(const Circle& c, const Point& p) {\n return intersection_cc(c, Circle(p, sqrt(norm(p - c.p) - c.r * c.r)));\n}\nvector<Line> tangent_cc(Circle c1, Circle c2) {\n vector<Line> res;\n if(c1.r < c2.r) swap(c1, c2);\n const Real r = abs(c2.p - c1.p);\n if(eq(r, 0.0)) return res;\n const Point u = (c2.p - c1.p) / r;\n const Point v = rot(u, PI * 0.5);\n for(const Real s : {Real(1.0), Real(-1.0)}) {\n const Real h = (c1.r + c2.r * s) / r;\n if(eq(abs(h), Real(1.0))) {\n res.emplace_back(c1.p + u * c1.r, c1.p + (u + v) * c1.r);\n } else if(abs(h) < Real(1.0)) {\n const Point uu = u * h, vv = v * sqrt(Real(1.0) - h * h);\n res.emplace_back(c1.p + (uu + vv) * c1.r, c2.p - (uu + vv) * c2.r * s);\n res.emplace_back(c1.p + (uu - vv) * c1.r, c2.p - (uu - vv) * c2.r * s);\n }\n }\n return res;\n}\nCircle inscribed_circle(const Point& a, const Point& b, const Point& c) {\n const Real A = abs(b - c), B = abs(c - a), C = abs(a - b);\n const Point x = Point((a * A + b * B + c * C) / (A + B + C));\n const Real r = dist_sp(Segment(a, b), x);\n return Circle(x, r);\n}\nCircle circumscribed_circle(const Point& a, const Point& b, const Point& c) {\n const Point m1((a + b) / 2.0), m2((b + c) / 2.0);\n const Point v((b - a).imag(), (a - b).real()), w((b - c).imag(), (c - b).real());\n const Line s(m1, Point(m1 + v)), t(m2, Point(m2 + w));\n const Point x = intersection_ll(s, t)[0];\n return Circle(x, abs(a - x));\n}\nCircle appollonius(const Point& p1, const Point& p2, const Real& a, const Real& b) {\n const Point q1 = (p1 * b + p2 * a) / (a + b), q2 = (-p1 * b + p2 * a) / (a - b);\n return Circle((q1 + q2) * 0.5, abs(q1 - q2) * 0.5);\n}\nReal area_cc(const Circle& c1, const Circle& c2) {\n const Real d = abs(c1.p - c2.p);\n if(c1.r + c2.r <= d + EPS) return 0.0;\n if(d <= abs(c1.r - c2.r) + EPS) {\n const Real r = min(c1.r, c2.r);\n return r * r * PI;\n }\n const Real rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (Real(2.0) * d);\n const Real theta = acos(rc / c1.r);\n const Real phi = acos((d - rc) / c2.r);\n return c1.r * c1.r * theta + c2.r * c2.r * phi - d * c1.r * sin(theta);\n}\nReal area_pc(const vector<Point>& ps, const Circle& c) {\n auto calc_element = [&](const Point& a, const Point& b, const Real& r, const bool triangle) -> Real {\n if(triangle) return cross(a, b) / 2.0;\n const Point tmp = b * Point(a.real(), -a.imag());\n const Real ang = atan2(tmp.imag(), tmp.real());\n return r * r * ang / 2.0;\n };\n auto cross_area = [&](const Circle& c, const Point& ia, const Point& ib) -> Real {\n const Point a = ia - c.p, b = ib - c.p;\n if(abs(a - b) < EPS) return 0;\n const bool isin_a = (abs(a) < c.r + EPS);\n const bool isin_b = (abs(b) < c.r + EPS);\n if(isin_a and isin_b) return calc_element(a, b, c.r, true);\n const Circle oc(Point(0.0, 0.0), c.r);\n const Segment seg(a, b);\n const vector<Point> cr = intersection_cs(oc, seg);\n if(cr.empty()) return calc_element(a, b, c.r, false);\n const Point s = cr[0], t = cr.back();\n return calc_element(s, t, c.r, true) + calc_element(a, s, c.r, isin_a) + calc_element(t, b, c.r, isin_b);\n };\n const int n = (int)ps.size();\n if(n < 3) return 0.0;\n Real S = 0;\n for(int i = 0; i < n; ++i) {\n S += cross_area(c, ps[i], ps[(i + 1) % n]);\n }\n return S;\n}\nint main(void) {\n while(1) {\n int n;\n cin >> n;\n if(n == 0) break;\n vector<Circle> c(n);\n vector<int> col(n);\n rep(i, 0, n) {\n cin >> c[i].p >> c[i].r >> col[i];\n }\n vector<vector<int>> intersect(n, vector<int>(n));\n rep(i, 0, n) {\n rep(j, 0, n) {\n intersect[i][j] = is_intersect_cc(c[i], c[j]);\n }\n }\n vector<int> dp(1 << n, -1);\n auto dfs = [&](auto& dfs, int mask) -> int {\n if(dp[mask] != -1) return dp[mask];\n int res = 0;\n rep(i, 0, n) {\n if(!(mask & (1 << i))) continue;\n rep(j, i + 1, n) {\n if(!(mask & (1 << j))) continue;\n if(col[i] != col[j]) continue;\n if(intersect[i][j] <= 2) continue;\n bool flag = true;\n rep(k, 0, n) {\n if(!(mask & (1 << k))) continue;\n if(k < i and intersect[k][i] <= 2) flag = false;\n if(k < j and intersect[k][j] <= 2) flag = false;\n }\n if(flag) {\n int nxt = mask xor (1 << i) xor (1 << j);\n res = max(res, 2 + dfs(dfs, nxt));\n }\n }\n }\n return dp[mask] = res;\n };\n cout << dfs(dfs, (1 << n) - 1) << '\\n';\n }\n}", "accuracy": 1, "time_ms": 1530, "memory_kb": 68932, "score_of_the_acc": -1.24, "final_rank": 13 }, { "submission_id": "aoj_1175_9717194", "code_snippet": "#include <bits/stdc++.h>\n using namespace std;\n \n template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\n template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n #define rep(i,n) for (int i = 0; i < (n); ++i)\n\n typedef long long ll;\n typedef unsigned long long ull;\n using P=pair<ll,ll>;\n using T=tuple<int,int,int>;\n const int INF=1001001001;\n const ll INFL=1e18;\n const int mod=998244353;\n\n\tstruct Point{\n\t\tint x,y,r,c;\n\t\tPoint(){}\n\t\tPoint(int x,int y,int r,int c):x(x),y(y),r(r),c(c){}\n\t};\n\n\tbool covered(Point& a,Point& b){\n\t\treturn (a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y)<(a.r+b.r)*(a.r+b.r);\n\t}\n\t\n\tbool isTop(int i,vector<Point>& ps,int vis){\n\t\tint n=ps.size();\n\t\trep(j,i){\n\t\t\tif(vis>>j&1)continue;\n\t\t\tif(covered(ps[i],ps[j]))return false;\n\t\t}\n\t\treturn true;\n\t}\n\n\tint dfs(int vis,vector<Point>& ps,map<int,int>& dp){\n\t\tif(dp.count(vis))return dp[vis];\n\n\t\tint n=ps.size();\n\t\tint mx=0;\n\t\trep(i,n){\n\t\t\trep(j,i){\n\t\t\t\tif(vis>>i&1 ||vis>>j&1)continue;\n\t\t\t\tif(!isTop(i,ps,vis)||!isTop(j,ps,vis))continue;\n\t\t\t\tif(ps[i].c!=ps[j].c)continue;\n\t\t\t\tint cnt=2+dfs(vis|1<<i|1<<j,ps,dp);\n\t\t\t\tchmax(mx,cnt);\n\t\t\t}\n\t\t}\n\t\treturn dp[vis]=mx;\n\t}\n\t\n bool solve(){\n\t\tint n;\n\t\tcin>>n;\n\t\tif(!n)return false;\n\n\t\tvector<Point>ps(n);\n\t\trep(i,n){\n\t\t\tint x,y,r,c;\n\t\t\tcin>>x>>y>>r>>c;\n\t\t\tps[i]=Point(x,y,r,c);\n\t\t}\n\n\t\tint vis=0;\n\t\tmap<int,int>dp;\n\t\tint ans=dfs(vis,ps,dp);\n\t\tcout<<ans<<endl;\n\t\treturn true;\n }\n\n int main(){\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n\t\twhile(1){\n\t\t\tif(!solve())break;\n\t\t}\n\t\t\n return 0;\n }", "accuracy": 1, "time_ms": 5500, "memory_kb": 52608, "score_of_the_acc": -1.7331, "final_rank": 20 }, { "submission_id": "aoj_1175_9558144", "code_snippet": "#include <algorithm>\n#include <bitset>\n#include <cmath>\n#include <cstdlib>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <unordered_set>\n#include <vector>\n\nusing namespace std;\nusing ll = long long;\n\nbool IsTop(const vector<int>& over, const int disks, const int disk) {\n\treturn !(over[disk] & disks);\n}\n\nvoid chmax(int& a, const int b) {\n\tif (a < b) a = b;\n}\n\nint _CountRemovableDisks(const vector<int>& over, const vector<int>& c, const int disks, vector<int>& memo) {\n\tif (memo[disks] >= 0) return memo[disks];\n\n\tint ans = 0;\n\n\tfor (int i = 0; i < over.size(); i++) {\n\t\tif (!(disks & (1 << i)) || !IsTop(over, disks, i)) continue;\n\t\tfor (int j = 0; j < i; j++) {\n\t\t\tif (!(disks & (1 << j)) || !IsTop(over, disks, j)) continue;\n\t\t\tif (c[i] != c[j]) continue;\n\t\t\tchmax(ans, _CountRemovableDisks(over, c, disks ^ ((1 << i) | (1 << j)), memo) + 2);\n\t\t}\n\t}\n\n\tmemo[disks] = ans;\n\treturn ans;\n}\n\nint CountRemovableDisks(const vector<int>& over, const vector<int>& c, const int disks) {\n\tvector<int> memo(1 << (over.size()), -1);\n\treturn _CountRemovableDisks(over, c, disks, memo);\n}\n\nbool Solve() {\n\tint n;\n\tcin >> n;\n\tif (n == 0) return false;\n\tvector<int> x(n), y(n), r(n), c(n);\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> x[i] >> y[i] >> r[i] >> c[i];\n\t}\n\n\tvector<int> over(n, 0);\n\tfor (int i = 0; i < n; i++) {\n\t\tfor (int j = 0; j < i; j++) {\n\t\t\tif ((x[i] - x[j]) * (x[i] - x[j]) + (y[i] - y[j]) * (y[i] - y[j]) < (r[i] + r[j]) * (r[i] + r[j])) {\n\t\t\t\tover[i] |= 1 << j;\n\t\t\t}\n\t\t}\n\t}\n\n\tint ans = CountRemovableDisks(over, c, (1 << n) - 1);\n\tcout << ans << endl;\n\n\treturn true;\n}\n\nint main(void) {\n\twhile (Solve());\n\treturn 0;\n}", "accuracy": 1, "time_ms": 520, "memory_kb": 68660, "score_of_the_acc": -1.0486, "final_rank": 10 }, { "submission_id": "aoj_1175_9556973", "code_snippet": "#include <algorithm>\n#include <bitset>\n#include <cmath>\n#include <cstdlib>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <unordered_set>\n#include <vector>\n\nusing namespace std;\nusing ll = long long;\n\nbool IsTop(const vector<int>& over, const int disks, const int disk) {\n\treturn !(over[disk] & disks);\n}\n\nvoid chmax(int& a, const int b) {\n\tif (a < b) a = b;\n}\n\nint _CountRemovableDisks(const vector<int>& over, const vector<int>& c, const int disks, vector<int>& memo) {\n\tif (memo[disks] >= 0) return memo[disks];\n\n\tint ans = 0;\n\n\tfor (int i = 0; i < over.size(); i++) {\n\t\tif (!(disks & (1 << i)) || !IsTop(over, disks, i)) continue;\n\t\tfor (int j = 0; j < i; j++) {\n\t\t\tif (!(disks & (1 << j)) || !IsTop(over, disks, j)) continue;\n\t\t\tif (c[i] != c[j]) continue;\n\t\t\tchmax(ans, _CountRemovableDisks(over, c, disks ^ ((1 << i) | (1 << j)), memo) + 2);\n\t\t}\n\t}\n\n\tmemo[disks] = ans;\n\treturn ans;\n}\n\nint CountRemovableDisks(const vector<int>& over, const vector<int>& c, const int disks) {\n\tvector<int> memo(1 << (over.size()), -1);\n\treturn _CountRemovableDisks(over, c, disks, memo);\n}\n\nbool Solve() {\n\tint n;\n\tcin >> n;\n\tif (n == 0) return false;\n\tvector<int> x(n), y(n), r(n), c(n);\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> x[i] >> y[i] >> r[i] >> c[i];\n\t}\n\n\tvector<int> over(n, 0);\n\tfor (int i = 0; i < n; i++) {\n\t\tfor (int j = 0; j < i; j++) {\n\t\t\tif ((x[i] - x[j]) * (x[i] - x[j]) + (y[i] - y[j]) * (y[i] - y[j]) < (r[i] + r[j]) * (r[i] + r[j])) {\n\t\t\t\tover[i] |= 1 << j;\n\t\t\t}\n\t\t}\n\t}\n\n\tint ans = CountRemovableDisks(over, c, (1 << n) - 1);\n\tcout << ans << endl;\n\n\treturn true;\n}\n\nint main(void) {\n\twhile (Solve());\n\treturn 0;\n}", "accuracy": 1, "time_ms": 530, "memory_kb": 68624, "score_of_the_acc": -1.0499, "final_rank": 11 }, { "submission_id": "aoj_1175_9517958", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint main() {\nwhile(1) {\n int N;\n cin >> N;\n if (N == 0) return 0;\n vector<int> X(N), Y(N), R(N), C(N);\n rep(i,0,N) cin >> X[i] >> Y[i] >> R[i] >> C[i], C[i]--;\n vector<int> B(N, 0);\n rep(i,0,N) {\n rep(j,0,i) {\n if ((X[i]-X[j])*(X[i]-X[j])+(Y[i]-Y[j])*(Y[i]-Y[j])<(R[i]+R[j])*(R[i]+R[j])) B[i] |= (1<<j);\n }\n }\n vector<bool> DP(1<<N,false);\n DP[0] = true;\n int ANS = 0;\n rep(i,0,1<<N) {\n if (!DP[i]) continue;\n int COUNT = 0;\n rep(j,0,N) {\n if ((i & (1<<j)) != 0) COUNT++;\n }\n chmax(ANS,COUNT);\n vector<vector<int>> V(4);\n rep(j,0,N) {\n if ((i & (1<<j)) == 0) {\n if ((i & B[j]) == B[j]) V[C[j]].push_back(j);\n }\n }\n rep(j,0,4) {\n rep(k,0,V[j].size()) {\n rep(l,0,k) {\n DP[i | (1<<V[j][k]) | (1<<V[j][l])] = true;\n }\n }\n }\n }\n cout << ANS << endl;\n}\n}", "accuracy": 1, "time_ms": 530, "memory_kb": 7528, "score_of_the_acc": -0.1387, "final_rank": 2 }, { "submission_id": "aoj_1175_9401610", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n#include <bits/stdc++.h>\n// #pragma GCC target(\"avx2\")\n// #pragma GCC optimize(\"O3\")\n// #pragma GCC optimize(\"unroll-loops\")\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = acos(-1.0);\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\ntemplate<typename T> void view(const vv<T>& vv){ for(const auto& v : vv){ view(v); } }\n\nint solve(int N){\n vi X(N), Y(N), R(N), C(N); rep(i, N) cin >> X[i] >> Y[i] >> R[i] >> C[i];\n vvi mem(4);\n rep(i, N) mem[C[i] - 1].push_back(i);\n vl up(N, 0);\n rep(j, N) rep(i, j){\n if ((X[i] - X[j]) * (X[i] - X[j]) + (Y[i] - Y[j]) * (Y[i] - Y[j]) < (R[i] + R[j]) * (R[i] + R[j])){\n up[j] |= (1 << i);\n }\n }\n int ans = 0;\n vi seen(1 << N, 0);\n function<void(int)> dfs = [&](int cmb){\n if (seen[cmb]) return;\n seen[cmb] = 1;\n ans = max(ans, N - __builtin_popcount(cmb));\n if (ans == N) return;\n for (auto v : mem){\n rep(j, len(v)) rep(i, j) if ((cmb >> v[i]) & 1 && (cmb >> v[j]) & 1){\n if ((up[v[i]] & cmb) == 0 && (up[v[j]] & cmb) == 0){\n dfs(cmb ^ (1 << v[i]) ^ (1 << v[j]));\n }\n }\n }\n };\n dfs((1 << N) - 1);\n return ans;\n}\n\nint main(){\n vi ans;\n while (true){\n int N; cin >> N;\n if (N == 0) break;\n ans.push_back(solve(N));\n }\n for (auto x : ans) cout << x << endl;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 68728, "score_of_the_acc": -0.9735, "final_rank": 9 }, { "submission_id": "aoj_1175_9174991", "code_snippet": "#include <bits/stdc++.h>\n\nbool solve() {\n int N;\n std::cin >> N;\n if (N == 0) return false;\n std::vector<int> X(N), Y(N), R(N), C(N);\n for (int i{} ; i < N ; i++) {\n std::cin >> X[i] >> Y[i] >> R[i] >> C[i];\n C[i]--;\n }\n std::vector<int> up(N);\n for (int i{} ; i < N ; i++) {\n for (int j{} ; j < i ; j++) {\n int dx{X[i] - X[j]}, dy{Y[i] - Y[j]};\n int d{dx * dx + dy * dy};\n if (d < (R[i] + R[j]) * (R[i] + R[j])) {\n up[i] |= (1 << j);\n }\n }\n }\n std::vector<bool> dp(1 << N);\n dp[0] = true;\n for (int bit{} ; bit < (1 << N) ; bit++) {\n if (!dp[bit]) continue;\n // std::cout << bit << \" go\" << std::endl;\n std::vector<std::vector<int>> rem(4);\n for (int i{} ; i < N ; i++) {\n if (bit & (1 << i)) continue;\n if ((up[i] & bit) != up[i]) continue;\n rem[C[i]].push_back(i);\n }\n for (int i{} ; i < 4 ; i++) {\n for (int j{} ; j < (int)rem[i].size() ; j++) {\n for (int k{j + 1} ; k < (int)rem[i].size() ; k++) {\n dp[bit | (1 << rem[i][j]) | (1 << rem[i][k])] = true;\n }\n }\n }\n }\n int ans{};\n for (int i{} ; i < (1 << N) ; i++) {\n if (dp[i]) ans = std::max(ans, __builtin_popcount(i));\n }\n std::cout << ans << '\\n';\n return true;\n}\n\nint main() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n while (solve()) ;\n}", "accuracy": 1, "time_ms": 590, "memory_kb": 7488, "score_of_the_acc": -0.1492, "final_rank": 3 } ]
aoj_1176_cpp
Planning Rolling Blackouts Faced with seriously tight power supply-demand balance, the electric power company for which you are working implemented rolling blackouts in this spring. It divided the servicing area into several groups of towns, and divided a day into several blackout periods. At each blackout period of a day, one of the groups, which alternates from one group to another, is cut off the electricity. By keeping the total demand of electricity used by the rest of the towns within the supply capacity, the company avoided unforeseeable large-scale blackout. Working at the customer relations department, you had to listen to so many complaints from the customers, which made you think that you could have a better implementation. Most of the complaints are about the frequent cut-offs. But you could have divided the area into a larger number of groups, which resulted in less frequent cut-offs for each group. The other complaints are about the complicated grouping (in fact, someone said that the shapes of the groups are fractals), which makes it impossible to understand which town belongs to which group without closely inspecting into the grouping list publicized by the company. With the rectangular servicing area and towns located in a grid form, you could have made a simpler grouping. When you talked your analysis directly to the president of the company, you are appointed to plan rolling blackouts for this summer. Be careful what you propose. Anyway, you need to divide the servicing area into as many groups as possible with keeping total demand of electricity within the supply capacity. It should also divide the towns into simple and easy to remember groups. Your task is to write a program, given a demand table (a table showing electricity demand of each town) and the supply capacity, that answers a grouping of towns that satisfy the following conditions. The grouping should be made by horizontally or vertically splitting the area in a recursive manner. In other words, the grouping must be a set of areas after applied the following splitting procedure to a set containing only the entire area for zero or more times: (The splitting procedure) remove one area from the set, either vertically or horizontally split it into two sub-areas, and put the sub-areas into the set. The maximum suppressed demand of the grouping, which is the greatest total demand of the all but one group, is no more than the supply capacity. The grouping has the largest number of groups among the groupings that satisfy the above conditions 1 and 2. The grouping has the greatest amount of reserve power among the groupings that satisfy the above conditions 1, 2 and 3, where the reserve power of a grouping is the difference between the supply capacity and the maximum suppressed demand. Note that the condition 1 does not allow such a grouping shown in Figure E-1. Figure E-1: A grouping that violates the condition 1 Input ...(truncated)
[ { "submission_id": "aoj_1176_10866686", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <iostream>\n#include <algorithm>\nconst int oo=1073741819;\nusing namespace std;\nint n,m,s,w_time;\nint sum[50][50],t[50][50][50][50],a[50][50];\nstruct sta{\n int tot,max;\n}f[50][50][50][50];\nvoid updata(sta &x,sta a,sta b)\n{\n if (!a.tot || !b.tot) return ;\n if (a.tot+b.tot>x.tot) {\n x.tot=a.tot+b.tot;\n x.max=min(a.max,b.max);\n// if (x.tot==5) cout<<a.tot<<' '<<b.tot<<endl;\n }\n else if (a.tot+b.tot==x.tot) {\n if (min(a.max,b.max)>x.max) \n x.max=min(a.max,b.max);\n }\n}\nvoid print(sta a)\n{\n cout<<a.tot<<' '<<a.max<<endl;\n}\nvoid dfs(int lx,int ly,int rx,int ry)\n{\n if (t[lx][ly][rx][ry]==w_time) return ;\n// cout<<lx<<' '<<ly<<' '<<rx<<' '<<ry<<endl;\n t[lx][ly][rx][ry]=w_time;\n f[lx][ly][rx][ry].tot=0,\n f[lx][ly][rx][ry].max=-oo;\n if (lx==rx && ly==ry) {\n if (sum[n][m]-a[lx][ly]<=s) {\n f[lx][ly][rx][ry].tot=1;\n f[lx][ly][rx][ry].max=s-(sum[n][m]-a[lx][ly]);\n }\n return ;\n }\n int Sum=sum[rx][ry]-sum[rx][ly-1]-sum[lx-1][ry]+sum[lx-1][ly-1];\n if (sum[n][m]-Sum<=s) {\n f[lx][ly][rx][ry].tot=1;\n f[lx][ly][rx][ry].max=s-(sum[n][m]-Sum);\n }\n for (int i=lx;i<=rx-1;i++) {\n dfs(lx,ly,i,ry);\n dfs(i+1,ly,rx,ry);\n updata(f[lx][ly][rx][ry],f[lx][ly][i][ry],f[i+1][ly][rx][ry]);\n // print(f[lx][ly][rx][ry]);\n }\n for (int i=ly;i<=ry-1;i++) {\n dfs(lx,ly,rx,i);\n dfs(lx,i+1,rx,ry);\n updata(f[lx][ly][rx][ry],f[lx][ly][rx][i],f[lx][i+1][rx][ry]);\n // print(f[lx][ly][rx][ry]);\n }\n// cout<<lx<<' '<<ly<<' '<<rx<<' '<<ry<<endl;\n// print(f[lx][ly][rx][ry]);\n}\nint main()\n{\n for (;scanf(\"%d%d%d\",&n,&m,&s)==3;) {\n if (!n && !m && !s) break;\n for (int i=1;i<=n;i++)\n for (int j=1;j<=m;j++)\n scanf(\"%d\",&a[i][j]);\n for (int i=1;i<=n;i++)\n for (int j=1;j<=m;j++) \n sum[i][j]=0;\n for (int i=1;i<=n;i++)\n for (int j=1;j<=m;j++)\n sum[i][j]=sum[i-1][j]+sum[i][j-1]-sum[i-1][j-1]+a[i][j];\n w_time++;\n // cout<<n<<' '<<m<<endl;\n dfs(1,1,n,m);\n printf(\"%d %d\\n\",f[1][1][n][m].tot,f[1][1][n][m].max);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 53172, "score_of_the_acc": -1.0286, "final_rank": 19 }, { "submission_id": "aoj_1176_10648871", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconstexpr pair<int, int> INIT = {-1, -1};\n\nvoid solve(int h, int w, int s, vector<vector<int>> u) {\n vector<vector<int>> pref(h + 1, vector<int>(w + 1, 0));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n pref[i + 1][j + 1] = pref[i][j + 1] + pref[i + 1][j] - pref[i][j] + u[i][j];\n }\n }\n auto get_pref = [&](int x1, int y1, int x2, int y2) { return pref[x2][y2] - pref[x1 - 1][y2] - pref[x2][y1 - 1] + pref[x1 - 1][y1 - 1]; };\n int total = get_pref(1, 1, h, w);\n\n auto chmax = [](pair<int, int>& a, pair<int, int>& b) -> bool {\n if (a.first == b.first && a.second < b.second) {\n a = b;\n return true;\n }\n if (a.first < b.first) {\n a = b;\n return true;\n }\n return false;\n };\n\n // dp[x1][y1][x2][y2] := x1,y1が左上,x2,y2が右下の長方形内の{グループの最大個数, 予備電力}\n vector dp(h + 1, vector(w + 1, vector(h + 1, vector<pair<int, int>>(w + 1, {-1, -1}))));\n auto dfs = [&](auto dfs, int x1, int y1, int x2, int y2) -> pair<int, int> {\n if (dp[x1][y1][x2][y2] != INIT) {\n return dp[x1][y1][x2][y2];\n }\n\n if (total - get_pref(x1, y1, x2, y2) > s) {\n return dp[x1][y1][x2][y2] = INIT;\n }\n\n pair<int, int> ret = {1, s - (total - get_pref(x1, y1, x2, y2))};\n for (int nx = x1; nx < x2; nx++) {\n auto g1 = dfs(dfs, x1, y1, nx, y2);\n auto g2 = dfs(dfs, nx + 1, y1, x2, y2);\n if (g1 == INIT || g2 == INIT) {\n continue;\n }\n pair<int, int> res = {g1.first + g2.first, min(g1.second, g2.second)};\n chmax(ret, res);\n }\n for (int ny = y1; ny < y2; ny++) {\n auto g1 = dfs(dfs, x1, y1, x2, ny);\n auto g2 = dfs(dfs, x1, ny + 1, x2, y2);\n if (g1 == INIT | g2 == INIT) {\n continue;\n }\n pair<int, int> res = {g1.first + g2.first, min(g1.second, g2.second)};\n chmax(ret, res);\n }\n\n return dp[x1][y1][x2][y2] = ret;\n };\n\n auto ans = dfs(dfs, 1, 1, h, w);\n cout << ans.first << \" \" << ans.second << endl;\n}\n\nint main() {\n while (true) {\n int h, w, s;\n cin >> h >> w >> s;\n if (h == 0 && w == 0 && s == 0) {\n break;\n }\n vector<vector<int>> u(h, vector<int>(w));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n cin >> u[i][j];\n }\n }\n solve(h, w, s, u);\n }\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 14212, "score_of_the_acc": -0.134, "final_rank": 9 }, { "submission_id": "aoj_1176_10648064", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconstexpr pair<int, int> INIT = {-1, -1};\n\nvoid solve(int h, int w, int s, vector<vector<int>> u) {\n vector<vector<int>> pref(h + 1, vector<int>(w + 1, 0));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n pref[i + 1][j + 1] = pref[i][j + 1] + pref[i + 1][j] - pref[i][j] + u[i][j];\n }\n }\n auto get_pref = [&](int x1, int y1, int x2, int y2) { return pref[x2][y2] - pref[x1 - 1][y2] - pref[x2][y1 - 1] + pref[x1 - 1][y1 - 1]; };\n int total = get_pref(1, 1, h, w);\n \n auto chmax = [&](pair<int, int>& a, pair<int, int>& b) -> bool {\n if (a.first == b.first && a.second < b.second) {\n a = b;\n return true;\n }\n if (a.first < b.first) {\n a = b;\n return true;\n }\n return false;\n };\n\n // dp[x1][y1][x2][y2] := x1,y1が左上,x2,y2が右下の長方形内の{グループの最大個数, 予備電力}\n vector dp(h + 1, vector(w + 1, vector(h + 1, vector<pair<int, int>>(w + 1, {-1, -1}))));\n auto dfs = [&](auto dfs, int x1, int y1, int x2, int y2) -> pair<int, int> {\n if (dp[x1][y1][x2][y2] != INIT) {\n return dp[x1][y1][x2][y2];\n }\n\n if (total - get_pref(x1, y1, x2, y2) > s) {\n return dp[x1][y1][x2][y2] = INIT;\n }\n\n pair<int, int> ret = {1, s - (total - get_pref(x1, y1, x2, y2))};\n for (int nx = x1; nx < x2; nx++) {\n auto g1 = dfs(dfs, x1, y1, nx, y2);\n auto g2 = dfs(dfs, nx + 1, y1, x2, y2);\n if (g1 == INIT || g2 == INIT) {\n continue;\n }\n auto [f1, s1] = g1;\n auto [f2, s2] = g2;\n pair<int, int> res = {f1 + f2, min(s1, s2)};\n chmax(ret, res);\n }\n for (int ny = y1; ny < y2; ny++) {\n auto g1 = dfs(dfs, x1, y1, x2, ny);\n auto g2 = dfs(dfs, x1, ny + 1, x2, y2);\n if (g1 == INIT || g2 == INIT) {\n continue;\n }\n auto [f1, s1] = g1;\n auto [f2, s2] = g2;\n pair<int, int> res = {f1 + f2, min(s1, s2)};\n chmax(ret, res);\n }\n\n return dp[x1][y1][x2][y2] = ret;\n };\n\n auto ans = dfs(dfs, 1, 1, h, w);\n cout << ans.first << \" \" << ans.second << endl;\n}\n\nint main() {\n while (true) {\n int h, w, s;\n cin >> h >> w >> s;\n if (h == 0 && w == 0 && s == 0) {\n break;\n }\n vector<vector<int>> u(h, vector<int>(w));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n cin >> u[i][j];\n }\n }\n solve(h, w, s, u);\n }\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 14280, "score_of_the_acc": -0.1356, "final_rank": 11 }, { "submission_id": "aoj_1176_10648062", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconstexpr pair<int, int> INIT = {-1, -1};\n\nvoid solve(int h, int w, int s, vector<vector<int>> u) {\n vector<vector<int>> pref(h + 1, vector<int>(w + 1, 0));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n pref[i + 1][j + 1] = pref[i][j + 1] + pref[i + 1][j] - pref[i][j] + u[i][j];\n }\n }\n auto get_pref = [&](int x1, int y1, int x2, int y2) { return pref[x2][y2] - pref[x1 - 1][y2] - pref[x2][y1 - 1] + pref[x1 - 1][y1 - 1]; };\n\n int total = get_pref(1, 1, h, w);\n\n auto chmax = [&](pair<int, int>& a, pair<int, int>& b) -> bool {\n if (a.first == b.first && a.second < b.second) {\n a = b;\n return true;\n }\n if (a.first < b.first) {\n a = b;\n return true;\n }\n return false;\n };\n\n // dp[x1][y1][x2][y2] := x1,y1が左上,x2,y2が右下の長方形内の{グループの最大個数, 予備電力}\n vector dp(h + 1, vector(w + 1, vector(h + 1, vector<pair<int, int>>(w + 1, {-1, -1}))));\n auto dfs = [&](auto dfs, int x1, int y1, int x2, int y2) -> pair<int, int> {\n if (dp[x1][y1][x2][y2] != INIT) {\n return dp[x1][y1][x2][y2];\n }\n\n if (total - get_pref(x1, y1, x2, y2) > s) {\n return dp[x1][y1][x2][y2] = INIT;\n }\n\n pair<int, int> ret = {1, s - (total - get_pref(x1, y1, x2, y2))};\n for (int nx = x1; nx < x2; nx++) {\n auto g1 = dfs(dfs, x1, y1, nx, y2);\n auto g2 = dfs(dfs, nx + 1, y1, x2, y2);\n if (g1 == INIT || g2 == INIT) {\n continue;\n }\n auto [f1, s1] = g1;\n auto [f2, s2] = g2;\n pair<int, int> res = {f1 + f2, min(s1, s2)};\n chmax(ret, res);\n }\n for (int ny = y1; ny < y2; ny++) {\n auto g1 = dfs(dfs, x1, y1, x2, ny);\n auto g2 = dfs(dfs, x1, ny + 1, x2, y2);\n if (g1 == INIT || g2 == INIT) {\n continue;\n }\n auto [f1, s1] = g1;\n auto [f2, s2] = g2;\n pair<int, int> res = {f1 + f2, min(s1, s2)};\n chmax(ret, res);\n }\n\n return dp[x1][y1][x2][y2] = ret;\n };\n\n auto ans = dfs(dfs, 1, 1, h, w);\n cout << ans.first << \" \" << ans.second << endl;\n}\n\nint main() {\n while (true) {\n int h, w, s;\n cin >> h >> w >> s;\n if (h == 0 && w == 0 && s == 0) {\n break;\n }\n vector<vector<int>> u(h, vector<int>(w));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n cin >> u[i][j];\n }\n }\n solve(h, w, s, u);\n }\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 14212, "score_of_the_acc": -0.134, "final_rank": 9 }, { "submission_id": "aoj_1176_10631697", "code_snippet": "//#pragma GCC optimize(\"O3\")\n#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,n) for (ll i=0;i<(ll)n;i++)\n#define rrep(i,n) for (ll i=n-1;i>=(ll)0;i--)\n#define loop(i,m,n) for(ll i=m;i<=(ll)n;i++)\n#define rloop(i,m,n) for(ll i=m;i>=(ll)n;i--)\n#define vl vector<ll>\n#define vvl vector<vector<ll>>\n#define vdbg(a) rep(ii,a.size()){cout<<a[ii]<<\" \";}cout<<endl;\n#define vpdbg(a) rep(ii,a.size()){cout<<\"{\"<<a[ii].first<<\",\"<<a[ii].second<<\"} \";}cout<<endl;\n#define vvdbg(a) rep(ii,a.size()){rep(jj,a[ii].size()){cout<<a[ii][jj]<<\" \";}cout<<endl;}\n#define setdbg(a) for(const auto & ii:a){cout<<ii<<\" \";}cout<<endl;\n#define inf 1e9\n#define mod 998244353LL\n//#define mod 1000000007LL\n#define eps 0.000000001\nrandom_device rnd;// 非決定的な乱数生成器\nmt19937 mt(rnd());// メルセンヌ・ツイスタの32ビット版、引数は初期シード\n\n//#include<boost/multiprecision/cpp_int.hpp>\n//#define bbi boost::multiprecision::cpp_int\n//#include<atcoder/lazysegtree>\n\n\n//整数同士の累乗の計算をする。\nll power(ll A, ll B) {\n\tll result = 1;\n\tfor (ll i=0;i<B;i++){\n\t\tresult *= A;\n\t}\n\treturn result;\n}\n\n// nのk乗をmodで割った余りを計算\nll power_mod(ll n, ll k){\n\tlong long result = 1;\n\twhile (k > 0){\n\t\tif ((k&1) ==1)result=(result*n)%mod;\n\t\tn=n*n%mod;\n\t\tk >>= 1;\n\t}\n\treturn result;\n}\n\n\n//受け取った2次元文字の外側に、文字pをコーティングする。\nvector<string> pad(vector<string> &s,char p){\n\tll h=s.size();\n\tll w=s[0].size();\n\tvector<string> res(h+2,string(w+2,p));\n\trep(i,h)rep(j,w)res[i+1][j+1]=s[i][j];\n\treturn res;\n}\n\n// Union-Find\nstruct UnionFind {\n\tvector<int> par, siz;\n\tUnionFind(int n) : par(n, -1) , siz(n, 1) { }\n\t// 根を求める\n\tint root(int x) {\n\t\tif (par[x] == -1) return x;\n\t\telse return par[x] = root(par[x]);\n\t}\n\t// x と y が同じグループに属するかどうか (根が一致するかどうか)\n\tbool issame(int x, int y) {\n\t\treturn root(x) == root(y);\n\t}\n\t// x を含むグループと y を含むグループとを併合する\n\tbool unite(int x, int y) {\n\t\tx = root(x), y = root(y);\n\t\tif (x == y) return false; \n\t\tif (siz[x] < siz[y]) swap(x, y);\n\t\tpar[y] = x;\n\t\tsiz[x] += siz[y];\n\t\treturn true;\n\t}\n\t// x を含むグループのサイズ\n\tint size(int x) {\n\t\treturn siz[root(x)];\n\t}\n};\n\n\n//グリッド問題等用\nvl dx={1,0,-1,0};\nvl dy={0,1,0,-1};\n\nll s;\nvvl u;\nunordered_map<ll,pair<ll,ll>> dp;\nvvl sums;\n\npair<ll,ll> dfs(ll aa){\n\tif(dp.count(aa))return dp[aa];\n\tvl a;\n\ta.push_back(aa%32);\n\ta.push_back((aa/32)%32);\n\ta.push_back((aa/1024)%32);\n\ta.push_back((aa/32768)%32);\n\n\tll sum=sums[a[0]][a[1]]+sums[a[2]+1][a[3]+1]-sums[a[0]][a[3]+1]-sums[a[2]+1][a[1]];\n\n\tif(sum<s){\n\t\tpair<ll,ll> ans={-inf,0};\n\t\tdp[aa]=ans;\n\t\treturn ans;\n\t}\n\tpair<ll,ll> ans={1,sum-s};\n\tif(sum<s*2){\n\t\tdp[aa]=ans;\n\t\treturn ans;\n\t}\n\t\n\t//iの下に横線で切る\n\tloop(i,a[0],a[2]-1){\n\t\tll first=a[0]+a[1]*32+i*1024+a[3]*32768;\n\t\tll second=i+1+a[1]*32+a[2]*1024+a[3]*32768;\n\t\tpair<ll,ll> tmp=dfs(first);\n\t\tpair<ll,ll> tmp2=dfs(second);\n\t\tans=max(ans,{tmp.first+tmp2.first,min(tmp.second,tmp2.second)});\n\t}\n\n\t//iの右に縦線で切る\n\tloop(i,a[1],a[3]-1){\n\t\tll first=a[0]+a[1]*32+a[2]*1024+i*32768;\n\t\tll second=a[0]+(i+1)*32+a[2]*1024+a[3]*32768;\n\t\tpair<ll,ll> tmp=dfs(first);\n\t\tpair<ll,ll> tmp2=dfs(second);\n\t\tans=max(ans,{tmp.first+tmp2.first,min(tmp.second,tmp2.second)});\n\t}\n\n\tdp[aa]=ans;\n\treturn ans;\n}\n\nll solve(){\n\tll h,w;\n\tcin>>h>>w>>s;\n\tif(h==0){return 1;}\n\tu=vvl(h,vl(w));\n\tsums=vvl(h+1,vl(w+1,0));\n\tdp.clear();\n\n\trep(i,h)rep(j,w){\n\t\tcin>>u[i][j];\n\t\tsums[i+1][j+1]=sums[i+1][j]+sums[i][j+1]-sums[i][j]+u[i][j];\n\t}\n\t\n\ts=sums[h][w]-s;\n\n\tll tmp=(h-1)*1024+(w-1)*32768;\n\tpair<ll,ll> ans=dfs(tmp);\n\tcout<<ans.first<<\" \"<<ans.second<<\"\\n\";\n\t\n\treturn 0;\n}\n\n//メイン\nint main(){\n\twhile(solve()==0);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1330, "memory_kb": 19684, "score_of_the_acc": -0.4085, "final_rank": 16 }, { "submission_id": "aoj_1176_10625085", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef int ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rrep(i,start,end) for (ll i = start;i >= (ll)(end);i--)\n#define repn(i,end) for(ll i = 0; i <= (ll)(end); i++)\n#define reps(i,start,end) for(ll i = start; i < (ll)(end); i++)\n#define repsn(i,start,end) for(ll i = start; i <= (ll)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef vector<ll> vll;\ntypedef vector<pair<ll ,ll>> vpll;\ntypedef vector<vector<ll>> vvll;\ntypedef set<ll> sll;\ntypedef map<ll , ll> mpll;\ntypedef pair<ll ,ll> pll;\ntypedef tuple<ll , ll , ll> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (ll)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1 << 30;\nconst ld EPS = 1e-9;\n \nll lceil(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b)+1;}else{return -((-a)/b);}}\nll lfloor(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b);}else{return -((-a)/b)-1;}}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\n//0indexed\ninline ll topbit(ll a){assert(a != 0);return 63 - __builtin_clzll(a);}\ninline ll smlbit(ll a){assert(a != 0);return __builtin_ctzll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\n// for AOJ or ICPC or etc..\ntemplate<class Tp>\nbool zero (const Tp &x) {\n return x == 0;\n}\n\ntemplate<class Tp, class... Args>\nbool zero (const Tp &x, const Args& ...args) {\n return zero(x) and zero(args...);\n}\n\nvoid solve(ll h,ll w,ll s){\n vvll u(h,vll(w));\n ll usum = 0;\n rep(i,h){\n cin >> u[i];\n rep(j,w){\n usum += u[i][j];\n }\n }\n vvll sum(h+1,vll(w+1));\n rep(i,h){\n rep(j,w){\n sum[i+1][j+1] = sum[i+1][j] + sum[i][j+1] - sum[i][j] + u[i][j]; \n }\n }\n auto getsum = [&](ll yl,ll yr,ll xl,ll xr){\n return sum[yr][xr] - sum[yr][xl] - sum[yl][xr] + sum[yl][xl];\n };\n ll least = usum - s;\n vector dp(h+1,vector(h+1,vector(w+1,vector<ll>(w+1,INF))));//個数、予備(leastと最小の差の最大)\n ll key = 10000;\n auto cmax = [&](ll &x,ll y) {\n ll xnum = x % key;\n ll xyobi= x / key;\n \n ll ynum = y % key;\n ll yyobi= y / key;\n if(xnum <ynum){\n x = y;\n }else if(xnum == ynum && xyobi < yyobi){\n x = y;\n }\n };\n auto clc = [&](ll num,ll yobi){\n return num + key * yobi;\n };\n auto revclc = [&](ll x) -> pll {\n ll num = x % key;\n ll yobi = x/ key;\n return {num,yobi};\n };\n ll badnum = 5000;\n auto dfs = [&](auto dfs, ll yl,ll yr,ll xl,ll xr)->ll {\n if(dp[yl][yr][xl][xr] != INF){\n return dp[yl][yr][xl][xr];\n }\n if(getsum(yl,yr,xl,xr) < least){//それがだめ\n return dp[yl][yr][xl][xr] = badnum;\n }\n //縦\n ll ans = clc(1,getsum(yl,yr,xl,xr)-least);\n reps(i,yl+1,yr){\n auto [num1,yobi1] = revclc(dfs(dfs,yl,i,xl,xr));\n auto [num2,yobi2] = revclc(dfs(dfs,i,yr,xl,xr));\n if(num1 == badnum or num2 == badnum)continue;\n cmax(ans,clc(num1+num2,min(yobi1,yobi2)));\n }\n reps(j,xl+1,xr){\n auto [num1,yobi1] = revclc(dfs(dfs,yl,yr,xl,j));\n auto [num2,yobi2] = revclc(dfs(dfs,yl,yr,j,xr));\n if(num1 == badnum or num2 == badnum)continue;\n cmax(ans,clc(num1+num2,min(yobi1,yobi2)));\n }\n return dp[yl][yr][xl][xr] = ans;\n };\n auto [num,yobi] = revclc(dfs(dfs,0,h,0,w));\n\n cout << num << \" \" << yobi << endl;\n\n}\n\n \nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true){\n LL(h,w,s);;\n if(zero(h,w,s))break;\n solve(h,w,s);\n }\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 9620, "score_of_the_acc": -0.0372, "final_rank": 1 }, { "submission_id": "aoj_1176_10600472", "code_snippet": "#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#ifndef ONLINE_JUDGE\n#define _GLIBCXX_DEBUG // 配列外参照のエラー\n#endif\n\n// スタンダードライブラリ\n#include <bits/stdc++.h>\nusing namespace std;\n\n// 多倍長整数\n// #if __has_include(<boost/multiprecision/cpp_int.hpp>)\n// #include <boost/multiprecision/cpp_int.hpp>\n// using lll =boost::multiprecision::int128_t;\n// #endif\n\n// atcoder関連\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\nusing namespace atcoder;\nusing mint = modint998244353;\nusing MINT = modint1000000007;\n#endif\n\n// 型関連\nusing ll = long long;\nusing lint = long long;\nusing pll = pair<ll, ll>;\nusing plll = tuple<ll, ll, ll>;\nusing pii = pair<int, int>;\nusing piii = tuple<ll, ll, ll>;\ntemplate <class T> using prique = priority_queue<T>;\n\n// 型定数\nconstexpr ll mod = 998244353;\nconstexpr ll MOD = 1000000007;\nint inf = 2e9;\nll INF = 9e18;\n#define endl '\\n';\n\n// 新規マクロ\n#define all(a) (a).begin(), (a).end()\n#define rep(i, N, limit) for (int i = (int)N; i < (int)limit; i++)\n\n///////////////////// vector関連\ntemplate <class T, size_t n, size_t idx = 0>\nauto make_vec(const size_t (&d)[n], const T &init) noexcept {\n if constexpr (idx < n)\n return std::vector(d[idx], make_vec<T, n, idx + 1>(d, init));\n else\n return init;\n}\n\ntemplate <class T, size_t n> auto make_vec(const size_t (&d)[n]) noexcept {\n return make_vec(d, T{});\n}\n\nint dx[4] = {1, 0, -1, 0};\nint dy[4] = {0, 1, 0, -1};\n\n/////////////////////////// print関連\ntemplate <typename T> void print(vector<T> A);\nvoid print();\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail);\nvoid print(string S);\ntemplate <typename T> void print(vector<vector<T>> &F);\n\n////////////////////////////\ninline string input();\ninline ll I();\ninline pll II();\n\n/////////////////////出力関連\ninline void Yes(bool f);\n\n///////////////////ここから//////////////////////\n\nbool solve() {\n int H, W, S;\n cin >> H >> W >> S;\n if (H == 0) {\n return false;\n }\n int all_sum = 0;\n vector<vector<int>> F(H, vector<int>(W));\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n cin >> F[i][j];\n all_sum += F[i][j];\n }\n }\n vector<vector<int>> psum(H + 1, vector<int>(W + 1));\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n psum[i + 1][j + 1] = F[i][j];\n }\n }\n for (int i = 0; i < H + 1; i++) {\n for (int j = 0; j < W; j++) {\n psum[i][j + 1] += psum[i][j];\n }\n }\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W + 1; j++) {\n psum[i + 1][j] += psum[i][j];\n }\n }\n\n auto kukei = [&](int x_l, int x_r, int y_l, int y_r) {\n return psum[x_r][y_r] - psum[x_r][y_l] - psum[x_l][y_r] +\n psum[x_l][y_l];\n };\n\n vector<vector<vector<vector<int>>>> memo;\n memo.assign(H + 1,\n vector<vector<vector<int>>>(\n H + 1, vector<vector<int>>(W + 1, vector<int>(W + 1, -1))));\n\n auto reset = [&]() {\n memo.assign(H + 1,\n vector<vector<vector<int>>>(\n H + 1, vector<vector<int>>(W + 1, vector<int>(W + 1, -1))));\n };\n auto f = [&](auto &f, int g_min, int x_l, int x_r, int y_l,\n int y_r) -> int {\n if (memo[x_l][x_r][y_l][y_r] != -1) {\n return memo[x_l][x_r][y_l][y_r];\n }\n if (kukei(x_l, x_r, y_l, y_r) < g_min) {\n return -1000000;\n }\n int ret = 1;\n for (int i = x_l + 1; i < x_r; i++) {\n if (kukei(x_l, i, y_l, y_r) >= g_min &&\n kukei(i, x_r, y_l, y_r) >= g_min) {\n ret = max(ret, f(f, g_min, x_l, i, y_l, y_r) +\n f(f, g_min, i, x_r, y_l, y_r));\n }\n }\n for (int i = y_l + 1; i < y_r; i++) {\n if (kukei(x_l, x_r, y_l, i) >= g_min &&\n kukei(x_l, x_r, i, y_r) >= g_min) {\n ret = max(ret, f(f, g_min, x_l, x_r, y_l, i) +\n f(f, g_min, x_l, x_r, i, y_r));\n }\n }\n memo[x_l][x_r][y_l][y_r] = ret;\n return ret;\n };\n\n reset();\n int g_count = f(f, all_sum - S, 0, H, 0, W);\n int ok = all_sum - S, ng = 200000;\n while (ng - ok > 1) {\n int mid = (ng + ok) / 2;\n reset();\n if (f(f, mid, 0, H, 0, W) >= g_count) {\n ok = mid;\n } else {\n ng = mid;\n }\n }\n\n print(g_count, S - (all_sum - ok));\n\n return true;\n}\nint main() {\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n while (solve())\n ;\n}\n\n////////////////////print/////////////////////////\n// 1次元ベクトルを出力する\ntemplate <typename T> void print(vector<T> A) {\n if (A.size() == 0) {\n return;\n }\n for (size_t i = 0; i < A.size() - 1; i++) {\n cout << A[i] << ' ';\n }\n cout << A[A.size() - 1] << endl;\n return;\n}\n\n// 2次元ベクトルを出力する\ntemplate <typename T> void print(vector<vector<T>> &F) {\n for (size_t i = 0; i < F.size(); i++) {\n for (size_t j = 0; j < F[i].size(); j++) {\n cout << F[i][j];\n if (j < F[i].size() - 1) {\n cout << ' ';\n }\n }\n cout << endl;\n }\n}\n\n// 空白行を出力するprint\nvoid print() { cout << endl; }\n\n// 数値・文字列を空白区切りで出力する. print(a,b)など\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n cout << head;\n if (sizeof...(tail) != 0)\n cout << \" \";\n print(forward<Tail>(tail)...);\n}\n\nvoid print(string S) { cout << S << endl; }\n\n/////////////////////初期化///////////////////////\n\ninline string input() {\n string S;\n cin >> S;\n return S;\n}\ninline ll I() {\n ll ret;\n cin >> ret;\n return ret;\n}\ninline pll II() {\n pll ret;\n cin >> ret.first >> ret.second;\n return ret;\n}\n\n//////////////出力関連\n\ninline void Yes(bool f) {\n if (f) {\n cout << \"Yes\" << endl;\n } else {\n cout << \"No\" << endl;\n }\n}", "accuracy": 1, "time_ms": 6710, "memory_kb": 10900, "score_of_the_acc": -0.9765, "final_rank": 18 }, { "submission_id": "aoj_1176_10529687", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\nusing vi = vector<int>;\nusing vll = vector<ll>;\nusing vvi = vector<vi>;\nusing vvll = vector<vll>;\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n#define FOR(i, a, b) for(ll i = a; i < (ll)(b); i++)\n#define all(a) (a).begin(),(a).end()\nconstexpr int INF = 1001001001;\nconstexpr ll LINF = 1001001001001001001ll;\nconstexpr int DX[] = {1, 0, -1, 0};\nconstexpr int DY[] = {0, 1, 0, -1};\n\nbool solve(){\n int h, w, s;\n cin >> h >> w >> s;\n if(h == 0) return false;\n vvi u(h+1, vi(w+1, 0));\n rep(i, h) rep(j, w) cin >> u[i+1][j+1];\n int sum = 0;\n rep(i, h) rep(j, w) sum += u[i+1][j+1];\n rep(i, h+1) rep(j, w) u[i][j+1] += u[i][j];\n rep(j, w+1) rep(i, h) u[i+1][j] += u[i][j]; \n int lb = sum - s;\n map<pair<P, P>, P> mp;\n auto f = [&](auto self, int si, int sj, int ti, int tj) -> P{\n if(mp.count({{si, sj}, {ti, tj}})) return mp[{{si, sj}, {ti, tj}}];\n int subsum = u[ti][tj] + u[si][sj] - u[ti][sj] - u[si][tj];\n if(subsum < lb) return {0, 0};\n P ret = {1, s - (sum - subsum)};\n for(int mi = si+1; mi < ti; mi++){\n P l = self(self, si, sj, mi, tj);\n P r = self(self, mi, sj, ti, tj);\n if(l.first == 0) continue;\n if(r.first == 0) continue;\n if(ret.first < l.first+r.first){\n ret = {l.first+r.first, min(l.second, r.second)};\n }\n else if(ret.first == l.first+r.first && ret.second < min(l.second, r.second)){\n ret = {l.first+r.first, min(l.second, r.second)};\n }\n }\n for(int mj = sj+1; mj < tj; mj++){\n P l = self(self, si, sj, ti, mj);\n P r = self(self, si, mj, ti, tj);\n if(l.first == 0) continue;\n if(r.first == 0) continue;\n if(ret.first < l.first+r.first){\n ret = {l.first+r.first, min(l.second, r.second)};\n }\n else if(ret.first == l.first+r.first && ret.second < min(l.second, r.second)){\n ret = {l.first+r.first, min(l.second, r.second)};\n }\n }\n return mp[{{si, sj}, {ti, tj}}] = ret;\n };\n auto ans = f(f, 0, 0, h, w);\n cout << ans.first << \" \" << ans.second << endl;\n return true;\n}\n\nint main(){\n while(solve());\n}", "accuracy": 1, "time_ms": 7080, "memory_kb": 20756, "score_of_the_acc": -1.2557, "final_rank": 20 }, { "submission_id": "aoj_1176_10463098", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing ull=unsigned long long;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define loop(n) for (int tjh = 0; tjh < (int)(n); tjh++)\n#define j0 jtmp0\n#define j1 jtmp1\nconstexpr int maxh=32;constexpr int mi=-1000'000;\nint h,w,s;\narray<array<int,maxh+1>,maxh+1>u;\narray<array<array<array<array<int,2>,maxh>,maxh>,maxh>,maxh>v;\nint p;array<int,2>t;\nsigned main() {\n cin.tie(0)->sync_with_stdio(0);\n cout<<fixed<<setprecision(16);\n for(;cin>>h>>w>>s,h;){\n rep(i,h)rep(j,w)cin>>u[i+1][j+1];\n rep(i,h+1)rep(j,w)u[i][j+1]+=u[i][j];\n rep(i,h)rep(j,w+1)u[i+1][j]+=u[i][j];\n s=u[h][w]-s;\n rep(k,h)rep(l,w)rep(i0,h-k)rep(j0,w-l){\n int i1=i0+k;int j1=j0+l;int i2=i1+1;int j2=j1+1;\n p=u[i2][j2]-u[i0][j2]-u[i2][j0]+u[i0][j0]-s;\n if(p<0){\n\tv[i0][i1][j0][j1]={mi,mi};\n\tcontinue;\n }\n v[i0][i1][j0][j1]={1,p};\n rep(i,i1-i0){\n\tt={\n\t v[i0][i0+i][j0][j1][0]+v[i0+i+1][i1][j0][j1][0],\n\t min(v[i0][i0+i][j0][j1][1],v[i0+i+1][i1][j0][j1][1])\n\t};\n\tif(v[i0][i1][j0][j1]<t)v[i0][i1][j0][j1]=t;\n }\n rep(i,j1-j0){\n\tt={\n\t v[i0][i1][j0][j0+i][0]+v[i0][i1][j0+i+1][j1][0],\n\t min(v[i0][i1][j0][j0+i][1],v[i0][i1][j0+i+1][j1][1])\n\t};\n\tif(v[i0][i1][j0][j1]<t)v[i0][i1][j0][j1]=t;\n }\n }\n cout<<v[0][h-1][0][w-1][0]<<' '<<v[0][h-1][0][w-1][1]<<'\\n';\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 11472, "score_of_the_acc": -0.0425, "final_rank": 2 }, { "submission_id": "aoj_1176_9910701", "code_snippet": "#include<bits/stdc++.h>\n// #include<atcoder/all>\n// #include<boost/multiprecision/cpp_int.hpp>\n\nusing namespace std;\n// using namespace atcoder;\n// using bint = boost::multiprecision::cpp_int;\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nusing P = pair<ll,ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing ve = vector<vector<int>>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\n#define rep(i,n) for(ll i = 0;i < (ll)n;i++)\n#define ALL(x) (x).begin(),(x).end()\n#define sz(c) ((ll)(c).size())\n#define LB(A,x) (int)(lower_bound(A.begin(),A.end(),x)-A.begin())\n#define UB(A,x) (int)(upper_bound(A.begin(),A.end(),x)-A.begin())\n// #define MOD 1000000007\n#define MOD 998244353\ntemplate<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T>ostream&operator<<(ostream&os,vector<T>&v){for(int i = 0;i < v.size();i++)os<<v[i]<<(i+1!=v.size()?\" \":\"\");return os;}\ntemplate<typename T>istream&operator>>(istream&is,vector<T>&v){for(T&in:v)is>>in;return is;}\ntemplate<typename T1,typename T2>ostream&operator<<(ostream&os,pair<T1,T2>&p){os<<p.first<<\" \"<<p.second;return os;}\ntemplate<typename T1,typename T2>istream&operator>>(istream&is,pair<T1,T2>&p){is>>p.first>>p.second;return is;}\ntemplate<typename T> inline bool chmax(T &a,T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> inline bool chmin(T &a,T b){if(a > b){a = b;return true;}return false;}\nld dist(ld x1,ld y1,ld x2, ld y2){return sqrtl((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));}\n\nconst ll inf = MOD;\n\nbool solve(){\n int h,w,S;cin >> h >> w >> S;\n if(!h)return false;\n vvi u(h,vi(w));\n rep(i,h)cin >> u[i];\n vvi rui(h+1,vi(w+1));\n rep(i,h)rep(j,w){\n rui[i+1][j+1] = rui[i+1][j] + rui[i][j+1] - rui[i][j] + u[i][j];\n }\n // l,r,u,d -> {group,max_juyo}\n map<tuple<int,int,int,int>,P> mem;\n // l r [)\n // u d [)\n auto calc = [&](int l,int r,int u,int d){\n return rui[d][r]-rui[d][l]-rui[u][r] + rui[u][l];\n };\n int tae = -S;// 各グループはtae以上\n rep(i,h)rep(j,w)tae += u[i][j];\n auto sub = [&](auto &sub,int l,int r,int u,int d)->P{\n if(mem.count(make_tuple(l,r,u,d)))return mem[make_tuple(l,r,u,d)];\n ll gr = 1,mn = calc(l,r,u,d);\n for(int m = l+1;m < r;m++){\n if(calc(l,m,u,d) >= tae && calc(m,r,u,d) >= tae){\n auto [g1,j1] = sub(sub,l,m,u,d);\n auto [g2,j2] = sub(sub,m,r,u,d);\n if(g1+g2 > gr){\n gr = g1+g2;mn = min(j1,j2);\n }else if(g1+g2 == gr)chmax(mn,min(j1,j2));\n }\n }\n for(int m = u+1;m < d;m++){\n if(calc(l,r,u,m) >= tae && calc(l,r,m,d) >= tae){\n auto [g1,j1] = sub(sub,l,r,u,m);\n auto [g2,j2] = sub(sub,l,r,m,d);\n if(g1+g2 > gr){\n gr = g1+g2;mn = min(j1,j2);\n }else if(g1+g2 == gr)chmax(mn,min(j1,j2));\n }\n }\n return mem[make_tuple(l,r,u,d)] = make_pair(gr,mn);\n };\n P res = sub(sub,0,w,0,h);\n res.second = S - (rui[h][w]-res.second);\n cout << res << \"\\n\";\n return true;\n}\n\nint main(){\n \n ios_base::sync_with_stdio(0), cin.tie(0);\n while(solve());\n \n\n return 0;\n}", "accuracy": 1, "time_ms": 4260, "memory_kb": 25148, "score_of_the_acc": -0.9531, "final_rank": 17 }, { "submission_id": "aoj_1176_9860630", "code_snippet": "#ifdef t9unkubj\n#include\"debug.cpp\"\n//#include\"template_no_debug.h\"\n#else \n#define dbg(...) 199958\n#endif\n\n#undef _GLIBCXX_DEBUG\n#pragma GCC optimize(\"O3\")\nusing namespace std;\n#include<bits/stdc++.h>\nusing ll=long long;\nusing ull=unsigned long long;\ntemplate<class T>using vc=vector<T>;\ntemplate<class T>using vvc=vc<vc<T>>;\n#define rep(i,n) for(ll i=0;i<(ll)(n);i++)\n#define REP(i,j,n) for(ll i=(j);i<(ll)(n);i++)\n#define DREP(i,n,m) for(ll i=(n);i>=(m);i--)\n#define drep(i,n) for(ll i=((n)-1);i>=0;i--)\n#define all(x) x.begin(),x.end()\n#define rall(x) x.rbegin(),x.rend()\ntemplate<class T,class F>\nbool chmin(T &x, F y){\n if(x>y){\n x=y;\n return true;\n }\n return false;\n}\ntemplate<class T, class F>\nbool chmax(T &x, F y){\n if(x<y){\n x=y;\n return true;\n }\n return false;\n}\ndouble pass_time=0;\nconst int N=33;\n//group 余り\npair<int,int> dp[N][N][N][N];\nint seen[N][N][N][N];\nvoid solve(){\nwhile(1){\n rep(i,N)rep(j,N)rep(k,N)rep(l,N)dp[i][j][k][l]={0,0},seen[i][j][k][l]=0;\n int h,w,s;\n cin>>h>>w>>s;\n if(h==0&&w==0&&s==0)break;\n vvc<int>u(h,vc<int>(w));\n int al=0;\n rep(i,h)rep(j,w)cin>>u[i][j],al+=u[i][j];\n vvc<int>pre(h+1,vc<int>(w+1));\n rep(i,h)rep(j,w)pre[i+1][j+1]=u[i][j];\n rep(i,h)rep(j,w+1)pre[i+1][j]+=pre[i][j];\n rep(i,h+1)rep(j,w)pre[i][j+1]+=pre[i][j];\n int least=al-s;\n //グループはleast以上\n auto dfs=[&](auto&dfs,int a,int b,int c,int d)->pair<int,int>{\n if(seen[a][b][c][d])return dp[a][b][c][d];\n seen[a][b][c][d]=1;\n dp[a][b][c][d]=make_pair(-1e5,-1);\n REP(i,a+1,b){\n auto p1=dfs(dfs,a,i,c,d);\n auto p2=dfs(dfs,i,b,c,d);\n chmax(dp[a][b][c][d],make_pair(p1.first+p2.first,min(p1.second,p2.second)));\n }\n REP(i,c+1,d){\n auto p1=dfs(dfs,a,b,c,i);\n auto p2=dfs(dfs,a,b,i,d);\n chmax(dp[a][b][c][d],make_pair(p1.first+p2.first,min(p1.second,p2.second)));\n }\n int thi=pre[b][d]-pre[b][c]-pre[a][d]+pre[a][c];\n if(thi>=least){\n chmax(dp[a][b][c][d],make_pair(1,thi-least));\n }\n \n return dp[a][b][c][d];\n };\n dfs(dfs,0,h,0,w);\n cout<<dp[0][h][0][w].first<<\" \"<<dp[0][h][0][w].second<<endl;\n}\n}\nsigned main(){\n#ifdef t9unkubj\nfreopen(\"input.txt\", \"r\", stdin);\nfreopen(\"output.txt\", \"w\", stdout);\n#endif\n cin.tie(0)->sync_with_stdio(0);\n pass_time=clock();\n int t=1;\n //cin>>t;\n while(t--)solve();\n pass_time=clock()-pass_time;\n dbg(pass_time/CLOCKS_PER_SEC);\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 17328, "score_of_the_acc": -0.187, "final_rank": 14 }, { "submission_id": "aoj_1176_9523045", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint N, M, S, X;\nint A[32][32];\npair<int,int> DP[33][33][33][33];\nbool memo[33][33][33][33];\n\npair<int,int> DFS(int LX, int RX, int LY, int RY) {\n if (memo[LX][RX][LY][RY]) return DP[LX][RX][LY][RY];\n int COUNT = 0;\n rep(i,LX,RX) rep(j,LY,RY) COUNT += A[i][j];\n if (COUNT < X) {\n memo[LX][RX][LY][RY] = true;\n return DP[LX][RX][LY][RY] = {-1,-1};\n }\n DP[LX][RX][LY][RY] = {1,COUNT-X};\n rep(MX,LX+1,RX) {\n pair<int,int> P1 = DFS(LX,MX,LY,RY), P2 = DFS(MX,RX,LY,RY);\n if (P1.first == -1 || P2.first == -1) continue;\n if (P1.first + P2.first > DP[LX][RX][LY][RY].first || (P1.first + P2.first == DP[LX][RX][LY][RY].first && min(P1.second, P2.second) > DP[LX][RX][LY][RY].second)) {\n DP[LX][RX][LY][RY] = {P1.first + P2.first, min(P1.second, P2.second)};\n }\n }\n rep(MY,LY+1,RY) {\n pair<int,int> P1 = DFS(LX,RX,LY,MY), P2 = DFS(LX,RX,MY,RY);\n if (P1.first + P2.first > DP[LX][RX][LY][RY].first || (P1.first + P2.first == DP[LX][RX][LY][RY].first && min(P1.second, P2.second) > DP[LX][RX][LY][RY].second)) {\n DP[LX][RX][LY][RY] = {P1.first + P2.first, min(P1.second, P2.second)};\n }\n }\n memo[LX][RX][LY][RY] = true;\n return DP[LX][RX][LY][RY];\n}\n\nint main() {\nwhile(1) {\n cin>> N >> M >> S;\n if (N == 0) return 0;\n rep(i,0,N+1) rep(j,0,N+1) rep(k,0,M+1) rep(l,0,M+1) memo[i][j][k][l] = false;\n int COUNT = 0;\n rep(i,0,N) rep(j,0,M) cin >> A[i][j], COUNT += A[i][j];\n X = COUNT - S;\n pair<int,int> ANS = DFS(0,N,0,M);\n cout << ANS.first << ' ' << ANS.second << endl;\n}\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 13640, "score_of_the_acc": -0.1109, "final_rank": 5 }, { "submission_id": "aoj_1176_9417248", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\n#define rep(i, a, b) for(ll i = a; i < b; ++i)\n#define rrep(i, a, b) for(ll i = a; i >= b; --i)\nconstexpr ll inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\ntemplate <typename T>\nstruct CumulativeSum2D {\n CumulativeSum2D(int H, int W)\n : h(H), w(W), data(H + 1, vector<T>(W + 1, 0)) {}\n void add(int i, int j, const T& x) {\n assert(0 <= i and i < h);\n assert(0 <= j and j < w);\n data[i + 1][j + 1] += x;\n }\n void init() {\n for(int i = 1; i < (int)data.size(); ++i) {\n for(int j = 1; j < (int)data[i].size(); ++j) {\n data[i][j] += data[i][j - 1] + data[i - 1][j] - data[i - 1][j - 1];\n }\n }\n }\n T sum(int li, int lj, int ri, int rj) {\n assert(0 <= li and li <= ri and ri <= h);\n assert(0 <= lj and lj <= rj and rj <= w);\n return data[ri][rj] - data[li][rj] - data[ri][lj] + data[li][lj];\n }\n T get(int i, int j) {\n assert(0 <= i and i < h);\n assert(0 <= j and j < w);\n return data[i + 1][j + 1] - data[i][j + 1] - data[i + 1][j] + data[i][j];\n }\n\n private:\n int h, w;\n vector<vector<T>> data;\n};\nint main(void) {\n while(true) {\n int h, w, s;\n cin >> h >> w >> s;\n if(h == 0 and w == 0 and s == 0) break;\n vector<vector<int>> u(h, vector<int>(w));\n CumulativeSum2D<int> cum(h, w);\n rep(i, 0, h) {\n rep(j, 0, w) {\n cin >> u[i][j];\n cum.add(i, j, u[i][j]);\n }\n }\n cum.init();\n int diff = cum.sum(0, 0, h, w) - s;\n vector<vector<vector<vector<pair<int, int>>>>> dp(h + 1, vector<vector<vector<pair<int, int>>>>(h + 1, vector<vector<pair<int, int>>>(w + 1, vector<pair<int, int>>(w + 1, {-1, -1}))));\n auto dfs = [&](auto& dfs, int li, int ri, int lj, int rj) -> pair<int, int> {\n if(dp[li][ri][lj][rj] != pair<int, int>{-1, -1}) return dp[li][ri][lj][rj];\n pair<int, int> res = {1, cum.sum(li, lj, ri, rj) - diff};\n rep(i, li + 1, ri) {\n if(cum.sum(li, lj, i, rj) >= diff and cum.sum(i, lj, ri, rj) >= diff) {\n pair<int, int> res1 = dfs(dfs, li, i, lj, rj);\n pair<int, int> res2 = dfs(dfs, i, ri, lj, rj);\n if(res1.first + res2.first > res.first) {\n res = {res1.first + res2.first, min(res1.second, res2.second)};\n } else if(res1.first + res2.first == res.first and min(res1.second, res2.second) > res.second) {\n res = {res1.first + res2.first, min(res1.second, res2.second)};\n }\n }\n }\n rep(j, lj + 1, rj) {\n if(cum.sum(li, lj, ri, j) >= diff and cum.sum(li, j, ri, rj) >= diff) {\n pair<int, int> res1 = dfs(dfs, li, ri, lj, j);\n pair<int, int> res2 = dfs(dfs, li, ri, j, rj);\n if(res1.first + res2.first > res.first) {\n res = {res1.first + res2.first, min(res1.second, res2.second)};\n } else if(res1.first + res2.first == res.first and min(res1.second, res2.second) > res.second) {\n res = {res1.first + res2.first, min(res1.second, res2.second)};\n }\n }\n }\n return dp[li][ri][lj][rj] = res;\n };\n pair<int, int> ans = dfs(dfs, 0, h, 0, w);\n cout << ans.first << ' ' << ans.second << '\\n';\n }\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 13996, "score_of_the_acc": -0.1248, "final_rank": 7 }, { "submission_id": "aoj_1176_9407376", "code_snippet": "#include<iostream>\nusing namespace std;\nconst int INF=1e9;\nconst pair<int,int>init_val=make_pair(-INF,-INF);\nint H,W,S,A[32][32];\nint sum;\npair<int,int>memo[33][33][33][33];\nbool vis[33][33][33][33];\nbool init()\n{\n cin>>H>>W>>S;\n if(H==0&&W==0&&S==0)return false;\n sum=0;\n for(int i=0;i<H;i++)for(int j=0;j<W;j++)cin>>A[i][j],sum+=A[i][j];\n for(int r1=0;r1<=H;r1++)for(int r2=0;r2<=H;r2++)\n {\n for(int c1=0;c1<=W;c1++)for(int c2=0;c2<=W;c2++)\n {\n vis[r1][r2][c1][c2]=false;\n memo[r1][r2][c1][c2]=init_val;\n }\n }\n return true;\n}\npair<int,int>dfs(int r1, int r2, int c1, int c2)\n{\n if(vis[r1][r2][c1][c2])return memo[r1][r2][c1][c2];\n vis[r1][r2][c1][c2]=true;\n int cur_sum=0;\n for(int i=r1;i<r2;i++)for(int j=c1;j<c2;j++)cur_sum+=A[i][j];\n if(sum-cur_sum>S)return init_val;\n memo[r1][r2][c1][c2]=make_pair(1,S-(sum-cur_sum));\n for(int i=r1+1;i<r2;i++)\n {\n auto[p1,p2]=dfs(r1,i,c1,c2);\n auto[q1,q2]=dfs(i,r2,c1,c2);\n memo[r1][r2][c1][c2]=max(memo[r1][r2][c1][c2],make_pair(p1+q1,min(p2,q2)));\n }\n for(int j=c1+1;j<c2;j++)\n {\n auto[p1,p2]=dfs(r1,r2,c1,j);\n auto[q1,q2]=dfs(r1,r2,j,c2);\n memo[r1][r2][c1][c2]=max(memo[r1][r2][c1][c2],make_pair(p1+q1,min(p2,q2)));\n }\n return memo[r1][r2][c1][c2];\n}\nbool solve()\n{\n if(!init())return false;\n auto[p1,p2]=dfs(0,H,0,W);\n cout<<p1<<' '<<p2<<endl;\n return true;\n}\nint main(){while(solve()){}}", "accuracy": 1, "time_ms": 220, "memory_kb": 13796, "score_of_the_acc": -0.1145, "final_rank": 6 }, { "submission_id": "aoj_1176_9290491", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, a, n) for (int i = a; i < n; i++)\n#define rrep(i, a, n) for (int i = a; i >= n; i--)\n#define inr(l, x, r) (l <= x && x < r)\n#define ll long long\n#define ld long double\n#define pii pair<int,int>\n\nconstexpr int IINF = 1001001001;\nconstexpr ll INF = 9e18;\n\ntemplate <class t, class u>\nvoid chmax(t& a, u b) {\n if (a < b) a = b;\n}\ntemplate <class t, class u>\nvoid chmin(t& a, u b) {\n if (b < a) a = b;\n}\n\nint main() {\n while(1){\n int h, w, s;cin >> h >> w >> s;\n if(h+w+s==0) return 0;\n vector<vector<int>> a(h, vector<int>(w));\n rep(i, 0, h)rep(j, 0, w) cin >> a[i][j];\n vector<vector<int>> sum(h+1, vector<int>(w+1,0));\n rep(i, 0, h){\n rep(j, 0, w){\n sum[i+1][j+1] = a[i][j]+sum[i+1][j]+sum[i][j+1]-sum[i][j]; \n }\n }\n // [u, d), [l, r)\n auto calcsum = [&](int u, int d, int l, int r)->int{\n return sum[d][r]-sum[d][l]-sum[u][r]+sum[u][l];\n };\n vector<vector<vector<vector<pii>>>> dp(h,vector<vector<vector<pii>>>(h+1,vector<vector<pii>>(w,vector<pii>(w+1,{-1,-1}))));\n int total = sum[h][w];\n\n rep(hw, 1, h+1)rep(ww, 1, w+1)rep(u, 0, h)rep(l, 0, w){\n int d = u+hw, r = l + ww;\n if(d > h || r > w) continue;\n if(total-calcsum(u, d, l, r)<=s) dp[u][d][l][r] = {1,s-total+calcsum(u, d, l, r)};\n rep(mid, u+1, d){\n pii udp = dp[u][mid][l][r], ddp = dp[mid][d][l][r];\n if(udp.first == -1 || ddp.first == -1) continue;\n chmax(dp[u][d][l][r],make_pair(udp.first+ddp.first,min(udp.second,ddp.second)));\n }\n rep(mid, l+1, r){\n pii ldp = dp[u][d][l][mid], rdp = dp[u][d][mid][r];\n if(ldp.first == -1 || rdp.first == -1) continue;\n chmax(dp[u][d][l][r],make_pair(ldp.first+rdp.first,min(ldp.second,rdp.second)));\n }\n }\n\n pii ans = dp[0][h][0][w];\n cout << ans.first << ' ' << ans.second << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 13252, "score_of_the_acc": -0.0934, "final_rank": 4 }, { "submission_id": "aoj_1176_9238107", "code_snippet": "#include <bits/stdc++.h>\n\nstd::ostream& operator<<(std::ostream& os, const std::pair<int, int>& P) {\n std::cout << '(' << P.first << ',' << P.second << ')';\n return os;\n}\n\n// 特殊な演算に注意\nstd::pair<int, int> operator+(const std::pair<int, int>& L, const std::pair<int, int>& R) {\n return std::pair<int, int>{ L.first + R.first, std::max(L.second, R.second) };\n}\n\nvoid chmax(std::pair<int, int>& L, const std::pair<int, int>& R) {\n if (L.first < R.first) L = R;\n else if (L.first == R.first and L.second > R.second) L = R;\n}\n\nbool solve() {\n int H, W, S;\n std::cin >> H >> W >> S;\n if (H == 0 and W == 0 and S == 0) return false;\n std::vector U(H, std::vector<int>(W));\n for (auto& u : U) {\n for (auto& x : u) std::cin >> x;\n }\n std::vector sum(H + 1, std::vector<int>(W + 1));\n for (int i{1} ; i <= H ; i++) {\n for (int j{1} ; j <= W ; j++) {\n sum[i][j] = sum[i - 1][j] + sum[i][j - 1] - sum[i - 1][j - 1] + U[i - 1][j - 1];\n }\n }\n auto query{[&](int l, int r, int u, int d) -> int {\n assert(0 <= l and l < r and r <= H);\n assert(0 <= u and u < d and d <= W);\n return sum[r][d] - sum[r][u] - sum[l][d] + sum[l][u];\n }};\n int all{sum[H][W]};\n std::vector dp(H + 1, std::vector(H + 1, std::vector(W + 1, std::vector<std::pair<int, int>>(W + 1, std::pair<int, int>(-1, -1)))));\n const std::pair<int, int> INVALID{-100, -100};\n auto rec{[&](auto rec, int l, int r, int u, int d) -> std::pair<int, int> {\n //std::cout << \"call \" << l << ' ' << r << ' ' << u << ' ' << d << std::endl;\n std::pair<int, int>& key{dp[l][r][u][d]};\n if (key != std::pair<int, int>{-1, -1}) return key;\n if (all - query(l, r, u, d) > S) {\n return key = INVALID;\n }\n key = std::pair{ 1, (all - query(l, r, u, d)) };\n for (int mid{l + 1} ; mid < r ; mid++) {\n auto front{rec(rec, l, mid, u, d)};\n auto back{rec(rec, mid, r, u, d)};\n if (front == INVALID or back == INVALID) continue;\n auto combined{front + back};\n chmax(key, combined);\n }\n for (int mid{u + 1} ; mid < d ; mid++) {\n auto front{rec(rec, l, r, u, mid)};\n auto back{rec(rec, l, r, mid, d)};\n if (front == INVALID or back == INVALID) continue;\n auto combined{front + back};\n chmax(key, combined);\n }\n //std::cout << l << ' ' << r << ' ' << u << ' ' << d << \" is \" << key << std::endl;\n return key;\n }};\n auto ans{rec(rec, 0, H, 0, W)};\n std::cout << ans.first << ' ' << S - ans.second << '\\n';\n return true;\n}\n\nint main() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n while (solve()) ;\n}", "accuracy": 1, "time_ms": 340, "memory_kb": 14032, "score_of_the_acc": -0.1371, "final_rank": 12 }, { "submission_id": "aoj_1176_9153328", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n// #pragma GCC target(\"avx2\")\n// #pragma GCC optimize(\"O3\")\n// #pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = 3.141592653589793;\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\ntemplate<typename T> void view(const vv<T>& vv){ for(const auto& v : vv){ view(v); } }\n\npair<int, int> solve(int H, int W, int S){\n vvi U(H, vi (W)); rep(i, H) rep(j, W) cin >> U[i][j];\n vv<vv<pair<int, int>>> memo(H, vvv<pair<int, int>>(W, vv<pair<int, int>>(H + 1, vc<pair<int, int>>(W + 1, {-1, -1}))));\n vvi cmsm(H + 1, vi(W + 1, 0));\n rep(i, H) rep(j, W) cmsm[i + 1][j + 1] = U[i][j] + cmsm[i + 1][j] + cmsm[i][j + 1] - cmsm[i][j];\n int sm = cmsm[H][W];\n function<pair<int, int>(int, int, int, int)> dp = [&](int x1, int y1, int x2, int y2) -> pair<int, int>{\n if (memo[x1][y1][x2][y2].first != -1) return memo[x1][y1][x2][y2];\n int p = S - (sm - (cmsm[x2][y2] - cmsm[x1][y2] - cmsm[x2][y1] + cmsm[x1][y1]));\n if (p < 0) return {-1, -1};\n int div = 1;\n for (int h = x1 + 1; h < x2; h++){\n auto [d1, p1] = dp(x1, y1, h, y2);\n auto [d2, p2] = dp(h, y1, x2, y2);\n if (d1 == -1 || d2 == -1) continue;\n if (div < d1 + d2){\n div = d1 + d2;\n p = min(p1, p2);\n }else if (div == d1 + d2) p = max(p, min(p1, p2));\n }\n for (int w = y1 + 1; w < y2; w++){\n auto [d1, p1] = dp(x1, y1, x2, w);\n auto [d2, p2] = dp(x1, w, x2, y2);\n if (d1 == -1 || d2 == -1) continue;\n if (div < d1 + d2){\n div = d1 + d2;\n p = min(p1, p2);\n }else if (div == d1 + d2) p = max(p, min(p1, p2));\n }\n return memo[x1][y1][x2][y2] = {div, p};\n };\n return dp(0, 0, H, W);\n}\n\nint main(){\n vc<pair<int, int>> ans;\n while (true){\n int H, W, S; cin >> H >> W >> S;\n if (H == 0) break;\n ans.push_back(solve(H, W, S));\n }\n for (auto x : ans) cout << x.first << \" \" << x.second << endl;\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 13332, "score_of_the_acc": -0.1296, "final_rank": 8 }, { "submission_id": "aoj_1176_8661395", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int, int> pi;\nint h, w, s, wa, u[33][33];\npi memo[33][33][33][33];\nint rui(int y1, int x1, int y2, int x2){\n return u[y2][x2]-u[y1-1][x2]-u[y2][x1-1]+u[y1-1][x1-1];\n}\npi dp(int y1, int x1, int y2, int x2){\n if(memo[y1][x1][y2][x2].first!=-1) return memo[y1][x1][y2][x2];\n pi res = pi(1, s-(wa-rui(y1, x1, y2, x2)));\n for(int i=x1;i<x2;i++){\n if(wa-rui(y1, x1, y2, i)>s || wa-rui(y1, i+1, y2, x2)>s) continue;\n pi p1 = dp(y1, x1, y2, i);\n pi p2 = dp(y1, i+1, y2, x2);\n res = max(res, pi(p1.first+p2.first, min(p1.second, p2.second)));\n }\n for(int i=y1;i<y2;i++){\n if(wa-rui(y1, x1, i, x2)>s || wa-rui(i+1, x1, y2, x2)>s) continue;\n pi p1 = dp(y1, x1, i, x2);\n pi p2 = dp(i+1, x1, y2, x2);\n res = max(res, pi(p1.first+p2.first, min(p1.second,p2.second)));\n }\n return memo[y1][x1][y2][x2] = res;\n}\nint main(){\n while(cin >> h >> w >> s, h){\n memset(u, 0, sizeof(u));\n for(int i=1;i<=h;i++){\n for(int j=1;j<=w;j++){\n cin >> u[i][j];\n u[i][j] += u[i-1][j]+u[i][j-1]-u[i-1][j-1];\n }\n }\n wa = u[h][w];\n fill_n(***memo, 33*33*33*33, pi(-1, -1));\n pi ans = dp(1, 1, h, w);\n cout << ans.first << \" \" << ans.second << endl;\n }\n return(0);\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 12344, "score_of_the_acc": -0.0811, "final_rank": 3 }, { "submission_id": "aoj_1176_8026680", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nstruct Sum2D {\n int h;\n int w;\n vector<vector<int>> sum;\n\n Sum2D(const vector<vector<int>>& vec) : h(vec.size()), w(vec.front().size()) {\n sum.resize(h + 1, vector<int>(w + 1));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n sum[i + 1][j + 1] = vec[i][j];\n }\n }\n\n for (int i = 0; i <= h; i++) {\n for (int j = 0; j < w; j++) {\n sum[i][j + 1] += sum[i][j];\n }\n }\n for (int i = 0; i < h; i++) {\n for (int j = 0; j <= w; j++) {\n sum[i + 1][j] += sum[i][j];\n }\n }\n }\n \n int get(int si, int sj, int ti, int tj) const {\n return sum[ti][tj] + sum[si][sj] - sum[ti][sj] - sum[si][tj];\n }\n};\n\nstruct Data {\n int size = -1;\n int power = -1;\n Data() = default;\n Data(int size, int power) : size(size), power(power) {}\n};\n\nbool operator<(const Data& lhs, const Data& rhs) {\n if (lhs.size == rhs.size) {\n return lhs.power < rhs.power;\n } else {\n return lhs.size < rhs.size;\n }\n}\n\nbool operator>(const Data& lhs, const Data& rhs) {\n if (lhs.size == rhs.size) {\n return lhs.power > rhs.power;\n } else {\n return lhs.size > rhs.size;\n }\n}\n\nbool operator==(const Data& lhs, const Data& rhs) {\n return lhs.size == rhs.size && lhs.power == rhs.power;\n}\n\nbool operator!=(const Data& lhs, const Data& rhs) {\n return !(lhs == rhs);\n}\n\nData operator+(const Data& lhs, const Data& rhs) {\n return Data(lhs.size + rhs.size, min(lhs.power, rhs.power));\n}\n\nbool solve() {\n int h, w, s;\n cin >> h >> w >> s;\n if (h == 0) return false;\n vector<vector<int>> u(h, vector<int>(w));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n cin >> u[i][j];\n }\n }\n Sum2D sum(u);\n int e = sum.get(0, 0, h, w);\n// cerr << e << '\\n';\n// return 0;\n \n vector dp(h + 1, vector<vector<vector<Data>>>(w + 1, vector<vector<Data>>(h + 1, vector<Data>(w + 1))));\n Data init;\n auto dfs = [&](auto dfs, int si, int sj, int ti, int tj) -> Data {\n if (dp[si][sj][ti][tj] != init) return dp[si][sj][ti][tj];\n if (e - sum.get(si, sj, ti, tj) > s) {\n return dp[si][sj][ti][tj] = init;\n }\n Data res(1, s - (e - sum.get(si, sj, ti, tj)));\n for (int i = si + 1; i < ti; i++) {\n Data data1 = dfs(dfs, si, sj, i, tj);\n Data data2 = dfs(dfs, i, sj, ti, tj);\n if (data1 == init || data2 == init) continue;\n res = max(res, data1 + data2);\n }\n for (int j = sj + 1; j < tj; j++) {\n Data data1 = dfs(dfs, si, sj, ti, j);\n Data data2 = dfs(dfs, si, j, ti, tj);\n if (data1 == init || data2 == init) continue;\n res = max(res, data1 + data2);\n }\n return dp[si][sj][ti][tj] = res;\n };\n auto [sz, power] = dfs(dfs, 0, 0, h, w);\n cout << sz << ' ' << power << '\\n';\n return true;\n}\n\nint main() {\n while (solve());\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 13956, "score_of_the_acc": -0.1382, "final_rank": 13 }, { "submission_id": "aoj_1176_8026287", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\ntemplate <typename T>\nclass CumlativeSum2D {\n private:\n const int h, w;\n std::vector<std::vector<T>> data;\n bool is_build = false;\n\n public:\n CumlativeSum2D(const std::vector<std::vector<T>> &vec) : h(vec.size()), w(vec.front().size()) {\n data.resize(h + 2, std::vector<T>(w + 2, 0));\n for (int i = 0 ; i < h ; i++) {\n for (int j = 0 ; j < w ; j++) {\n data[i + 1][j + 1] = vec[i][j];\n }\n }\n }\n\n void build() {\n assert(!is_build);\n for (int i = 0 ; i < h ; i++) {\n for (int j = 0 ; j < w ; j++) {\n data[i + 1][j + 1] += data[i][j + 1] + data[i + 1][j] - data[i][j];\n }\n }\n is_build = true;\n }\n\n T get_sum(const int i1, const int j1, const int i2, const int j2) {\n assert(0 <= i1 && i1 < h && 0 <= j1 && j1 < w);\n assert(0 <= i2 && i2 <= h && 0 <= j2 && j2 <= w);\n assert(i1 <= i2 && j1 <= j2);\n assert(is_build);\n return data[i2][j2] + data[i1][j1] - data[i2][j1] - data[i1][j2];\n }\n};\n\nstruct info {\n int part, yobi;\n bool can;\n info() : part(-1), yobi(-1), can(false) {}\n info(int p, int y, bool c) : part(p), yobi(y), can(c) {}\n};\n\nbool solve() {\n int h, w, s; cin >> h >> w >> s;\n if (h == 0) return false;\n\n vector A(h, vector<int>(w));\n for (auto& a : A) for (auto& x : a) cin >> x;\n\n CumlativeSum2D S(A);\n S.build();\n\n int allsum = S.get_sum(0, 0, h, w);\n\n vector dp(h + 1, vector(h + 1, vector(w + 1, vector(w + 1, info()))));\n vector used(h + 1, vector(h + 1, vector(w + 1, vector(w + 1, false)))); \n\n auto rec = [&](auto rec, int y1, int y2, int x1, int x2) -> info {\n if (used[y1][y2][x1][x2]) return dp[y1][y2][x1][x2];\n used[y1][y2][x1][x2] = true;\n\n info& res = dp[y1][y2][x1][x2];\n\n if (allsum - S.get_sum(y1, x1, y2, x2) > s) return res = info();\n\n int part = 1;\n int yobi = s - (allsum - S.get_sum(y1, x1, y2, x2));\n assert(yobi >= 0);\n\n for (int m = y1 + 1 ; m < y2 ; m++) {\n info top = rec(rec, y1, m, x1, x2);\n info down = rec(rec, m, y2, x1, x2);\n if (!top.can or !down.can) continue;\n if (part < top.part + down.part) {\n part = top.part + down.part;\n yobi = min(top.yobi, down.yobi);\n }\n else if (part == top.part + down.part) {\n yobi = max(yobi, min(top.yobi, down.yobi));\n }\n }\n\n for (int m = x1 + 1 ; m < x2 ; m++) {\n info top = rec(rec, y1, y2, x1, m);\n info down = rec(rec, y1, y2, m, x2);\n if (!top.can or !down.can) continue;\n if (part < top.part + down.part) {\n part = top.part + down.part;\n yobi = min(top.yobi, down.yobi);\n }\n else if (part == top.part + down.part) {\n yobi = max(yobi, min(top.yobi, down.yobi));\n }\n }\n\n return res = info(part, yobi, true);\n };\n\n info ans = rec(rec, 0, h, 0, w);\n\n cout << ans.part << ' ' << ans.yobi << endl;\n\n return true;\n}\n\nint main() {\n while (solve()) ;\n}", "accuracy": 1, "time_ms": 460, "memory_kb": 21188, "score_of_the_acc": -0.3185, "final_rank": 15 } ]
aoj_1178_cpp
A Broken Door There is a rectangular maze consisting of a number of square rooms arranged in grid. The maze is surrounded by walls except for its entry and exit. The entry to the maze is at the leftmost part of the upper side of the rectangular area, that is, the upper side of the uppermost leftmost room of the maze is open. The exit is located at the rightmost part of the lower side, likewise. There is a wall between each pair of vertically or horizontally adjacent rooms. Such a wall has either a door with a card key lock, or no door at all. If you insert a card to a door, the door opens and you can pass the door. The opened door will close immediately, and the inserted card won't return. You can open any door with any card. You cannot go through a wall that has no door. When a maze map is given, you can easily determine how many cards are needed to pass through the maze from the entry to the exit. In the maze in Figure G-1, you can pass through it with ten cards, following the path represented by the green arrows ( ) in Figure G-2. Figure G-1: A map of a maze Figure G-2: One of the shortest paths Now, you are informed that one of the doors is broken and can't be passed. But you don't know which door is broken. If you insert a card to a broken door, the inserted card immediately returns. However, you can't tell a broken door from a working door just by its appearance. Figure G-3: A maze that potentially can't be passed through If the door marked with a red X ( ) in Figure G-3 is broken, you have no way to pass through the maze from the entry to the exit. However, you can pass the maze in Figure G-1 whichever door is broken. When you intend to follow the shortest path in Figure G-2, and find that the door marked with a red X in Figure G-4 is broken, you might follow the path represented as green arrows. In this case, you need twenty cards. Figure G-4: A maze with a broken door However, you can pass through the maze with less cards. You should follow the path in Figure G-5, until you find the broken door. The path is not the shortest path because it needs twelve cards at least. After you've found a broken door on the path, you should follow the shortest path to the exit that doesn't use the broken door. With this strategy, you can pass the maze with sixteen cards whichever door is broken. Figure G-6 shows one of the worst cases of this strategy; it needs sixteen cards. Figure G-5: The path before you find the broken door Figure G-6: One of the worst cases of the strategy You are requested to write a program that prints the minimum number of cards to pass the maze whichever door is broken. Input The input consists of one or more datasets, each of which represents a maze. The number of datasets is no more than 100. The first line of a dataset contains two integer numbers, the height h and the width w of the rectangular maze, in this order. You may assume that 2 ≤ h, w ≤ 30. The following 2 × h − 1 lines of a dataset describe whether there are doo ...(truncated)
[ { "submission_id": "aoj_1178_10946388", "code_snippet": "#include<cstring>\n#include<cstdio>\n#include<algorithm>\nusing namespace std;\nint n, m, bak, cl, qx[909], qy[909], dis[33][33], pas[77][77], x, y, dx[4], dy[4], mn[33][33], ans[77][77][2];\nint main()\n{\n\tdx[0] = -1; dy[0] = 0;\n\tdx[1] = 0; dy[1] = -1;\n\tdx[2] = +1; dy[2] = 0;\n\tdx[3] = 0; dy[3] = +1;\n\t\tfor(;;)\n\t{\n\tfor(int i = 0; i < 77; i++) for(int j = 0; j < 77; j++) pas[i][j] = 1;\n\t\tscanf(\"%d%d\", &n, &m);\n\t\tif(!n or !m)\n\t\t\tbreak;\n\t\t//printf(\"%d %d\\n\", n, m);\n\t\tfor(int i = 1; i <= 2 * n - 1; i++)\n\t\t{\n\t\t\tif(i & 1)\n\t\t\t{\n\t\t\t\tfor(int j = 1; j < m; j++)\n\t\t\t\t{\n\t\t\t\t\tscanf(\"%d\", &pas[i + 1][j * 2 + 1]);\n\t\t\t\t}\n\t\t\t}else\n\t\t\t{\n\t\t\t\tfor(int j = 1; j <= m; j++)\n\t\t\t\t{\n\t\t\t\t\tscanf(\"%d\", &pas[i + 1][j * 2]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tbool flag = true;\n\t\tfor(int i = 2; i <= 2 * n; i++) for(int j = 2; j <= 2 * m; j++) if(i % 2 == 1 xor j % 2 == 1)\n\t\t{\n\t\t\t//\tprintf(\"%d %d\\n\", i,j);\n\t\t\tbak = pas[i][j];\n\t\t\tpas[i][j] = 1;\n\n\t\t\tqx[cl = 1] = n;\n\t\t\tqy[1] = m;\n\t\t\tfor(int i1 = 1; i1 <= n; i1++) for(int j1 = 1; j1 <= m; j1++) dis[i1][j1] = -1;\n\t\t\tdis[n][m] = 0;\n\t\t\tfor(int op = 1; op <= cl; op++)\n\t\t\t{\n\t\t\t//\tprintf(\"%d\\n\", op);\n\t\t\t\tx = qx[op]; y = qy[op];\n\t\t\t\tfor(int d = 0; d < 4; d++)\n\t\t\t\t{\n\t\t\t\t//\tprintf(\"%d %d\\n\", x + dx[d], y + dy[d]);\n\t\t\t\t\tif(!pas[2 * x + dx[d]][2 * y + dy[d]] and dis[x + dx[d]][y + dy[d]] == -1)\n\t\t\t\t\t{\n\t\t\t\t\t\tdis[x + dx[d]][y + dy[d]] = dis[x][y] + 1;\n\t\t\t\t\t\tqx[++cl] = x + dx[d];\n\t\t\t\t\t\tqy[cl] = y + dy[d];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(dis[1][1] == -1) {flag = false; break;}\n\t\t\tans[i][j][0] = dis[i / 2][j / 2];\n\t\t\tans[i][j][1] = dis[(i + 1) / 2][(j + 1) / 2];\n\t\t//\tprintf(\"ans[%d][%d][%d] = %d, ans[%d][%d][%d] = %d, \\n\", i, j,0, ans[i][j][0], i, j, 1, ans[i][j][1]);\n\t\t\tpas[i][j] = bak;\n\t\t}\n\t\tif(!flag) {printf(\"-1\\n\"); continue;}\n\t\tfor(int i = 1; i <= n; i++) for(int j = 1; j <= m; j++) mn[i][j] = 0x3fffffff;\n\t\tmn[n][m] = 0;\n\t\tqx[cl = 1] = n;\n\t\tqy[1] = m;\n\t\tfor(int op = 1; op <= cl; op++)\n\t\t{\n\t\t\tx = qx[op]; y = qy[op];\n\t\t\tfor(int d = 0; d < 4; d++)if(!pas[x * 2 + dx[d]][y * 2 + dy[d]])\n\t\t\t{\n\t\t\t\tint tmp = max(1 + mn[x][y], ans[x * 2 + dx[d]][y * 2 + dy[d]][(dx[d] + dy[d]) == 1?1:0]);\n\t\t\t\t//printf(\"%d %d %d\\n\", x, y, tmp);\n\t\t\t\tif(mn[x + dx[d]][y + dy[d]] > tmp)\n\t\t\t\t{\n\t\t\t\t\tmn[x + dx[d]][y + dy[d]] = tmp;\n\t\t\t\t\tqx[++cl] = x + dx[d];\n\t\t\t\t\tqy[cl] = y + dy[d];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\", mn[1][1]);\n\t}\n\tfclose(stdin);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 3052, "score_of_the_acc": -0.0588, "final_rank": 1 }, { "submission_id": "aoj_1178_9861764", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n/**\n * @brief template\n */\n\nint dx[4] = {0,1,0,-1}, dy[4] = {1,0,-1,0};\n\nint main() {\nwhile(1) {\n int N, M;\n cin >> N >> M;\n if (N == 0 && M == 0) return 0;\n vector B(N, vector(M, vector<bool>(4,false)));\n rep(i,0,N-1) {\n rep(j,0,M-1) {\n int A;\n cin >> A;\n if (A == 0) {\n B[i][j][0] = true;\n B[i][j+1][2] = true;\n }\n }\n rep(j,0,M) {\n int A;\n cin >> A;\n if (A == 0) {\n B[i][j][1] = true;\n B[i+1][j][3] = true;\n }\n }\n }\n rep(j,0,M-1) {\n int A;\n cin >> A;\n if (A == 0) {\n B[N-1][j][0] = true;\n B[N-1][j+1][2] = true;\n }\n }\n vector Dist(N, vector(M, vector<int>(4,inf)));\n auto getDist = [&](int SX, int SY) -> int {\n vector D(N, vector<int>(M, inf));\n queue<pair<int,int>> Q;\n Q.push({SX,SY});\n D[SX][SY] = 0;\n while(!Q.empty()) {\n auto [X, Y] = Q.front();\n Q.pop();\n rep(i,0,4) {\n if (!B[X][Y][i]) continue;\n int NX = X + dx[i], NY = Y + dy[i];\n if (chmin(D[NX][NY], D[X][Y] + 1)) {\n Q.push({NX,NY});\n }\n }\n }\n return D[N-1][M-1];\n };\n rep(i,0,N) {\n rep(j,0,M) {\n rep(k,0,4) {\n if (!B[i][j][k]) continue;\n B[i][j][k] = false;\n Dist[i][j][k] = getDist(i,j);\n B[i][j][k] = true;\n }\n }\n }\n vector ANS(N, vector<int>(M, inf));\n ANS[N-1][M-1] = 0;\n int Time = N * M * 3;\n while(Time--) {\n rep(i,0,N) {\n rep(j,0,M) {\n rep(k,0,4) {\n if (!B[i][j][k]) continue;\n int ni = i + dx[k], nj = j + dy[k];\n chmin(ANS[i][j], max(ANS[ni][nj]+1, Dist[i][j][k]));\n }\n }\n }\n }\n cout << (ANS[0][0] == inf ? -1 : ANS[0][0]) << endl;\n}\n}", "accuracy": 1, "time_ms": 720, "memory_kb": 3592, "score_of_the_acc": -0.5735, "final_rank": 12 }, { "submission_id": "aoj_1178_9374261", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\n#define rep(i,n) for(ll i=0;i<n;i++)\n#define all(A) A.begin(),A.end()\n\n\nvll dx = { 1,0,-1,0 };\nvll dy = { 0,-1,0,1 };\n\nvoid solve(ll H, ll W) {\n vector<vll> G(H, vll(W, 0));\n rep(i, 2 * H - 1) {\n if (i % 2 == 1) {\n rep(w, W) {\n ll a;\n cin >> a;\n if (a == 0) {\n G[i / 2][w] += 8;\n G[i / 2 + 1][w] += 2;\n }\n }\n }\n else {\n rep(w, W - 1) {\n ll a;\n cin >> a;\n if (a == 0) {\n G[i / 2][w] += 1;\n G[i / 2][w + 1] += 4;\n }\n }\n }\n }\n vector<vll> WD(H, vll(W, 0));\n rep(h, H)rep(w, W)rep(e, 4) {\n vector<vll> dis(H, vll(W, 1e18)); dis[h][w] = 0;\n queue<pair<ll, ll>> Q;\n Q.push({ h,w });\n while (!Q.empty()) {\n ll y = Q.front().first;\n ll x = Q.front().second;\n Q.pop();\n ll nd = dis[y][x];\n rep(d, 4) {\n ll ny = y + dy[d];\n ll nx = x + dx[d];\n if (ny < 0 || nx < 0 || ny >= H || nx >= W)continue;\n if (y == h && x == w && d == e)continue;\n if (G[y][x] & (1 << d)) {\n if (dis[ny][nx] > nd + 1) {\n dis[ny][nx] = nd + 1;\n Q.push({ ny,nx });\n }\n }\n }\n }\n WD[h][w] = max(WD[h][w], dis[H - 1][W - 1]);\n }\n ll L = 0, R = 1e18;\n while (R - L > 1) {\n ll M = (R + L) / 2;\n if (WD[0][0] > M) {\n L = M;\n continue;\n }\n queue<pair<ll, ll>> Q;\n Q.push({ 0,0 });\n vector<vector<bool>> seen(H, vector<bool>(W, 0));\n vector<vll> dis(H, vll(W, 1e18));\n dis[0][0] = 0;\n while (!Q.empty()) {\n ll y = Q.front().first;\n ll x = Q.front().second;\n Q.pop();\n if (seen[y][x])continue;\n seen[y][x] = 1;\n rep(d, 4) {\n if (G[y][x] & (1 << d)) {\n ll ny = y + dy[d];\n ll nx = x + dx[d];\n if (dis[ny][nx] > dis[y][x] + 1) {\n dis[ny][nx] = dis[y][x] + 1;\n if (dis[ny][nx] + WD[ny][nx] <= M) {\n Q.push({ ny,nx });\n }\n }\n }\n }\n }\n (seen[H - 1][W - 1] ? R : L) = M;\n }\n cout << (R < 1e17 ? R : -1) << endl;\n\n}\n\nint main() {\n\n ll H, W;\n while (cin >> H >> W) {\n if (H == 0)return 0;\n solve(H, W);\n }\n}", "accuracy": 1, "time_ms": 1290, "memory_kb": 3436, "score_of_the_acc": -1.0373, "final_rank": 17 }, { "submission_id": "aoj_1178_9250650", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nbool is_end = false;\n\n// 2\n// 3 * 1\n// 0\nint dx[4] = {1, 0, -1, 0};\nint dy[4] = {0, 1, 0, -1};\n\n\nvoid solve()\n{\n int H, W; cin >> H >> W;\n if (H == 0 && W == 0)\n {\n is_end = true;\n return;\n }\n \n vector<vector<int>> pair_to_num(H, vector<int>(W));\n vector<pair<int, int>> num_to_pair(H * W);\n for (int i = 0; i < H; ++i)\n {\n for (int j = 0; j < W; ++j)\n {\n pair_to_num[i][j] = i * W + j;\n num_to_pair[i * W + j] = {i, j};\n }\n }\n \n vector<vector<int>> graph(H * W, vector<int>(4, -1));\n for (int i = 0; i < 2 * H - 1; ++i)\n {\n if (i % 2 == 0)\n {\n for (int j = 0; j < W - 1; ++j)\n {\n int left = pair_to_num[i/2][j];\n int right = pair_to_num[i/2][j+1];\n \n int c; cin >> c;\n if (c == 0)\n {\n graph[left][1] = right;\n graph[right][3] = left;\n }\n \n }\n }\n else\n {\n for (int j = 0; j < W; ++j)\n {\n int up = pair_to_num[i/2][j];\n int down = pair_to_num[i/2+1][j];\n \n int c; cin >> c;\n if (c == 0)\n {\n graph[up][0] = down;\n graph[down][2] = up;\n }\n \n }\n }\n \n }\n \n int S = 0, T = H * W - 1;\n const int INF = 1e9;\n vector<vector<int>> dist_to_T(H * W, vector<int>(4, INF));\n \n for (int x = 0; x < H; ++x)\n {\n for (int y = 0; y < W; ++y)\n {\n for (int dir = 0; dir < 4; ++dir)\n {\n int v = pair_to_num[x][y];\n int nv = graph[v][dir];\n \n if (nv == -1) continue;\n \n {\n vector<int> dist(H * W, INF);\n queue<int> que;\n \n que.push(v);\n dist[v] = 0;\n \n while (!que.empty())\n {\n int u = que.front();\n que.pop();\n \n for (auto nu : graph[u])\n {\n if (nu == -1) continue;\n if (dist[nu] < INF) continue;\n if (u == v && nu == nv) continue;\n dist[nu] = dist[u] + 1;\n que.push(nu);\n }\n }\n \n \n dist_to_T[v][dir] = dist[T];\n \n // cout << x << \" \" << y << \" \" << dir << \" \" << dist_to_T[v][dir] << endl;\n }\n \n }\n }\n }\n \n // for (int dir = 0; dir < 4; ++dir)\n // {\n // cout << dir << \" \" << dist_to_T[0][dir] << endl;\n // }\n \n int ok = INF, ng = 0;\n while (abs(ok - ng) > 1)\n {\n int mid = (ok + ng) / 2;\n \n {\n vector<int> dist(H * W, INF);\n queue<int> que;\n \n que.push(S);\n dist[S] = 0;\n \n while (!que.empty())\n {\n int v = que.front();\n que.pop();\n \n for (int dir = 0; dir < 4; ++dir)\n {\n int nv = graph[v][dir];\n if (nv == -1) continue;\n if (dist[nv] < INF) continue;\n \n int sum = dist[v] + dist_to_T[v][dir];\n if (sum <= mid)\n {\n // if (v == 0 && dir == 0) cout << sum << \" \" << mid << endl;\n dist[nv] = dist[v] + 1;\n que.push(nv);\n }\n }\n }\n \n if (dist[T] < INF) ok = mid;\n else ng = mid;\n }\n \n }\n \n if (ok == INF) ok = -1;\n cout << ok << endl;\n \n \n return;\n}\n\nint main()\n{\n while (!is_end)\n {\n solve();\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 3320, "score_of_the_acc": -0.2361, "final_rank": 4 }, { "submission_id": "aoj_1178_9250640", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nbool is_end = false;\n\n// 2\n// 3 * 1\n// 0\nint dx[4] = {1, 0, -1, 0};\nint dy[4] = {0, 1, 0, -1};\n\n\nvoid solve()\n{\n int H, W; cin >> H >> W;\n if (H == 0 && W == 0)\n {\n is_end = true;\n return;\n }\n \n vector<vector<int>> pair_to_num(H, vector<int>(W));\n vector<pair<int, int>> num_to_pair(H * W);\n for (int i = 0; i < H; ++i)\n {\n for (int j = 0; j < W; ++j)\n {\n pair_to_num[i][j] = i * W + j;\n num_to_pair[i * W + j] = {i, j};\n }\n }\n \n vector<vector<int>> graph(H * W, vector<int>(4, -1));\n for (int i = 0; i < 2 * H - 1; ++i)\n {\n if (i % 2 == 0)\n {\n for (int j = 0; j < W - 1; ++j)\n {\n int left = pair_to_num[i/2][j];\n int right = pair_to_num[i/2][j+1];\n \n int c; cin >> c;\n if (c == 0)\n {\n graph[left][1] = right;\n graph[right][3] = left;\n }\n \n }\n }\n else\n {\n for (int j = 0; j < W; ++j)\n {\n int up = pair_to_num[i/2][j];\n int down = pair_to_num[i/2+1][j];\n \n int c; cin >> c;\n if (c == 0)\n {\n graph[up][0] = down;\n graph[down][2] = up;\n }\n \n }\n }\n \n }\n \n int S = 0, T = H * W - 1;\n const int INF = 1e9;\n vector<vector<int>> dist_to_T(H * W, vector<int>(4, INF));\n \n vector<int> dist(H * W, INF);\n queue<int> que;\n \n for (int x = 0; x < H; ++x)\n {\n for (int y = 0; y < W; ++y)\n {\n for (int dir = 0; dir < 4; ++dir)\n {\n int v = pair_to_num[x][y];\n int nv = graph[v][dir];\n \n if (nv == -1) continue;\n \n {\n dist.assign(H * W, INF);\n assert((int)que.size() == 0);\n \n que.push(v);\n dist[v] = 0;\n \n while (!que.empty())\n {\n int u = que.front();\n que.pop();\n \n for (auto nu : graph[u])\n {\n if (nu == -1) continue;\n if (dist[nu] < INF) continue;\n if (u == v && nu == nv) continue;\n dist[nu] = dist[u] + 1;\n que.push(nu);\n }\n }\n \n \n dist_to_T[v][dir] = dist[T];\n \n // cout << x << \" \" << y << \" \" << dir << \" \" << dist_to_T[v][dir] << endl;\n }\n \n }\n }\n }\n \n // for (int dir = 0; dir < 4; ++dir)\n // {\n // cout << dir << \" \" << dist_to_T[0][dir] << endl;\n // }\n \n int ok = INF, ng = 0;\n while (abs(ok - ng) > 1)\n {\n int mid = (ok + ng) / 2;\n \n {\n dist.assign(H * W, INF);\n assert((int)que.size() == 0);\n \n que.push(S);\n dist[S] = 0;\n \n while (!que.empty())\n {\n int v = que.front();\n que.pop();\n \n for (int dir = 0; dir < 4; ++dir)\n {\n int nv = graph[v][dir];\n if (nv == -1) continue;\n if (dist[nv] < INF) continue;\n \n int sum = dist[v] + dist_to_T[v][dir];\n if (sum <= mid)\n {\n // if (v == 0 && dir == 0) cout << sum << \" \" << mid << endl;\n dist[nv] = dist[v] + 1;\n que.push(nv);\n }\n }\n }\n \n if (dist[T] < INF) ok = mid;\n else ng = mid;\n }\n \n }\n \n if (ok == INF) ok = -1;\n cout << ok << endl;\n \n \n return;\n}\n\nint main()\n{\n while (!is_end)\n {\n solve();\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 3496, "score_of_the_acc": -0.2364, "final_rank": 5 }, { "submission_id": "aoj_1178_7984594", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<math.h>\n#include<iomanip>\n#include<algorithm>\n#include<set>\n#include<map>\n#include<queue>\n#include<stack>\n// #include<atcoder/all>\n\nusing namespace std;\n// using namespace atcoder;\nusing ll = long long;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n\nint main(){\n\twhile (true){\n\t\tint h, w;\n\t\tcin >> h >> w;\n\t\tif (h == 0 && w == 0) {\n\t\t\tbreak;\n\t\t}\n\t\tvector<vector<pii>> graph(h * w, vector<pii>(0));\n\t\tvector<pii> edges(0);\n\t\tint cnt = 0;\n\t\tfor (size_t i = 0; i < h; i++)\n\t\t{\n\t\t\tfor (size_t j = 0; j < w - 1; j++)\n\t\t\t{\n\t\t\t\tint x;\n\t\t\t\tcin >> x;\n\t\t\t\tif (x == 0) {\n\t\t\t\t\tedges.push_back(pii(i * w + j, i * w + (j + 1)));\n\t\t\t\t\tgraph[i * w + j].push_back(pii(i * w + (j + 1), cnt));\n\t\t\t\t\tedges.push_back(pii(i * w + (j + 1), i * w + j));\n\t\t\t\t\tgraph[i * w + (j + 1)].push_back(pii((i * w + j), cnt));\n\t\t\t\t\tcnt++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (i == h - 1) continue;\n\t\t\tfor (size_t j = 0; j < w; j++)\n\t\t\t{\n\t\t\t\tint x;\n\t\t\t\tcin >> x;\n\t\t\t\tif (x == 0) {\n\t\t\t\t\tedges.push_back(pii(i * w + j, (i + 1) * w + j));\n\t\t\t\t\tgraph[i * w + j].push_back(pii((i + 1) * w + j, cnt));\n\t\t\t\t\tedges.push_back(pii((i + 1) * w + j, i * w + j));\n\t\t\t\t\tgraph[(i + 1) * w + j].push_back(pii(i * w + j, cnt));\n\t\t\t\t\tcnt++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<vector<int>> dist_rem(cnt, vector<int>(h * w, 1000000000));\n\t\tfor (size_t i = 0; i < cnt; i++)\n\t\t{\n\t\t\tdist_rem[i][h * w - 1] = 0;\n\t\t}\n\t\t\n\t\tfor (size_t i = 0; i < cnt; i++)\n\t\t{\n\t\t\tqueue<int> q2;\n\t\t\tq2.push(h * w - 1);\n\t\t\twhile (q2.size() > 0) {\n\t\t\t\tint cur = q2.front();\n\t\t\t\tq2.pop();\n\t\t\t\tfor (auto _next: graph[cur]) {\n\t\t\t\t\tif (_next.second == i) continue;\n\t\t\t\t\tint next = _next.first;\n\t\t\t\t\tif (dist_rem[i][next] <= dist_rem[i][cur] + 1) continue;\n\t\t\t\t\tdist_rem[i][next] = dist_rem[i][cur] + 1;\n\t\t\t\t\tq2.push(next);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint ok = 1000000000;\n\t\tint ng = 0;\n\t\twhile (ok - ng > 1) {\n\t\t\tint mid = ng + (ok - ng) / 2;\n\t\t\t\n\t\t\tvector<int> dist_real(h * w, 1000000000);\n\t\t\tdist_real[0] = 0;\n\t\t\tqueue<int> q3;\n\t\t\tq3.push(0);\n\t\t\twhile (q3.size() > 0) {\n\t\t\t\tint cur = q3.front();\n\t\t\t\tq3.pop();\n\t\t\t\tfor (auto _next: graph[cur]) {\n\t\t\t\t\tint next = _next.first;\n\t\t\t\t\tint next_edge = _next.second;\n\t\t\t\t\tif (dist_real[next] <= dist_real[cur] + 1) continue;\n\t\t\t\t\tif (dist_real[cur] + dist_rem[next_edge][cur] > mid) continue;\n\t\t\t\t\tdist_real[next] = dist_real[cur] + 1;\n\t\t\t\t\tq3.push(next);\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif (dist_real[h * w - 1] <= mid) ok = mid;\n\t\t\telse ng = mid;\n\t\t}\n\t\tif (ok == 1000000000) {\n\t\t\tcout << -1 << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << ok << endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 9352, "score_of_the_acc": -0.6292, "final_rank": 14 }, { "submission_id": "aoj_1178_7984571", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<math.h>\n#include<iomanip>\n#include<algorithm>\n#include<set>\n#include<map>\n#include<queue>\n#include<stack>\n// #include<atcoder/all>\n\nusing namespace std;\n// using namespace atcoder;\nusing ll = long long;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n\nint main(){\n\twhile (true){\n\t\tint h, w;\n\t\tcin >> h >> w;\n\t\tif (h == 0 && w == 0) {\n\t\t\tbreak;\n\t\t}\n\t\tvector<vector<pii>> graph(h * w, vector<pii>(0));\n\t\tvector<pii> edges(0);\n\t\tint cnt = 0;\n\t\tfor (size_t i = 0; i < h; i++)\n\t\t{\n\t\t\tfor (size_t j = 0; j < w - 1; j++)\n\t\t\t{\n\t\t\t\tint x;\n\t\t\t\tcin >> x;\n\t\t\t\tif (x == 0) {\n\t\t\t\t\tedges.push_back(pii(i * w + j, i * w + (j + 1)));\n\t\t\t\t\tgraph[i * w + j].push_back(pii(i * w + (j + 1), cnt));\n\t\t\t\t\tedges.push_back(pii(i * w + (j + 1), i * w + j));\n\t\t\t\t\tgraph[i * w + (j + 1)].push_back(pii((i * w + j), cnt));\n\t\t\t\t\tcnt++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (i == h - 1) continue;\n\t\t\tfor (size_t j = 0; j < w; j++)\n\t\t\t{\n\t\t\t\tint x;\n\t\t\t\tcin >> x;\n\t\t\t\tif (x == 0) {\n\t\t\t\t\tedges.push_back(pii(i * w + j, (i + 1) * w + j));\n\t\t\t\t\tgraph[i * w + j].push_back(pii((i + 1) * w + j, cnt));\n\t\t\t\t\tedges.push_back(pii((i + 1) * w + j, i * w + j));\n\t\t\t\t\tgraph[(i + 1) * w + j].push_back(pii(i * w + j, cnt));\n\t\t\t\t\tcnt++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<int> dist(h * w, 1000000000);\n\t\tdist[0] = 0;\n\t\tvector<vector<int>> dist_rem(cnt, vector<int>(h * w, 1000000000));\n\t\tfor (size_t i = 0; i < cnt; i++)\n\t\t{\n\t\t\tdist_rem[i][h * w - 1] = 0;\n\t\t}\n\t\t\n\t\tqueue<int> q;\n\t\tq.push(0);\n\t\twhile (q.size() > 0) {\n\t\t\tint cur = q.front();\n\t\t\tq.pop();\n\t\t\tfor (auto _next: graph[cur]) {\n\t\t\t\tint next = _next.first;\n\t\t\t\tif (dist[next] <= dist[cur] + 1) continue;\n\t\t\t\tdist[next] = dist[cur] + 1;\n\t\t\t\tq.push(next);\n\t\t\t}\n\t\t}\n\t\tfor (size_t i = 0; i < cnt; i++)\n\t\t{\n\t\t\tqueue<int> q2;\n\t\t\tq2.push(h * w - 1);\n\t\t\twhile (q2.size() > 0) {\n\t\t\t\tint cur = q2.front();\n\t\t\t\tq2.pop();\n\t\t\t\tfor (auto _next: graph[cur]) {\n\t\t\t\t\tif (_next.second == i) continue;\n\t\t\t\t\tint next = _next.first;\n\t\t\t\t\tif (dist_rem[i][next] <= dist_rem[i][cur] + 1) continue;\n\t\t\t\t\tdist_rem[i][next] = dist_rem[i][cur] + 1;\n\t\t\t\t\tq2.push(next);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint ok = 1000000000;\n\t\tint ng = 0;\n\t\twhile (ok - ng > 1) {\n\t\t\tint mid = ng + (ok - ng) / 2;\n\t\t\t\n\t\t\tvector<int> dist_real(h * w, 1000000000);\n\t\t\tdist_real[0] = 0;\n\t\t\tqueue<int> q3;\n\t\t\tq3.push(0);\n\t\t\twhile (q3.size() > 0) {\n\t\t\t\tint cur = q3.front();\n\t\t\t\tq3.pop();\n\t\t\t\tfor (auto _next: graph[cur]) {\n\t\t\t\t\tint next = _next.first;\n\t\t\t\t\tint next_edge = _next.second;\n\t\t\t\t\tif (dist_real[next] <= dist_real[cur] + 1) continue;\n\t\t\t\t\tif (dist_real[cur] + dist_rem[next_edge][cur] > mid) continue;\n\t\t\t\t\tdist_real[next] = dist_real[cur] + 1;\n\t\t\t\t\tq3.push(next);\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif (dist_real[h * w - 1] <= mid) ok = mid;\n\t\t\telse ng = mid;\n\t\t}\n\t\tif (ok == 1000000000) {\n\t\t\tcout << -1 << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << ok << endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 9304, "score_of_the_acc": -0.6077, "final_rank": 13 }, { "submission_id": "aoj_1178_7118735", "code_snippet": "#line 1 \"a.cpp\"\n// cSpell:disable\n/*\tauthor: Kite_kuma\n\tcreated: 2022.11.22 14:09:21 */\n\n#line 2 \"SPJ-Library/graph/graph.hpp\"\n#include <algorithm>\n#include <cassert>\n#include <deque>\n#include <iostream>\n#include <limits>\n#include <queue>\n#include <tuple>\n#include <vector>\n\ntemplate <class cost_type = long long>\nclass graph {\n public:\n\tstruct edge {\n\t public:\n\t\tint from, to;\n\t\tcost_type cost;\n\t\tint id;\n\t\tedge() = default;\n\t\tedge(int from_, int to_, cost_type cost_ = 1, int id_ = -1) : from(from_), to(to_), cost(cost_), id(id_) {}\n\t\tbool operator<(const edge &a) const { return cost < a.cost; }\n\t\tbool operator>(const edge &a) const { return cost > a.cost; }\n\t\tfriend std::ostream &operator<<(std::ostream &s, const edge &a) {\n\t\t\ts << '(' << a.from << \" -> \" << a.to << \"), cost: \" << a.cost << \", id: \" << a.id;\n\t\t\treturn s;\n\t\t}\n\t};\n\n private:\n\tstd::vector<std::vector<edge>> edges;\n\tint next_edge_id = 0;\n\n public:\n\tinline const std::vector<edge> &operator[](int k) const { return edges[k]; }\n\tinline std::vector<edge> &operator[](int k) { return edges[k]; }\n\n\tint size() const { return int(edges.size()); }\n\tvoid resize(const int n) { edges.resize(n); }\n\tint edge_count() const { return next_edge_id; }\n\n\tfriend std::ostream &operator<<(std::ostream &s, const graph<cost_type> &g) {\n\t\ts << \"{\\n\";\n\t\tfor(const auto &adj : g.edges)\n\t\t\tfor(const auto &ed : adj) s << '\\t' << ed << '\\n';\n\t\ts << \"}\";\n\t\treturn s;\n\t}\n\n\tgraph() = default;\n\tgraph(int n) : edges(n) {}\n\tgraph(int n, int e, bool weight = 0, bool directed = 0, int idx = 1) : edges(n) { input(e, weight, directed, idx); }\n\tstatic constexpr cost_type INF = std::numeric_limits<cost_type>::max() / 3;\n\n\tvoid input(int e = -1, bool weight = false, bool directed = false, int idx = 1) {\n\t\tif(e == -1) e = size() - 1;\n\t\twhile(e--) {\n\t\t\tint u, v;\n\t\t\tstd::cin >> u >> v;\n\t\t\tcost_type cost = 1;\n\t\t\tif(weight) std::cin >> cost;\n\t\t\tadd_edge(u, v, cost, directed, idx);\n\t\t}\n\t}\n\n\tinline int add_edge(int u, int v, cost_type cost = 1, bool directed = false, int idx = 0) {\n\t\tu -= idx, v -= idx;\n\t\tedges[u].emplace_back(u, v, cost, next_edge_id);\n\t\tif(!directed && u != v) edges[v].emplace_back(v, u, cost, next_edge_id);\n\t\treturn next_edge_id++;\n\t}\n\n\t// Ο(V+E)\n\tstd::vector<cost_type> bfs(int s) const {\n\t\tstd::vector<cost_type> dist(size(), INF);\n\t\tstd::queue<int> que;\n\t\tdist[s] = 0;\n\t\tque.push(s);\n\t\twhile(!que.empty()) {\n\t\t\tint v = que.front();\n\t\t\tque.pop();\n\t\t\tfor(auto &e : edges[v]) {\n\t\t\t\tif(dist[e.to] != INF) continue;\n\t\t\t\tdist[e.to] = dist[v] + e.cost;\n\t\t\t\tque.push(e.to);\n\t\t\t}\n\t\t}\n\t\treturn dist;\n\t}\n\n\t// Ο(V+E)\n\t// constraint: cost of each edge is zero or x (>= 0)\n\tstd::vector<cost_type> zero_one_bfs(int s) const {\n\t\tstd::vector<cost_type> dist(size(), INF);\n\t\tstd::deque<int> deq;\n\t\tdist[s] = 0;\n\t\tdeq.push_back(s);\n\t\twhile(!deq.empty()) {\n\t\t\tint v = deq.front();\n\t\t\tdeq.pop_front();\n\t\t\tfor(auto &e : edges[v]) {\n\t\t\t\tif(dist[e.to] > dist[v] + e.cost) {\n\t\t\t\t\tdist[e.to] = dist[v] + e.cost;\n\t\t\t\t\te.cost ? deq.push_back(e.to) : deq.push_front(e.to);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn dist;\n\t}\n\n\t// Ο((E+V) lg E)\n\t// unreachable: INF\n\tstd::vector<cost_type> dijkstra(int s) const {\n\t\tstd::vector<cost_type> dist(size(), INF);\n\t\tconst auto compare = [](const std::pair<cost_type, int> &a, const std::pair<cost_type, int> &b) { return a.first > b.first; };\n\t\tstd::priority_queue<std::pair<cost_type, int>, std::vector<std::pair<cost_type, int>>, decltype(compare)> que{compare};\n\t\tdist[s] = 0;\n\t\tque.emplace(0, s);\n\t\twhile(!que.empty()) {\n\t\t\tstd::pair<cost_type, int> p = que.top();\n\t\t\tque.pop();\n\t\t\tint v = p.second;\n\t\t\tif(dist[v] < p.first) continue;\n\t\t\tfor(auto &e : edges[v]) {\n\t\t\t\tif(dist[e.to] > dist[v] + e.cost) {\n\t\t\t\t\tdist[e.to] = dist[v] + e.cost;\n\t\t\t\t\tque.emplace(dist[e.to], e.to);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn dist;\n\t}\n\n\t// Ο(VE)\n\t// unreachable: INF\n\t// reachable via negative cycle: -INF\n\tstd::vector<cost_type> bellman_ford(int s) const {\n\t\tint n = size();\n\t\tstd::vector<cost_type> res(n, INF);\n\t\tres[s] = 0;\n\t\tfor(int loop = 0; loop < n - 1; loop++) {\n\t\t\tfor(int v = 0; v < n; v++) {\n\t\t\t\tif(res[v] == INF) continue;\n\t\t\t\tfor(auto &e : edges[v]) {\n\t\t\t\t\tres[e.to] = std::min(res[e.to], res[v] + e.cost);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tstd::queue<int> que;\n\t\tstd::vector<int> chk(n);\n\t\tfor(int v = 0; v < n; v++) {\n\t\t\tif(res[v] == INF) continue;\n\t\t\tfor(auto &e : edges[v]) {\n\t\t\t\tif(res[e.to] > res[v] + e.cost and !chk[e.to]) {\n\t\t\t\t\tque.push(e.to);\n\t\t\t\t\tchk[e.to] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\twhile(!que.empty()) {\n\t\t\tint now = que.front();\n\t\t\tque.pop();\n\t\t\tfor(auto &e : edges[now]) {\n\t\t\t\tif(!chk[e.to]) {\n\t\t\t\t\tchk[e.to] = 1;\n\t\t\t\t\tque.push(e.to);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int i = 0; i < n; i++)\n\t\t\tif(chk[i]) res[i] = -INF;\n\t\treturn res;\n\t}\n\n\t// Ο(V^3)\n\tstd::vector<std::vector<cost_type>> warshall_floyd() const {\n\t\tconst int n = size();\n\t\tstd::vector<std::vector<cost_type>> dist(n, std::vector<cost_type>(n, INF));\n\t\tfor(int i = 0; i < n; i++) dist[i][i] = 0;\n\t\tfor(int i = 0; i < n; i++)\n\t\t\tfor(auto &e : edges[i]) dist[i][e.to] = std::min(dist[i][e.to], e.cost);\n\t\tfor(int k = 0; k < n; k++)\n\t\t\tfor(int i = 0; i < n; i++) {\n\t\t\t\tif(dist[i][k] == INF) continue;\n\t\t\t\tfor(int j = 0; j < n; j++) {\n\t\t\t\t\tif(dist[k][j] == INF) continue;\n\t\t\t\t\tdist[i][j] = std::min(dist[i][j], dist[i][k] + dist[k][j]);\n\t\t\t\t}\n\t\t\t}\n\t\treturn dist;\n\t}\n\n\t// Ο(V) (using DFS)\n\t// if a cycle exists, return {}\n\tstd::vector<int> topological_sort() const {\n\t\tstd::vector<int> res;\n\t\tstd::vector<int> used(size(), 0);\n\t\tbool not_DAG = false;\n\t\tauto dfs = [&](auto self, int k) -> void {\n\t\t\tif(not_DAG) return;\n\t\t\tif(used[k]) {\n\t\t\t\tif(used[k] == 1) not_DAG = true;\n\t\t\t\treturn;\n\t\t\t}\n\t\t\tused[k] = 1;\n\t\t\tfor(auto &e : edges[k]) self(self, e.to);\n\t\t\tused[k] = 2;\n\t\t\tres.push_back(k);\n\t\t};\n\t\tfor(int i = 0; i < size(); i++) dfs(dfs, i);\n\t\tif(not_DAG) return std::vector<int>{};\n\t\tstd::reverse(res.begin(), res.end());\n\t\treturn res;\n\t}\n\n\tbool is_dag() const { return !topological_sort().empty(); }\n\n\t// Ο(V)\n\t// array of the distance to the most distant vertex\n\t// constraint: the graph is a tree\n\tstd::vector<cost_type> height() const {\n\t\tauto vec1 = bfs(0);\n\t\tint v1 = -1, v2 = -1;\n\t\tcost_type dia = -1;\n\t\tfor(int i = 0; i < int(size()); i++)\n\t\t\tif(dia < vec1[i]) dia = vec1[i], v1 = i;\n\t\tvec1 = bfs(v1);\n\t\tdia = -1;\n\t\tfor(int i = 0; i < int(size()); i++)\n\t\t\tif(dia < vec1[i]) dia = vec1[i], v2 = i;\n\t\tauto vec2 = bfs(v2);\n\t\tfor(int i = 0; i < int(size()); i++) {\n\t\t\tif(vec1[i] < vec2[i]) vec1[i] = vec2[i];\n\t\t}\n\t\treturn vec1;\n\t}\n\n\t// O(V+E)\n\t// vector<(int)(0 or 1)>\n\t// if it is not bipartite, return {}\n\tstd::vector<int> bipartite_grouping() const {\n\t\tstd::vector<int> colors(size(), -1);\n\t\tauto dfs = [&](auto self, int now, int col) -> bool {\n\t\t\tcolors[now] = col;\n\t\t\tfor(auto &e : edges[now]) {\n\t\t\t\tif(col == colors[e.to]) return false;\n\t\t\t\tif(colors[e.to] == -1 and !self(self, e.to, !col)) return false;\n\t\t\t}\n\t\t\treturn true;\n\t\t};\n\t\tfor(int i = 0; i < int(size()); i++)\n\t\t\tif(colors[i] == -1 and !dfs(dfs, i, 0)) return std::vector<int>{};\n\t\treturn colors;\n\t}\n\n\tbool is_bipartite() const { return !bipartite_grouping().empty(); }\n\n\t// Ο(V+E)\n\t// (v1, v2, diameter)\n\tstd::tuple<int, int, cost_type> diameter() {\n\t\tstd::vector<cost_type> dist = bfs(0);\n\t\tauto it = std::max_element(dist.begin(), dist.end());\n\t\tconst int v = int(it - dist.begin());\n\t\tdist = bfs(v);\n\t\tit = std::max_element(dist.begin(), dist.end());\n\t\treturn std::make_tuple(v, int(it - dist.begin()), *it);\n\t}\n\n\t// Ο(V+E)\n\tstd::vector<int> subtree_size(const int root) {\n\t\tconst int n = size();\n\t\tstd::vector<int> ret(n, 1);\n\t\tauto dfs = [&](auto self, int now, int p = -1) -> void {\n\t\t\tfor(const auto &e : (*this)[now]) {\n\t\t\t\tif(e.to == p) continue;\n\t\t\t\tself(self, e.to, now);\n\t\t\t\tret[now] += ret[e.to];\n\t\t\t}\n\t\t};\n\t\tdfs(dfs, root);\n\t\treturn ret;\n\t}\n\n\t// Ο(ElgE)\n\tcost_type prim() const {\n\t\tcost_type res = 0;\n\t\tstd::priority_queue<edge, std::vector<edge>, std::greater<edge>> que;\n\t\tfor(auto &e : edges[0]) que.push(e);\n\t\tstd::vector<int> chk(size());\n\t\tchk[0] = 1;\n\t\tint cnt = 1;\n\t\twhile(cnt < size()) {\n\t\t\tauto e = que.top();\n\t\t\tque.pop();\n\t\t\tif(chk[e.to]) continue;\n\t\t\tcnt++;\n\t\t\tres += e.cost;\n\t\t\tchk[e.to] = 1;\n\t\t\tfor(auto &e2 : edges[e.to]) que.push(e2);\n\t\t}\n\t\treturn res;\n\t}\n\n\t// Ο(ElgE)\n\tcost_type kruskal() const {\n\t\tstd::vector<std::tuple<int, int, cost_type>> eds;\n\t\tfor(const auto &adj : edges)\n\t\t\tfor(const auto &ed : adj) eds.emplace_back(ed.from, ed.to, ed.cost);\n\t\tstd::sort(eds.begin(), eds.end(), [](const std::tuple<int, int, cost_type> &a, const std::tuple<int, int, cost_type> &b) {\n\t\t\treturn std::get<2>(a) < std::get<2>(b);\n\t\t});\n\t\tstd::vector<int> uf_data(size(), -1);\n\t\tauto root = [&uf_data](auto self, int x) -> int {\n\t\t\tif(uf_data[x] < 0) return x;\n\t\t\treturn uf_data[x] = self(self, uf_data[x]);\n\t\t};\n\t\tauto unite = [&uf_data, &root](int u, int v) -> bool {\n\t\t\tu = root(root, u), v = root(root, v);\n\t\t\tif(u == v) return false;\n\t\t\tif(uf_data[u] > uf_data[v]) std::swap(u, v);\n\t\t\tuf_data[u] += uf_data[v];\n\t\t\tuf_data[v] = u;\n\t\t\treturn true;\n\t\t};\n\t\tcost_type ret = 0;\n\t\tfor(auto &e : eds)\n\t\t\tif(unite(std::get<0>(e), std::get<1>(e))) ret += std::get<2>(e);\n\t\treturn ret;\n\t}\n\n\t// O(V)\n\tstd::vector<int> centroid() const {\n\t\tstd::vector<int> centroid, sz(size());\n\t\tauto dfs = [&](auto self, int now, int per) -> void {\n\t\t\tsz[now] = 1;\n\t\t\tbool is_centroid = true;\n\t\t\tfor(auto &e : edges[now]) {\n\t\t\t\tif(e.to != per) {\n\t\t\t\t\tself(self, e.to, now);\n\t\t\t\t\tsz[now] += sz[e.to];\n\t\t\t\t\tif(sz[e.to] > size() / 2) is_centroid = false;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(size() - sz[now] > size() / 2) is_centroid = false;\n\t\t\tif(is_centroid) centroid.push_back(now);\n\t\t};\n\t\tdfs(dfs, 0, -1);\n\t\treturn centroid;\n\t}\n\n\t// O(V+E)\n\t// bridge: (s, t) (s < t);\n\tstd::pair<std::vector<std::pair<int, int>>, std::vector<int>> bridges_and_articulations() const {\n\t\tstd::vector<int> order(size(), -1), low(size()), articulation;\n\t\tint order_next = 0;\n\t\tstd::vector<std::pair<int, int>> bridge;\n\t\tauto dfs = [&](auto self, int now, int par = -1) -> void {\n\t\t\tlow[now] = order[now] = order_next++;\n\t\t\tbool is_articulation = false;\n\t\t\tint cnt = 0;\n\t\t\tfor(auto &ed : edges[now]) {\n\t\t\t\tint &nxt = ed.to;\n\t\t\t\tif(nxt == par) continue;\n\t\t\t\tif(order[nxt] == -1) {\n\t\t\t\t\tcnt++;\n\t\t\t\t\tself(self, nxt, now);\n\t\t\t\t\tif(order[now] < low[nxt]) bridge.push_back(std::minmax(now, nxt));\n\t\t\t\t\tif(order[now] <= low[nxt]) is_articulation = true;\n\t\t\t\t\tlow[now] = std::min(low[now], low[nxt]);\n\t\t\t\t} else if(order[now] > order[nxt]) {\n\t\t\t\t\tlow[now] = std::min(low[now], order[nxt]);\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(par == -1 and cnt < 2) is_articulation = false;\n\t\t\tif(is_articulation) articulation.push_back(now);\n\t\t\treturn;\n\t\t};\n\t\tfor(int i = 0; i < (int)size(); i++)\n\t\t\tif(order[i] == -1) dfs(dfs, i);\n\t\treturn std::make_pair(bridge, articulation);\n\t}\n\n\t// Ο(V+E)\n\t// directed graph from root to leaf\n\tgraph root_to_leaf(int root = 0) const {\n\t\tgraph res(size());\n\t\tstd::vector<int> chk(size(), 0);\n\t\tchk[root] = 1;\n\t\tauto dfs = [&](auto self, int now) -> void {\n\t\t\tfor(auto &e : edges[now]) {\n\t\t\t\tif(chk[e.to] == 1) continue;\n\t\t\t\tchk[e.to] = 1;\n\t\t\t\tres.add_edge(now, e.to, e.cost, 1, 0);\n\t\t\t\tself(self, e.to);\n\t\t\t}\n\t\t};\n\t\tdfs(dfs, root);\n\t\treturn res;\n\t}\n\n\t// Ο(V+E)\n\t// directed graph from leaf to root\n\tgraph leaf_to_root(int root = 0) const {\n\t\tgraph res(size());\n\t\tstd::vector<int> chk(size(), 0);\n\t\tchk[root] = 1;\n\t\tauto dfs = [&](auto self, int now) -> void {\n\t\t\tfor(auto &e : edges[now]) {\n\t\t\t\tif(chk[e.to] == 1) continue;\n\t\t\t\tchk[e.to] = 1;\n\t\t\t\tres.add_edge(e.to, now, e.cost, 1, 0);\n\t\t\t\tself(self, e.to);\n\t\t\t}\n\t\t};\n\t\tdfs(dfs, root);\n\t\treturn res;\n\t}\n};\n#line 2 \"SPJ-Library/template/kuma.hpp\"\n\n#line 2 \"SPJ-Library/template/basic_func.hpp\"\n\n#line 7 \"SPJ-Library/template/basic_func.hpp\"\n\ntemplate <class T0, class T1, class T2>\ninline bool in_range(T0 x, T1 lef, T2 rig) {\n\treturn ((lef <= x) && (x < rig));\n}\n\ntemplate <class T>\ninline bool chmin(T &a, T b) {\n\tif(a > b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\ntemplate <class T>\ninline bool chmax(T &a, T b) {\n\tif(a < b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\n\nvoid Yes(bool flag = true) { std::cout << (flag ? \"Yes\" : \"No\") << '\\n'; }\nvoid YES(bool flag = true) { std::cout << (flag ? \"YES\" : \"NO\") << '\\n'; }\n\ntemplate <class T>\nvoid drop(T answer) {\n\tstd::cout << answer << '\\n';\n\texit(0);\n}\n\ntemplate <class T>\nvoid vout(std::vector<T> const &v, bool vertically = 0) {\n\tif(vertically) {\n\t\tfor(auto const &a : v) {\n\t\t\tstd::cout << a << '\\n';\n\t\t}\n\t\treturn;\n\t}\n\tfor(auto it = v.begin(); it != v.end(); it++) {\n\t\tstd::cout << (*it);\n\t\tif(it != v.end() - 1) {\n\t\t\tstd::cout << ' ';\n\t\t}\n\t}\n\tstd::cout << '\\n';\n\treturn;\n}\n\ninline void print() { std::cout << '\\n'; }\ntemplate <class T>\ninline void print(const T &x) {\n\tstd::cout << x << '\\n';\n\treturn;\n}\ntemplate <typename Head, typename... Tail>\nvoid print(const Head &H, const Tail &... T) {\n\tstd::cout << H << \" \";\n\tprint(T...);\n}\n\ntemplate <class T>\nvoid add(std::vector<T> &v, T value) {\n\tfor(auto &a : v) a += value;\n\treturn;\n}\n\ntemplate <class T>\nT greatest_lower_multiple(T x, T d) {\n\tif(d == 0) return 0;\n\tif(d < 0) d *= -1;\n\tT y = x % d;\n\tif(y < 0) y += d;\n\treturn x - y;\n}\n\ntemplate <class T>\nT least_upper_multiple(T x, T d) {\n\treturn -greatest_lower_multiple(-x, d);\n}\n\n// ceil(a / b);\ntemplate <class T>\nT dup(T a, T b) {\n\tassert(b);\n\tif(b < 0) {\n\t\ta *= -1;\n\t\tb *= -1;\n\t}\n\treturn least_upper_multiple(a, b) / b;\n}\n\nlong long pow_ll(long long a, long long n) {\n\tassert(n >= 0LL);\n\tif(n == 0) return 1LL;\n\tif(a == 0) return 0LL;\n\tif(a == 1) return 1LL;\n\tif(a == -1) return (n & 1LL) ? -1LL : 1LL;\n\tlong long res = 1;\n\twhile(n > 1LL) {\n\t\tif(n & 1LL) res *= a;\n\t\ta *= a;\n\t\tn >>= 1;\n\t}\n\treturn res * a;\n}\n\nlong long modpow(long long a, long long n, long long mod) {\t // a^n mod\n\tassert(n >= 0 && mod);\n\tif(mod == 1) return 0LL;\n\tlong long res = 1;\n\ta %= mod;\n\twhile(n > 0) {\n\t\tif(n & 1) res = res * a % mod;\n\t\ta = a * a % mod;\n\t\tn >>= 1;\n\t}\n\treturn res < 0 ? res + mod : res;\n}\n\n// return x which satisfies a * x % mod == gcd(a, mod)\n// not (mod | a)\nlong long modinv(long long a, const long long mod) {\n\tlong long b = mod, u = 1, v = 0;\n\twhile(b) {\n\t\tlong long t = a / b;\n\t\ta -= t * b;\n\t\tstd::swap(a, b);\n\t\tu -= t * v;\n\t\tstd::swap(u, v);\n\t}\n\tu %= mod;\n\tif(u < 0) u += mod;\n\treturn u;\n}\n\ntemplate <class T>\nint lb(const std::vector<T> &a, const T x) {\n\treturn (int)std::distance(a.begin(), std::lower_bound(a.begin(), a.end(), x));\n}\ntemplate <class T>\nint ub(const std::vector<T> &a, const T x) {\n\treturn (int)std::distance(a.begin(), std::upper_bound(a.begin(), a.end(), x));\n}\ntemplate <class T>\nvoid unq_sort(std::vector<T> &a) {\n\tstd::sort(a.begin(), a.end());\n\ta.erase(std::unique(a.begin(), a.end()), a.end());\n}\ntemplate <class T>\nstd::vector<int> press(const std::vector<T> &a) {\n\tstd::vector<T> vec = a;\n\tunq_sort(vec);\n\tstd::vector<int> ret;\n\tfor(const auto &v : a) ret.push_back(lb(vec, v));\n\treturn ret;\n}\n#line 1 \"SPJ-Library/template/header.hpp\"\n#include <bits/stdc++.h>\n#line 2 \"SPJ-Library/template/io.hpp\"\n\n#line 4 \"SPJ-Library/template/io.hpp\"\n\n#line 8 \"SPJ-Library/template/debug.hpp\"\n\n#line 3 \"SPJ-Library/template/constants.hpp\"\n\nconstexpr int inf = 1000'000'000;\nconstexpr long long INF = 1'000'000'000'000'000'000LL;\nconstexpr int mod_1000000007 = 1000000007;\nconstexpr int mod_998244353 = 998244353;\nconst long double pi = acosl(-1.);\nconstexpr int dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};\nconstexpr int dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};\n#line 10 \"SPJ-Library/template/debug.hpp\"\n\nnamespace viewer {\n\ntemplate <typename T, typename U>\nvoid view(const std::pair<T, U> &p);\n\ntemplate <class T0, class T1, class T2>\nvoid view(const std::tuple<T0, T1, T2> &p);\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid view(const std::tuple<T0, T1, T2, T3> &p);\n\nvoid view(const long long &e);\n\nvoid view(const int &e);\n\ntemplate <typename T>\nvoid view(const T &e);\n\ntemplate <typename T>\nvoid view(const std::set<T> &s);\n\ntemplate <typename T>\nvoid view(const std::unordered_set<T> &s);\n\ntemplate <typename T>\nvoid view(const std::multiset<T> &s);\n\ntemplate <typename T>\nvoid view(const std::unordered_multiset<T> &s);\n\ntemplate <typename T>\nvoid view(const std::vector<T> &v);\n\ntemplate <typename T, std::size_t ary_size>\nvoid view(const std::array<T, ary_size> &v);\n\ntemplate <typename T>\nvoid view(const std::vector<std::vector<T>> &vv);\n\ntemplate <typename T, typename U>\nvoid view(const std::vector<std::pair<T, U>> &v);\n\ntemplate <class T0, class T1, class T2>\nvoid view(const std::vector<std::tuple<T0, T1, T2>> &v);\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid view(const std::vector<std::tuple<T0, T1, T2, T3>> &v);\n\ntemplate <typename map_type>\nvoid view_map_container(const map_type &m);\n\ntemplate <typename T, typename U>\nvoid view(const std::map<T, U> &m);\n\ntemplate <typename T, typename U>\nvoid view(const std::unordered_map<T, U> &m);\n\ntemplate <typename container_type>\nvoid view_container(const container_type &c, bool vertically = false) {\n\ttypename container_type::const_iterator begin = c.begin();\n\tconst typename container_type::const_iterator end = c.end();\n\tif(vertically) {\n\t\tstd::cerr << \"{\\n\";\n\t\twhile(begin != end) {\n\t\t\tstd::cerr << '\\t';\n\t\t\tview(*(begin++));\n\t\t\tif(begin != end) std::cerr << ',';\n\t\t\tstd::cerr << '\\n';\n\t\t}\n\t\tstd::cerr << '}';\n\t\treturn;\n\t}\n\tstd::cerr << \"{ \";\n\twhile(begin != end) {\n\t\tview(*(begin++));\n\t\tif(begin != end) std::cerr << ',';\n\t\tstd::cerr << ' ';\n\t}\n\tstd::cerr << '}';\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::pair<T, U> &p) {\n\tstd::cerr << '(';\n\tview(p.first);\n\tstd::cerr << \", \";\n\tview(p.second);\n\tstd::cerr << ')';\n}\n\ntemplate <class T0, class T1, class T2>\nvoid view(const std::tuple<T0, T1, T2> &p) {\n\tstd::cerr << '(';\n\tview(std::get<0>(p));\n\tstd::cerr << \", \";\n\tview(std::get<1>(p));\n\tstd::cerr << \", \";\n\tview(std::get<2>(p));\n\tstd::cerr << ')';\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid view(const std::tuple<T0, T1, T2, T3> &p) {\n\tstd::cerr << '(';\n\tview(std::get<0>(p));\n\tstd::cerr << \", \";\n\tview(std::get<1>(p));\n\tstd::cerr << \", \";\n\tview(std::get<2>(p));\n\tstd::cerr << \", \";\n\tview(std::get<3>(p));\n\tstd::cerr << ')';\n}\n\nvoid view(const long long &e) {\n\tif(e == INF)\n\t\tstd::cerr << \"INF\";\n\telse if(e == -INF)\n\t\tstd::cerr << \"-INF\";\n\telse\n\t\tstd::cerr << e;\n}\n\nvoid view(const int &e) {\n\tif(e == inf)\n\t\tstd::cerr << \"inf\";\n\telse if(e == -inf)\n\t\tstd::cerr << \"-inf\";\n\telse\n\t\tstd::cerr << e;\n}\n\ntemplate <typename T>\nvoid view(const T &e) {\n\tstd::cerr << e;\n}\n\ntemplate <typename T>\nvoid view(const std::set<T> &s) {\n\tview_container(s);\n}\n\ntemplate <typename T>\nvoid view(const std::unordered_set<T> &s) {\n\tview_container(s);\n}\n\ntemplate <typename T>\nvoid view(const std::multiset<T> &s) {\n\tview_container(s);\n}\n\ntemplate <typename T>\nvoid view(const std::unordered_multiset<T> &s) {\n\tview_container(s);\n}\n\ntemplate <typename T>\nvoid view(const std::vector<T> &v) {\n\tview_container(v);\n}\n\ntemplate <typename T, std::size_t ary_size>\nvoid view(const std::array<T, ary_size> &v) {\n\tview_container(v);\n}\n\ntemplate <typename T>\nvoid view(const std::vector<std::vector<T>> &vv) {\n\tview_container(vv, true);\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::vector<std::pair<T, U>> &v) {\n\tview_container(v, true);\n}\n\ntemplate <class T0, class T1, class T2>\nvoid view(const std::vector<std::tuple<T0, T1, T2>> &v) {\n\tview_container(v, true);\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid view(const std::vector<std::tuple<T0, T1, T2, T3>> &v) {\n\tview_container(v, true);\n}\n\ntemplate <typename map_type>\nvoid view_map_container(const map_type &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(typename map_type::const_iterator it = m.begin(); it != m.end(); it++) {\n\t\tstd::cerr << \"\\t[\";\n\t\tview(it->first);\n\t\tstd::cerr << \"] : \";\n\t\tview(it->second);\n\t\tstd::cerr << '\\n';\n\t}\n\tstd::cerr << \"}\";\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::map<T, U> &m) {\n\tview_map_container(m);\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::unordered_map<T, U> &m) {\n\tview_map_container(m);\n}\n\n} // namespace viewer\n\n// when compiling : g++ foo.cpp -DLOCAL\n#ifdef LOCAL\nvoid debug_out() {}\ntemplate <typename T>\nvoid debug_out(const T &x) {\n\tviewer::view(x);\n}\ntemplate <typename Head, typename... Tail>\nvoid debug_out(const Head &H, const Tail &... T) {\n\tviewer::view(H);\n\tstd::cerr << \", \";\n\tdebug_out(T...);\n}\n#define debug(...) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"] : [\"; \\\n\t\tdebug_out(__VA_ARGS__); \\\n\t\tstd::cerr << \"]\\n\"; \\\n\t} while(0)\n#else\n#define debug(...) (void(0))\n#endif\n#line 2 \"SPJ-Library/template/scanner.hpp\"\n\n#line 6 \"SPJ-Library/template/scanner.hpp\"\n\nnamespace scanner {\ntemplate <class T>\nvoid scan(T &a) {\n\tstd::cin >> a;\n}\n\ntemplate <class T, class L>\nvoid scan(std::pair<T, L> &p) {\n\tscan(p.first);\n\tscan(p.second);\n}\n\ntemplate <class T0, class T1, class T2>\nvoid scan(std::tuple<T0, T1, T2> &p) {\n\tT0 t0;\n\tT1 t1;\n\tT2 t2;\n\tscan(t0);\n\tscan(t1);\n\tscan(t2);\n\tp = std::make_tuple(t0, t1, t2);\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid scan(std::tuple<T0, T1, T2, T3> &p) {\n\tT0 t0;\n\tT1 t1;\n\tT2 t2;\n\tT3 t3;\n\tscan(t0);\n\tscan(t1);\n\tscan(t2);\n\tscan(t3);\n\tp = std::make_tuple(t0, t1, t2, t3);\n}\n\ntemplate <class T>\nvoid scan(std::vector<T> &a) {\n\tfor(auto &i : a) scan(i);\n}\n\nvoid INPUT() {}\ntemplate <class Head, class... Tail>\nvoid INPUT(Head &head, Tail &... tail) {\n\tscan(head);\n\tINPUT(tail...);\n}\n} // namespace scanner\n#line 7 \"SPJ-Library/template/io.hpp\"\n\n#define VEC(type, name, size) \\\n\tvector<type> name(size); \\\n\tscanner::INPUT(name)\n#define VVEC(type, name, h, w) \\\n\tvector<vector<type>> name(h, vector<type>(w)); \\\n\tscanner::INPUT(name)\n#define INT(...) \\\n\tint __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LL(...) \\\n\tlong long __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define STR(...) \\\n\tstring __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define CHR(...) \\\n\tchar __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define DBL(...) \\\n\tdouble __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LD(...) \\\n\tlong double __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define TPL3(type0, type1, type2, name) \\\n\tstd::tuple<type0, type1, type2> name; \\\n\tscanner::INPUT(name);\n#define TPL4(type0, type1, type2, type3, name) \\\n\tstd::tuple<type0, type1, type2, type3> name; \\\n\tscanner::INPUT(name);\n\ntemplate <typename T1, typename T2>\nstd::istream &operator>>(std::istream &is, std::pair<T1, T2> &p) {\n\tis >> p.first >> p.second;\n\treturn is;\n}\n\ntemplate <typename T1, typename T2>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T1, T2> &p) {\n\tos << p.first << ' ' << p.second;\n\treturn os;\n}\n\nstruct fast_io {\n\tfast_io() {\n\t\tstd::ios::sync_with_stdio(false);\n\t\tstd::cin.tie(nullptr);\n\t\tstd::cout << std::fixed << std::setprecision(15);\n\t\tsrand((unsigned)time(NULL));\n\t}\n} fast_io_;\n#line 2 \"SPJ-Library/template/macros.hpp\"\n\n#define foa(s, v) for(auto &s : v)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\n#define pcnt(n) __builtin_popcountll((long long)n)\n\n#define REPname(a, b, c, d, e, ...) e\n#define rep(...) REPname(__VA_ARGS__, REP3, REP2, REP1, REP0)(__VA_ARGS__)\n#define REP0(x) for(int Counter_in_rep_macro = 0; Counter_in_rep_macro < (x); ++Counter_in_rep_macro)\n#define REP1(i, x) for(int i = 0; i < (x); ++i)\n#define REP2(i, l, r) for(int i = (l); i < (r); ++i)\n#define REP3(i, l, r, c) for(int i = (l); i < (r); i += (c))\n#define DREPname(a, b, c, d, e, ...) e\n#define drep(...) DREPname(__VA_ARGS__, DREP3, DREP2, DREP1)(__VA_ARGS__)\n#define DREP1(i, x) for(int i = (x)-1; i >= 0; --i)\n#define DREP2(i, l, r) for(int i = (r)-1; i >= (l); --i)\n#define DREP3(i, l, r, c) for(int i = (r)-1; i >= (l); i -= (c))\n\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\nusing vi = std::vector<int>;\nusing vvi = std::vector<std::vector<int>>;\nusing vvvi = std::vector<std::vector<std::vector<int>>>;\nusing vll = std::vector<ll>;\nusing vvll = std::vector<vll>;\nusing vvvll = std::vector<vvll>;\ntemplate <class T = ll>\nusing V = std::vector<T>;\ntemplate <class T = ll>\nusing VV = V<V<T>>;\ntemplate <class T = ll>\nusing VVV = V<V<V<T>>>;\ntemplate <class T = ll>\nusing pqup = std::priority_queue<T, std::vector<T>, std::greater<T>>;\ntemplate <class T = ll>\nusing pqdn = std::priority_queue<T>;\n#line 7 \"SPJ-Library/template/kuma.hpp\"\n\nusing namespace std;\n#line 7 \"a.cpp\"\n\nint solve(int h, int w) {\n\tvector<vector<int>> room_id(h, vi(w));\n\tint rid = 0;\n\tfoa(row, room_id) foa(c, row) c = rid++;\n\tvector<vector<int>> door_id(rid, vi(4, -1));\n\tauto adj_id = door_id;\n\tint did = 0;\n\tauto move_yoko = [&](int row_id) -> void {\n\t\trep(j, w - 1) {\n\t\t\tint c;\n\t\t\tcin >> c;\n\t\t\tint left = room_id[row_id][j];\n\t\t\tint right = room_id[row_id][j + 1];\n\n\t\t\tif(c == 0) {\n\t\t\t\tdoor_id[left][0] = did;\n\t\t\t\tdoor_id[right][2] = did++;\n\t\t\t\tadj_id[left][0] = right;\n\t\t\t\tadj_id[right][2] = left;\n\t\t\t}\n\t\t}\n\t\treturn;\n\t};\n\tauto move_tate = [&](int upper_row_id) -> void {\n\t\trep(j, w) {\n\t\t\tint c;\n\t\t\tcin >> c;\n\t\t\tint up = room_id[upper_row_id][j];\n\t\t\tint down = room_id[upper_row_id + 1][j];\n\n\t\t\tif(c == 0) {\n\t\t\t\tdoor_id[up][3] = did;\n\t\t\t\tdoor_id[down][1] = did++;\n\t\t\t\tadj_id[up][3] = down;\n\t\t\t\tadj_id[down][1] = up;\n\t\t\t}\n\t\t}\n\t\treturn;\n\t};\n\trep(r, h - 1) {\n\t\tmove_yoko(r);\n\t\tmove_tate(r);\n\t}\n\tmove_yoko(h - 1);\n\n\t// debug(room_id);\n\t// debug(door_id);\n\t// debug(rid, did);\n\n\tvector<vector<int>> to_goal;\n\trep(broken_id, did) {\n\t\tgraph<int> g(rid);\n\t\trep(i, h) rep(j, w) {\n\t\t\tconst int from = room_id[i][j];\n\t\t\t// debug(i, j, from);\n\t\t\trep(dir, 4) {\n\t\t\t\tint pass = door_id[from][dir];\n\t\t\t\t// debug(dir, pass);\n\t\t\t\tif(pass != -1 && pass != broken_id) {\n\t\t\t\t\tconst int to = adj_id[from][dir];\n\t\t\t\t\t// debug(from, to);\n\t\t\t\t\tassert(in_range(from, 0, rid) && in_range(to, 0, rid));\n\t\t\t\t\tg.add_edge(from, to, 1, true, 0);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tto_goal.push_back(g.bfs(room_id[h - 1][w - 1]));\n\t\tif(to_goal.back().front() == g.INF) return -1;\n\t}\n\n\t// debug(to_goal);\n\t// exit(0);\n\n\tvector<int> move_grid = {1, -w, -1, w};\n\n\tauto judge = [&](int card) -> bool {\n\t\tvector<int> dist(rid, inf);\n\t\tdist.front() = 0;\n\t\tqueue<int> q;\n\t\tq.push(0);\n\t\twhile(q.size()) {\n\t\t\tint now = q.front();\n\t\t\tq.pop();\n\t\t\tif(now == room_id.back().back()) return true;\n\t\t\trep(dir, 4) {\n\t\t\t\tint nxt_door = door_id[now][dir];\n\t\t\t\tif(nxt_door == -1) continue;\n\t\t\t\tint nxt_room = now + move_grid[dir];\n\t\t\t\tif(to_goal[nxt_door][now] + dist[now] <= card && chmin(dist[nxt_room], dist[now] + 1)) {\n\t\t\t\t\tq.push(nxt_room);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn false;\n\t};\n\n\tint ok = rid * 10;\n\tint ng = 0;\n\twhile(abs(ok - ng) > 1) {\n\t\tint med = (ok + ng) / 2;\n\n\t\tif(judge(med)) {\n\t\t\tok = med;\n\t\t} else {\n\t\t\tng = med;\n\t\t}\n\t}\n\n\treturn ok;\n}\nint main() {\n\tint h, w;\n\twhile(cin >> h >> w && h + w) {\n\t\tcout << solve(h, w) << '\\n';\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1120, "memory_kb": 9492, "score_of_the_acc": -1.4831, "final_rank": 18 }, { "submission_id": "aoj_1178_6813374", "code_snippet": "#pragma region Macros\n#if defined(noimi) && defined(_GLIBCXX_DEBUG) && defined(_GLIBCXX_DEBUG_PEDANTIC)\n// #pragma comment(linker, \"/stack:200000000\")\n#include <stdc++.h>\n#pragma GCC optimize(\"O3\")\n#else\n#pragma GCC optimize(\"Ofast\")\n// #pragma GCC optimize(\"unroll-loops\")\n// #pragma GCC target(\"popcnt\")\n// #pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2,tune=native\")\n// #pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2\")\n// #pragma GCC target(\"avx2\")\n// #include <bits/stdc++.h>\n#include <bits/stdc++.h>\n#endif\n#include <cstdint>\n#include <immintrin.h>\n#include <variant>\n\n#ifdef noimi\n#define oj_local(a, b) b\n#else\n#define oj_local(a, b) a\n#endif\n\n#define LOCAL if(oj_local(0, 1))\n#define OJ if(oj_local(1, 0))\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long int;\nusing i128 = __int128_t;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\nusing ld = long double;\ntemplate <typename T> using vc = vector<T>;\ntemplate <typename T> using vvc = vector<vc<T>>;\ntemplate <typename T> using vvvc = vector<vvc<T>>;\nusing vi = vc<int>;\nusing vl = vc<ll>;\nusing vpi = vc<pii>;\nusing vpl = vc<pll>;\ntemplate <class T> using pq = priority_queue<T>;\ntemplate <class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\ntemplate <typename T> int si(const T &x) { return x.size(); }\ntemplate <class T, class S> inline bool chmax(T &a, const S &b) { return (a < b ? a = b, 1 : 0); }\ntemplate <class T, class S> inline bool chmin(T &a, const S &b) { return (a > b ? a = b, 1 : 0); }\nvi iota(int n) {\n vi a(n);\n return iota(a.begin(), a.end(), 0), a;\n}\ntemplate <typename T> vi iota(const vector<T> &a, bool greater = false) {\n vi res(a.size());\n iota(res.begin(), res.end(), 0);\n sort(res.begin(), res.end(), [&](int i, int j) {\n if(greater) return a[i] > a[j];\n return a[i] < a[j];\n });\n return res;\n}\n\n// macros\n#define overload5(a, b, c, d, e, name, ...) name\n#define overload4(a, b, c, d, name, ...) name\n#define endl '\\n'\n#define REP0(n) for(ll jidlsjf = 0; jidlsjf < n; ++jidlsjf)\n#define REP1(i, n) for(ll i = 0; i < (n); ++i)\n#define REP2(i, a, b) for(ll i = (a); i < (b); ++i)\n#define REP3(i, a, b, c) for(ll i = (a); i < (b); i += (c))\n#define rep(...) overload4(__VA_ARGS__, REP3, REP2, REP1, REP0)(__VA_ARGS__)\n#define per0(n) for(int jidlsjf = 0; jidlsjf < (n); ++jidlsjf)\n#define per1(i, n) for(ll i = (n)-1; i >= 0; --i)\n#define per2(i, a, b) for(ll i = (a)-1; i >= b; --i)\n#define per3(i, a, b, c) for(ll i = (a)-1; i >= (b); i -= (c))\n#define per(...) overload4(__VA_ARGS__, per3, per2, per1, per0)(__VA_ARGS__)\n#define fore0(a) rep(a.size())\n#define fore1(i, a) for(auto &&i : a)\n#define fore2(a, b, v) for(auto &&[a, b] : v)\n#define fore3(a, b, c, v) for(auto &&[a, b, c] : v)\n#define fore4(a, b, c, d, v) for(auto &&[a, b, c, d] : v)\n#define fore(...) overload5(__VA_ARGS__, fore4, fore3, fore2, fore1, fore0)(__VA_ARGS__)\n#define fi first\n#define se second\n#define pb push_back\n#define ppb pop_back\n#define ppf pop_front\n#define eb emplace_back\n#define drop(s) cout << #s << endl, exit(0)\n#define si(c) (int)(c).size()\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define ub(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define rng(v, l, r) v.begin() + l, v.begin() + r\n#define all(c) begin(c), end(c)\n#define rall(c) rbegin(c), rend(c)\n#define SORT(v) sort(all(v))\n#define REV(v) reverse(all(v))\n#define UNIQUE(x) SORT(x), x.erase(unique(all(x)), x.end())\ntemplate <typename T = ll, typename S> T SUM(const S &v) { return accumulate(all(v), T(0)); }\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define overload2(_1, _2, name, ...) name\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define vv(type, name, h, ...) vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) vector<vector<vector<type>>> name(h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name(a, vector<vector<vector<type>>>(b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\nconstexpr pii dx4[4] = {pii{1, 0}, pii{0, 1}, pii{-1, 0}, pii{0, -1}};\nconstexpr pii dx8[8] = {{1, 0}, {1, 1}, {0, 1}, {-1, 1}, {-1, 0}, {-1, -1}, {0, -1}, {1, -1}};\n\nnamespace yesno_impl {\nconst string YESNO[2] = {\"NO\", \"YES\"};\nconst string YesNo[2] = {\"No\", \"Yes\"};\nconst string yesno[2] = {\"no\", \"yes\"};\nconst string firstsecond[2] = {\"second\", \"first\"};\nconst string FirstSecond[2] = {\"Second\", \"First\"};\nconst string possiblestr[2] = {\"impossible\", \"possible\"};\nvoid YES(bool t = 1) { cout << YESNO[t] << endl; }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { cout << YesNo[t] << endl; }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { cout << yesno[t] << endl; }\nvoid no(bool t = 1) { yes(!t); }\nvoid first(bool t = 1) { cout << firstsecond[t] << endl; }\nvoid First(bool t = 1) { cout << FirstSecond[t] << endl; }\nvoid possible(bool t = 1) { cout << possiblestr[t] << endl; }\n}; // namespace yesno_impl\nusing namespace yesno_impl;\n\n#define INT(...) \\\n int __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define LL(...) \\\n ll __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define STR(...) \\\n string __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define CHR(...) \\\n char __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define DBL(...) \\\n double __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define VEC(type, name, size) \\\n vector<type> name(size); \\\n IN(name)\n#define VEC2(type, name1, name2, size) \\\n vector<type> name1(size), name2(size); \\\n for(int i = 0; i < size; i++) IN(name1[i], name2[i])\n#define VEC3(type, name1, name2, name3, size) \\\n vector<type> name1(size), name2(size), name3(size); \\\n for(int i = 0; i < size; i++) IN(name1[i], name2[i], name3[i])\n#define VEC4(type, name1, name2, name3, name4, size) \\\n vector<type> name1(size), name2(size), name3(size), name4(size); \\\n for(int i = 0; i < size; i++) IN(name1[i], name2[i], name3[i], name4[i]);\n#define VV(type, name, h, w) \\\n vector<vector<type>> name(h, vector<type>(w)); \\\n IN(name)\nint scan() { return getchar(); }\nvoid scan(int &a) { cin >> a; }\nvoid scan(long long &a) { cin >> a; }\nvoid scan(char &a) { cin >> a; }\nvoid scan(double &a) { cin >> a; }\nvoid scan(string &a) { cin >> a; }\ntemplate <class T, class S> void scan(pair<T, S> &p) { scan(p.first), scan(p.second); }\ntemplate <class T> void scan(vector<T> &);\ntemplate <class T> void scan(vector<T> &a) {\n for(auto &i : a) scan(i);\n}\ntemplate <class T> void scan(T &a) { cin >> a; }\nvoid IN() {}\ntemplate <class Head, class... Tail> void IN(Head &head, Tail &...tail) {\n scan(head);\n IN(tail...);\n}\n\ntemplate <typename T, typename S> T ceil(T x, S y) {\n assert(y);\n return (y < 0 ? ceil(-x, -y) : (x > 0 ? (x + y - 1) / y : x / y));\n}\n\ntemplate <typename T, typename S> T floor(T x, S y) {\n assert(y);\n return (y < 0 ? floor(-x, -y) : (x > 0 ? x / y : x / y - (x % y == 0 ? 0 : 1)));\n}\ntemplate <class T> T POW(T x, int n) {\n T res = 1;\n for(; n; n >>= 1, x *= x)\n if(n & 1) res *= x;\n return res;\n}\ntemplate <class T, class S> T POW(T x, S n, const ll &mod) {\n T res = 1;\n x %= mod;\n for(; n; n >>= 1, x = x * x % mod)\n if(n & 1) res = res * x % mod;\n return res;\n}\nvector<pll> factor(ll x) {\n vector<pll> ans;\n for(ll i = 2; i * i <= x; i++)\n if(x % i == 0) {\n ans.push_back({i, 1});\n while((x /= i) % i == 0) ans.back().second++;\n }\n if(x != 1) ans.push_back({x, 1});\n return ans;\n}\ntemplate <class T> vector<T> divisor(T x) {\n vector<T> ans;\n for(T i = 1; i * i <= x; i++)\n if(x % i == 0) {\n ans.pb(i);\n if(i * i != x) ans.pb(x / i);\n }\n return ans;\n}\ntemplate <typename T> void zip(vector<T> &x) {\n vector<T> y = x;\n UNIQUE(y);\n for(int i = 0; i < x.size(); ++i) { x[i] = lb(y, x[i]); }\n}\ntemplate <class S> void fold_in(vector<S> &v) {}\ntemplate <typename Head, typename... Tail, class S> void fold_in(vector<S> &v, Head &&a, Tail &&...tail) {\n for(auto e : a) v.emplace_back(e);\n fold_in(v, tail...);\n}\ntemplate <class S> void renumber(vector<S> &v) {}\ntemplate <typename Head, typename... Tail, class S> void renumber(vector<S> &v, Head &&a, Tail &&...tail) {\n for(auto &&e : a) e = lb(v, e);\n renumber(v, tail...);\n}\ntemplate <class S, class... Args> vector<S> zip(vector<S> &head, Args &&...args) {\n vector<S> v;\n fold_in(v, head, args...);\n sort(all(v)), v.erase(unique(all(v)), v.end());\n renumber(v, head, args...);\n return v;\n}\ntemplate <typename T> vector<T> RUI(const vector<T> &v) {\n vector<T> res(v.size() + 1);\n for(int i = 0; i < v.size(); i++) res[i + 1] = res[i] + v[i];\n return res;\n}\n// 反時計周りに 90 度回転\ntemplate <typename T> void rot(vector<vector<T>> &v) {\n if(empty(v)) return;\n int n = v.size(), m = v[0].size();\n vector res(m, vector<T>(n));\n rep(i, n) rep(j, m) res[m - 1 - j][i] = v[i][j];\n v.swap(res);\n}\n// x in [l, r)\ntemplate <class T, class S> bool inc(const T &x, const S &l, const S &r) { return l <= x and x < r; }\n\n// 便利関数\nconstexpr ll ten(int n) { return n == 0 ? 1 : ten(n - 1) * 10; }\nconstexpr ll tri(ll n) { return n * (n + 1) / 2; }\n// l + ... + r\nconstexpr ll tri(ll l, ll r) { return (l + r) * (r - l + 1) / 2; }\nll max(int x, ll y) { return max((ll)x, y); }\nll max(ll x, int y) { return max(x, (ll)y); }\nint min(int x, ll y) { return min((ll)x, y); }\nint min(ll x, int y) { return min(x, (ll)y); }\n// bit 演算系\nll pow2(int i) { return 1LL << i; }\nint topbit(signed t) { return t == 0 ? -1 : 31 - __builtin_clz(t); }\nint topbit(ll t) { return t == 0 ? -1 : 63 - __builtin_clzll(t); }\nint lowbit(signed a) { return a == 0 ? 32 : __builtin_ctz(a); }\nint lowbit(ll a) { return a == 0 ? 64 : __builtin_ctzll(a); }\n// int allbit(int n) { return (1 << n) - 1; }\nconstexpr ll mask(int n) { return (1LL << n) - 1; }\n// int popcount(signed t) { return __builtin_popcount(t); }\n// int popcount(ll t) { return __builtin_popcountll(t); }\nint popcount(uint64_t t) { return __builtin_popcountll(t); }\nstatic inline uint64_t popcount64(uint64_t x) {\n uint64_t m1 = 0x5555555555555555ll;\n uint64_t m2 = 0x3333333333333333ll;\n uint64_t m4 = 0x0F0F0F0F0F0F0F0Fll;\n uint64_t h01 = 0x0101010101010101ll;\n\n x -= (x >> 1) & m1;\n x = (x & m2) + ((x >> 2) & m2);\n x = (x + (x >> 4)) & m4;\n\n return (x * h01) >> 56;\n}\nbool ispow2(int i) { return i && (i & -i) == i; }\n\nll rnd(ll l, ll r) { //[l, r)\n#ifdef noimi\n static mt19937_64 gen;\n#else\n static mt19937_64 gen(chrono::steady_clock::now().time_since_epoch().count());\n#endif\n return uniform_int_distribution<ll>(l, r - 1)(gen);\n}\nll rnd(ll n) { return rnd(0, n); }\n\ntemplate <class t> void random_shuffle(vc<t> &a) { rep(i, si(a)) swap(a[i], a[rnd(0, i + 1)]); }\n\nint in() {\n int x;\n cin >> x;\n return x;\n}\nll lin() {\n unsigned long long x;\n cin >> x;\n return x;\n}\n\ntemplate <class T, class S> pair<T, S> operator-(const pair<T, S> &x) { return pair<T, S>(-x.first, -x.second); }\ntemplate <class T, class S> pair<T, S> operator-(const pair<T, S> &x, const pair<T, S> &y) { return pair<T, S>(x.fi - y.fi, x.se - y.se); }\ntemplate <class T, class S> pair<T, S> operator+(const pair<T, S> &x, const pair<T, S> &y) { return pair<T, S>(x.fi + y.fi, x.se + y.se); }\ntemplate <class T> pair<T, T> operator&(const pair<T, T> &l, const pair<T, T> &r) { return pair<T, T>(max(l.fi, r.fi), min(l.se, r.se)); }\ntemplate <class T, class S> pair<T, S> operator+=(pair<T, S> &l, const pair<T, S> &r) { return l = l + r; }\ntemplate <class T, class S> pair<T, S> operator-=(pair<T, S> &l, const pair<T, S> &r) { return l = l - r; }\ntemplate <class T> bool intersect(const pair<T, T> &l, const pair<T, T> &r) { return (l.se < r.se ? r.fi < l.se : l.fi < r.se); }\n\ntemplate <typename T> struct edge {\n int from, to;\n T cost;\n int id;\n edge(int to, T cost) : from(-1), to(to), cost(cost) {}\n edge(int from, int to, T cost) : from(from), to(to), cost(cost) {}\n edge(int from, int to, T cost, int id) : from(from), to(to), cost(cost), id(id) {}\n constexpr bool operator<(const edge<T> &rhs) const noexcept { return cost < rhs.cost; }\n edge &operator=(const int &x) {\n to = x;\n return *this;\n }\n operator int() const { return to; }\n friend ostream operator<<(ostream &os, edge &e) { return os << e.to; }\n};\ntemplate <typename T> using Edges = vector<edge<T>>;\n\nusing Tree = vector<vector<int>>;\nusing Graph = vector<vector<int>>;\ntemplate <class T> using Wgraph = vector<vector<edge<T>>>;\nGraph getG(int n, int m = -1, bool directed = false, int margin = 1) {\n Tree res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n cin >> a >> b;\n a -= margin, b -= margin;\n res[a].emplace_back(b);\n if(!directed) res[b].emplace_back(a);\n }\n return res;\n}\nGraph getTreeFromPar(int n, int margin = 1) {\n Graph res(n);\n for(int i = 1; i < n; i++) {\n int a;\n cin >> a;\n res[a - margin].emplace_back(i);\n }\n return res;\n}\ntemplate <class T> Wgraph<T> getWg(int n, int m = -1, bool directed = false, int margin = 1) {\n Wgraph<T> res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n T c;\n scan(a), scan(b), scan(c);\n a -= margin, b -= margin;\n res[a].emplace_back(b, c);\n if(!directed) res[b].emplace_back(a, c);\n }\n return res;\n}\nvoid add(Graph &G, int x, int y) { G[x].eb(y), G[y].eb(x); }\ntemplate <class S, class T> void add(Wgraph<S> &G, int x, int y, T c) { G[x].eb(y, c), G[y].eb(x, c); }\n\n#define TEST \\\n INT(testcases); \\\n while(testcases--)\n\nistream &operator>>(istream &is, i128 &v) {\n string s;\n is >> s;\n v = 0;\n for(int i = 0; i < (int)s.size(); i++) {\n if(isdigit(s[i])) { v = v * 10 + s[i] - '0'; }\n }\n if(s[0] == '-') { v *= -1; }\n return is;\n}\n\nostream &operator<<(ostream &os, const i128 &v) {\n if(v == 0) { return (os << \"0\"); }\n i128 num = v;\n if(v < 0) {\n os << '-';\n num = -num;\n }\n string s;\n for(; num > 0; num /= 10) { s.push_back((char)(num % 10) + '0'); }\n reverse(s.begin(), s.end());\n return (os << s);\n}\nnamespace aux {\ntemplate <typename T, unsigned N, unsigned L> struct tp {\n static void output(std::ostream &os, const T &v) {\n os << std::get<N>(v) << (&os == &cerr ? \", \" : \" \");\n tp<T, N + 1, L>::output(os, v);\n }\n};\ntemplate <typename T, unsigned N> struct tp<T, N, N> {\n static void output(std::ostream &os, const T &v) { os << std::get<N>(v); }\n};\n} // namespace aux\ntemplate <typename... Ts> std::ostream &operator<<(std::ostream &os, const std::tuple<Ts...> &t) {\n if(&os == &cerr) { os << '('; }\n aux::tp<std::tuple<Ts...>, 0, sizeof...(Ts) - 1>::output(os, t);\n if(&os == &cerr) { os << ')'; }\n return os;\n}\ntemplate <class T, class S> ostream &operator<<(ostream &os, const pair<T, S> &p) {\n if(&os == &cerr) { return os << \"(\" << p.first << \", \" << p.second << \")\"; }\n return os << p.first << \" \" << p.second;\n}\ntemplate <class Ch, class Tr, class Container> std::basic_ostream<Ch, Tr> &operator<<(std::basic_ostream<Ch, Tr> &os, const Container &x) {\n bool f = true;\n if(&os == &cerr) os << \"[\";\n for(auto &y : x) {\n if(&os == &cerr)\n os << (f ? \"\" : \", \") << y;\n else\n os << (f ? \"\" : \" \") << y;\n f = false;\n }\n if(&os == &cerr) os << \"]\";\n return os;\n}\n\n#ifdef noimi\n#undef endl\nvoid debug() { cerr << endl; }\nvoid debug(bool) { cerr << endl; }\ntemplate <class Head, class... Tail> void debug(bool is_front, Head head, Tail... tail) {\n if(!is_front) cerr << \", \";\n cerr << head;\n debug(false, tail...);\n}\n\n#define dump(args...) \\\n { \\\n vector<string> _debug = _split(#args, ','); \\\n err(true, begin(_debug), args); \\\n }\n\nvector<string> _split(const string &s, char c) {\n vector<string> v;\n stringstream ss(s);\n string x;\n while(getline(ss, x, c)) {\n if(empty(v))\n v.eb(x);\n else {\n bool flag = false;\n for(auto [c, d] : {pair('(', ')'), pair('[', ']'), pair('{', '}')}) {\n if(count(all(v.back()), c) != count(all(v.back()), d)) flag = true;\n }\n if(flag)\n v.back() += \",\" + x;\n else\n v.eb(x);\n }\n }\n return move(v);\n}\n\nvoid err(bool, vector<string>::iterator) { cerr << endl; }\ntemplate <typename T, typename... Args> void err(bool is_front, vector<string>::iterator it, T a, Args... args) {\n if(!is_front) cerr << \", \";\n cerr << it->substr((*it)[0] == ' ', (*it).size()) << \" = \" << a, err(false, ++it, args...);\n}\n\n// #define dump(...) cerr << #__VA_ARGS__ << \" : \", debug(true, __VA_ARGS__)\n#else\n#define dump(...) static_cast<void>(0)\n#define dbg(...) static_cast<void>(0)\n#endif\nvoid OUT() { cout << endl; }\ntemplate <class Head, class... Tail> void OUT(const Head &head, const Tail &...tail) {\n cout << head;\n if(sizeof...(tail)) cout << ' ';\n OUT(tail...);\n}\n\ntemplate <typename T> static constexpr T inf = numeric_limits<T>::max() / 2;\ntemplate <class T, class S> constexpr pair<T, S> inf<pair<T, S>> = {inf<T>, inf<S>};\n\ntemplate <class F> struct REC {\n F f;\n REC(F &&f_) : f(std::forward<F>(f_)) {}\n template <class... Args> auto operator()(Args &&...args) const { return f(*this, std::forward<Args>(args)...); }\n};\n\ntemplate <class S> vector<pair<S, int>> runLength(const vector<S> &v) {\n vector<pair<S, int>> res;\n for(auto &e : v) {\n if(res.empty() or res.back().fi != e)\n res.eb(e, 1);\n else\n res.back().se++;\n }\n return res;\n}\nvector<pair<char, int>> runLength(const string &v) {\n vector<pair<char, int>> res;\n for(auto &e : v) {\n if(res.empty() or res.back().fi != e)\n res.eb(e, 1);\n else\n res.back().se++;\n }\n return res;\n}\n\nint toint(const char &c, const char start = 'a') { return c - start; }\nint toint(const char &c, const string &chars) { return find(all(chars), c) - begin(chars); }\nint alphabets_to_int(const char &c) { return (islower(c) ? c - 'a' : c - 'A' + 26); }\ntemplate <typename T> auto toint(const T &v, const char &start = 'a') {\n vector<decltype(toint(v[0]))> ret;\n ret.reserve(v.size());\n for(auto &&e : v) ret.emplace_back(toint(e, start));\n return ret;\n}\ntemplate <typename T> auto toint(const T &v, const string &start) {\n vector<decltype(toint(v[0]))> ret;\n ret.reserve(v.size());\n for(auto &&e : v) ret.emplace_back(toint(e, start));\n return ret;\n}\n// a -> 0, A -> 26\ntemplate <typename T> auto alphabets_to_int(const T &s) {\n vector<decltype(alphabets_to_int(s[0]))> res;\n res.reserve(s.size());\n for(auto &&e : s) { res.emplace_back(alphabets_to_int(e)); }\n return res;\n}\n\ntemplate <class T, class F> T bin_search(T ok, T ng, const F &f) {\n while(abs(ok - ng) > 1) {\n T mid = ok + ng >> 1;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\ntemplate <class T, class F> T bin_search_double(T ok, T ng, const F &f, int iter = 80) {\n while(iter--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\nstruct Setup_io {\n Setup_io() {\n ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);\n cout << fixed << setprecision(11);\n }\n} setup_io;\n\n#pragma endregion\n\nstruct Grid {\n int n, m;\n Grid(int n, int m) : n(n), m(m) {}\n struct GridSquare {\n const int &n, &m;\n int x, y;\n GridSquare(const int &n, const int &m, int x, int y) : x(x), y(y), n(n), m(m) {}\n struct itr {\n const int &n, &m, &x, &y;\n int i;\n itr(const int &n, const int &m, const int &x, const int &y) : n(n), m(m), x(x), y(y), i(0) {\n while(!inc(dx4[i].fi + x, 0, n) or !inc(dx4[i].se + x, 0, m)) { i++; }\n }\n bool operator!=(const itr &) const { return i != 4; }\n void operator++() {\n while(i != 4) {\n i++;\n if(inc(dx4[i].fi + x, 0, n) and inc(dx4[i].se + y, 0, m)) break;\n }\n }\n pair<int, int> operator*() const { return pair(x + dx4[i].fi, y + dx4[i].se); }\n };\n itr begin() const { return itr(n, m, x, y); }\n itr end() const { return itr(n, m, x, y); }\n };\n GridSquare get(int x, int y) { return GridSquare(n, m, x, y); }\n};\n\nint main() {\n rep(100) {\n INT(h, w);\n if(!h) exit(0);\n\n Grid G(h, w);\n\n int E = 1;\n using T = tuple<int, int, int>;\n vvv(T, g, h, w, 0);\n\n vector<pair<pii, pii>> edges;\n rep(i, h * 2 - 1) {\n if(i & 1) {\n VEC(int, a, w);\n rep(j, w) if(!a[j]) {\n g[i / 2][j].eb(i / 2 + 1, j, E);\n g[i / 2 + 1][j].eb(i / 2, j, E);\n edges.eb(pii(i / 2, j), pii(i / 2 + 1, j));\n E++;\n }\n } else {\n VEC(int, a, w - 1);\n rep(j, w - 1) {\n if(!a[j]) {\n g[i / 2][j].eb(i / 2, j + 1, E);\n g[i / 2][j + 1].eb(i / 2, j, E);\n edges.eb(pii(i / 2, j), pii(i / 2, j + 1));\n E++;\n }\n }\n }\n }\n\n vvv(int, d, h, w, E, inf<int>);\n queue<T> q;\n rep(i, 1, E) q.emplace(h - 1, w - 1, i), d[h - 1][w - 1][i] = 0;\n while(!empty(q)) {\n auto [i, j, k] = q.front();\n q.pop();\n fore(ni, nj, nk, g[i][j]) {\n if(nk == k) continue;\n if(chmin(d[ni][nj][k], d[i][j][k] + 1)) q.emplace(ni, nj, k);\n }\n }\n\n pqg<T> pq;\n pq.emplace(0, h - 1, w - 1);\n d[h - 1][w - 1][0] = 0;\n while(!empty(pq)) {\n auto [c, i, j] = pq.top();\n // dump(c, i, j);\n pq.pop();\n if(d[i][j][0] < c) continue;\n fore(ni, nj, nk, g[i][j]) {\n // dump(ni, nj, nk);\n // dump(d[ni][nj][0], d[i][j][0], d[ni][nj][nk]);\n if(chmin(d[ni][nj][0], max(d[i][j][0] + 1, d[ni][nj][nk]))) pq.emplace(d[ni][nj][0], ni, nj);\n }\n }\n\n int res = d[0][0][0];\n if(res >= inf<int>)\n OUT(-1);\n else\n OUT(res);\n }\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 10108, "score_of_the_acc": -0.7027, "final_rank": 15 }, { "submission_id": "aoj_1178_6330176", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\n\n#define REP(a, b) for (long long a = 0; a < b; ++a)\n#define ll long long\n#define ld long double\n#define ALL(x) begin(x), end(x)\n\n#define int long long\n\nvoid solve()\n{\n int h, w;\n cin >> h >> w;\n if (h == 0)\n exit(0);\n vector<vector<int>> move_right(h, vector<int>(w, 1));\n vector<vector<int>> move_left(h, vector<int>(w, 1));\n vector<vector<int>> move_up(h, vector<int>(w, 1));\n vector<vector<int>> move_down(h, vector<int>(w, 1));\n REP(i, 2 * h - 1)\n {\n if (i % 2 == 0)\n {\n REP(q, w - 1)\n {\n int a;\n cin >> a;\n if (a == 1)\n {\n move_right[i / 2][q] = 0;\n move_left[i / 2][q + 1] = 0;\n }\n }\n }\n else\n {\n REP(q, w)\n {\n int a;\n cin >> a;\n if (a == 1)\n {\n move_down[i / 2][q] = 0;\n move_up[i / 2 + 1][q] = 0;\n }\n }\n }\n }\n\n vector<vector<int>> dist(h, vector<int>(w, 0));\n REP(i, h)\n {\n REP(q, w)\n {\n int now_max = 0;\n REP(t, 4)\n {\n int x;\n if (t == 0)\n {\n x = move_down[i][q];\n move_down[i][q] = 0;\n }\n else if (t == 1)\n {\n x = move_up[i][q];\n move_up[i][q] = 0;\n }\n else if (t == 2)\n {\n x = move_right[i][q];\n move_right[i][q] = 0;\n }\n else\n {\n x = move_left[i][q];\n move_left[i][q] = 0;\n }\n vector<vector<int>> moves(h, vector<int>(w, 1e9));\n moves[i][q] = 0;\n queue<pair<int, int>> nexts;\n nexts.push({i, q});\n while (!nexts.empty())\n {\n pair<int, int> now = nexts.front();\n nexts.pop();\n int x = now.first, y = now.second;\n if (x > 0 and move_up[x][y] == 1)\n {\n if (moves[x - 1][y] == 1e9)\n {\n moves[x - 1][y] = moves[x][y] + 1;\n nexts.push({x - 1, y});\n }\n }\n if (x < h - 1 and move_down[x][y] == 1)\n {\n if (moves[x + 1][y] == 1e9)\n {\n moves[x + 1][y] = moves[x][y] + 1;\n nexts.push({x + 1, y});\n }\n }\n\n if (y > 0 and move_left[x][y] == 1)\n {\n if (moves[x][y - 1] == 1e9)\n {\n moves[x][y - 1] = moves[x][y] + 1;\n nexts.push({x, y - 1});\n }\n }\n if (y < w - 1 and move_right[x][y] == 1)\n {\n if (moves[x][y + 1] == 1e9)\n {\n moves[x][y + 1] = moves[x][y] + 1;\n nexts.push({x, y + 1});\n }\n }\n }\n\n now_max = max(now_max, moves[h - 1][w - 1]);\n if (t == 0)\n {\n move_down[i][q] = x;\n }\n else if (t == 1)\n {\n move_up[i][q] = x;\n }\n else if (t == 2)\n {\n move_right[i][q] = x;\n }\n else\n {\n move_left[i][q] = x;\n }\n }\n dist[i][q] = now_max;\n }\n }\n\n int bot = 1e9;\n int top = 0;\n while (bot - top > 1)\n {\n int mid = (bot + top) / 2;\n vector<vector<int>> moves(h, vector<int>(w, 1e9));\n moves[0][0] = 0;\n queue<pair<int, int>> nexts;\n nexts.push({0, 0});\n while (!nexts.empty())\n {\n pair<int, int> now = nexts.front();\n nexts.pop();\n int x = now.first, y = now.second;\n if (x > 0 and move_up[x][y] == 1)\n {\n if (moves[x - 1][y] == 1e9)\n {\n if (moves[x][y] + 1 + dist[x - 1][y] <= mid)\n {\n moves[x - 1][y] = moves[x][y] + 1;\n nexts.push({x - 1, y});\n }\n }\n }\n if (x < h - 1 and move_down[x][y] == 1)\n {\n if (moves[x + 1][y] == 1e9)\n {\n if (moves[x][y] + 1 + dist[x + 1][y] <= mid)\n {\n moves[x + 1][y] = moves[x][y] + 1;\n nexts.push({x + 1, y});\n }\n }\n }\n\n if (y > 0 and move_left[x][y] == 1)\n {\n if (moves[x][y - 1] == 1e9)\n {\n if (moves[x][y] + 1 + dist[x][y - 1] <= mid)\n {\n moves[x][y - 1] = moves[x][y] + 1;\n nexts.push({x, y - 1});\n }\n }\n }\n if (y < w - 1 and move_right[x][y] == 1)\n {\n if (moves[x][y + 1] == 1e9)\n {\n if (moves[x][y] + 1 + dist[x][y + 1] <= mid)\n {\n moves[x][y + 1] = moves[x][y] + 1;\n nexts.push({x, y + 1});\n }\n }\n }\n }\n if (moves[h - 1][w - 1] != 1e9)\n bot = mid;\n else\n top = mid;\n }\n if (bot == 1e9)\n bot = -1;\n cout << bot << endl;\n}\n\n#undef int\nint main()\n{\n iostream::sync_with_stdio(false);\n cout << fixed << setprecision(100);\n while (true)\n {\n solve();\n }\n}", "accuracy": 1, "time_ms": 740, "memory_kb": 3296, "score_of_the_acc": -0.5615, "final_rank": 11 }, { "submission_id": "aoj_1178_6144693", "code_snippet": "//https://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=1178&lang=jp\n/* スタート地点からの距離が小さい地点から順に「その地点に隣接するドアが一つ壊れた場合の\n最短距離」を決めていく。これを決める際、その地点にたどり着く前の地点の値との max を取れば\n順に求めていくことができる。ある種の dp と言えるだろうか。*/\n\n#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n#define repp(i,k, n) for(int i = (int)(k); i < (int)(n); i++)\n#define ALL(a) (a).begin(),(a).end()\nusing ll = long long;\nusing Pi = pair<int, int>;\nusing Pd = pair<double, double>;\nstruct Edge{int to; ll w; Edge(int to, ll w) : to(to), w(w) {}};\nusing Graph = vector<vector<Edge>>;\ntemplate<class T> bool chmax(T &a, const T &b) {if (a<b) { a=b; return 1;} return 0;}\ntemplate<class T> bool chmin(T &a, const T &b) {if (a>b) { a=b; return 1;} return 0;}\nconst int di[] = {-1,0,1,0};\nconst int dj[] = {0,-1,0,1};\nconst int di8[] = {-1, 0, 1, -1, 1, -1, 0, 1};\nconst int dj8[] = {1, 1, 1, 0, 0, -1, -1, -1};\n\nconstexpr int INF = 1e9 + 7;\n\ntemplate <typename T>\nclass BrokenDoor\n{\npublic:\n void getField(const int width, const int height)\n {\n width_m = width;\n height_m = height;\n worstShortestLength_m.resize(width_m * height_m, INF);\n graph_m.resize(width_m * height_m);\n rep(i, height_m){\n rep(j, width-1){\n int tmp; cin >> tmp;\n if(!tmp){\n graph_m[width_m * i + j].push_back(width*i + j + 1);\n graph_m[width_m * i + j + 1].push_back(width_m * i + j);\n }\n }\n if(i == height_m - 1) break;\n rep(j, width_m){\n int tmp; cin >> tmp;\n if(!tmp){\n graph_m[width_m * i + j].push_back(width * (i+1) + j);\n graph_m[width_m * (i+1) + j].push_back(width_m * i + j);\n }\n }\n }\n }\n\n T dp()\n {\n // とりあえず BFS を実行して各地点への最短距離を求める\n worstShortestLength_m[0] = execBFS(0, 0, make_pair(0, 0));\n // 各地点からゴールまでの最悪の場合の距離を更新していく\n queue<pair<int, int>> posQue;\n posQue.emplace(0, 0);\n worstShortestLength_m[0] = 0;\n while(!posQue.empty()){\n auto cPos = posQue.front().first;\n auto cLength = posQue.front().second;\n posQue.pop();\n for(const auto &to : graph_m[cPos]){\n if(chmin(worstShortestLength_m[to], execBFS(cPos, cLength, make_pair(cPos, to)))){\n posQue.emplace(to, cLength + 1);\n };\n }\n }\n return worstShortestLength_m[width_m * height_m - 1];\n }\nprivate:\n T execBFS(int start, T startLength, pair<int, int> brokenDoor)\n {\n vector<T> dist_tmp(width_m * height_m);\n // 全ての地点を未到達として初期化\n rep(i, width_m * height_m) dist_tmp[i] = INF;\n queue<int> que;\n que.push(start);\n dist_tmp[start] = startLength;\n while(!que.empty()){\n auto cPos = que.front();\n que.pop();\n for(const auto &to : graph_m[cPos]){\n if(brokenDoor.first == cPos && brokenDoor.second == to) continue;\n if(brokenDoor.first == to && brokenDoor.second == cPos) continue;\n if(chmin(dist_tmp[to], dist_tmp[cPos] + 1)){\n que.push(to);\n };\n }\n }\n // chmax(worstShortestLength_m[start], dist_tmp[width_m * height_m - 1]);\n return max(worstShortestLength_m[start], dist_tmp[width_m * height_m - 1]);\n }\n int width_m;\n int height_m;\n vector<vector<int>> graph_m;\n //vector<T> dist_m;\n vector<T> worstShortestLength_m;\n};\n\nclass Solver \n{\npublic:\n void solve()\n {\n int h, w;\n while(cin >> h >> w && h != 0){\n auto bd = make_unique<BrokenDoor<int>>();\n bd->getField(w, h);\n auto ans = bd->dp();\n if(ans != INF) cout << ans << endl;\n else cout << -1 << endl;\n }\n }\n};\nint main()\n{\n auto solver = make_shared<Solver>();\n solver->solve();\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 3412, "score_of_the_acc": -0.1947, "final_rank": 3 }, { "submission_id": "aoj_1178_6144686", "code_snippet": "//https://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=1178&lang=jp\n/* スタート地点からの距離が小さい地点から順に「その地点に隣接するドアが一つ壊れた場合の\n最短距離」を決めていく。これを決める際、その地点にたどり着く前の地点の値との max を取れば\n順に求めていくことができる。ある種の dp と言えるだろうか。*/\n\n#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n#define repp(i,k, n) for(int i = (int)(k); i < (int)(n); i++)\n#define ALL(a) (a).begin(),(a).end()\nusing ll = long long;\nusing Pi = pair<int, int>;\nusing Pd = pair<double, double>;\nstruct Edge{int to; ll w; Edge(int to, ll w) : to(to), w(w) {}};\nusing Graph = vector<vector<Edge>>;\ntemplate<class T> bool chmax(T &a, const T &b) {if (a<b) { a=b; return 1;} return 0;}\ntemplate<class T> bool chmin(T &a, const T &b) {if (a>b) { a=b; return 1;} return 0;}\nconst int di[] = {-1,0,1,0};\nconst int dj[] = {0,-1,0,1};\nconst int di8[] = {-1, 0, 1, -1, 1, -1, 0, 1};\nconst int dj8[] = {1, 1, 1, 0, 0, -1, -1, -1};\n\nconstexpr int INF = 1e9 + 7;\n\ntemplate <typename T>\nclass BrokenDoor\n{\npublic:\n void getField(const int width, const int height)\n {\n width_m = width;\n height_m = height;\n worstShortestLength_m.resize(width_m * height_m, INF);\n graph_m.resize(width_m * height_m);\n rep(i, height_m){\n rep(j, width-1){\n int tmp; cin >> tmp;\n if(!tmp){\n graph_m[width_m * i + j].push_back(width*i + j + 1);\n graph_m[width_m * i + j + 1].push_back(width_m * i + j);\n }\n }\n if(i == height_m - 1) break;\n rep(j, width_m){\n int tmp; cin >> tmp;\n if(!tmp){\n graph_m[width_m * i + j].push_back(width * (i+1) + j);\n graph_m[width_m * (i+1) + j].push_back(width_m * i + j);\n }\n }\n }\n }\n\n T dp()\n {\n // とりあえず BFS を実行して各地点への最短距離を求める\n worstShortestLength_m[0] = execBFS(0, 0, make_pair(0, 0));\n // 各地点からゴールまでの最悪の場合の距離を更新していく\n queue<pair<int, int>> posQue;\n posQue.emplace(0, 0);\n worstShortestLength_m[0] = 0;\n while(!posQue.empty()){\n auto cPos = posQue.front().first;\n auto cLength = posQue.front().second;\n posQue.pop();\n for(const auto &to : graph_m[cPos]){\n if(chmin(worstShortestLength_m[to], execBFS(cPos, cLength, make_pair(cPos, to)))){\n posQue.emplace(to, cLength + 1);\n };\n }\n }\n return worstShortestLength_m[width_m * height_m - 1];\n }\nprivate:\n T execBFS(int start, T startLength, pair<int, int> brokenDoor)\n {\n vector<T> dist_tmp(width_m * height_m);\n // 全ての地点を未到達として初期化\n rep(i, width_m * height_m) dist_tmp[i] = INF;\n queue<int> que;\n que.push(start);\n dist_tmp[start] = startLength;\n while(!que.empty()){\n auto cPos = que.front();\n que.pop();\n for(const auto &to : graph_m[cPos]){\n if(brokenDoor.first == cPos && brokenDoor.second == to) continue;\n if(brokenDoor.first == to && brokenDoor.second == cPos) continue;\n if(chmin(dist_tmp[to], dist_tmp[cPos] + 1)){\n que.push(to);\n };\n }\n }\n // 最初の最短距離の前計算の時は結果を保存\n //if(brokenDoor.first == 0 && brokenDoor.second == 0) dist_m = dist_tmp;\n chmax(worstShortestLength_m[start], dist_tmp[width_m * height_m - 1]);\n return worstShortestLength_m[start];\n }\n int width_m;\n int height_m;\n vector<vector<int>> graph_m;\n //vector<T> dist_m;\n vector<T> worstShortestLength_m;\n};\n\nclass Solver \n{\npublic:\n void solve()\n {\n int h, w;\n while(cin >> h >> w && h != 0){\n auto bd = make_unique<BrokenDoor<int>>();\n bd->getField(w, h);\n auto ans = bd->dp();\n if(ans != INF) cout << ans << endl;\n else cout << -1 << endl;\n }\n }\n};\nint main()\n{\n auto solver = make_shared<Solver>();\n solver->solve();\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 3384, "score_of_the_acc": -0.1835, "final_rank": 2 }, { "submission_id": "aoj_1178_6138288", "code_snippet": "#include <iostream>\n#include <queue>\n#include <vector>\nusing namespace std;\n\n// DOWN, RIGHT, UP, LEFT\nconst int dx[] = {1, 0, -1, 0};\nconst int dy[] = {0, 1, 0, -1};\nconst int H_MAX = 33;\nconst int W_MAX = 33;\nconst int MOVE_MAX = H_MAX * W_MAX;\nconst int PROHIBITED = -1;\nconst int DIST_MAX = 1e5;\n\nint h, w;\nint g[H_MAX][W_MAX][4];\nint dp[MOVE_MAX][H_MAX][W_MAX];\n\nvector<vector<int>> bfs() {\n vector<vector<int>> dist(h, vector<int>(w, DIST_MAX));\n queue<pair<int, int>> q;\n q.push({h-1, w-1});\n dist[h-1][w-1] = 0;\n while(!q.empty()) {\n auto now = q.front(); q.pop();\n int x = now.first, y = now.second;\n for(int i = 0; i < 4; i++) {\n int nx = x + dx[i], ny = y + dy[i];\n if(g[x][y][i] != PROHIBITED && \n dist[nx][ny] == DIST_MAX) {\n dist[nx][ny] = dist[x][y] + 1;\n q.push({nx, ny});\n }\n }\n }\n return dist;\n}\n\nint solve() {\n for(int i = 0; i < w; i++) {\n g[h-1][i][0] = PROHIBITED;\n g[0][i][2] = PROHIBITED;\n }\n for(int i = 0; i < h; i++) {\n g[i][w-1][1] = PROHIBITED;\n g[i][0][3] = PROHIBITED;\n }\n for(int i = 0; i < h; i++) {\n for(int j = 0; j < w-1; j++) {\n int x; cin >> x;\n g[i][j][1] = g[i][j+1][3] = x == 1 ? PROHIBITED : 0;\n }\n if(i != h-1) {\n for(int j = 0; j < w; j++) {\n int x; cin >> x;\n g[i][j][0] = g[i+1][j][2] = x == 1 ? PROHIBITED : 0;\n }\n }\n }\n \n for(int i = 0; i < h; i++) {\n for(int j = 0; j < w; j++) {\n for(int k = 0; k < 2; k++) {\n if(g[i][j][k] == PROHIBITED) continue;\n g[i][j][k] = PROHIBITED;\n if(k == 0) g[i+1][j][2] = PROHIBITED;\n else g[i][j+1][3] = PROHIBITED;\n auto &&dist = bfs();\n g[i][j][k] = dist[i][j];\n if(k == 0) g[i+1][j][2] = dist[i+1][j];\n else g[i][j+1][3] = dist[i][j+1];\n }\n }\n }\n \n for(int i = 0; i < h; i++) fill(dp[0][i], dp[0][i] + w, DIST_MAX);\n dp[0][0][0] = 0;\n for(int i = 1; i < MOVE_MAX; i++) {\n for(int j = 0; j < h; j++) fill(dp[i][j], dp[i][j] + w, DIST_MAX);\n for(int j = 0; j < h; j++) {\n for(int k = 0; k < w; k++) {\n for(int l = 0; l < 4; l++) {\n if(g[j][k][l] != PROHIBITED) {\n dp[i][j][k] = min(\n max(g[j+dx[l]][k+dy[l]][l^2] + i-1,\n dp[i-1][j+dx[l]][k+dy[l]]),\n dp[i][j][k]\n );\n }\n }\n }\n }\n }\n int ans = DIST_MAX;\n for(int i = 0; i < MOVE_MAX; i++) {\n ans = min(ans, dp[i][h-1][w-1]);\n }\n return ans == DIST_MAX ? -1 : ans;\n}\n\nint main() {\n vector<int> ans;\n while(1) {\n cin >> h >> w;\n if(h == 0 && w == 0) break;\n ans.emplace_back(solve());\n }\n for(auto &i : ans) cout << i << endl;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 8120, "score_of_the_acc": -0.7699, "final_rank": 16 }, { "submission_id": "aoj_1178_6044437", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n#define all(x) (x).begin(),(x).end()\n#define fi first\n#define se second\n#define mp make_pair\n#define si(x) int(x.size())\nconst int mod=1000000007,MAX=35,INF=1<<29;\nvector<int> dh={0,1,0,-1},dw={1,0,-1,0};\nbool S[MAX][MAX][4];\nint dis[MAX][MAX][4];\nint dp[MAX][MAX];\n\nint main(){\n \n std::ifstream in(\"text.txt\");\n std::cin.rdbuf(in.rdbuf());\n cin.tie(0);\n ios::sync_with_stdio(false);\n \n while(1){\n int H,W;cin>>H>>W;\n if(H==0) break;\n memset(S,0,sizeof(S));\n for(int i=0;i<H;i++){\n for(int j=0;j<W-1;j++){\n int t;cin>>t;t^=1;\n S[i][j][0]=S[i][j+1][2]=t;\n }\n if(i<H-1){\n for(int j=0;j<W;j++){\n int t;cin>>t;t^=1;\n S[i][j][1]=S[i+1][j][3]=t;\n }\n }\n }\n \n for(int i=0;i<H;i++){\n for(int j=0;j<W;j++){\n for(int k=0;k<4;k++){\n if(S[i][j][k]==0){\n dis[i][j][k]=-INF;\n continue;\n }\n for(int h=0;h<H;h++) for(int w=0;w<W;w++) dp[h][w]=INF;\n dp[i][j]=0;\n queue<pair<int,int>> Q;\n Q.push(mp(i,j));\n \n while(!Q.empty()){\n auto u=Q.front();Q.pop();\n for(int d=0;d<4;d++){\n if(u.fi==i&&u.se==j&&k==d) continue;\n if(k==0){\n if(u.fi==i&&u.se==j+1&&d==2) continue;\n }\n if(k==1){\n if(u.fi==i+1&&u.se==j&&d==3) continue;\n }\n if(k==2){\n if(u.fi==i&&u.se==j-1&&d==0) continue;\n }\n if(k==3){\n if(u.fi==i-1&&u.se==j&&d==1) continue;\n }\n int toh=u.fi+dh[d],tow=u.se+dw[d];\n if(toh<0||toh>=H||tow<0||tow>=W||S[u.fi][u.se][d]==0) continue;\n if(chmin(dp[toh][tow],dp[u.fi][u.se]+1)) Q.push(mp(toh,tow));\n }\n }\n dis[i][j][k]=dp[H-1][W-1];\n }\n }\n }\n \n //for(int i=0;i<H;i++) for(int j=0;j<W;j++) for(int k=0;k<4;k++) cout<<i<<\" \"<<j<<\" \"<<k<<\" \"<<dis[i][j][k]<<endl;\n \n int left=0,right=1805;\n while(right-left>1){\n int mid=(left+right)/2;\n for(int h=0;h<H;h++) for(int w=0;w<W;w++) dp[h][w]=INF;\n dp[0][0]=0;\n queue<pair<int,int>> Q;\n Q.push(mp(0,0));\n while(!Q.empty()){\n auto u=Q.front();Q.pop();\n int d=dp[u.fi][u.se];\n for(int k=0;k<4;k++){\n if(S[u.fi][u.se][k]==0) continue;\n int toh=u.fi+dh[k],tow=u.se+dw[k];\n if(toh<0||toh>=H||tow<0||tow>=W) continue;\n int ma=-INF;\n for(int x=0;x<4;x++){\n if((k^x)==2) continue;\n chmax(ma,dis[toh][tow][x]);\n }\n if(d+1+ma<=mid){\n if(chmin(dp[toh][tow],d+1)) Q.push(mp(toh,tow));\n }\n }\n }\n \n if(dp[H-1][W-1]<=mid) right=mid;\n else left=mid;\n }\n \n if(right==1805) cout<<-1<<\"\\n\";\n else cout<<right<<\"\\n\";\n }\n}", "accuracy": 1, "time_ms": 710, "memory_kb": 3416, "score_of_the_acc": -0.548, "final_rank": 10 }, { "submission_id": "aoj_1178_6009494", "code_snippet": "//#pragma GCC optimize(\"O3\")\n//#pragma GCC optimize(\"unroll-loops\")\n#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<ciso646>\n#include<random>\n#include<map>\n#include<set>\n#include<bitset>\n#include<stack>\n#include<unordered_map>\n#include<unordered_set>\n#include<utility>\n#include<cassert>\n#include<complex>\n#include<numeric>\n#include<array>\nusing namespace std;\n\n//#define int long long\ntypedef long long ll;\n\ntypedef unsigned long long ul;\ntypedef unsigned int ui;\nconstexpr ll mod = 998244353;\nconst ll INF = mod * mod;\ntypedef pair<int, int>P;\n\n#define rep(i,n) for(int i=0;i<n;i++)\n#define per(i,n) for(int i=n-1;i>=0;i--)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define per1(i,n) for(int i=n;i>=1;i--)\n#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)\n#define all(v) (v).begin(),(v).end()\ntypedef pair<ll, ll> LP;\ntypedef long double ld;\ntypedef pair<ld, ld> LDP;\nconst ld eps = 1e-8;\nconst ld pi = acosl(-1.0);\n\nll mod_pow(ll x, ll n, ll m = mod) {\n\tif (n < 0) {\n\t\tll res = mod_pow(x, -n, m);\n\t\treturn mod_pow(res, m - 2, m);\n\t}\n\tif (abs(x) >= m)x %= m;\n\tif (x < 0)x += m;\n\tll res = 1;\n\twhile (n) {\n\t\tif (n & 1)res = res * x % m;\n\t\tx = x * x % m; n >>= 1;\n\t}\n\treturn res;\n}\nstruct modint {\n\tll n;\n\tmodint() :n(0) { ; }\n\tmodint(ll m) :n(m) {\n\t\tif (n >= mod)n %= mod;\n\t\telse if (n < 0)n = (n % mod + mod) % mod;\n\t}\n\toperator int() { return n; }\n};\nbool operator==(modint a, modint b) { return a.n == b.n; }\nmodint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }\nmodint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }\nmodint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }\nmodint operator+(modint a, modint b) { return a += b; }\nmodint operator-(modint a, modint b) { return a -= b; }\nmodint operator*(modint a, modint b) { return a *= b; }\nmodint operator^(modint a, ll n) {\n\tif (n == 0)return modint(1);\n\tmodint res = (a * a) ^ (n / 2);\n\tif (n % 2)res = res * a;\n\treturn res;\n}\n\nll inv(ll a, ll p) {\n\treturn (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);\n}\nmodint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }\nmodint operator/=(modint& a, modint b) { a = a / b; return a; }\nconst int max_n = 1 << 2;\nmodint fact[max_n], factinv[max_n];\nvoid init_f() {\n\tfact[0] = modint(1);\n\tfor (int i = 0; i < max_n - 1; i++) {\n\t\tfact[i + 1] = fact[i] * modint(i + 1);\n\t}\n\tfactinv[max_n - 1] = modint(1) / fact[max_n - 1];\n\tfor (int i = max_n - 2; i >= 0; i--) {\n\t\tfactinv[i] = factinv[i + 1] * modint(i + 1);\n\t}\n}\nmodint comb(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[b] * factinv[a - b];\n}\nmodint combP(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[a - b];\n}\n\nint dx[4] = { 1,0,-1,0 };\nint dy[4] = { 0,-1,0,1 };\n\nll gcd(ll a, ll b) {\n\twhile (b) {\n\t\tll r = a % b; a = b; b = r;\n\t}\n\treturn a;\n}\n\nbool b[65][35];\nint dist[65][35][35][35];\n\nint val[35][35];\nint h, w;\nvoid solve() {\n\trep(i, 2 * h - 1) {\n\t\tif (i % 2 == 0)rep(j, w - 1)cin >> b[i][j];\n\t\telse rep(j, w)cin >> b[i][j];\n\t}\n\tauto trans = [&](int i, int j, int d)->P {\n\t\tif (d == 0) {\n\t\t\treturn { 2 * i + 1,j };\n\t\t}\n\t\telse if (d == 1) {\n\t\t\treturn { 2 * i,j-1 };\n\t\t}\n\t\telse if (d == 2) {\n\t\t\treturn { 2 * i - 1,j };\n\t\t}\n\t\telse {\n\t\t\treturn { 2 * i,j };\n\t\t}\n\t};\n\tauto isin = [&](int x, int y) {\n\t\treturn x >= 0 && x < h&& y >= 0 && y < w;\n\t};\n\trep(i, 2 * h - 1) {\n\t\trep(j, w) {\n\t\t\tif (j == w - 1 && i % 2 == 0)continue;\n\t\t\trep(x, h)rep(y, w) {\n\t\t\t\tdist[i][j][x][y] = mod;\n\t\t\t}\n\t\t\tdist[i][j][h - 1][w - 1] = 0;\n\t\t\tqueue<P> q;\n\t\t\tq.push({ h - 1,w - 1 });\n\t\t\twhile (!q.empty()) {\n\t\t\t\tP p = q.front(); q.pop();\n\t\t\t\tint cd = dist[i][j][p.first][p.second];\n\t\t\t\trep(d, 4) {\n\t\t\t\t\tint nx = p.first + dx[d];\n\t\t\t\t\tint ny = p.second + dy[d];\n\t\t\t\t\tif (!isin(nx, ny))continue;\n\t\t\t\t\tP z = trans(p.first, p.second, d);\n\t\t\t\t\tif (b[z.first][z.second] || z == P{i, j})continue;\n\t\t\t\t\tif (dist[i][j][nx][ny] > cd + 1) {\n\t\t\t\t\t\tdist[i][j][nx][ny] = cd + 1;\n\t\t\t\t\t\tq.push({ nx,ny });\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\trep(i, h)rep(j, w) {\n\t\tval[i][j] = mod;\n\t}\n\tval[h - 1][w - 1] = 0;\n\trep(_, h* w) {\n\t\trep(i, h)rep(j, w) {\n\t\t\trep(d, 4) {\n\t\t\t\tint nx = i + dx[d];\n\t\t\t\tint ny = j + dy[d];\n\t\t\t\tif (!isin(nx, ny))continue;\n\t\t\t\tP z = trans(i, j, d);\n\t\t\t\tif (b[z.first][z.second])continue;\n\t\t\t\tint cost = max(val[nx][ny] + 1, dist[z.first][z.second][i][j]);\n\t\t\t\tval[i][j] = min(val[i][j], cost);\n\t\t\t}\n\t\t}\n\t}\n\t/*rep(i, h) {\n\t\trep(j, w) {\n\t\t\tcout << val[i][j] << \" \";\n\t\t}cout << \"\\n\";\n\t}*/\n\tint ans = val[0][0];\n\tif (ans >= mod)cout << -1 << \"\\n\";\n\telse cout << ans << \"\\n\";\n}\n\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\tcout << fixed << setprecision(8);\n\t//init_f();\n\t//init();\n\t//int t; cin >> t; rep(i, t)\n\twhile(cin>>h>>w,h)\n\t\tsolve();\n\treturn 0;\n}", "accuracy": 1, "time_ms": 700, "memory_kb": 13340, "score_of_the_acc": -1.5042, "final_rank": 19 }, { "submission_id": "aoj_1178_5969172", "code_snippet": "#pragma region Macros\n#include <bits/stdc++.h>\nusing namespace std;\ntemplate <class T> inline bool chmax(T &a, T b) {\n if(a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <class T> inline bool chmin(T &a, T b) {\n if(a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\n#ifdef DEBUG\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << '(' << p.first << ',' << p.second << ')';\n return os;\n}\ntemplate <class T> ostream &operator<<(ostream &os, const vector<T> &v) {\n os << '{';\n for(int i = 0; i < (int)v.size(); i++) {\n if(i) { os << ','; }\n os << v[i];\n }\n os << '}';\n return os;\n}\nvoid debugg() { cerr << endl; }\ntemplate <class T, class... Args>\nvoid debugg(const T &x, const Args &... args) {\n cerr << \" \" << x;\n debugg(args...);\n}\n#define debug(...) \\\n cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"]: \", debugg(__VA_ARGS__)\n#define dump(x) cerr << __LINE__ << \" \" << #x << \" = \" << (x) << endl\n#else\n#define debug(...) (void(0))\n#define dump(x) (void(0))\n#endif\n\nstruct Setup {\n Setup() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(15);\n }\n} __Setup;\n\nusing ll = long long;\n#define OVERLOAD3(_1, _2, _3, name, ...) name\n#define ALL(v) (v).begin(), (v).end()\n#define RALL(v) (v).rbegin(), (v).rend()\n#define REP1(i, n) for(int i = 0; i < (n); i++)\n#define REP2(i, a, b) for(int i = (a); i < int(b); i++)\n#define REP(...) OVERLOAD3(__VA_ARGS__, REP2, REP1)(__VA_ARGS__)\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\nconst int INF = 1 << 29;\nconst ll LLINF = 1LL << 60;\nconstexpr int MOD = 1000000007;\nconstexpr int MOD2 = 998244353;\nconst int dx[4] = {1, 0, -1, 0};\nconst int dy[4] = {0, 1, 0, -1};\n\nvoid Case(int i) { cout << \"Case #\" << i << \": \"; }\nint popcount(int x) { return __builtin_popcount(x); }\nll popcount(ll x) { return __builtin_popcountll(x); }\n#pragma endregion Macros\n\nenum directions {\n D, R, U, L\n};\n\nbool solve() {\n int H, W;\n cin >> H >> W;\n if(H == 0 and W == 0) return false;\n vector walls(H, vector(W, vector<bool>(4, false)));\n vector<vector<int>> tate(H-1, vector<int>(W));\n REP(i, 2*H-1) {\n if(i % 2 == 0) {\n vector<int> v(W-1);\n REP(j, W-1) cin >> v[j];\n int r = i/2;\n REP(j, W) {\n walls[r][j][R] = (j < W-1 ? v[j] : 1);\n walls[r][j][L] = (j > 0 ? v[j-1] : 1);\n }\n } else {\n REP(j, W) cin >> tate[i/2][j];\n }\n }\n REP(i, H) REP(j, W) {\n walls[i][j][U] = (i > 0 ? tate[i-1][j] : 1);\n walls[i][j][D] = (i < H-1 ? tate[i][j] : 1);\n }\n\n auto bfs = [&](int sx, int sy, int gx, int gy) -> int {\n vector d(H, vector<int>(W, INF));\n d[sx][sy] = 0;\n queue<pair<int, int>> que;\n que.emplace(sx, sy);\n while(!que.empty()) {\n auto [x, y] = que.front();\n que.pop();\n REP(dir, 4) {\n int nx = x + dx[dir], ny = y + dy[dir];\n if(nx < 0 or nx >= H or ny < 0 or ny >= W) continue;\n bool ok = true;\n if(walls[x][y][dir]) continue;\n if(d[nx][ny] > d[x][y] + 1) {\n d[nx][ny] = d[x][y] + 1;\n que.emplace(nx, ny);\n }\n }\n }\n return d[gx][gy];\n };\n\n vector dist(H, vector(W, vector(4, INF)));\n\n REP(sx, H) REP(sy, W) REP(dir, 4) {\n if(walls[sx][sy][dir]) continue;\n walls[sx][sy][dir] = 1;\n dist[sx][sy][dir] = bfs(sx, sy, H-1, W-1); \n walls[sx][sy][dir] = 0;\n }\n\n int ok = INF, ng = -1;\n while(ok - ng > 1) {\n int mid = (ok + ng) / 2;\n vector d(H, vector<int>(W, INF));\n d[0][0] = 0;\n queue<pair<int, int>> que;\n que.emplace(0, 0);\n while(que.size()) {\n auto [x, y] = que.front();\n que.pop();\n REP(dir, 4) {\n if(dist[x][y][dir] + d[x][y] > mid) continue;\n int nx = x + dx[dir], ny = y + dy[dir];\n if(nx < 0 or nx >= H or ny < 0 or ny >= W) continue;\n if(d[nx][ny] > d[x][y] + 1) {\n d[nx][ny] = d[x][y] + 1;\n que.emplace(nx, ny);\n }\n }\n }\n (d[H-1][W-1] < INF ? ok : ng) = mid;\n }\n if(ok == INF) ok = -1;\n cout << ok << '\\n';\n \n return true;\n}\n\nint main() {\n while(solve());\n}", "accuracy": 1, "time_ms": 480, "memory_kb": 3464, "score_of_the_acc": -0.3594, "final_rank": 9 }, { "submission_id": "aoj_1178_5968355", "code_snippet": "#pragma GCC tag(\"avx2\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\nusing namespace std;\n#define DEBUG\n#ifdef DEBUG\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << '(' << p.first << ',' << p.second << ')';\n return os;\n}\ntemplate <class T> ostream &operator<<(ostream &os, const vector<T> &v) {\n os << '{';\n for(int i = 0; i < (int)v.size(); i++) {\n if(i) { os << ','; }\n os << v[i];\n }\n os << '}';\n return os;\n}\nvoid debugg() { cerr << endl; }\ntemplate <class T, class... Args>\nvoid debugg(const T &x, const Args &... args) {\n cerr << \" \" << x;\n debugg(args...);\n}\n#define debug(...) \\\n cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"]: \", debugg(__VA_ARGS__)\n#define dump(x) cerr << __LINE__ << \" \" << #x << \" = \" << (x) << endl\n#else\n#define debug(...) (void(0))\n#define dump(x) (void(0))\n#endif\nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vl;\ntypedef vector<vl> vvl;\ntypedef vector<char> vc;\ntypedef vector<string> vs;\ntypedef vector<bool> vb;\ntypedef vector<double> vd;\ntypedef pair<ll,ll> P;\ntypedef pair<int,int> pii;\ntypedef vector<P> vpl;\ntypedef tuple<ll,ll,ll> tapu;\n#define rep(i,n) for(int i=0; i<(n); i++)\n#define REP(i,a,b) for(int i=(a); i<(b); i++)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\ntemplate<typename T1,typename T2> inline bool chmin(T1 &a,T2 b){\n\tif(a>b){\n\t\ta = b; return true;\n\t}\n\telse return false;\n}\ntemplate<typename T1,typename T2> inline bool chmax(T1 &a,T2 b){\n\tif(a<b){\n\t\ta = b; return true;\n\t}\n\telse return false;\n}\ntemplate<typename T> inline void print(T &a){\n int sz = a.size();\n for(auto itr = a.begin(); itr != a.end(); itr++){\n\t\tcout << *itr;\n sz--;\n if(sz) cout << \" \";\n\t}\n cout << \"\\n\";\n}\ntemplate<typename T1,typename T2> inline void print2(T1 a, T2 b){\n\tcout << a << \" \" << b << \"\\n\";\n}\ntemplate<typename T1,typename T2,typename T3> inline void print3(T1 a, T2 b, T3 c){\n\tcout << a << \" \" << b << \" \" << c << \"\\n\";\n}\nvoid mark() {cout << \"#\" << \"\\n\";}\nll pcount(ll x) {return __builtin_popcountll(x);}\n//#include <atcoder/maxflow>\n//using namespace atcoder;\nconst int inf = (1<<30)-1;\nconst ll linf = 1LL<<61;\nconst int MAX = 5050000;\nint dy[8] = {0,1,0,-1,1,-1,-1,1};\nint dx[8] = {-1,0,1,0,1,-1,1,-1};\nconst double pi = acos(-1);\nconst double eps = 1e-9;\n//const int mod = 1e9 + 7;\nconst int mod = 998244353;\n\nbool in(ll y, ll x, ll h, ll w){\n return 0 <= y && y < h && 0 <= x && x < w;\n}\n\nbool in2(ll y, ll x, ll h, ll w, ll dir){\n int Y = y + dy[dir];\n int X = x + dx[dir];\n return 0 <= Y && Y < h && 0 <= X && X < w;\n}\n\nint main(){\n while(1){\n int h,w; cin >> h >> w;\n if(!h) break;\n vector<vvl> a(h,vvl(w,vl(4)));\n rep(i,h){\n rep(j,w-1){\n int x; cin >> x;\n a[i][j][2] = x;\n a[i][j+1][0] = x;\n }\n if(i<h-1){\n rep(j,w){\n int x; cin >> x;\n a[i][j][1] = x;\n a[i+1][j][3] = x;\n }\n }\n }\n vvl d2(h,vl(w,inf));\n auto calc = [&](int sy, int sx) -> int {\n rep(i,h) rep(j,w) d2[i][j] = inf;\n d2[sy][sx] = 0;\n queue<P> q;\n q.emplace(sy,sx);\n while(!q.empty()){\n P p = q.front(); q.pop();\n int y = p.first, x = p.second;\n rep(i,4){\n if(a[y][x][i]) continue;\n int ny = y + dy[i];\n int nx = x + dx[i];\n if(!in(ny,nx,h,w)) continue;\n if(d2[ny][nx] == inf){\n d2[ny][nx] = d2[y][x] + 1;\n q.emplace(ny,nx);\n }\n }\n }\n return d2[h-1][w-1];\n };\n vector<vvl> precalc(h,vvl(w,vl(4,inf)));\n rep(i,h) rep(j,w) rep(k,4){\n if(a[i][j][k]) continue;\n if(!in2(i,j,h,w,k)) continue;\n a[i][j][k] = 1;\n precalc[i][j][k] = calc(i,j);\n a[i][j][k] = 0;\n }\n\n int ok = inf, ng = 0;\n while(ok-ng > 1){\n int mid = (ok+ng) / 2;\n vvl d(h,vl(w,inf));\n d[0][0] = 0;\n queue<P> q;\n q.emplace(0,0);\n while(!q.empty()){\n P p = q.front(); q.pop();\n int y = p.first, x = p.second;\n //debug(mid,y,x,precalc[y][x]);\n bool f = true;\n rep(i,4){\n if(a[y][x][i]) continue;\n if(!in2(y,x,h,w,i)) continue;\n if(d[y][x] + precalc[y][x][i] > mid) f = false;\n }\n if(f){\n rep(i,4){\n if(a[y][x][i]) continue;\n int ny = y + dy[i];\n int nx = x + dx[i];\n if(!in(ny,nx,h,w)) continue;\n if(d[ny][nx] == inf){\n d[ny][nx] = d[y][x] + 1;\n q.emplace(ny,nx);\n }\n }\n }\n }\n if(d[h-1][w-1] <= mid) ok = mid;\n else ng = mid;\n }\n if(ok == inf) ok = -1;\n cout << ok << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 450, "memory_kb": 3608, "score_of_the_acc": -0.3482, "final_rank": 8 }, { "submission_id": "aoj_1178_5967435", "code_snippet": "#pragma GCC target(\"avx\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n#define endl \"\\n\"\n#define rep(i,N) for(int i=0;i<N;++i)\ntemplate<class T,class E> ostream& operator<<(ostream& os,const pair<T,E>& p){return os<<\"(\"<<p.first<<\",\"<<p.second<<\")\";}\ntemplate<class T> ostream& operator<<(ostream& os,const vector<T>& v){\n os<<\"{\";bool f=false;\n for(auto& x:v){if(f)os<<\",\";os<<x;f=true;}\n os<<\"}\";\n return os;\n}\ntemplate<class T> ostream& operator<<(ostream& os,const set<T>& v){\n os<<\"{\";bool f=false;\n for(auto& x:v){if(f)os<<\",\";os<<x;f=true;}\n os<<\"}\";\n return os;\n}\ntemplate<class T> ostream& operator<<(ostream& os,const multiset<T>& v){\n os<<\"{\";bool f=false;\n for(auto& x:v){if(f)os<<\",\";os<<x;f=true;}\n os<<\"}\";\n return os;\n}\ntemplate<class T,class E> ostream& operator<<(ostream& os,const map<T,E>& v){\n os<<\"{\";bool f=false;\n for(auto& x:v){if(f)os<<\",\";os<<x;f=true;}\n os<<\"}\";\n return os;\n}\ntemplate<class T> inline bool chmax(T& a,const T b){bool x=a<b;if(x)a=b;return x;}\ntemplate<class T> inline bool chmin(T& a,const T b){bool x=a>b;if(x)a=b;return x;}\n#ifdef DEBUG\nvoid debugg(){cout<<endl;}\ntemplate<class T,class... Args>void debugg(const T& x,const Args&... args){cout<<\" \"<<x;debugg(args...);}\n#define debug(...) cout<<__LINE__<<\" [\"<<#__VA_ARGS__<<\"]:\",debugg(__VA_ARGS__)\n#else\n#define debug(...) (void(0))\n#endif\n//LDRU\nconstexpr int dx[4]={1,0,-1,0};\nconstexpr int dy[4]={0,1,0,-1};\nconstexpr int inf=1<<20;\n\nint H,W;\n//dists[x][y][k]:地点(x,y)で方向kに壁があったときスタート地点から(x,y)に進む最短距離\n//distg[x][y][k]:地点(x,y)で方向kに壁があったとき(x,y)からゴール地点に進む最短距離\nint dists[30][30][4],distg[30][30][4];\nbool moveok[30][30][4];\nvoid input(){\n int i=0,f=0,x;\n rep(tmp,H*2-1){\n if(f){\n //縦方向 (i,j)->(i+1,j)\n rep(j,W){\n cin>>x;\n moveok[i][j][0]=moveok[i+1][j][2]=!x;\n }\n }else{\n //横方向 (i,j)->(i,j+1)\n rep(j,W-1){\n cin>>x;\n moveok[i][j][1]=moveok[i][j+1][3]=!x;\n }\n }\n i+=f;\n f^=1;\n }\n //進んじゃダメ\n rep(i,H)rep(j,W)rep(k,4)if(i+dx[k]<0||i+dx[k]>=H||j+dy[k]<0||j+dy[k]>=W)moveok[i][j][k]=false;\n}\n//BFS用配列\nint dist[30][30];\n//dists,distgを計算する\nvoid precalc(){\n rep(i,H)rep(j,W)rep(k,4){\n if(!moveok[i][j][k]){\n dists[i][j][k]=distg[i][j][k]=inf;\n continue;\n }\n moveok[i][j][k]=moveok[i+dx[k]][j+dy[k]][k^2]=false;\n rep(x,H)rep(y,W)dist[x][y]=inf;\n queue<tuple<int,int,int>> que;\n que.emplace(0,i,j);\n while(!que.empty()){\n auto[d,x,y]=que.front();que.pop();\n if(!chmin(dist[x][y],d))continue;\n rep(k,4)if(moveok[x][y][k])que.emplace(d+1,x+dx[k],y+dy[k]);\n }\n dists[i][j][k]=dist[0][0];\n distg[i][j][k]=dist[H-1][W-1];\n moveok[i][j][k]=moveok[i+dx[k]][j+dy[k]][k^2]=true;\n }\n}\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n while(1){\n cin>>H>>W;\n if(H+W==0)break;\n rep(i,H)rep(j,W)rep(k,4)dists[i][j][k]=distg[i][j][k]=0;\n input();\n precalc();\n int ok=inf,ng=0;\n while(ok-ng>1){\n int mid=(ok+ng)/2;\n rep(i,H)rep(j,W)dist[i][j]=inf;\n queue<tuple<int,int,int>> que;\n que.emplace(0,0,0);\n while(!que.empty()){\n auto[d,x,y]=que.front();que.pop();\n if(!chmin(dist[x][y],d))continue;\n //ここがポイント、dists[x][y]+distg[x][y]<=midではマズいことになる\n rep(k,4)if(moveok[x][y][k]&&dist[x][y]+distg[x][y][k]<=mid){\n que.emplace(d+1,x+dx[k],y+dy[k]);\n }\n }\n if(dist[H-1][W-1]!=inf)ok=mid;\n else ng=mid;\n }\n if(ok==inf)ok=-1;\n cout<<ok<<endl;\n }\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 3396, "score_of_the_acc": -0.2603, "final_rank": 7 }, { "submission_id": "aoj_1178_5967407", "code_snippet": "#pragma GCC target(\"avx\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n#define endl \"\\n\"\n#define rep(i,N) for(int i=0;i<N;++i)\ntemplate<class T,class E> ostream& operator<<(ostream& os,const pair<T,E>& p){return os<<\"(\"<<p.first<<\",\"<<p.second<<\")\";}\ntemplate<class T> ostream& operator<<(ostream& os,const vector<T>& v){\n os<<\"{\";bool f=false;\n for(auto& x:v){if(f)os<<\",\";os<<x;f=true;}\n os<<\"}\";\n return os;\n}\ntemplate<class T> ostream& operator<<(ostream& os,const set<T>& v){\n os<<\"{\";bool f=false;\n for(auto& x:v){if(f)os<<\",\";os<<x;f=true;}\n os<<\"}\";\n return os;\n}\ntemplate<class T> ostream& operator<<(ostream& os,const multiset<T>& v){\n os<<\"{\";bool f=false;\n for(auto& x:v){if(f)os<<\",\";os<<x;f=true;}\n os<<\"}\";\n return os;\n}\ntemplate<class T,class E> ostream& operator<<(ostream& os,const map<T,E>& v){\n os<<\"{\";bool f=false;\n for(auto& x:v){if(f)os<<\",\";os<<x;f=true;}\n os<<\"}\";\n return os;\n}\ntemplate<class T> inline bool chmax(T& a,const T b){bool x=a<b;if(x)a=b;return x;}\ntemplate<class T> inline bool chmin(T& a,const T b){bool x=a>b;if(x)a=b;return x;}\n#ifdef DEBUG\nvoid debugg(){cout<<endl;}\ntemplate<class T,class... Args>void debugg(const T& x,const Args&... args){cout<<\" \"<<x;debugg(args...);}\n#define debug(...) cout<<__LINE__<<\" [\"<<#__VA_ARGS__<<\"]:\",debugg(__VA_ARGS__)\n#else\n#define debug(...) (void(0))\n#endif\n//LDRU\nconstexpr int dx[4]={1,0,-1,0};\nconstexpr int dy[4]={0,1,0,-1};\nconstexpr int inf=1<<20;\n\nint H,W;\nint dists[30][30][4],distg[30][30][4];\nbool moveok[30][30][4];\nvoid input(){\n int i=0,f=0,x;\n rep(tmp,H*2-1){\n if(f){\n //縦方向 (i,j)->(i+1,j)\n rep(j,W){\n cin>>x;\n moveok[i][j][0]=moveok[i+1][j][2]=!x;\n }\n }else{\n //横方向 (i,j)->(i,j+1)\n rep(j,W-1){\n cin>>x;\n moveok[i][j][1]=moveok[i][j+1][3]=!x;\n }\n }\n i+=f;\n f^=1;\n }\n //進んじゃダメ\n rep(i,H)rep(j,W)rep(k,4)if(i+dx[k]<0||i+dx[k]>=H||j+dy[k]<0||j+dy[k]>=W)moveok[i][j][k]=false;\n}\nint dist[30][30];\nvoid precalc(){\n rep(i,H)rep(j,W)rep(k,4){\n if(!moveok[i][j][k]){\n dists[i][j][k]=distg[i][j][k]=inf;\n continue;\n }\n moveok[i][j][k]=moveok[i+dx[k]][j+dy[k]][k^2]=false;\n rep(x,H)rep(y,W)dist[x][y]=inf;\n queue<tuple<int,int,int>> que;\n que.emplace(0,i,j);\n while(!que.empty()){\n auto[d,x,y]=que.front();que.pop();\n if(!chmin(dist[x][y],d))continue;\n rep(k,4)if(moveok[x][y][k])que.emplace(d+1,x+dx[k],y+dy[k]);\n }\n dists[i][j][k]=dist[0][0];\n distg[i][j][k]=dist[H-1][W-1];\n moveok[i][j][k]=moveok[i+dx[k]][j+dy[k]][k^2]=true;\n }\n}\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n while(1){\n cin>>H>>W;\n if(H+W==0)break;\n rep(i,H)rep(j,W)rep(k,4)dists[i][j][k]=distg[i][j][k]=0;\n input();\n precalc();\n int ok=inf,ng=0;\n while(ok-ng>1){\n int mid=(ok+ng)/2;\n rep(i,H)rep(j,W)dist[i][j]=inf;\n queue<tuple<int,int,int>> que;\n que.emplace(0,0,0);\n while(!que.empty()){\n auto[d,x,y]=que.front();que.pop();\n if(!chmin(dist[x][y],d))continue;\n rep(k,4)if(moveok[x][y][k]&&dist[x][y]+distg[x][y][k]<=mid){\n que.emplace(d+1,x+dx[k],y+dy[k]);\n }\n }\n if(dist[H-1][W-1]!=inf)ok=mid;\n else ng=mid;\n }\n if(ok==inf)ok=-1;\n cout<<ok<<endl;\n }\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 3380, "score_of_the_acc": -0.2588, "final_rank": 6 }, { "submission_id": "aoj_1178_5959035", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<cstring>\n#include<string>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<map>\n#include<queue>\n#include<deque>\n#include<iomanip>\n#include<tuple>\n#include<cassert>\n#include<set>\n#include<complex>\n#include<numeric>\n#include<functional>\n#include<unordered_map>\n#include<unordered_set>\nusing namespace std;\ntypedef long long int LL;\ntypedef pair<int,int> P;\ntypedef pair<LL,LL> LP;\nconst int INF=1<<30;\nconst LL MAX=1e9+7;\n\nvoid array_show(int *array,int array_n,char middle=' '){\n for(int i=0;i<array_n;i++)printf(\"%d%c\",array[i],(i!=array_n-1?middle:'\\n'));\n}\nvoid array_show(LL *array,int array_n,char middle=' '){\n for(int i=0;i<array_n;i++)printf(\"%lld%c\",array[i],(i!=array_n-1?middle:'\\n'));\n}\nvoid array_show(vector<int> &vec_s,int vec_n=-1,char middle=' '){\n if(vec_n==-1)vec_n=vec_s.size();\n for(int i=0;i<vec_n;i++)printf(\"%d%c\",vec_s[i],(i!=vec_n-1?middle:'\\n'));\n}\nvoid array_show(vector<LL> &vec_s,int vec_n=-1,char middle=' '){\n if(vec_n==-1)vec_n=vec_s.size();\n for(int i=0;i<vec_n;i++)printf(\"%lld%c\",vec_s[i],(i!=vec_n-1?middle:'\\n'));\n}\ntemplate<typename T> ostream& operator<<(ostream& os,const vector<T>& v1){\n int n=v1.size();\n for(int i=0;i<n;i++){\n if(i)os<<\" \";\n os<<v1[i];\n }\n return os;\n}\ntemplate<typename T1,typename T2> ostream& operator<<(ostream& os,const pair<T1,T2>& p){\n os<<p.first<<\" \"<<p.second;\n return os;\n}\ntemplate<typename T> istream& operator>>(istream& is,vector<T>& v1){\n int n=v1.size();\n for(int i=0;i<n;i++)is>>v1[i];\n return is;\n}\ntemplate<typename T1,typename T2> istream& operator>>(istream& is,pair<T1,T2>& p){\n is>>p.first>>p.second;\n return is;\n}\n\nnamespace sol{\n typedef vector<int> V1;\n typedef vector<V1> V2;\n typedef vector<V2> V3;\n typedef vector<V3> V4;\n typedef tuple<int,int,int> T;\n V2 vw;\n\n P mid(P a,P b){\n if(a>b)swap(a,b);\n if(a.first==b.first)return {2*a.first,a.second};\n return {2*a.first+1,a.second};\n }\n bool is_wall(P a,P b){\n P pa=mid(a,b);\n return vw[pa.first][pa.second];\n }\n\n void solve(){\n int n,m;\n int i,j,k;\n int a,b,c;\n int p,q,r;\n while(cin>>n>>m){\n if(n==0)return;\n vw.assign(2*n-1,vector<int>(m));\n for(i=0;i<2*n-1;i++){\n for(j=0;j<m-1+i%2;j++){\n cin>>vw[i][j];\n }\n }\n V4 dp1(2*n,V3(m,V2(n,V1(m,INF))));\n queue<P> q1;\n for(i=0;i<2*n-1;i++){\n for(j=0;j<m-1+i%2;j++){\n q1.push({n-1,m-1});\n for(k=0;!q1.empty();k++){\n for(p=q1.size();p>0;p--){\n P pa=q1.front();q1.pop();\n if(dp1[i][j][pa.first][pa.second]!=INF)continue;\n dp1[i][j][pa.first][pa.second]=k;\n for(q=-1;q<=1;q++){\n for(r=-1;r<=1;r++){\n if((q+r+2)%2==0)continue;\n int x=pa.first+q,y=pa.second+r;\n if(x<0 || y<0 || n<=x || m<=y)continue;\n if(is_wall(pa,{x,y}))continue;\n if(mid(pa,{x,y})==P(i,j))continue;\n q1.push({x,y});\n }\n }\n }\n }\n }\n }\n V2 dis(n,V1(m,INF));\n priority_queue<T,vector<T>,greater<T>> q2;\n q2.push({0,n-1,m-1});\n while(!q2.empty()){\n tie(a,b,c)=q2.top();q2.pop();\n if(dis[b][c]!=INF || a>=INF)continue;\n dis[b][c]=a;\n for(q=-1;q<=1;q++){\n for(r=-1;r<=1;r++){\n if((q+r+2)%2==0)continue;\n int x=b+q,y=c+r;\n if(x<0 || y<0 || n<=x || m<=y)continue;\n if(is_wall({b,c},{x,y}))continue;\n P pa=mid({b,c},{x,y});\n int cost=max(a+1,dp1[pa.first][pa.second][x][y]);\n q2.push({cost,x,y});\n }\n }\n }\n int s=dis[0][0];\n if(s>=INF)s=-1;\n cout<<s<<endl;\n }\n }\n}\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n sol::solve();\n}", "accuracy": 1, "time_ms": 1020, "memory_kb": 11212, "score_of_the_acc": -1.5663, "final_rank": 20 } ]
aoj_1179_cpp
Millennium A wise king declared a new calendar. "Tomorrow shall be the first day of the calendar, that is, the day 1 of the month 1 of the year 1. Each year consists of 10 months, from month 1 through month 10, and starts from a big month . A common year shall start with a big month, followed by small months and big months one after another. Therefore the first month is a big month, the second month is a small month, the third a big month, ..., and the 10th and last month a small one. A big month consists of 20 days and a small month consists of 19 days. However years which are multiples of three, that are year 3, year 6, year 9, and so on, shall consist of 10 big months and no small month." Many years have passed since the calendar started to be used. For celebration of the millennium day (the year 1000, month 1, day 1), a royal lottery is going to be organized to send gifts to those who have lived as many days as the number chosen by the lottery. Write a program that helps people calculate the number of days since their birthdate to the millennium day. Input The input is formatted as follows. n Y 1 M 1 D 1 Y 2 M 2 D 2 ... Y n M n D n Here, the first line gives the number of datasets as a positive integer n , which is less than or equal to 100. It is followed by n datasets. Each dataset is formatted in a line and gives three positive integers, Y i (< 1000), M i (≤ 10), and D i (≤ 20), that correspond to the year, month and day, respectively, of a person's birthdate in the king's calendar. These three numbers are separated by a space. Output For the birthdate specified in each dataset, print in a line the number of days from the birthdate, inclusive, to the millennium day, exclusive. Output lines should not contain any character other than this number. Sample Input 8 1 1 1 344 3 1 696 5 1 182 9 5 998 8 7 344 2 19 696 4 19 999 10 20 Output for the Sample Input 196470 128976 59710 160715 252 128977 59712 1
[ { "submission_id": "aoj_1179_10683989", "code_snippet": "#line 1 \"speedrun.cpp\"\n#include <bits/stdc++.h>\n#line 1 \"/home/ardririy/repos/cp-libs/libraries-cpp/input.hpp\"\n\n\n#line 6 \"/home/ardririy/repos/cp-libs/libraries-cpp/input.hpp\"\nusing namespace std;\nvector<long long> i64_vec_IN(int n) {vector<long long> res(n); for(int i=0; i<n; i++) { cin >> res[i]; } return res; }\nvector<string> str_vec_IN(int n) { vector<string> res(n); for(int i=0; i<n; i++) { cin >> res[i]; } return res; }\nvector<vector<int>> graph_IN(int n, int m) { vector<vector<int>> g(n); int u, v; for(int i=0; i<m; i++) { cin >> u >> v; u--; v--; g[u].emplace_back(v); g[v].emplace_back(u); } return g; }\nvector<vector<pair<int, long long>>> weighted_graph_IN(int n, int m) { vector<vector<pair<int, long long>>> g(n); int u, v; long long w; for(int i=0; i<m; i++) { cin >> u >> v >> w; u--; v--; g[u].push_back({v, w}); g[v].push_back({u, w}); } return g; }\n\n\n#line 3 \"speedrun.cpp\"\n\nusing namespace std;\n//using namespace atcoder;\n\n#ifdef ADRY\n#include <dbg.h>\n#else\n// DO NOTHING\n#define dbg(...)\n#endif\n\n\n#define all(v) v.begin(),v.end()\n#define resort(v) sort(v.rbegin(),v.rend())\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll=vector<ll>;\nusing vvll = vector<vector<ll>>;\nusing P = pair<ll,ll>;\nusing vp=vector<pair<ll, ll>>;\nusing djks=priority_queue<P, vp, greater<P>>;\n\nconst int inf=1ll<<30;\n#define mod10 (ll)1e9+7\n#define mod99 (ll)998244353\nconst double PI = acos(-1);\n\n#define rep(i,n) for (ll i=0;i<(n);++i)\n#define per(i,n) for(ll i=(n)-1;i>=0;--i)\n#define rep2(i,a,n) for (ll i=(a);i<(n);++i)\n#define per2(i,a,n) for (ll i=(n)-1;i>=(a);--i)\n\n\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n\nll dx[] = {1, 0, -1, 0, -1, 1, -1, 1};\nll dy[] = {0, 1, 0, -1, -1, 1, 1, -1};\n\nint solve() {\n int y, m, d; cin >> y >> m >> d;\n\n int cy = y;\n int cm = m;\n int cd = d;\n int ans = 0;\n while(true) {\n ans++;\n\n cd++;\n if(cy%3==0 || cm%2==1) {\n if(cd==21) cd=1, cm++;\n } else {\n if(cd==20) cd=1, cm++;\n }\n\n if(cm==11) cm = 1, cy++;\n if(cy==1000) break;\n }\n cout << ans << '\\n';\n\n return 0;\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n int t; cin >> t;\n while(t--)solve();\n //while(!solve());\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3392, "score_of_the_acc": -0.2641, "final_rank": 13 }, { "submission_id": "aoj_1179_10557094", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n int n; cin >> n;\n\n auto next_day = [&](int &y, int &m, int &d) -> void {\n d += 1;\n if(y % 3 == 0){\n if(d > 20){\n m += 1, d = 1;\n }\n }\n else if(m % 2 == 1 and d > 20 or m % 2 == 0 and d > 19){\n m += 1, d = 1;\n }\n if(m > 10){\n y += 1, m = 1;\n }\n };\n\n auto f = [&](int y, int m, int d) -> int {\n int ret = 0;\n while(y < 1000){\n ++ret;\n next_day(y, m, d);\n }\n return ret;\n };\n\n for(int i = 0; i < n; ++i){\n int Y, M, D; cin >> Y >> M >> D;\n cout << f(Y, M, D) << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3352, "score_of_the_acc": -0.0123, "final_rank": 6 }, { "submission_id": "aoj_1179_10092789", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint day(int Y, int M) {\n return Y % 3 == 0 ? 20 : M % 2 == 0 ? 19 : 20;\n}\n\nint Y = 1000, M = 10, D = 20;\nint memo[1010][11][22];\n\nint solve(int y, int m, int d) {\n if (memo[y][m][d] != -1) return memo[y][m][d];\n d++;\n if (d > day(y, m)) {\n d = 1;\n m++;\n }\n if (m > M) {\n m = 1;\n y++;\n }\n if (y == 1000) return 1;\n return solve(y, m, d) + 1;\n}\n\nint main() {\n for (int y = 0; y < Y; y++) {\n for (int m = 1; m <= M; m++) {\n for (int d = 1; d <= D; d++) {\n memo[y][m][d] = -1;\n }\n }\n }\n int T;\n cin >> T;\n while (T--) {\n int y, m, d;\n cin >> y >> m >> d;\n cout << solve(y, m, d) << '\\n';\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4356, "score_of_the_acc": -0.5576, "final_rank": 16 }, { "submission_id": "aoj_1179_9408607", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\n#define rep(i, a, b) for(ll i = a; i < b; ++i)\n#define rrep(i, a, b) for(ll i = a; i >= b; --i)\nconstexpr ll inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\nint main(void) {\n int n;\n cin >> n;\n vector<int> y(n), m(n), d(n);\n rep(i, 0, n) {\n cin >> y[i] >> m[i] >> d[i];\n int ans = 0;\n while(y[i] != 1000) {\n ans++;\n d[i]++;\n if(y[i] % 3 == 0) {\n if(d[i] == 21) {\n d[i] = 1;\n m[i]++;\n if(m[i] == 11) {\n m[i] = 1;\n y[i]++;\n }\n }\n } else {\n if(m[i] % 2 == 0) {\n if(d[i] == 20) {\n d[i] = 1;\n m[i]++;\n if(m[i] == 11) {\n m[i] = 1;\n y[i]++;\n }\n }\n } else {\n if(d[i] == 21) {\n d[i] = 1;\n m[i]++;\n if(m[i] == 11) {\n m[i] = 1;\n y[i]++;\n }\n }\n }\n }\n }\n assert(y[i] == 1000 and m[i] == 1 and d[i] == 1);\n cout << ans << '\\n';\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3352, "score_of_the_acc": -0.0123, "final_rank": 6 }, { "submission_id": "aoj_1179_9394530", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (n); i++)\nusing ll = long long;\n#define all(x) x.begin(), x.end()\ntemplate <class A, class B>\ninline bool chmin(A &a, const B &b) {\n return b < a && (a = b, true);\n}\ntemplate <class A, class B>\ninline bool chmax(A &a, const B &b) {\n return b > a && (a = b, true);\n}\n\nint solve() {\n int y, m, d;\n cin >> y >> m >> d;\n int ans = 0;\n while (y != 1000) {\n ans++;\n int dd = (y % 3 == 0 ? 20 : (m % 2 == 0 ? 19 : 20));\n if (d < dd) {\n d++;\n } else {\n d = 1;\n if (m < 10) {\n m++;\n } else {\n m = 1;\n y++;\n }\n }\n }\n cout << ans << '\\n';\n return 0;\n}\n\nint main() {\n int n;\n cin >> n;\n while (n--) solve();\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3444, "score_of_the_acc": -0.2664, "final_rank": 15 }, { "submission_id": "aoj_1179_9344053", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define all(x) (x).begin(),(x).end()\n#define eb emplace_back\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing vl = vector<long long>;\nusing vvl = vector<vector<long long>>; using vs = vector<string>;\nusing pl = pair<long long, long long>;\ntemplate <typename T> inline bool chmin(T& a, const T& b) {bool compare = a > b; if (a > b) a = b; return compare;}\ntemplate <typename T> inline bool chmax(T& a, const T& b) {bool compare = a < b; if (a < b) a = b; return compare;}\ntemplate<class T>using rp_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate <typename T> T gcd(T a, T b) {if (b == 0)return a; else return gcd(b, a % b);}\ntemplate <typename T> inline T lcm(T a, T b) {return a /gcd(a, b)*b;}\nconst ll INF = 1LL << 60;\nconst ld PI = acos(-1);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec);\ntemplate <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr);\ntemplate <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec);\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const pair<T, U> &pa);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec);\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa);\ntemplate <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp);\ntemplate <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp);\ntemplate <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl);\n\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec) { os << '['; for (auto v : vec) os << v << ','; os << ']'; return os; }\ntemplate <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr) { os << '['; for (auto v : arr) os << v << ','; os << ']'; return os; }\ntemplate <class... T> std::istream &operator>>(std::istream &is, std::tuple<T...> &tpl) { std::apply([&is](auto &&... args) { ((is >> args), ...);}, tpl); return is; }\ntemplate <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl) { os << '('; std::apply([&os](auto &&... args) { ((os << args << ','), ...);}, tpl); return os << ')'; }\ntemplate <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec) { os << \"deq[\"; for (auto v : vec) os << v << ','; os << ']'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa) { return os << '(' << pa.first << ',' << pa.second << ')'; }\ntemplate <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << \"=>\" << v.second << ','; os << '}'; return os; }\ntemplate <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp) { os << '{'; for (auto v : mp) os << v.first << \"=>\" << v.second << ','; os << '}'; return os; }\n#ifdef LOCAL\nconst string COLOR_RESET = \"\\033[0m\", BRIGHT_GREEN = \"\\033[1;32m\", BRIGHT_RED = \"\\033[1;31m\", BRIGHT_CYAN = \"\\033[1;36m\", NORMAL_CROSSED = \"\\033[0;9;37m\", RED_BACKGROUND = \"\\033[1;41m\", NORMAL_FAINT = \"\\033[0;2m\";\n#define dbg(x) std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << \" = \" << (x) << NORMAL_FAINT << \" (L\" << __LINE__ << \") \" << __FILE__ << COLOR_RESET << std::endl\n#define dbgif(cond, x) ((cond) ? std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << \" = \" << (x) << NORMAL_FAINT << \" (L\" << __LINE__ << \") \" << __FILE__ << COLOR_RESET << std::endl : std::cerr)\n#else\n#define dbg(x) ((void)0)\n#define dbgif(cond, x) ((void)0)\n#endif\nvoid solve();\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout<<fixed<<setprecision(15);\n int num_tc = 1;\n //cin >> num_tc;\n rep(tc,num_tc){\n //cout << \"Case #\" << tc+1 << \": \" ;// << endl;\n solve();\n }\n}\n//見切り発車で実装しては行けない.頭の中でコードが完全に出来上がるまで書き始めるな.\n#define si(A) (int)(A).size()\nvoid solve(){\n int N;cin>>N;\n while(N--){\n ll Y,M,D;cin>>Y>>M>>D;\n ll cnt = 0;\n while(true){\n if(Y==1000&&M==1&&D==1)break;\n cnt++;\n D++;\n if(Y%3==0){\n if(D==21)D=1,M++;\n if(M==11)M=1,Y++;\n }else{\n if(M%2==1&&D==21)D=1,M++;\n else if(M%2==0&&D==20)D=1,M++;\n if(M==11)M=1,Y++;\n }\n }\n dbg(\"OK\");\n cout<<cnt<<endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3340, "score_of_the_acc": -0.2617, "final_rank": 12 }, { "submission_id": "aoj_1179_9280622", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n int n; cin>>n;\n vector<vector<int>> days(n,vector<int>(3));\n for(int i=0;i<n;i++){\n for(int j=0;j<3;j++){\n cin>>days[i][j];\n }\n }\n for(int i=0;i<n;i++){\n int count=0;\n while(days[i][0]<1000){\n if(days[i][0]%3==0 || days[i][1]%2==1){\n //大の月\n int pd=days[i][2];\n days[i][2]=(pd+1)%21;\n if(days[i][2]==0) days[i][2]++;\n\n int pm=days[i][1];\n days[i][1]=(pm+(pd+1)/21)%11;\n if(days[i][1]==0) days[i][1]++;\n\n days[i][0]+=(pm+(pd+1)/21)/11;\n }\n else if(days[i][1]%2==0){\n //小の月\n int pd=days[i][2];\n days[i][2]=(pd+1)%20;\n if(days[i][2]==0) days[i][2]++;\n\n int pm=days[i][1];\n days[i][1]=(pm+(pd+1)/20)%11;\n if(days[i][1]==0) days[i][1]++;\n\n days[i][0]+=(pm+(pd+1)/20)/11;\n }\n count++;\n }\n cout<<count<<endl;\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3396, "score_of_the_acc": -1.0143, "final_rank": 17 }, { "submission_id": "aoj_1179_9123277", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#ifdef LOCAL\n #include \"settings/debug.cpp\"\n #define _GLIBCXX_DEBUG\n#else\n #define Debug(...) void(0)\n#endif\n#define rep(i, n) for (int i = 0; i < (n); ++i)\nusing ll = long long;\nusing ull = unsigned long long;\n\nint main() {\n map<tuple<int, int, int>, int> mp;\n {\n int y = 1, m = 1, d = 1, idx = 1;\n while (y <= 1000) {\n Debug(y, m, d);\n mp[{ y, m, d }] = idx++;\n d++;\n if (y % 3 != 0 && m % 2 == 0 && d == 20) {\n d = 1, m++;\n }\n else if ((y % 3 == 0 || m % 2 != 0) && d == 21) {\n d = 1, m++;\n }\n if (m == 11) {\n m = 1, y++;\n }\n }\n }\n Debug(\"done\");\n int n;\n cin >> n;\n rep(i, n) {\n int y, m, d;\n cin >> y >> m >> d;\n cout << mp[{ 1000, 1, 1 }] - mp[{ y, m, d }] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 15652, "score_of_the_acc": -1.317, "final_rank": 19 }, { "submission_id": "aoj_1179_9104806", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int n;\n cin >> n;\n for(int i = 0; i < n; i++){\n int Y, M, D;\n cin >> Y >> M >> D;\n int ans = 0;\n while(Y != 1000){\n ans++;\n D++;\n if(Y % 3 == 0){\n if(D == 21){\n M += 1;\n D = 1;\n }\n }else{\n if(M % 2 == 0){\n if(D == 20){\n M += 1;\n D = 1;\n }\n }else{\n if(D == 21){\n M += 1;\n D = 1;\n }\n }\n }\n if(M == 11){\n Y += 1;\n M = 1;\n }\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3424, "score_of_the_acc": -0.2655, "final_rank": 14 }, { "submission_id": "aoj_1179_9060285", "code_snippet": "#include <iostream>\nusing namespace std;\n\nint main() {\n int n;\n cin >> n;\n for (int i = 0; i < n; i++) {\n int y, m, d;\n cin >> y >> m >> d;\n int cnt = 0;\n while (!(y == 1000 && m == 1 && d == 1)) {\n int M;\n if (m % 2 == 1 || y % 3 == 0) {\n M = 20;\n } else {\n M = 19;\n }\n if (d < M) {\n d++;\n } else if (m < 10) {\n m++;\n d = 1;\n } else {\n y++;\n m = 1;\n d = 1;\n }\n cnt++;\n }\n cout << cnt << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3084, "score_of_the_acc": -0.0002, "final_rank": 2 }, { "submission_id": "aoj_1179_8973991", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = 3.141592653589793;\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\ntemplate<typename T> void view(const vv<T>& vv){ for(const auto& v : vv){ view(v); } }\n\nconst tuple<int, int, int> millennium = {1000, 1, 1};\n\ntuple<int, int, int> next_day(tuple<int, int, int> &day){\n auto [y, m, d] = day;\n d++;\n if (y % 3 && m % 2 == 0 && d == 20){\n d = 1;\n m++;\n }else if (d == 21){\n d = 1;\n m++;\n }\n\n if (m == 11){\n m = 1;\n y++;\n }\n return {y, m, d};\n}\n\nint solve(tuple<int, int, int> day){\n int ans = 0;\n while (true){\n day = next_day(day);\n ans++;\n if (day == millennium) return ans;\n }\n}\n\nint main(){\n int T; cin >> T;\n vc<int> ans;\n while (T--){\n int y, m, d; cin >> y >> m >> d;\n ans.push_back(solve({y, m, d}));\n }\n for (auto x : ans) cout << x << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3208, "score_of_the_acc": -0.0058, "final_rank": 3 }, { "submission_id": "aoj_1179_8236313", "code_snippet": "#include<iostream>\n\nusing namespace std;\n\nint main(){\n \n int n;\n cin >> n;\n\n for(int i = 0 ; i < n ; i ++){\n int Y, M, D;\n cin >> Y >> M >> D;\n int totalDays = 0;\n\n while( Y < 1000 ){\n\n D ++;\n totalDays++;\n if(Y % 3 != 0){\n if(M % 2 == 0 && D == 20){\n D = 1;\n M++;\n }\n else if( M % 2 != 0 && D == 21){\n D = 1;\n M ++;\n } \n }\n else if( Y % 3 == 0){\n if(D == 21){\n D = 1;\n M ++;\n }\n }\n if(M == 11){\n M = 1;\n Y ++;\n }\n\n }\n\n cout << totalDays << endl;\n\n }\n\n return 0;\n \n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3080, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1179_8036721", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n map<vector<int>,int> Map;\n int now = 0;\n vector<int> today = {1,1,1};\n Map[today] = now;\n while(now <= 200000){\n now++;\n int Y = today[0];\n int M = today[1];\n int D = today[2];\n if(D <= 18) D++;\n else if(D == 19){\n if(Y%3 == 0) D++;\n else if(M%2 == 1) D++;\n else{\n if(M <= 8){\n M++;\n D = 1;\n }\n else{\n Y++;\n M = 1;\n D = 1;\n }\n }\n }\n else{\n if(M <= 9){\n M++;\n D = 1;\n }\n else{\n Y++;\n M = 1;\n D = 1;\n }\n }\n today[0] = Y;\n today[1] = M;\n today[2] = D;\n Map[today] = now;\n }\n int n;\n cin >> n;\n vector<int> theday = {1000,1,1};\n for(int i=0;i<n;i++){\n vector<int> day(3);\n for(int j=0;j<3;j++) cin >> day[j];\n cout << Map[theday]-Map[day] << endl;\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 25252, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_1179_7897904", "code_snippet": "#line 2 \"template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n#define square(x) ((x)*(x))\n#define endl '\\n'\n#define debug(val); cerr << #val << \": \" << val << endl;\n\n// 型エイリアス\nusing ll = long long int;\nusing ull = unsigned long long;\nusing pii = pair<int, int>;\nusing pll = pair<long long, long long>;\nusing uint = unsigned int;\nusing T3 = tuple<ll, int, int>;\n// 定数\nconstexpr int INT_INF = 1e9 + 1;\nconstexpr ll INF = 1LL << 60;\n// constexpr ll MOD = (long long)1e9 + 7;\nconstexpr ll MOD = 998244353;\n\n// 配列での方向\n// 上下左右(右から時計回り)\nconstexpr int dx[4] = { 1, 0, -1, 0 };\nconstexpr int dy[4] = { 0, 1, 0, -1 };\n// 斜め4方向(右上から時計回り)\n//constexpr int dx[4] = { 1, 1, -1, -1 };\n//constexpr int dy[4] = { -1, 1, 1, -1 };\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\nvoid Yes(bool yes)\n{\n if (yes) cout << \"Yes\" << '\\n';\n else cout << \"No\" << '\\n';\n}\n\n// pii\nostream& operator<<(ostream& os, pii p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\n// vector<T>\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v)\n{\n for (const T& val : v)\n {\n os << val << ' ';\n }\n\n return os;\n}\n// vector<vector<T>>\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<vector<T>>& v)\n{\n for (const vector<T>& line : v)\n {\n os << endl;\n for (const T& val : line)\n {\n os << val << ' ';\n }\n }\n\n return os;\n}\n// set<T>\ntemplate <typename T>\nostream& operator<<(ostream& os, const set<T>& s)\n{\n for (auto itr = s.begin(); itr != s.end(); ++itr)\n {\n os << *itr << ' ';\n }\n return os;\n}\n#line 2 \"a.cpp\"\n\nint N;\n\nint main(void) {\n\tcin >> N;\n\tfor (int i = 0; i < N; ++i) {\n\t\tint y, m, d;\n\t\tcin >> y >> m >> d;\n\n\t\tint days = 0;\n\t\twhile (true) {\n\t\t\tif (y == 1000 && m == 1 && d == 1) break;\n\n\t\t\tint daysInMonth = 0;\n\t\t\tif (y % 3 == 0) {\n\t\t\t\tdaysInMonth = 20;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (m % 2 == 1) daysInMonth = 20;\n\t\t\t\telse if (m % 2 == 0) daysInMonth = 19;\n\t\t\t}\n\t\t\t// d\n\t\t\tif (d == daysInMonth) {\n\t\t\t\tm = (m + 1) % 10;\n\t\t\t\td = 0;\n\t\t\t}\n\t\t\t// y\n\t\t\tif (m == 1 && d == 0) {\n\t\t\t\ty += 1;\n\t\t\t}\n\t\t\t++d;\n\t\t\t++days;\n\t\t}\n\t\tcout << days << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3440, "score_of_the_acc": -0.0162, "final_rank": 10 }, { "submission_id": "aoj_1179_6229926", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\n#define reps(i, a, b) for(long long (i) = (a); (i) < (b); ++(i))\n#define rep(i, n) for(long long (i) = 0; (i) < (n); ++(i))\n#define repr(i, b, a) for(long long (i) = (b); (i) >= (a); --(i))\nusing ll = long long;\nusing vl = vector<long long>;\nusing vvl = vector<vector<long long> >;\nusing pl = pair<long long, long long>;\nusing tl = tuple<long long, long long, long long>;\nusing graph = vector<vector<int> >;\nstruct Edge{\n int to;\n long long cost;\n Edge(int t, long long c) : to(t), cost(c) {}\n bool operator<(const Edge &a) const{return cost < a.cost;}\n bool operator>(const Edge &a) const{return cost > a.cost;}\n};\nusing wgraph = vector<vector<Edge> >;\nconstexpr long long INF = numeric_limits<long long>::max() / 8;\nconstexpr long long dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};\nconstexpr long long dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};\ntemplate<typename T, typename U> inline bool chmax(T &a, const U& b) {if(a<b){a=b;return true;}return false;}\ntemplate<typename T, typename U> inline bool chmin(T &a, const U& b) {if(a>b){a=b;return true;}return false;}\ntemplate<typename T, typename U> inline T POW(T x, U n) {T ret=1;while(n>0){if(n&1){ret=ret*x;}if(n>>=1){x=x*x;}}return ret;}\ntemplate<typename T, typename U> inline T MOD(T n, U m) {if(n >= 0) {return n % m;} else return (n%m + m)%m;}\ntemplate<typename T, typename U, typename V> inline T POWMOD(T x, U n, V m){T ret=1;x%=m;while(n>0){if(n&1)ret=ret*x%m;if(n>>=1){x=x*x%m;}}return ret%m;}\ntemplate<typename T, typename U> inline T div_ceil(T a, U b){return (a + b - 1) / b;}\ntemplate<typename T> inline long long KETA(T n, long long base = 10){long long ret = 0;while(n){ret++; n /= base;} return ret;}\ntemplate<typename T> inline long long popcount(T a){return __builtin_popcount(a);}\ntemplate<typename T> inline bool contains(T S, T i){return (S & (T(1) << i)) != 0;}\ntemplate<typename T> inline void fin(T a){cout << a << '\\n'; exit(0);}\ntemplate<typename T> inline long long ub_index(vector<T> &v, T a){return upper_bound(v.begin(), v.end(), a) - v.begin();}\ntemplate<typename T> inline long long lb_index(vector<T> &v, T a){return lower_bound(v.begin(), v.end(), a) - v.begin();}\ntemplate<typename T> inline long long ika_index(vector<T> &v, T a){return upper_bound(v.begin(), v.end(), a) - v.begin() - 1;}\ntemplate<typename T> inline long long miman_index(vector<T> &v, T a){return lower_bound(v.begin(), v.end(), a) - v.begin() - 1;}\ntemplate<typename T> inline T SUM(const vector<T> &v){return accumulate(v.begin(), v.end(), (T)0);}\ntemplate<typename T> inline T MIN(const vector<T> &v){return *min_element(v.begin(), v.end());}\ntemplate<typename T> inline T MAX(const vector<T> &v){return *max_element(v.begin(), v.end());}\n\ntemplate<typename T,typename S> ostream&operator<<(ostream&os,const pair<T,S>&p){os<<\"(\"<<p.first<<\", \"<<p.second<<\")\";return os;}\ntemplate<typename T,typename S> ostream&operator<<(ostream&os,const map<T,S>&ma){for(auto [a,b]:ma){os<<\"(\"<<a<<\", \"<<b<<\")\"<<\" \";}return os;}\ntemplate<typename T> ostream &operator<<(ostream&os,const set<T>&s){os<<\"{\";for(auto c:s)os<<c<<\" \";os<<\"}\";return os;}\ntemplate<typename T> ostream &operator<<(ostream&os,const multiset<T>&s){os<<\"{\";for(auto c:s)os<<c<<\" \";os<<\"}\";return os;}\ntemplate<typename T> ostream &operator<<(ostream&os,const vector<T>&v){os<<\"[\";for(int i=0;i<v.size();i++){os<<v[i]<<(i==v.size()-1?\"\":\" \");}os<<\"]\";return os;}\n\nvoid dump_func() {cerr << endl;}\ntemplate<class Head, class... Tail>\nvoid dump_func(Head&& head, Tail&&... tail){\n cerr << head;\n if(sizeof...(Tail) == 0) cerr << \" \";\n else cerr << \", \";\n dump_func(std::move(tail)...);\n}\n\n\n\n//#define ONLINE_JUDGE\n#ifdef ONLINE_JUDGE\n#define dump(...) true\n#else\n#define dump(...) cerr << __LINE__ << \" : (\" << #__VA_ARGS__ << \") = \"; \\\ndump_func(__VA_ARGS__)\n#endif\n\n\n\n\nvoid solve(){\n ll y, m, d; cin >> y >> m >> d;\n ll cnt = 0;\n while(y != 1000 or m != 1 or d != 1){\n cnt++;\n d++;\n if(y % 3 != 0 and m % 2 == 0){\n if(d == 20) {\n m++;\n d = 1;\n }\n } else if(d == 21){\n m++;\n d = 1;\n }\n if(m == 11){\n m = 1;\n d = 1;\n y++;\n }\n }\n cout << cnt << '\\n';\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << std::fixed << std::setprecision(15);\n\n int cases; cin >> cases;\n while(cases--){\n solve();\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3452, "score_of_the_acc": -0.0168, "final_rank": 11 }, { "submission_id": "aoj_1179_6011557", "code_snippet": "//GIVE ME AC!!!!!!!!!!!!!!!!!\n//#pragma GCC target(\"avx\")\n//#pragma GCC optimize(\"O3\")\n//#pragma GCC optimize(\"unroll-loops\")\n#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing ld=long double;\nusing vl=vector<ll>;\nusing vi=vector<int>;\nusing vs=vector<string>;\nusing vc=vector<char>;\nusing vvl=vector<vl>;\nusing P=pair<ll,ll>;\nusing vvc=vector<vc>;\nusing vd=vector<double>;\nusing vp=vector<P>;\nusing vb=vector<bool>;\n#define overload4(_1,_2,_3,_4,name,...) name\n#define overload3(_1,_2,_3,name,...) name\n#define rep1(a) for(__typeof(a) i=0;i<a;i++)\n#define rep2(i,a) for(__typeof(a) i=0;i<a;i++)\n#define rep3(i,a,b) for(__typeof(a) i=a;i<b;i++)\n#define rep4(i,a,b,c) for(__typeof(a) i=a;i<b;i+=c)\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep1(a) for(__typeof(a) i=(a)-1;i>=0;i--)\n#define rrep2(i,a) for(__typeof(a) i=(a)-1;i>=0;i--)\n#define rrep3(i,a,b) for(__typeof(a) i=(b)-1;i>=(a);i--)\n#define rrep(...) overload3(__VA_ARGS__,rrep3,rrep2,rrep1)(__VA_ARGS__)\n#define all1(i) begin(i),end(i)\n#define all2(i,a) begin(i),begin(i)+a\n#define all3(i,a,b) begin(i)+a,begin(i)+b\n#define all(...) overload3(__VA_ARGS__,all3,all2,all1)(__VA_ARGS__)\n#define rall(n) (n).rbegin(),(n).rend()\n#define pb push_back\n#define eb emplace_back\n#define MtSaka ios::sync_with_stdio(0);cin.tie(0);cout<<fixed<<setprecision(12)\n#define max_(a) *max_element(all(a))\n#define min_(a) *min_element(all(a))\n#define INT(...) int __VA_ARGS__;scan(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;scan(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__;scan(__VA_ARGS__)\n#define CHR(...) char __VA_ARGS__;scan(__VA_ARGS__)\n#define DBL(...) double __VA_ARGS__;scan(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__;scan(__VA_ARGS__)\nconst int dx[8]={1,0,-1,0,1,-1,-1,1};\nconst int dy[8]={0,1,0,-1,1,1,-1,-1};\nconst ll inf=2e18;\nconst ll MOD=1000000007;\nconst ll mod=998244353;\nconst double pi=acos(-1);\ntemplate<typename T1,typename T2 >\nostream &operator<<(ostream&os,const pair<T1,T2>&p){os<<p.first<<\" \"<<p.second;return os;}\ntemplate<typename T1,typename T2>\nistream &operator>>(istream&is,pair<T1,T2>&p){is>>p.first>>p.second;return is;}\ntemplate<typename T>\nostream &operator<<(ostream&os,const vector<T>&v){for(int i=0;i<(int)v.size();i++){os<<v[i]<<(i+1!=v.size()?\" \":\"\");}return os;}\ntemplate<typename T>\nistream &operator>>(istream&is,vector<T>&v){for(T &in:v){is>>in;}return is;}\nvoid scan(){}\ntemplate<class Head,class... Tail>\nvoid scan(Head&head,Tail&... tail){cin>>head;scan(tail...);}\ntemplate<class T>\nvoid print(const T &t){cout<<t<<'\\n';}\ntemplate<class Head, class... Tail>\nvoid print(const Head &head, const Tail &... tail){cout<<head<<' ';print(tail...);}\ntemplate<class... T>\nvoid fin(const T &... a){print(a...);exit(0);}\ntemplate<typename T>\nT sum_(vector<T>a){return accumulate(all(a),T(0));}\ntemplate<typename T1,typename T2>\ninline bool chmax(T1&a,T2 b){return a<b&&(a=b,true);}\ntemplate<typename T1,typename T2>\ninline bool chmin(T1&a,T2 b){return a>b&&(a=b,true);}\nint main(){\n ll cnt=0;\n map<tuple<ll,ll,ll>,ll>mp;\n rep(i,1,1000){\n rep(j,1,11){\n for(ll k=1;k<=((i%3==0||j%2==1)?20:19);k++){\n mp[tuple{i,j,k}]=cnt++;\n }\n }\n }\n LL(n);\n rep(n){\n LL(y,m,d);\n print(cnt-mp[tuple{y,m,d}]);\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 18700, "score_of_the_acc": -1.2045, "final_rank": 18 }, { "submission_id": "aoj_1179_6000613", "code_snippet": "/* C++ */\n#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef long double ld;\ntypedef vector<ll> vl;\ntypedef vector<vector<ll>> vvl;\ntypedef vector<vector<vector<ll>>> vvvl;\ntypedef pair<ll, ll> pint;\nconst ll MOD = 1000000007;\nconst ll INF = 922337203685477580;\n#define rep(i, n) for(ll i = (ll)0; i < (ll)(n); i++)\n#define Rep(i, s, t) for(ll i = (ll)(s); i < (ll)(t); i++)\n#define ALL(a) (a).begin(),(a).end()\n#define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n#define PI 3.14159265358979323846\n#define ifYN(x) cout << (x ? \"Yes\" : \"No\") << \"\\n\"\nll dx[4] = {-1, 1, 0, 0};\nll dy[4] = {0, 0, -1, 1};\n\ntemplate<class T> inline bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<class T> inline bool chmax(T& a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\nll Len(ll n) {\n if (n == 0) return 1;\n ll s = 0;\n while (n != 0) s++, n /= 10;\n return s;\n}\n\nll Sint(ll n) {\n ll ans = 0;\n while (n != 0) ans += n % 10, n /= 10;\n return ans;\n}\n\nll Svec(vector<ll> v){\n ll n = 0;\n rep(i, (ll)v.size()) n += v[i];\n return n;\n}\n\nll GCD(ll a, ll b) {\n return b ? GCD(b, a % b) : a;\n}\n\nll LCM(ll a, ll b){\n return a / GCD(a, b) * b;\n}\n\nll POW(ll a, ll n, ll mod = INF) {\n ll res = 1;\n while (n > 0) {\n if (n & 1) res = res * a % mod;\n a = a * a % mod;\n n >>= 1;\n }\n return res;\n}\n\nvoid dis(vector<ll> V) {\n rep(i, V.size()) cout << (i ? \" \" : \"\") << V[i];\n cout << endl;\n}\n\nvoid dis2(vector<vector<ll> > v) {\n rep (i, v.size()) {\n rep (j, v[0].size()) cout << v[i][j] << ' ';\n cout << endl;\n }\n}\n\nbool cmp(pint a, pint b) { return a.second < b.second; }\n\n//Range Add Query 区間加算、一点取得\n\nstruct RAQ {\n private:\n ll N; //2の冪乗\n vector<ll> node;\n\n public:\n RAQ(vector<ll> V) {\n N = 1;\n while (N < V.size()) N *= 2;\n node.resize(2 * N - 1, 0);\n rep (i, V.size()) node[i + N - 1] = V[i];\n }\n\n void add(ll a, ll b, ll val, ll k = 0, ll l = 0, ll r = -1) { //[a, b) [l, r)\n if (r < 0) r = N;\n if (r <= a || b <= l) return;\n if (a <= l && r <= b) {\n node[k] += val;\n return;\n }\n add(a, b, val, 2 * k + 1, l, (l + r) / 2);\n add(a, b, val, 2 * k + 2, (l + r) / 2, r);\n return;\n }\n\n ll get(ll ind) {\n ind += N - 1;\n ll ret = node[ind];\n while (ind > 0) {\n ind = (ind - 1) / 2;\n ret += node[ind];\n }\n return ret;\n }\n void dis() {\n ll ans = 1;\n ll id = 0;\n while (1) {\n rep (i, ans) cout << (i ? \" \" : \"\") << node[id], id++;\n cout << endl;\n if (ans == N) return;\n ans *= 2;\n }\n }\n};\n\nstruct T {\n ll y;\n ll m;\n ll d;\n};\n\nll f(ll y, ll m, ll d) {\n ll sum = 0;\n while(1) {\n if (y == 1000 && m == 1 && d == 1) break;\n sum++;\n if(y % 3 == 0) {\n if(d == 20) {\n d = 1;\n if(m == 10) {\n m = 1;\n y++;\n } else {\n m++;\n }\n } else {\n d++;\n }\n } else {\n if(m%2 == 1) {\n if(d == 20) {\n d = 1;\n if(m == 10) {\n m = 1;\n y++;\n } else {\n m++;\n }\n } else {\n d++;\n }\n } else {\n if(d == 19) {\n d = 1;\n if(m == 10) {\n m = 1;\n y++;\n } else {\n m++;\n }\n } else {\n d++;\n }\n }\n }\n }\n return sum;\n}\n\n/*↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓*/\nint main() {\n IOS;\n ll N; cin >> N;\n rep(i, N) {\n ll y, m, d; cin >> y >> m >> d;\n cout << f(y, m, d) << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3380, "score_of_the_acc": -0.0135, "final_rank": 9 }, { "submission_id": "aoj_1179_5957686", "code_snippet": "#include<iostream>\n\nusing namespace std;\n\n\nsigned main(){\n\t\n\tint n;\n\t\n\tcin>>n;\n\t\n\tfor(int _ = 0; _ < n; _++){\n\t\tint Y, M, D;\n\t\tint con = 0;\n\t\t\n\t\tcin>>Y>>M>>D;\n\t\t\n\t\twhile(Y < 1000){\n\t\t\tcon++;\n\t\t\t\n\t\t\t\n\t\t\tif(Y%3 == 0) {\n\t\t\t\tif(D == 20) M++, D = 1;\n\t\t\t\telse D++;\n\t\t\t} else {\n\t\t\t\tif(M%2) {\n\t\t\t\t\tif(D == 20) M++, D = 1;\n\t\t\t\t\telse D++;\n\t\t\t\t} else {\n\t\t\t\t\tif(D == 19) M++, D = 1;\n\t\t\t\t\telse D++;\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t\tif(M == 11) Y++, M = 1;\n\t\t}\n\t\t\n\t\tcout<<con<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3348, "score_of_the_acc": -0.0121, "final_rank": 5 }, { "submission_id": "aoj_1179_5922753", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\nusing ll=long long;\n#define overload4(_1, _2, _3, _4, name, ...) name\n#define rep1(n) for(ll i = 0; i < (n); ++i)\n#define rep2(i, n) for(ll i = 0; i < (n); ++i)\n#define rep3(i, a, b) for(ll i = (a); i < (b); ++i)\n#define rep4(i, a, b, c) for(ll i = (a); i < (b); i += (c))\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep1(n) for(ll i=n;i--;)\n#define rrep2(i,n) for(ll i=n;i--;)\n#define rrep3(i,a,b) for(ll i=b;i-->(a);)\n#define rrep4(i,a,b,c) for(ll i=(a)+((b)-(a)-1)/(c)*(c);i>=(a);i-=c)\n#define rrep(...) overload4(__VA_ARGS__,rrep4,rrep3,rrep2,rrep1)(__VA_ARGS__)\n#define all(i) begin(i), end(i)\n#define rall(i) (i).rbegin(), (i).rend()\n#define Sort(a) sort(all(a))\n#define Rev(a) reverse(all(a))\n#define elif else if\ntemplate<class T> bool chmin(T &a, const T &b){ if(a > b){ a = b; return 1; } else return 0; }\ntemplate<class T> bool chmax(T &a, const T &b){ if(a < b){ a = b; return 1; } else return 0; }\ntemplate<class T> ll sum(const T& a){ return accumulate(all(a), 0LL); }\ntemplate<class T> auto min(const T& a){ return *min_element(all(a)); }\ntemplate<class T> auto max(const T& a){ return *max_element(all(a)); }\nvector<ll> iota(ll n, ll begin = 0){ vector<ll> a(n); iota(a.begin(), a.end(), begin); return a; }\nconst int INF =0x3fffffff;\nconst ll INFll =0x1fffffffffffffff;// 4times ok\nconst int MOD= int(1e9)+7;\nconst int MODD=998244353;\nusing P= pair<int,int>;\nusing Pl= pair<ll,ll>;\nusing ld=long double;\nusing VVl=vector<vector<ll>>;\nusing VVd=vector<vector<ld>>;\nusing Vd=vector<ld>;\nusing tuplis =array<ll, 3>;\nusing quatro=array<ll,4>;\n#define vec(type,name,...) vector<type> name(__VA_ARGS__)\n#define vv(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\ntemplate<class T> using pq = priority_queue<T, vector<T>, greater<T>>;\nconst ll four[] = {0, 1, 0, -1, 0};\nconst ll eight[] = {0, 1, 1, 0, -1, -1, 1, -1, 0};\nconst ld EPS = 1e-9;\nconst ld PI = 3.1415926535897932;\nll gcd(ll a, ll b){ while(b){ ll c = b; b = a % b; a = c; } return a; }\nll lcm(ll a, ll b){ if(!a || !b) return 0; return a * b / gcd(a, b); }\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll isqr(ll x){ll r=sqrt(x)-1;while((r+1)*(r+1)<=x)r++;return r;}\nvector<ll> divisor(ll x){vector<ll> ans; for(ll i = 1; i * i <= x; i++) if(x % i == 0) ans.push_back(i); rrep(ans.size() - (ans.back() * ans.back() == x)) ans.push_back(x / ans[i]); return ans; }\nint scan(){ return getchar(); }\nvoid scan(int& a){ scanf(\"%d\", &a); }\nvoid scan(unsigned& a){ scanf(\"%u\", &a); }\nvoid scan(long& a){ scanf(\"%ld\", &a); }\nvoid scan(long long& a){ scanf(\"%lld\", &a); }\nvoid scan(unsigned long long& a){ scanf(\"%llu\", &a); }\nvoid scan(char& a){ do{ a = getchar(); }while(a == ' ' || a == '\\n'); }\nvoid scan(float& a){ scanf(\"%f\", &a); }\nvoid scan(double& a){ scanf(\"%lf\", &a); }\nvoid scan(long double& a){ scanf(\"%Lf\", &a); }\nvoid scan(vector<bool>& a){ for(unsigned i = 0; i < a.size(); i++){ int b; scan(b); a[i] = b; } }\nvoid scan(char a[]){ scanf(\"%s\", a); }\nvoid scan(string& a){ cin >> a; }\ntemplate<class T> void scan(vector<T>&);\ntemplate<class T, size_t size> void scan(array<T, size>&);\ntemplate<class T, class L> void scan(pair<T, L>&);\ntemplate<class T, size_t size> void scan(T(&)[size]);\ntemplate<class T> void scan(vector<T>& a){ for(auto&& i : a) scan(i); }\ntemplate<class T> void scan(deque<T>& a){ for(auto&& i : a) scan(i); }\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i); }\ntemplate<class T, class L> void scan(pair<T, L>& p){ scan(p.first); scan(p.second); }\ntemplate<class T, size_t size> void scan(T (&a)[size]){ for(auto&& i : a) scan(i); }\ntemplate<class T> void scan(T& a){ cin >> a; }\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){ scan(head); in(tail...); }\nvoid print(){ putchar(' '); }\nvoid print(bool a){ printf(\"%d\", a); }\nvoid print(int a){ printf(\"%d\", a); }\nvoid print(unsigned a){ printf(\"%u\", a); }\nvoid print(long a){ printf(\"%ld\", a); }\nvoid print(long long a){ printf(\"%lld\", a); }\nvoid print(unsigned long long a){ printf(\"%llu\", a); }\nvoid print(char a){ printf(\"%c\", a); }\nvoid print(char a[]){ printf(\"%s\", a); }\nvoid print(const char a[]){ printf(\"%s\", a); }\nvoid print(float a){ printf(\"%.15f\", a); }\nvoid print(double a){ printf(\"%.15f\", a); }\nvoid print(long double a){ printf(\"%.15Lf\", a); }\nvoid print(const string& a){ for(auto&& i : a) print(i); }\ntemplate<class T> void print(const complex<T>& a){ if(a.real() >= 0) print('+'); print(a.real()); if(a.imag() >= 0) print('+'); print(a.imag()); print('i'); }\ntemplate<class T> void print(const vector<T>&);\ntemplate<class T, size_t size> void print(const array<T, size>&);\ntemplate<class T, class L> void print(const pair<T, L>& p);\ntemplate<class T, size_t size> void print(const T (&)[size]);\ntemplate<class T> void print(const vector<T>& a){ if(a.empty()) return; print(a[0]); for(auto i = a.begin(); ++i != a.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T> void print(const deque<T>& a){ if(a.empty()) return; print(a[0]); for(auto i = a.begin(); ++i != a.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T, size_t size> void print(const array<T, size>& a){ print(a[0]); for(auto i = a.begin(); ++i != a.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T, class L> void print(const pair<T, L>& p){ print(p.first); putchar(' '); print(p.second); }\ntemplate<class T, size_t size> void print(const T (&a)[size]){ print(a[0]); for(auto i = a; ++i != end(a); ){ putchar(' '); print(*i); } }\ntemplate<class T> void print(const T& a){ cout << a; }\nint out(){ putchar('\\n'); return 0; }\ntemplate<class T> int out(const T& t){ print(t); putchar('\\n'); return 0; }\ntemplate<class Head, class... Tail> int out(const Head& head, const Tail&... tail){ print(head); putchar(' '); out(tail...); return 0; }\n#define INT(...) int __VA_ARGS__; in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__; in(__VA_ARGS__)\n#define ULL(...) ull __VA_ARGS__; in(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__; in(__VA_ARGS__)\n#define CHR(...) char __VA_ARGS__; in(__VA_ARGS__)\n#define DBL(...) double __VA_ARGS__; in(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; in(__VA_ARGS__)\n#define VEC(type,name,size) vector<type> name(size); in(name)\n#define VV(type, name, h, w) vector<vector<type>> name(h, vector<type>(w)); in(name)\n\nint main(){\n LL(n);\n while(n--){\n LL(y,m,d);\n ll ret=0;\n while(y!=1000){\n ret++;\n d++;\n ll mxd=20;\n if(y%3!=0 and m%2==0)mxd--;\n if(d>mxd){\n d=1;\n m++;\n }\n if(m>10){\n m=1;\n y++;\n }\n }\n out(ret);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3276, "score_of_the_acc": -0.0088, "final_rank": 4 }, { "submission_id": "aoj_1179_5820609", "code_snippet": "#line 1 \"/Users/nok0/Documents/Programming/nok0/cfmulti.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\n#pragma region Macros\n// rep macro\n#define foa(v, a) for(auto &v : a)\n#define REPname(a, b, c, d, e, ...) e\n#define REP(...) REPname(__VA_ARGS__, REP3, REP2, REP1, REP0)(__VA_ARGS__)\n#define REP0(x) for(int i = 0; i < (x); ++i)\n#define REP1(i, x) for(int i = 0; i < (x); ++i)\n#define REP2(i, l, r) for(int i = (l); i < (r); ++i)\n#define REP3(i, l, r, c) for(int i = (l); i < (r); i += (c))\n#define REPSname(a, b, c, ...) c\n#define REPS(...) REPSname(__VA_ARGS__, REPS1, REPS0)(__VA_ARGS__)\n#define REPS0(x) for(int i = 1; i <= (x); ++i)\n#define REPS1(i, x) for(int i = 1; i <= (x); ++i)\n#define RREPname(a, b, c, d, e, ...) e\n#define RREP(...) RREPname(__VA_ARGS__, RREP3, RREP2, RREP1, RREP0)(__VA_ARGS__)\n#define RREP0(x) for(int i = (x)-1; i >= 0; --i)\n#define RREP1(i, x) for(int i = (x)-1; i >= 0; --i)\n#define RREP2(i, r, l) for(int i = (r)-1; i >= (l); --i)\n#define RREP3(i, r, l, c) for(int i = (r)-1; i >= (l); i -= (c))\n#define RREPSname(a, b, c, ...) c\n#define RREPS(...) RREPSname(__VA_ARGS__, RREPS1, RREPS0)(__VA_ARGS__)\n#define RREPS0(x) for(int i = (x); i >= 1; --i)\n#define RREPS1(i, x) for(int i = (x); i >= 1; --i)\n\n// name macro\n#define pb push_back\n#define eb emplace_back\n#define SZ(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define popcnt(x) __builtin_popcountll(x)\ntemplate <class T = int>\nusing V = std::vector<T>;\ntemplate <class T = int>\nusing VV = std::vector<std::vector<T>>;\ntemplate <class T>\nusing pqup = std::priority_queue<T, std::vector<T>, std::greater<T>>;\nusing ll = long long;\nusing ld = long double;\nusing int128 = __int128_t;\nusing pii = std::pair<int, int>;\nusing pll = std::pair<long long, long long>;\n\n// input macro\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n\tis >> p.first >> p.second;\n\treturn is;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n\tfor(T &i : v) is >> i;\n\treturn is;\n}\nstd::istream &operator>>(std::istream &is, __int128_t &a) {\n\tstd::string s;\n\tis >> s;\n\t__int128_t ret = 0;\n\tfor(int i = 0; i < s.length(); i++)\n\t\tif('0' <= s[i] and s[i] <= '9')\n\t\t\tret = 10 * ret + s[i] - '0';\n\ta = ret * (s[0] == '-' ? -1 : 1);\n\treturn is;\n}\nnamespace scanner {\nvoid scan(int &a) { std::cin >> a; }\nvoid scan(long long &a) { std::cin >> a; }\nvoid scan(std::string &a) { std::cin >> a; }\nvoid scan(char &a) { std::cin >> a; }\nvoid scan(char a[]) { std::scanf(\"%s\", a); }\nvoid scan(double &a) { std::cin >> a; }\nvoid scan(long double &a) { std::cin >> a; }\ntemplate <class T, class U>\nvoid scan(std::pair<T, U> &p) { std::cin >> p; }\ntemplate <class T>\nvoid scan(std::vector<T> &a) { std::cin >> a; }\nvoid INPUT() {}\ntemplate <class Head, class... Tail>\nvoid INPUT(Head &head, Tail &... tail) {\n\tscan(head);\n\tINPUT(tail...);\n}\n} // namespace scanner\n#define VEC(type, name, size) \\\n\tstd::vector<type> name(size); \\\n\tscanner::INPUT(name)\n#define VVEC(type, name, h, w) \\\n\tstd::vector<std::vector<type>> name(h, std::vector<type>(w)); \\\n\tscanner::INPUT(name)\n#define INT(...) \\\n\tint __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LL(...) \\\n\tlong long __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define STR(...) \\\n\tstd::string __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define CHAR(...) \\\n\tchar __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define DOUBLE(...) \\\n\tdouble __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LD(...) \\\n\tlong double __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n\n// output-macro\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n\tos << p.first << \" \" << p.second;\n\treturn os;\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &a) {\n\tfor(int i = 0; i < int(a.size()); ++i) {\n\t\tif(i) os << \" \";\n\t\tos << a[i];\n\t}\n\treturn os;\n}\nstd::ostream &operator<<(std::ostream &dest, __int128_t &value) {\n\tstd::ostream::sentry s(dest);\n\tif(s) {\n\t\t__uint128_t tmp = value < 0 ? -value : value;\n\t\tchar buffer[128];\n\t\tchar *d = std::end(buffer);\n\t\tdo {\n\t\t\t--d;\n\t\t\t*d = \"0123456789\"[tmp % 10];\n\t\t\ttmp /= 10;\n\t\t} while(tmp != 0);\n\t\tif(value < 0) {\n\t\t\t--d;\n\t\t\t*d = '-';\n\t\t}\n\t\tint len = std::end(buffer) - d;\n\t\tif(dest.rdbuf()->sputn(d, len) != len) {\n\t\t\tdest.setstate(std::ios_base::badbit);\n\t\t}\n\t}\n\treturn dest;\n}\ntemplate <class T>\nvoid print(const T a) { std::cout << a << '\\n'; }\ntemplate <class Head, class... Tail>\nvoid print(Head H, Tail... T) {\n\tstd::cout << H << ' ';\n\tprint(T...);\n}\ntemplate <class T>\nvoid printel(const T a) { std::cout << a << '\\n'; }\ntemplate <class T>\nvoid printel(const std::vector<T> &a) {\n\tfor(const auto &v : a)\n\t\tstd::cout << v << '\\n';\n}\ntemplate <class Head, class... Tail>\nvoid printel(Head H, Tail... T) {\n\tstd::cout << H << '\\n';\n\tprintel(T...);\n}\nvoid Yes(const bool b = true) { std::cout << (b ? \"Yes\\n\" : \"No\\n\"); }\nvoid No() { std::cout << \"No\\n\"; }\nvoid YES(const bool b = true) { std::cout << (b ? \"YES\\n\" : \"NO\\n\"); }\nvoid NO() { std::cout << \"NO\\n\"; }\nvoid err(const bool b = true) {\n\tif(b) {\n\t\tstd::cout << \"-1\\n\", exit(0);\n\t}\n}\n\n//debug macro\nnamespace debugger {\ntemplate <class T>\nvoid view(const std::vector<T> &a) {\n\tstd::cerr << \"{ \";\n\tfor(const auto &v : a) {\n\t\tstd::cerr << v << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\ntemplate <class T>\nvoid view(const std::vector<std::vector<T>> &a) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &v : a) {\n\t\tstd::cerr << \"\\t\";\n\t\tview(v);\n\t\tstd::cerr << \"\\n\";\n\t}\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::vector<std::pair<T, U>> &a) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &p : a) std::cerr << \"\\t(\" << p.first << \", \" << p.second << \")\\n\";\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::map<T, U> &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &p : m) std::cerr << \"\\t[\" << p.first << \"] : \" << p.second << \"\\n\";\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::pair<T, U> &p) { std::cerr << \"(\" << p.first << \", \" << p.second << \")\"; }\ntemplate <class T>\nvoid view(const std::set<T> &s) {\n\tstd::cerr << \"{ \";\n\tfor(auto &v : s) {\n\t\tview(v);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <class T>\nvoid view(const T &e) { std::cerr << e; }\n} // namespace debugger\n#ifdef LOCAL\nvoid debug_out() {}\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head H, Tail... T) {\n\tdebugger::view(H);\n\tstd::cerr << \", \";\n\tdebug_out(T...);\n}\n#define debug(...) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"] : [\"; \\\n\t\tdebug_out(__VA_ARGS__); \\\n\t\tstd::cerr << \"\\b\\b]\\n\"; \\\n\t} while(false)\n#else\n#define debug(...) (void(0))\n#endif\n\n// vector macro\ntemplate <class T>\nint lb(const std::vector<T> &a, const T x) { return std::distance((a).begin(), std::lower_bound((a).begin(), (a).end(), (x))); }\ntemplate <class T>\nint ub(const std::vector<T> &a, const T x) { return std::distance((a).begin(), std::upper_bound((a).begin(), (a).end(), (x))); }\ntemplate <class T>\nvoid UNIQUE(std::vector<T> &a) {\n\tstd::sort(a.begin(), a.end());\n\ta.erase(std::unique(a.begin(), a.end()), a.end());\n}\ntemplate <class T>\nstd::vector<T> press(std::vector<T> &a) {\n\tauto res = a;\n\tUNIQUE(res);\n\tfor(auto &v : a)\n\t\tv = lb(res, v);\n\treturn res;\n}\n#define SORTname(a, b, c, ...) c\n#define SORT(...) SORTname(__VA_ARGS__, SORT1, SORT0, ...)(__VA_ARGS__)\n#define SORT0(a) std::sort((a).begin(), (a).end())\n#define SORT1(a, c) std::sort((a).begin(), (a).end(), [](const auto x, const auto y) { return x c y; })\ntemplate <class T>\nvoid ADD(std::vector<T> &a, const T x = 1) {\n\tfor(auto &v : a) v += x;\n}\ntemplate <class T>\nvoid SUB(std::vector<T> &a, const T x = 1) {\n\tfor(auto &v : a) v -= x;\n}\ntemplate <class T>\nvoid MUL(std::vector<T> &a, const T x) {\n\tfor(auto &v : a) v *= x;\n}\ntemplate <class T>\nvoid DIV(std::vector<T> &a, const T x) {\n\tfor(auto &v : a) v /= x;\n}\nstd::vector<std::pair<char, int>> rle(const string &s) {\n\tint n = s.size();\n\tstd::vector<std::pair<char, int>> ret;\n\tfor(int l = 0; l < n;) {\n\t\tint r = l + 1;\n\t\tfor(; r < n and s[l] == s[r]; r++) {}\n\t\tret.emplace_back(s[l], r - l);\n\t\tl = r;\n\t}\n\treturn ret;\n}\ntemplate <class T>\nstd::vector<std::pair<T, int>> rle(const std::vector<T> &v) {\n\tint n = v.size();\n\tstd::vector<std::pair<T, int>> ret;\n\tfor(int l = 0; l < n;) {\n\t\tint r = l + 1;\n\t\tfor(; r < n and v[l] == v[r]; r++) {}\n\t\tret.emplace_back(v[l], r - l);\n\t\tl = r;\n\t}\n\treturn ret;\n}\n\n// math macro\ntemplate <class T, class U>\ninline bool chmin(T &a, const U &b) { return a > b ? a = b, true : false; }\ntemplate <class T, class U>\ninline bool chmax(T &a, const U &b) { return a < b ? a = b, true : false; }\ntemplate <class T>\nT divup(T x, T y) { return (x + y - 1) / y; }\ntemplate <class T>\nT POW(T a, long long n) {\n\tT ret = 1;\n\twhile(n) {\n\t\tif(n & 1) ret *= a;\n\t\ta *= a;\n\t\tn >>= 1;\n\t}\n\treturn ret;\n}\n// modpow\nlong long POW(long long a, long long n, const int mod) {\n\tlong long ret = 1;\n\ta = (a % mod + mod) % mod;\n\twhile(n) {\n\t\tif(n & 1) (ret *= a) %= mod;\n\t\t(a *= a) %= mod;\n\t\tn >>= 1;\n\t}\n\treturn ret;\n}\n\n// others\nstruct fast_io {\n\tfast_io() {\n\t\tios::sync_with_stdio(false);\n\t\tcin.tie(nullptr);\n\t\tcout << fixed << setprecision(15);\n\t}\n} fast_io_;\nconst int inf = 1e9;\nconst ll INF = 1e18;\n#pragma endregion\n\nvoid main_();\n\nint main() {\n\tint t;\n\tcin >> t;\n\twhile(t--) main_();\n\treturn 0;\n}\n#line 2 \"a.cpp\"\n\nvoid main_() {\n\tINT(y, m, d);\n\tll res = 0;\n\twhile(y != 1000) {\n\t\tres++;\n\t\tbool big = 0;\n\t\tif(m & 1) big = 1;\n\t\tif(y % 3 == 0) big = 1;\n\t\tint MAX = (big ? 20 : 19);\n\t\tif(d < MAX) {\n\t\t\td++;\n\t\t\tcontinue;\n\t\t} else {\n\t\t\tm++;\n\t\t\td = 1;\n\t\t\tif(m == 11) {\n\t\t\t\tm = 1;\n\t\t\t\ty++;\n\t\t\t}\n\t\t}\n\t}\n\tprint(res);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3356, "score_of_the_acc": -0.0124, "final_rank": 8 } ]
aoj_1180_cpp
Recurring Decimals A decimal representation of an integer can be transformed to another integer by rearranging the order of digits. Let us make a sequence using this fact. A non-negative integer a 0 and the number of digits L are given first. Applying the following rules, we obtain a i +1 from a i . Express the integer a i in decimal notation with L digits. Leading zeros are added if necessary. For example, the decimal notation with six digits of the number 2012 is 002012. Rearranging the digits, find the largest possible integer and the smallest possible integer; In the example above, the largest possible integer is 221000 and the smallest is 000122 = 122. A new integer a i +1 is obtained by subtracting the smallest possible integer from the largest. In the example above, we obtain 220878 subtracting 122 from 221000. When you repeat this calculation, you will get a sequence of integers a 0 , a 1 , a 2 , ... . For example, starting with the integer 83268 and with the number of digits 6, you will get the following sequence of integers a 0 , a 1 , a 2 , ... . a 0 = 083268 a 1 = 886320 − 023688 = 862632 a 2 = 866322 − 223668 = 642654 a 3 = 665442 − 244566 = 420876 a 4 = 876420 − 024678 = 851742 a 5 = 875421 − 124578 = 750843 a 6 = 875430 − 034578 = 840852 a 7 = 885420 − 024588 = 860832 a 8 = 886320 − 023688 = 862632 … Because the number of digits to express integers is fixed, you will encounter occurrences of the same integer in the sequence a 0 , a 1 , a 2 , ... eventually. Therefore you can always find a pair of i and j that satisfies the condition a i = a j ( i > j ). In the example above, the pair ( i = 8, j = 1) satisfies the condition because a 8 = a 1 = 862632. Write a program that, given an initial integer a 0 and a number of digits L , finds the smallest i that satisfies the condition a i = a j ( i > j ). Input The input consists of multiple datasets. A dataset is a line containing two integers a 0 and L separated by a space. a 0 and L represent the initial integer of the sequence and the number of digits, respectively, where 1 ≤ L ≤ 6 and 0 ≤ a 0 < 10 L . The end of the input is indicated by a line containing two zeros; it is not a dataset. Output For each dataset, find the smallest number i that satisfies the condition a i = a j ( i > j ) and print a line containing three integers, j , a i and i − j . Numbers should be separated by a space. Leading zeros should be suppressed. Output lines should not contain extra characters. You can assume that the above i is not greater than 20. Sample Input 2012 4 83268 6 1112 4 0 1 99 2 0 0 Output for the Sample Input 3 6174 1 1 862632 7 5 6174 1 0 0 1 1 0 1
[ { "submission_id": "aoj_1180_10853944", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <vector>\n#include <map>\n#include <queue>\n#include <set>\nusing namespace std;\n#define SZ(v) ((int)(v).size())\n#define REP(i, n) for (int i = 0; i < (n); ++i)\n#define REPF(i, a, b) for (int i = (a); i <= (b); ++i)\n#define REPD(i, a, b) for (int i = (a); i >= (b); --i)\nconst int maxint = -1u>>1;\nconst int maxn = 10000000 + 2;\n\nint a, l;\nint d[maxn];\n\nint find_big(int x) {\n vector<int> v;\n while (x) {\n v.push_back(x % 10);\n x /= 10;\n }\n if (SZ(v) < l) {\n for (int i = SZ(v); i < l; ++i) v.push_back(0);\n }\n sort(v.begin(), v.end(), greater<int>());\n int res = 0;\n for (int i = 0; i < SZ(v); ++i) {\n res = res * 10 + v[i];\n }\n return res;\n}\n\nint find_small(int x) {\n vector<int> v;\n while (x) {\n v.push_back(x % 10);\n x /= 10;\n }\n if (SZ(v) < l) {\n for (int i = SZ(v); i < l; ++i) v.push_back(0);\n }\n sort(v.begin(), v.end());\n int res = 0;\n for (int i = 0; i < SZ(v); ++i) {\n res = res * 10 + v[i];\n }\n return res;\n}\n\nint main() {\n while (scanf(\"%d%d\", &a, &l) == 2 && a + l) {\n memset(d, -1, sizeof(d));\n int p = a, pos = 0;\n d[a] = pos++;\n while (true) {\n int big = find_big(p);\n int small = find_small(p);\n if (d[big - small] >= 0) {\n printf(\"%d %d %d\\n\", d[big - small], big - small, pos - d[big - small]);\n break;\n } \n p = big - small;\n d[p] = pos++;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 42548, "score_of_the_acc": -1.1014, "final_rank": 18 }, { "submission_id": "aoj_1180_6725397", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<algorithm>\n\nusing namespace std;\n\n\nsigned main(){\n\t\n\tfor(int _ = 1; ;_++){\n\t\tstring a;\n\t\tint L, t = 1;\n\t\tvector<int> used;\n\t\t\n\t\tcin>>a>>L;\n\t\t\n\t\tif(L == 0) break;\n\t\t\n\t\tfor(int i = 0; i < L; i++) t *= 10;\n\t\t\n\t\tused.resize(t);\n\t\t\n\t\tused[stoi(a)] = 1;\n\t\t\n\t\ta = string(L - a.size(), '0') + a;\n\t\t\n\t\tfor(int i = 2; ; i++){\n\t\t\tint maxi, mini, nex;\n\t\t\t\n\t\t\tsort(a.begin(), a.end());\n\t\t\t\n\t\t\tmini = stoi(a);\n\t\t\t\n\t\t\treverse(a.begin(), a.end());\n\t\t\t\n\t\t\tmaxi = stoi(a);\n\t\t\t\n\t\t\tnex = maxi - mini;\n\t\t\t\n\t\t\ta = to_string(nex);\n\t\t\t\n\t\t\ta = string(L - a.size(), '0') + a;\n\t\t\t\n\t\t\t// cout<<i<<\" \"<<a<<\" \"<<maxi<<\" - \"<<mini<<endl;\n\t\t\tif(used[nex]) {\n\t\t\t\tcout<<used[nex]-1<<\" \"<<stoi(a)<<\" \"<<i - used[nex] <<endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\t\n\t\t\tused[nex] = i;\n\t\t\t\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7396, "score_of_the_acc": -0.0092, "final_rank": 4 }, { "submission_id": "aoj_1180_6000624", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// clang-format off\n//#include <atcoder/modint>\n//using namespace atcoder;\nusing ll = long long;\nusing ld = long double;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\nusing pdd = pair<ld, ld>;\nusing vii = vector<int>;\nusing vll = vector<ll>;\nusing vdd = vector<ld>;\nusing vvii = vector<vector<int>>;\nusing vvll = vector<vector<ll>>;\nusing vvdd = vector<vector<ld>>;\nusing vvvii = vector<vector<vector<int>>>;\nusing vvvll = vector<vector<vector<ll>>>;\nusing vvvdd = vector<vector<vector<ld>>>;\ntemplate<class T, class U> using P = pair<T, U>;\ntemplate<class T> using V1 = vector<T>;\ntemplate<class T> using V2 = vector<vector<T>>;\ntemplate<class T> using V3 = vector<vector<vector<T>>>;\ntemplate<class T> using pque = priority_queue<T, vector<T>, greater<T>>;\n#define _overload3(_1, _2, _3, name, ...) name\n#define rep1(n) for (ll i = 0; i < (n); i++)\n#define rep2(i, n) for (ll i = 0; i < (n); i++)\n#define rep3(i, a, b) for (ll i = (a); i < (b); i++)\n#define rep(...) _overload3(__VA_ARGS__, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep1(n) for (ll i = (n) - 1; i >= 0; i--)\n#define rrep2(i, n) for (ll i = (n) - 1; i >= 0; i--)\n#define rrep3(i, a, b) for (ll i = (b) - 1; i >= (a); i--)\n#define rrep(...) _overload3(__VA_ARGS__, rrep3, rrep2, rrep1)(__VA_ARGS__)\n#define all(x) (x).begin(), (x).end()\n#define sz(x) ((int)(x).size())\n#define fi first\n#define se second\n#define pb push_back\n#define endl '\\n'\n#define popcnt(x) __builtin_popcountll(x)\n#define uniq(x) (x).erase(unique((x).begin(), (x).end()), (x).end());\n#define IOS ios::sync_with_stdio(false); cin.tie(nullptr);\nconst int inf = 1 << 30;\nconst ll INF = 1ll << 60;\nconst ld DINF = numeric_limits<ld>::infinity();\nconst ll mod = 1000000007;\n//const ll mod = 998244353;\nconst ld EPS = 1e-9;\nconst ld PI = 3.1415926535897932;\n//const ll dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};\n//const ll dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};\ntemplate<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }\ntemplate<typename T> T minV(const vector<T> &x) { return *min_element(all(x)); }\ntemplate<typename T> T maxV(const vector<T> &x) { return *max_element(all(x)); }\ntemplate<class T, class U> ostream &operator<<(ostream &os, const pair<T, U> &p) { return os << \"(\" << p.fi << \", \" << p.se << \")\"; }\ntemplate<class T> ostream &operator<<(ostream &os, const vector<T> &v) { os << \"[ \"; for (auto &z : v) os << z << \" \"; os << \"]\"; return os; }\n#ifdef _DEBUG\n#define show(x) cout << #x << \" = \" << x << endl;\n#else\n#define show(x)\n#endif\nll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; }\nll lcm(ll a, ll b) { return (a / gcd(a, b)) * b; }\nll rem(ll a, ll b) { return (a % b + b) % b; }\n// clang-format on\n\n// modint(ac-library)\n// using mint = modint998244353;\n// using mint = modint1000000007;\n// ostream &operator<<(ostream &os, const mint &p) { return os << p.val(); }\n\nll modpow(ll a, ll N, ll mod) {\n ll res = 1;\n // 例えば3=101(2)なので、下位bitから順に1ならa倍する\n while (N) {\n if (N & 1) res = res * a % mod;\n a = a * a % mod;\n N >>= 1;\n }\n return res;\n}\n\nll next(ll a, ll L) {\n vii b;\n ll cur = a;\n rep(i, L) {\n b.pb(a % 10);\n a /= 10;\n }\n sort(all(b));\n reverse(all(b));\n ll ma = 0;\n for (ll bi : b) {\n ma = ma * 10 + bi;\n }\n reverse(all(b));\n ll mi = 0;\n for (ll bi : b) {\n mi = mi * 10 + bi;\n }\n return ma - mi;\n}\n\nvoid solve(ll a, ll L) {\n vii seen(1000006, -1);\n int cnt = 0;\n while (1) {\n show(a);\n seen[a] = cnt++;\n a = next(a, L);\n if (seen[a] != -1) {\n cout << seen[a] << \" \" << a << \" \" << cnt - seen[a] << endl;\n return;\n }\n }\n return;\n}\n\nint main() {\n ll a, L;\n while (cin >> a >> L, L) {\n solve(a, L);\n }\n return 0;\n}\n\n/*\n\n*/", "accuracy": 1, "time_ms": 20, "memory_kb": 7272, "score_of_the_acc": -0.0202, "final_rank": 10 }, { "submission_id": "aoj_1180_5957714", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<algorithm>\n\nusing namespace std;\n\n\nsigned main(){\n\t\n\tfor(int _ = 1; ;_++){\n\t\tstring a;\n\t\tint L, t = 1;\n\t\tvector<int> used;\n\t\t\n\t\tcin>>a>>L;\n\t\t\n\t\tif(L == 0) break;\n\t\t\n\t\tfor(int i = 0; i < L; i++) t *= 10;\n\t\t\n\t\tused.resize(t);\n\t\t\n\t\tused[stoi(a)] = 1;\n\t\t\n\t\ta = string(L - a.size(), '0') + a;\n\t\t\n\t\tfor(int i = 2; ; i++){\n\t\t\tint maxi, mini, nex;\n\t\t\t\n\t\t\tsort(a.begin(), a.end());\n\t\t\t\n\t\t\tmini = stoi(a);\n\t\t\t\n\t\t\treverse(a.begin(), a.end());\n\t\t\t\n\t\t\tmaxi = stoi(a);\n\t\t\t\n\t\t\tnex = maxi - mini;\n\t\t\t\n\t\t\ta = to_string(nex);\n\t\t\t\n\t\t\ta = string(L - a.size(), '0') + a;\n\t\t\t\n\t\t\t// cout<<i<<\" \"<<a<<\" \"<<maxi<<\" - \"<<mini<<endl;\n\t\t\tif(used[nex]) {\n\t\t\t\tcout<<used[nex]-1<<\" \"<<stoi(a)<<\" \"<<i - used[nex] <<endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\t\n\t\t\tused[nex] = i;\n\t\t\t\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7376, "score_of_the_acc": -0.0087, "final_rank": 2 }, { "submission_id": "aoj_1180_5841116", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cmath>\n#include <algorithm>\n#include <string>\n#include <map>\n#include <bitset>\n#include <vector>\n#include <queue>\n#include <set>\n\nusing namespace std;\n\ntypedef long long ll;\n#define FOR(i,a,b) for(ll i = (a); i < (b); i++ )\n#define REP(i, n) FOR(i,0,n)\ntypedef pair< ll, ll > cp2;\ntypedef pair< string, cp2 > cp3;\n#define fi first\n#define se second\n#define sec se.fi\n#define thr se.se\nconst ll mod = 1000000000000000003;\n// 123456789012345678\n\n\n///////////////////////////////////////////////\n//\n//\n///////////////////////////////////////////////\n\n////////////////////////////////////////////////\n////////////////////////////////////////////////\n\nint A;\nint L;\n\nint f[1000000];\n\nint next_num( int A ){\n int d[L];\n int X = 0;\n int Y = 0;\n REP( i, L ){\n d[i] = A%10;\n A = A/10;\n }\n sort( d, d+L );\n REP( i, L ){\n X *= 10;\n Y *= 10;\n X += d[i];\n Y += d[L-i-1];\n }\n return Y-X;\n}\n\nint main(){\n \n while( 1 ){\n cin>>A>>L;\n int N = pow( 10, L );\n fill( f, f+N, -1 );\n if( A == 0 && L == 0 ) break;\n REP( i, N ){\n if( f[A] != -1 ){\n cout<<f[A]<<\" \"<<A<<\" \"<<i-f[A]<<endl;\n break;\n }\n f[A] = i;\n A = next_num( A );\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7720, "score_of_the_acc": -0.0184, "final_rank": 9 }, { "submission_id": "aoj_1180_5715847", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<functional>\n#define rep(i,n) for(ll i = 0; i < (n); i++)\nusing ll = long long;\nusing namespace std;\n\nint main(){\n vector<ll>ans;\n while(1){\n ll A, L;\n cin >> A >> L;\n if(L == 0) break; //Lは1より大きい条件なので、Lが0だったら終了。 \n vector<ll>index(1e6); //数列に現れた数字かどうかを確認するための配列。\n index[A] = 1; //Aという数字が得られたとき、配列のA番目に、数列の順番+1を格納する。+1するのは、0番目を1番目と考えたいから。(35行目参照)\n ll count = 1; //数列の順番+1を管理。\n while(1){ //同じ数字が現れるまで繰り返す\n count++;\n vector<ll>v_max(L); //最も大きい整数を作るための配列。\n rep(i,L){\n v_max[i] = A % 10; //Aの各桁の数を格納していく。\n A /= 10;\n }\n vector<ll>v_min = v_max; //最も小さい整数を作るための配列も準備。\n sort(v_max.begin(), v_max.end(), greater<>()); //降順にソート。\n sort(v_min.begin(), v_min.end()); //昇順にソート。\n ll x = 0, y = 0; //xが最も大きい、yが最も小さい整数。\n rep(i,L){ //ここでxとyを作る。\n x *= 10; y *= 10;\n x += v_max[i]; y += v_min[i]; \n }\n A = x - y;\n if(index[A] != 0){ //index[A]が0じゃない->数列の順番が格納されている->既に過去に現れた数字である\n ans.push_back(index[A]-1);\n ans.push_back(A);\n ans.push_back(count-index[A]);\n break;\n }else index[A] = count;\n }\n }\n rep(i,ans.size()/3) cout << ans[i*3] << ' ' << ans[i*3+1] << ' ' << ans[i*3+2] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 11192, "score_of_the_acc": -0.1307, "final_rank": 13 }, { "submission_id": "aoj_1180_5715806", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<functional>\n#define rep(i,n) for(ll i = 0; i < (n); i++)\nusing ll = long long;\nusing namespace std;\n\nint main(){\n vector<ll>ans;\n while(1){\n ll A, L;\n cin >> A >> L;\n if(L == 0) break;\n vector<ll>index(1e6);\n index[A] = 1;\n ll count = 1;\n while(1){\n count++;\n vector<ll>v_max(L);\n rep(i,L){\n v_max[i] = A % 10;\n A /= 10;\n }\n vector<ll>v_min = v_max;\n sort(v_max.begin(), v_max.end(), greater<>());\n sort(v_min.begin(), v_min.end());\n ll x = 0, y = 0;\n rep(i,L){\n x += v_max[i]; y += v_min[i];\n x *= 10; y *= 10;\n }\n x /= 10; y /= 10;\n A = x - y;\n if(index[A] != 0){\n ans.push_back(index[A]-1);\n ans.push_back(A);\n ans.push_back(count-index[A]);\n break;\n }else index[A] = count;\n }\n }\n rep(i,ans.size()/3) cout << ans[i*3] << ' ' << ans[i*3+1] << ' ' << ans[i*3+2] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 11260, "score_of_the_acc": -0.1326, "final_rank": 14 }, { "submission_id": "aoj_1180_5331302", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(int i = 0; i < n; i++)\n#define rep2(i, x, n) for(int i = x; i <= n; i++)\n#define rep3(i, x, n) for(int i = x; i >= n; i--)\n#define each(e, v) for(auto &e: v)\n#define pb push_back\n#define eb emplace_back\n#define all(x) x.begin(), x.end()\n#define rall(x) x.rbegin(), x.rend()\n#define sz(x) (int)x.size()\nusing ll = long long;\nusing pii = pair<int, int>;\nusing pil = pair<int, ll>;\nusing pli = pair<ll, int>;\nusing pll = pair<ll, ll>;\nconst int MOD = 1000000007;\n//const int MOD = 998244353;\nconst int inf = (1<<30)-1;\nconst ll INF = (1LL<<60)-1;\ntemplate<typename T> bool chmax(T &x, const T &y) {return (x < y)? (x = y, true) : false;};\ntemplate<typename T> bool chmin(T &x, const T &y) {return (x > y)? (x = y, true) : false;};\n\nstruct io_setup{\n io_setup(){\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cout << fixed << setprecision(15);\n }\n} io_setup;\n\nint nxt(int A, int K){\n vector<int> c(K);\n rep(i, K){\n c[i] = A%10, A /= 10;\n }\n\n sort(all(c));\n\n int L = 0;\n each(e, c) L *= 10, L += e;\n\n reverse(all(c));\n int R = 0;\n each(e, c) R *= 10, R += e;\n\n return R-L;\n}\n\nint main(){\n while(true){\n int A, K; cin >> A >> K;\n if(K == 0) break;\n\n int pw = 1;\n rep(i, K) pw *= 10;\n\n vector<int> ids(pw, -1);\n\n for(int i = 0; ; i++){\n if(ids[A] == -1) ids[A] = i;\n else{\n cout << ids[A] << ' ' << A << ' ' << i-ids[A] << '\\n';\n break;\n }\n A = nxt(A, K);\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7376, "score_of_the_acc": -0.0087, "final_rank": 2 }, { "submission_id": "aoj_1180_4957259", "code_snippet": "#include<bits/stdc++.h>\n//#include <atcoder/all>\n\n#define INF 1e9\n#define rep(i,n)for(int i=0;(i)<(int)(n);i++)\n#define REP(i,a,b)for(int i=(int)(a);(i)<=(int)(b);i++)\n#define ALL(a) (a).begin(),(a).end()\n#define chmax(a, b) a = max(a, b)\n#define chmin(a, b) a = min(a, b)\n#define pb push_back\n#define fi first\n#define se second\n#define sz(x) ((int)x.size())\n\nusing namespace std;\n//using namespace atcoder;\nusing ll = long long int;\nusing ld = long double;\nusing P = pair<ll, ll>;\nusing Graph = vector<vector<int>>;\n//using mint = modint1000000007;\n\nconst ll ZER = 0;\nconst ll MOD = 1e9 + 7;\n\nint main(){\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n\n int base, len;\n while(cin >> base >> len){\n if(base == 0 && len == 0)break;\n int cnt = 0;\n vector<vector<int>> a(31);\n vector<int> ch(1001000, -1);\n ch[base] = 0;\n REP(cnt, 1, 25){\n rep(i, len){\n a[cnt].pb(base % 10);\n base /= 10;\n }\n auto t1 = a[cnt], t2 = a[cnt];\n sort(ALL(t1));\n sort(ALL(t2), greater<int>());\n int ma = 0, mi = 0;\n rep(i, len)ma = 10 * ma + t2[i];\n rep(i, len)mi = 10 * mi + t1[i];\n base = ma - mi;\n if(ch[base] > -1){\n cout << ch[base] << \" \" << base << \" \" << cnt - ch[base] << endl;\n break;\n }\n else ch[base] = cnt;\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7296, "score_of_the_acc": -0.0209, "final_rank": 11 }, { "submission_id": "aoj_1180_4942824", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\n\nusing namespace std;\n\nint str2int(string s) {\n int ans = 0;\n for (int i = 0; i < s.size(); i++) {\n ans *= 10;\n ans += (int)(s[i] - '0');\n }\n return ans;\n}\n\nint main() {\n while (1) {\n string a; int n; cin >> a >> n;\n if (n == 0) { break; }\n\n while (a.size() < n) {\n a = \"0\" + a;\n }\n vector<int> v(1000000, -1);\n for (int i = 0; i <= 2000000; i++) {\n int b = str2int(a);\n if (v[b] != -1) {\n cout << v[b] << \" \" << b << \" \" << i - v[b] << endl;\n break;\n }\n v[b] = i;\n sort(a.begin(), a.end(), greater<int>());\n b = str2int(a);\n sort(a.begin(), a.end());\n b -= str2int(a);\n\n a = to_string(b);\n while (a.size() < n) {\n a = \"0\" + a;\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7144, "score_of_the_acc": -0.0166, "final_rank": 7 }, { "submission_id": "aoj_1180_4929591", "code_snippet": "#define _USE_MATH_DEFINES\n#include <iostream>\n#include <fstream>\n#include <sstream>\n#include <string>\n#include <cstring>\n#include <vector>\n#include <set>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <algorithm>\n#include <bitset>\n#include <cmath>\n#include <cstdlib>\n#include <ctime>\n#include <numeric>\n#include <functional>\n#include <cctype>\n#include <list>\n#include <limits>\n#include <cassert>\n#include <random>\n#include <time.h>\n#include <unordered_set>\n\nusing namespace std;\nusing Int = long long;\n\nconstexpr double EPS = 1e-10;\nconstexpr long long MOD = 1000000007;\n\nlong long mod_pow(long long x, long long n) {\n long long res = 1;\n for (int i = 0;i < 60; i++) {\n if (n >> i & 1) res = res * x % MOD;\n x = x * x % MOD;\n }\n return res;\n}\n\nlong long my_mod_pow(long long x, long long n) {\n\tlong long ret = 1;\n\tfor (; n > 0; n >>= 1, x = x * x % MOD) {\n\t\tif (n & 1) {\n\t\t\tret = ret * x % MOD;\n\t\t}\n\t}\n\treturn ret;\n}\n\ntemplate<typename T>\nT gcd(T a, T b) {\n return b != 0 ? gcd(b, a % b) : a;\n}\n\ntemplate<typename T>\nT lcm(T a, T b) {\n return a * b / gcd(a, b);\n}\n\nvoid fastInput() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n}\n\nvector<int> solve(int A, int L) {\n vector<int> table(10000000, -1);\n table[A] = 0;\n vector<int> tmp;\n for (int k = 1;; k++) {\n tmp.clear();\n for (int i = 0; i < L; i++) {\n tmp.push_back(A%10);\n A /= 10;\n }\n \n sort(tmp.begin(), tmp.end());\n reverse(tmp.begin(), tmp.end());\n int b = 0;\n int place = 1;\n for (int i = 0; i < L; i++) {\n b += place * tmp[i];\n place *= 10;\n }\n\n sort(tmp.begin(), tmp.end(), greater<int>());\n reverse(tmp.begin(), tmp.end());\n int a = 0;\n place = 1;\n for (int i = 0; i < L; i++) {\n a += place * tmp[i];\n place *= 10;\n }\n A = a - b;\n if (table[A] != -1) {\n return vector<int> {table[A], A, k - table[A]};\n } else {\n table[A] = k;\n }\n }\n}\n\nint main(void) {\n vector<vector<int>> ans;\n int A, L;\n cin >> A >> L;\n while (A != 0 || L != 0) {\n ans.push_back(solve(A, L));\n cin >> A >> L;\n }\n for (int i = 0; i < ans.size(); i++) {\n for (int j = 0; j < ans[i].size(); j++) {\n if (j != ans[i].size() -1) cout << ans[i][j] << \" \";\n else cout << ans[i][j];\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 700, "memory_kb": 41844, "score_of_the_acc": -1.9802, "final_rank": 20 }, { "submission_id": "aoj_1180_3845971", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\n#include<cmath>\n#include<limits>\n#include<algorithm>\n#include<numeric>\n#include<utility>\n\nusing ull = unsigned long long int;\nusing ll = long long int;\n\nint main(){\n std::vector<std::string> num;\n std::vector<int> keta;\n\n while(true){\n std::string _num;\n int _keta;\n std::cin >> _num >> _keta;\n\n if(_num == \"0\" && _keta == 0) break;\n for(int i=_num.size();i<_keta;i++){\n _num+='0';\n }\n num.emplace_back(_num);\n keta.emplace_back(_keta);\n }\n\n for(int i=0;i<num.size();i++){\n int _diff;\n int diff = std::stoi(num[i]);\n int cnt=1;\n\n std::vector<int> ans(1000000,0);\n\n ans[diff]=cnt;\n\n while(true){\n std::string max_s = std::to_string(diff);\n std::string min_s = std::to_string(diff);\n\n for(int j=max_s.size();j<keta[i];j++){\n max_s+='0';\n min_s+='0';\n }\n\n std::sort(max_s.begin(),max_s.end(),std::greater<int>());\n std::sort(min_s.begin(),min_s.end());\n int max = std::stoi(max_s);\n int min = std::stoi(min_s);\n\n _diff = max-min;\n //std::cout << \"diff \" << _diff << std::endl;\n cnt++;\n if(ans[_diff]!=0) break;\n else ans[_diff]=cnt;\n diff = _diff;\n }\n\n std::cout << ans[_diff]-1 << \" \" << _diff << \" \" << cnt-ans[_diff] << std::endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7104, "score_of_the_acc": -0.0155, "final_rank": 5 }, { "submission_id": "aoj_1180_3737235", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint a[1000000];\n\nint pow10(int n){\n int res = 1;\n for(int i = 0; i < n; i++) res *= 10;\n return res;\n}\n\nint main()\n{\n while(true){\n int n, l;\n cin >> n >> l;\n if(n == 0 && l == 0) break;\n fill(a, a + pow10(l), 0);\n int i = 1;\n while(true){\n if(a[n]) break;\n a[n] = i;\n i++;\n int cmax[6], cmin[6];\n for(int j = 0; j < l; j++){\n cmax[j] = cmin[j] = n % 10;\n n /= 10;\n }\n sort(cmax, cmax + l, greater<int>());\n sort(cmin, cmin + l);\n n = 0;\n for(int j = 0; j < l; j++){\n n = n + pow10(l - 1 - j) * (cmax[j] - cmin[j]);\n }\n }\n cout << a[n] - 1 << \" \" << n << \" \" << i - a[n] << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7068, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1180_3736511", "code_snippet": "// Undone\n#include <bits/stdc++.h>\nusing namespace std;\nint calc(string a) {\n string r = a;\n sort(r.begin(), r.end());\n string l = r;\n reverse(l.begin(), l.end());\n return (stoi(l) - stoi(r));\n}\n\nsigned main() {\n int _a, L;\n while (cin >> _a >> L, _a+L) {\n vector<int> used(1000000, 0), when(1000000, 0);\n int ans = 0;\n while (0 == 0) {\n string a = to_string(_a);\n while (a.length() < L) {\n a.insert(0, \"0\");\n }\n _a = stoi(a);\n used[_a] = 1;\n when[_a] = ans;\n _a = calc(a);\n ans++;\n if (used[_a] == 1) {\n cout << when[_a] << \" \" << _a << \" \" << (ans-when[_a]) << endl;\n break;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 10952, "score_of_the_acc": -0.2834, "final_rank": 17 }, { "submission_id": "aoj_1180_3726582", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n while(1){\n int a0, L;\n scanf(\"%d%d\", &a0, &L);\n if(L==0)break;\n int lst[1000000];\n for(int i=0;i<1000000;i++)lst[i]=-1;\n lst[a0]=0;\n for(int i=1;;i++){\n int a1=0, a2=0;\n int as[L];\n for(int j=0;j<L;j++){as[j]=a0%10;a0/=10;}\n sort(as, as+L);\n for(int j=0;j<L;j++){\n a1*=10;\n a2*=10;\n a1+=as[L-1-j];\n a2+=as[j];\n }\n a0=a1-a2;\n if(lst[a0]==-1)lst[a0]=i;\n else{\n printf(\"%d %d %d\\n\", lst[a0], a0, i-lst[a0]);\n break;\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7188, "score_of_the_acc": -0.0179, "final_rank": 8 }, { "submission_id": "aoj_1180_3723351", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define REP(i,n) for(int i=0; i<n; i++)\n#define FOR(i,a,b) for(int i=a; i<b; i++)\n#define FORR(i,a,b) for(int i=(int)b-1; i>=a; i--)\n\n#define ALL(v) (v).begin(), (v).end()\n\nusing ll = long long;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\nusing vi = vector<int>;\nusing vl = vector<ll>;\n\n#define DEBUG(x) cerr<<#x<<\": \"<<(x)<<endl\n\nint past[1252830];\n\nint main(){\n while(true){\n int a,l;\n cin>>a>>l;\n if(a+l==0)break;\n fill(past,past+1252830,-1);\n past[a] = 0;\n int i = 1;\n while(true){\n string s = to_string(a);\n while(s.size()!=l)s += \"0\";\n sort(ALL(s));\n int mn = stoi(s);\n reverse(ALL(s));\n int mx = stoi(s);\n a = mx - mn;\n if(past[a] != -1){\n printf(\"%d %d %d\\n\", past[a], a, i-past[a]);\n break;\n }\n past[a] = i;\n i++;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 8156, "score_of_the_acc": -0.0452, "final_rank": 12 }, { "submission_id": "aoj_1180_3722426", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define REP(i,n) for(int i=0; i<n; i++)\n\nusing ll = long long;\ntemplate<typename T>\nvoid fill_all(T& arr, const T& v) {\n arr = v;\n}\ntemplate<typename ARR, typename U>\nvoid fill_all(ARR& arr, const U& v) {\n for(auto& i: arr){fill_all(i, v);}\n}\n\nint used[2000000];\n\nint main(){\n \n while(1){\n int a, l;\n cin >> a>>l;\n if(a==0 && l==0){break;}\n fill_all(used, -1);\n\n size_t i = 0;\n for (; used[a] == -1 ; i++)\n {\n used[a] = i;\n string s = to_string(a);\n while(s.size()<l){\n s = \"0\"+s;\n }\n std::sort(s.begin(), s.end());\n int mmm = stoi(s);\n std::sort(s.begin(), s.end(), greater<>{});\n int maxmax = stoi(s);\n a = maxmax - mmm; \n }\n cout << used[a] <<' ' << a << ' ' << i-used[a] << endl;\n \n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 11092, "score_of_the_acc": -0.1714, "final_rank": 16 }, { "submission_id": "aoj_1180_3546485", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> l_l;\ntypedef pair<int, int> i_i;\n\n#define EPS (1e-7)\n#define INF (1e9)\n#define PI (acos(-1))\n//const ll mod = 1000000007;\nint digit(int in) {\n if(in < 10) return 1;\n else return 1 + digit(in / 10);\n}\n\nint main() {\n //cout.precision(10);\n cin.tie(0);\n ios::sync_with_stdio(false);\n while(true) {\n int a, L;\n cin >> a >> L;\n if(L == 0) break;\n vector<int> v;\n v.resize(1005000, -1);\n v[a] = 0;\n int index = 0;\n while(true) {\n index++;\n while(digit(a) < L && a != 0) a *= 10;\n string S = to_string(a);\n string T = S;\n sort(S.begin(), S.end());\n sort(T.begin(), T.end(), greater<char>());\n a = stoi(T) - stoi(S);\n if(v[a] != -1) break;\n v[a] = index;\n }\n cout << v[a] << \" \" << a << \" \" << index - v[a] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7136, "score_of_the_acc": -0.0164, "final_rank": 6 }, { "submission_id": "aoj_1180_3217637", "code_snippet": "//http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=1180\n#include <iostream>\n#include <string>\n#include <vector>\n#include <set>\n#include <map>\n#include <cmath>\n#include <algorithm>\n#include <iomanip>\n#include <queue>\nusing ll = long long;\nusing namespace std;\n\nint const MOD = 1e9 + 7;\n\nint main(void)\n{\n int n, L;\n\n while (cin >> n >> L, n || L)\n {\n int ans = 0;\n int t = n;\n map<int, int> mp;\n vector<vector<int>> memo(1e6);\n if (memo[t].size() == 2)\n break;\n\n memo[t].push_back(ans);\n\n while (1)\n {\n vector<int> v;\n\n while (t)\n {\n v.push_back(t % 10);\n t /= 10;\n }\n while (1)\n {\n if ((int)v.size() == L)\n break;\n v.push_back(0);\n }\n\n int minV = 0, maxV = 0;\n sort(v.begin(), v.end());\n\n t = 1;\n\n for (int i = 0; i < L; ++i)\n {\n maxV += t * v[i];\n t *= 10;\n }\n t = 1;\n for (int i = L - 1; i >= 0; --i)\n {\n minV += t * v[i];\n t *= 10;\n }\n t = maxV - minV;\n ans++;\n if (memo[t].size() == 2)\n break;\n\n memo[t].push_back(ans);\n }\n cout << memo[t][0] << \" \" << t << \" \" << memo[t][1] - memo[t][0] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 26604, "score_of_the_acc": -1.1448, "final_rank": 19 }, { "submission_id": "aoj_1180_3124734", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define INF_LL (int64)1e18\n#define INF (int32)1e9\n#define REP(i, n) for(int64 i = 0;i < (n);i++)\n#define FOR(i, a, b) for(int64 i = (a);i < (b);i++)\n#define all(x) x.begin(),x.end()\n#define fs first\n#define sc second\n\nusing int32 = int_fast32_t;\nusing uint32 = uint_fast32_t;\nusing int64 = int_fast64_t;\nusing uint64 = uint_fast64_t;\nusing PII = pair<int32, int32>;\nusing PLL = pair<int64, int64>;\n\nconst double eps = 1e-10;\n\ntemplate<typename A, typename B>inline void chmin(A &a, B b){if(a > b) a = b;}\ntemplate<typename A, typename B>inline void chmax(A &a, B b){if(a < b) a = b;}\n\nint64 calc(int64 x, int64 dig){\n\tvector<int32> v;\n\tREP(i, dig){\n\t\tv.push_back(x%10);\n\t\tx /= 10;\n\t}\n\tint64 mini = 0, maxi = 0;\n\tsort(all(v));\n\tREP(i, dig){\n\t\tmaxi = maxi*10+v[i];\n\t}\n\tfor(int32 i = dig-1;i >= 0;i--){\n\t\tmini = mini*10+v[i];\n\t}\n\treturn mini-maxi;\n}\n\nint32 memo[1123456];\n\nint main(void){\n\tint64 n, d;\n\twhile(cin >> n >> d && n+d){\n\t\tmemset(memo, -1, sizeof memo);\n\t\tint64 cnt = 0;\n\t\twhile(memo[n] == -1){\n\t\t\tmemo[n] = cnt;\n\t\t\tn = calc(n, d);\n\t\t\tcnt++;\n\t\t}\n\t\tcout << memo[n] << \" \" << n << \" \" << cnt-memo[n] << endl;\n\t}\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 11840, "score_of_the_acc": -0.1635, "final_rank": 15 } ]
aoj_1187_cpp
ICPC Ranking Your mission in this problem is to write a program which, given the submission log of an ICPC (International Collegiate Programming Contest), determines team rankings. The log is a sequence of records of program submission in the order of submission. A record has four fields: elapsed time, team number, problem number, and judgment. The elapsed time is the time elapsed from the beginning of the contest to the submission. The judgment field tells whether the submitted program was correct or incorrect, and when incorrect, what kind of an error was found. The team ranking is determined according to the following rules. Note that the rule set shown here is one used in the real ICPC World Finals and Regionals, with some detail rules omitted for simplification. Teams that solved more problems are ranked higher. Among teams that solve the same number of problems, ones with smaller total consumed time are ranked higher. If two or more teams solved the same number of problems, and their total consumed times are the same, they are ranked the same. The total consumed time is the sum of the consumed time for each problem solved. The consumed time for a solved problem is the elapsed time of the accepted submission plus 20 penalty minutes for every previously rejected submission for that problem. If a team did not solve a problem, the consumed time for the problem is zero, and thus even if there are several incorrect submissions, no penalty is given. You can assume that a team never submits a program for a problem after the correct submission for the same problem. Input The input is a sequence of datasets each in the following format. The last dataset is followed by a line with four zeros. M T P R m 1 t 1 p 1 j 1 m 2 t 2 p 2 j 2 ..... m R t R p R j R The first line of a dataset contains four integers M , T , P , and R . M is the duration of the contest. T is the number of teams. P is the number of problems. R is the number of submission records. The relations 120 ≤ M ≤ 300, 1 ≤ T ≤ 50, 1 ≤ P ≤ 10, and 0 ≤ R ≤ 2000 hold for these values. Each team is assigned a team number between 1 and T , inclusive. Each problem is assigned a problem number between 1 and P , inclusive. Each of the following R lines contains a submission record with four integers m k , t k , p k , and j k (1 ≤ k ≤ R ). m k is the elapsed time. t k is the team number. p k is the problem number. j k is the judgment (0 means correct, and other values mean incorrect). The relations 0 ≤ m k ≤ M −1, 1 ≤ t k ≤ T , 1 ≤ p k ≤ P , and 0 ≤ j k ≤ 10 hold for these values. The elapsed time fields are rounded off to the nearest minute. Submission records are given in the order of submission. Therefore, if i < j , the i -th submission is done before the j -th submission ( m i ≤ m j ). In some cases, you can determine the ranking of two teams with a difference less than a minute, by using this fact. However, such a fact is never used in the team ranking. Teams are ranked only using time informa ...(truncated)
[ { "submission_id": "aoj_1187_3560625", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS\n#include <stdio.h>\n#include <algorithm>\n#include <utility>\n#include <functional>\n#include <cstring>\n#include <queue>\n#include <stack>\n#include <math.h>\n#include <iterator>\n#include <vector>\n#include <string>\n#include <set>\n#include <math.h>\n#include <iostream> \n#include <random>\n#include<map>\n#include <iomanip>\n#include <time.h>\n#include <stdlib.h>\n#include <list>\n#include <typeinfo>\n#include <list>\n#include <set>\n#include <cassert>\n#include<fstream>\n#include <unordered_map> \nusing namespace std;\n#define Ma_PI 3.141592653589793\n#define eps 0.00000000000000000000000001\n#define LONG_INF 10000000000000000\n#define GOLD 1.61803398874989484820458\n#define MAX_MOD 1000000007\n#define REP(i,n) for(long long i = 0;i < n;++i)\nint main() {\n#define int long long \n\twhile (true) {\n\t\tint m, t, p, r;\n\t\tcin >> m >> t >> p >> r;\n\t\tint penalty[1000][1000] = {};\n\t\ttuple<int, int, int> team_info[1000] = {};\n\t\tif (m == 0) return 0;\n\t\tREP(i, r) {\n\t\t\tint a, b, c, d;\n\t\t\tcin >> a >> b >> c >> d;\n\t\t\tif (d == 0) {\n\t\t\t\t//Accepted\n\t\t\t\tget<0>(team_info[b]) += 1;//AC counter up\n\t\t\t\tget<2>(team_info[b]) += penalty[c][b];\n\t\t\t\tget<1>(team_info[b]) += a + penalty[c][b] * 20;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tpenalty[c][b]++;\n\t\t\t}\n\t\t}\n\t\tvector<tuple<int, int, int>> sortings;//AC,Time,number\n\t\tfor (int i = 1; i <= t; ++i) {\n\t\t\tsortings.push_back(make_tuple(get<0>(team_info[i]), get<1>(team_info[i]) * -1, i));\n\t\t}\n\t\tsort(sortings.begin(), sortings.end(), greater<tuple<int, int, int>>());\n\t\tqueue<int> teaming;\n\t\tpair<int, int> now_back = make_pair(-1, -1);\n\t\tfor (int i = 0; i < sortings.size(); ++i) {\n\t\t\tif (now_back == make_pair(get<0>(sortings[i]), get<1>(sortings[i]))) {\n\t\t\t\tteaming.push(get<2>(sortings[i]));\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (teaming.empty() == false) {\n\t\t\t\t\tint ok = 1;\n\t\t\t\t\twhile (teaming.empty() == false) {\n\t\t\t\t\t\tif (ok == 0) {\n\t\t\t\t\t\t\tcout << \"=\";\n\t\t\t\t\t\t}\n\t\t\t\t\t\tok = 0;\n\t\t\t\t\t\tcout << teaming.front();\n\t\t\t\t\t\tteaming.pop();\n\t\t\t\t\t}\n\t\t\t\t\tcout << \",\";\n\t\t\t\t}\n\t\t\t\tteaming.push(get<2>(sortings[i]));\n\t\t\t\tnow_back = make_pair(get<0>(sortings[i]), get<1>(sortings[i]));\n\t\t\t}\n\t\t}\n\t\tif (teaming.empty() == false) {\n\t\t\tint ok = 1;\n\t\t\twhile (teaming.empty() == false) {\n\t\t\t\tif (ok == 0) {\n\t\t\t\t\tcout << \"=\";\n\t\t\t\t}\n\t\t\t\tok = 0;\n\t\t\t\tcout << teaming.front();\n\t\t\t\tteaming.pop();\n\t\t\t}\n\t\t}\n\t\tcout << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 10920, "score_of_the_acc": -0.4938, "final_rank": 2 }, { "submission_id": "aoj_1187_2976466", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<cstring>\n#include<algorithm>\n\nusing namespace std;\n\nint M,T,P,R;\nint m[2000],t[2000],p[2000],j[2000];\nstruct team{\n\tint n,s,t,w[2000];\n};\n\nbool comp(const team &t1,const team &t2){\n\tif(t1.t==t2.t && t1.s==t2.s)return t1.n>t2.n;\n\tif(t1.s==t2.s)return t1.t<t2.t;\n\treturn t1.s>t2.s;\n};\n\nteam dat[2001];\n\nint main(void){\n\twhile(1){\n\t\tscanf(\"%d%d%d%d\",&M,&T,&P,&R);\n\t\tif(M+T+R+P==0)break;\n\t\tmemset(dat,0,sizeof(dat));\n\t\tfor(int i=0;i<T;i++)dat[i].n=i+1;\n\t\tfor(int i=0;i<R;i++){\n\t\t\tscanf(\"%d%d%d%d\",&m[i],&t[i],&p[i],&j[i]);\n\t\t\tif(j[i]!=0){\n\t\t\t\tdat[t[i]-1].w[p[i]]++;\n\t\t\t}else{\n\t\t\t\tdat[t[i]-1].s++;\n\t\t\t\tdat[t[i]-1].t+=m[i]+dat[t[i]-1].w[p[i]]*20;\n\t\t\t}\n\t\t}\n\t\tsort(dat,dat+T,comp);\n\t\tprintf(\"%d\",dat[0].n);\n\t\tfor(int i=1;i<T;i++){\n\t\t\tif(dat[i-1].s==dat[i].s && dat[i-1].t==dat[i].t)printf(\"=\");\n\t\t\telse printf(\",\");\n\t\t\tprintf(\"%d\",dat[i].n);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 18884, "score_of_the_acc": -2, "final_rank": 3 }, { "submission_id": "aoj_1187_2808286", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\nusing namespace std;\nstruct team{\n\tint num,p,cnt;\n\tint w[11];\n\tvoid init(int n)\n\t{\n\t\tnum=n;\n\t\tp=0;\n\t\tcnt=0;\n\t\tfor(int i=0;i++<10;)w[i]=0;\n\t}\n\tvoid submit(int m,int i,int j)\n\t{\n\t\tif(j)w[i]++;\n\t\telse p+=m+w[i]*20,cnt++;\n\t}\n\tbool operator<(team a)\n\t{\n\t\tif(cnt!=a.cnt)return cnt>a.cnt;\n\t\telse if(p!=a.p)return p<a.p;\n\t\telse return num>a.num;\n\t}\n\tbool operator==(team a)\n\t{\n\t\treturn cnt==a.cnt&&p==a.p;\n\t}\n};\nint M,T,P,R;\nmain()\n{\n\twhile(cin>>M>>T>>P>>R,M)\n\t{\n\t\tteam a[55];\n\t\tfor(int i=0;i++<T;)a[i].init(i);\n\t\tfor(int i=0;i<R;i++)\n\t\t{\n\t\t\tint b,c,d,e;cin>>b>>c>>d>>e;\n\t\t\ta[c].submit(b,d,e);\n\t\t}\n\t\tsort(a+1,a+T+1);\n\t\tfor(int i=0;i++<T;)\n\t\t{\n\t\t\tif(i==1)cout<<a[i].num;\n\t\t\telse\n\t\t\t{\n\t\t\t\tcout<<(a[i-1]==a[i]?\"=\":\",\")<<a[i].num;\n\t\t\t}\n\t\t}\n\t\tcout<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3152, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_1181_cpp
Biased Dice Professor Random, known for his research on randomized algorithms, is now conducting an experiment on biased dice. His experiment consists of dropping a number of dice onto a plane, one after another from a fixed position above the plane. The dice fall onto the plane or dice already there, without rotating, and may roll and fall according to their property. Then he observes and records the status of the stack formed on the plane, specifically, how many times each number appears on the faces visible from above. All the dice have the same size and their face numbering is identical, which we show in Figure C-1. Figure C-1: Numbering of a die The dice have very special properties, as in the following. (1) Ordinary dice can roll in four directions, but the dice used in this experiment never roll in the directions of faces 1, 2 and 3; they can only roll in the directions of faces 4, 5 and 6. In the situation shown in Figure C-2, our die can only roll to one of two directions. Figure C-2: An ordinary die and a biased die (2) The die can only roll when it will fall down after rolling, as shown in Figure C-3. When multiple possibilities exist, the die rolls towards the face with the largest number among those directions it can roll to. Figure C-3: A die can roll only when it can fall (3) When a die rolls, it rolls exactly 90 degrees, and then falls straight down until its bottom face touches another die or the plane, as in the case [B] or [C] of Figure C-4. (4) After rolling and falling, the die repeatedly does so according to the rules (1) to (3) above. Figure C-4: Example stacking of biased dice For example, when we drop four dice all in the same orientation, 6 at the top and 4 at the front, then a stack will be formed as shown in Figure C-4. Figure C-5: Example records After forming the stack, we count the numbers of faces with 1 through 6 visible from above and record them. For example, in the left case of Figure C-5, the record will be "0 2 1 0 0 0", and in the right case, "0 1 1 0 0 1". Input The input consists of several datasets each in the following format. n t 1 f 1 t 2 f 2 ... t n f n Here, n (1 ≤ n ≤ 100) is an integer and is the number of the dice to be dropped. t i and f i (1 ≤ t i , f i ≤ 6) are two integers separated by a space and represent the numbers on the top and the front faces of the i -th die, when it is released, respectively. The end of the input is indicated by a line containing a single zero. Output For each dataset, output six integers separated by a space. The integers represent the numbers of faces with 1 through 6 correspondingly, visible from above. There may not be any other characters in the output. Sample Input 4 6 4 6 4 6 4 6 4 2 5 3 5 3 8 4 2 4 2 4 2 4 2 4 2 4 2 4 2 4 2 6 4 6 1 5 2 3 5 3 2 4 4 2 0 Output for the Sample Input 0 1 1 0 0 1 1 0 0 0 1 0 1 2 2 1 0 0 2 3 0 0 0 0
[ { "submission_id": "aoj_1181_10609938", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\n#define all(v) v.begin(), v.end()\n#define rall(a) a.rbegin(), a.rend()\n#define fi first\n#define se second\n// #define endl \"\\n\"\n\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\n\ntemplate <typename T>\nusing vc = vector<T>; // prioriy_queueに必要なのでここにこれ書いてます\ntemplate <typename T>\nusing vv = vc<vc<T>>;\n#define int long long\nusing ll = long long;\nll INF = 2e18;\n\n#ifdef ONLINE_JUDGE\n// ジャッジ環境ではデバッグマクロを無効化\n#define debug_x(x) \\\n do \\\n { \\\n } while (0)\n#define debug_vc(v) \\\n do \\\n { \\\n } while (0)\n#define debug_vv(v) \\\n do \\\n { \\\n } while (0)\n#else\n// ローカルではデバッグ出力\n#define debug_x(x) cout << #x << \" = \" << (x) << endl\n#define debug_vc(v) \\\n { \\\n cout << #v << endl; \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << ' '; \\\n cout << endl; \\\n } // 一次元配列を出力する\n#define debug_vv(v) \\\n { \\\n cout << #v << endl; \\\n ll n = size(v); \\\n rep(i, n) \\\n { \\\n rep(j, size(v[i])) { cout << v[i][j] << ' '; } \\\n cout << endl; \\\n } \\\n } // 二次元配列を出力する\n#endif\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n#define rrep(i, n) for (ll i = 1; i <= (n); ++i)\n#define drep(i, n) for (ll i = (n) - 1; i >= 0; --i)\n#define nfor(i, s, n) for (ll i = s; i < n; i++) // i=s,s+1...n-1 ノーマルfor\n#define dfor(i, s, n) for (ll i = (s) - 1; i >= n; i--) // s-1スタートでnまで落ちる\n\nusing ld = long double;\nusing bl = bool;\n\ntemplate <class T>\nusing pq = priority_queue<T, vc<T>>; // 大きい順\ntemplate <class T>\nusing pq_g = priority_queue<T, vc<T>, greater<T>>; // 小さい順\n\nusing vl = vc<ll>;\nusing vvl = vv<ll>;\nusing vvvl = vv<vl>;\nusing vvvvl = vv<vvl>;\nusing vs = vc<string>;\nusing vvs = vv<string>;\nusing vb = vc<bl>;\nusing vvb = vv<bl>;\nusing vvvb = vv<vb>;\nusing vld = vc<ld>;\nusing vvld = vv<ld>;\nusing vvvld = vv<vld>;\nusing P = pair<ll, ll>;\nusing vP = vc<P>;\nusing vvP = vc<vP>;\nusing vvvP = vv<vP>;\n\n#define pb push_back\n\n#define YES cout << \"Yes\" << endl\n#define NO cout << \"No\" << endl\n#define YN \\\n { \\\n cout << \"Yes\" << endl; \\\n } \\\n else \\\n { \\\n cout << \"No\" << endl; \\\n } // if(a==b)YN;\n#define dame cout << -1 << endl\n\nstring dir = \"DRUL\"; // 第4象限の場合\n\nbool out_grid(ll i, ll j, ll h, ll w)\n{ // trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\nbl solve()\n{\n ll n;\n cin >> n;\n if (n == 0)\n return 0;\n vl t(n), f(n);\n rep(i, n)\n {\n cin >> t[i] >> f[i];\n }\n vvl die = {{}, {2, 3, 5, 4}, {1, 4, 6, 3}, {1, 2, 6, 5}, {1, 5, 6, 2}, {1, 3, 6, 4}, {2, 4, 5, 3}};\n map<P, ll> h;\n for (ll x = -200; x <= 200; x++)\n {\n for (ll y = -200; y <= 200; y++)\n {\n h[{x, y}] = 0;\n }\n }\n map<P, ll> me;\n vl ans(7);\n vl di = {1, 0, -1, 0}; // vl di={1,1,0,-1,-1,-1,0,1};\n vl dj = {0, 1, 0, -1}; // vl dj={0,1,1,1,0,-1,-1,-1};\n rep(i, n)\n {\n ll top = t[i];\n ll front = f[i];\n P cur = {0, 0};\n // cout << \"====================\" << endl;\n while (true)\n {\n // debug_x(top);\n // debug_x(front);\n // debug_vc(ans);\n // debug_x(cur.fi);\n // debug_x(cur.se);\n // debug_x(h[cur]);\n // debug_x(me[cur]);\n ll dirIdx = -1;\n ll maxMe = -1;\n rep(j, 4)\n {\n if (die[top][j] == front)\n {\n dirIdx = j;\n }\n }\n rep(k, 4)\n {\n auto [ii, jj] = cur;\n ll ni = ii + di[k];\n ll nj = jj + dj[k];\n P nex = {ni, nj};\n // debug_x(ni);\n // debug_x(nj);\n // debug_x(h[cur]);\n // debug_x(h[nex]);\n // debug_x(die[top][(dirIdx + k) % 4]);\n if (h[cur] - h[nex] <= 0)\n continue;\n maxMe = max(maxMe, die[top][(dirIdx + k) % 4]);\n }\n if (maxMe <= 3)\n {\n h[cur]++;\n ans[me[cur]]--;\n ans[top]++;\n me[cur] = top;\n break;\n }\n rep(k, 4)\n {\n auto [ii, jj] = cur;\n ll ni = ii + di[k];\n ll nj = jj + dj[k];\n if (h[{ii, jj}] - h[{ni, nj}] <= 0)\n continue;\n if (die[top][(dirIdx + k) % 4] != maxMe)\n continue;\n cur = {ni, nj};\n if (k == 0)\n {\n front = top;\n }\n if (k == 2)\n {\n front = 7 - top;\n }\n top = 7 - maxMe;\n break;\n }\n }\n }\n\n rrep(i, 6)\n {\n cout << ans[i];\n if (i != 6)\n cout << ' ';\n }\n cout << endl;\n\n return 1;\n}\n\nsigned main()\n{\n // g++ -std=c++20 -g -fsanitize=undefined,address\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n while (true)\n {\n if (!solve())\n break;\n }\n\n return 0;\n}\n\n/*\nshift+alt+Fで成形\nf2で変数名変更\n\nスニペット\nbasic\n m:atcoder以外用\n ma:ABC/ARC用\n mahc:AHC用\nmath\n floor:床関数\n ceil:天井関数\n comv:二項係数\n modpow: a^b mod m\n GCD:最大公約数\n extGCD:拡張ユークリッド互除法\n PFD:素因数分解\n isprime:エラトステネスの篩\n matrixpow:行列累乗\ndata_structure\n seg:セグメント木\ntechnic\n Compress:座標圧縮\n runlength:ランレングス圧縮\ngraph\n warshall:ワーシャルフロイド法\n dfs:深さ優先探索\n bfs:幅優先探索\n LCA:最近共通祖先\n*/", "accuracy": 1, "time_ms": 3990, "memory_kb": 13372, "score_of_the_acc": -0.7845, "final_rank": 18 }, { "submission_id": "aoj_1181_9797432", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\n#define dbg(x) \n#define ALL(v) v.begin(), v.end()\n\nusing pii = pair<int,int>;\nconstexpr int m = 201;\nint offset = 100;\narray<array<vector<pii>,7>,7> nx;\narray<array<vector<pii>,7>,7> dir;\n\nvoid solve()\n{\n int n;\n cin >> n;\n if (n == 0) exit(0);\n dbg(\"HELLO\")\n \n vector height(m, vector<int>(m));\n vector top(m, vector<int>(m));\n for (int i = 0; i < n; ++i) {\n int t,f;\n cin >> t >> f;\n int x=offset, y=offset;\n\n while (true) {\n int k = nx[t][f].size();\n assert(nx[t][f].size() == dir[t][f].size());\n dbg(k)\n int ma = -1;\n\n for (int j = 0; j < k; ++j) {\n dbg(j)\n int x2 = x + dir[t][f][j].first;\n int y2 = y + dir[t][f][j].second;\n if (height[y2][x2] < height[y][x]\n && (ma == -1 || 7-nx[t][f][j].first > 7-nx[t][f][ma].first)) {\n ma = j;\n }\n dbg(j)\n }\n if (ma == -1) {\n top[y][x] = t;\n height[y][x]++;\n break;\n }\n else {\n dbg(dir[t][f].size())\n dbg(nx[t][f].size())\n dbg(ma)\n x += dir[t][f].at(ma).first;\n dbg(\"A\")\n y += dir[t][f].at(ma).second;\n dbg(\"B\")\n tie(t,f) = nx[t][f].at(ma);\n dbg(\"D\")\n }\n }\n }\n vector<int> ans(7);\n for (int i = 0; i < m; ++i) {\n for (int j = 0; j < m; ++j) {\n ans[top[i][j]]++;\n }\n }\n for (int i = 1; i <= 6; ++i) {\n cout << ans[i] << \" \\n\"[i==6];\n }\n// if (n==100) {\n// for (int i = 0; i < m; ++i) {\n// for (int j = 0; j < m; ++j) {\n// cout << height[i][j];\n// }\n// cout << '\\n';\n// }\n// }\n dbg(\"X\")\n}\n\narray<int,7> left(array<int,7> v) {\n array<int, 7> ret;\n ret[1] = v[3];\n ret[2] = v[2];\n ret[3] = v[6];\n ret[4] = v[1];\n ret[5] = v[5];\n ret[6] = v[4];\n return ret;\n}\n\narray<int,7> right(array<int,7> v) {\n array<int, 7> ret;\n ret[1] = v[4];\n ret[2] = v[2];\n ret[3] = v[1];\n ret[4] = v[6];\n ret[5] = v[5];\n ret[6] = v[3];\n return ret;\n}\narray<int,7> up(array<int,7> v) {\n array<int, 7> ret;\n ret[1] = v[2];\n ret[2] = v[6];\n ret[3] = v[3];\n ret[4] = v[4];\n ret[5] = v[1];\n ret[6] = v[5];\n return ret;\n}\n\narray<int,7> down(array<int,7> v) {\n array<int, 7> ret;\n ret[1] = v[5];\n ret[2] = v[1];\n ret[3] = v[3];\n ret[4] = v[4];\n ret[5] = v[6];\n ret[6] = v[2];\n return ret;\n}\n\nint main()\n{\n array<array<int,7>,7> x;\n x[1][2] = 3;\n x[1][3] = 5;\n x[1][4] = 2;\n x[1][5] = 4;\n x[2][1] = 4;\n x[2][3] = 1;\n x[2][4] = 6;\n x[2][6] = 3;\n x[3][1] = 2;\n x[3][2] = 6;\n x[3][5] = 1;\n x[3][6] = 5;\n x[4][1] = 5;\n x[4][2] = 1;\n x[4][5] = 6;\n x[4][6] = 2;\n x[5][1] = 3;\n x[5][3] = 6;\n x[5][4] = 1;\n x[5][6] = 4;\n x[6][2] = 4;\n x[6][3] = 2;\n x[6][4] = 5;\n x[6][5] = 3;\n for (int t = 1; t <= 6; ++t) {\n for (int f = 1; f <= 6; ++f) {\n array<int,7> vec;\n fill(ALL(vec), 0);\n vec[1] = t;\n vec[2] = f;\n vec[3] = x[t][f];\n vec[4] = 7 - vec[3];\n vec[5] = 7 - vec[2];\n vec[6] = 7 - vec[1];\n {\n auto res = left(vec);\n if (4 <= res[6] && res[6] <= 6) {\n dir[t][f].emplace_back(-1, 0);\n nx[t][f].emplace_back(res[1], res[2]);\n }\n }\n {\n auto res = right(vec);\n if (4 <= res[6] && res[6] <= 6) {\n dir[t][f].emplace_back(1, 0);\n nx[t][f].emplace_back(res[1], res[2]);\n }\n }\n {\n auto res = up(vec);\n if (4 <= res[6] && res[6] <= 6) {\n dir[t][f].emplace_back(0,-1);\n nx[t][f].emplace_back(res[1], res[2]);\n }\n }\n {\n auto res = down(vec);\n if (4 <= res[6] && res[6] <= 6) {\n dir[t][f].emplace_back(0, 1);\n nx[t][f].emplace_back(res[1], res[2]);\n }\n }\n }\n }\n while (true) solve();\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3780, "score_of_the_acc": -0.0031, "final_rank": 7 }, { "submission_id": "aoj_1181_9556743", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\npair<int,int> Top[6] = {{2,3},{3,1},{1,2},{5,6},{6,4},{4,5}};\n\nint H[201][201] = {};\nint B[201][201] = {};\n\nstruct Dice {\n int A[6];\n int X, Y;\n\n Dice(int P, int Q) {\n A[0] = P, A[1] = Q;\n rep(i,0,6) {\n int F[4] = {Top[i].first, Top[i].second, 7-Top[i].first, 7-Top[i].second};\n rep(j,0,4) {\n if (P == F[j] && Q == (F[(j+1)%4])) {\n A[2] = i + 1;\n }\n }\n }\n rep(i,3,6) A[i] = 7 - A[5-i];\n X = 100, Y = 100;\n }\n};\n\nvoid Rot1(Dice& D) {\n D.X++;\n Dice Ret(D.A[4],D.A[0]);\n rep(i,0,6) D.A[i] = Ret.A[i];\n}\n\nvoid Rot2(Dice& D) {\n D.Y++;\n Dice Ret(D.A[3],D.A[1]);\n rep(i,0,6) D.A[i] = Ret.A[i];\n}\n\nvoid Rot3(Dice& D) {\n D.Y--;\n Dice Ret(D.A[2],D.A[1]);\n rep(i,0,6) D.A[i] = Ret.A[i];\n}\n\nvoid Rot4(Dice& D) {\n D.X--;\n Dice Ret(D.A[1],D.A[5]);\n rep(i,0,6) D.A[i] = Ret.A[i];\n}\n\nvoid Rot(Dice& D, int ID) {\n if (ID == 1) Rot1(D);\n if (ID == 2) Rot2(D);\n if (ID == 3) Rot3(D);\n if (ID == 4) Rot4(D);\n return;\n}\n\nint dx[6] = {0,1,0,0,-1,0}, dy[6] = {0,0,1,-1,0,0};\n\nbool Roll(Dice& D) {\n rrep(i,4,7) {\n rep(j,1,5) {\n if (D.A[j] != i) continue;\n int X = D.X, Y = D.Y;\n int NX = X + dx[j], NY = Y + dy[j];\n if (H[NX][NY] < H[X][Y]) {\n Rot(D,j);\n return true;\n }\n }\n }\n return false;\n}\n\nint main() {\nwhile(1) {\n int N;\n cin >> N;\n if (N == 0) return 0;\n rep(i,0,201) rep(j,0,201) H[i][j] = 0, B[i][j] = 0;\n rep(i,0,N) {\n int P, Q;\n cin >> P >> Q;\n Dice D(P,Q);\n while(1) {\n if (!Roll(D)) break;\n }\n H[D.X][D.Y]++;\n B[D.X][D.Y] = D.A[0];\n }\n int ANS[6] = {};\n rep(i,0,201) {\n rep(j,0,201) {\n if (B[i][j] >= 1) ANS[B[i][j] - 1]++;\n }\n }\n rep(i,0,6) cout << ANS[i] << (i == 5 ? '\\n' : ' ');\n}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3736, "score_of_the_acc": -0.0027, "final_rank": 5 }, { "submission_id": "aoj_1181_9347027", "code_snippet": "#line 1 \"main.cpp\"\n#include<bits/stdc++.h>\nusing namespace std;\n\n#line 1 \"/mnt/c/Users/hope_/ComPro/Libraries/Library/other/Dice.hpp\"\n// 面と変数の対応付けは Dice Stamp (https://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=2703) における\n// (l, r, f, b, d, u) から (xn, xp, yn, yp, zn, zp) に置き換えたものとする。(右手座標系)\n// 面の値(Label)のみを保持。一致判定などにおいて向きは非考慮。\n// Verified Link1: Dice Stamp (https://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=2703)\n\nstruct Dice{\n static constexpr int arr[7][7] = {\n {0,0,0,0,0,0,0},\n {0,0,4,2,5,3,0},\n {0,3,0,6,1,0,4},\n {0,5,1,0,0,6,2},\n {0,2,6,0,0,1,5},\n {0,4,0,1,6,0,3},\n {0,0,3,5,2,4,0}\n };\n int xnL, xpL, ynL, ypL, znL, zpL; // labels\n int xco, yco, zco; // x, y, z coordinate (for rolling the dice)\n\n Dice() : xnL(2), xpL(5), ynL(3), ypL(4), znL(6), zpL(1), xco(0), yco(0), zco(0) {}\n \n Dice(int xn, int xp, int yn, int yp, int zn, int zp, int xco = 0, int yco = 0, int zco = 0) :\n xnL(xn), xpL(xp), ynL(yn), ypL(yp), znL(zn), zpL(zp), xco(xco), yco(yco), zco(zco) {}\n\n // after initialization, make normal dice (set -1 to unknown label)\n // 右手座標系\n void makeNormalDice(int xn, int xp, int yn, int yp, int zn, int zp){\n if(xn == -1 && xp != -1){ xn = 7 - xp; }\n if(xp == -1 && xn != -1){ xp = 7 - xn; }\n if(yn == -1 && yp != -1){ yn = 7 - yp; }\n if(yp == -1 && yn != -1){ yp = 7 - yn; }\n if(zn == -1 && zp != -1){ zn = 7 - zp; }\n if(zp == -1 && zn != -1){ zp = 7 - zn; }\n if(xn == -1){\n assert(xp == -1 && yn != -1 && zn != -1);\n xp = arr[zp][yp];\n xn = 7 - xp;\n }\n if(yn == -1){\n assert(yp == -1 && xn != -1 && zn != -1);\n yp = arr[xp][zp];\n yn = 7 - yp;\n }\n if(zn == -1){\n assert(zp == -1 && xn != -1 && yn != -1);\n zp = arr[yp][xp];\n zn = 7 - zp;\n }\n xnL = xn, xpL = xp;\n ynL = yn, ypL = yp;\n znL = zn, zpL = zp;\n }\n\n // shift 4 params to left.\n // (a, b, c, d) -> (b, c, d, a)\n void shift(int& a, int& b, int& c, int& d){\n int tmp = a;\n a = b, b = c, c = d, d = tmp;\n }\n\n void rotXY(bool clockwise = false){\n if(clockwise) shift(xpL, ypL, xnL, ynL);\n else shift(xpL, ynL, xnL, ypL);\n }\n void rotYZ(bool clockwise = false){\n if(clockwise) shift(ypL, zpL, ynL, znL);\n else shift(ypL, znL, ynL, zpL);\n }\n void rotXZ(bool clockwise = false){\n if(clockwise) shift(xpL, zpL, xnL, znL);\n else shift(xpL, znL, xnL, zpL);\n }\n\n // roll dice\n void rotB(){ rotYZ(true); yco++; }\n void rotF(){ rotYZ(false); yco--; }\n void rotR(){ rotXZ(true); xco++; }\n void rotL(){ rotXZ(false); xco--; }\n\n friend ostream& operator<<(ostream& os, const Dice& dice){\n os << \"(xnL, xpL, ynL, ypL, znL, zpL) = (\";\n os << dice.xnL << \", \" << dice.xpL << \", \";\n os << dice.ynL << \", \" << dice.ypL << \", \";\n os << dice.znL << \", \" << dice.zpL << \"), \"; \n os << \"(x, y, z) = (\" << dice.xco << \", \" << dice.yco << \", \" << dice.zco << \")\"; \n return os;\n }\n};\n#line 5 \"main.cpp\"\n\nint main(){\n while(1){\n int N; cin >> N;\n if(N == 0) break;\n const int MAX_N = 210;\n const int CTR = 105;\n vector<vector<int>> height(MAX_N, vector<int>(MAX_N, 0));\n vector<vector<int>> val(MAX_N, vector<int>(MAX_N, 0));\n\n for(int i = 0; i < N; i++){\n int t, f; cin >> t >> f;\n Dice dice;\n dice.makeNormalDice(-1, f, -1, -1, -1, t);\n dice.xco = CTR, dice.yco = CTR;\n dice.zco = height[CTR][CTR] + 1;\n // cout << dice << endl;\n while(1){\n bool flag = 0;\n for(int j = 6; j >= 4; j--){\n if(dice.xnL == j && dice.zco > height[dice.xco - 1][dice.yco] + 1){\n dice.rotL();\n dice.zco = height[dice.xco][dice.yco] + 1;\n flag = 1; break;\n }\n if(dice.xpL == j && dice.zco > height[dice.xco + 1][dice.yco] + 1){\n dice.rotR();\n dice.zco = height[dice.xco][dice.yco] + 1;\n flag = 1; break;\n }\n if(dice.ynL == j && dice.zco > height[dice.xco][dice.yco - 1] + 1){\n dice.rotF();\n dice.zco = height[dice.xco][dice.yco] + 1;\n flag = 1; break;\n }\n if(dice.ypL == j && dice.zco > height[dice.xco][dice.yco + 1] + 1){\n dice.rotB();\n dice.zco = height[dice.xco][dice.yco] + 1;\n flag = 1; break;\n }\n }\n if(!flag) break;\n }\n height[dice.xco][dice.yco] = dice.zco;\n val[dice.xco][dice.yco] = dice.zpL;\n // cout << dice << \" \" << height[dice.xco][dice.yco] << endl;\n }\n\n vector<int> ans(6);\n for(int i = 0; i < MAX_N; i++){\n for(int j = 0; j < MAX_N; j++){\n if(val[i][j] != 0) ans[val[i][j] - 1]++;\n }\n }\n\n for(int i = 0; i < 6; i++){\n cout << ans[i];\n if(i != 6 - 1) cout << \" \";\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3704, "score_of_the_acc": -0.0023, "final_rank": 3 }, { "submission_id": "aoj_1181_9238334", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nstruct Dice{\n static constexpr int arr[7][7] = {\n {0,0,0,0,0,0,0},\n {0,0,4,2,5,3,0},\n {0,3,0,6,1,0,4},\n {0,5,1,0,0,6,2},\n {0,2,6,0,0,1,5},\n {0,4,0,1,6,0,3},\n {0,0,3,5,2,4,0}\n };\n int a, b, c, d, e, f;\n \n Dice(int x, int y) : a(x), c(y) {\n //cout << x << \" \" << y << endl;\n d = 7 - c;\n f = 7 - a;\n e = arr[x][y];\n b = 7 - e;\n //cout << a << b << c << d << e << f << endl;\n }\n void rotU(){\n int tmp = a;\n a = c;\n c = f;\n f = d;\n d = tmp;\n }\n void rotD(){\n rotU();\n rotU();\n rotU();\n }\n void rotL(){\n int tmp = a;\n a = e;\n e = f;\n f = b;\n b = tmp;\n }\n void rotR(){\n rotL();\n rotL();\n rotL();\n }\n};\n\nint main(){\n while(1){\n int N; cin >> N;\n if(N == 0) break;\n const int PAR = 211;\n vector<vector<int>> G(PAR, vector<int>(PAR, 0));\n vector<vector<int>> val(PAR, vector<int>(PAR, 0));\n\n for(int _ = 0; _ < N; _++){\n int t, f; cin >> t >> f;\n Dice dice(t, f);\n\n int r = 103, c = 103;\n while(1){\n int mx = 0;\n // U\n if(dice.d > mx && G[r - 1][c] < G[r][c]) mx = dice.d;\n // D\n if(dice.c > mx && G[r + 1][c] < G[r][c]) mx = dice.c;\n // L\n if(dice.b > mx && G[r][c - 1] < G[r][c]) mx = dice.b;\n // R\n if(dice.e > mx && G[r][c + 1] < G[r][c]) mx = dice.e;\n\n if(mx <= 3) break;\n\n // U\n if(dice.d == mx){ dice.rotU(); r--; }\n // D\n if(dice.c == mx){ dice.rotD(); r++; }\n // L\n if(dice.b == mx){ dice.rotL(); c--; }\n // R\n if(dice.e == mx){ dice.rotR(); c++; }\n }\n assert(0 <= r && r < PAR);\n assert(0 <= c && c < PAR);\n G[r][c]++;\n val[r][c] = dice.a;\n }\n\n vector<int> ans(7, 0);\n for(int i = 0; i < PAR; i++){\n for(int j = 0; j < PAR; j++){\n assert(0 <= val[i][j] && val[i][j] <= 6);\n ans[val[i][j]]++;\n }\n }\n\n for(int i = 0; i < 6; i++){\n cout << ans[i + 1];\n if(i != 5) cout << \" \";\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3712, "score_of_the_acc": -0.0024, "final_rank": 4 }, { "submission_id": "aoj_1181_9238100", "code_snippet": "#include <bits/stdc++.h>\n\nnamespace lib {\n\n using namespace std;\n template <typename T = int>\n class Dice {\n private:\n array<T, 6> data;\n public:\n int id_;\n Dice(int id_ = 0): id_(id_) {\n iota(data.begin(), data.end(), 1);\n }\n Dice(const array<T, 6>& data, int id_ = 0): data(data), id_(id_) {}\n\n void rotate_north() {\n T temp = data[5];\n data[5] = data[4];\n data[4] = data[0];\n data[0] = data[1];\n data[1] = temp;\n }\n\n void rotate_east() {\n T temp = data[5];\n data[5] = data[2];\n data[2] = data[0];\n data[0] = data[3];\n data[3] = temp;\n }\n\n void rotate_south() {\n T temp = data[5];\n data[5] = data[1];\n data[1] = data[0];\n data[0] = data[4];\n data[4] = temp;\n }\n\n void rotate_west() {\n T temp = data[5];\n data[5] = data[3];\n data[3] = data[0];\n data[0] = data[2];\n data[2] = temp;\n }\n\n T top() const {\n return data[0];\n }\n\n T front() const {\n return data[1];\n }\n\n T right() const {\n return data[2];\n }\n\n T left() const {\n return data[3];\n }\n\n T back() const {\n return data[4];\n }\n\n T bottom() const {\n return data[5];\n }\n\n int id() const {\n return id_;\n }\n\n static Dice match(T top_value, T front_value) {\n Dice temp = Dice();\n for (int i = 0; i < 6; i++) {\n for (int j = 0; j < 4; j++) {\n if (temp.top() == top_value && temp.front() == front_value) {\n return temp;\n }\n temp.rotate_east();\n }\n if (i & 1) {\n temp.rotate_east();\n } else {\n temp.rotate_west();\n }\n temp.rotate_south();\n } \n return temp;\n }\n };\n\n template <typename T>\n ostream& operator<<(ostream& stream, const Dice<T>& dice) {\n stream << \" -- Dice \" << dice.id() << \" -- \" << '\\n';\n stream << \"top \" << dice.top() << '\\n';\n stream << \"front \" << dice.front() << '\\n';\n stream << \"left \" << dice.left() << '\\n';\n stream << \"right \" << dice.right() << '\\n';\n stream << \"back \" << dice.back() << '\\n';\n stream << \"bottom \" << dice.bottom() << '\\n';\n return stream;\n }\n}\nusing lib::Dice;\n\nint solve() {\n int n;\n std::cin >> n;\n if (n == 0) return 1;\n const int OFFSET = 150;\n std::vector dices(OFFSET * 2, std::vector(2 * OFFSET, std::vector<Dice<int>>()));\n\n auto enable_roll = [&](int i, int j, int h) {\n if (h > (int)dices[i][j].size()) return true;\n return false;\n };\n\n auto roll = [&](auto self, int i, int j, int k) -> void {\n assert((int)dices[i][j].size() > k);\n auto dice = dices[i][j][k];\n for (int val = 6; val > 3; val--) {\n if (dice.left() == val && enable_roll(i, j - 1, k)) {\n dices[i][j].pop_back();\n dice.rotate_west();\n k = dices[i][j - 1].size();\n dices[i][j - 1].push_back(dice);\n self(self, i, j - 1, k);\n return;\n }\n if (dice.front() == val && enable_roll(i - 1, j, k)) {\n dices[i][j].pop_back();\n dice.rotate_south();\n k = dices[i - 1][j].size();\n dices[i - 1][j].push_back(dice);\n self(self, i - 1, j, k);\n return;\n }\n if (dice.back() == val && enable_roll(i + 1, j, k)) {\n dices[i][j].pop_back();\n dice.rotate_north();\n k = dices[i + 1][j].size();\n dices[i + 1][j].push_back(dice);\n self(self, i + 1, j, k);\n return;\n }\n if (dice.right() == val && enable_roll(i, j + 1, k)) {\n dices[i][j].pop_back();\n dice.rotate_east();\n k = dices[i][j + 1].size();\n dices[i][j + 1].push_back(dice);\n self(self, i, j + 1, k);\n return;\n }\n }\n };\n\n for (int i = 0; i < n; i++) {\n int t, f;\n std::cin >> t >> f;\n Dice<int> dice = Dice<int>::match(t, f);\n dice.id_ = i;\n int h = dices[OFFSET][OFFSET].size();\n dices[OFFSET][OFFSET].push_back(dice);\n roll(roll, OFFSET, OFFSET, h);\n }\n\n std::vector<int> ans(7);\n for (int i = 0; i < 2 * OFFSET; i++) {\n for (int j = 0; j < 2 * OFFSET; j++) {\n if (dices[i][j].empty()) continue;\n ans[dices[i][j].back().top()]++;\n }\n }\n\n for (int i = 1; i <= 6; i++) {\n std::cout << ans[i] << (i == 6 ? '\\n' : ' ');\n }\n return 0;\n}\n\nint main() {\n while (!solve());\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 5184, "score_of_the_acc": -0.0343, "final_rank": 11 }, { "submission_id": "aoj_1181_9238017", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nstruct Dice{\n static constexpr int arr[7][7] = {\n {0,0,0,0,0,0,0},\n {0,0,4,2,5,3,0},\n {0,3,0,6,1,0,4},\n {0,5,1,0,0,6,2},\n {0,2,6,0,0,1,5},\n {0,4,0,1,6,0,3},\n {0,0,3,5,2,4,0}\n };\n int a, b, c, d, e, f;\n \n Dice(int x, int y) : a(x), c(y) {\n //cout << x << \" \" << y << endl;\n d = 7 - c;\n f = 7 - a;\n e = arr[x][y];\n b = 7 - e;\n //cout << a << b << c << d << e << f << endl;\n }\n void rotU(){\n int tmp = a;\n a = c;\n c = f;\n f = d;\n d = tmp;\n }\n void rotD(){\n rotU();\n rotU();\n rotU();\n }\n void rotL(){\n int tmp = a;\n a = e;\n e = f;\n f = b;\n b = tmp;\n }\n void rotR(){\n rotL();\n rotL();\n rotL();\n }\n};\n\nint main(){\n while(1){\n int N; cin >> N;\n if(N == 0) break;\n const int PAR = 211;\n vector<vector<int>> G(PAR, vector<int>(PAR, 0));\n vector<vector<int>> val(PAR, vector<int>(PAR, 0));\n\n for(int _ = 0; _ < N; _++){\n int t, f; cin >> t >> f;\n Dice dice(t, f);\n\n int r = 103, c = 103;\n while(1){\n int mx = 0;\n // U\n if(dice.d > mx && G[r - 1][c] < G[r][c]) mx = dice.d;\n // D\n if(dice.c > mx && G[r + 1][c] < G[r][c]) mx = dice.c;\n // L\n if(dice.b > mx && G[r][c - 1] < G[r][c]) mx = dice.b;\n // R\n if(dice.e > mx && G[r][c + 1] < G[r][c]) mx = dice.e;\n\n if(mx <= 3) break;\n\n // U\n if(dice.d == mx){ dice.rotU(); r--; }\n // D\n if(dice.c == mx){ dice.rotD(); r++; }\n // L\n if(dice.b == mx){ dice.rotL(); c--; }\n // R\n if(dice.e == mx){ dice.rotR(); c++; }\n }\n assert(0 <= r && r < PAR);\n assert(0 <= c && c < PAR);\n G[r][c]++;\n val[r][c] = dice.a;\n }\n\n vector<int> ans(7, 0);\n for(int i = 0; i < PAR; i++){\n for(int j = 0; j < PAR; j++){\n assert(0 <= val[i][j] && val[i][j] <= 6);\n ans[val[i][j]]++;\n }\n }\n\n for(int i = 0; i < 6; i++){\n cout << ans[i + 1];\n if(i != 5) cout << \" \";\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3740, "score_of_the_acc": -0.0027, "final_rank": 6 }, { "submission_id": "aoj_1181_8974014", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\n} // namespace macro\n\nusing namespace macro;\n#line 3 \"B.cpp\"\n\nint main() {\n\n auto get_right = [&](int top, int front) {\n const static map<int, vector<int>> rs = {\n {1, {2, 3, 5, 4}},\n {2, {3, 1, 4, 6}},\n {3, {5, 1, 2, 6}},\n {4, {1, 5, 6, 2}},\n {5, {1, 3, 6, 4}},\n {6, {5, 3, 2, 4}}\n };\n for(auto& [x, vec] : rs) {\n for(int i : rep(4)) {\n if(vec[i] == top and vec[(i + 1) % 4] == front) {\n return x;\n }\n }\n }\n assert(0);\n };\n\n struct state {\n int top, front;\n int height;\n };\n\n while(true) {\n int n = in(); if(n == 0) break;\n\n map<pair<int,int>, state> data;\n const int MAX_C = 110;\n for(int x = -MAX_C; x <= +MAX_C; x++)\n for(int y = -MAX_C; y <= +MAX_C; y++)\n data[{x, y}] = state{-1, -1, 0};\n\n for(int n_ : rep(n)) {\n int top = in(), front = in();\n int x = 0, y = 0;\n while([&] {\n int right = get_right(top, front);\n int height = data[{x, y}].height + 1;\n for(int v = 6; v >= 4; v--) {\n if(right == v and data[{x + 1, y}].height + 2 <= height) {\n tie(x, y) = make_pair(x + 1, y);\n tie(top, front) = make_pair(7 - right, front);\n return true;\n }\n if(7 - right == v and data[{x - 1, y}].height + 2 <= height) {\n tie(x, y) = make_pair(x - 1, y);\n tie(top, front) = make_pair(right, front);\n return true;\n }\n if(7 - front == v and data[{x, y + 1}].height + 2 <= height) {\n tie(x, y) = make_pair(x, y + 1);\n tie(top, front) = make_pair(front, 7 - top);\n return true;\n }\n if(front == v and data[{x, y - 1}].height + 2 <= height) {\n tie(x, y) = make_pair(x, y - 1);\n tie(top, front) = make_pair(7 - front, top);\n return true;\n }\n }\n return false;\n }()) {}\n data[{x, y}] = state{top, front, data[{x, y}].height + 1};\n }\n\n vector<int> cnt(7, 0);\n for(int x = -MAX_C; x <= +MAX_C; x++)\n for(int y = -MAX_C; y <= +MAX_C; y++)\n if(data[{x, y}].height != 0) cnt[data[{x, y}].top]++;\n cnt.erase(cnt.begin());\n print(cnt);\n }\n}", "accuracy": 1, "time_ms": 1700, "memory_kb": 6528, "score_of_the_acc": -0.3217, "final_rank": 16 }, { "submission_id": "aoj_1181_8031964", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n\nstruct dice {\n int top, front;\n bool operator==(const dice &d) { return top == d.top && front == d.front; }\n};\n\nbool solve() {\n int N;\n cin >> N;\n if (N == 0) return false;\n ll M = 220;\n vector G(M, vector(M, vector<dice>(M, (dice){0, 0})));\n vector<vector<int>> round = {{2, 3, 5, 4}, {1, 4, 6, 3}, {1, 2, 6, 5},\n {1, 5, 6, 2}, {1, 3, 6, 4}, {2, 4, 5, 3}};\n\n vector<pair<int, int>> dxy = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};\n\n rep(n, N) {\n int t, f;\n cin >> t >> f;\n int x = 110, y = 110, z = 110;\n G[x][y][z] = (dice){t, f};\n while (true) {\n bool update = false;\n if (z == 0) break;\n if (G[x][y][z - 1] == (dice){0, 0}) {\n update = true;\n G[x][y][z - 1] = G[x][y][z];\n G[x][y][z] = (dice){0, 0};\n z--;\n } else {\n int top = G[x][y][z].top;\n int front = G[x][y][z].front;\n int diff = [&]() {\n rep(i, 4) if (round[top - 1][i] == G[x][y][z].front) {\n return i;\n }\n cout << \"WA\" << endl;\n exit(1);\n }();\n optional<pair<int, int>> nxt_xy = nullopt;\n optional<dice> nxt = nullopt;\n int val = -1;\n rep(i, 4) {\n // int v = round[top - 1][(i - diff + 4) % 4];\n int v = round[top - 1][(i + diff) % 4];\n if (v < 4) continue;\n if (v < val) continue;\n auto [dx, dy] = dxy[i];\n if (G[x + dx][y + dy][z] == (dice){0, 0} &&\n G[x + dx][y + dy][z - 1] == (dice){0, 0}) {\n val = v;\n nxt_xy = {dx, dy};\n if (i == 0) nxt = (dice){7 - v, top};\n if (i == 1) nxt = (dice){7 - v, front};\n if (i == 2) nxt = (dice){7 - v, 7 - top};\n if (i == 3) nxt = (dice){7 - v, front};\n }\n }\n if (nxt_xy) {\n auto [dx, dy] = nxt_xy.value();\n G[x + dx][y + dy][z - 1] = nxt.value();\n G[x][y][z] = (dice){0, 0};\n update = true;\n x = x + dx;\n y = y + dy;\n z = z - 1;\n }\n }\n if (!update) break;\n }\n\n // vector<int> cnt(7, 0);\n // rep(x, M) rep(y, M) {\n // for (int z = M - 1; z >= 0; z--) {\n // if (G[x][y][z] == (dice){0, 0}) continue;\n // cnt[G[x][y][z].top]++;\n // break;\n // }\n // }\n // cout << \"debug: \";\n // for (int i = 1; i < 7; i++) {\n // cout << cnt[i] << (i == 6 ? \"\\n\" : \" \");\n // }\n }\n\n vector<int> cnt(7, 0);\n rep(x, M) rep(y, M) {\n for (int z = M - 1; z >= 0; z--) {\n if (G[x][y][z] == (dice){0, 0}) continue;\n cnt[G[x][y][z].top]++;\n break;\n }\n }\n for (int i = 1; i < 7; i++) {\n cout << cnt[i] << (i == 6 ? \"\\n\" : \" \");\n }\n\n return true;\n}\n\nint main() {\n while (solve())\n ;\n}", "accuracy": 1, "time_ms": 5810, "memory_kb": 88408, "score_of_the_acc": -1.8428, "final_rank": 20 }, { "submission_id": "aoj_1181_8008145", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\n//---------------------------- テンプレゾーン --------------------------------//\n\nconst long long INF = 1000000010;\nconst long long INFL = 1000000000000000010;\nconst double MYPI = 3.14159265358979;\nconst double epsilon = 1e-10;\n\n\n\ntypedef long long ll;\ntypedef __int128_t lll;\ntypedef unsigned int uint;\ntypedef unsigned long long ull;\ntypedef long double ld;\ntypedef pair<ll, ll> pl;\ntypedef vector<ll> vl;\ntypedef vector<vl> vvl;\ntypedef vector<vvl> vvvl;\ntypedef vector<double> vd;\ntypedef vector<vd> vvd;\ntypedef vector<vvd> vvvd;\ntypedef vector<bool> vb;\ntypedef vector<vb> vvb;\ntypedef vector<vvb> vvvb;\ntypedef vector<char> vc;\ntypedef vector<vc> vvc;\ntypedef vector<vvc> vvvc;\ntypedef vector<pl> vp;\ntypedef tuple<ll, ll, ll> tt;\ntypedef vector<tuple<ll, ll, ll>> vt;\ntypedef vector<string> vs;\n\n#define overload3(a, b, c, d, ...) d\n#define overload4(a, b, c, d, e, ...) e\n#define overload5(a, b, c, d, e, f, ...) f\n#define overload6(a, b, c, d, e, f, g, ...) g\n#define pb push_back\n#define eb emplace_back\n#define MP make_pair\n#define REP_0(n) for(int _=0;_<(n);_++)\n#define REP_1(i, n) for(int i=0;i<(n);i++)\n#define REP_2(i, l, r) for(int i=(l);i<(r);i++)\n#define REP_3(i, l, r, d) for(int i=(l);i<(r);i+=(d))\n#define REP(...) overload4(__VA_ARGS__, REP_3, REP_2, REP_1, REP_0)(__VA_ARGS__)\n#define REPP(i, n) for(int i=1;i<=(n);i++)\n#define RREP_1(i, n) for(int i=(n)-1;i>=0;i--)\n#define RREP_2(i, l, r) for(int i=(r)-1;i>=(l);i--)\n#define RREP_3(i, l, r, d) for(int i=(r)-1;i>=(l);i-=(d))\n#define RREP(...) overload4(__VA_ARGS__, RREP_3, RREP_2, RREP_1)(__VA_ARGS__)\n#define RREPP(i, n) for(int i=(n);i>0;i--)\n#define EACH1(e, a) for(auto &e : a)\n#define EACH2(x, y, a) for(auto &[x, y] : a)\n#define EACH3(x, y, z, a) for(auto &[x, y, z] : a)\n#define EACH(...) overload4(__VA_ARGS__, EACH3, EACH2, EACH1)(__VA_ARGS__)\n#define ALL1(x) begin(x), end(x)\n#define ALL2(x, a) begin(x), begin(x) + a\n#define ALL3(x, a, b) begin(x) + a, begin(x) + b\n#define ALL(...) overload3(__VA_ARGS__, ALL3, ALL2, ALL1)(__VA_ARGS__)\n#define RALL1(i) (i).rbegin(), (i).rend()\n#define RALL2(i, a) (i).rend() - a, (i).rend()\n#define RALL3(i, a, b) (i).rend() - b, (i).rend() - a\n#define RALL(...) overload3(__VA_ARGS__, RALL3, RALL2, RALL1)(__VA_ARGS__)\n#define sz(x) (long long)x.size()\n#define LB(a, x) (lower_bound(a.begin(), a.end(), x) - a.begin())\n#define UB(a, x) (upper_bound(a.begin(), a.end(), x) - a.begin())\n#define FLG(x, i) (((x)>>(i)) & 1)\n#define CNTBIT(x) __builtin_popcountll(x)\n#define TOPBIT(t) (t == 0 ? -1 : 63 - __builtin_clzll(t))\n#define BTMBIT(t) (t == 0 ? 64 : __builtin_ctzll(t))\n#define IN(x, a, b) ((a) <= (x) && (x) < (b))\n#define INT(...) int __VA_ARGS__; input(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define CHAR(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define DBL(...) double __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) long double __VA_ARGS__; input(__VA_ARGS__)\n#define VL1(a, n) vector<long long> a(n); for(int I=0;I<(n);I++)cin >> a[I]\n#define VL2(a, b, n) vector<long long> a(n), b(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I]\n#define VL3(a, b, c, n) vector<long long> a(n), b(n), c(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I]\n#define VL4(a, b, c, d, n) vector<long long> a(n), b(n), c(n), d(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I] >> d[I]\n#define VL5(a, b, c, d, e, n) vector<long long> a(n), b(n), c(n), d(n), e(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I] >> d[I] >> e[I]\n#define VL(...) overload6(__VA_ARGS__, VL5, VL4, VL3, VL2, VL1)(__VA_ARGS__)\n#define VD1(a, n) vector<double> a(n); for(int I=0;I<(n);I++)cin >> a[I]\n#define VD2(a, b, n) vector<double> a(n), b(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I]\n#define VD3(a, b, c, n) vector<double> a(n), b(n), c(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I]\n#define VD4(a, b, c, d, n) vector<double> a(n), b(n), c(n), d(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I] >> d[I]\n#define VD5(a, b, c, d, e, n) vector<double> a(n), b(n), c(n), d(n), e(n); for(int I=0;I<(n);I++)cin >> a[I] >> b[I] >> c[I] >> d[I] >> e[I]\n#define VD(...) overload6(__VA_ARGS__, VD5, VD4, VD3, VD2, VD1)(__VA_ARGS__)\n#define VVL(a, n, m) vector<vector<long long> > a(n, vector<long long>(m)); for(int I=0;I<(n);I++)for(int J=0;J<(m);J++)cin >> a[I][J]\n#define VVC(s, n, m) vector<vector<char> > s(n, vector<char>(m)); for(int I=0;I<(n);I++)for(int J=0;J<(m);J++)cin >> s[I][J]\n#define VS(s, n) vector<string> s(n); for(int I=0;I<(n);I++)cin >> s[I];\n\ntemplate <typename T1, typename T2>\nostream &operator<<(ostream &os, const pair<T1, T2> &a){\n return os << a.first << \" \" << a.second;\n}\ntemplate <typename T1, typename T2, typename T3>\nostream &operator<<(ostream &os, const tuple<T1, T2, T3> &a){\n return os << get<0>(a) << \" \" << get<1>(a) << \" \" << get<2>(a);\n}\n\nstruct IoSetup{\n IoSetup() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n cout << fixed << setprecision(15);\n }\n} iosetup;\n\n#ifdef LOCAL\n# include <debug_print.hpp>\n# define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__)\n#else\n# define debug(...) (static_cast<void>(0))\n#endif\n\ntemplate <typename T>\nusing minheap = priority_queue<T, vector<T>, greater<T>>;\n \ntemplate <typename T>\nusing maxheap = priority_queue<T>;\n\ntemplate<class... T>\nvoid input(T&... a){\n (cin >> ... >> a);\n}\n\ntemplate <typename... T>\nconstexpr auto min(T... a){\n return min(initializer_list<common_type_t<T...>>{a...});\n}\ntemplate <typename... T>\nconstexpr auto max(T... a){\n return max(initializer_list<common_type_t<T...>>{a...});\n}\n\ntemplate <typename T1, typename T2>\nbool chmax(T1 &x, const T2 &y){\n return x < y ? x = y, true : false;\n}\ntemplate <typename T1, typename T2>\nbool chmin(T1 &x, const T2 &y){\n return x > y ? x = y, true : false;\n}\n\nvoid OUT(){cout << \"\\n\";}\n\ntemplate <typename T, typename... Ts>\nvoid OUT(const T &a, const Ts&... b){\n cout << a;\n (cout << ... << (cout << \" \", b));\n cout << \"\\n\";\n}\n\ntemplate <typename T>\nvoid OUT(const vector<T> &res){\n for(int i=0;i<(int)res.size();i++){\n cout << res[i] << \" \";\n }\n cout << \"\\n\";\n}\n\ntemplate <typename T>\nvoid OUT_(const T &a){\n cout << a << \" \";\n}\n\ntemplate <typename T>\nvoid OUTN(const vector<T> &res, long long margin = 0){\n for(int i=0;i<(int)res.size();i++){\n cout << res[i] + (T)margin << \"\\n\";\n }\n}\n\ntemplate <typename T>\nvoid OUTN_(const vector<T> &res, long long margin = 0){\n for(int i=0;i<(int)res.size();i++){\n cout << res[i] + (T)margin << \" \";\n }\n cout << \"\\n\";\n}\n\ntemplate <typename T>\nvoid OUTNN(const vector<vector<T>> &res, long long margin = 0){\n for(int i=0;i<(int)res.size();i++){\n for(int j=0;j<(int)res[i].size();j++){\n cout << res[i][j] + (T)margin << \" \";\n }\n cout << \"\\n\";\n }\n}\n\nvoid YES(const bool &res = true, bool Capital = false){\n if(Capital) cout << (res ? \"YES\" : \"NO\") << \"\\n\";\n else cout << (res ? \"Yes\" : \"No\") << \"\\n\";\n}\n\nvoid FIRST(const bool &res = true, bool Capital = false){\n if(Capital) cout << (res ? \"FIRST\" : \"SECOND\") << \"\\n\";\n else cout << (res ? \"First\" : \"Second\") << \"\\n\";\n}\n\ntemplate <typename T>\nvoid DEC(vector<T> &a, long long dif = 1){\n for(auto &x : a)x -= (T)dif;\n}\ntemplate <typename T>\nvoid DEC(vector<T> &a, vector<T> &b, long long dif = 1){\n for(auto &x : a)x -= (T)dif;\n for(auto &x : b)x -= (T)dif;\n}\ntemplate <typename T>\nvoid DEC(vector<vector<T>> &a, long long dif = 1){\n for(auto &v : a)for(auto &x : v)x -= (T)dif;\n}\n\ntemplate <typename T>\nvoid INC(vector<T> &a, long long dif = 1){\n for(auto &x : a)x += (T)dif;\n}\ntemplate <typename T>\nvoid INC(vector<T> &a, vector<T> &b, long long dif = 1){\n for(auto &x : a)x += (T)dif;\n for(auto &x : b)x += (T)dif;\n}\ntemplate <typename T>\nvoid INC(vector<vector<T>> &a, long long dif = 1){\n for(auto &v : a)for(auto &x : v)x += (T)dif;\n}\n\ntemplate <typename T>\nT SUM(const vector<T> &a){\n return accumulate(a.begin(), a.end(), (T)0);\n}\ntemplate <typename T>\nT SUM(const vector<vector<T>> &a){\n T ret = 0;\n for(int i=0;i<(int)a.size();i++)ret += accumulate(a[i].begin(), a[i].end(), (T)0);\n return ret;\n}\n\ntemplate <typename T>\nT MAX(const vector<T> &a){\n return *max_element(a.begin(), a.end());\n}\ntemplate <typename T>\nT MAX(const vector<vector<T>> &a){\n T ret = -INFL;\n for(int i=0;i<(int)a.size();i++)for(int j=0;j<(int)a[i].size();j++)if(ret < a[i][j])ret = a[i][j];\n return ret;\n}\n\ntemplate <typename T>\nint ARGMAX(const vector<T> &a){\n int ret = 0;\n for(int i=1;i<(int)a.size();i++)if(a[ret] < a[i])ret = i;\n return ret;\n}\ntemplate <typename T>\npair<int, int> ARGMAX(const vector<vector<T>> &a){\n pair<int, int> ret = {0, 0};\n for(int i=0;i<(int)a.size();i++)for(int j=0;j<(int)a[i].size();j++)if(a[ret.first][ret.second] < a[i][j])ret = {i, j};\n return ret;\n}\n\ntemplate <typename T>\nT MIN(const vector<T> &a){\n return *min_element(a.begin(), a.end());\n}\ntemplate <typename T>\nT MIN(const vector<vector<T>> &a){\n T ret = INFL;\n for(int i=0;i<(int)a.size();i++)for(int j=0;j<(int)a[i].size();j++)if(ret > a[i][j])ret = a[i][j];\n return ret;\n}\n\ntemplate <typename T>\nint ARGMIN(const vector<T> &a){\n int ret = 0;\n for(int i=1;i<(int)a.size();i++)if(a[ret] > a[i])ret = i;\n return ret;\n}\ntemplate <typename T>\npair<int, int> ARGMIN(const vector<vector<T>> &a){\n pair<int, int> ret = {0, 0};\n for(int i=0;i<(int)a.size();i++)for(int j=0;j<(int)a[i].size();j++)if(a[ret.first][ret.second] > a[i][j])ret = {i, j};\n return ret;\n}\n\ntemplate <typename T>\nint SIGN(const T &a){\n if(abs(a) < epsilon)return 0;\n return a > 0 ? 1 : -1;\n}\n\ntemplate <typename T>\nvector<T> UNIQ(vector<T> a){\n sort(a.begin(), a.end());\n a.erase(unique(a.begin(), a.end()), a.end());\n return a;\n}\n\ntemplate <typename T>\nvector<T> sorted(vector<T> a, bool Descending = false){\n sort(a.begin(), a.end());\n if(Descending)reverse(a.begin(), a.end());\n return a;\n}\n\ntemplate <typename T>\nvector<T> cumsum(const vector<T> &a){\n int n = (int)a.size();\n vector<T> ret(n+1, (T)0);\n for(int i=0;i<n;i++)ret[i+1] = ret[i] + a[i];\n return ret;\n}\ntemplate <typename T>\nvector<vector<T>> cumsum(const vector<vector<T>> &a){\n int n = (int)a.size(), m = (int)a[0].size();\n vector<vector<T>> ret(n+1, vector<T>(m+1, (T)0));\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)ret[i+1][j+1] = ret[i+1][j] + a[i][j];\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)ret[i+1][j+1] += ret[i][j+1];\n return ret;\n}\ntemplate <typename T>\nvector<vector<vector<T>>> cumsum(const vector<vector<vector<T>>> &a){\n int n = (int)a.size(), m = (int)a[0].size(), l = (int)a[0][0].size();\n vector<vector<vector<T>>> ret(n+1, vector<vector<T>>(m+1, vector<T>(l+1, (T)0)));\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)for(int k=0;k<l;k++)ret[i+1][j+1][k+1] = ret[i+1][j+1][k] + a[i][j][k];\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)for(int k=0;k<l;k++)ret[i+1][j+1][k+1] += ret[i][j+1][k+1];\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)for(int k=0;k<l;k++)ret[i+1][j+1][k+1] += ret[i+1][j][k+1];\n return ret;\n}\ntemplate <typename T>\nvoid cumsum_inplace(vector<T> &a){\n int n = (int)a.size();\n for(int i=0;i<n-1;i++)a[i+1] += a[i];\n}\ntemplate <typename T>\nvoid cumsum_inplace(vector<vector<T>> &a){\n int n = (int)a.size(), m = (int)a[0].size();\n for(int i=0;i<n-1;i++)for(int j=0;j<m;j++)a[i+1][j] += a[i][j];\n for(int i=0;i<n;i++)for(int j=0;j<m-1;j++)a[i][j+1] += a[i][j];\n}\ntemplate <typename T>\nvoid cumsum_inplace(vector<vector<vector<T>>> &a){\n int n = (int)a.size(), m = (int)a[0].size(), l = (int)a[0][0].size();\n for(int i=0;i<n-1;i++)for(int j=0;j<m;j++)for(int k=0;k<l;k++)a[i+1][j][k] += a[i][j][k];\n for(int i=0;i<n;i++)for(int j=0;j<m-1;j++)for(int k=0;k<l;k++)a[i][j+1][k] += a[i][j][k];\n for(int i=0;i<n;i++)for(int j=0;j<m;j++)for(int k=0;k<l-1;k++)a[i][j][k+1] += a[i][j][k];\n}\n\ntemplate< typename T = long long >\nstruct Edge {\n long long from, to;\n T cost;\n long long idx;\n Edge() = default;\n Edge(long long from, long long to, T cost = 1, long long idx = -1) : from(from), to(to), cost(cost), idx(idx) {}\n operator int() const { return to; }\n};\n\ntemplate< typename T = long long >\nstruct Graph {\n vector< vector< Edge< T > > > g, ginv;\n vector<int> indeg, outdeg;\n long long es;\n Graph() = default;\n explicit Graph(long long n) : g(n), ginv(n), indeg(n, 0), outdeg(n, 0), es(0) {}\n size_t size() const {\n return g.size();\n }\n void add_directed_edge(long long from, long long to, T cost = 1) {\n indeg[to]++, outdeg[from]++;\n //ginv[to].emplace_back(to, from, cost, es);\n g[from].emplace_back(from, to, cost, es++);\n }\n void add_edge(long long from, long long to, T cost = 1) {\n indeg[from]++, outdeg[from]++, indeg[to]++, outdeg[to]++;\n g[from].emplace_back(from, to, cost, es);\n g[to].emplace_back(to, from, cost, es++);\n }\n inline vector< Edge< T > > &operator[](const int &k) {\n return g[k];\n }\n inline const vector< Edge< T > > &operator[](const int &k) const {\n return g[k];\n }\n};\n\ntemplate< typename T = long long >\nusing Edges = vector< Edge< T > >;\n\ntemplate< typename T >\nstruct Enumeration {\nprivate:\n static vector< T > _fact, _finv, _inv;\n inline static void expand(size_t sz) {\n if(_fact.size() < sz + 1) {\n int pre_sz = max(1, (int) _fact.size());\n _fact.resize(sz + 1, T(1));\n _finv.resize(sz + 1, T(1));\n _inv.resize(sz + 1, T(1));\n for(int i = pre_sz; i <= (int) sz; i++) {\n _fact[i] = _fact[i - 1] * T(i);\n }\n _finv[sz] = T(1) / _fact[sz];\n for(int i = (int) sz - 1; i >= pre_sz; i--) {\n _finv[i] = _finv[i + 1] * T(i + 1);\n }\n for(int i = pre_sz; i <= (int) sz; i++) {\n _inv[i] = _finv[i] * _fact[i - 1];\n }\n }\n }\npublic:\n explicit Enumeration(size_t sz = 0) { expand(sz); }\n static inline T fact(int k) {\n expand(k);\n return _fact[k];\n }\n static inline T finv(int k) {\n expand(k);\n return _finv[k];\n }\n static inline T inv(int k) {\n expand(k);\n return _inv[k];\n }\n static T P(int n, int r) {\n if(r < 0 || n < r) return 0;\n return fact(n) * finv(n - r);\n }\n static T C(int p, int q) {\n if(q < 0 || p < q) return 0;\n return fact(p) * finv(q) * finv(p - q);\n }\n};\n\ntemplate< typename T >\nvector< T > Enumeration< T >::_fact = vector< T >();\ntemplate< typename T >\nvector< T > Enumeration< T >::_finv = vector< T >();\ntemplate< typename T >\nvector< T > Enumeration< T >::_inv = vector< T >();\n\ntemplate <typename T>\nT norm1(const pair<T, T> &a, const pair<T, T> &b = {(T)0, (T)0}){\n return abs(a.first - b.first) + abs(a.second - b.second);\n}\ntemplate <typename T>\nT norm22(const pair<T, T> &a, const pair<T, T> &b = {(T)0, (T)0}){\n return (a.first - b.first) * (a.first - b.first) + (a.second - b.second) * (a.second - b.second);\n}\ntemplate <typename T>\ndouble norm2(const pair<T, T> &a, const pair<T, T> &b = {(T)0, (T)0}){\n return sqrt(norm22(a, b));\n}\n\nlong long powll(long long a, long long n){\n assert(n >= 0);\n if(n == 0)return 1;\n long long ret = 1;\n while(n){\n if(n & 1)ret *= a;\n a *= a;\n n >>= 1;\n }\n return ret;\n}\n\nvector<long long> str_to_vl(const string &s){\n vector<long long> ret(s.size());\n if(s.size() == 0)return ret;\n if(0 <= s[0]-'A' && s[0]-'A' < 26) for(int i=0;i<(int)s.size();i++) ret[i] = s[i] - 'A';\n else if(0 <= s[0]-'a' && s[0]-'a' < 26) for(int i=0;i<(int)s.size();i++) ret[i] = s[i] - 'a';\n else if(0 <= s[0]-'0' && s[0]-'0' < 10) for(int i=0;i<(int)s.size();i++) ret[i] = s[i] - '0';\n else assert(0);\n return ret;\n}\n\n// 0-indexed\nlong long TOPDIGIT(long long x){\n assert(x >= 0);\n long long ret = 0;\n while(x >= 10){x /= 10; ret++;}\n return ret;\n}\n\ntemplate <typename T>\nvector<pair<T, int>> sorti(const vector<T> &a){\n vector<pair<T, int>> ret(a.size());\n for(int i=0;i<(int)a.size();i++){\n ret[i] = {a[i], i};\n }\n sort(ret.begin(), ret.end());\n return ret;\n}\ntemplate <typename T1, typename T2>\nvector<tuple<T1, T2, int>> sorti(const vector<T1> &a, const vector<T2> &b){\n assert(a.size() == b.size());\n vector<tuple<T1, T2, int>> ret(a.size());\n for(int i=0;i<(int)a.size();i++){\n ret[i] = {a[i], b[i], i};\n }\n sort(ret.begin(), ret.end());\n return ret;\n}\ntemplate <typename T1, typename T2, typename T3>\nvector<tuple<T1, T2, T3, int>> sorti(const vector<T1> &a, const vector<T2> &b, const vector<T3> &c){\n assert(a.size() == b.size() && a.size() == c.size());\n vector<tuple<T1, T2, T3, int>> ret(a.size());\n for(int i=0;i<(int)a.size();i++){\n ret[i] = {a[i], b[i], c[i], i};\n }\n sort(ret.begin(), ret.end());\n return ret;\n}\n\n// 高々小数第 k 位までの実数を 10^k 倍して整数化\nll decimal_to_ll(const string &s, int k){\n int n = s.size();\n for(int i=0;i<n;i++){\n if(s[i] == '.'){\n ll ret = stoll(s.substr(0, i) + s.substr(i + 1));\n for(int j=0;j<k-(n-1-i);j++)ret *= 10;\n return ret;\n }\n }\n ll ret = stoll(s);\n for(int i=0;i<k;i++)ret *= 10;\n return ret;\n}\n\nlong long max(const int &a, const long long &b){return max((long long)a, b);}\nlong long min(const int &a, const long long &b){return min((long long)a, b);}\n\nconst vector<long long> dy = {1, 0, -1, 0, 1, -1, -1, 1};\nconst vector<long long> dx = {0, 1, 0, -1, 1, 1, -1, -1};\n\nrandom_device seed_gen;\nmt19937_64 rnd;\n\n// [low, high] の範囲の値を持つ長さ len のランダムベクトルを生成\nvector<long long> random_vl(int len, long long low, long long high){\n uniform_int_distribution<long long> dist(low, high);\n vector<long long> ret(len);\n for(int i=0;i<len;i++)ret[i] = dist(rnd);\n return ret;\n};\n\nvector<long long> random_permutation(int len){\n uniform_int_distribution<int> dist(1, len);\n vector<long long> ret(len);\n set<int> se;\n for(int i=0;i<len;i++){\n int tmp = dist(rnd);\n while(se.count(tmp))tmp = dist(rnd);\n ret[i] = tmp;\n se.insert(ret[i]);\n }\n return ret;\n};\n\n//--------------------------- テンプレゾーン終 -------------------------------//\n\n//----------------------------- コピペゾーン ---------------------------------//\n\n\n\n//---------------------------- コピペゾーン終 --------------------------------//\n\n#define int long long\n\nvoid solve(){\n\tvvl ans;\n map<pl, ll> right, left;\n right[{1, 2}] = 3, right[{1, 3}] = 5;\n right[{6, 2}] = 4, right[{6, 3}] = 2;\n while(sz(right) < 24){\n auto nxt = right;\n EACH(p, z, right){\n auto [x, y] = p;\n nxt[{y, x}] = 7 - z;\n nxt[{y, z}] = x;\n }\n swap(nxt, right);\n }\n EACH(p, z, right){\n left[{p}] = 7 - z;\n }\n while(1){\n INT(n);\n if(n == 0)break;\n vvl height(201, vl(201, 0));\n vvl num = height;\n REP(n){\n INT(t, f);\n ll y = 100, x = 100, h = height[y][x];\n while(1){\n bool fin = true;\n RREP(i, 4, 7){\n if(t == 7 - i)continue;\n if(f == i && height[y+1][x] < h){\n h = height[y+1][x];\n y = y + 1;\n ll tmp = t;\n t = right[{t, right[{t, f}]}];\n f = tmp;\n fin = false;\n break;\n }\n if(f == 7 - i && height[y-1][x] < h){\n h = height[y-1][x];\n y = y - 1;\n ll tmp = t;\n t = f;\n f = 7 - tmp;\n fin = false;\n break;\n }\n if(right[{t, f}] == i && height[y][x+1] < h){\n h = height[y][x+1];\n x++;\n t = left[{t, f}];\n fin = false;\n break;\n }\n if(left[{t, f}] == i && height[y][x-1] < h){\n h = height[y][x-1];\n x--;\n t = right[{t, f}];\n fin = false;\n break;\n }\n }\n if(fin)break;\n }\n height[y][x] = h + 1;\n num[y][x] = t;\n }\n vl res(6, 0);\n REP(i, 201)REP(j, 201){\n if(num[i][j] == 0)continue;\n res[num[i][j]-1]++;\n }\n ans.pb(res);\n }\n REP(i, sz(ans)){\n REP(j, sz(ans[i]))cout << ans[i][j] << (j == sz(ans[i]) - 1 ? \"\\n\" : \" \");\n }\n}\n\nint solve_test(int n, vl a){\n\n return 0;\n}\n\nint solve_naive(int n, vl a){\n\n return 0;\n}\n\nvoid random_test(){\n rnd.seed(seed_gen());\n\n uniform_int_distribution<int> dist_n(4, 10), dist_m(4, 10), dist_a(1, 20), dist_b(1, 20); \n\n for(int test = 1; test <= 100; test++){\n int n = dist_n(rnd), m = dist_m(rnd);\n vl a = random_vl(n, 3, 20);\n auto Output = solve_test(n, a), Answer = solve_naive(n, a);\n if(Output != Answer){\n cout << \"Wrong Answer on Test #\" << test << '\\n';\n debug(n);\n debug(a);\n debug(Answer);\n debug(Output);\n break;\n }\n }\n}\n\nsigned main(){\n int T = 1;\n // cin >> T;\n\n while(T--) solve();\n\n // random_test();\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4036, "score_of_the_acc": -0.0056, "final_rank": 8 }, { "submission_id": "aoj_1181_7959112", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\n\nvvll D = {\n {1,2,4,3},\n {0,3,5,2},\n {0,1,5,4},\n {0,4,5,1},\n {0,2,5,3},\n {1,3,4,2}\n};\n\nvoid rot(vll& d, ll& F) {\n while (d[0] != F) {\n rotate(d.begin(), d.begin() + 1, d.end());\n }\n return;\n}\n\nvll dx = { 0,1,0,-1 };\nvll dy = { 1,0,-1,0 };\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n while (1) {\n vector<vector<pair<ll, ll>>> H(220, vector<pair<ll, ll>>(220, { 0,-1 }));\n ll N;\n cin >> N;\n if (N == 0)return 0;\n rep(i, N) {\n ll T, F;\n cin >> T >> F;\n T--; F--;\n ll y = 110, x = 110;\n vll d = D[T];\n rot(d, F);\n while (1) {\n ll OK = -1, M = -1;\n rep(t, 4) {\n if (H[y][x].first > H[y + dy[t]][x + dx[t]].first && d[t] > 2) {\n if (chmax(M, d[t]))OK = t;\n }\n }\n if (OK == -1)break;\n\n y += dy[OK];\n x += dx[OK];\n if (OK == 0) {\n ll NT = 5 - F;\n F = T;\n T = NT;\n d = D[NT];\n rot(d, F);\n }\n else if (OK == 1) {\n ll NT = d[3];\n d = D[d[3]];\n T = NT;\n rot(d, F);\n }\n else if (OK == 2) {\n d = D[F];\n ll NT = F;\n F = 5 - T;\n T = NT;\n rot(d, F);\n }\n else {\n T = d[1];\n d = D[d[1]];\n \n rot(d, F);\n }\n\n }\n H[y][x].first++;\n H[y][x].second = T;\n }\n vll an(6, 0);\n rep(i, 220)rep(j, 220)if (H[i][j].second >= 0) {\n an[H[i][j].second]++;\n }\n rep(i, 6)cout << an[i] << \" \\n\"[i == 5];\n }\n\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3812, "score_of_the_acc": -0.0069, "final_rank": 9 }, { "submission_id": "aoj_1181_7818562", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nstruct myrand {\n\trandom_device rnd;\n\tmt19937 mt;\n\tmyrand() : rnd{}, mt{ rnd() } {}\n\t// l <= i and i < r\n\tint get(int l, int r) {\n\t\treturn mt() % r + l;\n\t}\n};\n\nstruct Dice {\n\tint top, bottom, north, south, east, west;\n\n\tvoid init(){\n\t\ttop = 1;\n\t\tbottom = 6;\n\t\teast = 5;\n\t\twest = 2;\n\t\tsouth = 3;\n\t\tnorth = 4;\n\t}\n\n\tDice() {\n\t\tinit();\n\t}\n\n\tDice(int t,int e) {\n\t\tinit();\n\n\t\tmyrand rnd;\n\n\t\twhile(t != top or e != east) {\n\t\t\tif (rnd.get(0, 2) == 0) {\n\t\t\t\trotate_north();\n\t\t\t} else {\n\t\t\t\trotate_east();\n\t\t\t}\n\t\t}\n\t}\n\n\tvoid rotate_north() {\n\t\tint tmp = bottom;\n\t\tbottom = north;\n\t\tnorth = top;\n\t\ttop = south;\n\t\tsouth = tmp;\n\t}\n\n\tvoid rotate_east() {\n\t\tint tmp = bottom;\n\t\tbottom = east;\n\t\teast = top;\n\t\ttop = west;\n\t\twest = tmp;\n\t}\n\n\tvoid rotate_west() {\n\t\tint tmp = bottom;\n\t\tbottom = west;\n\t\twest = top;\n\t\ttop = east;\n\t\teast = tmp;\n\t}\n\n\tvoid rotate_south() {\n\t\tint tmp = bottom;\n\t\tbottom = south;\n\t\tsouth = top;\n\t\ttop = north;\n\t\tnorth = tmp;\n\t}\n};\n\n\nvector<pair<int, char>> aspects(Dice d) {\n\tvector<pair<int,char>> a = {\n\t\tmake_pair(d.north, 'N'),\n\t\tmake_pair(d.south, 'S'),\n\t\tmake_pair(d.west, 'W'),\n\t\tmake_pair(d.east, 'E')\n\t};\n\n\tsort(a.rbegin(), a.rend());\n\n\treturn a;\n}\n\n\npair<int,int> direction_to_dxdy(char dir){\n\tswitch (dir){\n\t\tcase 'N':\n\t\t\treturn make_pair(0, -1);\n\t\tcase 'S':\n\t\t\treturn make_pair(0, 1);\n\t\tcase 'W':\n\t\t\treturn make_pair(-1, 0);\n\t\tcase 'E':\n\t\t\treturn make_pair(1, 0);\n\t}\n\tint inf = 1<<30;\n\treturn make_pair(inf, inf);\n}\n\n\nbool solve() {\n\tint n;\n\tcin>>n;\n\n\tif (n == 0) {\n\t\treturn false;\n\t}\n\n\tmap<pair<int,int>, vector<Dice>> xy_to_dices;\n\n\tfor(int i=0;i<n;i++) {\n\t\tint t, f;\n\t\tcin >> t >> f;\n\n\t\tDice d(t,f);\n\n\t\tassert(t == d.top and f == d.east);\n\n\t\tint x = 0, y = 0;\n\t\txy_to_dices[make_pair(x,y)].push_back(d);\n\n\t\twhile(true) {\n\t\t\tbool rotated = false;\n\n\t\t\t// 大きい順に側面を見る\n\t\t\tvector<pair<int, char>> as = aspects(d);\n\t\t\tfor(auto [v, dir]:as){\n\t\t\t\tif (v < 4) {\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\n\t\t\t\tauto [dx, dy] = direction_to_dxdy(dir);\n\t\t\t\tint nx = x + dx;\n\t\t\t\tint ny = y + dy;\n\n\t\t\t\tint size = xy_to_dices[make_pair(x,y)].size();\n\t\t\t\tint to_size = xy_to_dices[make_pair(nx,ny)].size();\n\n\t\t\t\t// 転がれる場合\n\t\t\t\tif (size - to_size >= 2) {\n\t\t\t\t\txy_to_dices[make_pair(x,y)].pop_back();\n\t\t\t\t\tswitch(dir){\n\t\t\t\t\t\tcase 'N':\n\t\t\t\t\t\t\td.rotate_north();\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\tcase 'E':\n\t\t\t\t\t\t\td.rotate_east();\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\tcase 'W':\n\t\t\t\t\t\t\td.rotate_west();\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\tcase 'S':\n\t\t\t\t\t\t\td.rotate_south();\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\tdefault:\n\t\t\t\t\t\t\tassert(false);\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\txy_to_dices[make_pair(nx,ny)].push_back(d);\n\t\t\t\t\tx = nx;\n\t\t\t\t\ty = ny;\n\t\t\t\t\trotated = true;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif (not rotated) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t}\n\n\tvector<int> ans(6, 0);\n\n\tfor(auto [p, dices]: xy_to_dices) {\n\t\tif (dices.size() == 0) {\n\t\t\tcontinue;\n\t\t}\n\n\t\t// 最も上に積み上がっているサイコロの上面を見る\n\t\tans[dices.back().top - 1]++;\n\t}\n\n\tfor(int i=0;i<6;i++){\n\t\tif (i) {\n\t\t\tcout << \" \";\n\t\t}\n\t\tcout << ans[i];\n\t}\n\tcout << \"\\n\";\n\n\treturn true;\n}\n\n\nint main() {\n\twhile(solve()) {}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3468, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1181_7167814", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nstruct Dice {\n\tint a[6];\n};\n\n// サイコロ・方向\nint dx[4] = { 0, 0, -1, 1 };\nint dy[4] = { -1, 1, 0, 0 };\nint Important[4] = { 3, 2, 4, 1 };\nint Transform[4][6] = {\n\t{ 2, 1, 5, 0, 4, 3 },\n\t{ 3, 1, 0, 5, 4, 2 },\n\t{ 1, 5, 2, 3, 0, 4 },\n\t{ 4, 0, 2, 3, 5, 1 }\n};\n\n// その他の変数\nconst int OFFSET = 150;\nint N, A[1009], B[1009];\nint cnt[309][309];\nvector<int> Saikoro[309][309];\n\nDice Initial(int A0, int A1) {\n\tDice E;\n\tE.a[0] = A0;\n\tE.a[1] = A1;\n\n\t// 最初が 1 の場合\n\tif (A0 == 1 && A1 == 2) E.a[2] = 3;\n\tif (A0 == 1 && A1 == 3) E.a[2] = 5;\n\tif (A0 == 1 && A1 == 5) E.a[2] = 4;\n\tif (A0 == 1 && A1 == 4) E.a[2] = 2;\n\n\t// 最初が 2 の場合\n\tif (A0 == 2 && A1 == 3) E.a[2] = 1;\n\tif (A0 == 2 && A1 == 1) E.a[2] = 4;\n\tif (A0 == 2 && A1 == 4) E.a[2] = 6;\n\tif (A0 == 2 && A1 == 6) E.a[2] = 3;\n\n\t// 最初が 3 の場合\n\tif (A0 == 3 && A1 == 1) E.a[2] = 2;\n\tif (A0 == 3 && A1 == 2) E.a[2] = 6;\n\tif (A0 == 3 && A1 == 6) E.a[2] = 5;\n\tif (A0 == 3 && A1 == 5) E.a[2] = 1;\n\n\t// 最初が 4 の場合\n\tif (A0 == 4 && A1 == 5) E.a[2] = 6;\n\tif (A0 == 4 && A1 == 6) E.a[2] = 2;\n\tif (A0 == 4 && A1 == 2) E.a[2] = 1;\n\tif (A0 == 4 && A1 == 1) E.a[2] = 5;\n\n\t// 最初が 5 の場合\n\tif (A0 == 5 && A1 == 6) E.a[2] = 4;\n\tif (A0 == 5 && A1 == 4) E.a[2] = 1;\n\tif (A0 == 5 && A1 == 1) E.a[2] = 3;\n\tif (A0 == 5 && A1 == 3) E.a[2] = 6;\n\n\t// 最初が 6 の場合\n\tif (A0 == 6 && A1 == 4) E.a[2] = 5;\n\tif (A0 == 6 && A1 == 5) E.a[2] = 3;\n\tif (A0 == 6 && A1 == 3) E.a[2] = 2;\n\tif (A0 == 6 && A1 == 2) E.a[2] = 4;\n\n\t// その他\n\tE.a[3] = 7 - E.a[2];\n\tE.a[4] = 7 - E.a[1];\n\tE.a[5] = 7 - E.a[0];\n\treturn E;\n}\n\nDice Move(Dice E, int dir) {\n\tDice F;\n\tfor (int i = 0; i < 6; i++) F.a[i] = E.a[Transform[dir][i]];\n\treturn F;\n}\n\nvoid solve() {\n\t// 初期化\n\tfor (int i = 0; i <= 300; i++) {\n\t\tfor (int j = 0; j <= 300; j++) {\n\t\t\tcnt[i][j] = 0; Saikoro[i][j].clear();\n\t\t}\n\t}\n\n\t// シミュレーション\n\tfor (int i = 1; i <= N; i++) {\n\t\tDice G = Initial(A[i], B[i]);\n\t\tint cx = OFFSET, cy = OFFSET;\n\n\t\t// 転がりのシミュレーション\n\t\twhile (true) {\n\t\t\tint maxn = -1;\n\t\t\tint max_id = -1;\n\t\t\tfor (int dir = 0; dir < 4; dir++) {\n\t\t\t\tif (G.a[Important[dir]] <= 3) continue;\n\t\t\t\tint sx = cx + dx[dir];\n\t\t\t\tint sy = cy + dy[dir];\n\t\t\t\tif (cnt[sx][sy] >= cnt[cx][cy]) continue;\n\t\t\t\tif (maxn < G.a[Important[dir]]) {\n\t\t\t\t\tmaxn = G.a[Important[dir]];\n\t\t\t\t\tmax_id = dir;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (max_id == -1) break;\n\n\t\t\t// サイコロを転がす\n\t\t\tcx += dx[max_id];\n\t\t\tcy += dy[max_id];\n\t\t\tG = Move(G, max_id);\n\t\t}\n\n\t\t// サイコロを追加\n\t\tSaikoro[cx][cy].push_back(G.a[0]);\n\t\tcnt[cx][cy] += 1;\n\t}\n\n\t// 答えを計算\n\tvector<int> Answer(6, 0);\n\tfor (int i = 0; i <= 300; i++) {\n\t\tfor (int j = 0; j <= 300; j++) {\n\t\t\tif (Saikoro[i][j].size() == 0) continue;\n\t\t\tint val = Saikoro[i][j][Saikoro[i][j].size() - 1];\n\t\t\tAnswer[val - 1] += 1;\n\t\t}\n\t}\n\n\t// 答えを出力\n\tcout << Answer[0] << \" \" << Answer[1] << \" \" << Answer[2] << \" \" << Answer[3] << \" \" << Answer[4] << \" \" << Answer[5] << endl;\n}\n\nint main() {\n\twhile (true) {\n\t\t// 入力\n\t\tcin >> N; if (N == 0) break;\n\t\tfor (int i = 1; i <= N; i++) cin >> A[i] >> B[i];\n\n\t\t// 問題を解く\n\t\tsolve();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5956, "score_of_the_acc": -0.0247, "final_rank": 10 }, { "submission_id": "aoj_1181_6779204", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(x, y) for (int x = 0; x < y; x++)\n#define rrep(x, y) for (int x = y - 1; x >= 0; x--)\n#define orep(x, y) for (int x = 1; x <= y; x++)\n#define ll long long\ntemplate <class T>\nbool chmax(T &a, const T &b) {\n return a < b ? (a = b, 1) : 0;\n}\ntemplate <class T>\nbool chmin(T &a, const T &b) {\n return b < a ? (a = b, 1) : 0;\n}\nusing namespace std;\nusing P = pair<int, int>;\n\nconst vector<P> DIRS = {{1, 0}, {0, -1}, {-1, 0}, {0, 1}};\n\nstruct Dice {\n int top_n = -1, front_n = -1;\n\n vector<int> get_sides() {\n if (top_n == 6) {\n return vector<int>{2, 3, 5, 4};\n }\n if (top_n == 5) {\n return vector<int>{3, 1, 4, 6};\n }\n if (top_n == 4) {\n return vector<int>{1, 2, 6, 5};\n }\n if (top_n == 3) {\n return vector<int>{2, 1, 5, 6};\n }\n if (top_n == 2) {\n return vector<int>{1, 3, 6, 4};\n }\n if (top_n == 1) {\n return vector<int>{3, 2, 4, 5};\n }\n exit(1);\n }\n\n int get_bottom() { return 7 - top_n; }\n\n vector<P> get_dirs() {\n vector<int> sides = get_sides();\n\n vector<int> idx_list;\n for (int i = 6; i >= 4; i--) {\n rep(si, 4) {\n if (sides[si] == i) idx_list.push_back(si);\n }\n }\n\n int rotate_cnt = -1;\n rep(i, 4) {\n if (sides[i] == front_n) {\n rotate_cnt = i;\n }\n }\n\n return vector<P>{DIRS[(idx_list[0] - rotate_cnt + 4) % 4],\n DIRS[(idx_list[1] - rotate_cnt + 4) % 4]};\n }\n\n Dice rotate(P dir) {\n vector<int> sides = get_sides();\n int rotate_cnt = -1;\n rep(i, 4) {\n if (sides[i] == front_n) {\n rotate_cnt = i;\n }\n }\n\n int dir_no = -1;\n rep(i, 4) {\n if (DIRS[i].first == dir.first && DIRS[i].second == dir.second) {\n dir_no = i;\n }\n }\n\n int under_n = sides[(dir_no + rotate_cnt) % 4];\n if (dir_no == 0) {\n return Dice{7 - under_n, top_n};\n }\n if (dir_no == 2) {\n return Dice{7 - under_n, get_bottom()};\n }\n if (dir_no % 2) {\n return Dice{7 - under_n, front_n};\n }\n exit(1);\n }\n};\nstruct Floor {\n vector<vector<Dice>> floor;\n Floor() {\n vector<vector<Dice>> new_floor(100, vector<Dice>(100));\n swap(new_floor, floor);\n }\n\n Dice &get(int h, int w) { return floor[h + 50][w + 50]; }\n};\n\nstruct Field {\n int highest = 0;\n\n vector<Floor> field;\n Field() {\n vector<Floor> new_field(100);\n swap(field, new_field);\n }\n\n void fall(Dice a) {\n int now = highest - 1;\n Dice dice = a;\n int h = 0;\n int w = 0;\n while (1) {\n if (now < 0) break;\n bool has_move = false;\n auto dirs = a.get_dirs();\n for (auto d : dirs) {\n int new_h = h + d.first;\n int new_w = w + d.second;\n if (field[now].get(new_h, new_w).top_n == -1) {\n has_move = true;\n a = a.rotate(d);\n h = new_h;\n w = new_w;\n break;\n }\n }\n if (has_move) {\n now--;\n while (now >= 0 && field[now].get(h, w).top_n == -1) {\n now--;\n }\n } else {\n break;\n }\n }\n if (h == 0 && w == 0) {\n field[highest].get(h, w) = a;\n highest++;\n } else {\n field[now + 1].get(h, w) = a;\n }\n }\n\n void output() {\n vector<vector<bool>> used(100, vector<bool>(100, false));\n vector<int> ans(7);\n rrep(layer, 100) {\n rep(hi, 100) rep(wi, 100) {\n if (used[hi][wi]) continue;\n if (field[layer].floor[hi][wi].top_n == -1) continue;\n used[hi][wi] = true;\n ans[field[layer].floor[hi][wi].top_n]++;\n }\n }\n rep(i, 7) {\n if (i == 0) continue;\n if (i == 6) {\n cout << ans[i] << endl;\n } else {\n cout << ans[i] << \" \";\n }\n }\n }\n};\n\nbool func() {\n int n;\n cin >> n;\n if (n == 0) return false;\n\n Field field;\n rep(i, n) {\n int top, front;\n cin >> top >> front;\n field.fall(Dice{top, front});\n }\n field.output();\n return true;\n}\n\nint main() {\n while (func()) {\n ;\n }\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 11576, "score_of_the_acc": -0.127, "final_rank": 15 }, { "submission_id": "aoj_1181_6775241", "code_snippet": "// #define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\n//#include <atcoder/all>\nusing namespace std;\n//using namespace atcoder;\n\n#define int long long\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define rep(i, n) for (int i = 0; i < n; ++i)\n#define REP(i, n) for (int i = 0; i < n; ++i)\n#define range(i,a,b) ((a)<=(i) && (i)<(b))\n#define debug(x) cout << #x << \" = \" << (x) << endl;\n#define fs first\n#define sc second\n#define pb push_back\n#define eb emplace_back\n#define SP << \" \" <<\n\ntypedef long long ll;\ntypedef pair<int, int> P;\ntypedef tuple<int, int, int> T;\ntypedef vector<int> vec;\ntypedef vector<P> pvec;\ntypedef vector<vector<int>> vvec;\ntypedef vector<vector<P>> pvvec;\ntypedef priority_queue<int> PQI;\ntypedef priority_queue<P> PQP;\ntypedef priority_queue<int,vector<int>,greater<int>> PQIG;\ntypedef priority_queue<P,vector<P>,greater<P>> PQPG;\n\nconst vector<int> DX = {0, -1, 0, 1, 1, 1, -1, -1};\nconst vector<int> DY = {1, 0, -1, 0, 1, -1, 1, -1};\nconstexpr int MOD = (1000000007);\n// const int MOD = (998244353);\n// const int INF = (1 << 30); // 1073741824\nconst ll INF = (1LL << 60); // 1152921504606846976\nconst double PI = (3.141592653589794);\nconst double EPS = (0.0000000001); // 10^(-10)\n\ntemplate<class T> inline bool chmin(T& a, T b) {if (a > b) {a = b; return 1;} return 0;}\ntemplate<class T> inline bool chmax(T& a, T b) {if (a < b) {a = b; return 1;} return 0;}\ntemplate<class T> inline T ceil(T a, T b) {return T((a + b - 1) / b);}\ntemplate<class T> inline T round(T a, T b) {return T(a / b);}\ntemplate< typename T1, typename T2 > istream &operator>>(istream &is, pair< T1, T2 > &p) { is >> p.first >> p.second; return is; }\ntemplate <class T> inline void out(T &a) { bool flag=true; for(auto&x:a){if(flag) {flag=false;} else{ cout << ' '; } cout<<x; } cout << endl; }\n\n\n\n//----------------------------------------------------------------\nint nmax=200000; // 2*(10^5)\nvvec G(nmax);\n\nstruct sai{\n vvec rr={{0,3,5,2,4,0},\n {4,0,1,6,0,3},\n {2,6,0,0,1,5},\n {5,1,0,0,6,2},\n {3,0,6,1,0,4},\n {0,4,2,5,3,0}};\n int tf(int t,int f){\n return rr[t-1][f-1];\n };\n vec four(int t,int f){\n int r=tf(t,f);\n return vector<int>{f,r,7-f,7-r}; // 手前、右、奥、左 // x, y, -x, -y\n }\n};\n\nconst vector<int> dx = {1, 0, -1, 0, 1, 1, -1, -1};\nconst vector<int> dy = {0, 1, 0, -1, 1, -1, 1, -1};\n\nint h[300][300];\nint me[300][300];\n\nvoid solve4ts()\n{\n \n \n int n;\n cin>>n;\n if(n==0) exit(0);\n sai saikoro;\n \n int geta=150;\n rep(i,300) rep(j,300){\n h[i][j]=0;\n me[i][j]=0;\n }\n rep(_,n){\n \n int x=geta; int y=geta;\n int t,f; cin>>t>>f;\n while(true){\n bool koro=false;\n vec four = saikoro.four(t,f);\n for(int c=6;c>=4;c--){\n rep(dir,4){\n if(c==four[dir]){\n int nx=x+dx[dir];\n int ny=y+dy[dir];\n if(h[nx][ny]<h[x][y]){\n int nt,nf;\n int r=saikoro.tf(t,f);\n if(dir==0) nt=7-f,nf=t;\n if(dir==1) nt=7-r,nf=f;\n if(dir==2) nt=f,nf=7-t;\n if(dir==3) nt=r,nf=f;\n t=nt; f=nf; x=nx; y=ny;\n koro=true;\n break;\n }\n }\n }\n if(koro) break;\n }\n if(!koro) break;\n }\n h[x][y]++;\n me[x][y]=t;\n }\n vec count(10);\n rep(i,300) rep(j,300) count[me[i][j]]++;\n for(int i=1;i<=6;i++){\n if(i==6) cout<<count[i];\n else cout<<count[i]<<\" \";\n }\n cout<<endl;\n}\n//-----------------------------------------------------------------\n\nsigned main(){ ios::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(15);\n int repeat = INF;\n // cin >> repeat;\n while(repeat--) solve4ts();\n}\n\n/*\n\ng++ -std=c++1z code.cpp\n\n./a.out\n\npython3 expander.py code.cpp\n\n*/", "accuracy": 1, "time_ms": 20, "memory_kb": 9080, "score_of_the_acc": -0.0574, "final_rank": 14 }, { "submission_id": "aoj_1181_6775208", "code_snippet": "#include <bits/stdc++.h>\n#ifdef MY_DEBUG\n #include \"dprint.cpp\"\n # define dprint(a, ...);\\\n do {\\\n printf(\"line : %d, func : %s\\n\",\\\n __LINE__, __func__);\\\n dprint(#a,a,##__VA_ARGS__ );\\\n } while (0)\n#else\n #define dprint(a,...) \n#endif\nusing namespace std;\nvector<vector<vector<int>>>room;\nint n;\nvector<int> get_room(int x,int y){\n return room[x+n][y+n];\n}\n\nvoid set_room(int x,int y,int top){\n room[x+n][y+n][0]++;\n room[x+n][y+n][1]=top;\n}\n\nint get_right_side(int top,int front){\n top--;\n front--;\n int right_side[6][6]={\n {0,3,5,2,4,0},\n {4,0,1,6,0,3},\n {2,6,0,0,1,5},\n {5,1,0,0,6,2},\n {3,0,6,1,0,4},\n {0,4,2,5,3,0}\n };\n\n return right_side[top][front];\n\n}\n\nvoid solve(vector<vector<int>> vec){\n\nfor (auto v :vec){\n int now_x=0;\n int now_y=0;\n int now_z=get_room(now_x,now_x)[0];\n int now_top=v[0];\n int now_front=v[1];\n\n while (true){\n int rotate=-1;\n int rotate_num=-1;\n\n //front\n int dice=now_front;\n if(dice>=4&& rotate_num<dice){\n //目の大きさ的に回転する可能性あり\n if(get_room(now_x,now_y+1)[0]<now_z){\n //高低差あり\n rotate_num=dice;\n rotate=0;//front\n }\n }\n\n //back 7-front\n dice=7-now_front;\n if(dice>=4&& rotate_num<dice){\n //目の大きさ的に回転する可能性あり\n if(get_room(now_x,now_y-1)[0]<now_z){\n //高低差あり\n\n rotate_num=dice;\n rotate=1;//-front\n }\n }\n\n //right get_right_side(top,front)\n dice=get_right_side(now_top,now_front);\n if(dice>=4&& rotate_num<dice){\n //目の大きさ的に回転する可能性あり\n if(get_room(now_x+1,now_y)[0]<now_z){\n //高低差あり\n rotate_num=dice;\n rotate=2;//right\n }\n }\n //left 7-get_right_side(top,side)\n dice=7-get_right_side(now_top,now_front);\n if(dice>=4&& rotate_num<dice){\n //目の大きさ的に回転する可能性あり\n if(get_room(now_x-1,now_y)[0]<now_z){\n //高低差あり\n rotate_num=dice;\n rotate=3;//-right\n }\n }\n\n if(rotate_num==-1){\n //確定(転がることができない)\n set_room(now_x,now_y,now_top);\n break;\n }\n int t_front=now_front;\n int t_back=7-now_front;\n int t_right=get_right_side(now_top,now_front);\n int t_left=7-get_right_side(now_top,now_front);\n int t_top=now_top;\n int t_bottom=7-now_top;\n\n switch (rotate){\n case 0:\n now_front=t_top;\n now_top=t_back;\n \n now_y++;\n now_z=get_room(now_x,now_y)[0];\n break;\n \n case 1:\n now_front=t_bottom;\n now_top=t_front;\n\n now_y--;\n now_z=get_room(now_x,now_y)[0];\n break; \n case 2:\n now_top=t_left;\n\n now_x++;\n now_z=get_room(now_x,now_y)[0];\n break;\n\n case 3:\n now_top=t_right; \n\n now_x--;\n now_z=get_room(now_x,now_y)[0];\n break;\n }\n }\n \n \n\n}\n\n\n\n}\n\nint main() {\n while (true){\n cin >>n;\n if(n==0)break;\n\n vector<vector<int>> vec(n, vector<int>(2));\n for (int i = 0; i < n; i++){\n for(int j=0;j<2;j++){\n cin >> vec[i][j];\n }\n }\n room=vector<vector<vector<int>>>(2*n+1,vector<vector<int>>(2*n+1,vector<int>(2,0)));\n solve(vec);\n vector<int>ans(7,0);\n for (int i = 0; i < 2*n+1; i++){\n for (int j = 0; j < 2*n+1; j++){\n ans[room[i][j][1]]++;\n }\n \n }\n for (int i = 1; i <= 6; i++)\n {\n cout <<ans[i] ; \n if(i!=6)cout << \" \";\n }\n cout << endl;\n \n }\n \nreturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 7464, "score_of_the_acc": -0.0431, "final_rank": 13 }, { "submission_id": "aoj_1181_6773506", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n\nvector<int> make_dice(int t,int f){\n vector<int> dice(6);\n dice[0]=f,dice[2]=7-f;\n dice[4]=t,dice[5]=7-t;\n if(f==1&&t==2) dice[1]=3;\n if(f==1&&t==3) dice[1]=5;\n if(f==1&&t==4) dice[1]=2;\n if(f==1&&t==5) dice[1]=4;\n if(f==2&&t==1) dice[1]=4;\n if(f==2&&t==3) dice[1]=1;\n if(f==2&&t==4) dice[1]=6;\n if(f==2&&t==6) dice[1]=3;\n if(f==3&&t==1) dice[1]=2;\n if(f==3&&t==2) dice[1]=6;\n if(f==3&&t==5) dice[1]=1;\n if(f==3&&t==6) dice[1]=5;\n if(f==4&&t==1) dice[1]=5;\n if(f==4&&t==2) dice[1]=1;\n if(f==4&&t==5) dice[1]=6;\n if(f==4&&t==6) dice[1]=2;\n if(f==5&&t==1) dice[1]=3;\n if(f==5&&t==3) dice[1]=6;\n if(f==5&&t==4) dice[1]=1;\n if(f==5&&t==6) dice[1]=4;\n if(f==6&&t==2) dice[1]=4;\n if(f==6&&t==3) dice[1]=2;\n if(f==6&&t==4) dice[1]=5;\n if(f==6&&t==5) dice[1]=3;\n dice[3]=7-dice[1];\n return dice;\n}\n\nvector<int> rotate(vector<int> dice,int d){\n if(d==0){\n return {dice[4],dice[1],dice[5],dice[3],dice[2],dice[0]};\n }\n if(d==1){\n return {dice[0],dice[4],dice[2],dice[5],dice[3],dice[1]};\n }\n if(d==2){\n return {dice[5],dice[1],dice[4],dice[3],dice[0],dice[2]};\n }\n if(d==3){\n return {dice[0],dice[5],dice[2],dice[4],dice[1],dice[3]};\n }\n return {};\n}\n\nvoid solve(){\n while(1){\n map<pair<int,int>,int> num,height;\n vector<int> dx={0,-1,0,1},dy={-1,0,1,0};\n int n;\n cin>>n;\n if(n==0){\n break;\n }\n vector<int> t(n),f(n);\n for(int i=0;i<n;i++){\n cin>>t[i]>>f[i];\n }\n for(int i=0;i<n;i++){\n vector<int> dice=make_dice(t[i],f[i]);\n int x=0,y=0,h=height[{x,y}]+1;\n while(1){\n vector<pair<int,int>> possible_move;\n for(int d=0;d<4;d++){\n if(dice[d]>=4&&h>height[{x+dx[d],y+dy[d]}]+1){\n possible_move.push_back({dice[d],d});\n }\n }\n if(possible_move.size()==0){\n num[{x,y}]=dice[4];\n height[{x,y}]=h;\n break;\n }\n sort(possible_move.begin(),possible_move.end(),greater<pair<int,int>>());\n int rd=possible_move[0].second;\n x+=dx[rd],y+=dy[rd];\n h=height[{x,y}]+1;\n dice=rotate(dice,rd);\n }\n }\n vector<int> ans(7,0);\n for(int x=-200;x<=200;x++){\n for(int y=-200;y<=200;y++){\n ans[num[{x,y}]]++;\n }\n }\n for(int i=1;i<=5;i++){\n cout<<ans[i]<<\" \";\n }\n cout<<ans[6]<<endl;\n }\n return;\n}\n\nint main(){\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 3150, "memory_kb": 13232, "score_of_the_acc": -0.6383, "final_rank": 17 }, { "submission_id": "aoj_1181_6740167", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <deque>\n#include <queue>\n#include <string>\n#include <iomanip>\n#include <set>\n#include <unordered_set>\n#include <map>\n#include <unordered_map>\n#include <utility>\n#include <stack>\n#include <random>\n#include <stdio.h>\n#include <stdlib.h>\n#include <time.h>\n#include <math.h>\n#include <assert.h>\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\nusing namespace atcoder;\n#endif\nusing namespace std;\nusing ll=long long;\n#define read(x) cin>>(x);\n#define readll(x) ll (x);cin>>(x);\n#define readS(x) string (x);cin>>(x);\n#define readvll(x,N) vector<ll> (x)((N));for(int i=0;i<(N);i++){cin>>(x)[i];}\n#define rep(i,N) for(ll (i)=0;(i)<(N);(i)++)\n#define rep2d(i,j,H,W) for(ll (i)=0;(i)<(H);(i)++)for(ll (j)=0;(j)<(W);j++)\n#define is_in(x,y) (0<=(x) && (x)<H && 0<=(y) && (y)<W)\n#define yn {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}\ninline ll powll(ll x,ll n){ll r=1;while(n>0){if(n&1){r*=x;};x*=x;n>>=1;};return r;}\n\nconst ll M=200;\n\nstruct Dice{\n ll top,front,bottom,back,left,right;\n Dice(){\n top=1;\n front=3;\n bottom=6;\n back=4;\n left=2;\n right=5;\n }\n};\n\nvoid debug(Dice x){\n cerr<<x.top<<\" \"<<x.front<<\" \"<<x.bottom<<\" \"<<x.back<<\" \"<<x.left<<\" \"<<x.right<<endl;\n}\n\nDice roll_right(Dice x){\n Dice res;\n res.top=x.left;\n res.front=x.front;\n res.bottom=x.right;\n res.back=x.back;\n res.left=x.bottom;\n res.right=x.top;\n return res;\n}\n\nDice roll_left(Dice x){\n Dice res;\n res.top=x.right;\n res.front=x.front;\n res.bottom=x.left;\n res.back=x.back;\n res.left=x.top;\n res.right=x.bottom;\n return res;\n}\n\nDice roll_front(Dice x){\n Dice res;\n res.top=x.back;\n res.front=x.top;\n res.bottom=x.front;\n res.back=x.bottom;\n res.left=x.left;\n res.right=x.right;\n return res;\n}\n\nDice roll_back(Dice x){\n Dice res;\n res.top=x.front;\n res.front=x.bottom;\n res.bottom=x.back;\n res.back=x.top;\n res.left=x.left;\n res.right=x.right;\n return res;\n}\n\nDice spin_right(Dice x){\n Dice res;\n res.top=x.top;\n res.front=x.right;\n res.bottom=x.bottom;\n res.back=x.left;\n res.left=x.front;\n res.right=x.back;\n return res;\n}\n\nDice spin_left(Dice x){\n Dice res;\n res.top=x.top;\n res.front=x.left;\n res.bottom=x.bottom;\n res.back=x.right;\n res.left=x.back;\n res.right=x.front;\n return res;\n}\n\nDice getDice(ll t,ll f){\n Dice res;\n if(t==1){\n if(f==2){\n res=spin_left(res);\n return res;\n }else if(f==3){\n return res;\n }else if(f==4){\n res=spin_left(res);\n res=spin_left(res);\n return res;\n }else if(f==5){\n res=spin_right(res);\n return res;\n }else{\n exit(1);\n }\n }else if(t==2){\n res=roll_right(res);\n if(f==1){\n res=spin_right(res);\n return res;\n }else if(f==3){\n return res;\n }else if(f==4){\n res=spin_right(res);\n res=spin_right(res);\n return res;\n }else if(f==6){\n res=spin_left(res);\n return res;\n }else{\n exit(1);\n }\n }else if(t==3){\n res=roll_back(res);\n if(f==1){\n res=spin_left(res);\n res=spin_left(res);\n return res;\n }else if(f==2){\n res=spin_left(res);\n return res;\n }else if(f==5){\n res=spin_right(res);\n return res;\n }else if(f==6){\n return res;\n }else{\n exit(1);\n }\n }else if(t==4){\n res=roll_front(res);\n if(f==1){\n return res;\n }else if(f==2){\n res=spin_left(res);\n return res;\n }else if(f==5){\n res=spin_right(res);\n return res;\n }else if(f==6){\n res=spin_left(res);\n res=spin_left(res);\n return res;\n }else{\n exit(1);\n }\n }else if(t==5){\n res=roll_left(res);\n if(f==1){\n res=spin_left(res);\n return res;\n }else if(f==3){\n return res;\n }else if(f==4){\n res=spin_left(res);\n res=spin_left(res);\n return res;\n }else if(f==6){\n res=spin_right(res);\n return res;\n }else{\n exit(1);\n }\n }else{\n res=roll_left(res);\n res=roll_left(res);\n if(f==2){\n res=spin_right(res);\n return res;\n }else if(f==3){\n return res;\n }else if(f==4){\n res=spin_left(res);\n res=spin_left(res);\n return res;\n }else if(f==5){\n res=spin_left(res);\n return res;\n }else{\n exit(1);\n }\n }\n //exit(1);\n}\n\n\nvoid solve(ll n){\n ll t,f;\n vector<vector<pair<ll,ll>>> d(2*M+1,vector<pair<ll,ll>>(2*M+1,make_pair(0,0)));// 高さ、数\n vector<ll> ans(7);\n for(ll i=0;i<n;i++){\n cin>>t>>f;\n //cerr<<endl<<t<<\" \"<<f<<endl;\n Dice di=getDice(t,f);\n //debug(di);\n ll x=M,y=M;\n ll dx,dy;\n while(1){\n vector<pair<ll,pair<ll,ll>>> tmp;\n if(d[x][y].first>d[x+1][y].first && di.right>=4){\n tmp.push_back(make_pair(di.right,make_pair(1,0)));\n }\n if(d[x][y].first>d[x][y+1].first && di.back>=4){\n tmp.push_back(make_pair(di.back,make_pair(0,1)));\n }\n if(d[x][y].first>d[x-1][y].first && di.left>=4){\n tmp.push_back(make_pair(di.left,make_pair(-1,0)));\n }\n if(d[x][y].first>d[x][y-1].first && di.front>=4){\n tmp.push_back(make_pair(di.front,make_pair(0,-1)));\n }\n sort(tmp.rbegin(),tmp.rend());\n if(tmp.empty()){\n ans[d[x][y].second]--;\n ans[di.top]++;\n d[x][y].first++;\n d[x][y].second=di.top;\n break;\n }\n dx=tmp[0].second.first;\n dy=tmp[0].second.second;\n //cerr<<dx<<\" \"<<dy<<endl;\n if(dx==1 && dy==0){\n di=roll_right(di);\n }else if(dx==0 && dy==1){\n di=roll_back(di);\n }else if(dx==-1 && dy==0){\n di=roll_left(di);\n }else if(dx==0 && dy==-1){\n di=roll_front(di);\n }else{\n exit(1);\n }\n x+=dx;\n y+=dy;\n }\n }\n cout<<ans[1]<<\" \"<<ans[2]<<\" \"<<ans[3]<<\" \"<<ans[4]<<\" \"<<ans[5]<<\" \"<<ans[6]<<endl;\n}\n\nint main(){\n ll n;\n while(1){\n cin>>n;\n if(n==0){\n break;\n }\n solve(n);\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 5616, "score_of_the_acc": -0.0351, "final_rank": 12 }, { "submission_id": "aoj_1181_6014058", "code_snippet": "#pragma GCC target(\"avx,avx2\")\n//#pragma GCC optimize(\"Ofast\")\n//#undef LOCAL\n\n#include <unistd.h>\n#include <algorithm>\n#include <array>\n#include <cassert>\n#include <cctype>\n#include <cstring>\n#include <sstream>\n#include <string>\n#include <type_traits>\n#include <vector>\n\nnamespace yosupo {\n\nnamespace internal {\n\nint ceil_pow2(int n) {\n int x = 0;\n while ((1U << x) < (unsigned int)(n)) x++;\n return x;\n}\n\n} // namespace internal\n\nint bsf(unsigned int n) {\n return __builtin_ctz(n);\n}\nint bsf(unsigned long n) {\n return __builtin_ctzl(n);\n}\nint bsf(unsigned long long n) {\n return __builtin_ctzll(n);\n}\nint bsf(unsigned __int128 n) {\n unsigned long long low = (unsigned long long)(n);\n unsigned long long high = (unsigned long long)(n >> 64);\n return low ? __builtin_ctzll(low) : 64 + __builtin_ctzll(high);\n}\n\nint bsr(unsigned int n) {\n return 8 * (int)sizeof(unsigned int) - 1 - __builtin_clz(n);\n}\nint bsr(unsigned long n) {\n return 8 * (int)sizeof(unsigned long) - 1 - __builtin_clzl(n);\n}\nint bsr(unsigned long long n) {\n return 8 * (int)sizeof(unsigned long long) - 1 - __builtin_clzll(n);\n}\nint bsr(unsigned __int128 n) {\n unsigned long long low = (unsigned long long)(n);\n unsigned long long high = (unsigned long long)(n >> 64);\n return high ? 127 - __builtin_clzll(high) : 63 - __builtin_ctzll(low);\n}\n\nint popcnt(unsigned int n) {\n return __builtin_popcount(n);\n}\nint popcnt(unsigned long n) {\n return __builtin_popcountl(n);\n}\nint popcnt(unsigned long long n) {\n return __builtin_popcountll(n);\n}\n\n} // namespace yosupo\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\nnamespace yosupo {\n\nnamespace internal {\n\ntemplate <class T> using is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value || std::is_same<T, __int128>::value,\n std::true_type, std::false_type>::type;\n\ntemplate <class T> using is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type, std::false_type>::type;\n\ntemplate <class T> using make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value, __uint128_t, unsigned __int128>;\n\ntemplate <class T> using is_integral =\n typename std::conditional<std::is_integral<T>::value || internal::is_signed_int128<T>::value ||\n internal::is_unsigned_int128<T>::value,\n std::true_type, std::false_type>::type;\n\ntemplate <class T> using is_signed_int =\n typename std::conditional<(is_integral<T>::value && std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type, std::false_type>::type;\n\ntemplate <class T> using is_unsigned_int =\n typename std::conditional<(is_integral<T>::value && std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type, std::false_type>::type;\n\ntemplate <class T> using to_unsigned =\n typename std::conditional<is_signed_int128<T>::value, make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value, std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\ntemplate <class T> using is_integral_t = std::enable_if_t<is_integral<T>::value>;\n\ntemplate <class T> using is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\ntemplate <class T> using is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\ntemplate <class T> using to_unsigned_t = typename to_unsigned<T>::type;\n\n} // namespace internal\n\n} // namespace yosupo\n\nnamespace yosupo {\n\nstruct Scanner {\npublic:\n Scanner(const Scanner&) = delete;\n Scanner& operator=(const Scanner&) = delete;\n\n Scanner(FILE* fp) : fd(fileno(fp)) {}\n\n void read() {}\n template <class H, class... T> void read(H& h, T&... t) {\n bool f = read_single(h);\n assert(f);\n read(t...);\n }\n\n int read_unsafe() { return 0; }\n template <class H, class... T> int read_unsafe(H& h, T&... t) {\n bool f = read_single(h);\n if (!f) return 0;\n return 1 + read_unsafe(t...);\n }\n\n int close() { return ::close(fd); }\n\nprivate:\n static constexpr size_t SIZE = 1 << 15;\n\n int fd = -1;\n std::array<char, SIZE> line;\n size_t st = 0, ed = 0;\n bool eof = false;\n\n bool read_single(std::string& ref) {\n if (!skip_space()) return false;\n ref = \"\";\n while (true) {\n char c = top();\n if (c <= ' ') break;\n ref += c;\n st++;\n }\n return true;\n }\n bool read_single(double& ref) {\n std::string s;\n if (!read_single(s)) return false;\n ref = std::stod(s);\n return true;\n }\n\n template <class T, std::enable_if_t<std::is_same<T, char>::value>* = nullptr>\n bool read_single(T& ref) {\n if (!skip_space(50)) return false;\n ref = top();\n st++;\n return true;\n }\n\n template <class T, internal::is_signed_int_t<T>* = nullptr,\n std::enable_if_t<!std::is_same<T, char>::value>* = nullptr>\n bool read_single(T& sref) {\n using U = internal::to_unsigned_t<T>;\n if (!skip_space(50)) return false;\n bool neg = false;\n if (line[st] == '-') {\n neg = true;\n st++;\n }\n U ref = 0;\n do {\n ref = 10 * ref + (line[st++] & 0x0f);\n } while (line[st] >= '0');\n sref = neg ? -ref : ref;\n return true;\n }\n template <class U, internal::is_unsigned_int_t<U>* = nullptr,\n std::enable_if_t<!std::is_same<U, char>::value>* = nullptr>\n bool read_single(U& ref) {\n if (!skip_space(50)) return false;\n ref = 0;\n do {\n ref = 10 * ref + (line[st++] & 0x0f);\n } while (line[st] >= '0');\n return true;\n }\n\n bool reread() {\n if (ed - st >= 50) return true;\n if (st > SIZE / 2) {\n std::memmove(line.data(), line.data() + st, ed - st);\n ed -= st;\n st = 0;\n }\n if (eof) return false;\n auto u = ::read(fd, line.data() + ed, SIZE - ed);\n if (u == 0) {\n eof = true;\n line[ed] = '\\0';\n u = 1;\n }\n ed += u;\n return true;\n }\n\n char top() {\n if (st == ed) {\n bool f = reread();\n assert(f);\n }\n return line[st];\n }\n\n bool skip_space(unsigned int token_len = 0) {\n while (true) {\n while (st != ed && line[st] <= ' ') st++;\n if (ed - st > token_len) return true;\n for (auto i = st; i < ed; i++) {\n if (line[i] <= ' ') return true;\n }\n if (!reread()) return false;\n }\n }\n};\n\nstruct Printer {\npublic:\n template <char sep = ' ', bool F = false> void write() {}\n template <char sep = ' ', bool F = false, class H, class... T> void write(const H& h, const T&... t) {\n if (F) write_single(sep);\n write_single(h);\n write<true>(t...);\n }\n template <char sep = ' ', class... T> void writeln(const T&... t) {\n write<sep>(t...);\n write_single('\\n');\n }\n\n Printer(FILE* _fp) : fd(fileno(_fp)) {}\n ~Printer() { flush(); }\n\n int close() {\n flush();\n return ::close(fd);\n }\n\n void flush() {\n if (pos) {\n auto res = ::write(fd, line.data(), pos);\n assert(res != -1);\n pos = 0;\n }\n }\n\nprivate:\n static std::array<std::array<char, 2>, 100> small;\n static std::array<unsigned long long, 20> tens;\n\n static constexpr size_t SIZE = 1 << 15;\n int fd;\n std::array<char, SIZE> line;\n size_t pos = 0;\n std::stringstream ss;\n\n template <class T, std::enable_if_t<std::is_same<char, T>::value>* = nullptr>\n void write_single(const T& val) {\n if (pos == SIZE) flush();\n line[pos++] = val;\n }\n\n template <class T, internal::is_signed_int_t<T>* = nullptr,\n std::enable_if_t<!std::is_same<char, T>::value>* = nullptr>\n void write_single(const T& val) {\n using U = internal::to_unsigned_t<T>;\n if (val == 0) {\n write_single('0');\n return;\n }\n if (pos > SIZE - 50) flush();\n U uval = val;\n if (val < 0) {\n write_single('-');\n uval = -uval;\n }\n write_unsigned(uval);\n }\n\n template <class U, internal::is_unsigned_int_t<U>* = nullptr> void write_single(U uval) {\n if (uval == 0) {\n write_single('0');\n return;\n }\n if (pos > SIZE - 50) flush();\n\n write_unsigned(uval);\n }\n\n template <class U, internal::is_unsigned_int_t<U>* = nullptr> static int calc_len(U x) {\n int i = (bsr(x) * 3 + 3) / 10;\n if (x < tens[i])\n return i;\n else\n return i + 1;\n }\n\n template <class U, internal::is_unsigned_int_t<U>* = nullptr,\n std::enable_if_t<8 >= sizeof(U)>* = nullptr>\n void write_unsigned(U uval) {\n size_t len = calc_len(uval);\n pos += len;\n\n char* ptr = line.data() + pos;\n while (uval >= 100) {\n ptr -= 2;\n memcpy(ptr, small[uval % 100].data(), 2);\n uval /= 100;\n }\n if (uval >= 10) {\n memcpy(ptr - 2, small[uval].data(), 2);\n } else {\n *(ptr - 1) = char('0' + uval);\n }\n }\n\n template <class U, std::enable_if_t<internal::is_unsigned_int128<U>::value>* = nullptr>\n void write_unsigned(U uval) {\n static std::array<char, 50> buf;\n size_t len = 0;\n while (uval > 0) {\n buf[len++] = char((uval % 10) + '0');\n uval /= 10;\n }\n std::reverse(buf.begin(), buf.begin() + len);\n memcpy(line.data() + pos, buf.data(), len);\n pos += len;\n }\n\n void write_single(const std::string& s) {\n for (char c : s) write_single(c);\n }\n void write_single(const char* s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++) write_single(s[i]);\n }\n template <class T> void write_single(const std::vector<T>& val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) write_single(' ');\n write_single(val[i]);\n }\n }\n};\n\nstd::array<std::array<char, 2>, 100> Printer::small = [] {\n std::array<std::array<char, 2>, 100> table;\n for (int i = 0; i <= 99; i++) {\n table[i][1] = char('0' + (i % 10));\n table[i][0] = char('0' + (i / 10 % 10));\n }\n return table;\n}();\nstd::array<unsigned long long, 20> Printer::tens = [] {\n std::array<unsigned long long, 20> table;\n for (int i = 0; i < 20; i++) {\n table[i] = 1;\n for (int j = 0; j < i; j++) {\n table[i] *= 10;\n }\n }\n return table;\n}();\n\n} // namespace yosupo\nusing namespace yosupo;\n\n#include <algorithm>\n#include <array>\n#include <bitset>\n#include <cassert>\n#include <complex>\n#include <cstdio>\n#include <cstring>\n#include <iostream>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <string>\n#include <unordered_map>\n#include <unordered_set>\n#include <vector>\n\nusing namespace std;\n\nusing uint = unsigned int;\nusing ll = long long;\nusing ull = unsigned long long;\nconstexpr ll TEN(int n) {\n return (n == 0) ? 1 : 10 * TEN(n - 1);\n}\ntemplate <class T> using V = vector<T>;\ntemplate <class T> using VV = V<V<T>>;\n\n#ifdef LOCAL\n\nostream& operator<<(ostream& os, __int128_t x) {\n if (x < 0) {\n os << \"-\";\n x *= -1;\n }\n if (x == 0) {\n return os << \"0\";\n }\n string s;\n while (x) {\n s += char(x % 10 + '0');\n x /= 10;\n }\n reverse(s.begin(), s.end());\n return os << s;\n}\nostream& operator<<(ostream& os, __uint128_t x) {\n if (x == 0) {\n return os << \"0\";\n }\n string s;\n while (x) {\n s += char(x % 10 + '0');\n x /= 10;\n }\n reverse(s.begin(), s.end());\n return os << s;\n}\n\ntemplate <class T, class U> ostream& operator<<(ostream& os, const pair<T, U>& p);\ntemplate <class T> ostream& operator<<(ostream& os, const V<T>& v);\ntemplate <class T> ostream& operator<<(ostream& os, const deque<T>& v);\ntemplate <class T, size_t N> ostream& operator<<(ostream& os, const array<T, N>& a);\ntemplate <class T> ostream& operator<<(ostream& os, const set<T>& s);\ntemplate <class T, class U> ostream& operator<<(ostream& os, const map<T, U>& m);\n\ntemplate <class T, class U> ostream& operator<<(ostream& os, const pair<T, U>& p) {\n return os << \"P(\" << p.first << \",\" << p.second << \")\";\n}\n\ntemplate <class T> ostream& operator<<(ostream& os, const V<T>& v) {\n os << \"[\";\n bool f = false;\n for (auto d : v) {\n if (f) os << \",\";\n f = true;\n os << d;\n }\n return os << \"]\";\n}\n\ntemplate <class T> ostream& operator<<(ostream& os, const deque<T>& v) {\n os << \"[\";\n bool f = false;\n for (auto d : v) {\n if (f) os << \",\";\n f = true;\n os << d;\n }\n return os << \"]\";\n}\ntemplate <class T, size_t N> ostream& operator<<(ostream& os, const array<T, N>& a) {\n os << \"[\";\n bool f = false;\n for (auto d : a) {\n if (f) os << \",\";\n f = true;\n os << d;\n }\n return os << \"]\";\n}\n\ntemplate <class T> ostream& operator<<(ostream& os, const set<T>& s) {\n os << \"{\";\n bool f = false;\n for (auto d : s) {\n if (f) os << \",\";\n f = true;\n os << d;\n }\n return os << \"}\";\n}\n\ntemplate <class T, class U> ostream& operator<<(ostream& os, const map<T, U>& s) {\n os << \"{\";\n bool f = false;\n for (auto p : s) {\n if (f) os << \",\";\n f = true;\n os << p.first << \": \" << p.second;\n }\n return os << \"}\";\n}\n\nstruct PrettyOS {\n ostream& os;\n bool first;\n\n template <class T> auto operator<<(T&& x) {\n if (!first) os << \",\";\n first = false;\n os << x;\n return *this;\n }\n};\ntemplate <class... T> void dbg0(T&&... t) {\n (PrettyOS{cerr, true} << ... << t);\n}\n#define dbg(...) \\\n do { \\\n cerr << __LINE__ << \": \" << #__VA_ARGS__ << \" = \"; \\\n dbg0(__VA_ARGS__); \\\n cerr << endl; \\\n } while (false);\n#else\n#define dbg(...)\n#endif\n\nScanner sc = Scanner(stdin);\nPrinter pr = Printer(stdout);\n\n/**\n * サイコロ。6面あって、各面には数字が書かれている。\n * 転がすことができる。\n * 0: up, 1: front, 2: right, 3: left, 4: back, 5: down\n */\nstruct Dice {\n // 0: up, 1: front, 2: right, 3: left, 4: back, 5: down\n // 0: U, 1: F , 2: R, 3: L, 4: B, 5: D\n array<int, 6> num;\n Dice() { num = array<int, 6>{1, 2, 3, 4, 5, 6}; }\n Dice(const array<int, 6>& num) : num(num) {}\n // dice を up から見て、 North、East、West、South を考える\n // N\n // W d E\n // S\n void rollN() { roll_y_left_hand(); }\n void rollE() { roll_x_left_hand(); }\n void rollW() { roll_x_right_hand(); }\n void rollS() { roll_y_right_hand(); }\n\n void roll_x_right_hand() { roll(0, 3, 5, 2); }\n void roll_y_right_hand() { roll(0, 1, 5, 4); }\n void roll_z_right_hand() { roll(1, 2, 4, 3); }\n void roll_x_left_hand() { roll(0, 2, 5, 3); }\n void roll_y_left_hand() { roll(0, 4, 5, 1); }\n void roll_z_left_hand() { roll(1, 3, 4, 2); }\n\n // 6面サイコロを回転させるとき二つの面は変わらない\n // 3次元の軸に対して右回りの数列を渡すと右回りに回す\n // 例:roll_y\n // {0, 1, 5, 4} -> {0, 1, 4, 5} -> {0, 4, 1, 5} ->{4, 0, 1, 5}\n // 左回りの数列を渡すと左回りに回す\n // 例:roll_x\n // {0, 2, 5, 3} -> {3, 0, 2, 5}\n void roll(int i, int j, int k, int l) {\n swap(num[k], num[l]);\n swap(num[j], num[k]);\n swap(num[i], num[j]);\n }\n\n void roll(char c) {\n if (c == 'N') {\n rollN();\n return;\n }\n if (c == 'E') {\n rollE();\n return;\n }\n if (c == 'W') {\n rollW();\n return;\n }\n if (c == 'S') {\n rollS();\n return;\n }\n cerr << \"回転失敗!\\n\";\n }\n\n int operator[](char c) {\n string s = \"UFRLBD\";\n for (size_t i = 0; i < 6; ++i)\n if (s[i] == c) return num[i];\n return -1;\n }\n\n bool operator==(Dice rhs) {\n if (num == rhs.num) return true;\n return false;\n }\n\n // 回転も含めてサイコロが同一か判定\n bool is_same(Dice other) {\n for (int i = 0; i < 6; ++i) {\n for (int j = 0; j < 4; ++j) {\n if (*this == other) {\n return true;\n }\n other.roll_z_right_hand();\n }\n if (i % 2 == 0) {\n other.roll_x_right_hand();\n } else {\n other.roll_y_right_hand();\n }\n }\n return false;\n }\n};\n\nconst pair<int, int> dxy[] = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};\n\nint main() {\n int n;\n cin >> n;\n\n Dice criteria = Dice(array<int, 6>{1, 2, 3, 4, 5, 6});\n Dice zero = Dice(array<int, 6>{0, 0, 0, 0, 0, 0});\n\n map<pair<int, int>, char> mp;\n mp[{1, 0}] = 'S';\n mp[{0, 1}] = 'E';\n mp[{-1, 0}] = 'N';\n mp[{0, -1}] = 'W';\n\n map<pair<int, int>, char> mp2;\n mp2[{1, 0}] = 'F';\n mp2[{0, 1}] = 'R';\n mp2[{-1, 0}] = 'B';\n mp2[{0, -1}] = 'L';\n\n while (n != 0) {\n int u, f;\n V<VV<Dice>> dspace(2 * n + 1, VV<Dice>(2 * n + 1, V<Dice>(n + 5, zero)));\n VV<int> height(2 * n + 1, V<int>(2 * n + 1));\n\n // 転がせられるなら落とせる座標を返す\n // 転がせないなら-1,-1を返す\n auto isRollable = [&](Dice& dice, int x, int y) -> pair<int, int> {\n // 4近傍との高さに2以上の差がある かつ 転がる方向の面が4以上\n int rex = -1, rey = -1;\n int maxn = 3;\n for (auto [dx, dy] : dxy) {\n if (height[x][y] - height[x + dx][y + dy] > 1 && dice[mp2[{dx, dy}]] > maxn) {\n rex = dx;\n rey = dy;\n maxn = dice[mp2[{dx, dy}]];\n }\n }\n if (maxn != 3) {\n dice.roll(mp[{rex, rey}]);\n rex = x + rex;\n rey = y + rey;\n }\n return {rex, rey};\n };\n\n auto fallDice = [&](auto self, Dice& dice, int x, int y) -> void {\n dspace[x][y][height[x][y]] = dice;\n height[x][y]++;\n auto [newx, newy] = isRollable(dice, x, y);\n if (newx != -1 && newy != -1) {\n height[x][y]--;\n dspace[x][y][height[x][y]] = zero;\n self(self, dice, newx, newy);\n }\n };\n\n for (int i = 0; i < n; i++) {\n cin >> u >> f;\n array<int, 6> num = {u, f, 0, 0, 7 - f, 7 - u};\n\n int k = 0;\n for (int j = 1; j <= 6; ++j)\n if (j != u && j != f && j != 7 - u && j != 7 - f) {\n k = j;\n break;\n }\n num[2] = k;\n num[3] = 7 - k;\n\n Dice dice = Dice(num);\n if (!dice.is_same(criteria)) swap(dice.num[2], dice.num[3]);\n\n // dice を落とす\n // 転がるか判定 → 転がるならまた落とす\n fallDice(fallDice, dice, n, n);\n }\n V<int> ans(6);\n for (int i = 0; i < 2 * n + 1; i++) {\n for (int j = 0; j < 2 * n + 1; j++) {\n if (height[i][j] > 0) {\n ans[dspace[i][j][height[i][j] - 1].num[0] - 1]++;\n }\n }\n }\n pr.writeln(ans);\n\n cin >> n;\n }\n}", "accuracy": 1, "time_ms": 830, "memory_kb": 104256, "score_of_the_acc": -1.1414, "final_rank": 19 }, { "submission_id": "aoj_1181_6000705", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n\nstruct dice {\n vector<ll> n;\n dice(vector<ll> n = {1, 2, 3, 5, 4, 6}) : n(n) {}\n ll num() { return n[0]; }\n void rotate_left() { rotate(n.begin() + 1, n.begin() + 2, n.end() - 1); }\n void rotate_right() { rep(i, 3) rotate_left(); }\n void rotate_north() {\n swap(n[0], n[2]);\n swap(n[2], n[5]);\n swap(n[5], n[4]);\n }\n void rotate_east() {\n swap(n[0], n[3]);\n swap(n[3], n[5]);\n swap(n[5], n[1]);\n }\n void rotate_south() { rep(i, 3) rotate_north(); }\n void rotate_west() { rep(i, 3) rotate_east(); }\n};\n\nint main() {\n int n;\n while (cin >> n, n) {\n int a[201][201], b[201][201];\n rep(i, 201) rep(j, 201) a[i][j] = b[i][j] = 0;\n\n int t, f;\n rep(i, n) {\n cin >> t >> f;\n\n dice d;\n if (t == 2) d.rotate_west();\n if (t == 3) d.rotate_north();\n if (t == 4) d.rotate_south();\n if (t == 5) d.rotate_east();\n if (t == 6) d.rotate_north(), d.rotate_north();\n\n while (d.n[1] != f) d.rotate_left();\n\n int x = 100, y = 100;\n\n while (true) {\n vector<int> can;\n if (d.n[1] > 3 && a[x][y - 1] < a[x][y]) can.push_back(d.n[1]);\n if (d.n[2] > 3 && a[x + 1][y] < a[x][y]) can.push_back(d.n[2]);\n if (d.n[3] > 3 && a[x][y + 1] < a[x][y]) can.push_back(d.n[3]);\n if (d.n[4] > 3 && a[x - 1][y] < a[x][y]) can.push_back(d.n[4]);\n\n if (can.empty()) {\n a[x][y]++;\n b[x][y] = d.num();\n break;\n }\n\n sort(can.begin(), can.end());\n int c = can.back();\n\n if (d.n[1] == c) y--, d.rotate_east();\n if (d.n[2] == c) x++, d.rotate_south();\n if (d.n[3] == c) y++, d.rotate_west();\n if (d.n[4] == c) x--, d.rotate_north();\n }\n }\n\n int cnt[6] = {};\n rep(i, 201) rep(j, 201) cnt[b[i][j] - 1]++;\n rep(i, 6) cout << cnt[i] << (i == 5 ? '\\n' : ' ');\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3680, "score_of_the_acc": -0.0021, "final_rank": 2 } ]
aoj_1185_cpp
Patisserie ACM Amber Claes Maes, a patissier, opened her own shop last month. She decided to submit her work to the International Chocolate Patissier Competition to promote her shop, and she was pursuing a recipe of sweet chocolate bars. After thousands of trials, she finally reached the recipe. However, the recipe required high skill levels to form chocolate to an orderly rectangular shape. Sadly, she has just made another strange-shaped chocolate bar as shown in Figure G-1. Figure G-1: A strange-shaped chocolate bar Each chocolate bar consists of many small rectangular segments of chocolate. Adjacent segments are separated with a groove in between them for ease of snapping. She planned to cut the strange-shaped chocolate bars into several rectangular pieces and sell them in her shop. She wants to cut each chocolate bar as follows. The bar must be cut along grooves. The bar must be cut into rectangular pieces. The bar must be cut into as few pieces as possible. Following the rules, Figure G-2 can be an instance of cutting of the chocolate bar shown in Figure G-1. Figures G-3 and G-4 do not meet the rules; Figure G-3 has a non-rectangular piece, and Figure G-4 has more pieces than Figure G-2. Figure G-2: An instance of cutting that follows the rules Figure G-3: An instance of cutting that leaves a non-rectangular piece Figure G-4: An instance of cutting that yields more pieces than Figure G-2 Your job is to write a program that computes the number of pieces of chocolate after cutting according to the rules. Input The input is a sequence of datasets. The end of the input is indicated by a line containing two zeros separated by a space. Each dataset is formatted as follows. h w r (1, 1) ... r (1, w ) r (2, 1) ... r (2, w ) ... r ( h , 1) ... r ( h , w ) The integers h and w are the lengths of the two orthogonal dimensions of the chocolate, in number of segments. You may assume that 2 ≤ h ≤ 100 and 2 ≤ w ≤ 100. Each of the following h lines consists of w characters, each is either a " . " or a " # ". The character r ( i , j ) represents whether the chocolate segment exists at the position ( i , j ) as follows. " . ": There is no chocolate. " # ": There is a segment of chocolate. You can assume that there is no dataset that represents either multiple disconnected bars as depicted in Figure G-5 or a bar in a shape with hole(s) as depicted in Figure G-6 and G-7. You can also assume that there is at least one " # " character in each dataset. Figure G-5: Disconnected chocolate bars Figure G-6: A chocolate bar with a hole Figure G-7: Another instance of a chocolate bar with a hole Output For each dataset, output a line containing the integer representing the number of chocolate pieces obtained by cutting according to the rules. No other characters are allowed in the output. Sample Input 3 5 ###.# ##### ###.. 4 5 .#.## .#### ####. ##.#. 8 8 .#.#.#.# ######## .######. ######## .######. ######## .######. ######## 8 8 .#.#.#.# ######## .##.#.#. ##... ...(truncated)
[ { "submission_id": "aoj_1185_10882539", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct Bimatch{\n vector<vector<int>> g;\n vector<int> d, mc, used, vv;\n Bimatch(int n, int m): g(n), mc(m, -1), used(n){\n }\n void add(int u, int v){\n g[u].push_back(v);\n }\n void bfs(){\n d.assign(g.size(), -1);\n queue<int> q;\n for (int i = 0; i < g.size(); i++){\n if (!used[i]){\n q.push(i);\n d[i] = 0;\n }\n }\n while (!q.empty()){\n int x = q.front();\n q.pop();\n for (int e : g[x]){\n int c = mc[e];\n if (c >= 0 && d[c] == -1){\n d[c] = d[x] + 1;\n q.push(c);\n }\n }\n }\n }\n bool dfs(int x){\n vv[x] = true;\n for (int e : g[x]){\n int c = mc[e];\n if (c < 0 || (!vv[c] && d[c] == d[x] + 1 && dfs(c))){\n mc[e] = x;\n used[x] = true;\n return true;\n }\n }\n return false;\n }\n int match(){\n int ret = 0;\n while (true){\n bfs();\n vv.assign(g.size(), false);\n int f = 0;\n for (int i = 0; i < g.size(); i++){\n if (!used[i] && dfs(i)){\n f++;\n }\n }\n if (!f){\n return ret;\n }\n ret += f;\n }\n }\n};\nint main(){\n while (true){\n int h, w;\n cin >> h >> w;\n if (h == 0 && w == 0){\n break;\n }\n vector<vector<char>> r(h, vector<char>(w));\n for (int i = 0; i < h; i++){\n for (int j = 0; j < w; j++){\n cin >> r[i][j];\n }\n }\n int add = 0;\n for (int i = 0; i < h; i++){\n for (int j = 0; j < w; j++){\n if (r[i][j] == '#'){\n add++;\n }\n if (i < h - 1){\n if (r[i][j] == '#' && r[i + 1][j] == '#'){\n add--;\n }\n }\n if (j < w - 1){\n if (r[i][j] == '#' && r[i][j + 1] == '#'){\n add--;\n }\n }\n if (i < h - 1 && j < w - 1){\n if (r[i][j] == '#' && r[i][j + 1] == '#' && r[i + 1][j] == '#' && r[i + 1][j + 1] == '#'){\n add++;\n }\n }\n }\n }\n int ans = add;\n vector<int> X, Y;\n int V = 0;\n for (int i = 0; i < h - 1; i++){\n for (int j = 0; j < w - 1; j++){\n if ((r[i][j] == '#') + (r[i + 1][j] == '#') + (r[i][j + 1] == '#') + (r[i + 1][j + 1] == '#') == 3){\n X.push_back(i);\n Y.push_back(j);\n V++;\n }\n }\n }\n ans += V;\n vector<vector<int>> sum(h + 1, vector<int>(w + 1, 0));\n for (int i = 0; i < h; i++){\n for (int j = 0; j < w; j++){\n sum[i + 1][j + 1] = (r[i][j] == '.');\n }\n }\n for (int i = 1; i <= h; i++){\n for (int j = 1; j <= w; j++){\n sum[i][j] += sum[i - 1][j];\n }\n }\n for (int i = 1; i <= h; i++){\n for (int j = 1; j <= w; j++){\n sum[i][j] += sum[i][j - 1];\n }\n }\n auto get_sum = [&](int x1, int x2, int y1, int y2){\n return sum[x2][y2] - sum[x2][y1] - sum[x1][y2] + sum[x1][y1];\n };\n vector<vector<int>> idx1(h - 1), idx2(w - 1);\n for (int i = 0; i < V; i++){\n idx1[X[i]].push_back(i);\n idx2[Y[i]].push_back(i);\n }\n vector<pair<int, int>> L, R;\n for (int i = 0; i < h - 1; i++){\n int cnt = idx1[i].size();\n for (int j = 0; j < cnt - 1; j++){\n if (get_sum(i, i + 2, Y[idx1[i][j]] + 1, Y[idx1[i][j + 1]] + 1) == 0){\n L.push_back(make_pair(idx1[i][j], idx1[i][j + 1]));\n }\n }\n }\n for (int i = 0; i < w - 1; i++){\n int cnt = idx2[i].size();\n for (int j = 0; j < cnt - 1; j++){\n if (get_sum(X[idx2[i][j]] + 1, X[idx2[i][j + 1]] + 1, i, i + 2) == 0){\n R.push_back(make_pair(idx2[i][j], idx2[i][j + 1]));\n }\n }\n }\n int cntL = L.size();\n int cntR = R.size();\n Bimatch G(cntL, cntR);\n ans -= cntL + cntR;\n for (int i = 0; i < cntL; i++){\n for (int j = 0; j < cntR; j++){\n if (X[R[j].first] <= X[L[i].first] && X[L[i].first] <= X[R[j].second] && Y[L[i].first] <= Y[R[j].first] && Y[R[j].first] <= Y[L[i].second]){\n G.add(i, j);\n }\n }\n }\n ans += G.match();\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3868, "score_of_the_acc": -0.0177, "final_rank": 2 }, { "submission_id": "aoj_1185_10853227", "code_snippet": "#include<cstring>\n#include<cstdio>\n#include<vector>\n#include<algorithm>\n\nusing namespace std;\n\nstruct point {\n\tint x,y;\n\tpoint(){}\n\tpoint(int a, int b) : x(a), y(b) {}\n}P[11111];\n\nstruct data {\n\tint a1,a2,t;\n\tdata(){}\n\tdata(int a, int b, int c) : a1(a), a2(b), t(c) {}\n};\n\nchar B[111][111];\nint a[111][111],b[111][111];\nint n,m,sz;\n\nvector<data> H,V;\nvector<int> adj[11111];\nbool seen[11111];\nint R[11111];\n\nbool bpm(int u) {\n\tfor(int i=0;i<adj[u].size();++i) {\n\t\tint v = adj[u][i];\n\t\tif(seen[v]) continue;\n\t\tseen[v] = 1;\n\t\tif(R[v]==-1 || bpm(R[v])) {\n\t\t\tR[v] = u;\n\t\t\treturn 1;\n\t\t}\n\t} return 0;\n}\n\nint match() {\n\tmemset(R,-1,sizeof(R));\n\tint ret = 0;\n\tfor(int u=0;u<H.size();++u) {\n\t\tfor(int v=0;v<V.size();++v) seen[v]=0;\n\t\tif(bpm(u)) ret++;\n\t} return ret;\n}\n\nint main() {\n//#ifdef LOCAL\n//\tfreopen(\"input.txt\",\"r\",stdin);\n//#endif\n\twhile(1) {\n\t\tscanf(\"%d%d\",&n,&m),sz=0;\n\t\tif(n==0&&m==0) break;\n\t\tmemset(a,0,sizeof(a)),memset(b,0,sizeof(b));\n\t\tH.clear(),V.clear();\n\t\tfor(int i=1;i<=n;++i) scanf(\"%s\",B[i]+1);\n\t\tfor(int i=1;i<=n;++i) for(int j=1;j<=m;++j)\n\t\t\ta[i][j] = a[i][j-1] + (B[i][j]=='#'),\n\t\t\tb[i][j] = b[i-1][j] + (B[i][j]=='#');\n\t\tfor(int i=1;i<n;++i) for(int j=1;j<m;++j) {\n\t\t\tint cnt = 0;\n\t\t\tfor(int di=0;di<2;++di) for(int dj=0;dj<2;++dj)\n\t\t\t\tcnt += (B[i+di][j+dj] == '#');\n\t\t\tif(cnt == 3) P[sz++] = point(i,j);\n\t\t}\n\n\t\tfor(int i=0;i<sz;++i) for(int j=i+1;j<sz;++j) {\n\t\t\tif(P[i].x == P[j].x && a[P[i].x][P[j].y]-a[P[i].x][P[i].y]==P[j].y-P[i].y\n\t\t\t\t&& a[P[i].x+1][P[j].y]-a[P[i].x+1][P[i].y]==P[j].y-P[i].y)\n\t\t\t\tH.push_back(data(P[i].y,P[j].y,P[i].x));\n\t\t\tif(P[i].y == P[j].y && b[P[j].x][P[i].y]-b[P[i].x][P[i].y]==P[j].x-P[i].x\n\t\t\t\t&& b[P[j].x][P[i].y+1]-b[P[i].x][P[i].y+1]==P[j].x-P[i].x)\n\t\t\t\tV.push_back(data(P[i].x,P[j].x,P[i].y));\n\t\t}\n\n\t\tfor(int i=0;i<H.size();++i) for(int j=0;j<V.size();++j) {\n\t\t\tint x=H[i].t,y=V[j].t;\n\t\t\tint x1=V[j].a1,x2=V[j].a2;\n\t\t\tint y1=H[i].a1,y2=H[i].a2;\n\t\t\tif(x1<=x&&x<=x2&&y1<=y&&y<=y2) adj[i].push_back(j);\n\t\t} printf(\"%d\\n\",1+sz-(H.size()+V.size()-match()));\n\n\t\tfor(int i=0;i<H.size();++i) adj[i].clear();\n\t}\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3756, "score_of_the_acc": -0.0482, "final_rank": 8 }, { "submission_id": "aoj_1185_9854876", "code_snippet": "#line 1 \"library/Template/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n#line 2 \"library/Utility/fastio.hpp\"\n#include <unistd.h>\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n#line 3 \"sol.cpp\"\n\n#line 2 \"library/Graph/maxflow.hpp\"\n\nstruct MaxFlow {\n struct Edge {\n int to, rev;\n ll cap;\n };\n int V;\n vector<vector<Edge>> G;\n vector<int> itr, level;\n using P = pair<int, int>;\n vector<P> es;\n\n public:\n MaxFlow() {}\n MaxFlow(int V) : V(V) {\n G.assign(V, vector<Edge>());\n }\n int add_vertex() {\n G.push_back(vector<Edge>());\n return V++;\n }\n void add_edge(int from, int to, ll cap) {\n int fid = SZ(G[from]), tid = SZ(G[to]);\n if (from == to)\n tid++;\n es.push_back({from, fid});\n G[from].push_back({to, tid, cap});\n G[to].push_back({from, fid, 0});\n }\n struct Type {\n int from, to;\n ll cap, recap;\n };\n Type get_edge(int i) {\n auto [from, pos] = es[i];\n auto e = G[from][pos];\n auto re = G[e.to][e.rev];\n return Type{from, e.to, e.cap, re.cap};\n }\n void bfs(int s) {\n level.assign(V, -1);\n queue<int> q;\n level[s] = 0;\n q.push(s);\n while (!q.empty()) {\n int v = q.front();\n q.pop();\n for (auto &e : G[v]) {\n if (e.cap > 0 && level[e.to] < 0) {\n level[e.to] = level[v] + 1;\n q.push(e.to);\n }\n }\n }\n }\n ll dfs(int v, int t, ll f) {\n if (v == t)\n return f;\n for (int &i = itr[v]; i < (int)G[v].size(); i++) {\n Edge &e = G[v][i];\n if (e.cap > 0 && level[v] < level[e.to]) {\n ll d = dfs(e.to, t, min(f, e.cap));\n if (d > 0) {\n e.cap -= d, G[e.to][e.rev].cap += d;\n return d;\n }\n }\n }\n return 0;\n }\n ll run(int s, int t) {\n ll ret = 0, f;\n while (bfs(s), level[t] >= 0) {\n itr.assign(V, 0);\n while ((f = dfs(s, t, INF)) > 0)\n ret += f;\n }\n return ret;\n }\n vector<int> cut() {\n vector<int> ret(V);\n rep(v, 0, V) if (level[v] < 0) ret[v] = 1;\n return ret;\n }\n};\n\n/**\n * @brief Maximum Flow\n */\n#line 5 \"sol.cpp\"\n\nint main() {\n for (;;) {\n int H, W;\n read(H, W);\n if (H == 0 and W == 0)\n break;\n vector<string> a(H);\n read(a);\n\n using P = pair<int, int>;\n using Q = pair<P, int>;\n vector<Q> vs;\n int ret = 1;\n rep(i, 0, H - 1) rep(j, 0, W - 1) {\n int cnt = 0;\n rep(k, 0, 2) rep(l, 0, 2) if (a[i + k][j + l] == '#') cnt++;\n if (cnt == 3) {\n ret++;\n rep(k, 0, 2) rep(l, 0, 2) if (a[i + k][j + l] == '.') {\n if (k == 0) {\n vs.push_back({{i, j}, 0});\n }\n if (l == 0) {\n vs.push_back({{i, j}, 1});\n }\n }\n }\n }\n\n int n = SZ(vs);\n MaxFlow mf(n + 2);\n int S = n, T = n + 1;\n\n // line, profit\n vector<int> L(n);\n rep(i, 0, n) {\n auto [xy1, dir1] = vs[i];\n auto [x1, y1] = xy1;\n if (dir1 == 0) {\n L[i] = 1;\n for (;;) {\n int x = x1 + L[i], y = y1;\n if (x >= H - 1)\n break;\n if (a[x + 1][y] == '.' or a[x + 1][y + 1] == '.')\n break;\n L[i]++;\n }\n if (x1 + L[i] < H - 1 and (a[x1 + L[i] + 1][y1] == '#' or\n a[x1 + L[i] + 1][y1 + 1] == '#')) {\n ret--;\n mf.add_edge(i, T, 1);\n }\n } else {\n L[i] = 1;\n for (;;) {\n int x = x1, y = y1 + L[i];\n if (y >= W - 1)\n break;\n if (a[x][y + 1] == '.' or a[x + 1][y + 1] == '.')\n break;\n L[i]++;\n }\n if (y1 + L[i] < W - 1 and (a[x1][y1 + L[i] + 1] == '#' or\n a[x1 + 1][y1 + L[i] + 1] == '#')) {\n ret--;\n mf.add_edge(S, i, 1);\n }\n }\n }\n\n // cross, touch\n rep(i, 0, n) {\n auto [xy1, dir1] = vs[i];\n auto [x1, y1] = xy1;\n if (dir1 == 0) {\n rep(j, 0, n) {\n auto [xy2, dir2] = vs[j];\n auto [x2, y2] = xy2;\n if (dir2 == 1) {\n if (x1 < x2 and x2 < x1 + L[i] and y2 < y1 and\n y1 < y2 + L[j]) {\n mf.add_edge(j, i, inf);\n continue;\n }\n bool touch = 0;\n if (x1 == x2 and y1 == y2)\n touch = 1;\n if (x1 + L[i] == x2 and y1 == y2)\n touch = 1;\n if (x1 == x2 and y1 == y2 + L[j])\n touch = 1;\n if (x1 + L[i] == x2 and y1 == y2 + L[j])\n touch = 1;\n if (touch) {\n mf.add_edge(j, i, 1);\n }\n }\n }\n }\n }\n\n show(ret);\n ret += mf.run(S, T);\n print(ret);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4460, "score_of_the_acc": -0.0874, "final_rank": 10 }, { "submission_id": "aoj_1185_8515984", "code_snippet": "#include <complex>\n#include <iomanip>\n#include <iostream>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <stack>\n#include <unordered_map>\n#include <unordered_set>\nusing namespace std;\n\n#define rep(i, n) for (int i = 0; i < (n); i++)\n#define per(i, n) for (int i = (n)-1; i >= 0; i--)\n#define rep2(i, l, r) for (int i = (l); i < (r); i++)\n#define per2(i, l, r) for (int i = (r)-1; i >= (l); i--)\n#define each(e, x) for (auto &e : x)\n#define sz(x) (int)x.size()\n#define all(x) begin(x), end(x)\n#define rall(x) rbegin(x), rend(x)\n#define eb emplace_back\n#define MM << ' ' <<\n#define TT template <typename T>\nusing ll = long long;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n\nTT bool chmin(T &x, T y) { return x > y ? (x = y, true) : false; }\nTT bool chmax(T &x, T y) { return x < y ? (x = y, true) : false; }\n\nTT void print(vector<T> v, T x = 0) {\n int n = sz(v);\n rep(i, n) cout << v[i] + x << (i == n - 1 ? '\\n' : ' ');\n if (n == 0) cout << '\\n';\n}\n\nTT void printn(vector<T> v, T x = 0) {\n int n = sz(v);\n rep(i, n) cout << v[i] + x << '\\n';\n}\n\nTT void rearrange(vector<T> &v) {\n sort(all(v));\n v.erase(unique(all(v)), end(v));\n}\n\nTT int lb(vector<T> &v, T x) { return lower_bound(all(v), x) - begin(v); }\nTT int ub(vector<T> &v, T x) { return upper_bound(all(v), x) - begin(v); }\n\nconst int inf = (1 << 30) - 1;\nconst ll INF = (1LL << 60) - 1;\n\nstruct io_setup {\n io_setup() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cout << fixed << setprecision(15);\n }\n} io_setup;\n\nstruct BipartiteMatching {\n vector<vector<int>> es;\n vector<int> d, match;\n vector<bool> used, used2;\n int n, m;\n\n BipartiteMatching(int n, int m) : es(n), d(n), match(m), used(n), used2(n), n(n), m(m) {}\n\n void add_edge(int u, int v) { es[u].eb(v); }\n\n void bfs() {\n fill(all(d), -1);\n queue<int> que;\n rep(i, n) {\n if (!used[i]) {\n que.emplace(i);\n d[i] = 0;\n }\n }\n while (!empty(que)) {\n int i = que.front();\n que.pop();\n each(e, es[i]) {\n int j = match[e];\n if (j != -1 && d[j] == -1) {\n que.emplace(j);\n d[j] = d[i] + 1;\n }\n }\n }\n }\n\n bool dfs(int i) {\n used2[i] = true;\n each(e, es[i]) {\n int j = match[e];\n if (j == -1 || (!used2[j] && d[j] == d[i] + 1 && dfs(j))) {\n match[e] = i;\n used[i] = true;\n return true;\n }\n }\n return false;\n }\n\n int solve() {\n fill(all(match), -1);\n fill(all(used), false);\n int ret = 0;\n while (true) {\n bfs();\n fill(all(used2), false);\n int f = 0;\n rep(i, n) {\n if (!used[i] && dfs(i)) f++;\n }\n if (f == 0) break;\n ret += f;\n }\n return ret;\n }\n};\n\nint main() {\n while (true) {\n int H, W;\n cin >> H >> W;\n\n if (H == 0) break;\n\n vector<string> S(H);\n rep(i, H) cin >> S[i];\n\n auto count = [&](int i, int j) {\n int ret = 0;\n rep2(k, i, i + 2) rep2(l, j, j + 2) {\n if (S[k][l] == '#') ret++;\n }\n return ret;\n };\n\n vector<tuple<int, int, int>> yoko, tate;\n\n rep(i, H - 1) {\n int pre = -1;\n rep(j, W - 1) {\n if (count(i, j) == 3) {\n if (pre != -1) {\n if (S[i][pre + 1] == '#' && S[i + 1][pre + 1] == '#') {\n bool flag = true;\n rep2(k, pre + 1, j) {\n if (count(i, k) != 4) flag = false;\n }\n if (flag) yoko.eb(i, pre, j);\n }\n }\n pre = j;\n }\n }\n }\n\n rep(j, W - 1) {\n int pre = -1;\n rep(i, H - 1) {\n if (count(i, j) == 3) {\n if (pre != -1) {\n if (S[pre + 1][j] == '#' && S[pre + 1][j + 1] == '#') {\n bool flag = true;\n rep2(k, pre + 1, i) {\n if (count(k, j) != 4) flag = false;\n }\n if (flag) tate.eb(j, pre, i);\n }\n }\n pre = i;\n }\n }\n }\n\n auto intersect = [](tuple<int, int, int> yoko, tuple<int, int, int> tate) {\n auto [x, ly, ry] = yoko;\n auto [y, lx, rx] = tate;\n return (lx <= x && x <= rx && ly <= y && y <= ry);\n };\n\n int N = sz(yoko), M = sz(tate);\n\n BipartiteMatching G(N, M);\n rep(i, N) rep(j, M) {\n if (intersect(yoko[i], tate[j])) G.add_edge(i, j);\n }\n\n int pointNum = 0;\n rep(i, H - 1) rep(j, W - 1) {\n if (count(i, j) == 3) pointNum++;\n }\n\n int maxMatching = G.solve();\n int maxIndependentSet = N + M - maxMatching;\n\n cout << pointNum - maxIndependentSet + 1 << '\\n';\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3744, "score_of_the_acc": -0.0005, "final_rank": 1 }, { "submission_id": "aoj_1185_8337908", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, n) for (int i = 0; i < int(n); i++)\n#define per(i, n) for (int i = (n)-1; 0 <= i; i--)\n#define rep2(i, l, r) for (int i = (l); i < int(r); i++)\n#define per2(i, l, r) for (int i = (r)-1; int(l) <= i; i--)\n#define MM << \" \" <<\n#define pb push_back\n#define eb emplace_back\n#define all(x) begin(x), end(x)\n#define rall(x) rbegin(x), rend(x)\n// #define sz(x) (int)x.size()\n#define re(x) real(x)\n#define im(x) imag(x)\n\ntemplate<typename T>\nvoid print(const vector<T> &v) {\n int n = v.size();\n for (int i = 0; i < n; i++) cout << v[i] << (i == n - 1 ? '\\n' : ' ');\n if (v.empty()) cout << '\\n';\n}\n\ntemplate<class T>\nusing MaxHeap = priority_queue<T>;\ntemplate<class T>\nusing MinHeap = priority_queue<T, vector<T>, greater<T>>;\n\nusing ll = long long;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n\ntemplate<typename T>\nbool chmax(T &x, const T &y) {\n return (x < y) ? (x = y, true) : false;\n}\n\ntemplate<typename T>\nbool chmin(T &x, const T &y) {\n return (x > y) ? (x = y, true) : false;\n}\n\nint h, w;\nint dx[] = {0, -1, -1, 0};\nint dy[] = {0, 0, -1, -1};\n\nint sgn(int x) {\n return x == 0 ? 0 : (x < 0) ? -1 : 1; \n}\n\npair<int, set<pii>> sil(vector<string> a) {\n map<pii, vector<pii>> st;\n rep(i, h + 2) rep(j, w + 1) {\n if(a[i][j] != a[i][j + 1]) {\n pii s = {i, j + 1};\n pii t = {i + 1, j + 1};\n st[s].emplace_back(t);\n st[t].emplace_back(s);\n }\n }\n rep(i, h + 1) rep(j, w + 2) {\n if(a[i][j] != a[i + 1][j]) {\n pii s = {i + 1, j};\n pii t = {i + 1, j + 1};\n st[s].emplace_back(t);\n st[t].emplace_back(s);\n }\n }\n auto judge = [a](pii i) {\n auto [x, y] = i;\n int c = 0;\n for(auto &j : {0, -1}) for(auto &k : {0, -1}) {\n c += (a[x + j][y + k] == '#') ? 1 : 0;\n }\n return c == 3;\n };\n auto now = begin(st)->first;\n set<pii> used;\n vector<pii> crr;\n while(!used.count(now)) {\n used.insert(now);\n if(judge(now)) {\n crr.push_back(now);\n }\n for(auto &i : st[now]) {\n if(!used.count(i)) {\n now = i;\n break;\n }\n }\n }\n set<pii> res;\n map<pii, int> pp;\n rep(i, crr.size()) pp[crr[i]] = i;\n rep(i, crr.size()) {\n rep(j, 4) {\n auto [x, y] = crr[i];\n int s = j;\n int t = (j + 1) % 4;\n while(a[x + dx[s]][y + dy[s]] == '#' && a[x + dx[t]][y + dy[t]] == '#') {\n x += dx[s] + dx[t] + 1;\n y += dy[s] + dy[t] + 1;\n }\n if(pp.count({x, y})) {\n int tmp = pp[{x, y}];\n if(tmp < i) res.insert({tmp, i});\n }\n }\n }\n return {crr.size(), res};\n}\n\nint solve() {\n vector<string> a(h + 2);\n rep(i, h) cin >> a[i + 1];\n rep2(i, 1, h + 1) {\n a[i] = \".\" + a[i] + \".\";\n }\n rep(i, w + 2) {\n a[0] += \".\";\n a[h + 1] += \".\";\n }\n auto [n, p] = sil(a);\n // return n;\n vector<vector<int>> jud(n + 1, vector<int>());\n for(auto &i : p) {\n // jud[i.first].push_back(i.second);\n jud[i.second].push_back(i.first);\n }\n vector<vector<int>> dp(n + 1, vector<int>(n + 1, n * 3));\n per(i, n + 1) {\n dp[i][i] = 0;\n rep2(j, i + 1, n + 1) {\n for(auto &k : jud[j - 1]) {\n if(i <= k) chmin(dp[i][j], dp[i][k] + dp[k + 1][j - 1] + 1);\n }\n chmin(dp[i][j], dp[i][j - 1] + 1);\n chmin(dp[i][j], dp[i + 1][j] + 1);\n // if(2 <= j - i) {\n // if(jud[i][j - 1]) {\n // chmin(dp[i][j], dp[i + 1][j - 1] + 1);\n // }\n // }\n }\n }\n return dp[0][n] + 1;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n while(1) {\n cin >> h >> w;\n if(h == 0) break;\n cout << solve() << endl;\n }\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 97968, "score_of_the_acc": -1.4603, "final_rank": 20 }, { "submission_id": "aoj_1185_8012590", "code_snippet": "#include <algorithm>\n#include <bitset>\n#include <cassert>\n#include <cmath>\n#include <complex>\n#include <iomanip>\n#include <iostream>\n#include <limits>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <random>\n#include <set>\n#include <stack>\n#include <string>\n#include <tuple>\n#include <unordered_map>\n#include <unordered_set>\n#include <utility>\n#include <vector>\n\n#define rep(i, s, n) for (int i = (int)(s); i < (int)(n); i++)\n#define rrep(i, s, n) for (int i = (int)(n)-1; i >= (int)(s); i--)\n#define all(v) v.begin(), v.end()\n\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n\ntemplate <typename T> bool chmin(T &a, const T &b) {\n if (a <= b) return false;\n a = b;\n return true;\n}\ntemplate <typename T> bool chmax(T &a, const T &b) {\n if (a >= b) return false;\n a = b;\n return true;\n}\nusing namespace std;\n\ntemplate <typename fa> struct FordFulkerson {\n\tstruct edge{\n\t\tint to; fa cap; int rev; bool isrev;\n\t};\n\tconst fa INF;\n\tvector<vector<edge>> g;\n\tvector<int> used;\n\tint ts;\n\texplicit FordFulkerson(int v) : INF(numeric_limits<fa>::max()),g(v),used(v,-1),ts(0){}\n\tvoid add_edge(int from, int to, fa cap){\n\t\tg[from].push_back((edge){to,cap,(int)g[to].size(),false});\n\t\tg[to].push_back((edge){from,0,(int)g[from].size()-1,true});\n\t}\n\tfa dfs(int v, int t, fa flow){\n\t\tif(v==t)return flow;\n\t\tused[v] = ts;\n\t\tfor (auto &e: g[v]){\n\t\t\tif (e.cap>0&&used[e.to]!=ts){\n\t\t\t\tfa d=dfs(e.to,t,min(flow,e.cap));\n\t\t\t\tif(d>0){\n\t\t\t\t\te.cap-=d;\n\t\t\t\t\tg[e.to][e.rev].cap+=d;\n\t\t\t\t\treturn d;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn 0;\n\t}\n\tfa flow(int s, int t){\n\t\tfa ret = 0;\n\t\tfor (fa f; (f = dfs(s,t,INF))>0;ts++) ret+=f;\n\t\tts++;\n\t\treturn ret;\n\t}\n};\n\n\nvoid solve(int h, int w){\n\tvector c(h, vector<char>(w));\n\trep(i,0,h) rep(j,0,w) cin >> c[i][j];\n\t\n\tvector<pair<int,int>> points;\n\trep(i,0,h-1) rep(j,0,w-1){\n\t\tint cnt = 0;\n\t\trep(x,0,2) rep(y,0,2){\n\t\t\tif (c[i+x][j+y] == '#') cnt++;\n\t\t}\n\t\tif (cnt == 3){\n\t\t\tpoints.push_back(pair(i, j));\n\t\t}\n\t}\n\n\tint m = points.size();\n\t// taio\n\tvector<pair<int,int>> sets1;\n\tvector<pair<int,int>> sets2;\n\trep(i,0,m){\n\t\trep(j,i+1,m){\n\t\t\tif (points[i].first == points[j].first){\n\t\t\t\tint a = points[i].second;\n\t\t\t\tint b = points[j].second;\n\t\t\t\tint t = points[i].first;\n\t\t\t\tif (a > b) swap(a, b);\n\t\t\t\tbool mode = true;\n\t\t\t\trep(x,a+1,b+1){\n\t\t\t\t\tif (c[t][x] == '.' || c[t+1][x] == '.'){\n\t\t\t\t\t\tmode = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (mode){\n\t\t\t\t\tsets1.push_back(pair(i,j));\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (points[i].second == points[j].second){\n\t\t\t\tint a = points[i].first;\n\t\t\t\tint b = points[j].first;\n\t\t\t\tint t = points[i].second;\n\t\t\t\tif (a > b) swap(a, b);\n\t\t\t\tbool mode = true;\n\t\t\t\trep(x,a+1,b+1){\n\t\t\t\t\tif (c[x][t] == '.' || c[x][t+1] == '.'){\n\t\t\t\t\t\tmode = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (mode){\n\t\t\t\t\tsets2.push_back(pair(i,j));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint n1 = sets1.size();\n\tint n2 = sets2.size();\n\t//cout << n1 << \" \" << n2 << \" \" << m << endl;\n\n\tFordFulkerson<int> mf(n1+n2+2);\n\trep(i,0,n1){\n\t\trep(j,0,n2){\n\t\t\tset<int> r;\n\t\t\tint xt1 = points[sets1[i].first].second;\n\t\t\tint xt2 = points[sets1[i].second].second;\n\t\t\tint yv = points[sets1[i].first].first;\n\n\t\t\tif (xt1 > xt2) swap(xt1,xt2);\n\n\t\t\tint yt1 = points[sets2[j].first].first;\n\t\t\tint yt2 = points[sets2[j].second].first;\n\t\t\tint xv = points[sets2[j].first].second;\n\n\t\t\tif (yt1 > yt2) swap(yt1,yt2);\n\n\t\t\tif ((yt1 <= yv && yv <= yt2 && xt1 <= xv && xv <= xt2)){\n\t\t\t\tmf.add_edge(i, j+n1, 1);\n\t\t\t}\t\t\n\t\t}\n\t}\n\trep(i,0,n1){\n\t\tmf.add_edge(n1+n2, i, 1);\n\t}\n\trep(j,0,n2){\n\t\tmf.add_edge(j+n1, n1+n2+1, 1);\n\t}\n\t//cout << m << \" \" << n1 << \" \" << n2 << \" \" << \" \" << mf.flow(n1+n2, n1+n2+1) << endl;\n\tcout << m - n1 - n2 + mf.flow(n1+n2, n1+n2+1) + 1 << endl;\n}\n\nint main(){\n\twhile (true){\n\t\tint h, w; cin >> h >> w;\n\t\tif (h == 0 && w == 0) break;\n\t\tsolve(h, w);\n\t}\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3996, "score_of_the_acc": -0.1777, "final_rank": 14 }, { "submission_id": "aoj_1185_7221359", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nusing namespace std::chrono;\ntypedef long long int llint;\ntypedef long double lldo;\n#define mp make_pair\n#define mt make_tuple\n#define pub push_back\n#define puf push_front\n#define pob pop_back\n#define pof pop_front\n#define fir first\n#define sec second\n#define res resize\n#define ins insert\n#define era erase\n#define REP(i, n) for(int i = 0;i < (n);i++)\n/*cout<<fixed<<setprecision(20);cin.tie(0);ios::sync_with_stdio(false);*/\nconst int mod=1000000007;\nconst llint inf=2.19e7+1;\nconst long double pai=3.141592653589793238462643383279502884197;\nconst long double eps=1e-10;\ntemplate <class T,class U>bool chmin(T& a,U b){if(a>b){a=b;return true;}return false;}\ntemplate <class T,class U>bool chmax(T& a,U b){if(a<b){a=b;return true;}return false;}\nllint gcd(llint a,llint b){if(a%b==0){return b;}else return gcd(b,a%b);}\nllint lcm(llint a,llint b){if(a==0){return b;}return a/gcd(a,b)*b;}\ntemplate<class T> void SO(T& ve){sort(ve.begin(),ve.end());}\ntemplate<class T> void REV(T& ve){reverse(ve.begin(),ve.end());}\ntemplate<class T>int LBI(const vector<T>&ar,T in){return lower_bound(ar.begin(),ar.end(),in)-ar.begin();}\ntemplate<class T>int UBI(const vector<T>&ar,T in){return upper_bound(ar.begin(),ar.end(),in)-ar.begin();}\n\ntemplate<class T>using V=vector<T>;\ntemplate<class T>using VV=vector<vector<T>>;\nstruct E{int to,rev,cap;};\n\ntemplate<class C>\nstruct Maxflow{\n\tC flow;\n\tV<char>dual;\n};\n\ntemplate<class C>\nstruct MFExec{\n\tVV<E>& g;\n\tint s,t;\n\tV<int>level,iter;\n\tC dfs(int v,C f){\n\t\tif(v==t){return f;}\n\t\tC res=0;\n\t\tfor(int& i=iter[v];i<int(g[v].size());i++){\n\t\t\tE& e=g[v][i];\n\t\t\tif(e.cap<=0||level[v]>=level[e.to]){continue;}\n\t\t\tC d=dfs(e.to,min(f,e.cap));\n\t\t\te.cap-=d;\n\t\t\tg[e.to][e.rev].cap+=d;\n\t\t\tres+=d;\n\t\t\tf-=d;\n\t\t\tif(f==0){break;}\n\t\t}\n\t\treturn res;\n\t}\n\tMaxflow<C>info;\n\tMFExec(VV<E>&_g,int _s,int _t):g(_g),s(_s),t(_t){\n\t\tint N=int(g.size());\n\t\t\n\t\tinfo.flow=0;\n\t\tC& flow=info.flow;\n\t\twhile(1){\n\t\t\tqueue<int>que;\n\t\t\tlevel=V<int>(N,-1);\n\t\t\tlevel[s]=0;\n\t\t\tque.push(s);\n\t\t\twhile(!que.empty()){\n\t\t\t\tint v=que.front();\n\t\t\t\tque.pop();\n\t\t\t\tfor(E e:g[v]){\n\t\t\t\t\tif(e.cap<=0||level[e.to]>=0){continue;}\n\t\t\t\t\tlevel[e.to]=level[v]+1;\n\t\t\t\t\tque.push(e.to);\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(level[t]==-1){break;}\n\t\t\titer=V<int>(N,0);\n\t\t\twhile(1){\n\t\t\t\tC f=dfs(s,inf);\n\t\t\t\tif(!f){break;}\n\t\t\t\tflow+=f;\n\t\t\t}\n\t\t}\n\t}\n};\n\nvoid add_edge(VV<E>&in,int A,int B,int C){\n\tin[A].push_back(E{B,int(in[B].size()),C});\n\tin[B].push_back(E{A,int(in[A].size())-1,0});\n}\nint main(void){\n\t/*\n\tA,B 異なるときにコスト\n\t*/\n\twhile(-1){\n\t\t//ACM 洋菓子店 つくりかけ フローで解くべき\n\t\tint h,w,i,j;cin>>h>>w;\n\t\tif(h==0){break;}\n\t\tvector<string>mat(h+2);\n\t\tmat[0]=string(w+2,'.');\n\t\tmat[h+1]=string(w+2,'.');\n\t\tfor(i=1;i<=h;i++){\n\t\t\tcin>>mat[i];\n\t\t\tmat[i].insert(mat[i].begin(),'.');\n\t\t\tmat[i].pub('.');\n\t\t}\n\t\tVV<E> gra((h+1)*(w+1)*2+2);\n\t\t//横、縦の順\n\t\tint S=(h+1)*(w+1)*2,T=(h+1)*(w+1)*2+1;\n\t\tint ans=0;\n\t\tfor(i=0;i<=h;i++){\n\t\t\tfor(j=0;j<=w;j++){\n\t\t\t\tint X=(i*(w+1)+j)*2;\n\t\t\t\tif(mat[i][j+1]=='#'&&mat[i+1][j+1]=='#'){//次と連結する\n\t\t\t\t\tadd_edge(gra,X,X+2,2);\n\t\t\t\t\tadd_edge(gra,X+2,X,2);\n\t\t\t\t}\n\t\t\t\tif(mat[i+1][j]=='#'&&mat[i+1][j+1]=='#'){//次と連結する\n\t\t\t\t\tadd_edge(gra,X+1,X+1+(w+1)*2,2);\n\t\t\t\t\tadd_edge(gra,X+1+(w+1)*2,X+1,2);\n\t\t\t\t}\n\t\t\t\tif(mat[i][j]=='.'&&mat[i+1][j]=='.'){\n\t\t\t\t\tadd_edge(gra,X,T,2);\n\t\t\t\t}\n\t\t\t\tif(mat[i][j+1]=='.'&&mat[i+1][j+1]=='.'){\n\t\t\t\t\tadd_edge(gra,X,T,2);\n\t\t\t\t}\n\t\t\t\t\n\t\t\t\tif(mat[i][j]=='.'&&mat[i][j+1]=='.'){\n\t\t\t\t\tadd_edge(gra,S,X+1,2);\n\t\t\t\t}\n\t\t\t\tif(mat[i+1][j]=='.'&&mat[i+1][j+1]=='.'){\n\t\t\t\t\tadd_edge(gra,S,X+1,2);\n\t\t\t\t}\n\t\t\t\t\n\t\t\t\tadd_edge(gra,X,X+1,10);//両方はダメ\n\t\t\t\t\n\t\t\t\tint kaz=0;\n\t\t\t\tif(mat[i][j]=='#'){kaz++;}\n\t\t\t\tif(mat[i][j+1]=='#'){kaz++;}\n\t\t\t\tif(mat[i+1][j]=='#'){kaz++;}\n\t\t\t\tif(mat[i+1][j+1]=='#'){kaz++;}\n\t\t\t\tif(kaz==3){add_edge(gra,X+1,X,10);}//この角には必ずつける必要がある\n\t\t\t\tans+=kaz%2;\n\t\t\t}\n\t\t}\n\t\tMFExec<int> aaa=MFExec<int>(gra,S,T);\n\t\tcout<<(ans+aaa.info.flow)/4<<endl;\n\t}\n\treturn 0;\n}\n/*\n.#.##\n.####\n####.\n##.#.\n\n\n*/", "accuracy": 1, "time_ms": 370, "memory_kb": 6704, "score_of_the_acc": -0.5874, "final_rank": 17 }, { "submission_id": "aoj_1185_7168122", "code_snippet": "#include <iostream>\n#include <vector>\n#include <tuple>\n#include <algorithm>\nusing namespace std;\n\nstruct Edge {\n\tint to, cap, rev;\n};\n\nclass MaxFlow {\npublic:\n\tint size_ = 0;\n\tvector<Edge> G[10009];\n\tbool used[10009];\n\n\tvoid init(int sz) {\n\t\tsize_ = sz;\n\t\tfor (int i = 0; i < 10009; i++) G[i].clear();\n\t}\n\n\tvoid add_edge(int u, int v, int f) {\n\t\tG[u].push_back(Edge{ v, f, (int)G[v].size() });\n\t\tG[v].push_back(Edge{ u, 0, (int)G[u].size() - 1 });\n\t}\n\n\tint dfs(int pos, int goal, int f) {\n\t\tif (pos == goal) return f;\n\t\tused[pos] = true;\n\n\t\t// 辺を探索する\n\t\tfor (int i = 0; i < G[pos].size(); i++) {\n\t\t\tif (used[G[pos][i].to] == true || G[pos][i].cap == 0) continue;\n\t\t\tint F = dfs(G[pos][i].to, goal, min(f, G[pos][i].cap));\n\t\t\tif (F != 0) {\n\t\t\t\tG[pos][i].cap -= F;\n\t\t\t\tG[G[pos][i].to][G[pos][i].rev].cap += F;\n\t\t\t\treturn F;\n\t\t\t}\n\t\t}\n\n\t\t// 見つからなかった場合\n\t\treturn 0;\n\t}\n\n\tint max_flow(int s, int t) {\n\t\tint FLOW = 0;\n\t\twhile (true) {\n\t\t\tfor (int i = 0; i < size_; i++) used[i] = false;\n\t\t\tint f = dfs(s, t, 1000000007);\n\t\t\tif (f == 0) break;\n\t\t\tFLOW += f;\n\t\t}\n\t\treturn FLOW;\n\t}\n};\n\n// 入力\nint H, W;\nchar C[1009][1009];\n\n// フローなど\nMaxFlow Z;\nvector<tuple<int, int, int>> V1; // 縦\nvector<tuple<int, int, int>> V2; // 横\nint idx[1009][1009];\n\nint solve() {\n\t// 初期化\n\tV1.clear();\n\tV2.clear();\n\tfor (int i = 0; i < 109; i++) {\n\t\tfor (int j = 0; j < 109; j++) idx[i][j] = -1;\n\t}\n\n\t// 270 度を結ぶ線を探す(縦)\n\tfor (int i = 1; i <= H - 1; i++) {\n\t\tvector<int> vec;\n\t\tvec.push_back(0);\n\t\tfor (int j = 1; j <= W; j++) {\n\t\t\tint cnt = 0;\n\t\t\tif (C[i + 0][j] == '#') cnt += 1;\n\t\t\tif (C[i + 1][j] == '#') cnt += 1;\n\t\t\tvec.push_back(cnt);\n\t\t}\n\t\tvec.push_back(0);\n\n\t\t// 線を探す\n\t\tint Start = -1;\n\t\tfor (int j = 0; j < vec.size(); j++) {\n\t\t\tif (vec[j] == 2 && Start == -1) Start = j;\n\t\t\tif (vec[j] != 2 && Start != -1) {\n\t\t\t\tif (vec[Start - 1] == 1 && vec[j] == 1) {\n\t\t\t\t\tV1.push_back(make_tuple(i, Start - 1, j - 1));\n\t\t\t\t}\n\t\t\t\tStart = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\t// 270 度を結ぶ線を探す(横)\n\tfor (int j = 1; j <= W - 1; j++) {\n\t\tvector<int> vec;\n\t\tvec.push_back(0);\n\t\tfor (int i = 1; i <= H; i++) {\n\t\t\tint cnt = 0;\n\t\t\tif (C[i][j + 0] == '#') cnt += 1;\n\t\t\tif (C[i][j + 1] == '#') cnt += 1;\n\t\t\tvec.push_back(cnt);\n\t\t}\n\t\tvec.push_back(0);\n\n\t\t// 線を探す\n\t\tint Start = -1;\n\t\tfor (int i = 0; i < vec.size(); i++) {\n\t\t\tif (vec[i] == 2 && Start == -1) Start = i;\n\t\t\tif (vec[i] != 2 && Start != -1) {\n\t\t\t\tif (vec[Start - 1] == 1 && vec[i] == 1) {\n\t\t\t\t\tV2.push_back(make_tuple(j, Start - 1, i - 1));\n\t\t\t\t}\n\t\t\t\tStart = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\t// マッチングを求める(準備)\n\tint L1 = V1.size();\n\tint L2 = V2.size();\n\tZ.init(L1 + L2 + 3);\n\tfor (int i = 0; i < L2; i++) {\n\t\tfor (int j = get<1>(V2[i]); j <= get<2>(V2[i]); j++) idx[j][get<0>(V2[i])] = i;\n\t}\n\tfor (int i = 0; i < L1; i++) Z.add_edge(L1 + L2 + 0, i, 1);\n\tfor (int i = 0; i < L2; i++) Z.add_edge(L1 + i, L1 + L2 + 1, 1);\n\n\t// マッチングを求める\n\tfor (int i = 0; i < L1; i++) {\n\t\tfor (int j = get<1>(V1[i]); j <= get<2>(V1[i]); j++) {\n\t\t\tint val = idx[get<0>(V1[i])][j];\n\t\t\tif (val != -1) {\n\t\t\t\tZ.add_edge(i, L1 + val, 1);\n\t\t\t}\n\t\t}\n\t}\n\n\t// 最大フロー\n\tint Answer1 = Z.max_flow(L1 + L2 + 0, L1 + L2 + 1);\n\tint Answer2 = L1 + L2 - Answer1;\n\n\t// 答えを返す\n\tint Count270 = 0;\n\tfor (int i = 1; i <= H - 1; i++) {\n\t\tfor (int j = 1; j <= W - 1; j++) {\n\t\t\tint cnt = 0;\n\t\t\tif (C[i + 0][j + 0] == '#') cnt++;\n\t\t\tif (C[i + 0][j + 1] == '#') cnt++;\n\t\t\tif (C[i + 1][j + 0] == '#') cnt++;\n\t\t\tif (C[i + 1][j + 1] == '#') cnt++;\n\t\t\tif (cnt == 3) Count270 += 1;\n\t\t}\n\t}\n\treturn Count270 - Answer2 + 1;\n}\n\nint main() {\n\twhile (true) {\n\t\t// 入力\n\t\tcin >> H >> W; if (H == 0 && W == 0) break;\n\t\tfor (int i = 1; i <= H; i++) {\n\t\t\tfor (int j = 1; j <= W; j++) cin >> C[i][j];\n\t\t}\n\t\t\n\t\t// 出力\n\t\tint Answer = solve();\n\t\tcout << Answer << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 7592, "score_of_the_acc": -0.073, "final_rank": 9 }, { "submission_id": "aoj_1185_4952978", "code_snippet": "#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<ciso646>\n#include<random>\n#include<map>\n#include<set>\n#include<bitset>\n#include<stack>\n#include<unordered_map>\n#include<utility>\n#include<cassert>\n#include<complex>\n#include<numeric>\nusing namespace std;\n\n//#define int long long\ntypedef long long ll;\n\ntypedef unsigned long long ul;\ntypedef unsigned int ui;\nconstexpr ll mod = 1000000007;\nconst ll INF = mod * mod;\ntypedef pair<int, int>P;\n#define stop char nyaa;cin>>nyaa;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define per(i,n) for(int i=n-1;i>=0;i--)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define per1(i,n) for(int i=n;i>=1;i--)\n#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)\n#define all(v) (v).begin(),(v).end()\ntypedef pair<ll, ll> LP;\ntypedef double ld;\ntypedef pair<ld, ld> LDP;\nconst ld eps = 1e-12;\nconst ld pi = acos(-1.0);\n\nll mod_pow(ll x, ll n, ll m = mod) {\n\tll res = 1;\n\twhile (n) {\n\t\tif (n & 1)res = res * x % m;\n\t\tx = x * x % m; n >>= 1;\n\t}\n\treturn res;\n}\nstruct modint {\n\tll n;\n\tmodint() :n(0) { ; }\n\tmodint(ll m) :n(m) {\n\t\tif (n >= mod)n %= mod;\n\t\telse if (n < 0)n = (n % mod + mod) % mod;\n\t}\n\toperator int() { return n; }\n};\nbool operator==(modint a, modint b) { return a.n == b.n; }\nmodint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }\nmodint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }\nmodint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }\nmodint operator+(modint a, modint b) { return a += b; }\nmodint operator-(modint a, modint b) { return a -= b; }\nmodint operator*(modint a, modint b) { return a *= b; }\nmodint operator^(modint a, ll n) {\n\tif (n == 0)return modint(1);\n\tmodint res = (a * a) ^ (n / 2);\n\tif (n % 2)res = res * a;\n\treturn res;\n}\n\nll inv(ll a, ll p) {\n\treturn (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);\n}\nmodint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }\n\nconst int max_n = 1 << 20;\nmodint fact[max_n], factinv[max_n];\nvoid init_f() {\n\tfact[0] = modint(1);\n\tfor (int i = 0; i < max_n - 1; i++) {\n\t\tfact[i + 1] = fact[i] * modint(i + 1);\n\t}\n\tfactinv[max_n - 1] = modint(1) / fact[max_n - 1];\n\tfor (int i = max_n - 2; i >= 0; i--) {\n\t\tfactinv[i] = factinv[i + 1] * modint(i + 1);\n\t}\n}\nmodint comb(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[b] * factinv[a - b];\n}\n\nll gcd(ll a, ll b) {\n\tif (a < b)swap(a, b);\n\twhile (b) {\n\t\tll r = a % b; a = b; b = r;\n\t}\n\treturn a;\n}\n\n//x,yがax+by=gcd(a,b)の解になる\nll extgcd(ll a, ll b, ll& x, ll& y) {\n\tll d = a;\n\tif (b != 0) {\n\t\td = extgcd(b, a % b, y, x);\n\t\ty -= (a / b) * x;\n\t}\n\telse {\n\t\tx = 1; y = 0;\n\t}\n\treturn d;\n}\n//aのmod mでの逆元を求める\nll mod_inverse(ll a, ll m) {\n\tll x, y;\n\textgcd(a, m, x, y);\n\treturn (m + x % m) % m;\n}\n\n#include<cstring>\nstruct edge { int to, cap, rev; };\nvector<edge> G[100000];\nbool used[100000];\nvoid add_edge(int from, int to, int cap) {\n\t//cout << from << \" \" << to << \" \" << cap << \"\\n\";\n\tG[from].push_back(edge{ to, cap, (int)G[to].size() });\n\tG[to].push_back(edge{ from, 0, (int)G[from].size() - 1 });\n}\nint dfs(int v, int t, int f) {\n\tif (v == t)return f;\n\tused[v] = true;\n\tfor (int i = 0; i < (int)G[v].size(); i++) {\n\t\tedge& e = G[v][i];\n\t\tif (!used[e.to] && e.cap > 0) {\n\t\t\tint d = dfs(e.to, t, min(f, e.cap));\n\t\t\tif (d > 0) {\n\t\t\t\te.cap -= d;\n\t\t\t\tG[e.to][e.rev].cap += d;\n\t\t\t\treturn d;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\nint max_flow(int s, int t) {\n\tint flow = 0;\n\tfor (;;) {\n\t\tmemset(used, 0, sizeof(used));\n\t\tint f = dfs(s, t, mod);\n\t\tif (f == 0)return flow;\n\t\tflow += f;\n\t}\n}\n\nint h, w;\nvoid solve() {\n\tvector<string> s(h);\n\trep(i, h)cin >> s[i];\n\tmap<pair<P, P>, int> xt, yt;\n\tvector<P> ps;\n\trep(i, h - 1)rep(j, w - 1) {\n\t\tint cnt = 0;\n\t\trep(x, 2)rep(y, 2)if (s[i + x][j + y] == '#')cnt++;\n\t\tif (cnt == 3) {\n\t\t\tint d = 0;\n\t\t\trep(x, 2)rep(y, 2)if (s[i + x][j + y] != '#')d = 2 * x + y;\n\t\t\tint tx, ty;\n\t\t\tif (d % 2 == 0) {\n\t\t\t\tint cur = j + 1;\n\t\t\t\twhile (cur < w && s[i][cur] == '#' && s[i + 1][cur] == '#')cur++;\n\t\t\t\tcur--;\n\t\t\t\tpair<P, P> p = { {i,j},{i,cur} };\n\t\t\t\tif (xt.find(p) == xt.end()) {\n\t\t\t\t\txt[p] = xt.size();\n\t\t\t\t}\n\t\t\t\ttx = xt[p];\n\t\t\t}\n\t\t\telse {\n\t\t\t\tint cur = j;\n\t\t\t\twhile (cur >= 0 && s[i][cur] == '#' && s[i + 1][cur] == '#')cur--;\n\t\t\t\tpair<P, P> p = { {i,cur},{i,j} };\n\t\t\t\tif (xt.find(p) == xt.end())xt[p] = xt.size();\n\t\t\t\ttx = xt[p];\n\t\t\t}\n\t\t\tif (d < 2) {\n\t\t\t\tint cur = i + 1;\n\t\t\t\twhile (cur < h && s[cur][j] == '#' && s[cur][j + 1] == '#')cur++;\n\t\t\t\tcur--;\n\t\t\t\tpair<P, P> p = { {i,j},{cur,j} };\n\t\t\t\tif (yt.find(p) == yt.end())yt[p] = yt.size();\n\t\t\t\tty = yt[p];\n\t\t\t}\n\t\t\telse {\n\t\t\t\tint cur = i;\n\t\t\t\twhile (cur >= 0 && s[cur][j] == '#' && s[cur][j + 1] == '#')cur--;\n\t\t\t\tpair<P, P> p = { {cur,j},{i,j} };\n\t\t\t\tif (yt.find(p) == yt.end())yt[p] = yt.size();\n\t\t\t\tty = yt[p];\n\t\t\t}\n\t\t\tps.push_back({ tx,ty });\n\t\t}\n\t}\n\tint ss = xt.size() + yt.size();\n\tint tt = ss + 1;\n\trep(i, tt + 1)G[i].clear();\n\trep(i, xt.size()) {\n\t\tadd_edge(ss, i, 1);\n\t}\n\trep(i, yt.size()) {\n\t\tadd_edge(i + xt.size(), tt, 1);\n\t}\n\tfor (P p : ps) {\n\t\tadd_edge(p.first, p.second + xt.size(), 1);\n\t}\n\tfor (auto p1 : xt)for (auto p2 : yt) {\n\t\tpair<P, P> xp = p1.first, yp = p2.first;\n\t\tint zy = yp.first.second;\n\t\tbool valid = true;\n\t\tif (zy <= xp.first.second || xp.second.second <= zy)valid = false;\n\t\tint zx = xp.first.first;\n\t\tif (zx <= yp.first.first || yp.second.first <= zx)valid = false;\n\t\tif (valid) {\n\t\t\tadd_edge(p2.second + xt.size(), p1.second, 1);\n\t\t}\n\t}\n\tint ans = max_flow(ss, tt); ans++;\n\tcout << ans << \"\\n\";\n}\n\n\n\n\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\t//cout << fixed << setprecision(10);\n\t//init_f();\n\t//init();\n\t//expr();\n\t//int t; cin >> t; rep(i, t)\n\twhile (cin >> h >> w,h) {\n\t\tsolve();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 24932, "score_of_the_acc": -0.6538, "final_rank": 18 }, { "submission_id": "aoj_1185_4943447", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntemplate<typename flow_t>\nstruct Dinic{\n const flow_t INF;\n struct edge{\n int to;\n flow_t cap;\n int rev;\n bool isrev;\n int idx;\n };\n vector<vector<edge>>graph;\n vector<int>min_cost,iter;\n Dinic(int V):INF(numeric_limits<flow_t>::max()),graph(V){};\n void add_edge(int from,int to,flow_t cap,int idx=-1){\n // cout << \" \" << \"from \" << from << \", to \" << to << \", cap \" << cap << endl;\n graph[from].push_back({to,cap,(int)graph[to].size(),false,idx});\n graph[to].push_back({from,0,(int)graph[from].size()-1,true,idx});\n\n }\n bool bfs(int s,int t){\n min_cost.assign(graph.size(),-1);\n queue<int>que;\n min_cost[s]=0;\n que.push(s);\n while(!que.empty()&&min_cost[t]==-1){\n int p = que.front();\n que.pop();\n for(auto &e:graph[p]){\n if(e.cap>0&&min_cost[e.to]==-1){\n min_cost[e.to]=min_cost[p]+1;\n que.push(e.to);\n }\n }\n }\n return min_cost[t]!=-1;\n }\n flow_t dfs(int idx,const int t, flow_t flow){\n if(idx==t)return flow;\n for(int &i=iter[idx];i<graph[idx].size();i++){\n edge &e = graph[idx][i];\n if(e.cap>0&&min_cost[idx]<min_cost[e.to]){\n flow_t d = dfs(e.to,t,min(flow,e.cap));\n if(d>0){\n e.cap-=d;\n graph[e.to][e.rev].cap+=d;\n return d;\n }\n }\n }\n return 0;\n }\n flow_t max_flow(int s,int t){\n flow_t flow=0;\n while(bfs(s,t)){\n iter.assign(graph.size(),0);\n flow_t f = 0;\n while((f=dfs(s,t,INF))>0)flow+=f;\n\n }\n return flow;\n }\n};\n\nint h, w;\nvector<string> choco;\n\nbool input(void){\n cin >> h >> w;\n choco.resize(h);\n for (string& si : choco)\n cin >> si;\n return !(h == 0 && w == 0);\n}\n\nbool isNG(int x, int y){\n int cntChoco = 0;\n for (int dx = 0; dx <= 1; ++dx)\n for (int dy = 0; dy <= 1; ++dy)\n if (choco[x + dx][y + dy] == '#')\n ++cntChoco;\n return (cntChoco == 3);\n}\n\nbool canCut(int x1, int y1, int x2, int y2){\n if (y1 == y2){\n bool ret = true;\n for (int x = x1 + 1; x <= x2; ++x)\n ret = ret && (choco[x][y1] == '#' && choco[x][y1 + 1] == '#');\n return ret;\n }\n else if (x1 == x2){\n bool ret = true;\n for (int y = y1 + 1; y <= y2; ++y)\n ret = ret && (choco[x1][y] == '#' && choco[x1 + 1][y] == '#');\n return ret;\n }\n return false;\n}\n\nint NG[100][100];\nint constructNG(void){\n for (int i = 0; i < h - 1; ++i){\n for (int j = 0; j < w - 1; ++j){\n if (isNG(i, j)) NG[i][j] = 0;\n else NG[i][j] = -1;\n }\n }\n int tmp = 0;\n for (int i = 0; i < h - 1; ++i){\n for (int j = 0; j < w - 1; ++j){\n if (NG[i][j] >= 0)\n NG[i][j] = tmp++; // NGな点の頂点番号\n }\n }\n return tmp; // 頂点数\n}\n\nstruct Line{\n int x1, y1, x2, y2;\n Line() {}\n Line(int x1, int y1, int x2, int y2)\n : x1(x1), y1(y1), x2(x2), y2(y2) {}\n};\n\n// tate : y固定\n// yoko : x固定\nbool cross(Line& tate, Line& yoko){\n return (\n yoko.y1 <= tate.y1 && tate.y1 <= yoko.y2 &&\n tate.x1 <= yoko.x1 && tate.x2 >= yoko.x1\n );\n}\n\nvector<vector<int>> biG;\n\nint solve(void){\n int nNG = constructNG();\n if (nNG == 0) return 1;\n vector<Line> tate, yoko;\n for (int x = 0; x < h - 1; ++x){ // x固定でyを動かす\n vector<int> y_idx;\n for (int y = 0; y < w - 1; ++y)\n if (NG[x][y] >= 0)\n y_idx.push_back(y);\n for (int y1 : y_idx){\n for (int y2 : y_idx){\n if (y1 < y2){\n bool ok = canCut(x, y1, x, y2);\n if (ok){\n yoko.push_back(Line(x, y1, x, y2));\n }\n }\n }\n }\n }\n for (int y = 0; y < w - 1; ++y){ // y固定でxを動かす\n vector<int> x_idx;\n for (int x = 0; x < h - 1; ++x)\n if (NG[x][y] >= 0)\n x_idx.push_back(x);\n for (int x1 : x_idx){\n for (int x2 : x_idx){\n if (x1 < x2){\n bool ok = canCut(x1, y, x2, y);\n if (ok){\n tate.push_back(Line(x1, y, x2, y));\n }\n }\n }\n }\n }\n int line = tate.size() + yoko.size();\n int t = tate.size(), y = yoko.size();\n Dinic<int> d(line + 2);\n for (int i = 0; i < t; ++i)\n d.add_edge(0, i + 1, 1);\n for (int i = 0; i < y; ++i)\n d.add_edge(t + 1 + i, t + y + 1, 1);\n for (int i = 0; i < t; ++i){\n for (int j = 0; j < y; ++j){\n bool c = cross(tate[i], yoko[j]);\n if (c){\n d.add_edge(i + 1, t + 1 + j, 1);\n }\n }\n }\n int fl = d.max_flow(0, t + y + 1);\n int mis = line - fl;\n /* cout << \"line : \" << line << endl;\n cout << \"mis : \" << mis << endl;\n cout << \"nNG : \" << nNG << endl; */\n return (nNG - mis + 1);\n}\n\nint main(void){ \n while (input()){\n cout << solve() << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4536, "score_of_the_acc": -0.0247, "final_rank": 4 }, { "submission_id": "aoj_1185_4103609", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}\n\n\nstruct BiMatch{\n int n,time;\n vector<vector<int>> G;\n vector<int> match,used,dead;\n\n BiMatch(){}\n BiMatch(int n):n(n),time(0),G(n),\n match(n,-1),used(n,-1),dead(n,0){}\n\n void add_edge(int u,int v){\n G[u].emplace_back(v);\n G[v].emplace_back(u);\n }\n\n int dfs(int v){\n used[v]=time;\n for(int u:G[v]){\n if(dead[u]) continue;\n int w=match[u];\n if((w<0)||(used[w]<time&&dfs(w))){\n match[v]=u;\n match[u]=v;\n return 1;\n }\n }\n return 0;\n }\n\n int build(){\n int res=0;\n for(int v=0;v<n;v++){\n if(dead[v]) continue;\n if(match[v]<0){\n time++;\n res+=dfs(v);\n }\n }\n return res;\n }\n\n int disable(int v){\n assert(!dead[v]);\n int u=match[v];\n if(~u) match[u]=-1;\n match[v]=-1;\n dead[v]=1;\n time++;\n return ~u?dfs(u)-1:0;\n }\n\n int enable(int v){\n assert(dead[v]);\n dead[v]=0;\n time++;\n return dfs(v);\n }\n};\n\n//INSERT ABOVE HERE\nsigned main(){\n int h,w;\n while(cin>>h>>w,h){\n vector<string> st(h);\n for(int i=0;i<h;i++) cin>>st[i];\n using P = pair<int, int>;\n vector<P> vp;\n map<P, int> idx;\n\n vector<vector<int>> tp(h,vector<int>(w,-1));\n for(int i=0;i+1<h;i++){\n for(int j=0;j+1<w;j++){\n int num=0;\n for(int a=0;a<2;a++)\n for(int b=0;b<2;b++)\n num+=st[i+a][j+b]=='#';\n\n if(num==3){\n if(st[i+0][j+0]=='.') tp[i][j]=0;\n if(st[i+0][j+1]=='.') tp[i][j]=1;\n if(st[i+1][j+0]=='.') tp[i][j]=2;\n if(st[i+1][j+1]=='.') tp[i][j]=3;\n\n idx[P(i,j)]=vp.size();\n vp.emplace_back(i,j);\n }\n }\n }\n\n int n=vp.size();\n using P = pair<int, int>;\n vector<P> es;\n\n for(int i=0;i+1<h;i++){\n for(int j=0;j+1<w;j++){\n if(tp[i][j]<0) continue;\n if(tp[i][j]<2){\n for(int k=i+1;k+1<h;k++){\n if(tp[k][j]<0){\n if(st[k][j+0]=='#'&&st[k][j+1]=='#') continue;\n break;\n }\n if(tp[k][j]>=2)\n es.emplace_back(idx[P(i,j)],idx[P(k,j)]);\n break;\n }\n }\n if(tp[i][j]%2==0){\n for(int l=j+1;l+1<w;l++){\n if(tp[i][l]<0){\n if(st[i+0][l]=='#'&&st[i+1][l]=='#') continue;\n break;\n }\n if(tp[i][l]%2==1)\n es.emplace_back(idx[P(i,j)],idx[P(i,l)]);\n break;\n }\n }\n }\n }\n\n #define F first\n #define S second\n int m=es.size();\n BiMatch G(m);\n for(int i=0;i<m;i++){\n for(int j=0;j<m;j++){\n if(vp[es[i].F].F!=vp[es[i].S].F) continue;\n if(vp[es[j].F].S!=vp[es[j].S].S) continue;\n if(vp[es[j].F].S< vp[es[i].F].S) continue;\n if(vp[es[j].F].S> vp[es[i].S].S) continue;\n if(vp[es[i].F].F< vp[es[j].F].F) continue;\n if(vp[es[i].F].F> vp[es[j].S].F) continue;\n G.add_edge(i,j);\n // cout<<i<<\" \"<<j<<endl;\n }\n }\n\n cout<<n-(m-G.build())+1<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 3700, "score_of_the_acc": -0.2381, "final_rank": 15 }, { "submission_id": "aoj_1185_4003236", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll=long long;\n#define int ll\n\n#define rng(i,a,b) for(int i=int(a);i<int(b);i++)\n#define rep(i,b) rng(i,0,b)\n#define gnr(i,a,b) for(int i=int(b)-1;i>=int(a);i--)\n#define per(i,b) gnr(i,0,b)\n#define pb push_back\n#define eb emplace_back\n#define a first\n#define b second\n#define bg begin()\n#define ed end()\n#define all(x) x.bg,x.ed\n#ifdef LOCAL\n#define dmp(x) cerr<<__LINE__<<\" \"<<#x<<\" \"<<x<<endl\n#else\n#define dmp(x) void(0)\n#endif\n\ntemplate<class t,class u> void chmax(t&a,u b){if(a<b)a=b;}\ntemplate<class t,class u> void chmin(t&a,u b){if(b<a)a=b;}\n\ntemplate<class t> using vc=vector<t>;\ntemplate<class t> using vvc=vc<vc<t>>;\n\nusing pi=pair<int,int>;\nusing vi=vc<int>;\n\ntemplate<class t,class u>\nostream& operator<<(ostream& os,const pair<t,u>& p){\n\treturn os<<\"{\"<<p.a<<\",\"<<p.b<<\"}\";\n}\n\ntemplate<class t> ostream& operator<<(ostream& os,const vc<t>& v){\n\tos<<\"{\";\n\tfor(auto e:v)os<<e<<\",\";\n\treturn os<<\"}\";\n}\n\n#define mp make_pair\n#define mt make_tuple\n#define one(x) memset(x,-1,sizeof(x))\n#define zero(x) memset(x,0,sizeof(x))\n#ifdef LOCAL\nvoid dmpr(ostream&os){os<<endl;}\ntemplate<class T,class... Args>\nvoid dmpr(ostream&os,const T&t,const Args&... args){\n\tos<<t<<\" \";\n\tdmpr(os,args...);\n}\n#define dmp2(...) dmpr(cerr,\"Line:\",__LINE__,##__VA_ARGS__)\n#else\n#define dmp2(...) void(0)\n#endif\n\nusing uint=unsigned;\nusing ull=unsigned long long;\n\ntemplate<int i,class T>\nvoid print_tuple(ostream&,const T&){\n}\n\ntemplate<int i,class T,class H,class ...Args>\nvoid print_tuple(ostream&os,const T&t){\n\tif(i)os<<\",\";\n\tos<<get<i>(t);\n\tprint_tuple<i+1,T,Args...>(os,t);\n}\n\ntemplate<class ...Args>\nostream& operator<<(ostream&os,const tuple<Args...>&t){\n\tos<<\"{\";\n\tprint_tuple<0,tuple<Args...>,Args...>(os,t);\n\treturn os<<\"}\";\n}\n\nvoid print(ll x,int suc=1){\n\tcout<<x;\n\tif(suc==1)\n\t\tcout<<\"\\n\";\n\tif(suc==2)\n\t\tcout<<\" \";\n}\n\nll read(){\n\tll i;\n\tcin>>i;\n\treturn i;\n}\n\nvi readvi(int n,int off=0){\n\tvi v(n);\n\trep(i,n)v[i]=read()+off;\n\treturn v;\n}\n\ntemplate<class T>\nvoid print(const vector<T>&v,int suc=1){\n\trep(i,v.size())\n\t\tprint(v[i],i==int(v.size())-1?suc:2);\n}\n\nstring readString(){\n\tstring s;\n\tcin>>s;\n\treturn s;\n}\n\ntemplate<class T>\nT sq(const T& t){\n\treturn t*t;\n}\n\n//#define CAPITAL\nvoid yes(bool ex=true){\n\t#ifdef CAPITAL\n\tcout<<\"YES\"<<endl;\n\t#else\n\tcout<<\"Yes\"<<endl;\n\t#endif\n\tif(ex)exit(0);\n}\nvoid no(bool ex=true){\n\t#ifdef CAPITAL\n\tcout<<\"NO\"<<endl;\n\t#else\n\tcout<<\"No\"<<endl;\n\t#endif\n\tif(ex)exit(0);\n}\n\nconstexpr ll ten(int n){\n\treturn n==0?1:ten(n-1)*10;\n}\n\nconst ll infLL=LLONG_MAX/3;\n\n#ifdef int\nconst int inf=infLL;\n#else\nconst int inf=INT_MAX/2-100;\n#endif\n\nint topbit(signed t){\n\treturn t==0?-1:31-__builtin_clz(t);\n}\nint topbit(ll t){\n\treturn t==0?-1:63-__builtin_clzll(t);\n}\nint botbit(signed a){\n\treturn a==0?32:__builtin_ctz(a);\n}\nint botbit(ll a){\n\treturn a==0?64:__builtin_ctzll(a);\n}\nint popcount(signed t){\n\treturn __builtin_popcount(t);\n}\nint popcount(ll t){\n\treturn __builtin_popcountll(t);\n}\nbool ispow2(int i){\n\treturn i&&(i&-i)==i;\n}\nint mask(int i){\n\treturn (int(1)<<i)-1;\n}\n\nbool inc(int a,int b,int c){\n\treturn a<=b&&b<=c;\n}\n\ntemplate<class t> void mkuni(vc<t>&v){\n\tsort(all(v));\n\tv.erase(unique(all(v)),v.ed);\n}\n\nll rand_int(ll l, ll r) { //[l, r]\n\t#ifdef LOCAL\n\tstatic mt19937_64 gen;\n\t#else\n static random_device rd;\n static mt19937_64 gen(rd());\n #endif\n return uniform_int_distribution<ll>(l, r)(gen);\n}\n\ntemplate<class t>\nint lwb(const vc<t>&v,const t&a){\n\treturn lower_bound(all(v),a)-v.bg;\n}\n\ntemplate<class d>\nstruct maxflow{\n\tstruct E{\n\t\tint to,rev;\n\t\td cap;\n\t};\n\tvvc<E> g;\n\tvi itr,lv;\n\tmaxflow(int n):g(n),itr(n),lv(n){}\n\tvoid ae(int s,int t,d c){\n\t\tg[s].pb({t,(int)g[t].size(),c});\n\t\tg[t].pb({s,(int)g[s].size()-1,0});\n\t}\n\tvoid bfs(int s){\n\t\tfill(all(lv),-1);\n\t\tlv[s]=0;\n\t\tqueue<int> q;\n\t\tq.push(s);\n\t\twhile(q.size()){\n\t\t\tint v=q.front();q.pop();\n\t\t\tfor(auto e:g[v])if(e.cap>0&&lv[e.to]==-1){\n\t\t\t\tlv[e.to]=lv[v]+1;\n\t\t\t\tq.push(e.to);\n\t\t\t}\n\t\t}\n\t}\n\td dfs(int v,int t,d f){\n\t\tif(v==t)return f;\n\t\td res=0;\n\t\tfor(int&i=itr[v];i<(int)g[v].size();i++){\n\t\t\tE& e=g[v][i];\n\t\t\tif(e.cap>0&&lv[e.to]==lv[v]+1){\n\t\t\t\td a=dfs(e.to,t,min(f,e.cap));\n\t\t\t\tif(a>0){\n\t\t\t\t\te.cap-=a;\n\t\t\t\t\tg[e.to][e.rev].cap+=a;\n\t\t\t\t\tres+=a;\n\t\t\t\t\tf-=a;\n\t\t\t\t\tif(f<=0)break;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn res;\n\t}\n\td calc(int s,int t){\n\t\td f=0;\n\t\twhile(1){\n\t\t\tbfs(s);\n\t\t\tif(lv[t]==-1)\n\t\t\t\treturn f;\n\t\t\tfill(all(itr),0);\n\t\t\tf+=dfs(s,t,inf);\n\t\t}\n\t}\n};\n\nsigned main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\tcout<<fixed<<setprecision(20);\n\t\n\twhile(1){\n\t\tint h,w;cin>>h>>w;\n\t\tif(h==0)break;\n\t\t\n\t\tvvc<int> a(h+2);\n\t\ta[0]=vi(w+2,0);\n\t\trng(i,1,h+1){\n\t\t\ta[i].pb(0);\n\t\t\tstring s;cin>>s;\n\t\t\tfor(auto c:s)\n\t\t\t\ta[i].pb(c=='#');\n\t\t\ta[i].pb(0);\n\t\t}\n\t\ta[h+1]=vi(w+2,0);\n\t\th+=2;\n\t\tw+=2;\n\t\t\n\t\tvc<tuple<int,int,int>> ls[2];\n\t\trep(z,2){\n\t\t\trep(i,h-1)rep(j,w-1){\n\t\t\t\tif(a[i+1][j]&&a[i+1][j+1]&&a[i][j]+a[i][j+1]==1){\n\t\t\t\t\tint k=i+1;\n\t\t\t\t\twhile(a[k][j]+a[k][j+1]+a[k+1][j]+a[k+1][j+1]==4)k++;\n\t\t\t\t\tif(a[k+1][j]+a[k+1][j+1]==1){\n\t\t\t\t\t\tls[z].eb(j+1,i+1,k+1);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tvvc<int> b(w,vi(h));\n\t\t\trep(i,h)rep(j,w)\n\t\t\t\tb[j][i]=a[i][j];\n\t\t\tswap(a,b);\n\t\t\tswap(h,w);\n\t\t}\n\t\t\n\t\tint cnt=0;\n\t\trep(i,h-1)rep(j,w-1)if(a[i][j]+a[i][j+1]+a[i+1][j]+a[i+1][j+1]==3)\n\t\t\tcnt++;\n\t\t\n\t\tint x=ls[0].size(),y=ls[1].size();\n\t\t\n\t\tmaxflow<int> mf(1+x+y+1);\n\t\trep(i,x)mf.ae(0,1+i,1);\n\t\trep(i,y)mf.ae(1+x+i,1+x+y,1);\n\t\trep(i,x)rep(j,y){\n\t\t\tauto p=ls[0][i];\n\t\t\tauto q=ls[1][j];\n\t\t\tbool ok=true;\n\t\t\trep(_,2){\n\t\t\t\tif(!inc(get<1>(q),get<0>(p),get<2>(q)))\n\t\t\t\t\tok=false;\n\t\t\t\tswap(p,q);\n\t\t\t}\n\t\t\tif(ok){\n\t\t\t\tmf.ae(1+i,1+x+j,1);\n\t\t\t}\n\t\t}\n\t\t\n\t\tint f=mf.calc(0,1+x+y);\n\t\t\n\t\tcout<<cnt-(x+y-f)+1<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3976, "score_of_the_acc": -0.0347, "final_rank": 5 }, { "submission_id": "aoj_1185_3725851", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define REP(i,n) for(int i=0; i<n; i++)\n#define FOR(i,a,b) for(int i=a; i<b; i++)\n#define FORR(i,a,b) for(int i=(int)b-1; i>=a; i--)\n\n#define ALL(v) (v).begin(), (v).end()\n\nusing ll = long long;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\nusing vi = vector<int>;\nusing vl = vector<ll>;\n\n#define DEBUG(x) cerr<<#x<<\": \"<<(x)<<endl\n#define CHMIN(a,b) (a)=min((a),(b))\n#define CHMAX(a,b) (a)=max((a),(b))\n\nconst int INF = 1ll<<28;\nusing flow_type = int;\n\nstruct dinic{\n\tstruct edge{\n\t\tint from, to;\n\t\tflow_type cost;\n\t\tint rev;\n\t};\n\tint n;\n\tvector<vector<edge>> G,C;\n\tvector<int> level;\n\tvector<bool> finished;\n\tdinic(int n):n(n){\n\t\tG.assign(n,vector<edge>());\n\t\tlevel.assign(n,0);\n\t\tfinished.assign(n,false);\n\t}\n\tvoid add_edge(int from,int to,flow_type cost){\n\t\tedge s = (edge){from,to,cost,(int)G[to].size()};\n\t\tedge t = (edge){to,from,(flow_type)0,(int)G[from].size()};\n\t\tG[from].push_back(s);\n\t\tG[to].push_back(t);\n\t}\n\tflow_type dfs(int u, int t, flow_type cur){\n\t\tif(u==t || cur==0)return cur;\n\t\tif(finished[u])return 0;\n\t\tfinished[u] = true;\n\t\tfor(edge &e : C[u]){\n\t\t\tif(level[e.to] > level[u]){\n\t\t\t\tflow_type f = dfs(e.to, t, min(cur, e.cost));\n\t\t\t\tif(f>0){\n\t\t\t\t\te.cost -= f;\n\t\t\t\t\tC[e.to][e.rev].cost += f;\n\t\t\t\t\tfinished[u] = false;\n\t\t\t\t\treturn f;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn 0;\n\t}\n\tflow_type calc(int s, int t){\n\t\tC = G;\n\t\tflow_type total = 0;\n\t\twhile(true){\n\t\t\tREP(i,n)level[i] = -1;\n\t\t\tlevel[s] = 0;\n\t\t\tqueue<int> Q; Q.push(s);\n\t\t\tint d = n;\n\t\t\twhile(!Q.empty()){\n\t\t\t\tint u = Q.front(); Q.pop();\n\t\t\t\tfor(edge &e:C[u]){\n\t\t\t\t\tif(e.cost > 0 && level[e.to] == -1){\n\t\t\t\t\t\tQ.push(e.to);\n\t\t\t\t\t\tlevel[e.to] = level[u] + 1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tREP(i,n)finished[i] = false;\n\t\t\tbool flag = false;\n\t\t\twhile(true){\n\t\t\t\tflow_type f = dfs(s,t,INF);\n\t\t\t\tif(f==0)break;\n\t\t\t\ttotal += f;\n\t\t\t\tflag = true;\n\t\t\t}\n\t\t\tif(!flag)break;\n\t\t}\n\t\treturn total;\n\t}\n};\n\nint w,h;\nchar mp[125][125];\n\nbool vert(pair<pii,pii> line){\n\treturn line.first.second == line.second.second;\n}\n\nint main(){\n\twhile(true){\n\t\tscanf(\"%d%d\",&h,&w);\n\t\tif(h+w==0)break;\n\t\tREP(i,125)REP(j,125)mp[i][j] = '.';\n\t\tREP(i,h)scanf(\"%s\",mp[i+1]+1);\n\t\th+=2; w+=2;\n\t\tvector<pair<pii,pii>> lines;\n\t\tvector<pii> vertices;\n\t\tFOR(y1,1,h-1)FOR(x1,1,w-1){\n\t\t\tint cnt = 0;\n\t\t\tREP(dy,2)REP(dx,2)cnt += (mp[y1-dy][x1-dx]=='#');\n\t\t\tif(cnt!=3)continue;\n\t\t\tvertices.push_back(pii(y1,x1));\n\t\t\t{\n\t\t\t\tint cy=y1, cx=x1;\n\t\t\t\twhile(mp[cy][cx]=='#' && mp[cy-1][cx]=='#')cx++;\n\t\t\t\tint cnt = 0;\n\t\t\t\tREP(dy,2)REP(dx,2)cnt += (mp[cy-dy][cx-dx]=='#');\n\t\t\t\tif((cy!=y1 || cx!=x1) && cnt==3){\n\t\t\t\t\tlines.push_back(make_pair(pii(y1,x1),pii(cy,cx)));\n\t\t\t\t\t// printf(\"%d %d - %d %d\\n\",y1,x1,cy,cx);\n\t\t\t\t}\n\t\t\t}\n\t\t\t{\n\t\t\t\tint cy=y1, cx=x1;\n\t\t\t\twhile(mp[cy][cx]=='#' && mp[cy][cx-1]=='#')cy++;\n\t\t\t\tint cnt = 0;\n\t\t\t\tREP(dy,2)REP(dx,2)cnt += (mp[cy-dy][cx-dx]=='#');\n\t\t\t\tif((cy!=y1 || cx!=x1) && cnt==3){\n\t\t\t\t\tlines.push_back(make_pair(pii(y1,x1),pii(cy,cx)));\n\t\t\t\t\t// printf(\"%d %d - %d %d\\n\",y1,x1,cy,cx);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint N = lines.size();\n\t\tconst int S = N;\n\t\tconst int T = N+1;\n\t\tdinic D(N+2);\n\t\tREP(i,N){\n\t\t\tif(vert(lines[i])){\n\t\t\t\tD.add_edge(S,i,+1);\n\t\t\t\tD.add_edge(i,T,+0);\n\t\t\t}else{\n\t\t\t\tD.add_edge(S,i,+0);\n\t\t\t\tD.add_edge(i,T,+1);\n\t\t\t}\n\t\t}\n\t\tREP(i,N)REP(j,i){\n\t\t\tpair<pii,pii> a = lines[i], b = lines[j];\n\t\t\tif(vert(a)==vert(b))continue;\n\t\t\tbool flag = false;\n\t\t\tif(vert(b))flag=true,swap(a,b);\n\t\t\tassert(vert(a));\n\t\t\tif(b.second.second < a.first.second)continue;\n\t\t\tif(a.first.second < b.first.second)continue;\n\t\t\tif(a.second.first < b.first.first)continue;\n\t\t\tif(b.first.first < a.first.first)continue;\n\t\t\tif(!flag){\n\t\t\t\t// i is vert\n\t\t\t\tD.add_edge(i,j,+40000);\n\t\t\t}else{\n\t\t\t\tD.add_edge(j,i,+40000);\n\t\t\t}\n\t\t\t// DEBUG(i); DEBUG(j);\n\t\t}\n\t\tint unused = D.calc(S,T);\n\t\tint used = N - unused;\n\t\tint ans = used + (vertices.size() - 2*used) + 1;\n\t\tprintf(\"%d\\n\",ans);\n\t\t// break;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 4516, "score_of_the_acc": -0.1674, "final_rank": 13 }, { "submission_id": "aoj_1185_3693593", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i,n) for(ll (i) = (0);(i) < (n);++i)\n#define REV(i,n) for(ll (i) = (n) - 1;(i) >= 0;--i)\n#define PB push_back\n#define EB emplace_back\n#define MP make_pair\n#define FI first\n#define SE second\n#define SHOW1d(v,n) {REP(WW,n)cerr << v[WW] << ' ';cerr << endl << endl;}\n#define SHOW2d(v,WW,HH) {REP(W_,WW){REP(H_,HH)cerr << v[W_][H_] << ' ';cerr << endl;}cerr << endl;}\n#define ALL(v) v.begin(),v.end()\n#define Decimal fixed<<setprecision(20)\n#define INF 1000000000\n#define LLINF 1000000000000000000LL\n#define MOD 998244353\n\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n\nstruct Dinic {\n\tstruct edge{int to;long long cap,rev;};\n\tvector<vector<edge>> G;\n\tvector<int> level;\n\tvector<int> iter;\n\n\tDinic(int n):G(n, vector<edge>()),level(n),iter(n){}\n\n\tvoid add_edge(int from,int to,long long cap){\n\t\tG[from].push_back((edge){to,cap,(ll)G[to].size()});\n\t\tG[to].push_back((edge){from,0,(ll)G[from].size()-1});\n\t}\n\n\tvoid bfs(int s){\n\t\tfill(level.begin(), level.end(), -1);\n\t\tqueue<int> que;\n\t\tlevel[s] = 0;\n\t\tque.push(s);\n\t\twhile(!que.empty())\t{\n\t\t\tint v = que.front();que.pop();\n\t\t\tfor(int i = 0;i < G[v].size();++i){\n\t\t\t\tedge &e = G[v][i];\n\t\t\t\tif(e.cap > 0 && level[e.to] < 0){\n\t\t\t\t\tlevel[e.to] = level[v] + 1;\n\t\t\t\t\tque.push(e.to);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint dfs(int v ,int t,long long f){\n\t\tif(v == t)return f;\n\t\tfor(int &i = iter[v];i < G[v].size() ;++i){\n\t\t\tedge &e = G[v][i];\n\t\t\tif(e.cap > 0 && level[v] < level[e.to]){\n\t\t\t\tlong long d = dfs(e.to,t,min(f,e.cap));\n\t\t\t\tif(d > 0){\n\t\t\t\t\te.cap -= d;\n\t\t\t\t\tG[e.to][e.rev].cap += d;\n\t\t\t\t\treturn d;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn 0;\n\t}\n\n\tlong long solve(int s,int t){\n\t\tlong long flow = 0;\n\t\twhile(1){\n\t\t\tbfs(s);\n\t\t\tif(level[t] < 0)return flow;\n\t\t\tfill(iter.begin(), iter.end(), 0);\n\t\t\tlong long f;while((f = dfs(s,t,INF)) > 0)flow += f;\n\t\t}\n\t}\n};\n\nint getCount(int h, int w, vector<vector<char>> &mp){\n\tif(h < 0 || w < 0 || h + 1 >= mp.size() || w + 1 >= mp[0].size()) {\n\t\treturn -1;\n\t}\n\n\tint cou = 0;\n\tif(mp[h][w] == '#')cou++;\n\tif(mp[h+1][w] == '#')cou++;\n\tif(mp[h][w+1] == '#')cou++;\n\tif(mp[h+1][w+1] == '#')cou++;\n\treturn cou;\n}\n\nP searchPairTate(int h, int w, vector<vector<char>> &mp){\n\twhile(1) {\n\t\th++;\n\t\tif(mp[h][w] != '#' || mp[h][w+1] != '#'){\n\t\t\treturn MP(-1, -1);\n\t\t}\n\t\tif(getCount(h, w, mp) != 4) {\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(getCount(h, w, mp) == 3){\n\t\treturn MP(h, w);\n\t}\n\telse {\n\t\treturn MP(-1, -1);\n\t}\n}\n\nP searchPairYoko(int h, int w, vector<vector<char>> &mp){\n\twhile(1) {\n\t\tw++;\n\t\tif(mp[h][w] != '#' || mp[h+1][w] != '#'){\n\t\t\treturn MP(-1, -1);\n\t\t}\n\t\tif(getCount(h, w, mp) != 4) {\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(getCount(h, w, mp) == 3){\n\t\treturn MP(h, w);\n\t}\n\telse {\n\t\treturn MP(-1, -1);\n\t}\n}\n\nbool intersect(pair<P, P> a, pair<P, P> b){\n\tif(b.FI.SE < a.FI.SE || b.FI.SE > a.SE.SE){\n\t\treturn false;\n\t}\n\tif(a.FI.FI < b.FI.FI || a.FI.FI > b.SE.FI){\n\t\treturn false;\n\t}\n\treturn true;\n}\n\nvoid sovle(int h, int w){\n\tvector<vector<char>> mp(h, vector<char>(w));\n\tvector<pair<P, P>> tate;\n\tvector<pair<P, P>> yoko;\n\tint corner = 0;\n\n\tREP(i, h){\n\t\tREP(j, w){\n\t\t\tcin >> mp[i][j];\n\t\t}\n\t}\n\n\tREP(i, h-1){\n\t\tREP(j, w-1){\n\t\t\tint cou = getCount(i, j, mp);\n\t\t\tif(cou == 3){\n\t\t\t\tcorner++;\n\t\t\t\tP aite = searchPairTate(i, j, mp);\n\t\t\t\tif(aite.FI != -1){\n\t\t\t\t\ttate.EB(MP(i, j), MP(aite.FI, aite.SE));\n\t\t\t\t}\n\t\t\t\taite = searchPairYoko(i, j, mp);\n\t\t\t\tif(aite.FI != -1){\n\t\t\t\t\tyoko.EB(MP(i, j), MP(aite.FI, aite.SE));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tvector<vector<int>> v(tate.size() + yoko.size() + 2);\n\tDinic dinic(tate.size() + yoko.size() + 2);\n\tint start = tate.size() + yoko.size();\n\tint goal = tate.size() + yoko.size() + 1;\n\n\tREP(i, tate.size()){\n\t\tdinic.add_edge(start, i, 1);\n\t\tREP(j, yoko.size()) {\n\t\t\tif(intersect(yoko[j], tate[i])) {\n\t\t\t\tdinic.add_edge(i, j + tate.size(), 1);\n\t\t\t}\n\t\t}\n\t}\n\tREP(i, yoko.size()){\n\t\tdinic.add_edge(i + tate.size(), goal, 1);\n\t}\n\n\tcout << corner - (tate.size() + yoko.size() - dinic.solve(start, goal)) + 1 << endl;\n}\n\nint main(){\n\tcin.tie(0);cout.tie(0);ios::sync_with_stdio(false);\n\n\tint h, w;\n\twhile(cin >> h >> w,h + w){\n\t\tsovle(h, w);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 4060, "score_of_the_acc": -0.0356, "final_rank": 6 }, { "submission_id": "aoj_1185_3693591", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i,n) for(ll (i) = (0);(i) < (n);++i)\n#define REV(i,n) for(ll (i) = (n) - 1;(i) >= 0;--i)\n#define PB push_back\n#define EB emplace_back\n#define MP make_pair\n#define FI first\n#define SE second\n#define SHOW1d(v,n) {REP(WW,n)cerr << v[WW] << ' ';cerr << endl << endl;}\n#define SHOW2d(v,WW,HH) {REP(W_,WW){REP(H_,HH)cerr << v[W_][H_] << ' ';cerr << endl;}cerr << endl;}\n#define ALL(v) v.begin(),v.end()\n#define Decimal fixed<<setprecision(20)\n#define INF 1000000000\n#define LLINF 1000000000000000000LL\n#define MOD 998244353\n\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n\nstruct Dinic {\n\tstruct edge{int to;long long cap,rev;};\n\tvector<vector<edge>> G;\n\tvector<int> level;\n\tvector<int> iter;\n\n\tDinic(int n):G(n, vector<edge>()),level(n),iter(n){}\n\n\tvoid add_edge(int from,int to,long long cap){\n\t\tG[from].push_back((edge){to,cap,(ll)G[to].size()});\n\t\tG[to].push_back((edge){from,0,(ll)G[from].size()-1});\n\t}\n\n\tvoid bfs(int s){\n\t\tfill(level.begin(), level.end(), -1);\n\t\tqueue<int> que;\n\t\tlevel[s] = 0;\n\t\tque.push(s);\n\t\twhile(!que.empty())\t{\n\t\t\tint v = que.front();que.pop();\n\t\t\tfor(int i = 0;i < G[v].size();++i){\n\t\t\t\tedge &e = G[v][i];\n\t\t\t\tif(e.cap > 0 && level[e.to] < 0){\n\t\t\t\t\tlevel[e.to] = level[v] + 1;\n\t\t\t\t\tque.push(e.to);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint dfs(int v ,int t,long long f){\n\t\tif(v == t)return f;\n\t\tfor(int &i = iter[v];i < G[v].size() ;++i){\n\t\t\tedge &e = G[v][i];\n\t\t\tif(e.cap > 0 && level[v] < level[e.to]){\n\t\t\t\tlong long d = dfs(e.to,t,min(f,e.cap));\n\t\t\t\tif(d > 0){\n\t\t\t\t\te.cap -= d;\n\t\t\t\t\tG[e.to][e.rev].cap += d;\n\t\t\t\t\treturn d;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn 0;\n\t}\n\n\tlong long solve(int s,int t){\n\t\tlong long flow = 0;\n\t\twhile(1){\n\t\t\tbfs(s);\n\t\t\tif(level[t] < 0)return flow;\n\t\t\tfill(iter.begin(), iter.end(), 0);\n\t\t\tlong long f;while((f = dfs(s,t,INF)) > 0)flow += f;\n\t\t}\n\t}\n};\n\nint getCount(int h, int w, vector<vector<char>> &mp){\n\tif(h < 0 || w < 0 || h + 1 >= mp.size() || w + 1 >= mp[0].size()) {\n\t\treturn -1;\n\t}\n\n\tint cou = 0;\n\tif(mp[h][w] == '#')cou++;\n\tif(mp[h+1][w] == '#')cou++;\n\tif(mp[h][w+1] == '#')cou++;\n\tif(mp[h+1][w+1] == '#')cou++;\n\treturn cou;\n}\n\nP searchPairTate(int h, int w, vector<vector<char>> &mp){\n\twhile(1) {\n\t\th++;\n\t\tif(mp[h][w] != '#' || mp[h][w+1] != '#'){\n\t\t\treturn MP(-1, -1);\n\t\t}\n\t\tif(getCount(h, w, mp) != 4) {\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(getCount(h, w, mp) == 3){\n\t\treturn MP(h, w);\n\t}\n\telse {\n\t\treturn MP(-1, -1);\n\t}\n}\n\nP searchPairYoko(int h, int w, vector<vector<char>> &mp){\n\twhile(1) {\n\t\tw++;\n\t\tif(mp[h][w] != '#' || mp[h+1][w] != '#'){\n\t\t\treturn MP(-1, -1);\n\t\t}\n\t\tif(getCount(h, w, mp) != 4) {\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(getCount(h, w, mp) == 3){\n\t\treturn MP(h, w);\n\t}\n\telse {\n\t\treturn MP(-1, -1);\n\t}\n}\n\nbool intersect(pair<P, P> a, pair<P, P> b){\n\tif(b.FI.SE < a.FI.SE || b.FI.SE > a.SE.SE){\n\t\treturn false;\n\t}\n\tif(a.FI.FI < b.FI.FI || a.FI.FI > b.SE.FI){\n\t\treturn false;\n\t}\n\treturn true;\n}\n\nvoid sovle(int h, int w){\n\tvector<vector<char>> mp(h, vector<char>(w));\n\tvector<pair<P, P>> tate;\n\tvector<pair<P, P>> yoko;\n\tint corner = 0;\n\n\tREP(i, h){\n\t\tREP(j, w){\n\t\t\tcin >> mp[i][j];\n\t\t}\n\t}\n\n\tREP(i, h-1){\n\t\tREP(j, w-1){\n\t\t\tint cou = getCount(i, j, mp);\n\t\t\tif(cou == 3){\n\t\t\t\tcorner++;\n\t\t\t\tP aite = searchPairTate(i, j, mp);\n\t\t\t\tif(aite.FI != -1){\n\t\t\t\t\ttate.EB(MP(i, j), MP(aite.FI, aite.SE));\n\t\t\t\t}\n\t\t\t\taite = searchPairYoko(i, j, mp);\n\t\t\t\tif(aite.FI != -1){\n\t\t\t\t\tyoko.EB(MP(i, j), MP(aite.FI, aite.SE));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tvector<vector<int>> v(tate.size() + yoko.size() + 2);\n\tDinic dinic(tate.size() + yoko.size() + 2);\n\tint start = tate.size() + yoko.size();\n\tint goal = tate.size() + yoko.size() + 1;\n\n\tREP(i, tate.size()){\n\t\t//cout << tate[i].FI.FI << \" \" << tate[i].FI.SE << \" \" << tate[i].SE.FI << \" \" << tate[i].SE.SE << endl;\n\t\tdinic.add_edge(start, i, 1);\n\t\tREP(j, yoko.size()) {\n\t\t\tif(intersect(yoko[j], tate[i])) {\n\t\t\t\t//cout << tate[i].FI.FI << \" \" << tate[i].FI.SE << \" \" << tate[i].SE.FI << \" \" << tate[i].SE.SE << \" \" << yoko[i].FI.FI << \" \" << yoko[i].FI.SE << \" \" << yoko[i].SE.FI << \" \" << yoko[i].SE.SE << endl;\n\t\t\t\tdinic.add_edge(i, j + tate.size(), 1);\n\t\t\t}\n\t\t}\n\t}\n\tREP(i, yoko.size()){\n\t\t//cout << yoko[i].FI.FI << \" \" << yoko[i].FI.SE << \" \" << yoko[i].SE.FI << \" \" << yoko[i].SE.SE << endl;\n\t\tdinic.add_edge(i + tate.size(), goal, 1);\n\t}\n\n\t//cout << \"coner tate yoko \" << corner << \" \" << tate.size() << \" \" << yoko.size() << \" \" << dinic.solve(start, goal) << endl;\n\tcout << corner - (tate.size() + yoko.size() - dinic.solve(start, goal)) + 1 << endl;\n}\n\nint main(){\n\tcin.tie(0);cout.tie(0);ios::sync_with_stdio(false);\n\n\tint h, w;\n\twhile(cin >> h >> w,h + w){\n\t\tsovle(h, w);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 4104, "score_of_the_acc": -0.036, "final_rank": 7 }, { "submission_id": "aoj_1185_3641684", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nclass Increase {\npublic:\n int n, flowMax = 1000000;\n vector<map<int, int>> p;\n vector<int> parent;\n vector<int> stack;\n\n Increase(int n, vector<map<int, int>> &p) : n(n), p(p) { parent.resize(n); }\n\n int dfs(int id, int from, int flow) {\n if (parent[id] != id)\n return 0;\n stack.push_back(id);\n parent[id] = from;\n if (id == n - 1)\n return flow;\n for (auto &v : p[id])\n if (v.second > 0) {\n int next = dfs(v.first, id, min(flow, v.second));\n if (next > 0)\n return next;\n }\n return 0;\n }\n\n int solve() {\n int ret = 0, flow;\n for (int i = 0; i < n; i++)\n parent[i] = i;\n\n while ((flow = dfs(0, -1, flowMax)) > 0) {\n int now = n - 1;\n ret += flow;\n while (parent[now] >= 0) {\n p[parent[now]][now] -= flow;\n p[now][parent[now]] += flow;\n now = parent[now];\n }\n for (auto &v : stack)\n parent[v] = v;\n stack.clear();\n }\n return ret;\n }\n};\n\nint main() {\n while (true) {\n int h, w;\n cin >> h >> w;\n if (h == 0)\n break;\n vector<string> mp(h + 2);\n for (int i = 0; i < w + 2; i++) {\n mp[0].push_back('.');\n mp[h + 1].push_back('.');\n }\n\n for (int i = 0; i < h; i++) {\n string s;\n cin >> s;\n mp[i + 1] = \".\" + s + \".\";\n }\n\n h += 2;\n w += 2;\n\n int n = 0;\n vector<vector<int>> used(h, vector<int>(w));\n vector<pair<int, int>> edge;\n\n // 横\n int yoko = 1;\n for (int i = 0; i < h - 1; i++) {\n for (int j = 0; j < w - 1; j++) {\n // 右\n if (mp[i][j] == '.' && mp[i][j + 1] == '#' && mp[i + 1][j] == '#' &&\n mp[i + 1][j + 1] == '#') {\n n++;\n int ii = i, jj = j + 1;\n while (mp[ii][jj] == '#' && mp[ii + 1][jj] == '#') {\n jj++;\n }\n if (mp[ii][jj] == '#' || mp[ii + 1][jj] == '#') {\n int now = yoko++;\n for (jj -= 1; jj > j; jj--) {\n used[ii][jj] = now;\n }\n }\n } else if (mp[i][j] == '#' && mp[i][j + 1] == '.' &&\n mp[i + 1][j] == '#' && mp[i + 1][j + 1] == '#') {\n n++;\n } else if (mp[i][j] == '#' && mp[i][j + 1] == '#' &&\n mp[i + 1][j] == '.' && mp[i + 1][j + 1] == '#') {\n n++;\n int ii = i, jj = j + 1;\n while (mp[ii][jj] == '#' && mp[ii + 1][jj] == '#') {\n jj++;\n }\n if (mp[ii][jj] == '#' || mp[ii + 1][jj] == '#') {\n int now = yoko++;\n for (jj -= 1; jj > j; jj--) {\n used[ii][jj] = now;\n }\n }\n } else if (mp[i][j] == '#' && mp[i][j + 1] == '#' &&\n mp[i + 1][j] == '#' && mp[i + 1][j + 1] == '.') {\n n++;\n } else if (mp[i][j] == '#' && mp[i][j + 1] == '.' &&\n mp[i + 1][j] == '.' && mp[i + 1][j + 1] == '.') {\n n++;\n } else if (mp[i][j] == '.' && mp[i][j + 1] == '#' &&\n mp[i + 1][j] == '.' && mp[i + 1][j + 1] == '.') {\n n++;\n } else if (mp[i][j] == '.' && mp[i][j + 1] == '.' &&\n mp[i + 1][j] == '#' && mp[i + 1][j + 1] == '.') {\n n++;\n } else if (mp[i][j] == '.' && mp[i][j + 1] == '.' &&\n mp[i + 1][j] == '.' && mp[i + 1][j + 1] == '#') {\n n++;\n }\n }\n }\n\n int tate = yoko;\n for (int i = 0; i < h - 1; i++) {\n for (int j = 0; j < w - 1; j++) {\n if (mp[i][j] == '.' && mp[i][j + 1] == '#' && mp[i + 1][j] == '#' &&\n mp[i + 1][j + 1] == '#') {\n int ii = i + 1, jj = j;\n while (mp[ii][jj] == '#' && mp[ii][jj + 1] == '#') {\n ii++;\n }\n if (mp[ii][jj] == '#' || mp[ii][jj + 1] == '#') {\n int now = tate++;\n for (ii -= 1; ii > i; ii--) {\n if (used[ii][jj] > 0)\n edge.emplace_back(used[ii][jj], now);\n if (used[ii][jj + 1] > 0 && used[ii][jj] == 0)\n edge.emplace_back(used[ii][jj + 1], now);\n }\n if (used[ii][jj + 1] > 0)\n edge.emplace_back(used[ii][jj + 1], now);\n }\n } else if (mp[i][j] == '#' && mp[i][j + 1] == '.' &&\n mp[i + 1][j] == '#' && mp[i + 1][j + 1] == '#') {\n int ii = i + 1, jj = j;\n while (mp[ii][jj] == '#' && mp[ii][jj + 1] == '#') {\n ii++;\n }\n if (mp[ii][jj] == '#' || mp[ii][jj + 1] == '#') {\n int now = tate++;\n for (ii -= 1; ii > i; ii--) {\n if (used[ii][jj] > 0)\n edge.emplace_back(used[ii][jj], now);\n if (used[ii][jj + 1] > 0 && used[ii][jj] == 0)\n edge.emplace_back(used[ii][jj + 1], now);\n }\n if (used[ii][jj] > 0)\n edge.emplace_back(used[ii][jj], now);\n }\n }\n }\n }\n\n int m = tate + 1;\n // source: 0, sink: m - 1, yoko: [1, yoko), tate: [yoko, tate)\n vector<map<int, int>> p(m);\n for (int i = 0; i < yoko - 1; i++) {\n p[0][i + 1] = 1;\n }\n for (int i = yoko; i < tate; i++) {\n p[i][m - 1] = 1;\n }\n for (auto &v : edge) {\n p[v.first][v.second] = 1;\n }\n\n Increase g(m, p);\n int flow = g.solve();\n int indep = m - 2 - flow;\n\n cout << n / 2 - 1 - indep << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 4808, "score_of_the_acc": -0.1546, "final_rank": 12 }, { "submission_id": "aoj_1185_3606583", "code_snippet": "#include<bits/stdc++.h>\n#define X first\n#define Y second\n#define pb emplace_back\n#define FOR(i,a,b) for(int (i)=(a);i<(b);++(i))\n#define EFOR(i,a,b) for(int (i)=(a);i<=(b);++(i))\n#define rep(X,Y) for (int (X) = 0;(X) < (Y);++(X))\n#define REP rep\n#define rrep(X,Y) for (int (X) = (Y)-1;(X) >=0;--(X))\n#define all(X) (X).begin(),(X).end()\n#define eb emplace_back\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\ntypedef ll LL;\ntypedef pii PII;\ntypedef pll PLL;\nconst ll MOD=1e9+7;\n\n#define rall(X) (X).rbegin(),(X).rend()\n#define UNIQUE(X) (X).erase(unique(all(X)),(X).end())\n#define reps(X,S,Y) for (int (X) = S;(X) < (Y);++(X))\n#define rreps(X,S,Y) for (int (X) = (Y)-1;(X) >= (S);--(X))\ntemplate<class T> inline bool MX(T &l,const T &r){return l<r?l=r,1:0;}\ntemplate<class T> inline bool MN(T &l,const T &r){return l>r?l=r,1:0;}\n\nconst long long INF = (1ll << 50);\nstruct graph {\n typedef long long flow_type;\n struct edge {\n int src, dst;\n flow_type capacity, flow;\n size_t rev;\n };\n int n;\n vector<vector<edge>> adj;\n graph(int n) : n(n), adj(n) { }\n void add_edge(int src, int dst, flow_type capacity) {\n adj[src].push_back({src, dst, capacity, 0, adj[dst].size()});\n adj[dst].push_back({dst, src, 0, 0, adj[src].size()-1});\n }\n flow_type max_flow(int s, int t) {\n vector<int> level(n), iter(n);\n function<int(void)> levelize = [&]() { // foward levelize\n level.assign(n, -1); level[s] = 0;\n queue<int> Q; Q.push(s);\n while (!Q.empty()) {\n int u = Q.front(); Q.pop();\n if (u == t) break;\n for (auto &e: adj[u]) {\n if (e.capacity > e.flow && level[e.dst] < 0) {\n Q.push(e.dst);\n level[e.dst] = level[u] + 1;\n }\n }\n }\n return level[t];\n };\n function<flow_type(int, flow_type)> augment = [&](int u, flow_type cur) {\n if (u == t) return cur;\n for (int &i = iter[u]; i < adj[u].size(); ++i) {\n edge &e = adj[u][i], &r = adj[e.dst][e.rev];\n if (e.capacity > e.flow && level[u] < level[e.dst]) {\n flow_type f = augment(e.dst, min(cur, e.capacity - e.flow));\n if (f > 0) {\n e.flow += f;\n r.flow -= f;\n return f;\n }\n }\n }\n return flow_type(0);\n };\n for (int u = 0; u < n; ++u) // initialize\n for (auto &e: adj[u]) e.flow = 0;\n\n flow_type flow = 0;\n while (levelize() >= 0) {\n fill(all(iter), 0);\n for (flow_type f; (f = augment(s, INF)) > 0; )\n flow += f;\n }\n return flow;\n }\n};\n\n\nint H;\nint W;\nchar field[114][114];\n\nvoid Color(vector<vector<int>> &es, vector<int> &col, int v, int c=1) {\n col[v] = c;\n for (int u : es[v]) {\n if (col[u]) {\n assert(col[u] != col[v]);\n continue;\n }\n\n Color(es, col, u, 3-c);\n }\n}\n\nint Solve() {\n rep(i, H) {\n rep(j, W) {\n cin >> field[i][j];\n }\n }\n\n int ans = 1;\n map<pii, pii> hole;\n reps(i, 1, H) {\n reps(j, 1, W) {\n int cnt = 0;\n vector<pii> holes;\n rep(k, 2) {\n rep(l, 2) {\n if (field[i-k][j-l] != '#') holes.eb(pii(k, l));\n }\n }\n\n if (holes.size() == 1) {\n ans++;\n hole[pii(i, j)] = holes[0];\n }\n }\n }\n\n if (hole.empty()) return ans;\n\n using Seg = pair<pii, pii>;\n vector<Seg> segs;\n map<Seg, int> mp;\n reps(i, 1, H) {\n reps(j, 1, W) {\n if (!hole.count(pii(i, j))) continue;\n\n auto p = hole[pii(i, j)];\n if (p.X) {\n reps(ni, i+1, H) {\n int cnt = 0;\n rep(k, 2) {\n rep(l, 2) {\n cnt += (field[ni-k][j-l] == '#');\n }\n }\n \n if (cnt <= 2) break;\n if (hole.count(pii(ni, j))) {\n if (hole[pii(ni, j)].X == 0) {\n segs.eb(Seg(pii(i, j), pii(ni, j)));\n int v = mp.size();\n mp[segs.back()] = v;\n }\n break;\n } \n assert(cnt == 4);\n }\n }\n\n if (p.Y) {\n reps(nj, j+1, W) {\n int cnt = 0;\n rep(k, 2) {\n rep(l, 2) {\n cnt += (field[i-k][nj-l] == '#');\n }\n }\n \n if (cnt <= 2) break;\n if (hole.count(pii(i, nj))) {\n if (hole[pii(i, nj)].Y == 0) {\n segs.eb(Seg(pii(i, j), pii(i, nj)));\n int v = mp.size();\n mp[segs.back()] = v;\n }\n break;\n } \n assert(cnt == 4);\n }\n }\n }\n }\n \n vector<vector<int>> es(mp.size());\n for (auto &s : segs) {\n bool sd = s.X.X == s.Y.X;\n for (auto &t : segs) {\n bool td = t.X.X == t.Y.X;\n if (sd == td) continue;\n if (!sd) swap(s, t);\n if (min(s.X.Y, s.Y.Y) <= t.X.Y && t.X.Y <= max(s.X.Y, s.Y.Y)) {\n if (min(t.X.X, t.Y.X) <= s.X.X && s.X.X <= max(t.X.X, t.Y.X)) {\n int u = mp[s];\n int v = mp[t];\n es[u].eb(v);\n es[v].eb(u);\n }\n }\n if (!sd) swap(s, t);\n }\n }\n\n vector<int> col(mp.size());\n rep(v, mp.size()) {\n if (col[v]) continue;\n Color(es, col, v);\n }\n\n //vector<pii> rev(mp.size());\n //for (auto &p : mp) {\n // rev[p.Y] = p.X;\n //}\n\n //rep(v, mp.size()) {\n // for (int u : es[v]) {\n // if (v > u) continue;\n // auto a = rev[v];\n // cout << \"(\" << a.X << \", \" << a.Y << \"), \";\n // auto b = rev[u];\n // cout << \"(\" << b.X << \", \" << b.Y << \")\" << endl;\n // }\n //}\n\n int S = mp.size();\n int T = mp.size()+1;\n graph G(mp.size()+2);\n rep(v, mp.size()) {\n if (col[v] == 1) {\n G.add_edge(S, v, 1);\n } else {\n G.add_edge(v, T, 1);\n }\n }\n\n rep(v, mp.size()) {\n if (col[v] == 2) continue;\n for (int u : es[v]) {\n assert(col[u] == 2);\n G.add_edge(v, u, 1);\n }\n }\n \n int m = mp.size();\n return ans - (m - G.max_flow(S, T));\n}\n\nsigned main(){\n ios_base::sync_with_stdio(false);\n cout<<fixed<<setprecision(0);\n\n while (1) {\n cin >> H >> W;\n if (H == 0) return 0;\n cout << Solve() << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 5588, "score_of_the_acc": -0.4327, "final_rank": 16 }, { "submission_id": "aoj_1185_3488425", "code_snippet": "#include \"bits/stdc++.h\"\n#pragma GCC optimize(\"Ofast\")\n\n#pragma GCC target(\"avx,avx2\")\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ll=long long ;\n#define Whats(x) //cout<<#x<<\" is \"<<(x)<<endl\n\n\n////フォード - ファルカーソン法 O(Flow|E|)\n\ntypedef int Weight;\n\nconst Weight INF = 1e9;\nconst Weight ZERO = 0;\nstruct Edge {\n\tint src, dst;\n\tWeight weight;\n\tint rev;\n\tint id;\n\tEdge(int src_, int dst_, Weight weight_, const int rev_, const int id_) :\n\t\tsrc(src_), dst(dst_), weight(weight_), rev(rev_), id(id_) { }\n\tEdge(int src_, int dst_, Weight weight_, const int rev_) :\n\t\tsrc(src_), dst(dst_), weight(weight_), rev(rev_) { }\n\tEdge() :src(0), dst(0), weight(0) {\n\t}\n};\nbool operator < (const Edge &e, const Edge &f) {\n\treturn e.weight != f.weight ? e.weight > f.weight : // !!INVERSE!!\n\te.src != f.src ? e.src < f.src : e.dst < f.dst;\n}\ntypedef vector<Edge> Edges;\ntypedef vector<Edges> Graph;\n\ntypedef vector<Weight> Array;\ntypedef vector<Array> Matrix;\nvoid add_edge(Graph&g, int from, int to, int cap)\n{\n\tg[from].push_back(Edge(from, to, cap, (int)g[to].size()));\n\tg[to].push_back(Edge(to, from, 0, (int)g[from].size() - 1));\n}\n//二つを繋ぐ線を完全に消す\nvoid erase_edge(Graph&g, const int from, const int to) {\n\tg[from].erase(remove_if(g[from].begin(), g[from].end(), [=](const Edge&e) {return e.dst == to; }), g[from].end());\n\tg[to].erase(remove_if(g[to].begin(), g[to].end(), [=](const Edge&e) {return e.dst == from; }), g[to].end());\n}\nint dfs(vector<int>&used, Graph&g, int now, int t, int f)\n{\n\tif (now == t) {\n\t\treturn f;\n\t}\n\tused[now] = true;\n\tfor (int i = 0; i<g[now].size(); ++i) {\n\t\tEdge &e = g[now][i];\n\t\tif (!used[e.dst] && e.weight>0) {\n\t\t\tint d = dfs(used, g, e.dst, t, min(f, e.weight));\n\t\t\tif (d > 0) {\n\t\t\t\te.weight -= d;\n\t\t\t\tg[e.dst][e.rev].weight += d;\n\t\t\t\treturn d;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\nWeight fold_falc(Graph g, const int start, const int goal) {\n\tWeight ans = 0;\n\twhile (1) {\n\t\tvector<int>used(g.size());\n\t\tint flow = dfs(used, g, start, goal, INF);\n\t\tif (!flow)return ans;\n\t\telse ans += flow;\n\t}\n}\nstruct line {\n\tint l;\n\tint u;\n\tint r;\n\tint d;\n};\nint main() {\n\twhile (true) {\n\t\tint H,W;cin>>H>>W;\n\t\tif(!H)break;\n\t\tvector<string>field(H);\n\t\tfor(int i=0;i<H;++i)cin>>field[i];\n\n\t\tvector<vector<int>>nums(H+1,vector<int>(W+1));\n\t\tfor (int y = 0; y < H - 1; ++y) {\n\t\t\tfor (int x = 0; x < W - 1; ++x) {\n\t\t\t\tfor (int dx = 0; dx < 2; ++dx) {\n\t\t\t\t\tfor (int dy = 0; dy < 2; ++dy) {\n\t\t\t\t\t\tnums[y+1][x+1]+=field[y+dy][x+dx]=='#';\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<pair<int,int>>points;\n\t\tfor (int j = 1; j <= W; ++j) {\n\t\t\tfor (int i = 1; i <= H; ++i) {\n\n\t\t\t\tif(nums[i][j]==3)points.push_back(make_pair(j,i));\n\t\t\t}\n\t\t}\n\t\tvector<line>x_lines,y_lines;\n\t\tfor (int i = 0; i < points.size(); ++i) {\n\t\t\tfor (int j = i+1; j < points.size(); ++j) {\n\t\t\t\tint l=points[i].first,r=points[j].first;\n\t\t\t\tint u=points[i].second,d=points[j].second;\n\t\t\t\tif(l==r){\n\t\t\t\t\tint x=l;\n\t\t\t\t\tbool ok=true;\n\t\t\t\t\tfor (int y = u; y < d; ++y) {\n\t\t\t\t\t\tif(field[y][x-1]=='.')ok=false;\n\t\t\t\t\t\tif(field[y][x]=='.')ok=false;\n\t\t\t\t\t}\n\t\t\t\t\tif (ok) {\n\t\t\t\t\t\ty_lines.push_back(line{ l,u,r,d });\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(u==d){\n\t\t\t\t\tint y=u;\n\t\t\t\t\t\n\t\t\t\t\tbool ok = true;\n\t\t\t\t\tfor (int x = l; x < r; ++x) {\n\t\t\t\t\t\tif(field[y][x]=='.')ok=false;\n\t\t\t\t\t\tif(field[y-1][x]=='.')ok=false;\n\t\t\t\t\t}\n\t\t\t\t\tif (ok) {\n\t\t\t\t\t\tx_lines.push_back(line{ l,u,r,d });\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tconst int start=0;\n\t\tconst int xl=start+1;\n\t\tconst int yl=xl+x_lines.size();\n\t\tconst int goal=yl+y_lines.size();\n\t\tGraph g(goal+1);\n\t\tfor (int i = 0; i < x_lines.size(); ++i) {\n\t\t\tfor (int j = 0; j < y_lines.size(); ++j) {\n\t\t\t\tauto axl=x_lines[i];\n\t\t\t\tauto ayl=y_lines[j];\n\t\t\t\tbool ok=true;\n\t\t\t\t//Whats(axl.l);Whats(axl.r);\n\t\t\t\n\t\t\t\tif (axl.l <= ayl.l&&ayl.l <= axl.r) {\n\t\t\t\t\tif (ayl.u <= axl.u&&axl.u <= ayl.d) {\n\t\t\t\t\t\tok=false;\n\t\t\t\t\t\t//cout<<\"ng\"<<endl;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (!ok) {\n\t\t\t\t\tadd_edge(g,xl+i,yl+j,10000);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int i = 0; i < x_lines.size(); ++i) {\n\t\t\tadd_edge(g,start,xl+i,1);\n\t\t\tadd_edge(g,xl+i,goal,0);\n\t\t}\n\t\tfor (int i = 0; i < y_lines.size(); ++i) {\n\t\t\tadd_edge(g,start,yl+i,0);\n\t\t\tadd_edge(g,yl+i,goal,1);\n\t\t}\n\t\tint flow=fold_falc(g,start,goal);\n\t\tWhats(points.size());\n\t\tWhats(x_lines.size());\n\t\tWhats(y_lines.size());\n\t\tWhats(flow);\n\t\tint answer=1+points.size()-x_lines.size()-y_lines.size()+flow;\n\t\tcout<<answer<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 650, "memory_kb": 4732, "score_of_the_acc": -1.0109, "final_rank": 19 }, { "submission_id": "aoj_1185_3388600", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS\n\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <limits>\n#include <ctime>\n#include <cassert>\n#include <map>\n#include <set>\n#include <iostream>\n#include <memory>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <functional>\n#include <sstream>\n#include <stack>\n#include <queue>\n#include <numeric>\n#include <iterator>\n#include <bitset>\n#include <unordered_map>\n#include <unordered_set>\n\nusing namespace std;\n#define FOR(i,n) for(int i = 0; i < (n); i++)\n#define sz(c) ((int)c.size())\n#define ten(n) ((int)1e##n)\nusing ll = long long;\nusing Pii = pair<int, int>;\nusing Pll = pair<ll, ll>;\n\ntemplate<typename ...> static inline int getchar_unlocked(void) { return getchar(); }\ntemplate<typename ...> static inline void putchar_unlocked(int c) { putchar(c); }\n#define mygc(c) (c)=getchar_unlocked()\n#define mypc(c) putchar_unlocked(c)\nvoid reader(int& x) { int k, m = 0; x = 0; for (;;) { mygc(k); if (k == '-') { m = 1; break; }if ('0' <= k&&k <= '9') { x = k - '0'; break; } }for (;;) { mygc(k); if (k<'0' || k>'9')break; x = x * 10 + k - '0'; }if (m) x = -x; }\nvoid reader(ll& x) { int k, m = 0; x = 0; for (;;) { mygc(k); if (k == '-') { m = 1; break; }if ('0' <= k&&k <= '9') { x = k - '0'; break; } }for (;;) { mygc(k); if (k<'0' || k>'9')break; x = x * 10 + k - '0'; }if (m) x = -x; }\nint reader(char c[]) { int i, s = 0; for (;;) { mygc(i); if (i != ' '&&i != '\\n'&&i != '\\r'&&i != '\\t'&&i != EOF) break; }c[s++] = i; for (;;) { mygc(i); if (i == ' ' || i == '\\n' || i == '\\r' || i == '\\t' || i == EOF) break; c[s++] = i; }c[s] = '\\0'; return s; }\nint reader(string& c) { int i; for (;;) { mygc(i); if (i != ' '&&i != '\\n'&&i != '\\r'&&i != '\\t'&&i != EOF) break; }c.push_back(i); for (;;) { mygc(i); if (i == ' ' || i == '\\n' || i == '\\r' || i == '\\t' || i == EOF) break; c.push_back(i); }; return sz(c); }\ntemplate <class T, class S> void reader(T& x, S& y) { reader(x); reader(y); }\ntemplate <class T, class S, class U> void reader(T& x, S& y, U& z) { reader(x); reader(y); reader(z); }\ntemplate <class T, class S, class U, class V> void reader(T& x, S& y, U& z, V & w) { reader(x); reader(y); reader(z); reader(w); }\nvoid writer(int x, char c) { int s = 0, m = 0; char f[10]; if (x<0)m = 1, x = -x; while (x)f[s++] = x % 10, x /= 10; if (!s)f[s++] = 0; if (m)mypc('-'); while (s--)mypc(f[s] + '0'); mypc(c); }\nvoid writer(ll x, char c) { int s = 0, m = 0; char f[20]; if (x<0)m = 1, x = -x; while (x)f[s++] = x % 10, x /= 10; if (!s)f[s++] = 0; if (m)mypc('-'); while (s--)mypc(f[s] + '0'); mypc(c); }\nvoid writer(const char c[]) { int i; for (i = 0; c[i] != '\\0'; i++)mypc(c[i]); }\nvoid writer(const string& x, char c) { int i; for (i = 0; x[i] != '\\0'; i++)mypc(x[i]); mypc(c); }\nvoid writer(const char x[], char c) { int i; for (i = 0; x[i] != '\\0'; i++)mypc(x[i]); mypc(c); }\ntemplate<class T> void writerLn(T x) { writer(x, '\\n'); }\ntemplate<class T, class S> void writerLn(T x, S y) { writer(x, ' '); writer(y, '\\n'); }\ntemplate<class T, class S, class U> void writerLn(T x, S y, U z) { writer(x, ' '); writer(y, ' '); writer(z, '\\n'); }\ntemplate<class T, class S, class U, class V> void writerLn(T x, S y, U z, V v) { writer(x, ' '); writer(y, ' '); writer(z, ' '); writer(v, '\\n'); }\ntemplate<class T> void writerArr(T x[], int n) { if (!n) { mypc('\\n'); return; }FOR(i, n - 1)writer(x[i], ' '); writer(x[n - 1], '\\n'); }\ntemplate<class T> void writerArr(vector<T>& x) { writerArr(x.data(), (int)x.size()); }\n\ntemplate<class T> void chmin(T& a, const T& b) { if (a > b) a = b; }\ntemplate<class T> void chmax(T& a, const T& b) { if (a < b) a = b; }\n\ntemplate<class T> T gcd(T a, T b) { return b ? gcd(b, a % b) : a; }\ntemplate<class T> T lcm(T a, T b) { return a / gcd(a, b) * b; }\nll mod_pow(ll a, ll n, ll mod) {\n\tll ret = 1;\n\tll p = a % mod;\n\twhile (n) {\n\t\tif (n & 1) ret = ret * p % mod;\n\t\tp = p * p % mod;\n\t\tn >>= 1;\n\t}\n\treturn ret;\n}\ntemplate<class T> T extgcd(T a, T b, T& x, T& y) { for (T u = y = 1, v = x = 0; a;) { T q = b / a; swap(x -= q * u, u); swap(y -= q * v, v); swap(b -= q * a, a); } return b; }\nll mod_inv(ll a, ll m) { ll x, y; extgcd<ll>(a, m, x, y); return (m + x % m) % m; }\n\n#ifdef _MSC_VER\ntemplate <typename ... Args>\nvoid debugPrintf(const char *format, Args const & ... args) {\n\tfprintf(stderr, format, args ...);\n\tfflush(stderr);\n}\n#else\n#define debugPrintf(...)\n#endif\n\nconst int MAX_N = 100000;\nint match[MAX_N];\nbool used[MAX_N];\n\nbool dfs(vector<vector<int>>& G, int v) {\n\tused[v] = true;\n\tfor (auto u : G[v]) {\n\t\tint w = match[u];\n\t\tif (w < 0 || !used[w] && dfs(G, w)) {\n\t\t\tmatch[v] = u;\n\t\t\tmatch[u] = v;\n\t\t\treturn true;\n\t\t}\n\t}\n\treturn false;\n}\n\nint bipartite_matching(vector<vector<int>>& G) {\n\tint ret = 0;\n\tmemset(match, -1, sizeof(match));\n\tFOR(v, sz(G)) {\n\t\tif (match[v] < 0) {\n\t\t\tmemset(used, 0, sizeof(used));\n\t\t\tif (dfs(G, v)) ret++;\n\t\t}\n\t}\n\treturn ret;\n}\n\nint main() {\n\tint n, m;\n\twhile (cin >> n >> m && n) {\n\t\tstatic char b[100][101];\n\t\tFOR(i, n) cin >> b[i];\n\t\tvector<vector<int>> f(n - 1);\n\t\tFOR(i, n - 1) FOR(j, m - 1) {\n\t\t\tint cur = 0;\n\t\t\tFOR(x, 2) FOR(y, 2) {\n\t\t\t\tint tmp = b[i + x][j + y] == '#';\n\t\t\t\tcur += tmp *(1 << (2 * x + y));\n\t\t\t}\n\t\t\tf[i].push_back(cur);\n\t\t}\n\n\t\tint specialCount = 0;\n\t\tFOR(i, n - 1) FOR(j, m - 1) {\n\t\t\tint t = f[i][j];\n\t\t\tbool ok = false;\n\t\t\tFOR(k, 4) if (t == 15 - (1 << k)) ok = true;\n\t\t\tif (!ok) continue;\n\t\t\tspecialCount++;\n\t\t}\n\n\t\tvector<pair<Pii, Pii>> g[2];\n\t\tauto add_edge = [&](Pii a, Pii b) {\n\t\t\tif (a.first == b.first) g[0].emplace_back(a, b);\n\t\t\telse g[1].emplace_back(a, b);\n\t\t};\n\n\t\tFOR(i, n - 1) {\n\t\t\tPii tmp = { -1,-1 };\n\t\t\tFOR(j, m - 1) {\n\t\t\t\tint cur = f[i][j];\n\t\t\t\tif (cur == 15 - 1 || cur == 15 - 4) {\n\t\t\t\t\ttmp = Pii(i, j);\n\t\t\t\t} else if(cur == 15 - 2 || cur == 15 - 8) {\n\t\t\t\t\tif(tmp.first != -1) {\n\t\t\t\t\t\tadd_edge(tmp, Pii(i, j));\n\t\t\t\t\t\ttmp.first = -1;\n\t\t\t\t\t}\n\t\t\t\t} else if (cur == 15) {\n\t\t\t\t\tcontinue;\n\t\t\t\t} else {\n\t\t\t\t\ttmp.first = -1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tFOR(j, m - 1) {\n\t\t\tPii tmp = { -1,-1 };\n\t\t\tFOR(i, n - 1) {\n\t\t\t\tint cur = f[i][j];\n\t\t\t\tif (cur == 15 - 1 || cur == 15 - 2) {\n\t\t\t\t\ttmp = Pii(i, j);\n\t\t\t\t} else if (cur == 15 - 4 || cur == 15 - 8) {\n\t\t\t\t\tif (tmp.first != -1) {\n\t\t\t\t\t\tadd_edge(tmp, Pii(i, j));\n\t\t\t\t\t\ttmp.first = -1;\n\t\t\t\t\t}\n\t\t\t\t} else if (cur == 15) {\n\t\t\t\t\tcontinue;\n\t\t\t\t} else {\n\t\t\t\t\ttmp.first = -1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tvector<vector<int>> g2(sz(g[0]) + sz(g[1]));\n\t\tFOR(i, sz(g[0])) {\n\t\t\tFOR(j, sz(g[1])) {\n\t\t\t\tauto a = g[0][i].first, b = g[0][i].second;\n\t\t\t\tauto c = g[1][j].first, d = g[1][j].second;\n\n\t\t\t\tbool intersected1 = a.second <= c.second && c.second <= b.second;\n\t\t\t\tbool intersected2 = c.first <= a.first && a.first <= d.first;\n\t\t\t\tif (intersected1 && intersected2) {\n\t\t\t\t\tint u = i, v = sz(g[0]) + j;\n\t\t\t\t\tg2[u].push_back(v);\n\t\t\t\t\tg2[v].push_back(u);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tint matched = bipartite_matching(g2);\n\t\tint unmatched = sz(g2) - matched;\n\t\tint ans = specialCount - unmatched + 1;\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3872, "score_of_the_acc": -0.1288, "final_rank": 11 }, { "submission_id": "aoj_1185_3184682", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 8000\n#define SIZE 105\n\nenum Type{\n\tRight_Under,\n\tLeft_Under,\n\tRight_Up,\n\tLeft_Up,\n};\n\nstruct Edge{\n\tEdge(int arg_x1,int arg_y1, int arg_x2,int arg_y2){\n\t\tx1 = arg_x1;\n\t\ty1 = arg_y1;\n\t\tx2 = arg_x2;\n\t\ty2 = arg_y2;\n\t}\n\tint x1,y1,x2,y2;\n};\n\nint H,W;\nint V;\nvector<int> G[NUM];\nint match[NUM];\nbool used[NUM];\nbool check[SIZE][SIZE][4];\nchar base_map[SIZE][SIZE];\nvector<Edge> TATE,YOKO;\n\n\nvoid add_edge(int from,int to){\n\tG[from].push_back(to);\n\tG[to].push_back(from);\n}\n\nint dfs(int node_id){\n\tused[node_id] = true;\n\n\tfor(int i = 0; i < G[node_id].size(); i++){\n\t\tint adj_node_id = G[node_id][i],pair_id = match[adj_node_id];\n\t\tif((pair_id < 0)||\n\t\t\t\t(used[pair_id] == false && dfs(pair_id) == true)){\n\t\t\tmatch[node_id] = adj_node_id;\n\t\t\tmatch[adj_node_id] = node_id;\n\t\t\treturn true;\n\t\t}\n\t}\n\treturn false;\n}\n\n\nint bipartie_matching(){\n\tint ret = 0;\n\tfor(int i = 0; i < V; i++)match[i] = -1;\n\tfor(int node_id = 0; node_id < V; node_id++){\n\t\tif(match[node_id] < 0){\n\t\t\tfor(int i = 0; i < V; i++)used[i] = false;\n\t\t\tif(dfs(node_id)){\n\t\t\t\tret++;\n\t\t\t}\n\t\t}\n\t}\n\treturn ret;\n}\n\nbool rangeCheck(int row,int col){\n\tif(row >= 0 && row <= H-1 && col >= 0 && col <= W-1){\n\t\treturn true;\n\t}else{\n\t\treturn false;\n\t}\n}\n\nvoid func(){\n\n\tTATE.clear();\n\tYOKO.clear();\n\n\tfor(int x = 0; x <= W; x++){\n\t\tfor(int y = 0; y <= H; y++){\n\t\t\tfor(int a = 0; a < 4; a++){\n\t\t\t\tcheck[x][y][a] = false;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int row = 0; row < H; row++){\n\t\tscanf(\"%s\",base_map[row]);\n\t}\n\n\tint num_cut_point = 0;\n\tint tmp_x,tmp_y;\n\n\tfor(int row = 0; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\t\t\tif(base_map[row][col] == '#')continue;\n\n\t\t\t//Right_Under\n\t\t\tif(rangeCheck(row+1,col+1) == true && base_map[row][col+1] == '#' &&\n\t\t\t\t\tbase_map[row+1][col] == '#' && base_map[row+1][col+1] == '#'){\n\n\t\t\t\ttmp_x = col+1;\n\t\t\t\ttmp_y = row+1;\n\n\t\t\t\tcheck[tmp_x][tmp_y][Right_Under] = true;\n\n\t\t\t\tnum_cut_point++;\n\t\t\t}\n\n\t\t\t//Left_Under\n\t\t\tif(rangeCheck(row+1,col-1) == true && base_map[row][col-1] == '#' &&\n\t\t\t\t\tbase_map[row+1][col] == '#' && base_map[row+1][col-1] == '#'){\n\n\t\t\t\ttmp_x = col;\n\t\t\t\ttmp_y = row+1;\n\n\t\t\t\tcheck[tmp_x][tmp_y][Left_Under] = true;\n\n\t\t\t\tnum_cut_point++;\n\t\t\t}\n\n\t\t\t//Right_Up\n\t\t\tif(rangeCheck(row-1,col+1) == true && base_map[row-1][col] == '#' &&\n\t\t\t\t\tbase_map[row-1][col+1] == '#' && base_map[row][col+1] == '#'){\n\n\t\t\t\ttmp_x = col+1;\n\t\t\t\ttmp_y = row;\n\n\t\t\t\tcheck[tmp_x][tmp_y][Right_Up] = true;\n\n\t\t\t\tnum_cut_point++;\n\t\t\t}\n\n\t\t\t//Left_Up\n\t\t\tif(rangeCheck(row-1,col-1) == true && base_map[row-1][col] == '#' &&\n\t\t\t\t\tbase_map[row-1][col-1] == '#' && base_map[row][col-1] == '#'){\n\n\t\t\t\ttmp_x = col;\n\t\t\t\ttmp_y = row;\n\n\t\t\t\tcheck[tmp_x][tmp_y][Left_Up] = true;\n\n\t\t\t\tnum_cut_point++;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int y = 0; y <= H; y++){\n\t\tfor(int x = 0; x < W; x++){\n\n\t\t\tif(check[x][y][Right_Under] == true || check[x][y][Right_Up] == true){\n\n\t\t\t\tfor(int another = x+1; another <= W; another++){\n\n\t\t\t\t\tif(rangeCheck(y-1,another-1) == false || rangeCheck(y,another) == false ||\n\t\t\t\t\t\t\tbase_map[y-1][another-1] == '.' || base_map[y][another-1] == '.'){\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\n\t\t\t\t\tif(check[another][y][Left_Under] == true || check[another][y][Left_Up] == true){\n\t\t\t\t\t\tYOKO.push_back(Edge(x,y,another,y));\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int x = 0; x <= W; x++){\n\t\tfor(int y = 0; y < H; y++){\n\t\t\tif(check[x][y][Right_Under] == true || check[x][y][Left_Under] == true){\n\n\t\t\t\tfor(int another = y+1; another <= H; another++){\n\n\t\t\t\t\tif(rangeCheck(another-1,x-1) == false || rangeCheck(another-1,x) == false ||\n\t\t\t\t\t\t\tbase_map[another-1][x-1] == '.' || base_map[another-1][x] == '.'){\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\n\t\t\t\t\tif(check[x][another][Right_Up] == true || check[x][another][Left_Up] == true){\n\t\t\t\t\t\tTATE.push_back(Edge(x,y,x,another));\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tV = (int)TATE.size()+(int)YOKO.size();\n\n\tfor(int i = 0; i < NUM; i++){\n\t\tG[i].clear();\n\t}\n\n\tfor(int i = 0; i < YOKO.size(); i++){\n\t\tfor(int k = 0; k < TATE.size(); k++){\n\t\t\tif(TATE[k].x1 >= YOKO[i].x1 && TATE[k].x1 <= YOKO[i].x2 && YOKO[i].y1 >= TATE[k].y1 && YOKO[i].y1 <= TATE[k].y2){\n\t\t\t\tadd_edge(i,(int)YOKO.size()+k);\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",num_cut_point-(V-bipartie_matching())+1);\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d %d\",&H,&W);\n\t\tif(H == 0 && W == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3868, "score_of_the_acc": -0.0177, "final_rank": 2 } ]
aoj_1183_cpp
Chain-Confined Path There is a chain consisting of multiple circles on a plane. The first (last) circle of the chain only intersects with the next (previous) circle, and each intermediate circle intersects only with the two neighboring circles. Your task is to find the shortest path that satisfies the following conditions. The path connects the centers of the first circle and the last circle. The path is confined in the chain, that is, all the points on the path are located within or on at least one of the circles. Figure E-1 shows an example of such a chain and the corresponding shortest path. Figure E-1: An example chain and the corresponding shortest path Input The input consists of multiple datasets. Each dataset represents the shape of a chain in the following format. n x 1 y 1 r 1 x 2 y 2 r 2 ... x n y n r n The first line of a dataset contains an integer n (3 ≤ n ≤ 100) representing the number of the circles. Each of the following n lines contains three integers separated by a single space. ( x i , y i ) and r i represent the center position and the radius of the i -th circle C i . You can assume that 0 ≤ x i ≤ 1000, 0 ≤ y i ≤ 1000, and 1 ≤ r i ≤ 25. You can assume that C i and C i +1 (1 ≤ i ≤ n −1) intersect at two separate points. When j ≥ i +2, C i and C j are apart and either of them does not contain the other. In addition, you can assume that any circle does not contain the center of any other circle. The end of the input is indicated by a line containing a zero. Figure E-1 corresponds to the first dataset of Sample Input below. Figure E-2 shows the shortest paths for the subsequent datasets of Sample Input. Figure E-2: Example chains and the corresponding shortest paths Output For each dataset, output a single line containing the length of the shortest chain-confined path between the centers of the first circle and the last circle. The value should not have an error greater than 0.001. No extra characters should appear in the output. Sample Input 10 802 0 10 814 0 4 820 1 4 826 1 4 832 3 5 838 5 5 845 7 3 849 10 3 853 14 4 857 18 3 3 0 0 5 8 0 5 8 8 5 3 0 0 5 7 3 6 16 0 5 9 0 3 5 8 0 8 19 2 8 23 14 6 23 21 6 23 28 6 19 40 8 8 42 8 0 39 5 11 0 0 5 8 0 5 18 8 10 8 16 5 0 16 5 0 24 5 3 32 5 10 32 5 17 28 8 27 25 3 30 18 5 0 Output for the Sample Input 58.953437 11.414214 16.0 61.874812 63.195179
[ { "submission_id": "aoj_1183_10853933", "code_snippet": "/*\n * Author: xioumu\n * Created Time: 2012/7/20 10:46:25\n * File Name: e.cpp\n * solve: e.cpp\n */\n#include<cstdio>\n#include<cstring>\n#include<cstdlib>\n#include<cmath>\n#include<algorithm>\n#include<string>\n#include<map>\n#include<set>\nusing namespace std;\n#define sz(v) ((int)(v).size())\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n#define repf(i, a, b) for (int i = (a); i <= (b); ++i)\n#define repd(i, a, b) for (int i = (a); i >= (b); --i)\ntypedef long long lint;\nconst int maxint = -1u>>1;\nconst double esp = 1e-8;\nconst int maxn = 107;\nint sgn(double x){\n return (x > esp) - (x < -esp);\n}\ndouble sqr(double x){\n return x * x;\n}\nstruct point{\n double x, y;\n point(double _x = 0, double _y = 0) : x(_x), y(_y){}\n point operator + (const point& b) const{\n return point(x + b.x, y + b.y);\n }\n point operator - (const point& b) const{\n return point(x - b.x, y - b.y);\n }\n point operator * (const double &p) const{\n return point(x * p, y * p);\n }\n point operator / (const double &p) const{\n return point (x / p, y / p);\n }\n double operator * (const point& b) const{\n return x * b.y - b.x * y;\n }\n double len(){\n return sqrt(x * x + y * y);\n }\n point set(){\n double l = sqrt(x * x + y * y);\n return point(x / l, y / l); \n }\n void output(){\n printf(\"%f %f\\n\", x, y);\n }\n};\nint n;\ndouble r[maxn];\npoint cen[maxn], int_cir[maxn][3];\n//void cha(point a, point b, \nvoid inter_cir(int u, int v, point &p1, point &p2){\n point d0 = (cen[u] - cen[v]);\n point d1, d2;\n d1 = d0;\n d1 = point(d1.y, -d1.x);\n d2 = d1 * -1;\n double x1, x2, h;\n double a, b, c;\n a = r[v];\n b = r[u];\n c = (cen[v] - cen[u]).len();\n double coss = (c * c + a * a - b * b) / (2 * a * c);\n double sins = sqrt(1 - coss * coss);\n h = a * sins;\n x2 = a * coss; \n //x2 = sqrt(r[v] * r[v] - h * h);\n p1 = cen[v] + d0 * x2 / d0.len() + d1.set() * h;\n p2 = cen[v] + d0 * x2 / d0.len() + d2 * h / d2.len() ;\n //printf(\"%f\\n\", x2);\n //printf(\"(%f, %f)\\n\", (p1 - cen[v]).len(), (p1 - cen[u]).len() );\n //printf(\"(%f, %f)\\n\", (p2 - cen[v]).len(), (p2 - cen[u]).len() );\n\n}\n\nvoid getpoint(){\n point p1, p2; \n repf (i, 1, n - 1){\n inter_cir(i - 1, i, p1, p2); \n int_cir[i][0] = p1;\n int_cir[i][1] = p2; \n }\n int_cir[0][0] = int_cir[0][1] = cen[0];\n int_cir[n][0] = int_cir[n][1] = cen[n - 1];\n\n //for(int i = 1; i <= n; i++)\n //for(int j = 0; j < 2; j++)\n //int_cir[i][j].output();\n}\n\ndouble get_h(point o, point a, point b){\n //a = a + (b - a).set() * 100;\n //b = b + (a - b).set() * 100;\n return fabs((a - o) * (b - o)) / (a - b).len();\n}\n\nbool across(int w, point a, point b){\n double h = get_h(cen[w], a, b);\n if(sgn(r[w] - h) <= 0) return false;\n else return true;\n}\n\nvoid get_int(int w, point a, point b, point& p1, point& p2){\n double h = get_h(cen[w], a, b);\n double x1 = sqrt( sqr( (a - cen[w]).len() ) - sqr(h) );\n double x2 = sqrt( sqr(r[w]) - sqr(h) );\n p1 = a + (b - a).set() * (x1 - x2);\n p2 = a + (b - a).set() * (x1 + x2);\n //printf(\"(%f,%f)\\n\", (p1 - cen[w]).len(), (p2 - cen[w]).len());\n}\n\nbool in(point a, int w){\n return sgn( r[w] - (a - cen[w]).len() ) > 0;\n}\n\nbool connect(int w, int r, point a, point b){\n //if(r == 0 && w == 2){\n //printf(\"%d %d %.8f\\n\", r, w, (a - b).len() );\n //a.output();\n //b.output();\n //cen[1].output();\n //printf(\"## %.8f ##\\n\\n\", get_h(cen[1], a, b));\n //}\n for(int i = r; i < w; i++)\n if( !across(i, a, b) ){\n //if(i == 1 && r == 1 && w == 2){\n //printf(\"---\\n\");\n //printf(\"%d %d %f\\n\", r, w, (a - b).len());\n //a.output();\n //b.output();\n //cen[i].output();\n //printf(\"%f\\n%f\\n\", fabs( (a - cen[i]) * (b - cen[i])) , (a -cen[i]).len() );\n //printf(\"%.8f\\n\", fabs( (a - cen[i]) * (b - cen[i])) * 1.0 / (a -b).len());\n //printf(\"## %f ##\\n\\n\", get_h(cen[i], a, b));\n //}\n return false;\n }\n for(int i = r; i < w - 1; i++){\n point p[5];\n get_int(i, a, b, p[1], p[2]);\n get_int(i + 1, a, b, p[3], p[4]);\n for(int j = 1; j <= 2; j++)\n for(int k = 3; k <= 4; k++)\n if( !in( ( p[j] + p[k]) / 2, i) && !in( (p[j] + p[k]) / 2, i + 1) )\n return false;\n }\n return true;\n}\ndouble dis[maxn][3][maxn][3];\nvoid getline(){\n repf(i, 0, n + 1)\n repf(ki, 0, 1)\n repf(j, 0, n + 1)\n repf(kj, 0, 1)\n dis[i][ki][j][kj] = 1e100;\n for(int i = 1; i <= n; i++)\n for(int ki = 0; ki <= 1; ki++)\n for(int j = 0; j < i; j++){\n for(int kj = 0; kj <= 1; kj++){\n //printf(\"+===%f=====\\n\",dis[j][kj][i][ki]);\n if( connect(i, j, int_cir[i][ki], int_cir[j][kj]) ) {\n dis[i][ki][j][kj] = (int_cir[i][ki] - int_cir[j][kj]).len();\n dis[j][kj][i][ki] = dis[i][ki][j][kj];\n //if(i == 2 && j == 1) printf(\"+===%f=====\\n\",dis[j][kj][i][ki]);\n }\n }\n }\n}\nvoid init(){\n rep (i, n){\n double x, y;\n scanf(\"%lf%lf%lf\\n\", &x, &y, &r[i]); \n cen[i] = point(x, y);\n }\n}\ndouble dp[maxn][3];\nvoid getdp(){\n repf(i, 0, n)\n repf(j, 0, 1)\n dp[i][j] = 1e100;\n dp[0][0] = 0;\n for(int i = 1; i <= n; i++)\n for(int ki = 0; ki <= 1; ki++)\n for(int j = 0; j < i; j++)\n for(int kj = 0; kj <= 1; kj++)\n if(dp[i][ki] > dp[j][kj] + dis[i][ki][j][kj]){\n dp[i][ki] = dp[j][kj] + dis[i][ki][j][kj];\n //if(i == 2 && j == 1)\n //printf(\" %d %d+===%f=====\\n\", j, i, dis[j][kj][i][ki]);\n }\n //printf(\"========================\\n\");\n //for(int i = 0; i <= n; i++, printf(\"\\n\"))\n //for(int ki = 0; ki <= 1; ki++)\n //printf(\"%f \", dp[i][ki]);\n printf(\"%f\\n\",dp[n][0]);\n}\nint main(){\n while(scanf(\"%d\", &n) && n){\n init();\n getpoint();\n getline();\n getdp();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3792, "score_of_the_acc": -0.3021, "final_rank": 4 }, { "submission_id": "aoj_1183_10482241", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ld = long double;\n#undef long\n#define long long long\n#define ll long\n#define vec vector\n#define rep(i, n) for (long i = 0; i < n; i++)\n#define all(a) begin(a), end(a)\n#define sz(a) (int)(a).size()\ntemplate <typename T>\nbool chmin(T &x, T y)\n{\n if (y < x)\n {\n x = y;\n return true;\n }\n return false;\n}\ntemplate <typename T>\nbool chmax(T &x, T y)\n{\n if (x < y)\n {\n x = y;\n return true;\n }\n return false;\n}\ntemplate <typename T>\nostream &operator<<(ostream &os, vector<T> a)\n{\n const int n = a.size();\n rep(i, n)\n {\n os << a[i];\n if (i + 1 != n)\n os << \" \";\n }\n return os;\n}\nusing R = ld;\nusing point = complex<R>;\nconst R EPS(1e-10), PI(acosl(-1)), INF(1e18);\ninline bool eq(const R &a, const R &b) { return fabsl(b - a) < EPS; }\ninline int compare(const R &a, const R &b) { return eq(a, b) ? 0 : a < b ? -1\n : 1; }\nstruct circle\n{\n point center;\n R radius;\n circle() = default;\n circle(const point &center, const R &radius) : center(center), radius(radius) {}\n friend std::ostream &operator<<(std::ostream &os, const circle &c)\n {\n return os << '(' << c.center << \", \" << c.radius << ')';\n }\n friend std::istream &operator>>(std::istream &is, circle &c) { return is >> c.center >> c.radius; }\n};\nusing points = vec<point>;\npoints crosspoints(const circle &c1, const circle &c2)\n{\n R d = abs(c1.center - c2.center);\n if (compare(d, c1.radius + c2.radius) == 1)\n return points(0);\n if (compare(d, fabsl(c1.radius - c2.radius)) == -1)\n return points(0);\n bool one_crosspoint = false;\n if (eq(d, c1.radius + c2.radius) || eq(d, fabsl(c1.radius - c2.radius)))\n one_crosspoint = true;\n const R alpha =\n acosl((c1.radius * c1.radius + d * d - c2.radius * c2.radius) / (2 * c1.radius * d)); // cosine theorem\n const R beta = std::arg(c2.center - c1.center);\n if (one_crosspoint)\n return points{c1.center + std::polar(c1.radius, beta + alpha)};\n return points{c1.center + std::polar(c1.radius, beta + alpha), c1.center + std::polar(c1.radius, beta - alpha)};\n}\nstruct segment;\nstruct line\n{\n point a, b;\n line() = default;\n line(const point &a, const point &b) : a(a), b(b) {}\n // Ax + By + C = 0\n line(const R &A, const R &B, const R &C)\n {\n if (eq(A, 0))\n {\n assert(!eq(B, 0));\n a = point(0, -C / B), b = point(1, -(A + C) / B);\n }\n else\n {\n a = point(-C / A, 0), b = point(-(B + C) / A, 1);\n }\n }\n explicit line(const segment &seg);\n friend std::ostream &operator<<(std::ostream &os, const line &ln)\n {\n return os << '(' << ln.a << \" -- \" << ln.b << ')';\n }\n friend std::istream &operator>>(std::istream &is, line &a) { return is >> a.a >> a.b; }\n};\nstruct segment\n{\n point a, b;\n segment() = default;\n segment(const point &a, const point &b) : a(a), b(b) {}\n explicit segment(const line &ln) : a(ln.a), b(ln.b) {}\n friend std::ostream &operator<<(std::ostream &os, const segment &seg)\n {\n return os << '[' << seg.a << \" -- \" << seg.b << ']';\n }\n friend std::istream &operator>>(std::istream &is, segment &a) { return is >> a.a >> a.b; }\n};\nline::line(const segment &seg) : a(seg.a), b(seg.b) {}\nR dot(const point &a, const point &b) { return real(a) * real(b) + imag(a) * imag(b); }\nusing arrow = point;\n\ninline int sgn(const R &x) { return fabsl(x) < EPS ? 0 : (x < 0 ? -1 : 1); }\npoint projection(const line &l, const point &p)\n{\n return l.a + (l.a - l.b) * dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n}\npoints crosspoints(const circle &c, const line &l)\n{\n const point pr = projection(l, c.center);\n const R square = c.radius * c.radius - norm(pr - c.center);\n switch (sgn(square))\n {\n case 0:\n return points{pr};\n case -1:\n return points(0);\n }\n const arrow v = (l.b - l.a) / abs(l.b - l.a) * sqrt(square);\n return points{pr - v, pr + v};\n}\nenum CCW\n{\n ONLINE_FRONT = -2, // a,b,c が一直線上\n CLOCKWISE = -1, // c が a,b から時計回り側\n ON_SEGMENT = 0, // a,c,b が一直線上\n COUNTER_CLOCKWISE = 1, // c が a,b から反時計回り側\n ONLINE_BACK = 2, // c,a,b が一直線上\n};\nR cross(const point &a, const point &b) { return real(a) * imag(b) - imag(a) * real(b); }\nint ccw(const point &a, point b, point c)\n{\n b -= a, c -= a;\n const R crs_b_c = cross(b, c);\n if (crs_b_c > EPS)\n return CCW::COUNTER_CLOCKWISE;\n if (crs_b_c < -EPS)\n return CCW::CLOCKWISE;\n if (dot(b, c) < -EPS)\n return CCW::ONLINE_BACK;\n if (norm(b) + EPS < norm(c))\n return CCW::ONLINE_FRONT;\n return CCW::ON_SEGMENT;\n}\nint intersect(const segment &s, const point &p) { return int(ccw(s.a, s.b, p) == CCW::ON_SEGMENT); }\npoints crosspoints(const circle &c, const segment &s)\n{\n points ret;\n for (const auto &pt : crosspoints(c, line(s)))\n if (intersect(s, pt))\n ret.push_back(pt);\n return ret;\n}\nvoid solve()\n{\n while (true)\n {\n int n;\n cin >> n;\n if (n == 0)\n return;\n vec<circle> a(n);\n rep(i, n)\n {\n R x, y, r;\n cin >> x >> y >> r;\n a[i] = {{x, y}, r};\n }\n vec<points> b(n - 1);\n rep(i, n - 1)\n {\n b[i] = crosspoints(a[i], a[i + 1]);\n assert(sz(b[i]) == 2);\n }\n vec<vec<R>> d(n - 1, vec<R>(2, INF));\n R ans = INF;\n rep(i, n - 1)\n {\n rep(c0, 2)\n {\n { // 最初の円から\n segment seg = {a[0].center, b[i][c0]};\n bool ok = true;\n vec<pair<R, bool>> res;\n res.emplace_back(0, true);\n res.emplace_back(a[0].radius, false);\n res.emplace_back(abs(seg.a - seg.b), true);\n for (int k = 1; k <= i; k++)\n {\n auto c = crosspoints(a[k], seg);\n if (sz(c) != 2)\n {\n ok = false;\n break;\n }\n R d1 = abs(c[0] - a[0].center), d2 = abs(c[1] - a[0].center);\n if (d1 > d2)\n swap(d1, d2);\n res.emplace_back(d1, true);\n res.emplace_back(d2, false);\n }\n sort(all(res), [](pair<R, bool> &a, pair<R, bool> &b)\n {\n if(abs(a.first - b.first ) < EPS) return a.second ;\n return a.first < b.first; });\n int cnt = 0;\n for (auto [_, v] : res)\n {\n if (v)\n cnt++;\n else\n cnt--;\n ok &= cnt > 0;\n }\n if (ok)\n chmin(d[i][c0], abs(a[0].center - b[i][c0]));\n }\n rep(j, i) rep(c1, 2)\n {\n segment seg = {b[i][c0], b[j][c1]};\n bool ok = true;\n vec<pair<R, bool>> res;\n res.emplace_back(abs(seg.a - seg.b), true);\n for (int k = j + 1; k <= i; k++)\n {\n auto c = crosspoints(a[k], seg);\n if (sz(c) != 2)\n {\n ok = false;\n break;\n }\n R d1 = abs(c[0] - seg.a), d2 = abs(c[1] - seg.a);\n if (d1 > d2)\n swap(d1, d2);\n res.emplace_back(d1, true);\n res.emplace_back(d2, false);\n }\n sort(all(res), [](pair<R, bool> &a, pair<R, bool> &b)\n {\n if(abs(a.first - b.first ) < EPS) return a.second ;\n return a.first < b.first; });\n int cnt = 0;\n for (auto [_, v] : res)\n {\n if (v)\n cnt++;\n else\n cnt--;\n ok &= cnt > 0;\n }\n if (ok)\n chmin(d[i][c0], d[j][c1] + abs(seg.a - seg.b));\n }\n }\n R dm = abs(b[i][0] - b[i][1]);\n rep(c0, 2) chmin(d[i][c0], d[i][1 - c0] + dm);\n rep(c0, 2) // 最後の円へ\n {\n segment seg = {b[i][c0], a[n - 1].center};\n bool ok = true;\n vec<pair<R, bool>> res;\n res.emplace_back(abs(seg.a - seg.b) - a[n - 1].radius, true);\n for (int k = i + 1; k < n - 1; k++)\n {\n auto c = crosspoints(a[k], seg);\n if (sz(c) != 2)\n {\n ok = false;\n break;\n }\n R d1 = abs(c[0] - seg.a), d2 = abs(c[1] - seg.a);\n if (d1 > d2)\n swap(d1, d2);\n res.emplace_back(d1, true);\n res.emplace_back(d2, false);\n }\n sort(all(res), [](pair<R, bool> &a, pair<R, bool> &b)\n {\n if(abs(a.first - b.first ) < EPS) return a.second ;\n return a.first < b.first; });\n int cnt = 0;\n for (auto [_, v] : res)\n {\n if (v)\n cnt++;\n else\n cnt--;\n ok &= cnt > 0;\n }\n if (ok)\n chmin(ans, d[i][c0] + abs(seg.a - seg.b));\n }\n }\n {\n segment seg = {a[0].center, a[n - 1].center};\n bool ok = true;\n vec<pair<R, bool>> res;\n res.emplace_back(0, true);\n res.emplace_back(a[0].radius, false);\n res.emplace_back(abs(seg.a - seg.b) - a[n - 1].radius, true);\n for (int k = 1; k < n - 1; k++)\n {\n auto c = crosspoints(a[k], seg);\n if (sz(c) != 2)\n {\n ok = false;\n break;\n }\n R d1 = abs(c[0] - seg.a), d2 = abs(c[1] - seg.a);\n if (d1 > d2)\n swap(d1, d2);\n res.emplace_back(d1, true);\n res.emplace_back(d2, false);\n }\n sort(all(res), [](pair<R, bool> &a, pair<R, bool> &b)\n {\n if(abs(a.first - b.first ) < EPS) return a.second ;\n return a.first < b.first; });\n int cnt = 0;\n for (auto [_, v] : res)\n {\n if (v)\n cnt++;\n else\n cnt--;\n ok &= cnt > 0;\n }\n if (ok)\n chmin(ans, abs(seg.a - seg.b));\n }\n cout << ans << '\\n';\n }\n}\nint main()\n{\n cin.tie(0)->sync_with_stdio(0), cout.tie(0);\n cout << fixed << setprecision(20);\n int t = 1;\n // cin >> t;\n while (t--)\n solve();\n}", "accuracy": 1, "time_ms": 580, "memory_kb": 3996, "score_of_the_acc": -0.9073, "final_rank": 17 }, { "submission_id": "aoj_1183_10482069", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ld = long double;\n#undef long\n#define long long long\n#define ll long\n#define vec vector\n#define rep(i, n) for (long i = 0; i < n; i++)\n#define all(a) begin(a), end(a)\n#define sz(a) (int)(a).size()\ntemplate <typename T>\nbool chmin(T &x, T y)\n{\n if (y < x)\n {\n x = y;\n return true;\n }\n return false;\n}\ntemplate <typename T>\nbool chmax(T &x, T y)\n{\n if (x < y)\n {\n x = y;\n return true;\n }\n return false;\n}\ntemplate <typename T>\nostream &operator<<(ostream &os, vector<T> a)\n{\n const int n = a.size();\n rep(i, n)\n {\n os << a[i];\n if (i + 1 != n)\n os << \" \";\n }\n return os;\n}\nusing R = ld;\nusing point = complex<R>;\nconst R EPS(1e-10), PI(acosl(-1)), INF(1e18);\ninline bool eq(const R &a, const R &b) { return fabsl(b - a) < EPS; }\ninline int compare(const R &a, const R &b) { return eq(a, b) ? 0 : a < b ? -1\n : 1; }\nstruct circle\n{\n point center;\n R radius;\n circle() = default;\n circle(const point &center, const R &radius) : center(center), radius(radius) {}\n friend std::ostream &operator<<(std::ostream &os, const circle &c)\n {\n return os << '(' << c.center << \", \" << c.radius << ')';\n }\n friend std::istream &operator>>(std::istream &is, circle &c) { return is >> c.center >> c.radius; }\n};\nusing points = vec<point>;\npoints crosspoints(const circle &c1, const circle &c2)\n{\n R d = abs(c1.center - c2.center);\n if (compare(d, c1.radius + c2.radius) == 1)\n return points(0);\n if (compare(d, fabsl(c1.radius - c2.radius)) == -1)\n return points(0);\n bool one_crosspoint = false;\n if (eq(d, c1.radius + c2.radius) || eq(d, fabsl(c1.radius - c2.radius)))\n one_crosspoint = true;\n const R alpha =\n acosl((c1.radius * c1.radius + d * d - c2.radius * c2.radius) / (2 * c1.radius * d)); // cosine theorem\n const R beta = std::arg(c2.center - c1.center);\n if (one_crosspoint)\n return points{c1.center + std::polar(c1.radius, beta + alpha)};\n return points{c1.center + std::polar(c1.radius, beta + alpha), c1.center + std::polar(c1.radius, beta - alpha)};\n}\nstruct segment;\nstruct line\n{\n point a, b;\n line() = default;\n line(const point &a, const point &b) : a(a), b(b) {}\n // Ax + By + C = 0\n line(const R &A, const R &B, const R &C)\n {\n if (eq(A, 0))\n {\n assert(!eq(B, 0));\n a = point(0, -C / B), b = point(1, -(A + C) / B);\n }\n else\n {\n a = point(-C / A, 0), b = point(-(B + C) / A, 1);\n }\n }\n explicit line(const segment &seg);\n friend std::ostream &operator<<(std::ostream &os, const line &ln)\n {\n return os << '(' << ln.a << \" -- \" << ln.b << ')';\n }\n friend std::istream &operator>>(std::istream &is, line &a) { return is >> a.a >> a.b; }\n};\nstruct segment\n{\n point a, b;\n segment() = default;\n segment(const point &a, const point &b) : a(a), b(b) {}\n explicit segment(const line &ln) : a(ln.a), b(ln.b) {}\n friend std::ostream &operator<<(std::ostream &os, const segment &seg)\n {\n return os << '[' << seg.a << \" -- \" << seg.b << ']';\n }\n friend std::istream &operator>>(std::istream &is, segment &a) { return is >> a.a >> a.b; }\n};\nline::line(const segment &seg) : a(seg.a), b(seg.b) {}\nR dot(const point &a, const point &b) { return real(a) * real(b) + imag(a) * imag(b); }\nusing arrow = point;\n\ninline int sgn(const R &x) { return fabsl(x) < EPS ? 0 : (x < 0 ? -1 : 1); }\npoint projection(const line &l, const point &p)\n{\n return l.a + (l.a - l.b) * dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n}\npoints crosspoints(const circle &c, const line &l)\n{\n const point pr = projection(l, c.center);\n const R square = c.radius * c.radius - norm(pr - c.center);\n switch (sgn(square))\n {\n case 0:\n return points{pr};\n case -1:\n return points(0);\n }\n const arrow v = (l.b - l.a) / abs(l.b - l.a) * sqrtl(square);\n return points{pr - v, pr + v};\n}\nenum CCW\n{\n ONLINE_FRONT = -2, // a,b,c が一直線上\n CLOCKWISE = -1, // c が a,b から時計回り側\n ON_SEGMENT = 0, // a,c,b が一直線上\n COUNTER_CLOCKWISE = 1, // c が a,b から反時計回り側\n ONLINE_BACK = 2, // c,a,b が一直線上\n};\nR cross(const point &a, const point &b) { return real(a) * imag(b) - imag(a) * real(b); }\nint ccw(const point &a, point b, point c)\n{\n b -= a, c -= a;\n const R crs_b_c = cross(b, c);\n if (crs_b_c > EPS)\n return CCW::COUNTER_CLOCKWISE;\n if (crs_b_c < -EPS)\n return CCW::CLOCKWISE;\n if (dot(b, c) < -EPS)\n return CCW::ONLINE_BACK;\n if (norm(b) + EPS < norm(c))\n return CCW::ONLINE_FRONT;\n return CCW::ON_SEGMENT;\n}\nint intersect(const segment &s, const point &p) { return int(ccw(s.a, s.b, p) == CCW::ON_SEGMENT); }\npoints crosspoints(const circle &c, const segment &s)\n{\n points ret;\n for (const auto &pt : crosspoints(c, line(s)))\n if (intersect(s, pt))\n ret.push_back(pt);\n return ret;\n}\nvoid solve()\n{\n while (true)\n {\n int n;\n cin >> n;\n if (n == 0)\n return;\n vec<circle> a(n);\n rep(i, n)\n {\n R x, y, r;\n cin >> x >> y >> r;\n a[i] = {{x, y}, r};\n }\n vec<points> b(n - 1);\n rep(i, n - 1)\n {\n b[i] = crosspoints(a[i], a[i + 1]);\n assert(sz(b[i]) == 2);\n }\n vec<vec<R>> d(n - 1, vec<R>(2, INF));\n R ans = INF;\n rep(i, n - 1)\n {\n rep(c0, 2)\n {\n { // 最初の円から\n segment seg = {a[0].center, b[i][c0]};\n bool ok = true;\n vec<pair<R, bool>> res;\n res.emplace_back(0, true);\n res.emplace_back(a[0].radius, false);\n res.emplace_back(abs(seg.a - seg.b), true);\n for (int k = 1; k <= i; k++)\n {\n auto c = crosspoints(a[k], seg);\n if (sz(c) != 2)\n {\n ok = false;\n break;\n }\n R d1 = abs(c[0] - a[0].center), d2 = abs(c[1] - a[0].center);\n if (d1 > d2)\n swap(d1, d2);\n res.emplace_back(d1, true);\n res.emplace_back(d2, false);\n }\n sort(all(res), [](pair<R, bool> &a, pair<R, bool> &b)\n {\n if(abs(a.first - b.first ) < EPS) return a.second ;\n return a.first < b.first; });\n int cnt = 0;\n for (auto [_, v] : res)\n {\n if (v)\n cnt++;\n else\n cnt--;\n ok &= cnt > 0;\n }\n if (ok)\n chmin(d[i][c0], abs(a[0].center - b[i][c0]));\n }\n rep(j, i) rep(c1, 2)\n {\n segment seg = {b[i][c0], b[j][c1]};\n bool ok = true;\n vec<pair<R, bool>> res;\n res.emplace_back(abs(seg.a - seg.b), true);\n for (int k = j + 1; k <= i; k++)\n {\n auto c = crosspoints(a[k], seg);\n if (sz(c) != 2)\n {\n ok = false;\n break;\n }\n R d1 = abs(c[0] - seg.a), d2 = abs(c[1] - seg.a);\n if (d1 > d2)\n swap(d1, d2);\n res.emplace_back(d1, true);\n res.emplace_back(d2, false);\n }\n sort(all(res), [](pair<R, bool> &a, pair<R, bool> &b)\n {\n if(abs(a.first - b.first ) < EPS) return a.second ;\n return a.first < b.first; });\n int cnt = 0;\n for (auto [_, v] : res)\n {\n if (v)\n cnt++;\n else\n cnt--;\n ok &= cnt > 0;\n }\n if (ok)\n chmin(d[i][c0], d[j][c1] + abs(seg.a - seg.b));\n }\n }\n R dm = abs(b[i][0] - b[i][1]);\n rep(c0, 2) chmin(d[i][c0], d[i][1 - c0] + dm);\n rep(c0, 2) // 最後の円へ\n {\n segment seg = {b[i][c0], a[n - 1].center};\n bool ok = true;\n vec<pair<R, bool>> res;\n res.emplace_back(abs(seg.a - seg.b) - a[n - 1].radius, true);\n for (int k = i + 1; k < n - 1; k++)\n {\n auto c = crosspoints(a[k], seg);\n if (sz(c) != 2)\n {\n ok = false;\n break;\n }\n R d1 = abs(c[0] - seg.a), d2 = abs(c[1] - seg.a);\n if (d1 > d2)\n swap(d1, d2);\n res.emplace_back(d1, true);\n res.emplace_back(d2, false);\n }\n sort(all(res), [](pair<R, bool> &a, pair<R, bool> &b)\n {\n if(abs(a.first - b.first ) < EPS) return a.second ;\n return a.first < b.first; });\n int cnt = 0;\n for (auto [_, v] : res)\n {\n if (v)\n cnt++;\n else\n cnt--;\n ok &= cnt > 0;\n }\n if (ok)\n chmin(ans, d[i][c0] + abs(seg.a - seg.b));\n }\n }\n {\n segment seg = {a[0].center, a[n - 1].center};\n bool ok = true;\n vec<pair<R, bool>> res;\n res.emplace_back(0, true);\n res.emplace_back(a[0].radius, false);\n res.emplace_back(abs(seg.a - seg.b) - a[n - 1].radius, true);\n for (int k = 1; k < n - 1; k++)\n {\n auto c = crosspoints(a[k], seg);\n if (sz(c) != 2)\n {\n ok = false;\n break;\n }\n R d1 = abs(c[0] - seg.a), d2 = abs(c[1] - seg.a);\n if (d1 > d2)\n swap(d1, d2);\n res.emplace_back(d1, true);\n res.emplace_back(d2, false);\n }\n sort(all(res), [](pair<R, bool> &a, pair<R, bool> &b)\n {\n if(abs(a.first - b.first ) < EPS) return a.second ;\n return a.first < b.first; });\n int cnt = 0;\n for (auto [_, v] : res)\n {\n if (v)\n cnt++;\n else\n cnt--;\n ok &= cnt > 0;\n }\n if (ok)\n chmin(ans, abs(seg.a - seg.b));\n }\n cout << ans << '\\n';\n }\n}\nint main()\n{\n cin.tie(0)->sync_with_stdio(0), cout.tie(0);\n cout << fixed << setprecision(20);\n int t = 1;\n // cin >> t;\n while (t--)\n solve();\n}", "accuracy": 1, "time_ms": 580, "memory_kb": 3884, "score_of_the_acc": -0.78, "final_rank": 14 }, { "submission_id": "aoj_1183_9878122", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<long long, long long>;\n#define rep(i, a, b) for(long long i = (a); i < (b); ++i)\n#define rrep(i, a, b) for(long long i = (a); i >= (b); --i)\nconstexpr long long inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\nusing Real = long double;\nconstexpr Real EPS = Real(1e-8), PI = 3.141592653589793238462643383279L;\nint sign(const Real& r) {\n if(r <= -EPS) return -1;\n if(r >= +EPS) return +1;\n return 0;\n}\nbool eq(const Real& a, const Real& b) {\n return sign(a - b) == 0;\n}\nusing Point = complex<Real>;\nistream& operator>>(istream& is, Point& p) {\n Real a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n}\nostream& operator<<(ostream& os, const Point& p) {\n return os << p.real() << \" \" << p.imag();\n}\nPoint operator*(const Point& p, const Real& d) {\n return Point(p.real() * d, p.imag() * d);\n}\nPoint operator/(const Point& p, const Real& d) {\n return Point(p.real() / d, p.imag() / d);\n}\nPoint rot(const Point& p, const Real& theta) {\n return p * Point(cos(theta), sin(theta));\n}\nReal dot(const Point& p1, const Point& p2) {\n return (conj(p1) * p2).real();\n}\nReal cross(const Point& p1, const Point& p2) {\n return (conj(p1) * p2).imag();\n}\nReal dist(const Point& p1, const Point& p2) {\n return abs(p1 - p2);\n}\nbool comp_x(const Point& p1, const Point& p2) {\n return eq(p1.real(), p2.real()) ? p1.imag() < p2.imag() : p1.real() < p2.real();\n}\nbool comp_y(const Point& p1, const Point& p2) {\n return eq(p1.imag(), p2.imag()) ? p1.real() < p2.real() : p1.imag() < p2.imag();\n}\nbool comp_arg(const Point& p1, const Point& p2) {\n return arg(p1) < arg(p2);\n}\nint ccw(const Point& a, Point b, Point c) {\n b -= a;\n c -= a;\n if(sign(cross(b, c)) == 1) return 1;\n if(sign(cross(b, c)) == -1) return -1;\n if(sign(dot(b, c)) == -1) return +2;\n if(norm(b) < norm(c)) return -2;\n return 0;\n}\nReal closest_pair(vector<Point> ps) {\n if((int)ps.size() <= 1) return Real(1e18);\n sort(ps.begin(), ps.end(), comp_x);\n vector<Point> memo(ps.size());\n auto func = [&](const auto& func, const int l, const int r) -> Real {\n if(r - l <= 1) return Real(1e18);\n const int m = (l + r) >> 1;\n const Real x = ps[m].real();\n Real res = min(func(func, l, m), func(func, m, r));\n inplace_merge(ps.begin() + l, ps.begin() + m, ps.begin() + r, comp_y);\n int cnt = 0;\n for(int i = l; i < r; ++i) {\n if(abs(ps[i].real() - x) >= res) continue;\n for(int j = 0; j < cnt; ++j) {\n const Point d = ps[i] - memo[cnt - j - 1];\n if(d.imag() >= res) break;\n res = min(res, abs(d));\n }\n memo[cnt++] = ps[i];\n }\n return res;\n };\n return func(func, 0, (int)ps.size());\n}\nstruct Line {\n Point a, b;\n Line() = default;\n Line(const Point& a, const Point& b)\n : a(a), b(b) {}\n};\nusing Segment = Line;\nbool is_parallel(const Line& a, const Line& b) {\n return eq(cross(a.b - a.a, b.b - b.a), 0.0);\n}\nbool is_orthogonal(const Line& a, const Line& b) {\n return eq(dot(a.b - a.a, b.b - b.a), 0.0);\n}\nPoint projection(const Line& l, const Point& p) {\n Real t = dot(p - l.a, l.b - l.a) / norm(l.b - l.a);\n return l.a + (l.b - l.a) * t;\n}\nPoint reflection(const Line& l, const Point& p) {\n return p + (projection(l, p) - p) * 2.0;\n}\nbool is_intersect_lp(const Line& l, const Point& p) {\n return abs(ccw(l.a, l.b, p)) != 1;\n}\nbool is_intersect_sp(const Segment& s, const Point& p) {\n return ccw(s.a, s.b, p) == 0;\n}\nbool is_intersect_ll(const Line& l1, const Line& l2) {\n if(!eq(cross(l1.b - l1.a, l2.b - l2.a), 0.0)) return true;\n return eq(cross(l1.b - l1.a, l2.b - l1.a), 0.0);\n}\nbool is_intersect_ls(const Line& l, const Segment& s) {\n return sign(cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a)) <= 0;\n}\nbool is_intersect_sl(const Segment& s, const Line& l) {\n return is_intersect_ls(l, s);\n}\nbool is_intersect_ss(const Segment& s1, const Segment& s2) {\n if(ccw(s1.a, s1.b, s2.a) * ccw(s1.a, s1.b, s2.b) > 0) return false;\n return ccw(s2.a, s2.b, s1.a) * ccw(s2.a, s2.b, s1.b) <= 0;\n}\nvector<Point> intersection_ll(const Line& l1, const Line& l2) {\n vector<Point> res;\n if(!is_intersect_ll(l1, l2)) return res;\n Real a = cross(l1.b - l1.a, l2.b - l2.a);\n Real b = cross(l1.b - l1.a, l1.b - l2.a);\n if(eq(a, 0.0) and eq(b, 0.0)) {\n res.emplace_back(l2.a);\n } else {\n res.emplace_back(l2.a + (l2.b - l2.a) * b / a);\n }\n return res;\n}\nvector<Point> intersection_ss(const Segment& s1, const Segment& s2) {\n return is_intersect_ss(s1, s2) ? intersection_ll(Line(s1), Line(s2)) : vector<Point>();\n}\nReal dist_lp(const Line& l, const Point& p) {\n return abs(p - projection(l, p));\n}\nReal dist_sp(const Segment& s, const Point& p) {\n const Point h = projection(s, p);\n if(is_intersect_sp(s, h)) return abs(h - p);\n return min(abs(s.a - p), abs(s.b - p));\n}\nReal dist_ll(const Line& l1, const Line& l2) {\n if(is_intersect_ll(l1, l2)) return 0.0;\n return dist_lp(l1, l2.a);\n}\nReal dist_ss(const Segment& s1, const Segment& s2) {\n if(is_intersect_ss(s1, s2)) return 0.0;\n return min({dist_sp(s1, s2.a), dist_sp(s1, s2.b), dist_sp(s2, s1.a), dist_sp(s2, s1.b)});\n}\nReal dist_ls(const Line& l, const Segment& s) {\n if(is_intersect_ls(l, s)) return 0.0;\n return min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\nReal dist_sl(const Segment& s, const Line& l) {\n return dist_ls(l, s);\n}\nstruct Circle {\n Point p;\n Real r;\n Circle() = default;\n Circle(const Point& p, const Real& r)\n : p(p), r(r) {}\n};\nbool is_intersect_cp(const Circle& c, const Point& p) {\n return eq(abs(p - c.p), c.r);\n}\nbool is_intersect_cl(const Circle& c, const Line& l) {\n return sign(c.r - dist_lp(l, c.p)) >= 0;\n}\nint is_intersect_cc(Circle c1, Circle c2) {\n if(c1.r < c2.r) swap(c1, c2);\n const Real d = abs(c1.p - c2.p);\n const int a = sign(d - c1.r - c2.r);\n if(a >= 0) return a + 3;\n return sign(d - c1.r + c2.r) + 1;\n}\nvector<Point> intersection_cl(const Circle& c, const Line& l) {\n const Point h = projection(l, c.p);\n const Point e = (l.b - l.a) / abs(l.b - l.a);\n vector<Point> res;\n if(!is_intersect_cl(c, l)) return res;\n if(eq(dist_lp(l, c.p), c.r)) {\n res.emplace_back(h);\n } else {\n const Real b = sqrt(c.r * c.r - norm(h - c.p));\n res.emplace_back(h - e * b);\n res.emplace_back(h + e * b);\n }\n return res;\n}\nvector<Point> intersection_cs(const Circle& c, const Segment& s) {\n const vector<Point> cand = intersection_cl(c, Line(s));\n vector<Point> res;\n for(const Point& p : cand) {\n if(ccw(s.a, s.b, p) == 0) {\n res.emplace_back(p);\n }\n }\n return res;\n}\nvector<Point> intersection_cc(const Circle& c1, const Circle& c2) {\n const Real d = abs(c1.p - c2.p);\n const Real a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (Real(2.0) * c1.r * d));\n const Real t = atan2(c2.p.imag() - c1.p.imag(), c2.p.real() - c1.p.real());\n vector<Point> res;\n if(is_intersect_cc(c1, c2) % 4 == 0) return res;\n if(eq(a, 0.0)) {\n res.emplace_back(c1.p + rot(Point(c1.r, 0.0), t));\n } else {\n res.emplace_back(c1.p + rot(Point(c1.r, 0.0), t + a));\n res.emplace_back(c1.p + rot(Point(c1.r, 0.0), t - a));\n }\n return res;\n}\nvector<Point> tangent_cp(const Circle& c, const Point& p) {\n return intersection_cc(c, Circle(p, sqrt(norm(p - c.p) - c.r * c.r)));\n}\nvector<Line> tangent_cc(Circle c1, Circle c2) {\n vector<Line> res;\n if(c1.r < c2.r) swap(c1, c2);\n const Real r = abs(c2.p - c1.p);\n if(eq(r, 0.0)) return res;\n const Point u = (c2.p - c1.p) / r;\n const Point v = rot(u, PI * 0.5);\n for(const Real s : {Real(1.0), Real(-1.0)}) {\n const Real h = (c1.r + c2.r * s) / r;\n if(eq(abs(h), Real(1.0))) {\n res.emplace_back(c1.p + u * c1.r, c1.p + (u + v) * c1.r);\n } else if(abs(h) < Real(1.0)) {\n const Point uu = u * h, vv = v * sqrt(Real(1.0) - h * h);\n res.emplace_back(c1.p + (uu + vv) * c1.r, c2.p - (uu + vv) * c2.r * s);\n res.emplace_back(c1.p + (uu - vv) * c1.r, c2.p - (uu - vv) * c2.r * s);\n }\n }\n return res;\n}\nCircle inscribed_circle(const Point& a, const Point& b, const Point& c) {\n const Real A = abs(b - c), B = abs(c - a), C = abs(a - b);\n const Point x = Point((a * A + b * B + c * C) / (A + B + C));\n const Real r = dist_sp(Segment(a, b), x);\n return Circle(x, r);\n}\nCircle circumscribed_circle(const Point& a, const Point& b, const Point& c) {\n const Point m1((a + b) / 2.0), m2((b + c) / 2.0);\n const Point v((b - a).imag(), (a - b).real()), w((b - c).imag(), (c - b).real());\n const Line s(m1, Point(m1 + v)), t(m2, Point(m2 + w));\n const Point x = intersection_ll(s, t)[0];\n return Circle(x, abs(a - x));\n}\nCircle appollonius(const Point& p1, const Point& p2, const Real& a, const Real& b) {\n const Point q1 = (p1 * b + p2 * a) / (a + b), q2 = (-p1 * b + p2 * a) / (a - b);\n return Circle((q1 + q2) * 0.5, abs(q1 - q2) * 0.5);\n}\nReal area_cc(const Circle& c1, const Circle& c2) {\n const Real d = abs(c1.p - c2.p);\n if(c1.r + c2.r <= d + EPS) return 0.0;\n if(d <= abs(c1.r - c2.r) + EPS) {\n const Real r = min(c1.r, c2.r);\n return r * r * PI;\n }\n const Real rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (Real(2.0) * d);\n const Real theta = acos(rc / c1.r);\n const Real phi = acos((d - rc) / c2.r);\n return c1.r * c1.r * theta + c2.r * c2.r * phi - d * c1.r * sin(theta);\n}\nReal area_pc(const vector<Point>& ps, const Circle& c) {\n auto calc_element = [&](const Point& a, const Point& b, const Real& r, const bool triangle) -> Real {\n if(triangle) return cross(a, b) / 2.0;\n const Point tmp = b * Point(a.real(), -a.imag());\n const Real ang = atan2(tmp.imag(), tmp.real());\n return r * r * ang / 2.0;\n };\n auto cross_area = [&](const Circle& c, const Point& ia, const Point& ib) -> Real {\n const Point a = ia - c.p, b = ib - c.p;\n if(abs(a - b) < EPS) return 0;\n const bool isin_a = (abs(a) < c.r + EPS);\n const bool isin_b = (abs(b) < c.r + EPS);\n if(isin_a and isin_b) return calc_element(a, b, c.r, true);\n const Circle oc(Point(0.0, 0.0), c.r);\n const Segment seg(a, b);\n const vector<Point> cr = intersection_cs(oc, seg);\n if(cr.empty()) return calc_element(a, b, c.r, false);\n const Point s = cr[0], t = cr.back();\n return calc_element(s, t, c.r, true) + calc_element(a, s, c.r, isin_a) + calc_element(t, b, c.r, isin_b);\n };\n const int n = (int)ps.size();\n if(n < 3) return 0.0;\n Real S = 0;\n for(int i = 0; i < n; ++i) {\n S += cross_area(c, ps[i], ps[(i + 1) % n]);\n }\n return S;\n}\ntemplate <typename T>\nstruct Edge {\n int from, to;\n T cost;\n int idx;\n Edge()\n : from(-1), to(-1), cost(-1), idx(-1) {}\n Edge(const int from, const int to, const T& cost = 1, const int idx = -1)\n : from(from), to(to), cost(cost), idx(idx) {}\n operator int() const {\n return to;\n }\n};\ntemplate <typename T>\nstruct Graph {\n Graph(const int N)\n : n(N), es(0), g(N) {}\n int size() const {\n return n;\n }\n int edge_size() const {\n return es;\n }\n void add_edge(const int from, const int to, const T& cost = 1) {\n assert(0 <= from and from < n);\n assert(0 <= to and to < n);\n g[from].emplace_back(from, to, cost, es);\n g[to].emplace_back(to, from, cost, es++);\n }\n void add_directed_edge(const int from, const int to, const T& cost = 1) {\n assert(0 <= from and from < n);\n assert(0 <= to and to < n);\n g[from].emplace_back(from, to, cost, es++);\n }\n inline vector<Edge<T>>& operator[](const int& k) {\n assert(0 <= k and k < n);\n return g[k];\n }\n inline const vector<Edge<T>>& operator[](const int& k) const {\n assert(0 <= k and k < n);\n return g[k];\n }\n\n private:\n int n, es;\n vector<vector<Edge<T>>> g;\n};\ntemplate <typename T>\nusing Edges = vector<Edge<T>>;\ntemplate <typename T>\nvector<pair<T, int>> dijkstra(const Graph<T>& g, const int s = 0) {\n const int n = g.size();\n assert(0 <= s and s < n);\n vector<pair<T, int>> d(n, {numeric_limits<T>::max(), -1});\n priority_queue<pair<T, int>, vector<pair<T, int>>, greater<pair<T, int>>> pq;\n d[s] = {0, -1};\n pq.emplace(0, s);\n while(!pq.empty()) {\n const auto [dist, cur] = pq.top();\n pq.pop();\n if(d[cur].first < dist) continue;\n for(const Edge<T>& e : g[cur]) {\n if(d[e.to].first > d[cur].first + e.cost) {\n d[e.to] = {d[cur].first + e.cost, cur};\n pq.emplace(d[e.to].first, e.to);\n }\n }\n }\n return d;\n}\nint main(void) {\n while(1) {\n int n;\n cin >> n;\n if(n == 0) break;\n vector<Circle> c(n);\n rep(i, 0, n) {\n cin >> c[i].p >> c[i].r;\n }\n Graph<Real> g(2 * n);\n bool direct = true;\n rep(i, 0, n - 1) {\n vector<Point> u = intersection_cc(c[i], c[i + 1]);\n if(!is_intersect_ss(Segment(c[0].p, c[n - 1].p), Segment(u[0], u[1]))) {\n direct = false;\n break;\n }\n }\n if(direct) {\n g.add_edge(2 * n - 2, 2 * n - 1, dist(c[0].p, c[n - 1].p));\n }\n rep(i, 0, n - 1) {\n rep(i2, 0, 2) {\n Point s = c[0].p;\n Point t = intersection_cc(c[i], c[i + 1])[i2];\n bool flag = true;\n rep(k, 0, i) {\n vector<Point> u = intersection_cc(c[k], c[k + 1]);\n if(!is_intersect_ss(Segment(s, t), Segment(u[0], u[1]))) {\n flag = false;\n break;\n }\n }\n if(flag) {\n g.add_edge(2 * n - 2, i * 2 + i2, dist(s, t));\n }\n }\n }\n rep(i, 0, n - 1) {\n rep(i2, 0, 2) {\n Point s = c[n - 1].p;\n Point t = intersection_cc(c[i], c[i + 1])[i2];\n bool flag = true;\n rep(k, i + 1, n - 1) {\n vector<Point> u = intersection_cc(c[k], c[k + 1]);\n if(!is_intersect_ss(Segment(s, t), Segment(u[0], u[1]))) {\n flag = false;\n break;\n }\n }\n if(flag) {\n g.add_edge(i * 2 + i2, 2 * n - 1, dist(s, t));\n }\n }\n }\n rep(i, 0, n - 1) {\n rep(j, i + 1, n - 1) {\n rep(i2, 0, 2) {\n rep(j2, 0, 2) {\n Point s = intersection_cc(c[i], c[i + 1])[i2];\n Point t = intersection_cc(c[j], c[j + 1])[j2];\n bool flag = true;\n rep(k, i + 1, j) {\n vector<Point> u = intersection_cc(c[k], c[k + 1]);\n if(!is_intersect_ss(Segment(s, t), Segment(u[0], u[1]))) {\n flag = false;\n break;\n }\n }\n if(flag) {\n g.add_edge(i * 2 + i2, j * 2 + j2, dist(s, t));\n }\n }\n }\n }\n }\n cout << dijkstra(g, 2 * n - 2)[2 * n - 1].first << '\\n';\n }\n}", "accuracy": 1, "time_ms": 580, "memory_kb": 4312, "score_of_the_acc": -1.2664, "final_rank": 19 }, { "submission_id": "aoj_1183_9547678", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nusing T = double;\nconst T eps = 1e-12;\nusing Point = complex<T>;\nusing Poly = vector<Point>;\n#define X real()\n#define Y imag()\ntemplate <typename T> inline bool eq(const T &a, const T &b) {\n return fabs(a - b) < eps;\n}\nbool cmp(const Point &a, const Point &b) {\n auto sub = [&](Point a) {\n return (a.Y < 0 ? -1 : (a.Y == 0 && a.X >= 0 ? 0 : 1));\n };\n if (sub(a) != sub(b))\n return sub(a) < sub(b);\n return a.Y * b.X < a.X * b.Y;\n}\nstruct Line {\n Point a, b, dir;\n Line() {}\n Line(Point _a, Point _b) : a(_a), b(_b), dir(b - a) {}\n Line(T A, T B, T C) {\n if (eq(A, .0)) {\n a = Point(0, C / B), b = Point(1 / C / B);\n } else if (eq(B, .0)) {\n a = Point(C / A, 0), b = Point(C / A, 1);\n } else {\n a = Point(0, C / B), b = Point(C / A, 0);\n }\n }\n};\nstruct Segment : Line {\n Segment() {}\n Segment(Point _a, Point _b) : Line(_a, _b) {}\n};\nstruct Circle {\n Point p;\n T r;\n Circle() {}\n Circle(Point _p, T _r) : p(_p), r(_r) {}\n};\n\nistream &operator>>(istream &is, Point &p) {\n T x, y;\n is >> x >> y;\n p = Point(x, y);\n return is;\n}\nostream &operator<<(ostream &os, Point &p) {\n os << fixed << setprecision(12) << p.X << ' ' << p.Y;\n return os;\n}\nPoint unit(const Point &a) {\n return a / abs(a);\n}\nT dot(const Point &a, const Point &b) {\n return a.X * b.X + a.Y * b.Y;\n}\nT cross(const Point &a, const Point &b) {\n return a.X * b.Y - a.Y * b.X;\n}\nPoint rot(const Point &a, const T &theta) {\n return Point(cos(theta) * a.X - sin(theta) * a.Y,\n sin(theta) * a.X + cos(theta) * a.Y);\n}\nPoint rot90(const Point &a) {\n return Point(-a.Y, a.X);\n}\nT arg(const Point &a, const Point &b, const Point &c) {\n double ret = acos(dot(a - b, c - b) / abs(a - b) / abs(c - b));\n if (cross(a - b, c - b) < 0)\n ret = -ret;\n return ret;\n}\n\nPoint Projection(const Line &l, const Point &p) {\n T t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\nPoint Projection(const Segment &l, const Point &p) {\n T t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\nPoint Reflection(const Line &l, const Point &p) {\n return p + (Projection(l, p) - p) * 2.;\n}\nint ccw(const Point &a, Point b, Point c) {\n b -= a;\n c -= a;\n if (cross(b, c) > eps)\n return 1; // ccw\n\n if (cross(b, c) < -eps)\n return -1; // cw\n\n if (dot(b, c) < 0)\n return 2; // c,a,b\n\n if (norm(b) < norm(c))\n return -2; // a,b,c\n\n return 0; // a,c,b\n\n}\nbool isOrthogonal(const Line &a, const Line &b) {\n return eq(dot(a.b - a.a, b.b - b.a), .0);\n}\nbool isParallel(const Line &a, const Line &b) {\n return eq(cross(a.b - a.a, b.b - b.a), .0);\n}\nbool isIntersect(const Segment &a, const Segment &b) {\n return ccw(a.a, a.b, b.a) * ccw(a.a, a.b, b.b) <= 0 and\n ccw(b.a, b.b, a.a) * ccw(b.a, b.b, a.b) <= 0;\n}\nint isIntersect(const Circle &a, const Circle &b) {\n T d = abs(a.p - b.p);\n if (d > a.r + b.r + eps)\n return 4;\n if (eq(d, a.r + b.r))\n return 3;\n if (eq(d, abs(a.r - b.r)))\n return 1;\n if (d < abs(a.r - b.r) - eps)\n return 0;\n return 2;\n}\nT Dist(const Line &a, const Point &b) {\n Point c = Projection(a, b);\n return abs(c - b);\n}\nT Dist(const Segment &a, const Point &b) {\n if (dot(a.b - a.a, b - a.a) < eps)\n return abs(b - a.a);\n if (dot(a.a - a.b, b - a.b) < eps)\n return abs(b - a.b);\n return abs(cross(a.b - a.a, b - a.a)) / abs(a.b - a.a);\n}\nT Dist(const Segment &a, const Segment &b) {\n if (isIntersect(a, b))\n return .0;\n T res = min({Dist(a, b.a), Dist(a, b.b), Dist(b, a.a), Dist(b, a.b)});\n return res;\n}\nPoint Intersection(const Line &a, const Line &b) {\n T d1 = cross(a.b - a.a, b.b - b.a);\n T d2 = cross(a.b - a.a, a.b - b.a);\n if (eq(d1, 0.) and eq(d2, 0.))\n return b.a;\n return b.a + (b.b - b.a) * (d2 / d1);\n}\nPoly Intersection(const Circle &a, const Line &b) {\n Poly res;\n T d = Dist(b, a.p);\n if (d > a.r + eps)\n return res;\n Point h = Projection(b, a.p);\n if (eq(d, a.r)) {\n res.push_back(h);\n return res;\n }\n Point e = unit(b.b - b.a);\n T ph = sqrt(a.r * a.r - d * d);\n res.push_back(h - e * ph);\n res.push_back(h + e * ph);\n return res;\n}\nPoly Intersection(const Circle &a, const Segment &b) {\n Line c(b.a, b.b);\n Poly sub = Intersection(a, c);\n double xmi = min(b.a.X, b.b.X), xma = max(b.a.X, b.b.X);\n double ymi = min(b.a.Y, b.b.Y), yma = max(b.a.Y, b.b.Y);\n Poly res;\n rep(i, 0, sub.size()) {\n if (xmi <= sub[i].X + eps and sub[i].X - eps <= xma and\n ymi <= sub[i].Y + eps and sub[i].Y - eps <= yma) {\n res.push_back(sub[i]);\n }\n }\n return res;\n}\nPoly Intersection(const Circle &a, const Circle &b) {\n Poly res;\n int mode = isIntersect(a, b);\n T d = abs(a.p - b.p);\n if (mode == 4 or mode == 0)\n return res;\n if (mode == 3) {\n T t = a.r / (a.r + b.r);\n res.push_back(a.p + (b.p - a.p) * t);\n return res;\n }\n if (mode == 1) {\n if (b.r < a.r - eps) {\n res.push_back(a.p + (b.p - a.p) * (a.r / d));\n } else {\n res.push_back(b.p + (a.p - b.p) * (b.r / d));\n }\n return res;\n }\n T rc = (a.r * a.r + d * d - b.r * b.r) / d / 2.;\n T rs = sqrt(a.r * a.r - rc * rc);\n if (a.r - abs(rc) < eps)\n rs = 0;\n Point e = unit(b.p - a.p);\n res.push_back(a.p + rc * e + rs * e * Point(0, 1));\n res.push_back(a.p + rc * e + rs * e * Point(0, -1));\n return res;\n}\nPoly HalfplaneIntersection(vector<Line> &H) {\n sort(ALL(H), [&](Line &l1, Line &l2) { return cmp(l1.dir, l2.dir); });\n auto outside = [&](Line &L, Point p) -> bool {\n return cross(L.dir, p - L.a) < -eps;\n };\n deque<Line> deq;\n int sz = 0;\n rep(i, 0, SZ(H)) {\n while (sz > 1 and\n outside(H[i], Intersection(deq[sz - 1], deq[sz - 2]))) {\n deq.pop_back();\n sz--;\n }\n while (sz > 1 and outside(H[i], Intersection(deq[0], deq[1]))) {\n deq.pop_front();\n sz--;\n }\n if (sz > 0 and fabs(cross(H[i].dir, deq[sz - 1].dir)) < eps) {\n if (dot(H[i].dir, deq[sz - 1].dir) < 0) {\n return {};\n }\n if (outside(H[i], deq[sz - 1].a)) {\n deq.pop_back();\n sz--;\n } else\n continue;\n }\n deq.push_back(H[i]);\n sz++;\n }\n\n while (sz > 2 and outside(deq[0], Intersection(deq[sz - 1], deq[sz - 2]))) {\n deq.pop_back();\n sz--;\n }\n while (sz > 2 and outside(deq[sz - 1], Intersection(deq[0], deq[1]))) {\n deq.pop_front();\n sz--;\n }\n if (sz < 3)\n return {};\n deq.push_back(deq.front());\n Poly ret;\n rep(i, 0, sz) ret.push_back(Intersection(deq[i], deq[i + 1]));\n return ret;\n}\n\nT Area(const Poly &a) {\n T res = 0;\n int n = a.size();\n rep(i, 0, n) res += cross(a[i], a[(i + 1) % n]);\n return fabs(res / 2.);\n}\nT Area(const Poly &a, const Circle &b) {\n int n = a.size();\n if (n < 3)\n return .0;\n auto rec = [&](auto self, const Circle &c, const Point &p1,\n const Point &p2) {\n Point va = c.p - p1, vb = c.p - p2;\n T f = cross(va, vb), res = .0;\n if (eq(f, .0))\n return res;\n if (max(abs(va), abs(vb)) < c.r + eps)\n return f;\n if (Dist(Segment(p1, p2), c.p) > c.r - eps)\n return c.r * c.r * arg(vb * conj(va));\n auto u = Intersection(c, Segment(p1, p2));\n Poly sub;\n sub.push_back(p1);\n for (auto &x : u)\n sub.push_back(x);\n sub.push_back(p2);\n rep(i, 0, sub.size() - 1) res += self(self, c, sub[i], sub[i + 1]);\n return res;\n };\n T res = .0;\n rep(i, 0, n) res += rec(rec, b, a[i], a[(i + 1) % n]);\n return fabs(res / 2.);\n}\nT Area(const Circle &a, const Circle &b) {\n T d = abs(a.p - b.p);\n if (d >= a.r + b.r - eps)\n return .0;\n if (d <= abs(a.r - b.r) + eps) {\n T r = min(a.r, b.r);\n return M_PI * r * r;\n }\n T ath = acos((a.r * a.r + d * d - b.r * b.r) / d / a.r / 2.);\n T res = a.r * a.r * (ath - sin(ath * 2) / 2.);\n T bth = acos((b.r * b.r + d * d - a.r * a.r) / d / b.r / 2.);\n res += b.r * b.r * (bth - sin(bth * 2) / 2.);\n return fabs(res);\n}\nbool isConvex(const Poly &a) {\n int n = a.size();\n int cur, pre, nxt;\n rep(i, 0, n) {\n pre = (i - 1 + n) % n;\n nxt = (i + 1) % n;\n cur = i;\n if (ccw(a[pre], a[cur], a[nxt]) == -1)\n return 0;\n }\n return 1;\n}\nint isContained(const Poly &a,\n const Point &b) { // 0:not contain,1:on edge,2:contain\n\n bool res = 0;\n int n = a.size();\n rep(i, 0, n) {\n Point p = a[i] - b, q = a[(i + 1) % n] - b;\n if (p.Y > q.Y)\n swap(p, q);\n if (p.Y < eps and eps < q.Y and cross(p, q) > eps)\n res ^= 1;\n if (eq(cross(p, q), .0) and dot(p, q) < eps)\n return 1;\n }\n return (res ? 2 : 0);\n}\nPoly ConvexHull(Poly &a) {\n sort(ALL(a), [](const Point &p, const Point &q) {\n return (eq(p.Y, q.Y) ? p.X < q.X : p.Y < q.Y);\n });\n a.erase(unique(ALL(a)), a.end());\n int n = a.size(), k = 0;\n Poly res(n * 2);\n for (int i = 0; i < n; res[k++] = a[i++]) {\n while (k >= 2 and\n cross(res[k - 1] - res[k - 2], a[i] - res[k - 1]) < eps)\n k--;\n }\n for (int i = n - 2, t = k + 1; i >= 0; res[k++] = a[i--]) {\n while (k >= t and\n cross(res[k - 1] - res[k - 2], a[i] - res[k - 1]) < eps)\n k--;\n }\n res.resize(k - 1);\n return res;\n}\nT Diam(const Poly &a) {\n int n = a.size();\n int x = 0, y = 0;\n rep(i, 1, n) {\n if (a[i].Y > a[x].Y)\n x = i;\n if (a[i].Y < a[y].Y)\n y = i;\n }\n T res = abs(a[x] - a[y]);\n int i = x, j = y;\n do {\n if (cross(a[(i + 1) % n] - a[i], a[(j + 1) % n] - a[j]) < 0)\n i = (i + 1) % n;\n else\n j = (j + 1) % n;\n chmax(res, abs(a[i] - a[j]));\n } while (i != x or j != y);\n return res;\n}\nPoly Cut(const Poly &a, const Line &l) {\n int n = a.size();\n Poly res;\n rep(i, 0, n) {\n Point p = a[i], q = a[(i + 1) % n];\n if (ccw(l.a, l.b, p) != -1)\n res.push_back(p);\n if (ccw(l.a, l.b, p) * ccw(l.a, l.b, q) < 0)\n res.push_back(Intersection(Line(p, q), l));\n }\n return res;\n}\n\nT Closest(Poly &a) {\n int n = a.size();\n if (n <= 1)\n return 0;\n sort(ALL(a), [&](Point a, Point b) {\n return (eq(a.X, b.X) ? a.Y < b.Y : a.X < b.X);\n });\n Poly buf(n);\n auto rec = [&](auto self, int lb, int rb) -> T {\n if (rb - lb <= 1)\n return (T)INF;\n int mid = (lb + rb) >> 1;\n auto x = a[mid].X;\n T res = min(self(self, lb, mid), self(self, mid, rb));\n inplace_merge(a.begin() + lb, a.begin() + mid, a.begin() + rb,\n [&](auto p, auto q) { return p.Y < q.Y; });\n int ptr = 0;\n rep(i, lb, rb) {\n if (abs(a[i].X - x) >= res)\n continue;\n rep(j, 0, ptr) {\n auto sub = a[i] - buf[ptr - 1 - j];\n if (sub.Y >= res)\n break;\n chmin(res, abs(sub));\n }\n buf[ptr++] = a[i];\n }\n return res;\n };\n return rec(rec, 0, n);\n}\n\nCircle Incircle(const Point &a, const Point &b, const Point &c) {\n T A = abs(b - c), B = abs(c - a), C = abs(a - b);\n Point p(A * a.X + B * b.X + C * c.X, A * a.Y + B * b.Y + C * c.Y);\n p /= (A + B + C);\n T r = Dist(Line(a, b), p);\n return Circle(p, r);\n}\nCircle Circumcircle(const Point &a, const Point &b, const Point &c) {\n Line l1((a + b) / 2., (a + b) / 2. + (b - a) * Point(0, 1));\n Line l2((b + c) / 2., (b + c) / 2. + (c - b) * Point(0, 1));\n Point p = Intersection(l1, l2);\n return Circle(p, abs(p - a));\n}\nPoly tangent(const Point &a, const Circle &b) {\n return Intersection(b, Circle(a, sqrt(norm(b.p - a) - b.r * b.r)));\n}\nvector<Line> tangent(const Circle &a, const Circle &b) {\n vector<Line> res;\n T d = abs(a.p - b.p);\n if (eq(d, 0.))\n return res;\n Point u = unit(b.p - a.p);\n Point v = u * Point(0, 1);\n for (int t : {-1, 1}) {\n T h = (a.r + b.r * t) / d;\n if (eq(h * h, 1.)) {\n res.push_back(Line(a.p + (h > 0 ? u : -u) * a.r,\n a.p + (h > 0 ? u : -u) * a.r + v));\n } else if (1 > h * h) {\n Point U = u * h, V = v * sqrt(1 - h * h);\n res.push_back(Line(a.p + (U + V) * a.r, b.p - (U + V) * (b.r * t)));\n res.push_back(Line(a.p + (U - V) * a.r, b.p - (U - V) * (b.r * t)));\n }\n }\n return res;\n}\n\n/**\n * @brief Geometry\n */\n\nint main() {\nwhile(1) {\n int N;\n cin >> N;\n if (N == 0) return 0;\n vector<Circle> C(N);\n rep(i,0,N) {\n double PX, PY, R;\n cin >> PX >> PY >> R;\n Point p(PX,PY);\n Circle c(p,R);\n C[i] = c;\n }\n vector<Poly> V(N-1);\n vector<Segment> S(N-1);\n rep(i,0,N-1) {\n V[i] = Intersection(C[i], C[i+1]);\n Segment s(V[i][0], V[i][1]);\n S[i] = s;\n }\n vector<vector<double>> D(N-1,vector<double>(2,inf));\n bool check;\n rep(i,0,N-1) {\n rep(j,0,2) {\n Point p = V[i][j];\n { \n check = true;\n Segment s(p,C[0].p);\n rep(k,0,i) {\n if (!isIntersect(s,S[k])) check = false;\n }\n if (check) chmin(D[i][j], abs(p-C[0].p));\n }\n rep(k,0,i) {\n rep(l,0,2) {\n check = true;\n Segment s(p,V[k][l]);\n rep(m,k+1,i) {\n if (!isIntersect(s,S[m])) check = false;\n }\n if (check) chmin(D[i][j], D[k][l] + abs(p-V[k][l]));\n }\n }\n }\n }\n double ANS = inf;\n { check = true;\n Segment s(C[0].p, C[N-1].p);\n rep(i,0,N-1) {\n if (!isIntersect(s,S[i])) check = false;\n }\n if (check) chmin(ANS, abs(C[N-1].p-C[0].p));\n }\n rep(i,0,N-1) {\n rep(j,0,2) {\n check = true;\n Segment s(V[i][j], C[N-1].p);\n rep(k,i+1,N-1) {\n if (!isIntersect(s,S[k])) check = false;\n }\n if (check) chmin(ANS, D[i][j] + abs(C[N-1].p-V[i][j]));\n }\n }\n print(ANS);\n}\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3568, "score_of_the_acc": -0.0742, "final_rank": 1 }, { "submission_id": "aoj_1183_9436263", "code_snippet": "#include <iostream>\n#include <vector>\n#include <complex>\n#include <cmath>\n#include <limits>\n#include <queue>\n#include <iomanip>\n\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n#define rrep(i, n) for (int i = 1; i <= (n); ++i)\n#define srep(i, s, t) for (int i = s; i < (t); ++i)\n\ntemplate<class T, class U> bool chmin(T& a, const U& b){ if(a <= b) return 0; a = b; return 1; }\ntemplate<class T, class U> bool chmax(T& a, const U& b){ if(a >= b) return 0; a = b; return 1; }\n\nusing ll = long long; using ld = long double;\nusing vi = vector<int>; using vd = vector<double>;\nusing point = complex<double>;\nusing vp = vector<point>;\nusing ppp = pair<point, point>;\n\nconst double INF = numeric_limits<double>::infinity();\nconst ll LINF = 0x1fffffffffffffff;\nconst double EPS = 1e-10;\n\nclass Circle {\npublic:\n point ctr;\n double r;\n\n Circle() : ctr(0, 0), r(0) {}\n Circle(double x, double y, double r) : ctr(x, y), r(r) {}\n};\n\n// 2点で交わる前提で、2つの円の交点を返す\nppp intersection(const Circle& p, const Circle& q) {\n double d = abs(q.ctr - p.ctr); // 中心間距離d\n double y = (p.r * p.r - q.r * q.r + d * d) / (2 * d);\n double x = sqrt(p.r * p.r - y * y);\n\n point p1 = p.ctr + (y / d) * (q.ctr - p.ctr); // 交点の中点\n point offset = point((q.ctr.imag() - p.ctr.imag()) * (x / d), (q.ctr.real() - p.ctr.real()) * (-x / d));\n point p2 = p1 + offset;\n point p3 = p1 - offset;\n return make_pair(p2, p3);\n}\n\n// 線分(注:Lineは日本語で直線)\nstruct Line { point p, q; Line(point p, point q) : p(p), q(q) {} };\n\n// 外積\ndouble cross(point p, point q) { return imag(conj(p) * q); }\n\n// 交差判定\nbool ssIntersect(Line a, Line b) {\n if (abs(imag((a.q - a.p) / (b.q - b.p))) < EPS) return false;\n return cross(a.q - a.p, b.p - a.p) * cross(a.q - a.p, b.q - a.p) < 0 &&\n cross(b.q - b.p, a.p - b.p) * cross(b.q - b.p, a.q - b.p) < 0;\n}\n\nclass WeightedEdge {\npublic:\n int to;\n double cost;\n\n WeightedEdge() {}\n WeightedEdge(int to, double cost) : to(to), cost(cost){}\n};\n\nclass WeightedGraph {\n using E = WeightedEdge;\nprivate:\n vector<vector<E>> g;\n\npublic:\n WeightedGraph(int n) : g(n) {}\n\n const vector<E>& operator[](int at) const { return g[at]; }\n\n int size() const { return g.size(); }\n\n void addEdge(int a, int b, double weight) {\n g[a].emplace_back(b, weight);\n g[b].emplace_back(a, weight);\n }\n\n void addDirectedEdge(int from, int to, double weight) {\n g[from].emplace_back(to, weight);\n }\n\n void inputGraph(int m) {\n while (m-- > 0) {\n int a, b;\n double c;\n cin >> a >> b >> c;\n g[a].emplace_back(b, c);\n // g[b].emplace_back(a, c);\n }\n }\n // dijkstra\n vd Dijkstra(int start) const {\n int n = g.size();\n vd cost(n, INF);\n vector<bool> used(n);\n priority_queue<pair<double, int>, vector<pair<double, int>>, greater<pair<double, int>>> q;\n cost[start] = 0;\n q.emplace(0, start);\n while (!q.empty()) {\n int at = q.top().second;\n q.pop();\n if (used[at]) continue;\n used[at] = true;\n for (auto& e : g[at]) {\n int to = e.to;\n double c = e.cost;\n if (chmin(cost[to], cost[at] + c)) {\n q.emplace(cost[to], to);\n }\n }\n }\n return cost;\n }\n};\n\nint main() {\n int n; \n while(cin >> n, n) {\n vp ps; //points\n vector<Circle> cs(n); //circles\n rep(i, n) {\n double x, y, r;\n cin >> x >> y >> r;\n cs[i] = Circle(x, y, r);\n }\n ps.push_back(cs[0].ctr);\n rep(i, n - 1) {\n ppp is = intersection(cs[i], cs[i + 1]);\n ps.push_back(is.first);\n ps.push_back(is.second);\n }\n ps.push_back(cs.back().ctr); // ここまでで∑2nの点が格納された\n WeightedGraph g(2 * n); // 頂点数2nの重み付きグラフ\n rep(i, 2 * n) srep(j, i + 1, 2 * n) {\n bool flag = true;\n srep(k, (i + 1) / 2 + 1, (j + 1) / 2) {\n if (!ssIntersect(Line(ps[i], ps[j]), Line(ps[2 * k - 1], ps[2 * k]))){ flag = false; }\n }\n if (flag) { g.addEdge(i, j, abs(ps[i] - ps[j])); } \n }\n vd dist = g.Dijkstra(0);\n cout << fixed << setprecision(6) << dist.back() << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3748, "score_of_the_acc": -0.3255, "final_rank": 5 }, { "submission_id": "aoj_1183_9428078", "code_snippet": "// #pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n// #pragma GCC optimize(\"unroll-loops\")\n#include<bits/stdc++.h>\n// #include<sys/time.h>\n// #include<atcoder/modint>\n\nusing namespace std;\n\n// using P = pair<int, int>;\n\n// const int M = 998244353;\n// const long long LM = 1LL << 60;\n\nusing fltype = double;\nusing itype = long long;\nconst fltype eps = 1e-8;\nconst fltype inf = 1e20;\nusing Point = complex<fltype>;\nusing Line = pair<Point, Point>;\nusing Circle = pair<pair<itype, itype>, itype>;\n\n\nvector<fltype> crossparams(const Circle& c, const Line& l) {\n fltype x0 = real(l.first);\n fltype y0 = imag(l.first);\n fltype x = c.first.first - x0;\n fltype y = c.first.second - y0;\n fltype a = real(l.second) - x0;\n fltype b = imag(l.second) - y0;\n fltype d = a * a + b * b;\n a /= d;\n b /= d;\n fltype D = c.second * (fltype)c.second / d - (a * y - b * x) * (a * y - b * x);\n if (D < eps * eps) {\n return {};\n }\n else {\n fltype p = sqrt(D);\n return { a * x + b * y - p, a * x + b * y + p };\n }\n}\n\nvector<Point> crosspoints(const Circle& a, const Circle& b) {\n {\n itype d = (b.first.first - a.first.first) * (b.first.first - a.first.first) + (b.first.second - a.first.second) * (b.first.second - a.first.second);\n itype rp = (a.second + b.second) * (a.second + b.second);\n itype rm = (a.second - b.second) * (a.second - b.second);\n if (d > rp || rm > d) {\n return {};\n }\n }\n {\n fltype x0 = a.first.first;\n fltype y0 = a.first.second;\n fltype x = b.first.first - x0;\n fltype y = b.first.second - y0;\n fltype r1 = a.second * (fltype)a.second / (x * x + y * y);\n fltype r2 = b.second * (fltype)b.second / (x * x + y * y);\n fltype p = (1 + r1 - r2) / 2;\n fltype D = r1 - p * p;\n if (D < eps * eps) {\n return {\n Point(x0 + p * x, y0 + p * y),\n };\n }\n else {\n fltype q = sqrt(D);\n return {\n Point(x0 + p * x + q * y, y0 + p * y - q * x),\n Point(x0 + p * x - q * y, y0 + p * y + q * x),\n };\n }\n }\n}\n\nbool through(const vector<Circle>& cs, const Line& l) {\n if (abs(l.second - l.first) < eps) {\n return true;\n }\n vector<pair<fltype, int>> ts;\n for (const auto& c : cs) {\n auto r = crossparams(c, l);\n if (r.size() == 2) {\n ts.emplace_back(r[0], +1);\n ts.emplace_back(r[1], -1);\n }\n }\n sort(ts.begin(), ts.end());\n int c = 0;\n fltype s = 0;\n for (int i = 0; i + 1 < (int)ts.size(); ++i) {\n c += ts[i].second;\n if (c <= 0) {\n s += max(min(ts[i + 1].first, (fltype)1) - max(ts[i].first, (fltype)0), (fltype)(0));\n }\n }\n return s < eps;\n}\n\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(0);\n cout << fixed << setprecision(16);\n while (true) {\n int n;\n cin >> n;\n if (n == 0) {\n return 0;\n }\n vector<Circle> cs(n);\n for (int i = 0; i < n; ++i) {\n cin >> cs[i].first.first >> cs[i].first.second >> cs[i].second;\n }\n vector<Point> ps;\n ps.emplace_back((fltype)cs.front().first.first, (fltype)cs.front().first.second);\n for (int i = 0; i < n; ++i) {\n for (int j = i + 1; j < n; ++j) {\n for (auto& p : crosspoints(cs[i], cs[j])) {\n ps.push_back(p);\n }\n }\n }\n ps.emplace_back((fltype)cs.back().first.first, (fltype)cs.back().first.second);\n int m = ps.size();\n vector<fltype> dist(m, inf * 2);\n vector<bool> used(m);\n dist[0] = 0;\n while (true) {\n int nex = -1;\n for (int i = 0; i < m; ++i) {\n if (!used[i] && (nex == -1 || dist[i] < dist[nex])) {\n nex = i;\n }\n }\n if (nex == -1 || dist[nex] > inf) {\n break;\n }\n used[nex] = true;\n for (int i = max(0, nex - 1); i < m; ++i) {\n if (nex != i && through(cs, { ps[nex], ps[i] })) {\n dist[i] = min(dist[i], dist[nex] + abs(ps[i] - ps[nex]));\n }\n }\n }\n if (dist.back() > inf) {\n cout << \"impossible\\n\";\n }\n else {\n cout << dist.back() << '\\n';\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 340, "memory_kb": 3532, "score_of_the_acc": -0.22, "final_rank": 3 }, { "submission_id": "aoj_1183_9428072", "code_snippet": "// #pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n// #pragma GCC optimize(\"unroll-loops\")\n#include<bits/stdc++.h>\n// #include<sys/time.h>\n// #include<atcoder/modint>\n\nusing namespace std;\n\n// using P = pair<int, int>;\n\n// const int M = 998244353;\n// const long long LM = 1LL << 60;\n\nusing fltype = double;\nusing itype = long long;\nconst fltype eps = 1e-8;\nconst fltype inf = 1e20;\nusing Point = complex<fltype>;\nusing Line = pair<Point, Point>;\nusing Circle = pair<pair<itype, itype>, itype>;\n\n\nvector<fltype> crossparams(const Circle& c, const Line& l) {\n fltype x0 = real(l.first);\n fltype y0 = imag(l.first);\n fltype x = c.first.first - x0;\n fltype y = c.first.second - y0;\n fltype a = real(l.second) - x0;\n fltype b = imag(l.second) - y0;\n fltype d = a * a + b * b;\n a /= d;\n b /= d;\n fltype D = c.second * (fltype)c.second / d - (a * y - b * x) * (a * y - b * x);\n if (D < eps * eps) {\n return {};\n }\n else {\n fltype p = sqrt(D);\n return { a * x + b * y - p, a * x + b * y + p };\n }\n}\n\nvector<Point> crosspoints(const Circle& a, const Circle& b) {\n {\n itype d = (b.first.first - a.first.first) * (b.first.first - a.first.first) + (b.first.second - a.first.second) * (b.first.second - a.first.second);\n itype rp = (a.second + b.second) * (a.second + b.second);\n itype rm = (a.second - b.second) * (a.second - b.second);\n if (d > rp || rm > d) {\n return {};\n }\n }\n {\n fltype x0 = a.first.first;\n fltype y0 = a.first.second;\n fltype x = b.first.first - x0;\n fltype y = b.first.second - y0;\n fltype r1 = a.second * (fltype)a.second / (x * x + y * y);\n fltype r2 = b.second * (fltype)b.second / (x * x + y * y);\n fltype p = (1 + r1 - r2) / 2;\n fltype D = r1 - p * p;\n if (D < eps * eps) {\n return {\n Point(x0 + p * x, y0 + p * y),\n };\n }\n else {\n fltype q = sqrt(D);\n return {\n Point(x0 + p * x + q * y, y0 + p * y - q * x),\n Point(x0 + p * x - q * y, y0 + p * y + q * x),\n };\n }\n }\n}\n\nbool through(const vector<Circle>& cs, const Line& l) {\n if (abs(l.second - l.first) < eps) {\n return true;\n }\n vector<pair<fltype, int>> ts;\n for (const auto& c : cs) {\n auto r = crossparams(c, l);\n if (r.size() == 2) {\n ts.emplace_back(r[0], +1);\n ts.emplace_back(r[1], -1);\n }\n }\n sort(ts.begin(), ts.end());\n int c = 0;\n fltype s = 0;\n for (int i = 0; i + 1 < (int)ts.size(); ++i) {\n c += ts[i].second;\n if (c <= 0) {\n s += max(min(ts[i + 1].first, (fltype)1) - max(ts[i].first, (fltype)0), (fltype)(0));\n }\n }\n return s < eps;\n}\n\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(0);\n cout << fixed << setprecision(16);\n while (true) {\n int n;\n cin >> n;\n if (n == 0) {\n return 0;\n }\n vector<Circle> cs(n);\n for (int i = 0; i < n; ++i) {\n cin >> cs[i].first.first >> cs[i].first.second >> cs[i].second;\n }\n vector<Point> ps;\n ps.emplace_back((fltype)cs.front().first.first, (fltype)cs.front().first.second);\n ps.emplace_back((fltype)cs.back().first.first, (fltype)cs.back().first.second);\n for (int i = 0; i < n; ++i) {\n for (int j = i + 1; j < n; ++j) {\n for (auto& p : crosspoints(cs[i], cs[j])) {\n ps.push_back(p);\n }\n }\n }\n int m = ps.size();\n vector<fltype> dist(m, inf * 2);\n vector<bool> used(m);\n dist[0] = 0;\n while (!used[1]) {\n int nex = -1;\n for (int i = 0; i < m; ++i) {\n if (!used[i] && (nex == -1 || dist[i] < dist[nex])) {\n nex = i;\n }\n }\n if (nex == -1 || dist[nex] > inf) {\n break;\n }\n used[nex] = true;\n for (int i = 0; i < m; ++i) {\n if (nex != i && through(cs, { ps[nex], ps[i] })) {\n dist[i] = min(dist[i], dist[nex] + abs(ps[i] - ps[nex]));\n }\n }\n }\n if (dist[1] > inf) {\n cout << \"impossible\\n\";\n }\n else {\n cout << dist[1] << '\\n';\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 700, "memory_kb": 3548, "score_of_the_acc": -0.4782, "final_rank": 10 }, { "submission_id": "aoj_1183_9428070", "code_snippet": "// #pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n// #pragma GCC optimize(\"unroll-loops\")\n#include<bits/stdc++.h>\n// #include<sys/time.h>\n// #include<atcoder/modint>\n\nusing namespace std;\n\n// using P = pair<int, int>;\n\n// const int M = 998244353;\n// const long long LM = 1LL << 60;\n\nusing fltype = double;\nusing itype = long long;\nconst fltype eps = 1e-8;\nconst fltype inf = 1e20;\nusing Point = complex<fltype>;\nusing Line = pair<Point, Point>;\nusing Circle = pair<pair<itype, itype>, itype>;\n\n\nvector<fltype> crossparams(const Circle& c, const Line& l) {\n fltype x0 = real(l.first);\n fltype y0 = imag(l.first);\n fltype x = c.first.first - x0;\n fltype y = c.first.second - y0;\n fltype a = real(l.second) - x0;\n fltype b = imag(l.second) - y0;\n fltype d = a * a + b * b;\n a /= d;\n b /= d;\n fltype D = c.second * (fltype)c.second / d - (a * y - b * x) * (a * y - b * x);\n if (D < eps * eps) {\n return {};\n }\n else {\n fltype p = sqrt(D);\n return { a * x + b * y - p, a * x + b * y + p };\n }\n}\n\nvector<Point> crosspoints(const Circle& a, const Circle& b) {\n {\n itype d = (b.first.first - a.first.first) * (b.first.first - a.first.first) + (b.first.second - a.first.second) * (b.first.second - a.first.second);\n itype rp = (a.second + b.second) * (a.second + b.second);\n itype rm = (a.second - b.second) * (a.second - b.second);\n if (d > rp || rm > d) {\n return {};\n }\n }\n {\n fltype x0 = a.first.first;\n fltype y0 = a.first.second;\n fltype x = b.first.first - x0;\n fltype y = b.first.second - y0;\n fltype r1 = a.second * (fltype)a.second / (x * x + y * y);\n fltype r2 = b.second * (fltype)b.second / (x * x + y * y);\n fltype p = (1 + r1 - r2) / 2;\n fltype D = r1 - p * p;\n if (D < eps * eps) {\n return {\n Point(x0 + p * x, y0 + p * y),\n };\n }\n else {\n fltype q = sqrt(D);\n return {\n Point(x0 + p * x + q * y, y0 + p * y - q * x),\n Point(x0 + p * x - q * y, y0 + p * y + q * x),\n };\n }\n }\n}\n\nbool through(const vector<Circle>& cs, const Line& l) {\n if (abs(l.second - l.first) < eps) {\n return true;\n }\n vector<pair<fltype, int>> ts;\n for (const auto& c : cs) {\n auto r = crossparams(c, l);\n if (r.size() == 2) {\n ts.emplace_back(r[0], +1);\n ts.emplace_back(r[1], -1);\n }\n }\n sort(ts.begin(), ts.end());\n int c = 0;\n fltype s = 0;\n for (int i = 0; i + 1 < (int)ts.size(); ++i) {\n c += ts[i].second;\n if (c <= 0) {\n s += max(min(ts[i + 1].first, (fltype)1) - max(ts[i].first, (fltype)0), (fltype)(0));\n }\n }\n return s < eps;\n}\n\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(0);\n cout << fixed << setprecision(16);\n while (true) {\n int n;\n cin >> n;\n if (n == 0) {\n return 0;\n }\n vector<Circle> cs(n);\n for (int i = 0; i < n; ++i) {\n cin >> cs[i].first.first >> cs[i].first.second >> cs[i].second;\n }\n vector<Point> ps;\n ps.emplace_back((fltype)cs.front().first.first, (fltype)cs.front().first.second);\n ps.emplace_back((fltype)cs.back().first.first, (fltype)cs.back().first.second);\n for (int i = 0; i < n; ++i) {\n for (int j = i + 1; j < n; ++j) {\n for (auto& p : crosspoints(cs[i], cs[j])) {\n ps.push_back(p);\n }\n }\n }\n int m = ps.size();\n vector<fltype> dist(m, inf * 2);\n vector<bool> used(m);\n dist[0] = 0;\n while (true) {\n int nex = -1;\n for (int i = 0; i < m; ++i) {\n if (!used[i] && (nex == -1 || dist[i] < dist[nex])) {\n nex = i;\n }\n }\n if (nex == -1 || dist[nex] > inf) {\n break;\n }\n used[nex] = true;\n for (int i = 0; i < m; ++i) {\n if (nex != i && through(cs, { ps[nex], ps[i] })) {\n dist[i] = min(dist[i], dist[nex] + abs(ps[i] - ps[nex]));\n }\n }\n }\n if (dist[1] > inf) {\n cout << \"impossible\\n\";\n }\n else {\n cout << dist[1] << '\\n';\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 680, "memory_kb": 3556, "score_of_the_acc": -0.4739, "final_rank": 8 }, { "submission_id": "aoj_1183_9395271", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, a, n) for(int i = a; i < n; i++)\n#define rrep(i, a, n) for(int i = a; i >= n; i--)\n#define inr(l, x, r) (l <= x && x < r)\n#define ll long long\n#define ld long double\n\nconstexpr int IINF = 1001001;\nconstexpr ll INF = 9e18;\n\ntemplate<class t,class u> void chmax(t&a,u b){if(a<b)a=b;}\ntemplate<class t,class u> void chmin(t&a,u b){if(b<a)a=b;}\n\n/*\n前提\n- 点(位置ベクトル)を複素数型で扱う\n- 実軸(real)をx軸、虚軸(imag)をy軸として見る\n- 比較するときは、計算誤差を意識して EPS で判定 (equal関数)\n*/\n\n#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, a, n) for(int i = a; i < n; i++)\n\n/*\n前提\n- 点(位置ベクトル)を複素数型で扱う\n- 実軸(real)をx軸、虚軸(imag)をy軸として見る\n- 比較するときは、計算誤差を意識して EPS で判定 (equal関数)\n*/\n\nnamespace geometry {\n using D = long double;\n using Point = std::complex<D>;\n const D EPS = 1e-8;\n const D PI = M_PI;\n\n // 入出力ストリーム\n istream &operator>>(istream &is, Point &p) {\n D a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n }\n ostream &operator<<(ostream &os, Point &p) {\n return os << fixed << setprecision(20) << p.real() << \" \" << p.imag();\n }\n\n // d 倍する\n Point operator*(Point p, D d) {\n return Point(p.real() * d, p.imag() * d);\n }\n // 等しいかどうか(誤差で判定)\n inline bool equal(D a, D b) { return fabs(a - b) < EPS; }\n\n // 単位ベクトル\n Point unit_vector(Point a) { return a / abs(a); };\n\n // 法線ベクトル (逆向きがよければ (0, -1) をかける)\n Point normal_vector(Point a, D dir=1) { return a * Point(0, dir); }\n\n // 内積:a・b = |a||b|cosΘ\n D dot(Point a, Point b){\n return (a.real() * b.real() + a.imag() * b.imag());\n }\n\n // 外積:a×b = |a||b|sinΘ (外積の大きさではないか?)\n D cross(Point a, Point b){\n return (a.real() * b.imag() - a.imag() * b.real());\n }\n\n // 反時計回りに theta 回転\n Point rotate(Point a, D theta) {\n D c = cos(theta), s = sin(theta);\n return Point(c * a.real() - s * a.imag(), s * a.real() + c * a.imag());\n }\n\n // 直線 \n struct Line {\n Point a, b;\n Line() = default;\n Line(Point a_, Point b_) : a(a_), b(b_) { assert(a_ != b_); };\n // Ax+By=C\n Line(D A, D B, D C){\n if(equal(A, 0)){\n a = Point(0, C/B), b = Point(1, C/B);\n }else if(equal(B, 0)){\n b = Point(C/A, 0), a = Point(C/A, 1);\n }else{\n a = Point(0, C/B), b = Point(C/A, 0);\n }\n }\n };\n\n // 線分(Line と同じ)\n struct Segment : Line {\n Segment() = default;\n Segment(Point a_, Point b_) : Line(a_, b_) {};\n };\n\n // 円(中心と半径)\n struct Circle {\n Point p;\n D r;\n Circle() = default;\n Circle(Point p_, D r_) : p(p_), r(r_) {}\n };\n\n // 射影:直線(線分)に 点p から引いた垂線の足を求める\n Point projection(Line l, Point p){\n D t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n }\n Point projection(Segment l, Point p){\n D t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n }\n\n // 反射:直線を対象軸として 点p と線対称の位置にある点を求める\n Point reflection(Line l, Point p){\n return p + (projection(l, p)-p) * 2.0;\n }\n\n // 3点 a, b, c の位置関係\n // reference: https://sen-comp.hatenablog.com/entry/2020/03/12/145742#iSP3%E7%82%B9%E3%81%AE%E4%BD%8D%E7%BD%AE%E9%96%A2%E4%BF%82\n int ccw(Point a, Point b, Point c){\n b -= a, c -= a;\n // 点 a, b, c が\n if(cross(b, c) > EPS) return 1; // 反時計回りのとき\n if(cross(b, c) < -EPS) return -1; // 時計回りのとき\n \n // 同一直線上にある場合\n if(dot(b, c) < 0) return 2; // c, a, b の順\n if(norm(b) < norm(c)) return -2; // a, b, c の順\n return 0; // a, c, b の順\n }\n \n // 垂直(内積 == 0)\n bool is_vertical(Line a, Line b){\n return equal(dot(a.b - a.a, b.b - b.a), 0);\n }\n\n // 平行(外積 == 0)\n bool is_parallel(Line a, Line b){\n return equal(cross(a.b - a.a, b.b - b.a), 0);\n }\n\n // 線分の交差判定(線分 s に対して, 線分 t の端点が反対側にあればよい)\n bool is_intersect(Segment s, Segment t){\n return (ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0) && \n (ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0);\n }\n\n // 交点(交差する前提)\n Point cross_point(Line s, Line t){\n D d1 = cross(s.b - s.a, t.b - t.a);\n D d2 = cross(s.b - s.a, s.b - t.a);\n // s, t が一致する場合(適当な1点を返す)\n if(equal(abs(d1), 0) && equal(abs(d2), 0)) return t.a; \n \n return t.a + (t.b - t.a) * (d2/d1);\n }\n Point cross_point(Segment s, Segment t) {\n assert(is_intersect(s, t)); // 交差する前提\n return cross_point(Line(s), Line(t));\n }\n\n // 線分と点の距離(点p から線分のどこかへの最短距離)\n D dist_segment_point(Segment l, Point p){\n if(dot(l.b - l.a, p - l.a) < EPS) return abs(p - l.a);\n if(dot(l.a - l.b, p - l.b) < EPS) return abs(p - l.b);\n return abs(cross(l.b - l.a, p - l.a)) / abs(l.b - l.a);\n }\n // 線分と線分の距離\n D dist_segment_segment(Segment s, Segment t){\n if(is_intersect(s, t)) return 0.0;\n D res = min({\n dist_segment_point(s, t.a),\n dist_segment_point(s, t.b),\n dist_segment_point(t, s.a),\n dist_segment_point(t, s.b),\n });\n return res;\n }\n\n // Todo : 円, 多角形\n\n // 2つの円の交点\n pair< Point, Point > cross_point(const Circle &c1, const Circle &c2) {\n D d = abs(c1.p - c2.p);\n D a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d));\n D t = atan2(c2.p.imag() - c1.p.imag(), c2.p.real() - c1.p.real());\n Point p1 = c1.p + Point(cos(t + a) * c1.r, sin(t + a) * c1.r);\n Point p2 = c1.p + Point(cos(t - a) * c1.r, sin(t - a) * c1.r);\n return {p1, p2};\n }\n};\nusing namespace geometry;\n\n\nint main(){\n while(true){\n int n; cin >> n;\n if(n == 0) break;\n vector<Circle> circle(n);\n rep(i, 0, n){\n Point c;\n D r; cin >> c >> r;\n circle[i] = Circle(c, r);\n }\n \n vector<Segment> m(n-1);\n vector<vector<Point>> p(n+1, vector<Point>(2));\n p[0][0] = p[0][1] = circle[0].p;\n rep(i, 0, n-1){\n auto [p1, p2] = cross_point(circle[i], circle[i+1]);\n p[i+1][0] = p1, p[i+1][1] = p2;\n m[i] = Segment(p1, p2);\n }\n p[n][0] = p[n][1] = circle[n-1].p;\n vector<vector<D>> dp(n+1, vector<D>(2, 9e18));\n dp[0][0] = dp[0][1] = 0.0;\n rep(r, 1, n+1){\n rep(l, 0, r){\n rep(i1, 0, 2) rep(i2, 0, 2){\n // p[l][i1] -> p[r][i2]\n bool ok = true;\n Segment s = Segment(p[l][i1], p[r][i2]);\n rep(k, l, r-1){\n ok &= is_intersect(s, m[k]);\n }\n if(ok){\n chmin(dp[r][i2], dp[l][i1]+fabs(p[l][i1]-p[r][i2])); \n }\n }\n }\n }\n printf(\"%.20Lf\\n\", min(dp[n][0], dp[n][1]));\n }\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3864, "score_of_the_acc": -0.4773, "final_rank": 9 }, { "submission_id": "aoj_1183_9361910", "code_snippet": "#include <bits/stdc++.h>\n\n#include <algorithm>\n#include <cmath>\n#include <iostream>\n#include <iterator>\n#include <utility>\n#include <vector>\n\nusing Real = long double;\nconstexpr Real EPS = 1e-10;\nconst Real PI = std::acos(-1);\n\nint sign(Real x) {\n return x < -EPS ? -1 : x > EPS ? 1 : 0;\n}\n\nbool eq(Real lhs, Real rhs) {\n return sign(rhs - lhs) == 0;\n}\n\nbool lte(Real lhs, Real rhs) {\n return sign(rhs - lhs) >= 0;\n}\n\nbool lt(Real lhs, Real rhs) {\n return sign(rhs - lhs) > 0;\n}\n\nbool gte(Real lhs, Real rhs) {\n return lte(rhs, lhs);\n}\n\nbool gt(Real lhs, Real rhs) {\n return lt(rhs, lhs);\n}\n\nstruct Point {\n Real x;\n Real y;\n Point(Real x = 0, Real y = 0): x(x), y(y) {}\n Point& operator+=(Point rhs) {\n this->x += rhs.x;\n this->y += rhs.y;\n return *this;\n }\n Point& operator-=(Point rhs) {\n this->x -= rhs.x;\n this->y -= rhs.y;\n return *this;\n }\n Point& operator*=(Real k) {\n this->x *= k;\n this->y *= k;\n return *this;\n }\n Point& operator/=(Real k) {\n this->x /= k;\n this->y /= k;\n return *this;\n }\n friend Point operator+(Point lhs, Point rhs) {\n return lhs += rhs;\n }\n friend Point operator-(Point lhs, Point rhs) {\n return lhs -= rhs;\n }\n friend Point operator*(Point p, Real k) {\n return p *= k;\n }\n friend Point operator/(Point p, Real k) {\n return p /= k;\n }\n friend Point operator*(Real k, Point p) {\n return p * k;\n }\n friend Point operator/(Real k, Point p) {\n return p / k;\n }\n friend bool operator==(Point lhs, Point rhs) {\n return eq(lhs.x, rhs.x) && eq(lhs.y, rhs.y);\n }\n friend bool operator!=(Point lhs, Point rhs) {\n return !(lhs == rhs);\n }\n friend bool operator<(Point lhs, Point rhs) {\n if (eq(lhs.x, rhs.x)) return lt(lhs.y, rhs.y);\n return lt(lhs.x, rhs.x);\n }\n friend bool operator<=(Point lhs, Point rhs) {\n return lhs == rhs || lhs < rhs;\n }\n friend bool operator>(Point lhs, Point rhs) {\n return rhs < lhs;\n }\n friend bool operator>=(Point lhs, Point rhs) {\n return rhs <= lhs;\n }\n friend std::istream& operator>>(std::istream& is, Point& p) {\n is >> p.x >> p.y;\n return is;\n }\n friend std::ostream& operator<<(std::ostream& os, Point& p) {\n os << p.x << ' ' << p.y;\n return os;\n }\n};\n\nusing Points = std::vector<Point>;\nusing Polygon = Points;\nusing Vector = Point;\n\nReal norm(Vector p) {\n return p.x * p.x + p.y * p.y;\n}\n\nReal abs(Vector p) {\n return std::sqrt(norm(p));\n}\n\nReal dot(Vector lhs, Vector rhs) {\n return lhs.x * rhs.x + lhs.y * rhs.y;\n}\n\nReal cross(Vector lhs, Vector rhs) {\n return lhs.x * rhs.y - lhs.y * rhs.x;\n}\n\nint ccw(Point p0, Point p1, Point p2) {\n Vector a = p1 - p0;\n Vector b = p2 - p0;\n\n if (cross(a, b) > EPS) return 1;\n\n if (cross(a, b) < -EPS) return -1;\n\n if (dot(a, b) < 0) return 2;\n\n if (norm(a) < norm(b)) return -2;\n\n return 0;\n}\n\nstruct Circle {\n Real r;\n Point c;\n Circle() {}\n Circle(Real r, Point c): r(r), c(c) {}\n};\n\nstruct Segment {\n Segment() {}\n Segment(Point p0, Point p1): p0(p0), p1(p1) {}\n Point p0, p1;\n};\n\nstruct Line {\n Line() {}\n Line(Point p0, Point p1): p0(p0), p1(p1) {}\n explicit Line(Segment s): p0(s.p0), p1(s.p1) {}\n Point p0, p1;\n};\n\nReal distance(Point lhs, Point rhs) {\n return abs(rhs - lhs);\n}\n\nReal distance(Line l, Point p) {\n return std::abs(cross(l.p1 - l.p0, p - l.p0)) / abs(l.p1 - l.p0);\n}\n\nReal distance(Segment s, Point p) {\n if (dot(s.p1 - s.p0, p - s.p0) < 0) {\n return distance(p, s.p0);\n }\n if (dot(s.p0 - s.p1, p - s.p1) < 0) {\n return distance(p, s.p1);\n }\n return distance(Line(s), p);\n}\n\nbool intersect(Segment lhs, Segment rhs) {\n return ccw(lhs.p0, lhs.p1, rhs.p0) * ccw(lhs.p0, lhs.p1, rhs.p1) <= 0\n && ccw(rhs.p0, rhs.p1, lhs.p0) * ccw(rhs.p0, rhs.p1, lhs.p1) <= 0;\n}\n\nbool intersect(Segment s, Point p) {\n return ccw(s.p0, s.p1, p) == 0;\n}\n\nReal distance(Segment lhs, Segment rhs) {\n if (intersect(lhs, rhs)) {\n return Real(0);\n }\n return std::min({distance(lhs, rhs.p0), distance(lhs, rhs.p1), distance(rhs, lhs.p0), distance(rhs, lhs.p1)});\n}\n\nbool parallel(Vector lhs, Vector rhs) {\n return eq(cross(lhs, rhs), 0);\n}\n\nbool parallel(Segment lhs, Segment rhs) {\n return parallel(lhs.p0 - lhs.p1, rhs.p0 - rhs.p1);\n}\n\nbool parallel(Line lhs, Line rhs) {\n return parallel(lhs.p0 - lhs.p1, rhs.p0 - rhs.p1);\n}\n\nPoint crosspoint(Line lhs, Line rhs) {\n Real a = cross(lhs.p1 - lhs.p0, rhs.p1 - rhs.p0);\n Real b = cross(lhs.p1 - lhs.p0, lhs.p1 - rhs.p0);\n return rhs.p0 + (rhs.p1 - rhs.p0) * b / a;\n}\n\nbool intersect(Line l, Segment s) {\n return ccw(l.p0, l.p1, s.p0) * ccw(l.p0, l.p1, s.p1) <= 0;\n}\n\nbool intersect(Circle c, Line l) {\n return lte(distance(l, c.c), c.r);\n}\n\nbool contain(Circle c, Point p) {\n return lt(distance(c.c, p), c.r);\n}\n\nbool intersect(Circle c, Point p) {\n return eq(distance(c.c, p), c.r);\n}\n\nbool internal(Circle c, Point p) {\n return lt(distance(c.c, p), c.r);\n}\n\nbool intersect(Circle c, Segment s) {\n return lte(distance(s, c.c), c.r);\n}\n\nint intersect(Circle lhs, Circle rhs) {\n if (gt(lhs.r, rhs.r)) std::swap(lhs, rhs);\n Real d = distance(lhs.c, rhs.c);\n if (lt(lhs.r + rhs.r, d)) return 4;\n if (eq(lhs.r + rhs.r, d)) return 3;\n if (gt(lhs.r + d, rhs.r)) return 2;\n if (eq(lhs.r + d, rhs.r)) return 1;\n return 0;\n}\n\nbool orthogonal(Vector lhs, Vector rhs) {\n return eq(dot(lhs, rhs), 0);\n}\n\nbool orthogonal(Segment lhs, Segment rhs) {\n return orthogonal(lhs.p0 - lhs.p1, rhs.p0 - rhs.p1);\n}\n\nbool orthogonal(Line lhs, Line rhs) {\n return orthogonal(lhs.p0 - lhs.p1, rhs.p0 - rhs.p1);\n}\n\nPoint crosspoint(Segment lhs, Segment rhs) {\n Real d0 = distance(Line(lhs.p0, lhs.p1), rhs.p0);\n Real d1 = distance(Line(lhs.p0, lhs.p1), rhs.p1);\n return rhs.p0 + (rhs.p1 - rhs.p0) * (d0 / (d0 + d1));\n}\n\nReal arg(Vector p) {\n return std::atan2(p.y, p.x);\n}\n\nVector polar(Real a, Real r) {\n return Point(std::cos(r) * a, std::sin(r) * a);\n}\n\nPoint rotate(Point p, Real t) {\n Point v = polar(1, t);\n return Point(p.x * v.x - p.y * v.y, p.x * v.y + p.y * v.x);\n}\n\nReal angle(Point p0, Point p1, Point p2) {\n Real a = arg(p0 - p1);\n Real b = arg(p2 - p1);\n if (gt(a, b)) std::swap(a, b);\n return std::min(b - a, 2 * PI - (b - a));\n}\n\nPoints crosspoint(Circle lhs, Circle rhs) {\n Real d = abs(lhs.c - rhs.c);\n if (eq(d, lhs.r + rhs.r)) return {lhs.c + lhs.r * (rhs.c - lhs.c) / d};\n Real a = std::acos((lhs.r * lhs.r + d * d - rhs.r * rhs.r) / (2 * lhs.r * d));\n Real t = arg(rhs.c - lhs.c);\n return {lhs.c + polar(lhs.r, t + a), lhs.c + polar(lhs.r, t - a)};\n}\n\nPoint projection(Segment s, Point p) {\n Vector a = p - s.p0;\n Vector b = s.p1 - s.p0;\n Real t = dot(a, b) / norm(b);\n return s.p0 + t * b;\n}\n\nPoint projection(Line l, Point p) {\n Vector a = p - l.p0;\n Vector b = l.p1 - l.p0;\n Real t = dot(a, b) / norm(b);\n return l.p0 + t * b;\n}\n\nPoint reflection(Segment s, Point p) {\n return p + (projection(s, p) - p) * Real(2);\n}\n\nPoint reflection(Line l, Point p) {\n return p + (projection(l, p) - p) * Real(2);\n}\n\nPoints crosspoint(Circle c, Line l) {\n Vector p = projection(l, c.c);\n Real t = std::sqrt(c.r * c.r - norm(c.c - p));\n if (eq(t, 0)) return {p};\n Vector e = (l.p1 - l.p0) / abs(l.p1 - l.p0);\n return {p + t * e, p + -t * e};\n}\n\nPoints crosspoint(Circle c, Segment s) {\n auto cps = crosspoint(c, Line(s));\n Points temp;\n for (auto cp: cps) {\n if (intersect(s, cp)) temp.push_back(cp);\n }\n return temp;\n}\n\nReal area(Polygon poly) {\n int n = poly.size();\n Real result = 0;\n for (int i = 0; i < n; i++) {\n result += cross(poly[i], poly[(i + 1) % n]);\n }\n return result / 2;\n}\n\nReal perimeter(Polygon poly) {\n int n = poly.size();\n Real result = 0;\n for (int i = 0; i < n; i++) {\n result += abs(poly[i] - poly[(i + 1) % n]);\n }\n return result;\n}\n\nbool convex(Polygon poly) {\n int n = poly.size();\n for (int i = 0; i < n; i++) {\n if (ccw(poly[i], poly[(i + 1) % n], poly[(i + 2) % n]) == -1) return false;\n }\n return true;\n}\n\nint contain(Polygon poly, Point p) {\n int n = poly.size();\n bool parity = false;\n for (int i = 0; i < n; i++) {\n Point a = poly[i] - p;\n Point b = poly[(i + 1) % n] - p;\n if (gt(a.y, b.y)) std::swap(a, b);\n if (lte(a.y, 0) && lt(0, b.y) && lt(cross(a, b), 0)) parity ^= true;\n if (eq(cross(a, b), 0) && lte(dot(a, b), 0)) return 1;\n }\n return (parity ? 2 : 0);\n}\n\nPolygon convex_hull(Points points) {\n std::sort(points.begin(), points.end());\n if (points.size() < 3) return points;\n int n = points.size();\n Points lower, upper;\n lower.push_back(points[n - 1]);\n lower.push_back(points[n - 2]);\n upper.push_back(points[0]);\n upper.push_back(points[1]);\n for (int i = n - 3; i >= 0; i--) {\n for (int m = lower.size(); m >= 2 && ccw(lower[m - 2], lower[m - 1], points[i]) >= 0; m--) {\n lower.pop_back();\n }\n lower.push_back(points[i]);\n }\n for (int i = 2; i < n; i++) {\n for (int m = upper.size(); m >= 2 && ccw(upper[m - 2], upper[m - 1], points[i]) >= 0; m--) {\n upper.pop_back();\n }\n upper.push_back(points[i]);\n }\n std::reverse(lower.begin(), lower.end());\n std::copy(std::next(upper.rbegin()), std::prev(upper.rend()), std::back_inserter(lower));\n return lower;\n}\n\nPolygon convex_cut(Polygon poly, Line l) {\n int n = poly.size();\n Polygon res;\n for (int i = 0; i < n; i++) {\n Point a = poly[i];\n Point b = poly[(i + 1) % n];\n if (ccw(l.p0, l.p1, a) != -1) res.push_back(a);\n if (ccw(l.p0, l.p1, a) * ccw(l.p0, l.p1, b) == -1) {\n res.push_back(crosspoint(l, Line(a, b)));\n }\n }\n return res;\n}\n\nLine bisector(Point p0, Point p1, Point p2) {\n return Line(p1, p1 + polar(1, angle(p0, p1, p2) / 2));\n}\n\nCircle incircle(Point p0, Point p1, Point p2) {\n Point c = crosspoint(bisector(p0, p1, p2), bisector(p1, p2, p0));\n Real r = std::abs(2 * area({p0, p1, p2}) / perimeter({p0, p1, p2}));\n return Circle(r, c);\n}\n\nLine perpendicular(Line l, Point p) {\n Vector v = l.p1 - l.p0;\n return Line(p, p + Vector(-v.y, v.x));\n}\n\nLine perpendicular_bisector(Segment s) {\n return perpendicular(Line(s), (s.p0 + s.p1) / 2);\n}\n\nCircle circumscribed_circle(Point p0, Point p1, Point p2) {\n Point c = crosspoint(perpendicular_bisector(Segment(p0, p1)), perpendicular_bisector(Segment(p0, p2)));\n return Circle(distance(p0, c), c);\n}\n\nReal area(Circle c) {\n return c.r * c.r * PI;\n}\n\nPoints tangent(Circle c, Point p) {\n return crosspoint(c, Circle(std::sqrt(norm(c.c - p) - c.r * c.r), p));\n}\n\nbool contain(Polygon ps, Segment s) {\n if (contain(ps, s.p0) == 0 || contain(ps, s.p1) == 0) return false;\n int n = ps.size();\n Points cps;\n cps.push_back(s.p0);\n cps.push_back(s.p1);\n for (int i = 0; i < n; i++) {\n Segment t(ps[i], ps[(i + 1) % n]);\n if (parallel(s, t)) continue;\n if (!intersect(s, t)) continue;\n Point cp = crosspoint(s, t);\n if (cp != s.p0 && cp != s.p1 && cp != t.p0 && cp != t.p1) return false;\n cps.push_back(cp);\n }\n std::sort(cps.begin(), cps.end());\n int m = cps.size();\n for (int i = 0; i + 1 < m; i++) {\n if (contain(ps, (cps[i] + cps[i + 1]) / 2) == 0) return false;\n }\n return true;\n}\n\nstd::pair<Points, Points> lower_and_upper_convex_hull(Polygon ps) {\n auto it = std::max_element(ps.begin(), ps.end());\n Points lower(ps.begin(), it + 1);\n Points upper(it, ps.end());\n upper.push_back(ps.front());\n std::reverse(upper.begin(), upper.end());\n return {lower, upper};\n}\n\nReal y(Line l, Real x) {\n if (eq(l.p0.x, l.p1.x)) return std::min(l.p0.y, l.p1.y);\n return x * (l.p1.y - l.p0.y) / (l.p1.x - l.p0.x);\n}\n\nPolygon common_polygon(Polygon lhs, Polygon rhs) {\n if (lhs.size() < 3 || rhs.size() < 3) return {};\n auto [ll, lu] = lower_and_upper_convex_hull(lhs);\n auto [rl, ru] = lower_and_upper_convex_hull(rhs);\n constexpr Real INF = 1e18;\n ll.push_back(Point(INF, INF));\n lu.push_back(Point(INF, INF));\n rl.push_back(Point(INF, INF));\n ru.push_back(Point(INF, INF));\n\n Points lower, upper;\n for (int i = 0, j = 0, k = 0, l = 0;;) {\n if (ll[i] <= lu[j] && ll[i] <= rl[k] && ll[i] <= ru[l]) {\n if (0 < k && 0 < l) {\n if (lte(y(Line(rl[k - 1], rl[k]), ll[i].x), ll[i].y)\n && lte(ll[i].y, y(Line(ru[l - 1], ru[l]), ll[i].x))) {\n lower.push_back(ll[i]);\n }\n }\n if (i + 2 < (int)ll.size()) {\n Segment lls(ll[i], ll[i + 1]);\n if (0 < k) {\n Segment rls(rl[k - 1], rl[k]);\n if (intersect(lls, rls) && !parallel(lls, rls)) {\n lower.push_back(crosspoint(lls, rls));\n }\n }\n if (0 < l) {\n Segment rus(ru[l - 1], ru[l]);\n if (intersect(lls, rus) && !parallel(lls, rus)) {\n lower.push_back(crosspoint(lls, rus));\n upper.push_back(crosspoint(lls, rus));\n }\n }\n }\n i++;\n if (i + 1 == (int)ll.size() && j + 1 == (int)lu.size()) break;\n } else if (lu[j] <= ll[i] && lu[j] <= rl[k] && lu[j] <= ru[l]) {\n if (0 < k && 0 < l) {\n if (lte(y(Line(rl[k - 1], rl[k]), lu[j].x), lu[j].y)\n && lte(lu[j].y, y(Line(ru[l - 1], ru[l]), lu[j].x))) {\n upper.push_back(lu[j]);\n }\n }\n if (j + 2 < (int)lu.size()) {\n Segment lus(lu[j], lu[j + 1]);\n if (0 < l) {\n Segment rus(ru[l - 1], ru[l]);\n if (intersect(lus, rus) && !parallel(lus, rus)) {\n upper.push_back(crosspoint(lus, rus));\n }\n }\n if (0 < k) {\n Segment rls(rl[k - 1], rl[k]);\n if (intersect(lus, rls) && !parallel(lus, rls)) {\n lower.push_back(crosspoint(lus, rls));\n upper.push_back(crosspoint(lus, rls));\n }\n }\n }\n j++;\n if (i + 1 == (int)ll.size() && j + 1 == (int)lu.size()) break;\n } else if (rl[k] <= ll[i] && rl[k] <= lu[j] && rl[k] <= ru[l]) {\n if (0 < i && 0 < j) {\n if (lte(y(Line(ll[i - 1], ll[i]), rl[k].x), rl[k].y)\n && lte(rl[k].y, y(Line(lu[j - 1], lu[j]), rl[k].x))) {\n lower.push_back(rl[k]);\n }\n }\n if (k + 2 < (int)rl.size()) {\n Segment rls(rl[k], rl[k + 1]);\n if (0 < i) {\n Segment lls(ll[i - 1], ll[i]);\n if (intersect(rls, lls) && !parallel(rls, lls)) {\n lower.push_back(crosspoint(rls, lls));\n }\n }\n if (0 < j) {\n Segment lus(lu[j - 1], lu[j]);\n if (intersect(rls, lus) && !parallel(rls, lus)) {\n lower.push_back(crosspoint(rls, lus));\n upper.push_back(crosspoint(rls, lus));\n }\n }\n }\n k++;\n if (k + 1 == (int)rl.size() && l + 1 == (int)ru.size()) break;\n } else {\n if (0 < i && 0 < j) {\n if (lte(y(Line(ll[i - 1], ll[i]), ru[l].x), ru[l].y)\n && lte(ru[l].y, y(Line(lu[j - 1], lu[j]), ru[l].x))) {\n upper.push_back(ru[l]);\n }\n }\n if (l + 2 < (int)ru.size()) {\n Segment rus(ru[l], ru[l + 1]);\n if (0 < j) {\n Segment lus(lu[j - 1], lu[j]);\n if (intersect(rus, lus) && !parallel(rus, lus)) {\n upper.push_back(crosspoint(rus, lus));\n }\n }\n if (0 < i) {\n Segment lls(ll[i - 1], ll[i]);\n if (intersect(rus, lls) && !parallel(rus, lls)) {\n lower.push_back(crosspoint(rus, lls));\n upper.push_back(crosspoint(rus, lls));\n }\n }\n }\n l++;\n if (k + 1 == (int)rl.size() && l + 1 == (int)ru.size()) break;\n }\n }\n if (lower.empty() && upper.empty()) return {};\n std::cerr << lhs.size() << ' ' << rhs.size() << ' ' << lower.size() << ' ' << upper.size() << std::endl;\n\n std::copy(std::next(upper.rbegin()), std::prev(upper.rend()), std::back_inserter(lower));\n return lower;\n}\n\nbool intersect(Polygon lhs, Polygon rhs) {\n return lt(0, area(common_polygon(lhs, rhs)));\n}\n\nusing ll = long long;\n\n#define rep(i, l, r) for (ll i = (l); i < (r); i++)\n#define rrep(i, r, l) for (ll i = (r); i-- > (l);)\ntemplate <class T, class U>\nbool chmin(T& lhs, U rhs) {\n return lhs > rhs ? (lhs = rhs, true) : false;\n}\ntemplate <class T, class U>\nbool chmax(T& lhs, U rhs) {\n return lhs < rhs ? (lhs = rhs, true) : false;\n}\nusing namespace std;\n\nint solve() {\n int n;\n cin >> n;\n if (n == 0) return 1;\n vector<Circle> cs(n);\n rep(i, 0, n) {\n cin >> cs[i].c >> cs[i].r;\n }\n\n Points ps;\n ps.push_back(cs[0].c);\n ps.push_back(cs[n - 1].c);\n rep(i, 0, n - 1) {\n auto temp = crosspoint(cs[i], cs[i + 1]);\n copy(temp.begin(), temp.end(), back_inserter(ps));\n }\n\n int m = ps.size();\n constexpr Real INF = 1e18;\n vector dist(m, vector<Real>(m, INF));\n rep(i, 0, m) dist[i][i] = 0;\n rep(i, 0, m) rep(j, i + 1, m) if (i != j) {\n Segment s(ps[i], ps[j]);\n Points cps;\n cps.push_back(ps[i]);\n cps.push_back(ps[j]);\n rep(k, 0, n) {\n if (intersect(cs[k], s)) {\n auto temp = crosspoint(cs[k], s);\n copy(temp.begin(), temp.end(), back_inserter(cps));\n }\n }\n sort(cps.begin(), cps.end());\n bool out = false;\n rep(k, 0, (int)cps.size() - 1) {\n Point mid = (cps[k] + cps[k + 1]) / 2;\n bool ok = false;\n rep(l, 0, n) {\n if (intersect(cs[l], mid) || contain(cs[l], mid)) {\n ok = true;\n break;\n }\n }\n if (!ok) {\n out = true;\n break;\n }\n }\n if (!out) {\n dist[i][j] = dist[j][i] = distance(ps[i], ps[j]);\n }\n }\n rep(k, 0, m) rep(i, 0, m) rep(j, 0, m) {\n chmin(dist[i][j], dist[i][k] + dist[k][j]);\n }\n cout << fixed << setprecision(10);\n cout << dist[0][1] << '\\n';\n return 0;\n}\n\nint main() {\n while (!solve())\n ;\n}", "accuracy": 1, "time_ms": 1510, "memory_kb": 4412, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_1183_9313541", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vd = vector<double>;\nusing vvd = vector<vd>;\nusing vvvd = vector<vvd>;\n#define all(A) A.begin(),A.end()\n#define ALL(A) A.begin(),A.end()\n#define rep(i, n) for (int i = 0; i < (int) (n); i++)\n// template<class T>\n// void chmax(T& p, T q) { if (p < q)p = q; };\n\n//mugenさんライブラリ. \n#include<complex>\n#define mod 1000000007\nusing ll = long long;\nconst int INF = 1000000000;\nconst ll LINF = 1001002003004005006ll;\nint dx[] = { 1,0,-1,0 }, dy[] = { 0,1,0,-1 };\n// ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; }return false; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return true; }return false; }\n\nusing Real = double;\nconst Real EPS = 1e-6;\nconst Real pi = acosl(-1);\n\n\n// Point\nusing Point = complex<Real>;\nistream& operator>>(istream& is, Point& p) {\n Real a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n}\nostream& operator<<(ostream& os, Point& p) {\n return os << fixed << setprecision(12) << p.real() << ' ' << p.imag();\n}\ninline bool eq(Real a, Real b) {\n return fabs(a - b) < EPS;\n}\nPoint operator*(const Point& p, const Real& d) {\n return Point(real(p) * d, imag(p) * d);\n}\n\n// Line\nstruct Line {\n Point p1, p2;\n Line() = default;\n Line(Point p1, Point p2) :p1(p1), p2(p2) {}\n //Ax + By = C\n Line(Real A, Real B, Real C) {\n if (eq(A, 0)) p1 = Point(0, C / B), p2 = Point(1, C / B);\n else if (eq(B, 0))p1 = Point(C / A, 0), p2 = Point(C / A, 1);\n else p1 = Point(0, C / B), p2 = Point(C / A, 0);\n }\n};\n\n// Segment\nstruct Segment :Line {\n Segment() = default;\n Segment(Point p1, Point p2) :Line(p1, p2) {}\n};\nstruct Circle {\n Point center;\n Real r;\n Circle() = default;\n Circle(Point center, Real r) :center(center), r(r) {}\n};\n\nPoint rotate(Real theta, Point p) {\n return Point(cos(theta) * real(p) - sin(theta) * imag(p), sin(theta) * real(p) + cos(theta) * imag(p));\n}\nReal dot(Point a, Point b) {\n return real(a) * real(b) + imag(a) * imag(b);\n}\nReal cross(Point a, Point b) {\n return real(a) * imag(b) - imag(a) * real(b);\n}\nint ccw(Point a, Point b, Point c) {\n b -= a; c -= a;\n if (cross(b, c) > EPS) return 1;//COUNTER CLOCKWISE\n else if (cross(b, c) < -EPS) return -1;//CLOCKWISE\n else if (dot(b, c) < 0) return 2;//c--a--b ONLINE BACK\n else if (norm(b) < norm(c)) return -2;//a--b--c ONLINE FRONT\n else return 0;//a--c--b ON SEGMENT\n}\n//線分と線分の交差判定\nbool intersect(Segment s, Segment t) {\n return ccw(s.p1, s.p2, t.p1) * ccw(s.p1, s.p2, t.p2) <= 0 && ccw(t.p1, t.p2, s.p1) * ccw(t.p1, t.p2, s.p2) <= 0;\n}\n//円と円の位置関係,共通接線の個数を返す\nint intersect(Circle c1, Circle c2) {\n if (c1.r < c2.r) swap(c1, c2);\n Real d = abs(c1.center - c2.center);\n //2円が離れている\n if (c1.r + c2.r < d) return 4;\n //2円が外接する\n if (eq(c1.r + c2.r, d)) return 3;\n //2円が交わる\n if (c1.r - c2.r < d) return 2;\n //円が内接する\n if (eq(c1.r - c2.r, d)) return 1;\n //内包\n return 0;\n}\nReal dis(Point a, Point b) {\n return abs(a - b);\n}\nvector<Point> crosspoint(Circle c1, Circle c2) {\n vector<Point> ret;\n int isec = intersect(c1, c2);\n if (isec == 0 || isec == 4) return ret;\n Real d = abs(c1.center - c2.center);\n Real a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d));\n Real t = atan2(c2.center.imag() - c1.center.imag(), c2.center.real() - c1.center.real());\n ret.push_back(c1.center + Point(cos(t + a) * c1.r, sin(t + a) * c1.r));\n ret.push_back(c1.center + Point(cos(t - a) * c1.r, sin(t - a) * c1.r));\n return ret;\n}\n\nvoid solve(ll N) {\n vector<Circle> C(N);\n vector<Point> CO(N);\n rep(i, N) {\n double x, y, r;\n \n cin >> x >> y >> r; CO[i] = { x,y };\n C[i] = Circle({ x,y }, r);\n }\n vector<vector<Point>> P(N - 1);\n rep(i, N - 1)P[i] = crosspoint(C[i], C[i + 1]);\n bool OK=1;\n rep(k,N-1){\n if (!intersect(Segment(P[k][0], P[k][1]), Segment(CO[0], CO[N-1])))OK = 0;\n }\n if(OK){\n cout<<dis(CO[0],CO[N-1])<<endl;\n return;\n }\n vvd dist(N - 1, vd(2, 1e18));\n rep(i, N - 1) {\n rep(j, 2) {\n OK = 1;\n rep(k, i) {\n if (!intersect(Segment(P[k][0], P[k][1]), Segment(CO[0], P[i][j])))OK = 0;\n }\n if (OK) {\n dist[i][j] = dis(CO[0], P[i][j]);\n }\n }\n }\n rep(i, N - 1) {\n chmin(dist[i][0], dist[i][1] + dis(P[i][0], P[i][1]));\n chmin(dist[i][1], dist[i][0] + dis(P[i][0], P[i][1]));\n rep(j, 2) {\n for (ll p = i + 1; p < N - 1; p++) {\n rep(q, 2) {\n OK = 1;\n for (ll k = i + 1; k < p; k++) {\n if (!intersect(Segment(P[k][0], P[k][1]), Segment(P[p][q], P[i][j])))OK = 0;\n }\n if (OK)chmin(dist[p][q], dist[i][j] + dis(P[i][j], P[p][q]));\n }\n }\n }\n }\n double an = 1e18;\n rep(i, N - 1) {\n rep(j, 2) {\n OK = 1;\n for (ll k = i + 1; k < N - 1; k++) {\n if (!intersect(Segment(P[k][0], P[k][1]), Segment(CO[N - 1], P[i][j])))OK = 0;\n }\n if (OK)chmin(an, dist[i][j] + dis(P[i][j], CO[N - 1]));\n }\n }\n cout << fixed << setprecision(15) << an << endl;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n\n ll N;\n while (cin >> N) {\n if (N == 0)return 0;\n solve(N);\n }\n\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 4204, "score_of_the_acc": -0.8103, "final_rank": 16 }, { "submission_id": "aoj_1183_9211276", "code_snippet": "#include <bits/stdc++.h>\n\nusing R = long double;\nusing Point = std::pair<R, R>;\nusing Segment = std::pair<Point, Point>;\nusing Circle = std::pair<Point, R>;\n\nstd::ostream& operator<<(std::ostream& os, const Point& p) {\n os << '(' << p.first << ',' << p.second << ')';\n return os;\n}\n\nconst R EPS{1e-12l};\nconst R PI{acosl(-1.0l)};\n\nbool Negative(R v) {\n return v < -EPS;\n}\nbool Positive(R v) {\n return v > EPS;\n}\nbool Zero(R v) {\n return !Negative(v) and !Positive(v);\n}\nbool Smaller(R a, R b) {\n return Negative(a - b);\n}\nbool Bigger(R a, R b) {\n return Positive(a - b);\n}\nbool Equal(R a, R b) {\n return !Smaller(a, b) and !Bigger(a, b);\n}\n\nR Square(R v) {\n return (Zero(v) ? 0.0l : v * v);\n}\n\nPoint operator+(const Point& p, const Point& q) {\n return Point{p.first + q.first, p.second + q.second};\n}\n\nPoint operator-(const Point& p, const Point& q) {\n return Point{p.first - q.first, p.second - q.second};\n}\n\nPoint operator*(const Point& p, R v) {\n return Point{ p.first * v, p.second * v };\n}\n\nPoint operator/(const Point& p, R v) {\n assert(!Zero(v));\n return Point{ p.first / v, p.second / v };\n}\n\nR NormSquare(const Point& p) {\n return Square(p.first) + Square(p.second);\n}\n\nR Norm(const Point& p) {\n return sqrtl(NormSquare(p));\n}\n\nR DistanceSquare(const Point& p, const Point& q) {\n return NormSquare(p - q);\n}\n\nR Distance(const Point& p, const Point& q) {\n return sqrtl(DistanceSquare(p, q));\n}\n\nint NumberCommonTangent(const Circle& l, const Circle& r) {\n R dist{DistanceSquare(l.first, r.first)};\n R down{Square(std::abs(l.second - r.second))};\n if (Smaller(dist, down)) return 0;\n if (Equal(dist, down)) return 1;\n R up{Square(l.second + r.second)};\n if (Smaller(dist, up)) return 2;\n if (Equal(dist, up)) return 3;\n return 4;\n}\n\n// bool Intersect(const Circle& l, const Circle& r) {\n// int num{NumberCommonTangent(l, r)};\n// return 0 < num and num < 4;\n// }\n\nPoint Normalized(const Point& p) {\n return p / Norm(p);\n}\n\nR ArcToRad(R arc) {\n return (arc * PI) / 180.0l;\n}\n\nPoint RotatedByArc(const Point& p, R arc) {\n R rad{ArcToRad(arc)};\n return Point{\n p.first * cosl(rad) - p.second * sinl(rad),\n p.first * sinl(rad) + p.second * cosl(rad)\n };\n}\n\nstd::vector<Point> CrossPoint(const Circle& l, const Circle& r) {\n {\n int num{NumberCommonTangent(l, r)};\n assert(num == 2);\n }\n // assert(Intersect(l, r));\n assert(Positive(l.second));\n assert(Positive(r.second));\n R d{Distance(l.first, r.first)};\n R cosine{(Square(l.second) + Square(d) - Square(r.second)) / (2.0l * l.second * d)};\n R rc{l.second * cosine};\n R rs{sqrtl(Square(l.second) - Square(rc))};\n Point lr{Normalized(r.first - l.first)};\n Point h{l.first + lr * rc};\n std::vector<Point> res;\n res.push_back(h + RotatedByArc(lr, 90.0l) * rs);\n res.push_back(h + RotatedByArc(lr, -90.0l) * rs);\n return res;\n}\n\nenum RELATION {\n ONLINE_FRONT = -2,\n CLOCKWISE,\n ON_SEGMENT,\n COUNTER_CLOCKWISE,\n ONLINE_BACK\n};\n\nR Cross(const Point& p, const Point& q) {\n return p.first * q.second - p.second * q.first;\n}\n\nR Dot(const Point& p, const Point& q) {\n return p.first * q.first + p.second * q.second;\n}\n\nRELATION Relation(const Point& p0, const Point& p1, const Point& p2) {\n Point a{p1 - p0}, b{p2 - p0};\n if (Positive(Cross(a, b))) return COUNTER_CLOCKWISE;\n if (Negative(Cross(a, b))) return CLOCKWISE;\n if (Negative(Dot(a, b))) return ONLINE_BACK;\n if (Smaller(NormSquare(a), NormSquare(b))) return ONLINE_FRONT;\n return ON_SEGMENT;\n}\n\nbool Straddle(const Segment& l, const Segment& r) {\n return Relation(l.first, l.second, r.first) * Relation(l.first, l.second, r.second) <= 0;\n}\n\nbool Intersect(const Segment& l, const Segment& r) {\n return Straddle(l, r) and Straddle(r, l);\n}\n\nR Length(const Segment& s) {\n return Distance(s.first, s.second);\n}\n\nbool solve() {\n int N;\n std::cin >> N;\n if (N == 0) return false;\n std::vector<Circle> C(N);\n for (auto& [p, r] : C) {\n std::cin >> p.first >> p.second >> r;\n }\n // 円の交点の列挙\n std::vector<std::vector<Point>> P(N - 1); \n for (int i{} ; i < N - 1 ; i++) {\n for (const auto& p : CrossPoint(C[i], C[i + 1])) {\n P[i].push_back(p);\n }\n }\n // 円の交点を結ぶ線分の列挙\n std::vector<Segment> S(N - 1);\n for (int i{} ; i < N - 1 ; i++) {\n assert(P[i].size() == 2u);\n S[i] = Segment{P[i][0], P[i][1]};\n }\n // グラフの構築\n std::vector<std::vector<int>> id(N - 1);\n int n{};\n for (int i{} ; i < N - 1 ; i++) {\n id[i] = std::vector<int>(P[i].size());\n for (int j{} ; j < (int)P[i].size() ; j++) {\n id[i][j] = n++;\n }\n }\n std::vector g(n + 2, std::vector<R>(n + 2, (long double)1e18));\n for (int i{} ; i < n + 2 ; i++) {\n g[i][i] = 0;\n }\n for (int i{} ; i < N - 1 ; i++) {\n for (int j{} ; j < (int)P[i].size() ; j++) {\n bool ok{true};\n Segment s{C[0].first, P[i][j]};\n for (int k{} ; k < i ; k++) {\n ok &= Intersect(s, S[k]);\n }\n if (ok) {\n g[n][id[i][j]] = Length(s);\n }\n }\n }\n for (int i{} ; i < N - 1 ; i++) {\n for (int j{} ; j < (int)P[i].size() ; j++) {\n bool ok{true};\n Segment s{P[i][j], C[N - 1].first};\n for (int k{i + 1} ; k < N - 1 ; k++) {\n ok &= Intersect(s, S[k]);\n }\n if (ok) g[id[i][j]][n + 1] = Length(s);\n }\n }\n for (int i{} ; i < N - 1 ; i++) {\n for (int j{i + 1} ; j < N - 1 ; j++) {\n for (int k{} ; k < (int)P[i].size() ; k++) {\n for (int l{} ; l < (int)P[j].size() ; l++) {\n Segment s{P[i][k], P[j][l]};\n bool ok{true};\n for (int m{i + 1} ; m < j ; m++) {\n ok &= Intersect(s, S[m]);\n }\n if (ok) g[id[i][k]][id[j][l]] = Length(s);\n }\n }\n }\n }\n {\n bool ok{true};\n Segment s{C[0].first, C[N - 1].first};\n for (int i{} ; i < N - 1 ; i++) {\n ok &= Intersect(s, S[i]);\n }\n if (ok) g[n][n + 1] = Length(s);\n }\n // wf\n for (int k{} ; k < n + 2 ; k++) {\n for (int i{} ; i < n + 2 ; i++) {\n for (int j{} ; j < n + 2 ; j++) {\n g[i][j] = std::min(g[i][j], g[i][k] + g[k][j]);\n }\n }\n }\n std::cout << g[n][n + 1] << '\\n';\n return true;\n}\n\n\nint main() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n std::cout << std::fixed << std::setprecision(5);\n while (solve()) ;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 4352, "score_of_the_acc": -1.1652, "final_rank": 18 }, { "submission_id": "aoj_1183_8372030", "code_snippet": "#include <bits/stdc++.h>\n// #include <atcoder/modint>\n#define rng(a) a.begin(),a.end()\n#define rrng(a) a.rbegin(),a.rend()\n#define INF 2000000000000000000\n#define ull unsigned long long\n#define ll long long\n#define ld long double\n#define pll pair<ll, ll>\nusing namespace std;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\n\nconst ld EPS = 1e-7;\n\nstruct Point {\n ld x, y;\n Point(ld x = 0.0, ld y = 0.0) : x(x), y(y) {}\n\n ld cross(const Point &b) const {\n return x * b.y - y * b.x;\n }\n\n ld dot(const Point&b) const {\n return x * b.x + y * b.y;\n }\n};\ninline Point operator + (const Point &p, const Point &q) { return Point(p.x +q.x, p.y + q.y);}\ninline Point operator - (const Point &p, const Point &q) { return Point(p.x -q.x, p.y - q.y);}\ninline ld dot(const Point &p, const Point &q) {return p.x * q.x + p.y * q.y;}\ninline ld abs(const Point &p) {return sqrt(dot(p, p));}\ninline Point operator / (const Point &p, ld a) {return Point(p.x / a, p.y / a);}\ninline Point operator * (const Point &p, const Point &q) {return Point(p.x * q.x - p.y * q.y, p.x * q.y + p.y * q.x);}\ninline bool eq(const Point &p, const Point &q) {return abs(p - q) < EPS;}\n// inline Point cross(const Point& p, const Point &q) {\n// return p.x * q.y - p.y * q.x;\n// }\n\nstruct Circle: Point {\n ld r;\n Point p;\n Circle(Point p = Point(0.0, 0.0), ld r = 0.0): Point(p), r(r) {}\n};\n\nvector<Point> crosspoint(const Circle &e, const Circle &f) {\n vector<Point> res;\n ld d = abs(e - f);\n if (d < EPS) {\n return vector<Point>();\n }\n if (d > e.r + f.r + EPS) {\n return vector<Point>();\n }\n if (d < abs(e.r - f.r) - EPS) {\n return vector<Point>();\n }\n ld rcos = (d * d + e.r * e.r - f.r * f.r) / (2.0 * d), rsin;\n if (e.r - abs(rcos) < EPS) {\n rsin = 0;\n }\n else {\n rsin = sqrt(e.r * e.r - rcos * rcos);\n }\n Point dir = (f - e) / d;\n Point p1 = e + dir * Point(rcos, rsin);\n Point p2 = e + dir * Point(rcos, -rsin);\n res.push_back(p1);\n if (!eq(p1, p2)) {\n res.push_back(p2);\n }\n return res;\n}\n\nstruct Line {\n Point begin, end;\n\n Line(const Point &b, const Point &e) {\n begin = b, end = e;\n }\n\n Point vec() const {\n return end - begin;\n }\n};\n\nint sgn(const ld a) {\n return (a < -EPS ? -1: (a > EPS ? +1: 0));\n}\n\nint iSP(const Point &a, const Point& b, const Point&c) {\n int flg = sgn((b - a).cross(c - a));\n if (flg == 1) {\n return +1;\n }\n else if (flg == -1) {\n return -1;\n }\n else {\n if (sgn((b - a).dot(c - b)) > 0)\n return +2;\n else if (sgn((a - b).dot(c - a)) > 0)\n return -2;\n else\n return 0;\n }\n}\n\nconst Point error_val = {12121212.0, -3324134.0};\npair<bool, Point> segmentIntersection(const Line &s1, const Line& s2) {\n if (iSP(s1.begin, s1.end, s2.begin) * iSP(s1.begin, s1.end, s2.end) <= 0 && iSP(s2.begin, s2.end, s1.begin) * iSP(s2.begin, s2.end, s1.end) <= 0) {\n if (s1.vec().cross(s2.vec()) == 0)\n return pair<bool, Point>{true, error_val};\n else\n return make_pair(true, error_val);\n }\n return make_pair(false, error_val);\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n while (true) {\n \n ll N;\n cin >> N;\n if (N == 0) {\n break;\n }\n vector<Circle> circle(N);\n for (ll i = 0; i < N; ++i) {\n ll x, y, r;\n cin >> x >> y >> r;\n circle.at(i) = Circle(Point(x, y), r);\n }\n vector<Point> point;\n vector<Line> lines;\n point.push_back({circle.at(0).x, circle.at(0).y});\n for (ll i = 0; i < N - 1; ++i) {\n vector<Point> temp = crosspoint(circle.at(i), circle.at(i + 1));\n for (ll j = 0; j < 2; ++j) {\n point.push_back(temp.at(j));\n }\n lines.push_back(Line(temp.at(0), temp.at(1)));\n }\n point.push_back({circle.at(N - 1).x, circle.at(N - 1).y});\n ll M = point.size();\n vector<ld> dp(M, INF);\n dp.at(0) = 0;\n // for (ll i = 0; i < point.size(); ++i) {\n // cout << point.at(i).x << ' ' << point.at(i).y << \"\\n\";\n // }\n for (ll i = 0; i < M - 1; ++i) {\n ll i_index = (i + 1) / 2;\n for (ll j = i + 1; j < M; ++j) {\n ll j_index = min((ll)lines.size(), (j + 1) / 2);\n // cout << i << ' ' << i_index << ' ' << j << ' ' << j_index << \"\\n\";\n bool ok = true;\n Line l = Line(point.at(i), point.at(j));\n for (ll k = i_index; k < j_index; ++k) {\n pair<bool, Point> p = segmentIntersection(l, lines.at(k));\n if (!p.first) {\n ok = false;\n }\n }\n if (ok) {\n chmin(dp.at(j), dp.at(i) + abs(point.at(i) - point.at(j)));\n // cout << \"ok\" << \"\\n\";\n }\n }\n }\n cout << fixed << setprecision(15);\n // for (ll i = 0; i < M; ++i) {\n // cout << dp.at(i) << \" \";\n // }\n // cout << \"\\n\";\n cout << dp.at(M - 1) << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3552, "score_of_the_acc": -0.1761, "final_rank": 2 }, { "submission_id": "aoj_1183_8011335", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <bitset>\n#include <cassert>\n#include <cmath>\n#include <complex>\n#include <iomanip>\n#include <iostream>\n#include <limits>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <random>\n#include <set>\n#include <stack>\n#include <string>\n#include <tuple>\n#include <utility>\n#include <vector>\n\n#define rep(i,s,n) for(int i = int(s); i < int(n); i++)\n#define rrep(i,s,n) for(int i = int(n) - 1; i >= int(s); i--)\n#define all(v) v.begin(), v.end()\n\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\n\ntemplate<class T>\nbool chmin(T &a, T b) {\n if(a <= b) return false;\n a = b;\n return true;\n}\n\ntemplate<class T>\nbool chmax(T &a, T b) {\n if(a >= b) return false;\n a = b;\n return true;\n}\n\nusing namespace std;\n\nusing vec = complex<ld>;\nconst ld PI = acos(-1);\n\nvoid ldout(int len = 20){\n cout << fixed << setprecision(len);\n}\n\nint sgn(ld a, const ld eps = 1e-7){\n return (a < -eps) ? -1 : (a > eps) ? 1 : 0;\n}\n\nld dot(const vec &a, const vec &b){\n return (conj(a) * b).real();\n}\n\nld cross(const vec &a, const vec &b){\n return (conj(a) * b).imag();\n}\n\nint isp(const vec &a, const vec &b, const vec &c){\n int cross_sgn = sgn(cross(b-a, c-a));\n if (cross_sgn == 0){\n if (sgn(dot(b-a, c-a)) < 0) return -2;\n if (sgn(dot(a-b, c-b)) < 0) return 2;\n }\n return cross_sgn;\n}\n\nvec rot90(const vec &a){\n return {-a.imag(), a.real()};\n}\n\nstruct circle{\n vec c;\n ld r;\n};\n\nvector<vec> cross_point(const circle &c1, const circle &c2){\n vector<vec> ps;\n ld d = abs(c2.c-c1.c);\n ld x = (d*d + c1.r*c1.r - c2.r*c2.r) / (2*d);\n vec p = c1.c + (c2.c - c1.c) * x / d;\n vec v = rot90(c2.c - c1.c);\n v *= sqrtl(max(c1.r*c1.r-x*x,ld(0))) / abs(v);\n ps.emplace_back(p+v);\n ps.emplace_back(p-v);\n return ps;\n}\n\nstruct segment{\n vec a, b;\n};\n\nbool intersection_segment(const segment &a, const segment &b){\n if (sgn(isp(a.a, a.b, b.a) * isp(a.a, a.b, b.b)) <= 0 &&\n sgn(isp(b.a, b.b, a.a) * isp(b.a, b.b, a.b)) <= 0){\n return true;\n }else{\n return false;\n }\n}\n\nconst ld dinf = 2e9;\n\nvoid solve(int n){\n vector<circle> a(n);\n rep(i,0,n){\n ld x, y, r; cin >> x >> y >> r;\n a[i] = circle({vec(x,y),r});\n }\n vector<vec> ps(2*n);\n rep(i,0,n-1){\n vector<vec> cur = cross_point(a[i],a[i+1]);\n ps[2*i] = cur[0];\n ps[2*i+1] = cur[1];\n }\n ps[2*n-2] = a[0].c;\n ps[2*n-1] = a[n-1].c;\n vector<vector<ld>> dist(2*n,vector<ld>(2*n,dinf));\n auto add = [&](int u, int v, ld d){\n chmin(dist[u][v],d);\n chmin(dist[v][u],d);\n };\n // 2n-2 -> i\n rep(i,0,n-1){\n vec p = ps[2*n-2];\n rep(j,0,2){\n vec q = ps[2*i+j];\n bool ok = true;\n for (int k = 0; k < i; k++){\n segment test({ps[2*k],ps[2*k+1]});\n if (intersection_segment(segment({p,q}),test)){\n continue;\n }\n ok = false;\n break;\n }\n if (ok){\n add(2*n-2,2*i+j,abs(p-q));\n }\n }\n }\n // 2n-1 -> i\n rep(i,0,n-1){\n vec p = ps[2*n-1];\n rep(j,0,2){\n vec q = ps[2*i+j];\n bool ok = true;\n for (int k = i+1; k < n-1; k++){\n segment test({ps[2*k],ps[2*k+1]});\n if (intersection_segment(segment({p,q}),test)){\n continue;\n }\n ok = false;\n break;\n }\n if (ok){\n add(2*n-1,2*i+j,abs(p-q));\n }\n }\n }\n // 2n-2 -> 2n-1\n {\n bool ok = true;\n vec p = ps[2*n-2], q = ps[2*n-1];\n rep(k,0,n-1){\n segment test({ps[2*k],ps[2*k+1]});\n if (intersection_segment(segment({p,q}),test)){\n continue;\n }\n ok = false;\n break;\n }\n if (ok) add(2*n-2,2*n-1,abs(p-q));\n }\n // i -> j\n rep(i1,0,n-1) rep(j1,0,2) rep(i2,i1,n-1) rep(j2,0,2){\n vec p = ps[2*i1+j1], q = ps[2*i2+j2];\n bool ok = true;\n for (int k = i1+1; k < i2; k++){\n segment test({ps[2*k],ps[2*k+1]});\n if (intersection_segment(segment({p,q}),test)){\n continue;\n }\n ok = false;\n break;\n }\n if (ok) add(2*i1+j1,2*i2+j2,abs(p-q));\n }\n rep(i,0,2*n) dist[i][i] = 0;\n rep(k,0,2*n) rep(i,0,2*n) rep(j,0,2*n){\n chmin(dist[i][j],dist[i][k]+dist[k][j]);\n }\n cout << dist[2*n-2][2*n-1] << endl;\n}\n\nint main() {\n ldout(15);\n while (true){\n int n; cin >> n;\n if (n == 0) break;\n solve(n);\n } \n}", "accuracy": 1, "time_ms": 220, "memory_kb": 4104, "score_of_the_acc": -0.79, "final_rank": 15 }, { "submission_id": "aoj_1183_7954378", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long double D;\ntypedef complex<D> P;\nconst D eps = 1e-9;\nconst D INF = 1000000000.0;\n#define X real()\n#define Y imag()\n#define EQ(n,m) (abs((n) - (m)) < eps)\n\n// 内積 dot(a,b) = |a||b|cosθ\nD dot(P a, P b) {\n return (conj(a)*b).X;\n}\n// 外積 cross(a,b) = |a||b|sinθ\nD cross(P a, P b) {\n return (conj(a)*b).Y;\n}\n// 点の進行方向\nint ccw(P a, P b, P c) {\n b -= a; c -= a;\n if (cross(b,c) > eps) return +1; // counter clockwise\n if (cross(b,c) < -eps) return -1; // clockwise\n if (dot(b,c) < -eps) return +2; // c--a--b on line\n if (norm(b) < norm(c)) return -2; // a--b--c on line or a==b\n return 0; // a--c--b on line or a==c or b==c\n}\n\n// 線分と線分\nbool isecSS(P a1, P a2, P b1, P b2) {\n return ccw(a1, a2, b1)*ccw(a1, a2, b2) <= 0 &&\n ccw(b1, b2, a1)*ccw(b1, b2, a2) <= 0;\n}\n\nvector<P> crosspointCC(P a, D ar, P b, D br){\n vector<P> ps;\n P ab = b - a;\n D d = abs(ab);\n D crL = (norm(ab) + ar*ar - br*br) / (2*d);\n if (EQ(d,0) || ar < abs(crL)) return ps; // 交わりなし\n P abN = ab * P(0, sqrt(ar * ar - crL * crL) / d);\n P cp = a + crL / d * ab;\n ps.push_back(cp + abN);\n if(!EQ(norm(abN), 0)) ps.push_back(cp - abN);\n return ps;\n}\n\nint main(){\n while(true){\n int n;\n cin >> n;\n if(n == 0)break;\n vector<P> z(n);\n vector<D> r(n);\n for(int i = 0; i < n; i++){\n D x,y;\n cin >> x >> y >> r[i];\n z[i] = P(x,y);\n }\n \n vector<vector<P>> CC(n+1);\n CC[0] = vector<P> (2,z[0]);\n for(int i = 0; i < n - 1; i++){\n CC[i+1] = crosspointCC(z[i], r[i], z[i+1], r[i+1]);\n }\n CC[n] = vector<P> (2,z[n-1]);\n vector<vector<D>> dp(n+1, vector<D>(2, INF));\n dp[0][0] = 0;\n dp[0][1] = 0;\n \n for(int i = 0; i <= n; i++){\n for(int pi = 0; pi < 2; pi++){\n for(int j = i + 1; j <= n; j++){\n for(int pj = 0; pj < 2; pj++){\n bool ok = true;\n for(int k = i + 1; k < j; k++){\n ok &= isecSS(CC[i][pi], CC[j][pj], CC[k][0], CC[k][1]);\n }\n if(ok){\n dp[j][pj] = min(dp[j][pj], dp[i][pi] + abs(CC[j][pj] - CC[i][pi]));\n }\n }\n }\n }\n }\n cout << fixed << setprecision(10) << dp[n][0] << endl;\n }\n}", "accuracy": 1, "time_ms": 450, "memory_kb": 3584, "score_of_the_acc": -0.3524, "final_rank": 6 }, { "submission_id": "aoj_1183_7220429", "code_snippet": "//#define _GLIBCXX_DEBUG\n\n#include<bits/stdc++.h>\nusing namespace std;\n\n#define endl '\\n'\n#define lfs cout<<fixed<<setprecision(10)\n#define ALL(a) (a).begin(),(a).end()\n#define ALLR(a) (a).rbegin(),(a).rend()\n#define UNIQUE(a) (a).erase(unique((a).begin(),(a).end()),(a).end())\n#define spa << \" \" <<\n#define fi first\n#define se second\n#define MP make_pair\n#define MT make_tuple\n#define PB push_back\n#define EB emplace_back\n#define rep(i,n,m) for(ll i = (n); i < (ll)(m); i++)\n#define rrep(i,n,m) for(ll i = (ll)(m) - 1; i >= (ll)(n); i--)\nusing ll = long long;\nusing ld = long double;\nconst ll MOD1 = 1e9+7;\nconst ll MOD9 = 998244353;\nconst ll INF = 1e18;\nusing P = pair<ll, ll>;\ntemplate<typename T> using PQ = priority_queue<T>;\ntemplate<typename T> using QP = priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T1, typename T2>bool chmin(T1 &a,T2 b){if(a>b){a=b;return true;}else return false;}\ntemplate<typename T1, typename T2>bool chmax(T1 &a,T2 b){if(a<b){a=b;return true;}else return false;}\nll median(ll a,ll b, ll c){return a+b+c-max({a,b,c})-min({a,b,c});}\nvoid ans1(bool x){if(x) cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;}\nvoid ans2(bool x){if(x) cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;}\nvoid ans3(bool x){if(x) cout<<\"Yay!\"<<endl;else cout<<\":(\"<<endl;}\ntemplate<typename T1,typename T2>void ans(bool x,T1 y,T2 z){if(x)cout<<y<<endl;else cout<<z<<endl;}\ntemplate<typename T1,typename T2,typename T3>void anss(T1 x,T2 y,T3 z){ans(x!=y,x,z);};\ntemplate<typename T>void debug(const T &v,ll h,ll w,string sv=\" \"){for(ll i=0;i<h;i++){cout<<v[i][0];for(ll j=1;j<w;j++)cout<<sv<<v[i][j];cout<<endl;}};\ntemplate<typename T>void debug(const T &v,ll n,string sv=\" \"){if(n!=0)cout<<v[0];for(ll i=1;i<n;i++)cout<<sv<<v[i];cout<<endl;};\ntemplate<typename T>void debug(const vector<T>&v){debug(v,v.size());}\ntemplate<typename T>void debug(const vector<vector<T>>&v){for(auto &vv:v)debug(vv,vv.size());}\ntemplate<typename T>void debug(stack<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(queue<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(deque<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop_front();}cout<<endl;}\ntemplate<typename T>void debug(PQ<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(QP<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(const set<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T>void debug(const multiset<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,size_t size>void debug(const array<T, size> &a){for(auto z:a)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,typename V>void debug(const map<T,V>&v){for(auto z:v)cout<<\"[\"<<z.first<<\"]=\"<<z.second<<\",\";cout<<endl;}\ntemplate<typename T>vector<vector<T>>vec(ll x, ll y, T w){vector<vector<T>>v(x,vector<T>(y,w));return v;}\nll gcd(ll x,ll y){ll r;while(y!=0&&(r=x%y)!=0){x=y;y=r;}return y==0?x:y;}\n//vector<ll>dx={1,-1,0,0,1,1,-1,-1};vector<ll>dy={0,0,1,-1,1,-1,1,-1};\ntemplate<typename T>vector<T> make_v(size_t a,T b){return vector<T>(a,b);}\ntemplate<typename... Ts>auto make_v(size_t a,Ts... ts){return vector<decltype(make_v(ts...))>(a,make_v(ts...));}\ntemplate<typename T1, typename T2>ostream &operator<<(ostream &os, const pair<T1, T2>&p){return os << p.first << \" \" << p.second;}\ntemplate<typename T>ostream &operator<<(ostream &os, const vector<T> &v){for(auto &z:v)os << z << \" \";cout<<\"|\"; return os;}\ntemplate<typename T>void rearrange(vector<int>&ord, vector<T>&v){\n auto tmp = v;\n for(int i=0;i<tmp.size();i++)v[i] = tmp[ord[i]];\n}\ntemplate<typename Head, typename... Tail>void rearrange(vector<int>&ord,Head&& head, Tail&&... tail){\n rearrange(ord, head);\n rearrange(ord, tail...);\n}\ntemplate<typename T> vector<int> ascend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return v[i]<v[j];});\n return ord;\n}\ntemplate<typename T> vector<int> descend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return v[i]>v[j];});\n return ord;\n}\ntemplate<typename T> vector<T> inv_perm(const vector<T>&ord){\n vector<T>inv(ord.size());\n for(int i=0;i<ord.size();i++)inv[ord[i]] = i;\n return inv;\n}\nll FLOOR(ll n,ll div){assert(div>0);return n>=0?n/div:(n-div+1)/div;}\nll CEIL(ll n,ll div){assert(div>0);return n>=0?(n+div-1)/div:n/div;}\nll digitsum(ll n){ll ret=0;while(n){ret+=n%10;n/=10;}return ret;}\nll modulo(ll n,ll d){return (n%d+d)%d;};\ntemplate<typename T>T min(const vector<T>&v){return *min_element(v.begin(),v.end());}\ntemplate<typename T>T max(const vector<T>&v){return *max_element(v.begin(),v.end());}\ntemplate<typename T>T acc(const vector<T>&v){return accumulate(v.begin(),v.end(),T(0));};\ntemplate<typename T>T reverse(const T &v){return T(v.rbegin(),v.rend());};\n//mt19937 mt(chrono::steady_clock::now().time_since_epoch().count());\nint popcount(ll x){return __builtin_popcountll(x);};\nint poplow(ll x){return __builtin_ctzll(x);};\nint pophigh(ll x){return 63 - __builtin_clzll(x);};\ntemplate<typename T>T poll(queue<T> &q){auto ret=q.front();q.pop();return ret;};\ntemplate<typename T>T poll(priority_queue<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(QP<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(stack<T> &s){auto ret=s.top();s.pop();return ret;};\nll MULT(ll x,ll y){if(LLONG_MAX/x<=y)return LLONG_MAX;return x*y;}\nll POW2(ll x, ll k){ll ret=1,mul=x;while(k){if(mul==LLONG_MAX)return LLONG_MAX;if(k&1)ret=MULT(ret,mul);mul=MULT(mul,mul);k>>=1;}return ret;}\nll POW(ll x, ll k){ll ret=1;for(int i=0;i<k;i++){if(LLONG_MAX/x<=ret)return LLONG_MAX;ret*=x;}return ret;}\ntemplate< typename T = int >\nstruct edge {\n int to;\n T cost;\n int id;\n edge():id(-1){};\n edge(int to, T cost = 1, int id = -1):to(to), cost(cost), id(id){}\n operator int() const { return to; }\n};\n\ntemplate<typename T>\nusing Graph = vector<vector<edge<T>>>;\ntemplate<typename T>\nGraph<T>revgraph(const Graph<T> &g){\n Graph<T>ret(g.size());\n for(int i=0;i<g.size();i++){\n for(auto e:g[i]){\n int to = e.to;\n e.to = i;\n ret[to].push_back(e);\n }\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readGraph(int n,int m,int indexed=1,bool directed=false,bool weighted=false){\n Graph<T> ret(n);\n for(int es = 0; es < m; es++){\n int u,v;\n T w=1;\n cin>>u>>v;u-=indexed,v-=indexed;\n if(weighted)cin>>w;\n ret[u].emplace_back(v,w,es);\n if(!directed)ret[v].emplace_back(u,w,es);\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readParent(int n,int indexed=1,bool directed=true){\n Graph<T>ret(n);\n for(int i=1;i<n;i++){\n int p;cin>>p;\n p-=indexed;\n ret[p].emplace_back(i);\n if(!directed)ret[i].emplace_back(p);\n }\n return ret;\n}\n\ntemplate <typename F>\nclass\n#if defined(__has_cpp_attribute) && __has_cpp_attribute(nodiscard)\n [[nodiscard]]\n#endif // defined(__has_cpp_attribute) && __has_cpp_attribute(nodiscard)\nFixPoint final : private F\n{\npublic:\n template <typename G>\n explicit constexpr FixPoint(G&& g) noexcept\n : F{std::forward<G>(g)}\n {}\n\n template <typename... Args>\n constexpr decltype(auto)\n operator()(Args&&... args) const\n#if !defined(__GNUC__) || defined(__clang__) || __GNUC__ >= 9\n noexcept(noexcept(F::operator()(std::declval<FixPoint>(), std::declval<Args>()...)))\n#endif // !defined(__GNUC__) || defined(__clang__) || __GNUC__ >= 9\n {\n return F::operator()(*this, std::forward<Args>(args)...);\n }\n}; // class FixPoint\n\n\n#if defined(__cpp_deduction_guides)\ntemplate <typename F>\nFixPoint(F&&)\n-> FixPoint<std::decay_t<F>>;\n#endif // defined(__cpp_deduction_guides)\n\n\nnamespace\n{\n template <typename F>\n#if !defined(__has_cpp_attribute) || !__has_cpp_attribute(nodiscard)\n # if defined(__GNUC__) && (__GNUC__ > 3 || __GNUC__ == 3 && __GNUC_MINOR__ >= 4)\n __attribute__((warn_unused_result))\n# elif defined(_MSC_VER) && _MSC_VER >= 1700 && defined(_Check_return_)\n _Check_return_\n# endif // defined(__GNUC__) && (__GNUC__ > 3 || __GNUC__ == 3 && __GNUC_MINOR__ >= 4)\n#endif // !defined(__has_cpp_attribute) || !__has_cpp_attribute(nodiscard)\n inline constexpr decltype(auto)\n makeFixPoint(F&& f) noexcept\n {\n return FixPoint<std::decay_t<F>>{std::forward<std::decay_t<F>>(f)};\n }\n} // namespace\n\nusing Real = long double;\nusing Point = complex<Real>;\nconst Real EPS = 1e-10, PI = acos((Real)(-1.0));\n\ninline bool eq(Real a, Real b) { return fabs(b - a) < EPS; }\ninline bool eq(Point a, Point b) { return fabs(b - a) < EPS; }\n\nPoint operator*(const Point &p, const Real &d) {\n return Point(real(p) * d, imag(p) * d);\n}\n\nistream &operator>>(istream &is, Point &p) {\n Real a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n}\n\nostream &operator<<(ostream &os, Point &p) {\n return os << fixed << setprecision(10) << p.real() << \" \" << p.imag();\n}\n\nPoint rotate(Real theta, const Point &p) {\n return Point(cos(theta) * p.real() - sin(theta) * p.imag(), sin(theta) * p.real() + cos(theta) * p.imag());\n}\n\nnamespace std {\n bool operator<(const Point& a, const Point& b) {\n return !eq(a.real(), b.real()) ? a.real() < b.real() : a.imag() < b.imag();\n }\n}\n\nstruct Line {\n Point a, b;\n Line() = default;\n Line(Point a, Point b): a(a), b(b) {}\n\n friend ostream &operator<<(ostream &os, Line &p) {\n return os << p.a << \" to \" << p.b;\n }\n\n friend istream &operator>>(istream &is, Line &a) {\n return is >> a.a >> a.b;\n }\n};\n\nstruct Circle {\n Point c;\n Real r;\n Circle() = default;\n Circle(Point c, Real r): c(c), r(r) {}\n\n friend ostream &operator<<(ostream &os, Circle &c) {\n return os << c.c << \": \" << c.r;\n }\n\n friend istream &operator>>(istream &is, Circle &c) {\n return is >> c.c >> c.r;\n }\n};\n\nReal cross(const Point &a, const Point &b) {\n return real(a) * imag(b) - real(b) * imag(a);\n}\n\nReal dot(const Point &a, const Point &b) {\n return real(a) * real(b) + imag(a) * imag(b);\n}\n\nstruct Segment : Line {\n Segment() = default;\n Segment(Point a, Point b) : Line(a, b) {}\n};\n\nint ccw(const Point &a, Point b, Point c) {\n b = b - a, c = c - a;\n if (cross(b, c) > EPS) return +1; // COUNTER_CLOCKWISE\n if (cross(b, c) < -EPS) return -1; // CLOCKWISE\n if (dot(b, c) < 0) return +2; // ONLINE_BACK\n if (norm(b) < norm(c)) return -2; // ONLINE_FRONT\n return 0; // ON_SEGMENT\n}\n\nbool intersect(const Segment &s, const Point &p) {\n return ccw(s.a, s.b, p) == 0;\n}\n\nbool intersect(const Segment &s, const Segment&t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 && ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\nbool intersect(const Line &l, const Segment& s) {\n return cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < EPS;\n}\n\nint intersect(const Circle &c, const Circle &d) {\n Real dis = fabs(c.c - d.c);\n\n if (dis > c.r + d.r + EPS) return 4;\n else if (eq(dis, c.r + d.r)) return 3;\n else if (eq(dis, abs(c.r - d.r))) return 1;\n else if (dis + min(c.r, d.r) < max(c.r, d.r) - EPS) return 0;\n else return 2;\n}\n\nbool parallel(const Line &a, const Line &b) {\n return abs(cross(a.b - a.a, b.b - b.a)) < EPS;\n}\n\nbool orthogonal(const Line &a, const Line &b) {\n return abs(dot(a.b - a.a, b.b - b.a)) < EPS;\n}\n\nPoint projection(const Line& s, const Point &p) {\n double t = dot(p - s.a, s.b - s.a) / norm(s.b - s. a);\n return s.a + (s.b - s.a) * t;\n}\n\nPoint projection(const Segment& l, const Point &p) {\n return projection(Line(l), p);\n}\n\nPoint reflection(const Line &l, const Point &p) {\n Point r = projection(l, p);\n return p + (r - p) * 2;\n}\n\nReal distance(const Line &l, const Point &p) {\n Point r = projection(l, p);\n return fabs(p - r);\n}\n\nReal distance(const Segment&s, const Point &p) {\n Point r = projection(s, p);\n if (intersect(s, r)) return abs(r - p);\n return min(abs(s.a - p), abs(s.b - p));\n}\n\nReal distance(const Segment& a, const Segment& b) {\n if (intersect(a, b)) return 0;\n return min({\n distance(a, b.a),\n distance(a, b.b),\n distance(b, a.a),\n distance(b, a.b)\n });\n}\n\nbool contains(const Circle &c, const Point &p) {\n if (fabs(c.c - p) < c.r + EPS) return true;\n return false;\n}\n\nPoint crosspoint(const Line &l, const Line &m) {\n Real A = cross(l.b - l.a, m.b - m.a);\n Real B = cross(l.b - l.a, l.b - m.a);\n if (eq(abs(A), 0.0) && eq(abs(B), 0.0)) return m.a;\n return m.a + (m.b - m.a) * B / A;\n}\n\nPoint crosspoint(const Segment& l, const Segment& m) {\n return crosspoint(Line(l), Line(m));\n}\n\nLine bisector_of_angle(const Point& a, const Point& b, const Point& c) {\n Real d_ab = fabs(a - b);\n Real d_bc = fabs(b - c);\n Point c_ = b + (c - b) * d_ab / d_bc;\n\n return Line(b, (a + c_) * 0.5);\n}\n\nLine bisector(const Point& a, const Point& b) {\n Point c = (a + b) * 0.5;\n Point d = c + rotate(PI / 2, b - c);\n\n return Line(c, d);\n}\n\nint intersect(const Circle &c, const Line &l) {\n Real d = distance(l, c.c);\n\n if (d > c.r + EPS) return 0;\n if (eq(d, c.r)) return 1;\n return 2;\n}\n\npair<Point, Point> crosspoint(const Circle& c, const Line& l) {\n Real d = distance(l, c.c);\n\n Point p = projection(l, c.c);\n if (intersect(c, l) == 1) return { p, p };\n\n Real d2 = sqrt(c.r * c.r - d * d);\n Point v = (l.a - l.b) * (1.0 / fabs(l.a - l.b));\n\n return { p + d2 * v, p - d2 * v };\n}\n\nvector<Point> crosspoint(const Circle &c, const Segment &s) {\n int isect = intersect(c, Line(s));\n if (isect == 0) return {};\n\n auto [p1, p2] = crosspoint(c, Line(s));\n\n vector<Point> res;\n if (ccw(s.a, s.b, p1) == 0) res.push_back(p1);\n if (ccw(s.a, s.b, p2) == 0) res.push_back(p2);\n\n if (res.size() == 2 && ccw(s.a, p1, p2) == 0) swap(res[0], res[1]);\n return res;\n}\n\npair<Point, Point> crosspoint(const Circle &c1, const Circle &c2) {\n Real d = fabs(c1.c - c2.c);\n Real x1 = (c1.r * c1.r + d * d - c2.r * c2.r) / 2 / d;\n Real y = sqrt(c1.r * c1.r - x1 * x1);\n\n Point base = (c2.c * x1 + c1.c * (d - x1)) * (1.0 / d);\n Point v = rotate(PI / 2, c1.c - base);\n v = v / fabs(v);\n\n return { base + v * y, base - v * y };\n}\n\npair<Point, Point> tangent(const Circle &c, const Point &p) {\n Real d = fabs(c.c - p);\n Real d2 = sqrt(d * d - c.r * c.r);\n Real a = acos(d2 / d);\n\n\n Point q = c.c - p;\n q = q / fabs(q);\n\n// cout << d << \" \" << d2 << \" \" << a << \" \" << q << endl;\n return {\n p + rotate(a, q) * d2,\n p + rotate(-a, q) * d2\n };\n}\n\nvector<Segment> common_tangent(Circle c1, Circle c2) {\n int isect = intersect(c1, c2);\n Real d = fabs(c1.c - c2.c);\n Point v = (c2.c - c1.c) / d;\n\n vector<Segment> res;\n\n if (isect == 0) {\n return {};\n } else if (isect == 1) {\n auto [p1, p2] = crosspoint(c1, Line(c1.c, c2.c));\n if (eq(fabs(p2 - c2.c), c2.r)) swap(p1, p2);\n\n Point v = p1 + rotate(PI/2, c2.c - p1);\n return { Segment(p1, v) };\n } else if (isect == 2) {\n } else if (isect == 3) {\n auto [p1, p2] = crosspoint(c1, c2);\n res.emplace_back(p1, rotate(PI / 2, c1.c - p1) + p1);\n } else {\n Real a = d * c1.r / (c1.r + c2.r);\n Point p = c1.c + v * a;\n\n Real d1 = sqrt(a * a - c1.r * c1.r), d2 = sqrt(norm(p - c2.c) - c2.r * c2.r);\n Real theta = acos(d1 / a);\n\n// cout << d << endl;\n// cout << a << \" \" << d1 << \" \" << d2 << \" \" << theta << \": \" << p << endl;\n\n Point e = (c1.c - p) * (1.0 / fabs(c1.c - p));\n Point e1 = rotate(theta, e), e2 = rotate(-theta, e);\n\n res.emplace_back(p + e1 * d1, p - e1 * d2);\n res.emplace_back(p + e2 * d1, p - e2 * d2);\n }\n\n if (eq(c1.r, c2.r)) {\n Point e = rotate(PI / 2, v);\n res.push_back(Segment(c1.c + e * c1.r, c2.c + e * c1.r));\n res.push_back(Segment(c1.c - e * c1.r, c2.c - e * c1.r));\n return res;\n }\n\n if (c1.r > c2.r) swap(c1, c2);\n\n v = c1.c - c2.c;\n Point p = v * (1.0 / (c2.r - c1.r)) * c2.r + c2.c;\n\n auto [q1, q2] = tangent(c1, p);\n res.emplace_back(q1, crosspoint(c2, Line(p, q1)).first);\n res.emplace_back(q2, crosspoint(c2, Line(p, q2)).first);\n\n return res;\n}\n\nusing Polygon = vector<Point>;\n\nistream& operator>>(istream& is, Polygon &p) {\n for (int i = 0; i < p.size(); i++) is >> p[i];\n return is;\n}\n\nostream& operator<<(ostream& os, Polygon &p) {\n for (int i = 0; i < p.size(); i++) os << p[i] << endl;\n return os;\n}\n\nReal area(const Polygon& p) {\n Real res = 0;\n for (int i = 0; i < p.size(); i++) {\n res += cross(p[i], p[(i + 1) % p.size()]);\n }\n return abs(res)/2;\n}\n\nReal arcarea(const Circle &c, const Point &p1_, const Point &p2_) {\n Point p1 = p1_ - c.c, p2 = p2_ - c.c;\n Real a2 = atan2(imag(p2), real(p2));\n Point p = rotate(-a2, p1);\n Real a1 = atan2(imag(p), real(p));\n// cout << p1 << \" \" << p2 << \" --- \" << a2 << \" \" << a1 << endl;\n return - a1 / 2 * c.r * c.r;\n}\n\nint contains(Polygon g,Point p){\n int n=g.size();\n bool x=false;\n for(int i=0;i<n;i++){\n Point a=g[i]-p,b=g[(i+1)%n]-p;\n if(fabs(cross(a,b)) < EPS and dot(a,b) < EPS) return 1;\n if(a.imag()>b.imag()) swap(a,b);\n if(a.imag() < EPS and EPS < b.imag() and cross(a,b) > EPS ) {\n// cout << a << \" --- \" << b << \": \" << cross(a, b) << endl;\n x = !x;\n }\n }\n return (x?2:0);\n}\n\nPolygon convex_hull(Polygon Q) {\n sort(ALL(Q));\n\n Polygon upper({Q[0]}), lower({Q[0]});\n\n rep(i, 1, Q.size()) {\n while (upper.size() >= 2) {\n int _ccw = ccw(upper[upper.size() - 2], upper[upper.size() - 1], Q[i]);\n if (_ccw == 1) {\n upper.pop_back();\n } else {\n break;\n }\n }\n if (upper.size() <= 1) {\n upper.push_back(Q[i]);\n } else if (upper.size() > 1) {\n int _ccw = ccw(upper[upper.size() - 2], upper[upper.size() - 1], Q[i]);\n if (_ccw == -1 || _ccw == -2) {\n upper.push_back(Q[i]);\n }\n }\n }\n rep(i, 1, Q.size()) {\n while (lower.size() >= 2) {\n int _ccw = ccw(lower[lower.size() - 2], lower[lower.size() - 1], Q[i]);\n if (_ccw == -1) {\n lower.pop_back();\n } else {\n break;\n }\n }\n\n if (lower.size() <= 1) {\n lower.push_back(Q[i]);\n } else if (lower.size() > 1) {\n int _ccw = ccw(lower[lower.size() - 2], lower[lower.size() - 1], Q[i]);\n if (_ccw == 1 || _ccw == -2) {\n lower.push_back(Q[i]);\n }\n }\n }\n\n Polygon ret;\n\n rep(i, 0, lower.size()) {\n ret.push_back(lower[i]);\n// cout << lower[i] << endl;\n }\n\n// cout << \" | \" << endl;\n\n rrep(i, 0, upper.size()) {\n if (!eq(lower[0], upper[i]) && !eq(lower.back(), upper[i]))\n ret.push_back(upper[i]);\n// cout << upper[i] << endl;\n }\n\n int start = 0;\n\n// cout << ret.size() << endl;\n rep(i, 0, ret.size()) {\n if (ret[i].imag() < ret[start].imag() || (eq(ret[i].imag(), ret[start].imag()) && ret[i].real() < ret[start].real())) {\n start = i;\n }\n }\n\n// cout << ret.size() << endl;\n// rep(i, 0, ret.size()) {\n// auto p = ret[(i + start) % ret.size()];\n// cout << (int)p.real() << \" \" << (int)p.imag() << endl;\n// }\n//\n return ret;\n}\n\nReal closest_pair(vector<Point> &pts, int l, int r) {\n int m = (l + r) / 2;\n if (r - l <= 1) {\n return INF;\n } else if (r - l == 2) {\n if (imag(pts[l]) > imag(pts[l + 1])) swap(pts[l], pts[l + 1]);\n return fabs(pts[l] - pts[l + 1]);\n }\n\n Real mid = pts[m].real();\n Real d = min(closest_pair(pts, l, m), closest_pair(pts, m, r));\n\n inplace_merge(pts.begin() + l, pts.begin() + m, pts.begin() + r, [](const Point &a, const Point& b) {\n return a.imag() < b.imag();\n });\n\n vector<Point> ret;\n\n for (int i = l; i < r; i++) {\n if (fabs(pts[i].real() - mid) >= d) continue;\n\n for (int j = ret.size() - 1; j >= 0; j--) {\n if (fabs(imag(ret[j]) - imag(pts[i])) >= d) break;\n chmin(d, fabs(ret[j] - pts[i]));\n }\n\n ret.emplace_back(pts[i]);\n }\n\n return d;\n}\n\nbool contains(const Polygon &a, const Polygon &b) {\n rep(i, 0, b.size()) {\n if (!contains(a, b[i])) return false;\n }\n return true;\n}\n\n\nReal distance(const Polygon &a, const Point &p) {\n if (contains(a, p)) return 0;\n Real res = INF;\n rep(i, 0, a.size()) {\n Segment as(a[i], a[(i + 1) % a.size()]);\n chmin(res, distance(as, p));\n }\n return res;\n}\n\nReal distance(const Polygon &a, const Polygon &b) {\n// if (contains(a, b) || contains(b, a)) return 0;\n Real res = INF;\n rep(i, 0, a.size()) chmin(res, distance(b, a[i]));\n rep(i, 0, b.size()) chmin(res, distance(a, b[i]));\n return res;\n}\n\nstruct Point3d {\n Real x, y, z;\n Point3d() {}\n Point3d(Real x, Real y, Real z): x(x), y(y), z(z) {}\n};\n\nReal distance(const Point3d &a, const Point3d &b) {\n return sqrt(pow(a.x - b.x, 2) + pow(a.y - b.y, 2) + pow(a.z - b.z, 2));\n}\n\nvoid solve(int N) {\n vector<Circle> cs(N);\n rep(i, 0, N) cin >> cs[i];\n\n vector<vector<Point>> cps(N + 1);\n cps[0].push_back(cs[0].c);\n cps.back().push_back(cs.back().c);\n\n rep(i, 0, N - 1) {\n auto cr_ps = crosspoint(cs[i], cs[i + 1]);\n cps[i + 1].push_back(cr_ps.fi);\n cps[i + 1].push_back(cr_ps.se);\n }\n\n using PRI = pair<Real, int>;\n vector<vector<PRI>> G(2 * N + 2);\n int off = N + 1;\n rep(i, 0, N) {\n rep(_i, 0, cps[i].size()) {\n rep(j, i + 1, N + 1) {\n rep(_j, 0, cps[j].size()) {\n bool ok = 1;\n rep(k, i, j) {\n if (!intersect(Segment(cps[i][_i], cps[j][_j]), Segment(cps[k][0], cps[k][1]))) {\n ok = 0;\n break;\n }\n }\n\n if (ok) {\n G[i + _i * off].emplace_back(fabs(cps[i][_i] - cps[j][_j]), j + _j * off);\n }\n }\n }\n }\n }\n\n priority_queue<PRI, vector<PRI>, greater<PRI>> pq;\n vector<Real> d(G.size(), INF);\n pq.emplace(0, 0);\n d[0] = 0;\n while (pq.size()) {\n auto [dd, v] = pq.top(); pq.pop();\n if (dd > d[v]) continue;\n for (auto &[c, u] : G[v]) {\n if (c + dd < d[u]) {\n d[u] = c + dd;\n pq.emplace(d[u], u);\n }\n }\n }\n\n cout << d[N] << endl;\n}\n\nint main() {\n cin.tie();\n ios::sync_with_stdio(false);\n\n cout << fixed << setprecision(10);\n int N;\n while (cin >> N && N) {\n solve(N);\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4024, "score_of_the_acc": -0.5991, "final_rank": 13 }, { "submission_id": "aoj_1183_7184348", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n#include <algorithm>\nusing namespace std;\n\nconst double EPS = 1e-8;\n\nstruct Point {\n\tdouble px, py;\n};\n\nstruct Circle {\n\tPoint e;\n\tdouble r;\n};\n\nPoint operator-(const Point& a1, const Point& a2) {\n\treturn Point{ a1.px - a2.px, a1.py - a2.py };\n}\n\nPoint operator+(const Point& a1, const Point& a2) {\n\treturn Point{ a1.px + a2.px, a1.py + a2.py };\n}\n\ndouble ABS(Point E) {\n\treturn sqrt(E.px * E.px + E.py * E.py);\n}\n\ndouble crs(Point A1, Point A2) {\n\treturn A1.px * A2.py - A1.py * A2.px;\n}\n\npair<Point, Point> Cross_Circle(Circle A1, Circle A2) {\n\tPoint Diff = A2.e - A1.e;\n\tdouble dst = ABS(Diff);\n\tdouble angle = acos((A1.r * A1.r + dst * dst - A2.r * A2.r) / (2.0 * A1.r * dst));\n\tdouble t = atan2(Diff.py, Diff.px);\n\tPoint E1 = A1.e + Point{ A1.r * cos(angle + t), A1.r * sin(angle + t) };\n\tPoint E2 = A1.e + Point{ A1.r * cos(-angle + t), A1.r * sin(-angle + t) };\n\treturn make_pair(E1, E2);\n}\n\nint sgn(double E) {\n\tif (abs(E) <= EPS) return 0;\n\telse if (E > 0) return 1;\n\treturn -1;\n}\n\nbool Intersection(Point A1, Point A2, Point A3, Point A4) {\n\tint V1 = sgn(crs(A2 - A1, A3 - A1));\n\tint V2 = sgn(crs(A2 - A1, A4 - A1));\n\tif (V1 == -1 && V2 == -1) return false;\n\tif (V1 == 1 && V2 == 1) return false;\n\treturn true;\n}\n\nint N;\nCircle C[109];\n\nvoid solve() {\n\t// 交点の列挙\n\tPoint ZERO = Point{ 0.0, 0.0 };\n\tvector<vector<Point>> Cand(N + 1, vector<Point>(2, ZERO));\n\tCand[0][0] = C[1].e;\n\tCand[0][1] = C[1].e;\n\tCand[N][0] = C[N].e;\n\tCand[N][1] = C[N].e;\n\tfor (int i = 1; i <= N - 1; i++) {\n\t\tpair<Point, Point> ret = Cross_Circle(C[i], C[i + 1]);\n\t\tCand[i][0] = ret.first;\n\t\tCand[i][1] = ret.second;\n\t}\n\n\t// 動的計画法\n\tvector<vector<double>> dp(N + 1, vector<double>(2, 1e9));\n\tdp[0][0] = 0.0;\n\tdp[0][1] = 0.0;\n\tfor (int i = 0; i < 2 * (N + 1); i++) {\n\t\tfor (int j = i + 1; j < 2 * (N + 1); j++) {\n\t\t\tif (i == 0 && j == 6) {\n\t\t\t\ti += 0;\n\t\t\t}\n\n\t\t\tint L1 = i / 2, L2 = i % 2;\n\t\t\tint R1 = j / 2, R2 = j % 2; if (L1 == R1) continue;\n\t\t\tbool flag = true;\n\t\t\tfor (int k = L1 + 1; k <= R1 - 1; k++) {\n\t\t\t\tbool ret = Intersection(Cand[L1][L2], Cand[R1][R2], Cand[k][0], Cand[k][1]);\n\t\t\t\tif (ret == false) flag = false;\n\t\t\t}\n\n\t\t\t// 遷移\n\t\t\tif (flag == true) {\n\t\t\t\tdouble cost = ABS(Cand[R1][R2] - Cand[L1][L2]);\n\t\t\t\tdp[R1][R2] = min(dp[R1][R2], dp[L1][L2] + cost);\n\t\t\t}\n\t\t}\n\t}\n\n\t// 出力\n\tprintf(\"%.12lf\\n\", dp[N][0]);\n}\n\nint main() {\n\twhile (true) {\n\t\tcin >> N; if (N == 0) break;\n\t\tfor (int i = 1; i <= N; i++) cin >> C[i].e.px >> C[i].e.py >> C[i].r;\n\t\tsolve();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3968, "score_of_the_acc": -0.5088, "final_rank": 12 }, { "submission_id": "aoj_1183_7184080", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n#include <algorithm>\nusing namespace std;\n\nstruct Point {\n\tdouble px, py;\n};\n\nstruct Circle {\n\tPoint c;\n\tdouble r;\n};\n\nPoint operator-(const Point& a1, const Point& a2) {\n\treturn Point{ a1.px - a2.px, a1.py - a2.py };\n}\n\nPoint operator+(const Point& a1, const Point& a2) {\n\treturn Point{ a1.px + a2.px, a1.py + a2.py };\n}\n\n// 二点間の距離\ndouble Dist(Point A1, Point A2) {\n\tdouble diff_x = A1.px - A2.px;\n\tdouble diff_y = A1.py - A2.py;\n\treturn sqrt(diff_x * diff_x + diff_y * diff_y);\n}\n\n// 外積\ndouble crs(Point A1, Point A2) {\n\treturn A1.px * A2.py - A1.py * A2.px;\n}\n\n// 線分上で距離 dst 進んだ点\nPoint Walk(Point A1, Point A2, double dst) {\n\tPoint A3 = A2 - A1;\n\tdouble vx = dst * A3.px / sqrt(A3.px * A3.px + A3.py * A3.py);\n\tdouble vy = dst * A3.py / sqrt(A3.px * A3.px + A3.py * A3.py);\n\treturn Point{ A1.px + vx, A1.py + vy };\n}\n\n// 円と円の交点\npair<Point, Point> Cross_Circle(Circle A1, Circle A2) {\n\t// Step 1. 中点を求める\n\tdouble dst = Dist(A1.c, A2.c);\n\tdouble zure1 = (A1.r * A1.r - A2.r * A2.r) / (2 * dst);\n\tdouble zure2 = dst / 2.0 + zure1;\n\tPoint Mid = Walk(A1.c, A2.c, zure2);\n\n\t// Step 2. 答えを返す\n\tdouble rem = sqrt(A1.r * A1.r - zure2 * zure2);\n\tPoint Diff = A2.c - A1.c;\n\tPoint Vec = Point{ -Diff.py, Diff.px };\n\tPoint P1 = Mid + Walk(Point{ 0.0, 0.0 }, Vec, rem);\n\tPoint P2 = Mid + Walk(Point{ 0.0, 0.0 }, Vec, -rem);\n\treturn make_pair(P1, P2);\n}\n\n// 円と線分の距離\ndouble Dist_Line(Point A1, Point A2, Circle R) {\n\tPoint V1 = R.c - A1;\n\tPoint V2 = A2 - A1;\n\tdouble val = crs(V1, V2);\n\treturn val / Dist(A1, A2);\n}\n\n// 円と線分の交点\npair<Point, Point> Cross_Line(Point A1, Point A2, Circle R) {\n\t// Step 1. 中点を求める\n\tdouble dst = Dist_Line(A1, A2, R);\n\tdouble line_len = Dist(A1, A2);\n\tPoint Diff = A2 - A1;\n\tPoint Vec = { -Diff.py, Diff.px };\n\tPoint Mid;\n\tMid.px = R.c.px + Vec.px * (dst / line_len);\n\tMid.py = R.c.py + Vec.py * (dst / line_len);\n\n\t// Step 2. 答えを返す\n\tdouble rem = sqrt(R.r * R.r - dst * dst);\n\tPoint P1 = Mid + Walk(Point{ 0.0, 0.0 }, Diff, rem);\n\tPoint P2 = Mid + Walk(Point{ 0.0, 0.0 }, Diff, -rem);\n\treturn make_pair(P1, P2);\n}\n\n// A1A2 に対して A3 がどの位置にあるかを求める\ndouble Percentage(Point A1, Point A2, Point A3) {\n\tif (abs(A2.px - A1.px) > abs(A2.py - A1.py)) {\n\t\treturn (A3.px - A1.px) / (A2.px - A1.px);\n\t}\n\telse {\n\t\treturn (A3.py - A1.py) / (A2.py - A1.py);\n\t}\n}\n\nint N;\nCircle R[109];\n\nbool Hantei(Point A1, Point A2) {\n\t// 交差する部分の区間を求める\n\tvector<pair<double, double>> F;\n\tfor (int i = 1; i <= N; i++) {\n\t\tif (abs(Dist_Line(A1, A2, R[i])) >= R[i].r) continue;\n\t\tpair<Point, Point> E = Cross_Line(A1, A2, R[i]);\n\t\tdouble v1 = Percentage(A1, A2, E.first);\n\t\tdouble v2 = Percentage(A1, A2, E.second); if (v1 > v2) swap(v1, v2);\n\t\tF.push_back(make_pair(v1, v2));\n\t}\n\tsort(F.begin(), F.end());\n\n\t// 0-1 の範囲がすべて含まれているかを調べる\n\tdouble CurrentMax = 0.0;\n\tfor (int i = 0; i < F.size(); i++) {\n\t\tif (CurrentMax + (1e-9) < F[i].first) return false;\n\t\tCurrentMax = max(CurrentMax, F[i].second);\n\t\tif (CurrentMax >= 1.0 - (1e-9)) return true;\n\t}\n\treturn false;\n}\n\nvoid solve() {\n\t// あり得る点のリストを列挙する\n\tvector<Point> List;\n\tList.push_back(R[1].c);\n\tList.push_back(R[N].c);\n\tfor (int i = 1; i <= N - 1; i++) {\n\t\tpair<Point, Point> E = Cross_Circle(R[i], R[i + 1]);\n\t\tList.push_back(E.first);\n\t\tList.push_back(E.second);\n\t}\n\n\t// 配列の初期化\n\tvector<vector<double>> LEN(List.size(), vector<double>(List.size(), 1e9));\n\tfor (int i = 0; i < List.size(); i++) LEN[i][i] = 0;\n\n\t// 各線分について「通れるか」を判定する\n\tfor (int i = 0; i < List.size(); i++) {\n\t\tfor (int j = i + 1; j < List.size(); j++) {\n\t\t\tbool ret = Hantei(List[i], List[j]);\n\t\t\tif (ret == false) continue;\n\t\t\tLEN[i][j] = Dist(List[i], List[j]);\n\t\t\tLEN[j][i] = Dist(List[j], List[i]);\n\t\t}\n\t}\n\n\t// ベルマンフォード穂\n\tvector<double> dst(List.size(), 1e9);\n\tdst[0] = 0;\n\tfor (int t = 0; t < List.size(); t++) {\n\t\tfor (int i = 0; i < List.size(); i++) {\n\t\t\tfor (int j = 0; j < List.size(); j++) dst[j] = min(dst[j], dst[i] + LEN[i][j]);\n\t\t}\n\t}\n\n\t// 出力\n\tprintf(\"%.12lf\\n\", dst[1]);\n\n\t// デバッグ\n\tif (false) {\n\t\tvector<int> Path; int cx = 1;\n\t\tPath.push_back(cx);\n\t\twhile (cx != 0) {\n\t\t\tfor (int i = 0; i < List.size(); i++) {\n\t\t\t\tdouble goal1 = dst[i];\n\t\t\t\tdouble goal2 = dst[cx] - LEN[cx][i];\n\t\t\t\tif (fabs(goal1 - goal2) < 1e-6 && cx != i) { cx = i; break; }\n\t\t\t}\n\t\t\tPath.push_back(cx);\n\t\t}\n\t\treverse(Path.begin(), Path.end());\n\t\tcout << \"Path: \";\n\t\tfor (int i = 0; i < Path.size(); i++) {\n\t\t\tif (i >= 1) cout << \" -> \";\n\t\t\tcout << Path[i];\n\t\t}\n\t\tcout << endl;\n\t}\n}\n\nint main() {\n\twhile (true) {\n\t\t// 入力\n\t\tcin >> N; if (N == 0) break;\n\t\tfor (int i = 1; i <= N; i++) {\n\t\t\tcin >> R[i].c.px >> R[i].c.py >> R[i].r;\n\t\t}\n\n\t\t// 問題を解く\n\t\tsolve();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 340, "memory_kb": 3660, "score_of_the_acc": -0.3655, "final_rank": 7 }, { "submission_id": "aoj_1183_7100110", "code_snippet": "#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include<bits/stdc++.h>\n// #include<atcoder/modint>\nusing namespace std;\n// using namespace atcoder;\n\nstruct Point{\n\tlong double x;\n\tlong double y;\n};\n\nPoint operator+(const Point &l, const Point &r){\n\treturn Point{l.x + r.x, l.y + r.y};\n}\n\nlong double cross3(Point a, Point b, Point c){\n\treturn (b.x - a.x) * (c.y - a.y) - (b.y - a.y) * (c.x - a.x);\n}\n\nbool intersect(Point a1, Point a2, Point b1, Point b2){\n\tbool flg1 = cross3(a1, a2, b1) * cross3(a1, a2, b2) <= 0;\n\tbool flg2 = cross3(b1, b2, a1) * cross3(b1, b2, a2) <= 0;\n\treturn (flg1 && flg2);\n}\n\nlong double dist(Point a, Point b){\n\tlong double dx = a.x - b.x;\n\tlong double dy = a.y - b.y;\n\treturn sqrt(dx * dx + dy * dy);\n}\n\nvoid solve(){\n\tcout << fixed << setprecision(12);\n\twhile(1){\n\t\tint n;\n\t\tcin >> n;\n\t\tif(n == 0) return;\n\t\tvector<long double> X(n), Y(n), R(n);\n\t\tfor(int i = 0; i < n; i++) cin >> X[i] >> Y[i] >> R[i];\n\n\t\tvector<vector<Point>> LR(n + 1, vector<Point>(2));\n\t\tLR[0][0] = {X[0], Y[0]};\n\t\tLR[0][1] = {X[0], Y[0]};\n\n\t\tfor(int i = 1; i < n; i++){\n\t\t\tlong double d = dist(Point{X[i - 1], Y[i - 1]}, Point{X[i], Y[i]});\n\t\t\tlong double a = acos((R[i - 1] * R[i - 1] + d * d - R[i] * R[i]) / (2.0 * R[i - 1] * d));\n\t\t\tlong double t = atan2(Y[i] - Y[i - 1], X[i] - X[i - 1]);\n\t\t\tLR[i][0] = Point{X[i - 1], Y[i - 1]} + Point{cos(t + a) * R[i - 1], sin(t + a) * R[i - 1]};\n\t\t\tLR[i][1] = Point{X[i - 1], Y[i - 1]} + Point{cos(t - a) * R[i - 1], sin(t - a) * R[i - 1]};\n\t\t}\n\n\t\tLR[n][0] = {X[n - 1], Y[n - 1]};\n\t\tLR[n][1] = {X[n - 1], Y[n - 1]};\n\n\t\tvector<vector<long double>> dp(n + 1, vector<long double>(2, 1000000000.0));\n\t\tdp[0][0] = 0;\n\t\tdp[0][1] = 0;\n\t\tfor(int i = 1; i <= n; i++){\n\t\t\tfor(int bi = 0; bi < i; bi++){\n\t\t\t\tfor(int t1 = 0; t1 < 2; t1++) for(int t2 = 0; t2 < 2; t2++){\n\t\t\t\t\tbool ok = true;\n\t\t\t\t\tfor(int k = bi + 1; k < i; k++){\n\t\t\t\t\t\tif(!intersect(LR[bi][t1], LR[i][t2], LR[k][0], LR[k][1])){\n\t\t\t\t\t\t\tok = false;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif(ok){\n\t\t\t\t\t\tlong double d = dp[bi][t1] + dist(LR[bi][t1], LR[i][t2]);\n\t\t\t\t\t\tif(d < dp[i][t2]) dp[i][t2] = d;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << dp[n][0] << \"\\n\";\n\t}\n}\n\nint main(){\n\tcin.tie(0)->sync_with_stdio(0);\n\tint t;\n\tt = 1;\n\t// cin >> t;\n\twhile(t--) solve();\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3960, "score_of_the_acc": -0.4864, "final_rank": 11 } ]
aoj_1184_cpp
Generic Poker You have a deck of N × M cards. Each card in the deck has a rank. The range of ranks is 1 through M , and the deck includes N cards of each rank. We denote a card with rank m by m here. You can draw a hand of L cards at random from the deck. If the hand matches the given pattern, some bonus will be rewarded. A pattern is described as follows. hand_pattern = card_pattern 1 ' ' card_pattern 2 ' ' ... ' ' card_pattern L card_pattern = '*' | var_plus var_plus = variable | var_plus '+' variable = 'a' | 'b' | 'c' hand_pattern A hand matches the hand_pattern if each card_pattern in the hand_pattern matches with a distinct card in the hand. card_pattern If the card_pattern is an asterisk ('*'), it matches any card. Characters 'a', 'b', and 'c' denote variables and all the occurrences of the same variable match cards of the same rank. A card_pattern with a variable followed by plus ('+') characters matches a card whose rank is the sum of the rank corresponding to the variable and the number of plus characters. You can assume that, when a hand_pattern includes a card_pattern with a variable followed by some number of plus characters, it also includes card_patterns with that variable and all smaller numbers (including zero) of plus characters. For example, if 'a+++' appears in a hand_pattern, card_patterns 'a', 'a+', and 'a++' also appear in the hand_pattern. There is no restriction on which ranks different variables mean. For example, 'a' and 'b' may or may not match cards of the same rank. We show some example hand_patterns. The pattern a * b a b matches the hand: 3 3 10 10 9 with 'a's and 'b's meaning 3 and 10 (or 10 and 3), respectively. This pattern also matches the following hand. 3 3 3 3 9 In this case, both 'a's and 'b's mean 3. The pattern a a+ a++ a+++ a++++ matches the following hand. 4 5 6 7 8 In this case, 'a' should mean 4. Your mission is to write a program that computes the probability that a hand randomly drawn from the deck matches the given hand_pattern. Input The input is a sequence of datasets. Each dataset is formatted as follows. N M L card_pattern 1 card_pattern 2 ... card_pattern L The first line consists of three positive integers N , M , and L . N indicates the number of cards in each rank, M indicates the number of ranks, and L indicates the number of cards in a hand. N , M , and L are constrained as follows. 1 ≤ N ≤ 7 1 ≤ M ≤ 60 1 ≤ L ≤ 7 L ≤ N × M The second line describes a hand_pattern. The end of the input is indicated by a line containing three zeros separated by a single space. Output For each dataset, output a line containing a decimal fraction which means the probability of a hand matching the hand_pattern. The output should not contain an error greater than 10 −8 . No other characters should be contained in the output. Sample Input 1 1 1 a 3 3 4 a+ * a * 2 2 3 a a b 2 2 3 * * * 2 2 3 * b b 2 2 2 a a 2 3 3 a a+ a++ 2 6 6 a a+ a++ b b+ b++ 4 13 5 a a * * * 4 13 5 a a b b * 4 13 5 a a a * * 4 13 5 a a+ a+ ...(truncated)
[ { "submission_id": "aoj_1184_8998859", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\n} // namespace macro\n\nusing namespace macro;\n#line 2 \"cp-library/src/number/binom_table.hpp\"\n\ntemplate < class T >\nstd::vector< std::vector< T > > binom_table(int N) {\n std::vector table(N + 1, std::vector(N + 1, T(0)));\n table[0][0] = 1;\n for(int i : rep(1, N + 1)) {\n table[i][0] = 1;\n for(int j : rep(1, N + 1))\n table[i][j] = table[i - 1][j - 1] + table[i - 1][j];\n }\n return table;\n}\n#line 4 \"A.cpp\"\n\nauto comb = binom_table<i64>(500);\n\nf64 solve(int N, int M, int L) {\n vector<string> pattern = in(L);\n sort(pattern);\n\n vector<vector<int>> freqency;\n {\n map<char, vector<int>> mp;\n for(string s : pattern) {\n if(s == \"*\") {\n freqency.push_back({1});\n } else {\n int c = s.size() - 1;\n while(mp[s[0]].size() <= c) mp[s[0]].push_back(0);\n mp[s[0]][c] += 1;\n }\n }\n for(auto [key, vec] : mp) freqency.push_back(vec);\n }\n\n const int fsz = freqency.size();\n sort(freqency);\n set<vector<vector<int>>> st;\n do {\n auto dfs = [&](auto self, vector<vector<int>> now, int i) -> void {\n if(i == fsz) {\n st.insert(now);\n return;\n }\n\n now.push_back(freqency[i]);\n self(self, now, i + 1);\n now.pop_back();\n\n const int p = now.back().size();\n const int q = freqency[i].size();\n for(int j = 0; j <= p; j++) {\n vector<int> nxt(max(p, j + q), 0);\n for(int k = 0; k < p; k++) nxt[k] += now.back()[k];\n for(int k = 0; k < q; k++) nxt[j + k] += freqency[i][k];\n swap(nxt, now.back());\n self(self, now, i + 1);\n swap(nxt, now.back());\n }\n \n };\n dfs(dfs, {freqency[0]}, 1);\n } while(next_permutation(freqency.begin(), freqency.end()));\n\n i64 ans = 0;\n for(vector<vector<int>> a : st) {\n const int n = a.size();\n i64 f = 1;\n int s = n - 1;\n for(int i : rep(n)) {\n for(int c : a[i]) f *= comb[N][c];\n s += a[i].size();\n }\n if(0 <= M - s) ans += f * comb[M - s + n][n];\n }\n return ans / f64(comb[N * M][L]);\n}\n\nint main() {\n while(true) {\n int N = in(), M = in(), L = in();\n if(make_tuple(N, M, L) == make_tuple(0, 0, 0)) return 0;\n printer::precision(20);\n print(solve(N, M, L));\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5680, "score_of_the_acc": -0.401, "final_rank": 16 }, { "submission_id": "aoj_1184_8998857", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\n} // namespace macro\n\nusing namespace macro;\n#line 2 \"cp-library/src/number/binom_table.hpp\"\n\ntemplate < class T >\nstd::vector< std::vector< T > > binom_table(int N) {\n std::vector table(N + 1, std::vector(N + 1, T(0)));\n table[0][0] = 1;\n for(int i : rep(1, N + 1)) {\n table[i][0] = 1;\n for(int j : rep(1, N + 1))\n table[i][j] = table[i - 1][j - 1] + table[i - 1][j];\n }\n return table;\n}\n#line 4 \"A.cpp\"\n\nauto comb = binom_table<i64>(500);\n\nf64 solve(int N, int M, int L) {\n vector<string> pattern = in(L);\n sort(pattern);\n\n vector<vector<int>> freqency;\n {\n map<char, vector<int>> mp;\n for(string s : pattern) {\n if(s == \"*\") {\n freqency.push_back({1});\n } else {\n int c = s.size() - 1;\n while(mp[s[0]].size() <= c) mp[s[0]].push_back(0);\n mp[s[0]][c] += 1;\n }\n }\n for(auto [key, vec] : mp) freqency.push_back(vec);\n }\n\n const int fsz = freqency.size();\n sort(freqency);\n set<vector<vector<int>>> st;\n do {\n auto dfs = [&](auto self, vector<vector<int>> now, int i) -> void {\n if(i == fsz) {\n st.insert(now);\n return;\n }\n\n now.push_back(freqency[i]);\n self(self, now, i + 1);\n now.pop_back();\n\n const int p = now.back().size();\n const int q = freqency[i].size();\n for(int j = 0; j <= p; j++) {\n vector<int> nxt(max(p, j + q), 0);\n for(int k = 0; k < p; k++) nxt[k] += now.back()[k];\n for(int k = 0; k < q; k++) nxt[j + k] += freqency[i][k];\n swap(nxt, now.back());\n self(self, now, i + 1);\n swap(nxt, now.back());\n }\n \n };\n dfs(dfs, {freqency[0]}, 1);\n } while(next_permutation(freqency.begin(), freqency.end()));\n\n i64 ans = 0;\n for(vector<vector<int>> a : st) {\n const int n = a.size();\n i64 f = 1;\n int s = n - 1, t = n - 1;\n for(int i : rep(n)) {\n for(int c : a[i]) f *= comb[N][c];\n s += a[i].size();\n }\n if(0 <= M - s) ans += f * comb[M - s + t + 1][t + 1];\n }\n return ans / f64(comb[N * M][L]);\n}\n\nint main() {\n while(true) {\n int N = in(), M = in(), L = in();\n if(make_tuple(N, M, L) == make_tuple(0, 0, 0)) return 0;\n printer::precision(20);\n print(solve(N, M, L));\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5612, "score_of_the_acc": -0.3951, "final_rank": 15 }, { "submission_id": "aoj_1184_7184149", "code_snippet": "#include <bits/stdc++.h>\n\nint ri() {\n\tint n;\n\tscanf(\"%d\", &n);\n\treturn n;\n}\n\ntemplate<typename T> struct comb {\n\tstd::vector<std::vector<T> > ncr;\n\tstd::vector<T> fact;\n\tcomb (int n) : ncr(n + 1), fact(n + 1, 1) {\n\t\tfor (int i = 0; i <= n; i++) {\n\t\t\tncr[i].resize(i + 1, 1);\n\t\t\tfor (int j = 1; j < i; j++) ncr[i][j] = ncr[i - 1][j] + ncr[i - 1][j - 1];\n\t\t}\n\t\tfor (int i = 1; i <= n; i++) fact[i] = fact[i - 1] * i;\n\t}\n};\n\nbool match(std::vector<int> b, std::vector<std::vector<int> > lens) {\n\tif (!lens.size()) return true;\n\t\n\tfor (size_t i = 0; i < lens.size(); i++) {\n\t\tauto len = lens[i];\n\t\tauto new_lens = lens;\n\t\tnew_lens.erase(new_lens.begin() + i);\n\t\t\n\t\tfor (int j = 0; j + (int) len.size() <= (int) b.size(); j++) {\n\t\t\tauto new_b = b;\n\t\t\tbool ok = true;\n\t\t\tfor (int k = 0; k < (int) len.size(); k++) {\n\t\t\t\tif (new_b[j + k] < len[k]) {\n\t\t\t\t\tok = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tnew_b[j + k] -= len[k];\n\t\t\t}\n\t\t\tif (ok && match(new_b, new_lens)) return true;\n\t\t}\n\t}\n\treturn false;\n}\n\nbool solve() {\n\tint n = ri();\n\tint m = ri();\n\tint l = ri();\n\tif (!n && !m && !l) return false;\n\tstd::vector<int> cnt[3];\n\tfor (int i = 0; i < l; i++) {\n\t\tstd::string s;\n\t\tstd::cin >> s;\n\t\tif (s == \"*\") continue;\n\t\tauto &target = cnt[s[0] - 'a'];\n\t\tint cnt = (int) s.size() - 1;\n\t\tif ((int) target.size() <= cnt) target.resize(cnt + 1);\n\t\ttarget[cnt]++;\n\t}\n\t\n\tcomb<uint64_t> com(n * m);\n\t\n\tstd::vector<int> a(l - 1); // 0 : +0, 1 : +1, 2 : next component\n\tint64_t res = 0;\n\twhile (1) {\n\t\tstd::vector<std::vector<int> > unions;\n\t\tunions.push_back({ 1 });\n\t\tstd::vector<int> b = { 1 };\n\t\tfor (auto i : a) {\n\t\t\tif (i == 0) b.back()++, unions.back().back()++;\n\t\t\telse if (i == 1) b.push_back(1), unions.back().push_back(1);\n\t\t\telse b.push_back(0), b.push_back(1), unions.push_back({ 1 });\n\t\t}\n\t\tif (std::is_sorted(unions.begin(), unions.end())) {\n\t\t\tbool ok = match(b, {cnt[0], cnt[1], cnt[2]});\n\t\t\tfor (auto i : b) if (i > n) ok = false;\n\t\t\tif ((int) b.size() > m) ok = false;\n\t\t\t\n\t\t\tif (ok) {\n\t\t\t\t/*\n\t\t\t\tfor (auto i : b) std::cerr << i << \" \";\n\t\t\t\tstd::cerr << \" : \" << ok << std::endl;*/\n\t\t\t\t\n\t\t\t\tstd::map<std::vector<int>, int> cnt;\n\t\t\t\tstd::vector<int> cur;\n\t\t\t\tb.push_back(0);\n\t\t\t\tfor (auto i : b) {\n\t\t\t\t\tif (i) cur.push_back(i);\n\t\t\t\t\telse cnt[cur]++, cur.clear();\n\t\t\t\t}\n\t\t\t\tb.pop_back();\n\t\t\t\t\n\t\t\t\tint64_t cur_res = 1;\n\t\t\t\tcur_res *= com.fact[unions.size()];\n\t\t\t\tfor (auto &i : cnt) cur_res /= com.fact[i.second];\n\t\t\t\tfor (auto i : b) if (i) cur_res *= com.ncr[n][i];\n\t\t\t\tcur_res *= com.ncr[unions.size() + (m - (int) b.size())][unions.size()];\n\t\t\t\t// std::cerr << \" : ! \"<< cur_res << std::endl;\n\t\t\t\t\n\t\t\t\tres += cur_res;\n\t\t\t}\n\t\t}\n\t\t\n\t\tint head = 0;\n\t\twhile (head < l - 1 && ++a[head] == 3) a[head++] = 0;\n\t\tif (head == l - 1) break;\n\t}\n\t\n\tprintf(\"%.11f\\n\", (double) res / com.ncr[n * m][l]);\n\t\n\treturn true;\n}\nint main() {\n\twhile (solve());\n\treturn 0;\n}", "accuracy": 1, "time_ms": 610, "memory_kb": 3764, "score_of_the_acc": -0.321, "final_rank": 13 }, { "submission_id": "aoj_1184_7168191", "code_snippet": "#include <map>\n#include <set>\n#include <string>\n#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <functional>\nusing namespace std;\n\nint64_t comb(int x, int y) {\n\tif (x < y || y < 0) {\n\t\treturn 0;\n\t}\n\tint64_t res = 1;\n\tfor (int i = 1; i <= y; i++) {\n\t\tres *= x - y + i;\n\t\tres /= i;\n\t}\n\treturn res;\n}\n\nint main() {\n\twhile (true) {\n\t\tint N, M, L;\n\t\tcin >> N >> M >> L;\n\t\tif (N == 0 && M == 0 && L == 0) {\n\t\t\tbreak;\n\t\t}\n\t\tvector<vector<int> > vars;\n\t\tmap<char, vector<int> > d;\n\t\tfor (int i = 0; i < L; i++) {\n\t\t\tstring str;\n\t\t\tcin >> str;\n\t\t\tif (str == \"*\") {\n\t\t\t\tvars.push_back(vector<int>({ 1 }));\n\t\t\t}\n\t\t\telse {\n\t\t\t\td[str[0]].push_back(int(str.size()) - 1);\n\t\t\t}\n\t\t}\n\t\tfor (pair<char, vector<int> > i : d) {\n\t\t\tvector<int> v = i.second;\n\t\t\tint sz = *max_element(v.begin(), v.end()) + 1;\n\t\t\tvector<int> subvar(sz);\n\t\t\tfor (int j : v) {\n\t\t\t\tsubvar[j] += 1;\n\t\t\t}\n\t\t\tvars.push_back(subvar);\n\t\t}\n\t\tsort(vars.begin(), vars.end());\n\t\tset<vector<int> > s;\n\t\tdo {\n\t\t\tfunction<void(int, int, vector<int>)> dfs = [&](int pos, int l, vector<int> seq) {\n\t\t\t\tif (pos == int(vars.size())) {\n\t\t\t\t\ts.insert(seq);\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t\tint64_t res = 0;\n\t\t\t\tint nextl = (pos == 0 || vars[pos - 1] <= vars[pos] ? l : l + 1);\n\t\t\t\tfor (int i = nextl; i <= int(seq.size()); i++) {\n\t\t\t\t\tint limit_size = i + vars[pos].size();\n\t\t\t\t\tvector<int> nseq = seq;\n\t\t\t\t\tif (int(seq.size()) < limit_size) {\n\t\t\t\t\t\tnseq.resize(limit_size);\n\t\t\t\t\t}\n\t\t\t\t\tfor (int j = 0; j < int(vars[pos].size()); j++) {\n\t\t\t\t\t\tnseq[i + j] += vars[pos][j];\n\t\t\t\t\t}\n\t\t\t\t\tdfs(pos + 1, i, nseq);\n\t\t\t\t}\n\t\t\t\tif (pos >= 1) {\n\t\t\t\t\tvector<int> nseq_base = seq;\n\t\t\t\t\tnseq_base.push_back(0);\n\t\t\t\t\tnseq_base.insert(nseq_base.end(), vars[pos].begin(), vars[pos].end());\n\t\t\t\t\tdfs(pos + 1, seq.size() + 1, nseq_base);\n\t\t\t\t}\n\t\t\t};\n\t\t\tdfs(0, 0, vector<int>());\n\t\t} while (next_permutation(vars.begin(), vars.end()));\n\t\tint64_t answer = 0;\n\t\tfor (vector<int> v : s) {\n\t\t\tint sz = v.size();\n\t\t\tint blanks = 0;\n\t\t\tfor (int i = 0; i < sz; i++) {\n\t\t\t\tif (v[i] == 0) {\n\t\t\t\t\tblanks += 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\tint64_t subres = comb((M - (sz - blanks)) + 1, blanks + 1);\n\t\t\tfor (int i = 0; i < sz; i++) {\n\t\t\t\tsubres *= comb(N, v[i]);\n\t\t\t}\n\t\t\tanswer += subres;\n\t\t}\n\t\tint64_t combs = comb(N * M, L);\n\t\tcout.precision(18);\n\t\tcout << fixed << (long double)(answer) / (long double)(combs) << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3636, "score_of_the_acc": -0.2223, "final_rank": 8 }, { "submission_id": "aoj_1184_6039850", "code_snippet": "//#pragma GCC optimize(\"O3\")\n//#pragma GCC optimize(\"unroll-loops\")\n#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<ciso646>\n#include<random>\n#include<map>\n#include<set>\n#include<bitset>\n#include<stack>\n#include<unordered_map>\n#include<unordered_set>\n#include<utility>\n#include<cassert>\n#include<complex>\n#include<numeric>\n#include<array>\nusing namespace std;\n\n//#define int long long\ntypedef long long ll;\n\ntypedef unsigned long long ul;\ntypedef unsigned int ui;\nconst ll mod = 1000000009;\nconst ll INF = mod * mod;\ntypedef pair<int, int>P;\n\n#define rep(i,n) for(int i=0;i<n;i++)\n#define per(i,n) for(int i=n-1;i>=0;i--)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define per1(i,n) for(int i=n;i>=1;i--)\n#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)\n#define all(v) (v).begin(),(v).end()\ntypedef pair<ll, ll> LP;\ntypedef long double ld;\ntypedef pair<ld, ld> LDP;\nconst ld eps = 1e-8;\nconst ld pi = acosl(-1.0);\n\nll mod_pow(ll x, ll n, ll m = mod) {\n\tif (n < 0) {\n\t\tll res = mod_pow(x, -n, m);\n\t\treturn mod_pow(res, m - 2, m);\n\t}\n\tif (abs(x) >= m)x %= m;\n\tif (x < 0)x += m;\n\tll res = 1;\n\twhile (n) {\n\t\tif (n & 1)res = res * x % m;\n\t\tx = x * x % m; n >>= 1;\n\t}\n\treturn res;\n}\nstruct modint {\n\tll n;\n\tmodint() :n(0) { ; }\n\tmodint(ll m) :n(m) {\n\t\tif (n >= mod)n %= mod;\n\t\telse if (n < 0)n = (n % mod + mod) % mod;\n\t}\n\toperator int() { return n; }\n};\nbool operator==(modint a, modint b) { return a.n == b.n; }\nmodint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }\nmodint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }\nmodint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }\nmodint operator+(modint a, modint b) { return a += b; }\nmodint operator-(modint a, modint b) { return a -= b; }\nmodint operator*(modint a, modint b) { return a *= b; }\nmodint operator^(modint a, ll n) {\n\tif (n == 0)return modint(1);\n\tmodint res = (a * a) ^ (n / 2);\n\tif (n % 2)res = res * a;\n\treturn res;\n}\n\nll inv(ll a, ll p) {\n\treturn (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);\n}\nmodint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }\nmodint operator/=(modint& a, modint b) { a = a / b; return a; }\nconst int max_n = 1 << 10;\nmodint fact[max_n], factinv[max_n];\nvoid init_f() {\n\tfact[0] = modint(1);\n\tfor (int i = 0; i < max_n - 1; i++) {\n\t\tfact[i + 1] = fact[i] * modint(i + 1);\n\t}\n\tfactinv[max_n - 1] = modint(1) / fact[max_n - 1];\n\tfor (int i = max_n - 2; i >= 0; i--) {\n\t\tfactinv[i] = factinv[i + 1] * modint(i + 1);\n\t}\n}\nmodint comb(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[b] * factinv[a - b];\n}\nmodint combP(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[a - b];\n}\n\nvector<vector<int>> vs[8];\n\nld pas[100][100];\nvoid init() {\n\tvs[1].push_back({ 0 });\n\tfor (int c = 1; c < 7; c++) {\n\t\tfor (auto v : vs[c]) {\n\t\t\tint ma = 0;\n\t\t\tfor (int val : v)ma = max(ma, val);\n\t\t\trep(i, ma + 2) {\n\t\t\t\tvector<int> nv = v;\n\t\t\t\tnv.push_back(i);\n\t\t\t\tsort(all(nv));\n\t\t\t\tvs[c + 1].push_back(nv);\n\t\t\t}\n\t\t}\n\t\tsort(all(vs[c + 1]));\n\t\tvs[c + 1].erase(unique(all(vs[c + 1])), vs[c + 1].end());\n\t}\n\trep(i, 100)rep(j, 100) {\n\t\tif (i == 0 || j == 0)pas[i][j] = 1;\n\t\telse pas[i][j] = pas[i - 1][j] + pas[i][j - 1];\n\t}\n}\n\nint n, m, l;\nvoid solve() {\n\tvector<string> vc(l); rep(i, l)cin >> vc[i];\n\tauto isok = [&](vector<int> v) {\n\t\tvector<int> vals = v;\n\t\tsort(all(vals));\n\t\tvals.erase(unique(all(vals)), vals.end());\n\t\tmultiset<int> st; for (int val : v)st.insert(val);\n\t\trep(a, vals.size())rep(b, vals.size())rep(c, vals.size()) {\n\t\t\tarray<int, 3> ar = { vals[a],vals[b],vals[c] };\n\t\t\tmultiset<int> cop = st;\n\t\t\tbool valid = true;\n\t\t\trep(i, l) {\n\t\t\t\tif (vc[i][0] == '*')continue;\n\t\t\t\tint val = ar[vc[i][0] - 'a'];\n\t\t\t\tval += vc[i].size() - 1;\n\t\t\t\tif (cop.find(val) == cop.end())valid = false;\n\t\t\t\telse cop.erase(cop.find(val));\n\t\t\t}\n\t\t\tif (valid)return true;\n\t\t}\n\t\treturn false;\n\t};\n\tvector<vector<int>> vv;\n\tfor (int c = 1; c <= l; c++) {\n\t\tfor (auto v : vs[c])vv.push_back(v);\n\t}\n\tvector<vector<vector<int>>> vp(l + 1);\n\tvp[0].push_back({});\n\trep(i, vv.size()) {\n\t\trep(j, l+1) {\n\t\t\tint nj = j + vv[i].size();\n\t\t\tif (nj <= l) {\n\t\t\t\tfor (auto v : vp[j]) {\n\t\t\t\t\tvector<int> nv = v; nv.push_back(i);\n\t\t\t\t\tvp[nj].push_back(nv);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tld al = 1;\n\trep(i, l)al *= n * m - i;\n\trep1(i, l)al /= i;\n\tld ans = 0;\n\tfor (auto v : vp[l]) {\n\t\tvector<int> vals;\n\t\tint cur = 0;\n\t\tfor (int loc : v) {\n\t\t\trep(i, vv[loc].size()) {\n\t\t\t\tvals.push_back(cur + vv[loc][i]);\n\t\t\t}\n\t\t\tcur += vv[loc].back() + 2;\n\t\t}\n\t\t//rep(i, vals.size()) {\n\t\t//\tcout << vals[i] << \" \";\n\t\t//}cout << \"\\n\";\n\t\tif (isok(vals)) {\n\t\t\tld num = 1;\n\t\t\trep(i, vals.size()) {\n\t\t\t\tint cnt = 1;\n\t\t\t\twhile (i + 1 < vals.size() && vals[i] == vals[i + 1]) {\n\t\t\t\t\ti++; cnt++;\n\t\t\t\t}\n\t\t\t\t//n C cnt\n\t\t\t\tif (n < cnt)num = 0;\n\t\t\t\telse {\n\t\t\t\t\trep(i, cnt) {\n\t\t\t\t\t\tnum *= n-i;\n\t\t\t\t\t\tnum /= i + 1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\trep(i, v.size())num *= i + 1;\n\t\t\trep(i, v.size()) {\n\t\t\t\tint cnt = 1;\n\t\t\t\twhile (i + 1 < v.size() && v[i] == v[i + 1]) {\n\t\t\t\t\ti++; cnt++;\n\t\t\t\t}\n\t\t\t\trep(j, cnt)num /= j + 1;\n\t\t\t}\n\t\t\tint r = m - (cur - 1);\n\t\t\tif (r < 0)continue;\n\t\t\tint t = v.size();\n\t\t\tnum *= pas[r][t];\n\t\t\t\n\t\t\t//cout << num << \"\\n\";\n\t\t\tans += num;\n\t\t}\n\t}\n\tans /= al;\n\tcout << ans << \"\\n\";\n}\n\n\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\tcout << fixed << setprecision(10);\n\t//init_f();\n\tinit();\n\t//int t; cin >> t; rep(i, t)\n\twhile(cin>>n>>m>>l,n)\n\tsolve();\n\treturn 0;\n}", "accuracy": 1, "time_ms": 760, "memory_kb": 3760, "score_of_the_acc": -0.3426, "final_rank": 14 }, { "submission_id": "aoj_1184_4973131", "code_snippet": "//Let's join Kaede Takagaki Fan Club !!\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\ntypedef pair<int,P> P1;\ntypedef pair<P,P> P2;\n#define pu push\n#define pb push_back\n#define mp make_pair\n#define eps 1e-7\n#define INF 1000000000\n#define fi first\n#define sc second\n#define rep(i,x) for(int i=0;i<x;i++)\n#define repn(i,x) for(int i=1;i<=x;i++)\n#define SORT(x) sort(x.begin(),x.end())\n#define ERASE(x) x.erase(unique(x.begin(),x.end()),x.end())\n#define POSL(x,v) (lower_bound(x.begin(),x.end(),v)-x.begin())\n#define POSU(x,v) (upper_bound(x.begin(),x.end(),v)-x.begin())\n#define all(x) x.begin(),x.end()\ntemplate<class T>\nvoid dmp(T a){\n\trep(i,a.size()) cout << a[i] << \" \";\n\tcout << endl;\n}\ntemplate<class T>\nbool chmax(T&a, T b){\n\tif(a < b){\n\t\ta = b;\n\t\treturn 1;\n\t}\n\treturn 0;\n}\ntemplate<class T>\nbool chmin(T&a, T b){\n\tif(a > b){\n\t\ta = b;\n\t\treturn 1;\n\t}\n\treturn 0;\n}\ntemplate<class T>\nvoid g(T &a){\n\tcin >> a;\n}\ntemplate<class T>\nvoid o(const T &a,bool space=false){\n\tcout << a << (space?' ':'\\n');\n}\n//ios::sync_with_stdio(false);\nconst ll mod = 1000000007;//998244353\ntemplate<class T>\nvoid add(T&a,T b){\n\ta+=b;\n\tif(a >= mod) a-=mod;\n}\ntypedef long double ld;\nset<pair<vector<vector<int>>, long double>>S[8];\n\nvoid dfs(vector<int>vec, int num){\n\tif(vec.size() == num-1){\n\t\tvector<vector<int>>ret;\n\t\tvector<int>zan({1});\n\t\tfor(int i=0;i<vec.size();i++){\n\t\t\tif(vec[i] == 0) zan.back()++;\n\t\t\telse if(vec[i] == 1) zan.pb(1);\n\t\t\telse {\n\t\t\t\tret.pb(zan);\n\t\t\t\tzan = vector<int>({1});\n\t\t\t}\n\t\t}\n\t\tret.pb(zan); SORT(ret);\n\t\tlong double way = 1.0L;\n\t\trepn(i, ret.size()) way = way * (ld)i;\n\t\tvector<int>pre;\n\t\tint cnt = 1;\n\t\trep(i, ret.size()){\n\t\t\tif(pre != ret[i]){\n\t\t\t\trepn(i, cnt) way /= (ld)i;\n\t\t\t\tpre = ret[i]; cnt = 1;\n\t\t\t}\n\t\t\telse cnt++;\n\t\t}\n\t\trepn(i, cnt) way /= (ld)i;\n\t\tS[num].insert(mp(ret, way)); return;\n\t}\n\tfor(int i=-1;i<=1;i++){\n\t\tvec.pb(i);\n\t\tdfs(vec, num);\n\t\tvec.pop_back();\n\t}\n}\nint n, m, a;\nbool check(vector<vector<int>>vec, vector<vector<int>>cnt, int nxt){\n\tif(nxt == 3){\n\t\trep(i, vec.size()) rep(j, vec[i].size()) if(vec[i][j] < 0) return 0;\n\t\treturn 1;\n\t}\n\trep(i, vec.size()){\n\t\trep(j, vec[i].size()){\n\t\t\tbool bad = 0;\n\t\t\trep(k, cnt[nxt].size()){\n\t\t\t\tif(cnt[nxt][k] > 0 && j+k >= vec[i].size()) {bad = 1; break;}\n\t\t\t}\n\t\t\tif(bad) continue;\n\t\t\trep(k, cnt[nxt].size()){\n\t\t\t\tif(j+k >= vec[i].size()) break;\n\t\t\t\tvec[i][j+k] -= cnt[nxt][k];\n\t\t\t\tif(vec[i][j+k] < 0) bad = 1;\n\t\t\t}\n\t\t\tif(!bad && check(vec, cnt, nxt+1)) return true;\n\t\t\trep(k, cnt[nxt].size()){\n\t\t\t\tif(j+k >= vec[i].size()) break;\n\t\t\t\tvec[i][j+k] += cnt[nxt][k];\n\t\t\t}\n\t\t}\n\t}\n\treturn false;\n}\nld C(int a, int b){\n\tld ret = 1.0L;\n\tfor(int i=0;i<b;i++){\n\t\tret = ret * (ld)(a-i) / (ld)(i+1);\n\t}\n\treturn ret;\n}\nvoid solve(){\n\tvector<vector<int>>cnt;\n\trep(i, 3){\n\t\tcnt.pb(vector<int>(10, 0));\n\t}\n\trep(i, a){\n\t\tstring s; cin >> s;\n\t\tif(s[0] == '*') continue;\n\t\telse{\n\t\t\tcnt[s[0]-'a'][s.size()-1] ++;\n\t\t}\n\t}\n\tld ans = 0., all = 0.;\n\tfor(const auto at:S[a]){\n\t\tbool ok = check(at.fi, cnt, 0);\n\t\tld coef = (ld)(at.sc);\n\t\tint b = at.fi.size(), c = b-1, bad = 0;\n\t\trep(i, b){\n\t\t\tc += (at.fi)[i].size();\n\t\t\trep(j, (at.fi)[i].size()){\n\t\t\t\tif( (at.fi)[i][j] > n) bad = 1;\n\t\t\t\tcoef = coef * C(n, (at.fi)[i][j]);\n\t\t\t}\n\t\t}\n\t\tif(bad) continue;\n\t\tif(m-c >= 0) all += C(m-c+b, b) * coef;\n\t\tif(ok && m-c >= 0) ans += C(m-c+b, b) * coef;\n\t}\n\tprintf(\"%.10Lf\\n\", ans / all);\n}\nint main(){\n\tfor(int i=1;i<=7;i++){\n\t\tdfs(vector<int>(), i);\n\t}\n\twhile(1){\n\t\tcin >> n >> m >> a;\n\t\tif(n == 0 && m == 0 && a == 0) return 0;\n\t\tsolve();\n\t}\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3404, "score_of_the_acc": -0.2051, "final_rank": 6 }, { "submission_id": "aoj_1184_4109839", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing int64 = long long;\nconst int mod = 1e9 + 7;\n// const int mod = 998244353;\n\nconst int64 infll = (1LL << 62) - 1;\nconst int inf = (1 << 30) - 1;\n\nstruct IoSetup {\n IoSetup() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n cerr << fixed << setprecision(10);\n }\n} iosetup;\n\n\ntemplate< typename T1, typename T2 >\nostream &operator<<(ostream &os, const pair< T1, T2 > &p) {\n os << p.first << \" \" << p.second;\n return os;\n}\n\ntemplate< typename T1, typename T2 >\nistream &operator>>(istream &is, pair< T1, T2 > &p) {\n is >> p.first >> p.second;\n return is;\n}\n\ntemplate< typename T >\nostream &operator<<(ostream &os, const vector< T > &v) {\n for(int i = 0; i < (int) v.size(); i++) {\n os << v[i] << (i + 1 != v.size() ? \" \" : \"\");\n }\n return os;\n}\n\ntemplate< typename T >\nistream &operator>>(istream &is, vector< T > &v) {\n for(T &in : v) is >> in;\n return is;\n}\n\ntemplate< typename T1, typename T2 >\ninline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\n\ntemplate< typename T1, typename T2 >\ninline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\ntemplate< typename T = int64 >\nvector< T > make_v(size_t a) {\n return vector< T >(a);\n}\n\ntemplate< typename T, typename... Ts >\nauto make_v(size_t a, Ts... ts) {\n return vector< decltype(make_v< T >(ts...)) >(a, make_v< T >(ts...));\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value == 0 >::type fill_v(T &t, const V &v) {\n t = v;\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value != 0 >::type fill_v(T &t, const V &v) {\n for(auto &e : t) fill_v(e, v);\n}\n\ntemplate< typename F >\nstruct FixPoint : F {\n FixPoint(F &&f) : F(forward< F >(f)) {}\n\n template< typename... Args >\n decltype(auto) operator()(Args &&... args) const {\n return F::operator()(*this, forward< Args >(args)...);\n }\n};\n\ntemplate< typename F >\ninline decltype(auto) MFP(F &&f) {\n return FixPoint< F >{forward< F >(f)};\n}\n\ntemplate< typename T >\nvector< vector< T > > binomial_table(int N) {\n vector< vector< T > > mat(N + 1, vector< T >(N + 1));\n for(int i = 0; i <= N; i++) {\n for(int j = 0; j <= i; j++) {\n if(j == 0 || j == i) mat[i][j] = 1;\n else mat[i][j] = mat[i - 1][j - 1] + mat[i - 1][j];\n }\n }\n return mat;\n}\n\nint main() {\n int N, M, L;\n\n auto C = binomial_table< double >(150);\n\n auto dp = make_v< double >(61, 8, 8);\n auto memo = make_v< int >(61, 8, 8);\n auto rec = MFP([&](auto rec, int M, int N, int L) -> double {\n if(M == 0) return L == 0 ? 1.0 : 0.0;\n if(memo[M][N][L]) return dp[M][N][L];\n memo[M][N][L] = true;\n double ret = 0.0;\n for(int i = 0; i <= N && i <= L; i++) {\n ret += rec(M - 1, N, L - i) * C[N][i];\n }\n return dp[M][N][L] = ret;\n });\n\n while(cin >> N >> M >> L, N) {\n auto rank = make_v< int >(3, L);\n int any = 0;\n for(int i = 0; i < L; i++) {\n string s;\n cin >> s;\n if(s != \"*\") ++rank[s[0] - 'a'][(int) s.size() - 1];\n else any++;\n }\n for(int i = 0; i < 3; i++) {\n while(!rank[i].empty() && rank[i].back() == 0) {\n rank[i].pop_back();\n }\n }\n vector< int > op;\n\n auto is_match = [&]() -> bool {\n for(int i = 0; i + rank[0].size() <= op.size(); i++) {\n for(int j = 0; j + rank[1].size() <= op.size(); j++) {\n for(int k = 0; k + rank[2].size() <= op.size(); k++) {\n for(int l = 0; l < rank[0].size(); l++) {\n op[i + l] -= rank[0][l];\n }\n for(int l = 0; l < rank[1].size(); l++) {\n op[j + l] -= rank[1][l];\n }\n for(int l = 0; l < rank[2].size(); l++) {\n op[k + l] -= rank[2][l];\n }\n bool f = true;\n for(int l = 0; l < op.size(); l++) {\n f &= op[l] >= 0;\n }\n for(int l = 0; l < rank[0].size(); l++) {\n op[i + l] += rank[0][l];\n }\n for(int l = 0; l < rank[1].size(); l++) {\n op[j + l] += rank[1][l];\n }\n for(int l = 0; l < rank[2].size(); l++) {\n op[k + l] += rank[2][l];\n }\n if(f) return true;\n }\n }\n }\n return false;\n };\n double ue = 0;\n MFP([&](auto generate, int sum, int space) -> void {\n if(sum == L) {\n if(is_match()) {\n int f_sz = 0;\n while(f_sz < op.size() && op[f_sz] > 0) ++f_sz;\n int more = 0;\n for(int i = f_sz + 1; i < op.size(); i++) {\n if(op[i - 1] >= 1 && op[i] >= 1) ++more;\n }\n double mul = 0;\n for(int first = 0; first + f_sz <= M; first++) {\n int rest = M - (first + f_sz) - more;\n if(rest - space >= 0) {\n mul += C[rest - space][space];\n }\n }\n double vv = 1;\n for(int i = 0; i < op.size(); i++) {\n vv *= C[N][op[i]];\n }\n ue += vv * mul;\n }\n return;\n }\n op.emplace_back(0);\n if(op.size() >= 2 && op[op.size() - 2] > 0) {\n generate(sum, space + 1);\n }\n for(int i = 1; i <= N && sum + i <= L; i++) {\n op.back() = i;\n generate(sum + i, space);\n }\n op.pop_back();\n })(0, 0);\n cout << ue / rec(M, N, L) << endl;\n }\n}", "accuracy": 1, "time_ms": 380, "memory_kb": 3440, "score_of_the_acc": -0.2594, "final_rank": 10 }, { "submission_id": "aoj_1184_3841864", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\nstruct Info{\n\n\tchar ch;\n\tint maximum,count_table[7];\n};\n\nint table[7],work[7];\nint N,M,L;\nint check_index;\nll dp[8][61];\ndouble nCm[421][8];\nchar pattern[7][10];\nchar check_table[5040][7];\nvector<vector<Info>> SECTION;\nInfo info[7],calc_info[7],work_info[7],section[7];\n\n\n//連続した数字の塊【区間】を0~M-1に当てはめる【最大L個】\nll dfs(int section_index,int num_section,int num_index){\n\n\tif(num_index == M){\n\n\t\tif(section_index < num_section){ //当てはめをしていない区間あり\n\n\t\t\treturn 0;\n\t\t}else{\n\n\t\t\treturn 1;\n\t\t}\n\t}\n\n\tif(dp[section_index][num_index] != -1){\n\n\t\treturn dp[section_index][num_index];\n\t}\n\n\tll ret = 0;\n\n\t//割り当てない\n\tret += dfs(section_index,num_section,num_index+1);\n\n\t//割り当てる\n\tif(section_index < num_section){\n\n\t\tint tail = num_index+section[section_index].maximum;\n\t\tif(tail <= M-1){\n\n\t\t\t//★重複計上を防ぐため、区間と区間の間には少なくとも1つの空白を設ける★\n\t\t\tret += dfs(section_index+1,num_section,min(M,tail+2));\n\t\t}\n\t}\n\n\treturn dp[section_index][num_index] = ret;\n}\n\nvoid makeSection(int section_index,int num_info,int work_index){\n\n\tif(section_index == num_info){ //区間作成完了\n\n\t\t//既存区間と重複していないか調べる\n\t\tbool FLG = false;\n\n\t\tfor(int i = 0; i < SECTION.size(); i++){\n\t\t\tFLG = true;\n\t\t\tif(SECTION[i].size() != work_index){ //区間の数が異なるならOK\n\t\t\t\tFLG = false;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor(int k = 0; k < SECTION[i].size(); k++){\n\t\t\t\tif(SECTION[i][k].maximum != work_info[k].maximum){ //ある区間の長さが異なるならOK\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tfor(int p = 0; p <= SECTION[i][k].maximum; p++){\n\t\t\t\t\tif(SECTION[i][k].count_table[p] != work_info[k].count_table[p]){ //ある数字の数が異なるならOK\n\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!FLG)break;\n\t\t\t}\n\t\t\tif(FLG)break;\n\t\t}\n\n\t\tif(FLG)return;\n\n\t\tvector<Info> vec;\n\n\t\tfor(int i = 0; i < work_index; i++){\n\n\t\t\tvec.push_back(work_info[i]);\n\t\t}\n\n\t\tSECTION.emplace_back(vec);\n\n\t\treturn;\n\t}\n\n\t//既存の区間と重なりを持つ場合\n\tfor(int i = 0; i < work_index; i++){\n\t\tfor(int merge_head = 0; merge_head <= work_info[i].maximum+1; merge_head++){\n\n\t\t\tif(merge_head+calc_info[section_index].maximum >= min(L,M))continue;\n\n\t\t\t//数字の個数がNを越えないか調べる\n\t\t\tbool FLG = true;\n\t\t\tfor(int k = 0; merge_head+k <= work_info[i].maximum && k <= calc_info[section_index].maximum; k++){\n\t\t\t\tif(work_info[i].count_table[merge_head+k]+calc_info[section_index].count_table[k] > N){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif(!FLG)continue;\n\n\t\t\tint pre_max = work_info[i].maximum;\n\n\t\t\tfor(int k = 0; k <= calc_info[section_index].maximum; k++){\n\t\t\t\twork_info[i].count_table[merge_head+k] += calc_info[section_index].count_table[k];\n\t\t\t\twork_info[i].maximum = max(work_info[i].maximum,merge_head+k);\n\t\t\t}\n\n\t\t\tmakeSection(section_index+1,num_info,work_index);\n\n\t\t\t//元に戻す\n\t\t\tfor(int k = 0; k <= calc_info[section_index].maximum; k++){\n\t\t\t\twork_info[i].count_table[merge_head+k] -= calc_info[section_index].count_table[k];\n\t\t\t}\n\t\t\twork_info[i].maximum = pre_max;\n\t\t}\n\t}\n\n\n\t//新しい区間とする場合\n\twork_info[work_index] = calc_info[section_index];\n\tmakeSection(section_index+1,num_info,work_index+1);\n}\n\n\nvoid func(){\n\n\tfor(int i = 0; i < L; i++){\n\n\t\tscanf(\"%s\",pattern[i]);\n\t}\n\tprintf(\"\\n\");\n\n\tSECTION.clear();\n\n\tdouble num_all = nCm[N*M][L];\n\n\t/*patternに該当する場合の数を計上する*/\n\n\t//pattern情報を調べる\n\tint num_info = 0;\n\tfor(int i = 0; i < 7; i++){\n\t\tfor(int k = 0; k < 7; k++){\n\t\t\tinfo[i].count_table[k] = 0;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < L; i++){\n\n\t\tif(pattern[i][0] == '*'){ //独立させる\n\n\t\t\tinfo[num_info].ch = '*';\n\t\t\tinfo[num_info].maximum = 0;\n\t\t\tinfo[num_info].count_table[0] = 1;\n\n\t\t\tnum_info++;\n\n\t\t}else{\n\n\t\t\tint index = -1;\n\n\t\t\tfor(int k = 0; k < num_info; k++){\n\n\t\t\t\tif(info[k].ch == pattern[i][0]){\n\n\t\t\t\t\tindex = k;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif(index == -1){\n\n\t\t\t\tinfo[num_info].ch = pattern[i][0];\n\t\t\t\tinfo[num_info].maximum = 0;\n\t\t\t\tindex = num_info;\n\t\t\t\tnum_info++;\n\t\t\t}\n\n\t\t\tint num_plus = 0;\n\n\t\t\tfor(int k = 1; pattern[i][k] == '+'; k++,num_plus++);\n\n\t\t\tinfo[index].count_table[num_plus] += 1; //a a a++ a++ a+++ 等\n\t\t\tinfo[index].maximum = max(info[index].maximum,num_plus);\n\t\t}\n\t}\n\n\t//patternにマッチする場合を数え上げる\n\t//★★★★異なる変数の間には、表すランクについての制約はない★★★★\n\n\t//区間の集合を作成する\n\tint perm_table[7];\n\tfor(int i = 0; i < num_info; i++){\n\t\tperm_table[i] = i;\n\t}\n\n\tcheck_index = 0;\n\n\tdo{\n\n\t\tfor(int i = 0; i < num_info; i++){ //infoを固定すると計上漏れが発生する\n\n\t\t\tcalc_info[i] = info[perm_table[i]];\n\t\t}\n\n\t\tbool FLG = false;\n\n\t\t//既に処理していないか調べる\n\t\tfor(int i = 0; i < check_index; i++){\n\t\t\tFLG = true;\n\t\t\tfor(int k = 0; k < num_info; k++){\n\t\t\t\tif(check_table[i][k] != calc_info[k].ch){\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(FLG)break;\n\t\t}\n\n\t\tif(FLG)continue;\n\n\t\tfor(int i = 0; i < num_info; i++){\n\n\t\t\tcheck_table[check_index][i] = calc_info[i].ch;\n\t\t}\n\n\t\tcheck_index++;\n\n\t\tmakeSection(0,num_info,0);\n\n\t}while(next_permutation(perm_table,perm_table+num_info));\n\n\t//区間の集合を走査し、その割り当て方ごとに、場合の数を計上する\n\tdouble num_pattern = 0;\n\n\tfor(int i = 0; i < SECTION.size(); i++){\n\n\t\tint num_section = SECTION[i].size();\n\n\t\tfor(int k = 0; k < num_section; k++){\n\n\t\t\tsection[k] = SECTION[i][k];\t\t}\n\n\t\tdouble base = 1;\n\t\tfor(int k = 0; k < num_section; k++){\n\t\t\tfor(int p = 0; p <= SECTION[i][k].maximum; p++){\n\n\t\t\t\tbase *= nCm[N][SECTION[i][k].count_table[p]];\n\t\t\t}\n\t\t}\n\n\t\tfor(int a = 0; a <= num_section; a++){\n\t\t\tfor(int b = 0; b <= M; b++){\n\t\t\t\tdp[a][b] = -1;\n\t\t\t}\n\t\t}\n\n\t\tnum_pattern += base*dfs(0,num_section,0); //数字の選び方*区間の割り当て方を加算\n\t}\n\n\tprintf(\"%.10lf\\n\",num_pattern/num_all);\n}\n\nvoid makeTable(){\n\n\tnCm[0][0] = 1;\n\tfor(ll n = 1; n <= 420; n++) {\n\t\tfor (int m = 0; m <= 7; m++) {\n\t\t\tif(m > 0){\n\t\t\t\tnCm[n][m] = nCm[n-1][m]+nCm[n-1][m-1];\n\t\t\t}else{ //m == 0\n\t\t\t\tnCm[n][m] = 1;\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main(){\n\n\tmakeTable();\n\n\twhile(true){\n\n\t\tscanf(\"%d %d %d\",&N,&M,&L);\n\t\tif(N == 0 && M == 0 && L == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 480, "memory_kb": 3336, "score_of_the_acc": -0.2649, "final_rank": 11 }, { "submission_id": "aoj_1184_3841859", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\nstruct Info{\n\n\tchar ch;\n\tint maximum,count_table[7];\n};\n\nint table[7],work[7];\nint N,M,L;\nint check_index;\nll dp[8][61];\ndouble nPk[421][8],nCm[421][8];\nchar pattern[7][10];\nchar check_table[5040][7];\nvector<vector<Info>> SECTION;\nInfo info[7],calc_info[7],work_info[7],section[7];\n\n\n//連続した数字の塊【区間】を0~M-1に当てはめる【最大L個】\nll dfs(int section_index,int num_section,int num_index){\n\n\tif(num_index == M){\n\n\t\tif(section_index < num_section){ //当てはめをしていない区間あり\n\n\t\t\treturn 0;\n\t\t}else{\n\n\t\t\treturn 1;\n\t\t}\n\t}\n\n\tif(dp[section_index][num_index] != -1){\n\n\t\treturn dp[section_index][num_index];\n\t}\n\n\tll ret = 0;\n\n\t//割り当てない\n\tret += dfs(section_index,num_section,num_index+1);\n\n\t//割り当てる\n\tif(section_index < num_section){\n\n\t\tint tail = num_index+section[section_index].maximum;\n\t\tif(tail <= M-1){\n\n\t\t\t//★重複計上を防ぐため、区間と区間の間には少なくとも1つの空白を設ける★\n\t\t\tret += dfs(section_index+1,num_section,min(M,tail+2));\n\t\t}\n\t}\n\n\treturn dp[section_index][num_index] = ret;\n}\n\nvoid makeSection(int section_index,int num_info,int work_index){\n\n\tif(section_index == num_info){ //区間作成完了\n\n\t\t//既存区間と重複していないか調べる\n\t\tbool FLG = false;\n\n\t\tfor(int i = 0; i < SECTION.size(); i++){\n\t\t\tFLG = true;\n\t\t\tif(SECTION[i].size() != work_index){ //区間の数が異なるならOK\n\t\t\t\tFLG = false;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor(int k = 0; k < SECTION[i].size(); k++){\n\t\t\t\tif(SECTION[i][k].maximum != work_info[k].maximum){ //ある区間の長さが異なるならOK\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tfor(int p = 0; p <= SECTION[i][k].maximum; p++){\n\t\t\t\t\tif(SECTION[i][k].count_table[p] != work_info[k].count_table[p]){ //ある数字の数が異なるならOK\n\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!FLG)break;\n\t\t\t}\n\t\t\tif(FLG)break;\n\t\t}\n\n\t\tif(FLG)return;\n\n\t\tvector<Info> vec;\n\n\t\tfor(int i = 0; i < work_index; i++){\n\n\t\t\tvec.push_back(work_info[i]);\n\t\t}\n\n\t\tSECTION.emplace_back(vec);\n\n\t\treturn;\n\t}\n\n\t//既存の区間と重なりを持つ場合\n\tfor(int i = 0; i < work_index; i++){\n\t\tfor(int merge_head = 0; merge_head <= work_info[i].maximum+1; merge_head++){\n\n\t\t\tif(merge_head+calc_info[section_index].maximum >= min(L,M))continue;\n\n\t\t\t//数字の個数がNを越えないか調べる\n\t\t\tbool FLG = true;\n\t\t\tfor(int k = 0; merge_head+k <= work_info[i].maximum && k <= calc_info[section_index].maximum; k++){\n\t\t\t\tif(work_info[i].count_table[merge_head+k]+calc_info[section_index].count_table[k] > N){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif(!FLG)continue;\n\n\t\t\tint pre_max = work_info[i].maximum;\n\n\t\t\tfor(int k = 0; k <= calc_info[section_index].maximum; k++){\n\t\t\t\twork_info[i].count_table[merge_head+k] += calc_info[section_index].count_table[k];\n\t\t\t\twork_info[i].maximum = max(work_info[i].maximum,merge_head+k);\n\t\t\t}\n\n\t\t\tmakeSection(section_index+1,num_info,work_index);\n\n\t\t\t//元に戻す\n\t\t\tfor(int k = 0; k <= calc_info[section_index].maximum; k++){\n\t\t\t\twork_info[i].count_table[merge_head+k] -= calc_info[section_index].count_table[k];\n\t\t\t}\n\t\t\twork_info[i].maximum = pre_max;\n\t\t}\n\t}\n\n\n\t//新しい区間とする場合\n\twork_info[work_index] = calc_info[section_index];\n\tmakeSection(section_index+1,num_info,work_index+1);\n}\n\n\nvoid func(){\n\n\tfor(int i = 0; i < L; i++){\n\n\t\tscanf(\"%s\",pattern[i]);\n\t}\n\tprintf(\"\\n\");\n\n\tSECTION.clear();\n\n\tdouble num_all = nCm[N*M][L];\n\n\t/*patternに該当する場合の数を計上する*/\n\n\t//pattern情報を調べる\n\tint num_info = 0;\n\tfor(int i = 0; i < 7; i++){\n\t\tfor(int k = 0; k < 7; k++){\n\t\t\tinfo[i].count_table[k] = 0;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < L; i++){\n\n\t\tif(pattern[i][0] == '*'){ //独立させる\n\n\t\t\tinfo[num_info].ch = '*';\n\t\t\tinfo[num_info].maximum = 0;\n\t\t\tinfo[num_info].count_table[0] = 1;\n\n\t\t\tnum_info++;\n\n\t\t}else{\n\n\t\t\tint index = -1;\n\n\t\t\tfor(int k = 0; k < num_info; k++){\n\n\t\t\t\tif(info[k].ch == pattern[i][0]){\n\n\t\t\t\t\tindex = k;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif(index == -1){\n\n\t\t\t\tinfo[num_info].ch = pattern[i][0];\n\t\t\t\tinfo[num_info].maximum = 0;\n\t\t\t\tindex = num_info;\n\t\t\t\tnum_info++;\n\t\t\t}\n\n\t\t\tint num_plus = 0;\n\n\t\t\tfor(int k = 1; pattern[i][k] == '+'; k++,num_plus++);\n\n\t\t\tinfo[index].count_table[num_plus] += 1; //a a a++ a++ a+++ 等\n\t\t\tinfo[index].maximum = max(info[index].maximum,num_plus);\n\t\t}\n\t}\n\n\t//patternにマッチする場合を数え上げる\n\t//★★★★異なる変数の間には、表すランクについての制約はない★★★★\n\n\t//区間の集合を作成する\n\tint perm_table[7];\n\tfor(int i = 0; i < num_info; i++){\n\t\tperm_table[i] = i;\n\t}\n\n\tcheck_index = 0;\n\n\tdo{\n\n\t\tfor(int i = 0; i < num_info; i++){ //infoを固定すると計上漏れが発生する\n\n\t\t\tcalc_info[i] = info[perm_table[i]];\n\t\t}\n\n\t\tbool FLG = false;\n\n\t\t//既に処理していないか調べる\n\t\tfor(int i = 0; i < check_index; i++){\n\t\t\tFLG = true;\n\t\t\tfor(int k = 0; k < num_info; k++){\n\t\t\t\tif(check_table[i][k] != calc_info[k].ch){\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(FLG)break;\n\t\t}\n\n\t\tif(FLG)continue;\n\n\t\tfor(int i = 0; i < num_info; i++){\n\n\t\t\tcheck_table[check_index][i] = calc_info[i].ch;\n\t\t}\n\n\t\tcheck_index++;\n\n\t\tmakeSection(0,num_info,0);\n\n\t}while(next_permutation(perm_table,perm_table+num_info));\n\n\t//区間の集合を走査し、その割り当て方ごとに、場合の数を計上する\n\tdouble num_pattern = 0;\n\n\tfor(int i = 0; i < SECTION.size(); i++){\n\n\t\tint num_section = SECTION[i].size();\n\n\t\tfor(int k = 0; k < num_section; k++){\n\n\t\t\tsection[k] = SECTION[i][k];\t\t}\n\n\t\tdouble base = 1;\n\t\tfor(int k = 0; k < num_section; k++){\n\t\t\tfor(int p = 0; p <= SECTION[i][k].maximum; p++){\n\n\t\t\t\tbase *= nCm[N][SECTION[i][k].count_table[p]];\n\t\t\t}\n\t\t}\n\n\t\tfor(int a = 0; a <= num_section; a++){\n\t\t\tfor(int b = 0; b <= M; b++){\n\t\t\t\tdp[a][b] = -1;\n\t\t\t}\n\t\t}\n\n\t\tnum_pattern += base*dfs(0,num_section,0); //数字の選び方*区間の割り当て方を加算\n\t}\n\n\tprintf(\"%.10lf\\n\",num_pattern/num_all);\n}\n\nvoid makeTable(){\n\n\tfor(int n = 1; n <= 420; n++){\n\n\t\tnPk[n][0] = 1;\n\t\tnPk[n][1] = n;\n\n\t\tfor(int k = 2; k <= 7; k++){\n\n\t\t\tnPk[n][k] = nPk[n][k-1]*(n-(k-1));\n\t\t}\n\t}\n\n\tnCm[0][0] = 1;\n\tfor(ll n = 1; n <= 420; n++) {\n\t\tfor (int m = 0; m <= 7; m++) {\n\t\t\tif(m > 0){\n\t\t\t\tnCm[n][m] = nCm[n-1][m]+nCm[n-1][m-1];\n\t\t\t}else{ //m == 0\n\t\t\t\tnCm[n][m] = 1;\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main(){\n\n\tmakeTable();\n\n\twhile(true){\n\n\t\tscanf(\"%d %d %d\",&N,&M,&L);\n\t\tif(N == 0 && M == 0 && L == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 3432, "score_of_the_acc": -0.2674, "final_rank": 12 }, { "submission_id": "aoj_1184_3724586", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define REP(i,n) for(int i=0; i<n; i++)\n#define FOR(i,a,b) for(int i=a; i<b; i++)\n#define FORR(i,a,b) for(int i=(int)b-1; i>=a; i--)\n\n#define ALL(v) (v).begin(), (v).end()\n\nusing ll = long long;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\nusing vi = vector<int>;\nusing vl = vector<ll>;\n\n#define DEBUG(x) cerr<<#x<<\": \"<<(x)<<endl\n#define CHMIN(a,b) (a)=min((a),(b))\n#define CHMAX(a,b) (a)=max((a),(b))\n\nvoid debug_vec(vi v){\n for(int x:v){\n fprintf(stderr,\"%d,\",x);\n }fprintf(stderr,\"\\n\");\n}\n\nint n,m,l;\nchar hand[7][25];\nint typ[7];\nint pls[7];\n\nbool ctn(vi &a, vi &pat){\n REP(i,a.size())if(a[i]<pat[i])return false;\n return true;\n}\n\nll encode(const vi &v){\n ll ret = 0;\n REP(i,l){\n ret *= 256;\n ret += v[i];\n }\n return ret;\n}\nvi decode(ll x){\n vi v;\n REP(i,l){\n v.push_back(x%256);\n x/=256;\n }\n reverse(ALL(v));\n return v;\n}\n\nll fact[14];\nll comb[525][14];\n\nint main(){\n fact[0] = 1;\n FOR(i,1,14)fact[i]=i*fact[i-1];\n REP(i,525)REP(j,14){\n if(j>i)comb[i][j]=0;\n else if(i==j || j==0)comb[i][j]=1;\n else comb[i][j]=comb[i-1][j-1] + comb[i-1][j];\n }\n while(true){\n scanf(\"%d%d%d\",&n,&m,&l);\n if(n+m+l==0)break;\n REP(i,l){\n fill(hand[i],hand[i]+25,'\\0');\n scanf(\"%s\",hand[i]);\n }\n // to asterisk\n int a=0,b=0,c=0,d=0;\n REP(i,l){\n char x = hand[i][0];\n if(x=='*'){\n d++;\n typ[i]=3;\n pls[i]=0;\n }else if(x=='a'){\n a++;\n typ[i]=0;\n pls[i]=strlen(hand[i])-1;\n }else if(x=='b'){\n b++;\n typ[i]=1;\n pls[i]=strlen(hand[i])-1;\n }else if(x=='c'){\n c++;\n typ[i]=2;\n pls[i]=strlen(hand[i])-1;\n }\n }\n if(a==1){\n REP(i,l)if(typ[i]==0)typ[i]=3,pls[i]=0;\n a=0;\n }\n if(b==1){\n REP(i,l)if(typ[i]==1)typ[i]=3,pls[i]=0;\n b=0;\n }\n if(c==1){\n REP(i,l)if(typ[i]==2)typ[i]=3,pls[i]=0;\n c=0;\n }\n // sort\n if(a==0){\n // a<-c\n REP(i,l)if(typ[i]==2)typ[i]=0;\n a=c;c=0;\n }\n if(a==0){\n // a<-b\n REP(i,l)if(typ[i]==1)typ[i]=0;\n a=b;b=0;\n }\n if(b==0){\n // b<-c\n REP(i,l)if(typ[i]==2)typ[i]=1;\n b=c;c=0;\n }\n // REP(i,l)printf(\"%d %d\\n\",typ[i],pls[i]);\n // split\n if(a==0){\n // all asterisk\n puts(\"1.0000000000\");\n }else if(b==0){\n // single char\n vi pat(7,0);\n int mx = 0;\n REP(i,l)if(typ[i]==0)CHMAX(mx,pls[i]);\n REP(i,l)if(typ[i]==0){\n pat[6-mx+pls[i]]++;\n }\n // REP(i,7)printf(\"%d \",pat[i]);puts(\"\");\n map<vi,ll> dp[2][8][2];\n dp[0][0][0][vi(7,0)] = 1;\n int cur = 0;\n REP(t,m){\n int nxt = cur^1;\n REP(i,8)REP(j,2)dp[nxt][i][j].clear();\n REP(used,l+1)REP(flag,2)for(auto &P:dp[cur][used][flag]){\n REP(use,n+1){\n if(used+use>l)break;\n vi nv(7);\n REP(i,6)nv[i] = P.first[i+1];\n nv[6] = use;\n int nuse = used + use;\n int nflag = flag || ctn(nv,pat);\n dp[nxt][nuse][nflag][nv] += P.second * comb[n][use];\n }\n }\n cur = nxt;\n }\n ll ans = 0;\n for(auto &P:dp[cur][l][1]){\n ans += P.second;\n }\n // DEBUG(ans);\n printf(\"%.10f\\n\",1.0*ans/comb[n*m][l]);\n }else{\n vector<vi> pats;\n REP(c,3){\n vi pat;\n REP(i,l)if(typ[i]==c){\n while(pat.size() <= pls[i])pat.push_back(0);\n pat[pls[i]]++;\n }\n if(pat.size()>0)pats.push_back(pat);\n }\n REP(i,l)if(typ[i]==3){\n pats.push_back(vi(1,1));\n }\n sort(ALL(pats));\n set<vector<vi>> S;\n stack<vector<vi>> T;\n do{\n S.insert(pats);\n T.push(pats);\n }while(next_permutation(ALL(pats)));\n while(T.size()){\n vector<vi> V = T.top(); T.pop();\n int nn = V.size();\n REP(i,nn-1){\n vector<vi> NV;\n REP(j,nn){\n if(j==i){\n // insert combine\n NV.push_back(vi()); // dummy\n }else if(j==i+1){\n continue;\n }else{\n NV.push_back(V[j]);\n }\n }\n vi x = V[i];\n vi y = V[i+1];\n int xl = x.size();\n int yl = y.size();\n // slide y\n REP(j,xl+1){\n vi z(max(xl,j+yl),0);\n REP(k,xl)z[k]+=x[k];\n REP(k,yl)z[j+k]+=y[k];\n if(*max_element(ALL(z))>n)continue;\n vector<vi> NNV = NV;\n NNV[i] = z;\n if(!S.count(NNV)){\n S.insert(NNV);\n T.push(NNV);\n }\n }\n // slide x\n FOR(j,1,yl+1){\n vi z(max(j+xl,yl),0);\n REP(k,xl)z[j+k]+=x[k];\n REP(k,yl)z[k]+=y[k];\n if(*max_element(ALL(z))>n)continue;\n vector<vi> NNV = NV;\n NNV[i] = z;\n if(!S.count(NNV)){\n S.insert(NNV);\n T.push(NNV);\n }\n }\n }\n }\n ll total = comb[n*m][l];\n ll cnt = 0;\n for(vector<vi> pat:S){\n int nn = pat.size();\n // fprintf(stderr,\"nn=%d\\n\",nn);\n ll mul = 1;\n int len = 0;\n for(vi V:pat){\n // debug_vec(V);\n len += V.size();\n REP(i,V.size()){\n mul *= comb[n][V[i]];\n // fprintf(stderr, \"(%d,%d)\\n\", n,V[i]);\n }\n }\n // position: nn+1\n // num: m-len-(nn-1)=m-len-nn+1\n if(m-len<nn-1)continue;\n // DEBUG(mul);\n // DEBUG(m-len+1);\n // DEBUG(nn);\n // DEBUG(comb[m-len+1][nn]);\n mul *= comb[m-len+1][nn];\n // DEBUG(mul);\n cnt += mul;\n }\n // DEBUG(cnt);\n // DEBUG(total);\n // if(cnt<0)return 0;\n printf(\"%.10f\\n\",1.0*cnt/total);\n }\n // }else if(c==0){\n // // double char\n // if(d<=2){\n // // brute force\n // ll total = comb[n*m][l];\n // ll poyo = 0;\n // unordered_set<ll> S;\n // REP(x,m)REP(y,m)REP(z,m)REP(w,z+1){\n // int aa[] = {x,y,z,w};\n // vi v;\n // int po = 0;\n // REP(i,l){\n // if(typ[i]<3){\n // v.push_back(aa[typ[i]]+pls[i]);\n // }else{\n // v.push_back(aa[2+po]);\n // po++;\n // }\n // }\n // sort(ALL(v));\n // if(v.back()>=m){\n // // DEBUG(\"!?\");\n // continue;\n // }\n // int bef = -1;\n // int cnt = 0;\n // // ll pat = fact(l);\n // ll pat = 1;\n // REP(i,l){\n // if(v[i]==bef){\n // cnt++;\n // if(cnt>n)break;\n // }else{\n // // pat /= fact(cnt);\n // pat *= comb[n][cnt];\n // bef=v[i];\n // cnt=1;\n // }\n // }\n // if(cnt>n){\n // // DEBUG(\"!?\");\n // continue;\n // }\n // // pat /= fact(cnt);\n // pat *= comb[n][cnt];\n\n // ll id = encode(v);\n // if(S.count(id))continue;\n // S.insert(id);\n // poyo += pat;\n // }\n // printf(\"%.10f\\n\",1.0 * poyo / total);\n // }else{\n // // no brute-force\n // int hori=0, vert=0;\n // REP(c,2){\n // int c0=0,c1=0;\n // REP(i,l)if(typ[i]==c)(pls[i]==0?c0:c1)++;\n // if(c0==2){\n // vert++;\n // }else{\n // hori++;\n // }\n // }\n // puts(\"not implemented\");\n // }\n // }else{\n // // triple char\n // // brute force\n // ll total = comb[n*m][l];\n // ll poyo = 0;\n // unordered_set<ll> S;\n // REP(x,m)REP(y,m)REP(z,m)REP(w,m){\n // int aa[] = {x,y,z,w};\n // vi v;\n // REP(i,l){\n // v.push_back(aa[typ[i]]+pls[i]);\n // }\n // sort(ALL(v));\n // if(v.back()>=m){\n // // DEBUG(\"!?\");\n // continue;\n // }\n // int bef = -1;\n // int cnt = 0;\n // // ll pat = fact(l);\n // ll pat = 1;\n // REP(i,l){\n // if(v[i]==bef){\n // cnt++;\n // if(cnt>n)break;\n // }else{\n // // pat /= fact(cnt);\n // pat *= comb[n][cnt];\n // bef=v[i];\n // cnt=1;\n // }\n // }\n // if(cnt>n){\n // // DEBUG(\"!?\");\n // continue;\n // }\n // // pat /= fact(cnt);\n // pat *= comb[n][cnt];\n\n // ll id = encode(v);\n // if(S.count(id))continue;\n // S.insert(id);\n // poyo += pat;\n // }\n // printf(\"%.10f\\n\",1.0 * poyo / total);\n // }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 6860, "memory_kb": 5028, "score_of_the_acc": -1.343, "final_rank": 19 }, { "submission_id": "aoj_1184_3712586", "code_snippet": "//copied from http://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=1635223#1\n//my source code is http://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=3712456#1\n\n#include<stdio.h>\n#include<algorithm>\nusing namespace std;\nchar in[10][10];\nint pl[10];\nint u[10][10];\nint t3[10];\nint q[10];\nint used[10];\nint L;\nint dfs(int a){\n if(a==3){\n return 1;\n }\n if(u[a][0]==0)return dfs(a+1);\n for(int i=0;i<L;i++){\n if(used[i])continue;\n bool ok=true;\n for(int j=0;j<L;j++){\n int cnt=0;\n for(int k=0;k<L;k++){\n if(!used[k]&&q[k]==q[i]+j)cnt++;\n }\n if(cnt<u[a][j])ok=false;\n }\n if(ok){\n for(int j=0;j<L;j++){\n int cnt=0;\n for(int k=0;k<L;k++){\n if(cnt==u[a][j])break;\n if(!used[k]&&q[k]==q[i]+j){\n cnt++;\n used[k]=1;\n }\n }\n }\n if(dfs(a+1))return 1;\n for(int j=0;j<L;j++){\n int cnt=0;\n for(int k=0;k<L;k++){\n if(cnt==u[a][j])break;\n if(used[k]&&q[k]==q[i]+j){\n cnt++;\n used[k]=0;\n }\n }\n }\n }\n }\n return 0;\n}\nlong long C[10][10];\nint main(){\n int a,b,c;\n t3[0]=1;\n C[0][0]=1;\n for(int i=0;i<9;i++){\n for(int j=0;j<=i;j++){\n C[i+1][j]+=C[i][j];\n C[i+1][j+1]+=C[i][j];\n }\n }\n for(int i=1;i<10;i++)t3[i]=t3[i-1]*3;\n while(scanf(\"%d%d%d\",&a,&b,&c),a){\n L=c;\n for(int i=0;i<10;i++)for(int j=0;j<10;j++)u[i][j]=0;\n for(int i=0;i<c;i++){\n scanf(\"%s\",in[i]);\n pl[i]=0;\n for(int j=1;in[i][j];j++)pl[i]++;\n if(in[i][0]!='*')u[in[i][0]-'a'][pl[i]]++;\n }\n /* for(int i=0;i<3;i++){\n for(int j=0;j<7;j++)printf(\"%d \",u[i][j]);\n printf(\"\\n\");\n }*/\n long long ret=0;\n for(int i=0;i<t3[c-1];i++){\n q[0]=0;\n for(int j=0;j<c;j++)used[j]=0;\n for(int j=1;j<c;j++){\n q[j]=q[j-1]+i%t3[j]/t3[j-1];\n }\n if(!dfs(0))continue;\n long long tmp=1;\n int now=0;\n int div=1;\n int num=1;\n for(int j=0;j<c;j++){\n if(j&&q[j]!=q[j-1]){\n tmp*=C[a][now];\n now=1;\n num++;\n if(q[j-1]+1<q[j])div++;\n }else now++;\n }\n tmp*=C[a][now];\n int un=b-num;\n if(un<div-1)continue;\n un-=div-1;\n for(int j=0;j<div;j++){\n tmp*=(un+div-j);\n tmp/=(j+1);\n }\n // for(int j=0;j<c;j++)printf(\"%d \",q[j]);\n // printf(\": %lld\\n\",tmp);\n ret+=tmp;\n }\n long long total=1;\n for(int i=0;i<c;i++){\n total*=(a*b-i);\n total/=(i+1);\n }\n printf(\"%.12f\\n\",(double)ret/total);\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 2708, "score_of_the_acc": -0.1477, "final_rank": 4 }, { "submission_id": "aoj_1184_3712465", "code_snippet": "//copied from http://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=1635223#1\n//my source code is http://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=3712456#1\n\n#include<stdio.h>\n#include<algorithm>\nusing namespace std;\nchar in[10][10];\nint pl[10];\nint u[10][10];\nint t3[10];\nint q[10];\nint used[10];\nint L;\nint dfs(int a){\n if(a==3){\n return 1;\n }\n if(u[a][0]==0)return dfs(a+1);\n for(int i=0;i<L;i++){\n if(used[i])continue;\n bool ok=true;\n for(int j=0;j<L;j++){\n int cnt=0;\n for(int k=0;k<L;k++){\n if(!used[k]&&q[k]==q[i]+j)cnt++;\n }\n if(cnt<u[a][j])ok=false;\n }\n if(ok){\n for(int j=0;j<L;j++){\n int cnt=0;\n for(int k=0;k<L;k++){\n if(cnt==u[a][j])break;\n if(!used[k]&&q[k]==q[i]+j){\n cnt++;\n used[k]=1;\n }\n }\n }\n if(dfs(a+1))return 1;\n for(int j=0;j<L;j++){\n int cnt=0;\n for(int k=0;k<L;k++){\n if(cnt==u[a][j])break;\n if(used[k]&&q[k]==q[i]+j){\n cnt++;\n used[k]=0;\n }\n }\n }\n }\n }\n return 0;\n}\nlong long C[10][10];\nint main(){\n int a,b,c;\n t3[0]=1;\n C[0][0]=1;\n for(int i=0;i<9;i++){\n for(int j=0;j<=i;j++){\n C[i+1][j]+=C[i][j];\n C[i+1][j+1]+=C[i][j];\n }\n }\n for(int i=1;i<10;i++)t3[i]=t3[i-1]*3;\n while(scanf(\"%d%d%d\",&a,&b,&c),a){\n L=c;\n for(int i=0;i<10;i++)for(int j=0;j<10;j++)u[i][j]=0;\n for(int i=0;i<c;i++){\n scanf(\"%s\",in[i]);\n pl[i]=0;\n for(int j=1;in[i][j];j++)pl[i]++;\n if(in[i][0]!='*')u[in[i][0]-'a'][pl[i]]++;\n }\n /* for(int i=0;i<3;i++){\n for(int j=0;j<7;j++)printf(\"%d \",u[i][j]);\n printf(\"\\n\");\n }*/\n long long ret=0;\n for(int i=0;i<t3[c-1];i++){\n q[0]=0;\n for(int j=0;j<c;j++)used[j]=0;\n for(int j=1;j<c;j++){\n q[j]=q[j-1]+i%t3[j]/t3[j-1];\n }\n if(!dfs(0))continue;\n long long tmp=1;\n int now=0;\n int div=1;\n int num=1;\n for(int j=0;j<c;j++){\n if(j&&q[j]!=q[j-1]){\n tmp*=C[a][now];\n now=1;\n num++;\n if(q[j-1]+1<q[j])div++;\n }else now++;\n }\n tmp*=C[a][now];\n int un=b-num;\n if(un<div-1)continue;\n un-=div-1;\n for(int j=0;j<div;j++){\n tmp*=(un+div-j);\n tmp/=(j+1);\n }\n // for(int j=0;j<c;j++)printf(\"%d \",q[j]);\n // printf(\": %lld\\n\",tmp);\n ret+=tmp;\n }\n long long total=1;\n for(int i=0;i<c;i++){\n total*=(a*b-i);\n total/=(i+1);\n }\n printf(\"%.12f\\n\",(double)ret/total);\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 2752, "score_of_the_acc": -0.1515, "final_rank": 5 }, { "submission_id": "aoj_1184_2461614", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing LL = long long;\nusing D = double;\n\nLL N, M, L;\nvector<vector<LL>> CARD;\n\nLL partition(LL n, LL k) {\n static map<pair<LL, LL>, LL> memo;\n auto m = make_pair(n, k);\n if(memo.count(m)) return memo[m];\n if(k == 1) return 1;\n LL res = 0;\n for(LL i = 1; k - 1 <= n - i; ++i) res += partition(n - i, k - 1);\n return memo[m] = res;\n}\n\nLL combination(LL n, LL r) {\n static map<pair<LL, LL>, LL> memo;\n auto m = make_pair(n, r);\n if(memo.count(m)) return memo[m];\n return memo[m] = (r % n == 0 ? 1 : combination(n - 1, r - 1) + combination(n - 1, r));\n}\n\nbool valid(auto c, auto& hand) {\n if(c == 3) return true;\n\n if(CARD[c].empty()) return valid(c + 1, hand);\n\n for(auto i = 0; i + CARD[c].size() - 1 < hand.size(); ++i) {\n bool ok = true;\n for(auto j = 0; j < CARD[c].size(); ++j) if(hand[i + j] < CARD[c][j]) ok = false;\n if(!ok) continue;\n\n for(auto j = 0; j < CARD[c].size(); ++j) hand[i + j] -= CARD[c][j];\n ok = valid(c + 1, hand);\n for(auto j = 0; j < CARD[c].size(); ++j) hand[i + j] += CARD[c][j];\n\n// if(ok)cout<<\"OK\"<<endl;\n if(ok) return true;\n }\n return false;\n}\n\nLL count(auto& hand) {\n// return 1;\n LL res = 1;\n LL zero = 0;\n for(auto i: hand) {\n res *= combination(N, i);\n if(i == 0) ++zero;\n }\n if(zero) res *= partition(M - (hand.size() - zero), zero);\n return res;\n}\n\nLL dfs(auto& hand, LL remain, LL last) {\n LL res = 0;\n\n if(hand.size() > M) return 0;\n\n if(remain == 0) {\n// for(auto i:hand)cout<<\" \"<<i;cout<<endl;\n if(count(begin(hand), end(hand), 0ll) == 0) {\n if(hand.size() == M) if(valid(0, hand)) res += count(hand);\n } else {\n if(valid(0, hand)) res += count(hand);\n }\n }\n\n for(auto i = 0ll; i <= min(N, remain); ++i) {\n if(i == 0 && last == 0) continue;\n hand.emplace_back(i);\n res += dfs(hand, remain - i, i);\n hand.pop_back();\n }\n\n return res;\n}\n\nD solve() {\n for(auto c: CARD) if(c.size() > M) return 0;\n\n vector<LL> hand;\n D fit = dfs(hand, L, -1);\n D total = combination(N * M, L);\n// return fit;\n return fit / total;\n}\n\nint main() {\n while(cin >> N >> M >> L, N | M | L) {\n CARD = vector<vector<LL>>(3);\n\n for(auto i = 0; i < L; ++i) {\n string s;\n cin >> s;\n\n if(s.front() == '*') continue;\n\n auto& c = CARD[s.front() - 'a'];\n c.resize(max(c.size(), s.size()), 0);\n ++c[s.size() - 1];\n }\n\n cout << setprecision(10) << fixed << solve() << endl;\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3448, "score_of_the_acc": -0.2104, "final_rank": 7 }, { "submission_id": "aoj_1184_1635223", "code_snippet": "#include<stdio.h>\n#include<algorithm>\nusing namespace std;\nchar in[10][10];\nint pl[10];\nint u[10][10];\nint t3[10];\nint q[10];\nint used[10];\nint L;\nint dfs(int a){\n\tif(a==3){\n\t\treturn 1;\n\t}\n\tif(u[a][0]==0)return dfs(a+1);\n\tfor(int i=0;i<L;i++){\n\t\tif(used[i])continue;\n\t\tbool ok=true;\n\t\tfor(int j=0;j<L;j++){\n\t\t\tint cnt=0;\n\t\t\tfor(int k=0;k<L;k++){\n\t\t\t\tif(!used[k]&&q[k]==q[i]+j)cnt++;\n\t\t\t}\n\t\t\tif(cnt<u[a][j])ok=false;\n\t\t}\n\t\tif(ok){\n\t\t\tfor(int j=0;j<L;j++){\n\t\t\t\tint cnt=0;\n\t\t\t\tfor(int k=0;k<L;k++){\n\t\t\t\t\tif(cnt==u[a][j])break;\n\t\t\t\t\tif(!used[k]&&q[k]==q[i]+j){\n\t\t\t\t\t\tcnt++;\n\t\t\t\t\t\tused[k]=1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(dfs(a+1))return 1;\n\t\t\tfor(int j=0;j<L;j++){\n\t\t\t\tint cnt=0;\n\t\t\t\tfor(int k=0;k<L;k++){\n\t\t\t\t\tif(cnt==u[a][j])break;\n\t\t\t\t\tif(used[k]&&q[k]==q[i]+j){\n\t\t\t\t\t\tcnt++;\n\t\t\t\t\t\tused[k]=0;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\nlong long C[10][10];\nint main(){\n\tint a,b,c;\n\tt3[0]=1;\n\tC[0][0]=1;\n\tfor(int i=0;i<9;i++){\n\t\tfor(int j=0;j<=i;j++){\n\t\t\tC[i+1][j]+=C[i][j];\n\t\t\tC[i+1][j+1]+=C[i][j];\n\t\t}\n\t}\n\tfor(int i=1;i<10;i++)t3[i]=t3[i-1]*3;\n\twhile(scanf(\"%d%d%d\",&a,&b,&c),a){\n\t\tL=c;\n\t\tfor(int i=0;i<10;i++)for(int j=0;j<10;j++)u[i][j]=0;\n\t\tfor(int i=0;i<c;i++){\n\t\t\tscanf(\"%s\",in[i]);\n\t\t\tpl[i]=0;\n\t\t\tfor(int j=1;in[i][j];j++)pl[i]++;\n\t\t\tif(in[i][0]!='*')u[in[i][0]-'a'][pl[i]]++;\n\t\t}\n\t/*\tfor(int i=0;i<3;i++){\n\t\t\tfor(int j=0;j<7;j++)printf(\"%d \",u[i][j]);\n\t\t\tprintf(\"\\n\");\n\t\t}*/\n\t\tlong long ret=0;\n\t\tfor(int i=0;i<t3[c-1];i++){\n\t\t\tq[0]=0;\n\t\t\tfor(int j=0;j<c;j++)used[j]=0;\n\t\t\tfor(int j=1;j<c;j++){\n\t\t\t\tq[j]=q[j-1]+i%t3[j]/t3[j-1];\n\t\t\t}\n\t\t\tif(!dfs(0))continue;\n\t\t\tlong long tmp=1;\n\t\t\tint now=0;\n\t\t\tint div=1;\n\t\t\tint num=1;\n\t\t\tfor(int j=0;j<c;j++){\n\t\t\t\tif(j&&q[j]!=q[j-1]){\n\t\t\t\t\ttmp*=C[a][now];\n\t\t\t\t\tnow=1;\n\t\t\t\t\tnum++;\n\t\t\t\t\tif(q[j-1]+1<q[j])div++;\n\t\t\t\t}else now++;\n\t\t\t}\n\t\t\ttmp*=C[a][now];\n\t\t\tint un=b-num;\n\t\t\tif(un<div-1)continue;\n\t\t\tun-=div-1;\n\t\t\tfor(int j=0;j<div;j++){\n\t\t\t\ttmp*=(un+div-j);\n\t\t\t\ttmp/=(j+1);\n\t\t\t}\n\t\t//\tfor(int j=0;j<c;j++)printf(\"%d \",q[j]);\n\t\t//\tprintf(\": %lld\\n\",tmp);\n\t\t\tret+=tmp;\n\t\t}\n\t\tlong long total=1;\n\t\tfor(int i=0;i<c;i++){\n\t\t\ttotal*=(a*b-i);\n\t\t\ttotal/=(i+1);\n\t\t}\n\t\tprintf(\"%.12f\\n\",(double)ret/total);\n\t}\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 1072, "score_of_the_acc": -0.0088, "final_rank": 1 }, { "submission_id": "aoj_1184_1365825", "code_snippet": "#include <bits/stdc++.h>\n\n#ifdef LOCAL\n#include \"dump.hpp\"\n#else\n#define dump(...)\n#endif\n\nusing namespace std;\n\nconstexpr int MAX_N = 7;\nconstexpr int MAX_M = 60;\nconstexpr int MAX_L = 7;\n\nint N, M, L;\n\nmap<char, int> c;\nint kind[MAX_L];\nint num[MAX_L];\nint hand[MAX_L];\n\nlong long memo[MAX_N * MAX_M + 1][MAX_L + 1];\nlong long combination(int n, int k) {\n\tif(k == 0 || n == k) return 1;\n\tauto &res = memo[n][k];\n\tif(res) return res;\n\treturn res = combination(n - 1, k - 1) + combination(n - 1, k);\n}\n\nbool match() {\n\tvector<int> value(c.size());\n\tvector<int> card(hand, hand + L);\n\n\tdo {\n\t\tfill(begin(value), end(value), -1);\n\t\tfor(int i = 0; i < L; ++i) {\n\t\t\tif(kind[i] == -1) continue;\n\n\t\t\tif(value[kind[i]] == -1) {\n\t\t\t\tif(card[i] <= num[i]) goto fail;\n\t\t\t\tvalue[kind[i]] = card[i] - num[i];\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif(value[kind[i]] != card[i] - num[i]) goto fail;\n\t\t\t}\n\t\t}\n\t\treturn true;\n\n\tfail:;\n\t} while(next_permutation(begin(card), end(card)));\n\n\treturn false;\n}\n\nlong long calc() {\n\tif(!match()) return 0;\n\n\tlong long res = 1;\n\tmap<int, int> cnt;\n\tfor(int i = 0; i < L; ++i) {\n\t\t++cnt[hand[i]];\n\t}\n\n\tfor(const auto &e : cnt) {\n\t\tres *= combination(N, e.second);\n\t}\n\n\tint select = 1;\n\tfor(int i = 1; i < L; ++i) {\n\t\tif(hand[i - 1] + 1 < hand[i]) ++select;\n\t}\n\n\tres *= combination(M - (hand[L - 1] - select), select);\n\treturn res;\n}\n\nlong long dfs(int idx, int len) {\n\tif(idx == L) return calc();\n\n\tlong long res = 0;\n\tfor(int i = 0; i < 3; ++i) {\n\t\tif(i == 0 && len == N) continue;\n\t\tif(hand[0] + M <= hand[idx - 1] + i) break;\n\t\thand[idx] = hand[idx - 1] + i;\n\t\tres += dfs(idx + 1, (i ? 1 : len + 1));\n\t}\n\treturn res;\n}\n\nint main() {\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tcout.setf(ios::fixed);\n\t//cout.precision(10);\n\tcout.precision(9);\n\n\twhile(cin >> N >> M >> L && N) {\n\t\tc.clear();\n\n\t\tfor(int i = 0; i < L; ++i) {\n\t\t\tstring pattern;\n\t\t\tcin >> pattern;\n\n\t\t\tif(pattern == \"*\") {\n\t\t\t\tkind[i] = -1;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif(!c.count(pattern[0])) c.insert({pattern[0], c.size()});\n\t\t\t\tkind[i] = c[pattern[0]];\n\t\t\t\tnum[i] = pattern.size() - 1;\n\t\t\t}\n\t\t}\n\n\t\tdump(c);\n\t\thand[0] = 1;\n\t\tconst auto ans = (long double)dfs(1, 1) / combination(N * M, L);\n\t\tcout << ans << endl;\n\t}\n\n\treturn EXIT_SUCCESS;\n}", "accuracy": 1, "time_ms": 1420, "memory_kb": 1324, "score_of_the_acc": -0.2277, "final_rank": 9 }, { "submission_id": "aoj_1184_1365110", "code_snippet": "#define _USE_MATH_DEFINES\n#define _CRT_SECURE_NO_DEPRECATE\n\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <limits>\n#include <cfloat>\n#include <ctime>\n#include <cassert>\n#include <map>\n#include <utility>\n#include <set>\n#include <iostream>\n#include <memory>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <functional>\n#include <sstream>\n#include <complex>\n#include <stack>\n#include <queue>\n#include <numeric>\n#include <list>\n#include <iomanip>\n#include <fstream>\n#include <iterator>\n#include <bitset>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int, int> Pii;\ntypedef pair<ll, ll> Pll;\n\n#define FOR(i,n) for(int i = 0; i < (n); i++)\n#define sz(c) ((int)(c).size())\n#define ten(x) ((int)1e##x)\n#define tenll(x) ((ll)1e##x)\n\n// #pragma comment(linker,\"/STACK:36777216\")\n\ntemplate<class T> void chmax(T& l, const T r) { l = max(l, r); }\ntemplate<class T> void chmin(T& l, const T r) { l = min(l, r); }\ntemplate<class T> T gcd(T a, T b) { return b ? gcd(b, a % b) : a; }\ntemplate<class T> T extgcd(T a, T b, T& x, T& y) { for (T u = y = 1, v = x = 0; a;) { T q = b / a; swap(x -= q * u, u); swap(y -= q * v, v); swap(b -= q * a, a); } return b; }\ntemplate<class T> T mod_inv(T a, T m) { T x, y; extgcd(a, m, x, y); return (m + x % m) % m; }\nll mod_pow(ll a, ll n, ll mod) { ll ret = 1; ll p = a % mod; while (n) { if (n & 1) ret = ret * p % mod; p = p * p % mod; n >>= 1; } return ret; }\n\n#ifdef _WIN32\n# define mygc(c) (c)=getchar()\n# define mypc(c) putchar(c)\n#else\n# define mygc(c) (c)=getchar_unlocked()\n# define mypc(c) putchar_unlocked(c)\n#endif\n\nvoid reader(int& x) { int k, m = 0; x = 0; for (;;) { mygc(k); if (k == '-') { m = 1; break; }if ('0' <= k&&k <= '9') { x = k - '0'; break; } }for (;;) { mygc(k); if (k<'0' || k>'9')break; x = x * 10 + k - '0'; }if (m) x = -x; }\nvoid reader(ll& x) { int k, m = 0; x = 0; for (;;) { mygc(k); if (k == '-') { m = 1; break; }if ('0' <= k&&k <= '9') { x = k - '0'; break; } }for (;;) { mygc(k); if (k<'0' || k>'9')break; x = x * 10 + k - '0'; }if (m) x = -x; }\nint reader(char c[]) { int i, s = 0; for (;;) { mygc(i); if (i != ' '&&i != '\\n'&&i != '\\r'&&i != '\\t'&&i != EOF) break; }c[s++] = i; for (;;) { mygc(i); if (i == ' ' || i == '\\n' || i == '\\r' || i == '\\t' || i == EOF) break; c[s++] = i; }c[s] = '\\0'; return s; }\ntemplate <class T, class S> void reader(T& x, S& y) { reader(x); reader(y); }\ntemplate <class T, class S, class U> void reader(T& x, S& y, U& z) { reader(x); reader(y); reader(z); }\ntemplate <class T, class S, class U, class V> void reader(T& x, S& y, U& z, V & w) { reader(x); reader(y); reader(z); reader(w); }\n\nvoid writer(int x, char c) { int s = 0, m = 0; char f[10]; if (x<0)m = 1, x = -x; while (x)f[s++] = x % 10, x /= 10; if (!s)f[s++] = 0; if (m)mypc('-'); while (s--)mypc(f[s] + '0'); mypc(c); }\nvoid writer(ll x, char c) { int s = 0, m = 0; char f[20]; if (x<0)m = 1, x = -x; while (x)f[s++] = x % 10, x /= 10; if (!s)f[s++] = 0; if (m)mypc('-'); while (s--)mypc(f[s] + '0'); mypc(c); }\nvoid writer(const char c[]) { int i; for (i = 0; c[i] != '\\0'; i++)mypc(c[i]); }\nvoid writer(const char x[], char c) { int i; for (i = 0; x[i] != '\\0'; i++)mypc(x[i]); mypc(c); }\ntemplate<class T> void writerLn(T x) { writer(x, '\\n'); }\ntemplate<class T, class S> void writerLn(T x, S y) { writer(x, ' '); writer(y, '\\n'); }\ntemplate<class T, class S, class U> void writerLn(T x, S y, U z) { writer(x, ' '); writer(y, ' '); writer(z, '\\n'); }\ntemplate<class T> void writerArr(T x[], int n) { if (!n) { mypc('\\n'); return; }FOR(i, n - 1)writer(x[i], ' '); writer(x[n - 1], '\\n'); }\ntemplate<class T> void writerArr(vector<T>& v) { if (sz(v)) writerArr(&v[0], sz(v)); else writer(\"\\n\"); }\n\nconst int NCK = 500;\ndouble nck[NCK + 1][NCK + 1];\nvoid calc_nck(){\n\tFOR(i, NCK){\n\t\tnck[i][0] = nck[i][i] = 1;\n\t\tfor (int j = 1; j <= i; j++) {\n\t\t\tnck[i + 1][j] = (nck[i][j - 1] + nck[i][j]);\n\t\t}\n\t}\n}\n\nint n, m, l;\nint pattern[3][7];\nint ast;\ndouble ans;\n\nvoid check(const vector<vector<int>>& v){\n\n\tint x[60] = {};\n\tint mx = 0;\n\tFOR(i, sz(v)){\n\t\tFOR(j, sz(v[i])){\n\t\t\tx[mx++] = v[i][j];\n\t\t}\n\t\tmx++;\n\t}\n\tFOR(a, mx) FOR(b, mx) FOR(c, mx){\n\t\tint y[60] = {};\n\t\tFOR(i, 7){\n\t\t\ty[a + i] += pattern[0][i];\n\t\t\ty[b + i] += pattern[1][i];\n\t\t\ty[c + i] += pattern[2][i];\n\t\t}\n\t\tbool ok = true;\n\t\tFOR(i, 50) {\n\t\t\tif (x[i] < y[i]) {\n\t\t\t\tok = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (ok) {\n\t\t\tdouble add = 1;\n\t\t\tint z = sz(v) - 1;\n\t\t\tfor (auto& v1 : v){\n\t\t\t\tz += sz(v1) - 1;\n\t\t\t\tfor (auto i : v1) {\n\t\t\t\t\tadd *= nck[n][i];\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (m - z <= 0) return;\n\t\t\tadd *= nck[m - z][sz(v)];\n\t\t\tans += add;\n\t\t\t//if (add > 0) {\n\t\t\t//\tfor (auto& v1 : v) {\n\t\t\t//\t\tprintf(\"{\");\n\t\t\t//\t\tfor (auto i : v1) {\n\t\t\t//\t\t\tprintf(\"%d \", i);\n\t\t\t//\t\t}\n\t\t\t//\t\tprintf(\"} \");\n\t\t\t//\t}\n\t\t\t//\tprintf(\"%f\\n\", add);\n\t\t\t//}\n\t\t\treturn;\n\t\t}\n\t}\n}\n\nvoid dfs(vector<vector<int>>& v,int rem){\n\tif (rem == 0) {\n\t\tcheck(v);\n\t\treturn;\n\t}\n\tif (sz(v.back()) != 0) {\n\t\tv.emplace_back();\n\t\tdfs(v, rem);\n\t\tv.pop_back();\n\t}\n\tFOR(i, rem){\n\t\tif (i + 1 > n) break;\n\t\tv.back().push_back(i + 1);\n\t\tdfs(v, rem - i - 1);\n\t\tv.back().pop_back();\n\t}\n}\n\n\nvoid solve(){\n\tvector<vector<int>> v(1);\n\tdfs(v, l);\n\tans /= nck[n*m][l];\n}\n\nint main(){\n\tcalc_nck();\n\twhile (cin >> n >> m >> l, n) {\n\t\tans = 0;\n\t\tast = 0;\n\t\tmemset(pattern, 0, sizeof(pattern));\n\t\tFOR(i, l){\n\t\t\tstring s; cin >> s;\n\t\t\tif (s[0] != '*') pattern[s[0] - 'a'][sz(s) - 1]++;\n\t\t\telse ast++;\n\t\t}\n\t\tsolve();\n\t\tprintf(\"%.10lf\\n\", ans);\n\t}\n}", "accuracy": 1, "time_ms": 1940, "memory_kb": 3208, "score_of_the_acc": -0.467, "final_rank": 17 }, { "submission_id": "aoj_1184_1199176", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#include <set>\n#include <map>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <algorithm>\n#include <cstring>\n#include <functional>\n#include <cmath>\n#include <complex>\nusing namespace std;\n#define rep(i,n) for(int i=0;i<(n);++i)\n#define rep1(i,n) for(int i=1;i<=(n);++i)\n#define all(c) (c).begin(),(c).end()\n#define fs first\n#define sc second\n#define pb push_back\n#define show(x) cout << #x << \" \" << x << endl\ntypedef long long ll;\nint N,M,L,w;\nvector<int> cs[3];\nint p3[8];\nll C[421][421];\nbool acc(int id,int* mycnt){\n\tif(id>60) return false;\n\tmycnt[id]++;\n\treturn true;\n}\nint main(){\n\tp3[0]=1;\n\trep(i,7) p3[i+1]=p3[i]*3;\n\trep(i,421){\n\t\tC[i][0]=C[i][i]=1;\n\t\tfor(int j=1;j<min(i,8);j++) C[i][j]=C[i-1][j-1]+C[i-1][j];\n\t}\n\twhile(true){\n\t\tcin>>N>>M>>L;\n\t\tif(N==0) break;\n\t\trep(i,3) cs[i].clear();\n\t\tw=0;\n\t\trep(i,L){\n\t\t\tstring s;\n\t\t\tcin>>s;\n\t\t\tif(s[0]=='*') w++;\n\t\t\telse cs[s[0]-'a'].pb(s.size()-1);\n\t\t}\n\t\tif(cs[0].empty()&&!cs[1].empty()) swap(cs[0],cs[1]);\n\t\tif(cs[1].empty()&&!cs[2].empty()) swap(cs[1],cs[2]);\n\t\tif(cs[0].empty()&&!cs[2].empty()) swap(cs[0],cs[2]);\n\t\tint n=3;\n\t\tif(cs[2].empty()) n=2;\n\t\tif(cs[1].empty()) n=1;\n\t\tif(cs[0].empty()) n=3;\n\t\tll ans=0;\n\t\trep(i,p3[L-1]){\n\t\t\tint a[8]={},e[8]={},tmp=i,cnt[61]={};\n\t\t\tint gap=0,eq=0;\n\t\t\trep(j,L-1){\n\t\t\t\ta[j]=tmp%3;\n\t\t\t\ttmp/=3;\n\t\t\t\tif(a[j]==2) gap++;\n\t\t\t\tif(a[j]==0) eq++;\n\t\t\t}\n//\t\t\tif(gap>=n) continue;\n\t\t\trep(j,L-1){\n\t\t\t\tif(a[j]==2){\n\t\t\t\t\te[j+1]=(e[j]/10+1)*10;\n\t\t\t\t}else{\n\t\t\t\t\te[j+1]=e[j]+a[j];\n\t\t\t\t}\n\t\t\t}\n\t\t\trep(j,L) cnt[e[j]]++;\n\t\t\tbool can=0;\n\t\t\trep(j,61) if(cnt[j]>N) goto hoge;\n\t\t\trep(j,L) rep(k,L) rep(h,L){\n\t\t\t\tint mycnt[61]={};\n\t\t\t\tbool ok=1;\n\t\t\t\trep(jj,cs[0].size()) if(!acc(e[j]+cs[0][jj],mycnt)) ok=0;\n\t\t\t\trep(kk,cs[1].size()) if(!acc(e[k]+cs[1][kk],mycnt)) ok=0;\n\t\t\t\trep(hh,cs[2].size()) if(!acc(e[h]+cs[2][hh],mycnt)) ok=0;\n\t\t\t\tll co=1;\n\t\t\t\trep(p,61){\n\t\t\t\t\tif(cnt[p]<mycnt[p]) ok=0;\n\t\t\t\t}\n\t\t\t\tif(ok){\n\t\t\t\t\tcan=1;\n\t\t\t\t\tgoto hoge;\n\t\t\t\t}\n\t\t\t}\n\t\t\thoge:\n\t\t\tif(can){\n\t\t\t\tll co=1;\n\t\t\t\trep(p,61) co*=C[N][cnt[p]];\n//\t\t\t\tprintf(\"%d,%d,%d -> co=%lld\\n\",a[2],a[1],a[0],co);\n//\t\t\t\tshow(M-(L-1-eq));\n//\t\t\t\tshow(gap+1);\n\t\t\t\tif(M-(L-1-eq)<0||M-(L-1-eq)<gap+1) continue;\n//\t\t\t\tprintf(\"%d,%d,%d -> narabe=%lld\\n\",a[0],a[1],a[2],C[M-(L-1-eq)][gap+1]);\n\t\t\t\tco*=C[M-(L-1-eq)][gap+1];\n\t\t\t\tans+=co;\n//\t\t\t\tprintf(\"%d, %lld\\n\",i,co);\n\t\t\t}else{\n//\t\t\t\tprintf(\"%d,no\\n\",i);\n\t\t\t}\n\t\t}\n//\t\tprintf(\"ans=%lld\\nC[][]=%lld\\n\",ans,C[N*M][L]);\n\t\tprintf(\"%.12f\\n\",(double)ans/C[N*M][L]);\n\t}\n}", "accuracy": 1, "time_ms": 2520, "memory_kb": 2648, "score_of_the_acc": -0.5031, "final_rank": 18 }, { "submission_id": "aoj_1184_1176624", "code_snippet": "#include<cstdio>\n#include<vector>\n#include<string>\n#include<iomanip>\n#include<iostream>\n#include<algorithm>\n\nusing namespace std;\n\nvector<int> a[3];\n\nvoid parse(string str){\n\tif(str[0]=='*'){\n//\t\tstar++;\n\t}else{\n\t\tint cnt=str.size()-1;\n\t\tint id=str[0]-'a';\n\t\ta[id].push_back(cnt);\n\t}\n}\n\nint dif[7];\nint val[7];\nint L;\n\nbool used[7];\n\nint N,M;\n\nbool dfs(int id){\n\tif(id==3){\n\t\treturn true;\n\t}\n\tfor(int i=0;i<L;i++){\n\t\tvector<int> tmp;\n\t\tint k=0;\n\t\tint x=val[i];\n\t\tfor(int j=i;j<L;j++){\n\t\t\tif(k==a[id].size()) break;\n\t\t\tif(used[j]) continue;\n\t\t\tif(val[j]==x+a[id][k]){\n\t\t\t\ttmp.push_back(j);\n\t\t\t\tk++;\n\t\t\t}\n\t\t}\n\t\tif(k!=a[id].size()){\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int j=0;j<tmp.size();j++){\n\t\t\tused[tmp[j]]=true;\n\t\t}\n\t\tbool flg=dfs(id+1);\n\t\tif(flg) return true;\n\t\tfor(int j=0;j<tmp.size();j++){\n\t\t\tused[tmp[j]]=false;\n\t\t}\n\t}\n\treturn false;\n}\n\nbool check(){\n\tfor(int i=0;i+N<L;i++){\n\t\tif(val[i]==val[i+N]) return false;\n\t}\n\tif(val[L-1]-val[0]>M-1) return false;\n\tfor(int i=0;i<L;i++) used[i]=false;\n//\tprintf(\"dfs\\n\");\n\tbool flg=dfs(0);\n\treturn flg;\n}\n\ndouble C(int n,int r){\n\tif(r<0||r>n) return 0;\n\tdouble res=1;\n\tfor(int i=1;i<=r;i++){\n\t\tres*=(n-i+1);\n\t\tres/=i;\n\t}\n\treturn res;\n}\n\ndouble res;\n\nvoid calc(){\n//\tprintf(\"calc \");\n\tval[0]=0;\n\tfor(int i=1;i<L;i++){\n\t\tval[i]=val[i-1]+dif[i-1];\n\t}\n//\tfor(int i=0;i<L;i++) printf(\"%d \",val[i]);\n//\tprintf(\"\\n\");\n\tbool flg=check();\n\tif(flg==false) return;\n\tdouble all=C(N*M,L);\n\tdouble cur=0;\n\tint cnt=0;\n\tfor(int i=0;i<L-1;i++) if(dif[i]==2) cnt++;\n\tint sum=0;\n\tfor(int i=0;i<L-1;i++) if(dif[i]!=2) sum+=dif[i];\n//\tprintf(\"%d %d\\n\",cnt,sum);\n\tif(cnt==0){\n\t\tcur=M-sum;\n\t}else{\n\t\tfor(int i=cnt*2;i<=M-1-sum;i++){\n\t\t\tdouble ad=C(i-cnt-1,cnt-1);\n\t\t\tad*=(M-sum-i);\n\t\t\tcur+=ad;\n//\t\t\tprintf(\"+=(%d %d)=%f\\n\",i-cnt-1,cnt-1,C(i-cnt-1,cnt-1));\n\t\t}\n\t}\n\tfor(int i=0;i<L;i++){\n\t\tif(i!=0&&dif[i-1]==0) continue;\n\t\tint num=0;\n\t\tfor(int j=i;j<L;j++){\n\t\t\tif(val[i]==val[j]) num++;\n\t\t\telse break;\n\t\t}\n\t\tcur*=C(N,num);\n\t}\n//\tprintf(\"res+=%f\\n\",cur/all);\n\tres+=cur/all;\n}\n\nvoid dfs2(int i){\n\tif(i==L-1){\n\t\tcalc();\n\t\treturn;\n\t}\n\tfor(int j=0;j<=2;j++){\n\t\tdif[i]=j;\n\t\tdfs2(i+1);\n\t}\n}\n\ndouble solve(){\n\tif(L==1) return 1;\n\tres=0;\n\tdfs2(0);\n\treturn res;\n}\n\nvoid init(){\n\tfor(int i=0;i<3;i++) a[i].clear();\n}\n\nint main(){\n\tint T=1;\n\twhile(true){\n\t\tinit();\n\t\tcin>>N>>M>>L;\n\t\tif(N==0) break;\n\t\tfor(int i=0;i<L;i++){\n\t\t\tstring str;\n\t\t\tcin>>str;\n\t\t\tparse(str);\n\t\t}\n\t\tfor(int i=0;i<3;i++) sort(a[i].begin(),a[i].end());\n//\t\tfor(int i=0;i<3;i++){\n//\t\t\tfor(int j=0;j<a[i].size();j++) printf(\"%d \",a[i][j]);\n//\t\t\tprintf(\"\\n\");\n//\t\t}\n\t\tdouble ans=solve();\n\t//\tcout<<setprecision(9)<<ans<<\"\\n\";\n\t//\tprintf(\"case %d %.9f\\n\",T,ans);\n\t\tprintf(\"%.9f\\n\",ans);\n\t\tT++;\n//\t\tif(T==2) break;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 1268, "score_of_the_acc": -0.0243, "final_rank": 3 }, { "submission_id": "aoj_1184_1132465", "code_snippet": "#include <string> \n#include <algorithm> \n#include <cfloat> \n#include <climits> \n#include <cmath> \n#include <complex> \n#include <cstdio> \n#include <cstdlib> \n#include <cstring> \n#include <functional> \n#include <iostream> \n#include <map> \n#include <memory> \n#include <queue> \n#include <set> \n#include <sstream> \n#include <stack> \n#include <utility> \n#include <vector> \n\n#define EACH(i,c) for(__typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define ALL(x) (x).begin(),(x).end() \ntypedef long long ll;\nusing namespace std; \nconst double eps = 1e-10;\n\nll comb[450][10];\nint N, M, L, W;\nstring s[10];\nvector<vector<int> > nums;\n\nbool check(int k, vector<int> &hand){\n if(k == nums.size()) return true;\n int sz = nums[k].size();\n for(int i = 1; i + sz <= hand.size(); ++i){\n bool over = false;\n for(int j = 0; j < sz; ++j){\n hand[i+j] -= nums[k][j];\n over |= hand[i+j] < 0;\n }\n bool res = false;\n if(!over) res = check(k+1, hand);\n for(int j = 0; j < sz; ++j) hand[i+j] += nums[k][j];\n if(res) return true;\n }\n return false;\n}\nvoid print(const vector<int> &hand){\n cout << \"h\";\n for(int i = 1; i < hand.size(); ++i)\n cout << hand[i];\n cout << endl;\n}\nll dfs(int r, vector<int> &hand){\n ll res = 0;\n if(hand.size() > M+1) return 0;\n if(r == 0 && check(0, hand)){\n res = 1;\n int zr = 0;\n for(int i = 1; i < hand.size(); ++i){\n if(hand[i]) res *= comb[N][hand[i]];\n else zr++;\n }\n if(zr){\n int deck = M - (hand.size() - 1 - zr);\n res *= comb[deck-1][zr-1];\n }\n else if(hand.size() != M+1) res = 0;\n // print(hand);\n // cout << res << endl;\n }\n if(r > 0 || hand.back()){\n for(int i = hand.back()?0:1; i<=r && i<=N; ++i){\n hand.push_back(i);\n res += dfs(r-i, hand);\n hand.pop_back();\n }\n }\n return res;\n}\nint main(){\n memset(comb, 0, sizeof(comb));\n for(int i = 0; i < 450; ++i){\n comb[i][0] = 1;\n for(int j = 1; j <= min(i,9); ++j)\n comb[i][j] = comb[i-1][j-1] + comb[i-1][j];\n }\n for(;;){\n cin >> N >> M >> L;\n if(N == 0) return 0;\n nums.assign(3, vector<int>());\n for(int i = 0; i < L; ++i){\n cin >> s[i];\n if(s[i][0] != '*'){\n vector<int> &v = nums[s[i][0]-'a'];\n if(v.size() < s[i].size()) v.resize(s[i].size());\n v[s[i].size()-1]++;\n }\n }\n sort(ALL(nums)); reverse(ALL(nums));\n while(!nums.empty() && nums.back().empty()) nums.pop_back();\n vector<int> hand(1, -1);\n double res = (double)dfs(L, hand) / comb[N*M][L];\n printf(\"%.10f\\n\", res);\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1312, "score_of_the_acc": -0.0237, "final_rank": 2 }, { "submission_id": "aoj_1184_1131417", "code_snippet": "#include <cstdio>\n#include <cmath>\n#include <cstring>\n#include <cstdlib>\n#include <climits>\n#include <ctime>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <list>\n#include <vector>\n#include <set>\n#include <map>\n#include <iostream>\n#include <deque>\n#include <complex>\n#include <string>\n#include <iomanip>\n#include <sstream>\n#include <bitset>\n#include <valarray>\n#include <iterator>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned int uint;\ntypedef unsigned char uchar;\ntypedef unsigned long long ull;\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\n\n#define REP(i,x) for(int i=0;i<(int)(x);i++)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();i++)\n#define RREP(i,x) for(int i=((int)(x)-1);i>=0;i--)\n#define RFOR(i,c) for(__typeof((c).rbegin())i=(c).rbegin();i!=(c).rend();i++)\n#define ALL(container) container.begin(), container.end()\n#define RALL(container) container.rbegin(), container.rend()\n#define SZ(container) ((int)container.size())\n#define mp(a,b) make_pair(a, b)\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n\ntemplate<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }\ntemplate<class T> ostream& operator<<(ostream &os, const vector<T> &t) {\nos<<\"[\"; FOR(it,t) {if(it!=t.begin()) os<<\",\"; os<<*it;} os<<\"]\"; return os;\n}\ntemplate<class T> ostream& operator<<(ostream &os, const set<T> &t) {\nos<<\"{\"; FOR(it,t) {if(it!=t.begin()) os<<\",\"; os<<*it;} os<<\"}\"; return os;\n}\ntemplate<class S, class T> ostream& operator<<(ostream &os, const pair<S,T> &t) { return os<<\"(\"<<t.first<<\",\"<<t.second<<\")\";}\n\nconst int INF = 1<<28;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\n\n\nint N, M, L;\n\n// O(n^2)で<=nのコンビネーションを作る\n// (パスカルの三角形)\nll C[1010][1010];\n\nvoid make_C(){\n memset(C, 0, (int)sizeof(C)); \n for(int i = 0; i < 1010; i++){\n C[i][0] = C[i][i] = 1;\n for(int j = 1; j < i; j++) C[i][j] = C[i-1][j-1] + C[i-1][j];\n }\n}\nvector<vi> seqs;\nint check(const vi &hand, vector<vi> seqs){\n\tif(seqs.empty()) return 0;\n\tvi tar = seqs.back();\n\tint res = 0;\n\tREP(i, seqs.size()) res += accumulate(ALL(seqs[i]), 0);\n\tseqs.pop_back();\n\tREP(i, hand.size()){\n\t\tif(i && hand[i-1] == hand[i]) continue;\n\t\tvi next = hand;\n\t\tint base = hand[i];\n\t\tint f = 0;\n\t\tREP(d, tar.size()){\n\t\t\tREP(i, tar[d]){\n\t\t\t\tauto it = find(ALL(next), base + d);\n\t\t\t\tif(it == next.end()){\n\t\t\t\t\tf++;\n\t\t\t\t}else next.erase(it);\n\t\t\t}\n\t\t}\n\t\tif(res > f) res = min(res, f + check(next, seqs));\n\t\tif(res == 0) return 0;\n\t}\n\treturn res;\n}\n\nvector<int> compress(const vi &hand, const int tail){\n\tif(hand.empty()) return vector<int>();\n\tvector<int> res;\n\tint base = hand[0];\n\tint t = 1;\n\tfor(int i=1;i<hand.size();i++){\n\t\tif(hand[i] - hand[i-1] > 1){\n\t\t\tres.push_back(t);\n\t\t\tt = 1;\n\t\t\tbase = hand[i];\n\t\t}else{\n\t\t\tt += 1<<(3*(hand[i] - base));\n\t\t}\n\t}\n\tres.push_back(t);\n\tsort(res.begin(), res.end()-1);\n//\tcout << hand << \"->\" << res << endl;\n\tres.push_back(tail);\n\treturn res;\n}\n\nmap<vector<int>, ll> memo;\nll enumerate(vi &hand, int tail){\n\tif(count(ALL(hand), tail) > M) return 0;\n\t\n\tauto state = compress(hand, tail);\n\tauto memop = memo.find(state);\n\tif(memop != memo.end()) return memop->second;\n\t\n\tint need = check(hand, seqs);\n//\tcout << hand << \": \" << need << endl;\n\tif(need == 0){\n\t\tmap<int, int> dist;\n\t\tFOR(it, hand) dist[*it] ++;\n\t\tll res = 1;\n\t\tFOR(it, dist) res *= C[M][it->second];\n\t\tll rest = L - hand.size();\n\t\tll allr = M*(N-tail);\n\t\tif(rest){\n\t\t\thand.push_back(tail);\n\t\t\tres = res * C[allr][rest] + enumerate(hand, tail);\n\t\t\thand.pop_back();\n\t\t}\n//\t\tcout << hand << \": \" << res << endl;\n\t\treturn memo[state] = res;\n\t}else if(need > L - hand.size()) return memo[state] = 0;\n\tif(hand.size() == L){\n\t\treturn 0;\n\t}\n\tll res = 0;\n\thand.push_back(tail);\n\tfor(int i=tail;i<=N;i++){\n\t\thand.back() = i;\n\t\tres += enumerate(hand, i);\n\t}\n\thand.pop_back();\n\treturn memo[state] = res;\n}\n\n\nmain(){\n\tmake_C();\n\tios::sync_with_stdio(false);\n\twhile(cin >> M >> N >> L, N){\n\t\tseqs = vector<vi>(3);\n\t\tint ast=3;\n\t\tREP(i, L){\n\t\t\tstring s;\n\t\t\tcin >> s;\n\t\t\tif(s[0] != '*'){\n\t\t\t\tint d = s.size() - 1;\n\t\t\t\tint t = s[0] - 'a';\n\t\t\t\tif(seqs[t].size() <= d) seqs[t].resize(d+1);\n\t\t\t\tseqs[t][d] ++;\n\t\t\t}\n\t\t}\n\t\tRREP(i, seqs.size()){\n\t\t\tif(accumulate(ALL(seqs[i]), 0) <= 1) seqs.erase(seqs.begin() + i);\n\t\t}\n//\t\tcout << seqs << endl;\n\t\tvi hand;\n//\t\tprintf(\"%lld / %lld\\n\", enumerate(hand, 1), C[N*M][L]);\n\t\tprintf(\"%.10f\\n\", enumerate(hand, 1) / (double)C[N*M][L]);\n\t\tmemo.clear();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 4630, "memory_kb": 12604, "score_of_the_acc": -1.6745, "final_rank": 20 } ]
aoj_1182_cpp
Railway Connection Tokyo has a very complex railway system. For example, there exists a partial map of lines and stations as shown in Figure D-1. Figure D-1: A sample railway network Suppose you are going to station D from station A. Obviously, the path with the shortest distance is A→B→D. However, the path with the shortest distance does not necessarily mean the minimum cost. Assume the lines A-B, B-C, and C-D are operated by one railway company, and the line B-D is operated by another company. In this case, the path A→B→C→D may cost less than A→B→D. One of the reasons is that the fare is not proportional to the distance. Usually, the longer the distance is, the fare per unit distance is lower. If one uses lines of more than one railway company, the fares charged by these companies are simply added together, and consequently the total cost may become higher although the distance is shorter than the path using lines of only one company. In this problem, a railway network including multiple railway companies is given. The fare table (the rule to calculate the fare from the distance) of each company is also given. Your task is, given the starting point and the goal point, to write a program that computes the path with the least total fare. Input The input consists of multiple datasets, each in the following format. n m c s g x 1 y 1 d 1 c 1 ... x m y m d m c m p 1 ... p c q 1,1 ... q 1, p 1 -1 r 1,1 ... r 1, p 1 ... q c ,1 ... q c,p c -1 r c ,1 ... r c,p c Every input item in a dataset is a non-negative integer. Input items in the same input line are separated by a space. The first input line gives the size of the railway network and the intended trip. n is the number of stations (2 ≤ n ≤ 100). m is the number of lines connecting two stations (0 ≤ m ≤ 10000). c is the number of railway companies (1 ≤ c ≤ 20). s is the station index of the starting point (1 ≤ s ≤ n ). g is the station index of the goal point (1 ≤ g ≤ n , g ≠ s ). The following m input lines give the details of (railway) lines. The i -th line connects two stations x i and y i (1 ≤ x i ≤ n , 1 ≤ y i ≤ n , x i ≠ y i ). Each line can be traveled in both directions. There may be two or more lines connecting the same pair of stations. d i is the distance of the i -th line (1 ≤ d i ≤ 200). c i is the company index of the railway company operating the line (1 ≤ c i ≤ c ). The fare table (the relation between the distance and the fare) of each railway company can be expressed as a line chart. For the railway company j , the number of sections of the line chart is given by p j (1 ≤ p j ≤ 50). q j,k (1 ≤ k ≤ p j -1) gives the distance separating two sections of the chart (1 ≤ q j,k ≤ 10000). r j,k (1 ≤ k ≤ p j ) gives the fare increment per unit distance for the corresponding section of the chart (1 ≤ r j,k ≤ 100). More precisely, with the fare for the distance z denoted by f j ( z ), the fare for distance z satisfying q j , k -1 +1 ≤ z ≤ q j , k is computed by the recurrence relation f j ( z ...(truncated)
[ { "submission_id": "aoj_1182_10852690", "code_snippet": "/*\n * Author:heroming\n * File:heroming.cpp\n * Time:2012-7-19 9:33:45\n */\n#include <iostream>\n#include <cstdio>\n#include <string>\n#include <cstring>\n#include <cmath>\n#include <algorithm>\n#include <vector>\n#include <queue>\nusing namespace std;\n\n#define SZ(v) ((int)(v).size())\nconst int INFI = 1<<30;\nconst int MAXN = 102, MAXC = 22, MAXP = 52;\n\nbool inQ[MAXN];\nint n, m, c, s, g;\nint maps[MAXN][MAXN][MAXC], dis[MAXN];\nint P[MAXC], Q[MAXP][MAXP], R[MAXP][MAXP];\n\nint get_cost(int k, int d)\n{\n int x = 0;\n for (int i = 1; i < P[k]; ++ i)\n {\n if (d > Q[k][i])\n x += (Q[k][i] - Q[k][i - 1]) * R[k][i];\n else\n {\n x += (d - Q[k][i - 1]) * R[k][i];\n return x;\n }\n }\n return x + R[k][P[k]] * (d - Q[k][P[k] - 1]);\n}\n\nvoid SPFA()\n{\n memset(inQ, 0, sizeof(inQ));\n for (int i = 1; i <= n; ++ i)\n dis[i] = INFI;\n dis[s] = 0;\n queue<int> Q;\n Q.push(s);\n inQ[s] = 1;\n while (! Q.empty())\n {\n int u = Q.front();\n Q.pop();\n inQ[u] = 0;\n for (int i = 1; i <= n; ++ i)\n for (int j = 1; j <= c; ++ j)\n if (maps[u][i][j] != -1)\n {\n int p = get_cost(j, maps[u][i][j]);\n if (dis[u] + p < dis[i])\n {\n dis[i] = dis[u] + p;\n if (! inQ[i])\n {\n Q.push(i);\n inQ[i] = 1;\n }\n }\n }\n }\n}\n\nint main()\n{\n while (scanf(\"%d%d%d%d%d\", &n, &m, &c, &s, &g) != EOF && n)\n {\n memset(maps, -1, sizeof(maps));\n int x, y, w, e;\n for (int i = 0; i < m; ++ i)\n {\n scanf(\"%d%d%d%d\", &x, &y, &w, &e);\n if (maps[x][y][e] != -1)\n maps[x][y][e] = maps[y][x][e] = min(maps[x][y][e], w);\n else\n maps[x][y][e] = maps[y][x][e] = w;\n }\n for (int i = 1; i <= c; ++ i)\n scanf(\"%d\", &P[i]);\n for (int i = 1; i <= c; ++ i)\n {\n for (int j = 1; j < P[i]; ++ j)\n scanf(\"%d\", &Q[i][j]);\n for (int j = 1; j <= P[i]; ++ j)\n scanf(\"%d\", &R[i][j]);\n }\n for (int l = 1; l <= c; ++ l)\n for (int k = 1; k <= n; ++ k)\n for (int i = 1; i <= n; ++ i)\n for (int j = 1; j <= n; ++ j)\n {\n if (i == j || i == k || j == k || maps[i][k][l] == -1 || maps[k][j][l] == -1)\n continue;\n if (maps[i][j][l] == -1 || maps[i][k][l] + maps[k][j][l] < maps[i][j][l])\n maps[i][j][l] = maps[j][i][l] = maps[i][k][l] + maps[k][j][l];\n }\n\n SPFA();\n if (dis[g] == INFI)\n printf(\"-1\\n\");\n else\n printf(\"%d\\n\", dis[g]);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 4336, "score_of_the_acc": -0.6141, "final_rank": 10 }, { "submission_id": "aoj_1182_10688402", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <cmath>\n#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n\n#define mpair make_pair\n#define pii pair<int,int>\n#define MM(a,b) memset(a,b,sizeof(a));\ntypedef long long lld;\ntypedef unsigned long long u64;\ntemplate<class T> bool up_max(T& a,const T& b){return b>a? a=b,1 : 0;}\ntemplate<class T> bool up_min(T& a,const T& b){return b<a? a=b,1 : 0;}\n#define maxn 105\nconst int inf = 1000000000;\n\nint n,m,c;\n\nstruct Edge{\n int x,y,d,ci;\n void init(){\n scanf(\"%d%d%d%d\", &x,&y,&d,&ci);\n }\n}e[10010];\nstruct Info{\n int p[53], r[53];\n void init(){\n for(int i=1;i<p[0];++i) scanf(\"%d\", p+i);\n for(int i=1;i<=p[0];++i) scanf(\"%d\", r+i);\n }\n}info[25];\n\nint g[maxn][maxn];\nint endmap[maxn][maxn];\nint dis[maxn][maxn];\n\n\nint cal(int d,int ci){\n Info *h= &info[ci];\n if( h->p[0] == 1 || d<= h->p[1] ) return d* h->r[1];\n int i=1,cost= h->p[1] * h->r[1];\n while(1){\n if( (h->p[i] < d && d<= h->p[i+1]) || i== h->p[0]-1 ){\n cost += ( d - h->p[i] ) * h->r[i+1];\n break;\n }\n else cost += (h->p[i+1]-h->p[i]) * h->r[i+1];\n ++i;\n }\n return cost;\n}\n\nvoid floyd(){\n for(int k=1;k<=n;++k)\n for(int i=1;i<=n;++i)\n if( i!=k && g[i][k]!=inf )\n for(int j=1;j<=n;++j)\n if( j!=i && j!=k && g[k][j]!=inf )\n up_min( g[i][j], g[i][k] + g[k][j] );\n}\n\nint main()\n{\n //freopen(\"D.in\",\"r\",stdin);\n int st,ed;\n while( cin>>n>>m>>c>>st>>ed, n+m+c+st+ed ){\n for(int i=0;i<m;++i) e[i].init();\n for(int i=1;i<=c;++i) scanf(\"%d\", &info[i].p[0] );\n for(int i=1;i<=c;++i) info[i].init();\n\n for(int i=1;i<=n;++i)for(int j=1;j<=n;++j)endmap[i][j]= inf;\n\n for(int ci= 1; ci<=c; ++ci){\n for(int i=1;i<=n;++i)for(int j=1;j<=n;++j)g[i][j]= inf;\n for(int i=0;i<m;++i){\n if( e[i].ci == ci ){\n if( up_min( g[e[i].x][e[i].y], e[i].d ) )\n g[ e[i].y ][ e[i].x ]= e[i].d;\n }\n }\n floyd();\n\n for(int i=1;i<=n;++i)\n for(int j=1;j<=n;++j)\n if( i!=j && g[i][j]!=inf ){\n int t= cal( g[i][j], ci );\n if( up_min( endmap[i][j], t ) )\n endmap[j][i]= t;\n }\n }\n for(int i=1;i<=n;++i)for(int j=1;j<=n;++j)g[i][j]= endmap[i][j];\n floyd();\n if( g[st][ed] == inf ) puts(\"-1\");\n else printf(\"%d\\n\", g[st][ed]);\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3712, "score_of_the_acc": -0.0588, "final_rank": 1 }, { "submission_id": "aoj_1182_10648443", "code_snippet": "#include <queue>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#ifndef ONLINE_JUDGE\n#define _GLIBCXX_DEBUG // 配列外参照のエラー\n#endif\n\n// スタンダードライブラリ\n#include <bits/stdc++.h>\nusing namespace std;\n\n// 型関連\nusing ll = long long;\nusing lint = long long;\nusing pll = pair<ll, ll>;\nusing plll = tuple<ll, ll, ll>;\nusing pii = pair<int, int>;\nusing piii = tuple<ll, ll, ll>;\nusing vi = vector<int>;\nusing vvi = vector<vector<int>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing vvvvi = vector<vector<vector<vector<int>>>>;\nusing vl = vector<ll>;\nusing vvl = vector<vector<ll>>;\nusing vvvl = vector<vector<vector<ll>>>;\nusing vvvvl = vector<vector<vector<vector<ll>>>>;\n\ntemplate <class T> using prique = priority_queue<T>;\n\n// 型定数\nconstexpr ll mod = 998244353;\nconstexpr ll MOD = 1000000007;\nint INF32 = 1e9;\nll INF64 = 9e18;\n#define endl '\\n';\n\nint dx[4] = {1, 0, -1, 0};\nint dy[4] = {0, 1, 0, -1};\n\n/////////////////////////// print関連\ntemplate <typename T> void print(vector<T> A);\nvoid print();\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail);\nvoid print(string S);\ntemplate <typename T> void print(vector<vector<T>> &F);\n\ninline void Yes(bool f);\n\n///////////////////ここから//////////////////////\nbool solve() {\n int N, M, C, s, g;\n cin >> N >> M >> C >> s >> g;\n if (N == 0) {\n return false;\n }\n s--;\n g--;\n vvvi CE(C, vvi(N, vi(N, INF32)));\n\n for (int i = 0; i < M; i++) {\n int u, v, d, c;\n cin >> u >> v >> d >> c;\n u--, v--, c--;\n CE[c][u][v] = min(CE[c][u][v], d);\n CE[c][v][u] = min(CE[c][v][u], d);\n }\n\n int max_size = N * 200;\n vvl Ryokin(C);\n vector<int> P(C);\n for (int i = 0; i < C; i++) {\n cin >> P[i];\n }\n for (int i = 0; i < C; i++) {\n vector<ll> Q(P[i], 0);\n for (int j = 0; j < P[i]-1; j++) {\n cin >> Q[j + 1];\n }\n Q.push_back(max_size);\n vector<ll> R(P[i]);\n for (int j = 0; j < P[i]; j++) {\n cin >> R[j];\n }\n\n Ryokin[i].push_back(0);\n for (int j = 1; j < Q.size(); j++) {\n for (int k = Q[j - 1]; k < Q[j]; k++) {\n Ryokin[i].emplace_back(Ryokin[i].back() + R[j-1]);\n }\n }\n //print(Ryokin[i]);\n }\n\n vector<vector<pll>> G(N);\n for (int c = 0; c < C; c++) {\n for (int k = 0; k < N; k++) {\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n CE[c][i][j] = min(CE[c][i][j], CE[c][i][k] + CE[c][k][j]);\n }\n }\n }\n for (int i = 0; i < N; i++) {\n for (int j = i + 1; j < N; j++) {\n ll D = CE[c][i][j];\n if (D == INF32) {\n continue;\n }\n\n ll cost = Ryokin[c][D];\n G[i].emplace_back(j, cost);\n G[j].emplace_back(i, cost);\n }\n }\n }\n\n vector<ll> dist(N, INF64);\n vector<int> f(N, 0);\n priority_queue<pll, vector<pll>, greater<pll>> que;\n que.emplace(0, s);\n dist[s]=0;\n while (!que.empty()) {\n auto [D, v] = que.top();\n que.pop();\n if (f[v]) {\n continue;\n }\n f[v] = 1;\n for (auto [nv, cost] : G[v]) {\n if (dist[nv] > dist[v] + cost) {\n dist[nv] = dist[v] + cost;\n que.emplace(dist[nv],nv);\n }\n }\n }\n if (dist[g] == INF64) {\n print(-1);\n } else {\n print(dist[g]);\n }\n \n\n\n return true;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n while (solve())\n ;\n}\n\n////////////////////print/////////////////////////\n// 1次元ベクトルを出力する\ntemplate <typename T> void print(vector<T> A) {\n if (A.size() == 0) {\n return;\n }\n for (size_t i = 0; i < A.size() - 1; i++) {\n cout << A[i] << ' ';\n }\n cout << A[A.size() - 1] << endl;\n return;\n}\n\n// 2次元ベクトルを出力する\ntemplate <typename T> void print(vector<vector<T>> &F) {\n for (size_t i = 0; i < F.size(); i++) {\n for (size_t j = 0; j < F[i].size(); j++) {\n cout << F[i][j];\n if (j < F[i].size() - 1) {\n cout << ' ';\n }\n }\n cout << endl;\n }\n}\n\n// 空白行を出力するprint\nvoid print() { cout << endl; }\n\n// 数値・文字列を空白区切りで出力する. print(a,b)など\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n cout << head;\n if (sizeof...(tail) != 0)\n cout << \" \";\n print(forward<Tail>(tail)...);\n}\n\nvoid print(string S) { cout << S << endl; }\n\n//////////////出力関連\n\ninline void Yes(bool f) {\n if (f) {\n cout << \"Yes\" << endl;\n } else {\n cout << \"No\" << endl;\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 11080, "score_of_the_acc": -1.1471, "final_rank": 17 }, { "submission_id": "aoj_1182_10647161", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int INF = 1e9 + 7;\nint main(){\n while(true){\n int n,m,c,s,g;\n cin >> n >> m >> c >> s >> g;\n if(n == 0) break;\n s--;\n g--;\n vector<vector<vector<int>>>Dist(n,vector<vector<int>>(n,vector<int>(c,INF)));\n\n for(int i = 0;i < m;i++){\n int x,y,d,com;\n cin >> x >> y >> d >> com;\n x--;\n y--;\n com--;\n if(Dist[x][y][com] > d){\n Dist[x][y][com] = d;\n Dist[y][x][com] = d;\n }\n }\n \n vector<int>p(c);\n for(int i = 0;i < c;i++) cin >> p[i];\n \n \n for (int i = 0;i < c;i++){\n for (int j = 0;j < n;j++){\n for (int k = 0;k < n;k++){\n for (int k2 = 0;k2 < n;k2++){\n if (Dist[k][k2][i] > Dist[k][j][i] + Dist[j][k2][i]){\n Dist[k][k2][i] = Dist[k][j][i] + Dist[j][k2][i];\n }\n }\n }\n }\n\n \n if (p[i] == 0) continue;\n\n vector<int>q(p[i]-1);\n vector<int>r(p[i]);\n vector<int>C(100000, 0);\n\n for (int j = 0;j < p[i]-1;j++) cin >> q[j];\n for (int j = 0;j < p[i];j++) cin >> r[j];\n\n int cnt = 0;\n for (int j = 1;j < 100000;j++){\n if (cnt<p[i]-1 && j>q[cnt]) cnt++;\n C[j] = C[j - 1]+r[cnt];\n }\n\n for (int k = 0;k < n;k++) {\n for (int k2 = 0;k2 < n;k2++) {\n if (Dist[k][k2][i] < INF) {\n if (Dist[k][k2][i] < 100000) {\n Dist[k][k2][i] = C[Dist[k][k2][i]];\n } \n else {\n Dist[k][k2][i] = INF;\n }\n }\n }\n }\n}\n\n vector<vector<int>>vec(n,vector<int>(n,INF));\n for(int i = 0; i < n; i++){\n vec[i][i] = 0;\n for(int j = 0; j < n; j++){\n for(int k = 0; k < c; k++){\n if(vec[i][j] > Dist[i][j][k]){\n vec[i][j] = Dist[i][j][k];\n }\n }\n }\n }\n \n for(int i = 0; i < n; i++){\n for(int j = 0; j < n; j++){\n for(int k = 0; k < n; k++){\n if(vec[j][k] > vec[j][i] + vec[i][k]){\n vec[j][k] = vec[j][i] + vec[i][k];\n }\n }\n }\n }\n \n if(vec[s][g] < INF){\n cout << vec[s][g] << endl;\n }\n else{\n cout << -1 << endl;\n }\n\n \n }\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 4736, "score_of_the_acc": -0.7566, "final_rank": 14 }, { "submission_id": "aoj_1182_10645444", "code_snippet": "#include <vector>\n#include <iostream>\nusing namespace std;\n\nint main(){\n int n, m, c, s, g, x, y, ca, d, p;\n while(cin >> n >> m >> c >> s >> g && n != 0){\n s--;\n g--;\n vector< vector< vector <int> > > D(n, vector<vector<int> >(n, vector<int>(c, 10000000)));\n\n for(int i = 0; i < m; i++){\n cin >> x >> y >> d >> ca;\n x--; y--; ca--;\n if(D.at(x).at(y).at(ca) > d){\n D.at(x).at(y).at(ca) = d;\n D.at(y).at(x).at(ca) = d;\n }\n }\n\n vector<int> P(c);\n for(int i = 0; i < c; i++){\n cin >> P.at(i);\n }\n\n for(int l = 0; l < c; l++){\n // Warshall-Floyd\n for(int k = 0; k < n; k++){\n for(int i = 0; i < n; i++){\n for(int j = 0; j < n; j++){\n if(D.at(i).at(j).at(l) > D.at(i).at(k).at(l) + D.at(k).at(j).at(l)){\n D.at(i).at(j).at(l) = D.at(i).at(k).at(l) + D.at(k).at(j).at(l);\n }\n }\n }\n }\n\n p = P.at(l);\n if (p == 0) continue; // 料金情報がない会社はスキップ\n\n vector<int> Q(p - 1);\n vector<int> R(p);\n vector<int> C(20000, 0);\n\n for(int i = 0; i < p - 1; i++){\n cin >> Q.at(i);\n }\n for(int i = 0; i < p; i++){\n cin >> R.at(i);\n }\n\n int z = 0;\n for(int i = 1; i < 20000; i++){\n if(z < p - 1 && i > Q.at(z)){\n z++;\n }\n C.at(i) = C.at(i - 1) + R.at(z);\n }\n\n for(int i = 0; i < n; i++){\n for(int j = 0; j < n; j++){\n if(D.at(i).at(j).at(l) < 10000000){\n int dist = D.at(i).at(j).at(l);\n if (dist < 20000) {\n D.at(i).at(j).at(l) = C.at(dist);\n } else {\n D.at(i).at(j).at(l) = 10000000; // 無効距離は無限コストに\n }\n }\n }\n }\n }\n\n vector<vector<int>> A(n, vector<int>(n, 10000000));\n for(int i = 0; i < n; i++){\n A.at(i).at(i) = 0;\n for(int j = 0; j < n; j++){\n for(int k = 0; k < c; k++){\n if(A.at(i).at(j) > D.at(i).at(j).at(k)){\n A.at(i).at(j) = D.at(i).at(j).at(k);\n }\n }\n }\n }\n\n for(int k = 0; k < n; k++){\n for(int i = 0; i < n; i++){\n for(int j = 0; j < n; j++){\n if(A.at(i).at(j) > A.at(i).at(k) + A.at(k).at(j)){\n A.at(i).at(j) = A.at(i).at(k) + A.at(k).at(j);\n }\n }\n }\n }\n\n if(A.at(s).at(g) < 10000000){\n cout << A.at(s).at(g) << endl;\n } else {\n cout << \"-1\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 4444, "score_of_the_acc": -1.0993, "final_rank": 16 }, { "submission_id": "aoj_1182_10643614", "code_snippet": "#include <vector>\n#include <iostream> \n\nusing namespace std;\n\nint main(){\n int n,m,c,s,g,x,y,ca,d,p;\n while(cin>>n>>m>>c>>s>>g && n!=0){\n s--;\n g--;\n vector< vector< vector <int> > > D (n,vector<vector<int> >(n,vector<int>(c, 10000000)));\n for(int i=0; i<m; i++){\n cin>>x>>y>>d>>ca;\n if(D.at(x-1).at(y-1).at(ca-1)>d){\n D.at(x-1).at(y-1).at(ca-1)=d;\n D.at(y-1).at(x-1).at(ca-1)=d;\n }\n }\n vector<int> P(c);\n for(int i=0; i<c; i++){\n cin>>P.at(i);\n }\n for(int l=0; l<c; l++){\n for(int k=0; k<n; k++){\n for(int i=0;i<n;i++){\n for(int j=0; j<i;j++){\n if(D.at(i).at(j).at(l)>(D.at(i).at(k).at(l)+D.at(k).at(j).at(l))){\n D.at(i).at(j).at(l)=(D.at(i).at(k).at(l)+D.at(k).at(j).at(l));\n D.at(j).at(i).at(l)=D.at(i).at(j).at(l);\n }\n }\n }\n }\n p=P.at(l);\n vector<int> Q(p);\n vector<int> R(p);\n vector<int> C(20000,0);\n for(int i=0; i<p-1; i++){\n cin>>Q.at(i);\n }\n for(int i=0; i<p; i++){\n cin>>R.at(i);\n }\n int z=0;\n for(int i=1; i<20000; i++){\n if(z!=p-1 && i>Q.at(z)){\n z++;\n }\n C.at(i)=C.at(i-1)+R.at(z);\n }\n for(int i=0;i<n;i++){\n for(int j=0; j<n;j++){\n if(D.at(i).at(j).at(l)<10000000){\n int dist=D.at(i).at(j).at(l);\n D.at(i).at(j).at(l)=C.at(dist);\n }\n }\n }\n }\n vector<vector<int> >A(n,vector<int>(n,10000000));\n for(int i=0; i<n; i++){\n for(int j=0; j<n; j++){\n for(int k=0; k<c; k++){\n if(A.at(i).at(j)>D.at(i).at(j).at(k)){\n A.at(i).at(j) = D.at(i).at(j).at(k);\n }\n }\n }\n }\n for(int k=0; k<n; k++){\n for(int i=0;i<n;i++){\n for(int j=0; j<n;j++){\n if(A.at(i).at(j)>(A.at(i).at(k)+A.at(k).at(j))){\n A.at(i).at(j)=(A.at(i).at(k)+A.at(k).at(j));\n }\n }\n }\n }\n if(A.at(s).at(g)<10000000){\n cout<<A.at(s).at(g)<<endl;\n }\n else{\n cout<<\"-1\"<<endl;\n }\n }\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 4520, "score_of_the_acc": -0.6097, "final_rank": 9 }, { "submission_id": "aoj_1182_10642982", "code_snippet": "#include <cstdio>\n#include <queue>\n#include <tuple>\n#include <vector>\n#define repeat(i, n) for (int i = 0; (i) < int(n); ++(i))\nusing namespace std;\ntemplate <class T> inline void setmax(T & a, T const & b) { a = max(a, b); }\ntemplate <class T> inline void setmin(T & a, T const & b) { a = min(a, b); }\ntemplate <typename X, typename T> auto vectors(X x, T a) { return vector<T>(x, a); }\ntemplate <typename X, typename Y, typename Z, typename... Zs> auto vectors(X x, Y y, Z z, Zs... zs) { auto cont = vectors(y, z, zs...); return vector<decltype(cont)>(x, cont); }\ntemplate <class T> using reversed_priority_queue = priority_queue<T, vector<T>, greater<T> >;\n\nint main() {\n constexpr int inf = 1e9+7;\n while (true) {\n // input\n int n, m, company, start, goal; scanf(\"%d%d%d%d%d\", &n, &m, &company, &start, &goal); -- start; -- goal;\n if (n == 0) break;\n auto g = vectors(company, n, vector<pair<int, int> >());\n repeat (i, m) {\n int x, y, d, c; scanf(\"%d%d%d%d\", &x, &y, &d, &c); -- x; -- y; -- c;\n g[c][x].emplace_back(y, d);\n g[c][y].emplace_back(x, d);\n }\n vector<int> p(company);\n repeat (c, company) {\n scanf(\"%d\", &p[c]);\n }\n vector<vector<int> > q(company);\n vector<vector<int> > r(company);\n repeat (c, company) {\n q[c].resize(p[c] - 1);\n repeat (i, p[c] - 1) {\n scanf(\"%d\", &q[c][i]);\n }\n r[c].resize(p[c]);\n repeat (i, p[c]) {\n scanf(\"%d\", &r[c][i]);\n }\n }\n // solve\n // // initialize costs\n auto dist = vectors(company, n, n, inf);\n repeat (c, company) {\n repeat (i, n) {\n dist[c][i][i] = 0;\n for (auto e : g[c][i]) {\n int j, d; tie(j, d) = e;\n setmin(dist[c][i][j], d);\n }\n }\n repeat (k, n) repeat (i, n) repeat (j, n) { // Warshall-Floyd\n setmin(dist[c][i][j], dist[c][i][k] + dist[c][k][j]);\n }\n }\n auto cost = vectors(company, n, n, inf);\n repeat (c, company) {\n int max_dist = 0;\n repeat (i, n) repeat (j, n) if (dist[c][i][j] != inf) {\n setmax(max_dist, dist[c][i][j]);\n }\n vector<int> cost_at(max_dist + 3);\n int i = 0;\n repeat (d, cost_at.size() - 1) {\n if (i < p[c] - 1 and d == q[c][i]) ++ i;\n cost_at[d + 1] = cost_at[d] + r[c][i];\n }\n repeat (i, n) repeat (j, n) if (dist[c][i][j] != inf) {\n cost[c][i][j] = cost_at[dist[c][i][j]];\n }\n }\n // // Dijkstra\n vector<int> result(n, inf);\n vector<bool> fixed(n);\n reversed_priority_queue<pair<int, int> > que;\n result[start] = 0;\n que.emplace(0, start);\n while (not que.empty()) {\n int i = que.top().second; que.pop();\n if (fixed[i]) continue;\n fixed[i] = true;\n repeat (j, n) {\n int d = inf;\n repeat (c, company) {\n setmin(d, result[i] + cost[c][i][j]);\n }\n if (d < result[j]) {\n result[j] = d;\n que.emplace(d, j);\n }\n }\n }\n // output\n printf(\"%d\\n\", result[goal] == inf ? -1 : result[goal]);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4792, "score_of_the_acc": -0.2936, "final_rank": 3 }, { "submission_id": "aoj_1182_10630899", "code_snippet": "//#pragma GCC optimize(\"O3\")\n#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,n) for (ll i=0;i<(ll)n;i++)\n#define rrep(i,n) for (ll i=n-1;i>=(ll)0;i--)\n#define loop(i,m,n) for(ll i=m;i<=(ll)n;i++)\n#define rloop(i,m,n) for(ll i=m;i>=(ll)n;i--)\n#define vl vector<ll>\n#define vvl vector<vector<ll>>\n#define vdbg(a) rep(ii,a.size()){cout<<a[ii]<<\" \";}cout<<endl;\n#define vpdbg(a) rep(ii,a.size()){cout<<\"{\"<<a[ii].first<<\",\"<<a[ii].second<<\"} \";}cout<<endl;\n#define vvdbg(a) rep(ii,a.size()){rep(jj,a[ii].size()){cout<<a[ii][jj]<<\" \";}cout<<endl;}\n#define setdbg(a) for(const auto & ii:a){cout<<ii<<\" \";}cout<<endl;\n#define inf 1e9\n#define mod 998244353LL\n//#define mod 1000000007LL\n#define eps 0.000000001\nrandom_device rnd;// 非決定的な乱数生成器\nmt19937 mt(rnd());// メルセンヌ・ツイスタの32ビット版、引数は初期シード\n\n//#include<boost/multiprecision/cpp_int.hpp>\n//#define bbi boost::multiprecision::cpp_int\n//#include<atcoder/lazysegtree>\n\n\n//整数同士の累乗の計算をする。\nll power(ll A, ll B) {\n\tll result = 1;\n\tfor (ll i=0;i<B;i++){\n\t\tresult *= A;\n\t}\n\treturn result;\n}\n\n// nのk乗をmodで割った余りを計算\nll power_mod(ll n, ll k){\n\tlong long result = 1;\n\twhile (k > 0){\n\t\tif ((k&1) ==1)result=(result*n)%mod;\n\t\tn=n*n%mod;\n\t\tk >>= 1;\n\t}\n\treturn result;\n}\n\n\n//受け取った2次元文字の外側に、文字pをコーティングする。\nvector<string> pad(vector<string> &s,char p){\n\tll h=s.size();\n\tll w=s[0].size();\n\tvector<string> res(h+2,string(w+2,p));\n\trep(i,h)rep(j,w)res[i+1][j+1]=s[i][j];\n\treturn res;\n}\n\n// Union-Find\nstruct UnionFind {\n\tvector<int> par, siz;\n\tUnionFind(int n) : par(n, -1) , siz(n, 1) { }\n\t// 根を求める\n\tint root(int x) {\n\t\tif (par[x] == -1) return x;\n\t\telse return par[x] = root(par[x]);\n\t}\n\t// x と y が同じグループに属するかどうか (根が一致するかどうか)\n\tbool issame(int x, int y) {\n\t\treturn root(x) == root(y);\n\t}\n\t// x を含むグループと y を含むグループとを併合する\n\tbool unite(int x, int y) {\n\t\tx = root(x), y = root(y);\n\t\tif (x == y) return false; \n\t\tif (siz[x] < siz[y]) swap(x, y);\n\t\tpar[y] = x;\n\t\tsiz[x] += siz[y];\n\t\treturn true;\n\t}\n\t// x を含むグループのサイズ\n\tint size(int x) {\n\t\treturn siz[root(x)];\n\t}\n};\n\n\n//グリッド問題等用\nvl dx={1,0,-1,0};\nvl dy={0,1,0,-1};\n\nvoid warshall_floyd(vvl & d){\n\tll n=d.size();\n\trep(k,n)rep(i,n)rep(j,n)d[i][j] = min(d[i][j], d[i][k] + d[k][j]);\n}\n\nll solve(){\n\tll n,m,c,start,goal;\n\tcin>>n>>m>>c>>start>>goal;\n\tstart--,goal--;\n\tif(n==0){return 1;}\n\n\tvector<vvl> g(c,vvl(n,vl(n,inf)));\n\trep(i,m){\n\t\tll x,y,d,cc;\n\t\tcin>>x>>y>>d>>cc;\n\t\tx--,y--,cc--;\n\t\tg[cc][x][y]=min(g[cc][x][y],d);\n\t\tg[cc][y][x]=min(g[cc][y][x],d);\n\t}\n\n\trep(i,c){\n\t\twarshall_floyd(g[i]);\n\t}\n\n\tvl p(c);\n\trep(i,c)cin>>p[i];\n\n\t//cout<<\"test\"<<endl;\n\n\trep(i,c){\n\t\tvl q(p[i]-1);\n\t\tvl r(p[i]);\n\t\trep(j,p[i]-1)cin>>q[j];\n\t\trep(j,p[i])cin>>r[j];\n\t\tq.push_back(inf);\n\n\t\tvl nedan(20001);\n\t\tnedan[0]=0;\n\t\tll ind=0;\n\t\tloop(j,1,20000){\n\t\t\tnedan[j]=nedan[j-1]+r[ind];\n\t\t\tif(q[ind]==j)ind++;\n\t\t}\n\t\trep(j,n)rep(k,n){\n\t\t\tif(g[i][j][k]==inf)continue;\n\t\t\tg[i][j][k]=nedan[g[i][j][k]];\n\t\t}\n\t}\n\tvvl wf(n,vl(n,inf));\n\trep(i,c)rep(j,n)rep(k,n){\n\t\twf[j][k]=min(wf[j][k],g[i][j][k]);\n\t}\n\n\twarshall_floyd(wf);\n\tif(wf[start][goal]!=inf)cout<<wf[start][goal]<<\"\\n\";\n\telse cout<<-1<<\"\\n\";\n\treturn 0;\n}\n\n//メイン\nint main(){\n\twhile(solve()==0);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 5032, "score_of_the_acc": -0.385, "final_rank": 7 }, { "submission_id": "aoj_1182_10572190", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rrep(i,start,end) for (ll i = start;i >= (ll)(end);i--)\n#define repn(i,end) for(ll i = 0; i <= (ll)(end); i++)\n#define reps(i,start,end) for(ll i = start; i < (ll)(end); i++)\n#define repsn(i,start,end) for(ll i = start; i <= (ll)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef vector<ll> vll;\ntypedef vector<pair<ll ,ll>> vpll;\ntypedef vector<vector<ll>> vvll;\ntypedef set<ll> sll;\ntypedef map<ll , ll> mpll;\ntypedef pair<ll ,ll> pll;\ntypedef tuple<ll , ll , ll> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (ll)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1LL << 60;\nconst ld EPS = 1e-9;\n \nll lceil(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b)+1;}else{return -((-a)/b);}}\nll lfloor(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b);}else{return -((-a)/b)-1;}}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\n//0indexed\ninline ll topbit(ll a){assert(a != 0);return 63 - __builtin_clzll(a);}\ninline ll smlbit(ll a){assert(a != 0);return __builtin_ctzll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\nvoid solve(ll n,ll m,ll C,ll S,ll G){\n S--;\n G--;\n vector<vector<vector<pll>>> g(n,vector<vector<pll>>(C));\n rep(i,m){\n LL(x,y,d,c);\n x--;y--;\n c--;\n g[x][c].push_back({y,d});\n g[y][c].push_back({x,d});\n \n }\n vll P(C);\n cin >> P;\n vector<vector<ll>>Q(C),R(C);\n rep(i,C){\n rep(j,P[i]-1){\n LL(q);\n Q[i].push_back(q);\n }\n rep(j,P[i]){\n LL(r);\n R[i].push_back(r);\n }\n }\n\n ll maxdist = 20000 + 1;\n\n vvll Ccost(C,vll(maxdist));\n\n rep(i,C){\n ll r = R[i][0];\n ll j = 0;\n reps(d,1,maxdist){\n //dでのコストを計算\n Ccost[i][d] = Ccost[i][d-1]+r;\n if(j < P[i]-1 && Q[i][j] == d){\n //rの更新\n r = R[i][j+1];\n j++;\n }\n }\n }\n\n priority_queue<pll,vpll,greater<pll>> pq;\n vector<ll> dist(n,INF);\n dist[S] = 0;\n pq.push({0,S});\n\n while(!pq.empty()){\n auto [nowcost,now] = pq.top();\n pq.pop();\n if(dist[now] < nowcost)continue;\n //更新\n rep(i,C)if(!g[now][i].empty()){\n priority_queue<pll,vpll,greater<pll>> npq;\n vector<ll> ndist(n,INF);\n ndist[now] = 0;\n npq.push({0,now});\n while(!npq.empty()){\n auto [ncost,nnow] = npq.top();\n npq.pop();\n if(ndist[nnow] < ncost)continue;\n for(auto &[ny,nd]:g[nnow][i]){\n if(chmin(ndist[ny],ndist[nnow]+nd)){\n npq.push({ndist[ny],ny});\n }\n }\n }\n rep(j,n)if(ndist[j] != INF){\n if(chmin(dist[j],dist[now]+Ccost[i][ndist[j]])){\n pq.push({dist[j],j});\n }\n }\n }\n }\n if(dist[G] ==INF){\n cout << -1 << endl;\n }else{\n cout << dist[G] << endl;\n }\n\n}\n\n\n\nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true){\n LL(n,m,C,S,G);\n if(n == 0 && m == 0 && C == 0 && S == 0 && G == 0)break;\n solve(n,m,C,S,G);\n }\n\n\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 7148, "score_of_the_acc": -0.6428, "final_rank": 12 }, { "submission_id": "aoj_1182_10571798", "code_snippet": "#include <bits/extc++.h>\n \nusing namespace std;\n \n#define rep(i,n) for(int i=0;i<(n);++i)\n#define reps(i,n) for(int i=1;i<=(n);++i)\n#define all(x) begin(x),end(x)\n#define Fixed fixed << setprecision(12)\n#define updiv(a, b) (((a) + (b) - 1) / (b))\nusing pii = pair<int,int>;\nconstexpr int32_t INF = 0x3f3f3f3f;\nconstexpr int_fast64_t LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr int mod = 1e9+7;\n// constexpr int mod = 998244353;\n \ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n \n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n \ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n \ntemplate<class T, class U> istream& operator>>(istream& is, pair<T, U>& p){ is >> p.first >> p.second; return (is); }\ntemplate<class T, class U> ostream& operator<<(ostream& os, pair<T, U>& p){ os << p.first << ' ' << p.second; return (os); }\ntemplate<class T> istream& operator>>(istream& is, vector<T>& v){ for (auto &&e : v) is >> e; return (is); }\ntemplate<class T> ostream& operator<<(ostream& os, vector<T>& v){ for (auto &&e : v) os << e << ' '; return (os); }\n \ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n \ntemplate<typename A, typename B, typename F>\ninline bool compare(const A &a, const B &b, const F &f) {\n return lexicographical_compare(a.begin(), a.end(), b.begin(), b.end(), f);\n}\ntemplate<typename A, typename B>\ninline bool compare(const A &a, const B &b) {\n return lexicographical_compare(a.begin(), a.end(), b.begin(), b.end());\n}\n \ntemplate <class T> using max_heap = priority_queue<T>;\ntemplate <class T> using min_heap = priority_queue<T, vector<T>, greater<T> >;\ntemplate <class A, class B> using umap = unordered_map<A, B>;\ntemplate <class T> using uset = unordered_set<T>;\n \ntemplate <class T> using Set = __gnu_pbds::tree<T, __gnu_pbds::null_type, less<T>, __gnu_pbds::rb_tree_tag, __gnu_pbds::tree_order_statistics_node_update>;\n \ntemplate <class T> void bye(T x){ cout << x << '\\n'; exit(0); }\ninline int square(int a){ return (a * a); }\n \nconstexpr int dx[] = {1,0,-1,0,1,1,-1,-1};\nconstexpr int dy[] = {0,-1,0,1,1,-1,-1,1};\n\n#define ll int64_t\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout.setf(ios_base::fixed);\n cout.precision(12);\n\n int n, m, c, s, g;\n while (cin >> n >> m >> c >> s >> g, n) {\n --s, --g;\n vector<vector<tuple<int, int, int> > > graph(n);\n vector dist(c, vector(n, vector(n, (ll) INF)));\n vector cost(c, vector(10000 + 1, 0LL));\n\n for (int i = 0; i < m; ++i) {\n int x, y, d, ci;\n cin >> x >> y >> d >> ci;\n --x, --y, --ci;\n graph[x].emplace_back(y, d, ci);\n graph[y].emplace_back(x, d, ci);\n chmin(dist[ci][x][y], d);\n chmin(dist[ci][y][x], d);\n }\n\n vector<int> p(c);\n cin >> p;\n\n vector<vector<int> > q(c);\n vector<vector<int> > r(c);\n\n for (int i = 0; i < c; ++i) {\n q[i].resize(p[i] - 1);\n r[i].resize(p[i]);\n for (int j = 0; j < p[i] - 1; ++j) {\n cin >> q[i][j];\n }\n for (int j = 0; j < p[i]; ++j) {\n cin >> r[i][j];\n }\n\n int k = 0;\n for (int j = 1; j <= 10000; ++j) {\n cost[i][j] = cost[i][j - 1] + r[i][k];\n if (k < p[i] - 1 && q[i][k] == j) k++;\n }\n }\n\n for (int ci = 0; ci < c; ++ci) {\n for (int i = 0; i < n; ++i) {\n dist[ci][i][i] = 0;\n }\n\n for (int k = 0; k < n; ++k) {\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < n; ++j) {\n chmin(dist[ci][i][j], dist[ci][i][k] + dist[ci][k][j]);\n }\n }\n }\n }\n\n vector res(n, LINF);\n min_heap<pair<ll, int> > pq;\n\n res[s] = 0;\n pq.emplace(0, s);\n\n while (!pq.empty()) {\n auto [cur_cost, cur_node] = pq.top();\n pq.pop();\n if (res[cur_node] < cur_cost) continue;\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < c; ++j) {\n ll cc;\n ll di = dist[j][cur_node][i];\n if (di == INF) continue;\n if (di <= 10000) cc = cost[j][di];\n else cc = cost[j][10000] + (di - 10000) * r[j].back();\n if (chmin(res[i], res[cur_node] + cc)) {\n pq.emplace(res[i], i);\n }\n }\n }\n }\n\n // cerr << res << endl;\n\n cout << (res[g] == LINF ? -1 : res[g]) << '\\n';\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 6696, "score_of_the_acc": -0.6403, "final_rank": 11 }, { "submission_id": "aoj_1182_10571795", "code_snippet": "#include <bits/extc++.h>\n \nusing namespace std;\n \n#define rep(i,n) for(int i=0;i<(n);++i)\n#define reps(i,n) for(int i=1;i<=(n);++i)\n#define all(x) begin(x),end(x)\n#define Fixed fixed << setprecision(12)\n#define updiv(a, b) (((a) + (b) - 1) / (b))\nusing pii = pair<int,int>;\nconstexpr int32_t INF = 0x3f3f3f3f;\nconstexpr int_fast64_t LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr int mod = 1e9+7;\n// constexpr int mod = 998244353;\n \ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n \n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n \ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n \ntemplate<class T, class U> istream& operator>>(istream& is, pair<T, U>& p){ is >> p.first >> p.second; return (is); }\ntemplate<class T, class U> ostream& operator<<(ostream& os, pair<T, U>& p){ os << p.first << ' ' << p.second; return (os); }\ntemplate<class T> istream& operator>>(istream& is, vector<T>& v){ for (auto &&e : v) is >> e; return (is); }\ntemplate<class T> ostream& operator<<(ostream& os, vector<T>& v){ for (auto &&e : v) os << e << ' '; return (os); }\n \ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n \ntemplate<typename A, typename B, typename F>\ninline bool compare(const A &a, const B &b, const F &f) {\n return lexicographical_compare(a.begin(), a.end(), b.begin(), b.end(), f);\n}\ntemplate<typename A, typename B>\ninline bool compare(const A &a, const B &b) {\n return lexicographical_compare(a.begin(), a.end(), b.begin(), b.end());\n}\n \ntemplate <class T> using max_heap = priority_queue<T>;\ntemplate <class T> using min_heap = priority_queue<T, vector<T>, greater<T> >;\ntemplate <class A, class B> using umap = unordered_map<A, B>;\ntemplate <class T> using uset = unordered_set<T>;\n \ntemplate <class T> using Set = __gnu_pbds::tree<T, __gnu_pbds::null_type, less<T>, __gnu_pbds::rb_tree_tag, __gnu_pbds::tree_order_statistics_node_update>;\n \ntemplate <class T> void bye(T x){ cout << x << '\\n'; exit(0); }\ninline int square(int a){ return (a * a); }\n \nconstexpr int dx[] = {1,0,-1,0,1,1,-1,-1};\nconstexpr int dy[] = {0,-1,0,1,1,-1,-1,1};\n\n#define int ll\n#define ll int64_t\n\nsigned main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout.setf(ios_base::fixed);\n cout.precision(12);\n\n int n, m, c, s, g;\n while (cin >> n >> m >> c >> s >> g, n) {\n --s, --g;\n vector<vector<tuple<int, int, int> > > graph(n);\n vector dist(c, vector(n, vector(n, (ll) INF)));\n vector cost(c, vector(10000 + 1, 0LL));\n\n for (int i = 0; i < m; ++i) {\n int x, y, d, ci;\n cin >> x >> y >> d >> ci;\n --x, --y, --ci;\n graph[x].emplace_back(y, d, ci);\n graph[y].emplace_back(x, d, ci);\n chmin(dist[ci][x][y], d);\n chmin(dist[ci][y][x], d);\n }\n\n vector<int> p(c);\n cin >> p;\n\n vector<vector<int> > q(n);\n vector<vector<int> > r(n);\n\n for (int i = 0; i < c; ++i) {\n q[i].resize(p[i] - 1);\n r[i].resize(p[i]);\n for (int j = 0; j < p[i] - 1; ++j) {\n cin >> q[i][j];\n }\n for (int j = 0; j < p[i]; ++j) {\n cin >> r[i][j];\n }\n\n int k = 0;\n for (int j = 1; j <= 10000; ++j) {\n cost[i][j] = cost[i][j - 1] + r[i][k];\n if (k < p[i] - 1 && q[i][k] == j) k++;\n }\n }\n\n for (int ci = 0; ci < c; ++ci) {\n for (int i = 0; i < n; ++i) {\n dist[ci][i][i] = 0;\n }\n\n for (int k = 0; k < n; ++k) {\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < n; ++j) {\n chmin(dist[ci][i][j], dist[ci][i][k] + dist[ci][k][j]);\n }\n }\n }\n }\n\n vector res(n, LINF);\n min_heap<pair<ll, int> > pq;\n\n res[s] = 0;\n pq.emplace(0, s);\n\n while (!pq.empty()) {\n auto [cur_cost, cur_node] = pq.top();\n pq.pop();\n if (res[cur_node] < cur_cost) continue;\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < c; ++j) {\n ll cc;\n ll di = dist[j][cur_node][i];\n if (di == INF) continue;\n if (di <= 10000) cc = cost[j][di];\n else cc = cost[j][10000] + (di - 10000) * r[j].back();\n if (chmin(res[i], res[cur_node] + cc)) {\n pq.emplace(res[i], i);\n }\n }\n }\n }\n\n // cerr << res << endl;\n\n cout << (res[g] == LINF ? -1 : res[g]) << '\\n';\n }\n\n return 0;\n}", "accuracy": 0.5, "time_ms": 70, "memory_kb": 6820, "score_of_the_acc": -0.5689, "final_rank": 18 }, { "submission_id": "aoj_1182_10571790", "code_snippet": "#include <bits/extc++.h>\n \nusing namespace std;\n \n#define rep(i,n) for(int i=0;i<(n);++i)\n#define reps(i,n) for(int i=1;i<=(n);++i)\n#define all(x) begin(x),end(x)\n#define Fixed fixed << setprecision(12)\n#define updiv(a, b) (((a) + (b) - 1) / (b))\nusing pii = pair<int,int>;\nconstexpr int32_t INF = 0x3f3f3f3f;\nconstexpr int_fast64_t LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr int mod = 1e9+7;\n// constexpr int mod = 998244353;\n \ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n \n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n \ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n \ntemplate<class T, class U> istream& operator>>(istream& is, pair<T, U>& p){ is >> p.first >> p.second; return (is); }\ntemplate<class T, class U> ostream& operator<<(ostream& os, pair<T, U>& p){ os << p.first << ' ' << p.second; return (os); }\ntemplate<class T> istream& operator>>(istream& is, vector<T>& v){ for (auto &&e : v) is >> e; return (is); }\ntemplate<class T> ostream& operator<<(ostream& os, vector<T>& v){ for (auto &&e : v) os << e << ' '; return (os); }\n \ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n \ntemplate<typename A, typename B, typename F>\ninline bool compare(const A &a, const B &b, const F &f) {\n return lexicographical_compare(a.begin(), a.end(), b.begin(), b.end(), f);\n}\ntemplate<typename A, typename B>\ninline bool compare(const A &a, const B &b) {\n return lexicographical_compare(a.begin(), a.end(), b.begin(), b.end());\n}\n \ntemplate <class T> using max_heap = priority_queue<T>;\ntemplate <class T> using min_heap = priority_queue<T, vector<T>, greater<T> >;\ntemplate <class A, class B> using umap = unordered_map<A, B>;\ntemplate <class T> using uset = unordered_set<T>;\n \ntemplate <class T> using Set = __gnu_pbds::tree<T, __gnu_pbds::null_type, less<T>, __gnu_pbds::rb_tree_tag, __gnu_pbds::tree_order_statistics_node_update>;\n \ntemplate <class T> void bye(T x){ cout << x << '\\n'; exit(0); }\ninline int square(int a){ return (a * a); }\n \nconstexpr int dx[] = {1,0,-1,0,1,1,-1,-1};\nconstexpr int dy[] = {0,-1,0,1,1,-1,-1,1};\n\n#define ll int64_t\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout.setf(ios_base::fixed);\n cout.precision(12);\n\n int n, m, c, s, g;\n while (cin >> n >> m >> c >> s >> g, n) {\n --s, --g;\n vector<vector<tuple<int, int, int> > > graph(n);\n vector dist(c, vector(n, vector(n, (ll) INF)));\n vector cost(c, vector(10000 + 1, 0LL));\n\n for (int i = 0; i < m; ++i) {\n int x, y, d, ci;\n cin >> x >> y >> d >> ci;\n --x, --y, --ci;\n graph[x].emplace_back(y, d, ci);\n graph[y].emplace_back(x, d, ci);\n chmin(dist[ci][x][y], d);\n chmin(dist[ci][y][x], d);\n }\n\n vector<int> p(c);\n cin >> p;\n\n vector<vector<int> > q(n);\n vector<vector<int> > r(n);\n\n for (int i = 0; i < c; ++i) {\n q[i].resize(p[i] - 1);\n r[i].resize(p[i]);\n for (int j = 0; j < p[i] - 1; ++j) {\n cin >> q[i][j];\n }\n for (int j = 0; j < p[i]; ++j) {\n cin >> r[i][j];\n }\n\n int k = 0;\n for (int j = 1; j <= 10000; ++j) {\n cost[i][j] = cost[i][j - 1] + r[i][k];\n if (k < p[i] - 1 && q[i][k] == j) k++;\n }\n }\n\n for (int ci = 0; ci < c; ++ci) {\n for (int i = 0; i < n; ++i) {\n dist[ci][i][i] = 0;\n }\n\n for (int k = 0; k < n; ++k) {\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < n; ++j) {\n chmin(dist[ci][i][j], dist[ci][i][k] + dist[ci][k][j]);\n }\n }\n }\n }\n\n vector res(n, LINF);\n min_heap<pair<ll, int> > pq;\n\n res[s] = 0;\n pq.emplace(0, s);\n\n while (!pq.empty()) {\n auto [cur_cost, cur_node] = pq.top();\n pq.pop();\n if (res[cur_node] < cur_cost) continue;\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < c; ++j) {\n ll cc;\n ll di = dist[j][cur_node][i];\n if (di == INF) continue;\n if (di <= 10000) cc = cost[j][di];\n else cc = cost[j][10000] + (di - 10000) * r[j].back();\n if (cc < 0) return 0;\n if (chmin(res[i], res[cur_node] + cc)) {\n pq.emplace(res[i], i);\n }\n }\n }\n }\n\n // cerr << res << endl;\n\n cout << (res[g] == LINF ? -1 : res[g]) << '\\n';\n }\n\n return 0;\n}", "accuracy": 0.5, "time_ms": 90, "memory_kb": 6772, "score_of_the_acc": -0.6212, "final_rank": 19 }, { "submission_id": "aoj_1182_10571748", "code_snippet": "#include <bits/extc++.h>\n \nusing namespace std;\n \n#define rep(i,n) for(int i=0;i<(n);++i)\n#define reps(i,n) for(int i=1;i<=(n);++i)\n#define all(x) begin(x),end(x)\n#define Fixed fixed << setprecision(12)\n#define updiv(a, b) (((a) + (b) - 1) / (b))\nusing pii = pair<int,int>;\nconstexpr int32_t INF = 0x3f3f3f3f;\nconstexpr int_fast64_t LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr int mod = 1e9+7;\n// constexpr int mod = 998244353;\n \ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n \n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n \ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n \ntemplate<class T, class U> istream& operator>>(istream& is, pair<T, U>& p){ is >> p.first >> p.second; return (is); }\ntemplate<class T, class U> ostream& operator<<(ostream& os, pair<T, U>& p){ os << p.first << ' ' << p.second; return (os); }\ntemplate<class T> istream& operator>>(istream& is, vector<T>& v){ for (auto &&e : v) is >> e; return (is); }\ntemplate<class T> ostream& operator<<(ostream& os, vector<T>& v){ for (auto &&e : v) os << e << ' '; return (os); }\n \ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n \ntemplate<typename A, typename B, typename F>\ninline bool compare(const A &a, const B &b, const F &f) {\n return lexicographical_compare(a.begin(), a.end(), b.begin(), b.end(), f);\n}\ntemplate<typename A, typename B>\ninline bool compare(const A &a, const B &b) {\n return lexicographical_compare(a.begin(), a.end(), b.begin(), b.end());\n}\n \ntemplate <class T> using max_heap = priority_queue<T>;\ntemplate <class T> using min_heap = priority_queue<T, vector<T>, greater<T> >;\ntemplate <class A, class B> using umap = unordered_map<A, B>;\ntemplate <class T> using uset = unordered_set<T>;\n \ntemplate <class T> using Set = __gnu_pbds::tree<T, __gnu_pbds::null_type, less<T>, __gnu_pbds::rb_tree_tag, __gnu_pbds::tree_order_statistics_node_update>;\n \ntemplate <class T> void bye(T x){ cout << x << '\\n'; exit(0); }\ninline int square(int a){ return (a * a); }\n \nconstexpr int dx[] = {1,0,-1,0,1,1,-1,-1};\nconstexpr int dy[] = {0,-1,0,1,1,-1,-1,1};\n\n#define ll int64_t\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout.setf(ios_base::fixed);\n cout.precision(12);\n\n int n, m, c, s, g;\n while (cin >> n >> m >> c >> s >> g, n) {\n --s, --g;\n vector<vector<tuple<int, int, int> > > graph(n);\n vector dist(c, vector(n, vector(n, (ll) INF)));\n vector cost(c, vector(10000 + 1, 0LL));\n\n for (int i = 0; i < m; ++i) {\n int x, y, d, ci;\n cin >> x >> y >> d >> ci;\n --x, --y, --ci;\n graph[x].emplace_back(y, d, ci);\n graph[y].emplace_back(x, d, ci);\n chmin(dist[ci][x][y], d);\n chmin(dist[ci][y][x], d);\n }\n\n vector<int> p(c);\n cin >> p;\n\n vector<vector<int> > q(n);\n vector<vector<int> > r(n);\n\n for (int i = 0; i < c; ++i) {\n q[i].resize(p[i] - 1);\n r[i].resize(p[i]);\n for (int j = 0; j < p[i] - 1; ++j) {\n cin >> q[i][j];\n }\n for (int j = 0; j < p[i]; ++j) {\n cin >> r[i][j];\n }\n\n int k = 0;\n for (int j = 1; j <= 10000; ++j) {\n cost[i][j] = cost[i][j - 1] + r[i][k];\n if (k < p[i] - 1 && q[i][k] == j) k++;\n }\n }\n\n for (int ci = 0; ci < c; ++ci) {\n for (int i = 0; i < n; ++i) {\n dist[ci][i][i] = 0;\n }\n\n for (int k = 0; k < n; ++k) {\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < n; ++j) {\n chmin(dist[ci][i][j], dist[ci][i][k] + dist[ci][k][j]);\n }\n }\n }\n }\n\n vector res(n, LINF);\n min_heap<pair<ll, int> > pq;\n\n res[s] = 0;\n pq.emplace(0, s);\n\n while (!pq.empty()) {\n auto [cur_cost, cur_node] = pq.top();\n pq.pop();\n if (res[cur_node] < cur_cost) continue;\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < c; ++j) {\n ll cc;\n ll di = dist[j][cur_node][i];\n if (di == INF) continue;\n if (di <= 10000) cc = cost[j][di];\n else cc = cost[j][10000] + (di - 10000) * r[j].back();\n if (chmin(res[i], res[cur_node] + cc)) {\n pq.emplace(res[i], i);\n }\n }\n }\n }\n\n // cerr << res << endl;\n\n cout << (res[g] == LINF ? -1 : res[g]) << '\\n';\n }\n\n return 0;\n}", "accuracy": 0.5, "time_ms": 100, "memory_kb": 6620, "score_of_the_acc": -0.63, "final_rank": 20 }, { "submission_id": "aoj_1182_10509168", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\nusing vi = vector<int>;\nusing vll = vector<ll>;\nusing vvi = vector<vi>;\nusing vvll = vector<vll>;\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n#define FOR(i, a, b) for(ll i = a; i < (ll)(b); i++)\n#define all(a) (a).begin(),(a).end()\nconstexpr int INF = 1001001001;\nconstexpr ll LINF = 1001001001001001001ll;\nconstexpr int DX[] = {1, 0, -1, 0};\nconstexpr int DY[] = {0, 1, 0, -1};\n\nstruct Edge{\n int to, d, c;\n Edge(int to, int d, int c): to(to), d(d), c(c){}\n};\nbool solve(){\n int n, m, c, s, t;\n cin >> n >> m >> c >> s >> t;\n s--;t--;\n if(n == 0) return false;\n vector<vector<Edge>> g(n);\n rep(i, m){\n int x, y, d, cpy;\n cin >> x >> y >> d >> cpy;\n x--;y--;\n cpy--;\n g[x].emplace_back(y, d, cpy);\n g[y].emplace_back(x, d, cpy);\n }\n vector<int> p(c);\n rep(i, c){\n cin >> p[i];\n }\n vector<vector<pair<int, int>>> qr(c);\n rep(i, c){\n qr[i].resize(p[i]+1, {INF, INF});\n qr[i][0].first = 0;\n rep(j, p[i]-1){\n cin >> qr[i][j+1].first;\n }\n rep(j, p[i]){\n cin >> qr[i][j].second;\n }\n }\n rep(i, c){\n cout << \"company' \" << i << endl;\n rep(j, p[i]){\n cout << qr[i][j].first << \" \" << qr[i][j].second << endl;\n }\n cout << endl;\n }\n // cost, v, d, id_d, c\n using pqInfo = pair<pair<int, int>, pair<pair<int, int>, int>>;\n priority_queue<pqInfo, vector<pqInfo>, greater<pqInfo>> que;\n const int MAX_DIST = 10005;\n vector<vector<vector<int>>> cost(n, vector<vector<int>>(c, vector<int>(MAX_DIST, INF)));\n cost[s][0][0] = 0;\n que.push({{0, s}, {{0, 0}, 0}});\n while(!que.empty()){\n auto [costv, dc] = que.top();\n cout << costv.second << \" \" << dc.first.first << \" \" << dc.second << \" \" << costv.first << endl;\n que.pop();\n if(costv.second == t){\n cout << costv.first << endl;\n return true;\n }\n int v = costv.second;\n for(Edge e : g[costv.second]){\n if(e.c == dc.second){\n int ncost = costv.first;\n int nd = dc.first.first + e.d;\n int di = dc.first.second;\n int d = dc.first.first;\n while(qr[dc.second][di+1].first <= nd){\n ncost += qr[dc.second][di].second*(qr[dc.second][di+1].first - d);\n d = qr[dc.second][di+1].first;\n di++;\n }\n ncost += qr[dc.second][di].second*(nd - d);\n if(cost[v][dc.second][min(nd, MAX_DIST-1)] > ncost){\n cost[v][dc.second][min(nd, MAX_DIST-1)] = ncost;\n que.push({{ncost, e.to}, {{min(nd, MAX_DIST-1), di}, dc.second}});\n }\n }\n else{\n int ncost = costv.first;\n int nd = e.d;\n int di = 0;\n int d = 0;\n while(qr[e.c][di+1].first <= nd){\n ncost += qr[e.c][di].second*(qr[e.c][di+1].first - d);\n d = qr[e.c][di+1].first;\n di++;\n }\n ncost += qr[e.c][di].second*(nd - d);\n if(cost[v][e.c][min(nd, MAX_DIST-1)] > ncost){\n cost[v][e.c][min(nd, MAX_DIST-1)] = ncost;\n que.push({{ncost, e.to}, {{min(nd, MAX_DIST-1), di}, e.c}});\n }\n }\n }\n }\n cout << -1 << endl;\n return true;\n}\n\nvector<vector<int>> warshall_floyd(int n, vector<vector<Edge>> es){\n vector<vector<int>> dist(n, vector<int>(n, INF));\n rep(i, n){\n for(Edge e : es[i]){\n dist[i][e.to] = min(dist[i][e.to], e.d);\n }\n }\n rep(k, n){\n rep(i, n){\n rep(j, n){\n dist[i][j] = min(dist[i][j], dist[i][k] + dist[k][j]);\n }\n }\n }\n return dist;\n}\nbool solve2(){\n int n, m, c, s, t;\n cin >> n >> m >> c >> s >> t;\n s--;t--;\n if(n == 0) return false;\n vector<vector<vector<Edge>>> g(c, vector<vector<Edge>>(n));\n rep(i, m){\n int x, y, d, cpy;\n cin >> x >> y >> d >> cpy;\n x--;y--;\n cpy--;\n g[cpy][x].emplace_back(y, d, cpy);\n g[cpy][y].emplace_back(x, d, cpy);\n }\n vector<int> p(c);\n rep(i, c){\n cin >> p[i];\n }\n vector<vector<pair<int, int>>> qr(c);\n rep(i, c){\n qr[i].resize(p[i]+1, {INF, INF});\n qr[i][0].first = 0;\n rep(j, p[i]-1){\n cin >> qr[i][j+1].first;\n }\n rep(j, p[i]){\n cin >> qr[i][j].second;\n }\n }\n vector<vvi> dists(c);\n rep(i, c){\n dists[i] = warshall_floyd(n, g[i]);\n }\n vvi cost(n, vi(n, INF));\n auto get_cost = [&](int cpy, int distance) -> int{\n int di = 0;\n int nowd = 0;\n int ret = 0;\n while(qr[cpy][di+1].first <= distance){\n ret += qr[cpy][di].second*(qr[cpy][di+1].first - nowd);\n nowd = qr[cpy][di+1].first;\n di++;\n }\n ret += qr[cpy][di].second*(distance - nowd);\n return ret;\n };\n rep(k, c){\n rep(i, n){\n rep(j, n){\n if(dists[k][i][j] == INF) continue;\n cost[i][j] = min(cost[i][j], get_cost(k, dists[k][i][j]));\n }\n }\n }\n rep(k, n){\n rep(i, n){\n rep(j, n){\n cost[i][j] = min(cost[i][j], cost[i][k] + cost[k][j]);\n }\n }\n }\n cout << (cost[s][t] == INF ? -1 : cost[s][t]) << endl;\n return true;\n}\nint main(){\n bool con = true;\n while(con){\n con = solve2();\n }\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 4604, "score_of_the_acc": -0.2975, "final_rank": 4 }, { "submission_id": "aoj_1182_10411157", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int INF = 1e9;\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n while(true){\n int n, m, c, s, g;\n cin >> n >> m >> c >> s >> g;\n if(n==0 && m==0 && c==0 && s==0 && g==0) break;\n s--; g--;\n\n // 1) 各社ごとに距離行列を初期化\n vector<vector<vector<int>>> dist(c,\n vector<vector<int>>(n, vector<int>(n, INF)));\n for(int j=0;j<c;j++){\n for(int i=0;i<n;i++) dist[j][i][i] = 0;\n }\n\n // 1-2) 路線情報読み込み → 各社ごとの距離行列に格納\n for(int i=0;i<m;i++){\n int x,y,d,ci;\n cin >> x >> y >> d >> ci;\n x--; y--; ci--;\n dist[ci][x][y] = min(dist[ci][x][y], d);\n dist[ci][y][x] = min(dist[ci][y][x], d);\n }\n\n // 2) 各社ごとに Floyd-Warshall で全点対間最短距離を計算\n for(int j=0;j<c;j++){\n for(int k=0;k<n;k++){\n for(int i=0;i<n;i++){\n if(dist[j][i][k]==INF) continue;\n for(int l=0;l<n;l++){\n if(dist[j][k][l]==INF) continue;\n dist[j][i][l] = min(dist[j][i][l],\n dist[j][i][k] + dist[j][k][l]);\n }\n }\n }\n }\n\n // 3) 各社の運賃テーブルを読み込み(距離ごとの料金)\n vector<int> p(c); // 運賃段階の数\n for(int j=0;j<c;j++) cin >> p[j];\n vector<vector<int>> q(c), r(c); // q: 各段階の距離, r: 各段階の単価\n for(int j=0;j<c;j++){\n q[j].resize(max(0, p[j]-1));\n for(int k=0;k<p[j]-1;k++) cin >> q[j][k];\n r[j].resize(p[j]);\n for(int k=0;k<p[j]; k++) cin >> r[j][k];\n }\n\n // 4) 運賃計算関数(会社 j, 距離 z → 運賃)\n auto calcFare = [&](int j, int z){\n int fare = 0, prevQ = 0;\n for(int k=0;k<p[j] && z>0; k++){\n int limit = (k < p[j]-1 ? q[j][k] - prevQ : z);\n int use = min(limit, z);\n fare += use * r[j][k];\n z -= use;\n prevQ += use;\n }\n return fare;\n };\n\n // 5) 完全グラフ上に隣接リストを作成(各社の路線に対して運賃付きで辺を作成)\n vector<vector<pair<int,int>>> adj(n);\n for(int j=0;j<c;j++){\n for(int u=0;u<n;u++){\n for(int v=0;v<n;v++){\n if(u!=v && dist[j][u][v]<INF){\n int f = calcFare(j, dist[j][u][v]);\n adj[u].emplace_back(v, f);\n }\n }\n }\n }\n\n // 6) Dijkstra 法で最小運賃を求める\n vector<int> cost(n, INF);\n priority_queue<pair<int,int>,\n vector<pair<int,int>>, greater<>> pq;\n cost[s] = 0;\n pq.emplace(0, s);\n\n while(!pq.empty()){\n auto [cst, u] = pq.top(); pq.pop();\n if(cst > cost[u]) continue;\n if(u == g) break;\n for(auto [v, w] : adj[u]){\n if(cost[v] > cst + w){\n cost[v] = cst + w;\n pq.emplace(cost[v], v);\n }\n }\n }\n\n // 7) 最終的な答えを出力\n cout << (cost[g]==INF ? -1 : cost[g]) << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5732, "score_of_the_acc": -0.3036, "final_rank": 5 }, { "submission_id": "aoj_1182_10410982", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int INF = 1e9;\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n while(true){\n int n, m, c, s, g;\n cin >> n >> m >> c >> s >> g;\n if(n==0 && m==0 && c==0 && s==0 && g==0) break;\n s--; g--;\n\n // 1) 各社ごとに距離行列を初期化\n vector<vector<vector<int>>> dist(c,\n vector<vector<int>>(n, vector<int>(n, INF)));\n for(int j=0;j<c;j++){\n for(int i=0;i<n;i++) dist[j][i][i] = 0;\n }\n // 路線情報読み込み\n for(int i=0;i<m;i++){\n int x,y,d,ci;\n cin >> x >> y >> d >> ci;\n x--; y--; ci--;\n dist[ci][x][y] = min(dist[ci][x][y], d);\n dist[ci][y][x] = min(dist[ci][y][x], d);\n }\n\n // 2) Floyd–Warshall で各社の全点対間最短距離\n for(int j=0;j<c;j++){\n for(int k=0;k<n;k++){\n for(int i=0;i<n;i++){\n if(dist[j][i][k]==INF) continue;\n for(int l=0;l<n;l++){\n if(dist[j][k][l]==INF) continue;\n dist[j][i][l] = min(dist[j][i][l],\n dist[j][i][k] + dist[j][k][l]);\n }\n }\n }\n }\n\n // 3) 各社の運賃テーブル読み込み\n vector<int> p(c);\n for(int j=0;j<c;j++) cin >> p[j];\n vector<vector<int>> q(c), r(c);\n for(int j=0;j<c;j++){\n q[j].resize(max(0, p[j]-1));\n for(int k=0;k<p[j]-1;k++) cin >> q[j][k];\n r[j].resize(p[j]);\n for(int k=0;k<p[j]; k++) cin >> r[j][k];\n }\n\n // 4) 運賃計算関数(会社 j, 距離 z → fare)\n auto calcFare = [&](int j, int z){\n int fare = 0, prevQ = 0;\n for(int k=0;k<p[j] && z>0; k++){\n int limit = (k < p[j]-1 ? q[j][k] - prevQ : z);\n int use = min(limit, z);\n fare += use * r[j][k];\n z -= use;\n prevQ += use;\n }\n return fare;\n };\n\n // 5) 完全グラフ上の隣接リスト作成\n vector<vector<pair<int,int>>> adj(n);\n for(int j=0;j<c;j++){\n for(int u=0;u<n;u++){\n for(int v=0;v<n;v++){\n if(u!=v && dist[j][u][v]<INF){\n int f = calcFare(j, dist[j][u][v]);\n adj[u].emplace_back(v, f);\n }\n }\n }\n }\n\n // 6) Dijkstra で最小運賃\n vector<int> cost(n, INF);\n priority_queue<pair<int,int>,\n vector<pair<int,int>>, greater<>> pq;\n cost[s] = 0;\n pq.emplace(0, s);\n\n while(!pq.empty()){\n auto [cst, u] = pq.top(); pq.pop();\n if(cst > cost[u]) continue;\n if(u == g) break;\n for(auto [v, w] : adj[u]){\n if(cost[v] > cst + w){\n cost[v] = cst + w;\n pq.emplace(cost[v], v);\n }\n }\n }\n\n cout << (cost[g]==INF ? -1 : cost[g]) << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5884, "score_of_the_acc": -0.3242, "final_rank": 6 }, { "submission_id": "aoj_1182_10406917", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nconst ll INF = (1LL<<60);\n\nstruct FareTable {\n vector<int> q; // 分割点 q_1 … q_{p-1}\n vector<int> r; // 単価 r_1 … r_p\n ll operator()(int dist) const {\n if (dist==0) return 0;\n ll cost = 0;\n int prev = 0;\n int seg = 0;\n while (dist > 0) {\n int lim = (seg < (int)q.size() ? q[seg] : INT_MAX);\n int len = min(dist, lim - prev);\n cost += 1LL * len * r[seg];\n dist -= len;\n prev += len;\n if (prev == lim) ++seg; // 次の区間へ\n }\n return cost;\n }\n};\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n while (true) {\n int n,m,c,s,g; // 入力ヘッダ\n if(!(cin>>n>>m>>c>>s>>g)) return 0;\n if(n==0) break;\n --s; --g; // 0-index\n struct Edge{int u,v,d,comp;};\n vector<Edge> edges(m);\n for(auto& e:edges){\n cin>>e.u>>e.v>>e.d>>e.comp;\n --e.u; --e.v; --e.comp;\n }\n vector<int> p(c);\n for(int& v:p) cin>>v;\n\n vector<FareTable> fare(c);\n for(int j=0;j<c;++j){\n int pj=p[j];\n fare[j].q.resize(max(0,pj-1));\n for(int k=0;k<pj-1;++k) cin>>fare[j].q[k];\n fare[j].r.resize(pj);\n for(int k=0;k<pj;++k) cin>>fare[j].r[k];\n }\n\n /* --- 会社ごとの最短距離 --- */\n vector<vector<vector<int>>> dist(c,\n vector<vector<int>>(n, vector<int>(n, 1e9)));\n\n for(int j=0;j<c;++j)\n for(int i=0;i<n;++i) dist[j][i][i]=0;\n\n for(auto e:edges){\n dist[e.comp][e.u][e.v]=\n dist[e.comp][e.v][e.u]=\n min(dist[e.comp][e.u][e.v], e.d);\n }\n for(int j=0;j<c;++j){\n for(int k=0;k<n;++k)\n for(int i=0;i<n;++i){\n if(dist[j][i][k]==1e9) continue;\n for(int v=0;v<n;++v){\n dist[j][i][v]=min(dist[j][i][v],\n dist[j][i][k]+dist[j][k][v]);\n }\n }\n }\n\n /* --- メタグラフのコスト行列 --- */\n vector<vector<ll>> meta(n, vector<ll>(n, INF));\n for(int j=0;j<c;++j){\n for(int u=0;u<n;++u)\n for(int v=0;v<n;++v){\n int d = dist[j][u][v];\n if(d==1e9) continue;\n ll cost = fare[j](d);\n meta[u][v] = min(meta[u][v], cost);\n }\n }\n\n /* --- Dijkstra --- */\n vector<ll> d(n, INF);\n d[s]=0;\n priority_queue<pair<ll,int>,vector<pair<ll,int>>,\n greater<pair<ll,int>>> pq;\n pq.emplace(0,s);\n while(!pq.empty()){\n auto [du,u]=pq.top(); pq.pop();\n if(du!=d[u]) continue;\n if(u==g) break;\n for(int v=0;v<n;++v){\n if(meta[u][v]==INF) continue;\n ll nd = du + meta[u][v];\n if(nd<d[v]){\n d[v]=nd;\n pq.emplace(nd,v);\n }\n }\n }\n cout<<(d[g]==INF?-1:d[g])<<\"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4436, "score_of_the_acc": -0.0983, "final_rank": 2 }, { "submission_id": "aoj_1182_10388153", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\n/*\n * 1. 各会社ごとにワーシャルフロイドで最短距離を計算\n * 2. 運賃表をもとに各会社の距離→運賃を求める関数を作っておく\n * 3. 得られた距離に対して、運賃を計算して、新たな辺を追加\n * 4. 作ったグラフに対してダイクストラで答えを求める\n */\n\nconst ll INF = 4e18;\nusing edge = tuple<int, ll, int>;\n\nvoid warshall_floyd(vector<vector<ll>>& d, int n)\n{\n for (int k = 0; k < n; k++) {\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n d[i][j] = min(d[i][j], d[i][k] + d[k][j]);\n }\n }\n }\n}\n\nvoid solve(int N, int M, int C, int S, int G)\n{\n vector<vector<edge>> E(N);\n vector c_dist(C, vector<vector<ll>>(N, vector<ll>(N, INF)));\n for (int i = 0; i < M; i++) {\n int x, y, c;\n ll d;\n cin >> x >> y >> d >> c, x--, y--, c--;\n\n c_dist[c][x][y] = min(c_dist[c][x][y], d);\n c_dist[c][y][x] = min(c_dist[c][x][y], d);\n }\n\n vector<int> P(C);\n vector<vector<ll>> Q(C), R(C);\n for (auto& p: P) { cin >> p; }\n for (int c = 0; c < C; c++) {\n Q[c].resize(P[c] - 1);\n R[c].resize(P[c]);\n for (int i = 0; i < P[c] - 1; i++) cin >> Q[c][i];\n for (int i = 0; i < P[c]; i++) cin >> R[c][i];\n }\n\n vector<vector<ll>> pref(C);\n for (int c = 0; c < C; c++) {\n if (P[c] <= 1) continue;\n pref[c].resize(P[c] - 1);\n pref[c][0] = Q[c][0] * R[c][0];\n for (int i = 1; i < P[c] - 1; i++) {\n ll len = Q[c][i] - Q[c][i - 1];\n pref[c][i] = pref[c][i - 1] + len * R[c][i];\n }\n }\n\n // 会社ごとにワーシャルフロイド\n for (int c = 0; c < C; c++) { warshall_floyd(c_dist[c], N); }\n\n auto calc_cost = [&](int c, ll d) {\n if (d == INF) return INF;\n auto it = upper_bound(Q[c].begin(), Q[c].end(), d);\n int seg = it - Q[c].begin();\n ll prev_cost = seg > 0 ? pref[c][seg - 1] : 0;\n ll prev_dist = seg > 0 ? Q[c][seg - 1] : 0;\n return prev_cost + (d - prev_dist) * R[c][seg];\n };\n\n // グラフに新たな辺を追加\n for (int c = 0; c < C; c++) {\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (c_dist[c][i][j] == INF) continue;\n ll cost = calc_cost(c, c_dist[c][i][j]);\n E[i].emplace_back(j, cost, c);\n }\n }\n }\n\n // // ダイクストラで答えを求める\n vector<ll> dist(N, INF);\n priority_queue<pair<ll, int>, vector<pair<ll, int>>, greater<>> pq;\n dist[S] = 0;\n pq.emplace(0, S);\n while (!pq.empty()) {\n auto [cost, u] = pq.top();\n pq.pop();\n if (dist[u] < cost) continue;\n for (auto& [v, w, c]: E[u]) {\n if (dist[v] > cost + w) {\n dist[v] = cost + w;\n pq.emplace(dist[v], v);\n }\n }\n }\n\n cout << (dist[G] == INF ? -1 : dist[G]) << endl;\n}\n\nint main()\n{\n while (true) {\n int N, M, C, S, G;\n cin >> N >> M >> C >> S >> G, S--, G--;\n if (N == 0) break;\n solve(N, M, C, S, G);\n }\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 10336, "score_of_the_acc": -1.0755, "final_rank": 15 }, { "submission_id": "aoj_1182_10388059", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nconst ll INF = (ll)4e18;\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n while (true) {\n int N, M, C, s, g;\n cin >> N >> M >> C >> s >> g;\n if (!cin || N == 0) break;\n s--; g--;\n\n // 1) Read edges and build per-company distance matrix\n vector<vector<vector<ll>>> dist(C, vector<vector<ll>>(N, vector<ll>(N, INF)));\n for (int j = 0; j < C; j++) {\n for (int i = 0; i < N; i++) dist[j][i][i] = 0;\n }\n for (int i = 0; i < M; i++) {\n int x, y, d, c;\n cin >> x >> y >> d >> c;\n x--; y--; c--;\n dist[c][x][y] = min(dist[c][x][y], (ll)d);\n dist[c][y][x] = min(dist[c][y][x], (ll)d);\n }\n\n // Floyd-Warshall per company\n for (int j = 0; j < C; j++) {\n for (int k = 0; k < N; k++)\n for (int i = 0; i < N; i++) if (dist[j][i][k] < INF)\n for (int l = 0; l < N; l++) {\n ll nd = dist[j][i][k] + dist[j][k][l];\n if (nd < dist[j][i][l]) dist[j][i][l] = nd;\n }\n }\n\n // 2) Read fare tables for each company\n vector<int> p(C);\n for (int j = 0; j < C; j++) cin >> p[j];\n\n vector<vector<int>> q(C), r(C);\n for (int j = 0; j < C; j++) {\n if (p[j] > 1) {\n q[j].resize(p[j] - 1);\n for (int k = 0; k < p[j] - 1; k++) cin >> q[j][k];\n }\n r[j].resize(p[j]);\n for (int k = 0; k < p[j]; k++) cin >> r[j][k];\n }\n\n // Precompute prefix costs up to each breakpoint\n vector<vector<ll>> prefix(C);\n for (int j = 0; j < C; j++) {\n if (p[j] <= 1) continue;\n prefix[j].resize(p[j] - 1);\n // cost up to q[j][0]\n prefix[j][0] = (ll)q[j][0] * r[j][0];\n for (int k = 1; k < p[j] - 1; k++) {\n ll len = q[j][k] - q[j][k - 1];\n prefix[j][k] = prefix[j][k - 1] + len * r[j][k];\n }\n }\n\n // fare function: cost for distance z on company j\n auto fare = [&](int j, ll z) {\n if (z <= 0) return 0LL;\n int seg = 0;\n if (!q[j].empty()) {\n // find first q[j][seg] >= z\n auto it = upper_bound(q[j].begin(), q[j].end(), (int)z);\n seg = it - q[j].begin();\n }\n ll prev_cost = 0;\n ll prev_dist = 0;\n if (seg > 0) {\n prev_cost = prefix[j][seg - 1];\n prev_dist = q[j][seg - 1];\n }\n return prev_cost + (z - prev_dist) * r[j][seg];\n };\n\n // 3) Build meta-graph edges: from u to v with cost via company j\n vector<vector<pair<int,ll>>> metaE(N);\n for (int j = 0; j < C; j++) {\n for (int u = 0; u < N; u++) {\n for (int v = 0; v < N; v++) {\n if (u == v) continue;\n ll d = dist[j][u][v];\n if (d < INF) {\n ll cst = fare(j, d);\n metaE[u].emplace_back(v, cst);\n }\n }\n }\n }\n\n // 4) Dijkstra on meta-graph from s to g\n vector<ll> dmeta(N, INF);\n dmeta[s] = 0;\n priority_queue<pair<ll,int>, vector<pair<ll,int>>, greater<>> pq;\n pq.emplace(0, s);\n\n while (!pq.empty()) {\n auto [cd, u] = pq.top(); pq.pop();\n if (cd > dmeta[u]) continue;\n if (u == g) break;\n for (auto& [v, w] : metaE[u]) {\n ll nd = cd + w;\n if (nd < dmeta[v]) {\n dmeta[v] = nd;\n pq.emplace(nd, v);\n }\n }\n }\n\n ll ans = dmeta[g];\n if (ans >= INF/2) cout << -1 << \"\\n\";\n else cout << ans << \"\\n\";\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 8404, "score_of_the_acc": -0.6662, "final_rank": 13 }, { "submission_id": "aoj_1182_10144810", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define pi pair<int, int>\n#define fi first\n#define se second\n#define pb push_back\nconst int N = 100, M = 10000, MAX_EDGE = 200, MAX_COMPANIES = 20, INF = 1e9;\npi edges[M];\nvector<pi> vec[N];\nint cost_of_flight[MAX_COMPANIES][MAX_EDGE * N];\nint real_cost[N][N];\nint dist[N][N];\nsigned main() {\n cin.tie(0); ios_base::sync_with_stdio(0);\n int n, m, c, s, g;\n while (cin >> n >> m >> c >> s >> g) {\n// cerr << n << ' ' << m << \" \" << c << \" \" << s << \" \" << g << endl;\n if (n == 0 && m == 0 && c == 0 && s == 0 && g == 0) break;\n s--; g--;\n for (int i = 0; i < n; ++i) vec[i].clear();\n for (int i = 0; i < m; ++i) {\n int x, y, c, d;\n cin >> x >> y >> d >> c;\n c--;\n x--; y--;\n edges[i] = {c, d};\n vec[x].pb({y, i});\n vec[y].pb({x, i});\n }\n vector<int> section_number(c);\n for (int company = 0; company < c; ++company) cin >> section_number[company];\n for (int company = 0; company < c; ++company) {\n vector<int> q, r;\n for (int j = 0; j < section_number[company] - 1; ++j) {\n int x;\n cin >> x;\n q.pb(x);\n }\n for (int j = 0; j < section_number[company]; ++j) {\n int x;\n cin >> x;\n r.pb(x);\n }\n int current_index = 0;\n for (int distance = 1; distance < MAX_EDGE * N; ++distance) {\n if (current_index < q.size() && distance > q[current_index]) ++current_index;\n cost_of_flight[company][distance] = cost_of_flight[company][distance - 1] + r[current_index];\n }\n }\n for (int i = 0; i < n; ++i) for (int j = 0; j < n; ++j) real_cost[i][j] = INF;\n for (int company = 0; company < c; ++company) {\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < n; ++j) dist[i][j] = i == j ? 0 : INF;\n }\n for (int v = 0; v < n; ++v) {\n for (auto [u, edge]: vec[v]) {\n auto [new_company, length] = edges[edge];\n if (new_company != company) continue;\n dist[v][u] = min(dist[v][u], length);\n }\n }\n for (int k = 0; k < n; ++k) {\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < n; ++j) {\n dist[i][j] = min(dist[i][j], dist[i][k] + dist[k][j]);\n }\n }\n }\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < n; ++j) {\n if (dist[i][j] == INF) continue;\n real_cost[i][j] = min(real_cost[i][j], cost_of_flight[company][dist[i][j]]);\n }\n }\n }\n vector<int> result(n, INF), used(n, 0);\n result[s] = 0;\n while (1) {\n pi minimum = {INF, INF};\n for (int i = 0; i < n; ++i) {\n if (used[i]) continue;\n minimum = min(minimum, pi{result[i], i});\n }\n if (minimum.fi == INF) break;\n int v = minimum.se;\n used[v] = 1;\n for (int u = 0; u < n; ++u) {\n result[u] = min(result[u], result[v] + real_cost[v][u]);\n }\n }\n cout << (result[g] == INF ? -1 : result[g]) << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 5324, "score_of_the_acc": -0.4247, "final_rank": 8 } ]
aoj_1186_cpp
Integral Rectangles Let us consider rectangles whose height, h , and width, w , are both integers. We call such rectangles integral rectangles . In this problem, we consider only wide integral rectangles, i.e., those with w > h . We define the following ordering of wide integral rectangles. Given two wide integral rectangles, The one shorter in its diagonal line is smaller, and If the two have diagonal lines with the same length, the one shorter in its height is smaller. Given a wide integral rectangle, find the smallest wide integral rectangle bigger than the given one. Input The entire input consists of multiple datasets. The number of datasets is no more than 100. Each dataset describes a wide integral rectangle by specifying its height and width, namely h and w , separated by a space in a line, as follows. h w For each dataset, h and w (> h ) are both integers greater than 0 and no more than 100. The end of the input is indicated by a line of two zeros separated by a space. Output For each dataset, print in a line two numbers describing the height and width, namely h and w (> h ), of the smallest wide integral rectangle bigger than the one described in the dataset. Put a space between the numbers. No other characters are allowed in the output. For any wide integral rectangle given in the input, the width and height of the smallest wide integral rectangle bigger than the given one are both known to be not greater than 150. In addition, although the ordering of wide integral rectangles uses the comparison of lengths of diagonal lines, this comparison can be replaced with that of squares (self-products) of lengths of diagonal lines, which can avoid unnecessary troubles possibly caused by the use of floating-point numbers. Sample Input 1 2 1 3 2 3 1 4 2 4 5 6 1 8 4 7 98 100 99 100 0 0 Output for the Sample Input 1 3 2 3 1 4 2 4 3 4 1 8 4 7 2 8 3 140 89 109
[ { "submission_id": "aoj_1186_9327994", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\nusing namespace std;\nbool solve()\n{\n int H,W;\n cin>>H>>W;\n if(H==0&&W==0)return 0;\n vector<pair<int,int>>bigger;\n auto comp=[](pair<int,int>p,pair<int,int>q)\n {\n auto[ph,pw]=p;\n auto[qh,qw]=q;\n return ph*ph+pw*pw==qh*qh+qw*qw?ph<qh:ph*ph+pw*pw<qh*qh+qw*qw;\n };\n for(int h=1;h<=200;h++)for(int w=h+1;w<=200;w++)\n {\n if(comp(make_pair(H,W),make_pair(h,w)))bigger.push_back(make_pair(h,w));\n }\n sort(bigger.begin(),bigger.end(),comp);\n cout<<bigger[0].first<<' '<<bigger[0].second<<'\\n';\n return 1;\n}\nint main(){while(solve()){}}", "accuracy": 1, "time_ms": 90, "memory_kb": 3540, "score_of_the_acc": -0.4359, "final_rank": 15 }, { "submission_id": "aoj_1186_9303251", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n int h,w;\n int size=0;\n pair<int,pair<int,int> > rect[30000];\n for(int i=1;i<=150;i++){\n\t\tfor(int j=i+1;j<=150;j++){\n rect[size++]=make_pair(i*i+j*j,make_pair(i,j));\n }\n }\n while(1){\n cin>>h>>w;\n if(h==0&&w==0)break;\n \n sort(rect,rect+size);\n pair<int,pair<int,int> >q=make_pair(h*h+w*w,make_pair(h,w));\n pair<int,pair<int,int> >r=*upper_bound(rect,rect+size,q);\n cout<<r.second.first<<\" \"<<r.second.second<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3440, "score_of_the_acc": -0.0714, "final_rank": 3 }, { "submission_id": "aoj_1186_9303101", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n while(true){\n int h,w;\n cin >> h >> w;\n if(h==0&&w==0){\n break;\n }\n\n vector<tuple<double,int,int>>vec(0);\n for(int i=1;i<150;i++){\n for(int j=i+1;j<=150;j++){\n double len = sqrt(i*i+j*j);\n int tate=i;\n int yoko=j;\n vec.push_back({len,i,j});\n }\n }\n\n sort(vec.begin(),vec.end());\n for(int i=0;i<vec.size();i++){\n if(get<1>(vec[i])==h&&get<2>(vec[i])==w){\n cout << get<1>(vec[i+1]) << \" \" << get<2>(vec[i+1]) << endl;\n break;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3440, "score_of_the_acc": -0.2453, "final_rank": 12 }, { "submission_id": "aoj_1186_6780939", "code_snippet": "// #include \"atcoder/all\"\n#include <iostream> // cout, endl, cin\n#include <string> // string, to_string, stoi\n#include <vector> // vector\n#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound\n#include <utility> // pair, make_pair\n#include <tuple> // tuple, make_tuple\n#include <cstdint> // int64_t, int*_t\n#include <cstdio> // printf\n#include <map> // map\n#include <queue> // queue, priority_queue\n#include <set> // set\n#include <stack> // stack\n#include <deque> // deque\n#include <unordered_map> // unordered_map\n#include <unordered_set> // unordered_set\n#include <bitset> // bitset\n#include <cctype> // isupper, islower, isdigit, toupper, tolower\n#include <iomanip> // setprecision\n#include <complex> // complex\n#include <math.h>\n#include <functional>\n#include <cassert>\nusing namespace std;\n// using namespace atcoder;\nusing ll = long long;\nusing P = pair<ll,ll>;\nconstexpr ll INF = 1e18;\nconstexpr ll LLMAX = 9223372036854775807;\nconstexpr int inf = 1e9;\n// constexpr ll mod = 1000000007;\nconstexpr ll mod = 998244353;\n// 右下左上\nconst int dx[8] = {1, 0, -1, 0,1,1,-1,-1};\nconst int dy[8] = {0, 1, 0, -1,1,-1,1,-1};\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\nll gcd(ll a,ll b){if(b==0){return a;}else{return gcd(b,a%b);}};\n#define eb emplace_back\n#define pb pop_back\n#define eol endl\n// ---------------------------------------------------------------------------\n\nbool solve(){\n ll h,w;\n cin >> h >> w;\n if(h==0 && w==0) return false;\n ll res = h*h+w*w;\n ll mn = INF;\n P ans = P(INF,INF);\n for(ll i=1; i<500; i++){\n for(ll j=i+1; j<500; j++){\n if(i*i+j*j < res) continue;\n if(i*i+j*j > res){\n if(mn > i*i+j*j){\n mn = i*i+j*j;\n ans = P(i,j);\n }else if(mn == i*i+j*j){\n chmin(ans,P(i,j));\n }\n }else{\n if(i > h){\n if(mn > res){\n mn = res;\n ans = P(i,j);\n }else{\n chmin(ans,P(i,j));\n }\n }\n }\n }\n }\n cout << ans.first << \" \" << ans.second << endl;\n return true;\n}\n\nint main(){\n while(solve());\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3340, "score_of_the_acc": -0.0547, "final_rank": 2 }, { "submission_id": "aoj_1186_6780415", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint h, w;\n\nvoid solve(){\n int taikaku = h*h+w*w;\n int ans = 100000000;\n int ansH = 100000000;\n int ansW;\n for(int H = 1000; H >= 1; H--){\n for(int W = H+1; W <= 1000; W++){\n if(H == h && W == w) continue;\n if((H*H+W*W) >= taikaku && ans >= (H*H+W*W)){\n if((H*H+W*W) == taikaku){\n if(H < h) continue;\n }\n ans = H*H+W*W;\n ansH = H; ansW = W;\n }\n }\n }\n cout << ansH << \" \" << ansW << endl;\n}\nint main(){\n while(1){\n cin >> h >> w;\n if(h == 0 && w == 0) break;\n else solve();\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3068, "score_of_the_acc": -0.0963, "final_rank": 4 }, { "submission_id": "aoj_1186_6515518", "code_snippet": "#line 2 \"library/KowerKoint/base.hpp\"\n\n#ifndef ONLINE_JUDGE\n#define _GLIBCXX_DEBUG\n#endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define REP(i, n) for(int i = 0; i < (int)(n); i++)\n#define FOR(i, a, b) for(ll i = a; i < (ll)(b); i++)\n#define ALL(a) (a).begin(),(a).end()\n#define END(...) { print(__VA_ARGS__); return; }\n\nusing VI = vector<int>;\nusing VVI = vector<VI>;\nusing VVVI = vector<VVI>;\nusing ll = long long;\nusing VL = vector<ll>;\nusing VVL = vector<VL>;\nusing VVVL = vector<VVL>;\nusing VD = vector<double>;\nusing VVD = vector<VD>;\nusing VVVD = vector<VVD>;\nusing VS = vector<string>;\nusing VVS = vector<VS>;\nusing VVVS = vector<VVS>;\nusing VC = vector<char>;\nusing VVC = vector<VC>;\nusing VVVC = vector<VVC>;\nusing P = pair<int, int>;\nusing VP = vector<P>;\nusing VVP = vector<VP>;\nusing VVVP = vector<VVP>;\nusing LP = pair<ll, ll>;\nusing VLP = vector<LP>;\nusing VVLP = vector<VLP>;\nusing VVVLP = vector<VVLP>;\n\ntemplate <typename T>\nusing PQ = priority_queue<T>;\ntemplate <typename T>\nusing GPQ = priority_queue<T, vector<T>, greater<T>>;\n\nconstexpr int INF = 1001001001;\nconstexpr ll LINF = 1001001001001001001ll;\nconstexpr int DX[] = {1, 0, -1, 0};\nconstexpr int DY[] = {0, 1, 0, -1};\n\nvoid print() { cout << '\\n'; }\ntemplate<typename T>\nvoid print(const T &t) { cout << t << '\\n'; }\ntemplate<typename Head, typename... Tail>\nvoid print(const Head &head, const Tail &... tail) {\n cout << head << ' ';\n print(tail...);\n}\n\n#ifdef ONLINE_JUDGE\ntemplate<typename... Args>\nvoid dbg(const Args &... args) {}\n#else\nvoid dbg() { cerr << '\\n'; }\ntemplate<typename T>\nvoid dbg(const T &t) { cerr << t << '\\n'; }\ntemplate<typename Head, typename... Tail>\nvoid dbg(const Head &head, const Tail &... tail) {\n cerr << head << ' ';\n dbg(tail...);\n}\n#endif\n\ntemplate< typename T1, typename T2 >\nostream &operator<<(ostream &os, const pair< T1, T2 >& p) {\n os << p.first << \" \" << p.second;\n return os;\n}\n\ntemplate< typename T1, typename T2 >\nistream &operator>>(istream &is, pair< T1, T2 > &p) {\n is >> p.first >> p.second;\n return is;\n}\n\ntemplate< typename T >\nostream &operator<<(ostream &os, const vector< T > &v) {\n for(int i = 0; i < (int) v.size(); i++) {\n os << v[i] << (i + 1 != (int) v.size() ? \" \" : \"\");\n }\n return os;\n}\n\ntemplate< typename T >\nistream &operator>>(istream &is, vector< T > &v) {\n for(T &in : v) is >> in;\n return is;\n}\n\ntemplate<typename T>\nvector<vector<T>> split(typename vector<T>::const_iterator begin, typename vector<T>::const_iterator end, T val) {\n vector<vector<T>> res;\n vector<T> cur;\n for(auto it = begin; it != end; it++) {\n if(*it == val) {\n res.push_back(cur);\n cur.clear();\n } else cur.push_back(val);\n }\n res.push_back(cur);\n return res;\n}\n\nvector<string> split(typename string::const_iterator begin, typename string::const_iterator end, char val) {\n vector<string> res;\n string cur = \"\";\n for(auto it = begin; it != end; it++) {\n if(*it == val) {\n res.push_back(cur);\n cur.clear();\n } else cur.push_back(val);\n }\n res.push_back(cur);\n return res;\n}\n\ntemplate< typename T1, typename T2 >\ninline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\n\ntemplate< typename T1, typename T2 >\ninline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\ntemplate <typename T>\npair<VI, vector<T>> compress(const vector<T> &a) {\n int n = a.size();\n vector<T> x;\n REP(i, n) x.push_back(a[i]);\n sort(ALL(x)); x.erase(unique(ALL(x)), x.end());\n VI res(n);\n REP(i, n) res[i] = lower_bound(ALL(x), a[i]) - x.begin();\n return make_pair(res, x);\n}\n\ntemplate <typename T>\npair<vector<T>, vector<T>> factorial(int n) {\n vector<T> res(n+1), rev(n+1);\n res[0] = 1;\n REP(i, n) res[i+1] = res[i] * (i+1);\n rev[n] = 1 / res[n];\n for(int i = n; i > 0; i--) {\n rev[i-1] = rev[i] * i;\n }\n return make_pair(res, rev);\n}\n#line 2 \"Contests/Dummy/main.cpp\"\n\n/* #include <atcoder/all> */\n/* using namespace atcoder; */\n/* #include \"KowerKoint/expansion/ac-library/all.hpp\" */\n#line 1 \"library/ei1333/math/number-theory/prime-table.cpp\"\n/**\n * @brief Prime Table(素数テーブル)\n * @docs docs/prime-table.md\n */\nvector< bool > prime_table(int n) {\n vector< bool > prime(n + 1, true);\n if(n >= 0) prime[0] = false;\n if(n >= 1) prime[1] = false;\n for(int i = 2; i * i <= n; i++) {\n if(!prime[i]) continue;\n for(int j = i * i; j <= n; j += i) {\n prime[j] = false;\n }\n }\n return prime;\n}\n#line 7 \"Contests/Dummy/main.cpp\"\n\nbool solve(){\n VP v;\n FOR(i, 1, 150) FOR(j, i+1, 151) v.emplace_back(i, j);\n auto comp = [](const P& l, const P& r) {\n int dl = l.first*l.first + l.second*l.second;\n int dr = r.first*r.first + r.second*r.second;\n if(dl == dr) return l.first < r.first;\n return dl < dr;\n };\n sort(ALL(v), comp);\n while(1) {\n int h, w; cin >> h >> w;\n if(!h) break;\n print(*upper_bound(ALL(v), P(h, w), comp));\n }\n return false;\n}\n\n// generated by oj-template v4.7.2 (https://github.com/online-judge-tools/template-generator)\nint main() {\n // Fasterize input/output script\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(100);\n // scanf/printf user should delete this fasterize input/output script\n\n int t = 1;\n //cin >> t; // comment out if solving multi testcase\n for(int testCase = 1;testCase <= t;++testCase){\n while(solve());\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3560, "score_of_the_acc": -0.1349, "final_rank": 5 }, { "submission_id": "aoj_1186_6030184", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long LL;\ntypedef long double LD;\n\n#define rep(i, n) for (LL i = 0; i < (n); i++)\n\nint main()\n{\n \n while(1)\n {\n int h_limit = 150, w_limit = 150;\n int h, w; cin >> h >> w;\n\n if(!h && !w)\n break;\n \n\n vector<tuple<int,int,int>> data;\n\n for(int i=1; i<=h_limit+ 10; i++){\n\n for(int j=1; j<=w_limit + 10; j++){\n if(j > i)\n data.push_back(make_tuple(i*i+j*j,i,j));\n }\n\n }\n\n sort(data.begin(),data.end());\n\n int pos = -1;\n int diagonal = h * h + w * w;\n\n rep(i,data.size()){\n if(get<0>(data.at(i)) == diagonal && get<1>(data.at(i) )== h && get<2>(data.at(i)) == w ){\n pos = i + 1;\n break;\n }\n }\n \n //cout << \"pos:\" << pos << endl;\n //break;\n\n cout << get<1>(data.at(pos)) << \" \" << get<2>(data.at(pos)) << endl;\n\n }\n \n \n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3472, "score_of_the_acc": -0.2506, "final_rank": 13 }, { "submission_id": "aoj_1186_6016773", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing PLL = std::pair<ll, ll>;\n#define rep(i,n) for(ll i=0; i<(n); i++)\n#define all(x) (x).begin(), (x).end()\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n\n\nint main() {\n while(true){\n ll h, w; cin >> h >> w;\n if(h == 0 && w == 0) break;\n ll t = h*h+w*w;\n vector<tuple<ll, ll, ll>> v;\n \n for(ll H=1; H<=200; H++){\n for(ll W=1; W<200; W++){\n if(W>H) v.emplace_back(H*H+W*W, H, W);\n }\n }\n sort(all(v));\n ll ac = v.size(), wa = -1;\n // while(abs(ac-wa)>1){\n // ll mid = (ac+wa)/2;\n // auto [a, b, c] = v[mid];\n // if(a>t || (a==t && b>h)) ac=mid;\n // else wa = mid;\n // }\n // auto [A, B, C] = v[ac];\n // cout << B << \" \" << C << \"\\n\";\n for(auto [a, b, c] : v){\n if(a>t){\n cout << b << \" \" << c << \"\\n\";\n break;\n }else if(a == t && b>h){\n cout << b << \" \" << c << \"\\n\";\n break;\n }\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 4292, "score_of_the_acc": -0.6048, "final_rank": 17 }, { "submission_id": "aoj_1186_6016752", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing PLL = std::pair<ll, ll>;\n#define rep(i,n) for(ll i=0; i<(n); i++)\n#define all(x) (x).begin(), (x).end()\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n\n\nint main() {\n while(true){\n ll h, w; cin >> h >> w;\n if(h == 0 && w == 0) break;\n ll t = h*h+w*w;\n vector<tuple<ll, ll, ll>> v;\n \n for(ll H=1; H<=200; H++){\n for(ll W=1; W<200; W++){\n if(W>H) v.emplace_back(H*H+W*W, H, W);\n }\n }\n sort(all(v));\n ll ac = v.size(), wa = -1;\n while(abs(ac-wa)>1){\n ll mid = (ac+wa)/2;\n auto [a, b, c] = v[mid];\n if(a>t || (a==t && b>h)) ac=mid;\n else wa = mid;\n }\n auto [A, B, C] = v[ac];\n cout << B << \" \" << C << \"\\n\";\n // for(auto [a, b, c] : v){\n // if(a>t){\n // cout << b << \" \" << c << \"\\n\";\n // break;\n // }else if(a == t && b>h){\n // cout << b << \" \" << c << \"\\n\";\n // break;\n // }\n // }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 4428, "score_of_the_acc": -0.584, "final_rank": 16 }, { "submission_id": "aoj_1186_6016688", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nstruct P{\n int h;\n int w;\n\n P(int h, int w): h(h), w(w){}\n \n int l() const {\n return this->h * this->h + this->w * this->w;\n }\n\n bool operator<(const P &other) const {\n if(l() == other.l()) return this->h < other.h;\n else return l() < other.l();\n }\n};\n\nint main(){\n\n vector<P> d;\n for(int i = 1; i < 1000; i++){\n for(int j = i+1; j < 1000; j++){\n d.push_back(P(i, j));\n }\n }\n\n // cerr << d[2].h << \" \" << d[2].w << endl;\n\n sort(d.begin(), d.end());\n\n while(true){\n int h, w;\n cin >> h >> w;\n if(!h && !w) break;\n P c(h, w);\n int ac = d.size();\n int wa = -1;\n while(ac-wa > 1){\n int wj = (ac+wa)/2;\n if(c < d[wj]) ac = wj;\n else wa = wj;\n }\n cout << d[ac].h << \" \" << d[ac].w << '\\n';\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 9008, "score_of_the_acc": -1.087, "final_rank": 20 }, { "submission_id": "aoj_1186_5998873", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i=0; i<(n); i++)\n#define INF ((1LL<<62)-(1LL<<31))\n#define all(a) (a).begin(),(a).end()\n#define rall(a) (a).rbegin(),(a).rend()\ntypedef long long ll;\ntypedef pair<ll,ll> pl;\n\nint main() {\n while(true) {\n int h,w;\n cin >> h >> w;\n if((h|w)==0) break;\n ll dist=h*h+w*w;\n vector<pair<int,pair<int,int>>> ans;\n for(int i=1;i<=150;i++) {\n for(int j=i+1;j<=150;j++) {\n ll tot=i*i+j*j;\n if(dist<tot) ans.push_back({tot,{i,j}});\n else if(dist==tot&&h<i) ans.push_back({tot,{i,j}}); \n }\n } \n sort(all(ans));\n cout << ans[0].second.first << \" \" << ans[0].second.second << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3552, "score_of_the_acc": -0.177, "final_rank": 9 }, { "submission_id": "aoj_1186_5512024", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main() {\n int h, w;\n while(cin >> h >> w, h) {\n int cnt=h*h+w*w;\n vector<tuple<int, int, int>> mini;\n for(int i=1; i<=150; i++) {\n for(int j=i+1; j<=151; j++) {\n if(cnt<i*i+j*j) {\n mini.push_back(make_tuple(i*i+j*j, i, j));\n }\n else if(cnt==i*i+j*j&&h<i) {\n mini.push_back(make_tuple(i*i+j*j, i, j));\n }\n }\n }\n sort(mini.begin(), mini.end());\n cout << get<1>(mini[0]) << ' ' << get<2>(mini[0]) << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3576, "score_of_the_acc": -0.181, "final_rank": 10 }, { "submission_id": "aoj_1186_5512022", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main() {\n while(true) {\n int h, w;\n cin >> h >> w;\n if(h==0) return 0;\n int cnt=h*h+w*w;\n vector<tuple<int, int, int>> mini;\n for(int i=1; i<=150; i++) {\n for(int j=i+1; j<=151; j++) {\n if(cnt<i*i+j*j) {\n mini.push_back(make_tuple(i*i+j*j, i, j));\n }\n else if(cnt==i*i+j*j&&h<i) {\n mini.push_back(make_tuple(i*i+j*j, i, j));\n }\n }\n }\n sort(mini.begin(), mini.end());\n cout << get<1>(mini[0]) << ' ' << get<2>(mini[0]) << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3504, "score_of_the_acc": -0.169, "final_rank": 7 }, { "submission_id": "aoj_1186_5049372", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<queue>\n#include<iomanip>\n#include <string>\n#include <math.h>\nusing namespace std;\nint main(){\n long long int h,w,n=0,a=0,b=0;\n cin>>h;\n while(h!=0){\n a=0;\n b=0;\n cin>>w;\n n=h*h+w*w;\n for(int i=n;a==0&&b==0;i++){\n for(int j=1;(2*j*j)<(i)&&a==0;j++){\n for(int k=1;k<=(i-j*j);k++){\n if(k*k==i-j*j){\n if(i==n&&j>h){\n a=k;\n b=j;\n break;\n }\n else if(i!=n){\n a=k;\n b=j;\n break;\n }\n }\n }\n }\n }\n cout<<b<<' '<<a<<endl;\n cin>>h;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3012, "score_of_the_acc": -0.1739, "final_rank": 8 }, { "submission_id": "aoj_1186_4982607", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> P;\n\n#define eps 1e-9\n#define INF 2000000000 // 2e9\n#define LLINF 2000000000000000000ll // 2e18 (llmax:9e18)\n#define all(x) (x).begin(), (x).end()\n#define sq(x) ((x) * (x))\n\n#ifndef LOCAL\n#define dmp(...) ;\n#else\n#define dmp(...) \\\n cerr << \"[ \" << #__VA_ARGS__ << \" ] : \" << dump_str(__VA_ARGS__) << endl\n#endif\n\n// ---------------- Utility ------------------\n\ntemplate <class T>\nbool chmin(T &a, const T &b) {\n if (a <= b) return false;\n a = b;\n return true;\n}\ntemplate <class T>\nbool chmax(T &a, const T &b) {\n if (a >= b) return false;\n a = b;\n return true;\n}\n\ntemplate <class T>\nusing MaxHeap = priority_queue<T>;\ntemplate <class T>\nusing MinHeap = priority_queue<T, vector<T>, greater<T>>;\n\ntemplate <class T>\nvector<T> vect(int len, T elem) {\n return vector<T>(len, elem);\n}\n\n// ----------------- Input -------------------\n\ntemplate <class T, class U>\nistream &operator>>(istream &is, pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\n\ntemplate <class T>\nistream &operator>>(istream &is, vector<T> &vec) {\n for (int i = 0; i < vec.size(); i++) is >> vec[i];\n return is;\n}\n\n// ----------------- Output ------------------\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n return os << p.first << ',' << p.second;\n}\n\ntemplate <class T>\nostream &operator<<(ostream &os, const vector<T> &v) {\n for (const T &e : v) os << e << \" \";\n return os;\n}\n\ntemplate <class T>\nostream &operator<<(ostream &os, const deque<T> &d) {\n for (const T &e : d) os << e << \" \";\n return os;\n}\n\ntemplate <class T>\nostream &operator<<(ostream &os, const set<T> &s) {\n os << \"{ \";\n for (const T &e : s) os << e << \" \";\n return os << \"}\";\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const map<T, U> &m) {\n os << \"{ \";\n for (const auto &[key, val] : m) os << \"( \" << key << \" -> \" << val << \" ) \";\n return os << \"}\";\n}\n\nvoid dump_str_rec(ostringstream &) {}\n\ntemplate <class Head, class... Tail>\nvoid dump_str_rec(ostringstream &oss, Head &&head, Tail &&... tail) {\n oss << \", \" << head;\n dump_str_rec(oss, forward<Tail>(tail)...);\n}\n\ntemplate <class T, class... U>\nstring dump_str(T &&arg, U &&... args) {\n ostringstream oss;\n oss << arg;\n dump_str_rec(oss, forward<U>(args)...);\n return oss.str();\n}\n\n// --------------- Fast I/O ------------------\n\nvoid fastio() {\n cin.tie(0);\n ios::sync_with_stdio(0);\n cout << fixed << setprecision(20);\n}\n\n// ------------ End of template --------------\n\n#define endl \"\\n\"\n\nbool comp(P a, P b) {\n if (sq(a.first) + sq(a.second) == sq(b.first) + sq(b.second))\n return a.first < b.first;\n return sq(a.first) + sq(a.second) < sq(b.first) + sq(b.second);\n}\n\nbool solve() {\n int h, w;\n cin >> h >> w;\n if (h == 0 && w == 0) return false;\n P a(1000, 1000);\n for (int i = 1; i < 1000; i++) {\n for (int j = i + 1; j < 1000; j++) {\n if (!comp(P(h, w), P(i, j))) continue;\n if (comp(P(i, j), a)) a = P(i, j);\n }\n }\n cout << a.first << ' ' << a.second << endl;\n return true;\n}\n\nint main() {\n fastio();\n // solve();\n while (solve()) {}\n // int t; cin >> t; while(t--)solve();\n\n // int t; cin >> t;\n // for(int i=1;i<=t;i++){\n // cout << \"Case #\" << i << \": \";\n // solve();\n // }\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3140, "score_of_the_acc": -0.4127, "final_rank": 14 }, { "submission_id": "aoj_1186_4963455", "code_snippet": "//#include <tourist>\n#include <bits/stdc++.h>\n//#include <atcoder/all>\nusing namespace std;\n//using namespace atcoder;\ntypedef long long ll;\ntypedef unsigned int uint;\ntypedef unsigned long long ull;\ntypedef pair<ll, ll> p;\nconst int INF = 1e9;\nconst double eps = 1e-7;\nconst ll LINF = ll(1e18);\nconst int MOD = 1000000007;\nconst int dx[4] = {0, 1, 0, -1}, dy[4] = {-1, 0, 1, 0};\nconst int Dx[8] = {0, 1, 1, 1, 0, -1, -1, -1}, Dy[8] = {-1, -1, 0, 1, 1, 1, 0, -1};\n#define yes cout << \"Yes\" << endl\n#define YES cout << \"YES\" << endl\n#define no cout << \"No\" << endl\n#define NO cout << \"NO\" << endl\n#define rep(i, n) for (int i = 0; i < n; i++)\n#define ALL(v) v.begin(), v.end()\n#define debug(v) \\\n cout << #v << \":\"; \\\n for (auto x : v) \\\n { \\\n cout << x << ' '; \\\n } \\\n cout << endl;\ntemplate <class T>\nbool chmax(T &a, const T &b)\n{\n if (a < b)\n {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <class T>\nbool chmin(T &a, const T &b)\n{\n if (b < a)\n {\n a = b;\n return 1;\n }\n return 0;\n}\n//cout<<fixed<<setprecision(15);有効数字15桁\n//-std=c++14\n//g++ yarudake.cpp -std=c++17 -I .\nll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; }\nll lcm(ll a, ll b) { return a / gcd(a, b) * b; }\n\nint main()\n{\n cin.tie(0);\n ios::sync_with_stdio(false);\n vector<int> ansx,ansy;\n while(true){\n int x,y;\n cin>>x>>y;\n int l=x*x+y*y;\n int lw=INF;\n if(l==0)break;\n int resx,resy;\n for(int i=1;i<=500;i++){\n for(int j=i+1;j<=500;j++){\n int ltemp=i*i+j*j;\n if(ltemp>l&&ltemp<lw){\n lw=ltemp;\n resx=i;\n resy=j;\n }\n if (ltemp == l && ltemp < lw&&x<i){\n lw = ltemp;\n resx = i;\n resy = j;\n }\n }\n }\n ansx.push_back(resx);\n ansy.push_back(resy);\n }\n rep(i,ansx.size()){\n cout<<ansx[i]<<\" \"<<ansy[i]<<\"\\n\";\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3096, "score_of_the_acc": -0.014, "final_rank": 1 }, { "submission_id": "aoj_1186_4959421", "code_snippet": "#pragma GCC target (\"avx2\")\n#pragma GCC optimize (\"unroll-loops\")\n#pragma GCC optimize (\"O3\")\n#include \"bits/stdc++.h\"\n#include <unordered_set>\n#include <unordered_map>\n#include <random>\nusing namespace std;\ntypedef long long ll;\n#define pb push_back\n#define mp make_pair\n#define all(x) x.begin(), x.end()\n#define rep(i, n) for(int (i)=0; (i)<(n); (i)++)\n\npair<int, int> P(int h, int w){\n\treturn mp(h*h+w*w, h);\n}\n\nsigned main(){\n\twhile(true){\n\t\tint h, w;\n\t\tcin >> h >> w;\n\t\tif(h == 0) return 0;\n\t\tint ansH = 1000, ansW = 1000;\n\t\tfor(int i=1; i<=1000; i++){\n\t\t\tfor(int j=i+1; j<=1000; j++){\n\t\t\t\tif(P(h, w) < P(i, j) && P(i, j) <= P(ansH, ansW)){\n\t\t\t\t\tansH = i;\n\t\t\t\t\tansW = j;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << ansH << \" \" << ansW << endl;\n\t}\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3364, "score_of_the_acc": -0.1891, "final_rank": 11 }, { "submission_id": "aoj_1186_4957186", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i, n) for (int i = 0; i < (n); i++)\n\nint main() {\n while (1) {\n int h, w;\n cin >> h >> w;\n if (h == 0 && w == 0) return 0;\n int hoge = h * h + w * w;\n vector<pair<int, int>> ans;\n for (int iw = 1; iw < 151;iw++){\n for (int ih = 1; ih < iw;ih++){\n int piyo = iw * iw + ih * ih;\n if(hoge <= piyo){\n if (iw == w && ih == h) continue;\n if (hoge == piyo && ih < h) continue;\n ans.push_back(pair<int, int>(piyo, ih));\n }\n }\n }\n sort(ans.begin(), ans.end());\n int ww = (ans[0].first - ans[0].second * ans[0].second);\n int i;\n for (i = 1; i < 151; i++) {\n if (i * i == ww) break;\n }\n cout << ans[0].second << \" \" << i << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3340, "score_of_the_acc": -0.1417, "final_rank": 6 }, { "submission_id": "aoj_1186_4943546", "code_snippet": "# include <bits/stdc++.h>\nusing namespace std;\n\nstruct Rect {\n Rect() = default;\n Rect(int _h, int _w) : h(_h), w(_w) {}\n int diagonal2() const { return h*h + w*w; }\n int h, w;\n};\n\nbool operator <(const Rect& a, const Rect& b) {\n if (a.diagonal2() == b.diagonal2()) return a.h < b.h;\n return a.diagonal2() < b.diagonal2();\n}\n\nbool operator >(const Rect& a, const Rect& b) {\n if (a.diagonal2() == b.diagonal2()) return a.h > b.h;\n return a.diagonal2() > b.diagonal2();\n}\n\nvoid Main(const int H, const int W) {\n Rect input(H, W);\n Rect ans(5000, 5000);\n for (int h = 1; h < 1000; ++h) {\n for (int w = h + 1; w < 1000; ++w) {\n Rect rect(h, w);\n if (rect > input) {\n ans = min(ans, rect);\n }\n }\n }\n cout << ans.h << \" \" << ans.w << endl;\n}\n\nint main() {\n while (true) {\n int h, w;\n cin >> h >> w;\n if (!(h | w)) break;\n Main(h, w);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3084, "score_of_the_acc": -0.7511, "final_rank": 18 }, { "submission_id": "aoj_1186_4943531", "code_snippet": "# include <bits/stdc++.h>\n# define int long long\nusing namespace std;\n\nstruct Rect {\n Rect() = default;\n Rect(int _h, int _w) : h(_h), w(_w) {}\n int h, w;\n};\n\nbool operator <(const Rect& a, const Rect& b) {\n int A2 = a.h * a.h + a.w * a.w;\n int B2 = b.h * b.h + b.w * b.w;\n if (A2 == B2) {\n return a.h < b.h;\n }\n return A2 < B2;\n}\n\nbool operator >(const Rect& a, const Rect& b) {\n int A2 = a.h * a.h + a.w * a.w;\n int B2 = b.h * b.h + b.w * b.w;\n if (A2 == B2) {\n return a.h > b.h;\n }\n return A2 > B2;\n}\n\nvoid Main(const int H, const int W) {\n Rect input(H, W);\n Rect ans(100000, 100000);\n for (int h = 1; h < 1000; ++h) {\n for (int w = h + 1; w < 1000; ++w) {\n Rect rect(h, w);\n if (rect > input) {\n ans = min(ans, rect);\n }\n }\n }\n cout << ans.h << \" \" << ans.w << endl;\n}\n\nint32_t main() {\n while (true) {\n int h, w;\n cin >> h >> w;\n if (!(h | w)) break;\n Main(h, w);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3076, "score_of_the_acc": -1.0107, "final_rank": 19 } ]
aoj_1188_cpp
Hierarchical Democracy The presidential election in Republic of Democratia is carried out through multiple stages as follows. There are exactly two presidential candidates. At the first stage, eligible voters go to the polls of his/her electoral district. The winner of the district is the candidate who takes a majority of the votes. Voters cast their ballots only at this first stage. A district of the k -th stage ( k > 1) consists of multiple districts of the ( k − 1)-th stage. In contrast, a district of the ( k − 1)-th stage is a sub-district of one and only one district of the k -th stage. The winner of a district of the k -th stage is the candidate who wins in a majority of its sub-districts of the ( k − 1)-th stage. The final stage has just one nation-wide district. The winner of the final stage is chosen as the president. You can assume the following about the presidential election of this country. Every eligible voter casts a vote. The number of the eligible voters of each electoral district of the first stage is odd. The number of the sub-districts of the ( k − 1)-th stage that constitute a district of the k -th stage ( k > 1) is also odd. This means that each district of every stage has its winner (there is no tie). Your mission is to write a program that finds a way to win the presidential election with the minimum number of votes. Suppose, for instance, that the district of the final stage has three sub-districts of the first stage and that the numbers of the eligible voters of the sub-districts are 123, 4567, and 89, respectively. The minimum number of votes required to be the winner is 107, that is, 62 from the first district and 45 from the third. In this case, even if the other candidate were given all the 4567 votes in the second district, s/he would inevitably be the loser. Although you might consider this election system unfair, you should accept it as a reality. Input The entire input looks like: the number of datasets (=n) 1st dataset 2nd dataset … n-th dataset The number of datasets, n , is no more than 100. The number of the eligible voters of each district and the part-whole relations among districts are denoted as follows. An electoral district of the first stage is denoted as [ c ], where c is the number of the eligible voters of the district. A district of the k -th stage ( k > 1) is denoted as [ d 1 d 2 … d m ], where d 1 , d 2 , …, d m denote its sub-districts of the ( k − 1)-th stage in this notation. For instance, an electoral district of the first stage that has 123 eligible voters is denoted as [123]. A district of the second stage consisting of three sub-districts of the first stage that have 123, 4567, and 89 eligible voters, respectively, is denoted as [[123][4567][89]]. Each dataset is a line that contains the character string denoting the district of the final stage in the aforementioned notation. You can assume the following. The character string in each dataset does not include any characters except digits ( ...(truncated)
[ { "submission_id": "aoj_1188_10851154", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <algorithm>\n#include <string>\n#include <vector>\n#include <numeric>\n#define sz(x) int((x).size())\n#define all(x) (x).begin(), (x).end()\n#define phb push_back\nusing namespace std;\n\nint Z;\nstring str;\n\nvoid solve();\n\nint dfs(int, int);\n\nint main() {\n cin >> Z;\n for (int zi = 1; zi <= Z; ++zi) {\n cin >> str;\n solve();\n }\n\n return 0;\n}\n\nvoid solve() {\n cout << dfs(0, sz(str)) << \"\\n\";\n}\n\nint dfs(int l, int r) {\n ++l, --r;\n\n if (str[l] != '[') {\n istringstream iss(str.substr(l, r - l));\n int k;\n\n iss >> k;\n return (k + 1) / 2;\n }\n else {\n vector< int > vi;\n int cnt = 0, pre = l;\n\n for (int i = l; i < r; ++i) {\n if (str[i] == '[')\n ++cnt;\n else if (str[i] == ']') {\n --cnt;\n if (cnt == 0)\n vi.phb(dfs(pre, i + 1)), pre = i + 1;\n }\n }\n\n stable_sort(all(vi));\n return accumulate(vi.begin(), vi.begin() + (sz(vi) + 1) / 2, 0);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3448, "score_of_the_acc": -0.0451, "final_rank": 8 }, { "submission_id": "aoj_1188_9379471", "code_snippet": "#include <utility>\n\nnamespace atcoder {\n\nnamespace internal {\n\nconstexpr long long safe_mod(long long x, long long m) {\n x %= m;\n if (x < 0) x += m;\n return x;\n}\n\nstruct barrett {\n unsigned int _m;\n unsigned long long im;\n\n barrett(unsigned int m) : _m(m), im((unsigned long long)(-1) / m + 1) {}\n\n unsigned int umod() const { return _m; }\n\n unsigned int mul(unsigned int a, unsigned int b) const {\n\n unsigned long long z = a;\n z *= b;\n#ifdef _MSC_VER\n unsigned long long x;\n _umul128(z, im, &x);\n#else\n unsigned long long x =\n (unsigned long long)(((unsigned __int128)(z)*im) >> 64);\n#endif\n unsigned int v = (unsigned int)(z - x * _m);\n if (_m <= v) v += _m;\n return v;\n }\n};\n\nconstexpr long long pow_mod_constexpr(long long x, long long n, int m) {\n if (m == 1) return 0;\n unsigned int _m = (unsigned int)(m);\n unsigned long long r = 1;\n unsigned long long y = safe_mod(x, m);\n while (n) {\n if (n & 1) r = (r * y) % _m;\n y = (y * y) % _m;\n n >>= 1;\n }\n return r;\n}\n\nconstexpr bool is_prime_constexpr(int n) {\n if (n <= 1) return false;\n if (n == 2 || n == 7 || n == 61) return true;\n if (n % 2 == 0) return false;\n long long d = n - 1;\n while (d % 2 == 0) d /= 2;\n constexpr long long bases[3] = {2, 7, 61};\n for (long long a : bases) {\n long long t = d;\n long long y = pow_mod_constexpr(a, t, n);\n while (t != n - 1 && y != 1 && y != n - 1) {\n y = y * y % n;\n t <<= 1;\n }\n if (y != n - 1 && t % 2 == 0) {\n return false;\n }\n }\n return true;\n}\ntemplate <int n> constexpr bool is_prime = is_prime_constexpr(n);\n\nconstexpr std::pair<long long, long long> inv_gcd(long long a, long long b) {\n a = safe_mod(a, b);\n if (a == 0) return {b, 0};\n\n long long s = b, t = a;\n long long m0 = 0, m1 = 1;\n\n while (t) {\n long long u = s / t;\n s -= t * u;\n m0 -= m1 * u; // |m1 * u| <= |m1| * s <= b\n\n\n auto tmp = s;\n s = t;\n t = tmp;\n tmp = m0;\n m0 = m1;\n m1 = tmp;\n }\n if (m0 < 0) m0 += b / s;\n return {s, m0};\n}\n\nconstexpr int primitive_root_constexpr(int m) {\n if (m == 2) return 1;\n if (m == 167772161) return 3;\n if (m == 469762049) return 3;\n if (m == 754974721) return 11;\n if (m == 998244353) return 3;\n int divs[20] = {};\n divs[0] = 2;\n int cnt = 1;\n int x = (m - 1) / 2;\n while (x % 2 == 0) x /= 2;\n for (int i = 3; (long long)(i)*i <= x; i += 2) {\n if (x % i == 0) {\n divs[cnt++] = i;\n while (x % i == 0) {\n x /= i;\n }\n }\n }\n if (x > 1) {\n divs[cnt++] = x;\n }\n for (int g = 2;; g++) {\n bool ok = true;\n for (int i = 0; i < cnt; i++) {\n if (pow_mod_constexpr(g, (m - 1) / divs[i], m) == 1) {\n ok = false;\n break;\n }\n }\n if (ok) return g;\n }\n}\ntemplate <int m> constexpr int primitive_root = primitive_root_constexpr(m);\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\nnamespace atcoder {\n\nnamespace internal {\n\n#ifndef _MSC_VER\ntemplate <class T>\nusing is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value ||\n std::is_same<T, __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value,\n __uint128_t,\n unsigned __int128>;\n\ntemplate <class T>\nusing is_integral = typename std::conditional<std::is_integral<T>::value ||\n is_signed_int128<T>::value ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_signed_int = typename std::conditional<(is_integral<T>::value &&\n std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<(is_integral<T>::value &&\n std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<\n is_signed_int128<T>::value,\n make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\n#else\n\ntemplate <class T> using is_integral = typename std::is_integral<T>;\n\ntemplate <class T>\nusing is_signed_int =\n typename std::conditional<is_integral<T>::value && std::is_signed<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<is_integral<T>::value &&\n std::is_unsigned<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<is_signed_int<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type;\n\n#endif\n\ntemplate <class T>\nusing is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\ntemplate <class T>\nusing is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\ntemplate <class T> using to_unsigned_t = typename to_unsigned<T>::type;\n\n} // namespace internal\n\n} // namespace atcoder\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\nstruct modint_base {};\nstruct static_modint_base : modint_base {};\n\ntemplate <class T> using is_modint = std::is_base_of<modint_base, T>;\ntemplate <class T> using is_modint_t = std::enable_if_t<is_modint<T>::value>;\n\n} // namespace internal\n\ntemplate <int m, std::enable_if_t<(1 <= m)>* = nullptr>\nstruct static_modint : internal::static_modint_base {\n using mint = static_modint;\n\n public:\n static constexpr int mod() { return m; }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n static_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n static_modint(T v) {\n long long x = (long long)(v % (long long)(umod()));\n if (x < 0) x += umod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n static_modint(T v) {\n _v = (unsigned int)(v % umod());\n }\n static_modint(bool v) { _v = ((unsigned int)(v) % umod()); }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v -= rhs._v;\n if (_v >= umod()) _v += umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n unsigned long long z = _v;\n z *= rhs._v;\n _v = (unsigned int)(z % umod());\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n if (prime) {\n assert(_v);\n return pow(umod() - 2);\n } else {\n auto eg = internal::inv_gcd(_v, m);\n assert(eg.first == 1);\n return eg.second;\n }\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static constexpr unsigned int umod() { return m; }\n static constexpr bool prime = internal::is_prime<m>;\n};\n\ntemplate <int id> struct dynamic_modint : internal::modint_base {\n using mint = dynamic_modint;\n\n public:\n static int mod() { return (int)(bt.umod()); }\n static void set_mod(int m) {\n assert(1 <= m);\n bt = internal::barrett(m);\n }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n dynamic_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n long long x = (long long)(v % (long long)(mod()));\n if (x < 0) x += mod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n _v = (unsigned int)(v % mod());\n }\n dynamic_modint(bool v) { _v = ((unsigned int)(v) % mod()); }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v += mod() - rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n _v = bt.mul(_v, rhs._v);\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n auto eg = internal::inv_gcd(_v, mod());\n assert(eg.first == 1);\n return eg.second;\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static internal::barrett bt;\n static unsigned int umod() { return bt.umod(); }\n};\ntemplate <int id> internal::barrett dynamic_modint<id>::bt = 998244353;\n\nusing modint998244353 = static_modint<998244353>;\nusing modint1000000007 = static_modint<1000000007>;\nusing modint = dynamic_modint<-1>;\n\nnamespace internal {\n\ntemplate <class T>\nusing is_static_modint = std::is_base_of<internal::static_modint_base, T>;\n\ntemplate <class T>\nusing is_static_modint_t = std::enable_if_t<is_static_modint<T>::value>;\n\ntemplate <class> struct is_dynamic_modint : public std::false_type {};\ntemplate <int id>\nstruct is_dynamic_modint<dynamic_modint<id>> : public std::true_type {};\n\ntemplate <class T>\nusing is_dynamic_modint_t = std::enable_if_t<is_dynamic_modint<T>::value>;\n\n} // namespace internal\n\n} // namespace atcoder\n\n#include <iostream> // cout, endl, cin\n#include <string> // string, to_string, stoi\n#include <vector> // vector\n#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound\n#include <utility> // pair, make_pair\n#include <tuple> // tuple, make_tuple\n#include <cstdint> // int64_t, int*_t\n#include <cstdio> // printf\n#include <map> // map\n#include <queue> // queue, priority_queue\n#include <set> // set\n#include <stack> // stack\n#include <deque> // deque #include <unordered_map> // unordered_map #include <unordered_set> // unordered_set #include <bitset> // bitset\n#include <cctype> // isupper, islower, isdigit, toupper, tolower\n#include <math.h>\n#include <iomanip>\n#include <functional>\n#include<unordered_map>\n#include <random>\n#include<bitset>\nusing namespace std; \nusing namespace atcoder;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define repi(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n//#define endl '\\n'\n#define all(x) (x).begin(),(x).end()\n#define arr(x) (x).rbegin(),(x).rend()\ntypedef long long ll;\ntypedef unsigned long long ull;\nconst ll inf=4e18; \nusing graph = vector<vector<int> > ;\nusing vi=vector<int>;\nusing P= pair<ll,ll>; \nusing vvi=vector<vi>;\nusing vvvi=vector<vvi>;\nusing vll=vector<ll>; \nusing vvll=vector<vll>;\nusing vp=vector<P>;\nusing vvp=vector<vp>;\nusing vd=vector<double>;\nusing vvd =vector<vd>;\n//using vs=vector<string>;\n//string T=\"ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\n//string S=\"abcdefghijklmnopqrstuvwxyz\";\n//g++ main.cpp -std=c++17 -I . \n//cout <<setprecision(20);\n//cout << fixed << setprecision(10);\n//cin.tie(0); ios::sync_with_stdio(false);\n\nconst double PI = acos(-1);\nint vx[]={0,1,0,-1,-1,1,1,-1},vy[]={1,0,-1,0,1,1,-1,-1};\nvoid putsYes(bool f){cout << (f?\"Yes\":\"No\") << endl;}\nvoid putsYES(bool f){cout << (f?\"YES\":\"NO\") << endl;}\nvoid putsFirst(bool f){cout << (f?\"First\":\"Second\") << endl;}\nvoid debug(int test){cout << \"TEST\" << \" \" << test << endl;}\nll pow_pow(ll x,ll n,ll mod){\n if(n==0) return 1; \n x%=mod;\n ll res=pow_pow(x*x%mod,n/2,mod);\n if(n&1)res=res*x%mod;\n return res;\n}\nll gcdll(ll x,ll y){\n if(y==0)return x;\n return gcdll(y,x%y);\n}\nll INFF=1000100100100100100;\nll lcmll(ll x,ll y){\n ll X=(x/gcdll(x,y)),Y=y;\n if(X<=INFF/Y)return X*Y;\n else return INFF;\n}\ntemplate<class T> bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n else return false;\n}\ntemplate<class T> bool chmax(T& a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n else return false;\n}\nstruct edge{\n int to; ll cost;int t;\n edge(int to,ll cost,int t) : to(to),cost(cost),t(t){}\n};\nusing ve=vector<edge>;\nusing vve=vector<ve>;\nusing mint = modint;\n//using mint = modint1000000007;\nusing vm=vector<mint>;\nusing vvm=vector<vm>;\nusing vvvm=vector<vvm>;\nint mod = 1e9+9;\n//int mod=1e9+7;\nconstexpr int MAX =10;\nll fact[MAX],finv[MAX],inv[MAX];\nvoid initcomb(){\n fact[0]=fact[1]=1;\n finv[0]=finv[1]=1;\n inv[1]=1;\n for(int i=2;i<MAX;i++){\n fact[i]=fact[i-1]*i%mod;\n inv[i]=mod-inv[mod%i]*(mod/i)%mod;\n finv[i]=finv[i-1]*inv[i]%mod;\n }\n}\nll comb(ll n,ll k){\n if(n<k) return 0;\n if(n<0||k<0) return 0;\n return fact[n]*(finv[k]*finv[n-k]%mod)%mod;\n}\n\nstruct UnionFind { \n vector<int> par, siz;\n UnionFind(int n) : par(n, -1) , siz(n, 1) { } \n int root(int x) { \n if (par[x] == -1) return x;\n else return par[x] = root(par[x]);\n }\n bool issame(int x, int y) {\n return root(x) == root(y);\n }\n bool unite(int x, int y) {\n x = root(x), y = root(y);\n if (x == y) return false; \n if (siz[x] < siz[y]) swap(x, y);\n par[y] = x;\n siz[x] += siz[y];\n return true;\n }\n int size(int x) {\n return siz[root(x)];\n }\n};\nstruct Compress{\n vll a;\n int cnt;\n Compress() :cnt(0) {}\n void add(ll x){a.push_back(x);}\n void init(){\n sort(all(a));\n a.erase(unique(all(a)),a.end());\n cnt=a.size();\n }\n ll to(ll x){\n int index=lower_bound(all(a),x)-a.begin();\n return index;\n } //変換先\n ll from(int x){return a[x];}//逆引き\n int size(){return cnt;}\n};\nvll anss;\nint EXIT=0;\nvoid solve(int test){\n string s; cin >> s;\n int n=s.size();\n vi st;\n vi rs(n,-1);\n rep(i,n){\n if(s[i]=='[')st.push_back(i);\n if(s[i]==']'){\n int l=st.back();\n st.pop_back();\n rs[l]=i;\n }\n }\n vvi g(n);\n rep(i,n)if(rs[i]!=-1){\n for(int j=i-1; j>=0; j--){\n if(rs[j]>rs[i]){\n g[j].push_back(i);\n break;\n }\n }\n }\n vvll dp(n,vll(2,inf));\n auto dfs=[&](auto dfs,int v)->void{\n if(g[v].size()==0){\n int l=v+1,r=rs[v]-1;\n ll num=0;\n repi(j,l,r+1){\n num=num*10+s[j]-'0';\n }\n dp[v][0]=0;\n dp[v][1]=(num+1)/2;\n }\n else {\n int si=g[v].size();\n vll vals;\n for(auto &u:g[v]){\n dfs(dfs,u);\n vals.push_back(dp[u][1]);\n }\n sort(all(vals));\n dp[v][0]=0;\n dp[v][1]=0;\n rep(j,(si+1)/2)dp[v][1]+=vals[j];\n }\n };\n dfs(dfs,0);\n cout << dp[0][1] << endl;\n}\n//g++ cf.cpp -std=c++17 -I .\nint main(){cin.tie(0);ios::sync_with_stdio(false);\n {\n mod=998244353;\n initcomb();\n modint::set_mod(mod);\n }\n int t; cin >> t;\n rep(test,t)solve(test);\n /*\n for(int test=0;;test++){\n solve(test);\n if(EXIT)break;\n }\n */\n for(auto ans:anss){\n cout<< ans << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4156, "score_of_the_acc": -0.1449, "final_rank": 13 }, { "submission_id": "aoj_1188_8024532", "code_snippet": "#define _GLIBCXX_DEBUG /* これをするとvectorの配列外参照などがチェックされる */\n#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\n\nconst bool DEBUG = true;\n#define debug(x) \\\n if (DEBUG) cerr << __FILE__ << ':' << __LINE__ << \") \" << #x << \" : \" << (x) << endl;\n\n// [[[3][5][7]][[[5][2][3]]]\n\n// [ 読む\n// 中身評価\n// ] 読む\n// 中身 := 中のやつで過半数取るのに必要な\n\n/*\n ][ 以前のやつを\n calc(][ 以前のやつ)\n calc の結果を vector に入れて 最後にソート\n*/\n\n// sを評価\nll calc(string s) {\n \n\n\n string t = \"\";\n vector<ll> vec;\n s.pop_back();\n s.erase(s.begin());\n \n \n if (s.back() != ']')return (stoi(s) + 1) / 2;\n \n ll count = 0;\n for (int ind = 0; ind < s.size(); ind++) {\n if (s[ind] == '[')\n count++;\n else if (s[ind] == ']') {\n count--;\n }\n\n t += s[ind];\n if (count == 0) {\n vec.push_back(calc(t));\n t = \"\";\n } else {\n \n }\n }\n\n sort(vec.begin(), vec.end());\n int sz = int(vec.size());\n sz = (sz + 1) / 2;\n ll res = 0;\n for (int i = 0; i < sz; i++) {\n res += vec[i];\n }\n \n return res;\n}\n\nint main() {\n int n;\n cin >> n;\n while (n-- > 0) {\n string s;\n cin >> s;\n cout << calc(s) << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3504, "score_of_the_acc": -0.053, "final_rank": 9 }, { "submission_id": "aoj_1188_7939632", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define REP(i, n) for (int i = 0; i < n; ++i)\nint co;\nint func(string s) {\n vector<int> vv;\n if (s[co] != '[' && s[co] != ']') {\n int val = s[co++] - '0';\n while (s[co] != ']')\n val = 10 * val + (s[co++] - '0');\n vv.push_back(val / 2 + 1);\n } else {\n while (s[co++] == '[') {\n vv.push_back(func(s));\n if (s[co + 1] != ']')\n ++co;\n }\n }\n sort(vv.begin(), vv.end());\n int sum = 0;\n REP(i, vv.size() / 2 + 1) { sum += vv[i]; }\n return sum;\n}\nint main() {\n int n;\n vector<int> v;\n cin >> n;\n REP(i, n) {\n string s;\n cin >> s;\n co = 0;\n v.push_back(func(s));\n }\n REP(i, n) cout << v[i] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3272, "score_of_the_acc": -0.0203, "final_rank": 3 }, { "submission_id": "aoj_1188_7939591", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define reps(i, f, n) for (int i = f; i < int(n); i++)\n#define rep(i, n) reps(i, 0, n)\nint toint(string s) {\n stringstream sst;\n sst << s;\n int a;\n sst >> a;\n return a;\n}\nint rec(string s) {\n int kk = 0;\n rep(i, s.size()) {\n if (s[i] == '[' || s[i] == ']')\n kk++;\n }\n if (kk == 2) {\n return (toint(s.substr(1, s.size() - 2)) + 1) / 2;\n }\n int cnt = 0;\n int st = 0;\n vector<int> cand;\n rep(i, s.size()) {\n if (s[i] == '[') {\n if (cnt == 1)\n st = i;\n cnt++;\n }\n if (s[i] == ']') {\n cnt--;\n if (cnt == 1)\n cand.push_back(rec(s.substr(st, i - st + 1)));\n }\n }\n sort(cand.begin(), cand.end());\n int sum = 0;\n rep(i, (cand.size() + 1) / 2) { sum += cand[i]; }\n return sum;\n}\nint solve(string s) { return rec(s); }\nint main() {\n int n;\n cin >> n;\n rep(i, n) {\n string s;\n cin >> s;\n printf(\"%d\\n\", solve(s));\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3204, "score_of_the_acc": -1.0107, "final_rank": 15 }, { "submission_id": "aoj_1188_7939588", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <sstream>\n#include <string>\n#include <vector>\nusing namespace std;\n#define reps(i, f, n) for (int i = f; i < int(n); i++)\n#define rep(i, n) reps(i, 0, n)\nint solve(string s) {\n s.erase(s.begin());\n s.erase(s.begin() + s.size() - 1);\n int cnt = 0;\n rep(i, s.size()) {\n if (s[i] == '[' || s[i] == ']')\n cnt++;\n }\n if (cnt == 0) {\n stringstream sst;\n sst << s;\n int ret;\n sst >> ret;\n return ret / 2 + 1;\n }\n vector<int> cand;\n int st = 0;\n int ct = 0;\n rep(i, s.size()) {\n if (s[i] == '[')\n ct++;\n if (s[i] == ']')\n ct--;\n if (ct == 0) {\n cand.push_back(solve(s.substr(st, i - st + 1)));\n st = i + 1;\n }\n }\n sort(cand.begin(), cand.end());\n int ans = 0;\n rep(i, cand.size() / 2 + 1) { ans += cand[i]; }\n return ans;\n}\nint main() {\n int n;\n cin >> n;\n rep(i, n) {\n string s;\n cin >> s;\n cout << solve(s) << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3236, "score_of_the_acc": -1.0152, "final_rank": 16 }, { "submission_id": "aoj_1188_7939579", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <sstream>\n#include <string>\n#include <vector>\nusing namespace std;\nstring str;\nstring::iterator it;\nint s2i(string s) {\n stringstream ss(s);\n int x;\n ss >> x;\n return x / 2 + 1;\n}\nint calc() {\n int ans = 0;\n ++it;\n if (*it == '[') {\n vector<int> v;\n while (*it == '[') {\n v.push_back(calc());\n }\n sort(v.begin(), v.end());\n for (int i = 0; i < v.size() / 2 + 1; i++) {\n ans += v[i];\n }\n } else if (*it != ']') {\n string ss = \"\";\n while ('0' <= *it && *it <= '9') {\n ss += *it;\n ++it;\n }\n ans = s2i(ss);\n }\n ++it;\n return ans;\n}\nint main() {\n int n;\n cin >> n;\n while (n--) {\n cin >> str;\n it = str.begin();\n cout << calc() << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3128, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1188_7939546", "code_snippet": "#define _USE_MATH_DEFINES\n#include <algorithm>\n#include <cfloat>\n#include <climits>\n#include <cmath>\n#include <cstdio>\n#include <cstring>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <time.h>\n#include <vector>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int, int> i_i;\ntypedef pair<ll, int> ll_i;\ntypedef pair<double, int> d_i;\ntypedef pair<ll, ll> ll_ll;\ntypedef pair<double, double> d_d;\nstruct edge {\n int u, v;\n ll w;\n};\nll MOD = 1000000007;\nll _MOD = 1000000009;\ndouble EPS = 1e-10;\nint foo(string s) {\n s = s.substr(1, s.length() - 2);\n if (s[0] != '[') {\n stringstream ss(s);\n int x;\n ss >> x;\n return x / 2 + 1;\n }\n int y = 0, _i = 0;\n vector<int> v;\n for (int i = 0; i < s.length(); i++) {\n if (s[i] == '[')\n y++;\n else if (s[i] == ']')\n y--;\n if (y == 0) {\n string sub = s.substr(_i, i - _i + 1);\n v.push_back(foo(sub));\n _i = i + 1;\n }\n }\n sort(v.begin(), v.end());\n int sum = 0;\n for (int i = 0; i < v.size() / 2 + 1; i++)\n sum += v[i];\n return sum;\n}\nint main() {\n int T;\n cin >> T;\n while (T--) {\n string s;\n cin >> s;\n cout << foo(s) << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3240, "score_of_the_acc": -1.0158, "final_rank": 17 }, { "submission_id": "aoj_1188_7939544", "code_snippet": "#include <algorithm>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <ctype.h>\n#include <iostream>\n#include <list>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <string>\n#include <utility>\n#include <vector>\nusing namespace std;\nint StoI(string s) {\n int ans = 0;\n for (int i = 0; i < s.length(); i++) {\n ans += (s[i] - '0') * (int)pow(10, s.length() - 1 - i);\n }\n return ans;\n}\nlong long int solve(string s) {\n bool flag = false;\n string a = \"\";\n int leftnum = 0;\n vector<int> result;\n for (int i = 1; i < s.length() - 1; i++) {\n a += s[i];\n if (s[i] == '[')\n leftnum++;\n else if (s[i] == ']')\n leftnum--;\n if (leftnum > 1)\n flag = true;\n if (leftnum == 0) {\n if (flag) {\n result.push_back(solve(a));\n } else {\n a = a.substr(1, a.length() - 2);\n result.push_back(StoI(a) / 2 + 1);\n }\n a = \"\";\n flag = false;\n }\n }\n sort(result.begin(), result.end());\n long long int ans = 0;\n for (int i = 0; i < result.size() / 2 + 1; i++) {\n ans += result[i];\n }\n return ans;\n}\nint main() {\n int n;\n cin >> n;\n string s;\n for (int i = 0; i < n; i++) {\n cin >> s;\n cout << solve(s) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3388, "score_of_the_acc": -0.0366, "final_rank": 7 }, { "submission_id": "aoj_1188_7939537", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <sstream>\n#include <string>\n#include <vector>\n#define all(u) (u).begin(), (u).end()\n#define PB push_back\n#define REP(i, n) for (int i = 0; i < (n); i++)\nusing namespace std;\ntypedef vector<int> VI;\nint stoi(string num) {\n int ret;\n stringstream s;\n s << num;\n s >> ret;\n return ret;\n}\nstring str;\nint cur;\nint rec() {\n cur++;\n if (str[cur] != '[' && str[cur] != ']') {\n string t;\n while (str[cur] != '[' && str[cur] != ']') {\n t += str[cur];\n cur++;\n }\n cur++;\n return stoi(t) / 2 + 1;\n }\n VI vote;\n while (str[cur] != ']') {\n vote.PB(rec());\n }\n sort(all(vote));\n int ret = 0;\n REP(i, vote.size() / 2 + 1) { ret += vote[i]; }\n cur++;\n return ret;\n}\nint main() {\n int n;\n cin >> n;\n while (n--) {\n cin >> str;\n cur = 0;\n cout << rec() << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3196, "score_of_the_acc": -1.0096, "final_rank": 14 }, { "submission_id": "aoj_1188_7939475", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <string>\n#include <vector>\n#define REP(i, n) for (int i = 0; i < (int)(n); i++)\nusing namespace std;\ntypedef int number;\nint c;\nstring str;\nvoid debug(string str) {}\nint minimum(vector<number> v, int n) {\n sort(v.begin(), v.end());\n int sum = 0;\n REP(i, n) { sum += v[i]; }\n return sum;\n}\nnumber A();\nnumber Num();\nnumber A() {\n debug(\"A:\" + str.substr(c));\n if (str[c] == '[') {\n c++;\n int p;\n vector<number> children;\n while (p = c, (str[p] == '[' || isdigit(str[p]))) {\n number a = A();\n children.push_back(a);\n }\n c++;\n int len = children.size();\n return minimum(children, (1 + len) / 2);\n } else {\n number num = Num();\n return num;\n }\n}\nnumber Num() {\n debug(\"Num:\" + str.substr(c));\n int val = 0;\n while (isdigit(str[c])) {\n val = val * 10 + (str[c] - '0');\n c++;\n }\n return (1 + val) / 2;\n}\nint main() {\n int n;\n cin >> n;\n REP(i, n) {\n cin >> str;\n c = 0;\n cout << A() << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3240, "score_of_the_acc": -1.0158, "final_rank": 17 }, { "submission_id": "aoj_1188_7939465", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < int(n); ++i)\n#define all(a) a.begin(), a.end()\nint solve(string s, int &i) {\n vector<int> v;\n if (isdigit(s[i])) {\n int num = 0;\n while (isdigit(s[i])) {\n num = num * 10 + s[i] - '0';\n i++;\n }\n return num + 1;\n }\n while (s[i] == '[') {\n i++;\n v.push_back(solve(s, i));\n i++;\n }\n sort(all(v));\n int n = v.size(), sum = 0;\n rep(k, (n + 1) / 2) { sum += v[k]; }\n return sum;\n}\nint main(void) {\n int T;\n cin >> T;\n rep(_, T) {\n string s;\n cin >> s;\n int index = 0;\n cout << (solve(s, index) + 1) / 2 << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3200, "score_of_the_acc": -0.0101, "final_rank": 2 }, { "submission_id": "aoj_1188_6781163", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\n#define rep(i, n) for(int i = 0; i < (int)n; i++)\n#define repp(i, m, n) for(int i = (int)m; i < (int)n; i++)\n\n#define ALL(x) x.begin(),x.end()\n\n#define YESNO(bool) if(bool){cout<<\"YES\"<<endl;}else{cout<<\"NO\"<<endl;}\n#define yesno(bool) if(bool){cout<<\"yes\"<<endl;}else{cout<<\"no\"<<endl;}\n#define YesNo(bool) if(bool){cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}\n#define keta(x) cout << std::fixed << std::setprecision(15) << (double)x << endl;\n\nconst int MAXN = 7368792;\nint n;\nstring S;\nint N;\n\nusing Graph = vector<vector<int>>;\n\n//BFSを用いて始点sからの距離を求めるアルゴリズム\nvector<int> BFS(const Graph &G, int s){\n\n vector<int> dist(N, -1);\n queue<int> todo;\n dist[s] = 0; //開始の頂点の距離を0にする.\n\n //キューに追加\n todo.push(s);\n\n while(!todo.empty()){\n int v = todo.front();\n todo.pop();\n for(auto next_v : G[v]){\n if(dist[next_v] != -1) continue;\n dist[next_v] = dist[v] + 1;\n todo.push(next_v);\n }\n }\n return dist;\n}\n\nint solve(){\n int cnt = 0; //左括弧の数(頂点数)\n rep(i, S.size()){\n if(S[i] == '[') cnt++;\n }\n Graph G(cnt);\n N = cnt;\n\n //入力から木を構築\n map<int, int> V;\n rep(i, cnt){\n V[i] = -1; //何も書かれていない\n }\n stack<int> st;\n string num_st = \"\";\n int v_now = 0;\n rep(i, S.size()){\n if(i == 0){\n st.push(v_now);\n v_now++;\n }\n else{\n //左括弧がでてきたらstのtopと今入れようとしている頂点\n //を辺で結ぶ\n if(S[i] == '['){\n G[st.top()].push_back(v_now);\n G[v_now].push_back(st.top());\n st.push(v_now);\n v_now++;\n }else if(S[i] == ']'){\n //もし,num_stに数値が描き込まれていたら\n //st.top()の頂点にその数字を書き込む\n if(num_st != \"\"){\n V[st.top()] = stoi(num_st);\n num_st = \"\";\n }\n st.pop();\n }else{\n num_st += S[i];\n }\n }\n }\n\n vector<int> depth = BFS(G, 0);\n //木の深さを調べる\n int max_depth = 0;\n rep(i, N) max_depth = max(depth[i], max_depth);\n\n //深さと頂点の関係\n //最下層には数字が書かれている.\n vector<vector<int>> dp_V(max_depth+1);\n rep(i, N){\n dp_V[depth[i]].push_back(i);\n }\n\n //最下層の一つ上から頂点に対して計算を行う\n for(int i = max_depth-1; i >= 0; i--){\n for(auto v : dp_V[i]){\n vector<int> tmp;\n int tmp_ans = 0;\n for(auto v_chi : G[v]){\n //自分より一つ下ならtmpに追加\n if(depth[v_chi] == i+1){\n if(i+1 == max_depth) tmp.push_back(V[v_chi]/2+1);\n else tmp.push_back(V[v_chi]);\n }\n }\n sort(ALL(tmp));\n rep(j, tmp.size()/2+1){\n tmp_ans += tmp[j];\n }\n //頂点の更新\n V[v] = tmp_ans;\n }\n }\n return V[0];\n}\n\nint main(){\n cin >> n;\n vector<int> ans;\n rep(i, n){\n cin >> S;\n ans.push_back(solve());\n }\n for(auto p : ans){\n cout << p << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3892, "score_of_the_acc": -0.1077, "final_rank": 12 }, { "submission_id": "aoj_1188_6023323", "code_snippet": "#include <bits/stdc++.h>\n\nconst long long INF = 1e9;\nconst long long MOD = 1e9 + 7;\n//const long long MOD = 998244353;\nconst long long LINF = 1e18;\nusing namespace std;\n\n#define YES(n) cout << ((n) ? \"YES\" : \"NO\" ) << endl\n#define Yes(n) cout << ((n) ? \"Yes\" : \"No\" ) << endl\n#define POSSIBLE(n) cout << ((n) ? \"POSSIBLE\" : \"IMPOSSIBLE\" ) << endl\n#define Possible(n) cout << ((n) ? \"Possible\" : \"Impossible\" ) << endl\n#define dump(x) cout << #x << \" = \" << (x) << endl\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) for(int i=0;i<(n);++i)\n#define REPR(i,n) for(int i=n;i>=0;i--)\n#define COUT(x) cout<<(x)<<endl\n#define SCOUT(x) cout<<(x)<<\" \"\n#define VECCOUT(x) for(auto&youso_: (x) )cout<<right<<setw(10)<<youso_<<\",\";cout<<endl\n#define ENDL cout<<endl\n#define CIN(...) int __VA_ARGS__;CINT(__VA_ARGS__)\n#define LCIN(...) long long __VA_ARGS__;CINT(__VA_ARGS__)\n#define SCIN(...) string __VA_ARGS__;CINT(__VA_ARGS__)\n#define VECCIN(x) for(auto&youso_: (x) )cin>>youso_\n#define mp make_pair\n#define PQ priority_queue<long long>\n#define PQG priority_queue<long long,V,greater<long long>>\n\n\ntypedef long long ll;\ntypedef vector<long long> vl;\ntypedef vector<long long> vi;\ntypedef vector<bool> vb;\ntypedef vector<char> vc;\ntypedef vector<vl> vvl;\ntypedef vector<vi> vvi;\ntypedef vector<vb> vvb;\ntypedef vector<vc> vvc;\ntypedef pair<long long, long long> pll;\n\n\n#define COUT(x) cout<<(x)<<endl\nvoid CINT(){}\ntemplate <class Head,class... Tail>\nvoid CINT(Head&& head,Tail&&... tail){\n cin>>head;\n CINT(move(tail)...);\n}\ntemplate<class T>\nvoid mod(T &x) {\n x %= MOD;\n x += MOD;\n x %= MOD;\n}\n\nll GCD(ll a, ll b) {\n if(b == 0) return a;\n else return GCD(b, a%b);\n}\n\nstruct COMB{\n vl fact, fact_inv, inv;\n void init_nCk(long long SIZE) {\n fact.resize(SIZE + 5);\n fact_inv.resize(SIZE + 5);\n inv.resize(SIZE + 5);\n fact.at(0) = fact.at(1) = fact_inv.at(0) = fact_inv.at(1) = inv.at(1) = 1;\n for(long long i = 2; i < SIZE + 5; i++) {\n fact.at(i) = fact.at(i - 1)*i%MOD;\n inv.at(i) = MOD - inv.at(MOD%i)*(MOD/i)%MOD;\n fact_inv.at(i) = fact_inv.at(i - 1)*inv.at(i)%MOD;\n }\n }\n long long nCk (long long n, long long k) {\n assert(!(n < k));\n assert(!(n < 0 || k < 0));\n return fact.at(n)*(fact_inv.at(k)*fact_inv.at(n - k)%MOD)%MOD;\n }\n};\nll extGCD(ll a, ll b, ll &x, ll &y) {\n if(b == 0) {\n x = 1;\n y = 0;\n return a;\n }\n ll d = extGCD(b, a%b, y, x);\n y -= a/b*x;\n return d;\n}\n\nvector<string> sol(string S) {\n vector<string> res;\n S = S.substr(1, S.size() - 2);\n int count = 0;\n int s = 0;\n for(int i = 0; i < S.size(); i++) {\n if(S.at(i) == '[') {\n count++;\n if(count == 1) {\n s = i;\n }\n }\n if(S.at(i) == ']') {\n count--;\n if(count == 0) {\n res.push_back(S.substr(s, i - s + 1));\n }\n }\n }\n if(res.size() == 0) res.push_back(S);\n return res;\n}\n\n\nint solve(string S) {\n int sum = 0;\n\n vector<string> sl = sol(S);\n // VECCOUT(sl);\n\n // 処理終了\n if(sl.size() == 1) {\n istringstream s(sl.at(0));\n int ret = 0;\n s >> ret;\n return (ret + 1)/2;\n }\n vl res(sl.size(), 0);\n for(int i = 0; i < sl.size(); i++) {\n // 一段階バラバラにした文字列を撮るのに必要な票数\n res.at(i) = solve(sl.at(i));\n }\n sort(res.begin(),res.end());\n for(int i = 0; i < (res.size() + 1)/2; i++) {\n sum += res.at(i);\n }\n return sum;\n}\n\nvoid Main() {\n LCIN(N);\n for(int i = 0; i < N; i++) {\n SCIN(S);\n cout << solve(S) << endl;\n }\n}\n\nint main() {\n cout << fixed << setprecision(15);\n Main();\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3376, "score_of_the_acc": -0.0349, "final_rank": 6 }, { "submission_id": "aoj_1188_5875515", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n \n ios::sync_with_stdio(false);\n cin.tie(0);\n\n int n;\n cin >> n;\n for (int i=0;i<n;i++) {\n string s;\n cin >> s;\n int ns = s.size();\n stack<string> st;\n int tmp = 0;\n for (int j=0;j<ns;j++) {\n if (s[j] == '[') st.push(\"[\");\n else if (s[j] == ']') {\n vector<string> numss;\n st.push(to_string(tmp));\n tmp = 0;\n while (st.top() != \"[\") {\n numss.emplace_back(st.top());\n st.pop();\n }\n st.pop();\n vector<int> nums;\n int nt = numss.size();\n for (int k=0;k<nt;k++) {\n nums.emplace_back(stoi(numss[k]));\n }\n sort(nums.begin(),nums.end());\n int ned = 0;\n for (int k=0;k<=nt/2;k++) {\n if (nt == 1) ned += (nums[k]+1)/2;\n else ned += nums[k];\n }\n st.push(to_string(ned));\n }\n else {\n tmp *= 10;\n tmp += s[j]-'0';\n }\n /*stack<string> kst;\n while (!st.empty()) {\n kst.push(st.top());\n st.pop();\n }\n while (!kst.empty()) {\n cout << kst.top() << ' ';\n st.push(kst.top());\n kst.pop();\n }\n cout << endl;*/\n }\n cout << st.top() << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3556, "score_of_the_acc": -0.0603, "final_rank": 10 }, { "submission_id": "aoj_1188_5243827", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n//#include <atcoder/all>\n//using namespace atcoder;\n\nusing ll = long long;\nusing ld = long double;\nusing pll = pair<ll, ll>;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\nusing vvvll = vector<vector<vector<ll>>>;\nusing vpll = vector<pair<ll, ll>>;\n#define rep(i,n) for (ll i = 0; i < (n); i++)\n#define all(v) (v).begin(), (v).end()\n#define sz(x) ((int)(x).size())\n#define fi first\n#define se second\n#define pb push_back\n#define endl '\\n'\n#define IOS ios::sync_with_stdio(false); cin.tie(nullptr);\nconst int inf = 1<<30;\nconst ll INF = 1ll<<60;\n//const ll mod = 1000000007;\nconst ll mod = 998244353;\n//const ll dx[4] = {1, 0, -1, 0};\n//const ll dy[4] = {0, 1, 0, -1};\ntemplate<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }\n\ntemplate<class T> void disp1(vector<T> &array, bool blank=1) {\n rep(i, array.size()) cout << ((i&&blank) ? \" \" : \"\") << array[i];\n cout << endl;\n //cout << \" \";\n}\ntemplate<class T> void disp2(vector<vector<T>> &array, bool blank=1) {\n rep(i, array.size()) disp1(array[i], blank);\n}\n\nll rem(ll a, ll b) { return (a % b + b) % b; } // 余りを0~b-1に丸める\n// 小数の入力が文字で与えられたとき、10^n倍したものを返す\nll x10(string str_f, ll n) {\n if (str_f[0] == '-') return -x10(str_f.substr(1), n);\n ll times = 1; rep(i,n) times *= 10; // times = 10^n\n int id = -1; rep(i,str_f.size()) if (str_f[i] == '.') id = i;\n if (id == -1) { return stoll(str_f)*times; }\n string str_int = str_f.substr(0, id), str_dec = str_f.substr(id+1);\n while (str_dec.size() < n) str_dec += '0';\n return stoll(str_int)*times + stoll(str_dec);\n}\n// A^N (mod)\nll modpow(ll A, ll N, ll mod) {\n ll RES = 1;\n while (N) {\n if (N & 1) RES = RES * A % mod;\n A = A * A % mod;\n N >>= 1;\n }\n return RES;\n}\n\n//using mint = modint998244353;\n\nll dfs(string s) {\n // [ABC]みたいなやつがくるので、AとBとCに分解する\n vector<string> vs;\n int n = sz(s);\n // [A]みたいなやつが来た時の対処\n bool leaf = 1;\n for (int i = 1; i < n-1; i++) {\n if ((s[i] == '[') || (s[i] == ']')) leaf = 0;\n }\n //cout << leaf << endl;\n if (leaf) {\n string t = s.substr(1, n-2);\n //cout << t << endl;\n ll ret = stoll(t);\n return (ret+1)/2;\n }\n // [ABC]みたいなやつの処理\n int c = 0, id = 1;\n for (int i = 1; i < n-1; i++) {\n if (s[i] == '[') c++;\n if (s[i] == ']') c--;\n if (c == 0) {\n vs.pb(s.substr(id, i+1-id));\n id = i+1;\n }\n }\n vll ave;\n /*\n for (string si : vs) {\n puts(\"vs\");\n cout << si << endl;\n }\n */\n for (string si : vs) {\n ave.pb(dfs(si));\n }\n sort(all(ave));\n ll ret = 0;\n rep(i,sz(ave)/2+1) ret += ave[i];\n return ret;\n}\n\nint main() {\n ll n; cin >> n;\n rep(i,n) {\n string s; cin >> s;\n cout << dfs(s) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3312, "score_of_the_acc": -0.0259, "final_rank": 5 }, { "submission_id": "aoj_1188_4957369", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint process()\n{\n string str;\n cin >> str;\n array<vector<int>, 10000> vec = {};\n array<int,10000> level_size = {};\n string start = \"[\";\n string end = \"]\";\n int level = 0;\n int current = 0;\n for(int i=0;i<str.length();i++){\n if(str.compare(i,1,start)==0){\n level ++;\n }else if(str.compare(i,1,end)==0){\n if(current == 0){\n sort(vec[level].begin(),vec[level].end());\n int sum = 0;\n for(int i=0;i<(level_size[level]+1)/2;i++){\n sum += vec[level][i];\n }\n for(int i=0;i<vec[level].size();i++){\n vec[level][i] = 1e9;\n } \n level_size[level] = 0;\n level --;\n level_size[level] ++;\n vec[level].push_back(sum);\n }else{\n level --;\n vec[level].push_back((current+1)/2);\n current = 0;\n level_size[level] ++;\n }\n }else{\n current *= 10;\n current += stoi(str.substr(i,1));\n }\n }\n return vec[0][0];\n}\n\nint main()\n{\n int num;\n cin >> num;\n vector<int> ans;\n for(int i=0;i<num;i++){\n ans.push_back(process());\n }\n for(int i=0;i<num;i++){\n cout << ans[i] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4028, "score_of_the_acc": -1.1268, "final_rank": 19 }, { "submission_id": "aoj_1188_4946571", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)n;++i)\n#define reps(i,s,n) for(int i=s;i<(int)n;++i)\n\nusing namespace std;\nusing ll = long long;\nconstexpr ll LINF = 1LL<<60;\n\ntemplate<class T> using V = vector<T>;\ntemplate<class T> using VV = vector<vector<T>>;\n\nbool solve(){\n string s;\n cin>>s;\n V<ll> d;\n rep(i,s.size()){\n if(s[i]=='[')d.push_back(-1);\n else if(s[i]==']'){\n if(d.size()!=0 && d.back()>=0){\n d.back()=ceil((double)d.back()/2);\n }\n d.push_back(-2);\n }else {\n if(d.size()==0 || d.back()<0){\n d.push_back(s[i]-'0');\n }else{\n d.back()=d.back()*10+s[i]-'0';\n }\n }\n }\n rep(i,d.size()){\n if(d[i]!=-2)continue;\n V<ll> tmp;\n ll r=i;\n for(i--;d[i]>=0;i--){\n tmp.push_back(d[i]);\n }\n sort(tmp.begin(),tmp.end());\n ll ans=0;\n rep(j,ceil((double)tmp.size()/2)){\n ans+=tmp[j];\n }\n d[i]=ans;\n d.erase(d.begin()+i+1,d.begin()+r+1);\n \n /*rep(j,d.size()){\n if(d[j]>=0)cout<<d[j]<<\" \";\n else cout<<\"|\";\n }\n cout<<endl;*/\n }\n cout<<d[0]<<endl;\n return true;\n}\n\nint main(){\n ll n;\n cin>>n;\n rep(i,n)solve();\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3596, "score_of_the_acc": -0.066, "final_rank": 11 }, { "submission_id": "aoj_1188_4936958", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint n,cnt,tot,q,Q;\nstring s;\nvector<int> v;\nstack<int> sta[10000];\nint main(void){\n cin>>Q;\n while(Q--){\n for(int i=0;i<10000;i++)sta[i]={};\n v={};\n cnt=tot=0;\n cin>>s;\n for(int i=0;i<s.size();i++){\n //cout<<s[i]<<\" \"<<cnt<<endl;\n if(s[i]=='[')cnt++;\n else if(s[i]==']'){\n if(tot!=0){\n cnt--;\n //cout<<cnt<<\" \"<<tot<<endl;\n sta[cnt].push((tot+1)/2);\n tot=0;\n }\n else{\n v={};\n while(sta[cnt].size()){\n q=sta[cnt].top();\n sta[cnt].pop();\n v.push_back(q);\n //cout<<q<<endl;\n }\n sort(v.begin(),v.end());\n q=0;\n for(int j=0;j<=v.size()/2;j++)q+=v[j];\n cnt--;\n sta[cnt].push(q);\n }\n }\n else{\n tot*=10;\n tot+=(s[i]-'0');\n }\n }\n q=sta[0].top();\n cout<<q<<endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 10224, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_1188_4819651", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair< ll, ll > Pi;\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define rep2(i,n) for(int i=1;i<=(n);i++)\n#define rep3(i,i0,n) for(int i=i0;i<(n);i++)\n#define pb push_back\n#define mod 1000000007\nconst ll INF = 1LL << 60;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\nll gcd(ll a, ll b) {return b?gcd(b,a%b):a;}\nll lcm(ll a, ll b) {return a/gcd(a,b)*b;}\n#define all(x) x.begin(), x.end()\n#define mp make_pair\nbool compare(Pi a, Pi b) {\n if(a.first != b.first){\n return a.first < b.first;\n \n }else{\n return a.second < b.second;\n }\n}\n\n\nbool In_map(ll y,ll x,ll h,ll w){\n if(y<0 || x<0 || y>=h || x>=w){\n return 0;\n }else{\n return 1;\n }\n}\nconst vector<ll> dx{1,0,-1,0};\nconst vector<ll> dy{0,1,0,-1};\n\n\nint main() {\n ll N;\n cin >>N;\n rep(i,N){\n string S;\n cin>>S;\n ll M=S.size();\n ll K=0;\n rep(j,M){\n if(S[j]=='['){\n K++;\n }else{\n break;\n }\n }\n ll mode=0;\n vector<ll>cnt(K);\n vector<vector<ll>>sq(K);\n vector<ll>num;\n ll ct=0;\n ll dl=0;\n queue<ll>que;\n rep(j,M){\n //cout<<\"OK\"<<endl;\n if(S[j]==']'){\n ct++;\n if(j==M-1){\n if(ct>1){\n rep(k,ct-1){\n sq[k].pb(cnt[k]+1);\n }\n }\n }\n if(mode==0){\n //cout<<\"OK\"<<endl;\n num.pb(stoi(S.substr(j-dl,dl)));\n que.push((stoi(S.substr(j-dl,dl))+1)/2);\n dl=0;\n }\n \n mode=1;\n }else{\n if(S[j]=='['){\n if(ct==1){\n cnt[0]++;\n }else if(ct>1){\n rep(k,ct-1){\n sq[k].pb(cnt[k]+1);\n }\n \n \n rep(k,ct-1){\n cnt[k]=0;\n }\n cnt[ct-1]++;\n }\n ct=0;\n }else{\n dl++;\n mode=0;\n }\n }\n }\n /*rep(j,K){\n rep(k,sq[j].size()){\n cout<<sq[j][k]<<\" \";\n }\n cout<<endl;\n }*/\n\n /*rep(j,num.size()){\n cout<<num[j]<<endl;\n }*/\n vector<ll>ele(K);\n rep(j,K){\n ll now=0;\n rep(k,sq[j].size()){\n vector<ll>tmp;\n rep(m,sq[j][k]){\n tmp.pb(que.front());\n que.pop();\n }\n sort(all(tmp));\n ll sum=0;\n rep(m,(sq[j][k]+1)/2){\n sum+=tmp[m];\n }\n que.push(sum);\n }\n \n }\n cout<<que.front()<<endl;\n\n\n }\n\n \n \n\n\n return 0;\n \n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3292, "score_of_the_acc": -0.0231, "final_rank": 4 } ]
aoj_1189_cpp
Prime Caves An international expedition discovered abandoned Buddhist cave temples in a giant cliff standing on the middle of a desert. There were many small caves dug into halfway down the vertical cliff, which were aligned on square grids. The archaeologists in the expedition were excited by Buddha's statues in those caves. More excitingly, there were scrolls of Buddhism sutras (holy books) hidden in some of the caves. Those scrolls, which estimated to be written more than thousand years ago, were of immeasurable value. The leader of the expedition wanted to collect as many scrolls as possible. However, it was not easy to get into the caves as they were located in the middle of the cliff. The only way to enter a cave was to hang you from a helicopter. Once entered and explored a cave, you can climb down to one of the three caves under your cave; i.e., either the cave directly below your cave, the caves one left or right to the cave directly below your cave. This can be repeated for as many times as you want, and then you can descent down to the ground by using a long rope. So you can explore several caves in one attempt. But which caves you should visit? By examining the results of the preliminary attempts, a mathematician member of the expedition discovered that (1) the caves can be numbered from the central one, spiraling out as shown in Figure D-1; and (2) only those caves with their cave numbers being prime (let's call such caves prime caves ), which are circled in the figure, store scrolls. From the next attempt, you would be able to maximize the number of prime caves to explore. Figure D-1: Numbering of the caves and the prime caves Write a program, given the total number of the caves and the cave visited first, that finds the descending route containing the maximum number of prime caves. Input The input consists of multiple datasets. Each dataset has an integer m (1 ≤ m ≤ 10 6 ) and an integer n (1 ≤ n ≤ m ) in one line, separated by a space. m represents the total number of caves. n represents the cave number of the cave from which you will start your exploration. The last dataset is followed by a line with two zeros. Output For each dataset, find the path that starts from the cave n and contains the largest number of prime caves, and output the number of the prime caves on the path and the last prime cave number on the path in one line, separated by a space. The cave n , explored first, is included in the caves on the path. If there is more than one such path, output for the path in which the last of the prime caves explored has the largest number among such paths. When there is no such path that explores prime caves, output " 0 0 " (without quotation marks). Sample Input 49 22 46 37 42 23 945 561 1081 681 1056 452 1042 862 973 677 1000000 1000000 0 0 Output for the Sample Input 0 0 6 43 1 23 20 829 18 947 10 947 13 947 23 947 534 993541
[ { "submission_id": "aoj_1189_10852870", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,n) for(ll i=0;i<n;++i)\n#define RREP(i,n) for(ll i=n-1;i>=0;--i)\n#define FOR(i,m,n) for(ll i=m;i<n;++i)\n#define RFOR(i,m,n) for(ll i=n-1;i>=m;--i)\n#define ALL(v) (v).begin(),(v).end()\n#define PB(a) push_back(a)\n#define UNIQUE(v) v.erase(unique(ALL(v)),v.end());\n#define DUMP(v) REP(aa, (v).size()) { cout << v[a]; if (a != v.size() - 1)cout << \" \"; else cout << endl; }\n#define INF 1000000001ll\n#define MOD 1000000007ll\n#define EPS 1e-9\n\nconst int dx[8] = { 1,1,0,-1,-1,-1,0,1 };\nconst int dy[8] = { 0,1,1,1,0,-1,-1,-1 };\n\n\nusing namespace std;\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vl;\ntypedef vector<vi> vvi;\ntypedef vector<vl> vvl;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\nll max(ll a, int b) { return max(a, ll(b)); }\nll max(int a, ll b) { return max(ll(a), b); }\nll min(ll a, int b) { return min(a, ll(b)); }\nll min(int a, ll b) { return min(ll(a), b); }\n///(´・ω・`)(´・ω・`)(´・ω・`)(´・ω・`)(´・ω・`)(´・ω・`)///\nint m, n;\nvi isprime;\npii dfs(vector<vector<pii>> &dp, vvi &cave, int x, int y) {\n\tif (cave[y][x] > m)return pii(0, 0);\n\tif (dp[y][x] != pii(-1, -1))return dp[y][x];\n\tint dj[] = { -1,0,1 };\n\tpii ret=pii(0,0);\n\tREP(k, 3) {\n\t\tint nx = x + dj[k];\n\t\tret = max(ret, dfs(dp, cave, nx, y + 1));\n\t}\n\tif (isprime[cave[y][x]]) {\n\t\tret.first++;\n\t\tif (ret.second == 0)ret.second = cave[y][x];\n\t}\n\treturn dp[y][x] = ret;\n\t\n}\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tisprime.resize(1e6+1,1);\n\tisprime[0] = 0; isprime[1] = 0;\n\tREP(i, isprime.size()) {\n\t\tif (isprime[i]) {\n\t\t\tfor (int j = 2; j*i < isprime.size(); ++j) {\n\t\t\t\tisprime[i*j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\tvvi cave(2000, vi(2000,0));\n\tint i = 1000, j = 1001;\n\tint num = 2;\n\tcave[1000][1000]= 1;\n\tREP(k, 1005) {\n\t\tif (k % 2 == 0) {\n\t\t\tREP(m, k + 2) {\n\n\t\t\t\tcave[i][j] = num;\n\t\t\t\tnum++;\n\t\t\t\tif (m != k + 1)\ti--;\n\t\t\t}\n\t\t\tnum--;\n\t\t\tREP(m, k + 2) {\n\t\t\t\tcave[i][j] = num;\n\t\t\t\tnum++;\n\t\t\t\tj--;\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tREP(m, k + 2) {\n\t\t\t\tcave[i][j] = num;\n\t\t\t\tnum++;\n\t\t\t\tif (m != k + 1)\ti++;\n\t\t\t}\n\t\t\tnum--;\n\t\t\tREP(m, k + 2) {\n\t\t\t\tcave[i][j] = num;\n\t\t\t\tnum++;\n\t\t\t\tj++;\n\t\t\t}\n\t\t}\n\t}\n\twhile (1) {\n\t\t\n\t\tcin >> m >> n;\n\t\tif (!m)break;\n\t\tint sx, sy;\n\t\tREP(i, 2000) {\n\t\t\tREP(j, 2000) {\n\t\t\t\tif (cave[i][j] == n) {\n\t\t\t\t\tsx = j, sy = i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<vector<pii>> dp(2000,vector<pii> (2000, pii(-1,-1)));\n\t\tauto a = dfs(dp, cave, sx, sy);\n\t\tcout <<a.first<<\" \"<<a.second << endl;\n\n\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 590, "memory_kb": 54060, "score_of_the_acc": -0.9762, "final_rank": 13 }, { "submission_id": "aoj_1189_10671549", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nbool solve();\n\nusing ll = long long;\n#define rep(i, a, b) for (int i = a; i < (b); ++i)\n#define sz(x) (int)(x).size()\n#define all(x) x.begin(), x.end()\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\ntemplate <class T>\ninline bool chmin(T &a, T b) {\n return ((a > b) ? (a = b, 1) : (0));\n}\ntemplate <class T>\ninline bool chmax(T &a, T b) {\n return ((a < b) ? (a = b, 1) : (0));\n}\n\nconst int ispsz=100+int(1e6);\nbool isPrime[ispsz];\nint main() {\n for(int i=2;i<ispsz;i++){\n isPrime[i]=1;\n }\n for(int i=2;i<ispsz;i++){\n if(isPrime[i]){\n for(int j=2*i;j<ispsz;j+=i)isPrime[j]=0;\n }\n }\n\n while (solve());\n return 0;\n}\n\nbool solve() {\n int m,n;cin>>m>>n;\n if (n==0) return 0;\n int l=0;\n while(l*l<m)l++;\n if(l%2==0)l++;\n //lxlの正方形\n auto val(vector(l,vi(l,0)));\n const int di4[]={0,-1,0,1};\n const int dj4[]={1,0,-1,0};\n int ci=l/2,cj=l/2;\n int cdir=0;\n vector<pii>place(l*l+1,pii(0,0));\n rep(step,1,m+1){\n val[ci][cj]=step;\n place[step]=pii(ci,cj);\n if(step>1){\n int ndir=(cdir+1)%4;\n if(val[ci+di4[ndir]][cj+dj4[ndir]]==0)cdir=ndir;\n }\n ci+=di4[cdir];\n cj+=dj4[cdir];\n }\n // rep(i,0,l){\n // rep(j,0,l)printf(\"%4d\",val[i][j]);\n // printf(\"\\n\");\n // }\n vector<pii> dp(l,pii(-100,0));\n ci=place[n].first;\n cj=place[n].second;\n assert(n==val[ci][cj]);\n dp[cj]=pii(0,0);\n if(isPrime[val[ci][cj]])dp[cj]=pii(1,val[ci][cj]);\n \n for(;ci+1<l;ci++){\n vector<pii> old(l,pii(-100,0));\n swap(old,dp);\n rep(j,0,l){\n for(int dj=-1;dj<=1;dj++){\n int nj=j+dj;\n if(nj<0||nj>=l)continue;\n int v=val[ci+1][nj];\n if(isPrime[v]){\n dp[nj]=max(dp[nj],pii(old[j].first+1,v));\n }else{\n dp[nj]=max(dp[nj],pii(old[j].first,old[j].second));\n }\n }\n }\n }\n\n pii ans=pii(0,0);\n rep(j,0,l)ans=max(ans,dp[j]);\n cout<<ans.first<<\" \"<<ans.second<<endl;\n\n return 1;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 16176, "score_of_the_acc": -0.0743, "final_rank": 1 }, { "submission_id": "aoj_1189_10630546", "code_snippet": "//#pragma GCC optimize(\"O3\")\n#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,n) for (ll i=0;i<(ll)n;i++)\n#define rrep(i,n) for (ll i=n-1;i>=(ll)0;i--)\n#define loop(i,m,n) for(ll i=m;i<=(ll)n;i++)\n#define rloop(i,m,n) for(ll i=m;i>=(ll)n;i--)\n#define vl vector<ll>\n#define vvl vector<vector<ll>>\n#define vdbg(a) rep(ii,a.size()){cout<<a[ii]<<\" \";}cout<<endl;\n#define vpdbg(a) rep(ii,a.size()){cout<<\"{\"<<a[ii].first<<\",\"<<a[ii].second<<\"} \";}cout<<endl;\n#define vvdbg(a) rep(ii,a.size()){rep(jj,a[ii].size()){cout<<a[ii][jj]<<\" \";}cout<<endl;}\n#define setdbg(a) for(const auto & ii:a){cout<<ii<<\" \";}cout<<endl;\n#define inf 1e9\n#define mod 998244353LL\n//#define mod 1000000007LL\n#define eps 0.000000001\nrandom_device rnd;// 非決定的な乱数生成器\nmt19937 mt(rnd());// メルセンヌ・ツイスタの32ビット版、引数は初期シード\n\n//#include<boost/multiprecision/cpp_int.hpp>\n//#define bbi boost::multiprecision::cpp_int\n//#include<atcoder/lazysegtree>\n\n\n//整数同士の累乗の計算をする。\nll power(ll A, ll B) {\n\tll result = 1;\n\tfor (ll i=0;i<B;i++){\n\t\tresult *= A;\n\t}\n\treturn result;\n}\n\n// nのk乗をmodで割った余りを計算\nll power_mod(ll n, ll k){\n\tlong long result = 1;\n\twhile (k > 0){\n\t\tif ((k&1) ==1)result=(result*n)%mod;\n\t\tn=n*n%mod;\n\t\tk >>= 1;\n\t}\n\treturn result;\n}\n\n\n//受け取った2次元文字の外側に、文字pをコーティングする。\nvector<string> pad(vector<string> &s,char p){\n\tll h=s.size();\n\tll w=s[0].size();\n\tvector<string> res(h+2,string(w+2,p));\n\trep(i,h)rep(j,w)res[i+1][j+1]=s[i][j];\n\treturn res;\n}\n\n// Union-Find\nstruct UnionFind {\n\tvector<int> par, siz;\n\tUnionFind(int n) : par(n, -1) , siz(n, 1) { }\n\t// 根を求める\n\tint root(int x) {\n\t\tif (par[x] == -1) return x;\n\t\telse return par[x] = root(par[x]);\n\t}\n\t// x と y が同じグループに属するかどうか (根が一致するかどうか)\n\tbool issame(int x, int y) {\n\t\treturn root(x) == root(y);\n\t}\n\t// x を含むグループと y を含むグループとを併合する\n\tbool unite(int x, int y) {\n\t\tx = root(x), y = root(y);\n\t\tif (x == y) return false; \n\t\tif (siz[x] < siz[y]) swap(x, y);\n\t\tpar[y] = x;\n\t\tsiz[x] += siz[y];\n\t\treturn true;\n\t}\n\t// x を含むグループのサイズ\n\tint size(int x) {\n\t\treturn siz[root(x)];\n\t}\n};\n\n\n//グリッド問題等用\nvl dx={1,0,-1,0};\nvl dy={0,1,0,-1};\nvvl g(1000001);\nvector<bool> e(1000001,true);\n\nll solve(){\n\tll m,n;\n\tcin>>m>>n;\n\tif(m==0&&n==0){return 1;}\n\t\n\tpair<ll,ll> ans={0,0};\n\tvl dp(m+1,0);\n\tqueue<ll> qu;\n\tvector<bool> f(m+1,false);\n\tqu.push(n);\n\twhile(!qu.empty()){\n\t\tll tmp=qu.front();\n\t\tqu.pop();\n\t\t\n\t\tif(f[tmp])continue;\n\t\tf[tmp]=true;\n\n\t\tif(e[tmp]){\n\t\t\tdp[tmp]++;\n\t\t\tans=max(ans,{dp[tmp],tmp});\n\t\t}\n\n\t\trep(i,g[tmp].size()){\n\t\t\tif(g[tmp][i]>m)continue;\n\t\t\tdp[g[tmp][i]]=max(dp[g[tmp][i]],dp[tmp]);\n\t\t\tqu.push(g[tmp][i]);\n\t\t}\n\t}\n\tcout<<ans.first<<\" \"<<ans.second<<endl;\n\t//vdbg(g[37]);\n\treturn 0;\n}\n\n//メイン\nint main(){\n\t\n\tvvl mp(2000,vl(2000,inf));\n\tvector<pair<ll,ll>> inv(1010000);\n\tll cnt=1;\n\tpair<ll,ll> zahyou={1000,1000};\n\trep(i,inf){\n\t\t//右\n\t\trep(j,2*i+1){\n\t\t\tmp[zahyou.first][zahyou.second]=cnt;\n\t\t\tinv[cnt]=zahyou;\n\t\t\tzahyou.first++;\n\t\t\tcnt++;\n\t\t}\n\t\t//上\n\t\trep(j,2*i+1){\n\t\t\tmp[zahyou.first][zahyou.second]=cnt;\n\t\t\tinv[cnt]=zahyou;\n\t\t\tzahyou.second--;\n\t\t\tcnt++;\n\t\t}\n\t\t//左\n\t\trep(j,2*i+2){\n\t\t\tmp[zahyou.first][zahyou.second]=cnt;\n\t\t\tinv[cnt]=zahyou;\n\t\t\tzahyou.first--;\n\t\t\tcnt++;\n\t\t}\n\t\t//下\n\t\trep(j,2*i+2){\n\t\t\tmp[zahyou.first][zahyou.second]=cnt;\n\t\t\tinv[cnt]=zahyou;\n\t\t\tzahyou.second++;\n\t\t\tcnt++;\n\t\t}\n\t\tif(cnt>1000000)break;\n\t}\n\n\tloop(i,1,1000000){\n\t\tpair<ll,ll> xy=inv[i];\n\t\t\n\t\txy.second++;\n\t\txy.first--;\n\t\t\n\t\trep(j,3){\n\t\t\t//次があるなら\n\t\t\tif(mp[xy.first][xy.second]!=inf){\n\t\t\t\tg[i].push_back(mp[xy.first][xy.second]);\n\t\t\t}\n\t\t\txy.first++;\n\t\t}\n\t}\n\t\n\te[0]=false;\n\te[1]=false;\n\tloop(i,2,1000000){\n\t\tif(!e[i])continue;\n\t\tfor(ll j=i*i;j<=1000000;j+=i){\n\t\t\te[j]=false;\n\t\t}\n\t}\n\n\twhile(solve()==0);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 128476, "score_of_the_acc": -1.0955, "final_rank": 16 }, { "submission_id": "aoj_1189_10555142", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define all(a) (a).begin(), (a).end()\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rrep(i, n) for (int i = (int)(n); i >= 0; i--)\n#define range(i, l, r) for (int i = (int)(l); i < (int)(r); i++)\nusing ll = long long;\n\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v) {\n os << \"[\";\n for (int i = 0; i < v.size(); i++) {\n os << v[i] << (i == (v.size() - 1) ? \"\" : \", \");\n }\n os << \"]\";\n return os;\n}\n\ntemplate <typename T1, typename T2>\nostream& operator<<(ostream& os, const pair<T1, T2> p) {\n os << \"{\" << p.first << \", \" << p.second << \"}\";\n return os;\n}\n\npair<int, int> enc(int n) {\n if (n == 1) {\n return {0, 0};\n }\n int d = 1;\n n -= 2;\n while (n >= 8 * d) {\n n -= 8 * d;\n d++;\n }\n\n if (n < 2 * d) {\n return {d, -d + n + 1};\n } else if (n < 4 * d) {\n n -= 2 * d;\n return {d - 1 - n, d};\n } else if (n < 6 * d) {\n n -= 4 * d;\n return {-d, d - 1 - n};\n } else {\n n -= 6 * d;\n return {-d + n + 1, -d};\n }\n}\n\nint dec(int i, int j) {\n if (i == 0 && j == 0) return 1;\n int d = max(abs(i), abs(j));\n int base = pow(2 * d - 1, 2);\n if (i == d && j > -d) {\n return base + j + d;\n } else if (j == d) {\n return base + 2 * d + d - i;\n } else if (i == -d) {\n return base + 4 * d + d - j;\n } else {\n return base + 6 * d + i + d;\n }\n}\n\nmap<int, pair<int, int>> dp, ep;\n#include <cassert>\n\nint main() {\n int mx = 1000001;\n vector<int> min_factor(mx, 0);\n rep(i, mx) min_factor[i] = i;\n min_factor[0] = -1;\n min_factor[1] = -1;\n range(i, 2, mx) {\n if (min_factor[i] != i) continue;\n int j = i;\n while (j < mx) {\n min_factor[j] = i;\n j += i;\n }\n }\n\n while (true) {\n int m, n;\n cin >> m >> n;\n if (m == 0) break;\n dp.clear();\n ep.clear();\n\n pair<int, int> ans;\n if (min_factor[n] == n) {\n dp[n] = {1, n};\n ans = {1, n};\n } else {\n dp[n] = {0, 0};\n ans = {0, 0};\n }\n\n while (!dp.empty()) {\n ep.clear();\n for (auto [n, p] : dp) {\n auto [i, j] = enc(n);\n int nj = j - 1;\n range(ni, i - 1, i + 2) {\n int nn = dec(ni, nj);\n if (nn > m) continue;\n pair<int, int> val;\n if (min_factor[nn] == nn) {\n val = {p.first + 1, nn};\n } else {\n val = p;\n }\n ans = max(ans, val);\n if (ep.find(nn) == ep.end()) {\n ep[nn] = val;\n } else {\n ep[nn] = max(ep[nn], val);\n }\n }\n }\n swap(ep, dp);\n }\n cout << ans.first << \" \" << ans.second << endl;\n }\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 7100, "score_of_the_acc": -0.1224, "final_rank": 2 }, { "submission_id": "aoj_1189_10404779", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\nint w = 1100;\n\nvector<int> dx = {-1, 0, 1, 0};\nvector<int> dy = {0, 1, 0, -1};\nconst int INF = 2e9;\n\nvector<bool> sieve(int n)\n{\n vector<bool> is_prime(n + 1);\n for (int i = 0; i <= n; i++) is_prime[i] = true;\n is_prime[0] = is_prime[1] = false;\n for (int i = 2; i <= n; i++) {\n if (is_prime[i]) {\n for (int j = 2 * i; j <= n; j += i) is_prime[j] = false;\n }\n }\n return is_prime;\n}\n\nint main()\n{\n while (true) {\n int m, n;\n cin >> m >> n;\n if (m == 0) break;\n\n vector<vector<int>> grid(w, vector<int>(w, 0));\n vector<pair<int, int>> ma(m + 1);\n\n int dir = 2;\n int cur = 1, row = w / 2, col = w / 2;\n\n int mr = 0, mc = 0;\n while (true) {\n if (cur > m) break;\n\n grid[row][col] = cur;\n ma[cur] = {row, col};\n mr = max(mr, row);\n mc = max(mc, col);\n cur++;\n\n int nx = row + dx[(dir - 1 + 4) % 4];\n int ny = col + dy[(dir - 1 + 4) % 4];\n if (grid[nx][ny] == 0) { dir = (dir - 1 + 4) % 4; }\n\n row = row + dx[dir], col = col + dy[dir];\n }\n\n // for (int i = 5;i < 15;i++) {\n // for (int j = 5;j < 15;j++) {\n // cout << grid[i][j] << \" \";\n // }\n // cout << endl;\n // }\n\n auto is_prime = sieve(m + 1);\n vector<vector<int>> dp(w, vector<int>(w, -1));\n vector<vector<int>> lprime(w, vector<int>(w, 0));\n\n auto& [sr, sc] = ma[n];\n dp[sr][sc] = is_prime[grid[sr][sc]];\n lprime[sr][sc] = (is_prime[grid[sr][sc]] ? n : 0);\n\n for (int i = sr; i < mr; i++) {\n for (int j = 0; j < w; j++) {\n if (dp[i][j] != -1) {\n if (dp[i + 1][j] < dp[i][j] + is_prime[grid[i + 1][j]]) {\n dp[i + 1][j] = max(dp[i + 1][j],dp[i][j] + is_prime[grid[i + 1][j]]);\n lprime[i + 1][j] = (is_prime[grid[i + 1][j]] ? grid[i + 1][j]: lprime[i][j]);\n }\n }\n if (j - 1 >= 0 && dp[i][j - 1] != -1) {\n if (dp[i + 1][j] < dp[i][j - 1] + is_prime[grid[i + 1][j]]) {\n dp[i + 1][j] = max(dp[i + 1][j],dp[i][j - 1] + is_prime[grid[i + 1][j]]);\n lprime[i + 1][j] = (is_prime[grid[i + 1][j]] ? grid[i + 1][j]:lprime[i][j - 1]);\n }\n }\n if (j + 1 < w && dp[i][j + 1] != -1) {\n if (dp[i + 1][j] < dp[i][j + 1] + is_prime[grid[i + 1][j]]) {\n dp[i + 1][j] = dp[i][j + 1] + is_prime[grid[i + 1][j]];\n lprime[i + 1][j] = (is_prime[grid[i + 1][j]] ? grid[i + 1][j]: lprime[i][j + 1]);\n }\n }\n }\n }\n\n // cout << endl;\n // for (int i = 5;i < 15;i++) {\n // for (int j = 5;j < 15;j++) {\n // cout << dp[i][j] << \" \";\n // }\n // cout << endl;\n // }\n\n int ans = 0;\n int lp = 0;\n for (int j = 0; j < w; j++) {\n if (ans < dp[mr][j]) {\n ans = dp[mr][j];\n lp = lprime[mr][j];\n }else if (ans == dp[mr][j]) {\n if (lp < lprime[mr][j]) {\n lp = lprime[mr][j];\n }\n }\n }\n cout << ans << \" \" << lp << endl;\n }\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 25596, "score_of_the_acc": -0.284, "final_rank": 6 }, { "submission_id": "aoj_1189_10217256", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<long long, long long>;\n#define rep(i, a, b) for(long long i = (a); i < (b); ++i)\n#define rrep(i, a, b) for(long long i = (a); i >= (b); --i)\nconstexpr long long inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\nstruct EratosthenesSieve {\n vector<int> primes, min_factor, moebius, euler;\n EratosthenesSieve(const int n)\n : primes(), min_factor(n + 1), moebius(n + 1, 1), euler(n + 1) {\n assert(n >= 1);\n iota(min_factor.begin(), min_factor.end(), 0);\n min_factor[0] = min_factor[1] = -1;\n iota(euler.begin(), euler.end(), 0);\n for(int i = 2; i <= n; ++i) {\n if(min_factor[i] < i) continue;\n primes.emplace_back(i);\n moebius[i] = -1;\n euler[i] = euler[i] / i * (i - 1);\n for(int j = i * 2; j <= n; j += i) {\n if(min_factor[j] == j) min_factor[j] = i;\n if((j / i) % i == 0) moebius[j] = 0;\n else moebius[j] = -moebius[j];\n euler[j] = euler[j] / i * (i - 1);\n }\n }\n }\n};\nint main(void) {\n constexpr int sz = 1001;\n vector<vector<int>> num(sz, vector<int>(sz));\n int i = sz / 2, j = sz / 2, cur = 1;\n rep(k, 1, inf) {\n rep(_, 0, k) {\n num[i][j] = cur++;\n if(k % 2 == 1) j++;\n else j--;\n }\n if(cur > sz * sz) break;\n rep(_, 0, k) {\n num[i][j] = cur++;\n if(k % 2 == 1) i--;\n else i++;\n }\n }\n EratosthenesSieve sieve(sz * sz + 1);\n while(1) {\n int m, n;\n cin >> m >> n;\n if(m == 0 and n == 0) break;\n int si = -1, sj = -1;\n rep(i, 0, sz) {\n rep(j, 0, sz) {\n if(num[i][j] == n) {\n si = i;\n sj = j;\n }\n }\n }\n assert(si != -1 and sj != -1);\n vector<vector<pair<int, int>>> dp(sz, vector<pair<int, int>>(sz, {-1, -1}));\n dp[si][sj].first = sieve.min_factor[num[si][sj]] == num[si][sj];\n if(dp[si][sj].first == 0) dp[si][sj].second = 0;\n else dp[si][sj].second = num[si][sj];\n queue<pair<int, int>> que;\n que.push({si, sj});\n while(!que.empty()) {\n auto [i, j] = que.front();\n que.pop();\n rep(dj, -1, 2) {\n int ni = i + 1, nj = j + dj;\n if(0 <= ni and ni < sz and 0 <= nj and nj < sz and num[ni][nj] <= m) {\n if(dp[ni][nj].first == -1) que.push({ni, nj});\n if(dp[i][j].first + (sieve.min_factor[num[ni][nj]] == num[ni][nj]) > dp[ni][nj].first) {\n dp[ni][nj] = {dp[i][j].first + (sieve.min_factor[num[ni][nj]] == num[ni][nj]), dp[i][j].second};\n if(sieve.min_factor[num[ni][nj]] == num[ni][nj]) {\n dp[ni][nj].second = num[ni][nj];\n }\n } else if(dp[i][j].first + (sieve.min_factor[num[ni][nj]] == num[ni][nj]) == dp[ni][nj].first and dp[i][j].second > dp[ni][nj].second) {\n dp[ni][nj] = {dp[i][j].first + (sieve.min_factor[num[ni][nj]] == num[ni][nj]), dp[i][j].second};\n if(sieve.min_factor[num[ni][nj]] == num[ni][nj]) {\n dp[ni][nj].second = num[ni][nj];\n }\n }\n }\n }\n }\n pair<int, int> ans = {0, 0};\n rep(i, 0, sz) rep(j, 0, sz) ans = max(ans, dp[i][j]);\n cout << ans.first << ' ' << ans.second << '\\n';\n }\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 27276, "score_of_the_acc": -0.308, "final_rank": 8 }, { "submission_id": "aoj_1189_9821420", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int dx[4] = {0, -1, 0, 1};\nconst int dy[4] = {1, 0, -1, 0};\nbool isprime[1 << 20];\nint cell[1209][1209];\npair<int, int> dp[1209][1209];\n\nvoid Initialize() {\n\tfor (int i = 2; i <= 1000000; i++) isprime[i] = true;\n\tfor (int i = 2; i <= 1000000; i++) {\n\t\tfor (int j = 2 * i; j <= 1000000; j += i) isprime[j] = false;\n\t}\n}\n\npair<int, int> update(pair<int, int> initial, int pos) {\n\tif (isprime[pos] == false) return initial;\n\treturn make_pair(initial.first + 1, pos);\n}\n\npair<int, int> solve(int Num, int First) {\n\tfor (int i = 0; i <= 1200; i++) {\n\t\tfor (int j = 0; j <= 1200; j++) cell[i][j] = -1;\n\t\tfor (int j = 0; j <= 1200; j++) dp[i][j] = make_pair(-1000000, -1000000);\n\t}\n\n\t// Get Cell\n\tint sx = 600;\n\tint sy = 600;\n\tint dir = 0;\n\tfor (int i = 1; i <= Num; i++) {\n\t\tcell[sx][sy] = i;\n\t\tif (i == First) dp[sx][sy] = update(make_pair(0, 0), First);\n\t\tsx += dx[dir];\n\t\tsy += dy[dir];\n\t\tif (dir != 0) {\n\t\t\tif (abs(sx - 600) == abs(sy - 600)) dir = (dir + 1) % 4;\n\t\t}\n\t\telse {\n\t\t\tif (abs(sx - 600) + 1 == abs(sy - 600)) dir = (dir + 1) % 4;\n\t\t}\n\t}\n\n\t// Dynamic Programming\n\tpair<int, int> Answer = make_pair(0, 0);\n\tfor (int i = 1; i <= 1199; i++) {\n\t\tfor (int j = 1; j <= 1199; j++) {\n\t\t\tif (cell[i][j] == -1) continue;\n\t\t\tpair<int, int> v = max({dp[i - 1][j - 1], dp[i - 1][j], dp[i - 1][j + 1]});\n\t\t\tdp[i][j] = max(dp[i][j], update(v, cell[i][j]));\n\t\t\tAnswer = max(Answer, dp[i][j]);\n\t\t}\n\t}\n\n\t// Return\n\treturn Answer;\n}\n\nint main() {\n\tInitialize();\n\twhile (true) {\n\t\tint Num, First; cin >> Num >> First;\n\t\tif (Num == 0 && First == 0) break;\n\t\tpair<int, int> Answer = solve(Num, First);\n\t\tcout << Answer.first << \" \" << Answer.second << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 21384, "score_of_the_acc": -0.2292, "final_rank": 4 }, { "submission_id": "aoj_1189_9819674", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int dx[4] = {-1, 0, 1, 0};\nconst int dy[4] = {0, -1, 0, 1};\nbool isprime[1 << 20];\nint cell[1209][1209];\npair<int, int> dp[1209][1209];\n\nvoid Initialize() {\n\tfor (int i = 2; i <= 1000000; i++) isprime[i] = true;\n\tfor (int i = 2; i <= 1000000; i++) {\n\t\tfor (int j = 2 * i; j <= 1000000; j += i) isprime[j] = false;\n\t}\n}\n\npair<int, int> Solve(int Num, int Fst) {\n\tfor (int i = 0; i <= 1200; i++) {\n\t\tfor (int j = 0; j <= 1200; j++) cell[i][j] = -1;\n\t}\n\tcell[600][600] = 1;\n\tint sx = 600;\n\tint sy = 601;\n\tint dir = 0;\n\tfor (int i = 2; i <= Num; i++) {\n\t\tcell[sx][sy] = i;\n\t\tsx += dx[dir];\n\t\tsy += dy[dir];\n\t\tif (dir != 3) {\n\t\t\tif (abs(sx - 600) == abs(sy - 600)) dir = (dir + 1) % 4;\n\t\t}\n\t\telse {\n\t\t\tif (abs(sx - 600) + 1 == abs(sy - 600)) dir = (dir + 1) % 4;\n\t\t}\n\t}\n\n\t// Dynamic Programming\n\tpair<int, int> Answer = make_pair(0, 0);\n\tfor (int i = 0; i <= 1200; i++) {\n\t\tfor (int j = 0; j <= 1200; j++) {\n\t\t\tdp[i][j] = make_pair(-1000000, -1000000);\n\t\t\tif (cell[i][j] == Fst) {\n\t\t\t\tif (isprime[Fst] == true) dp[i][j] = make_pair(1, Fst);\n\t\t\t\telse dp[i][j] = make_pair(0, 0);\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = 1; i <= 1199; i++) {\n\t\tfor (int j = 1; j <= 1199; j++) {\n\t\t\tAnswer = max(Answer, dp[i][j]);\n\t\t\tif (cell[i + 1][j - 1] != -1) {\n\t\t\t\tpair<int, int> nex = dp[i][j];\n\t\t\t\tif (isprime[cell[i + 1][j - 1]] == true) { nex.first += 1; nex.second = cell[i + 1][j - 1]; }\n\t\t\t\tdp[i + 1][j - 1] = max(dp[i + 1][j - 1], nex);\n\t\t\t}\n\t\t\tif (cell[i + 1][j] != -1) {\n\t\t\t\tpair<int, int> nex = dp[i][j];\n\t\t\t\tif (isprime[cell[i + 1][j]] == true) { nex.first += 1; nex.second = cell[i + 1][j]; }\n\t\t\t\tdp[i + 1][j] = max(dp[i + 1][j], nex);\n\t\t\t}\n\t\t\tif (cell[i + 1][j + 1] != -1) {\n\t\t\t\tpair<int, int> nex = dp[i][j];\n\t\t\t\tif (isprime[cell[i + 1][j + 1]] == true) { nex.first += 1; nex.second = cell[i + 1][j + 1]; }\n\t\t\t\tdp[i + 1][j + 1] = max(dp[i + 1][j + 1], nex);\n\t\t\t}\n\t\t}\n\t}\n\n\t// Return\n\treturn Answer;\n}\n\nint main() {\n\tInitialize();\n\twhile (true) {\n\t\tint Num, First; cin >> Num >> First;\n\t\tif (Num == 0 && First == 0) break;\n\t\tpair<int, int> Answer = Solve(Num, First);\n\t\tcout << Answer.first << \" \" << Answer.second << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 21508, "score_of_the_acc": -0.2812, "final_rank": 5 }, { "submission_id": "aoj_1189_9555437", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint dx[4] = {1,0,-1,0}, dy[4] = {0,1,0,-1};\n\nint main() {\n bool Prime[1000001] = {};\n rep(i,0,1000001) Prime[i] = true;\n Prime[0] = Prime[1] = false;\n rep(i,2,1000001) {\n if (Prime[i]) {\n for (int j = 2; i * j <= 1000000; j++) {\n Prime[i*j] = false;\n }\n }\n }\n int MAXS = 1010;\n int Cave[MAXS][MAXS] = {};\n int X = MAXS/2, Y = MAXS/2, P = 1;\n Cave[X][Y] = P;\n rep(i,0,3000) {\n int dir = i % 4;\n rep(j,0,(i+2)/2) {\n X += dx[dir], Y += dy[dir], P++;\n if (P > 1000000) break;\n Cave[X][Y] = P;\n }\n if (P > 1000000) break;\n }\nwhile(1) {\n int N, M;\n cin >> N >> M;\n if (N == 0 && M == 0) return 0;\n vector<vector<int>> ANS(MAXS, vector<int>(MAXS,-inf));\n rep(i,0,MAXS) {\n rep(j,0,MAXS) {\n if (Cave[i][j] == M) {\n ANS[i][j] = 0;\n }\n }\n }\n rrep(j,0,MAXS-1) {\n rep(i,1,MAXS-1) {\n if (Cave[i][j] == 0 || N < Cave[i][j]) continue;\n chmax(ANS[i][j], ANS[i-1][j+1]);\n chmax(ANS[i][j], ANS[i][j+1]);\n chmax(ANS[i][j], ANS[i+1][j+1]);\n if (Prime[Cave[i][j]]) ANS[i][j]++;\n }\n }\n int ANSX = 0, ANSY = 0;\n rep(i,0,MAXS) {\n rep(j,0,MAXS) {\n if (ANS[i][j] <= 0) continue;\n if (!Prime[Cave[i][j]]) continue;\n if (ANS[i][j] > ANSX) ANSX = ANS[i][j], ANSY = Cave[i][j];\n else if (ANS[i][j] == ANSX) chmax(ANSY, Cave[i][j]);\n }\n }\n cout << ANSX << ' ' << ANSY << endl;\n}\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 12476, "score_of_the_acc": -0.1358, "final_rank": 3 }, { "submission_id": "aoj_1189_9409642", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing pll = pair<ll,ll>;\nusing plll = pair<pll,ll>;\nusing pii =pair<int,int>;\n\nconstexpr ll mod = 998244353;\n\nint dx[4]={0,-1,0,1};\nint dy[4]={1,0,-1,0};\n\nint dX[4]={0,-1,0,1};\nint dY[4]={1,0,-1,0};\n\n//library\n\n\n//end\n\n\n\n\n\nint main(){\n int max_n=1000005;\n vector<int> A(max_n,-1);\n\n\n for (int i=2; i<max_n; i++){\n if (A[i]==-1){\n for (int s=2; s<max_n; s++){\n if (i*s>=max_n)break;\n if (A[i*s]==-1)A[i*s]=i;\n }\n }\n }\n\n int N=1100;\n vector<vector<int>>F(N,vector<int>(N,0));\n vector<vector<int>>num(N,vector<int>(N,0));\n map<int,pii> invnow;\n int x=550, y=550,now=1;\n num[x][y]=1;\n invnow[now]=make_pair(x,y);\n\n int len=0;\n for (int i=0; i<2000; i++){\n if (i%2==0)len++;\n int d=i%4;\n for (int j=0; j<len; j++){\n x=x+dx[d];\n y=y+dy[d];\n now++;\n num[x][y]=now;\n invnow[now]=make_pair(x,y);\n if (now>=max_n) goto end;\n if (A[now]==-1)F[x][y]=1;\n }\n }\n\n end:;\n\n\n\n while (true){\n int m,n;\n cin>>m>>n;\n if (m==0)break;\n vector<vector<pii>> dp(N,vector<pii>(N,make_pair(-1,-1)));\n auto [x,y]=invnow[n];\n dp[x][y]=make_pair(0,-1);\n if (F[x][y]) dp[x][y]=make_pair(1,n);\n queue<int> que;\n que.push(n);\n\n pii ans=make_pair(0,0);\n set<int> dist;\n while (que.size()>0){\n n=que.front();\n //cout<<n<<' ';\n que.pop();\n if (dist.count(n)>0)continue;\n dist.insert(n);\n auto [x,y]=invnow[n];\n if (ans.first<dp[x][y].first){\n ans=dp[x][y];\n }\n if (ans.first==dp[x][y].first && ans.second<dp[x][y].second){\n ans=dp[x][y];\n }\n\n\n for (int d=-1; d<2; d++){\n int nx=x+1, ny=y+d;\n if (nx>=num.size() || ny<0)continue;\n if (num[nx][ny]>m)continue;\n\n int f=F[nx][ny], pre=dp[x][y].second;\n if (f>0)pre=num[nx][ny];\n\n if (dp[nx][ny].first<dp[x][y].first+f){\n dp[nx][ny]=make_pair(dp[x][y].first+f, pre);\n que.push(num[nx][ny]);\n }\n if (dp[nx][ny].first==dp[x][y].first+f && dp[nx][ny].second<pre){\n dp[nx][ny]=make_pair(dp[x][y].first+f, pre);\n que.push(num[nx][ny]);\n }\n }\n\n }\n\n cout<<ans.first<<' '<<ans.second<<endl;\n\n\n\n\n }\n\n}", "accuracy": 1, "time_ms": 600, "memory_kb": 116760, "score_of_the_acc": -1.4996, "final_rank": 18 }, { "submission_id": "aoj_1189_9373867", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (long long i = 0; i < (long long)(n); i++)\n#define rrep(i,start,end) for (long long i = start;i >= (long long)(end);i--)\n#define repn(i,end) for(long long i = 0; i <= (long long)(end); i++)\n#define reps(i,start,end) for(long long i = start; i < (long long)(end); i++)\n#define repsn(i,start,end) for(long long i = start; i <= (long long)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\ntypedef vector<long long> vll;\ntypedef vector<pair<long long ,long long>> vpll;\ntypedef vector<vector<long long>> vvll;\ntypedef set<ll> sll;\ntypedef map<long long , long long> mpll;\ntypedef pair<long long ,long long> pll;\ntypedef tuple<long long , long long , long long> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (int)x.size()\n// << std::fixed << std::setprecision(10)\nconst int INF = 1LL << 30;\nconst ld EPS = 1e-9;\n \ninline ll lfloor(ll x,ll m){return (x - ((x % m+ m)%m))/m;}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\n// for AOJ or ICPC or etc..\n// 全部が0だったらtrueを返す\ntemplate<class Tp> bool zero (const Tp &x) {return x == 0;}\ntemplate<class Tp, class... Args> bool zero (const Tp &x, const Args& ...args) {return zero(x) and zero(args...);}\n\n//https://drken1215.hatenablog.com/entry/2023/05/23/233000\n// A^N mod M\ntemplate<class T> T pow_mod(T A, T N, T M) {\n T res = 1 % M;\n A %= M;\n while (N) {\n if (N & 1) res = (res * A) % M;\n A = (A * A) % M;\n N >>= 1;\n }\n return res;\n}\n\nbool MillerRabin(long long N, vector<long long> A) {\n long long s = 0, d = N - 1;\n while (d % 2 == 0) {\n ++s;\n d >>= 1;\n }\n for (auto a : A) {\n if (N <= a) return true;\n long long t, x = pow_mod<__int128_t>(a, d, N);\n if (x != 1) {\n for (t = 0; t < s; ++t) {\n if (x == N - 1) break;\n x = __int128_t(x) * x % N;\n }\n if (t == s) return false;\n }\n }\n return true;\n}\n\nbool is_prime(long long N) {\n if (N <= 1) return false;\n if (N == 2) return true;\n if (N % 2 == 0) return false;\n if (N < 4759123141LL)\n return MillerRabin(N, {2, 7, 61});\n else\n return MillerRabin(N, {2, 325, 9375, 28178, 450775, 9780504, 1795265022});\n}\n\nmap<pair<int,int>,int> mp;\nint lim = lpow(10,6);\nvector<vector<int>> g;\nvector<int> ord;\n\nvoid pre(){\n mp[{0,0}] = 1;\n mp[{0,1}] = 0;\n pll lst = {0,1};\n repsn(i,3,lim){\n auto[y,x] = lst;\n ll d = mp[{y,x}];\n if(d == 0){\n //右\n if(!mp.count({y-1,x})){\n lst = {y-1,x};\n mp[{y-1,x}] = 1;\n }else{\n lst = {y,x+1};\n mp[{y,x+1}] = 0;\n }\n }else if(d == 1){\n //上\n if(!mp.count({y,x-1})){\n lst = {y,x-1};\n mp[{y,x-1}] = 2;\n }else{\n lst = {y-1,x};\n mp[{y-1,x}] = 1;\n }\n }else if(d == 2){\n //左\n if(!mp.count({y+1,x})){\n lst = {y+1,x};\n mp[{y+1,x}] = 3;\n }else{\n lst = {y,x-1};\n mp[{y,x-1}] = 2;\n }\n }else{\n //下\n if(!mp.count({y,x+1})){\n lst = {y,x+1};\n mp[{y,x+1}] = 0;\n }else{\n lst = {y+1,x};\n mp[{y+1,x}] = 3;\n }\n }\n mp[{y,x}] = i-1;\n }\n mp[lst] = lim;\n // cerr << \"here\" << endl;\n\n g.resize(lim+1);\n each(p,mp){\n auto[y,x] = p.first;\n ll i = p.second;\n if(mp.count({y+1,x+1})){\n g[i].push_back(mp[{y+1,x+1}]);\n }\n if(mp.count({y+1,x})){\n g[i].push_back(mp[{y+1,x}]);\n }\n if(mp.count({y+1,x-1})){\n g[i].push_back(mp[{y+1,x-1}]);\n }\n }\n // cerr <<\"here\" << endl;\n //隣接リストgを利用,n頂点\n auto topological_sort = [](vector<vector<int>> &g,ll n){\n vector<int> topological_order;\n \n vector<int> in_cnt(n);//入次数\n rep(i,n){\n for(ll p : g[i]){\n in_cnt[p]++;\n }\n }\n queue<int> que;\n //始点入れる\n rep(i,n){\n if(in_cnt[i] == 0){\n que.push(i);\n }\n }\n \n while(!que.empty()){\n ll now = que.front();\n que.pop();\n topological_order.push_back(now);\n for(ll p :g[now]){\n if(in_cnt[p] > 0){\n in_cnt[p]--;\n if(in_cnt[p] == 0){\n que.push(p);\n }\n }\n }\n }\n return topological_order;\n };\n ord = topological_sort(g,lim+1);\n mp.clear();\n\n}\n\n// 変数をちゃんと全部受け取る!\nvoid solve(ll m,ll n){\n //nから始めるm以上は通れない\n vector<pair<int,int>> dp(lim+1,{-INF,-INF});//個数、最後\n dp[n] = {0,0};\n rep(z,lim+1){\n ll i = ord[z];\n if(i > m)continue;\n if(dp[i].first < 0)continue;\n //自分が素数なら追加\n if(is_prime(i)){\n dp[i].first++;\n dp[i].second = i;\n }\n each(p,g[i])if(p <= m){\n if(dp[p].first < dp[i].first){\n dp[p] = dp[i];\n }else if(dp[p].first == dp[i].first){\n if(dp[p].second < dp[i].second){\n dp[p] = dp[i];\n }\n }\n }\n }\n pll ret = *max_element(all(dp));\n if(ret.first < 0){\n cout << 0 << \" \" << 0 << endl;\n }else{\n cout << ret.first << \" \" << ret.second << endl;\n }\n}\n \nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n pre();\n while(true){\n LL(m,n);//変数数調整\n if(zero(m,n))break;\n solve(m,n);\n }\n}", "accuracy": 1, "time_ms": 990, "memory_kb": 129276, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_1189_9266412", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define rep(i,n) for(int i = 0;i < n;i++)\n\n#define int ll\n#define IMAX ((1 << 31) - 1)\n#define LMAX ((1LL << 63) - 1)\n\n#define MAX_H 1001LL\n\nvector<int> isPrime;\nvector<vector<int>> caves;\nmap<int,pair<int,int>> mp;\n\nvoid main_() {\n int n,m;\n cin >> m >> n;\n if(n == 0) exit(0);\n\n vector<vector<int>> dp(MAX_H, vector<int>(MAX_H, 0));\n\n int from_x = mp.at(n).first;\n int from_y = mp.at(n).second;\n\n auto primeInt = [&](int i, int j){\n if(caves[i][j] > m) return 0LL;\n return isPrime.at(caves[i][j]);\n };\n\n int l = from_x;\n int r = from_x + 1;\n dp[from_y][from_x] = isPrime.at(n);\n\n int ans = isPrime.at(n);\n int last = (isPrime.at(n) ? n : 0);\n for(int i = from_y; i < MAX_H - 1; i++){\n\n for(int j = l; j < r; j++){\n for(int k = -1; k <= 1; k++){\n if(j + k < 0 || j + k >= MAX_H) continue;\n dp[i+1][j + k] = max(dp[i+1][j + k], dp[i][j] + primeInt(i+1,j+k));\n\n if(dp[i+1][j+k] > ans){\n ans = dp[i+1][j+k];\n last = caves[i+1][j+k];\n } else if(dp[i + 1][j + k] == ans && primeInt(i+1,j+k)) {\n last = max(last, caves[i+1][j+k]);\n }\n }\n }\n l = max(l-1, 0LL);\n r = min(r + 1, MAX_H);\n }\n\n cout << ans << \" \" << last << endl;\n}\n\nsigned main() {\n const int MAX = MAX_H * MAX_H;\n isPrime.resize(MAX + 1, 1);\n isPrime[0] = false;\n isPrime[1] = false;\n for(int i = 2; i*i < MAX + 1; i++) {\n for(int j = i*i; j < MAX + 1; j += i) {\n isPrime.at(j) = false;\n }\n }\n\n caves.resize(MAX_H, vector<int>(MAX_H, 0));\n int dx[4] = {1, 0, -1, 0};\n int dy[4] = {0, -1, 0, 1};\n int dir = 3;\n int x = MAX_H / 2;\n int y = MAX_H / 2;\n\n\n for(int i = 1;i <= MAX; i++){\n\n caves[y][x] = i;\n mp[i] = make_pair(x,y);\n\n // 左確認\n {\n int left = (dir + 1) % 4;\n int nx = x + dx[left];\n int ny = y + dy[left];\n if(caves[ny][nx] == 0) dir = left;\n }\n\n x += dx[dir];\n y += dy[dir];\n }\n\n// cout << mp.at(7).first << \" \" << mp.at(7).second << endl;\n// cout << isPrime.at(45) << endl;\n\n while(1) main_();\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 89328, "score_of_the_acc": -1.071, "final_rank": 15 }, { "submission_id": "aoj_1189_9244183", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nbool isPrime(int x){\n if(x == 1) return false;\n for(int i = 2; i * i <= x; i++){\n if(x % i == 0) return false;\n }\n return true;\n}\n\nint main(){\n const int MAX_N = 1000;\n const int dr[4] = {1, 0, -1, 0};\n const int dc[4] = {0, 1, 0, -1};\n vector<vector<bool>> isp(MAX_N, vector<bool>(MAX_N));\n vector<vector<bool>> used(MAX_N, vector<bool>(MAX_N));\n vector<vector<int>> val(MAX_N, vector<int>(MAX_N));\n vector<pair<int, int>> idx(MAX_N * MAX_N + 10);\n {\n int r = 0, c = 0;\n int dir = 3;\n for(int i = 1000000; i >= 1; i--){\n isp[r][c] = isPrime(i);\n used[r][c] = 1;\n idx[i] = make_pair(r, c);\n val[r][c] = i;\n // if(i < 30){\n // cout << i << \" \" << val[r][c] << \" \";\n // }\n if(i >= 2){\n while(1){\n int nr = r + dr[dir], nc = c + dc[dir];\n bool flag = 1;\n if(nr < 0 || MAX_N <= nr || nc < 0 || MAX_N <= nc) flag = 0;\n else if(used[nr][nc]) flag = 0;\n if(flag){\n r = nr, c = nc;\n break;\n }\n else{\n dir = (dir + 3) % 4;\n }\n }\n }\n // if(i < 30){\n // cout << val[r][c] << endl;\n // }\n }\n }\n\n // for(int i = 495; i <= 505; i++){\n // for(int j = 495; j <= 505; j++){\n // cout << val[i][j] << \" \";\n // }\n // cout << endl;\n // }\n\n vector<vector<pair<int, int>>> memo(MAX_N, vector<pair<int, int>>(MAX_N, make_pair(-1, -1)));\n auto rec = [&](auto f, int r, int c, int m) -> pair<int, int> {\n if(r < 0 || MAX_N <= r || c < 0 || MAX_N <= c) return make_pair(0, 0);\n if(val[r][c] > m) return make_pair(0, 0);\n if(memo[r][c].first != -1) return memo[r][c];\n\n int bo = 0, num = 0;\n if(isp[r][c]){\n // cout << val[r][c];\n bo = 1, num = val[r][c];\n }\n pair<int, int> mx = make_pair(0, 0);\n mx = max(mx, f(f, r + 1, c - 1, m));\n mx = max(mx, f(f, r + 1, c , m));\n mx = max(mx, f(f, r + 1, c + 1, m));\n mx.first += bo;\n if(mx.second == 0) mx.second = num;\n return memo[r][c] = mx;\n };\n\n while(1){\n int M, N; cin >> M >> N;\n if(M == 0) break;\n auto [p, q] = idx[N];\n auto [a1, a2] = rec(rec, p, q, M);\n cout << a1 << \" \" << a2 << endl;\n for(int i = 0; i < MAX_N; i++){\n for(int j = 0; j < MAX_N; j++){\n memo[i][j] = make_pair(-1, -1);\n }\n }\n }\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 23220, "score_of_the_acc": -0.2952, "final_rank": 7 }, { "submission_id": "aoj_1189_9244099", "code_snippet": "#include<bits/stdc++.h>\n//#include <atcoder/all>\nusing namespace std;\n//using namespace atcoder;\n\n#define all(v) v.begin(),v.end()\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll=vector<ll>;\nusing vvll = vector<vector<ll>>;\nusing P = pair<ll,ll>;\nusing vp=vector<pair<ll, ll>>;\n//using mint=modint1000000007;\n//using mint=modint998244353;\n\nconst ll INF=1ll<<60;\nll mod10=1e9+7;\nll mod99=998244353;\nconst double PI = acos(-1);\n\n#define rep(i,n) for (ll i=0;i<n;++i)\n#define per(i,n) for(ll i=n-1;i>=0;--i)\n#define rep2(i,a,n) for (ll i=a;i<n;++i)\n#define per2(i,a,n) for (ll i=a;i>=n;--i)\n\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n\nvector<ll> dx={0,-1,0,1},dy={1,0,-1,0};\nll si=1002;\nvll pri(si*si+1);\nvvll A(si,vll(si,0));\nll N,M;\nmap<ll,P> mp;\n\nmap<P,P> mp2;\n\nP ch(P ma,P a){\n if(ma.first<a.first) return a;\n else if(ma.first==a.first) return{ma.first,max(ma.second,a.second)};\n return ma;\n}\nP dfs(ll nowi,ll nowj){\n if(mp2.count({nowi,nowj})) return mp2[{nowi,nowj}];\n P ma={-1,-1};\n if(pri[A[nowi][nowj]]==A[nowi][nowj]) ma={1,A[nowi][nowj]};\n ll p=pri[A[nowi][nowj]]==A[nowi][nowj];\n if(A[nowi+1][nowj]<=M){\n auto [a,b]=dfs(nowi+1,nowj);\n ma=ch(ma,{a+p,b});\n }\n if(nowj>0&&A[nowi+1][nowj-1]<=M){\n auto [a,b]=dfs(nowi+1,nowj-1);\n ma=ch(ma,{a+p,b});\n }\n if(nowj<si-1&&A[nowi+1][nowj+1]<=M){\n auto [a,b]=dfs(nowi+1,nowj+1);\n ma=ch(ma,{a+p,b});\n }\n\n //cout << A[nowi][nowj]<<\" \"<<ma.first << endl;\n \n return mp2[{nowi,nowj}]=ma;\n}\n\n\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n \n rep2(i,2,si*si+1){\n if(pri[i]>0) continue;\n ll j=1;\n while(i*j<=si*si) pri[i*j]=i,j++;\n }\n\n ll now=1;\n ll cnt=0;\n ll nowi=si/2,nowj=si/2;\n ll d=0;\n while(1){\n mp[now]={nowi,nowj};\n A[nowi][nowj]=now;\n ll toi=nowi+dx[d],toj=nowj+dy[d];\n if(!(toi<si&&toj<si)||A[toi][toj]>0){\n d=(d+3)%4;\n toi=nowi+dx[d],toj=nowj+dy[d];\n if(!(toi<si&&toj<si)||A[toi][toj]>0){\n toi=-1;\n }\n }\n\n if(toi==-1) break;\n now++;\n nowi=toi,nowj=toj;\n d=(d+1)%4;\n }\n\n\n while(1){\n cin>>M>>N;\n if(N==0&&M==0) break;\n mp2.clear();\n auto [a,b]=dfs(mp[N].first,mp[N].second);\n if(a==-1) a=0,b=0;\n cout<<a<<\" \"<<b<<endl;\n }\n}", "accuracy": 1, "time_ms": 730, "memory_kb": 128968, "score_of_the_acc": -1.7322, "final_rank": 19 }, { "submission_id": "aoj_1189_9112054", "code_snippet": "#include <bits/stdc++.h>\n\nint main() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n\n const int dx[4]{ 0, -1, 0, 1 };\n const int dy[4]{ 1, 0, -1, 0 };\n std::map<std::pair<int, int>, int> map;\n int x{}, y{}, d{3};\n for (int i{1} ; i <= 1000000 ; i++) {\n assert(map.find({ x, y }) == map.end());\n map[{ x, y }] = i;\n int nd{(d + 1) % 4};\n if (map.find({ x + dx[nd], y + dy[nd] }) == map.end()) {\n x += dx[nd];\n y += dy[nd];\n d = nd;\n }\n else {\n x += dx[d];\n y += dy[d];\n }\n }\n std::vector<std::pair<int, int>> rev(1000001);\n for (auto [p, i] : map) {\n rev[i] = p;\n }\n std::vector<bool> P(1000001, true);\n P[0] = P[1] = false;\n for (int i{2} ; i * i <= 1000000 ; i++) {\n if (P[i]) {\n for (int j{i + i} ; j <= 1000000 ; j += i) {\n P[j] = false;\n }\n }\n }\n while (true) {\n int n, m;\n std::cin >> m >> n;\n if (n == 0 and m == 0) break;\n std::vector<int> memo(m + 1, -1), last(m + 1);\n auto rec{[&](auto rec, int i) -> int {\n if (i > m) return -1;\n if (memo[i] != -1) return memo[i];\n memo[i] = 0;\n auto [x, y]{rev[i]};\n for (int d{-1} ; d <= 1 ; d++) {\n auto it{map.find({ x + 1, y + d })};\n if (it != map.end()) {\n int v{rec(rec, it->second)}; \n if (memo[i] < v) {\n memo[i] = v;\n last[i] = last[it->second];\n }\n else if (memo[i] == v) {\n last[i] = std::max(last[i], last[it->second]);\n }\n }\n }\n if (P[i]) {\n memo[i]++;\n if (last[i] == 0) {\n last[i] = i;\n }\n }\n return memo[i];\n }};\n rec(rec, n);\n // for (int i{1} ; i <= m ; i++) {\n // std::cout << i << \" -> \" << memo[i] << ' ' << last[i] << std::endl;\n // }\n \n std::cout << memo[n] << ' ' << last[n] << '\\n';\n }\n}", "accuracy": 1, "time_ms": 580, "memory_kb": 81380, "score_of_the_acc": -1.1896, "final_rank": 17 }, { "submission_id": "aoj_1189_9094656", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define ALL(v) v.begin(),v.end()\n#define dbg(x) cerr << #x << \": \" << x << endl\ntemplate<class F, class S>\nostream& operator<<(ostream& os, pair<F,S> p) {\n os << '(' << p.first << ',' << p.second << ')';\n return os;\n}\ntemplate<class Iter>\nvoid print(Iter beg, Iter end) {\n for (auto itr = beg; itr != end; ++itr) {\n cerr << *itr << ' ';\n }\n cerr << '\\n';\n}\nint MAX = 1e6;\nint dx[]={1,0,-1,0};\nint dy[]={0,-1,0,1};\n\npair<vector<vector<int>>, vector<pair<int,int>>> gen() {\n map<pair<int,int>, int> mp;\n int dir = 0;\n int len=1;\n int num = 2;\n mp[{0,0}] = 1;\n int x=0, y=0;\n int mx=0, my=0;\n while (num <= MAX) {\n for (int cnt=0; cnt < 2; ++cnt) {\n for (int i = 0; i < len; ++i) {\n x += dx[dir];\n y += dy[dir];\n mp[{x,y}] = num++;\n }\n dir = (dir + 1) % 4;\n }\n ++len;\n }\n vector<vector<int>> op(1e3+1, vector<int>(1e3+1, MAX+1));\n vector<pair<int,int>> inv(MAX+1);\n for (auto [p, id] : mp) {\n if (id > 1e6) continue;\n auto [x,y] = p;\n op[y+500][x+499] = id;\n inv[id] = {x+499, y+500};\n }\n return {op, inv};\n}\n\nint main() {\n auto [grid, inv] = gen();\n\n vector<bool> isPrime(MAX+1,true);\n isPrime[0] = isPrime[1] = false;\n for (int i = 2; i <= MAX; ++i) {\n if (isPrime[i]) {\n for (int j=i*2; j <= MAX; j+=i) {\n isPrime[j] = false;\n }\n }\n }\n\n while (true) {\n int m,n;\n cin >> m >> n;\n if (m+n == 0) break;\n map<pair<int, int>, int> dp;\n map<pair<int, int>, int> ndp;\n pair<int, int> ans;\n dp[inv[n]] = 0;\n while (!dp.empty())\n {\n for (auto &v : dp)\n {\n int x = v.first.first, y = v.first.second;\n if (isPrime[grid[y][x]])\n {\n ++v.second;\n ans = max(ans, make_pair(v.second, grid[y][x]));\n }\n int nx = x + 1, ny = y + 1;\n if ((0 <= nx && nx < 1e3 && 0 <= ny && ny < 1e3) && grid[ny][nx] <= m)\n {\n auto &tmp = ndp[{nx, ny}];\n tmp = max(tmp, v.second);\n }\n nx = x, ny = y + 1;\n if ((0 <= nx && nx < 1e3 && 0 <= ny && ny < 1e3) && grid[ny][nx] <= m)\n {\n auto &tmp = ndp[{nx, ny}];\n tmp = max(tmp, v.second);\n }\n nx = x - 1, ny = y + 1;\n if ((0 <= nx && nx < 1e3 && 0 <= ny && ny < 1e3) && grid[ny][nx] <= m)\n {\n auto &tmp = ndp[{nx, ny}];\n tmp = max(tmp, v.second);\n }\n }\n swap(dp, ndp);\n ndp.clear();\n }\n cout << ans.first << ' ' << ans.second << endl;\n }\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 89036, "score_of_the_acc": -0.9768, "final_rank": 14 }, { "submission_id": "aoj_1189_9090134", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n \n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vc<vv<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst double pi = 3.141592653589793;\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(long long y, long long x, long long H, long long W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\ntemplate<typename T> void view(const vv<T>& vv){ for(const auto& v : vv){ view(v); } }\n\nvc<bool> eratosthenes(int t){\n vc<bool> is_prime(t + 1, true);\n is_prime[0] = false; is_prime[1] = false;\n for (int i = 0; i <= t; i++){\n if (is_prime[i]){\n for (int q = i * 2; q <= t; q += i){\n is_prime[q] = false;\n }\n }\n }\n return is_prime;\n}\n\nvvi cave(2001, vi(2000, inf));\nauto is_prime = eratosthenes(4004004);\n\nvi dx = {0, -1, 0, 1}, dy = {1, 0, -1, 0};\n\nvoid init(){\n int si = 1000, sj = 1000;\n cave[si][sj] = 1;\n int k = 0, num = 2;\n for (int d = 1; d <= 2000; d++){\n rep(_, 2){\n rep(t, d){\n si += dx[k];\n sj += dy[k];\n cave[si][sj] = num;\n num++;\n }\n k = (k + 1) % 4;\n }\n }\n}\n\npair<int, int> solve(int M, int N){\n int si = 0, sj = 0;\n rep(i, 2000) rep(j, 2000) if (cave[i][j] == N){\n si = i;\n sj = j;\n break;\n }\n vvi dp(2000, vi(2000, -1));\n if (is_prime[N]) dp[si][sj] = 1;\n else dp[si][sj] = 0;\n pair<int, int> ans = {0, 0};\n if (is_prime[N]) ans = {1, N};\n rep(i, 1999) rep(j, 2000) if (dp[i][j] != -1){\n for (int nj = max(0ll, j - 1); nj <= min(1999ll, j + 1); nj++) if (cave[i + 1][nj] <= M){\n if (is_prime[cave[i + 1][nj]] && dp[i + 1][nj] < dp[i][j] + 1){\n dp[i + 1][nj] = dp[i][j] + 1;\n ans = max(ans, {dp[i + 1][nj], cave[i + 1][nj]});\n }\n if (!is_prime[cave[i + 1][nj]] && dp[i + 1][nj] < dp[i][j]){\n dp[i + 1][nj] = dp[i][j];\n }\n }\n }\n return ans;\n}\n\nint main(){\n vc<pair<int, int>> ans;\n init();\n while (true){\n int M, N; cin >> M >> N;\n if (M == 0) break;\n ans.push_back(solve(M, N));\n }\n for (auto x : ans) cout << x.first << \" \" << x.second << endl;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 35132, "score_of_the_acc": -0.658, "final_rank": 12 }, { "submission_id": "aoj_1189_9071438", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\npair<int, int> Solve(int N, int M, vector<bool> primes) {\n\tvector<vector<int>> Grid(1200, vector<int>(1200, 0));\n\n\t// Get Grid\n\tint sx = 600, ax = -1;\n\tint sy = 600, ay = -1;\n\tint cnt = 1;\n\tconst int dx[4] = {0, -1, 0, 1};\n\tconst int dy[4] = {1, 0, -1, 0};\n\tGrid[600][600] = 1;\n\tif (M == 1) { ax = 600; ay = 600; }\n\n\t// Grid Main\n\tfor (int r = 2; r < 5000; r++) {\n\t\tfor (int i = 0; i < r / 2; i++) {\n\t\t\tsx += dx[(r + 2) % 4];\n\t\t\tsy += dy[(r + 2) % 4];\n\t\t\tcnt += 1;\n\t\t\tGrid[sx][sy] = cnt;\n\t\t\tif (cnt == M) { ax = sx; ay = sy; }\n\t\t\tif (cnt == N) break;\n\t\t}\n\t\tif (cnt == N) break;\n\t}\n\n\t// Dynamic Programming\n\tvector<vector<pair<int, int>>> dp(1200, vector<pair<int, int>>(1200, make_pair(-1000000, -1)));\n\tfor (int i = 1; i <= 1198; i++) {\n\t\tfor (int j = 1; j <= 1198; j++) {\n\t\t\tif (Grid[i][j] == M) {\n\t\t\t\tdp[i][j] = make_pair(0, 0);\n\t\t\t\tif (primes[M] == true) dp[i][j] = make_pair(1, M);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tdp[i][j] = max({dp[i - 1][j - 1], dp[i - 1][j], dp[i - 1][j + 1]});\n\t\t\t\tif (primes[Grid[i][j]] == true) {\n\t\t\t\t\tdp[i][j].first += 1;\n\t\t\t\t\tdp[i][j].second = Grid[i][j];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\t// Return\n\tpair<int, int> Answer = make_pair(0, 0);\n\tfor (int i = 1; i <= 1198; i++) Answer = max(Answer, dp[1198][i]);\n\treturn Answer;\n}\n\nint main() {\n\tvector<bool> primes(1000001, true);\n\tprimes[0] = false;\n\tprimes[1] = false;\n\tfor (int i = 2; i <= 1000000; i++) {\n\t\tfor (int j = 2 * i; j <= 1000000; j += i) primes[j] = false;\n\t}\n\n\t// Simulation\n\twhile (true) {\n\t\tint N, M; cin >> N >> M;\n\t\tif (N == 0 && M == 0) break;\n\t\tpair<int, int> ret = Solve(N, M, primes);\n\t\tcout << ret.first << \" \" << ret.second << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 20260, "score_of_the_acc": -0.5465, "final_rank": 9 }, { "submission_id": "aoj_1189_9069513", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\npair<int, int> Solve(int N, int M, vector<bool> primes) {\n\tvector<vector<int>> Grid(1200, vector<int>(1200, 0));\n\tint sx = 600, ax = -1;\n\tint sy = 600, ay = -1;\n\tint cnt = 1;\n\tconst int dx[4] = {0, -1, 0, 1};\n\tconst int dy[4] = {1, 0, -1, 0};\n\tGrid[600][600] = 1;\n\tif (M == 1) { ax = 600; ay = 600; }\n\n\t// Get Grid\n\tfor (int r = 0; r <= 6000; r++) {\n\t\tfor (int i = 0; i < (r + 2) / 2; i++) {\n\t\t\tsx += dx[r % 4];\n\t\t\tsy += dy[r % 4];\n\t\t\tcnt += 1;\n\t\t\tGrid[sx][sy] = cnt;\n\t\t\tif (cnt == M) { ax = sx; ay = sy; }\n\t\t\tif (cnt == N) break;\n\t\t}\n\t\tif (cnt == N) break;\n\t}\n\n\t// Dynamic Programming\n\tvector<vector<pair<int, int>>> dp(1200, vector<pair<int, int>>(1200, make_pair(-1000000, -1)));\n\tfor (int i = 1; i <= 1198; i++) {\n\t\tfor (int j = 1; j <= 1198; j++) {\n\t\t\tif (i == ax && j == ay) {\n\t\t\t\tdp[i][j] = make_pair(0, 0);\n\t\t\t\tif (primes[M] == true) dp[i][j] = make_pair(1, M);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tdp[i][j] = max({dp[i - 1][j - 1], dp[i - 1][j], dp[i - 1][j + 1]});\n\t\t\t\tif (primes[Grid[i][j]] == true) {\n\t\t\t\t\tdp[i][j].first += 1;\n\t\t\t\t\tdp[i][j].second = Grid[i][j];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\t// Get Answer\n\tpair<int, int> Answer = make_pair(0, 0);\n\tfor (int i = 1; i <= 1198; i++) Answer = max(Answer, dp[1198][i]);\n\treturn Answer;\n}\n\nint main() {\n\tvector<bool> primes(1000001, true);\n\tprimes[0] = false;\n\tprimes[1] = false;\n\tfor (int i = 2; i <= 1000000; i++) {\n\t\tfor (int j = i * 2; j <= 1000000; j += i) primes[j] = false;\n\t}\n\n\t// Simulation\n\twhile (true) {\n\t\tint N, M; cin >> N >> M;\n\t\tif (N == 0 && M == 0) break;\n\t\tpair<int, int> ret = Solve(N, M, primes);\n\t\tcout << ret.first << \" \" << ret.second << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 480, "memory_kb": 20264, "score_of_the_acc": -0.5873, "final_rank": 10 }, { "submission_id": "aoj_1189_9066686", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int dx[4] = {0, -1, 0, 1};\nconst int dy[4] = {1, 0, -1, 0};\n\npair<int, int> Solve(int N, int M, vector<bool> primes) {\n\tvector<vector<int>> Grid(1200, vector<int>(1200, 0));\n\tint px = 600, sx = -1;\n\tint py = 600, sy = -1;\n\tint dir = 0;\n\tint cnt = 1;\n\tGrid[600][600] = 1;\n\n\t// Get Index\n\tfor (int loop = 1; loop <= 6000; loop++) {\n\t\tfor (int i = 0; i < (loop + 1) / 2; i++) {\n\t\t\tpx += dx[dir];\n\t\t\tpy += dy[dir];\n\t\t\tcnt += 1;\n\t\t\tGrid[px][py] = cnt;\n\t\t\tif (cnt == N) break;\n\t\t}\n\t\tdir = (dir + 1) % 4;\n\t\tif (cnt == N) break;\n\t}\n\tfor (int i = 1; i <= 1198; i++) {\n\t\tfor (int j = 1; j <= 1198; j++) {\n\t\t\tif (Grid[i][j] == M) { sx = i; sy = j; }\n\t\t}\n\t}\n\n\t// DP Main\n\tvector<vector<pair<int, int>>> dp(1200, vector<pair<int, int>>(1200, make_pair(-100000000, -1)));\n\tfor (int i = 1; i <= 1198; i++) {\n\t\tfor (int j = 1; j <= 1198; j++) {\n\t\t\tif (i == sx && j == sy) {\n\t\t\t\tif (primes[M] == true) dp[i][j] = make_pair(1, M);\n\t\t\t\telse dp[i][j] = make_pair(0, 0);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tdp[i][j] = max({dp[i - 1][j - 1], dp[i - 1][j], dp[i - 1][j + 1]});\n\t\t\t\tif (primes[Grid[i][j]] == true) {\n\t\t\t\t\tdp[i][j].first += 1;\n\t\t\t\t\tdp[i][j].second = Grid[i][j];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\t// Return\n\tpair<int, int> Answer = make_pair(0, 0);\n\tfor (int i = 1; i <= 1198; i++) Answer = max(Answer, dp[1198][i]);\n\treturn Answer;\n}\n\nint main() {\n\t// Step 1. Enumerate Primes\n\tvector<bool> primes(1000001, true);\n\tprimes[0] = false;\n\tprimes[1] = false;\n\tfor (int i = 2; i <= 1000000; i++) {\n\t\tfor (int j = i * 2; j <= 1000000; j += i) primes[j] = false;\n\t}\n\n\t// Step 2. Simulation\n\twhile (true) {\n\t\tint N, M; cin >> N >> M; if (N == 0 && M == 0) break;\n\t\tpair<int, int> ret = Solve(N, M, primes);\n\t\tcout << ret.first << \" \" << ret.second << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 490, "memory_kb": 20324, "score_of_the_acc": -0.598, "final_rank": 11 } ]
aoj_1190_cpp
Anchored Balloon A balloon placed on the ground is connected to one or more anchors on the ground with ropes. Each rope is long enough to connect the balloon and the anchor. No two ropes cross each other. Figure E-1 shows such a situation. Figure E-1: A balloon and ropes on the ground Now the balloon takes off, and your task is to find how high the balloon can go up with keeping the rope connections. The positions of the anchors are fixed. The lengths of the ropes and the positions of the anchors are given. You may assume that these ropes have no weight and thus can be straightened up when pulled to whichever directions. Figure E-2 shows the highest position of the balloon for the situation shown in Figure E-1. Figure E-2: The highest position of the balloon Input The input consists of multiple datasets, each in the following format. n x 1 y 1 l 1 ... x n y n l n The first line of a dataset contains an integer n (1 ≤ n ≤ 10) representing the number of the ropes. Each of the following n lines contains three integers, x i , y i , and l i , separated by a single space. P i = ( x i , y i ) represents the position of the anchor connecting the i -th rope, and l i represents the length of the rope. You can assume that −100 ≤ x i ≤ 100, −100 ≤ y i ≤ 100, and 1 ≤ l i ≤ 300. The balloon is initially placed at (0, 0) on the ground. You can ignore the size of the balloon and the anchors. You can assume that P i and P j represent different positions if i ≠ j . You can also assume that the distance between P i and (0, 0) is less than or equal to l i −1. This means that the balloon can go up at least 1 unit high. Figures E-1 and E-2 correspond to the first dataset of Sample Input below. The end of the input is indicated by a line containing a zero. Output For each dataset, output a single line containing the maximum height that the balloon can go up. The error of the value should be no greater than 0.00001. No extra characters should appear in the output. Sample Input 3 10 10 20 10 -10 20 -10 10 120 1 10 10 16 2 10 10 20 10 -10 20 2 100 0 101 -90 0 91 2 0 0 53 30 40 102 3 10 10 20 10 -10 20 -10 -10 20 3 1 5 13 5 -3 13 -3 -3 13 3 98 97 168 -82 -80 193 -99 -96 211 4 90 -100 160 -80 -80 150 90 80 150 80 80 245 4 85 -90 290 -80 -80 220 -85 90 145 85 90 170 5 0 0 4 3 0 5 -3 0 5 0 3 5 0 -3 5 10 95 -93 260 -86 96 211 91 90 177 -81 -80 124 -91 91 144 97 94 165 -90 -86 194 89 85 167 -93 -80 222 92 -84 218 0 Output for the Sample Input 17.3205081 16.0000000 17.3205081 13.8011200 53.0000000 14.1421356 12.0000000 128.3928757 94.1879092 131.1240816 4.0000000 72.2251798
[ { "submission_id": "aoj_1190_10433181", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\ntypedef complex<double> Point;\nconst double EPS = 1e-8;\n\nstruct Circle {\n Point p;\n double r;\n};\n\n// 円の交点を求めるメソッド\npair<Point, Point> cc_cross(const Circle& c1, const Circle& c2) {\n double d = abs(c1.p - c2.p);\n double rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n double h2 = c1.r * c1.r - rc * rc;\n double rs = sqrt(max(0.0, h2));\n Point diff = (c2.p - c1.p) / d;\n return make_pair(c1.p + diff * Point(rc, rs), c1.p + diff * Point(rc, -rs));\n}\n\nbool ok(double z, vector<Point>& points, vector<double>& len) {\n int n = (int) points.size();\n vector<Circle> C(n);\n\n // 高さをもとに円を作成\n for (int i = 0; i < n; i++) {\n if (z > len[i]) {\n return false; // ロープより高いならfalse\n }\n\n double rr = sqrt(max(0.0, len[i] * len[i] - z * z));\n C[i] = Circle(points[i], rr);\n }\n\n // 交点があるかの判定\n for (int i = 0; i < n; i++) {\n bool ok = true;\n for (int j = 0; j < n; j++) {\n if (i == j) {\n continue;\n }\n\n double d2 = norm(C[i].p - C[j].p);\n if (d2 > C[j].r * C[j].r + EPS) {\n ok = false;\n }\n }\n if (ok) {\n return true;\n }\n }\n\n // 交点と、その他の円が重なっているかの判定\n for (int i = 0; i < n; i++) {\n for (int j = i + 1; j < n; j++) {\n auto [p1, p2] = cc_cross(C[i], C[j]);\n for (Point cp : {p1, p2}) {\n bool all = true;\n for (int k = 0; k < n; k++) {\n if (norm(cp - C[k].p) > C[k].r * C[k].r + EPS) {\n all = false;\n break;\n }\n }\n if (all) {\n return true;\n }\n }\n }\n }\n\n return false;\n}\n\nint main() {\n while (true) {\n int n;\n cin >> n;\n if (n == 0) {\n break;\n }\n\n vector<Point> points(n);\n vector<double> len(n);\n for (int i = 0; i < n; i++) {\n double x, y, l;\n cin >> x >> y >> l;\n points[i] = Point(x, y);\n len[i] = l;\n }\n\n double left = 0, right = 300;\n while (right - left > EPS) {\n double mid = (right + left) / 2;\n if (ok(mid, points, len)) {\n left = mid;\n } else {\n right = mid;\n }\n }\n printf(\"%.7f\\n\", left);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3840, "score_of_the_acc": -0.6893, "final_rank": 10 }, { "submission_id": "aoj_1190_10433160", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\ntypedef complex<double> Point;\nconst double EPS = 1e-8;\n\nstruct Circle {\n Point p;\n double r;\n};\n\n// 円の交点を求めるメソッド\npair<Point, Point> cc_cross(const Circle& c1, const Circle& c2) {\n double d = abs(c1.p - c2.p);\n double rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n double h2 = c1.r * c1.r - rc * rc;\n double rs = sqrt(max(0.0, h2));\n Point diff = (c2.p - c1.p) / d;\n return make_pair(c1.p + diff * Point(rc, rs), c1.p + diff * Point(rc, -rs));\n}\n\nbool ok(double z, vector<Point>& points, vector<double>& len) {\n int n = (int) points.size();\n vector<Circle> C(n);\n\n // 高さをもとに円を作成\n for (int i = 0; i < n; i++) {\n if (z > len[i]) {\n return false; // ロープより高いならfalse\n }\n\n double rr = sqrt(max(0.0, len[i] * len[i] - z * z));\n C[i] = Circle(points[i], rr);\n }\n\n // 交点があるかの判定\n for (int i = 0; i < n; i++) {\n bool ok = true;\n for (int j = 0; j < n; j++) {\n if (i == j) {\n continue;\n }\n\n double d2 = norm(C[i].p - C[j].p);\n if (d2 > C[j].r * C[j].r + EPS) {\n ok = false;\n }\n }\n if (ok) {\n return true;\n }\n }\n\n // 交点と、その他の円が重なっているかの判定\n for (int i = 0; i < n; i++) {\n for (int j = i + 1; j < n; j++) {\n auto [p1, p2] = cc_cross(C[i], C[j]);\n for (Point cp : {p1, p2}) {\n bool all = true;\n for (int k = 0; k < n; k++) {\n if (norm(cp - C[k].p) > C[k].r * C[k].r + EPS) {\n all = false;\n break;\n }\n }\n if (all) {\n return true;\n }\n }\n }\n }\n\n return false;\n}\n\nint main() {\n while (true) {\n int n;\n cin >> n;\n if (n == 0) {\n break;\n }\n\n vector<Point> points(n);\n vector<double> len(n);\n for (int i = 0; i < n; i++) {\n double x, y, l;\n cin >> x >> y >> l;\n points[i] = Point(x, y);\n len[i] = l;\n }\n\n double left = 0, right = 300;\n while (right - left > EPS) {\n double mid = (right + left) / 2;\n if (ok(mid, points, len)) {\n left = mid;\n } else {\n right = mid;\n }\n }\n printf(\"%.10f\\n\", left);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3840, "score_of_the_acc": -0.6893, "final_rank": 10 }, { "submission_id": "aoj_1190_10429268", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\ntypedef complex<double> Point;\nconst double EPS = 1e-8;\n\nstruct Circle {\n Point p;\n double r;\n};\n\n// 円の交点を求めるメソッド\npair<Point, Point> cc_cross(const Circle& c1, const Circle& c2) {\n double d = abs(c1.p - c2.p);\n double rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n double h2 = c1.r * c1.r - rc * rc;\n double rs = sqrt(max(0.0, h2));\n Point diff = (c2.p - c1.p) / d;\n return make_pair(c1.p + diff * Point(rc, rs), c1.p + diff * Point(rc, -rs));\n}\n\nbool ok(double z, vector<Point>& points, vector<double>& len) {\n int n = (int) points.size();\n vector<Circle> C(n);\n\n for (int i = 0; i < n; i++) {\n if (z > len[i]) {\n return false; // ロープより高いならfalse\n }\n\n double rr = sqrt(max(0.0, len[i] * len[i] - z * z));\n C[i] = Circle(points[i], rr);\n }\n\n // 交点があるかの判定\n for (int i = 0; i < n; i++) {\n bool ok = true;\n for (int j = 0; j < n; j++) {\n if (i == j) {\n continue;\n }\n\n double d2 = norm(C[i].p - C[j].p);\n if (d2 > C[j].r * C[j].r + EPS) {\n ok = false;\n }\n }\n if (ok) {\n return true;\n }\n }\n\n // 交点と、その他の円が重なっているかの判定\n for (int i = 0; i < n; i++) {\n for (int j = i + 1; j < n; j++) {\n auto [p1, p2] = cc_cross(C[i], C[j]);\n for (Point cp : {p1, p2}) {\n bool all = true;\n for (int k = 0; k < n; k++) {\n if (norm(cp - C[k].p) > C[k].r * C[k].r + EPS) {\n all = false;\n break;\n }\n }\n if (all) {\n return true;\n }\n }\n }\n }\n\n return false;\n}\n\nint main() {\n while (true) {\n int n;\n cin >> n;\n if (n == 0) {\n break;\n }\n\n vector<Point> points(n);\n vector<double> len(n);\n for (int i = 0; i < n; i++) {\n double x, y, l;\n cin >> x >> y >> l;\n points[i] = Point(x, y);\n len[i] = l;\n }\n\n double left = 0, right = 300;\n while (right - left > EPS) {\n double mid = (right + left) / 2;\n if (ok(mid, points, len)) {\n left = mid;\n } else {\n right = mid;\n }\n }\n printf(\"%.10f\\n\", left);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3840, "score_of_the_acc": -0.6893, "final_rank": 10 }, { "submission_id": "aoj_1190_10429119", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\ntypedef complex<double> Point;\nconst double EPS = 1e-8;\n\nstruct Circle {\n Point p;\n double r;\n};\n\npair<Point, Point> cc_cross(const Circle& c1, const Circle& c2) {\n double d = abs(c1.p - c2.p);\n double rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n double h2 = c1.r * c1.r - rc * rc;\n double rs = sqrt(max(0.0, h2));\n Point diff = (c2.p - c1.p) / d;\n return make_pair(c1.p + diff * Point(rc, rs), c1.p + diff * Point(rc, -rs));\n}\n\nbool ok(double z, vector<Point>& points, vector<double>& len) {\n int n = (int) points.size();\n vector<Circle> C(n);\n\n for (int i = 0; i < n; i++) {\n if (z > len[i]) {\n return false; // ロープより高いならfalse\n }\n\n double rr = sqrt(max(0.0, len[i] * len[i] - z * z));\n C[i] = Circle(points[i], rr);\n }\n\n for (int i = 0; i < n; i++) {\n bool ok = true;\n for (int j = 0; j < n; j++) {\n if (i == j) {\n continue;\n }\n double d2 = norm(C[i].p - C[j].p);\n if (d2 > C[j].r * C[j].r + EPS) {\n ok = false;\n break;\n }\n }\n if (ok) {\n return true;\n }\n }\n\n for (int i = 0; i < n; i++) {\n for (int j = i + 1; j < n; j++) {\n double d = abs(C[i].p - C[j].p);\n if (d > C[i].r + C[j].r + EPS) {\n continue;\n }\n if (d < (C[i].r - C[j].r) - EPS) {\n continue;\n }\n\n auto [p1, p2] = cc_cross(C[i], C[j]);\n for (Point pp : {p1, p2}) {\n bool all = true;\n for (int k = 0; k < n; k++) {\n if (norm(pp - C[k].p) > C[k].r * C[k].r + EPS) {\n all = false;\n break;\n }\n }\n if (all) {\n return true;\n }\n }\n }\n }\n\n return false;\n}\n\nint main() {\n while (true) {\n int n;\n cin >> n;\n if (n == 0) {\n break;\n }\n\n vector<Point> points(n);\n vector<double> len(n);\n for (int i = 0; i < n; i++) {\n double x, y, l;\n cin >> x >> y >> l;\n points[i] = Point(x, y);\n len[i] = l;\n }\n\n double left = 0, right = 300;\n while (right - left > EPS) {\n double mid = (right + left) / 2;\n if (ok(mid, points, len)) {\n left = mid;\n } else {\n right = mid;\n }\n }\n printf(\"%.10f\\n\", left);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3840, "score_of_the_acc": -0.6893, "final_rank": 10 }, { "submission_id": "aoj_1190_10429118", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\ntypedef complex<double> Point;\nconst double EPS = 1e-8;\n\nstruct Circle {\n Point p;\n double r;\n};\n\npair<Point, Point> cc_cross(const Circle& c1, const Circle& c2) {\n double d = abs(c1.p - c2.p);\n double rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n double h2 = c1.r * c1.r - rc * rc;\n double rs = sqrt(max(0.0, h2));\n Point diff = (c2.p - c1.p) / d;\n return make_pair(c1.p + diff * Point(rc, rs), c1.p + diff * Point(rc, -rs));\n}\n\nbool ok(double z, vector<Point>& points, vector<double>& len) {\n int n = (int) points.size();\n vector<Circle> C(n);\n\n for (int i = 0; i < n; i++) {\n if (z > len[i]) {\n return false; // ロープより高いならfalse\n }\n\n double rr = sqrt(max(0.0, len[i] * len[i] - z * z));\n C[i] = Circle(points[i], rr);\n }\n\n for (int i = 0; i < n; i++) {\n bool ok = true;\n for (int j = 0; j < n; j++) {\n if (i == j) {\n continue;\n }\n double d2 = norm(C[i].p - C[j].p);\n if (d2 > C[j].r * C[j].r + EPS) {\n ok = false;\n break;\n }\n }\n if (ok) {\n return true;\n }\n }\n\n for (int i = 0; i < n; i++) {\n for (int j = i + 1; j < n; j++) {\n double d = abs(C[i].p - C[j].p);\n if (d > C[i].r + C[j].r + EPS) {\n continue;\n }\n if (d < (C[i].r - C[j].r) - EPS) {\n continue;\n }\n\n auto [p1, p2] = cc_cross(C[i], C[j]);\n for (Point cand : {p1, p2}) {\n bool all = true;\n for (int k = 0; k < n; k++) {\n if (norm(cand - C[k].p) > C[k].r * C[k].r + EPS) {\n all = false;\n break;\n }\n }\n if (all) {\n return true;\n }\n }\n }\n }\n\n return false;\n}\n\nint main() {\n while (true) {\n int n;\n cin >> n;\n if (n == 0) {\n break;\n }\n\n vector<Point> points(n);\n vector<double> len(n);\n for (int i = 0; i < n; i++) {\n double x, y, l;\n cin >> x >> y >> l;\n points[i] = Point(x, y);\n len[i] = l;\n }\n\n double left = 0, right = 300;\n while (right - left > EPS) {\n double mid = (right + left) / 2;\n if (ok(mid, points, len)) {\n left = mid;\n } else {\n right = mid;\n }\n }\n printf(\"%.10f\\n\", left);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3840, "score_of_the_acc": -0.6893, "final_rank": 10 }, { "submission_id": "aoj_1190_10429022", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\ntypedef complex<double> Point;\nconst double EPS = 1e-8;\n\nstruct Circle {\n Point p;\n double r;\n};\n\npair<Point, Point> cc_cross(const Circle& c1, const Circle& c2) {\n double d = abs(c1.p - c2.p);\n double rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n double h2 = c1.r * c1.r - rc * rc;\n double rs = sqrt(max(0.0, h2));\n Point diff = (c2.p - c1.p) / d;\n return make_pair(c1.p + diff * Point(rc, rs), c1.p + diff * Point(rc, -rs));\n}\n\nbool ok(double z, vector<Point>& points, vector<double>& len) {\n int n = (int) points.size();\n vector<Circle> C(n);\n\n for (int i = 0; i < n; i++) {\n if (z > len[i]) {\n return false; // ロープより高いならfalse\n }\n\n double rr = sqrt(max(0.0, len[i] * len[i] - z * z));\n C[i] = Circle(points[i], rr);\n }\n\n for (int i = 0; i < n; i++) {\n bool ok = true;\n for (int j = 0; j < n; j++) {\n if (i == j) {\n continue;\n }\n double d2 = norm(C[i].p - C[j].p);\n if (d2 > C[j].r * C[j].r + EPS) {\n ok = false;\n break;\n }\n }\n if (ok) {\n return true;\n }\n }\n\n for (int i = 0; i < n; i++) {\n for (int j = i + 1; j < n; j++) {\n double d = abs(C[i].p - C[j].p);\n if (d > C[i].r + C[j].r + EPS) {\n continue;\n }\n if (d < fabs(C[i].r - C[j].r) - EPS) {\n continue;\n }\n\n auto [p1, p2] = cc_cross(C[i], C[j]);\n for (Point cand : {p1, p2}) {\n bool all = true;\n for (int k = 0; k < n; k++) {\n if (norm(cand - C[k].p) > C[k].r * C[k].r + EPS) {\n all = false;\n break;\n }\n }\n if (all) {\n return true;\n }\n }\n }\n }\n\n return false;\n}\n\nint main() {\n while (true) {\n int n;\n cin >> n;\n if (n == 0) {\n break;\n }\n\n vector<Point> points(n);\n vector<double> len(n);\n for (int i = 0; i < n; i++) {\n double x, y, l;\n cin >> x >> y >> l;\n points[i] = Point(x, y);\n len[i] = l;\n }\n\n double left = 0, right = 300;\n while (right - left > EPS) {\n double mid = (right + left) / 2;\n if (ok(mid, points, len)) {\n left = mid;\n } else {\n right = mid;\n }\n }\n printf(\"%.10f\\n\", left);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3840, "score_of_the_acc": -0.6893, "final_rank": 10 }, { "submission_id": "aoj_1190_10428972", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\ntypedef complex<double> Point;\n\nconst double EPS = 1e-7;\n\n\nstruct Circle {\n Point p;\n double r;\n};\n\n\n\npair<Point, Point> cc_cross(const Circle& c1, const Circle& c2) {\n double d = abs(c1.p - c2.p);\n \n double rc = (d*d + c1.r*c1.r - c2.r*c2.r) / (2*d);\n double h2 = c1.r*c1.r - rc*rc;\n \n double rs = sqrt(max(0.0, h2));\n Point diff = (c2.p - c1.p) / d;\n return make_pair(\n c1.p + diff * Point(rc, rs),\n c1.p + diff * Point(rc, -rs)\n );\n}\n\n\nbool centerContained(int i, const vector<Circle>& C) {\n for (int j = 0; j < (int)C.size(); j++) {\n if (i == j) continue;\n double d2 = norm(C[i].p - C[j].p);\n if (d2 > C[j].r*C[j].r + EPS) return false;\n }\n return true;\n}\n\n\nbool ok(double z,\n const vector<Point>& points,\n const vector<double>& len)\n{\n int n = points.size();\n vector<Circle> C(n);\n\n for (int i = 0; i < n; i++) {\n if (z > len[i]) return false;\n double rr = sqrt(max(0.0, len[i]*len[i] - z*z));\n C[i] = { points[i], rr };\n }\n \n for (int i = 0; i < n; i++) {\n if (centerContained(i, C)) return true;\n }\n \n for (int i = 0; i < n; i++) {\n for (int j = i+1; j < n; j++) {\n double d = abs(C[i].p - C[j].p);\n \n if (d > C[i].r + C[j].r + EPS) continue; \n if (d < fabs(C[i].r - C[j].r) - EPS) continue; \n \n auto [p1, p2] = cc_cross(C[i], C[j]);\n \n \n for (Point cand : {p1, p2}) {\n bool insideAll = true;\n for (int k = 0; k < n; k++) {\n if (norm(cand - C[k].p) > C[k].r*C[k].r + EPS) {\n insideAll = false;\n break;\n }\n }\n if (insideAll) return true;\n }\n }\n }\n return false;\n}\n\nint main(){\n while (true) {\n int n;\n cin >> n;\n if (!cin || n == 0) break;\n\n vector<Point> points(n);\n vector<double> len(n);\n for (int i = 0; i < n; i++) {\n double x, y, l;\n cin >> x >> y >> l;\n points[i] = Point(x, y);\n len[i] = l;\n }\n\n double left = 0.0, right = 0.0;\n \n for (double l : len) right = max(right, l);\n\n \n while (right - left > EPS) {\n double mid = (left + right) / 2;\n if (ok(mid, points, len)) {\n left = mid;\n } else {\n right = mid;\n }\n }\n\n \n cout << fixed << setprecision(7) << left << \"\\n\";\n }\n\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3576, "score_of_the_acc": -0.3786, "final_rank": 4 }, { "submission_id": "aoj_1190_10428970", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\ntypedef complex<double> Point;\n\nconst double EPS = 1e-7;\n\n\nstruct Circle {\n Point p;\n double r;\n};\n\n\n\npair<Point, Point> cc_cross(const Circle& c1, const Circle& c2) {\n double d = abs(c1.p - c2.p);\n \n double rc = (d*d + c1.r*c1.r - c2.r*c2.r) / (2*d);\n double h2 = c1.r*c1.r - rc*rc;\n \n double rs = sqrt(max(0.0, h2));\n Point diff = (c2.p - c1.p) / d;\n return make_pair(\n c1.p + diff * Point(rc, rs),\n c1.p + diff * Point(rc, -rs)\n );\n}\n\n\nbool centerContained(int i, const vector<Circle>& C) {\n for (int j = 0; j < (int)C.size(); j++) {\n if (i == j) continue;\n double d2 = norm(C[i].p - C[j].p);\n if (d2 > C[j].r*C[j].r + EPS) return false;\n }\n return true;\n}\n\n\nbool ok(double z,\n const vector<Point>& points,\n const vector<double>& len)\n{\n int n = points.size();\n vector<Circle> C(n);\n\n for (int i = 0; i < n; i++) {\n if (z > len[i]) return false; // ロープ長より高い\n double rr = sqrt(max(0.0, len[i]*len[i] - z*z));\n C[i] = { points[i], rr };\n }\n \n for (int i = 0; i < n; i++) {\n if (centerContained(i, C)) return true;\n }\n \n for (int i = 0; i < n; i++) {\n for (int j = i+1; j < n; j++) {\n double d = abs(C[i].p - C[j].p);\n \n if (d > C[i].r + C[j].r + EPS) continue; \n if (d < fabs(C[i].r - C[j].r) - EPS) continue; \n \n auto [p1, p2] = cc_cross(C[i], C[j]);\n \n \n for (Point cand : {p1, p2}) {\n bool insideAll = true;\n for (int k = 0; k < n; k++) {\n if (norm(cand - C[k].p) > C[k].r*C[k].r + EPS) {\n insideAll = false;\n break;\n }\n }\n if (insideAll) return true;\n }\n }\n }\n return false;\n}\n\nint main(){\n while (true) {\n int n;\n cin >> n;\n if (!cin || n == 0) break;\n\n vector<Point> points(n);\n vector<double> len(n);\n for (int i = 0; i < n; i++) {\n double x, y, l;\n cin >> x >> y >> l;\n points[i] = Point(x, y);\n len[i] = l;\n }\n\n double left = 0.0, right = 0.0;\n \n for (double l : len) right = max(right, l);\n\n \n while (right - left > EPS) {\n double mid = (left + right) / 2;\n if (ok(mid, points, len)) {\n left = mid;\n } else {\n right = mid;\n }\n }\n\n \n cout << fixed << setprecision(7) << left << \"\\n\";\n }\n\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3492, "score_of_the_acc": -0.2767, "final_rank": 1 }, { "submission_id": "aoj_1190_10428895", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct Point {\n double x, y;\n};\n\nconst double EPS = 1e-7;\n\nint circleIntersections(const Point& p1, double r1,\n const Point& p2, double r2,\n vector<Point>& points) {\n double dx = p2.x - p1.x;\n double dy = p2.y - p1.y;\n double d2 = dx*dx + dy*dy;\n if (d2 < EPS) return 0;\n double d = sqrt(d2);\n if (d > r1 + r2 + EPS) return 0;\n if (d < fabs(r1 - r2) - EPS) return 0; \n double a = (r1*r1 - r2*r2 + d2) / (2*d);\n double h2 = r1*r1 - a*a;\n if (h2 < -EPS) return 0;\n h2 = max(h2, 0.0);\n double xm = p1.x + a * dx / d;\n double ym = p1.y + a * dy / d;\n if (h2 < EPS) {\n points.push_back({xm, ym});\n return 1;\n } else {\n double h = sqrt(h2);\n double rx = -dy * (h / d);\n double ry = dx * (h / d);\n points.push_back({xm + rx, ym + ry});\n points.push_back({xm - rx, ym - ry});\n return 2;\n }\n}\n\nbool centerContained(int i, const vector<Point>& centers,\n const vector<double>& radii) {\n for (int j = 0; j < (int)centers.size(); j++) {\n if (i == j) continue;\n double dx = centers[i].x - centers[j].x;\n double dy = centers[i].y - centers[j].y;\n if (dx*dx + dy*dy > radii[j]*radii[j] + EPS) {\n return false;\n }\n }\n return true;\n}\n\nbool feasible(double z,\n const vector<Point>& stakes,\n const vector<double>& lengths) {\n int n = stakes.size();\n vector<double> r(n);\n for (int i = 0; i < n; i++) {\n if (z > lengths[i]) return false;\n r[i] = sqrt(max(0.0, lengths[i]*lengths[i] - z*z));\n }\n for (int i = 0; i < n; i++) {\n if (centerContained(i, stakes, r)) return true;\n }\n for (int i = 0; i < n; i++) {\n for (int j = i+1; j < n; j++) {\n vector<Point> pts;\n int cnt = circleIntersections(stakes[i], r[i], stakes[j], r[j], pts);\n for (auto& p : pts) {\n bool insideAll = true;\n for (int k = 0; k < n; k++) {\n double dx = p.x - stakes[k].x;\n double dy = p.y - stakes[k].y;\n if (dx*dx + dy*dy > r[k]*r[k] + EPS) {\n insideAll = false;\n break;\n }\n }\n if (insideAll) return true;\n }\n }\n }\n return false;\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n while (true) {\n int n;\n cin >> n;\n if (!cin || n == 0) break;\n\n vector<Point> stakes(n);\n vector<double> lengths(n);\n for (int i = 0; i < n; i++) {\n cin >> stakes[i].x >> stakes[i].y >> lengths[i];\n }\n\n double low = 0, high = 0;\n for (double l : lengths) high = max(high, l);\n\n for (int iter = 0; iter < 60; iter++) {\n double mid = (low + high) / 2;\n if (feasible(mid, stakes, lengths)) low = mid;\n else high = mid;\n }\n\n cout << fixed << setprecision(7) << low << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3840, "score_of_the_acc": -0.699, "final_rank": 16 }, { "submission_id": "aoj_1190_10217457", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<long long, long long>;\n#define rep(i, a, b) for(long long i = (a); i < (b); ++i)\n#define rrep(i, a, b) for(long long i = (a); i >= (b); --i)\nconstexpr long long inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\nusing Real = long double;\nconstexpr Real EPS = Real(1e-8), PI = 3.141592653589793238462643383279L;\nint sign(const Real& r) {\n if(r <= -EPS) return -1;\n if(r >= +EPS) return +1;\n return 0;\n}\nbool eq(const Real& a, const Real& b) {\n return sign(a - b) == 0;\n}\nusing Point = complex<Real>;\nistream& operator>>(istream& is, Point& p) {\n Real a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n}\nostream& operator<<(ostream& os, const Point& p) {\n return os << p.real() << \" \" << p.imag();\n}\nPoint operator*(const Point& p, const Real& d) {\n return Point(p.real() * d, p.imag() * d);\n}\nPoint operator/(const Point& p, const Real& d) {\n return Point(p.real() / d, p.imag() / d);\n}\nPoint rot(const Point& p, const Real& theta) {\n return p * Point(cos(theta), sin(theta));\n}\nReal dot(const Point& p1, const Point& p2) {\n return (conj(p1) * p2).real();\n}\nReal cross(const Point& p1, const Point& p2) {\n return (conj(p1) * p2).imag();\n}\nReal dist(const Point& p1, const Point& p2) {\n return abs(p1 - p2);\n}\nbool comp_x(const Point& p1, const Point& p2) {\n return eq(p1.real(), p2.real()) ? p1.imag() < p2.imag() : p1.real() < p2.real();\n}\nbool comp_y(const Point& p1, const Point& p2) {\n return eq(p1.imag(), p2.imag()) ? p1.real() < p2.real() : p1.imag() < p2.imag();\n}\nbool comp_arg(const Point& p1, const Point& p2) {\n return arg(p1) < arg(p2);\n}\nint ccw(const Point& a, Point b, Point c) {\n b -= a;\n c -= a;\n if(sign(cross(b, c)) == 1) return 1;\n if(sign(cross(b, c)) == -1) return -1;\n if(sign(dot(b, c)) == -1) return +2;\n if(norm(b) < norm(c)) return -2;\n return 0;\n}\nReal closest_pair(vector<Point> ps) {\n if((int)ps.size() <= 1) return Real(1e18);\n sort(ps.begin(), ps.end(), comp_x);\n vector<Point> memo(ps.size());\n auto func = [&](const auto& func, const int l, const int r) -> Real {\n if(r - l <= 1) return Real(1e18);\n const int m = (l + r) >> 1;\n const Real x = ps[m].real();\n Real res = min(func(func, l, m), func(func, m, r));\n inplace_merge(ps.begin() + l, ps.begin() + m, ps.begin() + r, comp_y);\n int cnt = 0;\n for(int i = l; i < r; ++i) {\n if(abs(ps[i].real() - x) >= res) continue;\n for(int j = 0; j < cnt; ++j) {\n const Point d = ps[i] - memo[cnt - j - 1];\n if(d.imag() >= res) break;\n res = min(res, abs(d));\n }\n memo[cnt++] = ps[i];\n }\n return res;\n };\n return func(func, 0, (int)ps.size());\n}\nstruct Line {\n Point a, b;\n Line() = default;\n Line(const Point& a, const Point& b)\n : a(a), b(b) {}\n};\nusing Segment = Line;\nbool is_parallel(const Line& a, const Line& b) {\n return eq(cross(a.b - a.a, b.b - b.a), 0.0);\n}\nbool is_orthogonal(const Line& a, const Line& b) {\n return eq(dot(a.b - a.a, b.b - b.a), 0.0);\n}\nPoint projection(const Line& l, const Point& p) {\n Real t = dot(p - l.a, l.b - l.a) / norm(l.b - l.a);\n return l.a + (l.b - l.a) * t;\n}\nPoint reflection(const Line& l, const Point& p) {\n return p + (projection(l, p) - p) * 2.0;\n}\nbool is_intersect_lp(const Line& l, const Point& p) {\n return abs(ccw(l.a, l.b, p)) != 1;\n}\nbool is_intersect_sp(const Segment& s, const Point& p) {\n return ccw(s.a, s.b, p) == 0;\n}\nbool is_intersect_ll(const Line& l1, const Line& l2) {\n if(!eq(cross(l1.b - l1.a, l2.b - l2.a), 0.0)) return true;\n return eq(cross(l1.b - l1.a, l2.b - l1.a), 0.0);\n}\nbool is_intersect_ls(const Line& l, const Segment& s) {\n return sign(cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a)) <= 0;\n}\nbool is_intersect_sl(const Segment& s, const Line& l) {\n return is_intersect_ls(l, s);\n}\nbool is_intersect_ss(const Segment& s1, const Segment& s2) {\n if(ccw(s1.a, s1.b, s2.a) * ccw(s1.a, s1.b, s2.b) > 0) return false;\n return ccw(s2.a, s2.b, s1.a) * ccw(s2.a, s2.b, s1.b) <= 0;\n}\nvector<Point> intersection_ll(const Line& l1, const Line& l2) {\n vector<Point> res;\n if(!is_intersect_ll(l1, l2)) return res;\n Real a = cross(l1.b - l1.a, l2.b - l2.a);\n Real b = cross(l1.b - l1.a, l1.b - l2.a);\n if(eq(a, 0.0) and eq(b, 0.0)) {\n res.emplace_back(l2.a);\n } else {\n res.emplace_back(l2.a + (l2.b - l2.a) * b / a);\n }\n return res;\n}\nvector<Point> intersection_ss(const Segment& s1, const Segment& s2) {\n return is_intersect_ss(s1, s2) ? intersection_ll(Line(s1), Line(s2)) : vector<Point>();\n}\nReal dist_lp(const Line& l, const Point& p) {\n return abs(p - projection(l, p));\n}\nReal dist_sp(const Segment& s, const Point& p) {\n const Point h = projection(s, p);\n if(is_intersect_sp(s, h)) return abs(h - p);\n return min(abs(s.a - p), abs(s.b - p));\n}\nReal dist_ll(const Line& l1, const Line& l2) {\n if(is_intersect_ll(l1, l2)) return 0.0;\n return dist_lp(l1, l2.a);\n}\nReal dist_ss(const Segment& s1, const Segment& s2) {\n if(is_intersect_ss(s1, s2)) return 0.0;\n return min({dist_sp(s1, s2.a), dist_sp(s1, s2.b), dist_sp(s2, s1.a), dist_sp(s2, s1.b)});\n}\nReal dist_ls(const Line& l, const Segment& s) {\n if(is_intersect_ls(l, s)) return 0.0;\n return min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\nReal dist_sl(const Segment& s, const Line& l) {\n return dist_ls(l, s);\n}\nstruct Circle {\n Point p;\n Real r;\n Circle() = default;\n Circle(const Point& p, const Real& r)\n : p(p), r(r) {}\n};\nbool is_intersect_cp(const Circle& c, const Point& p) {\n return eq(abs(p - c.p), c.r);\n}\nbool is_intersect_cl(const Circle& c, const Line& l) {\n return sign(c.r - dist_lp(l, c.p)) >= 0;\n}\nint is_intersect_cc(Circle c1, Circle c2) {\n if(c1.r < c2.r) swap(c1, c2);\n const Real d = abs(c1.p - c2.p);\n const int a = sign(d - c1.r - c2.r);\n if(a >= 0) return a + 3;\n return sign(d - c1.r + c2.r) + 1;\n}\nvector<Point> intersection_cl(const Circle& c, const Line& l) {\n const Point h = projection(l, c.p);\n const Point e = (l.b - l.a) / abs(l.b - l.a);\n vector<Point> res;\n if(!is_intersect_cl(c, l)) return res;\n if(eq(dist_lp(l, c.p), c.r)) {\n res.emplace_back(h);\n } else {\n const Real b = sqrt(c.r * c.r - norm(h - c.p));\n res.emplace_back(h - e * b);\n res.emplace_back(h + e * b);\n }\n return res;\n}\nvector<Point> intersection_cs(const Circle& c, const Segment& s) {\n const vector<Point> cand = intersection_cl(c, Line(s));\n vector<Point> res;\n for(const Point& p : cand) {\n if(ccw(s.a, s.b, p) == 0) {\n res.emplace_back(p);\n }\n }\n return res;\n}\nvector<Point> intersection_cc(const Circle& c1, const Circle& c2) {\n const Real d = abs(c1.p - c2.p);\n const Real a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (Real(2.0) * c1.r * d));\n const Real t = atan2(c2.p.imag() - c1.p.imag(), c2.p.real() - c1.p.real());\n vector<Point> res;\n if(is_intersect_cc(c1, c2) % 4 == 0) return res;\n if(eq(a, 0.0)) {\n res.emplace_back(c1.p + rot(Point(c1.r, 0.0), t));\n } else {\n res.emplace_back(c1.p + rot(Point(c1.r, 0.0), t + a));\n res.emplace_back(c1.p + rot(Point(c1.r, 0.0), t - a));\n }\n return res;\n}\nvector<Point> tangent_cp(const Circle& c, const Point& p) {\n return intersection_cc(c, Circle(p, sqrt(norm(p - c.p) - c.r * c.r)));\n}\nvector<Line> tangent_cc(Circle c1, Circle c2) {\n vector<Line> res;\n if(c1.r < c2.r) swap(c1, c2);\n const Real r = abs(c2.p - c1.p);\n if(eq(r, 0.0)) return res;\n const Point u = (c2.p - c1.p) / r;\n const Point v = rot(u, PI * 0.5);\n for(const Real s : {Real(1.0), Real(-1.0)}) {\n const Real h = (c1.r + c2.r * s) / r;\n if(eq(abs(h), Real(1.0))) {\n res.emplace_back(c1.p + u * c1.r, c1.p + (u + v) * c1.r);\n } else if(abs(h) < Real(1.0)) {\n const Point uu = u * h, vv = v * sqrt(Real(1.0) - h * h);\n res.emplace_back(c1.p + (uu + vv) * c1.r, c2.p - (uu + vv) * c2.r * s);\n res.emplace_back(c1.p + (uu - vv) * c1.r, c2.p - (uu - vv) * c2.r * s);\n }\n }\n return res;\n}\nCircle inscribed_circle(const Point& a, const Point& b, const Point& c) {\n const Real A = abs(b - c), B = abs(c - a), C = abs(a - b);\n const Point x = Point((a * A + b * B + c * C) / (A + B + C));\n const Real r = dist_sp(Segment(a, b), x);\n return Circle(x, r);\n}\nCircle circumscribed_circle(const Point& a, const Point& b, const Point& c) {\n const Point m1((a + b) / 2.0), m2((b + c) / 2.0);\n const Point v((b - a).imag(), (a - b).real()), w((b - c).imag(), (c - b).real());\n const Line s(m1, Point(m1 + v)), t(m2, Point(m2 + w));\n const Point x = intersection_ll(s, t)[0];\n return Circle(x, abs(a - x));\n}\nCircle appollonius(const Point& p1, const Point& p2, const Real& a, const Real& b) {\n const Point q1 = (p1 * b + p2 * a) / (a + b), q2 = (-p1 * b + p2 * a) / (a - b);\n return Circle((q1 + q2) * 0.5, abs(q1 - q2) * 0.5);\n}\nReal area_cc(const Circle& c1, const Circle& c2) {\n const Real d = abs(c1.p - c2.p);\n if(c1.r + c2.r <= d + EPS) return 0.0;\n if(d <= abs(c1.r - c2.r) + EPS) {\n const Real r = min(c1.r, c2.r);\n return r * r * PI;\n }\n const Real rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (Real(2.0) * d);\n const Real theta = acos(rc / c1.r);\n const Real phi = acos((d - rc) / c2.r);\n return c1.r * c1.r * theta + c2.r * c2.r * phi - d * c1.r * sin(theta);\n}\nReal area_pc(const vector<Point>& ps, const Circle& c) {\n auto calc_element = [&](const Point& a, const Point& b, const Real& r, const bool triangle) -> Real {\n if(triangle) return cross(a, b) / 2.0;\n const Point tmp = b * Point(a.real(), -a.imag());\n const Real ang = atan2(tmp.imag(), tmp.real());\n return r * r * ang / 2.0;\n };\n auto cross_area = [&](const Circle& c, const Point& ia, const Point& ib) -> Real {\n const Point a = ia - c.p, b = ib - c.p;\n if(abs(a - b) < EPS) return 0;\n const bool isin_a = (abs(a) < c.r + EPS);\n const bool isin_b = (abs(b) < c.r + EPS);\n if(isin_a and isin_b) return calc_element(a, b, c.r, true);\n const Circle oc(Point(0.0, 0.0), c.r);\n const Segment seg(a, b);\n const vector<Point> cr = intersection_cs(oc, seg);\n if(cr.empty()) return calc_element(a, b, c.r, false);\n const Point s = cr[0], t = cr.back();\n return calc_element(s, t, c.r, true) + calc_element(a, s, c.r, isin_a) + calc_element(t, b, c.r, isin_b);\n };\n const int n = (int)ps.size();\n if(n < 3) return 0.0;\n Real S = 0;\n for(int i = 0; i < n; ++i) {\n S += cross_area(c, ps[i], ps[(i + 1) % n]);\n }\n return S;\n}\nint main(void) {\n while(1) {\n int n;\n cin >> n;\n if(n == 0) break;\n vector<Point> ps(n);\n vector<Real> l(n);\n rep(i, 0, n) {\n cin >> ps[i] >> l[i];\n }\n Real lower = 0.0, upper = *ranges::min_element(l);\n rep(_, 0, 100) {\n Real mid = (lower + upper) / 2.0;\n vector<Circle> c(n);\n rep(i, 0, n) {\n c[i] = {ps[i], sqrtl(l[i] * l[i] - mid * mid)};\n }\n vector<Point> cand;\n rep(i, 0, n) cand.push_back(c[i].p);\n rep(i, 0, n) {\n rep(j, i + 1, n) {\n vector<Point> intersect = intersection_cc(c[i], c[j]);\n rep(k, 0, ssize(intersect)) {\n cand.push_back(intersect[k]);\n }\n }\n }\n bool res = false;\n for(const Point& p : cand) {\n bool flag = true;\n rep(i, 0, n) {\n if(dist(p, c[i].p) - EPS > c[i].r) {\n flag = false;\n }\n }\n if(flag) res = true;\n }\n if(res) {\n lower = mid;\n } else {\n upper = mid;\n }\n }\n cout << lower << '\\n';\n }\n}", "accuracy": 1, "time_ms": 1040, "memory_kb": 4096, "score_of_the_acc": -2, "final_rank": 19 }, { "submission_id": "aoj_1190_10215314", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint x[11], y[11], l[11];\nint n;\n\ndouble findH(double X, double Y) {\n double mn = 1e9;\n for (int i = 1;i <= n;i++) {\n double cur = l[i] * l[i] - (X - x[i]) * (X - x[i]) - (Y - y[i]) * (Y - y[i]);\n if (cur < mn) mn = cur;\n }\n return mn;\n}\n\ndouble findY(double X) {\n double l = -100, r = 100; \n for (int i = 1;i <= 100;i++) {\n double m1 = l + (r - l) / 3;\n double m2 = r - (r - l) / 3;\n if (findH(X, m1) < findH(X, m2)) {\n l = m1;\n } else {\n r = m2;\n }\n }\n return findH(X, l);\n}\n\nint main() {\n ios_base::sync_with_stdio(false); cin.tie(NULL);\n while (cin >> n) {\n if (n == 0) return 0;\n for (int i = 1;i <= n;i++) {\n cin >> x[i] >> y[i] >> l[i];\n }\n double l = -100, r = 100; \n for (int i = 1;i <= 100;i++) {\n double m1 = l + (r - l) / 3;\n double m2 = r - (r - l) / 3;\n if (findY(m1) < findY(m2)) {\n l = m1;\n } else {\n r = m2;\n }\n }\n cout << fixed << setprecision(5) << sqrt(findY(l)) << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 3496, "score_of_the_acc": -0.466, "final_rank": 5 }, { "submission_id": "aoj_1190_10213351", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint n;\nint l[10], x[10], y[10];\n\ndouble H(double Y, double X) {\n double min_val = 1e18;\n for (int i = 0; i < n; ++i) {\n double dx = X - x[i];\n double dy = Y - y[i];\n double val = l[i] * l[i] - dx*dx - dy*dy;\n if (val < min_val) min_val = val;\n }\n return min_val;\n}\n\ndouble optimizeY(double X) {\n double left = -100.0, right = 100.0;\n for (int i = 0; i < 100; ++i) {\n double m1 = left + (right - left) / 3;\n double m2 = right - (right - left) / 3;\n if (H(m1, X) < H(m2, X))\n left = m1;\n else\n right = m2;\n }\n return H(left, X);\n}\n\ndouble optimizeX() {\n double left = -100.0, right = 100.0;\n for (int i = 0; i < 100; ++i) {\n double m1 = left + (right - left) / 3;\n double m2 = right - (right - left) / 3;\n if (optimizeY(m1) < optimizeY(m2))\n left = m1;\n else\n right = m2;\n }\n return optimizeY(left);\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n while (cin >> n && n != 0) {\n for (int i = 0; i < n; ++i)\n cin >> x[i] >> y[i] >> l[i];\n double max_h_squared = optimizeX();\n double max_h = sqrt(max_h_squared);\n cout << fixed << setprecision(7) << max_h << '\\n';\n }\n return 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 3588, "score_of_the_acc": -0.5777, "final_rank": 8 }, { "submission_id": "aoj_1190_10212512", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n#include <iomanip>\n#include <algorithm>\n\nusing namespace std;\n\nstruct Anchor {\n double x, y, l;\n};\n\nstruct Circle {\n double x, y, r;\n Circle(double x_, double y_, double r_) : x(x_), y(y_), r(r_) {}\n};\n\nconst double EPS = 1e-8;\n\nbool isPossible(double z, const vector<Anchor>& anchors) {\n vector<Circle> circles;\n for (const auto& a : anchors) {\n if (z > a.l + EPS) return false;\n double r = sqrt(max(a.l * a.l - z * z, 0.0));\n circles.emplace_back(a.x, a.y, r);\n }\n\n // Check if any circle's center is inside all others\n for (int i = 0; i < circles.size(); ++i) {\n bool valid = true;\n for (int j = 0; j < circles.size(); ++j) {\n if (i == j) continue;\n double dx = circles[i].x - circles[j].x;\n double dy = circles[i].y - circles[j].y;\n double dist_sq = dx * dx + dy * dy;\n if (dist_sq > circles[j].r * circles[j].r + EPS) {\n valid = false;\n break;\n }\n }\n if (valid) return true;\n }\n\n // Check all pairs of circles for intersection points\n for (int i = 0; i < circles.size(); ++i) {\n for (int j = i + 1; j < circles.size(); ++j) {\n const Circle& c1 = circles[i];\n const Circle& c2 = circles[j];\n\n double dx = c2.x - c1.x;\n double dy = c2.y - c1.y;\n double d_sq = dx * dx + dy * dy;\n double d = sqrt(d_sq);\n\n if (d > c1.r + c2.r + EPS) continue;\n if (d + EPS < abs(c1.r - c2.r)) continue;\n\n double a = (c1.r * c1.r - c2.r * c2.r + d_sq) / (2 * d);\n double h_sq = c1.r * c1.r - a * a;\n if (h_sq < -EPS) continue;\n h_sq = max(h_sq, 0.0);\n double h = sqrt(h_sq);\n\n double xm = c1.x + (a * dx) / d;\n double ym = c1.y + (a * dy) / d;\n\n pair<double, double> points[2];\n points[0] = {xm - (h * dy) / d, ym + (h * dx) / d};\n points[1] = {xm + (h * dy) / d, ym - (h * dx) / d};\n\n for (const auto& p : points) {\n double x = p.first;\n double y = p.second;\n bool inside = true;\n for (int k = 0; k < circles.size(); ++k) {\n if (k == i || k == j) continue;\n const Circle& c = circles[k];\n double dxk = x - c.x;\n double dyk = y - c.y;\n double dist_sq = dxk * dxk + dyk * dyk;\n if (dist_sq > c.r * c.r + EPS) {\n inside = false;\n break;\n }\n }\n if (inside) return true;\n }\n }\n }\n\n return false;\n}\n\ndouble findMaxHeight(const vector<Anchor>& anchors) {\n double low = 0.0;\n double high = 0.0;\n for (const auto& a : anchors) {\n high = max(high, a.l);\n }\n high = 1e9; // Set a large initial upper bound\n\n // Binary search with sufficient iterations for precision\n double max_z = 0.0;\n for (int iter = 0; iter < 100; ++iter) {\n double mid = (low + high) / 2;\n if (isPossible(mid, anchors)) {\n max_z = mid;\n low = mid;\n } else {\n high = mid;\n }\n }\n return max_z;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n\n int n;\n while (cin >> n && n != 0) {\n vector<Anchor> anchors(n);\n for (int i = 0; i < n; ++i) {\n cin >> anchors[i].x >> anchors[i].y >> anchors[i].l;\n }\n double maxHeight = findMaxHeight(anchors);\n cout << fixed << setprecision(7) << maxHeight << '\\n';\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3560, "score_of_the_acc": -0.3495, "final_rank": 2 }, { "submission_id": "aoj_1190_9450641", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nusing T = double;\nconst T eps = 1e-12;\nusing Point = complex<T>;\nusing Poly = vector<Point>;\n#define X real()\n#define Y imag()\ntemplate <typename T> inline bool eq(const T &a, const T &b) {\n return fabs(a - b) < eps;\n}\nbool cmp(const Point &a, const Point &b) {\n auto sub = [&](Point a) {\n return (a.Y < 0 ? -1 : (a.Y == 0 && a.X >= 0 ? 0 : 1));\n };\n if (sub(a) != sub(b))\n return sub(a) < sub(b);\n return a.Y * b.X < a.X * b.Y;\n}\nstruct Line {\n Point a, b, dir;\n Line() {}\n Line(Point _a, Point _b) : a(_a), b(_b), dir(b - a) {}\n Line(T A, T B, T C) {\n if (eq(A, .0)) {\n a = Point(0, C / B), b = Point(1 / C / B);\n } else if (eq(B, .0)) {\n a = Point(C / A, 0), b = Point(C / A, 1);\n } else {\n a = Point(0, C / B), b = Point(C / A, 0);\n }\n }\n};\nstruct Segment : Line {\n Segment() {}\n Segment(Point _a, Point _b) : Line(_a, _b) {}\n};\nstruct Circle {\n Point p;\n T r;\n Circle() {}\n Circle(Point _p, T _r) : p(_p), r(_r) {}\n};\n\nistream &operator>>(istream &is, Point &p) {\n T x, y;\n is >> x >> y;\n p = Point(x, y);\n return is;\n}\nostream &operator<<(ostream &os, Point &p) {\n os << fixed << setprecision(12) << p.X << ' ' << p.Y;\n return os;\n}\nPoint unit(const Point &a) {\n return a / abs(a);\n}\nT dot(const Point &a, const Point &b) {\n return a.X * b.X + a.Y * b.Y;\n}\nT cross(const Point &a, const Point &b) {\n return a.X * b.Y - a.Y * b.X;\n}\nPoint rot(const Point &a, const T &theta) {\n return Point(cos(theta) * a.X - sin(theta) * a.Y,\n sin(theta) * a.X + cos(theta) * a.Y);\n}\nPoint rot90(const Point &a) {\n return Point(-a.Y, a.X);\n}\nT arg(const Point &a, const Point &b, const Point &c) {\n double ret = acos(dot(a - b, c - b) / abs(a - b) / abs(c - b));\n if (cross(a - b, c - b) < 0)\n ret = -ret;\n return ret;\n}\n\nPoint Projection(const Line &l, const Point &p) {\n T t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\nPoint Projection(const Segment &l, const Point &p) {\n T t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\nPoint Reflection(const Line &l, const Point &p) {\n return p + (Projection(l, p) - p) * 2.;\n}\nint ccw(const Point &a, Point b, Point c) {\n b -= a;\n c -= a;\n if (cross(b, c) > eps)\n return 1; // ccw\n\n if (cross(b, c) < -eps)\n return -1; // cw\n\n if (dot(b, c) < 0)\n return 2; // c,a,b\n\n if (norm(b) < norm(c))\n return -2; // a,b,c\n\n return 0; // a,c,b\n\n}\nbool isOrthogonal(const Line &a, const Line &b) {\n return eq(dot(a.b - a.a, b.b - b.a), .0);\n}\nbool isParallel(const Line &a, const Line &b) {\n return eq(cross(a.b - a.a, b.b - b.a), .0);\n}\nbool isIntersect(const Segment &a, const Segment &b) {\n return ccw(a.a, a.b, b.a) * ccw(a.a, a.b, b.b) <= 0 and\n ccw(b.a, b.b, a.a) * ccw(b.a, b.b, a.b) <= 0;\n}\nint isIntersect(const Circle &a, const Circle &b) {\n T d = abs(a.p - b.p);\n if (d > a.r + b.r + eps)\n return 4;\n if (eq(d, a.r + b.r))\n return 3;\n if (eq(d, abs(a.r - b.r)))\n return 1;\n if (d < abs(a.r - b.r) - eps)\n return 0;\n return 2;\n}\nT Dist(const Line &a, const Point &b) {\n Point c = Projection(a, b);\n return abs(c - b);\n}\nT Dist(const Segment &a, const Point &b) {\n if (dot(a.b - a.a, b - a.a) < eps)\n return abs(b - a.a);\n if (dot(a.a - a.b, b - a.b) < eps)\n return abs(b - a.b);\n return abs(cross(a.b - a.a, b - a.a)) / abs(a.b - a.a);\n}\nT Dist(const Segment &a, const Segment &b) {\n if (isIntersect(a, b))\n return .0;\n T res = min({Dist(a, b.a), Dist(a, b.b), Dist(b, a.a), Dist(b, a.b)});\n return res;\n}\nPoint Intersection(const Line &a, const Line &b) {\n T d1 = cross(a.b - a.a, b.b - b.a);\n T d2 = cross(a.b - a.a, a.b - b.a);\n if (eq(d1, 0.) and eq(d2, 0.))\n return b.a;\n return b.a + (b.b - b.a) * (d2 / d1);\n}\nPoly Intersection(const Circle &a, const Line &b) {\n Poly res;\n T d = Dist(b, a.p);\n if (d > a.r + eps)\n return res;\n Point h = Projection(b, a.p);\n if (eq(d, a.r)) {\n res.push_back(h);\n return res;\n }\n Point e = unit(b.b - b.a);\n T ph = sqrt(a.r * a.r - d * d);\n res.push_back(h - e * ph);\n res.push_back(h + e * ph);\n return res;\n}\nPoly Intersection(const Circle &a, const Segment &b) {\n Line c(b.a, b.b);\n Poly sub = Intersection(a, c);\n double xmi = min(b.a.X, b.b.X), xma = max(b.a.X, b.b.X);\n double ymi = min(b.a.Y, b.b.Y), yma = max(b.a.Y, b.b.Y);\n Poly res;\n rep(i, 0, sub.size()) {\n if (xmi <= sub[i].X + eps and sub[i].X - eps <= xma and\n ymi <= sub[i].Y + eps and sub[i].Y - eps <= yma) {\n res.push_back(sub[i]);\n }\n }\n return res;\n}\nPoly Intersection(const Circle &a, const Circle &b) {\n Poly res;\n int mode = isIntersect(a, b);\n T d = abs(a.p - b.p);\n if (mode == 4 or mode == 0)\n return res;\n if (mode == 3) {\n T t = a.r / (a.r + b.r);\n res.push_back(a.p + (b.p - a.p) * t);\n return res;\n }\n if (mode == 1) {\n if (b.r < a.r - eps) {\n res.push_back(a.p + (b.p - a.p) * (a.r / d));\n } else {\n res.push_back(b.p + (a.p - b.p) * (b.r / d));\n }\n return res;\n }\n T rc = (a.r * a.r + d * d - b.r * b.r) / d / 2.;\n T rs = sqrt(a.r * a.r - rc * rc);\n if (a.r - abs(rc) < eps)\n rs = 0;\n Point e = unit(b.p - a.p);\n res.push_back(a.p + rc * e + rs * e * Point(0, 1));\n res.push_back(a.p + rc * e + rs * e * Point(0, -1));\n return res;\n}\nPoly HalfplaneIntersection(vector<Line> &H) {\n sort(ALL(H), [&](Line &l1, Line &l2) { return cmp(l1.dir, l2.dir); });\n auto outside = [&](Line &L, Point p) -> bool {\n return cross(L.dir, p - L.a) < -eps;\n };\n deque<Line> deq;\n int sz = 0;\n rep(i, 0, SZ(H)) {\n while (sz > 1 and\n outside(H[i], Intersection(deq[sz - 1], deq[sz - 2]))) {\n deq.pop_back();\n sz--;\n }\n while (sz > 1 and outside(H[i], Intersection(deq[0], deq[1]))) {\n deq.pop_front();\n sz--;\n }\n if (sz > 0 and fabs(cross(H[i].dir, deq[sz - 1].dir)) < eps) {\n if (dot(H[i].dir, deq[sz - 1].dir) < 0) {\n return {};\n }\n if (outside(H[i], deq[sz - 1].a)) {\n deq.pop_back();\n sz--;\n } else\n continue;\n }\n deq.push_back(H[i]);\n sz++;\n }\n\n while (sz > 2 and outside(deq[0], Intersection(deq[sz - 1], deq[sz - 2]))) {\n deq.pop_back();\n sz--;\n }\n while (sz > 2 and outside(deq[sz - 1], Intersection(deq[0], deq[1]))) {\n deq.pop_front();\n sz--;\n }\n if (sz < 3)\n return {};\n deq.push_back(deq.front());\n Poly ret;\n rep(i, 0, sz) ret.push_back(Intersection(deq[i], deq[i + 1]));\n return ret;\n}\n\nT Area(const Poly &a) {\n T res = 0;\n int n = a.size();\n rep(i, 0, n) res += cross(a[i], a[(i + 1) % n]);\n return fabs(res / 2.);\n}\nT Area(const Poly &a, const Circle &b) {\n int n = a.size();\n if (n < 3)\n return .0;\n auto rec = [&](auto self, const Circle &c, const Point &p1,\n const Point &p2) {\n Point va = c.p - p1, vb = c.p - p2;\n T f = cross(va, vb), res = .0;\n if (eq(f, .0))\n return res;\n if (max(abs(va), abs(vb)) < c.r + eps)\n return f;\n if (Dist(Segment(p1, p2), c.p) > c.r - eps)\n return c.r * c.r * arg(vb * conj(va));\n auto u = Intersection(c, Segment(p1, p2));\n Poly sub;\n sub.push_back(p1);\n for (auto &x : u)\n sub.push_back(x);\n sub.push_back(p2);\n rep(i, 0, sub.size() - 1) res += self(self, c, sub[i], sub[i + 1]);\n return res;\n };\n T res = .0;\n rep(i, 0, n) res += rec(rec, b, a[i], a[(i + 1) % n]);\n return fabs(res / 2.);\n}\nT Area(const Circle &a, const Circle &b) {\n T d = abs(a.p - b.p);\n if (d >= a.r + b.r - eps)\n return .0;\n if (d <= abs(a.r - b.r) + eps) {\n T r = min(a.r, b.r);\n return M_PI * r * r;\n }\n T ath = acos((a.r * a.r + d * d - b.r * b.r) / d / a.r / 2.);\n T res = a.r * a.r * (ath - sin(ath * 2) / 2.);\n T bth = acos((b.r * b.r + d * d - a.r * a.r) / d / b.r / 2.);\n res += b.r * b.r * (bth - sin(bth * 2) / 2.);\n return fabs(res);\n}\nbool isConvex(const Poly &a) {\n int n = a.size();\n int cur, pre, nxt;\n rep(i, 0, n) {\n pre = (i - 1 + n) % n;\n nxt = (i + 1) % n;\n cur = i;\n if (ccw(a[pre], a[cur], a[nxt]) == -1)\n return 0;\n }\n return 1;\n}\nint isContained(const Poly &a,\n const Point &b) { // 0:not contain,1:on edge,2:contain\n\n bool res = 0;\n int n = a.size();\n rep(i, 0, n) {\n Point p = a[i] - b, q = a[(i + 1) % n] - b;\n if (p.Y > q.Y)\n swap(p, q);\n if (p.Y < eps and eps < q.Y and cross(p, q) > eps)\n res ^= 1;\n if (eq(cross(p, q), .0) and dot(p, q) < eps)\n return 1;\n }\n return (res ? 2 : 0);\n}\nPoly ConvexHull(Poly &a) {\n sort(ALL(a), [](const Point &p, const Point &q) {\n return (eq(p.Y, q.Y) ? p.X < q.X : p.Y < q.Y);\n });\n a.erase(unique(ALL(a)), a.end());\n int n = a.size(), k = 0;\n Poly res(n * 2);\n for (int i = 0; i < n; res[k++] = a[i++]) {\n while (k >= 2 and\n cross(res[k - 1] - res[k - 2], a[i] - res[k - 1]) < eps)\n k--;\n }\n for (int i = n - 2, t = k + 1; i >= 0; res[k++] = a[i--]) {\n while (k >= t and\n cross(res[k - 1] - res[k - 2], a[i] - res[k - 1]) < eps)\n k--;\n }\n res.resize(k - 1);\n return res;\n}\nT Diam(const Poly &a) {\n int n = a.size();\n int x = 0, y = 0;\n rep(i, 1, n) {\n if (a[i].Y > a[x].Y)\n x = i;\n if (a[i].Y < a[y].Y)\n y = i;\n }\n T res = abs(a[x] - a[y]);\n int i = x, j = y;\n do {\n if (cross(a[(i + 1) % n] - a[i], a[(j + 1) % n] - a[j]) < 0)\n i = (i + 1) % n;\n else\n j = (j + 1) % n;\n chmax(res, abs(a[i] - a[j]));\n } while (i != x or j != y);\n return res;\n}\nPoly Cut(const Poly &a, const Line &l) {\n int n = a.size();\n Poly res;\n rep(i, 0, n) {\n Point p = a[i], q = a[(i + 1) % n];\n if (ccw(l.a, l.b, p) != -1)\n res.push_back(p);\n if (ccw(l.a, l.b, p) * ccw(l.a, l.b, q) < 0)\n res.push_back(Intersection(Line(p, q), l));\n }\n return res;\n}\n\nT Closest(Poly &a) {\n int n = a.size();\n if (n <= 1)\n return 0;\n sort(ALL(a), [&](Point a, Point b) {\n return (eq(a.X, b.X) ? a.Y < b.Y : a.X < b.X);\n });\n Poly buf(n);\n auto rec = [&](auto self, int lb, int rb) -> T {\n if (rb - lb <= 1)\n return (T)INF;\n int mid = (lb + rb) >> 1;\n auto x = a[mid].X;\n T res = min(self(self, lb, mid), self(self, mid, rb));\n inplace_merge(a.begin() + lb, a.begin() + mid, a.begin() + rb,\n [&](auto p, auto q) { return p.Y < q.Y; });\n int ptr = 0;\n rep(i, lb, rb) {\n if (abs(a[i].X - x) >= res)\n continue;\n rep(j, 0, ptr) {\n auto sub = a[i] - buf[ptr - 1 - j];\n if (sub.Y >= res)\n break;\n chmin(res, abs(sub));\n }\n buf[ptr++] = a[i];\n }\n return res;\n };\n return rec(rec, 0, n);\n}\n\nCircle Incircle(const Point &a, const Point &b, const Point &c) {\n T A = abs(b - c), B = abs(c - a), C = abs(a - b);\n Point p(A * a.X + B * b.X + C * c.X, A * a.Y + B * b.Y + C * c.Y);\n p /= (A + B + C);\n T r = Dist(Line(a, b), p);\n return Circle(p, r);\n}\nCircle Circumcircle(const Point &a, const Point &b, const Point &c) {\n Line l1((a + b) / 2., (a + b) / 2. + (b - a) * Point(0, 1));\n Line l2((b + c) / 2., (b + c) / 2. + (c - b) * Point(0, 1));\n Point p = Intersection(l1, l2);\n return Circle(p, abs(p - a));\n}\nPoly tangent(const Point &a, const Circle &b) {\n return Intersection(b, Circle(a, sqrt(norm(b.p - a) - b.r * b.r)));\n}\nvector<Line> tangent(const Circle &a, const Circle &b) {\n vector<Line> res;\n T d = abs(a.p - b.p);\n if (eq(d, 0.))\n return res;\n Point u = unit(b.p - a.p);\n Point v = u * Point(0, 1);\n for (int t : {-1, 1}) {\n T h = (a.r + b.r * t) / d;\n if (eq(h * h, 1.)) {\n res.push_back(Line(a.p + (h > 0 ? u : -u) * a.r,\n a.p + (h > 0 ? u : -u) * a.r + v));\n } else if (1 > h * h) {\n Point U = u * h, V = v * sqrt(1 - h * h);\n res.push_back(Line(a.p + (U + V) * a.r, b.p - (U + V) * (b.r * t)));\n res.push_back(Line(a.p + (U - V) * a.r, b.p - (U - V) * (b.r * t)));\n }\n }\n return res;\n}\n\n/**\n * @brief Geometry\n */\n\nint main() {\nwhile(1) {\n int N;\n cin >> N;\n if (N == 0) return 0;\n vector<Point> P(N);\n vector<double> L(N);\n double OK = 0.0, NG = 300.0;\n rep(i,0,N) {\n double PX, PY;\n cin >> PX >> PY >> L[i];\n P[i] = Point(PX,PY);\n chmin(NG, L[i]);\n }\n while(NG - OK > eps) {\n double MID = (OK + NG) / 2.0;\n vector<Circle> C(N);\n rep(i,0,N) C[i].p = P[i], C[i].r = sqrt(L[i]*L[i]-MID*MID);\n vector<Point> V;\n rep(i,0,N) V.push_back(C[i].p);\n rep(i,0,N) {\n rep(j,i+1,N) {\n Poly Ret = Intersection(C[i],C[j]);\n for (Point IntP : Ret) V.push_back(IntP);\n }\n }\n bool check = false;\n for (Point A : V) {\n bool check2 = true;\n rep(i,0,N) {\n if (abs(A-C[i].p)>C[i].r+0.0000001) check2 = false;\n }\n if (check2) check = true;\n }\n if (check) OK = MID;\n else NG = MID;\n }\n print(OK);\n}\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3724, "score_of_the_acc": -0.6456, "final_rank": 9 }, { "submission_id": "aoj_1190_9450584", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nusing T = double;\nconst T eps = 1e-12;\nusing Point = complex<T>;\nusing Poly = vector<Point>;\n#define X real()\n#define Y imag()\ntemplate <typename T> inline bool eq(const T &a, const T &b) {\n return fabs(a - b) < eps;\n}\nbool cmp(const Point &a, const Point &b) {\n auto sub = [&](Point a) {\n return (a.Y < 0 ? -1 : (a.Y == 0 && a.X >= 0 ? 0 : 1));\n };\n if (sub(a) != sub(b))\n return sub(a) < sub(b);\n return a.Y * b.X < a.X * b.Y;\n}\nstruct Line {\n Point a, b, dir;\n Line() {}\n Line(Point _a, Point _b) : a(_a), b(_b), dir(b - a) {}\n Line(T A, T B, T C) {\n if (eq(A, .0)) {\n a = Point(0, C / B), b = Point(1 / C / B);\n } else if (eq(B, .0)) {\n a = Point(C / A, 0), b = Point(C / A, 1);\n } else {\n a = Point(0, C / B), b = Point(C / A, 0);\n }\n }\n};\nstruct Segment : Line {\n Segment() {}\n Segment(Point _a, Point _b) : Line(_a, _b) {}\n};\nstruct Circle {\n Point p;\n T r;\n Circle() {}\n Circle(Point _p, T _r) : p(_p), r(_r) {}\n};\n\nistream &operator>>(istream &is, Point &p) {\n T x, y;\n is >> x >> y;\n p = Point(x, y);\n return is;\n}\nostream &operator<<(ostream &os, Point &p) {\n os << fixed << setprecision(12) << p.X << ' ' << p.Y;\n return os;\n}\nPoint unit(const Point &a) {\n return a / abs(a);\n}\nT dot(const Point &a, const Point &b) {\n return a.X * b.X + a.Y * b.Y;\n}\nT cross(const Point &a, const Point &b) {\n return a.X * b.Y - a.Y * b.X;\n}\nPoint rot(const Point &a, const T &theta) {\n return Point(cos(theta) * a.X - sin(theta) * a.Y,\n sin(theta) * a.X + cos(theta) * a.Y);\n}\nPoint rot90(const Point &a) {\n return Point(-a.Y, a.X);\n}\nT arg(const Point &a, const Point &b, const Point &c) {\n double ret = acos(dot(a - b, c - b) / abs(a - b) / abs(c - b));\n if (cross(a - b, c - b) < 0)\n ret = -ret;\n return ret;\n}\n\nPoint Projection(const Line &l, const Point &p) {\n T t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\nPoint Projection(const Segment &l, const Point &p) {\n T t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\nPoint Reflection(const Line &l, const Point &p) {\n return p + (Projection(l, p) - p) * 2.;\n}\nint ccw(const Point &a, Point b, Point c) {\n b -= a;\n c -= a;\n if (cross(b, c) > eps)\n return 1; // ccw\n\n if (cross(b, c) < -eps)\n return -1; // cw\n\n if (dot(b, c) < 0)\n return 2; // c,a,b\n\n if (norm(b) < norm(c))\n return -2; // a,b,c\n\n return 0; // a,c,b\n\n}\nbool isOrthogonal(const Line &a, const Line &b) {\n return eq(dot(a.b - a.a, b.b - b.a), .0);\n}\nbool isParallel(const Line &a, const Line &b) {\n return eq(cross(a.b - a.a, b.b - b.a), .0);\n}\nbool isIntersect(const Segment &a, const Segment &b) {\n return ccw(a.a, a.b, b.a) * ccw(a.a, a.b, b.b) <= 0 and\n ccw(b.a, b.b, a.a) * ccw(b.a, b.b, a.b) <= 0;\n}\nint isIntersect(const Circle &a, const Circle &b) {\n T d = abs(a.p - b.p);\n if (d > a.r + b.r + eps)\n return 4;\n if (eq(d, a.r + b.r))\n return 3;\n if (eq(d, abs(a.r - b.r)))\n return 1;\n if (d < abs(a.r - b.r) - eps)\n return 0;\n return 2;\n}\nT Dist(const Line &a, const Point &b) {\n Point c = Projection(a, b);\n return abs(c - b);\n}\nT Dist(const Segment &a, const Point &b) {\n if (dot(a.b - a.a, b - a.a) < eps)\n return abs(b - a.a);\n if (dot(a.a - a.b, b - a.b) < eps)\n return abs(b - a.b);\n return abs(cross(a.b - a.a, b - a.a)) / abs(a.b - a.a);\n}\nT Dist(const Segment &a, const Segment &b) {\n if (isIntersect(a, b))\n return .0;\n T res = min({Dist(a, b.a), Dist(a, b.b), Dist(b, a.a), Dist(b, a.b)});\n return res;\n}\nPoint Intersection(const Line &a, const Line &b) {\n T d1 = cross(a.b - a.a, b.b - b.a);\n T d2 = cross(a.b - a.a, a.b - b.a);\n if (eq(d1, 0.) and eq(d2, 0.))\n return b.a;\n return b.a + (b.b - b.a) * (d2 / d1);\n}\nPoly Intersection(const Circle &a, const Line &b) {\n Poly res;\n T d = Dist(b, a.p);\n if (d > a.r + eps)\n return res;\n Point h = Projection(b, a.p);\n if (eq(d, a.r)) {\n res.push_back(h);\n return res;\n }\n Point e = unit(b.b - b.a);\n T ph = sqrt(a.r * a.r - d * d);\n res.push_back(h - e * ph);\n res.push_back(h + e * ph);\n return res;\n}\nPoly Intersection(const Circle &a, const Segment &b) {\n Line c(b.a, b.b);\n Poly sub = Intersection(a, c);\n double xmi = min(b.a.X, b.b.X), xma = max(b.a.X, b.b.X);\n double ymi = min(b.a.Y, b.b.Y), yma = max(b.a.Y, b.b.Y);\n Poly res;\n rep(i, 0, sub.size()) {\n if (xmi <= sub[i].X + eps and sub[i].X - eps <= xma and\n ymi <= sub[i].Y + eps and sub[i].Y - eps <= yma) {\n res.push_back(sub[i]);\n }\n }\n return res;\n}\nPoly Intersection(const Circle &a, const Circle &b) {\n Poly res;\n int mode = isIntersect(a, b);\n T d = abs(a.p - b.p);\n if (mode == 4 or mode == 0)\n return res;\n if (mode == 3) {\n T t = a.r / (a.r + b.r);\n res.push_back(a.p + (b.p - a.p) * t);\n return res;\n }\n if (mode == 1) {\n if (b.r < a.r - eps) {\n res.push_back(a.p + (b.p - a.p) * (a.r / d));\n } else {\n res.push_back(b.p + (a.p - b.p) * (b.r / d));\n }\n return res;\n }\n T rc = (a.r * a.r + d * d - b.r * b.r) / d / 2.;\n T rs = sqrt(a.r * a.r - rc * rc);\n if (a.r - abs(rc) < eps)\n rs = 0;\n Point e = unit(b.p - a.p);\n res.push_back(a.p + rc * e + rs * e * Point(0, 1));\n res.push_back(a.p + rc * e + rs * e * Point(0, -1));\n return res;\n}\nPoly HalfplaneIntersection(vector<Line> &H) {\n sort(ALL(H), [&](Line &l1, Line &l2) { return cmp(l1.dir, l2.dir); });\n auto outside = [&](Line &L, Point p) -> bool {\n return cross(L.dir, p - L.a) < -eps;\n };\n deque<Line> deq;\n int sz = 0;\n rep(i, 0, SZ(H)) {\n while (sz > 1 and\n outside(H[i], Intersection(deq[sz - 1], deq[sz - 2]))) {\n deq.pop_back();\n sz--;\n }\n while (sz > 1 and outside(H[i], Intersection(deq[0], deq[1]))) {\n deq.pop_front();\n sz--;\n }\n if (sz > 0 and fabs(cross(H[i].dir, deq[sz - 1].dir)) < eps) {\n if (dot(H[i].dir, deq[sz - 1].dir) < 0) {\n return {};\n }\n if (outside(H[i], deq[sz - 1].a)) {\n deq.pop_back();\n sz--;\n } else\n continue;\n }\n deq.push_back(H[i]);\n sz++;\n }\n\n while (sz > 2 and outside(deq[0], Intersection(deq[sz - 1], deq[sz - 2]))) {\n deq.pop_back();\n sz--;\n }\n while (sz > 2 and outside(deq[sz - 1], Intersection(deq[0], deq[1]))) {\n deq.pop_front();\n sz--;\n }\n if (sz < 3)\n return {};\n deq.push_back(deq.front());\n Poly ret;\n rep(i, 0, sz) ret.push_back(Intersection(deq[i], deq[i + 1]));\n return ret;\n}\n\nT Area(const Poly &a) {\n T res = 0;\n int n = a.size();\n rep(i, 0, n) res += cross(a[i], a[(i + 1) % n]);\n return fabs(res / 2.);\n}\nT Area(const Poly &a, const Circle &b) {\n int n = a.size();\n if (n < 3)\n return .0;\n auto rec = [&](auto self, const Circle &c, const Point &p1,\n const Point &p2) {\n Point va = c.p - p1, vb = c.p - p2;\n T f = cross(va, vb), res = .0;\n if (eq(f, .0))\n return res;\n if (max(abs(va), abs(vb)) < c.r + eps)\n return f;\n if (Dist(Segment(p1, p2), c.p) > c.r - eps)\n return c.r * c.r * arg(vb * conj(va));\n auto u = Intersection(c, Segment(p1, p2));\n Poly sub;\n sub.push_back(p1);\n for (auto &x : u)\n sub.push_back(x);\n sub.push_back(p2);\n rep(i, 0, sub.size() - 1) res += self(self, c, sub[i], sub[i + 1]);\n return res;\n };\n T res = .0;\n rep(i, 0, n) res += rec(rec, b, a[i], a[(i + 1) % n]);\n return fabs(res / 2.);\n}\nT Area(const Circle &a, const Circle &b) {\n T d = abs(a.p - b.p);\n if (d >= a.r + b.r - eps)\n return .0;\n if (d <= abs(a.r - b.r) + eps) {\n T r = min(a.r, b.r);\n return M_PI * r * r;\n }\n T ath = acos((a.r * a.r + d * d - b.r * b.r) / d / a.r / 2.);\n T res = a.r * a.r * (ath - sin(ath * 2) / 2.);\n T bth = acos((b.r * b.r + d * d - a.r * a.r) / d / b.r / 2.);\n res += b.r * b.r * (bth - sin(bth * 2) / 2.);\n return fabs(res);\n}\nbool isConvex(const Poly &a) {\n int n = a.size();\n int cur, pre, nxt;\n rep(i, 0, n) {\n pre = (i - 1 + n) % n;\n nxt = (i + 1) % n;\n cur = i;\n if (ccw(a[pre], a[cur], a[nxt]) == -1)\n return 0;\n }\n return 1;\n}\nint isContained(const Poly &a,\n const Point &b) { // 0:not contain,1:on edge,2:contain\n\n bool res = 0;\n int n = a.size();\n rep(i, 0, n) {\n Point p = a[i] - b, q = a[(i + 1) % n] - b;\n if (p.Y > q.Y)\n swap(p, q);\n if (p.Y < eps and eps < q.Y and cross(p, q) > eps)\n res ^= 1;\n if (eq(cross(p, q), .0) and dot(p, q) < eps)\n return 1;\n }\n return (res ? 2 : 0);\n}\nPoly ConvexHull(Poly &a) {\n sort(ALL(a), [](const Point &p, const Point &q) {\n return (eq(p.Y, q.Y) ? p.X < q.X : p.Y < q.Y);\n });\n a.erase(unique(ALL(a)), a.end());\n int n = a.size(), k = 0;\n Poly res(n * 2);\n for (int i = 0; i < n; res[k++] = a[i++]) {\n while (k >= 2 and\n cross(res[k - 1] - res[k - 2], a[i] - res[k - 1]) < eps)\n k--;\n }\n for (int i = n - 2, t = k + 1; i >= 0; res[k++] = a[i--]) {\n while (k >= t and\n cross(res[k - 1] - res[k - 2], a[i] - res[k - 1]) < eps)\n k--;\n }\n res.resize(k - 1);\n return res;\n}\nT Diam(const Poly &a) {\n int n = a.size();\n int x = 0, y = 0;\n rep(i, 1, n) {\n if (a[i].Y > a[x].Y)\n x = i;\n if (a[i].Y < a[y].Y)\n y = i;\n }\n T res = abs(a[x] - a[y]);\n int i = x, j = y;\n do {\n if (cross(a[(i + 1) % n] - a[i], a[(j + 1) % n] - a[j]) < 0)\n i = (i + 1) % n;\n else\n j = (j + 1) % n;\n chmax(res, abs(a[i] - a[j]));\n } while (i != x or j != y);\n return res;\n}\nPoly Cut(const Poly &a, const Line &l) {\n int n = a.size();\n Poly res;\n rep(i, 0, n) {\n Point p = a[i], q = a[(i + 1) % n];\n if (ccw(l.a, l.b, p) != -1)\n res.push_back(p);\n if (ccw(l.a, l.b, p) * ccw(l.a, l.b, q) < 0)\n res.push_back(Intersection(Line(p, q), l));\n }\n return res;\n}\n\nT Closest(Poly &a) {\n int n = a.size();\n if (n <= 1)\n return 0;\n sort(ALL(a), [&](Point a, Point b) {\n return (eq(a.X, b.X) ? a.Y < b.Y : a.X < b.X);\n });\n Poly buf(n);\n auto rec = [&](auto self, int lb, int rb) -> T {\n if (rb - lb <= 1)\n return (T)INF;\n int mid = (lb + rb) >> 1;\n auto x = a[mid].X;\n T res = min(self(self, lb, mid), self(self, mid, rb));\n inplace_merge(a.begin() + lb, a.begin() + mid, a.begin() + rb,\n [&](auto p, auto q) { return p.Y < q.Y; });\n int ptr = 0;\n rep(i, lb, rb) {\n if (abs(a[i].X - x) >= res)\n continue;\n rep(j, 0, ptr) {\n auto sub = a[i] - buf[ptr - 1 - j];\n if (sub.Y >= res)\n break;\n chmin(res, abs(sub));\n }\n buf[ptr++] = a[i];\n }\n return res;\n };\n return rec(rec, 0, n);\n}\n\nCircle Incircle(const Point &a, const Point &b, const Point &c) {\n T A = abs(b - c), B = abs(c - a), C = abs(a - b);\n Point p(A * a.X + B * b.X + C * c.X, A * a.Y + B * b.Y + C * c.Y);\n p /= (A + B + C);\n T r = Dist(Line(a, b), p);\n return Circle(p, r);\n}\nCircle Circumcircle(const Point &a, const Point &b, const Point &c) {\n Line l1((a + b) / 2., (a + b) / 2. + (b - a) * Point(0, 1));\n Line l2((b + c) / 2., (b + c) / 2. + (c - b) * Point(0, 1));\n Point p = Intersection(l1, l2);\n return Circle(p, abs(p - a));\n}\nPoly tangent(const Point &a, const Circle &b) {\n return Intersection(b, Circle(a, sqrt(norm(b.p - a) - b.r * b.r)));\n}\nvector<Line> tangent(const Circle &a, const Circle &b) {\n vector<Line> res;\n T d = abs(a.p - b.p);\n if (eq(d, 0.))\n return res;\n Point u = unit(b.p - a.p);\n Point v = u * Point(0, 1);\n for (int t : {-1, 1}) {\n T h = (a.r + b.r * t) / d;\n if (eq(h * h, 1.)) {\n res.push_back(Line(a.p + (h > 0 ? u : -u) * a.r,\n a.p + (h > 0 ? u : -u) * a.r + v));\n } else if (1 > h * h) {\n Point U = u * h, V = v * sqrt(1 - h * h);\n res.push_back(Line(a.p + (U + V) * a.r, b.p - (U + V) * (b.r * t)));\n res.push_back(Line(a.p + (U - V) * a.r, b.p - (U - V) * (b.r * t)));\n }\n }\n return res;\n}\n\n/**\n * @brief Geometry\n */\n\nint main() {\nwhile(1) {\n int N;\n cin >> N;\n if (N == 0) return 0;\n vector<Point> P(N);\n vector<double> L(N);\n double OK = 0.0, NG = 300.0;\n rep(i,0,N) {\n double PX, PY;\n cin >> PX >> PY >> L[i];\n P[i] = Point(PX,PY);\n chmin(NG, L[i]);\n }\n while(NG - OK > eps) {\n double MID = (OK + NG) / 2;\n vector<Circle> C(N);\n rep(i,0,N) C[i].p = P[i], C[i].r = sqrt(L[i]*L[i]-MID*MID);\n vector<Point> V;\n rep(i,0,N) V.push_back(C[i].p);\n rep(i,0,N) {\n rep(j,i+1,N) {\n Poly Ret = Intersection(C[i],C[j]);\n for (Point IntP : Ret) V.push_back(IntP);\n }\n }\n bool check = false;\n for (Point A : V) {\n bool check2 = true;\n rep(i,0,N) {\n if (sqrt(norm(A-C[i].p))>C[i].r+eps) check2 = false;\n }\n if (check2) check = true;\n }\n if (check) OK = MID;\n else NG = MID;\n }\n print(OK);\n}\n}", "accuracy": 0.5, "time_ms": 120, "memory_kb": 3728, "score_of_the_acc": -0.6602, "final_rank": 20 }, { "submission_id": "aoj_1190_9361808", "code_snippet": "#include <bits/stdc++.h>\n\n#include <algorithm>\n#include <cmath>\n#include <iostream>\n#include <iterator>\n#include <utility>\n#include <vector>\n\nusing Real = long double;\nconstexpr Real EPS = 1e-10;\nconst Real PI = std::acos(-1);\n\nint sign(Real x) {\n return x < -EPS ? -1 : x > EPS ? 1 : 0;\n}\n\nbool eq(Real lhs, Real rhs) {\n return sign(rhs - lhs) == 0;\n}\n\nbool lte(Real lhs, Real rhs) {\n return sign(rhs - lhs) >= 0;\n}\n\nbool lt(Real lhs, Real rhs) {\n return sign(rhs - lhs) > 0;\n}\n\nbool gte(Real lhs, Real rhs) {\n return lte(rhs, lhs);\n}\n\nbool gt(Real lhs, Real rhs) {\n return lt(rhs, lhs);\n}\n\nstruct Point {\n Real x;\n Real y;\n Point(Real x = 0, Real y = 0): x(x), y(y) {}\n Point& operator+=(Point rhs) {\n this->x += rhs.x;\n this->y += rhs.y;\n return *this;\n }\n Point& operator-=(Point rhs) {\n this->x -= rhs.x;\n this->y -= rhs.y;\n return *this;\n }\n Point& operator*=(Real k) {\n this->x *= k;\n this->y *= k;\n return *this;\n }\n Point& operator/=(Real k) {\n this->x /= k;\n this->y /= k;\n return *this;\n }\n friend Point operator+(Point lhs, Point rhs) {\n return lhs += rhs;\n }\n friend Point operator-(Point lhs, Point rhs) {\n return lhs -= rhs;\n }\n friend Point operator*(Point p, Real k) {\n return p *= k;\n }\n friend Point operator/(Point p, Real k) {\n return p /= k;\n }\n friend Point operator*(Real k, Point p) {\n return p * k;\n }\n friend Point operator/(Real k, Point p) {\n return p / k;\n }\n friend bool operator==(Point lhs, Point rhs) {\n return eq(lhs.x, rhs.x) && eq(lhs.y, rhs.y);\n }\n friend bool operator!=(Point lhs, Point rhs) {\n return !(lhs == rhs);\n }\n friend bool operator<(Point lhs, Point rhs) {\n if (eq(lhs.x, rhs.x)) return lt(lhs.y, rhs.y);\n return lt(lhs.x, rhs.x);\n }\n friend bool operator<=(Point lhs, Point rhs) {\n return lhs == rhs || lhs < rhs;\n }\n friend bool operator>(Point lhs, Point rhs) {\n return rhs < lhs;\n }\n friend bool operator>=(Point lhs, Point rhs) {\n return rhs <= lhs;\n }\n friend std::istream& operator>>(std::istream& is, Point& p) {\n is >> p.x >> p.y;\n return is;\n }\n friend std::ostream& operator<<(std::ostream& os, Point& p) {\n os << p.x << ' ' << p.y;\n return os;\n }\n};\n\nusing Points = std::vector<Point>;\nusing Polygon = Points;\nusing Vector = Point;\n\nReal norm(Vector p) {\n return p.x * p.x + p.y * p.y;\n}\n\nReal abs(Vector p) {\n return std::sqrt(norm(p));\n}\n\nReal dot(Vector lhs, Vector rhs) {\n return lhs.x * rhs.x + lhs.y * rhs.y;\n}\n\nReal cross(Vector lhs, Vector rhs) {\n return lhs.x * rhs.y - lhs.y * rhs.x;\n}\n\nint ccw(Point p0, Point p1, Point p2) {\n Vector a = p1 - p0;\n Vector b = p2 - p0;\n\n if (cross(a, b) > EPS) return 1;\n\n if (cross(a, b) < -EPS) return -1;\n\n if (dot(a, b) < 0) return 2;\n\n if (norm(a) < norm(b)) return -2;\n\n return 0;\n}\n\nstruct Circle {\n Real r;\n Point c;\n Circle() {}\n Circle(Real r, Point c): r(r), c(c) {}\n};\n\nstruct Segment {\n Segment() {}\n Segment(Point p0, Point p1): p0(p0), p1(p1) {}\n Point p0, p1;\n};\n\nstruct Line {\n Line() {}\n Line(Point p0, Point p1): p0(p0), p1(p1) {}\n explicit Line(Segment s): p0(s.p0), p1(s.p1) {}\n Point p0, p1;\n};\n\nReal distance(Point lhs, Point rhs) {\n return abs(rhs - lhs);\n}\n\nReal distance(Line l, Point p) {\n return std::abs(cross(l.p1 - l.p0, p - l.p0)) / abs(l.p1 - l.p0);\n}\n\nReal distance(Segment s, Point p) {\n if (dot(s.p1 - s.p0, p - s.p0) < 0) {\n return distance(p, s.p0);\n }\n if (dot(s.p0 - s.p1, p - s.p1) < 0) {\n return distance(p, s.p1);\n }\n return distance(Line(s), p);\n}\n\nbool intersect(Segment lhs, Segment rhs) {\n return ccw(lhs.p0, lhs.p1, rhs.p0) * ccw(lhs.p0, lhs.p1, rhs.p1) <= 0\n && ccw(rhs.p0, rhs.p1, lhs.p0) * ccw(rhs.p0, rhs.p1, lhs.p1) <= 0;\n}\n\nbool intersect(Segment s, Point p) {\n return ccw(s.p0, s.p1, p) == 0;\n}\n\nReal distance(Segment lhs, Segment rhs) {\n if (intersect(lhs, rhs)) {\n return Real(0);\n }\n return std::min({distance(lhs, rhs.p0), distance(lhs, rhs.p1), distance(rhs, lhs.p0), distance(rhs, lhs.p1)});\n}\n\nbool parallel(Vector lhs, Vector rhs) {\n return eq(cross(lhs, rhs), 0);\n}\n\nbool parallel(Segment lhs, Segment rhs) {\n return parallel(lhs.p0 - lhs.p1, rhs.p0 - rhs.p1);\n}\n\nbool parallel(Line lhs, Line rhs) {\n return parallel(lhs.p0 - lhs.p1, rhs.p0 - rhs.p1);\n}\n\nPoint crosspoint(Line lhs, Line rhs) {\n Real a = cross(lhs.p1 - lhs.p0, rhs.p1 - rhs.p0);\n Real b = cross(lhs.p1 - lhs.p0, lhs.p1 - rhs.p0);\n return rhs.p0 + (rhs.p1 - rhs.p0) * b / a;\n}\n\nbool intersect(Line l, Segment s) {\n return ccw(l.p0, l.p1, s.p0) * ccw(l.p0, l.p1, s.p1) <= 0;\n}\n\nbool intersect(Circle c, Line l) {\n return lte(distance(l, c.c), c.r);\n}\n\nbool contain(Circle c, Point p) {\n return lt(distance(c.c, p), c.r);\n}\n\nbool intersect(Circle c, Point p) {\n return eq(distance(c.c, p), c.r);\n}\n\nbool internal(Circle c, Point p) {\n return lt(distance(c.c, p), c.r);\n}\n\nbool intersect(Circle c, Segment s) {\n return lte(distance(s, c.c), c.r);\n}\n\nint intersect(Circle lhs, Circle rhs) {\n if (gt(lhs.r, rhs.r)) std::swap(lhs, rhs);\n Real d = distance(lhs.c, rhs.c);\n if (lt(lhs.r + rhs.r, d)) return 4;\n if (eq(lhs.r + rhs.r, d)) return 3;\n if (gt(lhs.r + d, rhs.r)) return 2;\n if (eq(lhs.r + d, rhs.r)) return 1;\n return 0;\n}\n\nbool orthogonal(Vector lhs, Vector rhs) {\n return eq(dot(lhs, rhs), 0);\n}\n\nbool orthogonal(Segment lhs, Segment rhs) {\n return orthogonal(lhs.p0 - lhs.p1, rhs.p0 - rhs.p1);\n}\n\nbool orthogonal(Line lhs, Line rhs) {\n return orthogonal(lhs.p0 - lhs.p1, rhs.p0 - rhs.p1);\n}\n\nPoint crosspoint(Segment lhs, Segment rhs) {\n Real d0 = distance(Line(lhs.p0, lhs.p1), rhs.p0);\n Real d1 = distance(Line(lhs.p0, lhs.p1), rhs.p1);\n return rhs.p0 + (rhs.p1 - rhs.p0) * (d0 / (d0 + d1));\n}\n\nReal arg(Vector p) {\n return std::atan2(p.y, p.x);\n}\n\nVector polar(Real a, Real r) {\n return Point(std::cos(r) * a, std::sin(r) * a);\n}\n\nPoint rotate(Point p, Real t) {\n Point v = polar(1, t);\n return Point(p.x * v.x - p.y * v.y, p.x * v.y + p.y * v.x);\n}\n\nReal angle(Point p0, Point p1, Point p2) {\n Real a = arg(p0 - p1);\n Real b = arg(p2 - p1);\n if (gt(a, b)) std::swap(a, b);\n return std::min(b - a, 2 * PI - (b - a));\n}\n\nPoints crosspoint(Circle lhs, Circle rhs) {\n Real d = abs(lhs.c - rhs.c);\n if (eq(d, lhs.r + rhs.r)) return {lhs.c + lhs.r * (rhs.c - lhs.c) / d};\n Real a = std::acos((lhs.r * lhs.r + d * d - rhs.r * rhs.r) / (2 * lhs.r * d));\n Real t = arg(rhs.c - lhs.c);\n return {lhs.c + polar(lhs.r, t + a), lhs.c + polar(lhs.r, t - a)};\n}\n\nPoint projection(Segment s, Point p) {\n Vector a = p - s.p0;\n Vector b = s.p1 - s.p0;\n Real t = dot(a, b) / norm(b);\n return s.p0 + t * b;\n}\n\nPoint projection(Line l, Point p) {\n Vector a = p - l.p0;\n Vector b = l.p1 - l.p0;\n Real t = dot(a, b) / norm(b);\n return l.p0 + t * b;\n}\n\nPoint reflection(Segment s, Point p) {\n return p + (projection(s, p) - p) * Real(2);\n}\n\nPoint reflection(Line l, Point p) {\n return p + (projection(l, p) - p) * Real(2);\n}\n\nPoints crosspoint(Circle c, Line l) {\n Vector p = projection(l, c.c);\n Real t = std::sqrt(c.r * c.r - norm(c.c - p));\n if (eq(t, 0)) return {p};\n Vector e = (l.p1 - l.p0) / abs(l.p1 - l.p0);\n return {p + t * e, p + -t * e};\n}\n\nReal area(Polygon poly) {\n int n = poly.size();\n Real result = 0;\n for (int i = 0; i < n; i++) {\n result += cross(poly[i], poly[(i + 1) % n]);\n }\n return result / 2;\n}\n\nReal perimeter(Polygon poly) {\n int n = poly.size();\n Real result = 0;\n for (int i = 0; i < n; i++) {\n result += abs(poly[i] - poly[(i + 1) % n]);\n }\n return result;\n}\n\nbool convex(Polygon poly) {\n int n = poly.size();\n for (int i = 0; i < n; i++) {\n if (ccw(poly[i], poly[(i + 1) % n], poly[(i + 2) % n]) == -1) return false;\n }\n return true;\n}\n\nint contain(Polygon poly, Point p) {\n int n = poly.size();\n bool parity = false;\n for (int i = 0; i < n; i++) {\n Point a = poly[i] - p;\n Point b = poly[(i + 1) % n] - p;\n if (gt(a.y, b.y)) std::swap(a, b);\n if (lte(a.y, 0) && lt(0, b.y) && lt(cross(a, b), 0)) parity ^= true;\n if (eq(cross(a, b), 0) && lte(dot(a, b), 0)) return 1;\n }\n return (parity ? 2 : 0);\n}\n\nPolygon convex_hull(Points points) {\n std::sort(points.begin(), points.end());\n if (points.size() < 3) return points;\n int n = points.size();\n Points lower, upper;\n lower.push_back(points[n - 1]);\n lower.push_back(points[n - 2]);\n upper.push_back(points[0]);\n upper.push_back(points[1]);\n for (int i = n - 3; i >= 0; i--) {\n for (int m = lower.size(); m >= 2 && ccw(lower[m - 2], lower[m - 1], points[i]) >= 0; m--) {\n lower.pop_back();\n }\n lower.push_back(points[i]);\n }\n for (int i = 2; i < n; i++) {\n for (int m = upper.size(); m >= 2 && ccw(upper[m - 2], upper[m - 1], points[i]) >= 0; m--) {\n upper.pop_back();\n }\n upper.push_back(points[i]);\n }\n std::reverse(lower.begin(), lower.end());\n std::copy(std::next(upper.rbegin()), std::prev(upper.rend()), std::back_inserter(lower));\n return lower;\n}\n\nPolygon convex_cut(Polygon poly, Line l) {\n int n = poly.size();\n Polygon res;\n for (int i = 0; i < n; i++) {\n Point a = poly[i];\n Point b = poly[(i + 1) % n];\n if (ccw(l.p0, l.p1, a) != -1) res.push_back(a);\n if (ccw(l.p0, l.p1, a) * ccw(l.p0, l.p1, b) == -1) {\n res.push_back(crosspoint(l, Line(a, b)));\n }\n }\n return res;\n}\n\nLine bisector(Point p0, Point p1, Point p2) {\n return Line(p1, p1 + polar(1, angle(p0, p1, p2) / 2));\n}\n\nCircle incircle(Point p0, Point p1, Point p2) {\n Point c = crosspoint(bisector(p0, p1, p2), bisector(p1, p2, p0));\n Real r = std::abs(2 * area({p0, p1, p2}) / perimeter({p0, p1, p2}));\n return Circle(r, c);\n}\n\nLine perpendicular(Line l, Point p) {\n Vector v = l.p1 - l.p0;\n return Line(p, p + Vector(-v.y, v.x));\n}\n\nLine perpendicular_bisector(Segment s) {\n return perpendicular(Line(s), (s.p0 + s.p1) / 2);\n}\n\nCircle circumscribed_circle(Point p0, Point p1, Point p2) {\n Point c = crosspoint(perpendicular_bisector(Segment(p0, p1)), perpendicular_bisector(Segment(p0, p2)));\n return Circle(distance(p0, c), c);\n}\n\nReal area(Circle c) {\n return c.r * c.r * PI;\n}\n\nPoints tangent(Circle c, Point p) {\n return crosspoint(c, Circle(std::sqrt(norm(c.c - p) - c.r * c.r), p));\n}\n\nbool contain(Polygon ps, Segment s) {\n if (contain(ps, s.p0) == 0 || contain(ps, s.p1) == 0) return false;\n int n = ps.size();\n Points cps;\n cps.push_back(s.p0);\n cps.push_back(s.p1);\n for (int i = 0; i < n; i++) {\n Segment t(ps[i], ps[(i + 1) % n]);\n if (parallel(s, t)) continue;\n if (!intersect(s, t)) continue;\n Point cp = crosspoint(s, t);\n if (cp != s.p0 && cp != s.p1 && cp != t.p0 && cp != t.p1) return false;\n cps.push_back(cp);\n }\n std::sort(cps.begin(), cps.end());\n int m = cps.size();\n for (int i = 0; i + 1 < m; i++) {\n if (contain(ps, (cps[i] + cps[i + 1]) / 2) == 0) return false;\n }\n return true;\n}\n\nstd::pair<Points, Points> lower_and_upper_convex_hull(Polygon ps) {\n auto it = std::max_element(ps.begin(), ps.end());\n Points lower(ps.begin(), it + 1);\n Points upper(it, ps.end());\n upper.push_back(ps.front());\n std::reverse(upper.begin(), upper.end());\n return {lower, upper};\n}\n\nReal y(Line l, Real x) {\n if (eq(l.p0.x, l.p1.x)) return std::min(l.p0.y, l.p1.y);\n return x * (l.p1.y - l.p0.y) / (l.p1.x - l.p0.x);\n}\n\nPolygon common_polygon(Polygon lhs, Polygon rhs) {\n if (lhs.size() < 3 || rhs.size() < 3) return {};\n auto [ll, lu] = lower_and_upper_convex_hull(lhs);\n auto [rl, ru] = lower_and_upper_convex_hull(rhs);\n constexpr Real INF = 1e18;\n ll.push_back(Point(INF, INF));\n lu.push_back(Point(INF, INF));\n rl.push_back(Point(INF, INF));\n ru.push_back(Point(INF, INF));\n\n Points lower, upper;\n for (int i = 0, j = 0, k = 0, l = 0;;) {\n if (ll[i] <= lu[j] && ll[i] <= rl[k] && ll[i] <= ru[l]) {\n if (0 < k && 0 < l) {\n if (lte(y(Line(rl[k - 1], rl[k]), ll[i].x), ll[i].y)\n && lte(ll[i].y, y(Line(ru[l - 1], ru[l]), ll[i].x))) {\n lower.push_back(ll[i]);\n }\n }\n if (i + 2 < (int)ll.size()) {\n Segment lls(ll[i], ll[i + 1]);\n if (0 < k) {\n Segment rls(rl[k - 1], rl[k]);\n if (intersect(lls, rls) && !parallel(lls, rls)) {\n lower.push_back(crosspoint(lls, rls));\n }\n }\n if (0 < l) {\n Segment rus(ru[l - 1], ru[l]);\n if (intersect(lls, rus) && !parallel(lls, rus)) {\n lower.push_back(crosspoint(lls, rus));\n upper.push_back(crosspoint(lls, rus));\n }\n }\n }\n i++;\n if (i + 1 == (int)ll.size() && j + 1 == (int)lu.size()) break;\n } else if (lu[j] <= ll[i] && lu[j] <= rl[k] && lu[j] <= ru[l]) {\n if (0 < k && 0 < l) {\n if (lte(y(Line(rl[k - 1], rl[k]), lu[j].x), lu[j].y)\n && lte(lu[j].y, y(Line(ru[l - 1], ru[l]), lu[j].x))) {\n upper.push_back(lu[j]);\n }\n }\n if (j + 2 < (int)lu.size()) {\n Segment lus(lu[j], lu[j + 1]);\n if (0 < l) {\n Segment rus(ru[l - 1], ru[l]);\n if (intersect(lus, rus) && !parallel(lus, rus)) {\n upper.push_back(crosspoint(lus, rus));\n }\n }\n if (0 < k) {\n Segment rls(rl[k - 1], rl[k]);\n if (intersect(lus, rls) && !parallel(lus, rls)) {\n lower.push_back(crosspoint(lus, rls));\n upper.push_back(crosspoint(lus, rls));\n }\n }\n }\n j++;\n if (i + 1 == (int)ll.size() && j + 1 == (int)lu.size()) break;\n } else if (rl[k] <= ll[i] && rl[k] <= lu[j] && rl[k] <= ru[l]) {\n if (0 < i && 0 < j) {\n if (lte(y(Line(ll[i - 1], ll[i]), rl[k].x), rl[k].y)\n && lte(rl[k].y, y(Line(lu[j - 1], lu[j]), rl[k].x))) {\n lower.push_back(rl[k]);\n }\n }\n if (k + 2 < (int)rl.size()) {\n Segment rls(rl[k], rl[k + 1]);\n if (0 < i) {\n Segment lls(ll[i - 1], ll[i]);\n if (intersect(rls, lls) && !parallel(rls, lls)) {\n lower.push_back(crosspoint(rls, lls));\n }\n }\n if (0 < j) {\n Segment lus(lu[j - 1], lu[j]);\n if (intersect(rls, lus) && !parallel(rls, lus)) {\n lower.push_back(crosspoint(rls, lus));\n upper.push_back(crosspoint(rls, lus));\n }\n }\n }\n k++;\n if (k + 1 == (int)rl.size() && l + 1 == (int)ru.size()) break;\n } else {\n if (0 < i && 0 < j) {\n if (lte(y(Line(ll[i - 1], ll[i]), ru[l].x), ru[l].y)\n && lte(ru[l].y, y(Line(lu[j - 1], lu[j]), ru[l].x))) {\n upper.push_back(ru[l]);\n }\n }\n if (l + 2 < (int)ru.size()) {\n Segment rus(ru[l], ru[l + 1]);\n if (0 < j) {\n Segment lus(lu[j - 1], lu[j]);\n if (intersect(rus, lus) && !parallel(rus, lus)) {\n upper.push_back(crosspoint(rus, lus));\n }\n }\n if (0 < i) {\n Segment lls(ll[i - 1], ll[i]);\n if (intersect(rus, lls) && !parallel(rus, lls)) {\n lower.push_back(crosspoint(rus, lls));\n upper.push_back(crosspoint(rus, lls));\n }\n }\n }\n l++;\n if (k + 1 == (int)rl.size() && l + 1 == (int)ru.size()) break;\n }\n }\n if (lower.empty() && upper.empty()) return {};\n std::cerr << lhs.size() << ' ' << rhs.size() << ' ' << lower.size() << ' ' << upper.size() << std::endl;\n\n std::copy(std::next(upper.rbegin()), std::prev(upper.rend()), std::back_inserter(lower));\n return lower;\n}\n\nbool intersect(Polygon lhs, Polygon rhs) {\n return lt(0, area(common_polygon(lhs, rhs)));\n}\n\nusing ll = long long;\n\n#define rep(i, l, r) for (ll i = (l); i < (r); i++)\n#define rrep(i, r, l) for (ll i = (r); i-- > (l);)\ntemplate <class T, class U>\nbool chmin(T& lhs, U rhs) {\n return lhs > rhs ? (lhs = rhs, true) : false;\n}\ntemplate <class T, class U>\nbool chmax(T& lhs, U rhs) {\n return lhs < rhs ? (lhs = rhs, true) : false;\n}\nusing namespace std;\n\nstruct Sphere {\n Real r;\n Point c;\n Sphere() {}\n Sphere(Real r, Point c): r(r), c(c) {}\n};\n\nint solve() {\n int n;\n cin >> n;\n if (n == 0) return 1;\n vector<Sphere> ss;\n rep(i, 0, n) {\n Sphere s;\n cin >> s.c >> s.r;\n ss.push_back(s);\n }\n\n auto satisfy = [&](Real h) {\n vector<Circle> cs;\n rep(i, 0, n) {\n if (lt(ss[i].r, h)) {\n return false;\n }\n Real r = sqrt(max(Real(0), ss[i].r * ss[i].r - h * h));\n cs.push_back(Circle(r, ss[i].c));\n }\n\n vector<bool> removed(n);\n int valid = n;\n rep(i, 0, n) rep(j, 0, n) if (i != j) {\n if (intersect(cs[i], cs[j]) == 0 && gt(cs[i].r, cs[j].r)) {\n removed[i] = true;\n valid--;\n break;\n }\n }\n\n Points cps;\n rep(i, 0, n) if (!removed[i]) {\n auto a = cs[i];\n rep(j, i + 1, n) if (!removed[i]) {\n auto b = cs[j];\n if (intersect(a, b) != 0 && intersect(a, b) != 4) {\n auto temp = crosspoint(a, b);\n copy(temp.begin(), temp.end(), back_inserter(cps));\n }\n }\n }\n\n for (auto cp: cps) {\n bool ok = true;\n for (auto c: cs) {\n ok &= contain(c, cp) || intersect(c, cp);\n }\n if (ok) return true;\n }\n\n return valid == 1;\n };\n\n Real ok = 0;\n Real ng = 500;\n const int LOOP = 100;\n rep(loop, 0, LOOP) {\n Real key = (ok + ng) / 2;\n (satisfy(key) ? ok : ng) = key;\n }\n cout << fixed << setprecision(10);\n cout << ok << endl;\n return 0;\n}\n\nint main() {\n while (!solve())\n ;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 3796, "score_of_the_acc": -0.8689, "final_rank": 17 }, { "submission_id": "aoj_1190_9302250", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (int i = 0; i < (int) (n); i++)\ntemplate<class T>\nvoid chmax(T& p, T q) { if (p < q)p = q; };\n\nll N;\nusing point = pair<double, double>;\nconst double eps = 1e-6;\n\npair<point, point> CC(point P, double R, point Q, double S) {\n Q.first -= P.first;\n Q.second -= P.second;\n double a = Q.first * Q.first + Q.second * Q.second + R * R - S * S;\n a /= 2.0;\n double d = Q.first * Q.first + Q.second * Q.second;\n double b = sqrt(d * R * R - a * a);\n point res1, res2;\n res1 = { (a * Q.first + Q.second * b) / d,(a * Q.second - Q.first * b) / d };\n res2 = { (a * Q.first - Q.second * b) / d,(a * Q.second + Q.first * b) / d };\n res1.first += P.first;\n res2.first += P.first;\n res1.second += P.second;\n res2.second += P.second;\n return { res1,res2 };\n}\n\nvoid solve() {\n vector<point> P(N);\n vector<double> R(N);\n rep(i, N)cin >> P[i].first >> P[i].second >> R[i];\n double down = 0.5, up = 305.0;\n rep(_, 100) {\n double M = (up + down) / 2.0;\n bool OK = 1;\n vector<double> T(N);\n rep(i, N) {\n if (R[i] * R[i] < M * M) {\n OK = 0;\n break;\n }\n T[i] = sqrt(R[i] * R[i] - M * M);\n }\n vector<point> CP;\n rep(i, N)CP.push_back(P[i]);\n rep(i, N)rep(j, i) {\n double dx = P[i].first - P[j].first;\n double dy = P[i].second - P[j].second;\n double dr = T[i] + T[j];\n if (dx * dx + dy * dy >= dr * dr) {\n continue;\n }\n auto [p1, p2] = CC(P[i], T[i], P[j], T[j]);\n CP.push_back(p1);\n CP.push_back(p2);\n }\n bool EG = 0;\n for (auto p : CP) {\n ll cnt = 0;\n rep(i, N) {\n double dx = p.first - P[i].first;\n double dy = p.second - P[i].second;\n if (dx * dx + dy * dy <= T[i] * T[i] + eps)cnt++;\n }\n if (cnt == N)EG = 1;\n }\n if (!EG)OK = 0;\n if (OK)down = M;\n else up = M;\n }\n cout << fixed << setprecision(15) << up << endl;\n\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n while (cin >> N) {\n if (N == 0)return 0;\n solve();\n }\n\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3644, "score_of_the_acc": -0.4806, "final_rank": 6 }, { "submission_id": "aoj_1190_9211776", "code_snippet": "#include <bits/stdc++.h>\n\nusing R = long double;\nusing Interval = std::pair<R, R>;\n\nconst R EPS{1e-12l};\nconst R PI{acosl(-1.0l)};\nbool Negative(R v) {\n return v < -EPS;\n}\nbool Positive(R v) {\n return v > EPS;\n}\nbool Zero(R v) {\n return !Negative(v) and !Positive(v);\n}\nbool Smaller(R a, R b) {\n return Negative(a - b);\n}\nbool Bigger(R a, R b) {\n return Positive(a - b);\n}\nbool Equal(R a, R b) {\n return !Smaller(a, b) and !Bigger(a, b);\n}\n\nR Square(R v) {\n return Zero(v) ? 0.0l : v * v;\n}\n\nstruct Point {\n R x, y;\n Point() = default;\n Point(R x, R y) : x{x}, y{y} {}\n Point(const Point& p) : x{p.x}, y{p.y} {}\n R normSquare() const {\n return Square(x) + Square(y);\n }\n R norm() const {\n return sqrtl(normSquare());\n }\n Point normalized() const {\n assert(!Zero(x) or !Zero(y));\n R v{norm()};\n return Point{x / v, y / v};\n }\n Point rotatedByRad(R rad) const {\n return Point{\n x * cosl(rad) - y * sinl(rad),\n x * sinl(rad) + y * cosl(rad)\n };\n }\n Point rotaedByArc(R arc) const {\n return rotatedByRad((arc * PI) / 180.0l);\n }\n friend std::ostream& operator<<(std::ostream& os, const Point& p) {\n os << '(' << p.x << ',' << p.y << ')';\n return os;\n }\n friend Point operator*(const Point& p, R v) {\n return Point{p.x * v, p.y * v};\n }\n friend Point operator+(const Point& p, const Point& q) {\n return Point{p.x + q.x, p.y + q.y};\n }\n friend Point operator-(const Point& p, const Point& q) {\n return Point{p.x - q.x, p.y - q.y};\n }\n friend R DistanceSquare(const Point& p, const Point& q) {\n Point diff{p - q};\n return diff.normSquare();\n }\n friend R Distance(const Point& p, const Point& q) {\n return sqrtl(DistanceSquare(p, q));\n }\n};\n\nstruct Circle {\n Point p;\n R r;\n Circle() = default;\n Circle(R x, R y, R r) : p{x, y}, r{r} {}\n R x() const { return p.x; };\n R y() const { return p.y; }\n friend int NumberCommonTangent(const Circle& c0, const Circle& c1) {\n R dist{DistanceSquare(c0.p, c1.p)};\n R down{Square(std::abs(c0.r - c1.r))};\n if (Smaller(dist, down)) return 0;\n if (Equal(dist, down)) return 1;\n R up{Square(c0.r + c1.r)};\n if (Smaller(dist, up)) return 2;\n if (Equal(dist, up)) return 3;\n return 4;\n }\n bool contains(const Circle& c) const {\n return Bigger(r, c.r) and NumberCommonTangent(*this, c) == 0;\n }\n friend bool Intersect(const Circle& c0, const Circle& c1) {\n int num{NumberCommonTangent(c0, c1)};\n return 0 < num and num < 4;\n }\n friend std::vector<Point> CrossPoint(const Circle& l, const Circle& r) {\n assert(Intersect(l, r));\n R d{Distance(l.p, r.p)};\n R cosine{(Square(l.r) + Square(d) - Square(r.r)) / (2.0l * l.r * d)};\n R rc{l.r * cosine};\n R rs{sqrtl(Square(l.r) - Square(rc))};\n Point lr{Point{r.p - l.p}.normalized()};\n Point h{l.p + lr * rc};\n std::vector<Point> res;\n res.push_back(h + lr.rotaedByArc(90.0l) * rs);\n res.push_back(h + lr.rotaedByArc(-90.0l) * rs);\n return res;\n }\n};\n\nbool HasCommonInterval(const std::vector<Interval>& I) {\n R l{-9e18}, r{9e18};\n for (auto [L, R] : I) {\n l = std::max(l, L);\n r = std::min(r, R);\n }\n return !Bigger(l, r);\n}\n\nbool HasCommonArea(const std::vector<Circle>& C) {\n std::vector<bool> ignore(C.size());\n for (int i{} ; i < (int)C.size() ; i++) {\n for (int j{} ; j < (int)C.size() ; j++) {\n if (i == j) continue;\n if (C[i].contains(C[j])) {\n ignore[i] = true;\n }\n }\n }\n int cnt{};\n for (int i{} ; i < (int)C.size() ; i++) {\n if (!ignore[i]) {\n // std::cout << C[i].p << ' ' << C[i].r << std::endl;\n cnt++;\n }\n }\n if (cnt <= 1) return true;\n for (int i{} ; i < (int)C.size() ; i++) {\n if (ignore[i]) continue;\n for (int j{i + 1} ; j < (int)C.size() ; j++) {\n if (ignore[j]) continue;\n if (!Intersect(C[i], C[j])) return false;\n for (const auto& p : CrossPoint(C[i], C[j])) {\n // std::cout << p << std::endl;\n std::vector<Interval> I;\n bool ok{true};\n for (int k{} ; k < (int)C.size() ; k++) {\n R d{Square(C[k].y() - p.y)};\n if (Bigger(d, Square(C[k].r))) {\n ok = false;\n }\n else {\n R len{sqrtl(Square(C[k].r) - d)};\n I.emplace_back(C[k].x() - len, C[k].x() + len);\n }\n }\n if (ok) ok &= HasCommonInterval(I);\n if (ok) return true;\n }\n }\n }\n return false;\n}\n\nbool solve() {\n int N;\n std::cin >> N;\n if (N == 0) return false;\n std::vector<R> X(N), Y(N), L(N);\n for (int i{} ; i < N ; i++) {\n std::cin >> X[i] >> Y[i] >> L[i];\n }\n if (N == 1) {\n std::cout << L[0] << '\\n';\n return true;\n }\n auto f{[&](R z) -> bool {\n std::vector<Circle> C(N);\n for (int i{} ; i < N ; i++) {\n if (!Smaller(z, L[i])) return false;\n C[i] = Circle{X[i], Y[i], sqrtl(Square(L[i]) - Square(z))};\n }\n return HasCommonArea(C);\n }};\n // std::cout << f(0) << std::endl;\n // return true;\n R ok{1.0l}, ng{301.0l};\n for (int _{} ; _ < 40 ; _++) {\n R mid{(ok + ng) / 2};\n if (f(mid)) ok = mid;\n else ng = mid;\n }\n std::cout << ok << '\\n';\n return true;\n}\n\nint main() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n std::cout << std::fixed << std::setprecision(8);\n while (solve()) ;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3648, "score_of_the_acc": -0.4854, "final_rank": 7 }, { "submission_id": "aoj_1190_9104758", "code_snippet": "#include <iostream>\n#include <vector>\n#include <complex>\n#include <cstdio>\n#include <cmath>\n\nusing namespace std;\n\nconst double EPS = 1e-10;\n\ntypedef complex<double> P;\ntypedef pair<P,double> circle;\n\ndouble cross(P a, P b) { return imag(conj(a)*b); }\n\nbool containPoint(const circle& c, const P& p){\n double dist = abs(c.first-p);\n return dist < c.second+EPS;\n}\n\nbool crossCircle(const circle& c1, const circle& c2){\n double r1 = c1.second;\n double r2 = c2.second;\n double d = abs(c1.first-c2.first);\n if(d<r1||d<r2)\n return d-abs(r1-r2)>EPS;\n return r1+r2-d>-EPS;\n}\n\nvoid crossPoint(vector<P> &res, const circle& c1, const circle& c2){\n double r1 = c1.second;\n double r2 = c2.second;\n double r3 = abs(c1.first-c2.first);\n double rc = (r3*r3+r1*r1-r2*r2)/(2*r3);\n double rs = sqrt(r1*r1-rc*rc);\n P dif = (c2.first-c1.first)/r3;\n res.push_back(c1.first+dif*P(rc, rs));\n res.push_back(c1.first+dif*P(rc,-rs));\n}\n\nbool valid(const vector<circle>& vc){\n vector<P> vp;\n for(int i=0;i<vc.size();i++){\n vp.push_back(vc[i].first);\n for(int j=i+1;j<vc.size();j++){\n if(crossCircle(vc[i], vc[j]))\n crossPoint(vp, vc[i], vc[j]);\n }\n }\n for(int i=0;i<vp.size();i++){\n bool ok = true;\n for(int j=0;j<vc.size();j++)\n if(!containPoint(vc[j], vp[i])) ok = false;\n if(ok) return true;\n }\n return false;\n}\n\nint main(){\n int n;\n int x[10], y[10], l[10]; \n while(cin >> n && n){\n int minL = 100000;\n for(int i=0;i<n;i++){\n cin >> x[i] >> y[i] >> l[i];\n minL = min(minL, l[i]);\n }\n double low = 1.0, high = minL;\n for(int i=0;i<200;i++){\n double mid = 0.5*(low+high);\n vector<circle> vc;\n for(int j=0;j<n;j++){\n double r = sqrt(l[j]*l[j]-mid*mid);\n vc.push_back(make_pair(P(x[j], y[j]), r));\n }\n if(valid(vc)) low = mid;\n else high = mid;\n }\n printf(\"%.8lf\\n\", 0.5*(low+high));\n }\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 3272, "score_of_the_acc": -0.3495, "final_rank": 2 }, { "submission_id": "aoj_1190_9095073", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define ALL(v) v.begin(),v.end()\n#define dbg(x) cerr << #x << \": \" << x << endl\ntemplate<class F, class S>\nostream& operator<<(ostream& os, pair<F,S> p) {\n os << '(' << p.first << ',' << p.second << ')';\n return os;\n}\ntemplate<class Iter>\nvoid print(Iter beg, Iter end) {\n for (auto itr = beg; itr != end; ++itr) {\n cerr << *itr << ' ';\n }\n cerr << '\\n';\n}\nusing ld = long double;\nconst ld EPS = 1e-7;\nusing Point = pair<ld,ld>;\nPoint operator+(const Point& a, const Point& b) {\n return {a.first+b.first, a.second+b.second};\n}\nPoint operator-(const Point& a, const Point& b) {\n return {a.first-b.first, a.second-b.second};\n}\nld abs(Point a) {\n return sqrtl(a.first*a.first + a.second*a.second);\n}\n\nstruct Circle {\n Point c;\n ld r;\n};\nld ar(Point p) {\n return atan2(p.second, p.first);\n}\nPoint polar(ld a, ld r) {\n return Point(cos(r) * a, sin(r) * a);\n}\nvector<Point> getCrossPoints(Circle c1, Circle c2) {\n ld d = abs(c1.c - c2.c);\n if (d > c1.r + c2.r) return vector<Point>();\n if (!((d + c1.r >= c2.r) && (d + c2.r >= c1.r) && (c1.r + c2.r >= d))) return vector<Point>();\n ld a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d));\n ld t = ar(c2.c - c1.c);\n vector<Point> v;\n v.push_back(c1.c + polar(c1.r, t + a));\n v.push_back(c1.c + polar(c1.r, t - a));\n return v;\n}\n\nint main() {\n while (true) {\n int n;\n cin >> n;\n if (n == 0) break;\n vector<int> x(n), y(n), l(n);\n for (int i = 0; i < n; ++i) {\n cin >> x[i] >> y[i] >> l[i];\n }\n auto isOk = [&](ld mid) -> bool {\n vector<Circle> circle(n);\n for (int i = 0; i < n; ++i) {\n ld z = l[i]*l[i] - mid*mid;\n if (z < 0) return false;\n circle[i] = {Point(x[i], y[i]), sqrtl(z)};\n }\n vector<Point> points;\n for (int i = 0; i < n; ++i) {\n for (int j = i+1; j < n; ++j) {\n for (auto y : getCrossPoints(circle[i], circle[j])) {\n points.push_back(y);\n }\n }\n }\n for (int i = 0; i < n; ++i) {\n points.push_back({x[i], y[i]});\n }\n for (auto point : points) {\n bool ok = true;\n for (int i = 0; i < n; ++i) {\n auto d = abs(point - Point(x[i], y[i]));\n if (d > circle[i].r + EPS) {\n ok = false;\n break;\n }\n }\n if (ok) return true;\n }\n return false;\n };\n ld ok = 0;\n ld ng = *max_element(ALL(l)) + 1;\n for (int t = 0; t < 100; ++t) {\n ld mid = (ok + ng) / 2;\n // cerr << mid << ' ' << isOk(mid) << '\\n';\n (isOk(mid) ? ok : ng) = mid;\n }\n cout << fixed << setprecision(20) << ok << '\\n';\n }\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 3924, "score_of_the_acc": -1.1311, "final_rank": 18 } ]
aoj_1193_cpp
Chain Disappearance Puzzle We are playing a puzzle. An upright board with H rows by 5 columns of cells, as shown in the figure below, is used in this puzzle. A stone engraved with a digit, one of 1 through 9, is placed in each of the cells. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. If there are stones in the cells above the cell with a disappeared stone, the stones in the above cells will drop down, filling the vacancy. The puzzle proceeds taking the following steps. When three or more stones in horizontally adjacent cells are engraved with the same digit, the stones will disappear. Disappearances of all such groups of stones take place simultaneously. When stones are in the cells above the emptied cells, these stones drop down so that the emptied cells are filled. After the completion of all stone drops, if one or more groups of stones satisfy the disappearance condition, repeat by returning to the step 1. The score of this puzzle is the sum of the digits on the disappeared stones. Write a program that calculates the score of given configurations of stones. Input The input consists of multiple datasets. Each dataset is formed as follows. Board height H Stone placement of the row 1 Stone placement of the row 2 ... Stone placement of the row H The first line specifies the height ( H ) of the puzzle board (1 ≤ H ≤ 10). The remaining H lines give placement of stones on each of the rows from top to bottom. The placements are given by five digits (1 through 9), separated by a space. These digits are engraved on the five stones in the corresponding row, in the same order. The input ends with a line with a single zero. Output For each dataset, output the score in a line. Output lines may not include any characters except the digits expressing the scores. Sample Input 1 6 9 9 9 9 5 5 9 5 5 9 5 5 6 9 9 4 6 3 6 9 3 3 2 9 9 2 2 1 1 1 10 3 5 6 5 6 2 2 2 8 3 6 2 5 9 2 7 7 7 6 1 4 6 6 4 9 8 9 1 1 8 5 6 1 8 1 6 8 2 1 2 9 6 3 3 5 5 3 8 8 8 5 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 3 2 2 8 7 4 6 5 7 7 7 8 8 9 9 9 0 Output for the Sample Input 36 38 99 0 72
[ { "submission_id": "aoj_1193_9527420", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nll MOD = 1'000'000'007;\nll inf = (1LL << 62);\n\n// clang-format off\nauto getll(){ll n; cin >> n; return n;}\nauto getstr(){string s; cin >> s; return s;}\nauto getdb(){double n; cin >> n; return n;}\nauto getvll(ll n){vector<ll> a(n); for (ll i = 0; i < n; ++i) a[i] = getll(); return a;}\nauto getvstr(ll n){vector<string> a(n); for (ll i = 0; i < n; ++i) a[i] = getstr(); return a;}\nauto getvdb(ll n){vector<double> a(n); for (ll i = 0; i < n; ++i) a[i] = getdb(); return a;}\n// clang-format on\n\npair<ll, ll> func(vector<ll>& a) {\n vector<pair<ll, ll>> tmp;\n ll curr = -1;\n for (ll i = 0; i < a.size(); ++i) {\n if (curr == -1 || a[i] != curr) {\n tmp.push_back({a[i], 1});\n curr = a[i];\n } else {\n tmp.back().second += 1;\n // curr = a[i];\n }\n }\n ll index = 0;\n for (auto& x : tmp) {\n if (x.first != 0 && x.second >= 3)\n return {index, x.second};\n index += x.second;\n }\n return {-1, -1};\n}\n\nint main() {\n vector<ll> ans;\n while (true) {\n ll h;\n cin >> h;\n if (h == 0)\n break;\n ll pt = 0;\n vector<vector<ll>> p(h, vector<ll>(5));\n for (ll i = 0; i < h; ++i) {\n for (ll j = 0; j < 5; ++j) {\n cin >> p[i][j];\n }\n }\n for (ll cnt = 0; cnt < h * 5 / 3 + 1; ++cnt) {\n for (ll i = 0; i < h; ++i) {\n auto cv = func(p[i]);\n if (cv.first != -1) {\n pt += p[i][cv.first] * cv.second;\n for (ll k = 0; k < cv.second; ++k) {\n p[i][cv.first + k] = 0;\n }\n }\n }\n for (ll i = 0; i < 5; ++i) {\n vector<ll> index(5, h - 1);\n for (ll j = h - 1; j >= 0; --j) {\n if (p[j][i] != 0) {\n p[index[i]][i] = p[j][i];\n index[i]--;\n }\n }\n for (ll j = index[i]; j >= 0; --j) {\n p[j][i] = 0;\n }\n }\n }\n ans.push_back(pt);\n }\n for (auto& x : ans)\n cout << x << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3460, "score_of_the_acc": -0.0343, "final_rank": 9 }, { "submission_id": "aoj_1193_9458159", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nbool check(vector<int> X, int L, int R) {\n bool check = true;\n rep(i,L,R-1) {\n if (X[i] != X[i+1]) check = false;\n }\n return check;\n}\n\nvoid refill(vector<int>& X, int L, int R) {\n rep(i,L,R) X[i] = 0;\n return;\n}\n\nvoid Solve(vector<vector<int>>& A, int N, int& ANS) {\n rep(i,0,N) {\n if (check(A[i],0,5)) ANS += A[i][0] * 5, refill(A[i],0,5);\n else if (check(A[i],0,4)) ANS += A[i][0] * 4, refill(A[i],0,4);\n else if (check(A[i],1,5)) ANS += A[i][1] * 4, refill(A[i],1,5);\n else if (check(A[i],0,3)) ANS += A[i][0] * 3, refill(A[i],0,3);\n else if (check(A[i],1,4)) ANS += A[i][1] * 3, refill(A[i],1,4);\n else if (check(A[i],2,5)) ANS += A[i][2] * 3, refill(A[i],2,5);\n }\n vector<vector<int>> X(5);\n rep(i,0,N) {\n rep(j,0,5) {\n if (A[i][j] != 0) X[j].push_back(A[i][j]);\n }\n }\n rep(j,0,5) {\n rep(k,0,(int)(X[j].size())) A[k][j] = X[j][k];\n rep(k,(int)(X[j].size()),N) A[k][j] = 0;\n }\n return;\n}\n\nint main() {\nwhile(1) {\n int N;\n cin >> N;\n if (N == 0) return 0;\n vector A(N,vector<int>(5));\n rrep(i,0,N) {\n rep(j,0,5) cin >> A[i][j];\n }\n int ANS = 0;\n rep(i,0,100) {\n Solve(A,N,ANS);\n }\n cout << ANS << endl;\n}\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3432, "score_of_the_acc": -0.0437, "final_rank": 10 }, { "submission_id": "aoj_1193_9247336", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<n;i++)\n\nint solve(int n){\n vector<vector<int>> board(n,vector(5,0));\n rep(i,n) rep(j,5) cin>>board[i][j];\n int score=0;\n rep(_,5*n){\n rep(i,n){\n set<int> set;\n rep(j,3) if(board[i][j]==board[i][j+1] && board[i][j+1]==board[i][j+2]){\n set.insert(j);\n set.insert(j+1);\n set.insert(j+2);\n }\n for(int idx:set){\n score+=board[i][idx];\n board[i][idx]=0;\n }\n }\n rep(__,n) rep(i,n-1){\n rep(j,5) if(board[i+1][j]==0) swap(board[i][j], board[i+1][j]);\n }\n }\n return score;\n}\n\nint main(){\n for(;;){\n int n; cin>>n;\n if(n==0) return 0;\n cout<<solve(n)<<endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3380, "score_of_the_acc": -0.027, "final_rank": 7 }, { "submission_id": "aoj_1193_9005691", "code_snippet": "#include <iostream>\n#include <array>\n\nusing namespace std;\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep1(i, n) for (int i = 1; i <= (int)(n); i++)\n#define all(x) x.begin(), x.end()\n\nint main() {\n\n array<array<int,5>,10> x{};\n int h;\n\n while (true) {\n cin >> h;\n if (h == 0) break;\n rep(i,h) rep(j,5) cin>>x[i][j];\n\n int score = 0;\n rep(_,500) {\n rep(i,h) {\n if (x[i][0] == x[i][1] && x[i][1] == x[i][2] && x[i][2] == x[i][3] && x[i][3] == x[i][4] && x[i][0] >= 1) {\n score += x[i][0] * 5;\n x[i][0] = 0;\n x[i][1] = 0;\n x[i][2] = 0;\n x[i][3] = 0;\n x[i][4] = 0;\n }\n }\n rep(i,h) rep(j,2) {\n if (x[i][j] == x[i][j+1] && x[i][j+1] == x[i][j+2] && x[i][j+2] == x[i][j+3] && x[i][j] >= 1) {\n score += x[i][j] * 4;\n x[i][j] = 0;\n x[i][j+1] = 0;\n x[i][j+2] = 0;\n x[i][j+3] = 0;\n }\n }\n rep(i,h) rep(j,3) {\n if (x[i][j] == x[i][j+1] && x[i][j+1] == x[i][j+2] && x[i][j] >= 1) {\n score += x[i][j] * 3;\n x[i][j] = 0;\n x[i][j+1] = 0;\n x[i][j+2] = 0;\n }\n }\n rep(_,500) {\n for (int i = 1; i < h; i++) rep(j,5) {\n if (x[i][j] == 0) {\n x[i][j] = x[i-1][j];\n x[i-1][j] = 0;\n }\n }\n }\n\n }\n cout << score << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 3100, "memory_kb": 3352, "score_of_the_acc": -0.6388, "final_rank": 12 }, { "submission_id": "aoj_1193_7956316", "code_snippet": "#include <bits/stdc++.h>\n#define fi first\n#define se second\n#define rep(i,s,n) for (int i = (s); i < (n); ++i)\n#define rrep(i,n,g) for (int i = (n)-1; i >= (g); --i)\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n#define len(x) (int)(x).size()\n#define dup(x,y) (((x)+(y)-1)/(y))\n#define pb push_back\n#define eb emplace_back\n#define Field(T) vector<vector<T>>\n#define pq(T) priority_queue<T, vector<T>, greater<T>>\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n\nvoid solve(int n) {\n vector<vector<int>> a(n, vector<int>(5));\n rep(i,0,n) rep(j,0,5) cin >> a[i][j];\n reverse(all(a));\n int step = 20;\n int ans = 0;\n while(step--) {\n rep(i,0,n) {\n rrep(l,6,3) {\n rep(j,0,6-l) {\n int x = 10, y = -1;\n rep(k,0,l) {\n x = min(x, a[i][j+k]);\n y = max(y, a[i][j+k]);\n }\n if (x == y && y > 0) {\n ans += x * l;\n rep(k,0,l) {\n a[i][j+k] = 0;\n }\n }\n }\n }\n }\n rep(j,0,5) {\n vector<int> b;\n rep(i,0,n) {\n if (a[i][j] != 0) {\n b.eb(a[i][j]);\n }\n }\n rep(i,0,len(b)) {\n a[i][j] = b[i];\n }\n rep(i,len(b),n) {\n a[i][j] = 0;\n }\n }\n }\n cout << ans << endl;\n}\n\nint main() {\n int n;\n while(1) {\n cin >> n;\n if (n == 0) break;\n solve(n);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3328, "score_of_the_acc": -0.0223, "final_rank": 3 }, { "submission_id": "aoj_1193_7940120", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main() {\n int H;\n char mas[10][5];\n while (cin >> H, H) {\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < 5; j++) {\n cin >> mas[i][j];\n }\n }\n int ret = 0;\n bool changed = true;\n for (int foo = 0; foo < 100; foo++) {\n for (int q = 0; q < 30; q++) {\n for (int i = H - 1; i > 0; i--) {\n for (int j = 0; j < 5; j++) {\n if (mas[i][j] == '*') {\n swap(mas[i][j], mas[i - 1][j]);\n }\n }\n }\n }\n for (int i = 0; i < H; i++) {\n char prev = mas[i][0];\n int cnt = 0;\n for (int j = 0; j < 5; j++) {\n if (mas[i][j] == '*') {\n cnt = 0;\n continue;\n }\n if (mas[i][j] != prev) {\n prev = mas[i][j];\n cnt = 0;\n }\n cnt++;\n if (cnt == 3) {\n ret += (mas[i][j] - '0') * 3;\n for (int k = j, l = 0; l < cnt; l++, k--) {\n mas[i][k] = '*';\n }\n } else if (cnt > 3) {\n ret += (mas[i][j] - '0');\n mas[i][j] = '*';\n }\n }\n }\n }\n cout << ret << endl;\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3084, "score_of_the_acc": -0.008, "final_rank": 2 }, { "submission_id": "aoj_1193_7940106", "code_snippet": "#include <iostream>\n#include <map>\n#include <string>\n#include <vector>\nusing namespace std;\nint res;\nvector<string> input(int n) {\n vector<string> res;\n for (int i = 0; i < n; i++) {\n string line;\n for (int j = 0; j < 5; j++) {\n char c;\n cin >> c;\n line += c;\n }\n res.push_back(line);\n line = \"\";\n }\n return res;\n}\npair<string, int> chek(string s) {\n int res = 0;\n string nu = \"00000\";\n if (s[0] == s[1] && s[1] == s[2] && s[2] == s[3] && s[3] == s[4] &&\n s[0] != '0') {\n return make_pair(nu, (s[0] - '0') * 5);\n }\n if (s[0] == s[1] && s[1] == s[2] && s[2] == s[3] && s[0] != '0') {\n return make_pair(nu.substr(0, 4) + s.substr(4, 1), (s[0] - '0') * 4);\n }\n if (s[1] == s[2] && s[2] == s[3] && s[3] == s[4] && s[1] != '0') {\n return make_pair(s.substr(0, 1) + nu.substr(0, 4), (s[1] - '0') * 4);\n }\n if (s[0] == s[1] && s[1] == s[2] && s[0] != '0') {\n return make_pair(nu.substr(0, 3) + s.substr(3, 2), (s[0] - '0') * 3);\n }\n if (s[1] == s[2] && s[2] == s[3] && s[1] != '0') {\n return make_pair(s.substr(0, 1) + nu.substr(0, 3) + s.substr(4, 1),\n (s[1] - '0') * 3);\n }\n if (s[2] == s[3] && s[3] == s[4] && s[2] != '0') {\n return make_pair(s.substr(0, 2) + nu.substr(0, 3), (s[2] - '0') * 3);\n }\n return make_pair(s, 0);\n}\nvector<string> move(vector<string> line) {\n for (int i = line.size() - 2; i >= 0; i--) {\n for (int j = 0; j < 5; j++) {\n if (line[i + 1][j] == '0') {\n line[i + 1][j] = line[i][j];\n line[i][j] = '0';\n }\n }\n }\n return line;\n}\nint main(void) {\n int n;\n while (cin >> n, n) {\n res = 0;\n vector<string> in = input(n);\n if (in.size() == 1) {\n pair<string, int> line = chek(in[0]);\n cout << line.second << endl;\n } else {\n bool con = true;\n int ll = 0;\n while (con) {\n con = false;\n for (int i = 0; i < in.size(); i++) {\n pair<string, int> line = chek(in[i]);\n in[i] = line.first;\n res += line.second;\n if (line.second)\n con = true;\n in = move(in);\n }\n }\n cout << res << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3168, "score_of_the_acc": -0.0077, "final_rank": 1 }, { "submission_id": "aoj_1193_7697873", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n\n while (true) {\n\n int h;\n cin >> h;\n if (h == 0) break;\n vector<vector<int> > x(2000, vector<int>(5, 0));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < 5; j++) {\n cin >> x[i][j];\n }\n }\n\n int score = 0;\n for (int i = 0; i < 500; i++) {\n for (int j = 0; j < h; j++) {\n if (x[j][0] == x[j][1] && x[j][1] == x[j][2] && x[j][2] == x[j][3] && x[j][3] == x[j][4] && x[j][0] >= 1) {\n score += x[j][0] * 5;\n x[j][0] = 0;\n x[j][1] = 0;\n x[j][2] = 0;\n x[j][3] = 0;\n x[j][4] = 0;\n }\n }\n for (int j = 0; j < h; j++) {\n for (int k = 0; k < 2; k++) {\n if (x[j][k + 0] == x[j][k + 1] && x[j][k + 1] == x[j][k + 2] && x[j][k + 2] == x[j][k + 3] && x[j][k + 0] >= 1) {\n score += x[j][k + 0] * 4;\n x[j][k + 0] = 0;\n x[j][k + 1] = 0;\n x[j][k + 2] = 0;\n x[j][k + 3] = 0;\n }\n }\n }\n for (int j = 0; j < h; j++) {\n for (int k = 0; k < 3; k++) {\n if (x[j][k + 0] == x[j][k + 1] && x[j][k + 1] == x[j][k + 2] && x[j][k + 0] >= 1) {\n score += x[j][k + 0] * 3;\n x[j][k + 0] = 0;\n x[j][k + 1] = 0;\n x[j][k + 2] = 0;\n }\n }\n }\n for (int j = 0; j < 500; j++) {\n for (int j = 1; j < h; j++) {\n for (int k = 0; k < 5; k++) {\n if (x[j][k] == 0) {\n x[j][k] = x[j - 1][k];\n x[j - 1][k] = 0;\n }\n }\n }\n }\n }\n cout << score << endl;\n }\n return (0);\n}", "accuracy": 1, "time_ms": 5040, "memory_kb": 3220, "score_of_the_acc": -1.0124, "final_rank": 14 }, { "submission_id": "aoj_1193_7001170", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nvoid remake(vector<int>& vec){\n vector<int> vec2;\n for(int i = 0 ; i < vec.size() ; i++){\n if(vec[i]>=0){\n vec2.push_back(vec[i]);\n }\n }\n while(vec2.size()<vec.size()){\n vec2.push_back(-1);\n }\n for(int i = 0 ; i < vec.size() ; i++){\n vec[i] = vec2[i];\n }\n}\n\nint solve(int H){\n int cnt = 0;\n vector vec(7,vector<int>(H,-1));\n for(int i = 0 ; i < H ; i++){\n for(int j = 1 ; j <= 5 ; j++){\n cin >> vec[j][i];\n }\n }\n for(int j = 1 ; j <= 5 ; j++){\n reverse(vec[j].begin(),vec[j].end());\n }\n for(int i = 0 ; i <= 18 ; i++){\n for(int h = 0 ; h < H ; h++){\n for(int j = 5 ; j >= 3 ; j--){\n for(int st = 1 ; st <= 5-j+1 ; st++){\n int en = st+j-1;\n int pre = vec[st][h];\n if(pre == -1)continue;\n bool ok = true;\n for(int a = st+1 ; a <= en ; a++){\n if(pre == -1){\n ok = false;\n }\n if(pre != vec[a][h]){\n ok = false;\n }\n }\n if(ok){\n for(int a = st ; a <= en ; a++){\n vec[a][h] = -1;\n }\n cnt += j*pre;\n break;\n }\n }\n }\n }\n for(int j = 1 ; j <= 5 ; j++){\n remake(vec[j]);\n }\n /*for(int h = 0 ; h < H ; h++){\n for(int j = 1 ; j <= 5 ; j++){\n cout << vec[j][h] << \" \";\n }\n cout << endl;\n }*/\n }\n return cnt;\n}\n\nint main(){\n while(1){\n int H;\n cin >> H;\n if(H == 0)break;\n cout << solve(H) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3332, "score_of_the_acc": -0.0226, "final_rank": 4 }, { "submission_id": "aoj_1193_6838379", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\ntemplate<class T,class U> inline bool chmin(T&x,U y){if(x>y){x=y;return true;}return false;}\ntemplate<class T,class U> inline bool chmax(T&x,U y){if(x<y){x=y;return true;}return false;}\ntemplate<class T> void my_printv(vector<T> v,bool endline = true){\n if(!v.empty()){ for(size_t i{}; i<v.size()-1; i++) cout<<v[i]<<' '; cout<<v.back(); }\n if(endline) cout<<endl;\n}\nusing ll = long long;\n\nconst int inf = INT_MAX / 2; const ll INF = 1LL << 60;\nconst ll MOD = 1000000007;\n\n////////////////////////////////////////////////////////////////////////////////////////////\n\n\nint main() {\n \n int n;\n while(cin>>n, n) {\n vector<vector<int>> t(n, vector<int> (5));\n for(auto&i:t) for(auto&j:i) cin>>j;\n int ans = 0;\n rep(_, 50*50) {\n rep(i, n) {\n int cnt = 0;\n rep(j, 5) {\n if(j == 0 or t[i][j] == t[i][j-1]) cnt++;\n else {\n if(cnt >= 3) {\n ans += cnt * t[i][j-1];\n rep(k, cnt) t[i][j-1-k] = 0;\n }\n cnt = 1;\n }\n }\n if(cnt >= 3) {\n ans += cnt * t[i][4];\n rep(k, cnt) t[i][4-k] = 0;\n }\n }\n\n rep(i, 5) {\n vector<int> tmp(n);\n int now = n-1;\n for(int j = n-1; j>=0;j--) if(t[j][i]) tmp[now--] = t[j][i];\n rep(j, n) t[j][i] = tmp[j];\n }\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 3336, "score_of_the_acc": -0.0806, "final_rank": 11 }, { "submission_id": "aoj_1193_6780832", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vvvvll = vector<vvvll>;\nusing vvvvvll = vector<vvvvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\nusing vd = vector<double>;\nusing vvd = vector<vd>;\nusing vvvd = vector<vvd>;\n#define all(A) A.begin(),A.end()\n#define ALL(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\nusing pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>;\n\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nll gcd(ll(a), ll(b)) {\n if (b == 0)return a;\n ll c = a;\n while (a % b != 0) {\n c = a % b;\n a = b;\n b = c;\n }\n return b;\n}\n\nvector<ll> fact, factinv, inv;\nll mod = 1e9 + 7;\nvoid prenCkModp(ll n) {\n fact.resize(n + 5);\n factinv.resize(n + 5);\n inv.resize(n + 5);\n fact.at(0) = fact.at(1) = 1;\n factinv.at(0) = factinv.at(1) = 1;\n inv.at(1) = 1;\n for (ll i = 2; i < n + 5; i++) {\n fact.at(i) = (fact.at(i - 1) * i) % mod;\n inv.at(i) = mod - (inv.at(mod % i) * (mod / i)) % mod;\n factinv.at(i) = (factinv.at(i - 1) * inv.at(i)) % mod;\n }\n\n}\nll nCk(ll n, ll k) {\n if (k < 0)return 0;\n if (n < k) return 0;\n return fact.at(n) * (factinv.at(k) * factinv.at(n - k) % mod) % mod;\n}\n\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n while (1) {\n ll H;\n cin >> H;\n if (H == 0)return 0;\n vvll A(H, vll(5));\n ll an = 0;\n rep(i, H)rep(j, 5) {\n cin >> A[i][j];\n an += A[i][j];\n }\n\n rep(d, 50) {\n rep(h, H) {\n vll D = A[h];\n rep(j, 3) {\n if (D[j] == D[j + 1]&&D[j+1] == D[j + 2]) {\n A[h][j] = A[h][j + 1] = A[h][j + 2] = 0;\n }\n }\n }\n\n rep(h, H) {\n for (ll h = H - 1; h > 0; h--) {\n rep(j, 5) {\n if (A[h][j] == 0) {\n swap(A[h][j], A[h - 1][j]);\n }\n }\n }\n }\n }\n rep(h, H)rep(j, 5)an -= A[h][j];\n cout << an << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3340, "score_of_the_acc": -0.0234, "final_rank": 5 }, { "submission_id": "aoj_1193_6721916", "code_snippet": "#define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\n//#include <atcoder/all>\nusing namespace std;\n//using namespace atcoder;\n\n#define int long long\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define rep(i, n) for (int i = 0; i < n; ++i)\n#define REP(i, n) for (int i = 0; i < n; ++i)\n#define range(i,a,b) ((a)<=(i) && (i)<(b))\n#define debug(x) cout << #x << \" = \" << (x) << endl;\n#define fs first\n#define sc second\n#define pb push_back\n#define eb emplace_back\n#define SP << \" \" <<\n\ntypedef long long ll;\ntypedef pair<int, int> P;\ntypedef tuple<int, int, int> T;\ntypedef vector<int> vec;\ntypedef vector<P> pvec;\ntypedef vector<vector<int>> vvec;\ntypedef vector<vector<P>> pvvec;\ntypedef priority_queue<int> PQI;\ntypedef priority_queue<P> PQP;\ntypedef priority_queue<int,vector<int>,greater<int>> PQIG;\ntypedef priority_queue<P,vector<P>,greater<P>> PQPG;\n\nconst vector<int> DX = {0, -1, 0, 1, 1, 1, -1, -1};\nconst vector<int> DY = {1, 0, -1, 0, 1, -1, 1, -1};\nconstexpr int MOD = (1000000007);\n// const int MOD = (998244353);\n// const int INF = (1 << 30); // 1073741824\nconst ll INF = (1LL << 60); // 1152921504606846976\nconst double PI = (3.141592653589794);\nconst double EPS = (0.0000000001); // 10^(-10)\n\ntemplate<class T> inline bool chmin(T& a, T b) {if (a > b) {a = b; return 1;} return 0;}\ntemplate<class T> inline bool chmax(T& a, T b) {if (a < b) {a = b; return 1;} return 0;}\ntemplate<class T> inline T ceil(T a, T b) {return T((a + b - 1) / b);}\ntemplate<class T> inline T round(T a, T b) {return T(a / b);}\ntemplate< typename T1, typename T2 > istream &operator>>(istream &is, pair< T1, T2 > &p) { is >> p.first >> p.second; return is; }\ntemplate <class T> inline void out(T &a) { bool flag=true; for(auto&x:a){if(flag) {flag=false;} else{ cout << ' '; } cout<<x; } cout << endl; }\n\n\n\n//----------------------------------------------------------------\nint nmax=200000; // 2*(10^5)\nvvec G(nmax);\n\n\n\n\n\nvoid solve4ts()\n{\n \n \n int h;\n cin>>h;\n if(h==0) exit(0);\n vector<vector<P>> a(5,vector<P>(h));\n rep(i,h){\n rep(j,5){\n int x;cin>>x;\n a[j][h-1-i]=P(h-i,x);\n }\n }\n int ans=0;\n while(true){\n int now=0; // 今回の消す値\n rep(j,5) sort(all(a[j])); // 毎回ソート\n rep(takasa,h){ // 高さごとに見る\n int atai=-1; // 今回の高さで揃った値\n set<int> st;\n rep(j,3){ // 0,1,2 1,2,3, 2,3,4\n if(a[j][takasa].sc==a[j+1][takasa].sc && a[j+1][takasa].sc==a[j+2][takasa].sc && a[j][takasa].sc!=INF){\n atai=a[j][takasa].sc; // 今回の高さの消す値\n st.insert(j);\n }\n }\n for(int index:st){\n rep(j,3){\n if(a[index+j][takasa].sc!=INF) now+=a[index+j][takasa].sc;\n a[index+j][takasa]=P(INF,INF);\n }\n }\n }\n ans+=now; // nowを加算\n if(now==0) break;\n }\n cout<<ans<<endl;\n}\n//-----------------------------------------------------------------\n\nsigned main(){ ios::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(15);\n int repeat = INF;\n // cin >> repeat;\n while(repeat--) solve4ts();\n}\n\n/*\n\ng++ -std=c++1z code.cpp\n\n./a.out\n\npython3 expander.py code.cpp\n\n*/", "accuracy": 1, "time_ms": 10, "memory_kb": 14044, "score_of_the_acc": -1, "final_rank": 13 }, { "submission_id": "aoj_1193_6024744", "code_snippet": "// https://ei1333.github.io/luzhiled/\n// http://beet-aizu.hatenablog.com/entry/2017/01/04/113233\n// http://www.prefield.com/algorithm/\n#include <bits/stdc++.h>\nconstexpr char bn = '\\n';\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing vl = vector<ll>;\nusing vd = vector<ld>;\nusing vs = vector<string>;\nusing vb = vector<bool>;\nusing vvl = vector<vector<ll>>;\nusing vvd = vector<vector<ld>>;\nusing vvs = vector<vector<string>>;\nusing vvb = vector<vector<bool>>;\n#define pb push_back\n#define eb emplace_back\n#define fi first\n#define se second\ntemplate<class T> using vc = vector<T>;\ntemplate<class T> using vvc = vector<vector<T>>;\nusing Graph = vector<vector<ll>>;\nconst ll INF = 1LL << 60;\nvoid init() {cin.tie(0);ios::sync_with_stdio(false);cout << fixed << setprecision(15);}\nconst ll tl= 1000000007;\n#define REP(i, n) for (ll i = 0; i < n; i++)\n#define REREP(i, n) for (ll i = n; i >= 0; i--)\n#define FOR(i, a, n) for (ll i = a; i < n; i++)\n#define REFOR(i, n, a) for (ll i = n; i >= a; i--)\n#define CLR(mat,f) memset(mat, f, sizeof(mat))\n#define IN(a, b, x) (a<=x&&x<=b)\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() ) //被り削除\n#define debug cout << \"line : \" << __LINE__ << \" debug\" << endl;\n#define ini(...) int __VA_ARGS__; in(__VA_ARGS__)\n#define inl(...) long long __VA_ARGS__; in(__VA_ARGS__)\n#define ind(...) long double __VA_ARGS__; in(__VA_ARGS__)\n#define ins(...) string __VA_ARGS__; in(__VA_ARGS__)\n#define inc(...) char __VA_ARGS__; in(__VA_ARGS__)\nvoid in(){} template <typename T,class... U> void in(T &t,U &...u){ cin >> t; in(u...);}\nvoid out(){cout << endl;} template <typename T,class... U> void out(const T &t,const U &...u){ cout << t; if(sizeof...(u)) cout << \" \"; out(u...);}\ntemplate<typename T>void die(T x){out(x); exit(0);}\n#define in1(A) REP(i,A.size()) in(A[i]);\n#define in2(A,B) REP(i,A.size()) in(A[i],B[i]);\n#define in3(s,t,u) REP(i,sz(s)){in(s[i] , t[i] , u[i]);}\n#define in4(s,t,u,v) REP(i,sz(s)){in(s[i] , t[i] , u[i] , v[i]);}\n#define each(x,v) for(auto& x : v)\n#define all(v) (v).begin(),(v).end()\n#define sz(v) ((int)(v).size())\nstruct Point{ ld x,y; };\nld dist(Point a, Point b){return sqrt(abs(a.x-b.x)*abs(a.x-b.x)+abs(a.y-b.y)*abs(a.y-b.y));} // 2点間の距離 \nll gcd(ll a, ll b) { return b != 0 ? gcd(b, a % b) : a; }\nll lcm(ll a,ll b){ return a / gcd(a,b) * b;} \nll modpow(ll a, ll n, ll mod) {\n ll res = 1;\n while (n > 0) {\n if (n & 1) res = res * a % mod;\n a = a * a % mod;\n n >>= 1;\n }\n return res;\n}\nll fact(ll n){ if(n < 2) return 1; return (n * fact(n-1))%tl; } //階乗\ninline ll updiv(ll a,ll b){ return (a + b - 1) / b; } //切り上げ\ntemplate<typename T,typename U>ll ceil(T a,U b){return (a + b - 1) / b;}\ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n#define YES(n) ((n) ? \"YES\" : \"NO\" )\n#define Yes(n) ((n) ? \"Yes\" : \"No\" )\n#define yes(n) ((n) ? \"yes\" : \"no\" )\nint dx[]={-1,0,1,0};\nint dy[]={0,1,0,-1};\n//-------------------------------------------------------------------------------------------------\n\nint main(){\n init();\n \n int h;\n vl an;\n while(cin >> h && h){\n \n vvl A(h,vl(5,0));\n REP(i,h){\n REP(j,5){\n cin >> A[i][j];\n }\n }\n ll ans= 0;\n REP(t,100){\n vvl B(h,vl(5,0)),C(h,vl(5,0));\n REP(i,h){\n FOR(j,1,4){\n if(A[i][j]!=0 && A[i][j-1]==A[i][j] && A[i][j]==A[i][j+1]){\n B[i][j-1]=1;\n B[i][j]=1;\n B[i][j+1]=1;\n }\n }\n REP(j,5) if(B[i][j]) ans+= A[i][j];\n }\n \n REP(j,5){\n for(int i=h-2; i>=0; i--){\n C[i][j]=B[i+1][j]+C[i+1][j];\n }\n }\n REP(j,5){\n for(int i=h-1; i>=0; i--){\n if(B[i][j]==0){\n A[i+C[i][j]][j]= A[i][j];\n if(C[i][j]!=0) A[i][j]=0; \n }else{\n A[i][j]=0;\n }\n }\n }\n // out(\"A\");\n // REP(i,h){\n // REP(j,5){\n // cout << A[i][j] << \" \";\n // }out();\n // }\n // out(\"B\");\n // REP(i,h){\n // REP(j,5){\n // cout << B[i][j] << \" \";\n // }out();\n // }\n }\n \n an.push_back(ans);\n }\n REP(i,an.size()) out(an[i]);\n // vl A(n); in1(A)\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3416, "score_of_the_acc": -0.0323, "final_rank": 8 }, { "submission_id": "aoj_1193_5891897", "code_snippet": "#include <bits/stdc++.h>\n//#include<atcoder/all>\nusing namespace std;\n//using namespace atcoder;\nusing ll = long long;\n#define all(A) A.begin(),A.end()\nusing vll = vector<ll>;\n#define rep(i, n) for (long long i = 0; i < (long long)(n); i++)\n\nll mod = 1e9+7;\n\nvll dx={1,0,-1};\nvll dy={1,0,-1};\nint main() {\n while(1){\n ll H;\n cin>>H;\n if(H==0)return 0;\n vector<vll> Q(H,vll(5));\n rep(h,H)rep(i,5)cin>>Q[h][i];\n ll an=0;\n rep(t,100){\n rep(h,H){\n ll L=2,R=2;\n rep(i,2){\n if(Q[h][R+1]==Q[h][2])R++;\n else break;\n }\n rep(i,2){\n if(Q[h][L-1]==Q[h][2])L--;\n else break;\n }\n if(R-L+1>=3){\n for(ll i=L;i<=R;i++){\n an+=Q[h][i];\n Q[h][i]=0;\n }\n }\n }\n rep(k,10){\n rep(h,H-1){\n rep(j,5){\n if(Q[H-h-1][j]==0)swap(Q[H-h-2][j],Q[H-h-1][j]);\n \n }\n \n }}\n /*\n rep(h,H){\n rep(j,5)cout<<Q[h][j]<<\" \";\n cout<<endl;\n }\n cout<<endl;*/\n }\n cout<<an<<endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3336, "score_of_the_acc": -0.025, "final_rank": 6 } ]
aoj_1191_cpp
Rotate and Rewrite Two sequences of integers A: A 1 A 2 ... A n and B: B 1 B 2 ... B m and a set of rewriting rules of the form " x 1 x 2 ... x k → y " are given. The following transformations on each of the sequences are allowed an arbitrary number of times in an arbitrary order independently. Rotate : Moving the first element of a sequence to the last. That is, transforming a sequence c 1 c 2 ... c p to c 2 ... c p c 1 . Rewrite : With a rewriting rule " x 1 x 2 ... x k → y ", transforming a sequence c 1 c 2 ... c i x 1 x 2 ... x k d 1 d 2 ... d j to c 1 c 2 ... c i y d 1 d 2 ... d j . Your task is to determine whether it is possible to transform the two sequences A and B into the same sequence. If possible, compute the length of the longest of the sequences after such a transformation. Input The input consists of multiple datasets. Each dataset has the following form. n m r A 1 A 2 ... A n B 1 B 2 ... B m R 1 ... R r The first line of a dataset consists of three positive integers n , m , and r, where n ( n ≤ 25) is the length of the sequence A, m ( m ≤ 25) is the length of the sequence B, and r ( r ≤ 60) is the number of rewriting rules. The second line contains n integers representing the n elements of A. The third line contains m integers representing the m elements of B. Each of the last r lines describes a rewriting rule in the following form. k x 1 x 2 ... x k y The first k is an integer (2 ≤ k ≤ 10), which is the length of the left-hand side of the rule. It is followed by k integers x 1 x 2 ... x k , representing the left-hand side of the rule. Finally comes an integer y , representing the right-hand side. All of A 1 , .., A n , B 1 , ..., B m , x 1 , ..., x k , and y are in the range between 1 and 30, inclusive. A line "0 0 0" denotes the end of the input. Output For each dataset, if it is possible to transform A and B to the same sequence, print the length of the longest of the sequences after such a transformation. Print -1 if it is impossible. Sample Input 3 3 3 1 2 3 4 5 6 2 1 2 5 2 6 4 3 2 5 3 1 3 3 2 1 1 1 2 2 1 2 1 1 2 2 2 2 1 7 1 2 1 1 2 1 4 1 2 4 3 1 4 1 4 3 2 4 2 4 16 14 5 2 1 2 2 1 3 2 1 3 2 2 1 1 3 1 2 2 1 3 1 1 2 3 1 2 2 2 2 1 3 2 3 1 3 3 2 2 2 1 3 2 2 1 2 3 1 2 2 2 4 2 1 2 2 2 0 0 0 Output for the Sample Input 2 -1 1 9
[ { "submission_id": "aoj_1191_10335939", "code_snippet": "// AOJ #1191 Rotate and Rewrite\n// 2025.3.30\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define NMAX 50\nconst int BAS = 1000;\nint A[NMAX+5], B[NMAX+5];\nbool dpA[NMAX+5][NMAX+5][600];\nbool dpB[NMAX+5][NMAX+5][600];\nint sudpA[NMAX+5][NMAX+5];\nint sudpB[NMAX+5][NMAX+5];\n\nint main(){\n while (true) {\n int n, m, r, N, M;\n cin >> n >> m >> r;\n if(n == 0) break;\n N = n << 1, M = m << 1;\n\n for (int i = 0; i < n; i++) cin >> A[i];\n for (int i = n; i < N; i++) A[i] = A[i - n];\n\n for (int i = 0; i < m; i++) cin >> B[i];\n for (int i = m; i < M; i++) B[i] = B[i - m];\n\n vector<tuple<int,int,int>> rules;\n int mkaz = 30;\n for (int h = 0; h < r; h++){\n int K;\n cin >> K;\n int pre;\n cin >> pre;\n for (int i = 1; i < K; i++){\n int cur;\n cin >> cur;\n if(i + 1 < K){\n mkaz++;\n rules.push_back(make_tuple(pre, cur, mkaz));\n pre = mkaz;\n } else {\n int out;\n cin >> out;\n rules.push_back(make_tuple(pre, cur, out));\n }\n }\n }\n\n memset(dpA, 0, sizeof(dpA));\n memset(dpB, 0, sizeof(dpB));\n for (int i = 0; i < N; i++) dpA[i][i+1][ A[i] ] = true;\n for (int i = 0; i < M; i++) dpB[i][i+1][ B[i] ] = true;\n\n memset(sudpA, 0, sizeof(sudpA));\n memset(sudpB, 0, sizeof(sudpB));\n for (int i = 1; i <= n; i++){\n for (int L = 0; L + i <= N; L++){\n int R = L + i;\n for (size_t j = 0; j < rules.size(); j++){\n int x, y, z;\n tie(x, y, z) = rules[j];\n for (int s = L + 1; s < R; s++)\n dpA[L][R][z] |= (dpA[L][s][x] && dpA[s][R][y]);\n }\n for (int k = 1; k <= 30; k++)\n if (dpA[L][R][k]) sudpA[L][R] += (1 << k);\n }\n }\n for (int i = 1; i <= m; i++){\n for (int L = 0; L + i <= M; L++){\n int R = L + i;\n for (size_t j = 0; j < rules.size(); j++){\n int x, y, z;\n tie(x, y, z) = rules[j];\n for (int s = L + 1; s < R; s++)\n dpB[L][R][z] |= (dpB[L][s][x] && dpB[s][R][y]);\n }\n for (int k = 1; k <= 30; k++)\n if (dpB[L][R][k]) sudpB[L][R] += (1 << k);\n }\n }\n\n int ans = -1;\n for (int As = 0; As < n; As++){\n for (int Bs = 0; Bs < m; Bs++){\n int ep[51][51] = {0};\n ep[As][Bs] = BAS;\n for (int Ax = As; Ax < As + n; Ax++){\n for (int Bx = Bs; Bx < Bs + m; Bx++){\n if (ep[Ax][Bx] == 0) continue;\n for (int Ay = Ax + 1; Ay <= As + n; Ay++){\n for (int By = Bx + 1; By <= Bs + m; By++){\n if (sudpA[Ax][Ay] & sudpB[Bx][By])\n ep[Ay][By] = max(ep[Ay][By], ep[Ax][Bx] + 1);\n }\n }\n }\n }\n ans = max(ans, ep[As+n][Bs+m] - BAS);\n }\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 6792, "score_of_the_acc": -0.1381, "final_rank": 5 }, { "submission_id": "aoj_1191_10335936", "code_snippet": "// AOJ #1191 Rotate and Rewrite\n// 2025.3.30\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define NMAX 50\nconst int BAS = 10000;\nbool dpA[NMAX+5][NMAX+5][600];\nbool dpB[NMAX+5][NMAX+5][600];\nint sudpA[NMAX+5][NMAX+5];\nint sudpB[NMAX+5][NMAX+5];\n\nint main(){\n while (true) {\n int n, m, r, N, M;\n cin >> n >> m >> r;\n if(n == 0) break;\n N = n << 1, M = m << 1;\n\n int A[NMAX] = {0}, B[NMAX] = {0};\n for (int i = 0; i < n; i++) cin >> A[i];\n for (int i = n; i < N; i++) A[i] = A[i - n];\n\n for (int i = 0; i < m; i++) cin >> B[i];\n for (int i = m; i < M; i++) B[i] = B[i - m];\n\n vector<tuple<int,int,int>> rules;\n int mkaz = 30;\n for (int h = 0; h < r; h++){\n int K;\n cin >> K;\n int pre;\n cin >> pre;\n for (int i = 1; i < K; i++){\n int cur;\n cin >> cur;\n if(i + 1 < K){\n mkaz++;\n rules.push_back(make_tuple(pre, cur, mkaz));\n pre = mkaz;\n } else {\n int out;\n cin >> out;\n rules.push_back(make_tuple(pre, cur, out));\n }\n }\n }\n\n memset(dpA, 0, sizeof(dpA));\n memset(dpB, 0, sizeof(dpB));\n for (int i = 0; i < N; i++) dpA[i][i+1][ A[i] ] = true;\n for (int i = 0; i < M; i++) dpB[i][i+1][ B[i] ] = true;\n\n memset(sudpA, 0, sizeof(sudpA));\n memset(sudpB, 0, sizeof(sudpB));\n for (int i = 1; i <= n; i++){\n for (int L = 0; L + i <= N; L++){\n int R = L + i;\n for (size_t j = 0; j < rules.size(); j++){\n int x, y, z;\n tie(x, y, z) = rules[j];\n for (int s = L + 1; s < R; s++)\n dpA[L][R][z] |= (dpA[L][s][x] && dpA[s][R][y]);\n }\n for (int k = 1; k <= 30; k++)\n if (dpA[L][R][k]) sudpA[L][R] += (1 << k);\n }\n }\n for (int i = 1; i <= m; i++){\n for (int L = 0; L + i <= M; L++){\n int R = L + i;\n for (size_t j = 0; j < rules.size(); j++){\n int x, y, z;\n tie(x, y, z) = rules[j];\n for (int s = L + 1; s < R; s++)\n dpB[L][R][z] |= (dpB[L][s][x] && dpB[s][R][y]);\n }\n for (int k = 1; k <= 30; k++)\n if (dpB[L][R][k]) sudpB[L][R] += (1 << k);\n }\n }\n\n int ans = -1;\n for (int As = 0; As < n; As++){\n for (int Bs = 0; Bs < m; Bs++){\n int ep[51][51] = {0};\n ep[As][Bs] = BAS;\n for (int Ax = As; Ax < As + n; Ax++){\n for (int Bx = Bs; Bx < Bs + m; Bx++){\n if (ep[Ax][Bx] == 0) continue;\n for (int Ay = Ax + 1; Ay <= As + n; Ay++){\n for (int By = Bx + 1; By <= Bs + m; By++){\n if (sudpA[Ax][Ay] & sudpB[Bx][By])\n ep[Ay][By] = max(ep[Ay][By], ep[Ax][Bx] + 1);\n }\n }\n }\n }\n ans = max(ans, ep[As+n][Bs+m] - BAS);\n }\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 6904, "score_of_the_acc": -0.1425, "final_rank": 6 }, { "submission_id": "aoj_1191_10335930", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define NMAX 65\n\nint N, M, R;\nint a[NMAX], b[NMAX];\nint nRule[NMAX];\nint fRule[NMAX][15];\nint tRule[NMAX];\n\nbool canA[NMAX][NMAX][30], canB[NMAX][NMAX][30];\nbool tmpDP[NMAX][NMAX][NMAX][10];\n\nvoid calccan(int *arr, int orig, bool can[NMAX][NMAX][30]) {\n for (int i = 0; i < NMAX; i++){\n for (int j = 0; j < NMAX; j++){\n for (int k = 0; k < 30; k++) can[i][j][k] = false;\n }\n }\n for (int i = 0; i < NMAX; i++){\n for (int j = 0; j < NMAX; j++){\n for (int r = 0; r < NMAX; r++){\n for (int l = 0; l < 10; l++) tmpDP[i][j][r][l] = (i == j && l == 0);\n }\n }\n }\n for (int i = 0; i < 2 * orig - 1; i++) can[i][i+1][ arr[i] ] = true;\n\n for (int len = 1; len <= orig; len++){\n for (int l = 0; l + len <= 2 * orig - 1; l++){\n int r = l + len;\n for (int rule = 0; rule < R; rule++){\n for (int j = 1; j <= nRule[rule]; j++){\n for (int x = l; x < r; x++){\n if (tmpDP[l][x][rule][j-1] && can[x][r][ fRule[rule][j-1] ])\n tmpDP[l][r][rule][j] = true;\n }\n }\n }\n for (int rule = 0; rule < R; rule++)\n if (tmpDP[l][r][rule][ nRule[rule] ]) can[l][r][ tRule[rule] ] = true;\n for (int rule = 0; rule < R; rule++)\n if (can[l][r][ fRule[rule][0] ]) tmpDP[l][r][rule][1] = true;\n }\n }\n}\n\nint main(){\n ios::sync_with_stdio(0);\n cin.tie(0);\n\n while (true) {\n cin >> N >> M >> R;\n if (N == 0) break;\n\n for (int i = 0; i < N; i++) cin >> a[i], a[i]--;\n for (int i = 0; i < N; i++) a[i + N] = a[i];\n for (int i = 0; i < M; i++) cin >> b[i], b[i]--;\n for (int i = 0; i < M; i++) b[i + M] = b[i];\n\n for (int i = 0; i < R; i++){\n int len;\n cin >> len;\n nRule[i] = len;\n for (int j = 0; j < len; j++){\n cin >> fRule[i][j];\n fRule[i][j]--;\n }\n cin >> tRule[i];\n tRule[i]--;\n }\n\n calccan(a, N, canA);\n calccan(b, M, canB);\n\n int ans = -1;\n for (int x = 0; x < N; x++){\n for (int y = 0; y < M; y++){\n int dp[26][26];\n for (int i = 0; i < 26; i++){\n for (int j = 0; j < 26; j++) dp[i][j] = -1;\n }\n dp[0][0] = 0;\n for (int i = 0; i <= N; i++){\n for (int j = 0; j <= M; j++){\n if (dp[i][j] < 0) continue;\n for (int k = 0; k < 30; k++){\n for (int c = 1; c <= N - i; c++){\n for (int d = 1; d <= M - j; d++){\n if (canA[x + i][x + i + c][k] && canB[y + j][y + j + d][k])\n dp[i + c][j + d] = max(dp[i + c][j + d], dp[i][j] + 1);\n }\n }\n }\n }\n }\n ans = max(ans, dp[N][M]);\n }\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 7140, "memory_kb": 6324, "score_of_the_acc": -1.1154, "final_rank": 18 }, { "submission_id": "aoj_1191_9278811", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate<class T>\nbool chmax(T &a, const T &b) {if (a < b) {a = b; return 1;} return 0;}\n\nusing ll = long long;\n\nbool is_end = false;\n\nvoid solve()\n{\n ll N, M, R; cin >> N >> M >> R;\n if (N == 0 && M == 0 && R == 0)\n {\n is_end = true;\n return;\n }\n vector<ll> A(N), B(M);\n for (auto &a : A) cin >> a, a--;\n for (auto &b : B) cin >> b, b--;\n vector< pair<ll, vector<ll>> > repl(R);\n for (int i = 0; i < R; ++i)\n {\n int k; cin >> k;\n vector<ll> vec;\n for (int i = 0; i < k; ++i)\n {\n ll x; cin >> x;\n x--;\n vec.emplace_back(x);\n }\n int y; cin >> y;\n y--;\n \n repl[i] = {y, vec};\n }\n \n vector<ll> AA(2 * N), BB(2 * M);\n for (int i = 0; i < N; ++i) AA[i] = AA[N + i] = A[i];\n for (int i = 0; i < M; ++i) BB[i] = BB[M + i] = B[i];\n \n // path[from][char][to] := false / true\n using bs = bitset<60>;\n vector<vector<bs>> pathA(2 * N, vector<bs>(30, 0));\n vector<vector<bs>> pathB(2 * M, vector<bs>(30, 0));\n {\n for (int i = 0; i < 2 * N; ++i)\n {\n int a = AA[i];\n pathA[i][a][i + 1] = true;\n }\n for (int i = 0; i < 2 * M; ++i)\n {\n int b = BB[i];\n pathB[i][b][i+1] = true;\n }\n }\n \n // A\n for (int diff = 2; diff <= N; ++diff)\n {\n for (int from = 0; from < 2 * N; ++from)\n {\n int to = from + diff;\n if (to > 2 * N) break;\n \n for (int r = 0; r < R; ++r)\n {\n auto [c, rule] = repl[r];\n \n bs vec(0), nvec(0);\n vec[from] = true;\n for (auto x : rule)\n {\n for (int pos = from; pos < to; ++pos)\n {\n if (vec[pos]) nvec |= pathA[pos][x];\n }\n \n swap(vec, nvec);\n nvec = 0;\n }\n if (vec[to]) pathA[from][c][to] = true;\n \n }\n }\n }\n \n // B\n for (int diff = 2; diff <= M; ++diff)\n {\n for (int from = 0; from < 2 * M; ++from)\n {\n int to = from + diff;\n if (to > 2 * M) break;\n \n for (int r = 0; r < R; ++r)\n {\n auto [c, rule] = repl[r];\n \n bs vec(0), nvec(0);\n vec[from] = true;\n for (auto x : rule)\n {\n for (int pos = from; pos < to; ++pos)\n {\n if (vec[pos]) nvec |= pathB[pos][x];\n }\n \n swap(vec, nvec);\n nvec = 0;\n }\n if (vec[to]) pathB[from][c][to] = true;\n \n }\n }\n }\n \n // for (int from = 0; from < 2 * N; ++from)\n // {\n // for (int to = 0; to < 2 * N; ++to)\n // {\n // for (int c = 0; c < 30; ++c)\n // {\n // if (pathA[from][c][to]) cout << from << \" \" << to << \" \" << c << endl;\n // }\n // }\n // }\n \n // cout << \"B\" << endl;\n // for (int from = 0; from < 2 * M; ++from)\n // {\n // for (int to = 0; to < 2 * M; ++to)\n // {\n // for (int c = 0; c < 30; ++c)\n // {\n // if (pathB[from][c][to]) cout << from << \" \" << to << \" \" << c << endl;\n // }\n // }\n // }\n \n vector graph(2*N, vector(2*M, vector<pair<int, int>>()));\n for (int sa = 0; sa < 2*N; ++sa)\n {\n for (int sb = 0; sb < 2*M; ++sb)\n {\n for (int ta = sa+1; ta < 2*N; ++ta)\n {\n for (int tb = sb+1; tb < 2*M; ++tb)\n {\n bool flg = false;\n for (int c = 0; c < 30; ++c)\n {\n if (pathA[sa][c][ta] && pathB[sb][c][tb]) flg = true;\n }\n if (flg) graph[sa][sb].push_back({ta, tb});\n // if (flg) cout << sa << \" \" << sb << \" \" << ta << \" \" << tb << endl;\n }\n }\n }\n }\n \n int res = -1;\n for (int sa = 0; sa < N; ++sa)\n {\n for (int sb = 0; sb < M; ++sb)\n {\n int ta = sa + N, tb = sb + M;\n \n vector dist(2*N, vector<int>(2*M, -1));\n dist[sa][sb] = 0;\n for (int a = sa; a < 2*N; ++a)\n {\n for (int b = sb; b < 2*M; ++b)\n {\n if(dist[a][b] == -1) continue;\n for (auto [na, nb] : graph[a][b])\n {\n chmax(dist[na][nb], dist[a][b] + 1);\n }\n }\n }\n \n chmax(res, dist[ta][tb]);\n }\n }\n \n cout << res << endl;\n \n return;\n}\n\nint main()\n{\n while (!is_end)\n {\n solve();\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 950, "memory_kb": 13588, "score_of_the_acc": -0.5098, "final_rank": 12 }, { "submission_id": "aoj_1191_8324049", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int INF = 1012345678;\n\nstruct rewrite {\n\tint len, target;\n\tvector<int> seq;\n};\n\nvector<vector<uint32_t> > get_createable(int N, int K, int L, const vector<int>& A, const vector<rewrite>& R) {\n\tvector<vector<uint32_t> > dp(N + 1);\n\tvector<vector<vector<vector<bool> > > > subdp(K);\n\tfor (int i = 0; i < K; i++) {\n\t\tsubdp[i].resize(N + 1);\n\t\tfor (int r = 0; r <= N; r++) {\n\t\t\tsubdp[i][r].resize(r, vector<bool>(R[i].len + 1));\n\t\t}\n\t}\n\tfor (int r = 1; r <= N; r++) {\n\t\tdp[r].resize(r);\n\t\tdp[r][r - 1] |= uint32_t(1) << A[r - 1];\n\t\tfor (int l = r - 1; l >= 0; l--) {\n\t\t\tfor (int m = l + 1; m < r; m++) {\n\t\t\t\tfor (int i = 0; i < K; i++) {\n\t\t\t\t\tfor (int j = 1; j < R[i].len; j++) {\n\t\t\t\t\t\tif (subdp[i][m][l][j] && ((dp[r][m] >> R[i].seq[j]) & 1) == 1) {\n\t\t\t\t\t\t\tsubdp[i][r][l][j + 1] = true;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor (int i = 0; i < K; i++) {\n\t\t\t\tif (subdp[i][r][l][R[i].len]) {\n\t\t\t\t\tdp[r][l] |= uint32_t(1) << R[i].target;\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor (int i = 0; i < K; i++) {\n\t\t\t\tif (((dp[r][l] >> R[i].seq[0]) & 1) == 1) {\n\t\t\t\t\tsubdp[i][r][l][1] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn dp;\n}\n\nint main() {\n\twhile (true) {\n\t\t// step #1. input\n\t\tint N, M, K;\n\t\tcin >> N >> M >> K;\n\t\tif (N == 0 && M == 0 && K == 0) {\n\t\t\tbreak;\n\t\t}\n\t\tvector<int> A(N), B(M);\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tcin >> A[i];\n\t\t}\n\t\tfor (int i = 0; i < M; i++) {\n\t\t\tcin >> B[i];\n\t\t}\n\t\tvector<rewrite> R(K);\n\t\tfor (int i = 0; i < K; i++) {\n\t\t\tcin >> R[i].len;\n\t\t\tR[i].seq.resize(R[i].len);\n\t\t\tfor (int j = 0; j < R[i].len; j++) {\n\t\t\t\tcin >> R[i].seq[j];\n\t\t\t}\n\t\t\tcin >> R[i].target;\n\t\t}\n\n\t\t// step #2. compression\n\t\tvector<int> comp;\n\t\tcomp.insert(comp.end(), A.begin(), A.end());\n\t\tcomp.insert(comp.end(), B.begin(), B.end());\n\t\tfor (int i = 0; i < K; i++) {\n\t\t\tcomp.insert(comp.end(), R[i].seq.begin(), R[i].seq.end());\n\t\t\tcomp.push_back(R[i].target);\n\t\t}\n\t\tsort(comp.begin(), comp.end());\n\t\tcomp.erase(unique(comp.begin(), comp.end()), comp.end());\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tA[i] = lower_bound(comp.begin(), comp.end(), A[i]) - comp.begin();\n\t\t}\n\t\tfor (int i = 0; i < M; i++) {\n\t\t\tB[i] = lower_bound(comp.begin(), comp.end(), B[i]) - comp.begin();\n\t\t}\n\t\tfor (int i = 0; i < K; i++) {\n\t\t\tfor (int j = 0; j < R[i].len; j++) {\n\t\t\t\tR[i].seq[j] = lower_bound(comp.begin(), comp.end(), R[i].seq[j]) - comp.begin();\n\t\t\t}\n\t\t\tR[i].target = lower_bound(comp.begin(), comp.end(), R[i].target) - comp.begin();\n\t\t}\n\t\tint L = comp.size();\n\n\t\t// step #3. compute \"creatable\" subsequence\n\t\tvector<int> DA(N * 2);\n\t\tfor (int i = 0; i < N * 2; i++) {\n\t\t\tDA[i] = A[i % N];\n\t\t}\n\t\tvector<int> DB(M * 2);\n\t\tfor (int i = 0; i < M * 2; i++) {\n\t\t\tDB[i] = B[i % M];\n\t\t}\n\t\tvector<vector<uint32_t> > f1 = get_createable(N * 2, K, L, DA, R);\n\t\tvector<vector<uint32_t> > f2 = get_createable(M * 2, K, L, DB, R);\n\t\tint ans = -INF;\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tfor (int j = 0; j < M; j++) {\n\t\t\t\tvector<vector<int> > dp(N + 1, vector<int>(M + 1, -INF));\n\t\t\t\tdp[0][0] = 0;\n\t\t\t\tfor (int k = 0; k <= N; k++) {\n\t\t\t\t\tfor (int l = 0; l <= M; l++) {\n\t\t\t\t\t\tfor (int x = 0; x < k; x++) {\n\t\t\t\t\t\t\tfor (int y = 0; y < l; y++) {\n\t\t\t\t\t\t\t\tif (dp[x][y] != -INF && (f1[k + i][x + i] & f2[l + j][y + j]) != 0) {\n\t\t\t\t\t\t\t\t\tdp[k][l] = max(dp[k][l], dp[x][y] + 1);\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (dp[N][M] != -INF) {\n\t\t\t\t\tans = max(ans, dp[N][M]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << (ans != -INF ? ans : -1) << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 760, "memory_kb": 8928, "score_of_the_acc": -0.2987, "final_rank": 9 }, { "submission_id": "aoj_1191_8323589", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint N, A[69];\nint M, B[69];\nint R, Y[69]; vector<int> X[69];\nbool Temp1[69][69][69];\nbool Temp2[69][69];\nint dpA[69][69];\nint dpB[69][69];\nint FinalDP[69][69];\n\nvoid Initialize() {\n\tfor (int i = 0; i < 69; i++) A[i] = 0;\n\tfor (int i = 0; i < 69; i++) B[i] = 0;\n\tfor (int i = 0; i < 69; i++) Y[i] = 0;\n\tfor (int i = 0; i < 69; i++) X[i].clear();\n\tfor (int i = 0; i < 69; i++) {\n\t\tfor (int j = 0; j < 69; j++) {\n\t\t\tTemp2[i][j] = false; dpA[i][j] = 0; dpB[i][j] = 0; FinalDP[i][j] = 0;\n\t\t\tfor (int k = 0; k < 69; k++) Temp1[i][j][k] = false;\n\t\t}\n\t}\n}\n\nint Second(int pos1, int pos2) {\n\tfor (int i = pos1; i <= pos1 + N; i++) {\n\t\tfor (int j = pos2; j <= pos2 + M; j++) FinalDP[i][j] = -(1 << 30);\n\t}\n\tFinalDP[pos1][pos2] = 0;\n\n\t// DP Main\n\tfor (int i = pos1; i < pos1 + N; i++) {\n\t\tfor (int j = pos2; j < pos2 + M; j++) {\n\t\t\tif (FinalDP[i][j] == -(1 << 30)) continue;\n\t\t\tfor (int k = i + 1; k <= pos1 + N; k++) {\n\t\t\t\tfor (int l = j + 1; l <= pos2 + M; l++) {\n\t\t\t\t\tint v1 = dpA[i % N][k % N];\n\t\t\t\t\tint v2 = dpB[j % M][l % M];\n\t\t\t\t\tif ((v1 & v2) == 0) continue;\n\t\t\t\t\tFinalDP[k][l] = max(FinalDP[k][l], FinalDP[i][j] + 1);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\t// Return\n\treturn FinalDP[pos1 + N][pos2 + M];\n}\n\nbool solve_sub(int cl, int cr, int idx, int sz) {\n\tfor (int i = 0; i <= X[idx].size(); i++) {\n\t\tfor (int j = cl; j <= cr; j++) Temp2[i][j] = false;\n\t}\n\tTemp2[0][cl] = true;\n\n\t// DP Sub\n\tfor (int i = 0; i < X[idx].size(); i++) {\n\t\tfor (int j = cl; j < cr; j++) {\n\t\t\tif (Temp2[i][j] == false) continue;\n\t\t\tfor (int k = j + 1; k <= cr; k++) {\n\t\t\t\tint v1 = j % sz;\n\t\t\t\tint v2 = k % sz;\n\t\t\t\tif (Temp1[v1][v2][X[idx][i]] == true) Temp2[i + 1][k] = true;\n\t\t\t}\n\t\t}\n\t}\n\treturn Temp2[X[idx].size()][cr];\n}\n\nvoid solve(vector<int> List) {\n\t// Init Part\n\tfor (int i = 0; i < List.size(); i++) {\n\t\tfor (int j = 0; j < List.size(); j++) {\n\t\t\tfor (int k = 1; k <= 30; k++) Temp1[i][j][k] = false;\n\t\t}\n\t}\n\tfor (int i = 0; i < List.size(); i++) Temp1[i][(i + 1) % List.size()][List[i]] = true;\n\n\t// Main Part\n\tfor (int haba = 2; haba <= List.size(); haba++) {\n\t\tfor (int l = 0; l < List.size(); l++) {\n\t\t\tint r = l + haba;\n\t\t\tfor (int i = 0; i < R; i++) {\n\t\t\t\tbool ret = solve_sub(l, r, i, List.size());\n\t\t\t\tif (ret == true) Temp1[l][r % List.size()][Y[i]] = true;\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main() {\n\twhile (true) {\n\t\tInitialize();\n\n\t\t// Step 1. Input\n\t\tcin >> N >> M >> R; if (N + M + R == 0) break;\n\t\tfor (int i = 0; i < N; i++) cin >> A[i];\n\t\tfor (int i = 0; i < M; i++) cin >> B[i];\n\t\tfor (int i = 0; i < R; i++) {\n\t\t\tint k; cin >> k;\n\t\t\tX[i] = vector<int>(k, 0);\n\t\t\tfor (int j = 0; j < k; j++) cin >> X[i][j];\n\t\t\tcin >> Y[i];\n\t\t}\n\n\t\t// Step 2. DP Part 1\n\t\tvector<int> ListA; for (int i = 0; i < N; i++) ListA.push_back(A[i]);\n\t\tvector<int> ListB; for (int i = 0; i < M; i++) ListB.push_back(B[i]);\n\t\tsolve(ListA);\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tfor (int j = 0; j < N; j++) {\n\t\t\t\tfor (int k = 1; k <= 30; k++) {\n\t\t\t\t\tif (Temp1[i][j][k] == true) dpA[i][j] += (1 << k);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tsolve(ListB);\n\t\tfor (int i = 0; i < M; i++) {\n\t\t\tfor (int j = 0; j < M; j++) {\n\t\t\t\tfor (int k = 1; k <= 30; k++) {\n\t\t\t\t\tif (Temp1[i][j][k] == true) dpB[i][j] += (1 << k);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\t// Step 3. DP Part 2\n\t\tint Answer = -(1 << 30);\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tfor (int j = 0; j < M; j++) {\n\t\t\t\tint ret = Second(i, j);\n\t\t\t\tAnswer = max(Answer, ret);\n\t\t\t}\n\t\t}\n\n\t\t// Step 4. Output\n\t\tif (Answer == -(1 << 30)) cout << \"-1\" << endl;\n\t\telse cout << Answer << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 900, "memory_kb": 3696, "score_of_the_acc": -0.1126, "final_rank": 3 }, { "submission_id": "aoj_1191_7999148", "code_snippet": "#include <algorithm>\n#include <bitset>\n#include <cassert>\n#include <cmath>\n#include <complex>\n#include <iomanip>\n#include <iostream>\n#include <limits>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <random>\n#include <set>\n#include <stack>\n#include <string>\n#include <tuple>\n#include <unordered_map>\n#include <unordered_set>\n#include <utility>\n#include <vector>\n\n#define rep(i, s, n) for (int i = int(s); i < int(n); i++)\n#define rrep(i, s, n) for (int i = int(n) - 1; i >= int(s); i--)\n#define all(v) v.begin(), v.end()\n\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n\ntemplate <class T> bool chmin(T &a, T b) {\n if (a <= b) return false;\n a = b;\n return true;\n}\n\ntemplate <class T> bool chmax(T &a, T b) {\n if (a >= b) return false;\n a = b;\n return true;\n}\n\n#define debug(...) \\\n std::cerr << \"LINE: \" << __LINE__ << \" [\" << #__VA_ARGS__ << \"]:\", \\\n debug_out(__VA_ARGS__)\n\nvoid debug_out() {\n std::cerr << std::endl;\n}\n\ntemplate <typename Head, typename... Tail> void debug_out(Head h, Tail... t) {\n std::cerr << \" \" << h;\n if (sizeof...(t) > 0) std::cerr << \",\";\n debug_out(t...);\n}\n\ntemplate <typename T1, typename T2>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T1, T2> &pa) {\n return os << pa.first << \" \" << pa.second;\n}\n\nint n, m, rs;\nstd::vector<std::vector<int>> a;\nstd::vector<std::vector<int>> xs;\nstd::vector<int> ys;\n\nbool dp[2][60][60][40];\nbool edp[2][60][60][60][20];\n\nvoid init() {\n a.clear();\n xs.clear();\n ys.clear();\n a.resize(2);\n a[0].resize(n);\n a[1].resize(m);\n xs.resize(rs);\n ys.resize(rs);\n rep(i, 0, 2) rep(j, 0, 60) rep(k, 0, 60) {\n rep(l, 0, 40) {\n dp[i][j][k][l] = false;\n }\n rep(l, 0, 60) {\n rep(x, 0, 20) {\n edp[i][j][k][l][x] = false;\n }\n }\n }\n}\n\nvoid calc() {\n int idx = 0;\n rep(i, 0, n) rep(j, 0, rs) edp[idx][i][i][j][0] = true;\n rep(i, 0, 2 * n) {\n dp[idx][i][i + 1][a[idx][i]] = true;\n }\n rep(len, 1, n + 1) {\n for (int l = 0; l + len < 2 * n; l++) {\n int r = l + len;\n rep(i, 0, rs) {\n rep(j, 1, int(xs[i].size()) + 1) {\n rep(k, l + 1, r) edp[idx][l][r][i][j] |=\n edp[idx][l][k][i][j - 1] & dp[idx][k][r][xs[i][j - 1]];\n }\n }\n rep(i, 0, rs) {\n if (edp[idx][l][r][i][xs[i].size()])\n dp[idx][l][r][ys[i]] = true;\n }\n rep(i, 0, rs) {\n if (dp[idx][l][r][xs[i][0]]) edp[idx][l][r][i][1] = true;\n }\n }\n }\n idx = 1;\n rep(i, 0, m) rep(j, 0, rs) edp[idx][i][i][j][0] = true;\n rep(i, 0, 2 * m) {\n dp[idx][i][i + 1][a[idx][i]] = true;\n }\n rep(len, 1, m + 1) {\n for (int l = 0; l + len < 2 * m; l++) {\n int r = l + len;\n rep(i, 0, rs) {\n rep(j, 1, int(xs[i].size()) + 1) {\n rep(k, l + 1, r) edp[idx][l][r][i][j] |=\n edp[idx][l][k][i][j - 1] & dp[idx][k][r][xs[i][j - 1]];\n }\n }\n rep(i, 0, rs) {\n if (edp[idx][l][r][i][xs[i].size()])\n dp[idx][l][r][ys[i]] = true;\n }\n rep(i, 0, rs) {\n if (dp[idx][l][r][xs[i][0]]) edp[idx][l][r][i][1] = true;\n }\n }\n }\n}\n\nbool solve() {\n std::cin >> n >> m >> rs;\n if (n == 0 && m == 0 && rs == 0) return false;\n init();\n rep(i, 0, n) {\n std::cin >> a[0][i];\n }\n rep(i, 0, n) a[0].emplace_back(a[0][i]);\n rep(i, 0, m) {\n std::cin >> a[1][i];\n }\n rep(i, 0, m) a[1].emplace_back(a[1][i]);\n rep(i, 0, rs) {\n int k;\n std::cin >> k;\n xs[i].resize(k);\n rep(j, 0, k) {\n std::cin >> xs[i][j];\n }\n std::cin >> ys[i];\n }\n calc();\n int ans = -1;\n rep(la, 0, n) {\n rep(lb, 0, m) {\n std::vector gdp(n + 1, std::vector<int>(m + 1, -1));\n gdp[0][0] = 0;\n rep(ra, 0, n) {\n rep(rb, 0, m) {\n if (gdp[ra][rb] == -1) continue;\n rep(raa, ra + 1, n + 1) {\n rep(rbb, rb + 1, m + 1) {\n rep(c, 0, 40) {\n if(dp[0][la + ra][la + raa][c] && dp[1][lb + rb][lb + rbb][c]) {\n chmax(gdp[raa][rbb], gdp[ra][rb] + 1);\n }\n }\n }\n }\n }\n }\n chmax(ans, gdp[n][m]);\n }\n }\n std::cout << ans << '\\n';\n return true;\n}\n\nint main() {\n while (solve())\n ;\n}", "accuracy": 1, "time_ms": 7110, "memory_kb": 11920, "score_of_the_acc": -1.3316, "final_rank": 19 }, { "submission_id": "aoj_1191_7965033", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, t) for (int i = (int)(s); i < (int)(t); ++i)\n#define revrep(i, t, s) for (int i = (int)(t)-1; i >= (int)(s); --i)\n#define all(x) begin(x), end(x)\ntemplate <typename T>\nbool chmax(T& a, const T& b) {\n return a < b ? (a = b, 1) : 0;\n}\ntemplate <typename T>\nbool chmin(T& a, const T& b) {\n return a > b ? (a = b, 1) : 0;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(15);\n\n const int X = 31;\n\n while (true) {\n int n, m, r;\n cin >> n >> m >> r;\n if (n == 0) break;\n vector<int> A(2 * n), B(2 * m);\n rep(i, 0, n) {\n int x;\n cin >> x;\n A[i] = A[n + i] = x;\n }\n rep(i, 0, m) {\n int x;\n cin >> x;\n B[i] = B[m + i] = x;\n }\n vector<vector<vector<int>>> rules(X);\n rep(_, 0, r) {\n int k;\n cin >> k;\n vector<int> xs(k);\n for (auto& x : xs) cin >> x;\n int y;\n cin >> y;\n rules[y].push_back(xs);\n }\n\n auto calc = [&](vector<int> A) {\n int n = A.size();\n vector dp(n, vector<int>(n + 1));\n rep(i, 0, n) { dp[i][i + 1] = 1 << A[i]; }\n rep(l, 2, n + 1) rep(i, 0, n - l + 1) {\n int j = i + l;\n\n rep(c, 0, X) for (auto& xs : rules[c]) {\n int k = xs.size();\n vector f(l + 1, vector<bool>(k + 1));\n\n f[0][0] = true;\n\n rep(s, 0, l) rep(t, s + 1, l + 1) {\n rep(u, 0, k) {\n if (f[s][u] && (dp[i + s][i + t] >> xs[u] & 1)) {\n f[t][u + 1] = true;\n }\n }\n }\n\n if (f[l][k]) {\n dp[i][j] |= 1 << c;\n }\n }\n }\n return dp;\n };\n\n auto dpA = calc(A);\n auto dpB = calc(B);\n\n int ans = -1;\n\n rep(shiftA, 0, n) rep(shiftB, 0, m) {\n vector g(n + 1, vector<int>(m + 1, -1e9));\n g[0][0] = 0;\n rep(i, 1, n + 1) rep(j, 1, m + 1) {\n rep(a, 0, i) rep(b, 0, j) {\n if (dpA[shiftA + a][shiftA + i] &\n dpB[shiftB + b][shiftB + j]) {\n chmax(g[i][j], g[a][b] + 1);\n }\n }\n }\n chmax(ans, g[n][m]);\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 2420, "memory_kb": 3524, "score_of_the_acc": -0.3249, "final_rank": 10 }, { "submission_id": "aoj_1191_7234123", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nusing namespace std::chrono;\ntypedef long long int llint;\ntypedef long double lldo;\n#define mp make_pair\n#define mt make_tuple\n#define pub push_back\n#define puf push_front\n#define pob pop_back\n#define pof pop_front\n#define fir first\n#define sec second\n#define res resize\n#define ins insert\n#define era erase\n#define REP(i, n) for(int i = 0;i < (n);i++)\n/*cout<<fixed<<setprecision(20);cin.tie(0);ios::sync_with_stdio(false);*/\nconst int mod=1000000007;\nconst llint inf=2.19e15+1;\nconst long double pai=3.141592653589793238462643383279502884197;\nconst long double eps=1e-10;\ntemplate <class T,class U>bool chmin(T& a,U b){if(a>b){a=b;return true;}return false;}\ntemplate <class T,class U>bool chmax(T& a,U b){if(a<b){a=b;return true;}return false;}\nllint gcd(llint a,llint b){if(a%b==0){return b;}else return gcd(b,a%b);}\nllint lcm(llint a,llint b){if(a==0){return b;}return a/gcd(a,b)*b;}\ntemplate<class T> void SO(T& ve){sort(ve.begin(),ve.end());}\ntemplate<class T> void REV(T& ve){reverse(ve.begin(),ve.end());}\ntemplate<class T>int LBI(const vector<T>&ar,T in){return lower_bound(ar.begin(),ar.end(),in)-ar.begin();}\ntemplate<class T>int UBI(const vector<T>&ar,T in){return upper_bound(ar.begin(),ar.end(),in)-ar.begin();}\n\nint main(void){\n\twhile(-1){\n\t\tint n,m,r,h,i,j,k;\n\t\tcin>>n>>m>>r;\n\t\tif(n==0){return 0;}\n\t\tint A[50]={};\n\t\tint B[50]={};\n\t\tfor(i=0;i<n;i++){cin>>A[i];}\n\t\tfor(i=n;i<n+n;i++){A[i]=A[i-n];}\n\t\tfor(i=0;i<m;i++){cin>>B[i];}\n\t\tfor(i=m;i<m+m;i++){B[i]=B[i-m];}\n\t\t\n\t\t\n\t\tvector<tuple<int,int,int>>rules;\n\t\tint mkaz=30;\n\t\tfor(h=0;h<r;h++){\n\t\t\tint Ka;cin>>Ka;\n\t\t\tint mae;cin>>mae;\n\t\t\tfor(i=1;i<Ka;i++){\n\t\t\t\tint now;cin>>now;\n\t\t\t\tif(i+1<Ka){\n\t\t\t\t\tmkaz++;\n\t\t\t\t\trules.pub(mt(mae,now,mkaz));\n\t\t\t\t\tmae=mkaz;\n\t\t\t\t}else{\n\t\t\t\t\tint ruy;cin>>ruy;\n\t\t\t\t\trules.pub(mt(mae,now,ruy));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\n\t\tstatic bool dpA[51][51][600]={};\n\t\tstatic bool dpB[51][51][600]={};\n\t\tfor(i=0;i<=50;i++){\n\t\t\tfor(j=0;j<=50;j++){\n\t\t\t\tfor(k=0;k<600;k++){\n\t\t\t\t\tdpA[i][j][k]=false;\n\t\t\t\t\tdpB[i][j][k]=false;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//R,文字種類 の Lbit目をみる\n\t\tfor(i=0;i<n+n;i++){\n\t\t\tdpA[i][i+1][A[i]]=1;\n\t\t}\n\t\tfor(i=0;i<m+m;i++){\n\t\t\tdpB[i][i+1][B[i]]=1;\n\t\t}\n\t\tint sudpA[51][51]={};\n\t\tint sudpB[51][51]={};\n\t\tfor(i=1;i<=n;i++){\n\t\t\tfor(int L=0;L+i<=n+n;L++){\n\t\t\t\tint R=L+i;\n\t\t\t\tfor(j=0;j<rules.size();j++){\n\t\t\t\t\tint x,y,z;\n\t\t\t\t\ttie(x,y,z)=rules[j];\n\t\t\t\t\tfor(int s=L+1;s<R;s++){\n\t\t\t\t\t\tdpA[L][R][z]|=dpA[L][s][x]&&dpA[s][R][y];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tfor(k=1;k<=30;k++){\n\t\t\t\t\tif(dpA[L][R][k]){sudpA[L][R]+=(1<<k);}\n\t\t\t\t}\n\t\t\t\t//cerr<<\"sudpA[\"<<L<<\"][\"<<R<<\"]=\"<<sudpA[L][R]<<endl;\n\t\t\t}\n\t\t}\n\t\tfor(i=1;i<=m;i++){\n\t\t\tfor(int L=0;L+i<=m+m;L++){\n\t\t\t\tint R=L+i;\n\t\t\t\tfor(j=0;j<rules.size();j++){\n\t\t\t\t\tint x,y,z;\n\t\t\t\t\ttie(x,y,z)=rules[j];\n\t\t\t\t\tfor(int s=L+1;s<R;s++){\n\t\t\t\t\t\tdpB[L][R][z]|=dpB[L][s][x]&&dpB[s][R][y];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tfor(k=1;k<=30;k++){\n\t\t\t\t\tif(dpB[L][R][k]){sudpB[L][R]+=(1<<k);}\n\t\t\t\t}\n\t\t\t\t//cerr<<\"sudpB[\"<<L<<\"][\"<<R<<\"]=\"<<sudpB[L][R]<<endl;\n\t\t\t}\n\t\t}\n\t\t\n\t\t\n\t\t//次 対応を走査\n\t\tint ans=-1;\n\t\tfor(int As=0;As<n;As++){\n\t\t\tfor(int Bs=0;Bs<m;Bs++){\n\t\t\t\tint ep[51][51]={};\n\t\t\t\tep[As][Bs]=mod;\n\t\t\t\tfor(int Ax=As;Ax<As+n;Ax++){\n\t\t\t\t\tfor(int Bx=Bs;Bx<Bs+m;Bx++){\n\t\t\t\t\t\tif(ep[Ax][Bx]==0){continue;}\n\t\t\t\t\t\t//ここから遷移する\n\t\t\t\t\t\tfor(int Ay=Ax+1;Ay<=As+n;Ay++){\n\t\t\t\t\t\t\tfor(int By=Bx+1;By<=Bs+m;By++){\n\t\t\t\t\t\t\t\tif(sudpA[Ax][Ay]&sudpB[Bx][By]){\n\t\t\t\t\t\t\t\t\tchmax(ep[Ay][By],ep[Ax][Bx]+1);\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tchmax(ans,ep[As+n][Bs+m]-mod);\n\t\t\t}\n\t\t}\n\t\tcout<<ans<<endl;\n\t}\n\treturn 0;\n}\n\n/*\n3 3 3\n1 2 3\n4 5 6\n2 1 2 5\n2 6 4 3\n2 5 3 1\n\n3 3 2\n1 1 1\n2 2 1\n2 1 1 2\n2 2 2 1\n\n7 1 2\n1 1 2 1 4 1 2\n4\n3 1 4 1 4\n3 2 4 2 4\n\n16 14 5\n2 1 2 2 1 3 2 1 3 2 2 1 1 3 1 2\n2 1 3 1 1 2 3 1 2 2 2 2 1 3\n2 3 1 3\n3 2 2 2 1\n3 2 2 1 2\n3 1 2 2 2\n4 2 1 2 2 2\n\n0 0 0\n*/", "accuracy": 1, "time_ms": 370, "memory_kb": 6428, "score_of_the_acc": -0.144, "final_rank": 7 }, { "submission_id": "aoj_1191_6046349", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n#define all(x) (x).begin(),(x).end()\n#define fi first\n#define se second\n#define mp make_pair\n#define si(x) int(x.size())\nconst int mod=1000000007,MAX=35,INF=1<<29;\n\nbool sub1[MAX][MAX][MAX];\nbool sub2[MAX][MAX][MAX];\nbool can[MAX][MAX];\nbool match[MAX][MAX][MAX][MAX];\nint dp[MAX*2][MAX*2];\n\nint main(){\n \n std::ifstream in(\"text.txt\");\n std::cin.rdbuf(in.rdbuf());\n cin.tie(0);\n ios::sync_with_stdio(false);\n \n while(1){\n int N,M,K;cin>>N>>M>>K;\n if(N==0) break;\n vector<int> A(N),B(M);\n for(int i=0;i<N;i++){\n cin>>A[i];A[i]--;\n }\n for(int i=0;i<N;i++) A.push_back(A[i]);\n for(int i=0;i<M;i++){\n cin>>B[i];B[i]--;\n }\n for(int i=0;i<M;i++) B.push_back(B[i]);\n vector<vector<int>> S(K);vector<int> T(K);\n for(int i=0;i<K;i++){\n int x;cin>>x;\n S[i].resize(x);\n for(int j=0;j<x;j++){\n cin>>S[i][j];S[i][j]--;\n }\n cin>>T[i];T[i]--;\n }\n memset(sub1,0,sizeof(sub1));\n memset(sub2,0,sizeof(sub2));\n \n for(int len=1;len<=N;len++){\n for(int l=0;l<N;l++){\n int r=(l+len-1)%N;\n if(len==1) sub1[l][r][A[l]]=true;\n else{\n for(int k=0;k<K;k++){\n memset(can,0,sizeof(can));\n can[l][0]=true;\n for(int i=l;i<l+len;i++){\n for(int j=si(S[k])-1;j>=0;j--){\n if(!can[i%N][j]) continue;\n for(int to=i+1;to<=l+len;to++){\n if(sub1[i%N][(to-1)%N][S[k][j]]) can[to%N][j+1]=true;\n }\n }\n }\n if(can[(l+len)%N][si(S[k])]) sub1[l][r][T[k]]=true;\n }\n }\n }\n }\n \n for(int len=1;len<=M;len++){\n for(int l=0;l<M;l++){\n int r=(l+len-1)%M;\n if(len==1) sub2[l][r][B[l]]=true;\n else{\n for(int k=0;k<K;k++){\n memset(can,0,sizeof(can));\n can[l][0]=true;\n for(int i=l;i<l+len;i++){\n for(int j=si(S[k])-1;j>=0;j--){\n if(!can[i%M][j]) continue;\n for(int to=i+1;to<=l+len;to++){\n if(sub2[i%M][(to-1)%M][S[k][j]]) can[to%M][j+1]=true;\n }\n }\n }\n if(can[(l+len)%M][si(S[k])]) sub2[l][r][T[k]]=true;\n }\n }\n }\n }\n \n memset(match,0,sizeof(match));\n for(int l1=0;l1<N;l1++){\n for(int r1=0;r1<N;r1++){\n for(int l2=0;l2<M;l2++){\n for(int r2=0;r2<M;r2++){\n for(int k=0;k<30;k++){\n if(sub1[l1][r1][k]&&sub2[l2][r2][k]) match[l1][r1][l2][r2]=true;\n }\n }\n }\n }\n }\n \n int ans=-1;\n \n for(int l1=0;l1<N;l1++){\n for(int l2=0;l2<M;l2++){\n for(int i=0;i<=2*N;i++) for(int j=0;j<=2*M;j++) dp[i][j]=-INF;\n dp[l1][l2]=0;\n for(int i=l1;i<l1+N;i++){\n for(int j=l2;j<l2+M;j++){\n if(dp[i][j]==-INF) continue;\n for(int a=i+1;a<=l1+N;a++){\n for(int b=j+1;b<=l2+M;b++){\n if(match[i%N][(a-1)%N][j%M][(b-1)%M]) chmax(dp[a][b],dp[i][j]+1);\n }\n }\n }\n }\n chmax(ans,dp[l1+N][l2+M]);\n }\n }\n \n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 960, "memory_kb": 4972, "score_of_the_acc": -0.1716, "final_rank": 8 }, { "submission_id": "aoj_1191_6039948", "code_snippet": "#pragma region Macros\n#pragma comment(linker, \"/stack:200000000\")\n// #pragma GCC optimize(\"unroll-loops\")\n// #pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2,tune=native\")\n// #pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2\")\n// #pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\n#define ll long long\nusing ld = long double;\n#define rep2(i, a, b) for(ll i = (a); i <= (b); i++)\n#define rep3(i, a, b) for(ll i = (a); i >= (b); --i)\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define each(i, a) for(auto &&i : a)\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define pb push_back\n#define eb emplace_back\n#define vi vector<int>\n#define vll vector<ll>\n#define vpi vector<pii>\n#define vpll vector<pll>\n#define overload2(_1, _2, name, ...) name\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define VEC(type, name, size) \\\n vector<type> name(size); \\\n IN(name)\n#define VEC2(type, name1, name2, size) \\\n vector<type> name1(size), name2(size); \\\n for(int i = 0; i < size; i++) IN(name1[i], name2[i])\n#define VEC3(type, name1, name2, name3, size) \\\n vector<type> name1(size), name2(size), name3(size); \\\n for(int i = 0; i < size; i++) IN(name1[i], name2[i], name3[i])\n#define vv(type, name, h, ...) vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define VV(type, name, h, w) \\\n vector<vector<type>> name(h, vector<type>(w)); \\\n IN(name)\n#define vvv(type, name, h, w, ...) vector<vector<vector<type>>> name(h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name(a, vector<vector<vector<type>>>(b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n#define mt make_tuple\n#define fi first\n#define se second\n#define all(c) begin(c), end(c)\n#define rall(c) rbegin(c), rend(c)\n#define SORT(v) sort(all(v))\n#define REV(v) reverse(all(v))\ntemplate <class T = ll, class S> T SUM(const S &v) { return accumulate(all(v), T(0)); }\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define ub(c, x) distance((c).begin(), upper_bound(all(c), (x)))\nusing namespace std;\nconstexpr pii dx4[4] = {pii{1, 0}, pii{0, 1}, pii{-1, 0}, pii{0, -1}};\nconstexpr pii dx8[8] = {{1, 0}, {1, 1}, {0, 1}, {-1, 1}, {-1, 0}, {-1, -1}, {0, -1}, {1, -1}};\nconst string YESNO[2] = {\"NO\", \"YES\"};\nconst string YesNo[2] = {\"No\", \"Yes\"};\nconst string yesno[2] = {\"no\", \"yes\"};\nvoid YES(bool t = 1) { cout << YESNO[t] << endl; }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { cout << YesNo[t] << endl; }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { cout << yesno[t] << endl; }\nvoid no(bool t = 1) { yes(!t); }\ntemplate <class T> using vc = vector<T>;\ntemplate <class T> using vvc = vector<vc<T>>;\ntemplate <class T> using vvvc = vector<vvc<T>>;\ntemplate <class T> using vvvvc = vector<vvvc<T>>;\ntemplate <class T> using pq = priority_queue<T>;\ntemplate <class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n#define si(c) (int)(c).size()\n#define INT(...) \\\n int __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define LL(...) \\\n ll __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define STR(...) \\\n string __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define CHR(...) \\\n char __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define DBL(...) \\\n double __VA_ARGS__; \\\n IN(__VA_ARGS__)\nint scan() { return getchar(); }\nvoid scan(int &a) { cin >> a; }\nvoid scan(long long &a) { cin >> a; }\nvoid scan(char &a) { cin >> a; }\nvoid scan(double &a) { cin >> a; }\nvoid scan(string &a) { cin >> a; }\ntemplate <class T, class S> void scan(pair<T, S> &p) { scan(p.first), scan(p.second); }\ntemplate <class T> void scan(vector<T> &);\ntemplate <class T> void scan(vector<T> &a) {\n for(auto &i : a) scan(i);\n}\ntemplate <class T> void scan(T &a) { cin >> a; }\nvoid IN() {}\ntemplate <class Head, class... Tail> void IN(Head &head, Tail &...tail) {\n scan(head);\n IN(tail...);\n}\n\ntemplate <class T, class S> inline bool chmax(T &a, const S &b) { return (a < b ? a = b, 1 : 0); }\ntemplate <class T, class S> inline bool chmin(T &a, const S &b) { return (a > b ? a = b, 1 : 0); }\nvi iota(int n) {\n vi a(n);\n iota(all(a), 0);\n return a;\n}\ntemplate <typename T> vi iota(vector<T> &a, bool greater = false) {\n vi res(a.size());\n iota(all(res), 0);\n sort(all(res), [&](int i, int j) {\n if(greater) return a[i] > a[j];\n return a[i] < a[j];\n });\n return res;\n}\n#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())\n\ntemplate <class T> T ceil(T x, T y) {\n assert(y >= 1);\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\n\ntemplate <class T> T floor(T x, T y) {\n assert(y >= 1);\n return (x > 0 ? x / y : (x + y - 1) / y);\n}\ntemplate <class T> T POW(T x, int n) {\n T res = 1;\n for(; n; n >>= 1, x *= x)\n if(n & 1) res *= x;\n return res;\n}\ntemplate <class T, class S> T POW(T x, S n, const ll &mod) {\n T res = 1;\n for(; n; n >>= 1, x = x * x % mod)\n if(n & 1) res = res * x % mod;\n return res;\n}\nvector<pll> factor(ll x) {\n vector<pll> ans;\n for(ll i = 2; i * i <= x; i++)\n if(x % i == 0) {\n ans.push_back({i, 1});\n while((x /= i) % i == 0) ans.back().second++;\n }\n if(x != 1) ans.push_back({x, 1});\n return ans;\n}\ntemplate <class T> vector<T> divisor(T x) {\n vector<T> ans;\n for(T i = 1; i * i <= x; i++)\n if(x % i == 0) {\n ans.pb(i);\n if(i * i != x) ans.pb(x / i);\n }\n return ans;\n}\ntemplate <typename T> void zip(vector<T> &x) {\n vector<T> y = x;\n UNIQUE(y);\n for(int i = 0; i < x.size(); ++i) { x[i] = lb(y, x[i]); }\n}\ntemplate <class S> void fold_in(vector<S> &v) {}\ntemplate <typename Head, typename... Tail, class S> void fold_in(vector<S> &v, Head &&a, Tail &&...tail) {\n for(auto e : a) v.emplace_back(e);\n fold_in(v, tail...);\n}\ntemplate <class S> void renumber(vector<S> &v) {}\ntemplate <typename Head, typename... Tail, class S> void renumber(vector<S> &v, Head &&a, Tail &&...tail) {\n for(auto &&e : a) e = lb(v, e);\n renumber(v, tail...);\n}\ntemplate <class S, class... Args> vector<S> zip(vector<S> &head, Args &&...args) {\n vector<S> v;\n fold_in(v, head, args...);\n sort(all(v)), v.erase(unique(all(v)), v.end());\n renumber(v, head, args...);\n return v;\n}\n\n// x in [l, r)\ntemplate <class T, class S> bool inc(const T &x, const S &l, const S &r) { return l <= x and x < r; }\n// (a, b) in [lx, rx) * [ly, ry)\ntemplate <class T, class S> bool inc(const pair<T, T> &x, const S &lx, const S &ly, const S &rx, const S &ry) { return inc(x.fi, lx, rx) && inc(x.se, ly, ry); }\n\nconstexpr ll ten(int n) { return n == 0 ? 1 : ten(n - 1) * 10; }\n// bit 演算系\nll pow2(int i) { return 1LL << i; }\nint topbit(signed t) { return t == 0 ? -1 : 31 - __builtin_clz(t); }\nint topbit(ll t) { return t == 0 ? -1 : 63 - __builtin_clzll(t); }\nint lowbit(signed a) { return a == 0 ? 32 : __builtin_ctz(a); }\nint lowbit(ll a) { return a == 0 ? 64 : __builtin_ctzll(a); }\n// int allbit(int n) { return (1 << n) - 1; }\nconstexpr ll allbit(int n) { return (1LL << n) - 1; }\n// int popcount(signed t) { return __builtin_popcount(t); }\n// int popcount(ll t) { return __builtin_popcountll(t); }\nint popcount(uint64_t t) { return __builtin_popcountll(t); }\nbool ispow2(int i) { return i && (i & -i) == i; }\n\nll rnd(ll l, ll r) { //[l, r)\n#ifdef _LOCAL\n static mt19937_64 gen;\n#else\n static mt19937_64 gen(chrono::steady_clock::now().time_since_epoch().count());\n#endif\n return uniform_int_distribution<ll>(l, r - 1)(gen);\n}\nll rnd(ll n) { return rnd(0, n); }\n\ntemplate <class t> void random_shuffle(vc<t> &a) { rep(i, si(a)) swap(a[i], a[rnd(0, i + 1)]); }\n\nint in() {\n int x;\n cin >> x;\n return x;\n}\nll lin() {\n unsigned long long x;\n cin >> x;\n return x;\n}\n\ntemplate <class T, class S> pair<T, S> operator-(const pair<T, S> &x, const pair<T, S> &y) { return pair<T, S>(x.fi - y.fi, x.se - y.se); }\ntemplate <class T, class S> pair<T, S> operator+(const pair<T, S> &x, const pair<T, S> &y) { return pair<T, S>(x.fi + y.fi, x.se + y.se); }\ntemplate <class T> pair<T, T> operator&(const pair<T, T> &l, const pair<T, T> &r) { return pair<T, T>(max(l.fi, r.fi), min(l.se, r.se)); }\ntemplate <class T, class S> pair<T, S> operator+=(pair<T, S> &l, const pair<T, S> &r) { return l = l + r; }\ntemplate <class T, class S> pair<T, S> operator-=(pair<T, S> &l, const pair<T, S> &r) { return l = l - r; }\ntemplate <class T> bool intersect(const pair<T, T> &l, const pair<T, T> &r) { return (l.se < r.se ? r.fi < l.se : l.fi < r.se); }\n\ntemplate <class T> ll operator*(const pair<T, T> &x, const pair<T, T> &y) { return (ll)x.fi * y.fi + (ll)x.se * y.se; }\n\ntemplate <typename T> struct edge {\n int from, to;\n T cost;\n int id;\n edge(int to, T cost) : from(-1), to(to), cost(cost) {}\n edge(int from, int to, T cost) : from(from), to(to), cost(cost) {}\n edge(int from, int to, T cost, int id) : from(from), to(to), cost(cost), id(id) {}\n constexpr bool operator<(const edge<T> &rhs) const noexcept { return cost < rhs.cost; }\n edge &operator=(const int &x) {\n to = x;\n return *this;\n }\n operator int() const { return to; }\n};\ntemplate <typename T> using Edges = vector<edge<T>>;\n\nusing Tree = vector<vector<int>>;\nusing Graph = vector<vector<int>>;\ntemplate <class T> using Wgraph = vector<vector<edge<T>>>;\nGraph getG(int n, int m = -1, bool directed = false, int margin = 1) {\n Tree res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n cin >> a >> b;\n a -= margin, b -= margin;\n res[a].emplace_back(b);\n if(!directed) res[b].emplace_back(a);\n }\n return res;\n}\nGraph getTreeFromPar(int n, int margin = 1) {\n Graph res(n);\n for(int i = 1; i < n; i++) {\n int a;\n cin >> a;\n res[a - margin].emplace_back(i);\n }\n return res;\n}\ntemplate <class T> Wgraph<T> getWg(int n, int m = -1, bool directed = false, int margin = 1) {\n Wgraph<T> res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n T c;\n cin >> a >> b >> c;\n a -= margin, b -= margin;\n res[a].emplace_back(b, c);\n if(!directed) res[b].emplace_back(a, c);\n }\n return res;\n}\nvoid add(Graph &G, int x, int y) { G[x].eb(y), G[y].eb(x); }\ntemplate <class S, class T> void add(Wgraph<S> &G, int x, int y, T c) { G[x].eb(y, c), G[y].eb(x, c); }\n\n#define i128 __int128_t\n#define ull unsigned long long int\n#define TEST \\\n INT(testcases); \\\n while(testcases--)\ntemplate <class T> ostream &operator<<(ostream &os, const vector<T> &v) {\n for(auto it = begin(v); it != end(v); ++it) {\n if(it == begin(v))\n os << *it;\n else\n os << \" \" << *it;\n }\n return os;\n}\ntemplate <class T, class S> ostream &operator<<(ostream &os, const pair<T, S> &p) {\n os << p.first << \" \" << p.second;\n return os;\n}\ntemplate <class S, class T> string to_string(pair<S, T> p) { return \"(\" + to_string(p.first) + \",\" + to_string(p.second) + \")\"; }\nstring to_string(string s) { return \"\\\"\" + s + \"\\\"\"; }\nstring to_string(char c) { return string(1, c); }\ntemplate <class T> string to_string(vector<T> s) {\n string res = \"{\";\n for(auto it = s.begin(); it != s.end(); it++) res += to_string(*it) + (next(it) == s.end() ? \"\" : \", \");\n return res + \"}\";\n}\ntemplate <class T> string to_string(set<T> s) {\n string res = \"{\";\n for(auto it = s.begin(); it != s.end(); it++) res += to_string(*it), res += (next(it) == end(s) ? \"\" : \", \");\n return res + \"}\";\n}\n\n#define endl '\\n'\n\n#ifdef _LOCAL\nvoid dump() { cerr << endl; }\ntemplate <class Head, class... Tail> void dump(Head head, Tail... tail) {\n cerr << to_string(head) << \" \";\n dump(tail...);\n}\n#undef endl\n#define debug(x) \\\n cout << #x << \": \"; \\\n dump(x)\n#else\nvoid dump() {}\ntemplate <class Head, class... Tail> void dump(Head head, Tail... tail) {}\n#define debug(x)\n#endif\ntemplate <class T> void print(const T &a) { cout << a; }\nvoid OUT() { cout << endl; }\ntemplate <class Head, class... Tail> void OUT(const Head &head, const Tail &...tail) {\n print(head);\n if(sizeof...(tail)) cout << ' ';\n OUT(tail...);\n}\n\ntemplate <typename T> static constexpr T inf = numeric_limits<T>::max() / 2;\n#define drop(s) cout << #s << endl, exit(0)\n\ntemplate <int N> struct ndFORarray {\n std::array<int, N> v;\n ndFORarray(std::array<int, N> v_) : v(v_) {}\n struct ndFORitr {\n const std::array<int, N> &v;\n std::array<int, N> tmp;\n bool is_end;\n ndFORitr(const std::array<int, N> &v_) : v(v_), tmp(), is_end(false) {}\n bool operator!=(const ndFORitr &) const { return !is_end; }\n void operator++() {\n int pos = N - 1;\n while(pos != -1) {\n tmp[pos] += 1;\n if(tmp[pos] == v[pos]) {\n tmp[pos] = 0;\n pos -= 1;\n } else {\n break;\n }\n }\n if(pos == -1) { is_end = true; }\n }\n const std::array<int, N> &operator*() const { return tmp; }\n };\n ndFORitr begin() const { return ndFORitr(v); }\n ndFORitr end() const { return ndFORitr(v); }\n};\n\nstruct ndFORvector {\n std::vector<int> v;\n ndFORvector(std::vector<int> v_) : v(v_) {}\n struct ndFORitr {\n const std::vector<int> &v;\n std::vector<int> tmp;\n bool is_end;\n ndFORitr(const std::vector<int> &v_) : v(v_), tmp(v.size(), 0), is_end(false) {}\n bool operator!=(const ndFORitr &) const { return !is_end; }\n void operator++() {\n int pos = v.size() - 1;\n while(pos != -1) {\n tmp[pos] += 1;\n if(tmp[pos] == v[pos]) {\n tmp[pos] = 0;\n pos -= 1;\n } else {\n break;\n }\n }\n if(pos == -1) { is_end = true; }\n }\n const std::vector<int> &operator*() const { return tmp; }\n };\n ndFORitr begin() const { return ndFORitr(v); }\n ndFORitr end() const { return ndFORitr(v); }\n};\n\nauto ndFOR(std::vector<int> v) { return ndFORvector(v); }\ntemplate <class... Ts> auto ndFOR(Ts... v) { return ndFORarray<std::tuple_size<std::tuple<Ts...>>::value>({v...}); }\ntemplate <class F> struct REC {\n F f;\n REC(F &&f_) : f(std::forward<F>(f_)) {}\n template <class... Args> auto operator()(Args &&...args) const { return f(*this, std::forward<Args>(args)...); }\n};\n\ntemplate <class S> vector<pair<S, int>> runLength(const vector<S> &v) {\n vector<pair<S, int>> res;\n for(auto &e : v) {\n if(res.empty() or res.back().fi != e)\n res.eb(e, 1);\n else\n res.back().se++;\n }\n return res;\n}\nvector<pair<char, int>> runLength(const string &v) {\n vector<pair<char, int>> res;\n for(auto &e : v) {\n if(res.empty() or res.back().fi != e)\n res.eb(e, 1);\n else\n res.back().se++;\n }\n return res;\n}\n\ntemplate <class T = int> struct Imos {\n int n;\n vector<T> a;\n Imos(int _n) : n(_n), a(_n + 1) {}\n void add(int l, int r, T val = 1) {\n if(l >= r) return;\n l = clamp(l, 0, n);\n r = clamp(r, 0, n + 1);\n a[l] += val;\n if(r <= n) a[r] -= val;\n }\n void build() {\n for(int i = 0; i < n; i++) a[i + 1] += a[i];\n }\n const T &operator[](int k) { return a[k]; }\n};\n\ntemplate <class T> struct RUI {\n vector<T> a;\n RUI(const vector<T> &v) : a(v.size() + 1) {\n for(int i = 0; i < v.size(); i++) a[i + 1] = a[i] + v[i];\n }\n T get(int l, int r) { return a[r] - a[l]; }\n};\n\ntemplate <class T, class F> T bin_search(T ok, T ng, const F &f) {\n while(abs(ok - ng) > 1) {\n T mid = ok + ng >> 1;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\ntemplate <class T, class F> T bin_search_double(T ok, T ng, const F &f, int iter = 80) {\n while(iter--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\nstruct Setup_io {\n Setup_io() {\n ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);\n cout << fixed << setprecision(15);\n }\n} setup_io;\n#pragma endregion\n\nint main() {\n while(1) {\n INT(n, m, r);\n if(!n) exit(0);\n VEC(int, a, n);\n VEC(int, b, m);\n rep(i, n) a[i]--;\n rep(i, m) b[i]--;\n\n struct S {\n vi v;\n vvc<int> match;\n S(vi a) : v(a) { match = vvc<int>(si(a) + 1, vi(si(a) + 1)); }\n S() = default;\n };\n\n vector<S> A, B;\n rep(i, n) {\n A.eb(a);\n rotate(begin(a), begin(a) + 1, end(a));\n }\n rep(i, m) {\n B.eb(b);\n rotate(begin(b), begin(b) + 1, end(b));\n }\n\n vector<pair<int, vi>> R;\n rep(i, r) {\n INT(k);\n VEC(int, x, k);\n rep(i, k) x[i]--;\n INT(y);\n y--;\n R.eb(y, x);\n }\n\n vv(int, DP, 30, 30);\n auto calc = [&](S &s) {\n auto &dp = s.match;\n int n = si(s.v);\n rep2(d, 1, n) {\n rep(i, n) {\n int j = i + d;\n if(j > n) break;\n if(d == 1) {\n dp[i][j] = 1 << s.v[i];\n continue;\n }\n for(auto &[y, x] : R) {\n if(dp[i][j] >> y & 1) continue;\n int k = si(x);\n rep(i, d + 1) rep(j, k + 1) DP[i][j] = 0;\n DP[0][0] = 1;\n rep(ii, d) rep(jj, k) {\n if(!DP[ii][jj]) continue;\n rep2(to, ii + 1, d) {\n int l = i + ii;\n int r = i + to;\n if(dp[l][r] >> x[jj] & 1) DP[to][jj + 1] = true;\n }\n }\n if(DP[d][k]) dp[i][j] |= 1 << y;\n }\n }\n }\n };\n each(e, A) calc(e);\n each(e, B) calc(e);\n\n int ma = -1;\n each(a, A) each(b, B) {\n rep(i, n + 1) rep(j, m + 1) DP[i][j] = -inf<int>;\n DP[0][0] = 0;\n auto &x = a.match, &y = b.match;\n rep(i, n) rep(j, m) {\n if(DP[i][j] < 0) continue;\n rep2(ii, i + 1, n) rep2(jj, j + 1, m) {\n if(x[i][ii] & y[j][jj]) chmax(DP[ii][jj], DP[i][j] + 1);\n }\n }\n chmax(ma, DP[n][m]);\n }\n OUT(ma);\n }\n}", "accuracy": 1, "time_ms": 390, "memory_kb": 3648, "score_of_the_acc": -0.0372, "final_rank": 2 }, { "submission_id": "aoj_1191_6029869", "code_snippet": "#line 1 \"other-workspace\\\\icpc\\\\f.cc\"\n#include <bits/stdc++.h>\n\nusing namespace std;\n\nvoid chgr(int &x, int y) {\n if (x < y) x = y;\n}\n\nint main() {\n constexpr auto sigma = 30;\n\n int n, m, r;\n\n while (1) {\n cin >> n >> m >> r;\n if (!n and !m and !r) break;\n\n vector<int> a(n), b(m);\n for (auto &&x : a) {\n cin >> x;\n --x;\n }\n for (auto &&x : b) {\n cin >> x;\n --x;\n }\n\n vector<vector<vector<int>>> trf(sigma);\n\n while (r--) {\n int k;\n cin >> k;\n vector<int> src;\n int dst;\n while (k--) {\n cin >> src.emplace_back();\n --src.back();\n }\n cin >> dst;\n --dst;\n trf[dst].emplace_back(src);\n }\n\n auto pre = [&](vector<int> v) {\n vector dp(v.size() + 1, vector<int>(v.size() + 1));\n\n for (auto j = 1; j <= v.size(); ++j) {\n dp[j - 1][j] = 1 << v[j - 1];\n\n for (auto i = j - 1; i--;) {\n for (auto c = 0; c < sigma; ++c) {\n // make [i, j) into c!\n auto succ = 0;\n\n for (auto &&src : trf[c]) {\n vector able(j + 1, vector<int>(src.size() + 1));\n able[i][0] = 1;\n\n for (auto l = i; l < j; l++) {\n for (auto k = 0; k < src.size(); k++) {\n if (!able[l][k]) continue;\n\n for (auto r = l + 1; r <= j; ++r) {\n if (dp[l][r] >> src[k] & 1) {\n able[r][k + 1] = 1;\n }\n }\n }\n }\n\n if (able.back().back()) {\n succ = 1;\n }\n }\n\n dp[i][j] |= succ << c;\n }\n }\n }\n\n return dp;\n };\n\n vector<vector<vector<int>>> dpa, dpb;\n\n for (auto t = 0; t < n; t++) {\n dpa.emplace_back(pre(a));\n rotate(begin(a), begin(a) + 1, end(a));\n }\n\n for (auto t = 0; t < m; t++) {\n dpb.emplace_back(pre(b));\n rotate(begin(b), begin(b) + 1, end(b));\n }\n\n auto answer = -1;\n\n for (auto &&ap : dpa) {\n for (auto &&bp : dpb) {\n vector dp(n + 1, vector(m + 1, -1));\n dp[0][0] = 0;\n\n for (auto il = 0; il < n; il++) {\n for (auto jl = 0; jl < m; jl++) {\n if (~dp[il][jl]) {\n for (auto ir = il + 1; ir <= n; ir++) {\n for (auto jr = jl + 1; jr <= m; jr++) {\n // A: [il, ir)\n // B: [jl, jr)\n if (ap[il][ir] & bp[jl][jr]) {\n chgr(dp[ir][jr], dp[il][jl] + 1);\n }\n }\n }\n }\n }\n }\n\n chgr(answer, dp[n][m]);\n }\n }\n\n cout << answer << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 3750, "memory_kb": 3608, "score_of_the_acc": -0.5198, "final_rank": 13 }, { "submission_id": "aoj_1191_6029792", "code_snippet": "#pragma region Macros\n#pragma comment(linker, \"/stack:200000000\")\n// #pragma GCC optimize(\"unroll-loops\")\n// #pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2,tune=native\")\n// #pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2\")\n// #pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\n#define ll long long\nusing ld = long double;\n#define rep2(i, a, b) for(ll i = (a); i <= (b); i++)\n#define rep3(i, a, b) for(ll i = (a); i >= (b); --i)\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define each(i, a) for(auto &&i : a)\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define pb push_back\n#define eb emplace_back\n#define vi vector<int>\n#define vll vector<ll>\n#define vpi vector<pii>\n#define vpll vector<pll>\n#define overload2(_1, _2, name, ...) name\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define VEC(type, name, size) \\\n vector<type> name(size); \\\n IN(name)\n#define VEC2(type, name1, name2, size) \\\n vector<type> name1(size), name2(size); \\\n for(int i = 0; i < size; i++) IN(name1[i], name2[i])\n#define VEC3(type, name1, name2, name3, size) \\\n vector<type> name1(size), name2(size), name3(size); \\\n for(int i = 0; i < size; i++) IN(name1[i], name2[i], name3[i])\n#define vv(type, name, h, ...) vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define VV(type, name, h, w) \\\n vector<vector<type>> name(h, vector<type>(w)); \\\n IN(name)\n#define vvv(type, name, h, w, ...) vector<vector<vector<type>>> name(h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name(a, vector<vector<vector<type>>>(b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n#define mt make_tuple\n#define fi first\n#define se second\n#define all(c) begin(c), end(c)\n#define rall(c) rbegin(c), rend(c)\n#define SORT(v) sort(all(v))\n#define REV(v) reverse(all(v))\ntemplate <class T = ll, class S> T SUM(const S &v) { return accumulate(all(v), T(0)); }\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define ub(c, x) distance((c).begin(), upper_bound(all(c), (x)))\nusing namespace std;\nconstexpr pii dx4[4] = {pii{1, 0}, pii{0, 1}, pii{-1, 0}, pii{0, -1}};\nconstexpr pii dx8[8] = {{1, 0}, {1, 1}, {0, 1}, {-1, 1}, {-1, 0}, {-1, -1}, {0, -1}, {1, -1}};\nconst string YESNO[2] = {\"NO\", \"YES\"};\nconst string YesNo[2] = {\"No\", \"Yes\"};\nconst string yesno[2] = {\"no\", \"yes\"};\nvoid YES(bool t = 1) { cout << YESNO[t] << endl; }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { cout << YesNo[t] << endl; }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { cout << yesno[t] << endl; }\nvoid no(bool t = 1) { yes(!t); }\ntemplate <class T> using vc = vector<T>;\ntemplate <class T> using vvc = vector<vc<T>>;\ntemplate <class T> using vvvc = vector<vvc<T>>;\ntemplate <class T> using vvvvc = vector<vvvc<T>>;\ntemplate <class T> using pq = priority_queue<T>;\ntemplate <class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n#define si(c) (int)(c).size()\n#define INT(...) \\\n int __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define LL(...) \\\n ll __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define STR(...) \\\n string __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define CHR(...) \\\n char __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define DBL(...) \\\n double __VA_ARGS__; \\\n IN(__VA_ARGS__)\nint scan() { return getchar(); }\nvoid scan(int &a) { cin >> a; }\nvoid scan(long long &a) { cin >> a; }\nvoid scan(char &a) { cin >> a; }\nvoid scan(double &a) { cin >> a; }\nvoid scan(string &a) { cin >> a; }\ntemplate <class T, class S> void scan(pair<T, S> &p) { scan(p.first), scan(p.second); }\ntemplate <class T> void scan(vector<T> &);\ntemplate <class T> void scan(vector<T> &a) {\n for(auto &i : a) scan(i);\n}\ntemplate <class T> void scan(T &a) { cin >> a; }\nvoid IN() {}\ntemplate <class Head, class... Tail> void IN(Head &head, Tail &...tail) {\n scan(head);\n IN(tail...);\n}\n\ntemplate <class T, class S> inline bool chmax(T &a, const S &b) { return (a < b ? a = b, 1 : 0); }\ntemplate <class T, class S> inline bool chmin(T &a, const S &b) { return (a > b ? a = b, 1 : 0); }\nvi iota(int n) {\n vi a(n);\n iota(all(a), 0);\n return a;\n}\ntemplate <typename T> vi iota(vector<T> &a, bool greater = false) {\n vi res(a.size());\n iota(all(res), 0);\n sort(all(res), [&](int i, int j) {\n if(greater) return a[i] > a[j];\n return a[i] < a[j];\n });\n return res;\n}\n#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())\n\ntemplate <class T> T ceil(T x, T y) {\n assert(y >= 1);\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\n\ntemplate <class T> T floor(T x, T y) {\n assert(y >= 1);\n return (x > 0 ? x / y : (x + y - 1) / y);\n}\ntemplate <class T> T POW(T x, int n) {\n T res = 1;\n for(; n; n >>= 1, x *= x)\n if(n & 1) res *= x;\n return res;\n}\ntemplate <class T, class S> T POW(T x, S n, const ll &mod) {\n T res = 1;\n for(; n; n >>= 1, x = x * x % mod)\n if(n & 1) res = res * x % mod;\n return res;\n}\nvector<pll> factor(ll x) {\n vector<pll> ans;\n for(ll i = 2; i * i <= x; i++)\n if(x % i == 0) {\n ans.push_back({i, 1});\n while((x /= i) % i == 0) ans.back().second++;\n }\n if(x != 1) ans.push_back({x, 1});\n return ans;\n}\ntemplate <class T> vector<T> divisor(T x) {\n vector<T> ans;\n for(T i = 1; i * i <= x; i++)\n if(x % i == 0) {\n ans.pb(i);\n if(i * i != x) ans.pb(x / i);\n }\n return ans;\n}\ntemplate <typename T> void zip(vector<T> &x) {\n vector<T> y = x;\n UNIQUE(y);\n for(int i = 0; i < x.size(); ++i) { x[i] = lb(y, x[i]); }\n}\ntemplate <class S> void fold_in(vector<S> &v) {}\ntemplate <typename Head, typename... Tail, class S> void fold_in(vector<S> &v, Head &&a, Tail &&...tail) {\n for(auto e : a) v.emplace_back(e);\n fold_in(v, tail...);\n}\ntemplate <class S> void renumber(vector<S> &v) {}\ntemplate <typename Head, typename... Tail, class S> void renumber(vector<S> &v, Head &&a, Tail &&...tail) {\n for(auto &&e : a) e = lb(v, e);\n renumber(v, tail...);\n}\ntemplate <class S, class... Args> vector<S> zip(vector<S> &head, Args &&...args) {\n vector<S> v;\n fold_in(v, head, args...);\n sort(all(v)), v.erase(unique(all(v)), v.end());\n renumber(v, head, args...);\n return v;\n}\n\n// x in [l, r)\ntemplate <class T, class S> bool inc(const T &x, const S &l, const S &r) { return l <= x and x < r; }\n// (a, b) in [lx, rx) * [ly, ry)\ntemplate <class T, class S> bool inc(const pair<T, T> &x, const S &lx, const S &ly, const S &rx, const S &ry) { return inc(x.fi, lx, rx) && inc(x.se, ly, ry); }\n\nconstexpr ll ten(int n) { return n == 0 ? 1 : ten(n - 1) * 10; }\n// bit 演算系\nll pow2(int i) { return 1LL << i; }\nint topbit(signed t) { return t == 0 ? -1 : 31 - __builtin_clz(t); }\nint topbit(ll t) { return t == 0 ? -1 : 63 - __builtin_clzll(t); }\nint lowbit(signed a) { return a == 0 ? 32 : __builtin_ctz(a); }\nint lowbit(ll a) { return a == 0 ? 64 : __builtin_ctzll(a); }\n// int allbit(int n) { return (1 << n) - 1; }\nconstexpr ll allbit(int n) { return (1LL << n) - 1; }\n// int popcount(signed t) { return __builtin_popcount(t); }\n// int popcount(ll t) { return __builtin_popcountll(t); }\nint popcount(uint64_t t) { return __builtin_popcountll(t); }\nbool ispow2(int i) { return i && (i & -i) == i; }\n\nll rnd(ll l, ll r) { //[l, r)\n#ifdef _LOCAL\n static mt19937_64 gen;\n#else\n static mt19937_64 gen(chrono::steady_clock::now().time_since_epoch().count());\n#endif\n return uniform_int_distribution<ll>(l, r - 1)(gen);\n}\nll rnd(ll n) { return rnd(0, n); }\n\ntemplate <class t> void random_shuffle(vc<t> &a) { rep(i, si(a)) swap(a[i], a[rnd(0, i + 1)]); }\n\nint in() {\n int x;\n cin >> x;\n return x;\n}\nll lin() {\n unsigned long long x;\n cin >> x;\n return x;\n}\n\ntemplate <class T, class S> pair<T, S> operator-(const pair<T, S> &x, const pair<T, S> &y) { return pair<T, S>(x.fi - y.fi, x.se - y.se); }\ntemplate <class T, class S> pair<T, S> operator+(const pair<T, S> &x, const pair<T, S> &y) { return pair<T, S>(x.fi + y.fi, x.se + y.se); }\ntemplate <class T> pair<T, T> operator&(const pair<T, T> &l, const pair<T, T> &r) { return pair<T, T>(max(l.fi, r.fi), min(l.se, r.se)); }\ntemplate <class T, class S> pair<T, S> operator+=(pair<T, S> &l, const pair<T, S> &r) { return l = l + r; }\ntemplate <class T, class S> pair<T, S> operator-=(pair<T, S> &l, const pair<T, S> &r) { return l = l - r; }\ntemplate <class T> bool intersect(const pair<T, T> &l, const pair<T, T> &r) { return (l.se < r.se ? r.fi < l.se : l.fi < r.se); }\n\ntemplate <class T> ll operator*(const pair<T, T> &x, const pair<T, T> &y) { return (ll)x.fi * y.fi + (ll)x.se * y.se; }\n\ntemplate <typename T> struct edge {\n int from, to;\n T cost;\n int id;\n edge(int to, T cost) : from(-1), to(to), cost(cost) {}\n edge(int from, int to, T cost) : from(from), to(to), cost(cost) {}\n edge(int from, int to, T cost, int id) : from(from), to(to), cost(cost), id(id) {}\n constexpr bool operator<(const edge<T> &rhs) const noexcept { return cost < rhs.cost; }\n edge &operator=(const int &x) {\n to = x;\n return *this;\n }\n operator int() const { return to; }\n};\ntemplate <typename T> using Edges = vector<edge<T>>;\n\nusing Tree = vector<vector<int>>;\nusing Graph = vector<vector<int>>;\ntemplate <class T> using Wgraph = vector<vector<edge<T>>>;\nGraph getG(int n, int m = -1, bool directed = false, int margin = 1) {\n Tree res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n cin >> a >> b;\n a -= margin, b -= margin;\n res[a].emplace_back(b);\n if(!directed) res[b].emplace_back(a);\n }\n return res;\n}\nGraph getTreeFromPar(int n, int margin = 1) {\n Graph res(n);\n for(int i = 1; i < n; i++) {\n int a;\n cin >> a;\n res[a - margin].emplace_back(i);\n }\n return res;\n}\ntemplate <class T> Wgraph<T> getWg(int n, int m = -1, bool directed = false, int margin = 1) {\n Wgraph<T> res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n T c;\n cin >> a >> b >> c;\n a -= margin, b -= margin;\n res[a].emplace_back(b, c);\n if(!directed) res[b].emplace_back(a, c);\n }\n return res;\n}\nvoid add(Graph &G, int x, int y) { G[x].eb(y), G[y].eb(x); }\ntemplate <class S, class T> void add(Wgraph<S> &G, int x, int y, T c) { G[x].eb(y, c), G[y].eb(x, c); }\n\n#define i128 __int128_t\n#define ull unsigned long long int\n#define TEST \\\n INT(testcases); \\\n while(testcases--)\ntemplate <class T> ostream &operator<<(ostream &os, const vector<T> &v) {\n for(auto it = begin(v); it != end(v); ++it) {\n if(it == begin(v))\n os << *it;\n else\n os << \" \" << *it;\n }\n return os;\n}\ntemplate <class T, class S> ostream &operator<<(ostream &os, const pair<T, S> &p) {\n os << p.first << \" \" << p.second;\n return os;\n}\ntemplate <class S, class T> string to_string(pair<S, T> p) { return \"(\" + to_string(p.first) + \",\" + to_string(p.second) + \")\"; }\nstring to_string(string s) { return \"\\\"\" + s + \"\\\"\"; }\nstring to_string(char c) { return string(1, c); }\ntemplate <class T> string to_string(vector<T> s) {\n string res = \"{\";\n for(auto it = s.begin(); it != s.end(); it++) res += to_string(*it) + (next(it) == s.end() ? \"\" : \", \");\n return res + \"}\";\n}\ntemplate <class T> string to_string(set<T> s) {\n string res = \"{\";\n for(auto it = s.begin(); it != s.end(); it++) res += to_string(*it), res += (next(it) == end(s) ? \"\" : \", \");\n return res + \"}\";\n}\n\n#define endl '\\n'\n\n#ifdef _LOCAL\nvoid dump() { cerr << endl; }\ntemplate <class Head, class... Tail> void dump(Head head, Tail... tail) {\n cerr << to_string(head) << \" \";\n dump(tail...);\n}\n#undef endl\n#define debug(x) \\\n cout << #x << \": \"; \\\n dump(x)\n#else\nvoid dump() {}\ntemplate <class Head, class... Tail> void dump(Head head, Tail... tail) {}\n#define debug(x)\n#endif\ntemplate <class T> void print(const T &a) { cout << a; }\nvoid OUT() { cout << endl; }\ntemplate <class Head, class... Tail> void OUT(const Head &head, const Tail &...tail) {\n print(head);\n if(sizeof...(tail)) cout << ' ';\n OUT(tail...);\n}\n\ntemplate <typename T> static constexpr T inf = numeric_limits<T>::max() / 2;\n#define drop(s) cout << #s << endl, exit(0)\n\ntemplate <int N> struct ndFORarray {\n std::array<int, N> v;\n ndFORarray(std::array<int, N> v_) : v(v_) {}\n struct ndFORitr {\n const std::array<int, N> &v;\n std::array<int, N> tmp;\n bool is_end;\n ndFORitr(const std::array<int, N> &v_) : v(v_), tmp(), is_end(false) {}\n bool operator!=(const ndFORitr &) const { return !is_end; }\n void operator++() {\n int pos = N - 1;\n while(pos != -1) {\n tmp[pos] += 1;\n if(tmp[pos] == v[pos]) {\n tmp[pos] = 0;\n pos -= 1;\n } else {\n break;\n }\n }\n if(pos == -1) { is_end = true; }\n }\n const std::array<int, N> &operator*() const { return tmp; }\n };\n ndFORitr begin() const { return ndFORitr(v); }\n ndFORitr end() const { return ndFORitr(v); }\n};\n\nstruct ndFORvector {\n std::vector<int> v;\n ndFORvector(std::vector<int> v_) : v(v_) {}\n struct ndFORitr {\n const std::vector<int> &v;\n std::vector<int> tmp;\n bool is_end;\n ndFORitr(const std::vector<int> &v_) : v(v_), tmp(v.size(), 0), is_end(false) {}\n bool operator!=(const ndFORitr &) const { return !is_end; }\n void operator++() {\n int pos = v.size() - 1;\n while(pos != -1) {\n tmp[pos] += 1;\n if(tmp[pos] == v[pos]) {\n tmp[pos] = 0;\n pos -= 1;\n } else {\n break;\n }\n }\n if(pos == -1) { is_end = true; }\n }\n const std::vector<int> &operator*() const { return tmp; }\n };\n ndFORitr begin() const { return ndFORitr(v); }\n ndFORitr end() const { return ndFORitr(v); }\n};\n\nauto ndFOR(std::vector<int> v) { return ndFORvector(v); }\ntemplate <class... Ts> auto ndFOR(Ts... v) { return ndFORarray<std::tuple_size<std::tuple<Ts...>>::value>({v...}); }\ntemplate <class F> struct REC {\n F f;\n REC(F &&f_) : f(std::forward<F>(f_)) {}\n template <class... Args> auto operator()(Args &&...args) const { return f(*this, std::forward<Args>(args)...); }\n};\n\ntemplate <class S> vector<pair<S, int>> runLength(const vector<S> &v) {\n vector<pair<S, int>> res;\n for(auto &e : v) {\n if(res.empty() or res.back().fi != e)\n res.eb(e, 1);\n else\n res.back().se++;\n }\n return res;\n}\nvector<pair<char, int>> runLength(const string &v) {\n vector<pair<char, int>> res;\n for(auto &e : v) {\n if(res.empty() or res.back().fi != e)\n res.eb(e, 1);\n else\n res.back().se++;\n }\n return res;\n}\n\ntemplate <class T = int> struct Imos {\n int n;\n vector<T> a;\n Imos(int _n) : n(_n), a(_n + 1) {}\n void add(int l, int r, T val = 1) {\n if(l >= r) return;\n l = clamp(l, 0, n);\n r = clamp(r, 0, n + 1);\n a[l] += val;\n if(r <= n) a[r] -= val;\n }\n void build() {\n for(int i = 0; i < n; i++) a[i + 1] += a[i];\n }\n const T &operator[](int k) { return a[k]; }\n};\n\ntemplate <class T> struct RUI {\n vector<T> a;\n RUI(const vector<T> &v) : a(v.size() + 1) {\n for(int i = 0; i < v.size(); i++) a[i + 1] = a[i] + v[i];\n }\n T get(int l, int r) { return a[r] - a[l]; }\n};\n\ntemplate <class T, class F> T bin_search(T ok, T ng, const F &f) {\n while(abs(ok - ng) > 1) {\n T mid = ok + ng >> 1;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\ntemplate <class T, class F> T bin_search_double(T ok, T ng, const F &f, int iter = 80) {\n while(iter--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\nstruct Setup_io {\n Setup_io() {\n ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);\n cout << fixed << setprecision(15);\n }\n} setup_io;\n#pragma endregion\n\nint main() {\n while(1) {\n INT(n, m, r);\n if(!n) exit(0);\n VEC(int, a, n);\n VEC(int, b, m);\n rep(i, n) a[i]--;\n rep(i, m) b[i]--;\n\n struct S {\n vi v;\n vvc<int> match;\n S(vi a) : v(a) { match = vvc<int>(si(a) + 1, vi(si(a) + 1)); }\n S() = default;\n };\n\n vector<S> A, B;\n rep(i, n) {\n A.eb(a);\n rotate(begin(a), begin(a) + 1, end(a));\n }\n rep(i, m) {\n B.eb(b);\n rotate(begin(b), begin(b) + 1, end(b));\n }\n\n vector<pair<int, vi>> R;\n rep(i, r) {\n INT(k);\n VEC(int, x, k);\n rep(i, k) x[i]--;\n INT(y);\n y--;\n R.eb(y, x);\n }\n\n vv(int, DP, 30, 30);\n auto calc = [&](S &s) {\n auto &dp = s.match;\n int n = si(s.v);\n rep2(d, 1, n) {\n rep(i, n) {\n int j = i + d;\n if(j > n) break;\n if(d == 1) {\n dp[i][j] = 1 << s.v[i];\n continue;\n }\n for(auto &[y, x] : R) {\n if(dp[i][j] >> y & 1) continue;\n int k = si(x);\n rep(i, d + 1) rep(j, k + 1) DP[i][j] = 0;\n DP[0][0] = 1;\n rep(ii, d) rep(jj, k) {\n if(!DP[ii][jj]) continue;\n rep2(to, ii + 1, d) {\n int l = i + ii;\n int r = i + to;\n if(dp[l][r] >> x[jj] & 1) DP[to][jj + 1] = true;\n }\n }\n if(DP[d][k]) dp[i][j] |= 1 << y;\n }\n }\n }\n };\n each(e, A) calc(e);\n each(e, B) calc(e);\n\n int ma = -1;\n each(a, A) each(b, B) {\n rep(i, n + 1) rep(j, m + 1) DP[i][j] = -inf<int>;\n DP[0][0] = 0;\n auto &x = a.match, &y = b.match;\n rep(i, n) rep(j, m) {\n if(DP[i][j] < 0) continue;\n rep2(ii, i + 1, n) rep2(jj, j + 1, m) {\n if(x[i][ii] & y[j][jj]) chmax(DP[ii][jj], DP[i][j] + 1);\n }\n }\n chmax(ma, DP[n][m]);\n }\n OUT(ma);\n }\n}", "accuracy": 1, "time_ms": 390, "memory_kb": 3596, "score_of_the_acc": -0.0352, "final_rank": 1 }, { "submission_id": "aoj_1191_6029771", "code_snippet": "#pragma region Macros\n#pragma comment(linker, \"/stack:200000000\")\n// #pragma GCC optimize(\"unroll-loops\")\n// #pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2,tune=native\")\n// #pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2\")\n// #pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\n#define ll long long\nusing ld = long double;\n#define rep2(i, a, b) for(ll i = (a); i <= (b); i++)\n#define rep3(i, a, b) for(ll i = (a); i >= (b); --i)\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define each(i, a) for(auto &&i : a)\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define pb push_back\n#define eb emplace_back\n#define vi vector<int>\n#define vll vector<ll>\n#define vpi vector<pii>\n#define vpll vector<pll>\n#define overload2(_1, _2, name, ...) name\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define VEC(type, name, size) \\\n vector<type> name(size); \\\n IN(name)\n#define VEC2(type, name1, name2, size) \\\n vector<type> name1(size), name2(size); \\\n for(int i = 0; i < size; i++) IN(name1[i], name2[i])\n#define VEC3(type, name1, name2, name3, size) \\\n vector<type> name1(size), name2(size), name3(size); \\\n for(int i = 0; i < size; i++) IN(name1[i], name2[i], name3[i])\n#define vv(type, name, h, ...) vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define VV(type, name, h, w) \\\n vector<vector<type>> name(h, vector<type>(w)); \\\n IN(name)\n#define vvv(type, name, h, w, ...) vector<vector<vector<type>>> name(h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name(a, vector<vector<vector<type>>>(b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n#define mt make_tuple\n#define fi first\n#define se second\n#define all(c) begin(c), end(c)\n#define rall(c) rbegin(c), rend(c)\n#define SORT(v) sort(all(v))\n#define REV(v) reverse(all(v))\ntemplate <class T = ll, class S> T SUM(const S &v) { return accumulate(all(v), T(0)); }\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define ub(c, x) distance((c).begin(), upper_bound(all(c), (x)))\nusing namespace std;\nconstexpr pii dx4[4] = {pii{1, 0}, pii{0, 1}, pii{-1, 0}, pii{0, -1}};\nconstexpr pii dx8[8] = {{1, 0}, {1, 1}, {0, 1}, {-1, 1}, {-1, 0}, {-1, -1}, {0, -1}, {1, -1}};\nconst string YESNO[2] = {\"NO\", \"YES\"};\nconst string YesNo[2] = {\"No\", \"Yes\"};\nconst string yesno[2] = {\"no\", \"yes\"};\nvoid YES(bool t = 1) { cout << YESNO[t] << endl; }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { cout << YesNo[t] << endl; }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { cout << yesno[t] << endl; }\nvoid no(bool t = 1) { yes(!t); }\ntemplate <class T> using vc = vector<T>;\ntemplate <class T> using vvc = vector<vc<T>>;\ntemplate <class T> using vvvc = vector<vvc<T>>;\ntemplate <class T> using vvvvc = vector<vvvc<T>>;\ntemplate <class T> using pq = priority_queue<T>;\ntemplate <class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n#define si(c) (int)(c).size()\n#define INT(...) \\\n int __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define LL(...) \\\n ll __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define STR(...) \\\n string __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define CHR(...) \\\n char __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define DBL(...) \\\n double __VA_ARGS__; \\\n IN(__VA_ARGS__)\nint scan() { return getchar(); }\nvoid scan(int &a) { cin >> a; }\nvoid scan(long long &a) { cin >> a; }\nvoid scan(char &a) { cin >> a; }\nvoid scan(double &a) { cin >> a; }\nvoid scan(string &a) { cin >> a; }\ntemplate <class T, class S> void scan(pair<T, S> &p) { scan(p.first), scan(p.second); }\ntemplate <class T> void scan(vector<T> &);\ntemplate <class T> void scan(vector<T> &a) {\n for(auto &i : a) scan(i);\n}\ntemplate <class T> void scan(T &a) { cin >> a; }\nvoid IN() {}\ntemplate <class Head, class... Tail> void IN(Head &head, Tail &...tail) {\n scan(head);\n IN(tail...);\n}\n\ntemplate <class T, class S> inline bool chmax(T &a, const S &b) { return (a < b ? a = b, 1 : 0); }\ntemplate <class T, class S> inline bool chmin(T &a, const S &b) { return (a > b ? a = b, 1 : 0); }\nvi iota(int n) {\n vi a(n);\n iota(all(a), 0);\n return a;\n}\ntemplate <typename T> vi iota(vector<T> &a, bool greater = false) {\n vi res(a.size());\n iota(all(res), 0);\n sort(all(res), [&](int i, int j) {\n if(greater) return a[i] > a[j];\n return a[i] < a[j];\n });\n return res;\n}\n#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())\n\ntemplate <class T> T ceil(T x, T y) {\n assert(y >= 1);\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\n\ntemplate <class T> T floor(T x, T y) {\n assert(y >= 1);\n return (x > 0 ? x / y : (x + y - 1) / y);\n}\ntemplate <class T> T POW(T x, int n) {\n T res = 1;\n for(; n; n >>= 1, x *= x)\n if(n & 1) res *= x;\n return res;\n}\ntemplate <class T, class S> T POW(T x, S n, const ll &mod) {\n T res = 1;\n for(; n; n >>= 1, x = x * x % mod)\n if(n & 1) res = res * x % mod;\n return res;\n}\nvector<pll> factor(ll x) {\n vector<pll> ans;\n for(ll i = 2; i * i <= x; i++)\n if(x % i == 0) {\n ans.push_back({i, 1});\n while((x /= i) % i == 0) ans.back().second++;\n }\n if(x != 1) ans.push_back({x, 1});\n return ans;\n}\ntemplate <class T> vector<T> divisor(T x) {\n vector<T> ans;\n for(T i = 1; i * i <= x; i++)\n if(x % i == 0) {\n ans.pb(i);\n if(i * i != x) ans.pb(x / i);\n }\n return ans;\n}\ntemplate <typename T> void zip(vector<T> &x) {\n vector<T> y = x;\n UNIQUE(y);\n for(int i = 0; i < x.size(); ++i) { x[i] = lb(y, x[i]); }\n}\ntemplate <class S> void fold_in(vector<S> &v) {}\ntemplate <typename Head, typename... Tail, class S> void fold_in(vector<S> &v, Head &&a, Tail &&...tail) {\n for(auto e : a) v.emplace_back(e);\n fold_in(v, tail...);\n}\ntemplate <class S> void renumber(vector<S> &v) {}\ntemplate <typename Head, typename... Tail, class S> void renumber(vector<S> &v, Head &&a, Tail &&...tail) {\n for(auto &&e : a) e = lb(v, e);\n renumber(v, tail...);\n}\ntemplate <class S, class... Args> vector<S> zip(vector<S> &head, Args &&...args) {\n vector<S> v;\n fold_in(v, head, args...);\n sort(all(v)), v.erase(unique(all(v)), v.end());\n renumber(v, head, args...);\n return v;\n}\n\n// x in [l, r)\ntemplate <class T, class S> bool inc(const T &x, const S &l, const S &r) { return l <= x and x < r; }\n// (a, b) in [lx, rx) * [ly, ry)\ntemplate <class T, class S> bool inc(const pair<T, T> &x, const S &lx, const S &ly, const S &rx, const S &ry) { return inc(x.fi, lx, rx) && inc(x.se, ly, ry); }\n\nconstexpr ll ten(int n) { return n == 0 ? 1 : ten(n - 1) * 10; }\n// bit 演算系\nll pow2(int i) { return 1LL << i; }\nint topbit(signed t) { return t == 0 ? -1 : 31 - __builtin_clz(t); }\nint topbit(ll t) { return t == 0 ? -1 : 63 - __builtin_clzll(t); }\nint lowbit(signed a) { return a == 0 ? 32 : __builtin_ctz(a); }\nint lowbit(ll a) { return a == 0 ? 64 : __builtin_ctzll(a); }\n// int allbit(int n) { return (1 << n) - 1; }\nconstexpr ll allbit(int n) { return (1LL << n) - 1; }\n// int popcount(signed t) { return __builtin_popcount(t); }\n// int popcount(ll t) { return __builtin_popcountll(t); }\nint popcount(uint64_t t) { return __builtin_popcountll(t); }\nbool ispow2(int i) { return i && (i & -i) == i; }\n\nll rnd(ll l, ll r) { //[l, r)\n#ifdef _LOCAL\n static mt19937_64 gen;\n#else\n static mt19937_64 gen(chrono::steady_clock::now().time_since_epoch().count());\n#endif\n return uniform_int_distribution<ll>(l, r - 1)(gen);\n}\nll rnd(ll n) { return rnd(0, n); }\n\ntemplate <class t> void random_shuffle(vc<t> &a) { rep(i, si(a)) swap(a[i], a[rnd(0, i + 1)]); }\n\nint in() {\n int x;\n cin >> x;\n return x;\n}\nll lin() {\n unsigned long long x;\n cin >> x;\n return x;\n}\n\ntemplate <class T, class S> pair<T, S> operator-(const pair<T, S> &x, const pair<T, S> &y) { return pair<T, S>(x.fi - y.fi, x.se - y.se); }\ntemplate <class T, class S> pair<T, S> operator+(const pair<T, S> &x, const pair<T, S> &y) { return pair<T, S>(x.fi + y.fi, x.se + y.se); }\ntemplate <class T> pair<T, T> operator&(const pair<T, T> &l, const pair<T, T> &r) { return pair<T, T>(max(l.fi, r.fi), min(l.se, r.se)); }\ntemplate <class T, class S> pair<T, S> operator+=(pair<T, S> &l, const pair<T, S> &r) { return l = l + r; }\ntemplate <class T, class S> pair<T, S> operator-=(pair<T, S> &l, const pair<T, S> &r) { return l = l - r; }\ntemplate <class T> bool intersect(const pair<T, T> &l, const pair<T, T> &r) { return (l.se < r.se ? r.fi < l.se : l.fi < r.se); }\n\ntemplate <class T> ll operator*(const pair<T, T> &x, const pair<T, T> &y) { return (ll)x.fi * y.fi + (ll)x.se * y.se; }\n\ntemplate <typename T> struct edge {\n int from, to;\n T cost;\n int id;\n edge(int to, T cost) : from(-1), to(to), cost(cost) {}\n edge(int from, int to, T cost) : from(from), to(to), cost(cost) {}\n edge(int from, int to, T cost, int id) : from(from), to(to), cost(cost), id(id) {}\n constexpr bool operator<(const edge<T> &rhs) const noexcept { return cost < rhs.cost; }\n edge &operator=(const int &x) {\n to = x;\n return *this;\n }\n operator int() const { return to; }\n};\ntemplate <typename T> using Edges = vector<edge<T>>;\n\nusing Tree = vector<vector<int>>;\nusing Graph = vector<vector<int>>;\ntemplate <class T> using Wgraph = vector<vector<edge<T>>>;\nGraph getG(int n, int m = -1, bool directed = false, int margin = 1) {\n Tree res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n cin >> a >> b;\n a -= margin, b -= margin;\n res[a].emplace_back(b);\n if(!directed) res[b].emplace_back(a);\n }\n return res;\n}\nGraph getTreeFromPar(int n, int margin = 1) {\n Graph res(n);\n for(int i = 1; i < n; i++) {\n int a;\n cin >> a;\n res[a - margin].emplace_back(i);\n }\n return res;\n}\ntemplate <class T> Wgraph<T> getWg(int n, int m = -1, bool directed = false, int margin = 1) {\n Wgraph<T> res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n T c;\n cin >> a >> b >> c;\n a -= margin, b -= margin;\n res[a].emplace_back(b, c);\n if(!directed) res[b].emplace_back(a, c);\n }\n return res;\n}\nvoid add(Graph &G, int x, int y) { G[x].eb(y), G[y].eb(x); }\ntemplate <class S, class T> void add(Wgraph<S> &G, int x, int y, T c) { G[x].eb(y, c), G[y].eb(x, c); }\n\n#define i128 __int128_t\n#define ull unsigned long long int\n#define TEST \\\n INT(testcases); \\\n while(testcases--)\ntemplate <class T> ostream &operator<<(ostream &os, const vector<T> &v) {\n for(auto it = begin(v); it != end(v); ++it) {\n if(it == begin(v))\n os << *it;\n else\n os << \" \" << *it;\n }\n return os;\n}\ntemplate <class T, class S> ostream &operator<<(ostream &os, const pair<T, S> &p) {\n os << p.first << \" \" << p.second;\n return os;\n}\ntemplate <class S, class T> string to_string(pair<S, T> p) { return \"(\" + to_string(p.first) + \",\" + to_string(p.second) + \")\"; }\nstring to_string(string s) { return \"\\\"\" + s + \"\\\"\"; }\nstring to_string(char c) { return string(1, c); }\ntemplate <class T> string to_string(vector<T> s) {\n string res = \"{\";\n for(auto it = s.begin(); it != s.end(); it++) res += to_string(*it) + (next(it) == s.end() ? \"\" : \", \");\n return res + \"}\";\n}\ntemplate <class T> string to_string(set<T> s) {\n string res = \"{\";\n for(auto it = s.begin(); it != s.end(); it++) res += to_string(*it), res += (next(it) == end(s) ? \"\" : \", \");\n return res + \"}\";\n}\n\n#define endl '\\n'\n\n#ifdef _LOCAL\nvoid dump() { cerr << endl; }\ntemplate <class Head, class... Tail> void dump(Head head, Tail... tail) {\n cerr << to_string(head) << \" \";\n dump(tail...);\n}\n#undef endl\n#define debug(x) \\\n cout << #x << \": \"; \\\n dump(x)\n#else\nvoid dump() {}\ntemplate <class Head, class... Tail> void dump(Head head, Tail... tail) {}\n#define debug(x)\n#endif\ntemplate <class T> void print(const T &a) { cout << a; }\nvoid OUT() { cout << endl; }\ntemplate <class Head, class... Tail> void OUT(const Head &head, const Tail &...tail) {\n print(head);\n if(sizeof...(tail)) cout << ' ';\n OUT(tail...);\n}\n\ntemplate <typename T> static constexpr T inf = numeric_limits<T>::max() / 2;\n#define drop(s) cout << #s << endl, exit(0)\n\ntemplate <int N> struct ndFORarray {\n std::array<int, N> v;\n ndFORarray(std::array<int, N> v_) : v(v_) {}\n struct ndFORitr {\n const std::array<int, N> &v;\n std::array<int, N> tmp;\n bool is_end;\n ndFORitr(const std::array<int, N> &v_) : v(v_), tmp(), is_end(false) {}\n bool operator!=(const ndFORitr &) const { return !is_end; }\n void operator++() {\n int pos = N - 1;\n while(pos != -1) {\n tmp[pos] += 1;\n if(tmp[pos] == v[pos]) {\n tmp[pos] = 0;\n pos -= 1;\n } else {\n break;\n }\n }\n if(pos == -1) { is_end = true; }\n }\n const std::array<int, N> &operator*() const { return tmp; }\n };\n ndFORitr begin() const { return ndFORitr(v); }\n ndFORitr end() const { return ndFORitr(v); }\n};\n\nstruct ndFORvector {\n std::vector<int> v;\n ndFORvector(std::vector<int> v_) : v(v_) {}\n struct ndFORitr {\n const std::vector<int> &v;\n std::vector<int> tmp;\n bool is_end;\n ndFORitr(const std::vector<int> &v_) : v(v_), tmp(v.size(), 0), is_end(false) {}\n bool operator!=(const ndFORitr &) const { return !is_end; }\n void operator++() {\n int pos = v.size() - 1;\n while(pos != -1) {\n tmp[pos] += 1;\n if(tmp[pos] == v[pos]) {\n tmp[pos] = 0;\n pos -= 1;\n } else {\n break;\n }\n }\n if(pos == -1) { is_end = true; }\n }\n const std::vector<int> &operator*() const { return tmp; }\n };\n ndFORitr begin() const { return ndFORitr(v); }\n ndFORitr end() const { return ndFORitr(v); }\n};\n\nauto ndFOR(std::vector<int> v) { return ndFORvector(v); }\ntemplate <class... Ts> auto ndFOR(Ts... v) { return ndFORarray<std::tuple_size<std::tuple<Ts...>>::value>({v...}); }\ntemplate <class F> struct REC {\n F f;\n REC(F &&f_) : f(std::forward<F>(f_)) {}\n template <class... Args> auto operator()(Args &&...args) const { return f(*this, std::forward<Args>(args)...); }\n};\n\ntemplate <class S> vector<pair<S, int>> runLength(const vector<S> &v) {\n vector<pair<S, int>> res;\n for(auto &e : v) {\n if(res.empty() or res.back().fi != e)\n res.eb(e, 1);\n else\n res.back().se++;\n }\n return res;\n}\nvector<pair<char, int>> runLength(const string &v) {\n vector<pair<char, int>> res;\n for(auto &e : v) {\n if(res.empty() or res.back().fi != e)\n res.eb(e, 1);\n else\n res.back().se++;\n }\n return res;\n}\n\ntemplate <class T = int> struct Imos {\n int n;\n vector<T> a;\n Imos(int _n) : n(_n), a(_n + 1) {}\n void add(int l, int r, T val = 1) {\n if(l >= r) return;\n l = clamp(l, 0, n);\n r = clamp(r, 0, n + 1);\n a[l] += val;\n if(r <= n) a[r] -= val;\n }\n void build() {\n for(int i = 0; i < n; i++) a[i + 1] += a[i];\n }\n const T &operator[](int k) { return a[k]; }\n};\n\ntemplate <class T> struct RUI {\n vector<T> a;\n RUI(const vector<T> &v) : a(v.size() + 1) {\n for(int i = 0; i < v.size(); i++) a[i + 1] = a[i] + v[i];\n }\n T get(int l, int r) { return a[r] - a[l]; }\n};\n\ntemplate <class T, class F> T bin_search(T ok, T ng, const F &f) {\n while(abs(ok - ng) > 1) {\n T mid = ok + ng >> 1;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\ntemplate <class T, class F> T bin_search_double(T ok, T ng, const F &f, int iter = 80) {\n while(iter--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\nstruct Setup_io {\n Setup_io() {\n ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);\n cout << fixed << setprecision(15);\n }\n} setup_io;\n#pragma endregion\n\nint main() {\n while(1) {\n INT(n, m, r);\n if(!n) exit(0);\n VEC(int, a, n);\n VEC(int, b, m);\n rep(i, n) a[i]--;\n rep(i, m) b[i]--;\n\n struct S {\n vi v;\n vvc<int> match;\n S(vi a) : v(a) { match = vvc<int>(si(a) + 1, vi(si(a) + 1)); }\n S() = default;\n };\n\n vector<S> A, B;\n rep(i, n) {\n A.eb(a);\n rotate(begin(a), begin(a) + 1, end(a));\n }\n rep(i, n) {\n B.eb(b);\n rotate(begin(b), begin(b) + 1, end(b));\n }\n\n vector<pair<int, vi>> R;\n rep(i, r) {\n INT(k);\n VEC(int, x, k);\n rep(i, k) x[i]--;\n INT(y);\n y--;\n R.eb(y, x);\n }\n\n vv(int, DP, 30, 30);\n auto calc = [&](S &s) {\n auto &dp = s.match;\n int n = si(s.v);\n rep2(d, 1, n) {\n rep(i, n) {\n int j = i + d;\n if(j > n) break;\n if(d == 1) {\n dp[i][j] = 1 << s.v[i];\n continue;\n }\n for(auto &[y, x] : R) {\n if(dp[i][j] >> y & 1) continue;\n int k = si(x);\n rep(i, d + 1) rep(j, k + 1) DP[i][j] = 0;\n DP[0][0] = 1;\n rep(ii, d) rep(jj, k) {\n if(!DP[ii][jj]) continue;\n rep2(to, ii + 1, d) {\n int l = i + ii;\n int r = i + to;\n if(dp[l][r] >> x[jj] & 1) DP[to][jj + 1] = true;\n }\n }\n if(DP[d][k]) dp[i][j] |= 1 << y;\n }\n }\n }\n };\n each(e, A) calc(e);\n each(e, B) calc(e);\n\n int ma = -1;\n each(a, A) each(b, B) {\n rep(i, n + 1) rep(j, m + 1) DP[i][j] = -inf<int>;\n DP[0][0] = 0;\n auto &x = a.match, &y = b.match;\n rep(i, n) rep(j, m) {\n if(DP[i][j] < 0) continue;\n rep2(ii, i + 1, n) rep2(jj, j + 1, m) {\n if(x[i][ii] & y[j][jj]) chmax(DP[ii][jj], DP[i][j] + 1);\n }\n }\n chmax(ma, DP[n][m]);\n }\n OUT(ma);\n }\n}", "accuracy": 0.5, "time_ms": 390, "memory_kb": 3720, "score_of_the_acc": -0.0401, "final_rank": 20 }, { "submission_id": "aoj_1191_6029063", "code_snippet": "//#pragma GCC optimize(\"O3\")\n//#pragma GCC optimize(\"unroll-loops\")\n#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<ciso646>\n#include<random>\n#include<map>\n#include<set>\n#include<bitset>\n#include<stack>\n#include<unordered_map>\n#include<unordered_set>\n#include<utility>\n#include<cassert>\n#include<complex>\n#include<numeric>\n#include<array>\nusing namespace std;\n\n//#define int long long\ntypedef long long ll;\n\ntypedef unsigned long long ul;\ntypedef unsigned int ui;\nconst ll mod = 1000000007;\nconst ll INF = mod * mod;\ntypedef pair<int, int>P;\n\n#define rep(i,n) for(int i=0;i<n;i++)\n#define per(i,n) for(int i=n-1;i>=0;i--)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define per1(i,n) for(int i=n;i>=1;i--)\n#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)\n#define all(v) (v).begin(),(v).end()\ntypedef pair<ll, ll> LP;\ntypedef long double ld;\ntypedef pair<ld, ld> LDP;\nconst ld eps = 1e-8;\nconst ld pi = acosl(-1.0);\n\nll mod_pow(ll x, ll n, ll m = mod) {\n\tif (n < 0) {\n\t\tll res = mod_pow(x, -n, m);\n\t\treturn mod_pow(res, m - 2, m);\n\t}\n\tif (abs(x) >= m)x %= m;\n\tif (x < 0)x += m;\n\tll res = 1;\n\twhile (n) {\n\t\tif (n & 1)res = res * x % m;\n\t\tx = x * x % m; n >>= 1;\n\t}\n\treturn res;\n}\nstruct modint {\n\tll n;\n\tmodint() :n(0) { ; }\n\tmodint(ll m) :n(m) {\n\t\tif (n >= mod)n %= mod;\n\t\telse if (n < 0)n = (n % mod + mod) % mod;\n\t}\n\toperator int() { return n; }\n};\nbool operator==(modint a, modint b) { return a.n == b.n; }\nmodint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }\nmodint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }\nmodint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }\nmodint operator+(modint a, modint b) { return a += b; }\nmodint operator-(modint a, modint b) { return a -= b; }\nmodint operator*(modint a, modint b) { return a *= b; }\nmodint operator^(modint a, ll n) {\n\tif (n == 0)return modint(1);\n\tmodint res = (a * a) ^ (n / 2);\n\tif (n % 2)res = res * a;\n\treturn res;\n}\n\nll inv(ll a, ll p) {\n\treturn (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);\n}\nmodint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }\nmodint operator/=(modint& a, modint b) { a = a / b; return a; }\nconst int max_n = 1 << 20;\nmodint fact[max_n], factinv[max_n];\nvoid init_f() {\n\tfact[0] = modint(1);\n\tfor (int i = 0; i < max_n - 1; i++) {\n\t\tfact[i + 1] = fact[i] * modint(i + 1);\n\t}\n\tfactinv[max_n - 1] = modint(1) / fact[max_n - 1];\n\tfor (int i = max_n - 2; i >= 0; i--) {\n\t\tfactinv[i] = factinv[i + 1] * modint(i + 1);\n\t}\n}\nmodint comb(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[b] * factinv[a - b];\n}\nmodint combP(int a, int b) {\n\tif (a < 0 || b < 0 || a < b)return 0;\n\treturn fact[a] * factinv[a - b];\n}\nint gcd(int a, int b) {\n\tif (a < b)swap(a, b);\n\twhile (b) {\n\t\tint r = a % b; a = b; b = r;\n\t}\n\treturn a;\n}\n\nconst int c = 31;\nbool ok[55][55][c];\nbool sub[55][11];\nvector<vector<int>> mk[c];\nvoid yaru(vector<int> a) {\n\tint n = a.size();\n\trep(i, n)Rep(j, i+1, n+1)rep(k, c)ok[i][j][k] = false;\n\trep(i, n)ok[i][i+1][a[i]] = true;\n\tfor (int len = 2; len <= n; len++) {\n\t\trep(l, n - len + 1) {\n\t\t\tint r = l + len;\n\t\t\t//[l,r)\n\t\t\trep(col, c) {\n\t\t\t\tfor (auto v : mk[col]) {\n\t\t\t\t\tRep1(i, l, r)rep(j, v.size()+1) {\n\t\t\t\t\t\tsub[i][j] = false;\n\t\t\t\t\t}\n\t\t\t\t\tsub[l][0] = true;\n\t\t\t\t\tRep(i, l, r) {\n\t\t\t\t\t\trep(j, v.size())if (sub[i][j]) {\n\t\t\t\t\t\t\tfor (int ni = i + 1; ni <= r; ni++) {\n\t\t\t\t\t\t\t\tif (ok[i][ni][v[j]]) {\n\t\t\t\t\t\t\t\t\tsub[ni][j + 1] = true;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (sub[r][v.size()]) {\n\t\t\t\t\t\tok[l][r][col] = true; break;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n\nbool oka[55][55][c];\nbool okb[55][55][c];\nint n, m, r;\n\nbool sok[55][55][55][55];\nvoid solve() {\n\trep(i, c)mk[i].clear();\n\tvector<int> a(n);\n\trep(i, n)cin >> a[i]; rep(i, n)a.push_back(a[i]);\n\tvector<int> b(m);\n\trep(i, m)cin >> b[i]; rep(i, m)b.push_back(b[i]);\n\trep(i, r) {\n\t\tint num; cin >> num;\n\t\tvector<int> v(num);\n\t\trep(j, num)cin >> v[j];\n\t\tint alf; cin >> alf;\n\t\tmk[alf].push_back(v);\n\t}\n\tyaru(a);\n\trep(i, a.size())Rep1(j, i + 1, a.size())rep(k, c) {\n\t\toka[i][j][k] = ok[i][j][k];\n\t}\n\tyaru(b);\n\trep(i, b.size())Rep1(j, i + 1, b.size())rep(k, c) {\n\t\tokb[i][j][k] = ok[i][j][k];\n\t}\n\trep(i, a.size())Rep(j, i + 1, a.size() + 1) {\n\t\trep(k, b.size())Rep(l, k + 1, b.size() + 1) {\n\t\t\tsok[i][j][k][l] = false;\n\t\t\trep(col, c) {\n\t\t\t\tif (oka[i][j][col] && okb[k][l][col]) {\n\t\t\t\t\tsok[i][j][k][l] = true; break;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint ans = -1;\n\trep(s, n)rep(t, m) {\n\t\t//[s,s+n)\n\t\t//[t,t+m)\n\t\tvector<vector<int>> dp(n + 1, vector<int>(m + 1,-1));\n\t\tdp[0][0] = 0;\n\t\trep(i, n + 1)rep(j, m + 1) {\n\t\t\tif (dp[i][j] < 0)continue;\n\t\t\tfor (int ni = i + 1; ni <= n; ni++) {\n\t\t\t\tfor (int nj = j + 1; nj <= m; nj++) {\n\t\t\t\t\tif (sok[s + i][s + ni][t + j][t + nj]) {\n\t\t\t\t\t\tdp[ni][nj] = max(dp[ni][nj], dp[i][j] + 1);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tans = max(ans, dp[n][m]);\n\t}\n\tcout << ans << \"\\n\";\n}\nsigned main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\t//cout << fixed << setprecision(10);\n\t//init_f();\n\t//init();\n\t//int t; cin >> t; rep(i, t)\n\twhile (cin>>n>>m>>r,n)\n\t\tsolve();\n\treturn 0;\n}", "accuracy": 1, "time_ms": 510, "memory_kb": 28656, "score_of_the_acc": -1.0403, "final_rank": 16 }, { "submission_id": "aoj_1191_5821073", "code_snippet": "/*\tauthor: Kite_kuma\n\tcreated: 2021.08.25 09:49:47 */\n\n// #ifdef LOCAL\n#define _GLIBCXX_DEBUG\n// #endif\n#include <bits/stdc++.h>\nusing namespace std;\n\n#pragma region macros\n\n#define foa(s, v) for(auto &s : v)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\n#define popcnt(n) __builtin_popcountll((long long)n)\n\n#define REPname(a, b, c, d, e, ...) e\n#define rep(...) REPname(__VA_ARGS__, REP3, REP2, REP1, REP0)(__VA_ARGS__)\n#define REP0(x) for(int Counter_in_rep_macro = 0; Counter_in_rep_macro < (x); ++Counter_in_rep_macro)\n#define REP1(i, x) for(int i = 0; i < (x); ++i)\n#define REP2(i, l, r) for(int i = (l); i < (r); ++i)\n#define REP3(i, l, r, c) for(int i = (l); i < (r); i += (c))\n\n#define DREPname(a, b, c, d, e, ...) e\n#define drep(...) DREPname(__VA_ARGS__, DREP3, DREP2, DREP1)(__VA_ARGS__)\n#define DREP1(i, x) for(int i = (x)-1; i >= 0; --i)\n#define DREP2(i, l, r) for(int i = (r)-1; i >= (l); --i)\n#define DREP3(i, l, r, c) for(int i = (r)-1; i >= (l); i -= (c))\n\n#pragma endregion\n\n#pragma region aliases\n\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\nusing vi = std::vector<int>;\nusing vvi = std::vector<std::vector<int>>;\nusing vvvi = std::vector<std::vector<std::vector<int>>>;\nusing vll = std::vector<ll>;\nusing vvll = std::vector<vll>;\nusing vvvll = std::vector<vvll>;\nusing pii = std::pair<int, int>;\nusing pll = std::pair<long long, long long>;\ntemplate <class T = ll>\nusing V = std::vector<T>;\ntemplate <class T = ll>\nusing VV = V<V<T>>;\ntemplate <class T = ll>\nusing VVV = V<V<V<T>>>;\ntemplate <class T = ll>\nusing pqup = std::priority_queue<T, std::vector<T>, std::greater<T>>;\ntemplate <class T = ll>\nusing pqdn = std::priority_queue<T>;\n\n#pragma endregion\n\n#pragma region constants\n\nconst int inf = 1e9;\nconst long long INF = 1e18;\nconst long double pi = acos(-1);\nconst char dl = '\\n';\nconst char sp = ' ';\nint dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};\nint dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};\n\nconst int mod_1000000007 = 1000000007;\nconst int mod_998244353 = 998244353;\n\n#pragma endregion\n\n#pragma region basic_operation\n\ntemplate <class T0, class T1, class T2>\ninline bool in_range(T0 x, T1 lef, T2 rig) {\n\treturn ((lef <= x) && (x < rig));\n}\n\ntemplate <class T>\ninline bool chmin(T &a, T b) {\n\tif(a > b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\ntemplate <class T>\ninline bool chmax(T &a, T b) {\n\tif(a < b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\n\nvoid Yes(bool f = 1) { std::cout << (f ? \"Yes\" : \"No\") << '\\n'; }\nvoid No() { std::cout << \"No\\n\"; }\nvoid YES(bool f = 1) { std::cout << (f ? \"YES\" : \"NO\") << '\\n'; }\nvoid NO() { std::cout << \"NO\\n\"; }\n\ntemplate <class T>\nvoid drop(T answer) {\n\tstd::cout << answer << '\\n';\n\texit(0);\n}\n\nvoid err(bool flag = true) {\n\tif(!flag) return;\n\tstd::cout << -1 << '\\n';\n\texit(0);\n}\n\ntemplate <class T>\nvoid vout(std::vector<T> const &v, bool vertically = 0) {\n\tif(vertically) {\n\t\tfor(auto const &a : v) {\n\t\t\tstd::cout << a << '\\n';\n\t\t}\n\t\treturn;\n\t}\n\tfor(auto it = v.begin(); it != v.end(); it++) {\n\t\tstd::cout << (*it);\n\t\tif(it != v.end() - 1) {\n\t\t\tstd::cout << ' ';\n\t\t}\n\t}\n\tstd::cout << '\\n';\n\treturn;\n}\n\ninline void print() { std::cout << '\\n'; }\ntemplate <class T>\ninline void print(T x) {\n\tstd::cout << x << '\\n';\n\treturn;\n}\ntemplate <typename Head, typename... Tail>\nvoid print(Head H, Tail... T) {\n\tstd::cout << H << \" \";\n\tprint(T...);\n}\n\ntemplate <class T>\nvoid add(std::vector<T> &v, T val) {\n\tfor(auto &a : v) a += val;\n\treturn;\n}\n\ntemplate <class T>\nT dup(T a, T b) {\n\tassert(b != 0);\n\treturn (a + b - 1) / b;\n}\n\ntemplate <class T>\nT greatest_lower_multiple(T x, T d) {\n\tif(d == 0) return 0;\n\tif(d < 0) d *= -1;\n\tT y = x % d;\n\tif(y < 0) y += d;\n\treturn x - y;\n}\n\ntemplate <class T>\nT least_upper_multiple(T x, T d) {\n\treturn -greatest_lower_multiple(-x, d);\n}\n\nlong long POW(long long a, long long n) {\n\tlong long res = 1;\n\twhile(n > 0) {\n\t\tif(n & 1) res = res * a;\n\t\ta = a * a;\n\t\tn >>= 1;\n\t}\n\treturn res;\n}\n\nlong long modpow(long long a, long long n, long long mod) {\t // a^n mod\n\tassert(n >= 0 && mod);\n\tif(mod == 1) return 0LL;\n\tlong long res = 1;\n\ta %= mod;\n\twhile(n > 0) {\n\t\tif(n & 1) res = res * a % mod;\n\t\ta = a * a % mod;\n\t\tn >>= 1;\n\t}\n\treturn res < 0 ? res + mod : res;\n}\n\n// return x which satisfies a * x % mod == gcd(a, mod)\n// not (mod | a)\nlong long modinv(long long a, long long mod) {\n\tlong long b = mod, u = 1, v = 0;\n\twhile(b) {\n\t\tlong long t = a / b;\n\t\ta -= t * b;\n\t\tstd::swap(a, b);\n\t\tu -= t * v;\n\t\tstd::swap(u, v);\n\t}\n\tu %= mod;\n\tif(u < 0) u += mod;\n\treturn u;\n}\n\ntemplate <class T>\nint lb(const std::vector<T> &a, const T x) {\n\treturn std::distance(a.begin(), std::lower_bound(a.begin(), a.end(), x));\n}\ntemplate <class T>\nint ub(const std::vector<T> &a, const T x) {\n\treturn std::distance(a.begin(), std::upper_bound(a.begin(), a.end(), x));\n}\ntemplate <class T>\nvoid unq_sort(std::vector<T> &a) {\n\tstd::sort(a.begin(), a.end());\n\ta.erase(std::unique(a.begin(), a.end()), a.end());\n}\ntemplate <class T>\nstd::vector<int> press(std::vector<T> &a) {\n\tauto vec = a;\n\tunq_sort(vec);\n\tstd::vector<int> ret;\n\tfor(auto &v : a) ret.push_back(lb(vec, v));\n\treturn ret;\n}\n\n#pragma endregion\n\n#pragma region input\n#define VEC(type, name, size) \\\n\tvector<type> name(size); \\\n\tscanner::INPUT(name)\n#define VVEC(type, name, h, w) \\\n\tvector<vector<type>> name(h, vector<type>(w)); \\\n\tscanner::INPUT(name)\n#define INT(...) \\\n\tint __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LL(...) \\\n\tlong long __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define STR(...) \\\n\tstring __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define CHR(...) \\\n\tchar __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define DBL(...) \\\n\tdouble __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LD(...) \\\n\tlong double __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define TPL3(type0, type1, type2, name) \\\n\tstd::tuple<type0, type1, type2> name; \\\n\tscanner::INPUT(name);\n#define TPL4(type0, type1, type2, type3, name) \\\n\tstd::tuple<type0, type1, type2, type3> name; \\\n\tscanner::INPUT(name);\n\nnamespace scanner {\ntemplate <class T>\nvoid scan(T &a) {\n\tstd::cin >> a;\n}\n\ntemplate <class T, class L>\nvoid scan(std::pair<T, L> &p) {\n\tscan(p.first);\n\tscan(p.second);\n}\n\ntemplate <class T0, class T1, class T2>\nvoid scan(std::tuple<T0, T1, T2> &p) {\n\tT0 t0;\n\tT1 t1;\n\tT2 t2;\n\tscan(t0);\n\tscan(t1);\n\tscan(t2);\n\tp = std::make_tuple(t0, t1, t2);\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid scan(std::tuple<T0, T1, T2, T3> &p) {\n\tT0 t0;\n\tT1 t1;\n\tT2 t2;\n\tT3 t3;\n\tscan(t0);\n\tscan(t1);\n\tscan(t2);\n\tscan(t3);\n\tp = std::make_tuple(t0, t1, t2, t3);\n}\n\ntemplate <class T>\nvoid scan(std::vector<T> &a) {\n\tfor(auto &i : a) scan(i);\n}\n\nvoid INPUT() {}\ntemplate <class Head, class... Tail>\nvoid INPUT(Head &head, Tail &... tail) {\n\tscan(head);\n\tINPUT(tail...);\n}\n} // namespace scanner\n\ntemplate <typename T1, typename T2>\nstd::istream &operator>>(std::istream &is, std::pair<T1, T2> &p) {\n\tis >> p.first >> p.second;\n\treturn is;\n}\n#pragma endregion\n\n#pragma region debug\n\n#pragma region output\ntemplate <typename T1, typename T2>\nstd::ostream &std::operator<<(std::ostream &os, const std::pair<T1, T2> &p) {\n\tos << p.first << \" \" << p.second;\n\treturn os;\n}\ntemplate <class T>\nstd::ostream &std::operator<<(std::ostream &os, const std::vector<T> &v) {\n\tfor(int i = 0; i < (int)v.size(); i++) {\n\t\tif(i) os << \" \";\n\t\tos << v[i];\n\t}\n\treturn os;\n}\n#pragma endregion\n\n#pragma region view\n\nnamespace viewer {\nvoid view(const long long e) {\n\tif(e == INF)\n\t\tstd::cerr << \"INF\";\n\telse if(e == -INF)\n\t\tstd::cerr << \"-INF\";\n\telse\n\t\tstd::cerr << e;\n}\n\nvoid view(const int e) {\n\tif(e == inf)\n\t\tstd::cerr << \"inf\";\n\telse if(e == -inf)\n\t\tstd::cerr << \"-inf\";\n\telse\n\t\tstd::cerr << e;\n}\n\ntemplate <typename T>\nvoid view(const T e) {\n\tstd::cerr << e;\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::pair<T, U> &p) {\n\tstd::cerr << \"(\";\n\tview(p.first);\n\tstd::cerr << \", \";\n\tview(p.second);\n\tstd::cerr << \")\";\n}\n\ntemplate <class T0, class T1, class T2>\nvoid view(const std::tuple<T0, T1, T2> &p) {\n\tstd::cerr << \"(\";\n\tview(std::get<0>(p));\n\tstd::cerr << \", \";\n\tview(std::get<1>(p));\n\tstd::cerr << \", \";\n\tview(std::get<2>(p));\n\tstd::cerr << \")\";\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid view(const std::tuple<T0, T1, T2, T3> &p) {\n\tstd::cerr << \"(\";\n\tview(std::get<0>(p));\n\tstd::cerr << \", \";\n\tview(std::get<1>(p));\n\tstd::cerr << \", \";\n\tview(std::get<2>(p));\n\tstd::cerr << \", \";\n\tview(std::get<3>(p));\n\tstd::cerr << \")\";\n}\n\ntemplate <typename T>\nvoid view(const std::set<T> &s) {\n\tif(s.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << \"{ \";\n\tfor(auto &t : s) {\n\t\tview(t);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <typename T>\nvoid view(const std::unordered_set<T> &s) {\n\tif(s.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << \"{ \";\n\tfor(auto &t : s) {\n\t\tview(t);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <typename T>\nvoid view(const std::vector<T> &v) {\n\tif(v.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << \"{ \";\n\tfor(const auto &e : v) {\n\t\tview(e);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <typename T>\nvoid view(const std::vector<std::vector<T>> &vv) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &v : vv) {\n\t\tstd::cerr << \"\\t\";\n\t\tview(v);\n\t\tstd::cerr << '\\n';\n\t}\n\tstd::cerr << \"}\";\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::vector<std::pair<T, U>> &v) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &c : v) {\n\t\tstd::cerr << \"\\t(\";\n\t\tview(c.first);\n\t\tstd::cerr << \", \";\n\t\tview(c.second);\n\t\tstd::cerr << \")\\n\";\n\t}\n\tstd::cerr << \"}\";\n}\n\ntemplate <class T0, class T1, class T2>\nvoid view(const std::vector<std::tuple<T0, T1, T2>> &v) {\n\tif(v.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << '{';\n\tfor(const auto &t : v) {\n\t\tstd::cerr << \"\\n\\t\";\n\t\tview(t);\n\t\tstd::cerr << \",\";\n\t}\n\tstd::cerr << \"\\n}\";\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid view(const std::vector<std::tuple<T0, T1, T2, T3>> &v) {\n\tif(v.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << '{';\n\tfor(const auto &t : v) {\n\t\tstd::cerr << \"\\n\\t\";\n\t\tview(t);\n\t\tstd::cerr << \",\";\n\t}\n\tstd::cerr << \"\\n}\";\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::map<T, U> &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &t : m) {\n\t\tstd::cerr << \"\\t[\";\n\t\tview(t.first);\n\t\tstd::cerr << \"] : \";\n\t\tview(t.second);\n\t\tstd::cerr << '\\n';\n\t}\n\tstd::cerr << \"}\";\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::unordered_map<T, U> &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &t : m) {\n\t\tstd::cerr << \"\\t[\";\n\t\tview(t.first);\n\t\tstd::cerr << \"] : \";\n\t\tview(t.second);\n\t\tstd::cerr << '\\n';\n\t}\n\tstd::cerr << \"}\";\n}\n} // namespace viewer\n\n#pragma endregion\n\n// when debugging : g++ foo.cpp -DLOCAL\n#ifdef LOCAL\nvoid debug_out() {}\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head H, Tail... T) {\n\tviewer::view(H);\n\tstd::cerr << \", \";\n\tdebug_out(T...);\n}\n#define debug(...) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"] : [\"; \\\n\t\tdebug_out(__VA_ARGS__); \\\n\t\tstd::cerr << \"\\b\\b]\\n\"; \\\n\t} while(0)\n#define dump(x) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" \" << #x << \" : \"; \\\n\t\tviewer::view(x); \\\n\t\tstd::cerr << '\\n'; \\\n\t} while(0)\n\n#else\n#define debug(...) (void(0))\n#define dump(x) (void(0))\n#endif\n\n#pragma endregion\n\nvvvi make_dp_table(vector<int> a, vector<vi> x, vector<int> y) {\n\tint n = a.size();\n\tint n2 = n + n;\n\tint r = x.size();\n\trep(i, n) a.push_back(a[i]);\n\tVV<VV<int>> dp_rule(n, vvvi(n2, vvi(r, vi(11))));\n\n\tvvvi ret(n, vvi(n2, vi(31)));\n\n\trep(len, 0, n + 1) {\n\t\trep(left, n) {\n\t\t\tint right = left + len;\n\t\t\trep(rule_number, r) {\n\t\t\t\trep(xr, 0, x[rule_number].size() + 1) {\n\t\t\t\t\t// dp_rule[left][right][rulenumber][xr]\n\t\t\t\t\tauto &change = dp_rule[left][right][rule_number][xr];\n\n\t\t\t\t\tif(len == 0) {\n\t\t\t\t\t\tchange = (xr == 0);\n\t\t\t\t\t} else {\n\t\t\t\t\t\tif(!xr) continue;\n\t\t\t\t\t\tif(len == 1) {\n\t\t\t\t\t\t\tif(a[left] == x[rule_number][0] && xr == 1) {\n\t\t\t\t\t\t\t\tchange = 1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t} else {\n\t\t\t\t\t\t\trep(mid, left + 1, right) {\n\t\t\t\t\t\t\t\tint m = mid;\n\t\t\t\t\t\t\t\tint R = right;\n\t\t\t\t\t\t\t\tif(m >= n) {\n\t\t\t\t\t\t\t\t\tm -= n;\n\t\t\t\t\t\t\t\t\tR -= n;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tchange |= (dp_rule[left][mid][rule_number][xr - 1] && ret[m][R][x[rule_number][xr - 1]]);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tauto &change = ret[left][right];\n\t\t\tif(len == 1) {\n\t\t\t\tchange[a[left]] = 1;\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\trep(rule_number, r) {\n\t\t\t\tif(dp_rule[left][right][rule_number][x[rule_number].size()]) {\n\t\t\t\t\tchange[y[rule_number]] = 1;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\trep(rule_number, r){\n\t\t\t\trep(number, 31){\n\t\t\t\t\tif(x[rule_number][0] == number && change[number]){\n\t\t\t\t\t\tdp_rule[left][right][rule_number][1] = 1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\treturn ret;\n}\n\nint solve(int n) {\n\tint m, r;\n\tcin >> m >> r;\n\n\tvector<int> a, b;\n\trep(n) {\n\t\tINT(x);\n\t\ta.push_back(x);\n\t}\n\trep(m) {\n\t\tINT(x);\n\t\tb.push_back(x);\n\t}\n\n\t// vector<pair<vector<int>, int>> rules;\n\tvvi x(r);\n\tvi y(r);\n\trep(i, r) {\n\t\tint len;\n\t\tcin >> len;\n\t\tx[i].resize(len);\n\t\trep(j, len) cin >> x[i][j];\n\t\tcin >> y[i];\n\t}\n\n\tdebug(x, y);\n\n\tauto dp_a = make_dp_table(a, x, y);\n\tauto dp_b = make_dp_table(b, x, y);\n\n\n\trep(i, n) a.push_back(a[i]);\n\trep(i, m) b.push_back(b[i]);\n\n\tint n2 = n + n;\n\tint m2 = m + m;\n\n\tvvi longest_path(n2, vi(m2));\n\n\tVV<VV<int>> match(n, vvvi(n2, vvi(m, vi(m2))));\n\n\trep(i, n) rep(j, i + 1, n2) rep(k, m) rep(l, k + 1, m2) {\n\t\trep(num, 31) {\n\t\t\tif(dp_a[i][j][num] && dp_b[k][l][num]) {\n\t\t\t\tmatch[i][j][k][l] = 1;\n\t\t\t}\n\t\t}\n\t}\n\n\tint ans = -1;\n\n\trep(start_a, n) rep(start_b, m) {\n\t\tint goal_a = start_a + n;\n\t\tint goal_b = start_b + m;\n\n\t\tvvi dp(n + 1, vi(m + 1, -inf));\n\t\tdp[0][0] = 0;\n\n\t\trep(i, start_a + 1, goal_a + 1) rep(j, start_b + 1, goal_b + 1) {\n\t\t\trep(pre_i, start_a, i) rep(pre_j, start_b, j) {\n\t\t\t\tint c, d, e, f;\n\t\t\t\tif(pre_i >= n) {\n\t\t\t\t\tc = pre_i - n;\n\t\t\t\t\td = i - n;\n\t\t\t\t} else {\n\t\t\t\t\tc = pre_i;\n\t\t\t\t\td = i;\n\t\t\t\t}\n\t\t\t\tif(pre_j >= m) {\n\t\t\t\t\te = pre_j - m;\n\t\t\t\t\tf = j - m;\n\t\t\t\t} else {\n\t\t\t\t\te = pre_j;\n\t\t\t\t\tf = j;\n\t\t\t\t}\n\t\t\t\tif(match[c][d][e][f]) {\n\t\t\t\t\tchmax(dp[i - start_a][j - start_b], dp[pre_i - start_a][pre_j - start_b] + 1);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tchmax(ans, dp[n][m]);\n\t}\n\n\treturn ans;\n}\n\nint main() {\n\tstd::ios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\tstd::cout << std::fixed << std::setprecision(15);\n\tsrand((unsigned)time(NULL));\n\n\tint n;\n\twhile(cin >> n) {\n\t\tif(!n) exit(0);\n\t\tcout << solve(n) << dl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2860, "memory_kb": 12612, "score_of_the_acc": -0.7465, "final_rank": 15 }, { "submission_id": "aoj_1191_3709978", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate<typename T>\nstd::vector<T> table(int n, T v) { return std::vector<T>(n, v); }\n\ntemplate <class... Args>\nauto table(int n, Args... args) {\n auto val = table(args...);\n return std::vector<decltype(val)>(n, std::move(val));\n}\n\nconstexpr int max_a = 30;\nconstexpr int max_k = 10;\n\nauto calc_can_make(vector<int> const& a, vector<vector<int>> const& xs, vector<int> const& ys) {\n const int n = a.size() / 2, r_sz = xs.size();\n auto can_make = table(a.size(), a.size(), max_a + 1, false);\n // r_dp[i][j][k][l] := can match a[i..j) with xs[k][0..l) ?\n auto r_dp = table(a.size(), a.size(), r_sz, max_k + 1, false);\n for(int i = 0; i + 1 < n * 2; ++i) {\n can_make[i][i + 1][a[i]] = true;\n }\n for(int i = 0; i < n; ++i) {\n for(int j = 0; j < r_sz; ++j) {\n r_dp[i][i][j][0] = true;\n }\n }\n for(int len = 1; len <= n; ++len) {\n for(int l = 0; l + len < 2 * n; ++l) {\n const int r = l + len;\n for(int i = 0; i < r_sz; ++i) {\n for(int j = 1; j <= (int)xs[i].size(); ++j) {\n for(int k = l; k < r; ++k) {\n r_dp[l][r][i][j] = r_dp[l][r][i][j] | (r_dp[l][k][i][j - 1] && can_make[k][r][xs[i][j - 1]]);\n }\n }\n }\n for(int i = 0; i < r_sz; ++i) {\n if(r_dp[l][r][i][xs[i].size()]) {\n can_make[l][r][ys[i]] = true;\n }\n }\n for(int i = 0; i < r_sz; ++i) {\n if(can_make[l][r][xs[i][0]]) {\n r_dp[l][r][i][1] = true;\n }\n }\n }\n }\n return can_make;\n}\n\nint main() {\n int n, m, r;\n while(cin >> n >> m >> r, n) {\n vector<int> a(n * 2), b(m * 2);\n vector<vector<int>> xs(r);\n vector<int> ys(r);\n for(int i = 0; i < n; ++i) {\n cin >> a[i];\n a[i + n] = a[i];\n }\n for(int i = 0; i < m; ++i) {\n cin >> b[i];\n b[i + m] = b[i];\n }\n for(int i = 0; i < r; ++i) {\n int k; cin >> k;\n xs[i].resize(k);\n for(auto& x : xs[i]) cin >> x;\n cin >> ys[i];\n }\n\n auto can_make_a = calc_can_make(a, xs, ys);\n auto can_make_b = calc_can_make(b, xs, ys);\n int ans = -1;\n for(int s1 = 0; s1 < n; ++s1) {\n for(int s2 = 0; s2 < m; ++s2) {\n vector<vector<int>> dp(n + 1, vector<int>(m + 1, -1));\n dp[0][0] = 0;\n for(int i = 0; i < n; ++i) {\n for(int j = 0; j < m; ++j) {\n if(dp[i][j] == -1) continue;\n for(int k = 1; k <= 30; ++k) {\n for(int l1 = 1; l1 <= n - i; ++l1) {\n if(!can_make_a[s1 + i][s1 + i + l1][k]) continue;\n for(int l2 = 1; l2 <= m - j; ++l2) {\n if(can_make_a[s1 + i][s1 + i + l1][k] && can_make_b[s2 + j][s2 + j + l2][k]) {\n dp[i + l1][j + l2] = max(dp[i + l1][j + l2], dp[i][j] + 1);\n }\n }\n }\n }\n }\n }\n ans = max(ans, dp[n][m]);\n }\n }\n\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 1920, "memory_kb": 14220, "score_of_the_acc": -0.6745, "final_rank": 14 }, { "submission_id": "aoj_1191_3672228", "code_snippet": "#include <bits/stdc++.h>\n\nclass Solve {\nprivate:\n\tusing vi = std::vector<int>;\n\tusing vvi = std::vector<vi>;\n\tusing vvvi = std::vector<vvi>;\n\tusing vvvvi = std::vector<vvvi>;\n\n\tusing vb = std::vector<bool>;\n\tusing vvb = std::vector<vb>;\n\tusing vvvb = std::vector<vvb>;\n\n\tint n, m, r;\n\tvvvi R;\n\n\tvi inputVector(int size)\n\t{\n\t\tstd::vector<int> ret(size);\n\t\tfor (auto& e: ret)\n\t\t{\n\t\t\tscanf(\"%d\", &e);\n\t\t\te--;\n\t\t}\n\t\treturn std::move(ret);\n\t}\n\tvoid inputR()\n\t{\n\t\tR.resize(30);\n\t\tfor (int i{}; i < r; i++)\n\t\t{\n\t\t\tint k;\n\t\t\tscanf(\"%d\", &k);\n\t\t\tstd::vector<int> tmp(k);\n\t\t\tfor (auto& e: tmp)\n\t\t\t{\n\t\t\t\tscanf(\"%d\", &e);\n\t\t\t\te--;\n\t\t\t}\n\t\t\tint y;\n\t\t\tscanf(\"%d\", &y);\n\t\t\ty--;\n\t\t\tR[y].push_back(tmp);\n\t\t}\n\t}\n\n\tvoid execute(vi& arr, vvvi& charTable, vvvb& canMake)\n\t{\n\t\tint size{(int)arr.size()};\n\t\tfor (int i{}; i < size; i++)\n\t\t{\n\t\t\tcharTable[i][arr[i]].push_back((i + 1) % size);\n\t\t\tcanMake[i][(i + 1) % size][arr[i]] = true;\n\t\t}\n\t\tfor (int width{2}; width <= size; width++)\n\t\t\tfor (int left{}; left < size; left++)\n\t\t\t\tfor (int char_i{}; char_i < 30; char_i++)\n\t\t\t\t\tfor (auto& e: R[char_i])\n\t\t\t\t\t\tif (e.size() <= width && stringFound(e, 0, left, width, charTable, canMake))\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tcharTable[left][char_i].push_back((left + width) % size);\n\t\t\t\t\t\t\tcanMake[left][(left + width) % size][char_i] = true;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t}\n\n\tbool stringFound(vi& arr, int arr_i, int left, int width, vvvi& charTable, vvvb& canMake)\n\t{\n\t\tint char_i{arr[arr_i]}, size{(int)charTable.size()};\n\t\tif (arr_i + 1 == (int)arr.size())\n\t\t\treturn canMake[left][(left + width) % size][char_i];\n\t\tfor (auto& e: charTable[left][char_i])\n\t\t{\n\t\t\tint next_width{e};\n\t\t\tif (e <= left) next_width += size;\n\t\t\tnext_width -= left;\n\t\t\tif ((int)arr.size() - (arr_i + 1) > width - next_width) break;\n\t\t\tif (stringFound(arr, arr_i + 1, e, width - next_width, charTable, canMake))\n\t\t\t\treturn true;\n\t\t}\n\t\treturn false;\n\t}\n\npublic:\n\tbool is_last_query{};\n\tSolve()\n\t{\n\t\tscanf(\"%d%d%d\", &n, &m, &r);\n\t\tif (n == 0)\n\t\t{\n\t\t\tis_last_query = true;\n\t\t\treturn;\n\t\t}\n\t\tvi A(inputVector(n)), B(inputVector(m));\n\t\tinputR();\n\t\tvvvb canMakeA(n, vvb(n, vb(30))), canMakeB(m, vvb(m, vb(30)));\n\t\tvvvi charTableA(n, vvi(30)), charTableB(m, vvi(30));\n\t\texecute(A, charTableA, canMakeA);\n\t\texecute(B, charTableB, canMakeB);\n\t\tvvvvi dp(n, vvvi(n, vvi(m, vi(m))));\n\t\tfor (int la{}; la < n; la++)\n\t\t\tfor (int lb{}; lb < m; lb++)\n\t\t\t\tfor (int ra{}; ra < n; ra++)\n\t\t\t\t\tfor (int rb{}; rb < m; rb++)\n\t\t\t\t\t\tfor (int char_i{}; char_i < 30; char_i++)\n\t\t\t\t\t\t\tif (canMakeA[la][ra][char_i] && canMakeB[lb][rb][char_i])\n\t\t\t\t\t\t\t\tdp[la][ra][lb][rb] = 1;\n\t\tfor (int wa{2}; wa <= n; wa++)\n\t\t\tfor (int wb{2}; wb <= m; wb++)\n\t\t\t\tfor (int la{}; la < n; la++)\n\t\t\t\t{\n\t\t\t\t\tint ra{(la + wa) % n};\n\t\t\t\t\tfor (int lb{}; lb < m; lb++)\n\t\t\t\t\t{\n\t\t\t\t\t\tint rb{(lb + wb) % m};\n\t\t\t\t\t\tfor (int ma{(la + 1) % n}; ma != ra; ma = (ma + 1) % n)\n\t\t\t\t\t\t\tfor (int mb{(lb + 1) % m}; mb != rb; mb = (mb + 1) % m)\n\t\t\t\t\t\t\t\tif (dp[la][ma][lb][mb] > 0 && dp[ma][ra][mb][rb] > 0)\n\t\t\t\t\t\t\t\t\tdp[la][ra][lb][rb] = std::max(dp[la][ra][lb][rb], dp[la][ma][lb][mb] + dp[ma][ra][mb][rb]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\tint max{};\n\n\t\tfor (int la{}; la < n; la++)\n\t\t\tfor (int lb{}; lb < m; lb++)\n\t\t\t\tmax = std::max(max, dp[la][la][lb][lb]);\n\t\tif (max == 0) puts(\"-1\");\n\t\telse printf(\"%d\\n\", max);\n\t}\n};\n\nint main()\n{\n\twhile (!Solve().is_last_query);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2660, "memory_kb": 5452, "score_of_the_acc": -0.4354, "final_rank": 11 }, { "submission_id": "aoj_1191_3215735", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 60\n\nenum Type{\n\tA,\n\tB,\n};\n\nint len[2],num_rule;\nint table[2][NUM];\nint num_left[NUM],from_table[NUM][10],to_table[NUM];\nint max_match[NUM][NUM];\nbool dp[2][NUM][NUM][30];\nbool dp2[2][NUM][NUM][NUM][11];\n\nvoid make_dp(Type type){\n\n\tint calc_len = 2*len[type]-1;\n\n\tfor(int left = 0; left < calc_len; left++){\n\t\tfor(int right = left; right < calc_len; right++){\n\n\t\t\tfor(int num = 0; num < 30; num++){\n\t\t\t\tdp[type][left][right][num] = false;\n\t\t\t}\n\n\t\t\tfor(int i = 0; i < num_rule; i++){\n\t\t\t\tfor(int k = 0; k <= num_left[i]; k++){\n\t\t\t\t\tdp2[type][left][right][i][k] = false;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < calc_len; i++){\n\t\tdp[type][i][i][table[type][i]] = true;\n\t}\n\n\tint right;\n\n\tfor(int length = 1; length <= len[type]; length++){\n\t\tfor(int left = 0; left+length <= calc_len; left++){\n\n\t\t\tright = left+length-1;\n\n\t\t\tfor(int i = 0; i < num_rule; i++){\n\t\t\t\tfor(int k = 0; k < num_left[i]; k++){\n\t\t\t\t\tfor(int mid = left; mid < right; mid++){\n\n\t\t\t\t\t\tif(dp2[type][left][mid][i][k] == true && dp[type][mid+1][right][from_table[i][k]] == true){\n\t\t\t\t\t\t\tdp2[type][left][right][i][k+1] = true;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tfor(int i = 0; i < num_rule; i++){\n\t\t\t\tif(dp2[type][left][right][i][num_left[i]]){\n\t\t\t\t\tdp[type][left][right][to_table[i]] = true;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tfor(int i = 0; i < num_rule; i++){\n\t\t\t\tif(dp[type][left][right][from_table[i][0]]){\n\t\t\t\t\tdp2[type][left][right][i][1] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid func(){\n\n\tfor(int i = 0; i < len[A]; i++){\n\n\t\tscanf(\"%d\",&table[A][i]);\n\t\ttable[A][i]--;\n\t\ttable[A][i+len[A]] = table[A][i];\n\t}\n\n\tfor(int i = 0; i < len[B]; i++){\n\n\t\tscanf(\"%d\",&table[B][i]);\n\t\ttable[B][i]--;\n\t\ttable[B][i+len[B]] = table[B][i];\n\t}\n\n\tfor(int i = 0; i < num_rule; i++){\n\n\t\tscanf(\"%d\",&num_left[i]);\n\n\t\tfor(int k = 0; k < num_left[i]; k++){\n\t\t\tscanf(\"%d\",&from_table[i][k]);\n\t\t\tfrom_table[i][k]--;\n\t\t}\n\t\tscanf(\"%d\",&to_table[i]);\n\t\tto_table[i]--;\n\t}\n\n\tmake_dp(A);\n\tmake_dp(B);\n\n\tint ans = -1;\n\tint A_right,B_right;\n\n\tfor(int A_left = 0; A_left < len[A]; A_left++){\n\t\tfor(int B_left = 0; B_left < len[B]; B_left++){\n\n\t\t\tfor(int i = 0; i <= len[A]; i++){\n\t\t\t\tfor(int k = 0; k <= len[B]; k++){\n\t\t\t\t\tmax_match[i][k] = -1;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tmax_match[0][0] = 0;\n\n\t\t\tfor(int len_A = 1; len_A <= len[A]; len_A++){\n\t\t\t\tA_right = A_left+len_A-1;\n\t\t\t\tfor(int len_B = 1; len_B <= len[B]; len_B++){\n\t\t\t\t\tB_right = B_left+len_B-1;\n\t\t\t\t\tfor(int A_mid = A_left; A_mid <= A_right; A_mid++){\n\t\t\t\t\t\tfor(int B_mid = B_left; B_mid <= B_right; B_mid++){\n\t\t\t\t\t\t\tif(max_match[A_mid-A_left][B_mid-B_left] == -1)continue;\n\n\t\t\t\t\t\t\tfor(int i = 0; i < 30; i++){\n\t\t\t\t\t\t\t\tif(dp[A][A_mid][A_right][i] == true && dp[B][B_mid][B_right][i] == true){\n\t\t\t\t\t\t\t\t\tmax_match[len_A][len_B] = max(max_match[len_A][len_B],max_match[A_mid-A_left][B_mid-B_left]+1);\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tans = max(ans,max_match[len[A]][len[B]]);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\",ans);\n}\n\nint main(){\n\n\twhile(true){\n\t\tscanf(\"%d %d %d\",&len[A],&len[B],&num_rule);\n\t\tif(len[A] == 0 && len[B] == 0 && num_rule == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 7170, "memory_kb": 5380, "score_of_the_acc": -1.0825, "final_rank": 17 }, { "submission_id": "aoj_1191_3170823", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))\n#define all(x) (x).begin(),(x).end()\n#define pb push_back\n#define fi first\n#define se second\n#define dbg(x) cout<<#x\" = \"<<((x))<<endl\ntemplate<class T,class U> ostream& operator<<(ostream& o, const pair<T,U> &p){o<<\"(\"<<p.fi<<\",\"<<p.se<<\")\";return o;}\ntemplate<class T> ostream& operator<<(ostream& o, const vector<T> &v){o<<\"[\";for(T t:v){o<<t<<\",\";}o<<\"]\";return o;}\n\nint main(){\n int n,m,RULE;\n while(scanf(\" %d %d %d\", &n, &m, &RULE),n){\n vector<int> A(n),B(m);\n rep(i,n){\n scanf(\" %d\", &A[i]);\n --A[i];\n }\n rep(i,m){\n scanf(\" %d\", &B[i]);\n --B[i];\n }\n\n vector< pair<vector<int>,int> > rule(RULE);\n rep(i,RULE){\n int k;\n scanf(\" %d\", &k);\n\n vector<int> x(k);\n int y;\n rep(j,k){\n scanf(\" %d\", &x[j]);\n --x[j];\n }\n scanf(\" %d\", &y);\n --y;\n\n rule[i] = {x,y};\n }\n\n auto make_f = [&](vector<int> &v){\n int V = v.size();\n int N = 2*V;\n vector<vector<int>> f(N,vector<int>(N));\n\n rep(i,N){\n int vv = v[i%V];\n f[i][i] |= (1<<vv);\n }\n\n for(int b=2; b<=V; ++b){\n for(int l=0; l+b-1<N; ++l){\n int r = l+b-1;\n\n // calc f[l][r]\n rep(rr,RULE){\n vector<int> x = rule[rr].fi;\n int y = rule[rr].se;\n\n int X = x.size();\n vector<vector<bool>> valid(b+1, vector<bool>(X+1));\n valid[0][0] = true;\n rep(i,b)rep(j,X)if(valid[i][j]){\n int val = x[j];\n for(int k=i; k<b; ++k){\n if(f[l+i][l+k]>>val&1) valid[k+1][j+1] = true;\n }\n }\n\n if(valid[b][X]) f[l][r] |= (1<<y);\n }\n }\n }\n\n // rep(i,N)rep(j,N) printf(\"f[%d][%d] = %d\\n\",i,j,f[i][j]);\n return f;\n };\n\n vector<vector<int>> fa = make_f(A), fb = make_f(B);\n int ans = -1;\n rep(i,n)rep(j,m){\n // printf(\"CALC %d %d\\n\",i,j);\n vector<vector<int>> dp(n+1,vector<int>(m+1,-1));\n dp[0][0]=0;\n rep(ii,n)rep(jj,m)if(dp[ii][jj]>=0){\n for(int ni=ii+1; ni<=n; ++ni)for(int nj=jj+1; nj<=m; ++nj){\n if(fa[i+ii][i+ni-1]&fb[j+jj][j+nj-1]) dp[ni][nj] = max(dp[ni][nj], dp[ii][jj]+1);\n }\n }\n ans = max(ans, dp[n][m]);\n }\n\n printf(\"%d\\n\", ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1030, "memory_kb": 3288, "score_of_the_acc": -0.1153, "final_rank": 4 } ]
aoj_1194_cpp
Vampire Mr. C is a vampire. If he is exposed to the sunlight directly, he turns into ash. Nevertheless, last night, he attended to the meeting of Immortal and Corpse Programmers Circle, and he has to go home in the near dawn. Fortunately, there are many tall buildings around Mr. C's home, and while the sunlight is blocked by the buildings, he can move around safely. The top end of the sun has just reached the horizon now. In how many seconds does Mr. C have to go into his safe coffin? To simplify the problem, we represent the eastern dawn sky as a 2-dimensional x - y plane, where the x axis is horizontal and the y axis is vertical, and approximate building silhouettes by rectangles and the sun by a circle on this plane. The x axis represents the horizon. We denote the time by t , and the current time is t =0. The radius of the sun is r and its center is at (0, - r ) when the time t =0. The sun moves on the x - y plane in a uniform linear motion at a constant velocity of (0, 1) per second. The sunlight is blocked if and only if the entire region of the sun (including its edge) is included in the union of the silhouettes (including their edges) and the region below the horizon (y ≤ 0). Write a program that computes the time of the last moment when the sunlight is blocked. The following figure shows the layout of silhouettes and the position of the sun at the last moment when the sunlight is blocked, that corresponds to the first dataset of Sample Input below. As this figure indicates, there are possibilities that the last moment when the sunlight is blocked can be the time t =0. The sunlight is blocked even when two silhouettes share parts of their edges. The following figure shows the layout of silhouettes and the position of the sun at the last moment when the sunlight is blocked, corresponding to the second dataset of Sample Input. In this dataset the radius of the sun is 2 and there are two silhouettes: the one with height 4 is in -2 ≤ x ≤ 0, and the other with height 3 is in 0 ≤ x ≤ 2. Input The input consists of multiple datasets. The first line of a dataset contains two integers r and n separated by a space. r is the radius of the sun and n is the number of silhouettes of the buildings. (1 ≤ r ≤ 20, 0 ≤ n ≤ 20) Each of following n lines contains three integers x li , x ri , h i (1 ≤ i ≤ n ) separated by a space. These three integers represent a silhouette rectangle of a building. The silhouette rectangle is parallel to the horizon, and its left and right edges are at x = x li and x = x ri , its top edge is at y = h i , and its bottom edge is on the horizon. (-20 ≤ x li < x ri ≤ 20, 0 < h i ≤ 20) The end of the input is indicated by a line containing two zeros separated by a space. Note that these silhouettes may overlap one another. Output For each dataset, output a line containing the number indicating the time t of the last moment when the sunlight is blocked. The value should not have an error greater than 0.001. No extra character ...(truncated)
[ { "submission_id": "aoj_1194_10850501", "code_snippet": "#include <cstdio>\n#include <cmath>\n#include <algorithm>\n#include <vector>\n\nusing namespace std;\n\nconst double EPS = 1e-9;\nbool EQ(double a, double b) { return abs(a - b) < EPS; }\n\ndouble getHeight(double r, double x) {\n\treturn sqrt(r * r - x * x);\n}\n\nint main(void) {\n\tint r, n;\n\tint T = 0;\n\twhile(scanf(\"%d %d\", &r, &n), r > 0) {\n\t\tT++;\n\t\tint left[20], right[20], height[20];\n\t\tfor(int i = 0; i < n; i++) {\n\t\t\tscanf(\"%d %d %d\", left + i, right + i, height + i);\n\t\t}\n\n\t\tvector<double> xs;\n\t\tconst double GAPEPS = 1e-7;\n\t\txs.push_back(-r + GAPEPS);\n\t\txs.push_back(r - GAPEPS);\n\t\txs.push_back(r);\n\t\txs.push_back(-r);\n\t\tfor(int i = 0; i < n; i++) {\n\t\t\tdouble cand = left[i] - GAPEPS;\n\t\t\tif(-r <= cand and cand <= r) xs.push_back(cand);\n\t\t\tcand = left[i] + GAPEPS;\n\t\t\tif(-r <= cand and cand <= r) xs.push_back(cand);\n\t\t\tcand = right[i] - GAPEPS;\n\t\t\tif(-r <= cand and cand <= r) xs.push_back(cand);\n\t\t\tcand = right[i] + GAPEPS;\n\t\t\tif(-r <= cand and cand <= r) xs.push_back(cand);\n\t\t\tcand = left[i];\n\t\t\tif(-r <= cand and cand <= r) xs.push_back(cand);\n\t\t\tcand = right[i];\n\t\t\tif(-r <= cand and cand <= r) xs.push_back(cand);\n\t\t}\n\t\tfor(int i = 1; i < 10001; i++) xs.push_back(-r + 2 * r / 10001.0 * i);\n\n\t\tsort(xs.begin(), xs.end());\n\n\t\tdouble s = 0, e = 100;\n\t\tfor(int lv = 0; lv < 100; lv++) {\n\t\t\tdouble mid = (s + e) / 2;\n\t\t\tbool isAble = true;\n\n\t\t\tfor(double x: xs) {\n\t\t\t\tbool isIncluded = false;\n\n\t\t\t\tdouble curHeight = getHeight(r, x) - r + mid;\n\t\t\t\tif(curHeight <= 0 or EQ(curHeight, 0)) continue;\n\t\t\t\tfor(int i = 0; i < n; i++)\n\t\t\t\t\tif(left[i] <= x and x <= right[i] and height[i] > curHeight and !EQ(height[i], curHeight)) {\n\t\t\t\t\t\tisIncluded = true;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\n\t\t\t\tif(!isIncluded) {\n\t\t\t\t\tisAble = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif(isAble) s = mid;\n\t\t\telse e = mid;\n\t\t}\n\n\t\tprintf(\"%.4lf\\n\", s);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 630, "memory_kb": 3008, "score_of_the_acc": -0.0856, "final_rank": 1 }, { "submission_id": "aoj_1194_10607261", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\n#define all(v) v.begin(), v.end()\n#define rall(a) a.rbegin(), a.rend()\n#define fi first\n#define se second\n#define endl \"\\n\"\n\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\n\ntemplate <typename T>\nusing vc = vector<T>; // prioriy_queueに必要なのでここにこれ書いてます\ntemplate <typename T>\nusing vv = vc<vc<T>>;\n#define int long long\nusing ll = long long;\nll INF = 2e18;\n\n#ifdef ONLINE_JUDGE\n// ジャッジ環境ではデバッグマクロを無効化\n#define debug_x(x) \\\n do \\\n { \\\n } while (0)\n#define debug_vc(v) \\\n do \\\n { \\\n } while (0)\n#define debug_vv(v) \\\n do \\\n { \\\n } while (0)\n#else\n// ローカルではデバッグ出力\n#define debug_x(x) cout << #x << \" = \" << (x) << endl\n#define debug_vc(v) \\\n { \\\n cout << #v << endl; \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << ' '; \\\n cout << endl; \\\n } // 一次元配列を出力する\n#define debug_vv(v) \\\n { \\\n cout << #v << endl; \\\n ll n = size(v); \\\n rep(i, n) \\\n { \\\n rep(j, size(v[i])) { cout << v[i][j] << ' '; } \\\n cout << endl; \\\n } \\\n } // 二次元配列を出力する\n#endif\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n#define rrep(i, n) for (ll i = 1; i <= (n); ++i)\n#define drep(i, n) for (ll i = (n) - 1; i >= 0; --i)\n#define nfor(i, s, n) for (ll i = s; i < n; i++) // i=s,s+1...n-1 ノーマルfor\n#define dfor(i, s, n) for (ll i = (s) - 1; i >= n; i--) // s-1スタートでnまで落ちる\n\nusing ld = long double;\nusing bl = bool;\n\ntemplate <class T>\nusing pq = priority_queue<T, vc<T>>; // 大きい順\ntemplate <class T>\nusing pq_g = priority_queue<T, vc<T>, greater<T>>; // 小さい順\n\nusing vl = vc<ll>;\nusing vvl = vv<ll>;\nusing vvvl = vv<vl>;\nusing vvvvl = vv<vvl>;\nusing vs = vc<string>;\nusing vvs = vv<string>;\nusing vb = vc<bl>;\nusing vvb = vv<bl>;\nusing vvvb = vv<vb>;\nusing vld = vc<ld>;\nusing vvld = vv<ld>;\nusing vvvld = vv<vld>;\nusing P = pair<ll, ll>;\nusing vP = vc<P>;\nusing vvP = vc<vP>;\nusing vvvP = vv<vP>;\n\n#define pb push_back\n\n#define YES cout << \"Yes\" << endl\n#define NO cout << \"No\" << endl\n#define YN \\\n { \\\n cout << \"Yes\" << endl; \\\n } \\\n else \\\n { \\\n cout << \"No\" << endl; \\\n } // if(a==b)YN;\n#define dame cout << -1 << endl\n\nstring dir = \"DRUL\"; // 第4象限の場合\nvl di = {1, 0, -1, 0}; // vl di={1,1,0,-1,-1,-1,0,1};\nvl dj = {0, 1, 0, -1}; // vl dj={0,1,1,1,0,-1,-1,-1};\n\nbool out_grid(ll i, ll j, ll h, ll w)\n{ // trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\nbl solve()\n{\n ll r, n;\n cin >> r >> n;\n if (n == 0 && r == 0)\n return 0;\n vl xl(n), xr(n), h(n);\n rep(i, n)\n {\n cin >> xl[i] >> xr[i] >> h[i];\n }\n // すべてのありうる頂点に対して全探索\n // vl maxH(41);\n // rep(i, n)\n // {\n // if(xl[i]<0){\n // xl[i]--;\n // }\n // if(xr[i]<0){\n // xr[i]--;\n // }\n // for (ll j = xl[i] + 1; j <= xr[i]; j++)\n // {\n // maxH[j+20] = max(maxH[j+20],h[i]);\n // }\n // }\n // debug_vc(maxH);\n // maxH[20] = min(maxH[19],maxH[21]);\n set<P> coord;\n set<P> isRight;\n set<P> isLeft;\n for (ll x = -20; x <= 20; x++)\n {\n for (ll y = 0; y <= 20; y++)\n {\n coord.insert({x, y});\n }\n }\n rep(i, n)\n {\n for (ll x = xl[i] + 1; x < xr[i]; x++)\n {\n for (ll y = 0; y < h[i]; y++)\n {\n coord.erase({x, y});\n }\n }\n for (ll y = 0; y < h[i]; y++)\n {\n isLeft.insert({xl[i], y});\n isRight.insert({xr[i], y});\n }\n }\n for (ll x = -20; x <= 20; x++)\n {\n for (ll y = 0; y <= 20; y++)\n {\n if (isRight.count({x, y}) && isLeft.count({x, y}))\n coord.erase({x, y});\n }\n }\n // for (ll x = -2; x <= 2; x++)\n // {\n // for (ll y = 0; y <= 4; y++)\n // {\n // if (coord.count({x,y})){\n // cout << x << y << endl;\n // }\n // }\n // }\n ld ans = 1e4;\n for (auto [x, y] : coord)\n {\n // debug_x(x);\n // debug_x(y);\n if (x <= -r || r <= x)\n continue;\n ans = min((ld)y - sqrt(r * r - x * x), ans);\n }\n cout << fixed << setprecision(10) << ans + r << endl;\n return 1;\n}\n\nsigned main()\n{\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n while (true)\n {\n if (!solve())\n break;\n }\n\n return 0;\n}\n\n/*\nshift+alt+Fで成形\nf2で変数名変更\n\nスニペット\nbasic\n m:atcoder以外用\n ma:ABC/ARC用\n mahc:AHC用\nmath\n floor:床関数\n ceil:天井関数\n comv:二項係数\n modpow: a^b mod m\n GCD:最大公約数\n extGCD:拡張ユークリッド互除法\n PFD:素因数分解\n isprime:エラトステネスの篩\n matrixpow:行列累乗\ndata_structure\n seg:セグメント木\ntechnic\n Compress:座標圧縮\n runlength:ランレングス圧縮\ngraph\n warshall:ワーシャルフロイド法\n dfs:深さ優先探索\n bfs:幅優先探索\n LCA:最近共通祖先\n*/", "accuracy": 1, "time_ms": 10, "memory_kb": 3508, "score_of_the_acc": -0.5, "final_rank": 6 }, { "submission_id": "aoj_1194_9259676", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nconst int MAX = 1000000005;\n\nbool solve() {\n int r, n;\n cin >> r >> n;\n if (r == 0 && n == 0) return false;\n vector<tuple<int, int, int>> rect(n);\n for (int i = 0; i < n; i++) {\n int xl, xr, h;\n cin >> xl >> xr >> h;\n rect[i] = {xl, xr, h};\n }\n double ans = 1e+10;\n for (int i = 1; i < 100000; i++) {\n double x = r*cos(i*M_PI/100000), y = r*sin(i*M_PI/100000);\n int maxh = 0;\n for (int j = 0; j < n; j++) {\n auto [xl, xr, h] = rect[j];\n if (x >= (double)xl && x <= (double)xr) {\n maxh = max(maxh, h);\n }\n }\n ans = min(ans, r + maxh - y);\n }\n cout << fixed << setprecision(10) << ans << endl;\n\n return true;\n}\n\nint main() {\n ios::sync_with_stdio(0); cin.tie();\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 380, "memory_kb": 3688, "score_of_the_acc": -0.7311, "final_rank": 10 }, { "submission_id": "aoj_1194_8007092", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n#define rep(i, s, n) for(int i = (int)(s); i < (int)(n); ++i)\n\nll INF = 1ll << 60;\n\nlong double solve(long double cy, int dr, int x){\n if(abs(x) == dr){\n return -1;\n }\n long double r = dr;\n long double x1 = x, x2 = x;\n long double cx = 0;\n long double y1 = 0;\n long double y2 = 1;\n long double xd = x2 - x1, yd = y2 - y1;\n long double X = x1 - cx, Y = y1 - cy;\n long double a = xd*xd + yd*yd;\n long double b = xd * X + yd * Y;\n long double c = X*X + Y*Y - r*r;\n // D = 0の時は1本で、D < 0の時は存在しない\n long double D = b*b - a*c;\n if(D <= 0){\n return -1;\n }\n long double s1 = (-b + sqrt(D)) / a;\n long double s2 = (-b - sqrt(D)) / a;\n return max(y1 + yd*s1, y1 + yd*s2);\n}\n\nint main(){\n vector<long double> ret;\n while(true){\n int r, n;\n cin >> r >> n;\n if(r == n && r == 0){\n break;\n }\n vi xl(n), xr(n), h(n);\n rep(i, 0, n){\n cin >> xl[i] >> xr[i] >> h[i];\n }\n map<pii, int> mx;\n rep(i, 0, n){\n rep(l, xl[i], xr[i]){\n if(!mx.count({l,l+1})){\n mx[{l,l+1}] = h[i];\n }\n else{\n mx[{l,l+1}] = max(mx[{l,l+1}], h[i]);\n }\n }\n }\n rep(i, -30, 30){\n if(!mx.count({i, i+1})){\n mx[{i,i+1}] = 0;\n }\n //cout << mx[{i,i+1}] << \" \";\n }\n //cout << endl;\n\n long double ans = 0;\n bool ck = true;\n\n rep(time, 0, 300000){\n long double t = 1.0*time/10000;\n rep(x, -r-1, r+2){\n if(solve(t-r, r, x) > 0 || solve(t-r, r, x+1) > 0){\n long double mxh = max(solve(t-r, r, x), solve(t-r, r, x+1));\n if(mxh > mx[{x,x+1}]){\n ck = false;\n /*\n cout << t << \"/\" << x << endl;\n cout << solve(t-r, r, x) <<\" \" << solve(t-r, r, x+1) << endl;\n */\n }\n }\n }\n if(ck){\n ans = t;\n }\n else{\n break;\n }\n }\n ret.push_back(ans);\n }\n\n cout << fixed << setprecision(10);\n for(auto r : ret){\n cout << r << endl;\n }\n \n return 0;\n \n}", "accuracy": 1, "time_ms": 7250, "memory_kb": 3512, "score_of_the_acc": -1.504, "final_rank": 19 }, { "submission_id": "aoj_1194_8007084", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n#define rep(i, s, n) for(int i = (int)(s); i < (int)(n); ++i)\n\nll INF = 1ll << 60;\n\nlong double solve(long double cy, int dr, int x){\n if(abs(x) == dr){\n return -1;\n }\n long double r = dr;\n long double x1 = x, x2 = x;\n long double cx = 0;\n long double y1 = 0;\n long double y2 = 1;\n long double xd = x2 - x1, yd = y2 - y1;\n long double X = x1 - cx, Y = y1 - cy;\n long double a = xd*xd + yd*yd;\n long double b = xd * X + yd * Y;\n long double c = X*X + Y*Y - r*r;\n // D = 0の時は1本で、D < 0の時は存在しない\n long double D = b*b - a*c;\n if(D <= 0){\n return -1;\n }\n long double s1 = (-b + sqrt(D)) / a;\n long double s2 = (-b - sqrt(D)) / a;\n return max(y1 + yd*s1, y1 + yd*s2);\n}\n\nint main(){\n vector<long double> ret;\n while(true){\n int r, n;\n cin >> r >> n;\n if(r == n && r == 0){\n break;\n }\n vi xl(n), xr(n), h(n);\n rep(i, 0, n){\n cin >> xl[i] >> xr[i] >> h[i];\n }\n map<pii, int> mx;\n rep(i, 0, n){\n rep(l, xl[i], xr[i]){\n if(!mx.count({l,l+1})){\n mx[{l,l+1}] = h[i];\n }\n else{\n mx[{l,l+1}] = max(mx[{l,l+1}], h[i]);\n }\n }\n }\n rep(i, -30, 30){\n if(!mx.count({i, i+1})){\n mx[{i,i+1}] = 0;\n }\n //cout << mx[{i,i+1}] << \" \";\n }\n //cout << endl;\n\n long double ans = 0;\n bool ck = true;\n\n rep(time, 1, 300000){\n long double t = 1.0*time/10000;\n long double dx;\n if(t > 2*r){\n dx = r;\n }\n else{\n dx = sqrt(2*t*r-t*t);\n }\n rep(x, ceil(-dx-2), dx+3){\n if(solve(t-r, r, x) > 0 || solve(t-r, r, x+1) > 0){\n long double mxh = max(solve(t-r, r, x), solve(t-r, r, x+1));\n if(mxh > mx[{x,x+1}]){\n ck = false;\n /*\n cout << t << \"/\" << x << endl;\n cout << solve(t-r, r, x) <<\" \" << solve(t-r, r, x+1) << endl;\n */\n }\n }\n }\n if(ck){\n ans = t;\n }\n else{\n break;\n }\n }\n ret.push_back(ans);\n }\n\n cout << fixed << setprecision(10);\n for(auto r : ret){\n cout << r << endl;\n }\n \n return 0;\n \n}", "accuracy": 0.5, "time_ms": 6750, "memory_kb": 3404, "score_of_the_acc": -1.3269, "final_rank": 20 }, { "submission_id": "aoj_1194_8002427", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nbool solve() {\n int n;\n double r;\n cin >> r >> n;\n if( abs(r) < 1e-3 ) return false;\n vector<pair<int, int>> event;\n for( int i = 0; i < n; i++ ) {\n int xl, xr, h;\n cin >> xl >> xr >> h;\n event.push_back(make_pair(xl, -h));\n event.push_back(make_pair(xr, h));\n }\n sort(event.begin(), event.end());\n vector<pair<int, int>> boundary;\n multiset<int> Sh;\n Sh.insert(0);\n boundary.push_back(make_pair(-40, 0));\n for( int i = 0; i < event.size(); i++ ) {\n int h_pre = *Sh.rbegin();\n auto [x, h] = event[i];\n if( h > 0 ) {\n Sh.erase(Sh.find(h));\n }else {\n Sh.insert(-h);\n }\n int h_cur = *Sh.rbegin();\n boundary.push_back(make_pair(x, h_pre));\n boundary.push_back(make_pair(x, h_cur));\n }\n boundary.push_back(make_pair(40, 0));\n double t = 0, step = 0.0001;\n auto dist = [&](double xl, double yl, double xr, double yr) -> double {\n if( xl > xr ) swap(xl, xr);\n if( yl > yr ) swap(yl, yr);\n if( xl == xr ) {\n double dy = max({0.0, yl-(-r+t), (-r+t)-yr});\n return hypot(xl, dy);\n }else {\n double dx = max({0.0, xl, -xr});\n return hypot(dx, yl-(-r+t));\n }\n };\n for( ; ; t+=step ) {\n bool is_covered = true;\n for( int i = 0; i < boundary.size()-1; i++ ) {\n auto [xl, yl] = boundary[i];\n auto [xr, yr] = boundary[i+1];\n if( dist(xl, yl, xr, yr) < r ) is_covered = false;\n }\n if( !is_covered ) break;\n }\n cout << fixed << setprecision(8) << t-step << endl;\n return true;\n}\nint main() {\n while( solve() ) {}\n}", "accuracy": 1, "time_ms": 5690, "memory_kb": 3472, "score_of_the_acc": -1.2485, "final_rank": 16 }, { "submission_id": "aoj_1194_7952406", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nbool solve() {\n int r, n;\n cin >> r >> n;\n if (r == 0 && n == 0) return false;\n set<pair<int, int>> s;\n for (int i = 0; i < n; i++) {\n int l, r, h;\n cin >> l >> r >> h;\n for (int j = l; j < r; j++) {\n for (int k = 0; k < h; k++) {\n s.emplace(j, k);\n }\n }\n }\n long double ans = 1e18;\n for (int x = -r + 1; x < r; x++) {\n for (int y = 0; y <= 30; y++) {\n long double dy = y - (sqrtl(r * r - x * x) - r);\n if (s.count(make_pair(x, y)) == 0 || s.count(make_pair(x - 1, y)) == 0) {\n ans = std::min(ans, dy);\n }\n }\n }\n cout << fixed << setprecision(10); \n cout << ans << '\\n';\n return true;\n}\n\nint main() {\n while (solve()) ; \n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3424, "score_of_the_acc": -0.416, "final_rank": 2 }, { "submission_id": "aoj_1194_7909704", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nusing ull = unsigned long long;\ntypedef pair<ll,ll> pll;\ntypedef vector<ll> vll;\ntypedef vector<pll> vpll;\ntemplate<class T> using pqmin = priority_queue<T, vector<T>, greater<T>>;\ntemplate<class T> using pqmax = priority_queue<T>;\nconst ll inf=LLONG_MAX/3;\nconst ll dx[] = {0, 1, 0, -1, 1, -1, 1, -1};\nconst ll dy[] = {1, 0, -1, 0, 1, 1, -1, -1};\n#define mp make_pair\n#define pb push_back\n#define eb emplace_back\n#define fi first\n#define se secondf\n#define all(x) x.begin(),x.end()\n#define si(x) ll(x.size())\n#define rep(i,n) for(ll i=0;i<n;i++)\n#define per(i,n) for(ll i=n-1;i>=0;i--)\n#define rng(i,l,r) for(ll i=l;i<r;i++)\n#define gnr(i,l,r) for(ll i=r-1;i>=l;i--)\n#define fore(i, a) for(auto &&i : a)\n#define fore2(a, b, v) for(auto &&[a, b] : v)\n#define fore3(a, b, c, v) for(auto &&[a, b, c] : v)\ntemplate<class T> bool chmin(T& a, const T& b){ if(a <= b) return 0; a = b; return 1; }\ntemplate<class T> bool chmax(T& a, const T& b){ if(a >= b) return 0; a = b; return 1; }\ntemplate<class T, class U> bool chmin(T& a, const U& b){ return chmin(a, (T)b); }\ntemplate<class T, class U> bool chmax(T& a, const U& b){ return chmax(a, (T)b); }\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__;in(__VA_ARGS__)\n#define CHR(...) char __VA_ARGS__;in(__VA_ARGS__)\n#define vec(type,name,...) vector<type>name(__VA_ARGS__)\n#define VEC(type,name,size) vector<type>name(size);in(name)\n#define VLL(name,size) vector<ll>name(size);in(name)\n#define vv(type,name,h,...) vector<vector<type>> name(h,vector<type>(__VA_ARGS__))\n#define VV(type,name,h,w) vector<vector<type>> name(h,vector<type>(w));in(name)\n#define vvv(type,name,h,w,...) vector<vector<vector<type>>> name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define SUM(...) accumulate(all(__VA_ARGS__),0LL)\ntemplate<class T> auto min(const T& a){ return *min_element(all(a)); }\ntemplate<class T> auto max(const T& a){ return *max_element(all(a)); }\ntemplate<class T, class F = less<>> void sor(T& a, F b = F{}){ sort(all(a), b); }\ntemplate<class T> void uniq(T& a){ sor(a); a.erase(unique(all(a)), end(a)); }\nvoid outb(bool x){cout<<(x?\"Yes\":\"No\")<<\"\\n\";}\nll max(int x, ll y) { return max((ll)x, y); }\nll max(ll x, int y) { return max(x, (ll)y); }\nint min(int x, ll y) { return min((ll)x, y); }\nint min(ll x, int y) { return min(x, (ll)y); }\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define lbg(c, x) distance((c).begin(), lower_bound(all(c), (x), greater{}))\n#define ub(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define ubg(c, x) distance((c).begin(), upper_bound(all(c), (x), greater{}))\nll gcd(ll a,ll b){return (b?gcd(b,a%b):a);}\nvector<pll> factor(ull x){ vector<pll> ans; for(ull i = 2; i * i <= x; i++) if(x % i == 0){ ans.push_back({i, 1}); while((x /= i) % i == 0) ans.back().second++; } if(x != 1) ans.push_back({x, 1}); return ans; }\nvector<ll> divisor(ull x){ vector<ll> ans; for(ull i = 1; i * i <= x; i++) if(x % i == 0) ans.push_back(i); per(i,ans.size() - (ans.back() * ans.back() == x)) ans.push_back(x / ans[i]); return ans; }\nvll prime_table(ll n){vec(ll,isp,n+1,1);vll res;rng(i,2,n+1)if(isp[i]){res.pb(i);for(ll j=i*i;j<=n;j+=i)isp[j]=0;}return res;}\n\ntemplate <class T, class S> pair<T, S> operator-(const pair<T, S> &x) { return pair<T, S>(-x.first, -x.second); }\ntemplate <class T, class S> pair<T, S> operator-(const pair<T, S> &x, const pair<T, S> &y) { return pair<T, S>(x.fi - y.fi, x.se - y.se); }\ntemplate <class T, class S> pair<T, S> operator+(const pair<T, S> &x, const pair<T, S> &y) { return pair<T, S>(x.fi + y.fi, x.se + y.se); }\ntemplate <class T> pair<T, T> operator&(const pair<T, T> &l, const pair<T, T> &r) { return pair<T, T>(max(l.fi, r.fi), min(l.se, r.se)); }\ntemplate <class T, class S> pair<T, S> operator+=(pair<T, S> &l, const pair<T, S> &r) { return l = l + r; }\ntemplate <class T, class S> pair<T, S> operator-=(pair<T, S> &l, const pair<T, S> &r) { return l = l - r; }\ntemplate <class T> bool intersect(const pair<T, T> &l, const pair<T, T> &r) { return (l.se < r.se ? r.fi < l.se : l.fi < r.se); }\n\ntemplate <class T> vector<T> &operator++(vector<T> &v) {\n fore(e, v) e++;\n return v;\n}\ntemplate <class T> vector<T> operator++(vector<T> &v, int) {\n auto res = v;\n fore(e, v) e++;\n return res;\n}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {\n fore(e, v) e--;\n return v;\n}\ntemplate <class T> vector<T> operator--(vector<T> &v, int) {\n auto res = v;\n fore(e, v) e--;\n return res;\n}\ntemplate <class T> vector<T> &operator+=(vector<T> &l, const vector<T> &r) {\n fore(e, r) l.eb(e);\n return l;\n}\n\ntemplate<class... Ts> void in(Ts&... t);\n[[maybe_unused]] void print(){}\ntemplate<class T, class... Ts> void print(const T& t, const Ts&... ts);\ntemplate<class... Ts> void out(const Ts&... ts){ print(ts...); cout << '\\n'; }\nnamespace IO{\n#define VOID(a) decltype(void(a))\nstruct S{ S(){ cin.tie(nullptr)->sync_with_stdio(0); fixed(cout).precision(12); } }S;\ntemplate<int I> struct P : P<I-1>{};\ntemplate<> struct P<0>{};\ntemplate<class T> void i(T& t){ i(t, P<3>{}); }\nvoid i(vector<bool>::reference t, P<3>){ int a; i(a); t = a; }\ntemplate<class T> auto i(T& t, P<2>) -> VOID(cin >> t){ cin >> t; }\ntemplate<class T> auto i(T& t, P<1>) -> VOID(begin(t)){ for(auto&& x : t) i(x); }\ntemplate<class T, size_t... idx> void ituple(T& t, index_sequence<idx...>){ in(get<idx>(t)...); }\ntemplate<class T> auto i(T& t, P<0>) -> VOID(tuple_size<T>{}){ ituple(t, make_index_sequence<tuple_size<T>::value>{}); }\ntemplate<class T> void o(const T& t){ o(t, P<4>{}); }\ntemplate<size_t N> void o(const char (&t)[N], P<4>){ cout << t; }\ntemplate<class T, size_t N> void o(const T (&t)[N], P<3>){ o(t[0]); for(size_t i = 1; i < N; i++){ o(' '); o(t[i]); } }\ntemplate<class T> auto o(const T& t, P<2>) -> VOID(cout << t){ cout << t; }\ntemplate<class T> auto o(const T& t, P<1>) -> VOID(begin(t)){ bool first = 1; for(auto&& x : t) { if(first) first = 0; else o(' '); o(x); } }\ntemplate<class T, size_t... idx> void otuple(const T& t, index_sequence<idx...>){ print(get<idx>(t)...); }\ntemplate<class T> auto o(T& t, P<0>) -> VOID(tuple_size<T>{}){ otuple(t, make_index_sequence<tuple_size<T>::value>{}); }\n#undef VOID\n}\n#define unpack(a) (void)initializer_list<int>{(a, 0)...}\ntemplate<class... Ts> void in(Ts&... t){ unpack(IO::i(t)); }\ntemplate<class T, class... Ts> void print(const T& t, const Ts&... ts){ IO::o(t); unpack(IO::o((cout << ' ', ts))); }\n#undef unpack\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n while(1){\n LL(r,n);\n if(n==0&&r==0)break;\n map<pll,bool> col;\n rep(i,n){\n LL(xl,xr,h);\n rng(x,xl,xr)rng(y,0,h){\n col[{x,y}]=1;\n }\n }\n auto inc=[&](double p,double x,double y){\n double d=pow(x,2)+pow(y-p,2);\n d=sqrt(d);\n return d<r;\n };\n auto f=[&](double t){\n double p=t-r;\n bool res=1;\n rng(x,-20,20)rng(y,0,20){\n bool ex=0;\n rng(dx,0,2)rng(dy,0,2){\n ex|=inc(p,x+dx,y+dy);\n }\n if(ex){\n res&=col[{x,y}];\n }\n }\n return res;\n };\n {\n double l=0,r=20;\n while(l<r-0.0001){\n double mid=(l+r)/2.0;\n (f(mid)?l:r)=mid;\n }\n cout<<fixed<<setprecision(4);\n out(l);\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3548, "score_of_the_acc": -0.5428, "final_rank": 8 }, { "submission_id": "aoj_1194_7700090", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <deque>\n#include <queue>\n#include <string>\n#include <iomanip>\n#include <set>\n#include <unordered_set>\n#include <map>\n#include <unordered_map>\n#include <utility>\n#include <stack>\n#include <random>\n#include <complex>\n#include <functional>\n#include <stdio.h>\n#include <stdlib.h>\n#include <time.h>\n#include <math.h>\n#include <assert.h>\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\nusing namespace atcoder;\n#endif\n#if __has_include(<boost/multiprecision/cpp_int.hpp>)\n#include <boost/multiprecision/cpp_int.hpp>\nusing cpp_int=boost::multiprecision::cpp_int;\n#endif\n#if __has_include(<boost/multiprecision/cpp_dec_float.hpp>)\n#include <boost/multiprecision/cpp_dec_float.hpp>\ntemplate<unsigned size>using cpp_float=boost::multiprecision::number<boost::multiprecision::cpp_dec_float<size>>;\ntemplate<unsigned size>using cpp_double=boost::multiprecision::number<boost::multiprecision::cpp_dec_float<size,long long>>;\n#endif\nusing namespace std;\nusing ll=long long;\n#define read(x) cin>>(x);\n#define readll(x) ll (x);cin>>(x);\n#define readS(x) string (x);cin>>(x);\n#define readvll(x,N) vector<ll> (x)((N));for(int i=0;i<(N);i++){cin>>(x)[i];}\n#define rep(i,N) for(ll (i)=0;(i)<(N);(i)++)\n#define rep2d(i,j,H,W) for(ll (i)=0;(i)<(H);(i)++)for(ll (j)=0;(j)<(W);j++)\n#define is_in(x,y) (0<=(x) && (x)<H && 0<=(y) && (y)<W)\n#define yn {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}\n#define double_out(x) fixed << setprecision(x)\ntemplate<class T> inline void erase_duplicate(vector<T>& A){sort(A.begin(),A.end());A.erase(unique(A.begin(),A.end()),A.end());}\ninline ll powll(ll x,ll n){ll r=1;while(n>0){if(n&1){r*=x;};x*=x;n>>=1;};return r;}\n\nvoid solve(ll r,ll n){\n vector<ll> xl(n),xr(n),h(n);\n for(ll i=0;i<n;i++){\n cin>>xl[i]>>xr[i]>>h[i];\n }\n // vector<ll> hmax(41);\n // for(ll i=0;i<n;i++){\n // for(ll j=xl[i]+20;j<xr[i]+20;j++){\n // hmax[j]=max(hmax[j],h[i]);\n // }\n // }\n // double ans=100000;\n // for(ll j=0;j<40;j++){\n // ll x1=j-20;\n // ll x2=j-20+1;\n // ll hh=hmax[j];\n // if(abs(x1)>abs(x2)){\n // swap(x1,x2);\n // hh=hmax[j+1];\n // }\n // if(abs(x1)>r || (abs(x1)==r && hh==0)){\n // continue;\n // }\n // ans=min(ans,hh-sqrt(r*r-x1*x1)+r);\n // cerr<<x1<<\" \"<<hh<<\" \"<<ans<<endl;\n // }\n double ans=1000000;\n for(double x=-20.0;x<=20.0;x+=0.00001){\n if(abs(x)>r){\n continue;\n }\n ll hh=0;\n for(ll i=0;i<n;i++){\n if(xl[i]<=x && x<=xr[i]){\n hh=max(hh,h[i]);\n }\n }\n ans=min(ans,hh-sqrt(r*r-x*x)+r);\n }\n cout<<double_out(10)<<ans<<endl;\n}\n\nint main(){\n ll r,n;\n while(cin>>r>>n,r){\n solve(r,n);\n }\n}", "accuracy": 1, "time_ms": 2960, "memory_kb": 3568, "score_of_the_acc": -0.9675, "final_rank": 11 }, { "submission_id": "aoj_1194_6771273", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n\nvoid solve(){\n while(1){\n int r,n;\n cin>>r>>n;\n if(r==0&&n==0) break;\n map<pair<double,double>,bool> mp;\n for(int i=0;i<n;i++){\n int xl,xr,h;\n cin>>xl>>xr>>h;\n for(double x=xl;x<=xr;x+=0.5){\n for(int y=0;y<=h;y++){\n mp[{x,y}]=true;\n }\n }\n }\n long double ans=1000000;\n for(int x=-20;x<=20;x++){\n for(int y=1;y<=20;y++){\n if(!mp[{x+0.5,y+1}]||!mp[{x-0.5,y+1}]){\n if(r*r-x*x>0){\n ans=min(ans,(long double)y+r-sqrt(r*r-x*x));\n }\n }\n }\n }\n for(int x=-20;x<=20;x++){\n if(!mp[{x-0.5,0}]||!mp[{x+0.5,0}]){\n if(r*r-x*x>0){\n ans=min(ans,(long double)r-sqrt(r*r-x*x));\n }\n }\n }\n cout<<fixed<<setprecision(6)<<ans<<endl;\n }\n}\nint main(){\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3504, "score_of_the_acc": -0.4974, "final_rank": 5 }, { "submission_id": "aoj_1194_6672119", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <deque>\n#include <queue>\n#include <string>\n#include <iomanip>\n#include <set>\n#include <unordered_set>\n#include <map>\n#include <unordered_map>\n#include <utility>\n#include <stack>\n#include <random>\n#include <stdio.h>\n#include <stdlib.h>\n#include <time.h>\n#include <math.h>\n#include <assert.h>\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\nusing namespace atcoder;\n#endif\nusing namespace std;\nusing ll=long long;\n#define read(x) cin>>(x);\n#define readll(x) ll (x);cin>>(x);\n#define readS(x) string (x);cin>>(x);\n#define readvll(x,N) vector<ll> (x)((N));for(int i=0;i<(N);i++){cin>>(x)[i];}\n#define rep(i,N) for(ll (i)=0;(i)<(N);(i)++)\n#define rep2d(i,j,H,W) for(ll (i)=0;(i)<(H);(i)++)for(ll (j)=0;(j)<(W);j++)\n#define is_in(x,y) (0<=(x) && (x)<H && 0<=(y) && (y)<W)\n#define yn {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}\n\nvoid solve(ll n,ll r){\n vector<ll> X1(n),X2(n),H(n);\n for(ll i=0;i<n;i++){\n cin>>X1[i]>>X2[i]>>H[i];\n }\n double ans=40.0;\n for(ll i=-r;i<r;i++){\n ll u=0;\n for(ll j=0;j<n;j++){\n if(X1[j]<=i && i<X2[j]){\n //cerr<<j<<endl;\n u=max(u,H[j]);\n }\n }\n //cerr<<\"i: \"<<i<<\" u:\"<<u<<endl;\n for(double j=0;j<1.0;j+=0.0001){\n double x=i+j;\n double t=(double)u-sqrt(r*r-x*x);\n ans=min(ans,(double)r+t);\n }\n }\n cout<<ans<<endl;\n}\n\nint main(){\n ll n;\n ll r;\n while(1){\n cin>>r>>n;\n if(n==0 && r==0){\n return 0;\n }\n solve(n,r);\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3448, "score_of_the_acc": -0.4441, "final_rank": 3 }, { "submission_id": "aoj_1194_6027343", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\n\nusing namespace std;\ntemplate <class T> using V = vector<T>;\ntemplate <class T> using VV = V<V<T>>;\n\nconst long double EPS = 1e-4;\nint r, n;\n\nint main() {\n cin >> r >> n;\n cout << fixed << setprecision(6);\n while (r != 0 || n != 0) {\n VV<int> shadow(41, V<int>(41));\n V<int> xls(n), xrs(n), hs(n);\n for (int i = 0; i < n; i++) {\n cin >> xls[i] >> xrs[i] >> hs[i];\n for (int x = xls[i] + 20; x < xrs[i] + 20; x++) {\n for (int y = 0; y < hs[i]; y++) {\n shadow[y][x] = 1;\n }\n }\n }\n // for (auto &&line : shadow) {\n // for (auto &&s : line) {\n // cout << s << \" \";\n // }\n // cout << \"\\n\";\n // }\n\n // 0.0005 ずつ yを上昇させてシミュレーション\n double t = 0.0;\n\n for (;;) {\n double new_t = t + 0.0005;\n bool ok = true;\n for (int i = -r; i <= r; i++) {\n int x = i;\n int y = floor(sqrt(r * r - x * x) - r + new_t);\n if (y < 0) continue;\n if (i == -r) {\n if (!shadow[y][x + 20]) ok = false;\n } else if (i == r) {\n if (!shadow[y][x + 20 - 1]) ok = false;\n } else if (!shadow[y][x + 20 - 1] || !shadow[y][x + 20]) {\n ok = false;\n }\n }\n if (!ok) break;\n t = new_t;\n }\n cout << t << \"\\n\";\n cin >> r >> n;\n }\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 3584, "score_of_the_acc": -0.6299, "final_rank": 9 }, { "submission_id": "aoj_1194_6027341", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\n\nusing namespace std;\ntemplate <class T> using V = vector<T>;\ntemplate <class T> using VV = V<V<T>>;\n\nconst long double EPS = 1e-4;\nint r, n;\n\nint main() {\n cin >> r >> n;\n cout << fixed << setprecision(6);\n while (r != 0 || n != 0) {\n VV<int> shadow(41, V<int>(41));\n V<int> xls(n), xrs(n), hs(n);\n for (int i = 0; i < n; i++) {\n cin >> xls[i] >> xrs[i] >> hs[i];\n for (int x = xls[i] + 20; x < xrs[i] + 20; x++) {\n for (int y = 0; y < hs[i]; y++) {\n shadow[y][x] = 1;\n }\n }\n }\n // for (auto &&line : shadow) {\n // for (auto &&s : line) {\n // cout << s << \" \";\n // }\n // cout << \"\\n\";\n // }\n\n // 0.0005 ずつ yを上昇させてシミュレーション\n double t = 0.0;\n\n for (;;) {\n double new_t = t + 0.00005;\n bool ok = true;\n for (int i = -r; i <= r; i++) {\n int x = i;\n int y = floor(sqrt(r * r - x * x) - r + new_t);\n if (y < 0) continue;\n if (i == -r) {\n if (!shadow[y][x + 20]) ok = false;\n } else if (i == r) {\n if (!shadow[y][x + 20 - 1]) ok = false;\n } else if (!shadow[y][x + 20 - 1] || !shadow[y][x + 20]) {\n ok = false;\n }\n }\n if (!ok) break;\n t = new_t;\n }\n cout << t << \"\\n\";\n cin >> r >> n;\n }\n}", "accuracy": 1, "time_ms": 4010, "memory_kb": 3504, "score_of_the_acc": -1.0485, "final_rank": 13 }, { "submission_id": "aoj_1194_6027332", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\ntemplate <class T> using V = vector<T>;\ntemplate <class T> using VV = V<V<T>>;\n\nconst long double EPS = 1e-4;\nint r, n;\n\nint main() {\n cin >> r >> n;\n cout << fixed << setprecision(6);\n while (r != 0 || n != 0) {\n VV<int> shadow(41, V<int>(41));\n V<int> xls(n), xrs(n), hs(n);\n for (int i = 0; i < n; i++) {\n cin >> xls[i] >> xrs[i] >> hs[i];\n for (int x = xls[i] + 20; x < xrs[i] + 20; x++) {\n for (int y = 0; y < hs[i]; y++) {\n shadow[y][x] = 1;\n }\n }\n }\n // for (auto &&line : shadow) {\n // for (auto &&s : line) {\n // cout << s << \" \";\n // }\n // cout << \"\\n\";\n // }\n\n // 0.0005 ずつ yを上昇させてシミュレーション\n double t = 0.0;\n\n for (;;) {\n double new_t = t + 0.00005;\n bool ok = true;\n for (int i = -r; i <= r; i++) {\n int x = i;\n int y = floor(sqrt(r * r - x * x) - r + new_t);\n if (y < 0) continue;\n if (i == -r) {\n if (!shadow[y][x + 20]) ok = false;\n } else if (i == r) {\n if (!shadow[y][x + 20 - 1]) ok = false;\n } else if (!shadow[y][x + 20 - 1] || !shadow[y][x + 20]) {\n ok = false;\n }\n }\n if (!ok) break;\n t = new_t;\n }\n cout << t << \"\\n\";\n cin >> r >> n;\n }\n}", "accuracy": 1, "time_ms": 4900, "memory_kb": 3516, "score_of_the_acc": -1.1834, "final_rank": 15 }, { "submission_id": "aoj_1194_5974732", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\ntemplate<typename F>\npair<double,double> Binary(double ok, double ng, const F &isok, int m = 200){\n for(int t = 0; t < m; t++){\n double wj = ((ok - ng)/2) + ng;\n (isok(wj)?ok : ng) = wj;\n }\n return {ok, ng};\n}\n\nnamespace geometry{\n constexpr double eps = 1e-9;\n bool eq(double a, double b){ return fabs(a - b) < eps; }\n template<typename T> bool eq(T a, T b){ return a == b; }\n bool is_zero(double a){ return fabs(a) < eps; }\n template<typename T> bool is_zero(T a){ return a == 0; }\n bool le(double a, double b){ return a <= b + eps; }\n template<typename T> bool le(T a, T b){ return a <= b; }\n bool lt(double a, double b){ return a < b - eps; }\n template<typename T> bool lt(T a, T b){ return a < b; }\n};\n\n\ntemplate<class T> struct Point{\n T x,y;\n Point(){}\n Point(T x, T y) : x(x), y(y) {}\n Point(const pair<T,T> &p) : x(p.first), y(p.second) {}\n\n Point operator*(const T b) const { return Point(x * b, y * b); }\n Point operator/(const T b) const { return Point(x / b, y / b); }\n Point operator+(const Point &b) const { return Point(x + b.x, y + b.y); }\n Point operator-(const Point &b) const { return Point(x - b.x, y - b.y); }\n Point operator*(const Point &b) const { return Point(x*b.x - y*b.y, x*b.y + y*b.x); }\n Point operator/(const Point &b) const { return Point(x*b.x + y*b.y, y*b.x - x*b.y)/(b.x*b.x + b.y*b.y); }\n\n Point &operator*=(const T b){ return (*this) = (*this) * b; }\n Point &operator/=(const T b){ return (*this) = (*this) / b; }\n Point &operator+=(const Point &b){ return (*this) = (*this) + b; }\n Point &operator-=(const Point &b){ return (*this) = (*this) - b; }\n Point &operator*=(const Point &b){ return (*this) = (*this) * b; }\n Point &operator/=(const Point &b){ return (*this) = (*this) / b; }\n \n bool operator==(const Point &b) const {\n return geometry::eq(x, b.x) && geometry::eq(y, b.y);\n }\n bool operator<(const Point &b) const { \n if(geometry::eq(x, b.x)) return y < b.y;\n return x < b.x;\n }\n T Norm() const { return x * x + y * y; }\n double Abs() const { return hypot<double>(x, y); }\n double dist(const Point &b) const { return hypot<double>(x - b.x, y - b.y); }\n double arg() const { return atan2<double>(y, x); }\n \n Point ArgVec() const {\n if((*this) == Point(0, 0)) return (*this);\n if(geometry::is_zero(x)) return Point(0, -1);\n return (*this) / gcd(x, y) * (x < 0 ? -1 : 1);\n }\n\n int ort() const {\n if(geometry::is_zero(x) && geometry::is_zero(y)) return 0;\n if(geometry::is_zero(y)) return x > 0 ? 1 : 3;\n if(geometry::is_zero(x)) return y > 0 ? 2 : 4;\n if (y > 0) return x > 0 ? 1 : 2;\n else return x > 0 ? 4 : 3;\n }\n Point rotate90() const { return Point(-y, x);}\n Point rotate180() const { return Point(-x, -y);}\n Point rotate270() const { return Point(y, -x);}\n\n Point flip_x(T p = 0) const { return Point(p*2 - x, y);}\n Point flip_y(T p = 0) const { return Point(x, p*2 - y);}\n\n Point rotate(double theta) const {\n return Point(cos(theta)*x - sin(theta)*y, sin(theta)*x + cos(theta)*y);\n }\n\n Point flip(double theta) const {\n return (*this).rotate(-theta).flip_y().rotate(theta);\n }\n\n friend ostream &operator<<(ostream &os, const Point &p) {\n return os << p.x << \" \" << p.y;\n }\n friend istream &operator>>(istream &is, Point &p) {\n T a, b; is >> a >> b;\n p = Point<T>(a, b);\n return (is);\n }\n};\n\ntemplate<typename T> Point<T> Polar(const T& rho, const T& theta = 0){\n return Point<T>(rho * cos(theta), rho * sin(theta));\n}\n\n\ntemplate<typename T> using Polygon = vector<Point<T>>;\n\ntemplate<class T> T Cross(const Point<T> &a, const Point<T> &b) { return a.x * b.y - a.y * b.x; }\n\ntemplate<class T> T Dot(const Point<T> &a, const Point<T> &b) { return a.x * b.x + a.y * b.y; }\n\ntemplate<class T> bool Intersect(const Point<T> &a, const Point<T> &b, const Point<T> &c, const Point<T> &d) {\n return (iSP(a, b, c)*iSP(a, b, d) <= 0) && (iSP(c, d, a)*iSP(c, d, b) <= 0);\n}\n\ntemplate<class T> int iSP(const Point<T> &a, const Point<T> &b, const Point<T> &c){\n T fl = Cross(b-a, c-a);\n if(geometry::lt(T(0), fl)) return 1; // CCW\n if(geometry::lt(fl, T(0))) return -1; // CW\n if(geometry::lt(T(0), Dot(b-a, c-b))) return 2; //abc\n if(geometry::lt(T(0), Dot(a-b, c-a))) return -2; //bac\n return 0; // acb\n}\n\ntemplate<class T> int angletype(const Point<T> &a, const Point<T> &b, const Point<T> &c){\n T v = Dot(a-b, c-a);\n if(geometry::is_zero(v)) return 0; // right angle\n if(v > 0) return 1; // acute angle\n return -1; // obtuse angle\n}\n\ntemplate<typename T>\nbool cmp_y(const Point<T>& p1, const Point<T> &p2){\n if(p1.y == p2.y) return p1.x < p2.x;\n return p1.y < p2.y;\n}\n\ntemplate<typename T>\nbool cmp_arg(const Point<T>& p1, const Point<T> &p2){\n if(p1.ort() != p2.ort()) return p1.ort() < p2.ort();\n return iSP(Point<T>(0,0), p1, p2) > 0;\n}\n\ntemplate<typename T>\nvoid ArgSort(Polygon<T> &ps){\n sort(begin(ps), end(ps), cmp_arg<T>);\n}\n\ntemplate<class T> struct Line{\n Point<T> a, b;\n Line() {}\n Line(const Point<T> &a, const Point<T> &b): a(a), b(b) {}\n Line(T A, T B, T C){ // Ax + By = C\n if(A == 0){ a = Point<T>(0, C/B); b = Point<T>(1, C/B); }\n else if(B == 0){ a = Point<T>(C/A, 0); b = Point<T>(C/A, 1); }\n else{ a = Point<T>(0, C/B); b = Point<T>(C/A, 0); }\n }\n //Line(const Segment<T> &s): a(s.a), b(s.b) {}\n Point<T> projection(const Point<T> &p) const {\n return a + (b - a)*Dot(p - a, b - a)/(b - a).Norm();\n }\n Point<T> reflection(const Point<T> &p) const {\n return p + (projection(p) - p)*2;\n }\n int angletype(const Line &l) const {\n if(geometry::is_zero(Cross(b-a, l.b-l.a))) return 1;\n if(geometry::is_zero(Dot(a-b, l.b-l.a))) return -1;\n return 0;\n }\n bool Intersect(const Line &l) const {\n return angletype(l) != 1;\n }\n Point<T> Cross_Point(const Line &l) const {\n if(geometry::is_zero(Cross(b-a,l.b-l.a))) return l.a;\n return (b - a)*Cross(l.a - a, l.b - l.a)/Cross(b - a,l.b - l.a) + a;\n }\n double dist(const Point<T> &p) const {\n return abs(Cross(p - a, b - a)/(b - a).Abs());\n }\n double dist(const Line &l) const {\n if(Intersect(l)) return 0;\n return dist(l.a);\n }\n};\n\ntemplate<class T> struct Segment{\n Point<T> a, b;\n Segment() {}\n Segment(const Point<T> &a, const Point<T> &b): a(a), b(b) {}\n\n double length() const { return a.dist(b); }\n bool Intersect(const Segment &s) const {\n return iSP(a, b, s.a)*iSP(a, b, s.b) <= 0 && iSP(s.a, s.b, a)*iSP(s.a, s.b, b) <= 0;\n }\n Point<T> Center() const { return (a + b) / 2; }\n Line<T> PerpBisector() const {\n Point<T> center = this->Center();\n return Line<T>((a - center).rotate90() + center, center);\n }\n int angletype(const Segment &s) const {\n if(geometry::is_zero(Cross(b-a, s.b-s.a))) return 1;\n if(geometry::is_zero(Dot(a-b, s.b-s.a))) return -1;\n return 0;\n }\n Point<T> Cross_Point(const Segment &s) const {\n if(geometry::is_zero(Cross(b-a,s.b-s.a))) return s.a;\n return (b - a)*Cross(s.a - a, s.b - s.a)/Cross(b - a, s.b - s.a) + a;\n }\n double dist(const Point<T> &p) const {\n if(Dot(b-a, p-a) < 0) return p.dist(a);\n if(Dot(a-b, p-b) < 0) return p.dist(b);\n return abs(Cross(p-a, b-a)/ (b-a).Abs());\n }\n double dist(const Segment &s) const {\n if(Intersect(s)) return 0;\n return min({dist(s.a), dist(s.b), s.dist(a), s.dist(b)});\n }\n};\n\ntemplate<typename T>\nstruct Triangle{\n Point<T> a, b, c;\n Triangle() {}\n Triangle(const Point<T> &a, const Point<T> &b, const Point<T> &c): a(a), b(b), c(c){}\n\n double angle_a() const {\n double ab = a.dist(b), bc = b.dist(c), ca = c.dist(a);\n return acos((ca*ca + ab*ab - bc*bc)/(2*ca*ab));\n }\n double angle_b() const {\n double ab = a.dist(b), bc = b.dist(c), ca = c.dist(a);\n return acos((ab*ab + bc*bc - ca*ca)/(2*ab*bc));\n }\n double angle_c() const {\n double ab = a.dist(b), bc = b.dist(c), ca = c.dist(a);\n return acos((bc*bc + ca*ca - ab*ab)/(2*bc*ca));\n }\n Point<T> divpoint(double p, double q, double r) const {\n return (a*p + b*q + c*r)/(p + q + r);\n }\n\n Point<T> centerofgravity() const {\n return (a + b + c)/3;\n }\n Point<T> circumcenter() const {\n Segment<T> s1(a, b), s2(a, c);\n return s1.PerpBisector().Cross_Point(s2.PerpBisector());\n }\n Point<T> orthocenter() const {\n return centerofgravity()*3 - circumcenter()*2;\n }\n Point<T> innercenter() const {\n return divpoint(b.dist(c), c.dist(a), a.dist(b));\n }\n Point<T> excenterA() const {\n return divpoint(-b.dist(c), c.dist(a), a.dist(b));\n }\n Point<T> excenterB() const {\n return divpoint(b.dist(c), -c.dist(a), a.dist(b));\n }\n Point<T> excenterC() const {\n return divpoint(b.dist(c), c.dist(a), -a.dist(b));\n }\n};\n\ntemplate<class T> struct Circle{\n Point<T> o;\n T r;\n Circle() {}\n Circle(const Point<T> &o, const T &r): o(o), r(r) {}\n Circle(const Point<T> &a, const Point<T> &b): o((a + b)/2), r(a.dist(b)/2) {}\n Circle(const Point<T> &a, const Point<T> &b, const Point<T> &c)\n : o(Triangle(a,b,c).circumcenter()), r(o.dist(a)) {}\n\n int Intersect(const Circle&c) const {\n if(r < c.r) return c.Intersect(*this);\n auto od = (o - c.o).Norm();\n auto ra = (r + c.r)*(r + c.r), rs = (r - c.r)*(r - c.r);\n if(geometry::lt(ra, od)) return 4;\n if(geometry::eq(ra, od)) return 3;\n if(geometry::lt(rs, od)) return 2;\n if(geometry::eq(rs, od)) return 1;\n return 0;\n }\n\n int Intersect(const Line<T> &l) const {\n double d = l.dist(o);\n if(geometry::lt<double>(d, r)) return 2;\n return geometry::eq(d, r);\n }\n\n int Contains(const Point<T> &p) const {\n auto od = (o - p).Norm();\n if(geometry::eq(od, r*r)) return 1; // on\n return (od > r*r) ? 2 : 0; // out/in\n }\n\n Polygon<T> Cross_Points(const Line<T> &l) const {\n int k = this->Intersect(l);\n if(k == 0) return {};\n Point<T> p = l.projection(o);\n if(k == 1) return {p};\n Point<T> d = (l.b - l.a)/l.a.dist(l.b);\n double base = sqrt(r*r - (p - o).Norm());\n return {p + d*base, p - d*base};\n }\n\n Polygon<T> Cross_Points(const Circle &c) const {\n int k = this->Intersect(c);\n if(k == 0 || k == 4) return {};\n double t = (c.o - o).arg();\n if(k == 1 || k == 3) return {o + Polar<T>(r, t)};\n double d = o.dist(c.o), a = acos((r*r + d*d - c.r*c.r) / (r * d * 2));\n return {o + Polar<T>(r, t + a), o + Polar<T>(r, t - a)};\n }\n\n friend ostream &operator<<(ostream &os, const Circle &c) {\n return os << c.o << \" \" << c.r;\n }\n friend istream &operator>>(istream &is, Circle &c) {\n Point<T> p; T l; is >> p >> l;\n c = Circle<T>(p, l);\n return (is);\n }\n};\n\n\n\nint main() {\n cout << fixed << setprecision(12);\n \n while(true){\n int r, n; cin >> r >> n;\n if(r+n == 0) return 0;\n\n int m = 40;\n\n vector<int> h(m);\n\n for(int i = 0; i < n; ++i){\n int l, r, y; cin >> l >> r >> y;\n for(int j = l; j < r; ++j) h[j+20] = max(h[j+20], y);\n }\n\n auto f = [&](double t){\n Point<double> c(0, t-r);\n Circle<double> sun(c, r);\n\n for(int i = 0; i < m-1; ++i){\n double y = min(h[i], h[i+1]), my = max(h[i], h[i+1]);\n double x = i - 19;\n /*\n 中心が (0, t-r) のとき, x = i-19での高さ\n //*/\n if(i-19 == r && t-r <= h[i]) continue;\n if(i-19 == -r && t-r <= h[i+1]) continue;\n\n Line<double> l(1, 0, i-19);\n auto ps = sun.Cross_Points(l);\n for(auto p : ps){\n if(p.y > y) return false;\n }\n }\n return true;\n };\n\n auto[ok,ng] = Binary(0, 40, f);\n cout << ok << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3480, "score_of_the_acc": -0.4734, "final_rank": 4 }, { "submission_id": "aoj_1194_5974620", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\nint main() {\n cout << fixed << setprecision(12);\n \n while(true){\n int r, n; cin >> r >> n;\n if(r+n == 0) return 0;\n\n int m = 40;\n\n vector<int> h(m);\n\n for(int i = 0; i < n; ++i){\n int l, r, y; cin >> l >> r >> y;\n for(int j = l; j < r; ++j) h[j+20] = max(h[j+20], y);\n }\n bool fl = true;\n double t = 0;\n while(fl){\n t += 0.0001;\n for(int i = 0; i < m-1; ++i){\n int y = min(h[i], h[i+1]);\n int x = i - 19;\n\n if(hypot(x, y+r-t) < r) fl = false;\n }\n \n }\n t -= -0.0001;\n cout << t << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 3940, "memory_kb": 3556, "score_of_the_acc": -1.0908, "final_rank": 14 }, { "submission_id": "aoj_1194_5274387", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\n\ndouble p(double a) { return a * a; }\n\nbool solve() {\n int rad, n;\n cin >> rad >> n;\n if(rad + n == 0) return false;\n\n map<int, int> mp;\n for(int x = -30; x < 30; ++x) mp[x] = rad;\n rep(_, n) {\n int l, r, h;\n cin >> l >> r >> h;\n for(int i = l; i < r; ++i) {\n mp[i] = max(mp[i], h + rad);\n }\n }\n\n double t = 0, d = 0.0001;\n for(bool ng = false; ng == false && t < 30; t += d) {\n for(auto &[x, h] : mp) if(p(x) + p(t - h) < p(rad)) ng = true;\n for(auto &[x, h] : mp) if(p(x + 1) + p(t - h) < p(rad)) ng = true;\n }\n cout << fixed << setprecision(10) << t - d << '\\n';\n return true;\n}\n\nint main() {\n while(solve());\n return 0;\n}", "accuracy": 1, "time_ms": 5050, "memory_kb": 3576, "score_of_the_acc": -1.2641, "final_rank": 17 }, { "submission_id": "aoj_1194_5041185", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define INF_LL (int64)1e18\n#define INF (int32)1e9\n#define REP(i, n) for(int64 i = 0;i < (n);i++)\n#define FOR(i, a, b) for(int64 i = (a);i < (b);i++)\n#define all(x) x.begin(),x.end()\n#define fs first\n#define sc second\n\nusing int32 = int_fast32_t;\nusing uint32 = uint_fast32_t;\nusing int64 = int_fast64_t;\nusing uint64 = uint_fast64_t;\nusing PII = pair<int32, int32>;\nusing PLL = pair<int64, int64>;\n\nconst double eps = 1e-10;\n\ntemplate<typename A, typename B>inline void chmin(A &a, B b){if(a > b) a = b;}\ntemplate<typename A, typename B>inline void chmax(A &a, B b){if(a < b) a = b;}\n\ntemplate<typename T>\nvector<T> make_v(size_t a){return vector<T>(a);}\n\ntemplate<typename T,typename... Ts>\nauto make_v(size_t a,Ts... ts){\n\treturn vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));\n}\n\ntemplate<typename T,typename U,typename... V>\ntypename enable_if<is_same<T, U>::value!=0>::type\nfill_v(U &u,const V... v){u=U(v...);}\n\ntemplate<typename T,typename U,typename... V>\ntypename enable_if<is_same<T, U>::value==0>::type\nfill_v(U &u,const V... v){\n\tfor(auto &e:u) fill_v<T>(e,v...);\n}\n\ntemplate <typename F>\nclass\nFixPoint : private F\n{\npublic:\n explicit constexpr FixPoint(F&& f) noexcept\n : F{std::forward<F>(f)}\n {}\n\n template <typename... Args>\n constexpr decltype(auto)\n operator()(Args&&... args) const\n {\n return F::operator()(*this, std::forward<Args>(args)...);\n }\n}; // class FixPoint\n\n\nnamespace\n{\n template <typename F>\n inline constexpr decltype(auto)\n makeFixPoint(F&& f) noexcept\n {\n return FixPoint<F>{std::forward<F>(f)};\n }\n} // namespace\n\ntemplate<typename T>\nclass Matrix{\nprivate:\n using size_type = ::std::size_t;\n using Row = ::std::vector<T>;\n using Mat = ::std::vector<Row>;\n\n size_type R, C; // row, column\n Mat A;\n\n void add_row_to_another(size_type r1, size_type r2, const T k){ // Row(r1) += Row(r2)*k\n for(size_type i = 0;i < C;i++)\n A[r1][i] += A[r2][i]*k;\n }\n\n void scalar_multiply(size_type r, const T k){\n for(size_type i = 0;i < C;i++)\n A[r][i] *= k;\n }\n\n void scalar_division(size_type r, const T k){\n for(size_type i = 0;i < C;i++)\n A[r][i] /= k;\n }\n\npublic:\n Matrix(){}\n Matrix(size_type r, size_type c) : R(r), C(c), A(r, Row(c)) {}\n Matrix(const Mat &m) : R(m.size()), C(m[0].size()), A(m) {}\n Matrix(const Mat &&m) : R(m.size()), C(m[0].size()), A(m) {}\n Matrix(const Matrix<T> &m) : R(m.R), C(m.C), A(m.A) {}\n Matrix(const Matrix<T> &&m) : R(m.R), C(m.C), A(m.A) {}\n Matrix<T> &operator=(const Matrix<T> &m){\n R = m.R; C = m.C; A = m.A;\n return *this;\n }\n Matrix<T> &operator=(const Matrix<T> &&m){\n R = m.R; C = m.C; A = m.A;\n return *this;\n }\n static Matrix I(const size_type N){\n Matrix m(N, N);\n for(size_type i = 0;i < N;i++) m[i][i] = 1;\n return m;\n }\n\n const Row& operator[](size_type k) const& { return A.at(k); }\n Row& operator[](size_type k) & { return A.at(k); }\n Row operator[](size_type k) const&& { return ::std::move(A.at(k)); }\n\n size_type row() const { return R; } // the number of rows\n size_type column() const { return C; }\n\n T determinant(){\n assert(R == C);\n Mat tmp = A;\n T res = 1;\n for(size_type i = 0;i < R;i++){\n for(size_type j = i;j < R;j++){ // satisfy A[i][i] > 0\n if (A[j][i] != 0) {\n if (i != j) res *= -1;\n swap(A[j], A[i]);\n break;\n }\n }\n if (A[i][i] == 0) return 0;\n res *= A[i][i];\n scalar_division(i, A[i][i]);\n for(size_type j = i+1;j < R;j++){\n add_row_to_another(j, i, -A[j][i]);\n }\n }\n swap(tmp, A);\n return res;\n }\n\n Matrix inverse(){\n assert(R == C);\n assert(determinant() != 0);\n Matrix inv(Matrix::I(R)), tmp(*this);\n for(size_type i = 0;i < R;i++){\n for(size_type j = i;j < R;j++){\n if (A[j][i] != 0) {\n swap(A[j], A[i]);\n swap(inv[j], inv[i]);\n break;\n }\n }\n inv.scalar_division(i, A[i][i]);\n scalar_division(i, A[i][i]);\n for(size_type j = 0;j < R;j++){\n if(i == j) continue;\n inv.add_row_to_another(j, i, -A[j][i]);\n add_row_to_another(j, i, -A[j][i]);\n }\n }\n (*this) = tmp;\n return inv;\n }\n\n Matrix& operator+=(const Matrix &B){\n assert(column() == B.column() && row() == B.row());\n for(size_type i = 0;i < R;i++)\n for(size_type j = 0;j < C;j++)\n (*this)[i][j] += B[i][j];\n return *this;\n }\n\n Matrix& operator-=(const Matrix &B){\n assert(column() == B.column() && row() == B.row());\n for(size_type i = 0;i < R;i++)\n for(size_type j = 0;j < C;j++)\n (*this)[i][j] -= B[i][j];\n return *this;\n }\n\n Matrix& operator*=(const Matrix &B){\n assert(column() == B.row());\n Matrix M(R, B.column());\n for(size_type i = 0;i < R;i++) {\n for(size_type j = 0;j < B.column();j++) {\n M[i][j] = 0;\n for(size_type k = 0;k < C;k++) {\n M[i][j] += (*this)[i][k] * B[k][j];\n }\n }\n }\n swap(M, *this);\n return *this;\n }\n\n Matrix& operator/=(const Matrix &B){\n assert(C == B.row());\n Matrix M(B);\n (*this) *= M.inverse();\n return *this;\n }\n\n Matrix operator+(const Matrix &B) const { return (Matrix(*this) += B); }\n Matrix operator-(const Matrix &B) const { return (Matrix(*this) -= B); }\n Matrix operator*(const Matrix &B) const { return (Matrix(*this) *= B); }\n Matrix operator/(const Matrix &B) const { return (Matrix(*this) /= B); }\n\n bool operator==(const Matrix &B) const {\n if (column() != B.column() || row() != B.row()) return false;\n for(size_type i = 0;i < row();i++)\n for(size_type j = 0;j < column();j++)\n if ((*this)[i][j] != B[i][j]) return false;\n return true;\n }\n bool operator!=(const Matrix &B) const { return !((*this) == B); }\n\n Matrix pow(size_type k, int64 m){\n assert(R == C);\n Matrix M(Matrix::I(R));\n while(k){\n if (k & 1) M *= (*this);\n k >>= 1;\n (*this) *= (*this);\n REP(i, R) {\n REP(j, C) {\n A[i][j] %= m;\n M[i][j] %= m;\n }\n }\n }\n A.swap(M.A);\n return *this;\n }\n\n friend ::std::ostream &operator<<(::std::ostream &os, Matrix &p){\n for(size_type i = 0;i < p.row();i++){\n for(size_type j = 0;j < p.column();j++){\n os << p[i][j] << \" \";\n }\n os << ::std::endl;\n }\n return os;\n }\n};\n\nint main(void) {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n int64 n, r;\n while (cin >> r >> n && r + n) {\n vector<int64> h(41, 0);\n REP(i, n) {\n int64 xl, xr, hi;\n cin >> xl >> xr >> hi;\n FOR(j, xl+20, xr+20) {\n chmax(h[j], hi);\n }\n }\n\n auto ok = [&](double x) {\n REP(j, 40) {\n double offl = j - 20, offr = j - 19;\n if (j-19 <= -r || r <= j-20) continue;\n double hmax = x + r * max(sin(atan2(sqrt(r * r - offl * offl), offl)), sin(atan2(sqrt(r * r - offr * offr), offr)));\n if (hmax > h[j]) return false;\n }\n return true;\n };\n double lo = -r, hi = 21, mi;\n REP(i, 100) {\n mi = (lo + hi) / 2;\n if (ok(mi)) lo = mi;\n else hi = mi;\n }\n cout << fixed << setprecision(10) << lo + r << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4008, "score_of_the_acc": -1, "final_rank": 12 }, { "submission_id": "aoj_1194_4968746", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int (i)=0;(i)<(n);(i)++)\n#define rrep(i,n) for(int (i)=((n)-1);(i)>=0;(i)--)\n#define itn int\n#define miele(v) min_element(v.begin(), v.end())\n#define maele(v) max_element(v.begin(), v.end())\n#define SUM(v) accumulate(v.begin(), v.end(), 0LL)\n#define lb(a, key) lower_bound(a.begin(),a.end(),key)\n#define ub(a, key) upper_bound(a.begin(),a.end(),key)\n#define COUNT(a, key) count(a.begin(), a.end(), key) \n#define BITCOUNT(x) __builtin_popcount(x)\n#define pb push_back\n#define all(x) (x).begin(),(x).end()\n#define F first\n#define S second\nusing P = pair <int,int>;\nusing WeightedGraph = vector<vector <P>>;\nusing UnWeightedGraph = vector<vector<int>>;\nusing Real = long double;\nusing Point = complex<Real>; //Point and Vector2d is the same!\nusing Vector2d = complex<Real>;\nconst long long INF = 1LL << 60;\nconst int MOD = 1000000007;\nconst double EPS = 1e-15;\nconst double PI=3.14159265358979323846;\ntemplate <typename T> \nint getIndexOfLowerBound(vector <T> &v, T x){\n return lower_bound(v.begin(),v.end(),x)-v.begin();\n}\ntemplate <typename T> \nint getIndexOfUpperBound(vector <T> &v, T x){\n return upper_bound(v.begin(),v.end(),x)-v.begin();\n}\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }\n#define DUMPOUT cerr\n#define repi(itr, ds) for (auto itr = ds.begin(); itr != ds.end(); itr++)\nistream &operator>>(istream &is, Point &p) {\n Real a, b; is >> a >> b; p = Point(a, b); return is;\n}\ntemplate <typename T, typename U>\nistream &operator>>(istream &is, pair<T,U> &p_var) {\n is >> p_var.first >> p_var.second;\n return is;\n}\ntemplate <typename T>\nistream &operator>>(istream &is, vector<T> &vec) {\n for (T &x : vec) is >> x;\n return is;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, pair<T, U> &pair_var) {\n DUMPOUT<<'{';\n os << pair_var.first;\n DUMPOUT<<',';\n os << \" \"<< pair_var.second;\n DUMPOUT<<'}';\n return os;\n}\ntemplate <typename T>\nostream &operator<<(ostream &os, vector<T> &vec) {\n DUMPOUT<<'[';\n for (int i = 0; i < vec.size(); i++) \n os << vec[i] << (i + 1 == vec.size() ? \"\" : \" \");\n DUMPOUT<<']';\n return os;\n}\ntemplate <typename T>\nostream &operator<<(ostream &os, vector<vector<T>> &df) {\n for (auto& vec : df) os<<vec;\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, map<T, U> &map_var) {\n DUMPOUT << \"{\";\n repi(itr, map_var) {\n os << *itr;\n itr++;\n if (itr != map_var.end()) DUMPOUT << \", \";\n itr--;\n }\n DUMPOUT << \"}\";\n return os;\n}\ntemplate <typename T>\nostream &operator<<(ostream &os, set<T> &set_var) {\n DUMPOUT << \"{\";\n repi(itr, set_var) {\n os << *itr;\n itr++;\n if (itr != set_var.end()) DUMPOUT << \", \";\n itr--;\n }\n DUMPOUT << \"}\";\n return os;\n}\nvoid print() {cout << endl;}\ntemplate <class Head, class... Tail>\nvoid print(Head&& head, Tail&&... tail) {\n cout << head;\n if (sizeof...(tail) != 0) cout << \" \";\n print(forward<Tail>(tail)...);\n}\nvoid dump_func() {DUMPOUT << '#'<<endl;}\ntemplate <typename Head, typename... Tail>\nvoid dump_func(Head &&head, Tail &&... tail) {\n DUMPOUT << head;\n if (sizeof...(Tail) > 0) DUMPOUT << \", \";\n dump_func(std::move(tail)...);\n}\n#ifdef DEBUG_\n#define DEB\n#define dump(...) \\\n DUMPOUT << \" \" << string(#__VA_ARGS__) << \": \" \\\n << \"[\" << to_string(__LINE__) << \":\" << __FUNCTION__ << \"]\" \\\n << endl \\\n << \" \", \\\n dump_func(__VA_ARGS__)\n#else\n#define DEB if (false)\n#define dump(...)\n#endif\n\nint main(void) { cin.tie(0); ios::sync_with_stdio(false);\n while(1){\n double r; int n; \n cin>>r>>n;\n if(r == 0 && n == 0) exit(0);\n vector <tuple <double,double,double>> p(n);\n double d = (r+r)/100000;\n for(int i=0;i<n;i++){\n int x1, x2, h;\n cin>>x1>>x2>>h;\n p[i] = {x1, x2, h};\n }\n double ans = 1145141919;\n for(double i=-r;i<=r;i+=d){\n double height = 0;\n for(int j=0;j<n;j++){\n if(get <0>(p[j]) <= i && get <1>(p[j]) >= i) chmax(height, get <2>(p[j]));\n }\n chmin(ans, height - (sqrt(r*r - i*i) - r));\n }\n printf(\"%.4f\\n\", ans);\n }\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3532, "score_of_the_acc": -0.5378, "final_rank": 7 }, { "submission_id": "aoj_1194_4958010", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(i, n) for(int i = 0; i < n; i++)\nusing namespace std;\n\ntypedef long long ll;\n\nconst int INF = 1 << 30;\nconst ll LLINF = 1LL << 62;\n\nconst double eps = 0.00001;\n\nint mod = 1000000007;\n\ndouble deg_to_rad(double deg){\n return deg * M_PI / 180;\n}\n\ndouble calcheight(vector<pair<pair<double, double>, double>>& towers, double x){\n double ret = 0;\n rep(i, towers.size()){\n if(towers[i].first.first <= x && x <= towers[i].first.second) ret = max(ret, towers[i].second);\n }\n return ret;\n}\n\nint main(void){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n vector<double> ans;\n while(true){\n double R; int N; cin >> R >> N;\n if(R <= 0 && N == 0) break;\n vector<pair<pair<double, double>, double>> towers(N);\n rep(i, N) cin >> towers[i].first.first >> towers[i].first.second >> towers[i].second;\n double ok = 0, ng = 1000;\n double m = (ok+ng)/2;\n while(abs(ok-ng) > eps){\n double c = m - R;\n double inc = 0.002;\n double nowDeg = 0;\n bool hide = true;\n\n while(nowDeg <= 180){\n bool res;\n double x = R * cos(deg_to_rad(nowDeg));\n double y = m - R + R * sin(deg_to_rad(nowDeg));\n double height = calcheight(towers, x);\n\n //cout << \"deg: \" << nowDeg << \", \" << y << \" \" << height << endl;\n if(height < y){\n hide = false;\n break;\n }\n nowDeg += inc;\n }\n if(hide) ok = m;\n else ng = m;\n m = (ok+ng)/2;\n }\n ans.push_back(ok);\n }\n rep(i, ans.size()) printf(\"%.6f\\n\", ans[i]);\n return 0;\n}", "accuracy": 1, "time_ms": 4840, "memory_kb": 3836, "score_of_the_acc": -1.4951, "final_rank": 18 } ]
aoj_1195_cpp
Encryption System A programmer developed a new encryption system. However, his system has an issue that two or more distinct strings are `encrypted' to the same string. We have a string encrypted by his system. To decode the original string, we want to enumerate all the candidates of the string before the encryption. Your mission is to write a program for this task. The encryption is performed taking the following steps. Given a string that consists only of lowercase letters ('a' to 'z'). Change the first 'b' to 'a'. If there is no 'b', do nothing. Change the first 'c' to 'b'. If there is no 'c', do nothing. ... Change the first 'z' to 'y'. If there is no 'z', do nothing. Input The input consists of at most 100 datasets. Each dataset is a line containing an encrypted string. The encrypted string consists only of lowercase letters, and contains at least 1 and at most 20 characters. The input ends with a line with a single '#' symbol. Output For each dataset, the number of candidates n of the string before encryption should be printed in a line first, followed by lines each containing a candidate of the string before encryption. If n does not exceed 10, print all candidates in dictionary order; otherwise, print the first five and the last five candidates in dictionary order. Here, dictionary order is recursively defined as follows. The empty string comes the first in dictionary order. For two nonempty strings x = x 1 ... x k and y = y 1 ... y l , the string x precedes the string y in dictionary order if x 1 precedes y 1 in alphabetical order ('a' to 'z'), or x 1 and y 1 are the same character and x 2 ... x k precedes y 2 ... y l in dictionary order. Sample Input enw abc abcdefghijklmnopqrst z # Output for the Sample Input 1 fox 5 acc acd bbd bcc bcd 17711 acceeggiikkmmooqqssu acceeggiikkmmooqqstt acceeggiikkmmooqqstu acceeggiikkmmooqrrtt acceeggiikkmmooqrrtu bcdefghijklmnopqrrtt bcdefghijklmnopqrrtu bcdefghijklmnopqrssu bcdefghijklmnopqrstt bcdefghijklmnopqrstu 0
[ { "submission_id": "aoj_1195_10848117", "code_snippet": "#include <stdio.h>\n#include <memory.h>\n#include <string.h>\n#define MAX 30\n\nchar ch[MAX], p[MAX];\nint len, b[MAX], ac[30], cnt;\nchar ch2[1050000][22];\n\nvoid dfs(int now, int sw){\n\tint i;\n\tb[now]=sw;\n\tif (now==len){\n\t\tfor (i=1;i<=len;i++){\n\t\t\tp[i]=ch[i];\n\t\t\tif (b[i]) p[i]++;\n\t\t}\n\t\tmemset(ac, 0, sizeof(ac));\n\t\tint flag=0;\n\t\tfor (i=1;i<=len;i++){\n\t\t\tif (ac[p[i]-'a']){\n\t\t\t\tif (p[i]!=ch[i]){\n\t\t\t\t\tflag=1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}else{\n\t\t\t\tac[p[i]-'a']=1;\n\t\t\t\tif (p[i]-1!=ch[i] && p[i]!='a'){\n\t\t\t\t\tflag=1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (flag==0){\n\t\t\tcnt++;\n\t\t\tfor (i=1;i<=len;i++) ch2[cnt][i]=p[i];\n\t\t}\n\t}else{\n\t\tdfs(now+1, 0);\n\t\tif (ch[now+1]!='z') dfs(now+1, 1);\n\t}\n}\n\nint main(void){\n\tint i,j;\n\tfor (;;){\n\t\tscanf(\"%s\", &ch[1]);\n\t\tif (ch[1]=='#') break;\n\t\tlen=strlen(&ch[1]);\n\t\tdfs(1, 0);\n\t\tif (ch[1]!='z') dfs(1, 1);\n\t\tprintf(\"%d\\n\", cnt);\n\t\tif (cnt>=10){\n\t\t\tfor (i=1;i<=5;i++) printf(\"%s\\n\", &ch2[i][1]);\n\t\t\tfor (i=cnt-4;i<=cnt;i++) printf(\"%s\\n\", &ch2[i][1]);\n\t\t}else{\n\t\t\tfor (i=1;i<=cnt;i++) printf(\"%s\\n\", &ch2[i][1]);\n\t\t}\n\t\tfor (i=1;i<=cnt;i++){\n\t\t\tfor (j=1;j<=len;j++) ch2[i][j]=0;\n\t\t}\n\t\tcnt=0;\n\n\t}\n\treturn false;\n}", "accuracy": 1, "time_ms": 1630, "memory_kb": 3196, "score_of_the_acc": -0.2028, "final_rank": 2 }, { "submission_id": "aoj_1195_10801516", "code_snippet": "#include <bits/stdc++.h>\n#define Mid (l + r >> 1)\n#define lson (rt << 1)\n#define rson (rt << 1 | 1)\nusing namespace std;\nint read() {\n\tchar c; int num, f = 1;\n\twhile(c = getchar(),!isdigit(c)) if(c == '-') f = -1; num = c - '0';\n\twhile(c = getchar(), isdigit(c)) num = num * 10 + c - '0';\n\treturn f * num;\n}\nstring s;\nvector<string> v;\nvoid dfs(char c) {\n\tif(c == 'a' - 1) {\n\t\tv.push_back(s);\n\t\treturn ;\n\t}\n\tint f = 0;\n\tfor(int i = 0; i < s.size(); i++) {\n\t\tif(s[i] == c + 1) {\n\t\t\tf = 1;\n\t\t\tbreak;\n\t\t} else if(s[i] == c) {\n\t\t\ts[i] = c + 1;\n\t\t\tdfs(c - 1);\n\t\t\ts[i] = c;\n\t\t}\n\t}\n\tif(!f) dfs(c - 1);\n}\nvoid work() {\n\tif(s.size() == 1 && s[0] == '#') exit(0);\n\tv.clear();\n\tdfs('y');\n\tsort(v.begin(), v.end());\n\tcout << v.size() << endl;\n\tif(v.size() <= 10) {\n\t\tfor(auto x : v)\n\t\t\tcout << x << endl;\n\t} else {\n\t\tfor(int i = 0; i < 5; i++)\n\t\t\tcout << v[i] << endl;\n\t\tfor(int i = v.size() - 5; i < v.size(); i++)\n\t\t\tcout << v[i] << endl;\n\t}\n}\nsigned main()\n{\n\twhile(cin >> s) work();\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4568, "score_of_the_acc": -0.4561, "final_rank": 9 }, { "submission_id": "aoj_1195_10612579", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\n#define all(v) v.begin(), v.end()\n#define rall(a) a.rbegin(), a.rend()\n#define fi first\n#define se second\n#define endl \"\\n\"\n\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\n\ntemplate <typename T>\nusing vc = vector<T>; // prioriy_queueに必要なのでここにこれ書いてます\ntemplate <typename T>\nusing vv = vc<vc<T>>;\n#define int long long\nusing ll = long long;\nll INF = 2e18;\n\n#ifdef ONLINE_JUDGE\n// ジャッジ環境ではデバッグマクロを無効化\n#define debug_x(x) \\\n do \\\n { \\\n } while (0)\n#define debug_vc(v) \\\n do \\\n { \\\n } while (0)\n#define debug_vv(v) \\\n do \\\n { \\\n } while (0)\n#else\n// ローカルではデバッグ出力\n#define debug_x(x) cout << #x << \" = \" << (x) << endl\n#define debug_vc(v) \\\n { \\\n cout << #v << endl; \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << ' '; \\\n cout << endl; \\\n } // 一次元配列を出力する\n#define debug_vv(v) \\\n { \\\n cout << #v << endl; \\\n ll n = size(v); \\\n rep(i, n) \\\n { \\\n rep(j, size(v[i])) { cout << v[i][j] << ' '; } \\\n cout << endl; \\\n } \\\n } // 二次元配列を出力する\n#endif\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n#define rrep(i, n) for (ll i = 1; i <= (n); ++i)\n#define drep(i, n) for (ll i = (n) - 1; i >= 0; --i)\n#define nfor(i, s, n) for (ll i = s; i < n; i++) // i=s,s+1...n-1 ノーマルfor\n#define dfor(i, s, n) for (ll i = (s) - 1; i >= n; i--) // s-1スタートでnまで落ちる\n\nusing ld = long double;\nusing bl = bool;\n\ntemplate <class T>\nusing pq = priority_queue<T, vc<T>>; // 大きい順\ntemplate <class T>\nusing pq_g = priority_queue<T, vc<T>, greater<T>>; // 小さい順\n\nusing vl = vc<ll>;\nusing vvl = vv<ll>;\nusing vvvl = vv<vl>;\nusing vvvvl = vv<vvl>;\nusing vs = vc<string>;\nusing vvs = vv<string>;\nusing vb = vc<bl>;\nusing vvb = vv<bl>;\nusing vvvb = vv<vb>;\nusing vld = vc<ld>;\nusing vvld = vv<ld>;\nusing vvvld = vv<vld>;\nusing P = pair<ll, ll>;\nusing vP = vc<P>;\nusing vvP = vc<vP>;\nusing vvvP = vv<vP>;\n\n#define pb push_back\n\n#define YES cout << \"Yes\" << endl\n#define NO cout << \"No\" << endl\n#define YN \\\n { \\\n cout << \"Yes\" << endl; \\\n } \\\n else \\\n { \\\n cout << \"No\" << endl; \\\n } // if(a==b)YN;\n#define dame cout << -1 << endl\n\nstring dir = \"DRUL\"; // 第4象限の場合\nvl di = {1, 0, -1, 0}; // vl di={1,1,0,-1,-1,-1,0,1};\nvl dj = {0, 1, 0, -1}; // vl dj={0,1,1,1,0,-1,-1,-1};\n\nbool out_grid(ll i, ll j, ll h, ll w)\n{ // trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\nbl solve()\n{\n string s;\n cin >> s;\n if (s == \"#\")\n return 0;\n ll n = s.size();\n vvs t(n + 1);\n t[0].pb({\"\"});\n rep(i, n)\n {\n char x = s[i];\n rep(j, t[i].size())\n {\n string st = t[i][j];\n bl include = false;\n rep(k, st.size())\n {\n if (st[k] == x)\n {\n include = true;\n break;\n }\n }\n if (include||x=='a')\n {\n string nex = st;\n nex += x;\n t[i + 1].pb(nex);\n if (x != 'z')\n {\n bl ok = true;\n rep(k, st.size())\n {\n if (st[k] == x + 1)\n {\n ok = false;\n break;\n }\n }\n if (!ok)\n continue;\n string nex2 = st;\n nex2 += (x + 1);\n t[i + 1].pb(nex2);\n }\n }\n else\n {\n if (x == 'z')\n continue;\n bl ok = true;\n rep(k, st.size())\n {\n if (st[k] == x + 1)\n {\n ok = false;\n break;\n }\n }\n if (!ok)\n continue;\n string nex = st;\n nex += (x + 1);\n t[i + 1].pb(nex);\n }\n }\n }\n // debug_vv(t);\n // rep(i, 25)\n // {\n // char tar = 'a' + i;\n // char prev = tar + 1;\n // vs cand;\n // for (auto t : st)\n // {\n // rep(j, t.size())\n // {\n // if (t[j] == tar)\n // {\n // t[j] = prev;\n // cand.pb(t);\n // t[j] = tar;\n // break;\n // }\n // }\n // }\n // rep(j, cand.size())\n // {\n // string tmp = cand[j];\n // rep(k, 25)\n // {\n // char tar = 'a' + k + 1;\n // char nex = tar - 1;\n // rep(l, tmp.size())\n // {\n // if (tmp[l] == tar)\n // {\n // tmp[l] = nex;\n // break;\n // }\n // }\n // // if (i < 3)\n // // {\n // // cout << i << endl;\n // // cout << t << endl;\n // // }\n // }\n // if (tmp == s)\n // {\n // // cout << \"ERIRIRIRIRIIRIIIIIII\" << t << endl;\n // st.insert(cand[j]);\n // }\n // }\n // }\n // vs elimi;\n // for (auto t : st)\n // {\n // // cout << \"start is\" << t << endl;\n // string start = t;\n // rep(i, 25)\n // {\n // char tar = 'a' + i + 1;\n // char nex = tar - 1;\n // rep(j, t.size())\n // {\n // if (t[j] == tar)\n // {\n // t[j] = nex;\n // break;\n // }\n // }\n // // if (i < 3)\n // // {\n // // cout << i << endl;\n // // cout << t << endl;\n // // }\n // }\n // if (t != s)\n // {\n // // cout << \"ERIRIRIRIRIIRIIIIIII\" << t << endl;\n // elimi.pb(start);\n // }\n // }\n // rep(i, elimi.size())\n // {\n // // cout << elimi[i] << endl;\n // st.erase(elimi[i]);\n // }\n cout << t[n].size() << endl;\n if (t[n].size() <= 10)\n {\n rep(i,t[n].size()){\n cout << t[n][i] << endl;\n }\n }\n else\n {\n for(ll i=0;i<5;i++){\n cout << t[n][i] << endl;\n }\n for(ll i=t[n].size()-5;i<t[n].size();i++){\n cout << t[n][i] << endl;\n }\n }\n return 1;\n}\n\nsigned main()\n{\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n while (true)\n {\n if (!solve())\n break;\n }\n return 0;\n}\n\n/*\nshift+alt+Fで成形\nf2で変数名変更\n\nスニペット\nbasic\n m:atcoder以外用\n ma:ABC/ARC用\n mahc:AHC用\nmath\n floor:床関数\n ceil:天井関数\n comv:二項係数\n modpow: a^b mod m\n GCD:最大公約数\n extGCD:拡張ユークリッド互除法\n PFD:素因数分解\n isprime:エラトステネスの篩\n matrixpow:行列累乗\ndata_structure\n seg:セグメント木\ntechnic\n Compress:座標圧縮\n runlength:ランレングス圧縮\ngraph\n warshall:ワーシャルフロイド法\n dfs:深さ優先探索\n bfs:幅優先探索\n LCA:最近共通祖先\n*/", "accuracy": 1, "time_ms": 20, "memory_kb": 6204, "score_of_the_acc": -1.0013, "final_rank": 16 }, { "submission_id": "aoj_1195_10556325", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef int ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rrep(i,start,end) for (ll i = start;i >= (ll)(end);i--)\n#define repn(i,end) for(ll i = 0; i <= (ll)(end); i++)\n#define reps(i,start,end) for(ll i = start; i < (ll)(end); i++)\n#define repsn(i,start,end) for(ll i = start; i <= (ll)(end); i++)\n#define each(p,a) for(auto &p:a)\ntypedef vector<ll> vll;\ntypedef vector<pair<ll ,ll>> vpll;\ntypedef vector<vector<ll>> vvll;\ntypedef set<ll> sll;\ntypedef map<ll , ll> mpll;\ntypedef pair<ll ,ll> pll;\ntypedef tuple<ll , ll , ll> tpl3;\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define Str(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define Ch(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define all(a) (a).begin(),(a).end()\n#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define sz(x) (ll)x.size()\n// << std::fixed << std::setprecision(10)\nconst ll INF = 1LL << 30;\nconst ld EPS = 1e-9;\n \nll lceil(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b)+1;}else{return -((-a)/b);}}\nll lfloor(ll a,ll b){if(a%b==0){return a/b;}if(a>=0){return (a/b);}else{return -((-a)/b)-1;}}\ninline ll positive_mod(ll a,ll m){return (a % m + m)%m;}\ninline ll popcnt(ull a){ return __builtin_popcountll(a);}\n//0indexed\ninline ll topbit(ll a){assert(a != 0);return 63 - __builtin_clzll(a);}\ninline ll smlbit(ll a){assert(a != 0);return __builtin_ctzll(a);}\ntemplate<class T> bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;}\ntemplate<class T> bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> std::istream &operator>>(std::istream&is,std::vector<T>&v){for(T &in:v){is>>in;}return is;}\ntemplate<typename T> std::ostream &operator<<(std::ostream&os,const std::vector<T>&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?\" \":\"\");}return os;}\ntemplate<typename T1, typename T2>std::ostream &operator<< (std::ostream &os, std::pair<T1,T2> p){os << \"{\" << p.first << \",\" << p.second << \"}\";return os;}\ntemplate<class... T>void input(T&... a){(cin >> ... >> a);}\nvoid print(){cout << endl;}\ntemplate<class T, class... Ts>void print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;}\ntemplate<class T> void pspace(const T& a){ cout << a << ' ';}\nvoid perr(){cerr << endl;}\ntemplate<class T, class... Ts>void perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;}\nvoid yes(bool i = true){ return print(i?\"yes\":\"no\"); }\nvoid Yes(bool i = true){ return print(i?\"Yes\":\"No\"); }\nvoid YES(bool i = true){ return print(i?\"YES\":\"NO\"); }\ntemplate <class T> vector<T> &operator++(vector<T> &v) {for(auto &e : v) e++;return v;}\ntemplate <class T> vector<T> operator++(vector<T> &v, signed) {auto res = v;for(auto &e : v) e++;return res;}\ntemplate <class T> vector<T> &operator--(vector<T> &v) {for(auto &e : v) e--;return v;}\ntemplate <class T> vector<T> operator--(vector<T> &v, signed) {auto res = v;for(auto &e : v) e--;return res;}\n//grid探索用\nvector<ll> _ta = {0,0,1,-1,1,1,-1,-1};\nvector<ll> _yo = {1,-1,0,0,1,-1,1,-1};\nbool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);}\n \nll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;}\nll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} \nconst ll MOD9 = 998244353LL;\nconst ll MOD10 = 1000000007LL;\n\npair<ll,set<string>> myans(string s){\n //答えの型注意\n ll n = sz(s);\n set<string> mae;\n set<string> usi;\n auto check = [&](string &t){\n vll fin(26,-1);\n // string u = t;\n rep(i,sz(t)){\n ll v= t[i]-'a';\n if(fin[v] == -1 && v != 0){\n fin[v] = i ;\n t[i] = char('a'+v-1);\n }\n }\n bool same = t == s;\n rep(i,26)if(fin[i]!= -1){\n ll v= t[fin[i]]-'a';\n t[fin[i]] = char('a' + v+1);\n }\n return same;\n };\n ll ans = 0;\n rep(i,1 << n){\n string t = \"\";\n bool able = true;\n rep(j,n){\n //次にする\n if(i >> j & 1){\n if(s[j] == 'z'){\n able = false;\n }else{\n t += char('a'+(s[j]-'a')+1);\n }\n }else{\n t += s[j];\n }\n }\n if(!able)continue;\n \n if(check(t)){\n ans++;\n mae.insert(t);\n while(sz(mae) > 5){\n mae.erase(*mae.rbegin());\n }\n usi.insert(t);\n while(sz(usi) > 5){\n usi.erase(*usi.begin());\n }\n }\n }\n set<string> ret = mae;\n each(p,usi){\n ret.insert(p);\n }\n // cout << ans << endl;\n // each(p,ret){\n // cout << p << endl;\n // }\n return {ans,ret};\n}\n\n\nint main(){\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true) {\n string s;\n cin >> s;\n if (s == \"#\") break;\n auto [ans,ret] = myans(s);\n cout << ans << endl;\n each(p,ret){\n cout << p << endl;\n }\n }\n // string t = \"acd\";\n // cout << encode(t) << endl;\n}", "accuracy": 1, "time_ms": 7050, "memory_kb": 3456, "score_of_the_acc": -0.9675, "final_rank": 15 }, { "submission_id": "aoj_1195_10447118", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\nconstexpr int SIZ = 26;\n\nvector<string> ans;\nvoid dfs(string cur, string& S, vector<bool> shifted) {\n if (cur.size() == S.size()) {\n ans.push_back(cur);\n return;\n }\n\n const int pos = static_cast<int>(cur.size());\n if (shifted[S[pos] - 'a'] || S[pos] == 'a') {\n cur.push_back(S[pos]);\n dfs(cur, S, shifted);\n cur.pop_back();\n }\n\n if (S[pos] != 'z') {\n if (shifted[S[pos] + 1 - 'a']) {\n return;\n }\n shifted[S[pos] + 1 - 'a'] = true;\n cur.push_back(static_cast<char>(S[pos] + 1));\n dfs(cur, S, shifted);\n cur.pop_back();\n shifted[S[pos] + 1 - 'a'] = false;\n }\n}\n\nint main() {\n while (true) {\n string S;\n cin >> S;\n if (S == \"#\") {\n break;\n }\n\n ans.clear();\n vector shifted(SIZ, false);\n dfs(\"\", S, shifted);\n\n ranges::sort(ans);\n ans.erase(ranges::unique(ans).begin(), ans.end());\n\n const int n = static_cast<int>(ans.size());\n cout << n << endl;\n if (n <= 10) {\n for (int i = 0; i < n; i++) {\n cout << ans[i] << endl;\n }\n } else {\n for (int i = 0; i < 5; i++) {\n cout << ans[i] << endl;\n }\n for (int i = n - 5; i < n; i++) {\n cout << ans[i] << endl;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4952, "score_of_the_acc": -0.585, "final_rank": 10 }, { "submission_id": "aoj_1195_10447112", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\nconstexpr int SIZ = 26;\n\nvector<string> ans;\nvoid solve(string cur, string& S, vector<bool> used) {\n if (cur.size() == S.size()) {\n ans.push_back(cur);\n return;\n }\n\n const int id = static_cast<int>(cur.size());\n if (used[S[id] - 'a'] || S[id] == 'a') {\n cur.push_back(S[id]);\n solve(cur, S, used);\n cur.pop_back();\n }\n\n if (S[id] != 'z') {\n if (used[S[id] + 1 - 'a']) {\n return;\n }\n used[S[id] + 1 - 'a'] = true;\n cur.push_back(char(S[id] + 1));\n solve(cur, S, used);\n cur.pop_back();\n used[S[id] + 1 - 'a'] = false;\n }\n}\n\nint main() {\n while (true) {\n string S;\n cin >> S;\n if (S == \"#\") {\n break;\n }\n\n ans.clear();\n vector used(SIZ, false);\n solve(\"\", S, used);\n\n ranges::sort(ans);\n ans.erase(ranges::unique(ans).begin(), ans.end());\n\n const int n = static_cast<int>(ans.size());\n cout << n << endl;\n if (n <= 10) {\n for (int i = 0; i < n; i++) {\n cout << ans[i] << endl;\n }\n } else {\n for (int i = 0; i < 5; i++) {\n cout << ans[i] << endl;\n }\n for (int i = n - 5; i < n; i++) {\n cout << ans[i] << endl;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4952, "score_of_the_acc": -0.585, "final_rank": 10 }, { "submission_id": "aoj_1195_10272480", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define all(a) a.begin(),a.end()\n#define reps(i, a, n) for (int i = (a); i < (int)(n); i++)\n#define rep(i, n) reps(i, 0, n)\n#define rreps(i, a, n) for (int i = (a); i > (int)(n); i--)\nconst long long mod = 1000000007;\nconst long long INF = 1e18;\nll myceil(ll a, ll b) {return (a+b-1)/b;}\n\n\nstring s;\nint n;\nvector<string> ans(0);\n\n\nvoid f(int st, string t) {\n if (st == -1) {\n ans.push_back(t);\n return;\n }\n\n int fl = 0;\n rep(i,n) {\n if (t[i] == 'a'+st) {\n fl++;\n t[i]++;\n f(st-1,t);\n t[i]--;\n }\n else if (t[i] == 'a'+st+1) {\n return;\n }\n }\n\n f(st-1,t);\n \n}\n\n\nvoid solve() {\n ans.resize(0);\n n = s.length();\n\n f(24,s);\n\n sort(all(ans));\n\n cout << ans.size() << endl;\n if (ans.size() >= 11) {\n rep(i,5) {\n cout << ans[i] << endl;\n }\n rep(i,5) {\n cout << ans[ans.size()+i-5] << endl;\n }\n }\n else {\n rep(i,ans.size()) {\n cout << ans[i] << endl;\n }\n }\n return;\n\n\n}\n\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n\n while (cin >> s && s != \"#\") {\n solve();\n }\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4500, "score_of_the_acc": -0.4348, "final_rank": 6 }, { "submission_id": "aoj_1195_10272414", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n// #pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = acos(-1.0);\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\ntemplate<typename T> void view(const vv<T>& vv){ for(const auto& v : vv){ view(v); } }\nvc<string> tot;\nstring S;\nvoid f(int c){\n if (c == 0){\n tot.push_back(S);\n return;\n }\n \n rep(i, len(S)){\n if (S[i] == 'a' + c) return;\n if (S[i] == 'a' + c - 1){\n S[i]++;\n f(c - 1);\n S[i]--;\n }\n }\n f(c - 1);\n}\nvoid solve(){\n tot.clear();\n f(25);\n sort(all(tot));\n cout << len(tot) << endl;\n if (len(tot) < 10){\n for (auto x : tot) cout << x << endl;\n }else{\n rep(i, 5) cout << tot[i] << endl;\n srep(i, len(tot) - 5, len(tot)) cout << tot[i] << endl;\n }\n}\n\nint main(){\n while (true){\n cin >> S;\n if (S == \"#\") break;\n solve();\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4540, "score_of_the_acc": -0.4468, "final_rank": 8 }, { "submission_id": "aoj_1195_9704774", "code_snippet": "#include <bits/stdc++.h>\n using namespace std;\n \n template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\n template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n #define rep(i,n) for (int i = 0; i < (n); ++i)\n\n typedef long long ll;\n typedef unsigned long long ull;\n using P=pair<ll,ll>;\n using tp=tuple<ll,ll,ll>;\n const int INF=1001001001;\n const ll INFL=1e18;\n const int mod=998244353;\n\n\tbool check(string s,string target){\n\t\tint n=s.size();\n\t\tfor(char c='b';c<='z';c++){\n\t\t\trep(i,n){\n\t\t\t\tif(s[i]==c){\n\t\t\t\t\ts[i]=c-1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn s==target;\n\t}\n\n\tvoid dfs(int i,string& s,string& target,vector<string>& t){\n\t\tint n=s.size();\n\t\tif(i==s.size()){\n\t\t\tif(check(s,target))t.push_back(s);\n\t\t\treturn;\n\t\t}\n\t\tdfs(i+1,s,target,t);\n\t\ts[i]+=1;\n\t\tdfs(i+1,s,target,t);\n\t\ts[i]-=1;\n\t}\n bool solve(){\n\t\tstring s;\n\t\tcin>>s;\n\t\tif(s==\"#\")return false;\n\n\t\tvector<string>t;\n\t\tstring target=s;\n\t\tdfs(0,s,target,t);\n\t\tsort(t.begin(),t.end());\n\n\t\tint T=t.size();\n\t\tcout<<T<<endl;\n\t\tif(T>10){\n\t\t\trep(i,5){\n\t\t\t\tcout<<t[i]<<endl;\n\t\t\t}\n\t\t\trep(i,5){\n\t\t\t\tcout<<t[T-5+i]<<endl;\n\t\t\t}\n\t\t}else{\n\t\t\trep(i,T){\n\t\t\t\tcout<<t[i]<<endl;\n\t\t\t}\n\t\t}\n\t\t\n\t\treturn true;\n }\n\n int main(){\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n\t\twhile(1){\n\t\t\tif(!solve())break;\n\t\t}\n\t\t\n return 0;\n }", "accuracy": 1, "time_ms": 6620, "memory_kb": 4968, "score_of_the_acc": -1.4164, "final_rank": 18 }, { "submission_id": "aoj_1195_9529179", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\ntemplate <unsigned mod = 1000000007> struct fp {\n unsigned v;\n static constexpr int get_mod() {\n return mod;\n }\n constexpr unsigned inv() const {\n assert(v != 0);\n int x = v, y = mod, p = 1, q = 0, t = 0, tmp = 0;\n while (y > 0) {\n t = x / y;\n x -= t * y, p -= t * q;\n tmp = x, x = y, y = tmp;\n tmp = p, p = q, q = tmp;\n }\n if (p < 0)\n p += mod;\n return p;\n }\n constexpr fp(ll x = 0) : v(x >= 0 ? x % mod : (mod - (-x) % mod) % mod) {}\n fp operator-() const {\n return fp() - *this;\n }\n fp pow(ull t) {\n fp res = 1, b = *this;\n while (t) {\n if (t & 1)\n res *= b;\n b *= b;\n t >>= 1;\n }\n return res;\n }\n fp &operator+=(const fp &x) {\n if ((v += x.v) >= mod)\n v -= mod;\n return *this;\n }\n fp &operator-=(const fp &x) {\n if ((v += mod - x.v) >= mod)\n v -= mod;\n return *this;\n }\n fp &operator*=(const fp &x) {\n v = ull(v) * x.v % mod;\n return *this;\n }\n fp &operator/=(const fp &x) {\n v = ull(v) * x.inv() % mod;\n return *this;\n }\n fp operator+(const fp &x) const {\n return fp(*this) += x;\n }\n fp operator-(const fp &x) const {\n return fp(*this) -= x;\n }\n fp operator*(const fp &x) const {\n return fp(*this) *= x;\n }\n fp operator/(const fp &x) const {\n return fp(*this) /= x;\n }\n bool operator==(const fp &x) const {\n return v == x.v;\n }\n bool operator!=(const fp &x) const {\n return v != x.v;\n }\n friend istream &operator>>(istream &is, fp &x) {\n return is >> x.v;\n }\n friend ostream &operator<<(ostream &os, const fp &x) {\n return os << x.v;\n }\n};\n\ntemplate <unsigned mod> void rd(fp<mod> &x) {\n fastio::rd(x.v);\n}\ntemplate <unsigned mod> void wt(fp<mod> x) {\n fastio::wt(x.v);\n}\n\ntemplate <typename T> T Inv(ll n) {\n static const int md = T::get_mod();\n static vector<T> buf({0, 1});\n assert(n > 0);\n n %= md;\n while (SZ(buf) <= n) {\n int k = SZ(buf), q = (md + k - 1) / k;\n buf.push_back(buf[k * q - md] * q);\n }\n return buf[n];\n}\n\ntemplate <typename T> T Fact(ll n, bool inv = 0) {\n static const int md = T::get_mod();\n static vector<T> buf({1, 1}), ibuf({1, 1});\n assert(n >= 0 and n < md);\n while (SZ(buf) <= n) {\n buf.push_back(buf.back() * SZ(buf));\n ibuf.push_back(ibuf.back() * Inv<T>(SZ(ibuf)));\n }\n return inv ? ibuf[n] : buf[n];\n}\n\ntemplate <typename T> T nPr(int n, int r, bool inv = 0) {\n if (n < 0 || n < r || r < 0)\n return 0;\n return Fact<T>(n, inv) * Fact<T>(n - r, inv ^ 1);\n}\ntemplate <typename T> T nCr(int n, int r, bool inv = 0) {\n if (n < 0 || n < r || r < 0)\n return 0;\n return Fact<T>(n, inv) * Fact<T>(r, inv ^ 1) * Fact<T>(n - r, inv ^ 1);\n}\ntemplate <typename T> T nHr(int n, int r, bool inv = 0) {\n return nCr<T>(n + r - 1, r, inv);\n}\n\n/**\n * @brief Modint\n */\n\npair<ll,vector<string>> DFS(string S, int K) {\n if (K == 0) return {1,{S}};\n vector<int> V;\n rep(i,0,S.size()) {\n if (S[i] == (char)(K+'a')) V.push_back(i);\n }\n ll Ret = 0;\n vector<string> ANS;\n pair<ll,vector<string>> P;\n if (V.empty()) {\n P = DFS(S,K-1);\n Ret += P.first;\n rep(i,0,P.second.size()) ANS.push_back(P.second[i]);\n rep(i,0,S.size()) {\n if (S[i] == (char)(K-1+'a')) {\n S[i] = (char)(K+'a');\n auto P = DFS(S,K-1);\n Ret += P.first;\n rep(i,0,P.second.size()) ANS.push_back(P.second[i]);\n S[i] = (char)(K-1+'a');\n }\n }\n }\n else {\n rep(i,0,V[0]) {\n if (S[i] == (char)(K-1+'a')) {\n S[i] = (char)(K+'a');\n P = DFS(S,K-1);\n Ret += P.first;\n rep(i,0,P.second.size()) ANS.push_back(P.second[i]);\n S[i] = (char)(K-1+'a');\n }\n }\n }\n sort(ANS.begin(), ANS.end());\n vector<string> ANS2;\n if (ANS.size() <= 10) ANS2 = ANS;\n else {\n rep(i,0,5) ANS2.push_back(ANS[i]);\n rep(i,0,5) ANS2.push_back(ANS[ANS.size()-5+i]);\n }\n return {Ret, ANS2};\n}\n\nint main() {\nwhile(1) {\n string S;\n cin >> S;\n if (S == \"#\") return 0;\n pair<ll,vector<string>> P = DFS(S,25);\n cout << P.first << endl;\n rep(i,0,P.second.size()) cout << P.second[i] << endl;\n}\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3420, "score_of_the_acc": -0.087, "final_rank": 1 }, { "submission_id": "aoj_1195_9360072", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing pll = pair<ll,ll>;\nusing plll = pair<pll,ll>;\nusing pii =pair<int,int>;\n\nconstexpr ll mod = 1000000007;\n\nint dx[4]={1,0,-1,0};\nint dy[4]={0,1,0,-1};\nint dX[4]={1,0,-1,0};\nint dY[4]={0,-1,0,1};\n\n\n\n//library\n\n//end\n\n\nusing Graph =vector<vector<ll>>;\n\nint main(){\n while (true){\n string S;\n cin>>S;\n if (S==\"#\")break;\n\n int n=S.size();\n vector<string> ans;\n\n for (int i=0; i<(1<<n); i++){\n unordered_set<int> cset;\n string T=S;\n for (int j=0; j<n; j++){\n int num=S[j]-'a';\n if ((1<<j)&i){\n if (cset.count(num+1)!=0 || S[j]=='z')goto end;\n cset.emplace(num+1);\n T[j]='a'+num+1;\n }\n else{\n if (cset.count(num)==0 && S[j]!='a')goto end;\n cset.emplace(num);\n }\n }\n ans.push_back(T);\n end:;\n }\n sort(ans.begin(),ans.end());\n cout<<ans.size()<<endl;\n if (ans.size()<10){\n for (auto v: ans)cout<<v<<endl;\n }\n else{\n for (int i=0; i<5; i++){\n cout<<ans[i]<<endl;\n }\n for (int i=4; i>=0; i--){\n cout<<ans[ans.size()-1-i]<<endl;\n }\n }\n\n }\n\n return 0;\n\n}", "accuracy": 1, "time_ms": 4630, "memory_kb": 4812, "score_of_the_acc": -1.1155, "final_rank": 17 }, { "submission_id": "aoj_1195_9303905", "code_snippet": "#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#include <bits/stdc++.h>\nusing namespace std;\n\nvector<short> exist(26);\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n while (true) {\n string s;\n cin >> s;\n if (s == \"#\") break;\n\n int n = s.size();\n vector<string> ans;\n for (int i = 0; i < (1<<n); ++i) {\n string t = s;\n for (int j = 0; j < n; ++j) {\n if ((i >> j & 1) && s[j] != 'z') {\n ++t[j];\n }\n }\n\n string cand = t;\n fill(exist.begin(), exist.end(), 0);\n for (char &c : t) {\n exist[c-'a'] = 1;\n }\n for (int i = 1; i < 26; ++i) {\n if (!exist[i]) continue;\n for (int j = 0; j < t.size(); ++j) {\n if (t[j] == 'a' + i) {\n t[j] -= 1;\n break;\n }\n }\n }\n if (s == t) ans.emplace_back(cand);\n }\n\n sort(ans.begin(), ans.end());\n ans.erase(unique(ans.begin(), ans.end()), ans.end());\n cout << ans.size() << '\\n';\n if (ans.size() <= 10) {\n for (string &c : ans) {\n cout << c << '\\n';\n }\n } else {\n int m = ans.size();\n for (int i = 0; i < 5; ++i) cout << ans[i] << '\\n';\n for (int i = m-5; i < m; ++i) cout << ans[i] << '\\n';\n }\n }\n}", "accuracy": 1, "time_ms": 7480, "memory_kb": 4936, "score_of_the_acc": -1.5134, "final_rank": 19 }, { "submission_id": "aoj_1195_9303888", "code_snippet": "#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#include <bits/stdc++.h>\nusing namespace std;\n\nvector<short> exist(26);\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n while (true) {\n string s;\n cin >> s;\n if (s == \"#\") break;\n\n int n = s.size();\n vector<string> ans;\n for (int i = 0; i < (1<<n); ++i) {\n string t = s;\n for (int j = 0; j < n; ++j) {\n if ((i >> j & 1) && s[j] != 'z') {\n ++t[j];\n }\n }\n\n string cand = t;\n fill(exist.begin(), exist.end(), 0);\n for (char &c : t) {\n exist[c-'a'] = 1;\n }\n for (int i = 1; i < 26; ++i) {\n if (!exist[i]) continue;\n for (int j = 0; j < t.size(); ++j) {\n if (t[j] == 'a' + i) {\n t[j] -= 1;\n break;\n }\n }\n }\n if (s == t) ans.emplace_back(cand);\n }\n\n unordered_set<string> st;\n for (string & t: ans) {\n st.emplace(t);\n }\n ans.clear();\n for (const string &t : st) {\n ans.emplace_back(t);\n }\n sort(ans.begin(), ans.end());\n cout << ans.size() << '\\n';\n if (ans.size() <= 10) {\n for (string &c : ans) {\n cout << c << '\\n';\n }\n } else {\n int m = ans.size();\n for (int i = 0; i < 5; ++i) cout << ans[i] << '\\n';\n for (int i = m-5; i < m; ++i) cout << ans[i] << '\\n';\n }\n }\n}", "accuracy": 1, "time_ms": 8000, "memory_kb": 6008, "score_of_the_acc": -1.9348, "final_rank": 20 }, { "submission_id": "aoj_1195_9173554", "code_snippet": "#include <bits/stdc++.h>\n\nint to(char c) {\n return c - 'a';\n}\n\nbool solve() {\n std::string S;\n std::cin >> S;\n if (S == \"#\") return false;\n std::vector<std::string> ans;\n auto rec{[&](auto rec, int i, int used, std::string& cur) -> void {\n if (i == (int)S.size()) {\n assert(cur.size() == S.size());\n ans.push_back(cur);\n return;\n }\n if (S[i] == 'a') {\n if (!(used & (1 << to('b')))) {\n cur += 'b';\n rec(rec, i + 1, used | (1 << to('b')), cur);\n cur.pop_back();\n }\n cur += 'a';\n rec(rec, i + 1, used, cur);\n cur.pop_back();\n }\n else if (S[i] == 'z') {\n if (!(used & (1 << to('z')))) {\n return;\n }\n cur += 'z';\n rec(rec, i + 1, used, cur);\n cur.pop_back();\n }\n else {\n if (!(used & (1 << to(S[i] + 1)))) {\n cur += S[i] + 1;\n rec(rec, i + 1, used | (1 << to(S[i] + 1)), cur);\n cur.pop_back();\n }\n if ((used & (1 << to(S[i])))) {\n cur += S[i];\n rec(rec, i + 1, used, cur);\n cur.pop_back();\n }\n }\n }};\n std::string T;\n rec(rec, 0, 0, T);\n std::sort(ans.begin(), ans.end());\n std::cout << ans.size() << '\\n';\n if (ans.size() <= 10u) {\n for (const auto& x : ans) std::cout << x << '\\n';\n }\n else {\n for (int i{} ; i < 5 ; i++) std::cout << ans[i] << '\\n';\n for (int i{4} ; i >= 0 ; i--) std::cout << ans[ans.size() - i - 1] << '\\n';\n }\n return true;\n}\n\nint main() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n while (solve()) ;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4400, "score_of_the_acc": -0.4003, "final_rank": 4 }, { "submission_id": "aoj_1195_8976254", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\n} // namespace macro\n\nusing namespace macro;\n#line 3 \"A.cpp\"\n\nvector<string> solve(string target) {\n vector<string> ans;\n auto dfs = [&](auto self, string s, int id) -> void {\n if(id == 25) {\n ans.push_back(s);\n return;\n } else {\n char y = char('z' - id - 1), z = char('z' - id);\n int lz = s.size();\n for(int i : revrep(s.size())) if(s[i] == z) lz = i;\n for(int i : rep(s.size())) if(s[i] == y and i < lz) {\n string t = s;\n t[i] = z;\n self(self, t, id + 1);\n }\n if(lz == s.size()) self(self, s, id + 1);\n }\n };\n\n dfs(dfs, target, 0);\n sort(ans);\n return ans;\n}\n\nint main() {\n while(true) {\n string s = in();\n if(s == \"#\") return 0;\n auto ans = solve(s);\n print(ans.size());\n if(ans.size() <= 10) {\n print_n(ans);\n } else {\n for(int i : rep(5)) print(ans[i]);\n for(int i : revrep(5)) print(ans[ans.size() - 1 - i]);\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4972, "score_of_the_acc": -0.5917, "final_rank": 12 }, { "submission_id": "aoj_1195_8291178", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nvoid solve(string S) {\n\tvector<string> Cand;\n\n\t// Brute Force\n\tfor (int i = 0; i < (1 << S.size()); i++) {\n\t\tvector<bool> used(26, false);\n\t\tbool flag = true;\n\t\tfor (int j = 0; j < S.size(); j++) {\n\t\t\tint chr = (S[j] - 'a');\n\t\t\tint prv = chr + ((i >> j) & 1);\n\t\t\tif (chr != prv && (S[j] == 'z' || used[prv] == true)) { flag = false; break; }\n\t\t\tif (chr == prv && (S[j] != 'a' && used[prv] == false)) { flag = false; break; }\n\t\t\tused[prv] = true;\n\t\t}\n\t\tif (flag == false) continue;\n\t\tstring str = \"\";\n\t\tfor (int j = 0; j < S.size(); j++) {\n\t\t\tif (((i >> j) & 1) == 1) str += (S[j] + 1);\n\t\t\tif (((i >> j) & 1) == 0) str += (S[j] + 0);\n\t\t}\n\t\tCand.push_back(str);\n\t}\n\n\t// Sorting\n\tsort(Cand.begin(), Cand.end());\n\tcout << Cand.size() << endl;\n\tif (Cand.size() <= 10) {\n\t\tfor (int i = 0; i < Cand.size(); i++) cout << Cand[i] << endl;\n\t}\n\telse {\n\t\tfor (int i = 0; i < 5; i++) cout << Cand[i] << endl;\n\t\tfor (int i = Cand.size() - 5; i < Cand.size(); i++) cout << Cand[i] << endl;\n\t}\n}\n\nint main() {\n\twhile (true) {\n\t\tstring str; cin >> str;\n\t\tif (str == \"#\") break;\n\t\tsolve(str);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 690, "memory_kb": 4776, "score_of_the_acc": -0.6104, "final_rank": 13 }, { "submission_id": "aoj_1195_8215570", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#define rep(i, a, n) for (int i = a; i < n; i++)\nusing namespace std;\n\nstring s;\nvector<string> vs;\n\nvoid dfs(string &t, int now) {\n if (now == s.size()) {\n vs.push_back(t);\n return;\n }\n int d[26] = {};\n rep(i, 0, now) d[t[i] - 'a']++;\n if (t[now] != 'z' && d[t[now] + 1 - 'a'] == 0) {\n t[now] = t[now] + 1;\n dfs(t, now + 1);\n t[now] = t[now] - 1;\n }\n if (t[now] == 'a' || d[t[now] - 'a'] != 0)\n dfs(t, now + 1);\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n while (1) {\n cin >> s;\n if (s == \"#\")\n break;\n vs.clear();\n dfs(s, 0);\n int ans = vs.size();\n sort(vs.begin(), vs.end());\n cout << ans << endl;\n if (ans <= 10) {\n rep(i, 0, ans) { cout << vs[i] << endl; }\n } else {\n rep(i, 0, 5) { cout << vs[i] << endl; }\n rep(i, ans - 5, ans) { cout << vs[i] << endl; }\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4452, "score_of_the_acc": -0.4176, "final_rank": 5 }, { "submission_id": "aoj_1195_8215566", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, a, n) for (int i = a; i < n; i++)\nusing namespace std;\nstring s;\nset<string> vs;\nbool f[26];\nvoid dfs(string t, int now) {\n if (now == s.size()) {\n vs.insert(t);\n return;\n }\n int d[26] = {};\n rep(i, 0, now) d[t[i] - 'a']++;\n if (t[now] != 'z' && d[t[now] + 1 - 'a'] == 0) {\n string tmp = t;\n tmp[now] = tmp[now] + 1;\n dfs(tmp, now + 1);\n }\n if (t[now] == 'a' || d[t[now] - 'a'] != 0)\n dfs(t, now + 1);\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n while (1) {\n cin >> s;\n if (s == \"#\")\n break;\n vs.clear();\n dfs(s, 0);\n int ans = vs.size();\n cout << ans << endl;\n auto it = vs.begin();\n if (ans <= 10) {\n rep(i, 0, ans) { \n cout << *it++ << endl; \n }\n } else {\n rep(i, 0, 5) { \n cout << *it++ << endl; \n }\n it = prev(vs.end(), 5);\n rep(i, ans - 5, ans) { \n cout << *it++ << endl; \n }\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5236, "score_of_the_acc": -0.6794, "final_rank": 14 }, { "submission_id": "aoj_1195_8215563", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, a, n) for (int i = a; i < n; i++)\nusing namespace std;\nstring s;\nvector<string> vs;\nvoid dfs(string t, int now) {\n if (now == s.size()) {\n vs.push_back(t);\n return;\n }\n int d[26] = {};\n rep(i, 0, now) d[t[i] - 'a']++;\n if (t[now] != 'z' && d[t[now] + 1 - 'a'] == 0) {\n string tmp = t;\n tmp[now] = tmp[now] + 1;\n dfs(tmp, now + 1);\n }\n if (t[now] == 'a' || d[t[now] - 'a'] != 0)\n dfs(t, now + 1);\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n while (1) {\n cin >> s;\n if (s == \"#\")\n break;\n vs.clear();\n dfs(s, 0);\n int ans = vs.size();\n sort(vs.begin(), vs.end());\n cout << ans << endl;\n if (ans <= 10) {\n rep(i, 0, ans) { cout << vs[i] << endl; }\n } else {\n rep(i, 0, 5) { cout << vs[i] << endl; }\n rep(i, ans - 5, ans) { cout << vs[i] << endl; }\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4336, "score_of_the_acc": -0.379, "final_rank": 3 }, { "submission_id": "aoj_1195_8215559", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, a, n) for (int i = a; i < n; i++)\nusing namespace std;\nstring s;\nvector<string> vs;\nbool f[26];\nvoid dfs(string t, int now) {\n if (now == s.size()) {\n vs.push_back(t);\n return;\n }\n int d[26] = {};\n rep(i, 0, now) d[t[i] - 'a']++;\n if (t[now] != 'z' && d[t[now] + 1 - 'a'] == 0) {\n string tmp = t;\n tmp[now] = tmp[now] + 1;\n dfs(tmp, now + 1);\n }\n if (t[now] == 'a' || d[t[now] - 'a'] != 0)\n dfs(t, now + 1);\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n while (1) {\n cin >> s;\n if (s == \"#\")\n break;\n vs.clear();\n dfs(s, 0);\n int ans = vs.size();\n sort(vs.begin(), vs.end());\n cout << ans << endl;\n if (ans <= 10) {\n rep(i, 0, ans) { cout << vs[i] << endl; }\n } else {\n rep(i, 0, 5) { cout << vs[i] << endl; }\n rep(i, ans - 5, ans) { cout << vs[i] << endl; }\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4520, "score_of_the_acc": -0.4402, "final_rank": 7 } ]
aoj_1192_cpp
Tax Rate Changed VAT (value-added tax) is a tax imposed at a certain rate proportional to the sale price. Our store uses the following rules to calculate the after-tax prices. When the VAT rate is x %, for an item with the before-tax price of p yen, its after-tax price of the item is p (100+ x ) / 100 yen, fractions rounded off. The total after-tax price of multiple items paid at once is the sum of after-tax prices of the items. The VAT rate is changed quite often. Our accountant has become aware that "different pairs of items that had the same total after-tax price may have different total after-tax prices after VAT rate changes." For example, when the VAT rate rises from 5% to 8%, a pair of items that had the total after-tax prices of 105 yen before can now have after-tax prices either of 107, 108, or 109 yen, as shown in the table below. Before-tax prices of two items After-tax price with 5% VAT After-tax price with 8% VAT 20, 80 21 + 84 = 105 21 + 86 = 107 2, 99 2 + 103 = 105 2 + 106 = 108 13, 88 13 + 92 = 105 14 + 95 = 109 Our accountant is examining effects of VAT-rate changes on after-tax prices. You are asked to write a program that calculates the possible maximum total after-tax price of two items with the new VAT rate, knowing their total after-tax price before the VAT rate change. Input The input consists of multiple datasets. Each dataset is in one line, which consists of three integers x , y , and s separated by a space. x is the VAT rate in percent before the VAT-rate change, y is the VAT rate in percent after the VAT-rate change, and s is the sum of after-tax prices of two items before the VAT-rate change. For these integers, 0 < x < 100, 0 < y < 100, 10 < s < 1000, and x ≠ y hold. For before-tax prices of items, all possibilities of 1 yen through s -1 yen should be considered. The end of the input is specified by three zeros separated by a space. Output For each dataset, output in a line the possible maximum total after-tax price when the VAT rate is changed to y %. Sample Input 5 8 105 8 5 105 1 2 24 99 98 24 12 13 26 1 22 23 1 13 201 13 16 112 2 24 50 1 82 61 1 84 125 1 99 999 99 1 999 98 99 999 1 99 11 99 1 12 0 0 0 Output for the Sample Input 109 103 24 24 26 27 225 116 62 111 230 1972 508 1004 20 7 Hints In the following table, an instance of a before-tax price pair that has the maximum after-tax price after the VAT-rate change is given for each dataset of the sample input. Dataset Before-tax prices After-tax price with y % VAT 5 8 105 13, 88 14 + 95 = 109 8 5 105 12, 87 12 + 91 = 103 1 2 24 1, 23 1 + 23 = 24 99 98 24 1, 12 1 + 23 = 24 12 13 26 1, 23 1 + 25 = 26 1 22 23 1, 22 1 + 26 = 27 1 13 201 1,199 1 +224 = 225 13 16 112 25, 75 29 + 87 = 116 2 24 50 25, 25 31 + 31 = 62 1 82 61 11, 50 20 + 91 = 111 1 84 125 50, 75 92 +138 = 230 1 99 999 92,899 183+1789 =1972 99 1 999 1,502 1 +507 = 508 98 99 999 5,500 9 +995 =1004 1 99 11 1, 10 1 + 19 = 20 99 ...(truncated)
[ { "submission_id": "aoj_1192_10851356", "code_snippet": "#include <cstdio>\n#include <algorithm>\n\nusing namespace std;\n\nint main(void) {\n\tint x, y, s;\n\twhile(scanf(\"%d %d %d\", &x, &y, &s), !(x == 0 and y == 0 and s == 0)) {\n\t\tint ans = 0;\n\n\t\tfor(int i = 1; i < s; i++) {\n\t\t\tint j = s - i;\n\t\t\tint xcost = 0;\n\t\t\twhile(xcost * (100 + x) / 100 <= i) xcost++;\n\t\t\txcost--;\n\t\t\tint ycost = 0;\n\t\t\twhile(ycost * (100 + x) / 100 <= j) ycost++;\n\t\t\tycost--;\n\n\t\t\tif(xcost * (100 + x) / 100 + ycost * (100 + x) / 100 != s) continue;\n\n\t\t\tint cand = xcost * (100 + y) / 100 + ycost * (100 + y) / 100;\n\t\t\tif(cand > ans) {\n\t\t\t\tans = cand;\n\t\t\t}\n\t\t}\n\n\t\tprintf(\"%d\\n\", ans);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 2944, "score_of_the_acc": -0.125, "final_rank": 1 }, { "submission_id": "aoj_1192_10767163", "code_snippet": "//Q:https://judge.u-aizu.ac.jp/onlinejudge/description.jsp?lang=jp&id=1192\n\n#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n int x, y, s;\n while (cin >> x >> y >> s) {\n if (x == 0 && y == 0 && s == 0) break;\n int ma = 0;\n for (int a = 1; a < s; a++) {\n for (int b = 1; b < s; b++){\n int ta = a * (100 + x) / 100;\n int tb = b * (100 + x) / 100;\n if (ta + tb == s) {\n int na = a * (100 + y) / 100;\n int nb = b * (100 + y) / 100;\n ma = max(ma, na + nb);\n }\n } \n }\n cout << ma << endl;\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3356, "score_of_the_acc": -0.8938, "final_rank": 13 }, { "submission_id": "aoj_1192_10683815", "code_snippet": "#include <iostream>\n#include <cassert>\nusing namespace std;\nusing ll = long long;\ntemplate<class T> inline bool chmax(T& a, const T& b) {if (a<b) {a=b; return true;} return false;}\ntemplate<class T> inline bool chmin(T& a, const T& b) {if (b<a) {a=b; return true;} return false;}\nconstexpr int INTINF = 1000001000;\nconstexpr int INTMAX = 2147483647;\nconstexpr ll LLMAX = 9223372036854775807;\nconstexpr ll LLINF = 4450000000011100000;\n\nint calc(int p, int x) {\n return p * (100 + x) / 100; \n}\n\nvoid solve(int x, int y, int s) {\n int ans = 0;\n // s: 税率がx%のときの税込み合計額\n // s = floor(p * (100+x) / x) + floor(\n for (int s1=1; s1<=s-1; s1++){\n for (int s2=1; s2<=s-1; s2++) {\n if (calc(s1,x) + calc(s2,x) != s) continue;\n chmax(ans, calc(s1,y) + calc(s2,y));\n }\n }\n cout << ans << endl;\n}\n\nint main() {\n ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n while(true) {\n int x, y, s; cin >> x >> y >> s;\n if (x==0 && y == 0 && s == 0) break;\n solve(x,y,s);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3456, "score_of_the_acc": -1.05, "final_rank": 15 }, { "submission_id": "aoj_1192_10683806", "code_snippet": "#include <bits/stdc++.h>\n#include <atcoder/all>\nusing namespace std;\nusing namespace atcoder;\n#define int long long\n\nvoid solve(int x, int y, int s) {\n int mx = 0;\n for (int i=1; i<s; ++i) {\n for (int j=1; j<s; ++j) {\n int before = i*(100+x)/100 + j*(100+x)/100;\n if (before != s) continue;\n int after = i*(100+y)/100 + j*(100+y)/100;\n mx = max(mx, after);\n }\n }\n cout << mx << endl;\n}\n\nsigned main() {\n ios::sync_with_stdio(false);cin.tie(nullptr);\n while(true) {\n int x, y, s;\n cin >> x >> y >> s;\n if (x+y+s == 0) break;\n solve(x, y, s);\n }\n}\n\n/*\nmemo\n\n*/", "accuracy": 1, "time_ms": 60, "memory_kb": 3584, "score_of_the_acc": -1.25, "final_rank": 17 }, { "submission_id": "aoj_1192_10661873", "code_snippet": "// This is free and unencumbered software released into the public domain.\n\n// Anyone is free to copy, modify, publish, use, compile, sell, or\n// distribute this software, either in source code form or as a compiled\n// binary, for any purpose, commercial or non-commercial, and by any\n// means.\n\n// In jurisdictions that recognize copyright laws, the author or authors\n// of this software dedicate any and all copyright interest in the\n// software to the public domain. We make this dedication for the benefit\n// of the public at large and to the detriment of our heirs and\n// successors. We intend this dedication to be an overt act of\n// relinquishment in perpetuity of all present and future rights to this\n// software under copyright law.\n\n// THE SOFTWARE IS PROVIDED \"AS IS\", WITHOUT WARRANTY OF ANY KIND,\n// EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF\n// MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT.\n// IN NO EVENT SHALL THE AUTHORS BE LIABLE FOR ANY CLAIM, DAMAGES OR\n// OTHER LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE,\n// ARISING FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR\n// OTHER DEALINGS IN THE SOFTWARE.\n\n// For more information, please refer to <http://unlicense.org>\n\n/****************/\n/* template.hpp */\n/****************/\n\n#include <cassert>\n#include <iomanip>\n#include <iostream>\n#include <limits>\n\nusing namespace std;\n\n\ntemplate <typename T> void debug(T x) {\n cerr << __LINE__ << \" \" << var_name(x) << \" \" << (x) << endl;\n}\n\ntemplate <typename T> void debug_v(T x) {\n cerr << __LINE__ << \" \" << var_name(x) << \" [\";\n bool first = true;\n for (const auto &itr : x) {\n if (!first) {\n cerr << \", \";\n }\n cerr << itr;\n first = false;\n }\n cerr << \"]\" << endl;\n}\n\nstruct Initializer {\n Initializer() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(15) << boolalpha;\n }\n} initializer;\n\ntemplate <typename T, typename S> bool chmin(T &a, const S &b) {\n return a > b ? a = b, true : false;\n}\n\ntemplate <typename T, typename S> bool chmax(T &a, const S &b) {\n return a < b ? a = b, true : false;\n}\n\ntemplate <typename T> constexpr T inf() {\n return numeric_limits<T>::max() / 2 - 1;\n}\n\n/************/\n/* main.cpp */\n/************/\n\nint main() {\n auto tax = [](int x, int p) { return x * (100 + p) / 100; };\n int x, y, s;\n while (true) {\n cin >> x >> y >> s;\n if (x == 0 && y == 0 && s == 0) {\n break;\n }\n int res = -1;\n for (int i = 1; i < s; ++i) {\n for (int j = i; j < s; ++j) {\n if (tax(i, x) + tax(j, x) == s) {\n chmax(res, tax(i, y) + tax(j, y));\n }\n }\n }\n cout << res << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3456, "score_of_the_acc": -0.8625, "final_rank": 12 }, { "submission_id": "aoj_1192_10609642", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing a2 = array<ll, 2>;\nusing a3 = array<ll, 3>;\n\ntemplate <typename A> void chmin(A &l, const A &r) {\n if(r < l)\n l = r;\n}\ntemplate <typename A> void chmax(A &l, const A &r) {\n if(l < r)\n l = r;\n}\n\nll mod = 998244353;\n\nll n,m,a;\nvoid input() {\n cin>>n>>m>>a;\n}\n\nvoid solve() {\n ll ans = 0;\n for(int i=1;i<=a;i++)\n {\n for(int j=i;j<=a;j++)\n {\n if((i*(100+n))/100+(j*(100+n))/100==a)\n {\n chmax(ans,(i*(100+m))/100+(j*(100+m))/100);\n }\n }\n }\n cout << ans << endl;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n\n while(1) {\n input();\n if(n == 0)\n break;\n solve();\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3340, "score_of_the_acc": -0.6813, "final_rank": 7 }, { "submission_id": "aoj_1192_10589197", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nusing ll = long long;\n\nll tax(ll price, ll tax_rate) {\n return (price * (100 + tax_rate)) / 100;\n}\n\nint main() {\n ll x, y, s;\n\n while (cin >> x >> y >> s) {\n if (x == 0 && y == 0 && s == 0) break;\n\n ll max_sum = 0;\n\n for (ll a = 1; a < s; ++a) {\n for (ll b = a; b < s; ++b) {\n ll sum_before = tax(a, x) + tax(b, x);\n if (sum_before == s) {\n ll sum_after = tax(a, y) + tax(b, y);\n max_sum = max(max_sum, sum_after);\n }\n }\n }\n\n cout << max_sum << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3372, "score_of_the_acc": -0.7937, "final_rank": 10 }, { "submission_id": "aoj_1192_10566459", "code_snippet": "// AOJ 1192 - Tax Rate Changed\n// ICPC Japan Domestic Contest 2014 - Problem A\n\n#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n while(true) {\n int X, Y, S; cin >> X >> Y >> S;\n if(X == 0) break;\n\n int ans = 0;\n for(int a = 1; a < S; ++a) {\n for(int b = 1; b <= S - a; ++b) {\n if(a * (100 + X) / 100 + b * (100 + X) / 100 == S) {\n ans = max(ans, a * (100 + Y) / 100 + b * (100 + Y) / 100);\n }\n }\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3320, "score_of_the_acc": -0.65, "final_rank": 6 }, { "submission_id": "aoj_1192_10488380", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing P = pair<int, int>;\nusing PP = pair<int, P>;\nusing PLL = pair<ll, ll>;\nusing PPLL = pair<ll, PLL>;\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define rrep(i, n) for(ll i = n - 1; i >= 0; --i)\n#define loop(i, a, b) for(ll i = a; i <= b; ++i)\n#define all(v) v.begin(), v.end()\n#define nC2(n) n * (n - 1) / 2\nconstexpr ll INF = 9009009009009009009LL;\nconstexpr int INF32 = 2002002002;\nconstexpr ll MOD = 998244353;\nconstexpr ll MOD107 = 1000000007;\n\n// Linear Algebra ////////////////////////////////////////////////\nconst double Rad2Deg = 180.0 / M_PI;\nconst double Deg2Rad = M_PI / 180.0;\n//////////////////////////////////////////////////////////////////\n\nint dx[8] = {0, 1, 0, -1, 1, 1, -1, -1};\nint dy[8] = {1, 0, -1, 0, 1, -1, 1, -1};\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) {\n\tif (a < b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\ntemplate <class T>\ninline bool chmin(T &a, const T &b) {\n\tif (a > b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\n\ntemplate <typename Container,\n typename = std::enable_if_t<\n !std::is_same_v<Container, std::string> &&\n std::is_convertible_v<decltype(std::declval<Container>().begin()),\n typename Container::iterator>>>\nostream &operator<<(ostream &os, const Container &container) {\n auto it = container.begin();\n auto end = container.end();\n\n if (it != end) {\n os << *it;\n ++it;\n }\n\tfor (; it != end; ++it) {\n\t\tos << \" \" << *it;\n\t}\n return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v) {\n for (size_t i = 0; i < v.size(); ++i) {\n os << v[i];\n if (i != v.size() - 1) os << \" \";\n }\n return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<vector<T>>& vv) {\n\tfor (size_t i = 0; i < vv.size(); ++i) {\n\t\tos << vv[i];\n\t\tif (i != vv.size() - 1) os << \"\\n\";\n }\n return os;\n}\ntemplate <typename T>\nistream& operator>>(istream& is, vector<T>& v) {\n\tassert(v.size() > 0);\n\tfor (size_t i = 0; i < v.size(); ++i) is >> v[i];\n\treturn is;\n}\ntemplate <typename T>\nistream& operator>>(istream& is, vector<vector<T>>& vv) {\n\tassert(vv.size() > 0);\n\tfor (size_t i = 0; i < vv.size(); ++i) is >> vv[i];\n\treturn is;\n}\n\nstruct phash {\n\ttemplate<class T1, class T2>\n inline size_t operator()(const pair<T1, T2> & p) const {\n auto h1 = hash<T1>()(p.first);\n auto h2 = hash<T2>()(p.second);\n\n\t\tsize_t seed = h1 + h2; \n\t\th1 = ((h1 >> 16) ^ h1) * 0x45d9f3b;\n h1 = ((h1 >> 16) ^ h1) * 0x45d9f3b;\n h1 = (h1 >> 16) ^ h1;\n seed ^= h1 + 0x9e3779b9 + (seed << 6) + (seed >> 2);\n\t\th2 = ((h2 >> 16) ^ h2) * 0x45d9f3b;\n h2 = ((h2 >> 16) ^ h2) * 0x45d9f3b;\n h2 = (h2 >> 16) ^ h2;\n seed ^= h2 + 0x9e3779b9 + (seed << 6) + (seed >> 2);\n return seed;\n }\n};\n\n\n\n\n\nint solve() {\n\tll x, y, s;\n\tcin >> x >> y >> s;\n\tif (x == 0) return 1;\n\n\tll ans = -INF;\n\tloop(i, 1, 999) {\n\t\tloop(j, 1, 999) {\n\t\t\tll before = i * (100 + x) / 100 + j * (100 + x) / 100;\n\t\t\tif (before == s) {\n\t\t\t\tll after = i * (100 + y) / 100 + j * (100 + y) / 100;\n\t\t\t\tchmax(ans, after);\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\n\treturn 0;\n}\n\nint main() {\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\n\twhile (!solve()) { }\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3584, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_1192_10454995", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n//#include <bits/stdc++.h>\nusing namespace std;\n\nint newtax(int a,int p){\n return p * (100 + a) / 100;\n}\n\nint main(){\n int x,y,s;\n while(true){\n cin >> x >> y >> s;\n if (x == 0 && y == 0 && s == 0){\n break;\n }\n int M = 0;\n /*\n for (int i = 1; i<s; i++){\n int sum = newtax(x,y,i) + newtax(x,y,s-i);\n M = max(M,sum);\n }\n */\n for (int i=1; i<s; i++){\n for (int j=1; j<s; j++){\n if (newtax(x,i) + newtax(x,j) == s){\n int sum = newtax(y,i) + newtax(y,j);\n M = max(M,sum);\n }\n }\n }\n cout << M << endl;\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3584, "score_of_the_acc": -1.25, "final_rank": 17 }, { "submission_id": "aoj_1192_10454965", "code_snippet": "#include<iostream>\n#include<map>\n#include<vector>\n#include<algorithm>\n#include<cmath>\n#include<climits>\n#include<ctime>\n#include<cstring>\n#include<numeric>\n\n#define ALL(v) (v).begin(),(v).end()\n#define REP(i,p,n) for(int i=p;i<(int)(n);++i)\n#define rep(i,n) REP(i,0,n)\n#define dump(a) (cerr << #a << \"=\" << (a) << endl)\n#define DUMP(list) cout << \"{ \"; for(auto nth : list){ cout << nth << \" \"; } cout << \"}\" << endl;\n\nusing namespace std;\n\nint calc(int p, int x){\n\treturn p*(100+x)/100;\n}\n\nint main()\n{\n\tint X,Y,S;\n\n\twhile(cin >> X >> Y >> S && X)\n\t{\n\t\tint ans=0;\n\t\tREP( y, 1, S ){\n\t\t\tREP( x, 1, S ){\t\n\t\t\t\tif(calc(x,X)+calc(y,X) == S){\n\t\t\t\t\tint x2 = calc(x,Y);\n\t\t\t\t\tint y2 = calc(y,Y);\n\t\t\t\t\tans = max(x2+y2,ans);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\t\n\t\tcout << ans << endl;\n\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3456, "score_of_the_acc": -1.05, "final_rank": 15 }, { "submission_id": "aoj_1192_10404467", "code_snippet": "#include <iostream> \nusing namespace std;\nint main() { \n int x,y,s;\n while (cin >> x && x>0){\n cin >>y;\n cin >>s;\n int a,b,max;\n max=0;\n for (int i=1;i<s;i++){\n for(int j=1;j<=i;j++){\n a=i*(100+x)/100;\n b=j*(100+x)/100;\n if(a+b==s){\n a=i*(100+y)/100;\n b=j*(100+y)/100;\n if((a+b)>max){\n max = a+b;\n }\n }\n }\n }\n cout<<max<<endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3364, "score_of_the_acc": -0.7188, "final_rank": 8 }, { "submission_id": "aoj_1192_10404425", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main() {\n int x,y,s;\n while(cin >> x >> y >> s){\n if(x == 0&&y == 0&&s == 0) break;\n int ans = 0;\n for(int i = 1; i < s; i++){\n for(int j = 1 ; j < s;j++){\n int I = i*(100+x)/100;\n int J = j*(100+x)/100;\n if(I+J == s){\n ans = max(ans,i*(100+y)/100+j*(100+y)/100);\n }\n }\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3356, "score_of_the_acc": -0.8938, "final_rank": 13 }, { "submission_id": "aoj_1192_10403360", "code_snippet": "#include <bits/stdc++.h>\n#include <atcoder/all>\nusing namespace atcoder;\nusing namespace std;\n#define all(...) std::begin(__VA_ARGS__), std::end(__VA_ARGS__)\n#define rall(...) std::rbegin(__VA_ARGS__), std::rend(__VA_ARGS__)\n#define OVERLOAD_REP(_1, _2, _3, _4, name, ...) name\n#define REP1(n) for(ll i=0;i<n;i++)\n#define REP2(i, n) for (ll i=0;i<n;i++)\n#define REP3(i, a, n) for (ll i=a;i<n;i++)\n#define REP4(i, a, b, n) for(ll i=a;i<n;i+=b)\n#define rep(...) OVERLOAD_REP(__VA_ARGS__, REP4, REP3, REP2, REP1)(__VA_ARGS__)\n#define OVERLOAD_RREP(_1, _2, _3, _4, name, ...) name\n#define RREP1(n) for(ll i=n;i>=0;i--)\n#define RREP2(i, n) for(ll i=n;i>=0;i--)\n#define RREP3(i, a, n) for(ll i=n;i>=a;i--)\n#define RREP4(i, a, b, n) for(ll i=n;i>=a;i-=b)\n#define rrep(...) OVERLOAD_RREP(__VA_ARGS__, RREP4, RREP3, RREP2, RREP1)(__VA_ARGS__)\n#define foa(a,v) (auto& a : (v))\n#define uniq(a) sort(all(a));a.erase(unique(all(a)),end(a))\n#define len(n) (long long)(n).size()\n#define pb push_back\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vs = vector<string>;\nusing vvs = vector<vs>;\nusing vvvs = vector<vvs>;\nusing vld = vector<ld>;\nusing vvld = vector<vld>;\nusing vvvld = vector<vvld>;\nusing vc = vector<char>;\nusing vvc = vector<vc>;\nusing vvvc = vector<vvc>;\nusing pll = pair<ll,ll>;\nusing vpll = vector<pll>;\ntemplate<class... T>\nconstexpr auto min(T... a){\n return min(initializer_list<common_type_t<T...>>{a...});\n}\ntemplate<class... T>\nconstexpr auto max(T... a){\n return max(initializer_list<common_type_t<T...>>{a...});\n}\ntemplate<class... T>\nvoid input(T&... a){\n (cin >> ... >> a);\n}\nll modpow(ll a,ll b,ll c){\n ll ans = 1;\n while (b){\n if (b & 1){\n ans *= a;\n ans %= c;\n }\n a *= a;\n a %= c;\n b /= 2;\n }\n return ans;\n}\n#define INT(...) int __VA_ARGS__; input(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define ULL(...) ull __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define CHA(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define VLL(name,length) vll name(length);rep(i,length){cin >> name[i];}\n#define VVLL(name,h,w) vvll name(h,vll(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVLL(name,a,b,c) vvvll name(a,vvll(b,vll(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VI(name,length) vi name(length);rep(i,length){cin >> name[i];}\n#define VVI(name,h,w) vvi name(h,vi(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVI(name,a,b,c) vvvi name(a,vvll(b,vi(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VLD(name,length) vld name(length);rep(i,length){cin >> name[i];}\n#define VVLD(name,h,w) vvld name(h,vld(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVLD(name,a,b,c) vvvld name(a,vvld(b,vld(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VC(name,length) vc name(length);rep(i,length){cin >> name[i];}\n#define VVC(name,h,w) vvc name(h,vc(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVC(name,a,b,c) vvvc name(a,vvc(b,vc(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VS(name,length) vs name(length);rep(i,length){cin >> name[i];}\n#define VVS(name,h,w) vvs name(h,vs(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVS(name,a,b,c) vvvs name(a,vvs(b,vs(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define PLL(name) pll name;cin>>name.first>>name.second;\n#define VPLL(name,length) vpll name(length);rep(i,length){cin>>name[i].first>>name[i].second;}\n\nvoid print(){cout << \"\\n\";}\ntemplate<class T, class... Ts>\nvoid print(const T& a, const Ts&... b){cout << a;(cout << ... << (cout << ' ', b));cout << '\\n';}\nvoid print(vll x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid print(vvll x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\n\nvoid solve(ll x,ll y,ll s){\n ll ans = 0;\n rep(i,1,s){\n rep(j,1,s){\n ll z = i * (100 + x) / 100 + j * (100 + x) / 100;\n if(z == s){\n ans = max(ans,i * (100 + y) / 100 + j * (100 + y) / 100);\n }\n }\n }\n print(ans);\n}\n\nint main(){\n while(1){\n LL(x,y,s);\n if(x == 0 && y == 0 && s == 0){break;}\n solve(x,y,s);\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3584, "score_of_the_acc": -1.25, "final_rank": 17 }, { "submission_id": "aoj_1192_9578905", "code_snippet": "#include <iostream>\n#include <cmath>\nusing namespace std;\nint X, Y, S;\n\nint tax(int rate, int price)\n{\n return ((100 + rate) * price) / 100;\n}\n\nint solve()\n{\n int maximum = 0;\n for (int i = 1; i < S; ++i)\n for (int j = i; j < S; ++j)\n if (tax(X, i) + tax(X, j) == S)\n maximum = max(maximum, tax(Y, i) + tax(Y, j));\n\n return maximum;\n}\n\nint main()\n{\n while (cin >> X >> Y >> S && X > 0)\n {\n cout << solve() << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3076, "score_of_the_acc": -0.2687, "final_rank": 4 }, { "submission_id": "aoj_1192_9570619", "code_snippet": "#include <iostream>\nusing namespace std;\n\nint x, y, s;\nint p1, p2, tax_old, tax_new;\n\nint main()\n{\n cin >> x >> y >> s;\n while (x || y || s)\n {\n for (p1 = 1; p1 < s; p1++)\n {\n for (p2 = 1; p2 <= s - p1; p2++)\n {\n tax_old = (p1 * (100 + x)) / 100 + (p2 * (100 + x)) / 100;\n if (tax_old == s)\n {\n tax_new = max(tax_new, (p1 * (100 + y)) / 100 + (p2 * (100 + y)) / 100);\n }\n }\n }\n\n cout << tax_new << endl;\n tax_new = 0;\n cin >> x >> y >> s;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3080, "score_of_the_acc": -0.275, "final_rank": 5 }, { "submission_id": "aoj_1192_9451321", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nint calculate_tax(int price, int tax_rate) {\n return (price * (100 + tax_rate)) / 100;\n}\n\nint main() {\n int x, y, s;\n\n while (true) {\n cin >> x >> y >> s;\n if (x == 0 && y == 0 && s == 0) break;\n\n int maximum = 0;\n\n for (int i = 1; i <= s - 1; ++i) {\n for (int k = i; k <= s - 1; ++k) {\n if (i + k > s) break;\n\n int old_total1 = calculate_tax(i, x);\n int old_total2 = calculate_tax(k, x);\n\n if (old_total1 + old_total2 == s) {\n int new_total = calculate_tax(i, y) + calculate_tax(k, y);\n maximum = max(maximum, new_total);\n }\n }\n }\n\n cout << maximum << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3084, "score_of_the_acc": -0.2188, "final_rank": 3 }, { "submission_id": "aoj_1192_9451176", "code_snippet": "#include <iostream>\n#include <cmath>\n#include <algorithm>\n\nusing namespace std;\n\nint calculate_tax_inclusive_price(int price, int tax_rate) {\n return (price * (100 + tax_rate)) / 100;\n}\n\nint main() {\n int x, y, s;\n\n while (true) {\n cin >> x >> y >> s;\n if (x == 0 && y == 0 && s == 0) break;\n\n int maximum = 0;\n\n for (int i = 1; i <= s - 1; ++i) {\n for (int k = i; k <= s - 1; ++k) {\n if (i + k > s) break;\n\n int old_total1 = calculate_tax_inclusive_price(i, x);\n int old_total2 = calculate_tax_inclusive_price(k, x);\n \n if (old_total1 + old_total2 == s) {\n int new_total = calculate_tax_inclusive_price(i, y) + calculate_tax_inclusive_price(k, y);\n maximum = max(maximum, new_total);\n }\n }\n }\n\n cout << maximum << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3072, "score_of_the_acc": -0.2, "final_rank": 2 }, { "submission_id": "aoj_1192_9351678", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define all(x) (x).begin(),(x).end()\n#define eb emplace_back\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing vl = vector<long long>;\nusing vvl = vector<vector<long long>>; using vs = vector<string>;\nusing pl = pair<long long, long long>;\ntemplate <typename T> inline bool chmin(T& a, const T& b) {bool compare = a > b; if (a > b) a = b; return compare;}\ntemplate <typename T> inline bool chmax(T& a, const T& b) {bool compare = a < b; if (a < b) a = b; return compare;}\ntemplate<class T>using rp_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate <typename T> T gcd(T a, T b) {if (b == 0)return a; else return gcd(b, a % b);}\ntemplate <typename T> inline T lcm(T a, T b) {return a /gcd(a, b)*b;}\nconst ll INF = 1LL << 60;\nconst ld PI = acos(-1);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec);\ntemplate <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr);\ntemplate <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec);\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const pair<T, U> &pa);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec);\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec);\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa);\ntemplate <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp);\ntemplate <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp);\ntemplate <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl);\n \ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::vector<T> &vec) { os << '['; for (auto v : vec) os << v << ','; os << ']'; return os; }\ntemplate <class OStream, class T, size_t sz> OStream &operator<<(OStream &os, const std::array<T, sz> &arr) { os << '['; for (auto v : arr) os << v << ','; os << ']'; return os; }\ntemplate <class... T> std::istream &operator>>(std::istream &is, std::tuple<T...> &tpl) { std::apply([&is](auto &&... args) { ((is >> args), ...);}, tpl); return is; }\ntemplate <class OStream, class... T> OStream &operator<<(OStream &os, const std::tuple<T...> &tpl) { os << '('; std::apply([&os](auto &&... args) { ((os << args << ','), ...);}, tpl); return os << ')'; }\ntemplate <class OStream, class T, class TH> OStream &operator<<(OStream &os, const std::unordered_set<T, TH> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::deque<T> &vec) { os << \"deq[\"; for (auto v : vec) os << v << ','; os << ']'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T> OStream &operator<<(OStream &os, const std::unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }\ntemplate <class OStream, class T, class U> OStream &operator<<(OStream &os, const std::pair<T, U> &pa) { return os << '(' << pa.first << ',' << pa.second << ')'; }\ntemplate <class OStream, class TK, class TV> OStream &operator<<(OStream &os, const std::map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << \"=>\" << v.second << ','; os << '}'; return os; }\ntemplate <class OStream, class TK, class TV, class TH> OStream &operator<<(OStream &os, const std::unordered_map<TK, TV, TH> &mp) { os << '{'; for (auto v : mp) os << v.first << \"=>\" << v.second << ','; os << '}'; return os; }\n#ifdef LOCAL\nconst string COLOR_RESET = \"\\033[0m\", BRIGHT_GREEN = \"\\033[1;32m\", BRIGHT_RED = \"\\033[1;31m\", BRIGHT_CYAN = \"\\033[1;36m\", NORMAL_CROSSED = \"\\033[0;9;37m\", RED_BACKGROUND = \"\\033[1;41m\", NORMAL_FAINT = \"\\033[0;2m\";\n#define dbg(x) std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << \" = \" << (x) << NORMAL_FAINT << \" (L\" << __LINE__ << \") \" << __FILE__ << COLOR_RESET << std::endl\n#define dbgif(cond, x) ((cond) ? std::cerr << BRIGHT_CYAN << #x << COLOR_RESET << \" = \" << (x) << NORMAL_FAINT << \" (L\" << __LINE__ << \") \" << __FILE__ << COLOR_RESET << std::endl : std::cerr)\n#else\n#define dbg(x) ((void)0)\n#define dbgif(cond, x) ((void)0)\n#endif\nvoid solve();\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout<<fixed<<setprecision(15);\n int num_tc = 1;\n //cin >> num_tc;\n rep(tc,num_tc){\n //cout << \"Case #\" << tc+1 << \": \" ;// << endl;\n solve();\n }\n}\n//見切り発車で実装しては行けない.頭の中でコードが完全に出来上がるまで書き始めるな.\n//オーバーフローしているか確認する\n//小さいケースで動いているかを確認する。\nvoid solve(){\n while(true){\n ll x,y,s;cin>>x>>y>>s;\n if(x==0&&y==0&&s==0)return;\n ll ans = 0;\n for(int i=1;i<s;i++){\n //元がi + j円\n for(int j=s-i;j>=1;j--){\n ll ni = i *(100+x)/100;\n ll nj = j *(100+x)/100;\n if(ni+nj==s){\n ll now = i*(100+y)/100;\n now+=j*(100+y)/100;\n chmax(ans,now);\n }\n }\n }\n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3388, "score_of_the_acc": -0.7562, "final_rank": 9 }, { "submission_id": "aoj_1192_9346148", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nconst int INF = (int)1e9 + 1001010;\nconst ll llINF = (long long)4e18 + 22000020;\nconst string endn = \"\\n\";\ntemplate <class T> inline auto vector2(size_t i, size_t j, const T &init = T()) {return vector(i, vector<T>(j, init));}\nconst string ELEM_SEPARATION = \" \", VEC_SEPARATION = endn;\ntemplate<class T> istream& operator >>(istream &i, vector<T> &A) {for(auto &I : A) {i >> I;} return i;}\ntemplate<class T> ostream& operator <<(ostream &o, const vector<T> &A) {int i=A.size(); for(const auto &I : A){o << I << (--i ? ELEM_SEPARATION : \"\");} return o;}\ntemplate<class T> ostream& operator <<(ostream &o, const vector<vector<T>> &A) {int i=A.size(); for(const auto &I : A){o << I << (--i ? VEC_SEPARATION : \"\");} return o;}\ntemplate<class T> vector<T>& operator ++(vector<T> &A, int n) {for(auto &I : A) {I++;} return A;}\ntemplate<class T> vector<T>& operator --(vector<T> &A, int n) {for(auto &I : A) {I--;} return A;}\ntemplate<class T, class U> bool chmax(T &a, const U &b) {return ((a < b) ? (a = b, true) : false);}\ntemplate<class T, class U> bool chmin(T &a, const U &b) {return ((a > b) ? (a = b, true) : false);}\nll floor(ll a, ll b){if (b < 0) a = -a, b = -b; if(a >= 0) return a / b; else return (a + 1) / b - 1;}\nll ceil(ll a, ll b){if (b < 0) a = -a, b = -b; if(a > 0) return (a - 1) / b + 1; else return a / b;}\nll bit(unsigned long long val, unsigned long long digit){return (val >> digit) & 1;}\n#ifdef DEBUG\n#include <debug_slephy.cpp>\n#else\n#define debug(...)\n#endif\n// ================================== ここまでテンプレ ==================================\n\n\nvoid solve(){\n ll x, y, s; cin >> x >> y >> s;\n if(x == 0) exit(0);\n\n // p円, x%\n auto add_tax = [&](ll p, ll x) -> ll {\n return floor(p * (100 + x), 100);\n };\n\n map<ll, ll> max_value;\n for(int p = 1; p < 1010; p++){\n ll t1 = add_tax(p, x);\n ll t2 = add_tax(p, y);\n chmax(max_value[t1], t2);\n }\n\n ll ans = 0;\n for(ll s1 = 1; s1 <= s-1; s1++){\n ll s2 = s - s1;\n ll this_ans = max_value[s1] + max_value[s2];\n chmax(ans, this_ans);\n }\n cout << ans << endl;\n}\n\nint main(int argc, char *argv[]){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n\n while(true) solve();\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3488, "score_of_the_acc": -0.85, "final_rank": 11 } ]
aoj_1196_cpp
Bridge Removal ICPC islands once had been a popular tourist destination. For nature preservation, however, the government decided to prohibit entrance to the islands, and to remove all the man-made structures there. The hardest part of the project is to remove all the bridges connecting the islands. There are n islands and n -1 bridges. The bridges are built so that all the islands are reachable from all the other islands by crossing one or more bridges. The bridge removal team can choose any island as the starting point, and can repeat either of the following steps. Move to another island by crossing a bridge that is connected to the current island. Remove one bridge that is connected to the current island, and stay at the same island after the removal. Of course, a bridge, once removed, cannot be crossed in either direction. Crossing or removing a bridge both takes time proportional to the length of the bridge. Your task is to compute the shortest time necessary for removing all the bridges. Note that the island where the team starts can differ from where the team finishes the work. Input The input consists of at most 100 datasets. Each dataset is formatted as follows. n p 2 p 3 ... p n d 2 d 3 ... d n The first integer n (3 ≤ n ≤ 800) is the number of the islands. The islands are numbered from 1 to n . The second line contains n -1 island numbers p i (1 ≤ p i < i ), and tells that for each i from 2 to n the island i and the island p i are connected by a bridge. The third line contains n -1 integers d i (1 ≤ d i ≤ 100,000) each denoting the length of the corresponding bridge. That is, the length of the bridge connecting the island i and p i is d i . It takes d i units of time to cross the bridge, and also the same units of time to remove it. Note that, with this input format, it is assured that all the islands are reachable each other by crossing one or more bridges. The input ends with a line with a single zero. Output For each dataset, print the minimum time units required to remove all the bridges in a single line. Each line should not have any character other than this number. Sample Input 4 1 2 3 10 20 30 10 1 2 2 1 5 5 1 8 8 10 1 1 20 1 1 30 1 1 3 1 1 1 1 0 Output for the Sample Input 80 136 2
[ { "submission_id": "aoj_1196_10853372", "code_snippet": "#include <stdio.h>\n#include <vector>\n#define MAX 810\n\nint n, p[MAX], d[MAX], check[MAX];\nint val, answer=2147483647;\nstruct data{\n\tint go, dis;\n};\nstd::vector<data> vec[MAX];\nint dy[MAX][2];\n\nvoid reset(void){\n\tint i;\n\tanswer=2147483647;\n\tfor (i=1;i<=n;i++){\n\t\tvec[i].clear();\n\t}\n}\n\nint max(int a, int b){\n\treturn (a>b) ? a : b;\n}\nint min(int a, int b){\n\treturn (a<b) ? a : b;\n}\n\nint dfs(int now, int root){\n\tint i, s, ret=0, t, minus=0;\n\tdata chd;\n\tcheck[now]=1;\n\ts=vec[now].size();\n\tfor (i=0;i<s;i++){\n\t\tchd=vec[now][i];\n\t\tif (check[chd.go]) continue;\n\t\tt=dfs(chd.go, root);\n\t\tif (t==0) ret+=chd.dis;\n\t\telse{\n\t\t\tret+=chd.dis*3+t;\n\t\t\tif (minus<chd.dis+t-min(dy[chd.go][0], dy[chd.go][1])){\n\t\t\t\tminus=chd.dis+t-min(dy[chd.go][0], dy[chd.go][1]);\n\t\t\t}\n\t\t}\n\t}\n\tdy[now][1]=ret;\n\tfor (i=0;i<s;i++){\n\t\tchd=vec[now][i];\n\t\tif (check[chd.go]) continue;\n\t\tif (ret-minus<dy[now][1] && minus!=100000000) dy[now][1]=ret-minus;\n\t}\n\tdy[now][0]=ret;\n\tcheck[now]=0;\n\treturn dy[now][0];\n}\n\nint main(void){\n\tint i, r;\n\tdata tmp;\n\tfor (;;){\n\t\tscanf(\"%d\", &n);\n\t\tif (n==0) break;\n\t\tfor (i=2;i<=n;i++) scanf(\"%d\", &p[i]);\n\t\tfor (i=2;i<=n;i++){\n\t\t\tscanf(\"%d\", &d[i]);\n\t\t\ttmp.go=p[i], tmp.dis=d[i];\n\t\t\tvec[i].push_back(tmp);\n\t\t\ttmp.go=i;\n\t\t\tvec[p[i]].push_back(tmp);\n\t\t}\n\n\t\tfor (r=1;r<=n;r++){\n\t\t\tval=dfs(r, r);\n\t\t\tif (min(dy[r][0],dy[r][1])<answer) answer=min(dy[r][0],dy[r][1]);\n\t\t\tfor (i=1;i<=n;i++){\n\t\t\t\tdy[i][0]=dy[i][1]=0;\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\", answer);\n\t\treset();\n\t}\n\treturn false;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 3104, "score_of_the_acc": -0.2604, "final_rank": 1 }, { "submission_id": "aoj_1196_10630144", "code_snippet": "//#pragma GCC optimize(\"O3\")\n#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,n) for (ll i=0;i<(ll)n;i++)\n#define rrep(i,n) for (ll i=n-1;i>=(ll)0;i--)\n#define loop(i,m,n) for(ll i=m;i<=(ll)n;i++)\n#define rloop(i,m,n) for(ll i=m;i>=(ll)n;i--)\n#define vl vector<ll>\n#define vvl vector<vector<ll>>\n#define vdbg(a) rep(ii,a.size()){cout<<a[ii]<<\" \";}cout<<endl;\n#define vpdbg(a) rep(ii,a.size()){cout<<\"{\"<<a[ii].first<<\",\"<<a[ii].second<<\"} \";}cout<<endl;\n#define vvdbg(a) rep(ii,a.size()){rep(jj,a[ii].size()){cout<<a[ii][jj]<<\" \";}cout<<endl;}\n#define setdbg(a) for(const auto & ii:a){cout<<ii<<\" \";}cout<<endl;\n#define inf 1e9\n#define mod 998244353LL\n//#define mod 1000000007LL\n#define eps 0.000000001\nrandom_device rnd;// 非決定的な乱数生成器\nmt19937 mt(rnd());// メルセンヌ・ツイスタの32ビット版、引数は初期シード\n\n//#include<boost/multiprecision/cpp_int.hpp>\n//#define bbi boost::multiprecision::cpp_int\n//#include<atcoder/lazysegtree>\n\n\n//整数同士の累乗の計算をする。\nll power(ll A, ll B) {\n\tll result = 1;\n\tfor (ll i=0;i<B;i++){\n\t\tresult *= A;\n\t}\n\treturn result;\n}\n\n// nのk乗をmodで割った余りを計算\nll power_mod(ll n, ll k){\n\tlong long result = 1;\n\twhile (k > 0){\n\t\tif ((k&1) ==1)result=(result*n)%mod;\n\t\tn=n*n%mod;\n\t\tk >>= 1;\n\t}\n\treturn result;\n}\n\n\n//受け取った2次元文字の外側に、文字pをコーティングする。\nvector<string> pad(vector<string> &s,char p){\n\tll h=s.size();\n\tll w=s[0].size();\n\tvector<string> res(h+2,string(w+2,p));\n\trep(i,h)rep(j,w)res[i+1][j+1]=s[i][j];\n\treturn res;\n}\n\n// Union-Find\nstruct UnionFind {\n\tvector<int> par, siz;\n\tUnionFind(int n) : par(n, -1) , siz(n, 1) { }\n\t// 根を求める\n\tint root(int x) {\n\t\tif (par[x] == -1) return x;\n\t\telse return par[x] = root(par[x]);\n\t}\n\t// x と y が同じグループに属するかどうか (根が一致するかどうか)\n\tbool issame(int x, int y) {\n\t\treturn root(x) == root(y);\n\t}\n\t// x を含むグループと y を含むグループとを併合する\n\tbool unite(int x, int y) {\n\t\tx = root(x), y = root(y);\n\t\tif (x == y) return false; \n\t\tif (siz[x] < siz[y]) swap(x, y);\n\t\tpar[y] = x;\n\t\tsiz[x] += siz[y];\n\t\treturn true;\n\t}\n\t// x を含むグループのサイズ\n\tint size(int x) {\n\t\treturn siz[root(x)];\n\t}\n};\n\n\n//グリッド問題等用\nvl dx={1,0,-1,0};\nvl dy={0,1,0,-1};\n\nvl dist;\nvector<vector<pair<ll,ll>>> g;\n\nvoid dfs(ll before,ll node){\n\trep(i,g[node].size()){\n\t\tif(g[node][i].first==before)continue;\n\t\t//次が葉じゃなければ遷移\n\t\tif(g[g[node][i].first].size()==1)continue;\n\t\tdist[g[node][i].first]=dist[node]+g[node][i].second;\n\t\tdfs(node,g[node][i].first);\n\t}\n}\n\nll solve(){\n\tll n;\n\tcin>>n;\n\tif(n==0){return 1;}\n\n\tdist=vl(n,0);\n\tg=vector<vector<pair<ll,ll>>>(n);\n\t\n\tvl p(n);\n\tvl d(n);\n\n\tll ans=0;\n\n\tloop(i,1,n-1)cin>>p[i],p[i]--;\n\tloop(i,1,n-1)cin>>d[i];\n\n\tloop(i,1,n-1){\n\t\tg[i].push_back({p[i],d[i]});\n\t\tg[p[i]].push_back({i,d[i]});\n\t\tans+=d[i];\n\t}\n\n\t//葉以外同士辺を全て2回足す\n\trep(i,n){\n\t\tif(g[i].size()==1)continue;\n\t\trep(j,g[i].size()){\n\t\t\tif(g[g[i][j].first].size()==1)continue;\n\t\t\tans+=g[i][j].second;\n\t\t}\n\t}\n\n\tll mxi;\n\trep(i,n){\n\t\tif(g[i].size()==1)continue;\n\t\tdfs(-1,i);\n\t\tmxi=i;\n\t\tbreak;\n\t}\n\n\trep(i,n){\n\t\tif(g[i].size()==1)continue;\n\t\tif(dist[i]>dist[mxi])mxi=i;\n\t}\n\tdist=vl(n);\n\tdfs(-1,mxi);\n\trep(i,n){\n\t\tif(g[i].size()==1)continue;\n\t\tif(dist[i]>dist[mxi])mxi=i;\n\t}\n\n\tans-=dist[mxi];\n\tcout<<ans<<endl;\n\treturn 0;\n}\n\n//メイン\nint main(){\n\twhile(solve()==0);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3544, "score_of_the_acc": -0.4867, "final_rank": 4 }, { "submission_id": "aoj_1196_10579935", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint diam(vector<vector<pair<int, int>>> G) {\n int N = G.size();\n auto D = [&] (int r) -> vector<int> {\n vector<int> d(N);\n auto dfs = [&] (auto dfs, int u, int p) -> void {\n for (auto [v, w] : G[u]) {\n if (v != p) {\n d[v] = d[u] + w;\n dfs(dfs, v, u);\n }\n }\n };\n dfs(dfs, r, -1);\n return d;\n };\n auto d = D(0);\n int r = max_element(d.begin(), d.end()) - d.begin();\n d = D(r);\n return *max_element(d.begin(), d.end());\n}\n\nbool solve() {\n int N;\n cin >> N;\n if (N == 0) return false;\n vector<int> P(N), D(N);\n for (int i = 1; i < N; i++) {\n cin >> P[i];\n P[i]--;\n }\n for (int i = 1; i < N; i++) cin >> D[i];\n vector<vector<pair<int, int>>> G(N);\n long long ans = 0;\n for (int i = 1; i < N; i++) {\n G[i].emplace_back(P[i], D[i]);\n G[P[i]].emplace_back(i, D[i]);\n ans += 3 * D[i];\n }\n vector<int> alive;\n for (int i = 0; i < N; i++) {\n if (G[i].size() > 1) alive.push_back(i);\n }\n vector<vector<pair<int, int>>> H(N);\n for (int u = 0; u < N; u++) {\n for (auto [v, w] : G[u]) {\n if (u < v) continue;\n if (G[u].size() > 1 && G[v].size() > 1) {\n int a = lower_bound(alive.begin(), alive.end(), u) - alive.begin();\n int b = lower_bound(alive.begin(), alive.end(), v) - alive.begin();\n H[a].emplace_back(b, w);\n H[b].emplace_back(a, w);\n } else {\n ans -= 2 * w;\n }\n }\n }\n ans -= diam(H);\n cout << ans << '\\n';\n return true;\n}\n\nint main() {\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3840, "score_of_the_acc": -0.8142, "final_rank": 15 }, { "submission_id": "aoj_1196_10571365", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint Diam(vector<vector<pair<int, int>>> G) {\n int N = G.size();\n auto BFS = [&] (int r) -> vector<int> {\n vector<int> D(N, 1 << 30);\n D[r] = 0;\n queue<int> q;\n q.push(r);\n while (q.size()) {\n int u = q.front();\n q.pop();\n for (auto [v, w] : G[u]) {\n if (D[v] > D[u] + w) {\n D[v] = D[u] + w;\n q.push(v);\n }\n }\n }\n return D;\n };\n auto D = BFS(0);\n int L = max_element(D.begin(), D.end()) - D.begin();\n D = BFS(L);\n return *max_element(D.begin(), D.end());\n}\n\nbool solve() {\n int N;\n cin >> N;\n if (N == 0) return false;\n vector<int> P(N), D(N);\n int ans = 0;\n for (int i = 1; i < N; i++) cin >> P[i], P[i]--;\n for (int i = 1; i < N; i++) cin >> D[i], ans += 3 * D[i];\n vector<vector<pair<int, int>>> G(N);\n for (int i = 1; i < N; i++) {\n G[i].emplace_back(P[i], D[i]);\n G[P[i]].emplace_back(i, D[i]);\n }\n vector<int> alive;\n for (int i = 0; i < N; i++) {\n if (G[i].size() >= 2) alive.push_back(i);\n }\n vector<int> id(N, -1);\n for (int i = 0; i < N; i++) {\n if (G[i].size() >= 2) {\n id[i] = lower_bound(alive.begin(), alive.end(), i) - alive.begin();\n }\n }\n int M = alive.size();\n vector<vector<pair<int, int>>> H(M);\n for (int u = 0; u < N; u++) {\n for (auto [v, d] : G[u]) {\n if (u > v) continue;\n if (G[u].size() >= 2 && G[v].size() >= 2) {\n H[id[u]].emplace_back(id[v], d);\n H[id[v]].emplace_back(id[u], d);\n } else {\n ans -= 2 * d;\n }\n }\n }\n cout << ans - Diam(H) << '\\n';\n return true;\n}\n\nint main() {\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3840, "score_of_the_acc": -0.8142, "final_rank": 15 }, { "submission_id": "aoj_1196_10554767", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define all(...) std::begin(__VA_ARGS__), std::end(__VA_ARGS__)\n#define rall(...) std::rbegin(__VA_ARGS__), std::rend(__VA_ARGS__)\n#define OVERLOAD_REP(_1, _2, _3, _4, name, ...) name\n#define REP1(n) for(ll i=0;i<(n);i++)\n#define REP2(i, n) for (ll i=0;i<(n);i++)\n#define REP3(i, a, n) for (ll i=a;i<(n);i++)\n#define REP4(i, a, b, n) for(ll i=a;i<(n);i+=b)\n#define rep(...) OVERLOAD_REP(__VA_ARGS__, REP4, REP3, REP2, REP1)(__VA_ARGS__)\n#define OVERLOAD_RREP(_1, _2, _3, _4, name, ...) name\n#define RREP1(n) for(ll i=(n)-1;i>=0;i--)\n#define RREP2(i, n) for(ll i=(n)-1;i>=0;i--)\n#define RREP3(i, a, n) for(ll i=(n)-1;i>=(a);i--)\n#define RREP4(i, a, b, n) for(ll i=(n)-1;i>=(a);i-=(b))\n#define rrep(...) OVERLOAD_RREP(__VA_ARGS__, RREP4, RREP3, RREP2, RREP1)(__VA_ARGS__)\n#define uniq(a) sort(all(a));a.erase(unique(all(a)),end(a))\n#define len(n) (long long)(n).size()\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vs = vector<string>;\nusing vvs = vector<vs>;\nusing vvvs = vector<vvs>;\nusing vld = vector<ld>;\nusing vvld = vector<vld>;\nusing vvvld = vector<vvld>;\nusing vc = vector<char>;\nusing vvc = vector<vc>;\nusing vvvc = vector<vvc>;\nusing pll = pair<ll,ll>;\nusing vpll = vector<pll>;\nusing vvpll = vector<vpll>;\n\nll intpow(ll a,ll b){\n ll ans = 1;\n while (b){\n if (b & 1){\n ans *= a;\n }\n a *= a;\n b /= 2;\n }\n return ans;\n}\nll modpow(ll a,ll b,ll c){\n ll ans = 1;\n while (b){\n if (b & 1){\n ans *= a;\n ans %= c;\n }\n a *= a;\n a %= c;\n b /= 2;\n }\n return ans;\n}\n\ntemplate<class... T>\nvoid input(T&... a){\n (cin >> ... >> a);\n}\n\n#define INT(...) int __VA_ARGS__; input(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__; input(__VA_ARGS__)\n#define ULL(...) ull __VA_ARGS__; input(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; input(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__; input(__VA_ARGS__)\n#define CHA(...) char __VA_ARGS__; input(__VA_ARGS__)\n#define VLL(name,length) vll name(length);rep(i,length){cin >> name[i];}\n#define VVLL(name,h,w) vvll name(h,vll(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVLL(name,a,b,c) vvvll name(a,vvll(b,vll(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VI(name,length) vi name(length);rep(i,length){cin >> name[i];}\n#define VVI(name,h,w) vvi name(h,vi(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVI(name,a,b,c) vvvi name(a,vvll(b,vi(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VLD(name,length) vld name(length);rep(i,length){cin >> name[i];}\n#define VVLD(name,h,w) vvld name(h,vld(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVLD(name,a,b,c) vvvld name(a,vvld(b,vld(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VC(name,length) vc name(length);rep(i,length){cin >> name[i];}\n#define VVC(name,h,w) vvc name(h,vc(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVC(name,a,b,c) vvvc name(a,vvc(b,vc(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define VS(name,length) vs name(length);rep(i,length){cin >> name[i];}\n#define VVS(name,h,w) vvs name(h,vs(w));rep(i,h)rep(j,w){cin >> name[i][j];}\n#define VVVS(name,a,b,c) vvvs name(a,vvs(b,vs(c)));rep(i,a)rep(j,b)rep(k,c){cin >> name[i][j][k];}\n#define PLL(name) pll name;cin>>name.first>>name.second;\n#define VPLL(name,length) vpll name(length);rep(i,length){cin>>name[i].first>>name[i].second;}\n\nvoid print(){cout << \"\\n\";}\n\ntemplate <typename T1, typename T2>\nstd::ostream& operator<<(std::ostream& os, const std::pair<T1, T2>& p) {\n os << \"(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\n\ntemplate <typename T>\nstd::ostream& operator<<(std::ostream& os, const std::vector<T>& vec) {\n os << \"[\";\n for (size_t i = 0; i < vec.size(); ++i) {\n os << vec[i];\n if (i + 1 < vec.size()) os << \", \";\n }\n os << \"]\";\n return os;\n}\n\ntemplate <typename T1, typename T2>\nstd::ostream& operator<<(std::ostream& os, const std::vector<std::pair<T1, T2>>& a) {\n os << \"[\";\n for (size_t j = 0; j < a.size(); ++j) {\n os << \"(\" << a[j].first << \", \" << a[j].second << \")\";\n\t\tif (j + 1 < a.size()) os << \", \";\n }\n\tos << \"]\";\n return os;\n}\n\ntemplate <typename T1, typename T2>\nstd::ostream& operator<<(std::ostream& os, const std::vector<std::vector<std::pair<T1, T2>>>& mat) {\n\tos << \"[\";\n for (size_t i = 0; i < mat.size(); ++i) {\n\t\tos << \"[\";\n for (size_t j = 0; j < mat[i].size(); ++j) {\n os << \"(\" << mat[i][j].first << \", \" << mat[i][j].second << \")\";\n\t\t\tif (j + 1 < mat[i].size()) os << \", \";\n }\n\t\tos << \"]\";\n\t\tif (i + 1 < mat.size()) os << \", \";\n }\n\tos << \"]\";\n return os;\n}\n\ntemplate <typename T>\nstd::ostream& operator<<(std::ostream& os, const std::set<T>& s) {\n os << \"{\";\n bool first = true;\n for (const auto& x : s) {\n if (!first) os << \", \";\n os << x;\n first = false;\n }\n os << \"}\";\n return os;\n}\n\ntemplate <typename K, typename V>\nstd::ostream& operator<<(std::ostream& os, const std::map<K, V>& m) {\n os << \"{\";\n bool first = true;\n for (const auto& [key, val] : m) {\n if (!first) os << \", \";\n os << key << \": \" << val;\n first = false;\n }\n os << \"}\";\n return os;\n}\n\ntemplate<class T, class... Ts>\nvoid print(const T& a, const Ts&... b){cout << a;(cout << ... << (cout << ' ', b));cout << '\\n';}\n\nvoid write(){cout << \"\\n\";}\ntemplate<class T, class... Ts>\nvoid write(const T& a, const Ts&... b){cout << a;(cout << ... << (cout << ' ', b));cout << '\\n';}\nvoid write(vll x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvll x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vi x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvi x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvvi x){rep(i,len(x))rep(j,len(x[i]))rep(k,len(x[i][j])){cout << x[i][j][k];if(k!=len(x[i][j])-1){cout << \" \";}else if(j!=len(x[i])-1){cout << \" | \";}else{cout << '\\n';}}}\nvoid write(vld x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvld x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvvld x){rep(i,len(x))rep(j,len(x[i]))rep(k,len(x[i][j])){cout << x[i][j][k];if(k!=len(x[i][j])-1){cout << \" \";}else if(j!=len(x[i])-1){cout << \" | \";}else{cout << '\\n';}}}\nvoid write(vc x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvc x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvvc x){rep(i,len(x))rep(j,len(x[i]))rep(k,len(x[i][j])){cout << x[i][j][k];if(k!=len(x[i][j])-1){cout << \" \";}else if(j!=len(x[i])-1){cout << \" | \";}else{cout << '\\n';}}}\nvoid write(vs x){rep(i,len(x)){cout << x[i];if(i!=len(x)-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvs x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j];if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\nvoid write(vvvs x){rep(i,len(x))rep(j,len(x[i]))rep(k,len(x[i][j])){cout << x[i][j][k];if(k!=len(x[i][j])-1){cout << \" \";}else if(j!=len(x[i])-1){cout << \" | \";}else{cout << '\\n';}}}\nvoid write(pll x){cout << x.first << ' ' << x.second << '\\n';}\nvoid write(vpll x){rep(i,len(x)){cout << x[i].first << ' ' << x[i].second << '\\n';}}\nvoid write(vvpll x){rep(i,len(x))rep(j,len(x[i])){cout << x[i][j].first << ' ' << x[i][j].second;if(j!=len(x[i])-1){cout << \" \";}else{cout << '\\n';}}}\n\ntemplate <typename T>\nT sum(const std::vector<T>& v) {\n return std::accumulate(v.begin(), v.end(), T(0));\n}\n\ntemplate<class T> bool chmin(T& a, const T& b){ if(a > b){ a = b; return 1; } return 0; }\ntemplate<class T> bool chmax(T& a, const T& b){ if(a < b){ a = b; return 1; } return 0; }\ntemplate<class T, class U> bool chmin(T& a, const U& b){ if(a > T(b)){ a = b; return 1; } return 0; }\ntemplate<class T, class U> bool chmax(T& a, const U& b){ if(a < T(b)){ a = b; return 1; } return 0; }\n\nlong long mod_mul(long long a, long long b, long long mod) {\n return (__int128)a * b % mod;\n}\n\nlong long mod_pow(long long a, long long b, long long mod) {\n long long result = 1;\n a %= mod;\n while (b > 0) {\n if (b & 1) result = mod_mul(result, a, mod);\n a = mod_mul(a, a, mod);\n b >>= 1;\n }\n return result;\n}\n\nbool MillerRabin(ll x){\n \n if(x <= 1){return false;}\n if(x == 2){return true;}\n if((x & 1) == 0){return false;}\n vll test;\n if(x < (1 << 30)){\n test = {2, 7, 61};\n } \n else{\n test = {2, 325, 9375, 28178, 450775, 9780504, 1795265022};\n }\n ll s = 0;\n ll d = x - 1;\n while((d & 1) == 0){\n s++;\n d >>= 1;\n }\n for(ll i:test){\n if(x <= i){return true;}\n ll y = mod_pow(i,d,x);\n if(y == 1 || y == x - 1){continue;}\n ll c = 0;\n for(int j=0;j<s-1;j++){\n y = mod_mul(y,y,x);\n if(y == x - 1){\n c = 1;\n break;\n }\n }\n if(c == 0){\n return false;\n }\n }\n return true;\n}\n\n#include<atcoder/dsu>\nvpll rle(vll seq){\n vpll res;\n for(auto x:seq){\n if(res.empty() || res.back().first != x){\n res.emplace_back(x,1);\n }\n else{\n res.back().second++;\n }\n }\n return res;\n}\nint main(){\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n \n while(1){\n LL(n);\n if(n == 0){break;}\n VLL(p,n-1);\n VLL(d,n-1);\n vvpll edge(n);\n vll deg(n,0);\n rep(i,n-1){\n edge[i+1].emplace_back(p[i]-1,d[i]);\n edge[p[i]-1].emplace_back(i+1,d[i]);\n deg[i+1]++;\n deg[p[i]-1]++;\n //print(i+1,p[i]-1,d[i]);\n }\n ll ans = 1LL<<60;\n vll dp1(n,1LL<<60);\n vll dp2(n,1LL<<60);\n auto dfs = [&](auto dfs, ll now, ll pa) -> void{\n dp1[now] = 0;\n vll a;\n vll b;\n for(auto [to,cost]:edge[now]){\n if(to == pa){\n continue;\n }\n if(deg[to] == 1){\n dp1[to] = 0;\n dp2[to] = 0;\n a.push_back(dp1[to]);\n b.push_back(dp2[to]);\n continue;\n }\n dfs(dfs,to,now);\n a.push_back(dp1[to] + 2 * cost);\n b.push_back(dp2[to] + 1 * cost);\n dp1[now] += dp1[to] + 2 * cost;\n }\n ll c = 1LL<<60;;\n rep(i,len(a)){\n chmin(c,-a[i]+b[i]);\n }\n dp2[now] = sum(a) + c;\n return;\n ll x = 0;\n rep(i,len(a)){\n ll temp = 0;\n rep(j,len(a)){\n temp += (i == j? b[j]:a[j]);\n }\n chmin(dp2[now],temp);\n }\n \n };\n\n rep(i,n){\n rep(j,n){\n dp1[j] = 1LL<<60;\n dp2[j] = 1LL<<60;\n \n }\n dfs(dfs,i,-1);\n chmin(ans,dp2[i]);\n //print(i,dp2[i] + sum(d),dp1,dp2);\n }\n print(ans + sum(d));\n //print(edge);\n }\n \n}", "accuracy": 1, "time_ms": 970, "memory_kb": 3840, "score_of_the_acc": -1.8142, "final_rank": 20 }, { "submission_id": "aoj_1196_10449339", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\nusing edge = pair<int, int>; // {to, cost}\n\nconstexpr int INF = 1e9;\nconstexpr bool DEBUG = false;\n\nvector<int> bfs(const int& n, const int& start_vertex, const vector<vector<edge>>& graph) {\n vector<int> dist(n, INF);\n queue<int> q;\n dist[start_vertex] = 0;\n q.push(start_vertex);\n\n while (!q.empty()) {\n const int from = q.front();\n q.pop();\n for (auto& [to, cost] : graph[from]) {\n if (dist[to] == INF) {\n dist[to] = dist[from] + cost;\n q.push(to);\n }\n }\n }\n\n return dist;\n}\n\nint solve(const int& n, const vector<int>& p, const vector<int>& d) {\n // グラフの作成\n int rm_cost = 0;\n vector<int> deg(n, 0);\n vector<vector<edge>> graph(n);\n for (int i = 0; i < n - 1; i++) {\n int u = i + 1;\n int v = p[i];\n int w = d[i];\n graph[u].emplace_back(v, w);\n graph[v].emplace_back(u, w);\n deg[u]++;\n deg[v]++;\n rm_cost += w;\n }\n\n // 葉を除いたグラフ作成\n int g_cost = 0;\n vector<vector<edge>> g(n);\n for (int i = 0; i < n - 1; i++) {\n int u = i + 1;\n int v = p[i];\n int w = d[i];\n if (deg[u] > 1 && deg[v] > 1) {\n g[u].emplace_back(v, w);\n g[v].emplace_back(u, w);\n g_cost += w;\n }\n }\n\n // 木の直径を求める\n int start_v = -1;\n for (int i = 0; i < n; i++) {\n if (deg[i] > 1) {\n start_v = i;\n }\n }\n const auto dist1 = bfs(n, start_v, g);\n\n int far_v = start_v;\n for (int i = 0; i < n; i++) {\n if (dist1[i] != INF && dist1[i] > dist1[far_v]) {\n far_v = i;\n }\n }\n const auto dist2 = bfs(n, far_v, g);\n\n int D = 0;\n for (int i = 0; i < n; i++) {\n if (dist2[i] != INF && dist2[i] > D) {\n D = dist2[i];\n }\n }\n\n // 答えを求める: 橋を取り除くコスト + 移動コスト(葉を除いたグラフの辺の総和*2 - 直径)\n const int mv_cost = g_cost * 2 - D;\n const int ret = rm_cost + mv_cost;\n if (DEBUG) {\n printf(\"%d+%d(2*%d-%d)=%d\\n\", rm_cost, mv_cost, g_cost, D, ret);\n }\n return ret;\n}\n\nint main() {\n while (true) {\n int n;\n cin >> n;\n if (n == 0) {\n break;\n }\n\n vector<int> p(n - 1);\n vector<int> d(n - 1);\n for (auto& pi : p) {\n cin >> pi;\n pi--;\n }\n for (auto& di : d) {\n cin >> di;\n }\n cout << solve(n, p, d) << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3584, "score_of_the_acc": -0.531, "final_rank": 7 }, { "submission_id": "aoj_1196_10449328", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\nusing edge = pair<int, int>; // {to, cost}\n\nconstexpr int INF = 1e9;\nconstexpr bool DEBUG = false;\n\nvector<int> bfs(const int& n, const int& start_vertex, const vector<vector<edge>>& graph) {\n vector<int> dist(n, INF);\n queue<int> q;\n dist[start_vertex] = 0;\n q.push(start_vertex);\n\n while (!q.empty()) {\n const int from = q.front();\n q.pop();\n for (auto& [to, cost] : graph[from]) {\n if (dist[to] == INF) {\n dist[to] = dist[from] + cost;\n q.push(to);\n }\n }\n }\n\n return dist;\n}\n\nint solve(const int& n, const vector<int>& p, const vector<int>& d) {\n // グラフの作成\n int rm_cost = 0;\n vector<int> deg(n, 0);\n vector<vector<edge>> graph(n);\n for (int i = 0; i < n - 1; i++) {\n int u = i + 1;\n int v = p[i];\n int w = d[i];\n graph[u].emplace_back(v, w);\n graph[v].emplace_back(u, w);\n deg[u]++;\n deg[v]++;\n rm_cost += w;\n }\n\n // 木の直径を求める(葉は考慮しない)\n int g_cost = 0;\n vector<vector<edge>> g(n);\n for (int i = 0; i < n - 1; i++) {\n int u = i + 1;\n int v = p[i];\n int w = d[i];\n if (deg[u] > 1 && deg[v] > 1) {\n g[u].emplace_back(v, w);\n g[v].emplace_back(u, w);\n g_cost += w;\n }\n }\n\n int start_v = -1;\n for (int i = 0; i < n; i++) {\n if (deg[i] > 1) {\n start_v = i;\n }\n }\n const auto dist1 = bfs(n, start_v, g);\n\n int far_v = start_v;\n for (int i = 0; i < n; i++) {\n if (dist1[i] != INF && dist1[i] > dist1[far_v]) {\n far_v = i;\n }\n }\n const auto dist2 = bfs(n, far_v, g);\n\n int D = 0;\n for (int i = 0; i < n; i++) {\n if (dist2[i] != INF && dist2[i] > D) {\n D = dist2[i];\n }\n }\n\n // 答えを求める: 橋を取り除くコスト + 移動コスト(葉を除いたグラフのコストの総和*2 - 直径)\n const int mv_cost = g_cost * 2 - D;\n const int ret = rm_cost + mv_cost;\n if (DEBUG) {\n printf(\"%d+%d(2*%d-%d)=%d\\n\", rm_cost, mv_cost, g_cost, D, ret);\n }\n return ret;\n}\n\nint main() {\n while (true) {\n int n;\n cin >> n;\n if (n == 0) {\n break;\n }\n\n vector<int> p(n - 1);\n vector<int> d(n - 1);\n for (auto& pi : p) {\n cin >> pi;\n pi--;\n }\n for (auto& di : d) {\n cin >> di;\n }\n cout << solve(n, p, d) << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3712, "score_of_the_acc": -0.6726, "final_rank": 12 }, { "submission_id": "aoj_1196_10449325", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\nusing edge = pair<int, int>; // {to, cost}\n\nconstexpr int INF = 1e9;\n\nvector<int> bfs(const int& n, const int& start_vertex, const vector<vector<edge>>& graph) {\n vector<int> dist(n, INF);\n queue<int> q;\n dist[start_vertex] = 0;\n q.push(start_vertex);\n\n while (!q.empty()) {\n const int from = q.front();\n q.pop();\n for (auto& [to, cost] : graph[from]) {\n if (dist[to] == INF) {\n dist[to] = dist[from] + cost;\n q.push(to);\n }\n }\n }\n\n return dist;\n}\n\nint solve(const int& n, const vector<int>& p, const vector<int>& d) {\n // グラフの作成\n int rm_cost = 0;\n vector<int> deg(n, 0);\n vector<vector<edge>> graph(n);\n for (int i = 0; i < n - 1; i++) {\n int u = i + 1;\n int v = p[i];\n int w = d[i];\n graph[u].emplace_back(v, w);\n graph[v].emplace_back(u, w);\n deg[u]++;\n deg[v]++;\n rm_cost += w;\n }\n\n // 木の直径を求める(葉は考慮しない)\n int g_cost = 0;\n vector<vector<edge>> g(n);\n for (int i = 0; i < n - 1; i++) {\n int u = i + 1;\n int v = p[i];\n int w = d[i];\n if (deg[u] > 1 && deg[v] > 1) {\n g[u].emplace_back(v, w);\n g[v].emplace_back(u, w);\n g_cost += w;\n }\n }\n\n\n int start_v = -1;\n for (int i = 0; i < n; i++) {\n if (deg[i] > 1) {\n start_v = i;\n }\n }\n const auto dist1 = bfs(n, start_v, g);\n\n int far_v = start_v;\n for (int i = 0; i < n; i++) {\n if (dist1[i] != INF && dist1[i] > dist1[far_v]) {\n far_v = i;\n }\n }\n const auto dist2 = bfs(n, far_v, g);\n\n int D = 0;\n for (int i = 0; i < n; i++) {\n if (dist2[i] != INF && dist2[i] > D) {\n D = dist2[i];\n }\n }\n\n // 答えを求める: 橋を取り除くコスト + 移動コスト(葉を除いたグラフのコストの総和*2 - 直径)\n const int mv_cost = g_cost * 2 - D;\n const int ret = rm_cost + mv_cost;\n // printf(\"%d+%d(2*%d-%d)=%d\\n\", rm_cost, mv_cost, g_cost, D, ret);\n return ret;\n}\n\nint main() {\n while (true) {\n int n;\n cin >> n;\n if (n == 0) {\n break;\n }\n\n vector<int> p(n - 1);\n vector<int> d(n - 1);\n for (auto& pi : p) {\n cin >> pi;\n pi--;\n }\n for (auto& di : d) {\n cin >> di;\n }\n cout << solve(n, p, d) << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3712, "score_of_the_acc": -0.6726, "final_rank": 12 }, { "submission_id": "aoj_1196_10449321", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\nusing edge = pair<int, int>; // {to, cost}\n\nconstexpr int INF = 1e9;\n\nvector<int> bfs(const int& n, const int& start_vertex, const vector<vector<edge>>& graph) {\n vector<int> dist(n, INF);\n queue<int> q;\n dist[start_vertex] = 0;\n q.push(start_vertex);\n\n while (!q.empty()) {\n const int from = q.front();\n q.pop();\n for (auto& [to, cost] : graph[from]) {\n if (dist[to] == INF) {\n dist[to] = dist[from] + cost;\n q.push(to);\n }\n }\n }\n\n return dist;\n}\n\nint solve(const int& n, const vector<int>& p, const vector<int>& d) {\n // グラフの作成\n vector<int> deg(n, 0);\n vector<vector<edge>> graph(n);\n for (int i = 1; i < n; i++) {\n graph[i].emplace_back(p[i - 1], d[i - 1]);\n graph[p[i - 1]].emplace_back(i, d[i - 1]);\n deg[i]++;\n deg[p[i - 1]]++;\n }\n\n // 木の直径を求める(葉は考慮しない)\n vector<vector<edge>> g(n);\n for (int i = 0; i < n - 1; i++) {\n int u = i + 1;\n int v = p[i];\n int w = d[i];\n if (deg[u] > 1 && deg[v] > 1) {\n g[u].emplace_back(v, w);\n g[v].emplace_back(u, w);\n }\n }\n\n\n int start_v = -1;\n for (int i = 0; i < n; i++) {\n if (deg[i] > 1) {\n start_v = i;\n }\n }\n const auto dist1 = bfs(n, start_v, g);\n\n int far_v = start_v;\n for (int i = 0; i < n; i++) {\n if (dist1[i] != INF && dist1[i] > dist1[far_v]) {\n far_v = i;\n }\n }\n const auto dist2 = bfs(n, far_v, g);\n\n int D = 0;\n for (int i = 0; i < n; i++) {\n if (dist2[i] != INF && dist2[i] > D) {\n D = dist2[i];\n }\n }\n\n // 答えを求める: 橋を取り除くコスト + 移動コスト(葉を除いたグラフのコストの総和*2 - 直径)\n int rm_cost = 0;\n for (auto& di : d) {\n rm_cost += di;\n }\n\n int g_cost = 0;\n for (int i = 0; i < n - 1; i++) {\n const int u = i + 1;\n const int v = p[i];\n if (deg[u] > 1 && deg[v] > 1) {\n g_cost += d[i];\n }\n }\n\n const int mv_cost = g_cost * 2 - D;\n const int ret = rm_cost + mv_cost;\n // printf(\"%d+%d(2*%d-%d)=%d\\n\", rm_cost, mv_cost, g_cost, D, ret);\n return ret;\n}\n\nint main() {\n while (true) {\n int n;\n cin >> n;\n if (n == 0) {\n break;\n }\n\n vector<int> p(n - 1);\n vector<int> d(n - 1);\n for (auto& pi : p) {\n cin >> pi;\n pi--;\n }\n for (auto& di : d) {\n cin >> di;\n }\n cout << solve(n, p, d) << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3712, "score_of_the_acc": -0.6726, "final_rank": 12 }, { "submission_id": "aoj_1196_9757618", "code_snippet": "#include <bits/stdc++.h>\n using namespace std;\n \n template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\n template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n #define rep(i,n) for (int i = 0; i < (n); ++i)\n\n typedef long long ll;\n typedef unsigned long long ull;\n using P=pair<int,int>;\n using T=tuple<ll,ll,ll>;\n const int INF=1001001001;\n const ll INFL=1e18;\n const int mod=998244353;\n\t\n\tvoid dfs(int v,int pre,vector<int>& mx,vector<vector<P>>& G){\n\t\tfor(auto[u,w]:G[v]){\n\t\t\tif(u==pre)continue;\n\t\t\tdfs(u,v,mx,G);\n\t\t\tchmax(mx[v],mx[u]+w);\n\t\t}\n\t}\n\n bool solve(){\n\t\tint n;\n\t\tcin>>n;\n\t\tif(!n)return false;\n\t\tvector<int>a(n),b(n),deg(n);\n\t\trep(i,n-1){\n\t\t\tcin>>a[i];\n\t\t\ta[i]--;\n\t\t\tdeg[a[i]]++;deg[i+1]++;\n\t\t}\n\t\trep(i,n-1){cin>>b[i];}\n\t\t\n\t\tvector<vector<P>>G(n);\n\t\tint tot=0;\n\t\trep(i,n-1){\n\t\t\tif(deg[a[i]]>1&&deg[i+1]>1){\n\t\t\t\ttot+=b[i]*3;\n\t\t\t\tG[i+1].push_back({a[i],b[i]});\n\t\t\t\tG[a[i]].push_back({i+1,b[i]});\n\t\t\t}else{\n\t\t\t\ttot+=b[i];\n\t\t\t}\n\t\t}\n\t\t\n\t\tint ans=INF;\n\t\trep(i,n){\n\t\t\tvector<int>mx(n);\n\t\t\tdfs(i,-1,mx,G);\n\t\t\tchmin(ans,tot-mx[i]);\n\t\t}\n\t\tcout<<ans<<endl;\n\t\t\n\t\treturn true;\n }\n\n int main(){\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n\t\twhile(1){\n\t\t\tif(!solve()){break;}\n\t\t}\n\t\t\n return 0;\n }", "accuracy": 1, "time_ms": 80, "memory_kb": 3584, "score_of_the_acc": -0.6039, "final_rank": 11 }, { "submission_id": "aoj_1196_9531684", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint Diam(int N, int S, vector<vector<pair<int,int>>>& G) {\n vector<int> DP(N,inf);\n queue<int> Q;\n DP[S] = 0;\n Q.push(S);\n while(!Q.empty()) {\n int P = Q.front();\n Q.pop();\n for (pair<int,int> E : G[P]) {\n if (DP[E.first] == inf) {\n DP[E.first] = DP[P] + E.second;\n Q.push(E.first);\n }\n }\n }\n int NS = -1, MAX = -1;\n rep(i,0,N) {\n if (DP[i] == inf) continue;\n if (DP[i] > MAX) {\n MAX = DP[i], NS = i;\n }\n }\n DP.assign(N,inf);\n DP[NS] = 0;\n Q.push(NS);\n while(!Q.empty()) {\n int P = Q.front();\n Q.pop();\n for (pair<int,int> E : G[P]) {\n if (DP[E.first] == inf) {\n DP[E.first] = DP[P] + E.second;\n Q.push(E.first);\n }\n }\n }\n int Ret = -1;\n rep(i,0,N) {\n if (DP[i] == inf) continue;\n chmax(Ret, DP[i]);\n }\n return Ret;\n}\n\nint main() {\nwhile(1) {\n int N;\n cin >> N;\n if (N == 0) return 0;\n vector<int> P(N,-1), D(N,0);\n vector<vector<pair<int,int>>> G(N);\n rep(i,1,N) cin >> P[i], P[i]--;\n rep(i,1,N) cin >> D[i];\n int ANS = 0;\n rep(i,1,N) {\n G[P[i]].push_back({i,D[i]});\n G[i].push_back({P[i],D[i]});\n ANS += D[i] * 3;\n }\n vector<int> S(N);\n rep(i,0,N) S[i] = G[i].size();\n rep(i,0,N) {\n if (S[i] == 1) {\n ANS -= G[i][0].second * 2;\n }\n }\n vector<vector<pair<int,int>>> NG(N);\n rep(i,0,N) {\n if (S[i] == 1) continue;\n for (pair<int,int> P : G[i]) {\n if (S[P.first] == 1) continue;\n NG[i].push_back(P);\n }\n }\n rep(i,0,N) {\n if (!NG[i].empty()) {\n ANS -= Diam(N,i,NG);\n break;\n }\n }\n cout << ANS << endl;\n}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3620, "score_of_the_acc": -0.5708, "final_rank": 8 }, { "submission_id": "aoj_1196_9447328", "code_snippet": "#include<bits/stdc++.h>\n// #include<atcoder/all>\n// #include<boost/multiprecision/cpp_int.hpp>\n\nusing namespace std;\n// using namespace atcoder;\n// using bint = boost::multiprecision::cpp_int;\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nusing P = pair<ll,ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing ve = vector<vector<int>>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\n#define rep(i,n) for(ll i = 0;i < (ll)n;i++)\n#define ALL(x) (x).begin(),(x).end()\n#define sz(c) ((ll)(c).size())\n#define LB(A,x) (int)(lower_bound(A.begin(),A.end(),x)-A.begin())\n#define UB(A,x) (int)(upper_bound(A.begin(),A.end(),x)-A.begin())\n// #define MOD 1000000007\n#define MOD 998244353\ntemplate<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T>ostream&operator<<(ostream&os,vector<T>&v){for(int i = 0;i < v.size();i++)os<<v[i]<<(i+1!=v.size()?\" \":\"\");return os;}\ntemplate<typename T>istream&operator>>(istream&is,vector<T>&v){for(T&in:v)is>>in;return is;}\ntemplate<typename T1,typename T2>ostream&operator<<(ostream&os,pair<T1,T2>&p){os<<p.first<<\" \"<<p.second;return os;}\ntemplate<typename T1,typename T2>istream&operator>>(istream&is,pair<T1,T2>&p){is>>p.first>>p.second;return is;}\ntemplate<typename T> inline bool chmax(T &a,T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> inline bool chmin(T &a,T b){if(a > b){a = b;return true;}return false;}\nld dist(ld x1,ld y1,ld x2, ld y2){return sqrtl((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));}\n\n// verify 木DP https://atcoder.jp/contests/dp/submissions/55190036\n// verify 全方位木DP(直径) https://onlinejudge.u-aizu.ac.jp/status/users/shkii/submissions/1/GRL_5_A/judge/9411502/C++17\n// verify 全方位木DP https://atcoder.jp/contests/arc179/submissions/55189994\ntuple<vector<int>,vector<int>,vector<int>> tree_dfs(vector<vector<int>> &v,int root = 0){\n int n = v.size();\n vector<int> par(n,-1); // par[i] := rootを根とした頂点iの親\n vector<int> par_idx(n,-1); // par_idx[ov] := v[ov]の中でpar[ov]がいるidx\n vector<int> order(n,-1); // order[i] := dfs帰りがけ順i番目の頂点。この昇順に木DP そのあと降順に全方位木DP\n int cnt = 0;\n auto dfs = [&](auto &dfs,int ov,int pre)->void{\n par[ov] = pre;\n for(int i = 0;i < v[ov].size();i++){\n int nv = v[ov][i];\n if(nv == pre){\n par_idx[ov] = i;\n continue;\n }\n dfs(dfs,nv,ov);\n }\n order[cnt++] = ov;\n };\n dfs(dfs,root,-1);\n return {par,par_idx,order};\n};\n\n\nint main(){\n \n ios_base::sync_with_stdio(0), cin.tie(0);\n while(1){\n int n;cin >> n;\n if(!n)break;\n vi p(n-1),d(n-1);\n cin >> p >> d;\n vi cnt(n);\n ll res = 0;\n rep(i,n-1){\n p[i]--;\n cnt[p[i]]++;cnt[i+1]++;\n res += d[i];\n }\n ve v(n);\n vvi w(n);\n int root = 0;\n rep(i,n-1){\n if(cnt[i+1] != 1 && cnt[p[i]] != 1){\n v[i+1].emplace_back(p[i]);\n v[p[i]].emplace_back(i+1);\n w[i+1].emplace_back(d[i]);\n w[p[i]].emplace_back(d[i]);\n res += 2*d[i];\n }\n }\n rep(i,n)if(cnt[i] != 1)root = i;\n vvi dp(n);\n auto [par,p_idx,ord] = tree_dfs(v,root);\n auto f = [](ll a,ll c,ll w){return max(a,c+w);};\n auto g = [](ll a,ll b){return max(a,b);};\n rep(_,n){\n int ov = ord[_];\n if(ov == -1)break;\n int deg = sz(v[ov]);\n dp[ov].resize(deg+1);\n rep(i,deg){\n int nv = v[ov][i];\n if(nv == par[ov])continue;\n dp[ov][i] = dp[nv][sz(v[nv])];\n dp[ov][deg] = f(dp[ov][deg],dp[ov][i],w[ov][i]);\n }\n }\n vi ans(n,-1);\n for(int _ = n-1;_ >= 0;_--){\n int ov = ord[_];\n if(ov == -1)continue;\n int deg = sz(v[ov]);\n vi L(deg+1),R(deg+1);\n rep(i,deg)L[i+1] = f(L[i],dp[ov][i],w[ov][i]);\n for(int i = deg-1;i >= 0;i--)R[i] = f(R[i+1],dp[ov][i],w[ov][i]);\n ans[ov] = L[deg];\n rep(i,deg){\n int nv = v[ov][i];\n if(nv == par[ov])continue;\n dp[nv][p_idx[nv]] = g(L[i],R[i+1]);\n }\n }\n res = res-*max_element(ALL(ans));\n cout << res << \"\\n\";\n }\n \n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3556, "score_of_the_acc": -0.5, "final_rank": 5 }, { "submission_id": "aoj_1196_9417088", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct Edge{\n int idx, val;\n Edge(int idx, int val) : idx(idx), val(val) {}\n};\n\nconstexpr long long INF = 1e18;\n\nint main() {\n while(true) {\n int N;\n cin >> N;\n if(N == 0) return 0;\n vector<vector<pair<int, Edge>>> G(N);\n vector<int> P(N), D(N);\n long long edge_sum = 0;\n for(int i = 1; i < N; i++) {\n cin >> P[i];\n P[i]--;\n }\n for(int i = 1; i < N; i++) {\n cin >> D[i];\n edge_sum += D[i];\n G[i].push_back({P[i], Edge(i, D[i])});\n G[P[i]].push_back({i, Edge(i, D[i])});\n }\n\n long long delete_sum = 0;\n set<int> delete_edge;\n for(int i = 0; i < N; i++) {\n if(G[i].size() != 1) continue;\n delete_edge.insert(G[i][0].second.idx);\n delete_sum += G[i][0].second.val;\n }\n \n int s = 0;\n while(G[s].size() == 1) s++;\n\n vector<long long> dist(N, INF);\n dist[s] = 0;\n priority_queue<pair<long long, int>> pq;\n pq.push({0, s});\n while(pq.size()) {\n auto [d, v] = pq.top(); pq.pop();\n for(auto [nv, e] : G[v]) {\n if(delete_edge.count(e.idx)) continue;\n if(dist[nv] <= dist[v] + e.val) continue;\n dist[nv] = dist[v] + e.val;\n pq.push({-dist[nv], nv});\n }\n }\n\n long long ma = 0;\n for(int i = 0; i < N; i++) {\n if(dist[i] == INF) continue;\n if(ma < dist[i]) {\n ma = dist[i];\n s = i;\n }\n }\n\n dist = vector<long long>(N, INF);\n dist[s] = 0;\n pq.push({0, s});\n while(pq.size()) {\n auto [d, v] = pq.top(); pq.pop();\n for(auto [nv, e] : G[v]) {\n if(delete_edge.count(e.idx)) continue;\n if(dist[nv] <= dist[v] + e.val) continue;\n dist[nv] = dist[v] + e.val;\n pq.push({-dist[nv], nv});\n }\n }\n\n ma = 0;\n for(int i = 0; i < N; i++) {\n if(dist[i] == INF) continue;\n if(ma < dist[i]) {\n ma = dist[i];\n s = i;\n }\n }\n\n long long ans = edge_sum + (edge_sum - delete_sum) * 2 - ma;\n cout << ans << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3488, "score_of_the_acc": -0.4352, "final_rank": 2 }, { "submission_id": "aoj_1196_9343042", "code_snippet": "// #pragma GCC target(\"avx2\")\n// #pragma GCC optimize(\"O3\")\n// #pragma GCC optimize(\"unroll-loops\")\n#include<bits/stdc++.h>\n#ifdef DEBUG\n#include \"cpp-dump/dump.hpp\"\n#define dump(...) cpp_dump(__VA_ARGS__)\n#else\n#define dump(...)\n#endif\nusing namespace std;\n#define rep(i,n) for (long long i=0;i<n;i++)\n#define loop(i,m,n) for(long long i=m;i<=n;i++)\n#define range(value,range) for(const auto &value : range)\n#define ll long long\n#define vl vector<long long>\n#define vvl vector<vector<long long>>\n#define vdbg(a) rep(ii,a.size()){cout<<a[ii]<<\" \";}cout<<endl;\n#define vvdbg(a) rep(ii,a.size()){rep(jj,a[ii].size()){cout<<a[ii][jj]<<\" \";}cout<<endl;}\n#define inf 4000000000000000000LL\n#define mod 998244353\nconst int lim = INT16_MAX;\nmap<pair<int, int>,ll> memo;\n\ntemplate<class Monoid> struct ReRooting {\n using Graph = vector<vector<int>>;\n using MergeFunc = function<Monoid(Monoid, Monoid)>;\n using AddNodeFunc = function<Monoid(int,int, Monoid)>;\n \n // core member\n Graph G;\n Monoid IDENTITY;\n MergeFunc MERGE;\n AddNodeFunc ADDNODE;\n \n // inner data\n vector<vector<Monoid>> dp;\n \n // constructor\n ReRooting() {}\n ReRooting(const Graph &g, const Monoid &identity,\n const MergeFunc &merge, const AddNodeFunc &addnode) {\n G = g;\n IDENTITY = identity;\n MERGE = merge;\n ADDNODE = addnode;\n build();\n }\n \n // re-looting dp\n Monoid rec(int v, int p) {\n Monoid res = IDENTITY;\n dp[v].assign(G[v].size(), IDENTITY);\n for (int i = 0; i < G[v].size(); ++i) {\n int v2 = G[v][i];\n if (v2 == p) continue;\n dp[v][i] = rec(v2, v);\n res = MERGE(res, dp[v][i]);\n }\n return ADDNODE(v,p, res);\n }\n void rerec(int v, int p, Monoid pval) {\n for (int i = 0; i < G[v].size(); ++i) {\n int v2 = G[v][i];\n if (v2 == p) {\n dp[v][i] = pval;\n continue;\n }\n }\n vector<Monoid> left(G[v].size() + 1, IDENTITY);\n vector<Monoid> right(G[v].size() + 1, IDENTITY);\n for (int i = 0; i < G[v].size(); ++i) {\n left[i + 1] = MERGE(left[i], dp[v][i]);\n right[i + 1] = MERGE(right[i], dp[v][(int)G[v].size() - i - 1]);\n }\n for (int i = 0; i < G[v].size(); ++i) {\n int v2 = G[v][i];\n if (v2 == p) continue;\n Monoid pval2 = MERGE(left[i], right[(int)G[v].size() - i - 1]);\n rerec(v2, v, ADDNODE(v,v2, pval2));\n }\n }\n void build() {\n dp.assign(G.size(), vector<Monoid>());\n int root = 0, nullparent = -1;\n rec(root, nullparent);\n rerec(root, nullparent, IDENTITY);\n }\n \n // getter\n Monoid get(int v) {\n Monoid res = IDENTITY;\n for (int i = 0; i < G[v].size(); ++i) {\n res = MERGE(res, dp[v][i]);\n }\n return ADDNODE(v,lim, res);\n }\n \n // dump\n friend constexpr ostream& operator << (ostream &os, const ReRooting<Monoid> &rr) {\n for (int v = 0; v < rr.G.size(); ++v) {\n for (int i = 0; i < rr.G[v].size(); ++i) {\n os << v << \" -> \" << rr.G[v][i] << \": \" << rr.dp[v][i] << endl;\n }\n }\n return os;\n }\n};\n\nll solve() {\n \n ll n;\n cin >> n;\n memo.clear();\n if (n == 0) return 1;\n vector<vector<int>> G(n);\n vector<ll> P(n), D(n);\n for (ll i = 0; i < n-1; ++i) {\n int p;\n cin >> p;\n --p;\n G[i+1].push_back(p);\n G[p].push_back(i+1);\n P[i] = p;\n }\n for (ll i = 0; i < n-1; ++i) {\n ll d;\n cin >> d;\n memo[{(int)i+1,P[i]}] = d;\n memo[{P[i],(int)i+1}] = d;\n }\n\n dump(memo);\n dump(G | cpp_dump::index());\n\n // 行って戻るコスト: 部分木の中のパスグラフの最大コスト\n using Monoid = pair<ll, ll>;\n Monoid identity = {0,0};\n auto merge = [&](Monoid a, Monoid b) -> Monoid{\n ll fir = a.first+b.first;\n ll sec = max(a.second, b.second);\n\n return {fir,sec};\n };\n\n auto addnode = [&](int from, int to, Monoid a) -> Monoid {\n if (to == lim) {\n return a;\n }\n\n if (a.first == 0) {\n return {memo[{from,to}],0};\n }\n\n return {memo[{from,to}]*3+a.first, memo[{from,to}]+a.second};\n };\n\n ReRooting<Monoid> reroot(G, identity,merge,addnode);\n\n ll ans = inf;\n for (ll i = 0; i < n; ++i) {\n ans = min(ans,reroot.get(i).first - reroot.get(i).second);\n }\n\n cout << ans << endl;\n\n return 0;\n\n}\n\nint main(){\n while(1){\n if(solve()==1)break;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4004, "score_of_the_acc": -1.0164, "final_rank": 17 }, { "submission_id": "aoj_1196_9343014", "code_snippet": "// #pragma GCC target(\"avx2\")\n// #pragma GCC optimize(\"O3\")\n// #pragma GCC optimize(\"unroll-loops\")\n#include<bits/stdc++.h>\n#ifdef DEBUG\n#include \"cpp-dump/dump.hpp\"\n#define dump(...) cpp_dump(__VA_ARGS__)\n#else\n#define dump(...)\n#endif\nusing namespace std;\n#define rep(i,n) for (long long i=0;i<n;i++)\n#define loop(i,m,n) for(long long i=m;i<=n;i++)\n#define range(value,range) for(const auto &value : range)\n#define ll long long\n#define vl vector<long long>\n#define vvl vector<vector<long long>>\n#define vdbg(a) rep(ii,a.size()){cout<<a[ii]<<\" \";}cout<<endl;\n#define vvdbg(a) rep(ii,a.size()){rep(jj,a[ii].size()){cout<<a[ii][jj]<<\" \";}cout<<endl;}\n#define inf 4000000000000000000LL\n#define mod 998244353\nconst int lim = INT16_MAX;\nmap<pair<int, int>,ll> memo;\n\ntemplate<class Monoid> struct ReRooting {\n using Graph = vector<vector<int>>;\n using MergeFunc = function<Monoid(Monoid, Monoid)>;\n using AddNodeFunc = function<Monoid(int,int, Monoid)>;\n \n // core member\n Graph G;\n Monoid IDENTITY;\n MergeFunc MERGE;\n AddNodeFunc ADDNODE;\n \n // inner data\n vector<vector<Monoid>> dp;\n \n // constructor\n ReRooting() {}\n ReRooting(const Graph &g, const Monoid &identity,\n const MergeFunc &merge, const AddNodeFunc &addnode) {\n G = g;\n IDENTITY = identity;\n MERGE = merge;\n ADDNODE = addnode;\n build();\n }\n \n // re-looting dp\n Monoid rec(int v, int p) {\n Monoid res = IDENTITY;\n dp[v].assign(G[v].size(), IDENTITY);\n for (int i = 0; i < G[v].size(); ++i) {\n int v2 = G[v][i];\n if (v2 == p) continue;\n dp[v][i] = rec(v2, v);\n res = MERGE(res, dp[v][i]);\n }\n return ADDNODE(v,p, res);\n }\n void rerec(int v, int p, Monoid pval) {\n for (int i = 0; i < G[v].size(); ++i) {\n int v2 = G[v][i];\n if (v2 == p) {\n dp[v][i] = pval;\n continue;\n }\n }\n vector<Monoid> left(G[v].size() + 1, IDENTITY);\n vector<Monoid> right(G[v].size() + 1, IDENTITY);\n for (int i = 0; i < G[v].size(); ++i) {\n left[i + 1] = MERGE(left[i], dp[v][i]);\n right[i + 1] = MERGE(right[i], dp[v][(int)G[v].size() - i - 1]);\n }\n for (int i = 0; i < G[v].size(); ++i) {\n int v2 = G[v][i];\n if (v2 == p) continue;\n Monoid pval2 = MERGE(left[i], right[(int)G[v].size() - i - 1]);\n rerec(v2, v, ADDNODE(v,v2, pval2));\n }\n }\n void build() {\n dp.assign(G.size(), vector<Monoid>());\n int root = 0, nullparent = -1;\n rec(root, nullparent);\n rerec(root, nullparent, IDENTITY);\n }\n \n // getter\n Monoid get(int v) {\n Monoid res = IDENTITY;\n for (int i = 0; i < G[v].size(); ++i) {\n res = MERGE(res, dp[v][i]);\n }\n return ADDNODE(v,lim, res);\n }\n \n // dump\n friend constexpr ostream& operator << (ostream &os, const ReRooting<Monoid> &rr) {\n for (int v = 0; v < rr.G.size(); ++v) {\n for (int i = 0; i < rr.G[v].size(); ++i) {\n os << v << \" -> \" << rr.G[v][i] << \": \" << rr.dp[v][i] << endl;\n }\n }\n return os;\n }\n};\n\nll solve() {\n \n ll n;\n cin >> n;\n memo.clear();\n if (n == 0) return 1;\n vector<vector<int>> G(n);\n vector<ll> P(n), D(n);\n for (ll i = 0; i < n-1; ++i) {\n int p;\n cin >> p;\n --p;\n G[i+1].push_back(p);\n G[p].push_back(i+1);\n P[i] = p;\n }\n for (ll i = 0; i < n-1; ++i) {\n ll d;\n cin >> d;\n memo[{(int)i+1,P[i]}] = d;\n memo[{P[i],(int)i+1}] = d;\n }\n\n dump(memo);\n dump(G | cpp_dump::index());\n\n // 行って戻るコスト: 部分木の中のパスグラフの最大コスト\n using Monoid = pair<ll, ll>;\n Monoid identity = {0,0};\n auto merge = [&](Monoid a, Monoid b) -> Monoid{\n ll fir = a.first+b.first;\n ll sec = max(a.second, b.second);\n\n return {fir,sec};\n };\n\n auto addnode = [&](int from, int to, Monoid a) -> Monoid {\n if (to == lim) {\n return a;\n }\n\n if (a.first == 0) {\n return {memo[{from,to}],0};\n }\n\n return {memo[{from,to}]*3+a.first, memo[{from,to}]+a.second};\n };\n\n ReRooting<Monoid> reroot(G, identity,merge,addnode);\n\n ll ans = inf;\n for (ll i = 0; i < n; ++i) {\n ans = min(ans,reroot.get(i).first - reroot.get(i).second);\n }\n\n cout << ans << endl;\n\n return 0;\n\n}\n\nint main(){\n while(1){\n if(solve()==1)break;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4008, "score_of_the_acc": -1.0208, "final_rank": 18 }, { "submission_id": "aoj_1196_9329403", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\n#define rep(i,n) for(int i = 0;i < n;i++)\n\n#define int ll\n\npair<int,int> far(int s, int n, const vector<vector<pair<int,int>>> &adj)\n{\n vector<int> dist(n, (1LL<<60));\n priority_queue<pair<int,int>> que;\n que.emplace(0,s);\n dist.at(s) = 0;\n\n while(!que.empty())\n {\n int d = - que.top().first;\n int now = que.top().second;\n que.pop();\n if(dist.at(now) < d) continue;\n dist.at(now) = d;\n for(auto [nxt, c] : adj.at(now))\n {\n if(dist.at(nxt) < d + c) continue;\n que.emplace(-(d+c), nxt);\n }\n }\n int pnt = s;\n int d = 0;\n rep(i,n)\n {\n if(dist.at(i) > d)\n {\n d = dist.at(i);\n pnt = i;\n }\n }\n return make_pair(pnt, d);\n}\n\nvoid main_()\n{\n int n;\n cin >> n;\n if(!n) exit(0);\n\n vector<int> b(n-1), c(n-1);\n rep(i,n-1) cin >> b[i];\n rep(i,n-1) b[i]--;\n rep(i,n-1) cin >> c[i];\n\n int sum_a = 0;\n rep(i,n-1) sum_a += c[i];\n\n vector<int> deg(n,1);\n deg[0] = 0;\n rep(i,n-1) deg.at(b[i]) += 1;\n\n set<int> st;\n rep(i,n)\n if(deg.at(i) >= 2) st.insert(i);\n\n int m = st.size();\n map<int, int> mp;\n int idx = 0;\n for(int i : st) mp[i] = idx++;\n // 1 ~ m\n vector<vector<pair<int,int>>> adj(m);\n int sum_b = 0;\n rep(i,n-1)\n {\n // i + 1 to b[i]\n int from = i + 1;\n if(st.find(from) == st.end()) continue;\n if(st.find(b[i]) == st.end()) continue;\n\n adj.at(mp[from]).emplace_back(mp[b[i]], c[i]);\n adj.at(mp[b[i]]).emplace_back(mp[from], c[i]);\n sum_b += c[i];\n }\n pair<int,int> one = far(0, m, adj);\n pair<int,int> two = far(one.first, m, adj);\n int dist = two.second;\n\n int ans = sum_a + (2*sum_b) - dist;\n cout << ans << endl;\n}\n\n\nsigned main()\n{\n while(1) main_();\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3624, "score_of_the_acc": -0.5856, "final_rank": 9 }, { "submission_id": "aoj_1196_9327982", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, a, n) for(int i = a; i < n; i++)\n#define rrep(i, a, n) for(int i = a; i >= n; i--)\n#define inr(l, x, r) (l <= x && x < r)\n#define ll long long\n#define ld long double\n\nconstexpr int IINF = 1001001001;\nconstexpr ll INF = 9e18;\n\ntemplate<class t,class u> void chmax(t&a,u b){if(a<b)a=b;}\ntemplate<class t,class u> void chmin(t&a,u b){if(b<a)a=b;}\n\nint main() {\n while(1){\n int n; cin >> n;\n if(n == 0) break;\n vector<vector<pair<int,int>>> g(n);\n vector<int> p(n-1), d(n-1);\n int dsum = 0;\n rep(i,0,n-1){\n cin >> p[i];\n p[i]--;\n }\n rep(i,0,n-1){\n cin >> d[i];\n dsum += d[i]*3;\n }\n rep(i,0,n-1){\n g[i+1].push_back({p[i],d[i]});\n g[p[i]].push_back({i+1,d[i]});\n }\n int ans = IINF;\n int maxdist;\n int res;\n\n auto dfs = [&](auto dfs, int v, int p, int dist)->void{\n if(g[v].size() >= 2 || g[v][0].first != p){\n chmax(maxdist, dist);\n }else{\n res -= 2*g[v][0].second;\n }\n for(auto nv: g[v]){\n if(nv.first == p) continue;\n dfs(dfs, nv.first, v, dist+nv.second);\n }\n };\n \n auto solve = [&](int i)->int{\n maxdist = 0;\n res = dsum;\n dfs(dfs, i, -1, 0);\n res -= maxdist;\n return res;\n };\n\n rep(i,0,n){\n chmin(ans,solve(i));\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3504, "score_of_the_acc": -0.5883, "final_rank": 10 }, { "submission_id": "aoj_1196_9269408", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nconst ll LINF = 1e18;\n\nint main(){\n while(1){\n int N; cin >> N;\n if(N == 0) break;\n vector<int> P(N - 1); for(int i = 0; i < N - 1; i++) cin >> P[i];\n vector<int> D(N - 1); for(int i = 0; i < N - 1; i++) cin >> D[i];\n\n vector<vector<pair<int, int>>> G(N);\n for(int i = 0; i < N - 1; i++){\n int u = P[i] - 1, v = i + 1;\n G[u].emplace_back(make_pair(v, D[i]));\n G[v].emplace_back(make_pair(u, D[i]));\n }\n\n auto dfs = [&](auto f, int u, int par) -> ll {\n ll res = 0;\n for(auto [v, d] : G[u]){\n\t\t\t\tif(v == par) continue;\n if(G[v].size() == 1) continue;\n else{\n res = max(res, f(f, v, u) + d);\n }\n }\n return res;\n };\n\n // auto rec = [&](auto f, int u, int par) -> ll {\n // ll res = 0;\n // for(auto [v, d] : G[u]){\n\t\t// \t\tcout << \"(\" << v << \",\" << d << \")\";\n // if(v == par) continue;\n // if(G[v].size() == 1) res += d;\n // else{\n // f(f, v, u);\n // res += d * 3;\n // }\n // }\n // return res;\n // };\n\n ll ans = LINF;\n\t\tll num = 0;\n\t\tfor(int i = 0; i < N; i++){\n\t\t\tfor(auto [j, d] : G[i]){\n\t\t\t\tif(i > j) continue;\n\t\t\t\tif(G[i].size() == 1 || G[j].size() == 1){\n\t\t\t\t\tnum += d;\n\t\t\t\t}\n\t\t\t\telse num += d * 3;\n\t\t\t}\n\t\t}\n for(int i = 0; i < N; i++){\n if(G[i].size() == 1) continue;\n\t\t\tll val = dfs(dfs, i, -1);\n\t\t\t// cout << num << \" \" << val << \" \";\n ans = min(ans, num - val);\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3484, "score_of_the_acc": -0.4829, "final_rank": 3 }, { "submission_id": "aoj_1196_9247544", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<n;i++)\n\nusing Edge=pair<int,int>;\nusing Graph=vector<vector<Edge>>;\n\n\n#define INF 1<<30\n\nvoid dijkstra(Graph& g, int s, int n, vector<int>& dist){\n dist.assign(n, INF);\n dist[s]=0;\n\n vector<int> seen(n,false);\n\n for(;;){\n int pos=-1;\n int mi=INF;\n rep(i,n){\n if(seen[i] || mi<= dist[i]) continue;\n pos=i;\n mi=dist[i];\n }\n if(pos==-1) break;\n\n seen[pos]=true;\n rep(i,g[pos].size()){\n int next=g[pos][i].first;\n int cost=g[pos][i].second;\n dist[next]=min(dist[next], dist[pos]+cost);\n }\n }\n}\n\nint solve(int n){\n vector<int> p(n-1), d(n-1);\n rep(i,n-1){cin>>p[i];p[i]--;}\n rep(i,n-1) cin>>d[i];\n\n int res=0;\n rep(i,n-1) res+=d[i];\n res*=3;\n\n Graph graph(n);\n rep(i,n-1){\n graph[i+1].push_back({p[i], d[i]});\n graph[p[i]].push_back({i+1, d[i]});\n }\n\n rep(i,n){\n if(graph[i].size()==1){\n res-=2*graph[i][0].second;\n int to=graph[i][0].first;\n graph[i][0].second=0;\n rep(j,graph[to].size()) if(graph[to][j].first==i) graph[to][j].second=0;\n }\n }\n\n vector<int> dist;\n dijkstra(graph,0,n,dist);\n int tmp=0;\n rep(i,n) if(dist[tmp]<dist[i]) tmp=i;\n dijkstra(graph,tmp,n,dist);\n tmp=0;\n rep(i,n) if(dist[tmp]<dist[i]) tmp=i;\n res-=dist[tmp];\n return res;\n\n}\n\nint main(){\n for(;;){\n int n; cin>>n;\n if(n==0) return 0;\n cout<<solve(n)<<endl;\n }\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3504, "score_of_the_acc": -0.5154, "final_rank": 6 }, { "submission_id": "aoj_1196_9180296", "code_snippet": "#include <bits/stdc++.h>\n\nbool solve() {\n int N;\n std::cin >> N;\n if (N == 0) return false;\n std::vector<std::vector<int>> g(N);\n for (int i{1} ; i < N ; i++) {\n int P;\n std::cin >> P;\n P--;\n g[P].push_back(i);\n g[i].push_back(P);\n }\n std::vector<int> D(N);\n for (int i{1} ; i < N ; i++) {\n std::cin >> D[i];\n }\n if (N == 2) {\n std::cout << D[1] << '\\n';\n return true;\n }\n auto cost{[&](int u, int v) -> int {\n assert(0 <= u and u < N);\n assert(0 <= v and v < N);\n return D[std::max(u, v)];\n }};\n std::vector<bool> leaf(N);\n for (int i{} ; i < N ; i++) {\n leaf[i] = (g[i].size() == 1u);\n }\n std::map<std::pair<int, int>, long long> dp1;\n // return to v\n auto rec1{[&](auto rec, int v, int p) -> long long {\n if (dp1.find(std::pair{ p, v }) != dp1.end()) {\n return dp1[std::pair{ p, v }];\n }\n long long res{};\n for (auto x : g[v]) {\n if (x == p) continue;\n if (leaf[x]) res += cost(v, x);\n else res += 3 * cost(v, x) + rec(rec, x, v);\n }\n return dp1[std::pair{ p, v }] = res;\n }};\n std::map<std::pair<int, int>, long long> dp2;\n auto rec2{[&](auto rec, int v, int p) -> long long {\n if (dp2.find(std::pair{ p, v }) != dp2.end()) {\n return dp2[std::pair{ p, v }];\n }\n long long base{};\n for (auto x : g[v]) {\n if (x == p) continue;\n if (leaf[x]) base += cost(v, x);\n else base += 3 * cost(v, x) + rec1(rec1, x, v);\n }\n long long res{base};\n for (auto x : g[v]) {\n if (x == p) continue;\n if (leaf[x]) continue;\n long long value{base};\n value -= 3 * cost(v, x) + rec1(rec1, x, v);\n value += 2 * cost(v, x) + rec(rec, x, v);\n res = std::min(res, value);\n }\n return dp2[std::pair{ p, v }] = res;\n }};\n long long ans{(long long)9e18};\n for (int s{} ; s < N ; s++) {\n if (leaf[s]) continue;\n ans = std::min(ans, rec2(rec2, s, -1));\n }\n std::cout << ans << '\\n';\n return true;\n}\n\nint main() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n while (solve()) ;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 3996, "score_of_the_acc": -1.1534, "final_rank": 19 } ]
aoj_1197_cpp
A Die Maker The work of die makers starts early in the morning. You are a die maker. You receive orders from customers, and make various kinds of dice every day. Today, you received an order of a cubic die with six numbers t 1 , t 2 , ..., t 6 on whichever faces. For making the ordered die, you use a tool of flat-board shape. You initially have a die with a zero on each face. If you rotate the die by 90 degrees on the tool towards one of northward, southward, eastward, and southward, the number on the face that newly touches the tool is increased by one. By rotating the die towards appropriate directions repeatedly, you may obtain the ordered die. The final numbers on the faces of the die is determined by the sequence of directions towards which you rotate the die. We call the string that represents the sequence of directions an operation sequence. Formally, we define operation sequences as follows. An operation sequence consists of n characters, where n is the number of rotations made. If you rotate the die eastward in the i -th rotation, the i -th character of the operation sequence is E . Similarly, if you rotate it westward, it is W , if southward, it is S , otherwise, if northward, it is N . For example, the operation sequence NWS represents the sequence of three rotations, northward first, westward next, and finally southward. Given six integers of the customer's order, compute an operation sequence that makes a die to order. If there are two or more possibilities, you should compute the earliest operation sequence in dictionary order. Input The input consists of multiple datasets. The number of datasets does not exceed 40. Each dataset has the following form. t 1 t 2 t 3 t 4 t 5 t 6 p q t 1 , t 2 , ..., t 6 are integers that represent the order from the customer. Further, p and q are positive integers that specify the output range of the operation sequence (see the details below). Each dataset satisfies 0 ≤ t 1 ≤ t 2 ≤ ... ≤ t 6 ≤ 5,000 and 1 ≤ p ≤ q ≤ t 1 + t 2 +...+ t 6 . A line containing six zeros denotes the end of the input. Output For each dataset, print the subsequence, from the p -th position to the q -th position, inclusively, of the operation sequence that is the earliest in dictionary order. If it is impossible to make the ordered die, print impossible . Here, dictionary order is recursively defined as follows. The empty string comes the first in dictionary order. For two nonempty strings x = x 1 ... x k and y = y 1 ... y l , the string x precedes the string y in dictionary order if x 1 precedes y 1 in alphabetical order ('A' to 'Z'), or x 1 and y 1 are the same character and x 2 ... x k precedes y 2 ... y l in dictionary order. Sample Input 1 1 1 1 1 1 1 6 1 1 1 1 1 1 4 5 0 0 0 0 0 2 1 2 0 0 2 2 2 4 5 9 1 2 3 4 5 6 15 16 0 1 2 3 5 9 13 16 2 13 22 27 31 91 100 170 0 0 0 0 0 0 Output for the Sample Input EEENEE NE impossible NSSNW EN EWNS SNSNSNSNSNSNSNSNSNSNSNSSNSNSNSNSNSNSNSNSNSNSNSNSNSNSNSNSNSNSNSNSNSNWEWE
[ { "submission_id": "aoj_1197_9857905", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n/**\n * @brief template\n */\n\nchar CINF = (char)('Z'+1);\nstring SINF(1,CINF);\n\nstring MOVE = \"ENSW\";\n\nstruct Dice {\n int A[6];\n int &operator[] (int i) {\n return A[i];\n }\n};\n\nDice rotE(Dice D) {\n Dice E;\n E[0] = D[1];\n E[1] = D[5];\n E[2] = D[2];\n E[3] = D[3];\n E[4] = D[0];\n E[5] = D[4];\n return E;\n}\n\nDice rotN(Dice D) {\n Dice E;\n E[0] = D[2];\n E[1] = D[1];\n E[2] = D[5];\n E[3] = D[0];\n E[4] = D[4];\n E[5] = D[3];\n return E;\n}\n\nDice rotS(Dice D) {\n Dice E;\n E[0] = D[3];\n E[1] = D[1];\n E[2] = D[0];\n E[3] = D[5];\n E[4] = D[4];\n E[5] = D[2];\n return E;\n}\n\nDice rotW(Dice D) {\n Dice E;\n E[0] = D[4];\n E[1] = D[0];\n E[2] = D[2];\n E[3] = D[3];\n E[4] = D[5];\n E[5] = D[1];\n return E;\n}\n\nDice rot(Dice D, int i) {\n if (i == 0) return rotE(D);\n if (i == 1) return rotN(D);\n if (i == 2) return rotS(D);\n if (i == 3) return rotW(D);\n return D;\n}\n\nstring Solve(vector<int> A) {\n auto Judge = [&](Dice D) -> bool {\n if (D[0] < 0) return false;\n int SUM = 0;\n rep(i,0,6) SUM += D[i];\n vector<int> Y(3);\n rep(i,0,3) Y[i] = D[i] + D[5-i];\n if (Y[0] > SUM / 2) return false;\n if (Y[1] > (SUM+1) / 2) return false;\n if (Y[2] > (SUM+1) / 2) return false;\n return true;\n };\n auto canMove = [&](Dice D, int i) -> bool {\n auto E = rot(D,i);\n E[0]--;\n return Judge(E);\n };\n bool check = false;\n Dice D;\n rep(i,0,6) D[i] = A[i];\n rep(i,0,4) {\n if (canMove(D,i)) check = true;\n }\n if (!check) return SINF;\n string Ret = \"\";\n int COUNT = 0;\n rep(i,0,6) COUNT += A[i];\n while(COUNT--) {\n int next = -1;\n rep(i,0,4) {\n if (canMove(D,i)) {\n next = i;\n break;\n }\n }\n Ret += MOVE[next];\n D = rot(D,next);\n D[0]--;\n }\n return Ret;\n}\n\nint main() {\nwhile(1) {\n vector<int> A(6);\n int COUNT = 0;\n rep(i,0,6) cin >> A[i], COUNT += A[i];\n if (COUNT == 0) return 0;\n int X, Y;\n cin >> X >> Y;\n X--;\n vector<int> ord(6);\n iota(ALL(ord),0);\n string ANS = SINF;\n do {\n vector<int> B(6);\n rep(i,0,6) B[i] = A[ord[i]];\n string Ret = Solve(B);\n chmin(ANS, Ret);\n } while(next_permutation(ALL(ord)));\n if (ANS == SINF) {\n cout << \"impossible\" << endl;\n }\n else {\n cout << ANS.substr(X,Y-X) << endl;\n }\n}\n}", "accuracy": 1, "time_ms": 6490, "memory_kb": 3260, "score_of_the_acc": -0.9462, "final_rank": 17 }, { "submission_id": "aoj_1197_9324064", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = int;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vd = vector<double>;\nusing vvd = vector<vd>;\nusing vvvd = vector<vvd>;\n#define all(A) A.begin(),A.end()\n#define ALL(A) A.begin(),A.end()\n#define rep(i, n) for (int i = 0; i < (int) (n); i++)\ntemplate<class T>\nbool chmax(T& p, T q) {\n if (p < q) {\n p = q; return 1;\n }\n return 0;\n};\ntemplate<class T>\nbool chmin(T& p, T q) {\n if (p > q) {\n p = q; return 1;\n }\n return 0;\n};\n\n\nvoid roll(vll &D, char C) {\n ll SV=D[0];\n if (C == 'E') {\n D[0] = D[1];\n D[1] = D[5];\n D[5] = D[3];\n D[3] = SV;\n }\n else if (C == 'W'){\n D[0] = D[3];\n D[3] = D[5];\n D[5] = D[1];\n D[1] = SV;\n }\n else if (C == 'N') {\n D[0] = D[4];\n D[4] = D[5];\n D[5] = D[2];\n D[2] = SV;\n }\n else if (C == 'S'){\n D[0] = D[2];\n D[2] = D[5];\n D[5] = D[4];\n D[4] = SV;\n }\n}\n\nbool is_valid(vll &D,char C){\n if(C=='E'||C=='W'){\n if(C=='E'&&D[1]==0)return 0;\n if(C=='W'&&D[3]==0)return 0;\n if (D[0] + D[5] > D[1] + D[2] + D[3] + D[4])return 0;\n if (D[1]-1 + D[3] > D[0] + D[2] + D[5] + D[4])return 0;\n if (D[2] + D[4] > D[1] + D[0] + D[3] + D[5])return 0;\n return 1;\n }\n if(C=='N'||C=='S'){\n if(C=='N'&&D[4]==0)return 0;\n if(C=='S'&&D[2]==0)return 0;\n if (D[0] + D[5] > D[1] + D[2] + D[3] + D[4])return 0;\n if (D[1] + D[3] > D[0] + D[2] + D[5] + D[4])return 0;\n if (D[2] + D[4]-1 > D[1] + D[0] + D[3] + D[5])return 0;\n return 1;\n }\n return 1;\n}\n\nvoid solve(vll D, ll S) {\n ll P, Q;\n cin >> P >> Q;\n P--; Q -= P;\n string AN ;\n rep(i,S)AN.push_back('Z');\n sort(all(D));\n ll MX=D[5];\n do {\n vll P = D;\n string R = \"\";\n string G = \"ENSW\";\n bool is_same=1;\n rep(i, S) {\n bool is_OK = 0;\n rep(k, 4) {\n if(i==0&&k!=0)break;\n if(is_valid(P,G[k])){\n roll(P, G[k]);\n P[0]--;\n R.push_back(G[k]);\n if(is_same&&G[k]>AN[i]){\n is_OK = 0;\n }\n if(G[k]<AN[i])is_same=0;\n is_OK = 1;\n break;\n }\n }\n if (!is_OK){\n R = \"Z\";\n break;\n }\n }\n chmin(AN, R);\n } while (next_permutation(all(D)));\n if (AN == \"Z\") {\n cout << \"impossible\" << endl;\n }\n else {\n cout << AN.substr(P, Q) << endl;\n }\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n vll D(6);\n while (1) {\n ll S = 0;\n rep(i, 6) {\n cin >> D[i];\n S += D[i];\n }\n if (S == 0)return 0;\n solve(D, S);\n }\n\n}", "accuracy": 1, "time_ms": 930, "memory_kb": 3512, "score_of_the_acc": -0.1398, "final_rank": 5 }, { "submission_id": "aoj_1197_9324063", "code_snippet": "#include <bits/stdc++.h>\n#include <time.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vd = vector<double>;\nusing vvd = vector<vd>;\nusing vvvd = vector<vvd>;\n#define all(A) A.begin(),A.end()\n#define ALL(A) A.begin(),A.end()\n#define rep(i, n) for (int i = 0; i < (int) (n); i++)\ntemplate<class T>\nbool chmax(T& p, T q) {\n if (p < q) {\n p = q; return 1;\n }\n return 0;\n};\ntemplate<class T>\nbool chmin(T& p, T q) {\n if (p > q) {\n p = q; return 1;\n }\n return 0;\n};\n\n\nvoid roll(vll &D, char C) {\n ll SV=D[0];\n if (C == 'E') {\n D[0] = D[1];\n D[1] = D[5];\n D[5] = D[3];\n D[3] = SV;\n }\n else if (C == 'W'){\n D[0] = D[3];\n D[3] = D[5];\n D[5] = D[1];\n D[1] = SV;\n }\n else if (C == 'N') {\n D[0] = D[4];\n D[4] = D[5];\n D[5] = D[2];\n D[2] = SV;\n }\n else if (C == 'S'){\n D[0] = D[2];\n D[2] = D[5];\n D[5] = D[4];\n D[4] = SV;\n }\n}\n\nbool is_valid(vll &D,char C){\n if(C=='E'||C=='W'){\n if(C=='E'&&D[1]==0)return 0;\n if(C=='W'&&D[3]==0)return 0;\n if (D[0] + D[5] > D[1] + D[2] + D[3] + D[4])return 0;\n if (D[1]-1 + D[3] > D[0] + D[2] + D[5] + D[4])return 0;\n if (D[2] + D[4] > D[1] + D[0] + D[3] + D[5])return 0;\n return 1;\n }\n if(C=='N'||C=='S'){\n if(C=='N'&&D[4]==0)return 0;\n if(C=='S'&&D[2]==0)return 0;\n if (D[0] + D[5] > D[1] + D[2] + D[3] + D[4])return 0;\n if (D[1] + D[3] > D[0] + D[2] + D[5] + D[4])return 0;\n if (D[2] + D[4]-1 > D[1] + D[0] + D[3] + D[5])return 0;\n return 1;\n }\n return 1;\n}\n\nbool is_valid(vll &D) {\n if (D[0]-1 + D[5] > D[1] + D[2] + D[3] + D[4])return 0;\n if (D[1] + D[3] > D[0] + D[2] + D[5] + D[4])return 0;\n if (D[2] + D[4] > D[1] + D[0] + D[3] + D[5])return 0;\n return 1;\n}\n\nvoid solve(vll D, ll S) {\n clock_t start = clock();\n ll P, Q;\n cin >> P >> Q;\n P--; Q -= P;\n string AN ;\n rep(i,S)AN.push_back('Z');\n sort(all(D));\n ll MX=D[5];\n do {\n vll P = D;\n string R = \"\";\n string G = \"ENSW\";\n bool is_same=1;\n rep(i, S) {\n bool is_OK = 0;\n rep(k, 4) {\n if(i==0&&k!=0)break;\n if(is_valid(P,G[k])){\n roll(P, G[k]);\n P[0]--;\n R.push_back(G[k]);\n if(is_same&&G[k]>AN[i]){\n is_OK = 0;\n }\n if(G[k]<AN[i])is_same=0;\n is_OK = 1;\n break;\n }\n }\n if (!is_OK){\n R = \"Z\";\n break;\n }\n }\n chmin(AN, R);\n } while (next_permutation(all(D)));\n if (AN == \"Z\") {\n cout << \"impossible\" << endl;\n }\n else {\n // cout<<\"OK\"<<endl;\n cout << AN.substr(P, Q) << endl;\n }\n clock_t end = clock();\n\n // const double time = static_cast<double>(end - start) / CLOCKS_PER_SEC * 1000.0;\n // cout<<time<<endl;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n vll D(6);\n while (1) {\n ll S = 0;\n rep(i, 6) {\n cin >> D[i];\n S += D[i];\n }\n if (S == 0)return 0;\n solve(D, S);\n }\n\n}", "accuracy": 1, "time_ms": 940, "memory_kb": 3588, "score_of_the_acc": -0.1635, "final_rank": 7 }, { "submission_id": "aoj_1197_9324060", "code_snippet": "#include <bits/stdc++.h>\n#include <time.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vd = vector<double>;\nusing vvd = vector<vd>;\nusing vvvd = vector<vvd>;\n#define all(A) A.begin(),A.end()\n#define ALL(A) A.begin(),A.end()\n#define rep(i, n) for (int i = 0; i < (int) (n); i++)\ntemplate<class T>\nbool chmax(T& p, T q) {\n if (p < q) {\n p = q; return 1;\n }\n return 0;\n};\ntemplate<class T>\nbool chmin(T& p, T q) {\n if (p > q) {\n p = q; return 1;\n }\n return 0;\n};\n\n\nvoid roll(vll &D, char C) {\n ll SV=D[0];\n if (C == 'E') {\n D[0] = D[1];\n D[1] = D[5];\n D[5] = D[3];\n D[3] = SV;\n }\n else if (C == 'W'){\n D[0] = D[3];\n D[3] = D[5];\n D[5] = D[1];\n D[1] = SV;\n }\n else if (C == 'N') {\n D[0] = D[4];\n D[4] = D[5];\n D[5] = D[2];\n D[2] = SV;\n }\n else if (C == 'S'){\n D[0] = D[2];\n D[2] = D[5];\n D[5] = D[4];\n D[4] = SV;\n }\n}\n\nbool is_valid(vll &D) {\n if (D[0]-1 + D[5] > D[1] + D[2] + D[3] + D[4])return 0;\n if (D[1] + D[3] > D[0] + D[2] + D[5] + D[4])return 0;\n if (D[2] + D[4] > D[1] + D[0] + D[3] + D[5])return 0;\n return 1;\n}\n\nvoid solve(vll D, ll S) {\n clock_t start = clock();\n ll P, Q;\n cin >> P >> Q;\n P--; Q -= P;\n string AN ;\n rep(i,S)AN.push_back('Z');\n sort(all(D));\n ll MX=D[5];\n do {\n vll P = D;\n string R = \"\";\n string G = \"ENSW\";\n bool is_same=1;\n rep(i, S) {\n bool is_OK = 0;\n rep(k, 4) {\n if(i==0&&k!=0)break;\n roll(P, G[k]);\n if (is_valid(P)&&P[0]>0) {\n P[0]--;\n R.push_back(G[k]);\n if(is_same&&G[k]>AN[i]){\n is_OK = 0;\n }\n if(G[k]<AN[i])is_same=0;\n is_OK = 1;\n break;\n }\n roll(P,G[3-k]);\n }\n if (!is_OK){\n R = \"Z\";\n break;\n }\n }\n chmin(AN, R);\n } while (next_permutation(all(D)));\n if (AN == \"Z\") {\n cout << \"impossible\" << endl;\n }\n else {\n // cout<<\"OK\"<<endl;\n cout << AN.substr(P, Q) << endl;\n }\n clock_t end = clock();\n\n // const double time = static_cast<double>(end - start) / CLOCKS_PER_SEC * 1000.0;\n // cout<<time<<endl;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n vll D(6);\n while (1) {\n ll S = 0;\n rep(i, 6) {\n cin >> D[i];\n S += D[i];\n }\n if (S == 0)return 0;\n solve(D, S);\n }\n\n}", "accuracy": 1, "time_ms": 1150, "memory_kb": 3496, "score_of_the_acc": -0.17, "final_rank": 8 }, { "submission_id": "aoj_1197_9324057", "code_snippet": "#include <bits/stdc++.h>\n#include <time.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vd = vector<double>;\nusing vvd = vector<vd>;\nusing vvvd = vector<vvd>;\n#define all(A) A.begin(),A.end()\n#define ALL(A) A.begin(),A.end()\n#define rep(i, n) for (int i = 0; i < (int) (n); i++)\ntemplate<class T>\nbool chmax(T& p, T q) {\n if (p < q) {\n p = q; return 1;\n }\n return 0;\n};\ntemplate<class T>\nbool chmin(T& p, T q) {\n if (p > q) {\n p = q; return 1;\n }\n return 0;\n};\n\n\nvll roll(vll &D, char C) {\n vll res = D;\n if (C == 'E') {\n res[0] = D[1];\n res[1] = D[5];\n res[5] = D[3];\n res[3] = D[0];\n }\n else if (C == 'W'){\n res[0] = D[3];\n res[3] = D[5];\n res[5] = D[1];\n res[1] = D[0];\n }\n else if (C == 'N') {\n res[0] = D[4];\n res[4] = D[5];\n res[5] = D[2];\n res[2] = D[0];\n }\n else if (C == 'S'){\n res[0] = D[2];\n res[2] = D[5];\n res[5] = D[4];\n res[4] = D[0];\n }\n return res;\n}\n\nbool is_valid(vll &D) {\n if (D[0]-1 + D[5] > D[1] + D[2] + D[3] + D[4])return 0;\n if (D[1] + D[3] > D[0] + D[2] + D[5] + D[4])return 0;\n if (D[2] + D[4] > D[1] + D[0] + D[3] + D[5])return 0;\n\n return 1;\n}\n\nvoid solve(vll D, ll S) {\n clock_t start = clock();\n ll P, Q;\n cin >> P >> Q;\n P--; Q -= P;\n string AN ;\n rep(i,S)AN.push_back('Z');\n sort(all(D));\n ll MX=D[5];\n do {\n vll P = D;\n string R = \"\";\n string G = \"ENSW\";\n bool is_same=1;\n rep(i, S) {\n bool is_OK = 0;\n rep(k, 4) {\n if(i==0&&k!=0)break;\n vll NP = roll(P, G[k]);\n if (is_valid(NP)&&NP[0]>0) {\n P = NP;\n P[0]--;\n R.push_back(G[k]);\n if(is_same&&G[k]>AN[i]){\n is_OK = 0;\n }\n if(G[k]<AN[i])is_same=0;\n is_OK = 1;\n break;\n }\n }\n if (!is_OK){\n R = \"Z\";\n break;\n }\n }\n chmin(AN, R);\n } while (next_permutation(all(D)));\n if (AN == \"Z\") {\n cout << \"impossible\" << endl;\n }\n else {\n // cout<<\"OK\"<<endl;\n cout << AN.substr(P, Q) << endl;\n }\n clock_t end = clock();\n\n // const double time = static_cast<double>(end - start) / CLOCKS_PER_SEC * 1000.0;\n // cout<<time<<endl;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n vll D(6);\n while (1) {\n ll S = 0;\n rep(i, 6) {\n cin >> D[i];\n S += D[i];\n }\n if (S == 0)return 0;\n solve(D, S);\n }\n\n}", "accuracy": 1, "time_ms": 4490, "memory_kb": 3528, "score_of_the_acc": -0.7077, "final_rank": 16 }, { "submission_id": "aoj_1197_9298481", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, t) for (int i = (int)(s); i < (int)(t); ++i)\n#define revrep(i, t, s) for (int i = (int)(t) - 1; i >= (int)(s); --i)\n#define all(x) begin(x), end(x)\ntemplate <typename T>\nbool chmax(T& a, const T& b) {\n return a < b ? (a = b, 1) : 0;\n}\ntemplate <typename T>\nbool chmin(T& a, const T& b) {\n return a > b ? (a = b, 1) : 0;\n}\n\nstruct Die {\n int top = 1, south = 2, east = 3, west = 4, north = 5, bottom = 6;\n\n void roll(char dir) {\n if (dir == 'N') {\n int tmp = top;\n top = south;\n south = bottom;\n bottom = north;\n north = tmp;\n } else if (dir == 'E') {\n int tmp = top;\n top = west;\n west = bottom;\n bottom = east;\n east = tmp;\n } else if (dir == 'W') {\n int tmp = top;\n top = east;\n east = bottom;\n bottom = west;\n west = tmp;\n } else if (dir == 'S') {\n int tmp = top;\n top = north;\n north = bottom;\n bottom = south;\n south = tmp;\n } else {\n assert(false);\n }\n }\n};\n\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v) {\n for (int i = 0; i < (int)v.size(); ++i) {\n os << v[i];\n if (i < (int)v.size() - 1) os << \" \";\n }\n return os;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(15);\n\n const string dir = \"ENSW\";\n\n auto check = [&](vector<int>& val, int cur) {\n int sum = 0;\n rep(i, 0, 6) {\n if (val[i] < 0) return false;\n sum += val[i];\n }\n rep(i, 0, 3) {\n int x = val[i] + val[5 - i];\n if (i == min(cur, 5 - i)) {\n if (sum - x < x) return false;\n } else {\n if (sum - x < x - 1) return false;\n }\n }\n return true;\n };\n\n while (true) {\n vector<int> t(6);\n int sum = 0;\n for (auto& x : t) cin >> x, sum += x;\n if (t[5] == 0) break;\n int p, q;\n cin >> p >> q;\n --p;\n\n string ans = \"Z\";\n\n vector<int> idx(6);\n iota(all(idx), 0);\n do {\n vector<int> val(6);\n rep(v, 0, 6) val[v] = t[idx[v]];\n if (val[0] == 0) continue;\n --val[0];\n string res = \"E\";\n Die die;\n die.roll('N');\n die.roll('N');\n // 1 is facing down\n\n int edges = sum - 1;\n rep(t, 0, sum - 1) {\n char move = '?';\n --edges;\n for (char c : dir) {\n die.roll(c);\n --val[die.bottom - 1];\n if (check(val, die.bottom - 1)) {\n move = c;\n break;\n } else {\n ++val[die.bottom - 1];\n die.roll(c);\n die.roll(c);\n die.roll(c);\n }\n }\n if (move == '?') {\n res = \"Z\";\n break;\n }\n res.push_back(move);\n }\n chmin(ans, res);\n } while (next_permutation(all(idx)));\n\n cout << (ans == \"Z\" ? \"impossible\" : ans.substr(p, q - p)) << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 2210, "memory_kb": 3456, "score_of_the_acc": -0.326, "final_rank": 13 }, { "submission_id": "aoj_1197_9248869", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(\"unroll-loops\")\n\nusing ll = long long;\n\ntemplate<class T>\nbool chmin(T &a, const T &b) {if (a > b) {a = b; return 1;} return 0;}\n\nbool is_end = false;\n\nstring ENSW = \"ENSW\";\n\n// origin = {0, 1, 2, 3, 4, 5}\nint rotate_dice[4][6] = \n{\n {2, 1, 5, 0, 4, 3}, // to E\n {4, 0, 2, 3, 5, 1}, // to N\n {1, 5, 2, 3, 0, 4}, // to S\n {3, 1, 0, 5, 4, 2} // to W\n};\n\nbool isvalid(const array<int, 6> &vec)\n{\n if (vec[0] < 0) return false;\n int sum = accumulate(vec.begin(), vec.end(), 0);\n \n if (2 * vec[0] + 2 * vec[5] > sum) return false;\n if (2 * vec[1] + 2 * vec[4] - 1 > sum) return false;\n if (2 * vec[2] + 2 * vec[3] - 1 > sum) return false;\n \n return true;\n}\n\nbool is_zero(const array<int, 6> &dice)\n{\n for (uint i = 0; i < 6; ++i)\n {\n if (dice[i] != 0) return false;\n }\n return true;\n}\n\n\nvector<int> global_vec(30000 + 100);\n\nbool dfs(int depth, array<int, 6> dice)\n{\n if (depth == 0) return true;\n \n for (uint dir = 0; dir < 4; ++dir)\n {\n array<int, 6> ndice = dice;\n for (int j = 0; j < 6; ++j) ndice[j] = dice[rotate_dice[dir][j]];\n ndice[0] -= 1;\n \n if (!isvalid(ndice)) continue;\n \n global_vec[depth] = dir;\n if (dfs(depth - 1, ndice)) return true;\n // global_vec.pop_back();\n }\n \n return false;\n}\n\n\nvoid solve()\n{\n array<int, 6> T;\n for (uint i = 0; i < 6; ++i) cin >> T[i];\n if (T[5] == 0)\n {\n is_end = true;\n return;\n }\n int P, Q; cin >> P >> Q;\n P--, Q--;\n \n int sum = accumulate(T.begin(), T.end(), 0);\n \n string res = \"Z\";\n do\n {\n \n if (dfs(sum, T))\n {\n string tmp = \"\";\n for (uint i = sum; i > 0; --i)\n {\n tmp += ENSW[global_vec[i]];\n }\n chmin(res, tmp);\n }\n \n } while (next_permutation(T.begin(), T.end()));\n \n if (res == \"Z\") cout << \"impossible\" << endl;\n else\n {\n string ans = res.substr(P, Q + 1 - P);\n cout << ans << endl;\n // cerr << -1 << endl;\n // cout << res << endl;\n }\n \n return;\n}\n\nint main()\n{\n while (!is_end)\n {\n solve();\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 1540, "memory_kb": 6696, "score_of_the_acc": -1.163, "final_rank": 20 }, { "submission_id": "aoj_1197_9070212", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\n} // namespace macro\n\nusing namespace macro;\n#line 3 \"A.cpp\"\n\nconst string op = \"ENSW\";\nusing dice = array<int, 6>;\nenum { l, r, f, b, d, u };\nconst vector<dice> g = {\n {d, u, f, b, r, l},\n {l, r, d, u, b, f},\n {l, r, u, d, f, b},\n {u, d, f, b, l, r}\n};\n\nstring solve(dice t) {\n sort(t);\n const int len = accumulate(t.begin(), t.end(), 0);\n string ans(len, 'Z');\n\n auto check = [&](dice& x) -> bool {\n for(int i : rep(6)) if(x[i] < 0) return false;\n int sum = accumulate(x.begin(), x.end(), 0);\n return x[0] + x[1] <= sum - (x[0] + x[1]) + 1\n and x[2] + x[3] <= sum - (x[2] + x[3]) + 1\n and x[4] + x[5] <= sum - (x[4] + x[5]) + 0;\n };\n\n do {\n if(check(t)) {\n string s = \"\";\n dice x = t;\n while(x != dice{}) {\n for(int k : rep(4)) {\n dice nx;\n for(int i : rep(6)) nx[i] = x[g[k][i]];\n nx[4] -= 1;\n if(check(nx)) {\n s += op[k];\n x = move(nx);\n break;\n }\n }\n }\n chmin(ans, s);\n }\n } while(next_permutation(t.begin(), t.end()));\n\n int p = in(), q = in(); p--;\n if(ans[0] == 'Z') return \"impossible\";\n return move(ans.substr(p, q - p));\n}\n\nint main() {\n while(true) {\n dice t;\n for(int i : rep(6)) t[i] = in();\n if(t == dice{}) return 0;\n print(solve(t));\n }\n}", "accuracy": 1, "time_ms": 1570, "memory_kb": 3504, "score_of_the_acc": -0.2387, "final_rank": 12 }, { "submission_id": "aoj_1197_9070202", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\n} // namespace macro\n\nusing namespace macro;\n#line 3 \"A.cpp\"\n\nconst string op = \"ENSW\";\nenum { l, r, f, b, d, u };\nconst vector<vector<int>> g = {\n {d, u, f, b, r, l},\n {l, r, d, u, b, f},\n {l, r, u, d, f, b},\n {u, d, f, b, l, r}\n};\n\nstring solve(vector<int> t) {\n sort(t);\n const int len = accumulate(t.begin(), t.end(), 0);\n string ans(len, 'Z');\n\n auto check = [&](vector<int>& x) -> bool {\n for(int i : rep(6)) if(x[i] < 0) return false;\n int sum = accumulate(x.begin(), x.end(), 0);\n return x[0] + x[1] <= sum - (x[0] + x[1]) + 1\n and x[2] + x[3] <= sum - (x[2] + x[3]) + 1\n and x[4] + x[5] <= sum - (x[4] + x[5]) + 0;\n };\n\n do {\n if(check(t)) {\n string s = \"\";\n vector<int> x = t;\n while(x != vector(6, 0)) {\n for(int k : rep(4)) {\n vector<int> nx(6);\n for(int i : rep(6)) nx[i] = x[g[k][i]];\n nx[4] -= 1;\n if(check(nx)) {\n s += op[k];\n x = move(nx);\n break;\n }\n }\n }\n chmin(ans, s);\n }\n } while(next_permutation(t.begin(), t.end()));\n\n int p = in(), q = in(); p--;\n if(ans[0] == 'Z') return \"impossible\";\n return move(ans.substr(p, q - p));\n}\n\nint main() {\n while(true) {\n vector<int> t = in(6);\n if(t == vector<int>(6, 0)) return 0;\n print(solve(t));\n }\n}", "accuracy": 1, "time_ms": 6360, "memory_kb": 3492, "score_of_the_acc": -0.9932, "final_rank": 18 }, { "submission_id": "aoj_1197_9035374", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\n#define rep(i, a, b) for(ll i = a; i < b; ++i)\n#define rrep(i, a, b) for(ll i = a; i >= b; --i)\nconstexpr ll inf = 4e18;\n\nbool check(vector<int> mass) {\n bool ok = true;\n if(mass[0]+mass[1] > mass[2]+mass[3]+mass[4]+mass[5]) ok = false;\n if(mass[2]+mass[3]-1 > mass[0]+mass[1]+mass[4]+mass[5]) ok = false;\n if(mass[4]+mass[5]-1 > mass[0]+mass[1]+mass[2]+mass[3]) ok = false;\n return ok;\n}\nint main(void) {\n cin.tie(0);\n ios::sync_with_stdio(0);\n vector<char> dir = {'E', 'N', 'S', 'W'};\n\n while(1) {\n string min_ans = \"\";\n vector<int> mass(6);\n rep(i, 0, 6) cin >> mass[i];\n bool end = true;\n rep(i, 0, 6) if(mass[i] != 0) end = false;\n if(end) break;\n int ans_l = 0;\n rep(i, 0, 6) ans_l += mass[i];\n do {\n string ans = \"\";\n vector<int> n_mass(6);\n rep(i, 0, 6) n_mass[i] = mass[i];\n\n if(!check(n_mass)) continue;\n while(1) {\n bool end = true;\n rep(i, 0, 6) if(n_mass[i] != 0) end = false;\n if(end) {\n if(min_ans == \"\") min_ans = ans;\n else if(min_ans > ans) min_ans = ans;\n break;\n }\n if(!check(n_mass)) break;\n rep(i, 0, 4) {\n vector<int> nv;\n if(i==0 and n_mass[2] != 0) {\n nv = {n_mass[2]-1, n_mass[3], n_mass[1], n_mass[0], n_mass[4], n_mass[5]};\n if(check(nv)) {\n swap(n_mass, nv);\n ans.push_back(dir[i]);\n break;\n }\n }\n else if(i==1 and n_mass[4] != 0) {\n nv = {n_mass[4]-1, n_mass[5], n_mass[2], n_mass[3], n_mass[1], n_mass[0]};\n if(check(nv)) {\n swap(n_mass, nv);\n ans.push_back(dir[i]);\n break;\n }\n }\n else if(i==2 and n_mass[5] != 0) {\n nv = {n_mass[5]-1, n_mass[4], n_mass[2], n_mass[3], n_mass[0], n_mass[1]};\n if(check(nv)) {\n swap(n_mass, nv);\n ans.push_back(dir[i]);\n break;\n }\n }\n else if(i==3 and n_mass[3] != 0) {\n nv = {n_mass[3]-1, n_mass[2], n_mass[0], n_mass[1], n_mass[4], n_mass[5]};\n if(check(nv)) {\n swap(n_mass, nv);\n ans.push_back(dir[i]);\n break;\n }\n }\n \n }\n }\n } while(next_permutation(mass.begin(), mass.end()));\n // cout << endl << endl << min_ans << endl;\n int p, q;\n cin >> p >> q;\n if(min_ans == \"\") {\n cout << \"impossible\" << endl;\n continue;\n }\n for(int i=p-1; i<q; i++) cout << min_ans[i];\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 6830, "memory_kb": 3548, "score_of_the_acc": -1.0838, "final_rank": 19 }, { "submission_id": "aoj_1197_7984127", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(i, s, n) for (int i = (int)(s); i < (int)(n); i++)\n#define rrep(i, s, n) for (int i = (int)(n)-1; i >= (int)(s); i--)\n#define all(v) v.begin(), v.end()\n\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n\ntemplate <typename T> bool chmin(T &a, const T &b) {\n if (a <= b) return false;\n a = b;\n return true;\n}\ntemplate <typename T> bool chmax(T &a, const T &b) {\n if (a >= b) return false;\n a = b;\n return true;\n}\n\n#define debug(...) \\\n std::cerr << \"LINE: \" << __LINE__ << \" [\" << #__VA_ARGS__ << \"]:\", \\\n debug_out(__VA_ARGS__)\n\nvoid debug_out() {\n std::cerr << std::endl;\n}\n\ntemplate <typename Head, typename... Tail> void debug_out(Head h, Tail... t) {\n std::cerr << \" \" << h;\n if (sizeof...(t) > 0) std::cerr << \" :\";\n debug_out(t...);\n}\n\ntemplate <typename T1, typename T2>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T1, T2> &pa) {\n return os << pa.first << \" \" << pa.second;\n}\n\ntemplate <typename T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &vec) {\n for (std::size_t i = 0; i < vec.size(); i++)\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \" \");\n return os;\n}\n\ntypedef std::string::const_iterator State;\n\nbool expect(State &begin, char expected) {\n return *begin == expected;\n}\n\nvoid consume(State &begin, char expected) {\n assert(*begin == expected);\n begin++;\n}\n\nbool isdigit(char c) {\n return '0' <= c && c <= '9';\n}\n\nbool isAlpha(char c) {\n return 'A' <= c && c <= 'Z';\n}\n\nbool isalpha(char c) {\n return 'a' <= c && c <= 'z';\n}\n\nstruct Dice {\n int up = 0, front = 1, right = 2, left = 3, back = 4, down = 5;\n\n Dice() = default;\n\n void setval(const std::vector<int> &_val) {\n assert(int(_val.size()) == 6);\n val = _val;\n }\n\n // y++\n void rollN() {\n int buff = down;\n down = back;\n back = up;\n up = front;\n front = buff;\n }\n\n // y--\n void rollS() {\n int buff = down;\n down = front;\n front = up;\n up = back;\n back = buff;\n }\n\n // x++\n void rollE() {\n int buff = down;\n down = right;\n right = up;\n up = left;\n left = buff;\n }\n\n // x--\n void rollW() {\n int buff = down;\n down = left;\n left = up;\n up = right;\n right = buff;\n }\n\n // 右回転(時計回り)\n void rollR() {\n int buff = right;\n right = back;\n back = left;\n left = front;\n front = buff;\n }\n\n // 左回転(反時計回り)\n void rollL() {\n int buff = left;\n left = back;\n back = right;\n right = front;\n front = buff;\n }\n\n void roll(char c) {\n if (c == 'N')\n rollN();\n else if (c == 'S')\n rollS();\n else if (c == 'E')\n rollE();\n else if (c == 'W')\n rollW();\n else if (c == 'R')\n rollR();\n else if (c == 'L')\n rollL();\n else\n assert(0);\n }\n\n int get_index(int x) const {\n for (int i = 0; i < 6; i++) {\n if (val[i] == x) return i;\n }\n assert(0);\n }\n\n std::vector<Dice> makeDice() const {\n std::vector<Dice> ret;\n for (int i = 0; i < 6; i++) {\n Dice d(*this);\n if (i == 1) d.rollN();\n if (i == 2) d.rollS();\n if (i == 3) {\n d.rollS();\n d.rollS();\n }\n if (i == 4) d.rollL();\n if (i == 5) d.rollR();\n for (int j = 0; j < 4; j++) {\n ret.emplace_back(d);\n d.rollE();\n }\n }\n return ret;\n }\n\n int top_val() const {\n return val[up];\n }\n\n int right_val() const {\n return val[right];\n }\n\n int left_val() const {\n return val[left];\n }\n\n int front_val() const {\n return val[front];\n }\n\n int back_val() const {\n return val[back];\n }\n\n int down_val() const {\n return val[down];\n }\n\n std::vector<int> now() const {\n std::vector<int> ret(6);\n ret[0] = top_val();\n ret[1] = front_val();\n ret[2] = right_val();\n ret[3] = left_val();\n ret[4] = back_val();\n ret[5] = down_val();\n return ret;\n }\n\n std::vector<int> val = {0, 1, 2, 3, 4, 5};\n};\n\nbool input(std::vector<int> &t) {\n int zero = 0;\n rep(i,0,6) {\n std::cin >> t[i];\n if(t[i] == 0) zero++;\n }\n if(zero == 6) return false;\n return true;\n}\n\nint main() {\n std::vector<int> t(6);\n while(input(t)) {\n int sum = 0;\n rep(i,0,6) sum += t[i];\n int p,q;\n std::cin >> p >> q;\n p--;\n std::vector<int> idxs(6);\n std::iota(all(idxs), 0);\n std::string ans = \"\";\n do {\n std::vector<int> val(6);\n rep(i,0,6) val[i] = t[idxs[i]];\n Dice dice;\n dice.setval(val);\n auto check = [&]() -> bool {\n int na = dice.top_val() + dice.down_val();\n int nb = dice.left_val() + dice.right_val();\n int nc = dice.front_val() + dice.back_val();\n return dice.top_val() >= 0 && na <= nb + nc && nb <= 1 + nc + na && nc <= 1 + na + nb;\n };\n if(!check()) {\n continue;\n }\n std::string s = \"\";\n rep(_,0,sum) {\n {\n dice.rollE();\n dice.val[dice.up]--;\n if(check()) {\n s += 'E';\n continue;\n }\n dice.val[dice.up]++;\n dice.rollW();\n }\n {\n dice.rollN();\n dice.val[dice.up]--;\n if(check()) {\n s += 'N';\n continue;\n }\n dice.val[dice.up]++;\n dice.rollS();\n }\n {\n dice.rollS();\n dice.val[dice.up]--;\n if(check()) {\n s += 'S';\n continue;\n }\n dice.val[dice.up]++;\n dice.rollN();\n } {\n dice.rollW();\n dice.val[dice.up]--;\n if(check()) {\n s += 'W';\n continue;\n }\n dice.val[dice.up]++;\n dice.rollE();\n }\n assert(0);\n }\n if(ans.empty()) ans = s;\n else chmin(ans, s);\n } while(std::next_permutation(all(idxs)));\n if(ans.empty()) {\n std::cout << \"impossible\\n\";\n continue;\n }\n std::cout << ans.substr(p, q-p) << '\\n';\n }\n}", "accuracy": 1, "time_ms": 640, "memory_kb": 3468, "score_of_the_acc": -0.0811, "final_rank": 3 }, { "submission_id": "aoj_1197_6021158", "code_snippet": "#include<bits/stdc++.h>\nusing ll = long long;\n#define var auto\nconst char newl = '\\n';\n\nusing namespace std;\n\ntemplate<typename T1, typename T2> inline void chmin(T1& a, T2 b) { if (a > b) a = b; }\ntemplate<typename T1, typename T2> inline void chmax(T1& a, T2 b) { if (a < b) a = b; }\n\ntemplate<typename T = int>\nstruct Die {\n array<T, 6> fs;\n int& top() { return fs[0]; }\n int& south() { return fs[1]; }\n int& east() { return fs[2]; }\n int& west() { return fs[3]; }\n int& north() { return fs[4]; }\n int& bottom() { return fs[5]; }\n\n int sum() { return fs[0] + fs[1] + fs[2] + fs[3] + fs[4] + fs[5]; }\n\n void roll(char c) {\n //the view from above\n // N\n //W E\n // S\n string b(\"EWNSRL\");\n int v[6][4] = { {0,3,5,2},\n {0,2,5,3},\n {0,1,5,4},\n {0,4,5,1},\n {1,2,4,3},\n {1,3,4,2} };\n for (int k = 0; k < 6; k++) {\n if (b[k] != c) continue;\n int t = fs[v[k][0]];\n fs[v[k][0]] = fs[v[k][1]];\n fs[v[k][1]] = fs[v[k][2]];\n fs[v[k][2]] = fs[v[k][3]];\n fs[v[k][3]] = t;\n break;\n }\n }\n using ll = long long;\n ll hash() {\n ll res = 0;\n for (int i = 0; i < 6; i++) res = res * 256 + fs[i];\n return res;\n }\n bool operator==(const Die& d) const {\n for (int i = 0; i < 6; i++) if (fs[i] != d.fs[i]) return 0;\n return 1;\n }\n};\n\ntemplate<typename T>\nvector<Die<T>> makeDice(Die<T> d) {\n vector<Die<T>> res;\n for (int i = 0; i < 6; i++) {\n Die t(d);\n if (i == 1) t.roll('N');\n if (i == 2) t.roll('S');\n if (i == 3) t.roll('S'), t.roll('S');\n if (i == 4) t.roll('L');\n if (i == 5) t.roll('R');\n for (int k = 0; k < 4; k++) {\n res.emplace_back(t);\n t.roll('E');\n }\n }\n return res;\n}\n\nstring rotates(\"ENSW\");\nbool is_valid(Die<int>& die) {\n int sum = die.sum();\n if (sum == 0) return true;\n if (sum % 2 == 1) {\n for (var&& c : rotates) {\n var nxt = die;\n nxt.roll(c);\n if (nxt.bottom() == 0) continue;\n nxt.bottom()--;\n if (is_valid(nxt)) return true;\n }\n return false;\n }\n\n int X = die.fs[2] + die.fs[3];\n int Y = die.fs[1] + die.fs[4];\n int Z = die.fs[0] + die.fs[5];\n\n if (X > Y) swap(Y, X);\n if (X + Y < Z) return true;\n if (Z < Y - X) return false;\n Z -= Y - X;\n\n return Z % 2 == 0;\n}\n\nbool solve() {\n vector<int> t(6);\n for (var&& elem : t) cin >> elem;\n var sum = accumulate(t.begin(), t.end(), 0);\n if (sum == 0) return false;\n int p, q;\n cin >> p >> q;\n\n string res;\n\n sort(t.begin(), t.end());\n do\n {\n Die die;\n for (int i = 0; i < t.size(); i++) die.fs[i] = t[i];\n \n // if (die.bottom() == 0) continue;\n // die.bottom()--;\n\n bool same = res.size() == sum;\n\n string cur_res = \"\";\n for (int cnt = 0; cnt < sum; cnt++) {\n for (var c : rotates) {\n // 枝刈り\n if (same && res[cnt] < c) break;\n\n var nxt = die;\n nxt.roll(c);\n if (nxt.bottom() == 0) continue;\n nxt.bottom()--;\n\n if (is_valid(nxt)) {\n die = nxt;\n cur_res += c;\n if (same && cur_res[cnt] < res[cnt]) same = false;\n goto end;\n }\n }\n break;\n end:;\n }\n\n if (cur_res.size() != sum) continue;\n res = cur_res;\n\n } while (next_permutation(t.begin(), t.end()));\n\n if (res == \"\") {\n cout << \"impossible\" << endl;\n }\n else {\n cout << res.substr(p - 1, q - p + 1) << endl;\n }\n\n \n return true;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n while (solve()){}\n}", "accuracy": 1, "time_ms": 1340, "memory_kb": 3428, "score_of_the_acc": -0.1802, "final_rank": 10 }, { "submission_id": "aoj_1197_6020837", "code_snippet": "#include<bits/stdc++.h>\nusing ll = long long;\n#define var auto\nconst char newl = '\\n';\n\nusing namespace std;\n\ntemplate<typename T1, typename T2> inline void chmin(T1& a, T2 b) { if (a > b) a = b; }\ntemplate<typename T1, typename T2> inline void chmax(T1& a, T2 b) { if (a < b) a = b; }\n\nbool is_opposite[6][6];\n\ntemplate<typename T = int>\nstruct Die {\n array<T, 6> fs;\n int& top() { return fs[0]; }\n int& south() { return fs[1]; }\n int& east() { return fs[2]; }\n int& west() { return fs[3]; }\n int& north() { return fs[4]; }\n int& bottom() { return fs[5]; }\n\n int sum() { return fs[0] + fs[1] + fs[2] + fs[3] + fs[4] + fs[5]; }\n\n void roll(char c) {\n //the view from above\n // N\n //W E\n // S\n string b(\"EWNSRL\");\n int v[6][4] = { {0,3,5,2},\n {0,2,5,3},\n {0,1,5,4},\n {0,4,5,1},\n {1,2,4,3},\n {1,3,4,2} };\n for (int k = 0; k < 6; k++) {\n if (b[k] != c) continue;\n int t = fs[v[k][0]];\n fs[v[k][0]] = fs[v[k][1]];\n fs[v[k][1]] = fs[v[k][2]];\n fs[v[k][2]] = fs[v[k][3]];\n fs[v[k][3]] = t;\n break;\n }\n }\n using ll = long long;\n ll hash() {\n ll res = 0;\n for (int i = 0; i < 6; i++) res = res * 256 + fs[i];\n return res;\n }\n bool operator==(const Die& d) const {\n for (int i = 0; i < 6; i++) if (fs[i] != d.fs[i]) return 0;\n return 1;\n }\n};\n\ntemplate<typename T>\nvector<Die<T>> makeDice(Die<T> d) {\n vector<Die<T>> res;\n for (int i = 0; i < 6; i++) {\n Die t(d);\n if (i == 1) t.roll('N');\n if (i == 2) t.roll('S');\n if (i == 3) t.roll('S'), t.roll('S');\n if (i == 4) t.roll('L');\n if (i == 5) t.roll('R');\n for (int k = 0; k < 4; k++) {\n res.emplace_back(t);\n t.roll('E');\n }\n }\n return res;\n}\n\nbool check(array<int, 6>& x) {\n int Z = x[0] + x[5];\n int Y = x[1] + x[4];\n int X = x[2] + x[3];\n\n if (X > Y) swap(Y, X);\n\n if (X + Y < Z) return true;\n\n if (Z < Y - X) return false;\n\n Z -= Y - X;\n\n return Z % 2 == 0;\n}\n\nstring rotates(\"ENSW\");\nbool is_valid(Die<int>& die) {\n int sum = die.sum();\n if (sum == 0) return true;\n if (sum % 2 == 1) {\n for (var&& c : rotates) {\n var nxt = die;\n nxt.roll(c);\n if (nxt.bottom() == 0) continue;\n nxt.bottom()--;\n if (is_valid(nxt)) return true;\n }\n return false;\n }\n\n return check(die.fs);\n\n int fst = 0;\n int fstInd = -1;\n int snd = 0;\n int sndInd = -1;\n for (int i = 0; i < 6; i++) {\n if (fst <= die.fs[i]) {\n snd = fst;\n sndInd = fstInd;\n fst = die.fs[i];\n fstInd = i;\n }\n else if (snd <= die.fs[i]) {\n snd = die.fs[i];\n sndInd = i;\n }\n }\n\n assert(sndInd != -1);\n \n if (not is_opposite[fstInd][sndInd]) return true;\n if (fst + snd <= sum / 2) return true;\n return false;\n}\n\nbool solve() {\n vector<int> t(6);\n for (var&& elem : t) cin >> elem;\n var sum = accumulate(t.begin(), t.end(), 0);\n if (sum == 0) return false;\n int p, q;\n cin >> p >> q;\n\n string res;\n\n sort(t.begin(), t.end());\n do\n {\n Die die;\n for (int i = 0; i < t.size(); i++) die.fs[i] = t[i];\n \n // if (die.bottom() == 0) continue;\n // die.bottom()--;\n\n bool same = res.size() == sum;\n\n string cur_res = \"\";\n for (int cnt = 0; cnt < sum; cnt++) {\n for (var c : rotates) {\n // 枝刈り\n if (same && res[cnt] < c) break;\n\n var nxt = die;\n nxt.roll(c);\n if (nxt.bottom() == 0) continue;\n nxt.bottom()--;\n\n if (is_valid(nxt)) {\n die = nxt;\n cur_res += c;\n if (same && cur_res[cnt] < res[cnt]) same = false;\n goto end;\n }\n }\n break;\n end:;\n }\n\n if (cur_res.size() != sum) continue;\n res = cur_res;\n\n } while (next_permutation(t.begin(), t.end()));\n\n if (res == \"\") {\n cout << \"impossible\" << endl;\n }\n else {\n cout << res.substr(p - 1, q - p + 1) << endl;\n }\n\n \n return true;\n}\n\nint main() {\n is_opposite[0][5] = true;\n is_opposite[5][0] = true;\n\n is_opposite[1][4] = true;\n is_opposite[4][1] = true;\n\n is_opposite[2][3] = true;\n is_opposite[3][2] = true;\n\n\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n while (solve()){}\n}", "accuracy": 1, "time_ms": 1320, "memory_kb": 3476, "score_of_the_acc": -0.191, "final_rank": 11 }, { "submission_id": "aoj_1197_5978745", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct Dice {\n std::array<int, 6> surface;\n\n Dice(int TOP = 1, int FRONT = 2) {\n assert(1 <= TOP and TOP <= 6);\n assert(1 <= FRONT and FRONT <= 6);\n assert(TOP + FRONT != 7);\n surface[0] = TOP;\n surface[1] = FRONT;\n surface[2] = dice[TOP - 1][FRONT - 1];\n surface[3] = 7 - surface[2];\n surface[4] = 7 - surface[1];\n surface[5] = 7 - surface[0];\n }\n\n Dice(const std::vector<int>& v) {\n assert(v.size() == 6);\n for (size_t i = 0; i < 6; i++) surface[i] = v[i];\n }\n\n const int& top() const { return surface[0]; }\n const int& front() const { return surface[1]; }\n const int& right() const { return surface[2]; }\n const int& left() const { return surface[3]; }\n const int& back() const { return surface[4]; }\n const int& bottom() const { return surface[5]; }\n const int& operator[](int k) const { return surface[k]; }\n\n int& top() { return surface[0]; }\n int& front() { return surface[1]; }\n int& right() { return surface[2]; }\n int& left() { return surface[3]; }\n int& back() { return surface[4]; }\n int& bottom() { return surface[5]; }\n int& operator[](int k) { return surface[k]; }\n\n bool operator==(const Dice& d) const { return surface == d.surface; }\n bool operator!=(const Dice& d) const { return surface != d.surface; }\n bool operator<(const Dice& d) const { return surface < d.surface; }\n\n int roll(int k) { // x++, x--, y++, y--, turn right, turn left\n assert(0 <= k and k < 6);\n int tmp = surface[code[k][0]];\n for (int i = 0; i < 3; i++) surface[code[k][i]] = surface[code[k][i + 1]];\n surface[code[k][3]] = tmp;\n return surface[0];\n }\n\n int rollc(char c) {\n for (int k = 0; k < 6; k++) {\n if (direction[k] != c) continue;\n return roll(k);\n }\n assert(false);\n }\n\n int hash() const {\n int res = 0;\n for (size_t i = 0; i < 6; i++) {\n assert(1 <= surface[i] and surface[i] <= 6);\n (res *= 6) += surface[i] - 1;\n }\n return res;\n }\n\n std::vector<Dice> make_all() {\n std::vector<Dice> res;\n for (int i = 0; i < 6; i++) {\n Dice d(*this);\n if (i == 1) d.roll(2);\n if (i == 2) d.roll(3);\n if (i == 3) d.roll(3), d.roll(3);\n if (i == 4) d.roll(5);\n if (i == 5) d.roll(4);\n for (int j = 0; j < 4; j++) {\n res.emplace_back(d);\n d.roll(0);\n }\n }\n return res;\n }\n\n Dice identifier() {\n auto dices = make_all();\n return *min_element(dices.begin(), dices.end());\n }\n\nprivate:\n const int dice[6][6] = {{0, 3, 5, 2, 4, 0}, {4, 0, 1, 6, 0, 3}, {2, 6, 0, 0, 1, 5},\n {5, 1, 0, 0, 6, 2}, {3, 0, 6, 1, 0, 4}, {0, 4, 2, 5, 3, 0}};\n const int code[6][4] = {{0, 3, 5, 2}, {0, 2, 5, 3}, {0, 1, 5, 4}, {0, 4, 5, 1}, {1, 2, 4, 3}, {1, 3, 4, 2}};\n const char direction[6] = {'E', 'W', 'N', 'S', 'R', 'L'};\n};\n\n/**\n * @brief Dice\n * @docs docs/util/Dice.md\n */\n\nconst string directions = \"EWNS\";\n\nvoid solve(vector<int> t) {\n string ans = \"\";\n sort(t.begin(), t.end());\n int sum = accumulate(t.begin(), t.end(), 0);\n\n do {\n Dice dice(t);\n string cur = \"\";\n bool update = true;\n for (int rest = sum - 1; rest >= 0 and exchange(update, false); rest--) {\n for (int dir : {0, 2, 3, 1}) {\n dice.roll(dir);\n dice.bottom()--;\n bool ok = true;\n if (dice.bottom() < 0) ok = false;\n for (int i = 0; i < 3; i++) {\n int opposite = dice[i] + dice[5 - i];\n if (opposite > rest - opposite + (i > 0)) ok = false;\n }\n if (ok) {\n update = true;\n cur += directions[dir];\n break;\n }\n dice.bottom()++;\n dice.roll(dir ^ 1);\n }\n }\n if (!update) continue;\n if (ans == \"\")\n ans = cur;\n else\n ans = min(ans, cur);\n } while (next_permutation(t.begin(), t.end()));\n\n int p, q;\n cin >> p >> q;\n if (ans == \"\") {\n cout << \"impossible\" << '\\n';\n return;\n }\n for (int i = --p; i < q; i++) cout << ans[i];\n cout << '\\n';\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n vector<int> t(6);\n while (1) {\n for (int i = 0; i < 6; i++) cin >> t[i];\n if (t.back() == 0) break;\n solve(t);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 960, "memory_kb": 3484, "score_of_the_acc": -0.1364, "final_rank": 4 }, { "submission_id": "aoj_1197_5978741", "code_snippet": "#define LOCAL\n#include <bits/stdc++.h>\nusing namespace std;\n#pragma region Macros\ntypedef long long ll;\ntypedef __int128_t i128;\ntypedef unsigned int uint;\ntypedef unsigned long long ull;\n#define ALL(x) (x).begin(), (x).end()\n\ntemplate <typename T> istream& operator>>(istream& is, vector<T>& v) {\n for (T& x : v) is >> x;\n return is;\n}\ntemplate <typename T> ostream& operator<<(ostream& os, const vector<T>& v) {\n for (int i = 0; i < (int)v.size(); i++) {\n os << v[i] << (i + 1 == (int)v.size() ? \"\" : \" \");\n }\n return os;\n}\ntemplate <typename T, typename U> ostream& operator<<(ostream& os, const pair<T, U>& p) {\n os << '(' << p.first << ',' << p.second << ')';\n return os;\n}\ntemplate <typename T, typename U> ostream& operator<<(ostream& os, const map<T, U>& m) {\n os << '{';\n for (auto itr = m.begin(); itr != m.end();) {\n os << '(' << itr->first << ',' << itr->second << ')';\n if (++itr != m.end()) os << ',';\n }\n os << '}';\n return os;\n}\ntemplate <typename T, typename U> ostream& operator<<(ostream& os, const unordered_map<T, U>& m) {\n os << '{';\n for (auto itr = m.begin(); itr != m.end();) {\n os << '(' << itr->first << ',' << itr->second << ')';\n if (++itr != m.end()) os << ',';\n }\n os << '}';\n return os;\n}\ntemplate <typename T> ostream& operator<<(ostream& os, const set<T>& s) {\n os << '{';\n for (auto itr = s.begin(); itr != s.end();) {\n os << *itr;\n if (++itr != s.end()) os << ',';\n }\n os << '}';\n return os;\n}\ntemplate <typename T> ostream& operator<<(ostream& os, const multiset<T>& s) {\n os << '{';\n for (auto itr = s.begin(); itr != s.end();) {\n os << *itr;\n if (++itr != s.end()) os << ',';\n }\n os << '}';\n return os;\n}\ntemplate <typename T> ostream& operator<<(ostream& os, const unordered_set<T>& s) {\n os << '{';\n for (auto itr = s.begin(); itr != s.end();) {\n os << *itr;\n if (++itr != s.end()) os << ',';\n }\n os << '}';\n return os;\n}\ntemplate <typename T> ostream& operator<<(ostream& os, const deque<T>& v) {\n for (int i = 0; i < (int)v.size(); i++) {\n os << v[i] << (i + 1 == (int)v.size() ? \"\" : \" \");\n }\n return os;\n}\n\ntemplate <int i, typename T> void print_tuple(ostream&, const T&) {}\ntemplate <int i, typename T, typename H, class... Args> void print_tuple(ostream& os, const T& t) {\n if (i) os << ',';\n os << get<i>(t);\n print_tuple<i + 1, T, Args...>(os, t);\n}\ntemplate <typename... Args> ostream& operator<<(ostream& os, const tuple<Args...>& t) {\n os << '{';\n print_tuple<0, tuple<Args...>, Args...>(os, t);\n return os << '}';\n}\n\nvoid debug_out() { cerr << '\\n'; }\ntemplate <class Head, class... Tail> void debug_out(Head&& head, Tail&&... tail) {\n cerr << head;\n if (sizeof...(Tail) > 0) cerr << \", \";\n debug_out(move(tail)...);\n}\n#ifdef LOCAL\n#define debug(...) \\\n cerr << \" \"; \\\n cerr << #__VA_ARGS__ << \" :[\" << __LINE__ << \":\" << __FUNCTION__ << \"]\" << '\\n'; \\\n cerr << \" \"; \\\n debug_out(__VA_ARGS__)\n#else\n#define debug(...) 42\n#endif\n\ntemplate <typename T> T gcd(T x, T y) { return y != 0 ? gcd(y, x % y) : x; }\ntemplate <typename T> T lcm(T x, T y) { return x / gcd(x, y) * y; }\n\nint topbit(signed t) { return t == 0 ? -1 : 31 - __builtin_clz(t); }\nint topbit(long long t) { return t == 0 ? -1 : 63 - __builtin_clzll(t); }\nint botbit(signed a) { return a == 0 ? 32 : __builtin_ctz(a); }\nint botbit(long long a) { return a == 0 ? 64 : __builtin_ctzll(a); }\nint popcount(signed t) { return __builtin_popcount(t); }\nint popcount(long long t) { return __builtin_popcountll(t); }\nbool ispow2(int i) { return i && (i & -i) == i; }\n\ntemplate <class T> T ceil(T x, T y) {\n assert(y >= 1);\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <class T> T floor(T x, T y) {\n assert(y >= 1);\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\n\ntemplate <class T1, class T2> inline bool chmin(T1& a, T2 b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <class T1, class T2> inline bool chmax(T1& a, T2 b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n#pragma endregion\n\n#include <array>\n#include <cassert>\n#include <string>\n#include <vector>\n\nstruct Dice {\n std::array<int, 6> surface;\n\n Dice(int TOP = 1, int FRONT = 2) {\n assert(1 <= TOP and TOP <= 6);\n assert(1 <= FRONT and FRONT <= 6);\n assert(TOP + FRONT != 7);\n surface[0] = TOP;\n surface[1] = FRONT;\n surface[2] = dice[TOP - 1][FRONT - 1];\n surface[3] = 7 - surface[2];\n surface[4] = 7 - surface[1];\n surface[5] = 7 - surface[0];\n }\n\n Dice(const std::vector<int>& v) {\n assert(v.size() == 6);\n for (size_t i = 0; i < 6; i++) surface[i] = v[i];\n }\n\n const int& top() const { return surface[0]; }\n const int& front() const { return surface[1]; }\n const int& right() const { return surface[2]; }\n const int& left() const { return surface[3]; }\n const int& back() const { return surface[4]; }\n const int& bottom() const { return surface[5]; }\n const int& operator[](int k) const { return surface[k]; }\n\n int& top() { return surface[0]; }\n int& front() { return surface[1]; }\n int& right() { return surface[2]; }\n int& left() { return surface[3]; }\n int& back() { return surface[4]; }\n int& bottom() { return surface[5]; }\n int& operator[](int k) { return surface[k]; }\n\n bool operator==(const Dice& d) const { return surface == d.surface; }\n bool operator!=(const Dice& d) const { return surface != d.surface; }\n bool operator<(const Dice& d) const { return surface < d.surface; }\n\n int roll(int k) { // x++, x--, y++, y--, turn right, turn left\n assert(0 <= k and k < 6);\n int tmp = surface[code[k][0]];\n for (int i = 0; i < 3; i++) surface[code[k][i]] = surface[code[k][i + 1]];\n surface[code[k][3]] = tmp;\n return surface[0];\n }\n\n int rollc(char c) {\n for (int k = 0; k < 6; k++) {\n if (direction[k] != c) continue;\n return roll(k);\n }\n assert(false);\n }\n\n int hash() const {\n int res = 0;\n for (size_t i = 0; i < 6; i++) {\n assert(1 <= surface[i] and surface[i] <= 6);\n (res *= 6) += surface[i] - 1;\n }\n return res;\n }\n\n std::vector<Dice> make_all() {\n std::vector<Dice> res;\n for (int i = 0; i < 6; i++) {\n Dice d(*this);\n if (i == 1) d.roll(2);\n if (i == 2) d.roll(3);\n if (i == 3) d.roll(3), d.roll(3);\n if (i == 4) d.roll(5);\n if (i == 5) d.roll(4);\n for (int j = 0; j < 4; j++) {\n res.emplace_back(d);\n d.roll(0);\n }\n }\n return res;\n }\n\n Dice identifier() {\n auto dices = make_all();\n return *min_element(dices.begin(), dices.end());\n }\n\nprivate:\n const int dice[6][6] = {{0, 3, 5, 2, 4, 0}, {4, 0, 1, 6, 0, 3}, {2, 6, 0, 0, 1, 5},\n {5, 1, 0, 0, 6, 2}, {3, 0, 6, 1, 0, 4}, {0, 4, 2, 5, 3, 0}};\n const int code[6][4] = {{0, 3, 5, 2}, {0, 2, 5, 3}, {0, 1, 5, 4}, {0, 4, 5, 1}, {1, 2, 4, 3}, {1, 3, 4, 2}};\n const char direction[6] = {'E', 'W', 'N', 'S', 'R', 'L'};\n};\n\n/**\n * @brief Dice\n * @docs docs/util/Dice.md\n */\n\nconst int INF = 1e9;\nconst long long IINF = 1e18;\nconst int dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1};\nconst long long MOD = 1000000007;\n// const long long MOD = 998244353;\n\nconst string directions = \"EWNS\";\n\nvoid solve(vector<int> t) {\n string ans = \"\";\n sort(t.begin(), t.end());\n int sum = accumulate(t.begin(), t.end(), 0);\n\n do {\n Dice dice(t);\n string cur = \"\";\n bool update = true;\n for (int rest = sum - 1; rest >= 0 and exchange(update, false); rest--) {\n for (int dir : {0, 2, 3, 1}) {\n dice.roll(dir);\n dice.bottom()--;\n bool ok = true;\n if (dice.bottom() < 0) ok = false;\n for (int i = 0; i < 3; i++) {\n int opposite = dice[i] + dice[5 - i];\n if (opposite > rest - opposite + (i > 0)) ok = false;\n }\n if (ok) {\n update = true;\n cur += directions[dir];\n break;\n }\n dice.bottom()++;\n dice.roll(dir ^ 1);\n }\n }\n if (!update) continue;\n if (ans == \"\")\n ans = cur;\n else\n ans = min(ans, cur);\n } while (next_permutation(t.begin(), t.end()));\n\n int p, q;\n cin >> p >> q;\n if (ans == \"\") {\n cout << \"impossible\" << '\\n';\n return;\n }\n for (int i = --p; i < q; i++) cout << ans[i];\n cout << '\\n';\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n vector<int> t(6);\n while (1) {\n for (int i = 0; i < 6; i++) cin >> t[i];\n if (t.back() == 0) break;\n solve(t);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 970, "memory_kb": 3560, "score_of_the_acc": -0.1601, "final_rank": 6 }, { "submission_id": "aoj_1197_5970955", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n#define all(x) (x).begin(),(x).end()\n#define fi first\n#define se second\n#define mp make_pair\n#define si(x) int(x.size())\nconst int mod=1000000007,MAX=200005,INF=1<<30;\n\nstruct dice{\n int u,f,r,b,l,d;\n \n void init(int uu,int ff,int rr,int bb,int ll,int dd){\n u=uu;\n f=ff;\n r=rr;\n b=bb;\n l=ll;\n d=dd;\n }\n \n void init(vector<int> S){\n init(S[0],S[1],S[2],S[3],S[4],S[5]);\n }\n \n void turnE(){\n int save=r;\n r=u;\n u=l;\n l=d;\n d=save;\n }\n \n void turnN(){\n int save=b;\n b=u;\n u=f;\n f=d;\n d=save;\n }\n \n void turnS(){\n int save=f;\n f=u;\n u=b;\n b=d;\n d=save;\n }\n \n void turnW(){\n int save=l;\n l=u;\n u=r;\n r=d;\n d=save;\n }\n \n bool check(){\n int x=l+r,y=f+b,z=u+d;\n if(d<0) return false;\n if(x==0&&y==0&z==0) return true;\n if(x>=y&&x>=z){\n if(x<=y+z+1) return true;\n else return false;\n }\n if(y>=x&&y>=z){\n if(y<=x+z+1) return true;\n else return false;\n }\n if(z>=x&&z>=y){\n if(z<=x+y) return true;\n else return false;\n }\n return false;\n }\n};\n\nint main(){\n \n std::ifstream in(\"text.txt\");\n std::cin.rdbuf(in.rdbuf());\n cin.tie(0);\n ios::sync_with_stdio(false);\n \n while(1){\n int sum=0;\n vector<int> S(6);\n for(int i=0;i<6;i++){\n cin>>S[i];\n sum+=S[i];\n }\n if(S.back()==0) break;\n int s,t;cin>>s>>t;s--;\n bool f=false;\n do{\n dice X;X.init(S);\n if(X.check()) f=true;\n }while(next_permutation(all(S)));\n \n if(!f){\n cout<<\"impossible\\n\";\n continue;\n }\n string ans=\"Z\";\n sort(all(S));\n \n do{\n dice X;X.init(S);\n if(!X.check()) continue;\n \n string T;\n for(int q=0;q<sum;q++){\n X.turnE();\n X.d--;\n if(X.check()){\n T+='E';\n continue;\n }else{\n X.d++;\n X.turnW();\n }\n \n X.turnN();\n X.d--;\n if(X.check()){\n T+='N';\n continue;\n }else{\n X.d++;\n X.turnS();\n }\n \n X.turnS();\n X.d--;\n if(X.check()){\n T+='S';\n continue;\n }else{\n X.d++;\n X.turnN();\n }\n \n X.turnW();\n X.d--;\n if(X.check()){\n T+='W';\n continue;\n }else{\n X.d++;\n X.turnE();\n }\n }\n \n chmin(ans,T);\n \n }while(next_permutation(all(S)));\n \n cout<<ans.substr(s,t-s)<<\"\\n\";\n }\n}", "accuracy": 1, "time_ms": 510, "memory_kb": 3308, "score_of_the_acc": -0.014, "final_rank": 1 }, { "submission_id": "aoj_1197_5951015", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<cstring>\n#include<string>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<map>\n#include<queue>\n#include<deque>\n#include<iomanip>\n#include<tuple>\n#include<cassert>\n#include<set>\n#include<complex>\n#include<numeric>\n#include<functional>\n#include<unordered_map>\n#include<unordered_set>\nusing namespace std;\ntypedef long long int LL;\ntypedef pair<int,int> P;\ntypedef pair<LL,LL> LP;\nconst int INF=1<<30;\nconst LL MAX=1e9+7;\n\nvoid array_show(int *array,int array_n,char middle=' '){\n for(int i=0;i<array_n;i++)printf(\"%d%c\",array[i],(i!=array_n-1?middle:'\\n'));\n}\nvoid array_show(LL *array,int array_n,char middle=' '){\n for(int i=0;i<array_n;i++)printf(\"%lld%c\",array[i],(i!=array_n-1?middle:'\\n'));\n}\nvoid array_show(vector<int> &vec_s,int vec_n=-1,char middle=' '){\n if(vec_n==-1)vec_n=vec_s.size();\n for(int i=0;i<vec_n;i++)printf(\"%d%c\",vec_s[i],(i!=vec_n-1?middle:'\\n'));\n}\nvoid array_show(vector<LL> &vec_s,int vec_n=-1,char middle=' '){\n if(vec_n==-1)vec_n=vec_s.size();\n for(int i=0;i<vec_n;i++)printf(\"%lld%c\",vec_s[i],(i!=vec_n-1?middle:'\\n'));\n}\ntemplate<typename T> ostream& operator<<(ostream& os,const vector<T>& v1){\n int n=v1.size();\n for(int i=0;i<n;i++){\n if(i)os<<\" \";\n os<<v1[i];\n }\n return os;\n}\ntemplate<typename T1,typename T2> ostream& operator<<(ostream& os,const pair<T1,T2>& p){\n os<<p.first<<\" \"<<p.second;\n return os;\n}\ntemplate<typename T> istream& operator>>(istream& is,vector<T>& v1){\n int n=v1.size();\n for(int i=0;i<n;i++)is>>v1[i];\n return is;\n}\ntemplate<typename T1,typename T2> istream& operator>>(istream& is,pair<T1,T2>& p){\n is>>p.first>>p.second;\n return is;\n}\n\nclass Dice{\n // 0\n //1234\n // 5\n //top:0, front:2, x:13, y:24, z:50\n static const int N=6;\n int A[N];\npublic:\n Dice(const vector<int> v1){\n assert(v1.size()>=N);\n for(int i=0;i<N;i++){\n A[i]=v1[i];\n }\n }\n\n //rotate: clockwise\n void rotateX(){//0->2->5->4->0\n swap(A[0],A[4]);\n swap(A[4],A[5]);\n swap(A[5],A[2]);\n }\n\n void rotateXrev(){\n swap(A[5],A[2]);\n swap(A[4],A[5]);\n swap(A[0],A[4]);\n }\n\n void rotateY(){//0->3->5->1\n swap(A[0],A[1]);\n swap(A[1],A[5]);\n swap(A[5],A[3]);\n }\n\n void rotateYrev(){\n swap(A[5],A[3]);\n swap(A[1],A[5]);\n swap(A[0],A[1]);\n }\n\n void rotateZ(){//1->2->3->4\n swap(A[4],A[3]);\n swap(A[3],A[2]);\n swap(A[2],A[1]);\n }\n\n void rotateZrev(){//1->2->3->4\n swap(A[2],A[1]);\n swap(A[3],A[2]);\n swap(A[4],A[3]);\n }\n\n bool check(){\n int a=0;\n for(int i=0;i<N;i++){\n if(A[i]<0)return false;\n a+=A[i];\n }\n if((A[0]+A[5])*2>a)return false;\n if((A[1]+A[3])*2-1>a)return false;\n if((A[2]+A[4])*2-1>a)return false;\n return true;\n }\n\n string calc(){\n string sa=\"ENSW\",ss=\"\";\n int i,j;\n while(1){\n for(i=0;i<4;i++){\n if(i==0)rotateX();\n if(i==1)rotateY();\n if(i==2)rotateYrev();\n if(i==3)rotateXrev();\n A[5]--;\n if(check())break;\n A[5]++;\n if(i==0)rotateXrev();\n if(i==1)rotateYrev();\n if(i==2)rotateY();\n if(i==3)rotateX();\n }\n if(A[5]<0 || i==4)return \"impossible\";\n ss.push_back(sa[i]);\n for(i=0;i<N;i++){\n if(A[i]>0)break;\n }\n if(i==N)return ss;\n }\n }\n\n\n template<typename T> T hash(int base){\n T s=0;\n for(int i=0;i<N;i++){\n s*=base;\n s+=A[i];\n }\n return s;\n }\n\n template<typename T> vector<T> all_hash(int base){\n int i,j;\n vector<T> vs;\n const int M=4;\n for(i=0;i<2*M;i++){\n if(i<M)rotateX();\n else rotateY();\n if(i>=M && i%2)continue;\n for(j=0;j<4;j++){\n rotateZ();\n vs.push_back(hash<T>(base));\n }\n }\n return vs;\n }\n};\n\n\nnamespace sol{\n const int N=6;\n string ss;\n vector<int> v1(N);\n vector<int> vi(N,-1);\n\n void dfs(int d){\n int i;\n if(d<N){\n for(i=0;i<N;i++){\n if(vi[i]!=-1)continue;\n vi[i]=d;\n dfs(d+1);\n vi[i]=-1;\n }\n return;\n }\n vector<int> v2(N);\n for(i=0;i<N;i++){\n v2[vi[i]]=v1[i];\n }\n Dice dice(v2);\n string sa=dice.calc();\n if(sa<ss)ss=sa;\n }\n\n void solve(){\n int n,m;\n int i,j,k;\n int a,b,c;\n int p,q;\n while(cin>>v1){\n sort(v1.begin(),v1.end());\n if(v1.back()==0)return;\n cin>>p>>q;\n p--;\n vi.assign(N,-1);\n ss=\"z\";\n dfs(0);\n if(ss==\"impossible\")cout<<ss<<endl;\n else cout<<ss.substr(p,q-p)<<endl;\n }\n }\n}\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n sol::solve();\n}", "accuracy": 1, "time_ms": 1330, "memory_kb": 3428, "score_of_the_acc": -0.1786, "final_rank": 9 }, { "submission_id": "aoj_1197_5801779", "code_snippet": "/**\n *\tauthor: nok0\n *\tcreated: 2021.06.29 22:18:07\n**/\n#ifdef LOCAL\n#define _GLIBCXX_DEBUG\n#endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\nusing namespace atcoder;\n#endif\n\n#pragma region Macros\n// rep macro\n#define foa(v, a) for(auto &v : a)\n#define REPname(a, b, c, d, e, ...) e\n#define REP(...) REPname(__VA_ARGS__, REP3, REP2, REP1, REP0)(__VA_ARGS__)\n#define REP0(x) for(int i = 0; i < (x); ++i)\n#define REP1(i, x) for(int i = 0; i < (x); ++i)\n#define REP2(i, l, r) for(int i = (l); i < (r); ++i)\n#define REP3(i, l, r, c) for(int i = (l); i < (r); i += (c))\n#define REPSname(a, b, c, ...) c\n#define REPS(...) REPSname(__VA_ARGS__, REPS1, REPS0)(__VA_ARGS__)\n#define REPS0(x) for(int i = 1; i <= (x); ++i)\n#define REPS1(i, x) for(int i = 1; i <= (x); ++i)\n#define RREPname(a, b, c, d, e, ...) e\n#define RREP(...) RREPname(__VA_ARGS__, RREP3, RREP2, RREP1, RREP0)(__VA_ARGS__)\n#define RREP0(x) for(int i = (x)-1; i >= 0; --i)\n#define RREP1(i, x) for(int i = (x)-1; i >= 0; --i)\n#define RREP2(i, r, l) for(int i = (r)-1; i >= (l); --i)\n#define RREP3(i, r, l, c) for(int i = (r)-1; i >= (l); i -= (c))\n#define RREPSname(a, b, c, ...) c\n#define RREPS(...) RREPSname(__VA_ARGS__, RREPS1, RREPS0)(__VA_ARGS__)\n#define RREPS0(x) for(int i = (x); i >= 1; --i)\n#define RREPS1(i, x) for(int i = (x); i >= 1; --i)\n\n// name macro\n#define pb push_back\n#define eb emplace_back\n#define SZ(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define popcnt(x) __builtin_popcountll(x)\ntemplate <class T = int>\nusing V = std::vector<T>;\ntemplate <class T = int>\nusing VV = std::vector<std::vector<T>>;\ntemplate <class T>\nusing pqup = std::priority_queue<T, std::vector<T>, std::greater<T>>;\nusing ll = long long;\nusing ld = long double;\nusing int128 = __int128_t;\nusing pii = std::pair<int, int>;\nusing pll = std::pair<long long, long long>;\n\n// input macro\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n\tis >> p.first >> p.second;\n\treturn is;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n\tfor(T &i : v) is >> i;\n\treturn is;\n}\nstd::istream &operator>>(std::istream &is, __int128_t &a) {\n\tstd::string s;\n\tis >> s;\n\t__int128_t ret = 0;\n\tfor(int i = 0; i < s.length(); i++)\n\t\tif('0' <= s[i] and s[i] <= '9')\n\t\t\tret = 10 * ret + s[i] - '0';\n\ta = ret * (s[0] == '-' ? -1 : 1);\n\treturn is;\n}\n#if __has_include(<atcoder/all>)\nstd::istream &operator>>(std::istream &is, atcoder::modint998244353 &a) {\n\tlong long v;\n\tis >> v;\n\ta = v;\n\treturn is;\n}\nstd::istream &operator>>(std::istream &is, atcoder::modint1000000007 &a) {\n\tlong long v;\n\tis >> v;\n\ta = v;\n\treturn is;\n}\ntemplate <int m>\nstd::istream &operator>>(std::istream &is, atcoder::static_modint<m> &a) {\n\tlong long v;\n\tis >> v;\n\ta = v;\n\treturn is;\n}\ntemplate <int m>\nstd::istream &operator>>(std::istream &is, atcoder::dynamic_modint<m> &a) {\n\tlong long v;\n\tis >> v;\n\ta = v;\n\treturn is;\n}\n#endif\nnamespace scanner {\nvoid scan(int &a) { std::cin >> a; }\nvoid scan(long long &a) { std::cin >> a; }\nvoid scan(std::string &a) { std::cin >> a; }\nvoid scan(char &a) { std::cin >> a; }\nvoid scan(char a[]) { std::scanf(\"%s\", a); }\nvoid scan(double &a) { std::cin >> a; }\nvoid scan(long double &a) { std::cin >> a; }\ntemplate <class T, class U>\nvoid scan(std::pair<T, U> &p) { std::cin >> p; }\ntemplate <class T>\nvoid scan(std::vector<T> &a) { std::cin >> a; }\nvoid INPUT() {}\ntemplate <class Head, class... Tail>\nvoid INPUT(Head &head, Tail &... tail) {\n\tscan(head);\n\tINPUT(tail...);\n}\n} // namespace scanner\n#define VEC(type, name, size) \\\n\tstd::vector<type> name(size); \\\n\tscanner::INPUT(name)\n#define VVEC(type, name, h, w) \\\n\tstd::vector<std::vector<type>> name(h, std::vector<type>(w)); \\\n\tscanner::INPUT(name)\n#define INT(...) \\\n\tint __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LL(...) \\\n\tlong long __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define STR(...) \\\n\tstd::string __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define CHAR(...) \\\n\tchar __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define DOUBLE(...) \\\n\tdouble __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LD(...) \\\n\tlong double __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n\n// output-macro\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n\tos << p.first << \" \" << p.second;\n\treturn os;\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &a) {\n\tfor(int i = 0; i < int(a.size()); ++i) {\n\t\tif(i) os << \" \";\n\t\tos << a[i];\n\t}\n\treturn os;\n}\nstd::ostream &operator<<(std::ostream &dest, __int128_t &value) {\n\tstd::ostream::sentry s(dest);\n\tif(s) {\n\t\t__uint128_t tmp = value < 0 ? -value : value;\n\t\tchar buffer[128];\n\t\tchar *d = std::end(buffer);\n\t\tdo {\n\t\t\t--d;\n\t\t\t*d = \"0123456789\"[tmp % 10];\n\t\t\ttmp /= 10;\n\t\t} while(tmp != 0);\n\t\tif(value < 0) {\n\t\t\t--d;\n\t\t\t*d = '-';\n\t\t}\n\t\tint len = std::end(buffer) - d;\n\t\tif(dest.rdbuf()->sputn(d, len) != len) {\n\t\t\tdest.setstate(std::ios_base::badbit);\n\t\t}\n\t}\n\treturn dest;\n}\n#if __has_include(<atcoder/all>)\nstd::ostream &operator<<(std::ostream &os, const atcoder::modint998244353 &a) { return os << a.val(); }\nstd::ostream &operator<<(std::ostream &os, const atcoder::modint1000000007 &a) { return os << a.val(); }\ntemplate <int m>\nstd::ostream &operator<<(std::ostream &os, const atcoder::static_modint<m> &a) { return os << a.val(); }\ntemplate <int m>\nstd::ostream &operator<<(std::ostream &os, const atcoder::dynamic_modint<m> &a) { return os << a.val(); }\n#endif\ntemplate <class T>\nvoid print(const T a) { std::cout << a << '\\n'; }\ntemplate <class Head, class... Tail>\nvoid print(Head H, Tail... T) {\n\tstd::cout << H << ' ';\n\tprint(T...);\n}\ntemplate <class T>\nvoid printel(const T a) { std::cout << a << '\\n'; }\ntemplate <class T>\nvoid printel(const std::vector<T> &a) {\n\tfor(const auto &v : a)\n\t\tstd::cout << v << '\\n';\n}\ntemplate <class Head, class... Tail>\nvoid printel(Head H, Tail... T) {\n\tstd::cout << H << '\\n';\n\tprintel(T...);\n}\nvoid Yes(const bool b = true) { std::cout << (b ? \"Yes\\n\" : \"No\\n\"); }\nvoid No() { std::cout << \"No\\n\"; }\nvoid YES(const bool b = true) { std::cout << (b ? \"YES\\n\" : \"NO\\n\"); }\nvoid NO() { std::cout << \"NO\\n\"; }\nvoid err(const bool b = true) {\n\tif(b) {\n\t\tstd::cout << \"-1\\n\", exit(0);\n\t}\n}\n\n//debug macro\nnamespace debugger {\ntemplate <class T>\nvoid view(const std::vector<T> &a) {\n\tstd::cerr << \"{ \";\n\tfor(const auto &v : a) {\n\t\tstd::cerr << v << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\ntemplate <class T>\nvoid view(const std::vector<std::vector<T>> &a) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &v : a) {\n\t\tstd::cerr << \"\\t\";\n\t\tview(v);\n\t\tstd::cerr << \"\\n\";\n\t}\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::vector<std::pair<T, U>> &a) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &p : a) std::cerr << \"\\t(\" << p.first << \", \" << p.second << \")\\n\";\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::map<T, U> &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &p : m) std::cerr << \"\\t[\" << p.first << \"] : \" << p.second << \"\\n\";\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::pair<T, U> &p) { std::cerr << \"(\" << p.first << \", \" << p.second << \")\"; }\ntemplate <class T>\nvoid view(const std::set<T> &s) {\n\tstd::cerr << \"{ \";\n\tfor(auto &v : s) {\n\t\tview(v);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <class T>\nvoid view(const T &e) { std::cerr << e; }\n} // namespace debugger\n#ifdef LOCAL\nvoid debug_out() {}\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head H, Tail... T) {\n\tdebugger::view(H);\n\tstd::cerr << \", \";\n\tdebug_out(T...);\n}\n#define debug(...) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"] : [\"; \\\n\t\tdebug_out(__VA_ARGS__); \\\n\t\tstd::cerr << \"\\b\\b]\\n\"; \\\n\t} while(false)\n#else\n#define debug(...) (void(0))\n#endif\n\n// vector macro\ntemplate <class T>\nint lb(const std::vector<T> &a, const T x) { return std::distance((a).begin(), std::lower_bound((a).begin(), (a).end(), (x))); }\ntemplate <class T>\nint ub(const std::vector<T> &a, const T x) { return std::distance((a).begin(), std::upper_bound((a).begin(), (a).end(), (x))); }\ntemplate <class T>\nvoid UNIQUE(std::vector<T> &a) {\n\tstd::sort(a.begin(), a.end());\n\ta.erase(std::unique(a.begin(), a.end()), a.end());\n}\ntemplate <class T>\nstd::vector<T> press(std::vector<T> &a) {\n\tauto res = a;\n\tUNIQUE(res);\n\tfor(auto &v : a)\n\t\tv = lb(res, v);\n\treturn res;\n}\n#define SORTname(a, b, c, ...) c\n#define SORT(...) SORTname(__VA_ARGS__, SORT1, SORT0, ...)(__VA_ARGS__)\n#define SORT0(a) std::sort((a).begin(), (a).end())\n#define SORT1(a, c) std::sort((a).begin(), (a).end(), [](const auto x, const auto y) { return x c y; })\ntemplate <class T>\nvoid ADD(std::vector<T> &a, const T x) {\n\tfor(auto &v : a) v += x;\n}\ntemplate <class T>\nvoid SUB(std::vector<T> &a, const T x = 1) {\n\tfor(auto &v : a) v -= x;\n}\ntemplate <class T>\nvoid MUL(std::vector<T> &a, const T x) {\n\tfor(auto &v : a) v *= x;\n}\ntemplate <class T>\nvoid DIV(std::vector<T> &a, const T x) {\n\tfor(auto &v : a) v /= x;\n}\n\n// math macro\ntemplate <class T, class U>\ninline bool chmin(T &a, const U &b) { return a > b ? a = b, true : false; }\ntemplate <class T, class U>\ninline bool chmax(T &a, const U &b) { return a < b ? a = b, true : false; }\ntemplate <class T>\nT divup(T x, T y) { return (x + y - 1) / y; }\ntemplate <class T>\nT POW(T a, long long n) {\n\tT ret = 1;\n\twhile(n) {\n\t\tif(n & 1) ret *= a;\n\t\ta *= a;\n\t\tn >>= 1;\n\t}\n\treturn ret;\n}\n// modpow\nlong long POW(long long a, long long n, const int mod) {\n\tlong long ret = 1;\n\twhile(n) {\n\t\tif(n & 1) (ret *= a) %= mod;\n\t\t(a *= a) %= mod;\n\t\tn >>= 1;\n\t}\n\treturn ret;\n}\n\n// others\nstruct fast_io {\n\tfast_io() {\n\t\tios::sync_with_stdio(false);\n\t\tcin.tie(nullptr);\n\t\tcout << fixed << setprecision(15);\n\t}\n} fast_io_;\nconst int inf = 1e9;\nconst ll INF = 1e18;\n#pragma endregion\n\nV<> nd(6);\nvoid main_() {\n\tstring ans = \"\";\n\tVEC(int, t, 6);\n\tint sum = accumulate(all(t), 0);\n\tif(!sum) exit(0);\n\tINT(p, q);\n\tV<> perm(6);\n\tiota(all(perm), 0);\n\tdo {\n\t\tstring res = \"\";\n\t\tV<> d(6);\n\t\tREP(i, 6) { d[i] = t[perm[i]]; }\n\n\t\tauto chk = [&d]() -> bool {\n\t\t\tif(*min_element(all(d)) < 0) return 0;\n\t\t\tint a = d[0] + d[1];\n\t\t\tint b = d[2] + d[3];\n\t\t\tint c = d[4] + d[5];\n\t\t\tbool ok = 1;\n\t\t\tok &= a <= b + c + 1;\n\t\t\tok &= b <= a + c + 1;\n\t\t\tok &= c <= a + b;\n\t\t\treturn ok;\n\t\t};\n\n\t\tauto east_rotate = [&]() {\n\t\t\tnd[2] = d[2];\n\t\t\tnd[3] = d[3];\n\t\t\tnd[4] = d[1];\n\t\t\tnd[1] = d[5];\n\t\t\tnd[5] = d[0];\n\t\t\tnd[0] = d[4];\n\t\t\td = nd;\n\t\t\treturn;\n\t\t};\n\n\t\tauto west_rotate = [&]() {\n\t\t\tnd[2] = d[2];\n\t\t\tnd[3] = d[3];\n\t\t\tnd[1] = d[4];\n\t\t\tnd[5] = d[1];\n\t\t\tnd[0] = d[5];\n\t\t\tnd[4] = d[0];\n\t\t\td = nd;\n\t\t\treturn;\n\t\t};\n\n\t\tauto north_rotate = [&]() {\n\t\t\tnd[0] = d[0];\n\t\t\tnd[1] = d[1];\n\t\t\tnd[4] = d[3];\n\t\t\tnd[3] = d[5];\n\t\t\tnd[5] = d[2];\n\t\t\tnd[2] = d[4];\n\t\t\td = nd;\n\t\t\treturn;\n\t\t};\n\n\t\tauto south_rotate = [&]() {\n\t\t\tnd[0] = d[0];\n\t\t\tnd[1] = d[1];\n\t\t\tnd[3] = d[4];\n\t\t\tnd[5] = d[3];\n\t\t\tnd[2] = d[5];\n\t\t\tnd[4] = d[2];\n\t\t\td = nd;\n\t\t\treturn;\n\t\t};\n\n\t\tREP(_, sum) {\n\t\t\t{\n\t\t\t\teast_rotate();\n\t\t\t\td[4]--;\n\t\t\t\tif(chk()) {\n\t\t\t\t\tres += 'E';\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\td[4]++;\n\t\t\t\twest_rotate();\n\t\t\t}\n\t\t\t{\n\t\t\t\tnorth_rotate();\n\t\t\t\td[4]--;\n\t\t\t\tif(chk()) {\n\t\t\t\t\tres += 'N';\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\td[4]++;\n\t\t\t\tsouth_rotate();\n\t\t\t}\n\t\t\t{\n\t\t\t\tsouth_rotate();\n\t\t\t\td[4]--;\n\t\t\t\tif(chk()) {\n\t\t\t\t\tres += 'S';\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\td[4]++;\n\t\t\t\tnorth_rotate();\n\t\t\t}\n\t\t\t{\n\t\t\t\twest_rotate();\n\t\t\t\td[4]--;\n\t\t\t\tif(chk()) {\n\t\t\t\t\tres += 'W';\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\td[4]++;\n\t\t\t\teast_rotate();\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\t\tif(SZ(res) == sum) {\n\t\t\tif(SZ(ans) == 0)\n\t\t\t\tans = res;\n\t\t\telse\n\t\t\t\tchmin(ans, res);\n\t\t}\n\t} while(next_permutation(all(perm)));\n\tif(SZ(ans) != sum) {\n\t\tprint(\"impossible\");\n\t\treturn;\n\t}\n\tREP(i, p - 1, q) {\n\t\tcout << ans[i];\n\t}\n\tcout << endl;\n\treturn;\n}\n\nint main() {\n\tint t = 1;\n\t//cin >> t;\n\twhile(1) main_();\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3050, "memory_kb": 3568, "score_of_the_acc": -0.4915, "final_rank": 15 }, { "submission_id": "aoj_1197_5628812", "code_snippet": "/**\n *\tauthor: nok0\n *\tcreated: 2021.06.29 22:18:07\n**/\n#ifdef LOCAL\n#define _GLIBCXX_DEBUG\n#endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\nusing namespace atcoder;\n#endif\n\n#pragma region Macros\n// rep macro\n#define foa(v, a) for(auto &v : a)\n#define REPname(a, b, c, d, e, ...) e\n#define REP(...) REPname(__VA_ARGS__, REP3, REP2, REP1, REP0)(__VA_ARGS__)\n#define REP0(x) for(int i = 0; i < (x); ++i)\n#define REP1(i, x) for(int i = 0; i < (x); ++i)\n#define REP2(i, l, r) for(int i = (l); i < (r); ++i)\n#define REP3(i, l, r, c) for(int i = (l); i < (r); i += (c))\n#define REPSname(a, b, c, ...) c\n#define REPS(...) REPSname(__VA_ARGS__, REPS1, REPS0)(__VA_ARGS__)\n#define REPS0(x) for(int i = 1; i <= (x); ++i)\n#define REPS1(i, x) for(int i = 1; i <= (x); ++i)\n#define RREPname(a, b, c, d, e, ...) e\n#define RREP(...) RREPname(__VA_ARGS__, RREP3, RREP2, RREP1, RREP0)(__VA_ARGS__)\n#define RREP0(x) for(int i = (x)-1; i >= 0; --i)\n#define RREP1(i, x) for(int i = (x)-1; i >= 0; --i)\n#define RREP2(i, r, l) for(int i = (r)-1; i >= (l); --i)\n#define RREP3(i, r, l, c) for(int i = (r)-1; i >= (l); i -= (c))\n#define RREPSname(a, b, c, ...) c\n#define RREPS(...) RREPSname(__VA_ARGS__, RREPS1, RREPS0)(__VA_ARGS__)\n#define RREPS0(x) for(int i = (x); i >= 1; --i)\n#define RREPS1(i, x) for(int i = (x); i >= 1; --i)\n\n// name macro\n#define pb push_back\n#define eb emplace_back\n#define SZ(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define popcnt(x) __builtin_popcountll(x)\ntemplate <class T = int>\nusing V = std::vector<T>;\ntemplate <class T = int>\nusing VV = std::vector<std::vector<T>>;\ntemplate <class T>\nusing pqup = std::priority_queue<T, std::vector<T>, std::greater<T>>;\nusing ll = long long;\nusing ld = long double;\nusing int128 = __int128_t;\nusing pii = std::pair<int, int>;\nusing pll = std::pair<long long, long long>;\n\n// input macro\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n\tis >> p.first >> p.second;\n\treturn is;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n\tfor(T &i : v) is >> i;\n\treturn is;\n}\nstd::istream &operator>>(std::istream &is, __int128_t &a) {\n\tstd::string s;\n\tis >> s;\n\t__int128_t ret = 0;\n\tfor(int i = 0; i < s.length(); i++)\n\t\tif('0' <= s[i] and s[i] <= '9')\n\t\t\tret = 10 * ret + s[i] - '0';\n\ta = ret * (s[0] == '-' ? -1 : 1);\n\treturn is;\n}\n#if __has_include(<atcoder/all>)\nstd::istream &operator>>(std::istream &is, atcoder::modint998244353 &a) {\n\tlong long v;\n\tis >> v;\n\ta = v;\n\treturn is;\n}\nstd::istream &operator>>(std::istream &is, atcoder::modint1000000007 &a) {\n\tlong long v;\n\tis >> v;\n\ta = v;\n\treturn is;\n}\ntemplate <int m>\nstd::istream &operator>>(std::istream &is, atcoder::static_modint<m> &a) {\n\tlong long v;\n\tis >> v;\n\ta = v;\n\treturn is;\n}\ntemplate <int m>\nstd::istream &operator>>(std::istream &is, atcoder::dynamic_modint<m> &a) {\n\tlong long v;\n\tis >> v;\n\ta = v;\n\treturn is;\n}\n#endif\nnamespace scanner {\nvoid scan(int &a) { std::cin >> a; }\nvoid scan(long long &a) { std::cin >> a; }\nvoid scan(std::string &a) { std::cin >> a; }\nvoid scan(char &a) { std::cin >> a; }\nvoid scan(char a[]) { std::scanf(\"%s\", a); }\nvoid scan(double &a) { std::cin >> a; }\nvoid scan(long double &a) { std::cin >> a; }\ntemplate <class T, class U>\nvoid scan(std::pair<T, U> &p) { std::cin >> p; }\ntemplate <class T>\nvoid scan(std::vector<T> &a) { std::cin >> a; }\nvoid INPUT() {}\ntemplate <class Head, class... Tail>\nvoid INPUT(Head &head, Tail &... tail) {\n\tscan(head);\n\tINPUT(tail...);\n}\n} // namespace scanner\n#define VEC(type, name, size) \\\n\tstd::vector<type> name(size); \\\n\tscanner::INPUT(name)\n#define VVEC(type, name, h, w) \\\n\tstd::vector<std::vector<type>> name(h, std::vector<type>(w)); \\\n\tscanner::INPUT(name)\n#define INT(...) \\\n\tint __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LL(...) \\\n\tlong long __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define STR(...) \\\n\tstd::string __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define CHAR(...) \\\n\tchar __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define DOUBLE(...) \\\n\tdouble __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LD(...) \\\n\tlong double __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n\n// output-macro\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n\tos << p.first << \" \" << p.second;\n\treturn os;\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &a) {\n\tfor(int i = 0; i < int(a.size()); ++i) {\n\t\tif(i) os << \" \";\n\t\tos << a[i];\n\t}\n\treturn os;\n}\nstd::ostream &operator<<(std::ostream &dest, __int128_t &value) {\n\tstd::ostream::sentry s(dest);\n\tif(s) {\n\t\t__uint128_t tmp = value < 0 ? -value : value;\n\t\tchar buffer[128];\n\t\tchar *d = std::end(buffer);\n\t\tdo {\n\t\t\t--d;\n\t\t\t*d = \"0123456789\"[tmp % 10];\n\t\t\ttmp /= 10;\n\t\t} while(tmp != 0);\n\t\tif(value < 0) {\n\t\t\t--d;\n\t\t\t*d = '-';\n\t\t}\n\t\tint len = std::end(buffer) - d;\n\t\tif(dest.rdbuf()->sputn(d, len) != len) {\n\t\t\tdest.setstate(std::ios_base::badbit);\n\t\t}\n\t}\n\treturn dest;\n}\n#if __has_include(<atcoder/all>)\nstd::ostream &operator<<(std::ostream &os, const atcoder::modint998244353 &a) { return os << a.val(); }\nstd::ostream &operator<<(std::ostream &os, const atcoder::modint1000000007 &a) { return os << a.val(); }\ntemplate <int m>\nstd::ostream &operator<<(std::ostream &os, const atcoder::static_modint<m> &a) { return os << a.val(); }\ntemplate <int m>\nstd::ostream &operator<<(std::ostream &os, const atcoder::dynamic_modint<m> &a) { return os << a.val(); }\n#endif\ntemplate <class T>\nvoid print(const T a) { std::cout << a << '\\n'; }\ntemplate <class Head, class... Tail>\nvoid print(Head H, Tail... T) {\n\tstd::cout << H << ' ';\n\tprint(T...);\n}\ntemplate <class T>\nvoid printel(const T a) { std::cout << a << '\\n'; }\ntemplate <class T>\nvoid printel(const std::vector<T> &a) {\n\tfor(const auto &v : a)\n\t\tstd::cout << v << '\\n';\n}\ntemplate <class Head, class... Tail>\nvoid printel(Head H, Tail... T) {\n\tstd::cout << H << '\\n';\n\tprintel(T...);\n}\nvoid Yes(const bool b = true) { std::cout << (b ? \"Yes\\n\" : \"No\\n\"); }\nvoid No() { std::cout << \"No\\n\"; }\nvoid YES(const bool b = true) { std::cout << (b ? \"YES\\n\" : \"NO\\n\"); }\nvoid NO() { std::cout << \"NO\\n\"; }\nvoid err(const bool b = true) {\n\tif(b) {\n\t\tstd::cout << \"-1\\n\", exit(0);\n\t}\n}\n\n//debug macro\nnamespace debugger {\ntemplate <class T>\nvoid view(const std::vector<T> &a) {\n\tstd::cerr << \"{ \";\n\tfor(const auto &v : a) {\n\t\tstd::cerr << v << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\ntemplate <class T>\nvoid view(const std::vector<std::vector<T>> &a) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &v : a) {\n\t\tstd::cerr << \"\\t\";\n\t\tview(v);\n\t\tstd::cerr << \"\\n\";\n\t}\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::vector<std::pair<T, U>> &a) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &p : a) std::cerr << \"\\t(\" << p.first << \", \" << p.second << \")\\n\";\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::map<T, U> &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &p : m) std::cerr << \"\\t[\" << p.first << \"] : \" << p.second << \"\\n\";\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::pair<T, U> &p) { std::cerr << \"(\" << p.first << \", \" << p.second << \")\"; }\ntemplate <class T>\nvoid view(const std::set<T> &s) {\n\tstd::cerr << \"{ \";\n\tfor(auto &v : s) {\n\t\tview(v);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <class T>\nvoid view(const T &e) { std::cerr << e; }\n} // namespace debugger\n#ifdef LOCAL\nvoid debug_out() {}\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head H, Tail... T) {\n\tdebugger::view(H);\n\tstd::cerr << \", \";\n\tdebug_out(T...);\n}\n#define debug(...) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"] : [\"; \\\n\t\tdebug_out(__VA_ARGS__); \\\n\t\tstd::cerr << \"\\b\\b]\\n\"; \\\n\t} while(false)\n#else\n#define debug(...) (void(0))\n#endif\n\n// vector macro\ntemplate <class T>\nint lb(const std::vector<T> &a, const T x) { return std::distance((a).begin(), std::lower_bound((a).begin(), (a).end(), (x))); }\ntemplate <class T>\nint ub(const std::vector<T> &a, const T x) { return std::distance((a).begin(), std::upper_bound((a).begin(), (a).end(), (x))); }\ntemplate <class T>\nvoid UNIQUE(std::vector<T> &a) {\n\tstd::sort(a.begin(), a.end());\n\ta.erase(std::unique(a.begin(), a.end()), a.end());\n}\ntemplate <class T>\nstd::vector<T> press(std::vector<T> &a) {\n\tauto res = a;\n\tUNIQUE(res);\n\tfor(auto &v : a)\n\t\tv = lb(res, v);\n\treturn res;\n}\n#define SORTname(a, b, c, ...) c\n#define SORT(...) SORTname(__VA_ARGS__, SORT1, SORT0, ...)(__VA_ARGS__)\n#define SORT0(a) std::sort((a).begin(), (a).end())\n#define SORT1(a, c) std::sort((a).begin(), (a).end(), [](const auto x, const auto y) { return x c y; })\ntemplate <class T>\nvoid ADD(std::vector<T> &a, const T x) {\n\tfor(auto &v : a) v += x;\n}\ntemplate <class T>\nvoid SUB(std::vector<T> &a, const T x = 1) {\n\tfor(auto &v : a) v -= x;\n}\ntemplate <class T>\nvoid MUL(std::vector<T> &a, const T x) {\n\tfor(auto &v : a) v *= x;\n}\ntemplate <class T>\nvoid DIV(std::vector<T> &a, const T x) {\n\tfor(auto &v : a) v /= x;\n}\n\n// math macro\ntemplate <class T, class U>\ninline bool chmin(T &a, const U &b) { return a > b ? a = b, true : false; }\ntemplate <class T, class U>\ninline bool chmax(T &a, const U &b) { return a < b ? a = b, true : false; }\ntemplate <class T>\nT divup(T x, T y) { return (x + y - 1) / y; }\ntemplate <class T>\nT POW(T a, long long n) {\n\tT ret = 1;\n\twhile(n) {\n\t\tif(n & 1) ret *= a;\n\t\ta *= a;\n\t\tn >>= 1;\n\t}\n\treturn ret;\n}\n// modpow\nlong long POW(long long a, long long n, const int mod) {\n\tlong long ret = 1;\n\twhile(n) {\n\t\tif(n & 1) (ret *= a) %= mod;\n\t\t(a *= a) %= mod;\n\t\tn >>= 1;\n\t}\n\treturn ret;\n}\n\n// others\nstruct fast_io {\n\tfast_io() {\n\t\tios::sync_with_stdio(false);\n\t\tcin.tie(nullptr);\n\t\tcout << fixed << setprecision(15);\n\t}\n} fast_io_;\nconst int inf = 1e9;\nconst ll INF = 1e18;\n#pragma endregion\n\nV<> nd(6);\nvoid main_() {\n\tstring ans = \"\";\n\tVEC(int, t, 6);\n\tint sum = accumulate(all(t), 0);\n\tif(!sum) exit(0);\n\tINT(p, q);\n\tV<> perm(6);\n\tiota(all(perm), 0);\n\tdo {\n\t\tstring res = \"\";\n\t\tV<> d(6);\n\t\tREP(i, 6) { d[i] = t[perm[i]]; }\n\n\t\tauto chk = [&d]() -> bool {\n\t\t\tif(*min_element(all(d)) < 0) return 0;\n\t\t\tint a = d[0] + d[1];\n\t\t\tint b = d[2] + d[3];\n\t\t\tint c = d[4] + d[5];\n\t\t\tbool ok = 1;\n\t\t\tok &= a <= b + c + 1;\n\t\t\tok &= b <= a + c + 1;\n\t\t\tok &= c <= a + b;\n\t\t\treturn ok;\n\t\t};\n\n\t\tauto east_rotate = [&]() {\n\t\t\tnd[2] = d[2];\n\t\t\tnd[3] = d[3];\n\t\t\tnd[4] = d[1];\n\t\t\tnd[1] = d[5];\n\t\t\tnd[5] = d[0];\n\t\t\tnd[0] = d[4];\n\t\t\td = nd;\n\t\t\treturn;\n\t\t};\n\n\t\tauto west_rotate = [&]() {\n\t\t\tnd[2] = d[2];\n\t\t\tnd[3] = d[3];\n\t\t\tnd[1] = d[4];\n\t\t\tnd[5] = d[1];\n\t\t\tnd[0] = d[5];\n\t\t\tnd[4] = d[0];\n\t\t\td = nd;\n\t\t\treturn;\n\t\t};\n\n\t\tauto north_rotate = [&]() {\n\t\t\tnd[0] = d[0];\n\t\t\tnd[1] = d[1];\n\t\t\tnd[4] = d[3];\n\t\t\tnd[3] = d[5];\n\t\t\tnd[5] = d[2];\n\t\t\tnd[2] = d[4];\n\t\t\td = nd;\n\t\t\treturn;\n\t\t};\n\n\t\tauto south_rotate = [&]() {\n\t\t\tnd[0] = d[0];\n\t\t\tnd[1] = d[1];\n\t\t\tnd[3] = d[4];\n\t\t\tnd[5] = d[3];\n\t\t\tnd[2] = d[5];\n\t\t\tnd[4] = d[2];\n\t\t\td = nd;\n\t\t\treturn;\n\t\t};\n\n\t\tREP(_, sum) {\n\t\t\t{\n\t\t\t\teast_rotate();\n\t\t\t\td[4]--;\n\t\t\t\tif(chk()) {\n\t\t\t\t\tres += 'E';\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\td[4]++;\n\t\t\t\twest_rotate();\n\t\t\t}\n\t\t\t{\n\t\t\t\tnorth_rotate();\n\t\t\t\td[4]--;\n\t\t\t\tif(chk()) {\n\t\t\t\t\tres += 'N';\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\td[4]++;\n\t\t\t\tsouth_rotate();\n\t\t\t}\n\t\t\t{\n\t\t\t\tsouth_rotate();\n\t\t\t\td[4]--;\n\t\t\t\tif(chk()) {\n\t\t\t\t\tres += 'S';\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\td[4]++;\n\t\t\t\tnorth_rotate();\n\t\t\t}\n\t\t\t{\n\t\t\t\twest_rotate();\n\t\t\t\td[4]--;\n\t\t\t\tif(chk()) {\n\t\t\t\t\tres += 'W';\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\td[4]++;\n\t\t\t\teast_rotate();\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\t\tif(SZ(res) == sum) {\n\t\t\tif(SZ(ans) == 0)\n\t\t\t\tans = res;\n\t\t\telse\n\t\t\t\tchmin(ans, res);\n\t\t}\n\t} while(next_permutation(all(perm)));\n\tif(SZ(ans) != sum) {\n\t\tprint(\"impossible\");\n\t\treturn;\n\t}\n\tREP(i, p - 1, q) {\n\t\tcout << ans[i];\n\t}\n\tcout << endl;\n\treturn;\n}\n\nint main() {\n\tint t = 1;\n\t//cin >> t;\n\twhile(1) main_();\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3050, "memory_kb": 3488, "score_of_the_acc": -0.4683, "final_rank": 14 }, { "submission_id": "aoj_1197_5628370", "code_snippet": "//#define _GLIBCXX_DEBUG\n\n#include<bits/stdc++.h>\nusing namespace std;\n\n#define endl '\\n'\n#define lfs cout<<fixed<<setprecision(10)\n#define ALL(a) (a).begin(),(a).end()\n#define ALLR(a) (a).rbegin(),(a).rend()\n#define spa << \" \" <<\n#define fi first\n#define se second\n#define MP make_pair\n#define MT make_tuple\n#define PB push_back\n#define EB emplace_back\n#define rep(i,n,m) for(ll i = (n); i < (ll)(m); i++)\n#define rrep(i,n,m) for(ll i = (ll)(m) - 1; i >= (ll)(n); i--)\nusing ll = long long;\nusing ld = long double;\nconst ll MOD1 = 1e9+7;\nconst ll MOD9 = 998244353;\nconst ll INF = 1e18;\nusing P = pair<ll, ll>;\ntemplate<typename T> using PQ = priority_queue<T>;\ntemplate<typename T> using QP = priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T1, typename T2>bool chmin(T1 &a,T2 b){if(a>b){a=b;return true;}else return false;}\ntemplate<typename T1, typename T2>bool chmax(T1 &a,T2 b){if(a<b){a=b;return true;}else return false;}\nll median(ll a,ll b, ll c){return a+b+c-max({a,b,c})-min({a,b,c});}\nvoid ans1(bool x){if(x) cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;}\nvoid ans2(bool x){if(x) cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;}\nvoid ans3(bool x){if(x) cout<<\"Yay!\"<<endl;else cout<<\":(\"<<endl;}\ntemplate<typename T1,typename T2>void ans(bool x,T1 y,T2 z){if(x)cout<<y<<endl;else cout<<z<<endl;} \ntemplate<typename T1,typename T2,typename T3>void anss(T1 x,T2 y,T3 z){ans(x!=y,x,z);}; \ntemplate<typename T>void debug(const T &v,ll h,ll w,string sv=\" \"){for(ll i=0;i<h;i++){cout<<v[i][0];for(ll j=1;j<w;j++)cout<<sv<<v[i][j];cout<<endl;}};\ntemplate<typename T>void debug(const T &v,ll n,string sv=\" \"){if(n!=0)cout<<v[0];for(ll i=1;i<n;i++)cout<<sv<<v[i];cout<<endl;};\ntemplate<typename T>void debug(const vector<T>&v){debug(v,v.size());}\ntemplate<typename T>void debug(const vector<vector<T>>&v){for(auto &vv:v)debug(vv,vv.size());}\ntemplate<typename T>void debug(stack<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(queue<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(deque<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop_front();}cout<<endl;}\ntemplate<typename T>void debug(PQ<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(QP<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(const set<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T>void debug(const multiset<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,size_t size>void debug(const array<T, size> &a){for(auto z:a)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,typename V>void debug(const map<T,V>&v){for(auto z:v)cout<<\"[\"<<z.first<<\"]=\"<<z.second<<\",\";cout<<endl;}\ntemplate<typename T>vector<vector<T>>vec(ll x, ll y, T w){vector<vector<T>>v(x,vector<T>(y,w));return v;}\nll gcd(ll x,ll y){ll r;while(y!=0&&(r=x%y)!=0){x=y;y=r;}return y==0?x:y;}\nvector<ll>dx={1,-1,0,0,1,1,-1,-1};vector<ll>dy={0,0,1,-1,1,-1,1,-1};\ntemplate<typename T>vector<T> make_v(size_t a,T b){return vector<T>(a,b);}\ntemplate<typename... Ts>auto make_v(size_t a,Ts... ts){return vector<decltype(make_v(ts...))>(a,make_v(ts...));}\ntemplate<typename T1, typename T2>ostream &operator<<(ostream &os, const pair<T1, T2>&p){return os << p.first << \" \" << p.second;}\ntemplate<typename T>ostream &operator<<(ostream &os, const vector<T> &v){for(auto &z:v)os << z << \" \";cout<<\"|\"; return os;}\ntemplate<typename T>void rearrange(vector<int>&ord, vector<T>&v){\n auto tmp = v;\n for(int i=0;i<tmp.size();i++)v[i] = tmp[ord[i]];\n}\ntemplate<typename Head, typename... Tail>void rearrange(vector<int>&ord,Head&& head, Tail&&... tail){\n rearrange(ord, head);\n rearrange(ord, tail...);\n}\ntemplate<typename T> vector<int> ascend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return v[i]<v[j];});\n return ord;\n}\ntemplate<typename T> vector<int> descend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return v[i]>v[j];});\n return ord;\n}\nll FLOOR(ll n,ll div){return n>=0?n/div:(n-div+1)/div;}\nll CEIL(ll n,ll div){return n>=0?(n+div-1)/div:n/div;}\nll digitsum(ll n){ll ret=0;while(n){ret+=n%10;n/=10;}return ret;}\ntemplate<typename T>T min(const vector<T>&v){return *min_element(v.begin(),v.end());}\ntemplate<typename T>T max(const vector<T>&v){return *max_element(v.begin(),v.end());}\ntemplate<typename T>T acc(const vector<T>&v){return accumulate(v.begin(),v.end(),T(0));};\ntemplate<typename T>T reverse(const T &v){return T(v.rbegin(),v.rend());};\n//mt19937 mt(chrono::steady_clock::now().time_since_epoch().count());\nint popcount(ll x){return __builtin_popcountll(x);};\nint poplow(ll x){return __builtin_ctzll(x);};\nint pophigh(ll x){return 63 - __builtin_clzll(x);};\ntemplate<typename T>T poll(queue<T> &q){auto ret=q.front();q.pop();return ret;};\ntemplate<typename T>T poll(priority_queue<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(QP<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(stack<T> &s){auto ret=s.top();s.pop();return ret;};\ntemplate< typename T = int >\nstruct edge {\n int to;\n T cost;\n int id;\n edge():id(-1){};\n edge(int to, T cost = 1, int id = -1):to(to), cost(cost), id(id){}\n operator int() const { return to; }\n};\n\ntemplate<typename T>\nusing Graph = vector<vector<edge<T>>>;\ntemplate<typename T>\nGraph<T>revgraph(const Graph<T> &g){\n Graph<T>ret(g.size());\n for(int i=0;i<g.size();i++){\n for(auto e:g[i]){\n int to = e.to;\n e.to = i;\n ret[to].push_back(e);\n }\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readGraph(int n,int m,int indexed=1,bool directed=false,bool weighted=false){\n Graph<T> ret(n);\n for(int es = 0; es < m; es++){\n int u,v;\n T w=1;\n cin>>u>>v;u-=indexed,v-=indexed;\n if(weighted)cin>>w;\n ret[u].emplace_back(v,w,es);\n if(!directed)ret[v].emplace_back(u,w,es);\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readParent(int n,int indexed=1,bool directed=true){\n Graph<T>ret(n);\n for(int i=1;i<n;i++){\n int p;cin>>p;\n p-=indexed;\n ret[p].emplace_back(i);\n if(!directed)ret[i].emplace_back(p);\n }\n return ret;\n}\ntemplate<typename T>\nstruct Dice{\n array<T, 6>ar;\n Dice() = default;\n // 1\n //342\n // 0\n // 5\n Dice(array<T, 6>ar):ar(ar){}\n //xが上下、yが左右\n //0:x++\n //1:x--\n //2:y++\n //3:y--\n //4:clockwise\n //5:counter-clockwise\n void roll(int x){\n array<int, 6>trans;\n if(x == 0)ar = {ar[4],ar[5],ar[2],ar[3],ar[1],ar[0]};\n if(x == 1)ar = {ar[5],ar[4],ar[2],ar[3],ar[0],ar[1]};\n if(x == 2)ar = {ar[0],ar[1],ar[4],ar[5],ar[3],ar[2]};\n if(x == 3)ar = {ar[0],ar[1],ar[5],ar[4],ar[2],ar[3]};\n if(x == 4)ar = {ar[2],ar[3],ar[1],ar[0],ar[4],ar[5]};\n if(x == 5)ar = {ar[3],ar[2],ar[0],ar[1],ar[4],ar[5]};\n }\n bool operator==(const Dice &d) const{\n return ar == d.ar;\n }\n bool operator!=(const Dice &d) const{\n return ar != d.ar;\n }\n bool operator<(const Dice &d) const{\n return ar < d.ar;\n }\n T &operator[](int x){\n return ar[x];\n }\n T operator[](int x) const{\n return ar[x];\n }\n vector<Dice<T>>makeAll(){\n vector<Dice<T>>ret;\n for(int i=0;i<6;i++){\n Dice tmp = *this;\n if(i==1)tmp.roll(0);\n if(i==2)tmp.roll(1);\n if(i==3)tmp.roll(1),tmp.roll(1);\n if(i==4)tmp.roll(4);\n if(i==5)tmp.roll(5);\n for(int k=0;k<4;k++){\n ret.push_back(tmp);\n tmp.roll(2);\n }\n }\n return ret;\n }\n Dice<T> minDice(){\n auto dice = this->makeAll();\n return *min_element(dice.begin(), dice.end());\n }\n};\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n ll res=0,buf=0;\n bool judge = true;\n while(1){\n array<int,6>t;\n rep(i,0,6)cin>>t[i];\n if(t[5]==0)break;\n int p,q;cin>>p>>q;\n sort(ALL(t));\n string ret=\"impossible\";\n string ope=\"SNEW\";\n int m=0;for(auto z:t)m+=z;\n auto check=[&](const Dice<int>&d,int sum){\n if((d[4]+d[5])*2>sum)return false;\n if((d[0]+d[1])*2>sum+1)return false;\n if((d[2]+d[3])*2>sum+1)return false;\n return true;\n };\n do{\n Dice<int>dice(t);\n if(!check(dice,m))continue;\n string s;\n rrep(sum,0,m){\n for(auto i:{2,1,0,3}){\n auto tmp=dice;\n tmp.roll(i);\n if(tmp[5]<=0)continue;\n tmp[5]-=1;\n if(check(tmp,sum)){\n s+=ope[i];\n dice=tmp;\n break;\n }\n }\n if(s.size()+sum!=m)break;\n }\n if(s.size()==m){\n chmin(ret,s);\n }\n }while(next_permutation(ALL(t)));\n //cout<<ret<<endl;\n if(ret[0]=='i')cout<<ret<<endl;\n else cout<<ret.substr(p-1,q-p+1)<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 620, "memory_kb": 3264, "score_of_the_acc": -0.0186, "final_rank": 2 } ]
aoj_1198_cpp
Don't Cross the Circles! There are one or more circles on a plane. Any two circles have different center positions and/or different radiuses. A circle may intersect with another circle, but no three or more circles have areas nor points shared by all of them. A circle may completely contain another circle or two circles may intersect at two separate points, but you can assume that the circumferences of two circles never touch at a single point. Your task is to judge whether there exists a path that connects the given two points, P and Q , without crossing the circumferences of the circles. You are given one or more point pairs for each layout of circles. In the case of Figure G-1, we can connect P and Q 1 without crossing the circumferences of the circles, but we cannot connect P with Q 2 , Q 3 , or Q 4 without crossing the circumferences of the circles. Figure G-1: Sample layout of circles and points Input The input consists of multiple datasets, each in the following format. n m Cx 1 Cy 1 r 1 ... Cx n Cy n r n Px 1 Py 1 Qx 1 Qy 1 ... Px m Py m Qx m Qy m The first line of a dataset contains two integers n and m separated by a space. n represents the number of circles, and you can assume 1 ≤ n ≤ 100. m represents the number of point pairs, and you can assume 1 ≤ m ≤ 10. Each of the following n lines contains three integers separated by a single space. ( Cx i , Cy i ) and r i represent the center position and the radius of the i -th circle, respectively. Each of the following m lines contains four integers separated by a single space. These four integers represent coordinates of two separate points P j = ( Px j , Py j ) and Q j =( Qx j , Qy j ). These two points P j and Q j form the j -th point pair. You can assume 0 ≤ Cx i ≤ 10000, 0 ≤ Cy i ≤ 10000, 1 ≤ r i ≤ 1000, 0 ≤ Px j ≤ 10000, 0 ≤ Py j ≤ 10000, 0 ≤ Qx j ≤ 10000, 0 ≤ Qy j ≤ 10000. In addition, you can assume P j or Q j are not located on the circumference of any circle. The end of the input is indicated by a line containing two zeros separated by a space. Figure G-1 shows the layout of the circles and the points in the first dataset of the sample input below. Figure G-2 shows the layouts of the subsequent datasets in the sample input. Figure G-2: Sample layout of circles and points Output For each dataset, output a single line containing the m results separated by a space. The j -th result should be "YES" if there exists a path connecting P j and Q j , and "NO" otherwise. Sample Input 5 3 0 0 1000 1399 1331 931 0 1331 500 1398 0 400 2000 360 340 450 950 1600 380 450 950 1399 1331 450 950 450 2000 1 2 50 50 50 0 10 100 90 0 10 50 50 2 2 50 50 50 100 50 50 40 50 110 50 40 50 0 0 4 1 25 100 26 75 100 26 50 40 40 50 160 40 50 81 50 119 6 1 100 50 40 0 50 40 50 0 48 50 50 3 55 55 4 55 105 48 50 55 55 50 20 6 270 180 50 360 170 50 0 0 50 10 0 10 0 90 50 0 180 50 90 180 50 180 180 50 205 90 50 180 0 50 65 0 20 75 30 16 90 78 36 105 30 16 115 0 20 128 48 15 128 100 15 280 0 30 330 0 30 305 65 42 0 2 ...(truncated)
[ { "submission_id": "aoj_1198_9340740", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing Real = long double;\nusing Point = complex<Real>;\nconst Real EPS = 1e-9, PI = acos(-1);\n\ninline bool eq(Real a, Real b) {\n return fabs(b - a) < EPS;\n}\n\nPoint operator*(const Point &p, const Real &d) {\n return Point(real(p) * d, imag(p) * d);\n}\n\nistream &operator>>(istream &is, Point &p) {\n Real a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n}\n\nostream &operator<<(ostream &os, Point &p) {\n return os << fixed << setprecision(10) << p.real() << \" \" << p.imag();\n}\n\n// 点 p を反時計回りに theta 回転\nPoint rotate(Real theta, const Point &p) {\n return Point(\n cos(theta) * p.real() - sin(theta) * p.imag(), sin(theta) * p.real() + cos(theta) * p.imag());\n}\n\nReal radian_to_degree(Real r) {\n return (r * 180.0 / PI);\n}\n\nReal degree_to_radian(Real d) {\n return (d * PI / 180.0);\n}\n\n// a-b-c の角度のうち小さい方を返す\nReal get_angle(const Point &a, const Point &b, const Point &c) {\n const Point v(b - a), w(c - b);\n Real alpha = atan2(v.imag(), v.real()), beta = atan2(w.imag(), w.real());\n if (alpha > beta) swap(alpha, beta);\n Real theta = (beta - alpha);\n return min(theta, 2 * acos(-1) - theta);\n}\n\nnamespace std {\nbool operator<(const Point &a, const Point &b) {\n return a.real() != b.real() ? a.real() < b.real() : a.imag() < b.imag();\n}\n} // namespace std\n\nstruct Line {\n Point a, b;\n\n Line() = default;\n\n Line(Point a, Point b) : a(a), b(b) {}\n\n Line(Real A, Real B, Real C) // Ax + By = C\n {\n if (eq(A, 0)) a = Point(0, C / B), b = Point(1, C / B);\n else if (eq(B, 0)) b = Point(C / A, 0), b = Point(C / A, 1);\n else a = Point(0, C / B), b = Point(C / A, 0);\n }\n\n friend ostream &operator<<(ostream &os, Line &p) { return os << p.a << \" to \" << p.b; }\n\n friend istream &operator>>(istream &is, Line &a) { return is >> a.a >> a.b; }\n};\n\nstruct Segment : Line {\n Segment() = default;\n\n Segment(Point a, Point b) : Line(a, b) {}\n};\n\nstruct Circle {\n Point p;\n Real r;\n\n Circle() = default;\n\n Circle(Point p, Real r) : p(p), r(r) {}\n};\n\nusing Points = vector<Point>;\nusing Polygon = vector<Point>;\nusing Segments = vector<Segment>;\nusing Lines = vector<Line>;\nusing Circles = vector<Circle>;\n\nReal cross(const Point &a, const Point &b) {\n return real(a) * imag(b) - imag(a) * real(b);\n}\n\nReal dot(const Point &a, const Point &b) {\n return real(a) * real(b) + imag(a) * imag(b);\n}\n\n// 点の回転方向\nint ccw(const Point &a, Point b, Point c) {\n b = b - a, c = c - a;\n if (cross(b, c) > EPS) return +1; // \"COUNTER_CLOCKWISE\"\n if (cross(b, c) < -EPS) return -1; // \"CLOCKWISE\"\n if (dot(b, c) < 0) return +2; // \"ONLINE_BACK\"\n if (norm(b) < norm(c)) return -2; // \"ONLINE_FRONT\"\n return 0; // \"ON_SEGMENT\"\n}\n\n// 平行判定\nbool parallel(const Line &a, const Line &b) {\n return eq(cross(a.b - a.a, b.b - b.a), 0.0);\n}\n\n// 垂直判定\nbool orthogonal(const Line &a, const Line &b) {\n return eq(dot(a.a - a.b, b.a - b.b), 0.0);\n}\n\n// 射影\n// 直線 l に p から垂線を引いた交点を求める\nPoint projection(const Line &l, const Point &p) {\n double t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\nPoint projection(const Segment &l, const Point &p) {\n double t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\n\n// 反射\n// 直線 l を対称軸として点 p と線対称にある点を求める\nPoint reflection(const Line &l, const Point &p) {\n return p + (projection(l, p) - p) * 2.0;\n}\n\nbool intersect(const Line &l, const Point &p) {\n return abs(ccw(l.a, l.b, p)) != 1;\n}\nbool intersect(const Line &l, const Line &m) {\n return abs(cross(l.b - l.a, m.b - m.a)) > EPS || abs(cross(l.b - l.a, m.b - l.a)) < EPS;\n}\nbool intersect(const Segment &s, const Point &p) {\n return ccw(s.a, s.b, p) == 0;\n}\nbool intersect(const Line &l, const Segment &s) {\n return cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < EPS;\n}\n\nReal distance(const Line &l, const Point &p);\n\nbool intersect(const Circle &c, const Line &l) {\n return distance(l, c.p) <= c.r + EPS;\n}\nbool intersect(const Circle &c, const Point &p) {\n return abs(abs(p - c.p) - c.r) < EPS;\n}\nbool intersect(const Segment &s, const Segment &t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\nint intersect(const Circle &c, const Segment &l) {\n if (norm(projection(l, c.p) - c.p) - c.r * c.r > EPS) return 0;\n auto d1 = abs(c.p - l.a), d2 = abs(c.p - l.b);\n if (d1 < c.r + EPS && d2 < c.r + EPS) return 0;\n if (d1 < c.r - EPS && d2 > c.r + EPS || d1 > c.r + EPS && d2 < c.r - EPS) return 1;\n const Point h = projection(l, c.p);\n if (dot(l.a - h, l.b - h) < 0) return 2;\n return 0;\n}\n// 0 -> 包含, 1 -> 内接, 2 -> 交差, 3 -> 外接, 4 -> 分離\nint intersect(Circle c1, Circle c2) {\n if (c1.r < c2.r) swap(c1, c2);\n Real d = abs(c1.p - c2.p);\n if (c1.r + c2.r < d) return 4;\n if (eq(c1.r + c2.r, d)) return 3;\n if (c1.r - c2.r < d) return 2;\n if (eq(c1.r - c2.r, d)) return 1;\n return 0;\n}\n\nReal distance(const Point &a, const Point &b) {\n return abs(a - b);\n}\nReal distance(const Line &l, const Point &p) {\n return abs(p - projection(l, p));\n}\nReal distance(const Line &l, const Line &m) {\n return intersect(l, m) ? 0 : distance(l, m.a);\n}\nReal distance(const Segment &s, const Point &p) {\n Point r = projection(s, p);\n if (intersect(s, r)) return abs(r - p);\n return min(abs(s.a - p), abs(s.b - p));\n}\nReal distance(const Segment &a, const Segment &b) {\n if (intersect(a, b)) return 0;\n return min({distance(a, b.a), distance(a, b.b), distance(b, a.a), distance(b, a.b)});\n}\nReal distance(const Line &l, const Segment &s) {\n if (intersect(l, s)) return 0;\n return min(distance(l, s.a), distance(l, s.b));\n}\n\nPoint crosspoint(const Line &l, const Line &m) {\n Real A = cross(l.b - l.a, m.b - m.a);\n Real B = cross(l.b - l.a, l.b - m.a);\n if (eq(abs(A), 0.0) && eq(abs(B), 0.0)) return m.a;\n return m.a + (m.b - m.a) * B / A;\n}\nPoint crosspoint(const Segment &l, const Segment &m) {\n return crosspoint(Line(l), Line(m));\n}\npair<Point, Point> crosspoint(const Circle &c, const Line l) {\n Point pr = projection(l, c.p);\n Point e = (l.b - l.a) / abs(l.b - l.a);\n if (eq(distance(l, c.p), c.r)) return {pr, pr};\n double base = sqrt(c.r * c.r - norm(pr - c.p));\n return {pr - e * base, pr + e * base};\n}\npair<Point, Point> crosspoint(const Circle &c, const Segment &l) {\n Line aa = Line(l.a, l.b);\n if (intersect(c, l) == 2) return crosspoint(c, aa);\n auto ret = crosspoint(c, aa);\n if (dot(l.a - ret.first, l.b - ret.first) < 0) ret.second = ret.first;\n else ret.first = ret.second;\n return ret;\n}\npair<Point, Point> crosspoint(const Circle &c1, const Circle &c2) {\n Real d = abs(c1.p - c2.p);\n Real a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d));\n Real t = atan2(c2.p.imag() - c1.p.imag(), c2.p.real() - c1.p.real());\n Point p1 = c1.p + Point(cos(t + a) * c1.r, sin(t + a) * c1.r);\n Point p2 = c1.p + Point(cos(t - a) * c1.r, sin(t - a) * c1.r);\n return {p1, p2};\n}\n\n// 点 p を通る円 c の接線\npair<Point, Point> tangent(const Circle &c1, const Point &p2) {\n return crosspoint(c1, Circle(p2, sqrt(norm(c1.p - p2) - c1.r * c1.r)));\n}\n\n// 円 c1, c2 の共通接線\nLines tangent(Circle c1, Circle c2) {\n Lines ret;\n if (c1.r < c2.r) swap(c1, c2);\n Real g = norm(c1.p - c2.p);\n if (eq(g, 0)) return ret;\n Point u = (c2.p - c1.p) / sqrt(g);\n Point v = rotate(PI * 0.5, u);\n for (int s : {-1, 1}) {\n Real h = (c1.r + s * c2.r) / sqrt(g);\n if (eq(1 - h * h, 0)) {\n ret.emplace_back(c1.p + u * c1.r, c1.p + (u + v) * c1.r);\n } else if (1 - h * h > 0) {\n Point uu = u * h, vv = v * sqrt(1 - h * h);\n ret.emplace_back(c1.p + (uu + vv) * c1.r, c2.p - (uu + vv) * c2.r * s);\n ret.emplace_back(c1.p + (uu - vv) * c1.r, c2.p - (uu - vv) * c2.r * s);\n }\n }\n return ret;\n}\n\n// 凸性判定\nbool is_convex(const Polygon &p) {\n int n = (int)p.size();\n for (int i = 0; i < n; i++) {\n if (ccw(p[(i + n - 1) % n], p[i], p[(i + 1) % n]) == -1) return false;\n }\n return true;\n}\n\n// 凸包\nPolygon convex_hull(Polygon &p) {\n int n = (int)p.size(), k = 0;\n if (n <= 2) return p;\n sort(p.begin(), p.end());\n vector<Point> ch(2 * n);\n for (int i = 0; i < n; ch[k++] = p[i++]) {\n while (k >= 2 && cross(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1]) < EPS) --k;\n }\n for (int i = n - 2, t = k + 1; i >= 0; ch[k++] = p[i--]) {\n while (k >= t && cross(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1]) < EPS) --k;\n }\n ch.resize(k - 1);\n return ch;\n}\n\n// 多角形と点の包含判定\nenum { OUT, ON, IN };\n\nint contains(const Polygon &Q, const Point &p) {\n bool in = false;\n for (int i = 0; i < Q.size(); i++) {\n Point a = Q[i] - p, b = Q[(i + 1) % Q.size()] - p;\n if (a.imag() > b.imag()) swap(a, b);\n if (a.imag() <= 0 && 0 < b.imag() && cross(a, b) < 0) in = !in;\n if (cross(a, b) == 0 && dot(a, b) <= 0) return ON;\n }\n return in ? IN : OUT;\n}\n\n// 線分の重複除去\nvoid merge_segments(vector<Segment> &segs) {\n auto merge_if_able = [](Segment &s1, const Segment &s2) {\n if (abs(cross(s1.b - s1.a, s2.b - s2.a)) > EPS) return false;\n if (ccw(s1.a, s2.a, s1.b) == 1 || ccw(s1.a, s2.a, s1.b) == -1) return false;\n if (ccw(s1.a, s1.b, s2.a) == -2 || ccw(s2.a, s2.b, s1.a) == -2) return false;\n s1 = Segment(min(s1.a, s2.a), max(s1.b, s2.b));\n return true;\n };\n\n for (int i = 0; i < segs.size(); i++) {\n if (segs[i].b < segs[i].a) swap(segs[i].a, segs[i].b);\n }\n for (int i = 0; i < segs.size(); i++) {\n for (int j = i + 1; j < segs.size(); j++) {\n if (merge_if_able(segs[i], segs[j])) {\n segs[j--] = segs.back(), segs.pop_back();\n }\n }\n }\n}\n\n// 線分アレンジメント\n// 任意の2線分の交点を頂点としたグラフを構築する\nvector<vector<int>> segment_arrangement(vector<Segment> &segs, vector<Point> &ps) {\n vector<vector<int>> g;\n int N = (int)segs.size();\n for (int i = 0; i < N; i++) {\n ps.emplace_back(segs[i].a);\n ps.emplace_back(segs[i].b);\n for (int j = i + 1; j < N; j++) {\n const Point p1 = segs[i].b - segs[i].a;\n const Point p2 = segs[j].b - segs[j].a;\n if (cross(p1, p2) == 0) continue;\n if (intersect(segs[i], segs[j])) {\n ps.emplace_back(crosspoint(segs[i], segs[j]));\n }\n }\n }\n sort(begin(ps), end(ps));\n ps.erase(unique(begin(ps), end(ps)), end(ps));\n\n int M = (int)ps.size();\n g.resize(M);\n for (int i = 0; i < N; i++) {\n vector<int> vec;\n for (int j = 0; j < M; j++) {\n if (intersect(segs[i], ps[j])) {\n vec.emplace_back(j);\n }\n }\n for (int j = 1; j < vec.size(); j++) {\n g[vec[j - 1]].push_back(vec[j]);\n g[vec[j]].push_back(vec[j - 1]);\n }\n }\n return (g);\n}\n\n// 凸多角形の切断\n// 直線 l.a-l.b で切断しその左側にできる凸多角形を返す\nPolygon convex_cut(const Polygon &U, Line l) {\n Polygon ret;\n for (int i = 0; i < U.size(); i++) {\n Point now = U[i], nxt = U[(i + 1) % U.size()];\n if (ccw(l.a, l.b, now) != -1) ret.push_back(now);\n if (ccw(l.a, l.b, now) * ccw(l.a, l.b, nxt) < 0) {\n ret.push_back(crosspoint(Line(now, nxt), l));\n }\n }\n return (ret);\n}\n\n// 多角形の面積\nReal area(const Polygon &p) {\n Real A = 0;\n for (int i = 0; i < p.size(); ++i) {\n A += cross(p[i], p[(i + 1) % p.size()]);\n }\n return A * 0.5;\n}\n\n// 円と多角形の共通部分の面積\nReal area(const Polygon &p, const Circle &c) {\n if (p.size() < 3) return 0.0;\n function<Real(Circle, Point, Point)> cross_area = [&](const Circle &c, const Point &a,\n const Point &b) {\n Point va = c.p - a, vb = c.p - b;\n Real f = cross(va, vb), ret = 0.0;\n if (eq(f, 0.0)) return ret;\n if (max(abs(va), abs(vb)) < c.r + EPS) return f;\n if (distance(Segment(a, b), c.p) > c.r - EPS) return c.r * c.r * arg(vb * conj(va));\n auto u = crosspoint(c, Segment(a, b));\n vector<Point> tot{a, u.first, u.second, b};\n for (int i = 0; i + 1 < tot.size(); i++) {\n ret += cross_area(c, tot[i], tot[i + 1]);\n }\n return ret;\n };\n Real A = 0;\n for (int i = 0; i < p.size(); i++) {\n A += cross_area(c, p[i], p[(i + 1) % p.size()]);\n }\n return A;\n}\n\n// 凸多角形の直径(最遠頂点対間距離)\nReal convex_diameter(const Polygon &p) {\n int N = (int)p.size();\n int is = 0, js = 0;\n for (int i = 1; i < N; i++) {\n if (p[i].imag() > p[is].imag()) is = i;\n if (p[i].imag() < p[js].imag()) js = i;\n }\n Real maxdis = norm(p[is] - p[js]);\n\n int maxi, maxj, i, j;\n i = maxi = is;\n j = maxj = js;\n do {\n if (cross(p[(i + 1) % N] - p[i], p[(j + 1) % N] - p[j]) >= 0) {\n j = (j + 1) % N;\n } else {\n i = (i + 1) % N;\n }\n if (norm(p[i] - p[j]) > maxdis) {\n maxdis = norm(p[i] - p[j]);\n maxi = i;\n maxj = j;\n }\n } while (i != is || j != js);\n return sqrt(maxdis);\n}\n\n// 最近点対\nReal closest_pair(Points ps) {\n if (ps.size() <= 1) throw(0);\n sort(begin(ps), end(ps));\n\n auto compare_y = [&](const Point &a, const Point &b) { return imag(a) < imag(b); };\n vector<Point> beet(ps.size());\n const Real INF = 1e18;\n\n function<Real(int, int)> rec = [&](int left, int right) {\n if (right - left <= 1) return INF;\n int mid = (left + right) >> 1;\n auto x = real(ps[mid]);\n auto ret = min(rec(left, mid), rec(mid, right));\n inplace_merge(begin(ps) + left, begin(ps) + mid, begin(ps) + right, compare_y);\n int ptr = 0;\n for (int i = left; i < right; i++) {\n if (abs(real(ps[i]) - x) >= ret) continue;\n for (int j = 0; j < ptr; j++) {\n auto luz = ps[i] - beet[ptr - j - 1];\n if (imag(luz) >= ret) break;\n ret = min(ret, abs(luz));\n }\n beet[ptr++] = ps[i];\n }\n return ret;\n };\n return rec(0, (int)ps.size());\n}\n\n// 平面グラフを多角形に分割する (基本的に反時計回り、外平面のみ時計回り)\n// graph は無向グラフを想定 (u-v <=> v-u)。変なグラフを入れると壊れるはず\nvector<vector<int>> decompose_to_cycle(const vector<vector<int>> &graph, const vector<Point> &pos) {\n assert(graph.size() == pos.size());\n int n = graph.size();\n int m = 0;\n map<array<int, 2>, int> mp;\n vector<array<int, 2>> edge;\n for (int i = 0; i < n; ++i) {\n for (auto ni : graph[i]) {\n mp[{i, ni}] = m++;\n edge.push_back({i, ni});\n }\n }\n \n vector<int> nex(m, -1);\n for (int i = 0; i < n; ++i) {\n if (graph[i].empty()) continue;\n \n vector<pair<long double, int>> adj;\n for (int ni : graph[i]) {\n Point diff = pos[ni] - pos[i];\n assert(pos[ni] != pos[i]);\n adj.push_back({arg(diff), ni});\n }\n \n sort(adj.begin(), adj.end());\n int siz = adj.size();\n adj.emplace_back(adj[0]);\n adj[siz].first += 2 * PI;\n \n for (int j = 0; j < siz; ++j) {\n auto [arg0, to] = adj[j];\n auto [arg1, from] = adj[j + 1];\n int ein = mp[{from, i}];\n int eout = mp[{i, to}];\n \n nex[ein] = eout;\n }\n }\n \n vector<vector<int>> ret;\n vector<bool> used(m, false);\n for (int i = 0; i < m; ++i) {\n if (used[i]) continue;\n \n vector<int> tmp;\n int now = i;\n while (!used[now]) {\n used[now] = true;\n tmp.emplace_back(edge[now][0]);\n now = nex[now];\n }\n ret.emplace_back(tmp);\n }\n \n return ret;\n}\n\n/*-- main --*/\n\nbool is_end = false;\n\nvoid solve()\n{\n int N, Q; cin >> N >> Q;\n if (N == 0 && Q == 0)\n {\n is_end = true;\n return;\n }\n vector<Circle> circles(N);\n vector<Point> centers(N);\n for (int i = 0; i < N; ++i)\n {\n Real x, y, r; cin >> x >> y >> r;\n centers[i] = Point(x, y);\n circles[i] = Circle(Point(x, y), r);\n }\n vector<array<Point, 2>> query(Q);\n for (int i = 0; i < Q; ++i)\n {\n int px, py, qx, qy; cin >> px >> py >> qx >> qy;\n query[i][0] = Point(px, py);\n query[i][1] = Point(qx, qy);\n }\n \n \n vector<vector<int>> graph(N);\n for (int i = 0; i < N; ++i)\n {\n for (int j = 0; j < N; ++j)\n {\n if (i == j) continue;\n if (intersect(circles[i], circles[j]) == 2) graph[i].emplace_back(j);\n }\n }\n vector<vector<int>> tmp = decompose_to_cycle(graph, centers);\n vector<Polygon> polygons(tmp.size());\n for (int i = 0; i < tmp.size(); ++i)\n {\n for (auto v : tmp[i])\n {\n polygons[i].emplace_back(centers[v]);\n }\n }\n \n for (int i = 0; i < Q; ++i)\n {\n auto [p, q] = query[i];\n \n vector<bool> isinp(N, false), isinq(N, false);\n int cntp = 0, cntq = 0;\n for (int j = 0; j < N; ++j)\n {\n Point center = circles[j].p;\n Real radius = circles[j].r;\n if (abs(center - p) < radius) isinp[j] = true, cntp++;\n if (abs(center - q) < radius) isinq[j] = true, cntq++;\n }\n \n bool flg = false;\n if (isinp != isinq) flg = false;\n else\n {\n flg = true;\n \n if (cntp == 0)\n {\n int siz = polygons.size();\n for (auto poly : polygons)\n {\n auto pp = contains(poly, p);\n auto qq = contains(poly, q);\n if (pp != qq) flg = false;\n }\n }\n }\n \n cout << (flg ? \"YES\" : \"NO\") << \" \\n\"[i+1 == Q];\n }\n \n return;\n}\n\nint main()\n{\n while (!is_end)\n {\n solve();\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3672, "score_of_the_acc": -0.0868, "final_rank": 11 }, { "submission_id": "aoj_1198_9035480", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\n#define rep(i, a, b) for(ll i = a; i < b; ++i)\n#define rrep(i, a, b) for(ll i = a; i >= b; --i)\nconstexpr ll inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\nvector<int> cycle_detection(const vector<vector<int>>& g) {\n int n = g.size();\n vector<int> r(n, -1), p(n, -1), d(n, 0);\n auto dfs = [&](auto& dfs, int r2, int cur) -> void {\n r[cur] = r2;\n for(int to : g[cur]) {\n if(r[to] == -1) {\n d[to] = d[cur] + 1;\n p[to] = cur;\n dfs(dfs, r2, to);\n }\n }\n };\n rep(i, 0, n) {\n if(p[i] == -1) {\n dfs(dfs, i, i);\n }\n }\n rep(i, 0, n) {\n for(int j : g[i]) {\n if(r[i] == r[j] and d[j] - d[i] > 1) {\n vector<int> cycle;\n for(int v = j; v != i; v = p[v]) {\n cycle.push_back(v);\n }\n cycle.push_back(i);\n return cycle;\n }\n }\n }\n return {};\n}\nusing Real = long double;\nconst Real EPS = 1e-6, PI = acos(Real(-1.0));\nint sign(const Real& r) {\n if(r <= -EPS) return -1;\n if(r >= +EPS) return +1;\n return 0;\n}\nbool eq(const Real& a, const Real& b) {\n return sign(a - b) == 0;\n}\nusing Point = complex<Real>;\nistream& operator>>(istream& is, Point& p) {\n Real a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n}\nReal dot(const Point& p1, const Point& p2) {\n return (conj(p1) * p2).real();\n}\nReal cross(const Point& p1, const Point& p2) {\n return (conj(p1) * p2).imag();\n}\nint ccw(const Point& a, Point b, Point c) {\n b -= a;\n c -= a;\n if(sign(cross(b, c)) == 1) return 1;\n if(sign(cross(b, c)) == -1) return -1;\n if(sign(dot(b, c)) == -1) return +2;\n if(norm(b) < norm(c)) return -2;\n return 0;\n}\nstruct Line {\n Point a, b;\n Line() = default;\n Line(const Point& a, const Point& b)\n : a(a), b(b) {}\n};\nusing Segment = Line;\nbool is_intersect_ss(const Segment& s1, const Segment& s2) {\n if(ccw(s1.a, s1.b, s2.a) * ccw(s1.a, s1.b, s2.b) > 0) return false;\n return ccw(s2.a, s2.b, s1.a) * ccw(s2.a, s2.b, s1.b) <= 0;\n}\nbool in_polygon(const vector<Point>& ps, const Point& p) {\n int n = ps.size();\n Segment seg = Segment(p, Point(p.real() + 1000000, p.imag() + 58));\n int cnt = 0;\n rep(i, 0, n) {\n Point dir = ps[(i + 1) % n] - ps[i];\n if(is_intersect_ss(seg, Segment(ps[i], ps[(i + 1) % n] - EPS * dir))) {\n cnt++;\n }\n }\n return cnt % 2 == 1;\n}\nstruct Circle {\n Point p;\n Real r;\n Circle() = default;\n Circle(const Point& p, const Real& r)\n : p(p), r(r) {}\n};\nint is_intersect_cc(Circle c1, Circle c2) {\n if(c1.r < c2.r) swap(c1, c2);\n Real d = abs(c1.p - c2.p);\n int a = sign(d - c1.r - c2.r);\n if(a >= 0) return a + 3;\n return sign(d - c1.r + c2.r) + 1;\n}\nbool is_contain_cp(Circle c, Point p) {\n return abs(p - c.p) < c.r;\n}\nint main(void) {\n while(1) {\n int n, m;\n cin >> n >> m;\n if(n == 0 and m == 0) break;\n vector<Circle> c(n);\n rep(i, 0, n) {\n cin >> c[i].p >> c[i].r;\n }\n rep(tc, 0, m) {\n Point p, q;\n cin >> p >> q;\n set<int> st1, st2;\n rep(i, 0, n) {\n if(is_contain_cp(c[i], p)) {\n st1.insert(i);\n }\n if(is_contain_cp(c[i], q)) {\n st2.insert(i);\n }\n }\n if(!st1.empty() or !st2.empty()) {\n if(st1 == st2) {\n cout << \"YES\";\n } else {\n cout << \"NO\";\n }\n if(tc + 1 < m) cout << ' ';\n continue;\n }\n vector<vector<int>> g(n);\n rep(i, 0, n) {\n rep(j, 0, i) {\n if(is_intersect_cc(c[i], c[j]) == 2) {\n g[i].push_back(j);\n g[j].push_back(i);\n }\n }\n }\n bool ans = true;\n while(1) {\n vector<int> cycle = cycle_detection(g);\n if(cycle.empty()) break;\n vector<Point> ps;\n rep(i, 0, (int)cycle.size()) {\n ps.push_back(c[cycle[i]].p);\n }\n if(in_polygon(ps, p) != in_polygon(ps, q)) {\n ans = false;\n break;\n }\n rep(i, 0, (int)g[cycle[0]].size()) {\n if(g[cycle[0]][i] == cycle[1]) {\n g[cycle[0]].erase(g[cycle[0]].begin() + i);\n break;\n }\n }\n rep(i, 0, (int)g[cycle[1]].size()) {\n if(g[cycle[1]][i] == cycle[0]) {\n g[cycle[1]].erase(g[cycle[1]].begin() + i);\n break;\n }\n }\n }\n if(ans) {\n cout << \"YES\";\n } else {\n cout << \"NO\";\n }\n if(tc < m - 1) cout << ' ';\n }\n cout << '\\n';\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3480, "score_of_the_acc": -0.0648, "final_rank": 9 }, { "submission_id": "aoj_1198_8006463", "code_snippet": "#line 1 \"test/geometry/aoj1198.test.cpp\"\n#define PROBLEM \"https://onlinejudge.u-aizu.ac.jp/problems/1198\"\n\n#line 2 \"template/template.hpp\"\n\n#include<bits/stdc++.h>\n\n#define rep(i,n) for (int i = 0; i < (int)(n); i++)\n#define reb(i,n) for (int i = (int)(n-1); i >= 0; i--)\n#define all(v) v.begin(),v.end()\n\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n\nusing namespace std;\n\nnamespace noya2{\n\n/* ~ (. _________ . /) */\n\n}\n\nusing namespace noya2;\n\ntemplate <typename T> bool chmin(T &a, const T &b) {\n if (a <= b) return false;\n a = b;\n return true;\n}\ntemplate <typename T> bool chmax(T &a, const T &b) {\n if (a >= b) return false;\n a = b;\n return true;\n}\n\ntemplate<class T>istream &operator>>(istream &is, vector<T> &v){\n for (auto &e : v) is >> e;\n return is;\n}\n\nvoid fast_io(){\n cin.tie(0); ios::sync_with_stdio(0); cout << fixed << setprecision(15);\n}\n\nconst int iinf = 1'000'000'007;\nconst ll linf = 2e18;\n#line 4 \"test/geometry/aoj1198.test.cpp\"\n\n#line 2 \"geometry/partition_by_circle.hpp\"\n\n#line 2 \"geometry/base_ld.hpp\"\n\n#line 4 \"geometry/base_ld.hpp\"\n\nnamespace noya2 {\n\nusing vec = complex<ld>;\n\nconst ld PI = acos(-1);\n\nvoid ldout(int len = 20) {\n cout << fixed << setprecision(len);\n}\n\nint sgn(ld a, const ld eps = 1e-7) {\n return (a < -eps) ? -1 : (a > eps) ? 1 : 0;\n}\n\nbool same_vec(vec a, vec b) {\n a -= b;\n return sgn(a.real()) == 0 && sgn(a.imag()) == 0;\n}\n\nld dot(const vec &a, const vec &b) {\n return (conj(a) * b).real();\n}\n\nld cross(const vec &a, const vec &b) {\n return (conj(a) * b).imag();\n}\n\nint isp(const vec &a, const vec &b, const vec &c) {\n int cross_sgn = sgn(cross(b - a, c - a));\n if (cross_sgn == 0) {\n if (sgn(dot(b - a, c - a)) < 0) return -2;\n if (sgn(dot(a - b, c - b)) < 0) return 2;\n }\n return cross_sgn;\n}\n\nvec rot90(const vec &a) {\n return {-a.imag(), a.real()};\n}\n\nvec rot(const vec &a, ld rad) {\n return a * vec(cosl(rad), sinl(rad));\n}\n\n\n} // namespace lib\n#line 2 \"data_structure/dsu.hpp\"\n\n#line 4 \"data_structure/dsu.hpp\"\n\nnamespace noya2{\n\nstruct dsu {\n public:\n dsu() : _n(0) {}\n dsu(int n) : _n(n), parent_or_size(n, -1) {}\n\n int merge(int a, int b) {\n assert(0 <= a && a < _n);\n assert(0 <= b && b < _n);\n int x = leader(a), y = leader(b);\n if (x == y) return x;\n if (-parent_or_size[x] < -parent_or_size[y]) std::swap(x, y);\n parent_or_size[x] += parent_or_size[y];\n parent_or_size[y] = x;\n return x;\n }\n\n bool same(int a, int b) {\n assert(0 <= a && a < _n);\n assert(0 <= b && b < _n);\n return leader(a) == leader(b);\n }\n\n int leader(int a) {\n assert(0 <= a && a < _n);\n if (parent_or_size[a] < 0) return a;\n return parent_or_size[a] = leader(parent_or_size[a]);\n }\n\n int size(int a) {\n assert(0 <= a && a < _n);\n return -parent_or_size[leader(a)];\n }\n\n std::vector<std::vector<int>> groups() {\n std::vector<int> leader_buf(_n), group_size(_n);\n for (int i = 0; i < _n; i++) {\n leader_buf[i] = leader(i);\n group_size[leader_buf[i]]++;\n }\n std::vector<std::vector<int>> result(_n);\n for (int i = 0; i < _n; i++) {\n result[i].reserve(group_size[i]);\n }\n for (int i = 0; i < _n; i++) {\n result[leader_buf[i]].push_back(i);\n }\n result.erase(\n std::remove_if(result.begin(), result.end(),\n [&](const std::vector<int>& v) { return v.empty(); }),\n result.end());\n return result;\n }\n\n private:\n int _n;\n // root node: -1 * component size\n // otherwise: parent\n std::vector<int> parent_or_size;\n};\n\n} // namespace noya2\n#line 6 \"geometry/partition_by_circle.hpp\"\n\nnamespace noya2{\n\nusing vec = complex<ld>;\n\nstruct circle {\n vec c;\n ld r;\n};\n\n// c1 != c2\nvector<ld> cross_point_x(const circle &c1, const circle &c2){\n assert(sgn(abs(c1.r - c2.r)) != 0 || sgn(abs(c1.c - c2.c)) != 0);\n ld d = abs(c1.c - c2.c);\n // 円が離れすぎている\n if (sgn(d - c1.r - c2.r) > 0) return {};\n // 円が近すぎる\n if (sgn(abs(c1.r - c2.r) - d) > 0) return {};\n // 外接している\n if (sgn(d - c1.r - c2.r) == 0){\n return {(c1.r*c2.c.real() + c2.r*c1.c.real()) / (c1.r + c2.r)};\n }\n // 内接している\n if (sgn(abs(c1.r - c2.r) - d) == 0){\n return {(c1.r * c2.c.real() - c2.r * c1.c.real()) / (c1.r - c2.r)};\n }\n // 2 点を共有する\n ld e = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n vec p = c1.c + (c2.c - c1.c) * e / d;\n vec v((c1.c - c2.c).imag(),(c2.c - c1.c).real());\n v *= sqrtl(max(c1.r * c1.r - e * e, ld(0))) / abs(v);\n return {(p+v).real(),(p-v).real()};\n}\n\nvector<ld> cross_point_y(const circle &c, const ld &x){\n int cond = sgn(abs(c.c.real() - x) - c.r); \n if (cond > 0) return {};\n if (cond == 0) return {c.c.imag()};\n ld ydiff = sqrtl(max(c.r*c.r - (x - c.c.real()) * (x - c.c.real()),ld(0)));\n return {c.c.imag()+ydiff,c.c.imag()-ydiff};\n}\n\nstruct Partition_by_Circles {\n vector<circle> a;\n // 同じ円は与えられない\n void add_circle(circle c){\n // x 座標で区切る場所が重ならないように 1 rad 回転しておく\n c.c = rot(c.c,1);\n a.emplace_back(c);\n }\n ld coordinate_width(){\n ld res = 0.0;\n for (auto &c : a){\n chmax(res,abs(c.c)+c.r);\n }\n return res;\n }\n vector<ld> x_coordinates(){\n vector<ld> xs;\n for (auto &c : a){\n xs.emplace_back(c.c.real()-c.r);\n xs.emplace_back(c.c.real()+c.r);\n }\n int siza = a.size();\n for (int i = 0; i < siza-1; i++) for (int j = i+1; j < siza; j++){\n for (auto x : cross_point_x(a[i],a[j])){\n bool yet = true;\n for (auto testx : xs){\n if (sgn(abs(x - testx)) == 0){\n yet = false;\n break;\n }\n }\n if (yet) xs.emplace_back(x);\n }\n }\n sort(all(xs));\n return xs;\n }\n using ylr = tuple<ld,int,int>;\n vector<ylr> y_coordinates(ld x){\n vector<ylr> ys;\n auto add = [&](ld y, int l, int r){\n bool yet = true;\n for (auto &[testy, testl, testr] : ys){\n if (sgn(abs(y - testy)) == 0){\n yet = false;\n testl += l;\n testr += r;\n break;\n }\n }\n if (yet) ys.push_back({y,l,r});\n };\n for (auto &c : a){\n auto vecy = cross_point_y(c,x);\n if (vecy.empty()) continue;\n if ((int)(vecy.size()) == 2){\n for (auto y : vecy) add(y,1,1);\n }\n else {\n if (c.c.real() < x){\n add(vecy[0],2,0);\n }\n else {\n add(vecy[0],0,2);\n }\n }\n }\n sort(all(ys),[&](ylr lhs, ylr rhs){\n return get<0>(lhs) < get<0>(rhs);\n });\n return ys;\n }\n dsu d;\n vector<ld> xs;\n vector<int> lower_idx;\n map<int,int> mp;\n vector<vector<int>> build_graph(ld max_width = 0){\n // 大きな円で全体を囲ってしまう\n if (sgn(max_width) == 0) max_width = coordinate_width()*2;\n a.push_back({vec(0,0),max_width});\n // x 座標の列挙\n xs = x_coordinates();\n // 各 x について y 座標の列挙\n vector<vector<ylr>> yss; yss.reserve(xs.size());\n for (auto &x : xs) yss.push_back(y_coordinates(x));\n // x で切って領域を舐める\n int idx = 0;\n vector<pair<int,int>> es, merge;\n vector<int> cur;\n for (int itr = 0; itr < (int)(xs.size())-1; itr++){\n lower_idx.emplace_back(idx);\n vector<int> lid, rid;\n for (int l = 0; l < (int)(yss[itr].size()); l++){\n for (int t = 0; t < get<2>(yss[itr][l]); t++){\n lid.emplace_back(l);\n }\n }\n for (int r = 0; r < (int)(yss[itr+1].size()); r++){\n for (int t = 0; t < get<1>(yss[itr+1][r]); t++){\n rid.emplace_back(r);\n }\n }\n assert(lid.size() == rid.size());\n int pre = 0;\n vector<int> nxt;\n for (int i = 0; i < (int)(lid.size())-1; i++){\n for (int t = 0; t < rid[i+1]-rid[i]; t++){\n nxt.emplace_back(idx);\n }\n if (i != 0){\n es.emplace_back(idx-1,idx);\n }\n if (lid[i+1] - lid[i] != 0){\n merge.emplace_back(cur[pre++],idx);\n }\n if (lid[i+1] - lid[i] == 2){\n merge.emplace_back(cur[pre++],idx);\n }\n idx++;\n }\n swap(cur,nxt);\n }\n // グラフを構築\n d = dsu(idx);\n for (auto &[u, v] : merge) d.merge(u,v);\n set<int> st;\n for (int i = 0; i < idx; i++) st.insert(d.leader(i));\n int vid = 0;\n for (auto v : st) mp[v] = vid++;\n vector<vector<int>> graph(vid);\n for (auto [u, v] : es){\n u = mp[d.leader(u)];\n v = mp[d.leader(v)];\n graph[u].emplace_back(v);\n graph[v].emplace_back(u);\n }\n return graph;\n }\n int get_area_idx(vec p){\n p = rot(p,1);\n int xid = int(lower_bound(all(xs),p.real()) - xs.begin()) - 1;\n vector<ld> ys;\n for (auto &[y, l, r] : y_coordinates(p.real())) ys.emplace_back(y);\n int yid = int(lower_bound(all(ys),p.imag()) - ys.begin()) - 1;\n return mp[d.leader(lower_idx[xid] + yid)];\n }\n};\n\n} //namespace noya2\n#line 6 \"test/geometry/aoj1198.test.cpp\"\n\nint main(){\n while (true){\n int n, m; cin >> n >> m;\n if (n == 0 && m == 0) break;\n Partition_by_Circles pc;\n while (n--){\n ld x, y, r; cin >> x >> y >> r;\n pc.add_circle(circle({vec(x,y),r}));\n }\n pc.build_graph(100000);\n string ans = \"\";\n while (m--){\n ld px, py, qx, qy; cin >> px >> py >> qx >> qy;\n int ip = pc.get_area_idx(vec(px,py));\n int iq = pc.get_area_idx(vec(qx,qy));\n ans += (ip == iq ? \"YES\" : \"NO\");\n ans += (m == 0 ? '\\n' : ' ');\n }\n cout << ans;\n }\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 4640, "score_of_the_acc": -0.3014, "final_rank": 16 }, { "submission_id": "aoj_1198_7993928", "code_snippet": "#line 1 \"test/geometry/aoj1198.test.cpp\"\n#define PROBLEM \"https://onlinejudge.u-aizu.ac.jp/problems/1198\"\n\n#line 2 \"template/template.hpp\"\n\n#include<bits/stdc++.h>\n\n#define rep(i,n) for (int i = 0; i < (int)(n); i++)\n#define reb(i,n) for (int i = (int)(n-1); i >= 0; i--)\n#define all(v) v.begin(),v.end()\n\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n\nusing namespace std;\n\nnamespace noya2{\n\n/* ~ (. _________ . /) */\n\n}\n\nusing namespace noya2;\n\ntemplate <typename T> bool chmin(T &a, const T &b) {\n if (a <= b) return false;\n a = b;\n return true;\n}\ntemplate <typename T> bool chmax(T &a, const T &b) {\n if (a >= b) return false;\n a = b;\n return true;\n}\n\ntemplate<class T>istream &operator>>(istream &is, vector<T> &v){\n for (auto &e : v) is >> e;\n return is;\n}\n\nvoid fast_io(){\n cin.tie(0); ios::sync_with_stdio(0); cout << fixed << setprecision(15);\n}\n\nconst int iinf = 1'000'000'007;\nconst ll linf = 2e18;\n#line 4 \"test/geometry/aoj1198.test.cpp\"\n\n#line 2 \"geometry/partition_by_circle.hpp\"\n\n#line 2 \"geometry/base_ld.hpp\"\n\n#line 4 \"geometry/base_ld.hpp\"\n\nnamespace noya2 {\n\nusing vec = complex<ld>;\n\nconst ld PI = acos(-1);\n\nvoid ldout(int len = 20) {\n cout << fixed << setprecision(len);\n}\n\nint sgn(ld a, const ld eps = 1e-7) {\n return (a < -eps) ? -1 : (a > eps) ? 1 : 0;\n}\n\nbool same_vec(vec a, vec b) {\n a -= b;\n return sgn(a.real()) == 0 && sgn(a.imag()) == 0;\n}\n\nld dot(const vec &a, const vec &b) {\n return (conj(a) * b).real();\n}\n\nld cross(const vec &a, const vec &b) {\n return (conj(a) * b).imag();\n}\n\nint isp(const vec &a, const vec &b, const vec &c) {\n int cross_sgn = sgn(cross(b - a, c - a));\n if (cross_sgn == 0) {\n if (sgn(dot(b - a, c - a)) < 0) return -2;\n if (sgn(dot(a - b, c - b)) < 0) return 2;\n }\n return cross_sgn;\n}\n\nvec rot90(const vec &a) {\n return {-a.imag(), a.real()};\n}\n\nvec rot(const vec &a, ld rad) {\n return a * vec(cosl(rad), sinl(rad));\n}\n\nbool comp_for_argument_sort(const vec &lhs, const vec &rhs) {\n // if (abs(arg(lhs)-arg(rhs)) < eps) return false; // need ?\n return arg(lhs) < arg(rhs);\n}\n\n} // namespace lib\n#line 5 \"geometry/partition_by_circle.hpp\"\n\nnamespace noya2{\n\nstruct dsu {\n dsu(int n = 0) : _n(n), pos(n, -1) {}\n\n int merge(int a, int b) {\n int x = leader(a), y = leader(b);\n if (x == y) return x;\n if (-pos[x] < -pos[y]) swap(x, y);\n pos[x] += pos[y];\n pos[y] = x;\n return x;\n }\n\n bool same(int a, int b) {\n return leader(a) == leader(b);\n }\n\n int leader(int a) {\n if (pos[a] < 0) return a;\n return pos[a] = leader(pos[a]);\n }\n private:\n int _n;\n vector<int> pos;\n};\n\nusing vec = complex<ld>;\n\nstruct circle {\n vec c;\n ld r;\n};\n\n// c1 != c2\nvector<ld> cross_point_x(const circle &c1, const circle &c2){\n assert(sgn(abs(c1.r - c2.r)) != 0 || sgn(abs(c1.c - c2.c)) != 0);\n ld d = abs(c1.c - c2.c);\n // 円が離れすぎている\n if (sgn(d - c1.r - c2.r) > 0) return {};\n // 円が近すぎる\n if (sgn(abs(c1.r - c2.r) - d) > 0) return {};\n // 外接している\n if (sgn(d - c1.r - c2.r) == 0){\n return {(c1.r*c2.c.real() + c2.r*c1.c.real()) / (c1.r + c2.r)};\n }\n // 内接している\n if (sgn(abs(c1.r - c2.r) - d) == 0){\n return {(c1.r * c2.c.real() - c2.r * c1.c.real()) / (c1.r - c2.r)};\n }\n // 2 点を共有する\n ld e = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n vec p = c1.c + (c2.c - c1.c) * e / d;\n vec v((c1.c - c2.c).imag(),(c2.c - c1.c).real());\n v *= sqrtl(max(c1.r * c1.r - e * e, ld(0))) / abs(v);\n return {(p+v).real(),(p-v).real()};\n}\n\nvector<ld> cross_point_y(const circle &c, const ld &x){\n int cond = sgn(abs(c.c.real() - x) - c.r); \n if (cond > 0) return {};\n if (cond == 0) return {c.c.imag()};\n ld ydiff = sqrtl(max(c.r*c.r - (x - c.c.real()) * (x - c.c.real()),ld(0)));\n return {c.c.imag()+ydiff,c.c.imag()-ydiff};\n}\n\nstruct Partition_by_Circles {\n vector<circle> a;\n // 同じ円は与えられない\n void add_circle(circle c){\n // x 座標で区切る場所が重ならないように 1 rad 回転しておく\n c.c = rot(c.c,1);\n a.emplace_back(c);\n }\n ld coordinate_width(){\n ld res = 0.0;\n for (auto &c : a){\n chmax(res,abs(c.c)+c.r);\n }\n return res;\n }\n vector<ld> x_coordinates(){\n vector<ld> xs;\n for (auto &c : a){\n xs.emplace_back(c.c.real()-c.r);\n xs.emplace_back(c.c.real()+c.r);\n }\n int siza = a.size();\n for (int i = 0; i < siza-1; i++) for (int j = i+1; j < siza; j++){\n for (auto x : cross_point_x(a[i],a[j])){\n bool yet = true;\n for (auto testx : xs){\n if (sgn(abs(x - testx)) == 0){\n yet = false;\n break;\n }\n }\n if (yet) xs.emplace_back(x);\n }\n }\n sort(all(xs));\n return xs;\n }\n using ylr = tuple<ld,int,int>;\n vector<ylr> y_coordinates(ld x){\n vector<ylr> ys;\n auto add = [&](ld y, int l, int r){\n bool yet = true;\n for (auto &[testy, testl, testr] : ys){\n if (sgn(abs(y - testy)) == 0){\n yet = false;\n testl += l;\n testr += r;\n break;\n }\n }\n if (yet) ys.push_back({y,l,r});\n };\n for (auto &c : a){\n auto vecy = cross_point_y(c,x);\n if (vecy.empty()) continue;\n if ((int)(vecy.size()) == 2){\n for (auto y : vecy) add(y,1,1);\n }\n else {\n if (c.c.real() < x){\n add(vecy[0],2,0);\n }\n else {\n add(vecy[0],0,2);\n }\n }\n }\n sort(all(ys),[&](ylr lhs, ylr rhs){\n return get<0>(lhs) < get<0>(rhs);\n });\n return ys;\n }\n dsu d;\n vector<ld> xs;\n vector<int> lower_idx;\n map<int,int> mp;\n vector<vector<int>> build_graph(){\n // 大きな円で全体を囲ってしまう\n a.push_back({vec(0,0),coordinate_width()*2});\n // x 座標の列挙\n xs = x_coordinates();\n // 各 x について y 座標の列挙\n vector<vector<ylr>> yss; yss.reserve(xs.size());\n for (auto &x : xs) yss.push_back(y_coordinates(x));\n // x で切って領域を舐める\n int idx = 0;\n vector<pair<int,int>> es, merge;\n vector<int> cur;\n for (int itr = 0; itr < (int)(xs.size())-1; itr++){\n lower_idx.emplace_back(idx);\n vector<int> lid, rid;\n for (int l = 0; l < (int)(yss[itr].size()); l++){\n for (int t = 0; t < get<2>(yss[itr][l]); t++){\n lid.emplace_back(l);\n }\n }\n for (int r = 0; r < (int)(yss[itr+1].size()); r++){\n for (int t = 0; t < get<1>(yss[itr+1][r]); t++){\n rid.emplace_back(r);\n }\n }\n assert(lid.size() == rid.size());\n int pre = 0;\n vector<int> nxt;\n for (int i = 0; i < (int)(lid.size())-1; i++){\n for (int t = 0; t < rid[i+1]-rid[i]; t++){\n nxt.emplace_back(idx);\n }\n if (i != 0){\n es.emplace_back(idx-1,idx);\n }\n if (lid[i+1] - lid[i] != 0){\n merge.emplace_back(cur[pre++],idx);\n }\n if (lid[i+1] - lid[i] == 2){\n merge.emplace_back(cur[pre++],idx);\n }\n idx++;\n }\n swap(cur,nxt);\n }\n // グラフを構築\n d = dsu(idx);\n for (auto &[u, v] : merge) d.merge(u,v);\n set<int> st;\n for (int i = 0; i < idx; i++) st.insert(d.leader(i));\n int vid = 0;\n for (auto v : st) mp[v] = vid++;\n vector<vector<int>> graph(vid);\n for (auto [u, v] : es){\n u = mp[d.leader(u)];\n v = mp[d.leader(v)];\n graph[u].emplace_back(v);\n graph[v].emplace_back(u);\n }\n return graph;\n }\n int get_area_idx(vec p){\n p = rot(p,1);\n int xid = int(lower_bound(all(xs),p.real()) - xs.begin()) - 1;\n vector<ld> ys;\n for (auto &[y, l, r] : y_coordinates(p.real())) ys.emplace_back(y);\n int yid = int(lower_bound(all(ys),p.imag()) - ys.begin()) - 1;\n return mp[d.leader(lower_idx[xid] + yid)];\n }\n};\n\n} //namespace noya2\n#line 6 \"test/geometry/aoj1198.test.cpp\"\n\nint main(){\n while (true){\n int n, m; cin >> n >> m;\n if (n == 0 && m == 0) break;\n Partition_by_Circles pc;\n while (n--){\n ld x, y, r; cin >> x >> y >> r;\n pc.add_circle(circle({vec(x,y),r}));\n }\n pc.build_graph();\n string ans = \"\";\n while (m--){\n ld px, py, qx, qy; cin >> px >> py >> qx >> qy;\n int ip = pc.get_area_idx(vec(px,py));\n int iq = pc.get_area_idx(vec(qx,qy));\n ans += (ip == iq ? \"YES\" : \"NO\");\n ans += (m == 0 ? '\\n' : ' ');\n }\n cout << ans;\n }\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 4724, "score_of_the_acc": -0.3171, "final_rank": 17 }, { "submission_id": "aoj_1198_7200612", "code_snippet": "#include <cmath>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nclass edge {\npublic:\n\tint to; bool vis;\n\tedge() : to(-1), vis(false) {}\n\tedge(int to_, bool vis_) : to(to_), vis(vis_) {}\n};\n\nint main() {\n\twhile (true) {\n\t\tint N, M;\n\t\tcin >> N >> M;\n\t\tif (N == 0 && M == 0) {\n\t\t\tbreak;\n\t\t}\n\t\tvector<int> IX(N), IY(N), IR(N);\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tcin >> IX[i] >> IY[i] >> IR[i];\n\t\t}\n\t\tauto sqr = [](int x) {\n\t\t\treturn x * x;\n\t\t};\n\t\tvector<bool> answers(M, true);\n\t\tfor (int id = 0; id < M; id++) {\n\t\t\tint PX, PY, QX, QY;\n\t\t\tcin >> PX >> PY >> QX >> QY;\n\t\t\tfor (int i = 0; i < N; i++) {\n\t\t\t\tif ((sqr(PX - IX[i]) + sqr(PY - IY[i]) < sqr(IR[i])) != (sqr(QX - IX[i]) + sqr(QY - IY[i]) < sqr(IR[i]))) {\n\t\t\t\t\tanswers[id] = false;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (answers[id]) {\n\t\t\t\t// step #1. find all necessary circles\n\t\t\t\tvector<int> X, Y, R;\n\t\t\t\tfor (int i = 0; i < N; i++) {\n\t\t\t\t\tif (sqr(PX - IX[i]) + sqr(PY - IY[i]) >= sqr(IR[i])) {\n\t\t\t\t\t\tX.push_back(IX[i]);\n\t\t\t\t\t\tY.push_back(IY[i]);\n\t\t\t\t\t\tR.push_back(IR[i]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tint K = X.size();\n\t\t\t\t\n\t\t\t\t// step #2. make graph\n\t\t\t\tvector<vector<edge> > G(K);\n\t\t\t\tfor (int i = 0; i < K; i++) {\n\t\t\t\t\tfor (int j = i + 1; j < K; j++) {\n\t\t\t\t\t\tint dist = sqr(X[j] - X[i]) + sqr(Y[j] - Y[i]);\n\t\t\t\t\t\tif (sqr(R[i] - R[j]) < dist && dist < sqr(R[i] + R[j])) {\n\t\t\t\t\t\t\tG[i].push_back(edge(j, false));\n\t\t\t\t\t\t\tG[j].push_back(edge(i, false));\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tfor (int i = 0; i < K; i++) {\n\t\t\t\t\tsort(G[i].begin(), G[i].end(), [&](const edge& ea, const edge& eb) {\n\t\t\t\t\t\treturn atan2(Y[ea.to] - Y[i], X[ea.to] - X[i]) < atan2(Y[eb.to] - Y[i], X[eb.to] - X[i]);\n\t\t\t\t\t});\n\t\t\t\t}\n\t\t\t\t\n\t\t\t\t// step #3. compute polygons\n\t\t\t\tvector<vector<int> > polygons;\n\t\t\t\tfor (int i = 0; i < K; i++) {\n\t\t\t\t\tfor (edge &e : G[i]) {\n\t\t\t\t\t\tif (e.vis == false) {\n\t\t\t\t\t\t\tvector<int> subpolygon;\n\t\t\t\t\t\t\tint pre = i, pos = e.to;\n\t\t\t\t\t\t\tdo {\n\t\t\t\t\t\t\t\tsubpolygon.push_back(pos);\n\t\t\t\t\t\t\t\tfor (int j = 0; j < int(G[pos].size()); j++) {\n\t\t\t\t\t\t\t\t\tif (G[pos][j].to == pre) {\n\t\t\t\t\t\t\t\t\t\tpre = pos;\n\t\t\t\t\t\t\t\t\t\tpos = G[pos][(j + 1) % G[pos].size()].to;\n\t\t\t\t\t\t\t\t\t\tG[pos][(j + 1) % G[pos].size()].vis = true;\n\t\t\t\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t} while(pos != e.to);\n\t\t\t\t\t\t\tpolygons.push_back(subpolygon);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\t\n\t\t\t\t// step #4. check if a point is inside polygon\n\t\t\t\tauto is_inside = [&](const vector<int>& poly, int x, int y) {\n\t\t\t\t\tint crosses = 0;\n\t\t\t\t\tfor (int i = 0; i < int(poly.size()); i++) {\n\t\t\t\t\t\tint xa = X[poly[i]], ya = Y[poly[i]];\n\t\t\t\t\t\tint xb = X[poly[(i + 1) % poly.size()]], yb = Y[poly[(i + 1) % poly.size()]];\n\t\t\t\t\t\tif (ya > yb) {\n\t\t\t\t\t\t\tswap(xa, xb);\n\t\t\t\t\t\t\tswap(ya, yb);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tif (ya <= y && y < yb && (xa - x) * (yb - y) - (xb - x) * (ya - y) >= 0) {\n\t\t\t\t\t\t\tcrosses += 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\treturn (crosses % 2 == 1);\n\t\t\t\t};\n\t\t\t\t\n\t\t\t\t// step #5. check for all polygons\n\t\t\t\tfor (vector<int> poly : polygons) {\n\t\t\t\t\tif (is_inside(poly, PX, PY) != is_inside(poly, QX, QY)) {\n\t\t\t\t\t\tanswers[id] = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int i = 0; i < M; i++) {\n\t\t\tif (i != 0) cout << ' ';\n\t\t\tcout << (answers[i] ? \"YES\" : \"NO\");\n\t\t}\n\t\tcout << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3748, "score_of_the_acc": -0.094, "final_rank": 12 }, { "submission_id": "aoj_1198_7127374", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing ld = long double;\nusing point = complex<ld>;\nusing polygon = vector<point>;\n\nconst ld pi = acosl(-1);\n\nconstexpr ld eps = 1e-9;\n\nbool is_zero(ld x) {\n return abs(x) < eps;\n}\nint compare(ld x, ld y) {\n return is_zero(x - y) ? 0 : x < y ? -1 : +1;\n}\n\nstruct circle {\n point p;\n ld r;\n circle() : p(0), r(0) {}\n circle(point p, ld r) : p(p), r(r) {}\n\n bool contains(point q) {\n return compare(abs(p - q), r) <= 0;\n }\n};\n\nbool is_in_polygon(polygon poly, point p) {\n int n = poly.size();\n ld sum = 0;\n for (int i = 0; i < n; ++i) {\n point p1 = poly[i], p2 = poly[(i + 1) % n];\n sum += arg((p2 - p) / (p1 - p));\n }\n return abs(sum) >= pi / 2;\n}\n\nvoid solve(int n, int m, vector<circle> cs) {\n vector<vector<int>> g = [&] {\n vector<set<int>> g(n);\n for (int i = 0; i < n; ++i) for (int j = 0; j < i; ++j) {\n ld d = abs(cs[i].p - cs[j].p);\n ld dl = abs(cs[i].r - cs[j].r), dr = cs[i].r + cs[j].r;\n if (compare(dl, d) < 0 and compare(d, dr) < 0) {\n g[i].insert(j);\n g[j].insert(i);\n }\n }\n\n auto deg_comp = [&](int i, int j) { return g[i].size() == g[j].size() ? i < j : g[i].size() < g[j].size(); };\n set<int, decltype(deg_comp)> st{ deg_comp };\n\n for (int i = 0; i < n; ++i) st.insert(i);\n\n while (st.size()) {\n int u = *st.begin();\n st.erase(st.begin());\n if (g[u].size() == 0) continue;\n if (g[u].size() >= 2) break;\n int v = *g[u].begin();\n g[u].clear();\n st.erase(v);\n g[v].erase(u);\n st.insert(v);\n }\n\n vector<vector<int>> res(n);\n for (int i = 0; i < n; ++i) for (int j : g[i]) res[i].push_back(j);\n return res;\n }();\n\n vector<map<int, int>> idx(n);\n\n for (int i = 0; i < n; ++i) {\n sort(\n g[i].begin(), g[i].end(),\n [&](int x, int y) {\n point p = cs[x].p - cs[i].p;\n point q = cs[y].p - cs[i].p;\n return arg(p) < arg(q);\n }\n );\n int siz = g[i].size();\n for (int j = 0; j < siz; ++j) {\n idx[i][g[i][j]] = j;\n }\n }\n\n vector<vector<int8_t>> seen(n);\n for (int i = 0; i < n; ++i) {\n seen[i].resize(g[i].size(), false);\n }\n\n vector<polygon> polygons;\n\n for (int i = 0; i < n; ++i) for (int j = 0; j < int(g[i].size()); ++j) if (not seen[i][j]) {\n polygon poly;\n for (int u = i, k = j;;) {\n poly.push_back(cs[u].p);\n int v = g[u][k];\n int rev_k = idx[v][u];\n assert(not seen[u][k]);\n seen[u][k] = true;\n int nk = (rev_k + g[v].size() - 1) % g[v].size();\n u = v, k = nk;\n if (u == i and k == j) {\n break;\n }\n }\n polygons.push_back(poly);\n // for (auto p : poly) {\n // cerr << \"(\" << real(p) << \", \" << imag(p) << \"), \";\n // }\n // cerr << endl;\n }\n\n for (int i = 0; i < m; ++i) {\n point p, q;\n\n {\n ld x1, y1, x2, y2;\n cin >> x1 >> y1 >> x2 >> y2;\n p = { x1, y1 };\n q = { x2, y2 };\n }\n\n vector<int> cp, cq;\n for (int i = 0; i < n; ++i) {\n if (cs[i].contains(p)) {\n cp.push_back(i);\n }\n if (cs[i].contains(q)) {\n cq.push_back(i);\n }\n }\n\n string ans = \"YES\";\n\n if (cp.size() or cq.size()) {\n if (cp != cq) {\n ans = \"NO\";\n }\n } else {\n for (const auto& poly : polygons) {\n if (is_in_polygon(poly, p) xor is_in_polygon(poly, q)) {\n ans = \"NO\";\n break;\n }\n }\n }\n\n cout << ans << \" \\n\"[i == m - 1];\n }\n}\n\nint main() {\n while (true) {\n int n, m;\n cin >> n >> m;\n\n if (n == 0 and m == 0) break;\n\n vector<circle> cs(n);\n for (int i = 0; i < n; ++i) {\n ld x, y, r;\n cin >> x >> y >> r;\n cs[i] = { point(x, y), r };\n }\n\n solve(n, m, cs);\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3512, "score_of_the_acc": -0.0501, "final_rank": 7 }, { "submission_id": "aoj_1198_6028340", "code_snippet": "/*\n正規版\nメモ\nnorm(P) Pの絶対値の2乗 abs(P)の2乗\nabs(P) Pの絶対値\narg(P)の戻り値の範囲は[-π, π]\npolar(長さ,角度(ラジアン))でPointができる\nint(-2.2+0.5)=-1\n*/\n\n#include <bits/stdc++.h>\nusing namespace std;\ntemplate<class T,class U>constexpr bool chmin(T&a,const U b){if(a<=b)return false;a=b;return true;}\ntemplate<class T,class U>constexpr bool chmax(T&a,const U b){if(a>=b)return false;a=b;return true;}\ntemplate<class T,class U>constexpr bool bitUP(const T n,const U k){return (n>>k)&1;}\n\n////////////////////////////\n// マクロや型\n////////////////////////////\n\nusing DD=long double;\n\nconst DD EPS=1e-9;\nconst DD INF=1e50;\nconst DD PI=acosl(-1.0);\n#define EQ(a,b) (abs( (a) - (b) )<EPS) //a==b\n#define LS(a,b) ( (a)+EPS<(b) ) //a<b\n#define GR(a,b) ( (a)>(b)+EPS ) //a>b\n#define LE(a,b) ( (a)<(b)+EPS ) //a<=b\n#define GE(a,b) ( (a)>(b)-EPS ) //a>=b\n\n#define X real()\n#define Y imag()\n\n\n//点\nusing Point=complex<DD>;\nistream &operator>>(istream &is, Point &p) {\n DD x,y;\n is>>x>>y;\n p=Point(x,y);\n return is;\n}\nvoid debug(Point p,string name=\"\"){\n cout<<p.X<<\" \"<<p.Y<<\" \"<<name<<endl;\n}\n\n//点a→点bの線分\n//aとbが等しい時、色々バグるから注意!\nstruct Segment{\n Point a,b;\n Segment()=default;\n Segment(Point a,Point b) :a(a),b(b){}\n Segment(DD ax,DD ay,DD bx,DD by):a(ax,ay),b(bx,by){}\n Segment(DD r,Point a) :a(a),b(a+polar((DD)1.0,r)){}\n void debug(bool isLine=false,string name=\"\"){\n string type=\"Segment \";\n if(isLine) type=\"Line \";\n cout<<type<<a.X<<\" \"<<a.Y<<\" \"<<b.X<<\" \"<<b.Y<<\" \"<<name<<endl;\n }\n};\nusing Line=Segment;\n\n//円\nstruct Circle{\n Point p;\n DD r;\n Circle()=default;\n Circle(Point p,DD r):p(p),r(r){}\n void debug(string name=\"\"){\n cout<<p.X<<\" \"<<p.Y<<\" \"<<\"circle\"<<\"_\"<<name<<endl;\n cout<<\"Circle \"<<p.X<<\" \"<<p.Y<<\" \"<<r<<endl;\n }\n};\n\nusing Polygon=vector<Point>;\nvoid debug(Polygon pol,string name=\"\"){\n cout<<\"Polygon\"<<\" \"<<name<<endl;\n for(auto p:pol){\n cout<<p.X<<\" \"<<p.Y<<endl;\n }\n cout<<\"...\"<<endl;\n}\n\n////////////////////////////\n// 基本計算\n////////////////////////////\n\n//度→ラジアン\ninline DD torad(const DD deg){return deg*PI/180;}\n//ラジアン→度\ninline DD todeg(const DD rad){return rad*180/PI;}\n//内積 |a||b|cosθ\ninline DD dot(const Point &a,const Point &b){return (conj(a)*b).X;}\n//外積 |a||b|sinθ\ninline DD cross(const Point &a,const Point &b){return (conj(a)*b).Y;}\n//ベクトルpを反時計回りにtheta(ラジアン)回転\nPoint rotate(const Point &p,const DD theta){return p*Point(cos(theta),sin(theta));}\n\n//余弦定理 cos(角度abc(ラジアン))を返す\n//長さの対応に注意 ab:辺abの長さ\n//verify:https://codeforces.com/gym/102056/problem/F\nDD cosine_formula(const DD ab,const DD bc,const DD ca){\n return (ab*ab+bc*bc-ca*ca)/(2*ab*bc);\n}\n\ninline bool xy_sort(const Point &a,const Point &b){\n if(a.X+EPS<b.X) return true;\n if(EQ(a.X,b.X) && a.Y+EPS<b.Y) return true;\n return false;\n}\ninline bool yx_sort(const Point &a,const Point &b){\n if(a.Y+EPS<b.Y) return true;\n if(EQ(a.Y,b.Y) && a.X+EPS<b.X) return true;\n return false;\n}\nnamespace std{\n inline bool operator<(const Point &a,const Point &b)noexcept{\n return xy_sort(a,b);\n }\n}\n//DDの比較関数\n//map<DD,vector<pii>,DDcom>\nstruct DDcom{\n bool operator()(const DD a, const DD b) const noexcept {\n return a+EPS<b;\n }\n};\n\n\n////////////////////////////\n// 平行や直交\n////////////////////////////\n\nbool isOrthogonal(const Point &a,const Point &b){\n return EQ(dot(a,b),0.0);\n}\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_A\nbool isOrthogonal(const Segment &s,const Segment &t){\n return EQ(dot(s.a-s.b,t.a-t.b),0.0);\n}\nbool isParallel(const Point &a,const Point &b){\n return EQ(cross(a,b),0.0);\n}\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_A\nbool isParallel(const Segment &s,const Segment &t){\n return EQ(cross(s.a-s.b,t.a-t.b),0);\n}\n//線分a→bに対して点cがどの位置にあるか\n//反時計回り:1 時計回り:-1 直線上(a,b,c:-2 a,c,b:0 c,a,b:2)\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_C\n//線分a→bの端点にcがあるなら0と判定されるはず\nint ccw(const Point &a,Point b,Point c){\n if(EQ(abs(b-c),0) or EQ(abs(a-c),0)) return 0;\n b-=a;c-=a;\n if(cross(b,c)>EPS) return 1;\n if(cross(b,c)<-EPS) return -1;\n if(dot(b,c)<-EPS) return 2;\n if(LS(norm(b),norm(c))) return -2;\n return 0;\n}\n\n////////////////////////////\n// 射影と反射\n////////////////////////////\n\n//射影\n//直線lに点pから垂線を引いたときの交点\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_A\nPoint project(const Point &p,const Line &l){\n Point base=l.b-l.a;\n DD r=dot(p-l.a,base)/norm(base);\n return l.a+base*r;\n}\n//反射\n//直線lに対して点pと対称な点\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_B\nPoint reflect(const Point &p,const Line &l){\n return p+(project(p,l)-p)*(DD)2.0;\n}\n//反射\n//直線lに対して線分sと対称な線分(直線でも使える)\n//verify:https://onlinejudge.u-aizu.ac.jp/solutions/problem/1171/review/6009447/bin101/C++17\nSegment reflect(const Segment &s,const Line &l){\n return Segment(reflect(s.a,l) , reflect(s.b,l));\n}\n\n////////////////////////////\n// 点との距離\n////////////////////////////\n\n//点と直線の距離\nDD DistPL(const Point &p,const Line &l){\n return abs(cross(l.b-l.a,p-l.a))/abs(l.b-l.a);\n}\n//点と線分の距離\nDD DistPS(const Point &p,const Segment &s){\n if( dot(s.b-s.a,p-s.a)<0.0 ) return abs(p-s.a);\n if( dot(s.a-s.b,p-s.b)<0.0 ) return abs(p-s.b);\n return DistPL(p,s);\n}\n\n////////////////////////////\n// 線分と直線\n////////////////////////////\n\n//線分a-b,c-dは交差するか?\n//接する場合も交差すると判定\n//接する場合は交差しないとするなら<=を<に変換\nbool intersect(const Point &a,const Point &b,const Point &c,const Point &d){\n return(ccw(a,b,c)*ccw(a,b,d)<=0 && ccw(c,d,a)*ccw(c,d,b)<=0);\n}\n//線分s,tは交差するか?\n//接する場合も交差すると判定\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_B&lang=ja\n//接する場合は交差しないとするならintersectの<=を<に変換\nbool intersect(const Segment &s,const Segment &t){\n return intersect(s.a,s.b,t.a,t.b);\n}\n// 2直線の交点\n// 線分の場合はintersectをしてから使う\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_C&lang=ja\nPoint crossPoint(const Line &s,const Line &t){\n Point base=t.b-t.a;\n DD d1=cross(base,t.a-s.a);\n DD d2=cross(base,s.b-s.a);\n if(EQ(d1,0) and EQ(d2,0)) return s.a; //同じ直線\n if(EQ(d2,0)) assert(false); //交点がない\n return s.a+d1/d2*(s.b-s.a);\n}\n//線分と線分の距離\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_D&lang=ja\nDD Dist(const Segment &s,const Segment &t){\n if(intersect(s,t)) return 0.0;\n return min(min(DistPS(t.a,s),DistPS(t.b,s)),min(DistPS(s.a,t),DistPS(s.b,t)) );\n}\nbool issame(const Line &l,const Line &m){\n if (GR(abs(cross(m.a - l.a, l.b - l.a)),0) ) return false;\n if (GR(abs(cross(m.b - l.a, l.b - l.a)),0) ) return false;\n return true;\n}\n\n////////////////////////////\n// 円\n////////////////////////////\n//直線lと円Cの交点\n//l.aにより近い方がindexが小さい\n//veirfy:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_D\nvector<Point> crossPointLC(const Line &l,const Circle &c){\n vector<Point> ret;\n if(GR(DistPL(c.p,l),c.r)) return ret; //交点がないとき、空ベクトルを返す\n Point pr=project(c.p,l);\n Point e=(l.b-l.a)/(abs(l.b-l.a));\n DD base=sqrt(c.r*c.r-norm(pr-c.p));\n ret.push_back(pr-e*base);\n ret.push_back(pr+e*base);\n if(EQ(DistPL(c.p,l),c.r)) ret.pop_back(); //接するとき\n return ret;\n}\n//線分sと円cの交点\n//交点がないときは空ベクトルを返す\n//線分の端が交わる場合も交点とみなす\n//s.aにより近い方がindexが小さい\nvector<Point> crossPointSC(const Segment &s,const Circle &c){\n vector<Point> ret;\n if(DistPS(c.p,s)>c.r+EPS) return ret;\n auto koho=crossPointLC(s,c);\n for(auto p:koho){\n if(ccw(s.a,s.b,p)==0 or EQ(abs(p-s.a),0) or EQ(abs(p-s.b),0)) ret.push_back(p);\n }\n return ret;\n}\n\n//円aと円bの共通接線の数\n//離れている:4 外接:3 交わる:2 内接:1 内包:0\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_A\nint intersect(const Circle &a,const Circle &b){\n DD d=abs(a.p-b.p);\n if(GR(d,a.r+b.r)) return 4;\n if(EQ(d,a.r+b.r)) return 3;\n if(EQ(d,abs(a.r-b.r))) return 1;\n if(LS(d,abs(a.r-b.r))) return 0;\n return 2;\n}\n\n//円aと円bの交点\n//交点がないときは空ベクトルを返す\n//事前にintersectをしたほうがいいかも\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_E\nvector<Point> crossPoint(const Circle &a,const Circle &b){\n vector<Point> ret;\n if(GR(abs(a.p-b.p),a.r+b.r)) return ret;\n DD d=abs(a.p-b.p);\n DD s=acosl((a.r*a.r+d*d-b.r*b.r)/(2*a.r*d)); //0~π\n DD t=arg(b.p-a.p);\n if(EQ(a.r+b.r,d)) ret.push_back(a.p+polar(a.r,t));\n else ret.push_back(a.p+polar(a.r,t+s)),ret.push_back(a.p+polar(a.r,t-s));\n return ret;\n}\n\n//点pから円cに接線を引いたときの接点\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_F&lang=ja\nvector<Point> TanLine(const Point &p,const Circle &c){\n vector<Point> ret;\n DD d=abs(p-c.p);\n if(LS(d,c.r)) return ret; //pがcの内部にある場合\n if(EQ(d,c.r)){\n ret.push_back(p);\n return ret; //円の線上にある場合\n } \n return crossPoint(c,Circle(p,sqrt(d*d-c.r*c.r)));\n}\n\n//円a,bの共通接線\n//https://www.slideshare.net/kujira16/ss-35861169\n//Line.aは円aと接線の交点\n//(接線と円bの交点)と(接線と円aの交点)が違う場合はLine.bは(接線と円bの交点)\n//一致する場合は円aの中心からLine.aに向かうベクトルを反時計回りに90度回転したものを\n//Line.aに足したもの\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_G\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=2201\nvector<Line> TanLine(const Circle &a,const Circle &b){\n DD d=abs(a.p-b.p);\n vector<Line> ret;\n //外接線\n if(intersect(a,b)>=2){\n if(EQ(a.r,b.r)){\n Point up=polar(a.r,arg(b.p-a.p)+PI/2);\n ret.emplace_back(a.p+up,b.p+up);\n ret.emplace_back(a.p-up,b.p-up);\n }else{\n Point q=(a.p*b.r-b.p*a.r)/(b.r-a.r);\n auto as=TanLine(q,a);\n auto bs=TanLine(q,b);\n assert(as.size()==2 and bs.size()==2);\n for(int i=0;i<2;i++){\n ret.emplace_back(as[i],bs[i]);\n }\n }\n }else if(intersect(a,b)==1){ //内接する場合\n Point dir;\n if(a.r>b.r) dir=polar(a.r,arg(b.p-a.p));\n else dir=polar(a.r,arg(a.p-b.p));\n ret.emplace_back(a.p+dir,a.p+dir+rotate(dir,PI/2));\n }\n //内接線\n if(GR(abs(a.p-b.p),a.r+b.r)){ //円が離れている場合\n Point q=a.p+(b.p-a.p)*a.r/(a.r+b.r);\n auto as=TanLine(q,a);\n auto bs=TanLine(q,b);\n assert(as.size()==2 and bs.size()==2);\n for(int i=0;i<2;i++){\n ret.emplace_back(as[i],bs[i]);\n }\n }else if(EQ(d,a.r+b.r)){ //円が接している場合\n Point dir=polar(a.r,arg(b.p-a.p));\n ret.emplace_back(a.p+dir,a.p+dir+rotate(dir,PI/2));\n }\n return ret;\n}\n//2つの円の共通部分の面積\n//参考: https://tjkendev.github.io/procon-library/python/geometry/circles_intersection_area.html\n//verify: https://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=6005736#1\nDD Area(const Circle &c1,const Circle &c2){\n DD cd=abs(c1.p-c2.p);\n if(LE(c1.r+c2.r,cd)) return 0; //円が離れている\n\n if(LE(cd,abs(c1.r-c2.r))) //片方の円が他方を包んでいる\n return min(c1.r,c2.r)*min(c1.r,c2.r)*PI;\n\n DD theta1=acosl(cosine_formula(c1.r,cd,c2.r));\n DD theta2=acosl(cosine_formula(c2.r,cd,c1.r));\n\n return c1.r*c1.r*theta1+c2.r*c2.r*theta2-c1.r*cd*sin(theta1);\n}\n\n\n////////////////////////////\n// 三角形\n////////////////////////////\n\n//ヘロンの公式 三角形の面積を返す\n//三角形が成立するか(平行ではないか)を忘れずに\nDD Heron(const DD ad,const DD bd,const DD cd){\n DD s=(ad+bd+cd)/2;\n return sqrt(s*(s-ad)*(s-bd)*(s-cd));\n}\n//三角形の外接円\n//isParallel()を使って三角形が成立するか(平行ではないか)を忘れずに\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_C\nCircle CircumscribedCircle(const Point &a,const Point &b,const Point &c){\n Point bc=(b+c)/(DD)2.0;\n Line aa(bc,bc+rotate(c-b,PI/2));\n Point ab=(a+b)/(DD)2.0;\n Line cc(ab,ab+rotate(b-a,PI/2));\n Point p=crossPoint(aa,cc);\n return Circle(p,abs(a-p));\n}\n//三角形の内接円\n//isParallel()を使って三角形が成立するか(平行ではないか)を忘れずに\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_B\nCircle InCircle(const Point &a,const Point &b,const Point &c){\n Line aa(a,a+polar((DD)1.0,(arg(b-a)+arg(c-a))/(DD)2.0));\n Line bb(b,b+polar((DD)1.0,(arg(a-b)+arg(c-b))/(DD)2.0));\n Point p=crossPoint(aa,bb);\n return Circle(p,DistPL(p,Line(a,b)));\n}\n\n////////////////////////////\n// 多角形\n////////////////////////////\n\n//点pが多角形gに対してどの位置にあるか\n//中:2 辺上:1 外:0\n//凸多角形である必要ない\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_C\nint contains(const Point &p,const vector<Point> &g){\n int n=(int)g.size();\n int x=false;\n for(int i=0;i<n;i++){\n Point a=g[i]-p,b=g[(i+1)%n]-p;\n if(EQ(cross(a,b),0) && dot(a,b)<EPS) return 1;\n if(a.Y>b.Y) swap(a,b);\n if(a.Y<EPS && EPS<b.Y && cross(a,b)>EPS) x=!x;\n }\n return (x?2:0);\n}\n//凸性判定\n//多角形gは凸か?\n//gは反時計回りでも時計回りでもいい\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_B\nbool isConvex(const vector<Point> &g){\n int n=(int)g.size();\n if(n<=3) return true;\n int flag=0;\n int t;\n for(int i=0;i<n;i++){\n Point a(g[(i+1)%n]-g[i]),b(g[(i+2)%n]-g[i]);\n if(cross(a,b)>EPS) t=1;\n else if(cross(a,b)<-EPS) t=-1;\n else continue;\n if(flag==-t) return false;\n flag=t;\n }\n return true;\n}\n\n//凸包 アンドリューのアルゴリズム\n//O(NlogN)\n//反時計回りの多角形を返す\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_4_A\nvector<Point> ConvexHull(vector<Point> s,const bool on_edge){\n int j;\n if(on_edge) j=-1;\n else j=1;\n int sz=(int)s.size();\n if(sz<3) return s;\n sort(s.begin(),s.end(),yx_sort);\n\n int n=0;\n vector<Point> res(2*sz);\n for(int i=0;i<sz;i++){\n while(n>=2 && cross(res[n-1]-res[n-2],s[i]-res[n-2])<EPS*j){\n n--;\n }\n res[n]=s[i];\n n++;\n }\n int t=n+1;\n for(int i=sz-2;i>=0;i--){\n while(n>=t && cross(res[n-1]-res[n-2],s[i]-res[n-2])<EPS*j){\n n--;\n }\n res[n]=s[i];\n n++;\n }\n res.resize(n-1);\n return res;\n}\n\n//多角形g(凸でなくてもいい)の符号付き面積\n//反時計回りの多角形なら正の値を返す 時計回りなら負\n//O(N)\n//https://imagingsolution.net/math/calc_n_point_area/\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_A\nDD Area(const vector<Point> &g){\n DD ret=0.0;\n int n=(int)g.size();\n for(int i=0;i<n;i++){\n ret+=cross(g[i],g[(i+1)%n]);\n }\n return ret/2.0;\n}\n\n//凸多角形gを直線lで切断\n//直線の左側(向きを考慮)にできる凸多角形を返す\n//多角形gが反時計回りならば、反時計回りで返す(時計回りなら時計回り)\n//直線上の頂点を含む線分の交点は含めてない\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_4_C\nvector<Point> ConvexCut(const vector<Point> &g,const Line &l){\n vector<Point> ret;\n int gz=(int)g.size();\n for(int i=0;i<gz;i++){\n Point now=g[i],next=g[(i+1)%gz];\n if(ccw(l.a,l.b,now)!=-1) ret.push_back(now);\n if(EQ(DistPL(now,l),0) or EQ(DistPL(next,l),0)) continue;\n if(ccw(l.a,l.b,now)*ccw(l.a,l.b,next)<0){\n ret.push_back(crossPoint(Line(now,next),l));\n }\n }\n return ret;\n}\n//部品\ninline DD calc(const Point &a,const Point &b,const DD &r,const bool triangle){\n if(triangle) return cross(a,b);\n else return r*r*arg(b/a);\n}\n//部品\nDD calcArea(const DD &r,const Point &a,const Point &b){\n if(EQ(abs(a-b),0)) return 0;\n bool ina=(abs(a)<r+EPS);\n bool inb=(abs(b)<r+EPS);\n if(ina && inb) return cross(a,b);\n auto cr=crossPointSC(Segment(a,b),Circle(Point(0,0),r));\n if(cr.empty()) return calc(a,b,r,false);\n auto s=cr[0],t=cr.back();\n return calc(s,t,r,true)+calc(a,s,r,ina)+calc(t,b,r,inb);\n}\n//円と多角形の共通部分の面積\n//多角形が反時計回りならば正の値を返す\n//凸多角形でなくても大丈夫\n//http://drken1215.hatenablog.com/entry/2020/02/02/091000\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_H&lang=ja\nDD Area(const Circle &c,const vector<Point> &g){\n DD ret=0.0;\n int gz=g.size();\n if(gz<=2) return ret;\n for(int i=0;i<gz;i++){\n Point a=g[i]-c.p,b=g[(i+1)%gz]-c.p;\n ret+=calcArea(c.r,g[i]-c.p,g[(i+1)%gz]-c.p);\n }\n return ret/2.0;\n}\n\n//点と多角形の距離\n//点が多角形の中にあるなら0\nDD Dist(const Point &a,const vector<Point> &b){\n\tif(b.size()==1) return abs(a-b[0]);\n\tif(contains(a,b)>=1) return 0.0L;\n\tDD ret=INF;\n\tfor(int i=0;i<b.size();i++){\n\t\tchmin(ret,DistPS(a,Segment(b[i],b[(i+1)%b.size()])));\n\t}\n\treturn ret;\n}\n\n//多角形と多角形の距離\n//どちらかが内側に入っていたら0\n//全ての線分の組み合わせの距離を求めて、その最小が答え\n//O(size(a)*size(b))\n//sizeが1の時は点との距離になる\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=2827\nDD Dist(const vector<Point> &a,const vector<Point> &b){\n\tDD ret=INF;\n\tif(a.size()==1) return Dist(a[0],b);\n\tif(b.size()==1) return Dist(b[0],a);\n\n\tif(contains(a[0],b)>=1) return 0.0L;\n\tif(contains(b[0],a)>=1) return 0.0L;\n\n\tfor(int i=0;i<a.size();i++){\n\t\tfor(int j=0;j<b.size();j++){\n\t\t\tSegment sa(a[i],a[(i+1)%a.size()]);\n\t\t\tSegment sb(b[j],b[(j+1)%b.size()]);\n\t\t\tchmin(ret,Dist(sa,sb));\n\t\t}\n\t}\n\treturn ret;\n}\n\n////////////////////////////\n// 最近(遠)点間距離\n////////////////////////////\n//部品\nDD RecClosetPair(const vector<Point>::iterator it,const int n){\n if(n<=1) return INF;\n int m=n/2;\n DD x=it[m].X;\n DD d=min(RecClosetPair(it,m),RecClosetPair(it+m,n-m));\n inplace_merge(it,it+m,it+n,yx_sort);\n vector<Point> v;\n for(int i=0;i<n;i++){\n if(abs(it[i].X-x)>=d) continue;\n for(int j=0;j<v.size();j++){\n DD dy=it[i].Y-v[(int)v.size()-1-j].Y;\n if(dy>=d) break;\n DD dx=it[i].X-v[(int)v.size()-1-j].X;\n d=min(d,sqrt(dx*dx+dy*dy));\n }\n v.push_back(it[i]);\n }\n return d;\n}\n//最近点対の距離\n//点が1つのときINFを返す\n//O(NlogN)\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_5_A\nDD ClosetPair(vector<Point> g){\n sort(g.begin(),g.end(),xy_sort);\n return RecClosetPair(g.begin(),g.size());\n}\n\n//最遠頂点間\n//verify:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_4_B\nDD Diameter(vector<Point> g){\n g=ConvexHull(g,1);\n int gz=g.size();\n int m=0,M=0;\n for(int i=1;i<gz;i++){\n if(g[i].Y<g[m].Y) m=i;\n if(g[i].Y>g[M].Y) M=i;\n }\n DD ret=0;\n int sm=m,sM=M;\n while(m!=sM || M!=sm){\n ret=max(ret,norm(g[m]-g[M]));\n if(cross(g[(m+1)%gz]-g[m],g[(M+1)%gz]-g[M])<0) m=(m+1)%gz;\n else M=(M+1)%gz;\n }\n return sqrt(ret);\n}\n//動的凸包\n//辺上にある点は含めない\n//verify:https://atcoder.jp/contests/geocon2013/tasks/geocon2013_c\nstruct DynamicConvex{\n\tset<Point> up,down;\n\tDynamicConvex(){}\n \n\tbool isContain(set<Point> &pol,Point p){\n\t\tif(pol.size()==0) return false;\n\t\tif(pol.size()==1){\n\t\t\tPoint q=*begin(pol);\n\t\t\treturn EQ(q.X,p.X) and GE(q.Y,p.Y);\n\t\t}\n\t\tassert(pol.size()>=2);\n auto left=begin(pol);\n auto right=(--end(pol));\n if(LS(p.X,left->X) or GR(p.X,right->X)) return false;\n \n \n auto q1=pol.upper_bound(Point(p.X,INF));\n if(q1==end(pol)){\n return GE(right->Y,p.Y);\n }\n auto q2=q1--; //q1が範囲外になるのは最初に弾いてる\n return GE(cross(p-*q1,*q2-*q1),0.0);\n\t}\n bool isContain(Point p){\n if(not isContain(up,p)) return false;\n if(not isContain(down,Point(p.X,-p.Y))) return false;\n return true;\n }\n \n\tvoid add(set<Point> &pol,Point p){\n\t\tif(pol.size()==0){\n\t\t\tpol.insert(p);\n\t\t\treturn;\n\t\t}\n\t\tif(pol.size()==1){\n Point q=*begin(pol);\n\t\t\tif(EQ(q.X,p.X)){\n pol.clear();\n pol.insert(max(p,q));\n\t\t\t}else{\n\t\t\t\tpol.insert(p);\n\t\t\t}\n return;\n\t\t}\n assert(pol.size()>=2);\n if(isContain(pol,p)) return;\n //left\n auto q1=pol.upper_bound(Point(p.X,INF));\n if(q1!=begin(pol)){\n q1--;\n while(pol.size()>=1 and q1!=begin(pol)){\n auto q2=q1--;\n if(GR(cross(*q2-p,*q1-p),0)) break;\n pol.erase(q2);\n }\n }\n //right\n q1=pol.lower_bound(Point(p.X,-INF));\n if(q1!=end(pol)){\n while(pol.size()>1 and q1!=--end(pol)){\n auto q2=q1++;\n if(GR(cross(*q1-p,*q2-p),0.0)) break;\n pol.erase(q2);\n }\n }\n pol.insert(p);\n\t}\n \n\tvoid add(Point p){\n\t\tadd(up,p);\n\t\tadd(down,Point(p.X,-p.Y)); //upと同じように処理をしたいから\n\t}\n};\n\n//垂直二等分線\n//p-↑-q こんなかんじ\n//voronoiで使う\nLine bisector(const Point &p, const Point &q) {\n Point c=(p+q)/DD(2.0);\n Point v=rotate(q-p,PI/2);\n v/=abs(v);\n return Line(c-v,c+v);\n}\n\n//ボロノイ図\n//pol:全体 ps:点の集合 id:中心となる点の添字 pp:中心となる点\n//計算量: pol.size()*ps.size()\n//verify: https://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=6005648#1\nvector<Point> voronoi(Polygon pol,const vector<Point> &ps,int id=-1,const Point pp=Point()){\n Point p;\n if(id!=-1) p=ps[id];\n else p=pp;\n for(size_t i=0;i<ps.size();i++){\n if(i==id) continue;\n Line l=bisector(p,ps[i]);\n pol=ConvexCut(pol,l);\n }\n return pol;\n}\n\nvector<Polygon> Pol;\nvector<int> vp;\nvector<Circle> C;\nusing Graph=vector<vector<int>>;\nGraph g;\nvector<bool> used;\n\nvoid dfs(int idx,int par){\n if(used[idx]) return;\n used[idx]=true;\n vp.push_back(idx);\n\n for(int to:g[idx]){\n if(to==par) continue;\n int start=-1;\n for(int i=0;i<vp.size();i++){\n if(vp[i]==to) start=i;\n }\n if(start==-1){\n dfs(to,idx);\n }else{\n Polygon pol;\n for(int i=start;i<vp.size();i++){\n pol.push_back(C[vp[i]].p);\n }\n Pol.push_back(pol);\n }\n }\n vp.pop_back();\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(0);\n cout << fixed << setprecision(20);\n\nwhile(true){\n int N,M;\n cin>>N>>M;\n if(N==0 and M==0) return 0;\n C.clear();\n C.resize(N);\n for(int i=0;i<N;i++) cin>>C[i].p>>C[i].r/*,C[i].debug({char('a'+i)})*/;\n\n g.clear();\n g.resize(N);\n for(int i=0;i<N;i++){\n for(int j=i+1;j<N;j++){\n if(intersect(C[i],C[j])==2){\n g[i].push_back(j);\n g[j].push_back(i);\n }\n }\n }\n used.clear();\n used.resize(N);\n Pol.clear();\n\n dfs(0,-1);\n for(int i=0;i<N;i++){\n dfs(i,-1);\n }\n vector<bool> ans;\n for(int i=0;i<M;i++){\n Point p,q; cin>>p>>q;\n /*string s;\n s+='a'+i;\n debug(p,s); debug(q,s);*/\n vector<bool> cp(N),cq(N);\n bool ok=false;\n for(int j=0;j<N;j++){\n if(LE(abs(p-C[j].p),C[j].r)){\n ok=true;\n cp[j]=true;\n }\n if(LE(abs(q-C[j].p),C[j].r)){\n cq[j]=true;\n }\n }\n if(cp==cq and ok){\n ans.push_back(true);\n }else if(cp!=cq){\n ans.push_back(false);\n }else{\n cp.clear(); cq.clear();\n cp.resize(Pol.size()); cq.resize(Pol.size());\n for(int j=0;j<Pol.size();j++){\n cp[j]=contains(p,Pol[j]);\n cq[j]=contains(q,Pol[j]);\n }\n if(cp==cq) ans.push_back(true);\n else ans.push_back(false);\n }\n }\n for(int i=0;i<ans.size();i++){\n if(i) cout<<\" \";\n if(ans[i]) cout<<\"YES\";\n else cout<<\"NO\";\n }\n cout<<endl;\n}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3664, "score_of_the_acc": -0.0715, "final_rank": 10 }, { "submission_id": "aoj_1198_5981741", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nnamespace geometry{\n constexpr double eps = 1e-9;\n bool eq(double a, double b){ return fabs(a - b) < eps; }\n template<typename T> bool eq(T a, T b){ return a == b; }\n bool is_zero(double a){ return fabs(a) < eps; }\n template<typename T> bool is_zero(T a){ return a == 0; }\n bool le(double a, double b){ return a <= b + eps; }\n template<typename T> bool le(T a, T b){ return a <= b; }\n bool lt(double a, double b){ return a < b - eps; }\n template<typename T> bool lt(T a, T b){ return a < b; }\n};\n\n\ntemplate<class T> struct Point{\n T x,y;\n Point(){}\n Point(T x, T y) : x(x), y(y) {}\n Point(const pair<T,T> &p) : x(p.first), y(p.second) {}\n\n Point operator*(const T b) const { return Point(x * b, y * b); }\n Point operator/(const T b) const { return Point(x / b, y / b); }\n Point operator+(const Point &b) const { return Point(x + b.x, y + b.y); }\n Point operator-(const Point &b) const { return Point(x - b.x, y - b.y); }\n Point operator*(const Point &b) const { return Point(x*b.x - y*b.y, x*b.y + y*b.x); }\n Point operator/(const Point &b) const { return Point(x*b.x + y*b.y, y*b.x - x*b.y)/(b.x*b.x + b.y*b.y); }\n\n Point &operator*=(const T b){ return (*this) = (*this) * b; }\n Point &operator/=(const T b){ return (*this) = (*this) / b; }\n Point &operator+=(const Point &b){ return (*this) = (*this) + b; }\n Point &operator-=(const Point &b){ return (*this) = (*this) - b; }\n Point &operator*=(const Point &b){ return (*this) = (*this) * b; }\n Point &operator/=(const Point &b){ return (*this) = (*this) / b; }\n \n bool operator==(const Point &b) const {\n return geometry::eq(x, b.x) && geometry::eq(y, b.y);\n }\n bool operator<(const Point &b) const { \n if(geometry::eq(x, b.x)) return y < b.y;\n return x < b.x;\n }\n T Norm() const { return x * x + y * y; }\n double Abs() const { return hypot<double>(x, y); }\n double dist(const Point &b) const { return hypot<double>(x - b.x, y - b.y); }\n double arg() const { return atan2<double>(y, x); }\n \n Point ArgVec() const {\n if((*this) == Point(0, 0)) return (*this);\n if(geometry::is_zero(x)) return Point(0, -1);\n return (*this) / gcd(x, y) * (x < 0 ? -1 : 1);\n }\n\n int ort() const {\n if(geometry::is_zero(x) && geometry::is_zero(y)) return 0;\n if(geometry::is_zero(y)) return x > 0 ? 1 : 3;\n if(geometry::is_zero(x)) return y > 0 ? 2 : 4;\n if (y > 0) return x > 0 ? 1 : 2;\n else return x > 0 ? 4 : 3;\n }\n Point rotate90() const { return Point(-y, x);}\n Point rotate180() const { return Point(-x, -y);}\n Point rotate270() const { return Point(y, -x);}\n\n Point flip_x(T p = 0) const { return Point(p*2 - x, y);}\n Point flip_y(T p = 0) const { return Point(x, p*2 - y);}\n\n Point rotate(double theta) const {\n return Point(cos(theta)*x - sin(theta)*y, sin(theta)*x + cos(theta)*y);\n }\n\n Point flip(double theta) const {\n return (*this).rotate(-theta).flip_y().rotate(theta);\n }\n\n friend ostream &operator<<(ostream &os, const Point &p) {\n return os << p.x << \" \" << p.y;\n }\n friend istream &operator>>(istream &is, Point &p) {\n T a, b; is >> a >> b;\n p = Point<T>(a, b);\n return (is);\n }\n};\n\ntemplate<typename T> Point<T> Polar(const T& rho, const T& theta = 0){\n return Point<T>(rho * cos(theta), rho * sin(theta));\n}\n\n\ntemplate<typename T> using Polygon = vector<Point<T>>;\n\ntemplate<class T> T Cross(const Point<T> &a, const Point<T> &b) { return a.x * b.y - a.y * b.x; }\n\ntemplate<class T> T Dot(const Point<T> &a, const Point<T> &b) { return a.x * b.x + a.y * b.y; }\n\ntemplate<class T> bool Intersect(const Point<T> &a, const Point<T> &b, const Point<T> &c, const Point<T> &d) {\n return (iSP(a, b, c)*iSP(a, b, d) <= 0) && (iSP(c, d, a)*iSP(c, d, b) <= 0);\n}\n\ntemplate<class T> int iSP(const Point<T> &a, const Point<T> &b, const Point<T> &c){\n T fl = Cross(b-a, c-a);\n if(geometry::lt(T(0), fl)) return 1; // CCW\n if(geometry::lt(fl, T(0))) return -1; // CW\n if(geometry::lt(T(0), Dot(b-a, c-b))) return 2; //abc\n if(geometry::lt(T(0), Dot(a-b, c-a))) return -2; //bac\n return 0; // acb\n}\n\ntemplate<class T> int angletype(const Point<T> &a, const Point<T> &b, const Point<T> &c){\n T v = Dot(a-b, c-a);\n if(geometry::is_zero(v)) return 0; // right angle\n if(v > 0) return 1; // acute angle\n return -1; // obtuse angle\n}\n\ntemplate<typename T>\nbool cmp_y(const Point<T>& p1, const Point<T> &p2){\n if(p1.y == p2.y) return p1.x < p2.x;\n return p1.y < p2.y;\n}\n\ntemplate<typename T>\nbool cmp_arg(const Point<T>& p1, const Point<T> &p2){\n if(p1.ort() != p2.ort()) return p1.ort() < p2.ort();\n return iSP(Point<T>(0,0), p1, p2) > 0;\n}\n\ntemplate<typename T>\nvoid ArgSort(Polygon<T> &ps){\n sort(begin(ps), end(ps), cmp_arg<T>);\n}\n\ntemplate<class T> struct Line{\n Point<T> a, b;\n Line() {}\n Line(const Point<T> &a, const Point<T> &b): a(a), b(b) {}\n Line(T A, T B, T C){ // Ax + By = C\n if(A == 0){ a = Point<T>(0, C/B); b = Point<T>(1, C/B); }\n else if(B == 0){ a = Point<T>(C/A, 0); b = Point<T>(C/A, 1); }\n else{ a = Point<T>(0, C/B); b = Point<T>(C/A, 0); }\n }\n //Line(const Segment<T> &s): a(s.a), b(s.b) {}\n Point<T> projection(const Point<T> &p) const {\n return a + (b - a)*Dot(p - a, b - a)/(b - a).Norm();\n }\n Point<T> reflection(const Point<T> &p) const {\n return p + (projection(p) - p)*2;\n }\n int angletype(const Line &l) const {\n if(geometry::is_zero(Cross(b-a, l.b-l.a))) return 1;\n if(geometry::is_zero(Dot(a-b, l.b-l.a))) return -1;\n return 0;\n }\n bool Intersect(const Line &l) const {\n return angletype(l) != 1;\n }\n Point<T> Cross_Point(const Line &l) const {\n if(geometry::is_zero(Cross(b-a,l.b-l.a))) return l.a;\n return (b - a)*Cross(l.a - a, l.b - l.a)/Cross(b - a,l.b - l.a) + a;\n }\n double dist(const Point<T> &p) const {\n return abs(Cross(p - a, b - a)/(b - a).Abs());\n }\n double dist(const Line &l) const {\n if(Intersect(l)) return 0;\n return dist(l.a);\n }\n};\n\ntemplate<class T> struct Segment{\n Point<T> a, b;\n Segment() {}\n Segment(const Point<T> &a, const Point<T> &b): a(a), b(b) {}\n\n double length() const { return a.dist(b); }\n bool Intersect(const Segment &s) const {\n return iSP(a, b, s.a)*iSP(a, b, s.b) <= 0 && iSP(s.a, s.b, a)*iSP(s.a, s.b, b) <= 0;\n }\n Point<T> Center() const { return (a + b) / 2; }\n Line<T> PerpBisector() const {\n Point<T> center = this->Center();\n return Line<T>((a - center).rotate90() + center, center);\n }\n int angletype(const Segment &s) const {\n if(geometry::is_zero(Cross(b-a, s.b-s.a))) return 1;\n if(geometry::is_zero(Dot(a-b, s.b-s.a))) return -1;\n return 0;\n }\n Point<T> Cross_Point(const Segment &s) const {\n if(geometry::is_zero(Cross(b-a,s.b-s.a))) return s.a;\n return (b - a)*Cross(s.a - a, s.b - s.a)/Cross(b - a, s.b - s.a) + a;\n }\n double dist(const Point<T> &p) const {\n if(Dot(b-a, p-a) < 0) return p.dist(a);\n if(Dot(a-b, p-b) < 0) return p.dist(b);\n return abs(Cross(p-a, b-a)/ (b-a).Abs());\n }\n double dist(const Segment &s) const {\n if(Intersect(s)) return 0;\n return min({dist(s.a), dist(s.b), s.dist(a), s.dist(b)});\n }\n};\n\ntemplate<typename T>\nstruct Triangle{\n Point<T> a, b, c;\n Triangle() {}\n Triangle(const Point<T> &a, const Point<T> &b, const Point<T> &c): a(a), b(b), c(c){}\n\n double angle_a() const {\n double ab = a.dist(b), bc = b.dist(c), ca = c.dist(a);\n return acos((ca*ca + ab*ab - bc*bc)/(2*ca*ab));\n }\n double angle_b() const {\n double ab = a.dist(b), bc = b.dist(c), ca = c.dist(a);\n return acos((ab*ab + bc*bc - ca*ca)/(2*ab*bc));\n }\n double angle_c() const {\n double ab = a.dist(b), bc = b.dist(c), ca = c.dist(a);\n return acos((bc*bc + ca*ca - ab*ab)/(2*bc*ca));\n }\n Point<T> divpoint(double p, double q, double r) const {\n return (a*p + b*q + c*r)/(p + q + r);\n }\n\n Point<T> centerofgravity() const {\n return (a + b + c)/3;\n }\n Point<T> circumcenter() const {\n Segment<T> s1(a, b), s2(a, c);\n return s1.PerpBisector().Cross_Point(s2.PerpBisector());\n }\n Point<T> orthocenter() const {\n return centerofgravity()*3 - circumcenter()*2;\n }\n Point<T> innercenter() const {\n return divpoint(b.dist(c), c.dist(a), a.dist(b));\n }\n Point<T> excenterA() const {\n return divpoint(-b.dist(c), c.dist(a), a.dist(b));\n }\n Point<T> excenterB() const {\n return divpoint(b.dist(c), -c.dist(a), a.dist(b));\n }\n Point<T> excenterC() const {\n return divpoint(b.dist(c), c.dist(a), -a.dist(b));\n }\n};\n\ntemplate<class T> struct Circle{\n Point<T> o;\n T r;\n Circle() {}\n Circle(const Point<T> &o, const T &r): o(o), r(r) {}\n Circle(const Point<T> &a, const Point<T> &b): o((a + b)/2), r(a.dist(b)/2) {}\n Circle(const Point<T> &a, const Point<T> &b, const Point<T> &c)\n : o(Triangle(a,b,c).circumcenter()), r(o.dist(a)) {}\n\n int Intersect(const Circle&c) const {\n if(r < c.r) return c.Intersect(*this);\n auto od = (o - c.o).Norm();\n auto ra = (r + c.r)*(r + c.r), rs = (r - c.r)*(r - c.r);\n if(geometry::lt(ra, od)) return 4;\n if(geometry::eq(ra, od)) return 3;\n if(geometry::lt(rs, od)) return 2;\n if(geometry::eq(rs, od)) return 1;\n return 0;\n }\n\n int Intersect(const Line<T> &l) const {\n double d = l.dist(o);\n if(geometry::lt<double>(d, r)) return 2;\n return geometry::eq(d, r);\n }\n\n int Contains(const Point<T> &p) const {\n auto od = (o - p).Norm();\n if(geometry::eq(od, r*r)) return 1; // on\n return (od > r*r) ? 2 : 0; // out/in\n }\n\n Polygon<T> Cross_Points(const Line<T> &l) const {\n int k = this->Intersect(l);\n if(k == 0) return {};\n Point<T> p = l.projection(o);\n if(k == 1) return {p};\n Point<T> d = (l.b - l.a)/l.a.dist(l.b);\n double base = sqrt(r*r - (p - o).Norm());\n return {p + d*base, p - d*base};\n }\n\n Polygon<T> Cross_Points(const Circle &c) const {\n int k = this->Intersect(c);\n if(k == 0 || k == 4) return {};\n double t = (c.o - o).arg();\n if(k == 1 || k == 3) return {o + Polar<T>(r, t)};\n double d = o.dist(c.o), a = acos((r*r + d*d - c.r*c.r) / (r * d * 2));\n return {o + Polar<T>(r, t + a), o + Polar<T>(r, t - a)};\n }\n\n friend ostream &operator<<(ostream &os, const Circle &c) {\n return os << c.o << \" \" << c.r;\n }\n friend istream &operator>>(istream &is, Circle &c) {\n Point<T> p; T l; is >> p >> l;\n c = Circle<T>(p, l);\n return (is);\n }\n};\n\n\ntemplate<typename T>\nint Contains(const Polygon<T> &ps, const Point<T>& p){\n bool in = false;\n int n = ps.size();\n for(int i = 0; i < n; i++){\n Point<T> a = ps[i] - p, b = ps[(i+1)%n] - p;\n if(a.y > b.y) swap(a, b);\n if(a.y <= 0 && 0 < b.y && Cross(a,b) < 0) in = !in;\n if(geometry::is_zero(Cross(a, b)) && geometry::le(Dot(a, b), T(0))) return 1; // on\n }\n return in? 2 : 0; // out/in\n}\n\ntemplate<typename T = int>\nstruct Edge{\n int src, to; T cost; int idx;\n Edge(){}\n Edge(int src, int to, T cost = -1, int idx = -1): src(src), to(to), cost(cost), idx(idx) {}\n operator int() const { return to; }\n};\ntemplate<typename T>\nusing Edges = vector<Edge<T>>;\n\ntemplate<typename T = bool>\nstruct Graph {\n vector<vector<Edge<T>>> g;\n size_t es;\n Graph() {};\n Graph(size_t n): g(n), es(0) {}\n size_t size() const { return g.size(); }\n int deg(int v) const { return int(g[v].size()); }\n\n vector<Edge<T>> &operator[](int k) { return g.at(k); }\n const vector<Edge<T>> &operator[](int k) const { return g.at(k); }\n vector<Edge<T>> &at(int k) { return g.at(k); }\n const vector<Edge<T>> &at(int k) const { return g.at(k); }\n\n void add_edge(int src, int to, T cost = 1){\n g[src].emplace_back(src, to, cost, es);\n g[to].emplace_back(to, src, cost, es++);\n }\n void add_directed_edge(int src, int to, T cost = 1){\n g[src].emplace_back(src, to, cost, es++);\n }\n\n void read(int m, int base = 1, bool weighted = false, bool directed = false, const T &id = 1){\n for (int i = 0; i < m; i++){\n int u, v; cin >> u >> v; u -= base; v -= base;\n T c = id;\n if(weighted) cin >> c;\n if(directed) add_directed_edge(u, v, c);\n else add_edge(u, v, c);\n }\n }\n};\n\ntemplate<typename T>\nstruct CycleDetection{\n Graph<T> g;\n bool directed;\n vector<int> used;\n vector<Edge<T>> pre, cycle;\n CycleDetection(const Graph<T> &g, bool directed = true)\n : g(g), directed(directed), used(g.size()), pre(g.size()) {}\n\n vector<Edge<T>> find(){\n for(int i = 0; i < (int)g.size(); i++){\n if(used[i]==0 && dfs(i)){\n reverse(cycle.begin(), cycle.end());\n return cycle;\n }\n }\n return {};\n }\n\nprivate:\n bool dfs(int v, int q = -1){\n used[v] = 1;\n for(auto&&e : g[v]){\n if(e == q && !directed) continue;\n if(used[e] == 0){\n pre[e] = e;\n if(dfs(e, v)) return true;\n }else if(used[e] == 1){\n int p = v;\n while(p != e){\n cycle.emplace_back(pre[p]);\n p = pre[p].src;\n }\n cycle.emplace_back(e);\n return true;\n }\n }\n used[v] = 2;\n return false;\n }\n};\n\ntemplate<typename T> T Area(const Polygon<T> &ps, bool harf = true){\n if((int)ps.size() < 3) return 0;\n T res = Cross(ps.back(), ps.front());\n for(int i = 0; i < (int)ps.size()-1; i++){\n res += Cross(ps[i], ps[i+1]);\n }\n if(harf) res /= 2;\n return res;\n}\n\n\nstruct Solver{\n Solver(int n, int m): n(n), m(m) {}\n using ll = long long;\n\n int n, m;\n vector<Circle<ll>> cs;\n void solve(){\n cs.resize(n);\n for(auto&c : cs) cin >> c;\n\n Edges<int> es;\n int t = 0;\n for(int j = 0; j < n; ++j){\n for(int i = 0; i < j; ++i){\n if(cs[i].Intersect(cs[j]) < 4){\n es.emplace_back(i, j, 0, t++);\n }\n }\n }\n\n string ans;\n while(m--) ans += (check(es) ? \"YES \"s : \"NO \"s);\n ans.pop_back();\n cout << ans << \"\\n\";\n }\n\n void ci(int i){ //cout << i << \":\"; }\n }\n\n bool check(Edges<int> es){\n Point<ll> p, q; cin >> p >> q;\n bool fl = false;\n for(auto&c : cs){\n if((c.Contains(p) < 2) != (c.Contains(q) < 2)){\n ci(0);\n return false;\n }\n fl |= c.Contains(p) < 2;\n }\n if(fl){\n ci(1);\n return true;\n }\n\n while(true){\n Graph<int> g(n);\n for(auto&e : es) g.add_edge(e.src, e.to);\n\n CycleDetection cd(g, false);\n auto cy = cd.find();\n if(cy.empty()) break;\n\n int l = int(cy.size());\n Polygon<ll> ps(l);\n for(int i = 0; i < l; ++i) ps[i] = cs[cy[i].src].o;\n\n if(Area(ps, false) < 0) reverse(begin(ps), end(ps));\n\n if(Contains(ps, p) != Contains(ps, q)){\n ci(2);\n return false;\n }\n\n l = int(es.size());\n auto e = cy[0];\n fl = false;\n for(int i = 0; i < l; ++i){\n if((e.src == es[i].src && e.to == es[i].to) || (e.src == es[i].to && e.to == es[i].src)){\n es.erase(begin(es) + i);\n fl = true;\n break;\n }\n }\n assert(fl);\n }\n ci(3);\n return true;\n }\n};\n\nint main() {\n while(true){\n int n, m; cin >> n >> m;\n if(n == 0) return 0;\n Solver solver(n, m);\n solver.solve();\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3400, "score_of_the_acc": -0.0361, "final_rank": 2 }, { "submission_id": "aoj_1198_5949708", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i = 0; i < (n); i++)\nusing namespace std;\ntypedef long long ll;\nusing Real = double;\nusing Point = complex< Real >;\nusing Polygon = vector< Point >;\nconst Real EPS = 1e-6, PI = acos(-1);\nconstexpr int COUNTER_CLOCKWISE = +1;\nconstexpr int CLOCKWISE = -1;\nconstexpr int ONLINE_BACK = +2; // c-a-b\nconstexpr int ONLINE_FRONT = -2; // a-b-c\nconstexpr int ON_SEGMENT = 0; // a-c-b\n\nPoint operator*(const Point &p, const Real &d) {\n return Point(real(p) * d, imag(p) * d);\n}\n\nPoint operator/(const Point &p, const Real &d) {\n return Point(real(p) / d, imag(p) / d);\n}\n\nistream &operator>>(istream &is, Point &p) {\n Real a, b; is >> a >> b;\n p = Point(a, b);\n return is;\n}\n\nostream &operator<<(ostream &os, const Point &p) {\n return os << fixed << setprecision(10) << real(p) << \" \" << imag(p);\n}\n\nnamespace std {\n bool operator<(const Point &a, const Point &b) {\n return a.real() != b.real() ? a.real() < b.real() : a.imag() < b.imag();\n }\n}\n\n// 符号\ninline int sign(const Real &r) {\n return r <= -EPS ? -1 : r >= EPS ? 1 : 0;\n}\n\n// a = b ? \ninline bool equals(const Real &a, const Real &b) {\n return sign(a - b) == 0;\n}\n\n\n// 単位ベクトル\nPoint unitVec(const Point &a){ return a / abs(a); }\n\n// 法線ベクトル 半時計周り\nPoint normVec(const Point &a){ return a * Point(0, 1); }\n//Point normVec(const Point &a){ return a * Point(0,-1); }\n\n// 内積\nReal dot(const Point &a, const Point &b) {\n return (a.real() * b.real() + a.imag() * b.imag());\n}\n\n// 外積\nReal cross(const Point &a, const Point &b) {\n return (a.real() * b.imag() - a.imag() * b.real());\n}\n\nPoint rotate(const Point &p, const Real &theta) {\n return Point(cos(theta) * p.real() - sin(theta) * p.imag(),\n sin(theta) * p.real() + cos(theta) * p.imag());\n}\n\nReal Radian_To_Degree(const Real &radian){ return radian * 180.0 / PI; }\nReal Degree_To_Radian(const Real &degree){ return degree * PI / 180.0; }\n\nstruct Line {\n Point a, b;\n Line() = default;\n Line(Point a, Point b) : a(a), b(b) {}\n\n // Ax + By = C\n Line(Real A, Real B, Real C) {\n if(equals(A, 0)) {\n a = Point(0, C / B), b = Point(1, C / B);\n }else if(equals(B,0)) {\n b = Point(C / A, 0), b = Point(C / A, 1);\n }else{\n a = Point(0, C / B), b = Point(C / A, 0);\n }\n }\n\n friend ostream &operator<<(ostream &os, Line &p) {\n return os << p.a << \" \" << p.b;\n }\n\n friend istream &operator>>(istream &is, Line &a) {\n return is >> a.a >> a.b;\n }\n};\n\nstruct Segment : Line {\n Segment() = default;\n Segment(Point a, Point b) : Line(a, b) {}\n};\n\nstruct Circle {\n Point p;\n Real r;\n Circle() = default;\n Circle(Point p, Real r) : p(p), r(r) {}\n\n friend ostream &operator<<(ostream &os, Circle &c) {\n return os << c.p << \" \" << c.r;\n }\n\n friend istream &operator>>(istream &is, Circle &c) {\n return is >> c.p >> c.r;\n }\n};\n\n// 直線lに点pから引いた垂線の足を求める\nPoint projection(const Line &l, const Point &p) {\n Real t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\n\nPoint projection(const Segment &l, const Point &p) {\n Real t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + (l.a - l.b) * t;\n}\n\n// 直線lに関して点pと対称な点を求める\nPoint reflection(const Line &l, const Point &p) {\n return p + (projection(l, p) - p) * 2.0;\n}\n\n// 点の回転方向\n// 点aを基準に点b,cの位置関係\nint ccw(const Point &a, Point b, Point c) {\n b = b - a, c = c - a;\n if(sign(cross(b, c)) == +1) return COUNTER_CLOCKWISE; // 反時計回り\n if(sign(cross(b, c)) == -1) return CLOCKWISE; // 時計回り\n if(sign(dot(b, c)) == -1) return ONLINE_BACK; // c - a - b\n if(norm(b) < norm(c)) return ONLINE_FRONT; // a - b - c\n return ON_SEGMENT; // a - c - b\n}\n\n// 2直線の直交判定\nbool is_orthogonal(const Line &a, const Line &b) {\n return equals(dot(a.b - a.a, b.b - b.a), 0);\n}\n\n// 2直線の平行判定\nbool is_parallel(const Line &a, const Line &b) {\n return equals(cross(a.b - a.a, b.b - b.a), 0);\n}\n\n// 線分の交差判定\nbool is_intersect_ss(const Segment &s, const Segment &t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\n// 直線の交差判定\nbool is_intersect_ll(const Line &l, const Line &m) {\n Real A = cross(l.b - l.a, m.b - m.a);\n Real B = cross(l.b - l.a, l.b - m.a);\n if(equals(abs(A), 0) && equals(abs(B), 0)) return true;\n return !is_parallel(l, m);\n}\n\n// 線分に点が乗っているか\nbool is_intersect_sp(const Segment &s, const Point &p) {\n return ccw(s.a, s.b, p) == ON_SEGMENT;\n}\n\n// 点と点の距離\nReal distance_pp(const Point &p1, const Point &p2) {\n return sqrt(pow(real(p1)-real(p2), 2) + pow(imag(p1)-imag(p2), 2));\n}\n\n// 点と直線の距離\nReal distance_lp(const Line &l, const Point &p) {\n return abs(p - projection(l, p));\n}\n\n// 直線と直線の距離\nReal distance_ll(const Line &l, const Line &m) {\n return is_intersect_ll(l, m) ? 0 : distance_lp(l, m.a);\n}\n\n// 点と線分の距離\nReal distance_sp(const Segment &s, const Point &p) {\n Point r = projection(s, p);\n if(is_intersect_sp(s, r)) return abs(r - p);\n return min(abs(s.a - p), abs(s.b - p));\n}\n\n// 線分と線分の距離\nReal distance_ss(const Segment &a, const Segment &b) {\n if(is_intersect_ss(a, b)) return 0;\n return min({distance_sp(a, b.a), distance_sp(a, b.b), distance_sp(b, a.a), distance_sp(b, a.b)});\n}\n\n// 交点\nPoint cross_point_ll(const Line &l, const Line &m) {\n Real A = cross(l.b - l.a, m.b - m.a);\n Real B = cross(l.b - l.a, l.b - m.a);\n if(equals(abs(A), 0) && equals(abs(B), 0)) return m.a;\n return m.a + (m.b - m.a) * B / A;\n}\n\n// 円と円の位置関係\nint intersect(Circle c1, Circle c2) {\n Real d = abs(c1.p - c2.p);\n return abs(c1.r - c2.r) - EPS < d && d < c1.r + c2.r + EPS;\n}\n\nReal area(const Polygon &p){\n Real A = 0;\n for(int i = 0; i < p.size(); i++){\n A += cross(p[i], p[(i + 1) % p.size()]);\n }\n return A * 0.5;\n}\n\nbool is_convex(const Polygon &p){\n for(int i = 0; i < p.size(); i++){\n if(ccw(p[(i + p.size() - 1) % p.size()], p[i], p[(i + 1) % p.size()]) == -1) return false;\n }\n return true;\n}\n\nenum { OUT, ON, IN };\nint contains(const Polygon &Q, const Point &p){\n bool in = false;\n for(int i = 0; i < Q.size(); i++){\n Point a = Q[i] - p, b = Q[(i + 1) % Q.size()] - p;\n if(a.imag() > b.imag()) swap(a, b);\n if(a.imag() <= 0 && 0 < b.imag() && cross(a, b) < 0) in = !in;\n if(cross(a, b) == 0 && dot(a, b) <= 0) return ON;\n }\n return in ? IN : OUT;\n}\n\nPolygon convex_hull(Polygon &p, bool strict = true){\n int n = (int)p.size(), k = 0;\n if(n <= 2) return p;\n sort(p.begin(), p.end());\n Polygon ch(2 * n);\n for(int i = 0; i < n; ch[k++] = p[i++]){\n while(k >= 2 && cross(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1]) < 0) --k;\n }\n for(int i = n - 2, t = k + 1; i >= 0; ch[k++] = p[i--]){\n while(k >= t && cross(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1]) < 0) --k;\n }\n ch.resize(k - 1);\n return ch;\n}\n\nReal convex_diameter(const Polygon &p){\n int n = (int)p.size();\n int is = 0, js = 0;\n for(int i = 1; i < n; i++){\n if(p[i].imag() > p[is].imag()) is = i;\n if(p[i].imag() < p[js].imag()) js = i;\n }\n Real maxdis = norm(p[is] - p[js]);\n int maxi, maxj, i, j;\n i = maxi = is;\n j = maxj = js;\n do {\n if(cross(p[(i + 1) % n] - p[i], p[(j + 1) % n] - p[j]) >= 0){\n j = (j + 1) % n;\n }else{\n i = (i + 1) % n;\n }\n\n if(norm(p[i] - p[j]) > maxdis){\n maxdis = norm(p[i] - p[j]);\n maxi = i;\n maxj = j;\n }\n\n }while(i != is || j != js);\n return sqrt(maxdis);\n}\n\nPolygon convex_cut(const Polygon &U, Line l){\n Polygon ret;\n for(int i = 0; i < U.size(); i++){\n Point now = U[i], nxt = U[(i + 1) % U.size()];\n if(ccw(l.a, l.b, now) != -1) ret.push_back(now);\n if(ccw(l.a, l.b, now) * ccw(l.a, l.b, nxt) < 0){\n ret.push_back(cross_point_ll(Line(now, nxt), l));\n }\n }\n return ret;\n}\n\nReal ClosetPair(Polygon& ps){\n if(ps.size() <= 1) throw (0);\n sort(begin(ps), end(ps));\n\n auto compare_y = [&](const Point &a, const Point &b) {\n return a.imag() < b.imag();\n };\n Polygon beet(ps.size());\n const double INF = 1e18;\n\n function< double(int, int) > rec = [&](int left, int right) {\n if(right - left <= 1) return INF;\n int mid = (left + right) >> 1;\n auto x = ps[mid].real();\n auto ret = min(rec(left, mid), rec(mid, right));\n inplace_merge(begin(ps) + left, begin(ps) + mid, begin(ps) + right, compare_y);\n int ptr = 0;\n for(int i = left; i < right; i++) {\n if(fabs((ps[i].real()) - x) >= ret) continue;\n for(int j = 0; j < ptr; j++) {\n auto luz = ps[i] - beet[ptr - j - 1];\n if(luz.imag() >= ret) break;\n ret = min(ret, abs(luz));\n }\n beet[ptr++] = ps[i];\n }\n return ret;\n };\n return rec(0, (int) ps.size());\n}\n\npair< Point, Point > cross_point_cc(const Circle &c1, const Circle &c2) {\n Real d = abs(c1.p - c2.p);\n Real a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d));\n Real t = atan2(c2.p.imag() - c1.p.imag(), c2.p.real() - c1.p.real());\n Point p1 = c1.p + Point(cos(t + a) * c1.r, sin(t + a) * c1.r);\n Point p2 = c1.p + Point(cos(t - a) * c1.r, sin(t - a) * c1.r);\n return {p1, p2};\n}\n\nconst int BOTTOM = 0;\nconst int LEFT = 1;\nconst int RIGHT = 2;\nconst int TOP = 3;\n\nclass endPoint {\n public:\n Point p;\n int seg; // id of Point\n int st; // kind of Point\n endPoint(){}\n endPoint(Point inp, int inseg, int inst):p(inp),seg(inseg),st(inst){}\n bool operator<(const endPoint &ep)const {\n if(p.imag() == ep.p.imag()) return st < ep.st;\n else return p.imag() < ep.p.imag();\n }\n};\n\nendPoint EP[220000];\nint Manhattan_Intersections(vector< Segment > s){\n int n = s.size();\n double hoge;\n\n for(int i = 0, k = 0; i < n; i++){\n if(s[i].a.imag() == s[i].b.imag()){\n if(s[i].a.real() > s[i].b.real()){\n hoge = s[i].a.real();\n s[i].a.real(s[i].b.real());\n s[i].b.real(hoge);\n }\n }else if(s[i].a.imag() > s[i].b.imag()){\n hoge = s[i].a.imag();\n s[i].a.imag(s[i].b.imag());\n s[i].b.imag(hoge);\n }\n\n if(s[i].a.imag() == s[i].b.imag()){\n EP[k++] = endPoint(s[i].a, i, LEFT);\n EP[k++] = endPoint(s[i].b, i, RIGHT);\n }else{\n EP[k++] = endPoint(s[i].a, i, BOTTOM);\n EP[k++] = endPoint(s[i].b, i, TOP);\n }\n }\n\n sort(EP, EP + 2 * n);\n set<int> BT;\n BT.insert(1000000001);\n int cnt = 0;\n for(int i = 0; i < 2 * n; i++){\n if(EP[i].st == TOP) BT.erase(EP[i].p.real());\n else if(EP[i].st == BOTTOM) BT.insert(EP[i].p.real());\n else if(EP[i].st == LEFT){\n set<int>::iterator b = lower_bound(BT.begin(), BT.end(), s[EP[i].seg].a.real());\n set<int>::iterator e = upper_bound(BT.begin(), BT.end(), s[EP[i].seg].b.real());\n cnt += distance(b, e);\n }\n }\n\n return cnt;\n}\n\n// 内接円\nCircle Inscribed_Circle(const Point& a, const Point& b, const Point& c){\n double A = abs(b - c), B = abs(c - a), C = abs(a - b);\n Point x = Point((a * A + b * B + c * C) / (A + B + C));\n double r = distance_sp(Segment(a,b),x);\n return Circle(x, r);\n}\n\n// 外接円\nCircle Circumscribed_Circle(const Point& a, const Point& b, const Point& c){\n Point m1((a+b)/2.0), m2((b+c)/2.0);\n Point v((b-a).imag(), (a-b).real()), w((b-c).imag(), (c-b).real());\n Line s(m1, Point(m1+v)), t(m2, Point(m2+w));\n const Point x = cross_point_ll(s, t);\n return Circle(x, abs(a-x));\n}\n\npair< Point, Point > cross_point_cl(const Circle &c, const Line &l) {\n Point pr = projection(l, c.p);\n if(equals(abs(pr - c.p), c.r)) return {pr, pr};\n Point e = (l.b - l.a) / abs(l.b - l.a);\n auto k = sqrt(norm(c.r) - norm(pr - c.p));\n return {pr - e * k, pr + e * k};\n}\n\n// 点pを通る円の接線\npair<Point,Point> tangent_cp(const Circle &c, const Point &p) {\n return cross_point_cc(c, Circle(p, sqrt(norm(c.p - p) - c.r * c.r)));\n}\n\n// 二つの円の共通接線\nvector< Line > tangent_cc(Circle c1, Circle c2){\n vector< Line > ret;\n if(c1.r < c2.r) swap(c1,c2);\n double g = norm(c1.p-c2.p);\n if(equals(g,0.0)) return ret;\n Point u = (c2.p-c1.p)/sqrt(g);\n Point v = rotate(u, PI * 0.5);\n for(int s:{-1,1}){\n double h = (c1.r+ s*c2.r)/sqrt(g);\n if(equals(1- h*h, 0)){\n ret.emplace_back(c1.p+u*c1.r, c1.p+(u+v)*c1.r);\n }else if(1-h*h > 0){\n Point uu = u*h, vv = v*sqrt(1-h*h);\n ret.emplace_back(c1.p+(uu+vv)*c1.r, c2.p-(uu+vv)*c2.r*s);\n ret.emplace_back(c1.p+(uu-vv)*c1.r, c2.p-(uu-vv)*c2.r*s);\n }\n }\n return ret;\n}\n\nReal area_poly_c(const Polygon &p, const Circle &c) {\n if(p.size() < 3) return 0.0;\n function< Real(Circle, Point, Point) > cross_area = [&](const Circle &c, const Point &a, const Point &b) {\n Point va = c.p - a, vb = c.p - b;\n Real f = cross(va, vb), ret = 0.0;\n if(equals(f, 0.0)) return ret;\n if(max(abs(va), abs(vb)) < c.r + EPS) return f;\n if(distance_sp(Segment(a, b), c.p) > c.r - EPS) return c.r * c.r * arg(vb * conj(va));\n auto u = cross_point_cl(c, Segment(a, b));\n vector< Point > tot{a, u.first, u.second, b};\n for(int i = 0; i + 1 < tot.size(); i++) {\n ret += cross_area(c, tot[i], tot[i + 1]);\n }\n return ret;\n };\n Real A = 0;\n for(int i = 0; i < p.size(); i++) {\n A += cross_area(c, p[i], p[(i + 1) % p.size()]);\n }\n return A;\n}\n\nReal area_cc(const Circle &c1, const Circle &c2) {\n Real d = abs(c1.p - c2.p);\n if(c1.r + c2.r <= d + EPS) return 0.0;\n if(d <= fabs(c1.r - c2.r) + EPS) {\n Real r = min(c1.r, c2.r);\n return r * r * PI;\n }\n Real rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n Real theta = acos(rc / c1.r);\n Real phi = acos((d - rc) / c2.r);\n return (c1.r * c1.r*theta + c2.r*c2.r*phi - d*c1.r*sin(theta));\n}\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n\n while(true) {\n int n,m; cin >> n >> m; if(n == 0 && m == 0) break;\n vector< Circle > Cs(n);\n rep(i,n) cin >> Cs[i];\n\n vector<string> ans;\n auto push = [&](string s){ ans.push_back(s); };\n\n rep(_,m) {\n Point p,q; cin >> p >> q;\n vector<int> id_p, id_q;\n rep(i,n) {\n if(abs(Cs[i].p - p) <= Cs[i].r) id_p.push_back(i);\n if(abs(Cs[i].p - q) <= Cs[i].r) id_q.push_back(i);\n }\n sort(id_p.begin(), id_p.end());\n sort(id_q.begin(), id_q.end());\n if(id_p.size() > 0 || id_q.size() > 0) {\n push(id_p == id_q ? \"YES\" : \"NO\"); continue;\n }\n vector<vector<int>> G(n);\n rep(i,n)rep(j,n)if(i < j) {\n if(intersect(Cs[i], Cs[j])) {\n G[i].push_back(j);\n G[j].push_back(i);\n }\n }\n\n bool ok = true;\n while(true) {\n vector<int> r(n, -1), f(n, -1), d(n, 0);\n auto search = [&](void) {\n function<void(int,int)> dfs = [&](int x, int v) -> void {\n r[v] = x;\n for(int to : G[v]) if(r[to] == -1) {\n d[to] = d[v] + 1;\n f[to] = v;\n dfs(x, to);\n } \n };\n\n rep(i,n) if(f[i] == -1) dfs(i, i);\n rep(i,n) {\n for(int to : G[i]) {\n if(r[i] == r[to] && d[to] - d[i] > 1) {\n vector<int> res;\n for(int v = to; v != i; v = f[v]) res.push_back(v);\n res.push_back(i);\n return res;\n }\n }\n }\n return vector<int>();\n };\n\n auto c = search();\n if(c.size() == 0) break;\n vector< Point > poly(c.size());\n rep(i,c.size()) poly[i] = Cs[c[i]].p;\n if(contains(poly, p) != contains(poly, q)) ok = false;\n\n rep(i,G[c[0]].size()) {\n if(G[c[0]][i] == c[1]) {\n G[c[0]].erase(G[c[0]].begin() + i); break;\n }\n }\n rep(i,G[c[1]].size()) {\n if(G[c[1]][i] == c[0]) {\n G[c[1]].erase(G[c[1]].begin() + i); break;\n }\n }\n }\n push(ok ? \"YES\" : \"NO\");\n }\n rep(i,m) { if(i) cout << \" \"; cout << ans[i]; } cout << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 8652, "score_of_the_acc": -1.0138, "final_rank": 18 }, { "submission_id": "aoj_1198_5903181", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n//geometry library by maine\n\n//basic\nusing Real = double;\nusing Point = complex<Real>;\n#define x real()\n#define y imag()\nconst Real EPS = 1e-8, PI = acos(-1), INF = 1e10;\n\nistream& operator>>(istream& is, Point& p) {\n Real a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n}\nostream& operator<<(ostream& os, Point p) {\n return os << fixed << setprecision(10) << p.x << \" \" << p.y;\n}\n\nPoint operator*(const Point& p, const Real& d) { return Point(p.x * d, p.y * d); }\n\nbool eq(const Real& r, const Real& s) { return abs(r - s) < EPS; }\nbool eq(const Point& p, const Point& q) { return abs(p - q) < EPS; }\n\nnamespace std {\nbool operator<(const Point& a, const Point& b) {\n return !eq(a.x, b.x) ? a.x < b.x : a.y < b.y;\n}\n} // namespace std\n\nReal get_angle(const Point& a, const Point& b, const Point& c) {\n return arg((c - a) / (b - a));\n}\n\ninline int inc(int i, int N) {\n return (i == N - 1 ? 0 : i + 1);\n}\ninline int dec(int i, int N) {\n return (i == 0 ? N - 1 : i - 1);\n}\n\n//unit vector\nPoint e(const Point& p) { return p / abs(p); }\n\n//angle transformation\nReal radian_to_degree(Real r) { return r * 180.0 / PI; }\nReal degree_to_radian(Real d) { return d * PI / 180.0; }\n\n//basic functions\nReal dot(const Point& p, const Point& q) { return p.x * q.x + p.y * q.y; }\nReal cross(const Point& p, const Point& q) { return p.x * q.y - p.y * q.x; }\nPoint rotate(const Real& theta, const Point& p) {\n return {cos(theta) * p.x - sin(theta) * p.y, sin(theta) * p.x + cos(theta) * p.y};\n}\nPoint rotate90(const Point& p) {\n return {-p.y, p.x};\n}\n\n//structs : Line, Segment, Circle\nstruct Line {\n Point a, b;\n Line() = default;\n Line(Point a, Point b) : a(a), b(b) {}\n Point d() const { return e(b - a); } //direction vector\n Point n() const {\n Point dd = d();\n return {dd.y, -dd.x};\n } //normal vector\n};\nstruct Segment : Line {\n Segment() = default;\n Segment(Point a, Point b) : Line(a, b) {}\n};\nstruct Circle {\n Point p;\n Real r;\n Circle() = default;\n Circle(Point p, Real r) : p(p), r(r){};\n};\nusing Points = vector<Point>;\nusing Polygon = vector<Point>;\nusing Polygons = vector<Polygon>;\nusing Lines = vector<Line>;\nusing Segments = vector<Segment>;\nusing Circles = vector<Circle>;\n\n//happy functions\n//https://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_C\nint ccw(const Point& a, const Point& bb, const Point& cc) {\n Point b = bb - a, c = cc - a;\n if (cross(b, c) > EPS)\n return 1; //COUNTER_CLOCKWISE\n if (cross(b, c) < -EPS)\n return -1; //CLOCKWISE\n if (dot(b, c) < 0)\n return 2; //ONLINE_BACK c-a-b\n if (norm(b) < norm(c))\n return -2; //ONLINE_FRONT a-b-c\n return 0; //ON_SEGMENT a-c-b\n}\n\nbool parallel(const Line& l, const Line& m) { return eq(cross(l.d(), m.d()), 0.0); }\nbool orthogonal(const Line& l, const Line& m) { return eq(dot(l.d(), m.d()), 0.0); }\nPoint projection(const Line& l, const Point& p) { return l.a + (l.a - l.b) * (dot(p - l.a, l.a - l.b) / norm(l.a - l.b)); }\nPoint reflection(const Line& l, const Point& p) { return p + (projection(l, p) - p) * 2.0; }\n\n//intersect\nbool intersect(const Line& l, const Point& p) { return abs(ccw(l.a, l.b, p)) != 1; }\nbool intersect(const Line& l, const Line& m) { return !parallel(l, m) || (parallel(l, m) && intersect(l, m.a)); }\nbool intersect(const Segment& s, const Point& p) { return ccw(s.a, s.b, p) == 0; }\nbool intersect(const Line& l, const Segment& s) { return cross(l.d(), s.a - l.a) * cross(l.d(), s.b - l.a) < EPS; }\nbool intersect(const Segment& s, const Segment& t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 && ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\nbool intersect_onsegment(const Segment& s, const Point& p) { return intersect(s, p) && !eq(s.a, p) && !eq(s.b, p); }\n\n//distance\nReal distance(const Point& p, const Point& q) { return abs(p - q); }\nReal distance(const Line& l, const Point& p) { return distance(p, projection(l, p)); }\nReal distance(const Line& l, const Line& m) { return intersect(l, m) ? 0 : distance(l, m.a); }\nReal distance(const Segment& s, const Point& p) {\n Point q = projection(s, p);\n return intersect(s, q) ? distance(p, q) : min(distance(s.a, p), distance(s.b, p));\n}\nReal distance(const Segment& s, const Segment& t) { return intersect(s, t) ? 0 : min({distance(s, t.a), distance(s, t.b), distance(t, s.a), distance(t, s.b)}); }\nReal distance(const Line& l, const Segment& s) { return intersect(l, s) ? 0 : min(distance(l, s.a), distance(l, s.b)); }\n\n//intersect circle\nbool intersect(const Circle& c, const Point& p) { return eq(distance(c.p, p), c.r); }\nbool intersect(const Circle& c, const Line& l) { return distance(l, c.p) <= c.r + EPS; }\nint intersect(const Circle& c, const Segment& s) {\n if (!intersect(c, Line(s)))\n return 0;\n Real da = distance(c.p, s.a), db = distance(c.p, s.b);\n if (da < c.r + EPS && db < c.r + EPS)\n return 0;\n if (da > db)\n swap(da, db);\n if (da < c.r - EPS && db > c.r + EPS)\n return 1;\n if (intersect(s, projection(s, c.p)))\n return 2;\n return 0;\n}\nint intersect(Circle c1, Circle c2) {\n if (c1.r < c2.r)\n swap(c1, c2);\n Real d = distance(c1.p, c2.p);\n if (c1.r + c2.r < d)\n return 4;\n if (eq(c1.r + c2.r, d))\n return 3;\n if (c1.r - c2.r < d)\n return 2;\n if (eq(c1.r - c2.r, d))\n return 1;\n return 0;\n}\n\n//crosspoint\nPoint crosspoint(const Line& l, const Line& m) {\n Real A = cross(l.b - l.a, m.b - m.a);\n Real B = cross(l.b - l.a, l.b - m.a);\n if (eq(abs(A), 0.0) && eq(abs(B), 0.0))\n return m.a;\n return m.a + (m.b - m.a) * B / A;\n}\nPoint crosspoint(const Segment& s, const Segment& t) { return crosspoint(Line(s), Line(t)); }\npair<Point, Point> crosspoint(const Circle& c, const Line& l) {\n Point p = projection(l, c.p);\n if (eq(distance(l, c.p), c.r))\n return {p, p};\n Real len = sqrt(c.r * c.r - norm(p - c.p));\n return {p - len * l.d(), p + len * l.d()};\n}\npair<Point, Point> crosspoint(const Circle& c, const Segment& s) {\n Line l(s);\n if (intersect(c, s) == 2)\n return crosspoint(c, l);\n auto ret = crosspoint(c, l);\n if (dot(s.a - ret.first, s.b - ret.first) < 0)\n ret.second = ret.first;\n else\n ret.first = ret.second;\n return ret;\n}\npair<Point, Point> crosspoint(const Circle& c1, const Circle& c2) {\n Real d = distance(c1.p, c2.p);\n Real a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d));\n Real t = atan2(c2.p.y - c1.p.y, c2.p.x - c1.p.x);\n Point p1 = c1.p + Point(cos(t + a) * c1.r, sin(t + a) * c1.r);\n Point p2 = c1.p + Point(cos(t - a) * c1.r, sin(t - a) * c1.r);\n return {p1, p2};\n}\n\n//tangent\npair<Point, Point> tangent(const Circle& c, const Point& p) {\n return crosspoint(c, Circle(p, sqrt(norm(c.p - p) - c.r * c.r)));\n}\nLines tangent(Circle c1, Circle c2) {\n Lines ret;\n if (c1.r < c2.r)\n swap(c1, c2);\n if (eq(c1.p, c2.p))\n return ret;\n Real g = norm(c1.p - c2.p);\n Point u = (c2.p - c1.p) / sqrt(g);\n Point v = rotate(PI / 2, u);\n for (int s : {-1, 1}) {\n Real h = (c1.r + s * c2.r) / sqrt(g);\n if (eq(1 - h * h, 0)) {\n ret.emplace_back(c1.p + u * c1.r, c1.p + (u + v) * c1.r);\n } else if (1 - h * h > 0) {\n Point uu = u * h, vv = v * sqrt(1 - h * h);\n ret.emplace_back(c1.p + (uu + vv) * c1.r, c2.p - (uu + vv) * c2.r * s);\n ret.emplace_back(c1.p + (uu - vv) * c1.r, c2.p - (uu - vv) * c2.r * s);\n }\n }\n return ret;\n}\n\n//convex\n//https://onlinejudge.u-aizu.ac.jp/courses/library/4/CGL/3/CGL_3_B\nbool is_convex(const Polygon& P) {\n int N = (int)P.size();\n for (int i = 0; i < N; i++) {\n if (ccw(P[i], P[(i + 1) % N], P[(i + 2) % N]) == -1)\n return false;\n }\n return true;\n}\n//https://onlinejudge.u-aizu.ac.jp/courses/library/4/CGL/4/CGL_4_A\nPolygon convex_hull(Points P) {\n int N = (int)P.size(), k = 0;\n if (N <= 2)\n return P;\n sort(begin(P), end(P));\n Points ret(2 * N);\n for (int i = 0; i < N; ret[k++] = P[i++]) {\n while (k >= 2 && cross(ret[k - 1] - ret[k - 2], P[i] - ret[k - 1]) < EPS)\n --k;\n }\n for (int i = N - 2, t = k + 1; i >= 0; ret[k++] = P[i--]) {\n while (k >= t && cross(ret[k - 1] - ret[k - 2], P[i] - ret[k - 1]) < EPS)\n --k;\n }\n ret.resize(k - 1);\n return ret;\n}\n//https://onlinejudge.u-aizu.ac.jp/courses/library/4/CGL/4/CGL_4_B\nReal convex_diameter(const Polygon& P) {\n int N = (int)P.size();\n int is = 0, js = 0;\n for (int i = 1; i < N; i++) {\n if (P[i].y < P[is].y)\n is = i;\n if (P[i].y > P[js].y)\n js = i;\n }\n Real maxdist = norm(P[is] - P[js]);\n int maxi, maxj, i, j;\n maxi = i = is;\n maxj = j = js;\n do {\n if (cross(P[inc(i, N)] - P[i], P[inc(j, N)] - P[j]) >= 0)\n j = inc(j, N);\n else\n i = inc(i, N);\n if (norm(P[i] - P[j]) > maxdist) {\n maxdist = norm(P[i] - P[j]);\n maxi = i;\n maxj = j;\n }\n } while (i != is || j != js);\n maxi = maxi;\n maxj = maxj;\n return sqrt(maxdist);\n}\n//https://onlinejudge.u-aizu.ac.jp/courses/library/4/CGL/4/CGL_4_C\nPolygon convex_cut(const Polygon& P, const Line& l) {\n Polygon ret;\n int N = (int)P.size();\n for (int i = 0; i < N; i++) {\n Point now = P[i], nxt = P[(inc(i, N))];\n if (ccw(l.a, l.b, now) != -1)\n ret.emplace_back(now);\n if (ccw(l.a, l.b, now) * ccw(l.a, l.b, nxt) == -1)\n ret.emplace_back(crosspoint(Line(now, nxt), l));\n }\n return ret;\n}\n\n//other\nenum\n{\n OUT,\n ON,\n IN\n};\n\n//https://onlinejudge.u-aizu.ac.jp/courses/library/4/CGL/3/CGL_3_C\nint contains(const Polygon& Q, const Point& p) {\n bool in = false;\n int N = (int)Q.size();\n for (int i = 0; i < N; i++) {\n Point a = Q[i] - p, b = Q[(i + 1) % N] - p;\n if (a.y > b.y)\n swap(a, b);\n if (a.y <= 0 && 0 < b.y && cross(a, b) < 0)\n in = !in;\n if (cross(a, b) == 0 && dot(a, b) <= 0)\n return ON;\n }\n return in ? IN : OUT;\n}\n\n//https://onlinejudge.u-aizu.ac.jp/courses/library/4/CGL/3/CGL_3_A\nReal area(const Polygon& P) {\n Real A = 0;\n for (int i = 0; i < (int)P.size(); i++) {\n A += cross(P[i], P[(i + 1) % P.size()]);\n }\n return A * 0.5;\n}\n\n//https://onlinejudge.u-aizu.ac.jp/courses/library/4/CGL/7/CGL_7_H\nReal cross_area(const Circle& c, const Point& a, const Point& b) {\n Point va = c.p - a, vb = c.p - b;\n Real f = cross(va, vb), ret = 0.0;\n if (eq(f, 0.0))\n return ret;\n if (max(abs(va), abs(vb)) < c.r + EPS)\n return f;\n if (distance(Segment(a, b), c.p) > c.r - EPS)\n return c.r * c.r * arg(vb * conj(va));\n auto u = crosspoint(c, Segment(a, b));\n vector<Point> V{a, u.first, u.second, b};\n for (int i = 0; i < (int)V.size() - 1; i++) {\n ret += cross_area(c, V[i], V[i + 1]);\n }\n return ret;\n}\nReal area(const Polygon& p, const Circle& c) {\n int N = (int)p.size();\n if (N < 3)\n return 0.0;\n Real ret = 0;\n for (int i = 0; i < N; i++) {\n ret += cross_area(c, p[i], p[inc(i, N)]);\n }\n return ret / 2.0;\n}\n\n//https://onlinejudge.u-aizu.ac.jp/problems/CGL_5_A\nReal closest_pair(Points& P, int left, int right) {\n if (right - left <= 1)\n return 1e18;\n int mid = (left + right) / 2;\n Real xx = P[mid].x;\n Real dist = min(closest_pair(P, left, mid), closest_pair(P, mid, right));\n inplace_merge(P.begin() + left, P.begin() + mid, P.begin() + right, [&](const Point& a, const Point& b) { return a.y < b.y; });\n Points memo;\n memo.reserve(right - left);\n for (int i = left; i < right; i++) {\n if (abs(P[i].x - xx) >= dist)\n continue;\n for (int j = (int)memo.size() - 1; j >= 0; j--) {\n if (P[i].y - memo[j].y >= dist)\n break;\n dist = min(dist, distance(P[i], memo[j]));\n }\n memo.emplace_back(P[i]);\n }\n return dist;\n}\nReal closest_pair(Points P) {\n sort(begin(P), end(P));\n return closest_pair(P, 0, (int)P.size());\n}\n\n//https://onlinejudge.u-aizu.ac.jp/courses/library/4/CGL/7/CGL_7_B\nCircle incircle(Polygon P) {\n assert((int)P.size() == 3);\n Real l0 = distance(P[1], P[2]), l1 = distance(P[0], P[2]), l2 = distance(P[0], P[1]);\n Circle c;\n c.p = crosspoint(Line(P[0], (P[1] * l1 + P[2] * l2) / (l1 + l2)), Line(P[1], (P[0] * l0 + P[2] * l2) / (l0 + l2)));\n c.r = distance(Line(P[0], P[1]), c.p);\n return c;\n}\n\n//https://onlinejudge.u-aizu.ac.jp/courses/library/4/CGL/7/CGL_7_C\nCircle circumcircle(Polygon P) {\n assert((int)P.size() == 3);\n Circle c;\n c.p = crosspoint(Line((P[0] + P[1]) / 2.0, (P[0] + P[1]) / 2.0 + rotate90(P[0] - P[1])),\n Line((P[0] + P[2]) / 2.0, (P[0] + P[2]) / 2.0 + rotate90(P[0] - P[2])));\n c.r = distance(c.p, P[0]);\n return c;\n}\n\n#undef x\n#undef y\n\nstruct UF {\n vector<int> data;\n UF(int n) : data(n, -1) {}\n int root(int k) {\n if (data[k] < 0)\n return k;\n return data[k] = root(data[k]);\n }\n bool unite(int x, int y) {\n x = root(x), y = root(y);\n if (x == y)\n return false;\n if (data[x] > data[y])\n swap(x, y);\n data[x] += data[y];\n data[y] = x;\n return true;\n }\n bool same(int x, int y) {\n return root(x) == root(y);\n }\n int size(int k) { return -data[root(k)]; }\n};\n\n\nint main() {\n int N, M;\n while (cin >> N >> M, N) {\n Circles C(N);\n for (auto&& c : C) {\n cin >> c.p >> c.r;\n }\n vector<vector<double>> ang(N);\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < i; j++) {\n auto &c1 = C[i], &c2 = C[j];\n if (intersect(c1, c2) == 2) {\n auto [p1, p2] = crosspoint(c1, c2);\n ang[i].emplace_back(arg(p1 - c1.p));\n ang[i].emplace_back(arg(p2 - c1.p));\n ang[j].emplace_back(arg(p1 - c2.p));\n ang[j].emplace_back(arg(p2 - c2.p));\n }\n }\n }\n int n = 0;\n vector<int> Vidx;\n for (auto&& V : ang) {\n for (auto&& x : V) {\n if (eq(-PI, x))\n x = PI;\n }\n if (V.size() == 0)\n V.emplace_back(0);\n sort(begin(V), end(V));\n Vidx.emplace_back(n);\n n += (int)V.size();\n }\n UF uf(n * 2);\n\n auto f = [&](int i, int j, bool outer) {\n j += (int)ang[i].size();\n if (j >= (int)ang[i].size())\n j %= (int)ang[i].size();\n return (Vidx[i] + j) * 2 + (int)outer;\n };\n\n vector<bool> canconnectin(n * 2, true);\n vector<bool> canconnectout(n * 2, true);\n\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (i == j)\n continue;\n auto c1 = C[i], c2 = C[j];\n if (intersect(c1, c2) == 2) {\n auto p = crosspoint(c1, c2).first;\n double a1 = arg(p - c1.p), a2 = arg(p - c2.p);\n if (eq(a1, -PI))\n a1 = PI;\n if (eq(a2, -PI))\n a2 = PI;\n int idx1 = lower_bound(cbegin(ang[i]), cend(ang[i]), a1 - EPS) - cbegin(ang[i]);\n int idx2 = lower_bound(cbegin(ang[j]), cend(ang[j]), a2 - EPS) - cbegin(ang[j]);\n uf.unite(f(i, idx1, true), f(j, idx2, false));\n uf.unite(f(i, idx1 + 1, true), f(j, idx2, true));\n uf.unite(f(i, idx1 + 1, false), f(j, idx2 + 1, true));\n uf.unite(f(i, idx1, false), f(j, idx2 + 1, false));\n canconnectin[f(i, idx1, false)] = false;\n canconnectout[f(i, idx1, true)] = false;\n canconnectin[f(j, idx2 + 1, false)] = false;\n canconnectin[f(j, idx2 + 1, true)] = false;\n }\n }\n }\n\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (i == j)\n continue;\n auto c1 = C[i], c2 = C[j];\n if (intersect(c1, c2) == 0 && c1.r > c2.r) {\n for (int idx1 = 0; idx1 < (int)ang[i].size(); idx1++) {\n for (int idx2 = 0; idx2 < (int)ang[j].size(); idx2++) {\n int f1 = f(i, idx1, false);\n int f2 = f(j, idx2, true);\n if (canconnectin[f1] && canconnectin[f2])\n uf.unite(f1, f2);\n }\n }\n }\n\n if (intersect(c1, c2) == 4) {\n Line L{c1.p, c2.p};\n Point p1 = crosspoint(c1, L).second;\n Point p2 = crosspoint(c2, L).first;\n Segment S{p1, p2};\n int cnt = 0;\n for (auto&& c : C) {\n cnt += intersect(c, S);\n }\n if (cnt == 0) {\n double a1 = arg(p1 - c1.p), a2 = arg(p2 - c2.p);\n if (eq(a1, -PI))\n a1 = PI;\n if (eq(a2, -PI))\n a2 = PI;\n int idx1 = lower_bound(cbegin(ang[i]), cend(ang[i]), a1 - EPS) - cbegin(ang[i]);\n int idx2 = lower_bound(cbegin(ang[j]), cend(ang[j]), a2 - EPS) - cbegin(ang[j]);\n uf.unite(f(i, idx1, true), f(j, idx2, true));\n }\n }\n }\n }\n\n vector<bool> ans;\n\n while (M--) {\n Point p, q;\n cin >> p >> q;\n\n auto find = [&](Point p) {\n vector<pair<double, int>> V;\n for (int i = 0; i < N; i++) {\n auto c = C[i];\n V.emplace_back(abs(distance(p, c.p) - c.r), i);\n }\n auto [d, i] = *min_element(cbegin(V), cend(V));\n auto c = C[i];\n bool outer = distance(p, c.p) >= c.r;\n double a = arg(p - c.p);\n if (eq(a, -PI))\n a = PI;\n int idx = lower_bound(cbegin(ang[i]), cend(ang[i]), a - EPS) - cbegin(ang[i]);\n return f(i, idx, outer);\n };\n\n ans.emplace_back(uf.same(find(p), find(q)));\n }\n\n for (int i = 0; i < ans.size(); i++) {\n cout << (ans[i] ? \"YES\" : \"NO\") << \" \\n\"[i == ans.size() - 1];\n }\n }\n}", "accuracy": 1, "time_ms": 1460, "memory_kb": 3900, "score_of_the_acc": -1.1154, "final_rank": 19 }, { "submission_id": "aoj_1198_5633420", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst double EPS = 0.0001;\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n point operator -(point P){\n return point(x - P.x, y - P.y);\n }\n};\ndouble abs(point P){\n return sqrt(P.x * P.x + P.y * P.y);\n}\ndouble dist(point P, point Q){\n return abs(Q - P);\n}\ndouble cross(point P, point Q){\n return P.x * Q.y - P.y * Q.x;\n}\nstruct line{\n point A, B;\n line(point A, point B): A(A), B(B){\n }\n};\npoint vec(line L){\n return L.B - L.A;\n}\nbool segment_intersect(line L1, line L2){\n if (cross(L1.A - L2.A, vec(L2)) * cross(L1.B - L2.A, vec(L2)) > 0){\n return false;\n }\n if (cross(L2.A - L1.A, vec(L1)) * cross(L2.B - L1.A, vec(L1)) > 0){\n return false;\n }\n return true;\n}\nbool point_in_polygon(point P, vector<point> Q){\n int N = Q.size();\n point P2 = point(P.x + 100000, P.y + 123456);\n int cnt = 0;\n for (int i = 0; i < N; i++){\n line L1(Q[i], Q[(i + 1) % N]);\n line L2(P, P2);\n if (segment_intersect(L1, L2)){\n cnt++;\n }\n }\n if (cnt % 2 == 1){\n return true;\n } else {\n return false;\n }\n}\nstruct circle{\n point C;\n double r;\n circle(){\n }\n};\nbool point_in_circle(point P, circle C){\n return dist(P, C.C) < C.r;\n}\nbool circle_intersect(circle C1, circle C2){\n double d = dist(C1.C, C2.C);\n return abs(C1.r - C2.r) - EPS < d && d < C1.r + C2.r + EPS;\n}\nvoid dfs(vector<vector<int>> &E, vector<int> &r, vector<int> &p, vector<int> &d, int r2, int v){\n r[v] = r2;\n for (int w : E[v]){\n if (r[w] == -1){\n d[w] = d[v] + 1;\n p[w] = v;\n dfs(E, r, p, d, r2, w);\n }\n }\n}\nvector<int> detect_cycle(vector<vector<int>> E){\n int N = E.size();\n vector<int> r(N, -1);\n vector<int> p(N, -1);\n vector<int> d(N, 0);\n for (int i = 0; i < N; i++){\n if (p[i] == -1){\n dfs(E, r, p, d, i, i);\n }\n }\n for (int i = 0; i < N; i++){\n for (int j : E[i]){\n if (r[i] == r[j] && d[j] - d[i] > 1){\n vector<int> c;\n for (int v = j; v != i; v = p[v]){\n c.push_back(v);\n }\n c.push_back(i);\n return c;\n }\n }\n }\n return vector<int>();\n}\nint main(){\n while (true){\n int n, m;\n cin >> n >> m;\n if (n == 0 && m == 0){\n break;\n }\n vector<circle> C(n);\n for (int i = 0; i < n; i++){\n cin >> C[i].C.x >> C[i].C.y >> C[i].r;\n }\n for (int i = 0; i < m; i++){\n point P, Q;\n cin >> P.x >> P.y >> Q.x >> Q.y;\n set<int> st1, st2;\n for (int j = 0; j < n; j++){\n if (point_in_circle(P, C[j])){\n st1.insert(j);\n }\n if (point_in_circle(Q, C[j])){\n st2.insert(j);\n }\n }\n if (!st1.empty() || !st2.empty()){\n if (st1 == st2){\n cout << \"YES\";\n } else {\n cout << \"NO\";\n }\n } else {\n vector<vector<int>> E(n);\n for (int j = 0; j < n; j++){\n for (int k = j + 1; k < n; k++){\n if (circle_intersect(C[j], C[k])){\n E[j].push_back(k);\n E[k].push_back(j);\n }\n }\n }\n bool ok = true;\n while (true){\n vector<int> c = detect_cycle(E);\n if (c.empty()){\n break;\n }\n int cnt = c.size();\n vector<point> p(cnt);\n for (int j = 0; j < cnt; j++){\n p[j] = C[c[j]].C;\n }\n if (point_in_polygon(P, p) != point_in_polygon(Q, p)){\n ok = false;\n }\n for (int j = 0; j < E[c[0]].size(); j++){\n if (E[c[0]][j] == c[1]){\n E[c[0]].erase(E[c[0]].begin() + j);\n break;\n }\n }\n for (int j = 0; j < E[c[1]].size(); j++){\n if (E[c[1]][j] == c[0]){\n E[c[1]].erase(E[c[1]].begin() + j);\n break;\n }\n }\n }\n if (ok){\n cout << \"YES\";\n } else {\n cout << \"NO\";\n }\n }\n if (i < m - 1){\n cout << ' ';\n }\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3508, "score_of_the_acc": -0.0493, "final_rank": 6 }, { "submission_id": "aoj_1198_5629175", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst double EPS = 0.0001;\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n point operator +(point P){\n return point(x + P.x, y + P.y);\n }\n point operator -(point P){\n return point(x - P.x, y - P.y);\n }\n point operator *(double k){\n return point(x * k, y * k);\n }\n point operator /(double k){\n return point(x / k, y / k);\n }\n};\ndouble abs(point P){\n return sqrt(P.x * P.x + P.y * P.y);\n}\ndouble dist(point P, point Q){\n return abs(Q - P);\n}\ndouble cross(point P, point Q){\n return P.x * Q.y - P.y * Q.x;\n}\nstruct line{\n point A, B;\n line(point A, point B): A(A), B(B){\n }\n};\npoint vec(line L){\n return L.B - L.A;\n}\nbool segment_intersect(line L1, line L2){\n if (cross(L1.A - L2.A, vec(L2)) * cross(L1.B - L2.A, vec(L2)) > 0){\n return false;\n }\n if (cross(L2.A - L1.A, vec(L1)) * cross(L2.B - L1.A, vec(L1)) > 0){\n return false;\n }\n return true;\n}\nstruct circle{\n point C;\n double r;\n circle(){\n }\n};\nbool point_in_circle(point P, circle C){\n return dist(P, C.C) < C.r;\n}\nbool circle_intersects(circle C1, circle C2){\n double d = dist(C1.C, C2.C);\n return abs(C1.r - C2.r) - EPS < d && d < C1.r + C2.r + EPS;\n}\nbool point_in_polygon(point P, vector<point> Q){\n int N = Q.size();\n point P2 = point(P.x + 100000, P.y + 123456);\n int cnt = 0;\n for (int i = 0; i < N; i++){\n line L1(Q[i], Q[(i + 1) % N]);\n line L2(P, P2);\n if (segment_intersect(L1, L2)){\n cnt++;\n }\n }\n if (cnt % 2 == 1){\n return true;\n } else {\n return false;\n }\n}\nvoid dfs(vector<vector<int>> &E, vector<int> &r, vector<int> &p, vector<int> &d, int r2, int v){\n r[v] = r2;\n for (int w : E[v]){\n if (r[w] == -1){\n d[w] = d[v] + 1;\n p[w] = v;\n dfs(E, r, p, d, r2, w);\n }\n }\n}\nvector<int> detect_cycle(vector<vector<int>> E){\n int N = E.size();\n vector<int> r(N, -1);\n vector<int> p(N, -1);\n vector<int> d(N, 0);\n for (int i = 0; i < N; i++){\n if (p[i] == -1){\n dfs(E, r, p, d, i, i);\n }\n }\n for (int i = 0; i < N; i++){\n for (int j : E[i]){\n if (r[i] == r[j] && d[j] - d[i] > 1){\n vector<int> c;\n for (int v = j; v != i; v = p[v]){\n c.push_back(v);\n }\n c.push_back(i);\n return c;\n }\n }\n }\n return vector<int>();\n}\nint main(){\n while (true){\n int n, m;\n cin >> n >> m;\n if (n == 0 && m == 0){\n break;\n }\n vector<circle> C(n);\n for (int i = 0; i < n; i++){\n cin >> C[i].C.x >> C[i].C.y >> C[i].r;\n }\n for (int i = 0; i < m; i++){\n point P, Q;\n cin >> P.x >> P.y >> Q.x >> Q.y;\n set<int> st1, st2;\n for (int j = 0; j < n; j++){\n if (point_in_circle(P, C[j])){\n st1.insert(j);\n }\n if (point_in_circle(Q, C[j])){\n st2.insert(j);\n }\n }\n if (!st1.empty() || !st2.empty()){\n if (st1 == st2){\n cout << \"YES\";\n } else {\n cout << \"NO\";\n }\n } else {\n vector<vector<int>> E(n);\n for (int j = 0; j < n; j++){\n for (int k = j + 1; k < n; k++){\n if (circle_intersects(C[j], C[k])){\n E[j].push_back(k);\n E[k].push_back(j);\n }\n }\n }\n bool ok = true;\n while (true){\n vector<int> c = detect_cycle(E);\n if (c.empty()){\n break;\n }\n int cnt = c.size();\n vector<point> p(cnt);\n for (int j = 0; j < cnt; j++){\n p[j] = C[c[j]].C;\n }\n if (point_in_polygon(P, p) != point_in_polygon(Q, p)){\n ok = false;\n }\n for (int j = 0; j < E[c[0]].size(); j++){\n if (E[c[0]][j] == c[1]){\n E[c[0]].erase(E[c[0]].begin() + j);\n break;\n }\n }\n for (int j = 0; j < E[c[1]].size(); j++){\n if (E[c[1]][j] == c[0]){\n E[c[1]].erase(E[c[1]].begin() + j);\n break;\n }\n }\n }\n if (ok){\n cout << \"YES\";\n } else {\n cout << \"NO\";\n }\n }\n if (i < m - 1){\n cout << ' ';\n }\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3500, "score_of_the_acc": -0.0478, "final_rank": 5 }, { "submission_id": "aoj_1198_5628739", "code_snippet": "/*\tauthor: Kite_kuma\n\tcreated: 2021.06.29 20:45:02 */\n\n// #ifdef LOCAL\n// #define _GLIBCXX_DEBUG\n// #endif\n#include <bits/stdc++.h>\nusing namespace std;\n\n#pragma region macros\n\n#define foa(s, v) for(auto &s : v)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\n#define popcnt(n) __builtin_popcountll((long long)n)\n\n#define REPname(a, b, c, d, e, ...) e\n#define rep(...) REPname(__VA_ARGS__, REP3, REP2, REP1, REP0)(__VA_ARGS__)\n#define REP0(x) for(int Counter_in_rep_macro = 0; Counter_in_rep_macro < (x); ++Counter_in_rep_macro)\n#define REP1(i, x) for(int i = 0; i < (x); ++i)\n#define REP2(i, l, r) for(int i = (l); i < (r); ++i)\n#define REP3(i, l, r, c) for(int i = (l); i < (r); i += (c))\n\n#define DREPname(a, b, c, d, e, ...) e\n#define drep(...) DREPname(__VA_ARGS__, DREP3, DREP2, DREP1)(__VA_ARGS__)\n#define DREP1(i, x) for(int i = (x)-1; i >= 0; --i)\n#define DREP2(i, l, r) for(int i = (r)-1; i >= (l); --i)\n#define DREP3(i, l, r, c) for(int i = (r)-1; i >= (l); i -= (c))\n\n#pragma endregion\n\n#pragma region aliases\n\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\nusing vi = std::vector<int>;\nusing vvi = std::vector<std::vector<int>>;\nusing vvvi = std::vector<std::vector<std::vector<int>>>;\nusing vll = std::vector<ll>;\nusing vvll = std::vector<vll>;\nusing vvvll = std::vector<vvll>;\nusing pii = std::pair<int, int>;\nusing pll = std::pair<long long, long long>;\ntemplate <class T = ll>\nusing V = std::vector<T>;\ntemplate <class T = ll>\nusing VV = V<V<T>>;\ntemplate <class T = ll>\nusing VVV = V<V<V<T>>>;\ntemplate <class T = ll>\nusing pqup = std::priority_queue<T, std::vector<T>, std::greater<T>>;\ntemplate <class T = ll>\nusing pqdn = std::priority_queue<T>;\n\n#pragma endregion\n\n#pragma region constants\n\nconst int inf = 1e9;\nconst long long INF = 1e18;\nconst long double pi = acos(-1);\nconst char dl = '\\n';\nconst char sp = ' ';\nint dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};\nint dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};\n\nconst int mod_1000000007 = 1000000007;\nconst int mod_998244353 = 998244353;\n\n#pragma endregion\n\n#pragma region basic_operation\n\ntemplate <class T0, class T1, class T2>\ninline bool in_range(T0 x, T1 lef, T2 rig) {\n\treturn ((lef <= x) && (x < rig));\n}\n\ntemplate <class T>\ninline bool chmin(T &a, T b) {\n\tif(a > b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\ntemplate <class T>\ninline bool chmax(T &a, T b) {\n\tif(a < b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\n\nvoid Yes(bool f = 1) { std::cout << (f ? \"Yes\" : \"No\") << '\\n'; }\nvoid No() { std::cout << \"No\\n\"; }\nvoid YES(bool f = 1) { std::cout << (f ? \"YES\" : \"NO\") << '\\n'; }\nvoid NO() { std::cout << \"NO\\n\"; }\n\ntemplate <class T>\nvoid drop(T answer) {\n\tstd::cout << answer << '\\n';\n\texit(0);\n}\n\nvoid err(bool flag = true) {\n\tif(!flag) return;\n\tstd::cout << -1 << '\\n';\n\texit(0);\n}\n\ntemplate <class T>\nvoid vout(std::vector<T> const &v, bool vertically = 0) {\n\tif(vertically) {\n\t\tfor(auto const &a : v) {\n\t\t\tstd::cout << a << '\\n';\n\t\t}\n\t\treturn;\n\t}\n\tfor(auto it = v.begin(); it != v.end(); it++) {\n\t\tstd::cout << (*it);\n\t\tif(it != v.end() - 1) {\n\t\t\tstd::cout << ' ';\n\t\t}\n\t}\n\tstd::cout << '\\n';\n\treturn;\n}\n\ninline void print() { std::cout << '\\n'; }\ntemplate <class T>\ninline void print(T x) {\n\tstd::cout << x << '\\n';\n\treturn;\n}\ntemplate <typename Head, typename... Tail>\nvoid print(Head H, Tail... T) {\n\tstd::cout << H << \" \";\n\tprint(T...);\n}\n\ntemplate <class T>\nvoid add(std::vector<T> &v, T val) {\n\tfor(auto &a : v) a += val;\n\treturn;\n}\n\ntemplate <class T>\nT dup(T a, T b) {\n\tassert(b != 0);\n\treturn (a + b - 1) / b;\n}\n\ntemplate <class T>\nT greatest_lower_multiple(T x, T d) {\n\tif(d == 0) return 0;\n\tif(d < 0) d *= -1;\n\tT y = x % d;\n\tif(y < 0) y += d;\n\treturn x - y;\n}\n\ntemplate <class T>\nT least_upper_multiple(T x, T d) {\n\treturn -greatest_lower_multiple(-x, d);\n}\n\nlong long POW(long long a, long long n) {\n\tlong long res = 1;\n\twhile(n > 0) {\n\t\tif(n & 1) res = res * a;\n\t\ta = a * a;\n\t\tn >>= 1;\n\t}\n\treturn res;\n}\n\nlong long modpow(long long a, long long n, long long mod) {\t // a^n mod\n\tassert(n >= 0 && mod);\n\tif(mod == 1) return 0LL;\n\tlong long res = 1;\n\twhile(n > 0) {\n\t\tif(n & 1) res = res * a % mod;\n\t\ta = a * a % mod;\n\t\tn >>= 1;\n\t}\n\treturn res < 0 ? res + mod : res;\n}\n\n// return x which satisfies a * x % mod == gcd(a, mod)\n// not (mod | a)\nlong long modinv(long long a, long long mod) {\n\tlong long b = mod, u = 1, v = 0;\n\twhile(b) {\n\t\tlong long t = a / b;\n\t\ta -= t * b;\n\t\tstd::swap(a, b);\n\t\tu -= t * v;\n\t\tstd::swap(u, v);\n\t}\n\tu %= mod;\n\tif(u < 0) u += mod;\n\treturn u;\n}\n\ntemplate <class T>\nint lb(const std::vector<T> &a, const T x) {\n\treturn std::distance(a.begin(), std::lower_bound(a.begin(), a.end(), x));\n}\ntemplate <class T>\nint ub(const std::vector<T> &a, const T x) {\n\treturn std::distance(a.begin(), std::upper_bound(a.begin(), a.end(), x));\n}\ntemplate <class T>\nvoid unq_sort(std::vector<T> &a) {\n\tstd::sort(a.begin(), a.end());\n\ta.erase(std::unique(a.begin(), a.end()), a.end());\n}\ntemplate <class T>\nstd::vector<int> press(std::vector<T> &a) {\n\tauto vec = a;\n\tunq_sort(vec);\n\tstd::vector<int> ret;\n\tfor(auto &v : a) ret.push_back(lb(vec, v));\n\treturn ret;\n}\n\n#pragma endregion\n\n#pragma region input\n#define VEC(type, name, size) \\\n\tvector<type> name(size); \\\n\tscanner::INPUT(name)\n#define VVEC(type, name, h, w) \\\n\tvector<vector<type>> name(h, vector<type>(w)); \\\n\tscanner::INPUT(name)\n#define INT(...) \\\n\tint __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LL(...) \\\n\tlong long __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define STR(...) \\\n\tstring __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define CHR(...) \\\n\tchar __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define DBL(...) \\\n\tdouble __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LD(...) \\\n\tlong double __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define TPL3(type0, type1, type2, name) \\\n\tstd::tuple<type0, type1, type2> name; \\\n\tscanner::INPUT(name);\n#define TPL4(type0, type1, type2, type3, name) \\\n\tstd::tuple<type0, type1, type2, type3> name; \\\n\tscanner::INPUT(name);\n\nnamespace scanner {\ntemplate <class T>\nvoid scan(T &a) {\n\tstd::cin >> a;\n}\n\ntemplate <class T, class L>\nvoid scan(std::pair<T, L> &p) {\n\tscan(p.first);\n\tscan(p.second);\n}\n\ntemplate <class T0, class T1, class T2>\nvoid scan(std::tuple<T0, T1, T2> &p) {\n\tT0 t0;\n\tT1 t1;\n\tT2 t2;\n\tscan(t0);\n\tscan(t1);\n\tscan(t2);\n\tp = std::make_tuple(t0, t1, t2);\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid scan(std::tuple<T0, T1, T2, T3> &p) {\n\tT0 t0;\n\tT1 t1;\n\tT2 t2;\n\tT3 t3;\n\tscan(t0);\n\tscan(t1);\n\tscan(t2);\n\tscan(t3);\n\tp = std::make_tuple(t0, t1, t2, t3);\n}\n\ntemplate <class T>\nvoid scan(std::vector<T> &a) {\n\tfor(auto &i : a) scan(i);\n}\n\nvoid INPUT() {}\ntemplate <class Head, class... Tail>\nvoid INPUT(Head &head, Tail &... tail) {\n\tscan(head);\n\tINPUT(tail...);\n}\n} // namespace scanner\n\ntemplate <typename T1, typename T2>\nstd::istream &operator>>(std::istream &is, std::pair<T1, T2> &p) {\n\tis >> p.first >> p.second;\n\treturn is;\n}\n#pragma endregion\n\n#pragma region debug\n\n#pragma region output\ntemplate <typename T1, typename T2>\nstd::ostream &std::operator<<(std::ostream &os, const std::pair<T1, T2> &p) {\n\tos << p.first << \" \" << p.second;\n\treturn os;\n}\ntemplate <class T>\nstd::ostream &std::operator<<(std::ostream &os, const std::vector<T> &v) {\n\tfor(int i = 0; i < (int)v.size(); i++) {\n\t\tif(i) os << \" \";\n\t\tos << v[i];\n\t}\n\treturn os;\n}\n#pragma endregion\n\n#pragma region view\n\nnamespace viewer {\nvoid view(const long long e) {\n\tif(e == INF)\n\t\tstd::cerr << \"INF\";\n\telse if(e == -INF)\n\t\tstd::cerr << \"-INF\";\n\telse\n\t\tstd::cerr << e;\n}\n\nvoid view(const int e) {\n\tif(e == inf)\n\t\tstd::cerr << \"inf\";\n\telse if(e == -inf)\n\t\tstd::cerr << \"-inf\";\n\telse\n\t\tstd::cerr << e;\n}\n\ntemplate <typename T>\nvoid view(const T e) {\n\tstd::cerr << e;\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::pair<T, U> &p) {\n\tstd::cerr << \"(\";\n\tview(p.first);\n\tstd::cerr << \", \";\n\tview(p.second);\n\tstd::cerr << \")\";\n}\n\ntemplate <class T0, class T1, class T2>\nvoid view(const std::tuple<T0, T1, T2> &p) {\n\tstd::cerr << \"(\";\n\tview(std::get<0>(p));\n\tstd::cerr << \", \";\n\tview(std::get<1>(p));\n\tstd::cerr << \", \";\n\tview(std::get<2>(p));\n\tstd::cerr << \")\";\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid view(const std::tuple<T0, T1, T2, T3> &p) {\n\tstd::cerr << \"(\";\n\tview(std::get<0>(p));\n\tstd::cerr << \", \";\n\tview(std::get<1>(p));\n\tstd::cerr << \", \";\n\tview(std::get<2>(p));\n\tstd::cerr << \", \";\n\tview(std::get<3>(p));\n\tstd::cerr << \")\";\n}\n\ntemplate <typename T>\nvoid view(const std::set<T> &s) {\n\tif(s.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << \"{ \";\n\tfor(auto &t : s) {\n\t\tview(t);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <typename T>\nvoid view(const std::unordered_set<T> &s) {\n\tif(s.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << \"{ \";\n\tfor(auto &t : s) {\n\t\tview(t);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <typename T>\nvoid view(const std::vector<T> &v) {\n\tif(v.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << \"{ \";\n\tfor(const auto &e : v) {\n\t\tview(e);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <typename T>\nvoid view(const std::vector<std::vector<T>> &vv) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &v : vv) {\n\t\tstd::cerr << \"\\t\";\n\t\tview(v);\n\t\tstd::cerr << '\\n';\n\t}\n\tstd::cerr << \"}\";\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::vector<std::pair<T, U>> &v) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &c : v) {\n\t\tstd::cerr << \"\\t(\";\n\t\tview(c.first);\n\t\tstd::cerr << \", \";\n\t\tview(c.second);\n\t\tstd::cerr << \")\\n\";\n\t}\n\tstd::cerr << \"}\";\n}\n\ntemplate <class T0, class T1, class T2>\nvoid view(const std::vector<std::tuple<T0, T1, T2>> &v) {\n\tif(v.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << '{';\n\tfor(const auto &t : v) {\n\t\tstd::cerr << \"\\n\\t\";\n\t\tview(t);\n\t\tstd::cerr << \",\";\n\t}\n\tstd::cerr << \"\\n}\";\n}\n\ntemplate <class T0, class T1, class T2, class T3>\nvoid view(const std::vector<std::tuple<T0, T1, T2, T3>> &v) {\n\tif(v.empty()) {\n\t\tstd::cerr << \"{ }\";\n\t\treturn;\n\t}\n\tstd::cerr << '{';\n\tfor(const auto &t : v) {\n\t\tstd::cerr << \"\\n\\t\";\n\t\tview(t);\n\t\tstd::cerr << \",\";\n\t}\n\tstd::cerr << \"\\n}\";\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::map<T, U> &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &t : m) {\n\t\tstd::cerr << \"\\t[\";\n\t\tview(t.first);\n\t\tstd::cerr << \"] : \";\n\t\tview(t.second);\n\t\tstd::cerr << '\\n';\n\t}\n\tstd::cerr << \"}\";\n}\n\ntemplate <typename T, typename U>\nvoid view(const std::unordered_map<T, U> &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &t : m) {\n\t\tstd::cerr << \"\\t[\";\n\t\tview(t.first);\n\t\tstd::cerr << \"] : \";\n\t\tview(t.second);\n\t\tstd::cerr << '\\n';\n\t}\n\tstd::cerr << \"}\";\n}\n} // namespace viewer\n\n#pragma endregion\n\n// when debugging : g++ foo.cpp -DLOCAL\n#ifdef LOCAL\nvoid debug_out() {}\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head H, Tail... T) {\n\tviewer::view(H);\n\tstd::cerr << \", \";\n\tdebug_out(T...);\n}\n#define debug(...) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"] : [\"; \\\n\t\tdebug_out(__VA_ARGS__); \\\n\t\tstd::cerr << \"\\b\\b]\\n\"; \\\n\t} while(0)\n#define dump(x) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" \" << #x << \" : \"; \\\n\t\tviewer::view(x); \\\n\t\tstd::cerr << '\\n'; \\\n\t} while(0)\n\n#else\n#define debug(...) (void(0))\n#define dump(x) (void(0))\n#endif\n\n#pragma endregion\n\n#pragma region geometry\n\nusing Real = long double; //時間がかかる割にdoubleと大差ない\nusing Point = complex<Real>;\nconst Real EPS = 1e-10, /*1e-8はたまに落ちる*/ PI = acos(-1);\n\ninline bool eq(Real a, Real b) { return fabs(b - a) < EPS; } //誤差無視の等式\n\n//実スカラー倍\nPoint operator*(const Point &p, const Real &d) { return Point(real(p) * d, imag(p) * d); }\n\n// point入力受け取り\nistream &operator>>(istream &is, Point &p) {\n\tReal a, b;\n\tis >> a >> b;\n\tp = Point(a, b);\n\treturn is;\n}\n// point出力\nostream &operator<<(ostream &os, Point &p) { return os << fixed << setprecision(10) << p.real() << \" \" << p.imag(); }\n\n// 点 p を反時計回りに theta 回転\nPoint rotate(Real theta, const Point &p) {\n\treturn Point(cos(theta) * p.real() - sin(theta) * p.imag(), sin(theta) * p.real() + cos(theta) * p.imag());\n}\n\nReal radian_to_degree(Real r) { return (r * 180.0 / PI); }\n\nReal degree_to_radian(Real d) { return (d * PI / 180.0); }\n\n// a-b-c の角度のうち小さい方を返す\nReal get_angle(const Point &a, const Point &b, const Point &c) {\n\tconst Point v(a - b), /* もとはv(b-a)になってたので修正 */ w(c - b);\n\tReal alpha = atan2(v.imag(), v.real()), beta = atan2(w.imag(), w.real());\n\tif(alpha > beta) swap(alpha, beta);\n\tReal theta = (beta - alpha);\n\treturn min(theta, 2 * acos(-1) - theta);\n}\n\nnamespace std {\nbool operator<(const Point &a, const Point &b) { return a.real() != b.real() ? a.real() < b.real() : a.imag() < b.imag(); }\n} // namespace std\n\nstruct Line {\n\tPoint a, b;\n\n\tLine() = default;\n\n\tLine(Point a, Point b) : a(a), b(b) {}\n\n\tLine(Real A, Real B, Real C) // Ax + By = C\n\t{\n\t\tif(eq(A, 0))\n\t\t\ta = Point(0, C / B), b = Point(1, C / B);\n\t\telse if(eq(B, 0))\n\t\t\tb = Point(C / A, 0), b = Point(C / A, 1);\n\t\telse\n\t\t\ta = Point(0, C / B), b = Point(C / A, 0);\n\t}\n\n\tfriend ostream &operator<<(ostream &os, Line &p) { return os << p.a << \" to \" << p.b; }\n\n\tfriend istream &operator>>(istream &is, Line &a) { return is >> a.a >> a.b; }\n};\n\nstruct Segment : Line {\n\tSegment() = default;\n\n\tSegment(Point a, Point b) : Line(a, b) {}\n};\n\nstruct Circle {\n\tPoint p;\n\tReal r;\n\n\tCircle() = default;\n\n\tCircle(Point p, Real r) : p(p), r(r) {}\n};\n\nusing Points = vector<Point>;\nusing Polygon = vector<Point>;\nusing Segments = vector<Segment>;\nusing Lines = vector<Line>;\nusing Circles = vector<Circle>;\n\n//外積\nReal cross(const Point &a, const Point &b) { return real(a) * imag(b) - imag(a) * real(b); }\n//内積\nReal dot(const Point &a, const Point &b) { return real(a) * real(b) + imag(a) * imag(b); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_C\n// 点の回転方向\nint ccw(const Point &a, Point b, Point c) {\n\tb = b - a, c = c - a;\n\tif(cross(b, c) > EPS) return +1; // \"COUNTER_CLOCKWISE\"\n\tif(cross(b, c) < -EPS) return -1; // \"CLOCKWISE\"\n\tif(dot(b, c) < 0) return +2;\t // \"ONLINE_BACK\"\n\tif(norm(b) < norm(c)) return -2; // \"ONLINE_FRONT\"\n\treturn 0;\t\t\t\t\t\t // \"ON_SEGMENT\"\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_A\n// 平行判定\nbool parallel(const Line &a, const Line &b) { return eq(cross(a.b - a.a, b.b - b.a), 0.0); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_A\n// 垂直判定\nbool orthogonal(const Line &a, const Line &b) { return eq(dot(a.a - a.b, b.a - b.b), 0.0); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_A\n// 射影\n// 直線 l に p から垂線を引いた交点を求める\nPoint projection(const Line &l, const Point &p) {\n\tdouble t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n\treturn l.a + (l.a - l.b) * t;\n}\n\nPoint projection(const Segment &l, const Point &p) {\n\tdouble t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n\treturn l.a + (l.a - l.b) * t;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_1_B\n// 反射\n// 直線 l を対称軸として点 p と線対称にある点を求める\nPoint reflection(const Line &l, const Point &p) { return p + (projection(l, p) - p) * 2.0; }\n\nbool intersect(const Line &l, const Point &p) { return abs(ccw(l.a, l.b, p)) != 1; }\n\nbool intersect(const Line &l, const Line &m) { return abs(cross(l.b - l.a, m.b - m.a)) > EPS || abs(cross(l.b - l.a, m.b - l.a)) < EPS; }\n\nbool intersect(const Segment &s, const Point &p) { return ccw(s.a, s.b, p) == 0; }\n\nbool intersect(const Line &l, const Segment &s) { return cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < EPS; }\n\nReal distance(const Line &l, const Point &p);\n\nbool intersect(const Circle &c, const Line &l) { return distance(l, c.p) <= c.r + EPS; }\n\nbool intersect(const Circle &c, const Point &p) { return abs(abs(p - c.p) - c.r) < EPS; }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_B\n// 線分同士の交差判定 (端点が他方の線分上にあるならば交差とみなす)\nbool intersect(const Segment &s, const Segment &t) {\n\treturn ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 && ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\nint intersect(const Circle &c, const Segment &l) {\n\tif(norm(projection(l, c.p) - c.p) - c.r * c.r > EPS) return 0;\n\tauto d1 = abs(c.p - l.a), d2 = abs(c.p - l.b);\n\tif(d1 < c.r + EPS && d2 < c.r + EPS) return 0;\n\tif(d1 < c.r - EPS && d2 > c.r + EPS || d1 > c.r + EPS && d2 < c.r - EPS) return 1;\n\tconst Point h = projection(l, c.p);\n\tif(dot(l.a - h, l.b - h) < 0) return 2;\n\treturn 0;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_A&lang=jp\nint intersect(Circle c1, Circle c2) {\n\tif(c1.r < c2.r) swap(c1, c2);\n\tReal d = abs(c1.p - c2.p);\n\tif(c1.r + c2.r < d) return 4;\t // 外に離れている\n\tif(eq(c1.r + c2.r, d)) return 3; // 外接\n\tif(c1.r - c2.r < d) return 2;\t // 交差\n\tif(eq(c1.r - c2.r, d)) return 1; // 内接\n\treturn 0;\t\t\t\t\t\t // 内包\n}\n\nReal distance(const Point &a, const Point &b) { return abs(a - b); }\n\nReal distance(const Line &l, const Point &p) { return abs(p - projection(l, p)); }\n\nReal distance(const Line &l, const Line &m) { return intersect(l, m) ? 0 : distance(l, m.a); }\n\nReal distance(const Segment &s, const Point &p) {\n\tPoint r = projection(s, p);\n\tif(intersect(s, r)) return abs(r - p);\n\treturn min(abs(s.a - p), abs(s.b - p));\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_D\nReal distance(const Segment &a, const Segment &b) {\n\tif(intersect(a, b)) return 0;\n\treturn min({distance(a, b.a), distance(a, b.b), distance(b, a.a), distance(b, a.b)});\n}\n\nReal distance(const Line &l, const Segment &s) {\n\tif(intersect(l, s)) return 0;\n\treturn min(distance(l, s.a), distance(l, s.b));\n}\n\nPoint crosspoint(const Line &l, const Line &m) {\n\tReal A = cross(l.b - l.a, m.b - m.a);\n\tReal B = cross(l.b - l.a, l.b - m.a);\n\tif(eq(abs(A), 0.0) && eq(abs(B), 0.0)) return m.a;\n\treturn m.a + (m.b - m.a) * B / A;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_2_C\nPoint crosspoint(const Segment &l, const Segment &m) { return crosspoint(Line(l), Line(m)); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_D\npair<Point, Point> crosspoint(const Circle &c, const Line l) {\n\tPoint pr = projection(l, c.p);\n\tPoint e = (l.b - l.a) / abs(l.b - l.a);\n\tif(eq(distance(l, c.p), c.r)) return {pr, pr};\n\tdouble base = sqrt(c.r * c.r - norm(pr - c.p));\n\treturn {pr - e * base, pr + e * base};\n}\n\npair<Point, Point> crosspoint(const Circle &c, const Segment &l) {\n\tLine aa = Line(l.a, l.b);\n\tif(intersect(c, l) == 2) return crosspoint(c, aa);\n\tauto ret = crosspoint(c, aa);\n\tif(dot(l.a - ret.first, l.b - ret.first) < 0)\n\t\tret.second = ret.first;\n\telse\n\t\tret.first = ret.second;\n\treturn ret;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_E\npair<Point, Point> crosspoint(const Circle &c1, const Circle &c2) {\n\tReal d = abs(c1.p - c2.p);\n\tReal a = acos((c1.r * c1.r + d * d - c2.r * c2.r) / (2 * c1.r * d)); // 余弦定理\n\tReal t = atan2(c2.p.imag() - c1.p.imag(), c2.p.real() - c1.p.real());\n\tPoint p1 = c1.p + Point(cos(t + a) * c1.r, sin(t + a) * c1.r);\n\tPoint p2 = c1.p + Point(cos(t - a) * c1.r, sin(t - a) * c1.r);\n\treturn {p1, p2};\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_F\n// \"点 p を通る円 c の接線\"の接点2つ\npair<Point, Point> tangent(const Circle &c1, const Point &p2) { return crosspoint(c1, Circle(p2, sqrt(norm(c1.p - p2) - c1.r * c1.r))); }\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_G\n// 円 c1, c2 の共通接線\nLines tangent(Circle c1, Circle c2) {\n\tLines ret;\n\tif(c1.r < c2.r) swap(c1, c2);\n\tReal g = norm(c1.p - c2.p);\n\tif(eq(g, 0)) return ret;\n\tPoint u = (c2.p - c1.p) / sqrt(g);\n\tPoint v = rotate(PI * 0.5, u);\n\tfor(int s : {-1, 1}) {\n\t\tReal h = (c1.r + s * c2.r) / sqrt(g);\n\t\tif(eq(1 - h * h, 0)) {\n\t\t\tret.emplace_back(c1.p + u * c1.r, c1.p + (u + v) * c1.r);\n\t\t} else if(1 - h * h > 0) {\n\t\t\tPoint uu = u * h, vv = v * sqrt(1 - h * h);\n\t\t\tret.emplace_back(c1.p + (uu + vv) * c1.r, c2.p - (uu + vv) * c2.r * s);\n\t\t\tret.emplace_back(c1.p + (uu - vv) * c1.r, c2.p - (uu - vv) * c2.r * s);\n\t\t}\n\t}\n\treturn ret;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_B\n// 凸性判定 (反時計回り)\nbool is_convex(const Polygon &p) {\n\tint n = (int)p.size();\n\tfor(int i = 0; i < n; i++) {\n\t\tif(ccw(p[(i + n - 1) % n], p[i], p[(i + 1) % n]) == -1) return false;\n\t}\n\treturn true;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_4_A\n// 凸包\nPolygon convex_hull(Polygon &p) {\n\tint n = (int)p.size(), k = 0;\n\tif(n <= 2) return p;\n\tsort(p.begin(), p.end()); // x -> yの順にソート\n\tvector<Point> ch(2 * n);\n\tfor(int i = 0; i < n; ch[k++] = p[i++]) { //下半分を構成\n\t\twhile(k >= 2 && cross(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1]) < EPS) --k;\n\t}\n\tfor(int i = n - 2, t = k + 1; i >= 0; ch[k++] = p[i--]) { //上半分を構成\n\t\twhile(k >= t && cross(ch[k - 1] - ch[k - 2], p[i] - ch[k - 1]) < EPS) --k;\n\t}\n\tch.resize(k - 1);\n\treturn ch;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_3_C\n// 多角形と点の包含判定\nenum { OUT, ON, IN };\n\nint contains(const Polygon &Q, const Point &p) {\n\tbool in = false;\n\tfor(int i = 0; i < Q.size(); i++) {\n\t\tPoint a = Q[i] - p, b = Q[(i + 1) % Q.size()] - p;\n\t\tif(a.imag() > b.imag()) swap(a, b);\n\t\tif(a.imag() <= 0 && 0 < b.imag() && cross(a, b) < 0) in = !in;\n\t\tif(cross(a, b) == 0 && dot(a, b) <= 0) return ON;\n\t}\n\treturn in ? IN : OUT;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_7_H\n// 円と多角形の共通部分の面積\nReal area(const Polygon &p, const Circle &c) {\n\tif(p.size() < 3) return 0.0;\n\tfunction<Real(Circle, Point, Point)> cross_area = [&](const Circle &c, const Point &a, const Point &b) {\n\t\tPoint va = c.p - a, vb = c.p - b;\n\t\tReal f = cross(va, vb), ret = 0.0;\n\t\tif(eq(f, 0.0)) return ret;\n\t\tif(max(abs(va), abs(vb)) < c.r + EPS) return f;\n\t\tif(distance(Segment(a, b), c.p) > c.r - EPS) return c.r * c.r * arg(vb * conj(va));\t // 0.5倍してなくない?\n\t\tauto u = crosspoint(c, Segment(a, b));\n\t\tvector<Point> tot{a, u.first, u.second, b};\n\t\tfor(int i = 0; i + 1 < tot.size(); i++) {\n\t\t\tret += cross_area(c, tot[i], tot[i + 1]);\n\t\t}\n\t\treturn ret;\n\t};\n\tReal A = 0;\n\tfor(int i = 0; i < p.size(); i++) {\n\t\tA += cross_area(c, p[i], p[(i + 1) % p.size()]);\n\t}\n\treturn A * 0.5;\t // 0.5倍が抜けていたので修正;\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_4_B\n// 凸多角形の直径(最遠頂点対間距離)\nReal convex_diameter(const Polygon &p) {\n\tint N = (int)p.size();\n\tint is = 0, js = 0;\n\tfor(int i = 1; i < N; i++) {\n\t\tif(p[i].imag() > p[is].imag()) is = i;\n\t\tif(p[i].imag() < p[js].imag()) js = i;\n\t}\n\tReal maxdis = norm(p[is] - p[js]);\n\n\tint maxi, maxj, i, j;\n\ti = maxi = is;\n\tj = maxj = js;\n\tdo {\n\t\tif(cross(p[(i + 1) % N] - p[i], p[(j + 1) % N] - p[j]) >= 0) {\n\t\t\tj = (j + 1) % N;\n\t\t} else {\n\t\t\ti = (i + 1) % N;\n\t\t}\n\t\tif(norm(p[i] - p[j]) > maxdis) {\n\t\t\tmaxdis = norm(p[i] - p[j]);\n\t\t\tmaxi = i;\n\t\t\tmaxj = j;\n\t\t}\n\t} while(i != is || j != js);\n\treturn sqrt(maxdis);\n}\n\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=CGL_5_A\n// 最近点対\nReal closest_pair(Points ps) {\n\tif(ps.size() <= 1) throw(0);\n\tsort(begin(ps), end(ps)); // xでソート\n\n\tauto compare_y = [&](const Point &a, const Point &b) { return imag(a) < imag(b); };\n\tvector<Point> beet(ps.size());\n\tconst Real INF = 1e18;\n\n\tfunction<Real(int, int)> rec = [&](int left, int right) {\n\t\tif(right - left <= 1) return INF;\n\t\tint mid = (left + right) >> 1;\n\t\tauto x = real(ps[mid]);\t // 領域内でx座標真中の点\n\t\tauto ret = min(rec(left, mid), rec(mid, right));\n\t\t// y座標でソートされた2つの区間をマージ\n\t\tinplace_merge(begin(ps) + left, begin(ps) + mid, begin(ps) + right, compare_y);\n\t\tint ptr = 0;\n\t\tfor(int i = left; i < right; i++) {\n\t\t\tif(abs(real(ps[i]) - x) >= ret) continue;\n\t\t\tfor(int j = 0; j < ptr; j++) {\n\t\t\t\tauto luz = ps[i] - beet[ptr - j - 1];\n\t\t\t\tif(imag(luz) >= ret) break;\n\t\t\t\tret = min(ret, abs(luz));\n\t\t\t}\n\t\t\tbeet[ptr++] = ps[i];\n\t\t}\n\t\treturn ret;\n\t};\n\treturn rec(0, (int)ps.size());\n}\n\n// (aからの距離):(bからの距離) = dist_a : dist_b となる点の集合(円)を返す\nCircle Apollonius_Circle(Point a, Point b, Real dist_a, Real dist_b) {\n\tassert(!eq(dist_a, dist_b)); //同じ場合はbisectionで\n\tReal asq = dist_a * dist_a, bsq = dist_b * dist_b;\n\tPoint p = (a * bsq - b * asq) * (1 / (bsq - asq));\n\tReal r = abs(a - b) * dist_a * dist_b / abs(asq - bsq);\n\treturn Circle(p, r);\n}\n\n// 二等分線\nLine bisection(Point a, Point b) {\n\ta = (a + b) * 0.5;\n\tb = rotate(PI / 2, b - a) + a;\n\treturn Line(a, b);\n}\n\n#pragma endregion\n\nvoid solve() {\n\tINT(n, m);\n\tif(n + m == 0) exit(0);\n\n\tCircles c;\n\trep(n) {\n\t\tReal x, y, r;\n\t\tcin >> x >> y >> r;\n\t\tc.emplace_back(Point(x, y), r);\n\t}\n\n\tVV<pair<Real, int>> g(n, V<pair<Real, int>>(n, pair(-1., 0)));\n\n\trep(i, n) rep(j, n) {\n\t\tif(i == j) continue;\n\t\tif(intersect(c[i], c[j]) == 2) {\n\t\t\t// g[i].emplace_back(arg(c[j].p - c[i].p), j);\n\t\t\tg[i][j] = pair(arg(c[j].p - c[i].p), 1);\n\t\t}\n\t}\n\n\n\tvector<vector<int>> convexes;\n\tvi visited(n);\n\trep(first, n) {\n\t\twhile(1) {\n\t\t\tbool b = true;\n\t\t\tvi cycle;\n\t\t\tReal direction = 0.;\n\t\t\tint now = first;\n\n\t\t\tdo {\n\t\t\t\tint nxt = -1;\n\t\t\t\tReal angle = -INF;\n\t\t\t\tauto nxt_dir = direction;\n\t\t\t\trep(j, n) {\n\t\t\t\t\tif(g[now][j].second == 0) continue;\n\t\t\t\t\tReal diff = g[now][j].first - direction;\n\t\t\t\t\twhile(diff < -pi + EPS * 2) diff += pi * 2;\n\t\t\t\t\twhile(diff >= pi - EPS) diff -= pi * 2;\n\n\t\t\t\t\tif(chmax(angle, diff)) {\n\t\t\t\t\t\tnxt = j;\n\t\t\t\t\t\tnxt_dir = g[now][j].first;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tif(nxt == -1) {\n\t\t\t\t\tb = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tg[now][nxt].second = 0;\n\t\t\t\tdirection = nxt_dir;\n\t\t\t\tnow = nxt;\n\t\t\t\tcycle.push_back(nxt);\n\t\t\t} while(now != first);\n\t\t\tif(!b) break;\n\t\t\tconvexes.push_back(cycle);\n\t\t}\n\t}\n\t// int cs = convexes.size();\n\n\tV<Polygon> plgns;\n\n\tfoa(cvx, convexes) {\n\t\tPolygon plgn;\n\t\tfoa(ver, cvx) plgn.push_back(c[ver].p);\n\t\tplgns.push_back(plgn);\n\t}\n\n\trep(loop, m) {\n\t\tPoint pee, kyu;\t // P, Q\n\t\t// Real x, y;\n\t\t// cin >> x >> y;\n\t\t// pee.emplace_back(x, y);\n\t\t// cin >> x >> y;\n\t\t// kyu.emplace_back(x, y);\n\t\tcin >> pee >> kyu;\n\n\t\tvector<int> pee_in;\n\t\tvector<int> kyu_in;\n\n\t\trep(i, n) {\n\t\t\tif(distance(c[i].p, pee) < c[i].r) {\n\t\t\t\tpee_in.push_back(i);\n\t\t\t}\n\t\t}\n\n\t\trep(i, n) {\n\t\t\tif(distance(c[i].p, kyu) < c[i].r) {\n\t\t\t\tkyu_in.push_back(i);\n\t\t\t}\n\t\t}\n\n\t\tif(!pee_in.empty()) {\n\t\t\tcout << (pee_in == kyu_in ? \"YES\" : \"NO\") << (loop == m - 1 ? '\\n' : ' ');\n\t\t\tcontinue;\n\t\t}\n\n\t\trep(i, plgns.size()) {\n\t\t\t// foa(plgn, plgns) {\n\t\t\tauto plgn = plgns[i];\n\t\t\tif(contains(plgn, pee) == IN) {\n\t\t\t\tpee_in.push_back(i);\n\t\t\t}\n\t\t}\n\n\t\trep(i, plgns.size()) {\n\t\t\t// foa(plgn, plgns) {\n\t\t\tauto plgn = plgns[i];\n\t\t\tif(contains(plgn, kyu) == IN) {\n\t\t\t\tkyu_in.push_back(i);\n\t\t\t}\n\t\t}\n\n\t\tcout << (pee_in == kyu_in ? \"YES\" : \"NO\") << (loop == m - 1 ? '\\n' : ' ');\n\t}\n\n\tdebug(convexes);\n\treturn;\n}\nint main() {\n\tstd::ios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\tstd::cout << std::fixed << std::setprecision(15);\n\tsrand((unsigned)time(NULL));\n\n\twhile(1) solve();\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4008, "score_of_the_acc": -0.1493, "final_rank": 15 }, { "submission_id": "aoj_1198_4326322", "code_snippet": "#include\"bits/stdc++.h\"\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(n);i++)\n#define FOR(i,m,n) for(int i=(m);i<(n);i++)\n#define REPR(i,n) for(int i=(n)-1;i>=0;i--)\nconst bool DEBUG = false;\nconst double EPS = 1e-8;\ntypedef complex<double>point;\npoint operator*(const point &p, const double &d) {\n\treturn point(real(p)*d, imag(p)*d);\n}\nnamespace std {\n\tbool operator<(const point &a, const point &b) {\n\t\treturn real(a) != real(b) ? real(a)<real(b) : imag(a)<imag(b);\n\t}\n}\ndouble dist(const point &a, const point &b) {\n\treturn abs(a - b);\n}\nstruct Line :public vector<point> {\n\tLine(const point &a, const point &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\ntypedef vector<Line> Lines;\ndouble cross(const point &a, const point &b) {\n\treturn real(a)*imag(b) - imag(a)*real(b);\n}\ndouble dot(const point &a, const point &b) {\n\treturn real(a)*real(b) + imag(a)*imag(b);\n}\nint ccw(point a, point b, point c) {\n\tb = b - a, c = c - a;\n\tif (cross(b, c)>EPS)return +1;\n\tif (cross(b, c)<-EPS)return -1;\n\tif (dot(b, c)<-EPS)return +2;\n\tif (norm(b)<norm(c))return -2;\n\treturn 0;\n}\n\nbool intersectSP(const Line &s, const point &p) {\n\treturn abs(s[0] - p) + abs(s[1] - p) - abs(s[1] - s[0])<EPS;\n}\nbool isSamePoint(const point &p1, const point &p2) {\n\treturn p1==p2||abs(p1 - p2)<=EPS;\n}\nbool intersectSS(const Line &s, const Line &t) {\n\treturn ccw(s[0], s[1], t[0])*ccw(s[0], s[1], t[1]) <= 0 &&\n\t\tccw(t[0], t[1], s[0])*ccw(t[0], t[1], s[1]) <= 0;\n}\nbool connectSS(const Line &s, const Line &t) {\n\tREP(i, 2)REP(j, 2) {\n\t\tif (isSamePoint(s[i], t[j]))return true;\n\t\t//if (s[i] == t[j])return true;\n\t}\n\treturn false;\n}\npoint crosspoint(const Line &l, const Line &m) {\n\tdouble A = cross(l[1] - l[0], m[1] - m[0]);\n\tdouble B = cross(l[1] - l[0], l[1] - m[0]);\n\tif (abs(A)<EPS&&abs(B)<EPS)return m[0];\n\tif (abs(A)<EPS)assert(false);\n\treturn m[0] + B / A * (m[1] - m[0]);\n}\nstruct Circle {\n\tpoint c; double r;\n\tint id;\n\tCircle(const point &c_, double r_, int id_) :c(c_), r(r_), id(id_) {}\n\tbool contains(const point &p) {\n\t\tif (dist(c, p)<r + EPS)return true;\n\t\telse return false;\n\t}\n};\n\nstruct Polygon :public vector<point> {\n\t//0->OUT,1->ON,2->IN\n\tint contains(const point &p) {\n\t\tbool in = false;\n\t\tint N = this->size();\n\t\tfor (int i = 0; i<N; i++) {\n\t\t\tpoint a = this->at(i) - p;\n\t\t\tpoint b = this->at((i + 1) % N) - p;\n\t\t\tif (imag(a)>imag(b))std::swap(a, b);\n\t\t\tif (imag(a) <= 0 && 0<imag(b))if (cross(a, b)<0)in = !in;\n\t\t\tif (cross(a, b) == 0 && dot(a, b) <= 0)return 1;\n\t\t}\n\t\treturn in ? 2 : 0;\n\t}\n\tvoid print() {\n\t\tif (DEBUG) {\n\t\t\tcerr << \"number of points:\" << this->size() << endl;\n for(int i=0;i<(int)this->size();i++){\n\t\t\t\tcerr << i + 1 << \":\" << this->at(i) << endl;\n\t\t\t}\n\t\t}\n\n\t}\n};\ntypedef vector<Circle> Circles;\nset<int> get_enclosing_circle(const point &p, const Circles &Cs) {\n\tset<int> ret;\n\tfor (auto c : Cs) {\n\t\tif (c.contains(p))ret.insert(c.id);\n\t}\n\treturn ret;\n}\n\nstruct Equiv {\n\tvector<int>links;\n\tEquiv(int n) :links(n) {\n\t\tREP(i, n)links[i] = i;\n\t}\n\tint find(int x) {\n\t\tint xx = links[x];\n\t\tif (xx == x)return x;\n\t\treturn links[x] = find(xx);\n\t}\n\tvoid unify(int x, int y) {\n\t\tint xx = find(x), yy = find(y);\n\t\tif (xx <= yy)links[yy] = xx;\n\t\telse links[xx] = yy;\n\t}\n};\ntypedef vector<Lines> vLines;\nvLines connectedComponent(const Lines &ls) {\n\tvLines ret;\n\tEquiv equiv(ls.size());\n\tREP(i, (int)ls.size()) {\n\t\tREP(j, i) {\n\t\t\tif (connectSS(ls[i], ls[j])) {\n\t\t\t\tequiv.unify(i, j);\n\t\t\t}\n\t\t}\n\t}\n\tREP(i, (int)ls.size()) {\n\t\tif (equiv.find(i) == i) {\n\t\t\tLines newLs;\n\t\t\tnewLs.push_back(ls[i]);\n\t\t\tFOR(j, i + 1, (int)ls.size()) {\n\t\t\t\tif (equiv.find(j) == i)newLs.push_back(ls[j]);\n\t\t\t}\n\t\t\tret.push_back(newLs);\n\t\t}\n\t}\n\treturn ret;\n}\ntypedef pair<double, point>doublePoint;\ntypedef vector<doublePoint>vDoublePoint;\ntypedef map<point, vDoublePoint>adjPoint;\ntypedef vector<point>Points;\n\npoint findNext(const vDoublePoint &vdp, const point &p) {\n\t//隣接点のリスト(偏角ソート済み)から移動前の点を探してその次\n\tint n = vdp.size();\n\tREP(i, n) {\n\t\tif (p == vdp[i].second) {\n\t\t\treturn vdp[(i + 1) % n].second;\n\t\t}\n\t}\n\treturn vdp[0].second;\n}\nbool used[101][101];\nvoid make_polys(point minPoint, vector<Polygon>&polys,adjPoint &aPoint,map<point, int>&p2id,\nmap<int, point>&id2p,int id) {\n\tPolygon ret;\n\tREP(i, id)REP(j, id)used[i][j] = false;\n\tret.push_back(minPoint);\n\tpoint curP = aPoint[minPoint][0].second;\n\tused[p2id[minPoint]][p2id[curP]] = true;\n\tpoint lastP = minPoint;\n\twhile (curP != minPoint) {\n\t\tret.push_back(curP);\n\t\tpoint nextP = findNext(aPoint[curP], lastP);\n\t\tused[p2id[curP]][p2id[nextP]] = true;\n\t\tlastP = curP;\n\t\tcurP = nextP;\n\t}\n\n\t\n\tpolys.push_back(ret);\n\n bool all_used=false;\n\twhile (!all_used) {\n all_used=true;\n\t\tbool found = false;\n\t\tpoint st, nx;\n st={1e9,1e9};\n\t\tREP(i, id) {\n if(found)break;\n\t\t\tfor (auto nxt : aPoint[id2p[i]]) {\n\t\t\t\tif (!used[i][p2id[nxt.second]]) {\n all_used=false;\n\t\t\t\t\tfound = true;\n if(id2p[i]<st){\n st=id2p[i];\n nx=nxt.second;\n }\n\t\t\t\t}\n\t\t\t}\n\t\t}\n if(all_used)break;\n\t\tPolygon res;\n\t\tres.push_back(st);\n\t\tres.push_back(nx);\n\t\tused[p2id[st]][p2id[nx]] = true;\n\t\tpoint cur = nx;\n\t\tpoint las = st;\n\t\twhile (cur != st) {\n\t\t\tvDoublePoint v = aPoint[cur];\n\t\t\tint n = v.size();\n\t\t\tint s_idx = -1;\n\t\t\tbool found = false;\n\t\t\tREP(i, n) {\n\t\t\t\tif (isSamePoint(v[i].second,las)) {\n\t\t\t\t\ts_idx = i; break;\n\t\t\t\t}\n\t\t\t}\n if(s_idx<0){\n cerr<<cur<<endl;\n cerr<<las<<endl;\n }\n assert(s_idx>=0);\n\t\t\tfor (int i = s_idx + 1; i < s_idx + n + 1; i++) {\n\t\t\t\tint idx = i % n;\n\t\t\t\tif (v[idx].second == cur)continue;\n\t\t\t\tint cur_id = p2id[cur];\n\t\t\t\tint nxt_id = p2id[v[idx].second];\n\t\t\t\tif (!used[cur_id][nxt_id]) {\n\t\t\t\t\tfound = true;\n\t\t\t\t\tlas = cur;\n\t\t\t\t\tcur = v[idx].second;\n\t\t\t\t\tused[cur_id][nxt_id] = true;\n\t\t\t\t\tres.push_back(cur);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\t//if(!found)break;\n\t\t\tif (cur == st)break;\n\t\t\tif (!found)goto END2;\n\t\t}\n\t\tpolys.push_back(res);\n\tEND2:;\n\t}\n\n}\nvector<Polygon> trace(const Lines &ls) {\n\t//隣接点(偏角付き)のリストを作成\n\tmap<point, vDoublePoint> aPoint;\n\t//頂点に番号を付けて辺の使用を記録\n\tmap<point, int>p2id;\n\tmap<int, point>id2p;\n\tint id = 0;\n\n\tREP(i, (int)ls.size()) {\n\t\tif (!p2id.count(ls[i][0])) {\n\t\t\tp2id[ls[i][0]] = id;\n\t\t\tid2p[id] = ls[i][0];\n\t\t\tid++;\n\t\t}\n\t\tif (!p2id.count(ls[i][1])) {\n\t\t\tp2id[ls[i][1]] = id;\n\t\t\tid2p[id] = ls[i][1];\n\t\t\tid++;\n\t\t}\n\t\taPoint[ls[i][0]].push_back(doublePoint(arg(ls[i][1] - ls[i][0]), ls[i][1]));\n\t\taPoint[ls[i][1]].push_back(doublePoint(arg(ls[i][0] - ls[i][1]), ls[i][0]));\n\t}\n\tvector<point>minPoints;\n REP(i,id)REP(j,id)used[i][j]=false;\n\t//x座標最小の点の計算と隣接点リストのソート\n\tpoint minPoint(INT_MAX, INT_MAX);\n\tadjPoint::iterator it;\n\tfor (it = aPoint.begin(); it != aPoint.end(); ++it) {\n\t\tpoint p = it->first;\n\t\tminPoints.push_back(p);\n\t\tminPoint = min(minPoint, p);\n\t\tvDoublePoint &vdp = it->second;\n\t\tsort(vdp.begin(), vdp.end());\n\t}\n\tvector<Polygon>polys;\n\tmake_polys(minPoint, polys, aPoint, p2id, id2p, id);\n\treturn polys;\n}\nbool intersectCC(const Circle &a, const Circle &b) {\n\tdouble d = dist(a.c, b.c);\n\treturn abs(a.r - b.r)<d + EPS && d - EPS<a.r + b.r;\n}\nbool unuse[101];\nbool canConnect(point p, point q, const Circles &circles) {\n\tset<int> p_enclose = get_enclosing_circle(p, circles);\n\tset<int> q_enclose = get_enclosing_circle(q, circles);\n\tif (p_enclose.size()>2) {\n\t\tcout << p << endl;\n\t\tfor (auto id : p_enclose) {\n\t\t\tcout << circles[id].c << \" \" << circles[id].r << endl;\n\t\t}\n\t}\n\tassert(p_enclose.size() <= 2);\n\tassert(q_enclose.size() <= 2);\n\tif (p_enclose != q_enclose) {\n\t\treturn false;\n\t}\n REP(i,100)unuse[i]=false;\n\tfor (auto id : p_enclose) {\n\t\tunuse[id] = true;\n\t}\n\tint n = circles.size();\n\tvector<Line>segments;\n\tREP(i, n) {\n\t\tif (unuse[i])continue;\n\t\tFOR(j, i, n) {\n\t\t\tif (i == j)continue;\n\t\t\tif (unuse[j])continue;\n\t\t\tif (intersectCC(circles[i], circles[j])) {\n\t\t\t\tsegments.push_back(Line(circles[i].c, circles[j].c));\n\t\t\t}\n\t\t}\n\t}\n\tvLines cc = connectedComponent(segments);\n\tfor (auto ls : cc) {\n\t\tif (ls.size() <= 2)continue;\n\t\tvector<Polygon>polys = trace(ls);\n\t\tfor (auto poly : polys) {\n\t\t\tif (poly.contains(p) != poly.contains(q))return false;\n\t\t}\n\t}\n\n\treturn true;\n}\n\nvoid solve() {\n\tint N, M; cin >> N >> M;\n\t//cerr << N << \" \" << M << endl;\n\tif (N == 0)exit(0);\n\tCircles circles;\n\tREP(i, N) {\n\t\tunuse[i] = false;\n\t\tdouble x, y, r; cin >> x >> y >> r;\n\t\tpoint c(x, y);\n\t\tcircles.push_back({ c,r ,i });\n\t}\n\twhile (M--) {\n\t\tdouble x1, y1, x2, y2; cin >> x1 >> y1 >> x2 >> y2;\n\t\tpoint p(x1, y1), q(x2, y2);\n\t\tif (canConnect(p, q, circles))cout << \"YES\";\n\t\telse cout << \"NO\";\n\t\tif (M)cout << \" \";\n\t\telse cout << endl;\n\t}\n}\nsigned main() {\n\twhile (true)solve();\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3580, "score_of_the_acc": -0.1248, "final_rank": 13 }, { "submission_id": "aoj_1198_4326321", "code_snippet": "#include\"bits/stdc++.h\"\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(n);i++)\n#define FOR(i,m,n) for(int i=(m);i<(n);i++)\n#define REPR(i,n) for(int i=(n)-1;i>=0;i--)\nconst bool DEBUG = false;\nconst double EPS = 1e-8;\ntypedef complex<double>point;\npoint operator*(const point &p, const double &d) {\n\treturn point(real(p)*d, imag(p)*d);\n}\nnamespace std {\n\tbool operator<(const point &a, const point &b) {\n\t\treturn real(a) != real(b) ? real(a)<real(b) : imag(a)<imag(b);\n\t}\n}\ndouble dist(const point &a, const point &b) {\n\treturn abs(a - b);\n}\nstruct Line :public vector<point> {\n\tLine(const point &a, const point &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\ntypedef vector<Line> Lines;\ndouble cross(const point &a, const point &b) {\n\treturn real(a)*imag(b) - imag(a)*real(b);\n}\ndouble dot(const point &a, const point &b) {\n\treturn real(a)*real(b) + imag(a)*imag(b);\n}\nint ccw(point a, point b, point c) {\n\tb = b - a, c = c - a;\n\tif (cross(b, c)>EPS)return +1;\n\tif (cross(b, c)<-EPS)return -1;\n\tif (dot(b, c)<-EPS)return +2;\n\tif (norm(b)<norm(c))return -2;\n\treturn 0;\n}\n\nbool intersectSP(const Line &s, const point &p) {\n\treturn abs(s[0] - p) + abs(s[1] - p) - abs(s[1] - s[0])<EPS;\n}\nbool isSamePoint(const point &p1, const point &p2) {\n\treturn p1==p2||abs(p1 - p2)<=EPS;\n}\nbool intersectSS(const Line &s, const Line &t) {\n\treturn ccw(s[0], s[1], t[0])*ccw(s[0], s[1], t[1]) <= 0 &&\n\t\tccw(t[0], t[1], s[0])*ccw(t[0], t[1], s[1]) <= 0;\n}\nbool connectSS(const Line &s, const Line &t) {\n\tREP(i, 2)REP(j, 2) {\n\t\tif (isSamePoint(s[i], t[j]))return true;\n\t\t//if (s[i] == t[j])return true;\n\t}\n\treturn false;\n}\npoint crosspoint(const Line &l, const Line &m) {\n\tdouble A = cross(l[1] - l[0], m[1] - m[0]);\n\tdouble B = cross(l[1] - l[0], l[1] - m[0]);\n\tif (abs(A)<EPS&&abs(B)<EPS)return m[0];\n\tif (abs(A)<EPS)assert(false);\n\treturn m[0] + B / A * (m[1] - m[0]);\n}\nstruct Circle {\n\tpoint c; double r;\n\tint id;\n\tCircle(const point &c_, double r_, int id_) :c(c_), r(r_), id(id_) {}\n\tbool contains(const point &p) {\n\t\tif (dist(c, p)<r + EPS)return true;\n\t\telse return false;\n\t}\n};\n\nstruct Polygon :public vector<point> {\n\t//0->OUT,1->ON,2->IN\n\tint contains(const point &p) {\n\t\tbool in = false;\n\t\tint N = this->size();\n\t\tfor (int i = 0; i<N; i++) {\n\t\t\tpoint a = this->at(i) - p;\n\t\t\tpoint b = this->at((i + 1) % N) - p;\n\t\t\tif (imag(a)>imag(b))std::swap(a, b);\n\t\t\tif (imag(a) <= 0 && 0<imag(b))if (cross(a, b)<0)in = !in;\n\t\t\tif (cross(a, b) == 0 && dot(a, b) <= 0)return 1;\n\t\t}\n\t\treturn in ? 2 : 0;\n\t}\n\tvoid print() {\n\t\tif (DEBUG) {\n\t\t\tcerr << \"number of points:\" << this->size() << endl;\n for(int i=0;i<(int)this->size();i++){\n\t\t\t\tcerr << i + 1 << \":\" << this->at(i) << endl;\n\t\t\t}\n\t\t}\n\n\t}\n};\ntypedef vector<Circle> Circles;\nset<int> get_enclosing_circle(const point &p, const Circles &Cs) {\n\tset<int> ret;\n\tfor (auto c : Cs) {\n\t\tif (c.contains(p))ret.insert(c.id);\n\t}\n\treturn ret;\n}\n\nstruct Equiv {\n\tvector<int>links;\n\tEquiv(int n) :links(n) {\n\t\tREP(i, n)links[i] = i;\n\t}\n\tint find(int x) {\n\t\tint xx = links[x];\n\t\tif (xx == x)return x;\n\t\treturn links[x] = find(xx);\n\t}\n\tvoid unify(int x, int y) {\n\t\tint xx = find(x), yy = find(y);\n\t\tif (xx <= yy)links[yy] = xx;\n\t\telse links[xx] = yy;\n\t}\n};\ntypedef vector<Lines> vLines;\nvLines connectedComponent(const Lines &ls) {\n\tvLines ret;\n\tEquiv equiv(ls.size());\n\tREP(i, (int)ls.size()) {\n\t\tREP(j, i) {\n\t\t\tif (connectSS(ls[i], ls[j])) {\n\t\t\t\tequiv.unify(i, j);\n\t\t\t}\n\t\t}\n\t}\n\tREP(i, (int)ls.size()) {\n\t\tif (equiv.find(i) == i) {\n\t\t\tLines newLs;\n\t\t\tnewLs.push_back(ls[i]);\n\t\t\tFOR(j, i + 1, (int)ls.size()) {\n\t\t\t\tif (equiv.find(j) == i)newLs.push_back(ls[j]);\n\t\t\t}\n\t\t\tret.push_back(newLs);\n\t\t}\n\t}\n\treturn ret;\n}\ntypedef pair<double, point>doublePoint;\ntypedef vector<doublePoint>vDoublePoint;\ntypedef map<point, vDoublePoint>adjPoint;\ntypedef vector<point>Points;\n\npoint findNext(const vDoublePoint &vdp, const point &p) {\n\t//隣接点のリスト(偏角ソート済み)から移動前の点を探してその次\n\tint n = vdp.size();\n\tREP(i, n) {\n\t\tif (p == vdp[i].second) {\n\t\t\treturn vdp[(i + 1) % n].second;\n\t\t}\n\t}\n\treturn vdp[0].second;\n}\nbool used[101][101];\nvoid make_polys(point minPoint, vector<Polygon>&polys,adjPoint &aPoint,map<point, int>&p2id,\nmap<int, point>&id2p,int id) {\n\tPolygon ret;\n\tREP(i, id)REP(j, id)used[i][j] = false;\n\tret.push_back(minPoint);\n\tpoint curP = aPoint[minPoint][0].second;\n\tused[p2id[minPoint]][p2id[curP]] = true;\n\tpoint lastP = minPoint;\n\twhile (curP != minPoint) {\n\t\tret.push_back(curP);\n\t\tpoint nextP = findNext(aPoint[curP], lastP);\n\t\tused[p2id[curP]][p2id[nextP]] = true;\n\t\tlastP = curP;\n\t\tcurP = nextP;\n\t}\n\t//ret.push_back(minPoint);\n\n\t\n\tpolys.push_back(ret);\n\n bool all_used=false;\n\twhile (!all_used) {\n all_used=true;\n\t\tbool found = false;\n\t\tpoint st, nx;\n st={1e9,1e9};\n\t\tREP(i, id) {\n if(found)break;\n\t\t\tfor (auto nxt : aPoint[id2p[i]]) {\n\t\t\t\tif (!used[i][p2id[nxt.second]]) {\n all_used=false;\n\t\t\t\t\tfound = true;\n if(id2p[i]<st){\n st=id2p[i];\n nx=nxt.second;\n }\n\t\t\t\t}\n\t\t\t}\n\t\t}\n if(all_used)break;\n\t\t//if (!found)break;\n\t\tPolygon res;\n\t\tres.push_back(st);\n\t\tres.push_back(nx);\n\t\tused[p2id[st]][p2id[nx]] = true;\n\t\tpoint cur = nx;\n\t\tpoint las = st;\n\t\twhile (cur != st) {\n\t\t\tvDoublePoint v = aPoint[cur];\n\t\t\tint n = v.size();\n\t\t\tint s_idx = -1;\n\t\t\tbool found = false;\n\t\t\tREP(i, n) {\n\t\t\t\tif (isSamePoint(v[i].second,las)) {\n\t\t\t\t\ts_idx = i; break;\n\t\t\t\t}\n\t\t\t}\n if(s_idx<0){\n cerr<<cur<<endl;\n cerr<<las<<endl;\n }\n assert(s_idx>=0);\n\t\t\tfor (int i = s_idx + 1; i < s_idx + n + 1; i++) {\n\t\t\t\tint idx = i % n;\n\t\t\t\tif (v[idx].second == cur)continue;\n\t\t\t\tint cur_id = p2id[cur];\n\t\t\t\tint nxt_id = p2id[v[idx].second];\n\t\t\t\tif (!used[cur_id][nxt_id]) {\n\t\t\t\t\tfound = true;\n\t\t\t\t\tlas = cur;\n\t\t\t\t\tcur = v[idx].second;\n\t\t\t\t\tused[cur_id][nxt_id] = true;\n\t\t\t\t\tres.push_back(cur);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\t//if(!found)break;\n\t\t\tif (cur == st)break;\n\t\t\tif (!found)goto END2;\n\t\t}\n\t\tpolys.push_back(res);\n\tEND2:;\n\t}\n\n}\nvector<Polygon> trace(const Lines &ls) {\n\t//隣接点(偏角付き)のリストを作成\n\tmap<point, vDoublePoint> aPoint;\n\t//頂点に番号を付けて辺の使用を記録\n\tmap<point, int>p2id;\n\tmap<int, point>id2p;\n\tint id = 0;\n\n\tREP(i, (int)ls.size()) {\n\t\tif (!p2id.count(ls[i][0])) {\n\t\t\tp2id[ls[i][0]] = id;\n\t\t\tid2p[id] = ls[i][0];\n\t\t\tid++;\n\t\t}\n\t\tif (!p2id.count(ls[i][1])) {\n\t\t\tp2id[ls[i][1]] = id;\n\t\t\tid2p[id] = ls[i][1];\n\t\t\tid++;\n\t\t}\n\t\taPoint[ls[i][0]].push_back(doublePoint(arg(ls[i][1] - ls[i][0]), ls[i][1]));\n\t\taPoint[ls[i][1]].push_back(doublePoint(arg(ls[i][0] - ls[i][1]), ls[i][0]));\n\t}\n\tvector<point>minPoints;\n REP(i,id)REP(j,id)used[i][j]=false;\n\t//vector<vector<bool>>used(id, vector<bool>(id));\n\t//REP(i,id)used[i][i]=true;\n\t//x座標最小の点の計算と隣接点リストのソート\n\tpoint minPoint(INT_MAX, INT_MAX);\n\tadjPoint::iterator it;\n\tfor (it = aPoint.begin(); it != aPoint.end(); ++it) {\n\t\tpoint p = it->first;\n\t\tminPoints.push_back(p);\n\t\tminPoint = min(minPoint, p);\n\t\tvDoublePoint &vdp = it->second;\n\t\tsort(vdp.begin(), vdp.end());\n\t}\n\tvector<Polygon>polys;\n\t//for (auto minpoint : minPoints) {\n\t//\tmake_polys(minpoint, polys, aPoint, p2id, id2p, id);\n\t//}\n\tmake_polys(minPoint, polys, aPoint, p2id, id2p, id);\n\treturn polys;\n}\nbool intersectCC(const Circle &a, const Circle &b) {\n\tdouble d = dist(a.c, b.c);\n\treturn abs(a.r - b.r)<d + EPS && d - EPS<a.r + b.r;\n}\nbool unuse[101];\nbool canConnect(point p, point q, const Circles &circles) {\n\tset<int> p_enclose = get_enclosing_circle(p, circles);\n\tset<int> q_enclose = get_enclosing_circle(q, circles);\n\tif (p_enclose.size()>2) {\n\t\tcout << p << endl;\n\t\tfor (auto id : p_enclose) {\n\t\t\tcout << circles[id].c << \" \" << circles[id].r << endl;\n\t\t}\n\t}\n\tassert(p_enclose.size() <= 2);\n\tassert(q_enclose.size() <= 2);\n\tif (p_enclose != q_enclose) {\n\t\treturn false;\n\t}\n REP(i,100)unuse[i]=false;\n\tfor (auto id : p_enclose) {\n\t\tunuse[id] = true;\n\t}\n\tint n = circles.size();\n\tvector<Line>segments;\n\tREP(i, n) {\n\t\tif (unuse[i])continue;\n\t\tFOR(j, i, n) {\n\t\t\tif (i == j)continue;\n\t\t\tif (unuse[j])continue;\n\t\t\tif (intersectCC(circles[i], circles[j])) {\n\t\t\t\tsegments.push_back(Line(circles[i].c, circles[j].c));\n\t\t\t}\n\t\t}\n\t}\n\tvLines cc = connectedComponent(segments);\n\tfor (auto ls : cc) {\n\t\tif (ls.size() <= 2)continue;\n\t\tvector<Polygon>polys = trace(ls);\n\t\tfor (auto poly : polys) {\n\t\t\t// for (auto pp : poly) {\n\t\t\t// \tcout << pp << endl;\n\t\t\t// }cout << endl;\n\t\t\tif (poly.contains(p) != poly.contains(q))return false;\n\t\t}\n\t}\n\n\treturn true;\n}\n\nvoid solve() {\n\tint N, M; cin >> N >> M;\n\t//cerr << N << \" \" << M << endl;\n\tif (N == 0)exit(0);\n\tCircles circles;\n\tREP(i, N) {\n\t\tunuse[i] = false;\n\t\tdouble x, y, r; cin >> x >> y >> r;\n\t\tpoint c(x, y);\n\t\tcircles.push_back({ c,r ,i });\n\t}\n\twhile (M--) {\n\t\tdouble x1, y1, x2, y2; cin >> x1 >> y1 >> x2 >> y2;\n\t\tpoint p(x1, y1), q(x2, y2);\n\t\tif (canConnect(p, q, circles))cout << \"YES\";\n\t\telse cout << \"NO\";\n\t\tif (M)cout << \" \";\n\t\telse cout << endl;\n\t}\n}\nsigned main() {\n\twhile (true)solve();\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3584, "score_of_the_acc": -0.1256, "final_rank": 14 }, { "submission_id": "aoj_1198_3616346", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\n#include<vector>\n#include<iomanip>\n#include<math.h>\n#include<complex>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<map>\n#include<set>\n#include<bitset>\n#include<functional>\n#include<assert.h>\n#include<numeric>\nusing namespace std;\n#define REP(i,m,n) for(int i=(int)(m) ; i < (int) (n) ; ++i )\n#define rep(i,n) REP(i,0,n)\nusing ll = long long;\nconst int inf=1e9+7;\nconst ll longinf=1LL<<60 ;\nconst ll mod=1e9+7 ;\n\nusing ld = double;\nusing Point = complex<ld>;\nconst ld eps = 1e-9;\nconst ld pi = acos(-1.0);\n\nbool eq(ld a, ld b) {\n\treturn (abs(a - b) < eps);\n}\n\nbool cmp(Point x,Point y){\n\tif(eq(x.real(),y.real()))return x.imag()<y.imag();\n\treturn x.real()<y.real();\n}\n\nbool eqq(Point x,Point y){\n\treturn eq(x.real(),y.real())&&eq(x.imag(),y.imag());\n}\n//内積\nld dot(Point a, Point b) {\n\treturn real(conj(a)*b);\n}\n//外積\nld cross(Point a, Point b) {\n\treturn imag(conj(a)*b);\n}\n\n\n//線分\n//直線にするなら十分通い2点を端点とすればよい\nclass Line {\npublic:\n\tPoint a, b;\n};\n//円\nclass Circle {\npublic:\n\tPoint p;\n\tld r;\n};\n//3点の位置関係\nint ccw(Point a, Point b, Point c) {\n\tb -= a; c -= a;\n\tif (cross(b, c) > eps)return 1;//a,b,cが反時計回り\n\tif (cross(b, c) < -eps)return -1;//a,b,cが時計回り\n\tif (dot(b, c) < 0)return 2;//c,a,bの順に一直線\n\tif (norm(b) < norm(c))return -2;//a,b,cの順に一直線\n\treturn 0;//a,c,bの順に一直線\n}\n//2直線の交差判定\nbool isis_ll(Line l, Line m) {\n\treturn !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\n//直線と線分の交差判定\nbool isis_ls(Line l, Line s) {\n\treturn (cross(l.b - l.a, s.a - l.a)*cross(l.b - l.a, s.b - l.a) < eps);\n}\n//点が直線上に存在するか\nbool isis_lp(Line l, Point p) {\n\treturn (abs(cross(l.b - p, l.a - p)) < eps);\n}\n//点が線分上に存在するか\nbool isis_sp(Line s, Point p) {\n\treturn (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n//線分と線分の交差判定\nbool isis_ss(Line s, Line t) {\n\tif (isis_sp(s, t.a) || isis_sp(s, t.b) || isis_sp(t, s.a) || isis_sp(t, s.b))return true;\n\treturn(cross(s.b - s.a, t.a - s.a)*cross(s.b - s.a, t.b - s.a) < -eps && cross(t.b - t.a, s.a - t.a)*cross(t.b - t.a, s.b - t.a) < -eps);\n}\n//点から直線への垂線の足\nPoint proj(Line l, Point p) {\n\tld t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n\treturn l.a + t * (l.a - l.b);\n}\n//直線と直線の交点\n//平行な2直線に対しては使うな!!!!\nPoint is_ll(Line s, Line t) {\n\tPoint sv = s.b - s.a; Point tv = t.b - t.a;\n\treturn s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n//直線と点の距離\nld dist_lp(Line l, Point p) {\n\treturn abs(p - proj(l, p));\n}\n//直線と直線の距離\nld dist_ll(Line l, Line m) {\n\treturn isis_ll(l, m) ? 0 : dist_lp(l, m.a);\n}\n//線分と直線の距離\nld dist_ls(Line l, Line s) {\n\treturn isis_ls(l, s) ? 0 : min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\n//線分と点の距離\nld dist_sp(Line s, Point p) {\n\tPoint r = proj(s, p);\n\treturn isis_sp(s, r) ? abs(p - r) : min(abs(p - s.a), abs(p - s.b));\n}\n//線分と線分の距離\nld dist_ss(Line s, Line t) {\n\tif (isis_ss(s, t))return 0;\n\treturn min({ dist_sp(s,t.a),dist_sp(s,t.b),dist_sp(t,s.a),dist_sp(t,s.b) });\n}\n\nbool included(Point p,vector<Point>& pol){\n int n=pol.size();\n ld area=0;\n rep(i,n){\n area+=arg((pol[i]-p)/(pol[(i+1)%n]-p));\n }\n return abs(area) > eps;\n}\n\nvoid solve(int n,int Q){\n Circle c[n];\n Point p[n];\n rep(i,n){\n double x,y,r;\n cin>>x>>y>>r;\n p[i]=Point(x,y);\n c[i]={p[i],r};\n }\n\n vector<int> in(n);\n rep(i,n)rep(j,n){\n if(i==j)continue;\n if(c[i].r>c[j].r+abs(c[i].p-c[j].p))in[j]=true;\n }\n vector<vector<int>> v(n);\n vector<vector<int>> used(n);\n rep(i,n){\n if(in[i])continue;\n rep(j,n){\n if(i==j||in[j])continue;\n if(c[i].r+c[j].r>abs(c[i].p-c[j].p)){\n v[i].push_back(j);\n }\n }\n used[i].resize(v[i].size());\n sort(v[i].begin(),v[i].end(),[&](int x,int y){\n return arg(c[x].p-c[i].p)<arg(c[y].p-c[i].p);\n });\n }\n vector<vector<Point>> pols;\n rep(i,n){\n rep(j,v[i].size()){\n if(used[i][j])continue;\n used[i][j]=true;\n vector<Point> pol;\n int pre=i, cur=v[i][j];\n pol.push_back(p[pre]);\n ld area=cross(p[cur],p[pre]);\n while(cur!=i){\n int nxt;\n rep(k,v[cur].size()){\n if(v[cur][k]==pre){\n used[cur][(k+1)%v[cur].size()]=true;\n nxt=v[cur][(k+1)%v[cur].size()];\n break;\n }\n }\n pre=cur;cur=nxt;\n area+=cross(p[cur],p[pre]);\n pol.push_back(p[pre]);\n }\n if(area>eps)pols.push_back(pol);\n }\n }\n rep(aaa,Q){\n Point q[2];\n rep(i,2){\n int x,y;\n cin>>x>>y;\n q[i]=Point(x,y);\n }\n vector<int> inc[2];\n rep(i,2){\n rep(j,n){\n if(abs(q[i]-p[j])<c[j].r)inc[i].push_back(j);\n }\n }\n if(inc[0]!=inc[1]){\n cout<<\"NO\";\n if(aaa!=Q-1)cout<<\" \";\n continue;\n }\n if(inc[0].size()&&inc[0]==inc[1]){\n cout<<\"YES\";\n if(aaa!=Q-1)cout<<\" \";\n continue;\n }\n rep(i,2){\n rep(j,pols.size()){\n if(included(q[i],pols[j]))inc[i].push_back(j);\n }\n }\n if(inc[0]==inc[1])cout<<\"YES\";\n else cout<<\"NO\";\n if(aaa!=Q-1)cout<<\" \";\n }\n cout<<endl;\n\n}\nint main(){\n int n,q;\n while(cin>>n>>q,n!=0)solve(n,q);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3564, "score_of_the_acc": -0.0598, "final_rank": 8 }, { "submission_id": "aoj_1198_3219839", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))\n#define all(x) (x).begin(),(x).end()\n#define pb push_back\n#define fi first\n#define se second\n#define dbg(x) cout<<#x\" = \"<<((x))<<endl\ntemplate<class T,class U> ostream& operator<<(ostream& o, const pair<T,U> &p){o<<\"(\"<<p.fi<<\",\"<<p.se<<\")\";return o;}\ntemplate<class T> ostream& operator<<(ostream& o, const vector<T> &v){o<<\"[\";for(T t:v){o<<t<<\",\";}o<<\"]\";return o;}\n\n/* 基本要素 */\ntypedef complex<double> Point;\ntypedef pair<Point, Point> Line;\ntypedef vector<Point> VP;\nconst double PI = acos(-1);\nconst double EPS = 1e-8; // 許容誤差^2\nconst double INF = 1e9;\n#define X real()\n#define Y imag()\n// #define LE(n,m) ((n) < (m) + EPS)\n#define LE(n,m) ((n) - (m) < EPS)\n// #define GE(n,m) ((n) + EPS > (m))\n#define GE(n,m) (EPS > (m) - (n))\n#define EQ(n,m) (abs((n)-(m)) < EPS)\n\n// 頂点の順序(sortやmax_elementに必要)\nnamespace std {\n bool operator<(const Point a, const Point b) {\n return a.X != b.X ? a.X < b.X : a.Y < b.Y;\n }\n}\n\n// 内積 dot(a,b) = |a||b|cosθ\ndouble dot(Point a, Point b) {\n return a.X*b.X + a.Y*b.Y;\n}\n\n// 外積 cross(a,b) = |a||b|sinθ\ndouble cross(Point a, Point b) {\n return a.X*b.Y - a.Y*b.X;\n}\n\n// 点の進行方向\n// !!! 誤差に注意 !!! (掛け算したものとかなり小さいものを比べているので)\nint ccw(Point a, Point b, Point c) {\n b -= a; c -= a;\n if (cross(b,c) > EPS) return +1; // counter clockwise\n if (cross(b,c) < -EPS) return -1; // clockwise\n if (dot(b,c) < -EPS) return +2; // c--a--b on line\n if (norm(b) < norm(c)) return -2; // a--b--c on line or a==b\n return 0; // a--c--b on line or a==c or b==c\n}\n\n// 多角形の内部判定\n// 点が領域内部なら1、境界上なら2、外部なら0を返す\nint inPolygon(const VP& ps, Point p) {\n int n = ps.size();\n bool in = false;\n rep (i, n) {\n Point a = ps[i] - p;\n Point b = ps[(i + 1) % n] - p;\n if (EQ(cross(a,b), 0) && LE(dot(a,b), 0)) return 2;\n if (a.Y > b.Y) swap(a,b);\n if ((a.Y*b.Y < 0 || (a.Y*b.Y < EPS && b.Y > EPS)) && LE(cross(a, b), 0)) in = !in;\n }\n return in;\n}\n\n\nPoint READ(){\n int x,y;\n cin >>x >>y;\n return Point(x,y);\n}\n\nint main(){\n int n,m;\n while(cin >>n >>m,n){\n VP c(n);\n vector<double> r(n);\n rep(i,n){\n c[i] = READ();\n cin >>r[i];\n }\n\n auto isecCC = [&](int a, int b){\n if(r[a] > r[b]) swap(a,b);\n double d = abs(c[a] - c[b]);\n\n if( r[a]+r[b] < d+EPS ) return false;\n if( d+r[a] < r[b]+EPS ) return false;\n return true;\n };\n\n using D = pair<double,int>;\n vector<vector<D>> g(n);\n rep(i,n){\n rep(j,n)if(j!=i && isecCC(i,j)){\n Point pp = c[j] - c[i];\n double theta = atan2(pp.Y,pp.X);\n g[i].pb({theta,j});\n }\n sort(all(g[i]));\n // dbg(g[i]);\n }\n\n // 領域\n vector<VP> pls;\n\n // (円i, 次に向かう方向)\n vector<vector<bool>> vis(n);\n rep(i,n) vis[i] = vector<bool>(g[i].size());\n\n using pi = pair<int,int>;\n rep(i,n){\n int GG = g[i].size();\n if(GG==0) continue;\n rep(ii,GG){\n if(vis[i][ii]) continue;\n\n queue<pi> que;\n stack<int> c_idx;\n vector<bool> in(n);\n\n in[i] = true;\n c_idx.push(i);\n vis[i][ii] = true;\n que.push({i,ii});\n while(!que.empty()){\n pi cur = que.front();\n que.pop();\n\n // dbg(cur);\n\n int idx = cur.fi;\n int dir = cur.se;\n\n int nidx = g[idx][dir].se;\n int ndir = -1;\n int sz = g[nidx].size();\n rep(j,sz){\n if(g[nidx][j].se == idx){\n ndir = (j+1)%sz;\n break;\n }\n }\n\n assert(ndir >= 0);\n if(!vis[nidx][ndir]){\n if(in[nidx]){\n VP poly;\n while(in[nidx]){\n assert(!c_idx.empty());\n int st_idx = c_idx.top();\n c_idx.pop();\n\n in[st_idx] = false;\n poly.pb(c[st_idx]);\n }\n\n pls.pb(poly);\n }\n\n in[nidx] = true;\n c_idx.push(nidx);\n vis[nidx][ndir] = true;\n que.push({nidx,ndir});\n }\n }\n\n VP poly;\n while(!c_idx.empty()){\n int st_idx = c_idx.top();\n c_idx.pop();\n\n in[st_idx] = false;\n poly.pb(c[st_idx]);\n }\n pls.pb(poly);\n }\n }\n\n // for(VP poly:pls) dbg(poly);\n\n auto IN = [&](int idx, Point p){\n double d = abs(p - c[idx]);\n return d < r[idx];\n };\n\n vector<bool> ans(m,true);\n rep(i,m){\n Point start = READ(), goal = READ();\n bool flg = false;\n rep(j,n){\n if(IN(j,start) || IN(j,goal)) flg = true;\n if( IN(j,start) != IN(j,goal) ) ans[i] = false;\n }\n\n if(!flg){\n for(VP poly:pls)if(poly.size()>=3){\n int vs = inPolygon(poly, start);\n int vg = inPolygon(poly, goal);\n if( vs != vg ) ans[i] = false;\n }\n }\n }\n\n rep(i,m){\n if(i) cout << \" \";\n cout << (ans[i]?\"YES\":\"NO\");\n }\n cout << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3492, "score_of_the_acc": -0.0395, "final_rank": 4 }, { "submission_id": "aoj_1198_3001798", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\n\n\n/* 幾何の基本 */\n\n#include <complex>\n\ntypedef complex<ld> Point;\n\n\nconst ld pi = acos(-1.0);\nconst ld dtop = pi / 180.;\nconst ld ptod = 1. / dtop;\n\nnamespace std {\n\tbool operator<(const Point &lhs, const Point &rhs) {\n\t\tif (lhs.real() < rhs.real() - eps) return true;\n\t\tif (lhs.real() > rhs.real() + eps) return false;\n\t\treturn lhs.imag() < rhs.imag();\n\t}\n}\n\n// 点の入力\nPoint input_Point() {\n\tld x, y;\n\tcin >> x >> y;\n\treturn Point(x, y);\n}\n\n// 誤差つき等号判定\nbool eq(const ld a, const ld b) {\n\treturn (abs(a - b) < eps);\n}\n\n// 内積\nld dot(const Point& a, const Point& b) {\n\treturn real(conj(a) * b);\n}\n\n// 外積\nld cross(const Point& a, const Point& b) {\n\treturn imag(conj(a) * b);\n}\n\n// 直線の定義\nclass Line {\npublic:\n\tPoint a, b;\n\tLine() : a(Point(0, 0)), b(Point(0, 0)) {}\n\tLine(Point a, Point b) : a(a), b(b) {}\n\tPoint operator[](const int _num)const {\n\t\tif (_num == 0)return a;\n\t\telse if (_num == 1)return b;\n\t\telse {\n\t\t\tassert(false);\n\t\t\treturn Point();\n\t\t}\n\t}\n};\n\n// 円の定義\nclass Circle {\npublic:\n\tPoint p;\n\tld r;\n\tCircle() : p(Point(0, 0)), r(0) {}\n\tCircle(Point p, ld r) : p(p), r(r) {}\n};\n\n// ccw\n// 1: a,b,cが反時計周りの順に並ぶ\n//-1: a,b,cが時計周りの順に並ぶ\n// 2: c,a,bの順に直線に並ぶ\n//-2: a,b,cの順に直線に並ぶ\n// 0: a,c,bの順に直線に並ぶ\nint ccw(const Point& a, const Point &b, const Point &c) {\n\tconst Point nb(b - a);\n\tconst Point nc(c - a);\n\tif (cross(nb, nc) > eps) return 1; // a,b,cが反時計周りの順に並ぶ\n\tif (cross(nb, nc) < -eps) return -1; // a,b,cが時計周りの順に並ぶ\n\tif (dot(nb, nc) < 0) return 2; // c,a,bの順に直線に並ぶ\n\tif (norm(nb) < norm(nc)) return -2; // a,b,cの順に直線に並ぶ\n\treturn 0; // a,c,bの順に直線に並ぶ\n}\n\n\n/* 交差判定 */\n\n// 直線と直線の交差判定\nbool isis_ll(const Line& l, const Line& m) {\n\treturn !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\n\n// 直線と線分の交差判定\nbool isis_ls(const Line& l, const Line& s) {\n\treturn isis_ll(l, s) &&\n\t\t(cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < eps);\n}\n\n// 線分と線分の交差判定\nbool isis_ss(const Line& s, const Line& t) {\n\treturn ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n\t\tccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\n// 点の直線上判定\nbool isis_lp(const Line& l, const Point& p) {\n\treturn (abs(cross(l.b - p, l.a - p)) < eps);\n}\n\n// 点の線分上判定\nbool isis_sp(const Line& s, const Point& p) {\n\treturn (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n\n// 垂線の足\nPoint proj(const Line &l, const Point& p) {\n\tld t = dot(p - l.a, l.b - l.a) / norm(l.a - l.b);\n\treturn l.a + t * (l.b - l.a);\n}\n\n//線対象の位置にある点\nPoint reflect(const Line &l, const Point &p) {\n\tPoint pr = proj(l, p);\n\treturn pr * 2.l - p;\n}\n\n// 直線と直線の交点\nPoint is_ll(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tassert(cross(sv, tv) != 0);\n\treturn s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n// 直線と直線の交点\nvector<Point> is_ll2(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tif (cross(sv, tv) != 0)return vector<Point>(1, is_ll(s, t));\n\telse {\n\t\tvector<Point>ans;\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tif (isis_sp(s, t[k]) && find(ans.begin(), ans.end(), t[k]) == ans.end())ans.push_back(t[k]);\n\t\t\tif (isis_sp(t, s[k]) && find(ans.begin(), ans.end(), s[k]) == ans.end())ans.push_back(s[k]);\n\t\t}\n\t\treturn ans;\n\t}\n}\n// 線分と線分の交点\n// 重なってる部分あるとassert(false)\nPoint is_ss(const Line &s, const Line& t) {\n\tif (isis_ss(s, t)) {\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tfor (int l = 0; l < 2; ++l) {\n\t\t\t\tif (s[k] == t[l])return s[k];\n\t\t\t}\n\t\t}\n\t\treturn is_ll(s, t);\n\t}\n\telse {\n\t\t//先にisis_ssしてね\n\t\tassert(false);\n\t\treturn Point(0, 0);\n\t}\n}\n// 線分と線分の交点\nvector<Point> is_ss2(const Line &s, const Line& t) {\n\tvector<Point> kouho(is_ll2(s, t));\n\tvector<Point>ans;\n\tfor (auto p : kouho) {\n\t\tif (isis_sp(s, p) && isis_sp(t, p))ans.emplace_back(p);\n\t}\n\treturn ans;\n}\n// 直線と点の距離\nld dist_lp(const Line& l, const Point& p) {\n\treturn abs(p - proj(l, p));\n}\n\n//直線と直線の距離\nld dist_ll(const Line& l, const Line& m) {\n\treturn isis_ll(l, m) ? 0 : dist_lp(l, m.a);\n}\n\n// 直線と線分の距離\nld dist_ls(const Line& l, const Line& s) {\n\treturn isis_ls(l, s) ? 0 : min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\n\n// 線分と点の距離\nld dist_sp(const Line& s, const Point& p) {\n\tPoint r = proj(s, p);\n\treturn isis_sp(s, r) ? abs(r - p) : min(abs(s.a - p), abs(s.b - p));\n}\n\n// 線分と線分の距離\nld dist_ss(const Line& s, const Line& t) {\n\tif (isis_ss(s, t)) return 0;\n\treturn min({ dist_sp(s, t.a), dist_sp(s, t.b), dist_sp(t, s.a), dist_sp(t, s.b) });\n}\n\n\n//直線と直線の二等分線のベクトル\nLine line_bisection(const Line &s, const Line &t) {\n\tconst Point laglanju(is_ll(s, t));\n\tconst Point avec = !(abs(laglanju - s[0])<eps) ? s[0] - laglanju : s[1] - laglanju;\n\tconst Point bvec = !(abs(laglanju - t[0])<eps) ? t[0] - laglanju : t[1] - laglanju;\n\n\treturn Line(laglanju, laglanju + (abs(bvec)*avec + abs(avec)*bvec) / (abs(avec) + abs(bvec)));\n}\n//点と点の垂直二等分線 aを左に見ながら\nLine point_bisection(const Point&a, const Point&b) {\n\tconst Point cen((a + b) / 2.l);\n\tconst Point vec = (b - a)*Point(0, 1);\n\treturn Line(cen, cen + vec);\n}\n\n//三つの点からなる外心\nPoint outer_center(const vector<Point>&ps) {\n\tassert(ps.size() == 3);\n\tLine l1 = point_bisection(ps[0], ps[1]);\n\tLine l2 = point_bisection(ps[1], ps[2]);\n\treturn is_ll(l1, l2);\n}\n\n\n//三つの直線からなる内心\n//三つの直線が並行でないことは確かめといてね\nPoint inner_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i <static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (vertics[0] == vertics[1] || vertics[1] == vertics[2] || vertics[2] == vertics[0])return vertics[0];\n\tLine bi1(line_bisection(Line(vertics[0], vertics[1]), Line(vertics[0], vertics[2])));\n\tLine bi2(line_bisection(Line(vertics[1], vertics[2]), Line(vertics[1], vertics[0])));\n\tif (bi1[0] == bi2[0])return bi1[0];\n\telse {\n\t\treturn is_ll(bi1, bi2);\n\t}\n}\n\n//三つの直線からなる傍心\n//三つの直線が並行でないことは確かめといてね\nvector<Point> ex_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i < static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (abs(vertics[0] - vertics[1])<eps || abs(vertics[1] - vertics[2])<eps || (abs(vertics[2] - vertics[0])<eps))return vector<Point>();\n\tvector<Point>ecs;\n\tfor (int i = 0; i < 3; ++i) {\n\t\tLine bi1(line_bisection(Line(vertics[i], vertics[i] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[i], vertics[(i + 1) % 3])));\n\t\tLine bi2(line_bisection(Line(vertics[(i + 1) % 3], vertics[(i + 1) % 3] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[(i + 1) % 3], vertics[i])));\n\t\tecs.push_back(is_ll(bi1, bi2));\n\t}\n\treturn ecs;\n}\n\n\n//a,b:並行\n//c:並行でない\n//三つの直線から同距離の位置を求める。\nvector<Point> same_dis(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tvertics.push_back(is_ll(ls[0], ls[2]));\n\tvertics.push_back(is_ll(ls[1], ls[2]));\n\n\tif (abs(vertics[0] - vertics[1]) < eps)return vector<Point>{vertics[0]};\n\tLine bis(line_bisection(ls[0], ls[1]));\n\tvector<Point>ecs;\n\n\tLine abi(line_bisection(Line(vertics[0], vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, abi));\n\n\n\tLine bbi(line_bisection(Line(vertics[0], 2.l*vertics[0] - vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, bbi));\n\n\treturn ecs;\n}\n/* 円 */\n\n// 円と円の交点\nvector<Point> is_cc(const Circle& c1, const Circle& c2) {\n\tvector<Point> res;\n\tld d = abs(c1.p - c2.p);\n\tld rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n\tld dfr = c1.r * c1.r - rc * rc;\n\tif (abs(dfr) < eps) dfr = 0.0;\n\telse if (dfr < 0.0) return res; // no intersection\n\tld rs = sqrt(dfr);\n\tPoint diff = (c2.p - c1.p) / d;\n\tres.push_back(c1.p + diff * Point(rc, rs));\n\tif (dfr != 0.0) res.push_back(c1.p + diff * Point(rc, -rs));\n\treturn res;\n}\n\n/*\n点が円の中にいるか\n0 => out\n1 => on\n2 => in*/\nint is_in_Circle(const Point& p, const Circle &cir) {\n\tld dis = abs(cir.p - p);\n\tif (dis > cir.r + eps)return 0;\n\telse if (dis < cir.r - eps)return 2;\n\telse return 1;\n}\nint is_in_Circle(const Circle &cir, const Point& p) {\n\tld dis = abs(cir.p - p);\n\tif (dis > cir.r + eps)return 0;\n\telse if (dis < cir.r - eps)return 2;\n\telse return 1;\n}\n/*\n円lcが円rcの中にいるか\n0 => out\n1 => on\n2 => in*/\nint Circle_in_Circle(const Circle &lc, const Circle&rc) {\n\tld dis = abs(lc.p - rc.p);\n\tif (dis < rc.r - lc.r - eps)return 2;\n\telse if (dis>rc.r - lc.r + eps)return 0;\n\telse return 1;\n}\n\n// 円と直線の交点\nvector<Point> is_lc(const Circle& c, const Line& l) {\n\tvector<Point> res;\n\tld d = dist_lp(l, c.p);\n\tif (d < c.r + eps) {\n\t\tld len = (d > c.r) ? 0.0 : sqrt(c.r * c.r - d * d); //safety;\n\t\tPoint nor = (l.a - l.b) / abs(l.a - l.b);\n\t\tres.push_back(proj(l, c.p) + len * nor);\n\t\tres.push_back(proj(l, c.p) - len * nor);\n\t}\n\treturn res;\n}\n\n// 円と線分の距離\nvector<Point> is_sc(const Circle& c, const Line& l) {\n\tvector<Point> v = is_lc(c, l), res;\n\tfor (Point p : v)\n\t\tif (isis_sp(l, p)) res.push_back(p);\n\treturn res;\n}\n\n// 円と点の接線\nvector<Line> tangent_cp(const Circle& c, const Point& p) {\n\tvector<Line> ret;\n\tPoint v = c.p - p;\n\tld d = abs(v);\n\tld l = sqrt(norm(v) - c.r * c.r);\n\tif (isnan(l)) { return ret; }\n\tPoint v1 = v * Point(l / d, c.r / d);\n\tPoint v2 = v * Point(l / d, -c.r / d);\n\tret.push_back(Line(p, p + v1));\n\tif (l < eps) return ret;\n\tret.push_back(Line(p, p + v2));\n\treturn ret;\n}\n\n// 円と円の接線\nvector<Line> tangent_cc(const Circle& c1, const Circle& c2) {\n\tvector<Line> ret;\n\tif (abs(c1.p - c2.p) - (c1.r + c2.r) > -eps) {\n\t\tPoint center = (c1.p * c2.r + c2.p * c1.r) / (c1.r + c2.r);\n\t\tret = tangent_cp(c1, center);\n\t}\n\tif (abs(c1.r - c2.r) > eps) {\n\t\tPoint out = (-c1.p * c2.r + c2.p * c1.r) / (c1.r - c2.r);\n\t\tvector<Line> nret = tangent_cp(c1, out);\n\t\tret.insert(ret.end(), nret.begin(), nret.end());\n\t}\n\telse {\n\t\tPoint v = c2.p - c1.p;\n\t\tv /= abs(v);\n\t\tPoint q1 = c1.p + v * Point(0, 1) * c1.r;\n\t\tPoint q2 = c1.p + v * Point(0, -1) * c1.r;\n\t\tret.push_back(Line(q1, q1 + v));\n\t\tret.push_back(Line(q2, q2 + v));\n\t}\n\treturn ret;\n}\n//二つの円の重なり面積\nld two_Circle_area(const Circle&l, const Circle&r) {\n\tld dis = abs(l.p - r.p);\n\tif (dis > l.r + r.r)return 0;\n\telse if (dis + r.r < l.r) {\n\t\treturn r.r*r.r*pi;\n\t}\n\telse if (dis + l.r < r.r) {\n\t\treturn l.r*l.r*pi;\n\t}\n\telse {\n\t\tld ans = (l.r)*(l.r)*acos((dis*dis + l.r*l.r - r.r*r.r) / (2 * dis*l.r)) +\n\t\t\t(r.r)*(r.r)*acos((dis*dis + r.r*r.r - l.r*l.r) / (2 * dis*r.r)) -\n\t\t\tsqrt(4 * dis*dis*l.r*l.r - (dis*dis + l.r*l.r - r.r*r.r)*(dis*dis + l.r*l.r - r.r*r.r)) / 2;\n\t\treturn ans;\n\t}\n\n}\n\n/* 多角形 */\n\ntypedef vector<Point> Polygon;\n\n\n// 面積\nld get_area(const Polygon &p) {\n\tld res = 0;\n\tint n = p.size();\n\tfor (int j = 0; j<n; ++j) res += cross(p[j], p[(j + 1) % n]);\n\treturn res / 2;\n}\n\n// 円の内外判定\n/*0 => out\n1 => on\n2 => in*/\nint convex_contains(const Polygon &poly, const Point& p) {\n\tld angle = 0;\n\tint n = poly.size();\n\tfor(int i=0;i<n;++i) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n];\n\t\tif (isis_sp(Line(a, b), p)) return 1;\n\t\tangle += arg((b - p) / (a - p));\n\t}\n\treturn eq(angle, 0) ? 0 : 2;\n}\n\n\nstruct Edge {\n\tint src;\n\tint dest;\n};\nusing Graph=vector<vector<Edge>>;\n\n//線分アレンジメント後に、\n//閉路の面積の和を求める。\nvoid dfs(set<pair<int,int>>&real_set,set<pair<int ,int>>&aset,const int now, const int from, vector<int>&prevs, vector<Polygon>&ans_polys, const vector<Point>&ps, const Graph&g) {\n\tvector<pair<ld, int>>next_points;\n\n\tPoint from_p = from == -1 ? ps[now] + Point(-3e6, 1) : ps[from];\n\tPoint now_p = ps[now];\n\tfor (auto e : g[now]) {\n\t\tif (e.dest == from)continue;\n\t\tPoint next_p = ps[e.dest];\n\n\t\tld costheta = dot(from_p - now_p, next_p - now_p) / (abs(from_p - now_p)*abs(next_p - now_p));\n\t\tcostheta *= 0.3;\n\t\tld d = acos(costheta);\n\t\tif (ccw(from_p, now_p, next_p) != 1) {\n\t\t\td = 2 * pi - d;\n\t\t}\n\t\tnext_points.push_back(make_pair(d, e.dest));\n\t}\n\tsort(next_points.begin(), next_points.end());\n\n\tfor (auto n_p : next_points) {\n\t\tif (aset.find(make_pair(now, n_p.second))!=aset.end()) {\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tif (real_set.find(make_pair(now, n_p.second)) != real_set.end()) {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\taset.emplace(now,n_p.second);\n\t\t}\n\n\t\tif (prevs[n_p.second] != -1) {\n\t\t\tint k=now;\n\t\t\tPolygon poly(1,ps[k]);\n\t\t\treal_set.emplace(k,n_p.second);\n\t\t\twhile (k != n_p.second) {\n\t\t\t\tint a = k;\n\t\t\t\tk=prevs[k];\n\t\t\t\treal_set.emplace(k,a);\n\t\t\t\tpoly.push_back(ps[k]);\n\t\t\t}\n\t\t\t\n\t\t\tld plus = get_area(poly);\n\t\t\tif (plus<eps) {\n\t\t\t\treverse(poly.begin(),poly.end());\n\t\t\t\tans_polys.push_back(poly);\n\t\t\t}\n\t\t\tthrow(false);\n\t\t}\n\t\telse {\n\n\t\t\tprevs[n_p.second] = now;\n\t\t\tdfs(real_set,aset, n_p.second, now, prevs, ans_polys, ps, g);\n\t\t\tprevs[n_p.second] = -1;\n\t\t}\n\n\t}\n\treturn ;\n}\n\nint main() {\n\tint t=0;\n\twhile (true) {\n\t\tint N,M;cin>>N>>M;\n\t\tt++;\n\n\t\tif(!N)break;\n\t\tvector<Circle>cs;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tint x,y,r;cin>>x>>y>>r;\n\t\t\tcs.push_back(Circle(Point(x,y),r));\n\t\t}\n\t\tvector<vector<Edge>>edges(N);\n\t\tGraph g(N);\n\t\tint sum=0;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tfor (int j = i + 1; j < N; ++j) {\n\t\t\t\t\n\t\t\t\tld dis=abs(cs[i].p-cs[j].p);\n\t\t\t\tif (Circle_in_Circle(cs[i], cs[j])<=1&&Circle_in_Circle(cs[j],cs[i])<=1&&dis<cs[i].r+cs[j].r) {\n\t\t\t\t\tedges[i].push_back(Edge{ i,j });\n\t\t\t\t\tedges[j].push_back(Edge{ j,i });\n\t\t\t\t\tsum++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<Point>ps(N);\n\t\tfor(int i=0;i<N;++i)ps[i]=cs[i].p;\n\n\t\tvector<Polygon>polys;\n\t\tset<pair<int,int>>aset;\n\n\t\tfor(int i=0;i<N;++i) {\n\t\t\tfor (int j = 0; j < edges[i].size();++j) {\n\t\t\t\tif (aset.find(make_pair(i, j)) == aset.end()) {\n\t\t\t\t\ttry {\n\t\t\t\t\t\tvector<int>prevs(N, -1);\n\t\t\t\t\t\tprevs[i] = -2;\n\t\t\t\t\t\tset<pair<int,int>>nset;\n\t\t\t\t\t\tdfs(aset,nset, i, -1, prevs, polys, ps, edges);\n\t\t\t\t\t}\n\t\t\t\t\tcatch (...) {\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tfor (int i = 0; i < M; ++i) {\n\t\t\tvector<Point>query_points;\n\t\t\t{\n\t\t\t\tint a,b,c,d;cin>>a>>b>>c>>d;\n\t\t\t\tPoint p,q;\n\t\t\t\tp=Point(a,b);\n\t\t\t\tq=Point(c,d);\n\t\t\t\tquery_points = vector<Point>{ p,q };\n\t\t\t}\n\t\t\tvector<vector<int>>in_circles(2);\n\t\t\tfor (int j = 0; j < 2; ++j) {\n\t\t\t\tfor (int k = 0; k < N; ++k) {\n\t\t\t\t\tif (is_in_Circle(cs[k], query_points[j])) {\n\t\t\t\t\t\tin_circles[j].push_back(true);\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\tin_circles[j].push_back(false);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tbool ok;\n\t\t\tif (in_circles[0] != in_circles[1]) {\n\t\t\t\tok=false;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (all_of(in_circles[0].begin(), in_circles[0].end(), [](const int a) {return a == 0; })) {\n\t\t\t\t\tvector<vector<int>>in_polygons(2,vector<int>(polys.size()));\n\t\t\t\t\tfor (int j = 0; j < 2; ++j) {\n\t\t\t\t\t\tfor (int k = 0; k < polys.size(); ++k) {\n\t\t\t\t\t\t\tif (convex_contains(polys[k], query_points[j])) {\n\t\t\t\t\t\t\t\tin_polygons[j][k] = true;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (in_polygons[0] == in_polygons[1]) {\n\t\t\t\t\t\tok=true;\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\tok=false;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tok=true;\n\t\t\t\t}\n\n\t\t\t}\n\t\t\tif(ok)cout<<\"YES\";\n\t\t\telse cout<<\"NO\";\n\t\t\tif(i==M-1)cout<<endl;\n\t\t\telse cout<<\" \";\n\t\t\t\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3280, "score_of_the_acc": -0.0345, "final_rank": 1 }, { "submission_id": "aoj_1198_3001762", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\n\n\n/* 幾何の基本 */\n\n#include <complex>\n\ntypedef complex<ld> Point;\n\n\nconst ld pi = acos(-1.0);\nconst ld dtop = pi / 180.;\nconst ld ptod = 1. / dtop;\n\nnamespace std {\n\tbool operator<(const Point &lhs, const Point &rhs) {\n\t\tif (lhs.real() < rhs.real() - eps) return true;\n\t\tif (lhs.real() > rhs.real() + eps) return false;\n\t\treturn lhs.imag() < rhs.imag();\n\t}\n}\n\n// 点の入力\nPoint input_Point() {\n\tld x, y;\n\tcin >> x >> y;\n\treturn Point(x, y);\n}\n\n// 誤差つき等号判定\nbool eq(const ld a, const ld b) {\n\treturn (abs(a - b) < eps);\n}\n\n// 内積\nld dot(const Point& a, const Point& b) {\n\treturn real(conj(a) * b);\n}\n\n// 外積\nld cross(const Point& a, const Point& b) {\n\treturn imag(conj(a) * b);\n}\n\n// 直線の定義\nclass Line {\npublic:\n\tPoint a, b;\n\tLine() : a(Point(0, 0)), b(Point(0, 0)) {}\n\tLine(Point a, Point b) : a(a), b(b) {}\n\tPoint operator[](const int _num)const {\n\t\tif (_num == 0)return a;\n\t\telse if (_num == 1)return b;\n\t\telse {\n\t\t\tassert(false);\n\t\t\treturn Point();\n\t\t}\n\t}\n};\n\n// 円の定義\nclass Circle {\npublic:\n\tPoint p;\n\tld r;\n\tCircle() : p(Point(0, 0)), r(0) {}\n\tCircle(Point p, ld r) : p(p), r(r) {}\n};\n\n// ccw\n// 1: a,b,cが反時計周りの順に並ぶ\n//-1: a,b,cが時計周りの順に並ぶ\n// 2: c,a,bの順に直線に並ぶ\n//-2: a,b,cの順に直線に並ぶ\n// 0: a,c,bの順に直線に並ぶ\nint ccw(const Point& a, const Point &b, const Point &c) {\n\tconst Point nb(b - a);\n\tconst Point nc(c - a);\n\tif (cross(nb, nc) > eps) return 1; // a,b,cが反時計周りの順に並ぶ\n\tif (cross(nb, nc) < -eps) return -1; // a,b,cが時計周りの順に並ぶ\n\tif (dot(nb, nc) < 0) return 2; // c,a,bの順に直線に並ぶ\n\tif (norm(nb) < norm(nc)) return -2; // a,b,cの順に直線に並ぶ\n\treturn 0; // a,c,bの順に直線に並ぶ\n}\n\n\n/* 交差判定 */\n\n// 直線と直線の交差判定\nbool isis_ll(const Line& l, const Line& m) {\n\treturn !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\n\n// 直線と線分の交差判定\nbool isis_ls(const Line& l, const Line& s) {\n\treturn isis_ll(l, s) &&\n\t\t(cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < eps);\n}\n\n// 線分と線分の交差判定\nbool isis_ss(const Line& s, const Line& t) {\n\treturn ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n\t\tccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\n// 点の直線上判定\nbool isis_lp(const Line& l, const Point& p) {\n\treturn (abs(cross(l.b - p, l.a - p)) < eps);\n}\n\n// 点の線分上判定\nbool isis_sp(const Line& s, const Point& p) {\n\treturn (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n\n// 垂線の足\nPoint proj(const Line &l, const Point& p) {\n\tld t = dot(p - l.a, l.b - l.a) / norm(l.a - l.b);\n\treturn l.a + t * (l.b - l.a);\n}\n\n//線対象の位置にある点\nPoint reflect(const Line &l, const Point &p) {\n\tPoint pr = proj(l, p);\n\treturn pr * 2.l - p;\n}\n\n// 直線と直線の交点\nPoint is_ll(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tassert(cross(sv, tv) != 0);\n\treturn s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n// 直線と直線の交点\nvector<Point> is_ll2(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tif (cross(sv, tv) != 0)return vector<Point>(1, is_ll(s, t));\n\telse {\n\t\tvector<Point>ans;\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tif (isis_sp(s, t[k]) && find(ans.begin(), ans.end(), t[k]) == ans.end())ans.push_back(t[k]);\n\t\t\tif (isis_sp(t, s[k]) && find(ans.begin(), ans.end(), s[k]) == ans.end())ans.push_back(s[k]);\n\t\t}\n\t\treturn ans;\n\t}\n}\n// 線分と線分の交点\n// 重なってる部分あるとassert(false)\nPoint is_ss(const Line &s, const Line& t) {\n\tif (isis_ss(s, t)) {\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tfor (int l = 0; l < 2; ++l) {\n\t\t\t\tif (s[k] == t[l])return s[k];\n\t\t\t}\n\t\t}\n\t\treturn is_ll(s, t);\n\t}\n\telse {\n\t\t//先にisis_ssしてね\n\t\tassert(false);\n\t\treturn Point(0, 0);\n\t}\n}\n// 線分と線分の交点\nvector<Point> is_ss2(const Line &s, const Line& t) {\n\tvector<Point> kouho(is_ll2(s, t));\n\tvector<Point>ans;\n\tfor (auto p : kouho) {\n\t\tif (isis_sp(s, p) && isis_sp(t, p))ans.emplace_back(p);\n\t}\n\treturn ans;\n}\n// 直線と点の距離\nld dist_lp(const Line& l, const Point& p) {\n\treturn abs(p - proj(l, p));\n}\n\n//直線と直線の距離\nld dist_ll(const Line& l, const Line& m) {\n\treturn isis_ll(l, m) ? 0 : dist_lp(l, m.a);\n}\n\n// 直線と線分の距離\nld dist_ls(const Line& l, const Line& s) {\n\treturn isis_ls(l, s) ? 0 : min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\n\n// 線分と点の距離\nld dist_sp(const Line& s, const Point& p) {\n\tPoint r = proj(s, p);\n\treturn isis_sp(s, r) ? abs(r - p) : min(abs(s.a - p), abs(s.b - p));\n}\n\n// 線分と線分の距離\nld dist_ss(const Line& s, const Line& t) {\n\tif (isis_ss(s, t)) return 0;\n\treturn min({ dist_sp(s, t.a), dist_sp(s, t.b), dist_sp(t, s.a), dist_sp(t, s.b) });\n}\n\n\n//直線と直線の二等分線のベクトル\nLine line_bisection(const Line &s, const Line &t) {\n\tconst Point laglanju(is_ll(s, t));\n\tconst Point avec = !(abs(laglanju - s[0])<eps) ? s[0] - laglanju : s[1] - laglanju;\n\tconst Point bvec = !(abs(laglanju - t[0])<eps) ? t[0] - laglanju : t[1] - laglanju;\n\n\treturn Line(laglanju, laglanju + (abs(bvec)*avec + abs(avec)*bvec) / (abs(avec) + abs(bvec)));\n}\n//点と点の垂直二等分線 aを左に見ながら\nLine point_bisection(const Point&a, const Point&b) {\n\tconst Point cen((a + b) / 2.l);\n\tconst Point vec = (b - a)*Point(0, 1);\n\treturn Line(cen, cen + vec);\n}\n\n//三つの点からなる外心\nPoint outer_center(const vector<Point>&ps) {\n\tassert(ps.size() == 3);\n\tLine l1 = point_bisection(ps[0], ps[1]);\n\tLine l2 = point_bisection(ps[1], ps[2]);\n\treturn is_ll(l1, l2);\n}\n\n\n//三つの直線からなる内心\n//三つの直線が並行でないことは確かめといてね\nPoint inner_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i <static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (vertics[0] == vertics[1] || vertics[1] == vertics[2] || vertics[2] == vertics[0])return vertics[0];\n\tLine bi1(line_bisection(Line(vertics[0], vertics[1]), Line(vertics[0], vertics[2])));\n\tLine bi2(line_bisection(Line(vertics[1], vertics[2]), Line(vertics[1], vertics[0])));\n\tif (bi1[0] == bi2[0])return bi1[0];\n\telse {\n\t\treturn is_ll(bi1, bi2);\n\t}\n}\n\n//三つの直線からなる傍心\n//三つの直線が並行でないことは確かめといてね\nvector<Point> ex_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i < static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (abs(vertics[0] - vertics[1])<eps || abs(vertics[1] - vertics[2])<eps || (abs(vertics[2] - vertics[0])<eps))return vector<Point>();\n\tvector<Point>ecs;\n\tfor (int i = 0; i < 3; ++i) {\n\t\tLine bi1(line_bisection(Line(vertics[i], vertics[i] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[i], vertics[(i + 1) % 3])));\n\t\tLine bi2(line_bisection(Line(vertics[(i + 1) % 3], vertics[(i + 1) % 3] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[(i + 1) % 3], vertics[i])));\n\t\tecs.push_back(is_ll(bi1, bi2));\n\t}\n\treturn ecs;\n}\n\n\n//a,b:並行\n//c:並行でない\n//三つの直線から同距離の位置を求める。\nvector<Point> same_dis(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tvertics.push_back(is_ll(ls[0], ls[2]));\n\tvertics.push_back(is_ll(ls[1], ls[2]));\n\n\tif (abs(vertics[0] - vertics[1]) < eps)return vector<Point>{vertics[0]};\n\tLine bis(line_bisection(ls[0], ls[1]));\n\tvector<Point>ecs;\n\n\tLine abi(line_bisection(Line(vertics[0], vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, abi));\n\n\n\tLine bbi(line_bisection(Line(vertics[0], 2.l*vertics[0] - vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, bbi));\n\n\treturn ecs;\n}\n/* 円 */\n\n// 円と円の交点\nvector<Point> is_cc(const Circle& c1, const Circle& c2) {\n\tvector<Point> res;\n\tld d = abs(c1.p - c2.p);\n\tld rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n\tld dfr = c1.r * c1.r - rc * rc;\n\tif (abs(dfr) < eps) dfr = 0.0;\n\telse if (dfr < 0.0) return res; // no intersection\n\tld rs = sqrt(dfr);\n\tPoint diff = (c2.p - c1.p) / d;\n\tres.push_back(c1.p + diff * Point(rc, rs));\n\tif (dfr != 0.0) res.push_back(c1.p + diff * Point(rc, -rs));\n\treturn res;\n}\n\n/*\n点が円の中にいるか\n0 => out\n1 => on\n2 => in*/\nint is_in_Circle(const Point& p, const Circle &cir) {\n\tld dis = abs(cir.p - p);\n\tif (dis > cir.r + eps)return 0;\n\telse if (dis < cir.r - eps)return 2;\n\telse return 1;\n}\nint is_in_Circle(const Circle &cir, const Point& p) {\n\tld dis = abs(cir.p - p);\n\tif (dis > cir.r + eps)return 0;\n\telse if (dis < cir.r - eps)return 2;\n\telse return 1;\n}\n/*\n円lcが円rcの中にいるか\n0 => out\n1 => on\n2 => in*/\nint Circle_in_Circle(const Circle &lc, const Circle&rc) {\n\tld dis = abs(lc.p - rc.p);\n\tif (dis < rc.r - lc.r - eps)return 2;\n\telse if (dis>rc.r - lc.r + eps)return 0;\n\telse return 1;\n}\n\n// 円と直線の交点\nvector<Point> is_lc(const Circle& c, const Line& l) {\n\tvector<Point> res;\n\tld d = dist_lp(l, c.p);\n\tif (d < c.r + eps) {\n\t\tld len = (d > c.r) ? 0.0 : sqrt(c.r * c.r - d * d); //safety;\n\t\tPoint nor = (l.a - l.b) / abs(l.a - l.b);\n\t\tres.push_back(proj(l, c.p) + len * nor);\n\t\tres.push_back(proj(l, c.p) - len * nor);\n\t}\n\treturn res;\n}\n\n// 円と線分の距離\nvector<Point> is_sc(const Circle& c, const Line& l) {\n\tvector<Point> v = is_lc(c, l), res;\n\tfor (Point p : v)\n\t\tif (isis_sp(l, p)) res.push_back(p);\n\treturn res;\n}\n\n// 円と点の接線\nvector<Line> tangent_cp(const Circle& c, const Point& p) {\n\tvector<Line> ret;\n\tPoint v = c.p - p;\n\tld d = abs(v);\n\tld l = sqrt(norm(v) - c.r * c.r);\n\tif (isnan(l)) { return ret; }\n\tPoint v1 = v * Point(l / d, c.r / d);\n\tPoint v2 = v * Point(l / d, -c.r / d);\n\tret.push_back(Line(p, p + v1));\n\tif (l < eps) return ret;\n\tret.push_back(Line(p, p + v2));\n\treturn ret;\n}\n\n// 円と円の接線\nvector<Line> tangent_cc(const Circle& c1, const Circle& c2) {\n\tvector<Line> ret;\n\tif (abs(c1.p - c2.p) - (c1.r + c2.r) > -eps) {\n\t\tPoint center = (c1.p * c2.r + c2.p * c1.r) / (c1.r + c2.r);\n\t\tret = tangent_cp(c1, center);\n\t}\n\tif (abs(c1.r - c2.r) > eps) {\n\t\tPoint out = (-c1.p * c2.r + c2.p * c1.r) / (c1.r - c2.r);\n\t\tvector<Line> nret = tangent_cp(c1, out);\n\t\tret.insert(ret.end(), nret.begin(), nret.end());\n\t}\n\telse {\n\t\tPoint v = c2.p - c1.p;\n\t\tv /= abs(v);\n\t\tPoint q1 = c1.p + v * Point(0, 1) * c1.r;\n\t\tPoint q2 = c1.p + v * Point(0, -1) * c1.r;\n\t\tret.push_back(Line(q1, q1 + v));\n\t\tret.push_back(Line(q2, q2 + v));\n\t}\n\treturn ret;\n}\n//二つの円の重なり面積\nld two_Circle_area(const Circle&l, const Circle&r) {\n\tld dis = abs(l.p - r.p);\n\tif (dis > l.r + r.r)return 0;\n\telse if (dis + r.r < l.r) {\n\t\treturn r.r*r.r*pi;\n\t}\n\telse if (dis + l.r < r.r) {\n\t\treturn l.r*l.r*pi;\n\t}\n\telse {\n\t\tld ans = (l.r)*(l.r)*acos((dis*dis + l.r*l.r - r.r*r.r) / (2 * dis*l.r)) +\n\t\t\t(r.r)*(r.r)*acos((dis*dis + r.r*r.r - l.r*l.r) / (2 * dis*r.r)) -\n\t\t\tsqrt(4 * dis*dis*l.r*l.r - (dis*dis + l.r*l.r - r.r*r.r)*(dis*dis + l.r*l.r - r.r*r.r)) / 2;\n\t\treturn ans;\n\t}\n\n}\n\n/* 多角形 */\n\ntypedef vector<Point> Polygon;\n\n\n// 面積\nld get_area(const Polygon &p) {\n\tld res = 0;\n\tint n = p.size();\n\tfor (int j = 0; j<n; ++j) res += cross(p[j], p[(j + 1) % n]);\n\treturn res / 2;\n}\n\n// 円の内外判定\n/*0 => out\n1 => on\n2 => in*/\nint convex_contains(const Polygon &poly, const Point& p) {\n\tld angle = 0;\n\tint n = poly.size();\n\tfor(int i=0;i<n;++i) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n];\n\t\tif (isis_sp(Line(a, b), p)) return 1;\n\t\tangle += arg((b - p) / (a - p));\n\t}\n\treturn eq(angle, 0) ? 0 : 2;\n}\n\n\nstruct Edge {\n\tint src;\n\tint dest;\n};\nusing Graph=vector<vector<Edge>>;\n\n//線分アレンジメント後に、\n//閉路の面積の和を求める。\nvoid dfs(set<pair<int ,int>>&aset,const int now, const int from, vector<int>&prevs, vector<Polygon>&ans_polys, const vector<Point>&ps, const Graph&g) {\n\tvector<pair<ld, int>>next_points;\n\n\tPoint from_p = from == -1 ? ps[now] + Point(-3e6, 0) : ps[from];\n\tPoint now_p = ps[now];\n\tfor (auto e : g[now]) {\n\t\tif (e.dest == from)continue;\n\t\tPoint next_p = ps[e.dest];\n\n\t\tld costheta = dot(from_p - now_p, next_p - now_p) / (abs(from_p - now_p)*abs(next_p - now_p));\n\t\tcostheta *= 0.3;\n\t\tld d = acos(costheta);\n\t\tif (ccw(from_p, now_p, next_p) != 1) {\n\t\t\td = 2 * pi - d;\n\t\t}\n\t\tnext_points.push_back(make_pair(d, e.dest));\n\t}\n\tsort(next_points.begin(), next_points.end());\n\n\tfor (auto n_p : next_points) {\n\t\tif (aset.find(make_pair(now, n_p.second))!=aset.end()) {\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\taset.emplace(now,n_p.second);\n\t\t}\n\n\t\tif (prevs[n_p.second] != -1) {\n\t\t\tint k=now;\n\t\t\tPolygon poly(1,ps[k]);\n\t\t\twhile (k != n_p.second) {\n\t\t\t\tk=prevs[k];\n\t\t\t\tpoly.push_back(ps[k]);\n\t\t\t}\n\t\t\t\n\t\t\tld plus = get_area(poly);\n\t\t\tif (plus<eps) {\n\t\t\t\treverse(poly.begin(),poly.end());\n\t\t\t\tans_polys.push_back(poly);\n\t\t\t}\n\t\t\tthrow(false);\n\t\t}\n\t\telse {\n\n\t\t\tprevs[n_p.second] = now;\n\t\t\tdfs(aset, n_p.second, now, prevs, ans_polys, ps, g);\n\t\t\tprevs[n_p.second] = -1;\n\t\t}\n\n\t}\n\treturn ;\n}\n\nint main() {\n\twhile (true) {\n\t\tint N,M;cin>>N>>M;\n\t\tif(!N)break;\n\t\tvector<Circle>cs;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tint x,y,r;cin>>x>>y>>r;\n\t\t\tcs.push_back(Circle(Point(x,y),r));\n\t\t}\n\t\tvector<vector<Edge>>edges(N);\n\t\tGraph g(N);\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tfor (int j = i + 1; j < N; ++j) {\n\t\t\t\t\n\t\t\t\tld dis=abs(cs[i].p-cs[j].p);\n\t\t\t\tif (Circle_in_Circle(cs[i], cs[j])==0&&Circle_in_Circle(cs[j],cs[i])==0&&dis<cs[i].r+cs[j].r) {\n\t\t\t\t\tedges[i].push_back(Edge{ i,j });\n\t\t\t\t\tedges[j].push_back(Edge{ j,i });\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<Point>ps(N);\n\t\tfor(int i=0;i<N;++i)ps[i]=cs[i].p;\n\n\t\tvector<Polygon>polys;\n\t\tset<pair<int,int>>aset;\n\n\t\tfor(int i=0;i<N;++i) {\n\t\t\tfor (int j = 0; j < edges[i].size();++j) {\n\t\t\t\tif (aset.find(make_pair(i, j)) == aset.end()) {\n\t\t\t\t\ttry {\n\t\t\t\t\t\tvector<int>prevs(N, -1);\n\t\t\t\t\t\tprevs[i] = -2;\n\t\t\t\t\t\tdfs(aset, i, -1, prevs, polys, ps, edges);\n\t\t\t\t\t}\n\t\t\t\t\tcatch (...) {\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tfor (int i = 0; i < M; ++i) {\n\t\t\tvector<Point>query_points;\n\t\t\t{\n\t\t\t\tint a,b,c,d;cin>>a>>b>>c>>d;\n\t\t\t\tPoint p,q;\n\t\t\t\tp=Point(a,b);\n\t\t\t\tq=Point(c,d);\n\t\t\t\tquery_points = vector<Point>{ p,q };\n\t\t\t}\n\t\t\tvector<vector<int>>in_circles(2);\n\t\t\tfor (int j = 0; j < 2; ++j) {\n\t\t\t\tfor (int k = 0; k < N; ++k) {\n\t\t\t\t\tif (is_in_Circle(cs[k], query_points[j])) {\n\t\t\t\t\t\tin_circles[j].push_back(true);\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\tin_circles[j].push_back(false);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tbool ok;\n\t\t\tif (in_circles[0] != in_circles[1]) {\n\t\t\t\tok=false;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (all_of(in_circles[0].begin(), in_circles[0].end(), [](const int a) {return a == 0; })) {\n\t\t\t\t\tvector<vector<int>>in_polygons(2,vector<int>(polys.size()));\n\t\t\t\t\tfor (int j = 0; j < 2; ++j) {\n\t\t\t\t\t\tfor (int k = 0; k < polys.size(); ++k) {\n\t\t\t\t\t\t\tif (convex_contains(polys[k], query_points[j])) {\n\t\t\t\t\t\t\t\tin_polygons[j][k] = true;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (in_polygons[0] == in_polygons[1]) {\n\t\t\t\t\t\tok=true;\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\tok=false;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tok=true;\n\t\t\t\t}\n\n\t\t\t}\n\t\t\tif(ok)cout<<\"YES\";\n\t\t\telse cout<<\"NO\";\n\t\t\tif(i==M-1)cout<<endl;\n\t\t\telse cout<<\" \";\n\t\t\t\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 0.5, "time_ms": 70, "memory_kb": 3360, "score_of_the_acc": -0.0563, "final_rank": 20 }, { "submission_id": "aoj_1198_2999426", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <iostream>\n#include <string>\n#include <cmath>\n#include <bitset>\n#include <vector>\n#include <map>\n#include <set>\n#include <queue>\n#include <deque>\n#include <algorithm>\n#include <fstream>\n#define EPS 1e-10\n \nusing namespace std;\ntypedef long long int ll;\n \nconst double PI=acos(-1.0);\n \ndouble add(double a, double b){\n if(abs(a+b)<EPS*(abs(a)+abs(b))) return 0;\n return a+b;\n}\n \nstruct P{\n double x, y;\n P() {}\n P(double x, double y): x(x), y(y){\n }\n P operator+ (P p){\n return P(add(x, p.x), add(y, p.y));\n }\n P operator- (P p){\n return P(add(x, -p.x), add(y, -p.y));\n }\n P operator* (double d){\n return P(x*d, y*d);\n }\n double dot(P p){\n return add(x*p.x, y*p.y);\n }\n double det(P p){\n return add(x*p.y, -y*p.x);\n }\n bool operator< (const P& p) const{\n if(abs(x-p.x)>EPS){\n return x<p.x;\n }else{\n return y<p.y-EPS;\n }\n }\n};\n \nbool on_seg(P p1, P p2, P q){\n return (p1-q).det(p2-q)==0 && (p1-q).dot(p2-q)<=0;\n}\n \nP intersection(P p1, P p2, P q1, P q2){\n return p1+(p2-p1)*((q2-q1).det(q1-p1) / (q2-q1).det(p2-p1));\n}\n \ndouble dist(P p1, P p2){\n return sqrt((p1-p2).dot(p1-p2));\n}\n \nbool in_polygon(vector<P> poly, P p){ //内ならtrue、多角形は反時計回り\n int ct=0;\n P inf=P(cos(1.0)*20000.0, sin(1.0)*20000.0);\n int N=poly.size();\n for(int i=0; i<N-1; i++){\n P q=intersection(poly[i], poly[i+1], p, inf);\n if(on_seg(poly[i], poly[i+1], q) && on_seg(p, inf, q)) ct++;\n }\n P q=intersection(poly[N-1], poly[0], p, inf);\n if(on_seg(poly[N-1], poly[0], q) && on_seg(p, inf, q)) ct++;\n if(ct%2==0){\n return false;\n }else{\n return true;\n }\n}\n \nint n;\nP c[102];\nbool nn[102][102];\nvector<int> v[102];\n \nvector<int> min_polygon0(P p, int j, int i){\n bool vec=0;\n if((c[i]-c[j]).det(p-c[j])>0) vec=1;\n vector<int> ppoly;\n ppoly.push_back(i);\n int i1=i, j1=j;\n int ct=1;\n while(ct<=n+3){\n int i2;\n double ang0;\n ang0=3.0*PI;\n for(int l=0; l<v[i1].size(); l++){\n int x=v[i1][l];\n if(x==j1) continue;\n if(nn[i1][x]==1) continue;\n double cs=((c[j1]-c[i1]).dot(c[x]-c[i1]))/(dist(c[j1], c[i1])*dist(c[x], c[i1]));\n double ang;\n if(abs(cs+1.0)<EPS){\n ang=PI;\n }else if(abs(cs-1.0)<EPS){\n ang=0;\n }else{\n ang=acos(cs);\n\t }\n if((c[j1]-c[i1]).det(c[x]-c[i1])<0){\n ang=2.0*PI-ang;\n }\n\t if(vec==1){\n\t\t ang=2.0*PI-ang;\n\t }\n if(ang0>ang){\n ang0=ang;\n i2=x;\n }\n }\n j1=i1;\n i1=i2;\n ppoly.push_back(i2);\n ct++;\n if(i1==j){\n break;\n }\n }\n vector<P> ppoly1;\n for(int i=0; i<ppoly.size(); i++){\n ppoly1.push_back(c[ppoly[i]]);\n }\n if(ct>=n+3 || in_polygon(ppoly1, p)==false){\n vector<int> emp;\n return emp;\n }else{\n return ppoly;\n }\n}\n \nvector<int> min_polygon(P p){\n for(int i=0; i<n; i++){\n for(int j=0; j<v[i].size(); j++){\n int x=v[i][j];\n if(nn[i][x]==1) continue;\n P mid=(c[i]+c[x])*0.5;\n bool e0=0;\n for(int k=0; k<n; k++){\n for(int l=0; l<v[k].size(); l++){\n int y=v[k][l];\n if(nn[k][y]==1) continue;\n if((k==i && y==x) || (k==x && y==i)) continue;\n if((mid-p).det(c[k]-c[y])==0){\n if(on_seg(mid, p, c[k]) || on_seg(mid, p, c[y]) || on_seg(c[k], c[y], mid) || on_seg(c[k], c[y], p)){\n e0=1;\n break;\n }\n }else{\n P r=intersection(mid, p, c[k], c[y]);\n if(on_seg(mid, p, r) && on_seg(c[k], c[y], r)){\n e0=1;\n break;\n }\n }\n }\n if(e0==1) break;\n }\n if(e0==0){\n vector<int> ppoly=min_polygon0(p, i, x);\n if(!ppoly.empty()){\n return ppoly;\n }\n }\n }\n }\n vector<int> emp;\n return emp;\n}\n \nint main()\n{\n while(1){\n int m;\n cin>>n>>m;\n if(n==0 && m==0) return 0;\n double r[100];\n for(int i=0; i<n; i++){\n double cx, cy;\n cin>>cx>>cy>>r[i];\n c[i]=P(cx, cy);\n }\n for(int i=0; i<100; i++){\n v[i].clear();\n }\n for(int i=0; i<n; i++){\n for(int j=i+1; j<n; j++){\n double d=dist(c[i], c[j]);\n if(abs(r[i]-r[j])<d && d<(r[i]+r[j])){\n v[i].push_back(j);\n v[j].push_back(i);\n }\n }\n }\n\n\t for(int i=0; i<n; i++){\n for(int j=0; j<n; j++){\n nn[i][j]=0;\n\t\t }\n }\n\t for(int t=0; t<3*n; t++){\n for(int i=0; i<n; i++){\n\t\t\tint ct=0;\n\t\t\t for(int j=0; j<v[i].size(); j++){\n\t\t\t\tif(nn[i][v[i][j]]==1) continue;\n\t\t\t\tct++;\n\t\t\t }\n if(ct==1){\n int j2;\n for(int j=0; j<v[i].size(); j++){\n\t\t\t\tif(nn[i][v[i][j]]==1) continue;\n\t\t\t\tj2=v[i][j];\n\t\t\t}\n nn[i][j2]=1;\n nn[j2][i]=1;\n \n }\n }\n\t }\n for(int k=0; k<m; k++){\n P p, q;\n double px, py, qx, qy;\n cin>>px>>py>>qx>>qy;\n p=P(px, py), q=P(qx, qy);\n bool ep[100], eq[100];\n bool e=0, e0=0;\n for(int i=0; i<n; i++){\n if(dist(p, c[i])<r[i]){\n ep[i]=1;\n e0=1;\n }else{\n ep[i]=0;\n }\n if(dist(q, c[i])<r[i]){\n eq[i]=1;\n e0=1;\n }else{\n eq[i]=0;\n }\n if(ep[i]!=eq[i]){\n if(k==m-1){\n cout<<\"NO\";\n }else{\n cout<<\"NO \";\n }\n e=1;\n break;\n }\n }\n if(e==1) continue;\n if(e0==1){\n if(k==m-1){\n cout<<\"YES\";\n }else{\n cout<<\"YES \";\n }\n continue;\n }\n \n vector<int> ppoly, qpoly;\n ppoly=min_polygon(p);\n qpoly=min_polygon(q);\n if(ppoly.empty() && qpoly.empty()){\n if(k==m-1){\n cout<<\"YES\";\n }else{\n cout<<\"YES \";\n }\n continue;\n }\n if(ppoly.empty() || qpoly.empty()){\n if(k==m-1){\n cout<<\"NO\";\n }else{\n cout<<\"NO \";\n }\n continue;\n }\n if(ppoly.size()!=qpoly.size()){\n if(k==m-1){\n cout<<\"NO\";\n }else{\n cout<<\"NO \";\n }\n continue;\n }\n sort(ppoly.begin(), ppoly.end());\n sort(qpoly.begin(), qpoly.end());\n bool ok=0;\n for(int i=0; i<ppoly.size(); i++){\n if(ppoly[i]!=qpoly[i]){\n ok=1;\n break;\n }\n }\n if(ok==0){\n if(k==m-1){\n cout<<\"YES\";\n }else{\n cout<<\"YES \";\n }\n }else{\n if(k==m-1){\n cout<<\"NO\";\n }else{\n cout<<\"NO \";\n }\n }\n }\n cout<<\"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3372, "score_of_the_acc": -0.0378, "final_rank": 3 } ]
aoj_1200_cpp
Problem A: Goldbach's Conjecture Goldbach's Conjecture: For any even number n greater than or equal to 4, there exists at least one pair of prime numbers p 1 and p 2 such that n = p 1 + p 2 . This conjecture has not been proved nor refused yet. No one is sure whether this conjecture actually holds. However, one can find such a pair of prime numbers, if any, for a given even number. The problem here is to write a program that reports the number of all the pairs of prime numbers satisfying the condition in the conjecture for a given even number. A sequence of even numbers is given as input. Corresponding to each number, the program should output the number of pairs mentioned above. Notice that we are intereseted in the number of essentially different pairs and therefore you should not count ( p 1 , p 2 ) and ( p 2 , p 1 ) separately as two different pairs. Input An integer is given in each input line. You may assume that each integer is even, and is greater than or equal to 4 and less than 2 15 . The end of the input is indicated by a number 0. Output Each output line should contain an integer number. No other characters should appear in the output. Sample Input 6 10 12 0 Output for the Sample Input 1 2 1
[ { "submission_id": "aoj_1200_11059833", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i,a,b) for(int i=(a);i<(b);i++)\n\nvector<int> ans_table(const int LIM=(1<<16)){\n vector<int>res(LIM);\n vector<int> isP(LIM,1);\n vector<int>primes;\n isP[0]=isP[1]=0;\n rep(i,2,LIM){\n if(!isP[i])continue;\n for(int j=2*i;j<LIM;j+=i)isP[j]=0;\n primes.push_back(i);\n }\n for(int p:primes)for(int q:primes)if(p<=q&&p+q<LIM)res[p+q]++;\n return res;\n}\n\nint main(){\n auto ans = ans_table();\n int N;\n while(cin>>N,N){\n cout<<ans[N]<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3840, "score_of_the_acc": -0.1389, "final_rank": 12 }, { "submission_id": "aoj_1200_10849396", "code_snippet": "#include <iostream>\n#include <vector>\n\nusing namespace std;\n\nbool isPrime(int n)\n{\n\tfor(int i = 2; i < n; i++)\n\t\tif((n%i)==0)\n\t\t\treturn false;\n\treturn true;\t\n}\n\nint main()\n{\n\tint n = 0;\n\t\n\t\n\twhile(true)\n\t{\n\t\tcin>>n;\n\n\t\tif(n == 0)\n\t\t\tbreak;\n\n\t\tvector <int> myArray;\n\t\tint c = 0;\n\n\t\tfor (int i = 2; i < n; i++)\n\t\t\tif(isPrime(i) == true)\n\t\t\t\tmyArray.push_back(i);\n\n\t\tfor(int j = 0; j < myArray.size(); j++)\n\t\t\tfor(int k = j; k < myArray.size(); k++)\n\t\t\t\tif((myArray[j] + myArray[k]) == n)\n\t\t\t\t\tc++;\n\n\t\tcout<<c<<endl;\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1020, "memory_kb": 3160, "score_of_the_acc": -0.258, "final_rank": 16 }, { "submission_id": "aoj_1200_5004710", "code_snippet": "#include <iostream>\n#include <vector>\n\nstd::vector<int> prime_list;\n\nbool prime(int n){\n for(int i=0;i<prime_list.size();i++){\n int p = prime_list[i];\n if(p == n){\n return true;\n }else if(n%p == 0){\n return false;\n }\n }\n int lastp = prime_list[prime_list.size()-1];\n for(int p=lastp;p<n;p+=2){\n if(prime(p) && (n%p==0)){\n return false;\n }\n }\n prime_list.push_back(n);\n return true;\n}\n\nint main(int argc, char**argv){\n int n;\n prime_list.push_back(3);\n while(true){\n std::cin >> n;\n if(n==0){\n break;\n }else if(n == 4){\n std::cout << 1 << std::endl;\n continue;\n }\n int c=0;\n for(int i=3;i<=(n/2);i+=2){\n if(prime(i) && prime(n-i)){\n c++;\n }\n }\n std::cout << c << std::endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3044, "score_of_the_acc": -0.1124, "final_rank": 8 }, { "submission_id": "aoj_1200_3901420", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define P pair<int,int>\n#define FOR(I,A,B) for(ll I = ll(A); I < ll(B); ++I)\n#define FORR(I,A,B) for(ll I = ll((B)-1); I >= ll(A); --I)\n#define TO(x,t,f) ((x)?(t):(f))\n#define SORT(x) (sort(x.begin(),x.end())) // 0 2 2 3 4 5 8 9\n#define POSL(x,v) (lower_bound(x.begin(),x.end(),v)-x.begin()) //xi>=v x is sorted\n#define POSU(x,v) (upper_bound(x.begin(),x.end(),v)-x.begin()) //xi>v x is sorted\n#define NUM(x,v) (POSU(x,v)-POSL(x,v)) //x is sorted\n#define REV(x) (reverse(x.begin(),x.end())) //reverse\nll gcd(ll a,ll b){if(a%b==0)return b;return gcd(b,a%b);}\nll lcm(ll a,ll b){ll c=gcd(a,b);return ((a/c)*(b/c)*c);}\n#define NEXTP(x) next_permutation(x.begin(),x.end())\nconst ll INF=ll(1e18)+ll(7);\nconst ll MOD=1000000007LL;\n#define out(a) cout<<fixed<<setprecision((a))\n#define YesNo(a) cout<<((a)?\"Yes\":\"No\")<<endl;\n#define YESNO(a) cout<<((a)?\"YES\":\"NO\")<<endl;\n\nnamespace FastFourierTransform {\n\tusing real=double;\n \n\tstruct C {\n\treal x, y;\n \n\tC() : x(0), y(0) {}\n \n\tC(real x, real y) : x(x), y(y) {}\n \n\tinline C operator+(const C &c) const { return C(x + c.x, y + c.y); }\n \n\tinline C operator-(const C &c) const { return C(x - c.x, y - c.y); }\n \n\tinline C operator*(const C &c) const { return C(x * c.x - y * c.y, x * c.y + y * c.x); }\n \n\tinline C conj() const { return C(x, -y); }\n\t};\n \n\tconst real PI = acosl(-1);\n\tint base = 1;\n\tvector< C > rts = {{0, 0},\n\t\t\t\t\t {1, 0}};\n\tvector< int > rev = {0, 1};\n \n \n\tvoid ensure_base(int nbase) {\n\tif(nbase <= base) return;\n\trev.resize(1 << nbase);\n\trts.resize(1 << nbase);\n\tfor(int i = 0; i < (1 << nbase); i++) {\n\t\trev[i] = (rev[i >> 1] >> 1) + ((i & 1) << (nbase - 1));\n\t}\n\twhile(base < nbase) {\n\t\treal angle = PI * 2.0 / (1 << (base + 1));\n\t\tfor(int i = 1 << (base - 1); i < (1 << base); i++) {\n\t\trts[i << 1] = rts[i];\n\t\treal angle_i = angle * (2 * i + 1 - (1 << base));\n\t\trts[(i << 1) + 1] = C(cos(angle_i), sin(angle_i));\n\t\t}\n\t\t++base;\n\t}\n\t}\n \n\tvoid fft(vector< C > &a, int n) {\n\tassert((n & (n - 1)) == 0);\n\tint zeros = __builtin_ctz(n);\n\tensure_base(zeros);\n\tint shift = base - zeros;\n\tfor(int i = 0; i < n; i++) {\n\t\tif(i < (rev[i] >> shift)) {\n\t\tswap(a[i], a[rev[i] >> shift]);\n\t\t}\n\t}\n\tfor(int k = 1; k < n; k <<= 1) {\n\t\tfor(int i = 0; i < n; i += 2 * k) {\n\t\tfor(int j = 0; j < k; j++) {\n\t\t\tC z = a[i + j + k] * rts[j + k];\n\t\t\ta[i + j + k] = a[i + j] - z;\n\t\t\ta[i + j] = a[i + j] + z;\n\t\t}\n\t\t}\n\t}\n\t}\n \n\tvector< int64_t > multiply(const vector< int > &a, const vector< int > &b) {\n\tint need = (int) a.size() + (int) b.size() - 1;\n\tint nbase = 1;\n\twhile((1 << nbase) < need) nbase++;\n\tensure_base(nbase);\n\tint sz = 1 << nbase;\n\tvector< C > fa(sz);\n\tfor(int i = 0; i < sz; i++) {\n\t\tint x = (i < (int) a.size() ? a[i] : 0);\n\t\tint y = (i < (int) b.size() ? b[i] : 0);\n\t\tfa[i] = C(x, y);\n\t}\n\tfft(fa, sz);\n\tC r(0, -0.25 / (sz >> 1)), s(0, 1), t(0.5, 0);\n\tfor(int i = 0; i <= (sz >> 1); i++) {\n\t\tint j = (sz - i) & (sz - 1);\n\t\tC z = (fa[j] * fa[j] - (fa[i] * fa[i]).conj()) * r;\n\t\tfa[j] = (fa[i] * fa[i] - (fa[j] * fa[j]).conj()) * r;\n\t\tfa[i] = z;\n\t}\n\tfor(int i = 0; i < (sz >> 1); i++) {\n\t\tC A0 = (fa[i] + fa[i + (sz >> 1)]) * t;\n\t\tC A1 = (fa[i] - fa[i + (sz >> 1)]) * t * rts[(sz >> 1) + i];\n\t\tfa[i] = A0 + A1 * s;\n\t}\n\tfft(fa, sz >> 1);\n\tvector< int64_t > ret(need);\n\tfor(int i = 0; i < need; i++) {\n\t\tret[i] = llround(i & 1 ? fa[i >> 1].y : fa[i >> 1].x);\n\t}\n\treturn ret;\n\t}\n};\n\n\nint main(){\n\tvector<int> isp((1<<15)+1,1);\n\tisp[0]=isp[1]=0;\n\tFOR(i,2,(1<<15)+1){\n\t\tif(isp[i]){\n\t\t\tfor(int j=i*2;j<((1<<15)+1);j+=i){\n\t\t\t\tisp[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\tauto s = FastFourierTransform::multiply(isp, isp);\n\tint n;\n\twhile(cin>>n,n){\n\t\tint x=0;\n\t\tif((n/2)*2==n)x=n/2;\n\t\tcout << int(s[n]+isp[x])/2 << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 8216, "score_of_the_acc": -0.3692, "final_rank": 18 }, { "submission_id": "aoj_1200_3337344", "code_snippet": "#include<iostream>\n#include<cmath>\nusing namespace std;\n\nbool judgePrimeNumber( int a )\n{\n for( int i = 2; i <= sqrt(a); i++ )\n if( a % i == 0 )\n return false;\n return true;\n}\n\nint main()\n{\n int n;\n\n while( cin >> n )\n {\n if( n == 0 )\n break;\n\n int cnt = 0;\n for( int i = 2; i <= n / 2; i++ )\n if( judgePrimeNumber(i) && judgePrimeNumber(n-i) )\n cnt++;\n cout << cnt << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3084, "score_of_the_acc": -0.0991, "final_rank": 5 }, { "submission_id": "aoj_1200_2827435", "code_snippet": "#include <iostream>\n using namespace std;\nbool primes[1000000];\n\nvoid Sieve(){\n for(int i= 2; i < 1000000; i++){\n primes[i] = true;\n } \n primes[1] = false;\n \n for(int i = 2; i <= 1000; i++){\n if(primes[i] == true)\n for(int j=i; j*i <= 1000000;j++){\n primes[j*i] = false;\n }\n }\n}\n\nbool IsPrime(int x){\n return primes[x];\n}\n\nint main(void){\n int k;\nfor(k = 1; k > 0; k++){\n Sieve();\n int n, c = 0;\n cin >> n;\n if(n == 0) break;\n else{\n for(int i = 0; i <= n/2; i++){\n if(IsPrime(i)==true){\n if(IsPrime(n - i)==true) c++;\n }\n }\n cout << c << endl;\n }\n}\n \n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4072, "score_of_the_acc": -0.1603, "final_rank": 14 }, { "submission_id": "aoj_1200_2733896", "code_snippet": "#include <iostream>\n#include <map>\n\nusing namespace std;\n\nmap<int, int> memo;\n\nbool is_prim(int n) {\n if (n == 1) return false;\n if (n == 2) return true;\n if ((n % 2) == 0) return false;\n\n // NOTE: Return cached result\n if (memo.find(n) != memo.end()) {\n return memo[n];\n }\n\n bool isPrime = true;\n\n for (int i = 3; i * i <= n; ++i) {\n // Check dividability\n if ((n % i) == 0) {\n isPrime = false;\n break;\n }\n }\n\n // NOTE: Cache result\n memo[n] = isPrime;\n\n return isPrime;\n}\n\nint count_prim(int n) {\n map<int, int> p;\n int r = 0;\n\n for(int i = 2; i <= n / 2; ++i) {\n // NOTE: only for debug\n // cout << i << \": \" << is_prim(i) << endl;\n // cout << n - i << \": \" << is_prim(n - i) << endl;\n if (is_prim(i) && is_prim(n - i)) {\n ++r;\n }\n }\n\n return r;\n}\n\nint main(int argc, char** argv) {\n int n;\n // NOTE: only for debug\n // cout << \"is_prim(1): \" << is_prim(1) << endl;\n // cout << \"is_prim(2): \" << is_prim(2) << endl;\n // cout << \"is_prim(3): \" << is_prim(3) << endl;\n // cout << \"is_prim(4): \" << is_prim(4) << endl;\n // cout << \"is_prim(5): \" << is_prim(5) << endl;\n // cout << \"is_prim(6): \" << is_prim(6) << endl;\n // cout << \"is_prim(7): \" << is_prim(7) << endl;\n // cout << \"is_prim(8): \" << is_prim(8) << endl;\n // cout << \"is_prim(9): \" << is_prim(9) << endl;\n // cout << \"is_prim(10): \" << is_prim(10) << endl;\n // cout << \"is_prim(11): \" << is_prim(11) << endl;\n // cout << \"is_prim(12): \" << is_prim(12) << endl;\n // cout << \"is_prim(13): \" << is_prim(13) << endl;\n // cout << \"is_prim(14): \" << is_prim(14) << endl;\n // cout << \"is_prim(15): \" << is_prim(15) << endl;\n // cout << \"is_prim(16): \" << is_prim(16) << endl;\n // cout << \"is_prim(17): \" << is_prim(17) << endl;\n // cout << \"is_prim(18): \" << is_prim(18) << endl;\n // cout << \"is_prim(19): \" << is_prim(19) << endl;\n // cout << \"is_prim(20): \" << is_prim(20) << endl;\n cin >> n;\n while (n != 0) {\n // Do here\n // cout << n << endl;\n int r = count_prim(n);\n cout << r << endl;\n\n cin >> n;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3720, "score_of_the_acc": -0.1326, "final_rank": 11 }, { "submission_id": "aoj_1200_2300213", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing db = double;\nusing ll = long long;\nusing vi = vector <int>;\nusing vl = vector <ll>;\n//#define op operator\n#define pb push_back\n\nconst int N = 1e5L + 11;\nint p[N];\n\nusing comp = complex<db>; //??????comp????????¶??´: d /= 1.5, ld /= 3\nusing vc = vector<comp>; const db PI = atan(1.0L) * 4;\nvoid dft(vc &a, int op = 1) {\n\tint n = a.size();\n\tfor (int i = 1, j = 0; i < n - 1; ++i) {\n\t\tfor (int s = n; j ^= s >>= 1, ~j & s;) {}\n\t\tif (i < j) swap(a[i], a[j]);\n\t}\n\tfor (int i = 1; i < n; i *= 2) {\n\t\tcomp u = {cos(PI / i), op * sin(PI / i)};\n\t\tfor (int j = 0; j < n; j += i * 2) {\n\t\t\tcomp w = 1;\n\t\t\tfor (int k = 0; k < i; ++k, w = w * u) {\n\t\t\t\tcomp x = a[j + k], y = w * a[j + k + i];\n\t\t\t\ta[j + k] = x + y, a[j + k + i] = x - y;\n\t}}}\n\tif (op == -1) for (int i = 0; i < n; ++i) a[i] /= n;\n}\nvl multi(vl a, vl b) { // ????????????: d <= 1e12, ld <= 1e14\n\tint n = 1; while (n < a.size() + b.size() - 1) n *= 2;\n\tvc fa(n), fb(n), fc(n);\n\tcopy(a.begin(), a.end(), fa.begin()); dft(fa);\n\tcopy(b.begin(), b.end(), fb.begin()); dft(fb);\n\tfor (int i = 0; i < n; ++i) fc[i] = fa[i] * fb[i];\n\tdft(fc, -1); vl c(n);\n\tfor (int i = 0; i < n; ++i) c[i] = round(fc[i].real());\n\treturn c;\n}\n\nint main() {\n\tfor(int i = 2; i < N; i ++) if(!p[i])\n\t\tfor(int j = i; j < N; j += i) if(!p[j]) p[j] = i;\n\n\tcout << fixed << setprecision(9);\n\tios :: sync_with_stdio(0);\n\n\tvector <ll> v(N, 0);\n\tfor(int i = 2; i < N; i ++)\n\t\tv[i] = p[i] == i;\n\tv = multi(v, v);\n\n\tfor(int n; cin >> n && n; ) {\n\t\tcout << v[n] / 2 + (p[n / 2] == n / 2) << '\\n';\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 20204, "score_of_the_acc": -1.0077, "final_rank": 20 }, { "submission_id": "aoj_1200_2277789", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<cstdio>\n#include<cmath>\n#include<math.h>\n#include<string>\n#include<string.h>\n#include<stack>\n#include<queue>\n#include<vector>\n#include<utility>\n#include<set>\n#include<map>\n#include<stdlib.h>\n#include<iomanip>\n\nusing namespace std;\n\n#define ll long long\n#define ld long double\n#define EPS 0.0000000001\n#define INF 1e9\n#define MOD 1000000007\n#define rep(i,n) for(i=0;i<n;i++)\n#define loop(i,a,n) for(i=a;i<n;i++)\n#define all(in) in.begin(),in.end()\n#define shosu(x) fixed<<setprecision(x)\n\ntypedef vector<int> vi;\ntypedef pair<int,int> pii;\n\nint main(void) {\n int i,j;\n int n;\n vector<bool> prime(40000,true);\n\n for(i=2;i<40000;i++)\n if(prime[i])\n for(j=2;i*j<40000;j++)\n prime[i*j]=false;\n\n vi ans(40000,0);\n\n for(i=2;i<40000;i++)\n if(prime[i])\n for(j=i;j<40000;j++)\n if(prime[j] && i+j<40000)\n ans[i+j]++;\n\n while(1){\n cin>>n;\n if(n==0)break;\n cout<<ans[n]<<endl;\n }\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 2988, "score_of_the_acc": -0.1156, "final_rank": 9 }, { "submission_id": "aoj_1200_2246713", "code_snippet": "#include <vector>\n#include <iostream>\n#include <utility>\n#include <algorithm>\n#include <string>\n#include <deque>\n#include <queue>\n#include <tuple>\n#include <queue>\n#include <functional>\n#include <cmath>\n#include <iomanip>\n#include <map>\n#include <set>\n#include <numeric>\n#include <unordered_map>\n#include <unordered_set>\n#include <complex>\n#include <iterator>\n#include <array>\n#include <memory>\n#include <stack>\n#define vi vector<int>\n#define vvi vector<vector<int> >\n#define ll long long int\n#define vl vector<ll>\n#define vvl vector<vector<ll>>\n#define vb vector<bool>\n#define vc vector<char>\n#define vs vector<string>\n#define ld long double\n#define INF 1e9\n#define EPS 0.0000000001\n#define rep(i,n) for(int i=0;i<n;i++)\n#define loop(i,s,n) for(int i=s;i<n;i++)\n#define all(in) in.begin(), in.end()\ntemplate<class T, class S> void cmin(T &a, const S &b) { if (a > b)a = b; }\ntemplate<class T, class S> void cmax(T &a, const S &b) { if (a < b)a = b; }\n#define MAX 32768+10000\nusing namespace std;\ntypedef pair<int, int> pii;\ntypedef pair<double,double>pdd;\ntypedef pair<ll,ll>pll;\nint main(){\n int n;\n vector<bool>Primecheck(MAX+1,true);\n vector<int>Primenumber(MAX+1,0); //Primearray\n int Primecounter =0; //Primearray counter;\n for(int i = 2; i<MAX+1;i++){\n if(Primecheck[i]){\n for(int j = 2;i*j<MAX;j++)\n Primecheck[i*j] = false;//?´???°??????Primearray???????´??????????????????°?????¨???false???\n Primenumber[Primecounter] = i;\n Primecounter++;\n }\n }\n while(cin>>n,n){\n int ans=0;\n for(int i=0; i<Primecounter;i++){\n if(Primenumber[i]>n)break;\n for(int j=i; j<Primecounter;j++){\n if(Primenumber[j]>n)break;\n if(Primenumber[i]+Primenumber[j]==n)\n ans++;\n }\n }\n cout<<ans<<endl;\n ans=0;\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 2992, "score_of_the_acc": -0.0989, "final_rank": 4 }, { "submission_id": "aoj_1200_2123551", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int n,a[33000]={0,0,1,1},c,i,j;\n for(i=4;i<33000;i++){\n for(j=2,c=1;j*j<=i;j++){\n if(i%j==0)c--;\n }\n if(c>0)a[i]=1;\n else a[i]=0;\n }\n while(cin>>n,n){\n for(i=3,c=0;i<n;){\n for(j=n-1;j>2;){\n\tif(i+j==n)c++;\n\twhile(!a[--j]);\n }\n while(!a[++i]);\n }\n cout<<(c-1)/2+1<<endl;\n }\n}", "accuracy": 1, "time_ms": 1550, "memory_kb": 3132, "score_of_the_acc": -0.3379, "final_rank": 17 }, { "submission_id": "aoj_1200_2123359", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nvector<int> pn;\nvector<bool> is_p;\n\nvoid enum_prime()\n{\n is_p.resize(1<<15, true);\n is_p[0] = is_p[1] = false;\n for(int i = 2; i < 1<<15; i++) {\n if(!is_p[i]) continue;\n pn.push_back(i);\n for(int j = i+i; j < 1<<15; j+=i) is_p[j] = false;\n }\n}\n\nint main()\n{\n int n;\n enum_prime();\n while(cin >> n, n) {\n int cnt = 0;\n for(int i = 0; i < pn.size() && pn[i] < n; i++) {\n for(int j= i; j < pn.size() && pn[i] + pn[j] <= n; j++) {\n\tif(pn[i] + pn[j] == n) cnt++;\n }\n }\n cout << cnt << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3100, "score_of_the_acc": -0.1015, "final_rank": 7 }, { "submission_id": "aoj_1200_2123205", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nbool check(int n){\n if(n==1||n==0)return 0;\n for(int i=2;i*i<=n;i++) if(n%i==0)return 0;\n return 1;\n}\n\nint main(){\n int n;\n \n while(cin>>n,n){\n int cnt=0;\n for(int i=0;i<n;i++)\n if(check(i)&&check(n-i)&&i<=n-i)cnt++;\n cout <<cnt<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3096, "score_of_the_acc": -0.1013, "final_rank": 6 }, { "submission_id": "aoj_1200_1953590", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <map>\n#include <algorithm>\n#include <sstream>\n#include <cmath>\n#include <set>\n#include <cstdio>\n#include <iomanip>\n\nusing namespace std;\n\n#define REP(i,n) for(int (i)=0;(i)<(int)(n);(i)++)\n#define RREP(i,n) for(int (i)=(int)(n)-1;(i)>=0;(i)--)\n#define REMOVE(Itr,n) (Itr).erase(remove((Itr).begin(),(Itr).end(),n),(Itr).end())\n#define PB_VEC(Itr1,Itr2) (Itr1).insert((Itr1).end(),(Itr2).begin(),(Itr2).end())\n#define UNIQUE(Itr) sort((Itr).begin(),(Itr).end()); (Itr).erase(unique((Itr).begin(),(Itr).end()),(Itr).end())\n\ntypedef long long ll;\n\nbool isPrime(int n){\n if(n==1)return false;\n if(n==2)return true;\n for(int i=2;i<sqrt(n)+1;i++){\n if((n%i)==0)return false;\n }\n return true;\n}\n\n\nint main(){\n \n while(true)\n {\n int n;\n cin>>n;\n if(n==0)\n {\n break;\n }\n \n int ans=0;\n for(int i=2;i<=n/2;i++)\n {\n if(isPrime(i)&&isPrime(n-i))ans++;\n }\n \n cout<<ans<<endl;\n \n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2984, "score_of_the_acc": -0.0939, "final_rank": 3 }, { "submission_id": "aoj_1200_1946089", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstdlib>\n#include <string>\n#include <vector>\n#include <deque>\n#include <list>\n#include <algorithm>\n#include <numeric>\n#include <functional>\n#include <cmath>\n#include <cstring>\n#include <cctype>\n#include <sstream>\n#include <set>\n#include <map>\n#include <stack>\n#include <queue>\n#include <complex>\nusing namespace std;\n#define REP(i,n) for(int i = 0; i < (int)n; i++)\n#define FOR(i,a,b) for(int i = a; i < (int)b; i++)\n#define pb push_back\n#define mp make_pair\ntypedef vector<int> vi;\ntypedef pair<int, int> pi;\ntypedef long long ll;\nconst int INF = 1<<28;\nconst ll MOD = 1000000007;\n\nint main() {\n\tvector<bool> prime(1<<15, true);\n\tprime[0] = prime[1] = false;\n\tFOR(i, 2, 1<<15) {\n\t\tif(prime[i]) {\n\t\t\tfor(int j=i*2; j < 1<<15; j += i)\n\t\t\t\tprime[j] = false;\n\t\t}\n\t}\n\tint n;\n\twhile(cin >> n, n) {\n\t\tint cnt = 0;\n\t\tREP(i, n) {\n\t\t\tif(prime[i] > n)\n\t\t\t\tbreak;\n\t\t\tFOR(j, i, n) {\n\t\t\t\tif(prime[j] > n)\n\t\t\t\t\tbreak;\n\t\t\t\tif(prime[i] && prime[j] && i + j == n) {\n\t\t\t\t\tcnt++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << cnt << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 6530, "memory_kb": 1200, "score_of_the_acc": -1, "final_rank": 19 }, { "submission_id": "aoj_1200_1895811", "code_snippet": "#include<bits/stdc++.h>\n#define range(i,a,b) for(int i = (a); i < (b); i++)\n#define rep(i,b) range(i,0,b)\n#define pb(a) push_back(a)\n#define all(a) (a).begin(), (a).end()\n#define debug(x) cout << \"debug \" << x << endl;\nusing namespace std;\n\n#define N (1 << 15) \n\nint main(){\n bool prime[N] = {1,1,0};\n vector<int> v;\n rep(i,N){\n if(!prime[i]){\n v.pb(i);\n for(int j = i + i; j < N; j+=i){\n prime[j] = 1;\n }\n }\n }\n map<int, int> cnt;\n rep(i,v.size()){\n range(j,i,v.size()){\n cnt[v[i] + v[j]]++;\n }\n }\n int n;\n while(cin >> n,n){\n cout << cnt[n] << endl;\n }\n}", "accuracy": 1, "time_ms": 390, "memory_kb": 2964, "score_of_the_acc": -0.1511, "final_rank": 13 }, { "submission_id": "aoj_1200_1892174", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <cstdio>\n#include <functional>\n#include <numeric>\n#include <stack>\n#include <queue>\n#include <map>\n#include <set>\n#include <utility>\n#include <sstream>\n#include <complex>\n#include <fstream>\n\nusing namespace std;\n\n#define FOR(i,a,b) for(long long i=(a);i<(b);i++)\n#define REP(i,N) for(long long i=0;i<(N);i++)\n#define ALL(s) (s).begin(),(s).end()\n#define fi first\n#define se second\n\n#define PI acos(-1.0)\n#define INF 10e7+9\n#define EPS 1e-10\n#define MAX_N 100100\n#define MAX_M 100100\n\ntypedef long long ll;\ntypedef pair<ll, ll> P;\ntypedef pair<double, double> PD;\ntypedef pair<string, ll> PS;\ntypedef vector<ll> V;\ntypedef pair<P, char> PC;\n\nint n;\nbool is_prime[100100];\nint prime[100100];\nint p = 0;\n\nint main(){\n\tfill(is_prime, is_prime + 100100, 1);\n\tis_prime[0] = is_prime[1] = 0;\n\tfor (int i = 2; i < 100100; i++){\n\t\tif (is_prime[i]){\n\t\t\tprime[p] = i;\n\t\t\tp++;\n\t\t\tfor (int j = i * 2; j < 100100; j += i){\n\t\t\t\tis_prime[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\twhile (cin >> n&&n){\n\t\tint ans = 0;\n\t\tREP(i, p){\n\t\t\tfor (int j = i; j < p; j++){\n\t\t\t\tif (prime[i] + prime[j] == n)ans++;\n\t\t\t}\n\t\t}\n\t\tcout << ans << endl;\n\t}\n}", "accuracy": 1, "time_ms": 1320, "memory_kb": 1296, "score_of_the_acc": -0.206, "final_rank": 15 }, { "submission_id": "aoj_1200_1887188", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std ;\n\n#define pb(n) push_back(n)\n#define fi first\n#define se second\n#define all(r) (r).begin(),(r).end()\n#define gsort(st,en) sort((st),(en),greater<int>())\n#define vmax(ary) *max_element(all(ary))\n#define vmin(ary) *min_element(all(ary))\n#define debug(x) cout<<#x<<\": \"<<x<<endl\n#define fcout(n) cout<<fixed<<setprecision((n))\n#define scout(n) cout<<setw(n)\n#define vary(type,name,size,init) vector< type> name(size,init)\n\n#define rep(i,n) for(int i = 0; i < (int)(n);++i)\n#define REP(i,a,b) for(int i = (a);i < (int)(b);++i)\n#define repi(it,array) for(auto it = array.begin(),end = array.end(); it != end;++it)\n#define repa(n,array) for(auto &n :(array))\n\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<ll>;\nusing dict = map<string,int>;\nusing pii = pair<int,int> ;\n\nconstexpr int imax = ((1<<30)-1)*2+1 ;\nconstexpr int inf = 100000000;\nconstexpr double PI = acos(-1.0) ;\ndouble eps = 1e-10 ;\nconst int dy[] = {-1,0,1,0};\nconst int dx[] = {0,-1,0,1};\n\ninline bool value(int x,int y,int w,int h){\n return (x >= 0 && x < w && y >= 0 && y < h);\n}\n\ntemplate<typename T>\nvoid Unique(vector<T> &v){\n sort(all(v));\n v.erase(unique(all(v)),v.end());\n}\n\ntemplate<typename T>\nT ston(string& str, T n){\n istringstream sin(str) ;\n T num ;\n sin >> num ;\n return num ;\n}\n\nvoid Ans(bool f){\n if(f) cout << \"YES\"<<endl;\n else cout << \"NO\"<<endl;\n}\nconst int PrimeMax = 50001;\nint is_prime[PrimeMax];\nvoid Eratosthenes(int N){\n for(int i = 0; i < N; i++){\n is_prime[i] = 1;\n }\n is_prime[1] = 0;\n for(int i = 2; i < N ; i++){\n if(is_prime[i]){\n for(int j = 0; i * (j + 2) < N; j++){\n is_prime[i *(j + 2)] = 0;\n }\n }\n }\n}\nint ans[50001];\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n Eratosthenes(PrimeMax);\n vary(int,v,0,0);\n v.clear();\n rep(i,PrimeMax){\n if(is_prime[i] != 0){\n v.pb(i);\n }\n }\n REP(i,1,v.size()){\n REP(j,i,v.size()){\n if(v[i] + v[j] < PrimeMax){\n ans[v[i]+v[j]]++;\n }\n }\n }\n int n;\n while(cin >> n&&n){\n cout << ans[n] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3532, "score_of_the_acc": -0.1227, "final_rank": 10 }, { "submission_id": "aoj_1200_1885090", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define all(c) (c).begin(),(c).end()\n#define rrep(i,n) for(int i=(int)(n)-1;i>=0;i--)\n#define REP(i,m,n) for(int i=(int)(m);i<(int)(n);i++)\n#define rep(i,n) REP(i,0,n)\n#define iter(c) __typeof((c).begin())\n#define tr(it,c) for(iter(c) it=(c).begin();it!=(c).end();it++)\n#define mem(a) memset(a,0,sizeof(a))\n#define pd(a) printf(\"%.10f\\n\",a)\n#define pb(a) push_back(a)\n#define in(a) insert(a)\n#define pi M_PI\n#define R cin>>\n#define F first\n#define S second\n#define C class\n#define ll long long\n#define ln cout<<'\\n'\ntemplate<C T>void pr(T a){cout<<a;ln;}\ntemplate<C T,C T2>void pr(T a,T2 b){cout<<a<<' '<<b;ln;}\ntemplate<C T,C T2,C T3>void pr(T a,T2 b,T3 c){cout<<a<<' '<<b<<' '<<c;ln;}\ntemplate<C T>void PR(T a,int n){rep(i,n){if(i)cout<<' ';cout<<a[i];}ln;}\nbool check(int n,int m,int x,int y){return x>=0&&x<n&&y>=0&&y<m;}\nconst ll MAX=1000000007,MAXL=1LL<<60,dx[4]={-1,0,1,0},dy[4]={0,1,0,-1};\ntypedef pair<int,int> P;\n\nvector<int> sieve(int n) {\n vector<int> p(n);\n REP(i,2,n) p[i]=i;\n for(int i=2; i*i<n; i++) {\n if(p[i]) {\n for(int j=i*i; j<n; j+=i) p[j]=0;\n }\n }\n p.erase(remove(all(p),0),p.end());\n return p;\n}\n\nvoid Main() {\n vector<int> p=sieve(33000);\n int n;\n while(R n && n) {\n int ans=0;\n rep(i,p.size()) {\n REP(j,i,p.size()) {\n if(p[i]+p[j]>n) break;\n if(n==p[i]+p[j]) ans++;\n }\n }\n pr(ans);\n }\n}\n\nint main() {\n ios::sync_with_stdio(0);cin.tie(0);\n Main();return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 1268, "score_of_the_acc": -0.0082, "final_rank": 1 }, { "submission_id": "aoj_1200_1885088", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define all(c) (c).begin(),(c).end()\n#define rrep(i,n) for(int i=(int)(n)-1;i>=0;i--)\n#define REP(i,m,n) for(int i=(int)(m);i<(int)(n);i++)\n#define rep(i,n) REP(i,0,n)\n#define iter(c) __typeof((c).begin())\n#define tr(it,c) for(iter(c) it=(c).begin();it!=(c).end();it++)\n#define mem(a) memset(a,0,sizeof(a))\n#define pd(a) printf(\"%.10f\\n\",a)\n#define pb(a) push_back(a)\n#define in(a) insert(a)\n#define pi M_PI\n#define R cin>>\n#define F first\n#define S second\n#define C class\n#define ll long long\n#define ln cout<<'\\n'\ntemplate<C T>void pr(T a){cout<<a;ln;}\ntemplate<C T,C T2>void pr(T a,T2 b){cout<<a<<' '<<b;ln;}\ntemplate<C T,C T2,C T3>void pr(T a,T2 b,T3 c){cout<<a<<' '<<b<<' '<<c;ln;}\ntemplate<C T>void PR(T a,int n){rep(i,n){if(i)cout<<' ';cout<<a[i];}ln;}\nbool check(int n,int m,int x,int y){return x>=0&&x<n&&y>=0&&y<m;}\nconst ll MAX=1000000007,MAXL=1LL<<60,dx[4]={-1,0,1,0},dy[4]={0,1,0,-1};\ntypedef pair<int,int> P;\n\nvector<int> sieve(int n) {\n vector<int> p(n);\n REP(i,2,n) p[i]=i;\n for(int i=2; i*i<n; i++) {\n if(p[i]) {\n for(int j=i*i; j<n; j+=i) p[j]=0;\n }\n }\n p.erase(remove(all(p),0),p.end());\n return p;\n}\n\nvoid Main() {\n vector<int> p=sieve(33000);\n int n;\n while(R n && n) {\n int ans=0;\n rep(i,p.size()) {\n REP(j,i,p.size()) {\n if(n==p[i]+p[j]) ans++;\n }\n }\n pr(ans);\n }\n}\n\nint main() {\n ios::sync_with_stdio(0);cin.tie(0);\n Main();return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 1268, "score_of_the_acc": -0.0266, "final_rank": 2 } ]
aoj_1202_cpp
Problem C: Mobile Phone Coverage A mobile phone company ACMICPC (Advanced Cellular, Mobile, and Internet-Connected Phone Corporation) is planning to set up a collection of antennas for mobile phones in a city called Maxnorm. The company ACMICPC has several collections for locations of antennas as their candidate plans, and now they want to know which collection is the best choice. for this purpose, they want to develop a computer program to find the coverage of a collection of antenna locations. Each antenna A i has power r i , corresponding to "radius". Usually, the coverage region of the antenna may be modeled as a disk centered at the location of the antenna ( x i , y i ) with radius r i . However, in this city Maxnorm such a coverage region becomes the square [ x i − r i , x i + r i ] × [ y i − r i , y i + r i ]. In other words, the distance between two points ( x p , y p ) and ( x q , y q ) is measured by the max norm max{ | x p − x q |, | y p − y q |}, or, the L ∞ norm, in this city Maxnorm instead of the ordinary Euclidean norm √ {( x p − x q ) 2 + ( y p − y q ) 2 }. As an example, consider the following collection of 3 antennas 4.0 4.0 3.0 5.0 6.0 3.0 5.5 4.5 1.0 depicted in the following figure where the i -th row represents x i , y i r i such that ( x i , y i ) is the position of the i -th antenna and r i is its power. The area of regions of points covered by at least one antenna is 52.00 in this case. Write a program that finds the area of coverage by a given collection of antenna locations. Input The input contains multiple data sets, each representing a collection of antenna locations. A data set is given in the following format. n x 1 y 1 r 1 x 2 y 2 r 2 . . . x n y n r n The first integer n is the number of antennas, such that 2 ≤ n ≤ 100. The coordinate of the i -th antenna is given by ( x i , y i ), and its power is r i . x i , y i and r i are fractional numbers between 0 and 200 inclusive. The end of the input is indicated by a data set with 0 as the value of n . Output For each data set, your program should output its sequence number (1 for the first data set, 2 for the second, etc.) and the area of the coverage region. The area should be printed with two digits to the right of the decimal point, after rounding it to two decimal places. The sequence number and the area should be printed on the same line with no spaces at the beginning and end of the line. The two numbers should be separated by a space. Sample Input 3 4.0 4.0 3.0 5.0 6.0 3.0 5.5 4.5 1.0 2 3.0 3.0 3.0 1.5 1.5 1.0 0 Output for the Sample Input 1 52.00 2 36.00
[ { "submission_id": "aoj_1202_3709040", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n// #define int ll\nusing PII = pair<ll, ll>;\n\n#define FOR(i, a, n) for (ll i = (ll)a; i < (ll)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define ALL(x) x.begin(), x.end()\n\ntemplate<typename T> T &chmin(T &a, const T &b) { return a = min(a, b); }\ntemplate<typename T> T &chmax(T &a, const T &b) { return a = max(a, b); }\ntemplate<typename T> bool IN(T a, T b, T x) { return a<=x&&x<b; }\ntemplate<typename T> T ceil(T a, T b) { return a/b + !!(a%b); }\n\ntemplate<typename T> vector<T> make_v(size_t a) { return vector<T>(a); }\ntemplate<typename T,typename... Ts>\nauto make_v(size_t a,Ts... ts) {\n return vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));\n}\ntemplate<typename T,typename V> typename enable_if<is_class<T>::value==0>::type\nfill_v(T &t, const V &v) { t=v; }\ntemplate<typename T,typename V> typename enable_if<is_class<T>::value!=0>::type\nfill_v(T &t, const V &v ) { for(auto &e:t) fill_v(e,v); }\n\ntemplate<class S,class T>\nostream &operator <<(ostream& out,const pair<S,T>& a) {\n out<<'('<<a.first<<','<<a.second<<')'; return out;\n}\ntemplate<class T>\nostream &operator <<(ostream& out,const vector<T>& a){\n out<<'[';\n for(const T &i: a) out<<i<<',';\n out<<']';\n return out;\n}\ntemplate<class T>\nostream &operator <<(ostream& out, const set<T>& a) {\n out<<'{';\n for(const T &i: a) out<<i<<',';\n out<<'}';\n return out;\n}\ntemplate<class T, class S>\nostream &operator <<(ostream& out, const map<T,S>& a) {\n out<<'{';\n for(auto &i: a) out<<i<<',';\n out<<'}';\n return out;\n}\n\nint dx[] = {0, 1, 0, -1}, dy[] = {1, 0, -1, 0}; // DRUL\nconst int INF = 1<<30;\nconst ll LLINF = 1LL<<60;\nconst ll MOD = 1000000007;\n\nstruct node {\n ll y, l, r;\n bool isadd;\n\n bool operator<(const node& a) {\n return y < a.y;\n }\n};\n\nsigned main(void)\n{\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n ll tc = 1;\n while(1) {\n ll n;\n cin >> n;\n if(!n) break;\n vector<node> v;\n REP(i, n) {\n double x, y, r;\n cin >> x >> y >> r;\n ll xx = x*100, yy = y*100, rr = r*100;\n v.push_back({yy-rr+20000, xx-rr+20000, xx+rr+20000, true});\n v.push_back({yy+rr+20000, xx-rr+20000, xx+rr+20000, false});\n }\n sort(ALL(v));\n\n vector<int> now(40001);\n ll prev = 0, width = 0, ans = 0;\n REP(i, v.size()) {\n // (y座標のdiff) * width\n ans += (v[i].y - prev) * width;\n // cout << \"y:\" << v[i].y << \" prev:\" << prev << \" width:\" << width << \" ans:\" << ans << endl;\n prev = v[i].y;\n // widthの計算\n // cout << \"l:\" << v[i].l << \" r:\" << v[i].r << \" isadd:\" << v[i].isadd << endl;\n if(v[i].isadd) FOR(x, v[i].l, v[i].r) now[x]++;\n else FOR(x, v[i].l, v[i].r) now[x]--;\n // cout << now << endl;\n width = 0;\n REP(x, 40001) width += (now[x]>0);\n }\n\n cout << tc << \" \" << fixed << setprecision(2) << ans/10000.0 << endl;\n tc++;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3424, "score_of_the_acc": -1, "final_rank": 11 }, { "submission_id": "aoj_1202_2052054", "code_snippet": "#include <bits/stdc++.h>\n#define rep( i, begin, end) for( int i = begin; i < end; i++ )\nusing namespace std;\n \nstruct coverage {\n double x1, x2, y1, y2;\n coverage( double x1, double x2, double y1, double y2 ) : x1( x1 ), x2( x2 ), y1( y1 ), y2( y2 ) { }\n};\n\nbool confirm( const coverage &region1, const coverage &region2 )\n{\n return( region1.x1 < region2.x2 && region2.x1 < region1.x2 && region1.y1 < region2.y2 && region2.y1 < region1.y2 );\n}\n \nint main() {\n int n, order = 0;\n double x, y, r, area;\n while( cin >> n ) {\n if( n == 0 )\n break;\n vector<coverage> square;\n vector<double> sx, sy;\n rep ( i, 0, n ) {\n cin >> x >> y >> r;\n square.push_back( coverage( x - r, x + r, y - r, y + r) );\n sx.push_back( x - r );\n sx.push_back( x + r );\n sy.push_back( y - r );\n sy.push_back( y + r );\n }\n area = 0;\n sort( sx.begin(), sx.end() );\n sort( sy.begin(), sy.end() );\n \n int a, b, c, flag;\n for( a = 0; a < sx.size() - 1; a++ )\n for( b = 0; b < sy.size() - 1; b++ )\n for( c = flag = 0; c < square.size(); c++) {\n if( confirm( square[c], coverage( sx[ a ], sx[ a + 1 ], sy[ b ], sy[ b + 1 ] ) ) )\n if( flag == 0 ) {\n area += ( sx[ a + 1 ] - sx[ a ] ) * ( sy[ b + 1 ] - sy[ b ] );\n\t\t\t\t\t\t\tflag++;\n\t\t\t\t\t\t}\n }\n cout << ++order << \" \" << fixed << setprecision(2) << area << endl;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3208, "score_of_the_acc": -0.9369, "final_rank": 9 }, { "submission_id": "aoj_1202_895720", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <sstream>\n#include <cstring>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n#include <numeric>\n#include <cctype>\n#include <tuple>\n\n#ifdef _MSC_VER\n#include <agents.h>\n#endif\n\n#define FOR(i, a, b) for(int i = (a); i < (int)(b); ++i)\n#define rep(i, n) FOR(i, 0, n)\n#define ALL(v) v.begin(), v.end()\n#define REV(v) v.rbegin(), v.rend()\n#define MEMSET(v, s) memset(v, s, sizeof(v))\n#define X first\n#define Y second\n\nusing namespace std;\n\nconst double EPS = 1e-9;\n\nstruct Rect{\n\tdouble l, t, r, b;\n\tbool contain(const Rect &rc){\n\t\treturn l - EPS < rc.l &&\n\t\t\tt - EPS < rc.t &&\n\t\t\tr + EPS > rc.r &&\n\t\t\tb + EPS > rc.b;\n\t}\n\tdouble S(){\n\t\treturn (r - l)*(b - t);\n\t}\n};\n\nint n;\nRect rect[500];\ndouble x[500], y[500];\n\nint main(){\n\tcout.setf(ios::fixed);\n\tcout.precision(2);\n\tint t = 1;\n\twhile (cin >> n, n){\n\t\trep(i, n){\n\t\t\tdouble xx, yy, rr;\n\t\t\tcin >> xx >> yy >> rr;\n\t\t\trect[i] = Rect{ xx - rr, yy - rr, xx + rr, yy + rr };\n\t\t\tx[i * 2] = xx - rr, x[i * 2 + 1] = xx + rr;\n\t\t\ty[i * 2] = yy - rr, y[i * 2 + 1] = yy + rr;\n\t\t}\n\t\tsort(x, x + 2 * n);\n\t\tsort(y, y + 2 * n);\n\n\t\tdouble ans = 0;\n\t\trep(i, 2 * n - 1) rep(j, 2 * n - 1) {\n\t\t\tRect r = {x[i], y[j], x[i+1], y[j+1]};\n\t\t\tint cnt = 0;\n\t\t\trep(k, n){\n\t\t\t\tif (rect[k].contain(r)) ++cnt;\n\t\t\t}\n\t\t\tif (cnt > 0) ans += r.S();\n\t\t}\n\t\tcout << t++ << \" \" << ans << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1320, "score_of_the_acc": -0.407, "final_rank": 7 }, { "submission_id": "aoj_1202_489488", "code_snippet": "//24\n#include<iostream>\n#include<algorithm>\n#include<iomanip>\n\nusing namespace std;\n\nstruct L{\n int y,l,r,f;\n bool operator<(L a)const{\n return y<a.y;\n }\n};\n\nint main(){\n int cs=0;\n for(int n;cin>>n,n;){\n L l[200];\n for(int i=0;i<n;i++){\n double x,y,r;\n cin>>x>>y>>r;\n L &a=l[2*i],&b=l[2*i+1];\n a.l=b.l=(x-r)*100+.5+20000;\n a.r=b.r=(x+r)*100+.5+20000;\n a.y=(y-r)*100+.5+20000;\n b.y=(y+r)*100+.5+20000;\n a.f=1;\n b.f=-1;\n }\n sort(l,l+n*2);\n int c[60001]={};\n unsigned sum=0;\n for(int i=0;i<2*n-1;i++){\n for(int j=l[i].l;j<l[i].r;j++){\n\tc[j]+=l[i].f;\n }\n int h=l[i+1].y-l[i].y;\n sum+=(60001-count(c,c+60001,0U))*h;\n }\n cout.precision(2);\n cout<<++cs<<' '<<fixed<<sum/10000.<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1548, "score_of_the_acc": -0.4629, "final_rank": 8 }, { "submission_id": "aoj_1202_466459", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n#include <cstdio>\n#include <iostream>\n#include <sstream>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <queue>\n#include <stack>\n#include <limits>\n#include <map>\n#include <string>\n#include <cstring>\n#include <set>\n#include <deque>\n#include <bitset>\n#include <list>\n#include <cctype>\n#include <utility>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair <int,int> P;\ntypedef pair <int,P > PP;\n\nint tx[] = {0,1,0,-1};\nint ty[] = {-1,0,1,0};\n\nstatic const double EPS = 1e-8;\n\nclass Data{\npublic:\n\tdouble x;\n\tdouble y;\n\tdouble r;\n\tData(double _x,double _y,double _r){\n\t\tx = _x;\n\t\ty = _y;\n\t\tr = _r;\n\t}\n};\n\nbitset<10000> found; \nbool filled[400][400];\nint main(){\n\tint n;\n\tint idx = 1;\n\twhile(~scanf(\"%d\",&n)){\n\t\tif(n==0) break;\n\n\t\tvector<Data> Points;\n\t\tmemset(filled,0,sizeof(filled));\n\n\t\tfor(int i=0;i<n;i++){\n\t\t\tdouble x,y,r;\n\t\t\tscanf(\"%lf %lf %lf\",&x,&y,&r);\n\t\t\tPoints.push_back(Data(x,y,r));\n\n\t\t\t//x=200; cx=20000;\n\t\t\t//x=0 cx=0;\n\t\t\t//r=200 ra=20000;\n\t\t\t//-20000<square<20000\n\n\t\t\tint cx = x*100.0;\n\t\t\tint cy = y*100.0;\n\t\t\tint ra = r*100.0; \n\t\t\t\n\t\t\tfor(int y=0;y<40000;y+=100){\n\t\t\t\tfor(int x=0;x<40000;x+=100){\n\t\t\t\t\tif(cx - ra + 20000 <= x && x+100 < cx+ra + 20000\n\t\t\t\t\t&& cy - ra + 20000 <= y && y+100 < cy+ra + 20000){\n\t\t\t\t\t\tfilled[y/100][x/100] = true;\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\n\t\tint res=0;\n\n\n\t\tfor(int y=0;y<40000;y+=100){\n\t\t\tfor(int x=0;x<40000;x+=100){\n\t\t\t\tif(filled[y/100][x/100]){\n\t\t\t\t\tres+= 10000;\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse{\n\n\t\t\t\t\tfound.reset();\n\t\t\t\t\tfor(int i=0;i<Points.size();i++){\n\t\t\t\t\t\tint cx = Points[i].x*100.0 + 20000;\n\t\t\t\t\t\tint cy = Points[i].y*100.0 + 20000;\n\t\t\t\t\t\tint ra = Points[i].r*100.0;\n\n\n\t\t\t\t\t\tif(cx+ra < x || x+100 <= cx - ra) continue;\n\t\t\t\t\t\tif(cy+ra < y || y+100 <= cy - ra) continue;\n\t\t\t\t\t\tfor(int dy= max(cy-ra,y);dy<min(cy+ra,y+100);dy++){\n\t\t\t\t\t\t\tfor(int dx = max(cx-ra,x);dx < min(cx+ra,x+100); dx++){\n\t\t\t\t\t\t\t\tfound[(dy-y)*100+(dx-x)] = true;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\n\t\t\t\t\t}\n\n\t\t\t\t\tres += found.count();\n\n\t\t\t\t}\n\n\t\t\t}\n\t\t}\n\n\t\tprintf(\"%d %.2lf\\n\",idx++,res/(double)10000);\t\t\n\t}\n}", "accuracy": 1, "time_ms": 940, "memory_kb": 1420, "score_of_the_acc": -1.4147, "final_rank": 12 }, { "submission_id": "aoj_1202_374538", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <vector>\n#include <list>\n#include <cmath>\n#include <fstream>\n#include <algorithm>\n#include <string>\n#include <queue>\n#include <set>\n#include <map>\n#include <complex>\n#include <iterator>\n#include <cstdlib>\n#include <cstring>\n#include <sstream>\n#include <stack>\n\nusing namespace std;\n\nconst double EPS=(1e-10);\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef complex<double> P;\ntypedef pair<P,P> Rect;\n\nbool EQ(double a,double b){\n return abs((a)-(b))<EPS;\n}\nvoid fast_stream(){\n std::ios_base::sync_with_stdio(0);\n}\n\nconst int INF=1000000000;\nint N;\n\nclass Event{\npublic:\n double y;\n bool isIn;\n int id;\n Event(){}\n Event(double y_,bool isIn_,int id_){\n y=y_;\n isIn=isIn_;\n id=id_;\n }\n bool operator<(const Event& e)const{\n return e.y>this->y; \n }\n};\nEvent evs[1001];\nRect recs[1001];\n\nclass UnionFindTree{\npublic:\n // index‚̐”‚̐eƒm[ƒh(‚ ‚éW‡‚̐e‚ðŒ©‚Â‚¯‚½‚¢‚Æ‚«‚Í‚±‚±‚𒼐ڎQÆ‚¹‚¸Afind‚ðŽg‚¤)\n vector<int> par;\n // index‚ðª‚Æ‚·‚é–Ø‚̃‰ƒ“ƒN\n vector<int> rank;\n vector<double> ls,rs;\n // –؂̍őå’l\n int treeSize;\npublic:\n UnionFindTree(int initTreeSize = 1000){\n // ˆø”‚Å—^‚¦‚ç‚ꂽ’l‚ðÅ‘åŠi”[”‚Æ‚·‚éUnionFindTree‚̍쐬\n treeSize = initTreeSize;\n init();\n }\n void init(){\n for(int i = 0; i < treeSize; i++){\n par.push_back(i);\n rank.push_back(0);\n ls.push_back(0);\n rs.push_back(0);\n }\n }\n // —^‚¦‚ç‚ꂽ”‚ªŠi”[‚³‚ê‚Ä‚¢‚é–Ø‚̃‹[ƒg‚ð’Tõ\n int find(int x){ \n if(par[x] == x)return x;\n else return par[x] = find(par[x]);\n }\n // ˜aW‡‚ð‚Æ‚éB‚½‚¾‚µ‚±‚±‚ł͊eW‡‚̐e‚Ì•t‚¯‘Ö‚¦‚Í‹N‚±‚ç‚È‚¢\n void unite(int x,int y,double l,double r){\n x = find(x);\n y = find(y);\n if(x == y)return;\n if(rank[x] < rank[y])par[x] = y;\n else{\n par[y] = x;\n if(rank[y] == rank[x])rank[x]++;\n }\n int p=find(x);\n ls[p]=l;\n rs[p]=r;\n }\n bool same(int x,int y){\n return find(x) == find(y);\n }\n};\n\nint main(){\n int cnt=0;\n while(cin>>N&&N){\n int NN=0;\n for(int i=0;i<N;i++){\n double x,y,r;\n cin>>x>>y>>r;\n recs[i].first=P(x-r,y-r);\n recs[i].second=P(x+r,y+r);\n if(EQ(r,0))continue;\n evs[2*NN]=Event(y-r,true,i);\n evs[2*NN+1]=Event(y+r,false,i);\n NN++;\n }\n sort(evs,evs+2*NN);\n double prvy=-INF;\n double sumLen=0;\n double res=0;\n vector<int> v;\n // y‚̏¬‚³‚¢‡”ԂɃCƒxƒ“ƒg‚ðˆ—\n for(int k=0;k<2*NN;k++){\n Event &e=evs[k];\n if(!EQ(prvy,-INF))res+=sumLen*(e.y-prvy);\n prvy=e.y;\n // “_‚̒ljÁAíœ\n if(e.isIn)v.push_back(e.id);\n else v.erase(find(v.begin(),v.end(),e.id));\n // ¡‰ñ‚̉¡•‚ðŒvŽZ\n UnionFindTree uft(v.size());\n for(int i=0;i<v.size();i++){\n\tuft.ls[i]=recs[v[i]].first.real();\n\tuft.rs[i]=recs[v[i]].second.real();\n }\n for(int i=0;i<v.size();i++){\n\tfor(int j=i+1;j<v.size();j++){\n\t // ”͈͂ª‚©‚Ô‚é‚æ‚¤‚È‚ç‚΁Aunite\n\t if((EQ(uft.rs[uft.find(i)]\n\t\t ,uft.ls[uft.find(j)])\n\t ||(uft.rs[uft.find(i)]\n\t\t >uft.ls[uft.find(j)]))\n\t &&(EQ(uft.ls[uft.find(i)]\n\t\t ,uft.rs[uft.find(j)])\n\t\t||(uft.ls[uft.find(i)]\n\t\t <uft.rs[uft.find(j)]))){\n\t double minx=min(uft.ls[uft.find(i)]\n\t\t\t ,uft.ls[uft.find(j)]);\n\t double maxx=max(uft.rs[uft.find(i)]\n\t\t\t ,uft.rs[uft.find(j)]);\n\t uft.unite(i,j,minx,maxx);\n\t }\n\t}\n }\n set<int> s;\n for(int i=0;i<v.size();i++)\n\ts.insert(uft.find(i));\n sumLen=0;\n for(set<int>::iterator it\n\t =s.begin();it!=s.end();it++){\n\tsumLen+=(uft.rs[*it]-uft.ls[*it]);\n }\n }\n cnt++;\n printf(\"%d %.2f\\n\",cnt,res);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1202_366524", "code_snippet": "#include<stdio.h>\n#include<vector>\n#include<algorithm>\nusing namespace std;\n\nstruct R\n{\n\tdouble x1,x2,y1,y2;\n\tR(double x1,double x2,double y1,double y2):x1(x1),x2(x2),y1(y1),y2(y2){}\n};\nbool F(const R &a,const R &b)\n{\n\treturn(a.x1<b.x2&&b.x1<a.x2&&a.y1<b.y2&&b.y1<a.y2);\n}\nint main()\n{\n\tint n,i,j,k,T=0;\n\tdouble x,y,p,res;\n\twhile(scanf(\"%d\",&n),n)\n\t{\n\t\tvector<R>v;\n\t\tvector<double>vx,vy;\n\t\twhile(n--)\n\t\t{\n\t\t\tscanf(\"%lf%lf%lf\",&x,&y,&p);\n\t\t\tv.push_back(R(x-p,x+p,y-p,y+p));\n\t\t\tvx.push_back(x-p);\n\t\t\tvx.push_back(x+p);\n\t\t\tvy.push_back(y-p);\n\t\t\tvy.push_back(y+p);\n\t\t}\n\t\tint f;\n\t\tres=0;\n\t\tsort(vx.begin(),vx.end());\n\t\tsort(vy.begin(),vy.end());\n\n\t\tfor(i=0;i+1<vx.size();++i)\n\t\t\tfor(j=0;j+1<vy.size();++j)\n\t\t\t\tfor(f=k=0;k<v.size();++k)\n\t\t\t\t\tif(F(v[k],R(vx[i],vx[i+1],vy[j],vy[j+1])))\n\t\t\t\t\t\tif(f++==0)\n\t\t\t\t\t\t\tres+=(vx[i+1]-vx[i])*(vy[j+1]-vy[j]);\n\t\tprintf(\"%d %.2f\\n\",++T,res);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 0, "score_of_the_acc": -0.086, "final_rank": 4 }, { "submission_id": "aoj_1202_236739", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <iomanip>\n#include <algorithm>\n#include <cmath>\n#include <string>\n#include <vector>\n#include <list>\n#include <queue>\n#include <stack>\n#include <set>\n#include <map>\n#include <bitset>\n#include <numeric>\n#include <climits>\n#include <cfloat>\nusing namespace std;\n\nint main()\n{\n int sequenceNum = 0;\n for(;;){\n int n;\n cin >> n;\n if(n == 0)\n return 0;\n\n vector<double> x(2*n), y(2*n), x1(n), y1(n), x2(n), y2(n);\n for(int i=0; i<n; ++i){\n double x0, y0, r;\n cin >> x0 >> y0 >> r;\n x[2*i] = x1[i] = x0 - r;\n x[2*i+1] = x2[i] = x0 + r;\n y[2*i] = y1[i] = y0 - r;\n y[2*i+1] = y2[i] = y0 + r;\n }\n sort(x.begin(), x.end());\n sort(y.begin(), y.end());\n\n double ret = 0.0;\n for(int i=0; i<2*n-1; ++i){\n for(int j=0; j<2*n-1; ++j){\n for(int k=0; k<n; ++k){\n if(x1[k] <= x[i] && x[i+1] <= x2[k] && y1[k] <= y[j] && y[j+1] <= y2[k]){\n ret += (y[j+1] - y[j]) * (x[i+1] - x[i]);\n break;\n }\n }\n }\n }\n printf(\"%d %.02f\\n\", ++sequenceNum, ret);\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 988, "score_of_the_acc": -0.3208, "final_rank": 5 }, { "submission_id": "aoj_1202_236737", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <iomanip>\n#include <algorithm>\n#include <cmath>\n#include <string>\n#include <vector>\n#include <list>\n#include <queue>\n#include <stack>\n#include <set>\n#include <map>\n#include <bitset>\n#include <numeric>\n#include <climits>\n#include <cfloat>\nusing namespace std;\n\nconst double EPS = 1.0e-10;\n\nclass Point\n{\npublic:\n double y, x;\n Point(){\n y = x = 0.0;\n }\n Point(double y0, double x0){\n y = y0;\n x = x0;\n }\n};\n\nint main()\n{\n int sequenceNum = 0;\n for(;;){\n int n;\n cin >> n;\n if(n == 0)\n return 0;\n\n vector<double> x(2*n), y(2*n);\n vector<Point> p1(n), p2(n);\n for(int i=0; i<n; ++i){\n double x0, y0, r;\n cin >> x0 >> y0 >> r;\n x[2*i] = p1[i].x = x0 - r;\n x[2*i+1] = p2[i].x = x0 + r;\n y[2*i] = p1[i].y = y0 - r;\n y[2*i+1] = p2[i].y = y0 + r;\n }\n sort(x.begin(), x.end());\n sort(y.begin(), y.end());\n\n double ret = 0.0;\n for(int i=0; i<2*n-1; ++i){\n for(int j=0; j<2*n-1; ++j){\n for(int k=0; k<n; ++k){\n if(p1[k].x <= x[i] && x[i+1] <= p2[k].x && p1[k].y <= y[j] && y[j+1] <= p2[k].y){\n ret += (y[j+1] - y[j]) * (x[i+1] - x[i]);\n break;\n }\n }\n }\n }\n printf(\"%d %.02f\\n\", ++sequenceNum, ret);\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 988, "score_of_the_acc": -0.3208, "final_rank": 5 }, { "submission_id": "aoj_1202_183990", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cstdio>\n#include <complex>\n#include <algorithm>\nusing namespace std;\ndouble unit = 0.001;\ntypedef complex<double> P;\n#define rep(i,n) for(int i=0;i<n;i++)\n\nbool cmp(const pair<P,P>&a,const pair<P,P>&b){\n\treturn a.first.imag() < b.first.imag();\n}\nint main(){\n\tint n,N=0;\n\twhile(cin >> n ,n){\n\t\tvector< pair<P,P> > data;\n\t\tdouble ans = 0;\n\t\trep(i,n){\n\t\t\tdouble a,b,r;\n\t\t\tcin >> a >> b >> r;\n\t\t\tdata.push_back(make_pair(P(a-r,b-r),P(a+r,b+r)));\n\t\t}\n\t\tsort(data.begin(),data.end(),cmp);\n\t\tfor(double x=-200;x<=400;x += unit){\n\t\t\tvector< pair<double,double> > L;\n\t\t\trep(i,n){\n\t\t\t\tif(data[i].first.real() <= x && x <= data[i].second.real()){\n\t\t\t\t\tL.push_back(make_pair(data[i].first.imag(),data[i].second.imag()));\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(L.size() == 0)continue;\n\t\t\tdouble sz = 0;\n\t\t\tdouble cs = L[0].first, ce = L[0].second;\t\t\n\t\t\tfor(int i=1;i<L.size();i++){\n\t\t\t\tif(L[i].first <= ce)ce = max(ce,L[i].second);\n\t\t\t\telse sz += ce-cs , cs = L[i].first , ce = L[i].second;\n\t\t\t}\n\t\t\tsz += ce-cs;\n\t\t\tans += sz * unit;\n\t\t}\n\t\tprintf(\"%d %.2lf\\n\",++N,ans);\n\t}\n \n}", "accuracy": 1, "time_ms": 660, "memory_kb": 988, "score_of_the_acc": -0.9875, "final_rank": 10 }, { "submission_id": "aoj_1202_170882", "code_snippet": "#include<iostream>\n#include<cmath>\n#include<vector>\n#include<set>\n#include<map>\n#include<complex>\n\n#define START 0\n#define END 1\nusing namespace std;\n\ntypedef complex<double> point;\n\nconst double infty = 1e40;\nconst double eps = 1e-10;\n\nbool eq(double a, double b){\n return abs(b-a) < eps;\n}\n\nstruct anntena{\n point ul, rd;\n anntena(point a, point b):ul(a),rd(b){}\n bool isinside(const point &t){\n if( ul.real()<=t.real()&&t.real()<=rd.real()&&\n\tul.imag()>=t.imag()&&t.imag()>=rd.imag())return true;\n return false;\n }\n};\n\nint main()\n{\n int n;\n int tc=1;\n while(cin>>n && n>0){\n double res = 0;\n set<double> X;\n set<double> Y;\n vector<anntena> va;\n\n for(int i = 0; i < n; ++i){\n double x,y,r;\n scanf(\"%lf%lf%lf\", &x, &y, &r);\n X.insert(x-r);\n X.insert(x+r);\n Y.insert(y-r);\n Y.insert(y+r);\n va.push_back( anntena(point(x-r,y+r), point(x+r,y-r) ) );\n }\n for(set<double>::iterator itx = X.begin(); itx != X.end(); ++itx){\n\n double x = *itx;\n ++itx;\n if(itx==X.end())break;\n double nx = *itx;\n --itx;\n double span_x = nx - x;\n for(set<double>::iterator ity = Y.begin(); ity != Y.end(); ++ity){\n\tdouble y = *ity;\n\t++ity;\n\tif(ity==Y.end())break;\n\tdouble ny = *ity;\n\t--ity;\n\tdouble span_y = ny - y;\n\tpoint cent = point((x+nx)/2,(y+ny)/2);\n\tbool cent_cont = false;\n\tfor(int i = 0; i < (int)va.size(); ++i){\n\t if( va[i].isinside( cent ) ) cent_cont = true;\n\t}\n\tif( cent_cont ){\n\t res += span_x * span_y;\n\t}\n } \n }\n printf(\"%d %.2lf\\n\", tc, res);\n ++tc;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1202_170881", "code_snippet": "#include<iostream>\n#include<cmath>\n#include<vector>\n#include<set>\n#include<map>\n#include<complex>\n\n#define START 0\n#define END 1\nusing namespace std;\n\ntypedef complex<double> point;\n\nconst double infty = 1e40;\nconst double eps = 1e-10;\n\nbool eq(double a, double b){\n return abs(b-a) < eps;\n}\n\nstruct anntena{\n point ul, rd;\n anntena(point a, point b):ul(a),rd(b){}\n bool isinside(const point &t){\n if( ul.real()<=t.real()&&t.real()<=rd.real()&&\n\tul.imag()>=t.imag()&&t.imag()>=rd.imag())return true;\n return false;\n }\n};\n\nint main()\n{\n int n;\n int tc=1;\n while(cin>>n && n>0){\n double res = 0;\n set<double> X;\n set<double> Y;\n vector<anntena> va;\n\n for(int i = 0; i < n; ++i){\n double x,y,r;\n scanf(\"%lf%lf%lf\", &x, &y, &r);\n //cin >> x >> y >> r;\n X.insert(x-r);\n X.insert(x+r);\n Y.insert(y-r);\n Y.insert(y+r);\n va.push_back( anntena(point(x-r,y+r), point(x+r,y-r) ) );\n }\n for(set<double>::iterator itx = X.begin(); itx != X.end(); ++itx){\n\n double x = *itx;\n ++itx;\n if(itx==X.end())break;\n double nx = *itx;\n --itx;\n double span_x = nx - x;\n for(set<double>::iterator ity = Y.begin(); ity != Y.end(); ++ity){\n\tdouble y = *ity;\n\t++ity;\n\tif(ity==Y.end())break;\n\tdouble ny = *ity;\n\t--ity;\n\tdouble span_y = ny - y;\n\t/*\n\tpoint lu = point(x,ny);\n\tpoint ru = point(nx,ny);\n\tpoint ld = point(x,y);\n\tpoint rd = point(nx,y);\n\t*/\n\tpoint cent = point((x+nx)/2,(y+ny)/2);\n\t//bool lu_cont = false;\n\t//bool rd_cont = false;\n\tbool cent_cont = false;\n\tfor(int i = 0; i < (int)va.size(); ++i){\n\t if( va[i].isinside( cent ) ) cent_cont = true;\n\t //if( va[i].isinside( rd ) ) rd_cont = true;\n\t}\n\tif( cent_cont ){//&& rd_cont ){\n\t res += span_x * span_y;\n\t}\n } \n }\n printf(\"%d %.2lf\\n\", tc, res);\n ++tc;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_1201_cpp
Problem B: Lattice Practices Once upon a time, there was a king who loved beautiful costumes very much. The king had a special cocoon bed to make excellent cloth of silk. The cocoon bed had 16 small square rooms, forming a 4 × 4 lattice, for 16 silkworms. The cocoon bed can be depicted as follows: The cocoon bed can be divided into 10 rectangular boards, each of which has 5 slits: Note that, except for the slit depth, there is no difference between the left side and the right side of the board (or, between the front and the back); thus, we cannot distinguish a symmetric board from its rotated image as is shown in the following: Slits have two kinds of depth, either shallow or deep. The cocoon bed should be constructed by fitting five of the boards vertically and the others horizontally, matching a shallow slit with a deep slit. Your job is to write a program that calculates the number of possible configurations to make the lattice. You may assume that there is no pair of identical boards. Notice that we are interested in the number of essentially different configurations and therefore you should not count mirror image configurations and rotated configurations separately as different configurations. The following is an example of mirror image and rotated configurations, showing vertical and horizontal boards separately, where shallow and deep slits are denoted by '1' and '0' respectively. Notice that a rotation may exchange position of a vertical board and a horizontal board. Input The input consists of multiple data sets, each in a line. A data set gives the patterns of slits of 10 boards used to construct the lattice. The format of a data set is as follows: XXXXX XXXXX XXXXX XXXXX XXXXX XXXXX XXXXX XXXXX XXXXX XXXXX Each x is either '0' or '1'. '0' means a deep slit, and '1' a shallow slit. A block of five slit descriptions corresponds to a board. There are 10 blocks of slit descriptions in a line. Two adjacent blocks are separated by a space. For example, the first data set in the Sample Input means the set of the following 10 boards: The end of the input is indicated by a line consisting solely of three characters "END". Output For each data set, the number of possible configurations to make the lattice from the given 10 boards should be output, each in a separate line. Sample Input 10000 01000 00100 11000 01100 11111 01110 11100 10110 11110 10101 01000 00000 11001 01100 11101 01110 11100 10110 11010 END Output for the Sample Input 40 6
[ { "submission_id": "aoj_1201_9634679", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\n#define LB(A,x) (lower_bound(ALL(A),x)-A.begin())\n#define UB(A,x) (upper_bound(ALL(A),x)-A.begin())\nint main(){\n while(1){\n vector<string>S(10);\n REP(i,10)cin>>S[i];\n vector<string>revS=S;\n REP(i,10)reverse(ALL(revS[i]));\n if(S[0]==\"END\")return 0;\n ll ans=0;\n REP(i,9)REP(j,9)if(i!=j)REP(k,9)if(k!=i&&k!=j)REP(l,9)if(l!=i&&l!=j&&l!=k)REP(m,i)if(m!=i&&m!=j&&m!=k&&m!=l){\n vector<string>T,revT,U={S[i],S[j],S[k],S[l],S[m]},revU={revS[i],revS[j],revS[k],revS[l],revS[m]};\n REP(n,10)if(n!=i&&n!=j&&n!=k&&n!=l&&n!=m){\n T.emplace_back(S[n]);\n revT.emplace_back(revS[n]);\n }\n REP(n,32){\n bool ok=1;\n REP(o,5)if((n>>o)%2&&U[o]==revU[o]){ok=0;break;}\n if(!ok)continue;\n vector<bool>K(5);\n REP(o,5){\n string t;\n REP(p,5){\n if((n>>p)%2)t+=revU[p][o];\n else t+=U[p][o];\n }\n REP(p,5)t[p]='1'+'0'-t[p];\n ll a=0;\n while(a<5&&T[a]!=t&&revT[a]!=t)a++;\n if(a==5||K[a]){ok=0;break;}\n K[a]=1;\n }\n if(ok){\n //cout<<S[i]<<endl<<S[j]<<endl<<S[k]<<endl<<S[l]<<endl<<S[m]<<endl;\n ans++;\n }\n }\n }\n ans/=2;\n cout<<ans<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3132, "score_of_the_acc": -0.0841, "final_rank": 7 }, { "submission_id": "aoj_1201_5372353", "code_snippet": "#include <iostream>\n#include<vector>\n#include<algorithm>\n#include<utility>\n#include<math.h>\n#include<iomanip>\n#include<string>\n#include <cassert>\n#include <complex>\n#include<bits/stdc++.h>\n\n#define rep(s,i,n) for(int i = s;i < n;i++)\n \nusing namespace std;\n \ntypedef long long ll; //10e18くらい\ntypedef long double ld;\ntypedef __int128_t lll;\ntypedef pair<ll, ll> pll;\n \nconst int dx[] = { 0,1,0,-1 };\nconst int dy[] = { 1,0,-1,0 };\nconst ll LongINF = 1e13 + 7;\nconst int INF = 1e9 + 7;\nconst ll LL_MAX = 9223372036854775807;\nconst ll LL_MIN = -9223372036854775807;\nconst double pi = 3.141592653589793;\n\n\nint dsp[3] = {-1,0,1};\n\n// int keta(ll i){\n\n// int keta = 0;\n// do{\n// keta++;\n// }while(i /= 10);\n\n// return keta;\n// }\n//素因数分解 O(√n)\n// vector<pair<ll,ll>> pfactor(ll n){\n// vector<pair<ll,ll>> factor;\n// ll ex; //指数\n// for(ll a = 2; a * a <= n; a++){\n// if(n % a != 0)continue;\n\n// ll ex = 0;\n\n// while(n % a == 0){\n// n /= a;\n// ex++;\n// }\n\n// factor.push_back({a,ex});\n// }\n\n// if(n != 1) factor.push_back({n,1});\n\n// return factor; \n// }\n\nstring s[10];\nstring srev[10];\nstring H[5];\nstring W[5];\nbool symm[10];//ブロックのスリットに対称性があるかどうか\n//噛み合うかどうか確認する\nbool check(int idx){\n rep(0,i,5){\n if(W[idx][i] == H[i][idx]) return false;\n }\n return true;\n}\n\nint solve(int idx,int S){\n if(S == (1<<10) - 1){\n return 1;\n }\n\n int res = 0;\n\n rep(0,i,10){\n //使ったブロックを、もう一度使うことは出来ない\n if( (S >> i) & 1)continue;\n //初めは縦に置く(idx < 5まで = 初めの五回)\n if(idx < 5){\n H[idx] = s[i];\n //S i番目のブロックを使ったらsのiビット目が1になる\n res += solve(idx + 1,S| 1 << i);\n //対称性がないなら同じところに逆向きにおいてみる\n if(!symm[i]){\n H[idx] = srev[i];\n res += solve(idx + 1, S | (1 << i));\n }\n //縦に置き終わったら、横においていく\n }else{\n W[idx - 5] = s[i];\n if(check(idx - 5)){\n res += solve(idx + 1,S | (1 << i));\n }\n if(!symm[i]){\n W[idx - 5] = srev[i];\n if(check(idx - 5)){\n res += solve(idx + 1,S | (1 << i));\n }\n }\n\n }\n }\n \n return res;\n}\n\n\n\n\nint main(void){\n\n \n while(cin >> s[0],s[0] != \"END\"){\n memset(symm,false,sizeof(symm));\n srev[0] = s[0];\n reverse(srev[0].begin(),srev[0].end());\n symm[0] = (s[0] == srev[0]);\n\n rep(0,i,9){\n cin >> s[i + 1];\n srev[i + 1] = s[i + 1];\n reverse(srev[i + 1].begin(),srev[i + 1].end());\n symm[i + 1] = (s[i + 1] == srev[i + 1]);//sとsrevが同じなら対称性がある\n }\n cout << solve(0,0)/8 << endl;\n\n // rep(0,i,10){\n // cout << s[i] << \":\" ;\n\n // cout << srev[i] << endl;\n // }\n \n } \n \n \n return 0;\n\n}", "accuracy": 1, "time_ms": 1580, "memory_kb": 3180, "score_of_the_acc": -0.2779, "final_rank": 10 }, { "submission_id": "aoj_1201_5035256", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int N=10;\n\nstring slit[N+N];\nint choose[N],used[N];\n\n\nint check(int n) {\n int k=n/2;\n for (int i=n-1; i>=0; i-=2) {\n if (slit[choose[i]][k]+slit[choose[n]][i/2]!='0'+'1') return 0;\n }\n return 1;\n}\n\nint search(int n) {\n if (n==N) return 1;\n\n int cnt=0;\n for (int i=0; i<N; i++) {\n if (used[i]) continue;\n used[i]=1;\n\n choose[n]=i;\n if (check(n)) cnt+=search(n+1);\n\n if (!slit[N+i].empty()) {\n choose[n]=N+i;\n if (check(n)) cnt+=search(n+1);\n }\n\n used[i]=0;\n }\n return cnt;\n}\n\nint solve() {\n cin>>slit[0];\n if (slit[0]==\"END\") return 0;\n for (int i=1; i<N; i++) cin>>slit[i];\n\n for (int i=0; i<N; i++) {\n string rev(rbegin(slit[i]),rend(slit[i]));\n slit[N+i]=(rev!=slit[i] ? rev : \"\");\n }\n\n memset(used,0,sizeof(used));\n cout<<search(0)/8<<'\\n';\n\n return 1;\n}\n\nint main() {\n while (solve());\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3288, "score_of_the_acc": -0.0776, "final_rank": 5 }, { "submission_id": "aoj_1201_4994264", "code_snippet": "#include <cmath>\n#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <set>\n#include <iomanip>\n#include <queue>\n#include <string>\n#include <map>\n#include <fstream>\n#include <cassert>\n#include <stack>\n#include <climits>\n#include <array>\n#include <unordered_set>\n#include <unordered_map>\n#include <memory>\n#include <functional>\n#include <cfloat>\n#include <numeric>\n#include <random>\n#include <sstream>\n#include <bitset>\nusing namespace std;\nint reverse(int n) {\n\tint result{ 0 };\n\tfor (auto i = 0; i < 5; ++i) {\n\t\tresult <<= 1;\n\t\tresult += n & 1;\n\t\tn >>= 1;\n\t}\n\treturn result;\n}\ntemplate<typename B>\nvoid iterate(const std::vector<int>& a, const int current, const int count, const B& block, std::vector<int> &use, std::vector<int>& not_use) {\n\tif (current == a.size()) {\n\t\treturn block(use, not_use);\n\t}\n\tif (a.size() > current + count) {\n\t\tnot_use.push_back(a[current]);\n\t\titerate(a, current + 1, count, block, use, not_use);\n\t\tnot_use.pop_back();\n\t}\n\tif (count > 0) {\n\t\tuse.push_back(a[current]);\n\t\titerate(a, current + 1, count - 1, block, use, not_use);\n\t\tuse.pop_back();\n\t}\n}\ntemplate<typename B>\nvoid iterate(const std::vector<int> &a, const B& block) {\n\tstd::vector<int> use, not_use; use.reserve(5); not_use.reserve(5);\n\tuse.push_back(a[0]);\n\titerate(a, 1, 4, block, use, not_use);\n}\n\nint solve(std::vector<int> boards) {\n\tfor (auto& a : boards) {\n\t\tif (a > reverse(a)) a = reverse(a);\n\t}\n\tstd::sort(boards.begin(), boards.end());\n\tint count{ 0 };\n\tconst auto block = [&count](std::vector<int> horizontal, std::vector<int> vertical) {\n\t\tstd::vector<int> index(5), actual(5); std::iota(index.begin(), index.end(), 0);\n\t\tint mask{ 0 }, c{ 0 };\n\t\tfor (auto i = 0; i < 5; ++i) {\n\t\t\tif (horizontal[i] == reverse(horizontal[i])) mask += 1 << i;\n\t\t}\n\t\tdo {\n\t\t\tif (index[0] > index[4]) continue;\n\t\t\tfor (auto pattern = 0; pattern < 32; ++pattern) {\n\t\t\t\tif ((mask & pattern) != 0) continue;\n\t\t\t\tfor (auto i = 0; i < 5; ++i) {\n\t\t\t\t\tactual[i] = (pattern >> index[i] & 1) == 0 ? horizontal[index[i]] : reverse(horizontal[index[i]]);\n\t\t\t\t}\n\t\t\t\tfor (auto i = 0; i < 5; ++i) {\n\t\t\t\t\tint target{ 0 };\n\t\t\t\t\tfor (auto j = 0; j < 5; ++j) {\n\t\t\t\t\t\ttarget += (((actual[j] >> i) & 1) ^ 1) << j;\n\t\t\t\t\t}\n\t\t\t\t\tauto find = std::find(vertical.begin() + i, vertical.end(), target);\n\t\t\t\t\tif (find == vertical.end()) {\n\t\t\t\t\t\tfind = std::find(vertical.begin() + i, vertical.end(), reverse(target));\n\t\t\t\t\t}\n\t\t\t\t\tif (find == vertical.end()) {\n\t\t\t\t\t\t--c;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\tstd::swap(vertical[i], *find);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\t++c;\n\t\t\t}\n\t\t} while (std::next_permutation(index.begin(), index.end()));\n\t\tcount += c;\n\t};\n\titerate(boards, block);\n\treturn count >> 1;\n}\n\nint main() {\n\twhile (true) {\n\t\tstd::string first; std::cin >> first;\n\t\tif (first == \"END\") break;\n\t\tstd::vector<int> boards(10);\n\t\tboards[0] = std::stoi(first, nullptr, 2);\n\t\tfor (auto i = 1; i < 10; ++i) {\n\t\t\tstd::cin >> first;\n\t\t\tboards[i] = std::stoi(first, nullptr, 2);\n\t\t}\n\t\tstd::cout << solve(boards) << '\\n';\n\t}\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3296, "score_of_the_acc": -0.0805, "final_rank": 6 }, { "submission_id": "aoj_1201_2590910", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\n#include <time.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\nchar table[20][6];\n\nint ans;\n\nvoid recursive(bool used[20],int yoko[5],int yoko_index,int tate[5],int tate_index,bool is_pre_yoko){\n\n\tif(is_pre_yoko == false && tate_index == 5){\n\t\tans++;\n\t\treturn;\n\t}\n\n\tif(is_pre_yoko == false){\n\n\t\tswitch(yoko_index){\n\t\tcase 0:\n\t\t\tfor(int i = 0; i < 20; i++){\n\t\t\t\tif(used[i] == false){\n\t\t\t\t\tint next_yoko[5];\n\t\t\t\t\tnext_yoko[0] = i;\n\t\t\t\t\tbool next_used[20];\n\t\t\t\t\tfor(int k = 0; k < 20; k++)next_used[k] = used[k];\n\t\t\t\t\tnext_used[i] = true;\n\t\t\t\t\tif(i <= 9)next_used[i+10] = true;\n\t\t\t\t\telse{\n\t\t\t\t\t\tnext_used[i-10] = true;\n\t\t\t\t\t}\n\t\t\t\t\trecursive(next_used,next_yoko,yoko_index+1,tate,tate_index,true);\n\t\t\t\t}\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 1:\n\t\t\tfor(int i = 0; i < 20; i++){\n\t\t\t\tif(used[i] == false && abs(table[tate[0]][1]-table[i][0]) == 1){\n\t\t\t\t\tint next_yoko[5];\n\t\t\t\t\tfor(int k = 0; k < 1; k++)next_yoko[k] = yoko[k];\n\t\t\t\t\tnext_yoko[1] = i;\n\t\t\t\t\tbool next_used[20];\n\t\t\t\t\tfor(int k = 0; k < 20; k++)next_used[k] = used[k];\n\t\t\t\t\tnext_used[i] = true;\n\t\t\t\t\tif(i <= 9)next_used[i+10] = true;\n\t\t\t\t\telse{\n\t\t\t\t\t\tnext_used[i-10] = true;\n\t\t\t\t\t}\n\t\t\t\t\trecursive(next_used,next_yoko,yoko_index+1,tate,tate_index,true);\n\t\t\t\t}\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 2:\n\t\t\tfor(int i = 0; i < 20; i++){\n\t\t\t\tif(used[i] == false && abs(table[tate[0]][2]-table[i][0]) == 1 && abs(table[tate[1]][2]-table[i][1]) == 1){\n\t\t\t\t\tint next_yoko[5];\n\t\t\t\t\tfor(int k = 0; k < 2; k++)next_yoko[k] = yoko[k];\n\t\t\t\t\tnext_yoko[2] = i;\n\t\t\t\t\tbool next_used[20];\n\t\t\t\t\tfor(int k = 0; k < 20; k++)next_used[k] = used[k];\n\t\t\t\t\tnext_used[i] = true;\n\t\t\t\t\tif(i <= 9)next_used[i+10] = true;\n\t\t\t\t\telse{\n\t\t\t\t\t\tnext_used[i-10] = true;\n\t\t\t\t\t}\n\t\t\t\t\trecursive(next_used,next_yoko,yoko_index+1,tate,tate_index,true);\n\t\t\t\t}\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 3:\n\t\t\tfor(int i = 0; i < 20; i++){\n\t\t\t\tif(used[i] == false && abs(table[tate[0]][3]-table[i][0]) == 1 && abs(table[tate[1]][3]-table[i][1]) == 1 &&\n\t\t\t\t\t\tabs(table[tate[2]][3]-table[i][2]) == 1 ){\n\t\t\t\t\tint next_yoko[5];\n\t\t\t\t\tfor(int k = 0; k < 3; k++)next_yoko[k] = yoko[k];\n\t\t\t\t\tnext_yoko[3] = i;\n\t\t\t\t\tbool next_used[20];\n\t\t\t\t\tfor(int k = 0; k < 20; k++)next_used[k] = used[k];\n\t\t\t\t\tnext_used[i] = true;\n\t\t\t\t\tif(i <= 9)next_used[i+10] = true;\n\t\t\t\t\telse{\n\t\t\t\t\t\tnext_used[i-10] = true;\n\t\t\t\t\t}\n\t\t\t\t\trecursive(next_used,next_yoko,yoko_index+1,tate,tate_index,true);\n\t\t\t\t}\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 4:\n\t\t\tfor(int i = 0; i < 20; i++){\n\t\t\t\tif(used[i] == false && abs(table[tate[0]][4]-table[i][0]) == 1 && abs(table[tate[1]][4]-table[i][1]) == 1 &&\n\t\t\t\t\t\tabs(table[tate[2]][4]-table[i][2]) == 1 && abs(table[tate[3]][4]-table[i][3]) == 1){\n\t\t\t\t\tint next_yoko[5];\n\t\t\t\t\tfor(int k = 0; k < 4; k++)next_yoko[k] = yoko[k];\n\t\t\t\t\tnext_yoko[4] = i;\n\t\t\t\t\tbool next_used[20];\n\t\t\t\t\tfor(int k = 0; k < 20; k++)next_used[k] = used[k];\n\t\t\t\t\tnext_used[i] = true;\n\t\t\t\t\tif(i <= 9)next_used[i+10] = true;\n\t\t\t\t\telse{\n\t\t\t\t\t\tnext_used[i-10] = true;\n\t\t\t\t\t}\n\t\t\t\t\trecursive(next_used,next_yoko,yoko_index+1,tate,tate_index,true);\n\t\t\t\t}\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\n\t}else{\n\n\t\tswitch(tate_index){\n\t\tcase 0:\n\t\t\tfor(int i = 0; i < 20; i++){\n\t\t\t\tif(used[i] == false && abs(table[yoko[0]][0] - table[i][0]) == 1){\n\t\t\t\t\tint next_tate[5];\n\t\t\t\t\tnext_tate[0] = i;\n\t\t\t\t\tbool next_used[20];\n\t\t\t\t\tfor(int k = 0; k < 20; k++)next_used[k] = used[k];\n\t\t\t\t\tnext_used[i] = true;\n\t\t\t\t\tif(i <= 9)next_used[i+10] = true;\n\t\t\t\t\telse{\n\t\t\t\t\t\tnext_used[i-10] = true;\n\t\t\t\t\t}\n\t\t\t\t\trecursive(next_used,yoko,yoko_index,next_tate,tate_index+1,false);\n\t\t\t\t}\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 1:\n\t\t\tfor(int i = 0; i < 20; i++){\n\t\t\t\tif(used[i] == false && abs(table[yoko[0]][1] - table[i][0]) == 1 && abs(table[yoko[1]][1]-table[i][1]) == 1){\n\t\t\t\t\tint next_tate[5];\n\t\t\t\t\tfor(int k = 0; k < 1; k++)next_tate[k] = tate[k];\n\t\t\t\t\tnext_tate[1] = i;\n\t\t\t\t\tbool next_used[20];\n\t\t\t\t\tfor(int k = 0; k < 20; k++)next_used[k] = used[k];\n\t\t\t\t\tnext_used[i] = true;\n\t\t\t\t\tif(i <= 9)next_used[i+10] = true;\n\t\t\t\t\telse{\n\t\t\t\t\t\tnext_used[i-10] = true;\n\t\t\t\t\t}\n\t\t\t\t\trecursive(next_used,yoko,yoko_index,next_tate,tate_index+1,false);\n\t\t\t\t}\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 2:\n\t\t\tfor(int i = 0; i < 20; i++){\n\t\t\t\tif(used[i] == false && abs(table[yoko[0]][2] - table[i][0]) == 1 && abs(table[yoko[1]][2]-table[i][1]) == 1 &&\n\t\t\t\t\t\tabs(table[yoko[2]][2]-table[i][2]) == 1){\n\t\t\t\t\tint next_tate[5];\n\t\t\t\t\tfor(int k = 0; k < 2; k++)next_tate[k] = tate[k];\n\t\t\t\t\tnext_tate[2] = i;\n\t\t\t\t\tbool next_used[20];\n\t\t\t\t\tfor(int k = 0; k < 20; k++)next_used[k] = used[k];\n\t\t\t\t\tnext_used[i] = true;\n\t\t\t\t\tif(i <= 9)next_used[i+10] = true;\n\t\t\t\t\telse{\n\t\t\t\t\t\tnext_used[i-10] = true;\n\t\t\t\t\t}\n\t\t\t\t\trecursive(next_used,yoko,yoko_index,next_tate,tate_index+1,false);\n\t\t\t\t}\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 3:\n\t\t\tfor(int i = 0; i < 20; i++){\n\t\t\t\tif(used[i] == false && abs(table[yoko[0]][3] - table[i][0]) == 1 && abs(table[yoko[1]][3]-table[i][1]) == 1 &&\n\t\t\t\t\t\tabs(table[yoko[2]][3]-table[i][2]) == 1 && abs(table[yoko[3]][3]-table[i][3]) == 1){\n\t\t\t\t\tint next_tate[5];\n\t\t\t\t\tfor(int k = 0; k < 3; k++)next_tate[k] = tate[k];\n\t\t\t\t\tnext_tate[3] = i;\n\t\t\t\t\tbool next_used[20];\n\t\t\t\t\tfor(int k = 0; k < 20; k++)next_used[k] = used[k];\n\t\t\t\t\tnext_used[i] = true;\n\t\t\t\t\tif(i <= 9)next_used[i+10] = true;\n\t\t\t\t\telse{\n\t\t\t\t\t\tnext_used[i-10] = true;\n\t\t\t\t\t}\n\t\t\t\t\trecursive(next_used,yoko,yoko_index,next_tate,tate_index+1,false);\n\t\t\t\t}\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 4:\n\t\t\tfor(int i = 0; i < 20; i++){\n\t\t\t\tif(used[i] == false && abs(table[yoko[0]][4] - table[i][0]) == 1 && abs(table[yoko[1]][4]-table[i][1]) == 1 &&\n\t\t\t\t\t\tabs(table[yoko[2]][4]-table[i][2]) == 1 && abs(table[yoko[3]][4]-table[i][3]) == 1 && abs(table[yoko[4]][4]-table[i][4]) == 1){\n\t\t\t\t\tint next_tate[5];\n\t\t\t\t\tfor(int k = 0; k < 4; k++)next_tate[k] = tate[k];\n\t\t\t\t\tnext_tate[4] = i;\n\t\t\t\t\tbool next_used[20];\n\t\t\t\t\tfor(int k = 0; k < 20; k++)next_used[k] = used[k];\n\t\t\t\t\tnext_used[i] = true;\n\t\t\t\t\tif(i <= 9)next_used[i+10] = true;\n\t\t\t\t\telse{\n\t\t\t\t\t\tnext_used[i-10] = true;\n\t\t\t\t\t}\n\t\t\t\t\trecursive(next_used,yoko,yoko_index,next_tate,tate_index+1,false);\n\t\t\t\t}\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\t}\n}\n\nvoid func(){\n\n\tfor(int i = 1; i <= 9; i++)scanf(\"%s\",table[i]);\n\n\tbool first_used[20];\n\tfor(int i = 0; i < 20; i++)first_used[i] = false;\n\n\tfor(int i = 0; i < 10; i++){\n\t\tfor(int k = 0; k < 5; k++)table[i+10][k] = table[i][4-k];\n\n\t\tif(table[i][0] == table[i][4] && table[i][1] == table[i][3]){\n\t\t\tfirst_used[i+10] = true;\n\t\t}\n\t}\n\n\tans = 0;\n\n\tint first_yoko[5],first_tate[5];\n\n\trecursive(first_used,first_yoko,0,first_tate,0,false);\n\n\tprintf(\"%d\\n\",ans/8);\n}\n\nint main(){\n\n\twhile(true){\n\t\tscanf(\"%s\",table[0]);\n\t\tif(table[0][0] == 'E')break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3168, "score_of_the_acc": -0.0749, "final_rank": 4 }, { "submission_id": "aoj_1201_2549491", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define N 100010\nusing namespace std;\ntypedef unsigned long long ull;\nconst int INF = 1LL<<55;\nconst int mod = (1e9)+7;\nconst double EPS = 1e-8;\nconst double PI = 6.0 * asin(0.5);\ntemplate<class T> T Max(T &a,T b){return a=max(a,b);}\ntemplate<class T> T Min(T &a,T b){return a=min(a,b);}\nvector<vector<int> > AB,A,B;\nint Aidx[5],Bidx[5];\n\nset<ull> S;\null VtoH(const vector<vector<int> > &v){\n const ull B = 1777771;\n ull res = 0;\n for(int i=0;i<5;i++)\n for(int j=0;j<5;j++) res = res * B + (v[i][j]+'0');\n return res;\n}\n\nvector<int> rev(vector<int> a){reverse(a.begin(),a.end());return a;}\nvoid mirror(vector<vector<int> > &res){for(int i=0;i<5;i++) res[i] = rev(res[i]);}\n\nvector<vector<int> > rot(const vector<vector<int> > &a){\n vector<vector<int> > res(5,vector<int>(5));\n for(int i=0;i<5;i++)\n for(int j=0;j<5;j++) res[i][j] = a[4-j][i];\n return res;\n}\n\nvoid insert(vector<vector<int> > &v){\n S.insert(VtoH(v));\n v = rot(v) , v = rot(v), S.insert(VtoH(v));\n mirror(v), S.insert(VtoH(v));\n v = rot(v) , v = rot(v), S.insert(VtoH(v));\n}\n\nbool canPut(int idx,int j){\n int a = 1, b = 1;\n for(int i=0;i<5;i++) if(A[i][j] == B[idx][i]) a = 0;\n for(int i=0;i<5;i++) if(A[i][j] == B[idx][4-i]) b = 0;\n return a || b;\n}\n\nbool can(){\n int used = 0;\n for(int i=0;i<5;i++){\n for(int nx=0;nx<5;nx++){\n if((used>>nx&1) || !canPut(nx,i)) continue;\n Bidx[i] = nx;\n used |= (1<<nx);\n break;\n }\n }\n return used == (1<<5)-1;\n}\n\nint solve(){\n S.clear();\n int res = 0;\n for(int i=0;i<5;i++) Aidx[i] = i;\n for(int bit=0;bit<(1<<10);bit++){\n if(__builtin_popcount(bit) != 5) continue; \n A.clear();B.clear();\n for(int i=0;i<10;i++) (bit>>i&1)? A.push_back(AB[i]):B.push_back(AB[i]);\n vector<vector<int> > tmp = A;\n do{\n for(int a=0;a<(1<<5);a++){\n for(int i=0;i<5;i++) A[Aidx[i]] = (a>>i&1)? rev(tmp[i]):tmp[i];\n if(!can() || S.count(VtoH(A))) continue;\n insert(A);\n res++;\n }\n } while(next_permutation(Aidx,Aidx+5));\n }\n return res/2;\n}\n\nsigned main(){\n while(1){\n AB.clear();\n for(int i=0;i<10;i++){\n string str;\n cin>>str;\n if(str == \"END\") return 0;\n vector<int> tmp(5);\n for(int j=0;j<5;j++) tmp[j] = str[j] - '0';\n AB.push_back(tmp);\n }\n cout<<solve()<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 2750, "memory_kb": 3200, "score_of_the_acc": -0.4305, "final_rank": 16 }, { "submission_id": "aoj_1201_2549490", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define N 100010\nusing namespace std;\ntypedef unsigned long long ull;\nconst int INF = 1LL<<55;\nconst int mod = (1e9)+7;\nconst double EPS = 1e-8;\nconst double PI = 6.0 * asin(0.5);\ntemplate<class T> T Max(T &a,T b){return a=max(a,b);}\ntemplate<class T> T Min(T &a,T b){return a=min(a,b);}\nvector<vector<int> > AB,A,B;\nint Aidx[5],Bidx[5];\n\nunordered_set<ull> S;\null VtoH(const vector<vector<int> > &v){\n const ull B = 1777771;\n ull res = 0;\n for(int i=0;i<5;i++)\n for(int j=0;j<5;j++) res = res * B + (v[i][j]+'0');\n return res;\n}\n\nvector<int> rev(vector<int> a){reverse(a.begin(),a.end());return a;}\nvoid mirror(vector<vector<int> > &res){for(int i=0;i<5;i++) res[i] = rev(res[i]);}\n\nvector<vector<int> > rot(const vector<vector<int> > &a){\n vector<vector<int> > res(5,vector<int>(5));\n for(int i=0;i<5;i++)\n for(int j=0;j<5;j++) res[i][j] = a[4-j][i];\n return res;\n}\n\nvoid insert(vector<vector<int> > &v){\n S.insert(VtoH(v));\n v = rot(v) , v = rot(v), S.insert(VtoH(v));\n mirror(v), S.insert(VtoH(v));\n v = rot(v) , v = rot(v), S.insert(VtoH(v));\n}\n\nbool canPut(int idx,int j){\n int a = 1, b = 1;\n for(int i=0;i<5;i++) if(A[i][j] == B[idx][i]) a = 0;\n for(int i=0;i<5;i++) if(A[i][j] == B[idx][4-i]) b = 0;\n return a || b;\n}\n\nbool can(){\n int used = 0;\n for(int i=0;i<5;i++){\n for(int nx=0;nx<5;nx++){\n if((used>>nx&1) || !canPut(nx,i)) continue;\n Bidx[i] = nx;\n used |= (1<<nx);\n break;\n }\n }\n return used == (1<<5)-1;\n}\n\nint solve(){\n S.clear();\n int res = 0;\n for(int i=0;i<5;i++) Aidx[i] = i;\n for(int bit=0;bit<(1<<10);bit++){\n if(__builtin_popcount(bit) != 5) continue; \n A.clear();B.clear();\n for(int i=0;i<10;i++) (bit>>i&1)? A.push_back(AB[i]):B.push_back(AB[i]);\n vector<vector<int> > tmp = A;\n do{\n for(int a=0;a<(1<<5);a++){\n for(int i=0;i<5;i++) A[Aidx[i]] = (a>>i&1)? rev(tmp[i]):tmp[i];\n if(!can() || S.count(VtoH(A))) continue;\n insert(A);\n res++;\n }\n } while(next_permutation(Aidx,Aidx+5));\n }\n return res/2;\n}\n\nsigned main(){\n while(1){\n AB.clear();\n for(int i=0;i<10;i++){\n string str;\n cin>>str;\n if(str == \"END\") return 0;\n vector<int> tmp(5);\n for(int j=0;j<5;j++) tmp[j] = str[j] - '0';\n AB.push_back(tmp);\n }\n cout<<solve()<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 2760, "memory_kb": 3196, "score_of_the_acc": -0.4317, "final_rank": 17 }, { "submission_id": "aoj_1201_2549488", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define N 100010\nusing namespace std;\ntypedef unsigned long long ull;\nconst int INF = 1LL<<55;\nconst int mod = (1e9)+7;\nconst double EPS = 1e-8;\nconst double PI = 6.0 * asin(0.5);\ntemplate<class T> T Max(T &a,T b){return a=max(a,b);}\ntemplate<class T> T Min(T &a,T b){return a=min(a,b);}\nvector<vector<int> > AB,A,B;\nint Aidx[5],Bidx[5];\n\nunordered_set<ull> S;\null VtoH(const vector<vector<int> > &v){\n const ull B = 1777771;\n ull res = 0;\n for(int i=0;i<5;i++)\n for(int j=0;j<5;j++) res = res * B + (v[i][j]+'0');\n return res;\n}\n\nvector<int> rev(vector<int> a){reverse(a.begin(),a.end());return a;}\nvoid mirror(vector<vector<int> > &res){for(int i=0;i<5;i++) res[i] = rev(res[i]);}\n\nvector<vector<int> > rot(const vector<vector<int> > &a){\n vector<vector<int> > res(5,vector<int>(5));\n for(int i=0;i<5;i++)\n for(int j=0;j<5;j++) res[i][j] = a[4-j][i];\n return res;\n}\n\nvoid insert(vector<vector<int> > v){\n S.insert(VtoH(v));\n v = rot(v) , v = rot(v), S.insert(VtoH(v));\n mirror(v), S.insert(VtoH(v));\n v = rot(v) , v = rot(v), S.insert(VtoH(v));\n}\n\nbool canPut(int idx,int j){\n int a = 1, b = 1;\n for(int i=0;i<5;i++) if(A[i][j] == B[idx][i]) a = 0;\n for(int i=0;i<5;i++) if(A[i][j] == B[idx][4-i]) b = 0;\n return a || b;\n}\n\nbool can(){\n int used = 0;\n for(int i=0;i<5;i++){\n for(int nx=0;nx<5;nx++){\n if((used>>nx&1) || !canPut(nx,i)) continue;\n Bidx[i] = nx;\n used |= (1<<nx);\n break;\n }\n }\n return used == (1<<5)-1;\n}\n\nint solve(){\n S.clear();\n int res = 0;\n for(int i=0;i<5;i++) Aidx[i] = i;\n for(int bit=0;bit<(1<<10);bit++){\n if(__builtin_popcount(bit) != 5) continue; \n A.clear();B.clear();\n for(int i=0;i<10;i++) (bit>>i&1)? A.push_back(AB[i]):B.push_back(AB[i]);\n vector<vector<int> > tmp = A;\n do{\n for(int a=0;a<(1<<5);a++){\n for(int i=0;i<5;i++) A[Aidx[i]] = (a>>i&1)? rev(tmp[i]):tmp[i];\n if(!can() || S.count(VtoH(A))) continue;\n insert(A);\n res++;\n }\n } while(next_permutation(Aidx,Aidx+5));\n }\n return res/2;\n}\n\nsigned main(){\n while(1){\n AB.clear();\n for(int i=0;i<10;i++){\n string str;\n cin>>str;\n if(str == \"END\") return 0;\n vector<int> tmp(5);\n for(int j=0;j<5;j++) tmp[j] = str[j] - '0';\n AB.push_back(tmp);\n }\n cout<<solve()<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 2730, "memory_kb": 3184, "score_of_the_acc": -0.4274, "final_rank": 15 }, { "submission_id": "aoj_1201_2549486", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define N 100010\nusing namespace std;\ntypedef unsigned long long ull;\nconst int INF = 1LL<<55;\nconst int mod = (1e9)+7;\nconst double EPS = 1e-8;\nconst double PI = 6.0 * asin(0.5);\ntemplate<class T> T Max(T &a,T b){return a=max(a,b);}\ntemplate<class T> T Min(T &a,T b){return a=min(a,b);}\nvector<vector<int> > AB,A,B;\nint Aidx[5],Bidx[5];\n\nunordered_set<ull> S;\null VtoH(const vector<vector<int> > &v){\n const ull B = 1777771;\n ull res = 0;\n for(int i=0;i<5;i++)\n for(int j=0;j<5;j++) res = res * B + (v[i][j]+'0');\n return res;\n}\n\nvector<int> rev(vector<int> a){reverse(a.begin(),a.end());return a;}\nvoid mirror(vector<vector<int> > &res){for(int i=0;i<5;i++) res[i] = rev(res[i]);}\n\nvector<vector<int> > rot(const vector<vector<int> > &a){\n vector<vector<int> > res(5,vector<int>(5));\n for(int i=0;i<5;i++)\n for(int j=0;j<5;j++) res[i][j] = a[4-j][i];\n return res;\n}\n\nvoid insert(vector<vector<int> > v){\n S.insert(VtoH(v));\n v = rot(v) , v = rot(v), S.insert(VtoH(v));\n mirror(v), S.insert(VtoH(v));\n v = rot(v) , v = rot(v), S.insert(VtoH(v));\n}\n\nbool canPut(int idx,int j){\n int a = 1, b = 1;\n for(int i=0;i<5;i++) if(A[i][j] == B[idx][i]) a = 0;\n for(int i=0;i<5;i++) if(A[i][j] == B[idx][4-i]) b = 0;\n return a || b;\n}\n\nbool can(){\n int used = 0;\n for(int i=0;i<5;i++){\n for(int nx=0;nx<5;nx++){\n if((used>>nx&1) || !canPut(nx,i)) continue;\n Bidx[i] = nx;\n used |= (1<<nx);\n break;\n }\n }\n return used == (1<<5)-1;\n}\n\nint solve(){\n S.clear();\n int res = 0;\n for(int i=0;i<5;i++) Aidx[i] = i;\n for(int bit=0;bit<(1<<10);bit++){\n if(__builtin_popcount(bit) != 5) continue; \n A.clear();B.clear();\n for(int i=0;i<10;i++) (bit>>i&1)? A.push_back(AB[i]):B.push_back(AB[i]);\n vector<vector<int> > tmp = A;\n do{\n for(int a=0;a<(1<<5);a++){\n for(int i=0;i<5;i++) A[Aidx[i]] = (a>>i&1)? rev(tmp[i]):tmp[i];\n if(S.count(VtoH(A)) || !can()) continue;\n insert(A);\n res++;\n }\n } while(next_permutation(Aidx,Aidx+5));\n }\n return res/2;\n}\n\nsigned main(){\n while(1){\n AB.clear();\n for(int i=0;i<10;i++){\n string str;\n cin>>str;\n if(str == \"END\") return 0;\n vector<int> tmp(5);\n for(int j=0;j<5;j++) tmp[j] = str[j] - '0';\n AB.push_back(tmp);\n }\n cout<<solve()<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 3160, "memory_kb": 3184, "score_of_the_acc": -0.4832, "final_rank": 18 }, { "submission_id": "aoj_1201_2548446", "code_snippet": "#include <bits/stdc++.h>\n#define r(i,n) for(int i=0;i<n;i++)\nusing namespace std;\nint ans;\nstring s[10],r[10];\nstring t1[5],t2[5];\nbool b[11];\nbool check(int p){\n r(i,5)if(t1[i][p]==t2[p][i])return 0;\n return 1;\n}\nvoid dfs2(int d){\n if(d==5)ans++;\n else{\n r(i,10)if(!b[i]){\n b[i]=1;\n t2[d]=s[i];\n if(check(d))dfs2(d+1);\n t2[d]=r[i];\n if(check(d))dfs2(d+1);\n b[i]=0;\n }\n }\n}\nvoid dfs(int d){\n if(d==5)dfs2(0);\n else{\n r(i,10)if(!b[i]){\n b[i]=1;\n t1[d]=s[i];\n dfs(d+1);\n t1[d]=r[i];\n dfs(d+1);\n b[i]=0;\n }\n }\n}\nmain(){\n while(cin>>s[0],s[0]!=\"END\"){\n memset(b,0,sizeof(b));\n ans=0;\n r[0]=s[0];\n reverse(r[0].begin(),r[0].end());\n r(i,9){\n cin>>s[i+1];\n r[i+1]=s[i+1];\n reverse(r[i+1].begin(),r[i+1].end());\n }\n int p=0;\n r(i,10)if(s[i]==r[i])p++;\n dfs(0);\n cout<<ans/(pow(2,p)*8)<<endl;\n }\n}", "accuracy": 1, "time_ms": 5080, "memory_kb": 3404, "score_of_the_acc": -0.7399, "final_rank": 19 }, { "submission_id": "aoj_1201_2293703", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define int long long\nstring s[10];\nset<int> si,us,cu;\nvector<int> v;\nint x,y;\nint calc(const int a[5][5]){\n int res=0;\n for(int i=0;i<5;i++)\n for(int j=0;j<5;j++)\n res+=(1LL<<(i*5+j))*a[i][j];\n return res;\n}\nint calc2(const int a[5][5]){\n int res=0;\n for(int i=0;i<5;i++)\n for(int j=0;j<5;j++)\n res+=(1LL<<(i*5+j))*a[i][4-j];\n return res;\n}\nstring t[5];\nbool check(){\n map<string,int> ms;\n for(int i=0;i<10;i++){\n if(cu.count(i)) continue;\n string tmp=s[i];\n ms[tmp]++;\n reverse(tmp.begin(),tmp.end());\n ms[tmp]++;\n }\n for(int i=0;i<5;i++){\n string tmp=t[i];\n ms[tmp]--;\n reverse(tmp.begin(),tmp.end());\n ms[tmp]--;\n if(ms[t[i]]<0) return false;\n }\n return true;\n}\nset<int> memo[6];\nvoid dfs(int d){\n if(memo[d].count(x)) return;\n memo[d].insert(x);\n if(d==5){\n if(si.count(x)) return;\n if(!check()) return;\n si.insert(x);\n return;\n }\n for(int i=0;i<20;i++){\n if(cu.count(i%10)) continue;\n cu.insert(i%10);\n if(i>=10) reverse(s[i%10].begin(),s[i%10].end());\n v.push_back(i%10);\n for(int j=0;j<5;j++){\n t[j]+=(s[i%10][j]=='1'?'0':'1');\n x+=(1LL<<(d*5+j))*(s[i%10][j]=='1');\n }\n dfs(d+1);\n v.pop_back();\n for(int j=0;j<5;j++){\n t[j].pop_back();\n x-=(1LL<<(d*5+j))*(s[i%10][j]=='1');\n }\n if(i>=10) reverse(s[i%10].begin(),s[i%10].end());\n cu.erase(i%10);\n }\n}\nsigned main(){\n while(cin>>s[0],s[0]!=\"END\"){\n for(int i=1;i<10;i++) cin>>s[i];\n si.clear();\n us.clear();\n for(int i=0;i<6;i++) memo[i].clear();\n x=y=0;\n dfs(0);\n int a[5][5];\n int c[5][5];\n int ans=0;\n for(int b:si){\n if(us.count(b)) continue;\n for(int i=0;i<5;i++)\n\tfor(int j=0;j<5;j++)\n\t a[i][j]=(b>>(i*5+j))&1;\n us.insert(calc(a));\n us.insert(calc2(a));\n for(int i=0;i<5;i++)\n\tfor(int j=0;j<5;j++)\n\t c[i][j]=a[4-j][i];\n us.insert(calc(c));\n us.insert(calc2(c));\n for(int i=0;i<5;i++)\n\tfor(int j=0;j<5;j++)\n\t c[i][j]=a[j][4-i];\n us.insert(calc(c));\n us.insert(calc2(c));\n for(int i=0;i<5;i++)\n\tfor(int j=0;j<5;j++)\n\t c[i][j]=a[4-i][4-j];\n us.insert(calc(c));\n us.insert(calc2(c));\n ans++;\n }\n //cout<<si.size()<<endl<<us.size()<<endl;\n cout<<ans/2<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 7710, "memory_kb": 30904, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_1201_2061405", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\n\n//// < \"d:\\d_download\\visual studio 2015\\projects\\programing_contest_c++\\debug\\a.txt\" > \"d:\\d_download\\visual studio 2015\\projects\\programing_contest_c++\\debug\\b.txt\"\n\nint getnum(vector<int>&used, const vector<vector<int>>&walls, vector<vector<int>>&decided,int now) {\n\tint sum = 0;\n\tif (now == 10)return 1;\n\telse \tif (now < 5) {\n\t\tconst int y = now;\n\t\tfor (int i = 0; i < 10; ++i) {\n\t\t\tif (used[i])continue;\n\t\t\telse {\n\t\t\t\tused[i] = true;\n\t\t\t\tfor (int rev = 0; rev < 2; ++rev) {\n\t\t\t\t\tif (rev&&walls[i][0] == walls[i][4] && walls[i][1] == walls[i][3])continue;\n\t\t\t\t\tfor (int x = 0; x < 5; ++x) {\n\t\t\t\t\t\tdecided[y][rev?4-x:x] = walls[i][x];\n\t\t\t\t\t}\n\t\t\t\t\tsum += getnum(used, walls, decided, now + 1);\n\t\t\t\t\tfor (int x = 0; x < 5; ++x) {\n\t\t\t\t\t\tdecided[y][rev ? 4 - x : x] = -1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tused[i] = false;\n\t\t\t\t\n\t\t\t}\n\t\t}\n\t\t\n\t}\n\telse {\n\t\tconst int x = now-5;\n\t\tfor (int i = 0; i < 10; ++i) {\n\t\t\tif (used[i])continue;\n\t\t\telse {\n\t\t\t\tused[i] = true;\n\t\t\t\tfor (int rev = 0; rev < 2; ++rev) {\n\t\t\t\t\tif (rev&&walls[i][0] == walls[i][4] && walls[i][1] == walls[i][3])continue;\n\n\t\t\t\t\tbool ok = true;\n\t\t\t\t\tfor (int y = 0; y < 5; ++y) {\n\t\t\t\t\t\tif (decided[rev ? 4 - y : y][x] == walls[i][y])ok = false;\n\t\t\t\t\t}\n\t\t\t\t\tif (!ok)continue;\n\t\t\t\t\t\n\t\t\t\t\tsum += getnum(used, walls, decided, now + 1);\n\n\t\t\t\t}\n\t\t\t\tused[i] = false;\n\n\t\t\t}\n\t\t}\n\n\t}\n\treturn sum;\n}\n\nint main() {\n\twhile (1) {\n\t\tvector<vector<int>>walls (10);\n\t\tfor (int i = 0; i < 10; ++i) {\n\t\t\tstring st; cin >> st;\n\t\t\tif (st == \"END\")return 0;\n\t\t\telse {\n\t\t\t\tfor (int j = 0; j< 5; ++j) {\n\t\t\t\t\twalls[i].push_back(st[j] == '1');\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<int>used(10, false);\n\t\tvector<vector<int>>decided(5, vector<int>(5, -1));\n\t\tint ans = getnum(used, walls, decided, 0);\n\t\tcout << ans/8<< endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 460, "memory_kb": 3120, "score_of_the_acc": -0.1305, "final_rank": 9 }, { "submission_id": "aoj_1201_1952873", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstdlib>\n#include <string>\n#include <vector>\n#include <deque>\n#include <list>\n#include <algorithm>\n#include <numeric>\n#include <functional>\n#include <cmath>\n#include <cstring>\n#include <cctype>\n#include <sstream>\n#include <set>\n#include <map>\n#include <stack>\n#include <queue>\n#include <complex>\nusing namespace std;\n#define REP(i,n) for(int i = 0; i < (int)n; i++)\n#define FOR(i,a,b) for(int i = a; i < (int)b; i++)\n#define pb push_back\n#define mp make_pair\ntypedef vector<int> vi;\ntypedef pair<int, int> pi;\ntypedef long long ll;\nconst int INF = 1<<28;\nconst ll MOD = 1000000007;\n\nint cnt;\nstring s[2][10];\nbool same[10];\n\nbool chk(string &a, string &b, int &pnt) {\n\tREP(i, 5) {\n\t\tif(a[i*5 + pnt - 5] == b[i])\n\t\t\treturn false;\n\t}\n\treturn true;\n}\n\nvoid dfs(int pnt, string done, bool b[2][10]) {\n\tif(pnt == 10) {\n\t\t/*\n\t\t//debug\n\t\tREP(i, 10) {\n\t\t\tREP(j, 5) {\n\t\t\t\tcout << done[i*5 + j] << ' ';\n\t\t\t}\n\t\t\tcout << endl;\n\t\t\tif(i == 4) cout << \"-----\" << endl;\n\t\t}\n\t\tcout << endl;\n\t\t*/\n\t\tcnt++;\n\t\treturn;\n\t}\n\tif(pnt < 5) {\n\t\tREP(i, 2) REP(j, 10) {\n\t\t\tif(!b[i][j]) {\n\t\t\t\tb[0][j] = true;\n\t\t\t\tb[1][j] = true;\n\t\t\t\tdfs(pnt+1, done + s[i][j], b);\n\t\t\t\tb[0][j] = false;\n\t\t\t\tif(!same[j]) b[1][j] = false;\n\t\t\t}\n\t\t}\n\t}\n\telse {\n\t\tREP(i, 2) REP(j, 10) {\n\t\t\tif(!b[i][j] && chk(done, s[i][j], pnt)) {\n\t\t\t\tb[0][j] = true;\n\t\t\t\tb[1][j] = true;\n\t\t\t\tdfs(pnt+1, done + s[i][j], b);\n\t\t\t\tb[0][j] = false;\n\t\t\t\tif(!same[j]) b[1][j] = false;\n\t\t\t}\n\t\t}\n\t}\n\treturn;\n}\n\nint main() {\n\tstring in;\n\twhile(cin >> in, in != \"END\") {\n\t\tbool b[2][10] = {};\n\t\tREP(i, 10) {\n\t\t\tif(i)\n\t\t\t\tcin >> in;\n\t\t\ts[0][i] = in;\n\t\t\treverse(in.begin(), in.end());\n\t\t\ts[1][i] = in;\n\t\t\tsame[i] = s[0][i] == s[1][i] ? true:false;\n\t\t}\n\t\tcnt = 0;\n\t\tdfs(0, \"\", b);\n\t\tcout << cnt / 8 << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 870, "memory_kb": 1200, "score_of_the_acc": -0.1196, "final_rank": 8 }, { "submission_id": "aoj_1201_1923923", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n/*\nstring cocoon[10];\nchar area[5][5];\nint ans;\n\nbool check(bool used[]){\n\tbool flag = false;\n\n\n\n\treturn flag;\n}\n\nvoid dfs(bool used[], depth){\n\tif (depth == 5){\n\n\t}\n\n\n\treturn;\n}\n\n\nint main(){\n\twhile (cin >> cocoon[0] && cocoon[0][0] != 'E'){\n\t\tfor (int i = 1; i < 10; i++){\n\t\t\tcin >> cocoon[i];\n\t\t}\n\n\t\tans = 0;\n\t\tbool used[10] = { false };\n\n\t\tcout << ans / 8 << endl;\n\t}\n\treturn 0;\n\n\n}\n\n*/\n\nint cocoon[10][5];\nint area[5][5];\nvector<int> bita, bitb;\nint ans;\n\nbool used[10];\n\nvoid check(int depth){\n\tint ret = 0;\n\n\tif (depth == 10){\n\t\tans++;\n\t\treturn;\n\t}\n\telse if (depth >= 5){\n\t\tfor (int i = 0; i < 5; i++){\n\t\t\tint num = bitb[i];\n\t\t\tif (used[num]) continue;\n\t\t\tused[num] = true;\n\t\t\tbool flag1 = true, flag2 = true;\n\n\t\t\tfor (int j = 0; j < 5; j++){\n\t\t\t\tif (area[j][depth - 5] == cocoon[num][j]) flag1 = false;\n\t\t\t\tif (area[j][depth - 5] == cocoon[num][4 - j]) flag2 = false;\n\t\t\t}\n\n\t\t\tif (flag1 || flag2) check(depth + 1);\n\t\t\t\n\t\t\tused[num] = false;\n\t\t}\n\t}\n\telse{\n\t\tfor (int i = 0; i < 5; i++){\n\t\t\tint num = bita[i];\n\t\t\tif (used[num]) continue;\n\t\t\tused[num] = true;\n\n\t\t\tfor (int j = 0; j < 5; j++){\n\t\t\t\tarea[depth][j] = cocoon[num][j];\n\t\t\t}\n\t\t\tcheck(depth + 1);\n\n\t\t\tif (cocoon[num][0] == cocoon[num][4] && cocoon[num][1] == cocoon[num][3]){\n\t\t\t\tused[num] = false;\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\tfor (int j = 0; j < 5; j++){\n\t\t\t\tarea[depth][j] = cocoon[num][4 - j];\n\t\t\t}\n\t\t\tcheck(depth + 1);\n\n\t\t\tused[num] = false;\n\t\t}\n\t}\n\n\treturn;\n}\n\n\nint main(void){\n\n\tchar in[50];\n\n\twhile (cin >> in){\n\t\tif (in[0] == 'E') break;\n\n\t\tfor (int j = 0; j < 5; j++){\n\t\t\tcocoon[0][j] = in[j] - '0';\n\t\t}\n\n\t\tfor (int i = 1; i <= 9; i++){\n\t\t\tcin >> in;\n\t\t\tfor (int j = 0; j < 5; j++){\n\t\t\t\tcocoon[i][j] = in[j] - '0';\n\t\t\t}\n\t\t}\n\t\t\n\t\tans = 0;\n\n\t\tfor (int i = 0; i < 512; i++){\n\t\t\t\n\t\t\tbita.clear();\n\t\t\tbitb.clear();\n\t\t\tint num = i;\n\t\t\tfor (int j = 0; j <= 9; j++){\n\t\t\t\tif (num % 2 != 0) bita.push_back(j);\n\t\t\t\telse bitb.push_back(j);\n\n\t\t\t\tnum = num / 2;\n\t\t\t}\n\n\t\t\tif (bita.size() != 5) continue;\n\n\t\t\tcheck(0);\n\n\t\t}\n\n\t\tcout << ans / 4 << endl;\n\n\t}\n\n\treturn 0;\n}\n\n\n\n/*\n\nvoid check(vector<int> a, vector<int> b){\n\n\tif (!a.empty()){\n\t\tint count = a.size();\n\t\tfor (int i = 0; i < count; i++){\n\t\t\tvector<int> aa(a);\n\t\t\tint num = a[i];\n\t\t\taa.erase(aa.begin() + i);\n\t\t\tfor (int j = 0; j < 5; j++){\n\t\t\t\tarea[5 - count][j] = cocoon[num][j];\n\t\t\t}\n\t\t\tcheck(aa, b);\n\t\t\tfor (int j = 0; j < 5; j++){\n\t\t\t\tarea[5 - count][j] = cocoon[num][4 - j];\n\t\t\t}\n\t\t\tcheck(aa, b);\n\t\t}\n\t}\n\telse if (!b.empty()){\n\t\tint count = b.size();\n\t\tfor (int i = 0; i < count; i++){\n\t\t\tvector<int> bb(b);\n\t\t\tint num = b[i];\n\t\t\tbool flag1 = true, flag2 = true;\n\t\t\tfor (int j = 0; j < 5; j++){\n\t\t\t\tif (area[j][5 - count] == cocoon[num][j]) flag1 = false;\n\t\t\t\tif (area[j][5 - count] == cocoon[num][4 - j]) flag2 = false;\n\t\t\t}\n\n\t\t\tbb.erase(bb.begin() + i);\n\n\t\t\tif (flag1) check(a, bb);\n\t\t\tif (flag2) check(a, bb);\n\t\t}\n\t}\n\telse{\n\t\tans++;\n\t\treturn;\n\t}\n\n\n\treturn;\n}\n\n\nint main(void){\n\n\tchar in[50];\n\tchar end[] = \"END\";\n\n\twhile (cin >> in){\n\t\tif (in[0] == 'E') break;\n\n\t\tfor (int j = 0; j < 5; j++){\n\t\t\tcocoon[0][j] = in[j] - '0';\n\t\t}\n\n\t\tfor (int i = 1; i <= 9; i++){\n\t\t\tcin >> in;\n\t\t\tfor (int j = 0; j < 5; j++){\n\t\t\t\tcocoon[i][j] = in[j] - '0';\n\t\t\t}\n\t\t}\n\n\t\tans = 0;\n\n\t\tfor (int i = 0; i < 512; i++){\n\t\t\tvector<int> bita, bitb;\n\t\t\tint bits = 0;\n\t\t\tint num = i;\n\t\t\tfor (int j = 0; j <= 9; j++){\n\t\t\t\tif (num % 2 != 0) bita.push_back(j);\n\t\t\t\telse bitb.push_back(j);\n\n\t\t\t\tnum = num / 2;\n\t\t\t}\n\n\t\t\tif (bita.size() != 5) continue;\n\n\t\t\tcheck(bita, bitb);\n\n\t\t}\n\n\t\tcout << ans / 32 << endl;\n\n\t}\n\n\treturn 0;\n}\n*/", "accuracy": 1, "time_ms": 110, "memory_kb": 1196, "score_of_the_acc": -0.0207, "final_rank": 1 }, { "submission_id": "aoj_1201_1874949", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n \nstring s[10],srev[10];\nstring H[5],W[5];\nbool eq[10];\n \nbool valid(int idx){\n for(int i = 0 ; i < 5 ; i++){\n\tif(W[idx][i] == H[i][idx]){\n\t return false;\n\t}\n }\n return true;\n}\n \nint solve(int idx,int S){\n if(S == (1<<10)-1){\n\treturn 1;\n }\n int res = 0;\n for(int i = 0 ; i < 10 ; i++){\n\tif((S >> i) & 1) continue;\n\tif(idx < 5){\n\t H[idx] = s[i];\n\t res += solve(idx+1,S|(1<<i));\n\t if(!eq[i]){\n\t\tH[idx] = srev[i];\n\t\tres += solve(idx+1,S|(1<<i));\n\t }\n\t}else{\n\t W[idx-5] = s[i];\n\t if(valid(idx-5)){\n\t\tres += solve(idx+1,S|(1<<i));\n\t }\n\t if(!eq[i]){\n\t\tW[idx-5] = srev[i];\n\t\tif(valid(idx-5)){\n\t\t res += solve(idx+1,S|(1<<i));\n\t\t}\n\t }\n\t}\n }\n return res;\n}\n \nint main(){ \n while(cin >> s[0], s[0] != \"END\"){\n\tmemset(eq,false,sizeof(eq));\n\tstring tmp = s[0];\n\treverse(tmp.begin(),tmp.end());\n\tsrev[0] = tmp;\n\teq[0] = s[0] == srev[0];\n\tfor(int i = 0 ; i < 9 ; i++){\n\t cin >> s[i+1];\n\t tmp = s[i+1];\n\t reverse(tmp.begin(),tmp.end());\n\t srev[i+1] = tmp;\n\t eq[i+1] = s[i+1] == srev[i+1];\n\t}\n\tcout << solve(0,0)/8 << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1580, "memory_kb": 3200, "score_of_the_acc": -0.2786, "final_rank": 11 }, { "submission_id": "aoj_1201_1159016", "code_snippet": "#include <string> \n#include <algorithm> \n#include <cfloat> \n#include <climits> \n#include <cmath> \n#include <complex> \n#include <cstdio> \n#include <cstdlib> \n#include <cstring> \n#include <functional> \n#include <iostream> \n#include <map> \n#include <memory> \n#include <queue> \n#include <set> \n#include <sstream> \n#include <stack> \n#include <utility> \n#include <vector> \n\n#define EACH(i,c) for(__typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define ALL(x) (x).begin(),(x).end() \nusing namespace std; \ntypedef long long ll;\nconst double eps = 1e-10;\n\nbool check(const vector<string> &l, const vector<string> &u, int bit){\n vector<string> v;\n for(int i = 0; i < 5; ++i){\n v.push_back(l[i]);\n if(bit >> i & 1){\n reverse(ALL(v[i]));\n if(v[i] == l[i]) return false;\n }\n // cout << v[i] << \" \";\n }\n // cout << endl;\n\n vector<int> used(5, -1);\n for(int j = 0; j < 5; ++j){\n string s = \"\";\n for(int i = 0; i < 5; ++i){\n if(v[i][j] == '0')\n s.push_back('1');\n else\n s.push_back('0');\n }\n string rs = s;\n reverse(ALL(rs));\n bool flag = false;\n for(int i = 0; i < 5; ++i){\n if(used[i] < 0 && (s == u[i] || rs == u[i])){\n used[i] = j;\n flag = true;\n break;\n }\n }\n if(!flag) return false;\n }\n /*\n for(int i = 0; i < 5; ++i){\n cout << v[i] << endl;\n }\n cout << endl;\n for(int i = 0; i < 5; ++i){\n cout << u[i] << \" \";\n }\n cout << endl;\n for(int i = 0; i < 5; ++i) cout << used[i] << \" \";\n cout << endl;\n */\n return true;\n}\nint main(){\n for(;;){\n vector<string> v(10);\n cin >> v[0];\n if(v[0] == \"END\") return 0;\n for(int i = 1; i < 10; ++i) cin >> v[i];\n sort(ALL(v));\n int cnt = 0;\n for(int s = 0; s < 1 << 10; ++s) if(__builtin_popcount(s) == 5 && s < (~s & 1023)){\n vector<string> lv, uv;\n for(int i = 0; i < 10; ++i)\n if(s >> i & 1)\n lv.push_back(v[i]);\n else\n uv.push_back(v[i]);\n do{\n for(int t = 0; t < 1 << 5; ++t){\n bool res = check(lv, uv, t);\n if(res){\n ++cnt;\n }\n }\n }while(next_permutation(ALL(lv)));\n }\n cout << cnt / 4 << endl;\n }\n}", "accuracy": 1, "time_ms": 2450, "memory_kb": 1208, "score_of_the_acc": -0.325, "final_rank": 13 }, { "submission_id": "aoj_1201_1129518", "code_snippet": "#include<stdio.h>\n#include<algorithm>\nusing namespace std;\nchar str[11][7];\nint used[11];\nint p[6][6];\nint solve(int a){\n\tif(a==10){\n\t\tfor(int i=0;i<5;i++)for(int j=0;j<5;j++)\n\t\t\tif(!p[i][j])return 0;\n\t\treturn 1;\n\t}\n\tint ret=0;\n\tfor(int i=0;i<10;i++){\n\t\tif(used[i])continue;\n\t\tused[i]=1;\n\t\tbool ok=true;\n\t\tif(a%2){\n\t\t\tfor(int j=0;j<5;j++){\n\t\t\t\tp[a/2][j]+=str[i][j]-'0';\n\t\t\t\tif(p[a/2][j]==2)ok=false;\n\t\t\t}\n\t\t}else{\n\t\t\tfor(int j=0;j<5;j++){\n\t\t\t\tp[j][a/2]+=str[i][j]-'0';\n\t\t\t\tif(p[j][a/2]==2)ok=false;\n\t\t\t}\n\t\t}\n\t\tif(ok)ret+=solve(a+1);\n\t\tused[i]=0;\n\t\tif(a%2){\n\t\t\tfor(int j=0;j<5;j++){\n\t\t\t\tp[a/2][j]-=str[i][j]-'0';\n\t\t\t}\n\t\t}else{\n\t\t\tfor(int j=0;j<5;j++){\n\t\t\t\tp[j][a/2]-=str[i][j]-'0';\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i=0;i<10;i++){\n\t\tif(used[i])continue;\n\t\tif(str[i][0]==str[i][4]&&str[i][1]==str[i][3])continue;\n\t\tused[i]=1;\n\t\tbool ok=true;\n\t\tif(a%2){\n\t\t\tfor(int j=0;j<5;j++){\n\t\t\t\tp[a/2][j]+=str[i][4-j]-'0';\n\t\t\t\tif(p[a/2][j]==2)ok=false;\n\t\t\t}\n\t\t}else{\n\t\t\tfor(int j=0;j<5;j++){\n\t\t\t\tp[j][a/2]+=str[i][4-j]-'0';\n\t\t\t\tif(p[j][a/2]==2)ok=false;\n\t\t\t}\n\t\t}\n\t\tif(ok)ret+=solve(a+1);\n\t\tused[i]=0;\n\t\tif(a%2){\n\t\t\tfor(int j=0;j<5;j++){\n\t\t\t\tp[a/2][j]-=str[i][4-j]-'0';\n\t\t\t}\n\t\t}else{\n\t\t\tfor(int j=0;j<5;j++){\n\t\t\t\tp[j][a/2]-=str[i][4-j]-'0';\n\t\t\t}\n\t\t}\n\t}\n\treturn ret;\n}\nint main(){\n\twhile(1){\n\t\tfor(int i=0;i<5;i++)for(int j=0;j<5;j++)p[i][j]=0;\n\t\tscanf(\"%s\",str[0]);\n\t\tfor(int i=0;i<10;i++)used[i]=0;\n\t\tif(str[0][0]=='E')break;\n\t\tfor(int i=1;i<10;i++)scanf(\"%s\",str[i]);\n\t\tint ret=solve(0);\n\t\tprintf(\"%d\\n\",ret/8);\n\t}\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 964, "score_of_the_acc": -0.0519, "final_rank": 3 }, { "submission_id": "aoj_1201_1122346", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <cstring>\nusing namespace std;\n\nint lat[5][5];\n\nvector<vector<int>> bx = {\n {0, 1, 2, 3, 4},\n {0, 1, 2, 3, 4},\n {0, 1, 2, 3, 4},\n {0, 1, 2, 3, 4},\n {0, 1, 2, 3, 4},\n {0, 0, 0, 0, 0},\n {1, 1, 1, 1, 1},\n {2, 2, 2, 2, 2},\n {3, 3, 3, 3, 3},\n {4, 4, 4, 4, 4}\n};\n\nvector<vector<int>> by = {\n {0, 0, 0, 0, 0},\n {1, 1, 1, 1, 1},\n {2, 2, 2, 2, 2},\n {3, 3, 3, 3, 3},\n {4, 4, 4, 4, 4},\n {0, 1, 2, 3, 4},\n {0, 1, 2, 3, 4},\n {0, 1, 2, 3, 4},\n {0, 1, 2, 3, 4},\n {0, 1, 2, 3, 4}\n};\n\nstring rev(string s) {\n reverse(s.begin(), s.end());\n return s;\n}\n\nint dfs(vector<string> &v, int k) {\n if (k == 10) {\n return 1;\n }\n vector<string> S(1, v[k]);\n if (v[k] != rev(v[k])) {\n S.push_back(rev(v[k]));\n }\n int ret = 0;\n for (string bloc : S) {\n for (int i=0; i<10; ++i) {\n bool ok = true;\n vector<int> t;\n for (int j=0; j<5; ++j) {\n if ((lat[by[i][j]][bx[i][j]] & 1 && bloc[j] - '0' == 0) ||\n (lat[by[i][j]][bx[i][j]] & 2 && bloc[j] - '0' == 1)) {\n ok = false;\n break;\n }\n t.push_back(lat[by[i][j]][bx[i][j]]);\n }\n if (ok) {\n for (int j=0; j<5; ++j) {\n lat[by[i][j]][bx[i][j]] |= (bloc[j] - '0' + 1);\n }\n ret += dfs(v, k+1);\n for (int j=0; j<5; ++j) {\n lat[by[i][j]][bx[i][j]] = t[j];\n }\n }\n }\n }\n return ret;\n}\n\nint main() {\n vector<string> v(10);\n while (cin >> v[0], v[0] != \"END\") {\n for (int i=1; i<10; ++i) {\n cin >> v[i];\n }\n memset(lat, 0, sizeof lat);\n int ret = dfs(v, 0);\n cout << (ret == 0 ? 0 : ret / 8) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 1220, "score_of_the_acc": -0.0449, "final_rank": 2 }, { "submission_id": "aoj_1201_1100714", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nstring s[10],srev[10];\nstring H[5],W[5];\nbool eq[10];\n\nbool valid(int idx){\n for(int i = 0 ; i < 5 ; i++){\n if(W[idx][i] == H[i][idx]){\n return false;\n }\n }\n return true;\n}\n\nint solve(int idx,int S){\n if(S == (1<<10)-1){\n return 1;\n }\n int res = 0;\n for(int i = 0 ; i < 10 ; i++){\n if((S >> i) & 1) continue;\n if(idx < 5){\n H[idx] = s[i];\n res += solve(idx+1,S|(1<<i));\n if(!eq[i]){\n H[idx] = srev[i];\n res += solve(idx+1,S|(1<<i));\n }\n }else{\n W[idx-5] = s[i];\n if(valid(idx-5)){\n res += solve(idx+1,S|(1<<i));\n }\n if(!eq[i]){\n W[idx-5] = srev[i];\n if(valid(idx-5)){\n res += solve(idx+1,S|(1<<i));\n }\n }\n }\n }\n return res;\n}\n\nint main(){ \n while(cin >> s[0], s[0] != \"END\"){\n memset(eq,false,sizeof(eq));\n string tmp = s[0];\n reverse(tmp.begin(),tmp.end());\n srev[0] = tmp;\n eq[0] = s[0] == srev[0];\n for(int i = 0 ; i < 9 ; i++){\n cin >> s[i+1];\n tmp = s[i+1];\n reverse(tmp.begin(),tmp.end());\n srev[i+1] = tmp;\n eq[i+1] = s[i+1] == srev[i+1];\n }\n cout << solve(0,0)/8 << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 2200, "memory_kb": 1200, "score_of_the_acc": -0.2923, "final_rank": 12 }, { "submission_id": "aoj_1201_1100272", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint ans;\nbool use[10];\nstring s[10],t[10];\n\nbool check(int n) {\n bool ck=true;\n for(int i=0; i<5; i++) {\n if(t[n][i]==t[i][n-5]) ck=false;\n }\n return ck;\n}\n\nvoid dfs(int n) {\n if(n==10) {\n ans++;\n return;\n }\n \n for(int i=0; i<10; i++) {\n if(!use[i]) {\n use[i]=true;\n \n t[n]=s[i];\n if(n<5) dfs(n+1);\n else {\n\tif(check(n)) {\n\t dfs(n+1);\n\t use[i]=false;\n\t return;\n\t}\n }\n\n reverse(s[i].begin(),s[i].end());\n t[n]=s[i];\n reverse(s[i].begin(),s[i].end());\n \n if(s[i]==t[n]) {\n\tuse[i]=false;\n\tcontinue;\n }\n \n if(n<5) dfs(n+1);\n else {\n\tif(check(n)) {\n\t dfs(n+1);\n\t use[i]=false;\n\t return;\n\t}\n }\n \n use[i]=false;\n }\n }\n}\n\nint main() {\n while(cin >> s[0]) {\n if(s[0]==\"END\") break;\n for(int i=1; i<10; i++) cin >> s[i];\n memset(use,false,sizeof(use));\n ans=0;\n dfs(0);\n cout << ans/8 << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 2740, "memory_kb": 1200, "score_of_the_acc": -0.3624, "final_rank": 14 } ]
aoj_1214_cpp
Problem G: Walking Ant Ants are quite diligent. They sometimes build their nests beneath flagstones. Here, an ant is walking in a rectangular area tiled with square flagstones, seeking the only hole leading to her nest. The ant takes exactly one second to move from one flagstone to another. That is, if the ant is on the flagstone with coordinates ( x , y ) at time t , she will be on one of the five flagstones with the following coordinates at time t + 1: ( x , y ), ( x + 1, y ), ( x - 1, y ), ( x , y + 1), ( x , y - 1). The ant cannot go out of the rectangular area. The ant can visit the same flagstone more than once. Insects are easy to starve. The ant has to go back to her nest without starving. Physical strength of the ant is expressed by the unit "HP". Initially, the ant has the strength of 6 HP. Every second, she loses 1 HP. When the ant arrives at a flagstone with some food on it, she eats a small piece of the food there, and recovers her strength to the maximum value, i.e., 6 HP, without taking any time. The food is plenty enough, and she can eat it as many times as she wants. When the ant's strength gets down to 0 HP, she dies and will not move anymore. If the ant's strength gets down to 0 HP at the moment she moves to a flagstone, she does not effectively reach the flagstone: even if some food is on it, she cannot eat it; even if the hole is on that stone, she has to die at the entrance of her home. If there is a puddle on a flagstone, the ant cannot move there. Your job is to write a program which computes the minimum possible time for the ant to reach the hole with positive strength from her start position, if ever possible. Input The input consists of multiple maps, each representing the size and the arrangement of the rectangular area. A map is given in the following format. w h d 11 d 12 d 13 ... d 1 w d 2 d 22 d 23 ... d 2 w ... d h 1 d h 2 d h 3 ... d h w The integers w and h are the numbers of flagstones in the x - and y -directions, respectively. w and h are less than or equal to 8. The integer d yx represents the state of the flagstone with coordinates ( x , y ) as follows. 0: There is a puddle on the flagstone, and the ant cannot move there. 1, 2: Nothing exists on the flagstone, and the ant can move there. '2' indicates where the ant initially stands. 3: The hole to the nest is on the flagstone. 4: Some food is on the flagstone. There is one and only one flagstone with a hole. Not more than five flagstones have food on them. The end of the input is indicated by a line with two zeros. Integer numbers in an input line are separated by at least one space character. Output for each map in the input, your program should output one line containing one integer representing the minimum time. If the ant cannot return to her nest, your program should output -1 instead of the minimum time. Sample Input 3 3 2 1 1 1 1 0 1 1 3 8 4 2 1 1 0 1 1 1 0 1 0 4 1 1 0 4 1 1 0 0 0 0 0 0 1 1 1 1 4 1 1 1 3 8 5 1 2 1 1 1 1 1 4 1 0 0 0 1 0 0 1 1 4 1 0 1 ...(truncated)
[ { "submission_id": "aoj_1214_5976490", "code_snippet": "#include<iostream>\n#include<cstring>\n#include<cstdio>\n#include<sstream>\n#include<algorithm>\n#include<cstdlib>\n#include<queue>\n#include<set>\n#include<map>\n#include<cmath>\n#include<ctime>\n#include<stack>\n#include<functional>\n#define INF 2100000000\n#define MOD 1000000007\n//freopen(\"input.txt\", \"r\", stdin);\n//freopen(\"output.txt\", \"w\", stdout);\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\nint w, h;\nint mp[10][10];\nint hp[10][10];\nint t[10][10];\nint vis[10][10];\nint ans = INF;\nint nxt[4][2] = {\n\t1,0,\n\t0,-1,\n\t-1,0,\n\t0,1\n};\nvoid dfs(int x, int y, int hp, int t)\n{\n\tif (hp == 0) return;\n\tif (mp[x][y] == 3)\n\t{\n\t\tans = min(ans, t);\n\t\treturn;\n\t}\n\tif (mp[x][y] == 4)\n\t{\n\t\thp = 6;\n\t\t//cout << t << endl;\n\t}\n\tfor (int i = 0; i < 4; i++)\n\t{\n\t\tint nx = x + nxt[i][0];\n\t\tint ny = y + nxt[i][1];\n\t\tif (nx > 0 && nx <= h && ny > 0 && ny <= w && mp[nx][ny] != 0 && vis[nx][ny] == 0)\n\t\t{\n\t\t\tif (mp[nx][ny] == 4) vis[nx][ny] = 1;;\n\t\t\tdfs(nx, ny, hp - 1, t + 1);\n\t\t\tif (mp[nx][ny] == 4) vis[nx][ny] = 0;\n\t\t}\n\t}\n}\nint main(void)\n{\n\twhile (scanf(\"%d %d\", &w, &h) == 2)\n\t{\n\t\tif (w == 0) break;\n\t\tint x = 0, y = 0;\n\t\tans = INF;\n\t\tfor (int i = 1; i <= h; i++)\n\t\t{\n\t\t\tfor (int j = 1; j <= w; j++)\n\t\t\t{\n\t\t\t\tscanf(\"%d\", &mp[i][j]);\n\t\t\t\tif (mp[i][j] == 2) x = i, y = j;\n\t\t\t}\n\t\t}\n\t\tdfs(x, y, 6, 0);\n\t\tif (ans == INF) printf(\"-1\\n\");\n\t\telse printf(\"%d\\n\", ans);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 6020, "memory_kb": 3204, "score_of_the_acc": -1.0544, "final_rank": 6 }, { "submission_id": "aoj_1214_2159175", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <iostream>\ntypedef long long int ll;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\nstruct Info{\n\tInfo(){\n\t\teat_after = row = col = hp = time = 0;\n\t}\n\n\tvoid set(int arg_row,int arg_col,int arg_hp,int arg_time,int arg_eat_after){\n\t\trow = arg_row;\n\t\tcol = arg_col;\n\t\thp = arg_hp;\n\t\ttime = arg_time;\n\t\teat_after = arg_eat_after;\n\t}\n\n\tint row,col,hp,time,eat_after;\n\tshort check[8][8];\n};\n\nstruct Data{\n\tint row,col;\n};\n\nint W,H,div_row[4] = {-1,0,0,1},div_col[5] = {0,-1,1,0};\nbool isCrearable;\n\nData data[7];\nint data_index,distMap[8][8],map[8][8];\nint start_row,start_col,goal_row,goal_col;\n\n\nbool rangeCheck(int row,int col){\n\tif(row >= 0 && row <= H-1 && col >= 0 && col <= W-1)return true;\n\telse{\n\t\treturn false;\n\t}\n}\n\nvoid dist5(int row,int col){\n\tint next_row,next_col;\n\tfor(int i = 0; i < 4; i++){\n\t\tnext_row = row+div_row[i],next_col = col+div_col[i];\n\t\tif(rangeCheck(next_row,next_col) == true && map[next_row][next_col] != 0 && distMap[next_row][next_col] > distMap[row][col]+1 && distMap[row][col] <= 4){\n\t\t\tdistMap[next_row][next_col] = min(distMap[next_row][next_col],distMap[row][col]+1);\n\t\t\tif(map[next_row][next_col] == 4){\n\t\t\t\tdistMap[next_row][next_col] = 0;\n\t\t\t\tdist5(next_row,next_col);\n\t\t\t}else if(next_row == start_row && next_col == start_col){\n\t\t\t\tisCrearable = true;\n\t\t\t\treturn;\n\t\t\t}else{\n\t\t\t\tdist5(next_row,next_col);\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid func(){\n\n\tfor(int i = 0; i < H; i++){\n\t\tfor(int k = 0; k < W; k++){\n\t\t\tscanf(\"%d\",&map[i][k]);\n\t\t\tif(map[i][k] == 2){\n\t\t\t\tstart_row = i;\n\t\t\t\tstart_col = k;\n\t\t\t\tmap[i][k] = 1;\n\t\t\t}else if(map[i][k] == 3){\n\t\t\t\tgoal_row = i;\n\t\t\t\tgoal_col = k;\n\t\t\t}\n\t\t}\n\t}\n\n\tisCrearable = false;\n\tfor(int i = 0; i < H; i++){\n\t\tfor(int k = 0; k < W; k++)distMap[i][k] = BIG_NUM;\n\t}\n\n\tdistMap[goal_row][goal_col] = 0;\n\tdata_index = 0;\n\n\tdist5(goal_row,goal_col);\n\n\tif(isCrearable == false){\n\t\tprintf(\"-1\\n\");\n\t\treturn;\n\t}\n\n\tint ans = -1,limit = 36;\n\tqueue<Info> Q;\n\tInfo current;\n\n\tInfo first;\n\n\tfor(int i = 0; i < H; i++){\n\t\tfor(int k = 0; k < W; k++)first.check[i][k] = 0;\n\t}\n\n\tfirst.check[start_row][start_col] = 1;\n\tfirst.set(start_row,start_col,6,0,3);\n\n\tQ.push(first);\n\n\twhile(!Q.empty()){\n\t\tcurrent = Q.front();\n\t\tQ.pop();\n\n\t\tif(current.hp == 0)continue;\n\n\t\tif(map[current.row][current.col] == 3){\n\t\t\tans = current.time;\n\t\t\tbreak;\n\t\t}else if(map[current.row][current.col] == 4){\n\t\t\tcurrent.hp = 6;\n\t\t\tcurrent.eat_after = 0;\n\t\t}\n\n\t\tif(current.time + abs(current.row-goal_row)+abs(current.col-goal_col) > limit)continue;\n\n\t\tfor(int i = 0; i < 4; i++){\n\t\t\tif(rangeCheck(current.row+div_row[i],current.col+div_col[i]) == true && map[current.row+div_row[i]][current.col+div_col[i]] != 0 &&\n\t\t\t\t\t((current.check[current.row+div_row[i]][current.col+div_col[i]] == 0) || (current.check[current.row+div_row[i]][current.col+div_col[i]] == 1 &&\tcurrent.eat_after <= 1))){\n\t\t\t\tInfo new_info;\n\t\t\t\tfor(int a = 0; a < H; a++){\n\t\t\t\t\tfor(int b = 0; b < W; b++){\n\t\t\t\t\t\tnew_info.check[a][b] = current.check[a][b];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tnew_info.check[current.row+div_row[i]][current.col+div_col[i]]++;\n\t\t\t\tnew_info.set(current.row+div_row[i],current.col+div_col[i],current.hp-1,current.time+1,current.eat_after+1);\n\t\t\t\tQ.push(new_info);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\",ans);\n}\n\nint main(){\n\n\twhile(true){\n\t\tscanf(\"%d %d\",&W,&H);\n\t\tif(W == 0 && H == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 24036, "score_of_the_acc": -0.4133, "final_rank": 3 }, { "submission_id": "aoj_1214_2158966", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <iostream>\ntypedef long long int ll;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\nint W,H,div_row[4] = {-1,0,0,1},div_col[5] = {0,-1,1,0};\n\nstruct Info{\n\tInfo(){\n\t\teat_after = row = col = hp = time = 0;\n\t}\n\n\tvoid set(int arg_row,int arg_col,int arg_hp,int arg_time,int arg_eat_after){\n\t\trow = arg_row;\n\t\tcol = arg_col;\n\t\thp = arg_hp;\n\t\ttime = arg_time;\n\t\teat_after = arg_eat_after;\n\t}\n\n\tint row,col,hp,time,eat_after;\n\tshort check[8][8];\n};\n\nbool rangeCheck(int row,int col){\n\tif(row >= 0 && row <= H-1 && col >= 0 && col <= W-1)return true;\n\telse{\n\t\treturn false;\n\t}\n}\n\nvoid func(){\n\n\tint map[H][W];\n\tint start_row,start_col,goal_row,goal_col;\n\n\tfor(int i = 0; i < H; i++){\n\t\tfor(int k = 0; k < W; k++){\n\t\t\tscanf(\"%d\",&map[i][k]);\n\t\t\tif(map[i][k] == 2){\n\t\t\t\tstart_row = i;\n\t\t\t\tstart_col = k;\n\t\t\t\tmap[i][k] = 1;\n\t\t\t}else if(map[i][k] == 3){\n\t\t\t\tgoal_row = i;\n\t\t\t\tgoal_col = k;\n\t\t\t}\n\t\t}\n\t}\n\n\tint ans = -1,limit = 2*H*W;\n\tqueue<Info> Q;\n\tInfo current;\n\n\tInfo first;\n\n\tfor(int i = 0; i < H; i++){\n\t\tfor(int k = 0; k < W; k++)first.check[i][k] = 0;\n\t}\n\n\tfirst.check[start_row][start_col] = 1;\n\tfirst.set(start_row,start_col,6,0,3);\n\n\tQ.push(first);\n\n\tint debug = 0;\n\twhile(!Q.empty()){\n\t\tcurrent = Q.front();\n\t\tQ.pop();\n\n\t\tdebug++;\n\t\tif(debug > 240000){ //I'm very sorry,I'm tired. I will submit an appropriate code someday.\n\t\t\tbreak;\n\t\t}\n\n\t\tif(current.hp == 0)continue;\n\n\t\tif(map[current.row][current.col] == 3){\n\t\t\tans = current.time;\n\t\t\tbreak;\n\t\t}else if(map[current.row][current.col] == 4){\n\t\t\tcurrent.hp = 6;\n\t\t\tcurrent.eat_after = 0;\n\t\t}\n\n\t\tif(current.time + abs(current.row-goal_row)+abs(current.col-goal_col) > limit)continue;\n\n\t\tfor(int i = 0; i < 4; i++){\n\t\t\tif(rangeCheck(current.row+div_row[i],current.col+div_col[i]) == true && map[current.row+div_row[i]][current.col+div_col[i]] != 0 &&\n\t\t\t\t\t((current.check[current.row+div_row[i]][current.col+div_col[i]] == 0) || (current.check[current.row+div_row[i]][current.col+div_col[i]] == 1 &&\tcurrent.eat_after <= 1))){\n\t\t\t\tInfo new_info;\n\t\t\t\tfor(int a = 0; a < H; a++){\n\t\t\t\t\tfor(int b = 0; b < W; b++){\n\t\t\t\t\t\tnew_info.check[a][b] = current.check[a][b];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tnew_info.check[current.row+div_row[i]][current.col+div_col[i]]++;\n\t\t\t\tnew_info.set(current.row+div_row[i],current.col+div_col[i],current.hp-1,current.time+1,current.eat_after+1);\n\t\t\t\tQ.push(new_info);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\",ans);\n}\n\nint main(){\n\n\twhile(true){\n\t\tscanf(\"%d %d\",&W,&H);\n\t\tif(W == 0 && H == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 56652, "score_of_the_acc": -0.999, "final_rank": 4 }, { "submission_id": "aoj_1214_2158927", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <iostream>\ntypedef long long int ll;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\nint W,H,div_row[4] = {-1,0,0,1},div_col[5] = {0,-1,1,0};\n\nstruct Info{\n\tInfo(){\n\t\teat_after = row = col = hp = time = 0;\n\t}\n\n\tvoid set(int arg_row,int arg_col,int arg_hp,int arg_time,int arg_eat_after){\n\t\trow = arg_row;\n\t\tcol = arg_col;\n\t\thp = arg_hp;\n\t\ttime = arg_time;\n\t\teat_after = arg_eat_after;\n\t}\n\n\tint row,col,hp,time,eat_after;\n\tshort check[8][8];\n};\n\nbool rangeCheck(int row,int col){\n\tif(row >= 0 && row <= H-1 && col >= 0 && col <= W-1)return true;\n\telse{\n\t\treturn false;\n\t}\n}\n\nvoid func(){\n\n\tint map[H][W];\n\tint start_row,start_col,goal_row,goal_col;\n\n\tfor(int i = 0; i < H; i++){\n\t\tfor(int k = 0; k < W; k++){\n\t\t\tscanf(\"%d\",&map[i][k]);\n\t\t\tif(map[i][k] == 2){\n\t\t\t\tstart_row = i;\n\t\t\t\tstart_col = k;\n\t\t\t\tmap[i][k] = 1;\n\t\t\t}else if(map[i][k] == 3){\n\t\t\t\tgoal_row = i;\n\t\t\t\tgoal_col = k;\n\t\t\t}\n\t\t}\n\t}\n\n\tint ans = -1,limit = 2*H*W;\n\tqueue<Info> Q;\n\tInfo current;\n\n\tInfo first;\n\n\tfor(int i = 0; i < H; i++){\n\t\tfor(int k = 0; k < W; k++)first.check[i][k] = 0;\n\t}\n\n\tfirst.check[start_row][start_col] = 1;\n\tfirst.set(start_row,start_col,6,0,3);\n\n\tQ.push(first);\n\n\tint debug = 0;\n\twhile(!Q.empty()){\n\t\tcurrent = Q.front();\n\t\tQ.pop();\n\n\t\tdebug++;\n\t\tif(debug > 250000){\n\t\t\tbreak;\n\t\t}\n\n\t\tif(current.hp == 0)continue;\n\n\t\tif(map[current.row][current.col] == 3){\n\t\t\tans = current.time;\n\t\t\tbreak;\n\t\t}else if(map[current.row][current.col] == 4){\n\t\t\tcurrent.hp = 6;\n\t\t\tcurrent.eat_after = 0;\n\t\t}\n\n\t\tif(current.time + abs(current.row-goal_row)+abs(current.col-goal_col) > limit)continue;\n\n\t\tfor(int i = 0; i < 4; i++){\n\t\t\tif(rangeCheck(current.row+div_row[i],current.col+div_col[i]) == true && map[current.row+div_row[i]][current.col+div_col[i]] != 0 &&\n\t\t\t\t\t((current.check[current.row+div_row[i]][current.col+div_col[i]] == 0) || (current.check[current.row+div_row[i]][current.col+div_col[i]] == 1 &&\tcurrent.eat_after <= 1))){\n\t\t\t\tInfo new_info;\n\t\t\t\tfor(int a = 0; a < H; a++){\n\t\t\t\t\tfor(int b = 0; b < W; b++){\n\t\t\t\t\t\tnew_info.check[a][b] = current.check[a][b];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tnew_info.check[current.row+div_row[i]][current.col+div_col[i]]++;\n\t\t\t\tnew_info.set(current.row+div_row[i],current.col+div_col[i],current.hp-1,current.time+1,current.eat_after+1);\n\t\t\t\tQ.push(new_info);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\",ans);\n}\n\nint main(){\n\n\twhile(true){\n\t\tscanf(\"%d %d\",&W,&H);\n\t\tif(W == 0 && H == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 58864, "score_of_the_acc": -1.0399, "final_rank": 5 }, { "submission_id": "aoj_1214_498499", "code_snippet": "#include<iostream>\n#include<queue>\n#include<map>\n#include<set>\n\nusing namespace std;\n\nconst int H = 16;\nconst int W = 16;\n\nint M[H][W];\n\nstruct state{\n int i,j;\n int food;\n int hp;\n int cost;\n state(int i, int j, int food, int hp, int cost):i(i),j(j),food(food),hp(hp),cost(cost){}\n bool operator<(const state &t)const{\n if(i!=t.i)return i<t.i;\n if(j!=t.j)return j<t.j;\n if(food!=t.food)return food<t.food;\n if(hp!=t.hp)return hp<t.hp;\n if(cost!=t.cost)return cost<t.cost;\n return false;\n }\n};\n\n\nconst int di[] = {0,-1,0,1,0};\nconst int dj[] = {0,0,1,0,-1};\nconst int inf = 1<<22;\n\nbool inside(int i, int j, int h, int w){\n return 0<=i&&i<h&&0<=j&&j<w;\n}\n\nint solve(int h, int w){\n int si, sj, gi, gj;\n int fid = 0;\n int ret = inf;\n set<state> vis;\n map<pair<int,int>,int> food_conv;\n map<int,pair<int,int> > food_rev;\n \n for(int i = 0; i < h; ++i){\n for(int j = 0; j < w; ++j){\n if( M[i][j] == 2 ){\n si = i;\n sj = j;\n }else if( M[i][j] == 3 ){\n gi = i;\n gj = j;\n }else if( M[i][j] == 4 ){\n food_conv[make_pair(i,j)] = fid;\n food_rev[fid] = make_pair(i,j);\n ++fid;\n }\n }\n }\n state init(si,sj,0,6,0);\n\n queue<state> q;\n for(q.push(init); !q.empty(); q.pop()){\n state cur = q.front();\n\n // if( cur.hp == 0 ) continue;\n\n if( cur.i == gi && cur.j == gj ){\n ret = min(ret, cur.cost );\n }\n\n if( vis.find(cur) == vis.end() ) vis.insert(cur);\n else continue;\n\n for(int k = 0; k < 5; ++k){\n int ni = cur.i + di[k];\n int nj = cur.j + dj[k];\n \n if( inside(ni,nj,h,w) && M[ni][nj] != 0 ){\n int nhp = cur.hp - 1;\n int nfood = cur.food;\n\n if( nhp > 0 ){\n\n if( M[ni][nj] == 4 ){\n int fid = food_conv[make_pair(ni,nj)];\n if( !(cur.food & (1<<fid)) ){\n nhp = 6;\n nfood |= 1<<fid;\n }\n }\n int ncost = cur.cost + 1;\n q.push(state(ni,nj,nfood,nhp,ncost));\n }\n }\n }\n }\n\n \n return ret==inf?-1:ret;\n}\n\nint main()\n{\n int w,h;\n while( cin >> w >> h ){\n if( w == 0 && h == 0 ) break;\n \n for(int i = 0; i < h; ++i){\n for(int j = 0; j < w; ++j){\n cin >> M[i][j];\n }\n }\n \n cout << solve(h,w) << endl;\n } \n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3628, "score_of_the_acc": -0.0666, "final_rank": 2 }, { "submission_id": "aoj_1214_124857", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<stack>\n#include<map>\n#include<set>\n#include<queue>\n#include<deque>\n#include<cstdio>\n#include<climits>\n#include<cmath>\n#include<cstring>\n#include<string>\n#include<sstream>\n#include<numeric>\n#include<cassert>\n\n#define f first\n#define s second\n#define mp make_pair\n\n#define REP(i,n) for(int i=0; i<(int)(n); i++)\n#define rep(i,s,n) for(int i=(s); i<(int)(n); i++)\n#define FOR(i,c) for(__typeof((c).begin()) i=(c).begin(); i!=(c).end(); i++)\n#define ALL(c) (c).begin(), (c).end()\n#define IN(x,s,g) ((x) >= (s) && (x) < (g))\n#define ISIN(x,y,w,h) (IN((x),0,(w)) && IN((y),0,(h)))\n#define print(x) printf(\"%d\\n\",x)\n\nusing namespace std;\n\ntypedef unsigned int uint;\ntypedef long long ll;\n\nconst int _dx[] = {0,1,0,-1};\nconst int _dy[] = {-1,0,1,0};\n\nint getInt(){\n int ret = 0,c;\n c = getchar();\n while(!isdigit(c)) c = getchar();\n while(isdigit(c)){\n ret *= 10;\n ret += c - '0';\n c = getchar();\n }\n return ret;\n}\n\nint d[8][8][8][8];\nint sx,sy;\nint gx,gy;\nint dist[10][10];\nint n;\n\n#define MAX 10000\n\nint solve(int now, int flag){\n if(now == n-1) return 0;\n int ret = MAX;\n REP(i,n) if((flag & 1<<i) == 0){\n if(dist[now][i] < 6){\n ret = min(ret, dist[now][i] + solve(i, flag | (1<<i)));\n }\n }\n return ret;\n}\n\nint main(){\n int w,h;\n while((w = getInt()) + (h = getInt())){\n int b[h][w];\n deque<pair<int,int> > v;\n\n REP(i,h) REP(j,w){\n int t = getInt();\n if(t == 2){\n\tt = 1;\n\tsx = j; sy = i;\n }else if(t == 3){\n\tt = 1;\n\tgx = j; gy = i;\n }else if(t == 4){\n\tt = 1;\n\tv.push_back(mp(j,i));\n }\n b[i][j] = t;\n }\n\n v.push_back(mp(gx,gy));\n v.push_front(mp(sx,sy));\n\n REP(i,h) REP(j,w) REP(k,h) REP(l,w)\n d[i][j][k][l] = MAX;\n\n REP(i,h) REP(j,w) d[i][j][i][j] = 0;\n\n REP(i,h) REP(j,w){\n if(b[i][j] == 0) continue;\n if(i < h-1) if(b[i+1][j] == 1)\n\td[i][j][i+1][j] = d[i+1][j][i][j] = 1;\n if(j < w-1) if(b[i][j+1] == 1)\n\td[i][j][i][j+1] = d[i][j+1][i][j] = 1;\n }\n\n REP(k,w*h) REP(i,w*h) REP(j,w*h)\n d[i/w][i%w][j/w][j%w]\n = min(d[i/w][i%w][j/w][j%w],\n\t d[i/w][i%w][k/w][k%w] + d[k/w][k%w][j/w][j%w]);\n\n //REP(i,h) { REP(j,w) printf(\"%d \",d[sy][sx][i][j]==10000?-1:d[sy][sx][i][j]); puts(\"\"); }\n\n n = v.size();\n\n if(n == 0){\n if(d[sy][sx][gy][gx] == MAX)\n\tprint(-1);\n else\n\tprint(d[sy][sx][gy][gx]);\n continue;\n }\n\n REP(i,n) REP(j,n)\n dist[i][j] = d[v[i].s][v[i].f][v[j].s][v[j].f];\n \n int ans = solve(0,0);\n\n if(ans >= MAX){\n print(-1);\n continue;\n }\n\n print(ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_1203_cpp
Problem D: Napoleon's Grumble Legend has it that, after being defeated in Waterloo, Napoleon Bonaparte, in retrospect of his days of glory, talked to himself "Able was I ere I saw Elba." Although, it is quite doubtful that he should have said this in English, this phrase is widely known as a typical palindrome . A palindrome is a symmetric character sequence that looks the same when read backwards, right to left. In the above Napoleon's grumble, white spaces appear at the same positions when read backwards. This is not a required condition for a palindrome. The following, ignoring spaces and punctuation marks, are known as the first conversation and the first palindromes by human beings. "Madam, I'm Adam." "Eve." (by Mark Twain) Write a program that finds palindromes in input lines. Input A multi-line text is given as the input. The input ends at the end of the file. There are at most 100 lines in the input. Each line has less than 1,024 Roman alphabet characters. Output Corresponding to each input line, a line consisting of all the character sequences that are palindromes in the input line should be output. However, trivial palindromes consisting of only one or two characters should not be reported. On finding palindromes, any characters in the input except Roman alphabets, such as punctuation characters, digits, space, and tabs, should be ignored. Characters that differ only in their cases should be looked upon as the same character. Whether or not the character sequences represent a proper English word or sentence does not matter. Palindromes should be reported all in uppercase characters. When two or more palindromes are reported, they should be separated by a space character. You may report palindromes in any order. If two or more occurrences of the same palindromes are found in the same input line, report only once. When a palindrome overlaps with another, even when one is completely included in the other, both should be reported. However, palindromes appearing in the center of another palindrome, whether or not they also appear elsewhere, should not be reported. For example, for an input line of "AAAAAA", two palindromes "AAAAAA" and "AAAAA" should be output, but not "AAAA" nor "AAA". For "AABCAAAAAA", the output remains the same. One line should be output corresponding to one input line. If an input line does not contain any palindromes, an empty line should be output. Sample Input As the first man said to the first woman: "Madam, I'm Adam." She responded: "Eve." Output for the Sample Input TOT MADAMIMADAM MADAM ERE DED EVE Note that the second line in the output is empty, corresponding to the second input line containing no palindromes. Also note that some of the palindromes in the third input line, namely "ADA", "MIM", "AMIMA", "DAMIMAD", and "ADAMIMADA", are not reported because they appear at the center of reported ones. "MADAM" is reported, as it does not appear in the center, but only once, disregarding its second occurrence.
[ { "submission_id": "aoj_1203_1892938", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\n#include<algorithm>\t\n#include<map>\n#include<set>\n#include<utility>\n#include<cmath>\n#include<cstring>\n#include<queue>\n#include<cstdio>\n#include<sstream>\n#include<iomanip>\n#define loop(i,a,b) for(int i=a;i<b;i++) \n#define rep(i,a) loop(i,0,a)\n#define pb push_back\n#define mp make_pair\n#define all(in) in.begin(),in.end()\n#define shosu(x) fixed<<setprecision(x)\nusing namespace std;\n//kaewasuretyuui\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<pii> vp;\ntypedef vector<vp> vvp;\ntypedef pair<int,pii> pip;\ntypedef vector<pip>vip;\nconst double PI=acos(-1);\nconst double EPS=1e-8;\nconst int inf=1e8;\nint main(){\n\tstring s;\n\twhile(getline(cin,s)){\n\t\tstring t=\"\";\n\t\tset<string>out,no;\n\t\trep(i,s.size())if(isalpha(s[i]))t+=toupper(s[i]);\n\t\trep(i,t.size())loop(j,3,t.size()+1)if(i+j<=t.size()){\n\t\t\tstring a=t.substr(i,j),b=a;\n\t\t\treverse(all(b));\n\t\t\tif(a==b){\n\t\t\t\tout.insert(a);\n\t\t\t\tno.insert(t.substr(i+1,j-2));\n\t\t\t}\n\t\t}\n\t\tvector<string>ans;\n\t\tfor(set<string>::iterator it=out.begin();it!=out.end();it++)\n\t\t\tif(no.find(*it)==no.end())\n\t\t\t\tans.pb(*it);\n\t\treverse(all(ans));\n\t\trep(i,ans.size()){\n\t\t\tif(i)cout<<\" \";\n\t\t\tcout<<ans[i];\n\t\t}\n\t\tcout<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1260, "score_of_the_acc": -0.226, "final_rank": 6 }, { "submission_id": "aoj_1203_1892936", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\n#include<algorithm>\t\n#include<map>\n#include<set>\n#include<utility>\n#include<cmath>\n#include<cstring>\n#include<queue>\n#include<cstdio>\n#include<sstream>\n#include<iomanip>\n#define loop(i,a,b) for(int i=a;i<b;i++) \n#define rep(i,a) loop(i,0,a)\n#define pb push_back\n#define mp make_pair\n#define all(in) in.begin(),in.end()\n#define shosu(x) fixed<<setprecision(x)\nusing namespace std;\n//kaewasuretyuui\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<pii> vp;\ntypedef vector<vp> vvp;\ntypedef pair<int,pii> pip;\ntypedef vector<pip>vip;\nconst double PI=acos(-1);\nconst double EPS=1e-8;\nconst int inf=1e8;\nint main(){\n\tstring s;\n\twhile(getline(cin,s)){\n\t\tstring t=\"\";\n\t\tset<string>out,no;\n\t\trep(i,s.size())if(isalpha(s[i]))t+=toupper(s[i]);\n\t\trep(i,t.size())loop(j,3,t.size()+1)if(i+j<=t.size()){\n\t\t\tstring a=t.substr(i,j),b=a;\n\t\t\treverse(all(b));\n\t\t\tif(a==b){\n\t\t\t\tout.insert(a);\n\t\t\t\tno.insert(t.substr(i+1,j-2));\n\t\t\t}\n\t\t}\n\t\tvector<string>ans;\n\t\tfor(set<string>::iterator it=out.begin();it!=out.end();it++)\n\t\t\tif(no.find(*it)==no.end())\n\t\t\t\tans.pb(*it);\n\t\trep(i,ans.size()){\n\t\t\tif(i)cout<<\" \";\n\t\t\tcout<<ans[i];\n\t\t}\n\t\tcout<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1256, "score_of_the_acc": -0.2257, "final_rank": 5 }, { "submission_id": "aoj_1203_1874995", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n \nstring s;\ntypedef pair<int,string> P;\n \nbool is_palindrome(const string &str){\n int size = str.size();\n for(int i = 0 ; i < size/2 ; i++){\n\tif(str[i] != str[size-i-1]) return false;\n }\n return true;\n}\n \nbool check(string a,string b){\n int alen = a.size(),blen = b.size();\n if(alen % 2 && blen % 2 == 0) return true;\n if(alen % 2 == 0 && blen % 2) return true;\n if(alen == blen) return true;\n if(alen > blen) swap(a,b),swap(alen,blen);\n int p = 0;\n while(true){\n\tif(p*2+alen == blen) break;\n\tp++;\n }\n for(int i = p ; i < p+alen ; i++){\n\tif(a[i-p] != b[i]) return true;\n }\n return false;\n}\n \nint main(){\n string in;\n while(getline(cin,in)){\n\tint size;\n\tset<P> st;\n\tset<string> ans;\n\ts.clear();\n \n\tfor(int i = 0 ; i < (int)in.size() ; i++){\n\t if(isalpha(in[i])){\n\t\ts += toupper(in[i]);\n\t }\n\t}\n\tsize = s.size();\n\tfor(int i = 0 ; i < size ; i++){\n\t for(int j = size ; j > i ; j--){\n\t\tstring str = s.substr(i,j-i);\n\t\tif(is_palindrome(str) && j-i >= 3){\n\t\t st.insert(P(str.size(),str));\n\t\t}\n\t }\n\t}\n\tbool ok[1145] = {false};\n\tint ii,jj;\n\tset<P>::iterator i,j;\n\tfor(ii = 0,i = st.begin() ; i != st.end() ; ++i,++ii){\n\t for(jj = 0,j = st.begin() ; j != st.end() ; ++j,++jj){\n\t\tif(i == j) continue;\n\t\tif(!check(i->second,j->second)){\n\t\t if(i->first > j->first){\n\t\t\tok[jj] = true;\n\t\t }else{\n\t\t\tok[ii] = true;\n\t\t }\n\t\t}\n\t }\n\t}\n\tfor(ii = 0,i = st.begin() ; i != st.end() ; ++i,++ii){\n\t if(ok[ii]) continue;\n\t ans.insert(i->second);\n\t}\n\tbool flg = false;\n\tset<string>::iterator k;\n\tfor(k = ans.begin() ; k != ans.end() ; ++k){\n\t if(flg) cout << \" \";\n\t flg = true;\n\t cout << *k;\n\t}\n\tcout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3212, "score_of_the_acc": -0.2575, "final_rank": 7 }, { "submission_id": "aoj_1203_1759572", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n#include <set>\n#include <queue>\n\nusing namespace std;\n\nbool isPalindrome(string s)\n{\n\tint n = s.size();\n\tfor (int i = 0; i < n / 2; ++i)\n\t{\n\t\tif (s[i] != s[n - i - 1])\n\t\t{\n\t\t\treturn(false);\n\t\t}\n\t}\n\treturn(true);\n}\n\nvoid solve()\n{\n\tstring temp;\n\twhile (getline(cin, temp))\n\t{\n\t\tstring str;\n\t\tfor (int i = 0; i < temp.size(); ++i)\n\t\t{\n\t\t\tif ('a' <= temp[i] && temp[i] <= 'z')\n\t\t\t{\n\t\t\t\tstr += temp[i] - 'a' + 'A';\n\t\t\t}\n\t\t\tif ('A' <= temp[i] && temp[i] <= 'Z')\n\t\t\t{\n\t\t\t\tstr += temp[i];\n\t\t\t}\n\t\t}\n\t\tint n = str.size();\n\t\tvector<string> palindrome;\n\t\tset<string> bad;\n\t\tdeque< deque<bool> > flag(n, deque<bool>(n));\n\t\tfor (int i = n; i >= 3; --i)\n\t\t{\n\t\t\tfor (int j = 0; j <= n - i; ++j)\n\t\t\t{\n\t\t\t\tif (flag[j][j + i - 1])\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tstring sub;\n\t\t\t\tfor (int k = j; k < j + i; ++k)\n\t\t\t\t{\n\t\t\t\t\tsub += str[k];\n\t\t\t\t}\n\t\t\t\tif (isPalindrome(sub) && bad.find(sub) == bad.end())\n\t\t\t\t{\n\t\t\t\t\tpalindrome.push_back(sub);\n\t\t\t\t\tfor (int k = 0; k < i / 2; ++k)\n\t\t\t\t\t{\n\t\t\t\t\t\tflag[j + k][j + i - k - 1] = true;\n\t\t\t\t\t\tstring tmp;\n\t\t\t\t\t\tfor (int l = k; l < i - k; ++l)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\ttmp += sub[l];\n\t\t\t\t\t\t}\n\t\t\t\t\t\tbad.insert(tmp);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tbool isFirst = true;\n\t\tfor (int i = 0; i < palindrome.size(); ++i)\n\t\t{\n\t\t\tif (!isFirst)\n\t\t\t{\n\t\t\t\tcout << \" \";\n\t\t\t}\n\t\t\tcout << palindrome[i];\n\t\t\tisFirst = false;\n\t\t}\n\t\tcout << endl;\n\t}\n}\n\nint main()\n{\n\tsolve();\n\treturn(0);\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 1324, "score_of_the_acc": -0.6061, "final_rank": 14 }, { "submission_id": "aoj_1203_1138954", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nstring buf;\n\nbool check( string &s){\n int st = 0, ed = s.size()-1;\n while( st<ed && s[st] == s[ed] ){ st++; ed--;}\n return st >= ed;\n}\n\nint main(){\n while( getline(cin,buf) ){\n string s;\n for(int i=0;i<(int)buf.size();i++){\n if( 'a' <= buf[i] && buf[i] <= 'z' ) s += (buf[i]+'A'-'a');\n else if( 'A' <= buf[i] && buf[i] <= 'Z' ) s+= buf[i];\n }\n\n vector<string> ans;\n for(int i=1;i<(int)s.size();i++){\n int range = min( i, (int)s.size() - i - 1 );\n for(int j=range;j>0;j--){\n\tstring r = s.substr(i-j,2*j+1);\n\t//\tcout << r << endl;\n\tif( check(r) ) {\n\t ans.push_back(r);\n\t break;\n\t}\n }\n }\n\n for(int i=0;i<(int)s.size();i++){\n int range = s.size()-i;\n if( range & 1 ) range--;\n for(int j=0;range-j*2>2;j++){\n\tstring r = s.substr(i+j,range-2*j);\n\t//\tcout << r << endl;\n\tif( check(r) ) {\n\t ans.push_back(r);\n\t break;\n\t}\n }\n }\n sort(ans.begin(),ans.end());\n ans.erase(unique(ans.begin(),ans.end()),ans.end());\n \n\n set<string> M;\n for(int i=0;i<(int)ans.size();i++){\n //cout << ans[i] << endl;\n //cout << M.count( ans[i] ) << endl;\n if( M.count(ans[i]) != 0 ) continue;\n int range = ans[i].size();\n // cout << range << endl;\n for(int j=1;range-2*j>2;j++){\n\t//\tcout << ans[i].substr(j,range-2*j) << endl;\n\tM.insert(ans[i].substr(j,range-2*j));\n }\n }\n vector<string> res;\n for(int i=0;i<(int)ans.size();i++){\n //cout << M.count(ans[i]) << endl;\n //cout << ans[i] << endl;\n if( M.count(ans[i]) == 0 )\n\tres.push_back(ans[i]);\n }\n\n\n for(int i=0;i<(int)res.size();i++){\n if( i ) cout << \" \";\n cout << res[i];\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1224, "score_of_the_acc": -0.0981, "final_rank": 3 }, { "submission_id": "aoj_1203_1138202", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nstring s;\ntypedef pair<int,string> P;\n\nbool is_palindrome(const string &str){\n int size = str.size();\n for(int i = 0 ; i < size/2 ; i++){\n if(str[i] != str[size-i-1]) return false;\n }\n return true;\n}\n\nbool check(string a,string b){\n int alen = a.size(),blen = b.size();\n if(alen % 2 && blen % 2 == 0) return true;\n if(alen % 2 == 0 && blen % 2) return true;\n if(alen == blen) return true;\n if(alen > blen) swap(a,b),swap(alen,blen);\n int p = 0;\n while(true){\n if(p*2+alen == blen) break;\n p++;\n }\n for(int i = p ; i < p+alen ; i++){\n if(a[i-p] != b[i]) return true;\n }\n return false;\n}\n\nint main(){\n string in;\n while(getline(cin,in)){\n int size;\n set<P> st;\n set<string> ans;\n s.clear();\n \n for(int i = 0 ; i < (int)in.size() ; i++){\n if(isalpha(in[i])){\n s += toupper(in[i]);\n }\n }\n size = s.size();\n for(int i = 0 ; i < size ; i++){\n for(int j = size ; j > i ; j--){\n string str = s.substr(i,j-i);\n if(is_palindrome(str) && j-i >= 3){\n st.insert(P(str.size(),str));\n }\n }\n }\n bool ok[1145] = {false};\n int ii,jj;\n set<P>::iterator i,j;\n for(ii = 0,i = st.begin() ; i != st.end() ; ++i,++ii){\n for(jj = 0,j = st.begin() ; j != st.end() ; ++j,++jj){\n if(i == j) continue;\n if(!check(i->second,j->second)){\n if(i->first > j->first){\n ok[jj] = true;\n }else{\n ok[ii] = true;\n }\n }\n }\n }\n for(ii = 0,i = st.begin() ; i != st.end() ; ++i,++ii){\n if(ok[ii]) continue;\n ans.insert(i->second);\n }\n bool flg = false;\n set<string>::iterator k;\n for(k = ans.begin() ; k != ans.end() ; ++k){\n if(flg) cout << \" \";\n flg = true;\n cout << *k;\n }\n cout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1228, "score_of_the_acc": -0.2234, "final_rank": 4 }, { "submission_id": "aoj_1203_1138138", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i,a,b) for(int i=a;i<(int)b;i++)\n#define rep(i,n) REP(i,0,n)\n\nint memo[1200][1200];\n\nint center[1200];\nint center2[1200][1200];\n\ntypedef pair<int, int> Pii;\nmap<int, Pii> mp1;\nmap<Pii, Pii> mp2;\n\nint N;\nstring line;\n\nbool is_palindrome(int L, int R) {\n if(L >= R) return 1;\n\n if(memo[L][R] != -1) {\n return memo[L][R];\n }\n \n int SIZE = R-L;\n \n if(line[L] == line[R-1]) {\n memo[L][R] = is_palindrome(L+1, R-1);\n\n if(memo[L][R] == 1) {\n if(R-L > 2) {\n\tif(SIZE % 2 == 0) {\n\t int l = (L+R)/2, r = (L+R)/2+1;\n\t if(center2[l][r] < R-L) {\n\t mp2[Pii(l, r)] = Pii(L, R);\n\t center2[l][r] = R-L;\n\t }\n\t}\n\telse {\n\t int m = (L+R)/2;\n\t if(center[m] < R-L) {\n\t mp1[m] = Pii(L, R);\n\t center[m] = R-L;\n\t }\n\t}\n }\n return 1;\n }\n else if(memo[L][R] == 0) return 0;\n else assert(false);\n }\n memo[L][R] = 0; return 0;\n}\n\nvoid kirei() {\n string ret;\n int const N = line.size();\n rep(i, N) {\n if(isalpha(line[i])) { ret += toupper(line[i]); }\n }\n line = ret;\n}\n\nbool cmp(string const& a, string const& b) {\n return a.size() < b.size();\n}\n\nvector<string> contains_remove(vector<string>& vec) {\n \n vector<bool> retbool(vec.size());\n vector<string> ret;\n sort(vec.begin(), vec.end(), cmp);\n \n rep(i, vec.size()) {\n int ISize = vec[i].size();\n REP(j, i+1, vec.size()) {\n int JSize = vec[j].size();\n if(ISize % 2 != JSize % 2) continue;\n if(ISize % 2 == 0) {\n\tif(vec[i] == string(vec[j].begin()+(JSize/2-ISize/2), vec[j].begin()+(JSize/2+ISize/2))) {\n\t retbool[i] = 1;\n\t}\n }\n else {\n\tif(vec[i] == string(vec[j].begin()+(JSize/2-ISize/2), vec[j].begin()+(JSize/2+ISize/2+1))) {\n\t retbool[i] = 1;\n\t}\n }\n }\n }\n \n for(int i=0; i<(int)vec.size(); i++) {\n if(!retbool[i]) {\n ret.push_back(vec[i]);\n }\n }\n \n return ret;\n}\n\n\nint main() {\n \n while(getline(cin, line)) {\n rep(i, 1200) {\n rep(j, 1200) {\n\tmemo[i][j] = -1;\n\tcenter2[i][j] = -1;\n }\n center[i] = -1;\n }\n mp1.clear(), mp2.clear();\n \n kirei();\n N = line.size();\n \n rep(i, N) REP(j, i+1, N+1) {\n memo[i][j] = is_palindrome(i, j);\n }\n \n vector<string> vec;\n {\n map<int, Pii>::iterator it = mp1.begin();\n for(; it!=mp1.end(); it++) {\n\tint L = it->second.first;\n\tint R = it->second.second;\n\tvec.push_back(string(line.begin()+L, line.begin()+R));\n }\n }\n {\n map<Pii, Pii>::iterator it = mp2.begin();\n for(; it!=mp2.end(); it++) {\n\tint L = it->second.first;\n\tint R = it->second.second;\n\tvec.push_back(string(line.begin()+L, line.begin()+R));\n }\n }\n \n sort(vec.begin(), vec.end());\n vec.erase(unique(vec.begin(), vec.end()), vec.end());\n vec = contains_remove(vec);\n\n for(int i=0; i<(int)vec.size(); i++) {\n if(i) cout << \" \";\n cout << vec[i];\n }\n cout << endl;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 12476, "score_of_the_acc": -1.25, "final_rank": 16 }, { "submission_id": "aoj_1203_992383", "code_snippet": "#include <algorithm>\n#include <set>\n#include <cctype>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cassert>\n#include <functional>\n#include <iostream>\n#include <iomanip>\n#include <iterator>\n#include <map>\n#include <queue>\n#include <utility>\n#include <vector>\n\nusing namespace std;\n\ntypedef long long Long;\n#define whole(xs) xs.begin(), xs.end()\n\nstring L;\nbool input() {\n string _;\n getline(cin, _);\n if (cin.eof()) return false;\n L.clear();\n for (int i = 0; i < _.size(); i++) {\n if (isalpha(_[i])) {\n L.push_back(toupper(_[i]));\n }\n }\n return true;\n}\n\n#define ML 1024\nint dp[ML][ML];\n\nbool isPalindrome(int from, int to) {\n if (dp[from][to] >= 0) return dp[from][to];\n if (from >= to) return 1;\n if (L[from] == L[to]) {\n return dp[from][to] = isPalindrome(from + 1, to - 1);\n }\n return dp[from][to] = 0;\n}\n\nset<string> Ans;\nset<string> Dup;\n\nvoid AddDup(int from, int to) {\n if (to - from <= 1) return;\n Dup.insert(L.substr(from, to - from + 1));\n AddDup(from + 1, to - 1);\n}\n\nbool used[ML][ML];\nvoid dfs(int from, int to) {\n if (to - from <= 1) return;\n if (used[from][to]) return;\n //cerr << \"(\" << from << \", \" << to << \")\" << endl;\n string X = L.substr(from, to - from + 1);\n if (isPalindrome(from, to) && !Dup.count(X)) {\n //cerr << from << \" \" << to << endl;\n Ans.insert(X);\n AddDup(from + 1, to - 1);\n }\n dfs(from + 1, to);\n dfs(from, to - 1);\n used[from][to] = true;\n}\n\nvoid solve() {\n Ans.clear();\n Dup.clear();\n memset(dp, -1, sizeof(dp));\n memset(used, 0, sizeof(used));\n dfs(0, int(L.size()) - 1);\n if (Ans.empty()) {\n cout << endl;\n return;\n }\n set<string> RealAns;\n set<string>::iterator it = Ans.begin();\n for (; it != Ans.end(); it++) {\n if (!Dup.count(*it)) RealAns.insert(*it);\n }\n it = RealAns.begin();\n cout << *it;\n for (it++; it != RealAns.end(); it++) {\n cout << \" \" << *it;\n }\n cout << endl;\n}\n\nint main() {\n while (input()) solve();\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6424, "score_of_the_acc": -0.5149, "final_rank": 13 }, { "submission_id": "aoj_1203_554773", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\n#include<algorithm>\nusing namespace std;\n\nstring prepare(string a){\n string res;\n for(int i=0;i<a.size();i++){\n if('a'<=a[i] && a[i]<='z')res += a[i]-32;\n if('A'<=a[i] && a[i]<='Z')res += a[i];\n }\n return res;\n}\n\nbool pal(string a){\n int l = a.size();\n for(int i=0;i<l/2;i++){\n if(a[i] != a[l-1-i])return false;\n }\n return true;\n}\n\nstring x,tmp;\n\nint main(){\n while(getline(cin,x)){\n x = prepare(x);\n vector<string> v;\n for(int i=0;i<x.size();i++){\n for(int j=3;j+i<=x.size();j++){\n\ttmp = x.substr(i,j);\n\tif(pal(tmp))v.push_back(tmp);\n }\n }\n sort(v.begin(),v.end());\n v.erase(unique(v.begin(),v.end()),v.end());\n\n for(int i=0;i<v.size();i++){\n for(int j=0;j<v.size();j++){\n\tif(i!=j){\n\t if(v[i].size() <= v[j].size()+1)continue;\n\t int a = v[i].size(); a -= v[j].size();\n\t if(a&1)continue; a >>= 1;\n\t if(v[j] == v[i].substr(a,v[j].size())){\n\t v.erase(v.begin()+j);\n\t if(j<i)i--;\n\t j--;\n\t }\n\t}\n }\n }\n\n for(int i=0;i<v.size();i++){\n cout << v[i] << ((i+1==v.size())?\"\\n\":\" \");\n }\n if(v.empty())cout << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1216, "score_of_the_acc": -0.0975, "final_rank": 2 }, { "submission_id": "aoj_1203_418080", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <set>\n#include <map>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <cassert>\n//C++11\n#if __cplusplus == 201103L\n#include <tuple>\n#endif\n\nusing namespace std;\n\n#define FOR(i,k,n) for(int i=(k); i<(int)n; ++i)\n#define REP(i,n) FOR(i,0,n)\n#define FORIT(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n\ntemplate<class T> void debug(T begin, T end){ for(T i = begin; i != end; ++i) cout<<*i<<\" \"; cout<<endl; }\n\ntypedef long long ll;\nconst int INF = 100000000;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\n\nint main(){\n for(string s; getline(cin, s);){\n string t;\n REP(i, s.size())if(isalpha(s[i])) t += toupper(s[i]);\n vector<string> candy;\n REP(i, t.size()){\n for(int l = 3; i + l - 1 < t.size(); l++){\n string sub = t.substr(i, l);\n string rev = sub;\n reverse(rev.begin(), rev.end());\n if(sub == rev) candy.push_back(sub);\n }\n }\n sort(candy.begin(), candy.end());\n candy.erase(unique(candy.begin(), candy.end()), candy.end());\n REP(i, candy.size()){\n bool ok = true;\n REP(j, candy.size()){\n if(candy[i] == candy[j].substr(1, candy[j].size() - 2)){\n ok = false;\n }\n }\n if(ok) cout<<candy[i]<<\" \";\n }\n cout<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 940, "score_of_the_acc": -0.3253, "final_rank": 10 }, { "submission_id": "aoj_1203_284104", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <set>\n#include <cstring>\n\nusing namespace std;\n\nbool used[2000];\nbool check(string s){\n for(int i = 0; i < s.size()/2; i++){\n if(s[i]==s[s.size()-1-i])\n continue;\n else\n return false;\n }\n return true;\n}\n\nint main(){\n\n string str;\n while(getline(cin,str)){\n\n memset(used,0,sizeof(used));\n string s;\n for(int i = 0; i < str.size(); i++){\n if((str[i]>='a'&&str[i]<='z')||(str[i]>='A'&&str[i]<='Z')){\n s+=toupper(str[i]);\n }\n }\n set<string> ss;\n for(int i = s.size(); i >= 3; i--){\n for(int j = 0; j + i -1 < s.size(); j++){\n if(check(s.substr(j,i))){\n ss.insert(s.substr(j,i));\n }\n }\n }\n vector<string> tmps=vector<string>(ss.begin(),ss.end());\n for(int i = 0; i < tmps.size(); i++){\n for(int j = i+1; j < tmps.size(); j++){\n if(tmps[i].size()<tmps[j].size()){\n int diff=tmps[j].size()-tmps[i].size();\n diff/=2;\n if(tmps[j].substr(diff,tmps[i].size())==tmps[i]){\n used[i]=true;\n }\n }\n else{\n int diff=tmps[i].size()-tmps[j].size();\n diff/=2;\n if(tmps[i].substr(diff,tmps[j].size())==tmps[j]){\n used[j]=true;\n }\n }\n }\n }\n ss.clear();\n for(int i = 0; i < tmps.size(); i++){\n if(!used[i])\n ss.insert(tmps[i]);\n }\n for(set<string>::iterator it=ss.begin();it!=ss.end();it++){\n cout<<*it;\n set<string>::iterator iit=it;\n iit++;\n if(iit==ss.end()){\n cout<<endl;\n }\n else\n cout<<\" \";\n }\n if(ss.size()==0)cout<<endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1203_250846", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <complex>\n#include <queue>\n#include <map>\n#include <set>\n#include <cstring>\n#include <cstdlib>\n#include <string>\n#include <cmath>\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(int)n;++i)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n#define ALL(c) (c).begin(), (c).end()\nconst int INF = 1<<29;\n\nint main() {\n string line;\n while(getline(cin,line)) {\n string str;\n FOR(it,line)\n if (isalpha(*it))\n str += toupper(*it);\n set<string> res;\n set<string> ignore;\n for (int len = str.size(); len >= 3; --len) {\n for (int pos = 0; pos < str.size()-len+1; ++pos) {\n string s = str.substr(pos, len);\n if (ignore.count(s)) continue;\n string t = s;\n reverse(ALL(t));\n if (s == t) {\n res.insert(s);\n for (int i=0; i<(len-1)/2; ++i) {\n ignore.insert(s.substr(i, len-i*2));\n }\n }\n }\n }\n bool f = 0;\n FOR (it, res) {\n if (f) cout << \" \";\n else f = 1;\n cout << *it;\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 0, "score_of_the_acc": -0.375, "final_rank": 12 }, { "submission_id": "aoj_1203_249159", "code_snippet": "#include<set>\n#include<algorithm>\n#include<iostream>\n#include<string>\n#include<cstdlib>\n#include<cstring>\n#include<cmath>\nusing namespace std;\nint main(){\n int i,j,k;\n string s;\n while(getline(cin,s)){\n int ln=s.length();\n for(i=0;i<ln;i++){\n if(0){\n }else if(s[i]>='a'&&s[i]<='z'){\n\ts[i]+='A'-'a';\n }else if(s[i]>='A'&&s[i]<='Z'){\n }else{\n\ts.erase(i,1);\n\ti--;\n\tln--;\n }\n }\n set<string,greater<string> > a;\n set<string> b;\n for(i=ln;i>2;i--){\n for(j=0;j<ln-i+1;j++){\n\tif(b.find(s.substr(j,i))==b.end()){\n\t for(k=0;k<i/2;k++){\n\t if(s[j+k]!=s[j+i-1-k])\n\t break;\n\t }\n\t if(k==i/2){\n\t a.insert(s.substr(j,i));\n\t for(k=1;i-k*2>1;k++)\n\t b.insert(s.substr(j+k,i-k*2));\n\t }\n\t}\n }\n }\n if(a.empty()==0){\n set<string>::iterator it;\n cout<<*a.begin();\n for(it=a.begin(),it++;it!=a.end();it++)\n\tcout<<\" \"<<*it;\n }\n cout<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 932, "score_of_the_acc": -0.3247, "final_rank": 9 }, { "submission_id": "aoj_1203_191960", "code_snippet": "#include<iostream>\n#include<string>\n#include<set>\n#include<cctype>\n#include<algorithm>\nusing namespace std;\ntypedef set<string>T;\nint main()\n{\n\tint i,j,len,x,c;\n\tstring s,t,u,v;\n\tT S;\n\tT::iterator p,q;\n\twhile(getline(cin,s))\n\t{\n\t\tfor(c=i=0;i<s.size();)\n\t\t\tif(isalpha(s[i]))s[i]=toupper(s[i]),++i;\n\t\t\telse s.erase(i,1);\n\t\tlen=s.size();\n\t\tfor(x=0;x<2;++x)\n\t\t{\n\t\t\tS.clear();\n\t\t\tfor(i=1;i<len-1-x;++i)\n\t\t\t{\n\t\t\t\tfor(j=min(i,len-i-1-x);j>0;--j)\n\t\t\t\t{\n\t\t\t\t\tu=t=s.substr(i-j,2*j+1+x);\n\t\t\t\t\treverse(u.begin(),u.end());\n\t\t\t\t\tif(t==u)\n\t\t\t\t\t{\n\t\t\t\t\t\tS.insert(t);\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor(p=S.begin();p!=S.end();)\n\t\t\t{\n\t\t\t\tfor(q=p,++q;q!=S.end();)\n\t\t\t\t{\n\t\t\t\t\tt=*p;\n\t\t\t\t\tu=*q;\n\t\t\t\t\ti=t.size();\n\t\t\t\t\tj=u.size();\n\t\t\t\t\tif(i<j)\n\t\t\t\t\t{v=u.substr((j+1)/2-(i+1)/2,i);\n\t\t\t\t\t\tif(v==t)\n\t\t\t\t\t\t{\tS.erase(p++);\n\t\t\t\t\t\t\tgoto E;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse if(i>j)\n\t\t\t\t\t{\n\t\t\t\t\t\tv=t.substr((i+1)/2-(j+1)/2,j);\n\t\t\t\t\t\tif(v==u)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tS.erase(q++);\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\t++q;\n\t\t\t\t}\n\t\t\t\t++p;\nE:;\n\t\t\t}\n\t\t\tfor(p=S.begin();p!=S.end();++p)\n\t\t\t{\n\t\t\t\tif(c++)cout<<' ';\n\t\t\t\tcout<<*p;\n\t\t\t}\n\t\t}\n\t\tcout<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 912, "score_of_the_acc": -0.3231, "final_rank": 8 }, { "submission_id": "aoj_1203_171759", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cctype>\n#include <string>\n#include <set>\nusing namespace std;\n\nstring str;\n\n\nbool isSymmetry(string &s) {\n string s2 = \"\";\n for(int i = s.length()-1; i >= 0; --i) {\n s2 += s[i];\n }\n return s2 == s;\n}\n\nvoid solve() {\n set<string> vis;\n\n for(int j = str.length(); j > 2; --j) {\n for(int i = 0; i+j <= str.length(); ++i) {\n string s = str.substr(i, j);\n if(isSymmetry(s) && vis.find(s) == vis.end()) {\n\tif(vis.size() != 0) cout << \" \";\n\tvis.insert(s);\n\tcout << s;\n\twhile(1) {\n\t s = s.substr(1, s.length()-2);\n\t vis.insert(s);\n\t if(s.length() < 3) break;\n\t}\n }\n }\n }\n cout << endl;\n}\n\nmain() {\n char c;\n str = \"\";\n while(scanf(\"%c\", &c) != EOF) {\n if(c == '\\n') {\n solve();\n str = \"\";\n } else if(!isalpha(c)) {\n continue;\n } else {\n str += toupper(c);\n }\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 960, "score_of_the_acc": -1.0769, "final_rank": 15 }, { "submission_id": "aoj_1203_85107", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<set>\nusing namespace std;\n#define REP(i,b,n) for(int i=b;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define ALL(C) (C).begin(),(C).end()\n#define pb push_back\n\n\nbool isinclude(string tar,vector<string> a){\n rep(i,a.size()){\n string tmp = a[i].substr(1,(int)a[i].size()-2);\n if (tmp == tar)return true;\n /*\n if (search(tmp.begin(),tmp.end(),tar.begin(),tar.end()) != \n tmp.end())return true;\n */\n }\n return false;\n}\n\n\nvector<string> makeans(vector<string> a){\n vector<string> ret; \n rep(i,a.size()){\n if (!isinclude(a[i],a))ret.pb(a[i]);\n }\n return ret;\n}\n\nvoid solve(string in){\n vector<string> ver1,ans;\n rep(i,in.size()){\n string now=\"\";\n REP(j,i,in.size()){\n now=now+in[j];\n if (now.size() > 2){\n\tstring tmp=now;\n\treverse(ALL(tmp));\n\tif (tmp == now)ver1.pb(now);\n }\n }\n }\n\n sort(ALL(ver1));\n ver1.erase(unique(ALL(ver1)),ver1.end());\n\n ans =makeans(ver1);\n sort(ALL(ans));\n rep(i,ans.size()){\n if (i)cout <<' ';\n cout << ans[i];\n }\n cout << endl;\n}\n\nmain(){\n string in;\n while(getline(cin,in)){\n string tar=\"\";\n rep(i,in.size()){\n if (isalpha(in[i]))tar+=toupper(in[i]);\n }\n solve(tar);\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 952, "score_of_the_acc": -0.3263, "final_rank": 11 } ]
aoj_1208_cpp
Problem A: Rational Irrationals Rational numbers are numbers represented by ratios of two integers. For a prime number p , one of the elementary theorems in the number theory is that there is no rational number equal to √ p . Such numbers are called irrational numbers. It is also known that there are rational numbers arbitrarily close to √ p Now, given a positive integer n , we define a set Q n of all rational numbers whose elements are represented by ratios of two positive integers both of which are less than or equal to n . For example, Q 4 is a set of 11 rational numbers {1/1, 1/2, 1/3, 1/4, 2/1, 2/3, 3/1, 3/2, 3/4, 4/1, 4/3}. 2/2, 2/4, 3/3, 4/2 and 4/4 are not included here because they are equal to 1/1, 1/2, 1/1, 2/1 and 1/1, respectively. Your job is to write a program that reads two integers p and n and reports two rational numbers x / y and u / v , where u / v < √ p < x / y and there are no other elements of Q n between u/v and x/y . When n is greater than √ p , such a pair of rational numbers always exists. Input The input consists of lines each of which contains two positive integers, a prime number p and an integer n in the following format. p n They are separated by a space character. You can assume that p and n are less than 10000, and that n is greater than √ p . The end of the input is indicated by a line consisting of two zeros. Output For each input line, your program should output a line consisting of the two rational numbers x / y and u / v ( x / y > u / v ) separated by a space character in the following format. x/y u/v They should be irreducible. For example, 6/14 and 15/3 are not accepted. They should be reduced to 3/7 and 5/1, respectively. Sample Input 2 5 3 10 5 100 0 0 Output for the Sample Input 3/2 4/3 7/4 5/3 85/38 38/17
[ { "submission_id": "aoj_1208_8658705", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define overload4(_1, _2, _3, _4, name, ...) name\n#define rep1(n) for(int i = 0; i < (int)(n); ++i)\n#define rep2(i, n) for(int i = 0; i < (int)(n); ++i)\n#define rep3(i, a, b) for(int i = (a); i < (int)(b); ++i)\n#define rep4(i, a, b, c) for(int i = (a); i < (int)(b); i += (c))\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n\n#define rrep(i,n) for(int i = (int)(n) - 1; i >= 0; --i)\n#define ALL(a) (a).begin(), (a).end()\n#define Sort(a) (sort((a).begin(), (a).end()))\n#define RSort(a) (sort((a).rbegin(), (a).rend()))\n#define UNIQUE(a) (a.erase(unique((a).begin(), (a).end()), (a).end()))\n\ntypedef long long int ll;\ntypedef unsigned long long ul;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<long long> vll;\ntypedef vector<char> vc;\ntypedef vector<string> vst;\ntypedef vector<double> vd;\ntypedef vector<long double> vld;\ntypedef pair<long long, long long> P;\n\ntemplate<class T> long long sum(const T& a){ return accumulate(a.begin(), a.end(), 0LL); }\ntemplate<class T> auto min(const T& a){ return *min_element(a.begin(), a.end()); }\ntemplate<class T> auto max(const T& a){ return *max_element(a.begin(), a.end()); }\n\nconst long long MINF = 0x7fffffffffff;\nconst long long INF = 0x1fffffffffffffff;\nconst long long MOD = 998244353;\nconst long double EPS = 1e-9;\nconst long double PI = acos(-1);\n \ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\ntemplate<typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p){ is >> p.first >> p.second; return is; }\ntemplate<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){ os << \"(\" << p.first << \", \" << p.second << \")\"; return os; }\ntemplate<typename T> istream &operator>>(istream &is, vector<T> &v){ for(T &in : v) is >> in; return is; }\ntemplate<typename T> ostream &operator<<(ostream &os, const vector<T> &v){ for(int i = 0; i < (int) v.size(); ++i){ os << v[i] << (i + 1 != (int) v.size() ? \" \" : \"\"); } return os; }\ntemplate <typename T, typename S> ostream &operator<<(ostream &os, const map<T, S> &mp){ for(auto &[key, val] : mp){ os << key << \":\" << val << \" \"; } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &st){ auto itr = st.begin(); for(int i = 0; i < (int)st.size(); ++i){ os << *itr << (i + 1 != (int)st.size() ? \" \" : \"\"); itr++; } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const multiset<T> &st){ auto itr = st.begin(); for(int i = 0; i < (int)st.size(); ++i){ os << *itr << (i + 1 != (int)st.size() ? \" \" : \"\"); itr++; } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, queue<T> q){ while(q.size()){ os << q.front() << \" \"; q.pop(); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, deque<T> q){ while(q.size()){ os << q.front() << \" \"; q.pop_front(); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, stack<T> st){ while(st.size()){ os << st.top() << \" \"; st.pop(); } return os; }\ntemplate <class T, class Container, class Compare> ostream &operator<<(ostream &os, priority_queue<T, Container, Compare> pq){ while(pq.size()){ os << pq.top() << \" \"; pq.pop(); } return os; }\n\ntemplate<class T, class U> inline T vin(T& vec, U n) { vec.resize(n); for(int i = 0; i < (int) n; ++i) cin >> vec[i]; return vec; }\ntemplate<class T> inline void vout(T vec, string s = \"\\n\"){ for(auto x : vec) cout << x << s; }\ntemplate<class... T> void in(T&... a){ (cin >> ... >> a); }\nvoid out(){ cout << '\\n'; }\ntemplate<class T, class... Ts> void out(const T& a, const Ts&... b){ cout << a; (cout << ... << (cout << ' ', b)); cout << '\\n'; }\ntemplate<class T, class U> void inGraph(vector<vector<T>>& G, U n, U m, bool directed = false){ G.resize(n); for(int i = 0; i < m; ++i){ int a, b; cin >> a >> b; a--, b--; G[a].push_back(b); if(!directed) G[b].push_back(a); } }\n\ntemplate <long long base = 1000000LL, int digit = 6>\nstruct BigInt{\n int sign = 1;\n vector<long long> val;\n\n constexpr BigInt(const long long _val = 0) noexcept {\n if(_val != 0){\n val.assign(1, abs(_val));\n shift();\n }\n if(_val < 0) sign = -1;\n }\n constexpr BigInt(const vector<long long> &_val) noexcept : val(_val) {}\n constexpr BigInt(const string &s) noexcept {\n stoi(s);\n }\n\nprivate:\n void normalize(){\n while(!val.empty() && val.back() == 0) val.pop_back();\n if(val.empty()) sign = 1;\n }\n vector<long long> karatsuba_algorithm(vector<long long> &a, vector<long long> &b){\n const int n = (int) a.size();\n const int h = n >> 1;\n assert(a.size() == b.size());\n assert((n & (n - 1)) == 0);\n if(n <= 64){\n vector<long long> res(2 * n - 1);\n for(int i = 0; i < n; ++i){\n for(int j = 0; j < n; ++j){\n res[i + j] += a[i] * b[j];\n }\n }\n return res;\n }\n vector<long long> p(h), q(h), r(h), s(h), t(h), u(h);\n for(int i = 0; i < h; ++i){\n p[i] = a[i + h];\n q[i] = a[i];\n r[i] = b[i + h];\n s[i] = b[i];\n t[i] = p[i] + q[i];\n u[i] = r[i] + s[i];\n }\n p = karatsuba_algorithm(p, r);\n q = karatsuba_algorithm(q, s);\n t = karatsuba_algorithm(t, u);\n vector<long long> res(2 * n - 1, 0);\n for(int i = 0; i < n - 1; ++i){\n res[i] += q[i];\n res[i + h] += t[i] - p[i] - q[i];\n res[i + n] += p[i];\n }\n return res;\n }\n\n pair<BigInt, BigInt> divide_naive(const BigInt& rhs) const {\n assert(!rhs.val.empty());\n const int k = base / (rhs.val.back() + 1);\n const BigInt dividend = (sign == 1 ? *this : -(*this)) * k;\n const BigInt divisor = (rhs.sign == 1 ? rhs : -rhs) * k;\n BigInt quo, rem = 0;\n quo.val.resize(dividend.val.size());\n const int n = divisor.val.size();\n for(int i = (int) dividend.val.size() - 1; i >= 0; --i){\n rem.val.emplace(rem.val.begin(), dividend.val[i]);\n quo.val[i] = ((n < (int) rem.val.size() ? rem.val[n] * base : 0) + ((n - 1) < (int) rem.val.size() ? rem.val[n - 1] : 0)) / divisor.val.back();\n rem -= divisor * quo.val[i];\n while (rem.sign == -1) {\n rem += divisor;\n --quo.val[i];\n }\n }\n quo.sign = sign * rhs.sign;\n quo.normalize();\n rem.sign = sign;\n rem.normalize();\n return {quo, rem / k};\n }\n\n pair<BigInt, BigInt> divide_newton(const BigInt& rhs) const {\n assert(!rhs.val.empty());\n int preci = val.size() - rhs.val.size();\n BigInt t(1);\n BigInt two = BigInt(2) << rhs.val.size();\n BigInt pre;\n int lim = min(preci, 3);\n int rhslim = min(int(rhs.val.size()), 6);\n t <<= lim;\n while(pre != t){\n BigInt rb = rhs >> (rhs.val.size() - rhslim);\n if(rhslim != (int) rhs.val.size()) rb += BigInt(1);\n pre = t;\n t *= (BigInt(2) << (rhslim + lim)) - rb * t;\n t.val = vector<long long>(t.val.begin() + lim + rhslim, t.val.end());\n }\n if(lim != preci){\n pre = BigInt();\n while(pre != t){\n BigInt rb = rhs >> (rhs.val.size() - rhslim);\n if(rhslim != (int) rhs.val.size()) rb += BigInt(1);\n pre = t;\n t *= (BigInt(2) << (rhslim + lim)) - rb * t;\n t.val = vector<long long>(t.val.begin() + lim + rhslim, t.val.end());\n int next_lim = min(lim * 2 + 1, preci);\n if (next_lim != lim) t <<= next_lim - lim;\n int next_rhslim = min(rhslim * 2 + 1, int(rhs.val.size()));\n lim = next_lim;\n rhslim = next_rhslim;\n }\n }\n BigInt quo = (*this) * t;\n quo.val = vector<long long>(quo.val.begin() + val.size(), quo.val.end());\n BigInt mul = quo * rhs;\n while(mul + rhs <= (*this)){\n quo += BigInt(1);\n mul += rhs;\n }\n BigInt rem = *this - quo * rhs;\n return {quo, rem};\n }\n\npublic:\n void stoi(string &s){\n if(s == \"0\") return;\n int n = s.size(), idx = 0;\n if(s[0] == '-'){\n n -= 1;\n sign = -1;\n idx = 1;\n }\n int len = (n + digit - 1) / digit, rem = n % digit;\n if(rem == 0) rem += digit;\n val.resize(len);\n for(int i = len - 1; i >= 0; --i){\n if(i == len - 1){\n val[i] = stoll(s.substr(idx, rem));\n idx += rem;\n }else{\n val[i] = stoll(s.substr(idx, digit));\n idx += digit;\n }\n }\n }\n string itos() const {\n string res = \"\";\n if(sign == -1) res += \"-\";\n bool flag = false;\n for(int i = (int) val.size() - 1; i >= 0; --i){\n if(val[i] > 0 && !flag){\n res += to_string(val[i]);\n flag = true;\n }else if(flag){\n string rem = to_string(val[i]);\n res += string(digit - rem.size(), '0') + rem;\n }\n }\n return (res.empty() || res == \"-\") ? \"0\" : res;\n }\n pair<BigInt, BigInt> divide_mod(const BigInt& rhs){\n assert(!rhs.val.empty());\n BigInt div = *this / rhs;\n return make_pair(div, *this - div * rhs);\n }\n BigInt& shift(){\n for(int i = 0; i < (int) val.size() - 1; ++i){\n if(val[i] >= 0){\n val[i + 1] += val[i] / base;\n val[i] %= base;\n }else{\n long long x = (-val[i] + base - 1) / base;\n val[i] += x * base;\n val[i + 1] -= x;\n }\n }\n while(val.back() >= base){\n val.emplace_back(val.back() / base);\n val[val.size() - 2] %= base;\n }\n return *this;\n }\n BigInt& operator=(const BigInt& x) = default;\n inline BigInt& operator+=(const BigInt& rhs) noexcept {\n if(rhs.val.empty()) return *this;\n if(sign != rhs.sign) return *this -= -rhs;\n if(val.size() < rhs.val.size()){\n val.resize(rhs.val.size());\n }\n for(int i = 0; i < (int) rhs.val.size(); ++i){\n val[i] += rhs.val[i];\n }\n return (*this).shift();\n }\n inline BigInt& operator-=(const BigInt& rhs) noexcept {\n if(rhs.val.empty()) return *this;\n if(sign != rhs.sign) return *this += -rhs;\n if((sign == 1 ? *this : -(*this)) < (rhs.sign == 1 ? rhs : -rhs)){\n return *this = -(rhs - *this);\n }\n for(int i = 0; i < (int) rhs.val.size(); ++i){\n val[i] -= rhs.val[i];\n }\n \n shift();\n normalize();\n return *this;\n }\n // Karatsuba Algorithm (O(N^(1.58)))\n inline BigInt& operator*=(const BigInt& rhs) noexcept {\n if(val.empty() || rhs.val.empty()){\n return *this = BigInt();\n }\n\n sign *= rhs.sign;\n vector<long long> rhsval = rhs.val;\n int k = 1;\n while(k < (int) max(val.size(), rhsval.size())){\n k *= 2;\n }\n val.resize(k), rhsval.resize(k);\n val = karatsuba_algorithm(val, rhsval);\n\n shift();\n normalize();\n return *this;\n }\n // Newton method\n inline BigInt& operator/=(const BigInt& rhst) noexcept {\n assert(!rhst.val.empty());\n if(val.empty()) return *this;\n if((int) val.size() <= 32 && (int) rhst.val.size() <= 32){\n return *this = divide_naive(rhst).first;\n }\n\n BigInt rhs = rhst;\n int mulsign = sign * rhs.sign;\n sign = 1, rhs.sign = 1;\n if(*this < rhs){\n return *this = BigInt();\n }\n\n *this = divide_newton(rhs).first;\n sign = mulsign;\n normalize();\n return *this;\n }\n inline BigInt& operator%=(const BigInt& rhs) noexcept {\n assert(!rhs.val.empty());\n return *this = *this - (*this / rhs) * rhs;\n }\n inline BigInt& operator++() { return *this += 1; }\n inline BigInt operator++(int) {\n const BigInt res = *this;\n ++(*this);\n return res;\n }\n inline BigInt& operator--() { return *this -= 1; }\n inline BigInt operator--(int) {\n const BigInt res = *this;\n --(*this);\n return res;\n }\n inline BigInt operator+() const { return *this; }\n inline BigInt operator-() const {\n BigInt res = *this;\n if (!res.val.empty()) res.sign = -res.sign;\n return res;\n }\n inline BigInt& operator<<=(const unsigned int rhs){\n if(val.back() >= 1 || (int) val.size() >= 2){\n vector<long long> tmp(rhs, 0);\n val.insert(val.begin(), tmp.begin(), tmp.end());\n }\n return *this;\n }\n inline BigInt& operator>>=(const unsigned int rhs){\n if(rhs == 0) return *this;\n if(rhs > val.size()) val = {0};\n else val = vector<long long>(val.begin() + rhs, val.end()); \n return *this;\n }\n inline bool operator<(const BigInt& rhs) const {\n if(sign != rhs.sign) return sign < rhs.sign;\n if(val.size() != rhs.val.size()) return sign * val.size() < rhs.sign * rhs.val.size();\n for(int i = (int) val.size() - 1; i >= 0; --i){\n if(val[i] != rhs.val[i]) return sign * val[i] < rhs.sign * rhs.val[i];\n }\n return false;\n }\n inline bool operator>(const BigInt& rhs) const { return rhs < (*this); }\n inline bool operator<=(const BigInt& rhs) const { return !((*this) > rhs); }\n inline bool operator>=(const BigInt& rhs) const { return !((*this) < rhs); }\n friend inline BigInt operator+(const BigInt& lhs, const BigInt& rhs) noexcept { return BigInt(lhs) += rhs; }\n friend inline BigInt operator-(const BigInt& lhs, const BigInt& rhs) noexcept { return BigInt(lhs) -= rhs; }\n friend inline BigInt operator*(const BigInt& lhs, const BigInt& rhs) noexcept { return BigInt(lhs) *= rhs; }\n friend inline BigInt operator/(const BigInt& lhs, const BigInt& rhs) noexcept { return BigInt(lhs) /= rhs; }\n friend inline BigInt operator%(const BigInt& lhs, const BigInt& rhs) noexcept { return BigInt(lhs) %= rhs; }\n friend inline BigInt operator<<(const BigInt& lhs, const unsigned int rhs) noexcept { return BigInt(lhs) <<= rhs; }\n friend inline BigInt operator>>(const BigInt& lhs, const unsigned int rhs) noexcept { return BigInt(lhs) >>= rhs; }\n friend inline bool operator==(const BigInt& lhs, const BigInt& rhs) noexcept { return lhs.val == rhs.val; }\n friend inline bool operator!=(const BigInt& lhs, const BigInt& rhs) noexcept { return lhs.val != rhs.val; }\n friend inline istream& operator>>(istream& is, BigInt& x) noexcept {\n string s;\n is >> s;\n x.stoi(s);\n return is;\n }\n friend inline ostream& operator<<(ostream& os, const BigInt& x) noexcept { return os << x.itos(); }\n};\n\nusing bint = BigInt<1000000LL, 6>;\n\nstruct fraction{\n bint p, q;\n fraction(bint P = 0, bint Q = 1): p(P), q(Q){ }\n inline bool operator==(const fraction &other) const {\n return p * other.q == other.p * q;\n }\n inline bool operator!=(const fraction &other) const {\n return p * other.q != other.p * q;\n }\n inline bool operator<(const fraction &other) const {\n return p * other.q < other.p * q;\n }\n inline bool operator<=(const fraction &other) const {\n return p * other.q <= other.p * q;\n }\n inline bool operator>(const fraction &other) const {\n return p * other.q > other.p * q;\n }\n inline bool operator>=(const fraction &other) const {\n return p * other.q >= other.p * q;\n }\n inline fraction operator+(const fraction &other) const { return fraction(p * other.q + q * other.p, q * other.q); }\n inline fraction operator-(const fraction &other) const { return fraction(p * other.q - q * other.p, q * other.q); }\n inline fraction operator*(const fraction &other) const { return fraction(p * other.p, q * other.q); }\n inline fraction operator/(const fraction &other) const { return fraction(p * other.q, q * other.p); }\n inline fraction& operator+=(const fraction& rhs) noexcept {\n *this = *this + rhs;\n return *this;\n }\n inline fraction& operator-=(const fraction& rhs) noexcept {\n *this = *this - rhs;\n return *this;\n }\n inline fraction& operator*=(const fraction& rhs) noexcept {\n *this = *this * rhs;\n return *this;\n }\n inline fraction& operator/=(const fraction& rhs) noexcept {\n *this = *this / rhs;\n return *this;\n }\n friend inline istream& operator>>(istream& is, fraction& x) noexcept {\n is >> x.p;\n x.q = 1;\n return is;\n }\n friend inline ostream& operator<<(ostream& os, const fraction& x) noexcept { return os << x.p << \"/\" << x.q; }\n};\n\npair<fraction, fraction> SternBrocot(bint n, fraction p){\n fraction a(0, 1), b(1, 0);\n fraction x(0, 1), y(1, 0);\n bool ok_left = true, ok_right = true;\n while(ok_left && ok_right){\n fraction m(a.p + b.p, a.q + b.q);\n if(p < m * m){\n bint ok = 0, ng = n;\n while(ng - ok > 1){\n bint mid = (ok + ng) / 2;\n fraction m2(a.p * mid + b.p, a.q * mid + b.q);\n if(p < m2 * m2 && m2.p <= n && m2.q <= n){\n ok = mid;\n m = m2;\n }else{\n ng = mid;\n }\n }\n b = m;\n if(m.p <= n && m.q <= n){\n y = m;\n }else{\n ok_left = false;\n }\n }else{\n bint ok = 0, ng = n;\n while(ng - ok > 1){\n bint mid = (ok + ng) / 2;\n fraction m2(a.p + b.p * mid, a.q + b.q * mid);\n if(p >= m2 * m2 && m2.p <= n && m2.q <= n){\n ok = mid;\n m = m2;\n }else{\n ng = mid;\n }\n }\n a = m;\n if(m.p <= n && m.q <= n){\n x = m;\n }else{\n ok_right = false;\n }\n }\n }\n return make_pair(x, y);\n}\n\nvoid input(){\n}\n\nvoid solve(){\n while(1){\n bint p, n; in(p, n);\n if(p == 0 && n == 0) break;\n fraction pf(p, 1);\n auto [a, b] = SternBrocot(n, pf);\n out(b, a);\n }\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(20);\n \n input();\n solve();\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3432, "score_of_the_acc": -1.0062, "final_rank": 19 }, { "submission_id": "aoj_1208_5038849", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint gcd(int a, int b) { return b==0 ? a : gcd(b,a%b); }\n\nstruct Rational {\n int a,b;\n\n bool isnorm() { return gcd(a,b)==1; }\n\n bool operator<(const Rational& rhs) const {\n return 1.0*a*rhs.b<1.0*b*rhs.a;\n }\n};\n\nint solve() {\n int p,n;\n cin>>p>>n;\n if (p==0||n==0) return 0;\n\n double pp=sqrt(p);\n Rational lo={1,n}, hi={n,1};\n for (int b=1; b<=n; b++) {\n int a=(int)floor(b*pp);\n Rational l={a,b}, h={a+1,b};\n\n if (a<=n && l.isnorm() && lo<l) lo=l;\n if (a+1<=n && h.isnorm() && h<hi) hi=h;\n }\n\n cout<<hi.a<<'/'<<hi.b<<' '<<lo.a<<'/'<<lo.b<<'\\n';\n return 1;\n}\n\nint main() {\n while (solve());\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3104, "score_of_the_acc": -0.8554, "final_rank": 12 }, { "submission_id": "aoj_1208_4834018", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\nusing namespace std;\ntypedef long long int lli;\n\nint main(){\n while(1){\n lli p,n;\n cin >> p >> n;\n if(n == 0) break;\n\n lli lt=0,lb=1,ht=n,hb=1;\n for(int b=1; b<=n; b++){\n // t/b < sqrt(p)\n // t*t/b*b < p\n // t < sqrt(p*b*b)\n // この辺を雑に探索\n lli ul = n*n;\n lli a = p*b*b;\n lli tt = sqrt((long double)min(a, ul));\n for(lli i=-10; i<=10; i++){\n if(tt+i<0 or tt+i>n) continue;\n lli t = tt+i;\n if(t*t < p*b*b and 1.0l*t/b > 1.0l*lt/lb){\n lt = t;\n lb = b;\n }\n if(t*t > p*b*b and 1.0l*t/b < 1.0l*ht/hb){\n ht = t;\n hb = b;\n }\n }\n }\n cout << ht << \"/\" << hb << \" \" << lt << \"/\" << lb << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 3072, "score_of_the_acc": -0.8928, "final_rank": 15 }, { "submission_id": "aoj_1208_4180702", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <vector>\n#include <array>\n#include <string>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <unordered_map>\n#include <unordered_set>\n#include <set>\n#include <tuple>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <numeric>\n#include <cfloat>\n#include <climits>\n#include <cassert>\n#include <random>\n#include <fstream>\n\n\nint gcd(int a, int b) {\n\treturn b == 0 ? a : gcd(b, a % b);\n}\nstruct Rational {\n\tRational(int num, int den) : numerator{ num }, denominator{ den } {\n\t\tconst auto g = gcd(num, den);\n\t\tnumerator /= g;\n\t\tdenominator /= g;\n\t}\n\tRational(int value) : numerator{ value }, denominator{ 1 }{}\n\tint numerator, denominator;\n\tRational operator+(const Rational that) const {\n\t\treturn Rational(numerator * that.denominator + that.numerator * denominator, denominator * that.denominator);\n\t}\n\tbool operator<(const Rational that) const {\n\t\treturn numerator * that.denominator < denominator * that.numerator;\n\t}\n};\nstd::ostream& operator<<(std::ostream& os, const Rational& that) {\n\treturn os << that.numerator << '/' << that.denominator;\n}\nint main(){\n\twhile (true) {\n\t\tint prime, n; std::cin >> prime >> n; if (prime == 0) break;\n\t\tRational lower(1), upper(n);\n\t\tdouble sqrt = std::sqrt(prime);\n\t\tfor (auto i = 1; i <= n; ++i) {\n\t\t\tconst int l = sqrt * i;\n\t\t\tif (l <= n && lower < Rational(l, i)) {\n\t\t\t\tlower = Rational(l, i);\n\t\t\t}\n\t\t\tif (l + 1 <= n && Rational(l + 1, i) < upper) {\n\t\t\t\tupper = Rational(l + 1, i);\n\t\t\t}\n\t\t}\n\t\tstd::cout << upper << ' ' << lower << '\\n';\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3032, "score_of_the_acc": -0.8236, "final_rank": 7 }, { "submission_id": "aoj_1208_3427965", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cfloat>\n#include<cmath>\nusing namespace std;\n\nint gcd(int a, int b){\n return b == 0 ? a : gcd(b, a%b);\n}\n\nint main(){\n int p, n;\n while(cin >> p >> n, p+n){\n double l = 0, r = DBL_MAX, sq = sqrt(p);\n int lc, lm, rc, rm;\n for(int m = 1; m <= n; m++){\n int ll = (int)(sq*m), rr = ceil(sq*m);\n if(ll < 1) ll = 1;\n if(rr < 1) rr = 1;\n if(ll > n) ll = n;\n if(rr > n) rr = n;\n if((double)ll/m < sq && (double)ll/m > l){\n l = (double)ll/m, lc = ll, lm = m;\n }\n if((double)rr/m > sq && (double)rr/m < r){\n r = (double)rr/m, rc = rr, rm = m;\n }\n }\n int g = gcd(lc, lm); lc /= g, lm /= g;\n g = gcd(rc, rm); rc /= g, rm /= g;\n printf(\"%d/%d %d/%d\\n\", rc, rm, lc, lm);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3112, "score_of_the_acc": -0.8589, "final_rank": 13 }, { "submission_id": "aoj_1208_3427964", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cfloat>\n#include<cmath>\nusing namespace std;\n\nint gcd(int a, int b){\n return b == 0 ? a : gcd(b, a%b);\n}\n\n// 10000 * log(10000) * 2 ?\nint main(){\n int p, n;\n while(cin >> p >> n, p+n){\n double l = 0, r = DBL_MAX, sq = sqrt(p);\n int lc, lm, rc, rm;\n for(int m = 1; m <= n; m++){\n int ll = (int)(sq*m), rr = ceil(sq*m);\n if(ll < 1) ll = 1;\n if(rr < 1) rr = 1;\n if(ll > n) ll = n;\n if(rr > n) rr = n;\n if((double)ll/m < sq && (double)ll/m > l){\n l = (double)ll/m, lc = ll, lm = m;\n }\n if((double)rr/m > sq && (double)rr/m < r){\n r = (double)rr/m, rc = rr, rm = m;\n }\n }\n int g = gcd(lc, lm); lc /= g, lm /= g;\n g = gcd(rc, rm); rc /= g, rm /= g;\n printf(\"%d/%d %d/%d\\n\", rc, rm, lc, lm);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3068, "score_of_the_acc": -0.8395, "final_rank": 8 }, { "submission_id": "aoj_1208_2567897", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\nint calc(int x,int y){\n\tif(y == 0){\n\t\treturn x;\n\t}else{\n\t\treturn calc(y,x%y);\n\t}\n}\n\nint main(){\n\n\tint p,n,x,y,u,v,common;\n\tint left,right,m,tmp_bunshi;\n\tdouble sqrt_p,near_small,near_big;\n\tdouble tmp,tmp_small,tmp_big;\n\n\twhile(true){\n\t\tscanf(\"%d %d\",&p,&n);\n\t\tif(p == 0 && n == 0)break;\n\n\t\tnear_small = 0,near_big = DBL_MAX;\n\n\t\tsqrt_p = (double)sqrt(p);\n\n\t\tfor(int bunbo = 1; bunbo <= n; bunbo++){\n\n\t\t\tleft = 1,right = n, m = (left+right)/2;\n\t\t\ttmp_small = 0;\n\n\t\t\twhile(left <= right){\n\t\t\t\ttmp = (double)m/(double)bunbo;\n\n\t\t\t\tif(tmp < sqrt_p){\n\t\t\t\t\ttmp_small = tmp;\n\t\t\t\t\ttmp_bunshi = m;\n\t\t\t\t\tleft = m+1;\n\t\t\t\t}else{\n\t\t\t\t\tright = m-1;\n\t\t\t\t}\n\t\t\t\tm = (left+right)/2;\n\t\t\t}\n\t\t\tif(near_small < tmp_small){\n\t\t\t\tnear_small = tmp_small;\n\t\t\t\tu = tmp_bunshi;\n\t\t\t\tv = bunbo;\n\t\t\t}\n\n\t\t\tleft = 1,right = n, m = (left+right)/2;\n\t\t\ttmp_big = DBL_MAX;\n\n\t\t\twhile(left <= right){\n\t\t\t\ttmp = (double)m/(double)bunbo;\n\n\t\t\t\tif(tmp > sqrt_p){\n\t\t\t\t\ttmp_big = tmp;\n\t\t\t\t\ttmp_bunshi = m;\n\t\t\t\t\tright = m-1;\n\t\t\t\t}else{\n\t\t\t\t\tleft = m+1;\n\t\t\t\t}\n\t\t\t\tm = (left+right)/2;\n\t\t\t}\n\n\t\t\tif(near_big > tmp_big){\n\t\t\t\tnear_big = tmp_big;\n\t\t\t\tx = tmp_bunshi;\n\t\t\t\ty = bunbo;\n\t\t\t}\n\t\t}\n\n\t\tif(u >= v){\n\t\t\tcommon = calc(u,v);\n\t\t}else{\n\t\t\tcommon = calc(v,u);\n\t\t}\n\n\t\tu /= common;\n\t\tv /= common;\n\n\t\tif(x >= y){\n\t\t\tcommon = calc(x,y);\n\t\t}else{\n\t\t\tcommon = calc(y,x);\n\t\t}\n\n\t\tx /= common;\n\t\ty /= common;\n\n\t\tprintf(\"%d/%d %d/%d\\n\",x,y,u,v);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 3124, "score_of_the_acc": -0.9054, "final_rank": 17 }, { "submission_id": "aoj_1208_2293940", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n double p;\n int n;\n while(cin>>p>>n,n){\n double t=sqrt(p);\n int x=0,y=1,u=1e9,v=1;\n for(int i=1;i<n;i++){\n int l=0,r=n+1,m;\n while(l<r){\n m=(l+r)/2;\n if(t<(1.0*m/i))r=m;\n else l=m+1;\n }\n if(x*i<(r-1)*y)x=r-1,y=i;\n if(r!=n+1&&u*i>v*r)u=r,v=i;\n }\n cout<<u<<'/'<<v<<' '<<x<<'/'<<y<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3156, "score_of_the_acc": -0.8969, "final_rank": 16 }, { "submission_id": "aoj_1208_2293751", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<double,pair<int,int> > VP;\nbool kyk(int,int);\nint main(){\n vector<int> jj(10005);\n for(int i=0;i<=10004;i++){\n jj[i]=i*i;\n }\n while(1){\n int p,n;\n cin >> p >> n;\n if(p==0&&n==0)break;\n vector<VP> sm;\n vector<VP> la;\n for(int i=1;i<=n;i++){\n VP pul;\n VP pus;\n pus.second.second=i;\n pul.second.second=i; \n int bns=lower_bound(jj.begin(),jj.end(),jj[i]*p)-jj.begin();\n if(bns-1>n)break;\n pul.second.first=jj[bns];\n pus.second.first=jj[bns-1];\n pul.first=(double)pul.second.first/(i*i);\n pus.first=(double)pus.second.first/(i*i);\n sm.push_back(pus);\n la.push_back(pul);\n }\n //cout << i*i << \" \"<< pus.first << endl;\n //cout << pul.first << endl << endl;\n sort(sm.begin(),sm.end());\n sort(la.begin(),la.end());\n for(int i=0;i<la.size();i++){\n if(kyk(la[i].second.first,la[i].second.second)&&la[i].second.first<=n*n){\n\tcout << (int)sqrt(la[i].second.first)<<\"/\"<<la[i].second.second<<\" \";\n\tbreak;\n }\n }\n for(int i=sm.size()-1;i>=0;i--){\n if(kyk(sm[i].second.first,sm[i].second.second)&&sm[i].second.first<=n*n){\n\tcout << (int)sqrt(sm[i].second.first)<<\"/\"<<sm[i].second.second<<endl;\n\tbreak;\n }\n }\t\n }\n \n return 0;\n}\nbool kyk(int a,int b){\n //cout << a << b <<endl;\n if(a==0||b==0)return 0;\n if(b!=1&&a==b*b)return 0;\n if(b!=1&&a%b==0)return 0;\n for(int i=2;i*i<=b*b;i++){\n if(a%i==0&&b%i==0)return 0;\n }\n return 1;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3176, "score_of_the_acc": -0.8871, "final_rank": 14 }, { "submission_id": "aoj_1208_2293738", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define int long long\nsigned main(){\n int p, n;\n while(cin >> p >> n, p || n) {\n int u = 1, v = 1, x = n, y = 1;\n for(int i = 1; i <= n; i++) {\n for(int j = u*i/v; j <= n; j++) {\n\tif(j*j <= p*i*i) {\n\t if(__gcd(i, j) != 1) continue;\n\t if(u*i - j*v < 0) u = j, v = i;\n\t} else {\n\t if(x*i - j*y > 0) x = j, y = i;\n\t break;\n\t}\n }\n }\n cout << x << \"/\" << y << \" \" << u << \"/\" << v << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3084, "score_of_the_acc": -0.8486, "final_rank": 10 }, { "submission_id": "aoj_1208_2293579", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n double p;\n int n;\n while(cin>>p>>n,n){\n double t=sqrt(p);\n int x=0,y=1,u=1e9,v=1;\n for(int i=1;i<n;i++){\n int l=0,r=n+1,m;\n while(l<r){\n\tm=(l+r)/2;\n\tif(t<(1.0*m/i))r=m;\n\telse l=m+1;\n }\n if(x*i<(r-1)*y)x=r-1,y=i;\n if(r!=n+1&&u*i>v*r)u=r,v=i;\n }\n cout<<u<<'/'<<v<<' '<<x<<'/'<<y<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3200, "score_of_the_acc": -0.9163, "final_rank": 18 }, { "submission_id": "aoj_1208_2062408", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\n\n//// < \"d:\\d_download\\visual studio 2015\\projects\\programing_contest_c++\\debug\\a.txt\" > \"d:\\d_download\\visual studio 2015\\projects\\programing_contest_c++\\debug\\b.txt\"\n\n\nint main() {\n\twhile (1) {\n\t\tint p, n; cin >> p >> n;\n\t\tif (!p)break;\n\t\tpair<int, int>minp, maxp;\n\t\tld minsa = 1e9, maxsa = 1e9;\n\t\tfor (long long int bo = 1; bo <= n; ++bo) {\n\t\t\tld num = sqrt(ld(bo*bo) * p);\n\t\t\tfor (int si = max(1, int(num - 2)); si <= min(n, int(num + 1)); ++si) {\n\t\t\t\tif (si*si < bo*bo*p) {\n\t\t\t\t\tif (minsa >sqrt(p)-ld(si)/bo ) {\n\t\t\t\t\t\tminp = (make_pair(si, bo));\n\t\t\t\t\t\tminsa = sqrt(p) - ld(si) / bo;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse if (si*si > bo*bo*p) {\n\t\t\t\t\tif (maxsa > ld(si) / bo - sqrt(p)) {\n\t\t\t\t\t\tmaxp = make_pair(si, bo);\n\t\t\t\t\t\tmaxsa = ld(si) / bo - sqrt(p);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << maxp.first << \"/\" << maxp.second << \" \" << minp.first << '/' << minp.second << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 2964, "score_of_the_acc": -0.7957, "final_rank": 6 }, { "submission_id": "aoj_1208_1886709", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\n#include<algorithm>\t\n#include<map>\n#include<set>\n#include<utility>\n#include<cmath>\n#include<cstring>\n#include<queue>\n#include<cstdio>\n#include<sstream>\n#include<iomanip>\n#define loop(i,a,b) for(int i=a;i<b;i++) \n#define rep(i,a) loop(i,0,a)\n#define pb push_back\n#define mp make_pair\n#define all(in) in.begin(),in.end()\n#define shosu(x) fixed<<setprecision(x)\nusing namespace std;\n//kaewasuretyuui\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<pii> vp;\ntypedef vector<vp> vvp;\ntypedef pair<int,pii> pip;\ntypedef vector<pip>vip;\nconst double PI=acos(-1);\nconst double EPS=1e-8;\nconst int inf=1e8;\nint gcd(int a,int b){\n\treturn (b==0?a:gcd(b,a%b));\n}\nint main(){\n\tint a,b;\n\twhile(cin>>a>>b,a+b){\n\t\tdouble q=sqrt(a);\n\t\tint c=1,d=1,e=1,f=inf;\n\t\tloop(i,1,b+1){\n\t\t\tint t=ceil(i/q);\n\t\t\tt--;\n\t\t\tif(q<(double)i/t&&(double)i/t<(double)f/e){\n\t\t\t\tf=i;e=t;\n\t\t\t\tint w=gcd(f,e);\n\t\t\t\tf/=w;t/=w;\n\t\t\t}\n\t\t\tt++;\n\t\t\tif(t!=0){\n\t\t\t\tif(q>(double)i/t&&(double)i/t>(double)d/c){\n\t\t\t\t\td=i;c=t;\n\t\t\t\t\tint w=gcd(d,c);\n\t\t\t\t\td/=w;c/=w;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout<<f<<\"/\"<<e<<\" \"<<d<<\"/\"<<c<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 1164, "score_of_the_acc": -0.0124, "final_rank": 1 }, { "submission_id": "aoj_1208_1874997", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n \n#define INF 1e9\n \nclass Fraction{\npublic:;\n double numerator,denominator;\n double div();\n};\n \ndouble Fraction::div(){\n return numerator/denominator;\n}\n \nostream &operator << (ostream &os,const Fraction &f){\n os << f.numerator << '/' << f.denominator;\n return os;\n}\n \nint main(){\n double p;\n int n;\n while(cin >> p >> n, p){\n\tp = sqrt(p);\n\tFraction a = (Fraction){-1,1};\n\tFraction b = (Fraction){INF,1};\n\tfor(int den = 1 ; den <= n ; den++){\n\t int l = 0, r = n+1;\n\t while(l < r){\n\t\tdouble mid = (l + r) / 2;\n\t\tif(mid < p*den){\n\t\t if(mid/den > a.div()){\n\t\t\ta = (Fraction){mid,den};\n\t\t }\n\t\t l = mid+1;\n\t\t}else{\n\t\t r = mid;\n\t\t}\n\t }\n\t l = 0, r = n+1;\n\t while(l < r){\n\t\tdouble mid = (l + r) / 2;\n\t\tif(mid > p*den){\n\t\t if(mid/den < b.div()){\n\t\t\tb = (Fraction){mid,den};\n\t\t }\n\t\t r = mid;\n\t\t}else{\n\t\t l = mid+1;\n\t\t}\n\t }\n\t}\n\tcout << b << \" \" << a << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 1284, "score_of_the_acc": -0.1271, "final_rank": 3 }, { "submission_id": "aoj_1208_1803620", "code_snippet": "#include<iostream>\n#include<cmath>\n#include<tuple>\nusing namespace std;\nint p, q;\nint main() {\n\twhile (true) {\n\t\tcin >> p >> q;\n\t\tif (p == 0 && q == 0)break;\n\t\ttuple<int, int, double>x, y;\n\t\tx = make_tuple(0, 0, 0);\n\t\ty = make_tuple(0, 0, 100000);\n\t\tdouble T = sqrt(1.0*p);\n\t\tfor (int i = 1; i <= q; i++) {\n\t\t\tdouble I = T*i;\n\t\t\tint J = I;\n\t\t\tdouble K = 1.0*J / i;\n\t\t\tdouble L = 1.0*(J + 1) / i;\n\t\t\tif (K > get<2>(x) && J <= q) {\n\t\t\t\tx = make_tuple(J, i, K);\n\t\t\t}\n\t\t\tif (L < get<2>(y) && J + 1 <= q) {\n\t\t\t\ty = make_tuple(J + 1, i, L);\n\t\t\t}\n\t\t}\n\t\tcout << get<0>(y) << '/' << get<1>(y) << ' ';\n\t\tcout << get<0>(x) << '/' << get<1>(x) << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3076, "score_of_the_acc": -0.8451, "final_rank": 9 }, { "submission_id": "aoj_1208_1801348", "code_snippet": "#include <cmath>\n#include <iostream>\nusing namespace std;\nint p, n; long double d;\nint main() {\n\twhile (cin >> p >> n, n) {\n\t\td = sqrtl(p);\n\t\tint p1 = 999999, q1 = 1, p2 = 0, q2 = 1;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tint j = i / d;\n\t\t\tif (0 < j && j <= n && 1.0L * i / j < 1.0L * p1 / q1) p1 = i, q1 = j;\n\t\t\tif (0 < (j + 1) && (j + 1) <= n && 1.0L * i / (j + 1) > 1.0L * p2 / q2) p2 = i, q2 = j + 1;\n\t\t}\n\t\tcout << p1 << '/' << q1 << ' ' << p2 << '/' << q2 << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3088, "score_of_the_acc": -0.8545, "final_rank": 11 }, { "submission_id": "aoj_1208_1274074", "code_snippet": "#include <iostream>\n#include <complex>\n#include <sstream>\n#include <string>\n#include <algorithm>\n#include <deque>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <vector>\n#include <set>\n#include <limits>\n#include <cstdio>\n#include <cctype>\n#include <cmath>\n#include <cstring>\n#include <cstdlib>\n#include <ctime>\nusing namespace std;\n#define REP(i, j) for(int i = 0; i < (int)(j); ++i)\n#define FOR(i, j, k) for(int i = (int)(j); i < (int)(k); ++i)\n#define SORT(v) sort((v).begin(), (v).end())\n#define REVERSE(v) reverse((v).begin(), (v).end())\nconst int INF = 10001;\n\nint gcd(int a, int b){ return (b == 0 ? a : gcd(b, a % b)); }\n\nclass R{\n public:\n double a, b;\n R(int aa, int bb) { a = aa; b = bb; int r; while((r = gcd(a, b)) != 1) { a /= r; b /= r; } }\n bool operator > (const R &r) const { return a / b > r.a / r.b; }\n bool operator < (const R &r) const { return a / b < r.a / r.b; }\n};\n\n\nint main() {\n double P;\n int N;\n while(cin >>P >>N && (P || N)){\n P = sqrt(P);\n R lower = R(-1, 1), upper = R(INF, 1);\n FOR(i, 1, N + 1){\n int l = 0, r = N + 1;\n while(r - l > 1){\n double m = (r + l) / 2;\n if(m / i >= P){\n r = m;\n upper = min(upper, R(r, i));\n }\n else{\n l = m;\n lower = max(lower, R(l, i));\n }\n }\n }\n cout <<upper.a <<\"/\" <<upper.b <<\" \" <<lower.a <<\"/\" <<lower.b <<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 2630, "memory_kb": 1284, "score_of_the_acc": -0.5931, "final_rank": 5 }, { "submission_id": "aoj_1208_1140042", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define INF 1e9\n\nclass Fraction{\npublic:;\n double numerator,denominator;\n double div();\n};\n\ndouble Fraction::div(){\n return numerator/denominator;\n}\n\nostream &operator << (ostream &os,const Fraction &f){\n os << f.numerator << '/' << f.denominator;\n return os;\n}\n\nint main(){\n double p;\n int n;\n while(cin >> p >> n, p){\n p = sqrt(p);\n Fraction a = (Fraction){-1,1};\n Fraction b = (Fraction){INF,1};\n for(int den = 1 ; den <= n ; den++){\n int l = 0, r = n+1;\n while(l < r){\n double mid = (l + r) / 2;\n if(mid < p*den){\n if(mid/den > a.div()){\n a = (Fraction){mid,den};\n }\n l = mid+1;\n }else{\n r = mid;\n }\n }\n l = 0, r = n+1;\n while(l < r){\n double mid = (l + r) / 2;\n if(mid > p*den){\n if(mid/den < b.div()){\n b = (Fraction){mid,den};\n }\n r = mid;\n }else{\n l = mid+1;\n }\n }\n }\n cout << b << \" \" << a << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 1284, "score_of_the_acc": -0.1271, "final_rank": 3 }, { "submission_id": "aoj_1208_1140040", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define INF 1e9\n\nclass Fraction{\npublic:;\n double numerator,denominator;\n double div();\n};\n\ndouble Fraction::div(){\n return numerator/denominator;\n}\n\nostream &operator << (ostream &os,const Fraction &f){\n os << f.numerator << '/' << f.denominator;\n return os;\n}\n\nint main(){\n double p;\n int n;\n while(cin >> p >> n, p){\n p = sqrt(p);\n Fraction a = (Fraction){-1,1};\n Fraction b = (Fraction){INF,1};\n for(int den = 1 ; den <= n ; den++){\n int l = 0, r = n+1;\n for(int i = 0 ; i < 150 ; i++){\n double mid = (l + r) / 2;\n if(mid < p*den){\n if(mid/den > a.div()){\n a = (Fraction){mid,den};\n }\n l = mid;\n }else{\n r = mid;\n }\n }\n l = 0, r = n+1;\n for(int i = 0 ; i < 150 ; i++){\n double mid = (l + r) / 2;\n if(mid > p*den){\n if(mid/den < b.div()){\n b = (Fraction){mid,den};\n }\n r = mid;\n }else{\n l = mid;\n }\n }\n }\n cout << b << \" \" << a << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 4860, "memory_kb": 1288, "score_of_the_acc": -1.0547, "final_rank": 20 }, { "submission_id": "aoj_1208_1139716", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define MAX 1000000007\n\nint main() {\n double p,n;\n while(cin >> p >> n) {\n if(p==0 && n==0) break;\n p=sqrt(p);\n int x=0,y=0,u=0,v=0;\n double a2=MAX,b2=MAX;\n for(int i=1; i<=n; i++) {\n int a=(int)(p*i);\n int b=a+1;\n if(a>n) break;\n if(__gcd(a,i)==1 && p-(double)a/i<a2) {\n\ta2=p-(double)a/i;\n\tu=a;v=i;\n }\n if(b>n) continue;\n if(__gcd(b,i)==1 && (double)b/i-p<b2) {\n\tb2=(double)b/i-p;\n\tx=b;y=i;\n }\n }\n printf(\"%d/%d %d/%d\\n\",x,y,u,v);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1200, "score_of_the_acc": -0.0159, "final_rank": 2 } ]
aoj_1204_cpp
Problem E: Pipeline Scheduling An arithmetic pipeline is designed to process more than one task simultaneously in an overlapping manner. It includes function units and data paths among them. Tasks are processed by pipelining : at each clock, one or more units are dedicated to a task and the output produced for the task at the clock is cascading to the units that are responsible for the next stage; since each unit may work in parallel with the others at any clock, more than one task may be being processed at a time by a single pipeline. In this problem, a pipeline may have a feedback structure, that is, data paths among function units may have directed loops as shown in the next figure. Example of a feed back pipeline Since an arithmetic pipeline in this problem is designed as special purpose dedicated hardware, we assume that it accepts just a single sort of task. Therefore, the timing information of a pipeline is fully described by a simple table called a reservation table , which specifies the function units that are busy at each clock when a task is processed without overlapping execution. Example of a "reservation table" In reservation tables, 'X' means "the function unit is busy at that clock" and '.' means "the function unit is not busy at that clock." In this case, once a task enters the pipeline, it is processed by unit0 at the first clock, by unit1 at the second clock, and so on. It takes seven clock cycles to perform a task. Notice that no special hardware is provided to avoid simultaneous use of the same function unit. Therefore, a task must not be started if it would conflict with any tasks being processed. For instance, with the above reservation table, if two tasks, say task 0 and task 1, were started at clock 0 and clock 1, respectively, a conflict would occur on unit0 at clock 5. This means that you should not start two tasks with single cycle interval. This invalid schedule is depicted in the following process table, which is obtained by overlapping two copies of the reservation table with one being shifted to the right by 1 clock. Example of a "conflict" ('0's and '1's in this table except those in the first row represent tasks 0 and 1, respectively, and 'C' means the conflict.) Your job is to write a program that reports the minimum number of clock cycles in which the given pipeline can process 10 tasks. Input The input consists of multiple data sets, each representing the reservation table of a pipeline. A data set is given in the following format. n x 0,0 x 0,1 ... x 0,n-1 x 1,0 x 1,1 ... x 1,n-1 x 2,0 x 2,1 ... x 2,n-1 x 3,0 x 3,1 ... x 3,n-1 x 4,0 x 4,1 ... x 4,n-1 The integer n (< 20) in the first line is the width of the reservation table, or the number of clock cycles that is necessary to perform a single task. The second line represents the usage of unit0, the third line unit1, and so on. x i,j is either 'X' or '.'. The former means reserved and the latter free . There are no spaces in any input line. For simplicity, we ...(truncated)
[ { "submission_id": "aoj_1204_2581073", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\nstruct Info{\n\tvoid set(int arg_task,int arg_num){\n\t\ttask = arg_task;\n\t\tnum = arg_num;\n\t}\n\tint task,num;\n};\n\nstruct Data{\n\tInfo unit_table[5];\n\tint clock,min_task,max_task;\n};\n\nchar table[5][20];\nint loc[20];\nint N;\n\nvoid func(){\n\n\tfor(int i = 0; i < 5; i++)scanf(\"%s\",table[i]);\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < 5; k++){\n\t\t\tif(table[k][i] == 'X'){\n\t\t\t\tloc[i] = k;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\n\tData first;\n\tfor(int unit = 0; unit < 5; unit++){\n\t\tif(table[unit][0] == 'X'){\n\t\t\tfirst.unit_table[unit].set(0,0);\n\t\t}else{\n\t\t\tfirst.unit_table[unit].set(BIG_NUM,BIG_NUM);\n\t\t}\n\t}\n\tfirst.clock = 1;\n\tfirst.min_task = 0;\n\tfirst.max_task = 0;\n\n\tqueue<Data> Q;\n\tQ.push(first);\n\n\tint count;\n\tbool collide;\n\n\twhile(!Q.empty()){\n\n\t\tData new_data;\n\t\tfor(int unit = 0; unit < 5; unit++)new_data.unit_table[unit].set(BIG_NUM,BIG_NUM);\n\n\t\tcollide = false;\n\t\tcount = 0;\n\t\tnew_data.min_task = BIG_NUM,new_data.max_task = -BIG_NUM;\n\n\t\tfor(int task = Q.front().min_task; task <= Q.front().max_task; task++){\n\t\t\tfor(int unit = 0; unit < 5; unit++){\n\t\t\t\tif(Q.front().unit_table[unit].task == task){\n\n\t\t\t\t\tif(Q.front().unit_table[unit].num < N-1){\n\t\t\t\t\t\tnew_data.min_task = min(new_data.min_task,task);\n\t\t\t\t\t\tnew_data.max_task = max(new_data.max_task,task);\n\n\t\t\t\t\t\tint next_loc = loc[Q.front().unit_table[unit].num+1];\n\t\t\t\t\t\tif(new_data.unit_table[next_loc].task == BIG_NUM){\n\t\t\t\t\t\t\tcount++;\n\t\t\t\t\t\t\tnew_data.unit_table[next_loc].task = task;\n\t\t\t\t\t\t\tnew_data.unit_table[next_loc].num = Q.front().unit_table[unit].num+1;\n\n\t\t\t\t\t\t\tif(task == 9 && Q.front().unit_table[unit].num+1 == N-1){\n\t\t\t\t\t\t\t\tprintf(\"%d\\n\",Q.front().clock+1);\n\t\t\t\t\t\t\t\treturn;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\tcollide = true;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(collide)break;\n\t\t}\n\t\tif(collide){\n\t\t\tQ.pop();\n\t\t\tcontinue;\n\t\t}\n\n\t\tif(new_data.unit_table[loc[0]].task == BIG_NUM && new_data.max_task < 9){\n\t\t\tData new_data_add;\n\t\t\tfor(int unit = 0; unit < 5; unit++){\n\t\t\t\tnew_data_add.unit_table[unit].set(new_data.unit_table[unit].task,new_data.unit_table[unit].num);\n\t\t\t}\n\t\t\tnew_data_add.unit_table[loc[0]].set(new_data.max_task+1,0);\n\t\t\tnew_data_add.clock = Q.front().clock+1;\n\t\t\tnew_data_add.min_task = new_data.min_task;\n\t\t\tnew_data_add.max_task = new_data.max_task+1;\n\n\t\t\tQ.push(new_data_add);\n\t\t}\n\n\t\tif(count > 0){\n\t\t\tnew_data.clock = Q.front().clock+1;\n\t\t\tQ.push(new_data);\n\t\t}\n\t\tQ.pop();\n\t}\n}\n\n\nint main(){\n\n\twhile(true){\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4456, "score_of_the_acc": -0.1626, "final_rank": 11 }, { "submission_id": "aoj_1204_2062326", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\n\n//// < \"d:\\d_download\\visual studio 2015\\projects\\programing_contest_c++\\debug\\a.txt\" > \"d:\\d_download\\visual studio 2015\\projects\\programing_contest_c++\\debug\\b.txt\"\n\nint getans(const bitset<19>&bs,int rest,vector<vector<int>>&memo,vector<int>&confs) {\n\tif (!rest)return 0;\n\telse {\n\t\tif (memo[rest][bs.to_ulong()] != -1)return memo[rest][bs.to_ulong()];\n\t\telse {\n\t\t\tint ans = 10000;\n\t\t\tfor (int bet = 1; bet < 19; ++bet) {\n\t\t\t\tbool ok = true;\n\t\t\t\tfor (int i = bet; i < 19; ++i) {\n\t\t\t\t\tif (bs[i] && confs[bet+18-i]) {\n\t\t\t\t\t\tok = false;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (ok) {\n\t\t\t\t\tbitset<19>nextbs;\n\t\t\t\t\tfor (int i = 0; i < 19 -bet; ++i) {\n\t\t\t\t\t\tnextbs[i] = bs[i + bet];\n\t\t\t\t\t}\n\t\t\t\t\tnextbs[18] = true;\n\t\t\t\t\tans = min(ans,bet + getans(nextbs, rest - 1, memo, confs));\n\t\t\t\t}\n\t\t\t}\n\t\t\treturn memo[rest][bs.to_ulong()] = ans;\n\t\t}\n\t}\n}\n\nint main() {\n\twhile (1) {\n\t\tint N; cin >> N;\n\t\tif (!N)break;\n\t\tvector<vector<int>>tables(5, vector<int>(N));\n\t\tfor (int i = 0; i < 5; ++i) {\n\t\t\tstring st; cin >> st;\n\t\t\tfor (int j = 0; j < N; ++j) {\n\t\t\t\ttables[i][j] = (st[j] == 'X');\n\t\t\t}\n\t\t}\n\t\tvector<int>conf(41);\n\t\tfor (int i = 1; i < N; ++i) {\n\t\t\tfor (int y = 0; y < 5; ++y) {\n\t\t\t\tfor (int l = 0; l < N-i; ++l) {\n\t\t\t\t\tint r = l + i;\n\t\t\t\t\tif (tables[y][l] && tables[y][r])conf[i] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tbitset<19>bs;\n\t\tvector<vector<int>>memo(11, vector<int>(1 << 19,-1));\n\t\tint ans = getans(bs, 10, memo, conf);\n\t\tcout << ans+N-1 << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 27412, "score_of_the_acc": -1.0113, "final_rank": 15 }, { "submission_id": "aoj_1204_1953384", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstdlib>\n#include <string>\n#include <vector>\n#include <deque>\n#include <list>\n#include <algorithm>\n#include <numeric>\n#include <functional>\n#include <cmath>\n#include <cstring>\n#include <cctype>\n#include <sstream>\n#include <set>\n#include <map>\n#include <stack>\n#include <queue>\n#include <complex>\nusing namespace std;\n#define REP(i,n) for(int i = 0; i < (int)n; i++)\n#define FOR(i,a,b) for(int i = a; i < (int)b; i++)\n#define pb push_back\n#define mp make_pair\ntypedef vector<int> vi;\ntypedef pair<int, int> pi;\ntypedef long long ll;\nconst int INF = 1<<28;\nconst ll MOD = 1000000007;\nvector<pi> x;\nint n, ans;\n\nvoid dfs(int pnt, int cnt, bool b[5][200]) {\n\tif(pnt + n > ans) return;\n\tif(cnt == 10) {\n\t\tans = min(ans, pnt + n-1);\n\t\treturn;\n\t}\n\tREP(i, x.size()) {\n\t\tif(b[x[i].first][x[i].second + pnt]) {\n\t\t\tdfs(pnt+1, cnt, b);\n\t\t\treturn;\n\t\t}\n\t}\n\tREP(i, x.size())\n\t\tb[x[i].first][x[i].second + pnt] = true;\n\tdfs(pnt+1, cnt+1, b);\n\tREP(i, x.size())\n\t\tb[x[i].first][x[i].second + pnt] = false;\n\tdfs(pnt+1, cnt, b);\n\treturn;\n}\n\nint main() {\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0);\n\twhile(cin >> n, n) {\n\t\tans = n * 10;\n\t\tx.clear();\n\t\tREP(i, 5) REP(j, n) {\n\t\t\tchar c; cin >> c;\n\t\t\tif(c == 'X')\n\t\t\t\tx.pb(mp(i, j));\n\t\t}\n\t\tbool b[5][200] = {};\n\t\tdfs(0, 0, b);\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1204, "score_of_the_acc": -0.0439, "final_rank": 4 }, { "submission_id": "aoj_1204_1171799", "code_snippet": "#include <iostream>\n#include <complex>\n#include <sstream>\n#include <string>\n#include <algorithm>\n#include <deque>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <vector>\n#include <set>\n#include <limits>\n#include <cstdio>\n#include <cctype>\n#include <cmath>\n#include <cstring>\n#include <cstdlib>\n#include <ctime>\nusing namespace std;\n#define REP(i, j) for(int i = 0; i < (int)(j); ++i)\n#define FOR(i, j, k) for(int i = (int)(j); i < (int)(k); ++i)\n#define SORT(v) sort((v).begin(), (v).end())\n#define REVERSE(v) reverse((v).begin(), (v).end())\ntypedef complex<double> P;\nconst int M = 5;\nconst int INF = 1e9;\n\nint N, ans = INF;\n\nint count(vector< vector<int> > &v){\n int ret = 0, j;\n REP(i, M){\n for(j = (int)v[i].size() - 1; j >= 0 && v[i][j] == -1; --j) ;\n ret = max(ret, j);\n }\n return ret + 1;\n}\n\nbool check(int x, int s, vector< vector<int> > &v, vector< vector<int> > &t){\n REP(i, M) REP(j, N) if(t[i][j] && v[i][j + x + s] != -1) return false;\n return true;\n}\n\nvoid dfs(int n, int x, vector< vector<int> > &v, vector< vector<int> > &t){\n if(n >= 10) if(x + N < ans) ans = x + N;\n if(x + N >= ans) return ;\n FOR(_, 1, N + 1){\n if(!check(x, _, v, t)) continue;\n REP(i, M) REP(j, N) if(t[i][j]) v[i][j + x + _] = n;\n dfs(n + 1, x + _, v, t);\n REP(i, M) REP(j, N) if(t[i][j]) v[i][j + x + _] = -1;\n }\n}\n\nint main() {\n while(cin >>N && N){\n ans = INF;\n vector< vector<int> > t(M, vector<int>(N)), v(M, vector<int>(N * 12, -1));\n REP(i, M){\n REP(j, N){\n char c; cin >>c;\n t[i][j] = (c == 'X' ? 1 : 0);\n if(t[i][j]) v[i][j] = 0;\n }\n }\n dfs(1, 0, v, t);\n cout <<ans <<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1220, "score_of_the_acc": -0.0445, "final_rank": 6 }, { "submission_id": "aoj_1204_1010649", "code_snippet": "#include<iostream>\n#include<bitset>\n#include<array>\n#include<utility>\n#include<vector>\n\nusing namespace std;\n\ntypedef array<bitset<200>,5> Board;\n\nint main(){\n for(int n;cin>>n,n;){\n Board b;\n for(int i=0;i<5;i++){\n for(int j=0;j<n;j++){\n\tchar c;\n\tcin>>c;\n\tb[i][j]=c=='X';\n }\n }\n const int BW=20;\n static bool t[1<<BW];\n for(int i=0;i<1<<BW;i++){\n Board c;\n Board cb=b;\n for(int j=0;j<BW;j++){\n\tif(i>>j&1){\n\t for(int k=0;k<5;k++){\n\t c[k]|=cb[k];\n\t }\n\t}\n\tfor(auto &e:cb){\n\t e<<=1;\n\t}\n }\n bool f=false;\n for(int j=0;j<5;j++){\n\tf|=(c[j]&b[j]).any();\n }\n t[i]=!f;\n }\n static int mem[1<<BW];\n fill(begin(mem),end(mem),-1);\n vector<pair<int,int> > stats[222];\n stats[0].emplace_back(0,0);\n for(int i=0;;i++){\n for(auto e:stats[i]){\n\tint f=e.first;\n\tint s=e.second;\n\tif(f==10){\n\t cout<<i+n-1<<endl;\n\t goto next;\n\t}\n\tif(mem[s]>=f)continue;\n\tmem[s]=f;\n\tstats[i+1].emplace_back(f,s<<1&(1<<BW)-1);\n\tif(t[s]){\n\t stats[i+1].emplace_back(f+1,(s|1)<<1&(1<<BW)-1);\n\t}\n }\n }\n next:\n ;\n }\n}", "accuracy": 1, "time_ms": 5720, "memory_kb": 6452, "score_of_the_acc": -1.043, "final_rank": 16 }, { "submission_id": "aoj_1204_896174", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <sstream>\n#include <cstring>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n#include <numeric>\n#include <cctype>\n#include <tuple>\n#include <array>\n\n#ifdef _MSC_VER\n#include <agents.h>\n#endif\n\n#define FOR(i, a, b) for(int i = (a); i < (int)(b); ++i)\n#define rep(i, n) FOR(i, 0, n)\n#define ALL(v) v.begin(), v.end()\n#define REV(v) v.rbegin(), v.rend()\n#define MEMSET(v, s) memset(v, s, sizeof(v))\n#define X first\n#define Y second\n\nusing namespace std;\n\nint ok[1 << 20];\nint used[5][50];\nint dp[2][1 << 20];\n\n\n\nint main(){\n\tint n;\n\twhile (cin >> n, n){\n\t\tarray<string, 5> ar;\n\t\trep(i, 5) cin >> ar[i];\n\n\t\tint len = 0;\n\t\trep(i, 5) rep(j, n) if (ar[i][j] == 'X') len = max(len, j+1);\n\n\t\trep(i, 1 << n){\n\t\t\tok[i] = 1;\n\t\t\tMEMSET(used, 0);\n\t\t\trep(j, n){\n\t\t\t\tif (i&(1 << j)){\n\t\t\t\t\trep(k, 5) rep(l, n){\n\t\t\t\t\t\tif (ar[k][l] != 'X') continue;\n\t\t\t\t\t\tif (used[k][l+j]) ok[i] = 0;\n\t\t\t\t\t\tused[k][l+j] = 1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t\t//if (ok[i]){\n\t\t\t//\trep(j, n) cout << !!(i&(1 << j));\n\t\t\t//\tcout << endl;\n\t\t\t//}\n\t\t}\n\t\tint mask = (1 << n) - 1;\n\n\t\tMEMSET(dp, 0);\n\t\trep(i, n * 15){\n\t\t\trep(j, 1 << n){\n\t\t\t\tint nxt = (i + 1) & 1, bits = (j << 1)&mask;\n\t\t\t\tdp[nxt][bits] = max(dp[nxt][bits], dp[i & 1][j]);\n\t\t\t\tif (ok[bits | 1]) dp[nxt][bits | 1] = max(dp[nxt][bits | 1], dp[i & 1][j] + 1);\n\t\t\t\tif (dp[nxt][bits | 1] == 10){\n\t\t\t\t\tcout << i + len << endl;\n\t\t\t\t\tgoto end;\n\t\t\t\t}\n\t\t\t}\n\t\t\t//rep(j, 1 << n){\n\t\t\t//\t\trep(k, n) cout << !!(j&(1 << n-k-1));\n\t\t\t//\t\tcout << endl;\n\t\t\t//\t\tcout << dp[i + 1 & 1][j] << endl;\n\t\t\t//}\n\t\t}\n\tend:;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 11444, "score_of_the_acc": -0.4175, "final_rank": 12 }, { "submission_id": "aoj_1204_652113", "code_snippet": "#include<iostream>\nusing namespace std;\n\nint n;\nint c;\nstring p[5];\n\nint rec(int id,int st,int pos){\n if(id == 10){\n return pos + n;\n }\n \n int res = 10000;\n for(int i=1;i<n;i++){\n if(pos+i>=res)return res;\n if(!((st>>i)&1)){\n int nxt = (st >> i) | c;\n res = min(res,rec(id+1,nxt,pos+i));\n }\n }\n return res;\n}\n\nint main(){\n cin.tie(0);\n std::ios::sync_with_stdio(false);\n while(cin >> n,n){\n for(int i=0;i<5;i++)cin >> p[i];\n\n c = 0;\n for(int i=1;i<n;i++){\n bool f = true;\n for(int j=0;j<5;j++){\n\tfor(int k=0;k<n;k++){\n\t if(k+i>=n)break;\n\t if(p[j][k] == p[j][k+i] && p[j][k] == 'X')f = false;\n\t}\n }\n if(!f)c |= 1<<i;\n }\n cout << rec(1,c,0) << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1200, "score_of_the_acc": -0.0466, "final_rank": 7 }, { "submission_id": "aoj_1204_652110", "code_snippet": "#include<iostream>\nusing namespace std;\n\nint n;\nint c;\nstring p[5];\n\nint rec(int id,int st,int pos){\n if(id == 10){\n return pos + n;\n }\n \n int res = 10000;\n for(int i=1;i<n;i++){\n if(!((st>>i)&1)){\n int nxt = (st >> i) | c;\n res = min(res,rec(id+1,nxt,pos+i));\n }\n }\n return res;\n}\n\nint main(){\n while(cin >> n,n){\n for(int i=0;i<5;i++)cin >> p[i];\n\n c = 0;\n for(int i=1;i<n;i++){\n bool f = true;\n for(int j=0;j<5;j++){\n\tfor(int k=0;k<n;k++){\n\t if(k+i>=n)break;\n\t if(p[j][k] == p[j][k+i] && p[j][k] == 'X'){\n\t f = false;\n\t break;\n\t }\n\t}\n\tif(!f)break;\n }\n if(!f)c |= 1<<i;\n }\n\n cout << rec(1,c,0) << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1204, "score_of_the_acc": -0.0468, "final_rank": 8 }, { "submission_id": "aoj_1204_628456", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <set>\n#include <map>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <cassert>\n//C++11\n#if __cplusplus == 201103L\n#include <tuple>\n#endif\n\nusing namespace std;\n\n#define FOR(i,k,n) for(int i=(k); i<(int)n; ++i)\n#define REP(i,n) FOR(i,0,n)\n#define FORIT(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n\ntemplate<class T> void debug(T begin, T end){ for(T i = begin; i != end; ++i) cout<<*i<<\" \"; cout<<endl; }\n\ntypedef long long ll;\nconst int INF = 100000000;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\nint W;\nbool used[5][410] = {};\nvector<string> grid;\nint min_ans;\nint dfs(int p, int bx){\n if(min_ans <= (10 - p) + bx + W - 1) return INF;\n if(p == 10) {\n return min_ans = bx + W - 1;\n }\n int res = INF;\n for(int dx = 0; dx <= W; dx++){\n if(p == 0 && dx > 0) break;\n bool bad = false;\n REP(y, 5) REP(x, W) if(grid[y][x] == 'X' && used[y][bx + dx + x]) bad = true;\n if(bad) continue;\n REP(y, 5) REP(x, W) if(grid[y][x] == 'X') used[y][bx + dx + x] = true;\n res = min(res, dfs(p + 1, bx + dx + 1));\n REP(y, 5) REP(x, W) if(grid[y][x] == 'X') used[y][bx + dx + x] = false;\n }\n return res;\n}\n\nint main(){\n while(cin>>W && W){\n grid.assign(5, \"\");\n REP(i, 5) cin>>grid[i];\n bool empty = true;\n REP(y, 5) REP(x, W) if(grid[y][x] != '.') empty = false;\n assert(not empty);\n memset(used, 0, sizeof(used));\n min_ans = INF;\n cout << dfs(0, 0) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1216, "score_of_the_acc": -0.0444, "final_rank": 5 }, { "submission_id": "aoj_1204_618446", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#include <complex>\n#include <algorithm>\n#include <set>\n#include <map>\n#include <queue>\n#include <string>\n#include <cstring>\n#include <stack>\n#include <cmath>\n#include <iomanip>\n#include <sstream>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef ll li;\ntypedef pair<int,int> PI;\n\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define REP(i,m,n) for(int i=m; i<=(int)(n); ++i)\n#define F first\n#define S second\n#define mp(a,b) make_pair(a,b)\n#define pb(a) push_back(a)\n#define SZ(a) (int)((a).size())\n#define ALL(a) a.begin(),a.end()\n#define FOR(it,a) for(__typeof(a.begin())it=a.begin();it!=a.end();++it)\n\nint n;\n\nstring in[5];\n\nbool nok(int sz){\n rep(i,5)\n rep(j,SZ(in[i]))\n if(sz+j<SZ(in[i]))\n if(in[i][j]=='X' && in[i][sz+j]=='X')\n return true;\n\n return false;\n}\n\nbool nokl[200];\nint ans;\nint len[10];\nvoid dfs(int ne,int nlen){\n if(ne==10){\n if(nlen+n-1<ans){\n ans = nlen+n-1;\n //cout << ans << endl;\n }\n return;\n }\n \n //cout << ne << ' ' << nlen << endl;\n\n for(int i=nlen;i<=nlen+n-1;++i){\n //if(i+n>ans) break;\n bool tok = false;\n rep(j,ne) if(nokl[i-len[j]]){\n tok=true;\n break;\n }\n if(tok) continue;\n len[ne] = i;\n dfs(ne+1,i+1);\n }\n}\n\nvoid solve(){\n memset(nokl,0,sizeof(nokl));\n rep(i,5) cin >> in[i];\n\n \n rep(i,SZ(in[0])){\n nokl[i+1] = nok(i+1);\n //if(nokl[i+1]) cout << i+1 << endl;\n }\n ans = 10*n;\n dfs(0,0);\n cout << ans << endl;\n}\n\nmain(){\n while(cin >> n,n) solve();\n}", "accuracy": 1, "time_ms": 7080, "memory_kb": 1204, "score_of_the_acc": -1.0439, "final_rank": 17 }, { "submission_id": "aoj_1204_618445", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#include <complex>\n#include <algorithm>\n#include <set>\n#include <map>\n#include <queue>\n#include <string>\n#include <cstring>\n#include <stack>\n#include <cmath>\n#include <iomanip>\n#include <sstream>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef ll li;\ntypedef pair<int,int> PI;\n\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define REP(i,m,n) for(int i=m; i<=(int)(n); ++i)\n#define F first\n#define S second\n#define mp(a,b) make_pair(a,b)\n#define pb(a) push_back(a)\n#define SZ(a) (int)((a).size())\n#define ALL(a) a.begin(),a.end()\n#define FOR(it,a) for(__typeof(a.begin())it=a.begin();it!=a.end();++it)\n\nint n;\n\nstring in[5];\n\nbool nok(int sz){\n rep(i,5)\n rep(j,SZ(in[i]))\n if(sz+j<SZ(in[i]))\n if(in[i][j]=='X' && in[i][sz+j]=='X')\n return true;\n\n return false;\n}\n\nbool nokl[200];\nint ans;\nint len[10];\nvoid dfs(int ne,int nlen){\n if(ne==10){\n if(nlen+n-1<ans){\n ans = nlen+n-1;\n //cout << ans << endl;\n }\n return;\n }\n \n //cout << ne << ' ' << nlen << endl;\n\n for(int i=nlen;i<=nlen+n-1;++i){\n //if(i+n>ans) break;\n bool tok = false;\n rep(j,ne) if(nokl[i-len[j]]) tok=true;\n if(tok) continue;\n len[ne] = i;\n dfs(ne+1,i+1);\n }\n}\n\nvoid solve(){\n memset(nokl,0,sizeof(nokl));\n rep(i,5) cin >> in[i];\n\n \n rep(i,SZ(in[0])){\n nokl[i+1] = nok(i+1);\n //if(nokl[i+1]) cout << i+1 << endl;\n }\n ans = 10*n;\n dfs(0,0);\n cout << ans << endl;\n}\n\nmain(){\n while(cin >> n,n) solve();\n}", "accuracy": 1, "time_ms": 6320, "memory_kb": 1204, "score_of_the_acc": -0.9364, "final_rank": 14 }, { "submission_id": "aoj_1204_618064", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<string>\n#include<stack>\nusing namespace std;\n\nint n, t;\nint head[10] = {0};\nint rsv[5][20];\nvector<vector<int> > crsv(5);\n\nbool mCheck(int head){\n\tfor(int a = 0; a < 5; a++){\n\t\tfor(int b = 0; b < n; b++){\n\t\t\tif(crsv[a][head+b] == 1 && rsv[a][b] == 1) return false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid set_crsv(int head){\n\tfor(int a = 0; a < 5; a++){\n\t\tfor(int b = 0; b < n; b++){\n\t\t\tif(rsv[a][b] == 1) crsv[a][head+b] = 1;\n\t\t}\n\t}\n}\n\nvoid clear_crsv(int head){\n\tfor(int a = 0; a < 5; a++){\n\t\tfor(int b = 0; b < n; b++){\n\t\t\tif(rsv[a][b] == 1) crsv[a][head+b] = 0;\n\t\t}\n\t}\n}\n\nint main(){\n\tint i, j;\n\tstring str;\n\t\n\tfor(i = 0; i < crsv.size(); i++) crsv[i] = vector<int>(201);\n\twhile(1){\n\t\tint ans = 99999;\n\n\t\tcin >> n;\n\t\tif(n == 0) break;\n\t\tfor(i = 0; i < 5; i++){\n\t\t\tfor(j = 0; j < 201; j++){\n\t\t\t\tcrsv[i][j] = 0;\n\t\t\t}\n\t\t}\n\t\tfor(i = 0; i < 5; i++){\n\t\t\tcin >> str;\n\t\t\tfor(j = 0; str[j] != 0; j++){\n\t\t\t\tif(str[j] == 'X') {\n\t\t\t\t\trsv[i][j] = 1;\n\t\t\t\t\tcrsv[i][j] = 1;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\trsv[i][j] = 0;\n\t\t\t\t\tcrsv[i][j] = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\n\t\tstack<pair<int, int> > stk;\n\t\tstack<vector<vector<int> > > stk2;\n\t\t\n\t\tstk.push(make_pair(0,0));\n\t\tstk2.push(crsv);\n\t\twhile(!stk.empty()){\n\t\t\tpair<int, int> tv = stk.top();\n\t\t\tcrsv = stk2.top();\n\t\t\tstk.pop();\n\t\t\tstk2.pop();\n\t\t\tset_crsv(tv.second);\n\t\t\t\n\t\t\tif(tv.second > ans) continue;\n\t\t\tif(tv.first == 9){\n\t\t\t\t//cout << \"A\" << tv.first << \" \" << tv.second << endl;\n\t\t\t\tans = min(ans, tv.second);\n\t\t\t\t/*\n\t\t\t\tfor(i = 0; i < 5; i++){\n\t\t\t\t\tfor(j = 0; j < 30; j++){\n\t\t\t\t\t\tcout << crsv[i][j];\n\t\t\t\t\t}\n\t\t\t\t\tcout << endl;\n\t\t\t\t}\n\t\t\t\t*/\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\t/*\n\t\t\tcout << \"POP: \";\n\t\t\tcout << tv.first << \" \" << tv.second;\n\t\t\tcout << endl;\n\t\t\t*/\n\t\t\t\n\t\t\ttv.first++;\t\t\t\t\n\t\t\tfor(i = n-1; i >= 0; i--){\n\t\t\t\tif(mCheck(tv.second + i)){\n\t\t\t\t\ttv.second += i;\n\t\t\t\t\t/*\n\t\t\t\t\tcout << \"PUSH: \";\n\t\t\t\t\tcout << tv.first << \" \" << tv.second;\n\t\t\t\t\tcout << endl;\n\t\t\t\t\t*/\n\t\t\t\t\tstk.push(tv);\n\t\t\t\t\tstk2.push(crsv);\n\t\t\t\t\ttv.second -= i;\n\t\t\t\t}\n\t\t\t}\n\t\t\t\t\t\n\t\t\t//if(stk.top().second <= tv.second) clear_crsv(tv.second);\t\t\t\n\t\t}\n\t\t\n\t\tans += n;\n\t\tcout << ans << endl;\n\t\t\n\t}\n\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1364, "score_of_the_acc": -0.0526, "final_rank": 9 }, { "submission_id": "aoj_1204_497929", "code_snippet": "#include<iostream>\n#include<queue>\n#include<algorithm>\n#include<functional>\n\nusing namespace std;\n\nvector<string> task;\nconst int inf = 1<<22;\n\nstruct state{\n int num;\n int pos[10];\n int cost;\n state(){\n cost = 0;\n num = 0;\n fill(pos,pos+10,-1);\n }\n state(int p[10], int n, int c){\n copy(p,p+10,pos);\n cost = c;\n num = n;\n }\n bool operator>(const state &t)const{\n return cost>t.cost;\n }\n};\n\nvoid rev(char M[5][300], const state &t){\n for(int i = 0; i < 10; ++i){\n if( t.pos[i] > -1 ){\n for(int j = 0; j < (int)task.size(); ++j){\n for(int k = 0; k < (int)task[j].size(); ++k){\n if( task[j][k] != '.'){\n M[j][t.pos[i]+k] = task[j][k];\n }\n }\n }\n }\n }\n}\n\nbool canPut(char M[5][300], int st, int offset){\n for(int i = 0; i < (int)task.size(); ++i){\n for(int j = 0; j < (int)task[i].size(); ++j){\n if( task[i][j] != '.' && M[i][st+offset+j] != 0 ){\n return false;\n }\n }\n }\n return true;\n}\n\nint solve(int n){\n state init;\n init.num = 0;\n init.pos[init.num] = 0;\n init.cost = n;\n int ret = inf;\n\n priority_queue<state, vector<state>, greater<state> > q;\n int vis[10];\n fill(vis,vis+10,inf);\n \n q.push(init);\n while(!q.empty()){\n state cur = q.top(); q.pop();\n if( cur.num == 9 ){\n return cur.cost;\n ret = min(ret, cur.cost);\n }\n \n int initial = *max_element(cur.pos,cur.pos+10);\n char M[5][300] = {{0}};\n rev(M,cur);\n for(int off = 1; off <= n; ++off){\n if(canPut(M,initial,off)){\n state next = cur;\n next.num++;\n next.pos[next.num] = initial + off;\n next.cost = initial + off + n;\n \n if( vis[next.num] > next.cost ){\n // vis[next.num] = next.cost;\n q.push(next);\n }\n }\n }\n }\n return ret;\n}\n\nint main()\n{\n int n;\n while(true){\n task.clear();\n cin >> n;\n if(n == 0) break;\n for(int i = 0; i < 5; ++i){\n string s;\n cin >> s;\n task.push_back(s);\n }\n cout << solve(n) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 2128, "score_of_the_acc": -0.079, "final_rank": 10 }, { "submission_id": "aoj_1204_386649", "code_snippet": "#include <iostream>\n#include <cstring>\nusing namespace std;\n\nint n, res;\nchar t[5][22], ans[5][302];\n\nbool check(int idx){\n for(int i = 0; i < 5; i++){\n for(int j = 0; j < n; j++){\n if(t[i][j] == 'X' && ans[i][idx + j] != '.'){\n return false;\n }\n }\n }\n return true;\n}\n\nvoid draw(int idx, char ch){\n for(int i = 0; i < 5; i++){\n for(int j = 0; j < n; j++){\n if(t[i][j] == 'X'){\n ans[i][idx + j] = ch;\n }\n }\n }\n}\n\nvoid dfs(int idx, int cnt){\n if(cnt == 10){\n res = min(res, idx - 1);\n return;\n }\n if(idx > cnt * n || idx == res){\n return;\n }\n\n dfs(idx + 1, cnt);\n\n if(check(idx)){\n draw(idx, '0' + cnt);\n dfs(idx + 1, cnt + 1);\n draw(idx, '.');\n }\n}\n\nint main(){\n while(cin >> n, n){\n for(int i = 0; i < 5; i++){\n cin >> t[i];\n }\n memset(ans, '.', sizeof(ans));\n res = n * 10 - n;\n dfs(0, 0);\n cout << res + n << endl;\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 876, "score_of_the_acc": -0.0362, "final_rank": 2 }, { "submission_id": "aoj_1204_250870", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <complex>\n#include <queue>\n#include <map>\n#include <set>\n#include <cstring>\n#include <cstdlib>\n#include <string>\n#include <cmath>\n#include <bitset>\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(int)n;++i)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n#define ALL(c) (c).begin(), (c).end()\nconst int INF = 1<<29;\n\n\nint n;\nint dame;\n\nint rec(int S, int num) { // ツつサツづ個クツδ債ッツクツづタツスツクツづーツ始ツづ淞づァツづェツづ按つッツづェツづ篠ビツッツトツつェツ1\n// cout << bitset<7>(S) << \" \" << num << endl;\n if (num == 10) return n;\n int res = INF;\n for (int i=1;i<n;++i) {\n if (!(S >> i & 1)) {\n int tmp = S >> i;\n tmp |= dame;\n res = min(res, rec(tmp, num+1) + i);\n }\n }\n return res;\n}\n\nint main() {\n while(cin>>n,n) {\n int table[n];\n REP(i,5) {\n REP(j,n) {\n char c;\n cin >> c;\n if (c == 'X')\n table[j] = i; \n }\n }\n dame = 0;\n for (int i=1; i<n; ++i) {\n REP(j, i) {\n if (table[i] == table[j]) {\n dame |= 1 << i-j;\n }\n }\n }\n cout << rec(dame,1) << endl;\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 0, "score_of_the_acc": -0.0057, "final_rank": 1 }, { "submission_id": "aoj_1204_121463", "code_snippet": "#include <iostream>\n#include <queue>\nusing namespace std;\n\nint n;\nint data[5][20];\n\nclass State {\npublic:\n int clock;\n int cnt;\n int task[5][40];\n\n bool operator <(const State &s) const {\n return clock > s.clock;\n }\n\n State() {\n clock = 0;\n cnt = 0;\n for(int i = 0; i < 5; i++) {\n for(int j = 0; j < 40; j++) {\n\ttask[i][j] = 0;\n }\n }\n }\n\n bool isPut() {\n for(int i = 0; i < 5; i++) {\n for(int j = 0; j < n; j++) {\n\tif(data[i][j] == 1 && task[i][40-n+j] != 0) return false;\n }\n }\n return true;\n }\n\n void put() {\n for(int i = 0; i < 5; i++) {\n for(int j = 0; j < n; j++) {\n\ttask[i][40-n+j] += data[i][j];\n }\n }\n cnt++;\n }\n\n void shiftL() {\n for(int i = 0; i < 5; i++) {\n for(int j = 0; j < 40; j++) {\n\tif(j+1 == 40) task[i][j] = 0;\n\telse task[i][j] = task[i][j+1];\n }\n }\n clock++;\n }\n};\n\nvoid bfs() {\n priority_queue<State> PQ;\n State s;\n s.put();\n s.clock = n;\n PQ.push(s);\n while(!PQ.empty()) {\n s = PQ.top();\n PQ.pop();\n\n if(s.cnt == 10) {\n cout << s.clock << endl;\n break;\n }\n\n for(int i = 0; i < n; i++) {\n s.shiftL();\n State s2 = s;\n if(s2.isPut()) {\n\ts2.put();\n\tPQ.push(s2);\n }\n }\n }\n}\n\nint main() {\n while(1) {\n cin >> n;\n if(n == 0) break;\n for(int i = 0; i < 5; i++) {\n for(int j = 0; j < n; j++) {\n\tchar c;\n\tcin >> c;\n\tif(c == 'X') data[i][j] = 1;\n\telse data[i][j] = 0;\n }\n }\n\n bfs();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 12000, "score_of_the_acc": -0.4562, "final_rank": 13 }, { "submission_id": "aoj_1204_26646", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\n#define rep(i, n) for ( int i = 0; i < n; i++)\n#define MAX 20\n#define H 5\n#define N 10\n\nint n, minw;\nchar P[H][MAX], B[H][MAX*N];\n\nbool invalid(int p){\n rep(i, H) rep(j, n){\n\tif ( P[i][j] == 'X' && B[i][j+p] != '.' ) return true;\n }\n return false;\n}\n\nvoid setTask(int p, char ch){\n rep(i, H) for ( int j = p; j < p+n; j++ ){\n\tif ( P[i][j-p] == 'X' )\tB[i][j] = ch;\n }\n}\n\nvoid rec( int pos, int last){\n if ( pos == N ){ minw = min(minw, last+n); return; }\n if ( minw <= last+n-1 + (n-pos) ) return;\n for ( int j = last+1; j <= last+n; j++ ){\n\tif ( invalid(j) ) continue;\n\tsetTask(j, 'X');\n\trec(pos+1, j);\n\tsetTask(j, '.');\n }\n}\n\nvoid init(){\n minw = (1<<21);\n rep(i, H) rep(j, MAX*N) B[i][j] = '.';\n}\n\nmain(){\n while ( cin >> n && n ){\n\trep(i, H) rep(j, n) cin >> P[i][j];\n\tinit();\n\trec(0, -1);\n\tcout << minw << endl;\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 868, "score_of_the_acc": -0.0373, "final_rank": 3 } ]
aoj_1218_cpp
Problem C: Push!! Mr. Schwarz was a famous powerful pro wrestler. He starts a part time job as a warehouseman. His task is to move a cargo to a goal by repeatedly pushing the cargo in the warehouse, of course, without breaking the walls and the pillars of the warehouse. There may be some pillars in the warehouse. Except for the locations of the pillars, the floor of the warehouse is paved with square tiles whose size fits with the cargo. Each pillar occupies the same area as a tile. Initially, the cargo is on the center of a tile. With one push, he can move the cargo onto the center of an adjacent tile if he is in proper position. The tile onto which he will move the cargo must be one of (at most) four tiles (i.e., east, west, north or south) adjacent to the tile where the cargo is present. To push, he must also be on the tile adjacent to the present tile. He can only push the cargo in the same direction as he faces to it and he cannot pull it. So, when the cargo is on the tile next to a wall (or a pillar), he can only move it along the wall (or the pillar). Furthermore, once he places it on a corner tile, he cannot move it anymore. He can change his position, if there is a path to the position without obstacles (such as the cargo and pillars) in the way. The goal is not an obstacle. In addition, he can move only in the four directions (i.e., east, west, north or south) and change his direction only at the center of a tile. As he is not so young, he wants to save his energy by keeping the number of required pushes as small as possible. But he does not mind the count of his pedometer, because walking is very light exercise for him. Your job is to write a program that outputs the minimum number of pushes required to move the cargo to the goal, if ever possible. Input The input consists of multiple maps, each representing the size and the arrangement of the warehouse. A map is given in the following format. w h d 11 d 12 d 13 ... d 1 w d 21 d 22 d 23 ... d 2 w ... d h 1 d h 2 d h 3 ... d h w The integers w and h are the lengths of the two sides of the floor of the warehouse in terms of widths of floor tiles. w and h are less than or equal to 7. The integer d ij represents what is initially on the corresponding floor area in the following way. 0: nothing (simply a floor tile) 1: a pillar 2: the cargo 3: the goal 4: the warehouseman (Mr. Schwarz) Each of the integers 2, 3 and 4 appears exactly once as d ij in the map. Integer numbers in an input line are separated by at least one space character. The end of the input is indicated by a line containing two zeros. Output For each map, your program should output a line containing the minimum number of pushes. If the cargo cannot be moved to the goal, -1 should be output instead. Sample Input 5 5 0 0 0 0 0 4 2 0 1 1 0 1 0 0 0 1 0 0 0 3 1 0 0 0 0 5 3 4 0 0 0 0 2 0 0 0 0 0 0 0 0 3 7 5 1 1 4 1 0 0 0 1 1 2 1 0 0 0 3 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 1 0 0 0 6 6 0 0 0 0 0 3 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 ...(truncated)
[ { "submission_id": "aoj_1218_3807528", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\n\nconstexpr long double EPS = 1e-15;\nconst long double PI = acos(-1);\nconstexpr int inf = 2e9;\nconstexpr ll INF = 2e18;\nconstexpr ll MOD = 1e9+7;\nconstexpr ll MOD1 = 998244353;\ntypedef pair<ll,ll> P;\n\n//#define all(v) (v).begin(), (v).end()\n#define rep(i,a,b) for (int i = (a); i < (b); i++)\n#define REP(i,n) rep(i,0,n)\n#define sz(s) (s).size()\n#define pb push_back\n#define fi first\n#define se second\n//#define mp make_pair\n\nint w,h;\nint gh,gw;\nmap<string,int> mp;\nint dh[4] = {0,0,1,-1};\nint dw[4] = {1,-1,0,0};\n\nint id (int hh, int ww) {\n return w * hh + ww;\n}\n\nvoid out(string s) {\n REP(i,h) {\n REP(j,w) {\n cout << s[id(i,j)];\n }\n cout << endl;\n }\n cout << endl;\n}\n\nvoid solve() {\nwhile (cin >> w >> h) {\n if (w == 0 && h == 0) break;\n mp.clear();\n string s;\n REP(hh,h) {\n REP(ww,w) {\n char c;\n cin >> c;\n if (c == '3') {\n gh = hh;\n gw = ww;\n }\n s +=c;\n }\n }\n int ans = inf;\n mp[s] = 0;\n queue<pair<string,int>> que;\n que.push({s,0});\n while (!que.empty()) {\n string maze = que.front().fi;\n int cost = que.front().se;\n que.pop();\n if (cost > mp[maze]) continue;\n \n int hh = -1,ww;\n REP(i,h) {\n REP(j,w) {\n if (maze[id(i,j)] == '4') {\n hh = i;\n ww = j;\n break;\n }\n }\n if (hh != -1) break;\n }\n for (int i = 0; i < 4; i++) {\n\n int th = hh + dh[i];\n int tw = ww + dw[i];\n if (th < 0 || th >= h || tw < 0 || tw >= w) continue;\n if (maze[id(th,tw)] == '1') continue;\n\n if (maze[id(th,tw)] == '0' || maze[id(th,tw)] == '3') {\n string tmp = maze;\n swap(tmp[id(th,tw)], tmp[id(hh,ww)]);\n if (mp.count(tmp)) continue;\n mp[tmp] = cost;\n que.push({tmp, cost});\n }\n\n if (maze[id(th,tw)] == '2') {\n int tth = th + dh[i];\n int ttw = tw + dw[i];\n if (tth < 0 || tth >= h || ttw < 0 || ttw >= w) continue;\n if (maze[id(tth,ttw)] == '1') continue;\n string tmp = maze;\n swap(tmp[id(tth,ttw)], tmp[id(th,tw)]);\n swap(tmp[id(th,tw)], tmp[id(hh,ww)]);\n if (mp.count(tmp)) continue;\n mp[tmp] = cost + 1;\n if (tth == gh && ttw == gw) {\n ans = min(ans, cost + 1);\n continue;\n }\n que.push({tmp, cost + 1});\n }\n\n }\n }\n if (ans == inf) cout << -1 << endl;\n else cout << ans << endl;\n}\n}\n\n\nint main(int argc, char *argv[]){\n\n // /* Regular */\n // int case_num = 1;\n // if (argc > 1 && stoi(argv[1])) cin >> case_num;\n // REP(case_no, case_num) {\n // cerr << endl << \"case \" << case_no + 1 << endl;\n // solve();\n // }\n\n /* AOJ */\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 9176, "score_of_the_acc": -1.6, "final_rank": 11 }, { "submission_id": "aoj_1218_1571205", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <queue>\n#define f first\n#define s second\n#define INF (1e9)\n#define N 7\nusing namespace std;\ntypedef pair<int,int> P;\nint bfs(int,int,int,int,int,int);\nbool check(int,int,int,int,int,int);\nint w,h,data[N][N],d[N][N],cnt[N][N];\nint dy[4]={-1,0,1,0};\nint dx[4]={0,1,0,-1};\ntypedef struct data{\n int cy,cx,wy,wx;\n} dat;\n\nint main(){\n int sy,sx,gy,gx,wy,wx,ans;\n while(1){\n cin>>w>>h;\n if(!w&&!h) break;\n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++){\n\tcin >> data[i][j];\n\tif(data[i][j]==2) sy=i,sx=j;\n\telse if(data[i][j]==3) gy=i,gx=j;\n\telse if(data[i][j]==4) wy=i,wx=j;\n\td[i][j]=INF;\n }\n ans=bfs(sy,sx,wy,wx,gy,gx);\n cout << ans << endl;\n }\n return 0;\n}\n\nint bfs(int sy,int sx,int wy,int wx,int gy,int gx){\n queue<dat > q;\n int flag;\n dat k={sy,sx,wy,wx};\n q.push(k);\n d[sy][sx]=0;\n for(int i=0;i<N;i++)\n for(int j=0;j<N;j++) cnt[i][j]=0;\n while(!q.empty()){\n dat u=q.front();\n q.pop();\n flag=0;\n for(int i=0;i<4;i++){\n int ny=u.cy+dy[i],nx=u.cx+dx[i];\n if(ny<0||nx<0||h<=ny||w<=nx||data[ny][nx]==1) continue;\n if(check(u.wy,u.wx,u.cy-dy[i],u.cx-dx[i],u.cy,u.cx)){\n\td[ny][nx]=d[u.cy][u.cx]+1;\n\tcnt[nx][ny]++;\n\tif(cnt[nx][ny]==500){\n\t flag=1;\n\t break;\n\t}\n\tif(d[gy][gx]!=INF){\n\t flag=2;\n\t break;\n\t}\n\tdat t={ny,nx,u.cy-dy[i],u.cx-dx[i]};\n\tq.push(t);\n }\n }\n if(flag) break;\n }\n if(flag==2) return d[gy][gx];\n if(flag) return -1;\n if(d[gy][gx]!=INF) return d[gy][gx];\n return -1;\n}\n\nbool check(int sy,int sx,int gy,int gx,int xy,int xx){\n if(gy<0||gx<0||h<=gy||w<=gx) return false;\n if(data[gy][gx]==1) return false;\n bool c[N][N];\n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++) c[i][j]=false;\n queue<P > q;\n q.push(make_pair(sy,sx));\n c[sy][sx]=true;\n while(!q.empty()){\n P u=q.front();\n q.pop();\n for(int i=0;i<4;i++){\n int ny=u.f+dy[i],nx=u.s+dx[i];\n if(ny<0||nx<0||h<=ny||w<=nx||data[ny][nx]==1||(ny==xy&&nx==xx)) continue;\n if(c[ny][nx]==true) continue;\n c[ny][nx]=true;\n q.push(make_pair(ny,nx));\n }\n }\n if(c[gy][gx]==true) return true;\n return false;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1280, "score_of_the_acc": -0.014, "final_rank": 1 }, { "submission_id": "aoj_1218_1571195", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <queue>\n#define f first\n#define s second\n#define INF (1e9)\n#define N 7\nusing namespace std;\ntypedef pair<int,int> P;\nint bfs(int,int,int,int,int,int);\nbool check(int,int,int,int,int,int);\nint w,h,data[N][N],d[N][N],cnt[N][N];\nint dy[4]={-1,0,1,0};\nint dx[4]={0,1,0,-1};\ntypedef struct data{\n int cy,cx,wy,wx;\n} dat;\n\nint main(){\n int sy,sx,gy,gx,wy,wx,ans;\n while(1){\n cin>>w>>h;\n if(!w&&!h) break;\n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++){\n\tcin >> data[i][j];\n\tif(data[i][j]==2) sy=i,sx=j;\n\telse if(data[i][j]==3) gy=i,gx=j;\n\telse if(data[i][j]==4) wy=i,wx=j;\n\td[i][j]=INF;\n }\n ans=bfs(sy,sx,wy,wx,gy,gx);\n cout << ans << endl;\n }\n return 0;\n}\n\nint bfs(int sy,int sx,int wy,int wx,int gy,int gx){\n queue<dat > q;\n int flag;\n dat k={sy,sx,wy,wx};\n q.push(k);\n d[sy][sx]=0;\n for(int i=0;i<N;i++)\n for(int j=0;j<N;j++) cnt[i][j]=0;\n while(!q.empty()){\n dat u=q.front();\n q.pop();\n flag=0;\n for(int i=0;i<4;i++){\n int ny=u.cy+dy[i],nx=u.cx+dx[i];\n if(ny<0||nx<0||h<=ny||w<=nx||data[ny][nx]==1) continue;\n if(check(u.wy,u.wx,u.cy-dy[i],u.cx-dx[i],u.cy,u.cx)){\n\td[ny][nx]=d[u.cy][u.cx]+1;\n\tcnt[nx][ny]++;\n\tif(cnt[nx][ny]==1000){\n\t flag=1;\n\t break;\n\t}\n\tif(d[gy][gx]!=INF){\n\t flag=2;\n\t break;\n\t}\n\tdat t={ny,nx,u.cy-dy[i],u.cx-dx[i]};\n\tq.push(t);\n }\n }\n if(flag) break;\n }\n if(flag==2) return d[gy][gx];\n if(flag) return -1;\n if(d[gy][gx]!=INF) return d[gy][gx];\n return -1;\n}\n\nbool check(int sy,int sx,int gy,int gx,int xy,int xx){\n if(gy<0||gx<0||h<=gy||w<=gx) return false;\n if(data[gy][gx]==1) return false;\n bool c[N][N];\n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++) c[i][j]=false;\n queue<P > q;\n q.push(make_pair(sy,sx));\n c[sy][sx]=true;\n while(!q.empty()){\n P u=q.front();\n q.pop();\n for(int i=0;i<4;i++){\n int ny=u.f+dy[i],nx=u.s+dx[i];\n if(ny<0||nx<0||h<=ny||w<=nx||data[ny][nx]==1||(ny==xy&&nx==xx)) continue;\n if(c[ny][nx]==true) continue;\n c[ny][nx]=true;\n q.push(make_pair(ny,nx));\n }\n }\n if(c[gy][gx]==true) return true;\n return false;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1280, "score_of_the_acc": -0.014, "final_rank": 1 }, { "submission_id": "aoj_1218_1571192", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <queue>\n#define f first\n#define s second\n#define INF (1e9)\n#define N 7\nusing namespace std;\ntypedef pair<int,int> P;\nint bfs(int,int,int,int,int,int);\nbool check(int,int,int,int,int,int);\nint w,h,data[N][N],d[N][N],cnt[N][N];\nint dy[4]={-1,0,1,0};\nint dx[4]={0,1,0,-1};\ntypedef struct data{\n int cy,cx,wy,wx;\n} dat;\n\nint main(){\n int sy,sx,gy,gx,wy,wx,ans;\n while(1){\n cin>>w>>h;\n if(!w&&!h) break;\n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++){\n\tcin >> data[i][j];\n\tif(data[i][j]==2) sy=i,sx=j;\n\telse if(data[i][j]==3) gy=i,gx=j;\n\telse if(data[i][j]==4) wy=i,wx=j;\n\td[i][j]=INF;\n }\n ans=bfs(sy,sx,wy,wx,gy,gx);\n cout << ans << endl;\n }\n return 0;\n}\n\nint bfs(int sy,int sx,int wy,int wx,int gy,int gx){\n queue<dat > q;\n int flag;\n dat k={sy,sx,wy,wx};\n q.push(k);\n d[sy][sx]=0;\n for(int i=0;i<N;i++)\n for(int j=0;j<N;j++) cnt[i][j]=0;\n while(!q.empty()){\n dat u=q.front();\n q.pop();\n flag=0;\n for(int i=0;i<4;i++){\n int ny=u.cy+dy[i],nx=u.cx+dx[i];\n if(ny<0||nx<0||h<=ny||w<=nx||data[ny][nx]==1) continue;\n if(check(u.wy,u.wx,u.cy-dy[i],u.cx-dx[i],u.cy,u.cx)){\n\td[ny][nx]=d[u.cy][u.cx]+1;\n\tcnt[nx][ny]++;\n\tif(cnt[nx][ny]==10000){\n\t flag=1;\n\t break;\n\t}\n\tif(d[gy][gx]!=INF){\n\t flag=2;\n\t break;\n\t}\n\tdat t={ny,nx,u.cy-dy[i],u.cx-dx[i]};\n\tq.push(t);\n }\n }\n if(flag) break;\n }\n if(flag==2) return d[gy][gx];\n if(flag) return -1;\n if(d[gy][gx]!=INF) return d[gy][gx];\n return -1;\n}\n\nbool check(int sy,int sx,int gy,int gx,int xy,int xx){\n if(gy<0||gx<0||h<=gy||w<=gx) return false;\n if(data[gy][gx]==1) return false;\n bool c[N][N];\n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++) c[i][j]=false;\n queue<P > q;\n q.push(make_pair(sy,sx));\n c[sy][sx]=true;\n while(!q.empty()){\n P u=q.front();\n q.pop();\n for(int i=0;i<4;i++){\n int ny=u.f+dy[i],nx=u.s+dx[i];\n if(ny<0||nx<0||h<=ny||w<=nx||data[ny][nx]==1||(ny==xy&&nx==xx)) continue;\n if(c[ny][nx]==true) continue;\n c[ny][nx]=true;\n q.push(make_pair(ny,nx));\n }\n }\n if(c[gy][gx]==true) return true;\n return false;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1356, "score_of_the_acc": -0.0901, "final_rank": 5 }, { "submission_id": "aoj_1218_1571190", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <queue>\n#define f first\n#define s second\n#define INF (1e9)\n#define N 7\nusing namespace std;\ntypedef pair<int,int> P;\nint bfs(int,int,int,int,int,int);\nbool check(int,int,int,int,int,int);\nint w,h,data[N][N],d[N][N],cnt[N][N];\nint dy[4]={-1,0,1,0};\nint dx[4]={0,1,0,-1};\ntypedef struct data{\n int cy,cx,wy,wx;\n} dat;\n\nint main(){\n int sy,sx,gy,gx,wy,wx,ans;\n while(1){\n cin>>w>>h;\n if(!w&&!h) break;\n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++){\n\tcin >> data[i][j];\n\tif(data[i][j]==2) sy=i,sx=j;\n\telse if(data[i][j]==3) gy=i,gx=j;\n\telse if(data[i][j]==4) wy=i,wx=j;\n\td[i][j]=INF;\n }\n ans=bfs(sy,sx,wy,wx,gy,gx);\n cout << ans << endl;\n }\n return 0;\n}\n\nint bfs(int sy,int sx,int wy,int wx,int gy,int gx){\n queue<dat > q;\n int flag;\n dat k={sy,sx,wy,wx};\n q.push(k);\n d[sy][sx]=0;\n for(int i=0;i<N;i++)\n for(int j=0;j<N;j++) cnt[i][j]=0;\n while(!q.empty()){\n dat u=q.front();\n q.pop();\n flag=0;\n for(int i=0;i<4;i++){\n int ny=u.cy+dy[i],nx=u.cx+dx[i];\n if(ny<0||nx<0||h<=ny||w<=nx||data[ny][nx]==1) continue;\n if(check(u.wy,u.wx,u.cy-dy[i],u.cx-dx[i],u.cy,u.cx)){\n\td[ny][nx]=d[u.cy][u.cx]+1;\n\tcnt[nx][ny]++;\n\tif(cnt[nx][ny]==100000){\n\t flag=1;\n\t break;\n\t}\n\tif(d[gy][gx]!=INF){\n\t flag=2;\n\t break;\n\t}\n\tdat t={ny,nx,u.cy-dy[i],u.cx-dx[i]};\n\tq.push(t);\n }\n }\n if(flag) break;\n }\n if(flag==2) return d[gy][gx];\n if(flag) return -1;\n if(d[gy][gx]!=INF) return d[gy][gx];\n return -1;\n}\n\nbool check(int sy,int sx,int gy,int gx,int xy,int xx){\n if(gy<0||gx<0||h<=gy||w<=gx) return false;\n if(data[gy][gx]==1) return false;\n bool c[N][N];\n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++) c[i][j]=false;\n queue<P > q;\n q.push(make_pair(sy,sx));\n c[sy][sx]=true;\n while(!q.empty()){\n P u=q.front();\n q.pop();\n for(int i=0;i<4;i++){\n int ny=u.f+dy[i],nx=u.s+dx[i];\n if(ny<0||nx<0||h<=ny||w<=nx||data[ny][nx]==1||(ny==xy&&nx==xx)) continue;\n if(c[ny][nx]==true) continue;\n c[ny][nx]=true;\n q.push(make_pair(ny,nx));\n }\n }\n if(c[gy][gx]==true) return true;\n return false;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 3692, "score_of_the_acc": -1.0152, "final_rank": 10 }, { "submission_id": "aoj_1218_808767", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <queue>\n\nusing namespace std;\n\ntypedef pair<int, int> P;\n\nconst int dx[] = {1, 0, -1, 0};\nconst int dy[] = {0, 1, 0, -1};\n\nint H, W;\nint field[8][8];\nbool arrive[8][8][8][8][8][8];\n\nvoid init(){\n memset(field, 0, sizeof(field));\n memset(arrive, false, sizeof(arrive));\n}\n\nvoid canArrive(int bx, int by, int sx, int sy){\n int tmp_field[8][8];\n memset(tmp_field, 0, sizeof(tmp_field));\n for(int i = 0 ; i < H ; i++){\n for(int j = 0 ; j < W ; j++){\n if(field[i][j] != 1) tmp_field[i][j] = 0;\n else tmp_field[i][j] = field[i][j];\n }\n }\n \n tmp_field[by][bx] = 2;\n\n queue<P> que;\n que.push(P(sx, sy));\n while(!que.empty()){\n P q = que.front(); que.pop();\n arrive[by][bx][sy][sx][q.second][q.first] = true;\n \n for(int i = 0 ; i < 4 ; i++){\n int nx = q.first + dx[i], ny = q.second + dy[i];\n if(nx < 0 || nx >= W || ny < 0 || ny >= H) continue;\n if(tmp_field[ny][nx] != 0) continue;\n if(arrive[by][bx][sy][sx][ny][nx]) continue;\n que.push(P(nx, ny));\n } \n }\n}\n\nstruct State{\n int x, y, sx, sy, cost;\n State(int x, int y, int sx, int sy, int cost) : x(x), y(y), sx(sx), sy(sy), cost(cost){}\n};\n\nconst bool operator < (const State &a, const State &b){\n return a.cost > b.cost;\n}\n\nint bfs(){\n int sx, sy, bx, by;\n for(int i = 0 ; i < H ; i++){\n for(int j = 0 ; j < W ; j++){\n if(field[i][j] == 2) bx = j, by = i;\n if(field[i][j] == 4) sx = j, sy = i;\n }\n }\n \n priority_queue<State> que;\n que.push(State(bx, by, sx, sy, 0));\n \n bool used[8][8][8][8];\n memset(used, false, sizeof(used));\n \n while(!que.empty()){\n State p = que.top(); que.pop();\n\n if(field[p.y][p.x] == 3) return p.cost; \n\n if(used[p.y][p.x][p.sy][p.sx]) continue;\n used[p.y][p.x][p.sy][p.sx] = true;\n \n for(int i = 0 ; i < 4 ; i++){\n int nx1, nx2, ny1, ny2;\n nx1 = p.x + dx[i], ny1 = p.y + dy[i];\n nx2 = p.x - dx[i], ny2 = p.y - dy[i];\n if(nx1 < 0 || nx1 >= W || ny1 < 0 || ny1 >= H ||\n\t nx2 < 0 || nx2 >= W || ny2 < 0 || ny2 >= H) continue;\n if(field[ny1][nx1] == 1) continue;\n if(field[ny2][nx2] == 1) continue;\n if(!arrive[p.y][p.x][p.sy][p.sx][ny2][nx2]) continue; \n que.push(State(nx1, ny1, nx2, ny2, p.cost+1));\n } \n }\n return -1;\n}\n\nint main(){\n while(cin >> W >> H, W|H){\n init();\n \n for(int i = 0 ; i < H ; i++)\n for(int j = 0 ; j < W ; j++) cin >> field[i][j];\n \n for(int by = 0 ; by < H ; by++){\n for(int bx = 0 ; bx < W ; bx++){\n\tif(field[by][bx] == 1) continue;\n\tfor(int sy = 0 ; sy < H ; sy++){\n\t for(int sx = 0 ; sx < W ; sx++){\n\t if(sy == by && sx == bx) continue;\n\t if(field[sy][sx] == 1) continue;\n\t canArrive(bx, by, sx, sy);\n\t }\n\t}\n }\n }\n cout << bfs() << endl; \n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1492, "score_of_the_acc": -0.1071, "final_rank": 6 }, { "submission_id": "aoj_1218_808766", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <queue>\n\nusing namespace std;\n\ntypedef pair<int, int> P;\n\nconst int dx[] = {1, 0, -1, 0};\nconst int dy[] = {0, 1, 0, -1};\n\nint H, W;\nint field[8][8];\nbool arrive[8][8][8][8][8][8];\n\nvoid init(){\n memset(field, 0, sizeof(field));\n memset(arrive, false, sizeof(arrive));\n}\n\nbool canArrive(int bx, int by, int sx, int sy){\n int tmp_field[8][8];\n memset(tmp_field, 0, sizeof(tmp_field));\n for(int i = 0 ; i < H ; i++){\n for(int j = 0 ; j < W ; j++){\n if(field[i][j] != 1) tmp_field[i][j] = 0;\n else tmp_field[i][j] = field[i][j];\n }\n }\n \n tmp_field[by][bx] = 2;\n\n queue<P> que;\n que.push(P(sx, sy));\n while(!que.empty()){\n P q = que.front(); que.pop();\n arrive[by][bx][sy][sx][q.second][q.first] = true;\n \n for(int i = 0 ; i < 4 ; i++){\n int nx = q.first + dx[i], ny = q.second + dy[i];\n if(nx < 0 || nx >= W || ny < 0 || ny >= H) continue;\n if(tmp_field[ny][nx] != 0) continue;\n if(arrive[by][bx][sy][sx][ny][nx]) continue;\n que.push(P(nx, ny));\n } \n }\n}\n\n\nstruct State{\n int x, y, sx, sy, cost;\n State(int x, int y, int sx, int sy, int cost) : x(x), y(y), sx(sx), sy(sy), cost(cost){}\n};\n\nconst bool operator < (const State &a, const State &b){\n return a.cost > b.cost;\n}\n\nint bfs(){\n int sx, sy, bx, by;\n for(int i = 0 ; i < H ; i++){\n for(int j = 0 ; j < W ; j++){\n if(field[i][j] == 2) bx = j, by = i;\n if(field[i][j] == 4) sx = j, sy = i;\n }\n }\n \n priority_queue<State> que;\n que.push(State(bx, by, sx, sy, 0));\n \n bool used[8][8][8][8];\n memset(used, false, sizeof(used));\n \n while(!que.empty()){\n State p = que.top(); que.pop();\n\n if(field[p.y][p.x] == 3) return p.cost; \n\n if(used[p.y][p.x][p.sy][p.sx]) continue;\n used[p.y][p.x][p.sy][p.sx] = true;\n \n for(int i = 0 ; i < 4 ; i++){\n int nx1, nx2, ny1, ny2;\n nx1 = p.x + dx[i], ny1 = p.y + dy[i];\n nx2 = p.x - dx[i], ny2 = p.y - dy[i];\n if(nx1 < 0 || nx1 >= W || ny1 < 0 || ny1 >= H ||\n\t nx2 < 0 || nx2 >= W || ny2 < 0 || ny2 >= H) continue;\n if(field[ny1][nx1] == 1) continue;\n if(field[ny2][nx2] == 1) continue;\n if(!arrive[p.y][p.x][p.sy][p.sx][ny2][nx2]) continue; \n que.push(State(nx1, ny1, nx2, ny2, p.cost+1));\n } \n }\n return -1;\n}\n\nint main(){\n while(cin >> W >> H, W|H){\n init();\n \n for(int i = 0 ; i < H ; i++)\n for(int j = 0 ; j < W ; j++) cin >> field[i][j];\n \n for(int by = 0 ; by < H ; by++){\n for(int bx = 0 ; bx < W ; bx++){\n\tif(field[by][bx] == 1) continue;\n\tfor(int sy = 0 ; sy < H ; sy++){\n\t for(int sx = 0 ; sx < W ; sx++){\n\t if(sy == by && sx == bx) continue;\n\t if(field[sy][sx] == 1) continue;\n\t canArrive(bx, by, sx, sy);\n\t }\n\t}\n }\n }\n\n cout << bfs() << endl;\n \n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1488, "score_of_the_acc": -0.0733, "final_rank": 3 }, { "submission_id": "aoj_1218_808764", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <queue>\n\nusing namespace std;\n\ntypedef pair<int, int> P;\n\nconst int dx[] = {1, 0, -1, 0};\nconst int dy[] = {0, 1, 0, -1};\n\nint H, W;\nint field[8][8];\nbool arrive[8][8][8][8][8][8];\n\nvoid init(){\n memset(field, 0, sizeof(field));\n memset(arrive, false, sizeof(arrive));\n}\n\nvoid canArrive(int bx, int by, int sx, int sy){\n int tmp_field[8][8];\n memset(tmp_field, 0, sizeof(tmp_field));\n for(int i = 0 ; i < H ; i++){\n for(int j = 0 ; j < W ; j++){\n if(field[i][j] != 1) tmp_field[i][j] = 0;\n else tmp_field[i][j] = field[i][j];\n }\n }\n \n tmp_field[by][bx] = 2;\n\n queue<P> que;\n que.push(P(sx, sy));\n while(!que.empty()){\n P q = que.front(); que.pop();\n arrive[by][bx][sy][sx][q.second][q.first] = true;\n \n for(int i = 0 ; i < 4 ; i++){\n int nx = q.first + dx[i], ny = q.second + dy[i];\n if(nx < 0 || nx >= W || ny < 0 || ny >= H) continue;\n if(tmp_field[ny][nx] != 0) continue;\n if(arrive[by][bx][sy][sx][ny][nx]) continue;\n que.push(P(nx, ny));\n } \n }\n}\n\n\nstruct State{\n int x, y, sx, sy, cost;\n State(int x, int y, int sx, int sy, int cost) : x(x), y(y), sx(sx), sy(sy), cost(cost){}\n};\n\nconst bool operator < (const State &a, const State &b){\n return a.cost > b.cost;\n}\n\nint bfs(){\n int sx, sy, bx, by;\n for(int i = 0 ; i < H ; i++){\n for(int j = 0 ; j < W ; j++){\n if(field[i][j] == 2) bx = j, by = i;\n if(field[i][j] == 4) sx = j, sy = i;\n }\n }\n \n priority_queue<State> que;\n que.push(State(bx, by, sx, sy, 0));\n \n bool used[8][8][8][8];\n memset(used, false, sizeof(used));\n \n while(!que.empty()){\n State p = que.top(); que.pop();\n\n if(field[p.y][p.x] == 3) return p.cost; \n\n if(used[p.y][p.x][p.sy][p.sx]) continue;\n used[p.y][p.x][p.sy][p.sx] = true;\n \n for(int i = 0 ; i < 4 ; i++){\n int nx1, nx2, ny1, ny2;\n nx1 = p.x + dx[i], ny1 = p.y + dy[i];\n nx2 = p.x - dx[i], ny2 = p.y - dy[i];\n if(nx1 < 0 || nx1 >= W || ny1 < 0 || ny1 >= H ||\n\t nx2 < 0 || nx2 >= W || ny2 < 0 || ny2 >= H) continue;\n if(field[ny1][nx1] == 1) continue;\n if(field[ny2][nx2] == 1) continue;\n if(!arrive[p.y][p.x][p.sy][p.sx][ny2][nx2]) continue; \n que.push(State(nx1, ny1, nx2, ny2, p.cost+1));\n } \n }\n return -1;\n}\n\nint main(){\n while(cin >> W >> H, W|H){\n init();\n \n for(int i = 0 ; i < H ; i++)\n for(int j = 0 ; j < W ; j++) cin >> field[i][j];\n \n for(int by = 0 ; by < H ; by++){\n for(int bx = 0 ; bx < W ; bx++){\n\tif(field[by][bx] == 1) continue;\n\tfor(int sy = 0 ; sy < H ; sy++){\n\t for(int sx = 0 ; sx < W ; sx++){\n\t if(sy == by && sx == bx) continue;\n\t if(field[sy][sx] == 1) continue;\n\t canArrive(bx, by, sx, sy);\n\t }\n\t}\n }\n }\n\n cout << bfs() << endl;\n \n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1492, "score_of_the_acc": -0.1071, "final_rank": 6 }, { "submission_id": "aoj_1218_743099", "code_snippet": "#include<iostream>\n#include<vector>\n#include<queue>\n#include<algorithm>\n#include<string>\n#include<sstream>\n#include<cmath>\nusing namespace std;\n#define REP(i, j) for(int i = 0; i < j; i++)\n#define FOR(i, j, k) for(int i = j; i < k; i++)\nconst int H = 7;\nconst int W = 7;\nconst int P = H * W + 10;\nconst int INF = P * P;\n\nclass C{\n public:\n int y, x, cy, cx, s, p;\n C(int _y, int _x, int _cy, int _cx, int _s, int _p){\n y = _y;\n x = _x;\n cy = _cy;\n cx = _cx;\n s = _s;\n p = _p;\n }\n bool operator >(const C c) const{\n return p > c.p;\n }\n};\n\nint w, h;\n\nint main(){\n while(cin >>w >>h && w){\n vector< vector<int> > v(h, vector<int>(w));\n int sy, sx, scy, scx;\n REP(i, h){\n REP(j, w){\n cin >>v[i][j];\n if(v[i][j] == 4){\n sy = i;\n sx = j;\n v[i][j] = 0;\n }\n if(v[i][j] == 2){\n scy = i;\n scx = j;\n v[i][j] = 0;\n }\n }\n }\n\n int ans = -1;\n priority_queue<C, vector<C>, greater<C> > open;\n open.push( C(sy, sx, scy, scx, 0, 0) );\n int closed[P][H][W][H][W];\n REP(i, P) REP(j, H) REP(k, W) REP(l, H) REP(m, W) closed[i][j][k][l][m] = INF;\n\n\n while(!open.empty()){\n C now = open.top();\n open.pop();\n\n //debug\n //cout <<now.y <<\" \" <<now.x <<\" \" <<now.cy <<\" \" <<now.cx <<\" \" <<now.s <<\" \" <<now.p <<endl;\n\n if(v[now.cy][now.cx] == 3){\n ans = now.p;\n break;\n }\n\n //debug\n //cout <<\"step 1\" <<endl;\n //cout <<now.s <<\" \" <<closed[now.p][now.y][now.x][now.cy][now.cx] <<endl;\n\n if(now.s >= closed[now.p][now.y][now.x][now.cy][now.cx]) continue;\n closed[now.p][now.y][now.x][now.cy][now.cx] = now.s;\n\n //debug\n //cout <<\"step 2\" <<endl;\n\n int my[] = {1, -1, 0, 0};\n int mx[] = {0, 0, 1, -1};\n REP(i, 4){\n int ny = now.y + my[i];\n int nx = now.x + mx[i];\n if(ny < 0 || nx < 0 || ny >= h || nx >= w || v[ny][nx] == 1) continue;\n if(ny == now.cy && nx == now.cx){\n int ncy = ny + my[i];\n int ncx = nx + mx[i];\n if(ncy < 0 || ncx < 0 || ncy >= h || ncx >= w || v[ncy][ncx] == 1) continue;\n open.push( C(ny, nx, ncy, ncx, now.s + 1, now.p + 1) );\n } else{\n open.push( C(ny, nx, now.cy, now.cx, now.s + 1, now.p) );\n }\n }\n }\n\n cout <<ans <<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1796, "score_of_the_acc": -0.0784, "final_rank": 4 }, { "submission_id": "aoj_1218_493737", "code_snippet": "//42\n#include<iostream>\n#include<algorithm>\n\nusing namespace std;\n\nint main(){\n for(int w,h;cin>>w>>h,w|h;){\n int g[7][7];\n int wx,wy,cx,cy,gx,gy;\n for(int i=0;i<h;i++){\n for(int j=0;j<w;j++){\n\tcin>>g[i][j];\n\tif(g[i][j]==2){\n\t cx=j;\n\t cy=i;\n\t}else if(g[i][j]==4){\n\t wx=j;\n\t wy=i;\n\t}else if(g[i][j]==3){\n\t gx=j;\n\t gy=i;\n\t}\n }\n }\n int d[7][7][7][7];\n fill(d[0][0][0],d[7][0][0],1<<30);\n d[cy][cx][wy][wx]=0;\n for(int i=0;i<w*w*h*h;i++){\n for(int j=0;j<h;j++){\n\tfor(int k=0;k<w;k++){\n\t for(int l=0;l<h;l++){\n\t for(int m=0;m<w;m++){\n\t for(int n=0;n<4;n++){\n\t\tint dd[]={0,1,0,-1,0};\n\t\tint ny=l+dd[n];\n\t\tint nx=m+dd[n+1];\n\t\tif(0<=nx&&nx<w&&0<=ny&&ny<h&&g[ny][nx]!=1){\n\t\t if(ny!=j||nx!=k){\n\t\t d[j][k][ny][nx]=min(d[j][k][ny][nx],d[j][k][l][m]);\n\t\t }else{\n\t\t int nny=ny+dd[n];\n\t\t int nnx=nx+dd[n+1];\n\t\t if(0<=nny&&nny<h&&0<=nnx&&nnx<w&&g[nny][nnx]!=1){\n\t\t d[nny][nnx][ny][nx]=min(d[nny][nnx][ny][nx],d[j][k][l][m]+1);\n\t\t }\n\t\t }\n\t\t}\n\t }\n\t }\n\t }\n\t}\n }\n }\n int me=*min_element(d[gy][gx][0],d[gy][gx+1][0]);\n cout<<((me==1<<30)?-1:me)<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 1168, "score_of_the_acc": -1, "final_rank": 9 }, { "submission_id": "aoj_1218_285716", "code_snippet": "#include <iostream>\n#include <queue>\n#include <vector>\n#include <algorithm>\n#include <cstring>\n\nusing namespace std;\n\nconst int dy[]={-1,0,0,1};\nconst int dx[]={0,-1,1,0};\n\nint main(){\n\n int w,h;\n int field[20][20];\n while(cin>>w>>h&&!(w==0&&h==0)){\n int gy,gx,sy,sx;\n int mx,my;\n for(int i = 0; i < h; i++){\n for(int j = 0; j < w; j++){\n cin>>field[i][j];\n if(field[i][j]==3){\n gy=i;\n gx=j;\n }\n else if(field[i][j]==2){\n sy=i;\n sx=j;\n }\n else if(field[i][j]==4){\n mx=j;\n my=i;\n }\n if(field[i][j]!=1)\n field[i][j]=0;\n }\n }\n queue<pair<int,pair<pair<int,int>,pair<int,int> > > > *prv=new queue<pair<int,pair<pair<int,int>,pair<int,int> > > > ();\n queue<pair<int,pair<pair<int,int>,pair<int,int> > > > *nxt=new queue<pair<int,pair<pair<int,int>,pair<int,int> > > > ();\n prv->push(make_pair(0,make_pair(make_pair(sy,sx),make_pair(my,mx))));\n bool passed[100][10][10][10][10];\n memset(passed,0,sizeof(passed));\n passed[0][sy][sx][my][mx]=true;\n int time=0;\n const int INF=1000000000;\n int minTime=INF;\n while(prv->size()){\n while(prv->size()){\n pair<int,int> ccp=prv->front().second.first;\n pair<int,int> cmp=prv->front().second.second;\n int cnt=prv->front().first;\n prv->pop();\n if(ccp.first==gy&&ccp.second==gx)\n minTime=min(minTime,cnt);\n // l‚𒆐S‚ɍl‚¦‚é\n for(int i = 0; i < 4; i++){\n int ny=dy[i]+cmp.first;\n int nx=dx[i]+cmp.second;\n if(ny>=0&&nx>=0&&nx<w&&ny<h&&field[ny][nx]==0){\n // ‚»‚̏ꏊ‚ɉו¨‚ª‚ ‚é‚©‚Ç‚¤‚©\n if(!(ccp.first==ny&&ccp.second==nx)){\n if(!passed[cnt][ccp.first][ccp.second][ny][nx]){\n passed[cnt][ccp.first][ccp.second][ny][nx]=true;\n nxt->push(make_pair(cnt,make_pair(ccp,make_pair(ny,nx))));\n }\n }\n // ‰×•¨‚ª‚ ‚é‚È‚çA‰×•¨‚ð“®‚©‚¹‚éê‡A“®‚©‚·\n else{\n int nccy=ccp.first+dy[i];\n int nccx=ccp.second+dx[i];\n if(cnt<99&&nccy>=0&&nccx>=0&&nccy<h&&nccx<w&&field[nccy][nccx]==0){\n if(!passed[cnt+1][nccy][nccx][ny][nx]){\n passed[cnt+1][nccy][nccx][ny][nx]=true;\n nxt->push(make_pair(cnt+1,make_pair(make_pair(nccy,nccx),make_pair(ny,nx))));\n }\n }\n }\n }\n }\n }\n time++;\n swap(prv,nxt);\n }\n if(minTime==INF)cout<<-1<<endl;\n else cout<<minTime<<endl;\n delete prv;\n delete nxt;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1892, "score_of_the_acc": -0.1237, "final_rank": 8 } ]
aoj_1216_cpp
Problem A: Lost in Space William Robinson was completely puzzled in the music room; he could not find his triangle in his bag. He was sure that he had prepared it the night before. He remembered its clank when he had stepped on the school bus early that morning. No, not in his dream. His triangle was quite unique: no two sides had the same length, which made his favorite peculiar jingle. He insisted to the music teacher, Mr. Smith, that his triangle had probably been stolen by those aliens and thrown away into deep space. Your mission is to help Will find his triangle in space. His triangle has been made invisible by the aliens, but candidate positions of its vertices are somehow known. You have to tell which three of them make his triangle. Having gone through worm-holes, the triangle may have changed its size. However, even in that case, all the sides are known to be enlarged or shrunk equally, that is, the transformed triangle is similar to the original. Input The very first line of the input has an integer which is the number of data sets. Each data set gives data for one incident such as that of Will’s. At least one and at most ten data sets are given. The first line of each data set contains three decimals that give lengths of the sides of the original triangle, measured in centimeters. Three vertices of the original triangle are named P, Q, and R. Three decimals given in the first line correspond to the lengths of sides QR, RP, and PQ, in this order. They are separated by one or more space characters. The second line of a data set has an integer which is the number of points in space to be considered as candidates for vertices. At least three and at most thirty points are considered. The rest of the data set are lines containing coordinates of candidate points, in light years. Each line has three decimals, corresponding to x, y, and z coordinates, separated by one or more space characters. Points are numbered in the order of their appearances, starting from one. Among all the triangles formed by three of the given points, only one of them is similar to the original, that is, ratios of the lengths of any two sides are equal to the corresponding ratios of the original allowing an error of less than 0.01 percent. Other triangles have some of the ratios different from the original by at least 0.1 percent. The origin of the coordinate system is not the center of the earth but the center of our galaxy. Note that negative coordinate values may appear here. As they are all within or close to our galaxy, coordinate values are less than one hundred thousand light years. You don’t have to take relativistic effects into account, i.e., you may assume that we are in a Euclidean space. You may also assume in your calculation that one light year is equal to 9.461 × 10 12 kilometers. A succeeding data set, if any, starts from the line immediately following the last line of the preceding data set. Output For each data set, one line should be output. That li ...(truncated)
[ { "submission_id": "aoj_1216_3807101", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <numeric>\n\n#define REP(i, a, b) for (int i = int(a); i < int(b); i++)\nusing namespace std;\ntypedef long long int ll;\n\n// clang-format off\n#ifdef _DEBUG_\n#define dump(...) do{ cerr << __LINE__ << \":\\t\" << #__VA_ARGS__ << \" = \"; PPPPP(__VA_ARGS__); cerr << endl; } while(false)\ntemplate<typename T> void PPPPP(T t) { cerr << t; }\ntemplate<typename T, typename... S> void PPPPP(T t, S... s) { cerr << t << \", \"; PPPPP(s...); }\n#else\n#define dump(...)\n#endif\ntemplate<typename T> vector<T> make_v(size_t a, T b) { return vector<T>(a, b); }\ntemplate<typename... Ts> auto make_v(size_t a, Ts... ts) { return vector<decltype(make_v(ts...))>(a, make_v(ts...)); }\ntemplate<typename T>\nbool chmin(T &a, T b) { if (a > b) {a = b; return true; } return false;}\ntemplate<typename T>\nbool chmax(T &a, T b) { if (a < b) {a = b; return true; } return false;}\n// clang-format on\n\n#include <valarray>\n#include <cmath>\n\ndouble calc(valarray<double> p1, valarray<double> p2) {\n double res = 0.0;\n REP (i, 0, 3) {\n res += pow(p1[i] - p2[i], 2);\n }\n return sqrt(res);\n}\n\nvoid subMain() {\n valarray<double> len(3);\n REP(i, 0, 3) {\n cin >> len[i];\n }\n int n;\n cin >> n;\n vector<valarray<double>> point(n, valarray<double>(3));\n REP(i, 0, n) {\n REP(j, 0, 3) {\n cin >> point[i][j];\n }\n }\n REP(i, 0, n) {\n REP(j, 0, n) {\n REP(k, 0, n) {\n if (i == j || j == k || k == i) continue;\n valarray<double> res = {\n calc(point[i], point[j]),\n calc(point[j], point[k]),\n calc(point[k], point[i]),\n };\n res /= len;\n double eps = 1e-3;\n if (abs(res[0] - res[1]) <= eps && abs(res[0] - res[2]) <= eps && abs(res[1] - res[2]) <= eps) {\n cout << k + 1 << \" \" << i + 1 << \" \" << j + 1 << endl;\n return;\n }\n }\n }\n }\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int T;\n cin >> T;\n REP(t, 0, T) {\n subMain();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3284, "score_of_the_acc": -0.9739, "final_rank": 17 }, { "submission_id": "aoj_1216_2376234", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct P{\n double x, y, z;\n P():x(0), y(0), z(0){}\n P(double x, double y, double z):x(x), y(y), z(z){}\n P operator+(const P& b)const{\n P res;\n res.x = x + b.x;\n res.y = y + b.y;\n res.z = z + b.z;\n return res;\n }\n P operator-(const P& b)const{\n P res;\n res.x = x - b.x;\n res.y = y - b.y;\n res.z = z - b.z;\n return res;\n }\n bool operator<(const P& b)const{\n if(x == b.x)\n if(y == b.y)\n return z < b.z;\n else\n return y < b.y;\n else\n return x < b.x;\n }\n};\n\nbool eq(double a, double b){\n return abs(a-b) < 0.0001;\n}\n\n// Experimence\nint main(void){\n int T; cin >> T;\n while(T--){\n double QR, RP, PQ; cin >> QR >> RP >> PQ;\n double P_arg = acos((PQ*PQ+RP*RP-QR*QR) / (2*PQ*RP));\n double Q_arg = acos((PQ*PQ+QR*QR-RP*RP) / (2*PQ*QR));\n double R_arg = acos((QR*QR+RP*RP-PQ*PQ) / (2*QR*RP));\n int N; cin >> N;\n vector<P> points(N);\n for(int i = 0; i < N; i++){\n cin >> points[i].x >> points[i].y >> points[i].z;\n }\n for(int i = 0; i < N; i++){\n for(int j = 0; j < N; j++){\n for(int k = 0; k < N; k++){\n if(i == j || j == k || i == k) continue;\n vector<P> triangle(3);\n triangle[0] = points[i];\n triangle[1] = points[j];\n triangle[2] = points[k];\n\n //do{\n vector<double> edge(3);\n for(int edge_idx = 0; edge_idx < 3; edge_idx++){\n P subtract = triangle[edge_idx%3] - triangle[(edge_idx+1)%3];\n edge[edge_idx] = sqrt(subtract.x*subtract.x + subtract.y*subtract.y + subtract.z*subtract.z);\n }\n double arg1, arg2, arg3;\n arg1 = acos((edge[0]*edge[0]+edge[2]*edge[2]-edge[1]*edge[1]) / (2*edge[0]*edge[2]));\n arg2 = acos((edge[0]*edge[0]+edge[1]*edge[1]-edge[2]*edge[2]) / (2*edge[0]*edge[1]));\n arg3 = acos((edge[1]*edge[1]+edge[2]*edge[2]-edge[0]*edge[0]) / (2*edge[1]*edge[2]));\n //DEBUG\n if(eq(P_arg, arg1) && eq(Q_arg, arg2) && eq(R_arg, arg3)){\n cout << i+1 << \" \" << j+1 << \" \" << k+1 << endl;\n i = N; j = N; k = N;\n }\n //}while(next_permutation(triangle.begin(), triangle.end()));\n\n //cout << i << j << k << endl;\n }\n }\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3372, "score_of_the_acc": -1.5, "final_rank": 20 }, { "submission_id": "aoj_1216_1893151", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\n#include<algorithm>\t\n#include<map>\n#include<set>\n#include<utility>\n#include<cmath>\n#include<cstring>\n#include<queue>\n#include<cstdio>\n#include<sstream>\n#include<iomanip>\n#define loop(i,a,b) for(int i=a;i<b;i++) \n#define rep(i,a) loop(i,0,a)\n#define pb push_back\n#define mp make_pair\n#define all(in) in.begin(),in.end()\n#define shosu(x) fixed<<setprecision(x)\nusing namespace std;\n//kaewasuretyuui\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<pii> vp;\ntypedef vector<vp> vvp;\ntypedef pair<int,pii> pip;\ntypedef vector<pip>vip;\nconst double PI=acos(-1);\nconst double EPS=1e-2;\nconst int inf=1e8;\nint main(){\n\tint q;\n\tcin>>q;\n\twhile(q--){\n\t\tdouble x,y,z;\n\t\tcin>>x>>y>>z;\n\t\tint n;\n\t\tcin>>n;\n\t\tvector<vector<double> >in(n,vector<double>(3));\n\t\trep(i,n)rep(j,3)cin>>in[i][j];\n\t\trep(i,n)rep(j,n)rep(k,n)if(i!=j&&j!=k&&k!=i){\n\t\t\tdouble a=hypot(hypot(in[i][0]-in[j][0],in[i][1]-in[j][1]),in[i][2]-in[j][2]);\n\t\t\tdouble b=hypot(hypot(in[k][0]-in[j][0],in[k][1]-in[j][1]),in[k][2]-in[j][2]);\n\t\t\tdouble c=hypot(hypot(in[i][0]-in[k][0],in[i][1]-in[k][1]),in[i][2]-in[k][2]);\n\t\t\tdouble t=a/x;\n\t\t\tif(abs(x*t-a)<EPS&&abs(y*t-b)<EPS&&abs(z*t-c)<EPS)cout<<k+1<<\" \"<<i+1<<\" \"<<j+1<<endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1268, "score_of_the_acc": -0.876, "final_rank": 16 }, { "submission_id": "aoj_1216_1451534", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int uli;\nconst int mx=40;\ndouble x[mx],y[mx],z[mx];\nconst double eps=1e-4;\ndouble d(int i,int j){\n return sqrt(pow(x[i]-x[j],2)+pow(y[i]-y[j],2)+pow(z[i]-z[j],2));\n}\nbool eq(double x,double y){\n return fabs(x-y)<eps;\n}\nint main(){\n int t,n;\n scanf(\"%d\",&t);\n double qr,rp,pq;\n while(t--){\n scanf(\"%lf %lf %lf\",&qr,&rp,&pq);\n scanf(\"%d\",&n);\n for(int i=0;i<n;i++){\n scanf(\"%lf %lf %lf\",x+i,y+i,z+i);\n }\n int p,q,r;\n for(int i=0;i<n;i++){\n for(int j=0;j<n;j++) if(j!=i){\n for(int k=0;k<n;k++) if(k!=i && k!=j){\n double l1=d(i,j);\n double l2=d(j,k);\n double l3=d(k,i);\n double r1=l1/qr;\n double r2=l2/rp;\n double r3=l3/pq;\n if(eq(r1,r2)&&eq(r1,r3)&&eq(r2,r3)){\n q=i,r=j,p=k; \n }\n }\n }\n }\n printf(\"%d %d %d\\n\",p+1,q+1,r+1);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1228, "score_of_the_acc": -0.3642, "final_rank": 7 }, { "submission_id": "aoj_1216_1332049", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define EPS 1e-7\n#define equals(a,b) (fabs(a-b) < EPS)\n\nstruct Point{\n double x,y,z;\n\n double getDist(const Point &p){\n return sqrt(pow(x-p.x,2)+pow(y-p.y,2)+pow(z-p.z,2));\n }\n};\n\nint main(){\n int Tc,N;\n double QR,RP,PQ;\n cin >> Tc;\n while(Tc--){\n cin >> QR >> RP >> PQ >> N;\n Point p[N];\n for(int i = 0 ; i < N ; i++){\n cin >> p[i].x >> p[i].y >> p[i].z;\n }\n double qr,rp,pq;\n for(int i = 0 ; i < N ; i++){\n for(int j = 0 ; j < N ; j++){\n if(i == j){ continue; }\n for(int k = 0 ; k < N ; k++){\n if(i == k || j == k){ continue; }\n qr = p[j].getDist(p[k]);\n rp = p[k].getDist(p[i]);\n pq = p[i].getDist(p[j]);\n if(equals(QR/qr,RP/rp) && equals(RP/rp,PQ/pq)){\n cout << i+1 << \" \" << j+1 << \" \" << k+1 << endl;\n goto end;\n }\n }\n }\n }\n end:;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1236, "score_of_the_acc": -0.3665, "final_rank": 8 }, { "submission_id": "aoj_1216_1162333", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nconst double EPS = 0.05;\ninline double dis(vector<double> a, vector<double> b){\n double res = 0;\n for(int i=0;i<3;i++)res += (a[i]-b[i])*(a[i]-b[i]);\n return sqrt(res);\n}\n\nint main(){\n int casenum;\n cin >> casenum;\n while(casenum--){\n double qr,rp,pq;\n cin >> qr >> rp >> pq;\n int n;\n cin >> n;\n vector< vector<double> > vp(n,vector<double>(3));\n for(int i=0;i<n;i++){\n for(int j=0;j<3;j++)cin >> vp[i][j];\n }\n\n bool f = true;\n for(int i=0;f && i<n;i++){\n for(int j=0;f && j<n;j++){\n\tif(i==j)continue;\n\tfor(int k=0;f && k<n;k++){\n\t if(i==k)continue;\n\n\t double d1 = dis(vp[j],vp[k]), d2 = dis(vp[k],vp[i]), d3 = dis(vp[i],vp[j]);\n\t double ratio = d1/qr;\n\t if( abs(ratio*rp-d2)<EPS && abs(ratio*pq-d3)<EPS){\n\t cout << i+1 << \" \" << j+1 << \" \" << k+1 << endl;\n\t f = false;\n\t }\n\t}\n }\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1256, "score_of_the_acc": -1.3725, "final_rank": 19 }, { "submission_id": "aoj_1216_1103848", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct P {\n double x,y,z;\n};\n\ndouble D(P a, P b) {\n return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y)+(a.z-b.z)*(a.z-b.z));\n}\n\nbool equal(double a, double b) {\n return fabs(a-b)<0.0000001;\n}\n\nint main() {\n int T;\n cin >> T;\n while(T--) {\n double l[3];\n for(int i=0; i<3; i++) cin >> l[i];\n int n;\n cin >> n;\n P a[n];\n for(int i=0; i<n; i++) cin >> a[i].x >> a[i].y >> a[i].z;\n for(int i=0; i<n; i++) {\n for(int j=0; j<n; j++) {\n\tfor(int k=0; k<n; k++) {\n\t if(i==j || j==k || k==i) continue;\n\t double d1=l[2]/D(a[i],a[j]);\n\t double d2=l[0]/D(a[j],a[k]);\n\t double d3=l[1]/D(a[k],a[i]);\n\t if(!equal(d1,d2) || !equal(d1,d3)) continue;\n\t cout << i+1 << \" \" << j+1 << \" \" << k+1 << endl;\n\t goto End;\n\t}\n }\n }\n End:;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1236, "score_of_the_acc": -0.3665, "final_rank": 8 }, { "submission_id": "aoj_1216_1092546", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n\nusing namespace std;\ntypedef double D;\nstruct P {\n\tD x, y, z;\n\tP(){}\n\tP(D xx, D yy, D zz):x(xx), y(yy), z(zz){}\n};\n\nD dis(P a, P b) {\n\treturn sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y)+(a.z-b.z)*(a.z-b.z));\n}\n\nconst double EPS = 0.05;\n\nint main()\n{\n\tint N; cin>>N;\n\twhile (N--) {\n\t\tD QR, RP, PQ;\n\t\tcin>>QR>>RP>>PQ;\n\t\tint M; cin>>M;\n\t\tvector<P> points;\n\t\t\n\t\tfor (int i=0; i<M; i++) {\n\t\t\tdouble x, y, z;\n\t\t\tcin>>x>>y>>z;\n\t\t\tpoints.push_back(P(x, y, z));\n\t\t}\n\t\t\n\t\tfor (int p=0; p<M; p++) {\n\t\t\tfor (int q=0; q<M; q++) {\n\t\t\t\tfor (int r=0; r<M; r++) {\n\t\t\t\t\tif (p!=q && p!=r) {\n\t\t\t\t\t\tD a = dis(points[p], points[q])/PQ;\n\t\t\t\t\t\tD b = dis(points[q], points[r])/QR;\n\t\t\t\t\t\tD c = dis(points[r], points[p])/RP;\n\t\t\t\t\t\tif (fabs(a-b)<EPS && fabs(b-c)<EPS && fabs(c-a)<EPS) {\n\t\t\t\t\t\t\tcout << (p+1) << \" \" << (q+1) << \" \" << (r+1) << endl;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1248, "score_of_the_acc": -0.3701, "final_rank": 14 }, { "submission_id": "aoj_1216_902177", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <sstream>\n#include <cstring>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n#include <numeric>\n#include <cctype>\n#include <tuple>\n\n#ifdef _MSC_VER\n#include <agents.h>\n#endif\n\n#define FOR(i, a, b) for(int i = (a); i < (int)(b); ++i)\n#define rep(i, n) FOR(i, 0, n)\n#define ALL(v) v.begin(), v.end()\n#define REV(v) v.rbegin(), v.rend()\n#define MEMSET(v, s) memset(v, s, sizeof(v))\n#define X first\n#define Y second\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> P;\n\ninline double sq(double x){\n\treturn x*x;\n}\n\ndouble x[100], y[100], z[100];\n\ndouble dist(int i, int j){\n\treturn sqrt(sq(x[i] - x[j]) + sq(y[i] - y[j]) + sq(z[i] - z[j]));\n}\n\ndouble EPS = 1e-4;\nbool check(double a, double b, double c){\n\tif (abs(a - b) > EPS) return false;\n\tif (abs(b - c) > EPS) return false;\n\tif (abs(c - a) > EPS) return false;\n\treturn true;\n}\n\nint main(){\n\tint T;\n\tcin >> T;\n\twhile (T--){\n\t\tdouble a, b, c;\n\t\tcin >> a >> b >> c;\n\t\tint n;\n\t\tcin >> n;\n\t\trep(i, n) cin >> x[i] >> y[i] >> z[i];\n\n\t\trep(i, n) rep(j, n) rep(k, n){\n\t\t\tif (i == j && j == k) continue;\n\t\t\tif (check(dist(j, k) / a, dist(k, i) / b, dist(i, j) / c)){\n\t\t\t\tcout << i+1 << \" \" << j+1 << \" \" << k+1 << endl;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1236, "score_of_the_acc": -0.3665, "final_rank": 8 }, { "submission_id": "aoj_1216_499198", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cmath>\n\nusing namespace std;\n\nconst double eps = 5e-3;\n\nstruct point {\n double x,y,z;\n point(){}\n point(double x, double y, double z):x(x),y(y),z(z){}\n point operator-(const point &t){\n return point(x-t.x,y-t.y,z-t.z);\n }\n};\n\ndouble abs(const point &a){\n return sqrt(a.x*a.x + a.y*a.y + a.z*a.z);\n}\n\nbool eq( double a, double b){\n return abs(a/b-b/a)<0.0001;\n}\n\nint main()\n{\n int T;\n cin >> T;\n for(int tc=0;tc<T;++tc){\n int n;\n double l[3];\n vector<point> vp;\n\n for(int i = 0; i < 3; ++i){\n // QR , RP , PQ\n cin >> l[i];\n }\n\n cin >> n;\n for(int i = 0; i < n; ++i){\n point p; cin >> p.x >> p.y >> p.z;\n vp.push_back( p );\n }\n\n for(int a = 0; a < n; ++a){\n \n for(int b = 0; b < n; ++b){\n if( a == b ) continue;\n \n for(int c = 0; c < n; ++c){\n if( b == c || a == c ) continue;\n \n double tl[3];\n \n tl[0] = abs(vp[a]-vp[b]);\n tl[1] = abs(vp[b]-vp[c]);\n tl[2] = abs(vp[c]-vp[a]);\n if( eq(tl[2]/l[2], tl[1]/l[1]) &&\n eq(tl[2]/l[2], tl[0]/l[0]) ){\n cout << c+1 << ' ' << a+1 << ' ' << b+1 << endl;\n }\n }\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1240, "score_of_the_acc": -0.3677, "final_rank": 12 }, { "submission_id": "aoj_1216_499197", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cmath>\n\nusing namespace std;\n\nconst double eps = 5e-3;\n\nstruct point {\n double x,y,z;\n point(){}\n point(double x, double y, double z):x(x),y(y),z(z){}\n point operator-(const point &t){\n return point(x-t.x,y-t.y,z-t.z);\n }\n};\n\ndouble abs(const point &a){\n return sqrt(a.x*a.x + a.y*a.y + a.z*a.z);\n}\n\nbool eq( double a, double b){\n return abs(a/b-b/a)<0.0001;\n}\n\n// a b c\n// Q R P\nconst int possible[3][3] = { {1,1,0},\n {0,1,1},\n {1,0,1} };\n\nbool determine(int p[3], int q[3], int depth, pair<int,int> out[3] ){\n if( depth == 3 ){\n for(int i = 0; i < depth; ++i){\n for(int j = i+1; j < depth; ++j){\n if( (out[i].first == out[j].first || out[i].second == out[j].second) ){\n return false;\n }\n }\n }\n return true;\n }\n for(int j = 0; j < 3; ++j){\n for(int k = 0; k < 3; ++k){\n if( possible[p[depth]][j] && possible[q[depth]][k] ){\n out[depth] = make_pair(j,k);\n if( determine(p,q,depth+1,out) ) return true;\n }\n }\n }\n return false;\n}\n\nint main()\n{\n int T;\n cin >> T;\n for(int tc=0;tc<T;++tc){\n int n;\n pair<double,int> l[3];\n vector<point> vp;\n\n for(int i = 0; i < 3; ++i){\n // QR , RP , PQ\n cin >> l[i].first;\n l[i].second = i;\n }\n // sort(l,l+3);\n\n cin >> n;\n for(int i = 0; i < n; ++i){\n point p; cin >> p.x >> p.y >> p.z;\n vp.push_back( p );\n }\n\n for(int a = 0; a < n; ++a){\n \n for(int b = 0; b < n; ++b){\n if( a == b ) continue;\n \n for(int c = 0; c < n; ++c){\n if( b == c || a == c ) continue;\n \n pair<double,int> tl[3];\n \n tl[0] = make_pair(abs(vp[a]-vp[b]),0);\n tl[1] = make_pair(abs(vp[b]-vp[c]),1);\n tl[2] = make_pair(abs(vp[c]-vp[a]),2);\n // sort(tl,tl+3);\n \n if( eq( tl[2].first / l[2].first, tl[1].first / l[1].first ) &&\n eq( tl[2].first / l[2].first, tl[0].first / l[0].first) ) {\n\n cout << c+1 << ' ' << a+1 << ' ' << b+1 << endl;\n /*\n int pp[3] = { l[2].second, l[1].second, l[0].second};\n int qq[3] = {tl[2].second,tl[1].second,tl[0].second};\n pair<int,int> res[3];\n determine(pp,qq,0,res);\n\n sort(res,res+3);\n\n cout << a << ' ' << b << ' ' << c << endl;\n for(int i = 0; i < 3; ++i){\n cout << res[i].first << ' ' << res[i].second << endl;\n }\n swap(res[0],res[2]);\n swap(res[1],res[2]);\n\n int id[3] = {a,b,c};\n for(int i = 0; i < 3; ++i){\n if( i ) cout << ' ';\n cout << 1+id[res[i].second];\n }\n cout << endl;\n */\n }\n }\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1240, "score_of_the_acc": -0.3677, "final_rank": 12 }, { "submission_id": "aoj_1216_487419", "code_snippet": "//12\n#include<iostream>\n#include<algorithm>\n#include<cmath>\n\nusing namespace std;\n\nstruct P{\n double x,y,z;\n double sq(double a){\n return a*a;\n }\n double ds(P a){\n return sqrt(sq(x-a.x)+sq(y-a.y)+sq(z-a.z));\n }\n};\n\nint main(){\n int t;\n cin>>t;\n while(t--){\n double qr,rp,pq;\n int np;\n cin>>qr>>rp>>pq>>np;\n P ps[30];\n for(int i=0;i<np;i++){\n cin>>ps[i].x>>ps[i].y>>ps[i].z;\n }\n double e=1<<30;\n int p,q,r;\n for(int i=0;i<np;i++){\n for(int j=0;j<np;j++){\n\tfor(int k=0;k<np;k++){\n\t double cqr,crp,cpq;\n\t cqr=ps[j].ds(ps[k])/qr;\n\t crp=ps[k].ds(ps[i])/rp;\n\t cpq=ps[i].ds(ps[j])/pq;\n\t cqr/=crp;\n\t cpq/=crp;\n\t double me=max(fabs(cqr-1),fabs(cpq-1));\n\t if(min(cqr,min(crp,cpq))>0&&me<e){\n\t e=me;\n\t p=i;\n\t q=j;\n\t r=k;\n\t }\n\t}\n }\n }\n cout<<p+1<<' '<<q+1<<' '<<r+1<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1236, "score_of_the_acc": -0.3665, "final_rank": 8 }, { "submission_id": "aoj_1216_444011", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <set>\n#include <map>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <cassert>\n\nusing namespace std;\n\n#define FOR(i,k,n) for(int i=(k); i<(int)n; ++i)\n#define REP(i,n) FOR(i,0,n)\n#define FORIT(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n\ntemplate<class T> void debug(T begin, T end){ for(T i = begin; i != end; ++i) cout<<*i<<\" \"; cout<<endl; }\n\ntypedef long long ll;\nconst int INF = 100000000;\nconst double EPS = 1e-4;\nconst int MOD = 1000000007;\nstruct P{\n double x, y, z;\n};\ndouble dist(double x, double y, double z){\n return sqrt(x*x + y*y + z*z);\n}\ndouble dist2(P p, P q){\n return dist(p.x-q.x, p.y-q.y, p.z-q.z);\n}\n\nint main(){\n int T; cin>>T;\n while(T--){\n double target[3];\n REP(i, 3) cin>>target[i];\n int N; cin>>N;\n vector<P> points(N);\n REP(i, N){\n cin>>points[i].x>>points[i].y>>points[i].z;\n }\n REP(i, N)REP(j, N)REP(k, N)if(i != j && j != k && k != i){\n double tri[3];\n tri[0] = dist2(points[i], points[j]);\n tri[1] = dist2(points[j], points[k]);\n tri[2] = dist2(points[k], points[i]);\n bool ok = true;\n REP(idx, 3){\n if(abs(tri[(idx+1)%3]/tri[idx] - target[(idx+1)%3]/target[idx]) > EPS){\n ok = false;\n }\n }\n if(ok) printf(\"%d %d %d\\n\", k+1, i+1, j+1);\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1216_366539", "code_snippet": "#include<stdio.h>\n#include<math.h>\nstruct P{double x,y,z;};\n#define S(x) ((x)*(x))\ndouble D(P a,P b){return sqrt(S(a.x-b.x)+S(a.y-b.y)+S(a.z-b.z));}\nint G(double x,double y)\n{\n\treturn (x*0.9998<=y&&y<=x*1.0002);\n}\nint F(P p,P q)\n{\n\tdouble c=q.x/p.x,d=q.y/p.y,e=q.z/p.z;\n\treturn G(c,d)&&G(c,e);\n}\nint main()\n{\n\tP p,a[100];\n\tint T,n,i,j,k;\n\tfor(scanf(\"%d\",&T);T--;)\n\t{\n\t\tscanf(\"%lf%lf%lf%d\",&p.x,&p.y,&p.z,&n);\n\t\tfor(i=0;i<n;++i)scanf(\"%lf%lf%lf\",&a[i].x,&a[i].y,&a[i].z);\n\t\tfor(i=0;i<n;++i)for(j=0;j<n;++j)for(k=0;k<n;++k)\n\t\t{\n\t\t\tif(i==j||j==k)continue;\n\t\t\tP x={D(a[j],a[k]),D(a[k],a[i]),D(a[i],a[j])};\n\t\t\tif(F(p,x))printf(\"%d %d %d\\n\",i+1,j+1,k+1);\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1216_319912", "code_snippet": "#include <cstdio>\n#include <algorithm>\n#include <queue>\n#include <cmath>\n#define REP(i,n) for(int i=0; i<(int)(n); i++)\n\nusing namespace std;\n\ndouble x[30];\ndouble y[30];\ndouble z[30];\n\ninline double dbl(double i){ return i * i; }\n\ndouble dist(int i, int j){\n return sqrt( dbl(x[i] - x[j]) +\n\t dbl(y[i] - y[j]) +\n\t dbl(z[i] - z[j]) );\n}\n\nint main(){\n int cc;\n double qr, rp, pq;\n scanf(\"%d\", &cc);\n\n while(cc --> 0){\n int n; \n scanf(\"%lf%lf%lf\", &qr, &rp, &pq);\n scanf(\"%d\", &n);\n REP(i,n) scanf(\"%lf%lf%lf\",x+i,y+i,z+i);\n vector<int> v(n);\n v[n-1] = v[n-2] = v[n-3] = 1;\n do{\n vector<int> pqr;\n REP(i,n) if(v[i]) pqr.push_back(i);\n\n do{\n\tconst int p = pqr[0];\n\tconst int q = pqr[1];\n\tconst int r = pqr[2];\n\tconst double e1 = dist(p, q) / pq;\n\tconst double e2 = dist(q, r) / qr;\n\tconst double e3 = dist(r, p) / rp;\n\tconst double eps = 1e-5;\n\n\tif(std::abs(e1 - e2) < e1 * eps &&\n\t std::abs(e2 - e3) < e2 * eps &&\n\t std::abs(e3 - e1) < e3 * eps){\n\t printf(\"%d %d %d\\n\", p + 1, q + 1, r + 1);\n\t goto next;\n\t}\n }while(next_permutation(pqr.begin(), pqr.end()));\n }while(next_permutation(v.begin(), v.end()));\n next:;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1216_285584", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <complex>\n#include <cmath>\n\nusing namespace std;\n\ntypedef complex<double> P;\n\nstruct Triangle{\n double qr,rp,pq;\n};\n\nstruct Point{\n double x,y,z;\n};\n\n#define EPS (0.05)\n#define EQ(a,b) (abs((a)-(b))<EPS)\n\nint main(){\n\n int t;\n cin>>t;\n while(t--){\n Point p[100];\n int n;\n Triangle org;\n cin>>org.qr>>org.rp>>org.pq;\n cin>>n;\n for(int i = 0; i < n; i++)\n cin>>p[i].x>>p[i].y>>p[i].z;\n // ツ三ツ点ツ選ツづアツづ堕環篠猟チツェツッツク\n for(int i = 0; i < n; i++){\n for(int j = 0; j < n; j++){\n for(int k = 0; k < n; k++){\n if(i==j||j==k||k==i)\n continue;\n // ツ選ツづアツつセツ点ツづ三ツ陛督づーツ催ャツづゥ\n double pq=sqrt(pow(p[i].x-p[j].x,2)+pow(p[i].y-p[j].y,2)+pow(p[i].z-p[j].z,2));\n double qr=sqrt(pow(p[j].x-p[k].x,2)+pow(p[j].y-p[k].y,2)+pow(p[j].z-p[k].z,2));\n double rp=sqrt(pow(p[k].x-p[i].x,2)+pow(p[k].y-p[i].y,2)+pow(p[k].z-p[i].z,2));\n // ツ三ツ陛督づ個氾、ツ猟ヲツづーツ確ツ認\n double pqPer=pq/org.pq;\n double qrPer=qr/org.qr;\n double rpPer=rp/org.rp;\n // match\n if(EQ(pqPer,qrPer)&&EQ(qrPer,rpPer))\n cout<<i+1<<\" \"<<j+1<<\" \"<<k+1<<endl;\n }\n }\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1216_279616", "code_snippet": "#include<iostream>\n#include<vector>\n#include<cmath>\nusing namespace std;\n\n#define EPS 0.0002\n\nstruct Point{double x,y,z;};\ndouble getDistance(Point p1,Point p2)\n{\n return sqrt(pow(p1.x-p2.x,2.0)+pow(p1.y-p2.y,2.0)+pow(p1.z-p2.z,2.0));\n}\n\nint main()\n{\n int n,m,P,Q,R;\n double original[3],x,y,z;\n int i,j,k,t;\n cin>>n;\n while(n-->0){\n for(i=0;i<3;i++)cin>>original[i];\n\n cin>>m;\n vector<Point>v(m);\n for(i=0;i<m;i++){\n cin>>x>>y>>z;\n Point p={x,y,z};\n v[i]=p;\n }\n\n P=0;\n for(i=0;i<m;i++){\n for(j=0;j<m;j++){\n\tif(i==j)continue;\n\tfor(k=0;k<m;k++){\n\t if(i==k||j==k)continue;\n\t double d[3]={getDistance(v[j],v[k]),getDistance(v[k],v[i]),getDistance(v[i],v[j])};\n\t bool ok=true;\n\t for(t=0;t<3;t++){\n\t if(original[t]/original[(t+1)%3]-d[t]/d[(t+1)%3]>EPS)ok=false;\n\t }\n\t if(ok){\n\t P=i+1;\n\t Q=j+1;\n\t R=k+1;\n\t }\n\t if(P)break;\n\t}\n\tif(P)break;\n }\n if(P)break;\n }\n\n cout<<P<<\" \"<<Q<<\" \"<<R<<endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1216_279615", "code_snippet": "#include<iostream>\n#include<vector>\n#include<cmath>\nusing namespace std;\n\n#define EPS 0.0002\n\nstruct Point{double x,y,z;};\ndouble getDistance(Point p1,Point p2)\n{\n return sqrt(pow(p1.x-p2.x,2.0)+pow(p1.y-p2.y,2.0)+pow(p1.z-p2.z,2.0));\n}\n\nint main()\n{\n int n,m,P,Q,R;\n double original[3],x,y,z;\n int i,j,k;\n cin>>n;\n while(n-->0){\n for(i=0;i<3;i++)cin>>original[i];\n\n cin>>m;\n vector<Point>v(m);\n for(i=0;i<m;i++){\n cin>>x>>y>>z;\n Point p={x,y,z};\n v[i]=p;\n }\n\n P=0;\n for(i=0;i<m;i++){\n for(j=0;j<m;j++){\n\tif(i==j)continue;\n\tfor(k=0;k<m;k++){\n\t if(i==k||j==k)continue;\n\t Point p[3]={v[i],v[j],v[k]};\n\t bool ok=true;\n\t double d[3]={getDistance(p[1],p[2]),getDistance(p[2],p[0]),getDistance(p[0],p[1])};\n\t for(int s=0;s<3;s++){\n\t if(original[s]/original[(s+1)%3]-d[s]/d[(s+1)%3]>EPS)ok=false;\n\t }\n\t if(ok){\n\t P=i+1;\n\t Q=j+1;\n\t R=k+1;\n\t }\n\t if(P)break;\n\t}\n\tif(P)break;\n }\n if(P)break;\n }\n\n cout<<P<<\" \"<<Q<<\" \"<<R<<endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 968, "score_of_the_acc": -0.7871, "final_rank": 15 }, { "submission_id": "aoj_1216_279613", "code_snippet": "#include<iostream>\n#include<vector>\n#include<cmath>\nusing namespace std;\n\n#define EPS 0.0002\n\nstruct Point{double x,y,z;};\ndouble getDistance(Point p1,Point p2)\n{\n return sqrt(pow(p1.x-p2.x,2.0)+pow(p1.y-p2.y,2.0)+pow(p1.z-p2.z,2.0));\n}\n\nint main()\n{\n int n,m,P,Q,R;\n double original[3],x,y,z;\n int i,j,k,l;\n cin>>n;\n while(n-->0){\n for(i=0;i<3;i++)cin>>original[i];\n\n cin>>m;\n vector<Point>v(m);\n for(i=0;i<m;i++){\n cin>>x>>y>>z;\n Point p={x,y,z};\n v[i]=p;\n }\n\n P=0;\n for(i=0;i<m;i++){\n for(j=0;j<m;j++){\n\tif(i==j)continue;\n\tfor(k=0;k<m;k++){\n\t if(i==k||j==k)continue;\n\t Point p[3]={v[i],v[j],v[k]};\n\t bool ok=true;\n\t double d[3]={getDistance(p[1],p[2]),getDistance(p[2],p[0]),getDistance(p[0],p[1])};\n\t for(int s=0;s<3;s++){\n\t for(int t=0;t<3;t++){\n\t if(original[s]/original[t]-d[s]/d[t]>EPS)ok=false;\n\t }\n\t }\n\t if(ok){\n\t P=i+1;\n\t Q=j+1;\n\t R=k+1;\n\t }\n\t if(P)break;\n\t}\n\tif(P)break;\n }\n if(P)break;\n }\n\n cout<<P<<\" \"<<Q<<\" \"<<R<<endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 968, "score_of_the_acc": -1.2871, "final_rank": 18 }, { "submission_id": "aoj_1216_273893", "code_snippet": "#define _USE_MATH_DEFINES\n#include <iostream>\n#include <memory>\n#include <memory.h>\n#include <fstream>\n#include <cmath>\n#include <numeric>\n#include <vector>\n#include <stack>\n#include <string>\n#include <queue>\n#include <sstream>\n#include <cstdlib>\n#include <cassert>\n#include <cstdio>\n#include <cstring>\n#include <map>\n#include <set>\n#include <iomanip>\n#include <list>\n#include <cctype>\n#include <algorithm>\n#include <complex>\nusing namespace std;\n\ntypedef complex<double> xy_t;\ntypedef pair<xy_t, xy_t> line;\ntypedef long long ll;\ntypedef pair<int, int> P;\ntypedef pair<double, double> Pd;\ntypedef pair<int, P> PP;\ntypedef pair<int, PP> PPP;\nconst int INF = 1 << 29;\nconst double EPS = 1E-4;\n\n#define rep(i, n) for(int i = 0; i < n; i++)\n#define rep2(i, m, n) for(int i = m; i < n; i++)\n\nlong double QR, RP, PQ;\nlong double x[100];\nlong double y[100];\nlong double z[100];\nlong double dist(int i, int j){\n\tlong double dx = abs(x[i] - x[j]);\n\tlong double dy = abs(y[i] - y[j]);\n\tlong double dz = abs(z[i] - z[j]);\n\treturn sqrt(dx * dx + dy * dy + dz * dz);\n}\n\nint main(){\n\tint T;\n\tint n;\n\tlong double pq, qr, rp;\n\tcin >> T;\n\trep(t, T){\n\t\tcin >> QR >> RP >> PQ;\n\t\tcin >> n;\n\t\trep(i, n){\n\t\t\tcin >> x[i] >> y[i] >> z[i];\n\t\t}\n\t\n\t\trep(i, n) rep(j, n) rep(k, n){\n\t\t\tif(i == j || j == k || k == i) continue;\n\t\t\tpq = dist(i, j);\n\t\t\tqr = dist(j, k);\n\t\t\trp = dist(k, i);\n\t\t\tlong double ratio = pq / PQ;\n\t\t\tif(abs(ratio - qr / QR) < EPS && abs(ratio - rp / RP) < EPS){\n\t\t\t\tcout << i + 1 << \" \" << j + 1 << \" \" << k + 1 << endl;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_1209_cpp
Problem B: Square Coins People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Coins with values of all square numbers up to 289 (= 17 2 ), i.e., 1-credit coins, 4-credit coins, 9-credit coins, ..., and 289-credit coins, are available in Silverland. There are four combinations of coins to pay ten credits: ten 1-credit coins, one 4-credit coin and six 1-credit coins, two 4-credit coins and two 1-credit coins, and one 9-credit coin and one 1-credit coin. Your mission is to count the number of ways to pay a given amount using coins of Silverland. Input The input consists of lines each containing an integer meaning an amount to be paid, followed by a line containing a zero. You may assume that all the amounts are positive and less than 300. Output For each of the given amount, one line containing a single integer representing the number of combinations of coins should be output. No other characters should appear in the output. Sample Input 2 10 30 0 Output for the Sample Input 1 4 27
[ { "submission_id": "aoj_1209_2539223", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint count( int S[], int m, int n )\n{\n if (n == 0)\n return 1;\n if (n < 0)\n return 0;\n if (m <=0 && n >= 1)\n return 0;\n return count( S, m - 1, n ) + count( S, m, n-S[m-1] );\n}\nint main()\n{\n int n;\n while(cin>>n){\n if(n==0) exit(0);\n else{\n int arr[300];\n int j=0;\n for(int i=1;i<=n;i++){\n if((i*i)<=n){\n arr[j++]=i*i;\n }\n }\n cout<<count(arr,j,n)<<endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3020, "score_of_the_acc": -0.1619, "final_rank": 9 }, { "submission_id": "aoj_1209_1981849", "code_snippet": "#include <iostream>\n#include <string>\n#include<bits/stdc++.h>\nusing namespace std;\n \nint coin[17];\nint ans;\n \nvoid solve(int n, int u){\n \n for (int i = u; i >= 0; i--){\n if (n > coin[i]) solve(n - coin[i], i);\n else if (n == coin[i]) ans++;\n }\n \n return;\n}\n \n \nint main(void){\n \n int n;\n\n for (int i = 0; i < 17; i++){\n coin[i] = (i + 1) * (i + 1);\n }\n \n while (cin >> n, n){\n ans = 0;\n solve(n, 16);\n cout << ans << endl;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1168, "score_of_the_acc": -0.0626, "final_rank": 5 }, { "submission_id": "aoj_1209_1923947", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n\nint square[] = { 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289 };\nint ans;\n\n\nvoid dfs(int num, int upper){\n\t//cout << num << \"\\t\" << upper << endl;\n\n\tfor (int i = upper; i >= 0; i--){\n\t\tif (num > square[i]) dfs(num - square[i], i);\n\t\telse if (num == square[i]) ans++;\n\t}\n\n\treturn;\n}\n\n\nint main(void){\n\n\tint num;\n\n\twhile (cin >> num, num){\n\t\tans = 0;\n\t\tdfs(num, 16);\n\n\t\tcout << ans << endl;\n\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1164, "score_of_the_acc": -0.0624, "final_rank": 2 }, { "submission_id": "aoj_1209_1890569", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std ;\n\n#define pb(n) push_back(n)\n#define fi first\n#define se second\n#define all(r) (r).begin(),(r).end()\n#define vmax(ary) *max_element(all(ary))\n#define vmin(ary) *min_element(all(ary))\n#define debug(x) cout<<#x<<\": \"<<x<<endl\n#define fcout(n) cout<<fixed<<setprecision((n))\n#define scout(n) cout<<setw(n)\n#define vary(type,name,size,init) vector< type> name(size,init)\n#define vvl(v,w,h,init) vector<vector<ll>> v(w,vector<ll>(h,init))\n#define mp(a,b) make_pair(a,b)\n\n#define rep(i,n) for(int i = 0; i < (int)(n);++i)\n#define REP(i,a,b) for(int i = (a);i < (int)(b);++i)\n#define repi(it,array) for(auto it = array.begin(),end = array.end(); it != end;++it)\n#define repa(n,array) for(auto &n :(array))\n\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<ll>;\nusing dict = map<string,int>;\nusing pii = pair<int,int> ;\nusing pll = pair<ll,ll> ;\n\nconst int mod = 1000000007;\nconstexpr int inf = ((1<<30)-1)*2+1 ;\nconstexpr double PI = acos(-1.0) ;\ndouble eps = 1e-10 ;\n\nvector<vector<ll>> dp(1000,vector<ll>(20,0));\n\nvary(int,v,0,0);\nint tar;\nint DP(int i,int k){\n if(k == tar){\n return 1;\n }\n if(k > tar) return 0;\n int cnt = 0;\n dp[i][k] = 1;\n REP(j,i,18){\n cnt += DP(j,k+v[j]);\n }\n return cnt;\n}\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n v.clear();\n REP(i,0,18){\n v.pb(i*i);\n }\n int n;\n while(cin >> n&&n){\n tar = n;\n dp = vector<vector<ll>>(1000,vector<ll>(1000,0));\n cout << DP(1,0) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 18652, "score_of_the_acc": -1.2917, "final_rank": 16 }, { "submission_id": "aoj_1209_1446038", "code_snippet": "#include <algorithm>\n#include <functional>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <string>\n#include <sstream>\n#include <iostream>\n#include <iomanip>\n#include <vector>\n#include <list>\n#include <stack>\n#include <queue>\n#include <map>\n#include <set>\n#include <bitset>\n#include <climits>\n\n#define all(c) (c).begin(), (c).end()\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define pb(e) push_back(e)\n#define mp(a, b) make_pair(a, b)\n#define fr first\n#define sc second\n\nconst int INF=100000000;\nint dx[4]={1,0,-1,0};\nint dy[4]={0,1,0,-1};\nusing namespace std;\ntypedef pair<int ,int > P;\ntypedef long long ll;\n\n\nll dfs(int x,int a) {\n if(x==0) return 1;\n ll ret=0;\n rep(i,18) if(a<=i) {\n if(x-i*i>=0) {\n ret+=dfs(x-i*i,i);\n }\n }\n\n return ret;\n}\n\nint main() {\n ll x;\n while(cin>>x) {\n if(x==0) break;\n cout<<dfs(x,1)<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 1164, "score_of_the_acc": -0.5207, "final_rank": 13 }, { "submission_id": "aoj_1209_1356427", "code_snippet": "#ifndef _GLIBCXX_NO_ASSERT\n#include <cassert>\n#endif\n#include <cctype>\n#include <cerrno>\n#include <cfloat>\n#include <ciso646>\n#include <climits>\n#include <clocale>\n#include <cmath>\n#include <csetjmp>\n#include <csignal>\n#include <cstdarg>\n#include <cstddef>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <ctime>\n\n#ifdef __GXX_EXPERIMENTAL_CXX0X__\n#include <ccomplex>\n#include <cfenv>\n#include <cinttypes>\n#include <cstdbool>\n#include <cstdint>\n#include <ctgmath>\n#include <cwchar>\n#include <cwctype>\n#endif\n\n#include <algorithm>\n#include <bitset>\n#include <complex>\n#include <deque>\n#include <exception>\n#include <fstream>\n#include <functional>\n#include <iomanip>\n#include <ios>\n#include <iosfwd>\n#include <iostream>\n#include <istream>\n#include <iterator>\n#include <limits>\n#include <list>\n#include <locale>\n#include <map>\n#include <memory>\n#include <new>\n#include <numeric>\n#include <ostream>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <stdexcept>\n#include <streambuf>\n#include <string>\n#include <typeinfo>\n#include <utility>\n#include <valarray>\n#include <vector>\n\n#ifdef __GXX_EXPERIMENTAL_CXX0X__\n#include <array>\n#include <atomic>\n#include <chrono>\n#include <condition_variable>\n#include <forward_list>\n#include <future>\n#include <initializer_list>\n#include <mutex>\n#include <random>\n#include <ratio>\n#include <regex>\n#include <system_error>\n#include <thread>\n#include <tuple>\n#include <typeindex>\n#include <type_traits>\n#include <unordered_map>\n#include <unordered_set>\n#endif\n\nusing namespace std;\n\nint data[18] = {};\n\nlong long int saiki(int N,int reb)\n{\n\tif (!N)return 1;\n\twhile (data[reb] > N)reb--;\n\tlong long int count = 0;\n\tfor (size_t i = reb; i >0; i--)\n\t{\n\t\tcount += saiki(N - data[i], i);\n\t}\n\treturn count;\n}\n\nint main()\n{\n\tint N;\n\tfor (size_t i = 0; i < 18; i++)\n\t{\n\t\tdata[i] = i*i;\n\t}\n\twhile (cin >> N, N)\n\t{\n\t\tcout << saiki(N, 17) << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1164, "score_of_the_acc": -0.0624, "final_rank": 2 }, { "submission_id": "aoj_1209_1237336", "code_snippet": "#include<cstdio>\n#include<algorithm>\n#include<vector>\n#include<iostream>\nusing namespace std;\nint n;\nint v[17];\nint dfs(int pos,int sum){\n if(pos==17){\n if(sum==n)return 1;\n else return 0;\n }\n int res=0;\n for(int i=0;sum+v[pos]*i<=n;i++)res+=dfs(pos+1,sum+v[pos]*i);\n return res;\n}\nint main(){\n for(int i=0;i<17;i++)v[i]=(i+1)*(i+1);\n while(cin>>n,n)cout<<dfs(0,0)<<endl;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 1160, "score_of_the_acc": -0.4789, "final_rank": 12 }, { "submission_id": "aoj_1209_668536", "code_snippet": "#include <iostream>\n\nusing namespace std;\n\nint div[17];\n\nint dfs(int num, int s)\n{\n int ret = 0;\n\n if (num == 0)\n return 1;\n else if (num < 0)\n return 0;\n\n for (int i = s; i < 17; i++) {\n if (num < div[i])\n break;\n ret += dfs(num - div[i], i);\n }\n return ret;\n}\n\nint main()\n{\n int n;\n\n for (int i = 1; i <= 17; i++)\n div[i - 1] = i * i;\n\n while (cin >> n, n) {\n int ans = 0;\n\n cout << dfs(n, 0) << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1164, "score_of_the_acc": -0.0624, "final_rank": 2 }, { "submission_id": "aoj_1209_516568", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n\nusing namespace std;\n\nvoid MakeData(int, int, bool, vector<int>, vector<int>&);\nvoid NextData(vector<int>, vector<int>&);\n\nint main(){\n int i, n;\n vector<int> coin, data;\n\n for(i=1; i<=17; ++i) coin.push_back(i*i);\n\n while(1){\n cin >> n;\n if(n == 0) break;\n MakeData(n, n, true, coin, data);\n\n for(i=1; data[0]!=1; ++i) NextData(coin, data);\n cout << i << endl;\n data.clear();\n }\n return 0;\n}\n\nvoid MakeData(int n, int m, bool is_upper,\n\t vector<int> coin, vector<int>& data){\n vector<int>::iterator i;\n if(is_upper) i = upper_bound(coin.begin(), coin.end(), m);\n else i = lower_bound(coin.begin(), coin.end(), m);\n --i;\n while(1){\n if(n >= *i){\n data.push_back(*i);\n n -= *i;\n if(n == 0) return;\n }else{\n --i;\n }\n }\n}\n\nvoid NextData(vector<int> coin, vector<int>& data){\n int n, sum;\n vector<int>::iterator i, j;\n i = find(data.begin(), data.end(), 1);\n n = *(i-1);\n if(i == data.end()){\n data.pop_back();\n MakeData(n, n, false, coin, data);\n }else{\n for(j=i-1, sum=0; j!=data.end(); ++j) sum += *j;\n data.erase(i-1, data.end());\n MakeData(sum, n, false, coin, data);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1220, "score_of_the_acc": -0.0654, "final_rank": 6 }, { "submission_id": "aoj_1209_465451", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <climits>\n#include <cfloat>\n#include <cstring>\n#include <map>\n#include <utility>\n#include <set>\n#include <iostream>\n#include <memory>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <functional>\n#include <sstream>\n#include <complex>\n#include <stack>\n#include <queue>\n\n#define FOR(i,b,n) for(int i=b;i<n;i++)\n#define RFOR(i,b,n) for(int i=n-1;i>=b;i--)\n#define CLR(mat) memset(mat, 0, sizeof(mat))\n#define NCLR(mat) memset(mat, -1, sizeof(mat))\n\nusing namespace std;\n\nstatic const double EPS = 1e-9;\ntypedef long long ll;\ntypedef pair<int, int> paii;\n\nint coin[18] = {0}; \nint n, res = 0;\n\nvoid solve_rec(int sum, int i)\n{\n\tif( i <= 17)\n\t{\n\t\tif( sum == n)\n\t\t\tres++;\n\t\telse if(sum < n)\n\t\t{\n\t\t\tsolve_rec(sum+coin[i], i);\n\t\t\tsolve_rec(sum, i+1);\n\t\t}\n\t}\n\t\n\treturn;\n}\n\nint solve()\n{\n\tres = 0;\n\tsolve_rec(0, 1);\n\treturn res;\n}\n\nvoid init()\n{\n\tFOR(i, 1, 18)\n\t{\n\t\tcoin[i] = i*i;\n\t}\n\t\n\treturn;\n}\n\nint main()\n{\n\tinit();\n\t\n\twhile(cin >> n, n)\n\t{\n\t\tcout << solve() << endl;\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 1168, "score_of_the_acc": -0.6876, "final_rank": 14 }, { "submission_id": "aoj_1209_371652", "code_snippet": "#include <iostream>\n#include <cstring>\n\nusing namespace std;\nint dp[18][301][301];\nint hoge;\nint main(){\n memset(dp,0,sizeof(dp));\n for(int i=0;i<301;++i) dp[0][i][i] = 1;\n \n for(int i=1;i<18;i++){\n for(int j=0;j<301;j++){\n for(int k=0;k<301;++k){\n int cnt=0;\n while((i+1)*(i+1)*cnt+k<301){\n dp[i][j+cnt][(i+1)*(i+1)*cnt+k] += dp[i-1][j][k];\n cnt++;\n }\n }\n }\n }\n\n int n;\n while(cin >> n && n){\n int ret=0;\n for(int i=0;i<301;++i) ret+= dp[17][i][n];\n cout << ret << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 7124, "score_of_the_acc": -0.4653, "final_rank": 11 }, { "submission_id": "aoj_1209_340626", "code_snippet": "#include<cstdio>\n#include<cstdlib>\n#include<cstring>\n#include<cmath>\n#include<cassert>\n#include<iostream>\n#include<sstream>\n#include<string>\n#include<vector>\n#include<queue>\n#include<set>\n#include<map>\n#include<utility>\n#include<numeric>\n#include<algorithm>\n#include<bitset>\n#include<complex>\n#include<stack>\n\nusing namespace std;\n\ntypedef long long Int;\ntypedef vector<int> vint;\ntypedef pair<int,int> pint;\ntypedef vector<string> vstring;\ntypedef vector<pint> vpint;\n\nstruct Edge{int to,from,cost;};\n\n#ifdef DEBUGLOCAL\n#define debug cout\n#else\nstringstream __ss__;\n#define debug __ss__\n#endif\n\ntemplate<class T> void pv(T a, T b) { for (T i = a; i != b; ++i) debug << *i << \" \"; debug << endl; }\ntemplate<class T> void chmin(T &t, T f) { if (t > f) t = f; }\ntemplate<class T> void chmax(T &t, T f) { if (t < f) t = f; }\nint in() { int x; scanf(\"%d\", &x); return x; }\n\n#define rep(i,n) for(int i=0;i<(n);++i)\n#define repd(i,n) for(int i=(n)-1;i>=0;i--)\n#define repn(i,m,n) for(int i=(m);i<=(n);++i)\n#define repnd(i,m,n) for(int i=(n)-1;i>=(m);i--)\n#define rep0(i,n) for(i=0;i<(n);++i)\n#define all(n) n.begin(),n.end()\n#define sz(n) ((int)(n).size())\n#define IL for(;;)\n#define MP make_pair\n#define PB push_back\n#define SS stringstream\n#define X second\n#define Y first\n#define PUTLINE debug<<\"LINE:\"<<__LINE__<<endl;\n\nconst int INF = 2147483647/3;\nconst double EPS = 1e-10;\nconst double PI = acos(-1.0);\n\nconst int dx[]={1,-1,0,0,1,-1,1,-1,0};\nconst int dy[]={0,0,1,-1,1,-1,-1,1,0};\n\nint solve(int n,int a){\n\tif(n==0)return 1;\n\tint res=0;\n\tfor(int i=a;i*i<=n;++i){\n\t\tres+=solve(n-i*i,i);\n\t}\n\treturn res;\n}\n\nint main() {\n\tint n;\n\tIL{\n\t\tcin>>n;\n\t\tif(n==0)break;\n\t\tcout<<solve(n,1)<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 876, "score_of_the_acc": -0.172, "final_rank": 10 }, { "submission_id": "aoj_1209_317707", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <string>\n\nusing namespace std;\n\nconst int N = 17;\nint n;\n\nint dfs(int i)\n{\n\tif (n < 0) {\n\t\treturn 0;\n\t}\n\tif (n == 0) {\n\t\treturn 1;\n\t}\n\tint ans = 0;\n\tfor (int j = i; j <= N; j++) {\n\t\tn -= j * j;\n\t\tans += dfs(j);\n\t\tn += j * j;\n\t}\n\treturn ans;\n}\n\nvoid solve()\n{\n\tint ans = dfs(1);\n\tcout << ans << endl;\n}\n\nint main()\n{\n\twhile (cin >> n, n) {\n\t\tsolve();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 872, "score_of_the_acc": -1.0468, "final_rank": 15 }, { "submission_id": "aoj_1209_157610", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <cassert>\n#include <cctype>\n#include <complex>\n#include <cstdio>\n#include <map>\n#include <math.h>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <vector>\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<n;i++)\n\nint n;\n\nint solve(int n,int m){\n\tif(!n)return 1;\n\tif(n<0)return 0;\n\tint res=0;\n\trep(i,m)res+=solve(n-(i+1)*(i+1),i+1);\n\treturn res;\n}\n\nint main(){\n\twhile(cin>>n&&n)cout<<solve(n,17)<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 0, "score_of_the_acc": -0.0417, "final_rank": 1 }, { "submission_id": "aoj_1209_120892", "code_snippet": "#include <iostream>\n#include <cmath>\nusing namespace std;\n\nint value[301];\n\nint pow(int x, int n) {\n int ans = 1;\n for(int i = 0; i < n; i++) {\n ans *= x;\n }\n return ans;\n}\n\nbool isHeiho(int x) {\n return (double)((int)sqrt(x)) == sqrt(x);\n}\n\nvoid rec(int minI, int x, int maxX) {\n if(x == 0) {\n value[maxX]++;\n return;\n }\n for(int i = minI; i <= 17; i++) {\n int tmp = pow(i, 2);\n if(tmp <= x) rec(i, x-tmp, maxX);\n if(tmp > x) break;\n }\n}\n\nint main() {\n for(int i = 1; i <= 30; i++) {\n value[i] = 0;\n }\n\n while(1) {\n int price;\n cin >> price;\n if(price == 0) break;\n if(value[price] == 0) {\n rec(1, price, price);\n }\n cout << value[price] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 868, "score_of_the_acc": -0.1299, "final_rank": 8 }, { "submission_id": "aoj_1209_93535", "code_snippet": "#include<stdio.h>\n#include<string.h>\n\nint c,sq[18];\n\nint count(int n,int i){\n\tif(n==0)return 0;\n\tint j;\n\tfor(j=i;j>=1;j--){\n\t\tif(n<sq[j])continue;\n\t\tif(n==sq[j]){\n\t\t\t++c;\n\t\t\tcontinue;\n\t\t}\n\t\tcount(n-sq[j],j);\n\t}\n\treturn 0;\n}\n\nint main(){\n\n\tint i,j,n;\n\t\n\tfor(i=0;i<=17;i++){\n\t\tsq[i]=i*i;\n\t}\n\t\n\twhile(0<=scanf(\"%d\",&n)){\n\t\tif(n==0)break;\n\t\tc=0;\n\t\t\n\t\tfor(i=1;i<=17;i++){\n\t\t\tif(n<sq[i]){\n\t\t\t\t--i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tcount(n,i);\n\t\tprintf(\"%d\\n\",c);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 760, "score_of_the_acc": -0.0824, "final_rank": 7 } ]
aoj_1215_cpp
Problem H: Co-occurrence Search A huge amount of information is being heaped on WWW. Albeit it is not well-organized, users can browse WWW as an unbounded source of up-to-date information, instead of consulting established but a little out-of-date encyclopedia. However, you can further exploit WWW by learning more about keyword search algorithms. For example, if you want to get information on recent comparison between Windows and UNIX, you may expect to get relevant description out of a big bunch of Web texts, by extracting texts that contain both keywords "Windows" and "UNIX" close together. Here we have a simplified version of this co-occurrence keyword search problem, where the text and keywords are replaced by a string and key characters, respectively. A character string S of length n (1 ≤ n ≤ 1,000,000) and a set K of k distinct key characters a 1 , ..., a k (1 ≤ k ≤ 50) are given. Find every shortest substring of S that contains all of the key characters a 1 , ..., a k . Input The input is a text file which contains only printable characters (ASCII codes 21 to 7E in hexadecimal) and newlines. No white space such as space or tab appears in the input. The text is a sequence of the shortest string search problems described above. Each problem consists of character string S i and key character set K i ( i = 1, 2, ..., p ). Every S i and K i is followed by an empty line. However, any single newline between successive lines in a string should be ignored; that is, newlines are not part of the string. For various technical reasons, every line consists of at most 72 characters. Each key character set is given in a single line. The input is terminated by consecutive empty lines; p is not given explicitly. Output All of p problems should be solved and their answers should be output in order. However, it is not requested to print all of the shortest substrings if more than one substring is found in a problem, since found substrings may be too much to check them all. Only the number of the substrings together with their representative is requested instead. That is, for each problem i , the number of the shortest substrings should be output followed by the first (or the leftmost) shortest substring s i 1 , obeying the following format: the number of the shortest substrings for the i-th problem empty line the first line of s i1 the second line of s i1 ... the last line of s i1 empty line for the substring termination where each line of the shortest substring s i 1 except for the last line should consist of exactly 72 characters and the last line (or the single line if the substring is shorter than or equal to 72 characters, of course) should not exceed 72 characters. If there is no such substring for a problem, the output will be a 0 followed by an empty line; no more successive empty line should be output because there is no substring to be terminated. Sample Input Thefirstexampleistrivial. mfv AhugeamountofinformationisbeingheapedonWWW.Alb ...(truncated)
[ { "submission_id": "aoj_1215_2683439", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\n#include <time.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\nstring buf,line,pattern;\nvector<int> LOC[128];\n\n\nbool check(int start,int end){\n\n\tbool FLG;\n\n\tint left,right,m,tmp_start,tmp_end;\n\n\tfor(int i = 0; i < pattern.length(); i++){\n\t\tint ch = pattern[i];\n\n\t\tleft = 0,right = LOC[ch].size()-1,m = (left+right)/2;\n\t\ttmp_start = BIG_NUM;\n\n\t\twhile(left <= right){\n\t\t\tif(LOC[ch][m] >= start){\n\t\t\t\ttmp_start = m;\n\t\t\t\tright = m-1;\n\t\t\t}else{\n\t\t\t\tleft = m+1;\n\t\t\t}\n\t\t\tm = (left+right)/2;\n\t\t}\n\t\tif(tmp_start == BIG_NUM)return false;\n\n\t\tleft = tmp_start,right = LOC[ch].size()-1,m = (left+right)/2;\n\t\ttmp_end = BIG_NUM;\n\n\t\twhile(left <= right){\n\t\t\tif(LOC[ch][m] <= end){\n\t\t\t\ttmp_end = m;\n\t\t\t\tleft = m+1;\n\t\t\t}else{\n\t\t\t\tright = m-1;\n\t\t\t}\n\t\t\tm = (left+right)/2;\n\t\t}\n\t\tif(tmp_end == BIG_NUM)return false;\n\t}\n\treturn true;\n}\n\nvoid func(){\n\n\tfor(int i = 0; i < 128; i++)LOC[i].clear();\n\n\tline += buf;\n\twhile(true){\n\t\tgetline(cin,buf);\n\t\tif(buf == \"\")break;\n\t\tline += buf;\n\t}\n\tgetline(cin,pattern);\n\tgetline(cin,buf);\n\n\tfor(int i = 0; i < line.length(); i++){\n\t\tLOC[line[i]].push_back(i);\n\t}\n\n\tfor(int i = 0; i < pattern.length(); i++){\n\t\tif(LOC[pattern[i]].size() == 0){\n\t\t\tprintf(\"0\\n\\n\");\n\t\t\treturn;\n\t\t}\n\t}\n\n\tbool FLG;\n\tint left,right,m,minimum = BIG_NUM,ans_count = 1,tmp_end;\n\tint ans_start,ans_end;\n\n\tfor(int start = 0; start < line.length(); start++){\n\n\t\tleft = start,right = line.length()-1,m = (left+right)/2;\n\t\ttmp_end = BIG_NUM;\n\n\t\twhile(left <= right){\n\t\t\tif(check(start,m)){\n\t\t\t\ttmp_end = m;\n\t\t\t\tright = m-1;\n\t\t\t}else{\n\t\t\t\tleft = m+1;\n\t\t\t}\n\t\t\tm = (left+right)/2;\n\t\t}\n\t\tif(tmp_end == BIG_NUM)continue;\n\n\t\tif(tmp_end-start+1 < minimum){\n\n\t\t\tminimum = tmp_end-start+1;\n\t\t\tans_count = 1;\n\t\t\tans_start = start;\n\t\t\tans_end = tmp_end;\n\n\t\t}else if(tmp_end-start+1 == minimum){\n\t\t\tans_count++;\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\\n\",ans_count);\n\tfor(int i = ans_start; i <= ans_end; i += 72){\n\t\tfor(int k = i; k <= min(ans_end,i+71); k++){\n\t\t\tprintf(\"%c\",line[k]);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\tprintf(\"\\n\");\n\n\tline.clear();\n\tpattern.clear();\n}\n\n\nint main(){\n\n\twhile(true){\n\t\tgetline(cin,buf);\n\t\tif(buf == \"\")break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2150, "memory_kb": 6068, "score_of_the_acc": -1.7524, "final_rank": 20 }, { "submission_id": "aoj_1215_2198500", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define int long long\n#define all(v) begin(v), end(v)\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n#define reps(i, s, n) for(int i = (int)(s); i < (int)(n); i++)\n#define min(...) min({__VA_ARGS__})\n#define max(...) max({__VA_ARGS__})\n\ntemplate<class T1, class T2> void chmin(T1 &a, T2 b){if(a>b)a=b;}\ntemplate<class T1, class T2> void chmax(T1 &a, T2 b){if(a<b)a=b;}\n\nusing pint = pair<int, int>;\nusing tint = tuple<int, int, int>;\nusing vint = vector<int>;\n\nconst int inf = 1LL << 55;\nconst int mod = 1e9 + 7;\n\nsigned main()\n{\n cin.tie(0);\n ios_base::sync_with_stdio(0);\n cout << fixed << setprecision(12);\n\n string line;\n while(getline(cin, line), line != \"\") {\n string s = line, a;\n while(getline(cin, line), line != \"\") s += line;\n getline(cin, a);\n\n int n = s.size(), k = a.size();\n vint pos[55];\n rep(i, n) rep(j, k) {\n if(s[i] == a[j]) pos[j].push_back(i);\n }\n bool imp = false;\n rep(i, k) if(!pos[i].size()) imp = true;\n if(imp) {\n cout << 0 << endl << endl;\n getline(cin, line);\n continue;\n }\n\n int idx[55] = {};\n int ans = 0, head = 0, len = n;\n rep(i, n) {\n int tail = i;\n rep(j, k) chmax(tail, pos[j][idx[j]]);\n if(tail-i+1 < len) ans = 0, head = i, len = tail-i+1;\n if(tail-i+1 == len) ans++;\n int p = a.find(s[i]);\n if(p != -1) {\n\tidx[p]++;\n\tif(idx[p] >= pos[p].size()) break;\n }\n }\n\n string t = s.substr(head, len);\n cout << ans << endl;\n rep(i, t.size()) {\n if(i%72 == 0) cout << endl;\n cout << t[i];\n }\n cout << endl << endl;\n getline(cin, line);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3476, "score_of_the_acc": -0.3254, "final_rank": 11 }, { "submission_id": "aoj_1215_2197064", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nstring S,K;\nconst int n = 1<<8;\n\nint getlen(){\n int mx[n],res=1e9;\n memset(mx,-1,sizeof(mx));\n for(int i=0;i<S.size();i++){\n int ch = S[i];\n mx[ch] = max(mx[ch],i);\n int c=0,l=1e9;\n for(int j=0;j<K.size();j++)c+=mx[K[j]]>=0,l=min(l,mx[K[j]]);\n if(c<K.size()) continue;\n res=min(res,i-l);\n }\n return res;\n}\n\nint count(int len){\n int cnt[n]={},res=0;\n for(int i=0;i<S.size();i++){\n cnt[S[i]]++;\n int c=0;\n for(int j=0;j<K.size();j++)c+=cnt[K[j]]>0;\n if(c==K.size())res++;\n if(i-len>=0) cnt[S[i-len]]--;\n }\n return res;\n}\n\nstring getstr(int len){\n int cnt[n]={},res=0;\n for(int i=0;i<S.size();i++){\n cnt[S[i]]++;\n int c=0;\n for(int j=0;j<K.size();j++)c+=cnt[K[j]]>0;\n if(c==K.size()) return S.substr(i-len,len+1);\n if(i-len>=0) cnt[S[i-len]]--;\n }\n return \"\";\n}\n\nint main(){\n while(1){\n S.clear();\n while(1){\n string s; \n getline(cin,s);\n if(s.empty()) break;\n S+=s;\n }\n if(S.empty())break;\n getline(cin,K);\n \n int len = getlen();\n cout<<count(len)<<endl;\n string str = getstr(len);\n for(int i=0;i<str.size();i++){\n if(i!=str.size()-1&&i%72==0)cout<<endl;\n cout<<str[i];\n }\n cout<<endl;\n if(len<1e9)cout<<endl;\n getline(cin,K); \n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3376, "score_of_the_acc": -0.3269, "final_rank": 12 }, { "submission_id": "aoj_1215_2196819", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nint main(){\n string buf;\n while(getline(cin,buf),buf!=\"\"){\n string s=buf;\n while(getline(cin,buf),buf!=\"\") s+=buf;\n string a;\n getline(cin,a);\n //cout<<s<<endl<<a<<endl;\n \n int n=a.size();\n vector<int> pos[n];\n for(int i=0;i<(int)s.size();i++)\n for(int j=0;j<n;j++)\n if(s[i]==a[j]) pos[j].push_back(i);\n \n bool f=1;\n for(int i=0;i<n;i++) f&=!!(pos[i].size());\n if(!f){\n cout<<0<<endl<<endl;\n getline(cin,buf);\n continue;\n }\n \n int idx[n];\n memset(idx,0,sizeof(idx));\n \n int ans=0,len=s.size()+1,head=0;\n for(int i=0;i<(int)s.size();i++){\n int nxt=i;\n for(int j=0;j<n;j++)\n nxt=max(nxt,pos[j][idx[j]]);\n \n if(nxt-i+1<len) ans=0,len=nxt-i+1,head=i;\n if(nxt-i+1==len) ans++;\n \n for(int j=0;j<n;j++){\n if(s[i]==a[j]) idx[j]++;\n if(idx[j]>=(int)pos[j].size()) goto LAB;\n }\n }\n \n LAB:\n string str=s.substr(head,len);\n \n cout<<ans<<endl;\n for(int i=0;i<(int)str.size();i++){\n if(i%72==0) cout<<endl;\n cout<<str[i];\n }\n cout<<endl<<endl;;\n //ready for next;\n getline(cin,buf);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3608, "score_of_the_acc": -0.3621, "final_rank": 14 }, { "submission_id": "aoj_1215_2196733", "code_snippet": "#include<bits/stdc++.h>\n#define M 1000005\n#define N 300\nusing namespace std;\nstring s,t,temp;\nint scnt[N],tcnt[N],ans[M],B[M],E[M];\n\nint main(){\n while(1){\n getline(cin,temp);\n if(temp==\"\")break;\n s=\"\";\n s+=temp;\n while(1){\n getline(cin,temp);\n s+=temp;\n if(temp==\"\")break;\n }\n getline(cin,temp);\n t=temp;\n getline(cin,temp);\n int flag=0;\n memset(tcnt,0,sizeof(tcnt));\n for(int i=0;i<(int)t.size();i++)\n tcnt[(int)t[i]]++;\n int cnt=0,idx=0;\n memset(scnt,0,sizeof(scnt));\n memset(ans,0,sizeof(ans)); \n for(int i=0;i<(int)s.size();i++){\n if(scnt[(int)s[i]]<tcnt[(int)s[i]])cnt++;\n scnt[(int)s[i]]++;\n if(cnt==t.size()){\n\tflag=1;\n\tif(!ans[i-idx+1]){\n\t B[i-idx+1]=idx;\n\t E[i-idx+1]=i;\n\t ans[i-idx+1]++;\n\t}else ans[i-idx+1]++;\n\twhile(1){\n\t if(scnt[(int)s[idx]]==tcnt[(int)s[idx]]){\n\t scnt[(int)s[idx]]--;\n\t idx++;\n\t cnt--;\n\t break;\n\t }\n\t scnt[(int)s[idx]]--;\n\t idx++;\n\t if(cnt==t.size()){\n\t if(!ans[i-idx+1]){\n\t B[i-idx+1]=idx;\n\t E[i-idx+1]=i;\n\t ans[i-idx+1]++;\n\t }else ans[i-idx+1]++;\n\t }\n\t}\n }\n }\n if(!flag)cout<<0<<endl<<endl;\n for(int i=0;i<M;i++)\n if(ans[i]){\n\tcout<<ans[i]<<endl<<endl;\n\tstring str=s.substr(B[i],E[i]-B[i]+1);\n\tfor(int j=0;j<str.size();j++){\n\t cout<<str[j];\n\t if(!((j+1)%72))cout<<endl;\n\t}\n\tif(str.size()%72)cout<<endl;\n\tcout<<endl;\n\tbreak;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7508, "score_of_the_acc": -1, "final_rank": 19 }, { "submission_id": "aoj_1215_2196625", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nint main(){\n string buf;\n while(getline(cin,buf),buf!=\"\"){\n string s=buf;\n while(getline(cin,buf),buf!=\"\") s+=buf;\n string a;\n getline(cin,a);\n //cout<<s<<endl<<a<<endl;\n \n int n=a.size();\n vector<int> pos[n];\n for(int i=0;i<(int)s.size();i++)\n for(int j=0;j<n;j++)\n\tif(s[i]==a[j]) pos[j].push_back(i);\n\n bool f=1;\n for(int i=0;i<n;i++) f&=!!(pos[i].size());\n if(!f){\n cout<<0<<endl<<endl;\n getline(cin,buf);\n continue;\n }\n \n int idx[n];\n memset(idx,0,sizeof(idx));\n \n int ans=0,len=s.size()+1,head=0;\n for(int i=0;i<(int)s.size();i++){\n int nxt=i;\n for(int j=0;j<n;j++)\n\tnxt=max(nxt,pos[j][idx[j]]);\n\n if(nxt-i+1<len) ans=0,len=nxt-i+1,head=i;\n if(nxt-i+1==len) ans++;\n\n for(int j=0;j<n;j++){\n\tif(s[i]==a[j]) idx[j]++;\n\tif(idx[j]>=(int)pos[j].size()) goto LAB;\n }\n }\n \n LAB:\n string str=s.substr(head,len);\n \n cout<<ans<<endl;\n for(int i=0;i<(int)str.size();i++){\n if(i%72==0) cout<<endl;\n cout<<str[i];\n }\n cout<<endl<<endl;;\n //ready for next;\n getline(cin,buf);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3448, "score_of_the_acc": -0.3393, "final_rank": 13 }, { "submission_id": "aoj_1215_1130392", "code_snippet": "/*\n000000000011111111112222222222333333333344444444\n012345678901234567890123456789012345678901234567\nTfefirstemampleistrivivlTfefirstemampleistrifivl\n . . .\nlen = 18 sp = 3\nlen = 15 sp = 11\nlen = 12 sp = 22\nlen = 12 sp = 35\nmfv\n \n000000000011111111112222222222\n012345678901234567890123456789\naabbccbbccaabbaacceeddffccaabb\n . ..\n \nlen = 4 sp = 1\n \nabc\n \n*/\n \n#include<set>\n#include<iostream>\n#include<cmath>\n#include<cstdio>\n \n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define inf (1<<29)\n \nusing namespace std;\n \nvoid compute(string text,string S)\n{\n int nt = text.size(),nS = S.size();\n int mlen = inf;\n string ans;\n set<string> all;\n bool found[nS];\n int CNT = 0;\n int fpos[nS];\n rep(i,nS)found[i] = false;\n \n rep(i,nt)\n {\n bool update = false;\n int cnt = 0,mn,mx;\n mn = inf,mx = -inf;\n rep(j,nS)\n {\n if(S[j] == text[i])\n {\n update = true;\n found[j] = true;\n fpos[j] = i;\n }\n if(found[j])\n {\n cnt++;\n mn = min(mn,fpos[j]);\n mx = max(mx,fpos[j]);\n }\n }\n if(cnt == nS)\n {\n int cost = mx - mn + 1;\n if(cost < mlen)\n {\n mlen = cost;\n ans = text.substr(mn,cost);\n all.clear();\n CNT = 1;\n all.insert(text.substr(mn,cost));\n }\n else if(cost == mlen)\n {\n if(update)CNT++;\n all.insert(text.substr(mn,cost));\n }\n }\n }\n cout << CNT << endl << endl;\n //printf(\"%d\\n\\n\",(int)all.size());\n \n if(all.empty())\n {\n return;\n }\n \n rep(i,ans.size())\n if((i+1)%72 == 0 && i != 0)\n printf(\"%c\\n\",ans[i]);\n else\n printf(\"%c\",ans[i]);\n if(ans.size()%72 != 0)puts(\"\\n\");\n else puts(\"\");\n}\n \nint main()\n{\n string blank;\n while(getline(cin,blank))\n {\n string text,S;\n text += blank;\n while(getline(cin,blank))\n {\n if(blank.empty())break;\n text += blank;\n }\n if(text.empty())goto Fin;\n while(getline(cin,blank))\n if(blank.empty())break;\n else S += blank;\n compute(text,S);\n }\n Fin:;\n return 0;\n}", "accuracy": 1, "time_ms": 550, "memory_kb": 2652, "score_of_the_acc": -0.4174, "final_rank": 16 }, { "submission_id": "aoj_1215_1100289", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n while(1) {\n string s=\"\",t,r;\n getline(cin,s);\n if(s==\"\") break;\n while(1) {\n getline(cin,r);\n if(r==\"\") break;\n s+=r;\n }\n getline(cin,t);\n getline(cin,r);\n \n map<char,int> m,d;\n m.clear();\n d.clear();\n for(int i=0; i<t.size(); i++) d[t[i]]=1;\n vector<int> v;\n for(int i=0; i<s.size(); i++) {\n if(d[s[i]]==1) v.push_back(i);\n }\n int x=0,cnt=0;\n string ans=s;\n for(int i=0; i<v.size(); i++) {\n char c=s[v[i]];\n m[c]++;\n if(m.size()==t.size()) {\n\twhile(m[s[v[x]]]>1) {\n\t m[s[v[x]]]--;\n\t x++;\n\t}\n\tif(ans.size()==v[i]-v[x]+1) {\n\t cnt++;\n\t} else if(ans.size()>v[i]-v[x]+1) {\n\t cnt=1;\n\t ans=s.substr(v[x],v[i]-v[x]+1);\n\t}\n }\n }\n \n if(cnt==0) cout << cnt << endl;\n else {\n cout << cnt << endl << endl;\n for(int i=0; i<ans.size(); i++) {\n\tcout << ans[i];\n\tif((i+1)%72==0) cout << endl;\n }\n if(ans.size()%72) cout << endl;\n }\n cout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 2116, "score_of_the_acc": -0.0776, "final_rank": 9 }, { "submission_id": "aoj_1215_1081269", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n\n#include <iostream>\n#include <cstdio>\n#include <sstream>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <queue>\n#include <stack>\n#include <limits>\n#include <map>\n#include <string>\n#include <cstring>\n#include <set>\n#include <deque>\n#include <bitset>\n#include <list>\n#include <cctype>\n#include <utility>\n#include <assert.h>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair <int,int> P;\ntypedef pair <int,P> PP;\n \nstatic const double EPS = 1e-8;\n\nvoid print_text(const string& text){\n int offset = 0;\n int text_i = 0;\n while(offset < text.size()){\n for(text_i = offset; text_i < text.size(); text_i++){\n if(text_i - offset >= 72) break;\n printf(\"%c\",text[text_i]);\n }\n printf(\"\\n\");\n offset += 72;\n }\n}\n\nvoid print_co_occurrence(const string& text,const string& query){\n\n int head = 0;\n int tail = 0;\n\n int include_keys = 0;\n int freq[256] = {};\n\n bool is_key[256];\n memset(is_key,false,sizeof(is_key));\n\n for(int query_i = 0; query_i < query.size(); query_i++){\n is_key[query[query_i]] = true;\n }\n\n int min_tail = INF;\n int min_len = INF;\n int ans_freq = 0;\n string ans = \"\";\n\n while(tail < text.size()){\n for(;head < text.size();head++){\n if(is_key[text[head]] && !freq[text[head]]++){\n include_keys++;\n if(include_keys == query.size()){\n head++;\n break;\n }\n }\n }\n\n for(;tail <= head;tail++){\n if(is_key[text[tail]] && !--freq[text[tail]]){\n\n if(include_keys == query.size()) {\n if((head -1) - tail + 1 < min_len){\n min_len = (head -1) - tail + 1;\n ans = text.substr(tail,(head -1) - tail + 1);\n ans_freq = 1;\n }\n else if((head -1) - tail + 1 == min_len){\n ans_freq++;\n }\n }\n include_keys--;\n tail++;\n break;\n }\n }\n }\n\n if(ans_freq == 0){\n printf(\"%d\\n\",ans_freq);\n printf(\"\\n\");\n }\n else{\n printf(\"%d\\n\",ans_freq);\n printf(\"\\n\");\n print_text(ans);\n printf(\"\\n\");\n }\n}\n\nint main(){\n string str;\n int phase = 0;\n string text = \"\";\n string query = \"\";\n while(getline(cin,str)){\n if(str.size() == 0){\n phase++;\n continue;\n }\n if(phase % 2 == 0){\n text += str;\n }\n else{\n query = str;\n\n print_co_occurrence(text,query);\n \n query = \"\";\n text = \"\";\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1844, "score_of_the_acc": -0.0308, "final_rank": 2 }, { "submission_id": "aoj_1215_1081268", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n\n#include <iostream>\n#include <cstdio>\n#include <sstream>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <queue>\n#include <stack>\n#include <limits>\n#include <map>\n#include <string>\n#include <cstring>\n#include <set>\n#include <deque>\n#include <bitset>\n#include <list>\n#include <cctype>\n#include <utility>\n#include <assert.h>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair <int,int> P;\ntypedef pair <int,P> PP;\n \nstatic const double EPS = 1e-8;\n\nvoid print_text(const string& text){\n int offset = 0;\n int text_i = 0;\n while(offset < text.size()){\n for(text_i = offset; text_i < text.size(); text_i++){\n if(text_i - offset >= 72) break;\n printf(\"%c\",text[text_i]);\n }\n printf(\"\\n\");\n offset += 72;\n }\n}\n\nvoid print_co_occurrence(const string& text,const string& query){\n\n int head = 0;\n int tail = 0;\n\n int include_keys = 0;\n int freq[1024] = {};\n\n bool is_key[1024];\n memset(is_key,false,sizeof(is_key));\n\n for(int query_i = 0; query_i < query.size(); query_i++){\n is_key[query[query_i]] = true;\n }\n\n int min_tail = INF;\n int min_len = INF;\n int ans_freq = 0;\n string ans = \"\";\n\n while(tail < text.size()){\n for(;head < text.size();head++){\n if(is_key[text[head]] && !freq[text[head]]++){\n include_keys++;\n if(include_keys == query.size()){\n head++;\n break;\n }\n }\n }\n\n for(;tail <= head;tail++){\n if(is_key[text[tail]] && !--freq[text[tail]]){\n\n if(include_keys == query.size()) {\n if((head -1) - tail + 1 < min_len){\n min_len = (head -1) - tail + 1;\n ans = text.substr(tail,(head -1) - tail + 1);\n ans_freq = 1;\n }\n else if((head -1) - tail + 1 == min_len){\n ans_freq++;\n }\n }\n include_keys--;\n tail++;\n break;\n }\n }\n }\n\n if(ans_freq == 0){\n printf(\"%d\\n\",ans_freq);\n printf(\"\\n\");\n }\n else{\n printf(\"%d\\n\",ans_freq);\n printf(\"\\n\");\n print_text(ans);\n printf(\"\\n\");\n }\n}\n\nint main(){\n string str;\n int phase = 0;\n string text = \"\";\n string query = \"\";\n while(getline(cin,str)){\n if(str.size() == 0){\n phase++;\n continue;\n }\n if(phase % 2 == 0){\n text += str;\n }\n else{\n query = str;\n\n print_co_occurrence(text,query);\n \n query = \"\";\n text = \"\";\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1848, "score_of_the_acc": -0.0315, "final_rank": 3 }, { "submission_id": "aoj_1215_902066", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <sstream>\n#include <cstring>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n#include <numeric>\n#include <cctype>\n#include <tuple>\n\n#ifdef _MSC_VER\n#include <agents.h>\n#endif\n\n#define FOR(i, a, b) for(int i = (a); i < (int)(b); ++i)\n#define rep(i, n) FOR(i, 0, n)\n#define ALL(v) v.begin(), v.end()\n#define REV(v) v.rbegin(), v.rend()\n#define MEMSET(v, s) memset(v, s, sizeof(v))\n#define X first\n#define Y second\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> P;\n\nint valid[256];\nint cnt[256];\nint kind;\n\nvoid add(char c){\n\tif (!valid[c]) return;\n\tif (cnt[c]++) return;\n\t++kind;\n}\n\nvoid sub(char c){\n\tif (!valid[c]) return;\n\tif (--cnt[c]) return;\n\t--kind;\n}\n\nint main(){\n\tstring str, key;\n\twhile (1){\n\t\tstr.clear();\n\t\tkey.clear();\n\n\t\twhile (true){\n\t\t\tgetline(cin, key);\n\t\t\tif (key.empty() || !cin) break;\n\t\t\tstr += key;\n\t\t}\n\t\tif (str.empty() || !cin) break;\n\n\t\tgetline(cin, key);\n\t\tcin.ignore();\n\n\t\t//cout << str << endl;\n\t\t//cout << key << endl;\n\t\tMEMSET(cnt, 0);\n\t\tMEMSET(valid, 0);\n\t\tkind = 0;\n\t\tfor (auto &c : key) valid[c] = 1;\n\t\tint n = str.size(), m = key.size();\n\n\t\tint l = 0, r = 0;\n\t\tint ans = n + 1;\n\t\tint anscnt = 0;\n\t\tP p;\n\t\twhile (1){\n\t\t\twhile (kind < m && r < n){\n\t\t\t\tadd(str[r++]);\n\t\t\t}\n\t\t\tif (kind == m){\n\t\t\t\tif (r - l < ans){\n\t\t\t\t\tans = r - l;\n\t\t\t\t\tp = make_pair(l, r);\n\t\t\t\t\tanscnt = 1;\n\t\t\t\t}\n\t\t\t\telse if (r - l == ans){\n\t\t\t\t\t++anscnt;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (l >= r) break;\n\t\t\tsub(str[l++]);\n\t\t}\n\n\t\tcout << anscnt << endl;\n\t\tint chr = 0;\n\t\tif (anscnt){\n\t\t\tcout << endl;\n\t\t\tfor (int i = p.first; i < p.second; ++i){\n\t\t\t\tcout << str[i];\n\t\t\t\t++chr;\n\t\t\t\tif (chr % 72 == 0) cout << endl;\n\t\t\t}\n\t\t\tif (chr % 72) cout << endl;\n\t\t}\n\t\tcout << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1692, "score_of_the_acc": -0.0047, "final_rank": 1 }, { "submission_id": "aoj_1215_794481", "code_snippet": "#include<iostream>\n#include<cmath>\n#include<cstdio>\n \n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define inf (1<<29)\n \nusing namespace std;\n \nvoid compute(string text,string S)\n{\n int nt = text.size(),nS = S.size();\n int mlen = inf;\n string ans;\n bool found[nS];\n int CNT = 0;\n int fpos[nS];\n rep(i,nS)found[i] = false;\n \n rep(i,nt)\n {\n bool update = false;\n int cnt = 0,mn,mx;\n mn = inf,mx = -inf;\n rep(j,nS)\n\t{\n\t if(S[j] == text[i])\n\t {\n\t update = true;\n\t found[j] = true;\n\t fpos[j] = i;\n\t }\n\t if(found[j])\n\t {\n\t cnt++;\n\t mn = min(mn,fpos[j]);\n\t mx = max(mx,fpos[j]);\n\t }\n\t}\n if(cnt == nS)\n\t{\n\t int cost = mx - mn + 1;\n\t if(cost < mlen)\n\t {\n\t mlen = cost;\n\t ans = text.substr(mn,cost);\n\t CNT = 1;\n\t }\n\t else if(cost == mlen && update)CNT++;\t \n\t}\n }\n cout << CNT << endl << endl;\n if(!CNT)return;\n\n rep(i,ans.size())\n if((i+1)%72 == 0 && i != 0)\n printf(\"%c\\n\",ans[i]);\n else\n printf(\"%c\",ans[i]);\n if(ans.size()%72 != 0)puts(\"\\n\");\n else puts(\"\");\n}\n \nint main()\n{\n string blank;\n while(getline(cin,blank))\n {\n string text,S;\n text += blank;\n while(getline(cin,blank))\n\t{\n\t if(blank.empty())break;\n\t text += blank;\n\t}\n if(text.empty())goto Fin;\n while(getline(cin,blank))\n\tif(blank.empty())break;\n\telse S += blank;\n compute(text,S);\n }\n Fin:;\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 2384, "score_of_the_acc": -0.161, "final_rank": 10 }, { "submission_id": "aoj_1215_794479", "code_snippet": "/*\n000000000011111111112222222222333333333344444444\n012345678901234567890123456789012345678901234567\nTfefirstemampleistrivivlTfefirstemampleistrifivl\n . . .\nlen = 18 sp = 3\nlen = 15 sp = 11\nlen = 12 sp = 22\nlen = 12 sp = 35\nmfv\n \n000000000011111111112222222222\n012345678901234567890123456789\naabbccbbccaabbaacceeddffccaabb\n . ..\n \nlen = 4 sp = 1\n \nabc\n \n*/\n \n#include<set>\n#include<iostream>\n#include<cmath>\n#include<cstdio>\n \n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define inf (1<<29)\n \nusing namespace std;\n \nvoid compute(string text,string S)\n{\n int nt = text.size(),nS = S.size();\n int mlen = inf;\n string ans;\n set<string> all;\n bool found[nS];\n int CNT = 0;\n int fpos[nS];\n rep(i,nS)found[i] = false;\n \n rep(i,nt)\n {\n bool update = false;\n int cnt = 0,mn,mx;\n mn = inf,mx = -inf;\n rep(j,nS)\n\t{\n\t if(S[j] == text[i])\n\t {\n\t update = true;\n\t found[j] = true;\n\t fpos[j] = i;\n\t }\n\t if(found[j])\n\t {\n\t cnt++;\n\t mn = min(mn,fpos[j]);\n\t mx = max(mx,fpos[j]);\n\t }\n\t}\n if(cnt == nS)\n\t{\n\t int cost = mx - mn + 1;\n\t if(cost < mlen)\n\t {\n\t mlen = cost;\n\t ans = text.substr(mn,cost);\n\t all.clear();\n\t CNT = 1;\n\t all.insert(text.substr(mn,cost));\n\t }\n\t else if(cost == mlen)\n\t {\n\t if(update)CNT++;\n\t all.insert(text.substr(mn,cost));\n\t }\n\t}\n }\n cout << CNT << endl << endl;\n //printf(\"%d\\n\\n\",(int)all.size());\n \n if(all.empty())\n {\n return;\n }\n\n rep(i,ans.size())\n if((i+1)%72 == 0 && i != 0)\n printf(\"%c\\n\",ans[i]);\n else\n printf(\"%c\",ans[i]);\n if(ans.size()%72 != 0)puts(\"\\n\");\n else puts(\"\");\n}\n \nint main()\n{\n string blank;\n while(getline(cin,blank))\n {\n string text,S;\n text += blank;\n while(getline(cin,blank))\n\t{\n\t if(blank.empty())break;\n\t text += blank;\n\t}\n if(text.empty())goto Fin;\n while(getline(cin,blank))\n\tif(blank.empty())break;\n\telse S += blank;\n compute(text,S);\n }\n Fin:;\n return 0;\n}", "accuracy": 1, "time_ms": 550, "memory_kb": 2656, "score_of_the_acc": -0.4181, "final_rank": 17 }, { "submission_id": "aoj_1215_793468", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <string>\n#include <map>\n#include <set>\nusing namespace std;\n \n#define FOUND 1\n#define NOT_FOUND -1\n \nbool compare(string s1, string s2){\n if(s1.size() == s2.size()) return s1 < s2;\n return s1.size() < s2.size();\n} \n \nint main(){\n string in, sub;\n string seq;\n bool flag = true;\n while(getline(cin, in)){\n if(!flag && (in.size() == 0 || cin.eof())){\n if(cin.eof()) sub += in; \n flag = true;\n \n map<char, int > mp;\n set<char> data;\n \n for(int i = 0 ; i < sub.size() ; i++) data.insert(sub[i]);\n for(int i = 0 ; i < sub.size() ; i++) mp[ sub[i] ] = NOT_FOUND;\n \n int ans = 0;\n int len = (1<<29);\n string ans2;\n \n for(int i = 0 ; i < seq.size() ; i++){\n if(data.find(seq[i]) == data.end()) continue;\n mp[ seq[i] ] = i;\n \n int left = (1<<29);\n bool ok = true;\n for(int j = 0 ; j < sub.size() ; j++){\n if(mp[ sub[j] ] == NOT_FOUND){\n ok = false;\n break;\n }\n left = min(left, mp[ sub[j] ]);\n }\n \n if(!ok) continue;\n \n if(i - left == len) ans++;\n if(i - left < len){\n len = i - left;\n ans = 1;\n //cout << \"i = \" << i << \" left = \" << left << endl;\n //cout << i << endl;\n ans2 = seq.substr(left, i-left+1);\n //cout << seq.substr(left, i-left+1) << endl;\n }\n \n }\n \n cout << ans << endl << endl;\n if(ans != 0){\n for(int i = 0 ; i < ans2.size() ; i += 72){\n cout << ans2.substr(i, 72) << endl;\n }\n if(!cin.eof()) cout << endl;\n }\n \n //cout << \"ans_len = \" << len << endl;\n //cout << \"ans_cnt = \" << ans << endl;\n //cout << \"seq = \" << seq << endl;\n //cout << \"sub = \" << sub << endl;\n //cout << endl;\n seq = \"\", sub = \"\";\n continue;\n }\n else if(flag && in.size() != 0){\n seq += in;\n continue;\n }\n else if(flag && in.size() == 0){\n flag = false;\n continue;\n }\n else if(!flag && in.size() != 0){\n sub += in;\n continue;\n }\n \n \n \n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 1832, "score_of_the_acc": -0.0474, "final_rank": 5 }, { "submission_id": "aoj_1215_793466", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <string>\n#include <map>\n#include <set>\nusing namespace std;\n\n#define FOUND 1\n#define NOT_FOUND -1\n\nbool compare(string s1, string s2){\n if(s1.size() == s2.size()) return s1 < s2;\n return s1.size() < s2.size();\n} \n\nint main(){\n string in, sub;\n string seq;\n bool flag = true;\n while(getline(cin, in)){\n if(!flag && (in.size() == 0 || cin.eof())){\n if(cin.eof()) sub += in; \n flag = true;\n \n map<char, int > mp;\n set<char> data;\n\n for(int i = 0 ; i < sub.size() ; i++) data.insert(sub[i]);\n for(int i = 0 ; i < sub.size() ; i++) mp[ sub[i] ] = NOT_FOUND;\n \n int ans = 0;\n int len = (1<<29);\n string ans2;\n \n for(int i = 0 ; i < seq.size() ; i++){\n\tif(data.find(seq[i]) == data.end()) continue;\n\tmp[ seq[i] ] = i;\n\t\n\tint left = (1<<29);\n\tbool ok = true;\n\tfor(int j = 0 ; j < sub.size() ; j++){\n\t if(mp[ sub[j] ] == NOT_FOUND){\n\t ok = false;\n\t break;\n\t }\n\t left = min(left, mp[ sub[j] ]);\n\t}\n\t\n\tif(!ok) continue;\n\t\n\tif(i - left == len) ans++;\n\tif(i - left < len){\n\t len = i - left;\n\t ans = 1;\n\t //cout << \"i = \" << i << \" left = \" << left << endl;\n\t //cout << i << endl;\n\t ans2 = seq.substr(left, i-left+1);\n\t //cout << seq.substr(left, i-left+1) << endl;\n\t}\n\t\n }\n \n cout << ans << endl << endl;\n if(ans != 0){\n\tfor(int i = 0 ; i < ans2.size() ; i += 72){\n\t cout << ans2.substr(i, 72) << endl;\n\t}\n\tif(!cin.eof()) cout << endl;\n }\n\n //cout << \"ans_len = \" << len << endl;\n //cout << \"ans_cnt = \" << ans << endl;\n //cout << \"seq = \" << seq << endl;\n //cout << \"sub = \" << sub << endl;\n //cout << endl;\n seq = \"\", sub = \"\";\n continue;\n }\n else if(flag && in.size() != 0){\n seq += in;\n continue;\n }\n else if(flag && in.size() == 0){\n flag = false;\n continue;\n }\n else if(!flag && in.size() != 0){\n sub += in;\n continue;\n }\n \n \n\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 1832, "score_of_the_acc": -0.0521, "final_rank": 6 }, { "submission_id": "aoj_1215_793406", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\n\n#define INF (1<<29)\n#define all(c) (c).begin(),(c).end()\n\nusing namespace std;\n\n\nint main(void){\n\n string s,t,in;\n bool f=false;\n while(true){\n s.clear();\n t.clear();\n while(true){\n getline(cin,in);\n if(in.size()==0)break;\n s+=in;\n }\n\n while(true){\n getline(cin,in);\n if(in.size()==0)break;\n t+=in;\n }\n\n if(s.size()==0 && t.size()==0)break;\n\n //if(f)cout << endl;\n f=true;\n\n int sl=s.size(),tl=t.size();\n int now[tl],ans=0;\n string res=\"\";\n\n fill(now,now+tl,INF);\n\n int tmp=0;\n for(int i=0;i<sl;i++){\n for(int j=0;j<tl;j++){\n if(s[i]==t[j]){\n now[j]=min(now[j],i);\n }\n }\n }\n\n bool flag=false;\n for(int i=0;i<tl;i++){\n flag|=(now[i]>=INF);\n }\n if(flag){\n cout << 0 << endl << endl;;\n continue;\n }\n\n int left=INF,right=-1,lid,rid;\n for(int i=0;i<tl;i++){\n if(left>now[i])left=now[i],lid=i;\n if(right<now[i])right=now[i],rid=i;\n }\n ans++;\n res=s.substr(left,right-left+1);\n\n while(true){\n int mn=INF,id=0;\n for(int i=0;i<tl;i++){\n if(mn>now[i])mn=now[i],id=i;\n }\n while(now[id]<sl && s[++now[id]]!=t[id]);\n if(s[now[id]]!=t[id])break;\n int l=INF,r=0;\n bool fg=true;\n for(int i=0;i<tl;i++){\n l=min(l,now[i]);\n r=max(r,now[i]);\n fg&=(now[i]>=sl-1);\n }\n if(fg)break;\n if(res.size()>r-l+1){\n ans=0;\n res=s.substr(l,r-l+1);\n }\n if(res.size()==r-l+1)ans++;\n }\n cout << ans << endl << endl;\n for(int i=0;i<res.size();i++){\n cout << res[i];\n if((i+1)%72==0)cout << endl;\n }\n if(res.size()%72>0)cout << endl;\n cout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 1828, "score_of_the_acc": -0.0654, "final_rank": 8 }, { "submission_id": "aoj_1215_793371", "code_snippet": "#include<iostream>\n#include<map>\n#include<cstring>\n\nusing namespace std;\n\nconst int MAX = 51;\n\nstring text, key;\nmap<char,int> M;\nint numKey[MAX];\n\ntypedef long long ll;\n\nbool input(){\n text = \"\";\n\n string s = \"\";\n if(!getline(cin,s)) return false;\n if(s == \"\") return false;\n text = s;\n while(getline(cin,s)&&s!=\"\") text += s;\n getline(cin,s);\n key = s;\n getline(cin,s); // for blank line\n return true;\n}\n\n\n\nvoid solve(){\n\n memset(numKey,0,sizeof(numKey));\n\n M.clear();\n for(int i = 0; i < (int)key.length(); i++)\n M[key[i]] = i;\n\n ll need = (1LL<<key.length())-1;\n\n string first = \"\";\n int num = 0;\n\n int s = 0, t = 0;\n\n while(s <= t && t <= (int)text.length()){\n if(need == 0){\n // if(text.size() > 400 && t-s < 50) cout << text.substr(s,t-s) << endl;\n if(first != \"\" && (int)first.length() == t-s){\n\tnum++;\n }\n if(first == \"\" || (int)first.length() > t-s){\n\tfirst = text.substr(s,t-s);\n\tnum = 1;\n }\n\n if(M.count(text[s]) != 0){\n\tnumKey[M[text[s]]]--;\n\tif(numKey[M[text[s]]] == 0) need |= (1LL<<M[text[s]]);\n }\n s++;\n }else{\n if(M.count(text[t]) != 0){\n\tif(need&(1LL<<M[text[t]])) need -= (1LL<<M[text[t]]);\n\tnumKey[M[text[t]]]++;\n }\n t++;\n }\n }\n // cout << \"min \" << minT << endl;\n if(num == 0) cout << num << endl;\n else{\n cout << num << endl << endl;\n\n for(int i = 0; i < (int)first.length(); i++){\n cout << first[i];\n if((i+1)%72 == 0) cout<<endl;\n }\n if((int)first.size()%72)cout << endl;\n }\n cout << endl;\n}\t \n\nint main(){\n\n // bool isFirst = true;\n while(input()){\n // if(isFirst) isFirst = false;\n // else cout << endl;\n solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 1832, "score_of_the_acc": -0.0521, "final_rank": 6 }, { "submission_id": "aoj_1215_772986", "code_snippet": "#include <iostream>\n#include <string>\n#include <algorithm>\nusing namespace std;\n\nstring S,K;\nconst int INF=1<<28;\n\nvoid solve(){\n\tstring ans;\n\tint len=INF, cnt=0;\n\tint left=INF;\n\tint idx[K.length()];\n//\tfill(begin(idx), end(idx), 0);\n\tfor(int i=0; i<K.length(); ++i)idx[i]=-1;\n\n\tfor(int p=0; p<S.length(); ++p){\n\t\tfor(int k=0; k<K.length(); ++k){\n\t\t\tif(S[p]==K[k]){\n\t\t\t\tidx[k]=p;\n\t\t\t\tleft=INF;\n\t\t\t\tfor(int i=0; i<K.length(); ++i)\tleft=min(left, idx[i]);\n\t\t\t\tif(left>=0){\n//\t\t\t\t\tcout << left << \" \" << p << endl;\n\t\t\t\t\tstring cand=S.substr(left, p-left+1);\n\t\t\t\t\tif(len>cand.length()){\n\t\t\t\t\t\tcnt=1;\n\t\t\t\t\t\tlen=cand.length();\n\t\t\t\t\t\tans=cand;\n\t\t\t\t\t}else if(len==cand.length()){\n\t\t\t\t\t\t++cnt;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tif(len>=INF){\n\t\tcout << 0 << endl;\n\t}else{\n\t\tcout << cnt << endl;\n\t\tcout << endl;\n\n\t\tfor(int i=0; i<ans.size(); ++i){\n\t\t\tif(i>0 && i%72==0)\tcout<<endl;\n\t\t\tcout << ans[i];\n\t\t}\n\t\tcout<<endl;\n\t}\n\tcout<<endl;\n}\n\nint main(){\n\tfor(int cnt=0;;++cnt){\n\t\tstring tmp;\n\t\tif(getline(cin,tmp).eof())\tbreak;\n\t\tif(tmp==\"\")\tbreak;\n\t\tS=tmp;\n\t\twhile(true){\n\t\t\tgetline(cin,tmp);\n\t\t\tif(tmp==\"\")\tbreak;\n\t\t\tS+=tmp;\n\t\t}\n\t\tgetline(cin,K);\n\t\tgetline(cin,tmp);\n//\t\tcout<<S<<endl;\n//\t\tcout<<K<<endl;\n//\t\tif(cnt>0)\tcout<<endl;\n\t\tsolve();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 1828, "score_of_the_acc": -0.0467, "final_rank": 4 }, { "submission_id": "aoj_1215_605320", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <set>\n#include <map>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <cassert>\n\nusing namespace std;\n\n#define FOR(i,k,n) for(int i=(k); i<(int)(n); ++i)\n#define REP(i,n) FOR(i,0,n)\n#define FORIT(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n\ntemplate<class T> void debug(T begin, T end){ for(T i = begin; i != end; ++i) cerr<<*i<<\" \"; cerr<<endl; }\ninline bool valid(int x, int y, int W, int H){ return (x >= 0 && y >= 0 && x < W && y < H); }\n\ntypedef long long ll;\nconst int INF = 100000000;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\nint dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};\nint dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};\n\nint main(){\n bool begin = true;\n while(true){\n string s, text, query;\n while(getline(cin, s) && s != \"\"){\n text += s;\n }\n if(text == \"\") break;\n getline(cin, query);\n assert(query != \"\");\n getline(cin, s); // empty\n assert(s == \"\");\n\n /*\n if(begin) begin = false;\n else cout << endl;\n */\n\n int N = text.size();\n int L = query.size();\n\n map<char, int> to_idx;\n REP(i, L) to_idx[query[i]] = i;\n\n vector<int> idx_vec[100];\n REP(i, N) if(to_idx.count(text[i])) idx_vec[to_idx[text[i]]].push_back(i);\n\n bool ok = true;\n REP(i, L) if(idx_vec[i].empty()) ok = false;\n if(!ok){\n cout << 0 << endl;\n cout << endl;\n continue;\n }\n\n map<int, set<int> > cnt;\n int shortest_length = INF;\n vector<int> cur(L);\n while(true){\n int b = idx_vec[0][cur[0]], e = idx_vec[0][cur[0]];\n REP(i, L) {\n b = min(b, idx_vec[i][cur[i]]);\n e = max(e, idx_vec[i][cur[i]]);\n }\n int l = e - b + 1;\n shortest_length = min(shortest_length, l);\n if(shortest_length == l) cnt[l].insert(b);\n\n int idx = -1;\n REP(i, L)if(cur[i] + 1 < idx_vec[i].size()){\n if(idx == -1 || idx_vec[i][cur[i] + 1] < idx_vec[idx][cur[idx] + 1]){\n idx = i;\n }\n }\n if(idx == -1) break;\n cur[idx] += 1;\n }\n cout << cnt[shortest_length].size() << endl;\n cout << endl;\n string ans = text.substr(*cnt[shortest_length].begin(), shortest_length);\n for(int i = 0; i < ans.size(); i += 72){\n if(i + 72 < ans.size()) cout << ans.substr(i, 72) << endl;\n else cout << ans.substr(i) << endl;\n }\n cout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3712, "score_of_the_acc": -0.366, "final_rank": 15 }, { "submission_id": "aoj_1215_525767", "code_snippet": "//47\n#include<iostream>\n#include<sstream>\n#include<string>\n#include<map>\n#include<algorithm>\n#include<set>\n\nusing namespace std;\n\nint main(){\n for(string si;getline(cin,si),si!=\"\";){\n string s;\n do{\n s+=si;\n getline(cin,si);\n }while(si!=\"\");\n string k;\n getline(cin,k);\n cin.ignore();\n map<char,int> m;\n int f=0,l=1<<30;\n int n=0;\n set<long long> st;\n for(int i=0;i<s.size();i++){\n if(k.find(s[i])!=string::npos){\n\tm[s[i]]=i;\n }\n if(m.size()!=k.size())continue;\n int cl=0,cf=1<<30;\n for(int j=0;j<k.size();j++){\n\tcl=max(cl,m[k[j]]);\n\tcf=min(cf,m[k[j]]);\n }\n if(!st.insert((long long)cl<<32|cf).second)continue;\n if(cl-cf<=l-f){\n\tif(cl-cf<l-f){\n\t f=cf;\n\t l=cl;\n\t n=0;\n\t}\n\tn++;\n }\n }\n cout<<n<<endl<<endl;\n if(n){\n string t=s.substr(f,l-f+1);\n for(int i=0;i<t.size();i+=72){\n\tcout<<t.substr(i,72)<<endl;\n }\n cout<<endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 3424, "score_of_the_acc": -0.424, "final_rank": 18 } ]
aoj_1217_cpp
Problem B: Family Tree A professor of anthropology was interested in people living in isolated islands and their history. He collected their family trees to conduct some anthropological experiment. For the experiment, he needed to process the family trees with a computer. For that purpose he translated them into text files. The following is an example of a text file representing a family tree. John Robert Frank Andrew Nancy David Each line contains the given name of a person. The name in the first line is the oldest ancestor in this family tree. The family tree contains only the descendants of the oldest ancestor. Their husbands and wives are not shown in the family tree. The children of a person are indented with one more space than the parent. For example, Robert and Nancy are the children of John, and Frank and Andrew are the children of Robert. David is indented with one more space than Robert, but he is not a child of Robert, but of Nancy. To represent a family tree in this way, the professor excluded some people from the family trees so that no one had both parents in a family tree. For the experiment, the professor also collected documents of the families and extracted the set of statements about relations of two persons in each family tree. The following are some examples of statements about the family above. John is the parent of Robert. Robert is a sibling of Nancy. David is a descendant of Robert. For the experiment, he needs to check whether each statement is true or not. For example, the first two statements above are true and the last statement is false. Since this task is tedious, he would like to check it by a computer program. Input The input contains several data sets. Each data set consists of a family tree and a set of statements. The first line of each data set contains two integers n (0 < n < 1000) and m (0 < m < 1000) which represent the number of names in the family tree and the number of statements, respectively. Each line of the input has less than 70 characters. As a name, we consider any character string consisting of only alphabetic characters. The names in a family tree have less than 20 characters. The name in the first line of the family tree has no leading spaces. The other names in the family tree are indented with at least one space, i.e., they are descendants of the person in the first line. You can assume that if a name in the family tree is indented with k spaces, the name in the next line is indented with at most k + 1 spaces. This guarantees that each person except the oldest ancestor has his or her parent in the family tree. No name appears twice in the same family tree. Each line of the family tree contains no redundant spaces at the end. Each statement occupies one line and is written in one of the following formats, where X and Y are different names in the family tree. X is a child of Y . X is the parent of Y . X is a sibling of Y . X is a descendant of Y . X is an ancestor of Y . Names not appe ...(truncated)
[ { "submission_id": "aoj_1217_2170790", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint dep[100010];\nint par[100010][19];\nvector<int> g[100010];\nvoid dfs(int v,int u,int d){\n dep[v]=d;\n for(int i=0; i<g[v].size(); i++){\n int w=g[v][i];if(w==u) continue;\n par[w][0]=v;dfs(w,v,d+1);\n }\n}\nint lcp(int a,int b){\n if(dep[a]<dep[b]) swap(a,b);\n for(int i=0; i<19; i++){\n if((dep[a]-dep[b])&(1<<i)) a=par[a][i];\n }\n if(a==b) return a;\n for(int i=18;i>=0;i--){\n if(par[a][i]!=par[b][i]) a=par[a][i],b=par[b][i];\n }\n return par[a][0];\n}\nint n,m;\nvoid init() {\n memset(par,0,sizeof(par));\n dfs(0,-1,0);\n for(int i=0; i<18; i++)for(int j=0; j<n; j++) par[j][i+1]=par[par[j][i]][i];\n}\n\nstring r[111111];\nint main() {\n while(cin >> n >> m && n) {\n for(int i=0; i<n; i++) g[i].clear();\n string s;\n getline(cin,s);\n map<string,int> ma;\n for(int i=0; i<n; i++) {\n getline(cin,s);\n stringstream ss;\n string t;\n ss << s;\n ss >> t;\n ma[t]=i;\n int c=0;\n for(int j=0; j<s.size(); j++) {\n if(s[j]==' ') c++;\n else break;\n }\n if(c) {\n g[ma[t]].push_back(ma[r[c-1]]);\n g[ma[r[c-1]]].push_back(ma[t]);\n }\n r[c]=t;\n }\n init();\n while(m--) {\n getline(cin,s);\n stringstream ss;\n ss << s;\n string x,y,z;\n ss >> x;\n ss >> z;ss >> z;ss >> z;\n ss >> y;ss >> y;\n y=y.substr(0,y.size()-1);\n int xx=ma[x],yy=ma[y];\n bool f=0;\n if(z==\"parent\") {\n if(lcp(xx,yy)==xx&&dep[yy]-dep[xx]==1) f=1;\n } else if(z==\"child\") {\n if(lcp(xx,yy)==yy&&dep[xx]-dep[yy]==1) f=1;\n } else if(z==\"sibling\") {\n if(dep[xx]==dep[yy]&&dep[xx]-dep[lcp(xx,yy)]==1) f=1;\n } else if(z==\"descendant\") {\n if(lcp(xx,yy)==yy&&dep[xx]-dep[yy]>=1) f=1;\n } else {\n if(lcp(xx,yy)==xx&&dep[yy]-dep[xx]>=1) f=1;\n }\n if(f) cout << \"True\" << endl;\n else cout << \"False\" << endl;\n }\n cout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 13916, "score_of_the_acc": -1, "final_rank": 18 }, { "submission_id": "aoj_1217_2065883", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\n\n//// < \"d:\\d_download\\visual studio 2015\\projects\\programing_contest_c++\\debug\\a.txt\" > \"d:\\d_download\\visual studio 2015\\projects\\programing_contest_c++\\debug\\b.txt\"\n\nstruct tree {\n\tstring name;\n\tint depth;\n\tvector<unique_ptr<tree>>childs;\n\ttree(const string _name,const int _depth) :name(_name),depth(_depth),childs() {\n\n\t}\n};\nunique_ptr<tree> maketree(vector<string>&sts, vector<int>&ns,int depth,int &a) {\n\tunique_ptr<tree> t(std::make_unique<tree>(sts[a],depth));\n\twhile (a+1!=sts.size()&&ns[a+1] > depth) {\n\t\ta++;\n\t\tt->childs.push_back(maketree(sts, ns, depth + 1, a));\n\t\t\n\t}\n\treturn t;\n}\n\nvector<string> split(const string &str, char delim) {\n\tvector<string> res;\n\tsize_t current = 0, found;\n\twhile ((found = str.find_first_of(delim, current)) != string::npos) {\n\t\tres.push_back(string(str, current, found - current));\n\t\tcurrent = found + 1;\n\t}\n\tres.push_back(string(str, current, str.size() - current));\n\treturn res;\n}\nint dfs(const unique_ptr<tree>&tp,int type,string a,string b,bool flag) {\n\t//a is parant of b\n\tif (type == 0) {\n\t\tif (a == tp->name) {\n\t\t\tfor (auto&& c : tp->childs) {\n\t\t\t\tif (c->name == b)return 1;\n\t\t\t}\n\t\t\treturn 0;\n\t\t}\n\t\telse {\n\t\t\tfor (auto &&c : tp->childs) {\n\t\t\t\tint num=dfs(c, type, a, b,flag);\n\t\t\t\tif (num != -1)return num;\n\t\t\t}\n\t\t\treturn -1;\n\t\t}\n\t}\n\telse if (type == 1) {\n\t\tif (flag) {\n\t\t\tif (tp->name == b)return 1;\n\t\t\tfor (auto &&c : tp->childs) {\n\t\t\t\tint num = dfs(c, type, a, b, flag);\n\t\t\t\tif (num != -1)return num;\n\t\t\t}\n\t\t\treturn -1;\n\t\t}\n\t\telse {\n\t\t\tif (tp->name == a)flag = true;\n\t\t\tfor (auto &&c : tp->childs) {\n\t\t\t\tint num = dfs(c, type, a, b, flag);\n\t\t\t\tif (num != -1)return num;\n\t\t\t}\n\t\t\tif (flag)return 0;\n\t\t\telse return -1;\n\t\t}\n\t}\n\telse {\n\t\tint same = 0;\n\t\tfor (auto&&c : tp->childs) {\n\t\t\tif (c->name == a)same++;\n\t\t\tif (c->name == b)same++;\n\t\t\tint num = dfs(c, type, a, b, flag);\n\t\t\tif (num != -1)return num;\n\t\t}\n\t\tif (same == 2)return 1;\n\t\telse if (same == 1)return 0;\n\t\telse return -1;\n\t}\n}\n\nint main() {\n\twhile (1) {\n\n\t\tint N, M; cin >> N >> M;\n\t\tif (!N)break;\n\t\tunique_ptr<tree> t;\n\t\t{\n\t\t\tvector<string>sts;\n\t\t\tvector<int>ns;\n\t\t\tstring st; getline(cin, st);\n\t\t\tfor (int i = 0; i < N; ++i) {\n\t\t\t\tgetline(cin, st);\n\t\t\t\tint n = st.find_first_not_of(' ');\n\t\t\t\tsts.push_back(st.substr(n));\n\t\t\t\tns.push_back(n);\n\t\t\t}\n\n\t\t\tint a = 0;\n\t\t\tt = maketree(sts, ns, 0, a);\n\t\t}\n\t\t\n\t\twhile (M--) {\n\t\t\tstring st;\n\t\t\tgetline(cin, st);\n\t\t\tvector<string>sts(split(st, ' '));\n\t\t\tstring a = sts[0];\n\t\t\tstring b = sts[5].substr(0, sts[5].size() - 1);\n\t\t\tint ans;\n\t\t\tif (sts[3] == \"child\") {\n\t\t\t\tans = dfs(t, 0, b, a, false);\n\t\t\t}\n\t\t\telse if (sts[3] == \"ancestor\") {\n\t\t\t\tans = dfs(t,1, a, b, false);\n\t\t\t}\n\t\t\telse if (sts[3] == \"sibling\") {\n\t\t\t\tans = dfs(t, 2, a, b, false);\n\t\t\t}\n\t\t\telse if (sts[3] == \"parent\") {\n\t\t\t\tans = dfs(t, 0, a, b, false);\n\t\t\t}\n\t\t\telse if (sts[3] == \"descendant\") {\n\t\t\t\tans = dfs(t, 1, b, a, false);\n\t\t\t}\n\t\t\tif (ans == 1)cout << \"True\" << endl;\n\t\t\telse if (ans == 0)cout << \"False\" << endl;\n\t\t\telse assert(false);\n\t\t}\n\t\tcout << endl;\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3168, "score_of_the_acc": -0.1467, "final_rank": 13 }, { "submission_id": "aoj_1217_1980409", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nmap <string, string> child_parent;\nstring lastname[2000];\n\nbool child(string a, string b){\n\tif (child_parent[a] == b) return true;\n\telse return false;\n}\n\nbool parent(string a, string b){\n\tif (a == child_parent[b]) return true;\n\telse return false;\n}\n\nbool sibling(string a, string b){\n\tif (child_parent[a] == child_parent[b]) return true;\n\telse return false;\n}\n\nbool ancestor(string a, string b){\n\tif (child_parent[b] == \"none\") return false;\n\telse if (parent(a, b)) return true;\n\telse return ancestor(a, child_parent[b]);\n}\n\nbool descendant(string a, string b){\n\treturn ancestor(b, a);\n}\n\nint main(void){\n\n\tint n, m;\n\n\twhile (cin >> n >> m, n, m){\n\n\t\tchild_parent.clear();\n\t\tcin.ignore();\n\n\t\tfor (int i = 0; i < n; i++){\n\t\t\tstring s;\n\t\t\tgetline(cin, s);\n\n\t\t\tint count = 0;\n\t\t\tfor (int j = 0; j < s.size(); j++){\n\t\t\t\tif (s[j] == ' ') count++;\n\t\t\t}\n\n\t\t\tif (count == 0) child_parent[s] = \"none\";\n\t\t\telse child_parent[s.substr(count)] = lastname[count - 1];\n\n\t\t\tlastname[count] = s.substr(count);\n\n\t\t}\n\n\t\tfor (int i = 0; i < m; i++){\n\t\t\tstring a, b,relate, buff;\n\t\t\tcin >> a >> buff >> buff >> relate >> buff;\n\t\t\tchar bb[200];\n\t\t\tscanf(\" %[^.].\", &bb);\n\t\t\tb = bb;\n\n\t\t\tbool flag = false;\n\t\t\tif (relate == \"child\") flag = child(a, b);\n\t\t\telse if (relate == \"parent\") flag = parent(a, b);\n\t\t\telse if (relate == \"sibling\") flag = sibling(a, b);\n\t\t\telse if (relate == \"descendant\") flag = descendant(a, b);\n\t\t\telse if (relate == \"ancestor\") flag = ancestor(a, b);\n\n\t\t\tif (flag) cout << \"True\" << endl;\n\t\t\telse cout << \"False\" << endl;\n\t\t}\n\n\t\t\n\n\t\tcout << endl;\n\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1396, "score_of_the_acc": -0.006, "final_rank": 8 }, { "submission_id": "aoj_1217_1963864", "code_snippet": "#include <vector>\n#include <list>\n#include <map>\n#include <set>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <algorithm>\n#include <functional>\n#include <numeric>\n#include <utility>\n#include <sstream>\n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <cmath>\n#include <cstdlib>\n#include <cctype>\n#include <string>\n#include <cstring>\nusing namespace std;\n#define REP(i,n) for(int i = 0; i < (int)n; i++)\n#define FOR(i,a,b) for(int i = a; i < (int)b; i++)\n#define pb push_back\n#define mp make_pair\ntypedef vector<int> vi;\ntypedef pair<int, int> pi;\ntypedef long long ll;\nconst int INF = 1<<28;\nconst ll MOD = 1000000007;\nconst int dx[] = {1, 0, -1, 0}, dy[] = {0, 1, 0, -1};\n\nbool des(string a, string b, map<string, string> &m) {\n\tstring s = a;\n\twhile(s != \"\") {\n\t\tif(s == b)\n\t\t\treturn true;;\n\t\ts = m[s];\n\t}\n\treturn false;\n}\n\nint main() {\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0);\n\tint n, m;\n\twhile(cin >> n >> m, n|m) {\n\t\tcin.ignore();\n\t\tvector<string> v(1000);\n\t\tmap<string, string> ma;\n\t\tREP(i, n) {\n\t\t\tstring s;\n\t\t\tgetline(cin, s);\n\t\t\tint cnt = 0;\n\t\t\twhile(s[cnt] == ' ')\n\t\t\t\tcnt++;\n\t\t\ts = s.substr(cnt);\n\t\t\tma[s] = cnt ? v[cnt-1] : \"\";\n\t\t\tv[cnt] = s;\n\t\t}\n\t\tREP(i, m) {\n\t\t\tstring in1, in2, in3;\n\t\t\tcin >> in1;\n\t\t\tcin >> in2 >> in2 >> in2;\n\t\t\tcin >> in3 >> in3;\n\t\t\tin3.erase(in3.end() - 1);\n\t\t\tbool ans = false;\n\t\t\tif(in2 == \"child\" && ma[in1] == in3)\n\t\t\t\tans = true;\n\t\t\telse if(in2 == \"parent\" && ma[in3] == in1)\n\t\t\t\tans = true;\n\t\t\telse if(in2 == \"sibling\" && ma[in1] == ma[in3])\n\t\t\t\tans = true;\n\t\t\telse if(in2 == \"descendant\")\n\t\t\t\tans = des(in1, in3, ma);\n\t\t\telse if(in2 == \"ancestor\")\n\t\t\t\tans = des(in3, in1, ma);\n\t\t\tcout << (ans ? \"True\" : \"False\") << endl;\n\t\t}\n\t\tcout << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1348, "score_of_the_acc": -0.0022, "final_rank": 4 }, { "submission_id": "aoj_1217_1963852", "code_snippet": "#include <vector>\n#include <list>\n#include <map>\n#include <set>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <algorithm>\n#include <functional>\n#include <numeric>\n#include <utility>\n#include <sstream>\n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <cmath>\n#include <cstdlib>\n#include <cctype>\n#include <string>\n#include <cstring>\nusing namespace std;\n#define REP(i,n) for(int i = 0; i < (int)n; i++)\n#define FOR(i,a,b) for(int i = a; i < (int)b; i++)\n#define pb push_back\n#define mp make_pair\ntypedef vector<int> vi;\ntypedef pair<int, int> pi;\ntypedef long long ll;\nconst int INF = 1<<28;\nconst ll MOD = 1000000007;\nconst int dx[] = {1, 0, -1, 0}, dy[] = {0, 1, 0, -1};\n\nint main() {\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0);\n\tint n, m;\n\twhile(cin >> n >> m, n|m) {\n\t\tcin.ignore();\n\t\tvector<string> v(1000);\n\t\tmap<string, string> ma;\n\t\tREP(i, n) {\n\t\t\tstring s;\n\t\t\tgetline(cin, s);\n\t\t\tint cnt = 0;\n\t\t\twhile(s[cnt] == ' ')\n\t\t\t\tcnt++;\n\t\t\ts = s.substr(cnt);\n\t\t\tif(!cnt)\n\t\t\t\tma[s] = \"\";\n\t\t\telse\n\t\t\t\tma[s] = v[cnt-1];\n\t\t\tv[cnt] = s;\n\t\t}\n\t\tREP(i, m) {\n\t\t\tstring in1, in2, in3;\n\t\t\tcin >> in1;\n\t\t\tcin >> in2 >> in2 >> in2;\n\t\t\tcin >> in3 >> in3;\n\t\t\tin3.erase(in3.end() - 1);\n\t\t\tbool ans = false;\n\t\t\tif(in2 == \"child\" && ma[in1] == in3)\n\t\t\t\tans = true;\n\t\t\telse if(in2 == \"parent\" && ma[in3] == in1)\n\t\t\t\tans = true;\n\t\t\telse if(in2 == \"sibling\" && ma[in1] == ma[in3])\n\t\t\t\tans = true;\n\t\t\telse if(in2 == \"descendant\") {\n\t\t\t\tstring s = ma[in1];\n\t\t\t\twhile(s != \"\") {\n\t\t\t\t\tif(s == in3)\n\t\t\t\t\t\tans = true;\n\t\t\t\t\ts = ma[s];\n\t\t\t\t}\n\t\t\t}\n\t\t\telse if(in2 == \"ancestor\") {\n\t\t\t\tstring s = ma[in3];\n\t\t\t\twhile(s != \"\") {\n\t\t\t\t\tif(s == in1)\n\t\t\t\t\t\tans = true;\n\t\t\t\t\ts = ma[s];\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(ans)\n\t\t\t\tcout << \"True\" << endl;\n\t\t\telse\n\t\t\t\tcout << \"False\" << endl;\n\t\t}\n\t\tcout << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1344, "score_of_the_acc": -0.0019, "final_rank": 3 }, { "submission_id": "aoj_1217_1418111", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <string>\n#include <vector>\n#include <unordered_map>\n#include <functional>\nusing namespace std;\ntypedef unordered_map<string,string> mss;\n\nunordered_map<string,function<bool(const string&,const string&,mss&)>>T={\n\t{\"child\",[](const string &x,const string &y,mss &parent){return parent[x]==y;}},\n\t{\"parent\",[](const string &x,const string &y,mss &parent){return parent[y]==x;}},\n\t{\"sibling\",[](const string &x,const string &y,mss &parent){return parent[x]==parent[y];}},\n\t{\"descendant\",[](const string &x,const string &y,mss &parent){\n\t\tstring z=parent[x];\n\t\tfor(;;){\n\t\t\tif(z==y)return true;\n\t\t\tif(parent[z]==\"\")return false;\n\t\t\tz=parent[z];\n\t\t}\n\t}},\n\t{\"ancestor\",[](const string &x,const string &y,mss &parent){\n\t\tstring z=parent[y];\n\t\tfor(;;){\n\t\t\tif(z==x)return true;\n\t\t\tif(parent[z]==\"\")return false;\n\t\t\tz=parent[z];\n\t\t}\n\t}},\n\n};\nint main(){\n\tint N,Q;\n\tstring line;\n\tfor(;cin>>N>>Q,N;){\n\t\tgetline(cin,line);\n\t\tmss parent;\n\t\tvector<string>stack;\n\t\tgetline(cin,line);\n\t\tparent[line]=\"\";\n\t\tstack.push_back(line);\n\t\tfor(int i=1;i<N;i++){\n\t\t\tgetline(cin,line);\n\t\t\tint idx=0;\n\t\t\tfor(;line[idx]==' ';idx++);\n\t\t\tstring name=line.substr(idx);\n\t\t\tif(idx>stack.size())return 1;\n\t\t\tfor(;idx<stack.size();stack.pop_back());\n\t\t\tparent[name]=stack[stack.size()-1];\n\t\t\tstack.push_back(name);\n\t\t}\n\t\tfor(int i=0;i<Q;i++){\n\t\t\tgetline(cin,line);\n\t\t\tistringstream ss(line);\n\t\t\tstring x,z,y;\n\t\t\tss>>x>>y>>y>>z>>y>>y;\n\t\t\ty=y.substr(0,y.size()-1);\n\t\t\tcout<<(T[z](x,y,parent)?\"True\":\"False\")<<endl;\n\t\t}\n\t\tcout<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1340, "score_of_the_acc": -0.0016, "final_rank": 2 }, { "submission_id": "aoj_1217_1334247", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define MAX_N 1010\n\nstruct P{\n int p,l;\n};\n\nP p[MAX_N];\nstring s[MAX_N];\nbool used[MAX_N];\nint N;\n\nvoid init(int N){\n for(int i = 0 ; i < N ; i++){\n p[i].p = i;\n }\n}\n\nbool find(int x,int target){\n if(p[x].p == target){\n return true;\n }\n if(p[x].p == x){ return false; }\n return find(p[x].p,target);\n}\n\nvoid make(int n,int parent,int root,int depth){\n set<int> children;\n if(used[n]){ return; }\n used[n] = true;\n p[n].p = parent; p[n].l = depth;\n for(int i = n+1 ; i < N ; i++){\n int len = s[i].size();\n if(depth+1 >= len){ continue; }\n if(s[i][depth] != '.'){ break; }\n if(s[i][depth] == '.' && s[i][depth+1] != '.'){\n children.insert(i);\n make(i,n,root,depth+1);\n }\n }\n}\n\nint main(){\n int M;\n while(cin >> N >> M, N){\n map<string,int> mp;\n int cur = 0;\n init(N); cin.ignore();\n for(int i = 0 ; i < N ; i++){\n getline(cin,s[i]);\n for(int j = 0 ; j < (int)s[i].size() ; j++){\n if(s[i][j] != ' '){\n mp[s[i].substr(j)] = cur++;\n break;\n }\n s[i][j] = '.';\n }\n used[i] = false;\n }\n for(int i = 0 ; i < N ; i++){\n if(used[i]){ continue; }\n if(s[i][0] != '.'){\n make(i,i,i,0);\n }\n }\n string ord,a,b,c;\n for(int i = 0 ; i < M ; i++){\n getline(cin,ord);\n stringstream ss(ord);\n ss >> a;\n ss >> ord; ss >> ord;\n ss >> c;\n ss >> ord;\n ss >> b;\n b.resize(b.size()-1);\n bool ans = false;\n if(c == \"parent\"){\n if(p[mp[b]].p == mp[a]){\n ans = true;\n }\n }else if(c == \"child\"){\n if(p[mp[a]].p == mp[b]){\n ans = true;\n }\n }else if(c == \"ancestor\"){\n if(p[mp[a]].l < p[mp[b]].l && find(mp[b],mp[a])){\n ans = true;\n }\n }else if(c == \"descendant\"){\n if(p[mp[a]].l > p[mp[b]].l && find(mp[a],mp[b])){\n ans = true;\n }\n }else{\n if(p[mp[a]].l == p[mp[b]].l && p[mp[a]].p == p[mp[b]].p){\n ans = true;\n }\n }\n cout << (ans ? \"True\" : \"False\") << endl;\n }\n cout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1440, "score_of_the_acc": -0.0095, "final_rank": 11 }, { "submission_id": "aoj_1217_1162680", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nstruct node{\n string name;\n int parent;\n vector<int> child;\n\n node(string s=\"\"):name(s){ parent = -1; child.clear(); }\n\n void set_par(int a){ parent = a; }\n void add_child(int a){ child.push_back(a); }\n};\n\nvector<node> tree;\nmap<string,int> id;\n\ninline bool is_par(string my, string your){\n int par = tree[id[my]].parent;\n if(par<0)return false;\n return tree[par].name == your;\n}\n\ninline bool is_child(string my, string your){\n for(int c : tree[ id[my] ].child){\n if(tree[c].name == your)return true;\n }\n return false;\n}\n\ninline bool is_sib(string my, string your){\n int par = tree[id[my]].parent;\n if(par<0)return false;\n return is_child(tree[par].name, your);\n}\n\ninline bool is_anc(string my, string your){\n if(my == your)return true;\n int par = tree[id[my]].parent;\n if(par<0)return false;\n return is_anc(tree[par].name, your);\n}\n\ninline bool is_des(string my, string your){\n if(my == your)return true;\n for(int c : tree[ id[my] ].child){\n if(is_des(tree[c].name,your))return true;\n }\n return false; \n}\n\nint main(){\n int n,m;\n while(cin >> n >> m, n){\n stack< pair<int,int> > s;\n id.clear();\n tree.resize(n);\n\n cin.ignore();\n for(int i=0;i<n;i++){\n string name;\n getline(cin,name);\n //cout << name << endl;\n int indent = 0;\n while(name[indent]==' ')indent++;\n name = name.substr(indent);\n tree[i] = node(name);\n id[name] = i;\n\n while(s.size() && s.top().second+1 != indent)s.pop();\n if(s.size()){\n\ttree[i].set_par( s.top().first );\n\ttree[s.top().first].add_child(i);\n }\n s.push( make_pair(i,indent) );\n }\n\n /*\n for(int i=0;i<n;i++){\n cout << tree[i].name << endl;\n cout << tree[i].parent << endl;\n for(int c : tree[i].child)cout << c << \" \"; cout << endl;\n }\n */\n\n for(int i=0;i<m;i++){\n string my,your,query,dummy;\n cin >> your >> dummy >> dummy >> query >> dummy >> my;\n my = my.substr(0,my.size()-1);\n\n //cout << my << \" \" << your << \" \" << query << endl;\n\n bool f = false;\n if(query == \"child\")f = is_child(my,your);\n else if(query == \"parent\")f = is_par(my,your);\n else if(query == \"sibling\")f = is_sib(my,your);\n else if(query == \"ancestor\")f = is_anc(my,your);\n else f = is_des(my,your);\n\n if(f)cout << \"True\" << endl;\n else cout << \"False\" << endl;\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1420, "score_of_the_acc": -0.0079, "final_rank": 9 }, { "submission_id": "aoj_1217_992599", "code_snippet": "#include <algorithm>\n#include <sstream>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cassert>\n#include <functional>\n#include <iostream>\n#include <iomanip>\n#include <iterator>\n#include <map>\n#include <queue>\n#include <utility>\n#include <vector>\n\nusing namespace std;\n\ntypedef long long Long;\n#define whole(xs) xs.begin(), xs.end()\n\nstruct Q {\n string Relation, Name1, Name2;\n Q(const string& Relation, const string& Name1, const string& Name2) \n : Relation(Relation), Name1(Name1), Name2(Name2) {}\n};\nostream& operator<<(ostream& os, const Q& q) {\n os << \"(\" << q.Relation << \", \" << q.Name1 << \", \" << q.Name2 << \")\";\n return os;\n}\n\nint N, M;\nvector<int> Parent;\nvector<Q> Queries;\nmap<string, int> Id;\nvector<int> Prev;\n\nint CountPrefixSpaces(const string& s) {\n int i;\n for (i = 0; i < s.size() && s[i] == ' '; i++) ;\n return i;\n}\n\nbool input() {\n string l;\n getline(cin, l);\n istringstream is; is.str(l);\n is >> N >> M;\n is.clear();\n if (N == 0 && M == 0) return false;\n Parent.resize(N, -1);\n Queries.clear();\n Id.clear();\n Prev.resize(N, -1);\n for (int i = 0; i < N; i++) {\n getline(cin, l);\n is.str(l);\n string Name;\n is >> Name;\n is.clear();\n Id[Name] = i;\n int C = CountPrefixSpaces(l);\n Prev[C] = i;\n if (C != 0) {\n Parent[i] = Prev[C - 1];\n }\n }\n for (int i = 0; i < M; i++) {\n getline(cin, l);\n is.str(l);\n string Name1, Relation, Name2;\n string _;\n is >> Name1;\n for (int k = 0; k < 2; k++) is >> _;\n is >> Relation;\n is >> _;\n is >> Name2;\n Name2 = Name2.substr(0, Name2.size() - 1);\n is.clear();\n Queries.push_back(Q(Relation, Name1, Name2));\n }\n return true;\n}\n\nvoid solve() {\n for (int i = 0; i < M; i++) {\n string& Relation = Queries[i].Relation,\n Name1 = Queries[i].Name1,\n Name2 = Queries[i].Name2;\n int x = Id[Name1], y = Id[Name2];\n if (Relation == \"child\") {\n cout << (y == Parent[x] ? \"True\" : \"False\") << endl;\n } else if (Relation == \"parent\") {\n cout << (x == Parent[y] ? \"True\" : \"False\") << endl;\n } else if (Relation == \"sibling\") {\n cout << (Parent[x] == Parent[y] ? \"True\" : \"False\") << endl;\n } else if (Relation == \"descendant\") {\n while (x >= 0) {\n if (y == x) {\n cout << \"True\" << endl;\n goto fin1;\n }\n x = Parent[x];\n }\n cout << \"False\" << endl;\n fin1:;\n } else if (Relation == \"ancestor\") {\n while (y >= 0) {\n if (y == x) {\n cout << \"True\" << endl;\n goto fin2;\n }\n y = Parent[y];\n }\n cout << \"False\" << endl;\n fin2:;\n } else {\n assert(0);\n }\n }\n cout << endl;\n}\n\nint main() {\n while (input()) solve();\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1528, "score_of_the_acc": -0.0165, "final_rank": 12 }, { "submission_id": "aoj_1217_902209", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <sstream>\n#include <cstring>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n#include <numeric>\n#include <cctype>\n#include <tuple>\n\n#ifdef _MSC_VER\n#include <agents.h>\n#endif\n\n#define FOR(i, a, b) for(int i = (a); i < (int)(b); ++i)\n#define rep(i, n) FOR(i, 0, n)\n#define ALL(v) v.begin(), v.end()\n#define REV(v) v.rbegin(), v.rend()\n#define MEMSET(v, s) memset(v, s, sizeof(v))\n#define X first\n#define Y second\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> P;\n\nint par[1010];\nint last[100];\nmap<string, int> name;\n\nbool check_ancestor(int a, int d){\n\tif (a < 0 || d < 0) return false;\n\tif (a == par[d]) return true;\n\treturn check_ancestor(a, par[d]);\n}\n\nint main(){\n\tint n, q;\n\twhile (cin >> n >> q, n|q){\n\t\tname.clear();\n\t\tMEMSET(last, -1);\n\t\tMEMSET(par, -1);\n\t\tcin.ignore();\n\t\trep(i, n){\n\t\t\tstring s;\n\t\t\tgetline(cin, s);\n\t\t\tint cnt = count(ALL(s), ' ');\n\t\t\tlast[cnt] = i;\n\t\t\tname[s.substr(cnt)] = i;\n\t\t\tif (!cnt) continue;\n\t\t\tpar[i] = last[cnt - 1];\n\t\t}\n\t\twhile (q--){\n\t\t\tstring a, b, c, d, e, f;\n\t\t\tcin >> a >> b >> c >> d >> e >> f;\n\t\t\t//cout << f.substr(0, f.size() - 1) << endl;\n\t\t\tint x = name[a], y = name[f.substr(0, f.size() - 1)];\n\t\t\tbool ok;\n\t\t\tswitch (d[0]){\n\t\t\tcase 'c':\n\t\t\t\tok = par[x] == y;\n\t\t\t\tbreak;\n\t\t\tcase 'a':\n\t\t\t\tok = check_ancestor(x, y);\n\t\t\t\tbreak;\n\t\t\tcase 's':\n\t\t\t\tok = par[x] == par[y];\n\t\t\t\tbreak;\n\t\t\tcase 'p':\n\t\t\t\tok = x == par[y];\n\t\t\t\tbreak;\n\t\t\tcase 'd':\n\t\t\t\tok = check_ancestor(y, x);\n\t\t\t}\n\t\t\tcout << (ok ? \"True\" : \"False\") << endl;\n\t\t}\n\t\tcout << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1320, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1217_786340", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cstring>\n\nusing namespace std;\n\ntypedef pair<int,string> P;\n\n// family tree\nstruct Node{\n vector<Node*> child;\n Node* parent;\n string name;\n Node():name(\"\"){}\n Node(vector<Node*> c, Node* p, string s):child(c),parent(p),name(s){}\n\n void init(){\n for(int i = 0; i < (int)child.size(); i++)\n child[i]->init();\n child.clear();\n }\n\n bool isSibling(const string& A, const string& B){\n return find(A)->parent==find(B)->parent;\n }\n\n bool isChild(const string& A){\n for(int i = 0; i < (int)child.size(); i++)\n if(child[i]->name == A) return true;\n return false;\n }\n\n bool isDecendant(const string& A){\n for(int i = 0; i < (int)child.size(); i++)\n if(child[i]->name == A) return true;\n \n bool res = false;\n for(int i = 0; i < (int)child.size(); i++)\n res = res||child[i]->isDecendant(A);\n return res;\n }\n\n Node* find(const string& name){\n for(int i = 0; i < (int)child.size(); i++)\n if(child[i]->name == name) return child[i];\n\n for(int i = 0; i < (int)child.size(); i++){\n Node* tmp = child[i]->find(name);\n if(tmp != NULL) return tmp;\n }\n return NULL;\n }\n};\n\nint N,M;\nNode* top = new Node(vector<Node*>(), top, \"\");\n\nP devide(const string& s){\n int blank = 0;\n for(int i = 0; i < (int)s.length(); i++) if(s[i] == ' ') blank++;\n return P(blank,s.substr(blank));\n}\n\nvoid input(){\n cin.ignore();\n \n Node* now = top;\n int depth = -1;\n\n for(int i = 0; i < N; i++){\n string s;\n getline(cin,s);\n P p = devide(s);\n \n if(p.first == depth){\n Node* nex = new Node(vector<Node*>(), now->parent, p.second);\n ((now->parent)->child).push_back(nex);\n now = nex;\n }\n\n if(p.first < depth){\n // go up\n int diff = depth-p.first+1;\n for(int i = 0; i < diff; i++) now = now->parent;\n Node* nex = new Node(vector<Node*>(), now, p.second);\n now->child.push_back(nex);\n now = nex;\n depth = p.first;\n }\n \n if(p.first > depth){\n // go down\n Node* nex = new Node(vector<Node*>(), now, p.second);\n now->child.push_back(nex);\n now = nex;\n depth = p.first;\n }\n }\n}\n\nvoid solve(){\n\n for(int i = 0; i < M; i++){\n string X,Y,Q,trash;\n cin >> X >> trash >> trash >> Q >> trash >> Y;\n bool ans = false;\n Y = Y.substr(0,Y.length()-1);\n\n if(Q[0]=='c') ans = (top->find(Y))->isChild(X);\n if(Q[0]=='p') ans = (top->find(X))->isChild(Y);\n if(Q[0]=='s') ans = top->isSibling(X,Y);\n if(Q[0]=='d') ans = (top->find(Y))->isDecendant(X);\n if(Q[0]=='a') ans = (top->find(X))->isDecendant(Y);\n \n cout << (ans?\"True\":\"False\") << endl;\n }\n cout << endl;\n}\n\nint main(){\n \n while(cin >> N >> M && N+M){\n top->init();\n input();\n solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1360, "score_of_the_acc": -0.0032, "final_rank": 5 }, { "submission_id": "aoj_1217_781895", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <map>\n\nusing namespace std;\n\ntypedef pair<int, string> P;\n\nmap<string, P> fam;\n\nvector<string> s;\nvector<string> name;\nint N, Q;\n\nvoid output(){\n string op;\n for(int i = 0 ; i < Q ; i++){\n string relation, X, Y;\n for(int j = 0 ; j < 6 ; j++){\n cin >> op;\n if(j == 0) X = op;\n if(j == 3) relation = op;\n if(j == 5) Y = op;\n }\n Y.erase(Y.end()-1);\n \n if(relation == \"parent\"){\n relation = \"child\";\n swap(X, Y);\n }\n if(relation == \"descendant\"){\n relation = \"ancestor\";\n swap(X, Y);\n }\n \n bool ans = false;\n \n if(relation == \"child\"){\n ans = fam[X].second == Y;\n }\n else if(relation == \"ancestor\"){\n while(fam[Y].first != 0){\n\tif(fam[Y].second == X){\n\t ans = true;\n\t break;\n\t}\n\tY = fam[Y].second;\n }\n }\n else if(relation == \"sibling\"){\n int gen = fam[Y].first;\n string par = fam[Y].second;\n for(map<string, P>::iterator it = fam.begin() ; it != fam.end() ; it++){\n\tif(it->first == X){\n\t if(it->second.first == gen && it->second.second == par){\n\t ans = true;\n\t break;\n\t }\n\t}\n }\n }\n if(ans) cout << \"True\" << endl;\n else cout << \"False\" << endl;\n }\n}\n\nint main(){\n while(cin >> N >> Q, N|Q){\n fam.clear();\n s.clear();\n name.clear();\n cin.ignore();\n string tmp;\n for(int i = 0 ; i < N ; i++){\n getline(cin, tmp);\n s.push_back(tmp);\n }\n \n name = s;\n \n for(int i = 0 ; i < N ; i++){\n while(name[i][0] == ' ') name[i].erase(name[i].begin());\n }\n \n for(int i = 0 ; i < N ; i++){\n int gen = 0;\n for(int j = 0 ; j < (int)s[i].size() ; j++){\n\tif(s[i][j] != ' ') break;\n\tgen++;\n }\n for(int j = i ; j >= 0 ; j--){\n\tif(s[j][gen-1] != ' '){\n\t fam[ name[i] ] = P(gen, name[j]);\n\t break;\n\t}\n }\n }\n \n output();\n cout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1536, "score_of_the_acc": -0.1838, "final_rank": 15 }, { "submission_id": "aoj_1217_781894", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <map>\n\nusing namespace std;\n\ntypedef pair<int, string> P;\n\nmap<string, P> fam;\n\nvector<string> s;\nvector<string> name;\nint N, Q;\n\nvoid output(){\n string op;\n for(int i = 0 ; i < Q ; i++){\n string relation, X, Y;\n for(int j = 0 ; j < 6 ; j++){\n cin >> op;\n if(j == 0) X = op;\n if(j == 3) relation = op;\n if(j == 5) Y = op;\n }\n Y.erase(Y.end()-1);\n \n if(relation == \"parent\"){\n relation = \"child\";\n swap(X, Y);\n }\n if(relation == \"descendant\"){\n relation = \"ancestor\";\n swap(X, Y);\n }\n \n bool ans = false;\n \n if(relation == \"child\"){\n ans = fam[X].second == Y;\n }\n else if(relation == \"ancestor\"){\n while(fam[Y].first != 0){\n\tif(fam[Y].second == X){\n\t ans = true;\n\t break;\n\t}\n\tY = fam[Y].second;\n }\n }\n else if(relation == \"sibling\"){\n int gen = fam[Y].first;\n string par = fam[Y].second;\n for(map<string, P>::iterator it = fam.begin() ; it != fam.end() ; it++){\n\tif(it->first == X){\n\t if(it->second.first == gen && it->second.second == par){\n\t ans = true;\n\t break;\n\t }\n\t}\n }\n }\n if(ans) cout << \"True\" << endl;\n else cout << \"False\" << endl;\n }\n}\n\nint main(){\n while(cin >> N >> Q, N|Q){\n fam.clear();\n s.clear();\n name.clear();\n cin.ignore();\n string tmp;\n for(int i = 0 ; i < N ; i++){\n getline(cin, tmp);\n s.push_back(tmp);\n }\n \n name = s;\n \n for(int i = 0 ; i < N ; i++){\n while(name[i][0] == ' ') name[i].erase(name[i].begin());\n /*\n for(int j = 0 ; j < (int)name[i].size() ; j++){\n\tif(name[i][j] == ' ') name[i].erase(name[i].begin()+j);\n }\n */\n }\n \n for(int i = 0 ; i < N ; i++){\n int gen = 0;\n for(int j = 0 ; j < (int)s[i].size() ; j++){\n\tif(s[i][j] != ' ') break;\n\tgen++;\n }\n for(int j = i ; j >= 0 ; j--){\n\tif(s[j][gen-1] != ' '){\n\t fam[ name[i] ] = P(gen, name[j]);\n\t break;\n\t}\n }\n }\n \n output();\n cout << endl;\n /*\n for(map<string, P>::iterator it = fam.begin() ; it != fam.end() ; it++){\n cout << it->first << ' ' << it->second.first << ' ' << it->second.second << endl;\n }\n */\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1536, "score_of_the_acc": -0.1838, "final_rank": 15 }, { "submission_id": "aoj_1217_585866", "code_snippet": "#include<map>\n#include<sstream>\n#include<cstdlib>\n#include<vector>\n#include<algorithm>\n#include<iostream>\n#include<cassert>\n#define F first\n#define S second\n#define pb push_back\n#define all(n) n.begin(),n.end()\nusing namespace std;\ntypedef pair<string,int> SI;\n \nint oldest,youngest;\n \nvoid split(vector<SI>& vec,string line)\n{\n int space_cnt = 0;\n for(int i=0;line[i] == ' ';i++,space_cnt++){}\n \n vec.push_back(SI(line.substr(space_cnt,line.size()-space_cnt),space_cnt));\n oldest = min(oldest,space_cnt);\n youngest = max(youngest,space_cnt);\n}\n \nvoid ParseAndSolve(vector<SI>& vec,map<string,int>& index_tree,string line)\n{\n vector<string> info;\n stringstream ss(line);\n string mid;\n vector<string> ope; \n \n \n for(int i=0;i<ss.str().size();i++)\n {\n if((ss >> mid).fail())\n goto skip;\n \n ope.push_back(mid);\n \n }\n \n skip:\n \n info.push_back(ope[0]);\n for(int i=1;i<ope.size()-1;i++)\n {\n if(ope[i] == \"child\" || ope[i] == \"parent\" || ope[i] == \"sibling\" || ope[i] == \"descendant\" || ope[i] == \"ancestor\")\n {\n info.push_back(ope[i]);\n break;\n }\n }\n info.push_back(ope[ope.size()-1].substr(0,ope[ope.size()-1].size()));\n \n \n assert(info.size() == 3);\n \n string X,Y;\n X = info[0],Y = info[2];\n \n if(info[1][0] == 'c')\n {\n int Yindex = index_tree[Y]; \n int Xindex = index_tree[X];\n \n if(vec[Xindex].S <= vec[Yindex].S || Yindex+1 >= vec.size() || vec[Yindex+1].S != vec[Xindex].S)\n {\n cout << \"False\" << endl;\n return;\n }\n \n \n int parent_level = vec[Yindex].S;\n \n for(int i=Yindex+1;parent_level < vec[i].S && i < vec.size();i++)\n {\n \n if(vec[i].F == X)\n {\n cout << \"True\" << endl;\n return;\n }\n }\n \n cout << \"False\" << endl;\n return;\n }\n else if(info[1][0] == 'p')\n {\n \n int Xindex = index_tree[X];\n int Yindex = index_tree[Y];\n \n if(vec[Xindex].S >= vec[Yindex].S || Xindex+1 >= vec.size() || vec[Xindex+1].S != vec[Yindex].S )\n {\n cout << \"False\" << endl;\n return;\n }\n \n \n int parent_level = vec[Xindex].S;\n \n for(int i=Xindex+1;parent_level < vec[i].S && i < vec.size();i++ )\n {\n if(vec[i].F == Y)\n {\n cout << \"True\" << endl;\n return;\n }\n }\n \n cout << \"False\" << endl;\n return;\n \n \n }\n else if(info[1][0] == 's')\n {\n int Xindex = index_tree[X];\n int Yindex = index_tree[Y];\n \n if(vec[Xindex].S != vec[Yindex].S || min(Xindex,Yindex)+1 >= vec.size())\n {\n cout << \"False\" << endl;\n return;\n }\n \n int sibling_level = vec[Xindex].S;\n \n int Maxindex,Minindex;\n string Maxname,Minname;\n \n if(Xindex > Yindex)\n {\n Maxindex = Xindex,Minindex = Yindex;\n Maxname = X,Minname = Y;\n }\n else\n {\n Maxindex = Yindex,Minindex = Xindex;\n Maxname = Y,Minname = X;\n }\n \n for(int i=Minindex+1;i<vec.size() && sibling_level <= vec[i].S;i++)\n {\n if(Maxname == vec[i].F)\n {\n cout << \"True\" << endl;\n return;\n }\n }\n cout << \"False\" << endl;\n return;\n \n }\n else if(info[1][0] == 'd')\n {\n int Xindex = index_tree[X];\n int Yindex = index_tree[Y];\n \n if(Yindex+1 >= vec.size() || vec[Xindex].S <= vec[Yindex].S)\n {\n cout << \"False\" << endl;\n return;\n }\n \n for(int i=Yindex+1;i<vec.size() && vec[i].S > vec[Yindex].S;i++)\n {\n if(vec[i].F == vec[Xindex].F)\n {\n cout << \"True\" << endl;\n return;\n }\n }\n \n cout << \"False\" << endl;\n return;\n }\n else if(info[1][0] == 'a')\n {\n int Xindex = index_tree[X];\n int Yindex = index_tree[Y];\n if(Xindex+1 >= vec.size() || vec[Xindex].S >= vec[Yindex].S)\n {\n cout << \"False\" << endl;\n return;\n }\n \n for(int i=Xindex+1;i < vec.size() && vec[i].S > vec[Xindex].S;i++)\n {\n if(vec[i].F == vec[Yindex].F)\n {\n cout << \"True\" << endl;\n return;\n }\n }\n \n cout << \"False\" << endl;\n return;\n }\n else\n assert(false);\n \n \n}\n \nint main()\n{\n int n,m;\n while(true)\n {\n cin >> n >> m;\n \n if(!(n+m))\n break;\n oldest = (1<<28);\n youngest = -1;\n cin.ignore();\n string line;\n vector<SI> vec;\n for(int i=0;i<n;i++)\n {\n getline(cin,line);\n \n split(vec,line);\n }\n \n map<string,int> index_tree;\n for(int i=0;i<n;i++)\n index_tree[vec[i].F] = i;\n \n for(int i=0;i<m;i++)\n {\n getline(cin,line);\n \n ParseAndSolve(vec,index_tree,line.substr(0,line.size()-1));\n \n }\n \n cout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1360, "score_of_the_acc": -0.0032, "final_rank": 5 }, { "submission_id": "aoj_1217_585862", "code_snippet": "#include<map>\n#include<sstream>\n#include<cstdlib>\n#include<vector>\n#include<algorithm>\n#include<iostream>\n#include<cassert>\n#define F first\n#define S second\n#define pb push_back\n#define all(n) n.begin(),n.end()\nusing namespace std;\ntypedef pair<string,int> SI;\n\nint oldest,youngest;\n\nvoid split(vector<SI>& vec,string line)\n{\n int space_cnt = 0;\n for(int i=0;line[i] == ' ';i++,space_cnt++){}\n\n vec.push_back(SI(line.substr(space_cnt,line.size()-space_cnt),space_cnt));\n oldest = min(oldest,space_cnt);\n youngest = max(youngest,space_cnt);\n}\n\nvoid ParseAndSolve(vector<SI>& vec,map<string,int>& index_tree,string line)\n{\n vector<string> info;\n stringstream ss(line);\n string mid;\n vector<string> ope; \n \n\n for(int i=0;i<ss.str().size();i++)\n {\n if((ss >> mid).fail())\n\tgoto skip;\n \n ope.push_back(mid);\n \n }\n\n skip:\n\n info.push_back(ope[0]);\n for(int i=1;i<ope.size()-1;i++)\n {\n if(ope[i] == \"child\" || ope[i] == \"parent\" || ope[i] == \"sibling\" || ope[i] == \"descendant\" || ope[i] == \"ancestor\")\n\t{\n\t info.push_back(ope[i]);\n\t break;\n\t}\n }\n info.push_back(ope[ope.size()-1].substr(0,ope[ope.size()-1].size()));\n\n\n assert(info.size() == 3);\n\n string X,Y;\n X = info[0],Y = info[2];\n\n if(info[1][0] == 'c')\n {\n int Yindex = index_tree[Y]; \n int Xindex = index_tree[X];\n\n if(vec[Xindex].S <= vec[Yindex].S || Yindex+1 >= vec.size() || vec[Yindex+1].S != vec[Xindex].S)\n\t{\n\t cout << \"False\" << endl;\n\t return;\n\t}\n\n \n int parent_level = vec[Yindex].S;\n\n for(int i=Yindex+1;parent_level < vec[i].S && i < vec.size();i++)\n\t{\n\n\t if(vec[i].F == X)\n\t {\n\t cout << \"True\" << endl;\n\t return;\n\t }\n\t}\n\n cout << \"False\" << endl;\n return;\n }\n else if(info[1][0] == 'p')\n {\n\n int Xindex = index_tree[X];\n int Yindex = index_tree[Y];\n\n if(vec[Xindex].S >= vec[Yindex].S || Xindex+1 >= vec.size() || vec[Xindex+1].S != vec[Yindex].S )\n\t{\n\t cout << \"False\" << endl;\n\t return;\n\t}\n\n\n int parent_level = vec[Xindex].S;\n\n for(int i=Xindex+1;parent_level < vec[i].S && i < vec.size();i++ )\n\t{\n\t if(vec[i].F == Y)\n\t {\n\t cout << \"True\" << endl;\n\t return;\n\t }\n\t}\n\n cout << \"False\" << endl;\n return;\n\n\n }\n else if(info[1][0] == 's')\n {\n int Xindex = index_tree[X];\n int Yindex = index_tree[Y];\n\n if(vec[Xindex].S != vec[Yindex].S || min(Xindex,Yindex)+1 >= vec.size())\n\t{\n\t cout << \"False\" << endl;\n\t return;\n\t}\n\n int sibling_level = vec[Xindex].S;\n\n int Maxindex,Minindex;\n string Maxname,Minname;\n\n if(Xindex > Yindex)\n\t{\n\t Maxindex = Xindex,Minindex = Yindex;\n\t Maxname = X,Minname = Y;\n\t}\n else \n\t{\n\t Maxindex = Yindex,Minindex = Xindex;\n\t Maxname = Y,Minname = X;\n\t}\n\n for(int i=Minindex+1;i<vec.size() && sibling_level <= vec[i].S;i++)\n\t{\n\t if(Maxname == vec[i].F)\n\t {\n\t cout << \"True\" << endl;\n\t return;\n\t }\n\t}\n cout << \"False\" << endl;\n return;\n\n }\n else if(info[1][0] == 'd')\n {\n int Xindex = index_tree[X];\n int Yindex = index_tree[Y];\n\n if(Yindex+1 >= vec.size() || vec[Xindex].S <= vec[Yindex].S)\n\t{\n\t cout << \"False\" << endl;\n\t return;\n\t}\n\n for(int i=Yindex+1;i<vec.size() && vec[i].S > vec[Yindex].S;i++)\n\t{\n\t if(vec[i].F == vec[Xindex].F)\n\t {\n\t cout << \"True\" << endl;\n\t return;\n\t }\n\t}\n\n cout << \"False\" << endl;\n return;\n }\n else if(info[1][0] == 'a')\n {\n int Xindex = index_tree[X];\n int Yindex = index_tree[Y];\n if(Xindex+1 >= vec.size() || vec[Xindex].S >= vec[Yindex].S)\n\t{\n\t cout << \"False\" << endl;\n\t return;\n\t}\n\n for(int i=Xindex+1;i < vec.size() && vec[i].S > vec[Xindex].S;i++)\n\t{\n\t if(vec[i].F == vec[Yindex].F)\n\t {\n\t cout << \"True\" << endl;\n\t return;\n\t }\n\t}\n\n cout << \"False\" << endl;\n return;\n }\n else \n assert(false);\n \n\n}\n\nint main()\n{\n int n,m;\n while(true)\n {\n cin >> n >> m;\n \n if(!(n+m))\n\tbreak;\n oldest = (1<<28);\n youngest = -1;\n cin.ignore();\n string line;\n vector<SI> vec;\n for(int i=0;i<n;i++)\n\t{\n\t getline(cin,line);\n\t\n\t split(vec,line);\n\t}\n\n map<string,int> index_tree;\n for(int i=0;i<n;i++)\n\tindex_tree[vec[i].F] = i;\n\n for(int i=0;i<m;i++)\n\t{\n\t getline(cin,line);\n\t \n\t ParseAndSolve(vec,index_tree,line.substr(0,line.size()-1));\n\t \n\t}\n\n cout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1360, "score_of_the_acc": -0.0032, "final_rank": 5 }, { "submission_id": "aoj_1217_585857", "code_snippet": "#include<map>\n#include<sstream>\n#include<cstdlib>\n#include<vector>\n#include<algorithm>\n#include<iostream>\n#include<cassert>\n#define F first\n#define S second\n#define pb push_back\n#define all(n) n.begin(),n.end()\nusing namespace std;\ntypedef pair<string,int> SI;\n\nint oldest,youngest;\n\nvoid split(vector<SI>& vec,string line)\n{\n int space_cnt = 0;\n for(int i=0;line[i] == ' ';i++,space_cnt++){}\n\n vec.push_back(SI(line.substr(space_cnt,line.size()-space_cnt),space_cnt));\n oldest = min(oldest,space_cnt);\n youngest = max(youngest,space_cnt);\n}\n\nvoid ParseAndSolve(vector<SI>& vec,map<string,int>& index_tree,map<int,vector<string> >& space_tree,map<string,int>& level_tree,string line)\n{\n vector<string> info;\n stringstream ss(line);\n string mid;\n vector<string> ope; \n \n\n for(int i=0;i<ss.str().size();i++)\n {\n if((ss >> mid).fail())\n\tgoto skip;\n \n ope.push_back(mid);\n \n }\n\n skip:\n\n info.push_back(ope[0]);\n for(int i=1;i<ope.size()-1;i++)\n {\n if(ope[i] == \"child\" || ope[i] == \"parent\" || ope[i] == \"sibling\" || ope[i] == \"descendant\" || ope[i] == \"ancestor\")\n\t{\n\t info.push_back(ope[i]);\n\t break;\n\t}\n }\n info.push_back(ope[ope.size()-1].substr(0,ope[ope.size()-1].size()));\n\n\n assert(info.size() == 3);\n\n string X,Y;\n X = info[0],Y = info[2];\n\n if(info[1][0] == 'c')\n {\n int Yindex = index_tree[Y]; \n int Xindex = index_tree[X];\n\n if(level_tree[X] <= level_tree[Y] || Yindex+1 >= vec.size() || vec[Yindex+1].S != vec[Xindex].S)\n\t{\n\t cout << \"False\" << endl;\n\t return;\n\t}\n\n \n int parent_level = vec[Yindex].S;\n\n for(int i=Yindex+1;parent_level < vec[i].S && i < vec.size();i++)\n\t{\n\n\t if(vec[i].F == X)\n\t {\n\t cout << \"True\" << endl;\n\t return;\n\t }\n\t}\n\n cout << \"False\" << endl;\n return;\n }\n else if(info[1][0] == 'p')\n {\n\n int Xindex = index_tree[X];\n int Yindex = index_tree[Y];\n\n if(level_tree[X] >= level_tree[Y] || Xindex+1 >= vec.size() || vec[Xindex+1].S != vec[Yindex].S )\n\t{\n\t cout << \"False\" << endl;\n\t return;\n\t}\n\n\n int parent_level = vec[Xindex].S;\n\n for(int i=Xindex+1;parent_level < vec[i].S && i < vec.size();i++ )\n\t{\n\t if(vec[i].F == Y)\n\t {\n\t cout << \"True\" << endl;\n\t return;\n\t }\n\t}\n\n cout << \"False\" << endl;\n return;\n\n\n }\n else if(info[1][0] == 's')\n {\n int Xindex = index_tree[X];\n int Yindex = index_tree[Y];\n\n if(vec[Xindex].S != vec[Yindex].S || min(Xindex,Yindex)+1 >= vec.size())\n\t{\n\t cout << \"False\" << endl;\n\t return;\n\t}\n\n int sibling_level = vec[Xindex].S;\n\n int Maxindex,Minindex;\n string Maxname,Minname;\n\n if(Xindex > Yindex)\n\t{\n\t Maxindex = Xindex,Minindex = Yindex;\n\t Maxname = X,Minname = Y;\n\t}\n else \n\t{\n\t Maxindex = Yindex,Minindex = Xindex;\n\t Maxname = Y,Minname = X;\n\t}\n\n for(int i=Minindex+1;i<vec.size() && sibling_level <= vec[i].S;i++)\n\t{\n\t if(Maxname == vec[i].F)\n\t {\n\t cout << \"True\" << endl;\n\t return;\n\t }\n\t}\n cout << \"False\" << endl;\n return;\n\n }\n else if(info[1][0] == 'd')\n {\n int Xindex = index_tree[X];\n int Yindex = index_tree[Y];\n\n if(Yindex+1 >= vec.size() || vec[Xindex].S <= vec[Yindex].S)\n\t{\n\t cout << \"False\" << endl;\n\t return;\n\t}\n\n for(int i=Yindex+1;i<vec.size() && vec[i].S > vec[Yindex].S;i++)\n\t{\n\t if(vec[i].F == vec[Xindex].F)\n\t {\n\t cout << \"True\" << endl;\n\t return;\n\t }\n\t}\n\n cout << \"False\" << endl;\n return;\n }\n else if(info[1][0] == 'a')\n {\n int Xindex = index_tree[X];\n int Yindex = index_tree[Y];\n if(Xindex+1 >= vec.size() || vec[Xindex].S >= vec[Yindex].S)\n\t{\n\t cout << \"False\" << endl;\n\t return;\n\t}\n\n for(int i=Xindex+1;i < vec.size() && vec[i].S > vec[Xindex].S;i++)\n\t{\n\t if(vec[i].F == vec[Yindex].F)\n\t {\n\t cout << \"True\" << endl;\n\t return;\n\t }\n\t}\n\n cout << \"False\" << endl;\n return;\n }\n else \n assert(false);\n \n\n}\n\nint main()\n{\n int n,m;\n while(true)\n {\n cin >> n >> m;\n //cerr << n << \" \" << m << endl;\n if(!(n+m))\n\tbreak;\n oldest = (1<<28);\n youngest = -1;\n cin.ignore();\n string line;\n vector<SI> vec;\n for(int i=0;i<n;i++)\n\t{\n\t getline(cin,line);\n\t //cerr << line << endl;\n\t split(vec,line);\n\t}\n\n map<int,vector<string> > space_tree;\n map<string,int> level_tree;\n map<string,int> index_tree;\n for(int i=0;i<n;i++)\n\t{\n\t index_tree[vec[i].F] = i;\n\t level_tree[vec[i].F] = vec[i].S;\n\t space_tree[vec[i].S].pb(vec[i].F);\n\t}\n\n for(int i=0;i<m;i++)\n\t{\n\t getline(cin,line);\n\t //cerr << line << endl;\n\t ParseAndSolve(vec,index_tree,space_tree,level_tree,line.substr(0,line.size()-1));\n\t \n\t}\n\n cout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1428, "score_of_the_acc": -0.0086, "final_rank": 10 }, { "submission_id": "aoj_1217_561684", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <map>\nusing namespace std;\n\n\nstruct Person {\n string name;\n Person *parent;\n};\n\nconst int MAXN = 1005;\nint N, M;\nmap<string, Person*> conv;\nPerson root, person[MAXN];\n\nvoid init() {\n conv.clear();\n root.name = \"root\";\n root.parent = NULL;\n}\n\nbool child(Person *a, Person *b) { // a is child of b\n return a->parent == b;\n}\n\nbool sibling(Person *a, Person *b) {\n return a->parent == b->parent;\n}\n\nbool descendant(Person *a, Person *b) { // a is descendant of b\n while(a != NULL) {\n if(a->parent == b) return true;\n a = a->parent;\n }\n return false;\n}\n\nint main() {\n while(cin >> N >> M && (N|M)) {\n cin.ignore();\n init();\n Person *cp = &root;\n int depth = -1;\n for(int i = 0; i < N; ++i) {\n string line;\n getline(cin, line);\n int sp = 0;\n for(int j = 0; j < line.size() && line[j] == ' '; ++j, ++sp);\n\n Person &c = person[i];\n c.name = line.substr(sp);\n conv[c.name] = &person[i];\n\n if(sp > depth) {\n c.parent = cp;\n } else {\n for(int j = 0; j < depth-sp; ++j) {\n cp = cp->parent;\n }\n c.parent = cp->parent;\n }\n cp = &c;\n depth = sp;\n }\n\n while(M--) {\n string x, y, type;\n string dumy;\n cin >> x >> dumy >> dumy >> type >> dumy >> y;\n y = y.substr(0, y.size()-1);\n bool output = false;\n if(0) {\n } else if(type == \"child\") {\n output = child(conv[x], conv[y]);\n } else if(type == \"parent\") {\n output = child(conv[y], conv[x]);\n } else if(type == \"sibling\") {\n output = sibling(conv[x], conv[y]);\n } else if(type == \"descendant\") {\n output = descendant(conv[x], conv[y]);\n } else if(type == \"ancestor\") {\n output = descendant(conv[y], conv[x]);\n }\n cout << (output ? \"True\" : \"False\") << endl;\n }\n cout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1344, "score_of_the_acc": -0.1686, "final_rank": 14 }, { "submission_id": "aoj_1217_539282", "code_snippet": "#include <vector>\n#include <list>\n#include <map>\n#include <set>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <algorithm>\n#include <utility>\n#include <functional>\n#include <sstream>\n#include <iostream>\n#include <cstdio>\n#include <cmath>\n#include <cstdlib>\n#include <cctype>\n#include <string>\n#include <cstring>\n#include <ctime>\n#include <climits>\n#include <cassert>\nusing namespace std;\ninline int toInt(string s) {int v; istringstream sin(s);sin>>v;return v;}\ntemplate<class T> inline string toString(T x) {ostringstream sout;sout<<x;return sout.str();}\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<string> vs;\ntypedef pair<int, int> pii;\ntypedef long long ll;\n#define ALL(a) (a).begin(),(a).end()\n#define RALL(a) (a).rbegin(),(a).rend()\n#define EXIST(s,e) ((s).find(e)!=(s).end())\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) FOR(i,0,n)\n#define EACH(t,i,c) for(t::iterator i=(c).begin(); i!=(c).end(); ++i)\nconst double EPS = 1e-10;\nconst double PI = acos(-1.0);\n\nstruct person{\n\tvector<person> children;\n\tstring name;\n\tperson(string name):name(name){}\n\tint construct(vs &names,int indent,int index){\n\t\tFOR(i,index,names.size()){\n\t\t\tint next_indent=count(ALL(names[i]),' ');\n\t\t\tif(next_indent==indent+1){\n\t\t\t\tstring next_name=names[i];\n\t\t\t\tnext_name.erase(next_name.begin(),next_name.begin()+next_indent);\n\t\t\t\tchildren.push_back(person(next_name));\n\t\t\t}else if(next_indent>indent+1){\n\t\t\t\ti=children[children.size()-1].construct(names,indent+1,i)-1;\n\t\t\t}else{\n\t\t\t\treturn i;\n\t\t\t}\n\t\t}\n\t\treturn names.size();\n\t}\n\tbool is_child(string a,string b){\n\t\tif(name==b){\n\t\t\tREP(i,children.size()){\n\t\t\t\tif(children[i].name==a){\n\t\t\t\t\treturn true;\n\t\t\t\t}\n\t\t\t}\n\t\t\treturn false;\n\t\t}\n\t\tREP(i,children.size()){\n\t\t\tif(children[i].is_child(a,b)){\n\t\t\t\treturn true;\n\t\t\t}\n\t\t}\n\t\treturn false;\n\t}\n\tbool is_descendant(string a,string b,bool flag=false){\n\t\tif(flag&&name==a){\n\t\t\treturn true;\n\t\t}\n\t\tif(name==b||flag){\n\t\t\tREP(i,children.size()){\n\t\t\t\tif(children[i].is_descendant(a,b,true)){\n\t\t\t\t\treturn true;\n\t\t\t\t}\n\t\t\t}\n\t\t\treturn false;\n\t\t}\n\t\tREP(i,children.size()){\n\t\t\tif(children[i].is_descendant(a,b)){\n\t\t\t\treturn true;\n\t\t\t}\n\t\t}\n\t\treturn false;\n\t}\n\tbool is_parent(string a,string b){\n\t\tif(name==a){\n\t\t\tREP(i,children.size()){\n\t\t\t\tif(children[i].name==b){\n\t\t\t\t\treturn true;\n\t\t\t\t}\n\t\t\t}\n\t\t\treturn false;\n\t\t}\n\t\tREP(i,children.size()){\n\t\t\tif(children[i].is_parent(a,b)){\n\t\t\t\treturn true;\n\t\t\t}\n\t\t}\n\t\treturn false;\n\t}\n\tbool is_ancestor(string a,string b,bool flag=false){\n\t\tif(flag&&name==b){\n\t\t\treturn true;\n\t\t}\n\t\tif(name==a||flag){\n\t\t\tREP(i,children.size()){\n\t\t\t\tif(children[i].is_ancestor(a,b,true)){\n\t\t\t\t\treturn true;\n\t\t\t\t}\n\t\t\t}\n\t\t\treturn false;\n\t\t}\n\t\tREP(i,children.size()){\n\t\t\tif(children[i].is_ancestor(a,b)){\n\t\t\t\treturn true;\n\t\t\t}\n\t\t}\n\t\treturn false;\n\t}\n\tbool is_sibling(string a,string b){\n\t\tbool flag=false;\n\t\tREP(i,children.size()){\n\t\t\tif(children[i].name==a||children[i].name==b){\n\t\t\t\tif(flag){\n\t\t\t\t\treturn true;\n\t\t\t\t}\n\t\t\t\tflag=true;\n\t\t\t}\n\t\t}\n\t\tREP(i,children.size()){\n\t\t\tif(children[i].is_sibling(a,b)){\n\t\t\t\treturn true;\n\t\t\t}\n\t\t}\n\t\treturn false;\n\t}\n};\n\nint main(){\n\tint n,m;\n\twhile(cin>>n>>m,n&&m){\n\t\tstring name;\n\t\tgetline(cin,name);\n\t\tgetline(cin,name);\n\t\tperson root=person(name);\n\t\tvs names;\n\t\tREP(i,n-1){\n\t\t\tgetline(cin,name);\n\t\t\tnames.push_back(name);\n\t\t}\n\t\tint index=0;\n\t\troot.construct(names,0,index);\n\t\tREP(i,m){\n\t\t\tstring a,b,rel,trash;\n\t\t\tcin>>a>>trash>>trash>>rel>>trash>>b;\n\t\t\tbool ok;\n\t\t\tb.erase(b.end()-1,b.end());\n\t\t\tif(rel==\"child\"){\n\t\t\t\tok=root.is_child(a,b);\n\t\t\t}else if(rel==\"parent\"){\n\t\t\t\tok=root.is_parent(a,b);\n\t\t\t}else if(rel==\"ancestor\"){\n\t\t\t\tok=root.is_ancestor(a,b);\n\t\t\t}else if(rel==\"descendant\"){\n\t\t\t\tok=root.is_descendant(a,b);\n\t\t\t}else if(rel==\"sibling\"){\n\t\t\t\tok=root.is_sibling(a,b);\n\t\t\t}else{\n\t\t\t\tassert(0);\n\t\t\t}\n\t\t\tcout<<(ok?\"True\":\"False\")<<endl;\n\t\t}\n\t\tcout<<endl;\n\n\t}\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1460, "score_of_the_acc": -0.3444, "final_rank": 17 }, { "submission_id": "aoj_1217_521468", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#include<deque>\n#include<map>\n#include<set>\n#include<string>\n#include<sstream>\n#include<cstdio>\n#include<cmath>\n#include<cstring>\n#include<cctype>\n#include<climits>\nusing namespace std;\n#define REP(i, j) for(int i = 0; i < j; i++)\n#define FOR(i, j, k) for(int i = j; i < k; i++)\n#define P pair<int, string>\nconst int INF = INT_MAX / 2;\nconst int MAX_M = 1010;\n\nP cntSpace(string str){\n int cnt = 0;\n while(str[cnt] == ' ') cnt++;\n return P(cnt, str.substr(cnt));\n}\n\nbool isParent(int x, int y, vector<int> parent){\n if(parent[y] == x) return true;\n else return false;\n}\n\nbool checkQ(string str, map<string, int> list_i, vector<int> parent){\n stringstream ss(str);\n vector<string> vec;\n string tmp;\n while(ss >>tmp) vec.push_back(tmp);\n\n int x = list_i[vec[0]];\n int y = list_i[vec[5].erase(vec[5].size() - 1)];\n\n if(vec[3] == \"child\") return isParent(y, x, parent);\n if(vec[3] == \"parent\") return isParent(x, y, parent);\n if(vec[3] == \"sibling\") return parent[x] == parent[y];\n if(vec[3] == \"descendant\"){\n int now_x = x;\n while(parent[now_x] != -1){\n if(isParent(y, now_x, parent) == true) return true;\n now_x = parent[now_x];\n }\n return false;\n }\n if(vec[3] == \"ancestor\"){\n int now_y = y;\n while(parent[now_y] != -1){\n if(isParent(x, now_y, parent) == true) return true;\n now_y = parent[now_y];\n }\n return false;\n }\n}\n\n\n\nint main(){\n int m, n;\n while(cin >>m >>n && (n && m)){\n string name_line;\n getline(cin, name_line);\n\n vector<int> parent(m);\n int current_parent_i[MAX_M];\n map<string, int> list_i;\n\n parent[0] = -1;\n\n REP(i, m){\n getline(cin, name_line);\n\n P rank_and_name = cntSpace(name_line);\n current_parent_i[rank_and_name.first + 1] = i;\n list_i[rank_and_name.second] = i;\n\n if(i != 0){\n int now_parent = current_parent_i[rank_and_name.first];\n parent[i] = now_parent;\n }\n }\n\n REP(i, n){\n string q;\n getline(cin, q);\n bool ans = checkQ(q, list_i, parent);\n if(ans) cout <<\"True\" <<endl;\n else cout <<\"False\" <<endl;\n }\n cout <<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 1432, "score_of_the_acc": -1.0089, "final_rank": 19 }, { "submission_id": "aoj_1217_521127", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#include<deque>\n#include<map>\n#include<set>\n#include<string>\n#include<sstream>\n#include<cstdio>\n#include<cmath>\n#include<cstring>\n#include<cctype>\n#include<climits>\nusing namespace std;\n#define REP(i, j) for(int i = 0; i < j; i++)\n#define FOR(i, j, k) for(int i = j; i < k; i++)\n#define P pair<int, string>\nconst int INF = INT_MAX / 2;\nconst int MAX_M = 1010;\n\nP cntSpace(string str){\n int cnt = 0;\n while(str[cnt] == ' ') cnt++;\n return P(cnt, str.substr(cnt));\n}\n\nbool isParent(int x, int y, vector<int> parent){\n if(parent[y] == x) return true;\n else return false;\n}\n\nbool checkQ(string str, map<string, int> list_i, vector<int> parent){\n stringstream ss(str);\n vector<string> vec;\n string tmp;\n while(ss >>tmp) vec.push_back(tmp);\n\n int x = list_i[vec[0]];\n int y = list_i[vec[5].erase(vec[5].size() - 1)];\n\n if(vec[3] == \"child\") return isParent(y, x, parent);\n if(vec[3] == \"parent\") return isParent(x, y, parent);\n if(vec[3] == \"sibling\") return parent[x] == parent[y];\n if(vec[3] == \"descendant\"){\n int now_x = x;\n while(parent[now_x] != -1){\n if(isParent(y, now_x, parent) == true) return true;\n now_x = parent[now_x];\n }\n return false;\n }\n if(vec[3] == \"ancestor\"){\n int now_y = y;\n while(parent[now_y] != -1){\n if(isParent(x, now_y, parent) == true) return true;\n now_y = parent[now_y];\n }\n return false;\n }\n}\n\n\n\nint main(){\n while(true){\n string str_m_n;\n getline(cin, str_m_n);\n stringstream ss(str_m_n);\n int m, n;\n ss >>m >>n;\n if(!m && !n) break;\n\n vector<int> parent(m);\n int current_parent_i[MAX_M];\n map<string, int> list_i;\n\n parent[0] = -1;\n\n REP(i, m){\n string name_line;\n getline(cin, name_line);\n stringstream ss(name_line);\n P rank_and_name = cntSpace(name_line);\n current_parent_i[rank_and_name.first + 1] = i;\n list_i[rank_and_name.second] = i;\n if(i != 0){\n int now_parent = current_parent_i[rank_and_name.first];\n parent[i] = now_parent;\n }\n }\n\n REP(i, n){\n string q;\n getline(cin, q);\n bool ans = checkQ(q, list_i, parent);\n if(ans) cout <<\"True\" <<endl;\n else cout <<\"False\" <<endl;\n }\n cout <<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 1432, "score_of_the_acc": -1.0089, "final_rank": 19 } ]
aoj_1221_cpp
Problem F: Numoeba A scientist discovered a strange variation of amoeba. The scientist named it numoeba . A numoeba, though it looks like an amoeba, is actually a community of cells, which always forms a tree. The scientist called the cell leader that is at the root position of the tree. For example, in Fig. 1, the leader is A . In a numoeba, its leader may change time to time. For example, if E gets new leadership, the tree in Fig. 1 becomes one in Fig. 2. We will use the terms root, leaf, parent, child and subtree for a numoeba as defined in the graph theory. Numoeba changes its physical structure at every biological clock by cell division and cell death. The leader may change depending on this physical change. The most astonishing fact about the numoeba cell is that it contains an organic unit called numbosome , which represents an odd integer within the range from 1 to 12,345,677. At every biological clock, the value of a numbosome changes from n to a new value as follows: The maximum odd factor of 3 n + 1 is calculated. This value can be obtained from 3 n + 1 by repeating division by 2 while even. If the resulting integer is greater than 12,345,678, then it is subtracted by 12,345,678. For example, if the numbosome value of a cell is 13, 13 × 3 + 1 = 40 is divided by 2 3 = 8 and a new numbosome value 5 is obtained. If the numbosome value of a cell is 11,111,111, it changes to 4,320,989, instead of 16,666,667. If 3 n + 1 is a power of 2, yielding 1 as the result, it signifies the death of the cell as will be described below. At every biological clock, the next numbosome value of every cell is calculated and the fate of the cell and thereby the fate of numoeba is determined according to the following steps. A cell that is a leaf and increases its numbosome value is designated as a candidate leaf. A cell dies if its numbosome value becomes 1. If the dying cell is the leader of the numoeba, the numoeba dies as a whole. Otherwise, all the cells in the subtree from the dying cell (including itself) die. However, there is an exceptional case where the cells in the subtree do not necessarily die; if there is only one child cell of the dying non-leader cell, the child cell will replace the dying cell. Thus, a straight chain simply shrinks if its non-leader constituent dies. For example, consider a numoeba with the leader A below. If the leader A dies in (1), the numoeba dies. If the cell D dies in (1), (1) will be as follows. And, if the cell E dies in (1), (1) will be as follows. Note that this procedure is executed sequentially, top-down from the root of the numoeba to leaves. If the cells E and F will die in (1), the death of F is not detected at the time the procedure examines the cell E . The numoeba, therefore, becomes (3). One should not consider in such a way that the death of F makes G the only child of E , and, therefore, G will replace the dying E . If a candidate leaf survives with the numbosome value of n , it spawns a cell as its child, ...(truncated)
[ { "submission_id": "aoj_1221_1092280", "code_snippet": "#include<iostream>\n#include<vector>\n#include<tuple>\n#include<algorithm>\nusing namespace std;\n\nconst int MOD = 12345678;\nconst int NIL = -1;\n\nclass Numoeba {\npublic:\n Numoeba(const int n) :max_cell_(1), root_(0) {create_cell(n);}\n tuple<int, int> die() {\n for(int step = 1; step <= 500; ++step) {\n int t = dead_.size() - count(dead_.begin(), dead_.end(), true);\n max_cell_ = max(max_cell_, t);\n vector<int> candidate;\n int new_leader_id, new_leader_n = NIL;\n// cout<<step<<endl;\n// cout<<\"root: \"<<root_<<endl;\n// cout<<\"dead: \";for(const auto&d:dead_)cout<<\" \"<<d;cout<<endl;\n// cout<<\"numb: \";for(const auto&d:numbosome_)cout<<\" \"<<d;cout<<endl;\n if(traverse(root_, NIL, candidate, new_leader_id, new_leader_n)) return tuple<int, int>(step, max_cell_);\n for(auto& e: edge_) for(int i = 0; i < e.size(); ++i) if(dead_[e[i]]) e.erase(e.begin() + i--);\n// cout<<\"candidate: \";for(const auto&d:candidate)cout<<\" \"<<d;cout<<endl;\n for(const auto& c: candidate) {\n int n = (numbosome_[c] + 1) / 2;\n if(!(n & 1)) ++n;\n// if(n <= 1) continue;\n// if(dead_[c]) continue;\n add_child(c, create_cell(n));\n }\n if(new_leader_id == NIL) continue;\n root_ = new_leader_id;\n int n = (numbosome_[root_] + 1) / 2;\n if(!(n & 1)) --n;\n// if(n <= 1) continue;\n add_child(root_, create_cell(n));\n }\n return tuple<int, int>(NIL, max_cell_);\n }\nprivate:\n bool traverse(const int current, const int previous, vector<int>& candidate, int& new_leader_id, int& new_leader_n) {\n int pn = numbosome_[current];\n if(update(current) == 1) {\n dead_[current] = true;\n if(current == root_) return true;\n if(edge_[current].size() == 2) {\n int next = edge_[current][0];\n if(next == previous) next = edge_[current][1];\n for(auto& id: edge_[previous]) if(id == current) id = next;\n for(auto& id: edge_[next]) if(id == current) id = previous;\n return traverse(next, previous, candidate, new_leader_id, new_leader_n);\n }\n for(const auto& next: edge_[current]) if(next != previous) erase(next, current);\n return false;\n }\n if(numbosome_[current] > pn && edge_[current].size() <= 1) candidate.push_back(current);\n if(numbosome_[current] == new_leader_n) new_leader_id = NIL;\n if(numbosome_[current] > new_leader_n) {\n new_leader_n = numbosome_[current];\n new_leader_id = current;\n }\n for(const auto& next: edge_[current]) {\n if(next == previous) continue;\n if(traverse(next, current, candidate, new_leader_id, new_leader_n)) return true;\n }\n return false;\n }\n void erase(const int current, const int previous) {\n dead_[current] = true;\n for(const auto& next: edge_[current]) if(next != previous) erase(next, current);\n }\n int create_cell(const int n) {\n numbosome_.push_back(n);\n dead_.push_back(false);\n edge_.push_back(vector<int>());\n return (dead_.size() - 1);\n }\n void add_child(const int pid, const int cid) {\n edge_[pid].push_back(cid);\n edge_[cid].push_back(pid);\n }\n int update(const int id) {\n numbosome_[id] = numbosome_[id] * 3 + 1;\n while(!(numbosome_[id] & 1)) numbosome_[id] >>= 1;\n if(numbosome_[id] > MOD) numbosome_[id] -= MOD;\n// while(numbosome_[id] > MOD) numbosome_[id] -= MOD;\n return numbosome_[id];\n }\n int root_;\n int max_cell_;\n vector<int> numbosome_;\n vector<bool> dead_;\n vector<vector<int>> edge_;\npublic:\nvoid print(){\ncout<<\"root: \"<<root_<<endl;\ncout<<\"dead: \";for(const auto&d:dead_)cout<<\" \"<<d;cout<<endl;\ncout<<\"numb: \";for(const auto&d:numbosome_)cout<<\" \"<<d;cout<<endl;\ncout<<dead_.size()<<endl;\n}\n};\n\n\nint main() {\n int k;\n while(cin >> k, k) {\n Numoeba n(k);\n int step, numbosome;\n tie(step, numbosome) = n.die();\n cout << step << \" \" << numbosome << endl;\n// n.print();\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1484, "score_of_the_acc": -1, "final_rank": 4 }, { "submission_id": "aoj_1221_568200", "code_snippet": "#include<cstdio>\n#include<vector>\n\n#define rep(i,n) for(int i=0;i<(n);i++)\n\nusing namespace std;\n\nint idx,val[5000];\nbool cand[5000]; // candidate leaf かどうか\nvector<int> G[5000];\n\n// u を根とする部分木を削除\nvoid destroy(int u,int pre){\n\trep(i,G[u].size()) if(G[u][i]!=pre) destroy(G[u][i],u);\n\tG[u].clear();\n}\n\n// numbosome の計算\nvoid dfs0(int u,int pre){\n\tint a=3*val[u]+1;\n\twhile(a%2==0) a/=2;\n\tif(a>12345678) a-=12345678;\n\tcand[u]=(G[u].size()<=1&&val[u]<a);\n\tval[u]=a;\n\trep(i,G[u].size()) if(G[u][i]!=pre) dfs0(G[u][i],u);\n}\n\n// val==1 の頂点を削除\nbool dfs1(int u,int pre){\n\tif(val[u]==1){\n\t\tif(pre!=-1 && G[u].size()==2){ // special case\n\t\t\tint v=(G[u][0]==pre?G[u][1]:G[u][0]);\n\t\t\tG[u].clear();\n\t\t\trep(i,G[v].size()) if(G[v][i]==u) G[v].erase(G[v].begin()+i);\n\t\t\tG[pre].push_back( v );\n\t\t\tG[ v ].push_back(pre);\n\t\t\tdfs1(v,pre);\n\t\t\treturn false;\n\t\t}\n\t\telse{\n\t\t\tdestroy(u,pre);\n\t\t\treturn pre==-1;\n\t\t}\n\t}\n\telse{\n\t\trep(i,G[u].size()) if(G[u][i]!=pre) {\n\t\t\tint v=G[u][i];\n\t\t\tif(val[v]==1) G[u].erase(G[u].begin()+i--);\n\t\t\tdfs1(v,u);\n\t\t}\n\t\treturn false;\n\t}\n}\n\n// leaf bonus の処理\nvoid dfs2(int u,int pre){\n\tif(cand[u]){\n\t\tG[ u ].push_back(idx);\n\t\tG[idx].push_back( u );\n\t\tval[idx]=(val[u]+1)/2;\n\t\tif(val[idx]%2==0) val[idx]++;\n\t\tidx++;\n\t}\n\telse{\n\t\trep(i,G[u].size()) if(G[u][i]!=pre) dfs2(G[u][i],u);\n\t}\n}\n\n// 生きている頂点のリストを求める\nvoid dfs3(int u,int pre,vector<int> &res){\n\tres.push_back(u);\n\trep(i,G[u].size()) if(G[u][i]!=pre) dfs3(G[u][i],u,res);\n}\n\nint main(){\n\twhile(scanf(\"%d\",val),val[0]){\n\t\tidx=1;\n\t\tint t,leader=0,sz=1;\n\t\tfor(t=1;;t++){\n\t\t\t// step 0\n\t\t\tdfs0(leader,-1);\n\n\t\t\t// step 1\n\t\t\tif(dfs1(leader,-1)) break;\n\n\t\t\t// step 2\n\t\t\tdfs2(leader,-1);\n\n\t\t\t// step 3\n\t\t\tvector<int> seq;\n\t\t\tdfs3(leader,-1,seq);\n\t\t\tint next=-1;\n\t\t\tbool dup=false;\n\t\t\trep(i,seq.size()){\n\t\t\t\tif(next==-1 || val[seq[i]]>val[next]){\n\t\t\t\t\tnext=seq[i];\n\t\t\t\t\tdup=false;\n\t\t\t\t}\n\t\t\t\telse if(val[seq[i]]==val[next]){\n\t\t\t\t\tdup=true;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!dup){ // leader bonus\n\t\t\t\tleader=next;\n\t\t\t\tG[leader].push_back(idx);\n\t\t\t\tG[idx].push_back(leader);\n\t\t\t\tval[idx]=(val[leader]+1)/2;\n\t\t\t\tif(val[idx]%2==0) val[idx]--;\n\t\t\t\tseq.push_back(idx);\n\t\t\t\tidx++;\n\t\t\t}\n\n\t\t\tsz=max(sz,(int)seq.size());\n\t\t}\n\n\t\tprintf(\"%d %d\\n\",t,sz);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1344, "score_of_the_acc": -1.0307, "final_rank": 5 }, { "submission_id": "aoj_1221_412802", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <functional>\nusing namespace std;\n\nconst int MOD = 12345678;\n\n\nclass Cell\n{\npublic:\n int v;\n Cell* parent;\n bool visited, candidate,leaf;\n vector<Cell*> child;\n\n Cell(int v, Cell* parent)\n :v(v),parent(parent),visited(false),candidate(false),leaf(false)\n {}\n\n void update() {\n int p = v;\n\tv = 3*v + 1;\n\n while(v%2!=1) {\n v/=2;\n }\n\n v %= MOD;\n\tif(p < v) candidate = true;\n }\n};\n\nint count(Cell* cell)\n{\n\tint res = 1;\n\tfor(int i=0; i<cell->child.size(); i++)\n\t\tres += count(cell->child[i]);\n\n\treturn res;\n}\n\nvoid getValues(Cell* cell, vector<int>& res)\n{\n\tres.push_back(cell->v);\n\tfor(int i=0; i<cell->child.size(); i++) {\n\t\tgetValues(cell->child[i], res);\n\t}\n}\n\nCell* getNewLeader(Cell* cell, int v)\n{\n\tif(cell->v == v) return cell;\n\n\tfor(int i=0; i<cell->child.size(); i++){\n\t\tCell* res = getNewLeader(cell->child[i], v);\n\t\tif(res != NULL) return res;\n\t}\n\n\treturn NULL;\n}\n\nvoid checkLeaf(Cell* cell)\n{\n\tif(cell->child.size() == 0) cell->leaf = true;\n\tfor(int i=0; i<cell->child.size(); i++) {\n\t\tcheckLeaf(cell->child[i]);\n\t}\n}\n\nCell* selectLeader(Cell* root, bool& uniq)\n{\n\tvector<int> values;\n\tgetValues(root, values);\n\n\tsort(values.begin(), values.end(), greater<int>());\n\n\tif(values[0] == values[1]) {\n\t\tuniq = false;\n\t\treturn root->child[0];\n\t}\n\n\tuniq = true;\n\tCell* newleader = getNewLeader(root, values[0]);\n\n\treturn newleader;\n}\n\nvoid add(Cell* parent, int v)\n{\n\tparent->child.push_back(new Cell(v, parent));\n}\n\nvoid leaderBonus(Cell* leader)\n{\n int v = (leader->v+1)/2;\n if(v%2==0) v -= 1;\n\n add(leader, v);\n}\n\nvoid leafBonus(Cell* cell)\n{\n\tif(cell->leaf){\n int v = (cell->v+1)/2;\n if(v%2==0) v += 1;\n\n if(cell->candidate) {\n\t\t add(cell, v);\n\t }\n }\n\telse{\n for(int i=0; i<cell->child.size(); i++)\n\t\tleafBonus(cell->child[i]);\n }\n}\n\nvoid newTree(Cell* prev, Cell* next)\n{\n prev->visited = true;\n Cell* c = new Cell(prev->v, next);\n next->child.push_back(c);\n\n if(prev->parent) {\n if(!prev->parent->visited) {\n if(prev->parent->v != -1) {\n\t\tprev->parent->visited = true;\n\t\tnewTree(prev->parent, c);\n }\n }\n \n for(int i=0; i<prev->child.size(); i++) {\n if(!prev->child[i]->visited) {\n\t\tprev->child[i]->visited = true;\n\t\tnewTree(prev->child[i], c);\n }\n }\n }\n}\n\nvoid remove(Cell *cell)\n{\n\tfor(int i=0; i<cell->child.size(); i++) {\n\t\tremove(cell->child[i]);\n\t}\n\n\tdelete cell;\n}\n\nbool died(Cell *cell, bool leader)\n{\n\tif(cell->v == 1) {\n\t\tif(leader) {\n\t\t\tremove(cell);\n\t\t}\n\t\telse {\n\t\t\tCell* parent = cell->parent;\n\t\t\tint n=-1;\n\t\t\tfor(int i=0; i<parent->child.size(); i++) {\n\t\t\t\tif(parent->child[i] == cell) \n\t\t\t\t\tn = i;\n\t\t\t}\n\n\t\t\tparent->child.erase(parent->child.begin()+n);\n\t\t\t\n\t\t\tif(cell->child.size() != 1)\n\t\t\t{\n\t\t\t\tremove(cell);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tCell* grandchild = cell->child[0];\n\n\t\t\t\tparent->child.push_back(grandchild);\n\t\t\t\tgrandchild->parent = parent;\n\t\t\n\t\t\t\tdelete cell;\n\t\t\t\tcell = NULL;\n\t\t\t}\n\n\t\t\tdied(parent, false);\n\t\t\treturn true;\n\t\t}\n\t}\n\telse {\n\t\tfor(int i=0; i<cell->child.size(); i++) \n\t\t\tif(died(cell->child[i], false)) break;\n\t}\n\t\n\n return false;\n}\n\nvoid update(Cell* cell)\n{\n\tcell->update();\n\tfor(int i = 0; i < cell->child.size(); i++) {\n\t\tupdate(cell->child[i]);\n\t}\n}\n\nvoid solve(int v)\n{\n Cell* root = new Cell(-1, NULL);\n root->visited = true;\n add(root, v);\n\n Cell* leader = root->child[0];\n \n int cycle = 0, m = 1;\n while(1) {\n cycle++;\n\n update(leader);\n\tcheckLeaf(leader);\n\n\tdied(root, true);\n\tif(root->child.size() == 0) break;\n\n\tleafBonus(leader);\n\n Cell* newroot = new Cell(-1, NULL);\n\tnewroot->visited = true;\n\n\tbool uniq;\n leader = selectLeader(root, uniq);\n newTree(leader, newroot);\n\n\tleader = newroot->child[0]; \n\n if(uniq) leaderBonus(leader);\n\n m = max(m, count(leader));\n\n remove(root->child[0]);\n\n root = newroot;\n }\n\n cout << cycle << \" \" << m << endl;\n}\n\nint main()\n{\n int N;\n while(cin >> N, N)\n {\n solve(N);\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 1008, "score_of_the_acc": -1.6792, "final_rank": 8 }, { "submission_id": "aoj_1221_366863", "code_snippet": "#include<cstdio>\n#include<vector>\n#include<algorithm>\n#include<set>\n#include<map>\nusing namespace std;\ntypedef set<int> Edge;\nstruct Cell\n{\n\tint v;\n\tEdge edge;\n\tCell(int v):v(v),edge(){}\n\tCell():v(-1),edge(){}\n};\ntypedef map<int,Cell>Numoeba;\ntypedef Numoeba::value_type Pair;\n\nNumoeba numoeba;\nint makeIndex;\n\nint Collatz(int x)\n{\n\tx=3*x+1;\n\twhile(x%2==0)\n\t\tx/=2;\n\tif(x>=12345678)\n\t\tx-=12345678;\n\treturn x;\n}\nvoid ConnectEdge(int x,int y)\n{\n\tnumoeba.find(x)->second.edge.insert(y);\n\tnumoeba.find(y)->second.edge.insert(x);\n}\nvoid EraseEdge(int controlIndex,int erasedIndex)\n{\n\tnumoeba.find(controlIndex)->second.edge.erase(erasedIndex);\n}\nvoid Spawn(int K,int fromID)\n{\n\tnumoeba.insert( Pair(makeIndex,Cell(K)) );\n\tConnectEdge(fromID, makeIndex);\n\t++makeIndex;\n}\nvoid Kill(int id,int fromID,bool willDie)\n{\n\tconst Cell &cell=numoeba.find(id)->second;\n\tif(cell.v==1 || willDie)\n\t{\n\t\tif(!willDie && fromID>=0 && cell.edge.size()==2)\n\t\t{\n\t\t\tEdge::iterator ite=cell.edge.begin();\n\t\t\tif(*ite==fromID)\n\t\t\t\t++ite;\n\t\t\tint childID = *ite;\n\t\t\tEraseEdge(fromID, id);\n\t\t\tEraseEdge(childID,id);\n\t\t\tConnectEdge(childID,fromID);\n\t\t\tnumoeba.erase(id);\n\t\t\tKill(childID,fromID,false);\n\t\t}\n\t\telse\n\t\t{\n\t\t\tfor(Edge::iterator ite=cell.edge.begin(); ite!=cell.edge.end();)\n\t\t\t{\n\t\t\t\tif(*ite!=fromID)\n\t\t\t\t\tKill(*(ite++), id, true);\n\t\t\t\telse ++ite;\n\t\t\t}\n\t\t\tif(fromID>=0)\n\t\t\t\tEraseEdge(fromID,id);\n\t\t\tnumoeba.erase(id);\n\t\t}\n\t}\n\telse\n\t{\n\t\tfor(Edge::iterator ite=cell.edge.begin(); ite!=cell.edge.end();)\n\t\t\tif(*ite!=fromID)\n\t\t\t\tKill(*(ite++),id,false);\n\t\t\telse ++ite;\n\t}\n}\n\nint main()\n{\n\tvector<int>candidate;\n\tint K,T,maxCell,rootIndex, i;\n\twhile(scanf(\"%d\",&K),K)\n\t{\n\t\tmaxCell=1;\n\t\trootIndex = makeIndex = 0;\n\t\tnumoeba.clear();\n\t\tnumoeba.insert(Pair(makeIndex++,Cell(K)));\n\t\tfor(T=1;;++T)\n\t\t{\n\t\t\tcandidate.clear();\n\t\t\tfor(Numoeba::iterator ite=numoeba.begin(); ite!=numoeba.end(); ++ite)\n\t\t\t{\n\t\t\t\tint x=Collatz(ite->second.v);\n\t\t\t\tif(x>ite->second.v && (ite->second.edge.size()==1&&ite->first!=rootIndex || numoeba.size()==1))\n\t\t\t\t\tcandidate.push_back(ite->first);\n\t\t\t\tite->second.v = x;\n\t\t\t}\n\t\t\tKill(rootIndex,-1,false);\n\t\t\tif(numoeba.empty())\n\t\t\t\tbreak;\n\n\t\t\tfor(i=0; i<candidate.size(); ++i)\n\t\t\t{\n\t\t\t\tNumoeba::iterator ite=numoeba.find(candidate[i]);\n\t\t\t\tif(ite!=numoeba.end())\n\t\t\t\t{\n\t\t\t\t\tint v=(ite->second.v+1)/2;\n\t\t\t\t\tif(v%2==0)++v;\n\t\t\t\t\tSpawn(v,candidate[i]);\n\t\t\t\t}\n\t\t\t}\n\t\t\tint maxV=0, count=0, index=-1;\n\t\t\tfor(Numoeba::iterator ite=numoeba.begin(); ite!=numoeba.end(); ++ite)\n\t\t\t{\n\t\t\t\tint v=ite->second.v;\n\t\t\t\tif(maxV < v)\n\t\t\t\t{\n\t\t\t\t\tmaxV = v;\n\t\t\t\t\tindex=ite->first;\n\t\t\t\t\tcount=1;\n\t\t\t\t}\n\t\t\t\telse if(maxV == v)\n\t\t\t\t\t++count;\n\t\t\t}\n\t\t\tif(count==1)\n\t\t\t{\n\t\t\t\tint v=(maxV+1)/2;\n\t\t\t\tif(v%2==0)--v;\n\t\t\t\tSpawn(v,index);\n\t\t\t\trootIndex = index;\n\t\t\t}\n\t\t\tmaxCell = max<int>(maxCell, numoeba.size());\n\t\t}\n\t\tprintf(\"%d %d\\n\",T,maxCell);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 868, "score_of_the_acc": -0.8349, "final_rank": 3 }, { "submission_id": "aoj_1221_260254", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <iomanip>\n#include <algorithm>\n#include <cmath>\n#include <string>\n#include <vector>\n#include <list>\n#include <queue>\n#include <stack>\n#include <set>\n#include <map>\n#include <bitset>\n#include <numeric>\n#include <climits>\n#include <cfloat>\nusing namespace std;\n\nclass Cell\n{\npublic:\n int value;\n list<Cell*> to;\n bool candidate;\n\n Cell(int value0){\n value = value0;\n }\n ~Cell(){\n list<Cell*>::iterator it = to.begin();\n while(it != to.end()){\n (*it)->to.erase(find((*it)->to.begin(), (*it)->to.end(), this));\n delete *it;\n ++ it;\n }\n }\n\n void updateValue()\n {\n long long a = value;\n a *= 3;\n ++ a;\n while(a % 2 == 0)\n a /= 2;\n -- a;\n a %= 12345678;\n ++ a;\n candidate = (a > value);\n value = a;\n }\n\n void update(Cell* prev)\n {\n updateValue();\n candidate &= (to.size() == 0 || (prev != NULL && to.size() == 1));\n\n if(value == 1){\n if(prev != NULL && to.size() == 2){\n list<Cell*>::iterator it = to.begin();\n if(*it == prev)\n ++ it;\n prev->to.push_back(*it);\n *find((*it)->to.begin(), (*it)->to.end(), this) = prev;\n to.erase(it);\n }\n return;\n }\n\n list<Cell*>::iterator it = to.begin();\n while(it != to.end()){\n if(*it != prev){\n (*it)->update(this);\n if((*it)->value == 1){\n (*it)->to.erase(find((*it)->to.begin(), (*it)->to.end(), this));\n delete *it;\n it = to.erase(it);\n }else{\n ++ it;\n }\n }else{\n ++ it;\n }\n }\n\n if(candidate){\n int a = (value + 1) / 2;\n if(a % 2 == 0)\n ++ a;\n Cell* c = new Cell(a);\n c->to.push_back(this);\n to.push_back(c);\n }\n }\n\n static Cell* maxCell;\n static int maxValue;\n static bool ng;\n int findMax(Cell* prev)\n {\n if(value > maxValue){\n maxValue = value;\n maxCell = this;\n ng = false;\n }else if(value == maxValue){\n ng = true;\n }\n\n int num = 1;\n list<Cell*>::iterator it = to.begin();\n while(it != to.end()){\n if(*it != prev){\n num += (*it)->findMax(this);\n }\n ++ it;\n }\n\n return num;\n }\n\n void addLeaderBonus()\n {\n int a = (value + 1) / 2;\n if(a % 2 == 0)\n -- a;\n Cell* c = new Cell(a);\n c->to.push_back(this);\n to.push_back(c);\n }\n};\nCell* Cell::maxCell;\nint Cell::maxValue;\nbool Cell::ng;\n\nCell* leader;\n\nint main()\n{\n for(;;){\n int n;\n cin >> n;\n if(n == 0)\n return 0;\n\n leader = new Cell(n);\n int t = 0;\n int ret = 1;\n for(;;){\n ++ t;\n leader->update(NULL);\n if(leader->value == 1)\n break;\n\n Cell::maxValue = -1;\n int num = leader->findMax(NULL);\n if(!Cell::ng){\n leader = Cell::maxCell;\n leader->addLeaderBonus();\n ++ num;\n }\n ret = max(ret, num);\n }\n\n cout << t << ' ' << ret << endl;\n\n delete leader;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1221_90736", "code_snippet": "#include<cstdlib>\n#include<cstdio>\n#include<iostream>\n#include<vector>\nusing namespace std;\n#define REP(i,b,n) for(int i=b;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define ALL(C) (C).begin(),(C).end()\n#define pb push_back\n\nclass Tree{\npublic:\n int value;\n vector<Tree*> child;\n Tree *parent;\n bool iscand;\n Tree(){};\n Tree(int tv,Tree *tp){\n child.clear();\n parent=tp;\n value=tv;\n iscand=false;\n child.pb(tp);\n }\n bool isvalid(int i){\n if (child[i] == NULL || child[i] == parent)return false;\n return true;\n }\n void del(Tree *now){\n rep(i,child.size()){\n if (now == child[i]){\n\tchild.erase(child.begin()+i);\n\ti--;\n }\n }\n }\n int count_valid(){\n int cnt=0;\n rep(i,child.size()){\n if (isvalid(i))cnt++;\n }\n return cnt;\n }\n};\n\nint compute(int n){\n n = 3*n+1;\n while(n%2 == 0)n/=2;\n if (n > 12345678)n-=12345678;\n return n;\n}\n\nvoid update(Tree *now){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n update(now->child[i]);\n }\n int tmp=now->value;\n now->value=compute(now->value);\n if (now->count_valid() ==0 && tmp < now->value)now->iscand=true;\n else now->iscand=false;\n}\n\n\nvoid get_all_death(Tree *now,vector<Tree*> &wildel){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n get_all_death(now->child[i],wildel);\n }\n wildel.pb(now);\n}\n\nbool death(Tree *now,vector<Tree*> &wildel){\n if (now->value == 1){\n int cnt = 0;//count child\n Tree *ins=NULL;\n rep(i,now->child.size()){\n if (now->isvalid(i)){\n\tcnt++;\n\tins=now->child[i];\n }\n }\n if (cnt == 1 && now->parent != NULL){\n now->parent->child.pb(ins);//because of chain\n ins->parent=now->parent;\n ins->del(now);\n ins->child.pb(now->parent);\n\n wildel.pb(now);\n }else get_all_death(now,wildel);\n return true;\n }\n\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n if (death(now->child[i],wildel)){\n now->child.erase(now->child.begin()+i);\n i--;\n }\n }\n return false;//survive\n}\n\nvoid make_child(Tree *now){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n make_child(now->child[i]);\n }\n \n if (now->iscand){\n int newvalue = (now->value+1)/2;\n if (newvalue%2 == 0)newvalue++;\n Tree *newnode;\n newnode = new Tree(newvalue,now);\n now->child.pb(newnode);\n }\n}\n\nvoid find_new_leader(Tree *now,int &maxval,int &maxcnt,Tree* &who){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n find_new_leader(now->child[i],maxval,maxcnt,who);\n }\n \n if (now->value > maxval){\n maxval=now->value;\n maxcnt=1;\n who=now;\n }else if (now->value == maxval)maxcnt++;\n}\n\nvoid replace(Tree *now,Tree *parent){\n if (now == NULL)return;\n replace(now->parent,now);\n now->parent=parent;\n}\n\nTree* find_leader(Tree *root){\n int maxval=0,maxcnt=0;\n Tree *who=NULL;\n find_new_leader(root,maxval,maxcnt,who);\n if (maxcnt == 1){\n replace(who,NULL);\n int newvalue = (who->value+1)/2;\n if (newvalue %2 == 0)newvalue--;\n\n Tree *bonus;\n bonus=new Tree(newvalue,who);\n who->child.pb(bonus);\n return who;\n }else return root;\n}\n\nvoid del_travarse(Tree *now,vector<Tree*> &wildel){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n del_travarse(now->child[i],wildel);\n }\n\n rep(i,wildel.size()){\n now->del(wildel[i]);\n }\n}\n\nbool operation_death(Tree *root){\n bool ret=false;\n vector<Tree*> wildel;\n if (death(root,wildel))ret=true;\n del_travarse(root,wildel);\n rep(i,wildel.size())free(wildel[i]);\n return ret;\n}\n\nvoid count_node(Tree *now,int &cnt){\n cnt++;\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n count_node(now->child[i],cnt);\n }\n}\n\nvoid solve(int val){\n Tree *root;\n root=new Tree(val,NULL);\n int cnt=1;\n int maxnum=1;\n while(true){\n update(root);\n if (operation_death(root))break;\n make_child(root);\n root = find_leader(root);\n int tmp = 0;\n count_node(root,tmp);\n maxnum=max(maxnum,tmp);\n cnt++;\n }\n \n cout << cnt <<\" \" << maxnum << endl;\n return;\n}\n\nmain(){\n int n;\n while(cin>>n && n){\n solve(n);\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 0, "score_of_the_acc": -0.375, "final_rank": 2 }, { "submission_id": "aoj_1221_90731", "code_snippet": "#include<cstdlib>\n#include<cstdio>\n#include<iostream>\n#include<vector>\nusing namespace std;\n#define REP(i,b,n) for(int i=b;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define ALL(C) (C).begin(),(C).end()\n#define pb push_back\n\nclass Tree{\npublic:\n int value;\n vector<Tree*> child;\n Tree *parent;\n bool iscand;\n Tree(){};\n Tree(int tv,Tree *tp){\n child.clear();\n parent=tp;\n value=tv;\n iscand=false;\n child.pb(tp);\n }\n bool isvalid(int i){\n if (child[i] == NULL || child[i] == parent)return false;\n return true;\n }\n void del(Tree *now){\n rep(i,child.size()){\n if (now == child[i]){\n\tchild.erase(child.begin()+i);\n\ti--;\n }\n }\n }\n int count_valid(){\n int cnt=0;\n rep(i,child.size()){\n if (isvalid(i))cnt++;\n }\n return cnt;\n }\n};\n\nint compute(int n){\n n = 3*n+1;\n while(n%2 == 0)n/=2;\n if (n > 12345678)n-=12345678;\n return n;\n}\n\nvoid update(Tree *now){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n update(now->child[i]);\n }\n int tmp=now->value;\n now->value=compute(now->value);\n if (now->count_valid() ==0 && tmp < now->value)now->iscand=true;\n else now->iscand=false;\n}\n\n\nvoid get_all_death(Tree *now,vector<Tree*> &wildel){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n get_all_death(now->child[i],wildel);\n }\n wildel.pb(now);\n}\n\nbool death(Tree *now,vector<Tree*> &wildel){\n if (now->value == 1){\n int cnt = 0;//count child\n Tree *ins=NULL;\n rep(i,now->child.size()){\n if (now->isvalid(i)){\n\tcnt++;\n\tins=now->child[i];\n }\n }\n if (cnt == 1 && now->parent != NULL){\n now->parent->child.pb(ins);//because of chain\n ins->parent=now->parent;\n ins->del(now);\n ins->child.pb(now->parent);\n\n wildel.pb(now);\n }else get_all_death(now,wildel);\n return true;\n }\n\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n if (death(now->child[i],wildel)){\n now->child.erase(now->child.begin()+i);\n i--;\n }\n }\n return false;//survive\n}\n\nvoid make_child(Tree *now){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n make_child(now->child[i]);\n }\n \n if (now->iscand){\n int newvalue = (now->value+1)/2;\n if (newvalue%2 == 0)newvalue++;\n Tree *newnode;\n newnode = new Tree(newvalue,now);\n now->child.pb(newnode);\n }\n}\n\nvoid find_new_leader(Tree *now,int &maxval,int &maxcnt,Tree* &who){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n find_new_leader(now->child[i],maxval,maxcnt,who);\n }\n \n if (now->value > maxval){\n maxval=now->value;\n maxcnt=1;\n who=now;\n }else if (now->value == maxval)maxcnt++;\n}\n\nvoid replace(Tree *now,Tree *parent){\n if (now == NULL)return;\n replace(now->parent,now);\n now->parent=parent;\n}\n\nTree* find_leader(Tree *root){\n int maxval=0,maxcnt=0;\n Tree *who=NULL;\n find_new_leader(root,maxval,maxcnt,who);\n if (maxcnt == 1){\n replace(who,NULL);\n int newvalue = (who->value+1)/2;\n if (newvalue %2 == 0)newvalue--;\n\n Tree *bonus;\n bonus=new Tree(newvalue,who);\n who->child.pb(bonus);\n return who;\n }else return root;\n}\n\nvoid del_travarse(Tree *now,vector<Tree*> &wildel){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n del_travarse(now->child[i],wildel);\n }\n\n rep(i,wildel.size()){\n now->del(wildel[i]);\n }\n}\n\nbool operation_death(Tree *root){\n bool ret=false;\n vector<Tree*> wildel;\n if (death(root,wildel))ret=true;\n // del_travarse(root,wildel);\n // rep(i,wildel.size())free(wildel[i]);\n return ret;\n}\n\nvoid count_node(Tree *now,int &cnt){\n cnt++;\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n count_node(now->child[i],cnt);\n }\n}\n\nvoid solve(int val){\n Tree *root;\n root=new Tree(val,NULL);\n int cnt=1;\n int maxnum=1;\n while(true){\n update(root);\n if (operation_death(root))break;\n make_child(root);\n root = find_leader(root);\n int tmp = 0;\n count_node(root,tmp);\n maxnum=max(maxnum,tmp);\n cnt++;\n }\n \n cout << cnt <<\" \" << maxnum << endl;\n return;\n}\n\nmain(){\n int n;\n while(cin>>n && n){\n solve(n);\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1436, "score_of_the_acc": -1.0927, "final_rank": 6 }, { "submission_id": "aoj_1221_90728", "code_snippet": "#include<cstdlib>\n#include<cstdio>\n#include<iostream>\n#include<vector>\nusing namespace std;\n#define REP(i,b,n) for(int i=b;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define ALL(C) (C).begin(),(C).end()\n#define pb push_back\n\nclass Tree{\npublic:\n int value;\n vector<Tree*> child;\n Tree *parent;\n bool iscand;\n Tree(){};\n Tree(int tv,Tree *tp){\n child.clear();\n parent=tp;\n value=tv;\n iscand=false;\n child.pb(tp);\n }\n bool isvalid(int i){\n if (child[i] == NULL || child[i] == parent)return false;\n return true;\n }\n void del(Tree *now){\n rep(i,child.size()){\n if (now == child[i]){\n\tchild.erase(child.begin()+i);\n\ti--;\n }\n }\n }\n int count_valid(){\n int cnt=0;\n rep(i,child.size()){\n if (isvalid(i))cnt++;\n }\n return cnt;\n }\n};\n\nint compute(int n){\n n = 3*n+1;\n while(n%2 == 0)n/=2;\n if (n > 12345678)n-=12345678;\n return n;\n}\n\nvoid update(Tree *now){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n update(now->child[i]);\n }\n int tmp=now->value;\n now->value=compute(now->value);\n if (now->count_valid() ==0 && tmp < now->value)now->iscand=true;\n else now->iscand=false;\n}\n\n\nvoid get_all_death(Tree *now,vector<Tree*> &wildel){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n get_all_death(now->child[i],wildel);\n }\n wildel.pb(now);\n}\n\nbool death(Tree *now,vector<Tree*> &wildel){\n if (now->value == 1){\n int cnt = 0;//count child\n Tree *ins=NULL;\n rep(i,now->child.size()){\n if (now->isvalid(i)){\n\tcnt++;\n\tins=now->child[i];\n }\n }\n if (cnt == 1 && now->parent != NULL){\n now->parent->child.pb(ins);//because of chain\n ins->parent=now->parent;\n ins->del(now);\n ins->child.pb(now->parent);\n\n wildel.pb(now);\n }else get_all_death(now,wildel);\n return true;\n }\n\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n if (death(now->child[i],wildel)){\n now->child.erase(now->child.begin()+i);\n i--;\n }\n }\n return false;//survive\n}\n\nvoid make_child(Tree *now){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n make_child(now->child[i]);\n }\n \n if (now->iscand){\n int newvalue = (now->value+1)/2;\n if (newvalue%2 == 0)newvalue++;\n Tree *newnode;\n newnode = new Tree(newvalue,now);\n now->child.pb(newnode);\n }\n}\n\nvoid find_new_leader(Tree *now,int &maxval,int &maxcnt,Tree* &who){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n find_new_leader(now->child[i],maxval,maxcnt,who);\n }\n \n if (now->value > maxval){\n maxval=now->value;\n maxcnt=1;\n who=now;\n }else if (now->value == maxval)maxcnt++;\n}\n\nvoid replace(Tree *now,Tree *parent){\n if (now == NULL)return;\n replace(now->parent,now);\n now->parent=parent;\n}\n\nTree* find_leader(Tree *root){\n int maxval=0,maxcnt=0;\n Tree *who=NULL;\n find_new_leader(root,maxval,maxcnt,who);\n if (maxcnt == 1){\n replace(who,NULL);\n int newvalue = (who->value+1)/2;\n if (newvalue %2 == 0)newvalue--;\n\n Tree *bonus;\n bonus=new Tree(newvalue,who);\n who->child.pb(bonus);\n return who;\n }else return root;\n}\n\nvoid travarse(Tree *now){\n cout <<\"I'm \" << now->value <<\" : \" <<now <<\" \" << now->parent<<\" : \";\n rep(i,now->child.size()){\n //if (!now->isvalid(i))continue;\n if (now->child[i] == now)continue;\n else if (now->child[i] != NULL)cout << now->child[i]->value <<\",\";\n else cout << now->child[i]<<\",\";\n }\n cout << endl;\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n travarse(now->child[i]);\n }\n}\n\n\nvoid del_travarse(Tree *now,vector<Tree*> &wildel){\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n del_travarse(now->child[i],wildel);\n }\n\n rep(i,wildel.size()){\n now->del(wildel[i]);\n }\n}\n\nbool operation_death(Tree *root){\n bool ret=false;\n vector<Tree*> wildel;\n if (death(root,wildel))ret=true;\n // cout << wildel.size() << endl;\n del_travarse(root,wildel);\n rep(i,wildel.size())free(wildel[i]);\n return ret;\n}\n\nvoid count_node(Tree *now,int &cnt){\n cnt++;\n rep(i,now->child.size()){\n if (!now->isvalid(i))continue;\n count_node(now->child[i],cnt);\n }\n}\n\nvoid solve(int val){\n Tree *root;\n root=new Tree(val,NULL);\n int cnt=1;\n int maxnum=1;\n while(true){\n update(root);\n\n // cout <<\"update end\"<<endl;\n // travarse(root);cout << endl;\n\n if (operation_death(root))break;\n\n //cout <<\"death end\" << endl;\n // travarse(root);cout << endl;\n\n make_child(root);\n //cout << \"make_child end\" << endl;\n //travarse(root);\n\n root = find_leader(root);\n\n\n int tmp = 0;\n count_node(root,tmp);\n maxnum=max(maxnum,tmp);\n // cout <<\"find leader end\" << endl;\n // travarse(root);cout << endl;\n //break;\n //if (cnt+1 == 105)travarse(root);\n cnt++;\n }\n \n cout << cnt <<\" \" << maxnum << endl;\n return;\n}\n\nmain(){\n int n;\n while(cin>>n && n){\n // cout <<\"initial value is \" << n << endl;\n solve(n);\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 1172, "score_of_the_acc": -1.2898, "final_rank": 7 } ]
aoj_1227_cpp
Problem D: 77377 At the risk of its future, International Cellular Phones Corporation (ICPC) invests its resources in developing new mobile phones, which are planned to be equipped with Web browser, mailer, instant messenger, and many other advanced communication tools. Unless members of ICPC can complete this stiff job, it will eventually lose its market share. You are now requested to help ICPC to develop intriguing text input software for small mobile terminals. As you may know, most phones today have twelve buttons, namely, ten number buttons from " 0 " to " 9 " and two special buttons " * " and " # ". Although the company is very ambitious, it has decided to follow today's standards and conventions. You should not change the standard button layout, and should also pay attention to the following standard button assignment. button letters button letters 2 a, b, c 6 m, n, o 3 d, e, f 7 p, q, r, s 4 g, h, i 8 t, u, v 5 j, k, l 9 w, x, y, z This means that you can only use eight buttons for text input. Most users of current ICPC phones are rushed enough to grudge wasting time on even a single button press. Your text input software should be economical of users' time so that a single button press is suffcient for each character input. In consequence, for instance, your program should accept a sequence of button presses " 77377 " and produce the word " press ". Similarly, it should translate " 77377843288866 " into "press the button". Ummm... It seems impossible to build such text input software since more than one English letter is represented by a digit!. For instance, " 77377 " may represent not only "press" but also any one of 768 (= 4 × 4 × 3 × 4 × 4) character strings. However, we have the good news that the new model of ICPC mobile phones has enough memory to keep a dictionary. You may be able to write a program that filters out false words , i.e., strings not listed in the dictionary. Input The input consists of multiple data sets, each of which represents a dictionary and a sequence of button presses in the following format. n word 1 . . . word n sequence n in the first line is a positive integer, representing the number of words in the dictionary. The next n lines, each representing a word in the dictionary, only contain lower case letters from ` a ' to ` z '. The order of words in the dictionary is arbitrary (not necessarily in the lexicographic order). No words occur more than once in the dictionary. The last line, sequence, is the sequence of button presses, and only contains digits from ` 2 ' to ` 9 '. You may assume that a dictionary has at most one hundred words and that the length of each word is between one and fifty, inclusive. You may also assume that the number of input digits in the sequence is between one and three hundred, inclusive. A line containing a zero indicates the end of the input. Output For each data set, your program should print all sequences that can be represented by the input sequence of button presses. Each s ...(truncated)
[ { "submission_id": "aoj_1227_746368", "code_snippet": "// start: 10:34\n// stop: 10:43\n// start: 10:50\n// stop: 11:22\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <climits>\n#include <cctype>\n#include <algorithm>\n#include <numeric>\n#include <iostream>\n#include <string>\n#include <vector>\n#include <queue>\n#include <set>\n#include <map>\n#include <complex>\n#include <sstream>\n#include <deque>\n\n#define REP(i, n) for ( int i = 0; i < n; i++ )\n\nusing namespace std;\n\nmap<char, vector<char> > table;\n// map<string, int> close;\n\nstruct input {\n int idx;\n string str;\n string current;\n vector<string> words;\n};\n\n// なければ空文字列を返す?\nbool in_dictionary(vector<string> &dict, string word) {\n REP(i, dict.size()) {\n if ( dict[i] == word ) {\n return true;\n }\n }\n return false;\n}\n\nbool dict_match(vector<string> &dict, string word) {\n REP(i, dict.size()) {\n int match = 0;\n REP(j, word.size()) {\n if(dict[i][j] == word[j]) match++;\n else break;\n }\n if(match == word.size()) {\n // cout << word << \" match: \" << dict[i] << endl;\n return true;\n }\n }\n // cout << word << \" is not match.\" << endl;\n return false;\n}\n\nvoid dump(vector<string> &arr) {\n REP(i, arr.size()) {\n cout << arr[i] << \" \";\n }\n cout << endl;\n}\n\nstring join(vector<string> &arr, string glue = \" \") {\n string ret = arr[0];\n for(int i = 1; i < arr.size(); i++) {\n ret += glue + arr[i];\n }\n return ret;\n}\n\nvector<string> decode(vector<string> &dict, string line) {\n vector<string> ret(1);\n\n queue<input> inputs;\n struct input init = {0, \"\", \"\", vector<string>()};\n\n inputs.push(init);\n\n while(!inputs.empty()) {\n struct input inp = inputs.front(); inputs.pop();\n\n string key = inp.str + inp.current;\n // if(close[key]) continue;\n // close[key] = 1;\n\n if(inp.idx >= line.size() && inp.current == \"\") {\n ret.push_back(join(inp.words));\n // cout << \"end of parse!!!!! \" << ret.size() << endl;\n // dump(ret);\n // break;\n }\n\n REP(i, table[line[inp.idx]].size()) {\n string tmp_current = inp.current, tmp_str = inp.str;\n vector<string> tmp_words = inp.words;\n\n tmp_current += table[line[inp.idx]][i];\n tmp_str += table[line[inp.idx]][i];\n\n // cout << tmp_current << \" in-dic:\" << in_dictionary(dict, tmp_current) << endl;\n if(in_dictionary(dict, tmp_current)) {\n string match_current = tmp_current;\n vector<string> match_words = tmp_words;\n\n match_words.push_back(match_current);\n match_current = \"\";\n // cout << inp.idx+1 << \" add dump: \";\n // dump(match_words);\n\n struct input match_inp = {inp.idx+1, tmp_str, match_current, match_words};\n inputs.push(match_inp);\n }\n\n // cout << tmp_current << \" \" << dict_match(dict, tmp_current) << endl;\n if(inp.idx <= line.size() && dict_match(dict, tmp_current)) {\n struct input new_inp = {inp.idx+1, tmp_str, tmp_current, tmp_words};\n inputs.push(new_inp);\n }\n }\n }\n\n return ret;\n}\n\n// vector<string> convert(input inp) {\n\n// }\n\nint main() {\n int n;\n table['2'] = vector<char>(3);\n table['3'] = vector<char>(3);\n table['4'] = vector<char>(3);\n table['5'] = vector<char>(3);\n table['6'] = vector<char>(3);\n table['7'] = vector<char>(4);\n table['8'] = vector<char>(3);\n table['9'] = vector<char>(4);\n\n table['2'][0] = 'a';\n table['2'][1] = 'b';\n table['2'][2] = 'c';\n table['3'][0] = 'd';\n table['3'][1] = 'e';\n table['3'][2] = 'f';\n table['4'][0] = 'g';\n table['4'][1] = 'h';\n table['4'][2] = 'i';\n table['5'][0] = 'j';\n table['5'][1] = 'k';\n table['5'][2] = 'l';\n table['6'][0] = 'm';\n table['6'][1] = 'n';\n table['6'][2] = 'o';\n table['7'][0] = 'p';\n table['7'][1] = 'q';\n table['7'][2] = 'r';\n table['7'][3] = 's';\n table['8'][0] = 't';\n table['8'][1] = 'u';\n table['8'][2] = 'v';\n table['9'][0] = 'w';\n table['9'][1] = 'x';\n table['9'][2] = 'y';\n table['9'][3] = 'z';\n\n while(cin >> n, n) {\n vector<string> dict(n);\n string line;\n\n // close.clear();\n\n REP(i, n) {\n cin >> dict[i];\n }\n\n cin >> line;\n\n vector<string> results = decode(dict, line);\n REP(i, results.size()) {\n if ( results[i] != \"\" ) cout << results[i] << \".\" << endl;\n }\n cout << \"--\" << endl;\n } \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1308, "score_of_the_acc": -1, "final_rank": 3 }, { "submission_id": "aoj_1227_261577", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <iomanip>\n#include <algorithm>\n#include <cmath>\n#include <string>\n#include <vector>\n#include <list>\n#include <queue>\n#include <stack>\n#include <set>\n#include <map>\n#include <bitset>\n#include <numeric>\n#include <climits>\n#include <cfloat>\nusing namespace std;\n\nint main()\n{\n int num[] = {3, 3, 3, 3, 3, 4, 3, 4};\n char x = 'a';\n vector<char> button(256);\n for(int i=0; i<8; ++i){\n for(int j=0; j<num[i]; ++j){\n button[x] = '2' + i;\n ++ x;\n }\n }\n\n for(;;){\n int n;\n cin >> n;\n if(n == 0)\n return 0;\n\n map<string, vector<string> > dic;\n for(int i=0; i<n; ++i){\n string s;\n cin >> s;\n int m = s.size();\n string b(m, ' ');\n for(int i=0; i<m; ++i)\n b[i] = button[s[i]];\n dic[b].push_back(s);\n }\n\n string press;\n cin >> press;\n n = press.size();\n vector<vector<string> > ret(n+1);\n ret[0].push_back(\"\");\n for(int i=0; i<n; ++i){\n for(int j=max(0, i-49); j<=i; ++j){\n string s = press.substr(j, i-j+1);\n map<string, vector<string> >::iterator it = dic.find(s);\n if(it != dic.end()){\n for(unsigned k=0; k<ret[j].size(); ++k){\n for(unsigned l=0; l<it->second.size(); ++l){\n ret[i+1].push_back(ret[j][k] + it->second[l] + ' ');\n }\n }\n }\n }\n }\n\n for(unsigned k=0; k<ret[n].size(); ++k){\n ret[n][k][ret[n][k].size()-1] = '.';\n cout << ret[n][k] << endl;\n }\n cout << \"--\" << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1227_188154", "code_snippet": "#include <iostream>\n#include <map>\n#include <string>\nusing namespace std;\n\nconst string ButtonTable = \"22233344455566677778889999\";\n\nstring hash(const string& s)\n{\n string t = \"\";\n for (unsigned int i = 0; i < s.size(); ++i)\n t += ButtonTable[s[i] - 'a'];\n return t;\n}\n\nvoid solve(multimap<string, string>& dic, string seq, string ans)\n{\n for (unsigned int i = 1; i <= seq.size(); ++i) {\n string h = seq.substr(0, i), rem = seq.substr(i);\n for (multimap<string, string>::iterator it = dic.find(h); it != dic.end() && (*it).first == h; ++it) {\n if (rem.empty()) \n\tcout << ans << (*it).second << \".\" << endl;\n else\n\tsolve(dic, rem, ans + (*it).second + \" \");\n }\n }\n return;\n}\n\nint main()\n{\n int n;\n while (cin >> n) {\n if (n == 0)\n break;\n\n multimap<string, string> dic;\n for (int i = 0; i < n; ++i) {\n string s;\n cin >> s;\n dic.insert(multimap<string, string>::value_type(hash(s), s));\n }\n\n string seq;\n cin >> seq;\n solve(dic, seq, \"\");\n\n cout << \"--\" << endl;\n\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1227_121290", "code_snippet": "#include <iostream>\n#include <map>\n#include <queue>\n#include <algorithm>\n#include <set>\n#include <vector>\nusing namespace std;\n\nstruct NODE{\n\tstring now;\n\tvector<string> words;\n};\n\nint main(){\n\tint table[26]={2,2,2,3,3,3,4,4,4,5,5,5,6,6,6,7,7,7,7,8,8,8,9,9,9,9};\n\tint n;\n\twhile(cin >> n ,n ){\n\t\tvector< pair<string,string> > data;\n\t\tstring s;\n\t\tset< vector<string> > ret;\n\t\tfor(int i=0;i<n;i++){\n\t\t\tcin >> s;\n\t\t\tstring tmp = s;\n\t\t\tfor(int j=0;j<s.length();j++){\n\t\t\t\ts[j] = table[s[j]-'a']+'0';\n\t\t\t}\n\t\t\tdata.push_back( make_pair(tmp,s) );\n\t\t}\n\t\tstring hoge;\n\t\tcin >> hoge;\n\t\t\n\t\tqueue<NODE> Q;\n\t\tNODE t;\n\t\tQ.push(t);\n\t\t\n\t\t//set<string> done;\n\t\t\n\t\twhile(Q.size()){\n\t\t\tNODE q = Q.front();Q.pop();\n\t\t\t//cout << q.now << endl;\n\t\t\tif( q.now == hoge){\n\t\t\t\tret.insert(q.words);\n\t\t\t}\n\t\t\t\n\t\t\tfor(int i=0;i<data.size();i++){\n\t\t\t\tNODE next = {q.now + data[i].second,q.words};\n\t\t\t\tnext.words.push_back(data[i].first);\n\t\t\t\tif( hoge.find(next.now) != 0)continue;\n\t\t\t\t//if( done.find(next.now) != done.end() )continue;\n\t\t\t\t//done.insert(next.now);\n\t\t\t\tQ.push(next);\n\t\t\t}\n\t\t}\n\t\t//sort(ret.begin(),ret.end(),greater<string>());\n\t\tfor( set<vector<string> >::iterator it = ret.begin(); it != ret.end(); ++it){\n\t\t\tfor(int i=0; i<(*it).size();i++)\n\t\t\t\tcout << (*it)[i] << (i == (*it).size()-1?\".\\n\":\" \");\n\t\t}\n\t\tcout << \"--\" << endl;\n\t}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 944, "score_of_the_acc": -1.7217, "final_rank": 4 } ]
aoj_1219_cpp
Problem D: Pump up Batteries Bill is a boss of security guards. He has pride in that his men put on wearable computers on their duty. At the same time, it is his headache that capacities of commercially available batteries are far too small to support those computers all day long. His men come back to the office to charge up their batteries and spend idle time until its completion. Bill has only one battery charger in the office because it is very expensive. Bill suspects that his men spend much idle time waiting in a queue for the charger. If it is the case, Bill had better introduce another charger. Bill knows that his men are honest in some sense and blindly follow any given instructions or rules. Such a simple-minded way of life may lead to longer waiting time, but they cannot change their behavioral pattern. Each battery has a data sheet attached on it that indicates the best pattern of charging and consuming cycle. The pattern is given as a sequence of pairs of consuming time and charging time. The data sheet says the pattern should be followed cyclically to keep the battery in quality. A guard, trying to follow the suggested cycle strictly, will come back to the office exactly when the consuming time passes out, stay there until the battery has been charged for the exact time period indicated, and then go back to his beat. The guards are quite punctual. They spend not a second more in the office than the time necessary for charging up their batteries. They will wait in a queue, however, if the charger is occupied by another guard, exactly on first-come-first-served basis. When two or more guards come back to the office at the same instance of time, they line up in the order of their identifi- cation numbers, and, each of them, one by one in the order of that line, judges if he can use the charger and, if not, goes into the queue. They do these actions in an instant. Your mission is to write a program that simulates those situations like Bill’s and reports how much time is wasted in waiting for the charger. Input The input consists of one or more data sets for simulation. The first line of a data set consists of two positive integers separated by a space character: the number of guards and the simulation duration. The number of guards does not exceed one hundred. The guards have their identification numbers starting from one up to the number of guards. The simulation duration is measured in minutes, and is at most one week, i.e., 10080 (min.). Patterns for batteries possessed by the guards follow the first line. For each guard, in the order of identification number, appears the pattern indicated on the data sheet attached to his battery. A pattern is a sequence of positive integers, whose length is a multiple of two and does not exceed fifty. The numbers in the sequence show consuming time and charging time alternately. Those times are also given in minutes and are at most one day, i.e., 1440 (min.). A space character or a newline follows e ...(truncated)
[ { "submission_id": "aoj_1219_7227174", "code_snippet": "#include <iostream>\n#include <queue>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nstruct E{\n\tint ot;\n\tint nt;\n\tint t;\n\tint no;\n\tint s;\n\tbool operator<(const E& e)const{\n\t\tif(t!=e.t)return t>e.t;\n\t\treturn no>e.no;\n\t}\n};\n\nvoid f(int n,int m){\n\tvector<vector<int> > ds;\n\tvector<int> v;\n\tvector<int> ss;\n\tpriority_queue<E> pqw;\n\tqueue<E> qs;\n\t\n\tfor(int i=0;i<n;i++){\n\t\tint t;\n\t\tds.push_back(v);\n\t\twhile(true){\n\t\t\tcin>>t;\n\t\t\tif(t==0)break;\n\t\t\tds[i].push_back(t);\n\t\t}\n\t\tss.push_back(ds[i].size());\n\t\tE e;\n\t\te.t=ds[i][0];\n\t\te.ot=0;\n\t\te.no=i;\n\t\te.s=0;\n\t\tpqw.push(e);\n\t}\n\t\n\tint t=0;\n\tint z=0;\n\tlong long int ans=0;\n\tbool addo=true;\n\twhile(pqw.size()>0 || qs.size()>0){\n\t\tz++;\n\t\tE e1;\n\t\tif(qs.size()==0 && pqw.size()>0){\n\t\t\te1=pqw.top();\n\t\t\tpqw.pop();\n\t\t\taddo=true;\n\t\t}else if(pqw.size()==0 && qs.size()>0){\n\t\t\te1=qs.front();\n\t\t\tqs.pop();\n\t\t\tif(qs.size()>0){\n\t\t\t\tE e2=qs.front();\n\t\t\t\tqs.front().nt=e1.t;\n\t\t\t\tqs.front().t=e1.t+ds[e2.no][e2.s];\n\t\t\t}\n\t\t\taddo=false;\n\t\t}else{\n\t\t\tE eq=qs.front();\n\t\t\tE ep=pqw.top();\n\t\t\t\n\t\t\tif(eq.t<=ep.t){\n\t\t\t\te1=qs.front();\n\t\t\t\tqs.pop();\n\t\t\t\tif(qs.size()>0){\n\t\t\t\t\tE e2=qs.front();\n\t\t\t\t\tqs.front().nt=e1.t;\n\t\t\t\t\tqs.front().t=e1.t+ds[e2.no][e2.s];\n\t\t\t\t}\n\t\t\t\taddo=false;\n\t\t\t}else{\n\t\t\t\te1=pqw.top();\n\t\t\t\tpqw.pop();\n\t\t\t\taddo=true;\n\t\t\t}\n\t\t}\n\t\t//cout<<e1.no<<\" \"<<e1.t<<\" \"<<t<<\" \"<<e1.ot<<\" \"<<ds[e1.no][e1.s]<<\" \"<<addo<<\" \"<<ans;\n\t\t//if(qs.size()>0){\n\t\t//\tcout<<\" \"<<qs.front().t;\n\t\t//}\n\t\t//cout<<endl;\n\t\tif(addo==false){\n\t\t\tans+=min(m,e1.nt)-e1.ot;\n\t\t}\n\t\t\n\t\tif(e1.t>=m){\n\t\t\tcontinue;\n\t\t}\n\t\tt=e1.t;\n\t\t\n\t\te1.s=(e1.s+1)%ss[e1.no];\n\t\tif(addo==true){\n\t\t\te1.ot=t;\n\t\t\tif(qs.size()==0){\n\t\t\t\te1.t=t+ds[e1.no][e1.s];\n\t\t\t\te1.nt=e1.ot;\n\t\t\t}\n\t\t\tqs.push(e1);\n\t\t}else{\n\t\t\t\n\t\t\te1.t=t+ds[e1.no][e1.s];\n\t\t\tpqw.push(e1);\n\t\t}\n\t\n\t}\n\tcout<<ans<<endl;\n}\n\nint main() {\n\twhile(true){\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tif(n==0 && m==0)break;\n\t\tf(n,m);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3168, "score_of_the_acc": -0.467, "final_rank": 13 }, { "submission_id": "aoj_1219_3807639", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <numeric>\n\n#define REP(i, a, b) for (int i = int(a); i < int(b); i++)\nusing namespace std;\ntypedef long long int ll;\n\n// clang-format off\n#ifdef _DEBUG_\n#define dump(...) do{ cerr << __LINE__ << \":\\t\" << #__VA_ARGS__ << \" = \"; PPPPP(__VA_ARGS__); cerr << endl; } while(false)\ntemplate<typename T> void PPPPP(T t) { cerr << t; }\ntemplate<typename T, typename... S> void PPPPP(T t, S... s) { cerr << t << \", \"; PPPPP(s...); }\n#else\n#define dump(...)\n#endif\ntemplate<typename T> vector<T> make_v(size_t a, T b) { return vector<T>(a, b); }\ntemplate<typename... Ts> auto make_v(size_t a, Ts... ts) { return vector<decltype(make_v(ts...))>(a, make_v(ts...)); }\ntemplate<typename T>\nbool chmin(T &a, T b) { if (a > b) {a = b; return true; } return false;}\ntemplate<typename T>\nbool chmax(T &a, T b) { if (a < b) {a = b; return true; } return false;}\n// clang-format on\n\n#include <utility>\nusing Bat = pair<int, int>;\n#include <queue>\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n, t;\n while (cin >> n >> t, n + t) {\n vector<vector<Bat>> v(n);\n REP(i, 0, n) {\n for (;;) {\n int a, b;\n cin >> a;\n if (a == 0) break;\n cin >> b;\n v[i].emplace_back(a, b);\n }\n }\n queue<int> q;\n vector<int> cur(n), pat(n, 0);\n REP(i, 0, n) {\n cur[i] = v[i][0].first;\n }\n ll ans = 0;\n int rem = 0, irem = -1;\n REP(T, 0, t) {\n REP(i, 0, n) {\n if (cur[i] == -1) continue;\n if (cur[i]-- == 0) {\n q.emplace(i);\n }\n }\n if (irem == -1 && q.size()) {\n irem = q.front();\n rem = v[irem][pat[irem]].second;\n q.pop();\n }\n if (irem != -1 && --rem == 0) {\n pat[irem] = (pat[irem] + 1) % v[irem].size();\n cur[irem] = v[irem][pat[irem]].first;\n irem = -1;\n rem = -1;\n }\n ans += q.size();\n /*\n REP(i, 0, n) {\n cout << cur[i] << \" \";\n }\n cout << q.size() << endl;\n */\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3164, "score_of_the_acc": -0.5461, "final_rank": 14 }, { "submission_id": "aoj_1219_3807450", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\n\nconstexpr long double EPS = 1e-15;\nconst long double PI = acos(-1);\nconstexpr int inf = 2e9;\nconstexpr ll INF = 2e18;\nconstexpr ll MOD = 1e9+7;\nconstexpr ll MOD1 = 998244353;\ntypedef pair<ll,ll> P;\n\n//#define all(v) (v).begin(), (v).end()\n#define rep(i,a,b) for (int i = (a); i < (b); i++)\n#define REP(i,n) rep(i,0,n)\n#define sz(s) (s).size()\n#define pb push_back\n#define fi first\n#define se second\n//#define mp make_pair\n\nbool pattern[110][10100];\nint pos[110];\nint n,m;\n\nvoid solve() {\nwhile (cin >> n >> m) {\n if (n == 0 && m == 0) break;\n \n for (int i = 0; i < n; i++) {\n pos[i] = 0;\n vector<int> v;\n int k;\n while (cin >> k, k) {\n v.pb(k);\n }\n int p = 0;\n bool status = 0;\n int vv = 0;\n while (p <= 10090) {\n int kk = v[vv];\n REP(j,kk) {\n if (p + 1 >= 10100) break;\n pattern[i][p++] = status;\n }\n vv = (vv + 1) % sz(v);\n status = !status;\n }\n }\n\n ll ans = 0;\n bool inque[110] = {};\n queue<int> que;\n for (int i = 0; i < m; i++) {\n for (int j = 0; j < n; j++) {\n if (!pattern[j][pos[j]]) pos[j]++;\n else {\n if (!inque[j]) {\n que.push(j);\n inque[j] = 1;\n }\n }\n }\n if (!que.empty()) {\n pos[que.front()]++;\n ans += que.size() - 1;\n if (pattern[que.front()][pos[que.front()]] == 0) {\n inque[que.front()] = 0;\n que.pop();\n }\n }\n // REP(j,n) {\n // cout << pos[j] << \" \";\n // }\n // cout << endl;\n }\n cout << ans << endl;\n}\n}\n\n\nint main(int argc, char *argv[]){\n\n // /* Regular */\n // int case_num = 1;\n // if (argc > 1 && stoi(argv[1])) cin >> case_num;\n // REP(case_no, case_num) {\n // cerr << endl << \"case \" << case_no + 1 << endl;\n // solve();\n // }\n\n /* AOJ */\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4036, "score_of_the_acc": -0.8207, "final_rank": 17 }, { "submission_id": "aoj_1219_2589731", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\nstruct Info{\n\tint cicle[51],cicile_index,cicle_num,wait_time,tmp_time;\n\tbool is_queue;\n};\n\nint N,Time_Limit;\nInfo info[100];\n\nvoid func(){\n\n\tint tmp;\n\n\tfor(int i = 0; i < N; i++){\n\t\tinfo[i].cicile_index = 0;\n\t\tinfo[i].wait_time = 0;\n\t\tinfo[i].tmp_time = 0;\n\t\tinfo[i].is_queue = false;\n\n\t\tfor(int k = 0; ;k++){\n\t\t\tscanf(\"%d\",&tmp);\n\t\t\tif(tmp != 0){\n\t\t\t\tinfo[i].cicle[k] = tmp;\n\t\t\t}else{\n\t\t\t\tinfo[i].cicle_num = k;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\n\tqueue<int> Q;\n\tbool Finished;\n\n\tfor(int time = 0; time < Time_Limit; time++){\n\t\tFinished = false;\n\t\tfor(int i = 0; i < N; i++){\n\t\t\tif(info[i].is_queue == false){\n\t\t\t\tinfo[i].tmp_time++;\n\t\t\t\tif(info[i].tmp_time == info[i].cicle[info[i].cicile_index]){\n\t\t\t\t\tinfo[i].tmp_time = 0;\n\t\t\t\t\tinfo[i].cicile_index++;\n\t\t\t\t\tQ.push(i);\n\t\t\t\t\tinfo[i].is_queue = true;\n\t\t\t\t}\n\t\t\t}else{\n\t\t\t\tif(i == Q.front()){\n\t\t\t\t\tinfo[i].tmp_time++;\n\t\t\t\t\tif(info[i].tmp_time == info[i].cicle[info[i].cicile_index]){\n\t\t\t\t\t\tinfo[i].tmp_time = 0;\n\t\t\t\t\t\tif(info[i].cicile_index == info[i].cicle_num-1){\n\t\t\t\t\t\t\tinfo[i].cicile_index = 0;\n\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\tinfo[i].cicile_index++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tinfo[i].is_queue = false;\n\t\t\t\t\t\tFinished = true;\n\t\t\t\t\t}\n\t\t\t\t}else{\n\t\t\t\t\tinfo[i].wait_time++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(Finished)Q.pop();\n\t}\n\n\tint ans = 0;\n\n\tfor(int i = 0; i < N; i++){\n\t\tans += info[i].wait_time;\n\t}\n\n\tprintf(\"%d\\n\",ans);\n}\n\nint main(){\n\n\twhile(true){\n\t\tscanf(\"%d %d\",&N,&Time_Limit);\n\t\tif(N == 0 && Time_Limit == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3236, "score_of_the_acc": -0.5621, "final_rank": 16 }, { "submission_id": "aoj_1219_2309658", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define F first\n#define S second\ntypedef pair<int,int> P;\n \nint main() {\n int n,t;\n while(cin>>n>>t&&n) {\n vector<P> v[n];\n int c[n],d=0;\n memset(c,0,sizeof(c));\n priority_queue<P,vector<P>,greater<P> > que;\n for(int i=0; i<n; i++) {\n int x,y;\n while(cin>>x&&x) {\n cin>>y;\n v[i].push_back(P(x,y));\n }\n if(v[i].size()) que.push(P(v[i][0].F,i));\n }\n int ans=0;\n for(int i=0; i<t; i++) {\n if(que.top().F<=i&&!d) {\n P p=que.top();que.pop();\n ans+=max(0,i-p.F);\n int k=p.S;\n d+=v[k][c[k]].S;\n c[k]=(c[k]+1)%v[k].size();\n que.push(P(i+v[k][c[k]].F+d,k));\n }\n if(d) d--;\n }\n while(!que.empty()) {\n P p=que.top();que.pop();\n ans+=max(0,t-p.F);\n }\n cout<<ans<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3124, "score_of_the_acc": -0.4571, "final_rank": 12 }, { "submission_id": "aoj_1219_2134138", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\n\n//// < \"d:\\d_download\\visual studio 2015\\projects\\programing_contest_c++\\debug\\a.txt\" > \"d:\\d_download\\visual studio 2015\\projects\\programing_contest_c++\\debug\\b.txt\"\n\n\nint main() {\n\twhile (1) {\n\t\tint N, T; cin >> N >> T;\n\t\tif (!N)break;\n\t\tint num = 0;\n\t\tvector<int>v;\n\t\tvector<vector<int>>guards(N);\n\t\twhile (num < N) {\n\t\t\tint a; cin >> a;\n\t\t\tif (a != 0) {\n\t\t\t\tguards[num].push_back(a);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tnum++;\n\t\t\t}\n\t\t}\n\t\tvector<pair<int, int>>status(N,make_pair(0,0));\n\t\tdeque<int>que;\n\t\tint ans = 0;\n\t\tfor (int t = 0; t < T; ++t) {\n\t\t\tint nbat = -1;\n\t\t\tif (!que.empty()) {\n\t\t\t\tans += que.size() - 1;\n\t\t\t\tnbat = que.front();\n\t\t\t}\n\t\t\tfor (int i = 0; i < N; ++i) {\n\t\t\t\t\n\t\t\t\tbool nowbat = status[i].first % 2;\n\t\t\t\tif (nowbat) {\n\t\t\t\t\tif (i ==nbat) {\n\t\t\t\t\t\tstatus[i].second++;\n\t\t\t\t\t\tif (status[i].second == guards[i][status[i].first]) {\n\t\t\t\t\t\t\tstatus[i].second = 0;\n\t\t\t\t\t\t\tstatus[i].first = (status[i].first + 1) % guards[i].size();\n\t\t\t\t\t\t\tque.pop_front();\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tstatus[i].second++;\n\t\t\t\t\tif (status[i].second == guards[i][status[i].first]) {\n\t\t\t\t\t\tstatus[i].second = 0;\n\t\t\t\t\t\tstatus[i].first = (status[i].first+1) % guards[i].size();\n\t\t\t\t\t\tque.push_back(i);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3184, "score_of_the_acc": -0.5505, "final_rank": 15 }, { "submission_id": "aoj_1219_1964425", "code_snippet": "#include <vector>\n#include <list>\n#include <map>\n#include <set>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <algorithm>\n#include <functional>\n#include <numeric>\n#include <utility>\n#include <sstream>\n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <cmath>\n#include <cstdlib>\n#include <cctype>\n#include <string>\n#include <cstring>\nusing namespace std;\n#define REP(i,n) for(int i = 0; i < (int)n; i++)\n#define FOR(i,a,b) for(int i = a; i < (int)b; i++)\n#define pb push_back\n#define mp make_pair\ntypedef vector<int> vi;\ntypedef pair<int, int> pi;\ntypedef long long ll;\nconst int INF = 1<<28;\nconst ll MOD = 1000000007;\nconst int dx[] = {1, 0, -1, 0}, dy[] = {0, 1, 0, -1};\n\nstruct guard {\n\tvector<bool> cycle;\n\tint cnt;\n};\n\nint main() {\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0);\n\n\tint g, d;\n\twhile(cin >> g >> d, g|d) {\n\t\tvector<guard> v(g);\n\t\tREP(i, g) {\n\t\t\tint in, in2 = 1;\n\t\t\twhile(cin >> in, in) {\n\t\t\t\tREP(j, in)\n\t\t\t\t\tv[i].cycle.pb(in2);\n\t\t\t\tin2 = (in2 + 1) % 2;\n\t\t\t}\n\t\t}\n\n\t\tqueue<int> q;\n\t\tset<int> s;\n\t\tREP(i, d) {\n\t\t\tREP(j, g) {\n\t\t\t\tif(v[j].cycle[v[j].cnt % v[j].cycle.size()])\n\t\t\t\t\tv[j].cnt++;\n\t\t\t\telse {\n\t\t\t\t\tif(!s.count(j)) {\n\t\t\t\t\t\tq.push(j);\n\t\t\t\t\t\ts.insert(j);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(q.size()) {\n\t\t\t\tint top = q.front();\n\t\t\t\tv[top].cnt++;\n\t\t\t\tif(v[top].cycle[v[top].cnt % v[top].cycle.size()]) {\n\t\t\t\t\tq.pop(); s.erase(top);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint ans = 0;\n\t\tREP(i, g)\n\t\t\tans += d - v[i].cnt;\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 1388, "score_of_the_acc": -1.0696, "final_rank": 18 }, { "submission_id": "aoj_1219_1162858", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n cin.tie(0); ios::sync_with_stdio(0);\n int n,T;\n while(cin >> n >> T, n){\n vector< vector<int> > cycle(n);\n for(int i=0;i<n;i++){\n int tmp;\n while(cin >> tmp, tmp)cycle[i].push_back(tmp);\n }\n vector<int> pos(n,0), end_time(n);\n for(int i=0;i<n;i++){\n end_time[i] = cycle[i][0];\n (pos[i] += 1) %= cycle[i].size();\n }\n\n queue<int> q;\n int charge = -1, charge_id = -1;\n int ans = 0;\n\n for(int t=0;t<T;t++){\n for(int i=0;i<n;i++){\n\tif(t==end_time[i]){\n\t end_time[i] = -1;\n\t q.push(i);\n\t}\n }\n \n if(charge <= t){\n\tif(charge_id>=0){\n\t end_time[charge_id] = t + cycle[charge_id][pos[charge_id]];\n\t (pos[charge_id] += 1) %= cycle[charge_id].size();\n\t charge = charge_id = -1;\n\t}\n\n\tif(q.size()){\n\t int nxt = q.front(); q.pop();\n\t charge = t + cycle[nxt][pos[nxt]];\n\t (pos[nxt] += 1) %= cycle[nxt].size();\n\t charge_id = nxt;\n\t}\n }\n\n ans += q.size();\n }\n\t \n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1240, "score_of_the_acc": -0.0766, "final_rank": 1 }, { "submission_id": "aoj_1219_1159232", "code_snippet": "#include <string> \n#include <algorithm> \n#include <cfloat> \n#include <climits> \n#include <cmath> \n#include <complex> \n#include <cstdio> \n#include <cstdlib> \n#include <cstring> \n#include <functional> \n#include <iostream> \n#include <map> \n#include <memory> \n#include <queue> \n#include <set> \n#include <sstream> \n#include <stack> \n#include <utility> \n#include <vector> \n\n#define EACH(i,c) for(__typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define ALL(x) (x).begin(),(x).end() \ntypedef long long ll;\nusing namespace std; \nconst double eps = 1e-10;\n\nstruct E{\n int id, time;\n E(){}\n E(int id, int time) : id(id), time(time) { }\n};\nbool operator<(const E &a, const E &b){\n if(a.time == b.time) return a.id > b.id;\n else return a.time > b.time;\n}\n\nint main(){\n for(;;){\n int n, m;\n cin >> n >> m;\n if(n == 0 && m == 0) return 0;\n vector<vector<int> > v(n);\n for(int i = 0; i < n; ++i){\n for(;;){\n int t;\n cin >> t;\n if(t == 0) break;\n v[i].push_back(t);\n }\n }\n\n vector<int> idx(n);\n priority_queue<E> eve;\n queue<int> Q;\n\n int res = 0;\n for(int i = 0; i < n; ++i){\n eve.push(E(i, v[i][0]));\n }\n eve.push(E(n, m));\n int lt = 0;\n while(!eve.empty()){\n int ct = eve.top().time;\n int id = eve.top().id;\n eve.pop();\n // cout << ct << \",\" << id << \",\" << max(0, (int)Q.size()-1) * (ct - lt) << endl;\n res += max(0, (int)Q.size()-1) * (ct - lt);\n if(id == n) break;\n else if(id < 0){\n int id = Q.front(); Q.pop();\n idx[id] = (idx[id] + 1) % v[id].size();\n eve.push(E(id, ct + v[id][idx[id]]));\n if(!Q.empty()){\n eve.push(E(-1, ct + v[Q.front()][idx[Q.front()]]));\n }\n }\n else if(idx[id] % 2 == 0){\n idx[id] = (idx[id] + 1) % v[id].size();\n if(Q.empty()){\n Q.push(id);\n eve.push(E(-1, ct + v[id][idx[id]]));\n }\n else{\n Q.push(id);\n }\n }\n lt = ct;\n }\n cout << res << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1248, "score_of_the_acc": -0.0784, "final_rank": 2 }, { "submission_id": "aoj_1219_1081141", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n\n#include <iostream>\n#include <cstdio>\n#include <sstream>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <queue>\n#include <stack>\n#include <limits>\n#include <map>\n#include <string>\n#include <cstring>\n#include <set>\n#include <deque>\n#include <bitset>\n#include <list>\n#include <cctype>\n#include <utility>\n#include <assert.h>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair <int,int> P;\ntypedef pair <int,P> PP;\n \nstatic const double EPS = 1e-8;\n\nclass State {\npublic:\n int _id;\n int _time;\n int _occupy;\n State(int id,int time,int occupy) : _id(id),_time(time), _occupy(occupy) {}\n bool operator<(const State& s) const {\n if(_time == s._time) return _id < s._id;\n return _time < s._time;\n }\n bool operator>(const State& s) const {\n if(_time == s._time) return _id > s._id;\n return _time > s._time;\n }\n};\n\nint main(){\n int num_of_guards;\n int simulation_duration;\n while(~scanf(\"%d %d\",&num_of_guards,&simulation_duration)){\n if(num_of_guards == 0 && simulation_duration == 0) break;\n\n vector<int> time_table[101];\n for(int guard_i = 0; guard_i < num_of_guards; guard_i++){\n int consuming_duration;\n int charging_duration;\n while(~scanf(\"%d\",&consuming_duration)){\n if(consuming_duration == 0) break;\n scanf(\"%d\",&charging_duration);\n time_table[guard_i].push_back(consuming_duration);\n time_table[guard_i].push_back(charging_duration);\n }\n }\n \n int for_queue[101];\n int next_process[101];\n bool is_inque[101];\n memset(next_process,0,sizeof(next_process));\n memset(for_queue,0,sizeof(for_queue));\n memset(is_inque,false,sizeof(is_inque));\n\n priority_queue<State,vector<State>,greater<State> > que;\n int res = 0;\n for(int time = 0; time < simulation_duration;time++){\n char action[101];\n memset(action,'-',sizeof(action));\n for(int guard_i = 0; guard_i < num_of_guards; guard_i++){\n if(next_process[guard_i] % 2 == 0){ // to consume\n if(is_inque[guard_i]){\n continue;\n }\n for_queue[guard_i] = time_table[guard_i][next_process[guard_i] % time_table[guard_i].size()] - 1;\n next_process[guard_i]++;\n action[guard_i] = '*';\n }\n else{ //to charge\n if(for_queue[guard_i] > 0){\n action[guard_i] = '*';\n for_queue[guard_i]--;\n continue;\n }\n\n que.push(State(guard_i,time,time_table[guard_i][next_process[guard_i] % time_table[guard_i].size()]));\n next_process[guard_i]++;\n is_inque[guard_i] = true;\n }\n }\n if(!que.empty()){\n State s = que.top();\n que.pop();\n action[s._id] = '.';\n if(s._occupy - 1 > 0){\n que.push(State(s._id,s._time,s._occupy-1));\n }\n else{\n is_inque[s._id] = false;\n }\n }\n\n res += count(action,action+num_of_guards,'-');\n\n // for debug\n // printf(\"time:%d\\n\",time);\n // for(int guard_i = 0; guard_i < num_of_guards; guard_i++){\n // printf(\"%c\\n\",action[guard_i]);\n // }\n // printf(\"\\n\");\n }\n\n printf(\"%d\\n\",res);\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 1228, "score_of_the_acc": -0.2339, "final_rank": 10 }, { "submission_id": "aoj_1219_1078664", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n\n#include <iostream>\n#include <cstdio>\n#include <sstream>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <queue>\n#include <stack>\n#include <limits>\n#include <map>\n#include <string>\n#include <cstring>\n#include <set>\n#include <deque>\n#include <bitset>\n#include <list>\n#include <cctype>\n#include <utility>\n#include <assert.h>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair <int,int> P;\ntypedef pair <int,P> PP;\n \nstatic const double EPS = 1e-8;\n\nclass State {\npublic:\n int _id;\n int _time;\n int _occupy;\n State(int id,int time,int occupy) : _id(id),_time(time), _occupy(occupy) {}\n bool operator<(const State& s) const {\n if(_time == s._time) return _id < s._id;\n return _time < s._time;\n }\n bool operator>(const State& s) const {\n if(_time == s._time) return _id > s._id;\n return _time > s._time;\n }\n};\n\nint main(){\n int num_of_guards;\n int simulation_duration;\n while(~scanf(\"%d %d\",&num_of_guards,&simulation_duration)){\n if(num_of_guards == 0 && simulation_duration == 0) break;\n\n vector<int> time_table[101];\n for(int guard_i = 0; guard_i < num_of_guards; guard_i++){\n int comsuming_duration;\n int charging_duration;\n while(~scanf(\"%d\",&comsuming_duration)){\n if(comsuming_duration == 0) break;\n scanf(\"%d\",&charging_duration);\n time_table[guard_i].push_back(comsuming_duration);\n time_table[guard_i].push_back(charging_duration);\n }\n }\n \n int for_queue[101];\n int next_process[101];\n bool is_inque[101];\n memset(next_process,0,sizeof(next_process));\n memset(for_queue,0,sizeof(for_queue));\n memset(is_inque,false,sizeof(is_inque));\n\n priority_queue<State,vector<State>,greater<State> > que;\n int res = 0;\n for(int time = 0; time < simulation_duration;time++){\n char action[101];\n memset(action,'-',sizeof(action));\n for(int guard_i = 0; guard_i < num_of_guards; guard_i++){\n if(next_process[guard_i] % 2 == 0){ // to consume\n if(is_inque[guard_i]){\n continue;\n }\n for_queue[guard_i] = time_table[guard_i][next_process[guard_i] % time_table[guard_i].size()] - 1;\n next_process[guard_i]++;\n action[guard_i] = '*';\n }\n else{ //to charge\n if(for_queue[guard_i] > 0){\n action[guard_i] = '*';\n for_queue[guard_i]--;\n continue;\n }\n\n que.push(State(guard_i,time,time_table[guard_i][next_process[guard_i] % time_table[guard_i].size()]));\n next_process[guard_i]++;\n is_inque[guard_i] = true;\n }\n }\n if(!que.empty()){\n State s = que.top();\n que.pop();\n action[s._id] = '.';\n if(s._occupy - 1 > 0){\n que.push(State(s._id,s._time,s._occupy-1));\n }\n else{\n is_inque[s._id] = false;\n }\n }\n\n res += count(action,action+num_of_guards,'-');\n\n // for debug\n // printf(\"time:%d\\n\",time);\n // for(int guard_i = 0; guard_i < num_of_guards; guard_i++){\n // printf(\"%c\\n\",action[guard_i]);\n // }\n // printf(\"\\n\");\n }\n\n printf(\"%d\\n\",res);\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 1232, "score_of_the_acc": -0.2348, "final_rank": 11 }, { "submission_id": "aoj_1219_1030907", "code_snippet": "#include<iostream>\n#include<vector>\n#include<queue>\n\nusing namespace std;\n\nint main(){\n for(int g,d;cin>>g>>d,g|d;){\n vector<char> t[100];\n for(int i=0;i<g;i++){\n bool on=true;\n for(int ti;cin>>ti,ti;){\n\tvector<char> v(ti,on);\n\tt[i].insert(end(t[i]),begin(v),end(v));\n\ton=!on;\n }\n }\n bool inque[100]={};\n queue<int> que;\n int a=0;\n int x[100]={};\n for(int i=0;i<d;i++){\n a+=max<int>(0,que.size()-1);\n for(int j=0;j<g;j++){\n\tif(!inque[j]){\n\t x[j]=(x[j]+1)%t[j].size();\n\t}\n }\n if(!que.empty()){\n\tint id=que.front();\n\tx[id]=(x[id]+1)%t[id].size();\n\tif(t[id][x[id]]){\n\t que.pop();\n\t inque[id]=false;\n\t}\n }\n for(int j=0;j<g;j++){\n\tif(!inque[j]&&!t[j][x[j]]){\n\t que.push(j);\n\t inque[j]=true;\n\t}\n }\n }\n cout<<a<<endl;\n }\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 2572, "score_of_the_acc": -1.0939, "final_rank": 19 }, { "submission_id": "aoj_1219_991398", "code_snippet": "#include<bits/stdc++.h>\n\n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n\nusing namespace std;\n\ntypedef pair<int,int> ii;\n\nstruct Data{\n int id,stamp;\n bool operator < ( const Data& data ) const {\n if( stamp != data.stamp ) return stamp > data.stamp;\n return id > data.id;\n }\n};\n\nvector<ii> cycle[110];\nint n,m,run_time[110],indices[110],charger,charge_id;\nbool inQueue[110];\n\nint simulate(){\n\n rep(i,n) run_time[i] = cycle[i][0].first, indices[i] = 0, inQueue[i] = false;\n charger = 0, charge_id = -1;\n priority_queue<Data> Q;\n int ret = 0;\n rep(_,m){\n\n rep(i,n) {\n if( run_time[i] <= 0 && !inQueue[i] ) {\n Q.push((Data){i,_});\n inQueue[i] = true;\n }\n run_time[i]--;\n }\n\n if( charger == 0 && !Q.empty() ) {\n charge_id = Q.top().id; Q.pop();\n charger = cycle[charge_id][indices[charge_id]].second;\n } \n\n if( charger ) {\n --charger;\n if( charger <= 0 ) {\n inQueue[charge_id] = false;\n ( indices[charge_id] += 1 ) %= (int)cycle[charge_id].size();\n run_time[charge_id] = cycle[charge_id][indices[charge_id]].first;\n }\n } \n\n ret += (int)Q.size();\n\n }\n\n return ret;\n}\n\nint main(){\n while( cin >> n >> m, n | m ){\n rep(i,n) {\n int a,b;\n cycle[i].clear();\n while( cin >> a , a ){\n cin >> b;\n cycle[i].push_back(ii(a,b));\n }\n }\n\n cout << simulate() << endl;\n\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1252, "score_of_the_acc": -0.1193, "final_rank": 3 }, { "submission_id": "aoj_1219_991396", "code_snippet": "#include<bits/stdc++.h>\n\n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n\nusing namespace std;\n\ntypedef pair<int,int> ii;\n\nstruct Data{\n int id,stamp;\n bool operator < ( const Data& data ) const {\n if( stamp != data.stamp ) return stamp > data.stamp;\n return id > data.id;\n }\n};\n\nvector<ii> cycle[110];\nint n,m,run_time[110],indices[110],charger,charge_id;\nbool inQueue[110];\n\n//char debug[110][1000000];\n\nint simulate(){\n\n //rep(i,110) rep(j,1000000) debug[i][j] = '?';\n\n rep(i,n) run_time[i] = cycle[i][0].first, indices[i] = 0, inQueue[i] = false;\n charger = 0, charge_id = -1;\n priority_queue<Data> Q;\n int ret = 0;\n rep(_,m){\n\n rep(i,n) {\n if( run_time[i] <= 0 && !inQueue[i] ) {\n Q.push((Data){i,_});\n inQueue[i] = true;\n }\n run_time[i]--;\n }\n\n if( charger == 0 && !Q.empty() ) {\n charge_id = Q.top().id; Q.pop();\n charger = cycle[charge_id][indices[charge_id]].second;\n } \n\n if( charger ) {\n --charger;\n if( charger <= 0 ) {\n inQueue[charge_id] = false;\n ( indices[charge_id] += 1 ) %= (int)cycle[charge_id].size();\n run_time[charge_id] = cycle[charge_id][indices[charge_id]].first;\n charge_id = -1;\n }\n } \n\n /*\n rep(i,n) if( inQueue[i] ) {\n debug[i][_] = '-';\n if( i == charge_id ) debug[i][_] = '.';\n } else debug[i][_] = '*';\n */\n\n ret += (int)Q.size();\n\n }\n /*\n rep(i,n){\n rep(j,m){\n cout << debug[i][j];\n }\n cout << endl;\n }\n */\n\n return ret;\n}\n\nint main(){\n while( cin >> n >> m, n | m ){\n rep(i,n) {\n int a,b;\n cycle[i].clear();\n while( cin >> a , a ){\n cin >> b;\n cycle[i].push_back(ii(a,b));\n }\n }\n\n cout << simulate() << endl;\n\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1252, "score_of_the_acc": -0.1193, "final_rank": 3 }, { "submission_id": "aoj_1219_902277", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <sstream>\n#include <cstring>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n#include <numeric>\n#include <cctype>\n#include <tuple>\n\n#ifdef _MSC_VER\n#include <agents.h>\n#endif\n\n#define FOR(i, a, b) for(int i = (a); i < (int)(b); ++i)\n#define rep(i, n) FOR(i, 0, n)\n#define ALL(v) v.begin(), v.end()\n#define REV(v) v.rbegin(), v.rend()\n#define MEMSET(v, s) memset(v, s, sizeof(v))\n#define X first\n#define Y second\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> P;\n\nint sch[110][10100];\nint inq[110];\n\nint main(){\n\tint n, t;\n\twhile (cin >> n >> t, n | t){\n\t\tMEMSET(sch, 0);\n\t\tvector<int> cur(n), len(n);\n\t\trep(i, n){\n\t\t\tint x;\n\t\t\tint y = 0;\n\t\t\twhile (cin >> x, x){\n\t\t\t\tfor (int j = len[i]; j < len[i] + x; ++j){\n\t\t\t\t\tsch[i][j] = y;\n\t\t\t\t}\n\t\t\t\tlen[i] += x;\n\t\t\t\ty ^= 1;\n\t\t\t}\n\t\t}\n\t\t//rep(i, n){\n\t\t//\trep(j, t){\n\t\t//\t\tcout << (sch[i][j%len[i]] ? \".\" : \"*\");\n\t\t//\t}\n\t\t//\tcout << endl;\n\t\t//}\n\n\t\tqueue<int> q;\n\t\tMEMSET(inq, 0);\n\t\tint ans = 0;\n\t\trep(i, t){\n\t\t\trep(j, n){\n\t\t\t\tif (inq[j]) continue;\n\t\t\t\tif (sch[j][cur[j] % len[j]]){\n\t\t\t\t\tq.push(j);\n\t\t\t\t\tinq[j] = 1;\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\t++cur[j];\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (q.empty()) continue;\n\t\t\tans += q.size() - 1;\n\t\t\tint use = q.front();\n\t\t\t++cur[use];\n\t\t\tif (!sch[use][cur[use] % len[use]]){\n\t\t\t\tq.pop();\n\t\t\t\tinq[use] = 0;\n\t\t\t}\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 5556, "score_of_the_acc": -1.36, "final_rank": 20 }, { "submission_id": "aoj_1219_846037", "code_snippet": "#include <iostream>\n#include <complex>\n#include <sstream>\n#include <string>\n#include <algorithm>\n#include <deque>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <vector>\n#include <set>\n#include <limits>\n#include <cstdio>\n#include <cctype>\n#include <cmath>\n#include <cstdlib>\n#include <ctime>\nusing namespace std;\n#define REP(i, j) for(int i = 0; i < j; ++i)\n#define FOR(i, j, k) for(int i = j; i < k; ++i)\n#define P pair<int, int>\n\nclass C{\n public:\n int now, cnt, num, stay_num;\n vector<int> v;\n C(){ now = 0; cnt = 0; stay_num = 0; }\n};\n\nint main() {\n int n, time;\n while(cin >>n >>time && n){\n vector<C> v(n);\n REP(i, n){\n int tmp;\n while(cin >>tmp && tmp) v[i].v.push_back(tmp);\n v[i].num = i;\n }\n\n int ans = 0, next = 0, last = 0;\n REP(t, time){\n bool stay_end = false;\n REP(i, n){\n //稼働中\n if(v[i].now % 2 == 0){\n v[i].cnt += 1;\n if(v[i].cnt >= v[i].v[ v[i].now ]){\n v[i].cnt = 0;\n v[i].now = (v[i].now + 1 >= v[i].v.size() ? 0 : v[i].now + 1);\n v[i].stay_num = last;\n last += 1;\n }\n }\n //待ち番号 == next\n else if(v[i].stay_num == next){\n v[i].cnt += 1;\n if(v[i].cnt >= v[i].v[ v[i].now ]){\n v[i].cnt = 0;\n v[i].now = (v[i].now + 1 >= v[i].v.size() ? 0 : v[i].now + 1);\n stay_end = true;\n }\n }\n //待ち番号 > next\n else{\n ans += 1;\n }\n }\n if(stay_end) next += 1;\n }\n cout <<ans <<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 1240, "score_of_the_acc": -0.1966, "final_rank": 8 }, { "submission_id": "aoj_1219_605262", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <set>\n#include <map>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <cassert>\n\nusing namespace std;\n\n#define FOR(i,k,n) for(int i=(k); i<(int)(n); ++i)\n#define REP(i,n) FOR(i,0,n)\n#define FORIT(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n\ntemplate<class T> void debug(T begin, T end){ for(T i = begin; i != end; ++i) cerr<<*i<<\" \"; cerr<<endl; }\ninline bool valid(int x, int y, int W, int H){ return (x >= 0 && y >= 0 && x < W && y < H); }\n\ntypedef long long ll;\nconst int INF = 100000000;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\nint dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};\nint dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};\n\nint main(){\n int N, T;\n while(cin >> N >> T && N){\n vector<int> v[100];\n REP(i, N){\n int t; \n while(cin >> t && t) v[i].push_back(t);\n }\n vector<int> cur(N);\n vector<int> rest(N);\n REP(i, N) rest[i] = v[i][0];\n int now_use = -1;\n queue<int> que;\n int ans = 0;\n REP(t, T){\n if(now_use == -1 && !que.empty()){\n now_use = que.front();\n que.pop();\n }\n ans += que.size();\n REP(i, N){\n if(now_use == i || cur[i] % 2 == 0){\n rest[i]--;\n if(rest[i] == 0){\n cur[i] = (cur[i] + 1) % v[i].size();\n rest[i] = v[i][cur[i]];\n if(now_use == i) now_use = -1;\n if(cur[i] % 2 == 1){\n que.push(i);\n }\n }\n }\n }\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 1240, "score_of_the_acc": -0.1566, "final_rank": 5 }, { "submission_id": "aoj_1219_556949", "code_snippet": "#include<queue>\n#include<cstdio>\n\n#define rep(i,n) for(int i=0;i<(n);i++)\n\nusing namespace std;\n\nint main(){\n\tfor(int n,T;scanf(\"%d%d\",&n,&T),n;){\n\t\tvector<int> pttn[100];\n\t\trep(i,n){\n\t\t\twhile(1){\n\t\t\t\tint t; scanf(\"%d\",&t);\n\t\t\t\tif(t==0) break;\n\t\t\t\tpttn[i].push_back(t);\n\t\t\t}\n\t\t}\n\n\t\tint ans=0;\n\t\tint idx[100]={},cons[100]={},charge=-1;\n\t\tqueue<int> wait;\n\t\twhile(T--){\n\t\t\tif(charge==-1 && !wait.empty()){\n\t\t\t\tcharge=wait.front();\n\t\t\t\twait.pop();\n\t\t\t}\n\n\t\t\trep(i,n){\n\t\t\t\tif(idx[i]%2==0 || i==charge){\n\t\t\t\t\tcons[i]++;\n\t\t\t\t\tif(cons[i]==pttn[i][idx[i]]){ // 充電したくなる or 充電が終わる\n\t\t\t\t\t\tif(idx[i]%2==0) wait.push(i);\n\t\t\t\t\t\telse charge=-1;\n\t\t\t\t\t\tidx[i]=(idx[i]+1)%pttn[i].size();\n\t\t\t\t\t\tcons[i]=0;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse{ // 充電器が空くのを待つ\n\t\t\t\t\tans++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tprintf(\"%d\\n\",ans);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 1076, "score_of_the_acc": -0.2, "final_rank": 9 }, { "submission_id": "aoj_1219_540803", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <queue>\nusing namespace std;\n\nconst int MAXN = 101;\nconst int MAXM = 10080;\nint N, M;\nvector<int> T[MAXN];\n\nint main() {\n while(cin >> N >> M && (N|M)) {\n for(int i = 0; i < MAXN; ++i) T[i].clear();\n for(int i = 0; i < N; ++i) {\n int a;\n while(cin >> a && a) {\n\tT[i].push_back(a);\n }\n }\n queue<int> que;\n int ju_den = -1;\n int p[MAXN];\n int t[MAXN];\n fill(p,p+MAXN, 0);\n for(int j = 0; j < N; ++j) t[j] = T[j][0];\n int ans = 0;\n for(int i = 0; i < M; ++i) {\n for(int j = 0; j < N; ++j) {\n\tif(p[j]%2 == 0) {\n\t --t[j];\n\t if(t[j] == 0) {\n\t p[j] = (p[j]+1)%T[j].size();\n\t t[j] = T[j][p[j]];\n\t que.push(j);\n\t }\n\t} else {\n\t if(ju_den == j) {\n\t --t[j];\n\t if(t[j] == 0) {\n\t p[j] = (p[j]+1)%T[j].size();\n\t t[j] = T[j][p[j]];\n\t ju_den = -1;\n\t }\n\t } else {\n\t ++ans;\n\t }\n\t}\n }\n if(que.size() && ju_den == -1) {\n\tju_den = que.front();\n\tque.pop();\n }\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 1248, "score_of_the_acc": -0.1584, "final_rank": 6 }, { "submission_id": "aoj_1219_539025", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <queue>\n \nusing namespace std;\n\nconst int N = 100;\nint n, m;\nvector<int> data[N];\n \nint main(){\n while(cin >> n >> m && (n|m)){\n for(int i=0;i<n;i++){\n data[i].clear();\n while(1){\n int in;\n cin >> in;\n if(in == 0) break;\n data[i].push_back(in);\n }\n }\n int ans = 0, rem[N], idx[N];\n priority_queue<pair<int, int> > q;\n bool flag[N];\n for(int i=0;i<n;i++) rem[i] = data[i][0];\n fill(idx, idx+n, 0);\n fill(flag, flag+n, false);\n for(int k=0;k<m;k++){\n pair<int, int> tmp = make_pair(1, 1);\n if(q.size()){ tmp = q.top(); q.pop(); }\n for(int i=0;i<n;i++){\n if(!flag[i]){\n rem[i]--;\n if(rem[i] == 0){\n idx[i] = (idx[i] + 1) % data[i].size();\n rem[i] = data[i][idx[i]];\n flag[i] = true;\n q.push(make_pair(-k, -i));\n }\n }else{\n if(-tmp.second == i){\n rem[i]--;\n if(rem[i] == 0){\n idx[i] = (idx[i] + 1) % data[i].size();\n rem[i] = data[i][idx[i]];\n flag[i] = false;\n }else q.push(tmp);\n }else ans++;\n }\n }\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 1248, "score_of_the_acc": -0.1584, "final_rank": 6 } ]
aoj_1225_cpp
Problem B: e-Market The city of Hakodate recently established a commodity exchange market. To participate in the market, each dealer transmits through the Internet an order consisting of his or her name, the type of the order (buy or sell), the name of the commodity, and the quoted price. In this market a deal can be made only if the price of a sell order is lower than or equal to the price of a buy order. The price of the deal is the mean of the prices of the buy and sell orders, where the mean price is rounded downward to the nearest integer. To exclude dishonest deals, no deal is made between a pair of sell and buy orders from the same dealer. The system of the market maintains the list of orders for which a deal has not been made and processes a new order in the following manner. For a new sell order, a deal is made with the buy order with the highest price in the list satisfying the conditions. If there is more than one buy order with the same price, the deal is made with the earliest of them. For a new buy order, a deal is made with the sell order with the lowest price in the list satisfying the conditions. If there is more than one sell order with the same price, the deal is made with the earliest of them. The market opens at 7:00 and closes at 22:00 everyday. When the market closes, all the remaining orders are cancelled. To keep complete record of the market, the system of the market saves all the orders it received everyday. The manager of the market asked the system administrator to make a program which reports the activity of the market. The report must contain two kinds of information. For each commodity the report must contain informationon the lowest, the average and the highest prices of successful deals. For each dealer, the report must contain information on the amounts the dealer paid and received for commodities. Input The input contains several data sets. Each data set represents the record of the market on one day. The first line of each data set contains an integer n ( n < 1000) which is the number of orders in the record. Each line of the record describes an order, consisting of the name of the dealer, the type of the order, the name of the commodity, and the quoted price. They are separated by a single space character. The name of a dealer consists of capital alphabetical letters and is less than 10 characters in length. The type of an order is indicated by a string, " BUY " or " SELL ". The name of a commodity is a single capital letter. The quoted price is a positive integer less than 1000. The orders in a record are arranged according to time when they were received and the first line of the record corresponds to the oldest order. The end of the input is indicated by a line containing a zero. Output The output for each data set consists of two parts separated by a line containing two hyphen (` - ') characters. The first part is output for commodities. For each commodity, your program should output the name of the comm ...(truncated)
[ { "submission_id": "aoj_1225_1083098", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n\n#include <iostream>\n#include <cstdio>\n#include <sstream>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <queue>\n#include <stack>\n#include <limits>\n#include <map>\n#include <string>\n#include <cstring>\n#include <set>\n#include <deque>\n#include <bitset>\n#include <list>\n#include <cctype>\n#include <utility>\n#include <assert.h>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair <int,int> P;\ntypedef pair <int,P> PP;\n \nstatic const double EPS = 1e-8;\n\nclass Deal {\npublic:\n string _dealer_name;\n string _type;\n string _commodity_name;\n int _price;\n int _id;\n Deal(string dealer_name,string type,string commodity_name,int price,int id) \n : _dealer_name(dealer_name), _type(type), _commodity_name(commodity_name), _price(price), _id(id) {}\n};\n\nclass DealerResult {\npublic:\n int _paid;\n int _received;\n DealerResult() : _paid(0),_received(0) {}\n};\n\nclass CommodityResult {\npublic:\n int _lowest;\n int _mean;\n int _highest;\n vector<int> _purchase_history;\n void init(){\n if(_purchase_history.size() > 0){\n sort(_purchase_history.begin(),_purchase_history.end());\n _highest = *(_purchase_history.end()-1);\n _lowest = *(_purchase_history.begin());\n \n int sum = 0;\n for(int i=0;i<_purchase_history.size();i++){\n sum += _purchase_history[i];\n }\n _mean = sum / _purchase_history.size();\n }\n }\n CommodityResult() : _lowest(0), _mean(0), _highest(0) {}\n};\n\nint main(){\n int total_dealers;\n while(~scanf(\"%d\",&total_dealers)){\n if(total_dealers == 0) break;\n\n vector<Deal> deals;\n for(int dealer_i = 0; dealer_i < total_dealers; dealer_i++){\n string dealer_name,type,commodity_name;\n int price;\n cin >> dealer_name >> type >> commodity_name >> price;\n deals.push_back(Deal(dealer_name,type,commodity_name,price,dealer_i));\n }\n\n bool used[1001];\n memset(used,false,sizeof(used));\n\n map<string,CommodityResult> commodity_result;\n map<string,DealerResult> dealer_result;\n\n for(int dealer_i = 0; dealer_i < total_dealers; dealer_i++){\n dealer_result[deals[dealer_i]._dealer_name] = DealerResult();\n }\n\n for(int dealer_i = 0; dealer_i < total_dealers; dealer_i++){\n if(used[dealer_i]) continue;\n int current_sell_price = INF; // lowest\n int current_buy_price = -INF; // highest\n int target_id = -1;\n\n for(int dealer_j = 0; dealer_j < dealer_i; dealer_j++){\n if(used[dealer_j]) continue;\n if(deals[dealer_i]._type == deals[dealer_j]._type) continue;\n if(deals[dealer_i]._dealer_name == deals[dealer_j]._dealer_name) continue;\n if(deals[dealer_i]._commodity_name != deals[dealer_j]._commodity_name) continue;\n\n if(deals[dealer_i]._type == \"BUY\"){\n if(deals[dealer_j]._price <= deals[dealer_i]._price){\n if(current_sell_price > deals[dealer_j]._price){\n current_sell_price = deals[dealer_j]._price;\n target_id = dealer_j;\n }\n }\n }\n else if(deals[dealer_i]._type == \"SELL\"){\n if(deals[dealer_j]._price >= deals[dealer_i]._price){\n if(current_buy_price < deals[dealer_j]._price){\n current_buy_price = deals[dealer_j]._price;\n target_id = dealer_j;\n }\n }\n }\n }\n\n if(target_id != -1){\n if(deals[dealer_i]._type == \"BUY\"){\n dealer_result[deals[dealer_i]._dealer_name]._paid += (current_sell_price + deals[dealer_i]._price) / 2;\n dealer_result[deals[target_id]._dealer_name]._received += (current_sell_price + deals[dealer_i]._price) / 2;\n commodity_result[deals[dealer_i]._commodity_name]._purchase_history\n .push_back((current_sell_price + deals[dealer_i]._price) / 2);\n }\n\n if(deals[dealer_i]._type == \"SELL\"){\n dealer_result[deals[dealer_i]._dealer_name]._received += (current_buy_price + deals[dealer_i]._price) / 2;\n dealer_result[deals[target_id]._dealer_name]._paid += (current_buy_price + deals[dealer_i]._price) / 2;\n commodity_result[deals[dealer_i]._commodity_name]._purchase_history\n .push_back((current_buy_price + deals[dealer_i]._price) / 2);\n }\n \n used[dealer_i] = true;\n used[target_id] = true;\n }\n }\n\n for(map<string,CommodityResult>::iterator it = commodity_result.begin();\n it != commodity_result.end();\n it++){\n it->second.init();\n printf(\"%s %d %d %d\\n\",it->first.c_str(),it->second._lowest,it->second._mean,it->second._highest);\n }\n\n printf(\"--\\n\");\n for(map<string,DealerResult>::iterator it = dealer_result.begin();\n it != dealer_result.end();\n it++){\n\n printf(\"%s %d %d\\n\",it->first.c_str(),it->second._paid,it->second._received);\n }\n printf(\"----------\\n\");\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1496, "score_of_the_acc": -1, "final_rank": 6 }, { "submission_id": "aoj_1225_997494", "code_snippet": "//#include <bits/stdc++.h>\n//#define _ ios_base::sync_with_stdio(0);cin.tie(0);\n#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <cmath>\n#include <cstdlib>\n#include <queue>\n#include <vector>\n#include <algorithm>\n#include <cctype>\n#include <fstream>\n#include <map>\n#include <list>\n#include <set>\n#include <string>\n#include <stack>\n#include <bitset>\n\n#define sz 50005\n#define pb(a) push_back(a)\n#define pp pop_back()\n#define ll long long\n#define fread freopen(\"input.txt\",\"r\",stdin)\n#define fwrite freopen(\"output.txt\",\"w\",stdout)\n#define inf (1e9)\n#define chng(a,b) a^=b^=a^=b;\n#define clr(abc,z) memset(abc,z,sizeof(abc))\n#define PI acos(-1)\n#define fr(i,a,b) for(i=a;i<=b;i++)\n#define print1(a) cout<<a<<endl\n#define print2(a,b) cout<<a<<\" \"<<b<<endl\n#define print3(a,b,c) cout<<a<<\" \"<<b<<\" \"<<c<<endl\n#define mod 1000000007\nusing namespace std;\n\nstruct person\n{\n char name[15];\n int buy, sell;\n person(char line[])\n {\n strcpy(name, line);\n buy=sell=0;\n }\n};\n\nstruct commodity\n{\n char name[5];\n int n, sum, mn, mx;\n commodity(char line[])\n {\n sum = n = 0;\n mn = inf;\n mx = -inf;\n strcpy(name,line );\n }\n};\n\nstruct product\n{\n char name[15];\n char prod[5];\n int price;\n int cnt;\n\n product(char line1[], char line2[], int p, int c)\n {\n strcpy(name, line1);\n strcpy(prod, line2);\n price = p;\n cnt = c;\n }\n};\n\n\nvector<person>per;\nvector<commodity>thing;\nvector<product>buys, sells;\n\nbool compbuy(const product &a, const product &b)\n{\n if(a.price==b.price) return a.cnt<b.cnt;\n return a.price>b.price;\n}\nbool compsell(const product &a, const product &b)\n{\n if(a.price==b.price) return a.cnt<b.cnt;\n return a.price<b.price;\n}\n\nbool printCompThing(const commodity &a, const commodity &b)\n{\n return strcmp(a.name,b.name)<0;\n}\n\nbool printCompPerson(const person &a, const person &b)\n{\n return strcmp(a.name,b.name)<0;\n}\n\nvoid printall()\n{\n sort(thing.begin(), thing.end(), printCompThing);\n for (int i = 0; i<thing.size(); i++)\n printf(\"%s %d %d %d\\n\", thing[i].name, thing[i].mn, thing[i].sum/thing[i].n, thing[i].mx);\n puts(\"--\");\n\n sort(per.begin(), per.end(), printCompPerson);\n for (int i = 0; i<per.size(); i++)\n printf(\"%s %d %d\\n\", per[i].name, per[i].buy, per[i].sell);\n puts(\"----------\");\n\n return;\n}\n\nvoid printBuyList()\n{\n cout<<\"Buy ---------------\"<<endl;\n for (int i = 0; i<buys.size(); i++)\n cout<<\"N: \"<<buys[i].name<<\" Prod: \"<<buys[i].prod<<\" Price: \"<<buys[i].price<<\" cnt: \"<<buys[i].cnt<<endl;\n cout<<\"-------------------\"<<endl;\n return;\n}\n\nvoid printSellList()\n{\n cout<<\"Sell---------------\"<<endl;\n for (int i = 0; i<sells.size(); i++)\n cout<<\"N: \"<<sells[i].name<<\" Prod: \"<<sells[i].prod<<\" Price: \"<<sells[i].price<<\" cnt: \"<<sells[i].cnt<<endl;\n cout<<\"-------------------\"<<endl;\n return;\n}\n\n\n\n\nint main()\n{\n#ifdef ENAM\n fread;\n fwrite;\n#endif // ENAM\n int t, n, m, cas=1, price, x,y, dealprice;\n char name[20], type[10], com[5];\n\n\n while(~scanf(\"%d\", &n)&&n)\n {\n per.clear();\n thing.clear();\n buys.clear();\n sells.clear();\n\n for (int i = 0; i<n; i++)\n {\n// printBuyList();\n// printSellList();\n scanf(\" %s %s %s %d\", name, type, com, &price);\n int j;\n for (j = 0; j<per.size(); j++)\n if(!strcmp(per[j].name, name)) break;\n\n if(j==per.size()) per.pb(person(name));\n\n// printf(\"::>> %s %s %s %d\\n\", name, type, com, price);\n\n if(!strcmp(type, \"SELL\"))\n {\n if(!buys.empty())\n {\n sort(buys.begin(), buys.end(), compbuy);\n for (j = 0; j<buys.size(); j++)\n {\n if(strcmp(buys[j].name, name) && !strcmp(com,buys[j].prod) && price<= buys[j].price)\n {\n dealprice = (price+buys[j].price)/2;\n\n int ii;\n //selling person update\n for (ii = 0; ii<per.size(); ii++ )\n if(!strcmp(per[ii].name, name)) break;\n per[ii].sell+=dealprice;\n\n //buying person update\n for (ii = 0; ii<per.size(); ii++ )\n if(!strcmp(per[ii].name, buys[j].name)) break;\n per[ii].buy+=dealprice;\n\n //commodity update\n for (ii = 0; ii<thing.size(); ii++ )\n if(!strcmp(thing[ii].name, com)) break;\n\n if(ii==thing.size()) thing.pb(commodity(com));\n\n thing[ii].n++;\n thing[ii].sum+=dealprice;\n thing[ii].mn = min(thing[ii].mn, dealprice);\n thing[ii].mx = max(thing[ii].mx, dealprice);\n\n break;\n }\n }\n\n if(j==buys.size()) sells.pb(product(name,com, price,i));\n else buys.erase(buys.begin()+j);\n }\n else sells.pb(product(name,com, price,i));\n }\n else\n {\n// printf(\":->%s %s %s %d\\n\", name, type, com, price);\n if(!sells.empty())\n {\n sort(sells.begin(), sells.end(), compsell);\n int j;\n for (j = 0; j<sells.size(); j++)\n {\n if(strcmp(sells[j].name, name) && !strcmp(com,sells[j].prod) && sells[j].price <= price)\n {\n dealprice = (price+sells[j].price)/2;\n\n int ii;\n //buying person update\n for (ii = 0; ii<per.size(); ii++ )\n if(!strcmp(per[ii].name, name)) break;\n per[ii].buy+=dealprice;\n\n //selling person update\n for (ii = 0; ii<per.size(); ii++ )\n if(!strcmp(per[ii].name, sells[j].name)) break;\n per[ii].sell+=dealprice;\n\n //commodity update\n for (ii = 0; ii<thing.size(); ii++ )\n if(!strcmp(thing[ii].name, com)) break;\n\n if(ii==thing.size()) thing.pb(commodity(com));\n\n thing[ii].n++;\n thing[ii].sum+=dealprice;\n thing[ii].mn = min(thing[ii].mn, dealprice);\n thing[ii].mx = max(thing[ii].mx, dealprice);\n\n break;\n }\n }\n\n if(j==sells.size()) buys.pb(product(name,com, price,i));\n else sells.erase(sells.begin()+j);\n }\n else buys.pb(product(name,com, price,i));\n }\n }\n printall();\n }\n return 0;\n}\n\n/*\n3\nPERLIS SELL A 300\nMILKES BUY A 200\nHAMMING SELL A 100\n4\nBACKUS SELL A 10\nFLOYD BUY A 20\nIVERSON SELL B 30\nBACKUS BUY B 40\n7\nMILKINSON SELL A 500\nMCCARTHY BUY C 300\nMILKINSON SELL C 200\nDIJKSTRA SELL B 100\nBACHMAN BUY A 400\nDIJKSTRA BUY A 600\nMILKINSON SELL A 300\n2\nABCD SELL X 10\nABC BUY X 15\n2\nA SELL M 100\nA BUY M 100\n0\n*/", "accuracy": 1, "time_ms": 10, "memory_kb": 1256, "score_of_the_acc": -0.8396, "final_rank": 3 }, { "submission_id": "aoj_1225_955139", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <vector>\n#include <tuple>\n#include <map>\n\nusing namespace std;\n\nint main(){\n\tint n;\n\twhile (cin >> n, n){\n\t\tvector<tuple<string, char, string, int>> v(n);\n\t\tvector<int> used(n);\n\n\t\tmap<string, pair<int, int>> comm_minmax;\n\t\tmap<string, pair<int, int>> comm_sumcnt;\n\t\tmap<string, pair<int, int>> dealer;\n\n\t\tfor (int i = 0; i < n; ++i){\n\t\t\tstring a, b, c;\n\t\t\tint x;\n\t\t\tcin >> a >> b >> c >> x;\n\t\t\tv[i] = make_tuple(a, b[0], c, x);\n\t\t\tdealer[a];\n\t\t\tint idx = -1, opt = x;\n\t\t\tbool buy = b[0] == 'B';\n\t\t\tfor (int j = 0; j < i; ++j){\n\t\t\t\tif (used[j]) continue;\n\t\t\t\tif (a != get<0>(v[j]) && b[0] != get<1>(v[j]) && c == get<2>(v[j])){\n\t\t\t\t\tint y = get<3>(v[j]);\n\t\t\t\t\tif (buy && y <= opt){\n\t\t\t\t\t\topt = y - 1, idx = j;\n\t\t\t\t\t}\n\t\t\t\t\tif (!buy && y >= opt){\n\t\t\t\t\t\topt = y + 1, idx = j;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (idx < 0) continue;\n\t\t\tused[i] = used[idx] = 1;\n\t\t\tstring buyer = a, seller = get<0>(v[idx]);\n\t\t\tif (!buy) swap(buyer, seller);\n\n\t\t\tif (buyer == seller) continue;\n\t\t\tauto &c1 = comm_minmax[c], &c2 = comm_sumcnt[c], &db = dealer[buyer], &ds = dealer[seller];\n\t\t\tint val = (x + get<3>(v[idx])) / 2;\n\t\t\tc1.first = c1.first ? min(c1.first, val) : val, c1.second = c1.second ? max(c1.second, val) : val;\n\t\t\tc2.first += val, ++c2.second;\n\t\t\tdb.first += val, ds.second += val;\n\t\t}\n\n\t\tfor (auto &c : comm_minmax){\n\t\t\tint mean = comm_sumcnt[c.first].first / comm_sumcnt[c.first].second;\n\t\t\tcout << c.first << ' ' << c.second.first << ' ' << mean << ' ' << c.second.second << '\\n';\n\t\t}\n\t\tcout << \"--\\n\";\n\t\tfor (auto &d : dealer){\n\t\t\tcout << d.first << ' ' << d.second.first << ' ' << d.second.second << '\\n';\n\t\t}\n\t\tcout << \"----------\\n\";\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1356, "score_of_the_acc": -0.9064, "final_rank": 4 }, { "submission_id": "aoj_1225_812171", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <map>\nusing namespace std;\n\n#define INF (1<<29)\n\ntypedef pair<int, int> P;\ntypedef pair<P, P> PP;\n\nstruct Order{\n string pname, dname;\n string order;\n int price;\n Order(string pname, string dname, string order, int price) :\n pname(pname), dname(dname), order(order), price(price){}\n};\n \n\nint main(){\n int n;\n while(cin >> n, n){\n bool used[1010];\n memset(used, false, sizeof(used));\n vector<Order> market;\n map<string, P> person;\n map<string, PP> item;\n \n string pname, dname, order;\n int price;\n for(int i = 0 ; i < n ; i++){\n cin >> pname >> order >> dname >> price;\n market.push_back(Order(pname, dname, order, price));\n if(person.find(pname) == person.end()) person[pname] = P(0, 0);\n if(order == \"SELL\"){\n\tint number = -1;\n\tint p = -1;\n\tfor(int j = 0 ; j < (int)market.size() ; j++){\n\t if(market[j].order == \"BUY\" && market[j].pname != pname &&\n\t market[j].dname == dname && market[j].price >= price &&\n\t !used[j]){\n\t if(p < market[j].price){\n\t number = j;\n\t p = market[j].price;\n\t }\n\t }\n\t}\n\tif(number == -1) continue;\n\tint deal = (price + p) / 2;\n\tperson[pname].second += deal;\n\tperson[market[number].pname].first += deal;\n\titem[dname].first.first += deal;\n\titem[dname].first.second++;\n\titem[dname].second.first = max(item[dname].second.first, deal);\n\tif(item[dname].first.second == 1) item[dname].second.second = deal;\n\telse item[dname].second.second = min(item[dname].second.second, deal);\n\tused[i] = used[number] = true;\n }\n\n if(order == \"BUY\"){\n\tint number = -1;\n\tint p = INF;\n\tfor(int j = 0 ; j < (int)market.size() ; j++){\n\t if(market[j].order == \"SELL\" && market[j].pname != pname &&\n\t market[j].dname == dname && market[j].price <= price &&\n\t !used[j]){\n\t if(p > market[j].price){\n\t number = j;\n\t p = market[j].price;\n\t }\n\t }\n\t}\n\tif(number == -1) continue;\n\tint deal = (price + p) / 2;\n\tperson[pname].first += deal;\n\tperson[market[number].pname].second += deal;\t \n\tused[i] = used[number] = true;\n\titem[dname].first.first += deal;\n\titem[dname].first.second++;\n\titem[dname].second.first = max(item[dname].second.first, deal);\n\tif(item[dname].first.second == 1) item[dname].second.second = deal;\n\telse item[dname].second.second = min(item[dname].second.second, deal); \n }\n }\n \n for(map<string, PP>::iterator it = item.begin() ; it != item.end() ; it++){\n cout << it->first << ' '\n\t << it->second.second.second << ' '\n\t << it->second.first.first / it->second.first.second << ' '\n\t << it->second.second.first << endl;\t \n\n }\n cout << \"--\" << endl;\n \n for(map<string, P>::iterator it = person.begin() ; it != person.end() ; it++){\n cout << it->first << ' '\n\t << it->second.first << ' '\n\t << it->second.second << endl;\n }\n cout << \"----------\" << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1416, "score_of_the_acc": -0.9465, "final_rank": 5 }, { "submission_id": "aoj_1225_744846", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<map>\n#include<cmath>\n#include<vector>\n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define inf (1<<29)\n#define all(n) (n).begin(),(n).end()\nusing namespace std;\ntypedef pair<int,int> ii;//first -> paid, received\nstruct P\n{\n int low,avg,hig,total,cnt;\n P(int low=inf,int avg=0,int hig=-inf):low(low),avg(avg),hig(hig){total = cnt = 0;}\n};\nstruct Merchandise\n{\n int index,price;\n string name,dealer;\n bool completed;\n Merchandise(int index=-inf,string dealer=\"x\",string name=\"x\",int price=-inf):index(index),price(price),name(name),dealer(dealer){completed = false;}\n bool operator < (const Merchandise &a)const\n {\n if(price == a.price)return index < a.index;\n return price < a.price;\n }\n};\nint n;\n\nbool cmp(const Merchandise &a,const Merchandise &b)//use this method to sort the vector Buy\n{\n if(a.price == b.price)return a.index < b.index;\n return a.price > b.price;\n}\n\nint main()\n{\n while(cin >> n,n)\n {\n map<string,ii> dealer;\n map<string,P> commodity;\n vector<Merchandise> Sell,Buy;\n rep(i,n)\n\t{\n\t string sdealer,name,order;\n\t int price;\n\t cin >> sdealer >> order >> name >> price;\n\t dealer[sdealer] = dealer[sdealer];\n\t if(order[0] == 'S')\n\t {\n\t Sell.push_back(Merchandise(i,sdealer,name,price));\n\t int index = Sell.size()-1;\n\t int bsize = Buy.size();\n\t rep(j,bsize)\n\t\t{\n\t\t if(Buy[j].completed)continue;\n\t\t if(Buy[j].dealer == sdealer)continue;\n\t\t if(Buy[j].name == name && Buy[j].price >= price)\n\t\t {\n\t\t //cout << \"Sell \" << sdealer << \" the commodity \" << name << \" to \" << Buy[j].dealer << endl;\n\t\t Buy[j].completed = true;\n\t\t Sell[index].completed = true;\n\t\t int value = (int)floor((Buy[j].price+price)/2.0);\n\t\t dealer[Buy[j].dealer].first += value;\n\t\t dealer[sdealer].second += value;\n\t\t commodity[name].low = min(commodity[name].low,value);\n\t\t commodity[name].hig = max(commodity[name].hig,value);\n\t\t commodity[name].total += value;\n\t\t commodity[name].cnt++;\n\t\t break;\n\t\t }\n\t\t}\n\t sort(all(Sell));\n\t }\n\t else\n\t {\n\t Buy.push_back(Merchandise(i,sdealer,name,price));\n\t int index = Buy.size()-1;\n\t int ssize = Sell.size();\n\t rep(j,ssize)\n\t\t{\n\t\t if(Sell[j].completed)continue;\n\t\t if(Sell[j].dealer == sdealer)continue;\n\t\t if(Sell[j].name == name && Sell[j].price <= price)\n\t\t {\n\t\t //cout << \"Buy \" << sdealer << \" the commodity \" << name << \" from \" << Sell[j].dealer << endl;\n\t\t Sell[j].completed = true;\n\t\t Buy[index].completed = true;\n\t\t int value = (int)floor((Sell[j].price+price)/2.0);\n\t\t dealer[Sell[j].dealer].second += value;\n\t\t dealer[sdealer].first += value;\n\t\t commodity[name].low = min(commodity[name].low,value);\n\t\t commodity[name].hig = max(commodity[name].hig,value);\n\t\t commodity[name].total += value;\n\t\t commodity[name].cnt++;\n\t\t break;\n\t\t }\n\t\t}\n\t sort(all(Buy),cmp);\n\t }\n\t}\n\n for(map<string,P>::iterator it = commodity.begin(); it != commodity.end(); it++)\n\t{\n\t cout << (it->first) << \" \" << (it->second.low) << \" \" << (int)floor((it->second.total)/(it->second.cnt)) << \" \" << (it->second.hig) << endl;\n\t}\n cout << \"--\" << endl;\n\n for(map<string,ii>::iterator it = dealer.begin();it != dealer.end();it++)\n\t{\n\t cout << (it->first) << \" \" << (it->second.first) << \" \" << (it->second.second) << endl; \n\t}\n cout << \"----------\" << endl;\n\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 1376, "score_of_the_acc": -1.1506, "final_rank": 7 }, { "submission_id": "aoj_1225_225825", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <map>\nusing namespace std;\n\n#define MAX (1<<24)\n#define MIN (-1)\n\nclass State\n{\npublic:\n\tstring n,t;\n\tchar c;\n\tint p,r;\n\tState(string n, string t, char c, int p, int r)\n\t\t:n(n),t(t),c(c),p(p),r(r)\n\t{}\n\n\tbool operator<(const State& s) const\n\t{\n\t\tif(t!=s.t) return t<s.t;\n\t\tif(t==\"SELL\" && p!=s.p) return p<s.p;\n\t\tif(t==\"BUY\" && p!=s.p) return p>s.p;\n\n\t\treturn r<s.r;\n\t}\n};\n\nclass Dealer\n{\npublic:\n\tstring n;\n\tint s,b;\n\tDealer(string n, int s, int b)\n\t\t:n(n),s(s),b(b)\n\t{}\n\n\tbool operator<(const Dealer& d) const\n\t{\n\t\treturn n<d.n;\n\t}\n};\n\nint main()\n{\n\tint N;\n\twhile(cin >> N, N)\n\t{\n\t\tint mi[30], ma[30], tt[30], nm[30];\n\t\tfor(int i=0; i<30; i++)\n\t\t{\n\t\t\tmi[i]=MAX;\n\t\t\tma[i]=MIN;\n\t\t\ttt[i]=0;\n\t\t\tnm[i]=0;\n\t\t}\n\n\t\tint n=0;\n\t\tmap<string, int> d;\n\t\tvector<State> st;\n\t\tvector<Dealer> dr;\n\t\tfor(int i=0; i<N; i++)\n\t\t{\n\t\t\tbool dealed=0;\n\t\t\tstring a,b;\n\t\t\tchar c;\n\t\t\tint p;\n\t\t\t\n\t\t\tcin >> a >> b >> c >> p;\n\t\t\tif(!d.count(a))\n\t\t\t{\n\t\t\t\td[a]=dr.size();\n\t\t\t\tdr.push_back(Dealer(a,0,0));\n\t\t\t}\n\n\t\t\tfor(int j=0; j<st.size(); j++)\n\t\t\t{\n\t\t\t\tif(st[j].t==b) continue;\n\t\t\t\tif(st[j].c!=c) continue;\n\n\t\t\t\tif(st[j].n==a) continue;\n\n\t\t\t\tif(b==\"SELL\")\n\t\t\t\t{\n\t\t\t\t\tif(p<=st[j].p)\n\t\t\t\t\t{\n\t\t\t\t\t\tint np=(p+st[j].p)/2;\n\t\t\t\t\t\tint z=st[j].c-'A';\n\t\t\t\t\t\tmi[z]=min(mi[z], np);\n\t\t\t\t\t\tma[z]=max(ma[z], np);\n\t\t\t\t\t\ttt[z]+=np;\n\t\t\t\t\t\tnm[z]++;\n\n\t\t\t\t\t\tdr[d[a]].s+=np;\n\t\t\t\t\t\tdr[d[st[j].n]].b+=np;\n\n\t\t\t\t\t\tdealed=true;\n\t\t\t\t\t\tst.erase(st.begin()+j);\n\t\t\t\t\t}\n\n\t\t\t\t\t\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tif(p>=st[j].p)\n\t\t\t\t\t{\n\t\t\t\t\t\tint np=(p+st[j].p)/2;\n\t\t\t\t\t\tint z=st[j].c-'A';\n\t\t\t\t\t\tmi[z]=min(mi[z], np);\n\t\t\t\t\t\tma[z]=max(ma[z], np);\n\t\t\t\t\t\ttt[z]+=np;\n\t\t\t\t\t\tnm[z]++;\n\n\t\t\t\t\t\tdr[d[a]].b+=np;\n\t\t\t\t\t\tdr[d[st[j].n]].s+=np;\n\n\t\t\t\t\t\tdealed=true;\n\t\t\t\t\t\tst.erase(st.begin()+j);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tbreak;\n\t\t\t}\n\n\t\t\tif(!dealed) st.push_back(State(a,b,c,p,i));\n\t\t\tsort(st.begin(), st.end());\n\t\t}\n\n\t\tfor(int i=0; i<26; i++)\n\t\t{\n\t\t\tif(nm[i]==0) continue;\n\t\t\tcout << (char)(i+'A') << \" \" << mi[i] << \" \" << (int)(tt[i]/nm[i]) << \" \"<< ma[i] << endl;\n\t\t}\n\t\tcout << \"--\" << endl;\n\n\t\tsort(dr.begin(), dr.end());\n\n\t\tfor(int i=0; i<dr.size(); i++)\n\t\t{\n\t\t\tcout << dr[i].n << \" \" << dr[i].b << \" \" << dr[i].s << endl;\n\t\t}\n\t\tcout << \"----------\" << endl;\n\t}\n\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 992, "score_of_the_acc": -1.6631, "final_rank": 8 }, { "submission_id": "aoj_1225_178446", "code_snippet": "#include <iostream>\n#include <vector>\n#include <map>\n#include <algorithm>\nusing namespace std;\n\nclass P{\npublic:\n\tint price,id;\n\tstring name,com;\n\tbool flg; //true:w“ü, false:”„‹p\n\n\tP(string _name,bool _flg,string _com,int _price,int _id){\n\t\tname = _name;\n\t\tflg = _flg;\n\t\tcom = _com;\n\t\tprice = _price;\n\t\tid = _id;\n\t}\n\n\tbool operator<(const P &p)const{\n\t\tif(price == p.price) return id < p.id;\n\t\tif(flg) return price > p.price;\n\t\treturn price < p.price;\n\t}\n};\n\ntypedef struct{int min,sum,max,n;}Com;\ntypedef struct{int pay,recv;}Dealer;\n\nint main(void){\n\tint n;\n\n\twhile(cin>>n,n){\n\t\tvector<P> buy,sell;\n\t\tmap<string,Com> mc;\n\t\tmap<string,Dealer> md;\n\n\t\tfor(int i=0;i<n;i++){\n\t\t\tstring name,flg,com;\n\t\t\tint price;\n\t\t\tcin>>name>>flg>>com>>price;\n\n\t\t\tmd[name].pay += 0; //ƒL[“o˜^‚Ì‚½‚ß\n\n\t\t\tif(flg == \"BUY\"){\n\t\t\t\tbool buyFlg = false;\n\t\t\t\tfor(int j=0;j<sell.size();j++){\n\t\t\t\t\tif(com == sell[j].com && name != sell[j].name && price >= sell[j].price){\n\t\t\t\t\t\tint deal = (price + sell[j].price) / 2;\n\n\t\t\t\t\t\tif(mc[com].min == 0){\n\t\t\t\t\t\t\tCom tmp = {deal,deal,deal,1};\n\t\t\t\t\t\t\tmc[com] = tmp;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse{\n\t\t\t\t\t\t\tif(mc[com].max < deal) mc[com].max = deal;\n\t\t\t\t\t\t\tif(mc[com].min > deal) mc[com].min = deal;\n\t\t\t\t\t\t\tmc[com].sum += deal;\n\t\t\t\t\t\t\tmc[com].n++;\n\t\t\t\t\t\t}\n\n\t\t\t\t\t\tmd[name].pay += deal;\n\t\t\t\t\t\tmd[sell[j].name].recv += deal;\n\t\t\t\t\t\tsell.erase(sell.begin()+j);\n\t\t\t\t\t\tbuyFlg = true;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tif(!buyFlg){\n\t\t\t\t\tbuy.push_back(P(name,true,com,price,i));\n\t\t\t\t\tsort(buy.begin(),buy.end());\n\t\t\t\t}\n\t\t\t}\n\t\t\telse{\n\t\t\t\tbool sellFlg = false;\n\t\t\t\tfor(int j=0;j<buy.size();j++){\n\t\t\t\t\tif(com == buy[j].com && name != buy[j].name && buy[j].price >= price){\n\t\t\t\t\t\tint deal = (price + buy[j].price) / 2;\n\n\t\t\t\t\t\tif(mc[com].min == 0){\n\t\t\t\t\t\t\tCom tmp = {deal,deal,deal,1};\n\t\t\t\t\t\t\tmc[com] = tmp;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse{\n\t\t\t\t\t\t\tif(mc[com].max < deal) mc[com].max = deal;\n\t\t\t\t\t\t\tif(mc[com].min > deal) mc[com].min = deal;\n\t\t\t\t\t\t\tmc[com].sum += deal;\n\t\t\t\t\t\t\tmc[com].n++;\n\t\t\t\t\t\t}\n\n\t\t\t\t\t\tmd[buy[j].name].pay += deal;\n\t\t\t\t\t\tmd[name].recv += deal;\n\t\t\t\t\t\tbuy.erase(buy.begin()+j);\n\t\t\t\t\t\tsellFlg = true;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tif(!sellFlg){\n\t\t\t\t\tsell.push_back(P(name,false,com,price,i));\n\t\t\t\t\tsort(sell.begin(),sell.end());\n\t\t\t\t}\n\t\t\t}\n\n\t\t}\n\n\t\tfor(map<string,Com>::iterator i=mc.begin();i!=mc.end();i++){\n\t\t\tcout<<(i->first)<<\" \"<<(i->second).min<<\" \"<<(i->second).sum / (i->second).n<<\" \"<<(i->second).max<<endl;\n\t\t}\n\t\tcout<<\"--\\n\";\n\n\t\tfor(map<string,Dealer>::iterator i=md.begin();i!=md.end();i++){\n\t\t\tcout<<(i->first)<<\" \"<<(i->second).pay<<\" \"<<(i->second).recv<<endl;\n\t\t}\n\t\tcout<<\"----------\\n\";\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 980, "score_of_the_acc": -0.732, "final_rank": 2 }, { "submission_id": "aoj_1225_178410", "code_snippet": "#include<iostream>\n#include<string>\n#include<map>\n#include<vector>\n\nusing namespace std;\nconst int infty = 100000;\n\nstruct order{\n string who;\n string does;\n string item;\n int val;\n};\n\nstruct item{\n vector<int> v;\n};\n\nstruct dealer{\n int sell;\n int buy;\n};\n\n#define SELL 0\n#define BUY 1\n\nint minimumValue(const vector<int> &v){\n int ret = infty;\n for(int i = 0; i < (int)v.size(); ++i) ret = min(ret, v[i] );\n return ret;\n}\nint maximumValue(const vector<int> &v){\n int ret = 0;\n for(int i = 0; i < (int)v.size(); ++i) ret = max(ret, v[i] );\n return ret;\n}\nint meanValue(const vector<int> &v){\n int sum = 0;\n for(int i = 0; i < (int)v.size(); ++i)sum+=v[i];\n return sum / v.size();\n}\n\nint main()\n{\n while(true){\n int records;\n cin >> records;\n if(records==0)break;\n vector<order> os;\n map<string,item> items;\n map<string,dealer> dealers;\n bool dealed[records];\n for(int i = 0; i < records; ++i){\n order o;\n cin >> o.who >> o.does >> o.item >> o.val;\n items[o.item] = item();\n dealers[o.who] = dealer();\n os.push_back(o);\n dealed[i] = false;\n }\n for(int i = 0; i < (int)os.size(); ++i){\n int max_deal_val = 0;\n int min_deal_val = infty;\n int anti_dealer = infty;\n for(int j = i-1; j >= 0; --j){\n\tif( os[j].who != os[i].who && os[j].does != os[i].does && os[j].item == os[i].item &&\n\t !dealed[i] && !dealed[j] ){\n\t if( os[i].does == \"SELL\" ){\n\t if( os[i].val <= os[j].val ){\n\t if( os[j].val > max_deal_val ){\n\t\tmax_deal_val = os[j].val;\n\t\tanti_dealer = j;\n\t }else if( os[j].val == max_deal_val ){\n\t\tanti_dealer = min( anti_dealer, j );\n\t }\n\t }\n\t }else{\n\t if( os[j].val <= os[i].val ){\n\t if( os[j].val < min_deal_val ){\n\t\tmin_deal_val = os[j].val;\n\t\tanti_dealer = j;\n\t }else if( os[j].val == min_deal_val ){\n\t\tanti_dealer = min( anti_dealer, j );\n\t }\n\t }\n\t }\n\t}\n }\n if( anti_dealer < infty ){\n\t// deal occured\n\tdealed[i] = true;\n\tdealed[anti_dealer] = true;\n\tint deal_val = (os[anti_dealer].val + os[i].val) /2;\n\titems[ os[i].item ].v.push_back( deal_val );\n\tif( os[i].does == \"SELL\" ){\n\t dealers[ os[i].who ].sell += deal_val;\n\t dealers[ os[anti_dealer].who ].buy += deal_val;\n\t}else{\n\t dealers[ os[i].who ].buy += deal_val;\n\t dealers[ os[anti_dealer].who ].sell += deal_val;\n\t}\n }\n }\n\n for(map<string,item>::iterator it = items.begin(); it != items.end(); ++it){\n if( it->second.v.size() > 0 ){\n\tint minv = minimumValue( it->second.v );\n\tint maxv = maximumValue( it->second.v );\n\tint avgv = meanValue( it->second.v );\n\tcout << it->first << ' ' << minv << ' ' << avgv << ' ' << maxv << endl;\n }\n }\n cout << \"--\" << endl;\n for(map<string,dealer>::iterator it = dealers.begin(); it != dealers.end(); ++it){\n cout << it->first << ' ' << it->second.buy << ' ' << it->second.sell << endl;\n }\n cout << \"----------\" << endl;\n \n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_1222_cpp
Problem G: Telescope Dr. Extreme experimentally made an extremely precise telescope to investigate extremely curi- ous phenomena at an extremely distant place. In order to make the telescope so precise as to investigate phenomena at such an extremely distant place, even quite a small distortion is not allowed. However, he forgot the influence of the internal gas affected by low-frequency vibration of magnetic flux passing through the telescope. The cylinder of the telescope is not affected by the low-frequency vibration, but the internal gas is. The cross section of the telescope forms a perfect circle. If he forms a coil by putting extremely thin wire along the (inner) circumference, he can measure (the average vertical component of) the temporal variation of magnetic flux:such measurement would be useful to estimate the influence. But points on the circumference at which the wire can be fixed are limited; furthermore, the number of special clips to fix the wire is also limited. To obtain the highest sensitivity, he wishes to form a coil of a polygon shape with the largest area by stringing the wire among carefully selected points on the circumference. Your job is to write a program which reports the maximum area of all possible m -polygons (polygons with exactly m vertices) each of whose vertices is one of the n points given on a circumference with a radius of 1. An example of the case n = 4 and m = 3 is illustrated below. In the figure above, the equations such as " p 1 = 0.0" indicate the locations of the n given points, and the decimals such as "1.000000" on m -polygons indicate the areas of m -polygons. Parameter p i denotes the location of the i -th given point on the circumference (1 ≤ i ≤ n ). The location p of a point on the circumference is in the range 0 ≤ p < 1, corresponding to the range of rotation angles from 0 to 2 π radians. That is, the rotation angle of a point at p to the point at 0 equals 2 π radians. ( π is the circular constant 3.14159265358979323846....) You may rely on the fact that the area of an isosceles triangle ABC (AB = AC = 1) with an interior angle BAC of α radians (0 < α < π ) is (1/2)sin α , and the area of a polygon inside a circle with a radius of 1 is less than π . Input The input consists of multiple subproblems followed by a line containing two zeros that indicates the end of the input. Each subproblem is given in the following format. n m p 1 p 2 ... p n n is the number of points on the circumference (3 ≤ n ≤ 40). m is the number of vertices to form m -polygons (3 ≤ m ≤ n ). The locations of n points, p 1 , p 2 ,..., p n , are given as decimals and they are separated by either a space character or a newline. In addition, you may assume that 0 ≤ p 1 < p 2 < ... < p n < 1. Output For each subproblem, the maximum area should be output, each in a separate line. Each value in the output may not have an error greater than 0.000001 and its fractional part should be represented by 6 decimal digits after the decim ...(truncated)
[ { "submission_id": "aoj_1222_3709885", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n// #define int ll\nusing PII = pair<ll, ll>;\n\n#define FOR(i, a, n) for (ll i = (ll)a; i < (ll)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define ALL(x) x.begin(), x.end()\n\ntemplate<typename T> T &chmin(T &a, const T &b) { return a = min(a, b); }\ntemplate<typename T> T &chmax(T &a, const T &b) { return a = max(a, b); }\ntemplate<typename T> bool IN(T a, T b, T x) { return a<=x&&x<b; }\ntemplate<typename T> T ceil(T a, T b) { return a/b + !!(a%b); }\n\ntemplate<typename T> vector<T> make_v(size_t a) { return vector<T>(a); }\ntemplate<typename T,typename... Ts>\nauto make_v(size_t a,Ts... ts) {\n return vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));\n}\ntemplate<typename T,typename V> typename enable_if<is_class<T>::value==0>::type\nfill_v(T &t, const V &v) { t=v; }\ntemplate<typename T,typename V> typename enable_if<is_class<T>::value!=0>::type\nfill_v(T &t, const V &v ) { for(auto &e:t) fill_v(e,v); }\n\ntemplate<class S,class T>\nostream &operator <<(ostream& out,const pair<S,T>& a) {\n out<<'('<<a.first<<','<<a.second<<')'; return out;\n}\ntemplate<class T>\nostream &operator <<(ostream& out,const vector<T>& a){\n out<<'[';\n for(const T &i: a) out<<i<<',';\n out<<']';\n return out;\n}\ntemplate<class T>\nostream &operator <<(ostream& out, const set<T>& a) {\n out<<'{';\n for(const T &i: a) out<<i<<',';\n out<<'}';\n return out;\n}\ntemplate<class T, class S>\nostream &operator <<(ostream& out, const map<T,S>& a) {\n out<<'{';\n for(auto &i: a) out<<i<<',';\n out<<'}';\n return out;\n}\n\nint dx[] = {0, 1, 0, -1}, dy[] = {1, 0, -1, 0}; // DRUL\nconst int INF = 1<<30;\nconst ll LLINF = 1LL<<60;\nconst ll MOD = 1000000007;\n\nusing R = double;\nR x[41][41][41], dp[41][41][41], area[41][41][41];\nsigned main(void)\n{\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n constexpr R PI = acos(-1);\n\n while(1) {\n ll n, m;\n cin >> n >> m;\n if(!n) break;\n vector<R> p(n);\n REP(i, n) cin >> p[i], p[i] *= 2*PI;\n\n REP(i, n) FOR(j, i, n) FOR(k, j, n) {\n area[i][j][k] = (sin(p[j]-p[i]) + sin(p[k]-p[j]) + sin(p[i]-p[k]))/2;\n }\n\n REP(i, 41) REP(j, 41) REP(k, 41) dp[i][j][k] = -LLINF;\n REP(i, 41) REP(j, 41) dp[i][j][2] = 0;\n\n R ans = -LLINF;\n REP(l, n) FOR(cnt, 2, m) FOR(r, l+1, n) FOR(i, r+1, n) {\n if(dp[l][r][cnt] == -LLINF) continue;\n chmax(dp[l][i][cnt+1], dp[l][r][cnt] + area[l][r][i]);\n if(cnt+1 <= m) chmax(ans, dp[l][i][cnt+1]);\n }\n\n cout << fixed << setprecision(6) << ans << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4548, "score_of_the_acc": -0.1548, "final_rank": 8 }, { "submission_id": "aoj_1222_3709729", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n// #define int ll\nusing PII = pair<ll, ll>;\n\n#define FOR(i, a, n) for (ll i = (ll)a; i < (ll)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define ALL(x) x.begin(), x.end()\n\ntemplate<typename T> T &chmin(T &a, const T &b) { return a = min(a, b); }\ntemplate<typename T> T &chmax(T &a, const T &b) { return a = max(a, b); }\ntemplate<typename T> bool IN(T a, T b, T x) { return a<=x&&x<b; }\ntemplate<typename T> T ceil(T a, T b) { return a/b + !!(a%b); }\n\ntemplate<typename T> vector<T> make_v(size_t a) { return vector<T>(a); }\ntemplate<typename T,typename... Ts>\nauto make_v(size_t a,Ts... ts) {\n return vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));\n}\ntemplate<typename T,typename V> typename enable_if<is_class<T>::value==0>::type\nfill_v(T &t, const V &v) { t=v; }\ntemplate<typename T,typename V> typename enable_if<is_class<T>::value!=0>::type\nfill_v(T &t, const V &v ) { for(auto &e:t) fill_v(e,v); }\n\ntemplate<class S,class T>\nostream &operator <<(ostream& out,const pair<S,T>& a) {\n out<<'('<<a.first<<','<<a.second<<')'; return out;\n}\ntemplate<class T>\nostream &operator <<(ostream& out,const vector<T>& a){\n out<<'[';\n for(const T &i: a) out<<i<<',';\n out<<']';\n return out;\n}\ntemplate<class T>\nostream &operator <<(ostream& out, const set<T>& a) {\n out<<'{';\n for(const T &i: a) out<<i<<',';\n out<<'}';\n return out;\n}\ntemplate<class T, class S>\nostream &operator <<(ostream& out, const map<T,S>& a) {\n out<<'{';\n for(auto &i: a) out<<i<<',';\n out<<'}';\n return out;\n}\n\nint dx[] = {0, 1, 0, -1}, dy[] = {1, 0, -1, 0}; // DRUL\nconst int INF = 1<<30;\nconst ll LLINF = 1LL<<60;\nconst ll MOD = 1000000007;\n\nusing R = double;\nR x[41][41][41], dp[41][41][41], area[41][41][41];\nsigned main(void)\n{\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n constexpr R PI = acos(-1);\n\n while(1) {\n ll n, m;\n cin >> n >> m;\n if(!n) break;\n vector<R> p(n);\n REP(i, n) cin >> p[i], p[i] *= 2*PI;\n\n REP(i, n) FOR(j, i, n) FOR(k, j, n) {\n area[i][j][k] = (sin(p[j]-p[i]) + sin(p[k]-p[j]) + sin(p[i]-p[k]))/2;\n }\n\n REP(i, 41) REP(j, 41) REP(k, 41) dp[i][j][k] = -LLINF;\n REP(i, 41) REP(j, 41) dp[i][j][2] = 0;\n\n R ans = -LLINF;\n REP(sp, n) FOR(cnt, 2, m) FOR(lp, sp+1, n) FOR(np, lp+1, n) {\n if(dp[sp][lp][cnt] == -LLINF) continue;\n chmax(dp[sp][np][cnt+1], dp[sp][lp][cnt] + area[sp][lp][np]);\n if(cnt+1 <= m) chmax(ans, dp[sp][np][cnt+1]);\n }\n\n cout << fixed << setprecision(6) << ans << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4536, "score_of_the_acc": -0.1543, "final_rank": 7 }, { "submission_id": "aoj_1222_3699589", "code_snippet": "#include <iostream>\n#include <vector>\n#include <complex>\n#include <cmath>\nusing namespace std;\nusing D = double;\nusing P = complex<D>;\nconstexpr D pi = acos(-1);\n\nD cross(const P &a, const P &b){ return a.real()*b.imag()-a.imag()*b.real();}\n\nint main(){\n int n, m;\n while(cin >> n >> m, n){\n vector<D> A(n);\n for(int i = 0; i < n; ++i){\n cin >> A[i];\n }\n D ans = 0;\n for(int i = 0; i < n; ++i){\n vector<vector<D>> dp(n,vector<D>(m+1,0));\n for(int j = i+1; j < n; ++j){\n for(int k = i+1; k < j; ++k){\n for(int l = 2; l < m; ++l){\n P a = polar(1.,2*pi*A[i]), b = polar(1.,2*pi*A[k]), c = polar(1.,2*pi*A[j]);\n D s = abs(cross(b-a,c-a))/2;\n dp[j][l+1] = max(dp[k][l] + s, dp[j][l+1]);\n if(l+1 == m) ans = max(ans,dp[j][l+1]);\n }\n }\n }\n }\n printf(\"%.6f\\n\",ans);\n }\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 3632, "score_of_the_acc": -0.3345, "final_rank": 14 }, { "submission_id": "aoj_1222_3644675", "code_snippet": "#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<ciso646>\n#include<random>\n#include<map>\n#include<set>\n#include<complex>\n#include<bitset>\n#include<stack>\n#include<unordered_map>\n#include<utility>\n#include<cassert>\nusing namespace std;\n\ntypedef long long ll;\n\ntypedef unsigned long long ul;\ntypedef unsigned int ui;\nconst ll mod = 998244353;\ntypedef long double ld;\ntypedef complex<ld> Point;\nconst ll INF = mod * mod;\ntypedef pair<int, int> P;\n#define stop char nyaa;cin>>nyaa;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define per(i,n) for(int i=n-1;i>=0;i--)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define per1(i,n) for(int i=n;i>=1;i--)\n#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)\nconst ld eps = 1e-8;\nconst ld pi = acos(-1.0);\ntypedef pair<ld, ld> LDP;\ntypedef pair<ll, ll> LP;\ntypedef vector<int> vec;\ntypedef vector<string> svec;\n\nbool eq(ld a, ld b) {\n\treturn (abs(a - b) < eps);\n}\n\nclass Line {\npublic:\n\tPoint a, b;\n};\nclass Circle {\npublic:\n\tPoint p; ld r;\n};\n\nld dot(Point a, Point b) {\n\treturn real(conj(a)*b);\n}\nld cross(Point a, Point b) {\n\treturn imag(conj(a)*b);\n}\nnamespace std {\n\tbool operator<(const Point &lhs, const Point &rhs) {\n\t\treturn lhs.real() == rhs.real() ? lhs.imag() < rhs.imag() : lhs.real() < rhs.real();\n\t}\n}\nPoint proj(Line l, Point p) {\n\tld t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n\treturn l.a + t * (l.a - l.b);\n}\n\nld dist_lp(Line l, Point p) {\n\treturn abs(p - proj(l, p));\n}\n\nint ccw(Point a, Point b, Point c) {\n\tb -= a; c -= a;\n\tif (cross(b, c) > eps)return 1;//a,b,cが反時計回り\n\tif (cross(b, c) < -eps)return -1;//a,b,cが時計回り\n\tif (dot(b, c) < 0)return 2;//c,a,bの順に一直線\n\tif (norm(b) < norm(c))return -2;//a,b,cの順に一直線\n\treturn 0;//a,c,bの順に一直線\n}\nbool isis_ll(Line l, Line m) {\n\treturn !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\nPoint is_ll(Line s, Line t) {\n\tPoint sv = s.b - s.a; Point tv = t.b - t.a;\n\treturn s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n\n//直線lに幅dをつける\nvector<Line> make_w(Line l, ld d) {\n\tPoint dif = l.b - l.a;\n\tdif = dif*Point{0, 1};\n\tdif = dif * (d / abs(dif));\n\tvector<Line> ret;\n\tfor (int id = 1; id >= -1; id -= 2) {\n\t\tPoint a = l.a + dif * (ld)id;\n\t\tPoint b = l.b + dif * (ld)id;\n\t\tret.push_back({ a,b });\n\t}\n\treturn ret;\n}\n\ntypedef vector<Point> polygon;\npolygon ConvexHull(polygon p) {\n\tint n = p.size();\n\tint k = 0;\n\tsort(p.begin(), p.end());\n\tpolygon ch(2 * n);\n\tfor (int i = 0; i < n; ch[k++] = p[i++]) {\n\t\twhile (k >= 2 && ccw(ch[k - 2], ch[k - 1], p[i]) <= 0)--k;\n\t}\n\tfor (int i = n - 2, t = k + 1; i >= 0; ch[k++] = p[i--]) {\n\t\twhile (k >= t && ccw(ch[k - 2], ch[k - 1], p[i]) <= 0)--k;\n\t}\n\tch.resize(k - 1);\n\treturn ch;\n}\npolygon convex_cut(const polygon &p, Line l) {\n\tvector<Point> ret;\n\trep(i, p.size()) {\n\t\tPoint a = p[i], b = p[(i + 1) % p.size()];\n\t\tif (ccw(l.a, l.b, a) != -1)ret.push_back(a);\n\t\tif (ccw(l.a, l.b, a)*ccw(l.a, l.b, b)<0) {\n\t\t\tret.push_back(is_ll({ a,b }, l));\n\t\t}\n\t}\n\treturn ret;\n}\nld area(const polygon &p){\n\tld ret = 0;\n\tint n = p.size();\n\trep(j, n)ret += cross(p[j], p[(j + 1) % n]);\n\treturn ret / 2.0;\n}\nld max_distance(const polygon &p) {\n\t//assert(p.size()>1);\n\tpolygon g = ConvexHull(p);\n\tint n = g.size(), a = 0, b = 1;\n\tld ret = abs(g[0] - g[1]);\n\twhile (a < n) {\n\t\tPoint p1 = g[a%n], p2 = g[(a + 1) % n];\n\t\tPoint q1 = g[b%n], q2 = g[(b + 1) % n];\n\t\tif (arg((p2 - p1) / (q1 - q2)) > 0)++b; else ++a;\n\t\tret = max(ret, abs(p1 - q1));\n\t}\n\treturn ret;\n}\n\nvector<Point> is_cc(Circle c1, Circle c2) {\n\tvector<Point> res;\n\tld d = abs(c1.p - c2.p);\n\tld rc = (d*d + c1.r*c1.r - c2.r*c2.r) / (2 * d);\n\tld dfr = c1.r*c1.r - rc * rc;\n\tif (abs(dfr) < eps)dfr = 0.0;\n\tif (dfr < 0.0)return res;\n\tld rs = sqrt(dfr);\n\tPoint diff = (c2.p - c1.p) / d;\n\tres.push_back(c1.p + diff * Point(rc, rs));\n\tif (dfr != 0.0)res.push_back(c1.p + diff * Point(rc, -rs));\n\treturn res;\n}\nbool in_Circle(Circle a, Circle b) {\n\tld dist = abs(b.p - a.p);\n\treturn dist < b.r - a.r+eps;\n}\n\nld calc(ld t) {\n\tld theta = pi*t;\n\treturn sin(theta)*cos(theta);\n}\nint n, m;\nvoid solve() {\n\tvector<ld> p(n);\n\trep(i, n)cin >> p[i];\n\tld ans = -mod;\n\trep(i, n) {\n\t\tvector<vector<ld>> dp(n);\n\t\trep(j, n)dp[j].resize(m,-mod);\n\t\tdp[0][0] = 0;\n\t\trep1(j, n - 1) {\n\t\t\tint id = (i + j)%n;\n\t\t\trep(k, j) {\n\t\t\t\tint pid = (i + k) % n;\n\t\t\t\trep(l, m-1) {\n\t\t\t\t\tld dif = p[id] - p[pid];\n\t\t\t\t\tif (dif < 0)dif += 1;\n\t\t\t\t\tdp[j][l + 1] = max(dp[j][l + 1], dp[k][l] + calc(dif));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\trep(j, n) {\n\t\t\tint id = (i + j) % n;\n\t\t\tld dif = p[i] - p[id];\n\t\t\tif (dif < 0)dif += 1;\n\t\t\tld sum = calc(dif) + dp[j][m - 1];\n\t\t\tans = max(ans, sum);\n\t\t\t/*if (sum > 0.731010) {\n\t\t\t\tcout << i << \" \" << j << \" \" << dp[j][m-1]<<\" \"<<calc(dif) << endl;\n\t\t\t}*/\n\t\t}\n\t}\n\tcout << ans << endl;\n\t//cout << calc(0.24) << endl;\n\t/*rep(i, 40) {\n\t\tld u = 0.002*i;\n\t\t\tcout << u << \" \" << calc(u) << endl;\n\t}*/\n}\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\tcout << fixed << setprecision(6);\n\tint t = 1;\n\twhile (cin >> n>>m, n) {\n\t\tsolve();\n\t}\n\t//solve();\n\t//stop\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1050, "memory_kb": 3564, "score_of_the_acc": -0.9755, "final_rank": 18 }, { "submission_id": "aoj_1222_3641949", "code_snippet": "#include<iomanip>\n#include<limits>\n#include<thread>\n#include<utility>\n#include<iostream>\n#include<string>\n#include<algorithm>\n#include<set>\n#include<map>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<cmath>\n#include<numeric>\n#include<cassert>\n#include<random>\n#include<chrono>\n#include<unordered_set>\n#include<unordered_map>\n#include<fstream>\n#include<list>\n#include<functional>\n#include<bitset>\n#include<complex>\n#include<tuple>\nusing namespace std;\ntypedef unsigned long long int ull;\ntypedef long long int ll;\ntypedef pair<ll,ll> pll;\ntypedef long double D;\ntypedef complex<D> P;\n#define F first\n#define S second\nconst ll E=1e18+7;\nconst ll MOD=1000000007;\n\n\ntemplate<typename T,typename U>istream & operator >> (istream &i,pair<T,U> &A){i>>A.F>>A.S; return i;}\ntemplate<typename T>istream & operator >> (istream &i,vector<T> &A){for(auto &I:A){i>>I;} return i;}\ntemplate<typename T,typename U>ostream & operator << (ostream &o,pair<T,U> &A){o<<A.F<<\" \"<<A.S; return o;}\ntemplate<typename T>ostream & operator << (ostream &o,vector<T> &A){ll i=A.size(); for(auto &I:A){o<<I<<(--i?\" \":\"\");} return o;}\ntemplate<typename T>vector<T> & cset(vector<T> &A,T e=T()){for(auto &I:A){I=e;} return A;}\n\nnamespace Geometry{\n typedef long double D;\n typedef complex<long double> P;\n typedef pair<P,D> C;\n \n const D EPS=1e-9;\n const D PI=asin(1)*2;\n const D INF=1e18;\n \n const static bool comp(const P &p1,const P &p2){return p1.real()==p2.real()?p1.imag()<p2.imag():p1.real()<p2.real();}\n \n D dot(P p1,P p2){return p1.real()*p2.real()+p1.imag()*p2.imag();}\n \n D cross(P p1,P p2){return p1.real()*p2.imag()-p1.imag()*p2.real();}\n \n P project(P vec,P x){return vec*(x/vec).real();}\n \n P project(P p1,P p2,P x){return p1+project(p2-p1,x-p1);}\n \n P reflect(P vec,P x){return vec*conj(x/vec);}\n \n P reflect(P p1,P p2,P x){return p1+reflect(p2-p1,x-p1);}\n \n bool intersectSL(P p1,P p2,P vec){vec/=abs(vec); p1/=vec; p2/=vec; return (p1.imag()<EPS && p2.imag()>-EPS) || (p1.imag()>-EPS && p2.imag()<EPS);}\n \n bool intersectSL(P p1,P p2,P p3,P p4){return intersectSL(p1-p4,p2-p4,p3-p4);}\n \n bool intersectSS(P p1,P p2,P p3,P p4){return (dot(p2-p1,p3-p1)<-EPS && dot(p2-p1,p4-p1)<-EPS) || (dot(p1-p2,p3-p2)<-EPS && dot(p1-p2,p4-p2)<-EPS)?false:intersectSL(p1,p2,p3,p4) && intersectSL(p3,p4,p1,p2);}\n \n D distLP(P vec,P x){return abs((x/vec).imag())*abs(vec);}\n \n D distLP(P p1,P p2,P x){return distLP(p2-p1,x-p1);}\n \n D distSP(P p1,P p2,P x){return dot(p2-p1,x-p1)<-EPS?abs(x-p1):dot(p1-p2,x-p2)<-EPS?abs(x-p2):distLP(p1,p2,x);}\n \n D distSS(P p1,P p2,P p3,P p4){return intersectSS(p1,p2,p3,p4)?0.0:min(min(distSP(p1,p2,p3),distSP(p1,p2,p4)),min(distSP(p3,p4,p1),distSP(p3,p4,p2)));}\n \n P crosspointLL(P p1,P p2,P vec){return abs(cross(p2-p1,vec))<EPS?vec:vec*cross(p2-p1,p2)/cross(p2-p1,vec);}\n \n P crosspointLL(P p1,P p2,P p3,P p4){return p4+crosspointLL(p1-p4,p2-p4,p3-p4);}\n \n P crosspointSS(P p1,P p2,P p3,P p4){return distSP(p1,p2,p3)<EPS?p3:distSP(p1,p2,p4)<EPS?p4:crosspointLL(p1,p2,p3,p4);}\n \n bool intersectShL(P p1,P p2,P vec){vec/=abs(vec); return intersectSL(p1,p2,vec) && crosspointLL(p1/vec,p2/vec,vec/vec).real()>-EPS;}\n \n bool intersectShL(P p1,P p2,P p3,P p4){return intersectShL(p1-p3,p2-p3,p4-p3);}\n \n //1::in,0::on edge,-1::out\n int contain(const vector<P> &poly,const P &p){\n vector<P> A={{65537,96847},{-24061,6701},{56369,-86509},{-93763,-78049},{56957,10007}};\n vector<bool> cnt(5,false);\n for(int i=1;i<=poly.size();i++){\n if(distSP(poly[i-1],poly[i%poly.size()],p)<EPS){return 0;}\n for(int j=0;j<5;j++){\n if(intersectShL(poly[i-1],poly[i%poly.size()],p,p+A[j])){cnt[j]=!cnt[j];}\n }\n }\n int in=0;\n for(int j=0;j<5;j++){if(cnt[j]){in++;}}\n return in>=3?1:-1;\n }\n \n vector<P> convexcut(const vector<P> &poly,P p1,P p2){\n vector<P> ret;\n for(int i=1;i<=poly.size();i++){\n if(cross(p2-p1,poly[i-1]-p1)>-EPS){ret.push_back(poly[i-1]);}\n if(intersectSL(poly[i-1],poly[i%poly.size()],p1,p2) && distLP(p1,p2,poly[i-1])>EPS && distLP(p1,p2,poly[i%poly.size()])>EPS){ret.push_back(crosspointLL(poly[i-1],poly[i%poly.size()],p1,p2));}\n }\n return ret;\n }\n \n D area(const vector<P> &poly){\n D ans=0;\n for(int i=2;i<poly.size();i++){ans+=cross(poly[i-1]-poly[0],poly[i]-poly[0]);}\n return abs(ans)/2;\n }\n \n vector<P> convexhull(vector<P> pts){\n vector<P> ret;\n sort(pts.begin(),pts.end(),comp);\n for(auto &I:pts){\n if(!ret.empty() && I==ret.back()){continue;}\n while(ret.size()>=2 && cross(ret.back()-ret[ret.size()-2],I-ret.back())<-EPS){ret.pop_back();}\n ret.push_back(I);\n }\n reverse(pts.begin(),pts.end());\n for(auto &I:pts){\n if(!ret.empty() && I==ret.back()){continue;}\n while(ret.size()>=2 && cross(ret.back()-ret[ret.size()-2],I-ret.back())<-EPS){ret.pop_back();}\n ret.push_back(I);\n }\n if(ret[0]==ret.back()){ret.pop_back();}\n return ret;\n }\n \n //4::seperate,3::circumscribe,2::intersect,1::inscribe,0::contain,-1::same\n int intersectCC(C c1,C c2){\n D d=abs(c1.F-c2.F),r=c1.S+c2.S,dif=abs(c2.S-c1.S);\n if(d<EPS && dif<EPS){return -1;}\n if(d-r>EPS){return 4;}\n if(d-r>-EPS){return 3;}\n if(d-dif>EPS){return 2;}\n if(d-dif>-EPS){return 1;}\n return 0;\n }\n \n vector<P> crosspointLC(P p1,P p2,C c){\n vector<P> ret;\n P pr=project(p1,p2,c.F);\n D d=distLP(p1,p2,c.F);\n if(d-c.S>EPS){return ret;}\n if(d-c.S>-EPS){ret.push_back(pr); return ret;}\n P vec=p2-p1; vec*=sqrt(c.S*c.S-d*d)/abs(vec);\n ret.push_back(pr-vec);\n ret.push_back(pr+vec);\n return ret;\n }\n \n vector<P> crosspointSC(P p1,P p2,C c){\n vector<P> ret;\n for(auto &I:crosspointLC(p1,p2,c)){if(distSP(p1,p2,I)<EPS){ret.push_back(I);}}\n return ret;\n }\n \n vector<P> crosspointCC(C c1,C c2){\n vector<P> ret;\n P vec=c2.F-c1.F;\n D base=(c1.S*c1.S+norm(vec)-c2.S*c2.S)/(2*abs(vec));\n D h=sqrt(c1.S*c1.S-base*base);\n vec/=abs(vec);\n ret.push_back(c1.F+vec*P(base,-h));\n ret.push_back(c1.F+vec*P(base,h));\n return ret;\n }\n \n vector<P> tangentCP(C c,P p){return crosspointCC(c,C(p,sqrt(norm(c.F-p)-c.S*c.S)));}\n \n vector<pair<P,P>> tangentCC(C c1,C c2){\n vector<pair<P,P>> ret;\n P d=c2.F-c1.F;\n for(D i:{-1,1}){\n D r=c1.S+c2.S*i;\n if(intersectCC(c1,c2)>i+1){\n for(P s:{-1i,1i}){\n P p=r+s*sqrt(norm(d)-norm(r));\n ret.push_back({c1.F+d*c1.S/norm(d)*p,c2.F-d*i*c2.S/norm(d)*p});\n }\n }\n }\n return ret;\n }\n \n D area(const vector<P> &poly,C c){\n D ret=0;\n for(int i=0;i<poly.size();i++){\n P a=poly[i]-c.F,b=poly[(i+1)%poly.size()]-c.F;\n if(abs(a)<c.S+EPS && abs(b)<c.S+EPS){ret+=cross(a,b);}\n else{\n vector<P> A=crosspointSC(a,b,{0,c.S});\n if(A.empty()){ret+=c.S*c.S*arg(b/a);}\n else{\n ret+=(abs(a)<c.S?cross(a,A[0]):c.S*c.S*arg(A[0]/a));\n ret+=(abs(b)<c.S?cross(A.back(),b):c.S*c.S*arg(b/A.back()));\n ret+=cross(A[0],A.back());\n }\n }\n }\n return abs(ret)/2;\n }\n \n //反時計回り\n D diameter(const vector<P> &poly){\n D ret=0;\n ll l=0,r=0,n=poly.size();\n if(n==2){return abs(poly[0]-poly[1]);}\n for(int i=0;i<n;i++){\n if(comp(poly[l],poly[i])){l=i;}\n if(comp(poly[i],poly[r])){r=i;}\n }\n ll sl=r,sr=l;\n while(sl!=l || sr!=r){\n ret=max(ret,abs(poly[r]-poly[l]));\n if(cross(poly[(l+1)%n]-poly[l],poly[(r+1)%n]-poly[r])<0){(++l)%=n;}\n else{(++r)%=n;}\n }\n return ret;\n }\n \n D closestpair(vector<P> pt){\n sort(pt.begin(),pt.end(),comp);\n D ret=INF;\n for(ll i=1;i<pt.size();i<<=1){\n for(ll j=0;i+j<pt.size();j+=i*2){\n ll m=i+j;\n vector<P> R;\n D l=-INF,r=INF;\n for(ll k=j;k<m;k++){l=max(l,pt[k].real());}\n for(ll k=0;m+k<pt.size() && k<i;k++){r=min(r,pt[m+k].real());}\n for(ll k=0;m+k<pt.size() && k<i;k++){if(pt[m+k].real()-l<ret){R.push_back(pt[m+k]);}}\n ll idx=0;\n for(ll k=j;k<m;k++){\n if(r-pt[k].real()>ret){continue;}\n while(idx<R.size() && pt[k].imag()-R[idx].imag()>ret){idx++;}\n for(ll n=idx;n<R.size() && R[n].imag()-pt[k].imag()<ret;n++){ret=min(ret,abs(R[n]-pt[k]));}\n }\n inplace_merge(pt.begin()+j,pt.begin()+m,j+i*2<pt.size()?pt.begin()+j+2*i:pt.end(),[](const P &a,const P &b){return a.imag()==b.imag()?a.real()<b.real():a.imag()<b.imag();});\n }\n }\n return ret;\n }\n \n istream & operator >> (istream &i,P &p){D x,y; i>>x>>y; p={x,y}; return i;}\n istream & operator >> (istream &i,C &p){D x,y; i>>x>>y>>p.S; p.F={x,y}; return i;}\n};\n\nusing namespace Geometry;\n\n\nD cul(const vector<P> &A,ll s,ll n,ll m){\n vector<vector<D>> dp(n,vector<D>(m,-E));\n dp[s][0]=0;\n for(ll i=s+1;i<n;i++){\n for(int j=1;j<m;j++){\n for(int k=0;k<i;k++){dp[i][j]=max(dp[i][j],dp[k][j-1]+cross(A[k],A[i]));}\n }\n }\n D ret=-E;\n for(ll i=s+1;i<n;i++){ret=max(ret,dp[i].back()+cross(A[i],A[s]));}\n return ret;\n}\n\n\nint main(){\n ll n,m;\n while(cin>>n>>m,n){\n vector<D> R(n);\n cin>>R;\n vector<P> A(n);\n for(int i=0;i<n;i++){A[i]=polar((D)1,R[i]*2*PI);}\n D ret=0;\n for(int i=0;i<n;i++){ret=max(ret,cul(A,i,n,m));}\n cout<<fixed<<setprecision(6)<<ret/2<<endl;\n }\n \n \n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3632, "score_of_the_acc": -0.1141, "final_rank": 4 }, { "submission_id": "aoj_1222_3047541", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <complex>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\nconst double EPS = 1e-8;\nconst double INF = 1e18;\nconst double PI = acos(-1);\ntypedef complex<double> P;\ntypedef vector<P> VP;\n#define X real()\n#define Y imag()\n\ndouble cross(P a, P b){\n return (conj(a)*b).Y;\n}\ndouble gettriarea(P a, P b, P c){\n return abs(cross(b-a, c-a)) /2;\n}\n\nint main(){\n while(1){\n int n,m;\n cin >> n >> m;\n if(n==0) break;\n\n VP p(n);\n for(int i=0; i<n; i++){\n double d;\n cin >> d;\n p[i] = P(1, 0) *P(cos(d*2*PI), sin(d*2*PI));\n }\n double ans = 0;\n for(int sp=0; sp<n; sp++){\n p.push_back(p[0]);\n p.erase(p.begin());\n vector<vector<double> > dp(n+1, vector<double>(n+1, 0));\n for(int cp=2; cp<n; cp++){\n for(int cn=3; cn<=cp +1; cn++){\n for(int lp=cn-2; lp<cp; lp++){\n dp[cp][cn] = max(dp[cp][cn], dp[lp][cn-1] +gettriarea(p[0], p[lp], p[cp]));\n }\n }\n }\n for(int i=0; i<n; i++){\n ans = max(ans, dp[i][m]);\n }\n }\n cout << fixed << setprecision(6);\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3488, "score_of_the_acc": -0.1077, "final_rank": 3 }, { "submission_id": "aoj_1222_2669299", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\nconst ld pi=acos(-1.0);\n\nld solve(int N, int M, vector<ld>ps) {\n\tvector<vector<vector<ld>>>dp(N+1,vector<vector<ld>>(M+1,vector<ld>(N,-1e8)));\n\tdp[1][1][0]=0;\n\tfor (int now = 1; now < N; ++now) {\n\t\tfor (int used_cnt = 0; used_cnt <= M; ++used_cnt) {\n\t\t\tfor (int pre_use_id = 0; pre_use_id < now; ++pre_use_id) {\n\t\t\t\tdp[now+1][used_cnt][pre_use_id]=max(dp[now+1][used_cnt][pre_use_id],\n\t\t\t\t\tdp[now][used_cnt][pre_use_id]);\n\n\t\t\t\tif (used_cnt != M) {\n\n\t\t\t\t\tld plus = 0.5*(sin(2 * pi*(ps[now] - ps[pre_use_id])));\n\t\t\t\t\tdp[now + 1][used_cnt + 1][now] = max(\n\t\t\t\t\t\tdp[now + 1][used_cnt + 1][now],\n\t\t\t\t\t\tdp[now][used_cnt][pre_use_id] + plus);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tld ans=0;\n\tfor (int pre_use_id = 0; pre_use_id < N; ++pre_use_id) {\n\n\t\tld plus = 0.5*(sin(2 * pi*(ps[0] - ps[pre_use_id])));\n\t\tans=max(ans,dp[N][M][pre_use_id]+plus);\n\t}\n\treturn ans;\n}\n\nint main() {\n\twhile (true) {\n\t\tint N, M; cin >> N >> M;\n\t\tif(!N)break;\n\t\tvector<ld>ps;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tld theta; cin >> theta;\n\t\t\tps.push_back(theta);\n\t\t}\n\n\t\tld ans = 0;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\trotate(ps.begin(), ps.begin() + 1, ps.end());\n\t\t\tans = max(ans, solve(N, M, ps));\n\t\t}\n\t\tcout<<setprecision(6)<<fixed<<ans<<endl;\n\t}\n\t\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1200, "memory_kb": 3768, "score_of_the_acc": -1.1117, "final_rank": 20 }, { "submission_id": "aoj_1222_2599425", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\n#include <time.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\nstruct Point{\n\tdouble x,y;\n};\n\nint N,M;\n\nPoint point[40];\ndouble dp[40][40][41];\n\ndouble calc(int start,int last,int next){\n return fabs((point[start].x*point[last].y-point[last].x*point[start].y)+(point[last].x*point[next].y-point[next].x*point[last].y)+\n \t\t(point[next].x*point[start].y-point[start].x*point[next].y))/2;\n}\n\nvoid func(){\n\n\tdouble tmp;\n\n\tfor(int i = 0; i < N; i++){\n\t\tscanf(\"%lf\",&tmp);\n\t\tpoint[i].x = cos(tmp*2.0*M_PI);\n\t\tpoint[i].y = sin(tmp*2.0*M_PI);\n\t}\n\n\tfor(int a = 0; a < 40; a++){\n\t\tfor(int b = 0; b < 40; b++){\n\t\t\tfor(int c = 0; c <= 40; c++)dp[a][b][c] = 0.0;\n\t\t}\n\t}\n\n\tdouble ans = 0.0;\n\n\tfor(int start = 0; start < N; start++){\n\t\tfor(int count = 2; count < M; count++){\n\t\t\tfor(int last = start; last < N; last++){\n\t\t\t\tfor(int next = last+1; next < N; next++){\n\t\t\t\t\tdp[start][next][count+1] = max(dp[start][next][count+1],dp[start][last][count]+calc(start,last,next));\n\n\t\t\t\t\tif(count+1 == M)ans = max(ans,dp[start][next][count+1]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%.6lf\\n\",ans);\n}\n\nint main(){\n\n\twhile(true){\n\t\tscanf(\"%d %d\",&N,&M);\n\t\tif(N == 0 && M == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4092, "score_of_the_acc": -0.1261, "final_rank": 5 }, { "submission_id": "aoj_1222_2548402", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n \n#define MAX_N 41\n \nconst double Pi = acos(-1);\n \ndouble getAngle(double p, double q) {\n // assert(p < q);\n \n return (p-q)*2*Pi;\n}\n \n#define eps 1e-8\n \ndouble getArea(double p, double q) {\n //cout<<getAngle(p,q)<<endl;\n //if(getAngle(p,q) > 0.5) return fabs(sin(1-getAngle(p, q))/2);\n return (sin(getAngle(p, q))/2);\n}\n \nint n, m;\ndouble p[MAX_N];\n \ndouble dp[MAX_N][MAX_N][MAX_N];\n \ndouble solve(int idx, int curr, int start) {\n if(idx == m) {\n //if((1+p[start]-p[curr])-0.5 > 0) return -getArea(p[curr], p[start]);\n return getArea(p[start], p[curr]);\n }\n if(curr+1 == n) return -1e9;\n double &res = dp[idx][curr][start];\n if(res != -1) return res;\n for(int i = curr+1; i < n; i++) {\n res = max(res, solve(idx+1, i, start) + getArea(p[i], p[curr]));\n }\n return res;\n}\n \nint main() {\n while(cin >> n >> m, n || m) {\n for(int i = 0; i < n; i++) cin >> p[i];\n \n double ans = 0;\n for(int i = 0; i < MAX_N; i++)\n for(int j = 0; j < MAX_N; j++)\n for(int k = 0; k < MAX_N; k++)\n dp[i][j][k] = -1;\n \n for(int i = 0; i < n; i++) {\n ans = max(ans, solve(1, i, i));\n }\n printf(\"%.6f\\n\", ans);\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4004, "score_of_the_acc": -0.1561, "final_rank": 11 }, { "submission_id": "aoj_1222_2548307", "code_snippet": "#include<bits/stdc++.h>\n \nusing namespace std;\n \ntypedef complex<double> P;\n \nint n,m;\ndouble p[50];\n \ndouble cal(int a,int b,int c){\n \n double res;\n \n P s=P(cos(p[a]),sin(p[a])),t=P(cos(p[b]),sin(p[b])),u=P(cos(p[c]),sin(p[c]));\n \n double aa=abs(s-t),bb=abs(t-u),cc=abs(u-s);\n double ss=(aa+bb+cc)/2;\n \n res=sqrt(ss*(ss-aa)*(ss-bb)*(ss-cc));\n \n return res;\n}\n \nint main(){\n \n \n while(cin>>n>>m,n){\n \n for(int i=0;i<n;i++){\n cin>>p[i];\n p[i]*=2*M_PI;\n }\n \n double dp[50][50][50]={};\n \n for(int i=0;i<n;i++)\n for(int j=i+1;j<n;j++)\n for(int k=2;k<m;k++)\n for(int l=j+1;l<n;l++){\n dp[i][l][k+1]=max(dp[i][l][k+1],dp[i][j][k]+cal(i,j,l));\n }\n \n double ans=0;\n for(int i=0;i<n;i++)\n for(int j=i+1;j<n;j++)ans=max(ans,dp[i][j][m]);\n \n printf(\"%.6f\\n\",ans);\n \n }\n \n \n \n return 0;\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 4560, "score_of_the_acc": -0.4774, "final_rank": 15 }, { "submission_id": "aoj_1222_2547962", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define MAX_N 41\n\nconst double Pi = acos(-1);\n\ndouble getAngle(double p, double q) {\n // assert(p < q);\n \n return (p-q)*2*Pi;\n}\n\n#define eps 1e-8\n\ndouble getArea(double p, double q) {\n //cout<<getAngle(p,q)<<endl;\n //if(getAngle(p,q) > 0.5) return fabs(sin(1-getAngle(p, q))/2);\n return (sin(getAngle(p, q))/2);\n}\n\nint n, m;\ndouble p[MAX_N];\n\ndouble dp[MAX_N][MAX_N][MAX_N];\n\ndouble solve(int idx, int curr, int start) {\n if(idx == m) {\n //if((1+p[start]-p[curr])-0.5 > 0) return -getArea(p[curr], p[start]);\n return getArea(p[start], p[curr]);\n }\n if(curr+1 == n) return -1e9;\n double &res = dp[idx][curr][start];\n if(res != -1) return res;\n for(int i = curr+1; i < n; i++) {\n res = max(res, solve(idx+1, i, start) + getArea(p[i], p[curr]));\n }\n return res;\n}\n\nint main() {\n while(cin >> n >> m, n || m) {\n for(int i = 0; i < n; i++) cin >> p[i];\n\n double ans = 0;\n for(int i = 0; i < MAX_N; i++)\n for(int j = 0; j < MAX_N; j++)\n\tfor(int k = 0; k < MAX_N; k++)\n\t dp[i][j][k] = -1;\n \n for(int i = 0; i < n; i++) {\n ans = max(ans, solve(1, i, i));\n }\n printf(\"%.6f\\n\", ans);\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4000, "score_of_the_acc": -0.1559, "final_rank": 10 }, { "submission_id": "aoj_1222_2547866", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\ntypedef complex<double> P;\n\nint n,m;\ndouble p[50];\n\ndouble cal(int a,int b,int c){\n\n double res;\n\n P s=P(cos(p[a]),sin(p[a])),t=P(cos(p[b]),sin(p[b])),u=P(cos(p[c]),sin(p[c]));\n\n double aa=abs(s-t),bb=abs(t-u),cc=abs(u-s);\n double ss=(aa+bb+cc)/2;\n\n res=sqrt(ss*(ss-aa)*(ss-bb)*(ss-cc));\n\n return res;\n}\n\nint main(){\n\n\n while(cin>>n>>m,n){\n\n for(int i=0;i<n;i++){\n cin>>p[i];\n p[i]*=2*M_PI;\n }\n\n double dp[50][50][50]={};\n \n for(int i=0;i<n;i++)\n for(int j=i+1;j<n;j++)\n for(int k=2;k<m;k++)\n\tfor(int l=j+1;l<n;l++){\n\t dp[i][l][k+1]=max(dp[i][l][k+1],dp[i][j][k]+cal(i,j,l));\n\t}\n\n double ans=0;\n for(int i=0;i<n;i++)\n for(int j=i+1;j<n;j++)ans=max(ans,dp[i][j][m]);\n \n printf(\"%.6f\\n\",ans);\n \n }\n\n\n \n return 0;\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 4572, "score_of_the_acc": -0.4779, "final_rank": 16 }, { "submission_id": "aoj_1222_2340584", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define int long long\n#define all(v) begin(v), end(v)\n#define reps(i, m, n) for(int i = (int)(m); i < (int)(n); i++)\n#define rep(i, n) reps(i, 0, n)\n\ntemplate<class T1, class T2> void chmin(T1 &a, T2 b){if(a>b)a=b;}\ntemplate<class T1, class T2> void chmax(T1 &a, T2 b){if(a<b)a=b;}\n\nusing pint = pair<int, int>;\nusing tint = tuple<int, int, int>;\nusing vint = vector<int>;\n\nconst int inf = 1LL << 55;\nconst int mod = 1e9 + 7;\n\nint n, m;\ndouble p[88];\ndouble dp[44][44][44];\n\nconst double Pi = acos(-1);\ndouble area(int a, int b) {\n return sin((p[b]-p[a])*2*Pi)/2;\n}\n\ndouble solve(int fr, int la, int cnt) {\n if(cnt == m) return (la-fr < 0.5 ? -1 : 1)*area(la, n+fr);\n if(la == n-1) return -DBL_MAX/3;\n double &res = dp[fr][la][cnt];\n if(res != -DBL_MAX/3) return res;\n res = -DBL_MAX/5;\n reps(i, la+1, n) {\n chmax(res, solve(fr, i, cnt+1)+area(la, i));\n }\n return res;\n}\n\nsigned main()\n{\n cin.tie(0);\n ios_base::sync_with_stdio(0);\n cout << fixed << setprecision(6);\n\n while(cin >> n >> m, n || m) {\n rep(i, n) cin >> p[i];\n rep(i, n) p[n+i] = p[i]+1;\n rep(i, 44) rep(j, 44) rep(k, 44) dp[i][j][k] = -DBL_MAX/3;\n double ans = 0;\n rep(i, n) chmax(ans, solve(i, i, 1));\n cout << ans << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4172, "score_of_the_acc": -0.1551, "final_rank": 9 }, { "submission_id": "aoj_1222_2340418", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define int long long\nstruct Point{\n double x,y;\n Point(){}\n Point(double x,double y):x(x),y(y){}\n Point operator+(Point a){return Point(x+a.x,y+a.y);}\n Point operator-(Point a){return Point(x-a.x,y-a.y);}\n Point operator*(double k){return Point(x*k,y*k);}\n Point operator/(double k){return Point(x/k,y/k);}\n};\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\ndouble norm(Point a){\n return a.x*a.x+a.y*a.y;\n}\ndouble abs(Point a){\n return sqrt(norm(a));\n}\ndouble dot(Point a,Point b){\n return a.x*b.x+a.y*b.y;\n}\ndouble cross(Point a,Point b){\n return a.x*b.y-a.y*b.x;\n}\nconst double PI=3.141592653589793238;\nPoint trans(double k){\n return Point(cos(k*2*PI),sin(k*2*PI));\n}\nint n,m;\nPolygon p;\ndouble dp[50][50][50];\ndouble dfs(int b,int c,int d){\n if(d==m) return 0;\n if(dp[b][c][d]>=0) return dp[b][c][d];\n double res=0;\n for(int a=c;a!=b;a=(a+1)%n){\n res=max(res,dfs(b,a,d+1)+abs(cross(p[a]-p[b],p[c]-p[b])));\n }\n return dp[b][c][d]=res;\n}\nsigned main(){\n while(cin>>n>>m,n||m){\n p.clear();\n p.resize(n);\n for(int i=0;i<n;i++){\n double k;\n cin>>k;\n p[i]=trans(k);\n //cout<<p[i].x<<\" \"<<p[i].y<<endl;\n }\n for(int i=0;i<50;i++)\n for(int j=0;j<50;j++)\n\tfor(int k=0;k<50;k++)\n\t dp[i][j][k]=-1;\n double ans=0;\n for(int i=0;i<n;i++){\n for(int j=0;j<n;j++){\n\tif(i==j) continue;\n\tans=max(ans,dfs(i,j,2));\n }\n }\n printf(\"%.6f\\n\",ans/2.0);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 4396, "score_of_the_acc": -0.2582, "final_rank": 13 }, { "submission_id": "aoj_1222_1977735", "code_snippet": "#include <vector>\n#include <list>\n#include <map>\n#include <set>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <algorithm>\n#include <functional>\n#include <numeric>\n#include <utility>\n#include <sstream>\n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <cmath>\n#include <cstdlib>\n#include <cctype>\n#include <string>\n#include <cstring>\nusing namespace std;\n#define REP(i,n) for(int i = 0; i < (int)n; i++)\n#define FOR(i,a,b) for(int i = a; i < (int)b; i++)\n#define pb push_back\n#define mp make_pair\ntypedef vector<int> vi;\ntypedef pair<int, int> pi;\ntypedef long long ll;\nconst int INF = 1<<28;\nconst ll MOD = 1000000007;\nconst int dx[] = {1, 0, -1, 0}, dy[] = {0, 1, 0, -1};\n\ndouble area(double a, double b, double c) {\n\treturn sin((b-a)*2*M_PI)/2 + sin((c-b)*2*M_PI)/2 + sin((a-c)*2*M_PI)/2;\n}\n\nint main() {\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0);\n\n\tint n, m;\n\twhile(cin >> n >> m, n|m) {\n\t\tdouble dp[40][40][40] = {};\n\t\tdouble p[n];\n\t\tREP(i, n)\n\t\t\tcin >> p[i];\n\t\tREP(i, m-2) {\n\t\t\tREP(j, n-2) {\n\t\t\t\tFOR(k, j+2, n) {\n\t\t\t\t\tFOR(l, j+1, k) {\n\t\t\t\t\t\tif(i)\n\t\t\t\t\t\t\tdp[i][j][k] = max(dp[i][j][k], dp[i-1][j][l] + area(p[j], p[l], p[k]));\n\t\t\t\t\t\telse\n\t\t\t\t\t\t\tdp[i][j][k] = max(dp[i][j][k], area(p[j], p[l], p[k]));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tdouble ans = -1;\n\t\tREP(i, n) REP(j, n)\n\t\t\tans = max(ans, dp[m-3][i][j]);\n\t\tcout << fixed << setprecision(6) << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 1864, "score_of_the_acc": -0.188, "final_rank": 12 }, { "submission_id": "aoj_1222_1876158", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define MAX 45\n#define PI acos(-1)\n#define INF (1<<29)\ntypedef pair<double, double> P;\n\nint N, M;\ndouble memo[MAX][MAX][MAX];\nvector<double> x, y;\n\ndouble area(int a, int b, int c)\n{\n vector<P> p(3);\n p[0] = P(x[a], y[a]);\n p[1] = P(x[b], y[b]);\n p[2] = P(x[c], y[c]); \n \n double res = 0;\n for (int i = 1; i < 4; i++) {\n\tres += (p[i%3].first - p[i-1].first) * (p[i%3].second + p[i-1].second);\n }\n res /= 2.0;\n return abs(res);\n}\n\ndouble get_max_area(int L, int R, int m)\n{\n if (m == M) {\n return 0;\n } \n double &res = memo[L][R][m];\n if (res != -1) {\n return res;\n }\n for (int i = R+1; i < N; i++) {\n res = max(res, get_max_area(L, i, m+1) + area(L, R, i));\n }\n return res;\n}\n\nint main()\n{\n double p;\n while (cin >> N >> M, N) {\n x.clear(); y.clear();\n x.resize(N); y.resize(N);\n for (int i = 0; i < N; i++) {\n cin >> p;\n p *= (2.0 * PI);\n x[i] = cos(p); y[i] = sin(p);\n }\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n for (int k = 0; k < N; k++) {\n memo[i][j][k] = -1;\n }\n }\n }\n\n double mx = 0;\n for (int i = 0; i < N; i++) {\n for (int j = i+1; j < N; j++) {\n for (int k = j+1; k < N; k++) {\n mx = max(mx, get_max_area(i, k, 3) + area(i, j, k));\n }\n }\n }\n printf(\"%.6f\\n\", mx);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4076, "score_of_the_acc": -0.1508, "final_rank": 6 }, { "submission_id": "aoj_1222_1751496", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i,a,b) for(int i=a;i<(int)b;i++)\n#define rep(i,n) REP(i,0,n)\n\n///double dp[44][44];\nvector<double> ps;\nint N, M;\n\ndouble const pi = acos(-1);\n\ndouble triangle(int s, int t, int k) {\n vector<int> idxs = {s, t, k};\n sort(idxs.begin(), idxs.end());\n\n double a = 2 * pi * ps[idxs[0]];\n double b = 2 * pi * ps[idxs[1]];\n double c = 2 * pi * ps[idxs[2]];\n\n double ba = b - a;\n double cb = c - b;\n double ac = a - c;\n\n while(ba < 0) { ba += 2 * pi; }\n while(cb < 0) { cb += 2 * pi; }\n while(ac < 0) { ac += 2 * pi; }\n\n return (sin(ba) + sin(cb) + sin(ac)) / 2.0;\n}\n\nint st;\nmap<pair<int, int>, double> mp;\n\ndouble dfs(int curr, int rem) {\n if(rem == 0) { return 0.0; }\n if(N + st - curr + 1 <= 1) { return -100000000; }\n if(mp.find({curr, rem}) != mp.end()) { return mp[{curr, rem}]; }\n auto& ret = mp[{curr, rem}];\n\n REP(i, curr + 1, N + st) {\n double d = triangle(st % N, curr % N, i % N);\n d += dfs(i, rem-1);\n ret = max(ret, d);\n }\n return ret;\n}\n\nint main() {\n\n for(;cin >> N >> M && (N|M);) {\n ps.clear();\n ps.resize(N);\n rep(i, N) cin >> ps[i];\n sort(ps.begin(), ps.end());\n double ans = -10000000000;\n rep(i, N) {\n mp.clear();\n st = i;\n ans = max(ans, dfs(i, M-1));\n }\n\n printf(\"%.6f\\n\", ans);\n\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 720, "memory_kb": 3592, "score_of_the_acc": -0.6971, "final_rank": 17 }, { "submission_id": "aoj_1222_1751313", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef pair<double,double> P;\ndouble S(double a,double b,double c) {\n double s=(a+b+c)/2;\n return sqrt(s*(s-a)*(s-b)*(s-c));\n}\ndouble D(P a,P b) {\n return sqrt((a.first-b.first)*(a.first-b.first)+(a.second-b.second)*(a.second-b.second));\n}\ndouble calc(P a,P b, P c) {\n return S(D(a,b),D(a,c),D(b,c));\n}\n \ndouble toRad(double agl) {\n return agl*M_PI/180.0;\n}\nP Q(double e) {\n double w=toRad(360*e);\n return P(sin(w),cos(w));\n}\n\nint main() {\n int n,m;\n while(cin >> n >> m && n) {\n P p[n];\n for(int i=0; i<n; i++) {\n double x;\n cin >> x;\n p[i]=Q(x);\n }\n double ans=0;\n for(int i=0; i<n; i++) {\n double dp[n][m+1];\n for(int j=0;j<n;j++)for(int k=0;k<=m;k++)dp[j][k]=-1; \n for(int j=i+1; j<n; j++) dp[j][2]=0;\n for(int j=i+1; j<n; j++) {\n for(int k=2; k<m; k++) {\n if(dp[j][k]<0) continue;\n for(int l=j+1; l<n; l++) {\n dp[l][k+1]=max(dp[l][k+1],dp[j][k]+calc(p[i],p[j],p[l]));\n if(k+1==m) ans=max(ans,dp[l][k+1]);\n }\n }\n } \n }\n printf(\"%.6f\\n\",ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 1256, "score_of_the_acc": -0.0254, "final_rank": 1 }, { "submission_id": "aoj_1222_1751304", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef complex<double> P;\n\ndouble dp[41][41][41][41];\ndouble getA[41][41][41];\nint nx[41];\nconst double INF = 1e100;\n\ndouble cross( P a, P b ){ return a.real() * b.imag() - a.imag() * b.real(); }\n\nint N,M;\n\nP getpos(double p){\n double a = 2*M_PI*p;\n return P( cos(a), sin(a) );\n}\n\nvoid init(const vector<P> pos){\n for(int i=0;i<N;i++) nx[i] = (i+1)%N;\n for(int i=0;i<N;i++)\n for(int j=0;j<N;j++)\n for(int k=0;k<N;k++)\n for(int l=0;l<=M;l++)\n dp[i][j][k][l] = -1.0;\n\n for(int i=0;i<N;i++)\n for(int j=0;j<N;j++)\n for(int k=0;k<N;k++)\n getA[i][j][k] = cross( pos[j]-pos[i], pos[k]-pos[i] )/2.0;\n \n}\n\n\ndouble solve(int a,int b,int c,int m){\n if( abs(dp[a][b][c][m]+1.0) > 0.5 ) return dp[a][b][c][m];\n if( m == M ) return dp[a][b][c][m] = 0.0;\n if( c == a ) return dp[a][b][c][m] = -INF;\n int nc = nx[c];\n return dp[a][b][c][m] = max( solve( a, c, nc, m+1 ) + getA[a][b][c],\n solve( a, b, nc, m ) ); \n}\n\nint main(){\n while( cin >> N >> M && (N||M) ){\n vector<P> pos;\n for(int i=0;i<N;i++){\n double p; cin >> p;\n pos.push_back( getpos(p) );\n }\n init(pos);\n double res = 0.0;\n for(int i=0;i<N;i++){\n for(int j=0;j<N;j++){\n if( i == j ) continue;\n res = max( res, solve( i, j, nx[j], 2 ) );\n }\n }\n printf(\"%.6lf\\n\",res);\n }\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 23748, "score_of_the_acc": -1.0763, "final_rank": 19 }, { "submission_id": "aoj_1222_1751295", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef complex<double> P;\n#define MAX_N 45\ndouble PI = acos(-1.0);\ndouble INF = 1e9;\n\nint n,m;\nP t[MAX_N];\ndouble dp[MAX_N][MAX_N];\n\ndouble calc(P s,P t){\n return imag(t*conj(s))/2.0;\n}\n\ndouble solve(int si){\n P a[MAX_N];\n for(int i=0;i<n;i++){\n a[i]=t[(i+si)%n];\n }\n\n for(int i=0;i<MAX_N;i++)\n for(int j=0;j<MAX_N;j++)\n\tdp[i][j]=-INF;\n dp[0][1]=0;\n\n double res=0;\n\n for(int i=0;i<n;i++){\n for(int j=1;j<m;j++){\n for(int k=i+1;k<n;k++){\n\tdp[k][j+1]=max(dp[k][j+1],dp[i][j]+calc(a[i],a[k]));\n }\n }\n res=max(res, dp[i][m]+calc(a[i],a[0]));\n }\n return res;\n}\n\nint main(){\n while(1){\n cin>>n>>m;\n if(n==0&&m==0)break;\n for(int i=0;i<n;i++){\n double d;\n cin>>d;\n t[i]=P(cos(d*2.0*PI),sin(d*2.0*PI));\n }\n double ans=0;\n for(int i=0;i<n;i++)ans=max(ans,solve(i));\n printf(\"%.6f\\n\",ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 1276, "score_of_the_acc": -0.0433, "final_rank": 2 } ]
aoj_1226_cpp
Problem C: Fishnet A fisherman named Etadokah awoke in a very small island. He could see calm, beautiful and blue sea around the island. The previous night he had encountered a terrible storm and had reached this uninhabited island. Some wrecks of his ship were spread around him. He found a square wood-frame and a long thread among the wrecks. He had to survive in this island until someone came and saved him. In order to catch fish, he began to make a kind of fishnet by cutting the long thread into short threads and fixing them at pegs on the square wood-frame (Figure 1). He wanted to know the sizes of the meshes of the fishnet to see whether he could catch small fish as well as large ones. The wood-frame is perfectly square with four thin edges one meter long.. a bottom edge, a top edge, a left edge, and a right edge. There are n pegs on each edge, and thus there are 4 n pegs in total. The positions ofpegs are represented by their ( x , y )-coordinates. Those of an example case with n = 2 are depicted in Figures 2 and 3. The position of the i th peg on the bottom edge is represented by ( a i , 0) . That on the top edge, on the left edge and on the right edge are represented by ( b i , 1) , (0, c i ), and (1, d i ), respectively. The long thread is cut into 2 n threads with appropriate lengths. The threads are strained between ( a i , 0) and ( b i , 1) , and between (0, c i ) and (1, d i ) ( i = 1,..., n ) . You should write a program that reports the size of the largest mesh among the ( n + 1) 2 meshes of the fishnet made by fixing the threads at the pegs. You may assume that the thread he found is long enough to make the fishnet and that the wood-frame is thin enough for neglecting its thickness. Figure 1. A wood-frame with 8 pegs. Figure 2. Positions of pegs (indicated by small black circles) Figure 3. A fishnet and the largest mesh (shaded) Input The input consists of multiple subproblems followed by a line containing a zero that indicates the end of input. Each subproblem is given in the following format. n a 1 a 2 ... a n b 1 b 2 ... b n c 1 c 2 ... c n d 1 d 2 ... d n An integer n followed by a newline is the number of pegs on each edge. a 1 ,..., a n , b 1 ,..., b n , c 1 ,..., c n , d 1 ,..., d n are decimal fractions, and they are separated by a space character except that a n , b n , c n and d n are followed by a new line. Each a i ( i = 1,..., n ) indicates the x -coordinate of the i th peg on the bottom edge. Each b i ( i = 1,..., n ) indicates the x -coordinate of the i th peg on the top edge. Each c i ( i = 1,..., n ) indicates the y -coordinate of the i th peg on the left edge. Each d i ( i = 1,..., n ) indicates the y -coordinate of the i th peg on the right edge. The decimal fractions are represented by 7 digits after the decimal point. In addition you may assume that 0 < n ≤ 30 , 0 < a 1 < a 2 < ... < a n < 1, 0 < b 1 < b 2 < ... < b n < 1 , 0 < c 1 < c 2 < ... < c n < 1 and 0 < d 1 ≤ d 2 < ... < d n < 1 . Output For each subpr ...(truncated)
[ { "submission_id": "aoj_1226_3043409", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <complex>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <array>\nusing namespace std;\nconst double EPS = 1e-10;\nconst double INF = 1e12;\n#define EQ(n,m) (abs((n)-(m)) < EPS)\n#define X real()\n#define Y imag()\n\ntypedef complex<double> P;\ntypedef vector<P> VP;\nstruct L : array<P, 2>{\n L(const P& a, const P& b){ at(0)=a; at(1)=b; }\n L(){}\n};\n\nnamespace std{\n bool operator < (const P& a, const P& b){\n return !EQ(a.X,b.X) ? a.X<b.X : a.Y+EPS<b.Y;\n }\n bool operator == (const P& a, const P& b){\n return abs(a-b) < EPS;\n }\n}\n\ndouble dot(P a, P b){\n return (conj(a)*b).X;\n}\ndouble cross(P a, P b){\n return (conj(a)*b).Y;\n}\nint ccw(P a, P b, P c){\n b -= a;\n c -= a;\n if(cross(b,c) > EPS) return +1; //ccw\n if(cross(b,c) < -EPS) return -1; //cw\n if(dot(b,c) < -EPS) return +2; //c-a-b\n if(abs(c)-abs(b) > EPS) return -2; //a-b-c\n return 0; //a-c-b\n}\n\nP crosspointLL(const L &l, const L &m) {\n double A = cross(l[1]-l[0], m[1]-m[0]);\n double B = cross(l[1]-l[0], l[1]-m[0]);\n return m[0] + B/A *(m[1]-m[0]);\n}\ndouble getarea(const VP &poly){\n double ret = 0;\n for (int i=0; i<(int)poly.size(); i++){ \n ret += cross(poly[i], poly[(i+1)%poly.size()]);\n }\n return ret*0.5;\n}\nVP convex_cut(const VP& p, const L& l){\n VP ret;\n int n = p.size();\n for(int i=0; i<n; i++){\n P curr = p[i];\n P next = p[(i+1)%n];\n if(ccw(l[0], l[1], curr) != -1) ret.push_back(curr);\n if(ccw(l[0], l[1], curr) *ccw(l[0], l[1], next) == -1){\n ret.push_back(crosspointLL(L(curr, next), l));\n }\n }\n return ret;\n}\n\n\nint main(){\n while(1){\n int n;\n cin >> n;\n if(n==0) break;\n\n double in;\n VP a(n+2),b(n+2),c(n+2),d(n+2);\n for(int i=1; i<=n; i++){ cin >> in; a[i] = P(in, 0); }\n for(int i=1; i<=n; i++){ cin >> in; b[i] = P(in, 1); }\n for(int i=1; i<=n; i++){ cin >> in; c[i] = P(0, in); }\n for(int i=1; i<=n; i++){ cin >> in; d[i] = P(1, in); }\n VP sq{P(0,0),P(1,0),P(1,1),P(0,1)};\n a[0] = c[0] = sq[0];\n a[n+1] = d[0] = sq[1];\n b[n+1] = d[n+1] = sq[2];\n b[0] = c[n+1] = sq[3];\n\n double ans = 0;\n for(int i=0; i<n+1; i++){\n for(int j=0; j<n+1; j++){\n L cut[4] = {L(b[i], a[i]), L(a[i+1], b[i+1]), L(c[j], d[j]), L(d[j+1], c[j+1])};\n VP poly = sq;\n for(int t=0; t<4; t++){\n poly = convex_cut(poly, cut[t]);\n }\n ans = max(ans, getarea(poly));\n }\n }\n cout << fixed << setprecision(6);\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3296, "score_of_the_acc": -0.9258, "final_rank": 5 }, { "submission_id": "aoj_1226_2669485", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\n\n\n/* 幾何の基本 */\n\n#include <complex>\n\ntypedef complex<ld> Point;\n\n\nconst ld pi = acos(-1.0);\nconst ld dtop = pi / 180.;\nconst ld ptod = 1. / dtop;\n\nnamespace std {\n\tbool operator<(const Point &lhs, const Point &rhs) {\n\t\tif (lhs.real() < rhs.real() - eps) return true;\n\t\tif (lhs.real() > rhs.real() + eps) return false;\n\t\treturn lhs.imag() < rhs.imag();\n\t}\n}\n\n// 点の入力\nPoint input_Point() {\n\tld x, y;\n\tcin >> x >> y;\n\treturn Point(x, y);\n}\n\n// 誤差つき等号判定\nbool eq(const ld a, const ld b) {\n\treturn (abs(a - b) < eps);\n}\n\n// 内積\nld dot(const Point& a, const Point& b) {\n\treturn real(conj(a) * b);\n}\n\n// 外積\nld cross(const Point& a, const Point& b) {\n\treturn imag(conj(a) * b);\n}\n\n// 直線の定義\nclass Line {\npublic:\n\tPoint a, b;\n\tLine() : a(Point(0, 0)), b(Point(0, 0)) {}\n\tLine(Point a, Point b) : a(a), b(b) {}\n\tPoint operator[](const int _num)const {\n\t\tif (_num == 0)return a;\n\t\telse if (_num == 1)return b;\n\t\telse {\n\t\t\tassert(false);\n\t\t\treturn Point();\n\t\t}\n\t}\n};\n\n// 円の定義\nclass Circle {\npublic:\n\tPoint p;\n\tld r;\n\tCircle() : p(Point(0, 0)), r(0) {}\n\tCircle(Point p, ld r) : p(p), r(r) {}\n};\n\n// ccw\n// 1: a,b,cが反時計周りの順に並ぶ\n//-1: a,b,cが時計周りの順に並ぶ\n// 2: c,a,bの順に直線に並ぶ\n//-2: a,b,cの順に直線に並ぶ\n// 0: a,c,bの順に直線に並ぶ\nint ccw(const Point& a, const Point &b, const Point &c) {\n\tconst Point nb(b - a);\n\tconst Point nc(c - a);\n\tif (cross(nb, nc) > eps) return 1; // a,b,cが反時計周りの順に並ぶ\n\tif (cross(nb, nc) < -eps) return -1; // a,b,cが時計周りの順に並ぶ\n\tif (dot(nb, nc) < 0) return 2; // c,a,bの順に直線に並ぶ\n\tif (norm(nb) < norm(nc)) return -2; // a,b,cの順に直線に並ぶ\n\treturn 0; // a,c,bの順に直線に並ぶ\n}\n\n\n/* 交差判定 */\n\n// 直線と直線の交差判定\nbool isis_ll(const Line& l, const Line& m) {\n\treturn !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\n\n// 直線と線分の交差判定\nbool isis_ls(const Line& l, const Line& s) {\n\treturn isis_ll(l, s) &&\n\t\t(cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < eps);\n}\n\n// 線分と線分の交差判定\nbool isis_ss(const Line& s, const Line& t) {\n\treturn ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n\t\tccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\n// 点の直線上判定\nbool isis_lp(const Line& l, const Point& p) {\n\treturn (abs(cross(l.b - p, l.a - p)) < eps);\n}\n\n// 点の線分上判定\nbool isis_sp(const Line& s, const Point& p) {\n\treturn (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n\n// 垂線の足\nPoint proj(const Line &l, const Point& p) {\n\tld t = dot(p - l.a, l.b - l.a) / norm(l.a - l.b);\n\treturn l.a + t * (l.b - l.a);\n}\n\n//線対象の位置にある点\nPoint reflect(const Line &l, const Point &p) {\n\tPoint pr = proj(l, p);\n\treturn pr * 2.l - p;\n}\n\n// 直線と直線の交点\nPoint is_ll(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tassert(cross(sv, tv) != 0);\n\treturn s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n// 直線と直線の交点\nvector<Point> is_ll2(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tif (cross(sv, tv) != 0)return vector<Point>(1, is_ll(s, t));\n\telse {\n\t\tvector<Point>ans;\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tif (isis_sp(s, t[k]) && find(ans.begin(), ans.end(), t[k]) == ans.end())ans.push_back(t[k]);\n\t\t\tif (isis_sp(t, s[k]) && find(ans.begin(), ans.end(), s[k]) == ans.end())ans.push_back(s[k]);\n\t\t}\n\t\treturn ans;\n\t}\n}\n// 線分と線分の交点\n// 重なってる部分あるとassert(false)\nPoint is_ss(const Line &s, const Line& t) {\n\tif (isis_ss(s, t)) {\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tfor (int l = 0; l < 2; ++l) {\n\t\t\t\tif (s[k] == t[l])return s[k];\n\t\t\t}\n\t\t}\n\t\treturn is_ll(s, t);\n\t}\n\telse {\n\t\t//先にisis_ssしてね\n\t\tassert(false);\n\t\treturn Point(0, 0);\n\t}\n}\n// 線分と線分の交点\nvector<Point> is_ss2(const Line &s, const Line& t) {\n\tvector<Point> kouho(is_ll2(s, t));\n\tvector<Point>ans;\n\tfor (auto p : kouho) {\n\t\tif (isis_sp(s, p) && isis_sp(t, p))ans.emplace_back(p);\n\t}\n\treturn ans;\n}\n// 直線と点の距離\nld dist_lp(const Line& l, const Point& p) {\n\treturn abs(p - proj(l, p));\n}\n\n//直線と直線の距離\nld dist_ll(const Line& l, const Line& m) {\n\treturn isis_ll(l, m) ? 0 : dist_lp(l, m.a);\n}\n\n// 直線と線分の距離\nld dist_ls(const Line& l, const Line& s) {\n\treturn isis_ls(l, s) ? 0 : min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\n\n// 線分と点の距離\nld dist_sp(const Line& s, const Point& p) {\n\tPoint r = proj(s, p);\n\treturn isis_sp(s, r) ? abs(r - p) : min(abs(s.a - p), abs(s.b - p));\n}\n\n// 線分と線分の距離\nld dist_ss(const Line& s, const Line& t) {\n\tif (isis_ss(s, t)) return 0;\n\treturn min({ dist_sp(s, t.a), dist_sp(s, t.b), dist_sp(t, s.a), dist_sp(t, s.b) });\n}\n\n\n//直線と直線の二等分線のベクトル\nLine line_bisection(const Line &s, const Line &t) {\n\tconst Point laglanju(is_ll(s, t));\n\tconst Point avec = !(abs(laglanju - s[0])<eps) ? s[0] - laglanju : s[1] - laglanju;\n\tconst Point bvec = !(abs(laglanju - t[0])<eps) ? t[0] - laglanju : t[1] - laglanju;\n\n\treturn Line(laglanju, laglanju + (abs(bvec)*avec + abs(avec)*bvec) / (abs(avec) + abs(bvec)));\n}\n//点と点の垂直二等分線 aを左に見ながら\nLine point_bisection(const Point&a, const Point&b) {\n\tconst Point cen((a + b) / 2.l);\n\tconst Point vec = (b - a)*Point(0, 1);\n\treturn Line(cen, cen + vec);\n}\n\n//三つの点からなる外心\nPoint outer_center(const vector<Point>&ps) {\n\tassert(ps.size() == 3);\n\tLine l1 = point_bisection(ps[0], ps[1]);\n\tLine l2 = point_bisection(ps[1], ps[2]);\n\treturn is_ll(l1, l2);\n}\n\n\n//三つの直線からなる内心\n//三つの直線が並行でないことは確かめといてね\nPoint inner_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i <static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (vertics[0] == vertics[1] || vertics[1] == vertics[2] || vertics[2] == vertics[0])return vertics[0];\n\tLine bi1(line_bisection(Line(vertics[0], vertics[1]), Line(vertics[0], vertics[2])));\n\tLine bi2(line_bisection(Line(vertics[1], vertics[2]), Line(vertics[1], vertics[0])));\n\tif (bi1[0] == bi2[0])return bi1[0];\n\telse {\n\t\treturn is_ll(bi1, bi2);\n\t}\n}\n\n//三つの直線からなる傍心\n//三つの直線が並行でないことは確かめといてね\nvector<Point> ex_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i < static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (abs(vertics[0] - vertics[1])<eps || abs(vertics[1] - vertics[2])<eps || (abs(vertics[2] - vertics[0])<eps))return vector<Point>();\n\tvector<Point>ecs;\n\tfor (int i = 0; i < 3; ++i) {\n\t\tLine bi1(line_bisection(Line(vertics[i], vertics[i] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[i], vertics[(i + 1) % 3])));\n\t\tLine bi2(line_bisection(Line(vertics[(i + 1) % 3], vertics[(i + 1) % 3] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[(i + 1) % 3], vertics[i])));\n\t\tecs.push_back(is_ll(bi1, bi2));\n\t}\n\treturn ecs;\n}\n\n\n//a,b:並行\n//c:並行でない\n//三つの直線から同距離の位置を求める。\nvector<Point> same_dis(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tvertics.push_back(is_ll(ls[0], ls[2]));\n\tvertics.push_back(is_ll(ls[1], ls[2]));\n\n\tif (abs(vertics[0] - vertics[1]) < eps)return vector<Point>{vertics[0]};\n\tLine bis(line_bisection(ls[0], ls[1]));\n\tvector<Point>ecs;\n\n\tLine abi(line_bisection(Line(vertics[0], vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, abi));\n\n\n\tLine bbi(line_bisection(Line(vertics[0], 2.l*vertics[0] - vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, bbi));\n\n\treturn ecs;\n}\n/* 円 */\n\n// 円と円の交点\nvector<Point> is_cc(const Circle& c1, const Circle& c2) {\n\tvector<Point> res;\n\tld d = abs(c1.p - c2.p);\n\tld rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n\tld dfr = c1.r * c1.r - rc * rc;\n\tif (abs(dfr) < eps) dfr = 0.0;\n\telse if (dfr < 0.0) return res; // no intersection\n\tld rs = sqrt(dfr);\n\tPoint diff = (c2.p - c1.p) / d;\n\tres.push_back(c1.p + diff * Point(rc, rs));\n\tif (dfr != 0.0) res.push_back(c1.p + diff * Point(rc, -rs));\n\treturn res;\n}\n\n/*\n点が円の中にいるか\n0 => out\n1 => on\n2 => in*/\nint is_in_Circle(const Point& p, const Circle &cir) {\n\tld dis = abs(cir.p - p);\n\tif (dis > cir.r + eps)return 0;\n\telse if (dis < cir.r - eps)return 2;\n\telse return 1;\n}\nint is_in_Circle(const Circle &cir, const Point& p) {\n\tld dis = abs(cir.p - p);\n\tif (dis > cir.r + eps)return 0;\n\telse if (dis < cir.r - eps)return 2;\n\telse return 1;\n}\n/*\n円lcが円rcの中にいるか\n0 => out\n1 => on\n2 => in*/\nint Circle_in_Circle(const Circle &lc, const Circle&rc) {\n\tld dis = abs(lc.p - rc.p);\n\tif (dis < rc.r - lc.r - eps)return 2;\n\telse if (dis>rc.r - lc.r + eps)return 0;\n\telse return 1;\n}\n\n// 円と直線の交点\nvector<Point> is_lc(const Circle& c, const Line& l) {\n\tvector<Point> res;\n\tld d = dist_lp(l, c.p);\n\tif (d < c.r + eps) {\n\t\tld len = (d > c.r) ? 0.0 : sqrt(c.r * c.r - d * d); //safety;\n\t\tPoint nor = (l.a - l.b) / abs(l.a - l.b);\n\t\tres.push_back(proj(l, c.p) + len * nor);\n\t\tres.push_back(proj(l, c.p) - len * nor);\n\t}\n\treturn res;\n}\n\n// 円と線分の距離\nvector<Point> is_sc(const Circle& c, const Line& l) {\n\tvector<Point> v = is_lc(c, l), res;\n\tfor (Point p : v)\n\t\tif (isis_sp(l, p)) res.push_back(p);\n\treturn res;\n}\n\n// 円と点の接線\nvector<Line> tangent_cp(const Circle& c, const Point& p) {\n\tvector<Line> ret;\n\tPoint v = c.p - p;\n\tld d = abs(v);\n\tld l = sqrt(norm(v) - c.r * c.r);\n\tif (isnan(l)) { return ret; }\n\tPoint v1 = v * Point(l / d, c.r / d);\n\tPoint v2 = v * Point(l / d, -c.r / d);\n\tret.push_back(Line(p, p + v1));\n\tif (l < eps) return ret;\n\tret.push_back(Line(p, p + v2));\n\treturn ret;\n}\n\n// 円と円の接線\nvector<Line> tangent_cc(const Circle& c1, const Circle& c2) {\n\tvector<Line> ret;\n\tif (abs(c1.p - c2.p) - (c1.r + c2.r) > -eps) {\n\t\tPoint center = (c1.p * c2.r + c2.p * c1.r) / (c1.r + c2.r);\n\t\tret = tangent_cp(c1, center);\n\t}\n\tif (abs(c1.r - c2.r) > eps) {\n\t\tPoint out = (-c1.p * c2.r + c2.p * c1.r) / (c1.r - c2.r);\n\t\tvector<Line> nret = tangent_cp(c1, out);\n\t\tret.insert(ret.end(), nret.begin(), nret.end());\n\t}\n\telse {\n\t\tPoint v = c2.p - c1.p;\n\t\tv /= abs(v);\n\t\tPoint q1 = c1.p + v * Point(0, 1) * c1.r;\n\t\tPoint q2 = c1.p + v * Point(0, -1) * c1.r;\n\t\tret.push_back(Line(q1, q1 + v));\n\t\tret.push_back(Line(q2, q2 + v));\n\t}\n\treturn ret;\n}\n//二つの円の重なり面積\nld two_Circle_area(const Circle&l, const Circle&r) {\n\tld dis = abs(l.p - r.p);\n\tif (dis > l.r + r.r)return 0;\n\telse if (dis + r.r < l.r) {\n\t\treturn r.r*r.r*pi;\n\t}\n\telse if (dis + l.r < r.r) {\n\t\treturn l.r*l.r*pi;\n\t}\n\telse {\n\t\tld ans = (l.r)*(l.r)*acos((dis*dis + l.r*l.r - r.r*r.r) / (2 * dis*l.r)) +\n\t\t\t(r.r)*(r.r)*acos((dis*dis + r.r*r.r - l.r*l.r) / (2 * dis*r.r)) -\n\t\t\tsqrt(4 * dis*dis*l.r*l.r - (dis*dis + l.r*l.r - r.r*r.r)*(dis*dis + l.r*l.r - r.r*r.r)) / 2;\n\t\treturn ans;\n\t}\n\n}\n\n/* 多角形 */\n\ntypedef vector<Point> Polygon;\n\n\n\n//多角形(複数の点)の最小包含円をO(N=頂点数)で求めるアルゴリズム\n//同一直線上に三つの点がないこと\n#include<random>\nCircle welzl(vector<Point>ps) {\n\tstruct solver {\n\t\tCircle solve(vector<Point>&ps, vector<Point>&rs) {\n\t\t\tif (ps.empty() || rs.size() == 3) {\n\t\t\t\tif (rs.size() == 1) {\n\t\t\t\t\treturn Circle(Point(rs[0]), 0);\n\t\t\t\t}\n\t\t\t\telse if (rs.size() == 2) {\n\t\t\t\t\treturn Circle((rs[0] + rs[1]) / 2.0l, abs(rs[1] - rs[0]) / 2);\n\t\t\t\t}\n\t\t\t\telse if (rs.size() == 3) {\n\t\t\t\t\tvector<Line> ls(3);\n\t\t\t\t\tfor (int i = 0; i < 3; ++i) {\n\t\t\t\t\t\tls[i] = Line(rs[i], rs[(i + 1) % 3]);\n\t\t\t\t\t}\n\t\t\t\t\tPoint center = outer_center(rs);\n\t\t\t\t\treturn Circle(center, abs(center - rs[0]));\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\treturn Circle(Point(), 0);\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\n\t\t\t\tPoint p_ba = ps.back();\n\t\t\t\tps.pop_back();\n\t\t\t\tCircle d = solve(ps, rs);\n\t\t\t\tps.push_back(p_ba);\n\t\t\t\tif (is_in_Circle(d, p_ba)) {\n\t\t\t\t\treturn d;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\trs.push_back(p_ba);\n\t\t\t\t\tps.pop_back();\n\t\t\t\t\tauto ans = solve(ps, rs);\n\t\t\t\t\tps.push_back(p_ba);\n\t\t\t\t\trs.pop_back();\n\t\t\t\t\treturn ans;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}so;\n\tstd::random_device rd;\n\tstd::mt19937 mt(rd());\n\tshuffle(ps.begin(), ps.end(), mt);\n\tvector<Point>rs;\n\tCircle ans = so.solve(ps, rs);\n\treturn ans;\n}\n// 面積\nld get_area(const Polygon &p) {\n\tld res = 0;\n\tint n = p.size();\n\tfor (int j = 0; j<n; ++j) res += cross(p[j], p[(j + 1) % n]);\n\treturn res / 2;\n}\n\n//多角形の回転方向\nbool is_counter_clockwise(const Polygon &poly) {\n\tld angle = 0;\n\tint n = poly.size();\n\tfor(int i=0;i<n;++i) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n], c = poly[(i + 2) % n];\n\t\tangle += arg((c - b) / (b - a));\n\t}\n\treturn angle > eps;\n}\n\n// 円の内外判定\n/*0 => out\n1 => on\n2 => in*/\nint is_in_Polygon(const Polygon &poly, const Point& p) {\n\tld angle = 0;\n\tint n = poly.size();\n\tfor(int i=0;i<n;++i) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n];\n\t\tif (isis_sp(Line(a, b), p)) return 1;\n\t\tangle += arg((b - p) / (a - p));\n\t}\n\treturn eq(angle, 0) ? 0 : 2;\n}\n//円の内外判定2 高速\nenum { out, on, in };\nint convex_contains(const Polygon &P, const Point &p) {\n\tconst int n = P.size();\n\tPoint g = (P[0] + P[n / 3] + P[2 * n / 3]) / 3.0l; // inner-point\n\tint a = 0, b = n;\n\twhile (a + 1 < b) { // invariant: c is in fan g-P[a]-P[b]\n\t\tint c = (a + b) / 2;\n\t\tif (cross(P[a] - g, P[c] - g) > 0) { // angle < 180 deg\n\t\t\tif (cross(P[a] - g, p - g) > 0 && cross(P[c] - g, p - g) < 0) b = c;\n\t\t\telse a = c;\n\t\t}\n\t\telse {\n\t\t\tif (cross(P[a] - g, p - g) < 0 && cross(P[c] - g, p - g) > 0) a = c;\n\t\t\telse b = c;\n\t\t}\n\t}\n\tb %= n;\n\tif (cross(P[a] - p, P[b] - p) < 0) return 0;\n\tif (cross(P[a] - p, P[b] - p) > 0) return 2;\n\treturn 1;\n}\n\n// 凸包\n//点や線を返すことも有り得るので注意\nPolygon convex_hull(vector<Point> ps) {\n\tint n = ps.size();\n\tint k = 0;\n\tsort(ps.begin(), ps.end());\n\tPolygon ch(2 * n);\n\tfor (int i = 0; i < n; ch[k++] = ps[i++])\n\t\twhile (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tfor (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--])\n\t\twhile (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tch.resize(k - 1);\n\treturn ch;\n}\n\n\n\n//凸カット\nvector<Polygon> convex_cut(const Polygon &ps, const Line& l) {\n\tint n = ps.size();\n\tPolygon q;\n\tPolygon r;\n\tfor(int i=0;i<n;++i) {\n\t\tPoint a = ps[i], b = ps[(i + 1) % n];\n\t\tLine m = Line(a, b);\n\t\tif (ccw(l.a, l.b, a) != -1) q.push_back(a);\n\t\tif (ccw(l.a, l.b, a) != 1) r.push_back(a);\n\t\tif (ccw(l.a, l.b, a) * ccw(l.a, l.b, b) < 0 && isis_ll(l, m)) {\n\t\t\tq.push_back(is_ll(l, m));\n\t\t\tr.push_back(is_ll(l, m));\n\t\t}\n\t}\n\tconst vector<Polygon>polys{ q,r };\n\treturn polys;\n}\n\nint main() {\n\twhile (true) {\n\t\tint N;cin>>N;\n\t\tif(!N)break;\n\t\tvector<ld>us,ds,ls,rs;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tld n;cin>>n;\n\t\t\tds.push_back(n);\n\t\t}\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tld n; cin >> n;\n\t\t\tus.push_back(n);\n\t\t}\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tld n; cin >> n;\n\t\t\tls.push_back(n);\n\t\t}\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tld n; cin >> n;\n\t\t\trs.push_back(n);\n\t\t}\n\n\t\tPolygon start_poly{\n\t\t\tPoint(0,0),\n\t\t\tPoint(1,0),\n\t\t\tPoint(1,1),\n\t\t\tPoint(0,1)\n\t\t};\n\n\t\tvector<Polygon>polys{ start_poly };\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tvector<Polygon>nextpolys;\n\t\t\tfor (auto po : polys) {\n\t\t\t\tLine l(Point(ds[i],0),Point(us[i],1));\n\t\t\t\tauto pos=convex_cut(po,l);\n\n\t\t\t\tfor (auto aa : pos) {\n\t\t\t\t\tif (abs(get_area(aa)) > eps) {\n\n\t\t\t\t\t\tnextpolys.push_back(aa);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tpolys=nextpolys;\n\t\t}\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tvector<Polygon>nextpolys;\n\t\t\tfor (auto po : polys) {\n\t\t\t\tLine l(Point(0,ls[i]), Point(1,rs[i]));\n\t\t\t\tauto pos = convex_cut(po, l);\n\n\t\t\t\tfor (auto aa : pos) {\n\t\t\t\t\tif (abs(get_area(aa)) > eps) {\n\n\t\t\t\t\t\tnextpolys.push_back(aa);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tpolys = nextpolys;\n\t\t}\n\t\tld ans=0;\n\t\tfor (auto poly : polys) {\n\t\t\tans=max(ans,abs(get_area(poly)));\n\t\t}\n\t\tcout<<setprecision(6)<<fixed<<ans<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3560, "score_of_the_acc": -2, "final_rank": 6 }, { "submission_id": "aoj_1226_2340439", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define int long long\n#define EPS (1e-10)\nstruct Point{\n double x,y;\n Point(){}\n Point(double x,double y):x(x),y(y){}\n Point operator+(Point a){return Point(x+a.x,y+a.y);}\n Point operator-(Point a){return Point(x-a.x,y-a.y);}\n Point operator*(double k){return Point(x*k,y*k);}\n Point operator/(double k){return Point(x/k,y/k);}\n};\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\nstruct Segment{\n Point p1,p2;\n Segment(){}\n Segment(Point p1,Point p2):p1(p1),p2(p2){}\n};\ntypedef Segment Line;\ndouble norm(Point a){\n return a.x*a.x+a.y*a.y;\n}\ndouble abs(Point a){\n return sqrt(norm(a));\n}\ndouble dot(Point a,Point b){\n return a.x*b.x+a.y*b.y;\n}\ndouble cross(Point a,Point b){\n return a.x*b.y-a.y*b.x;\n}\nconst double PI=3.141592653589793238;\nPoint trans(double k){\n return Point(cos(k*2*PI),sin(k*2*PI));\n}\nint ccw(Point p0,Point p1,Point p2){\n Vector a=p1-p0;\n Vector b=p2-p0;\n if(cross(a,b)>EPS) return 1;\n if(cross(a,b)<-EPS) return -1;\n if(dot(a,b)<-EPS) return 2;\n if(norm(a)<norm(b)) return -2;\n return 0;\n}\nPoint getCrossPointLL(Line l1,Line l2){\n double a=cross(l1.p2-l1.p1,l2.p2-l2.p1);\n double b=cross(l1.p2-l1.p1,l1.p2-l2.p1);\n if(abs(a)<EPS&&abs(b)<EPS) return l2.p1;\n return l2.p1+(l2.p2-l2.p1)*(b/a);\n}\nPolygon convexCut(Polygon p,Line l){\n Polygon q;\n for(int i=0;i<(int)p.size();i++){\n Point a=p[i],b=p[(i+1)%p.size()];\n if(ccw(l.p1,l.p2,a)!=-1) q.push_back(a);\n if(ccw(l.p1,l.p2,a)*ccw(l.p1,l.p2,b)<0)\n q.push_back(getCrossPointLL(Line(a,b),l));\n }\n return q;\n}\ndouble area(Polygon s){\n double res=0;\n for(int i=0;i<(int)s.size();i++){\n res+=cross(s[i],s[(i+1)%s.size()])/2.0;\n }\n return abs(res);\n}\nint n,m;\nPolygon a,b,c,d;\nsigned main(){\n while(cin>>n,n){\n a.clear();\n b.clear();\n c.clear();\n d.clear();\n double k;\n a.push_back(Point(0,0));\n b.push_back(Point(0,1));\n c.push_back(Point(0,0));\n d.push_back(Point(1,0));\n for(int i=0;i<n&&cin>>k;i++) a.push_back(Point(k,0));\n for(int i=0;i<n&&cin>>k;i++) b.push_back(Point(k,1));\n for(int i=0;i<n&&cin>>k;i++) c.push_back(Point(0,k));\n for(int i=0;i<n&&cin>>k;i++) d.push_back(Point(1,k));\n a.push_back(Point(1,0));\n b.push_back(Point(1,1));\n c.push_back(Point(0,1));\n d.push_back(Point(1,1));\n double ans=0;\n Polygon ba(4);\n ba[0]=Point(0,0);\n ba[1]=Point(1,0);\n ba[2]=Point(1,1);\n ba[3]=Point(0,1);\n for(int i=0;i<n+1;i++){\n for(int j=0;j<n+1;j++){\n\tPolygon t(ba);\n\tt=convexCut(t,Line(b[i],a[i]));\n\tt=convexCut(t,Line(a[i+1],b[i+1]));\n\tt=convexCut(t,Line(c[j],d[j]));\n\tt=convexCut(t,Line(d[j+1],c[j+1]));\n\tans=max(ans,area(t));\n }\n } \n printf(\"%.6f\\n\",ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3068, "score_of_the_acc": -0.8618, "final_rank": 4 }, { "submission_id": "aoj_1226_1983926", "code_snippet": "#include <vector>\n#include <list>\n#include <map>\n#include <set>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <algorithm>\n#include <functional>\n#include <numeric>\n#include <utility>\n#include <sstream>\n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <cmath>\n#include <cstdlib>\n#include <cctype>\n#include <string>\n#include <cstring>\nusing namespace std;\n#define REP(i,n) for(int i = 0; i < (int)n; i++)\n#define FOR(i,a,b) for(int i = a; i < (int)b; i++)\n#define pb push_back\n#define mp make_pair\ntypedef vector<int> vi;\ntypedef pair<int, int> pi;\ntypedef long long ll;\ntypedef unsigned long long ull;\nconst int IINF = 1<<28;\nconst ll MOD = 1000000007;\nconst int dx[] = {1, 0, -1, 0}, dy[] = {0, 1, 0, -1};\n\n// Geometric Library\n#include <complex>\n#define curr(P, i) P[i]\n#define next(P, i) P[(i+1)%P.size()]\ntypedef complex<double> P;\ntypedef vector<P> G;\nconst double EPS = 1e-8;\nconst double INF = 1e12;\nnamespace std {\n\tbool operator < (const P& a, const P& b) {\n\t\t//return real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n\t\tif(imag(a) < imag(b))\n\t\t\treturn true;\n\t\tif(imag(a) == imag(b) && real(a) < real(b))\n\t\t\treturn true;\n\t\treturn false;\n\t}\n}\ndouble cross(const P& a, const P& b) { return imag(conj(a)*b); }\ndouble dot(const P& a, const P& b) { return real(conj(a)*b); }\nstruct L : public vector<P> {\n\tL(const P &a, const P &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\nint ccw(P a, P b, P c) {\n\tb -= a; c -= a;\n\tif (cross(b, c) > 0) return +1; // counter clockwise\n\tif (cross(b, c) < 0) return -1; // clockwise\n\tif (dot(b, c) < 0) return +2; // c--a--b on line\n\tif (norm(b) < norm(c)) return -2; // a--b--c on line\n\treturn 0;\n}\nP crosspoint(const L &l, const L &m) {\n\tdouble A = cross(l[1] - l[0], m[1] - m[0]);\n\tdouble B = cross(l[1] - l[0], l[1] - m[0]);\n\tif (abs(A) < EPS && abs(B) < EPS) return m[0]; // same line\n\treturn m[0] + B / A * (m[1] - m[0]);\n}\nG convex_cut(const G& g, const L& l) {\n\tG Q;\n\tfor (int i = 0; i < g.size(); ++i) {\n\t\tP A = curr(g, i), B = next(g, i);\n\t\tif (ccw(l[0], l[1], A) != -1) Q.push_back(A);\n\t\tif (ccw(l[0], l[1], A)*ccw(l[0], l[1], B) < 0)\n\t\tQ.push_back(crosspoint(L(A, B), l));\n\t}\n\treturn Q;\n}\ndouble area2(const G& g) {\n\tdouble A = 0;\n\tfor (int i = 0; i < g.size(); ++i) \n\t\tA += cross(curr(g, i), next(g, i));\n\treturn A / 2.0;\n}\n\nint main() {\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0);\n\n\n\tint n;\n\twhile(cin >> n, n) {\n\t\tvector<G> v(n+2);\n\t\tREP(i, 4) {\n\t\t\tREP(j, n) {\n\t\t\t\tdouble in; cin >> in;\n\t\t\t\tif(i == 0)\n\t\t\t\t\tv[0].pb(P(0, in));\n\t\t\t\telse if(i == 1)\n\t\t\t\t\tv[n+1].pb(P(1, in));\n\t\t\t\telse if(i == 2)\n\t\t\t\t\tv[j+1].pb(P(in, 0));\n\t\t\t\telse if(i == 3)\n\t\t\t\t\tv[j+1].pb(P(in, 1));\n\t\t\t}\n\t\t}\n\t\tREP(i, n)\n\t\t\tREP(j, n)\n\t\t\t\tv[i+1].pb(crosspoint(L(v[i+1][0], v[i+1][1]), L(v[0][j], v[n+1][j])));\n\t\tv[0].pb(P(0, 0)); v[0].pb(P(0, 1));\n\t\tv[n+1].pb(P(1, 0)); v[n+1].pb(P(1, 1));\n\t\tREP(i, n+2)\n\t\t\tsort(v[i].begin(), v[i].end());\n\t\tdouble ans = 0;\n\t\tREP(i, n+1) {\n\t\t\tREP(j, n+1) {\n\t\t\t\tG g;\n\t\t\t\tg.pb(v[i][j]);\n\t\t\t\tg.pb(v[i+1][j]);\n\t\t\t\tg.pb(v[i+1][j+1]);\n\t\t\t\tg.pb(v[i][j+1]);\n\t\t\t\tans = max(ans, area2(g));\n\t\t\t}\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1328, "score_of_the_acc": -0.373, "final_rank": 3 }, { "submission_id": "aoj_1226_331877", "code_snippet": "#include <string> \n#include <algorithm> \n#include <cfloat> \n#include <climits> \n#include <cmath> \n#include <complex> \n#include <cstdio> \n#include <cstdlib> \n#include <cstring> \n#include <functional> \n#include <iostream> \n#include <map> \n#include <memory> \n#include <queue> \n#include <set> \n#include <sstream> \n#include <stack> \n#include <utility> \n#include <vector> \n\n#define EACH(i,c) for(typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define ALL(x) (x).begin(),(x).end() \ntypedef long long ll;\nusing namespace std; \nconst double eps = 1e-10;\n\nconst int MAX_N = 30;\n\ntypedef complex<double> P;\n\nbool operator < (const P &a, const P &b){\n return a.real() != b.real() ? a.real() < b.real() : a.imag() < b.imag();\n}\ndouble dot(const P &a, const P &b){\n return real(conj(a) * b);\n}\ndouble cross(const P &a, const P &b){\n return imag(conj(a) * b);\n}\n\nstruct Line : public vector<P> {\n Line(const P &a, const P &b) {\n push_back(a); push_back(b);\n }\n Line(double x1, double y1, double x2, double y2){\n push_back(P(x1, y1));\n push_back(P(x2, y2));\n }\n};\n\ntypedef vector<P> Polygon;\n\nstruct Circle{\n P p; double r;\n Circle(const P &p, double r) : p(p), r(r) { }\n};\n\nP intersection_ls(const Line &a, const Line &b){\n P vb = b[1] - b[0];\n double d1 = abs(cross(vb, a[0] - b[0]));\n double d2 = abs(cross(vb, a[1] - b[0]));\n double t = d1 / (d1 + d2);\n return a[0] + (a[1] - a[0]) * t;\n}\n\nint n;\ndouble a[MAX_N], b[MAX_N], c[MAX_N], d[MAX_N];\nvoid solve(){\n double res = 0.0;\n a[0] = b[0] = c[0] = d[0] = 0.0;\n a[n + 1] = b[n + 1] = c[n + 1] = d[n + 1] = 1.0;\n for(int i = 0; i <= n; ++i){\n for(int j = 0; j <= n; ++j){\n Line l1 = Line(a[i], 0, b[i], 1);\n Line l2 = Line(a[i + 1], 0, b[i + 1], 1);\n Line l3 = Line(0, c[j], 1, d[j]);\n Line l4 = Line(0, c[j + 1], 1, d[j + 1]);\n P p1 = intersection_ls(l1, l3);\n P p2 = intersection_ls(l1, l4);\n P p3 = intersection_ls(l2, l3);\n P p4 = intersection_ls(l2, l4);\n double tmp = (abs(cross(p2 - p1, p3 - p1)) + abs(cross(p3 - p4, p2 - p4))) / 2.0;\n res = max(res, tmp);\n }\n }\n printf(\"%.9f\\n\", res);\n}\nint main(){\n while(cin >> n, n){\n for(int i = 1; i <= n; ++i) cin >> a[i];\n for(int i = 1; i <= n; ++i) cin >> b[i];\n for(int i = 1; i <= n; ++i) cin >> c[i];\n for(int i = 1; i <= n; ++i) cin >> d[i];\n solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1226_27311", "code_snippet": "#include<iostream>\n#include<cfloat>\n#include<cassert>\n#include<cmath>\n#include<vector>\n\nusing namespace std;\n\n#define EPS (1e-10)\n#define equals(a, b) (fabs((a) - (b)) < EPS )\n#define dle(a, b) (equals(a, b) || a < b )\nstatic const double PI = acos(-1);\n\nclass Point{\n public:\n double x, y;\n \n Point ( double x = 0, double y = 0): x(x), y(y){}\n \n Point operator + ( Point p ){ return Point(x + p.x, y + p.y); }\n Point operator - ( Point p ){ return Point(x - p.x, y - p.y); }\n Point operator * ( double a ){ return Point(x*a, y*a); }\n Point operator / ( double a ){ return Point(x/a, y/a); }\n\n double abs() { return sqrt(norm());}\n double norm() { return x*x + y*y; }\n\n bool operator < ( const Point &p ) const {\n\treturn x != p.x ? x < p.x : y < p.y;\n }\n\n bool operator == ( const Point &p ) const {\n\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n }\n};\n\ntypedef Point Vector;\n\nclass Segment{\n public:\n Point p1, p2;\n Segment(Point s = Point(), Point t = Point()): p1(s), p2(t){}\n};\n\ntypedef vector<Point> Polygon;\n\ndouble norm( Vector a ){ return a.x*a.x + a.y*a.y; }\ndouble abs( Vector a ){ return sqrt(norm(a)); }\nPoint polar( double a, double r ){ return Point(cos(r)*a, sin(r)*a);}\ndouble getDistance( Vector a, Vector b ){ return abs(a - b); }\ndouble dot( Vector a, Vector b ){ return a.x*b.x + a.y*b.y; }\ndouble cross( Vector a, Vector b ){ return a.x*b.y - a.y*b.x; }\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\nint ccw( Point p0, Point p1, Point p2 ){\n Vector a = p1 - p0;\n Vector b = p2 - p0;\n if ( cross(a, b) > EPS ) return COUNTER_CLOCKWISE;\n if ( cross(a, b) < -EPS ) return CLOCKWISE;\n if ( dot(a, b) < -EPS ) return ONLINE_BACK;\n if ( norm(a) < norm(b) ) return ONLINE_FRONT;\n return ON_SEGMENT;\n}\n\nbool isIntersect(Point p1, Point p2, Point p3, Point p4){\n return ( ccw(p1, p2, p3) * ccw(p1, p2, p4) <= 0 &&\n\t ccw(p3, p4, p1) * ccw(p3, p4, p2) <= 0 );\n}\n\nbool isIntersect(Segment s1, Segment s2){\n return isIntersect(s1.p1, s1.p2, s2.p1, s2.p2);\n}\n\nPoint getCrossPoint(Segment s1, Segment s2){\n assert( isIntersect(s1, s2) );\n Vector base = s2.p2 - s2.p1;\n double d1 = abs(cross(base, s1.p1 - s2.p1));\n double d2 = abs(cross(base, s1.p2 - s2.p1));\n double t = d1/(d1 + d2);\n return s1.p1 + (s1.p2 - s1.p1)*t;\n}\n\ndouble getArea(Polygon p){\n double sum = 0.0;\n for(int i = 0; i < p.size(); i++){\n\tsum += cross(p[i], p[(i+1)%p.size()]);\n }\n return abs(sum/2);\n}\n\n#define MAX 30\n\nint main(){\n double a[MAX+2], b[MAX+2], c[MAX+2], d[MAX+2];\n int n;\n Segment V[MAX+2], H[MAX+2];\n\n Point P[MAX+2][MAX+2];\n\n while( cin >> n && n ){\n\tfor ( int i = 1; i <= n; i++ ) cin >> a[i];\n\tfor ( int i = 1; i <= n; i++ ) cin >> b[i];\n\tfor ( int i = 1; i <= n; i++ ) cin >> c[i];\n\tfor ( int i = 1; i <= n; i++ ) cin >> d[i];\n\n\tV[0] = Segment(Point(0, 0), Point(0, 1));\n\tfor ( int i = 1; i <= n; i++ ){\n\t V[i] = Segment(Point(a[i], 0), Point(b[i], 1));\n\t}\n\tV[n+1] = Segment(Point(1, 0), Point(1, 1));\n\n\tH[0] = Segment(Point(0, 0), Point(1, 0));\n\tfor ( int i = 1; i <= n; i++ ){\n\t H[i] = Segment(Point(0, c[i]), Point(1, d[i]));\n\t}\n\tH[n+1] = Segment(Point(0, 1), Point(1, 1));\n\n\t\n\tfor ( int y = 0; y < n+2; y++ ){\n\t for ( int x = 0; x < n+2; x++ ){\n\t\tP[y][x] = getCrossPoint(H[y], V[x]);\n\t }\n\t}\n\n\tdouble maxa = 0;\n\n\tfor ( int y = 1; y < n+2; y++ ){\n\t for ( int x = 1; x < n+2; x++ ){\n\t\tPolygon S;\n\t\tS.push_back(P[y][x]);\n\t\tS.push_back(P[y][x-1]);\n\t\tS.push_back(P[y-1][x-1]);\n\t\tS.push_back(P[y-1][x]);\n\t\tmaxa = max( maxa, getArea(S) );\n\t }\n\t}\n\n\tprintf(\"%.12lf\\n\", maxa);\n }\n\n\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_1224_cpp
Problem A: Starship Hakodate-maru The surveyor starship Hakodate-maru is famous for her two fuel containers with unbounded capacities. They hold the same type of atomic fuel balls. There, however, is an inconvenience. The shapes of the fuel containers # 1 and # 2 are always cubic and regular tetrahedral respectively. Both of the fuel containers should be either empty or filled according to their shapes. Otherwise, the fuel balls become extremely unstable and may explode in the fuel containers. Thus, the number of fuel balls for the container # 1 should be a cubic number ( n 3 for some n = 0, 1, 2, 3,... ) and that for the container # 2 should be a tetrahedral number ( n ( n + 1)( n + 2)/6 for some n = 0, 1, 2, 3,... ). Hakodate-maru is now at the star base Goryokaku preparing for the next mission to create a precise and detailed chart of stars and interstellar matters. Both of the fuel containers are now empty. Commander Parus of Goryokaku will soon send a message to Captain Future of Hakodate-maru on how many fuel balls Goryokaku can supply. Captain Future should quickly answer to Commander Parus on how many fuel balls she requests before her ship leaves Goryokaku. Of course, Captain Future and her omcers want as many fuel balls as possible. For example, consider the case Commander Parus offers 151200 fuel balls. If only the fuel container # 1 were available (i.e. ifthe fuel container # 2 were unavailable), at most 148877 fuel balls could be put into the fuel container since 148877 = 53 × 53 × 53 < 151200 < 54 × 54 × 54 . If only the fuel container # 2 were available, at most 147440 fuel balls could be put into the fuel container since 147440 = 95 × 96 × 97/6 < 151200 < 96 × 97 × 98/6 . Using both of the fuel containers # 1 and # 2, 151200 fuel balls can be put into the fuel containers since 151200 = 39 × 39 × 39 + 81 × 82 × 83/6 . In this case, Captain Future's answer should be "151200". Commander Parus's offer cannot be greater than 151200 because of the capacity of the fuel storages of Goryokaku. Captain Future and her omcers know that well. You are a fuel engineer assigned to Hakodate-maru. Your duty today is to help Captain Future with calculating the number of fuel balls she should request. Input The input is a sequence of at most 1024 positive integers. Each line contains a single integer. The sequence is followed by a zero, which indicates the end of data and should not be treated as input. You may assume that none of the input integers is greater than 151200. Output The output is composed of lines, each containing a single integer. Each output integer should be the greatest integer that is the sum of a nonnegative cubic number and a nonnegative tetrahedral number and that is not greater than the corresponding input number. No other characters should appear in the output. Sample Input 100 64 50 20 151200 0 Output for the Sample Input 99 64 47 20 151200
[ { "submission_id": "aoj_1224_4858248", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main() {\n int n;\n while(cin >>n,n){\n int ans = 0;\n for(int i=0;i*i*i<151200; i++){\n int sum = 0;\n for(int j=0; sum <= n ;j++){\n ans = max(ans, sum);\n sum = i*i*i + (j*(j+1)*(j+2))/6.0;\n }\n }cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3060, "score_of_the_acc": -0.9129, "final_rank": 16 }, { "submission_id": "aoj_1224_4477120", "code_snippet": "#define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int n; cin>>n;\n while(n != 0){\n int ans = 0;\n for(int i=0;i*i*i<151200; i++){\n int s = 0;\n for(int j=0; s <= n ;j++){\n ans = max(ans, s);\n s = pow(i, 3) + (j*(j+1)*(j+2))/6.0;\n }\n }\n cout << ans << endl;\n cin >> n;\n }\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 3172, "score_of_the_acc": -1.9463, "final_rank": 19 }, { "submission_id": "aoj_1224_2779554", "code_snippet": "#include \"bits/stdc++.h\"\n/*\n#include <iostream>\n#include <vector>\n#include <map>\n#include <utility>\n#include <algorithm>\n#include <cmath>\n#include <cstdio>\n#include <cstring>\n#include <stack>\n#include <queue>\n#include <set>\n#include <unordered_map>\n#include <unordered_set>\n#include <numeric>\n#include <complex>\n#include <bitset>\n#include <functional>\n#include <stack>\n#include <regex>\n#include <tuple>\n*/\n#define int long long\n#define REP(i,a,n) for(int i=a;i<n;++i)\n#define rep(i,n) REP(i,0,n)\n#define REV(i,a,n) for(int i=n;i>=a;--i)\n#define all(e) e.begin(),e.end()\n#define rall(e) e.rbegin(),e.rend()\n#define pb push_back\n#define mp make_pair\n#define fs first\n#define sc second\n#define mod 1000000007\n#define show(n) cerr<<#n<<\" = \"<<n<<endl\n#define showp(n) cerr<<n.fs<<\", \"<<n.sc<<endl\n#define shows(n) for(auto z:n){cerr<<z<<\", \";}cerr<<endl\n#define showsp(n) for(auto z:n){cerr<<z.fs<<\" \"<<z.sc<<\", \"}cerr<<endl\n\n#define yes printf(\"Yes\\n\")\n#define no printf(\"No\\n\")\n#define case(i) printf(\"Case #%lld: \",i)\n\nusing namespace std;\n\nusing ull=unsigned long long;\nusing vi=vector<int>;\nusing pint=pair<int,int>;\n\nconst int INF=1LL<<55;\n\nint tf;\nint ans=0;\n\nvoid solve(){\n ans = 0;\n int t;\n int i=1;\n while(true){\n t=pow(i,3);\n if(t>tf) break;\n ans=max(ans,t);\n i++;\n }\n int maxA=i;\n i=1;\n while(true){\n t=i*(i+1)*(i+2)/6;\n if(t>tf) break;\n ans=max(ans,t);\n i++;\n }\n int maxB=i;\n rep(i,maxA){\n rep(j,maxB){\n t=pow(i,3)+j*(j+1)*(j+2)/6;\n if(t>tf) break;\n ans=max(ans,t);\n }\n }\n cout<<ans<<endl;\n return;\n}\n\nsigned main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n int i=1;\n int t;\n \n while(cin>>tf,tf){\n solve();\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 3352, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_1224_2779543", "code_snippet": "#include <iostream>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <vector>\n#include <list>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <map>\n#include <set>\n#include <bitset>\n#include <tuple>\n#include <cassert>\n#include <exception>\n#include <iomanip>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<ll,ll> P;\ntypedef vector<int> vi;\ntypedef vector<ll> vll;\ntypedef vector<char> vc;\ntypedef vector<string> vs;\ntypedef vector<P> vp;\n#define rep(i,a,n) for(ll i = (a);i < (n);i++)\n#define per(i,a,n) for(ll i = (a);i > (n);i--)\n#define lep(i,a,n) for(ll i = (a);i <= (n);i++)\n#define pel(i,a,n) for(ll i = (a);i >= (n);i--)\n#define clr(a,b) memset((a),(b),sizeof(a))\n#define pb push_back\n#define mp make_pair\n#define all(c) (c).begin(),(c).end()\n#define sz size()\n#define print(X) cout << (X) << endl\nstatic const int INF = 1e+9+7;\nll n,m,l;\nstring s,t;\nint d[200010],dp[1010][1010];\ndouble w[1000],v[1000];\ndouble box[200010];\nchar field[200][200];\n\nint main(){\n while(1){\n cin >> n;\n if(!n)break;\n ll ans = 0;\n lep(i,1,96){\n l = pow(i,3);\n if(l <= n)ans = max(ans,l);\n }\n lep(i,1,96){\n l = i * (i+1)*(i+2)/6;\n if(l <= n)ans = max(ans,l);\n }\n lep(i,1,96){\n l = pow(i,3);\n lep(j,1,96){\n m = j*(j+1)*(j+2)/6;\n if(l + m <= n)ans = max(ans,l+m);\n }\n }\n print(ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3288, "score_of_the_acc": -1.0578, "final_rank": 18 }, { "submission_id": "aoj_1224_2122304", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define MAX 151200\ntypedef long long ll;\n \nint main(void){\n ll N;\n while(cin >> N, N){\n int ans = 0;\n for(int cube = 0; cube * cube * cube <= MAX; cube++){\n for(int tr = 0; tr * (tr+1) * (tr+2) / 6 <= MAX; tr++){\n int cuben = cube * cube * cube;\n int trn = tr*(tr+1)*(tr+2)/6;\n if(cuben <= N){\n ans = max(ans, cuben);\n }\n if(trn <= N){\n ans = max(ans, trn);\n }\n if(cuben + trn <= N){\n ans = max(ans, cuben + trn);\n }\n }\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3060, "score_of_the_acc": -0.9129, "final_rank": 16 }, { "submission_id": "aoj_1224_2116802", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define MAX 151200\ntypedef long long ll;\n\nint main(void){\n ll N;\n while(cin >> N, N){\n int ans = 0;\n for(int cube = 0; cube * cube * cube <= MAX; cube++){\n for(int tr = 0; tr * (tr+1) * (tr+2) / 6 <= MAX; tr++){\n\tint cuben = cube * cube * cube;\n\tint trn = tr*(tr+1)*(tr+2)/6;\n\tif(cuben <= N){\n\t ans = max(ans, cuben);\n\t}\n\tif(trn <= N){\n\t ans = max(ans, trn);\n\t}\n\tif(cuben + trn <= N){\n\t ans = max(ans, cuben + trn);\n\t}\n }\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3056, "score_of_the_acc": -0.9117, "final_rank": 15 }, { "submission_id": "aoj_1224_1955793", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstdlib>\n#include <string>\n#include <vector>\n#include <deque>\n#include <list>\n#include <algorithm>\n#include <numeric>\n#include <functional>\n#include <cmath>\n#include <cstring>\n#include <cctype>\n#include <sstream>\n#include <set>\n#include <map>\n#include <stack>\n#include <queue>\n#include <complex>\nusing namespace std;\n#define REP(i,n) for(int i = 0; i < (int)n; i++)\n#define FOR(i,a,b) for(int i = a; i < (int)b; i++)\n#define pb push_back\n#define mp make_pair\ntypedef vector<int> vi;\ntypedef pair<int, int> pi;\ntypedef long long ll;\nconst int INF = 1<<28;\nconst ll MOD = 1000000007;\nconst int dx[] = {1, 0, -1, 0}, dy[] = {0, 1, 0, -1};\n\nint main() {\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0);\n\n\tvi v1, v2;\n\tfor(int i=0; i*i*i <= 151200; i++)\n\t\tv1.pb(i*i*i);\n\tfor(int i=0; i*(i+1)*(i+2)/6 <= 151200; i++)\n\t\tv2.pb(i*(i+1)*(i+2)/6);\n\n\tint n;\n\twhile(cin >> n, n) {\n\t\tint ans = 0;\n\t\tREP(i, v1.size())\n\t\t\tREP(j, v2.size())\n\t\t\t\tif(v1[i] + v2[j] <= n && v1[i] + v2[j] > ans) {\n\t\t\t\t\tans = v1[i] + v2[j];\n\t\t\t\t}\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1220, "score_of_the_acc": -0.364, "final_rank": 11 }, { "submission_id": "aoj_1224_1851549", "code_snippet": "#include<iostream>\nusing namespace std;\nint g[60], h[100];\nint main() {\n\tfor (int i = 0; i < 60; i++)g[i] = i*i*i;\n\tfor (int i = 0; i < 100; i++)h[i] = i*(i + 1)*(i + 2) / 6;\n\twhile (true) {\n\t\tint p, q = 0; cin >> p; if (p == 0)break;\n\t\tfor (int i = 0; i < 60; i++) {\n\t\t\tfor (int j = 0; j < 100; j++) {\n\t\t\t\tint t = g[i] + h[j];\n\t\t\t\tif (t <= p && q < t)q = t;\n\t\t\t}\n\t\t}\n\t\tcout << q << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1160, "score_of_the_acc": -0.3461, "final_rank": 5 }, { "submission_id": "aoj_1224_1546400", "code_snippet": "#include <algorithm>\n#include <functional>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <string>\n#include <sstream>\n#include <iostream>\n#include <iomanip>\n#include <vector>\n#include <list>\n#include <stack>\n#include <queue>\n#include <map>\n#include <set>\n#include <bitset>\n#include <climits>\n\n#define all(c) (c).begin(), (c).end()\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define pb(e) push_back(e)\n#define mp(a, b) make_pair(a, b)\n#define fr first\n#define sc second\n\nconst int INF=100000000;\nint dx[4]={1,0,-1,0};\nint dy[4]={0,1,0,-1};\nusing namespace std;\ntypedef pair<int ,int > P;\ntypedef long long ll;\n\nint N;\nint cubic(int n) {\n return n*n*n;\n}\nint tetrahedral(int n) {\n return n*(n+1)*(n+2)/6;\n}\nvoid solve() {\n int ans=0;\n rep(n1,100) rep(n2,100) {\n if(cubic(n1)+tetrahedral(n2)<=N) {\n ans=max(ans,cubic(n1)+tetrahedral(n2));\n }\n }\n\n cout<<ans<<endl;\n}\n\nint main() {\n while(cin>>N) {\n if(!N) break;\n solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1160, "score_of_the_acc": -0.423, "final_rank": 13 }, { "submission_id": "aoj_1224_1168335", "code_snippet": "#include <functional>\n#include <algorithm>\n#include <iostream>\n#include <numeric>\n#include <iomanip>\n#include <utility>\n#include <cstdlib>\n#include <sstream>\n#include <bitset>\n#include <vector>\n#include <cstdio>\n#include <ctime>\n#include <queue>\n#include <deque>\n#include <cmath>\n#include <stack>\n#include <list>\n#include <map>\n#include <set>\n\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<(n);i++)\n\nint main(){\n int n;\n while(cin>>n){\n if(n==0)break;\n\n int ma=-1;\n \n rep(i,55){\n rep(j,100){\n int calc= i*i*i + (int)(j*(j+1)*(j+2)/6);\n if( calc <=n ){\n ma=max( ma , calc );\n }\n else break;\n }\n }\n cout<<ma<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1160, "score_of_the_acc": -0.3461, "final_rank": 5 }, { "submission_id": "aoj_1224_1012178", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main()\n{\n int n, ans;\n vector<int> c1, c2;\n for (int i = 0; i <= 53; i++) {\n c1.push_back(i * i * i);\n }\n for (int i = 0; i <= 95; i++) {\n c2.push_back(i * (i + 1) * (i + 2) / 6);\n }\n while (cin >> n && n) {\n ans = 0;\n for (int i = 0; i < c1.size(); i++) {\n for (int j = 0; j < c2.size(); j++) {\n if (c1[i] + c2[j] > n) {\n continue;\n }\n ans = max(ans, c1[i] + c2[j]);\n }\n }\n cout << ans << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1216, "score_of_the_acc": -0.3628, "final_rank": 10 }, { "submission_id": "aoj_1224_842044", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nconst int MAX_C = 60;\nconst int MAX_T = 150;\n\nint c[MAX_C],t[MAX_T];\n\nvoid init_c(){\n for(int i = 0 ; i < MAX_C ; i++){\n c[i] = i*i*i;\n }\n}\n\nvoid init_t(){\n for(int i = 2 ; i < MAX_T ; i++){\n t[i-2] = i*(i-1)*(i-2)/6;\n }\n}\n\nint main(){\n int n;\n\n init_c();\n init_t();\n\n while(cin >> n ,n){\n int ans = 0;\n\n for(int i = 0 ; i < MAX_C ; i++){\n for(int j = 0 ; j < MAX_T-2 ; j++){\n\tif(c[i]+t[j] <= n){\n\t ans = max(ans , c[i] + t[j]);\n\t}\n }\n }\n cout << ans << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1160, "score_of_the_acc": -0.3461, "final_rank": 5 }, { "submission_id": "aoj_1224_835311", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<map>\nusing namespace std;\nint main(){\n int n;\n while(cin >> n , n){\n int ret = 0, RIPPO = 0;\n for(int i = 0 ; (RIPPO = i * i * i) <= n ; i++ ){\n int SANKAKU = 0;\n for(int j = 0 ; RIPPO + ( SANKAKU = j * ( j + 1 ) * ( j + 2 ) / 6 ) <= n ; j++ ){\n\tret = max( ret, RIPPO + SANKAKU);\n }\n }\n cout << ret << endl;\n } \n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1160, "score_of_the_acc": -0.3461, "final_rank": 5 }, { "submission_id": "aoj_1224_751012", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n\n\n\nint A(int num){\n\treturn num*num*num;\n}\n\nint B(int num){\n\treturn (num*(num+1)*(num+2))/6;\n}\n\n\nint main(){\n\tfor(int n,ans=0;cin>>n,n;ans=0){\n\t\tfor(int i=0;i<54;i++){\n\t\t\tfor(int j=0;j<96;j++){\n\t\t\t\tif(A(i)+B(j)<=n)ans=max(ans,A(i)+B(j));\n\t\t\t}\n\t\t}\n\t\tcout<<ans<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1160, "score_of_the_acc": -0.3461, "final_rank": 5 }, { "submission_id": "aoj_1224_594562", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\n#define M (151200)\n\nvector<int> p, q;\nvoid init() {\n p.push_back(0);\n for (int i = 1; i * i * i <= M; i++) {\n p.push_back(i * i * i);\n }\n q.push_back(0);\n for (int i = 1; i * (i + 1) * (i + 2) / 6 <= M; i++) {\n q.push_back(i * (i + 1) * (i + 2) / 6);\n }\n}\n\nint solve(int n) {\n int ret = 0;\n for (int i = 0; i < p.size(); i++) {\n for (int j = 0; j < q.size(); j++) {\n if (p[i] + q[j] > n) continue;\n ret = max(ret, p[i] + q[j]);\n }\n }\n return ret;\n}\n\nint main() {\n init();\n int n;\n while (cin >> n, n) {\n cout << solve(n) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1216, "score_of_the_acc": -0.4397, "final_rank": 14 }, { "submission_id": "aoj_1224_528000", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\n#define MAX 151200\n\nint main(){\n vector<int> cubic;\n vector<int> tetra;\n\n cubic.push_back(0);\n for(int i = 1; i * i * i <= MAX; i++){\n cubic.push_back(i * i * i);\n }\n tetra.push_back(0);\n for(int i = 1; i * (i + 1) * (i + 2) / 6 <= MAX; i++){\n tetra.push_back(i * (i + 1) * (i + 2) / 6);\n }\n\n int n;\n\n while(cin >> n, n){\n int ans = 0;\n\n for(int i = 0; i < cubic.size(); i++){\n for(int j = 0; j < tetra.size(); j++){\n\tint sum = cubic[i] + tetra[j];\n\n\tif(sum <= n){\n\t ans = max(ans, sum);\n\t}\n }\n }\n\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1220, "score_of_the_acc": -0.364, "final_rank": 11 }, { "submission_id": "aoj_1224_464177", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<cmath>\nusing namespace std;\nconst int INF = (1 << 21);\n\nint a(int x){\n return x * x * x;\n}\n\nint b(int x){\n return (x * (x - 1) * (x - 2)) / 6;\n}\n\nint c(int n, int x){\n return n - x;\n}\n\nint main(){\n int n;\n while(cin >>n){\n if(n == 0) break;\n int ans = INF, tmp;\n for(int i = 1; i < 100; i++){\n tmp = c(n, a(i));\n if(tmp < 0) break;\n else ans = min(ans, tmp);\n for(int j = 1; j < 100; j++){\n tmp = c(n, a(i) + b(j));\n if(tmp < 0) break;\n else ans = min(ans, tmp);\n }\n\n }\n for(int i = 1; i < 100; i++){\n tmp = c(n, b(i));\n if(tmp < 0) break;\n else ans = min(ans, tmp);\n }\n cout <<n - ans <<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1224_464095", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<cmath>\nusing namespace std;\nconst int DEF = (1 << 21);\n\nint a(int x){\n return x * x * x;\n}\n\nint b(int x){\n return (x * (x - 1) * (x - 2)) / 6;\n}\n\nint c(int n, int x){\n return n - x;\n}\n\nint main(){\n int n;\n while(cin >>n){\n if(n == 0) break;\n int ans = DEF, tmp;\n for(int i = 1; i < 100; i++){\n tmp = c(n, a(i));\n if(tmp < 0) break;\n else ans = min(ans, tmp);\n for(int j = 1; j < 100; j++){\n tmp = c(n, a(i) + b(j));\n if(tmp < 0) break;\n else ans = min(ans, tmp);\n }\n\n }\n for(int i = 1; i < 100; i++){\n tmp = c(n, b(i));\n if(tmp < 0) break;\n else ans = min(ans, tmp);\n }\n cout <<n - ans <<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1224_392357", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <set>\n#include <map>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <cassert>\n\nusing namespace std;\n\n#define FOR(i,k,n) for(int i=(k); i<(int)n; ++i)\n#define REP(i,n) FOR(i,0,n)\n#define FORIT(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n\ntemplate<class T> void debug(T begin, T end){ for(T i = begin; i != end; ++i) cout<<*i<<\" \"; cout<<endl; }\n\ntypedef long long ll;\nconst int INF = 100000000;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\n\nint main(){\n int n;\n while(cin>>n && n){\n int ans = 0;\n REP(x, 55)REP(y, 96){\n int l = x * x * x + y * (y + 1) * (y + 2) / 6;\n if(l <= n) ans = max(ans, l);\n }\n cout<<ans<<endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 868, "score_of_the_acc": -0.3359, "final_rank": 4 }, { "submission_id": "aoj_1224_354633", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <vector>\n#include <list>\n#include <string>\n#include <set>\n#include <map>\n#include <stack>\n#include <queue>\n#include <algorithm>\n#include <numeric>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <climits>\nusing namespace std;\n\nint main() {\n int n;\n while ( cin >> n && n ) {\n int res = 0;\n for ( int i = 0; i < 54; ++ i ) {\n for ( int j = 0; j < 100; ++ j ) {\n int sum = i * i * i + j * ( j + 1 ) * ( j + 2 ) / 6;\n if ( sum <= n ) res = max( res, sum );\n }\n }\n cout << res << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 0, "score_of_the_acc": -0.0769, "final_rank": 3 } ]
aoj_1229_cpp
Problem F: Young, Poor and Busy Ken and Keiko are young, poor and busy. Short explanation: they are students, and ridden with part-time jobs. To make things worse, Ken lives in Hakodate and Keiko in Tokyo. They want to meet, but since they have neither time nor money, they have to go back to their respective jobs immediately after, and must be careful about transportation costs. Help them find the most economical meeting point. Ken starts from Hakodate, Keiko from Tokyo. They know schedules and fares for all trains, and can choose to meet anywhere including their hometowns, but they cannot leave before 8am and must be back by 6pm in their respective towns. Train changes take no time (one can leave the same minute he/she arrives), but they want to meet for at least 30 minutes in the same city. There can be up to 100 cities and 2000 direct connections, so you should devise an algorithm clever enough for the task. Input The input is a sequence of data sets. The first line of a data set contains a single integer, the number of connections in the timetable. It is not greater than 2000. Connections are given one on a line, in the following format. Start_city HH : MM Arrival_city HH : MM price Start_city and Arrival_city are composed of up to 16 alphabetical characters, with only the first one in upper case. Departure and arrival times are given in hours and minutes (two digits each, separated by ":") from 00:00 to 23:59. Arrival time is strictly after departure time. The price for one connection is an integer between 1 and 10000, inclusive. Fields are separated by spaces. The end of the input is marked by a line containing a zero. Output The output should contain one integer for each data set, the lowest cost possible. This is the total fare of all connections they use. If there is no solution to a data set, you should output a zero. The solution to each data set should be given in a separate line. Sample Input 5 Hakodate 08:15 Morioka 12:30 2500 Morioka 14:05 Hakodate 17:30 2500 Morioka 15:30 Hakodate 18:00 3000 Morioka 14:30 Tokyo 17:50 3000 Tokyo 08:30 Morioka 13:35 3000 4 Hakodate 08:15 Morioka 12:30 2500 Morioka 14:04 Hakodate 17:30 2500 Morioka 14:30 Tokyo 17:50 3000 Tokyo 08:30 Morioka 13:35 3000 18 Hakodate 09:55 Akita 10:53 3840 Hakodate 14:14 Akita 16:09 1920 Hakodate 18:36 Akita 19:33 3840 Hakodate 08:00 Morioka 08:53 3550 Hakodate 22:40 Morioka 23:34 3550 Akita 14:23 Tokyo 14:53 2010 Akita 20:36 Tokyo 21:06 2010 Akita 08:20 Hakodate 09:18 3840 Akita 13:56 Hakodate 14:54 3840 Akita 21:37 Hakodate 22:35 3840 Morioka 09:51 Tokyo 10:31 2660 Morioka 14:49 Tokyo 15:29 2660 Morioka 19:42 Tokyo 20:22 2660 Morioka 15:11 Hakodate 16:04 3550 Morioka 23:03 Hakodate 23:56 3550 Tokyo 09:44 Morioka 11:04 1330 Tokyo 21:54 Morioka 22:34 2660 Tokyo 11:34 Akita 12:04 2010 0 Output for the Sample Input 11000 0 11090
[ { "submission_id": "aoj_1229_2940627", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 100\n#define BASE 480\n#define MAX 600\n\nenum Type{\n\tA,\n\tB,\n};\n\nstruct Edge{\n\tEdge(int arg_to,int arg_cost,int arg_start_time,int arg_arrive_time){\n\t\tto = arg_to;\n\t\tcost = arg_cost;\n\t\tstart_time = arg_start_time;\n\t\tarrive_time = arg_arrive_time;\n\t}\n\tbool operator<(const struct Edge &arg) const{ //出発時刻の昇順\n\t\treturn start_time < arg.start_time;\n\t}\n\tint to,cost,start_time,arrive_time;\n};\n\nstruct Info{\n\tInfo(int arg_node_id,int arg_sum_cost,int arg_current_time){\n\t\tnode_id = arg_node_id;\n\t\tsum_cost = arg_sum_cost;\n\t\tcurrent_time = arg_current_time;\n\t}\n\tbool operator<(const struct Info &arg) const{ //総コストの昇順(PQ)\n\t\treturn sum_cost > arg.sum_cost;\n\t}\n\tint node_id,sum_cost,current_time;\n};\n\nstruct Data{\n\tData(int arg_rev_start_time,int arg_sum_cost){\n\t\trev_start_time = arg_rev_start_time;\n\t\tsum_cost = arg_sum_cost;\n\t}\n\tbool operator<(const struct Data &arg) const{ //帰宅開始時刻の昇順\n\t\treturn rev_start_time < arg.rev_start_time;\n\t}\n\tint rev_start_time,sum_cost;\n};\n\nint N;\nint node_index;\nint min_cost[2][NUM][601],return_min_cost[NUM][601];\nint A_id,B_id;\nvector<int> work[2][NUM];\nvector<Data> return_start[NUM];\nconst string start_A = \"Hakodate\";\nconst string start_B = \"Tokyo\";\n\nmap<string,int> MAP;\nmap<int,int> CALC;\nvector<Edge> G[NUM];\n\n//時刻を分に直す\nint getNUM(char work[6]){\n\n\tint hour = 10*(work[0]-'0')+(work[1]-'0');\n\tint minute = 10*(work[3]-'0')+(work[4]-'0');\n\n\treturn 60*hour+minute;\n}\n\n//8時~18時の時間帯か\nbool rangeCheck(int tmp_time){\n\tif(tmp_time >= BASE && tmp_time <= BASE+MAX)return true;\n\telse{\n\t\treturn false;\n\t}\n}\n\nvoid dijkstra(Type type,int start_id){\n\n\tfor(int i = 0; i < node_index; i++){\n\t\tfor(int k = 0; k <= MAX; k++){\n\t\t\tmin_cost[type][i][k] = BIG_NUM;\n\t\t}\n\t}\n\n\tmin_cost[type][start_id][0] = 0; //8時に出発\n\n\tpriority_queue<Info> Q;\n\tQ.push(Info(start_id,0,BASE));\n\n\tint next_node,next_cost,next_time;\n\n\twhile(!Q.empty()){\n\n\t\tif(Q.top().sum_cost > min_cost[type][Q.top().node_id][Q.top().current_time-BASE]){\n\t\t\tQ.pop();\n\t\t}else{\n\n\t\t\tfor(int i = 0; i < G[Q.top().node_id].size(); i++){\n\t\t\t\t//既に出発している、または有効時間外ならSKIP\n\t\t\t\tif(Q.top().current_time > G[Q.top().node_id][i].start_time)continue;\n\t\t\t\tif(rangeCheck(G[Q.top().node_id][i].start_time) == false || rangeCheck(G[Q.top().node_id][i].arrive_time) == false)continue;\n\n\t\t\t\tnext_node = G[Q.top().node_id][i].to;\n\t\t\t\tnext_cost = Q.top().sum_cost+G[Q.top().node_id][i].cost;\n\t\t\t\tnext_time = G[Q.top().node_id][i].arrive_time;\n\n\t\t\t\tif(min_cost[type][next_node][next_time-BASE] > next_cost){\n\n\t\t\t\t\tmin_cost[type][next_node][next_time-BASE] = next_cost;\n\t\t\t\t\tQ.push(Info(next_node,next_cost,next_time));\n\t\t\t\t}\n\t\t\t}\n\t\t\tQ.pop();\n\t\t}\n\t}\n}\n\nint rev_dijkstra(int start_id){\n\n\tint ret = BIG_NUM;\n\tint next_node,next_cost,next_time;\n\tint A_min,B_min;\n\tpriority_queue<Info> Q;\n\n\tfor(int p = 0; p < return_start[start_id].size(); p++){ //start時刻を全探索\n\n\t\tint start_time = return_start[start_id][p].rev_start_time;\n\t\tint start_cost = return_start[start_id][p].sum_cost;\n\n\t\tfor(int a = 0; a < node_index; a++){\n\t\t\tfor(int k = start_time-BASE; k <= MAX; k++)return_min_cost[a][k] = BIG_NUM;\n\t\t}\n\n\t\treturn_min_cost[start_id][start_time-BASE] = 0; //★帰宅のコスト\n\t\tQ.push(Info(start_id,0,start_time));\n\n\t\tA_min = BIG_NUM;\n\t\tB_min = BIG_NUM;\n\n\t\twhile(!Q.empty()){\n\n\t\t\tif(Q.top().sum_cost > return_min_cost[Q.top().node_id][Q.top().current_time-BASE]){\n\t\t\t\tQ.pop();\n\t\t\t}else{\n\n\t\t\t\tfor(int i = 0; i < G[Q.top().node_id].size(); i++){\n\t\t\t\t\t//既に出発している、または有効時間外ならSKIP\n\t\t\t\t\tif(Q.top().current_time > G[Q.top().node_id][i].start_time)continue;\n\t\t\t\t\tif(rangeCheck(G[Q.top().node_id][i].start_time) == false || rangeCheck(G[Q.top().node_id][i].arrive_time) == false)continue;\n\n\t\t\t\t\tnext_node = G[Q.top().node_id][i].to;\n\t\t\t\t\tnext_cost = Q.top().sum_cost+G[Q.top().node_id][i].cost;\n\t\t\t\t\tnext_time = G[Q.top().node_id][i].arrive_time;\n\n\t\t\t\t\tif(return_min_cost[next_node][next_time-BASE] > next_cost){\n\t\t\t\t\t\treturn_min_cost[next_node][next_time-BASE] = next_cost;\n\n\t\t\t\t\t\tQ.push(Info(next_node,next_cost,next_time));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tQ.pop();\n\t\t\t}\n\t\t}\n\n\t\tfor(int time = start_time-BASE; time <= MAX; time++){\n\t\t\tif(return_min_cost[A_id][time] != BIG_NUM){\n\t\t\t\tA_min = min(A_min,return_min_cost[A_id][time]);\n\t\t\t}\n\t\t\tif(return_min_cost[B_id][time] != BIG_NUM){\n\t\t\t\tB_min = min(B_min,return_min_cost[B_id][time]);\n\t\t\t}\n\t\t}\n\n\t\tif(A_min == BIG_NUM || B_min == BIG_NUM)continue;\n\n\t\tret = min(ret,start_cost+A_min+B_min);\n\t}\n\treturn ret;\n}\n\nvoid func(){\n\n\tMAP.clear();\n\tfor(int i = 0; i < NUM; i++)G[i].clear();\n\n\tnode_index = 0;\n\n\tstring start,arrival;\n\tchar start_buf[6],arrive_buf[6];\n\tint start_time,arrive_time;\n\tint price,start_id,arrive_id;\n\n\tfor(int loop = 0; loop < N; loop++){\n\t\tcin >> start >> start_buf >> arrival >> arrive_buf >> price;\n\n\t\tauto at = MAP.find(start);\n\n\t\tif(at == MAP.end()){\n\t\t\tMAP[start] = node_index;\n\t\t\tstart_id = node_index;\n\t\t\tnode_index++;\n\n\t\t}else{\n\t\t\tstart_id = MAP[start];\n\t\t}\n\n\t\tat = MAP.find(arrival);\n\n\t\tif(at == MAP.end()){\n\t\t\tMAP[arrival] = node_index;\n\t\t\tarrive_id = node_index;\n\t\t\tnode_index++;\n\n\t\t}else{\n\t\t\tarrive_id = MAP[arrival];\n\t\t}\n\n\t\tstart_time = getNUM(start_buf);\n\t\tarrive_time = getNUM(arrive_buf);\n\n\t\tif(rangeCheck(start_time) == false || rangeCheck(arrive_time) == false)continue;\n\n\t\tG[start_id].push_back(Edge(arrive_id,price,start_time,arrive_time));\n\t}\n\n\tA_id = MAP[start_A];\n\tB_id = MAP[start_B];\n\n\t//函館、東京から、各都市への到着可能時刻と、同時刻での最小コストを求める\n\tdijkstra(A,A_id);\n\tdijkstra(B,B_id);\n\n\tfor(int town = 0; town < node_index; town++){\n\n\t\twork[A][town].clear();\n\t\twork[B][town].clear();\n\n\t\treturn_start[town].clear();\n\t}\n\n\tint rev_start_time,tmp_cost;\n\n\t//各町から、函館or北海道への、帰宅開始可能時刻をworkにpushする\n\tfor(int town = 0; town < node_index; town++){\n\t\tfor(int time = 0; time <= MAX; time++){\n\n\t\t\tif(min_cost[A][town][time] != BIG_NUM){\n\t\t\t\twork[A][town].push_back(time+BASE);\n\t\t\t}\n\n\t\t\tif(min_cost[B][town][time] != BIG_NUM){\n\t\t\t\twork[B][town].push_back(time+BASE);\n\t\t\t}\n\t\t}\n\n\t\t//★最低30分会うので、帰宅開始可能時刻と、そのコストを求める★\n\t\tif(work[A][town].size() == 0 || work[B][town].size() == 0)continue;\n\n\t\tCALC.clear();\n\n\t\tfor(int time = 1; time <= MAX; time++){\n\t\t\tmin_cost[A][town][time] = min(min_cost[A][town][time],min_cost[A][town][time-1]);\n\t\t\tmin_cost[B][town][time] = min(min_cost[B][town][time],min_cost[B][town][time-1]);\n\t\t}\n\n\t\tfor(int i = 0; i < work[A][town].size(); i++){\n\t\t\tfor(int k = 0; k < work[B][town].size(); k++){\n\t\t\t\trev_start_time = max(work[A][town][i],work[B][town][k])+30;\n\t\t\t\tif(!rangeCheck(rev_start_time))continue;\n\n\t\t\t\tauto at2 = CALC.find(rev_start_time);\n\t\t\t\ttmp_cost = min_cost[A][town][work[A][town][i]-BASE]+min_cost[B][town][work[B][town][k]-BASE];\n\n\t\t\t\tif(at2 == CALC.end() || tmp_cost < CALC[rev_start_time]){\n\t\t\t\t\tCALC[rev_start_time] = tmp_cost;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tfor(auto at3: CALC){\n\t\t\treturn_start[town].push_back(Data(at3.first,at3.second));\n\t\t}\n\t\tsort(return_start[town].begin(),return_start[town].end());\n\t}\n\n\t//各町から、出発時刻別の、函館または東京への帰宅最短コストを求める\n\tint ans = BIG_NUM;\n\tint ret;\n\n\tfor(int start_town = 0; start_town < node_index; start_town++){\n\t\tif(return_start[start_town].size() == 0)continue; //そもそも会えない街ならSKIP\n\n\t\tret = rev_dijkstra(start_town);\n\t\tif(ret == BIG_NUM)continue; //函館または東京に戻れないならSKIP\n\n\t\tans = min(ans,ret);\n\t}\n\n\tif(ans == BIG_NUM){\n\t\tprintf(\"0\\n\");\n\t}else{\n\t\tprintf(\"%d\\n\",ans);\n\t}\n}\n\nint main(){\n\n\twhile(true){\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3592, "score_of_the_acc": -0.1136, "final_rank": 4 }, { "submission_id": "aoj_1229_1526289", "code_snippet": "#include<bits/stdc++.h>\n\n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n\nusing namespace std;\n\nstruct Info {\n int fromStationID,toStationID;\n int fromTimeID,toTimeID;\n int cost;\n};\n\nconst int IINF = INT_MAX;\nconst int MAX_STATION = 100;\nconst int MAX_EVENT = 4000;\nint toDest[2][MAX_STATION][MAX_EVENT+10]; // toDest[0][][] <- hakodate, toDest[1][][] <- tokyo, toDest[][stationID][timeID] := ????????????stationID???timeID??????????????§?????°?????????????°?\nint fromDest[2][MAX_STATION][MAX_EVENT+10]; // fromDest[0][][] <- hakodate, fromDest[1][][] <- tokyo, fromDest[][stationID][timeID] := ???????????§???stationID??????timeID??????????????????????????°????????????????????????????????????????°????\n\nint stationIDIndex;\nmap<string,int> stationIDTable;\nvector<int> T;\n\nvoid init(){\n stationIDIndex = 0;\n stationIDTable.clear();\n T.clear();\n}\n\ninline int convertStringIntoTime(string s){\n return ( ( s[0] - '0' ) * 10 + ( s[1] - '0' ) ) * 60 + ( ( s[3] - '0' ) * 10 + ( s[4] - '0' ) ) ;\n}\n\ninline int calcTimeID(int _time) {\n return lower_bound(T.begin(),T.end(),_time) - T.begin();\n}\n\nInfo convertStringIntoInfo(string context){\n vector<string> buf;\n stringstream ss;\n ss << context;\n while( ss >> context ){\n buf.push_back(context);\n }\n assert( buf.size() == 5 );\n int fromStationID = ( stationIDTable.count(buf[0]) ? stationIDTable[buf[0]] : ( stationIDTable[buf[0]] = stationIDIndex++ ) );\n int toStationID = ( stationIDTable.count(buf[2]) ? stationIDTable[buf[2]] : ( stationIDTable[buf[2]] = stationIDIndex++ ) );\n int fromTime = convertStringIntoTime(buf[1]);\n int toTime = convertStringIntoTime(buf[3]);\n if( fromTime < convertStringIntoTime(\"08:00\") || toTime > convertStringIntoTime(\"18:00\") ) {\n return (Info){-1,-1,-1,-1,-1};\n }\n T.push_back(fromTime);\n T.push_back(toTime);\n return (Info){fromStationID,toStationID,fromTime,toTime,(atoi)(buf[4].c_str())};\n}\n\nbool cmp_to(const Info &a,const Info &b) {\n if( a.toTimeID != b.toTimeID) a.toTimeID < b.toTimeID;\n return a.fromTimeID < b.fromTimeID;\n}\n\nbool cmp_from(const Info &a,const Info &b) {\n if( a.fromTimeID != b.fromTimeID ) a.fromTimeID > b.fromTimeID;\n return a.toTimeID > b.toTimeID;\n}\n\nvoid makeToDest(vector<Info> &vec,int hakodateID,int tokyoID,int startTimeID,int endTimeID) {\n assert( startTimeID == 0 );\n rep(i,2) rep(j,stationIDIndex) rep(k,endTimeID+1) toDest[i][j][k] = IINF;\n toDest[0][hakodateID][startTimeID] = toDest[1][tokyoID][startTimeID] = 0;\n sort(vec.begin(),vec.end(),cmp_to);\n int cur = 0;\n\n REP(timeID,startTimeID,endTimeID+1){\n if( timeID-1 >= startTimeID ) {\n rep(stationID,stationIDIndex){\n\trep(j,2){\n\t toDest[j][stationID][timeID] = min(toDest[j][stationID][timeID],\n\t\t\t\t\t toDest[j][stationID][timeID-1]);\n\t}\n }\n }\n while( cur < (int)vec.size() && vec[cur].fromTimeID == timeID ){\n rep(j,2){\n\tif( toDest[j][vec[cur].fromStationID][timeID] == IINF ) continue;\n\ttoDest[j][vec[cur].toStationID][vec[cur].toTimeID] = min(toDest[j][vec[cur].toStationID][vec[cur].toTimeID],\n\t\t\t\t\t\t\t\t toDest[j][vec[cur].fromStationID][timeID]+vec[cur].cost);\n }\n ++cur;\n }\n }\n}\n\nvoid makeFromDest(vector<Info> &vec,int hakodateID,int tokyoID,int startTimeID,int endTimeID) {\n rep(i,2) rep(j,stationIDIndex) rep(k,endTimeID+1) fromDest[i][j][k] = IINF;\n fromDest[0][hakodateID][endTimeID] = fromDest[1][tokyoID][endTimeID] = 0;\n sort(vec.begin(),vec.end(),cmp_from);\n int cur = 0;\n for(int timeID=endTimeID;timeID>=startTimeID;timeID--){\n if( timeID+1 <= endTimeID ) {\n rep(stationID,stationIDIndex){\n\trep(j,2){\n\t fromDest[j][stationID][timeID] = min(fromDest[j][stationID][timeID],\n\t\t\t\t\t fromDest[j][stationID][timeID+1]);\n\t}\n }\n }\n while( cur < (int)vec.size() && vec[cur].toTimeID == timeID ) {\n rep(j,2){\n\tif( fromDest[j][vec[cur].toStationID][timeID] == IINF ) continue;\n\tfromDest[j][vec[cur].fromStationID][vec[cur].fromTimeID] = min(fromDest[j][vec[cur].fromStationID][vec[cur].fromTimeID],\n\t\t\t\t\t\t\t\t fromDest[j][vec[cur].toStationID][timeID]+vec[cur].cost);\n }\n ++cur;\n }\n }\n}\n\nvoid compute(vector<Info> &vec){\n\n if( !stationIDTable.count(\"Hakodate\") || !stationIDTable.count(\"Tokyo\") ) {\n puts(\"0\");\n return;\n }\n\n int hakodateID = stationIDTable[\"Hakodate\"];\n int tokyoID = stationIDTable[\"Tokyo\"];\n int startTimeID = calcTimeID(convertStringIntoTime(\"08:00\")); \n int endTimeID = calcTimeID(convertStringIntoTime(\"18:00\")); \n makeToDest(vec,hakodateID,tokyoID,startTimeID,endTimeID);\n makeFromDest(vec,hakodateID,tokyoID,startTimeID,endTimeID);\n\n int mini = IINF;\n rep(rendezvous,stationIDIndex){\n REP(timeID,startTimeID,endTimeID+1){\n if( toDest[0][rendezvous][timeID] == IINF || toDest[1][rendezvous][timeID] == IINF ) continue;\n int leaveTimeID = lower_bound(T.begin(),T.end(),T[timeID]+30) - T.begin();\n if( leaveTimeID >= (int)T.size() ) continue;\n if( fromDest[0][rendezvous][leaveTimeID] == IINF || fromDest[1][rendezvous][leaveTimeID] == IINF ) continue;\n mini = min(mini,\n\t\t toDest[0][rendezvous][timeID]+toDest[1][rendezvous][timeID]+\n\t\t fromDest[0][rendezvous][leaveTimeID]+fromDest[1][rendezvous][leaveTimeID]);\n }\n } \n if( mini == IINF ) puts(\"0\");\n else cout << mini << endl;\n}\n\nint main(){\n int n;\n while( cin >> n, n ) {\n init();\n cin.ignore();\n vector<Info> vec;\n rep(i,n){\n string s;\n getline(cin,s);\n Info info = convertStringIntoInfo(s);\n if( info.fromStationID == -1 ) continue;\n vec.push_back(info);\n }\n T.push_back(convertStringIntoTime(\"08:00\"));\n T.push_back(convertStringIntoTime(\"18:00\"));\n sort(T.begin(),T.end());\n T.erase(unique(T.begin(),T.end()),T.end());\n rep(i,(int)vec.size()) {\n vec[i].fromTimeID = calcTimeID(vec[i].fromTimeID);\n vec[i].toTimeID = calcTimeID(vec[i].toTimeID);\n }\n compute(vec);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5740, "score_of_the_acc": -0.1767, "final_rank": 6 }, { "submission_id": "aoj_1229_1131515", "code_snippet": "#include<string>\n#include<stdio.h>\n#include<algorithm>\n#include<queue>\n#include<vector>\n#include<map>\nusing namespace std;\nchar in[20];\nvector<pair<pair<int,int>,int> >g[110][1440];\nvector<pair<pair<int,int>,int> >g2[110][1440];\nint ijk[110][1440];\nint v[110][1440];\nint s[4][110][1440];\nint main(){\n\tint a;\n\twhile(scanf(\"%d\",&a),a){\n\t\tfor(int i=0;i<110;i++)for(int j=0;j<1440;j++){\n\t\t\tg[i][j].clear();\n\t\t\tg2[i][j].clear();\n\t\t}\n\t\tmap<string,int>m;\n\t\tm[\"Hakodate\"]=0;\n\t\tm[\"Tokyo\"]=1;\n\t\tint n=2;\n\t\tfor(int i=0;i<a;i++){\n\t\t\tscanf(\"%s\",in);\n\t\t\tstring na=in;\n\t\t\tif(!m.count(na))m[na]=n++;\n\t\t\tint p=m[na];\n\t\t\tint H,M;\n\t\t\tscanf(\"%d:%d\",&H,&M);\n\t\t\tint t1=H*60+M;\n\t\t\tscanf(\"%s\",in);\n\t\t\tstring nb=in;\n\t\t\tif(!m.count(nb))m[nb]=n++;\n\t\t\tint q=m[nb];\n\t\t\tscanf(\"%d:%d\",&H,&M);\n\t\t\tint t2=H*60+M;\n\t\t\tint r;\n\t\t\tscanf(\"%d\",&r);\n\t\t\tg[p][t1].push_back(make_pair(make_pair(q,t2),r));\n\t\t\tg2[q][t2].push_back(make_pair(make_pair(p,t1),r));\n\t\t}\n\t\tfor(int i=0;i<110;i++)for(int j=0;j<1440;j++){\n\t\t\tv[i][j]=0;ijk[i][j]=99999999;\n\t\t}\n\t\tpriority_queue<pair<int,pair<int,int> > > Q;\n\t\tQ.push(make_pair(0,make_pair(0,480)));\n\t\tijk[0][480]=0;\n\t\twhile(Q.size()){\n\t\t\tint cost=-Q.top().first;\n\t\t\tint at=Q.top().second.first;\n\t\t\tint t=Q.top().second.second;\n\t\t\tQ.pop();\n\t\t\tif(v[at][t])continue;\n\t\t\tv[at][t]=1;\n\t\t\tif(t<1080&&!v[at][t+1]&&ijk[at][t+1]>cost){\n\t\t\t\tijk[at][t+1]=cost;\n\t\t\t\tQ.push(make_pair(-cost,make_pair(at,t+1)));\n\t\t\t}\n\t\t\tfor(int i=0;i<g[at][t].size();i++){\n\t\t\t\tint x=g[at][t][i].first.first;\n\t\t\t\tint y=g[at][t][i].first.second;\n\t\t\t\tint z=g[at][t][i].second;\n\t\t\t\tif(!v[x][y]&&ijk[x][y]>cost+z){\n\t\t\t\t\tijk[x][y]=cost+z;\n\t\t\t\t\tQ.push(make_pair(-cost-z,make_pair(x,y)));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<n;i++)for(int j=0;j<1440;j++)\n\t\t\ts[0][i][j]=ijk[i][j];\n\t\tfor(int i=0;i<110;i++)for(int j=0;j<1440;j++){\n\t\t\tv[i][j]=0;ijk[i][j]=99999999;\n\t\t}\n\t\tQ.push(make_pair(0,make_pair(1,480)));\n\t\tijk[1][480]=0;\n\t\twhile(Q.size()){\n\t\t\tint cost=-Q.top().first;\n\t\t\tint at=Q.top().second.first;\n\t\t\tint t=Q.top().second.second;\n\t\t\tQ.pop();\n\t\t\tif(v[at][t])continue;\n\t\t\tv[at][t]=1;\n\t\t\tif(t<1080&&!v[at][t+1]&&ijk[at][t+1]>cost){\n\t\t\t\tijk[at][t+1]=cost;\n\t\t\t\tQ.push(make_pair(-cost,make_pair(at,t+1)));\n\t\t\t}\n\t\t\tfor(int i=0;i<g[at][t].size();i++){\n\t\t\t\tint x=g[at][t][i].first.first;\n\t\t\t\tint y=g[at][t][i].first.second;\n\t\t\t\tint z=g[at][t][i].second;\n\t\t\t\tif(!v[x][y]&&ijk[x][y]>cost+z){\n\t\t\t\t\tijk[x][y]=cost+z;\n\t\t\t\t\tQ.push(make_pair(-cost-z,make_pair(x,y)));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<n;i++)for(int j=0;j<1440;j++)\n\t\t\ts[1][i][j]=ijk[i][j];\n\t\tfor(int i=0;i<110;i++)for(int j=0;j<1440;j++){\n\t\t\tv[i][j]=0;ijk[i][j]=99999999;\n\t\t}\n\t\tQ.push(make_pair(0,make_pair(0,1080)));\n\t\tijk[0][1080]=0;\n\t\twhile(Q.size()){\n\t\t\tint cost=-Q.top().first;\n\t\t\tint at=Q.top().second.first;\n\t\t\tint t=Q.top().second.second;\n\t\t\tQ.pop();\n\t\t\tif(v[at][t])continue;\n\t\t\tv[at][t]=1;\n\t\t\tif(t>480&&!v[at][t-1]&&ijk[at][t-1]>cost){\n\t\t\t\tijk[at][t-1]=cost;\n\t\t\t\tQ.push(make_pair(-cost,make_pair(at,t-1)));\n\t\t\t}\n\t\t\tfor(int i=0;i<g2[at][t].size();i++){\n\t\t\t\tint x=g2[at][t][i].first.first;\n\t\t\t\tint y=g2[at][t][i].first.second;\n\t\t\t\tint z=g2[at][t][i].second;\n\t\t\t\tif(!v[x][y]&&ijk[x][y]>cost+z){\n\t\t\t\t\tijk[x][y]=cost+z;\n\t\t\t\t\tQ.push(make_pair(-cost-z,make_pair(x,y)));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<n;i++)for(int j=0;j<1440;j++)\n\t\t\ts[2][i][j]=ijk[i][j];\n\t\tfor(int i=0;i<110;i++)for(int j=0;j<1440;j++){\n\t\t\tv[i][j]=0;ijk[i][j]=99999999;\n\t\t}\n\t\tQ.push(make_pair(0,make_pair(1,1080)));\n\t\tijk[1][1080]=0;\n\t\twhile(Q.size()){\n\t\t\tint cost=-Q.top().first;\n\t\t\tint at=Q.top().second.first;\n\t\t\tint t=Q.top().second.second;\n\t\t\tQ.pop();\n\t\t\tif(v[at][t])continue;\n\t\t\tv[at][t]=1;\n\t\t\tif(t>480&&!v[at][t-1]&&ijk[at][t-1]>cost){\n\t\t\t\tijk[at][t-1]=cost;\n\t\t\t\tQ.push(make_pair(-cost,make_pair(at,t-1)));\n\t\t\t}\n\t\t\tfor(int i=0;i<g2[at][t].size();i++){\n\t\t\t\tint x=g2[at][t][i].first.first;\n\t\t\t\tint y=g2[at][t][i].first.second;\n\t\t\t\tint z=g2[at][t][i].second;\n\t\t\t\tif(!v[x][y]&&ijk[x][y]>cost+z){\n\t\t\t\t\tijk[x][y]=cost+z;\n\t\t\t\t\tQ.push(make_pair(-cost-z,make_pair(x,y)));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<n;i++)for(int j=0;j<1440;j++)\n\t\t\ts[3][i][j]=ijk[i][j];\n\t\tint ret=999999999;\n\t\tfor(int i=0;i<n;i++){\n\t\t\tfor(int j=480;j<=1410;j++){\n\t\t\t\tret=min(ret,s[0][i][j]+s[1][i][j]+s[2][i][j+30]+s[3][i][j+30]);\n\t\t\t}\n\t\t}\n\t\tif(ret>99999999)printf(\"0\\n\");\n\t\telse printf(\"%d\\n\",ret);\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 10864, "score_of_the_acc": -0.3345, "final_rank": 8 }, { "submission_id": "aoj_1229_960812", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <sstream>\n#include <cstring>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n#include <numeric>\n#include <cctype>\n#include <tuple>\n#include <iterator>\n#include <bitset>\n#include <random>\n#include <assert.h>\n#include <unordered_map>\n\n#ifdef _MSC_VER\n#include <agents.h>\n#endif\n\n#define FOR(i, a, b) for(int i = (a); i < (int)(b); ++i)\n#define rep(i, n) FOR(i, 0, n)\n#define ALL(v) v.begin(), v.end()\n#define REV(v) v.rbegin(), v.rend()\n#define MEMSET(v, s) memset(v, s, sizeof(v))\n#define X first\n#define Y second\n#define MP make_pair\n#define umap unordered_map\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\ntypedef pair<int, int> P;\n\nconst int N = 110;\nconst int T = 610;\n\nint cost[4][N*T];\n\ninline int f(int n, int t){\n\treturn n*T + t;\n}\n\nvector<P> G[N*T], rev[N*T];\nvector<int> v[N];\n\nvoid dijk(int start, int t, int *opt, vector<P> *graph){\n\topt[f(start, t)] = 0;\n\tpriority_queue<P, vector<P>, greater<P>> q;\n\tq.push(MP(0, f(start, t)));\n\n\twhile (!q.empty()){\n\t\tint d = q.top().first;\n\t\tint pos = q.top().second;\n\n\t\tq.pop();\n\n\t\tif (opt[pos] < d) continue;\n\n\t\tfor (auto &e : graph[pos]){\n\t\t\tif (opt[e.first] <= d + e.second)continue;\n\t\t\topt[e.first] = d + e.second;\n\t\t\tq.push(MP(d + e.second, e.first));\n\t\t}\n\t}\n}\n\nvoid pp(int i, int pos, int t){\n\tcout << (i % 2 ? \"to\" : \"from\") << \" \" << (i / 2 ? \"Hakodate\" : \"Tokyo\") << endl;\n\tcout << cost[i][f(pos, t)] << endl;\n}\n\nint main(){\n\tint n;\n\twhile (cin >> n, n){\n\t\trep(i, N*T) G[i].clear();\n\t\trep(i, N*T) rev[i].clear();\n\t\trep(i, N) v[i].clear(), v[i].push_back(0), v[i].push_back(600);\n\n\t\tmap<string, int> m;\n\t\tint idx = 0;\n\t\tm[\"Tokyo\"] = idx++;\n\t\tm[\"Hakodate\"] = idx++;\n\t\trep(i, n){\n\t\t\tstring s, t;\n\t\t\tint h1, m1, h2, m2, cost;\n\t\t\tchar c;\n\t\t\tcin >> s >> h1 >> c >> m1 >> t >> h2 >> c >> m2 >> cost;\n\t\t\tint t1 = h1 * 60 + m1 - 480, t2 = h2 * 60 + m2 - 480;\n\t\t\tif (0 <= t1 && t1 <= 600 && 0 <= t2 && t2 <= 600){\n\t\t\t\tif (!m.count(s)) m[s] = idx++;\n\t\t\t\tif (!m.count(t)) m[t] = idx++;\n\t\t\t\tint from = f(m[s], t1), to = f(m[t], t2);\n\t\t\t\tG[from].push_back(MP(to, cost));\n\t\t\t\trev[to].push_back(MP(from, cost));\n\t\t\t\tv[m[s]].push_back(t1);\n\t\t\t\tv[m[t]].push_back(t2);\n\t\t\t}\n\t\t}\n\n\t\trep(i, idx){\n\t\t\tsort(ALL(v[i]));\n\t\t\tv[i].erase(unique(ALL(v[i])), v[i].end());\n\t\t\trep(j, v[i].size()){\n\t\t\t\tif (j + 1 < v[i].size()) G[f(i, v[i][j])].push_back(MP(f(i, v[i][j + 1]), 0));\n\t\t\t\tif (j - 1 >= 0) rev[f(i, v[i][j])].push_back(MP(f(i, v[i][j - 1]), 0));\n\t\t\t}\n\t\t}\n\n\t\trep(i, 4){\n\t\t\tMEMSET(cost[i], 0x7f);\n\t\t\t// Tokyo -> x, x -> Tokyo, Hakodate -> x, x -> Hakodate\n\t\t\tdijk(i / 2, i % 2 ? 600 : 0, cost[i], i % 2 ? rev : G);\n\t\t}\n\n\t\trep(k, 2) rep(i, idx){\n\t\t\tfor (int j = 0+1; j <= 600; ++j){\n\t\t\t\tcost[k * 2][f(i, j)] = min(cost[k * 2][f(i, j)], cost[k * 2][f(i, j - 1)]);\n\t\t\t}\n\t\t\tfor (int j = 600-1; j >= 0; --j){\n\t\t\t\tcost[k * 2 + 1][f(i, j)] = min(cost[k * 2 + 1][f(i, j)], cost[k * 2 + 1][f(i, j + 1)]);\n\t\t\t}\n\t\t}\n\n\t\tint ans = 1e9;\n\t\trep(i, idx) for (int j = 0; j <= 600 - 30; ++j){\n\t\t\t//pp(0, i, j);\n\t\t\t//pp(1, i, j+30);\n\t\t\t//pp(2, i, j);\n\t\t\t//pp(3, i, j+30);\n\t\t\tint a = f(i, j), b = f(i, j + 30);\n\t\t\tif ((cost[0][a] | cost[1][b] | cost[2][a] | cost[3][b]) >= ans) continue;\n\t\t\tans = min(ans, cost[0][a] + cost[1][b] + cost[2][a] + cost[3][b]);\n\t\t}\n\t\tcout << (ans < 1e9 ? ans : 0) << endl;\n\t}\n\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5608, "score_of_the_acc": -0.1727, "final_rank": 5 }, { "submission_id": "aoj_1229_505246", "code_snippet": "#include<iostream>\n#include<queue>\n#include<string>\n#include<map>\n#include<cstdlib>\n#include<algorithm>\n#include<functional>\n#include<set>\n#include<cstdio>\n#include<cassert>\n\nusing namespace std;\n\n#define foreach(i,o) for(__typeof((o).begin()) i = (o).begin(); i != (o).end(); ++i)\n\nconst int max_place = 101;\nconst int max_time = 601;\nconst int MAX_V = 2010;\nconst int inf = 1<<28;\n\nstruct edge{\n int src, dst;\n int cost;\n edge(int src, int dst, int cost):src(src), dst(dst), cost(cost){}\n};\n\nstruct state{\n int pos;\n int prev;\n int cost;\n \n state(int pos, int prev, int cost):pos(pos),prev(prev),cost(cost){}\n\n bool operator>(const state &t)const{\n if(cost!=t.cost)return cost>t.cost;\n if(prev!=t.prev)return prev>t.prev;\n if(pos!=t.pos)return pos>t.pos;\n return false;\n }\n};\n\ntypedef vector<edge> edges;\ntypedef vector<edges> graph;\n\nint convTime(const string &s){\n int h = atoi(s.substr(0,2).c_str());\n int m = atoi(s.substr(3,2).c_str());\n return 60 * h + m;\n}\n\nstring revTime(int t){\n char buf[32];\n sprintf(buf, \"%02d:%02d\", t/60, t%60);\n return string(buf);\n}\n\nint **dist = NULL;\nvoid johnson(const graph &tmp_g){\n graph g = tmp_g;\n const int v = g.size();\n \n for(int i = 0; i < v; ++i){\n dist[i] = new int[v];\n for(int j = 0; j < v; ++j){\n dist[i][j] = inf;\n }\n dist[i][i] = 0;\n }\n\n for(int s = 0; s < v; ++s){\n priority_queue<state, vector<state>, greater<state> > q;\n q.push(state(s,s,0));\n while(!q.empty()){\n state cur = q.top(); q.pop();\n for(int i = 0; i < (int)g[cur.pos].size(); ++i){\n edge e = g[cur.pos][i];\n int cost = cur.cost + e.cost;\n assert(cost>=0);\n if(dist[s][e.dst] > cost){\n dist[s][e.dst] = cost;\n q.push(state(e.dst,cur.pos,cost));\n }\n }\n }\n }\n \n return ; \n}\n\nint main()\n{\n int n;\n while(cin>>n && n){\n int id = 1;\n int vid = 0;\n map<string,int> cityDict;\n map<int,string> revCityDict;\n set<int> cityEvTimes[max_place];\n graph g(MAX_V);\n \n map<pair<int,int>, int> vID;\n map<int,pair<int,int> > revID;\n \n for(int i = 0; i < n; ++i){\n string from, ftime, to, ttime;\n int cost;\n\n cin >> from >> ftime >> to >> ttime >> cost;\n if(!cityDict.count(from)){\n cityDict[from] = id;\n revCityDict[id] = from;\n ++id;\n }\n if(!cityDict.count(to)){\n cityDict[to] = id;\n revCityDict[id] = to;\n ++id;\n }\n\n int src = cityDict[from];\n int dst = cityDict[to];\n int srcTime = convTime(ftime) - 480;\n int dstTime = convTime(ttime) - 480;\n \n if( dstTime >= 0 && dstTime < max_time && srcTime >= 0 && srcTime < max_time ){\n if( !vID.count(make_pair(src,srcTime)) ){\n vID[make_pair(src,srcTime)] = vid;\n revID[vid] = make_pair(src,srcTime);\n ++vid;\n }\n cityEvTimes[src].insert(srcTime);\n if( !vID.count(make_pair(dst,dstTime)) ){\n vID[make_pair(dst,dstTime)] = vid;\n revID[vid] = make_pair(dst,dstTime);\n ++vid;\n }\n cityEvTimes[dst].insert(dstTime);\n \n g[vID[make_pair(src,srcTime)]].push_back( edge(vID[make_pair(src,srcTime)], vID[make_pair(dst,dstTime)], cost) );\n }\n\n }\n g.resize(vID.size());\n \n for(int i = 1; i < id; ++i){\n foreach(it2, cityEvTimes[i]){\n set<int>::iterator it3 = it2;\n ++it3;\n if( it3 != cityEvTimes[i].end() ){\n g[vID[make_pair(i,*it2)]].push_back( edge(vID[make_pair(i,*it2)], vID[make_pair(i,*it3)], 0) );\n }\n }\n }\n \n dist=new int*[g.size()];\n for(int i = 0; i < (int)g.size(); ++i){\n dist[i] = new int[g.size()];\n }\n \n johnson(g);\n\n int res = inf;\n int kenInitial = cityDict[\"Tokyo\"];\n int keikoInitial = cityDict[\"Hakodate\"];\n\n int ken_st, keiko_st;\n if( cityEvTimes[kenInitial].size() > 0 && cityEvTimes[keikoInitial].size() > 0 ){\n ken_st = vID[make_pair(kenInitial, *(cityEvTimes[kenInitial].begin()))];\n keiko_st = vID[make_pair(keikoInitial, *(cityEvTimes[keikoInitial].begin()))];\n\n for(int i = 1; i < id; ++i){\n foreach(ev1, cityEvTimes[i]){\n int v1 = vID[make_pair(i,*ev1)];\n foreach(ev2, cityEvTimes[i]){\n int v2 = vID[make_pair(i,*ev2)];\n int st = max(*ev1, *ev2) + 30;\n int from = -1;\n\n if(cityEvTimes[i].lower_bound(st)!=cityEvTimes[i].end()){\n from = vID[make_pair(i,*(cityEvTimes[i].lower_bound(st)))];\n }\n if(from<0)continue;\n foreach(ev3, cityEvTimes[kenInitial]){\n if( *ev3 < st ) continue;\n int v3 = vID[make_pair(kenInitial,*ev3)];\n foreach(ev4, cityEvTimes[keikoInitial]){\n if( *ev4 < st ) continue;\n int v4 = vID[make_pair(keikoInitial, *ev4)];\n res = min(res, dist[ken_st][v1] + dist[keiko_st][v2] + dist[from][v3] + dist[from][v4]);\n }\n }\n }\n }\n }\n }\n \n\n if(res>=inf)res = 0;\n cout << res << endl;\n\n for(int i = 0; i < (int)g.size(); ++i){\n delete [] dist[i];\n }\n delete [] dist;\n \n }\n return 0;\n}", "accuracy": 1, "time_ms": 1550, "memory_kb": 23180, "score_of_the_acc": -0.9418, "final_rank": 10 }, { "submission_id": "aoj_1229_505244", "code_snippet": "#include<iostream>\n#include<queue>\n#include<string>\n#include<map>\n#include<cstdlib>\n#include<algorithm>\n#include<functional>\n#include<set>\n#include<cstdio>\n#include<cassert>\n\nusing namespace std;\n\n#define foreach(i,o) for(__typeof((o).begin()) i = (o).begin(); i != (o).end(); ++i)\n\nconst int max_place = 101;\nconst int max_time = 601;\nconst int MAX_V = 2010;\nconst int inf = 1<<28;\n\nstruct edge{\n int src, dst;\n int cost;\n edge(int src, int dst, int cost):src(src), dst(dst), cost(cost){}\n};\n\nstruct state{\n int pos;\n int prev;\n int cost;\n \n state(int pos, int prev, int cost):pos(pos),prev(prev),cost(cost){}\n\n bool operator>(const state &t)const{\n if(cost!=t.cost)return cost>t.cost;\n if(prev!=t.prev)return prev>t.prev;\n if(pos!=t.pos)return pos>t.pos;\n return false;\n }\n};\n\ntypedef vector<edge> edges;\ntypedef vector<edges> graph;\n\nint convTime(const string &s){\n int h = atoi(s.substr(0,2).c_str());\n int m = atoi(s.substr(3,2).c_str());\n return 60 * h + m;\n}\n\nstring revTime(int t){\n char buf[32];\n sprintf(buf, \"%02d:%02d\", t/60, t%60);\n return string(buf);\n}\n\n// static int dist[MAX_V][MAX_V];\nint **dist = NULL;\n// = new int* [v];\nvoid johnson(const graph &tmp_g){\n graph g = tmp_g;\n \n const int v = g.size();\n // [v];\n // int **prev = new static int prev[MAX_V][MAX_V];\n \n for(int i = 0; i < v; ++i){\n dist[i] = new int[v];\n for(int j = 0; j < v; ++j){\n dist[i][j] = inf;\n // prev[i][j] = -1;\n }\n dist[i][i] = 0;\n }\n\n for(int s = 0; s < v; ++s){\n priority_queue<state, vector<state>, greater<state> > q;\n q.push(state(s,s,0));\n // bool vis[v]\n while(!q.empty()){\n state cur = q.top(); q.pop();\n // if(prev[s][cur.pos]!=-1)continue;\n // prev[s][cur.pos] = cur.prev;\n for(int i = 0; i < (int)g[cur.pos].size(); ++i){\n edge e = g[cur.pos][i];\n int cost = cur.cost + e.cost;\n assert(cost>=0);\n if(dist[s][e.dst] > cost){\n dist[s][e.dst] = cost;\n q.push(state(e.dst,cur.pos,cost));\n }\n }\n }\n }\n \n return ; \n}\n\nint main()\n{\n int n;\n while(cin>>n && n){\n int id = 1;\n int vid = 0;\n map<string,int> cityDict;\n map<int,string> revCityDict;\n set<int> cityEvTimes[max_place];\n graph g(MAX_V);\n \n map<pair<int,int>, int> vID;\n map<int,pair<int,int> > revID;\n \n for(int i = 0; i < n; ++i){\n string from, ftime, to, ttime;\n int cost;\n\n cin >> from >> ftime >> to >> ttime >> cost;\n if(!cityDict.count(from)){\n cityDict[from] = id;\n revCityDict[id] = from;\n ++id;\n }\n if(!cityDict.count(to)){\n cityDict[to] = id;\n revCityDict[id] = to;\n ++id;\n }\n\n int src = cityDict[from];\n int dst = cityDict[to];\n int srcTime = convTime(ftime) - 480;\n int dstTime = convTime(ttime) - 480;\n \n if( dstTime >= 0 && dstTime < max_time && srcTime >= 0 && srcTime < max_time ){\n if( !vID.count(make_pair(src,srcTime)) ){\n vID[make_pair(src,srcTime)] = vid;\n revID[vid] = make_pair(src,srcTime);\n ++vid;\n }\n cityEvTimes[src].insert(srcTime);\n if( !vID.count(make_pair(dst,dstTime)) ){\n vID[make_pair(dst,dstTime)] = vid;\n revID[vid] = make_pair(dst,dstTime);\n ++vid;\n }\n cityEvTimes[dst].insert(dstTime);\n \n g[vID[make_pair(src,srcTime)]].push_back( edge(vID[make_pair(src,srcTime)], vID[make_pair(dst,dstTime)], cost) );\n }\n\n }\n g.resize(vID.size());\n \n for(int i = 1; i < id; ++i){\n foreach(it2, cityEvTimes[i]){\n set<int>::iterator it3 = it2;\n ++it3;\n if( it3 != cityEvTimes[i].end() ){\n g[vID[make_pair(i,*it2)]].push_back( edge(vID[make_pair(i,*it2)], vID[make_pair(i,*it3)], 0) );\n }\n }\n }\n \n dist=new int*[g.size()];\n for(int i = 0; i < (int)g.size(); ++i){\n dist[i] = new int[g.size()];\n }\n \n johnson(g);\n\n int res = inf;\n int kenInitial = cityDict[\"Tokyo\"];\n int keikoInitial = cityDict[\"Hakodate\"];\n\n int ken_st, keiko_st;\n if( cityEvTimes[kenInitial].size() > 0 && cityEvTimes[keikoInitial].size() > 0 ){\n ken_st = vID[make_pair(kenInitial, *(cityEvTimes[kenInitial].begin()))];\n keiko_st = vID[make_pair(keikoInitial, *(cityEvTimes[keikoInitial].begin()))];\n\n for(int i = 1; i < id; ++i){\n foreach(ev1, cityEvTimes[i]){\n int v1 = vID[make_pair(i,*ev1)];\n foreach(ev2, cityEvTimes[i]){\n int v2 = vID[make_pair(i,*ev2)];\n int st = max(*ev1, *ev2) + 30;\n int from = -1;\n\n if(cityEvTimes[i].lower_bound(st)!=cityEvTimes[i].end()){\n from = vID[make_pair(i,*(cityEvTimes[i].lower_bound(st)))];\n }\n if(from<0)continue;\n foreach(ev3, cityEvTimes[kenInitial]){\n if( *ev3 < st ) continue;\n int v3 = vID[make_pair(kenInitial,*ev3)];\n foreach(ev4, cityEvTimes[keikoInitial]){\n if( *ev4 < st ) continue;\n int v4 = vID[make_pair(keikoInitial, *ev4)];\n res = min(res, dist[ken_st][v1] + dist[keiko_st][v2] + dist[from][v3] + dist[from][v4]);\n }\n }\n }\n }\n }\n \n }\n \n\n if(res>=inf)res = 0;\n cout << res << endl;\n\n for(int i = 0; i < (int)g.size(); ++i){\n delete [] dist[i];\n }\n delete [] dist;\n \n }\n return 0;\n}", "accuracy": 1, "time_ms": 1540, "memory_kb": 23184, "score_of_the_acc": -0.9405, "final_rank": 9 }, { "submission_id": "aoj_1229_505240", "code_snippet": "#include<iostream>\n#include<queue>\n#include<string>\n#include<map>\n#include<cstdlib>\n#include<algorithm>\n#include<functional>\n#include<set>\n#include<cstdio>\n#include<cassert>\n\nusing namespace std;\n\n#define foreach(i,o) for(__typeof((o).begin()) i = (o).begin(); i != (o).end(); ++i)\n\nconst int max_place = 101;\nconst int max_time = 601;\nconst int MAX_V = 2010;\nconst int inf = 1<<28;\n\nstruct edge{\n int src, dst;\n int cost;\n edge(int src, int dst, int cost):src(src), dst(dst), cost(cost){}\n};\n\nstruct state{\n int pos;\n int prev;\n int cost;\n \n state(int pos, int prev, int cost):pos(pos),prev(prev),cost(cost){}\n\n bool operator>(const state &t)const{\n if(cost!=t.cost)return cost>t.cost;\n if(prev!=t.prev)return prev>t.prev;\n if(pos!=t.pos)return pos>t.pos;\n return false;\n }\n};\n\ntypedef vector<edge> edges;\ntypedef vector<edges> graph;\n\nint convTime(const string &s){\n int h = atoi(s.substr(0,2).c_str());\n int m = atoi(s.substr(3,2).c_str());\n return 60 * h + m;\n}\n\nstring revTime(int t){\n char buf[32];\n sprintf(buf, \"%02d:%02d\", t/60, t%60);\n return string(buf);\n}\n\nstatic int dist[MAX_V][MAX_V];\nvoid johnson(const graph &tmp_g){\n graph g = tmp_g;\n \n const int v = g.size();\n //static int h[MAX_V];\n static int prev[MAX_V][MAX_V];\n \n\n /*\n for(int i = 0; i < v; ++i){\n h[i] = 0;\n }\n */\n\n /*\n for(int i = 0; i <= v; ++i){\n bool end = true;\n for(int j = 0; j < v; ++j){\n for(int k = 0; k < (int)g[j].size(); ++k){\n edge e = g[j][k];\n int tmp = h[j] + e.cost;\n if( h[e.dst] > tmp ){\n h[e.dst] = tmp;\n end = false;\n }\n }\n }\n if(end)break;\n // do not detect an negative cycle.\n }\n */\n\n for(int i = 0; i < v; ++i){\n for(int j = 0; j < v; ++j){\n dist[i][j] = inf;\n prev[i][j] = -1;\n }\n dist[i][i] = 0;\n }\n\n /*\n for(int i = 0; i < v; ++i){\n for(int j = 0; j < (int)g[i].size(); ++j){\n g[i][j].cost += h[i] - h[g[i][j].dst];\n }\n }\n */\n\n for(int s = 0; s < v; ++s){\n priority_queue<state, vector<state>, greater<state> > q;\n q.push(state(s,s,0));\n while(!q.empty()){\n state cur = q.top(); q.pop();\n if(prev[s][cur.pos]!=-1)continue;\n prev[s][cur.pos] = cur.prev;\n for(int i = 0; i < (int)g[cur.pos].size(); ++i){\n edge e = g[cur.pos][i];\n int cost = cur.cost + e.cost;\n assert(cost>=0);\n if(dist[s][e.dst] > cost){\n dist[s][e.dst] = cost;\n q.push(state(e.dst,cur.pos,cost));\n }\n }\n }\n // for(int i = 0; i < v; ++i){\n //dist[s][i] += h[i] - h[s];\n //}\n }\n\n return ; \n}\n\nint main()\n{\n int n;\n while(cin>>n && n){\n int id = 1;\n int vid = 0;\n map<string,int> cityDict;\n map<int,string> revCityDict;\n set<int> cityEvTimes[max_place];\n graph g(MAX_V);\n \n map<pair<int,int>, int> vID;\n map<int,pair<int,int> > revID;\n \n for(int i = 0; i < n; ++i){\n string from, ftime, to, ttime;\n int cost;\n\n cin >> from >> ftime >> to >> ttime >> cost;\n if(!cityDict.count(from)){\n cityDict[from] = id;\n revCityDict[id] = from;\n ++id;\n }\n if(!cityDict.count(to)){\n cityDict[to] = id;\n revCityDict[id] = to;\n ++id;\n }\n\n int src = cityDict[from];\n int dst = cityDict[to];\n int srcTime = convTime(ftime) - 480;\n int dstTime = convTime(ttime) - 480;\n \n if( dstTime >= 0 && dstTime < max_time && srcTime >= 0 && srcTime < max_time ){\n if( !vID.count(make_pair(src,srcTime)) ){\n vID[make_pair(src,srcTime)] = vid;\n revID[vid] = make_pair(src,srcTime);\n ++vid;\n }\n cityEvTimes[src].insert(srcTime);\n if( !vID.count(make_pair(dst,dstTime)) ){\n vID[make_pair(dst,dstTime)] = vid;\n revID[vid] = make_pair(dst,dstTime);\n ++vid;\n }\n cityEvTimes[dst].insert(dstTime);\n \n g[vID[make_pair(src,srcTime)]].push_back( edge(vID[make_pair(src,srcTime)], vID[make_pair(dst,dstTime)], cost) );\n }\n\n }\n g.resize(vID.size());\n \n for(int i = 1; i < id; ++i){\n foreach(it2, cityEvTimes[i]){\n set<int>::iterator it3 = it2;\n ++it3;\n if( it3 != cityEvTimes[i].end() ){\n g[vID[make_pair(i,*it2)]].push_back( edge(vID[make_pair(i,*it2)], vID[make_pair(i,*it3)], 0) );\n }\n }\n }\n \n johnson(g);\n\n int res = inf;\n int kenInitial = cityDict[\"Tokyo\"];\n int keikoInitial = cityDict[\"Hakodate\"];\n\n int ken_st, keiko_st;\n if( cityEvTimes[kenInitial].size() > 0 && cityEvTimes[keikoInitial].size() > 0 ){\n ken_st = vID[make_pair(kenInitial, *(cityEvTimes[kenInitial].begin()))];\n keiko_st = vID[make_pair(keikoInitial, *(cityEvTimes[keikoInitial].begin()))];\n\n for(int i = 1; i < id; ++i){\n foreach(ev1, cityEvTimes[i]){\n int v1 = vID[make_pair(i,*ev1)];\n foreach(ev2, cityEvTimes[i]){\n int v2 = vID[make_pair(i,*ev2)];\n int st = max(*ev1, *ev2) + 30;\n int from = -1;\n\n if(cityEvTimes[i].lower_bound(st)!=cityEvTimes[i].end()){\n from = vID[make_pair(i,*(cityEvTimes[i].lower_bound(st)))];\n }\n if(from<0)continue;\n foreach(ev3, cityEvTimes[kenInitial]){\n if( *ev3 < st ) continue;\n int v3 = vID[make_pair(kenInitial,*ev3)];\n foreach(ev4, cityEvTimes[keikoInitial]){\n if( *ev4 < st ) continue;\n int v4 = vID[make_pair(keikoInitial, *ev4)];\n res = min(res, dist[ken_st][v1] + dist[keiko_st][v2] + dist[from][v3] + dist[from][v4]);\n }\n }\n }\n }\n }\n \n }\n \n\n if(res>=inf)res = 0;\n cout << res << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1670, "memory_kb": 32480, "score_of_the_acc": -1.2459, "final_rank": 13 }, { "submission_id": "aoj_1229_505238", "code_snippet": "#include<iostream>\n#include<queue>\n#include<string>\n#include<map>\n#include<cstdlib>\n#include<algorithm>\n#include<functional>\n#include<set>\n#include<cstdio>\n#include<cassert>\n\nusing namespace std;\n\n#define foreach(i,o) for(__typeof((o).begin()) i = (o).begin(); i != (o).end(); ++i)\n\nconst int max_place = 101;\nconst int max_time = 601;\nconst int MAX_V = 2010;\nconst int inf = 1<<28;\n\nstruct edge{\n int src, dst;\n int cost;\n edge(int src, int dst, int cost):src(src), dst(dst), cost(cost){}\n};\n\nstruct state{\n int pos;\n int prev;\n int cost;\n \n state(int pos, int prev, int cost):pos(pos),prev(prev),cost(cost){}\n\n bool operator>(const state &t)const{\n if(cost!=t.cost)return cost>t.cost;\n if(prev!=t.prev)return prev>t.prev;\n if(pos!=t.pos)return pos>t.pos;\n return false;\n }\n};\n\ntypedef vector<edge> edges;\ntypedef vector<edges> graph;\n\nint convTime(const string &s){\n int h = atoi(s.substr(0,2).c_str());\n int m = atoi(s.substr(3,2).c_str());\n return 60 * h + m;\n}\n\nstring revTime(int t){\n char buf[32];\n sprintf(buf, \"%02d:%02d\", t/60, t%60);\n return string(buf);\n}\n\nstatic int dist[MAX_V][MAX_V];\nvoid johnson(const graph &tmp_g){\n graph g = tmp_g;\n \n const int v = g.size();\n static int h[MAX_V];\n static int prev[MAX_V][MAX_V];\n \n\n for(int i = 0; i < v; ++i){\n h[i] = 0;\n }\n\n for(int i = 0; i <= v; ++i){\n bool end = true;\n for(int j = 0; j < v; ++j){\n for(int k = 0; k < (int)g[j].size(); ++k){\n edge e = g[j][k];\n int tmp = h[j] + e.cost;\n if( h[e.dst] > tmp ){\n h[e.dst] = tmp;\n end = false;\n }\n }\n }\n if(end)break;\n // do not detect an negative cycle.\n }\n\n for(int i = 0; i < v; ++i){\n for(int j = 0; j < v; ++j){\n dist[i][j] = inf;\n prev[i][j] = -1;\n }\n dist[i][i] = 0;\n }\n\n for(int i = 0; i < v; ++i){\n for(int j = 0; j < (int)g[i].size(); ++j){\n g[i][j].cost += h[i] - h[g[i][j].dst];\n }\n }\n\n for(int s = 0; s < v; ++s){\n priority_queue<state, vector<state>, greater<state> > q;\n q.push(state(s,s,0));\n while(!q.empty()){\n state cur = q.top(); q.pop();\n if(prev[s][cur.pos]!=-1)continue;\n prev[s][cur.pos] = cur.prev;\n for(int i = 0; i < (int)g[cur.pos].size(); ++i){\n edge e = g[cur.pos][i];\n int cost = cur.cost + e.cost;\n assert(cost>=0);\n if(dist[s][e.dst] > cost){\n dist[s][e.dst] = cost;\n q.push(state(e.dst,cur.pos,cost));\n }\n }\n }\n for(int i = 0; i < v; ++i){\n dist[s][i] += h[i] - h[s];\n }\n }\n\n return ; \n}\n\nint main()\n{\n int n;\n while(cin>>n && n){\n int id = 1;\n int vid = 0;\n map<string,int> cityDict;\n map<int,string> revCityDict;\n set<int> cityEvTimes[max_place];\n graph g(MAX_V);\n \n map<pair<int,int>, int> vID;\n map<int,pair<int,int> > revID;\n \n for(int i = 0; i < n; ++i){\n string from, ftime, to, ttime;\n int cost;\n\n cin >> from >> ftime >> to >> ttime >> cost;\n if(!cityDict.count(from)){\n cityDict[from] = id;\n revCityDict[id] = from;\n ++id;\n }\n if(!cityDict.count(to)){\n cityDict[to] = id;\n revCityDict[id] = to;\n ++id;\n }\n\n int src = cityDict[from];\n int dst = cityDict[to];\n int srcTime = convTime(ftime) - 480;\n int dstTime = convTime(ttime) - 480;\n \n if( dstTime >= 0 && dstTime < max_time && srcTime >= 0 && srcTime < max_time ){\n if( !vID.count(make_pair(src,srcTime)) ){\n vID[make_pair(src,srcTime)] = vid;\n revID[vid] = make_pair(src,srcTime);\n ++vid;\n }\n cityEvTimes[src].insert(srcTime);\n if( !vID.count(make_pair(dst,dstTime)) ){\n vID[make_pair(dst,dstTime)] = vid;\n revID[vid] = make_pair(dst,dstTime);\n ++vid;\n }\n cityEvTimes[dst].insert(dstTime);\n \n g[vID[make_pair(src,srcTime)]].push_back( edge(vID[make_pair(src,srcTime)], vID[make_pair(dst,dstTime)], cost) );\n }\n\n }\n g.resize(vID.size());\n \n for(int i = 1; i < id; ++i){\n foreach(it2, cityEvTimes[i]){\n set<int>::iterator it3 = it2;\n ++it3;\n if( it3 != cityEvTimes[i].end() ){\n g[vID[make_pair(i,*it2)]].push_back( edge(vID[make_pair(i,*it2)], vID[make_pair(i,*it3)], 0) );\n }\n }\n }\n \n johnson(g);\n\n int res = inf;\n int kenInitial = cityDict[\"Tokyo\"];\n int keikoInitial = cityDict[\"Hakodate\"];\n\n int ken_st, keiko_st;\n if( cityEvTimes[kenInitial].size() > 0 && cityEvTimes[keikoInitial].size() > 0 ){\n ken_st = vID[make_pair(kenInitial, *(cityEvTimes[kenInitial].begin()))];\n keiko_st = vID[make_pair(keikoInitial, *(cityEvTimes[keikoInitial].begin()))];\n\n for(int i = 1; i < id; ++i){\n foreach(ev1, cityEvTimes[i]){\n int v1 = vID[make_pair(i,*ev1)];\n foreach(ev2, cityEvTimes[i]){\n int v2 = vID[make_pair(i,*ev2)];\n int st = max(*ev1, *ev2) + 30;\n int from = -1;\n\n if(cityEvTimes[i].lower_bound(st)!=cityEvTimes[i].end()){\n from = vID[make_pair(i,*(cityEvTimes[i].lower_bound(st)))];\n }\n if(from<0)continue;\n foreach(ev3, cityEvTimes[kenInitial]){\n if( *ev3 < st ) continue;\n int v3 = vID[make_pair(kenInitial,*ev3)];\n foreach(ev4, cityEvTimes[keikoInitial]){\n if( *ev4 < st ) continue;\n int v4 = vID[make_pair(keikoInitial, *ev4)];\n res = min(res, dist[ken_st][v1] + dist[keiko_st][v2] + dist[from][v3] + dist[from][v4]);\n }\n }\n }\n }\n }\n \n }\n \n\n if(res>=inf)res = 0;\n cout << res << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1650, "memory_kb": 32480, "score_of_the_acc": -1.243, "final_rank": 12 }, { "submission_id": "aoj_1229_505236", "code_snippet": "#include<iostream>\n#include<queue>\n#include<string>\n#include<map>\n#include<cstdlib>\n#include<algorithm>\n#include<functional>\n#include<set>\n#include<cstdio>\n#include<cassert>\n\nusing namespace std;\n\n#define foreach(i,o) for(__typeof((o).begin()) i = (o).begin(); i != (o).end(); ++i)\n\nconst int max_place = 101;\nconst int max_time = 601;\nconst int MAX_V = 2010;\nconst int inf = 1<<28;\n\nstruct edge{\n int src, dst;\n int cost;\n edge(int src, int dst, int cost):src(src), dst(dst), cost(cost){}\n};\n\nstruct state{\n int pos;\n int prev;\n int cost;\n \n state(int pos, int prev, int cost):pos(pos),prev(prev),cost(cost){}\n\n bool operator>(const state &t)const{\n if(cost!=t.cost)return cost>t.cost;\n if(prev!=t.prev)return prev>t.prev;\n if(pos!=t.pos)return pos>t.pos;\n return false;\n }\n \n /*\n bool operator<(const state &t)const{\n if(pos!=t.pos)return pos<t.pos;\n return false;\n }\n */\n};\n\ntypedef vector<edge> edges;\ntypedef vector<edges> graph;\n\nint convTime(const string &s){\n int h = atoi(s.substr(0,2).c_str());\n int m = atoi(s.substr(3,2).c_str());\n return 60 * h + m;\n}\n\nstring revTime(int t){\n char buf[32];\n sprintf(buf, \"%02d:%02d\", t/60, t%60);\n return string(buf);\n}\n\nstatic int dist[MAX_V][MAX_V];\nvoid johnson(const graph &tmp_g){\n graph g = tmp_g;\n \n const int v = g.size();\n static int h[MAX_V];\n static int prev[MAX_V][MAX_V];\n \n\n for(int i = 0; i < v; ++i){\n h[i] = 0;\n }\n\n for(int i = 0; i <= v; ++i){\n bool end = true;\n for(int j = 0; j < v; ++j){\n for(int k = 0; k < (int)g[j].size(); ++k){\n edge e = g[j][k];\n int tmp = h[j] + e.cost;\n if( h[e.dst] > tmp ){\n h[e.dst] = tmp;\n end = false;\n }\n }\n }\n if(end)break;\n // do not detect an negative cycle.\n }\n\n for(int i = 0; i < v; ++i){\n for(int j = 0; j < v; ++j){\n dist[i][j] = inf;\n prev[i][j] = -1;\n }\n dist[i][i] = 0;\n }\n\n for(int i = 0; i < v; ++i){\n for(int j = 0; j < (int)g[i].size(); ++j){\n g[i][j].cost += h[i] - h[g[i][j].dst];\n }\n }\n\n for(int s = 0; s < v; ++s){\n priority_queue<state, vector<state>, greater<state> > q;\n q.push(state(s,s,0));\n while(!q.empty()){\n state cur = q.top(); q.pop();\n if(prev[s][cur.pos]!=-1)continue;\n prev[s][cur.pos] = cur.prev;\n for(int i = 0; i < (int)g[cur.pos].size(); ++i){\n edge e = g[cur.pos][i];\n int cost = cur.cost + e.cost;\n assert(cost>=0);\n if(dist[s][e.dst] > cost){\n dist[s][e.dst] = cost;\n q.push(state(e.dst,cur.pos,cost));\n }\n }\n }\n for(int i = 0; i < v; ++i){\n dist[s][i] += h[i] - h[s];\n }\n }\n\n return ; \n}\n\nint main()\n{\n int n;\n while(cin>>n && n){\n int id = 1;\n int vid = 0;\n map<string,int> cityDict;\n map<int,string> revCityDict;\n set<int> cityEvTimes[max_place];\n graph g(MAX_V);\n \n map<pair<int,int>, int> vID;\n map<int,pair<int,int> > revID;\n \n for(int i = 0; i < n; ++i){\n string from, ftime, to, ttime;\n int cost;\n\n cin >> from >> ftime >> to >> ttime >> cost;\n if(!cityDict.count(from)){\n cityDict[from] = id;\n revCityDict[id] = from;\n ++id;\n }\n if(!cityDict.count(to)){\n cityDict[to] = id;\n revCityDict[id] = to;\n ++id;\n }\n\n int src = cityDict[from];\n int dst = cityDict[to];\n int srcTime = convTime(ftime) - 480;\n int dstTime = convTime(ttime) - 480;\n \n if( dstTime >= 0 && dstTime < max_time && srcTime >= 0 && srcTime < max_time ){\n if( !vID.count(make_pair(src,srcTime)) ){\n vID[make_pair(src,srcTime)] = vid;\n revID[vid] = make_pair(src,srcTime);\n ++vid;\n }\n cityEvTimes[src].insert(srcTime);\n if( !vID.count(make_pair(dst,dstTime)) ){\n vID[make_pair(dst,dstTime)] = vid;\n revID[vid] = make_pair(dst,dstTime);\n ++vid;\n }\n cityEvTimes[dst].insert(dstTime);\n \n g[vID[make_pair(src,srcTime)]].push_back( edge(vID[make_pair(src,srcTime)], vID[make_pair(dst,dstTime)], cost) );\n }\n\n }\n g.resize(vID.size());\n \n for(int i = 1; i < id; ++i){\n // sort( it->second.begin(), it->second.end() );\n foreach(it2, cityEvTimes[i]){\n // g[it->first].push_back( edge(it->first, it->second[i], it->first, it->second[i], 0) );\n set<int>::iterator it3 = it2;\n ++it3;\n if( it3 != cityEvTimes[i].end() ){\n g[vID[make_pair(i,*it2)]].push_back( edge(vID[make_pair(i,*it2)], vID[make_pair(i,*it3)], 0) );\n }\n }\n }\n \n\n /*\n for(int i = 0; i < (int)g.size(); ++i){\n cout << i << ' ' << revCityDict[i] << ':' << endl;\n for(int j = 0; j < (int)g[i].size(); ++j){\n edge e = g[i][j];\n cout << revCityDict[e.src] << ' ' << revTime(e.srcTime) << ' ' << revCityDict[e.dst] << ' ' << revTime(e.dstTime) << endl;\n }\n }\n cout << \"---\"<<endl;\n */\n\n /*\n foreach(i,revID){\n cout << revCityDict[i->second.first] << ' ' << revTime(i->second.second+480) << endl;\n }\n */\n\n johnson(g);\n\n /*\n for(int i = 0; i < (int)g.size(); ++i){\n for(int j = 0; j < (int)g.size(); ++j){\n cout << i << ' ' << j << \" : \" << dist[i][j] <<endl;\n }\n }\n */\n\n int res = inf;\n int kenInitial = cityDict[\"Tokyo\"];\n int keikoInitial = cityDict[\"Hakodate\"];\n\n //cout << kenInitial << ' ' << keikoInitial << endl;\n\n int ken_st, keiko_st;\n if( cityEvTimes[kenInitial].size() > 0 && cityEvTimes[keikoInitial].size() > 0 ){\n ken_st = vID[make_pair(kenInitial, *(cityEvTimes[kenInitial].begin()))];\n keiko_st = vID[make_pair(keikoInitial, *(cityEvTimes[keikoInitial].begin()))];\n\n //cout <<ken_st << ' ' <<keiko_st << endl;\n \n for(int i = 1; i < id; ++i){\n foreach(ev1, cityEvTimes[i]){\n int v1 = vID[make_pair(i,*ev1)];\n foreach(ev2, cityEvTimes[i]){\n int v2 = vID[make_pair(i,*ev2)];\n int st = max(*ev1, *ev2) + 30;\n int from = -1;\n\n if(cityEvTimes[i].lower_bound(st)!=cityEvTimes[i].end()){\n from = vID[make_pair(i,*(cityEvTimes[i].lower_bound(st)))];\n }\n if(from<0)continue;\n\n //cout << v1 << ' ' << v2 << ' ' << from << endl;\n\n foreach(ev3, cityEvTimes[kenInitial]){\n if( *ev3 < st ) continue;\n int v3 = vID[make_pair(kenInitial,*ev3)];\n foreach(ev4, cityEvTimes[keikoInitial]){\n if( *ev4 < st ) continue;\n int v4 = vID[make_pair(keikoInitial, *ev4)];\n // cout << i << ' ' << revTime(*ev1+480) << ' ' << revTime(*ev2+480) << ' ' << revTime(*ev3+480) << ' ' << revTime(*ev4+480) << ' ' << revTime(st+480) << \" : \" << sssp[0][i][*ev1] << ' '<<sssp[1][i][*ev2]<<' '<<sssp[2][kenInitial][*ev3]<< ' ' <<sssp[2][keikoInitial][*ev4] << endl;\n res = min(res, dist[ken_st][v1] + dist[keiko_st][v2] + dist[from][v3] + dist[from][v4]);\n }\n }\n }\n }\n }\n \n }\n \n\n if(res>=inf)res = 0;\n cout << res << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1680, "memory_kb": 32476, "score_of_the_acc": -1.2473, "final_rank": 14 }, { "submission_id": "aoj_1229_410216", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <cstring>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <queue>\n#include <map>\nusing namespace std;\n\nconst int INF = (1<<28);\nconst int STR = (8*60);\nconst int LIM = (18*60);\n\nclass Train\n{\npublic:\n\tint src,dst,dep,arv,cst;\n\tTrain(int src, int dst, int dep, int arv, int cst)\n\t\t:src(src),dst(dst),dep(dep),arv(arv),cst(cst)\n\t{}\n};\n\nclass State\n{\npublic:\n\tint p,tm,cst,pvT, pvC;\n\tState(int p, int tm, int cst, int pvT, int pvC)\n\t\t:p(p),tm(tm),cst(cst),pvT(pvT),pvC(pvC)\n\t{}\n\n\tbool operator<(const State& s) const\n\t{\n\t\tif(cst != s.cst) return cst > s.cst;\n\t\treturn tm > s.tm;\n\t}\n};\n\ntypedef vector<Train> City;\ntypedef vector<vector<int> > Matrix;\n\nint toMin(string s)\n{\n\tstringstream ss(s);\n\tint h,m;\n\tchar t;\n\tss >> h >> t >> m;\n\n\treturn h*60+m;\n}\n\nbool used[100][2005];\n\nint dijkstra_go(int S, int T, int u, vector<City>& cities)\n{\n\tpriority_queue<State> q;\n\n\tfor(int i=0; i<cities[S].size(); i++)\n\t\tq.push(State(cities[S][i].dst, cities[S][i].arv, cities[S][i].cst, i, S));\n\n\tmemset(used, 0, sizeof(used));\n\n\twhile(!q.empty()) {\n\t\tState s=q.top(); q.pop();\n\t\tif(used[s.pvC][s.pvT]) continue;\n\t\tused[s.pvC][s.pvT] = true;\n\n\t\tif(s.pvC == T && s.pvT == u) return s.cst-cities[s.pvC][s.pvT].cst;\n\n\t\tfor(int i=0; i<cities[s.p].size(); i++) {\n\t\t\tTrain t = cities[s.p][i];\n\t\t\tif(used[s.p][i]) continue;\n\t\t\tif(s.tm > t.dep) continue;\n\t\t\tif(i == u && s.p == T && s.tm + 30 > t.dep) continue;\n\n\t\t\tq.push(State(t.dst, t.arv, s.cst+t.cst, i, s.p));\n\t\t}\n\t}\n\n\treturn INF;\n}\n\nint dijkstra_back(int S, int T, int u, vector<City>& cities)\n{\n\tif(S == T) return 0;\n\n\tpriority_queue<State> q;\n\tq.push(State(cities[S][u].dst, cities[S][u].arv, cities[S][u].cst, u, S));\n\n\tmemset(used, 0, sizeof(used));\n\n\twhile(!q.empty()) {\n\t\tState s = q.top(); q.pop();\n\t\tif(used[s.pvC][s.pvT]) continue;\n\t\tused[s.pvC][s.pvT] = true;\n\n\t\tif(s.p == T) return s.cst;\n\n\t\tfor(int i=0; i<cities[s.p].size(); i++) {\n\t\t\tTrain t = cities[s.p][i];\n\t\t\tif(used[s.p][i]) continue;\n\t\t\tif(s.tm > t.dep) continue;\n\n\t\t\tq.push(State(t.dst, t.arv, s.cst+t.cst, i, s.p));\n\t\t}\n\t}\n\n\treturn INF;\n}\n\nint solve(int Hakodate, int Tokyo, vector<City>& cities)\n{\n\tMatrix goKen(cities.size());\n\tfor(int i=0; i<cities.size(); i++) {\n\t\tgoKen[i].resize(cities[i].size());\n\t\tfor(int j=0; j<cities[i].size(); j++) {\n\t\t\tgoKen[i][j] = INF;\n\t\t}\n\t}\n\n\tMatrix backKen(goKen), goKeiko(goKen), backKeiko(goKen);\n\n\tfor(int i=0; i<cities.size(); i++)\n\tfor(int j=0; j<cities[i].size(); j++) {\n\t\tgoKen[i][j] = dijkstra_go(Hakodate, i, j, cities);\n\t\tgoKeiko[i][j] = dijkstra_go(Tokyo, i, j, cities);\n\t\tbackKen[i][j] = dijkstra_back(i, Hakodate, j, cities);\n\t\tbackKeiko[i][j] = dijkstra_back(i, Tokyo, j, cities);\n\t}\n\n\tint res = INF;\n\tfor(int i=0; i<cities.size(); i++)\n\tfor(int j=0; j<cities[i].size(); j++)\n\tfor(int k=0; k<cities[i].size(); k++)\n\t{\n\t\tint g = (cities[i][j].dep < cities[i][k].dep ? j : k);\n\t\tres = min(res, goKeiko[i][g]+goKen[i][g]+backKeiko[i][j]+backKen[i][k]);\n\t}\n\n\tif(res == INF) res = 0;\n\n\treturn res;\n}\n\nint main()\n{\n\tint N;\n\twhile(cin >> N, N) {\n\t\t\n\t\tint cnt=0;\n\t\tmap<string, int> dic;\n\t\tvector<City> cities(N);\n\t\tfor(int i=0; i<N; i++) {\n\t\t\tstring src,dst,t,s;\n\t\t\tint c;\n\t\t\tcin >> src >> t >> dst >> s >> c;\n\t\t\t\n\t\t\tif(!dic.count(src)) dic[src] = cnt++;\n\t\t\tif(!dic.count(dst)) dic[dst] = cnt++;\n\n\t\t\tint l = toMin(t), r = toMin(s);\n\t\t\tif(l < STR || r < STR|| l > LIM || r > LIM) continue;\n\n\t\t\tcities[dic[src]].push_back(Train(dic[src], dic[dst], l, r, c));\n\t\t}\n\n\t\tint hako = dic[\"Hakodate\"];\n\t\tint tokyo = dic[\"Tokyo\"];\n\n\t\tcities[hako].push_back(Train(hako, hako, LIM, LIM, 0));\n\t\tcities[tokyo].push_back(Train(tokyo, tokyo, LIM, LIM, 0));\n\n\t\tcout << solve(hako, tokyo, cities) << endl;\n\t}\n\n}", "accuracy": 1, "time_ms": 1880, "memory_kb": 1396, "score_of_the_acc": -0.32, "final_rank": 7 }, { "submission_id": "aoj_1229_363161", "code_snippet": "#define INF 10000000\n#define BIAS 24*60\n#include <stdlib.h>\n#include <math.h>\n#include <stdio.h>\n#include <string.h>\n\nchar gCity[2001][64];\nint gCityNum = 0;\nint from_hakodate[2001][101];\nint to_hakodate[2001][101];\nint from_tokyo[2001][101];\nint to_tokyo[2001][101];\n\nstruct Train{\n int from, to;\n int dpt, arv;\n int fare;\n};\n\nint max(int lhs,int rhs){\n if(lhs > rhs) return lhs;\n else return rhs;\n}\n\nint min(int lhs,int rhs){\n if(lhs > rhs) return rhs;\n else return lhs;\n}\n\nint getCityNum(char* cityName){\n int i;\n for(i=0;i<gCityNum;i++){\n if(strcmp(gCity[i],cityName)==0) return i;\n }\n \n strcpy(gCity[gCityNum],cityName);\n return gCityNum++;\n}\n\nvoid setTrain(int idx,struct Train* trains,\n\t int dptH,int dptM,int arvH,int arvM,int fare,\n\t char dptCity[64],char arvCity[64]){\n trains[idx].from = getCityNum(dptCity);\n trains[idx].to = getCityNum(arvCity);\n trains[idx].dpt = dptH*60 + dptM;\n trains[idx].arv = arvH*60 + arvM;\n trains[idx].fare = fare;\n}\n\nvoid setRTrain(int idx,struct Train* trains,\n\t int dptH,int dptM,int arvH,int arvM,int fare,\n\t char dptCity[64],char arvCity[64]){\n trains[idx].from = getCityNum(arvCity);\n trains[idx].to = getCityNum(dptCity);\n trains[idx].dpt = BIAS - (arvH*60 + arvM);\n trains[idx].arv = BIAS - (dptH*60 + dptM);\n trains[idx].fare = fare;\n}\n\nint seekMaxFareTrain(struct Train* trains,int ub){\n int i;\n int maxFare = -1;\n int res;\n for(i=0;i<ub;i++){\n if(maxFare < trains[i].fare){\n maxFare = trains[i].fare;\n res = i;\n }\n }\n return res;\n}\n\nint seekMostDelayTrain(struct Train* trains,int ub){\n int i;\n int mostDelay = -1;\n int res;\n for(i=0;i<ub;i++){\n if(mostDelay < abs(trains[i].dpt - trains[i].arv)){\n mostDelay = abs(trains[i].dpt - trains[i].arv);\n res = i;\n }\n }\n return res;\n}\n\nint change(int city,int id,struct Train* trains){\n int i;\n for(i=id-1;i>=0;i--){\n if(trains[i].arv <= trains[id].dpt\n && trains[i].to == city){\n return i;\n }\n } \n\n return 0;\n}\n\nint fr(char* name,int trainNum,int table[2001][101], struct Train* trains){\n int src = getCityNum(name);\n\n //printf(\"%s %d\\n\",name,src);\n\n table[0][src] = 0;\n int i;\n for(i=0;i<trainNum;i++){\n int j;\n for(j=0;j<gCityNum;j++){\n if(j==trains[i].to){\n\ttable[i+1][j] = min(table[i][j],table[change(trains[i].from,i,trains)+1][trains[i].from]+trains[i].fare);\n }\n else table[i+1][j] = table[i][j];\n }\n }\n}\n\nvoid printTable(int table[2001][101],int n){\n int i;\n for(i=0;i<=n;i++){\n int j;\n for(j=0;j<gCityNum;j++){\n printf(\"%d \",table[i][j]);\n }\n printf(\"\\n\");\n }\n}\n\nint mycmp(const void* t1,const void* t2){\n return ((const struct Train*)t1)->arv - ((const struct Train*)t2)->arv;\n}\n\nvoid printTrains(struct Train* trains,int n){\n int i;\n for(i=0;i<n;i++){\n printf(\"%d %d %d %d %d\\n\",\n\t trains[i].from,trains[i].dpt,trains[i].to,\n\t trains[i].arv,trains[i].fare);\n }\n}\n\nint calc_cost(int city,struct Train* trains,struct Train* rtrains,int trainNum){\n int i;\n int res = INF;\n for(i=0;i<trainNum;i++){\n int j;\n for(j=trainNum-1;j>=0;j--){\n int stay = (BIAS - rtrains[j].arv) - trains[i].arv;\n if(stay < 30) continue;\n\n int c = from_hakodate[i+1][city]\n\t+ from_tokyo[i+1][city]\n\t+ to_hakodate[j+1][city]\n\t+ to_tokyo[j+1][city];\n res = min(res,c);\n }\n }\n return res;\n}\n\nint main(){\n int n;\n while(~scanf(\"%d\",&n)){\n if(n==0) break;\n struct Train* trains = (struct Train*)malloc(n*sizeof(struct Train));\n struct Train* rtrains = (struct Train*)malloc(n*sizeof(struct Train));\n int i=0;\n int j=0;\n for(i=0,j=0;i<n;i++){\n int dptH,dptM,arvH,arvM,fare;\n char dptCity[64],arvCity[64];\n scanf(\"%s %d:%d %s %d:%d %d\",dptCity,&dptH,&dptM,arvCity,&arvH,&arvM,&fare);\n if((dptH*60 + dptM < 8*60) || (arvH*60 + arvM > 18*60)) continue;\n setTrain(j,trains,dptH,dptM,arvH,arvM,fare,dptCity,arvCity);\n setRTrain(j++,rtrains,dptH,dptM,arvH,arvM,fare,dptCity,arvCity);\n }\n\n // printTrains(trains,j);\n // printf(\"\\n\");\n qsort(trains,j,sizeof(struct Train),mycmp);\n qsort(rtrains,j,sizeof(struct Train),mycmp);\n\n // printTrains(trains,j);\n // printf(\"\\n\");\n\n memset(from_hakodate,0x3,sizeof(from_hakodate)); \n fr(\"Hakodate\",j,from_hakodate,trains);\n\n memset(from_tokyo,0x3,sizeof(from_tokyo)); \n fr(\"Tokyo\",j,from_tokyo,trains);\n\n memset(to_hakodate,0x3,sizeof(to_hakodate)); \n fr(\"Hakodate\",j,to_hakodate,rtrains);\n\n memset(to_tokyo,0x3,sizeof(to_tokyo)); \n fr(\"Tokyo\",j,to_tokyo,rtrains);\n\n\n int mincost = INF;\n \n for(i=0;i<gCityNum;i++){\n mincost = min(calc_cost(i,trains,rtrains,j),mincost);\n }\n //printTable(to_hakodate,j);\n //printTable(to_tokyo,j);\n \n //printf(\"\\n\");\n //printf(\"cityname:%s cityid:%d\\n\",arvCity,getCityNum(arvCity));\n\n printf(\"%d\\n\",mincost == INF ? 0:mincost);\n\n memset(gCity,'\\0',sizeof(gCity));\n gCityNum = 0;\n free(trains);\n free(rtrains);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 0, "score_of_the_acc": -0.0089, "final_rank": 2 }, { "submission_id": "aoj_1229_293760", "code_snippet": "#include <iostream>\n#include <fstream>\n#include <sstream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <map>\n#include <set>\n#include <complex>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <cctype>\n#include <climits>\nusing namespace std;\n\ntypedef long long ll;\n\n#define REP(i,n,m) for(int i=n;i<m;i++)\n#define rep(i,n) REP(i,0,n)\n\nclass E{\npublic:\n int to;\n int ft,tt;\n int cost;\n\n E(){}\n E(int _to,int _ft,int _tt,int _cost){\n to = _to;\n ft = _ft;\n tt = _tt;\n cost = _cost;\n }\n};\n\nclass State{\npublic:\n int id,tm,cost;\n\n State(){}\n State(int _id,int _tm,int _cost){\n id = _id;\n tm = _tm;\n cost = _cost;\n }\n\n bool operator<(const State &st)const{\n return cost > st.cost;\n }\n};\n\nint n,m;\nint A,B;\nint LEAVE,BACK;\nint ac[102][2000],bc[102][2000];\nint r_ac[102][2000],r_bc[102][2000];\nmap<string,int> name;\nvector<E> t[102],rt[102];\n\nint TimeToInt(string s){\n int h = (s[0] - '0') * 10 + (s[1] - '0');\n int m = (s[3] - '0') * 10 + (s[4] - '0');\n return h * 60 + m;\n}\n\nint NameToInt(string s){\n int tmp = name[s];\n if(tmp == 0){\n name[s] = name.size();\n }\n return name[s];\n}\n\nvoid calCost(int start,int closed[102][2000]){\n priority_queue<State> open;\n rep(i,102) rep(j,2000) closed[i][j] = -1;\n open.push(State(start,LEAVE,0));\n\n while(!open.empty()){\n State st = open.top(); open.pop();\n if(closed[st.id][st.tm] != -1) continue;\n closed[st.id][st.tm] = st.cost;\n\n rep(i,t[st.id].size()){\n E e = t[st.id][i];\n if(st.tm <= e.ft){\n open.push(State(e.to,e.tt,st.cost+e.cost));\n }\n }\n }\n}\n\nvoid calRevCost(int start,int closed[102][2000]){\n priority_queue<State> open;\n rep(i,102) rep(j,2000) closed[i][j] = -1;\n open.push(State(start,BACK,0));\n\n while(!open.empty()){\n State st = open.top(); open.pop();\n if(closed[st.id][st.tm] != -1) continue;\n closed[st.id][st.tm] = st.cost;\n\n rep(i,rt[st.id].size()){\n E e = rt[st.id][i];\n if(st.tm >= e.ft){\n open.push(State(e.to,e.tt,st.cost+e.cost));\n }\n }\n }\n\n REP(i,1,n){\n int minCost = INT_MAX;\n for(int j=1999;j>=0;j--){\n if(closed[i][j] != -1){\n minCost = min(minCost,closed[i][j]);\n }\n closed[i][j] = (minCost == INT_MAX ? -1 : minCost);\n }\n }\n}\n\nint main(){\n LEAVE = TimeToInt(\"08:00\");\n BACK = TimeToInt(\"18:00\");\n\n while(cin>>m,m){\n name.clear();\n rep(i,102){\n t[i].clear();\n rt[i].clear();\n }\n\n rep(i,m){\n string from,to,ft,tt;\n int cost;\n cin>>from>>ft>>to>>tt>>cost;\n\n int fromID = NameToInt(from);\n int toID = NameToInt(to);\n int ft_int = TimeToInt(ft);\n int tt_int = TimeToInt(tt);\n\n t[fromID].push_back(E(toID,ft_int,tt_int,cost));\n rt[toID].push_back(E(fromID,tt_int,ft_int,cost));\n }\n\n n = name.size() + 1;\n A = NameToInt(\"Hakodate\");\n B = NameToInt(\"Tokyo\");\n\n calCost(A,ac);\n calCost(B,bc);\n\n calRevCost(A,r_ac);\n calRevCost(B,r_bc);\n\n int ans = INT_MAX;\n REP(i,1,n){\n REP(atime,LEAVE,BACK+1){\n if(ac[i][atime] == -1) continue;\n REP(btime,LEAVE,BACK+1){\n if(bc[i][btime] == -1) continue;\n int maxTime = max(atime,btime);\n if(r_ac[i][maxTime+30] == -1 || r_bc[i][maxTime+30] == -1) break;\n ans = min(ans,ac[i][atime] + bc[i][btime] + r_ac[i][maxTime+30] + r_bc[i][maxTime+30]);\n }\n }\n }\n cout<<(ans == INT_MAX ? 0 : ans)<<endl;\n\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 0, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1229_289502", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <cstring>\n#include <map>\n#include <queue>\n\nusing namespace std;\n\nint strToTime(string &s){\n return atoi(s.substr(0,2).c_str())*60 + atoi(s.substr(3,2).c_str());\n}\n\nstruct edge{\n int cost;\n int start;\n int goal;\n int to;\n bool operator<(const edge &e)const{\n return start>e.start;\n }\n};\n\nvector<edge> G[101];\n\nstruct Sit{\n int cTime;\n int cost;\n int node;\n\n bool operator<(const Sit &s)const{\n return cTime>s.cTime;\n }\n};\n\nconst int INF=1000000000;\n\nint backMinCost(int idx,int sTime,int snode);\n\nqueue<Sit> *pprv;\nqueue<Sit> *nnxt;\n\nint main(){\n pprv=new queue<Sit>();\n nnxt=new queue<Sit>();\n queue<Sit> *prv=new queue<Sit>();\n queue<Sit> *nxt=new queue<Sit>();\n\n int n;\n while(cin>>n&&n!=0){\n for(int i = 0; i < 101; i++)G[i].clear();\n map<string,vector<pair<int,int> > > startAndFinTimes;\n map<string,int> stationIdx;\n stationIdx[\"Tokyo\"]=0;\n stationIdx[\"Hakodate\"]=1;\n int idx=2;\n for(int i = 0; i < n; i++){\n string st,ft;\n string s1,s2;\n edge e;\n cin>>s1>>st>>s2>>ft>>e.cost;\n e.start=strToTime(st);\n e.goal=strToTime(ft);\n if(stationIdx.find(s1)==stationIdx.end())\n stationIdx[s1]=idx++;\n if(stationIdx.find(s2)==stationIdx.end())\n stationIdx[s2]=idx++;\n e.to=stationIdx[s2];\n G[stationIdx[s1]].push_back(e);\n }\n for(int i = 0; i < 101; i++)sort(G[i].begin(),G[i].end());\n\n map<int,int> minCosts[2][101];\n for(int i = 0; i < 2; i++){\n Sit ss;\n ss.cost=0;\n ss.cTime=480;\n ss.node=i;\n prv->push(ss);\n minCosts[i][ss.node][ss.cTime]=0;\n while(prv->size()){\n while(prv->size()){\n Sit s=prv->front();prv->pop();\n for(int ii = 0; ii < G[s.node].size(); ii++){\n edge &e=G[s.node][ii];\n // ŽžŠÔ‚͂ǂñ‚Ç‚ñ¬‚³‚­‚È‚Á‚Ä‚¢‚­‚Ì‚Å\n if(e.start<s.cTime)\n break;\n if(e.start>60*18||e.goal>60*18)\n continue;\n Sit ns=s;\n ns.cost+=e.cost;\n ns.cTime=e.goal;\n ns.node=e.to;\n if(minCosts[i][ns.node].find(ns.cTime)!=minCosts[i][ns.node].end()){\n if(minCosts[i][ns.node][ns.cTime]>ns.cost){\n minCosts[i][ns.node][ns.cTime]=ns.cost;\n nxt->push(ns);\n }\n }\n else{\n minCosts[i][ns.node][ns.cTime]=ns.cost;\n nxt->push(ns);\n }\n }\n }\n swap(prv,nxt);\n }\n }\n int minCost=INF;\n for(int i = 0; i < idx; i++){\n for(map<int,int>::iterator it=minCosts[0][i].begin();it!=minCosts[0][i].end();it++){\n for(map<int,int>::iterator iit=minCosts[1][i].begin();iit!=minCosts[1][i].end();iit++){\n int sum=it->second+iit->second;\n int nextStartTime=max(it->first,iit->first)+30;\n int res=backMinCost(0,nextStartTime,i);\n int res2=backMinCost(1,nextStartTime,i);\n if(res!=INF&&res2!=INF){\n sum+=res+res2;\n minCost=min(minCost,sum);\n }\n }\n }\n }\n if(minCost==INF)cout<<0<<endl;\n else cout<<minCost<<endl;\n }\n delete prv;\n delete nxt;\n delete nnxt;\n delete pprv;\n return 0;\n}\n\nint backMinCost(int idx,int sTime,int snode){\n map<int,int> d[101];\n Sit ss;\n ss.cost=0;\n ss.node=snode;\n ss.cTime=sTime;\n pprv->push(ss);\n d[snode][ss.cTime]=ss.cost;\n while(pprv->size()){\n while(pprv->size()){\n Sit s=pprv->front();pprv->pop();\n for(int ii = 0; ii < G[s.node].size(); ii++){\n edge &e=G[s.node][ii];\n // ŽžŠÔ‚͂ǂñ‚Ç‚ñ¬‚³‚­‚È‚Á‚Ä‚¢‚­‚Ì‚Å\n if(e.start<s.cTime)\n break;\n if(e.start>60*18||e.goal>60*18)\n continue;\n Sit ns=s;\n ns.cost+=e.cost;\n ns.cTime=e.goal;\n ns.node=e.to;\n if(d[ns.node].find(ns.cTime)!=d[ns.node].end()){\n if(d[ns.node][ns.cTime]>ns.cost){\n d[ns.node][ns.cTime]=ns.cost;\n nnxt->push(ns);\n }\n }\n else{\n d[ns.node][ns.cTime]=ns.cost;\n nnxt->push(ns);\n }\n }\n }\n swap(pprv,nnxt);\n }\n int res=INF;\n for(map<int,int>::iterator it=d[idx].begin();it!=d[idx].end();it++)\n res=min(res,it->second);\n return res;\n}", "accuracy": 1, "time_ms": 6760, "memory_kb": 1064, "score_of_the_acc": -1.0328, "final_rank": 11 }, { "submission_id": "aoj_1229_90969", "code_snippet": "#include<iostream>\n#include<queue>\n#include<vector>\n#include<algorithm>\n#include<map>\nusing namespace std;\n#define REP(i,b,n) for(int i=b;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define ALL(C) (C).begin(),(C).end()\n#define pb push_back\n#define mp make_pair\n\nconst int N = 100;\nconst int inf = (1 << 28);\n\nclass Edge{\npublic:\n int sh,sm,dh,dm;\n int d;\n int cost;\n};\n\nclass state{\npublic:\n int now,h,m;\n int cost;\n bool operator<(const state & a)const{\n return cost > a.cost;\n }\n};\n\nbool isless(int h,int m,int nh,int nm){\n if (h < nh)return true;\n else if (h == nh && m <= nm)return true;\n return false;\n}\n\nbool isgreater(int h,int m,int nh,int nm){\n if (h > nh)return true;\n else if (h == nh && m >= nm)return true;\n return false;\n}\n\nvoid dijkstra(int n,int s,vector<Edge>*edge,int cost[24][60][N],\n\t bool isrev){\n rep(i,24)rep(j,60)rep(k,n)cost[i][j][k]=inf;\n priority_queue<state> Q;\n if (isrev)Q.push((state){s,17,59,0});\n else Q.push((state){s,8,0,0});\n\n while(!Q.empty()){\n state now = Q.top();Q.pop();\n if (cost[now.h][now.m][now.now] != inf)continue;\n cost[now.h][now.m][now.now]=now.cost;\n rep(i,edge[now.now].size()){\n if (isrev){\n\tif (isgreater(now.h,now.m,edge[now.now][i].sh,edge[now.now][i].sm))\n\t Q.push((state){edge[now.now][i].d,edge[now.now][i].dh,\n\t\t\t edge[now.now][i].dm,\n\t\t\t now.cost+edge[now.now][i].cost});\n }else {\n\tif (isless(now.h,now.m,edge[now.now][i].sh,edge[now.now][i].sm))\n\t Q.push((state){edge[now.now][i].d,edge[now.now][i].dh,\n\t\t\t edge[now.now][i].dm,\n\t\t\t now.cost+edge[now.now][i].cost});\n }\n }\n }\n\n\n if (isrev){\n rep(k,100){\n int tmp = inf;\n for(int i=17;i>=6;i--){\n\tfor(int j=59;j>=0;j--){\n\t cost[i][j][k]=min(cost[i][j][k],tmp);\n\t tmp=min(cost[i][j][k],tmp);\n\t}\n }\n }\n }else {\n rep(k,100){\n int tmp = inf;\n rep(i,24){\n\trep(j,60){\n\t cost[i][j][k]=min(cost[i][j][k],tmp);\n\t tmp=min(tmp,cost[i][j][k]);\n\t}\n }\n }\n }\n}\n\n//from tokyo,from hakodate, to tokyo,to hakodate\nint ft[24][60][N],fh[24][60][N],tt[24][60][N],th[24][60][N];\nint solve(int n,int hakodate,int tokyo,vector<Edge>*edge,\n\t vector<Edge>*revedge){\n\n\n dijkstra(n,tokyo,edge,ft,false);\n dijkstra(n,hakodate,edge,fh,false);\n dijkstra(n,tokyo,revedge,tt,true);\n dijkstra(n,hakodate,revedge,th,true);\n\n \n int ret = inf;\n rep(k,n){\n int tmp = inf;\n REP(i,8,18){\n rep(j,30){\n\ttmp=min(tmp,ft[i][j][k]+fh[i][j][k]+tt[i][j+30][k]+th[i][j+30][k]);\n }\n REP(j,30,60){\n\ttmp=min(tmp,ft[i][j][k]+fh[i][j][k]+tt[i+1][(j+30)%60][k]+th[i+1][(j+30)%60][k]);\n }\n }\n ret=min(ret,tmp);\n }\n return ret;\n}\n\n\nint getnum(string &a,map<string,int> & M){\n int index=M.size();\n if (M.find(a) == M.end())M[a]=index;\n return M[a];\n}\n\nmain(){\n int n;\n vector<Edge> edge[N];\n vector<Edge> rev[N];\n const string name[2]={\"Hakodate\",\"Tokyo\"};\n while(cin>>n && n){\n rep(i,N)edge[i].clear(),rev[i].clear();\n map<string,int> M;\n\n string from,to;\n int f,t;\n int sh,sm,dh,dm;\n int cost;\n char dummy;\n rep(i,n){\n cin>>from>>sh>>dummy>>sm;\n cin>>to>>dh>>dummy>>dm;\n cin>>cost;\n f=getnum(from,M);\n t=getnum(to,M);\n edge[f].pb((Edge){sh,sm,dh,dm,t,cost});\n rev[t].pb((Edge){dh,dm,sh,sm,f,cost});\n }\n\n \n int ans = solve(M.size(),M[name[0]],M[name[1]],edge,rev);\n if (ans == inf)cout <<0<<endl;\n else cout << ans << endl;\n\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3392, "score_of_the_acc": -0.1059, "final_rank": 3 } ]
aoj_1228_cpp
Problem E: Beehives Taro and Hanako, students majoring in biology, have been engaged long in observations of beehives. Their interest is in finding any egg patterns laid by queen bees of a specific wild species. A queen bee is said to lay a batch ofeggs in a short time. Taro and Hanako have never seen queen bees laying eggs. Thus, every time they find beehives, they find eggs just laid in hive cells. Taro and Hanako have a convention to record an egg layout.. they assume the queen bee lays eggs, moving from one cell to an adjacent cell along a path containing no cycles. They record the path of cells with eggs. There is no guarantee in biology for them to find an acyclic path in every case. Yet they have never failed to do so in their observations. There are only six possible movements from a cell to an adjacent one, and they agree to write down those six by letters a, b, c, d, e, and f ounterclockwise as shown in Figure 2. Thus the layout in Figure 1 may be written down as "faafd". Taro and Hanako have investigated beehives in a forest independently. Each has his/her own way to approach beehives, protecting oneself from possible bee attacks. They are asked to report on their work jointly at a conference, and share their own observation records to draft a joint report. At this point they find a serious fault in their convention. They have never discussed which direction, in an absolute sense, should be taken as "a", and thus Figure 2 might be taken as, e.g., Figure 3 or Figure 4. The layout shown in Figure 1 may be recorded differently, depending on the direction looking at the beehive and the path assumed: "bcbdb" with combination of Figure 3 and Figure 5, or "bccac" with combination of Figure 4 and Figure 6. A beehive can be observed only from its front side and never from its back, so a layout cannot be confused with its mirror image. Since they may have observed the same layout independently, they have to find duplicated records in their observations (Of course, they do not record the exact place and the exact time of each observation). Your mission is to help Taro and Hanako by writing a program that checks whether two observation records are made from the same layout. Input The input starts with a line containing the number of record pairs that follow. The number is given with at most three digits. Each record pair consists of two lines of layout records and a line containing a hyphen. Each layout record consists of a sequence of letters a, b, c, d, e, and f. Note that a layout record may be an empty sequence if a queen bee laid only one egg by some reason. You can trust Taro and Hanako in that any of the paths in the input does not force you to visit any cell more than once. Any of lines in the input contain no characters other than those described above, and contain at most one hundred characters. Output For each pair of records, produce a line containing either " true " or " false ": " true " if the two records represent the same layout, ...(truncated)
[ { "submission_id": "aoj_1228_2649936", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\n#include <time.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\nstring line;\n\nstruct Info{\n\tInfo(int arg_row,int arg_col){\n\t\trow = arg_row;\n\t\tcol = arg_col;\n\t}\n\tint row,col;\n};\n\nchar buf1[101],buf2[101],buf3[101];\nbool table1[201][201],table2[201][201];\nint len_1,len_2,start_row = 100,start_col = 100,G[128];\nint diff_row[6] = {1,1,0,-1,-1,0},diff_col[6] = {0,-1,-1,0,1,1};\nint loc[6][6] = {{0,1,2,3,4,5},{1,2,3,4,5,0},{2,3,4,5,0,1},{3,4,5,0,1,2},{4,5,0,1,2,3},{5,0,1,2,3,4}};\nvector<Info> V;\n\nvoid func(){\n\n\tgetchar();\n\tgetline(cin,line);\n\tfor(len_1 = 0; len_1 != line.length(); len_1++){\n\t\tbuf1[len_1] = line[len_1];\n\t}\n\tbuf1[len_1] = '\\0';\n\n\tgetline(cin,line);\n\tfor(len_2 = 0; len_2 != line.length(); len_2++){\n\t\tbuf2[len_2] = line[len_2];\n\t}\n\tbuf2[len_2] = '\\0';\n\tscanf(\"%s\",buf3);\n\n\tfor(len_1 = 0; buf1[len_1] != '\\0'; len_1++);\n\tfor(len_2 = 0; buf2[len_2] != '\\0'; len_2++);\n\n\tif(len_1 != len_2){\n\t\tprintf(\"false\\n\");\n\t\treturn;\n\t}else if(len_1 == 0 && len_2 == 0){\n\t\tprintf(\"true\\n\");\n\t\treturn;\n\t}\n\n\tfor(int row = 0; row <= 200; row++){\n\t\tfor(int col = 0; col <= 200; col++){\n\t\t\ttable1[row][col] = false;\n\t\t\ttable2[row][col] = false;\n\t\t}\n\t}\n\n\tV.clear();\n\n\tint tmp_row = start_row,tmp_col = start_col,tmp;\n\ttable1[start_row][start_col] = true;\n\tV.push_back(Info(start_row,start_col));\n\n\tfor(int i = 0; i < len_1; i++){\n\t\ttmp = G[buf1[i]];\n\t\ttmp_row += diff_row[tmp];\n\t\ttmp_col += diff_col[tmp];\n\t\ttable1[tmp_row][tmp_col] = true;\n\t\tV.push_back(Info(tmp_row,tmp_col));\n\t}\n\n\tbool FLG;\n\tvector<Info> X;\n\n\tfor(int loop = 0; loop < V.size(); loop++){\n\n\t\tfor(int k = 0; k < 6; k++){\n\n\t\t\tfor(int i = 0; i < X.size(); i++){\n\t\t\t\ttable2[X[i].row][X[i].col] = false;\n\t\t\t}\n\t\t\tX.clear();\n\n\t\t\ttmp_row = V[loop].row;\n\t\t\ttmp_col = V[loop].col;\n\t\t\ttable2[tmp_row][tmp_col] = true;\n\t\t\tX.push_back(Info(tmp_row,tmp_col));\n\n\t\t\tFLG = true;\n\t\t\tfor(int i = 0; i < len_2; i++){\n\n\t\t\t\ttmp = loc[k][G[buf2[i]]];\n\t\t\t\ttmp_row += diff_row[tmp];\n\t\t\t\ttmp_col += diff_col[tmp];\n\t\t\t\tif(table1[tmp_row][tmp_col] == false){\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\ttable2[tmp_row][tmp_col] = true;\n\t\t\t\tX.push_back(Info(tmp_row,tmp_col));\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\tfor(int i = 0; i < V.size(); i++){\n\t\t\t\tif(table2[V[i].row][V[i].col] == false){\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(FLG){\n\t\t\t\tprintf(\"true\\n\");\n\t\t\t\treturn;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"false\\n\");\n}\n\n\nint main(){\n\n\tint case_num;\n\tscanf(\"%d\",&case_num);\n\n\tG['a'] = 0;\n\tG['b'] = 1;\n\tG['c'] = 2;\n\tG['d'] = 3;\n\tG['e'] = 4;\n\tG['f'] = 5;\n\n\tfor(int i = 0; i < case_num; i++)func();\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3324, "score_of_the_acc": -0.4711, "final_rank": 17 }, { "submission_id": "aoj_1228_2548403", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n \nconst int dx[] = {0, 1, 1, 0, -1, -1};\nconst int dy[] = {-1, 0, 1, 1, 0, -1};\n \nusing Point = pair<int, int>;\n \nint main() {\n int T;\n cin >> T;\n cin.ignore(); \n while(T--) {\n string s, t, sp; \n //cin >> s >> t >> sp;\n getline(cin, s);\n getline(cin, t);\n getline(cin, sp);\n if(s.size() != t.size()) {\n cout << \"false\" << endl;\n continue;\n }\n int x = 0, y = 0;\n set<Point> vis;\n vis.insert(Point(0, 0));\n for(char c : s) {\n int k = c-'a';\n x += dx[k], y += dy[k];\n vis.insert(Point(x, y));\n }\n for(int i = 0; i < 6; i++) {\n for(Point p : vis) {\n set<Point> st;\n int x = p.first, y = p.second;\n st.insert(Point(x, y));\n for(char c : t) {\n int k = c-'a';\n x += dx[(k+i)%6], y += dy[(k+i)%6];\n if(!vis.count(Point(x, y))) {\n break;\n } else {\n st.insert(Point(x, y));\n }\n }\n if(st == vis) {\n cout << \"true\" << endl;\n goto end;\n }\n }\n }\n cout << \"false\" << endl;\n end: ;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3156, "score_of_the_acc": -0.4605, "final_rank": 15 }, { "submission_id": "aoj_1228_2548382", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<n;i++)\nusing namespace std;\nstring s,t;\nint n;\nint dy1[6]={1,1,0,-1,-1,0};\nint dx1[6]={0,-1,-1,0,1,1};\nint dy2[6]={-1,-1,0,1,1,0};\nint dx2[6]={0,1,1,0,-1,-1};\nbool b[1000][1000];\nbool c[1000][1000];\nmain(){\n cin>>n;\n while(n--){\n memset(b,0,sizeof(b));\n cin>>s;\n if(s==\"-\"){\n cout<<\"true\"<<endl;\n continue;\n }\n int y=500,x=500;\n b[y][x]=1;\n vector<int>X,Y;\n X.push_back(x);\n Y.push_back(y);\n rep(i,s.size()){\n x+=dx1[s[i]-'a'];\n y+=dy1[s[i]-'a'];\n b[y][x]=1;\n X.push_back(x);\n Y.push_back(y);\n }\n cin>>t;\n if(t==\"-\"){\n cout<<\"false\"<<endl;\n continue;\n }\n rep(i,2){\n rep(j,6){\n rep(l,X.size()){\n int f=0,y=Y[l],x=X[l];\n rep(k,t.size()){\n if(i){\n x+=dx2[(t[k]-'a'+j)%6];\n y+=dy2[(t[k]-'a'+j)%6];\n }else{\n x+=dx1[(t[k]-'a'+j)%6];\n y+=dy1[(t[k]-'a'+j)%6];\n }\n if(b[y][x])f++;\n }\n if(f==t.size())goto L;\n }\n }\n reverse(t.begin(),t.end());\n }\n cout<<\"false\"<<endl;\n if(0){L:;cout<<\"true\"<<endl;}\n cin>>s;\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4140, "score_of_the_acc": -0.6132, "final_rank": 18 }, { "submission_id": "aoj_1228_2548240", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nconst int dx[] = {0, 1, 1, 0, -1, -1};\nconst int dy[] = {-1, 0, 1, 1, 0, -1};\n\nusing Point = pair<int, int>;\n\nint main() {\n int T;\n cin >> T;\n cin.ignore(); \n while(T--) {\n string s, t, sp; \n //cin >> s >> t >> sp;\n getline(cin, s);\n getline(cin, t);\n getline(cin, sp);\n if(s.size() != t.size()) {\n cout << \"false\" << endl;\n continue;\n }\n int x = 0, y = 0;\n set<Point> vis;\n vis.insert(Point(0, 0));\n for(char c : s) {\n int k = c-'a';\n x += dx[k], y += dy[k];\n vis.insert(Point(x, y));\n }\n for(int i = 0; i < 6; i++) {\n for(Point p : vis) {\n\tset<Point> st;\n\tint x = p.first, y = p.second;\n\tst.insert(Point(x, y));\n\tfor(char c : t) {\n\t int k = c-'a';\n\t x += dx[(k+i)%6], y += dy[(k+i)%6];\n\t if(!vis.count(Point(x, y))) {\n\t break;\n\t } else {\n\t st.insert(Point(x, y));\n\t }\n\t}\n\tif(st == vis) {\n\t cout << \"true\" << endl;\n\t goto end;\n\t}\n }\n }\n cout << \"false\" << endl;\n end: ;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3172, "score_of_the_acc": -0.4694, "final_rank": 16 }, { "submission_id": "aoj_1228_2548097", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint dy[6]={1,1,0,-1,-1,0};\nint dx[6]={0,-1,-1,0,1,1};\n\nint base[1000][1000];\nint cnum[300];\nchar cc[300];\n\nint main(){\n\n cnum['a']=0;\n cnum['b']=1;\n cnum['c']=2;\n cnum['d']=3;\n cnum['e']=4;\n cnum['f']=5;\n \n cc['a']='d';\n cc['b']='e';\n cc['c']='f';\n cc['d']='a';\n cc['e']='b';\n cc['f']='c';\n \n int n;\n\n cin>>n;\n \n while(n--){\n \n string s;\n string t;\n \n cin>>s;\n \n if(s==\"-\"){\n cout<<\"true\"<<endl;\n continue;\n }\n\n vector<int> X, Y;\n \n int y=500, x=500;\n\n memset(base,0,sizeof(base));\n\n base[y][x]=1;\n X.push_back(x);\n Y.push_back(y);\n \n for(int i=0;i<s.size();i++){\n \n y+=dy[cnum[s[i]]];\n x+=dx[cnum[s[i]]];\n\n base[y][x]=1;\n X.push_back(x);\n Y.push_back(y);\n }\n\n cin>>t;\n \n if(t==\"-\"){\n cout<<\"false\"<<endl;\n continue;\n }\n \n bool ans=false;\n \n for(int T=0;T<X.size();T++){\n \n for(int i=0;i<6;i++){\n\n\t\n\tint flag=0;\n\n\ty=Y[T], x=X[T];\n \n\tfor(int j=0;j<t.size();j++){\n \n\t y+=dy[(cnum[t[j]]+i)%6];\n\t x+=dx[(cnum[t[j]]+i)%6];\n\t\n\t if(!base[y][x]) flag=1;\n\t}\n \n\tif(!flag) ans=true;\n \n }\n\n reverse(t.begin(),t.end());\n \n for(int i=0;i<6;i++){\n \n\tint flag=0;\n \n\ty=Y[T], x=X[T];\n\t\n\tfor(int j=0;j<t.size();j++){\n\t\n\t y+=dy[(cnum[cc[t[j]]]+i)%6];\n\t x+=dx[(cnum[cc[t[j]]]+i)%6];\n\t\n\t if(!base[y][x]) flag=1;\n\t}\n\n\tif(!flag) ans=true;\n \n }\n \n reverse(t.begin(),t.end());\n\n }\n \n if(s.size()!=t.size()) ans=false;\n\n if(ans) cout<<\"true\"<<endl;\n else cout<<\"false\"<<endl;\n \n cin>>s;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 7056, "score_of_the_acc": -1.0795, "final_rank": 19 }, { "submission_id": "aoj_1228_1828590", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int,int> P;\nvector<int> ss(string&s ){\n vector<int> v;\n for(int i=0;i<(int)s.size();i++){\n v.push_back( s[i] - 'a' );\n }\n return v;\n}\n\nint dx[2][6]={ {0,-1,-1,0,1,1},\n {0,1,1,0,-1,-1} };\nint dy[2][6]={ {1,1,0,-1,-1,0},\n {1,0,-1,-1,0,1} };\n\nvoid dfs(int x,int y,int c,int k,const vector<int>& v,set<P> &s){\n s.insert(P(x,y));\n if( c == (int)v.size() ) return;\n int d = (v[c]+k)%6;\n dfs( x + dx[0][d], y + dy[0][d], c+1, k, v, s );\n}\n\nbool eq(const set<P>& a, const set<P>& b){\n if(a.size() != b.size() ) return false;\n for( auto x = a.begin(), y = b.begin(); x != a.end() || y != b.end(); x++, y++ )\n if( *x != *y ) return false;\n return true;\n}\n\nvoid view(const set<P> &s ){\n for( auto x : s ){\n cout << x.first << \" \" <<x.second << endl;\n }\n}\n\nint main(){\n\n int T;\n cin >> T;\n getchar();\n while(T--){\n string S1,S2; \n getline(cin,S1);\n getline(cin,S2);\n vector<int> v1 = ss( S1 ), v2 = ss( S2 );\n getline(cin,S1); \n bool f = false;\n for(int i=0;i<6;i++){\n set<P> s1;\n dfs( 0,0,0,i,v1,s1 );\n //cout << \"s1------------- \"<< endl;\n // view(s1);\n for(int j=0;j<6;j++){\n for( auto ps : s1 ){\n set<P> s2;\n dfs(ps.first,ps.second,0,j,v2,s2);\n //cout << \"s2 \"<< endl;\n //view(s2);\n if( eq(s1, s2) ) {\n //cout << \"ok---------\" << endl;\n f = true;\n }\n }\n } \n }\n if( f ) cout << \"true\" << endl;\n else cout << \"false\" << endl;\n }\n}", "accuracy": 1, "time_ms": 1520, "memory_kb": 3140, "score_of_the_acc": -1.445, "final_rank": 20 }, { "submission_id": "aoj_1228_1828466", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef vector<int> vec;\ntypedef vector<vec> mat;\n\nvoid pr(mat a){\n int h=a.size(),w=a[0].size();\n for(int i=0;i<h;i++){\n for(int j=0;j<w;j++){\n cout<<a[i][j];\n }\n cout<<endl;\n }\n cout<<endl;\n}\n\n\nmat cut(mat a){\n \n int h=a.size(),w=a[0].size();\n int ay=1e9,ax=1e9,by=0,bx=0;\n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++)\n if(a[i][j]!=0){\n ay=min(ay,i);\n ax=min(ax,j);\n by=max(by,i);\n bx=max(bx,j);\n }\n \n mat res=mat(by-ay+1,vec(bx-ax+1));\n for(int y=ay;y<=by;y++)\n for(int x=ax;x<=bx;x++)\n res[y-ay][x-ax]=a[y][x];\n return res;\n}\n\n\nint main(){\n int Tc;cin>>Tc;\n cin.ignore();\n while(Tc--){\n\n int F;\n string s;\n getline(cin,s);\n \n F=s.size()+2;\n int py=F,px=F;\n mat A(F+F,vec(F+F,0));\n A[py][px]=1;\n for(int i=0;i<(int)s.size();i++){\n if(s[i]=='a')px++;\n if(s[i]=='b')py--;\n if(s[i]=='c')py--,px--;\n if(s[i]=='d')px--;\n if(s[i]=='e')py++;\n if(s[i]=='f')py++,px++;\n A[py][px]=1;\n }\n A=cut(A);\n\n getline(cin,s);\n bool ans=false;\n for(int T=0;T<6;T++){\n F=s.size()+2;\n mat B(F+F,vec(F+F,0));\n py=F,px=F;\n B[py][px]=1;\n \n for(int i=0;i<(int)s.size();i++){\n if(s[i]=='a')px++,s[i]='b';\n else if(s[i]=='b')py--,s[i]='c';\n else if(s[i]=='c')py--,px--,s[i]='d';\n else if(s[i]=='d')px--,s[i]='e';\n else if(s[i]=='e')py++,s[i]='f';\n else if(s[i]=='f')py++,px++,s[i]='a';\n B[py][px]=1;\n }\n\n B=cut(B);\n if(A==B)ans=true;\n }\n cout<< (ans?\"true\":\"false\") <<endl;\n string tmp;\n getline(cin,tmp);\n assert(tmp==\"-\");\n\n }\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 1532, "score_of_the_acc": -0.2635, "final_rank": 13 }, { "submission_id": "aoj_1228_1130939", "code_snippet": "#include<stdio.h>\n#include<algorithm>\n#include<vector>\nusing namespace std;\nchar str[1100];\nint dx[]={1,1,0,-1,-1,0};\nint dy[]={0,1,1,0,-1,-1};\n\nint main(){\n\tint a;scanf(\"%d\",&a);\n\tgets(str);\n\twhile(a--){\n\t\tgets(str);\n\t\tvector<pair<int,int> >v;\n\t\tint r=0;int c=0;\n\t\tv.push_back(make_pair(0,0));\n\t\tfor(int i=0;str[i];i++){\n\t\t\tr+=dx[str[i]-'a'];\n\t\t\tc+=dy[str[i]-'a'];\n\t\t\tv.push_back(make_pair(r,c));\n\t\t}\n\t\tstd::sort(v.begin(),v.end());\n\t\tgets(str);\n\t\tint ret=0;\n\t\tfor(int i=0;i<6;i++){\n\t\t\tfor(int t=0;t<v.size();t++){\n\t\t\t\tvector<pair<int,int> >w;\n\t\t\t\tint nr=v[t].first;int nc=v[t].second;\n\t\t\t\tw.push_back(make_pair(nr,nc));\n\t\t\t\tfor(int j=0;str[j];j++){\n\t\t\t\t\tnr+=dx[(str[j]-'a'+i)%6];\n\t\t\t\t\tnc+=dy[(str[j]-'a'+i)%6];\n\t\t\t\t\tw.push_back(make_pair(nr,nc));\n\t\t\t\t}\n\t\t\t\tstd::sort(w.begin(),w.end());\n\t\t\t\tbool ok=true;\n\t\t\t\tif(v.size()!=w.size())continue;\n\t\t\t\tfor(int j=0;j<v.size();j++){\n\t\t\t\t\tif(v[j].first!=w[j].first||v[j].second!=w[j].second)ok=false;\n\t\t\t\t}\n\t\t\t\tif(ok){ret=1;break;}\n\t\t\t}\n\t\t\tif(ret)break;\n\t\t}\n\t\tif(ret)printf(\"true\\n\");\n\t\telse printf(\"false\\n\");\n\t\tgets(str);\n\t}\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 1012, "score_of_the_acc": -0.2361, "final_rank": 12 }, { "submission_id": "aoj_1228_1053417", "code_snippet": "#include<iostream>\n#include<set>\n#include<vector>\n#include<iterator>\n#include<utility>\n#include<algorithm>\n#include<cstdio>\n#include<string>\n\nusing namespace std;\n\nint main(){\n int T;\n cin>>T;\n cin.ignore(1);\n while(T--){\n set<set<pair<int,int> > >ss[2];\n for(int i=0;i<2;i++){\n string str;\n getline(cin,str);\n for(int j=0;j<6;j++){\n\tset<pair<int,int> > s;\n\tint y=0,x=0;\n\tfor(int k=0;;k++){\n\t s.insert(make_pair(x,y)).second;\n\t if(k==str.size())break;\n\t static int dy[]={-1,-1,0,1,1,0};\n\t static int dx[]={0,-1,-1,0,1,1};\n\t int idx=(j+str[k]-'a')%6;\n\t y+=dy[idx];\n\t x+=dx[idx];\n\t}\n\tint mx=999,my=999;\n\tfor(auto e:s){\n\t mx=min(mx,e.first);\n\t my=min(my,e.second);\n\t}\n\tset<pair<int,int> > ns;\n\tfor(auto e:s){\n\t ns.insert(make_pair(e.first-mx,e.second-my));\n\t}\n\tss[i].insert(ns);\n }\n } \n cin.ignore(2);\n vector<set<pair<int,int> > > v;\n set_intersection(begin(ss[0]),end(ss[0]),begin(ss[1]),end(ss[1]),back_inserter(v));\n cout<<boolalpha<<(!v.empty())<<endl;\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 1276, "score_of_the_acc": -0.214, "final_rank": 11 }, { "submission_id": "aoj_1228_955482", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <vector>\n#include <set>\n\nusing namespace std;\n\nint dx[] = {-1, -1, 0, 1, 1, 0};\nint dy[] = {-1, 0, 1, 1, 0, -1};\n\nvector<pair<int, int>> make_set(string &s, int i){\n\tvector<pair<int, int>> ret;\n\tauto pos = make_pair(0, 0);\n\n\tret.push_back(pos);\n\tfor (auto c : s){\n\t\tpos.first += dx[(c - 'a' + i) % 6];\n\t\tpos.second += dy[(c - 'a' + i) % 6];\n\t\tret.push_back(pos);\n\t}\n\tsort(ret.begin(), ret.end());\n\treturn ret;\n}\n\nbool check(string &s, string &t){\n\tvector<pair<int, int>> s1 = make_set(s, 0);\n\tvector<vector<pair<int, int>>> s2(6);\n\tfor (int i = 0; i < 6; ++i) s2[i] = make_set(t, i);\n\n\tfor (auto p : s1){\n\t\tfor (int i = 0; i < 6; ++i){\n\t\t\tbool ok = true;\n\t\t\tfor (int j = 0; j < s1.size(); ++j){\n\t\t\t\tint x = s1[j].first - p.first;\n\t\t\t\tint y = s1[j].second - p.second;\n\t\t\t\tif (make_pair(x, y) != s2[i][j]) ok = false;\n\t\t\t}\n\n\t\t\tif (ok) return true;\n\t\t}\n\t}\n\treturn false;\n}\n\nint main(){\n\tint n;\n\tcin >> n;\n\tcin.ignore();\n\tfor (int i = 0; i < n; ++i){\n\t\tstring s, t, u;\n\t\tgetline(cin, s);\n\t\tgetline(cin, t);\n\t\tgetline(cin, u);\n\t\tif (s.size() == t.size() && check(s, t)) cout << \"true\" << '\\n';\n\t\telse cout << \"false\" << '\\n';\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1208, "score_of_the_acc": -0.1778, "final_rank": 7 }, { "submission_id": "aoj_1228_920121", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n\n#include <iostream>\n#include <cstdio>\n#include <sstream>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <queue>\n#include <stack>\n#include <limits>\n#include <map>\n#include <string>\n#include <cstring>\n#include <set>\n#include <deque>\n#include <bitset>\n#include <list>\n#include <cctype>\n#include <utility>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair <int,int> P;\ntypedef pair <int,P> PP;\n \nstatic const double EPS = 1e-8;\n\npair<int,int> maja(int x) {\n if (x == 0) return pair<int,int>(0,0);\n int n = static_cast<int>(ceil((-1.0+sqrt(1.0+4.0/3.0*x))/2.0));\n int a = 3*n*(n-1), d = static_cast<int>(ceil((1.0*x-a)/n-1.0));\n int k = x - a - n * d;\n switch (d) {\n case 0: return pair<int,int>(n-k,k);\n case 1: return pair<int,int>(-k,n);\n case 2: return pair<int,int>(-n,n-k);\n case 3: return pair<int,int>(-n+k,-k);\n case 4: return pair<int,int>(k,-n);\n case 5: return pair<int,int>(n,-n+k);\n }\n}\n\nint majadist(const pair<int,int> &a, const pair<int,int> &b) {\n int dx = abs(a.first - b.first);\n int dy = abs(a.second - b.second);\n int dz = abs(a.first+a.second-b.first-b.second);\n return min(dx+dy, min(dx+dz, dy+dz));\n}\n\nint main(){\n string strN;\n \n int char2num[256];\n char2num['f'] = 1;\n char2num['e'] = 2;\n char2num['d'] = 3;\n char2num['c'] = 4;\n char2num['b'] = 5;\n char2num['a'] = 6;\n int chars[] = {'f','e','d','c','b','a'};\n\n while(getline(cin,strN)){\n int N = atoi(strN.c_str());\n \n for(int i=0;i<N;i++){\n string routes[2];\n map<pair<int,int>,bool> visited[2][6];\n\n for(int person=0;person<2;person++){\n\tgetline(cin,routes[person]);\n\n\tfor(int offset=0;offset< 6;offset++){\n\t for(int char_idx=0;char_idx<6;char_idx++){\n\t char2num[chars[char_idx]]\n\t = (char_idx + offset) % 6 + 1;\t \n\t } \n\t pair<int,int> current(0,0);\n\t visited[person][offset][current] = true;\n\n\t for(int k=0;k<routes[person].size();k++){\n\t current.first \n\t += maja(char2num[routes[person][k]]).first;\n\t current.second \n\t += maja(char2num[routes[person][k]]).second;\n\t // cout << \"x: \" << current.first;\n\t // cout << \" y: \" << current.second << endl;\n\t visited[person][offset][current] = true;\n\t }\n\t}\n }\n\t\n string garbage;\n getline(cin,garbage);\n\n bool res = false;\n for(int src_offset=0;src_offset< 6;src_offset++){\n\tfor(int dst_offset=0;dst_offset< 6;dst_offset++){\n\t int offset_x\n\t = visited[1][dst_offset].begin()->first.first\n\t - visited[0][src_offset].begin()->first.first;\n\t int offset_y\n\t = visited[1][dst_offset].begin()->first.second\n\t - visited[0][src_offset].begin()->first.second;\n\n\t bool isok = true;\n\t for(map<pair<int,int>,bool>::iterator it = visited[0][src_offset].begin();\n\t it != visited[0][src_offset].end();\n\t it++){\n\t pair<int,int> moved(it->first.first+offset_x,\n\t\t\t\tit->first.second+offset_y);\n\t if(visited[1][dst_offset].find(moved) == visited[1][dst_offset].end()){\n\t isok = false;\n\t break;\n\t }\n\t }\n\t res |= isok;\n\t}\n }\n printf(\"%s\\n\",res ? \"true\" : \"false\");\n }\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 1260, "score_of_the_acc": -0.2051, "final_rank": 10 }, { "submission_id": "aoj_1228_794805", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint dx[] = {0, -1, -1, 0, 1, 1};\nint dy[] = {-1, -1, 0, 1, 1, 0};\n\ntypedef pair<int, int> P; \n\nvector<P> move(int d, vector<int> m){\n int x = 0, y = 0;\n int mx = 0, my = 0;\n vector<P> path;\n path.push_back(P(0, 0));\n for(int i = 0 ; i < (int)m.size() ; i++){\n x += dx[ (m[i]+d)%6 ] ,y += dy[ (m[i]+d)%6 ];\n mx = min(mx, x), my = min(my, y);\n path.push_back(P(x, y));\n }\n sort(path.begin(), path.end());\n for(int i = 0 ; i < (int)path.size() ; i++){\n path[i].first -= mx, path[i].second -= my;\n }\n return path;\n}\n\nbool solve(vector<int> m1, vector<int> m2){\n vector<P> path1 = move(0, m1);\n \n for(int i = 0 ; i < 6 ; i++){\n vector<P> path2 = move(i, m2);\n if(path1 == path2) return true;\n }\n return false;\n}\nint main(){\n int n;\n cin >> n;\n cin.ignore();\n string s1, s2, tmp;\n for(int i = 0 ; i < n ; i++){\n getline(cin, s1);\n getline(cin, s2);\n getline(cin, tmp);\n \n vector<int> m1, m2;\n for(int i = 0 ; i < (int)s1.size() ; i++) m1.push_back(s1[i]-'a');\n for(int i = 0 ; i < (int)s2.size() ; i++) m2.push_back(s2[i]-'a');\n \n if(solve(m1, m2)) cout << \"true\" << endl;\n else cout << \"false\" << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.1746, "final_rank": 6 }, { "submission_id": "aoj_1228_794765", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint dx[] = {0, -1, -1, 0, 1, 1};\nint dy[] = {-1, -1, 0, 1, 1, 0};\n\ntypedef pair<int, int> P; \n\nint main(){\n int n;\n cin >> n;\n cin.ignore();\n string s1, s2, tmp;\n for(int i = 0 ; i < n ; i++){\n getline(cin, s1);\n getline(cin, s2);\n getline(cin, tmp);\n \n vector<int> m1, m2;\n for(int i = 0 ; i < (int)s1.size() ; i++) m1.push_back(s1[i]-'a');\n for(int i = 0 ; i < (int)s2.size() ; i++) m2.push_back(s2[i]-'a');\n \n vector<P> path1;\n int x1 = 0, y1 = 0; \n int mx1 = 0, my1 = 0;\n path1.push_back(P(0, 0));\n for(int i = 0 ; i < (int)m1.size() ; i++){\n x1 += dx[ m1[i] ];\n y1 += dy[ m1[i] ];\n path1.push_back(P(x1, y1));\n mx1 = min(mx1, x1);\n my1 = min(my1, y1); \n }\n for(int i = 0 ; i < path1.size() ; i++){\n path1[i].first -= mx1;\n path1[i].second -= my1;\n }\n sort(path1.begin(), path1.end()); \n \n bool flag = false; \n for(int i = 0 ; i < 6 ; i++){\n int x2 = 0, y2 = 0;\n int mx2 = 0, my2 = 0;\n vector<P> path2;\n path2.push_back(P(0, 0));\n for(int j = 0 ; j < (int)m2.size() ; j++){\n\tx2 += dx[ (m2[j]+i)%6 ];\n\ty2 += dy[ (m2[j]+i)%6 ];\n\tpath2.push_back(P(x2, y2));\n\tmx2 = min(mx2, x2);\n\tmy2 = min(my2, y2);\n }\n for(int j = 0 ; j < path2.size() ; j++){\n\tpath2[j].first -= mx2;\n\tpath2[j].second -= my2;\n }\n sort(path2.begin(), path2.end());\n if(path1 == path2){\n\tflag = true;\n\tgoto END;\n }\n }\n END:;\n if(flag) cout << \"true\" << endl;\n else cout << \"false\" << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1228, "score_of_the_acc": -0.174, "final_rank": 5 }, { "submission_id": "aoj_1228_794746", "code_snippet": "#include<iostream>\n#include<cmath>\n#include<algorithm>\n#include<vector>\n#include<cassert>\n#include<set>\n#include<cstdio>\n\n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define inf (1<<29)\n\nusing namespace std;\n\ntypedef pair<int,int> ii;\n\nconst string roulette = \"abcdef\";\nint dx[] = {-1,-1,+0,+1,+1,+0};\nint dy[] = {+1,+0,-1,-1,+0,+1};\nstring line1,line2;\nint N;\nvector<int> Index[2];\n\nbool check(vector<ii> v1,vector<ii> v2)\n{\n sort(v1.begin(),v1.end());\n sort(v2.begin(),v2.end());\n rep(i,N)if(v1[i] != v2[i])return false;\n return true;\n}\n\nvoid compute()\n{\n if(line1.size() != line2.size())\n {\n cout << \"false\" << endl;\n return;\n }\n N = line2.size();\n \n vector<ii> ori;\n int mx,my;\n ori.push_back(ii(0,0));\n \n int x = 0, y = 0;\n mx = my = 0;\n rep(i,N)\n {\n\tx += dx[line1[i]-'a'];\n\ty += dy[line1[i]-'a'];\n\tmx = min(mx,x);\n\tmy = min(my,y);\n\tori.push_back(ii(x,y));\n }\n \n\n rep(i,ori.size())ori[i].first -= mx, ori[i].second -= my;\n\n\n rep(j,7)//dir\n {\n vector<ii> cont;\n cont.push_back(ii(0,0));\n x = y = 0;\n mx = x, my = y;\n rep(i,N)\n\t{\n\t x += dx[(line2[i]-'a'+j)%6];\n\t y += dy[(line2[i]-'a'+j)%6];\n\t mx = min(mx,x);\n\t my = min(my,y);\n\t cont.push_back(ii(x,y));\n\t}\n \n rep(i,cont.size())cont[i].first -= mx,cont[i].second -= my;\n \n if(check(ori,cont))\n\t{\n\t cout << \"true\" << endl;\n\t return;\n\t}\n \n }\n \n \n \n \n cout << \"false\" << endl;\n}\n\n\nint main()\n{\n int n; \n while(cin >> n)\n {\n cin.ignore();\n string blank;\n while(n--)\n\t{\n\t line1.clear();\n\t line2.clear();\n\t char c;\n\t while((c = getchar()) != '\\n')line1 += c;\n\t while((c = getchar()) != '\\n')line2 += c;\n\t cin >> blank;\n\t cin.ignore();\n\t compute();\n\t}\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1216, "score_of_the_acc": -0.1723, "final_rank": 4 }, { "submission_id": "aoj_1228_545467", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <map>\n#include <set>\nusing namespace std;\n\nconst int dx[6] = {1,0,-1,-1,0,1};\nconst int dy[6] = {0,1,1,0,-1,-1};\n\nset<pair<int,int> > move(const string &s, int diff) {\n int x, y, mx, my;\n set<pair<int,int> > res;\n x = y = mx = my = 0;\n res.insert(make_pair(x,y));\n for(int i = 0; i < s.size(); ++i) {\n int d = (s[i]-'a'+diff)%6;\n x += dx[d];\n y += dy[d];\n res.insert(make_pair(x,y));\n mx = min(mx, x);\n my = min(my, y);\n }\n set<pair<int,int> > res2;\n for(set<pair<int,int> >::iterator it = res.begin();\n it != res.end(); ++it) {\n res2.insert(make_pair(it->first - mx, it->second - my));\n }\n return res2;\n}\n\nint main() {\n int Tc;\n cin >> Tc;\n cin.ignore();\n for(int tc = 0; tc < Tc; ++tc) {\n string s, t, dummy;\n getline(cin, s);\n getline(cin, t);\n getline(cin, dummy);\n set<pair<int,int> > ss = move(s, 0);\n bool res = false;\n for(int i = 0; i < 6; ++i) {\n if(move(t, i) == ss) {\n\tres = true;\n\tbreak;\n }\n }\n if(res) cout << \"true\" << endl;\n else cout << \"false\" << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1212, "score_of_the_acc": -0.1784, "final_rank": 8 }, { "submission_id": "aoj_1228_542578", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <cstdio>\n \nusing namespace std;\n \ntypedef pair<int, int> P;\n\nset<P> vis[2];\nstring in[2];\nint dy[6] = {1, 0, -1, -1, 0, 1};\nint dx[6] = {0, 1, 1, 0, -1, -1};\n \nvoid calc(int p, int d){\n int x = 0, y = 0;\n int mx = 0, my = 0;\n set<P> tmp;\n tmp.insert(P(y, x));\n for(int i=0;i<in[p].size();i++){\n y += dy[(in[p][i]-'a'+d)%6];\n x += dx[(in[p][i]-'a'+d)%6];\n mx = min(mx, x);\n my = min(my, y);\n tmp.insert(P(y, x));\n }\n for(set<P>::iterator ite=tmp.begin();ite!=tmp.end();ite++){\n vis[p].insert(P(ite->first-my, ite->second-mx));\n }\n}\n\nbool solve(){\n vis[0].clear();\n calc(0, 0);\n for(int i=0;i<6;i++){\n vis[1].clear();\n calc(1, i);\n if(vis[0] == vis[1]) return true;\n }\n return false;\n}\n \nint main(){\n int T;\n cin >> T;\n getchar();\n while(T--){\n string s;\n for(int i=0;i<2;i++){\n getline(cin, in[i]);\n }\n getline(cin, s);\n cout << (solve() ? \"true\" : \"false\") << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1212, "score_of_the_acc": -0.1784, "final_rank": 8 }, { "submission_id": "aoj_1228_520256", "code_snippet": "#include<cstdio>\n#include<cstring>\n#include<algorithm>\n\n#define rep(i,n) for(int i=0;i<(n);i++)\n\nusing namespace std;\n\nconst int dx[6]={1,0,-1,-1,0,1};\nconst int dy[2][6]={{0,1,0,-1,-1,-1},{1,1,1,0,-1,0}};\n\nbool solve(const char *s,const char *t){\n\tint m=strlen(s)-1,n=strlen(t)-1;\n\n\tif(m!=n) return false;\n\n\tpair<int,int> p[128];\n\tint x=0,y=0;\n\trep(i,m+1){\n\t\tp[i]=make_pair(x,y);\n\t\tif(i<m){\n\t\t\ty+=dy[x&1][s[i]-'a'];\n\t\t\tx+=dx[s[i]-'a'];\n\t\t}\n\t}\n\n\trep(k,m+1) rep(d,6) {\n\t\tbool ok=true;\n\t\tint x=p[k].first,y=p[k].second;\n\t\trep(i,n+1){\n\t\t\tif(find(p,p+m+1,make_pair(x,y))==p+m+1){ ok=false; break; }\n\t\t\tif(i<n){\n\t\t\t\ty+=dy[x&1][(t[i]-'a'+d)%6];\n\t\t\t\tx+=dx[(t[i]-'a'+d)%6];\n\t\t\t}\n\t\t}\n\t\tif(ok) return true;\n\t}\n\treturn false;\n}\n\nint main(){\n\tint T; scanf(\"%d\",&T);\n\tfor(getchar();T--;){\n\t\tchar s[128],t[128];\n\t\tfgets(s,128,stdin);\n\t\tfgets(t,128,stdin);\n\t\tgetchar(); getchar();\n\t\tputs(solve(s,t)?\"true\":\"false\");\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1016, "score_of_the_acc": -0.144, "final_rank": 3 }, { "submission_id": "aoj_1228_495906", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <set>\n#include <map>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <cassert>\n\nusing namespace std;\n\n#define FOR(i,k,n) for(int i=(k); i<(int)n; ++i)\n#define REP(i,n) FOR(i,0,n)\n#define FORIT(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n\ntemplate<class T> void debug(T begin, T end){ for(T i = begin; i != end; ++i) cout<<*i<<\" \"; cout<<endl; }\n\ntypedef long long ll;\nconst int INF = 100000000;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\ntypedef pair<int, int> P;\nvoid move(int x, int y, int& nx, int& ny, int r){\n int dx[6] = {1, 0, -1, -1, 0, 1};\n int dy[6] = {1, 1, 0, -1, -1, 0};\n nx = x + dx[r];\n ny = y + dy[r];\n}\n\nint main(){\n int N;\n cin>>N;\n cin.ignore();\n while(N--){\n string s, t, tmp;\n getline(cin, s);\n getline(cin, t);\n getline(cin, tmp);\n set<P> p_set;\n int x = 0, y = 0;\n p_set.insert(P(x, y));\n REP(i, s.size()){\n move(x, y, x, y, s[i] - 'a');\n //printf(\"(%d %d) \", x, y);\n p_set.insert(P(x, y));\n }\n bool ans = false;\n REP(d, 6){\n vector<P> p_vect;\n x = 0, y = 0;\n p_vect.push_back(P(x, y));\n REP(i, t.size()){\n move(x, y, x, y, (t[i] - 'a' + d) % 6);\n p_vect.push_back(P(x, y));\n }\n REP(i, p_vect.size()){\n int bx = p_vect[i].first, by = p_vect[i].second;\n set<P> p_set2;\n REP(j, p_vect.size()){\n p_set2.insert(P(p_vect[j].first - bx, p_vect[j].second - by));\n }\n if(p_set == p_set2) ans = true;\n }\n }\n if(ans) cout<<\"true\"<<endl;\n else cout<<\"false\"<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 390, "memory_kb": 1212, "score_of_the_acc": -0.4234, "final_rank": 14 }, { "submission_id": "aoj_1228_331309", "code_snippet": "#include<iostream>\n#include<string>\nusing namespace std;\n#define rep(i, n) for ( int i = 0; i < (int)n; i++ )\n#define MAX 250\n\nbool compute(string str1, string str2){\n bool V1[MAX][MAX], V2[MAX][MAX];\n int ldy1, ldx1, rty1, rtx1;\n int dy[6] = {1, 1, 0, -1, -1, 0};\n int dx[6] = {0, -1, -1, 0, 1, 1};\n if ( str1.size() != str2.size() ) return false;\n int n = (int)str1.size()*2+2;\n rep(y, n) rep(x, n) V1[y][x] = false;\n\n int py = n/2;\n int px = n/2;\n V1[py][px] = true;\n ldy1 = rty1 = py;\n ldx1 = rtx1 = px;\n rep(i, str1.size()){\n int r = (str1[i]-'a')%6;\n py += dy[r];\n px += dx[r];\n V1[py][px] = true;\n ldy1 = min(ldy1, py);\n ldx1 = min(ldx1, px);\n rty1 = max(rty1, py);\n rtx1 = max(rtx1, px);\n }\n\n rep(d, 6){\n int ldy2, ldx2, rty2, rtx2;\n py = n/2;\n px = n/2;\n ldy2 = rty2 = py;\n ldx2 = rtx2 = px;\n rep(y, n) rep(x, n) V2[y][x] = false;\n V2[py][px] = true;\n rep(i, str2.size()){\n int r = (str2[i]-'a'+d)%6;\n py += dy[r];\n px += dx[r];\n V2[py][px] = true;\n ldy2 = min(ldy2, py);\n ldx2 = min(ldx2, px);\n rty2 = max(rty2, py);\n rtx2 = max(rtx2, px);\n }\n if ( !(rty1-ldy1 == rty2-ldy2 && rtx1-ldx1 == rtx2-ldx2 ) ) continue;\n int h = rty1-ldy1+1;\n int w = rtx1-ldx1+1;\n bool same = true;\n rep(y, h) rep(x, w){\n if ( V1[y+ldy1][x+ldx1] != V2[y+ldy2][x+ldx2] ) {same = false; break;}\n }\n if ( same ) return true;\n }\n return false;\n}\n\nmain(){\n int tcase; cin >> tcase;\n string str1, str2, kasu;\n getline(cin, kasu);\n rep(t, tcase) {\n getline(cin, str1);\n getline(cin, str2);\n if (compute(str1, str2) ) cout << \"true\" << endl;\n else cout << \"false\" << endl;\n getline(cin, kasu);\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 0, "score_of_the_acc": -0.0066, "final_rank": 1 }, { "submission_id": "aoj_1228_293288", "code_snippet": "#include <iostream>\n#include <fstream>\n#include <sstream>\n#include <string>\n#include <vector>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <climits>\n#include <cctype>\n#include <complex>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int,int> P;\n\n#define REP(i,n,m) for(int i=n;i<m;i++)\n#define rep(i,n) REP(i,0,n)\n\nint dx[] = {1,0,-1,-1, 0,1};\nint dy[] = {1,1, 0,-1,-1,0};\n\nbool equals(set<P> a,set<P> b){\n if(a.size() != b.size()) return false;\n\n set<P>::iterator iterA = a.begin();\n set<P>::iterator iterB = b.begin();\n int diffX = (iterA->first) - (iterB->first);\n int diffY = (iterA->second) - (iterB->second);\n\n while(iterA != a.end()){\n if((iterA->first) - (iterB->first) != diffX ||\n (iterA->second) - (iterB->second) != diffY){\n return false;\n }\n iterA++;\n iterB++;\n }\n return true;\n}\n\nint main(){\n int T;\n string tmp;\n cin>>T;\n getline(cin,tmp);\n\n while(T--){\n string a,b;\n getline(cin,a);\n getline(cin,b);\n getline(cin,tmp);\n\n set<P> aset;\n P p(0,0);\n aset.insert(p);\n\n rep(i,a.length()){\n p.first += dx[a[i] - 'a'];\n p.second += dy[a[i] - 'a'];\n aset.insert(p);\n }\n\n /*\n for(set<P>::iterator iter=aset.begin();iter!=aset.end();iter++){\n cout<<(iter->first)<<\",\"<<(iter->second)<<endl;\n }\n cout<<\"--\\n\";\n */\n\n bool flg = false;\n\n rep(i,6){\n set<P> bset;\n bset.clear();\n p = P(0,0);\n bset.insert(p);\n rep(j,b.length()){\n p.first += dx[((int)b[j] - 'a' + i) % 6];\n p.second += dy[((int)b[j] - 'a' + i) % 6];\n bset.insert(p);\n }\n /*\n if(b.length() > 0 && b[0] == 'b'){\n for(set<P>::iterator iter=bset.begin();iter!=bset.end();iter++){\n cout<<(iter->first)<<\",\"<<(iter->second)<<endl;\n }\n cout<<endl;\n }\n */\n\n if(equals(aset,bset)){\n flg = true;\n break;\n }\n }\n\n if(flg){\n cout<<\"true\\n\";\n }\n else{\n cout<<\"false\\n\";\n }\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 0, "score_of_the_acc": -0.0199, "final_rank": 2 } ]
aoj_1232_cpp
Problem A: Calling Extraterrestrial Intelligence Again A message from humans to extraterrestrial intelligence was sent through the Arecibo radio telescope in Puerto Rico on the afternoon of Saturday November l6, l974. The message consisted of l679 bits and was meant to be translated to a rectangular picture with 23 × 73 pixels. Since both 23 and 73 are prime numbers, 23 × 73 is the unique possible size of the translated rectangular picture each edge of which is longer than l pixel. Of course, there was no guarantee that the receivers would try to translate the message to a rectangular picture. Even if they would, they might put the pixels into the rectangle incorrectly. The senders of the Arecibo message were optimistic. We are planning a similar project. Your task in the project is to find the most suitable width and height of the translated rectangular picture. The term ``most suitable'' is defined as follows. An integer m greater than 4 is given. A positive fraction a / b less than or equal to 1 is also given. The area of the picture should not be greater than m . Both of the width and the height of the translated picture should be prime numbers. The ratio of the width to the height should not be less than a / b nor greater than 1. You should maximize the area of the picture under these constraints. In other words, you will receive an integer m and a fraction a / b . It holds that m > 4 and 0 < a / b ≤ 1 . You should find the pair of prime numbers p , q such that pq ≤ m and a / b ≤ p / q ≤ 1 , and furthermore, the product pq takes the maximum value among such pairs of two prime numbers. You should report p and q as the "most suitable" width and height of the translated picture. Input The input is a sequence of at most 2000 triplets of positive integers, delimited by a space character in between. Each line contains a single triplet. The sequence is followed by a triplet of zeros, 0 0 0, which indicates the end of the input and should not be treated as data to be processed. The integers of each input triplet are the integer m , the numerator a , and the denominator b described above, in this order. You may assume 4 < m < 100000 and 1 ≤ a ≤ b ≤ 1000. Output The output is a sequence of pairs of positive integers. The i -th output pair corresponds to the i -th input triplet. The integers of each output pair are the width p and the height q described above, in this order. Each output line contains a single pair. A space character is put between the integers as a delimiter. No other characters should appear in the output. Sample Input 5 1 2 99999 999 999 1680 5 16 1970 1 1 2002 4 11 0 0 0 Output for the Sample Input 2 2 313 313 23 73 43 43 37 53
[ { "submission_id": "aoj_1232_10896784", "code_snippet": "#include<bits/stdc++.h>\n// #include<atcoder/all>\n// #include<boost/multiprecision/cpp_int.hpp>\n\nusing namespace std;\n// using namespace atcoder;\n// using bint = boost::multiprecision::cpp_int;\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing ve = vector<vector<int>>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\n#define rep(i,s,n) for(ll i = (ll)s;i < (ll)n;i++)\n#define rrep(i,l,r) for(ll i = r-1;i >= l;i--)\n#define ALL(x) (x).begin(),(x).end()\n#define sz(c) ((ll)(c).size())\n#define LB(A,x) (int)(lower_bound(A.begin(),A.end(),x)-A.begin())\n#define UB(A,x) (int)(upper_bound(A.begin(),A.end(),x)-A.begin())\n// #define MOD 1000000007\n#define MOD 998244353\ntemplate<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T>ostream&operator<<(ostream&os,vector<T>&v){for(int i = 0;i < v.size();i++)os<<v[i]<<(i+1!=v.size()?\" \":\"\");return os;}\ntemplate<typename T>istream&operator>>(istream&is,vector<T>&v){for(T&in:v)is>>in;return is;}\ntemplate<typename T1,typename T2>ostream&operator<<(ostream&os,pair<T1,T2>&p){os<<p.first<<\" \"<<p.second;return os;}\ntemplate<typename T1,typename T2>istream&operator>>(istream&is,pair<T1,T2>&p){is>>p.first>>p.second;return is;}\ntemplate<typename T> inline bool chmax(T &a,T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> inline bool chmin(T &a,T b){if(a > b){a = b;return true;}return false;}\nld dist(ld x1,ld y1,ld x2, ld y2){return sqrtl((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));}\n\n\nint main(){\n \n ios_base::sync_with_stdio(0), cin.tie(0);\n vi P;\n vb mem(100000,1);mem[0] = mem[1] = 0;\n for(int i = 2;i < 100000;i++){\n if(!mem[i])continue;\n P.emplace_back(i);\n for(int j = 2*i;j < 100000;j += i)mem[j] = 0;\n }\n while(1){\n int m,a,b;cin >> m >> a >> b;\n if(!m)break;\n // maximize pq s.t. pq <= m && a/b <= p/q <= 1\n ll x = 0,y = 0;\n rep(p,0,sz(P))rep(q,p,sz(P)){\n if(P[p]*P[q] > m)break;\n if(a*P[q] <= b*P[p] && x*y < P[p]*P[q]){x = P[p],y = P[q];}\n }\n cout << x << \" \" << y << \"\\n\";\n }\n \n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3512, "score_of_the_acc": -0.1727, "final_rank": 8 }, { "submission_id": "aoj_1232_10720609", "code_snippet": "// AOJ 1232 - Calling Extraterrestrial Intelligence Again\n// ICPC Asia Japan Regional Contest 2002 - Problem A\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nset<ll> prime;\n\nbool solve() {\n int m, a, b; cin >> m >> a >> b;\n if(m == 0) return false;\n\n int area = 0;\n pair<int,int> best;\n for(ll q : prime) {\n for(ll p : prime) {\n if(p > q) break;\n if(p * q > m) break;\n if(a*q <= b*p && area < p*q) {\n area = p * q;\n best = make_pair(p, q);\n }\n }\n }\n cout << best.first << ' ' << best.second << endl;\n return true;\n}\n\nint main() {\n for(ll i = 3; i < 100000; i += 2) prime.insert(i);\n for(ll i : prime) {\n for(ll j = i; i*j < 100000; j += 2) {\n prime.erase(i * j);\n }\n }\n prime.insert(2);\n \n while(solve()) {}\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 5760, "score_of_the_acc": -1.0355, "final_rank": 20 }, { "submission_id": "aoj_1232_10022080", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define all(a) a.begin(),a.end()\n#define reps(i, a, n) for (int i = (a); i < (int)(n); i++)\n#define rep(i, n) reps(i, 0, n)\n#define rreps(i, a, n) for (int i = (a); i > (int)(n); i--)\nconst long long mod = 1000000007;\nconst long long INF = 1e18;\nll myceil(ll a, ll b) {return (a+b-1)/b;}\n\n\nvector<int> prime(0);\nint m,a,b;\n\nvoid solve() {\n ll ans = 0;\n pair<int,int> ap;\n for (int i = 0; i < prime.size(); i++) {\n int q = prime[i];\n auto pi = upper_bound(all(prime),min(m/q,q));\n pi--;\n ll p = *pi;\n\n if (p*b >= a*q && p <= q) {\n if (ans < p*q) {\n ans = p*q;\n ap = {p,q};\n }\n }\n }\n\n cout << ap.first << ' ' << ap.second << endl;\n return;\n}\n\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n\n prime.push_back(2);\n prime.push_back(3);\n int fl = 0;\n for (int i = 5; i < 10050; i+=2) {\n fl = 0;\n for (int j = 3; j*j<=i; j+=2) {\n if (i%j==0) {\n fl = 1;\n break;\n }\n }\n if (fl == 0) {\n prime.push_back(i);\n }\n }\n\n cin >> m >> a >> b;\n while (m != 0) {\n solve();\n cin >> m >> a >> b;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3476, "score_of_the_acc": -0.1566, "final_rank": 5 }, { "submission_id": "aoj_1232_9572606", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint main() {\n int MAXS = 1000010;\n vector<bool> Prime(MAXS,true);\n Prime[0] = Prime[1] = false;\n rep(i,2,MAXS) {\n if (Prime[i]) {\n rep(j,2,MAXS) {\n if (i * j >= MAXS) break;\n Prime[i*j] = false;\n }\n }\n }\nwhile(1) {\n int M, A, B;\n cin >> M >> A >> B;\n if (M == 0) return 0;\n int X, Y, MAX = 0;\n rep(i,1,MAXS) {\n if (i*i > M) break;\n if (!Prime[i]) continue;\n rep(j,i,(i*B)/A+1) {\n if (i*j>M) break;\n if (!Prime[j]) continue;\n if (MAX < i * j) X = i, Y = j, MAX = i * j;\n }\n }\n cout << X << ' ' << Y << endl;\n}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3516, "score_of_the_acc": -0.1713, "final_rank": 7 }, { "submission_id": "aoj_1232_9279442", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <vector>\n\n#define ll long long\nusing namespace std;\n\nint main() {\n vector<ll> prime;\n vector<bool> check(8000, true);\n check[0] = false;\n check[1] = false;\n for (ll i = 2; i < 8000; i++) {\n if (check[i]) {\n for (ll j = i * 2; j < 8000; j += i) {\n check[j] = false;\n }\n }\n }\n\n for (ll i = 0; i < 8000; i++) {\n if (check[i]) {\n prime.push_back(i);\n }\n }\n\n while (1) {\n ll m = 0, a = 0, b = 0, p = 0, q = 0, max = -1;\n double ab;\n cin >> m >> a >> b;\n ab = (double)a /b;\n if (m == 0 && a == 0 && b == 0) {\n break;\n }\n\n for (ll i = 0; i < prime.size(); i++) {\n for (ll j = 0; j < prime.size(); j++) {\n if ((ab <= (double)prime[i] / (double)prime[j])&&((double)prime[i]/(double)prime[j]<=1.0) && (prime[i] * prime[j] <= m)){\n if ((max < prime[i] * prime[j])) {\n max = prime[i] * prime[j];\n p = prime[i];\n q = prime[j];\n }\n }\n }\n }\n\n cout << p << \" \" << q << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 7070, "memory_kb": 3120, "score_of_the_acc": -1.0251, "final_rank": 18 }, { "submission_id": "aoj_1232_9279439", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <vector>\n\n#define ll long long\nusing namespace std;\n\nint main() {\n vector<ll> prime;\n vector<bool> check(8000, true);\n check[0] = false;\n check[1] = false;\n for (ll i = 2; i < 8000; i++) {\n if (check[i]) {\n for (ll j = i * 2; j < 8000; j += i) {\n check[j] = false;\n }\n }\n }\n\n for (ll i = 0; i < 8000; i++) {\n if (check[i]) {\n prime.push_back(i);\n }\n }\n\n while (1) {\n ll m = 0, a = 0, b = 0, p = 0, q = 0, max = -1;\n double ab;\n cin >> m >> a >> b;\n ab = (double)a /(double) b;\n if (m == 0 && a == 0 && b == 0) {\n break;\n }\n\n for (ll i = 0; i < prime.size(); i++) {\n for (ll j = 0; j < prime.size(); j++) {\n if ((ab <= (double)prime[i] / (double)prime[j])&&((double)prime[i]/(double)prime[j]<=1.0) && (prime[i] * prime[j] <= m)){\n if ((max < prime[i] * prime[j])) {\n max = prime[i] * prime[j];\n p = prime[i];\n q = prime[j];\n }\n }\n }\n }\n\n cout << p << \" \" << q << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 7070, "memory_kb": 3136, "score_of_the_acc": -1.031, "final_rank": 19 }, { "submission_id": "aoj_1232_9144690", "code_snippet": "#include <algorithm>\n#include <cmath>\n#include <cstdlib>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <string>\n#include <vector>\n\nusing namespace std;\n\nvector<int> generatePrimes(int max) {\n\tvector<bool> is_prime_list(max, true);\n\tvector<int> primes;\n\tis_prime_list[0] = is_prime_list[1] = false;\n\n\tfor (int i = 2; i <= max; i++) {\n\t\tif (!is_prime_list[i]) continue;\n\t\tprimes.push_back(i);\n\t\tfor (int j = 2 * i; j <= max; j += i) {\n\t\t\tis_prime_list[j] = false;\n\t\t}\n\t}\n\n\treturn primes;\n}\n\nint main() {\n\tvector<int> primes = generatePrimes(50000);\n\n\twhile (true) {\n\t\tint m, a, b;\n\t\tcin >> m >> a >> b;\n\t\tif (m == 0 && a == 0 && b == 0) break;\n\n\t\tint max = 0, max_p = 0, max_q = 0;\n\t\tfor (auto p = primes.begin(); p != primes.end() && *p <= m; p++) {\n\t\t\tfor (auto q = p; q != primes.end() && *p * *q <= m && a * *q <= b * *p; q++) {\n\t\t\t\tif (max < *p * *q) {\n\t\t\t\t\tmax = *p * *q;\n\t\t\t\t\tmax_p = *p;\n\t\t\t\t\tmax_q = *q;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tcout << max_p << \" \" << max_q << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3400, "score_of_the_acc": -0.137, "final_rank": 3 }, { "submission_id": "aoj_1232_9144086", "code_snippet": "#include <algorithm>\n#include <bitset>\n#include <cctype>\n#include <cmath>\n#include <deque>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <vector>\n// #include<atcoder/all>\n\nusing namespace std;\n// using namespace atcoder;\n\n#define ll long long\n#define ull unsigned long long\n#define rep(i, start, end) for (ll i = (ll)start; i < (ll)end; i++)\n#define rep2(i, start, end) for (ll i = (ll)start; i <= (ll)end; i++)\n#define rrep(i, start, end) for (ll i = (ll)start; i >= (ll)end; i--)\n#define all(a) a.begin(), a.end()\n#define P pair<int, int>\n#define Pll pair<ll, ll>\n\ntemplate <class T>\nvoid chmin(T &a, T b) {\n if (a > b) a = b;\n}\n\ntemplate <class T>\nvoid chmax(T &a, T b) {\n if (a < b) a = b;\n}\n\nvoid yn(bool x) { cout << (x ? \"Yes\" : \"No\") << endl; }\n\nll digit(ll n) {\n ll digit_num = 0;\n while (n > 0) {\n digit_num++;\n n /= 10;\n }\n return digit_num;\n}\n\nvoid t() { cout << \"Takahashi\" << endl; }\n\nll power_mod(ll n, ll k, ll mod) {\n // ll mod = 998244353;\n ll result = 1;\n while (k > 0) {\n if ((k & 1) == 1) result = (result * n) % mod;\n n = n * n % mod;\n k >>= 1;\n }\n return result;\n}\n\nint chc_n(char c) {\n int a = c - 'a';\n return a;\n}\n\nchar chn_c(int a) {\n char c = a + 'a';\n return c;\n}\n\nll ch_10num(string s, ll k) {\n ll ans = 0;\n for (char x : s) {\n ans *= k;\n ans += x - '0';\n // cout << ans << endl;\n }\n return ans;\n}\n\nconst int inf = 1 << 30;\n\nconst ll INF = 1ll << 60;\n\nconst int dx[9] = {-1, 0, 1, 0, 1, 1, -1, -1, 0},\n dy[9] = {0, 1, 0, -1, 1, -1, 1, -1, 0};\n\n/*-------------------------------template-------------------------------*/\n\nint main() {\n vector<bool> hurui(8000, true);\n hurui[0] = hurui[1] = false;\n rep(i, 2, 8000) {\n if (hurui[i] == true) {\n for (int j = 2 * i; j < 8000; j += i) {\n hurui[j] = false;\n }\n }\n }\n vector<int> prime;\n rep(i, 2, 8000) {\n if (hurui[i]) prime.push_back(i);\n }\n int primeSize = prime.size();\n while (1) {\n int m, a, b, p = 0, q = 0;\n cin >> m >> a >> b;\n if (m == 0 and a == 0 and b == 0) break;\n rep(i, 0, primeSize) {\n rep(j, i, primeSize){\n if(prime[i]*prime[j] > p*q and prime[i]*prime[j] <= m and (double)a/b <= (double)prime[i]/prime[j]){\n p = prime[i];\n q = prime[j];\n }\n }\n }\n cout << p << \" \" << q << endl;\n }\n}", "accuracy": 1, "time_ms": 790, "memory_kb": 3188, "score_of_the_acc": -0.1594, "final_rank": 6 }, { "submission_id": "aoj_1232_8993670", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n// #pragma GCC target(\"avx2\")\n// #pragma GCC optimize(\"O3\")\n// #pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = 3.141592653589793;\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\ntemplate<typename T> void view(const vv<T>& vv){ for(const auto& v : vv){ view(v); } }\n\nvc<bool> eratosthenes(int t){\n vc<bool> is_prime(t + 1, true);\n is_prime[0] = false; is_prime[1] = false;\n for (int i = 0; i <= t; i++){\n if (is_prime[i]){\n for (int q = i * 2; q <= t; q += i){\n is_prime[q] = false;\n }\n }\n }\n return is_prime;\n}\n\nauto is_prime = eratosthenes(100000);\nvi prime;\n\npair<int, int> solve(int M, int A, int B){\n int ansp = 2, ansq = 2;\n for (auto q : prime) if (q <= M){\n auto it = lower_bound(all(prime), min(q, M / q));\n if (it != prime.end() && *it * q <= M && *it <= q && A * q <= B * *it){\n if (ansp * ansq < *it * q){\n ansp = *it;\n ansq = q;\n }\n }if (it != prime.begin()){\n it--;\n if (A * q <= B * *it && ansp * ansq < *it * q){\n ansp = *it;\n ansq = q;\n }\n }\n }\n return {ansp, ansq};\n}\n\nint main(){\n rep(i, 100000) if (is_prime[i]) prime.push_back(i);\n vc<pair<int, int>> ans;\n while (true){\n int M, A, B; cin >> M >> A >> B;\n if (M == 0) break;\n ans.push_back(solve(M, A, B));\n }\n for (auto x : ans) cout << x.first << \" \" << x.second << endl;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3552, "score_of_the_acc": -0.1988, "final_rank": 10 }, { "submission_id": "aoj_1232_8966972", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\n#define rep(i, a, b) for(ll i = a; i < b; ++i)\n#define rrep(i, a, b) for(ll i = a; i >= b; --i)\nconstexpr ll inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\npair<vector<int>, vector<int>> seive(int n) {\n assert(n >= 1);\n vector<int> min_factor(n + 1);\n iota(min_factor.begin(), min_factor.end(), 0);\n min_factor[0] = min_factor[1] = -1;\n vector<int> prime;\n for(long long i = 2; i <= n; ++i) {\n if(min_factor[i] < i) continue;\n prime.push_back(i);\n for(long long j = i * i; j <= n; j += i) {\n if(min_factor[j] == j) min_factor[j] = i;\n }\n }\n return {prime, min_factor};\n}\nint main(void) {\n auto [prime, min_factor] = seive(100000);\n while(1) {\n ll m, a, b;\n cin >> m >> a >> b;\n if(m == 0 and a == 0 and b == 0) break;\n P ans = {0, 0};\n for(ll q : prime) {\n if(q > m / 2) break;\n for(ll p : prime) {\n if(p * q > m or p > q) break;\n if(a * q <= b * p and p * q > ans.first * ans.second) {\n ans = {p, q};\n }\n }\n }\n cout << ans.first << ' ' << ans.second << '\\n';\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3936, "score_of_the_acc": -0.3279, "final_rank": 14 }, { "submission_id": "aoj_1232_8396781", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nvector<int> vec;\nvoid furui(){\n bool f[100010]={};\n vec.push_back(2);\n for(int i=3;i<320;i+=2){\n if(f[i]) continue;\n vec.push_back(i);\n for(int j=i*i;j<100000;j+=i) f[j] = true;\n }\n for(int i=323;i<50000;i+=2){\n if(!f[i]) vec.push_back(i);\n }\n}\nint main(){\n int m, a, b;\n furui();\n while(cin >> m >> a >> b, m){\n int p=0, q=0;\n for(int i=0;i<vec.size();i++){\n for(int j=i;j<vec.size()&&vec[i]*vec[j]<=m&&a*vec[j]<=b*vec[i];j++){\n if(p*q<vec[i]*vec[j]){\n p = vec[i];\n q = vec[j];\n }\n }\n }\n cout << p << \" \" << q << endl;\n }\n return(0);\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 3120, "score_of_the_acc": -0.0521, "final_rank": 1 }, { "submission_id": "aoj_1232_8396774", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nvector<int> vec;\nvoid furui(){\n bool f[100010]={};\n vec.push_back(2);\n for(int i=3;i<320;i+=2){\n if(f[i]) continue;\n vec.push_back(i);\n for(int j=i*i;j<100000;j+=i) f[j] = true;\n }\n for(int i=323;i<50000;i+=2){\n if(!f[i]) vec.push_back(i);\n }\n}\nint main(){\n int m, a, b;\n furui();\n while(cin >> m >> a >> b, m){\n int p=0, q=0;\n for(int i=0;i<vec.size();i++){\n for(int j=i;j<vec.size()&&vec[i]*vec[j]<=m;j++){\n if(a*vec[j]<=b*vec[i]){\n if(p*q<vec[i]*vec[j]){\n p = vec[i];\n q = vec[j];\n }\n }\n }\n }\n cout << p << \" \" << q << endl;\n }\n return(0);\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3220, "score_of_the_acc": -0.0932, "final_rank": 2 }, { "submission_id": "aoj_1232_8029186", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n while (1) {\n int m, a, b;\n cin >> m >> a >> b;\n \n if(m == 0 and a == 0 and b == 0) break;\n \n int ans = 0, ansx, ansy;\n double flag = (double)a / b;\n for (int i = 1; i <= m; i++) {\n for (int j = 1; i * j <= m; j++) {\n if(ans <= i * j and flag <= (double)i / j and (double)i / j <= 1) {\n int flag2 = 1;\n for(int k = 2; k * k <= i; k++) {\n if(i == 2) break;\n if(i % k == 0) flag2 = 0;\n }\n for(int k = 2; k * k <= j; k++) {\n if(j == 2) break;\n if(j % k == 0) flag2 = 0;\n }\n \n if(flag2 == 1) {\n ans = i * j;\n ansx = i;\n ansy = j;\n }\n }\n }\n }\n \n cout << ansx << ' ' << ansy << endl;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 1000, "memory_kb": 3052, "score_of_the_acc": -0.139, "final_rank": 4 }, { "submission_id": "aoj_1232_8017679", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<queue>\n#include<set>\n\nusing namespace std;\nusing ll = long long;\n\nll n,a,b;\nvoid solve(){\n vector<int> use(n+1,0);\n vector<ll> can;\n for(int i = 2;i<=n;i++) if(use[i]==0){\n can.push_back(i);\n for(int j = i;j<=n;j+=i) use[j] = 1;\n }\n ll ans = 0;\n ll ni = 0;\n ll nj = 0;\n for(int i = 0;i<can.size();i++) for(int j = i;j<can.size();j++){\n ll now = can[i] * can[j];\n if(now>n) break;\n if(can[j]*a>can[i]*b) continue;\n if(ans<now){\n ans = now;\n ni = can[i];\n nj = can[j];\n }\n }\n cout<<ni<<\" \"<<nj<<endl;\n}\n\nint main(){\n while(true){\n cin>>n>>a>>b;\n if(n==0) break;\n solve();\n }\n}", "accuracy": 1, "time_ms": 340, "memory_kb": 3780, "score_of_the_acc": -0.3142, "final_rank": 13 }, { "submission_id": "aoj_1232_7979292", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n\tint m, a, b;\n\twhile(cin >> m >> a >> b, m) {\n\t\t\n\t\tvector<bool> p(m+1, true);\n\t\tp[0] = false;\n\t\tp[1] = false;\n\t\tfor(int i=2;i*i<=m;i++) {\n\t\t\tfor(int j=2;i*j<=m;j++) {\n\t\t\t\tp[i*j] = false;\n\t\t\t}\n\t\t}\n\t\tint s = 0;\n\t\tint ansx, ansy;\n\t\tfor(int i=2;i*i<=m;i++) {\n\t\t\tfor(int j=i;i*j<=m;j++) {\n\t\t\t\tif(!p[i] || !p[j]) continue; \n\t\t\t\t\n\t\t\t\tif(m >= i*j && (1.0*a/b) <= (1.0*i/j)) {\n\t\t\t\t\tif(s <= i*j) {\n\t\t\t\t\t\tansx = i;\n\t\t\t\t\t\tansy = j;\n\t\t\t\t\t\ts = i*j;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t}\n\t\t}\n\t\tcout << ansx << \" \" << ansy << endl;\n\t}\n}", "accuracy": 1, "time_ms": 890, "memory_kb": 3404, "score_of_the_acc": -0.2534, "final_rank": 12 }, { "submission_id": "aoj_1232_7130039", "code_snippet": "#include<bits/stdc++.h>\n#define int ll\n#define rep(i, N) for(int i = 0; i < (int)(N); ++i)\n#define per(i, N) for(int i = (int)(N)-1; i >= 0; --i)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\n#define bit(n, k) (((n) >> (k)) & 1)\n#define pcnt(n) (bitset<64>(n).count())\n#define endl '\\n'\n#define fi first\n#define se second\n#define mkpr make_pair\n#define mktpl make_tuple\n#define eb emplace_back\n\n#ifdef LOCAL\n#define debug(x) cerr << \"line:\"<< __LINE__ << \" \" << #x << \" = \" << x << '\\n'\n#define dbgln() cerr << \"line:\" << __LINE__ << \" passed.\\n\"\n#else\n#define debug(x) void(0)\n#define dbgln() void(0)\n#endif\n\nusing namespace std;\nusing ll = int64_t;\nusing ull = uint64_t;\nusing ld = long double;\nusing point = struct{ ld x, y; };\nusing State = string::iterator;\ntemplate<class T> using max_heap = priority_queue<T>;\ntemplate<class T> using min_heap = priority_queue<T, vector<T>, greater<T>>;\ntemplate<class T> using vec = vector<T>;\ntemplate<class T> using vvec = vec<vec<T>>;\ntemplate<class T> using vvvec = vec<vvec<T>>;\n\nconstexpr ld EPS = 1e-10;\nld Pi = acos(-1);\nconstexpr int INF = 1001001001;\nconstexpr ll LINF = 1001001001001001001ll;\nconstexpr ll MOD = (1) ? 998244353 : 1e9+7;\nconstexpr int NIL = -1;\nconstexpr int pm[2] = {1, -1};\nconstexpr int dy[4] = {0, 1, 0, -1};\nconstexpr int dx[4] = {1, 0, -1, 0};\nconstexpr int dy8[8] = {0, 1, 1, 1, 0, -1, -1, -1};\nconstexpr int dx8[8] = {1, 1, 0, -1, -1, -1, 0, 1};\n\nll cel(ll a, ll b){ return (a + b - 1) / b;}\nll Gcd(ll a, ll b){ return b ? Gcd(b, a % b) : abs(a);}\nll Lcm(ll a, ll b){ return a / Gcd(a, b) * b;}\ntemplate<class T> T powi(T x, ll exp){\n return exp > 0 ? (exp & 1 ? x : 1) * powi(x * x, exp >> 1) : x / x;\n}\nll modpow(ll x, ll exp, ll mod){\n x %= mod;\n return exp > 0 ? (exp & 1 ? x : 1) * modpow(x * x, exp >> 1, mod) % mod : 1;\n}\ntemplate<class T> bool chmin(T &a, T b){ return a > b ? (a = b, true) : 0;}\ntemplate<class T> bool chmax(T &a, T b){ return a < b ? (a = b, true) : 0;}\n\nusing Pair = pair<ll, ll>;\nusing Tpl = tuple<int, int, int>;\n\nbool isPrime(ll p){\n if(p < 2) return false;\n for(ll i = 2; i * i <= p; i++){\n if(p % i == 0) return false;\n }\n return true;\n}\n\nvoid Main(){\n vec<int> Prime(100010, NIL);\n vec<int> mx_P(100010, NIL);\n rep(i, 100010){\n if(isPrime(i)) Prime[i] = i;\n }\n rep(i, 100010){\n if(i == 0) continue;\n if(Prime[i] == NIL) mx_P[i] = mx_P[i - 1];\n else mx_P[i] = i;\n }\n //rep(i, 10) cout << mx_P[i] << endl;\n while(1){\n //cout << mx_P[99999 / 313] << endl;\n int M, A, B; cin >> M >> A >> B;\n if(M == 0) break;\n ll ans = 0, P = 0, Q = 0;\n rep(i, M + 1){\n if(i == 0) continue;\n if(mx_P[M / i] == NIL) continue;\n if(Prime[i] == NIL) continue;\n int val = mx_P[min(i, M / i)];\n if(val == NIL) continue;\n //debug(Prime[M / i]);\n //debug(i);\n if(i * A <= val * B){\n if(chmax(ans, i * val)){\n P = val, Q = i;\n }\n }\n }\n cout << P << \" \" << Q << endl;\n }\n}\nint a = 313*313;\nsigned main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout << fixed << setprecision(15);\n Main();\n return 0;\n}", "accuracy": 1, "time_ms": 650, "memory_kb": 4340, "score_of_the_acc": -0.565, "final_rank": 16 }, { "submission_id": "aoj_1232_6783499", "code_snippet": "#line 1 \"a.cpp\"\n/**\n *\tauthor: nok0\n *\tcreated: 2022.07.05 15:37:36\n**/\n#line 1 \"/Users/nok0/Documents/Programming/nok0/cftemp.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\n#pragma region Macros\n// rep macro\n#define foa(v, a) for(auto &v : a)\n#define repname(a, b, c, d, e, ...) e\n#define rep(...) repname(__VA_ARGS__, rep3, rep2, rep1, rep0)(__VA_ARGS__)\n#define rep0(x) for(int i = 0; i < (x); ++i)\n#define rep1(i, x) for(int i = 0; i < (x); ++i)\n#define rep2(i, l, r) for(int i = (l); i < (r); ++i)\n#define rep3(i, l, r, c) for(int i = (l); i < (r); i += (c))\n#define repsname(a, b, c, ...) c\n#define reps(...) repsname(__VA_ARGS__, reps1, reps0)(__VA_ARGS__)\n#define reps0(x) for(int i = 1; i <= (x); ++i)\n#define reps1(i, x) for(int i = 1; i <= (x); ++i)\n#define rrepname(a, b, c, d, e, ...) e\n#define rrep(...) rrepname(__VA_ARGS__, rrep3, rrep2, rrep1, rrep0)(__VA_ARGS__)\n#define rrep0(x) for(int i = (x)-1; i >= 0; --i)\n#define rrep1(i, x) for(int i = (x)-1; i >= 0; --i)\n#define rrep2(i, r, l) for(int i = (r)-1; i >= (l); --i)\n#define rrep3(i, r, l, c) for(int i = (r)-1; i >= (l); i -= (c))\n#define rrepsname(a, b, c, ...) c\n#define rreps(...) rrepsname(__VA_ARGS__, rreps1, rreps0)(__VA_ARGS__)\n#define rreps0(x) for(int i = (x); i >= 1; --i)\n#define rreps1(i, x) for(int i = (x); i >= 1; --i)\n\n// name macro\n#define pb push_back\n#define eb emplace_back\n#define SZ(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define popcnt(x) __builtin_popcountll(x)\ntemplate <class T = int>\nusing V = std::vector<T>;\ntemplate <class T = int>\nusing VV = std::vector<std::vector<T>>;\ntemplate <class T>\nusing pqup = std::priority_queue<T, std::vector<T>, std::greater<T>>;\nusing ll = long long;\nusing ld = long double;\nusing int128 = __int128_t;\nusing pii = std::pair<int, int>;\nusing pll = std::pair<long long, long long>;\n\n// input macro\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n\tis >> p.first >> p.second;\n\treturn is;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n\tfor(T &i : v) is >> i;\n\treturn is;\n}\nstd::istream &operator>>(std::istream &is, __int128_t &a) {\n\tstd::string s;\n\tis >> s;\n\t__int128_t ret = 0;\n\tfor(int i = 0; i < s.length(); i++)\n\t\tif('0' <= s[i] and s[i] <= '9')\n\t\t\tret = 10 * ret + s[i] - '0';\n\ta = ret * (s[0] == '-' ? -1 : 1);\n\treturn is;\n}\nnamespace scanner {\nvoid scan(int &a) { std::cin >> a; }\nvoid scan(long long &a) { std::cin >> a; }\nvoid scan(std::string &a) { std::cin >> a; }\nvoid scan(char &a) { std::cin >> a; }\nvoid scan(char a[]) { std::scanf(\"%s\", a); }\nvoid scan(double &a) { std::cin >> a; }\nvoid scan(long double &a) { std::cin >> a; }\ntemplate <class T, class U>\nvoid scan(std::pair<T, U> &p) { std::cin >> p; }\ntemplate <class T>\nvoid scan(std::vector<T> &a) { std::cin >> a; }\nvoid INPUT() {}\ntemplate <class Head, class... Tail>\nvoid INPUT(Head &head, Tail &...tail) {\n\tscan(head);\n\tINPUT(tail...);\n}\n} // namespace scanner\n#define VEC(type, name, size) \\\n\tstd::vector<type> name(size); \\\n\tscanner::INPUT(name)\n#define VVEC(type, name, h, w) \\\n\tstd::vector<std::vector<type>> name(h, std::vector<type>(w)); \\\n\tscanner::INPUT(name)\n#define INT(...) \\\n\tint __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LL(...) \\\n\tlong long __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define STR(...) \\\n\tstd::string __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define CHAR(...) \\\n\tchar __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define DOUBLE(...) \\\n\tdouble __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n#define LD(...) \\\n\tlong double __VA_ARGS__; \\\n\tscanner::INPUT(__VA_ARGS__)\n\n// output-macro\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n\tos << p.first << \" \" << p.second;\n\treturn os;\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &a) {\n\tfor(int i = 0; i < int(a.size()); ++i) {\n\t\tif(i) os << \" \";\n\t\tos << a[i];\n\t}\n\treturn os;\n}\nstd::ostream &operator<<(std::ostream &dest, __int128_t &value) {\n\tstd::ostream::sentry s(dest);\n\tif(s) {\n\t\t__uint128_t tmp = value < 0 ? -value : value;\n\t\tchar buffer[128];\n\t\tchar *d = std::end(buffer);\n\t\tdo {\n\t\t\t--d;\n\t\t\t*d = \"0123456789\"[tmp % 10];\n\t\t\ttmp /= 10;\n\t\t} while(tmp != 0);\n\t\tif(value < 0) {\n\t\t\t--d;\n\t\t\t*d = '-';\n\t\t}\n\t\tint len = std::end(buffer) - d;\n\t\tif(dest.rdbuf()->sputn(d, len) != len) {\n\t\t\tdest.setstate(std::ios_base::badbit);\n\t\t}\n\t}\n\treturn dest;\n}\ntemplate <class T>\nvoid print(const T a) { std::cout << a << '\\n'; }\ntemplate <class Head, class... Tail>\nvoid print(Head H, Tail... T) {\n\tstd::cout << H << ' ';\n\tprint(T...);\n}\ntemplate <class T>\nvoid printel(const T a) { std::cout << a << '\\n'; }\ntemplate <class T>\nvoid printel(const std::vector<T> &a) {\n\tfor(const auto &v : a)\n\t\tstd::cout << v << '\\n';\n}\ntemplate <class Head, class... Tail>\nvoid printel(Head H, Tail... T) {\n\tstd::cout << H << '\\n';\n\tprintel(T...);\n}\nvoid Yes(const bool b = true) { std::cout << (b ? \"Yes\\n\" : \"No\\n\"); }\nvoid No() { std::cout << \"No\\n\"; }\nvoid YES(const bool b = true) { std::cout << (b ? \"YES\\n\" : \"NO\\n\"); }\nvoid NO() { std::cout << \"NO\\n\"; }\nvoid err(const bool b = true) {\n\tif(b) {\n\t\tstd::cout << \"-1\\n\", exit(0);\n\t}\n}\n\n//debug macro\nnamespace debugger {\ntemplate <class T>\nvoid view(const std::vector<T> &a) {\n\tstd::cerr << \"{ \";\n\tfor(const auto &v : a) {\n\t\tstd::cerr << v << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\ntemplate <class T>\nvoid view(const std::vector<std::vector<T>> &a) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &v : a) {\n\t\tstd::cerr << \"\\t\";\n\t\tview(v);\n\t\tstd::cerr << \"\\n\";\n\t}\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::vector<std::pair<T, U>> &a) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &p : a) std::cerr << \"\\t(\" << p.first << \", \" << p.second << \")\\n\";\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::map<T, U> &m) {\n\tstd::cerr << \"{\\n\";\n\tfor(const auto &p : m) std::cerr << \"\\t[\" << p.first << \"] : \" << p.second << \"\\n\";\n\tstd::cerr << \"}\";\n}\ntemplate <class T, class U>\nvoid view(const std::pair<T, U> &p) { std::cerr << \"(\" << p.first << \", \" << p.second << \")\"; }\ntemplate <class T>\nvoid view(const std::set<T> &s) {\n\tstd::cerr << \"{ \";\n\tfor(auto &v : s) {\n\t\tview(v);\n\t\tstd::cerr << \", \";\n\t}\n\tstd::cerr << \"\\b\\b }\";\n}\n\ntemplate <class T>\nvoid view(const T &e) { std::cerr << e; }\n} // namespace debugger\n#ifdef LOCAL\nvoid debug_out() {}\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head H, Tail... T) {\n\tdebugger::view(H);\n\tstd::cerr << \", \";\n\tdebug_out(T...);\n}\n#define debug(...) \\\n\tdo { \\\n\t\tstd::cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"] : [\"; \\\n\t\tdebug_out(__VA_ARGS__); \\\n\t\tstd::cerr << \"\\b\\b]\\n\"; \\\n\t} while(false)\n#else\n#define debug(...) (void(0))\n#endif\n\n// vector macro\ntemplate <class T>\nint lb(const std::vector<T> &a, const T x) { return std::distance((a).begin(), std::lower_bound((a).begin(), (a).end(), (x))); }\ntemplate <class T>\nint ub(const std::vector<T> &a, const T x) { return std::distance((a).begin(), std::upper_bound((a).begin(), (a).end(), (x))); }\ntemplate <class T>\nvoid UNIQUE(std::vector<T> &a) {\n\tstd::sort(a.begin(), a.end());\n\ta.erase(std::unique(a.begin(), a.end()), a.end());\n}\ntemplate <class T>\nstd::vector<T> press(std::vector<T> &a) {\n\tauto res = a;\n\tUNIQUE(res);\n\tfor(auto &v : a)\n\t\tv = lb(res, v);\n\treturn res;\n}\n#define SORTname(a, b, c, ...) c\n#define SORT(...) SORTname(__VA_ARGS__, SORT1, SORT0, ...)(__VA_ARGS__)\n#define SORT0(a) std::sort((a).begin(), (a).end())\n#define SORT1(a, c) std::sort((a).begin(), (a).end(), [](const auto x, const auto y) { return x c y; })\ntemplate <class T>\nvoid ADD(std::vector<T> &a, const T x = 1) {\n\tfor(auto &v : a) v += x;\n}\ntemplate <class T>\nvoid SUB(std::vector<T> &a, const T x = 1) {\n\tfor(auto &v : a) v -= x;\n}\nstd::vector<std::pair<char, int>> rle(const string &s) {\n\tint n = s.size();\n\tstd::vector<std::pair<char, int>> ret;\n\tfor(int l = 0; l < n;) {\n\t\tint r = l + 1;\n\t\tfor(; r < n and s[l] == s[r]; r++) {}\n\t\tret.emplace_back(s[l], r - l);\n\t\tl = r;\n\t}\n\treturn ret;\n}\ntemplate <class T>\nstd::vector<std::pair<T, int>> rle(const std::vector<T> &v) {\n\tint n = v.size();\n\tstd::vector<std::pair<T, int>> ret;\n\tfor(int l = 0; l < n;) {\n\t\tint r = l + 1;\n\t\tfor(; r < n and v[l] == v[r]; r++) {}\n\t\tret.emplace_back(v[l], r - l);\n\t\tl = r;\n\t}\n\treturn ret;\n}\nstd::vector<int> iota(int n) {\n\tstd::vector<int> p(n);\n\tstd::iota(p.begin(), p.end(), 0);\n\treturn p;\n}\ntemplate <class T>\nstruct cum_vector {\npublic:\n\tcum_vector() = default;\n\ttemplate <class U>\n\tcum_vector(const std::vector<U> &vec) : cum((int)vec.size() + 1) {\n\t\tfor(int i = 0; i < (int)vec.size(); i++)\n\t\t\tcum[i + 1] = cum[i] + vec[i];\n\t}\n\tT prod(int l, int r) {\n\t\treturn cum[r] - cum[l];\n\t}\n\nprivate:\n\tstd::vector<T> cum;\n};\n\n// math macro\ntemplate <class T, class U>\ninline bool chmin(T &a, const U &b) { return a > b ? a = b, true : false; }\ntemplate <class T, class U>\ninline bool chmax(T &a, const U &b) { return a < b ? a = b, true : false; }\ntemplate <class T>\nT divup(T x, T y) { return (x + y - 1) / y; }\ntemplate <class T>\nT POW(T a, long long n) {\n\tT ret = 1;\n\twhile(n) {\n\t\tif(n & 1) ret *= a;\n\t\ta *= a;\n\t\tn >>= 1;\n\t}\n\treturn ret;\n}\n// modpow\nlong long POW(long long a, long long n, const int mod) {\n\tlong long ret = 1;\n\ta = (a % mod + mod) % mod;\n\twhile(n) {\n\t\tif(n & 1) (ret *= a) %= mod;\n\t\t(a *= a) %= mod;\n\t\tn >>= 1;\n\t}\n\treturn ret;\n}\ntemplate <class T, class F>\nT bin_search(T ok, T ng, const F &f) {\n\twhile(abs(ok - ng) > 1) {\n\t\tT mid = (ok + ng) >> 1;\n\t\t(f(mid) ? ok : ng) = mid;\n\t}\n\treturn ok;\n}\ntemplate <class T, class F>\nT bin_search(T ok, T ng, const F &f, int loop) {\n\tfor(int i = 0; i < loop; i++) {\n\t\tT mid = (ok + ng) / 2;\n\t\t(f(mid) ? ok : ng) = mid;\n\t}\n\treturn ok;\n}\n\n// others\nstruct fast_io {\n\tfast_io() {\n\t\tios::sync_with_stdio(false);\n\t\tcin.tie(nullptr);\n\t\tcout << fixed << setprecision(15);\n\t}\n} fast_io_;\nconst int inf = 1e9;\nconst ll INF = 1e18;\n#pragma endregion\n\nvoid main_();\n\nint main() {\n\tmain_();\n\treturn 0;\n}\n#line 2 \"/Users/nok0/Documents/Programming/nok0/math/osa_k.hpp\"\n\nstruct osa_k {\nprivate:\n\tstd::vector<int> spf, pr;\n\npublic:\n\tosa_k() = default;\n\n\tosa_k(int MAX) : spf(MAX + 1) {\n\t\tfor(int i = 2; i <= MAX; i++) {\n\t\t\tif(spf[i] == 0) {\n\t\t\t\tspf[i] = i;\n\t\t\t\tpr.push_back(i);\n\t\t\t}\n\t\t\tfor(int j = 0; j < pr.size() and pr[j] <= spf[i] and i * pr[j] <= MAX; j++)\n\t\t\t\tspf[i * pr[j]] = pr[j];\n\t\t}\n\t}\n\n\tstd::vector<std::pair<int, int>> PF(int n) {\n\t\tstd::vector<std::pair<int, int>> divisor;\n\t\tif(n == 1) return divisor;\n\t\tint before = spf[n], cnt = 0;\n\t\twhile(n > 1) {\n\t\t\tif(spf[n] == before) {\n\t\t\t\tcnt++;\n\t\t\t\tn /= spf[n];\n\t\t\t} else {\n\t\t\t\tdivisor.emplace_back(before, cnt);\n\t\t\t\tbefore = spf[n];\n\t\t\t\tcnt = 1;\n\t\t\t\tn /= spf[n];\n\t\t\t}\n\t\t}\n\t\tdivisor.emplace_back(before, cnt);\n\t\treturn divisor;\n\t}\n\n\tint smallestprimefactor(const int n) const {\n\t\treturn spf[n];\n\t}\n\n\tbool isPrime(const int n) const {\n\t\treturn n == spf[n];\n\t}\n};\n#line 7 \"a.cpp\"\n\nosa_k pf(200000);\nV<> primes;\n\nvoid solve() {\n\tLL(m, a, b);\n\tif(!m) exit(0);\n\tll mx = 0;\n\tint pres = -1, qres = -1;\n\tfor(auto p : primes) {\n\t\tfor(auto q : primes) {\n\t\t\tif(p * q > m) break;\n\t\t\tif(p > q) continue;\n\t\t\tif(a * q > p * b) continue;\n\t\t\tif(chmax(mx, p * q)) {\n\t\t\t\tpres = p, qres = q;\n\t\t\t}\n\t\t}\n\t}\n\tprint(pres, qres);\n}\n\nvoid main_() {\n\treps(i, 50000) {\n\t\tif(pf.isPrime(i)) primes.pb(i);\n\t}\n\twhile(true) {\n\t\tsolve();\n\t}\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4148, "score_of_the_acc": -0.409, "final_rank": 15 }, { "submission_id": "aoj_1232_6761088", "code_snippet": "#include <bits/stdc++.h>\n\n#ifdef _MSC_VER\n# include <intrin.h>\n#else\n# include <x86intrin.h>\n#endif\n\n#include <limits>\n#include <type_traits>\n\nnamespace suisen {\n// ! utility\ntemplate <typename ...Types>\nusing constraints_t = std::enable_if_t<std::conjunction_v<Types...>, std::nullptr_t>;\ntemplate <bool cond_v, typename Then, typename OrElse>\nconstexpr decltype(auto) constexpr_if(Then&& then, OrElse&& or_else) {\n if constexpr (cond_v) {\n return std::forward<Then>(then);\n } else {\n return std::forward<OrElse>(or_else);\n }\n}\n\n// ! function\ntemplate <typename ReturnType, typename Callable, typename ...Args>\nusing is_same_as_invoke_result = std::is_same<std::invoke_result_t<Callable, Args...>, ReturnType>;\ntemplate <typename F, typename T>\nusing is_uni_op = is_same_as_invoke_result<T, F, T>;\ntemplate <typename F, typename T>\nusing is_bin_op = is_same_as_invoke_result<T, F, T, T>;\n\ntemplate <typename Comparator, typename T>\nusing is_comparator = std::is_same<std::invoke_result_t<Comparator, T, T>, bool>;\n\n// ! integral\ntemplate <typename T, typename = constraints_t<std::is_integral<T>>>\nconstexpr int bit_num = std::numeric_limits<std::make_unsigned_t<T>>::digits;\ntemplate <typename T, unsigned int n>\nstruct is_nbit { static constexpr bool value = bit_num<T> == n; };\ntemplate <typename T, unsigned int n>\nstatic constexpr bool is_nbit_v = is_nbit<T, n>::value;\n\n// ?\ntemplate <typename T>\nstruct safely_multipliable {};\ntemplate <>\nstruct safely_multipliable<int> { using type = long long; };\ntemplate <>\nstruct safely_multipliable<long long> { using type = __int128_t; };\ntemplate <>\nstruct safely_multipliable<unsigned int> { using type = unsigned long long; };\ntemplate <>\nstruct safely_multipliable<unsigned long int> { using type = __uint128_t; };\ntemplate <>\nstruct safely_multipliable<unsigned long long> { using type = __uint128_t; };\ntemplate <>\nstruct safely_multipliable<float> { using type = float; };\ntemplate <>\nstruct safely_multipliable<double> { using type = double; };\ntemplate <>\nstruct safely_multipliable<long double> { using type = long double; };\ntemplate <typename T>\nusing safely_multipliable_t = typename safely_multipliable<T>::type;\n\ntemplate <typename T, typename = void>\nstruct rec_value_type {\n using type = T;\n};\ntemplate <typename T>\nstruct rec_value_type<T, std::void_t<typename T::value_type>> {\n using type = typename rec_value_type<typename T::value_type>::type;\n};\ntemplate <typename T>\nusing rec_value_type_t = typename rec_value_type<T>::type;\n\n} // namespace suisen\n\n// ! type aliases\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\n\ntemplate <typename T>\nusing pq_greater = std::priority_queue<T, std::vector<T>, std::greater<T>>;\ntemplate <typename T, typename U>\nusing umap = std::unordered_map<T, U>;\n\n// ! macros (capital: internal macro)\n#define OVERLOAD2(_1,_2,name,...) name\n#define OVERLOAD3(_1,_2,_3,name,...) name\n#define OVERLOAD4(_1,_2,_3,_4,name,...) name\n\n#define REP4(i,l,r,s) for(std::remove_reference_t<std::remove_const_t<decltype(r)>>i=(l);i<(r);i+=(s))\n#define REP3(i,l,r) REP4(i,l,r,1)\n#define REP2(i,n) REP3(i,0,n)\n#define REPINF3(i,l,s) for(std::remove_reference_t<std::remove_const_t<decltype(l)>>i=(l);;i+=(s))\n#define REPINF2(i,l) REPINF3(i,l,1)\n#define REPINF1(i) REPINF2(i,0)\n#define RREP4(i,l,r,s) for(std::remove_reference_t<std::remove_const_t<decltype(r)>>i=(l)+fld((r)-(l)-1,s)*(s);i>=(l);i-=(s))\n#define RREP3(i,l,r) RREP4(i,l,r,1)\n#define RREP2(i,n) RREP3(i,0,n)\n\n#define rep(...) OVERLOAD4(__VA_ARGS__, REP4 , REP3 , REP2 )(__VA_ARGS__)\n#define rrep(...) OVERLOAD4(__VA_ARGS__, RREP4 , RREP3 , RREP2 )(__VA_ARGS__)\n#define repinf(...) OVERLOAD3(__VA_ARGS__, REPINF3, REPINF2, REPINF1)(__VA_ARGS__)\n\n#define CAT_I(a, b) a##b\n#define CAT(a, b) CAT_I(a, b)\n#define UNIQVAR(tag) CAT(tag, __LINE__)\n#define loop(n) for (std::remove_reference_t<std::remove_const_t<decltype(n)>> UNIQVAR(loop_variable) = n; UNIQVAR(loop_variable) --> 0;)\n\n#define all(iterable) std::begin(iterable), std::end(iterable)\n#define input(type, ...) type __VA_ARGS__; read(__VA_ARGS__)\n\n#ifdef LOCAL\n# define debug(...) debug_internal(#__VA_ARGS__, __VA_ARGS__)\n\ntemplate <class T, class... Args>\nvoid debug_internal(const char* s, T&& first, Args&&... args) {\n constexpr const char* prefix = \"[\\033[32mDEBUG\\033[m] \";\n constexpr const char* open_brakets = sizeof...(args) == 0 ? \"\" : \"(\";\n constexpr const char* close_brakets = sizeof...(args) == 0 ? \"\" : \")\";\n std::cerr << prefix << open_brakets << s << close_brakets << \": \" << open_brakets << std::forward<T>(first);\n ((std::cerr << \", \" << std::forward<Args>(args)), ...);\n std::cerr << close_brakets << \"\\n\";\n}\n\n#else\n# define debug(...) void(0)\n#endif\n\n// ! I/O utilities\n\n// __int128_t\nstd::ostream& operator<<(std::ostream& dest, __int128_t value) {\n std::ostream::sentry s(dest);\n if (s) {\n __uint128_t tmp = value < 0 ? -value : value;\n char buffer[128];\n char* d = std::end(buffer);\n do {\n --d;\n *d = \"0123456789\"[tmp % 10];\n tmp /= 10;\n } while (tmp != 0);\n if (value < 0) {\n --d;\n *d = '-';\n }\n int len = std::end(buffer) - d;\n if (dest.rdbuf()->sputn(d, len) != len) {\n dest.setstate(std::ios_base::badbit);\n }\n }\n return dest;\n}\n// __uint128_t\nstd::ostream& operator<<(std::ostream& dest, __uint128_t value) {\n std::ostream::sentry s(dest);\n if (s) {\n char buffer[128];\n char* d = std::end(buffer);\n do {\n --d;\n *d = \"0123456789\"[value % 10];\n value /= 10;\n } while (value != 0);\n int len = std::end(buffer) - d;\n if (dest.rdbuf()->sputn(d, len) != len) {\n dest.setstate(std::ios_base::badbit);\n }\n }\n return dest;\n}\n\n// pair\ntemplate <typename T, typename U>\nstd::ostream& operator<<(std::ostream& out, const std::pair<T, U>& a) {\n return out << a.first << ' ' << a.second;\n}\n// tuple\ntemplate <unsigned int N = 0, typename ...Args>\nstd::ostream& operator<<(std::ostream& out, const std::tuple<Args...>& a) {\n if constexpr (N >= std::tuple_size_v<std::tuple<Args...>>) {\n return out;\n } else {\n out << std::get<N>(a);\n if constexpr (N + 1 < std::tuple_size_v<std::tuple<Args...>>) {\n out << ' ';\n }\n return operator<<<N + 1>(out, a);\n }\n}\n// vector\ntemplate <typename T>\nstd::ostream& operator<<(std::ostream& out, const std::vector<T>& a) {\n for (auto it = a.begin(); it != a.end();) {\n out << *it;\n if (++it != a.end()) out << ' ';\n }\n return out;\n}\n// array\ntemplate <typename T, size_t N>\nstd::ostream& operator<<(std::ostream& out, const std::array<T, N>& a) {\n for (auto it = a.begin(); it != a.end();) {\n out << *it;\n if (++it != a.end()) out << ' ';\n }\n return out;\n}\ninline void print() { std::cout << '\\n'; }\ntemplate <typename Head, typename... Tail>\ninline void print(const Head& head, const Tail &...tails) {\n std::cout << head;\n if (sizeof...(tails)) std::cout << ' ';\n print(tails...);\n}\ntemplate <typename Iterable>\nauto print_all(const Iterable& v, std::string sep = \" \", std::string end = \"\\n\") -> decltype(std::cout << *v.begin(), void()) {\n for (auto it = v.begin(); it != v.end();) {\n std::cout << *it;\n if (++it != v.end()) std::cout << sep;\n }\n std::cout << end;\n}\n\n__int128_t parse_i128(std::string& s) {\n __int128_t ret = 0;\n for (int i = 0; i < int(s.size()); i++) if ('0' <= s[i] and s[i] <= '9') ret = 10 * ret + s[i] - '0';\n if (s[0] == '-') ret = -ret;\n return ret;\n}\n__uint128_t parse_u128(std::string& s) {\n __uint128_t ret = 0;\n for (int i = 0; i < int(s.size()); i++) if ('0' <= s[i] and s[i] <= '9') ret = 10 * ret + s[i] - '0';\n return ret;\n}\n// __int128_t\nstd::istream& operator>>(std::istream& in, __int128_t& v) {\n std::string s;\n in >> s;\n v = parse_i128(s);\n return in;\n}\n// __uint128_t\nstd::istream& operator>>(std::istream& in, __uint128_t& v) {\n std::string s;\n in >> s;\n v = parse_u128(s);\n return in;\n}\n// pair\ntemplate <typename T, typename U>\nstd::istream& operator>>(std::istream& in, std::pair<T, U>& a) {\n return in >> a.first >> a.second;\n}\n// tuple\ntemplate <unsigned int N = 0, typename ...Args>\nstd::istream& operator>>(std::istream& in, std::tuple<Args...>& a) {\n if constexpr (N >= std::tuple_size_v<std::tuple<Args...>>) {\n return in;\n } else {\n return operator>><N + 1>(in >> std::get<N>(a), a);\n }\n}\n// vector\ntemplate <typename T>\nstd::istream& operator>>(std::istream& in, std::vector<T>& a) {\n for (auto it = a.begin(); it != a.end(); ++it) in >> *it;\n return in;\n}\n// array\ntemplate <typename T, size_t N>\nstd::istream& operator>>(std::istream& in, std::array<T, N>& a) {\n for (auto it = a.begin(); it != a.end(); ++it) in >> *it;\n return in;\n}\ntemplate <typename ...Args>\nvoid read(Args &...args) {\n (std::cin >> ... >> args);\n}\n\n// ! integral utilities\n\n// Returns pow(-1, n)\ntemplate <typename T>\nconstexpr inline int pow_m1(T n) {\n return -(n & 1) | 1;\n}\n// Returns pow(-1, n)\ntemplate <>\nconstexpr inline int pow_m1<bool>(bool n) {\n return -int(n) | 1;\n}\n\n// Returns floor(x / y)\ntemplate <typename T>\nconstexpr inline T fld(const T x, const T y) {\n return (x ^ y) >= 0 ? x / y : (x - (y + pow_m1(y >= 0))) / y;\n}\ntemplate <typename T>\nconstexpr inline T cld(const T x, const T y) {\n return (x ^ y) <= 0 ? x / y : (x + (y + pow_m1(y >= 0))) / y;\n}\n\ntemplate <typename T, suisen::constraints_t<suisen::is_nbit<T, 16>> = nullptr>\n__attribute__((target(\"popcnt\"))) constexpr inline int popcount(const T x) { return _mm_popcnt_u32(x); }\ntemplate <typename T, suisen::constraints_t<suisen::is_nbit<T, 32>> = nullptr>\n__attribute__((target(\"popcnt\"))) constexpr inline int popcount(const T x) { return _mm_popcnt_u32(x); }\ntemplate <typename T, suisen::constraints_t<suisen::is_nbit<T, 64>> = nullptr>\n__attribute__((target(\"popcnt\"))) constexpr inline int popcount(const T x) { return _mm_popcnt_u64(x); }\ntemplate <typename T, suisen::constraints_t<suisen::is_nbit<T, 16>> = nullptr>\nconstexpr inline int count_lz(const T x) { return x ? __builtin_clz(x) : suisen::bit_num<T>; }\ntemplate <typename T, suisen::constraints_t<suisen::is_nbit<T, 32>> = nullptr>\nconstexpr inline int count_lz(const T x) { return x ? __builtin_clz(x) : suisen::bit_num<T>; }\ntemplate <typename T, suisen::constraints_t<suisen::is_nbit<T, 64>> = nullptr>\nconstexpr inline int count_lz(const T x) { return x ? __builtin_clzll(x) : suisen::bit_num<T>; }\ntemplate <typename T, suisen::constraints_t<suisen::is_nbit<T, 16>> = nullptr>\nconstexpr inline int count_tz(const T x) { return x ? __builtin_ctz(x) : suisen::bit_num<T>; }\ntemplate <typename T, suisen::constraints_t<suisen::is_nbit<T, 32>> = nullptr>\nconstexpr inline int count_tz(const T x) { return x ? __builtin_ctz(x) : suisen::bit_num<T>; }\ntemplate <typename T, suisen::constraints_t<suisen::is_nbit<T, 64>> = nullptr>\nconstexpr inline int count_tz(const T x) { return x ? __builtin_ctzll(x) : suisen::bit_num<T>; }\ntemplate <typename T>\nconstexpr inline int floor_log2(const T x) { return suisen::bit_num<T> -1 - count_lz(x); }\ntemplate <typename T>\nconstexpr inline int ceil_log2(const T x) { return floor_log2(x) + ((x & -x) != x); }\ntemplate <typename T>\nconstexpr inline int kth_bit(const T x, const unsigned int k) { return (x >> k) & 1; }\ntemplate <typename T>\nconstexpr inline int parity(const T x) { return popcount(x) & 1; }\n\n// ! container\n\ntemplate <typename T, typename Comparator, suisen::constraints_t<suisen::is_comparator<Comparator, T>> = nullptr>\nauto priqueue_comp(const Comparator comparator) {\n return std::priority_queue<T, std::vector<T>, Comparator>(comparator);\n}\n\ntemplate <typename Iterable>\nauto isize(const Iterable& iterable) -> decltype(int(iterable.size())) {\n return iterable.size();\n}\n\ntemplate <typename T, typename Gen, suisen::constraints_t<suisen::is_same_as_invoke_result<T, Gen, int>> = nullptr>\nauto generate_vector(int n, Gen generator) {\n std::vector<T> v(n);\n for (int i = 0; i < n; ++i) v[i] = generator(i);\n return v;\n}\ntemplate <typename T>\nauto generate_range_vector(T l, T r) {\n return generate_vector(r - l, [l](int i) { return l + i; });\n}\ntemplate <typename T>\nauto generate_range_vector(T n) {\n return generate_range_vector(0, n);\n}\n\ntemplate <typename T>\nvoid sort_unique_erase(std::vector<T>& a) {\n std::sort(a.begin(), a.end());\n a.erase(std::unique(a.begin(), a.end()), a.end());\n}\n\ntemplate <typename InputIterator, typename BiConsumer>\nauto foreach_adjacent_values(InputIterator first, InputIterator last, BiConsumer f) -> decltype(f(*first++, *last), void()) {\n if (first != last) for (auto itr = first, itl = itr++; itr != last; itl = itr++) f(*itl, *itr);\n}\ntemplate <typename Container, typename BiConsumer>\nauto foreach_adjacent_values(Container c, BiConsumer f) -> decltype(c.begin(), c.end(), void()) {\n foreach_adjacent_values(c.begin(), c.end(), f);\n}\n\n// ! other utilities\n\n// x <- min(x, y). returns true iff `x` has chenged.\ntemplate <typename T>\ninline bool chmin(T& x, const T& y) {\n if (y >= x) return false;\n x = y;\n return true;\n}\n// x <- max(x, y). returns true iff `x` has chenged.\ntemplate <typename T>\ninline bool chmax(T& x, const T& y) {\n if (y <= x) return false;\n x = y;\n return true;\n}\n\ntemplate <typename T, std::enable_if_t<std::is_integral_v<T>, std::nullptr_t> = nullptr>\nstd::string bin(T val, int bit_num = -1) {\n std::string res;\n if (bit_num >= 0) {\n for (int bit = bit_num; bit-- > 0;) res += '0' + ((val >> bit) & 1);\n } else {\n for (; val; val >>= 1) res += '0' + (val & 1);\n std::reverse(res.begin(), res.end());\n }\n return res;\n}\n\ntemplate <typename T, std::enable_if_t<std::is_integral_v<T>, std::nullptr_t> = nullptr>\nstd::vector<T> digits_low_to_high(T val, T base = 10) {\n std::vector<T> res;\n for (; val; val /= base) res.push_back(val % base);\n if (res.empty()) res.push_back(T{ 0 });\n return res;\n}\ntemplate <typename T, std::enable_if_t<std::is_integral_v<T>, std::nullptr_t> = nullptr>\nstd::vector<T> digits_high_to_low(T val, T base = 10) {\n auto res = digits_low_to_high(val, base);\n std::reverse(res.begin(), res.end());\n return res;\n}\n\ntemplate <typename T>\nstd::string join(const std::vector<T>& v, const std::string& sep, const std::string& end) {\n std::ostringstream ss;\n for (auto it = v.begin(); it != v.end();) {\n ss << *it;\n if (++it != v.end()) ss << sep;\n }\n ss << end;\n return ss.str();\n}\n\nnamespace suisen {}\nusing namespace suisen;\nusing namespace std;\n\nstruct io_setup {\n io_setup(int precision = 20) {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(precision);\n }\n} io_setup_{};\n\n// ! code from here\n\n#include <cassert>\n#include <cmath>\n#include <vector>\n\n#include <cstdint>\n\nnamespace suisen::internal::sieve {\n\nconstexpr std::uint8_t K = 8;\nconstexpr std::uint8_t PROD = 2 * 3 * 5;\nconstexpr std::uint8_t RM[K] = { 1, 7, 11, 13, 17, 19, 23, 29 };\nconstexpr std::uint8_t DR[K] = { 6, 4, 2, 4, 2, 4, 6, 2 };\nconstexpr std::uint8_t DF[K][K] = {\n { 0, 0, 0, 0, 0, 0, 0, 1 }, { 1, 1, 1, 0, 1, 1, 1, 1 },\n { 2, 2, 0, 2, 0, 2, 2, 1 }, { 3, 1, 1, 2, 1, 1, 3, 1 },\n { 3, 3, 1, 2, 1, 3, 3, 1 }, { 4, 2, 2, 2, 2, 2, 4, 1 },\n { 5, 3, 1, 4, 1, 3, 5, 1 }, { 6, 4, 2, 4, 2, 4, 6, 1 },\n};\nconstexpr std::uint8_t DRP[K] = { 48, 32, 16, 32, 16, 32, 48, 16 };\nconstexpr std::uint8_t DFP[K][K] = {\n { 0, 0, 0, 0, 0, 0, 0, 8 }, { 8, 8, 8, 0, 8, 8, 8, 8 },\n { 16, 16, 0, 16, 0, 16, 16, 8 }, { 24, 8, 8, 16, 8, 8, 24, 8 },\n { 24, 24, 8, 16, 8, 24, 24, 8 }, { 32, 16, 16, 16, 16, 16, 32, 8 },\n { 40, 24, 8, 32, 8, 24, 40, 8 }, { 48, 32, 16, 32, 16, 32, 48, 8 },\n};\n\nconstexpr std::uint8_t MASK[K][K] = {\n { 0x01, 0x02, 0x04, 0x08, 0x10, 0x20, 0x40, 0x80 }, { 0x02, 0x20, 0x10, 0x01, 0x80, 0x08, 0x04, 0x40 },\n { 0x04, 0x10, 0x01, 0x40, 0x02, 0x80, 0x08, 0x20 }, { 0x08, 0x01, 0x40, 0x20, 0x04, 0x02, 0x80, 0x10 },\n { 0x10, 0x80, 0x02, 0x04, 0x20, 0x40, 0x01, 0x08 }, { 0x20, 0x08, 0x80, 0x02, 0x40, 0x01, 0x10, 0x04 },\n { 0x40, 0x04, 0x08, 0x80, 0x01, 0x10, 0x20, 0x02 }, { 0x80, 0x40, 0x20, 0x10, 0x08, 0x04, 0x02, 0x01 },\n};\nconstexpr std::uint8_t OFFSET[K][K] = {\n { 0, 1, 2, 3, 4, 5, 6, 7, },\n { 1, 5, 4, 0, 7, 3, 2, 6, },\n { 2, 4, 0, 6, 1, 7, 3, 5, },\n { 3, 0, 6, 5, 2, 1, 7, 4, },\n { 4, 7, 1, 2, 5, 6, 0, 3, },\n { 5, 3, 7, 1, 6, 0, 4, 2, },\n { 6, 2, 3, 7, 0, 4, 5, 1, },\n { 7, 6, 5, 4, 3, 2, 1, 0, },\n};\n\nconstexpr std::uint8_t mask_to_index(const std::uint8_t bits) {\n switch (bits) {\n case 1 << 0: return 0;\n case 1 << 1: return 1;\n case 1 << 2: return 2;\n case 1 << 3: return 3;\n case 1 << 4: return 4;\n case 1 << 5: return 5;\n case 1 << 6: return 6;\n case 1 << 7: return 7;\n default: assert(false);\n }\n}\n} // namespace suisen::internal::sieve\n\nnamespace suisen {\n\ntemplate <unsigned int N>\nclass SimpleSieve {\n private:\n static constexpr unsigned int siz = N / internal::sieve::PROD + 1;\n static std::uint8_t flag[siz];\n public:\n SimpleSieve() {\n using namespace internal::sieve;\n flag[0] |= 1;\n unsigned int k_max = (unsigned int) std::sqrt(N + 2) / PROD;\n for (unsigned int kp = 0; kp <= k_max; ++kp) {\n for (std::uint8_t bits = ~flag[kp]; bits; bits &= bits - 1) {\n const std::uint8_t mp = mask_to_index(bits & -bits), m = RM[mp];\n unsigned int kr = kp * (PROD * kp + 2 * m) + m * m / PROD;\n for (std::uint8_t mq = mp; kr < siz; kr += kp * DR[mq] + DF[mp][mq], ++mq &= 7) {\n flag[kr] |= MASK[mp][mq];\n }\n }\n }\n }\n std::vector<int> prime_list(unsigned int max_val = N) const {\n using namespace internal::sieve;\n std::vector<int> res { 2, 3, 5 };\n res.reserve(max_val / 25);\n for (unsigned int i = 0, offset = 0; i < siz and offset < max_val; ++i, offset += PROD) {\n for (uint8_t f = ~flag[i]; f;) {\n uint8_t g = f & -f;\n res.push_back(offset + RM[mask_to_index(g)]);\n f ^= g;\n }\n }\n while (res.size() and (unsigned int) res.back() > max_val) res.pop_back();\n return res;\n }\n bool is_prime(const unsigned int p) const {\n using namespace internal::sieve;\n switch (p) {\n case 2: case 3: case 5: return true;\n default:\n switch (p % PROD) {\n case RM[0]: return ((flag[p / PROD] >> 0) & 1) == 0;\n case RM[1]: return ((flag[p / PROD] >> 1) & 1) == 0;\n case RM[2]: return ((flag[p / PROD] >> 2) & 1) == 0;\n case RM[3]: return ((flag[p / PROD] >> 3) & 1) == 0;\n case RM[4]: return ((flag[p / PROD] >> 4) & 1) == 0;\n case RM[5]: return ((flag[p / PROD] >> 5) & 1) == 0;\n case RM[6]: return ((flag[p / PROD] >> 6) & 1) == 0;\n case RM[7]: return ((flag[p / PROD] >> 7) & 1) == 0;\n default: return false;\n }\n }\n }\n};\ntemplate <unsigned int N>\nstd::uint8_t SimpleSieve<N>::flag[SimpleSieve<N>::siz];\n\ntemplate <unsigned int N>\nclass Sieve {\n private:\n static constexpr unsigned int base_max = (N + 1) * internal::sieve::K / internal::sieve::PROD;\n static unsigned int pf[base_max + internal::sieve::K];\n\n public:\n Sieve() {\n using namespace internal::sieve;\n pf[0] = 1;\n unsigned int k_max = ((unsigned int) std::sqrt(N + 1) - 1) / PROD;\n for (unsigned int kp = 0; kp <= k_max; ++kp) {\n const int base_i = kp * K, base_act_i = kp * PROD;\n for (int mp = 0; mp < K; ++mp) {\n const int m = RM[mp], i = base_i + mp;\n if (pf[i] == 0) {\n unsigned int act_i = base_act_i + m;\n unsigned int base_k = (kp * (PROD * kp + 2 * m) + m * m / PROD) * K;\n for (std::uint8_t mq = mp; base_k <= base_max; base_k += kp * DRP[mq] + DFP[mp][mq], ++mq &= 7) {\n pf[base_k + OFFSET[mp][mq]] = act_i;\n }\n }\n }\n }\n }\n bool is_prime(const unsigned int p) const {\n using namespace internal::sieve;\n switch (p) {\n case 2: case 3: case 5: return true;\n default:\n switch (p % PROD) {\n case RM[0]: return pf[p / PROD * K + 0] == 0;\n case RM[1]: return pf[p / PROD * K + 1] == 0;\n case RM[2]: return pf[p / PROD * K + 2] == 0;\n case RM[3]: return pf[p / PROD * K + 3] == 0;\n case RM[4]: return pf[p / PROD * K + 4] == 0;\n case RM[5]: return pf[p / PROD * K + 5] == 0;\n case RM[6]: return pf[p / PROD * K + 6] == 0;\n case RM[7]: return pf[p / PROD * K + 7] == 0;\n default: return false;\n }\n }\n }\n int prime_factor(const unsigned int p) const {\n using namespace internal::sieve;\n switch (p % PROD) {\n case 0: case 2: case 4: case 6: case 8:\n case 10: case 12: case 14: case 16: case 18:\n case 20: case 22: case 24: case 26: case 28: return 2;\n case 3: case 9: case 15: case 21: case 27: return 3;\n case 5: case 25: return 5;\n case RM[0]: return pf[p / PROD * K + 0] ? pf[p / PROD * K + 0] : p;\n case RM[1]: return pf[p / PROD * K + 1] ? pf[p / PROD * K + 1] : p;\n case RM[2]: return pf[p / PROD * K + 2] ? pf[p / PROD * K + 2] : p;\n case RM[3]: return pf[p / PROD * K + 3] ? pf[p / PROD * K + 3] : p;\n case RM[4]: return pf[p / PROD * K + 4] ? pf[p / PROD * K + 4] : p;\n case RM[5]: return pf[p / PROD * K + 5] ? pf[p / PROD * K + 5] : p;\n case RM[6]: return pf[p / PROD * K + 6] ? pf[p / PROD * K + 6] : p;\n case RM[7]: return pf[p / PROD * K + 7] ? pf[p / PROD * K + 7] : p;\n default: assert(false);\n }\n }\n /**\n * Returns a vector of `{ prime, index }`.\n */\n std::vector<std::pair<int, int>> factorize(unsigned int n) const {\n assert(0 < n and n <= N);\n std::vector<std::pair<int, int>> prime_powers;\n while (n > 1) {\n int p = prime_factor(n), c = 0;\n do { n /= p, ++c; } while (n % p == 0);\n prime_powers.emplace_back(p, c);\n }\n return prime_powers;\n }\n /**\n * Returns the divisors of `n`.\n * It is NOT guaranteed that the returned vector is sorted.\n */\n std::vector<int> divisors(unsigned int n) const {\n assert(0 < n and n <= N);\n std::vector<int> divs { 1 };\n for (auto [prime, index] : factorize(n)) {\n int sz = divs.size();\n for (int i = 0; i < sz; ++i) {\n int d = divs[i];\n for (int j = 0; j < index; ++j) {\n divs.push_back(d *= prime);\n }\n }\n }\n return divs;\n }\n};\ntemplate <unsigned int N>\nunsigned int Sieve<N>::pf[Sieve<N>::base_max + internal::sieve::K];\n} // namespace suisen\n\nSieve<100000> sieve;\n\nint main() {\n vector<int> primes;\n rep(i, 1, 100000) {\n if (sieve.is_prime(i)) {\n primes.push_back(i);\n }\n }\n while (true) {\n input(int, m, a, b);\n if (m == 0) break;\n\n int ans_p = 0, ans_q = 0;\n for (int q : primes) {\n int pl = cld(a * q, b);\n int pr = min(fld(m, q), q);\n auto it = upper_bound(all(primes), pr);\n if (it != primes.begin()) {\n int p = *--it;\n if (pl <= p and ans_p * ans_q < p * q) {\n ans_p = p, ans_q = q;\n }\n }\n }\n print(ans_p, ans_q);\n\n }\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 3664, "score_of_the_acc": -0.2473, "final_rank": 11 }, { "submission_id": "aoj_1232_6736721", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef long double ld;\n\ntypedef vector<int> vi;\ntypedef vector<ll> vl;\ntypedef vector<vector<int>> vvi;\ntypedef vector<vector<ll>> vvl;\n\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\ntypedef vector<pii> vpii;\ntypedef vector<pll> vpll;\n\n#define FOR(i, a, b) for(ll i=(a); i<(b); ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define NREP(i, n) FOR(i, 1, n+1)\n\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\n\nbool isfin = 0;\nconst ll INF = 1e15;\n\nconst ll nmax = 1e5 + 1000;\nll isprime[nmax];\nll preprime[nmax];\n\nvoid init() {\n REP(i, nmax) {\n if(i <= 1) {continue;}\n \n ll flg = 1;\n for(ll j = 2; j * j <= i; ++j) {\n if(i % j == 0) {flg = 0;}\n }\n \n if(flg) {isprime[i] = 1;}\n }\n \n ll now = -1;\n REP(i, nmax) {\n if(isprime[i]) {\n now = i;\n }\n preprime[i] = now;\n }\n \n return;\n}\n\nvoid calc() {\n ll M, A, B; cin >> M >> A >> B;\n \n if(M == 0) {\n isfin = 1;\n return;\n }\n \n ll P = 2, Q = 2;\n ll mult = P * Q;\n \n REP(q, nmax) {\n if(q <= 1) {continue;}\n if(isprime[q] == 0) {continue;}\n \n ll mn = (A * q + B - 1) / B;\n ll mx = min(q, M / q);\n \n ll p = preprime[mx];\n \n if(p == -1) {continue;} \n if(p < mn) {continue;}\n \n if(chmax(mult, p * q)) {\n P = p, Q = q;\n }\n }\n \n cout << P << \" \" << Q << endl;\n \n return;\n}\n\nint main(void) {\n init();\n while(1) {\n calc();\n if(isfin) {break;}\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 610, "memory_kb": 4932, "score_of_the_acc": -0.7779, "final_rank": 17 }, { "submission_id": "aoj_1232_6736477", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, t) for (int i = (int)(s); i < (int)(t); ++i)\n#define revrep(i, t, s) for (int i = (int)(t)-1; i >= (int)(s); --i)\n#define all(x) begin(x), end(x)\ntemplate <typename T> bool chmax(T& a, const T& b) { return a < b ? (a = b, 1) : 0; }\ntemplate <typename T> bool chmin(T& a, const T& b) { return a > b ? (a = b, 1) : 0; }\n\nstd::vector<bool> prime_table(int n) {\n std::vector<bool> prime(n + 1, true);\n prime[0] = prime[1] = false;\n for (int j = 4; j <= n; j += 2) prime[j] = false;\n for (int i = 3; i * i <= n; i += 2) {\n if (!prime[i]) continue;\n for (int j = i * i; j <= n; j += 2 * i) prime[j] = false;\n }\n return prime;\n}\n\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(15);\n\n auto table = prime_table(1e5);\n vector<ll> primes;\n rep(i,2,1e5) if (table[i]) primes.push_back(i);\n while (true) {\n int m, a, b;\n cin >> m >> a >> b;\n if (m == 0) break;\n tuple<ll, int, int> ans(0, 0, 0);\n rep(i,0,primes.size()) {\n int lb = i-1, ub = primes.size();\n ll p = primes[i];\n while (ub - lb > 1) {\n int j = (lb + ub) / 2;\n ll q = primes[j];\n if (p*q > m || a*q > p*b) ub = j;\n else lb = j;\n }\n if (lb >= i) chmax(ans, {primes[i]*primes[lb], primes[i], primes[lb]});\n }\n auto [_, p, q] = ans;\n cout << p << \" \" << q << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 3460, "score_of_the_acc": -0.1847, "final_rank": 9 } ]
aoj_1230_cpp
Problem G: Nim Let's play a traditional game Nim. You and I are seated across a table and we have a hundred stones on the table (we know the number of stones exactly). We play in turn and at each turn, you or I can remove one to four stones from the heap. You play first and the one who removed the last stone loses. In this game, you have a winning strategy. To see this, you first remove four stones and leave 96 stones. No matter how I play, I will end up with leaving 92-95 stones. Then you will in turn leave 91 stones for me (verify this is always possible). This way, you can always leave 5 k + 1 stones for me and finally I get the last stone, sigh. If we initially had 101 stones, on the other hand, I have a winning strategy and you are doomed to lose. Let's generalize the game a little bit. First, let's make it a team game. Each team has n players and the 2 n players are seated around the table, with each player having opponents at both sides. Turns round the table so the two teams play alternately. Second, let's vary the maximum number ofstones each player can take. That is, each player has his/her own maximum number ofstones he/she can take at each turn (The minimum is always one). So the game is asymmetric and may even be unfair. In general, when played between two teams of experts, the outcome of a game is completely determined by the initial number ofstones and the minimum number of stones each player can take at each turn. In other words, either team has a winning strategy. You are the head-coach of a team. In each game, the umpire shows both teams the initial number of stones and the maximum number of stones each player can take at each turn. Your team plays first. Your job is, given those numbers, to instantaneously judge whether your team has a winning strategy. Incidentally, there is a rumor that Captain Future and her officers of Hakodate-maru love this game, and they are killing their time playing it during their missions. You wonder where the stones are?. Well, they do not have stones but do have plenty of balls in the fuel containers!. Input The input is a sequence of lines, followed by the last line containing a zero. Each line except the last is a sequence of integers and has the following format. n S M 1 M 2 ... M 2 n where n is the number of players in a team, S the initial number of stones, and M i the maximum number of stones i th player can take. 1st, 3rd, 5th, ... players are your team's players and 2nd, 4th, 6th, ... the opponents. Numbers are separated by a single space character. You may assume 1 ≤ n ≤ 10, 1 ≤ M i ≤ 16, and 1 ≤ S ≤ 2 13 . Output The out put should consist of lines each containing either a one, meaning your team has a winning strategy, or a zero otherwise. Sample Input 1 101 4 4 1 100 4 4 3 97 8 7 6 5 4 3 0 Output for the Sample Input 0 1 1
[ { "submission_id": "aoj_1230_9710661", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint n;\nmap <pair <int, int>, int> mp;\n\nbool get_res(vector <int> &v, int id, int s) {\n if(s == 0) return 1;\n if(mp[{id, s}]) return mp[{id, s}];\n\n bool res = 0;\n for(int i = 1; i <= v[id]; i++) {\n if(s - i < 0)\n break;\n res |= !(get_res(v, id % n + 1, s - i));\n }\n mp[{id, s}] = res;\n return res;\n}\n\nint main() {\n while(cin >> n) {\n if(n == 0) break;\n int s; cin >> s;\n mp.clear();\n n *= 2;\n vector <int> v(n + 1);\n for(int i = 1; i <= n; i++)\n cin >> v[i];\n cout << get_res(v, 1, s) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 780, "memory_kb": 10484, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_1230_3953533", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <numeric>\n\n#define REP(i, a, b) for (int i = int(a); i < int(b); i++)\nusing namespace std;\ntypedef long long int ll;\n\n// clang-format off\n#ifdef _DEBUG_\n#define dump(...) do{ cerr << __LINE__ << \":\\t\" << #__VA_ARGS__ << \" = \"; PPPPP(__VA_ARGS__); cerr << endl; } while(false)\ntemplate<typename T> void PPPPP(T t) { cerr << t; }\ntemplate<typename T, typename... S> void PPPPP(T t, S... s) { cerr << t << \", \"; PPPPP(s...); }\n#else\n#define dump(...)\n#endif\ntemplate<typename T> vector<T> make_v(size_t a, T b) { return vector<T>(a, b); }\ntemplate<typename... Ts> auto make_v(size_t a, Ts... ts) { return vector<decltype(make_v(ts...))>(a, make_v(ts...)); }\ntemplate<typename T>\nbool chmin(T &a, T b) { if (a > b) {a = b; return true; } return false;}\ntemplate<typename T>\nbool chmax(T &a, T b) { if (a < b) {a = b; return true; } return false;}\n// clang-format on\n\n#include <functional>\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n;\n while (cin >> n, n) {\n int S;\n cin >> S;\n n *= 2;\n vector<int> a(n);\n REP(i, 0, n) {\n cin >> a[i];\n }\n\n auto memo = make_v(S + 1, n, -1);\n function<int(int, int)> rec = [&](int rest, int turn) {\n if (memo[rest][turn] != -1) return memo[rest][turn];\n if (rest == 0) {\n return 1;\n }\n int ans = 1;\n REP(i, 1, a[turn] + 1) {\n if (rest < i) continue;\n ans *= rec(rest - i, (turn + 1) % n);\n }\n return memo[rest][turn] = (ans == 0);\n };\n cout << rec(S, 0) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4176, "score_of_the_acc": -0.2922, "final_rank": 15 }, { "submission_id": "aoj_1230_2566784", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\nenum Type{\n\tSente,\n\tGote,\n\tUnknown,\n};\n\nint N,stone_num;\nint me[10],enemy[10];\nType memo[2][10][8193];\n\nType recursive(Type turn,int rest_num,int index){\n\n\tif(memo[turn][index][rest_num] != Unknown)return memo[turn][index][rest_num];\n\n\tType result;\n\n\tif(turn == Sente){\n\n\t\tif(rest_num == 1){\n\t\t\treturn memo[turn][index][rest_num] = Gote;\n\t\t}\n\n\t\tresult = Gote;\n\n\t\tfor(int num = 1; num <= me[index] && rest_num-num >= 1; num++){\n\t\t\tif(recursive(Gote,rest_num-num,index) == Sente){\n\t\t\t\tresult = Sente;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t}else{\n\n\t\tif(rest_num == 1){\n\t\t\treturn memo[turn][index][rest_num] = Sente;\n\t\t}\n\n\t\tresult = Sente;\n\n\t\tfor(int num = 1; num <= enemy[index] && rest_num-num >= 1; num++){\n\t\t\tif(recursive(Sente,rest_num-num,(index+1)%N) == Gote){\n\t\t\t\tresult = Gote;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn memo[turn][index][rest_num] = result;\n}\n\n\nvoid func(){\n\tscanf(\"%d\",&stone_num);\n\n\tfor(int i = 0; i < 2; i++){\n\t\tfor(int k = 0; k < N; k++){\n\t\t\tfor(int p = 0; p <= stone_num; p++){\n\t\t\t\tmemo[i][k][p] = Unknown;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tscanf(\"%d %d\",&me[i],&enemy[i]);\n\t}\n\n\tif(recursive(Sente,stone_num,0) == Sente){\n\t\tprintf(\"1\\n\");\n\t}else{\n\t\tprintf(\"0\\n\");\n\t}\n}\n\n\nint main(){\n\n\twhile(true){\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3840, "score_of_the_acc": -0.2409, "final_rank": 12 }, { "submission_id": "aoj_1230_2376144", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint n,a[20],dp[1<<13][20];\n\nint main() {\n while(cin >> n && n) {\n int m;\n cin >> m;\n n*=2;\n for(int i=0; i<n; i++) cin >> a[i];\n for(int i=0; i<n; i++) dp[0][i]=1;\n for(int t=1; t<=m; t++) {\n for(int i=0; i<n; i++) {\n dp[t][i]=0;\n for(int k=1; k<=a[i]; k++) {\n if(t-k>=0) dp[t][i]=max(dp[t][i],dp[t-k][(i+1)%n]^1);\n }\n }\n }\n cout << dp[m][0] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3500, "score_of_the_acc": -0.202, "final_rank": 11 }, { "submission_id": "aoj_1230_2376104", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint n;\nint s;\nint m[20];\n\nbool visited[(1<<14)][20];\nint mem[(1<<14)][20];\n\nint solve(int s,int id){\n if(visited[s][id]){\n return mem[s][id];\n }\n\n visited[s][id]=1;\n \n if( s==0 ){\n return mem[s][id]=id%2;\n }\n\n \n if(id%2==1){\n\n for(int i=1;i<=m[id];i++){\n if( solve( max(s-i,0) , (id+1)%(n+n) ) == 1 ){\n return mem[s][id]=1;\n }\n }\n return mem[s][id]=0;\n \n }else{\n\n for(int i=1;i<=m[id];i++){\n if( solve( max(s-i,0) , (id+1)%(n+n) ) == 0 ){\n return mem[s][id]=0;\n }\n }\n return mem[s][id]=1;\n }\n\n assert(0);\n return mem[s][id]=-1; \n}\n\nint main(){\n while(1){\n cin>>n;\n if(n==0)break;\n memset( visited, false , sizeof(visited));\n cin>>s;\n for(int i=0;i<n+n;i++)cin>>m[i];\n cout<<1-solve(s,0)<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4108, "score_of_the_acc": -0.2715, "final_rank": 14 }, { "submission_id": "aoj_1230_2376102", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define int long long\nint n, S, M[22];\nint dp[1<<15][22];\nsigned main(){\n while(cin >> n, n) {\n cin >> S;\n for(int i = 0; i < 2*n; i++) cin >> M[i];\n memset(dp, -1, sizeof(dp));\n for(int i = 0; i < 2*n; i++) dp[1][i] = 0;\n for(int i = 2; i <= S; i++){\n for(int j = 0; j < 2*n; j++) {\n\tbool flag = false;\t\n\tfor(int k = 1; k <= min(i, M[j]); k++) {\n\t if(!dp[i-k][(j+1)%(2*n)]) flag = true;\n\t}\n\tdp[i][j] = (int)flag;\n }\n }\n cout << dp[S][0] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 8716, "score_of_the_acc": -0.798, "final_rank": 19 }, { "submission_id": "aoj_1230_2192583", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define repl(i,a,b) for(int i=(int)(a);i<(int)(b);i++)\n#define rep(i,n) repl(i,0,n)\n#define mp(a,b) make_pair((a),(b))\n#define pb(a) push_back((a))\n#define all(x) (x).begin(),(x).end()\n#define uniq(x) sort(all(x)),(x).erase(unique(all(x)),end(x))\n#define fi first\n#define se second\n#define dbg(x) cout<<#x\" = \"<<((x))<<endl\ntemplate<class T,class U> ostream& operator<<(ostream& o, const pair<T,U> &p){o<<\"(\"<<p.fi<<\",\"<<p.se<<\")\";return o;}\ntemplate<class T> ostream& operator<<(ostream& o, const vector<T> &v){o<<\"[\";for(T t:v){o<<t<<\",\";}o<<\"]\";return o;}\n\n#define INF 2147483600\n\nbool memo[2<<14][35];\nbool visited[2<<14][35];\nvector<int> m;\n\nbool dfs(int s, int t){\n if(visited[s][t]) return memo[s][t];\n visited[s][t]=true;\n if(s==0) return memo[s][t]=true;\n if(s==1) return memo[s][t]=false;\n int nt = (t+1)%m.size();\n repl(i,1,m[t]+1){\n if(dfs(s-i,nt)==false) return memo[s][t]=true;\n }\n return memo[s][t]=false;\n}\n\nint main(){\n int n;\n while(cin>>n, n){\n int s;\n cin>>s;\n m.resize(2*n);\n rep(i,2*n) cin>>m[i];\n\n fill(visited[0], visited[2<<14], false);\n if(dfs(s,0)) cout<<1<<endl;\n else cout<<0<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4840, "score_of_the_acc": -0.3551, "final_rank": 18 }, { "submission_id": "aoj_1230_2095072", "code_snippet": "#include<iostream>\nusing namespace std;\nint s, n, a[25], dp[10000][25];\nint solve(int r, int s) {\n\tif (r == 0) { dp[r][s] = 0; return 0; }\n\tif (dp[r][s] >= 0)return dp[r][s];\n\tint flag = 0;\n\tfor (int i = 1; i <= a[s]; i++) {\n\t\tif (r - i < 0)continue;\n\t\tif (solve(r - i, (s + 1) % n) == false)flag = 1;\n\t}\n\tdp[r][s] = flag;\n\treturn flag;\n}\nint main() {\n\twhile (true) {\n\t\tfor (int i = 0; i < 10000; i++) { for (int j = 0; j < 25; j++)dp[i][j] = -1; }\n\t\tcin >> n; if (n == 0)break; cin >> s; s--; n *= 2; for (int i = 0; i < n; i++)cin >> a[i];\n\t\tcout << solve(s, 0) << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4408, "score_of_the_acc": -0.3058, "final_rank": 16 }, { "submission_id": "aoj_1230_2086343", "code_snippet": "#include <vector>\n#include <iostream>\nusing namespace std;\nint n, s; vector<int> a; vector<vector<bool> > vis, dp;\nbool solve(int x, int t) {\n\tif (vis[x][t]) return dp[x][t];\n\tbool ret = false;\n\tfor (int i = 1; i <= a[t] && x - i > 0; i++) {\n\t\tif (!solve(x - i, (t + 1) % (2 * n))) ret = true;\n\t}\n\tvis[x][t] = true;\n\treturn dp[x][t] = ret;\n}\nint main() {\n\twhile (cin >> n, n) {\n\t\tcin >> s; a.resize(2 * n);\n\t\tfor (int i = 0; i < 2 * n; i++) cin >> a[i];\n\t\tvis = vector<vector<bool> >(s + 1, vector<bool>(2 * n, false));\n\t\tdp = vector<vector<bool> >(s + 1, vector<bool>(2 * n));\n\t\tcout << solve(s, 0) << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4420, "score_of_the_acc": -0.3201, "final_rank": 17 }, { "submission_id": "aoj_1230_1967858", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstdlib>\n#include <string>\n#include <vector>\n#include <deque>\n#include <list>\n#include <algorithm>\n#include <numeric>\n#include <functional>\n#include <cmath>\n#include <cstring>\n#include <cctype>\n#include <sstream>\n#include <set>\n#include <map>\n#include <stack>\n#include <queue>\n#include <complex>\nusing namespace std;\n#define REP(i,n) for(int i = 0; i < (int)n; i++)\n#define FOR(i,a,b) for(int i = a; i < (int)b; i++)\n#define pb push_back\n#define mp make_pair\ntypedef vector<int> vi;\ntypedef pair<int, int> pi;\ntypedef long long ll;\nconst int INF = 1<<28;\nconst ll MOD = 1000000007;\nconst int dx[] = {1, 0, -1, 0}, dy[] = {0, 1, 0, -1};\n\nint n, m[20], dp[20][1<<13 + 1];\n\nint dfs(int idx, int rem){\n\tint &res = dp[idx][rem];\n\tif(res != -1) return res;\n\tif(rem == 1) return res = 0;\n \n\tFOR(i, 1, m[idx]+1) {\n\t\tif(rem - i < 1)\n\t\t\tbreak;\n\t\tif(!dfs((idx + 1) % n, rem - i))\n\t\t\treturn res = 1;\n\t}\n\treturn res = 0;\n}\n \nint main() {\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0);\n\n\twhile(cin >> n, n) {\n\t\tn += n;\n\t\tint s; cin >> s;\n\t\tREP(i, n)\n\t\t\tcin >> m[i];\n\t\tmemset(dp, -1, sizeof(dp));\n\t\tcout << dfs(0, s) << endl;\n\t\t/*\n\t\tREP(i, n*2) {\n\t\t\tREP(j, s)\n\t\t\t\tcout << dp[i][j] << ' ';\n\t\t\tcout << endl;\n\t\t}\n\t\t*/\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 2736, "score_of_the_acc": -0.1277, "final_rank": 8 }, { "submission_id": "aoj_1230_1882002", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n \n#define MAX_N 10\n#define MAX_S (1<<13)\n \nint N,M[2*MAX_N];\nint memo[2*MAX_N][MAX_S+1];\n \nint solve(int p,int rem){\n if(rem == 0) return memo[p][rem] = 1;\n if(memo[p][rem] >= 0) return memo[p][rem];\n for(int i = 1 ; i <= M[p] ; i++){\n\tif(rem-i < 0) continue;\n\tif(solve((p+1)%N,rem-i) == 0){\n\t return memo[p][rem] = 1;\n\t}\n }\n return memo[p][rem] = 0;\n}\n \nint main(){\n int S;\n while(cin >> N,N){\n\tcin >> S;\n\tN *= 2;\n\tfor(int i = 0 ; i < N ; i++){\n\t cin >> M[i];\n\t}\n\tmemset(memo,-1,sizeof(memo));\n\tcout << solve(0,S) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3872, "score_of_the_acc": -0.2445, "final_rank": 13 }, { "submission_id": "aoj_1230_1459716", "code_snippet": "//Nim\n\n#define _CRT_SECURE_NO_WARNINGS\n#include<cstdio>\n#include<cstring>\n#define clr(a,v) memset((a),(v),sizeof(a))\nconst int MAX_N = 10, MAX_S = 1 << 13;\n\nint n, S, M[2 * MAX_N];\nint dp[2 * MAX_N][MAX_S + 1];\n\nbool rec(int i, int j){\n\tif (j <= 1)return false;\n\tint &ret = dp[i][j];\n\tif (ret != -1)return ret;\n\tfor (int k = 1; k <= M[i]; ++k){\n\t\tif (j - k >= 1){\n\t\t\tif (!rec((i + 1) % (n << 1), j - k))return ret = true;\n\t\t}\n\t}\n\treturn ret = false;\n}\n\nint main(){\n\twhile (scanf(\"%d\", &n), n){\n\t\tscanf(\"%d\", &S);\n\t\tfor (int i = 0; i < (n << 1); ++i){\n\t\t\tscanf(\"%d\", M + i);\n\t\t}\n\t\tclr(dp, -1);\n\t\tprintf(\"%d\\n\", rec(0, S));\n\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1928, "score_of_the_acc": -0.0224, "final_rank": 3 }, { "submission_id": "aoj_1230_1458850", "code_snippet": "// AOJ 1230 (http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=1230)\n#include<cstdio>\n#include<cstring>\n#define rep(i,a) for(int i=0;i<(a);++i)\n#define clr(a,v) memset((a),(v),sizeof(a))\n\nconst int MAX_N = 10, MAX_S = 1<<13;\n\nint n, S, M[2*MAX_N];\nint dp[2*MAX_N][MAX_S+1];\n\nbool rec( int i, int j )\n{\n\tif( j <= 1 )\n\t\treturn false;\n\n\tint &ret = dp[i][j];\n\n\tif( ~ret )\n\t\treturn ret;\n\n\trep( k, M[i] ) if( j-k-1 >= 1 ) if( !rec( (i+1)%(n<<1), j-k-1 ) )\n\t\treturn ret = true;\n\n\treturn ret = false;\n}\n\nint main()\n{\n\twhile( scanf( \"%d\", &n ), n )\n\t{\n\t\tscanf( \"%d\", &S );\n\t\trep( i, n<<1 )\n\t\t\tscanf( \"%d\", M+i );\n\n\t\tclr( dp, -1 );\n\t\tprintf( \"%d\\n\", rec( 0, S ) );\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1912, "score_of_the_acc": -0.0336, "final_rank": 4 }, { "submission_id": "aoj_1230_1342875", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define MAX_N 10\n#define MAX_S (1<<13)\n\nint N,M[2*MAX_N];\nint memo[2*MAX_N][MAX_S+1];\n\nint solve(int p,int rem){\n if(rem == 0){ return memo[p][rem] = 1; }\n if(memo[p][rem] >= 0){ return memo[p][rem]; }\n for(int i = 1 ; i <= M[p] ; i++){\n if(rem-i < 0){ continue; }\n if(solve((p+1)%N,rem-i) == 0){\n return memo[p][rem] = 1;\n }\n }\n return memo[p][rem] = 0;\n}\n\nint main(){\n int S;\n while(cin >> N,N){\n cin >> S;\n N *= 2;\n for(int i = 0 ; i < N ; i++){\n cin >> M[i];\n }\n memset(memo,-1,sizeof(memo));\n cout << solve(0,S) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 2060, "score_of_the_acc": -0.0505, "final_rank": 6 }, { "submission_id": "aoj_1230_1144595", "code_snippet": "#include <stdio.h>\n#include <cctype>\n#include <limits.h>\n#include <math.h>\n#include <complex>\n#include <bitset>\n#include <vector>\n#include <map>\n#include <set>\n#include <stack>\n#include <queue>\n#include <cstring>\n#include <string>\n#include <sstream>\n#include <algorithm>\n#include <iomanip>\n#include <iostream>\n\n#define VARIABLE(x) cerr << #x << \"=\" << x << endl\n#define BINARY(x) static_cast<bitset<16> >(x)\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define REP(i,m,n) for (int i=m;i<(int)(n);i++)\n#define if_range(x, y, w, h) if (0<=(int)(x) && (int)(x)<(int)(w) && 0<=(int)(y) && (int)(y)<(int)(h))\n\nconst int INF = 1e9;\nconst double EPS = 1e-8;\nconst double PI = 3.14159;\nint dx[4]={0, 1, 0, -1}, dy[4]={-1, 0, 1, 0};\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> P;\n\n/* struct P {\n\tint x, y, n;\n\tP(int n, int x, int y):n(n), x(x), y(y){}\n\tP(){}\n}; */\n\n\n/** Problem1230 : Nim **/\nvector<int> lim;\nint N;\nconst int MAX_N = 20, MAX_S = 1<<13;\nint dp[MAX_S][MAX_N];\n\n\nbool isWinning(int n, int p)\n{\n\tif (n==1) return false;\n\tif (dp[n][p]!=-1) return dp[n][p];\n\t\n\tbool res = false;\n\tfor (int i=1; i<=lim[p]; i++) {\n\t\tif (n-i>=0)\n\t\t\tres |= !isWinning(n-i, (p+1)%(2*N));\n\t}\n\t\n\t//cerr << n << \" \" << p << \" \" << res << endl;\n\t\n\treturn dp[n][p]=res;\n}\n\nint main()\n{\n\tint S;\n\twhile (cin>>N, N) {\n\t\tcin>>S;\n\t\tmemset(dp, -1, sizeof(dp));\n\t\tlim.resize(2*N);\n\t\trep(i, 2*N) cin>>lim[i];\n\t\t\n\t\tcout << isWinning(S, 0) << endl;\n\t}\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 2284, "score_of_the_acc": -0.089, "final_rank": 7 }, { "submission_id": "aoj_1230_1131521", "code_snippet": "#include<stdio.h>\n#include<algorithm>\nusing namespace std;\nint c[30];\nint n;\nint dp[11000][21];\nint solve(int a,int b){\n\tif(a<=0)return 1;\n\tif(~dp[a][b])return dp[a][b];\n\tfor(int i=1;i<=c[b];i++){\n\t\tif(!solve(a-i,(b+1)%(n*2)))return dp[a][b]=1;\n\t}\n\treturn dp[a][b]=0;\n}\nint main(){\n\tint a;\n\tint b;\n\twhile(scanf(\"%d\",&a),a){\n\t\tn=a;\n\t\tscanf(\"%d\",&b);\n\t\tfor(int i=0;i<a*2;i++)scanf(\"%d\",c+i);\n\t\tfor(int i=0;i<=b;i++)for(int j=0;j<a*2;j++)dp[i][j]=-1;\n\t\tprintf(\"%d\\n\",solve(b,0));\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1732, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1230_1079658", "code_snippet": "#include <iostream>\n#include <vector>\n\nusing namespace std;\n\n#define rep(i, n) for(int i=0; i<(n); ++i)\n\nint solve(int n, int S, vector<int>& M){\n vector<vector<int> > dp(S+1, vector<int>(2*n));\n for(int i=2; i<=S; ++i)for(int j=0; j<(int)M.size(); ++j){\n for(int k=1; k<=M[j] && k<=i; ++k){\n if(!dp[i-k][(j+1)%(int)M.size()]){\n dp[i][j] = 1;\n break;\n }\n }\n }\n return dp[S][0];\n}\n\nint main(){\n int n;\n while(cin >> n, n){\n int S;\n cin >> S;\n vector<int> M(2*n);\n rep(i, 2*n)cin >> M[i];\n cout << solve(n, S, M) << '\\n';\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1800, "score_of_the_acc": -0.0078, "final_rank": 2 }, { "submission_id": "aoj_1230_972623", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nlong long int GR[8200][21];\n\nint main() {\n\n for ( long long int i = 0; i < 21; i++ ) {\n GR[1][i] = 0;\n }\n\n long long int n, S, input;\n\n while( true ) {\n\n cin >> n;\n\n if ( n == 0 ) break;\n\n cin >> S;\n\n vector< long long int > m;\n\n for ( long long int i = 0; i < n * 2; i++ ) {\n\n cin >> input;\n\n m.push_back( input );\n\n }\n\n for ( long long int i = 2; i <= S; i++ ) {\n\n for ( long long int j = 0; j < n * 2; j++ ) {\n\n\tbool flag[17] = {};\n\n\tfor ( long long int k = max( 1LL, i - m[j] ); k < i; k++ ) {\n\n\t flag[ GR[k][(j+1)%(n*2)] ] = true;\n\n\t}\n\n\tint cnt = 0;\n\twhile( flag[cnt] ) {cnt++;}\n\tGR[i][j] = cnt;\n\n }\n\n }\n\n cout << ( GR[S][0] == 0 ? \"0\" : \"1\" ) << endl;\n\n }\n\n return 0;\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2112, "score_of_the_acc": -0.0434, "final_rank": 5 }, { "submission_id": "aoj_1230_921105", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n\n#include <iostream>\n#include <cstdio>\n#include <sstream>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <queue>\n#include <stack>\n#include <limits>\n#include <map>\n#include <string>\n#include <cstring>\n#include <set>\n#include <deque>\n#include <bitset>\n#include <list>\n#include <cctype>\n#include <utility>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair <int,int> P;\ntypedef pair <int,P> PP;\n \nstatic const double EPS = 1e-8;\n\nint dp[1<<14][21];\n\nint dfs(int total_players,int upto[21],\n\tint current_stones,int player_idx){\n if(dp[current_stones][player_idx] != -1){\n return dp[current_stones][player_idx];\n }\n if(current_stones == 0){\n return 1;\n }\n\n int res = 0;\n\n for(int use = 1; \n use <= upto[player_idx] \n\t&& current_stones - use >= 0; \n use++){\n if(dfs(total_players,upto,\n\t current_stones - use,\n\t (player_idx + 1) % total_players) == 0){\n res = 1;\n break;\n }\n }\n return (dp[current_stones][player_idx] = res);\n}\n\nint main(){\n int total_players;\n while(~scanf(\"%d\",&total_players)){\n if(total_players == 0) break;\n\n int initial_stones;\n scanf(\"%d\",&initial_stones);\n\n int upto[21];\n memset(upto,0,sizeof(upto));\n for(int player_idx=0;player_idx < total_players * 2;player_idx++){\n scanf(\"%d\",upto + player_idx);\n }\n\n memset(dp,-1,sizeof(dp));\n printf(\"%d\\n\",dfs(total_players * 2,upto,initial_stones,0));\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2968, "score_of_the_acc": -0.1412, "final_rank": 9 }, { "submission_id": "aoj_1230_921104", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n\n#include <iostream>\n#include <cstdio>\n#include <sstream>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <queue>\n#include <stack>\n#include <limits>\n#include <map>\n#include <string>\n#include <cstring>\n#include <set>\n#include <deque>\n#include <bitset>\n#include <list>\n#include <cctype>\n#include <utility>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair <int,int> P;\ntypedef pair <int,P> PP;\n \nstatic const double EPS = 1e-8;\n\nint dp[1<<14][21];\n\nint dfs(int total_players,int upto[21],\n\tint current_stones,int player_idx){\n if(dp[current_stones][player_idx] != -1){\n return dp[current_stones][player_idx];\n }\n if(current_stones == 0){\n return 1;\n }\n\n int res = 0;\n\n for(int use = 1; \n use <= upto[player_idx] \n\t&& current_stones - use >= 0; \n use++){\n if(dfs(total_players,upto,\n\t current_stones - use,\n\t (player_idx + 1) % total_players) == 0){\n res = 1;\n }\n }\n return (dp[current_stones][player_idx] = res);\n}\n\nint main(){\n int total_players;\n while(~scanf(\"%d\",&total_players)){\n if(total_players == 0) break;\n\n int initial_stones;\n scanf(\"%d\",&initial_stones);\n\n int upto[21];\n memset(upto,0,sizeof(upto));\n for(int player_idx=0;player_idx < total_players * 2;player_idx++){\n scanf(\"%d\",upto + player_idx);\n }\n\n memset(dp,-1,sizeof(dp));\n printf(\"%d\\n\",dfs(total_players * 2,upto,initial_stones,0));\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 2968, "score_of_the_acc": -0.1542, "final_rank": 10 } ]
aoj_1237_cpp
Problem F: Shredding Company You have just been put in charge of developing a new shredder for the Shredding Company. Although a ``normal'' shredder would just shred sheets of paper into little pieces so that the contents would become unreadable, this new shredder needs to have the following unusual basic characteristics. The shredder takes as input a target number and a sheet of paper with a number written on it. It shreds (or cuts) the sheet into pieces each of which has one or more digits on it. The sum of the numbers written on each piece is the closest possible number to the target number, without going over it. For example, suppose that the target number is 50 , and the sheet of paper has the number 12346 . The shredder would cut the sheet into four pieces, where one piece has 1 , another has 2 , the third has 34 , and the fourth has 6 . This is because their sum 43 (= 1 + 2 + 34 + 6) is closest to the target number 50 of all possible combinations without going over 50. For example, a combination where the pieces are 1 , 23 , 4 , and 6 is not valid, because the sum of this combination 34 (= 1 + 23 + 4 + 6) is less than the above combination's 43. The combination of 12 , 34 , and 6 is not valid either, because the sum 52 (= 12+34+6) is greater than the target number of 50. Figure 1. Shredding a sheet of paper having the number 12346 when the target number is 50 There are also three special rules: If the target number is the same as the number on the sheet of paper, then the paper is not cut. For example, if the target number is 100 and the number on the sheet of paper is also 100 , then the paper is not cut. If it is not possible to make any combination whose sum is less than or equal to the target number, then error is printed on a display. For example, if the target number is 1 and the number on the sheet of paper is 123 , it is not possible to make any valid combination, as the combination with the smallest possible sum is 1 , 2 , 3 . The sum for this combination is 6, which is greater than the target number, and thus error is printed. If there is more than one possible combination where the sum is closest to the target number without going over it, then rejected is printed on a display. For example, if the target number is 15 , and the number on the sheet of paper is 111 , then there are two possible combinations with the highest possible sum of 12: (a) 1 and 11 and (b) 11 and 1 ; thus rejected is printed. In order to develop such a shredder, you have decided to first make a simple program that would simulate the above characteristics and rules. Given two numbers, where the first is the target number and the second is the number on the sheet of paper to be shredded, you need to figure out how the shredder should ``cut up'' the second number. Input The input consists of several test cases, each on one line, as follows: t 1 num 1 t 2 num 2 ... t n num n 0 0 Each test case consists of the following two positive integers, which are separated ...(truncated)
[ { "submission_id": "aoj_1237_3989783", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n//repetition\n#define FOR(i,a,b) for(ll i=(a);i<(b);++i)\n#define rep(i, n) for(ll i = 0; i < (ll)(n); i++)\n\n//container util\n#define all(x) (x).begin(),(x).end()\n\n//typedef\ntypedef long long ll;\ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<ll> VLL;\ntypedef vector<VLL> VVLL;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<ll, ll> PLL;\n\n//const value\n//const ll MOD = 1e9 + 7;\n//const int dx[] = {0,1,0,-1};//{0,0,1,1,1,-1,-1,-1};\n//const int dy[] = {1,0,-1,0};//{1,-1,0,1,-1,0,1,-1};\n\n//conversion\ninline int toInt(string s) {int v; istringstream sin(s);sin>>v;return v;}\ninline ll toLL(string s) {ll v; istringstream sin(s);sin>>v;return v;}\ntemplate<class T> inline string toString(T x) {ostringstream sout;sout<<x;return sout.str();}\nll t;\nstring num;\nll ans;\nint dp[1010101];\nvoid dfs(int current,int amari, int cnt){\n if(current == num.size() && cnt == 0){\n dp[amari]++;\n return;\n }\n\n // 区切る場合\n int mm = cnt*10 + (num[current]-'0');\n if(amari - mm >= 0) dfs(current+1, amari-mm, 0);\n else return;\n\n // 区切らない場合\n if(current+1 < num.size()) dfs(current+1, amari, mm);\n\n}\n\nVI ansDFS(int current, int amari, int cnt, VI v){\n VI notAns;\n if(current == num.size()){\n if(ans == amari && cnt == -1) {\n return v;\n }\n else return notAns;\n }\n cnt = max(0,cnt);\n VI ansV0;\n VI ansV1;\n\n int mm = cnt*10 + (num[current]-'0');\n if(amari - mm < 0) return notAns;\n\n // 区切らない場合\n if(not(current > 0 && num[current] == '0' && num[current-1] == '0')) ansV0 = ansDFS(current+1, amari, mm, v);\n\n // 区切る場合\n v.push_back(mm);\n // cout << mm << endl;\n ansV1 = ansDFS(current+1, amari-mm, -1,v);\n\n if(ansV0.size() > 0) return ansV0;\n else return ansV1;\n}\n\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(0);\n\n while(true){\n cin >> t >> num;\n if(t == 0 && num == \"0\") break;\n\n\n rep(j,1010101) dp[j] = 0;\n dfs(0,t,0);\n bool flag = false;\n\n rep(i,t+1){\n if(dp[i] == 1){\n ans = i;\n\n VI v;\n VI ansV = ansDFS(0, t ,0, v);\n ans = t - ans;\n cout << ans << \" \";\n // cout << \"Vsize is \" << ansV.size() << endl;\n rep(j,ansV.size()){\n if(ansV.size() == j+1) cout << ansV[j] << endl;\n else cout << ansV[j] << \" \";\n }\n\n flag = true;\n break;\n }else if(dp[i] > 1){\n cout << \"rejected\" << endl;\n flag = true;\n break;\n }\n }\n if(flag == false){\n cout << \"error\" << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7072, "score_of_the_acc": -0.1297, "final_rank": 4 }, { "submission_id": "aoj_1237_2960830", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n\nint main(){\n int t;\n string num;\n while(cin>>t>>num,t!=0 || num!=\"0\"){\n vector<vector<int>> dp(num.size()+1,vector<int>(t+1,0));\n dp[0][0]=1;\n for(int i=0;i<num.size();i++){\n for(int j=0;j<=t;j++){\n for(int k=i+1;k<=num.size();k++){\n //cut num[i,k)\n int cutnum=stoi(num.substr(i,k-i));\n if(cutnum+j<=t) dp[k][j+cutnum]+=dp[i][j];\n }\n }\n }\n for(int i=t;i>=-1;i--){\n if(i==-1){\n cout<<\"error\"<<endl;\n break;\n }\n if(dp[num.size()][i]){\n if(dp[num.size()][i]>=2){\n cout<<\"rejected\"<<endl;\n }\n else{\n vector<string> res;\n int pos=num.size();\n int val=i;\n while(pos>0){\n for(int j=0;j<pos;j++){\n //cut num[j,pos)\n int v=stoi(num.substr(j,pos-j));\n if(val-v>=0 && dp[j][val-v]==1){\n res.push_back(num.substr(j,pos-j));\n pos=j;\n val-=v;\n break;\n }\n }\n }\n cout<<i<<\" \";\n reverse(res.begin(),res.end());\n for(int j=0;j<res.size();j++){\n cout<<res[j] <<(j+1==res.size() ? \"\\n\" : \" \");\n }\n }\n break; \n }\n }\n \n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 1490, "memory_kb": 29188, "score_of_the_acc": -1.5882, "final_rank": 10 }, { "submission_id": "aoj_1237_2404713", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll, ll> P;\n\n#define each(i,a) for (auto&& i : a)\n#define FOR(i,a,b) for (ll i=(a),__last_##i=(b);i<__last_##i;i++)\n#define RFOR(i,a,b) for (ll i=(b)-1,__last_##i=(a);i>=__last_##i;i--)\n#define REP(i,n) FOR(i,0,n)\n#define RREP(i,n) RFOR(i,0,n)\n#define __GET_MACRO3(_1, _2, _3, NAME, ...) NAME\n#define rep(...) __GET_MACRO3(__VA_ARGS__, FOR, REP)(__VA_ARGS__)\n#define rrep(...) __GET_MACRO3(__VA_ARGS__, RFOR, RREP)(__VA_ARGS__)\n#define pb push_back\n#define all(a) (a).begin(),(a).end()\n#define chmin(x,v) x = min(x, v)\n#define chmax(x,v) x = max(x, v)\n\nconst ll linf = 1e18;\nconst int inf = 1e9;\nconst double eps = 1e-12;\nconst double pi = acos(-1);\n\ntemplate<typename T>\nistream& operator>>(istream& is, vector<T>& vec) {\n each(x,vec) is >> x;\n return is;\n}\ntemplate<typename T>\nostream& operator<<(ostream& os, const vector<T>& vec) {\n rep(i,vec.size()) {\n if (i) os << \" \";\n os << vec[i];\n }\n return os;\n}\ntemplate<typename T>\nostream& operator<<(ostream& os, const vector< vector<T> >& vec) {\n rep(i,vec.size()) {\n if (i) os << endl;\n os << vec[i];\n }\n return os;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n ll n; string s;\n while (cin >> n >> s, n || s != \"0\") {\n ll m = linf;\n vector<ll> ans;\n bool rejected = false;\n try {\n set<vector<ll>> used;\n rep(a, 7) rep(b, 7) rep(c, 7) rep(d, 7) rep(e, 7) rep(f, 7) {\n if (a + b + c + d + e + f != s.size()) continue;\n vector<ll> v;\n if (a) v.pb(a);\n if (b) v.pb(b);\n if (c) v.pb(c);\n if (d) v.pb(d);\n if (e) v.pb(e);\n if (f) v.pb(f);\n if (used.count(v) > 0) continue;\n used.insert(v);\n ll cnt = 0;\n vector<ll> vals;\n bool flag = true;\n rep(i, v.size()) {\n string str = s.substr(cnt, v[i]);\n if (str.size() > 1 && str[0] == '0') {\n // flag = false;\n // break;\n }\n vals.pb(stoll(str));\n cnt += v[i];\n }\n if (!flag) continue;\n ll sum = 0;\n rep(i, vals.size()) sum += vals[i];\n if (sum > n) continue;\n if (n - sum == m) {\n rejected = true;\n }\n else if (n - sum < m) {\n rejected = false;\n m = n - sum;\n ans = vals;\n }\n }\n if (rejected) throw string(\"rejected\");\n if (m == linf) throw string(\"error\");\n cout << n - m << \" \" << ans << endl;\n }\n catch (string err) {\n cout << err << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3308, "score_of_the_acc": -0.0438, "final_rank": 3 }, { "submission_id": "aoj_1237_2022789", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\n\nint mypow(int x, int y) {\n int ret = 1;\n while(y > 0) {\n ret *= x;\n y--;\n }\n return ret;\n}\nint main() {\n int t, num;\n while(cin >> t >> num, t) {\n vector<vector<vector<int>>> ret(1000000);\n ret[num].push_back({num});\n\n for(int i=1; i<(1<<5); ++i) {\n int top = 0;\n for(int j=4; j>=0; --j) {\n if((i >> j) % 2 == 1) {\n top = j;\n break;\n }\n }\n if(mypow(10, top+1) > num) {\n break;\n }\n int rest = num;\n vector<int> v2;\n int sum=0;\n int prev_b = -1;\n for(int b=0; b<5; ++b) {\n if((i >> b) % 2 == 1) {\n int tmp = 0;\n if(prev_b != -1) {\n tmp = mypow(10, b - prev_b);\n } else {\n tmp = mypow(10, b+1);\n }\n v2.push_back(rest % tmp); // todo\n sum += rest % tmp;\n rest /= tmp;\n prev_b = b;\n if(rest == 0) {\n break;\n }\n }\n }\n if(rest != 0) {\n v2.push_back(rest);\n }\n sum += rest;\n //cout << \"rest = \" << rest << \" sum=\" << sum << endl;\n //cout << endl;\n //for(auto x : v2) {\n // cout << x << endl;\n //}\n //cout << endl;\n if(sum == 0) {\n continue;\n }\n ret[sum].push_back(v2);\n }\n\n bool finded = false;\n for(int i=t; i>=0; --i) {\n if(ret[i].size() >= 2) {\n cout << \"rejected\" << endl;\n finded = true;\n break;\n } else if(ret[i].size() == 1) {\n finded = true;\n cout << i << \" \";\n reverse(ret[i][0].begin(), ret[i][0].end());\n for(int j=0; j<ret[i][0].size()-1; ++j) {\n cout << ret[i][0][j] << \" \";\n }\n cout << ret[i][0][ret[i][0].size()-1] << endl;\n break;\n }\n }\n if(!finded) {\n cout << \"error\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 470, "memory_kb": 26564, "score_of_the_acc": -0.8438, "final_rank": 7 }, { "submission_id": "aoj_1237_2014259", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cstring>\n#include <string>\n#include <algorithm>\n#include <iomanip>\n#include <cmath>\n#include <cassert>\nusing namespace std;\ntypedef pair<int, vector<string> > P;\n\nint t;\nstring s;\n\nP f(string s, vector<bool> cut) {\n\tP ret;\n\tstring a;\n\ta += s[0];\n\tfor(int i = 0; i < cut.size(); i++) {\n\t\tif(cut[i]) {\n\t\t\tret.second.push_back(a);\n\t\t\ta = s[i + 1];\n\t\t}\n\t\telse {\n\t\t\ta += s[i + 1];\n\t\t}\n\t}\n\tret.second.push_back(a);\n\tfor(int i = 0; i < ret.second.size(); i++) {\n\t\ta = ret.second[i];\n\t\twhile(a.size() > 1 && a.front() == '0') a = a.substr(1, a.size() - 1);\n\t\tret.first += atoi(a.c_str());\n\t}\n\treturn ret;\n}\n\nvector<vector<string> > ans[1000000];\n\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\n\n\twhile(cin >> t >> s, t && s != \"0\") {\n\t\tfor(int i = 0; i < 1000000; i++) {\n\t\t\tans[i].clear();\n\t\t}\n\t\tint n = s.size();\n\t\tint m = -1;\n\t\tfor(int bit = 0; bit < 1 << (n - 1); bit++) {\n\t\t\tvector<bool> cut(n - 1);\n\t\t\tfor(int i = 0; i < n - 1; i++) {\n\t\t\t\tif(bit >> i & 1) cut[i] = true;\n\t\t\t}\n\t\t\tP p = f(s, cut);\n\t\t\tif(p.first > t) continue;\n\t\t\tm = max(m, p.first);\n\t\t\tans[p.first].push_back(p.second);\n\t\t}\n\t\tif(m == -1) {\n\t\t\tcout << \"error\" << endl;\n\t\t}\n\t\telse if(ans[m].size() >= 2) {\n\t\t\tcout << \"rejected\" << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << m;\n\t\t\tfor(string v : ans[m][0]) {\n\t\t\t\tcout << \" \" << v;\n\t\t\t}\n\t\t\tcout << endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 26644, "score_of_the_acc": -0.7374, "final_rank": 6 }, { "submission_id": "aoj_1237_1060725", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n#include <map>\n#include <algorithm>\n\n#define REP(i,n) for(int i=0;i<(int)(n);i++)\n\nusing namespace std;\n\nint dig(int n) {\n if(n<10)return 1;\n else return dig(n/10)+1;\n}\n\nint main() {\n while(1){\n int t,n;\n cin>>t>>n;\n if(!n)break;\n t=min(t,n);\n int s=dig(n);\n string ns=to_string(n);\n vector<vector<int>> dp(s+1,vector<int>(n+1));\n dp[0][0] = 1;\n REP(i,s+1){\n REP(j,i){\n auto sub=ns.substr(j,i-j);\n int m=stoi(sub);\n REP(k,n-m+1){\n if (dp[i][k+m] == 0 && dp[j][k] > 0)\n dp[i][k+m] = j+1;\n else if ((dp[i][k+m] != 0 && dp[j][k] != 0) || dp[j][k] < 0)\n dp[i][k+m] = -1;\n }\n }\n }\n bool ok=false;\n for (int u=t;u>0;--u) {\n if (dp[s][u] > 0) {\n vector<int> res;\n int i=s;\n int j=u;\n do {\n int oldi=i;\n i=dp[i][j]-1;\n auto sub=ns.substr(i,oldi-i);\n res.push_back(stoi(sub));\n j-=stoi(sub);\n } while(i>0);\n reverse(begin(res),end(res));\n cout<<u;\n for(int v:res) cout<<' '<<v;\n cout<<endl;\n ok = true;\n break;\n } else if (dp[s][u] < 0) {\n cout<<\"rejected\"<<endl;\n ok = true;\n break;\n }\n }\n if (!ok)\n cout<<\"error\"<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 760, "memory_kb": 35300, "score_of_the_acc": -1.2235, "final_rank": 9 }, { "submission_id": "aoj_1237_720042", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n\nusing namespace std;\n\nunsigned short dp[7][1000000];\nunsigned char pr[7][1000000];\nint df[7][1000000];\n\nint main(){\n\twhile(true){\n\t\tint n;\n\t\tstring s;\n\t\tcin >> n >> s;\n\t\tif(n == 0 && s == \"0\"){ break; }\n\t\tconst int m = s.size();\n\t\tfor(int i = 0; i <= m; ++i){\n\t\t\tfor(int j = 0; j <= n; ++j){\n\t\t\t\tdp[i][j] = pr[i][j] = df[i][j] = 0;\n\t\t\t}\n\t\t}\n\t\tdp[0][0] = 1;\n\t\tfor(int i = 0; i < m; ++i){\n\t\t\tint x = 0;\n\t\t\tfor(int j = i; j < m; ++j){\n\t\t\t\tx = (x * 10) + s[j] - '0';\n\t\t\t\tif(x > n){ break; }\n\t\t\t\tfor(int k = 0; k + x <= n; ++k){\n\t\t\t\t\tif(dp[i][k] == 0){ continue; }\n\t\t\t\t\tdp[j + 1][k + x] += dp[i][k];\n\t\t\t\t\tpr[j + 1][k + x] = i;\n\t\t\t\t\tdf[j + 1][k + x] = x;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint answer = -1;\n\t\tfor(int i = n; answer < 0 && i >= 0; --i){\n\t\t\tif(dp[m][i] != 0){ answer = i; }\n\t\t}\n\t\tif(answer < 0){\n\t\t\tcout << \"error\" << endl;\n\t\t}else if(dp[m][answer] >= 2){\n\t\t\tcout << \"rejected\" << endl;\n\t\t}else{\n\t\t\tcout << answer;\n\t\t\tvector<int> cut;\n\t\t\tint r = m, c = answer;\n\t\t\tdo {\n\t\t\t\tconst int d = df[r][c];\n\t\t\t\tcut.push_back(d);\n\t\t\t\tr = pr[r][c];\n\t\t\t\tc -= d;\n\t\t\t} while(r > 0);\n\t\t\tfor(int i = cut.size() - 1; i >= 0; --i){\n\t\t\t\tcout << \" \" << cut[i];\n\t\t\t}\n\t\t\tcout << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 48764, "score_of_the_acc": -1.0068, "final_rank": 8 }, { "submission_id": "aoj_1237_654601", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <climits>\n#include <cfloat>\n#include <map>\n#include <utility>\n#include <set>\n#include <iostream>\n#include <memory>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <functional>\n#include <sstream>\n#include <complex>\n#include <stack>\n#include <queue>\n#include <cstring>\n#include <sstream>\n#include <cassert>\n#include <ctime>\n#include <list>\n#include <numeric>\n#include <fstream>\n\nusing namespace std;\nstatic const double EPS = 1e-8;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<ll,ll> PI;\n#ifndef M_PI\nconst double M_PI=acos(-1.0);\n#endif\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n#define FORR(i,c) for(__typeof((c).rbegin())i=(c).rbegin();i!=(c).rend();++i)\n#define ALL(c) (c).begin(), (c).end()\n#define mp(a,b) make_pair(a,b)\n#define pb(a) push_back(a)\n#define SZ(a) (int((a).size()))\n#define F first\n#define S second\nvoid pkuassert(bool b){if(!b){int a=0;cout << 1/a << endl;}};\nint dx[]={0,-1,0,1,1,1,-1,-1},dy[]={1,0,-1,0,1,-1,1,-1};\n\nstring in;\n\nint num(int s,int t){\n int ret=0;\n rep(i,t-s) ret=ret*10+in[s+i]-'0';\n return ret;\n}\nint memo[6][1000000];\n\nint rec(int ne,int les,bool pr=false){\n if(les<0) return 0;\n if(ne==SZ(in)) return les==0;\n if(!pr && memo[ne][les]!=-1) return memo[ne][les];\n if(num(ne,SZ(in))<les) return 0;\n int& ret=memo[ne][les]=0;\n \n for(int i=ne+1;i<=SZ(in);++i){\n ret += rec(i,les-num(ne,i));\n if(pr && ret){\n cout << ' ' << in.substr(ne,i-ne);\n rec(i,les-num(ne,i),true);\n return 0;\n }\n if(ret>1) return ret=2;\n }\n return ret;\n}\n\nint t;\nvoid solve(){\n memset(memo,-1,sizeof(memo));\n while(t){\n if(rec(0,t)==1){\n cout << t;\n rec(0,t,true);\n cout << endl;\n return;\n }\n if(rec(0,t)>1){\n cout << \"rejected\" << endl;\n return;\n }\n --t;\n }\n cout << \"error\" << endl;\n}\n\nint main(){\n while(cin >> t >> in && t && in!=\"0\") solve();\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 24660, "score_of_the_acc": -0.5537, "final_rank": 5 }, { "submission_id": "aoj_1237_590687", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <map>\n#include <sstream>\nusing namespace std;\n\n#define INF (1<<29)\n\nint toInt(string s){\n istringstream iss(s);\n int a;\n iss >> a;\n return a;\n}\n\nint main(){\n int n;\n string s;\n while(cin >> n >> s){\n if(n == 0 && s == \"0\") break;\n int ans = -1;\n vector<string> ans2;\n map<int, int> is_found;\n \n for(int i = 0 ; i < (1<<s.size()) ; i++){\n vector<string> tmp;\n int pos = 0;\n int point = 0;\n for(int j = 0 ; j < s.size() ; j++){\n\tif(j == s.size()-1){\n\t string t = s.substr(pos, j-pos+1);\n\t tmp.push_back(t);\n\t pos = j+1;\n\t point += toInt(t);\n\t}\n\t\n\telse if((1<<j) & i){\n\t string t = s.substr(pos, j-pos+1);\n\t tmp.push_back(t);\n\t pos = j+1;\n\t point += toInt(t);\n\t}\n }\n \n is_found[point]++;\n if(point <= n && n-point < n-ans){\n\tans = point;\n\tans2 = tmp;\n }\n /*\n cout << point << ' ';\n for(int b = 0 ; b < tmp.size() ; b++){\n\tcout << tmp[b] << ' ';\n }\n cout << endl;\n */\n }\n \n //cout << is_found[ans] << endl;\n bool f = true;\n if(is_found[ans] > 2) f = false;\n \n if(ans == -1) cout << \"error\" << endl;\n else if(!f){\n cout << \"rejected\" << endl;\n }\n else{\n cout << ans << ' ';\n for(int i = 0 ; i < ans2.size() ; i++){\n\tcout << ans2[i];\n\tif(i != ans2.size()-1) cout << ' ';\n\telse cout << endl;\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1228, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1237_588934", "code_snippet": "#include<iostream>\n#include<sstream>\n\nusing namespace std;\n\n#define rep(i, n) for (int i = 0; i < int(n); ++i)\n\nint main() {\n while (true) {\n int t;\n string n;\n cin >> t >> n;\n if (t == 0 && n == \"0\") break;\n int res = 0, b;\n rep (i, 1 << (n.size() - 1)) {\n int p = 0, r = 0;\n rep (j, n.size() - 1) {\n\tif (i & 1 << j) {\n\t stringstream ss;\n\t ss << n.substr(p, j - p + 1);\n\t int a;\n\t ss >> a;\n\t r += a;\n\t p = j + 1;\n\t}\n }\n stringstream ss;\n ss << n.substr(p);\n int a;\n ss >> a;\n r += a;\n if (r <= t && res < r) {\n\tres = r;\n\tb = i;\n } else if (res == r) {\n\tb = -1;\n }\n }\n if (res == 0) cout << \"error\" << endl;\n else if (b == -1) cout << \"rejected\" << endl;\n else {\n cout << res << \" \" << n[0];\n rep (i, n.size() - 1) {\n\tif (b & 1 << i) cout << \" \";\n\tcout << n[i + 1];\n }\n cout << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1236, "score_of_the_acc": -0.0002, "final_rank": 2 } ]
aoj_1239_cpp
Problem H: Viva Confetti Do you know confetti ? They are small discs of colored paper, and people throw them around during parties or festivals. Since people throw lots of confetti, they may end up stacked one on another, so there may be hidden ones underneath. A handful of various sized confetti have been dropped on a table. Given their positions and sizes, can you tell us how many of them you can see? The following figure represents the disc configuration for the first sample input, where the bottom disc is still visible. Input The input is composed of a number of configurations of the following form. n x 1 y 1 z 1 x 2 y 2 z 2 . . . x n y n z n The first line in a configuration is the number of discs in the configuration (a positive integer not more than 100), followed by one Ine descriptions of each disc: coordinates of its center and radius, expressed as real numbers in decimal notation, with up to 12 digits after the decimal point. The imprecision margin is ±5 × 10 -13 . That is, it is guaranteed that variations of less than ±5 × 10 -13 on input values do not change which discs are visible. Coordinates of all points contained in discs are between -10 and 10. Confetti are listed in their stacking order, x 1 y 1 r 1 being the bottom one and x n y n r n the top one. You are observing from the top. The end of the input is marked by a zero on a single line. Output For each configuration you should output the number of visible confetti on a single line. Sample Input 3 0 0 0.5 -0.9 0 1.00000000001 0.9 0 1.00000000001 5 0 1 0.5 1 1 1.00000000001 0 2 1.00000000001 -1 1 1.00000000001 0 -0.00001 1.00000000001 5 0 1 0.5 1 1 1.00000000001 0 2 1.00000000001 -1 1 1.00000000001 0 0 1.00000000001 2 0 0 1.0000001 0 0 1 2 0 0 1 0.00000001 0 1 0 Output for the Sample Input 3 5 4 2 2
[ { "submission_id": "aoj_1239_4761256", "code_snippet": "#include<iostream>\n#include<cfloat>\n#include<cassert>\n#include<cmath>\n#include<cstdio>\n#include<vector>\n#include<set>\n#include<algorithm>\n\nusing namespace std;\n\n#define EPS (1e-15)\n#define equals(a, b) (fabs((a) - (b)) < EPS )\n#define dle(a, b) (equals(a, b) || a < b )\nstatic const double PI = acos(-1);\n\nclass Point{\npublic:\n double x, y;\n\n Point ( double x = 0, double y = 0): x(x), y(y){}\n\n Point operator + ( Point p ){ return Point(x + p.x, y + p.y); }\n Point operator - ( Point p ){ return Point(x - p.x, y - p.y); }\n Point operator * ( double a ){ return Point(x*a, y*a); }\n Point operator / ( double a ){ return Point(x/a, y/a); }\n Point operator / ( Point p ) { return Point((x*p.x+y*p.y)/(p.x*p.x+p.y*p.y), (y*p.x-x*p.y)/(p.x*p.x+p.y*p.y)); }\n \n double abs() { return sqrt(norm());}\n double norm() { return x*x + y*y; }\n\n bool operator < ( const Point &p ) const {\n return x != p.x ? x < p.x : y < p.y;\n }\n\n bool operator == ( const Point &p ) const {\n return fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n }\n};\n\ntypedef Point Vector;\n\n\nclass Segment{\npublic:\n Point p1, p2;\n Segment(Point s = Point(), Point t = Point()): p1(s), p2(t){}\n\n};\n\ntypedef Segment Line;\n\nstatic const int CIRCLE_NON = 0;\nstatic const int CIRCLE_OUT = 1;\nstatic const int CIRCLE_IN = 2;\nstatic const int CIRCLE_CROSS = 3;\n\nclass Circle{\npublic:\n Point c;\n double r;\n Circle(Point c = Point(), double r = 0.0): c(c), r(r){}\n};\n\ndouble norm( Vector a ){ return a.x*a.x + a.y*a.y; }\ndouble abs( Vector a ){ return sqrt(norm(a)); }\nPoint polar( double a, double r ){ return Point(cos(r)*a, sin(r)*a);}\ndouble getDistance( Vector a, Vector b ){ return abs(a - b); }\ndouble dot( Vector a, Vector b ){ return a.x*b.x + a.y*b.y; }\ndouble cross( Vector a, Vector b ){ return a.x*b.y - a.y*b.x; }\n\nPoint project( Segment s, Point p ){\n Vector base = s.p2 - s.p1;\n double t = dot(p - s.p1, base)/norm(base);\n return s.p1 + base*t;\n}\n\ndouble getAngle(Point p){\n double polar = atan2(p.y, p.x);\n return (dle(0, polar))? polar : 2.0*acos(-1)+polar;\n}\n\nint isIntersect(Circle c1, Circle c2){\n double d = abs(c1.c - c2.c);\n if ( c1.r + c2.r < d ) return CIRCLE_NON; // no overlap\n if ( d + c2.r < c1.r ) return CIRCLE_IN; // c1 includes c2\n if ( d + c1.r < c2.r ) return CIRCLE_OUT; // c2 includes c1\n return CIRCLE_CROSS;\n}\n\ndouble getDistanceLP(Line s, Point p){\n return abs(cross(s.p2 - s.p1, p - s.p1)/abs(s.p2 - s.p1));\n}\n\ndouble arg(Vector p){\n return atan2(p.y, p.x);\n}\n\npair<Point, Point> getCrossPoints(Circle c1, Circle c2){\n assert( isIntersect( c1, c2 ) );\n double d = abs(c1.c - c2.c);\n double a = acos((c1.r*c1.r+d*d-c2.r*c2.r)/(2*c1.r*d));\n double t = arg(c2.c - c1.c);\n return make_pair(c1.c+polar(c1.r, t+a), c1.c+polar(c1.r, t-a));\n}\n\nbool isIntersect( Circle c1, Line l ){\n double d = getDistanceLP(l, c1.c);\n return ( equals(d, c1.r) || d < c1.r );\n}\n\npair<Point, Point> getCrossPoints(Circle c, Line l ){\n assert( isIntersect( c, l ) );\n Vector pr = project(l, c.c);\n Vector e = (l.p2 - l.p1)/abs(l.p2 - l.p1);\n double base = sqrt(c.r*c.r - norm(pr-c.c));\n return make_pair(pr + e*base, pr - e*base);\n}\n\nCircle C[100];\nint n;\n\nvoid compute(){\n vector<Point> candidates;\n vector<double> Y; \n\n Y.push_back(-100.0);\n Y.push_back(100.0);\n\n for ( int i = 0; i < n; i++ ){\n Y.push_back(C[i].c.y - C[i].r);\n Y.push_back(C[i].c.y + C[i].r);\n }\n \n for ( int i = 0; i < n-1; i++ ){\n for ( int j = i+1; j < n; j++ ){\n if ( isIntersect(C[i], C[j]) != CIRCLE_CROSS ) continue;\n pair<Point, Point> pp = getCrossPoints(C[i], C[j]);\n Y.push_back(pp.first.y);\n Y.push_back(pp.second.y);\n }\n }\n\n sort(Y.begin(), Y.end());\n\n for ( int k = 0; k < Y.size()-1; k++ ){\n double my = (Y[k+1] + Y[k])/2;\n Line l = Line(Point(-100, my), Point(100, my));\n vector<double> X;\n X.push_back(-100);\n X.push_back(100);\n for ( int i = 0; i < n; i++ ){\n if ( !isIntersect(C[i], l) ) continue;\n pair<Point, Point> pp = getCrossPoints(C[i], l);\n X.push_back(pp.first.x);\n X.push_back(pp.second.x);\n }\n sort(X.begin(), X.end());\n\n for ( int i = 0; i < X.size()-1; i++ ){\n candidates.push_back(Point((X[i+1]+X[i])/2, my));\n }\n }\n\n int ans = 0;\n for ( int i = 0; i < n; i++ ){\n for ( int c = 0; c < candidates.size(); c++ ){\n Point t = candidates[c];\n bool f = true;\n if ( abs(C[i].c - t) > C[i].r ) {\n\tcontinue;\n }\n for ( int j = i+1; j < n; j++ ){\n\tif ( dle(abs(C[j].c - t), C[j].r) ) {\n\t f = false;\n\t break;\n\t}\n }\n if ( f ) {\n\tans++;\n\tbreak;\n }\n }\n }\n\n printf(\"%d\\n\", ans);\n}\n\nint main(){\n double x, y, r;\n while(1){\n cin >> n;\n if ( n == 0 ) break;\n for ( int i = 0; i < n; i++ ){\n cin >> x >> y >> r; C[i] = Circle( Point(x, y), r);\n }\n compute();\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5544, "score_of_the_acc": -1.5, "final_rank": 5 }, { "submission_id": "aoj_1239_1669020", "code_snippet": "#include<bits/stdc++.h>\n\n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define EPS (1e-14)\n#define equals(a,b) (fabs((a)-(b)) < EPS)\n#define COUNTER_CLOCKWISE 1\n#define CLOCKWISE -1 \n#define ONLINE_BACK 2\n#define ONLINE_FRONT -2\n#define ON_SEGMENT 0\n\nusing namespace std;\n\nclass Point{\npublic:\n double x,y;\n\n Point(double x = 0,double y = 0): x(x),y(y){}\n\n Point operator + (Point p){return Point(x+p.x,y+p.y);}\n Point operator - (Point p){return Point(x-p.x,y-p.y);}\n Point operator * (double a){return Point(a*x,a*y);}\n Point operator / (double a){return Point(x/a,y/a);}\n Point operator * (Point a){ return Point(x * a.x - y * a.y, x * a.y + y * a.x); }\n\n bool operator < (const Point& p) const{ return !equals(x,p.x)?x<p.x:(!equals(y,p.y)&&y<p.y); }\n\n bool operator == (const Point& p)const{ return fabs(x-p.x) < EPS && fabs(y-p.y) < EPS; }\n\n};\n\nstruct Segment{\n Point p1,p2;\n Segment(Point p1 = Point(),Point p2 = Point()):p1(p1),p2(p2){}\n bool operator < (const Segment& s) const { return ( p2 == s.p2 ) ? p1 < s.p1 : p2 < s.p2; }\n bool operator == (const Segment& s) const { return ( s.p1 == p1 && s.p2 == p2 ) || ( s.p1 == p2 && s.p2 == p1 ); }\n\n};\n\ntypedef Point Vector;\ntypedef Segment Line;\n\ndouble dot(Point a,Point b){ return a.x*b.x + a.y*b.y; }\n\ndouble cross(Point a,Point b){ return a.x*b.y - a.y*b.x; }\n\ndouble norm(Point a){ return a.x*a.x+a.y*a.y; }\n\ndouble abs(Point a){ return sqrt(norm(a)); }\n\nint ccw(Point p0,Point p1,Point p2){\n Point a = p1-p0;\n Point b = p2-p0;\n if(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n if(cross(a,b) < -EPS)return CLOCKWISE;\n if(dot(a,b) < -EPS)return ONLINE_BACK;\n if(norm(a) < norm(b))return ONLINE_FRONT;\n return ON_SEGMENT;\n}\n\npair<Point, Point> crosspointCC( Point C1, double r1, Point C2, double r2) {\n complex<double> c1(C1.x,C1.y);\n complex<double> c2(C2.x,C2.y);\n complex<double> A = conj(c2-c1), B = (r2*r2-r1*r1-(c2-c1)*conj(c2-c1)), C = r1*r1*(c2-c1);\n complex<double> D = B*B-4.0*A*C;\n complex<double> z1 = (-B+sqrt(D))/(2.0*A)+c1, z2 = (-B-sqrt(D))/(2.0*A)+c1;\n return pair<Point, Point>(Point(z1.real(),z1.imag()),Point(z2.real(),z2.imag()));\n}\n\n// ??? a ?????? b ????????????????????????\nbool insideCC(Point a,double ra,Point b,double rb){\n double d = sqrt(norm(a-b));\n double r1 = max(ra,rb);\n double r2 = min(ra,rb);\n \n if(!equals(d,r1-r2) && d < r1-r2) return ra < rb; \n return false;\n}\n\n\n//cross product of pq and pr\ndouble cross3p(Point p,Point q,Point r) { return (r.x-q.x) * (p.y -q.y) - (r.y - q.y) * (p.x - q.x); }\n \n//returns true if point r is on the same line as the line pq\nbool collinear(Point p,Point q,Point r) { return fabs(cross3p(p,q,r)) < EPS; }\n \n//returns true if point t is on the left side of line pq\nbool ccwtest(Point p,Point q,Point r){\n return cross3p(p,q,r) > 0; //can be modified to accept collinear points\n}\n \nbool onSegment(Point p,Point q,Point r){\n return collinear(p,q,r) && equals(sqrt(pow(p.x-r.x,2)+pow(p.y-r.y,2)) + sqrt(pow(r.x-q.x,2) + pow(r.y-q.y,2) ),sqrt(pow(p.x-q.x,2)+pow(p.y-q.y,2)) ) ;\n}\n\n\n\nbool intersectLL(Line l, Line m) {\n return abs(cross(l.p2-l.p1, m.p2-m.p1)) > EPS || // non-parallel\n abs(cross(l.p2-l.p1, m.p1-l.p1)) < EPS; // same line\n}\nbool intersectLS(Line l, Line s) {\n return cross(l.p2-l.p1, s.p1-l.p1)* // s[0] is left of l\n cross(l.p2-l.p1, s.p2-l.p1) < EPS; // s[1] is right of l\n}\nbool intersectLP(Line l,Point p) {\n return abs(cross(l.p2-p, l.p1-p)) < EPS;\n}\nbool intersectSS(Line s, Line t) {\n return ccw(s.p1,s.p2,t.p1)*ccw(s.p1,s.p2,t.p2) <= 0 &&\n ccw(t.p1,t.p2,s.p1)*ccw(t.p1,t.p2,s.p2) <= 0;\n}\nbool intersectSP(Line s, Point p) {\n return abs(s.p1-p)+abs(s.p2-p)-abs(s.p2-s.p1) < EPS; // triangle inequality\n}\n\nPoint projection(Line l,Point p) {\n double t = dot(p-l.p1, l.p1-l.p2) / norm(l.p1-l.p2);\n return l.p1 + (l.p1-l.p2)*t;\n}\nPoint reflection(Line l,Point p) {\n return p + (projection(l, p) - p) * 2;\n}\ndouble distanceLP(Line l, Point p) {\n return abs(p - projection(l, p));\n}\ndouble distanceLL(Line l, Line m) {\n return intersectLL(l, m) ? 0 : distanceLP(l, m.p1);\n}\n\ndouble distanceLS(Line l, Line s) {\n if (intersectLS(l, s)) return 0;\n return min(distanceLP(l, s.p1), distanceLP(l, s.p2));\n}\ndouble distanceSP(Line s, Point p) {\n Point r = projection(s, p);\n if (intersectSP(s, r)) return abs(r - p);\n return min(abs(s.p1 - p), abs(s.p2 - p));\n}\n\ndouble distanceSS(Line s, Line t) {\n if (intersectSS(s, t)) return 0;\n return min(min(distanceSP(s, t.p1), distanceSP(s, t.p2)),\n min(distanceSP(t, s.p1), distanceSP(t, s.p2)));\n}\n\nPoint crosspoint(Line l,Line m){\n double A = cross(l.p2-l.p1,m.p2-m.p1);\n double B = cross(l.p2-l.p1,l.p2-m.p1);\n if(abs(A) < EPS && abs(B) < EPS){\n vector<Point> vec;\n vec.push_back(l.p1),vec.push_back(l.p2),vec.push_back(m.p1),vec.push_back(m.p2);\n sort(vec.begin(),vec.end());\n assert(vec[1] == vec[2]); //???????????°??????????????????\n return vec[1];\n //return m.p1;\n }\n if(abs(A) < EPS)assert(false);\n return m.p1 + (m.p2-m.p1)*(B/A);\n}\n\n\n\n\n\n// <---------\n\ninline bool LT(double a,double b) { return !equals(a,b) && a < b; }\ninline bool LTE(double a,double b) { return equals(a,b) || a < b; }\n\nint n;\nPoint ps[110];\ndouble rs[110];\n\nbool insideAny(int i) {\n REP(j,i+1,n) if( insideCC(ps[i],rs[i],ps[j],rs[j]) ) return true;\n return false;\n}\n\nbool trivialFail(int i) {\n if( insideAny(i) ) return true;\n REP(j,i+1,n) if( ps[i] == ps[j] && equals(rs[i],rs[j]) ) return true;\n return false;\n}\n\nPoint vir;\nbool comp_angle(const Point &a,const Point &b) {\n return LT(atan2(vir.y-a.y,vir.x-a.x),atan2(vir.y-b.y,vir.x-b.x));\n}\n\nbool comp_dist(Point a,Point b) {\n return LTE(abs(a-vir),abs(b-vir));\n}\n\npair<Point,Point> crosspointCL(Point cp,double r,Line l) {\n double dist = distanceLP(l,cp);\n Vector v = (l.p1-l.p2) / abs(l.p1-l.p2);\n if( equals(dist,0) ) {\n return pair<Point,Point>(Point(cp+v*r),Point(cp-v*r));\n } else {\n double x = sqrt(r*r-dist*dist);\n return pair<Point,Point>(Point(cp+v*x),Point(cp-v*x));\n }\n}\n\nbool visibleCheckPoint(Point p,int i) {\n REP(j,i+1,n) {\n double dist = abs(p-ps[j]);\n if( LT(dist,rs[j]) ) return false;\n }\n return true;\n}\n\nbool visibleCheckSeg(Segment seg,int i) {\n deque<Point> deq;\n deq.push_back(seg.p1);\n deq.push_back(seg.p2);\n rep(j,2) {\n double dist = abs(deq[j]-ps[i]);\n if( equals(dist,rs[i]) || dist < rs[i] ) if( visibleCheckPoint(deq[j],i) ) return true;\n }\n return false;\n REP(j,i+1,n) {\n double dist = distanceLP(seg,ps[j]);\n if( LTE(rs[j],dist) ) continue;\n pair<Point,Point> pp = crosspointCL(ps[j],rs[j],seg);\n if( onSegment(seg.p1,seg.p2,pp.first) ) deq.push_back(pp.first);\n if( onSegment(seg.p1,seg.p2,pp.second) ) deq.push_back(pp.second);\n }\n \n // sort\n vir = seg.p1;\n sort(deq.begin(),deq.end(),comp_dist);\n \n // check\n rep(j,(int)deq.size()-1) {\n Point p1 = deq[j];\n Point p2 = deq[j+1];\n Point mp = (p1+p2)/2.0;\n double dist = abs(mp-ps[i]);\n if( equals(dist,rs[i]) || dist < rs[i] ) if( visibleCheckPoint(mp,i) ) return true;\n }\n return false;\n}\n\nbool visibleCheckArcJ(int i,int j) {\n deque<Point> deq;\n REP(k,i,n) {\n if( ps[j] == ps[k] && equals(rs[j],rs[k]) ) continue;\n {\n double dist = abs(ps[k]-ps[j]); \n double rdist = rs[k]+rs[j];\n if( equals(dist,rdist) || dist > rdist ) continue;\n }\n pair<Point,Point> pp = crosspointCC(ps[j],rs[j],ps[k],rs[k]);\n deq.push_back(pp.first);\n deq.push_back(pp.second);\n }\n vir = ps[j];\n sort(deq.begin(),deq.end(),comp_angle);\n rep(k,(int)deq.size()) {\n Point p1 = deq[k] - ps[j];\n Point p2 = deq[(k+1)%(int)deq.size()] - ps[j];\n Point mp = ( p1 + p2 ) / 2.0;\n mp = mp + ps[j];\n Vector v = ( mp - ps[j] ) / abs( mp - ps[j] );\n Segment seg = Segment(ps[j]+v*rs[j],ps[j]-v*rs[j]);\n if( visibleCheckSeg(seg,i) ) return true;\n }\n return false;\n}\n\nvoid compute() {\n int cnt = 0;\n rep(i,n) { // check the i-th circle whether the circle is visible or not\n if( trivialFail(i) ) continue;\n bool success = false;\n bool success2 = true;\n REP(j,i+1,n) { \n {\n\tdouble dist = abs(ps[i]-ps[j]); \n\tdouble rdist = rs[i]+rs[j];\n\tif( equals(dist,rdist) || dist > rdist ) continue;\n }\n if( insideCC(ps[j],rs[j],ps[i],rs[i]) ) continue; \n success2 = false;\n if( visibleCheckArcJ(i,j) ) { success = true; break; }\n }\n if( success || success2 ) ++cnt;\n }\n cout << cnt << endl;\n}\n\nint main() {\n while( cin >> n, n ) {\n rep(i,n) cin >> ps[i].x >> ps[i].y >> rs[i];\n compute();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1360, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1239_1668972", "code_snippet": "#include<bits/stdc++.h>\n\n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define EPS (1e-14)\n#define equals(a,b) (fabs((a)-(b)) < EPS)\n#define COUNTER_CLOCKWISE 1\n#define CLOCKWISE -1 \n#define ONLINE_BACK 2\n#define ONLINE_FRONT -2\n#define ON_SEGMENT 0\n\nusing namespace std;\n\nclass Point{\npublic:\n double x,y;\n\n Point(double x = 0,double y = 0): x(x),y(y){}\n\n Point operator + (Point p){return Point(x+p.x,y+p.y);}\n Point operator - (Point p){return Point(x-p.x,y-p.y);}\n Point operator * (double a){return Point(a*x,a*y);}\n Point operator / (double a){return Point(x/a,y/a);}\n Point operator * (Point a){ return Point(x * a.x - y * a.y, x * a.y + y * a.x); }\n\n bool operator < (const Point& p) const{ return !equals(x,p.x)?x<p.x:(!equals(y,p.y)&&y<p.y); }\n\n bool operator == (const Point& p)const{ return fabs(x-p.x) < EPS && fabs(y-p.y) < EPS; }\n\n};\n\nstruct Segment{\n Point p1,p2;\n Segment(Point p1 = Point(),Point p2 = Point()):p1(p1),p2(p2){}\n bool operator < (const Segment& s) const { return ( p2 == s.p2 ) ? p1 < s.p1 : p2 < s.p2; }\n bool operator == (const Segment& s) const { return ( s.p1 == p1 && s.p2 == p2 ) || ( s.p1 == p2 && s.p2 == p1 ); }\n\n};\n\ntypedef Point Vector;\ntypedef Segment Line;\n\ndouble dot(Point a,Point b){ return a.x*b.x + a.y*b.y; }\n\ndouble cross(Point a,Point b){ return a.x*b.y - a.y*b.x; }\n\ndouble norm(Point a){ return a.x*a.x+a.y*a.y; }\n\ndouble abs(Point a){ return sqrt(norm(a)); }\n\nint ccw(Point p0,Point p1,Point p2){\n Point a = p1-p0;\n Point b = p2-p0;\n if(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n if(cross(a,b) < -EPS)return CLOCKWISE;\n if(dot(a,b) < -EPS)return ONLINE_BACK;\n if(norm(a) < norm(b))return ONLINE_FRONT;\n return ON_SEGMENT;\n}\n\npair<Point, Point> crosspointCC( Point C1, double r1, Point C2, double r2) {\n complex<double> c1(C1.x,C1.y);\n complex<double> c2(C2.x,C2.y);\n complex<double> A = conj(c2-c1), B = (r2*r2-r1*r1-(c2-c1)*conj(c2-c1)), C = r1*r1*(c2-c1);\n complex<double> D = B*B-4.0*A*C;\n complex<double> z1 = (-B+sqrt(D))/(2.0*A)+c1, z2 = (-B-sqrt(D))/(2.0*A)+c1;\n return pair<Point, Point>(Point(z1.real(),z1.imag()),Point(z2.real(),z2.imag()));\n}\n\n// ??? a ?????? b ????????????????????????\nbool insideCC(Point a,double ra,Point b,double rb){\n double d = sqrt(norm(a-b));\n double r1 = max(ra,rb);\n double r2 = min(ra,rb);\n \n if(!equals(d,r1-r2) && d < r1-r2) return ra < rb; \n return false;\n}\n\n\n//cross product of pq and pr\ndouble cross3p(Point p,Point q,Point r) { return (r.x-q.x) * (p.y -q.y) - (r.y - q.y) * (p.x - q.x); }\n \n//returns true if point r is on the same line as the line pq\nbool collinear(Point p,Point q,Point r) { return fabs(cross3p(p,q,r)) < EPS; }\n \n//returns true if point t is on the left side of line pq\nbool ccwtest(Point p,Point q,Point r){\n return cross3p(p,q,r) > 0; //can be modified to accept collinear points\n}\n \nbool onSegment(Point p,Point q,Point r){\n return collinear(p,q,r) && equals(sqrt(pow(p.x-r.x,2)+pow(p.y-r.y,2)) + sqrt(pow(r.x-q.x,2) + pow(r.y-q.y,2) ),sqrt(pow(p.x-q.x,2)+pow(p.y-q.y,2)) ) ;\n}\n\n\n\nbool intersectLL(Line l, Line m) {\n return abs(cross(l.p2-l.p1, m.p2-m.p1)) > EPS || // non-parallel\n abs(cross(l.p2-l.p1, m.p1-l.p1)) < EPS; // same line\n}\nbool intersectLS(Line l, Line s) {\n return cross(l.p2-l.p1, s.p1-l.p1)* // s[0] is left of l\n cross(l.p2-l.p1, s.p2-l.p1) < EPS; // s[1] is right of l\n}\nbool intersectLP(Line l,Point p) {\n return abs(cross(l.p2-p, l.p1-p)) < EPS;\n}\nbool intersectSS(Line s, Line t) {\n return ccw(s.p1,s.p2,t.p1)*ccw(s.p1,s.p2,t.p2) <= 0 &&\n ccw(t.p1,t.p2,s.p1)*ccw(t.p1,t.p2,s.p2) <= 0;\n}\nbool intersectSP(Line s, Point p) {\n return abs(s.p1-p)+abs(s.p2-p)-abs(s.p2-s.p1) < EPS; // triangle inequality\n}\n\nPoint projection(Line l,Point p) {\n double t = dot(p-l.p1, l.p1-l.p2) / norm(l.p1-l.p2);\n return l.p1 + (l.p1-l.p2)*t;\n}\nPoint reflection(Line l,Point p) {\n return p + (projection(l, p) - p) * 2;\n}\ndouble distanceLP(Line l, Point p) {\n return abs(p - projection(l, p));\n}\ndouble distanceLL(Line l, Line m) {\n return intersectLL(l, m) ? 0 : distanceLP(l, m.p1);\n}\n\ndouble distanceLS(Line l, Line s) {\n if (intersectLS(l, s)) return 0;\n return min(distanceLP(l, s.p1), distanceLP(l, s.p2));\n}\ndouble distanceSP(Line s, Point p) {\n Point r = projection(s, p);\n if (intersectSP(s, r)) return abs(r - p);\n return min(abs(s.p1 - p), abs(s.p2 - p));\n}\n\ndouble distanceSS(Line s, Line t) {\n if (intersectSS(s, t)) return 0;\n return min(min(distanceSP(s, t.p1), distanceSP(s, t.p2)),\n min(distanceSP(t, s.p1), distanceSP(t, s.p2)));\n}\n\nPoint crosspoint(Line l,Line m){\n double A = cross(l.p2-l.p1,m.p2-m.p1);\n double B = cross(l.p2-l.p1,l.p2-m.p1);\n if(abs(A) < EPS && abs(B) < EPS){\n vector<Point> vec;\n vec.push_back(l.p1),vec.push_back(l.p2),vec.push_back(m.p1),vec.push_back(m.p2);\n sort(vec.begin(),vec.end());\n assert(vec[1] == vec[2]); //???????????°??????????????????\n return vec[1];\n //return m.p1;\n }\n if(abs(A) < EPS)assert(false);\n return m.p1 + (m.p2-m.p1)*(B/A);\n}\n\n\n\n\n\n// <---------\n\ninline bool LT(double a,double b) { return !equals(a,b) && a < b; }\ninline bool LTE(double a,double b) { return equals(a,b) || a < b; }\n\nint n;\nPoint ps[110];\ndouble rs[110];\n\nbool insideAny(int i) {\n REP(j,i+1,n) if( insideCC(ps[i],rs[i],ps[j],rs[j]) ) return true;\n return false;\n}\n\nbool trivialFail(int i) {\n if( insideAny(i) ) return true;\n REP(j,i+1,n) if( ps[i] == ps[j] && equals(rs[i],rs[j]) ) return true;\n return false;\n}\n\nPoint vir;\nbool comp_angle(const Point &a,const Point &b) {\n return LT(atan2(vir.y-a.y,vir.x-a.x),atan2(vir.y-b.y,vir.x-b.x));\n}\n\nbool comp_dist(Point a,Point b) {\n return LTE(abs(a-vir),abs(b-vir));\n}\n\npair<Point,Point> crosspointCL(Point cp,double r,Line l) {\n double dist = distanceLP(l,cp);\n Vector v = (l.p1-l.p2) / abs(l.p1-l.p2);\n if( equals(dist,0) ) {\n return pair<Point,Point>(Point(cp+v*r),Point(cp-v*r));\n } else {\n double x = sqrt(r*r-dist*dist);\n return pair<Point,Point>(Point(cp+v*x),Point(cp-v*x));\n }\n}\n\nbool visibleCheckPoint(Point p,int i) {\n REP(j,i+1,n) {\n double dist = abs(p-ps[j]);\n if( LT(dist,rs[j]) ) return false;\n }\n return true;\n}\n\nbool visibleCheckSeg(Segment seg,int i) {\n deque<Point> deq;\n deq.push_back(seg.p1);\n deq.push_back(seg.p2);\n REP(j,i+1,n) {\n double dist = distanceLP(seg,ps[j]);\n if( LTE(rs[j],dist) ) continue;\n pair<Point,Point> pp = crosspointCL(ps[j],rs[j],seg);\n if( onSegment(seg.p1,seg.p2,pp.first) ) deq.push_back(pp.first);\n if( onSegment(seg.p1,seg.p2,pp.second) ) deq.push_back(pp.second);\n }\n \n // sort\n vir = seg.p1;\n sort(deq.begin(),deq.end(),comp_dist);\n \n // check\n rep(j,(int)deq.size()-1) {\n Point p1 = deq[j];\n Point p2 = deq[j+1];\n Point mp = (p1+p2)/2.0;\n double dist = abs(mp-ps[i]);\n if( equals(dist,rs[i]) || dist < rs[i] ) if( visibleCheckPoint(mp,i) ) return true;\n }\n return false;\n}\n\nbool visibleCheckArcJ(int i,int j) {\n deque<Point> deq;\n REP(k,i,n) {\n if( ps[j] == ps[k] && equals(rs[j],rs[k]) ) continue;\n {\n double dist = abs(ps[k]-ps[j]); \n double rdist = rs[k]+rs[j];\n if( equals(dist,rdist) || dist > rdist ) continue;\n }\n pair<Point,Point> pp = crosspointCC(ps[j],rs[j],ps[k],rs[k]);\n deq.push_back(pp.first);\n deq.push_back(pp.second);\n }\n vir = ps[j];\n sort(deq.begin(),deq.end(),comp_angle);\n rep(k,(int)deq.size()) {\n Point p1 = deq[k] - ps[j];\n Point p2 = deq[(k+1)%(int)deq.size()] - ps[j];\n Point mp = ( p1 + p2 ) / 2.0;\n mp = mp + ps[j];\n Vector v = ( mp - ps[j] ) / abs( mp - ps[j] );\n Segment seg = Segment(ps[j]+v*rs[j],ps[j]-v*rs[j]);\n if( visibleCheckSeg(seg,i) ) return true;\n }\n return false;\n}\n\nvoid compute() {\n int cnt = 0;\n rep(i,n) { // check the i-th circle whether the circle is visible or not\n if( trivialFail(i) ) continue;\n bool success = false;\n bool success2 = true;\n REP(j,i+1,n) { \n {\n\tdouble dist = abs(ps[i]-ps[j]); \n\tdouble rdist = rs[i]+rs[j];\n\tif( equals(dist,rdist) || dist > rdist ) continue;\n }\n if( insideCC(ps[j],rs[j],ps[i],rs[i]) ) continue; \n success2 = false;\n if( visibleCheckArcJ(i,j) ) { success = true; break; }\n }\n if( success || success2 ) ++cnt;\n }\n cout << cnt << endl;\n}\n\nint main() {\n while( cin >> n, n ) {\n rep(i,n) cin >> ps[i].x >> ps[i].y >> rs[i];\n compute();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 1372, "score_of_the_acc": -0.5029, "final_rank": 3 }, { "submission_id": "aoj_1239_1668936", "code_snippet": "#include<bits/stdc++.h>\n\n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define EPS (1e-14)\n#define equals(a,b) (fabs((a)-(b)) < EPS)\n#define COUNTER_CLOCKWISE 1\n#define CLOCKWISE -1 \n#define ONLINE_BACK 2\n#define ONLINE_FRONT -2\n#define ON_SEGMENT 0\n\nusing namespace std;\n\nclass Point{\npublic:\n double x,y;\n\n Point(double x = 0,double y = 0): x(x),y(y){}\n\n Point operator + (Point p){return Point(x+p.x,y+p.y);}\n Point operator - (Point p){return Point(x-p.x,y-p.y);}\n Point operator * (double a){return Point(a*x,a*y);}\n Point operator / (double a){return Point(x/a,y/a);}\n Point operator * (Point a){ return Point(x * a.x - y * a.y, x * a.y + y * a.x); }\n\n bool operator < (const Point& p) const{ return !equals(x,p.x)?x<p.x:(!equals(y,p.y)&&y<p.y); }\n\n bool operator == (const Point& p)const{ return fabs(x-p.x) < EPS && fabs(y-p.y) < EPS; }\n\n};\n\nstruct Segment{\n Point p1,p2;\n Segment(Point p1 = Point(),Point p2 = Point()):p1(p1),p2(p2){}\n bool operator < (const Segment& s) const { return ( p2 == s.p2 ) ? p1 < s.p1 : p2 < s.p2; }\n bool operator == (const Segment& s) const { return ( s.p1 == p1 && s.p2 == p2 ) || ( s.p1 == p2 && s.p2 == p1 ); }\n\n};\n\ntypedef Point Vector;\ntypedef Segment Line;\ntypedef vector<Point> Polygon;\n\nostream& operator << (ostream& os,const Point& a){ os << \"(\" << a.x << \",\" << a.y << \")\"; }\n\nostream& operator << (ostream& os,const Segment& a){ os << \"( \" << a.p1 << \" , \" << a.p2 << \" )\"; }\n\ndouble dot(Point a,Point b){ return a.x*b.x + a.y*b.y; }\n\ndouble cross(Point a,Point b){ return a.x*b.y - a.y*b.x; }\n\ndouble norm(Point a){ return a.x*a.x+a.y*a.y; }\n\ndouble abs(Point a){ return sqrt(norm(a)); }\n\n//rad ????§???????????????¢?????§?????????????????¨\nPoint rotate(Point a,double rad){ return Point(cos(rad)*a.x - sin(rad)*a.y,sin(rad)*a.x + cos(rad)*a.y); }\n\n// ??????????????¢????????????\ndouble toRad(double agl){ return agl*M_PI/180.0; }\n\n// a => prev, b => cur, c=> next\n// prev ?????? cur ????????£??? next ????????????????§????????±???????\ndouble getArg(Point a,Point b,Point c){\n double arg1 = atan2(b.y-a.y,b.x-a.x);\n double arg2 = atan2(c.y-b.y,c.x-b.x);\n double arg = fabs( arg1 - arg2 );\n while( arg > M_PI ) arg -= 2.0 * M_PI;\n return fabs(arg);\n}\n\nint ccw(Point p0,Point p1,Point p2){\n Point a = p1-p0;\n Point b = p2-p0;\n if(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n if(cross(a,b) < -EPS)return CLOCKWISE;\n if(dot(a,b) < -EPS)return ONLINE_BACK;\n if(norm(a) < norm(b))return ONLINE_FRONT;\n return ON_SEGMENT;\n}\n\npair<Point, Point> crosspointCC( Point C1, double r1, Point C2, double r2) {\n complex<double> c1(C1.x,C1.y);\n complex<double> c2(C2.x,C2.y);\n complex<double> A = conj(c2-c1), B = (r2*r2-r1*r1-(c2-c1)*conj(c2-c1)), C = r1*r1*(c2-c1);\n complex<double> D = B*B-4.0*A*C;\n complex<double> z1 = (-B+sqrt(D))/(2.0*A)+c1, z2 = (-B-sqrt(D))/(2.0*A)+c1;\n return pair<Point, Point>(Point(z1.real(),z1.imag()),Point(z2.real(),z2.imag()));\n}\n\n// ??? a ?????? b ????????????????????????\nbool insideCC(Point a,double ra,Point b,double rb){\n double d = sqrt(norm(a-b));\n double r1 = max(ra,rb);\n double r2 = min(ra,rb);\n \n if(!equals(d,r1-r2) && d < r1-r2) return ra < rb; \n return false;\n}\n\n\n//cross product of pq and pr\ndouble cross3p(Point p,Point q,Point r) { return (r.x-q.x) * (p.y -q.y) - (r.y - q.y) * (p.x - q.x); }\n \n//returns true if point r is on the same line as the line pq\nbool collinear(Point p,Point q,Point r) { return fabs(cross3p(p,q,r)) < EPS; }\n \n//returns true if point t is on the left side of line pq\nbool ccwtest(Point p,Point q,Point r){\n return cross3p(p,q,r) > 0; //can be modified to accept collinear points\n}\n \nbool onSegment(Point p,Point q,Point r){\n return collinear(p,q,r) && equals(sqrt(pow(p.x-r.x,2)+pow(p.y-r.y,2)) + sqrt(pow(r.x-q.x,2) + pow(r.y-q.y,2) ),sqrt(pow(p.x-q.x,2)+pow(p.y-q.y,2)) ) ;\n}\n\n\n\nbool intersectLL(Line l, Line m) {\n return abs(cross(l.p2-l.p1, m.p2-m.p1)) > EPS || // non-parallel\n abs(cross(l.p2-l.p1, m.p1-l.p1)) < EPS; // same line\n}\nbool intersectLS(Line l, Line s) {\n return cross(l.p2-l.p1, s.p1-l.p1)* // s[0] is left of l\n cross(l.p2-l.p1, s.p2-l.p1) < EPS; // s[1] is right of l\n}\nbool intersectLP(Line l,Point p) {\n return abs(cross(l.p2-p, l.p1-p)) < EPS;\n}\nbool intersectSS(Line s, Line t) {\n return ccw(s.p1,s.p2,t.p1)*ccw(s.p1,s.p2,t.p2) <= 0 &&\n ccw(t.p1,t.p2,s.p1)*ccw(t.p1,t.p2,s.p2) <= 0;\n}\nbool intersectSP(Line s, Point p) {\n return abs(s.p1-p)+abs(s.p2-p)-abs(s.p2-s.p1) < EPS; // triangle inequality\n}\n\nPoint projection(Line l,Point p) {\n double t = dot(p-l.p1, l.p1-l.p2) / norm(l.p1-l.p2);\n return l.p1 + (l.p1-l.p2)*t;\n}\nPoint reflection(Line l,Point p) {\n return p + (projection(l, p) - p) * 2;\n}\ndouble distanceLP(Line l, Point p) {\n return abs(p - projection(l, p));\n}\ndouble distanceLL(Line l, Line m) {\n return intersectLL(l, m) ? 0 : distanceLP(l, m.p1);\n}\n\ndouble distanceLS(Line l, Line s) {\n if (intersectLS(l, s)) return 0;\n return min(distanceLP(l, s.p1), distanceLP(l, s.p2));\n}\ndouble distanceSP(Line s, Point p) {\n Point r = projection(s, p);\n if (intersectSP(s, r)) return abs(r - p);\n return min(abs(s.p1 - p), abs(s.p2 - p));\n}\n\ndouble distanceSS(Line s, Line t) {\n if (intersectSS(s, t)) return 0;\n return min(min(distanceSP(s, t.p1), distanceSP(s, t.p2)),\n min(distanceSP(t, s.p1), distanceSP(t, s.p2)));\n}\n\nPoint crosspoint(Line l,Line m){\n double A = cross(l.p2-l.p1,m.p2-m.p1);\n double B = cross(l.p2-l.p1,l.p2-m.p1);\n if(abs(A) < EPS && abs(B) < EPS){\n vector<Point> vec;\n vec.push_back(l.p1),vec.push_back(l.p2),vec.push_back(m.p1),vec.push_back(m.p2);\n sort(vec.begin(),vec.end());\n assert(vec[1] == vec[2]); //???????????°??????????????????\n return vec[1];\n //return m.p1;\n }\n if(abs(A) < EPS)assert(false);\n return m.p1 + (m.p2-m.p1)*(B/A);\n}\n\n\n\n\n\n// <---------\n\ninline bool LT(double a,double b) { return !equals(a,b) && a < b; }\ninline bool LTE(double a,double b) { return equals(a,b) || a < b; }\n\nint n;\nPoint ps[110];\ndouble rs[110];\n\nbool insideAny(int i) {\n REP(j,i+1,n) if( insideCC(ps[i],rs[i],ps[j],rs[j]) ) return true;\n return false;\n}\n\nbool trivialFail(int i) {\n if( insideAny(i) ) return true;\n REP(j,i+1,n) if( ps[i] == ps[j] && equals(rs[i],rs[j]) ) return true;\n return false;\n}\n\nPoint vir;\nbool comp_angle(const Point &a,const Point &b) {\n return LT(atan2(vir.y-a.y,vir.x-a.x),atan2(vir.y-b.y,vir.x-b.x));\n}\n\nbool comp_dist(Point a,Point b) {\n return LTE(abs(a-vir),abs(b-vir));\n}\n\npair<Point,Point> crosspointCL(Point cp,double r,Line l) {\n double dist = distanceLP(l,cp);\n Vector v = (l.p1-l.p2) / abs(l.p1-l.p2);\n if( equals(dist,0) ) {\n return pair<Point,Point>(Point(cp+v*r),Point(cp-v*r));\n } else {\n double x = sqrt(r*r-dist*dist);\n return pair<Point,Point>(Point(cp+v*x),Point(cp-v*x));\n }\n}\n\nbool visibleCheckPoint(Point p,int i) {\n REP(j,i+1,n) {\n double dist = abs(p-ps[j]);\n if( LT(dist,rs[j]) ) return false;\n }\n return true;\n}\n\nbool visibleCheckSeg(Segment seg,int i) {\n deque<Point> deq;\n deq.push_back(seg.p1);\n deq.push_back(seg.p2);\n REP(j,i+1,n) {\n double dist = distanceLP(seg,ps[j]);\n if( LTE(rs[j],dist) ) continue;\n pair<Point,Point> pp = crosspointCL(ps[j],rs[j],seg);\n if( onSegment(seg.p1,seg.p2,pp.first) ) deq.push_back(pp.first);\n if( onSegment(seg.p1,seg.p2,pp.second) ) deq.push_back(pp.second);\n }\n \n // sort\n vir = seg.p1;\n sort(deq.begin(),deq.end(),comp_dist);\n \n // check\n rep(j,(int)deq.size()-1) {\n Point p1 = deq[j];\n Point p2 = deq[j+1];\n Point mp = (p1+p2)/2.0;\n double dist = abs(mp-ps[i]);\n if( equals(dist,rs[i]) || dist < rs[i] ) {\n if( visibleCheckPoint(mp,i) ) return true;\n }\n }\n return false;\n}\n\nbool visibleCheckArcJ(int i,int j) {\n deque<Point> deq;\n REP(k,i,n) {\n if( ps[j] == ps[k] && equals(rs[j],rs[k]) ) continue;\n {\n double dist = abs(ps[k]-ps[j]); \n double rdist = rs[k]+rs[j];\n if( equals(dist,rdist) || dist > rdist ) continue;\n }\n pair<Point,Point> pp = crosspointCC(ps[j],rs[j],ps[k],rs[k]);\n deq.push_back(pp.first);\n deq.push_back(pp.second);\n }\n vir = ps[j];\n sort(deq.begin(),deq.end(),comp_angle);\n //deq.erase(unique(deq.begin(),deq.end()),deq.end());\n rep(k,(int)deq.size()) {\n Point p1 = deq[k] - ps[j];\n Point p2 = deq[(k+1)%(int)deq.size()] - ps[j];\n Point mp = ( p1 + p2 ) / 2.0;\n mp = mp + ps[j];\n Vector v = ( mp - ps[j] ) / abs( mp - ps[j] );\n Segment seg = Segment(ps[j]+v*rs[j],ps[j]-v*rs[j]);\n //cout << \"CHECK SEG \" << seg << endl;\n if( visibleCheckSeg(seg,i) ) {\n //cout << \"VISIBLE ARC \" << seg << endl;\n return true;\n }\n }\n return false;\n}\n\nvoid compute() {\n int cnt = 0;\n rep(i,n) { // check the i-th circle whether the circle is visible or not\n //cout << i << \"-th \" << ps[i] << \", \" << rs[i] << endl;\n if( trivialFail(i) ) {\n //cout << i << \" is trivialFail\" << endl;\n continue;\n }\n bool success = false;\n bool success2 = true;\n REP(j,i+1,n) { \n //cout <<\">> \" << j << \" \" << ps[j] << \",\" << rs[j] << endl;\n {\n\tdouble dist = abs(ps[i]-ps[j]); \n\tdouble rdist = rs[i]+rs[j];\n\tif( equals(dist,rdist) || dist > rdist ) {\n\t //puts(\"OVER\");\n\t continue;\n\t}\n }\n if( insideCC(ps[j],rs[j],ps[i],rs[i]) ) {\n\t//puts(\"INSIDE\");\n\tcontinue;\n }\n success2 = false;\n if( visibleCheckArcJ(i,j) ) { \n\t//puts(\"VISIBLE\");\n\tsuccess = true; break; \n }\n //puts(\"INVISIBLE\");\n }\n if( success || success2 ) ++cnt;\n }\n cout << cnt << endl;\n}\n\nint main() {\n while( cin >> n, n ) {\n rep(i,n) cin >> ps[i].x >> ps[i].y >> rs[i];\n compute();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 1372, "score_of_the_acc": -0.3779, "final_rank": 2 }, { "submission_id": "aoj_1239_1656014", "code_snippet": "#include<iostream>\n#include<cfloat>\n#include<cassert>\n#include<cmath>\n#include<cstdio>\n#include<vector>\n#include<set>\n#include<algorithm>\n\nusing namespace std;\n\n#define EPS (1e-15)\n#define equals(a, b) (fabs((a) - (b)) < EPS )\n#define dle(a, b) (equals(a, b) || a < b )\nstatic const double PI = acos(-1);\n\nclass Point{\npublic:\n double x, y;\n\n Point ( double x = 0, double y = 0): x(x), y(y){}\n\n Point operator + ( Point p ){ return Point(x + p.x, y + p.y); }\n Point operator - ( Point p ){ return Point(x - p.x, y - p.y); }\n Point operator * ( double a ){ return Point(x*a, y*a); }\n Point operator / ( double a ){ return Point(x/a, y/a); }\n Point operator / ( Point p ) { return Point((x*p.x+y*p.y)/(p.x*p.x+p.y*p.y), (y*p.x-x*p.y)/(p.x*p.x+p.y*p.y)); }\n \n double abs() { return sqrt(norm());}\n double norm() { return x*x + y*y; }\n\n bool operator < ( const Point &p ) const {\n return x != p.x ? x < p.x : y < p.y;\n }\n\n bool operator == ( const Point &p ) const {\n return fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n }\n};\n\ntypedef Point Vector;\n\n\nclass Segment{\npublic:\n Point p1, p2;\n Segment(Point s = Point(), Point t = Point()): p1(s), p2(t){}\n\n};\n\ntypedef Segment Line;\n\nstatic const int CIRCLE_NON = 0;\nstatic const int CIRCLE_OUT = 1;\nstatic const int CIRCLE_IN = 2;\nstatic const int CIRCLE_CROSS = 3;\n\nclass Circle{\npublic:\n Point c;\n double r;\n Circle(Point c = Point(), double r = 0.0): c(c), r(r){}\n};\n\ndouble norm( Vector a ){ return a.x*a.x + a.y*a.y; }\ndouble abs( Vector a ){ return sqrt(norm(a)); }\nPoint polar( double a, double r ){ return Point(cos(r)*a, sin(r)*a);}\ndouble getDistance( Vector a, Vector b ){ return abs(a - b); }\ndouble dot( Vector a, Vector b ){ return a.x*b.x + a.y*b.y; }\ndouble cross( Vector a, Vector b ){ return a.x*b.y - a.y*b.x; }\n\nPoint project( Segment s, Point p ){\n Vector base = s.p2 - s.p1;\n double t = dot(p - s.p1, base)/norm(base);\n return s.p1 + base*t;\n}\n\ndouble getAngle(Point p){\n double polar = atan2(p.y, p.x);\n return (dle(0, polar))? polar : 2.0*acos(-1)+polar;\n}\n\nint isIntersect(Circle c1, Circle c2){\n double d = abs(c1.c - c2.c);\n if ( c1.r + c2.r < d ) return CIRCLE_NON; // no overlap\n if ( d + c2.r < c1.r ) return CIRCLE_IN; // c1 includes c2\n if ( d + c1.r < c2.r ) return CIRCLE_OUT; // c2 includes c1\n return CIRCLE_CROSS;\n}\n\ndouble getDistanceLP(Line s, Point p){\n return abs(cross(s.p2 - s.p1, p - s.p1)/abs(s.p2 - s.p1));\n}\n\ndouble arg(Vector p){\n return atan2(p.y, p.x);\n}\n\npair<Point, Point> getCrossPoints(Circle c1, Circle c2){\n assert( isIntersect( c1, c2 ) );\n double d = abs(c1.c - c2.c);\n double a = acos((c1.r*c1.r+d*d-c2.r*c2.r)/(2*c1.r*d));\n double t = arg(c2.c - c1.c);\n return make_pair(c1.c+polar(c1.r, t+a), c1.c+polar(c1.r, t-a));\n}\n\nbool isIntersect( Circle c1, Line l ){\n double d = getDistanceLP(l, c1.c);\n return ( equals(d, c1.r) || d < c1.r );\n}\n\npair<Point, Point> getCrossPoints(Circle c, Line l ){\n assert( isIntersect( c, l ) );\n Vector pr = project(l, c.c);\n Vector e = (l.p2 - l.p1)/abs(l.p2 - l.p1);\n double base = sqrt(c.r*c.r - norm(pr-c.c));\n return make_pair(pr + e*base, pr - e*base);\n}\n\nCircle C[100];\nint n;\n\nvoid compute(){\n vector<Point> candidates;\n vector<double> Y; \n\n Y.push_back(-100.0);\n Y.push_back(100.0);\n\n for ( int i = 0; i < n; i++ ){\n Y.push_back(C[i].c.y - C[i].r);\n Y.push_back(C[i].c.y + C[i].r);\n }\n \n for ( int i = 0; i < n-1; i++ ){\n for ( int j = i+1; j < n; j++ ){\n if ( isIntersect(C[i], C[j]) != CIRCLE_CROSS ) continue;\n pair<Point, Point> pp = getCrossPoints(C[i], C[j]);\n Y.push_back(pp.first.y);\n Y.push_back(pp.second.y);\n }\n }\n\n sort(Y.begin(), Y.end());\n\n for ( int k = 0; k < Y.size()-1; k++ ){\n double my = (Y[k+1] + Y[k])/2;\n Line l = Line(Point(-100, my), Point(100, my));\n vector<double> X;\n X.push_back(-100);\n X.push_back(100);\n for ( int i = 0; i < n; i++ ){\n if ( !isIntersect(C[i], l) ) continue;\n pair<Point, Point> pp = getCrossPoints(C[i], l);\n X.push_back(pp.first.x);\n X.push_back(pp.second.x);\n }\n sort(X.begin(), X.end());\n\n for ( int i = 0; i < X.size()-1; i++ ){\n candidates.push_back(Point((X[i+1]+X[i])/2, my));\n }\n }\n\n int ans = 0;\n for ( int i = 0; i < n; i++ ){\n for ( int c = 0; c < candidates.size(); c++ ){\n Point t = candidates[c];\n bool f = true;\n if ( abs(C[i].c - t) > C[i].r ) {\n\tcontinue;\n }\n for ( int j = i+1; j < n; j++ ){\n\tif ( dle(abs(C[j].c - t), C[j].r) ) {\n\t f = false;\n\t break;\n\t}\n }\n if ( f ) {\n\tans++;\n\tbreak;\n }\n }\n }\n\n printf(\"%d\\n\", ans);\n}\n\nint main(){\n double x, y, r;\n while(1){\n cin >> n;\n if ( n == 0 ) break;\n for ( int i = 0; i < n; i++ ){\n cin >> x >> y >> r; C[i] = Circle( Point(x, y), r);\n }\n compute();\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3360, "score_of_the_acc": -1.478, "final_rank": 4 } ]
aoj_1234_cpp
Problem C: GIGA Universe Cup Following FIFA World Cup, a larger competition called ``GIGA Universe Cup'' is taking place somewhere in our universe. Both FIFA World Cup and GIGA Universe Cup are two rounds competitions that consist of the first round, also known as ``group league,'' and the second called ``final tournament.'' In the first round, participating teams are divided into groups of four teams each. Each team in a group plays a match against each of the other teams in the same group. For example, let's say we have a group of the following four teams, ``Engband, Swedon, Argontina, and Nigerua.'' They play the following six matches: Engband - Swedon, Engband - Argontina, Engband - Nigerua, Swedon - Argontina, Swedon - Nigerua, and Argontina - Nigerua. The result of a single match is shown by the number of goals scored by each team, like ``Engband 1 - 0 Argontina,'' which says Engband scored one goal whereas Argontina zero. Based on the result of a match, points are given to the two teams as follows and used to rank teams. If a team wins a match (i.e., scores more goals than the other), three points are given to it and zero to the other. If a match draws (i.e., the two teams score the same number of goals), one point is given to each. The goal difference of a team in given matches is the total number of goals it scored minus the total number of goals its opponents scored in these matches. For example, if we have three matches ``Swedon 1 - 2 Engband,'' ``Swedon 3 - 4 Nigerua,'' and ``Swedon 5 - 6 Argontina,'' then the goal difference of Swedon in these three matches is (1 + 3 + 5) - (2 + 4+ 6) = -3. Given the results of all the six matches in a group, teams are ranked by the following criteria, listed in the order of priority (that is, we first apply (a) to determine the ranking, with ties broken by (b), with ties broken by (c), and so on). (a) greater number of points in all the group matches; (b) greater goal difference in all the group matches; (c) greater number of goals scored in all the group matches. If two or more teams are equal on the basis of the above three criteria, their place shall be determined by the following criteria, applied in this order: (d) greater number of points obtained in the group matches between the teams concerned; (e) greater goal difference resulting from the group matches between the teams concerned; (f) greater number of goals scored in the group matches between the teams concerned; If two or more teams are stiIl equal, apply (d), (e), and (f) as necessary to each such group. Repeat this until those three rules to equal teams do not make any further resolution. Finally, teams that still remain equal are ordered by: (g) drawing lots by the Organizing Committee for the GIGA Universe Cup. The two teams coming first and second in each group qualify for the second round. Your job is to write a program which, given the results of matches played so far in a group and one team specified in the group, calculates the ...(truncated)
[ { "submission_id": "aoj_1234_4943973", "code_snippet": "#include <stdio.h>\n#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n#define Inf 1000000000\n\nvector<double> p(9);\n\nvector<vector<string>> get(vector<pair<pair<string,string>,pair<int,int>>> S){\n\n\tmap<string,vector<int>> mp;\n\tvector<int> base(3,0);\n\trep(i,S.size()){\n\t\tmp[S[i].first.first]=base;\n\t\tmp[S[i].first.second]=base;\n\t}\n\t\n\trep(i,S.size()){\n\t\tstring TeamA = S[i].first.first;\n\t\tstring TeamB = S[i].first.second;\n\t\tint A = S[i].second.first;\n\t\tint B = S[i].second.second;\n\t\t\n\t\tif(A==B){\n\t\t\tmp[TeamA][0]++;\n\t\t\tmp[TeamB][0]++;\n\t\t}\n\t\telse if(A>B){\n\t\t\tmp[TeamA][0]+=3;\n\t\t}\n\t\telse{\n\t\t\tmp[TeamB][0]+=3;\n\t\t}\n\t\t\n\t\tmp[TeamA][1]+=A-B;\n\t\tmp[TeamB][1]+=B-A;\n\t\t\n\t\tmp[TeamA][2]+=A;\n\t\tmp[TeamB][2]+=B;\n\t}\n\t\n\tvector<pair<vector<int>,string>> V;\n\tfor(auto a:mp){\n\t\tV.emplace_back(a.second,a.first);\n\t}\n\t\n\tsort(V.rbegin(),V.rend());\n\t\n\tvector<vector<string>> ret;\n\trep(i,V.size()){\n\t\tif(i==0 || V[i-1].first!=V[i].first){\n\t\t\tret.push_back(vector<string>(1,V[i].second));\n\t\t}\n\t\telse ret.back().push_back(V[i].second);\n\t}\n\t\n\tif(ret.size()==1)return ret;\n\tvector<vector<string>> temp;\n\trep(i,ret.size()){\n\t\tif(ret[i].size()==1){\n\t\t\ttemp.push_back(ret[i]);\n\t\t\tcontinue;\n\t\t}\n\t\tsort(ret[i].begin(),ret[i].end());\n\t\tvector<pair<pair<string,string>,pair<int,int>>> nS;\n\t\trep(j,S.size()){\n\t\t\tstring x = S[j].first.first,y = S[j].first.second;\n\t\t\tif(binary_search(ret[i].begin(),ret[i].end(),x)&&binary_search(ret[i].begin(),ret[i].end(),y)){\n\t\t\t\tnS.push_back(S[j]);\n\t\t\t}\n\t\t}\n\t\tvector<vector<string>> X = get(nS);\n\t\trep(j,X.size()){\n\t\t\ttemp.push_back(X[j]);\n\t\t}\n\t}\n\t\n\treturn temp;\n\t\n}\n\ndouble get(vector<string> S){\n\tvector<string> names(4);\n\tstring target;\n\trep(i,4){\n\t\tnames[i] = S[i+1].substr(1,3);\n\t\tif(S[i+1][0]=='*'){\n\t\t\ttarget = names[i];\n\t\t}\n\t}\n\n\tvector<pair<pair<string,string>,pair<int,int>>> matches;\n\tvector<int> emp;\n\trep(i,4){\n\t\trep(j,4){\n\t\t\tif(i>=j)continue;\n\t\t\tchar c0 = S[i+1][6+j*5],c1 = S[i+1][6+j*5+2];\n\t\t\tif(c0=='_'){\n\t\t\t\temp.push_back(matches.size());\n\t\t\t\tmatches.emplace_back(make_pair(names[i],names[j]),make_pair(-1,-1));\n\t\t\t}\n\t\t\telse matches.emplace_back(make_pair(names[i],names[j]),make_pair(c0-'0',c1-'0'));\n\t\t}\n\t}\n\n\tdouble ret = 0.0;\n\trep(i,9){\n\t\trep(j,9){\n\t\t\trep(k,9){\n\t\t\t\trep(l,9){\n\t\t\t\t\t\n\t\t\t\t\tmatches[emp[0]].second.first = i;\n\t\t\t\t\tmatches[emp[0]].second.second = j;\n\t\t\t\t\tmatches[emp[1]].second.first = k;\n\t\t\t\t\tmatches[emp[1]].second.second = l;\n\t\t\t\t\tdouble P = p[i]*p[j]*p[k]*p[l];\n\t\t\t\t\tvector<string> temp;\n\t\t\t\t\tvector<vector<string>> result = get(matches);\n\t\t\t\t\tif(result[0].size()==1){\n\t\t\t\t\t\tif(result[0][0]==target){\n\t\t\t\t\t\t\tret += P;\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse{\n\t\t\t\t\t\t\ttemp = result[1];\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse temp = result[0];\n\t\t\t\t\t\n\t\t\t\t\tbool f = false;\n\t\t\t\t\trep(x,temp.size()){\n\t\t\t\t\t\tif(temp[x]==target){\n\t\t\t\t\t\t\tf=true;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif(f){\n\t\t\t\t\t\tif(result[0].size()==1)ret += P / (double)temp.size();\n\t\t\t\t\t\telse{\n\t\t\t\t\t\t\tdouble s = temp.size();\n\t\t\t\t\t\t\tret += P * (1.0-(s-1.0) * (s-2.0) / s / (s-1.0));\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\t\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t\n\treturn ret;\n\t\n}\n\nint main(){\n\t\n\trep(i,9){\n\t\tp[i] = pow(0.25,i);\n\t\tp[i] *= pow(0.75,8-i);\n\t\trep(j,8){\n\t\t\tp[i] *= j+1;\n\t\t}\n\t\trep(j,i){\n\t\t\tp[i] /= j+1;\n\t\t}\n\t\trep(j,8-i){\n\t\t\tp[i] /= j+1;\n\t\t}\n\t}\n\t\n\tint t;\n\tcin>>t;\n\t\n\trep(_,t){\n\t\tvector<string> S(5);\n\t\trep(i,5)cin>>S[i];\n\t\t\n\t\tcout<<fixed<<setprecision(10)<<get(S)<<endl;\n\t}\n\t\n return 0;\n}", "accuracy": 1, "time_ms": 1040, "memory_kb": 3800, "score_of_the_acc": -1.1914, "final_rank": 19 }, { "submission_id": "aoj_1234_4868319", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint M[4][4];\ndouble score[9];\ndouble p;\n\nint check(int n,vector<int> a,int id){\n\tint m=a.size();\n\tvector<int> P(m),GD(m),GS(m);\n\tfor(int i=0;i<m;i++){\n\t\tfor(int j=i+1;j<m;j++){\n\t\t\tint k=a[i],l=a[j];\n\t\t\tif(M[k][l]>M[l][k])P[i]+=3;\n\t\t\telse if(M[k][l]==M[l][k])P[i]++,P[j]++;\n\t\t\telse P[j]+=3;\n\t\t\tGD[i]+=M[k][l]-M[l][k],GD[j]+=M[l][k]-M[k][l];\n\t\t\tGS[i]+=M[k][l],GS[j]+=M[l][k];\n\t\t}\n\t}\n\tvector<pair<pair<int,int>,pair<int,int>>> v;\n\tfor(int i=0;i<m;i++){\n\t\tv.push_back(make_pair(make_pair(P[i],GD[i]),make_pair(GS[i],a[i])));\n\t}\n\tsort(v.rbegin(), v.rend());\n\tint cnt=0; bool flag=false;\n\tvector<int> na;\n\tfor(int i=0;i<m;i++){\n\t\tif(v[i].first.first==v[0].first.first and v[i].first.second==v[0].first.second and v[i].second.first==v[0].second.first){\n\t\t\tcnt++; na.push_back(v[i].second.second);\n\t\t\tif(v[i].second.second==id)flag=true;\n\t\t}\n\t}\n\tif(cnt<=n and flag)return 1;\n\tif(cnt>=n and !flag)return 0;\n\tif(cnt==1 and n==2 and !flag){\n\t\tna.pop_back();\n\t\tfor(int i=1;i<m;i++){\n\t\t\tif(v[i].first.first==v[1].first.first and v[i].first.second==v[1].first.second and v[i].second.first==v[1].second.first){\n\t\t\t\tna.push_back(v[i].second.second);\n\t\t\t\tif(v[i].second.second==id)flag=true;\n\t\t\t}\n\t\t}\n\t\tif(!flag)return 0;\n\t\telse if(na.size()==1)return 1;\n\t\telse return check(1,na,id);\n\t}\n\telse{\n\t\tif(m==(int)na.size()){\n\t\t\tp*=(double)n;\n\t\t\treturn (int)na.size();\n\t\t}\n\t\telse return check(n,na,id);\n\t}\n}\n\nvoid solve(){\n\tstring T; cin >> T;\n\tint id=-1;\n\tfor(int i=0,j=0;i<4&&j<T.size();){\n\t\tif(T[j]=='_')j++;\n\t\telse if(T[j]=='*')id=i,j++;\n\t\telse i++,j+=3;\n\t}\n\tvector<string> s(4);\n\tfor(int i=0;i<4;i++) cin >> s[i];\n\tvector<int> r;\n\tfor(int i=0;i<4;i++){\n\t\tfor(int j=i+1;j<4;j++){\n\t\t\tif(s[i][j*5+6]=='_'){\n\t\t\t\tr.push_back(i);r.push_back(j);\n\t\t\t}\n\t\t\telse{\n\t\t\t\tint s1=s[i][j*5+6]-'0', s2=s[i][j*5+8]-'0';\n\t\t\t\tM[i][j]=s1, M[j][i]=s2;\n\t\t\t}\n\t\t}\n\t}\n\tdouble res=0.0;\n\tfor(int i=0;i<=8;i++){\n\t\tfor(int j=0;j<=8;j++){\n\t\t\tfor(int k=0;k<=8;k++){\n\t\t\t\tfor(int l=0;l<=8;l++){\n\t\t\t\t\tp=score[i]*score[j]*score[k]*score[l];\n\t\t\t\t\tM[r[0]][r[1]]=i,M[r[1]][r[0]]=j,M[r[2]][r[3]]=k,M[r[3]][r[2]]=l;\n\t\t\t\t\tvector<int> a={0,1,2,3};\n\t\t\t\t\tint t=check(2,a,id);\n\t\t\t\t\tif(t){\n\t\t\t\t\t\tp/=(double)t;\n\t\t\t\t\t\tres+=p;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%.7f\\n\",res);\n}\n\nint main(){\n\t// 前計算\n\tconst int base=1*2*3*4*5*6*7*8;\n\tfor(int i=0;i<=8;i++){\n\t\tdouble res=base;\n\t\tfor(int j=1;j<=i;j++){\n\t\t\tres/=(double)j;\n\t\t\tres*=(0.25);\n\t\t}\n\t\tfor(int j=1;j<=8-i;j++){\n\t\t\tres/=(double)j;\n\t\t\tres*=(0.75);\n\t\t}\n\t\tscore[i]=res;\n\t}\n\tint q; cin >> q;\n\twhile(q--)solve();\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 3136, "score_of_the_acc": -0.072, "final_rank": 2 }, { "submission_id": "aoj_1234_4811441", "code_snippet": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <stack>\n#include <algorithm>\n#include <cmath>\n#include <queue>\n#include <bitset>\n#include <iomanip>\n#include <limits>\n#include <chrono>\n#include <random>\n#include <array>\n#include <unordered_map>\n#include <functional>\n#include <complex>\n#include <numeric>\n#include <cctype>\n#include <map>\n#include <set>\n#include <cstdlib>\n#include <bitset>\n#include <tuple>\n#include <assert.h>\n#include <deque>\n#include <utility>\n\n\nusing namespace std;\ntypedef long long ll;\n\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\ntemplate<typename T> T gcd(T a, T b) { a = abs(a), b = abs(b); while (b > 0) { tie(a, b) = make_pair(b, a % b); } return a; }\n//mt19937 rnd(chrono::steady_clock::now().time_since_epoch().count());\n\nconstexpr long long INF = 1LL << 60;\nconstexpr int inf = 1000000007;\nconstexpr long long mod = 1000000007LL;\n//constexpr long long mod = 998244353LL;\n\nusing Real = double;\nvector<int> hidx = { 1,1,1,2,2,3 };\nvector<int> widx = { 11,16,21,16,21,21 };\nvector<Real> p(10);\nint tidx[50][50];\n\nstruct Data {\n\tint score, diff, goal, id;\n\tData() = default;\n\tData(int score, int diff, int goal, int id) :score(score), diff(diff), goal(goal), id(id) {}\n\tbool operator<(const Data& d)const {\n\t\treturn make_tuple(score, diff, goal) < make_tuple(d.score, d.diff, d.goal);\n\t}\n\tbool operator>(const Data& d)const {\n\t\treturn make_tuple(score, diff, goal) > make_tuple(d.score, d.diff, d.goal);\n\t}\n\tbool operator==(const Data& d)const {\n\t\treturn make_tuple(score, diff, goal) == make_tuple(d.score, d.diff, d.goal);\n\t}\n};\n\nvoid calc_data(Data& a, Data& b, int af, int bf) {\n\ta.diff += af - bf;\n\tb.diff += bf - af;\n\ta.goal += af;\n\tb.goal += bf;\n\tif (af == bf) {\n\t\ta.score += 1;\n\t\tb.score += 1;\n\t}\n\telse if (af > bf) {\n\t\ta.score += 3;\n\t}\n\telse {\n\t\tb.score += 3;\n\t}\n}\nReal calc(array<string, 5>& vs, int my) {\n\tvector<bool> bad(4); int cnt = 0;\n\tbool tw = false;\n\t{\n\t\tvector<Data> d(4); for (int i = 0; i < 4; i++) d[i].id = i;\n\t\tfor (int i = 0; i < 6; i++) {\n\t\t\tint f = vs[hidx[i]][widx[i]] - '0';\n\t\t\tint s = vs[hidx[i]][widx[i] + 2] - '0';\n\t\t\tint fi = tidx[hidx[i]][widx[i]];\n\t\t\tint si = tidx[hidx[i]][widx[i] + 2];\n\t\t\tcalc_data(d[fi], d[si], f, s);\n\t\t}\n\t\tsort(d.rbegin(), d.rend());\n\n\t\tif (d[0] == d.back()) return 0.5;\n\t\telse if (d[0] == d[2]) {\n\t\t\tif (d[3].id == my) return 0.0;\n\t\t\tcnt = 2;\n\t\t\tbad[d[3].id] = true;\n\t\t}\n\t\telse if (d[0] == d[1]) {\n\t\t\tif (d[0].id == my or d[1].id == my) return 1.0;\n\t\t\telse return 0.0;\n\t\t}\n\t\telse {\n\t\t\tif (d[0].id == my) return 1.0;\n\t\t\tif (d[1] > d[2]) {\n\t\t\t\tif (d[1].id == my) return 1.0;\n\t\t\t\telse return 0.0;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (d[2] > d[3]) {\n\t\t\t\t\tif (d[3].id == my) return 0.0;\n\t\t\t\t\tcnt = 1;\n\t\t\t\t\tbad[d[0].id] = true;\n\t\t\t\t\tbad[d[3].id] = true;\n\t\t\t\t\ttw = true;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tcnt = 1;\n\t\t\t\t\tbad[d[0].id] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif (!tw) {\n\t\tvector<Data> d(4);\n\t\tfor (int i = 0; i < 4; i++) {\n\t\t\td[i].id = i;\n\t\t\tif (bad[i]) d[i].score -= 100000;\n\t\t}\n\t\tfor (int i = 0; i < 6; i++) {\n\t\t\tint f = vs[hidx[i]][widx[i]] - '0';\n\t\t\tint s = vs[hidx[i]][widx[i] + 2] - '0';\n\t\t\tint fi = tidx[hidx[i]][widx[i]];\n\t\t\tint si = tidx[hidx[i]][widx[i] + 2];\n\t\t\tif (bad[fi] or bad[si]) continue;\n\t\t\tcalc_data(d[fi], d[si], f, s);\n\t\t}\n\t\tsort(d.rbegin(), d.rend());\n\t\td.pop_back();\n\t\tif (d[0] == d.back()) return (Real)cnt / 3.0;\n\t\telse if (d[0] == d[1]) {\n\t\t\tif (d[2].id == my) return 0.0;\n\t\t\telse if (cnt == 2) return 1.0;\n\t\t\telse {\n\t\t\t\ttw = true;\n\t\t\t\tbad[d[2].id] = true;\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tif (d[0].id == my) return 1.0;\n\t\t\telse if (cnt == 1) return 0.0;\n\t\t\telse {\n\t\t\t\tif (d[1] > d[2]) {\n\t\t\t\t\tif (d[1].id == my) return 1.0;\n\t\t\t\t\telse return 0.0;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tcnt = 1;\n\t\t\t\t\ttw = true;\n\t\t\t\t\tbad[d[0].id] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tvector<Data> d(4);\n\tfor (int i = 0; i < 4; i++) {\n\t\td[i].id = i;\n\t\tif (bad[i]) d[i].score -= 100000;\n\t}\n\tfor (int i = 0; i < 6; i++) {\n\t\tint f = vs[hidx[i]][widx[i]] - '0';\n\t\tint s = vs[hidx[i]][widx[i] + 2] - '0';\n\t\tint fi = tidx[hidx[i]][widx[i]];\n\t\tint si = tidx[hidx[i]][widx[i] + 2];\n\t\tif (bad[fi] or bad[si]) continue;\n\t\tcalc_data(d[fi], d[si], f, s);\n\t}\n\tsort(d.rbegin(), d.rend());\n\td.pop_back(); d.pop_back();\n\tif (d[0] == d[1]) return 1.0 / 2.0;\n\telse if (d[0].id == my) return 1.0;\n\telse return 0.0;\n}\n\n\nvoid solve() {\n\tarray<string, 5> vs; for (int i = 0; i < 5; i++) cin >> vs[i];\n\tvector<pair<int, int>> r;\n\tint my = -1;\n\tfor (int i = 1; i < 5; i++) if (vs[i][0] == '*') my = i - 1;\n\tReal res = 0.0;\n\tfor (int i = 0; i < 6; i++) {\n\t\tif (vs[hidx[i]][widx[i]] == '_') {\n\t\t\tr.emplace_back(hidx[i], widx[i]);\n\t\t\tr.emplace_back(hidx[i], widx[i] + 2);\n\t\t}\n\t}\n\tint t[4];\n\tfor (t[0] = 0; t[0] < 9; t[0]++)for (t[1] = 0; t[1] < 9; t[1]++)for (t[2] = 0; t[2] < 9; t[2]++) for (t[3] = 0; t[3] < 9; t[3]++) {\n\t\tfor (int i = 0; i < 4; i++) vs[r[i].first][r[i].second] = (char)('0' + t[i]);\n\t\tres += calc(vs, my) * p[t[0]] * p[t[1]] * p[t[2]] * p[t[3]];\n\t\tfor (int i = 0; i < 4; i++) vs[r[i].first][r[i].second] = '_';\n\t}\n\tcout << fixed << setprecision(12) << res << \"\\n\";\n}\nint main()\n{\n\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\n\tvector<Real> f(10); f[0] = f[1] = 1; for (int i = 2; i < 10; i++) f[i] = f[i - 1] * i;\n\tfor (int i = 0; i < 9; i++) {\n\t\tp[i] = f[8] / (f[i] * f[8 - i]) * pow(0.25, i) * pow(0.75, 8 - i);\n\t}\n\tfor (int i = 0; i < 6; i++) {\n\t\ttidx[hidx[i]][widx[i]] = hidx[i] - 1;\n\t\ttidx[hidx[i]][widx[i] + 2] = (widx[i] - 6) / 5;\n\t}\n\tint kkt; cin >> kkt; while (kkt--) solve();\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3416, "score_of_the_acc": -0.4419, "final_rank": 14 }, { "submission_id": "aoj_1234_4806732", "code_snippet": "#include \"iostream\"\n#include \"climits\"\n#include \"list\"\n#include \"queue\"\n#include \"stack\"\n#include \"set\"\n#include \"functional\"\n#include \"algorithm\"\n#include \"string\"\n#include \"map\"\n#include \"unordered_map\"\n#include \"unordered_set\"\n#include \"iomanip\"\n#include \"cmath\"\n#include \"random\"\n#include \"bitset\"\n#include \"cstdio\"\n#include \"numeric\"\n#include \"cassert\"\n#include \"ctime\"\n\nusing namespace std;\n\nconstexpr long long int MOD = 1000000007;\n//constexpr int MOD = 1000000007;\n//constexpr int MOD = 998244353;\n//constexpr long long int MOD = 998244353;\nconstexpr double EPS = 1e-12;\n\n//int N, M, K, T, H, W, L, R;\nlong long int N, M, K, T, H, W, L, R;\n\nvector<long double>p(9);\n\nstruct Team {\n\tvector<int>a, b, c;\n\tint index;\n\tTeam() {\n\t\ta.resize(4);\n\t\tb.resize(4);\n\t\tc.resize(4);\n\t}\n};\n\nint Check_min(Team s, Team t, int bit = 15) {\n\tint sa, sb, sc, ta, tb, tc;\n\tsa = sb = sc = ta = tb = tc = 0;\n\tfor (int i = 0; i < 4; i++) {\n\t\tfor (int j = 0; j < 4; j++) {\n\t\t\tif ((bit >> j) & 1) {\n\t\t\t\tsa += s.a[j];\n\t\t\t\tsb += s.b[j];\n\t\t\t\tsc += s.c[j];\n\t\t\t\tta += t.a[j];\n\t\t\t\ttb += t.b[j];\n\t\t\t\ttc += t.c[j];\n\t\t\t}\n\t\t}\n\t}\n\tauto sbox = make_pair(sa, make_pair(sb, sc));\n\tauto tbox = make_pair(ta, make_pair(tb, tc));\n\tif (sbox < tbox)return 0;\n\tif (sbox == tbox)return 1;\n\treturn 2;\n}\n\nlong double Check(vector<vector<int>>plus, vector<pair<int, int>>vp, vector<int>num, int cnt) {\n\tfor (int i = 0; i < 4; i++) {\n\t\tplus[vp[i].first][vp[i].second] = num[i];\n\t}\n\tvector<Team>team(4);\n\tfor (int i = 0; i < 4; i++) {\n\t\tteam[i].index = i;\n\t\tfor (int j = i + 1; j < 4; j++) {\n\t\t\tteam[i].b[j] += plus[i][j];\n\t\t\tteam[i].b[j] -= plus[j][i];\n\t\t\tteam[j].b[i] += plus[j][i];\n\t\t\tteam[j].b[i] -= plus[i][j];\n\t\t\tteam[i].c[j] += plus[i][j];\n\t\t\tteam[j].c[i] += plus[j][i];\n\t\t\tif (plus[i][j] > plus[j][i]) {\n\t\t\t\tteam[i].a[j] = 3;\n\t\t\t}\n\t\t\telse if (plus[i][j] == plus[j][i]) {\n\t\t\t\tteam[i].a[j] = team[j].a[i] = 1;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tteam[j].a[i] = 3;\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = 0; i < 4; i++) {\n\t\tfor (int j = 0; j < 3; j++) {\n\t\t\tauto c = Check_min(team[j], team[j + 1]);\n\t\t\tif (c == 0)swap(team[j], team[j + 1]);\n\t\t}\n\t}\n\tif (Check_min(team[0], team[3]) == 1)return 0.5;\n\tif (Check_min(team[0], team[2]) == 1) {\n\t\tif (team[3].index == cnt)return 0;\n\t\tint bit = 0;\n\t\tfor (int i = 0; i < 3; i++) {\n\t\t\tbit |= 1 << team[i].index;\n\t\t}\n\t\tfor (int i = 0; i < 3; i++) {\n\t\t\tfor (int j = 0; j < 2; j++) {\n\t\t\t\tif (Check_min(team[j], team[j + 1], bit) == 0)swap(team[j], team[j + 1]);\n\t\t\t}\n\t\t}\n\t\tif (Check_min(team[0], team[2], bit) == 1)return (long double)2 / 3;\n\t\tif (Check_min(team[0], team[1], bit) == 1) {\n\t\t\tif (team[2].index == cnt)return 0;\n\t\t\treturn 1;\n\t\t}\n\t\tif (Check_min(team[1], team[2]) == 1) {\n\t\t\tif (team[0].index == cnt)return 1;\n\t\t\tbit = 1 << team[1].index;\n\t\t\tbit |= 1 << team[2].index;\n\t\t\tif (Check_min(team[1], team[2], bit) == 0)swap(team[1], team[2]);\n\t\t\tif (Check_min(team[1], team[2], bit) == 1)return 0.5;\n\t\t\tif (team[1].index == cnt)return 1;\n\t\t\treturn 0;\n\t\t}\n\t\tif (team[2].index == cnt)return 0;\n\t\treturn 1;\n\t}\n\tif (Check_min(team[1], team[3]) == 1) {\n\t\tif (team[0].index == cnt)return 1;\n\t\tint bit = 0;\n\t\tfor (int i = 1; i < 4; i++) {\n\t\t\tbit |= 1 << team[i].index;\n\t\t}\n\t\tfor (int i = 0; i < 3; i++) {\n\t\t\tfor (int j = 1; j < 3; j++) {\n\t\t\t\tif (Check_min(team[j], team[j + 1], bit) == 0)swap(team[j], team[j + 1]);\n\t\t\t}\n\t\t}\n\t\tif (Check_min(team[1], team[3], bit) == 1)return (long double)1 / 3;\n\t\tif (Check_min(team[2], team[3], bit) == 1) {\n\t\t\tif (team[1].index == cnt)return 1;\n\t\t\treturn 0;\n\t\t}\n\t\tif (Check_min(team[1], team[2]) == 1) {\n\t\t\tif (team[3].index == cnt)return 0;\n\t\t\tbit = 1 << team[1].index;\n\t\t\tbit |= 1 << team[2].index;\n\t\t\tif (Check_min(team[1], team[2], bit) == 0)swap(team[1], team[2]);\n\t\t\tif (Check_min(team[1], team[2], bit) == 1)return 0.5;\n\t\t\tif (team[1].index == cnt)return 1;\n\t\t\treturn 0;\n\t\t}\n\t\tif (team[1].index == cnt)return 1;\n\t\treturn 0;\n\t}\n\tif (Check_min(team[1], team[2]) == 1) {\n\t\tif (team[0].index == cnt)return 1;\n\t\tif (team[3].index == cnt)return 0;\n\t\tint bit = 1 << team[1].index;\n\t\tbit |= 1 << team[2].index;\n\t\tif (Check_min(team[1], team[2], bit) == 1)return 0.5;\n\t\tif (Check_min(team[1], team[2], bit) == 0)swap(team[1], team[2]);\n\t\tif (team[1].index == cnt)return 1;\n\t\treturn 0;\n\t}\n\tif (team[0].index == cnt || team[1].index == cnt)return 1;\n\treturn 0;\n}\n\nlong double Solve() {\n\tvector<string>s(5);\n\tfor (auto &i : s)cin >> i;\n\tint cnt = -1;\n\tfor (int i = 1; i < s.size(); i++) {\n\t\tif (s[i][0] == '*')cnt = i - 1;\n\t}\n\tvector<vector<int>>plus(4, vector<int>(4));\n\tvector<pair<int, int>>vp;\n\tfor (int i = 0; i < 4; i++) {\n\t\tfor (int j = i + 1; j < 4; j++) {\n\t\t\tif (s[i + 1][j * 5 + 6] == '_') {\n\t\t\t\tvp.push_back({ i,j });\n\t\t\t\tvp.push_back({ j,i });\n\t\t//\t\tcout << i << \" \" << j << endl;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tplus[i][j] = s[i + 1][j * 5 + 6] - '0';\n\t\t\t\tplus[j][i] = s[i + 1][j * 5 + 8] - '0';\n\t\t\t}\n\t\t}\n\t}\n\tvector<int>num(4);\n\tlong double ret = 0;\n\twhile (num[0] < 9) {\n\t\tauto by = Check(plus, vp, num, cnt);\n\t\tret += p[num[0]] * p[num[1]] * p[num[2]] * p[num[3]] * by;\n\t\tnum.back()++;\n\t\tint c = 3;\n\t\twhile (c&&num[c] > 8) {\n\t\t\tnum[c--] = 0;\n\t\t\tnum[c]++;\n\t\t}\n\t}\n\treturn ret;\n}\n\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\n\tfor (int i = 0; i <= 8; i++) {\n\t\tp[i] = 1;\n\t\tfor (int j = 2; j <= 8; j++)p[i] *= j;\n\t\tfor (int j = 1; j <= i; j++) {\n\t\t\tp[i] /= j;\n\t\t}\n\t\tfor (int j = 1; j <= 8 - i; j++) {\n\t\t\tp[i] /= j;\n\t\t\tp[i] *= 3;\n\t\t}\n\t\tfor (int j = 1; j <= 8; j++)p[i] /= 4;\n\t}\n\tcin >> T;\n\twhile (T--) {\n\t\tauto box = Solve();\n\t\tcout << setprecision(20) << box << endl;\n\t}\n}", "accuracy": 1, "time_ms": 2120, "memory_kb": 3308, "score_of_the_acc": -0.6872, "final_rank": 18 }, { "submission_id": "aoj_1234_4765387", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n cout << fixed << setprecision(7);\n vector<int> fact(9);\n fact[0] = 1;\n for (int i = 1; i < 9; i++){\n fact[i]= fact[i - 1] * i;\n }\n vector<double> p(9);\n for (int i = 0; i < 9; i++){\n p[i] = (double) fact[8] / fact[i] / fact[8 - i] * pow(0.25, i) * pow(0.75, 8 - i);\n }\n int t;\n cin >> t;\n for (int i = 0; i < t; i++){\n vector<string> S(5);\n for (int j = 0; j < 5; j++){\n cin >> S[j];\n }\n vector<vector<int>> score(4, vector<int>(4, -1));\n for (int j = 0; j < 4; j++){\n for (int k = j + 1; k < 4; k++){\n char c1 = S[j + 1][k * 5 + 6];\n if (c1 != '_'){\n score[j][k] = c1 - '0';\n }\n char c2 = S[j + 1][k * 5 + 8];\n if (c2 != '_'){\n score[k][j] = c2 - '0';\n }\n }\n }\n vector<pair<int, int>> s;\n for (int j = 0; j < 4; j++){\n for (int k = 0; k < 4; k++){\n if (j != k){\n if (score[j][k] == -1){\n s.push_back(make_pair(j, k));\n }\n }\n }\n }\n int team;\n for (int j = 0; j < 4; j++){\n if (S[j + 1][0] == '*'){\n team = j;\n }\n }\n double ans = 0;\n vector<int> r(4);\n for (r[0] = 0; r[0] <= 8; r[0]++){\n for (r[1] = 0; r[1] <= 8; r[1]++){\n for (r[2] = 0; r[2] <= 8; r[2]++){\n for (r[3] = 0; r[3] <= 8; r[3]++){\n double tmp = 1;\n for (int j = 0; j < 4; j++){\n tmp *= p[r[j]];\n }\n vector<vector<int>> result = score;\n for (int j = 0; j < 4; j++){\n result[s[j].first][s[j].second] = r[j];\n }\n vector<set<int>> rank(1);\n for (int j = 0; j < 4; j++){\n rank[0].insert(j);\n }\n while (1){\n bool update = false;\n vector<set<int>> rank2;\n vector<int> points(4, 0);\n vector<int> gdiff(4, 0);\n vector<int> goals(4, 0);\n int cnt = rank.size();\n for (int j = 0; j < cnt; j++){\n int sz = rank[j].size();\n for (int k = 0; k < 4; k++){\n for (int l = k + 1; l < 4; l++){\n if (rank[j].count(k) && rank[j].count(l)){\n if (result[k][l] > result[l][k]){\n points[k] += 3;\n } else if (result[k][l] < result[l][k]){\n points[l] += 3;\n } else {\n points[k]++;\n points[l]++;\n }\n gdiff[k] += result[k][l] - result[l][k];\n gdiff[l] += result[l][k] - result[k][l];\n goals[k] += result[k][l];\n goals[l] += result[l][k];\n }\n }\n }\n map<tuple<int, int, int>, set<int>> mp;\n for (int k : rank[j]){\n mp[make_tuple(points[k], gdiff[k], goals[k])].insert(k);\n }\n if (mp.size() > 1){\n update = true;\n }\n for (auto itr = mp.rbegin(); itr != mp.rend(); itr++){\n rank2.push_back((*itr).second);\n }\n }\n if (!update){\n break;\n } else {\n swap(rank, rank2);\n }\n }\n if (rank[0].count(team)){\n if (rank[0].size() <= 2){\n ans += tmp;\n } else {\n ans += tmp * 2 / rank[0].size();\n }\n } else if (rank[0].size() == 1 && rank[1].count(team)){\n ans += tmp / rank[1].size();\n }\n }\n }\n }\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 1230, "memory_kb": 3412, "score_of_the_acc": -0.6646, "final_rank": 17 }, { "submission_id": "aoj_1234_4745741", "code_snippet": "#include <bits/stdc++.h>\n#define For(i, a, b) for(int (i)=(int)(a); (i)<(int)(b); ++(i))\n#define rFor(i, a, b) for(int (i)=(int)(a)-1; (i)>=(int)(b); --(i))\n#define rep(i, n) For((i), 0, (n))\n#define rrep(i, n) rFor((i), (n), 0)\n#define fi first\n#define se second\nusing namespace std;\ntypedef long long lint;\ntypedef unsigned long long ulint;\ntypedef pair<int, int> pii;\ntypedef pair<lint, lint> pll;\ntemplate<class T> bool chmax(T &a, const T &b){if(a<b){a=b; return true;} return false;}\ntemplate<class T> bool chmin(T &a, const T &b){if(a>b){a=b; return true;} return false;}\ntemplate<class T> T div_floor(T a, T b){\n if(b < 0) a *= -1, b *= -1;\n return a>=0 ? a/b : (a+1)/b-1;\n}\ntemplate<class T> T div_ceil(T a, T b){\n if(b < 0) a *= -1, b *= -1;\n return a>0 ? (a-1)/b+1 : a/b;\n}\n\nconstexpr lint mod = 1000000007;\nconstexpr lint INF = mod * mod;\nconstexpr int MAX = 100010;\n\nint myteam;\npii board[4][4];\ndouble fact[10], prob[10];\ndouble ans;\n\nvector<int> order(int S){\n vector<int> point(4, 0), diff(4, 0), score(4, 0);\n vector<int> id;\n rep(i, 4)if(S>>i & 1) id.push_back(i);\n rep(x, 4)if(S>>x & 1){\n For(y, x+1, 4)if(S>>y & 1){\n int s, t;\n tie(s, t) = board[x][y];\n score[x] += s; score[y] += t;\n diff[x] += s - t; diff[y] += t - s;\n\n if(s > t) point[x] += 3;\n else if(s < t) point[y] += 3;\n else point[x] += 1, point[y] += 1;\n }\n }\n auto cmp = [&](const int &i, const int &j){\n if(point[i] != point[j]) return point[i] > point[j];\n if(diff[i] != diff[j]) return diff[i] > diff[j];\n return score[i] > score[j];\n };\n sort(id.begin(), id.end(), cmp);\n\n vector<int> pri(4, -1);\n int cur = 0;\n for(int l=0; l<(int)id.size();){\n int r = l;\n int T = 0;\n while(r < (int)id.size() && !cmp(id[l], id[r])){\n T |= (1 << id[r]);\n ++r;\n }\n if(r - l == 1 || S == T){\n For(i, l, r) pri[id[i]] = cur;\n ++cur;\n }\n else{\n auto p = order(T);\n int ncur = cur + 1;\n For(i, l, r) pri[id[i]] = cur + p[id[i]], chmax(ncur, pri[id[i]] + 1);\n cur = ncur;\n }\n l = r;\n }\n\n return pri;\n}\n\nvoid dfs(int cur, double p){\n if(cur == 2){\n auto pri = order((1<<4)-1);\n int mypos, cnt[4];\n rep(i, 4) cnt[i] = 0;\n rep(i, 4){\n if(i == myteam) mypos = pri[i];\n ++cnt[pri[i]];\n }\n\n if(mypos == 0) p *= min(1.0, 2.0 / (double)cnt[0]);\n else if(mypos == 1 && (int)cnt[0] < 2){\n p *= 1.0 / (double)cnt[1];\n }\n else p = 0;\n\n ans += p;\n return;\n }\n\n rep(x, 4)For(y, x+1, 4)if(board[x][y].fi < 0){\n rep(s, 9)rep(t, 9){\n board[x][y] = {s, t};\n dfs(cur + 1, p * prob[s] * prob[t]);\n }\n board[x][y] = {-1, -1};\n return;\n }\n}\n\nvoid solve(){\n char gomi, name[5];\n rep(i, 4) scanf(\" %c\", &gomi);\n rep(i, 4){\n rep(j, 5) scanf(\" %c\", &name[j]);\n if(name[1] == '*') myteam = i;\n }\n\n rep(i, 4)rep(j, 4) board[i][j] = {-1, -1};\n rep(i, 4){\n char gomi, result[5];\n rep(k, 4) scanf(\" %c\", &gomi);\n rep(j, 4){\n rep(k, 5) scanf(\" %c\", &result[k]);\n if(isdigit(result[2])){\n board[i][j] = {result[2] - '0', result[4] - '0'};\n }\n }\n }\n\n ans = 0;\n dfs(0, 1.0);\n printf(\"%.10lf\\n\", ans);\n}\n\nint main(){\n fact[0] = 1;\n For(i, 1, 10) fact[i] = fact[i-1] * i;\n rep(p, 9){\n prob[p] = 40320 / fact[p] / fact[8-p] * pow(0.25, p) * pow(0.75, 8-p);\n }\n int t;\n scanf(\"%d\", &t);\n rep(tt, t){\n solve();\n }\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3412, "score_of_the_acc": -0.4536, "final_rank": 15 }, { "submission_id": "aoj_1234_4683852", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef int64_t Int;\n#define all(x) (x).begin(), (x).end()\n \nconst double EPS = 1e-10;\nconst Int INF = 1e18;\nconst int inf = 1e9;\nconst Int mod = 1e9+7;\n\nbool print_space_enable = false;\nvoid print() { \n cout << endl; \n print_space_enable = false;\n}\n\ntemplate <class Head, class... Tail>\nvoid print(Head&& head, Tail&&... tail) {\n if (print_space_enable) cout << \" \";\n cout << fixed << setprecision(7) << head;\n print_space_enable = true;\n print(std::forward<Tail>(tail)...);\n}\n\ntemplate<typename T>\nvoid print(vector<T> v) {\n for (size_t i = 0; i < v.size(); i++) {\n if (i > 0) std::cout << \" \";\n std::cout << v[i];\n }\n std::cout << std::endl;\n}\n\ndouble pro[10];\npair<Int, Int> score[5][5];\n\nvoid calc_pro() {\n double x[10];\n x[0] = x[1] = 1.0;\n for (int i = 1; i <= 8; i++) {\n x[i + 1] = x[i] * (double)(i + 1);\n }\n for (int i = 0; i <= 8; i++) {\n pro[i] = x[8] / (x[i] * x[8 - i]);\n for (int j = 0; j < i; j++) {\n pro[i] *= 1.0 / 4.0;\n }\n for (int j = 0; j < 8 - i; j++) {\n pro[i] *= 3.0 / 4.0;\n }\n }\n}\n\nvoid s(vector<vector<Int>> &v, Int x) {\n for (Int i = 0; i < (Int)v.size(); i++) {\n for (Int j = 0; j < (Int)v.size() - 1; j++) {\n if (v[j][x] < v[j + 1][x]) {\n swap(v[j], v[j + 1]);\n }\n }\n }\n}\n\ndouble f(vector<vector<Int>> v, Int check_team) {\n s(v, 2);\n s(v, 1);\n s(v, 0);\n vector<Int> rank[4];\n rank[0].push_back(v[0][3]);\n Int pre = 0;\n for (Int i = 1; i < 4; i++) {\n if (v[i - 1][0] == v[i][0] and v[i - 1][1] == v[i][1] and v[i - 1][2] == v[i][2]) {\n rank[pre].push_back(v[i][3]);\n } else {\n pre++;\n rank[pre].push_back(v[i][3]);\n }\n }\n if (rank[0].size() == 4) {\n return 1.0 / 2.0;\n }\n if (rank[0].size() == 3) {\n if (rank[1][0] == check_team) {\n return 0.0;\n } else {\n Int ex = rank[1][0];\n Int mp[4];\n for (Int i = 0; i < 4; i++) {\n mp[v[i][3]] = i;\n }\n for (Int i = 0; i < 4; i++) {\n if (i == ex) continue;\n Int a = score[ex][i].first;\n Int b = score[ex][i].second;\n if (a < b) {\n v[mp[i]][0] -= 3;\n }\n if (a == b) {\n v[mp[i]][0] -= 1;\n }\n v[mp[i]][1] -= b - a;\n v[mp[i]][2] -= b;\n }\n vector<vector<Int>> v2;\n for (Int i = 0; i < 4; i++) {\n if (v[i][3] == ex) continue;\n v2.push_back(v[i]);\n }\n s(v2, 2);\n s(v2, 1);\n s(v2, 0);\n vector<Int> rank2[3];\n rank2[0].push_back(v2[0][3]);\n Int pre = 0;\n for (Int i = 1; i < 3; i++) {\n if (v2[i - 1][0] == v2[i][0] and v2[i - 1][1] == v2[i][1] and v2[i - 1][2] == v2[i][2]) {\n rank2[pre].push_back(v2[i][3]);\n } else {\n pre++;\n rank2[pre].push_back(v2[i][3]);\n }\n }\n if (rank2[0].size() == 3) {\n return 2.0 / 3.0;\n }\n if (rank2[0].size() == 2) {\n if (rank2[1][0] == check_team) {\n return 0.0;\n } else {\n return 1.0;\n }\n }\n if (rank2[0].size() == 1) {\n if (rank2[0][0] == check_team) {\n return 1.0;\n } else {\n if (rank2[1].size() == 1) {\n if (rank2[1][0] == check_team) {\n return 1.0;\n } else {\n return 0.0;\n }\n } else {\n assert(rank2[1].size() == 2);\n Int a = score[rank2[1][0]][rank2[1][1]].first;\n Int b = score[rank2[1][0]][rank2[1][1]].second;\n if (a == b) {\n return 1.0 / 2.0;\n } else {\n if ((a > b and rank2[1][0] == check_team) or (a < b and rank2[1][1] == check_team)) {\n return 1.0;\n } else {\n return 0.0;\n }\n }\n }\n }\n }\n }\n }\n if (rank[0].size() == 2) {\n if (rank[0][0] == check_team or rank[0][1] == check_team) {\n return 1.0;\n } else {\n return 0.0;\n }\n }\n if (rank[0].size() == 1) {\n if (rank[0][0] == check_team) {\n return 1.0;\n } else {\n if (rank[1].size() == 3) {\n Int ex = rank[0][0];\n Int mp[4];\n for (Int i = 0; i < 4; i++) {\n mp[v[i][3]] = i;\n }\n for (Int i = 0; i < 4; i++) {\n if (i == ex) continue;\n Int a = score[ex][i].first;\n Int b = score[ex][i].second;\n if (a < b) {\n v[mp[i]][0] -= 3;\n }\n if (a == b) {\n v[mp[i]][0] -= 1;\n }\n v[mp[i]][1] -= b - a;\n v[mp[i]][2] -= b;\n }\n vector<vector<Int>> v2;\n for (Int i = 0; i < 4; i++) {\n if (v[i][3] == ex) continue;\n v2.push_back(v[i]);\n }\n s(v2, 2);\n s(v2, 1);\n s(v2, 0);\n vector<Int> rank2[3];\n rank2[0].push_back(v2[0][3]);\n Int pre = 0;\n for (Int i = 1; i < 3; i++) {\n if (v2[i - 1][0] == v2[i][0] and v2[i - 1][1] == v2[i][1] and v2[i - 1][2] == v2[i][2]) {\n rank2[pre].push_back(v2[i][3]);\n } else {\n pre++;\n rank2[pre].push_back(v2[i][3]);\n }\n }\n if (rank2[0].size() == 3) {\n return 1.0 / 3.0;\n }\n if (rank2[0].size() == 2) {\n if (rank2[1][0] == check_team) {\n return 0.0;\n } else {\n Int a = score[rank2[0][0]][rank2[0][1]].first;\n Int b = score[rank2[0][0]][rank2[0][1]].second;\n if (a == b) {\n return 1.0 / 2.0;\n } else {\n if ((a > b and rank2[0][0] == check_team) or (a < b and rank2[0][1] == check_team)) { \n return 1.0;\n } else {\n return 0.0;\n }\n }\n }\n }\n if (rank2[0].size() == 1) {\n if (rank2[0][0] == check_team) {\n return 1.0;\n } else {\n return 0.0;\n }\n }\n }\n if (rank[1].size() == 2) {\n if (rank[2][0] == check_team) {\n return 0.0;\n } else {\n Int a = score[rank[1][0]][rank[1][1]].first;\n Int b = score[rank[1][0]][rank[1][1]].second;\n if (a == b) {\n return 1.0 / 2.0;\n } else {\n if ((a > b and rank[1][0] == check_team) or (a < b and rank[1][1] == check_team)) { \n return 1.0;\n } else {\n return 0.0;\n }\n }\n }\n }\n if (rank[1].size() == 1) {\n if (rank[1][0] == check_team) {\n return 1.0;\n } else {\n return 0.0;\n }\n }\n }\n }\n}\n\nint main() {\n Int t;\n cin >> t;\n calc_pro();\n vector<double> r;\n while (t--) {\n vector<vector<Int>> v(4, vector<Int>(4, 0));\n for (Int i = 0; i < 4; i++) v[i][3] = i;\n Int check_team = -1;\n pair<Int, Int> b1 = {-1, -1}, b2 = {-1, -1};\n for (Int i = 0; i <= 4; i++) {\n string s;\n cin >> s;\n if (i == 0) continue;\n if (s[0] == '*') {\n check_team = i - 1;\n }\n for (Int j = (i + 1) * 5; j < (Int)s.size(); j+=5) {\n Int team_A = i - 1;\n Int team_B = j / 5 - 1;\n Int point_A = -1, point_B = -1;\n for (Int k = 0; k < 4; k++) {\n if (k == 1 and s[j + k] != '_') {\n point_A = s[j + k] - '0';\n }\n if (k == 3 and s[j + k] != '_') {\n point_B = s[j + k] - '0';\n }\n }\n score[team_A][team_B] = {point_A, point_B};\n score[team_B][team_A] = {point_B, point_A};\n if (point_A < 0) {\n if (b1.first < 0) {\n b1 = {team_A, team_B};\n } else {\n b2 = {team_A, team_B};\n }\n } else {\n if (point_A > point_B) {\n v[team_A][0] += 3;\n } else if (point_A < point_B) {\n v[team_B][0] += 3;\n } else {\n v[team_A][0] += 1;\n v[team_B][0] += 1;\n }\n v[team_A][1] += point_A - point_B;\n v[team_B][1] += point_B - point_A;\n v[team_A][2] += point_A;\n v[team_B][2] += point_B;\n }\n }\n }\n double res = 0;\n for (Int i = 0; i <= 8; i++) {\n for (Int j = 0; j <= 8; j++) {\n if (i > j) {\n v[b1.first][0] += 3;\n } else if (i < j) {\n v[b1.second][0] += 3;\n } else {\n v[b1.first][0] += 1;\n v[b1.second][0] += 1;\n }\n v[b1.first][1] += i - j;\n v[b1.second][1] += j - i;\n v[b1.first][2] += i;\n v[b1.second][2] += j;\n score[b1.first][b1.second] = {i, j};\n score[b1.second][b1.first] = {j, i};\n for (Int k = 0; k <= 8; k++) {\n for (Int l = 0; l <= 8; l++) {\n if (k > l) {\n v[b2.first][0] += 3;\n } else if (k < l) {\n v[b2.second][0] += 3;\n } else {\n v[b2.first][0] += 1;\n v[b2.second][0] += 1;\n }\n v[b2.first][1] += k - l;\n v[b2.second][1] += l - k;\n v[b2.first][2] += k;\n v[b2.second][2] += l;\n score[b2.first][b2.second] = {k, l};\n score[b2.second][b2.first] = {l, k};\n \n // double p = f(v, check_team);\n\n // if (i > j and k < l and p != 0 and p != 1) {\n // print(\"-------\");\n // for (Int i = 0; i < (Int)v.size(); i++) {\n // print(v[i]);\n // }\n // print(f(v, check_team));\n // }\n\n res += pro[i] * pro[j] * pro[k] * pro[l] * f(v, check_team);\n\n if (k > l) {\n v[b2.first][0] -= 3;\n } else if (k < l) {\n v[b2.second][0] -= 3;\n } else {\n v[b2.first][0] -= 1;\n v[b2.second][0] -= 1;\n }\n v[b2.first][1] -= k - l;\n v[b2.second][1] -= l - k;\n v[b2.first][2] -= k;\n v[b2.second][2] -= l;\n }\n }\n if (i > j) {\n v[b1.first][0] -= 3;\n } else if (i < j) {\n v[b1.second][0] -= 3;\n } else {\n v[b1.first][0] -= 1;\n v[b1.second][0] -= 1;\n }\n v[b1.first][1] -= i - j;\n v[b1.second][1] -= j - i;\n v[b1.first][2] -= i;\n v[b1.second][2] -= j;\n }\n }\n r.push_back(res);\n //print(ma);\n }\n for (Int i = 0; i < (Int)r.size(); i++) {\n print(r[i]);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3176, "score_of_the_acc": -0.1165, "final_rank": 3 }, { "submission_id": "aoj_1234_4289974", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define all(x) (x).begin(),(x).end()\n#define double long double\nconst int mod=1000000007,MAX=203,INF=1<<20;\n\nstruct data{\n int point;\n int diff;\n int goal;\n int id;\n \n bool operator<(const data &another) const\n {\n if(point==another.point){\n if(diff==another.diff){\n if(goal==another.goal){\n return id<another.id;\n }\n return goal<another.goal;\n }\n return diff<another.diff;\n }\n return point<another.point;\n };\n \n bool operator == (const data &another) const\n {\n return point==another.point&&diff==another.diff&&goal==another.goal;\n };\n};\n\nvector<int> dh={1,1,1,2,2,3},dw={11,16,21,16,21,21};\n\nvoid f(data &a,data &b,int scorea,int scoreb){\n if(scorea==scoreb){\n a.point++;\n b.point++;\n a.goal+=scorea;\n b.goal+=scoreb;\n }else if(scorea>scoreb){\n a.point+=3;\n a.diff+=scorea-scoreb;\n b.diff+=scoreb-scorea;\n a.goal+=scorea;\n b.goal+=scoreb;\n }else{\n b.point+=3;\n a.diff+=scorea-scoreb;\n b.diff+=scoreb-scorea;\n a.goal+=scorea;\n b.goal+=scoreb;\n }\n \n}\n\nint main(){\n \n std::ifstream in(\"text.txt\");\n std::cin.rdbuf(in.rdbuf());\n cin.tie(0);\n ios::sync_with_stdio(false);\n \n int Q;cin>>Q;\n vector<double> p(9);\n for(double i=0.0;i<=8.0;i++){\n p[i]=1.0;\n for(double j=1.0;j<=8.0;j++) p[i]*=j;\n for(double j=1.0;j<=i;j++) p[i]/=j;\n for(double j=1.0;j<=8.0-i;j++) p[i]/=j;\n \n for(double j=1.0;j<=8.0-i;j++) p[i]*=3.0;\n for(double j=1.0;j<=8.0;j++) p[i]/=4.0;\n }\n \n while(Q--){\n vector<string> S(5);\n for(int i=0;i<5;i++) cin>>S[i];\n double ans=0.0;\n int my;\n vector<data> T(4);\n \n for(int i=1;i<5;i++) if(S[i][0]=='*') my=i-1;\n \n vector<pair<int,int>> ch;\n \n for(int k=0;k<6;k++){\n if(S[dh[k]][dw[k]]=='_'){\n ch.push_back({dh[k],dw[k]});\n ch.push_back({dh[k],dw[k]+2});\n }\n }\n \n for(int q1=0;q1<9;q1++){\n for(int q2=0;q2<9;q2++){\n for(int q3=0;q3<9;q3++){\n for(int q4=0;q4<9;q4++){\n double pp=p[q1]*p[q2]*p[q3]*p[q4];\n vector<int> sco(4);\n sco[0]=q1;\n sco[1]=q2;\n sco[2]=q3;\n sco[3]=q4;\n \n for(int k=0;k<4;k++) S[ch[k].first][ch[k].second]=char('0'+sco[k]);\n \n vector<int> use(4,0);\n \n while(1){\n vector<data> T(4);\n int fi=0;\n for(int i=0;i<4;i++){\n T[i].id=i;\n if(use[i]==1) T[i].point+=1000;\n if(use[i]==2) T[i].point-=1000;\n if(use[i]==0) fi++;\n }\n \n for(int k=0;k<6;k++){\n int a=S[dh[k]][dw[k]]-'0',b=S[dh[k]][dw[k]+2]-'0';\n \n if(use[dh[k]-1]||use[(dw[k]-6)/5]) continue;\n \n f(T[dh[k]-1],T[(dw[k]-6)/5],a,b);\n \n //cout<<a<<\" \"<<b<<endl;\n }\n \n int cnta=0,cntb=0;\n for(int i=0;i<4;i++){\n //if(i==my) continue;\n if(!(T[i]==T[my])){\n if(T[i]<T[my]) cntb++;\n if(T[my]<T[i]) cnta++;\n }\n }\n \n int posa,posb;\n posa=cnta;\n posb=3-cntb;\n \n sort(all(T));\n reverse(all(T));\n \n if(posb<=1){\n ans+=pp;\n break;\n }else if(posa>=2){\n break;\n }else{\n if(fi==posb-posa+1){\n double cnt=0;\n for(int i=posa;i<=posb;i++) if(i<=1) cnt++;\n ans+=pp*cnt/(double)(fi);\n break;\n }else{\n for(int i=0;i<posa;i++) use[T[i].id]=1;\n for(int i=posb+1;i<4;i++) use[T[i].id]=2;\n for(int i=posa;i<=posb;i++){\n //if(use[T[i].id]) cout<<\"!\"<<endl;\n use[T[i].id]=0;\n }\n }\n }\n }\n \n for(int k=0;k<4;k++) S[ch[k].first][ch[k].second]='_';\n }\n }\n }\n }\n cout<<fixed<<setprecision(7)<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3304, "score_of_the_acc": -0.2849, "final_rank": 9 }, { "submission_id": "aoj_1234_4252005", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS\n#define _USE_MATH_DEFINES\n\n#pragma comment (linker, \"/STACK:526000000\")\n\n#include \"bits/stdc++.h\"\n\nusing namespace std;\ntypedef string::const_iterator State;\n#define eps 1e-11L\n#define MAX_MOD 1000000007LL\n#define GYAKU 500000004LL\n\n#define MOD 998244353LL\n#define seg_size 262144 * 4LL\n#define pb push_back\n#define mp make_pair\ntypedef long long ll;\n#define REP(a,b) for(long long (a) = 0;(a) < (b);++(a))\n#define ALL(x) (x).begin(),(x).end()\n\nvoid init() {\n iostream::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n}\n\n\n//#define int ll\n\nunsigned long xor128() {\n static unsigned long x = 123456789, y = 362436069, z = 521288629, w = 88675123;\n unsigned long t = (x ^ (x << 11));\n x = y; y = z; z = w;\n return (w = (w ^ (w >> 19)) ^ (t ^ (t >> 8)));\n}\nstring names[4];\nint target = 0;\nvector<pair<pair<int, int>, pair<int, int>>> results;\nlong double calc() {\n vector<int> going{ 0,1,2,3 };\n vector<int> winner;\n REP(t, 3) {\n map<tuple<int, int, int>, vector<int>> next;\n tuple<int, int, int> cnter[4] = {};\n REP(i, going.size()) {\n REP(q, going.size()) {\n REP(j, results.size()) {\n if (results[j].first == mp((int)going[i], (int)going[q])) {\n if (results[j].second.first == results[j].second.second) {\n get<0>(cnter[going[i]])--;\n get<0>(cnter[going[q]])--;\n }\n else if (results[j].second.first > results[j].second.second) {\n get<0>(cnter[going[i]]) -= 3;\n }\n else {\n get<0>(cnter[going[q]]) -= 3;\n }\n get<1>(cnter[going[i]]) -= results[j].second.first - results[j].second.second;\n get<1>(cnter[going[q]]) -= results[j].second.second - results[j].second.first;\n get<2>(cnter[going[i]]) -= results[j].second.first;\n get<2>(cnter[going[q]]) -= results[j].second.second;\n }\n }\n }\n }\n REP(i, going.size()) {\n next[cnter[going[i]]].push_back(going[i]);\n }\n if ((*next.begin()).second.size() + winner.size() >= 2) {\n going = (*next.begin()).second;\n }\n else {\n vector<int> hoge = (*next.begin()).second;\n REP(j, hoge.size()) {\n winner.push_back(hoge[j]);\n }\n auto x = next.begin();\n x++;\n if (x != next.end()) {\n going = (*x).second;\n }\n else {\n going.clear();\n break;\n }\n }\n }\n REP(i, winner.size()) {\n if (winner[i] == target) {\n return 1.0L;\n }\n }\n long double now = 2 - (int)winner.size();\n REP(i, going.size()) {\n if (target == going[i]) {\n return now / (long double)(going.size());\n }\n }\n return 0;\n}\nlong double memo[9];\nlong double scoring(int a) {\n if (memo[a]) return memo[a];\n long double ans = 1;\n for (int i = 2; i <= 8; ++i) {\n ans *= (long double)i;\n }\n for (int i = 2; i <= a; ++i) {\n ans /= (long double)i;\n }\n for (int i = 2; i <= 8 - a; ++i) {\n ans /= (long double)i;\n }\n REP(i, a) {\n ans /= (long double)4;\n }\n REP(i, 8 - a) {\n ans /= (long double)4;\n ans *= (long double)3;\n }\n return memo[a] = ans;\n}\nvoid solve() {\n results.clear();\n vector<string> inputs;\n string a;\n cin >> a;\n REP(i, 4) {\n string a;\n cin >> a;\n inputs.push_back(a);\n }\n REP(i, 4) {\n if (inputs[i][0] == '*') {\n target = i;\n }\n names[i] = inputs[i].substr(1, 3);\n }\n vector<pair<int, int>> no;\n REP(i, 4) {\n for (int q = i+1; q < 4; ++q) {\n string b = inputs[i].substr(6 + q * 5, 3);\n if (b[0] == '_') {\n no.push_back(mp(i, q));\n }\n else {\n pair<pair<int, int>, pair<int, int>> now = mp(mp((int)i, (int)q), mp((int)(b[0] - '0'), (int)(b[2] - '0')));\n results.push_back(now);\n }\n }\n }\n results.push_back(mp(no[0], mp(-1, -1)));\n results.push_back(mp(no[1], mp(-1, -1)));\n long double ans = 0;\n REP(i, 9) {\n REP(q, 9) {\n REP(j, 9) {\n REP(t, 9) {\n long double prob = scoring(i) * scoring(q) * scoring(j) * scoring(t);\n results[results.size()-1].second = mp(i, q);\n results[results.size()-2].second = mp(j, t);\n ans += prob * calc();\n }\n }\n }\n }\n cout << ans << endl;\n}\n\n#undef int\nint main() {\n init();\n int t;\n cin >> t;\n REP(tea,t)\n solve();\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 3296, "score_of_the_acc": -0.3241, "final_rank": 12 }, { "submission_id": "aoj_1234_3836016", "code_snippet": "#include <iomanip>\n#include <iostream>\n#include <cmath>\n#include <vector>\n#include <string>\n\nusing Bool = bool;\nusing Int = long long int;\nusing Real = long double;\nusing Char = char;\nusing String = std::string;\ntemplate <class T>\nusing Vector = std::vector<T>;\ntemplate <class T>\nusing Matrix = Vector<Vector<T>>;\n\nstruct Fout {\n Int precision;\n Fout(Int precision) : precision(precision) {}\n};\nstd::ostream& operator<<(std::ostream& os, const Fout& fio) {\n os << std::fixed << std::setprecision(fio.precision);\n return os;\n}\n\n// p勝する確率\nVector<Real> prob;\n\nvoid init() {\n prob.resize(9);\n prob[0] = std::pow(0.75L, 8);\n for (Int i = 1; i <= 8; ++i) {\n prob[i] = prob[i - 1] * Real(9 - i) / Real(i * 3);\n }\n}\n\n// 入力から得点表を生成\n// 先頭が自チーム、埋まってない箇所は-1 ~ -4が振られる\nMatrix<Int> parse() {\n String s;\n std::cin >> s;\n\n Vector<Vector<Int>> score(4, Vector<Int>(4, 0));\n\n {\n Int me = 0, cnt = -1;\n\n for (Int i = 0; i < 4; ++i) {\n std::cin >> s;\n if (s.front() == '*') me = i;\n\n for (Int j = i + 1; j < 4; ++j) {\n Char x = s[j * 5 + 6];\n score[i][j] = (x == '_' ? cnt-- : x - '0');\n x = s[j * 5 + 8];\n score[j][i] = (x == '_' ? cnt-- : x - '0');\n }\n }\n\n // 自チームを先頭へ移動\n std::swap(score[0], score[me]);\n for (auto& v : score) std::swap(v[0], v[me]);\n }\n\n return score;\n}\n\nvoid solve() {\n auto score = parse();\n Real ans = 0;\n\n // 空欄の点数を全列挙\n for (Int b = 0; b < 6561; ++b) {\n // デコード\n Vector<Int> pts(4);\n {\n Int c = b;\n for (Int i = 0; i < 4; ++i) {\n pts[i] = c % 9;\n c /= 9;\n }\n }\n\n Real pr = 1;\n for (auto p : pts) pr *= prob[p];\n\n // 空欄を埋める\n auto nscore = score;\n for (auto& v : nscore) {\n for (auto& x : v) {\n if (x < 0) x = pts[-x - 1];\n }\n }\n\n Vector<Vector<Int>> result(4);\n\n for (Int q = 0; q < 3; ++q) {\n // 現時点で自チームと同率のチームを列挙\n Vector<Bool> cons(4);\n for (Int i = 0; i < 4; ++i) {\n cons[i] = (result[i] == result[0]);\n }\n\n // 同率チーム間のポイント、得失点差、得点\n Matrix<Int> tmpres(4, Vector<Int>(3, 0));\n for (Int i = 0; i < 4; ++i) {\n if (!cons[i]) continue;\n for (Int j = 0; j < 4; ++j) {\n if (i == j || !cons[j]) continue;\n\n Int me = nscore[i][j], op = nscore[j][i];\n tmpres[i][0] += (me > op ? 3 : me == op);\n tmpres[i][1] += me - op;\n tmpres[i][2] += me;\n }\n }\n\n // テーブルを拡張\n for (Int i = 0; i < 4; ++i) {\n if (cons[i])\n std::move(tmpres[i].begin(), tmpres[i].end(),\n std::back_inserter(result[i]));\n }\n }\n\n Int u = 0, m = 0; // 自チームと比べて上、同率のチーム数\n for (Int i = 0; i < 4; ++i) {\n if (result[i] > result[0]) {\n ++u;\n } else if (result[i] == result[0]) {\n ++m;\n }\n }\n\n if (u >= 2) { // 枠が埋まっている\n pr = 0;\n } else if (u + m >= 3) { // 残り2-u枠をmチームで取り合う\n pr *= Real(2 - u) / Real(m);\n }\n ans += pr;\n }\n\n std::cout << Fout(7) << ans << std::endl;\n}\n\nint main() {\n init();\n Int n;\n std::cin >> n;\n for (Int i = 0; i < n; ++i) solve();\n return 0;\n}", "accuracy": 1, "time_ms": 850, "memory_kb": 3184, "score_of_the_acc": -0.2589, "final_rank": 8 }, { "submission_id": "aoj_1234_3836015", "code_snippet": "#if __has_include(\"../library/Basic/Debug.hpp\")\n\n#include \"../library/Basic/Debug.hpp\"\n\n#else\n\n/* ----- Header Files ----- */\n// IO\n#include <cstdio>\n#include <iomanip>\n#include <ios>\n#include <iostream>\n\n// algorithm\n#include <algorithm>\n#include <cmath>\n#include <numeric>\n\n// container\n#include <vector>\n#include <string>\n#include <tuple>\n#include <set>\n#include <map>\n#include <stack>\n#include <queue>\n#include <deque>\n\n// others\n#include <random>\n#include <limits>\n#include <functional>\n#include <ctime>\n#include <cassert>\n#include <cstdint>\n\n\n/* ----- Type Alias ----- */\nusing Bool = bool;\nusing Int = long long int;\nusing Real = long double;\nusing Char = char;\nusing String = std::string;\ntemplate <class... Ts>\nusing Tuple = std::tuple<Ts...>;\n\ntemplate <class T>\nusing Vector = std::vector<T>;\ntemplate <class T>\nusing Matrix = Vector<Vector<T>>;\ntemplate <class T>\nusing Queue = std::queue<T>;\ntemplate <class T>\nusing Stack = std::stack<T>;\ntemplate <class T>\nusing Deque = std::deque<T>;\n\ntemplate <class T>\nusing MaxHeap = std::priority_queue<T>;\ntemplate <class T>\nusing MinHeap = std::priority_queue<T, std::vector<T>, std::greater<T>>;\ntemplate <class T>\nusing Set = std::set<T>;\ntemplate <class T, class U>\nusing Map = std::map<T, U>;\n\ntemplate <class T, class... Us>\nusing Func = std::function<T(Us...)>;\n\ntemplate <class T>\nT genv(T v) { return v; }\n\ntemplate <class T, class... Ts>\nauto genv(size_t l, Ts... ts) {\n return Vector<decltype(genv<T>(ts...))>(l, genv<T>(ts...));\n}\n\ntemplate <class Cost = Int>\nstruct Edge {\n Int src, dst;\n Cost cost;\n Edge(Int src = -1, Int dst = -1, Cost cost = 1)\n : src(src), dst(dst), cost(cost){};\n\n bool operator<(const Edge<Cost>& e) const { return this->cost < e.cost; }\n bool operator>(const Edge<Cost>& e) const { return this->cost > e.cost; }\n};\n\ntemplate <class Cost = Int>\nusing Edges = Vector<Edge<Cost>>;\ntemplate <class Cost = Int>\nusing Graph = Vector<Vector<Edge<Cost>>>;\n\n#endif\n\n/* ----- Misc ----- */\nvoid fastio() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n}\n\nstruct Fout {\n Int precision;\n Fout(Int precision) : precision(precision) {}\n};\nstd::ostream& operator<<(std::ostream& os, const Fout& fio) {\n os << std::fixed << std::setprecision(fio.precision);\n return os;\n}\n\n\n/* ----- Constants ----- */\n// constexpr Int INF = std::numeric_limits<Int>::max() / 3;\n// constexpr Int MOD = 1000000007;\n// constexpr Real PI = acos(-1);\n// constexpr Real EPS = 1e-10;\n// std::mt19937 mt(int(std::time(nullptr)));\n\nVector<Real> prob;\n\nvoid init() {\n prob.resize(9);\n prob[0] = std::pow(0.75L, 8);\n for (Int i = 1; i <= 8; ++i) {\n prob[i] = prob[i - 1] * Real(9 - i) / Real(i * 3);\n }\n}\n\nvoid solve() {\n String s;\n std::cin >> s;\n\n Vector<Vector<Int>> score(4, Vector<Int>(4, 0));\n\n {\n Int me = 0, cnt = -1;\n\n for (Int i = 0; i < 4; ++i) {\n std::cin >> s;\n if (s.front() == '*') me = i;\n\n for (Int j = i + 1; j < 4; ++j) {\n Char x = s[j * 5 + 6];\n score[i][j] = (x == '_' ? cnt-- : x - '0');\n x = s[j * 5 + 8];\n score[j][i] = (x == '_' ? cnt-- : x - '0');\n }\n }\n\n std::swap(score[0], score[me]);\n for (auto& v : score) std::swap(v[0], v[me]);\n }\n\n Real ans = 0;\n for (Int b = 0; b < 6561; ++b) {\n Vector<Int> pts(4);\n {\n Int c = b;\n for (Int i = 0; i < 4; ++i) {\n pts[i] = c % 9;\n c /= 9;\n }\n }\n\n Real pr = 1;\n for (auto p : pts) pr *= prob[p];\n\n auto s = score;\n for (auto& v : s) {\n for (auto& x : v) {\n if (x < 0) x = pts[-x - 1];\n }\n }\n\n Vector<Vector<Int>> result(4);\n\n for (Int q = 0; q < 3; ++q) {\n Int cons = 1;\n for (Int i = 1; i < 4; ++i) {\n if (result[i] == result[0]) cons += (1 << i);\n }\n\n Vector<Vector<Int>> tmpres(4, Vector<Int>(3, 0));\n for (Int i = 0; i < 4; ++i) {\n if (((cons >> i) & 1) == 0) continue;\n for (Int j = 0; j < 4; ++j) {\n if (i == j || ((cons >> j) & 1) == 0) continue;\n tmpres[i][0] += (s[i][j] > s[j][i] ? 3 : s[i][j] == s[j][i]);\n tmpres[i][1] += s[i][j] - s[j][i];\n tmpres[i][2] += s[i][j];\n }\n }\n\n for (Int i = 0; i < 4; ++i) {\n if ((cons >> i) & 1)\n std::move(tmpres[i].begin(), tmpres[i].end(),\n std::back_inserter(result[i]));\n }\n }\n\n Int u = 0, m = 0;\n for (Int i = 0; i < 4; ++i) {\n if (result[i] > result[0]) {\n ++u;\n } else if (result[i] == result[0]) {\n ++m;\n }\n }\n\n if (u >= 2) {\n pr = 0;\n } else if (u + m >= 3) {\n pr *= Real(2 - u) / Real(m);\n }\n ans += pr;\n }\n\n std::cout << Fout(7) << ans << std::endl;\n}\n\nint main() {\n init();\n Int n;\n std::cin >> n;\n for (Int i = 0; i < n; ++i) solve();\n return 0;\n}", "accuracy": 1, "time_ms": 870, "memory_kb": 3272, "score_of_the_acc": -0.3908, "final_rank": 13 }, { "submission_id": "aoj_1234_3568063", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<iomanip>\n#include<vector>\nusing namespace std;\ndouble W[9];\nint x[4][4]={{0,1,1,1},{1,0,2,2},{1,2,0,3},{1,2,3,0}};\nint y[4][4]={{0,11,16,21},{11,0,16,21},{16,16,0,21},{21,21,21,0}};\nint mx[6]={1,1,1,2,2,3},my[6]={11,16,21,16,21,21};\nint ax[12]={1,1,1,1,1,1,2,2,2,2,3,3},ay[12]={11,13,16,18,21,23,16,18,21,23,21,23};\nstring s[5];\nint winner;\ndouble dfs(int id)\n{\n\tif(id==12)\n\t{\n\t\tvector<pair<pair<int,pair<int,int> >,int> >A(4);\n\t\tfor(int i=0;i<4;i++)\n\t\t{\n\t\t\tint p=0,d=0,g=0;\n\t\t\tfor(int j=0;j<4;j++)\n\t\t\t{\n\t\t\t\tif(i==j)continue;\n\t\t\t\tint a=s[x[i][j]][y[i][j]]-'0';\n\t\t\t\tint b=s[x[i][j]][y[i][j]+2]-'0';\n\t\t\t\tif(x[i][j]>i)\n\t\t\t\t{\n\t\t\t\t\tp+=a>b?3:a==b?1:0;\n\t\t\t\t\td+=a-b;\n\t\t\t\t\tg+=a;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tp+=b>a?3:b==a?1:0;\n\t\t\t\t\td+=b-a;\n\t\t\t\t\tg+=b;\n\t\t\t\t}\n\t\t\t}\n\t\t\tA[i]=make_pair(make_pair(-p,make_pair(-d,-g)),i);\n\t\t}\n\t\tsort(A.begin(),A.end());\n\t\tvector<int>B;\n\t\tint p=0;\n\t\tfor(int i=1;i<=4;i++)\n\t\t{\n\t\t\tif(i<4&&A[p].first==A[i].first)continue;\n\t\t\telse\n\t\t\t{\n\t\t\t\tif(p+1==i)B.push_back(A[p].second);\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tvector<int>I;\n\t\t\t\t\tfor(int j=p;j<i;j++)I.push_back(A[j].second);\n\t\t\t\t\tint pre=114514;\n\t\t\t\t\twhile(I.size()<pre)\n\t\t\t\t\t{\n\t\t\t\t\t\tpre=I.size();\n\t\t\t\t\t\tvector<pair<pair<int,pair<int,int> >,int> >C;\n\t\t\t\t\t\tfor(int j=0;j<I.size();j++)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tint p=0,d=0,g=0;\n\t\t\t\t\t\t\tfor(int k=0;k<I.size();k++)\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tif(j==k)continue;\n\t\t\t\t\t\t\t\tint a=s[x[I[j]][I[k]]][y[I[j]][I[k]]]-'0';\n\t\t\t\t\t\t\t\tint b=s[x[I[j]][I[k]]][y[I[j]][I[k]]+2]-'0';\n\t\t\t\t\t\t\t\tif(x[I[j]][I[k]]>I[j])\n\t\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\t\tp+=a>b?3:a==b?1:0;\n\t\t\t\t\t\t\t\t\td+=a-b;\n\t\t\t\t\t\t\t\t\tg+=a;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\telse\n\t\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\t\tp+=b>a?3:b==a?1:0;\n\t\t\t\t\t\t\t\t\td+=b-a;\n\t\t\t\t\t\t\t\t\tg+=b;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tC.push_back(make_pair(make_pair(-p,make_pair(-d,-g)),I[j]));\n\t\t\t\t\t\t}\n\t\t\t\t\t\tsort(C.begin(),C.end());\n\t\t\t\t\t\tint q=0;\n\t\t\t\t\t\tvector<int>J;\n\t\t\t\t\t\tfor(int j=1;j<=C.size();j++)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tif(j<C.size()&&C[q].first==C[j].first)continue;\n\t\t\t\t\t\t\telse\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tif(q+1==j)B.push_back(C[q++].second);\n\t\t\t\t\t\t\t\telse\n\t\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\t\tbool flag=0;\n\t\t\t\t\t\t\t\t\tfor(int k=0;k<I.size();k++)flag|=I[k]==winner;\n\t\t\t\t\t\t\t\t\tif(!flag)\n\t\t\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\t\t\tfor(;q<j;q++)B.push_back(C[q].second);\n\t\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\t\telse\n\t\t\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\t\t\tfor(;q<j;q++)J.push_back(C[q].second);\n\t\t\t\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t\tI=J;\n\t\t\t\t\t}\n\t\t\t\t\tif(!I.empty())\n\t\t\t\t\t{\n\t\t\t\t\t\tbool flag=0;\n\t\t\t\t\t\tfor(int j=0;j<I.size();j++)flag|=I[j]==winner;\n\t\t\t\t\t\tif(!flag)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tfor(int j=0;j<I.size();j++)B.push_back(I[j]);\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tif(B.size()>=2)return 0;\n\t\t\t\t\t\t\telse\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tdouble rest=2-B.size();\n\t\t\t\t\t\t\t\treturn rest/I.size();\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tp=i;\n\t\t\t}\n\t\t}\n\t\treturn B[0]==winner||B[1]==winner;\n\t}\n\telse\n\t{\n\t\tif(s[ax[id]][ay[id]]!='_')return dfs(id+1);\n\t\telse\n\t\t{\n\t\t\tdouble ret=0;\n\t\t\tfor(char c='0';c<='8';c++)\n\t\t\t{\n\t\t\t\ts[ax[id]][ay[id]]=c;\n\t\t\t\tret+=W[c-'0']*dfs(id+1);\n\t\t\t\ts[ax[id]][ay[id]]='_';\n\t\t\t}\n\t\t\treturn ret;\n\t\t}\n\t}\n}\nmain()\n{\n\tfor(int p=0;p<=8;p++)\n\t{\n\t\tW[p]=1;\n\t\tfor(int j=1;j<=8;j++)W[p]*=j;\n\t\tfor(int j=1;j<=p;j++)W[p]/=j;\n\t\tfor(int j=1;j<=8-p;j++)W[p]/=j;\n\t\tfor(int j=1;j<=p;j++)W[p]/=4;\n\t\tfor(int j=1;j<=8-p;j++)W[p]*=3./4;\n\t}\n\tint T;cin>>T;\n\tfor(;T--;)\n\t{\n\t\tfor(int i=0;i<5;i++)\n\t\t{\n\t\t\tcin>>s[i];\n\t\t\tif(s[i][0]=='*')winner=i-1;\n\t\t}\n\t\tcout<<fixed<<setprecision(9)<<dfs(0)<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3192, "score_of_the_acc": -0.128, "final_rank": 4 }, { "submission_id": "aoj_1234_3321193", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ld=long double;\nstruct Match{\n int lhs,rhs;\n int lhsp,rhsp;\n};\n\nvoid debug(Match x){\n //cerr<<x.lhs<<\"vs\"<<x.rhs<<\" \"<<x.lhsp<<\"-\"<<x.rhsp<<endl;\n}\nvoid debug(vector<Match> x){\n //cerr<<\"#These are match\"<<endl;\n for(int i=0;i<x.size();i++){\n debug(x[i]);\n }\n}\nld winner(const vector<Match> &match,int tar,int place){\n vector<int> pt(4);\n vector<int> gd(4);\n vector<int> sc(4);\n for(auto &m:match){\n pt[m.lhs]++;\n pt[m.rhs]++;\n if(m.lhsp<m.rhsp) pt[m.rhs]+=300;\n else if(m.lhsp>m.rhsp) pt[m.lhs]+=300;\n else pt[m.rhs]+=100,pt[m.lhs]+=100;\n gd[m.lhs]+=m.lhsp-m.rhsp;\n gd[m.rhs]+=m.rhsp-m.lhsp;\n sc[m.lhs]+=m.lhsp;\n sc[m.rhs]+=m.rhsp;\n }\n vector<int> rs(4);\n for(int i=0;i<4;i++) rs[i]=pt[i]*1e5+gd[i]*1e3+sc[i];\n int x=*max_element(rs.begin(),rs.end());\n if(rs[tar]==x){\n if(count(rs.begin(),rs.end(),x)==1) return 1;\n vector<Match> next;\n for(auto &m:match){\n if(rs[m.lhs]==x && rs[m.rhs]==x) next.push_back(m);\n }\n //cerr<<\"#\"<<next.size()<<endl;\n if(match.size()==next.size()){\n int cnt=count(rs.begin(),rs.end(),x);\n if(cnt==1) return 1;\n else return ld(place)/cnt;\n }\n else return winner(next,tar,place);\n }\n if(place<=count(rs.begin(),rs.end(),x)) return 0;\n int sndmax=0;\n for(int i=0;i<4;i++){\n if(rs[i]!=x) sndmax=max(sndmax,rs[i]);\n }\n if(rs[tar]==sndmax){\n if(count(rs.begin(),rs.end(),sndmax)==1) return 1;\n vector<Match> next;\n for(auto &m:match){\n if(rs[m.lhs]==sndmax && rs[m.rhs]==sndmax) next.push_back(m);\n }\n return winner(next,tar,1);\n }\n return 0;\n}\nld pos(int point){\n ld res=1;\n for(int i=0;i<8;i++) res*=(i+1);\n for(int i=0;i<point;i++) res*=0.25/(i+1);\n for(int i=0;i<8-point;i++) res*=0.75/(i+1);\n return res;\n}\nint cnt=0;\nld dfs(int idx,vector<Match> &match,ld p,int tar){\n if(idx==match.size()){\n ld x=winner(match,tar,2);\n cnt++;\n debug(match);\n //cerr<<x<<endl;\n return p*x;\n }\n ld res=0;\n if(match[idx].lhsp==-1){\n for(int i=0;i<=8;i++){\n for(int j=0;j<=8;j++){\n match[idx].lhsp=i;\n match[idx].rhsp=j;\n res+=dfs(idx+1,match,p*pos(i)*pos(j),tar);\n match[idx].lhsp=-1;\n match[idx].rhsp=-1;\n }\n }\n }\n else{\n return dfs(idx+1,match,p,tar);\n }\n return res;\n}\nld solve(){\n array<string,5> table;\n for(int i=0;i<5;i++) cin>>table[i];\n int tar=0;\n for(int i=0;i<4;i++){\n if(table[i+1][0]=='*') tar=i;\n }\n const int WIDTH=5;\n const int LHS=1;\n const int RHS=3;\n vector<Match> match;\n for(int i=0;i<4;i++){\n for(int j=0;j<i;j++){\n char lhsp=table[j+1][WIDTH*(i+1)+LHS];\n char rhsp=table[j+1][WIDTH*(i+1)+RHS];\n if(isdigit(lhsp)){\n assert(isdigit(rhsp));\n match.push_back(Match{j,i,lhsp-'0',rhsp-'0'});\n }\n else{\n match.push_back(Match{j,i,-1,-1});\n }\n }\n }\n assert(match.size()==6);\n return dfs(0,match,1,tar);\n}\nint main(){\n int n;\n cin>>n;\n cout<<setprecision(10)<<fixed;\n for(int i=0;i<n;i++){\n cout<<solve()<<endl; \n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3212, "score_of_the_acc": -0.159, "final_rank": 6 }, { "submission_id": "aoj_1234_3264952", "code_snippet": "#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<ciso646>\n#include<random>\n#include<map>\n#include<set>\n#include<complex>\n#include<bitset>\n#include<stack>\n#include<unordered_map>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned int ui;\nconst ll mod = 1000000007;\nconst ll INF = (ll)1000000007 * 1000000007;\ntypedef pair<int, int> P;\n#define stop char nyaa;cin>>nyaa;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define per(i,n) for(int i=n-1;i>=0;i--)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define per1(i,n) for(int i=n;i>=1;i--)\n#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)\ntypedef long double ld;\ntypedef complex<ld> Point;\nconst ld eps = 1e-4;\nconst ld pi = acos(-1.0);\ntypedef pair<ll, ll> LP;\ntypedef pair<ld, ld> LDP;\nstruct result {\n\tint x, y, cx, cy;\n};\nresult a[6];\nint target;\nint c[4];\nvoid a_calc() {\n\trep(i, 4) {\n\t\tc[i] = 0;\n\t}\n\trep(i, 6) {\n\t\tif (a[i].cx > a[i].cy)c[a[i].x] += 3;\n\t\telse if (a[i].cx < a[i].cy)c[a[i].y] += 3;\n\t\telse {\n\t\t\tc[a[i].x]++; c[a[i].y]++;\n\t\t}\n\t}\n}\nvoid b_calc() {\n\trep(i, 4) {\n\t\tc[i] = 0;\n\t}\n\trep(i, 6) {\n\t\tc[a[i].x] += a[i].cx - a[i].cy;\n\t\tc[a[i].y] += a[i].cy - a[i].cx;\n\t}\n}\nvoid c_calc() {\n\trep(i, 4) {\n\t\tc[i] = 0;\n\t}\n\trep(i, 6) {\n\t\tc[a[i].x] += a[i].cx;\n\t\tc[a[i].y] += a[i].cy;\n\t}\n}\nvoid d_calc(vector<int> v) {\n\trep(i, 4) {\n\t\tc[i] = 0;\n\t}\n\tint exi[4] = {};\n\trep(i, v.size()) {\n\t\texi[v[i]] = 1;\n\t}\n\trep(i, 6) {\n\t\tif (!exi[a[i].x] || !exi[a[i].y])continue;\n\t\tif (a[i].cx > a[i].cy)c[a[i].x] += 3;\n\t\telse if (a[i].cx < a[i].cy)c[a[i].y] += 3;\n\t\telse {\n\t\t\tc[a[i].x]++; c[a[i].y]++;\n\t\t}\n\t}\n}\nvoid e_calc(vector<int> v) {\n\trep(i, 4) {\n\t\tc[i] = 0;\n\t}\n\tint exi[4] = {};\n\trep(i, v.size()) {\n\t\texi[v[i]] = 1;\n\t}\n\trep(i, 6) {\n\t\tif (!exi[a[i].x] || !exi[a[i].y])continue;\n\t\tc[a[i].x] += a[i].cx - a[i].cy;\n\t\tc[a[i].y] += a[i].cy - a[i].cx;\n\t}\n}\nvoid f_calc(vector<int> v) {\n\trep(i, 4) {\n\t\tc[i] = 0;\n\t}\n\tint exi[4] = {};\n\trep(i, v.size()) {\n\t\texi[v[i]] = 1;\n\t}\n\trep(i, 6) {\n\t\tif (!exi[a[i].x] || !exi[a[i].y])continue;\n\t\tc[a[i].x] += a[i].cx;\n\t\tc[a[i].y] += a[i].cy;\n\t}\n}\nvector<int> a_rule(vector<int> u) {\n\tvector<int> res;\n\ta_calc();\n\tvector<P> v;\n\trep(i, u.size()) {\n\t\tv.push_back({ c[u[i]],u[i] });\n\t}\n\tsort(v.begin(), v.end(),greater<P>());\n\tint cnt = 0;\n\trep(i, v.size()) {\n\t\tres.push_back(v[i].second);\n\t\twhile (i + 1 < v.size() && v[i].first == v[i + 1].first) {\n\t\t\ti++; res.push_back(v[i].second);\n\t\t}\n\t\tcnt++;\n\t\tif (cnt == 1)break;\n\t}\n\tsort(res.begin(), res.end()); return res;\n}\nvector<int> b_rule(vector<int> v) {\n\tvector<int> res;\n\tb_calc();\n\tvector<P> u;\n\trep(i, v.size()) {\n\t\tu.push_back({ c[v[i]],v[i] });\n\t}\n\tsort(u.begin(), u.end(), greater<P>());\n\tint cnt = 0;\n\trep(i, u.size()) {\n\t\tres.push_back(u[i].second);\n\t\twhile (i + 1 < u.size() && u[i].first == u[i + 1].first) {\n\t\t\ti++; res.push_back(u[i].second);\n\t\t}\n\t\tcnt++; if (cnt == 1)break;\n\t}\n\tsort(res.begin(), res.end()); return res;\n}\nvector<int> c_rule(vector<int> v) {\n\tvector<int> res; c_calc();\n\tvector<P> u;\n\trep(i, v.size()) {\n\t\tu.push_back({ c[v[i]],v[i] });\n\t}\n\tsort(u.begin(), u.end(), greater<P>());\n\tint cnt = 0;\n\trep(i, u.size()) {\n\t\tres.push_back(u[i].second);\n\t\twhile (i + 1 < u.size() && u[i].first == u[i + 1].first) {\n\t\t\ti++; res.push_back(u[i].second);\n\t\t}\n\t\tcnt++; if (cnt == 1)break;\n\t}\n\tsort(res.begin(), res.end()); return res;\n}\nvector<int> d_rule(vector<int> v) {\n\tvector<int> res; d_calc(v);\n\tvector<P> u;\n\trep(i, v.size()) {\n\t\tu.push_back({ c[v[i]],v[i] });\n\t}\n\tsort(u.begin(), u.end(), greater<P>());\n\tint cnt = 0;\n\trep(i, u.size()) {\n\t\tres.push_back(u[i].second);\n\t\twhile (i + 1 < u.size() && u[i].first == u[i + 1].first) {\n\t\t\ti++; res.push_back(u[i].second);\n\t\t}\n\t\tcnt++; if (cnt == 1)break;\n\t}\n\tsort(res.begin(), res.end()); return res;\n}\nvector<int> e_rule(vector<int> v) {\n\tvector<int> res; e_calc(v);\n\tvector<P> u;\n\trep(i, v.size()) {\n\t\tu.push_back({ c[v[i]],v[i] });\n\t}\n\tsort(u.begin(), u.end(), greater<P>());\n\tint cnt = 0;\n\trep(i, u.size()) {\n\t\tres.push_back(u[i].second);\n\t\twhile (i + 1 < u.size() && u[i].first == u[i + 1].first) {\n\t\t\ti++; res.push_back(u[i].second);\n\t\t}\n\t\tcnt++; if (cnt == 1)break;\n\t}\n\tsort(res.begin(), res.end()); return res;\n}\nvector<int> f_rule(vector<int> v) {\n\tvector<int> res; f_calc(v);\n\tvector<P> u;\n\trep(i, v.size()) {\n\t\tu.push_back({ c[v[i]],v[i] });\n\t}\n\tsort(u.begin(), u.end(), greater<P>());\n\tint cnt = 0;\n\trep(i, u.size()) {\n\t\tres.push_back(u[i].second);\n\t\twhile (i + 1 < u.size() && u[i].first == u[i + 1].first) {\n\t\t\ti++; res.push_back(u[i].second);\n\t\t}\n\t\tcnt++; if (cnt == 1)break;\n\t}\n\tsort(res.begin(), res.end()); return res;\n}\nld ret() {\n\tbool one = false;\n\tvector<int> v = { 0,1,2,3 }; vector<int> cop;\n\tcop = v; v = a_rule(v);\n\tif (v.size() == 1 && !one) {\n\t\tone = true;\n\t\tif (v[0] == target)return 1;\n\t\tvector<int> cv;\n\t\trep(i, cop.size()) {\n\t\t\tif (v[0] == cop[i])continue;\n\t\t\tcv.push_back(cop[i]);\n\t\t}\n\t\tv = cv;\n\t\tv = a_rule(v);\n\t}\n\tif (v.size() == 1) {\n\t\tif (v[0] == target)return 1;\n\t\telse return 0;\n\t}\n\tcop = v; v = b_rule(v);\n\tif (v.size() == 1 && !one) {\n\t\tone = true;\n\t\tif (v[0] == target)return 1;\n\t\tvector<int> cv;\n\t\trep(i, cop.size()) {\n\t\t\tif (v[0] == cop[i])continue;\n\t\t\tcv.push_back(cop[i]);\n\t\t}\n\t\tv = cv;\n\t\tv = b_rule(v);\n\t}\n\tif (v.size() == 1) {\n\t\tif (v[0] == target)return 1;\n\t\telse return 0;\n\t}\n\tcop = v; v = c_rule(v);\n\tif (v.size() == 1 && !one) {\n\t\tone = true;\n\t\tif (v[0] == target)return 1;\n\t\tvector<int> cv;\n\t\trep(i, cop.size()) {\n\t\t\tif (v[0] == cop[i])continue;\n\t\t\tcv.push_back(cop[i]);\n\t\t}\n\t\tv = cv;\n\t\tv = c_rule(v);\n\t}\n\tif (v.size() == 1) {\n\t\tif (v[0] == target)return 1;\n\t\telse return 0;\n\t}\n\tcop = v;\n\t\tv = d_rule(v);\n\tif (v.size() == 1 && !one) {\n\t\tone = true;\n\t\tif (v[0] == target)return 1;\n\t\tvector<int> cv;\n\t\trep(i, cop.size()) {\n\t\t\tif (v[0] == cop[i])continue;\n\t\t\tcv.push_back(cop[i]);\n\t\t}\n\t\tv = cv;\n\t\t\tv = d_rule(v);\n\t}\n\tif (v.size() == 1) {\n\t\tif (v[0] == target)return 1;\n\t\telse return 0;\n\t}cop = v;\n\t\tv = e_rule(v);\n\tif (v.size() == 1 && !one) {\n\t\tone = true;\n\t\tif (v[0] == target)return 1;\n\t\tvector<int> cv;\n\t\trep(i, cop.size()) {\n\t\t\tif (v[0] == i)continue;\n\t\t\tcv.push_back(cop[i]);\n\t\t}\n\t\tv = cv;\n\t\t\tv = e_rule(v);\n\t}\n\tif (v.size() == 1) {\n\t\tif (v[0] == target)return 1;\n\t\telse return 0;\n\t}cop = v;\n\t\tv = f_rule(v);\n\tif (v.size() == 1 && !one) {\n\t\tone = true;\n\t\tif (v[0] == target)return 1;\n\t\tvector<int> cv;\n\t\trep(i, cop.size()) {\n\t\t\tif (v[0] == cop[i])continue;\n\t\t\tcv.push_back(cop[i]);\n\t\t}\n\t\tv = cv;\n\t\t\tv =f_rule(v);\n\t}\n\tif (v.size() == 1) {\n\t\tif (v[0] == target)return 1;\n\t\telse return 0;\n\t}cop = v;\n\t\tv = d_rule(v);\n\tif (v.size() == 1 && !one) {\n\t\tone = true;\n\t\tif (v[0] == target)return 1;\n\t\tvector<int> cv;\n\t\trep(i, cop.size()) {\n\t\t\tif (v[0] == cop[i])continue;\n\t\t\tcv.push_back(cop[i]);\n\t\t}\n\t\tv = cv;\n\t\t\tv = d_rule(v);\n\t}\n\tif (v.size() == 1) {\n\t\tif (v[0] == target)return 1;\n\t\telse return 0;\n\t}cop = v;\n\t\tv = e_rule(v);\n\tif (v.size() == 1 && !one) {\n\t\tone = true;\n\t\tif (v[0] == target)return 1;\n\t\tvector<int> cv;\n\t\trep(i, cop.size()) {\n\t\t\tif (v[0] == i)continue;\n\t\t\tcv.push_back(cop[i]);\n\t\t}\n\t\tv = cv;\n\t\tv = e_rule(v);\n\t}\n\tif (v.size() == 1) {\n\t\tif (v[0] == target)return 1;\n\t\telse return 0;\n\t}cop = v;\n\t\tv = f_rule(v);\n\tif (v.size() == 1 && !one) {\n\t\tone = true;\n\t\tif (v[0] == target)return 1;\n\t\tvector<int> cv;\n\t\trep(i, cop.size()) {\n\t\t\tif (v[0] == cop[i])continue;\n\t\t\tcv.push_back(cop[i]);\n\t\t}\n\t\tv = cv;\n\t\t\tv = f_rule(v);\n\t}\n\tif (v.size() == 1) {\n\t\tif (v[0] == target)return 1;\n\t\telse return 0;\n\t}cop = v;\n\t\tv = d_rule(v);\n\tif (v.size() == 1 && !one) {\n\t\tone = true;\n\t\tif (v[0] == target)return 1;\n\t\tvector<int> cv;\n\t\trep(i, cop.size()) {\n\t\t\tif (v[0] == cop[i])continue;\n\t\t\tcv.push_back(cop[i]);\n\t\t}\n\t\tv = cv;\n\t\t\tv = d_rule(v);\n\t}\n\tif (v.size() == 1) {\n\t\tif (v[0] == target)return 1;\n\t\telse return 0;\n\t}cop = v;\n\t\tv = e_rule(v);\n\tif (v.size() == 1 && !one) {\n\t\tone = true;\n\t\tif (v[0] == target)return 1;\n\t\tvector<int> cv;\n\t\trep(i, cop.size()) {\n\t\t\tif (v[0] == i)continue;\n\t\t\tcv.push_back(cop[i]);\n\t\t}\n\t\tv = cv;\n\t\t\tv = e_rule(v);\n\t}\n\tif (v.size() == 1) {\n\t\tif (v[0] == target)return 1;\n\t\telse return 0;\n\t}cop = v;\n\t\tv = f_rule(v);\n\tif (v.size() == 1 && !one) {\n\t\tone = true;\n\t\tif (v[0] == target)return 1;\n\t\tvector<int> cv;\n\t\trep(i, cop.size()) {\n\t\t\tif (v[0] == cop[i])continue;\n\t\t\tcv.push_back(cop[i]);\n\t\t}\n\t\tv = cv;\n\t\t\tv = f_rule(v);\n\t}\n\tif (v.size() == 1) {\n\t\tif (v[0] == target)return 1;\n\t\telse return 0;\n\t}\n\tif (!one) {\n\t\trep(i, v.size()) {\n\t\t\tif (v[i] == target) {\n\t\t\t\treturn 2 / (ld)v.size();\n\t\t\t}\n\t\t}\n\t\treturn 0;\n\t}\n\telse {\n\t\trep(i, v.size()) {\n\t\t\tif (v[i] == target) {\n\t\t\t\treturn 1 / (ld)v.size();\n\t\t\t}\n\t\t}\n\t\treturn 0;\n\t}\n}\nld pos[9];\nld pp[9];\nvoid init() {\n\tpp[0] = 1;\n\trep1(i, 8) {\n\t\tpp[i] = pp[i - 1] * i;\n\t}\n\trep(i, 9) {\n\t\tpos[i] = pp[8] / (pp[i] * pp[8 - i]);\n\t\trep(j, i) {\n\t\t\tpos[i] *= 0.25;\n\t\t}\n\t\trep(j, 8 - i) {\n\t\t\tpos[i] *= 0.75;\n\t\t}\n\t\t//cout << pos[i] << endl;\n\t}\n}\nP check[6] = { {1,11},{1,16},{1,21},{2,16},{2,21},{3,21} };\nP loc[6] = { {0,1},{0,2},{0,3},{1,2},{1,3},{2,3} };\nint main() {\n\tinit();\n\tcout << fixed << setprecision(8);\n\tint n; cin >> n;\n\trep(aa, n) {\n\t\tstring s[5];\n\t\trep(i, 5) {\n\t\t\tcin >> s[i];\n\t\t\tif (s[i][0] == '*')target = i-1;\n\t\t}\n\t\tld out = 0;\n\t\t//int num = 0, hie = 0;\n\t\trep(p1, 9) {\n\t\t\trep(p2, 9) {\n\t\t\t\trep(p3, 9) {\n\t\t\t\t\trep(p4, 9) {\n\t\t\t\t\t\tint now = 0; int cnow = 0;\n\t\t\t\t\t\trep(i, 6) {\n\t\t\t\t\t\t\tint x = check[i].first; int y = check[i].second;\n\t\t\t\t\t\t\tif (s[x][y] == '_') {\n\t\t\t\t\t\t\t\tif (cnow == 0) {\n\t\t\t\t\t\t\t\t\ta[i] = { loc[i].first,loc[i].second,p1,p2 }; cnow++;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\telse {\n\t\t\t\t\t\t\t\t\ta[i] = { loc[i].first,loc[i].second,p3,p4 };\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\telse {\n\t\t\t\t\t\t\t\ta[i] = { loc[i].first,loc[i].second,s[x][y] - '0',s[x][y + 2] - '0' };\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t\tout += pos[p1] * pos[p2] * pos[p3] * pos[p4] * ret();\n\t\t\t\t\t\t//if (ret() == 1)num++;\n\t\t\t\t\t\t//if (ret() == 0)hie++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << out << endl;\n\t\t//cout << num << \" \" << hie << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 3280, "score_of_the_acc": -0.2969, "final_rank": 10 }, { "submission_id": "aoj_1234_3075088", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 4\n\nstruct Info{\n\tbool operator<(const struct Info& arg) const{\n\n\t\tif(points != arg.points){\n\n\t\t\treturn points > arg.points;\n\n\t\t}else if(goal_diff != arg.goal_diff){\n\n\t\t\treturn goal_diff > arg.goal_diff;\n\t\t}else{\n\t\t\treturn sum_goal > arg.sum_goal;\n\t\t}\n\t}\n\tbool operator==(const struct Info &arg) const{\n\t\treturn points == arg.points && goal_diff == arg.goal_diff && sum_goal == arg.sum_goal;\n\t}\n\n\tint team_id,points,goal_diff,sum_goal;\n};\n\nstruct Data{\n\tint from_team,to_team;\n};\n\nstruct State{\n\tState(int arg_team_id,int arg_rank){\n\n\t\tteam_id = arg_team_id;\n\t\trank = arg_rank;\n\t}\n\tint team_id,rank;\n};\n\nint num_case;\nchar table[5][25];\ndouble poss_point[9];\nInfo info[5];\nData data[2];\n\n\nint get_point(char buf[3]){\n\n\tint from_point = buf[0]-'0';\n\tint to_point = buf[2]-'0';\n\n\tif(from_point > to_point){\n\n\t\treturn 3;\n\n\t}else if(from_point == to_point){\n\n\t\treturn 1;\n\n\t}else{\n\n\t\treturn 0;\n\t}\n}\n\nint get_diff(char buf[3]){\n\n\tint from_point = buf[0]-'0';\n\tint to_point = buf[2]-'0';\n\n\treturn from_point-to_point;\n}\n\nvoid init(vector<int> member){\n\n\tfor(int i = 0; i < member.size(); i++){\n\t\tinfo[member[i]].points = 0;\n\t\tinfo[member[i]].goal_diff = 0;\n\t\tinfo[member[i]].sum_goal = 0;\n\t}\n}\n\n//最大2位以内を返す関数(1位が2チーム以上あったら、即返却)\nvector<State> select(vector<int> member){\n\n\tInfo tmp_info[5];\n\tfor(int i = 0; i < member.size(); i++){\n\n\t\ttmp_info[member[i]].points = 0;\n\t\ttmp_info[member[i]].goal_diff = 0;\n\t\ttmp_info[member[i]].sum_goal = 0;\n\t\ttmp_info[member[i]].team_id = member[i];\n\t}\n\n\tint tmp_row,tmp_col,tmp;\n\tchar calc_buf[3];\n\n\tfor(int i = 0; i < member.size()-1; i++){\n\t\tfor(int k = i+1; k < member.size(); k++){\n\n\t\t\ttmp_row = member[i];\n\t\t\ttmp_col = 4+5*(member[k]-1);\n\n\t\t\tfor(int a = 2; a <= 4; a++){\n\t\t\t\tcalc_buf[a-2] = table[tmp_row][tmp_col+a];\n\t\t\t}\n\n\t\t\ttmp = get_point(calc_buf);\n\n\t\t\tif(tmp == 1){\n\n\t\t\t\ttmp_info[member[i]].points += 1;\n\t\t\t\ttmp_info[member[k]].points += 1;\n\n\t\t\t}else{\n\n\t\t\t\ttmp_info[member[i]].points += tmp;\n\t\t\t\ttmp_info[member[k]].points += 3-tmp;\n\t\t\t}\n\n\t\t\ttmp = get_diff(calc_buf);\n\n\t\t\ttmp_info[member[i]].goal_diff += tmp;\n\t\t\ttmp_info[member[k]].goal_diff -= tmp;\n\n\t\t\ttmp_info[member[i]].sum_goal += calc_buf[0]-'0';\n\t\t\ttmp_info[member[k]].sum_goal += calc_buf[2]-'0';\n\t\t}\n\t}\n\n\tvector<State> ret;\n\tvector<Info> calc_info;\n\n\tint num = (int)member.size();\n\t//printf(\"num:%d\\n\",num);\n\n\tfor(int i = 0; i < num; i++){\n\t\tcalc_info.push_back(tmp_info[member[i]]);\n\t}\n\n\tsort(calc_info.begin(),calc_info.end());\n\n\tint base_index = 0,rank = 0,right;\n\n\twhile(ret.size() < 2 && rank < 2 && base_index < num){\n\n\t\tret.push_back(State(calc_info[base_index].team_id,rank));\n\n\t\tright = base_index+1;\n\t\tif(right == num)break;\n\n\t\tif(calc_info[base_index] == calc_info[right]){\n\n\t\t\twhile(right < num && calc_info[base_index] == calc_info[right]){\n\t\t\t\tret.push_back(State(calc_info[right].team_id,rank));\n\t\t\t\tright++;\n\t\t\t}\n\t\t\tbase_index = right;\n\n\t\t}else{\n\n\t\t\tbase_index = right;\n\t\t}\n\t\trank++;\n\t}\n\n\treturn ret;\n}\n\nvoid func(){\n\n\tint base_team,work_index,data_index = 0;\n\n\tchar work[3];\n\tvector<int> member;\n\n\tfor(int i = 1; i <= 4; i++){\n\t\tmember.push_back(i);\n\t\tinfo[i].team_id = i;\n\t}\n\n\tinit(member);\n\n\tint from_team,to_team,tmp;\n\n\tfor(int row = 0; row <= NUM; row++){\n\t\tscanf(\"%s\",table[row]);\n\t\tif(table[row][0] == '*'){\n\t\t\tbase_team = row;\n\t\t}\n\n\t\tif(row == 0)continue;\n\n\t\tfrom_team = row;\n\t\tto_team = from_team+1;\n\n\t\tfor(int start_col = 4+5*row; start_col <= 19; start_col += 5,to_team++){\n\n\t\t\tif(table[row][start_col+2] == '_'){ //★結果不明な組合せ★\n\n\t\t\t\tdata[data_index].from_team = from_team;\n\t\t\t\tdata[data_index++].to_team = to_team;\n\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\twork_index = 0;\n\t\t\tfor(int i = 2; i <= 4; i++){\n\t\t\t\twork[work_index++] = table[row][start_col+i];\n\t\t\t}\n\n\t\t\t//勝ち点\n\t\t\ttmp = get_point(work);\n\n\t\t\tif(tmp == 1){\n\n\t\t\t\tinfo[from_team].points += 1;\n\t\t\t\tinfo[to_team].points += 1;\n\n\t\t\t}else{\n\n\t\t\t\tinfo[from_team].points += tmp;\n\t\t\t\tinfo[to_team].points += 3-tmp;\n\t\t\t}\n\n\t\t\t//goal_diff\n\t\t\ttmp = get_diff(work);\n\t\t\tinfo[from_team].goal_diff += tmp;\n\t\t\tinfo[to_team].goal_diff -= tmp;\n\n\t\t\t//goal総数\n\t\t\tinfo[from_team].sum_goal += work[0]-'0';\n\t\t\tinfo[to_team].sum_goal += work[2]-'0';\n\t\t}\n\t}\n\n\tdouble ans = 0;\n\tdouble tmp_poss;\n\n\tvector<State> Top_Group;\n\n\tint tmp_from,tmp_to;\n\tint pre_size,num_decided,tmp_index,num_rank_0;\n\n\tbool check[5];\n\tbool FLG;\n\n\t//未判明の、2試合の得点を全探索\n\tfor(int from_1 = 0; from_1 <= 8;from_1++){\n\t\tfor(int to_1 = 0; to_1 <= 8; to_1++){\n\t\t\tfor(int from_2 = 0; from_2 <= 8; from_2++){\n\t\t\t\tfor(int to_2 = 0; to_2 <= 8; to_2++){\n\n\t\t\t\t\tTop_Group.clear();\n\t\t\t\t\ttmp_poss = 1.0;\n\n\t\t\t\t\t//まず、このトーナメント表が出来上がる確率を求める\n\t\t\t\t\ttmp_poss *= poss_point[from_1];\n\t\t\t\t\ttmp_poss *= poss_point[to_1];\n\t\t\t\t\ttmp_poss *= poss_point[from_2];\n\t\t\t\t\ttmp_poss *= poss_point[to_2];\n\n\t\t\t\t\tmember.clear();\n\t\t\t\t\tfor(int i = 1; i <= 4; i++){\n\t\t\t\t\t\tmember.push_back(i);\n\t\t\t\t\t}\n\n\t\t\t\t\t//★表を完成させる★\n\n\t\t\t\t\tfor(int loop = 0; loop < 2; loop++){\n\n\t\t\t\t\t\tfrom_team = data[loop].from_team;\n\t\t\t\t\t\tto_team = data[loop].to_team;\n\n\t\t\t\t\t\tif(loop == 0){\n\n\t\t\t\t\t\t\ttmp_from = from_1;\n\t\t\t\t\t\t\ttmp_to = to_1;\n\n\t\t\t\t\t\t}else{\n\n\t\t\t\t\t\t\ttmp_from = from_2;\n\t\t\t\t\t\t\ttmp_to = to_2;\n\t\t\t\t\t\t}\n\n\t\t\t\t\t\t//★テーブルを埋める★\n\t\t\t\t\t\ttable[from_team][4+5*(to_team-1)+2] = '0'+tmp_from;\n\t\t\t\t\t\ttable[from_team][4+5*(to_team-1)+3] = '-';\n\t\t\t\t\t\ttable[from_team][4+5*(to_team-1)+4] = '0'+tmp_to;\n\t\t\t\t\t}\n\n\t\t\t\t\tnum_decided = 0;\n\t\t\t\t\t//上位チームを選んでみる(1回目)\n\t\t\t\t\tTop_Group = select(member);\n\n\t\t\t\t\tFLG = false;\n\n\t\t\t\t\tnum_rank_0 = 0;\n\t\t\t\t\tfor(int k = 0; k < Top_Group.size(); k++){\n\n\t\t\t\t\t\tif(Top_Group[k].rank == 0)num_rank_0++;\n\n\t\t\t\t\t\tif(base_team == Top_Group[k].team_id){\n\t\t\t\t\t\t\ttmp_index = k;\n\t\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\n\t\t\t\t\tif(Top_Group.size() == 2){\n\n\t\t\t\t\t\t//上位2チームに入っていればOK、そうでなければ不可\n\t\t\t\t\t\tif(FLG){\n\t\t\t\t\t\t\tans += tmp_poss;\n\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\t//Do nothing\n\t\t\t\t\t\t}\n\t\t\t\t\t\tcontinue;\n\n\t\t\t\t\t}else if(Top_Group.size() == 3){\n\n\t\t\t\t\t\t//★★上位3チームに含まれていなければ不可★★\n\t\t\t\t\t\tif(!FLG)continue;\n\n\t\t\t\t\t\t//★単独1位ならOK★\n\t\t\t\t\t\tif(Top_Group[tmp_index].rank == 0 && num_rank_0 == 1){\n\t\t\t\t\t\t\tans += tmp_poss;\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\n\t\t\t\t\t}else{ //Top_Group.size() == 4\n\n\t\t\t\t\t\t//★単独1位ならOK★\n\t\t\t\t\t\tif(Top_Group[tmp_index].rank == 0 && num_rank_0 == 1){\n\t\t\t\t\t\t\tans += tmp_poss;\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\n\t\t\t\t\t//通過or脱落が確定した人物を取り除く\n\t\t\t\t\tif(num_rank_0 == (int)Top_Group.size()){ //1位が3個か4個\n\n\t\t\t\t\t\tif(num_rank_0 == 3){ //1人脱落\n\n\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++)check[k] = false;\n\n\t\t\t\t\t\t\tfor(int i = 0; i < Top_Group.size(); i++){\n\t\t\t\t\t\t\t\tcheck[Top_Group[i].team_id] = true;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tmember.clear();\n\n\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++){\n\t\t\t\t\t\t\t\tif(check[k]){\n\t\t\t\t\t\t\t\t\tmember.push_back(k);\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t}else{ //1位が4人\n\t\t\t\t\t\t\t//Do nothing\n\t\t\t\t\t\t}\n\n\t\t\t\t\t}else if(num_rank_0 != (int)Top_Group.size()){ //num_rank_0が2以上なら、1ターン目で返る==Top_Groupのサイズと一致する。よって、num_rank_0 == 1\n\n\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++)check[k] = false;\n\n\t\t\t\t\t\t\tfor(int i = 0; i < Top_Group.size(); i++){\n\t\t\t\t\t\t\t\tcheck[Top_Group[i].team_id] = true;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tmember.clear();\n\n\t\t\t\t\t\t\tfor(int k = 0; k < Top_Group.size(); k++){\n\t\t\t\t\t\t\t\tif(Top_Group[k].rank != 0)continue;\n\n\t\t\t\t\t\t\t\tnum_decided++;\n\t\t\t\t\t\t\t\tcheck[Top_Group[k].team_id] = false; //通過が確定したので集合から除く\n\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++){\n\t\t\t\t\t\t\t\tif(check[k]){\n\t\t\t\t\t\t\t\t\tmember.push_back(k);\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t}\n\n\t\t\t\t\tint debug = (int)member.size();\n\t\t\t\t\tpre_size = (int)member.size();\n\n\t\t\t\t\t//★★2位通過が決定するまで、ループ★★\n\t\t\t\t\twhile(true){\n\n\t\t\t\t\t\tTop_Group = select(member);\n\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\tnum_rank_0 = 0;\n\t\t\t\t\t\tfor(int k = 0; k < Top_Group.size(); k++){\n\n\t\t\t\t\t\t\tif(Top_Group[k].rank == 0)num_rank_0++;\n\n\t\t\t\t\t\t\tif(base_team == Top_Group[k].team_id){\n\t\t\t\t\t\t\t\ttmp_index = k;\n\t\t\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\n\t\t\t\t\t\tif(num_decided+(int)Top_Group.size() == 2){ //上位2チーム決定\n\n\t\t\t\t\t\t\tif(FLG){ //上位2チームに含まれれば良い\n\n\t\t\t\t\t\t\t\tans += tmp_poss;\n\n\t\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\t\t//Do nothing\n\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\tbreak;\n\n\t\t\t\t\t\t}else if(num_decided+num_rank_0 == 2){ //1位のチームのみ抜き出せば、上位2チーム決定\n\n\t\t\t\t\t\t\tif(FLG == true && Top_Group[tmp_index].rank == 0){ //1位\n\n\t\t\t\t\t\t\t\tans += tmp_poss;\n\n\t\t\t\t\t\t\t}else{ //★他のチームによって枠が取られた場合★\n\n\t\t\t\t\t\t\t\t//Do nothing\n\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\n\n\t\t\t\t\t\t//通過or脱落が確定した人物を取り除く\n\t\t\t\t\t\tif(num_rank_0 == (int)Top_Group.size()){ //1位が2~4個\n\n\t\t\t\t\t\t\tif(num_rank_0 <= 3){ //1人~2人脱落\n\n\t\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++)check[k] = false;\n\n\t\t\t\t\t\t\t\tfor(int i = 0; i < Top_Group.size(); i++){\n\t\t\t\t\t\t\t\t\tcheck[Top_Group[i].team_id] = true;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tmember.clear();\n\n\t\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++){\n\t\t\t\t\t\t\t\t\tif(check[k]){\n\t\t\t\t\t\t\t\t\t\tmember.push_back(k);\n\t\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\t}else{ //1位が4人\n\t\t\t\t\t\t\t\t//Do nothing\n\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t}else if(num_rank_0 != Top_Group.size()){\n\n\t\t\t\t\t\t\t\tif(FLG == true && Top_Group[tmp_index].rank == 0){ //単独1位\n\t\t\t\t\t\t\t\t\tans += tmp_poss;\n\t\t\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++)check[k] = false;\n\n\t\t\t\t\t\t\t\tfor(int i = 0; i < member.size(); i++){\n\t\t\t\t\t\t\t\t\tcheck[member[i]] = true;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tmember.clear();\n\n\t\t\t\t\t\t\t\tfor(int k = 0; k < Top_Group.size(); k++){\n\t\t\t\t\t\t\t\t\tif(Top_Group[k].rank != 0)continue;\n\n\t\t\t\t\t\t\t\t\tnum_decided++;\n\t\t\t\t\t\t\t\t\tcheck[Top_Group[k].team_id] = false; //通過が確定したので集合から除く\n\t\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++){\n\t\t\t\t\t\t\t\t\tif(check[k]){\n\t\t\t\t\t\t\t\t\t\tmember.push_back(k);\n\t\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\n\n\t\t\t\t\t\tif((int)member.size() == pre_size){\n\n\t\t\t\t\t\t\tif(FLG){\n\n\t\t\t\t\t\t\t\tif(num_decided == 1){ //1つ選ぶ\n\n\t\t\t\t\t\t\t\t\tans += tmp_poss/(double)member.size();\n\n\t\t\t\t\t\t\t\t}else{ //★★★2つ選ぶ★★★\n\n\t\t\t\t\t\t\t\t\tans += tmp_poss*2.0/(double)member.size();\n\t\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\t}else{\n\n\t\t\t\t\t\t\t\t//Do nothing\n\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\n\t\t\t\t\t\tpre_size = (int)member.size();\n\t\t\t\t\t}\n\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%.10lf\\n\",ans);\n\n}\n\nvoid calc_poss(){\n\n\tint nCm[9][9];\n\n\tfor(int i = 0; i <= 8; i++){\n\t\tfor(int k = 0; k <= 8; k++)nCm[i][k]= 0;\n\t}\n\n\tnCm[0][0] = 1;\n\tfor(int n = 1; n <= 8; n++) {\n\t\tfor (int k = 0; k <= 8; k++) {\n\t\t\tif(k > 0){\n\t\t\t\tnCm[n][k] = nCm[n-1][k]+nCm[n-1][k-1];\n\t\t\t}else{ //k == 0\n\t\t\t\tnCm[n][k] = 1;\n\t\t\t}\n\t\t}\n\t}\n\n\tdouble poss;\n\n\tfor(int point = 0; point <= 8; point++){\n\n\t\tposs = nCm[8][point];\n\n\t\tfor(int i = 0; i < point; i++){\n\t\t\tposs *= 0.25;\n\t\t}\n\t\tfor(int i = 0; i < 8-point; i++){\n\t\t\tposs *= 0.75;\n\t\t}\n\t\tposs_point[point] = poss;\n\t}\n}\n\nint main(){\n\n\tcalc_poss();\n\n\tscanf(\"%d\",&num_case);\n\n\tfor(int loop = 0; loop < num_case; loop++){\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3252, "score_of_the_acc": -0.2211, "final_rank": 7 }, { "submission_id": "aoj_1234_3075078", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 4\n\nstruct Info{\n\tbool operator<(const struct Info& arg) const{\n\n\t\tif(points != arg.points){\n\n\t\t\treturn points > arg.points;\n\n\t\t}else if(goal_diff != arg.goal_diff){\n\n\t\t\treturn goal_diff > arg.goal_diff;\n\t\t}else{\n\t\t\treturn sum_goal > arg.sum_goal;\n\t\t}\n\t}\n\tbool operator==(const struct Info &arg) const{\n\t\treturn points == arg.points && goal_diff == arg.goal_diff && sum_goal == arg.sum_goal;\n\t}\n\n\tint team_id,points,goal_diff,sum_goal;\n};\n\nstruct Data{\n\tint from_team,to_team;\n};\n\nstruct State{\n\tState(int arg_team_id,int arg_rank){\n\n\t\tteam_id = arg_team_id;\n\t\trank = arg_rank;\n\t}\n\tint team_id,rank;\n};\n\nint num_case;\nchar table[5][25];\ndouble poss_point[9];\nInfo info[5];\nData data[2];\n\n\nint get_point(char buf[3]){\n\n\tint from_point = buf[0]-'0';\n\tint to_point = buf[2]-'0';\n\n\tif(from_point > to_point){\n\n\t\treturn 3;\n\n\t}else if(from_point == to_point){\n\n\t\treturn 1;\n\n\t}else{\n\n\t\treturn 0;\n\t}\n}\n\nint get_diff(char buf[3]){\n\n\tint from_point = buf[0]-'0';\n\tint to_point = buf[2]-'0';\n\n\treturn from_point-to_point;\n}\n\nvoid init(vector<int> member){\n\n\tfor(int i = 0; i < member.size(); i++){\n\t\tinfo[member[i]].points = 0;\n\t\tinfo[member[i]].goal_diff = 0;\n\t\tinfo[member[i]].sum_goal = 0;\n\t}\n}\n\n//最大2位以内を返す関数(1位が2チーム以上あったら、即返却)\nvector<State> select(vector<int> member){\n\n\tInfo tmp_info[5];\n\tfor(int i = 0; i < member.size(); i++){\n\n\t\ttmp_info[member[i]].points = 0;\n\t\ttmp_info[member[i]].goal_diff = 0;\n\t\ttmp_info[member[i]].sum_goal = 0;\n\t\ttmp_info[member[i]].team_id = member[i];\n\t}\n\n\tint tmp_row,tmp_col,tmp;\n\tchar calc_buf[3];\n\n\tfor(int i = 0; i < member.size()-1; i++){\n\t\tfor(int k = i+1; k < member.size(); k++){\n\n\t\t\ttmp_row = member[i];\n\t\t\ttmp_col = 4+5*(member[k]-1);\n\n\t\t\tfor(int a = 2; a <= 4; a++){\n\t\t\t\tcalc_buf[a-2] = table[tmp_row][tmp_col+a];\n\t\t\t}\n\n\t\t\ttmp = get_point(calc_buf);\n\n\t\t\tif(tmp == 1){\n\n\t\t\t\ttmp_info[member[i]].points += 1;\n\t\t\t\ttmp_info[member[k]].points += 1;\n\n\t\t\t}else{\n\n\t\t\t\ttmp_info[member[i]].points += tmp;\n\t\t\t\ttmp_info[member[k]].points += 3-tmp;\n\t\t\t}\n\n\t\t\ttmp = get_diff(calc_buf);\n\n\t\t\ttmp_info[member[i]].goal_diff += tmp;\n\t\t\ttmp_info[member[k]].goal_diff -= tmp;\n\n\t\t\ttmp_info[member[i]].sum_goal += calc_buf[0]-'0';\n\t\t\ttmp_info[member[k]].sum_goal += calc_buf[2]-'0';\n\t\t}\n\t}\n\n\tvector<State> ret;\n\tvector<Info> calc_info;\n\n\tint num = (int)member.size();\n\t//printf(\"num:%d\\n\",num);\n\n\tfor(int i = 0; i < num; i++){\n\t\tcalc_info.push_back(tmp_info[member[i]]);\n\t}\n\n\tsort(calc_info.begin(),calc_info.end());\n\n\tint base_index = 0,rank = 0,right;\n\n\twhile(ret.size() < 2 && rank < 2 && base_index < num){\n\n\t\tret.push_back(State(calc_info[base_index].team_id,rank));\n\n\t\tright = base_index+1;\n\t\tif(right == num)break;\n\n\t\tif(calc_info[base_index] == calc_info[right]){\n\n\t\t\twhile(right < num && calc_info[base_index] == calc_info[right]){\n\t\t\t\tret.push_back(State(calc_info[right].team_id,rank));\n\t\t\t\tright++;\n\t\t\t}\n\t\t\tbase_index = right;\n\n\t\t}else{\n\n\t\t\tbase_index = right;\n\t\t}\n\t\trank++;\n\t}\n\n\treturn ret;\n}\n\nvoid func(){\n\n\tint base_team,work_index,data_index = 0;\n\n\tchar work[3];\n\tvector<int> member;\n\n\tfor(int i = 1; i <= 4; i++){\n\t\tmember.push_back(i);\n\t\tinfo[i].team_id = i;\n\t}\n\n\tinit(member);\n\n\tint from_team,to_team,tmp;\n\n\tfor(int row = 0; row <= NUM; row++){\n\t\tscanf(\"%s\",table[row]);\n\t\tif(table[row][0] == '*'){\n\t\t\tbase_team = row;\n\t\t}\n\n\t\tif(row == 0)continue;\n\n\t\tfrom_team = row;\n\t\tto_team = from_team+1;\n\n\t\tfor(int start_col = 4+5*row; start_col <= 19; start_col += 5,to_team++){\n\n\t\t\tif(table[row][start_col+2] == '_'){ //★結果不明な組合せ★\n\n\t\t\t\tdata[data_index].from_team = from_team;\n\t\t\t\tdata[data_index++].to_team = to_team;\n\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\twork_index = 0;\n\t\t\tfor(int i = 2; i <= 4; i++){\n\t\t\t\twork[work_index++] = table[row][start_col+i];\n\t\t\t}\n\n\t\t\t//勝ち点\n\t\t\ttmp = get_point(work);\n\n\t\t\tif(tmp == 1){\n\n\t\t\t\tinfo[from_team].points += 1;\n\t\t\t\tinfo[to_team].points += 1;\n\n\t\t\t}else{\n\n\t\t\t\tinfo[from_team].points += tmp;\n\t\t\t\tinfo[to_team].points += 3-tmp;\n\t\t\t}\n\n\t\t\t//goal_diff\n\t\t\ttmp = get_diff(work);\n\t\t\tinfo[from_team].goal_diff += tmp;\n\t\t\tinfo[to_team].goal_diff -= tmp;\n\n\t\t\t//goal総数\n\t\t\tinfo[from_team].sum_goal += work[0]-'0';\n\t\t\tinfo[to_team].sum_goal += work[2]-'0';\n\t\t}\n\t}\n\n\tdouble ans = 0;\n\tdouble tmp_poss;\n\n\tvector<State> Top_Group;\n\n\tint tmp_from,tmp_to;\n\tint pre_size,num_decided,tmp_index,num_rank_0;\n\n\tbool check[5];\n\tbool FLG;\n\n\t//未判明の、2試合の得点を全探索\n\tfor(int from_1 = 0; from_1 <= 8;from_1++){\n\t\tfor(int to_1 = 0; to_1 <= 8; to_1++){\n\t\t\tfor(int from_2 = 0; from_2 <= 8; from_2++){\n\t\t\t\tfor(int to_2 = 0; to_2 <= 8; to_2++){\n\n\t\t\t\t\tTop_Group.clear();\n\t\t\t\t\ttmp_poss = 1.0;\n\n\t\t\t\t\t//まず、このトーナメント表が出来上がる確率を求める\n\t\t\t\t\ttmp_poss *= poss_point[from_1];\n\t\t\t\t\ttmp_poss *= poss_point[to_1];\n\t\t\t\t\ttmp_poss *= poss_point[from_2];\n\t\t\t\t\ttmp_poss *= poss_point[to_2];\n\n\t\t\t\t\tmember.clear();\n\t\t\t\t\tfor(int i = 1; i <= 4; i++){\n\t\t\t\t\t\tmember.push_back(i);\n\t\t\t\t\t}\n\n\t\t\t\t\t//★表を完成させる★\n\n\t\t\t\t\tfor(int loop = 0; loop < 2; loop++){\n\n\t\t\t\t\t\tfrom_team = data[loop].from_team;\n\t\t\t\t\t\tto_team = data[loop].to_team;\n\n\t\t\t\t\t\tif(loop == 0){\n\n\t\t\t\t\t\t\ttmp_from = from_1;\n\t\t\t\t\t\t\ttmp_to = to_1;\n\n\t\t\t\t\t\t}else{\n\n\t\t\t\t\t\t\ttmp_from = from_2;\n\t\t\t\t\t\t\ttmp_to = to_2;\n\t\t\t\t\t\t}\n\n\t\t\t\t\t\t//★テーブルを埋める★\n\t\t\t\t\t\ttable[from_team][4+5*(to_team-1)+2] = '0'+tmp_from;\n\t\t\t\t\t\ttable[from_team][4+5*(to_team-1)+3] = '-';\n\t\t\t\t\t\ttable[from_team][4+5*(to_team-1)+4] = '0'+tmp_to;\n\t\t\t\t\t}\n\n\t\t\t\t\tnum_decided = 0;\n\t\t\t\t\t//上位チームを選んでみる(1回目)\n\t\t\t\t\tTop_Group = select(member);\n\n\t\t\t\t\tFLG = false;\n\n\t\t\t\t\tnum_rank_0 = 0;\n\t\t\t\t\tfor(int k = 0; k < Top_Group.size(); k++){\n\n\t\t\t\t\t\tif(Top_Group[k].rank == 0)num_rank_0++;\n\n\t\t\t\t\t\tif(base_team == Top_Group[k].team_id){\n\t\t\t\t\t\t\ttmp_index = k;\n\t\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\n\t\t\t\t\tif(Top_Group.size() == 2){\n\n\t\t\t\t\t\t//上位2チームに入っていればOK、そうでなければ不可\n\t\t\t\t\t\tif(FLG){\n\t\t\t\t\t\t\tans += tmp_poss;\n\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\t//Do nothing\n\t\t\t\t\t\t}\n\t\t\t\t\t\tcontinue;\n\n\t\t\t\t\t}else if(Top_Group.size() == 3){\n\n\t\t\t\t\t\t//★★上位3チームに含まれていなければ不可★★\n\t\t\t\t\t\tif(!FLG)continue;\n\n\t\t\t\t\t\t//★単独1位ならOK★\n\t\t\t\t\t\tif(Top_Group[tmp_index].rank == 0 && num_rank_0 == 1){\n\t\t\t\t\t\t\tans += tmp_poss;\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\n\t\t\t\t\t}else{ //Top_Group.size() == 4\n\n\t\t\t\t\t\t//★単独1位ならOK★\n\t\t\t\t\t\tif(Top_Group[tmp_index].rank == 0 && num_rank_0 == 1){\n\t\t\t\t\t\t\tans += tmp_poss;\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\n\t\t\t\t\t//通過or脱落が確定した人物を取り除く\n\t\t\t\t\tif(num_rank_0 == (int)Top_Group.size()){ //1位が3個か4個\n\n\t\t\t\t\t\tif(num_rank_0 == 3){ //1人脱落\n\n\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++)check[k] = false;\n\n\t\t\t\t\t\t\tfor(int i = 0; i < Top_Group.size(); i++){\n\t\t\t\t\t\t\t\tcheck[Top_Group[i].team_id] = true;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tmember.clear();\n\n\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++){\n\t\t\t\t\t\t\t\tif(check[k]){\n\t\t\t\t\t\t\t\t\tmember.push_back(k);\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t}else{ //1位が4人\n\t\t\t\t\t\t\t//Do nothing\n\t\t\t\t\t\t}\n\n\t\t\t\t\t}else if(num_rank_0 != (int)Top_Group.size()){ //num_rank_0が2以上なら、1ターン目で返る==Top_Groupのサイズと一致する。よって、num_rank_0 == 1\n\n\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++)check[k] = false;\n\n\t\t\t\t\t\t\tfor(int i = 0; i < Top_Group.size(); i++){\n\t\t\t\t\t\t\t\tcheck[Top_Group[i].team_id] = true;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tmember.clear();\n\n\t\t\t\t\t\t\tfor(int k = 0; k < Top_Group.size(); k++){\n\t\t\t\t\t\t\t\tif(Top_Group[k].rank != 0)continue;\n\n\t\t\t\t\t\t\t\tnum_decided++;\n\t\t\t\t\t\t\t\tcheck[Top_Group[k].team_id] = false; //通過が確定したので集合から除く\n\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++){\n\t\t\t\t\t\t\t\tif(check[k]){\n\t\t\t\t\t\t\t\t\tmember.push_back(k);\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t}\n\n\t\t\t\t\tint debug = (int)member.size();\n\t\t\t\t\tpre_size = (int)member.size();\n\n\t\t\t\t\t//★★2位通過が決定するまで、ループ★★\n\t\t\t\t\twhile(true){\n\n\t\t\t\t\t\tTop_Group = select(member);\n\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\tnum_rank_0 = 0;\n\t\t\t\t\t\tfor(int k = 0; k < Top_Group.size(); k++){\n\n\t\t\t\t\t\t\tif(Top_Group[k].rank == 0)num_rank_0++;\n\n\t\t\t\t\t\t\tif(base_team == Top_Group[k].team_id){\n\t\t\t\t\t\t\t\ttmp_index = k;\n\t\t\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\n\t\t\t\t\t\tif(num_decided+(int)Top_Group.size() == 2){ //上位2チーム決定\n\n\t\t\t\t\t\t\tif(FLG){ //上位2チームに含まれれば良い\n\n\t\t\t\t\t\t\t\tans += tmp_poss;\n\n\t\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\t\t//Do nothing\n\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\tbreak;\n\n\t\t\t\t\t\t}else if(num_decided+num_rank_0 == 2){ //1位のチームのみ抜き出せば、上位2チーム決定\n\n\t\t\t\t\t\t\tif(FLG == true && Top_Group[tmp_index].rank == 0){ //1位\n\n\t\t\t\t\t\t\t\tans += tmp_poss;\n\n\t\t\t\t\t\t\t}else{ //★他のチームによって枠が取られた場合★\n\n\t\t\t\t\t\t\t\t//Do nothing\n\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\n\n\t\t\t\t\t\t//通過or脱落が確定した人物を取り除く\n\t\t\t\t\t\tif(num_rank_0 == (int)Top_Group.size()){ //1位が2~4個\n\n\t\t\t\t\t\t\tif(num_rank_0 <= 1){\n\t\t\t\t\t\t\t\tprintf(\"Screw\\n\");\n\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\tif(num_rank_0 <= 3){ //1人~2人脱落\n\n\t\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++)check[k] = false;\n\n\t\t\t\t\t\t\t\tfor(int i = 0; i < Top_Group.size(); i++){\n\t\t\t\t\t\t\t\t\tcheck[Top_Group[i].team_id] = true;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tmember.clear();\n\n\t\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++){\n\t\t\t\t\t\t\t\t\tif(check[k]){\n\t\t\t\t\t\t\t\t\t\tmember.push_back(k);\n\t\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\t}else{ //1位が4人\n\t\t\t\t\t\t\t\t//Do nothing\n\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t}else if(num_rank_0 != Top_Group.size()){\n\n\t\t\t\t\t\t\t\tif(num_rank_0 >= 2){\n\t\t\t\t\t\t\t\t\tprintf(\"ABAB498\\n\");\n\t\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\t\tif(FLG == true && Top_Group[tmp_index].rank == 0){ //単独1位\n\t\t\t\t\t\t\t\t\tans += tmp_poss;\n\t\t\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++)check[k] = false;\n\n\t\t\t\t\t\t\t\tfor(int i = 0; i < member.size(); i++){\n\t\t\t\t\t\t\t\t\tcheck[member[i]] = true;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tmember.clear();\n\n\t\t\t\t\t\t\t\tfor(int k = 0; k < Top_Group.size(); k++){\n\t\t\t\t\t\t\t\t\tif(Top_Group[k].rank != 0)continue;\n\n\t\t\t\t\t\t\t\t\tnum_decided++;\n\t\t\t\t\t\t\t\t\tcheck[Top_Group[k].team_id] = false; //通過が確定したので集合から除く\n\t\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\t\tfor(int k = 1; k <= 4; k++){\n\t\t\t\t\t\t\t\t\tif(check[k]){\n\t\t\t\t\t\t\t\t\t\tmember.push_back(k);\n\t\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\n\n\t\t\t\t\t\tif((int)member.size() == pre_size){\n\n\t\t\t\t\t\t\tif(FLG){\n\n\t\t\t\t\t\t\t\tif(num_decided == 1){\n\n\t\t\t\t\t\t\t\t\tans += tmp_poss/(double)member.size();\n\n\t\t\t\t\t\t\t\t}else{\n\n\t\t\t\t\t\t\t\t\tans += tmp_poss*2.0/(double)member.size();\n\t\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\t}else{\n\n\t\t\t\t\t\t\t\t//Do nothing\n\t\t\t\t\t\t\t}\n\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\n\t\t\t\t\t\tpre_size = (int)member.size();\n\t\t\t\t\t}\n\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%.10lf\\n\",ans);\n\n}\n\nvoid calc_poss(){\n\n\tint nCm[9][9];\n\n\tfor(int i = 0; i <= 8; i++){\n\t\tfor(int k = 0; k <= 8; k++)nCm[i][k]= 0;\n\t}\n\n\tnCm[0][0] = 1;\n\tfor(int n = 1; n <= 8; n++) {\n\t\tfor (int k = 0; k <= 8; k++) {\n\t\t\tif(k > 0){\n\t\t\t\tnCm[n][k] = nCm[n-1][k]+nCm[n-1][k-1];\n\t\t\t}else{ //k == 0\n\t\t\t\tnCm[n][k] = 1;\n\t\t\t}\n\t\t}\n\t}\n\n\tdouble poss;\n\n\tfor(int point = 0; point <= 8; point++){\n\n\t\tposs = nCm[8][point];\n\n\t\tfor(int i = 0; i < point; i++){\n\t\t\tposs *= 0.25;\n\t\t}\n\t\tfor(int i = 0; i < 8-point; i++){\n\t\t\tposs *= 0.75;\n\t\t}\n\t\tposs_point[point] = poss;\n\t}\n}\n\nint main(){\n\n\tcalc_poss();\n\t//return 0;\n\n\tscanf(\"%d\",&num_case);\n\n\tfor(int loop = 0; loop < num_case; loop++){\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3112, "score_of_the_acc": -0.0176, "final_rank": 1 }, { "submission_id": "aoj_1234_3040843", "code_snippet": "#include <bits/stdc++.h>\n#define double long double\n#define int long long\nusing namespace std;\n\ntypedef pair<int,int> P;\ntypedef pair<string,string> P1;\ntypedef pair<int,string> P2;\ntypedef pair<P,P2> P3;\n\nint fac(int n){\n int res = 1;\n for(int i=1;i<=n;i++) res *= i;\n return res;\n}\n\ndouble get(int i){\n return fac(8) * pow(1.0/4,i) * pow(3.0/4,8-i) / ( fac(i) * fac( 8 - i ) );\n}\n\nstring s[5];\nstring target;\ndouble ans;\n\nvector<P3> calcOrder(set<string> teams){\n \n map<string,int> points, diff, ggoals;\n \n for(int i=0;i<5;i++){\n \n for(int j=0;j<(int)s[i].size();j++){\n \n if( s[i][j] != '-' ) continue;\n \n string t1 = s[i].substr( 1, 3 );\n string t2 = s[0].substr( j - 1, 3 );\n \n if( teams.count(t1) == 0 ) continue;\n if( teams.count(t2) == 0 ) continue;\n \n int t1p = s[i][j-1] - '0';\n int t2p = s[i][j+1] - '0';\n \n if( t1p > t2p ) points[t1] += 3;\n if( t1p == t2p ) points[t1]++, points[t2]++;\n if( t1p < t2p ) points[t2] += 3;\n \n diff[t1] += t1p - t2p;\n diff[t2] += t2p - t1p;\n \n ggoals[t1] += t1p;\n ggoals[t2] += t2p;\n \n }\n \n }\n \n vector<P3> res;\n \n for(string team : teams){\n res.push_back(P3(P(points[team],diff[team]),P2(ggoals[team],team)));\n }\n \n sort( res.begin(), res.end(), greater<P3>() );\n \n return res;\n}\n\nvoid cal(double p){\n \n set<string> teams;\n \n for(int i=0;i<5;i++){\n \n for(int j=0;j<(int)s[i].size();j++){\n \n if( s[i][j] != '-' ) continue;\n \n string t1 = s[i].substr( 1, 3 );\n string t2 = s[0].substr( j - 1, 3 );\n \n teams.insert(t1);\n teams.insert(t2);\n \n }\n \n }\n \n vector<P3> order = calcOrder( teams );\n \n int cnt = 5, add = 0, L, R;\n \n while(cnt--){\n \n int A, B, C;\n \n for(int i=0;i<(int)order.size();i++){\n \n if( order[i].second.second == target ){\n\tA = order[i].first.first;\n\tB = order[i].first.second;\n\tC = order[i].second.first;\n }\n \n }\n \n int l = 4, r = 0;\n \n for(int i=0;i<(int)order.size();i++){\n \n if( A == order[i].first.first && B == order[i].first.second && C == order[i].second.first ){\n \n\tl = min( l, i );\n\tr = max( r, i );\n \n }\n \n }\n \n teams.clear();\n \n for(int i=l;i<=r;i++) teams.insert( order[i].second.second );\n \n add += l;\n \n L = l, R = r;\n \n order = calcOrder( teams );\n \n }\n \n if( L == R ){\n \n if( add <= 1 ) ans += p;\n \n }else{\n \n if( add <= 1 ){\n \n double chance = 1 - add + 1;\n double all = R - L + 1;\n \n ans += p * chance / all;\n \n }\n \n }\n \n}\n\nvector<P> YX;\n\nsigned main(){\n \n int T;\n cin>>T;\n \n while(T--){\n \n YX.clear();\n ans = 0;\n \n for(int i=0;i<5;i++) cin>>s[i];\n \n for(int i=0;i<(int)s[0].size();i++){\n if( s[0][i] == '*' ) target = s[0].substr( i + 1, 3 );\n }\n \n for(int i=0;i<5;i++){\n for(int j=0;j<(int)s[i].size();j++){\n\tif( s[i][j] == '-' && s[i][j-1] == '_' ) YX.push_back(P(i,j-1));\n\n\tif( s[i][j] == '-' && s[i][j+1] == '_' ) YX.push_back(P(i,j+1));\n }\n }\n \n for(int i=0;i<=8;i++){\n for(int j=0;j<=8;j++){\n\tfor(int k=0;k<=8;k++){\n\t for(int l=0;l<=8;l++){\n\t \n\t s[YX[0].first][YX[0].second] = i + '0';\n\t s[YX[1].first][YX[1].second] = j + '0';\n\t s[YX[2].first][YX[2].second] = k + '0';\n\t s[YX[3].first][YX[3].second] = l + '0';\n\t \n\t cal( get(i) * get(j) * get(k) * get(l) );\n\t \n\t }\n\t}\n }\n }\n \n printf(\"%.7Lf\\n\", ans);\n\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 5180, "memory_kb": 3472, "score_of_the_acc": -1.5233, "final_rank": 20 }, { "submission_id": "aoj_1234_2996375", "code_snippet": "#include <bits/stdc++.h>\n#define r(i,n) for(int i=0;i<n;i++)\nusing namespace std;\ntypedef pair<int,int>P;\ntypedef pair<P,P>P2;\n#define F first\n#define S second\nint a[4][4],kati[4],goal[4],goaled[4],gdiff[4],id;\nstring s[5];\nvoid Perse(){\n\tmemset(a,0,sizeof(a));\n\ta[0][1]=s[1][11]-'0';\n\ta[0][2]=s[1][16]-'0';\n\ta[0][3]=s[1][21]-'0';\n\ta[1][0]=s[1][13]-'0';\n\ta[1][2]=s[2][16]-'0';\n\ta[1][3]=s[2][21]-'0';\n\ta[2][0]=s[1][18]-'0';\n\ta[2][1]=s[2][18]-'0';\n\ta[2][3]=s[3][21]-'0';\n\ta[3][0]=s[1][23]-'0';\n\ta[3][1]=s[2][23]-'0';\n\ta[3][2]=s[3][23]-'0';\n\tr(i,5)if(s[i][0]=='*')id=i-1;\n}\nvector<P>use;\nvoid FILL(vector<char> v){\n\tint c=0;\n\tif(s[1][11]=='_')s[1][11]=v[c++],use.push_back(P(1,11));\n\tif(s[1][16]=='_')s[1][16]=v[c++],use.push_back(P(1,16));\n\tif(s[1][21]=='_')s[1][21]=v[c++],use.push_back(P(1,21));\n\tif(s[1][13]=='_')s[1][13]=v[c++],use.push_back(P(1,13));\n\tif(s[2][16]=='_')s[2][16]=v[c++],use.push_back(P(2,16));\n\tif(s[2][21]=='_')s[2][21]=v[c++],use.push_back(P(2,21));\n\tif(s[1][18]=='_')s[1][18]=v[c++],use.push_back(P(1,18));\n\tif(s[2][18]=='_')s[2][18]=v[c++],use.push_back(P(2,18));\n\tif(s[3][21]=='_')s[3][21]=v[c++],use.push_back(P(3,21));\n\tif(s[1][23]=='_')s[1][23]=v[c++],use.push_back(P(1,23));\n\tif(s[2][23]=='_')s[2][23]=v[c++],use.push_back(P(2,23));\n\tif(s[3][23]=='_')s[3][23]=v[c++],use.push_back(P(3,23));\n}\n\nvoid calc(vector<int> v){\n\tmemset(kati,0,sizeof(kati));\n\tmemset(goal,0,sizeof(goal));\n\tmemset(gdiff,0,sizeof(gdiff));\n\tmemset(goaled,0,sizeof(goaled));\n\tint c[4]={};\n\tr(i,v.size())c[v[i]]=1;\n\tr(i,4)if(c[i]){\n\t\tr(j,4)if(c[j])if(i!=j){\n\t\t\tif(a[i][j]>a[j][i])kati[i]+=3;\n\t\t\telse if(a[i][j]==a[j][i])kati[i]+=1;\n\t\t\tgoal[i]+=a[i][j];\n\t\t\tgoaled[i]+=a[j][i];\n\t\t}\n\t\tgdiff[i]=goal[i]-goaled[i];\n\t}\n}\n\nvoid END(){\n\texit(0);\n}\n\ndouble get_score(){\n\tPerse();\n\tvector<int>v;\n\tint ue=0;\n\tr(i,4)v.push_back(i);\n\tint CC=10;\n\twhile(CC--){\n\t\tcalc(v);\n\t\tvector<P2>sco;\n\t\tr(i,v.size()){\n\t\t\tsco.push_back(P2(P(kati[v[i]],gdiff[v[i]]),P(goal[v[i]],v[i])));\n\t\t}\n\t\tsort(sco.begin(),sco.end(),greater<P2>());\n\t\tint cnt=0;\n\t\tvector<int>vip[4];\n\t\tvip[0].push_back(sco[0].S.S);\n\t\tr(i,sco.size()-1){\n\t\t\tif(sco[i].F.F==sco[i+1].F.F&&\n\t\t\t\tsco[i].F.S==sco[i+1].F.S&&\n\t\t\t\t\tsco[i].S.F==sco[i+1].S.F){\n\t\t\t\t\t\tvip[cnt].push_back(sco[i+1].S.S);\n\t\t\t\t\t}\n\t\t\telse{\n\t\t\t\tvip[++cnt].push_back(sco[i+1].S.S);\n\t\t\t}\n\t\t}\n\t\tv.clear();\n\t\tr(i,4){\n\t\t\tr(j,vip[i].size()){\n\t\t\t\tif(vip[i][j]==id){\n\t\t\t\t\tif(i==0&&vip[i].size()==1){\n\t\t\t\t\t\tif(ue<=1)return 1;\n\t\t\t\t\t\telse return 0;\n\t\t\t\t\t}\n\t\t\t\t\tr(k,vip[i].size()){\n\t\t\t\t\t\tv.push_back(vip[i][k]);\n\t\t\t\t\t}\n\t\t\t\t\tgoto L;\n\t\t\t\t}\n\t\t\t}\n\t\t\tue+=vip[i].size();\n\t\t}\n\t\tL:;\n\t}\n\treturn (2.0-ue)/v.size();\n}\ndouble kai[10];\nint main(){\n\tint test;\n\tcin>>test;\n\tkai[0]=kai[1]=1;\n\tfor(int i=2;i<10;i++) kai[i]=kai[i-1]*i;\n\twhile(test--){\n\t\tdouble ans=0;\n\t\tr(i,5)cin>>s[i];\n\t\tr(i,9)r(j,9)r(k,9)r(l,9){\n\t\t\tdouble d1=(kai[8]/(kai[i]*kai[8-i]))*pow(0.25,i)*pow(0.75,8-i);\n\t\t\tdouble d2=(kai[8]/(kai[j]*kai[8-j]))*pow(0.25,j)*pow(0.75,8-j);\n\t\t\tdouble d3=(kai[8]/(kai[k]*kai[8-k]))*pow(0.25,k)*pow(0.75,8-k);\n\t\t\tdouble d4=(kai[8]/(kai[l]*kai[8-l]))*pow(0.25,l)*pow(0.75,8-l);\n\t\t\tvector<char>v;\n\t\t\tv.push_back(char(i+'0'));\n\t\t\tv.push_back(char(j+'0'));\n\t\t\tv.push_back(char(k+'0'));\n\t\t\tv.push_back(char(l+'0'));\n\t\t\tFILL(v);\n\t\t\tans+=d1*d2*d3*d4*get_score();\n\t\t\tr(m,4){\n\t\t\t\ts[use[m].F][use[m].S]='_';\n\t\t\t}\n\t\t\tuse.clear();\n\t\t}\n\t\tprintf(\"%.9f\\n\",ans);\n\t}\n}", "accuracy": 1, "time_ms": 390, "memory_kb": 3276, "score_of_the_acc": -0.3028, "final_rank": 11 }, { "submission_id": "aoj_1234_2832654", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing pii = pair<int, int>;\n\nstruct team {\n int id;\n int goal, score, goal_diff;\n\n team() : id(-1), goal(0), score(0), goal_diff(0) {}\n\n bool operator<(const team& t) const {\n if(score != t.score) return score < t.score;\n if(goal_diff != t.goal_diff) return goal_diff < t.goal_diff;\n return goal < t.goal;\n }\n bool operator==(const team& t) const {\n return score == t.score && goal_diff == t.goal_diff && goal == t.goal;\n }\n};\n\nint main() {\n cout << fixed << setprecision(7);\n\n vector<double> possibility(9);\n vector<double> fact(9, 1);\n for(int i = 2; i <= 8; ++i) {\n fact[i] = fact[i - 1] * i;\n }\n for(int i = 0; i <= 8; ++i) {\n possibility[i] = fact[8] / fact[i] / fact[8 - i] * pow(0.25, i) * pow(0.75, 8 - i);\n }\n\n int T;\n cin >> T;\n while(T--) {\n int target = 0;\n vector<team> teams(4);\n vector<vector<int>> goal(4, vector<int>(4));\n for(int i = 0; i < 4; ++i) {\n teams[i].id = i;\n }\n\n auto calc_scores = [](team& t1, team& t2, int g1, int g2) {\n t1.goal += g1;\n t1.goal_diff += g1 - g2;\n t2.goal += g2;\n t2.goal_diff += g2 - g1;\n if(g1 > g2) {\n t1.score += 3;\n } else if(g2 > g1) {\n t2.score += 3;\n } else {\n t1.score += 1;\n t2.score += 1;\n }\n };\n\n vector<pii> not_yet;\n for(int i = 0; i < 5; ++i) {\n string s;\n cin >> s;\n if(s[0] == '*') {\n target = i - 1;\n }\n if(i == 0) continue;\n for(int j = 6 + i * 5; j <= 21; j += 5) {\n int a = i - 1, b = (j - 6) / 5;\n if(s[j] == '_') {\n not_yet.emplace_back(a, b);\n continue;\n }\n calc_scores(teams[a], teams[b], s[j] - '0', s[j + 2] - '0');\n goal[a][b] = s[j] - '0';\n goal[b][a] = s[j + 2] - '0';\n }\n }\n assert(not_yet.size() == 2);\n\n function<double(vector<team>, int, int)> order = [&](vector<team> teams, int rest, int prev_size) {\n const int n = teams.size();\n double res = 0;\n sort(rbegin(teams), rend(teams));\n for(int i = 0; i < n && rest > 0; ++i) {\n vector<team> concerned(1);\n concerned[0].id = teams[i].id;\n while(i + 1 < n && teams[i] == teams[i + 1]) {\n team new_team;\n new_team.id = teams[++i].id;\n concerned.push_back(move(new_team));\n }\n const int m = concerned.size();\n\n if(m == prev_size) {\n bool found = false;\n for(auto& t : concerned) {\n found |= t.id == target;\n }\n\n return found ? min((double)rest / m, 1.0) : 0.0;\n } else {\n for(int ti = 0; ti < m; ++ti) {\n for(int tj = ti + 1; tj < m; ++tj) {\n const int i1 = concerned[ti].id, i2 = concerned[tj].id;\n calc_scores(concerned[ti], concerned[tj], goal[i1][i2], goal[i2][i1]);\n }\n }\n res += order(concerned, rest, m);\n }\n\n rest -= m;\n }\n\n return res;\n };\n\n double ans = 0;\n for(int i = 0; i <= 8; ++i) {\n for(int j = 0; j <= 8; ++j) {\n for(int k = 0; k <= 8; ++k) {\n for(int l = 0; l <= 8; ++l) {\n const int a = not_yet[0].first, b = not_yet[0].second;\n const int c = not_yet[1].first, d = not_yet[1].second;\n auto tmp_teams = teams;\n calc_scores(tmp_teams[a], tmp_teams[b], i, j);\n calc_scores(tmp_teams[c], tmp_teams[d], k, l);\n goal[a][b] = i, goal[b][a] = j;\n goal[c][d] = k, goal[d][c] = l;\n ans += order(tmp_teams, 2, 4) * possibility[i] * possibility[j] * possibility[k] * possibility[l];\n }\n }\n }\n }\n\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3420, "score_of_the_acc": -0.4653, "final_rank": 16 }, { "submission_id": "aoj_1234_2709754", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <utility>\n#include <iomanip>\nusing namespace std;\ndouble fact(int n){\n if(n==0) return 1;\n return n*fact(n-1);\n}\n\ndouble solve(int t, int r, vector<int> tl, vector<vector<int> > &score){\n int n = tl.size();\n vector<int> gp(n, 0), gd(n, 0), gn(n, 0);\n vector<pair<pair<pair<int,int>, int>, int> > cmp(n);\n for(int i=0; i<n; i++){\n for(int j=i+1; j<n; j++){\n int ti = tl[i], tj = tl[j];\n gd[i] += score[ti][tj] -score[tj][ti];\n gd[j] += score[tj][ti] -score[ti][tj];\n gn[i] += score[ti][tj];\n gn[j] += score[tj][ti];\n if(score[ti][tj] < score[tj][ti]){\n gp[j] += 3;\n }else if(score[ti][tj] > score[tj][ti]){\n gp[i] += 3;\n }else{\n gp[i]++;\n gp[j]++;\n }\n }\n }\n for(int i=0; i<n; i++){\n cmp[i] = make_pair(make_pair(make_pair(-gp[i], -gd[i]), -gn[i]), i);\n }\n sort(cmp.begin(), cmp.end());\n vector<int> ord(n);\n for(int i=0; i<n; i++) ord[i] = cmp[i].second;\n\n int samecount=1;\n int start=0;\n for(int i=1; i<n; i++){\n if(gp[ord[i]]==gp[ord[0]] && gd[ord[i]]==gd[ord[0]] && gn[ord[i]]==gn[ord[0]]){\n samecount++;\n }else{\n break;\n }\n }\n if(samecount==n){\n return (double)r/n;\n }\n\n if(samecount==1 && r==2){\n if(tl[ord[0]]==t){\n return 1;\n }else{\n start = 1;\n samecount = 1;\n r--;\n for(int i=2; i<n; i++){\n if(gp[ord[i]]==gp[ord[1]] && gd[ord[i]]==gd[ord[1]] && gn[ord[i]]==gn[ord[1]]){\n samecount++;\n }else{\n break;\n }\n }\n }\n }\n\n for(int i=start+samecount; i<n; i++){\n if(tl[ord[i]] == t) return 0;\n }\n if(samecount==r){\n return 1;\n }\n vector<int> ntl(samecount);\n for(int i=0; i<samecount; i++){\n ntl[i] = tl[ord[start +i]];\n }\n return solve(t, r, ntl, score);\n}\n\nint main(){\n double table[9];\n for(int i=0; i<=8; i++){\n table[i] = fact(8) /(fact(i)*fact(8-i)) *pow(0.25, i) *pow(0.75, 8-i);\n }\n cout << fixed;\n cout << setprecision(7);\n \n int ds;\n cin >> ds;\n for(int r=0; r<ds; r++){\n string s;\n cin >> s;\n int t;\n vector<vector<int> > score(4, vector<int>(4, 0));\n vector<vector<int> > emp(2);\n for(int i=0; i<4; i++){\n cin >> s;\n if(s[0]=='*') t=i;\n for(int j=i+1; j<4; j++){\n int fs = 6 +5*j;\n int ss = fs +2;\n if(s[fs]=='_'){\n emp[0].push_back(i);\n emp[1].push_back(j);\n }else{\n score[i][j] = s[fs]-'0';\n score[j][i] = s[ss]-'0';\n }\n }\n }\n\n double ans=0;\n vector<int> tl(4);\n for(int i=0; i<4; i++) tl[i]=i;\n for(int i=0; i<=8; i++){\n for(int j=0; j<=8; j++){\n for(int k=0; k<=8; k++){\n for(int l=0; l<=8; l++){\n score[emp[0][0]][emp[1][0]] = i;\n score[emp[1][0]][emp[0][0]] = j;\n score[emp[0][1]][emp[1][1]] = k;\n score[emp[1][1]][emp[0][1]] = l;\n ans += table[i]*table[j]*table[k]*table[l] *solve(t, 2, tl, score);\n }\n }\n }\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3212, "score_of_the_acc": -0.1571, "final_rank": 5 } ]
aoj_1233_cpp
Problem B: Equals are Equals Mr. Simpson got up with a slight feeling of tiredness. It was the start of another day of hard work. A bunch of papers were waiting for his inspection on his desk in his office. The papers contained his students' answers to questions in his Math class, but the answers looked as if they were just stains of ink. His headache came from the ``creativity'' of his students. They provided him a variety of ways to answer each problem. He has his own answer to each problem, which is correct, of course, and the best from his aesthetic point of view. Some of his students wrote algebraic expressions equivalent to the expected answer, but many of them look quite different from Mr. Simpson's answer in terms of their literal forms. Some wrote algebraic expressions not equivalent to his answer, but they look quite similar to it. Only a few of the students' answers were exactly the same as his. It is his duty to check if each expression is mathematically equivalent to the answer he has prepared. This is to prevent expressions that are equivalent to his from being marked as ``incorrect'', even if they are not acceptable to his aesthetic moral. He had now spent five days checking the expressions. Suddenly, he stood up and yelled, ``I've had enough! I must call for help.'' Your job is to write a program to help Mr. Simpson to judge if each answer is equivalent to the ``correct'' one. Algebraic expressions written on the papers are multi-variable polynomials over variable symbols a , b ,..., z with integer coefficients, e.g., ( a + b 2 )( a - b 2 ), ax 2 +2 bx + c and ( x 2 +5 x + 4)( x 2 + 5 x + 6) + 1. Mr. Simpson will input every answer expression as it is written on the papers; he promises you that an algebraic expression he inputs is a sequence of terms separated by additive operators ` + ' and ` - ', representing the sum of the terms with those operators, if any; a term is a juxtaposition of multiplicands, representing their product; and a multiplicand is either (a) a non-negative integer as a digit sequence in decimal, (b) a variable symbol (one of the lowercase letters ` a ' to ` z '), possibly followed by a symbol ` ^ ' and a non-zero digit, which represents the power of that variable, or (c) a parenthesized algebraic expression, recursively. Note that the operator ` + ' or ` - ' appears only as a binary operator and not as a unary operator to specify the sing of its operand. He says that he will put one or more space characters before an integer if it immediately follows another integer or a digit following the symbol ` ^ '. He also says he may put spaces here and there in an expression as an attempt to make it readable, but he will never put a space between two consecutive digits of an integer. He remarks that the expressions are not so complicated, and that any expression, having its ` - 's replaced with ` + 's, if any, would have no variable raised to its 10th power, nor coefficient more than a billion, even if it is fully e ...(truncated)
[ { "submission_id": "aoj_1233_8484392", "code_snippet": "#include <bits/stdc++.h>\n\nconstexpr int W = 26;\nusing Var = std::array<int, W>;\nstd::ostream& operator<<(std::ostream& os, const Var& var) {\n os << '(';\n for (int i = 0; i < W; i++) {\n if (var[i] == 0) continue;\n os << '(' << (char)(i + 'a') << '^' << var[i] << ')';\n }\n os << ')';\n return os;\n}\n\nVar op(const Var& lhs, const Var& rhs) {\n Var res;\n res.fill(0);\n for (int i = 0; i < W; i++) {\n res[i] = lhs[i] + rhs[i];\n }\n return res;\n}\n\nstruct Poly {\n // data[var] = coef;\n std::map<Var, long long> data;\n\n Poly(long long value = 0) {\n Var var;\n var.fill(0);\n data[var] = value;\n }\n Poly(char c, int exp = 1) {\n Var var;\n var.fill(0);\n var[c - 'a'] += exp;\n data[var] = 1;\n }\n\n friend Poly operator+(const Poly& lhs, const Poly& rhs) {\n if (lhs.data.size() > rhs.data.size()) return rhs + lhs;\n auto res = rhs;\n for (const auto& [var, coef]: lhs.data) {\n res.data[var] += coef;\n }\n return res;\n }\n\n friend Poly operator-(const Poly& lhs, const Poly& rhs) {\n auto res = lhs;\n for (const auto& [var, coef]: rhs.data) {\n res.data[var] -= coef;\n }\n return res;\n }\n\n friend Poly operator*(const Poly& lhs, const Poly& rhs) {\n Poly res;\n for (const auto& [var1, coef1]: lhs.data) {\n for (const auto& [var2, coef2]: rhs.data) {\n res.data[op(var1, var2)] += coef1 * coef2;\n }\n }\n return res;\n }\n\n friend bool operator==(Poly& lhs, Poly& rhs) {\n for (const auto& [var, coef]: lhs.data) {\n if (rhs.data[var] != coef) return false;\n }\n for (const auto& [var, coef]: rhs.data) {\n if (lhs.data[var] != coef) return false;\n }\n return true;\n }\n\n Poly pow(int exp) {\n Poly base(*this);\n Poly res;\n while (exp > 0) {\n if (exp & 1) res = res + base;\n base = base + base;\n exp >>= 1;\n }\n return res;\n }\n\n friend std::ostream& operator<<(std::ostream& os, const Poly& poly) {\n for (const auto& [var, coef]: poly.data) {\n if (coef == 0) continue;\n if (coef > 0) {\n os << '+';\n }\n os << coef << var << ' ';\n }\n return os;\n }\n};\n\nstruct Parser {\n using CopyIter = std::string::const_iterator;\n using Iter = CopyIter&;\n std::string line;\n Parser() {}\n void skip(Iter it, char c) {\n // std::cerr << *it << ' ' << c << std::endl;\n assert(*it == c);\n ++it;\n }\n void skip_space(Iter it) {\n while (it != line.end() && *it == ' ') ++it;\n }\n\n Poly parse(const std::string& s) {\n line = s;\n auto it = line.cbegin();\n auto res = expr(it);\n assert(it == line.end());\n return res;\n }\n\n Poly expr(Iter it) {\n auto res = term(it);\n\n while (it != line.end() && (*it == '+' || *it == '-')) {\n if (*it == '+') {\n skip(it, '+');\n skip_space(it);\n res = res + term(it);\n } else {\n skip(it, '-');\n skip_space(it);\n res = res - term(it);\n }\n }\n\n skip_space(it);\n return res;\n }\n\n Poly term(Iter it) {\n auto res = factor(it);\n\n while (it != line.end() && *it != '+' && *it != '-' && *it != ')') {\n res = res * factor(it);\n }\n\n skip_space(it);\n return res;\n }\n\n Poly factor(Iter it) {\n if (std::isdigit(*it)) {\n return nonnegative_number(it);\n } else if (std::isalpha(*it)) {\n return variable(it);\n } else {\n skip(it, '(');\n skip_space(it);\n auto res = expr(it);\n skip(it, ')');\n skip_space(it);\n return res;\n }\n }\n\n Poly nonnegative_number(Iter it) {\n long long res = 0;\n while (it != line.end() && std::isdigit(*it)) {\n char c = *it;\n skip(it, c);\n res = 10 * res + c - '0';\n }\n skip_space(it);\n return Poly(res);\n }\n\n Poly variable(Iter it) {\n char var = *it;\n assert(std::isalpha(var));\n skip(it, var);\n skip_space(it);\n Poly res(var);\n if (it != line.end() && *it == '^') {\n skip(it, '^');\n skip_space(it);\n char exp = *it;\n assert(std::isdigit(exp) && exp != '0');\n skip(it, exp);\n res = Poly(var, exp - '0');\n }\n skip_space(it);\n return res;\n }\n};\n\nvoid parser_test() {\n std::vector<std::string> tests = {\n \"a+b+c\",\n \"a a a\",\n \"a^2 a a\",\n \"(a^2+b)(a+b)\",\n \"2ab (4a+2b)\",\n \"2 2 3 3 3 a\"\n };\n\n for (auto test: tests) {\n std::cerr << test << \": \";\n Parser parser;\n std::cerr << parser.parse(test) << std::endl;\n }\n}\n\nint main() {\n // parser_test();\n Parser parser;\n while (true) {\n std::string line;\n std::getline(std::cin, line);\n if (line == \".\") break;\n Poly answer = parser.parse(line);\n\n while (true) {\n std::getline(std::cin, line);\n if (line == \".\") break;\n Poly solution = parser.parse(line);\n if (answer == solution) {\n std::cout << \"yes\" << std::endl;\n } else {\n std::cout << \"no\" << std::endl;\n }\n }\n\n std::cout << \".\" << std::endl;\n }\n}", "accuracy": 1, "time_ms": 3480, "memory_kb": 9316, "score_of_the_acc": -1.744, "final_rank": 20 }, { "submission_id": "aoj_1233_6058521", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct monomial{\n vector<pair<char, int>> deg;\n monomial(){\n }\n monomial(char c, int x){\n deg.push_back(make_pair(c, x));\n }\n};\nbool operator ==(monomial A, monomial B){\n return A.deg == B.deg;\n}\nbool operator < (monomial A, monomial B){\n return A.deg < B.deg;\n}\nmonomial operator *(monomial A, monomial B){\n int N = A.deg.size();\n int M = B.deg.size();\n for (int i = 0; i < M; i++){\n bool ok = false;\n for (int j = 0; j < N; j++){\n if (A.deg[j].first == B.deg[i].first){\n A.deg[j].second += B.deg[i].second;\n ok = true;\n }\n }\n if (!ok){\n A.deg.push_back(B.deg[i]);\n }\n }\n sort(A.deg.begin(), A.deg.end());\n return A;\n}\nostream& operator <<(ostream& os, monomial A){\n int N = A.deg.size();\n for (int i = 0; i < N; i++){\n cout << A.deg[i].first;\n if (A.deg[i].second >= 2){\n cout << \"^\" << A.deg[i].second;\n }\n }\n return os;\n}\nstruct polynomial{\n vector<pair<monomial, int>> term;\n polynomial(){\n }\n polynomial(int x){\n if (x != 0){\n term.push_back(make_pair(monomial(), x));\n }\n }\n polynomial(char c, int x){\n term.push_back(make_pair(monomial(c, x), 1));\n }\n};\nbool operator ==(polynomial A, polynomial B){\n return A.term == B.term;\n}\npolynomial operator -(polynomial A){\n int N = A.term.size();\n for (int i = 0; i < N; i++){\n A.term[i].second *= -1;\n }\n return A;\n}\npolynomial operator +(polynomial A, polynomial B){\n int N = A.term.size();\n int M = B.term.size();\n for (int i = 0; i < M; i++){\n bool ok = false;\n for (int j = 0; j < N; j++){\n if (A.term[j].first == B.term[i].first){\n A.term[j].second += B.term[i].second;\n ok = true;\n }\n }\n if (!ok){\n A.term.push_back(B.term[i]);\n }\n }\n sort(A.term.begin(), A.term.end());\n int K = A.term.size();\n polynomial ans;\n for (int i = 0; i < K; i++){\n if (A.term[i].second != 0){\n ans.term.push_back(A.term[i]);\n }\n }\n return ans;\n}\npolynomial operator -(polynomial A, polynomial B){\n return A + (-B);\n}\npolynomial operator *(polynomial A, polynomial B){\n int N = A.term.size();\n int M = B.term.size();\n map<monomial, int> mp;\n for (int i = 0; i < N; i++){\n for (int j = 0; j < M; j++){\n monomial X = A.term[i].first * B.term[j].first;\n int coef = A.term[i].second * B.term[j].second;\n mp[X] += coef;\n }\n }\n polynomial ans;\n for (auto P : mp){\n if (P.second != 0){\n ans.term.push_back(P);\n }\n }\n return ans;\n}\nostream& operator <<(ostream& os, polynomial A){\n int N = A.term.size();\n for (int i = 0; i < N; i++){\n if (i > 0 && A.term[i].second > 0){\n cout << '+';\n }\n if (A.term[i].second < 0){\n cout << \"-\" ;\n }\n int x = abs(A.term[i].second);\n if (x > 1){\n cout << x;\n }\n cout << A.term[i].first;\n }\n return os;\n}\nint number(string &S, int &p){\n int ans = 0;\n while (isdigit(S[p]) != 0){\n ans = ans * 10 + (S[p] - '0');\n p++;\n }\n return ans;\n}\npolynomial expression(string &S, int &p);\npolynomial factor(string &S, int &p){\n if (S[p] == '('){\n p++;\n polynomial ans = expression(S, p);\n p++;\n return ans;\n } else if (isdigit(S[p]) != 0){\n int x = number(S, p);\n return polynomial(x);\n } else {\n char c = S[p];\n p++;\n int x = 1;\n if (S[p] == '^'){\n p++;\n x = number(S, p);\n }\n return polynomial(c, x);\n }\n}\npolynomial term(string &S, int &p){\n int p2 = p;\n polynomial ans = factor(S, p);\n while (true){\n if (S[p] == '*'){\n p++;\n }\n if (S[p] == '+' || S[p] == '-' || S[p] == ')' || S[p] == '='){\n break;\n }\n polynomial A = factor(S, p);\n ans = ans * A;\n }\n return ans;\n}\npolynomial expression(string &S, int &p){\n polynomial ans = term(S, p);\n while (true){\n if (S[p] == '+'){\n p++;\n ans = ans + term(S, p);\n } else if (S[p] == '-'){\n p++;\n ans = ans - term(S, p);\n } else {\n break;\n }\n }\n return ans;\n} \nint main(){\n while (true){\n vector<string> S;\n while (true){\n string s;\n getline(cin, s);\n if (s == \".\"){\n break;\n }\n int N = s.size();\n string t;\n t += s[0];\n for (int i = 1; i < N; i++){\n if (s[i] != ' '){\n if (isdigit(s[i]) != 0 && isdigit(t.back()) != 0 && isdigit(s[i - 1]) == 0){\n t += '*';\n }\n t += s[i];\n }\n }\n S.push_back(t);\n }\n if (S.empty()){\n break;\n }\n int N = S.size();\n vector<polynomial> P(N);\n for (int i = 0; i < N; i++){\n S[i] += '=';\n int p = 0;\n P[i] = expression(S[i], p);\n }\n for (int i = 1; i < N; i++){\n if (P[i] == P[0]){\n cout << \"yes\" << endl;\n } else {\n cout << \"no\" << endl;\n }\n }\n cout << \".\" << endl;\n }\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 9444, "score_of_the_acc": -0.7842, "final_rank": 18 }, { "submission_id": "aoj_1233_4972347", "code_snippet": "#include \"iostream\"\n#include \"climits\"\n#include \"list\"\n#include \"queue\"\n#include \"stack\"\n#include \"set\"\n#include \"functional\"\n#include \"algorithm\"\n#include \"string\"\n#include \"map\"\n#include \"unordered_map\"\n#include \"unordered_set\"\n#include \"iomanip\"\n#include \"cmath\"\n#include \"random\"\n#include \"bitset\"\n#include \"cstdio\"\n#include \"numeric\"\n#include \"cassert\"\n#include \"ctime\"\n#include \"complex\"\n\nusing namespace std;\n\nconstexpr long long int MOD = 1000000007;\n//constexpr int MOD = 1000000007;\n//constexpr int MOD = 998244353;\n//constexpr long long int MOD = 998244353;\nconstexpr double EPS = 1e-12;\n\n//int N, M, K, T, H, W, L, R;\nlong long int N, M, K, T, H, W, L, R;\n\nstruct Component {\n\tvector<long long int>dir;\n\tlong long int by;\n\tComponent() {\n\t\tby = -1;\n\t\tdir.resize(26);\n\t}\n\tComponent(vector<long long int>d, long long int b) :dir(d), by(b) {\n\n\t}\n\tbool operator<(const Component&c)const {\n\t\treturn make_pair(dir, by) < make_pair(c.dir, c.by);\n\t}\n\tbool operator!=(const Component&c)const {\n\t\treturn make_pair(by, dir) != make_pair(c.by, c.dir);\n\t}\n\tComponent operator*(const Component&c)const {\n\t\tComponent ret(dir, by);\n\t\tfor (int i = 0; i < 26; i++) {\n\t\t\tret.dir[i] += c.dir[i];\n\t\t}\n\t\tret.by *= c.by;\n\t\treturn ret;\n\t}\n};\n\nstruct Expression {\n\tvector<Component>v;\n\tExpression() {\n\t}\n\tExpression(vector<Component>vv) :v(vv) {\n\n\t}\n\tvoid ExpSort() {\n\t\tsort(v.begin(), v.end());\n\t\tvector<Component>w;\n\t\tfor (auto i : v) {\n\t\t\tif (w.empty() || w.back().dir != i.dir) {\n\t\t\t\tw.push_back(i);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tw.back().by += i.by;\n\t\t\t}\n\t\t}\n\t\tv.clear();\n\t\tfor (auto i : w) {\n\t\t\tif (i.by)v.push_back(i);\n\t\t}\n\t}\n\tbool operator==(const Expression&e)const {\n\t\tif (v.size() != e.v.size())return false;\n\t\tfor (int i = 0; i < v.size(); i++) {\n\t\t\tif (v[i] != e.v[i])return false;\n\t\t}\n\t\treturn true;\n\t}\n\tExpression operator+(const Expression&e)const {\n\t\tauto ret = Expression(v);\n\t\tfor (auto i : e.v)ret.v.push_back(i);\n\t\treturn ret;\n\t}\n\tExpression operator-(const Expression&e)const {\n\t\tauto ret = Expression(v);\n\t\tfor (auto i : e.v) {\n\t\t\tret.v.push_back(i);\n\t\t\tret.v.back().by *= -1;\n\t\t}\n\t\treturn ret;\n\t}\n\tExpression operator*(const Expression&e)const {\n\t\tauto ret = Expression();\n\t\tfor (auto i : v) {\n\t\t\tfor (auto j : e.v) {\n\t\t\t\tret.v.push_back(i*j);\n\t\t\t}\n\t\t}\n\t\treturn ret;\n\t}\n\tExpression operator^(const Expression&e)const {\n\t\tauto ret = Expression(v);\n\t\tfor (auto &i : ret.v) {\n\t\t\tfor (auto &j : i.dir) j *= e.v.front().by;\n\t\t}\n\t\tret.v.front().by = powl(ret.v.front().by, e.v.front().by);\n\t\treturn ret;\n\t}\n};\n\n\nvoid DEBUG(Expression e) {\n\tcout << e.v.size() << endl;\n\tfor (auto i : e.v) {\n\t\tcout << i.by;\n\t\tfor (auto j : i.dir)cout << \" \" << j;\n\t\tcout << endl;\n\t}\n}\n\nExpression func(string s) {\n//\tcout << s << endl;\n\tint num = 0;\n\tfor (int i = s.size() - 1; i >= 0; i--) {\n\t\tif (s[i] == ')') num++;\n\t\tif (s[i] == '(') num--;\n\t\tif (num == 0) {\n\t\t\tif (s[i] == '+') {\n\t\t\t\tauto a = func(s.substr(0, i));\n\t\t\t\tauto b = func(s.substr(i + 1, s.size() - i - 1));\n\t\t\t\treturn a + b;\n\t\t\t}\n\t\t\tif (s[i] == '-') {\n\t\t\t\tauto a = func(s.substr(0, i));\n\t\t\t\tauto b = func(s.substr(i + 1, s.size() - i - 1));\n\t\t\t\treturn a - b;\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = s.size() - 1; i >= 0; i--) {\n\t\tif (s[i] == ')') num++;\n\t\tif (s[i] == '(') num--;\n\t\tif (num == 0) {\n\t\t\tif (s[i] == '*') {\n\t\t\t\tauto a = func(s.substr(0, i));\n\t\t\t\tauto b = func(s.substr(i + 1, s.size() - i - 1));\n\t\t\t\treturn a * b;\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = s.size() - 1; i >= 0; i--) {\n\t\tif (s[i] == ')') num++;\n\t\tif (s[i] == '(') num--;\n\t\tif (num == 0) {\n\t\t\tif (s[i] == '^') {\n\t\t\t\tauto a = func(s.substr(0, i));\n\t\t\t\tauto b = func(s.substr(i + 1, s.size() - i - 1));\n\t\t\t\treturn a ^ b;\n\t\t\t}\n\t\t}\n\t}\n\tif (s.front() == '(') {\n\t\treturn func(s.substr(1, s.size() - 2));\n\t}\n\tComponent ret;\n\tfor (auto i : s) {\n\t\tif (i >= 'a'&&i <= 'z') {\n\t\t\tret.dir[i - 'a']++;\n\t\t}\n\t\telse {\n\t\t\tif (ret.by == -1)ret.by = 0;\n\t\t\tret.by *= 10;\n\t\t\tret.by += i - '0';\n\t\t}\n\t}\n\tif(ret.by==-1)ret.by *= -1;\n\tExpression re;\n\tre.v.push_back(ret);\n\treturn re;\n}\n\nbool IsNum(char c) {\n\treturn (c >= '0'&&c <= '9') ;\n}\n\nbool IsAlpha(char c) {\n\treturn (c >= 'a'&&c <= 'z');\n}\n\nstring EraseSpace(string s) {\n\tstring ret;\n\tfor (auto i : s) {\n\t\tif (i != ' ')ret.push_back(i);\n\t\telse {\n\t\t\tif (!ret.empty() && ret.back() != ' ')ret.push_back(i);\n\t\t}\n\t}\n\twhile (ret.back() == ' ')ret.pop_back();\n\ts = ret;\n\tfor (int i = 1; i + 1 < s.size(); i++) {\n\t\tauto bf = s[i - 1];\n\t\tauto nx = s[i + 1];\n\t\tif (s[i] == ' ') {\n\t\t\tif (IsNum(bf) || IsAlpha(bf) || bf == ')') {\n\t\t\t\tif (IsNum(nx) || IsAlpha(nx) || nx == '(') {\n\t\t\t\t\ts[i] = '*';\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tret.clear();\n\tfor (auto i : s) {\n\t\tif (i == ' ')continue;\n\t\tif (ret.empty()) {\n\t\t\tret.push_back(i);\n\t\t\tcontinue;\n\t\t}\n\t\tif (ret.back() == ')'&&(i == '('||IsNum(i)||IsAlpha(i)))ret.push_back('*');\n\t\telse if ((ret.back() == ')' || IsNum(ret.back()) || IsAlpha(ret.back())) && i == '(')ret.push_back('*');\n\t\telse if (IsNum(ret.back()) && IsAlpha(i))ret.push_back('*');\n\t\telse if (IsAlpha(ret.back()) && IsNum(i))ret.push_back('*');\n\t\telse if (IsAlpha(ret.back()) && IsAlpha(i))ret.push_back('*');\n\t\tret.push_back(i);\n\t}\n\treturn ret;\n}\n\n\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\n\tstring s;\n\twhile (getline(cin, s), s != \".\") {\n\t\tauto ans = func(EraseSpace(s));\n\t\tans.ExpSort();\n\t//\tDEBUG(ans);\n\t\twhile (getline(cin, s), s != \".\") {\n\t\t\tauto box = func(EraseSpace(s));\n\t\t\tbox.ExpSort();\n\t\t//\tDEBUG(box);\n\t\t\tif (ans == box)cout << \"yes\\n\";\n\t\t\telse cout << \"no\\n\";\n\t\t}\n\t\tcout << s << endl;\n\t}\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3816, "score_of_the_acc": -0.1419, "final_rank": 12 }, { "submission_id": "aoj_1233_4962252", "code_snippet": "#include<iostream>\n#include<vector>\n#include<map>\nusing namespace std;\nstruct Str{\n\tstring s;\n\tStr():s(){}\n\tconst char operator[](int id)const{return s[id];}\n\tconst size_t size()const{return s.size();}\n\tStr&operator+=(const char c){\n\t\ts+=c;\n\t\treturn*this;\n\t}\n\tStr operator*(const Str&a){\n\t\tStr ret;\n\t\tint i=0,j=0;\n\t\twhile(i<s.size()||j<a.size())\n\t\t{\n\t\t\tif(i<s.size()&&j<a.size())\n\t\t\t{\n\t\t\t\tif(s[i]<a[j])ret+=s[i++];\n\t\t\t\telse ret+=a[j++];\n\t\t\t}\n\t\t\telse if(i<s.size())ret+=s[i++];\n\t\t\telse ret+=a[j++];\n\t\t}\n\t\treturn ret;\n\t}\n\tbool operator<(const Str&a)const{\n\t\treturn s<a.s;\n\t}\n\tbool operator==(const Str&a)const{return s==a.s;}\n};\nstruct exp{\n\tmap<Str,int>mp;\n\texp():mp(){}\n\tint&operator[](const Str&a){return mp[a];}\n\texp norm(){\n\t\texp ret;\n\t\tfor(pair<Str,int>p:mp)if(p.second!=0)ret[p.first]=p.second;\n\t\treturn ret;\n\t}\n\texp operator+(const exp&a){\n\t\texp ret=*this;\n\t\tfor(pair<Str,int>p:a.mp)ret[p.first]+=p.second;\n\t\treturn ret.norm();\n\t}\n\texp operator-(const exp&a){\n\t\texp ret=*this;\n\t\tfor(pair<Str,int>p:a.mp)ret[p.first]-=p.second;\n\t\treturn ret.norm();\n\t}\n\texp operator*(const exp&a){\n\t\texp ret;\n\t\tfor(pair<Str,int>p:mp)for(pair<Str,int>q:a.mp)\n\t\t{\n\t\t\tret[p.first*q.first]+=p.second*q.second;\n\t\t}\n\t\treturn ret.norm();\n\t}\n\tbool operator==(const exp&a)const{return mp==a.mp;}\n\tvoid dump()const{\n\t\tbool fst=true;\n\t\tfor(pair<Str,int>p:mp)\n\t\t{\n\t\t\tif(!fst)cout<<\"+\";\n\t\t\telse fst=false;\n\t\t\tcout<<p.second<<\"*\"<<p.first.s;\n\t\t}\n\t\tcout<<endl;\n\t}\n};\nvector<string>now;\nvoid parse(string s)\n{\n\tnow.clear();\n\tfor(int i=0;i<s.size();i++)\n\t{\n\t\tif(s[i]==' ')continue;\n\t\telse if(isdigit(s[i]))\n\t\t{\n\t\t\tint j=i;\n\t\t\twhile(isdigit(s[j]))j++;\n\t\t\tnow.push_back(s.substr(i,j-i));\n\t\t\ti=j-1;\n\t\t}\n\t\telse now.push_back(string(1,s[i]));\n\t}\n}\nexp f(int&);\nexp g(int&);\nexp term(int&);\nexp f(int&id)\n{\n\texp ret=g(id);\n\twhile(id<now.size()&&(now[id]==\"+\"||now[id]==\"-\"))\n\t{\n\t\tstring op=now[id++];\n\t\texp nxt=g(id);\n\t\tif(op==\"+\")ret=ret+nxt;\n\t\telse ret=ret-nxt;\n\t}\n\treturn ret;\n}\nexp g(int&id)\n{\n\texp ret=term(id);\n\twhile(id<now.size()&&now[id]!=\"+\"&&now[id]!=\"-\"&&now[id]!=\")\")\n\t{\n\t\tret=ret*term(id);\n\t}\n\treturn ret;\n}\nint to_i(string s)\n{\n\tint ret=0;\n\tfor(char c:s)ret=ret*10+c-'0';\n\treturn ret;\n}\nexp term(int&id)\n{\n\texp ret;\n\tif(now[id]==\"(\")\n\t{\n\t\tid++;\n\t\tret=f(id);\n\t\tid++;\n\t}\n\telse if(isdigit(now[id][0]))\n\t{\n\t\tret[Str()]=to_i(now[id++]);\n\t}\n\telse\n\t{\n\t\tStr tmp;\n\t\ttmp.s=now[id++];\n\t\tret[tmp]=1;\n\t}\n\tif(id<now.size()&&now[id]==\"^\")\n\t{\n\t\tid++;\n\t\tint n=to_i(now[id++]);\n\t\texp ans=ret;\n\t\tfor(int i=1;i<n;i++)ans=ans*ret;\n\t\tret=ans;\n\t}\n\treturn ret;\n}\nmain()\n{\n\twhile(true)\n\t{\n\t\tstring s;\n\t\tgetline(cin,s);\n\t\tif(s==\".\")break;\n\t\tparse(s);\n\t\tint id=0;\n\t\texp ans=f(id).norm();\n\t\twhile(true)\n\t\t{\n\t\t\tgetline(cin,s);\n\t\t\tif(s==\".\")break;\n\t\t\tparse(s);\n\t\t\tid=0;\n\t\t\texp ret=f(id).norm();\n\t\t\tcout<<(ans==ret?\"yes\":\"no\")<<endl;\n\t\t}\n\t\tcout<<\".\"<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3328, "score_of_the_acc": -0.1198, "final_rank": 9 }, { "submission_id": "aoj_1233_4931020", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\n#define all(x) (x).begin(),(x).end()\n#define fi first\n#define se second\n#define mp make_pair\n#define si(x) int(x.size())\nconst int mod=1000000007,MAX=1005;\nconst int INF=1e6;\n//const ll INF=1LL<<60;\nstring S;\n\nvector<vector<ll>> dai(100,vector<ll>(26));\nvector<ll> ans(100),comp(100);\nint t;\n\nll expr(int &i);\nll term(int &i);\nll rui(int &i);\nll factor(int &i);\nll number(int &i);\n\nll expr(int &i){\n ll res=term(i);\n while(i<si(S)){\n if(S[i]==' ') i++;\n else if(S[i]=='+'){\n i++;\n ll x=term(i);\n res+=x;\n }else if(S[i]=='-'){\n i++;\n ll x=term(i);\n res-=x;\n }else{\n break;\n }\n }\n return res;\n}\n\nll term(int &i){\n ll res=rui(i);\n \n while(i<si(S)){\n if(S[i]==' ') i++;\n else if(S[i]=='+'||S[i]=='-'||S[i]==')') break;\n else{\n ll x=rui(i);\n res*=x;\n }\n }\n \n return res;\n}\n\nll rui(int &i){\n ll res=factor(i);\n \n while(i<si(S)){\n if(S[i]==' ') i++;\n else if(S[i]=='^'){\n i++;\n ll x=factor(i);\n ll k=res;\n res=1;\n for(int j=0;j<x;j++) res*=k;\n }else break;\n }\n \n return res;\n}\n\nll factor(int &i){\n while(S[i]==' ') i++;\n \n if(i<si(S)&&S[i]=='('){\n i++;\n ll x=expr(i);\n while(S[i]==' ') i++;\n assert(S[i]=')');\n i++;\n \n return x;\n }else{\n return number(i);\n }\n}\n\nll number(int &i){\n while(S[i]==' ') i++;\n if(isdigit(S[i])){\n ll res=0;\n while(i<si(S)&&isdigit(S[i])){\n res*=10;\n res+=ll(S[i]-'0');\n i++;\n }\n return res;\n }else{\n ll x=dai[t][S[i]-'a'];\n i++;\n return x;\n }\n}\n\nint main(){\n \n std::ifstream in(\"text.txt\");\n std::cin.rdbuf(in.rdbuf());\n cin.tie(0);\n ios::sync_with_stdio(false);\n \n mt19937_64 rng(58);\n \n for(int i=0;i<100;i++){\n for(int j=0;j<26;j++){\n dai[i][j]=rng()%9+1;\n }\n }\n \n while(1){\n getline(cin,S);\n if(S==\".\") break;\n \n t=0;\n while(t<100){\n int i=0;\n comp[t]=expr(i);\n t++;\n }\n ans=comp;\n \n while(1){\n getline(cin,S);\n if(S==\".\"){\n cout<<\".\\n\";\n break;\n }\n \n t=0;\n \n while(t<100){\n int i=0;\n comp[t]=expr(i);\n t++;\n }\n \n if(ans==comp) cout<<\"yes\"<<endl;\n else cout<<\"no\"<<endl;\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3260, "score_of_the_acc": -0.0747, "final_rank": 2 }, { "submission_id": "aoj_1233_4535459", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\nusing namespace std;\n\nstruct Polynomial{\n map<string, int> terms;\n Polynomial(int a){\n terms[\"\"] = a;\n }\n Polynomial(string s){\n terms[s] = 1;\n }\n Polynomial(){}\n static void erase_zero(Polynomial &a){\n for(auto it=a.terms.begin(); it!=a.terms.end();){\n if(it->second == 0){\n it = a.terms.erase(it);\n }else{\n it++;\n }\n }\n }\n Polynomial operator +(const Polynomial &a) const{\n Polynomial res = *this;\n for(const auto &p: a.terms){\n res.terms[p.first] += p.second;\n }\n erase_zero(res);\n return res;\n }\n Polynomial operator -(const Polynomial &a) const{\n Polynomial res = *this;\n for(const auto &p: a.terms){\n res.terms[p.first] -= p.second;\n }\n erase_zero(res);\n return res;\n }\n Polynomial operator *(const Polynomial &a) const{\n Polynomial res;\n for(const auto &p: terms){\n for(const auto &q: a.terms){\n string key = p.first + q.first;\n sort(key.begin(), key.end());\n res.terms[key] += p.second * q.second;\n }\n }\n erase_zero(res);\n return res;\n }\n bool operator ==(const Polynomial &a) const{\n return terms == a.terms;\n }\n};\n\nint getnum(int &p, const string &s){\n int num = 0;\n while(p<(int)s.length() and '0'<=s[p] and s[p]<='9'){\n num *= 10;\n num += s[p]-'0';\n p++;\n }\n return num;\n}\nPolynomial parse(int &p, const string &s){\n Polynomial res;\n Polynomial term(1);\n int sign = 1;\n while(1){\n if(p<(int)s.length() and s[p] == ' '){\n p++;\n continue;\n }\n if(p>=(int)s.length() or s[p]=='+' or s[p]=='-' or s[p]==')'){\n if(sign == 1) res = res + term;\n else res = res - term;\n term = Polynomial(1);\n if(p>=(int)s.length() or s[p]==')'){\n p++;\n return res;\n }\n if(s[p] == '+') sign = 1;\n else sign = -1;\n p++;\n continue;\n }\n if('0'<=s[p] and s[p]<='9'){\n term = term * Polynomial(getnum(p, s));\n continue;\n }\n if('a'<=s[p] and s[p]<='z'){\n char var = s[p];\n p++;\n int num = 1;\n while(p<(int)s.length() and s[p]==' '){\n p++;\n }\n if(p<(int)s.length() and s[p]=='^'){\n p++;\n while(s[p] == ' ') p++;\n num = getnum(p, s);\n }\n term = term * Polynomial(string(num, var));\n continue;\n }\n if(s[p] == '('){\n p++;\n term = term * parse(p, s);\n continue;\n }\n }\n}\n\nint main(){\n while(1){\n vector<string> s;\n string t;\n while(getline(cin, t), t!=\".\"){\n s.push_back(t);\n }\n if(s.empty()) break;\n\n vector<Polynomial> p;\n for(auto ss: s){\n int i=0;\n p.push_back(parse(i, ss));\n }\n for(int i=1; i<(int)p.size(); i++){\n if(p[i] == p[0]){\n cout << \"yes\" << endl;\n }else{\n cout << \"no\" << endl;\n }\n }\n cout << \".\" << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 11632, "score_of_the_acc": -1.0173, "final_rank": 19 }, { "submission_id": "aoj_1233_3723771", "code_snippet": "#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<ciso646>\n#include<random>\n#include<map>\n#include<set>\n#include<bitset>\n#include<stack>\n#include<unordered_map>\n#include<utility>\n#include<cassert>\nusing namespace std;\n\ntypedef long long ll;\n\ntypedef unsigned long long ul;\ntypedef unsigned int ui;\nconst ll mod = 998244353;\nconst ll INF = mod * mod;\ntypedef pair<int, int> P;\n#define stop char nyaa;cin>>nyaa;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define per(i,n) for(int i=n-1;i>=0;i--)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define per1(i,n) for(int i=n;i>=1;i--)\n#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)\ntypedef pair<ll, ll> LP;\ntypedef vector<int> vec;\ntypedef vector<string> svec;\ntypedef long double ld;\ntypedef pair<ld, ld> LDP;\nconst ld eps = 1e-8;\n\nll expr(string& s, int& i);\nll term1(string& s, int& i);\nll term(string& s, int& i);\nll factor(string& s, int& i);\nll number(string& s, int& i);\n\nbool isdigit(char t) {\n\treturn '0' <= t && t <= '9';\n}\nbool isalf(char t) {\n\treturn 'a' <= t && t <= 'z';\n}\n\nll mod_pow(ll x, int n) {\n\tll ret = 1;\n\twhile (n > 0) {\n\t\tif (n % 2)ret = ret * x%mod;\n\t\tx = x * x%mod; n >>= 1;\n\t}\n\treturn ret;\n}\n\nll expr(string& s, int& i) {\n\tll val = term1(s, i);\n\twhile (i < s.length()) {\n\t\tif (s[i] == ' ') {\n\t\t\ti++; continue;\n\t\t}\n\t\tif (s[i] == '+' || s[i] == '-') {\n\t\t\tchar op = s[i];\n\t\t\ti++;\n\t\t\tll val2 = term1(s, i);\n\t\t\tif (op == '+') {\n\t\t\t\tval += val2; if (val >= mod)val -= mod;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tval += mod - val2; while (val >= mod)val -= mod;\n\t\t\t}\n\t\t}\n\t\telse break;\n\t}\n\t//cout << i << \" expr \" << val << endl;\n\treturn val;\n}\nll term1(string& s, int& i) {\n\tll val = term(s, i);\n\twhile (i < s.length() && s[i] == ' ')i++;\n\tif (i >= s.length() || s[i] == '+' || s[i] == '-'||s[i]==')') {\n\t\treturn val;\n\t}\n\telse {\n\t\tll val2 = term1(s, i);\n\t\tval = val * val2%mod;\n\t}\n\t//cout << i << \" term1 \" << val << endl;\n\treturn val;\n}\nll term(string& s, int& i) {\n\tll val = factor(s, i);\n\twhile (i < s.length() && s[i] == ' ')i++;\n\tif (i<s.length() && s[i] == '^') {\n\t\ti++;\n\t\tll val2 = number(s, i);\n\t\tval = mod_pow(val, val2);\n\t}\n\t//cout << i << \" term \" << val << endl;\n\treturn val;\n}\nll factor(string& s, int& i) {\n\twhile (i < s.length() && s[i] == ' ')i++;\n\tif (i<s.length() && isdigit(s[i]))return number(s, i);\n\ti++;\n\twhile (i < s.length() && s[i] == ' ')i++;\n\tll ret = expr(s, i);\n\ti++;\n\twhile (i < s.length() && s[i] == ' ')i++;\n\t//cout << i << \" fact \" << ret << endl;\n\treturn ret;\n}\nll number(string& s, int& i) {\n\twhile (s[i] == ' ')i++;\n\tll ret = s[i++] - '0';\n\twhile (i < s.length() && isdigit(s[i])) {\n\t\tret = ret * 10 + s[i++] - '0';\n\t\tret %= mod;\n\t}\n\t//cout << i << \" numb \" << ret << endl;\n\treturn ret;\n}\n\nvector<vector<ll>> gene(int len) {\n\trandom_device rnd;\n\tmt19937 mt(rnd());\n\tuniform_int_distribution<> u(0, 2147483647);\n\tvector<vector<ll>> ret(len);\n\trep(i, len) {\n\t\tret[i].resize(26);\n\t\trep(j, 26) {\n\t\t\tret[i][j] = u(mt);\n\t\t}\n\t}\n\treturn ret;\n}\n\nll calc(string s, vector<ll> t) {\n\tstring upd;\n\trep(i, s.length()) {\n\t\tif (isalf(s[i])) {\n\t\t\tstring u = to_string(t[s[i] - 'a']);\n\t\t\tupd.push_back(' ');\n\t\t\tupd = upd + u;\n\t\t}\n\t\telse if (isdigit(s[i])) {\n\t\t\tint le = i;\n\t\t\twhile (i + 1 < s.length() && isdigit(s[i + 1]))i++;\n\t\t\tupd.push_back(' ');\n\t\t\tRep1(j, le, i)upd.push_back(s[j]);\n\t\t}\n\t\telse {\n\t\t\tupd.push_back(s[i]);\n\t\t}\n\t}\n\tint i = 0;\n\t//cout << s << endl;\n\t//cout << upd << endl;\n\t//cout << upd << endl;\n\treturn expr(upd, i);\n}\n\nconst int sz = 100;\nbool solve() {\n\tstring s;\n\tvector<string> v;\n\twhile (getline(cin, s)) {\n\t\tif (s[0] == '.') {\n\t\t\tbreak;\n\t\t}\n\t\tv.push_back(s);\n\t}\n\tif (v.size() == 0)return false;\n\tvector<vector<ll>> test = gene(sz);\n\tvector<vector<ll>> ans(v.size());\n\trep(i, v.size()) {\n\t\tans[i].resize(sz);\n\t\trep(j, sz) {\n\t\t\tans[i][j] = calc(v[i], test[j]);\n\t\t\t//cout << i << \" \" << ans[i][j] << endl;\n\t\t}\n\t}\n\tfor (int i = 1; i < v.size(); i++) {\n\t\tbool f = (ans[i] == ans[0]);\n\t\tif (f) {\n\t\t\tcout << \"yes\" << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << \"no\" << endl;\n\t\t}\n\t}\n\tcout << \".\" << endl;\n\treturn true;\n}\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\n\t/*string s = \"a+b+c\";\n\tstring ss = \"(a+b)+c\";\n\tvector<ll> c(26, 0); c[0] = 1, c[1] = 2; c[2] = 3;\n\tcout << calc(s, c) << endl;\n\tcout << calc(ss, c) << endl;*/\n\n\t//cout << fixed << setprecision(10);\n\t//init();\n\twhile (true) {\n\t\tif (!solve())break;\n\t}\n\t//stop\n\t\treturn 0;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 4080, "score_of_the_acc": -0.2636, "final_rank": 17 }, { "submission_id": "aoj_1233_3312395", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}\n\n//INSERT ABOVE HERE\n\nstruct T{\n map<string, Int> ms;\n T(){}\n T(string s, Int c){\n sort(s.begin(),s.end());\n ms[s]+=c;\n }\n\n T operator+=(const T &a){\n for(auto p:a.ms)\n ms[p.first]+=p.second;\n return *this;\n }\n \n T operator-=(const T &a){\n for(auto p:a.ms)\n ms[p.first]-=p.second;\n return *this;\n }\n \n T operator+(const T &a) const{\n T res(*this);\n return res+=a;\n }\n \n T operator-(const T &a) const{\n T res(*this);\n return res-=a;\n }\n \n T operator*(const T &a) const{\n T res;\n for(auto p:ms)\n for(auto q:a.ms)\n res+=T(p.first+q.first,p.second*q.second);\n return res;\n }\n\n T pow(Int k) const{\n assert(k>=1);\n T res(*this);\n for(Int i=1;i<k;i++) res=res*(*this);\n return res;\n }\n\n map<string, Int> norm(){\n map<string, Int> res;\n for(auto p:ms)\n if(p.second) res[p.first]=p.second;\n return res;\n }\n};\n\nusing V = vector<string>; \nT expr (const V &vs,Int &p);\nT term (const V &vs,Int &p);\nT factor(const V &vs,Int &p);\nT power (const V &vs,Int &p);\nInt number(const V &vs,Int &p);\n\nT expr (const V &vs,Int &p){\n T res=term(vs,p);\n while(p<(Int)vs.size()){\n if(vs[p]==\"+\"s){\n p++;\n res=res+term(vs,p);\n continue;\n }\n if(vs[p]==\"-\"s){\n p++;\n res=res-term(vs,p);\n continue;\n }\n break;\n }\n return res;\n}\n\nT term (const V &vs,Int &p){ \n T res=factor(vs,p);\n while(p<(Int)vs.size()){\n if(vs[p]==\"+\"s) break;\n if(vs[p]==\"-\"s) break;\n if(vs[p]==\"^\"s) break;\n if(vs[p]==\")\"s) break;\n res=res*factor(vs,p);\n }\n return res;\n}\n\nT factor(const V &vs,Int &p){ \n T res=power(vs,p);\n if(p<(Int)vs.size()&&vs[p]==\"^\"s){\n p++;\n Int k=number(vs,p);\n return res.pow(k);\n } \n return res;\n}\n\nT power (const V &vs,Int &p){\n if(vs[p]==\"(\"s){\n p++;\n T res=expr(vs,p);\n assert(vs[p]==\")\"s);\n p++;\n return res;\n }\n if(isalpha(vs[p][0])) return T(vs[p++],1);\n return T(\"\"s, number(vs,p));\n}\n\nInt number(const V &vs,Int &p){\n return stoll(vs[p++]);\n}\n\nT tran(string s){\n Int n=s.size();\n string t;\n for(Int i=0;i<n;i++){\n if(!isdigit(s[i])) t+=' ';\n t+=s[i];\n if(!isdigit(s[i])) t+=' ';\n } \n V vs;\n stringstream ss(t);\n while(ss>>t) vs.emplace_back(t);\n Int p=0;\n return expr(vs,p);\n}\n\nsigned main(){\n string s;\n while(getline(cin,s)){\n if(s==\".\"s) break;\n auto vs=tran(s);\n while(1){\n string t;\n getline(cin,t); \n if(t==\".\"s) break;\n auto vt=tran(t);\n cout<<(vs.norm()==vt.norm()?\"yes\":\"no\")<<endl;\n } \n cout<<\".\"<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 3476, "score_of_the_acc": -0.1997, "final_rank": 13 }, { "submission_id": "aoj_1233_2984295", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))\n#define all(x) (x).begin(),(x).end()\n#define pb push_back\n#define fi first\n#define se second\n#define dbg(x) cout<<#x\" = \"<<((x))<<endl\ntemplate<class T,class U> ostream& operator<<(ostream& o, const pair<T,U> &p){o<<\"(\"<<p.fi<<\",\"<<p.se<<\")\";return o;}\ntemplate<class T> ostream& operator<<(ostream& o, const vector<T> &v){o<<\"[\";for(T t:v){o<<t<<\",\";}o<<\"]\";return o;}\n\nusing f = map<string,ll>;\n\nvoid PRINT(f a){\n for(const auto &p:a){\n cout << p.se << p.fi << \" + \";\n }\n cout << endl;\n}\n\nf norm(f a){\n f ret;\n for(const auto &p:a){\n string v = p.fi;\n sort(all(v));\n if(p.se != 0) ret[v] = p.se;\n }\n return ret;\n}\n\nf sub(f a){\n a = norm(a);\n\n f ret;\n for(const auto &p:a){\n string v = p.fi;\n if(p.se != 0) ret[v] = -p.se;\n }\n return ret;\n}\n\nf add(f a, f b){\n a = norm(a);\n b = norm(b);\n\n for(const auto &p:b) a[p.fi] += p.se;\n\n return norm(a);\n}\n\nf mul(f a, f b){\n a = norm(a);\n b = norm(b);\n\n f ret;\n for(const auto &p:a)for(const auto &q:b){\n string var = p.fi+q.fi;\n sort(all(var));\n\n ret[var] += p.se*q.se;\n }\n return norm(ret);\n}\n\nf E(string s);\n\nf T(string s){\n int n = s.size();\n f ret;\n ret[\"\"]=1;\n\n int idx = 0;\n while(idx<n){\n f m;\n if(s[idx]==' '){\n ++idx;\n continue;\n }\n else if(s[idx]=='('){\n int ep = idx;\n int p = 0;\n while(ep<n){\n if(s[ep]=='(') ++p;\n if(s[ep]==')'){\n --p;\n if(p==0) break;\n }\n ++ep;\n }\n assert(ep<n);\n assert(s[ep]==')');\n\n string t = s.substr(idx+1,ep-idx-1);\n m = E(t);\n idx = ep+1;\n }\n else if(isdigit(s[idx])){\n ll val = 0;\n while(idx<n && isdigit(s[idx])){\n val = val*10 + (s[idx]-'0');\n ++idx;\n }\n\n int pw = 1;\n int nx = idx;\n while(nx<n && s[nx]==' ') ++nx;\n if(nx<n && s[nx]=='^'){\n ++nx;\n while(nx<n && s[nx]==' ') ++nx;\n\n assert(nx<n);\n assert(isdigit(s[nx]));\n\n pw = 0;\n while(nx<n && isdigit(s[nx])){\n pw = 10*pw + (s[nx]-'0');\n ++nx;\n }\n }\n\n ll vv = 1;\n rep(_,pw) vv *= val;\n\n m[\"\"] = vv;\n idx = nx;\n }\n else if(islower(s[idx])){\n char c = s[idx];\n ++idx;\n\n int pw = 1;\n int nx = idx;\n while(nx<n && s[nx]==' ') ++nx;\n if(nx<n && s[nx]=='^'){\n ++nx;\n while(nx<n && s[nx]==' ') ++nx;\n\n assert(nx<n);\n assert(isdigit(s[nx]));\n\n pw = 0;\n while(nx<n && isdigit(s[nx])){\n pw = 10*pw + (s[nx]-'0');\n ++nx;\n }\n }\n\n string t = \"\";\n rep(_,pw) t += c;\n\n m[t] = 1;\n idx = nx;\n }\n else assert(false);\n\n ret = mul(ret, m);\n }\n\n return norm(ret);\n}\n\nf E(string s){\n int n = s.size();\n f ret;\n\n int p = 0;\n int start = 0;\n bool plus = true;\n\n rep(i,n){\n if(s[i]=='(') ++p;\n if(s[i]==')') --p;\n\n if(s[i]=='+' || s[i]=='-'){\n if(p==0){\n string term = s.substr(start,i-start);\n f t = norm(T(term));\n if(!plus) t = sub(t);\n plus = (s[i]=='+');\n\n ret = add(ret, t);\n\n start = i+1;\n }\n }\n }\n\n string term = s.substr(start,n-start);\n f t = norm(T(term));\n if(!plus) t = sub(t);\n\n ret = add(ret, t);\n\n return norm(ret);\n}\n\nint main(){\n string s;\n while(getline(cin, s),(s!=\".\")){\n f S = E(s);\n // PRINT(S);\n\n string t;\n while(getline(cin, t),(t!=\".\")){\n f T = E(t);\n // PRINT(T);\n cout << (S==T?\"yes\":\"no\") << endl;\n }\n cout << \".\" << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 3644, "score_of_the_acc": -0.2125, "final_rank": 15 }, { "submission_id": "aoj_1233_2880819", "code_snippet": "#include <cstdio>\n#include <cstdint>\n#include <cassert>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <random>\n\nintmax_t ppow(intmax_t base, intmax_t iexp) {\n intmax_t res=1;\n for (intmax_t dbl=base; iexp; iexp>>=1) {\n if (iexp & 1)\n res *= dbl;\n\n dbl *= dbl;\n }\n return res;\n}\n\nintmax_t apply(intmax_t lhs, char op, intmax_t rhs) {\n switch (op) {\n case '+': return lhs + rhs;\n case '-': return lhs - rhs;\n case '*': return lhs * rhs;\n case '^': return ppow(lhs, rhs);\n default: assert(false);\n }\n}\n\nintmax_t fourt(\n const std::string &s, size_t &i, const std::vector<intmax_t> &vars,\n const std::vector<std::string> &ops={\"+-\", \"*\", \"^\", \"\"},\n size_t prec=0) {\n\n /* tsurai parser */\n if (ops[prec].empty()) {\n if (s[i] == '(') {\n intmax_t tmp=fourt(s, ++i, vars, ops, 0);\n assert(s[i] == ')');\n ++i;\n return tmp;\n }\n if (isalpha(s[i])) {\n // we assume only one-character variables\n return vars[s[i++]-'a'];\n }\n intmax_t res=0;\n while (s[i] >= '0' && s[i] <= '9')\n res = res*10 + s[i++]-'0';\n return res;\n }\n\n intmax_t res=fourt(s, i, vars, ops, prec+1);\n while (i < s.length()) {\n char op=s[i];\n if (!std::count(ops[prec].begin(), ops[prec].end(), op))\n break;\n intmax_t tmp=fourt(s, ++i, vars, ops, prec+1);\n res = apply(res, op, tmp);\n }\n return res;\n}\n\nintmax_t parse(const std::string &s, const std::vector<intmax_t> &vars) {\n size_t i=0;\n return fourt(s, i, vars);\n}\n\nstd::string normalize(const std::string &s) {\n // explicit `*' signs and no spaces\n std::string res;\n enum {\n NONE, PAREN, FACTOR, OPERATOR\n } last=NONE;\n for (size_t i=0; i<s.length(); ++i) {\n if (s[i] == '(') {\n if (last == FACTOR) {\n res += '*';\n }\n res += '(';\n last = PAREN;\n } else if (s[i] == ')') {\n res += ')';\n last = FACTOR;\n } else if (isalnum(s[i])) {\n if (last == FACTOR) {\n res += '*';\n }\n res += s[i];\n if (isdigit(s[i])) {\n while (i+1 < s.length() && isdigit(s[i+1]))\n res += s[++i];\n }\n last = FACTOR;\n } else if (!isspace(s[i])) {\n res += s[i];\n last = OPERATOR;\n }\n }\n // fprintf(stderr, \"#< %s\\n\", res.c_str());\n return res;\n}\n\nstd::mt19937 rsk(0315);\nint testcase_ends() {\n char buf[96];\n fgets(buf, sizeof buf, stdin);\n std::string s=buf;\n if (s == \".\\n\")\n return 1;\n\n s = normalize(s);\n while (true) {\n fgets(buf, sizeof buf, stdin);\n std::string t=buf;\n if (t == \".\\n\") {\n printf(\".\\n\");\n return 0;\n }\n\n t = normalize(t);\n bool yes=true;\n for (int i=0; i<810; ++i) {\n std::vector<intmax_t> vars(26);\n for (int j=0; j<26; ++j)\n vars[j] = rsk() % 100;\n \n if (parse(s, vars) != parse(t, vars))\n yes = false;\n }\n\n printf(\"%s\\n\", yes? \"yes\":\"no\");\n }\n}\n\nint main() {\n while (!testcase_ends()) {}\n}", "accuracy": 1, "time_ms": 760, "memory_kb": 2584, "score_of_the_acc": -0.2139, "final_rank": 16 }, { "submission_id": "aoj_1233_2880805", "code_snippet": "#include <cstdio>\n#include <cstdint>\n#include <cassert>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <map>\n\n//#define fprintf(...) void(0)\n\nclass Poly {\n std::map<std::string, int> coefs;\n // e.g. coefs[\"aab\"] == 2 <=> the polynomial has the term 2 a^2 b\n const std::string s;\n\n Poly &operator ^=(const Poly &oth) {\n if (oth.coefs.size() == 1 && oth.coefs.find(\"\") != oth.coefs.end()) {\n return (*this) ^= oth.coefs.find(\"\")->second;\n } else if (oth.coefs.empty()) {\n // means 0\n coefs.clear();\n coefs[\"\"] = 1; // means 1\n return (*this);\n }\n\n assert(false);\n }\n\n Poly &op_eq(char op, const Poly &rhs) {\n // (*this) @= rhs\n switch (op) {\n case '+': return (*this) += rhs;\n case '-': return (*this) -= rhs;\n case '*': return (*this) *= rhs;\n case '^': return (*this) ^= rhs;\n default: assert(false);\n }\n }\n\n Poly fourt(\n size_t &i, \n const std::vector<std::string> &ops={\"+-\", \"*\", \"^\", \"\"},\n size_t prec=0) {\n\n /* based-on tsurai parser */\n\n if (ops[prec].empty()) {\n if (s[i] == '(') {\n Poly tmp=fourt(++i, ops, 0);\n assert(s[i] == ')');\n ++i;\n return tmp;\n }\n if (isalpha(s[i])) {\n // we assume only one-character variables\n return Poly(s[i++]);\n }\n int coef=0;\n while (s[i] >= '0' && s[i] <= '9')\n coef = coef*10 + s[i++]-'0';\n return Poly(coef);\n }\n\n Poly res=fourt(i, ops, prec+1);\n while (i < s.length()) {\n char op=s[i];\n if (!std::count(ops[prec].begin(), ops[prec].end(), op))\n break;\n Poly tmp=fourt(++i, ops, prec+1);\n res.op_eq(op, tmp);\n }\n return res;\n }\n\n Poly &normalized() {\n for (auto it=coefs.begin(); it!=coefs.end(); ++it)\n if (it->second == 0)\n coefs.erase(it);\n\n return *this;\n }\n\npublic:\n Poly(const std::string &s): s(s) {\n size_t i=0;\n coefs = fourt(i).coefs; // ugh\n }\n\n Poly(char ch): s(1, ch) {\n assert(isalpha(ch));\n coefs[s] = 1;\n }\n\n Poly(int n): s(std::to_string(n)) {\n if (n)\n coefs[\"\"] = n;\n }\n\n Poly &operator +=(const Poly &oth) {\n for (const auto &p: oth.coefs) {\n const std::string &param=p.first;\n int coef=p.second;\n coefs[param] += coef;\n }\n return normalized();\n }\n\n Poly &operator -=(const Poly &oth) {\n for (const auto &p: oth.coefs) {\n const std::string &param=p.first;\n int coef=p.second;\n coefs[param] -= coef;\n }\n return normalized();\n }\n\n Poly &operator *=(const Poly &oth) {\n Poly tmp(*this);\n coefs.clear();\n for (const auto &pl: tmp.coefs) {\n for (const auto &pr: oth.coefs) {\n std::string param=pl.first+pr.first;\n std::sort(param.begin(), param.end());\n coefs[param] += pl.second*pr.second;\n }\n }\n return normalized();\n }\n\n Poly &operator ^=(int iexp) {\n if (iexp == 0) {\n // does not appear in #1233\n coefs.clear();\n coefs[\"\"] = 1; // means 1\n } else {\n Poly tmp(*this);\n for (int i=1; i<iexp; ++i)\n // O(iexp) multiplications, ugh\n *this *= tmp;\n }\n return normalized();\n }\n\n Poly operator +(const Poly &oth) const { return Poly(*this) += oth; }\n Poly operator -(const Poly &oth) const { return Poly(*this) -= oth; }\n Poly operator *(const Poly &oth) const { return Poly(*this) *= oth; }\n Poly operator ^(int iexp) const { return Poly(*this) ^= iexp; }\n bool operator ==(const Poly &oth) const { return coefs == oth.coefs; }\n\n void debug() const {\n if (coefs.empty()) {\n fprintf(stderr, \"#> 0\\n\");\n return;\n }\n fprintf(stderr, \"#>\");\n for (const auto &p: coefs)\n fprintf(stderr, \" %d%s\", p.second, p.first.c_str());\n fprintf(stderr, \"\\n\");\n }\n};\n\nstd::string normalize(const std::string &s) {\n // explicit `*' signs and no spaces\n std::string res;\n enum {\n NONE, PAREN, FACTOR, OPERATOR\n } last=NONE;\n for (size_t i=0; i<s.length(); ++i) {\n if (s[i] == '(') {\n if (last == FACTOR) {\n res += '*';\n }\n res += '(';\n last = PAREN;\n } else if (s[i] == ')') {\n res += ')';\n last = FACTOR;\n } else if (isalnum(s[i])) {\n if (last == FACTOR) {\n res += '*';\n }\n res += s[i];\n if (isdigit(s[i])) {\n while (i+1 < s.length() && isdigit(s[i+1]))\n res += s[++i];\n }\n last = FACTOR;\n } else if (!isspace(s[i])) {\n res += s[i];\n last = OPERATOR;\n }\n }\n // fprintf(stderr, \"#< %s\\n\", res.c_str());\n return res;\n}\n\nint testcase_ends() {\n char buf[96];\n fgets(buf, sizeof buf, stdin);\n std::string s=buf;\n if (s == \".\\n\")\n return 1;\n\n s = normalize(s);\n Poly ps(s);\n while (true) {\n fgets(buf, sizeof buf, stdin);\n std::string t=buf;\n if (t == \".\\n\") {\n printf(\".\\n\");\n return 0;\n }\n\n t = normalize(t);\n Poly pt(t);\n printf(\"%s\\n\", (ps == pt)? \"yes\":\"no\");\n }\n}\n\nint main() {\n while (!testcase_ends()) {}\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3112, "score_of_the_acc": -0.0815, "final_rank": 5 }, { "submission_id": "aoj_1233_2880804", "code_snippet": "#include <cstdio>\n#include <cstdint>\n#include <cassert>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <map>\n\n#define fprintf(...) void(0)\n\nclass Poly {\n std::map<std::string, int> coefs;\n // e.g. coefs[\"aab\"] == 2 <=> the polynomial has the term 2 a^2 b\n const std::string s;\n\n Poly &operator ^=(const Poly &oth) {\n if (oth.coefs.size() == 1 && oth.coefs.find(\"\") != oth.coefs.end()) {\n return (*this) ^= oth.coefs.find(\"\")->second;\n } else if (oth.coefs.empty()) {\n // means 0\n coefs.clear();\n coefs[\"\"] = 1; // means 1\n return (*this);\n }\n\n assert(false);\n }\n\n Poly &op_eq(char op, const Poly &rhs) {\n // (*this) @= rhs\n switch (op) {\n case '+': return (*this) += rhs;\n case '-': return (*this) -= rhs;\n case '*': return (*this) *= rhs;\n case '^': return (*this) ^= rhs;\n default: assert(false);\n }\n }\n\n Poly fourt(\n size_t &i, \n const std::vector<std::string> &ops={\"+-\", \"*\", \"^\", \"\"},\n size_t prec=0) {\n\n if (ops[prec].empty()) {\n if (s[i] == '(') {\n Poly tmp=fourt(++i, ops, 0);\n assert(s[i] == ')');\n ++i;\n return tmp;\n }\n if (isalpha(s[i])) {\n // we assume only one-character variables\n return Poly(s[i++]);\n }\n int coef=0;\n while (s[i] >= '0' && s[i] <= '9')\n coef = coef*10 + s[i++]-'0';\n return Poly(coef);\n }\n\n Poly res=fourt(i, ops, prec+1);\n while (i < s.length()) {\n char op=s[i];\n if (!std::count(ops[prec].begin(), ops[prec].end(), op))\n break;\n Poly tmp=fourt(++i, ops, prec+1);\n res.op_eq(op, tmp);\n }\n return res;\n }\n\n Poly &normalized() {\n for (auto it=coefs.begin(); it!=coefs.end(); ++it) {\n if (it->second == 0) {\n fprintf(stderr, \"Removed: %s\\n\", it->first.c_str());\n coefs.erase(it);\n }\n }\n return *this;\n }\n\npublic:\n Poly(const std::string &s): s(s) {\n size_t i=0;\n coefs = fourt(i).coefs; // ugh\n }\n\n Poly(char ch): s(1, ch) {\n assert(isalpha(ch));\n coefs[s] = 1;\n }\n\n Poly(int n): s(std::to_string(n)) {\n if (n)\n coefs[\"\"] = n;\n }\n\n Poly &operator +=(const Poly &oth) {\n for (const auto &p: oth.coefs) {\n const std::string &param=p.first;\n int coef=p.second;\n coefs[param] += coef;\n }\n return normalized();\n }\n\n Poly &operator -=(const Poly &oth) {\n for (const auto &p: oth.coefs) {\n const std::string &param=p.first;\n int coef=p.second;\n coefs[param] -= coef;\n }\n return normalized();\n }\n\n Poly &operator *=(const Poly &oth) {\n Poly tmp(*this);\n coefs.clear();\n for (const auto &pl: tmp.coefs) {\n for (const auto &pr: oth.coefs) {\n std::string param=pl.first+pr.first;\n std::sort(param.begin(), param.end());\n coefs[param] += pl.second*pr.second;\n }\n }\n return normalized();\n }\n\n Poly &operator ^=(int iexp) {\n if (iexp == 0) {\n // does not appear in #1233\n coefs.clear();\n coefs[\"\"] = 1; // means 1\n } else {\n Poly tmp(*this);\n for (int i=1; i<iexp; ++i)\n // O(iexp) multiplications, ugh\n *this *= tmp;\n }\n return normalized();\n }\n\n Poly operator +(const Poly &oth) const { return Poly(*this) += oth; }\n Poly operator -(const Poly &oth) const { return Poly(*this) -= oth; }\n Poly operator *(const Poly &oth) const { return Poly(*this) *= oth; }\n Poly operator ^(int iexp) const { return Poly(*this) ^= iexp; }\n bool operator ==(const Poly &oth) const { return coefs == oth.coefs; }\n\n void debug() const {\n if (coefs.empty()) {\n fprintf(stderr, \"#> 0\\n\");\n return;\n }\n fprintf(stderr, \"#>\");\n for (const auto &p: coefs)\n fprintf(stderr, \" %d%s\", p.second, p.first.c_str());\n fprintf(stderr, \"\\n\");\n }\n};\n\nstd::string normalize(const std::string &s) {\n // explicit `*' signs and no spaces\n std::string res;\n enum {\n NONE, PAREN, FACTOR, OPERATOR\n } last=NONE;\n for (size_t i=0; i<s.length(); ++i) {\n if (s[i] == '(') {\n if (last == FACTOR) {\n res += '*';\n }\n res += '(';\n last = PAREN;\n } else if (s[i] == ')') {\n res += ')';\n last = FACTOR;\n } else if (isalnum(s[i])) {\n if (last == FACTOR) {\n res += '*';\n }\n res += s[i];\n if (isdigit(s[i])) {\n while (i+1 < s.length() && isdigit(s[i+1]))\n res += s[++i];\n }\n last = FACTOR;\n } else if (!isspace(s[i])) {\n res += s[i];\n last = OPERATOR;\n }\n }\n fprintf(stderr, \"#< %s\\n\", res.c_str());\n return res;\n}\n\nint testcase_ends() {\n char buf[96];\n fgets(buf, sizeof buf, stdin);\n std::string s=buf;\n if (s == \".\\n\")\n return 1;\n\n s = normalize(s);\n Poly ps(s);\n ps.debug();\n while (true) {\n fgets(buf, sizeof buf, stdin);\n std::string t=buf;\n if (t == \".\\n\") {\n printf(\".\\n\");\n return 0;\n }\n\n t = normalize(t);\n Poly pt(t);\n pt.debug();\n printf(\"%s\\n\", (ps == pt)? \"yes\":\"no\");\n }\n}\n\nint main() {\n while (!testcase_ends()) {}\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3112, "score_of_the_acc": -0.0757, "final_rank": 3 }, { "submission_id": "aoj_1233_2833675", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct term {\n int coff;\n vector<int> deg;\n\n term() : coff(1), deg(26, 0) {}\n\n bool operator<(const term& other) const {\n return deg < other.deg;\n }\n bool operator==(const term& other) const {\n return coff == other.coff && deg == other.deg;\n }\n};\n\nstruct expression {\n void add_term(term new_term) {\n for(auto& t : terms) {\n if(t.deg == new_term.deg) {\n t.coff += new_term.coff;\n return;\n }\n }\n terms.push_back(move(new_term));\n sort(begin(terms), end(terms));\n clean_up();\n }\n\n void add_expr(expression e) {\n for(auto& t : e.terms) {\n add_term(t);\n }\n clean_up();\n }\n\n expression operator-() const {\n expression res;\n res.terms = terms;\n for(auto& t : res.terms) {\n t.coff = -t.coff;\n }\n return res;\n }\n\n bool operator==(expression const& other) const {\n return terms == other.terms;\n }\n\n void clean_up() {\n terms.erase(remove_if(begin(terms), end(terms),\n [](const auto& t1) {\n return t1.coff == 0;\n }),\n end(terms));\n }\n\n void debug_print() const {\n cout << \"sz: \" << terms.size() << endl;\n for(auto& t : terms) {\n cout << \"coff: \" << t.coff << \" deg: \";\n for(int i = 0; i < 26; ++i) {\n cout << t.deg[i] << ' ';\n }\n cout << endl;\n }\n }\n\n vector<term> terms;\n};\n\nterm operator*(term a, term const& rhs) {\n a.coff *= rhs.coff;\n for(int i = 0; i < 26; ++i) {\n a.deg[i] += rhs.deg[i];\n }\n return a;\n}\n\nexpression operator*(expression const& lhs, expression const& rhs) {\n expression res;\n for(auto const& t1 : lhs.terms) {\n for(auto const& t2 : rhs.terms) {\n res.add_term(t1 * t2);\n }\n }\n return res;\n}\n\n\nexpression parse_expr(string const& s, int& p);\nexpression parse_term(string const& s, int& p);\nexpression parse_factor(string const& s, int& p);\nvoid skip_sp(string const& s, int& p);\nint number(string const& s, int& p);\n\nexpression parse_expr(string const& s, int& p) {\n auto e = parse_term(s, p);\n skip_sp(s, p);\n while(p < (int)s.size() && (s[p] == '+' || s[p] == '-')) {\n const char op = s[p++];\n skip_sp(s, p);\n auto t2 = parse_term(s, p);\n if(op == '-') {\n t2 = -t2;\n }\n e.add_expr(t2);\n skip_sp(s, p);\n }\n return e;\n}\n\nexpression parse_term(string const& s, int& p) {\n auto e = parse_factor(s, p);\n skip_sp(s, p);\n while(p < (int)s.size() && s[p] != '+' && s[p] != '-' && s[p] != ')') {\n auto f = parse_factor(s, p);\n e = e * f;\n }\n return e;\n}\n\nexpression parse_factor(string const& s, int& p) {\n expression res;\n skip_sp(s, p);\n\n if(s[p] == '(') {\n skip_sp(s, ++p);\n auto e = parse_expr(s, p);\n res = e;\n skip_sp(s, p);\n assert(s[p] == ')');\n skip_sp(s, ++p); // )\n if(p < (int)s.size() && s[p] == '^') {\n skip_sp(s, ++p);\n int d = number(s, p); // todo: only \"^ (number)\" ?\n for(int i = 0; i < d - 1; ++i) {\n res = res * e;\n }\n }\n skip_sp(s, p);\n } else if(isdigit(s[p])) {\n const int n = number(s, p);\n term t;\n t.coff = n;\n res.add_term(t);\n skip_sp(s, p);\n } else if(isalpha(s[p])) {\n const int idx = s[p++] - 'a';\n term t;\n t.deg[idx] = 1;\n skip_sp(s, p);\n if(p < (int)s.size() && s[p] == '^') {\n skip_sp(s, ++p);\n t.deg[idx] *= number(s, p);\n skip_sp(s, p);\n }\n res.add_term(t);\n } else {\n cout << \"str: \" << s << \" p: \" << p << \" s[p]: \" << s[p] << endl;\n assert(false);\n }\n\n return res;\n}\n\nint number(string const& s, int& p) {\n assert(isdigit(s[p]));\n int res = 0;\n while(p < (int)s.size() && isdigit(s[p])) {\n res *= 10;\n res += s[p++] - '0';\n }\n return res;\n}\n\nvoid skip_sp(string const& s, int& p) {\n while(p < (int)s.size() && s[p] == ' ') {\n p++;\n }\n}\n\nexpression parse(string const& s) {\n int p = 0;\n return parse_expr(s, p);\n}\n\n\nint main() {\n string s;\n while(getline(cin, s), s[0] != '.') {\n if(s.back() == '\\r') s.pop_back();\n const auto target = parse(s);\n string t;\n while(getline(cin, t), t[0] != '.') {\n if(t.back() == '\\r') t.pop_back();\n const auto ss = parse(t);\n if(target == ss) {\n cout << \"yes\" << endl;\n } else {\n cout << \"no\" << endl;\n }\n }\n cout << \".\" << endl;\n }\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 3372, "score_of_the_acc": -0.2027, "final_rank": 14 }, { "submission_id": "aoj_1233_2565832", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nusing K = string;\nusing M = map<K, int>;\n\nK mul(K k1, K k2){\n\tk1 += k2;\n\tsort(k1.begin(), k1.end());\n\treturn k1;\n}\n\nM add(M m1, M m2){\n\tfor(auto v : m2){\n\t\tm1[v.first] += v.second;\n\t}\n\treturn m1;\n}\n\nM mul(M m1, M m2){\n\tM ret;\n\tfor(const auto& v1 : m1){\n\t\tfor(const auto& v2 : m2){\n\t\t\tK k = mul(v1.first, v2.first);\n\t\t\tret[k] += v1.second * v2.second;\n\t\t}\n\t}\n\treturn ret;\n}\n\nM pow(M m, int x){\n\tM ret;\n\tret[\"\"] = 1;\n\tM a = m;\n\twhile(x){\n\t\tif(x & 1) ret = mul(ret, a);\n\t\tx /= 2;\n\t\ta = mul(a, a);\n\t}\n\treturn ret;\n}\n\nint c;\nint N;\nstring s;\n\nM exp();\nM term();\nM fact();\n\nvoid skip(){\n\twhile(c < N && (s[c] == ' ')) c++;\n}\n\nM exp(){\n\tskip();\n\tM t1 = term();\n\n\tskip();\n\twhile(c < N && (s[c] == '+' || s[c] == '-')){\n\t\tchar ch = s[c];\n\t\tc++;\n\t\tskip();\n\t\tM t2 = term();\n\t\tif(ch == '-'){\n\t\t\tfor(auto& v : t2){\n\t\t\t\tv.second *= -1;\n\t\t\t}\n\t\t}\n\t\tt1 = add(t1, t2);\n\t}\n\treturn t1;\n}\n\nM term(){\n\tskip();\n\tM f1 = fact();\n\tskip();\n\twhile(c < N && (isalnum(s[c]) || s[c] == '(')){\n\t\tM f2 = fact();\n\t\tskip();\n\t\tf1 = mul(f1, f2);\n\t}\n\treturn f1;\n}\n\nM fact(){\n\tskip();\n\tM r;\n\tif(s[c] == '('){\n\t\tc++;\n\t\tr = exp();\n\t\tc++;\n\t\tskip();\n\t}\n\telse if(isalpha(s[c])){\n\t\tK k;\n\t\tk += s[c];\n\t\tc++;\n\t\tr[k]++;\n\t}\n\telse if(isdigit(s[c])){\n\t\tint x = 0;\n\t\twhile(c < N && isdigit(s[c])){\n\t\t\tx = x * 10 + s[c] - '0';\n\t\t\tc++;\n\t\t}\n\t\tr[\"\"] += x;\n\t}\n\tskip();\n\tif(c < N && s[c] == '^'){\n\t\tc++;\n\t\tskip();\n\t\tint x = s[c] - '0';\n\t\tc++;\n\t\tskip();\n\t\tr = pow(r, x);\n\t}\n\treturn r;\n}\n\nM f(string t){\n\tc = 0;\n\ts = t;\n\tN = s.size();\n\treturn exp();\n}\n\nM filter(M m){\n\tM ret;\n\tfor(auto v : m){\n\t\tif(v.second == 0) continue;\n\t\tret[v.first] = v.second;\n\t}\n\treturn ret;\n}\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n#ifdef LOCAL\n\tstd::ifstream in(\"in\");\n\tstd::cin.rdbuf(in.rdbuf());\n#endif\n\n\t//auto ret = f(\"a- (b-c)+2\");\n\n\tstring x, y;\n\twhile(getline(cin, x), x != \".\"){\n\t\tM xm = filter(f(x));\n\t\twhile(getline(cin, y), y != \".\"){\n\t\t\tauto res = filter(f(y));\n\t\t\tif(xm == res){\n\t\t\t\tcout << \"yes\" << endl;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tcout << \"no\" << endl;\n\t\t\t}\n\t\t}\n\t\tcout << \".\" << endl;\n\t}\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3380, "score_of_the_acc": -0.1082, "final_rank": 6 }, { "submission_id": "aoj_1233_2555742", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define r(i,n) for(int i=0;i<n;i++)\n#define mod 1000000007\nusing namespace std;\nstring s,t;\nint p;\nmap<char,int>m;\nvoid convertS(){\n r(i,s.size()){\n if(i&&s[i]==' '){\n if(s[i-1]==')'&&s[i+1]=='(')s[i]='*';\n else if(isalpha(s[i-1])&&isalpha(s[i+1]))s[i]='*';\n else if(s[i-1]==')'&&isalpha(s[i+1]))s[i]='*';\n else if(isalpha(s[i-1])&&s[i+1]=='(')s[i]='*';\n else if(s[i-1]==')'&&isdigit(s[i+1]))s[i]='*';\n else if(isdigit(s[i-1])&&s[i+1]=='(')s[i]='*';\n else if(isdigit(s[i-1])&&isalpha(s[i+1]))s[i]='*';\n else if(isalpha(s[i-1])&&isdigit(s[i+1]))s[i]='*';\n else if(isdigit(s[i-1])&&isdigit(s[i+1]))s[i]='*';\n else s.erase(s.begin()+i--);\n }\n if(isdigit(s[i])&&isalpha(s[i+1]))s.insert(s.begin()+i+1,'*');\n if(isalpha(s[i])&&isalpha(s[i+1]))s.insert(s.begin()+i+1,'*');\n if(isalpha(s[i])&&isdigit(s[i+1]))s.insert(s.begin()+i+1,'*');\n if(s[i]==')'&&isalpha(s[i+1]))s.insert(s.begin()+i+1,'*');\n if(s[i]==')'&&isdigit(s[i+1]))s.insert(s.begin()+i+1,'*');\n if(s[i+1]=='('&&isalpha(s[i]))s.insert(s.begin()+i+1,'*');\n if(s[i+1]=='('&&isdigit(s[i]))s.insert(s.begin()+i+1,'*');\n if(s[i+1]=='('&&s[i]==')')s.insert(s.begin()+i+1,'*');\n }\n}\nvoid convertT(){\n r(i,t.size()){\n if(i&&t[i]==' '){\n if(t[i-1]==')'&&t[i+1]=='(')t[i]='*';\n else if(isalpha(t[i-1])&&isalpha(t[i+1]))t[i]='*';\n else if(t[i-1]==')'&&isalpha(t[i+1]))t[i]='*';\n else if(isalpha(t[i-1])&&t[i+1]=='(')t[i]='*';\n else if(t[i-1]==')'&&isdigit(t[i+1]))t[i]='*';\n else if(isdigit(t[i-1])&&t[i+1]=='(')t[i]=='*';\n else if(isdigit(t[i-1])&&isalpha(t[i+1]))t[i]='*';\n else if(isalpha(t[i-1])&&isdigit(t[i+1]))t[i]='*';\n else if(isdigit(t[i-1])&&isdigit(t[i+1]))t[i]='*';\n else t.erase(t.begin()+i--);\n }\n if(isdigit(t[i])&&isalpha(t[i+1]))t.insert(t.begin()+i+1,'*');\n if(isalpha(t[i])&&isalpha(t[i+1]))t.insert(t.begin()+i+1,'*');\n if(isalpha(t[i])&&isdigit(t[i+1]))t.insert(t.begin()+i+1,'*');\n if(t[i]==')'&&isalpha(t[i+1]))t.insert(t.begin()+i+1,'*');\n if(t[i]==')'&&isdigit(t[i+1]))t.insert(t.begin()+i+1,'*');\n if(t[i+1]=='('&&isalpha(t[i]))t.insert(t.begin()+i+1,'*');\n if(t[i+1]=='('&&isdigit(t[i]))t.insert(t.begin()+i+1,'*');\n if(t[i+1]=='('&&t[i]==')')t.insert(t.begin()+i+1,'*');\n }\n}\nint Sbnf1();\nint get_S(){\n int res=0;\n if(s[p]=='(')p++,res=Sbnf1(),p++;\n else if(isdigit(s[p])){\n while(isdigit(s[p])){\n res=res*10+(s[p++]-'0');\n }\n }\n else res=m[s[p++]];\n return res%mod;\n}\nint Sbnf3(){\n int res=get_S();\n while(s[p]=='^'){\n p++;\n int ret=get_S(),kit=res;\n r(i,ret-1){\n res*=kit;\n res=res%mod;\n }\n }\n return res%mod;\n}\nint Sbnf2(){\n int res=Sbnf3();\n while(s[p]=='*'){\n p++;\n res*=Sbnf3();\n res=res%mod;\n }\n return res%mod;\n}\nint Sbnf1(){\n int res=Sbnf2();\n while(s[p]=='+'||s[p]=='-'){\n int pp=p++;\n if(s[pp]=='+')res+=Sbnf2();\n if(s[pp]=='-')res-=Sbnf2();\n while(res<0)res+=mod;\n res=res%mod;\n }\n return res%mod;\n}\nint Tbnf1();\nint get_T(){\n int res=0;\n if(t[p]=='(')p++,res=Tbnf1(),p++;\n else if(isdigit(t[p])){\n while(isdigit(t[p])){\n res=res*10+(t[p++]-'0');\n }\n }\n else res=m[t[p++]];\n return res%mod;\n}\nint Tbnf3(){\n int res=get_T();\n while(t[p]=='^'){\n p++;\n int ret=get_T(),kit=res;\n r(i,ret-1){\n res*=kit;\n res=res%mod;\n }\n }\n return res%mod;\n}\nint Tbnf2(){\n int res=Tbnf3();\n while(t[p]=='*'){\n p++;\n res*=Tbnf3();\n res=res%mod;\n }\n return res%mod;\n}\nint Tbnf1(){\n int res=Tbnf2();\n while(t[p]=='+'||t[p]=='-'){\n int pp=p++;\n if(t[pp]=='+')res+=Tbnf2();\n if(t[pp]=='-')res-=Tbnf2();\n while(res<0)res+=mod;\n res=res%mod;\n }\n return res%mod;\n}\nmain(){\n while(getline(cin,t)){\n if(t==\".\")break;\n convertT();\n while(getline(cin,s)){\n if(s==\".\"){\n cout<<'.'<<endl;\n break;\n }\n int flag = 0;\n convertS();\n r(i,100){\n r(j,26)m[j+'a']=rand()%mod;\n p=0;\n int y=Tbnf1()%mod;\n p=0;\n int x=Sbnf1()%mod;\n if(y!=x)flag++;\n }\n cout<<(flag?\"no\":\"yes\")<<endl;\n }\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3140, "score_of_the_acc": -0.0759, "final_rank": 4 }, { "submission_id": "aoj_1233_2548634", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef unsigned long long ll;\n \nstring s;\nint p;\n \nll A[200][300];\nint idx;\n \nll bnf();\n \nll get_num(){\n \n if(s[p]=='('){\n \n p++;\n \n ll res=bnf();\n \n p++;\n \n return res;\n }\n \n if('a'<=s[p]&&s[p]<='z') return A[idx][s[p++]];\n \n ll num=0;\n \n while('0'<=s[p]&&s[p]<='9') num=num*10+s[p]-'0', p++;\n \n return num;\n \n}\n \nll bnf3(){\n \n ll res=get_num();\n \n while(p<s.size()){\n \n if(s[p]=='^'){\n \n p++;\n \n ll r=get_num();\n \n ll tmp=1;\n \n for(int i=0;i<r;i++) tmp*=res;\n \n res=tmp;\n \n }else break;\n \n }\n \n return res;\n}\n \nll bnf2(){\n \n ll res=bnf3();\n \n while(p<s.size()){\n \n if(s[p]=='*'){\n \n p++;\n \n ll r=bnf3();\n \n res*=r;\n \n }else break;\n \n }\n \n return res;\n}\n \nll bnf(){\n \n ll res=bnf2();\n \n while(p<s.size()){\n \n if(s[p]=='+'){\n \n p++;\n \n ll r=bnf2();\n \n res+=r;\n \n }\n else if(s[p]=='-'){\n \n p++;\n \n ll r=bnf2();\n \n res-=r;\n \n }else break;\n \n }\n \n return res;\n}\n \nvoid change(){\n \n for(int i=0;i<s.size();i++)\n if((s[i]==')'||('a'<=s[i]&&s[i]<='z')||('0'<=s[i]&&s[i]<='9')))\n if((s[i+1]=='('||('a'<=s[i+1]&&s[i+1]<='z')||('0'<=s[i+1]&&s[i+1]<='9')))\n if(!('0'<=s[i]&&s[i]<='9'&&'0'<=s[i+1]&&s[i+1]<='9'))\n s=s.substr(0,i+1)+'*'+s.substr(i+1);\n \n \n for(int i=0;i<s.size();i++)\n \n if(s[i]==' ')\n \n while(s[i]==' '&&i+1<s.size()&&s[i+1]==' ') s.erase(s.begin()+i);\n \n \n if(s[0]==' ') s.erase(s.begin());\n \n if(s[s.size()-1]==' ') s.erase(s.begin()+s.size()-1);\n \n for(int i=0;i<s.size();i++)\n if(s[i]==' ')\n if((s[i-1]==')'||('a'<=s[i-1]&&s[i-1]<='z')||('0'<=s[i-1]&&s[i-1]<='9')))\n if((s[i+1]=='('||('a'<=s[i+1]&&s[i+1]<='z')||('0'<=s[i+1]&&s[i+1]<='9'))) s[i]='*';\n \n for(int i=0;i<s.size();i++)\n \n if(s[i]==' ') s.erase(s.begin()+i), i--;\n \n \n}\n \nint main(){\n \n for(int T=0;T<200;T++)\n \n for(int i=0;i<300;i++) A[T][i]=rand();\n \n while(1){\n \n string tmp=s;\n \n getline(cin,s);\n \n if(s==\".\") break;\n \n change();\n \n ll base[200];\n \n for(int T=0;T<200;T++){\n idx=T;\n p=0;\n base[T]=bnf();\n }\n \n while(1){\n \n getline(cin,s);\n \n if(s==\".\"){\n cout<<\".\"<<endl;\n break;\n }\n \n change();\n \n bool ans=true;\n \n for(int T=0;T<200;T++){\n \n idx=T; \n p=0;\n \n ll r=bnf();\n \n if(base[T]!=r) ans=false;\n \n }\n \n if(ans) cout<<\"yes\"<<endl;\n else cout<<\"no\"<<endl;\n \n }\n \n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3640, "score_of_the_acc": -0.1283, "final_rank": 11 }, { "submission_id": "aoj_1233_2548404", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\nusing namespace std;\ntypedef pair<string,int> P;\ntypedef map<string,int> M;\n\nM add(M a,M b){\n for(P p2:b) a[p2.first] += p2.second;\n return a;\n}\n\nM Minus(M a,M b){\n for(P p2:b) a[p2.first] -= p2.second;\n return a;\n}\n \nM mult(M a,M b){\n M res;\n for(P p1:a)\n for(P p2:b){\n string s = p1.first + p2.first; sort(s.begin(),s.end());\n int num = p1.second * p2.second;\n res[s] += num;\n }\n return res;\n}\n \nM bnf();\nint pos;\nstring S;\nvoid skipsp(){while(S[pos] == ' ') pos++;}\n \nint getNum(){\n int res = 0;\n while(isdigit(S[pos])) res = res * 10 + S[pos++]-'0';\n return res;\n}\n \nint getNum2(const string &S,int &pos){\n int res = 0;\n while(isdigit(S[pos])) res = res * 10 + S[pos++]-'0';\n return res;\n}\n\nstring getBlock(){\n string res;\n skipsp();\n while(isdigit(S[pos]) || isalpha(S[pos])) res += S[pos++];\n skipsp();\n if(S[pos] == '^') {\n pos++;\n skipsp();\n assert(isdigit(S[pos])&&\"hut\");\n int p = getNum();\n for(int i=0;i<p-1;i++) res += res.back();\n }\n return res;\n}\n \nM BtoM(string b){\n M res;\n int num = 1;\n string val;\n for(int i=0;i<(int)b.size();i++){\n char ch = b[i];\n if(isalpha(ch)) val += ch;\n else if(isdigit(ch)) num *= getNum2(b,i),i--;\n else assert(ch == ' ' && \"BtoM\");\n }\n res[val] = num;\n return res;\n}\n \nM calc(){\n M res; res[\"\"] = 1;\n while(1){\n skipsp();\n char ch = S[pos];\n if(ch == '(') pos++,res = mult(res,bnf()),pos++;\n else if(isalpha(ch) || isdigit(ch)){\n string block = getBlock();\n res = mult(res,BtoM(block));\n }\n else if(ch == '^') assert(!\"^\");\n else break;\n }\n return res;\n}\n \nM bnf(){\n M res = calc();\n while(1){\n skipsp();\n char ch = S[pos];\n if(isalpha(ch) || isdigit(ch)) res = mult(res,calc());\n else if(ch == '+')pos++,res = add(res,calc());\n else if(ch == '-')pos++,res = Minus(res,calc());\n else if(ch == '(') pos++,res = mult(res,bnf()),pos++;\n else if(ch == '^') assert(!\"^\");\n else break;\n }\n for(auto it=res.begin();it!=res.end();it++) if(it->second == 0) res.erase(it);\n return res;\n}\n \nsigned main(){\n while(1){\n getline(cin,S);\n if(S == \".\") break;\n pos = 0;\n M ori = bnf();\n while(1){\n getline(cin,S);\n if(S == \".\") break;\n pos = 0;\n M res = bnf();\n cout<<((ori == res)? \"yes\":\"no\")<<endl;\n }\n cout<<\".\"<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3444, "score_of_the_acc": -0.1124, "final_rank": 7 }, { "submission_id": "aoj_1233_2548386", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\nusing namespace std;\ntypedef pair<string,int> P;\ntypedef map<string,int> M;\n \nvoid pr(M a,string s=\"\"){\n return;\n cout<<s<<endl;\n for(P p:a) cout<<p.first<<\" \"<<p.second<<endl;\n cout<<\"end\"<<endl;\n}\n \nM add(M a,M b,int f=1){\n for(P p2:b) a[p2.first] += f * p2.second;\n return a;\n}\n \nM mult(M a,M b){\n M res;\n for(P p1:a)\n for(P p2:b){\n string s = p1.first + p2.first; sort(s.begin(),s.end());\n int num = p1.second * p2.second;\n res[s] += num;\n }\n return res;\n}\n \n \nM bnf();\nint pos;\nstring S;\nvoid skipsp(){while(S[pos] == ' ') pos++;}\n \nint getNum(){\n int res = 0;\n while((int)S.size()> pos && isdigit(S[pos])) res = res * 10 + S[pos++]-'0';\n return res;\n}\n \nint getNum2(const string &S,int &pos){\n int res = 0;\n while((int)S.size()>pos && isdigit(S[pos])) res = res * 10 + S[pos++]-'0';\n return res;\n}\n \nstring getBlock(){\n string res;\n skipsp();\n while(isdigit(S[pos]) || isalpha(S[pos])) res += S[pos++];\n skipsp();\n if(S[pos] == '^') {\n pos++;\n skipsp();\n assert(isdigit(S[pos])&&\"hut\");\n int p = getNum();\n for(int i=0;i<p-1;i++) res += res.back();\n }\n return res;\n}\n \nM BtoM(string b){\n M res;\n int num = 1;\n string val;\n for(int i=0;i<(int)b.size();i++){\n char ch = b[i];\n if(isalpha(ch)) val += ch;\n else if(isdigit(ch)) num *= getNum2(b,i),i--;\n else if(ch != ' ') assert(!\"BtoM\");\n }\n res[val] = num;\n return res;\n}\n \nM calc(){\n M res; res[\"\"] = 1;\n while(1){\n skipsp();\n char ch = S[pos];\n if(ch == '(') pos++,res = mult(res,bnf()),pos++;\n else if(isalpha(ch) || isdigit(ch)){\n string block = getBlock();\n res = mult(res,BtoM(block));\n }\n else if(ch == '^') assert(!\"^\");\n else break;\n }\n pr(res,\"calc,res\");\n return res;\n}\n \nM bnf(){\n M res = calc();\n pr(res,\"start bnf\");\n while(1){\n skipsp();\n char ch = S[pos];\n if(isalpha(ch) || isdigit(ch)) res = mult(res,calc());\n else if(ch == '+')pos++,res = add(res,calc());\n else if(ch == '-')pos++,res = add(res,calc(),-1);\n else if(ch == '(') pos++,res = mult(res,bnf()),pos++;\n else if(ch == '^') assert(!\"^\");\n else break;\n }\n \n for(auto it=res.begin();it!=res.end();it++) if(it->second==0) res.erase(it);\n pr(res,\"return bnf\");\n return res;\n}\n \nsigned main(){\n while(1){\n getline(cin,S);\n //cin.ignore();\n if(S == \".\") break;\n pos = 0;\n M ori = bnf();\n pr(ori,\"ori\");\n while(1){\n getline(cin,S);\n if(S == \".\") break;\n pos = 0;\n M res = bnf();\n cout<<((ori == res)? \"yes\":\"no\")<<endl;\n pr(res,S);\n }\n cout<<\".\"<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3428, "score_of_the_acc": -0.1135, "final_rank": 8 }, { "submission_id": "aoj_1233_2548314", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef unsigned long long ll;\n\nstring s;\nint p;\n\nll A[200][300];\nint idx;\n\nll bnf();\n\nll get_num(){\n\n if(s[p]=='('){\n \n p++;\n\n ll res=bnf();\n \n p++;\n\n return res;\n }\n \n if('a'<=s[p]&&s[p]<='z') return A[idx][s[p++]];\n \n ll num=0;\n \n while('0'<=s[p]&&s[p]<='9') num=num*10+s[p]-'0', p++;\n\n return num;\n \n}\n\nll bnf3(){\n\n ll res=get_num();\n \n while(p<s.size()){\n\n if(s[p]=='^'){\n\n p++;\n\n ll r=get_num();\n\n ll tmp=1;\n\n for(int i=0;i<r;i++) tmp*=res;\n\n res=tmp;\n \n }else break;\n \n }\n \n return res;\n}\n\nll bnf2(){\n\n ll res=bnf3();\n\n while(p<s.size()){\n\n if(s[p]=='*'){\n\n p++;\n\n ll r=bnf3();\n \n res*=r;\n \n }else break;\n \n }\n \n return res;\n}\n\nll bnf(){\n\n ll res=bnf2();\n \n while(p<s.size()){\n \n if(s[p]=='+'){\n\n p++;\n \n ll r=bnf2();\n \n res+=r;\n \n }\n else if(s[p]=='-'){\n\n p++;\n\n ll r=bnf2();\n\n res-=r;\n \n }else break;\n \n }\n \n return res;\n}\n\nvoid change(){\n \n for(int i=0;i<s.size();i++)\n if((s[i]==')'||('a'<=s[i]&&s[i]<='z')||('0'<=s[i]&&s[i]<='9')))\n if((s[i+1]=='('||('a'<=s[i+1]&&s[i+1]<='z')||('0'<=s[i+1]&&s[i+1]<='9')))\n\tif(!('0'<=s[i]&&s[i]<='9'&&'0'<=s[i+1]&&s[i+1]<='9'))\n\t s=s.substr(0,i+1)+'*'+s.substr(i+1);\n\n \n for(int i=0;i<s.size();i++)\n \n if(s[i]==' ')\n \n while(s[i]==' '&&i+1<s.size()&&s[i+1]==' ') s.erase(s.begin()+i);\n \n\n if(s[0]==' ') s.erase(s.begin());\n \n if(s[s.size()-1]==' ') s.erase(s.begin()+s.size()-1);\n\n for(int i=0;i<s.size();i++)\n if(s[i]==' ')\n if((s[i-1]==')'||('a'<=s[i-1]&&s[i-1]<='z')||('0'<=s[i-1]&&s[i-1]<='9')))\n\tif((s[i+1]=='('||('a'<=s[i+1]&&s[i+1]<='z')||('0'<=s[i+1]&&s[i+1]<='9'))) s[i]='*';\n\n for(int i=0;i<s.size();i++)\n \n if(s[i]==' ') s.erase(s.begin()+i), i--;\n \n \n}\n\nint main(){\n \n for(int T=0;T<200;T++)\n \n for(int i=0;i<300;i++) A[T][i]=rand();\n \n while(1){\n\n string tmp=s;\n \n getline(cin,s);\n \n if(s==\".\") break;\n \n change();\n \n ll base[200];\n\n for(int T=0;T<200;T++){\n idx=T;\n p=0;\n base[T]=bnf();\n }\n \n while(1){\n \n getline(cin,s);\n \n if(s==\".\"){\n\tcout<<\".\"<<endl;\n\tbreak;\n }\n \n change();\n \n bool ans=true;\n \n for(int T=0;T<200;T++){\n \n\tidx=T; \n\tp=0;\n \n\tll r=bnf();\n\t\n\tif(base[T]!=r) ans=false;\n\t\n }\n \n if(ans) cout<<\"yes\"<<endl;\n else cout<<\"no\"<<endl;\n \n }\n \n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3632, "score_of_the_acc": -0.1274, "final_rank": 10 }, { "submission_id": "aoj_1233_2469770", "code_snippet": "#include <bits/stdc++.h>\n \n#define _overload(_1,_2,_3,name,...) name\n#define _rep(i,n) _range(i,0,n)\n#define _range(i,a,b) for(int i=(int)(a);i<(int)(b);++i)\n#define rep(...) _overload(__VA_ARGS__,_range,_rep,)(__VA_ARGS__)\n \n#define _rrep(i,n) _rrange(i,n,0)\n#define _rrange(i,a,b) for(int i=(int)(a)-1;i>=(int)(b);--i)\n#define rrep(...) _overload(__VA_ARGS__,_rrange,_rrep,)(__VA_ARGS__)\n \n#define _all(arg) begin(arg),end(arg)\n#define uniq(arg) sort(_all(arg)),(arg).erase(unique(_all(arg)),end(arg))\n#define getidx(ary,key) lower_bound(_all(ary),key)-begin(ary)\n#define clr(a,b) memset((a),(b),sizeof(a))\n#define bit(n) (1LL<<(n))\n \n// #define DEBUG\n \n#ifdef DEBUG\n #define dump(...) fprintf(stderr, __VA_ARGS__)\n#else\n #define dump(...)\n#endif\n \ntemplate<class T>bool chmax(T &a, const T &b) { return (a<b)?(a=b,1):0;}\ntemplate<class T>bool chmin(T &a, const T &b) { return (b<a)?(a=b,1):0;}\n \nusing namespace std;\nusing ll=long long;\nusing vi=vector<int>;\nusing vll=vector<ll>;\n \nconst double EPS = 1e-10;\nconst double PI = acos(-1.0);\nconst ll inf =1LL << 62;\nconst ll mod=1000000007LL;\nconst int dx[4]={1,0,-1,0};\nconst int dy[4]={0,1,0,-1};\n \n \nll extgcd(ll a,ll b,ll& x,ll& y){x=1,y=0;ll g=a;if(b!=0) g=extgcd(b,a%b,y,x),y-=a/b*x;return g;}\nll ADD(const ll &a, const ll &b,const ll &mod) { return (a+b)%mod;}\nll SUB(const ll &a, const ll &b,const ll &mod) { return (a-b+mod)%mod;}\nll MUL(const ll &a, const ll &b,const ll &mod) { return (1LL*a*b)%mod;}\nll DIV(const ll &a, const ll &b,const ll &mod) {ll x,y; extgcd(b,mod,x,y);return MUL(a,(x+mod)%mod,mod);}\n \nrandom_device rd;\nmt19937 mt(rd());\nuniform_int_distribution<int> dice(1,6);\nuniform_real_distribution<double> score(0.0,10.0);\n\nstring f;\nint len;\nint p = 0;\n\nll exp();\nll term();\nll fact();\n\nll tbl['z' - 'a' + 1];\ninline ll c2n(char c){\n return tbl[c - 'a'];\n}\n\nchar next_c(){\n while(p < len and f[p] == ' ') p++;\n return f[p];\n}\n\nll exp(){\n ll ret = term();\n\n char c;\n while(c = next_c(), (c == '+' or c == '-')){\n p++;\n ll r = term();\n if(c == '+') ret = ADD(ret, r, mod);\n else ret = SUB(ret, r, mod);\n }\n\n return ret;\n}\n\nconst ll ERR = 2LL * mod;\n\nll term(){\n ll ret = fact();\n\n ll r;\n while((r = fact()) != ERR){\n ret = MUL(ret, r, mod);\n }\n\n return ret;\n}\n\ninline ll num(){\n ll ret = 0LL;\n next_c();\n while(isdigit(f[p])){\n ret = ret * 10 + (f[p] - '0');\n p++; // [0,9]\n }\n return ret % mod;\n} \n\nll fact(){\n ll ret = ERR;\n\n char c = next_c();\n if(c == '('){\n p++; // (\n ret = exp();\n assert(next_c() == ')'); p++;\n }\n else if(islower(c)){\n p++; // [a,z]\n ret = c2n(c);\n\n c = next_c();\n if(c == '^'){\n p++; // ^\n ll d = num();\n ll b = ret;\n rep(loop, d - 1){\n ret = MUL(ret, b, mod);\n }\n }\n }\n else if(isdigit(c)){\n ret = num();\n }\n else {\n // cerr << \"cur... \" << c << endl;\n }\n\n return ret;\n}\n\nint main(void){\n cin.tie(0);\n ios::sync_with_stdio(false);\n auto myrand = bind(uniform_int_distribution<int>(0, (int)1e6), mt19937(static_cast<unsigned int>(time(nullptr))));\n\n while(true){\n string mine;\n getline(cin, mine);\n if(mine == \".\") break;\n \n while(true){\n string opp;\n getline(cin, opp);\n if(opp == \".\") break;\n\n bool ok = true;\n rep(loop, 1000){\n rep(i, 'z' - 'a' + 1) tbl[i] = myrand();\n\n // cerr << \"-> \" << mine << endl;\n f = mine; p = 0; len = f.size(); ll a = exp();\n // cerr << \"-> \" << opp << endl;\n f = opp; p = 0; len = f.size(); ll b = exp();\n\n if(a != b){\n ok = false;\n break;\n }\n }\n\n if(ok){\n cout << \"yes\" << endl;\n }\n else {\n cout << \"no\" << endl;\n }\n }\n cout << \".\" << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3056, "score_of_the_acc": -0.0522, "final_rank": 1 } ]
aoj_1238_cpp
Problem G: True Liars After having drifted about in a small boat for a couple of days, Akira Crusoe Maeda was finally cast ashore on a foggy island. Though he was exhausted and despaired, he was still fortunate to remember a legend of the foggy island, which he had heard from patriarchs in his childhood. This must be the island in the legend. In the legend, two tribes have inhabited the island, one is divine and the other is devilish; once members of the divine tribe bless you, your future is bright and promising, and your soul will eventually go to Heaven; in contrast, once members of the devilish tribe curse you, your future is bleak and hopeless, and your soul will eventually fall down to Hell. In order to prevent the worst-case scenario, Akira should distinguish the devilish from the divine. But how? They looked exactly alike and he could not distinguish one from the other solely by their appearances. He still had his last hope, however. The members of the divine tribe are truth-tellers, that is, they always tell the truth and those of the devilish tribe are liars, that is, they always tell a lie. He asked some of the whether or not some are divine. They knew one another very much and always responded to him "faithfully" according to their individual natures (i.e., they always tell the truth or always a lie). He did not dare to ask any other forms of questions, since the legend says that a devilish member would curse a person forever when he did not like the question. He had another piece of useful information: the legend tells the populations of both tribes. These numbers in the legend are trustworthy since everyone living on this island is immortal and none have ever been born at least these millennia. You are a good computer programmer and so requested to help Akira by writing a program that classifies the inhabitants according to their answers to his inquiries. Input The input consists of multiple data sets, each in the following format: n p 1 p 2 x 1 y 1 a 1 x 2 y 2 a 2 ... x i y i a i ... x n y n a n The first line has three non-negative integers n , p 1 , and p 2 . n is the number of questions Akira asked. p 1 and p 2 are the populations of the divine and devilish tribes, respectively, in the legend. Each of the following n lines has two integers x i , y i and one word a i . x i and y i are the identification numbers of inhabitants, each of which is between 1 and p 1 + p 2 , inclusive. a i is either "yes", if the inhabitant x i said that the inhabitant y i was a member of the divine tribe, or "no", otherwise. Note that x i and y i can be the same number since "are you a member of the divine tribe?" is a valid question. Note also that two lines may have the same x 's and y 's since Akira was very upset and might have asked the same question to the same one more than once. You may assume that n is less than 1000 and that p 1 and p 2 are less than 300. A line with three zeros, i.e., "0 0 0", represents the end of the input. You can assume ...(truncated)
[ { "submission_id": "aoj_1238_5010193", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<cstring>\nusing namespace std;\n\nconst int N = 2010;\nint fa[N], siz[N], a[N], f[N][N], pre[N][N], ans[N], b[N], c[N]; \nbool vis[N], in[N];\nint findfa(int x) {\n\treturn fa[x] == x ? x : fa[x] = findfa(fa[x]);\n}\n\nvoid merge(int x, int y) {\n\tx = findfa(x); y = findfa(y);\n\tif (x == y) return ;\n\tfa[x] = y; siz[y] += siz[x];\n}\n\nint main() {\n\tint n, p1, p2, m;\n\twhile (~scanf(\"%d%d%d\", &n, &p1, &p2) && (n | p1 | p2)) {\n\t\tmemset(f, 0, sizeof(f));\n\t\tmemset(vis, 0, sizeof(vis));\n\t\tmemset(in, 0, sizeof(in));\n\t\tmemset(pre, 0, sizeof(pre));\n\t\tm = p1 + p2;\n\t\tfor (int i = 1; i <= m * 2; i++) fa[i] = i;\n\t\tfor (int i = 1; i <= m; i++) siz[i] = 1, siz[i + m] = 0;\n\t\tfor (int i = 1, x, y; i <= n; i++) {\n\t\t\tchar s[10];\n\t\t\tscanf(\"%d%d%s\", &x, &y, s);\n\t\t\tif (s[0] == 'y') merge(x, y), merge(x + m, y + m);\n\t\t\telse merge(x + m, y), merge(x, y + m);\n\t\t}\n\t\tint cnt = 0;\n\t\tfor (int i = 1; i <= m; i++) {\n\t\t\tint x = findfa(i), y = findfa(i + m);\n\t\t\tif (vis[x] || vis[y]) continue ;\n\t\t\ta[++cnt] = x; b[cnt] = y;\n\t\t\tvis[x] = vis[y] = 1;\n\t\t}\n//\t\tfor (int i = 1; i <= cnt; i++)\n//\t\t\tprintf(\"%d%c\", a[i], \" \\n\"[i == cnt]);\n//\t\tfor (int i = 1; i <= cnt; i++)\n//\t\t\tprintf(\"%d%c\", b[i], \" \\n\"[i == cnt]);\n\t\tf[0][0] = 1;\n\t\tfor (int i = 1; i <= cnt; i++)\n\t\t\tfor (int j = 0; j <= m; j++) \n\t\t\t\tif (f[i - 1][j]) {\n\t\t\t\t\tf[i][j + siz[a[i]]] += f[i - 1][j], pre[i][j + siz[a[i]]] = j;\n\t\t\t\t\tf[i][j + siz[b[i]]] += f[i - 1][j], pre[i][j + siz[b[i]]] = j;\n\t\t\t\t}\n\t\tif (p1 == p2) puts(\"no\");\n\t\telse {\n\t\t\tif (f[cnt][p1] == 1) {\n\t\t\t\tint k = 0, s = p1;\n\t\t\t\tfor (int i = cnt; i >= 1; i--)\n\t\t\t\t\tif (s - siz[a[i]] == pre[i][s]) in[a[i]] = 1, s -= siz[a[i]];\n\t\t\t\t\telse in[b[i]] = 1, s -= siz[b[i]];\n//\t\t\t\tfor (int i = 1; i <= m; i++)\n//\t\t\t\t\tprintf(\"%d%c\", findfa(i), \" \\n\"[i == m]);\n//\t\t\t\tfor (int i = 1; i <= m * 2; i++)\n//\t\t\t\t\tprintf(\"%d%c\", in[i], \" \\n\"[i == m * 2]);\n\t\t\t\tfor (int i = 1; i <= m; i++)\n\t\t\t\t\tif (in[findfa(i)]) ans[++k] = i;\n\t\t\t\tfor (int i = 1; i <= k; i++)\n\t\t\t\t\tprintf(\"%d\\n\", ans[i]);\n\t\t\t\tputs(\"end\");\n\t\t\t}\n\t\t\telse puts(\"no\");\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 34724, "score_of_the_acc": -0.3854, "final_rank": 9 }, { "submission_id": "aoj_1238_4591393", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define _GLIBCXX_DEBUG\n\nvector<int> P; // parent\nvector<int> divine; // 0:not_checked, 1:true, -1:lie\nmap<int, vector<int>> groups; // <根、葉>\nint m;\n\n// 未完成\n\nvoid init() {\n groups.clear();\n P = vector<int>(m + 1);\n divine = vector<int>(m + 1);\n for (int i = 1; i <= m; i++) {\n P[i] = i;\n groups[i].push_back(i);\n }\n}\nint root(int c) {\n if (P[c] == c)\n return c;\n return (P[c] = root(P[c]));\n}\nbool is_same_set(int a, int b) { return root(a) == root(b); }\n// 子のgroupに入っている要素を親のgroupに移し替える。\nvoid unite(int c, int p) {\n groups[root(p)].insert(groups[root(p)].end(), groups[root(c)].begin(),\n groups[root(c)].end());\n groups.erase(root(c));\n P[root(c)] = root(p);\n}\n// 結合して子になるグループのdivineをすべて裏返してから結合\nvoid r_unite(int c, int p) {\n for (int i : groups[root(c)]) {\n divine[i] *= -1;\n }\n unite(c, p);\n}\n\nint main() {\n int n, t, l;\n while (cin >> n >> t >> l) {\n if (!n && !t && !l)\n break;\n\n m = t + l;\n init();\n /* cout << m << endl; */\n // グループ分け\n for (int i = 0; i < n; i++) {\n int x, y;\n string a;\n cin >> x >> y >> a;\n int honest = (a == \"yes\") ? 1 : -1;\n if (x == y || is_same_set(x, y))\n continue;\n int reverse;\n if (divine[x]) {\n reverse = divine[x] * honest;\n } else {\n reverse = honest;\n divine[x] = 1;\n }\n assert(reverse != 0);\n if (divine[y] && reverse != divine[y])\n r_unite(y, x);\n else {\n unite(y, x);\n divine[y] = reverse;\n }\n assert(divine[y] != 0);\n }\n // test------------\n /* for (int i : groups[1]) { */\n /* cout << i << ' ' << divine[i] << endl; */\n /* } */\n //----------------\n map<int, pair<int, int>> pair_t_l; //<root of group, <truth_teller, liar>>\n for (auto group = groups.begin(); group != groups.end(); ++group) {\n int t_teller = 0, liar = 0;\n for (int i : group->second) {\n if (divine[i] == 1)\n t_teller++;\n // 言及されていない人は嘘つきとみなす。\n else { // bug:{}をつけないと行を加えたときにつけ忘れる。\n divine[i] = -1;\n liar++;\n }\n }\n /* cout << t_teller << ' ' << liar << endl; */\n pair_t_l[group->first] = make_pair(t_teller, liar);\n }\n\n int num_g = groups.size();\n vector<vector<int>> dp(\n num_g + 1,\n vector<int>(\n t + 1, 0)); // dp[i][j]:i個のグループでj人の正直者を何通りつくれるか\n vector<vector<set<int>>> p_rev(\n num_g + 1, vector<set<int>>(t + 1)); //裏返るグループを保存する配列\n int gc = 0;\n // 動的計画法\n for (auto P = pair_t_l.begin(); P != pair_t_l.end(); ++P) {\n gc++;\n pair<int, int> p = P->second; //<truth_teller, liar>\n /* // もし正直者と嘘つきの数が同じなら答えはnoなので抜ける */\n /* if (p.first == p.second) { */\n /* dp[num_g][t] = 10; */\n /* break; */\n /* } */\n if (gc == 1) {\n dp[gc][p.first]++;\n dp[gc][p.second]++;\n /* cout << p.second << endl; */\n if (p.second <= t)\n p_rev.at(gc).at(p.second).insert(P->first);\n }\n for (int j = 0; j <= t; j++) { // bug:jを1から始めるとt=0のとき間違う\n /* cout << gc << ' ' << j << ' ' << p.first << ' ' << p.second << ' ' */\n /* << dp[gc - 1][j] << endl; */\n if (p.first + j <= t) {\n dp[gc][p.first + j] += dp[gc - 1][j];\n if (dp[gc - 1][j]) {\n for (auto group : p_rev[gc - 1][j]) {\n p_rev[gc][p.first + j].insert(group);\n }\n }\n }\n if (p.second + j <= t) {\n dp[gc][p.second + j] += dp[gc - 1][j];\n /* assert(!(gc==2&&p.second+j==4)); */\n if (dp[gc - 1][j]) {\n for (auto group : p_rev[gc - 1][j]) {\n p_rev[gc][p.second + j].insert(group);\n }\n p_rev[gc][p.second + j].insert(P->first);\n }\n /* cout<<gc<<' '<<p.second+j<<' '<<dp[gc][p.second + j]<<endl; */\n }\n }\n }\n\n /* for (int i : divine) */\n /* cout << i << endl; */\n vector<int> ans;\n for (int group : p_rev[num_g][t]) {\n /* cout<<1<<endl; */\n /* assert(groups.count(1)==0); */\n for (int person : groups[group]) {\n divine[person] *= -1;\n }\n }\n for (auto group = groups.begin(); group != groups.end(); ++group) {\n /* cout << group->first << ' '; */\n for (int person : group->second) {\n /* cout << person << ' '; */\n if (divine[person] == 1)\n ans.push_back(person);\n }\n /* cout << endl; */\n }\n sort(ans.begin(), ans.end());\n /* cout << groups.size() << endl; */\n /* cout << root(24) << endl; */\n\n if (dp[num_g][t] != 1) {\n cout << \"no\" << endl;\n } else {\n for (int i : ans)\n cout << i << endl;\n cout << \"end\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 14724, "score_of_the_acc": -0.1487, "final_rank": 7 }, { "submission_id": "aoj_1238_2803088", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define int short\n\nusing vint = vector<int>;\n\nstruct edge {\n\tint to, kind;\n\tedge(){}\n\tedge(int to, int kind):to(to), kind(kind){}\n};\n\nusing Graph = vector<vector<edge> >;\n\nstruct UF {\n\tvint data;\n\tUF(){}\n\tvoid init(int n) {\n\t\tdata.clear();\n\t\tdata.resize(n, -1);\n\t}\n\tint find(int x) {\n\t\treturn data[x] < 0 ? x : data[x] = find(data[x]);\t \n\t}\n\tint size(int x) {\n\t\treturn -data[find(x)];\n\t}\n\tbool same(int x, int y) {\n\t\treturn find(x) == find(y);\n\t}\n\tvoid unite(int x, int y) {\n\t\tx = find(x), y = find(y);\n\t\tif(x == y) return;\n\t\tif(data[x] > data[y]) swap(x, y);\n\t\tdata[x] += data[y];\n\t\tdata[y] = x;\n\t}\n};\n\nint Q, A, B, N;\nGraph graph;\nGraph rgraph;\nUF uf;\n\nvint col[2];\nvint divines[2];\n\nvoid fillcolor(int s, int c) {\n\tqueue<int> que;\n\tque.push(s);\n\tcol[c][s] = c;\n\tif(!c) ++divines[c][s];\n\twhile(!que.empty()) {\n\t\tint u = que.front(); que.pop();\n\t\tfor(edge e : graph[u]) {\n\t\t\tif(col[c][e.to] == -1) {\n\t\t\t\tque.push(e.to);\n\t\t\t\tcol[c][e.to] = col[c][u]^e.kind;\n\t\t\t\tif(!col[c][e.to]) ++divines[c][s];\n\t\t\t} else if(col[c][e.to] != (col[c][u]^e.kind)) {\n\t\t\t\tdivines[c][s] = -1;\t\t\t\t\n\t\t\t\treturn;\n\t\t\t}\n\t\t}\n\t\tfor(edge e : rgraph[u]) {\n\t\t\tif(col[c][e.to] == -1) {\n\t\t\t\tque.push(e.to);\n\t\t\t\tcol[c][e.to] = col[c][u]^e.kind;\n\t\t\t\tif(!col[c][e.to]) ++divines[c][s];\t\t\t\t\n\t\t\t} else if(col[c][e.to] != (col[c][u]^e.kind)) {\n\t\t\t\tdivines[c][s] = -1;\n\t\t\t\treturn;\n\t\t\t}\n\t\t}\n\t}\n\t//cout << s << \" \" << c << \" \" << divines[c][s] << endl;\n}\n\nvoid init() {\n\tgraph.clear();\n\tgraph.resize(N);\n\trgraph.clear();\n\trgraph.resize(N);\n\tcol[0].clear();\n\tcol[0].resize(N, -1);\n\tcol[1].clear();\n\tcol[1].resize(N, -1);\n\tdivines[0].clear();\n\tdivines[0].resize(N);\n\tdivines[1].clear();\n\tdivines[1].resize(N);\n\tuf.init(N);\n}\n\nusing Pi = pair<int, int>;\n\n//int dp[303][303][303];\nPi rev[303][303][303];\n\nsigned main() {\n\twhile(cin >> Q >> A >> B, Q || A || B) {\n\t\tN = A + B;\t\t\n\t\tinit();\n\t\tfor(int i = 0; i < Q; ++i) {\n\t\t\tint a, b;\n\t\t\tstring s;\n\t\t\tcin >> a >> b >> s;\n\t\t\t--a, --b;\n\t\t\tgraph[a].emplace_back(b, s == \"no\");\n\t\t\trgraph[b].emplace_back(a, s == \"no\");\n\t\t\tuf.unite(a, b);\n\t\t}\n\t\t//map<int, int> mp;\n\t\tvint mp(N);\n\t\tint sz = 0;\n\t\tfor(int i = 0; i < N; ++i) {\n\t\t\tif(uf.find(i) != i) continue;\n\t\t\tmp[sz++] = i;\n\t\t\tfor(int j = 0; j < 2; ++j) {\n\t\t\t\tfillcolor(i, j);\n\t\t\t}\n\t\t}\n\t\tfor(int i = 0; i < 303; ++i) {\n\t\t\tfor(int j = 0; j < 303; ++j) {\n\t\t\t\tfor(int k = 0; k < 303; ++k) {\n\t\t\t\t\t//dp[i][j][k] = 0;\n\t\t\t\t\trev[i][j][k] = Pi(-2, -2);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//dp[0][0][0] = 1;\n\t\trev[0][0][0] = Pi(-1, -1);\n\t\tfor(int i = 0; i < sz; ++i) {\n\t\t\tfor(int j = 0; j <= A; ++j) {\n\t\t\t\tfor(int k = 0; k <= B; ++k) {\n\t\t\t\t\t//if(!dp[i][j][k]) continue;\n\t\t\t\t\tif(rev[i][j][k].first == -2) continue;\t\t\t\t\t\n\t\t\t\t\tfor(int l = 0; l < 2; ++l) {\n\t\t\t\t\t\tif(divines[l][mp[i]] == -1) continue;\n\t\t\t\t\t\tint x = divines[l][mp[i]];\n\t\t\t\t\t\tint y = uf.size(mp[i])-x;\n\t\t\t\t\t\tif(j+x > A || k+y > B) continue;\n\t\t\t\t\t\t//if(!dp[i+1][j+x][k+y]) {\n\t\t\t\t\t\tif(rev[i+1][j+x][k+y].first == -2) {\n\t\t\t\t\t\t\t//dp[i+1][j+x][k+y] = 1;\n\t\t\t\t\t\t\trev[i+1][j+x][k+y] = Pi(mp[i], l);\n\t\t\t\t\t\t} else {\n\t\t\t\t\t\t\t//dp[i+1][j+x][k+y] = 2;\n\t\t\t\t\t\t\trev[i+1][j+x][k+y] = Pi(-1, -1);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//if(dp[sz][A][B] != 1) {\n\t\tif(rev[sz][A][B].first < 0) {\t\t\n\t\t\tcout << \"no\" << endl;\n\t\t\tcontinue;\n\t\t} else {\n\t\t\tvint ans;\n\t\t\tint a = A, b = B;\n\t\t\tfor(int i = sz; i > 0; --i) {\n\t\t\t\tPi p = rev[i][a][b];\n\t\t\t\tfor(int j = 0; j < N; ++j) {\n\t\t\t\t\tif(uf.find(j) != p.first) continue;\n\t\t\t\t\tif(!col[p.second][j]) ans.push_back(j);\n\t\t\t\t}\n\t\t\t\ta -= divines[p.second][p.first];\n\t\t\t\tb -= (uf.size(p.first)-divines[p.second][p.first]);\n\t\t\t}\n\t\t\tsort(ans.begin(), ans.end());\n\t\t\tfor(int id : ans) cout << id+1 << endl;\n\t\t\tcout << \"end\" << endl;\n\t\t}\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 111736, "score_of_the_acc": -1.9997, "final_rank": 12 }, { "submission_id": "aoj_1238_2802955", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define int short\n\nusing vint = vector<int>;\n\nstruct edge {\n\tint to, kind;\n\tedge(){}\n\tedge(int to, int kind):to(to), kind(kind){}\n};\n\nusing Graph = vector<vector<edge> >;\n\nstruct UF {\n\tvint data;\n\tUF(){}\n\tvoid init(int n) {\n\t\tdata.clear();\n\t\tdata.resize(n, -1);\n\t}\n\tint find(int x) {\n\t\treturn data[x] < 0 ? x : data[x] = find(data[x]);\t \n\t}\n\tint size(int x) {\n\t\treturn -data[find(x)];\n\t}\n\tbool same(int x, int y) {\n\t\treturn find(x) == find(y);\n\t}\n\tvoid unite(int x, int y) {\n\t\tx = find(x), y = find(y);\n\t\tif(x == y) return;\n\t\tif(data[x] > data[y]) swap(x, y);\n\t\tdata[x] += data[y];\n\t\tdata[y] = x;\n\t}\n};\n\nint Q, A, B, N;\nGraph graph;\nGraph rgraph;\nUF uf;\n\nvint col[2];\nvint divines[2];\n\nvoid fillcolor(int s, int c) {\n\tqueue<int> que;\n\tque.push(s);\n\tcol[c][s] = c;\n\tif(!c) ++divines[c][s];\n\twhile(!que.empty()) {\n\t\tint u = que.front(); que.pop();\n\t\tfor(edge e : graph[u]) {\n\t\t\tif(col[c][e.to] == -1) {\n\t\t\t\tque.push(e.to);\n\t\t\t\tcol[c][e.to] = col[c][u]^e.kind;\n\t\t\t\tif(!col[c][e.to]) ++divines[c][s];\n\t\t\t} else if(col[c][e.to] != (col[c][u]^e.kind)) {\n\t\t\t\tdivines[c][s] = -1;\t\t\t\t\n\t\t\t\treturn;\n\t\t\t}\n\t\t}\n\t\tfor(edge e : rgraph[u]) {\n\t\t\tif(col[c][e.to] == -1) {\n\t\t\t\tque.push(e.to);\n\t\t\t\tcol[c][e.to] = col[c][u]^e.kind;\n\t\t\t\tif(!col[c][e.to]) ++divines[c][s];\t\t\t\t\n\t\t\t} else if(col[c][e.to] != (col[c][u]^e.kind)) {\n\t\t\t\tdivines[c][s] = -1;\n\t\t\t\treturn;\n\t\t\t}\n\t\t}\n\t}\n\t//cout << s << \" \" << c << \" \" << divines[c][s] << endl;\n}\n\nvoid init() {\n\tgraph.clear();\n\tgraph.resize(N);\n\trgraph.clear();\n\trgraph.resize(N);\n\tcol[0].clear();\n\tcol[0].resize(N, -1);\n\tcol[1].clear();\n\tcol[1].resize(N, -1);\n\tdivines[0].clear();\n\tdivines[0].resize(N);\n\tdivines[1].clear();\n\tdivines[1].resize(N);\n\tuf.init(N);\n}\n\nusing Pi = pair<int, int>;\n\n//int dp[303][303][303];\nPi rev[303][303][303];\n\nsigned main() {\n\twhile(cin >> Q >> A >> B, Q || A || B) {\n\t\tN = A + B;\t\t\n\t\tinit();\n\t\tfor(int i = 0; i < Q; ++i) {\n\t\t\tint a, b;\n\t\t\tstring s;\n\t\t\tcin >> a >> b >> s;\n\t\t\t--a, --b;\n\t\t\tgraph[a].emplace_back(b, s == \"no\");\n\t\t\trgraph[b].emplace_back(a, s == \"no\");\n\t\t\tuf.unite(a, b);\n\t\t}\n\t\t//map<int, int> mp;\n\t\tvint mp(N);\n\t\tint sz = 0;\n\t\tfor(int i = 0; i < N; ++i) {\n\t\t\tif(uf.find(i) != i) continue;\n\t\t\tmp[sz++] = i;\n\t\t\tfor(int j = 0; j < 2; ++j) {\n\t\t\t\tfillcolor(i, j);\n\t\t\t}\n\t\t}\n\t\tfor(int i = 0; i < 303; ++i) {\n\t\t\tfor(int j = 0; j < 303; ++j) {\n\t\t\t\tfor(int k = 0; k < 303; ++k) {\n\t\t\t\t\t//dp[i][j][k] = 0;\n\t\t\t\t\trev[i][j][k] = Pi(-2, -2);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//dp[0][0][0] = 1;\n\t\trev[0][0][0] = Pi(-1, -1);\n\t\tfor(int i = 0; i < sz; ++i) {\n\t\t\tfor(int j = 0; j <= A; ++j) {\n\t\t\t\tfor(int k = 0; k <= B; ++k) {\n\t\t\t\t\t//if(!dp[i][j][k]) continue;\n\t\t\t\t\tif(rev[i][j][k].first == -2) continue;\t\t\t\t\t\n\t\t\t\t\tfor(int l = 0; l < 2; ++l) {\n\t\t\t\t\t\tif(divines[l][mp[i]] == -1) continue;\n\t\t\t\t\t\tint x = divines[l][mp[i]];\n\t\t\t\t\t\tint y = uf.size(mp[i])-x;\n\t\t\t\t\t\tif(j+x > A || k+y > B) continue;\n\t\t\t\t\t\t//if(!dp[i+1][j+x][k+y]) {\n\t\t\t\t\t\tif(rev[i+1][j+x][k+y].first == -2) {\n\t\t\t\t\t\t\t//dp[i+1][j+x][k+y] = 1;\n\t\t\t\t\t\t\trev[i+1][j+x][k+y] = Pi(mp[i], l);\n\t\t\t\t\t\t} else {\n\t\t\t\t\t\t\t//dp[i+1][j+x][k+y] = 2;\n\t\t\t\t\t\t\trev[i+1][j+x][k+y] = Pi(-1, -1);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//if(dp[sz][A][B] != 1) {\n\t\tif(rev[sz][A][B].first < 0) {\t\t\n\t\t\tcout << \"no\" << endl;\n\t\t\tcontinue;\n\t\t} else {\n\t\t\tvint ans;\n\t\t\tint a = A, b = B;\n\t\t\tfor(int i = sz; i > 0; --i) {\n\t\t\t\tPi p = rev[i][a][b];\n\t\t\t\tfor(int j = 0; j < N; ++j) {\n\t\t\t\t\tif(uf.find(j) != p.first) continue;\n\t\t\t\t\tif(!col[p.second][j]) ans.push_back(j);\n\t\t\t\t}\n\t\t\t\ta -= divines[p.second][p.first];\n\t\t\t\tb -= (uf.size(p.first)-divines[p.second][p.first]);\n\t\t\t}\n\t\t\tsort(ans.begin(), ans.end());\n\t\t\tfor(int id : ans) cout << id+1 << endl;\n\t\t\tcout << \"end\" << endl;\n\t\t}\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 111768, "score_of_the_acc": -1.9722, "final_rank": 11 }, { "submission_id": "aoj_1238_2660712", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define FOR(i,a,b) for (int i=(a);i<(b);i++)\n#define RFOR(i,a,b) for (int i=(b)-1;i>=(a);i--)\n#define REP(i,n) for (int i=0;i<(n);i++)\n#define RREP(i,n) for (int i=(n)-1;i>=0;i--)\ntypedef long long LL;\n//??°????????¨\n#define MAX_N 800\ntypedef pair<int,int>P;\nvector<P>G[MAX_N];\n\nbool used[MAX_N];\nvector<int> color[2][MAX_N+1];\n\nvoid init(){\n\tREP(i,MAX_N){\n\t\tG[i].clear();\n\t\tused[i]=false;\n\t\tcolor[0][i].clear();\n\t\tcolor[1][i].clear();\n\t}\n}\n\nvoid biparate(int v,int num,int c){\n\tif(used[v]==true)return;\n\tused[v]=true;\n\tcolor[c][num].push_back(v);\n\tREP(i,G[v].size()){\n\t\tbiparate(G[v][i].first,num,(c+G[v][i].second)%2);\n\t}\n}\n\n#define NONE 0\n#define UNI 1\n#define MUL 2\n\nint main(){\n\tint n,p1,p2;\n\twhile(cin>>n>>p1>>p2,n+p1+p2){\n\t\tinit();\n\t\tREP(i,n){\n\t\t\tint x,y;\n\t\t\tstring s;\n\t\t\tcin>>x>>y>>s;\n\t\t\tx--;y--;\n\t\t\tint z=0;\n\t\t\tif(s==\"no\")z=1;//no????????¢\n\t\t\tG[x].push_back(P(y,z));\n\t\t\tG[y].push_back(P(x,z));\n\t\t}\n\t\t//?????¨??°??????\n\t\t{\n\t\t\tint num=0;\n\t\t\tREP(i,p1+p2){\n\t\t\t\tif(used[i]==false){\n\t\t\t\t\tbiparate(i,num,0);\n\t\t\t\t\tnum++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//??????????????????\n\t\tvector<int>np[MAX_N+2];\n\t\t//vector<vector<int>>back(MAX_N);\n\t\tREP(i,MAX_N+1){\n\t\t\tnp[0].push_back(NONE);\n\t\t}\n\t\tnp[0][0]=UNI;\n\t\tREP(i,MAX_N){\n\t\t\tif((color[0][i].size()==0)&&(color[1][i].size()==0)){\n\t\t\t\tnp[i+1]=np[i];\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tREP(j,MAX_N+1){\n\t\t\t\tnp[i+1].push_back(NONE);\n\t\t\t}\n\t\t\tREP(j,MAX_N){\n\t\t\t\t//0?????\\??????\n\t\t\t\tif(np[i][j]==UNI){\n\t\t\t\t\tif(np[i+1][j+color[0][i].size()]==NONE){\n\t\t\t\t\t\tnp[i+1][j+color[0][i].size()]=UNI;\n\t\t\t\t\t}else{\n\t\t\t\t\t\t//if(color[0][i].size()!=0)\n\t\t\t\t\t\tnp[i+1][j+color[0][i].size()]=MUL;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(np[i][j]==MUL){\n\t\t\t\t\tnp[i+1][j+color[0][i].size()]=MUL;\n\t\t\t\t}\n\t\t\t\t//1?????\\??????\n\t\t\t\tif(np[i][j]==UNI){\n\t\t\t\t\tif(np[i+1][j+color[1][i].size()]==NONE){\n\t\t\t\t\t\tnp[i+1][j+color[1][i].size()]=UNI;\n\t\t\t\t\t}else{\n\t\t\t\t\t\t//if(color[1][i].size()!=0)\n\t\t\t\t\t\tnp[i+1][j+color[1][i].size()]=MUL;\n\t\t\t\t\t}\n\t\t\t\t\t\n\t\t\t\t}\n\t\t\t\tif(np[i][j]==MUL){\n\t\t\t\t\tnp[i+1][j+color[1][i].size()]=MUL;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\n\t\t\n\t\tif(np[MAX_N][p1]==UNI){\n\t\t\tvector<int>ans;\n\t\t\tint now=p1;\n\t\t\tfor(int i=MAX_N;i>=0;i--){\n\t\t\t\tif((color[0][i].size()==0)&&(color[1][i].size()==0))continue;\n\t\t\t\t//cout<<now<<endl;\n\t\t\t\tif(np[i][now-color[0][i].size()]==1){\n\t\t\t\t\tREP(j,color[0][i].size()){\n\t\t\t\t\t\tans.push_back(color[0][i][j]);\n\t\t\t\t\t}\n\t\t\t\t\tnow-=color[0][i].size();\n\t\t\t\t}else{\n\t\t\t\t\tREP(j,color[1][i].size()){\n\t\t\t\t\t\tans.push_back(color[1][i][j]);\n\t\t\t\t\t}\n\t\t\t\t\tnow-=color[1][i].size();\n\t\t\t\t}\n\t\t\t\t\n\t\t\t}\n\t\t\tsort(ans.begin(),ans.end());\n\t\t\tREP(i,ans.size()){\n\t\t\t\tcout<<ans[i]+1<<endl;\n\t\t\t}\n\t\t\tcout<<\"end\"<<endl;\n\t\t}else if(np[MAX_N][p2]==UNI){\n\t\t vector<int>ans;\n\t\t\tint now=p2;\n\t\t\tfor(int i=MAX_N;i>=0;i--){\n\t\t\t\tif((color[0][i].size()==0)&&(color[1][i].size()==0))continue;\n\t\t\t\t//cout<<now<<endl;\n\t\t\t\tif(np[i][now-color[0][i].size()]==1){\n\t\t\t\t\tREP(j,color[1][i].size()){\n\t\t\t\t\t\tans.push_back(color[1][i][j]);\n\t\t\t\t\t}\n\t\t\t\t\tnow-=color[0][i].size();\n\t\t\t\t}else{\n\t\t\t\t\tREP(j,color[0][i].size()){\n\t\t\t\t\t\tans.push_back(color[0][i][j]);\n\t\t\t\t\t}\n\t\t\t\t\tnow-=color[1][i].size();\n\t\t\t\t}\n\t\t\t\t\n\t\t\t}\n\t\t\tsort(ans.begin(),ans.end());\n\t\t\tREP(i,ans.size()){\n\t\t\t\tcout<<ans[i]+1<<endl;\n\t\t\t}\n\t\t\t\n\t\t\tcout<<\"end\"<<endl;\n\t\t}else{\n\t\t\tcout<<\"no\"<<endl;\n\t\t}\n\t\t\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5676, "score_of_the_acc": -0.039, "final_rank": 3 }, { "submission_id": "aoj_1238_2628577", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing pii = pair<int, int>;\n\nstruct edge {\n int to;\n bool yes;\n};\n\nusing edges = vector<edge>;\nusing graph = vector<edges>;\n\n// (divine, devilish)\npii dfs(graph const& g, int v, bool divine, vector<bool>& checked) {\n auto res = make_pair((int)divine, (int)!divine);\n checked[v] = true;\n for(auto& e : g[v]) {\n if(checked[e.to]) {\n continue;\n }\n bool next_state = (divine && e.yes || !divine && !e.yes);\n auto t = dfs(g, e.to, next_state, checked);\n res.first += t.first;\n res.second += t.second;\n }\n return res;\n}\n\nvoid determine(graph const& g, int v, bool divine, vector<int>& res) {\n res[v] = divine;\n for(auto& e : g[v]) {\n if(res[e.to] != -1) {\n continue;\n }\n bool next_state = (divine && e.yes || !divine && !e.yes);\n determine(g, e.to, next_state, res);\n }\n}\n\nstruct data {\n int person_id;\n bool divine;\n pii each_num; // (divine, devilish)\n data() : person_id(-1), divine(false), each_num(make_pair(0, 0))\n {}\n};\n\nint main() {\n int n, p1, p2;\n while(cin >> n >> p1 >> p2, n || p1 || p2) {\n graph g(p1 + p2);\n if(n == 0) {\n if(p2 == 0) {\n for(int i = 1; i <= p1 + p2; ++i) {\n cout << i << endl;\n }\n } else if(p1 != 0) {\n cout << \"no\" << endl;\n continue;\n }\n cout << \"end\" << endl;\n continue;\n }\n for(int i = 0; i < n; ++i) {\n int x, y;\n string a;\n cin >> x >> y >> a;\n g[x - 1].push_back(edge{y - 1, a == \"yes\"});\n g[y - 1].push_back(edge{x - 1, a == \"yes\"});\n }\n vector<vector<vector<data>>> dp(1, vector<vector<data>>(p1 + 1, vector<data>(p2 + 1)));\n dp[0][0][0].person_id = 0;\n vector<bool> checked(p1 + p2);\n for(int i = 0; i < p1 + p2; ++i) {\n auto now = dp.back();\n vector<vector<data>> nxt(p1 + 1, vector<data>(p2 + 1));\n if(!checked[i]) {\n for(int b = 0; b <= 1; ++b) {\n data d;\n d.person_id = i;\n d.divine = b;\n auto checked2 = checked;\n d.each_num = dfs(g, i, b, checked);\n if(b == 0) {\n checked = checked2; // restore\n }\n for(int j = 0; j <= p1; ++j) {\n for(int k = 0; k <= p2; ++k) {\n if(now[j][k].person_id == -1) {\n continue;\n }\n int nj = j + d.each_num.first, nk = k + d.each_num.second;\n if(nj > p1 || nk > p2 || nxt[nj][nk].person_id == -2) {\n continue;\n }\n if(nxt[nj][nk].person_id >= 0 || now[j][k].person_id == -2) { // ambiguous\n nxt[nj][nk].person_id = -2;\n continue;\n }\n nxt[nj][nk] = d;\n }\n }\n }\n dp.push_back(move(nxt));\n }\n }\n auto now = dp.back()[p1][p2];\n if(now.person_id < 0) {\n cout << \"no\" << endl;\n } else {\n vector<int> res(p1 + p2, -1);\n int P1 = p1, P2 = p2;\n for(int i = dp.size() - 1; i > 0; --i) {\n auto d = dp[i][P1][P2];\n determine(g, d.person_id, d.divine, res);\n P1 -= d.each_num.first;\n P2 -= d.each_num.second;\n }\n for(int i = 0; i < p1 + p2; ++i) {\n if(res[i] == 1) {\n cout << i + 1 << endl;\n }\n }\n cout << \"end\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 22876, "score_of_the_acc": -0.5837, "final_rank": 10 }, { "submission_id": "aoj_1238_1822961", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\ntemplate<class T>\nusing Table = vector<vector<T>>;\nconst ld eps=1e-9;\n\n//// < \"D:\\D_Download\\Visual Studio 2015\\Projects\\programing_contest_c++\\Debug\\a.txt\"\n\n\nstruct edge {\n int from;\n int to;\n bool same;\n edge(int f, int t, bool s):from(f), to(t), same(s) {\n\n }\n /*bool operator ==(edge &e) {\n return from == e.from&&to == e.to&&same == e.same;\n }*/\n};\n\nvector<int>types;\nvector<vector<edge>>edges;\npair<vector<int>, vector<int>>dfs(const int now,const bool div) {\n types[now] = div;\n pair<vector<int>, vector<int>>apair;\n if (div)apair.first.push_back(now);\n else apair.second.push_back(now);\n for (auto e : edges[now]) {\n if (types[e.to] == -1) {\n const bool tdiv = e.same ? div : !div;\n auto p(dfs(e.to, tdiv));\n apair.first.insert(apair.first.end(), p.first.begin(), p.first.end());\n apair.second.insert(apair.second.end(), p.second.begin(), p.second.end());\n }\n }\n return apair;\n}\nstruct d{\n int num;\n vector<bool>his;\n d() :num(0), his() {\n\n }\n};\nint main() {\n while (1) {\n edges.clear();\n types.clear();\n int N, P, Q; cin >> N >> P >> Q;\n if (!N&&!P&&!Q)break;\n edges.resize(P+Q);\n types.resize(P + Q);\n fill(types.begin(), types.end(), -1);\n vector<vector<int>>gyou(P + Q, vector<int>(P + Q, -1));\n for (int i = 0; i < N; ++i) {\n int x, y; string a; cin >> x >> y >> a;\n x--; y--;\n if (x == y)continue;\n bool same = a == \"yes\";\n gyou[x][y] = same;\n gyou[y][x] = same;\n\n }\n for (int i = 0; i < P + Q; ++i) {\n for (int j = 0; j < P + Q; ++j) {\n if (gyou[i][j] != -1) {\n edges[i].push_back(edge(i, j, gyou[i][j]));\n }\n }\n }\n vector<pair<vector<int>, vector<int>>>ps;\n for (int i = 0; i < P + Q; ++i) {\n if (types[i] == -1) {\n auto p = dfs(i, true);\n ps.push_back(p);\n }\n }\n //dp[???][?\\???°]\n vector<vector<d>>dp(ps.size() + 1, vector<d>(P + Q +1));\n dp[0][0].num = 1;\n for (int t = 0; t < ps.size(); ++t) {\n for (int dnum = 0; dnum <= P + Q; ++dnum) {\n if (dp[t][dnum].num) {\n for (int i = 0; i < 2; ++i) {\n const int nextdnum = (!i)?dnum + ps[t].first.size():dnum+ps[t].second.size();\n vector<bool>nexthis(dp[t][dnum].his);\n nexthis.push_back(!i);\n dp[t + 1][nextdnum].num+=dp[t][dnum].num;\n if (dp[t + 1][nextdnum].num == 1) {\n dp[t + 1][nextdnum].his = nexthis;\n }\n }\n \n }\n }\n }\n if (dp[ps.size()][P].num == 1) {\n set<int>divs;\n vector<bool>his(dp[ps.size()][P].his);\n for (int t = 0; t < ps.size(); ++t) {\n vector<int>v;\n if (his[t]) {\n v = ps[t].first;\n }\n else {\n v = ps[t].second;\n }\n for (auto n : v) {\n divs.emplace(n);\n }\n }\n for (auto d : divs) {\n cout << d + 1 << endl;\n }\n cout << \"end\" << endl;\n }\n else {\n cout << \"no\" << endl;\n }\n \n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6244, "score_of_the_acc": -0.0441, "final_rank": 4 }, { "submission_id": "aoj_1238_1531341", "code_snippet": "#include<iostream>\n#include<vector>\n#include<bitset>\n\nusing namespace std;\n\nvector<int> edges[623][2];\nbool used[623];\nunsigned valid[623][623];\nbitset<623> dp[623][623];\nint dpx;\nint temp[623];\n\nvoid rec(int v,int p,int d){\n if(temp[v]){\n if(temp[v]!=d)throw -1;\n }else{\n temp[v]=d;\n for(int i=0;i<2;i++){\n for(auto e:edges[v][i]){\n\tif(v==p)continue;\n\trec(e,v,(i?1:-1)*d);\n }\n }\n }\n}\n\nvoid srec(int v,int p){\n if(!used[v]++){\n for(int i=0;i<2;i++){\n for(auto e:edges[v][i]){\n\tif(e==p)continue;\n\tsrec(e,v);\n }\n }\n }\n}\n\nbitset<623> record;\n\nvoid dodp(int v){\n for(int i=0;i<2;i++){\n fill(begin(temp),end(temp),0);\n try{\n rec(v,-1,i?1:-1);\n bitset<623> r;\n for(int i=0;i<623;i++){\n\tr[i]=temp[i]==1;\n }\n int ndiv=r.count();\n for(int j=600;j-ndiv>=0;j--){\n\tif(valid[dpx][j-ndiv]){\n\t if(valid[dpx+1][j]==0&&valid[dpx][j-ndiv]==1){\n\t valid[dpx+1][j]=1;\n\t dp[dpx+1][j]=dp[dpx][j-ndiv]|r;\n\t }else{\n\t valid[dpx+1][j]=2;\n\t }\n\t}\n }\n }catch(...){}\n }\n srec(v,-1);\n dpx++;\n}\n\nint main(){\n for(int n,p1,p2;cin>>n>>p1>>p2,n|p1|p2;){\n for(auto &e:edges){\n for(auto &f:e){\n\tf.clear();\n }\n }\n fill(begin(used),end(used),false);\n fill(valid[0],valid[623],0);\n while(n--){\n int x,y;\n char a[9];\n cin>>x>>y>>a;\n edges[x][a[0]=='y'].push_back(y);\n edges[y][a[0]=='y'].push_back(x);\n }\n valid[0][0]=1;\n dpx=0;\n for(int i=1;i<=p1+p2;i++){\n if(!used[i]){\n\tdodp(i);\n }\n }\n if(valid[dpx][p1]!=1){\n cout<<\"no\"<<endl;\n }else{\n for(int i=1;i<=p1+p2;i++){\n\tif(dp[dpx][p1][i]){\n\t cout<<i<<endl;\n\t}\n }\n cout<<\"end\"<<endl;\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 33124, "score_of_the_acc": -0.2876, "final_rank": 8 }, { "submission_id": "aoj_1238_1175150", "code_snippet": "#include <string> \n#include <algorithm> \n#include <cfloat> \n#include <climits> \n#include <cmath> \n#include <complex> \n#include <cstdio> \n#include <cstdlib> \n#include <cstring> \n#include <functional> \n#include <iostream> \n#include <map> \n#include <memory> \n#include <queue> \n#include <set> \n#include <sstream> \n#include <stack> \n#include <utility> \n#include <vector> \n\n#define EACH(i,c) for(__typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define ALL(x) (x).begin(),(x).end() \ntypedef long long ll;\nusing namespace std; \nconst double eps = 1e-10;\n\nstruct UnionFind{\n vector<int> parent, rank;\n UnionFind(int n){ parent = vector<int>(n, -1); rank = vector<int>(n, 0); }\n int find(int x){\n if(parent[x] == -1) return x;\n else return (parent[x] = find(parent[x]));\n }\n bool unite(int x, int y){\n x = find(x);\n y = find(y);\n if(x == y) return false;\n if(rank[x] < rank[y])\n parent[x] = y;\n else\n parent[y] = x;\n if(rank[x] == rank[y])\n ++rank[x];\n return true;\n }\n bool same(int x, int y){\n return find(x) == find(y);\n }\n};\n\nint dp[1010][1010], lst[1010][1010];\nint main(){\n for(;;){\n int n, p1, p2;\n cin >> n >> p1 >> p2;\n if(n == 0 && p1 == 0 && p2==0) return 0;\n int m = p1 + p2;\n UnionFind uf(2 * m);\n for(int i=0;i<n;++i){\n int x, y;\n string s;\n cin >> x >> y >> s;\n --x; --y;\n if(s == \"yes\"){\n uf.unite(x, y);\n uf.unite(x+m, y+m);\n }\n else{\n uf.unite(x, y+m);\n uf.unite(x+m, y);\n }\n }\n map<int, int> mp;\n vector<int> v, w, z;\n map<int, vector<int> > va, vb;\n for(int i=0;i<m;++i){\n int a = uf.find(i);\n int b = uf.find(i + m);\n if(mp.find(a) != mp.end()){\n int pp = mp[a];\n if(a == uf.find(pp))\n va[pp].push_back(i);\n else\n vb[pp].push_back(i);\n }\n else{\n mp[a] = mp[b] = i;\n va[i].push_back(i);\n }\n }\n EACH(i, va){\n v.push_back(i->second.size());\n w.push_back(vb[i->first].size());\n z.push_back(i->first);\n }\n memset(dp, 0, sizeof(dp));\n memset(lst, -1, sizeof(lst));\n dp[0][0] = 1;\n for(int i=0;i<v.size();++i){\n for(int j=0;j<=m;++j){\n if(j >= v[i]){\n dp[i+1][j] += dp[i][j-v[i]];\n if(dp[i][j-v[i]])lst[i+1][j] = j-v[i];\n }\n if(j >= w[i]){\n dp[i+1][j] += dp[i][j-w[i]];\n if(dp[i][j-w[i]])lst[i+1][j] = j-w[i];\n }\n }\n }\n /*\n cout << p1 << endl;\n for(int i=0;i<=3;++i){\n for(int j=0;j<=4;++j){cout.width(3); cout << lst[i][j];}\n cout << endl;\n }\n */\n if(dp[(int)v.size()][p1] != 1)\n cout << \"no\" << endl;\n else{\n vector<int> f(m);\n int num = p1;\n for(int i=v.size()-1;i>=0;--i){\n int bnum = lst[i+1][num];\n if(bnum+v[i] == num){\n EACH(j, va[z[i]]) f[*j] = 1;\n }\n else{\n EACH(j, vb[z[i]]) f[*j] = 1;\n }\n num = bnum;\n }\n for(int i=0;i<m;++i){\n if(f[i]) cout << i+1 << endl;\n }\n cout << \"end\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 9264, "score_of_the_acc": -0.0715, "final_rank": 6 }, { "submission_id": "aoj_1238_1105932", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nclass UnionFind {\nprivate:\n vector<int> par, rank;\npublic:\n UnionFind(int n) {\n par = rank = vector<int>(n);\n for(int i = 0; i < n; ++i) par[i] = i;\n }\n\n int find(int x) {\n return par[x] == x ? x : par[x] = find(par[x]);\n }\n\n bool same(int x, int y) {\n return find(x) == find(y);\n }\n\n void unite(int x, int y) {\n x = find(x);\n y = find(y);\n if(x == y) return;\n if(rank[x] < rank[y]) {\n par[x] = y;\n } else {\n par[y] = x;\n if(rank[x] == rank[y]) ++rank[x];\n }\n }\n};\n\nint main() {\n for(int n, p1, p2; cin >> n >> p1 >> p2 && (n|p1|p2); ) {\n int m = p1+p2;\n UnionFind uf(m*2);\n for(int i = 0; i < n; ++i) {\n int x, y;\n string a;\n cin >> x >> y >> a;\n --x; --y;\n if(a == \"yes\") {\n uf.unite(x, y);\n uf.unite(x+m, y+m);\n } else {\n uf.unite(x, y+m);\n uf.unite(x+m, y);\n }\n }\n\n bool no_flag = false;\n map<int, pair<int, int> > group;\n for(int i = 0; i < m; ++i) {\n if(uf.same(i, i+m)) {\n no_flag = true;\n break;\n }\n int root = uf.find(i);\n int add = 1;\n if(root >= m) {\n root -= m;\n add = 0;\n }\n group[root].first++;\n group[root].second += add;\n }\n if(no_flag) {\n cout << \"no\" << endl;\n continue;\n }\n\n vector<int> roots;\n vector<pair<int, int> > v;\n for(map<int, pair<int,int> >::iterator it = group.begin();\n it != group.end(); ++it) {\n roots.push_back(it->first);\n v.push_back(make_pair(it->second.second, \n it->second.first - it->second.second));\n }\n\n int size = v.size();\n vector<vector<int> > dp(size+1, vector<int>(p1+1, 0));\n vector<vector<int> > prev(size+1, vector<int>(p1+1, -1));\n dp[0][0] = 1;\n for(int i = 0; i < v.size(); ++i) {\n for(int j = 0; j <= p1; ++j) {\n if(!dp[i][j]) continue;\n try {\n int nj = j + v[i].first;\n if(nj > p1) throw 0;\n dp[i+1][nj] += 1;\n prev[i+1][nj] = 0;\n } catch(...) {}\n try {\n int nj = j + v[i].second;\n if(nj > p1) throw 0;\n dp[i+1][nj] += 1;\n prev[i+1][nj] = 1;\n } catch(...) {}\n }\n }\n\n if(dp[v.size()][p1] != 1) {\n cout << \"no\" << endl;\n continue;\n }\n\n vector<int> r(m*2);\n {\n int i = v.size();\n int j = p1;\n while(prev[i][j] != -1) {\n if(prev[i][j] == 0) {\n r[roots[i-1]] = 1;\n j -= v[i-1].first;\n } else {\n r[roots[i-1]+m] = 1;\n j -= v[i-1].second;\n }\n --i;\n }\n }\n for(int i = 0; i < m; ++i) {\n if(r[uf.find(i)]) {\n cout << i+1 << endl;\n }\n }\n cout << \"end\" << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1372, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_1238_811989", "code_snippet": "#include <bits/stdc++.h>\n#define REP(i,n) for(int i=0; i<(int)(n); ++i)\n\nusing namespace std;\n\nconst int MAX_V = 666;\n\nint N, P1, P2, M;\nint d[MAX_V][MAX_V];\nbool used[MAX_V];\nint id[MAX_V];\nint val[MAX_V];\n\ntypedef pair<int, int> P;\nP dfs(int u, int c, int k){\n if(used[u]) return P(0, 0);\n used[u] = true;\n id[u] = k;\n val[u] = c;\n P res(0, 0);\n if(c == 0) res.first ++;\n if(c == 1) res.second ++;\n REP(v, M) if(d[u][v] >= 0){\n P p = dfs(v, c ^ d[u][v], k);\n res = P(res.first + p.first, res.second + p.second);\n }\n return res;\n}\n\nvoid add(int& x, int y){\n x = min(x + y, 2);\n}\n\nint main(){\n int N, P1, P2;\n while(cin >> N >> P1 >> P2 && !(N == 0 && P1 == 0 && P2 == 0)){\n M = P1 + P2;\n memset(d, -1, sizeof(d));\n REP(i, N){\n int x, y;\n string s;\n cin >> x >> y >> s;\n d[x - 1][y - 1] = d[y - 1][x - 1] = (s[0] == 'y' ? 0 : 1);\n }\n memset(used, 0, sizeof(used));\n int K = 0;\n vector<P> vp;\n REP(i, M) if(!used[i]){\n P p = dfs(i, 0, K++);\n vp.push_back(p);\n }\n\n int dp[MAX_V][MAX_V] = {};\n int back[MAX_V][MAX_V] = {};\n dp[0][0] = 1;\n for(int i = 0; i < vp.size(); i++){\n for(int j = M; j >= 0; j--){\n if(dp[i][j] >= 1){\n add(dp[i + 1][j + vp[i].first], dp[i][j]);\n add(dp[i + 1][j + vp[i].second], dp[i][j]);\n back[i + 1][j + vp[i].first] = 0;\n back[i + 1][j + vp[i].second] = 1;\n }\n }\n }\n if(dp[vp.size()][P1] == 1){\n int curr = P1;\n for(int i = vp.size() - 1; i >= 0; i--){\n if(back[i + 1][curr] == 0){\n curr -= vp[i].first;\n }else{\n curr -= vp[i].second;\n\n for(int u = 0; u < M; u++)\n if(id[u] == i)\n val[u] ^= 1;\n }\n }\n for(int i = 0; i < M; i++){\n if(val[i] == 0){\n cout << i + 1 << endl;\n }\n }\n cout << \"end\" << endl;\n }else{\n cout << \"no\" << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6432, "score_of_the_acc": -0.0458, "final_rank": 5 }, { "submission_id": "aoj_1238_647391", "code_snippet": "#include<iostream>\n#include<sstream>\n#include<algorithm>\n#include<set>\n#include<map>\n#include<queue>\n#include<complex>\n#include<cstdio>\n#include<cstdlib>\n#include<cstring>\n#include<cassert>\n\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define all(c) (c).begin(),(c).end()\n#define mp make_pair\n#define pb push_back\n#define each(i,c) for(__typeof((c).begin()) i=(c).begin();i!=(c).end();i++)\n#define dbg(x) cerr<<__LINE__<<\": \"<<#x<<\" = \"<<(x)<<endl\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef pair<int,int> pi;\nconst int inf = (int)1e9;\nconst double INF = 1e12, EPS = 1e-9;\n\nint q, n, m, p[1200], prev[610][610], dp[610][610];\nint root(int x){\n\tif(p[x] == x) return x;\n\treturn p[x] = root(p[x]);\n}\nvoid merge(int a, int b){\n\ta = root(a); b = root(b);\n\tif(a != b) p[b] = a;\n}\n\nint main(){\n\twhile(cin >> q >> n >> m, q + n + m){\n\t\trep(i, 2 * (n + m)) p[i] = i;\n\t\trep(i, q){\n\t\t\tstring c;\n\t\t\tint a, b;\n\t\t\tcin >> a >> b >> c;\n\t\t\ta--; b--;\n\t\t\tif(c == \"yes\") rep(j, 2) merge(2 * a + j, 2 * b + j);\n\t\t\telse rep(j, 2) merge(2 * a + j, 2 * b + 1 - j);\n\t\t}\n\t\tmap<int, vi> s;\n\t\tvector<vi> ys, ns;\n\t\tvector<pi> v;\n\t\tvi ans; int p;\n\t\tbool use[1200] = {};\n\t\t\n\t\trep(i, 2 * (n + m)) s[root(i)].pb(i);\n\t\trep(i, 2 * (n + m)){\n\t\t\tint t = 0, l = 0, r = root(i);\n\t\t\tif(use[r / 2]) continue;\n\t\t\tuse[r / 2] = 1;\n\t\t\tvi a, b;\n\t\t\teach(j, s[r]){\n\t\t\t\tif(*j % 2) l++, b.pb(*j / 2);\n\t\t\t\telse t++, a.pb(*j / 2);\n\t\t\t}\n\t\t\tv.pb(mp(t, l));\n\t\t\tys.pb(a); ns.pb(b);\n\t\t}\n\t\tmemset(dp, 0, sizeof(dp));\n\t\tdp[0][0] = 1;\n\t\trep(i, v.size()) for(int j = n + m; j >= 0; j--) if(dp[i][j]){\n\t\t\tdp[i][j] = min(dp[i][j], 100);\n\t\t\tif(j + v[i].first <= n + m) dp[i + 1][j + v[i].first] += dp[i][j], prev[i + 1][j + v[i].first] = 0;\n\t\t\tif(j + v[i].second<= n + m) dp[i + 1][j + v[i].second]+= dp[i][j], prev[i + 1][j + v[i].second]= 1;\n\t\t}\n\t\tp = v.size() - 1;\n\t\tif(dp[p + 1][n] != 1){\n\t\t\tcout << \"no\" << endl;\n\t\t\tgoto END;\n\t\t}\n\t\twhile(p >= 0){\n\t\t\tif(prev[p + 1][n]) rep(j, ns[p].size()) ans.pb(ns[p][j]);\n\t\t\telse rep(j, ys[p].size()) ans.pb(ys[p][j]);\n\t\t\tn -= prev[p + 1][n] ? ns[p].size() : ys[p].size();\n\t\t\tp--;\n\t\t}\n\t\tsort(all(ans));\n\t\trep(i, ans.size()) cout << ans[i] + 1 << endl;\n\t\tcout << \"end\" << endl;\n\t\tEND:;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3084, "score_of_the_acc": -0.0155, "final_rank": 2 } ]
aoj_1241_cpp
Problem B: Lagrange's Four-Square Theorem The fact that any positive integer has a representation as the sum of at most four positive squares (i.e. squares of positive integers) is known as Lagrange’s Four-Square Theorem. The first published proof of the theorem was given by Joseph-Louis Lagrange in 1770. Your mission however is not to explain the original proof nor to discover a new proof but to show that the theorem holds for some specific numbers by counting how many such possible representations there are. For a given positive integer n, you should report the number of all representations of n as the sum of at most four positive squares. The order of addition does not matter, e.g. you should consider 4 2 + 3 2 and 3 2 + 4 2 are the same representation. For example, let’s check the case of 25. This integer has just three representations 1 2 +2 2 +2 2 +4 2 , 3 2 + 4 2 , and 5 2 . Thus you should report 3 in this case. Be careful not to count 4 2 + 3 2 and 3 2 + 4 2 separately. Input The input is composed of at most 255 lines, each containing a single positive integer less than 2 15 , followed by a line containing a single zero. The last line is not a part of the input data. Output The output should be composed of lines, each containing a single integer. No other characters should appear in the output. The output integer corresponding to the input integer n is the number of all representations of n as the sum of at most four positive squares. Sample Input 1 25 2003 211 20007 0 Output for the Sample Input 1 3 48 7 738
[ { "submission_id": "aoj_1241_10895268", "code_snippet": "#include<bits/stdc++.h>\n// #include<atcoder/all>\n// #include<boost/multiprecision/cpp_int.hpp>\n\nusing namespace std;\n// using namespace atcoder;\n// using bint = boost::multiprecision::cpp_int;\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing ve = vector<vector<int>>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\n#define rep(i,s,n) for(ll i = (ll)s;i < (ll)n;i++)\n#define rrep(i,l,r) for(ll i = r-1;i >= l;i--)\n#define ALL(x) (x).begin(),(x).end()\n#define sz(c) ((ll)(c).size())\n#define LB(A,x) (int)(lower_bound(A.begin(),A.end(),x)-A.begin())\n#define UB(A,x) (int)(upper_bound(A.begin(),A.end(),x)-A.begin())\n// #define MOD 1000000007\n#define MOD 998244353\ntemplate<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T>ostream&operator<<(ostream&os,vector<T>&v){for(int i = 0;i < v.size();i++)os<<v[i]<<(i+1!=v.size()?\" \":\"\");return os;}\ntemplate<typename T>istream&operator>>(istream&is,vector<T>&v){for(T&in:v)is>>in;return is;}\ntemplate<typename T1,typename T2>ostream&operator<<(ostream&os,pair<T1,T2>&p){os<<p.first<<\" \"<<p.second;return os;}\ntemplate<typename T1,typename T2>istream&operator>>(istream&is,pair<T1,T2>&p){is>>p.first>>p.second;return is;}\ntemplate<typename T> inline bool chmax(T &a,T b){if(a < b){a = b;return true;}return false;}\ntemplate<typename T> inline bool chmin(T &a,T b){if(a > b){a = b;return true;}return false;}\nld dist(ld x1,ld y1,ld x2, ld y2){return sqrtl((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));}\n\n\nint main(){\n \n ios_base::sync_with_stdio(0), cin.tie(0);\n vi pw(1 << 8);\n rep(i,0,1 << 8)pw[i] = i*i;\n while(1){\n int n;cin >> n;\n if(!n)break;\n const int MX = 1 << 8;\n int res = 0;\n rep(i,0,MX)rep(j,i,MX)rep(k,j,MX){\n ll d = n-(i*i + j*j + k*k);\n if(k*k <= d && pw[LB(pw,d)] == d)res++;\n }\n cout << res << \"\\n\";\n }\n \n\n return 0;\n}", "accuracy": 1, "time_ms": 730, "memory_kb": 3220, "score_of_the_acc": -0.2155, "final_rank": 6 }, { "submission_id": "aoj_1241_10189432", "code_snippet": "#include <vector>\n#include <iostream>\nusing namespace std;\n\nint main() {\n\tconst int LIMIT = 1 << 15;\n\tvector<int> counter(LIMIT + 1);\n\tfor (int a = 0; a * a <= LIMIT; a++) {\n\t\tfor (int b = a; a * a + b * b <= LIMIT; b++) {\n\t\t\tfor (int c = b; a * a + b * b + c * c <= LIMIT; c++) {\n\t\t\t\tfor (int d = c; a * a + b * b + c * c + d * d <= LIMIT; d++) {\n\t\t\t\t\tcounter[a * a + b * b + c * c + d * d]++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\twhile (true) {\n\t\tint N;\n\t\tcin >> N;\n\t\tif (N == 0) {\n\t\t\tbreak;\n\t\t}\n\t\tcout << counter[N] << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3436, "score_of_the_acc": -0.0124, "final_rank": 1 }, { "submission_id": "aoj_1241_10022090", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define all(a) a.begin(),a.end()\n#define reps(i, a, n) for (int i = (a); i < (int)(n); i++)\n#define rep(i, n) reps(i, 0, n)\n#define rreps(i, a, n) for (int i = (a); i > (int)(n); i--)\nconst long long mod = 1000000007;\nconst long long INF = 1e18;\nll myceil(ll a, ll b) {return (a+b-1)/b;}\n\nint n;\n\nvoid solve() {\n int ans = 0;\n\n for (int i = 0; i*i<n; i++) {\n for (int j = i; i*i+j*j<n; j++) {\n for (int k = j; i*i+j*j+k*k<n; k++) {\n if (n-i*i-j*j-k*k >= k*k && (int)pow(n-i*i-j*j-k*k,0.5)*(int)pow(n-i*i-j*j-k*k,0.5) == n-i*i-j*j-k*k) {\n ans++;\n }\n }\n }\n }\n\n cout << ans << endl;\n return;\n}\n\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n\n cin >> n;\n while (n != 0) {\n solve();\n cin >> n;\n }\n}", "accuracy": 1, "time_ms": 1800, "memory_kb": 3744, "score_of_the_acc": -0.5391, "final_rank": 9 }, { "submission_id": "aoj_1241_9834899", "code_snippet": "#include <iostream>\n#include <vector>\n\nint main() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n\n std::vector dp(5, std::vector<long long>(1 << 15));\n dp[0][0] = 1;\n for (int v{1} ; v * v < (1 << 15) ; v++) {\n std::vector next{dp};\n for (int i{1} ; i <= 4 ; i++) {\n int add{i * v * v};\n for (int j{} ; j + add < (1 << 15) ; j++) {\n for (int k{} ; k + i <= 4 ; k++) {\n next[k + i][j + add] += dp[k][j];\n }\n }\n }\n dp = std::move(next);\n }\n while (true) {\n int v;\n std::cin >> v;\n if (v == 0) break;\n // std::cout << dp[1][v] << ' ' << dp[2][v] << ' ' << dp[3][v] << ' ' << dp[4][v] << std::endl;\n std::cout << dp[1][v] + dp[2][v] + dp[3][v] + dp[4][v] << '\\n';\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5556, "score_of_the_acc": -0.0785, "final_rank": 4 }, { "submission_id": "aoj_1241_9572679", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n#include <unistd.h>\n\nnamespace fastio {\nstatic constexpr uint32_t SZ = 1 << 17;\nchar ibuf[SZ];\nchar obuf[SZ];\nchar out[100];\n// pointer of ibuf, obuf\n\n\nuint32_t pil = 0, pir = 0, por = 0;\n\nstruct Pre {\n char num[10000][4];\n constexpr Pre() : num() {\n for (int i = 0; i < 10000; i++) {\n int n = i;\n for (int j = 3; j >= 0; j--) {\n num[i][j] = n % 10 | '0';\n n /= 10;\n }\n }\n }\n} constexpr pre;\n\ninline void load() {\n memmove(ibuf, ibuf + pil, pir - pil);\n pir = pir - pil + fread(ibuf + pir - pil, 1, SZ - pir + pil, stdin);\n pil = 0;\n if (pir < SZ)\n ibuf[pir++] = '\\n';\n}\n\ninline void flush() {\n fwrite(obuf, 1, por, stdout);\n por = 0;\n}\n\nvoid rd(char &c) {\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n}\n\nvoid rd(string &x) {\n x.clear();\n char c;\n do {\n if (pil + 1 > pir)\n load();\n c = ibuf[pil++];\n } while (isspace(c));\n do {\n x += c;\n if (pil == pir)\n load();\n c = ibuf[pil++];\n } while (!isspace(c));\n}\n\ntemplate <typename T> void rd_real(T &x) {\n string s;\n rd(s);\n x = stod(s);\n}\n\ntemplate <typename T> void rd_integer(T &x) {\n if (pil + 100 > pir)\n load();\n char c;\n do\n c = ibuf[pil++];\n while (c < '-');\n bool minus = 0;\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (c == '-') {\n minus = 1, c = ibuf[pil++];\n }\n }\n x = 0;\n while ('0' <= c) {\n x = x * 10 + (c & 15), c = ibuf[pil++];\n }\n if constexpr (is_signed<T>::value || is_same_v<T, i128>) {\n if (minus)\n x = -x;\n }\n}\n\nvoid rd(int &x) {\n rd_integer(x);\n}\nvoid rd(ll &x) {\n rd_integer(x);\n}\nvoid rd(i128 &x) {\n rd_integer(x);\n}\nvoid rd(uint &x) {\n rd_integer(x);\n}\nvoid rd(ull &x) {\n rd_integer(x);\n}\nvoid rd(u128 &x) {\n rd_integer(x);\n}\nvoid rd(double &x) {\n rd_real(x);\n}\nvoid rd(long double &x) {\n rd_real(x);\n}\n\ntemplate <class T, class U> void rd(pair<T, U> &p) {\n return rd(p.first), rd(p.second);\n}\ntemplate <size_t N = 0, typename T> void rd_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n rd(x);\n rd_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void rd(tuple<T...> &tpl) {\n rd_tuple(tpl);\n}\n\ntemplate <size_t N = 0, typename T> void rd(array<T, N> &x) {\n for (auto &d : x)\n rd(d);\n}\ntemplate <class T> void rd(vector<T> &x) {\n for (auto &d : x)\n rd(d);\n}\n\nvoid read() {}\ntemplate <class H, class... T> void read(H &h, T &...t) {\n rd(h), read(t...);\n}\n\nvoid wt(const char c) {\n if (por == SZ)\n flush();\n obuf[por++] = c;\n}\nvoid wt(const string s) {\n for (char c : s)\n wt(c);\n}\nvoid wt(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++)\n wt(s[i]);\n}\n\ntemplate <typename T> void wt_integer(T x) {\n if (por > SZ - 100)\n flush();\n if (x < 0) {\n obuf[por++] = '-', x = -x;\n }\n int outi;\n for (outi = 96; x >= 10000; outi -= 4) {\n memcpy(out + outi, pre.num[x % 10000], 4);\n x /= 10000;\n }\n if (x >= 1000) {\n memcpy(obuf + por, pre.num[x], 4);\n por += 4;\n } else if (x >= 100) {\n memcpy(obuf + por, pre.num[x] + 1, 3);\n por += 3;\n } else if (x >= 10) {\n int q = (x * 103) >> 10;\n obuf[por] = q | '0';\n obuf[por + 1] = (x - q * 10) | '0';\n por += 2;\n } else\n obuf[por++] = x | '0';\n memcpy(obuf + por, out + outi + 4, 96 - outi);\n por += 96 - outi;\n}\n\ntemplate <typename T> void wt_real(T x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << double(x);\n string s = oss.str();\n wt(s);\n}\n\nvoid wt(int x) {\n wt_integer(x);\n}\nvoid wt(ll x) {\n wt_integer(x);\n}\nvoid wt(i128 x) {\n wt_integer(x);\n}\nvoid wt(uint x) {\n wt_integer(x);\n}\nvoid wt(ull x) {\n wt_integer(x);\n}\nvoid wt(u128 x) {\n wt_integer(x);\n}\nvoid wt(double x) {\n wt_real(x);\n}\nvoid wt(long double x) {\n wt_real(x);\n}\n\ntemplate <class T, class U> void wt(const pair<T, U> val) {\n wt(val.first);\n wt(' ');\n wt(val.second);\n}\ntemplate <size_t N = 0, typename T> void wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) {\n wt(' ');\n }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T> void wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S> void wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T> void wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i)\n wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() {\n wt('\\n');\n}\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&...tail) {\n wt(head);\n if (sizeof...(Tail))\n wt(' ');\n print(forward<Tail>(tail)...);\n}\nvoid __attribute__((destructor)) _d() {\n flush();\n}\n} // namespace fastio\n\n\nusing fastio::flush;\nusing fastio::print;\nusing fastio::read;\n\ninline void first(bool i = true) {\n print(i ? \"first\" : \"second\");\n}\ninline void Alice(bool i = true) {\n print(i ? \"Alice\" : \"Bob\");\n}\ninline void Takahashi(bool i = true) {\n print(i ? \"Takahashi\" : \"Aoki\");\n}\ninline void yes(bool i = true) {\n print(i ? \"yes\" : \"no\");\n}\ninline void Yes(bool i = true) {\n print(i ? \"Yes\" : \"No\");\n}\ninline void No() {\n print(\"No\");\n}\ninline void YES(bool i = true) {\n print(i ? \"YES\" : \"NO\");\n}\ninline void NO() {\n print(\"NO\");\n}\ninline void Yay(bool i = true) {\n print(i ? \"Yay!\" : \":(\");\n}\ninline void Possible(bool i = true) {\n print(i ? \"Possible\" : \"Impossible\");\n}\ninline void POSSIBLE(bool i = true) {\n print(i ? \"POSSIBLE\" : \"IMPOSSIBLE\");\n}\n\n/**\n * @brief Fast IO\n */\n\nint main() {\nwhile(1) {\n int N;\n cin >> N;\n if (N == 0) return 0;\n int ANS = 0;\n rep(i,0,200) {\n rep(j,0,i+1) {\n rep(k,0,j+1) {\n if (i*i+j*j+k*k > N) break;\n int l = sqrt(N-i*i-j*j-k*k);\n if (l <= k && i*i+j*j+k*k+l*l == N) ANS++;\n }\n }\n }\n cout << ANS << endl;\n}\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 3496, "score_of_the_acc": -0.0719, "final_rank": 3 }, { "submission_id": "aoj_1241_9028215", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\n#define rep(i, a, b) for(ll i = a; i < b; ++i)\n#define rrep(i, a, b) for(ll i = a; i >= b; --i)\nconstexpr ll inf = 4e18;\nstruct SetupIO {\n SetupIO() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout << fixed << setprecision(30);\n }\n} setup_io;\nint main(void) {\n while(true) {\n ll n;\n cin >> n;\n if(n == 0) break;\n ll ans = 0;\n rep(i, 1, 200) {\n if(i * i == n) ans++;\n if(i * i > n) break;\n rep(j, i, 200) {\n if(i * i + j * j == n) ans++;\n if(i * i + j * j > n) break;\n rep(k, j, 200) {\n if(i * i + j * j + k * k == n) ans++;\n if(i * i + j * j + k * k > n) break;\n rep(l, k, 200) {\n if(i * i + j * j + k * k + l * l == n) ans++;\n if(i * i + j * j + k * k + l * l > n) break;\n }\n }\n }\n }\n cout << ans << '\\n';\n }\n}", "accuracy": 1, "time_ms": 670, "memory_kb": 3220, "score_of_the_acc": -0.1981, "final_rank": 5 }, { "submission_id": "aoj_1241_8993567", "code_snippet": "// (⁠◕⁠ᴗ⁠◕⁠✿⁠)\n\n// #pragma GCC target(\"avx2\")\n// #pragma GCC optimize(\"O3\")\n// #pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define srep(i, s, n) for (ll i = s; i < (n); i++)\n#define len(x) ((int)(x).size())\n#define all(x) (x).begin(), (x).end()\nusing namespace std;\ntemplate<typename T> using vc = vector<T>;\ntemplate<typename T> using vv = vc<vc<T>>;\ntemplate<typename T> using vvv = vv<vc<T>>;\nusing vi = vc<int>;using vvi = vv<int>; using vvvi = vv<vi>;\nusing ll = long long;using vl = vc<ll>;using vvl = vv<ll>; using vvvl = vv<vl>;\nusing ld = long double; using vld = vc<ld>; using vvld = vc<vld>; using vvvld = vc<vvld>;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nconst ld pi = 3.141592653589793;\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\n// const ll mod = 1000000007;\nconst ll mod = 998244353;\ninline bool inside(ll y, ll x, ll H, ll W) {return 0 <= (y) and (y) < (H) and 0 <= (x) and (x) < (W); }\n\n#define debug(var) do{std::cout << #var << \" : \\n\";view(var);}while(0)\ntemplate<typename T> void view(T e){cout << e << endl;}\ntemplate<typename T> void view(const vc<T>& v){for(const auto& e : v){ cout << e << \" \"; } cout << endl;}\ntemplate<typename T> void view(const vv<T>& vv){ for(const auto& v : vv){ view(v); } }\n\nvi sq;\n\nint solve(int N){\n int ans = 0;\n for (int a = 0; a * a <= N; a++) for (int b = a; b * b + a * a <= N; b++) for (int c = b; c * c + b * b + a * a <= N; c++){\n int tmp = a * a + b * b + c * c;\n if (tmp <= N && c <= sq[N - tmp]) ans++;\n }\n return ans;\n}\n\nint main(){\n sq.resize(1 << 15, -1);\n for (int i = 0; i * i < 1 << 15; i++) sq[i * i] = i;\n vc<int> ans;\n while (true){\n int N; cin >> N;\n if (N == 0) break;\n ans.push_back(solve(N));\n }\n for (auto x : ans) cout << fixed << setprecision(16) << x << endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3056, "score_of_the_acc": -0.0171, "final_rank": 2 }, { "submission_id": "aoj_1241_8861691", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n#include <algorithm>\n#include <bitset>\n#include <cctype>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <iostream>\n#include <limits>\n#include <list>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> P;\ntypedef pair<int, P> PP;\nint tx[] = {0, 1, 0, -1};\nint ty[] = {-1, 0, 1, 0};\nstatic const double EPS = 1e-8;\nint dp[1000000][5];\nint main() {\n int n;\n while (~scanf(\"%d\", &n)) {\n if (n == 0)\n break;\n memset(dp, 0, sizeof(dp));\n dp[0][0] = 1;\n for (int i = 1; i * i <= n; i++) {\n for (int k = 1; k <= 4; k++) {\n for (int j = i * i; j <= n; j++) {\n dp[j][k] += dp[j - i * i][k - 1];\n }\n }\n }\n printf(\"%d\\n\", dp[n][4] + dp[n][3] + dp[n][2] + dp[n][1]);\n }\n}", "accuracy": 1, "time_ms": 1630, "memory_kb": 22636, "score_of_the_acc": -0.976, "final_rank": 18 }, { "submission_id": "aoj_1241_8861687", "code_snippet": "#include <cstdio>\n#include <cstring>\nusing namespace std;\n\nint dp[1000000][5];\n\nint main() {\n int n;\n while (~scanf(\"%d\", &n)) {\n if (n == 0) break;\n\n memset(dp, 0, sizeof(dp));\n dp[0][0] = 1;\n \n for (int i = 1; i * i <= n; i++) {\n int square = i * i; // Store square value to avoid repeated computation\n for (int k = 1; k <= 4; k++) {\n #pragma omp parallel for // Compiler directive for parallel execution\n for (int j = square; j <= n; j++) {\n dp[j][k] += dp[j - square][k - 1];\n }\n }\n }\n\n printf(\"%d\\n\", dp[n][4] + dp[n][3] + dp[n][2] + dp[n][1]);\n }\n}", "accuracy": 1, "time_ms": 1630, "memory_kb": 22216, "score_of_the_acc": -0.9652, "final_rank": 15 }, { "submission_id": "aoj_1241_8861685", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n#include <algorithm>\n#include <bitset>\n#include <cctype>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <iostream>\n#include <limits>\n#include <list>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> P;\ntypedef pair<int, P> PP;\nint tx[] = {0, 1, 0, -1};\nint ty[] = {-1, 0, 1, 0};\nstatic const double EPS = 1e-8;\nint dp[1000000][5];\nint main() {\n int n;\n while (~scanf(\"%d\", &n)) {\n if (n == 0)\n break;\n memset(dp, 0, sizeof(dp));\n dp[0][0] = 1;\n for (int i = 1; i * i <= n; i++) {\n for (int k = 1; k <= 4; k++) {\n for (int j = 0; j <= n - i * i; j++) { // Optimized loop\n dp[j + i * i][k] += dp[j][k - 1]; // Adjusted the index\n }\n }\n }\n printf(\"%d\\n\", dp[n][4] + dp[n][3] + dp[n][2] + dp[n][1]);\n }\n}", "accuracy": 1, "time_ms": 1640, "memory_kb": 22736, "score_of_the_acc": -0.9815, "final_rank": 19 }, { "submission_id": "aoj_1241_8836958", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n#include <algorithm>\n#include <bitset>\n#include <cctype>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <iostream>\n#include <limits>\n#include <list>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> P;\ntypedef pair<int, P> PP;\nint tx[] = {0, 1, 0, -1};\nint ty[] = {-1, 0, 1, 0};\nstatic const double EPS = 1e-8;\n\nint main() {\n int n;\n while (~scanf(\"%d\", &n)) {\n if (n == 0)\n break;\n int** dp = new int*[n + 1];\n for (int i = 0; i <= n; i++) {\n dp[i] = new int[5];\n memset(dp[i], 0, sizeof(int) * 5);\n }\n dp[0][0] = 1;\n for (int i = 1; i * i <= n; i++) {\n int square = i * i;\n for (int k = 1; k <= 4; k++) {\n for (int j = square; j <= n; j++) {\n dp[j][k] += dp[j - square][k - 1];\n }\n }\n }\n printf(\"%d\\n\", dp[n][4] + dp[n][3] + dp[n][2] + dp[n][1]);\n\n for (int i = 0; i <= n; i++) {\n delete[] dp[i];\n }\n delete[] dp;\n }\n}", "accuracy": 1, "time_ms": 2700, "memory_kb": 4112, "score_of_the_acc": -0.8095, "final_rank": 12 }, { "submission_id": "aoj_1241_8819380", "code_snippet": "#define _USE_MATH_DEFINES\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\nusing namespace std;\ntypedef long long ll;\nstatic const double EPS = 1e-8;\nint dp[1000000][5];\nint main() {\n int n;\n while (~scanf(\"%d\", &n)) {\n if (n == 0)\n break;\n memset(dp, 0, sizeof(dp));\n dp[0][0] = 1;\n for (int i = 1; i * i <= n; i++) {\n int square = i * i; // Calculate i*i once to avoid repeated calculations\n for (int k = 1; k <= 4; k++) {\n for (int j = square; j <= n; j++) {\n dp[j][k] += dp[j - square][k - 1];\n }\n }\n }\n printf(\"%d\\n\", dp[n][4] + dp[n][3] + dp[n][2] + dp[n][1]);\n }\n}", "accuracy": 1, "time_ms": 1620, "memory_kb": 22144, "score_of_the_acc": -0.9604, "final_rank": 13 }, { "submission_id": "aoj_1241_8819378", "code_snippet": "#include <cstdio>\n#include <cstring>\nusing namespace std;\n\nstatic const int MAX_N = 100000;\nint dp[MAX_N][5];\n\nint main() {\n int n;\n while (~scanf(\"%d\", &n)) {\n if (n == 0)\n break;\n memset(dp, 0, sizeof(dp));\n dp[0][0] = 1;\n for (int i = 1; i * i <= n; i++) {\n int sq = i * i;\n for (int k = 1; k <= 4; k++) {\n for (int j = sq; j <= n; j++) {\n dp[j][k] += dp[j - sq][k - 1];\n }\n }\n }\n int result = dp[n][4] + dp[n][3] + dp[n][2] + dp[n][1];\n printf(\"%d\\n\", result);\n }\n}", "accuracy": 1, "time_ms": 1370, "memory_kb": 4532, "score_of_the_acc": -0.4348, "final_rank": 8 }, { "submission_id": "aoj_1241_8819377", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\nusing namespace std;\nint dp[1000000][5];\nint main() {\n int n;\n while (~scanf(\"%d\", &n)) {\n if (n == 0)\n break;\n memset(dp, 0, sizeof(dp));\n dp[0][0] = 1;\n for (int i = 1; i * i <= n; i++) {\n int square = i * i;\n for (int k = 1; k <= 4; k++) {\n for (int j = square; j <= n; j++) {\n dp[j][k] += dp[j - square][k - 1];\n }\n }\n }\n printf(\"%d\\n\", dp[n][4] + dp[n][3] + dp[n][2] + dp[n][1]);\n }\n}", "accuracy": 1, "time_ms": 1640, "memory_kb": 22212, "score_of_the_acc": -0.968, "final_rank": 17 }, { "submission_id": "aoj_1241_8819374", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n#include <algorithm>\n#include <bitset>\n#include <cctype>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <iostream>\n#include <limits>\n#include <list>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> P;\ntypedef pair<int, P> PP;\nint tx[] = {0, 1, 0, -1};\nint ty[] = {-1, 0, 1, 0};\nstatic const double EPS = 1e-8;\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n int n;\n while (~scanf(\"%d\", &n)) {\n if (n == 0)\n break;\n int dp[n+1][5];\n memset(dp, 0, sizeof(dp));\n dp[0][0] = 1;\n for (int i = 1; i * i <= n; i++) {\n int square = i * i;\n for (int k = 1; k <= 4; k++) {\n for (int j = square; j <= n; j++) {\n dp[j][k] += dp[j - square][k - 1];\n }\n }\n }\n printf(\"%d\\n\", dp[n][4] + dp[n][3] + dp[n][2] + dp[n][1]);\n }\n}", "accuracy": 1, "time_ms": 1380, "memory_kb": 3864, "score_of_the_acc": -0.4205, "final_rank": 7 }, { "submission_id": "aoj_1241_8807889", "code_snippet": "#include <cstdio>\n#include <cstring>\n\nint dp[1000000][5];\n\nint main() {\n int n;\n while (scanf(\"%d\", &n) != EOF) {\n if (n == 0)\n break;\n memset(dp, 0, sizeof(dp));\n dp[0][0] = 1;\n for (int i = 1; i * i <= n; i++) {\n for (int k = 1; k <= 4; k++) {\n for (int j = i * i; j <= n; j++) {\n dp[j][k] += dp[j - i * i][k - 1];\n }\n }\n }\n printf(\"%d\\n\", dp[n][4] + dp[n][3] + dp[n][2] + dp[n][1]);\n }\n}", "accuracy": 1, "time_ms": 1640, "memory_kb": 22116, "score_of_the_acc": -0.9655, "final_rank": 16 }, { "submission_id": "aoj_1241_8807888", "code_snippet": "#include <cstdio>\n#include <cstring>\n\nconst int MAX_N = 1000000;\nconst int MAX_K = 5;\n\nlong long dp[MAX_N][MAX_K];\n\nint main() {\n int n;\n while (~scanf(\"%d\", &n)) {\n if (n == 0)\n break;\n memset(dp, 0, sizeof(dp));\n dp[0][0] = 1;\n for (int i = 1; i * i <= n; i++) {\n for (int k = 1; k <= 4; k++) {\n for (int j = i * i; j <= n; j++) {\n dp[j][k] += dp[j - i * i][k - 1];\n }\n }\n }\n printf(\"%lld\\n\", dp[n][4] + dp[n][3] + dp[n][2] + dp[n][1]);\n }\n}", "accuracy": 1, "time_ms": 3460, "memory_kb": 41816, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_1241_8807884", "code_snippet": "#include <cstdio>\n#include <cstring>\n\nint main() {\n int n;\n while (~scanf(\"%d\", &n)) {\n if (n == 0)\n break;\n \n int** dp = new int*[n+1];\n for (int i = 0; i <= n; i++) {\n dp[i] = new int[5];\n memset(dp[i], 0, sizeof(int) * 5);\n }\n \n dp[0][0] = 1;\n for (int i = 1; i * i <= n; i++) {\n for (int k = 1; k <= 4; k++) {\n for (int j = i * i; j <= n; j++) {\n dp[j][k] += dp[j - i * i][k - 1];\n }\n }\n }\n \n int result = dp[n][4] + dp[n][3] + dp[n][2] + dp[n][1];\n \n for (int i = 0; i <= n; i++) {\n delete[] dp[i];\n }\n delete[] dp;\n \n printf(\"%d\\n\", result);\n }\n}", "accuracy": 1, "time_ms": 2700, "memory_kb": 3720, "score_of_the_acc": -0.7994, "final_rank": 11 }, { "submission_id": "aoj_1241_8807879", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <cmath>\n\nconst int MAX_N = 1000000;\nconst int MAX_K = 5;\n\nint dp[MAX_N][MAX_K];\n\nint main() {\n int n;\n while (~scanf(\"%d\", &n)) {\n if (n == 0)\n break;\n memset(dp, 0, sizeof(dp));\n dp[0][0] = 1;\n for (int i = 1; i <= sqrt(n); i++) {\n for (int k = 1; k <= 4; k++) {\n for (int j = i * i; j <= n; j++) {\n dp[j][k] += dp[j - i * i][k - 1];\n }\n }\n }\n printf(\"%d\\n\", dp[n][4] + dp[n][3] + dp[n][2] + dp[n][1]);\n }\n}", "accuracy": 1, "time_ms": 1630, "memory_kb": 22212, "score_of_the_acc": -0.9651, "final_rank": 14 }, { "submission_id": "aoj_1241_8396148", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint sum(long long n, int m, long long ini){\n if(n == 0) return 1;\n if(m == 0) return 0;\n int res = 0;\n for(long long i=ini;i*i<=n;i++){\n res += sum(n-i*i, m-1, i);\n }\n return res;\n}\nint main(){\n long long n;\n while(cin >> n, n){\n cout << sum(n, 4, 1) << endl;\n }\n return(0);\n}", "accuracy": 1, "time_ms": 1920, "memory_kb": 2956, "score_of_the_acc": -0.5536, "final_rank": 10 } ]
aoj_1247_cpp
Problem H: Monster Trap Once upon a time when people still believed in magic, there was a great wizard Aranyaka Gondlir. After twenty years of hard training in a deep forest, he had finally mastered ultimate magic, and decided to leave the forest for his home. Arriving at his home village, Aranyaka was very surprised at the extraordinary desolation. A gloom had settled over the village. Even the whisper of the wind could scare villagers. It was a mere shadow of what it had been. What had happened? Soon he recognized a sure sign of an evil monster that is immortal. Even the great wizard could not kill it, and so he resolved to seal it with magic. Aranyaka could cast a spell to create a monster trap: once he had drawn a line on the ground with his magic rod, the line would function as a barrier wall that any monster could not get over. Since he could only draw straight lines, he had to draw several lines to complete a monster trap, i.e., magic barrier walls enclosing the monster. If there was a gap between barrier walls, the monster could easily run away through the gap. For instance, a complete monster trap without any gaps is built by the barrier walls in the left figure, where “M” indicates the position of the monster. In contrast, the barrier walls in the right figure have a loophole, even though it is almost complete. Your mission is to write a program to tell whether or not the wizard has successfully sealed the monster. Input The input consists of multiple data sets, each in the following format. n x 1 y 1 x' 1 y' 1 x 2 y 2 x' 2 y' 2 ... x n y n x' n y' n The first line of a data set contains a positive integer n, which is the number of the line segments drawn by the wizard. Each of the following n input lines contains four integers x , y , x' , and y' , which represent the x - and y -coordinates of two points ( x , y ) and ( x' , y' ) connected by a line segment. You may assume that all line segments have non-zero lengths. You may also assume that n is less than or equal to 100 and that all coordinates are between -50 and 50, inclusive. For your convenience, the coordinate system is arranged so that the monster is always on the origin (0, 0). The wizard never draws lines crossing (0, 0). You may assume that any two line segments have at most one intersection point and that no three line segments share the same intersection point. You may also assume that the distance between any two intersection points is greater than 10 -5 . An input line containing a zero indicates the end of the input. Output For each data set, print “yes” or “no” in a line. If a monster trap is completed, print “yes”. Otherwise, i.e., if there is a loophole, print “no”. Sample Input 8 -7 9 6 9 -5 5 6 5 -10 -5 10 -5 -6 9 -9 -6 6 9 9 -6 -1 -2 -3 10 1 -2 3 10 -2 -3 2 -3 8 -7 9 5 7 -5 5 6 5 -10 -5 10 -5 -6 9 -9 -6 6 9 9 -6 -1 -2 -3 10 1 -2 3 10 -2 -3 2 -3 0 Output for the Sample Input yes no
[ { "submission_id": "aoj_1247_8388160", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 998244353\n//#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 30005\n\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n};\n\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\n\nint N;\nLine line[SIZE];\nPoint point[SIZE];\nvector<Point> V[SIZE];\nvector<int> G[SIZE],ON_SEG[SIZE],CONTAIN[SIZE],EDGES;\nset<int> SET;\nPolygon POL;\nbool CATCH,DEL[SIZE],visited[SIZE];\nmap<pair<int,int>,int> MAP;\nint numE = 0,numDEG[SIZE];\nmap<int,pair<int,int>> REV;\n\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//■■直線ではなく、線分の交差判定■■\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n//線分と線分の距離\ndouble getDistance(Line A,Line B){\n\tif(is_Cross(A,B))return 0.0;\n\treturn min(min(getDistanceSP(A,B.p[0]),getDistanceSP(A,B.p[1])),\n\t\t\tmin(getDistanceSP(B,A.p[0]),getDistanceSP(B,A.p[1])));\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//2つのvectorがなすラジアンを求める関数\ndouble calc_rad(Vector vec1,Vector vec2){\n\n\tdouble tmp = dot(vec1,vec2)/(abs(vec1)*abs(vec2));\n\n\tif(fabs(tmp+1.0) < EPS){\n\n\t\treturn M_PI;\n\t}\n\n\tif(fabs(tmp-1.0) < EPS){\n\n\t\treturn 0.0;\n\t}\n\n\treturn acos(dot(vec1,vec2)/(abs(vec1)*abs(vec2)));\n}\n\n//3点がなすラジアンを求める関数(ccw(base,a,b) == CCW)\ndouble calc_rad(Point base,Point a,Point b){\n\n\tVector vec1 = b-base;\n\tVector vec2 = a-base;\n\n\treturn calc_rad(vec1,vec2);\n}\n\n\n/*\n * ■辺始まり辺終わりにするとWAする\n * 点始まり点終わりにする、ただし途中で訪問した辺は再訪しない■*\n * */\nvoid dfs(int pre,int node){\n\n\tif(CATCH)return;\n\n\tPoint pre_p = point[pre];\n\tPoint now = point[node];\n\n\tdouble mini = BIG_NUM;\n\tint ind = -1;\n\n\tfor(int i = 0; i < G[node].size(); i++){\n\t\tint adj = G[node][i];\n\t\tif(adj == pre)continue;\n\n\t\tPoint next = point[adj];\n\n\t\tdouble tmp_rad;\n\t\tif(ccw(now,pre_p,next) == CLOCKWISE){\n\n\t\t\ttmp_rad = calc_rad(now,next,pre_p);\n\t\t\ttmp_rad = 2*M_PI-tmp_rad;\n\t\t}else{\n\n\t\t\ttmp_rad = calc_rad(now,pre_p,next);\n\t\t}\n\n\n\t\tif(mini > tmp_rad+EPS){\n\n\t\t\tmini = tmp_rad;\n\t\t\tind = i;\n\t\t}\n\t}\n\n\tif(ind == -1)return;\n\n\tint next = G[node][ind];\n\tint next_e_ind = MAP[make_pair(node,G[node][ind])];\n\n\tif(SET.count(next) > 0){\n\n\t\tEDGES.push_back(next_e_ind);\n\n\t\tCATCH = true;\n\t\t//図形が完成した場合、訪問済みの辺は再訪しない\n\t\tfor(int i = 0; i < EDGES.size(); i++){\n\n\t\t\tvisited[EDGES[i]] = true;\n\t\t}\n\n\t\tPolygon work;\n\t\t//■■最初にnextに到達するまでの点は削除する\n\t\tbool FLG = false;\n\t\tfor(int i = 0; i < POL.size(); i++){\n\t\t\tif(POL[i] == point[next]){\n\n\t\t\t\tFLG = true;\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\twork.push_back(POL[i]);\n\t\t}\n\n\t\tPOL.clear();\n\t\tPOL = work;\n\n\t\treturn;\n\t}\n\n\tif(visited[next_e_ind])return;\n\n\tSET.insert(G[node][ind]);\n\tPOL.push_back(point[G[node][ind]]);\n\tEDGES.push_back(next_e_ind);\n\tdfs(node,G[node][ind]);\n}\n\n//点のradを求める関数\ndouble calc_rad(Point p){\n\n\tif(p.y == 0){\n\n\t\tif(p.x > 0){\n\n\t\t\treturn 0;\n\n\t\t}else{ //p.x < 0\n\n\t\t\treturn M_PI;\n\t\t}\n\n\t}else if(p.x == 0){\n\n\t\tif(p.y > 0){\n\n\t\t\treturn M_PI/2.0;\n\t\t}else{\n\n\n\t\t\treturn 3*M_PI/2.0;\n\t\t}\n\n\t}else{\n\n\t\tdouble base = atan(fabs(p.y)/fabs(p.x));\n\n\t\tif(p.x > 0){\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn base;\n\n\t\t\t}else{ //p.y < 0\n\n\t\t\t\treturn 2*M_PI-base;\n\t\t\t}\n\n\t\t}else{ //p.x < 0\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn M_PI-base;\n\n\t\t\t}else{\n\n\t\t\t\treturn base+M_PI;\n\t\t\t}\n\t\t}\n\t}\n}\n\n\nvoid func(){\n\n\tint num_point = 0;\n\tnumE = 0;\n\n\tMAP.clear();\n\tREV.clear();\n\n\tfor(int i = 0; i < SIZE; i++){\n\n\t\tV[i].clear();\n\t\tG[i].clear();\n\t\tON_SEG[i].clear();\n\t\tCONTAIN[i].clear();\n\t\tvisited[i] = false;\n\t}\n\n\tPoint base = Point(0,0);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf %lf %lf\",&line[i].p[0].x,&line[i].p[0].y,&line[i].p[1].x,&line[i].p[1].y);\n\t}\n\n\t//交点を全列挙\n\tfor(int i = 0; i < N-1; i++){\n\t\tfor(int k = i+1; k < N; k++){\n\t\t\tif(!is_Cross(line[i],line[k]))continue;\n\n\t\t\tPoint cross_p = calc_Cross_Point(line[i],line[k]);\n\n\t\t\tbool FLG = true;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == cross_p){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\t//辺が持つ点の番号を保存\n\t\t\tCONTAIN[i].push_back(num_point);\n\t\t\tCONTAIN[k].push_back(num_point);\n\n\t\t\t//どの辺の上に乗っているか\n\t\t\tON_SEG[num_point].push_back(i);\n\t\t\tON_SEG[num_point].push_back(k);\n\n\t\t\tpoint[num_point++] = cross_p;\n\t\t\tV[i].push_back(cross_p);\n\t\t\tV[k].push_back(cross_p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\n\t\tDEL[i] = false;\n\t}\n\n\n\t//■■交点数が1なら行き止まりなので点を削除\n\tqueue<int> que;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tnumDEG[i] = V[i].size();\n\n\t\tif(numDEG[i] == 1){\n\n\t\t\tint ind = CONTAIN[i][0];\n\n\t\t\tDEL[ind] = true; //点を削除\n\t\t\tque.push(ind);\n\t\t\tnumDEG[i] = 0;\n\t\t}\n\t}\n\n\twhile(!que.empty()){\n\n\t\tint ind = que.front(); //消す点番号\n\t\tque.pop();\n\n\t\tfor(int k = 0; k < ON_SEG[ind].size(); k++){\n\n\t\t\tint seg = ON_SEG[ind][k]; //消す点が含まれている辺番号\n\t\t\tif(numDEG[seg] == 0)continue;\n\n\t\t\tnumDEG[seg]--;\n\t\t\tif(numDEG[seg] == 1){ //■次数が0になった\n\t\t\t\tfor(int a = 0; a < CONTAIN[seg].size(); a++){ //残っている1点を探す\n\n\t\t\t\t\tint tmp_ind = CONTAIN[seg][a]; //点番号\n\t\t\t\t\tif(DEL[tmp_ind])continue;\n\n\t\t\t\t\tDEL[tmp_ind] = true;\n\t\t\t\t\tnumDEG[seg] = 0;\n\t\t\t\t\tque.push(tmp_ind);\n\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(V[i].size() <= 1)continue;\n\n\t\tsort(V[i].begin(),V[i].end());\n\n\t\tvector<int> vec; //点番号を並び順に格納\n\n\t\tfor(int k = 0; k < V[i].size(); k++){\n\t\t\tint ind = -1;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == V[i][k]){\n\n\t\t\t\t\tind = a;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tvec.push_back(ind);\n\t\t}\n\n\t\tvector<int> work;\n\t\tfor(int k = 0; k < vec.size(); k++){\n\t\t\tif(!DEL[vec[k]]){\n\n\t\t\t\twork.push_back(vec[k]);\n\t\t\t}\n\t\t}\n\n\t\tif(work.size() == 0)continue;\n\n\t\tfor(int k = 0; k < work.size()-1; k++){\n\n\t\t\tint p = work[k];\n\t\t\tint q = work[k+1];\n\n\t\t\t//■辺に向きをつける\n\t\t\tREV[numE] = make_pair(p,q);\n\t\t\tMAP[make_pair(p,q)] = numE++;\n\n\t\t\tREV[numE] = make_pair(q,p);\n\t\t\tMAP[make_pair(q,p)] = numE++;\n\n\t\t\tG[p].push_back(q);\n\t\t\tG[q].push_back(p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\t\tif(G[i].size() == 0)continue;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tint e_ind = MAP[make_pair(i,G[i][k])];\n\t\t\tif(visited[e_ind])continue;\n\n\t\t\tPOL.clear();\n\t\t\tSET.clear();\n\t\t\tEDGES.clear();\n\n\t\t\tPOL.push_back(point[i]);\n\t\t\tPOL.push_back(point[G[i][k]]);\n\n\t\t\tSET.insert(i);\n\t\t\tSET.insert(G[i][k]); //最初の2点を全探索\n\n\t\t\tEDGES.push_back(e_ind);\n\n\t\t\tCATCH = false;\n\t\t\tdfs(i,G[i][k]);\n\t\t\tif(CATCH){\n\n\n\t\t\t\tif(contains(POL,base) == 2){\n\n\t\t\t\t\tprintf(\"yes\\n\");\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"no\\n\");\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 11348, "score_of_the_acc": -0.8996, "final_rank": 4 }, { "submission_id": "aoj_1247_8388148", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 998244353\n//#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 30005\n\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n};\n\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\n\nint N;\nLine line[SIZE];\nPoint point[SIZE];\nvector<Point> V[SIZE];\nvector<int> G[SIZE],ON_SEG[SIZE],CONTAIN[SIZE],EDGES;\nset<int> SET;\nPolygon POL;\nbool CATCH,DEL[SIZE],visited[SIZE];\nmap<pair<int,int>,int> MAP;\nint numE = 0,numDEG[SIZE];\nmap<int,pair<int,int>> REV;\n\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//■■直線ではなく、線分の交差判定■■\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n//線分と線分の距離\ndouble getDistance(Line A,Line B){\n\tif(is_Cross(A,B))return 0.0;\n\treturn min(min(getDistanceSP(A,B.p[0]),getDistanceSP(A,B.p[1])),\n\t\t\tmin(getDistanceSP(B,A.p[0]),getDistanceSP(B,A.p[1])));\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//2つのvectorがなすラジアンを求める関数\ndouble calc_rad(Vector vec1,Vector vec2){\n\n\tdouble tmp = dot(vec1,vec2)/(abs(vec1)*abs(vec2));\n\n\tif(fabs(tmp+1.0) < EPS){\n\n\t\treturn M_PI;\n\t}\n\n\tif(fabs(tmp-1.0) < EPS){\n\n\t\treturn 0.0;\n\t}\n\n\treturn acos(dot(vec1,vec2)/(abs(vec1)*abs(vec2)));\n}\n\n//3点がなすラジアンを求める関数(ccw(base,a,b) == CCW)\ndouble calc_rad(Point base,Point a,Point b){\n\n\tVector vec1 = b-base;\n\tVector vec2 = a-base;\n\n\treturn calc_rad(vec1,vec2);\n}\n\n\n/*\n * ■辺始まり辺終わりにするとWAする\n * 点始まり点終わりにする、ただし途中で訪問した辺は再訪しない■*\n * */\nvoid dfs(int pre,int node){\n\n\tif(CATCH)return;\n\n\tPoint pre_p = point[pre];\n\tPoint now = point[node];\n\n\tdouble mini = BIG_NUM;\n\tint ind = -1;\n\n\tfor(int i = 0; i < G[node].size(); i++){\n\t\tint adj = G[node][i];\n\t\tif(adj == pre)continue;\n\n\t\tPoint next = point[adj];\n\n\t\tdouble tmp_rad;\n\t\tif(ccw(now,pre_p,next) == CLOCKWISE){\n\n\t\t\ttmp_rad = calc_rad(now,next,pre_p);\n\t\t\ttmp_rad = 2*M_PI-tmp_rad;\n\t\t}else{\n\n\t\t\ttmp_rad = calc_rad(now,pre_p,next);\n\t\t}\n\n\n\t\tif(mini > tmp_rad+EPS){\n\n\t\t\tmini = tmp_rad;\n\t\t\tind = i;\n\t\t}\n\t}\n\n\tif(ind == -1)return;\n\n\tint next = G[node][ind];\n\tint next_e_ind = MAP[make_pair(node,G[node][ind])];\n\n\tif(SET.count(next) > 0){\n\n\t\tEDGES.push_back(next_e_ind);\n\n\t\tCATCH = true;\n\t\t//図形が完成した場合、訪問済みの辺は再訪しない\n\t\tfor(int i = 0; i < EDGES.size(); i++){\n\n\t\t\tvisited[EDGES[i]] = true;\n\t\t}\n\n\t\tPolygon work;\n\t\t//■■最初にnextに到達するまでの点は削除する\n\t\tbool FLG = false;\n\t\tfor(int i = 0; i < POL.size(); i++){\n\t\t\tif(POL[i] == point[next]){\n\n\t\t\t\tFLG = true;\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\twork.push_back(POL[i]);\n\t\t}\n\n\t\tPOL.clear();\n\t\tPOL = work;\n\n\t\treturn;\n\t}\n\n\tif(visited[next_e_ind])return;\n\n\tSET.insert(G[node][ind]);\n\tPOL.push_back(point[G[node][ind]]);\n\tEDGES.push_back(next_e_ind);\n\tdfs(node,G[node][ind]);\n}\n\n//点のradを求める関数\ndouble calc_rad(Point p){\n\n\tif(p.y == 0){\n\n\t\tif(p.x > 0){\n\n\t\t\treturn 0;\n\n\t\t}else{ //p.x < 0\n\n\t\t\treturn M_PI;\n\t\t}\n\n\t}else if(p.x == 0){\n\n\t\tif(p.y > 0){\n\n\t\t\treturn M_PI/2.0;\n\t\t}else{\n\n\n\t\t\treturn 3*M_PI/2.0;\n\t\t}\n\n\t}else{\n\n\t\tdouble base = atan(fabs(p.y)/fabs(p.x));\n\n\t\tif(p.x > 0){\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn base;\n\n\t\t\t}else{ //p.y < 0\n\n\t\t\t\treturn 2*M_PI-base;\n\t\t\t}\n\n\t\t}else{ //p.x < 0\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn M_PI-base;\n\n\t\t\t}else{\n\n\t\t\t\treturn base+M_PI;\n\t\t\t}\n\t\t}\n\t}\n}\n\n\nvoid func(){\n\n\tint num_point = 0;\n\tnumE = 0;\n\n\tMAP.clear();\n\tREV.clear();\n\n\tfor(int i = 0; i < SIZE; i++){\n\n\t\tV[i].clear();\n\t\tG[i].clear();\n\t\tON_SEG[i].clear();\n\t\tCONTAIN[i].clear();\n\t\tvisited[i] = false;\n\t}\n\n\tPoint base = Point(0,0);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf %lf %lf\",&line[i].p[0].x,&line[i].p[0].y,&line[i].p[1].x,&line[i].p[1].y);\n\t}\n\n\t//交点を全列挙\n\tfor(int i = 0; i < N-1; i++){\n\t\tfor(int k = i+1; k < N; k++){\n\t\t\tif(!is_Cross(line[i],line[k]))continue;\n\n\t\t\tPoint cross_p = calc_Cross_Point(line[i],line[k]);\n\n\t\t\tbool FLG = true;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == cross_p){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\t//辺が持つ点の番号を保存\n\t\t\tCONTAIN[i].push_back(num_point);\n\t\t\tCONTAIN[k].push_back(num_point);\n\n\t\t\t//どの辺の上に乗っているか\n\t\t\tON_SEG[num_point].push_back(i);\n\t\t\tON_SEG[num_point].push_back(k);\n\n\t\t\tpoint[num_point++] = cross_p;\n\t\t\tV[i].push_back(cross_p);\n\t\t\tV[k].push_back(cross_p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\n\t\tDEL[i] = false;\n\t}\n\n\n\t//■■交点数が1なら行き止まりなので点を削除\n\tqueue<int> que;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tnumDEG[i] = V[i].size();\n\n\t\tif(numDEG[i] == 1){\n\n\t\t\tint ind = CONTAIN[i][0];\n\n\t\t\tDEL[ind] = true; //点を削除\n\t\t\tque.push(ind);\n\t\t\tnumDEG[i] = 0;\n\t\t}\n\t}\n\n\twhile(!que.empty()){\n\n\t\tint ind = que.front(); //消す点番号\n\t\tque.pop();\n\n\t\tfor(int k = 0; k < ON_SEG[ind].size(); k++){\n\n\t\t\tint seg = ON_SEG[ind][k]; //消す点が含まれている辺番号\n\t\t\tif(numDEG[seg] == 0)continue;\n\n\t\t\tnumDEG[seg]--;\n\t\t\tif(numDEG[seg] == 1){ //■次数が0になった\n\t\t\t\tfor(int a = 0; a < CONTAIN[seg].size(); a++){ //残っている1点を探す\n\n\t\t\t\t\tint tmp_ind = CONTAIN[seg][a]; //点番号\n\t\t\t\t\tif(DEL[tmp_ind])continue;\n\n\t\t\t\t\tDEL[tmp_ind] = true;\n\t\t\t\t\tnumDEG[seg] = 0;\n\t\t\t\t\tque.push(tmp_ind);\n\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(V[i].size() <= 1)continue;\n\n\t\tsort(V[i].begin(),V[i].end());\n\n\t\tvector<int> vec; //点番号を並び順に格納\n\n\t\tfor(int k = 0; k < V[i].size(); k++){\n\t\t\tint ind = -1;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == V[i][k]){\n\n\t\t\t\t\tind = a;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tvec.push_back(ind);\n\t\t}\n\n\t\tvector<int> work;\n\t\tfor(int k = 0; k < vec.size(); k++){\n\t\t\tif(!DEL[vec[k]]){\n\n\t\t\t\twork.push_back(vec[k]);\n\t\t\t}\n\t\t}\n\n\t\tif(work.size() == 0)continue;\n\n\t\tfor(int k = 0; k < work.size()-1; k++){\n\n\t\t\tint p = work[k];\n\t\t\tint q = work[k+1];\n\n\t\t\t//■辺に向きをつける\n\t\t\tREV[numE] = make_pair(p,q);\n\t\t\tMAP[make_pair(p,q)] = numE++;\n\n\t\t\tREV[numE] = make_pair(q,p);\n\t\t\tMAP[make_pair(q,p)] = numE++;\n\n\t\t\tG[p].push_back(q);\n\t\t\tG[q].push_back(p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\t\tif(G[i].size() == 0)continue;\n\n\t\tvector<pair<double,int>> work;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tPoint adj = point[G[i][k]]-point[i]; //■注意\n\t\t\tdouble tmp_rad = calc_rad(adj);\n\t\t\twork.push_back(make_pair(tmp_rad,k));\n\t\t}\n\n\t\tsort(work.begin(),work.end());\n\n\t\tint mini_ind = work[0].second;\n\t\tint maxi_ind = work.back().second;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\t\t\tif(k != mini_ind && k != maxi_ind)continue; //■■最も外側の隣接でないならSKIP\n\n\t\t\tint e_ind = MAP[make_pair(i,G[i][k])];\n\t\t\tif(visited[e_ind])continue;\n\n\t\t\tPOL.clear();\n\t\t\tSET.clear();\n\t\t\tEDGES.clear();\n\n\t\t\tPOL.push_back(point[i]);\n\t\t\tPOL.push_back(point[G[i][k]]);\n\n\t\t\tSET.insert(i);\n\t\t\tSET.insert(G[i][k]); //最初の2点を全探索\n\n\t\t\tEDGES.push_back(e_ind);\n\n\t\t\tCATCH = false;\n\t\t\tdfs(i,G[i][k]);\n\t\t\tif(CATCH){\n\n\n\t\t\t\tif(contains(POL,base) == 2){\n\n\t\t\t\t\tprintf(\"yes\\n\");\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"no\\n\");\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 11396, "score_of_the_acc": -0.9035, "final_rank": 5 }, { "submission_id": "aoj_1247_8387786", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 998244353\n//#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 30005\n\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n};\n\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\n\nint N;\nLine line[SIZE];\nPoint point[SIZE];\nvector<Point> V[SIZE];\nvector<int> G[SIZE],ON_SEG[SIZE],CONTAIN[SIZE],EDGES;\nset<int> SET;\nPolygon POL;\nbool CATCH,DEL[SIZE],visited[SIZE];\nmap<pair<int,int>,int> MAP;\nint numE = 0,numDEG[SIZE];\nmap<int,pair<int,int>> REV;\n\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//■■直線ではなく、線分の交差判定■■\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n//線分と線分の距離\ndouble getDistance(Line A,Line B){\n\tif(is_Cross(A,B))return 0.0;\n\treturn min(min(getDistanceSP(A,B.p[0]),getDistanceSP(A,B.p[1])),\n\t\t\tmin(getDistanceSP(B,A.p[0]),getDistanceSP(B,A.p[1])));\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//2つのvectorがなすラジアンを求める関数\ndouble calc_rad(Vector vec1,Vector vec2){\n\n\tdouble tmp = dot(vec1,vec2)/(abs(vec1)*abs(vec2));\n\n\tif(fabs(tmp+1.0) < EPS){\n\n\t\treturn M_PI;\n\t}\n\n\tif(fabs(tmp-1.0) < EPS){\n\n\t\treturn 0.0;\n\t}\n\n\treturn acos(dot(vec1,vec2)/(abs(vec1)*abs(vec2)));\n}\n\n//3点がなすラジアンを求める関数(ccw(base,a,b) == CCW)\ndouble calc_rad(Point base,Point a,Point b){\n\n\tVector vec1 = b-base;\n\tVector vec2 = a-base;\n\n\treturn calc_rad(vec1,vec2);\n}\n\n\n/*\n * ■辺始まり辺終わりにするとWAする\n * 点始まり点終わりにする、ただし途中で訪問した辺は再訪しない■*\n * */\nvoid dfs(int pre,int node){\n\n\tif(CATCH)return;\n\n\tPoint pre_p = point[pre];\n\tPoint now = point[node];\n\n\tdouble maxi = -BIG_NUM;\n\tint ind = -1;\n\n\tfor(int i = 0; i < G[node].size(); i++){\n\t\tint adj = G[node][i];\n\t\tif(adj == pre)continue;\n\n\t\tPoint next = point[adj];\n\n\t\tdouble tmp_rad = calc_rad(now,pre_p,next);\n\n\t\tif(maxi+EPS < tmp_rad){\n\n\t\t\tmaxi = tmp_rad;\n\t\t\tind = i;\n\t\t}\n\t}\n\n\tif(ind == -1)return;\n\n\tint next = G[node][ind];\n\tint next_e_ind = MAP[make_pair(node,G[node][ind])];\n\n\tif(SET.count(next) > 0){\n\n\t\tEDGES.push_back(next_e_ind);\n\n\t\tCATCH = true;\n\t\t//図形が完成した場合、訪問済みの辺は再訪しない\n\t\tfor(int i = 0; i < EDGES.size(); i++){\n\n\t\t\tvisited[EDGES[i]] = true;\n\t\t}\n\n\t\tPolygon work;\n\t\t//■■最初にnextに到達するまでの点は削除する\n\t\tbool FLG = false;\n\t\tfor(int i = 0; i < POL.size(); i++){\n\t\t\tif(POL[i] == point[next]){\n\n\t\t\t\tFLG = true;\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\twork.push_back(POL[i]);\n\t\t}\n\n\t\tPOL.clear();\n\t\tPOL = work;\n\n\t\treturn;\n\t}\n\n\tif(visited[next_e_ind])return;\n\n\tSET.insert(G[node][ind]);\n\tPOL.push_back(point[G[node][ind]]);\n\tEDGES.push_back(next_e_ind);\n\tdfs(node,G[node][ind]);\n}\n\n//点のradを求める関数\ndouble calc_rad(Point p){\n\n\tif(p.y == 0){\n\n\t\tif(p.x > 0){\n\n\t\t\treturn 0;\n\n\t\t}else{ //p.x < 0\n\n\t\t\treturn M_PI;\n\t\t}\n\n\t}else if(p.x == 0){\n\n\t\tif(p.y > 0){\n\n\t\t\treturn M_PI/2.0;\n\t\t}else{\n\n\n\t\t\treturn 3*M_PI/2.0;\n\t\t}\n\n\t}else{\n\n\t\tdouble base = atan(fabs(p.y)/fabs(p.x));\n\n\t\tif(p.x > 0){\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn base;\n\n\t\t\t}else{ //p.y < 0\n\n\t\t\t\treturn 2*M_PI-base;\n\t\t\t}\n\n\t\t}else{ //p.x < 0\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn M_PI-base;\n\n\t\t\t}else{\n\n\t\t\t\treturn base+M_PI;\n\t\t\t}\n\t\t}\n\t}\n}\n\n\nvoid func(){\n\n\tint num_point = 0;\n\tnumE = 0;\n\n\tMAP.clear();\n\tREV.clear();\n\n\tfor(int i = 0; i < SIZE; i++){\n\n\t\tV[i].clear();\n\t\tG[i].clear();\n\t\tON_SEG[i].clear();\n\t\tCONTAIN[i].clear();\n\t\tvisited[i] = false;\n\t}\n\n\tPoint base = Point(0,0);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf %lf %lf\",&line[i].p[0].x,&line[i].p[0].y,&line[i].p[1].x,&line[i].p[1].y);\n\t}\n\n\t//交点を全列挙\n\tfor(int i = 0; i < N-1; i++){\n\t\tfor(int k = i+1; k < N; k++){\n\t\t\tif(!is_Cross(line[i],line[k]))continue;\n\n\t\t\tPoint cross_p = calc_Cross_Point(line[i],line[k]);\n\n\t\t\tbool FLG = true;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == cross_p){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\t//辺が持つ点の番号を保存\n\t\t\tCONTAIN[i].push_back(num_point);\n\t\t\tCONTAIN[k].push_back(num_point);\n\n\t\t\t//どの辺の上に乗っているか\n\t\t\tON_SEG[num_point].push_back(i);\n\t\t\tON_SEG[num_point].push_back(k);\n\n\t\t\tpoint[num_point++] = cross_p;\n\t\t\tV[i].push_back(cross_p);\n\t\t\tV[k].push_back(cross_p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\n\t\tDEL[i] = false;\n\t}\n\n\n\t//■■交点数が1なら行き止まりなので点を削除\n\tqueue<int> que;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tnumDEG[i] = V[i].size();\n\n\t\tif(numDEG[i] == 1){\n\n\t\t\tint ind = CONTAIN[i][0];\n\n\t\t\tDEL[ind] = true; //点を削除\n\t\t\tque.push(ind);\n\t\t\tnumDEG[i] = 0;\n\t\t}\n\t}\n\n\twhile(!que.empty()){\n\n\t\tint ind = que.front(); //消す点番号\n\t\tque.pop();\n\n\t\tfor(int k = 0; k < ON_SEG[ind].size(); k++){\n\n\t\t\tint seg = ON_SEG[ind][k]; //消す点が含まれている辺番号\n\t\t\tif(numDEG[seg] == 0)continue;\n\n\t\t\tnumDEG[seg]--;\n\t\t\tif(numDEG[seg] == 1){ //■次数が0になった\n\t\t\t\tfor(int a = 0; a < CONTAIN[seg].size(); a++){ //残っている1点を探す\n\n\t\t\t\t\tint tmp_ind = CONTAIN[seg][a]; //点番号\n\t\t\t\t\tif(DEL[tmp_ind])continue;\n\n\t\t\t\t\tDEL[tmp_ind] = true;\n\t\t\t\t\tnumDEG[seg] = 0;\n\t\t\t\t\tque.push(tmp_ind);\n\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(V[i].size() <= 1)continue;\n\n\t\tsort(V[i].begin(),V[i].end());\n\n\t\tvector<int> vec; //点番号を並び順に格納\n\n\t\tfor(int k = 0; k < V[i].size(); k++){\n\t\t\tint ind = -1;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == V[i][k]){\n\n\t\t\t\t\tind = a;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tvec.push_back(ind);\n\t\t}\n\n\t\tvector<int> work;\n\t\tfor(int k = 0; k < vec.size(); k++){\n\t\t\tif(!DEL[vec[k]]){\n\n\t\t\t\twork.push_back(vec[k]);\n\t\t\t}\n\t\t}\n\n\t\tif(work.size() == 0)continue;\n\n\t\tfor(int k = 0; k < work.size()-1; k++){\n\n\t\t\tint p = work[k];\n\t\t\tint q = work[k+1];\n\n\t\t\t//■辺に向きをつける\n\t\t\tREV[numE] = make_pair(p,q);\n\t\t\tMAP[make_pair(p,q)] = numE++;\n\n\t\t\tREV[numE] = make_pair(q,p);\n\t\t\tMAP[make_pair(q,p)] = numE++;\n\n\t\t\tG[p].push_back(q);\n\t\t\tG[q].push_back(p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\t\tif(G[i].size() == 0)continue;\n\n\t\tvector<pair<double,int>> work;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tPoint adj = point[G[i][k]]-point[i]; //■注意\n\t\t\tdouble tmp_rad = calc_rad(adj);\n\t\t\twork.push_back(make_pair(tmp_rad,k));\n\t\t}\n\n\t\tsort(work.begin(),work.end());\n\n\t\tint mini_ind = work[0].second;\n\t\tint maxi_ind = work.back().second;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\t\t\tif(k != mini_ind && k != maxi_ind)continue; //■■最も外側の隣接でないならSKIP\n\n\t\t\tint e_ind = MAP[make_pair(i,G[i][k])];\n\t\t\tif(visited[e_ind])continue;\n\n\t\t\tPOL.clear();\n\t\t\tSET.clear();\n\t\t\tEDGES.clear();\n\n\t\t\tPOL.push_back(point[i]);\n\t\t\tPOL.push_back(point[G[i][k]]);\n\n\t\t\tSET.insert(i);\n\t\t\tSET.insert(G[i][k]); //最初の2点を全探索\n\n\t\t\tEDGES.push_back(e_ind);\n\n\t\t\tCATCH = false;\n\t\t\tdfs(i,G[i][k]);\n\t\t\tif(CATCH){\n\n\n\t\t\t\tif(contains(POL,base) == 2){\n\n\t\t\t\t\tprintf(\"yes\\n\");\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"no\\n\");\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 11384, "score_of_the_acc": -0.9204, "final_rank": 6 }, { "submission_id": "aoj_1247_8387742", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 998244353\n//#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 30005\n\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n};\n\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\n\nint N;\nLine line[SIZE];\nPoint point[SIZE];\nvector<Point> V[SIZE];\nvector<int> G[SIZE],ON_SEG[SIZE],CONTAIN[SIZE],EDGES;\nset<int> SET;\nPolygon POL;\nbool CATCH,DEL[SIZE],visited[SIZE];\nmap<pair<int,int>,int> MAP;\nint numE = 0,numDEG[SIZE];\nmap<int,pair<int,int>> REV;\n\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//■■直線ではなく、線分の交差判定■■\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n//線分と線分の距離\ndouble getDistance(Line A,Line B){\n\tif(is_Cross(A,B))return 0.0;\n\treturn min(min(getDistanceSP(A,B.p[0]),getDistanceSP(A,B.p[1])),\n\t\t\tmin(getDistanceSP(B,A.p[0]),getDistanceSP(B,A.p[1])));\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//2つのvectorがなすラジアンを求める関数\ndouble calc_rad(Vector vec1,Vector vec2){\n\n\tdouble tmp = dot(vec1,vec2)/(abs(vec1)*abs(vec2));\n\n\tif(fabs(tmp+1.0) < EPS){\n\n\t\treturn M_PI;\n\t}\n\n\tif(fabs(tmp-1.0) < EPS){\n\n\t\treturn 0.0;\n\t}\n\n\treturn acos(dot(vec1,vec2)/(abs(vec1)*abs(vec2)));\n}\n\n//3点がなすラジアンを求める関数(ccw(base,a,b) == CCW)\ndouble calc_rad(Point base,Point a,Point b){\n\n\tVector vec1 = b-base;\n\tVector vec2 = a-base;\n\n\treturn calc_rad(vec1,vec2);\n}\n\n\n/*\n * ■辺始まり辺終わりにするとWAする\n * 点始まり点終わりにする、ただし途中で訪問した辺は再訪しない■*\n * */\nvoid dfs(int pre,int node){\n\n\tif(CATCH)return;\n\n\tPoint pre_p = point[pre];\n\tPoint now = point[node];\n\n\tdouble maxi = -BIG_NUM;\n\tint ind = -1;\n\n\tfor(int i = 0; i < G[node].size(); i++){\n\t\tint adj = G[node][i];\n\t\tif(adj == pre)continue;\n\n\t\tPoint next = point[adj];\n\n\t\tdouble tmp_rad = calc_rad(now,pre_p,next);\n\n\t\tif(maxi+EPS < tmp_rad){\n\n\t\t\tmaxi = tmp_rad;\n\t\t\tind = i;\n\t\t}\n\t}\n\n\tif(ind == -1)return;\n\n\tint next = G[node][ind];\n\tint next_e_ind = MAP[make_pair(node,G[node][ind])];\n\n\tif(SET.count(next) > 0){\n\n\t\tCATCH = true;\n\t\t//図形が完成した場合、訪問済みの辺は再訪しない\n\t\tfor(int i = 0; i < EDGES.size(); i++){\n\n\t\t\tvisited[EDGES[i]] = true;\n\t\t}\n\n\t\tPolygon work;\n\t\t//■■最初にnextに到達するまでの点は削除する\n\t\tbool FLG = false;\n\t\tfor(int i = 0; i < POL.size(); i++){\n\t\t\tif(POL[i] == point[next]){\n\n\t\t\t\tFLG = true;\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\twork.push_back(POL[i]);\n\t\t}\n\n\t\tPOL.clear();\n\t\tPOL = work;\n\n\t\treturn;\n\t}\n\n\tif(visited[next_e_ind])return;\n\n\tSET.insert(G[node][ind]);\n\tPOL.push_back(point[G[node][ind]]);\n\t//EDGES.push_back(next_e_ind);\n\tdfs(node,G[node][ind]);\n}\n\n//点のradを求める関数\ndouble calc_rad(Point p){\n\n\tif(p.y == 0){\n\n\t\tif(p.x > 0){\n\n\t\t\treturn 0;\n\n\t\t}else{ //p.x < 0\n\n\t\t\treturn M_PI;\n\t\t}\n\n\t}else if(p.x == 0){\n\n\t\tif(p.y > 0){\n\n\t\t\treturn M_PI/2.0;\n\t\t}else{\n\n\n\t\t\treturn 3*M_PI/2.0;\n\t\t}\n\n\t}else{\n\n\t\tdouble base = atan(fabs(p.y)/fabs(p.x));\n\n\t\tif(p.x > 0){\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn base;\n\n\t\t\t}else{ //p.y < 0\n\n\t\t\t\treturn 2*M_PI-base;\n\t\t\t}\n\n\t\t}else{ //p.x < 0\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn M_PI-base;\n\n\t\t\t}else{\n\n\t\t\t\treturn base+M_PI;\n\t\t\t}\n\t\t}\n\t}\n}\n\n\nvoid func(){\n\n\tint num_point = 0;\n\tnumE = 0;\n\n\tMAP.clear();\n\tREV.clear();\n\n\tfor(int i = 0; i < SIZE; i++){\n\n\t\tV[i].clear();\n\t\tG[i].clear();\n\t\tON_SEG[i].clear();\n\t\tCONTAIN[i].clear();\n\t\tvisited[i] = false;\n\t}\n\n\tPoint base = Point(0,0);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf %lf %lf\",&line[i].p[0].x,&line[i].p[0].y,&line[i].p[1].x,&line[i].p[1].y);\n\t}\n\n\t//交点を全列挙\n\tfor(int i = 0; i < N-1; i++){\n\t\tfor(int k = i+1; k < N; k++){\n\t\t\tif(!is_Cross(line[i],line[k]))continue;\n\n\t\t\tPoint cross_p = calc_Cross_Point(line[i],line[k]);\n\n\t\t\tbool FLG = true;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == cross_p){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\t//辺が持つ点の番号を保存\n\t\t\tCONTAIN[i].push_back(num_point);\n\t\t\tCONTAIN[k].push_back(num_point);\n\n\t\t\t//どの辺の上に乗っているか\n\t\t\tON_SEG[num_point].push_back(i);\n\t\t\tON_SEG[num_point].push_back(k);\n\n\t\t\tpoint[num_point++] = cross_p;\n\t\t\tV[i].push_back(cross_p);\n\t\t\tV[k].push_back(cross_p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\n\t\tDEL[i] = false;\n\t}\n\n\n\t//■■交点数が1なら行き止まりなので点を削除\n\tqueue<int> que;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tnumDEG[i] = V[i].size();\n\n\t\tif(numDEG[i] == 1){\n\n\t\t\tint ind = CONTAIN[i][0];\n\n\t\t\tDEL[ind] = true; //点を削除\n\t\t\tque.push(ind);\n\t\t\tnumDEG[i] = 0;\n\t\t}\n\t}\n\n\twhile(!que.empty()){\n\n\t\tint ind = que.front(); //消す点番号\n\t\tque.pop();\n\n\t\tfor(int k = 0; k < ON_SEG[ind].size(); k++){\n\n\t\t\tint seg = ON_SEG[ind][k]; //消す点が含まれている辺番号\n\t\t\tif(numDEG[seg] == 0)continue;\n\n\t\t\tnumDEG[seg]--;\n\t\t\tif(numDEG[seg] == 1){ //■次数が0になった\n\t\t\t\tfor(int a = 0; a < CONTAIN[seg].size(); a++){ //残っている1点を探す\n\n\t\t\t\t\tint tmp_ind = CONTAIN[seg][a]; //点番号\n\t\t\t\t\tif(DEL[tmp_ind])continue;\n\n\t\t\t\t\tDEL[tmp_ind] = true;\n\t\t\t\t\tnumDEG[seg] = 0;\n\t\t\t\t\tque.push(tmp_ind);\n\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(V[i].size() <= 1)continue;\n\n\t\tsort(V[i].begin(),V[i].end());\n\n\t\tvector<int> vec; //点番号を並び順に格納\n\n\t\tfor(int k = 0; k < V[i].size(); k++){\n\t\t\tint ind = -1;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == V[i][k]){\n\n\t\t\t\t\tind = a;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tvec.push_back(ind);\n\t\t}\n\n\t\tvector<int> work;\n\t\tfor(int k = 0; k < vec.size(); k++){\n\t\t\tif(!DEL[vec[k]]){\n\n\t\t\t\twork.push_back(vec[k]);\n\t\t\t}\n\t\t}\n\n\t\tif(work.size() == 0)continue;\n\n\t\tfor(int k = 0; k < work.size()-1; k++){\n\n\t\t\tint p = work[k];\n\t\t\tint q = work[k+1];\n\n\t\t\t//■辺に向きをつける\n\t\t\tREV[numE] = make_pair(p,q);\n\t\t\tMAP[make_pair(p,q)] = numE++;\n\n\t\t\tREV[numE] = make_pair(q,p);\n\t\t\tMAP[make_pair(q,p)] = numE++;\n\n\t\t\tG[p].push_back(q);\n\t\t\tG[q].push_back(p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\t\tif(G[i].size() == 0)continue;\n\n\t\tvector<pair<double,int>> work;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tPoint adj = point[G[i][k]]-point[i]; //■注意\n\t\t\tdouble tmp_rad = calc_rad(adj);\n\t\t\twork.push_back(make_pair(tmp_rad,k));\n\t\t}\n\n\t\tsort(work.begin(),work.end());\n\n\t\tint mini_ind = work[0].second;\n\t\tint maxi_ind = work.back().second;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\t\t\tif(k != mini_ind && k != maxi_ind)continue; //■■最も外側の隣接でないならSKIP\n\n\t\t\tint e_ind = MAP[make_pair(i,G[i][k])];\n\t\t\tif(visited[e_ind])continue;\n\n\t\t\tPOL.clear();\n\t\t\tSET.clear();\n\t\t\tEDGES.clear();\n\n\t\t\tPOL.push_back(point[i]);\n\t\t\tPOL.push_back(point[G[i][k]]);\n\n\t\t\tSET.insert(i);\n\t\t\tSET.insert(G[i][k]); //最初の2点を全探索\n\n\t\t\tEDGES.push_back(e_ind);\n\n\t\t\tCATCH = false;\n\t\t\tdfs(i,G[i][k]);\n\t\t\tif(CATCH){\n\n\n\t\t\t\tif(contains(POL,base) == 2){\n\n\t\t\t\t\tprintf(\"yes\\n\");\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"no\\n\");\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 11244, "score_of_the_acc": -0.9337, "final_rank": 9 }, { "submission_id": "aoj_1247_8387201", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 998244353\n//#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 30005\n\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n};\n\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\n\nint N;\nLine line[SIZE];\nPoint point[SIZE];\nvector<Point> V[SIZE];\nvector<int> G[SIZE],ON_SEG[SIZE],CONTAIN[SIZE],EDGES;\nset<int> SET;\nPolygon POL;\nbool CATCH,DEL[SIZE],visited[SIZE];\nmap<pair<int,int>,int> MAP;\nint numE = 0,numDEG[SIZE];\nmap<int,pair<int,int>> REV;\n\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//■■直線ではなく、線分の交差判定■■\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n//線分と線分の距離\ndouble getDistance(Line A,Line B){\n\tif(is_Cross(A,B))return 0.0;\n\treturn min(min(getDistanceSP(A,B.p[0]),getDistanceSP(A,B.p[1])),\n\t\t\tmin(getDistanceSP(B,A.p[0]),getDistanceSP(B,A.p[1])));\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//2つのvectorがなすラジアンを求める関数\ndouble calc_rad(Vector vec1,Vector vec2){\n\n\tdouble tmp = dot(vec1,vec2)/(abs(vec1)*abs(vec2));\n\n\tif(fabs(tmp+1.0) < EPS){\n\n\t\treturn M_PI;\n\t}\n\n\tif(fabs(tmp-1.0) < EPS){\n\n\t\treturn 0.0;\n\t}\n\n\treturn acos(dot(vec1,vec2)/(abs(vec1)*abs(vec2)));\n}\n\n//3点がなすラジアンを求める関数(ccw(base,a,b) == CCW)\ndouble calc_rad(Point base,Point a,Point b){\n\n\tVector vec1 = b-base;\n\tVector vec2 = a-base;\n\n\treturn calc_rad(vec1,vec2);\n}\n\n\n/*\n * ■辺始まり辺終わりにするとWAする\n * 点始まり点終わりにする、ただし途中で訪問した辺は再訪しない■*\n * */\nvoid dfs(int pre,int node){\n\n\tif(CATCH)return;\n\n\tPoint pre_p = point[pre];\n\tPoint now = point[node];\n\n\tdouble maxi = -BIG_NUM;\n\tint ind = -1;\n\n\tfor(int i = 0; i < G[node].size(); i++){\n\t\tint adj = G[node][i];\n\t\tif(adj == pre)continue;\n\n\t\tPoint next = point[adj];\n\n\t\tdouble tmp_rad = calc_rad(now,pre_p,next);\n\n\t\tif(maxi+EPS < tmp_rad){\n\n\t\t\tmaxi = tmp_rad;\n\t\t\tind = i;\n\t\t}\n\t}\n\n\tif(ind == -1)return;\n\n\tint next = G[node][ind];\n\tif(SET.count(next) > 0){\n\n\t\tCATCH = true;\n\t\t//図形が完成した場合、訪問済みの辺は再訪しない\n\t\tfor(int i = 0; i < EDGES.size(); i++){\n\n\t\t\tvisited[EDGES[i]] = true;\n\t\t}\n\n\t\tPolygon work;\n\t\t//■■最初にnextに到達するまでの点は削除する\n\t\tbool FLG = false;\n\t\tfor(int i = 0; i < POL.size(); i++){\n\t\t\tif(POL[i] == point[next]){\n\n\t\t\t\tFLG = true;\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\twork.push_back(POL[i]);\n\t\t}\n\n\t\tPOL.clear();\n\t\tPOL = work;\n\n\t\treturn;\n\t}\n\tint next_e_ind = MAP[make_pair(node,G[node][ind])];\n\tif(visited[next_e_ind])return;\n\n\tSET.insert(G[node][ind]);\n\tPOL.push_back(point[G[node][ind]]);\n\tEDGES.push_back(next_e_ind);\n\tdfs(node,G[node][ind]);\n}\n\n//点のradを求める関数\ndouble calc_rad(Point p){\n\n\tif(p.y == 0){\n\n\t\tif(p.x > 0){\n\n\t\t\treturn 0;\n\n\t\t}else{ //p.x < 0\n\n\t\t\treturn M_PI;\n\t\t}\n\n\t}else if(p.x == 0){\n\n\t\tif(p.y > 0){\n\n\t\t\treturn M_PI/2.0;\n\t\t}else{\n\n\n\t\t\treturn 3*M_PI/2.0;\n\t\t}\n\n\t}else{\n\n\t\tdouble base = atan(fabs(p.y)/fabs(p.x));\n\n\t\tif(p.x > 0){\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn base;\n\n\t\t\t}else{ //p.y < 0\n\n\t\t\t\treturn 2*M_PI-base;\n\t\t\t}\n\n\t\t}else{ //p.x < 0\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn M_PI-base;\n\n\t\t\t}else{\n\n\t\t\t\treturn base+M_PI;\n\t\t\t}\n\t\t}\n\t}\n}\n\n\nvoid func(){\n\n\tint num_point = 0;\n\tnumE = 0;\n\n\tMAP.clear();\n\tREV.clear();\n\n\tfor(int i = 0; i < SIZE; i++){\n\n\t\tV[i].clear();\n\t\tG[i].clear();\n\t\tON_SEG[i].clear();\n\t\tCONTAIN[i].clear();\n\t\tvisited[i] = false;\n\t}\n\n\tPoint base = Point(0,0);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf %lf %lf\",&line[i].p[0].x,&line[i].p[0].y,&line[i].p[1].x,&line[i].p[1].y);\n\t}\n\n\t//交点を全列挙\n\tfor(int i = 0; i < N-1; i++){\n\t\tfor(int k = i+1; k < N; k++){\n\t\t\tif(!is_Cross(line[i],line[k]))continue;\n\n\t\t\tPoint cross_p = calc_Cross_Point(line[i],line[k]);\n\n\t\t\tbool FLG = true;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == cross_p){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\t//辺が持つ点の番号を保存\n\t\t\tCONTAIN[i].push_back(num_point);\n\t\t\tCONTAIN[k].push_back(num_point);\n\n\t\t\t//どの辺の上に乗っているか\n\t\t\tON_SEG[num_point].push_back(i);\n\t\t\tON_SEG[num_point].push_back(k);\n\n\t\t\tpoint[num_point++] = cross_p;\n\t\t\tV[i].push_back(cross_p);\n\t\t\tV[k].push_back(cross_p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\n\t\tDEL[i] = false;\n\t}\n\n\n\t//■■交点数が1なら行き止まりなので点を削除\n\tqueue<int> que;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tnumDEG[i] = V[i].size();\n\n\t\tif(numDEG[i] == 1){\n\n\t\t\tint ind = CONTAIN[i][0];\n\n\t\t\tDEL[ind] = true; //点を削除\n\t\t\tque.push(ind);\n\t\t\tnumDEG[i] = 0;\n\t\t}\n\t}\n\n\twhile(!que.empty()){\n\n\t\tint ind = que.front(); //消す点番号\n\t\tque.pop();\n\n\t\tfor(int k = 0; k < ON_SEG[ind].size(); k++){\n\n\t\t\tint seg = ON_SEG[ind][k]; //消す点が含まれている辺番号\n\t\t\tif(numDEG[seg] == 0)continue;\n\n\t\t\tnumDEG[seg]--;\n\t\t\tif(numDEG[seg] == 1){ //■次数が0になった\n\t\t\t\tfor(int a = 0; a < CONTAIN[seg].size(); a++){ //残っている1点を探す\n\n\t\t\t\t\tint tmp_ind = CONTAIN[seg][a]; //点番号\n\t\t\t\t\tif(DEL[tmp_ind])continue;\n\n\t\t\t\t\tDEL[tmp_ind] = true;\n\t\t\t\t\tnumDEG[seg] = 0;\n\t\t\t\t\tque.push(tmp_ind);\n\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(V[i].size() <= 1)continue;\n\n\t\tsort(V[i].begin(),V[i].end());\n\n\t\tvector<int> vec; //点番号を並び順に格納\n\n\t\tfor(int k = 0; k < V[i].size(); k++){\n\t\t\tint ind = -1;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == V[i][k]){\n\n\t\t\t\t\tind = a;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tvec.push_back(ind);\n\t\t}\n\n\t\tvector<int> work;\n\t\tfor(int k = 0; k < vec.size(); k++){\n\t\t\tif(!DEL[vec[k]]){\n\n\t\t\t\twork.push_back(vec[k]);\n\t\t\t}\n\t\t}\n\n\t\tif(work.size() == 0)continue;\n\n\t\tfor(int k = 0; k < work.size()-1; k++){\n\n\t\t\tint p = work[k];\n\t\t\tint q = work[k+1];\n\n\t\t\t//■辺に向きをつける\n\t\t\tREV[numE] = make_pair(p,q);\n\t\t\tMAP[make_pair(p,q)] = numE++;\n\n\t\t\tREV[numE] = make_pair(q,p);\n\t\t\tMAP[make_pair(q,p)] = numE++;\n\n\t\t\tG[p].push_back(q);\n\t\t\tG[q].push_back(p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\t\tif(G[i].size() == 0)continue;\n\n\t\tvector<pair<double,int>> work;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tPoint adj = point[G[i][k]]-point[i]; //■注意\n\t\t\tdouble tmp_rad = calc_rad(adj);\n\t\t\twork.push_back(make_pair(tmp_rad,k));\n\t\t}\n\n\t\tsort(work.begin(),work.end());\n\n\t\tint mini_ind = work[0].second;\n\t\tint maxi_ind = work.back().second;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\t\t\tif(k != mini_ind && k != maxi_ind)continue; //■■最も外側の隣接でないならSKIP\n\n\t\t\tint e_ind = MAP[make_pair(i,G[i][k])];\n\t\t\tif(visited[e_ind])continue;\n\n\t\t\tPOL.clear();\n\t\t\tSET.clear();\n\t\t\tEDGES.clear();\n\n\t\t\tPOL.push_back(point[i]);\n\t\t\tPOL.push_back(point[G[i][k]]);\n\n\t\t\tSET.insert(i);\n\t\t\tSET.insert(G[i][k]); //最初の2点を全探索\n\n\t\t\tEDGES.push_back(e_ind);\n\n\t\t\tCATCH = false;\n\t\t\tdfs(i,G[i][k]);\n\t\t\tif(CATCH){\n\n\n\t\t\t\tif(contains(POL,base) == 2){\n\n\t\t\t\t\tprintf(\"yes\\n\");\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"no\\n\");\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 11368, "score_of_the_acc": -0.9217, "final_rank": 7 }, { "submission_id": "aoj_1247_8387133", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 998244353\n//#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 30005\n\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n};\n\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\n\nint N;\nLine line[SIZE];\nPoint point[SIZE];\nvector<Point> V[SIZE];\nvector<int> G[SIZE],ON_SEG[SIZE],CONTAIN[SIZE],EDGES;\nset<int> SET;\nPolygon POL;\nbool CATCH,DEL[SIZE],visited[SIZE];\nmap<pair<int,int>,int> MAP;\nint numE = 0,numDEG[SIZE];\nmap<int,pair<int,int>> REV;\n\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//■■直線ではなく、線分の交差判定■■\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n//線分と線分の距離\ndouble getDistance(Line A,Line B){\n\tif(is_Cross(A,B))return 0.0;\n\treturn min(min(getDistanceSP(A,B.p[0]),getDistanceSP(A,B.p[1])),\n\t\t\tmin(getDistanceSP(B,A.p[0]),getDistanceSP(B,A.p[1])));\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//2つのvectorがなすラジアンを求める関数\ndouble calc_rad(Vector vec1,Vector vec2){\n\n\tdouble tmp = dot(vec1,vec2)/(abs(vec1)*abs(vec2));\n\n\tif(fabs(tmp+1.0) < EPS){\n\n\t\treturn M_PI;\n\t}\n\n\tif(fabs(tmp-1.0) < EPS){\n\n\t\treturn 0.0;\n\t}\n\n\treturn acos(dot(vec1,vec2)/(abs(vec1)*abs(vec2)));\n}\n\n//3点がなすラジアンを求める関数(ccw(base,a,b) == CCW)\ndouble calc_rad(Point base,Point a,Point b){\n\n\tVector vec1 = b-base;\n\tVector vec2 = a-base;\n\n\treturn calc_rad(vec1,vec2);\n}\n\n\n/*\n * ■辺始まり辺終わりにするとWAする\n * 点始まり点終わりにする、ただし途中で訪問した辺は再訪しない■*\n * */\nvoid dfs(int pre,int node){\n\n\tif(CATCH)return;\n\n\tPoint pre_p = point[pre];\n\tPoint now = point[node];\n\n\tdouble maxi = -BIG_NUM;\n\tint ind = -1;\n\n\tfor(int i = 0; i < G[node].size(); i++){\n\t\tint adj = G[node][i];\n\t\tif(adj == pre)continue;\n\n\t\tPoint next = point[adj];\n\n\t\tdouble tmp_rad = calc_rad(now,pre_p,next);\n\n\t\tif(maxi+EPS < tmp_rad){\n\n\t\t\tmaxi = tmp_rad;\n\t\t\tind = i;\n\t\t}\n\t}\n\n\tif(ind == -1)return;\n\n\tint next = G[node][ind];\n\tif(SET.count(next) > 0){\n\n\t\tCATCH = true;\n\t\t//図形が完成した場合、訪問済みの辺は再訪しない\n\t\tfor(int i = 0; i < EDGES.size(); i++){\n\n\t\t\tvisited[EDGES[i]] = true;\n\t\t}\n\n\t\tPolygon work;\n\t\t//■■最初にnextに到達するまでの点は削除する\n\t\tbool FLG = false;\n\t\tfor(int i = 0; i < POL.size(); i++){\n\t\t\tif(POL[i] == point[next]){\n\n\t\t\t\tFLG = true;\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\twork.push_back(POL[i]);\n\t\t}\n\n\t\tPOL.clear();\n\t\tPOL = work;\n\n\t\treturn;\n\t}\n\tint next_e_ind = MAP[make_pair(node,G[node][ind])];\n\tif(visited[next_e_ind])return;\n\n\tSET.insert(G[node][ind]);\n\tPOL.push_back(point[G[node][ind]]);\n\tEDGES.push_back(next_e_ind);\n\tdfs(node,G[node][ind]);\n}\n\n//点のradを求める関数\ndouble calc_rad(Point p){\n\n\tif(p.y == 0){\n\n\t\tif(p.x > 0){\n\n\t\t\treturn 0;\n\n\t\t}else{ //p.x < 0\n\n\t\t\treturn M_PI;\n\t\t}\n\n\t}else if(p.x == 0){\n\n\t\tif(p.y > 0){\n\n\t\t\treturn M_PI/2.0;\n\t\t}else{\n\n\n\t\t\treturn 3*M_PI/2.0;\n\t\t}\n\n\t}else{\n\n\t\tdouble base = atan(fabs(p.y)/fabs(p.x));\n\n\t\tif(p.x > 0){\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn base;\n\n\t\t\t}else{ //p.y < 0\n\n\t\t\t\treturn 2*M_PI-base;\n\t\t\t}\n\n\t\t}else{ //p.x < 0\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn M_PI-base;\n\n\t\t\t}else{\n\n\t\t\t\treturn base+M_PI;\n\t\t\t}\n\t\t}\n\t}\n}\n\n\nvoid func(){\n\n\tint num_point = 0;\n\tnumE = 0;\n\n\tMAP.clear();\n\tREV.clear();\n\n\tfor(int i = 0; i < SIZE; i++){\n\n\t\tV[i].clear();\n\t\tG[i].clear();\n\t\tON_SEG[i].clear();\n\t\tCONTAIN[i].clear();\n\t\tvisited[i] = false;\n\t}\n\n\tPoint base = Point(0,0);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf %lf %lf\",&line[i].p[0].x,&line[i].p[0].y,&line[i].p[1].x,&line[i].p[1].y);\n\t}\n\n\t//交点を全列挙\n\tfor(int i = 0; i < N-1; i++){\n\t\tfor(int k = i+1; k < N; k++){\n\t\t\tif(!is_Cross(line[i],line[k]))continue;\n\n\t\t\tPoint cross_p = calc_Cross_Point(line[i],line[k]);\n\n\t\t\tbool FLG = true;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == cross_p){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\t//辺が持つ点の番号を保存\n\t\t\tCONTAIN[i].push_back(num_point);\n\t\t\tCONTAIN[k].push_back(num_point);\n\n\t\t\t//どの辺の上に乗っているか\n\t\t\tON_SEG[num_point].push_back(i);\n\t\t\tON_SEG[num_point].push_back(k);\n\n\t\t\tpoint[num_point++] = cross_p;\n\t\t\tV[i].push_back(cross_p);\n\t\t\tV[k].push_back(cross_p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\n\t\tDEL[i] = false;\n\t}\n\n\n\t//■■交点数が1なら行き止まりなので点を削除\n\tqueue<int> que;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tnumDEG[i] = V[i].size();\n\n\t\tif(numDEG[i] == 1){\n\n\t\t\tint ind = CONTAIN[i][0];\n\n\t\t\tDEL[ind] = true; //点を削除\n\t\t\tque.push(ind);\n\t\t\tnumDEG[i] = 0;\n\t\t}\n\t}\n\n\twhile(!que.empty()){\n\n\t\tint ind = que.front(); //消す点番号\n\t\tque.pop();\n\n\t\tfor(int k = 0; k < ON_SEG[ind].size(); k++){\n\n\t\t\tint seg = ON_SEG[ind][k]; //消す点が含まれている辺番号\n\t\t\tif(numDEG[seg] == 0)continue;\n\n\t\t\tnumDEG[seg]--;\n\t\t\tif(numDEG[seg] == 1){ //■次数が0になった\n\t\t\t\tfor(int a = 0; a < CONTAIN[seg].size(); a++){ //残っている1点を探す\n\n\t\t\t\t\tint tmp_ind = CONTAIN[seg][a]; //点番号\n\t\t\t\t\tif(DEL[tmp_ind])continue;\n\n\t\t\t\t\tDEL[tmp_ind] = true;\n\t\t\t\t\tnumDEG[seg] = 0;\n\t\t\t\t\tque.push(tmp_ind);\n\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(V[i].size() <= 1)continue;\n\n\t\tsort(V[i].begin(),V[i].end());\n\n\t\tvector<int> vec; //点番号を並び順に格納\n\n\t\tfor(int k = 0; k < V[i].size(); k++){\n\t\t\tint ind = -1;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == V[i][k]){\n\n\t\t\t\t\tind = a;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tvec.push_back(ind);\n\t\t}\n\n\t\tvector<int> work;\n\t\tfor(int k = 0; k < vec.size(); k++){\n\t\t\tif(!DEL[vec[k]]){\n\n\t\t\t\twork.push_back(vec[k]);\n\t\t\t}\n\t\t}\n\n\t\tif(work.size() == 0)continue;\n\n\t\tfor(int k = 0; k < work.size()-1; k++){\n\n\t\t\tint p = work[k];\n\t\t\tint q = work[k+1];\n\n\t\t\t//■辺に向きをつける\n\t\t\tREV[numE] = make_pair(p,q);\n\t\t\tMAP[make_pair(p,q)] = numE++;\n\n\t\t\tREV[numE] = make_pair(q,p);\n\t\t\tMAP[make_pair(q,p)] = numE++;\n\n\t\t\tG[p].push_back(q);\n\t\t\tG[q].push_back(p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\t\tif(G[i].size() == 0)continue;\n\n\t\tvector<pair<double,int>> work;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tPoint adj = point[G[i][k]];\n\t\t\tdouble tmp_rad = calc_rad(adj);\n\t\t\twork.push_back(make_pair(tmp_rad,k));\n\t\t}\n\n\t\tsort(work.begin(),work.end());\n\n\t\tint mini_ind = work[0].second;\n\t\tint maxi_ind = work.back().second;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\t\t\tif(k != mini_ind && k != maxi_ind)continue; //■■最も外側の隣接でないならSKIP\n\n\t\t\tint e_ind = MAP[make_pair(i,G[i][k])];\n\t\t\tif(visited[e_ind])continue;\n\n\t\t\tPOL.clear();\n\t\t\tSET.clear();\n\t\t\tEDGES.clear();\n\n\t\t\tPOL.push_back(point[i]);\n\t\t\tPOL.push_back(point[G[i][k]]);\n\n\t\t\tSET.insert(i);\n\t\t\tSET.insert(G[i][k]); //最初の2点を全探索\n\n\t\t\tEDGES.push_back(e_ind);\n\n\t\t\tCATCH = false;\n\t\t\tdfs(i,G[i][k]);\n\t\t\tif(CATCH){\n\n\n\t\t\t\tif(contains(POL,base) == 2){\n\n\t\t\t\t\tprintf(\"yes\\n\");\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"no\\n\");\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 11380, "score_of_the_acc": -0.9261, "final_rank": 8 }, { "submission_id": "aoj_1247_8385725", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 998244353\n//#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 30005\n\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n};\n\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\n\nint N;\nLine line[SIZE];\nPoint point[SIZE];\nvector<Point> V[SIZE];\nvector<int> G[SIZE],ON_SEG[SIZE],CONTAIN[SIZE],EDGES;\nset<int> SET;\nPolygon POL;\nbool CATCH,DEL[SIZE],visited[SIZE];\nmap<pair<int,int>,int> MAP;\nint numE = 0,numDEG[SIZE];\nmap<int,pair<int,int>> REV;\n\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//■■直線ではなく、線分の交差判定■■\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n//線分と線分の距離\ndouble getDistance(Line A,Line B){\n\tif(is_Cross(A,B))return 0.0;\n\treturn min(min(getDistanceSP(A,B.p[0]),getDistanceSP(A,B.p[1])),\n\t\t\tmin(getDistanceSP(B,A.p[0]),getDistanceSP(B,A.p[1])));\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//2つのvectorがなすラジアンを求める関数\ndouble calc_rad(Vector vec1,Vector vec2){\n\n\tdouble tmp = dot(vec1,vec2)/(abs(vec1)*abs(vec2));\n\n\tif(fabs(tmp+1.0) < EPS){\n\n\t\treturn M_PI;\n\t}\n\n\tif(fabs(tmp-1.0) < EPS){\n\n\t\treturn 0.0;\n\t}\n\n\treturn acos(dot(vec1,vec2)/(abs(vec1)*abs(vec2)));\n}\n\n//3点がなすラジアンを求める関数(ccw(base,a,b) == CCW)\ndouble calc_rad(Point base,Point a,Point b){\n\n\tVector vec1 = b-base;\n\tVector vec2 = a-base;\n\n\treturn calc_rad(vec1,vec2);\n}\n\n\n/*\n * ■辺始まり辺終わりにするとWAする\n * 点始まり点終わりにする、ただし途中で訪問した辺は再訪しない■*\n * */\nvoid dfs(int pre,int node){\n\n\tif(CATCH)return;\n\n\tPoint pre_p = point[pre];\n\tPoint now = point[node];\n\n\tdouble maxi = -BIG_NUM;\n\tint ind = -1;\n\n\tfor(int i = 0; i < G[node].size(); i++){\n\t\tint adj = G[node][i];\n\t\tif(adj == pre)continue;\n\n\t\tPoint next = point[adj];\n\n\t\tdouble tmp_rad = calc_rad(now,pre_p,next);\n\n\t\tif(maxi+EPS < tmp_rad){\n\n\t\t\tmaxi = tmp_rad;\n\t\t\tind = i;\n\t\t}\n\t}\n\n\tif(ind == -1)return;\n\n\tint next = G[node][ind];\n\tif(SET.count(next) > 0){\n\n\t\tCATCH = true;\n\t\t//図形が完成した場合、訪問済みの辺は再訪しない\n\t\tfor(int i = 0; i < EDGES.size(); i++){\n\n\t\t\tvisited[EDGES[i]] = true;\n\t\t}\n\n\t\tPolygon work;\n\t\t//■■最初にnextに到達するまでの点は削除する\n\t\tbool FLG = false;\n\t\tfor(int i = 0; i < POL.size(); i++){\n\t\t\tif(POL[i] == point[next]){\n\n\t\t\t\tFLG = true;\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\twork.push_back(POL[i]);\n\t\t}\n\n\t\tPOL.clear();\n\t\tPOL = work;\n\n\t\treturn;\n\t}\n\n\n\tint next_e_ind = MAP[make_pair(node,G[node][ind])];\n\n\tSET.insert(G[node][ind]);\n\tPOL.push_back(point[G[node][ind]]);\n\tEDGES.push_back(next_e_ind);\n\tdfs(node,G[node][ind]);\n}\n\nvoid func(){\n\n\tint num_point = 0;\n\tnumE = 0;\n\n\tMAP.clear();\n\tREV.clear();\n\n\tfor(int i = 0; i < SIZE; i++){\n\n\t\tV[i].clear();\n\t\tG[i].clear();\n\t\tON_SEG[i].clear();\n\t\tCONTAIN[i].clear();\n\t\tvisited[i] = false;\n\t}\n\n\tPoint base = Point(0,0);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf %lf %lf\",&line[i].p[0].x,&line[i].p[0].y,&line[i].p[1].x,&line[i].p[1].y);\n\t}\n\n\t//交点を全列挙\n\tfor(int i = 0; i < N-1; i++){\n\t\tfor(int k = i+1; k < N; k++){\n\t\t\tif(!is_Cross(line[i],line[k]))continue;\n\n\t\t\tPoint cross_p = calc_Cross_Point(line[i],line[k]);\n\n\t\t\tbool FLG = true;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == cross_p){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\t//辺が持つ点の番号を保存\n\t\t\tCONTAIN[i].push_back(num_point);\n\t\t\tCONTAIN[k].push_back(num_point);\n\n\t\t\t//どの辺の上に乗っているか\n\t\t\tON_SEG[num_point].push_back(i);\n\t\t\tON_SEG[num_point].push_back(k);\n\n\t\t\tpoint[num_point++] = cross_p;\n\t\t\tV[i].push_back(cross_p);\n\t\t\tV[k].push_back(cross_p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\n\t\tDEL[i] = false;\n\t}\n\n\n\t//■■交点数が1なら行き止まりなので点を削除\n\tqueue<int> que;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tnumDEG[i] = V[i].size();\n\n\t\tif(numDEG[i] == 1){\n\n\t\t\tint ind = CONTAIN[i][0];\n\n\t\t\tDEL[ind] = true; //点を削除\n\t\t\tque.push(ind);\n\t\t\tnumDEG[i] = 0;\n\t\t}\n\t}\n\n\twhile(!que.empty()){\n\n\t\tint ind = que.front(); //消す点番号\n\t\tque.pop();\n\n\t\tfor(int k = 0; k < ON_SEG[ind].size(); k++){\n\n\t\t\tint seg = ON_SEG[ind][k]; //消す点が含まれている辺番号\n\t\t\tif(numDEG[seg] == 0)continue;\n\n\t\t\tnumDEG[seg]--;\n\t\t\tif(numDEG[seg] == 1){ //■次数が0になった\n\t\t\t\tfor(int a = 0; a < CONTAIN[seg].size(); a++){ //残っている1点を探す\n\n\t\t\t\t\tint tmp_ind = CONTAIN[seg][a]; //点番号\n\t\t\t\t\tif(DEL[tmp_ind])continue;\n\n\t\t\t\t\tDEL[tmp_ind] = true;\n\t\t\t\t\tnumDEG[seg] = 0;\n\t\t\t\t\tque.push(tmp_ind);\n\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(V[i].size() <= 1)continue;\n\n\t\tsort(V[i].begin(),V[i].end());\n\n\t\tvector<int> vec; //点番号を並び順に格納\n\n\t\tfor(int k = 0; k < V[i].size(); k++){\n\t\t\tint ind = -1;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == V[i][k]){\n\n\t\t\t\t\tind = a;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tvec.push_back(ind);\n\t\t}\n\n\t\tvector<int> work;\n\t\tfor(int k = 0; k < vec.size(); k++){\n\t\t\tif(!DEL[vec[k]]){\n\n\t\t\t\twork.push_back(vec[k]);\n\t\t\t}\n\t\t}\n\n\t\tif(work.size() == 0)continue;\n\n\t\tfor(int k = 0; k < work.size()-1; k++){\n\n\t\t\tint p = work[k];\n\t\t\tint q = work[k+1];\n\n\t\t\t//■辺に向きをつける\n\t\t\tREV[numE] = make_pair(p,q);\n\t\t\tMAP[make_pair(p,q)] = numE++;\n\n\t\t\tREV[numE] = make_pair(q,p);\n\t\t\tMAP[make_pair(q,p)] = numE++;\n\n\t\t\tG[p].push_back(q);\n\t\t\tG[q].push_back(p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\t\tif(G[i].size() == 0)continue;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tint e_ind = MAP[make_pair(i,G[i][k])];\n\t\t\tif(visited[e_ind])continue;\n\n\t\t\tPOL.clear();\n\t\t\tSET.clear();\n\t\t\tEDGES.clear();\n\n\t\t\tPOL.push_back(point[i]);\n\t\t\tPOL.push_back(point[G[i][k]]);\n\n\t\t\tSET.insert(i);\n\t\t\tSET.insert(G[i][k]); //最初の2点を全探索\n\n\t\t\tEDGES.push_back(e_ind);\n\n\t\t\tCATCH = false;\n\t\t\tdfs(i,G[i][k]);\n\t\t\tif(CATCH){\n\n\n\t\t\t\tif(contains(POL,base) == 2){\n\n\t\t\t\t\tprintf(\"yes\\n\");\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"no\\n\");\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 480, "memory_kb": 11280, "score_of_the_acc": -0.956, "final_rank": 12 }, { "submission_id": "aoj_1247_8385719", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 998244353\n//#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 30005\n\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n};\n\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\n\nint N;\nLine line[SIZE];\nPoint point[SIZE];\nvector<Point> V[SIZE];\nvector<int> G[SIZE],ON_SEG[SIZE],CONTAIN[SIZE],EDGES;\nset<int> SET;\nPolygon POL;\nbool CATCH,DEL[SIZE],visited[SIZE];\nmap<pair<int,int>,int> MAP;\nint numE = 0,numDEG[SIZE];\nmap<int,pair<int,int>> REV;\n\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//■■直線ではなく、線分の交差判定■■\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n//線分と線分の距離\ndouble getDistance(Line A,Line B){\n\tif(is_Cross(A,B))return 0.0;\n\treturn min(min(getDistanceSP(A,B.p[0]),getDistanceSP(A,B.p[1])),\n\t\t\tmin(getDistanceSP(B,A.p[0]),getDistanceSP(B,A.p[1])));\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//2つのvectorがなすラジアンを求める関数\ndouble calc_rad(Vector vec1,Vector vec2){\n\n\tdouble tmp = dot(vec1,vec2)/(abs(vec1)*abs(vec2));\n\n\tif(fabs(tmp+1.0) < EPS){\n\n\t\treturn M_PI;\n\t}\n\n\tif(fabs(tmp-1.0) < EPS){\n\n\t\treturn 0.0;\n\t}\n\n\treturn acos(dot(vec1,vec2)/(abs(vec1)*abs(vec2)));\n}\n\n//3点がなすラジアンを求める関数(ccw(base,a,b) == CCW)\ndouble calc_rad(Point base,Point a,Point b){\n\n\tVector vec1 = b-base;\n\tVector vec2 = a-base;\n\n\treturn calc_rad(vec1,vec2);\n}\n\n\n/*\n * ■辺始まり辺終わりにするとWAする\n * 点始まり点終わりにする、ただし途中で訪問した辺は再訪しない■*\n * */\nvoid dfs(int pre,int node){\n\n\tif(CATCH)return;\n\n\t/*if(node == start && pre != start){\n\n\t\t//図形が完成した場合、訪問済みの辺は再訪しない\n\t\tfor(int i = 0; i < EDGES.size(); i++){\n\n\t\t\tvisited[EDGES[i]] = true;\n\t\t}\n\n\t\tCATCH = true;\n\t\treturn;\n\t}*/\n\n\tPoint pre_p = point[pre];\n\tPoint now = point[node];\n\n\tdouble maxi = -BIG_NUM;\n\tint ind = -1;\n\n\tfor(int i = 0; i < G[node].size(); i++){\n\t\tint adj = G[node][i];\n\t\tif(adj == pre)continue;\n\n\t\tPoint next = point[adj];\n\n\t\tdouble tmp_rad = calc_rad(now,pre_p,next);\n\n\t\tif(maxi+EPS < tmp_rad){\n\n\t\t\tmaxi = tmp_rad;\n\t\t\tind = i;\n\t\t}\n\t}\n\n\tif(ind == -1)return;\n\n\tint next = G[node][ind];\n\tif(SET.count(next) > 0){\n\n\t\tCATCH = true;\n\t\t//図形が完成した場合、訪問済みの辺は再訪しない\n\t\tfor(int i = 0; i < EDGES.size(); i++){\n\n\t\t\tvisited[EDGES[i]] = true;\n\t\t}\n\n\t\tPolygon work;\n\t\t//■■最初にnextに到達するまでの点は削除する\n\t\tbool FLG = false;\n\t\tfor(int i = 0; i < POL.size(); i++){\n\t\t\tif(POL[i] == point[next]){\n\n\t\t\t\tFLG = true;\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\twork.push_back(POL[i]);\n\t\t}\n\n\t\tPOL.clear();\n\t\tPOL = work;\n\n\t\treturn;\n\t}\n\n\n\tint next_e_ind = MAP[make_pair(node,G[node][ind])];\n\n\tSET.insert(G[node][ind]);\n\tPOL.push_back(point[G[node][ind]]);\n\tEDGES.push_back(next_e_ind);\n\tdfs(node,G[node][ind]);\n}\n\nvoid func(){\n\n\tint num_point = 0;\n\tnumE = 0;\n\n\tMAP.clear();\n\tREV.clear();\n\n\tfor(int i = 0; i < SIZE; i++){\n\n\t\tV[i].clear();\n\t\tG[i].clear();\n\t\tON_SEG[i].clear();\n\t\tCONTAIN[i].clear();\n\t\tvisited[i] = false;\n\t}\n\n\tPoint base = Point(0,0);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf %lf %lf\",&line[i].p[0].x,&line[i].p[0].y,&line[i].p[1].x,&line[i].p[1].y);\n\t}\n\n\t//交点を全列挙\n\tfor(int i = 0; i < N-1; i++){\n\t\tfor(int k = i+1; k < N; k++){\n\t\t\tif(!is_Cross(line[i],line[k]))continue;\n\n\t\t\tPoint cross_p = calc_Cross_Point(line[i],line[k]);\n\n\t\t\tbool FLG = true;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == cross_p){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\t//辺が持つ点の番号を保存\n\t\t\tCONTAIN[i].push_back(num_point);\n\t\t\tCONTAIN[k].push_back(num_point);\n\n\t\t\t//どの辺の上に乗っているか\n\t\t\tON_SEG[num_point].push_back(i);\n\t\t\tON_SEG[num_point].push_back(k);\n\n\t\t\tpoint[num_point++] = cross_p;\n\t\t\tV[i].push_back(cross_p);\n\t\t\tV[k].push_back(cross_p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\n\t\tDEL[i] = false;\n\t}\n\n\n\t//■■交点数が1なら行き止まりなので点を削除\n\tqueue<int> que;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tnumDEG[i] = V[i].size();\n\n\t\tif(numDEG[i] == 1){\n\n\t\t\tint ind = CONTAIN[i][0];\n\n\t\t\tDEL[ind] = true; //点を削除\n\t\t\tque.push(ind);\n\t\t\tnumDEG[i] = 0;\n\t\t}\n\t}\n\n\twhile(!que.empty()){\n\n\t\tint ind = que.front(); //消す点番号\n\t\tque.pop();\n\n\t\tfor(int k = 0; k < ON_SEG[ind].size(); k++){\n\n\t\t\tint seg = ON_SEG[ind][k]; //消す点が含まれている辺番号\n\t\t\tif(numDEG[seg] == 0)continue;\n\n\t\t\tnumDEG[seg]--;\n\t\t\tif(numDEG[seg] == 1){ //■次数が0になった\n\t\t\t\tfor(int a = 0; a < CONTAIN[seg].size(); a++){ //残っている1点を探す\n\n\t\t\t\t\tint tmp_ind = CONTAIN[seg][a]; //点番号\n\t\t\t\t\tif(DEL[tmp_ind])continue;\n\n\t\t\t\t\tDEL[tmp_ind] = true;\n\t\t\t\t\tnumDEG[seg] = 0;\n\t\t\t\t\tque.push(tmp_ind);\n\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(V[i].size() <= 1)continue;\n\n\t\tsort(V[i].begin(),V[i].end());\n\n\t\tvector<int> vec; //点番号を並び順に格納\n\n\t\tfor(int k = 0; k < V[i].size(); k++){\n\t\t\tint ind = -1;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == V[i][k]){\n\n\t\t\t\t\tind = a;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tvec.push_back(ind);\n\t\t}\n\n\t\tvector<int> work;\n\t\tfor(int k = 0; k < vec.size(); k++){\n\t\t\tif(!DEL[vec[k]]){\n\n\t\t\t\twork.push_back(vec[k]);\n\t\t\t}\n\t\t}\n\n\t\tif(work.size() == 0)continue;\n\n\t\tfor(int k = 0; k < work.size()-1; k++){\n\n\t\t\tint p = work[k];\n\t\t\tint q = work[k+1];\n\n\t\t\tREV[numE] = make_pair(p,q);\n\t\t\tMAP[make_pair(p,q)] = numE++;\n\n\t\t\tREV[numE] = make_pair(q,p);\n\t\t\tMAP[make_pair(q,p)] = numE++;\n\n\t\t\tG[p].push_back(q);\n\t\t\tG[q].push_back(p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\t\tif(G[i].size() == 0)continue;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tint e_ind = MAP[make_pair(i,G[i][k])];\n\t\t\tif(visited[e_ind])continue;\n\n\t\t\tPOL.clear();\n\t\t\tSET.clear();\n\t\t\tEDGES.clear();\n\n\t\t\tPOL.push_back(point[i]);\n\t\t\tPOL.push_back(point[G[i][k]]);\n\n\t\t\tSET.insert(i);\n\t\t\tSET.insert(G[i][k]); //最初の2点を全探索\n\n\t\t\tEDGES.push_back(e_ind);\n\n\t\t\tCATCH = false;\n\t\t\tdfs(i,G[i][k]);\n\t\t\tif(CATCH){\n\n\n\t\t\t\tif(contains(POL,base) == 2){\n\n\t\t\t\t\tprintf(\"yes\\n\");\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"no\\n\");\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 480, "memory_kb": 11164, "score_of_the_acc": -0.9431, "final_rank": 11 }, { "submission_id": "aoj_1247_8385708", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 998244353\n//#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 30005\n\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n};\n\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\n\nint N;\nLine line[SIZE];\nPoint point[SIZE];\nvector<Point> V[SIZE];\nvector<int> G[SIZE],ON_SEG[SIZE],CONTAIN[SIZE],EDGES;\nset<int> SET;\nPolygon POL;\nbool CATCH,DEL[SIZE],visited[SIZE];\nmap<pair<int,int>,int> MAP;\nint numE = 0,numDEG[SIZE];\nmap<int,pair<int,int>> REV;\n\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//■■直線ではなく、線分の交差判定■■\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n//線分と線分の距離\ndouble getDistance(Line A,Line B){\n\tif(is_Cross(A,B))return 0.0;\n\treturn min(min(getDistanceSP(A,B.p[0]),getDistanceSP(A,B.p[1])),\n\t\t\tmin(getDistanceSP(B,A.p[0]),getDistanceSP(B,A.p[1])));\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//2つのvectorがなすラジアンを求める関数\ndouble calc_rad(Vector vec1,Vector vec2){\n\n\tdouble tmp = dot(vec1,vec2)/(abs(vec1)*abs(vec2));\n\n\tif(fabs(tmp+1.0) < EPS){\n\n\t\treturn M_PI;\n\t}\n\n\tif(fabs(tmp-1.0) < EPS){\n\n\t\treturn 0.0;\n\t}\n\n\treturn acos(dot(vec1,vec2)/(abs(vec1)*abs(vec2)));\n}\n\n//3点がなすラジアンを求める関数(ccw(base,a,b) == CCW)\ndouble calc_rad(Point base,Point a,Point b){\n\n\tVector vec1 = b-base;\n\tVector vec2 = a-base;\n\n\treturn calc_rad(vec1,vec2);\n}\n\n\nvoid dfs(int start,int pre,int node){\n\n\tif(CATCH)return;\n\n\tif(node == start && pre != start){\n\n\t\t//図形が完成した場合、訪問済みの両端点は再訪しない\n\t\tfor(int i = 0; i < EDGES.size(); i++){\n\n\t\t\tvisited[EDGES[i]] = true;\n\t\t}\n\n\t\tCATCH = true;\n\t\treturn;\n\t}\n\n\tPoint pre_p = point[pre];\n\tPoint now = point[node];\n\n\tdouble maxi = -BIG_NUM;\n\tint ind = -1;\n\n\tfor(int i = 0; i < G[node].size(); i++){\n\t\tint adj = G[node][i];\n\t\tif(adj == pre)continue;\n\n\t\tif(adj != start && SET.count(adj) > 0)continue;\n\t\tif(adj == start && pre == start)continue;\n\n\t\tPoint next = point[adj];\n\n\t\tdouble tmp_rad = calc_rad(now,pre_p,next);\n\n\t\tif(maxi+EPS < tmp_rad){\n\n\t\t\tmaxi = tmp_rad;\n\t\t\tind = i;\n\t\t}\n\t}\n\n\tif(ind == -1)return;\n\n\tint next_e_ind = MAP[make_pair(node,G[node][ind])];\n\n\tSET.insert(G[node][ind]);\n\tPOL.push_back(point[G[node][ind]]);\n\tEDGES.push_back(next_e_ind);\n\tdfs(start,node,G[node][ind]);\n}\n\nvoid func(){\n\n\tint num_point = 0;\n\tnumE = 0;\n\n\tMAP.clear();\n\tREV.clear();\n\n\tfor(int i = 0; i < SIZE; i++){\n\n\t\tV[i].clear();\n\t\tG[i].clear();\n\t\tON_SEG[i].clear();\n\t\tCONTAIN[i].clear();\n\t\tvisited[i] = false;\n\t}\n\n\tPoint base = Point(0,0);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf %lf %lf\",&line[i].p[0].x,&line[i].p[0].y,&line[i].p[1].x,&line[i].p[1].y);\n\t}\n\n\t//交点を全列挙\n\tfor(int i = 0; i < N-1; i++){\n\t\tfor(int k = i+1; k < N; k++){\n\t\t\tif(!is_Cross(line[i],line[k]))continue;\n\n\t\t\tPoint cross_p = calc_Cross_Point(line[i],line[k]);\n\n\t\t\tbool FLG = true;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == cross_p){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\t//辺が持つ点の番号を保存\n\t\t\tCONTAIN[i].push_back(num_point);\n\t\t\tCONTAIN[k].push_back(num_point);\n\n\t\t\t//どの辺の上に乗っているか\n\t\t\tON_SEG[num_point].push_back(i);\n\t\t\tON_SEG[num_point].push_back(k);\n\n\t\t\tpoint[num_point++] = cross_p;\n\t\t\tV[i].push_back(cross_p);\n\t\t\tV[k].push_back(cross_p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\n\t\tDEL[i] = false;\n\t}\n\n\n\t//■■交点数が1なら行き止まりなので点を削除\n\tqueue<int> que;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tnumDEG[i] = V[i].size();\n\n\t\tif(numDEG[i] == 1){\n\n\t\t\tint ind = CONTAIN[i][0];\n\n\t\t\tDEL[ind] = true; //点を削除\n\t\t\tque.push(ind);\n\t\t\tnumDEG[i] = 0;\n\t\t}\n\t}\n\n\twhile(!que.empty()){\n\n\t\tint ind = que.front(); //消す点番号\n\t\tque.pop();\n\n\t\tfor(int k = 0; k < ON_SEG[ind].size(); k++){\n\n\t\t\tint seg = ON_SEG[ind][k]; //消す点が含まれている辺番号\n\t\t\tif(numDEG[seg] == 0)continue;\n\n\t\t\tnumDEG[seg]--;\n\t\t\tif(numDEG[seg] == 1){ //■次数が0になった\n\t\t\t\tfor(int a = 0; a < CONTAIN[seg].size(); a++){ //残っている1点を探す\n\n\t\t\t\t\tint tmp_ind = CONTAIN[seg][a]; //点番号\n\t\t\t\t\tif(DEL[tmp_ind])continue;\n\n\t\t\t\t\tDEL[tmp_ind] = true;\n\t\t\t\t\tnumDEG[seg] = 0;\n\t\t\t\t\tque.push(tmp_ind);\n\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(V[i].size() <= 1)continue;\n\n\t\tsort(V[i].begin(),V[i].end());\n\n\t\tvector<int> vec; //点番号を並び順に格納\n\n\t\tfor(int k = 0; k < V[i].size(); k++){\n\t\t\tint ind = -1;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == V[i][k]){\n\n\t\t\t\t\tind = a;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tvec.push_back(ind);\n\t\t}\n\n\t\tvector<int> work;\n\t\tfor(int k = 0; k < vec.size(); k++){\n\t\t\tif(!DEL[vec[k]]){\n\n\t\t\t\twork.push_back(vec[k]);\n\t\t\t}\n\t\t}\n\n\t\tif(work.size() == 0)continue;\n\n\t\tfor(int k = 0; k < work.size()-1; k++){\n\n\t\t\tint p = work[k];\n\t\t\tint q = work[k+1];\n\n\t\t\tREV[numE] = make_pair(p,q);\n\t\t\tMAP[make_pair(p,q)] = numE++;\n\n\t\t\tREV[numE] = make_pair(q,p);\n\t\t\tMAP[make_pair(q,p)] = numE++;\n\n\t\t\tG[p].push_back(q);\n\t\t\tG[q].push_back(p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\t\tif(G[i].size() == 0)continue;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tint e_ind = MAP[make_pair(i,G[i][k])];\n\t\t\tif(visited[e_ind])continue;\n\n\t\t\tPOL.clear();\n\t\t\tSET.clear();\n\t\t\tEDGES.clear();\n\n\t\t\tPOL.push_back(point[i]);\n\t\t\tPOL.push_back(point[G[i][k]]);\n\n\t\t\tSET.insert(i);\n\t\t\tSET.insert(G[i][k]); //最初の2点を全探索\n\n\t\t\tEDGES.push_back(e_ind);\n\n\t\t\tCATCH = false;\n\t\t\tdfs(i,i,G[i][k]);\n\t\t\tif(CATCH){\n\n\n\t\t\t\tif(contains(POL,base) == 2){\n\n\t\t\t\t\tprintf(\"yes\\n\");\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"no\\n\");\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3750, "memory_kb": 12288, "score_of_the_acc": -1.5671, "final_rank": 20 }, { "submission_id": "aoj_1247_8385265", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 998244353\n//#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 10005\n\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n};\n\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\n\nint N;\nLine line[SIZE];\nPoint point[SIZE];\nvector<Point> V[SIZE];\nvector<int> G[SIZE],ON_SEG[SIZE],CONTAIN[SIZE];\nset<int> SET;\nPolygon POL;\nbool CATCH,DEL[SIZE],visited[SIZE];\nmap<pair<int,int>,int> MAP;\nint numE = 0,numDEG[SIZE];\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//■■直線ではなく、線分の交差判定■■\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n//線分と線分の距離\ndouble getDistance(Line A,Line B){\n\tif(is_Cross(A,B))return 0.0;\n\treturn min(min(getDistanceSP(A,B.p[0]),getDistanceSP(A,B.p[1])),\n\t\t\tmin(getDistanceSP(B,A.p[0]),getDistanceSP(B,A.p[1])));\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//2つのvectorがなすラジアンを求める関数\ndouble calc_rad(Vector vec1,Vector vec2){\n\n\tdouble tmp = dot(vec1,vec2)/(abs(vec1)*abs(vec2));\n\n\tif(fabs(tmp+1.0) < EPS){\n\n\t\treturn M_PI;\n\t}\n\n\tif(fabs(tmp-1.0) < EPS){\n\n\t\treturn 0.0;\n\t}\n\n\treturn acos(dot(vec1,vec2)/(abs(vec1)*abs(vec2)));\n}\n\n//3点がなすラジアンを求める関数(ccw(base,a,b) == CCW)\ndouble calc_rad(Point base,Point a,Point b){\n\n\tVector vec1 = b-base;\n\tVector vec2 = a-base;\n\n\treturn calc_rad(vec1,vec2);\n}\n\n\nvoid dfs(int start,int pre,int node){\n\n\tif(CATCH)return;\n\n\tif(node == start && pre != start){\n\n\t\tCATCH = true;\n\t\treturn;\n\t}\n\n\tPoint pre_p = point[pre];\n\tPoint now = point[node];\n\n\tdouble maxi = -BIG_NUM;\n\tint ind = -1;\n\n\tfor(int i = 0; i < G[node].size(); i++){\n\t\tint adj = G[node][i];\n\t\tif(adj == pre)continue;\n\n\t\tif(adj != start && SET.count(adj) > 0)continue;\n\t\tif(adj == start && pre == start)continue;\n\n\t\tPoint next = point[adj];\n\n\t\tdouble tmp_rad = calc_rad(now,pre_p,next);\n\n\t\tif(maxi+EPS < tmp_rad){\n\n\t\t\tmaxi = tmp_rad;\n\t\t\tind = i;\n\t\t}\n\t}\n\n\tif(ind == -1)return;\n\n\tSET.insert(G[node][ind]);\n\tPOL.push_back(point[G[node][ind]]);\n\tdfs(start,node,G[node][ind]);\n}\n\nvoid func(){\n\n\tint num_point = 0;\n\tfor(int i = 0; i < SIZE; i++){\n\n\t\tV[i].clear();\n\t\tG[i].clear();\n\t\tON_SEG[i].clear();\n\t\tCONTAIN[i].clear();\n\t}\n\n\tPoint base = Point(0,0);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf %lf %lf\",&line[i].p[0].x,&line[i].p[0].y,&line[i].p[1].x,&line[i].p[1].y);\n\t}\n\n\t//交点を全列挙\n\tfor(int i = 0; i < N-1; i++){\n\t\tfor(int k = i+1; k < N; k++){\n\t\t\tif(!is_Cross(line[i],line[k]))continue;\n\n\t\t\tPoint cross_p = calc_Cross_Point(line[i],line[k]);\n\n\t\t\tbool FLG = true;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == cross_p){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\t//辺が持つ点の番号を保存\n\t\t\tCONTAIN[i].push_back(num_point);\n\t\t\tCONTAIN[k].push_back(num_point);\n\n\t\t\t//どの辺の上に乗っているか\n\t\t\tON_SEG[num_point].push_back(i);\n\t\t\tON_SEG[num_point].push_back(k);\n\n\t\t\tpoint[num_point++] = cross_p;\n\t\t\tV[i].push_back(cross_p);\n\t\t\tV[k].push_back(cross_p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\n\t\tDEL[i] = false;\n\t}\n\n\n\t//■■交点数が1なら行き止まりなので点を削除\n\tqueue<int> que;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tnumDEG[i] = V[i].size();\n\n\t\tif(numDEG[i] == 1){\n\n\t\t\tint ind = CONTAIN[i][0];\n\n\t\t\tDEL[ind] = true; //点を削除\n\t\t\tque.push(ind);\n\t\t\tnumDEG[i] = 0;\n\t\t}\n\t}\n\n\twhile(!que.empty()){\n\n\t\tint ind = que.front(); //消す点番号\n\t\tque.pop();\n\n\t\tfor(int k = 0; k < ON_SEG[ind].size(); k++){\n\n\t\t\tint seg = ON_SEG[ind][k]; //消す点が含まれている辺番号\n\t\t\tif(numDEG[seg] == 0)continue;\n\n\t\t\tnumDEG[seg]--;\n\t\t\tif(numDEG[seg] == 1){ //■次数が0になった\n\t\t\t\tfor(int a = 0; a < CONTAIN[seg].size(); a++){ //残っている1点を探す\n\n\t\t\t\t\tint tmp_ind = CONTAIN[seg][a]; //点番号\n\t\t\t\t\tif(DEL[tmp_ind])continue;\n\n\t\t\t\t\tDEL[tmp_ind] = true;\n\t\t\t\t\tnumDEG[seg] = 0;\n\t\t\t\t\tque.push(tmp_ind);\n\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(V[i].size() <= 1)continue;\n\n\t\tsort(V[i].begin(),V[i].end());\n\n\t\tvector<int> vec; //点番号を並び順に格納\n\n\t\tfor(int k = 0; k < V[i].size(); k++){\n\t\t\tint ind = -1;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == V[i][k]){\n\n\t\t\t\t\tind = a;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tvec.push_back(ind);\n\t\t}\n\n\t\tvector<int> work;\n\t\tfor(int k = 0; k < vec.size(); k++){\n\t\t\tif(!DEL[vec[k]]){\n\n\t\t\t\twork.push_back(vec[k]);\n\t\t\t}\n\t\t}\n\n\t\tif(work.size() == 0)continue;\n\n\t\tfor(int k = 0; k < work.size()-1; k++){\n\n\t\t\tint p = work[k];\n\t\t\tint q = work[k+1];\n\n\t\t\tG[p].push_back(q);\n\t\t\tG[q].push_back(p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\t\tif(G[i].size() == 0)continue;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tPOL.clear();\n\t\t\tSET.clear();\n\n\t\t\tPOL.push_back(point[i]);\n\t\t\tPOL.push_back(point[G[i][k]]);\n\n\t\t\tSET.insert(i);\n\t\t\tSET.insert(G[i][k]); //最初の2点を全探索\n\n\t\t\tCATCH = false;\n\t\t\tdfs(i,i,G[i][k]);\n\t\t\tif(CATCH){\n\n\n\t\t\t\tif(contains(POL,base) == 2){\n\n\t\t\t\t\tprintf(\"yes\\n\");\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"no\\n\");\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 6590, "memory_kb": 5680, "score_of_the_acc": -1.2622, "final_rank": 19 }, { "submission_id": "aoj_1247_8367553", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 998244353\n//#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 10005\n\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n};\n\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\n\nint N;\nLine line[SIZE];\nPoint point[SIZE];\nvector<Point> V[SIZE];\nvector<int> G[SIZE];\nset<int> SET;\nPolygon POL;\nbool CATCH,DEL[SIZE];\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//■■直線ではなく、線分の交差判定■■\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n//線分と線分の距離\ndouble getDistance(Line A,Line B){\n\tif(is_Cross(A,B))return 0.0;\n\treturn min(min(getDistanceSP(A,B.p[0]),getDistanceSP(A,B.p[1])),\n\t\t\tmin(getDistanceSP(B,A.p[0]),getDistanceSP(B,A.p[1])));\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//2つのvectorがなすラジアンを求める関数\ndouble calc_rad(Vector vec1,Vector vec2){\n\n\tdouble tmp = dot(vec1,vec2)/(abs(vec1)*abs(vec2));\n\n\tif(fabs(tmp+1.0) < EPS){\n\n\t\treturn M_PI;\n\t}\n\n\tif(fabs(tmp-1.0) < EPS){\n\n\t\treturn 0.0;\n\t}\n\n\treturn acos(dot(vec1,vec2)/(abs(vec1)*abs(vec2)));\n}\n\n//3点がなすラジアンを求める関数(ccw(base,a,b) == CCW)\ndouble calc_rad(Point base,Point a,Point b){\n\n\tVector vec1 = b-base;\n\tVector vec2 = a-base;\n\n\treturn calc_rad(vec1,vec2);\n}\n\n\nvoid dfs(int start,int pre,int node){\n\n\tif(CATCH)return;\n\n\tif(node == start && pre != start){\n\n\t\tCATCH = true;\n\t\treturn;\n\t}\n\n\tPoint pre_p = point[pre];\n\tPoint now = point[node];\n\n\tdouble maxi = -BIG_NUM;\n\tint ind = -1;\n\n\tfor(int i = 0; i < G[node].size(); i++){\n\t\tint adj = G[node][i];\n\t\tif(adj == pre)continue;\n\n\t\tif(adj != start && SET.count(adj) > 0)continue;\n\t\tif(adj == start && pre == start)continue;\n\n\t\tPoint next = point[adj];\n\n\t\tdouble tmp_rad = calc_rad(now,pre_p,next);\n\n\t\tif(maxi+EPS < tmp_rad){\n\n\t\t\tmaxi = tmp_rad;\n\t\t\tind = i;\n\t\t}\n\t}\n\n\tif(ind == -1)return;\n\n\tSET.insert(G[node][ind]);\n\tPOL.push_back(point[G[node][ind]]);\n\tdfs(start,node,G[node][ind]);\n}\n\nvoid func(){\n\n\tint num_point = 0;\n\tfor(int i = 0; i < SIZE; i++){\n\n\t\tV[i].clear();\n\t\tG[i].clear();\n\t}\n\n\tPoint base = Point(0,0);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf %lf %lf\",&line[i].p[0].x,&line[i].p[0].y,&line[i].p[1].x,&line[i].p[1].y);\n\t}\n\n\t//交点を全列挙\n\tfor(int i = 0; i < N-1; i++){\n\t\tfor(int k = i+1; k < N; k++){\n\t\t\tif(!is_Cross(line[i],line[k]))continue;\n\n\t\t\tPoint cross_p = calc_Cross_Point(line[i],line[k]);\n\n\t\t\tbool FLG = true;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == cross_p){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\tpoint[num_point++] = cross_p;\n\t\t\tV[i].push_back(cross_p);\n\t\t\tV[k].push_back(cross_p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\n\t\tDEL[i] = false;\n\t}\n\t//■■交点数が1なら行き止まりなので点を削除\n\tfor(int i = 0; i < N; i++){\n\t\tif(V[i].size() == 1){\n\n\t\t\tint ind = -1;\n\t\t\tfor(int k = 0; k < num_point; k++){\n\t\t\t\tif(point[k] == V[i][0]){\n\n\t\t\t\t\tind = k;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tDEL[ind] = true;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(V[i].size() <= 1)continue;\n\n\t\tsort(V[i].begin(),V[i].end());\n\n\t\tvector<int> vec;\n\n\t\tfor(int k = 0; k < V[i].size(); k++){\n\t\t\tint ind = -1;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == V[i][k]){\n\n\t\t\t\t\tind = a;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tvec.push_back(ind);\n\t\t}\n\n\t\tvector<int> work;\n\t\tfor(int k = 0; k < vec.size(); k++){\n\t\t\tif(!DEL[vec[k]]){\n\n\t\t\t\twork.push_back(vec[k]);\n\t\t\t}\n\t\t}\n\n\t\tvec = work;\n\n\t\tfor(int k = 0; k < vec.size()-1; k++){\n\n\t\t\tint p = vec[k];\n\t\t\tint q = vec[k+1];\n\n\t\t\tG[p].push_back(q);\n\t\t\tG[q].push_back(p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\t\tif(G[i].size() == 0)continue;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tPOL.clear();\n\t\t\tSET.clear();\n\n\t\t\tPOL.push_back(point[i]);\n\t\t\tPOL.push_back(point[G[i][k]]);\n\n\t\t\tSET.insert(i);\n\t\t\tSET.insert(G[i][k]); //最初の2点を全探索\n\n\t\t\tCATCH = false;\n\t\t\tdfs(i,i,G[i][k]);\n\t\t\tif(CATCH){\n\n\n\t\t\t\tif(contains(POL,base) == 2){\n\n\t\t\t\t\tprintf(\"yes\\n\");\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"no\\n\");\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 6550, "memory_kb": 5016, "score_of_the_acc": -1.1819, "final_rank": 18 }, { "submission_id": "aoj_1247_8367548", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 998244353\n//#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 10005\n\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n};\n\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\n\nint N;\nLine line[SIZE];\nPoint point[SIZE];\nvector<Point> V[SIZE];\nvector<int> G[SIZE];\nset<int> SET;\nPolygon POL;\nbool CATCH,DEL[SIZE];\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//■■直線ではなく、線分の交差判定■■\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n//線分と線分の距離\ndouble getDistance(Line A,Line B){\n\tif(is_Cross(A,B))return 0.0;\n\treturn min(min(getDistanceSP(A,B.p[0]),getDistanceSP(A,B.p[1])),\n\t\t\tmin(getDistanceSP(B,A.p[0]),getDistanceSP(B,A.p[1])));\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//2つのvectorがなすラジアンを求める関数\ndouble calc_rad(Vector vec1,Vector vec2){\n\n\tdouble tmp = dot(vec1,vec2)/(abs(vec1)*abs(vec2));\n\n\tif(fabs(tmp+1.0) < EPS){\n\n\t\treturn M_PI;\n\t}\n\n\tif(fabs(tmp-1.0) < EPS){\n\n\t\treturn 0.0;\n\t}\n\n\treturn acos(dot(vec1,vec2)/(abs(vec1)*abs(vec2)));\n}\n\n//3点がなすラジアンを求める関数(ccw(base,a,b) == CCW)\ndouble calc_rad(Point base,Point a,Point b){\n\n\tVector vec1 = b-base;\n\tVector vec2 = a-base;\n\n\treturn calc_rad(vec1,vec2);\n}\n\nbool DEBUG = false;\n\n\nvoid dfs(int start,int pre,int node){\n\n\tif(CATCH)return;\n\n\tif(DEBUG){\n\n\t\tprintf(\"start:%d pre:%d node:%d ■現在の座標\\n\",start,pre,node);\n\t\tpoint[node].debug();\n\t}\n\n\tif(node == start && pre != start){\n\n\t\tCATCH = true;\n\t\tif(DEBUG){\n\t\t\tprintf(\"■■とらえた\\n\");\n\t\t\tprintf(\"start: [%d] \",start);\n\t\t\tpoint[start].debug();\n\t\t\tprintf(\"pre: [%d] \",pre);\n\t\t\tpoint[pre].debug();\n\t\t}\n\t\treturn;\n\t}\n\n\tPoint pre_p = point[pre];\n\tPoint now = point[node];\n\n\tdouble maxi = -BIG_NUM;\n\tint ind = -1;\n\n\tfor(int i = 0; i < G[node].size(); i++){\n\t\tint adj = G[node][i];\n\t\tif(adj == pre)continue;\n\n\t\tif(adj != start && SET.count(adj) > 0)continue;\n\t\tif(adj == start && pre == start)continue;\n\n\t\tPoint next = point[adj];\n\n\t\t//if(ccw(now,next,pre_p) == CLOCKWISE)continue;\n\n\n\t\tdouble tmp_rad = calc_rad(now,pre_p,next);\n\t\t//printf(\"tmp_rad:%.3lf\\n\",tmp_rad);\n\t\tif(maxi+EPS < tmp_rad){\n\n\t\t\t//printf(\"tmp_rad:%.3lf\\n\",tmp_rad);\n\t\t\tmaxi = tmp_rad;\n\t\t\tind = i;\n\t\t}\n\t}\n\n\tif(ind == -1)return;\n\n\tSET.insert(G[node][ind]);\n\tPOL.push_back(point[G[node][ind]]);\n\tdfs(start,node,G[node][ind]);\n}\n\nvoid func(){\n\n\tint num_point = 0;\n\tfor(int i = 0; i < SIZE; i++){\n\n\t\tV[i].clear();\n\t\tG[i].clear();\n\t}\n\n\tPoint base = Point(0,0);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf %lf %lf\",&line[i].p[0].x,&line[i].p[0].y,&line[i].p[1].x,&line[i].p[1].y);\n\t}\n\n\t//交点を全列挙\n\tfor(int i = 0; i < N-1; i++){\n\t\tfor(int k = i+1; k < N; k++){\n\t\t\tif(!is_Cross(line[i],line[k]))continue;\n\n\t\t\tPoint cross_p = calc_Cross_Point(line[i],line[k]);\n\n\t\t\tbool FLG = true;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == cross_p){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\t//cross_p.debug();\n\n\t\t\tpoint[num_point++] = cross_p;\n\t\t\tV[i].push_back(cross_p);\n\t\t\tV[k].push_back(cross_p);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_point; i++){\n\n\t\tDEL[i] = false;\n\t}\n\t//交点数が1なら行き止まりなので点を削除\n\tfor(int i = 0; i < N; i++){\n\t\tif(V[i].size() == 1){\n\n\t\t\tint ind = -1;\n\t\t\tfor(int k = 0; k < num_point; k++){\n\t\t\t\tif(point[k] == V[i][0]){\n\n\t\t\t\t\tind = k;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tDEL[ind] = true;\n\t\t}\n\t}\n\n/*\n\tfor(int i = 0; i < num_point; i++){\n\n\t\tprintf(\"点%d \",i);\n\t\tpoint[i].debug();\n\t}*/\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(V[i].size() <= 1)continue;\n\n\t\tsort(V[i].begin(),V[i].end());\n\n\t\t/*printf(\"\\n線分%d\",i);\n\t\tfor(int a = 0; a < V[i].size(); a++){\n\n\t\t\tV[i][a].debug();\n\t\t}*/\n\n\t\tvector<int> vec;\n\n\t\tfor(int k = 0; k < V[i].size(); k++){\n\t\t\tint ind = -1;\n\t\t\tfor(int a = 0; a < num_point; a++){\n\t\t\t\tif(point[a] == V[i][k]){\n\n\t\t\t\t\tind = a;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tvec.push_back(ind);\n\t\t}\n\n\t\tvector<int> work;\n\t\tfor(int k = 0; k < vec.size(); k++){\n\t\t\tif(!DEL[vec[k]]){\n\n\t\t\t\twork.push_back(vec[k]);\n\t\t\t}\n\t\t}\n\n\t\tvec = work;\n\n\t\tfor(int k = 0; k < vec.size()-1; k++){\n\n\t\t\tint p = vec[k];\n\t\t\tint q = vec[k+1];\n\n\t\t\tG[p].push_back(q);\n\t\t\tG[q].push_back(p);\n\t\t}\n\t}\n/*\n\tfor(int i = 0; i < num_point; i++){\n\t\t//f(i != 0 && i != 1)continue;\n\n\t\tprintf(\"\\n点%dです\\n\",i);\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tprintf(\"点%dと隣接\\n\",G[i][k]);\n\t\t}\n\t}\n\treturn;*/\n\n\tfor(int i = 0; i < num_point; i++){\n\t\tif(G[i].size() == 0)continue;\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tPOL.clear();\n\t\t\tSET.clear();\n\n\t\t\tPOL.push_back(point[i]);\n\t\t\tPOL.push_back(point[G[i][k]]);\n\n\t\t\tSET.insert(i);\n\t\t\tSET.insert(G[i][k]); //最初の2点を全探索\n\n\t\t\tif(DEBUG){\n\t\t\t\tprintf(\"\\n◎◎◎dfs\\n\");\n\t\t\t}\n\n\t\t\tCATCH = false;\n\t\t\tdfs(i,i,G[i][k]);\n\t\t\tif(CATCH){\n\n\n\t\t\t\tif(contains(POL,base) == 2){\n\n\t\t\t\t\tif(DEBUG){\n\t\t\t\t\t\tfor(int a = 0; a < POL.size(); a++){\n\n\t\t\t\t\t\t\tPOL[a].debug();\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\n\t\t\t\t\tprintf(\"yes\\n\");\n\t\t\t\t\treturn;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"no\\n\");\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 6560, "memory_kb": 4848, "score_of_the_acc": -1.1647, "final_rank": 17 }, { "submission_id": "aoj_1247_4320286", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#pragma GCC optimize(\"unroll-loops\")\n#include\"bits/stdc++.h\"\n\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(n);i++)\n#define FOR(i,m,n) for(int i=(m);i<(n);i++)\n\nconst bool DEBUG = false;\n\nconst double EPS = 1e-8;\ntypedef complex<double> point;\nistream &operator>>(istream &is, point &p) {\n\tdouble a, b;\n\tis >> a >> b;\n\tp = point(a, b);\n\treturn is;\n}\npoint operator*(const point&p, const double &d) {\n\treturn point(real(p)*d, imag(p)*d);\n}\nnamespace std {\n\tbool operator < (const point& a, const point& b) {\n\t\treturn real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n\t}\n}\n\n//直線or線分\nstruct Line : public vector<point> {\n\tLine(const point &a, const point &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\ntypedef vector<Line>Lines;\n\n\ndouble cross(const point& a, const point& b) {\n\treturn real(a)*imag(b) - imag(a)*real(b);\n}\ndouble dot(const point& a, const point& b) {\n\treturn real(a)*real(b) + imag(a)*imag(b);\n}\nint ccw(point a, point b, point c) {\n\tb = b - a; c = c - a;\n\tif (cross(b, c) > EPS) return +1; // counter clockwise\n\tif (cross(b, c) < -EPS) return -1; // clockwise\n\tif (dot(b, c) < -EPS) return +2; // c--a--b on line\n\tif (norm(b) < norm(c)) return -2; // a--b--c on line\n\treturn 0;\n}\n//交差判定\nbool intersectLL(const Line &l1, const Line &l2) {\n\treturn abs(cross(l1[1] - l1[0], l2[1] - l2[0])) > EPS || //non-parallel\n\t\tabs(cross(l1[1] - l1[0], l2[0] - l1[0])) < EPS; //same line\n}\nbool intersectLS(const Line &l, const Line &s) {\n\treturn cross(l[1] - l[0], s[0] - l[0])* // s[0] is left of l\n\t\tcross(l[1] - l[0], s[1] - l[0]) < EPS; // s[1] is right of l\n}\nbool intersectLP(const Line &l, const point &p) {\n\treturn abs(cross(l[1] - p, l[0] - p)) < EPS;\n}\n//端点に乗ってたらfalse\nbool intersectSP_without_endpoint(const Line &s, const point &p) {\n\tif (abs(s[0] - p) < EPS || abs(s[1] - p) < EPS)return false;\n\treturn abs(s[0] - p) + abs(s[1] - p) - abs(s[1] - s[0]) < EPS; //triangle inequality\n}\n\nbool intersectSP(const Line &s, const point &p) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\treturn abs(s[0] - p) + abs(s[1] - p) - abs(s[1] - s[0]) < EPS; //triangle inequality\n}\nbool connectSS(const Line &s, const Line &t) {\n\tif (intersectSP(s, t[0]) || intersectSP(s, t[1]) || intersectSP(t, s[0]) || intersectSP(t, s[1]))return true;\n\telse return false;\n}\nbool isSamePoint(const point &p1, const point &p2) {\n\treturn abs(p1 - p2)<EPS;\n}\nbool connectSS_with_endpoint(const Line &s, const Line &t) {\n\tREP(i, 2)REP(j, 2) {\n\t\t//if(isSamePoint(s[i],t[j]))return true;\n\t\tif (s[i] == t[j])return true;\n\t}\n\treturn false;\n}\nbool intersectSS(const Line &s, const Line &t) {\n\treturn ccw(s[0], s[1], t[0])*ccw(s[0], s[1], t[1]) <= 0 &&\n\t\tccw(t[0], t[1], s[0])*ccw(t[0], t[1], s[1]) <= 0;\n}\nbool intersectSS_strict(const Line &s, const Line &t) {\n\t//端点が線分上に乗っている場合はfalseにする\n\tif (connectSS(s, t))return false;\n\treturn ccw(s[0], s[1], t[0])*ccw(s[0], s[1], t[1]) <= 0 &&\n\t\tccw(t[0], t[1], s[0])*ccw(t[0], t[1], s[1]) <= 0;\n}\n\nbool isOn(const Line &l, const point &p) {\n\tif (l[0] == p || l[1] == p)return false;\n\tpoint d = l[1] - l[0];\n\tpoint p0 = (p - l[0]) / d;\n\treturn p0.imag() == 0.0&&0.0<p0.real() && p0.real()<1.0;\n}\nbool intersect(const Line &l0, const Line &l1, point &p) {\n\tif (connectSS_with_endpoint(l0, l1) || isOn(l0, l1[0]) || isOn(l0, l1[1]) || isOn(l1, l0[0]) || isOn(l1, l0[1]))return false;\n\tpoint d = l0[1] - l0[0];\n\tpoint p0 = (l1[0] - l0[0]) / d;\n\tpoint p1 = (l1[1] - l0[0]) / d;\n\tif (p0.imag()*p1.imag() >= 0)return false;\n\tdouble t = p0.imag() / (p0.imag() - p1.imag());\n\tdouble s = p0.real()*(1 - t) + p1.real()*t;\n\tif (s <= 0.0 || 1.0 <= s)return false;\n\tp = l0[0] + d * s;\n\treturn true;\n}\n\n//距離,交点\n//射影 直線lにpから下した垂線との交点\n\npoint projection(const Line &l, const point &p) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\tdouble t = dot(p - l[0], l[0] - l[1]) / norm(l[0] - l[1]);\n\treturn l[0] + (l[0] - l[1])*t;\n}\n//射影 直線lを対象軸としてpと線対称にある点\npoint reflection(const Line &l, const point &p) {\n\treturn p + (projection(l, p) - p) * 2;\n}\ndouble distancePP(const point& a, const point& b) {\n\treturn sqrt(norm(a - b));\n}\ndouble distanceLP(const Line &l, const point &p) {\n\treturn abs(p - projection(l, p));\n}\ndouble distanceLL(const Line&l, const Line &m) {\n\treturn intersectLL(l, m) ? 0 : distanceLP(l, m[0]);\n}\ndouble distanceLS(const Line &l, const Line &s) {\n\tif (intersectLS(l, s))return 0;\n\treturn min(distanceLP(l, s[0]), distanceLP(l, s[1]));\n}\ndouble distanceSP(const Line &s, const point &p) {\n\tconst point r = projection(s, p);\n\tif (intersectSP(s, r))return abs(r - p);\n\treturn min(abs(s[0] - p), abs(s[1] - p));\n}\ndouble distanceSS(const Line &s, const Line &t) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\tif (intersectSS(s, t))return 0;\n\treturn min({ distanceSP(s,t[0]),distanceSP(s,t[1]),distanceSP(t,s[0]),distanceSP(t,s[1]) });\n}\npoint crosspoint(const Line &l, const Line &m) {\n\tdouble A = cross(l[1] - l[0], m[1] - m[0]);\n\tdouble B = cross(l[1] - l[0], l[1] - m[0]);\n\tif (abs(A) < EPS&&abs(B) < EPS)return m[0];//same line\n\tif (abs(A) < EPS)assert(false); // Precondition not satisfied\n\treturn m[0] + B / A * (m[1] - m[0]);\n}\ndouble dist(point &p1, point &p2) {\n\treturn abs(p1 - p2);\n}\n\n//線分同士の交点で分割して端点以外の共有点を持たないようにする\nvoid splitSegments(Lines &ls) {\n\t//端点が線分上に乗っている場合の分割\n\tfor (int i = 0; i < (int)ls.size(); i++){\n\t\tint mx = ls.size();\n\t\tfor (int j = i + 1; j < (int)ls.size(); j++) {\n\t\t\tif (j >= mx)break;\n\t\t\tfor (int k = 0; k < 2; k++) {\n\t\t\t\t//if(isOn(ls[i],ls[j][k])){\n\t\t\t\tif (intersectSP_without_endpoint(ls[i], ls[j][k])) {\n\t\t\t\t\tls.push_back(Line(ls[i][0], ls[j][k]));\n\t\t\t\t\tls[i][0] = ls[j][k];\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\t//else if(isOn(ls[j],ls[i][k])){\n\t\t\t\telse if (intersectSP_without_endpoint(ls[j], ls[i][k])) {\n\t\t\t\t\tls.push_back(Line(ls[j][0], ls[i][k]));\n\t\t\t\t\tls[j][0] = ls[i][k];\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t//cerr << \"split-1\" << endl;\n\t//線分が交差している場合の分割\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\tLine li = ls[i];\n\t\tint mx = ls.size();\n\t\tfor (int j = i + 1; j < (int)ls.size(); j++) {\n\t\t\tpoint cross_p;\n\t\t\tif (j >= mx)break;\n\t\t\t//if (intersect(ls[i], ls[j], cross_p)) {\n\t\t\tif (intersectSS_strict(ls[i], ls[j])) {\n\t\t\t\tcross_p = crosspoint(ls[i], ls[j]);\n\t\t\t\tls.push_back(Line(ls[i][0], cross_p));\n\t\t\t\tls[i][0] = cross_p;\n\t\t\t\tls.push_back(Line(ls[j][0], cross_p));\n\t\t\t\tls[j][0] = cross_p;\n\t\t\t}\n\t\t}\n\t}\n}\n\n//線分の集合(split済み)を連結成分に分解する(union-find)\n\nstruct Equiv {\n\tvector<int>links;\n\t//大きさ1の同値類をn個作る\n\tEquiv(int n) :links(n) {\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tlinks[i] = i;\n\t\t}\n\t}\n\t//xの属する同値類の代表元を返す\n\tint find(int x) {\n\t\tint xx = links[x];\n\t\tif (xx == x)return x;\n\t\treturn links[x] = find(xx);\n\t}\n\tvoid unify(int x, int y) {\n\t\tint xx = find(x), yy = find(y);\n\t\tif (xx <= yy)links[yy] = xx;\n\t\telse links[xx] = yy;\n\t}\n};\n\ntypedef vector<Lines>vLines;\nvLines connectedComponent(const Lines &ls) {\n\tvLines ret;\n\tEquiv equiv(ls.size());\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\tfor (int j = 0; j < i; j++) {\n\t\t\tif (connectSS_with_endpoint(ls[i], ls[j])) {\n\t\t\t\tequiv.unify(i, j);\n\t\t\t}\n\t\t}\n\t}\n\t//cerr << \"connected-1\" << endl;\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\tif (equiv.find(i) == i) {\n\t\t\tLines newLs;\n\t\t\tnewLs.push_back(ls[i]);\n\t\t\tfor (int j = i + 1; j < (int)ls.size(); j++) {\n\t\t\t\tif (equiv.find(j) == i)newLs.push_back(ls[j]);\n\t\t\t}\n\t\t\tret.push_back(newLs);\n\t\t}\n\t}\n\treturn ret;\n}\n//左手法でのトレース\n//偏角でソートされた隣接点のvectorを得る\ntypedef pair<double, point>doublePoint;\ntypedef vector<doublePoint> vDoublePoint;\ntypedef map<point, vDoublePoint> adjPoint;\ntypedef vector<point>points;\n//移動前の点と隣接点のリストから移動先を決定\npoint findNext(const vDoublePoint &vdp, const point &p) {\n\tfor (int i = 0; i < (int)vdp.size() - 1; i++) {\n\t\tif (p == vdp[i].second) {\n\t\t\treturn vdp[i + 1].second;\n\t\t}\n\t}\n\treturn vdp[0].second;\n}\n//左手法でトレースして通った点の列を返す\npoints trace(const Lines &ls) {\n\tadjPoint aPoint;\n\t//隣接点(偏角付き)のリストを作成\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\taPoint[ls[i][0]].push_back(doublePoint(arg(ls[i][1] - ls[i][0]), ls[i][1]));\n\t\taPoint[ls[i][1]].push_back(doublePoint(arg(ls[i][0] - ls[i][1]), ls[i][0]));\n\t}\n\t//x座標最小の点の計算と隣接点リストのソート\n\tpoint minPoint(INT_MAX, INT_MAX);\n\tadjPoint::iterator it;\n\tfor (it = aPoint.begin(); it != aPoint.end(); ++it) {\n\t\tpoint p = it->first;\n\t\tminPoint = min(minPoint, p);\n\t\tvDoublePoint &vdp = it->second;\n\t\tsort(vdp.begin(), vdp.end());\n\t}\n\tpoints ret;\n\tret.push_back(minPoint);\n\t//最初の移動先\n\tpoint curP = aPoint[minPoint][0].second;\n\tpoint lastP = minPoint;\n\t//トレースの繰り返し\n\twhile (curP != minPoint) {\n\t\tif (DEBUG)cerr << curP << endl;\n\t\tret.push_back(curP);\n\t\tpoint nextP = findNext(aPoint[curP], lastP);\n\t\t//if(isSamePoint(curP,nextP))break;\n\t\tlastP = curP;\n\t\tcurP = nextP;\n\t}\n\t//開始点を最後にも追加\n\tret.push_back(minPoint);\n\treturn ret;\n}\n\nbool isInside(const points &ps) {\n\tLine l0(point(0, 0), point(51.0, 1.0 / 20000.0));\n\tint count = 0;\n\tfor (int i = 0; i < (int)ps.size() - 1; i++) {\n\t\tpoint dummy;\n\t\tLine l1(ps[i], ps[i + 1]);\n\t\tif (intersect(l0, l1, dummy))count++;\n\t}\n\treturn (count & 1) == 1;\n}\n\n\n//円\nstruct Circle {\n\tpoint p; double r;\n\tCircle(const point &p_, double r_) : p(p_), r(r_) { }\n};\n\n//凸包\nvector<point> convex_hull(vector<point> ps) {\n\tint n = ps.size(), k = 0;\n\tsort(ps.begin(), ps.end());\n\tvector<point> ch(2 * n);\n\tfor (int i = 0; i < n; ch[k++] = ps[i++]) // lower-hull\n\t\twhile (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tfor (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--]) // upper-hull\n\t\twhile (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tch.resize(k - 1);\n\treturn ch;\n}\n\n//2点を通る半径Rの円の中心\npair<point, point> get_circle_from_2points(point &p1, point &p2, double R) {\n\tdouble d = dist(p1, p2);\n\tdouble x1 = p1.real(), x2 = p2.real();\n\tdouble y1 = p1.imag(), y2 = p2.imag();\n\tif (p1.imag() == p2.imag()) {\n\t\tdouble x = (x1 + x2) / 2.0;\n\t\tdouble dy = sqrt(R - d * d / 4);\n\t\treturn { { x,y1 + dy },{ x,y1 - dy } };\n\t}\n\telse {\n\t\tdouble m = (x1 - x2) / (y2 - y1);\n\t\tdouble t = sqrt(R*R - d * d / 4);\n\t\tdouble dx = sqrt((t*t) / (m*m + 1));\n\t\tdouble dy = sqrt(t*t - dx * dx);\n\t\tdouble gx = (x1 + x2) / 2;\n\t\tdouble gy = (y1 + y2) / 2;\n\t\tif (m > EPS) {\n\t\t\treturn { { gx + dx,gy + dy },{ gx - dx,gy - dy } };\n\t\t}\n\t\telse {\n\t\t\treturn { { gx + dx,gy - dy },{ gx - dx,gy + dy } };\n\t\t}\n\t}\n}\n//長方形\nstruct Square {\n\tdouble lx, ly, rx, ry;\n\tSquare(double lx_, double ly_, double rx_, double ry_) :lx(lx_), ly(ly_), rx(rx_), ry(ry_) {};\n\tbool include(point &p) {\n\t\treturn p.real() + EPS >= lx && p.real() - EPS <= rx && p.imag() + EPS >= ly && p.imag() - EPS <= ry;\n\t}\n};\n\nstruct Polygon : public vector<point> {\n\t//0->OUT, 1->ON, 2->IN\n\tint contains(const point &p) {\n\t\tbool in = false;\n\t\tint N = this->size();\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tpoint a = this->at(i) - p;\n\t\t\tpoint b = this->at((i + 1) % N) - p;\n\t\t\tif (imag(a) > imag(b)) {\n\t\t\t\tstd::swap(a, b);\n\t\t\t}\n\t\t\tif (imag(a) <= 0 && 0 < imag(b))\n\t\t\t\tif (cross(a, b) < 0)in = !in;\n\t\t\tif (cross(a, b) == 0 && dot(a, b) <= 0)return 1;\n\t\t}\n\t\treturn in ? 2 : 0;\n\t}\n};\nclock_t START, END;\nbool trapAll() {\n\tint N; cin >> N;\n\tif (N == 0) {\n\t\tEND = clock();\n\t\tdouble t = (double)(END - START) / CLOCKS_PER_SEC;\n\t\t//cerr << \"elapsed time\" << t << \"[sec]\" << endl;\n\t\texit(0);\n\t}\n\tLines ls;\n\tREP(i, N) {\n\t\tdouble x1, y1, x2, y2;\n\t\tcin >> x1 >> y1 >> x2 >> y2;\n\t\tpoint p1(x1, y1);\n\t\tpoint p2(x2, y2);\n\t\tls.push_back(Line(p1, p2));\n\t}\n\tsplitSegments(ls);\n\t// for(auto l:ls){\n\t// \tcerr<<l[0]<<\" \"<<l[1]<<endl;\n\t// }\n\t//cerr << \"splitted\" << endl;\n\tvLines vls = connectedComponent(ls);\n\tfor (auto lines : vls) {\n\t\t//if(isInside(trace(lines)))return true;\n\t\tPolygon poly;\n\t\tpoints ps = trace(lines);\n\t\tfor (auto p : ps) {\n\t\t\tpoly.push_back(p);\n\t\t}\n\t\tif (poly.contains(point(0, 0)))return true;\n\t}\n\treturn false;\n}\n\nvoid solve() {\n\tif (trapAll())cout << \"yes\" << endl;\n\telse cout << \"no\" << endl;\n\tif (DEBUG)cerr << \"+++++++++++++\" << endl;\n}\nsigned main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tSTART = clock();\n\twhile (true)\n\t\tsolve();\n\n}", "accuracy": 1, "time_ms": 3930, "memory_kb": 6452, "score_of_the_acc": -0.9429, "final_rank": 10 }, { "submission_id": "aoj_1247_4320285", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#pragma GCC optimize(\"unroll-loops\")\n#include\"bits/stdc++.h\"\n\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(n);i++)\n#define FOR(i,m,n) for(int i=(m);i<(n);i++)\n\nconst bool DEBUG = false;\n\nconst double EPS = 1e-8;\ntypedef complex<double> point;\nistream &operator>>(istream &is, point &p) {\n\tdouble a, b;\n\tis >> a >> b;\n\tp = point(a, b);\n\treturn is;\n}\npoint operator*(const point&p, const double &d) {\n\treturn point(real(p)*d, imag(p)*d);\n}\nnamespace std {\n\tbool operator < (const point& a, const point& b) {\n\t\treturn real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n\t}\n}\n\n//直線or線分\nstruct Line : public vector<point> {\n\tLine(const point &a, const point &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\ntypedef vector<Line>Lines;\n\n\ndouble cross(const point& a, const point& b) {\n\treturn real(a)*imag(b) - imag(a)*real(b);\n}\ndouble dot(const point& a, const point& b) {\n\treturn real(a)*real(b) + imag(a)*imag(b);\n}\nint ccw(point a, point b, point c) {\n\tb = b - a; c = c - a;\n\tif (cross(b, c) > EPS) return +1; // counter clockwise\n\tif (cross(b, c) < -EPS) return -1; // clockwise\n\tif (dot(b, c) < -EPS) return +2; // c--a--b on line\n\tif (norm(b) < norm(c)) return -2; // a--b--c on line\n\treturn 0;\n}\n//交差判定\nbool intersectLL(const Line &l1, const Line &l2) {\n\treturn abs(cross(l1[1] - l1[0], l2[1] - l2[0])) > EPS || //non-parallel\n\t\tabs(cross(l1[1] - l1[0], l2[0] - l1[0])) < EPS; //same line\n}\nbool intersectLS(const Line &l, const Line &s) {\n\treturn cross(l[1] - l[0], s[0] - l[0])* // s[0] is left of l\n\t\tcross(l[1] - l[0], s[1] - l[0]) < EPS; // s[1] is right of l\n}\nbool intersectLP(const Line &l, const point &p) {\n\treturn abs(cross(l[1] - p, l[0] - p)) < EPS;\n}\n//端点に乗ってたらfalse\nbool intersectSP_without_endpoint(const Line &s, const point &p) {\n\tif (abs(s[0] - p) < EPS || abs(s[1] - p) < EPS)return false;\n\treturn abs(s[0] - p) + abs(s[1] - p) - abs(s[1] - s[0]) < EPS; //triangle inequality\n}\n\nbool intersectSP(const Line &s, const point &p) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\treturn abs(s[0] - p) + abs(s[1] - p) - abs(s[1] - s[0]) < EPS; //triangle inequality\n}\nbool connectSS(const Line &s, const Line &t) {\n\tif (intersectSP(s, t[0]) || intersectSP(s, t[1]) || intersectSP(t, s[0]) || intersectSP(t, s[1]))return true;\n\telse return false;\n}\nbool isSamePoint(const point &p1, const point &p2) {\n\treturn abs(p1 - p2)<EPS;\n}\nbool connectSS_with_endpoint(const Line &s, const Line &t) {\n\tREP(i, 2)REP(j, 2) {\n\t\t//if(isSamePoint(s[i],t[j]))return true;\n\t\tif (s[i] == t[j])return true;\n\t}\n\treturn false;\n}\nbool intersectSS(const Line &s, const Line &t) {\n\treturn ccw(s[0], s[1], t[0])*ccw(s[0], s[1], t[1]) <= 0 &&\n\t\tccw(t[0], t[1], s[0])*ccw(t[0], t[1], s[1]) <= 0;\n}\nbool intersectSS_strict(const Line &s, const Line &t) {\n\t//端点が線分上に乗っている場合はfalseにする\n\tif (connectSS(s, t))return false;\n\treturn ccw(s[0], s[1], t[0])*ccw(s[0], s[1], t[1]) <= 0 &&\n\t\tccw(t[0], t[1], s[0])*ccw(t[0], t[1], s[1]) <= 0;\n}\n\nbool isOn(const Line &l, const point &p) {\n\tif (l[0] == p || l[1] == p)return false;\n\tpoint d = l[1] - l[0];\n\tpoint p0 = (p - l[0]) / d;\n\treturn p0.imag() == 0.0&&0.0<p0.real() && p0.real()<1.0;\n}\nbool intersect(const Line &l0, const Line &l1, point &p) {\n\tif (connectSS_with_endpoint(l0, l1) || isOn(l0, l1[0]) || isOn(l0, l1[1]) || isOn(l1, l0[0]) || isOn(l1, l0[1]))return false;\n\tpoint d = l0[1] - l0[0];\n\tpoint p0 = (l1[0] - l0[0]) / d;\n\tpoint p1 = (l1[1] - l0[0]) / d;\n\tif (p0.imag()*p1.imag() >= 0)return false;\n\tdouble t = p0.imag() / (p0.imag() - p1.imag());\n\tdouble s = p0.real()*(1 - t) + p1.real()*t;\n\tif (s <= 0.0 || 1.0 <= s)return false;\n\tp = l0[0] + d * s;\n\treturn true;\n}\n\n//距離,交点\n//射影 直線lにpから下した垂線との交点\n\npoint projection(const Line &l, const point &p) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\tdouble t = dot(p - l[0], l[0] - l[1]) / norm(l[0] - l[1]);\n\treturn l[0] + (l[0] - l[1])*t;\n}\n//射影 直線lを対象軸としてpと線対称にある点\npoint reflection(const Line &l, const point &p) {\n\treturn p + (projection(l, p) - p) * 2;\n}\ndouble distancePP(const point& a, const point& b) {\n\treturn sqrt(norm(a - b));\n}\ndouble distanceLP(const Line &l, const point &p) {\n\treturn abs(p - projection(l, p));\n}\ndouble distanceLL(const Line&l, const Line &m) {\n\treturn intersectLL(l, m) ? 0 : distanceLP(l, m[0]);\n}\ndouble distanceLS(const Line &l, const Line &s) {\n\tif (intersectLS(l, s))return 0;\n\treturn min(distanceLP(l, s[0]), distanceLP(l, s[1]));\n}\ndouble distanceSP(const Line &s, const point &p) {\n\tconst point r = projection(s, p);\n\tif (intersectSP(s, r))return abs(r - p);\n\treturn min(abs(s[0] - p), abs(s[1] - p));\n}\ndouble distanceSS(const Line &s, const Line &t) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\tif (intersectSS(s, t))return 0;\n\treturn min({ distanceSP(s,t[0]),distanceSP(s,t[1]),distanceSP(t,s[0]),distanceSP(t,s[1]) });\n}\npoint crosspoint(const Line &l, const Line &m) {\n\tdouble A = cross(l[1] - l[0], m[1] - m[0]);\n\tdouble B = cross(l[1] - l[0], l[1] - m[0]);\n\tif (abs(A) < EPS&&abs(B) < EPS)return m[0];//same line\n\tif (abs(A) < EPS)assert(false); // Precondition not satisfied\n\treturn m[0] + B / A * (m[1] - m[0]);\n}\ndouble dist(point &p1, point &p2) {\n\treturn abs(p1 - p2);\n}\n\n//線分同士の交点で分割して端点以外の共有点を持たないようにする\nvoid splitSegments(Lines &ls) {\n\t//端点が線分上に乗っている場合の分割\n\tfor (int i = 0; i < (int)ls.size(); i++){\n\t\tint mx = ls.size();\n\t\tfor (int j = i + 1; j < (int)ls.size(); j++) {\n\t\t\tif (j >= mx)break;\n\t\t\tfor (int k = 0; k < 2; k++) {\n\t\t\t\t//if(isOn(ls[i],ls[j][k])){\n\t\t\t\tif (intersectSP_without_endpoint(ls[i], ls[j][k])) {\n\t\t\t\t\tls.push_back(Line(ls[i][0], ls[j][k]));\n\t\t\t\t\tls[i][0] = ls[j][k];\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\t//else if(isOn(ls[j],ls[i][k])){\n\t\t\t\telse if (intersectSP_without_endpoint(ls[j], ls[i][k])) {\n\t\t\t\t\tls.push_back(Line(ls[j][0], ls[i][k]));\n\t\t\t\t\tls[j][0] = ls[i][k];\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t//cerr << \"split-1\" << endl;\n\t//線分が交差している場合の分割\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\tLine li = ls[i];\n\t\tint mx = ls.size();\n\t\tfor (int j = i + 1; j < (int)ls.size(); j++) {\n\t\t\tpoint cross_p;\n\t\t\tif (j >= mx)break;\n\t\t\tif (intersect(ls[i], ls[j], cross_p)) {\n\t\t\t\t//if (intersectSS_strict(ls[i], ls[j])) {\n\t\t\t\t//point cross_p = crosspoint(ls[i], ls[j]);\n\t\t\t\tls.push_back(Line(ls[i][0], cross_p));\n\t\t\t\tls[i][0] = cross_p;\n\t\t\t\tls.push_back(Line(ls[j][0], cross_p));\n\t\t\t\tls[j][0] = cross_p;\n\t\t\t}\n\t\t}\n\t}\n}\n\n//線分の集合(split済み)を連結成分に分解する(union-find)\n\nstruct Equiv {\n\tvector<int>links;\n\t//大きさ1の同値類をn個作る\n\tEquiv(int n) :links(n) {\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tlinks[i] = i;\n\t\t}\n\t}\n\t//xの属する同値類の代表元を返す\n\tint find(int x) {\n\t\tint xx = links[x];\n\t\tif (xx == x)return x;\n\t\treturn links[x] = find(xx);\n\t}\n\tvoid unify(int x, int y) {\n\t\tint xx = find(x), yy = find(y);\n\t\tif (xx <= yy)links[yy] = xx;\n\t\telse links[xx] = yy;\n\t}\n};\n\ntypedef vector<Lines>vLines;\nvLines connectedComponent(const Lines &ls) {\n\tvLines ret;\n\tEquiv equiv(ls.size());\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\tfor (int j = 0; j < i; j++) {\n\t\t\tif (connectSS_with_endpoint(ls[i], ls[j])) {\n\t\t\t\tequiv.unify(i, j);\n\t\t\t}\n\t\t}\n\t}\n\t//cerr << \"connected-1\" << endl;\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\tif (equiv.find(i) == i) {\n\t\t\tLines newLs;\n\t\t\tnewLs.push_back(ls[i]);\n\t\t\tfor (int j = i + 1; j < (int)ls.size(); j++) {\n\t\t\t\tif (equiv.find(j) == i)newLs.push_back(ls[j]);\n\t\t\t}\n\t\t\tret.push_back(newLs);\n\t\t}\n\t}\n\treturn ret;\n}\n//左手法でのトレース\n//偏角でソートされた隣接点のvectorを得る\ntypedef pair<double, point>doublePoint;\ntypedef vector<doublePoint> vDoublePoint;\ntypedef map<point, vDoublePoint> adjPoint;\ntypedef vector<point>points;\n//移動前の点と隣接点のリストから移動先を決定\npoint findNext(const vDoublePoint &vdp, const point &p) {\n\tfor (int i = 0; i < (int)vdp.size() - 1; i++) {\n\t\tif (p == vdp[i].second) {\n\t\t\treturn vdp[i + 1].second;\n\t\t}\n\t}\n\treturn vdp[0].second;\n}\n//左手法でトレースして通った点の列を返す\npoints trace(const Lines &ls) {\n\tadjPoint aPoint;\n\t//隣接点(偏角付き)のリストを作成\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\taPoint[ls[i][0]].push_back(doublePoint(arg(ls[i][1] - ls[i][0]), ls[i][1]));\n\t\taPoint[ls[i][1]].push_back(doublePoint(arg(ls[i][0] - ls[i][1]), ls[i][0]));\n\t}\n\t//x座標最小の点の計算と隣接点リストのソート\n\tpoint minPoint(INT_MAX, INT_MAX);\n\tadjPoint::iterator it;\n\tfor (it = aPoint.begin(); it != aPoint.end(); ++it) {\n\t\tpoint p = it->first;\n\t\tminPoint = min(minPoint, p);\n\t\tvDoublePoint &vdp = it->second;\n\t\tsort(vdp.begin(), vdp.end());\n\t}\n\tpoints ret;\n\tret.push_back(minPoint);\n\t//最初の移動先\n\tpoint curP = aPoint[minPoint][0].second;\n\tpoint lastP = minPoint;\n\t//トレースの繰り返し\n\twhile (curP != minPoint) {\n\t\tif (DEBUG)cerr << curP << endl;\n\t\tret.push_back(curP);\n\t\tpoint nextP = findNext(aPoint[curP], lastP);\n\t\t//if(isSamePoint(curP,nextP))break;\n\t\tlastP = curP;\n\t\tcurP = nextP;\n\t}\n\t//開始点を最後にも追加\n\tret.push_back(minPoint);\n\treturn ret;\n}\n\nbool isInside(const points &ps) {\n\tLine l0(point(0, 0), point(51.0, 1.0 / 20000.0));\n\tint count = 0;\n\tfor (int i = 0; i < (int)ps.size() - 1; i++) {\n\t\tpoint dummy;\n\t\tLine l1(ps[i], ps[i + 1]);\n\t\tif (intersect(l0, l1, dummy))count++;\n\t}\n\treturn (count & 1) == 1;\n}\n\n\n//円\nstruct Circle {\n\tpoint p; double r;\n\tCircle(const point &p_, double r_) : p(p_), r(r_) { }\n};\n\n//凸包\nvector<point> convex_hull(vector<point> ps) {\n\tint n = ps.size(), k = 0;\n\tsort(ps.begin(), ps.end());\n\tvector<point> ch(2 * n);\n\tfor (int i = 0; i < n; ch[k++] = ps[i++]) // lower-hull\n\t\twhile (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tfor (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--]) // upper-hull\n\t\twhile (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tch.resize(k - 1);\n\treturn ch;\n}\n\n//2点を通る半径Rの円の中心\npair<point, point> get_circle_from_2points(point &p1, point &p2, double R) {\n\tdouble d = dist(p1, p2);\n\tdouble x1 = p1.real(), x2 = p2.real();\n\tdouble y1 = p1.imag(), y2 = p2.imag();\n\tif (p1.imag() == p2.imag()) {\n\t\tdouble x = (x1 + x2) / 2.0;\n\t\tdouble dy = sqrt(R - d * d / 4);\n\t\treturn { { x,y1 + dy },{ x,y1 - dy } };\n\t}\n\telse {\n\t\tdouble m = (x1 - x2) / (y2 - y1);\n\t\tdouble t = sqrt(R*R - d * d / 4);\n\t\tdouble dx = sqrt((t*t) / (m*m + 1));\n\t\tdouble dy = sqrt(t*t - dx * dx);\n\t\tdouble gx = (x1 + x2) / 2;\n\t\tdouble gy = (y1 + y2) / 2;\n\t\tif (m > EPS) {\n\t\t\treturn { { gx + dx,gy + dy },{ gx - dx,gy - dy } };\n\t\t}\n\t\telse {\n\t\t\treturn { { gx + dx,gy - dy },{ gx - dx,gy + dy } };\n\t\t}\n\t}\n}\n//長方形\nstruct Square {\n\tdouble lx, ly, rx, ry;\n\tSquare(double lx_, double ly_, double rx_, double ry_) :lx(lx_), ly(ly_), rx(rx_), ry(ry_) {};\n\tbool include(point &p) {\n\t\treturn p.real() + EPS >= lx && p.real() - EPS <= rx && p.imag() + EPS >= ly && p.imag() - EPS <= ry;\n\t}\n};\n\nstruct Polygon : public vector<point> {\n\t//0->OUT, 1->ON, 2->IN\n\tint contains(const point &p) {\n\t\tbool in = false;\n\t\tint N = this->size();\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tpoint a = this->at(i) - p;\n\t\t\tpoint b = this->at((i + 1) % N) - p;\n\t\t\tif (imag(a) > imag(b)) {\n\t\t\t\tstd::swap(a, b);\n\t\t\t}\n\t\t\tif (imag(a) <= 0 && 0 < imag(b))\n\t\t\t\tif (cross(a, b) < 0)in = !in;\n\t\t\tif (cross(a, b) == 0 && dot(a, b) <= 0)return 1;\n\t\t}\n\t\treturn in ? 2 : 0;\n\t}\n};\nclock_t START, END;\nbool trapAll() {\n\tint N; cin >> N;\n\tif (N == 0) {\n\t\tEND = clock();\n\t\tdouble t = (double)(END - START) / CLOCKS_PER_SEC;\n\t\t//cerr << \"elapsed time\" << t << \"[sec]\" << endl;\n\t\texit(0);\n\t}\n\tLines ls;\n\tREP(i, N) {\n\t\tdouble x1, y1, x2, y2;\n\t\tcin >> x1 >> y1 >> x2 >> y2;\n\t\tpoint p1(x1, y1);\n\t\tpoint p2(x2, y2);\n\t\tls.push_back(Line(p1, p2));\n\t}\n\tsplitSegments(ls);\n\t// for(auto l:ls){\n\t// \tcerr<<l[0]<<\" \"<<l[1]<<endl;\n\t// }\n\t//cerr << \"splitted\" << endl;\n\tvLines vls = connectedComponent(ls);\n\tfor (auto lines : vls) {\n\t\tif(isInside(trace(lines)))return true;\n\t\t// Polygon poly;\n\t\t// points ps = trace(lines);\n\t\t// for (auto p : ps) {\n\t\t// \tpoly.push_back(p);\n\t\t// }\n\t\t// if (poly.contains(point(0, 0)))return true;\n\t}\n\treturn false;\n}\n\nvoid solve() {\n\tif (trapAll())cout << \"yes\" << endl;\n\telse cout << \"no\" << endl;\n\tif (DEBUG)cerr << \"+++++++++++++\" << endl;\n}\nsigned main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tSTART = clock();\n\twhile (true)\n\t\tsolve();\n\n}", "accuracy": 1, "time_ms": 5130, "memory_kb": 6292, "score_of_the_acc": -1.1079, "final_rank": 13 }, { "submission_id": "aoj_1247_4320282", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#pragma GCC optimize(\"unroll-loops\")\n#include\"bits/stdc++.h\"\n\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(n);i++)\n#define FOR(i,m,n) for(int i=(m);i<(n);i++)\n\nconst bool DEBUG = false;\n\nconst double EPS = 1e-8;\ntypedef complex<double> point;\nistream &operator>>(istream &is, point &p) {\n double a, b;\n is >> a >> b;\n p = point(a, b);\n return is;\n}\npoint operator*(const point&p, const double &d) {\n\treturn point(real(p)*d, imag(p)*d);\n}\nnamespace std {\n\tbool operator < (const point& a, const point& b) {\n\t\treturn real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n\t}\n}\n\n//直線or線分\nstruct Line : public vector<point> {\n\tLine(const point &a, const point &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\ntypedef vector<Line>Lines;\n\n\ndouble cross(const point& a, const point& b) {\n return real(a)*imag(b)-imag(a)*real(b);\n}\ndouble dot(const point& a, const point& b) {\n return real(a)*real(b)+imag(a)*imag(b);\n}\nint ccw(point a, point b, point c) {\n\tb =b-a; c =c - a;\n\tif (cross(b, c) > EPS) return +1; // counter clockwise\n\tif (cross(b, c) < -EPS) return -1; // clockwise\n\tif (dot(b, c) < -EPS) return +2; // c--a--b on line\n\tif (norm(b) < norm(c)) return -2; // a--b--c on line\n\treturn 0;\n}\n//交差判定\nbool intersectLL(const Line &l1, const Line &l2) {\n\treturn abs(cross(l1[1] - l1[0], l2[1] - l2[0])) > EPS || //non-parallel\n\t\tabs(cross(l1[1] - l1[0], l2[0] - l1[0])) < EPS; //same line\n}\nbool intersectLS(const Line &l, const Line &s) {\n\treturn cross(l[1] - l[0], s[0] - l[0])* // s[0] is left of l\n\t\tcross(l[1] - l[0], s[1] - l[0]) < EPS; // s[1] is right of l\n}\nbool intersectLP(const Line &l, const point &p) {\n\treturn abs(cross(l[1] - p, l[0] - p)) < EPS;\n}\n//端点に乗ってたらfalse\nbool intersectSP_without_endpoint(const Line &s, const point &p) {\n\tif (abs(s[0] - p) < EPS || abs(s[1] - p) < EPS)return false;\n\treturn abs(s[0] - p) + abs(s[1] - p) - abs(s[1] - s[0]) < EPS; //triangle inequality\n}\n\nbool intersectSP(const Line &s, const point &p) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\treturn abs(s[0] - p) + abs(s[1] - p) - abs(s[1] - s[0]) < EPS; //triangle inequality\n}\nbool connectSS(const Line &s, const Line &t) {\n\tif (intersectSP(s, t[0]) || intersectSP(s, t[1]) || intersectSP(t, s[0]) || intersectSP(t, s[1]))return true;\n\telse return false;\n}\nbool isSamePoint(const point &p1,const point &p2){\n\treturn abs(p1-p2)<EPS;\n}\nbool connectSS_with_endpoint(const Line &s,const Line &t){\n\tREP(i,2)REP(j,2){\n\t\t//if(isSamePoint(s[i],t[j]))return true;\n\t\tif(s[i]==t[j])return true;\n\t}\n\treturn false;\n}\nbool intersectSS(const Line &s, const Line &t) {\n\treturn ccw(s[0],s[1],t[0])*ccw(s[0],s[1],t[1]) <= 0 &&\n\t\tccw(t[0],t[1],s[0])*ccw(t[0],t[1],s[1]) <= 0;\n}\nbool intersectSS_strict(const Line &s, const Line &t) {\n\t//端点が線分上に乗っている場合はfalseにする\n\tif (connectSS(s, t))return false;\n\treturn ccw(s[0],s[1],t[0])*ccw(s[0],s[1],t[1]) <= 0 &&\n\t\tccw(t[0],t[1],s[0])*ccw(t[0],t[1],s[1]) <= 0;\n}\n\nbool isOn(const Line &l,const point &p){\n\tif(l[0]==p||l[1]==p)return false;\n\tpoint d=l[1]-l[0];\n\tpoint p0=(p-l[0])/d;\n\treturn p0.imag()==0.0&&0.0<p0.real()&&p0.real()<1.0;\n}\nbool intersect(const Line &l0,const Line &l1, point &p){\n\tif(connectSS_with_endpoint(l0,l1)||isOn(l0,l1[0])||isOn(l0,l1[1])||isOn(l1,l0[0])||isOn(l1,l0[1]))return false;\n\tpoint d = l0[1]-l0[0];\n\tpoint p0=(l1[0]-l0[0])/d;\n\tpoint p1=(l1[1]-l0[0])/d;\n\tif(p0.imag()*p1.imag()>=0)return false;\n\tdouble t=p0.imag()/(p0.imag()-p1.imag());\n\tdouble s=p0.real()*(1-t)+p1.real()*t;\n\tif(s<=0.0||1.0<=s)return false;\n\tp=l0[0]+d*s;\n\treturn true;\n}\n\n//距離,交点\n//射影 直線lにpから下した垂線との交点\n\npoint projection(const Line &l, const point &p) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\tdouble t = dot(p - l[0], l[0] - l[1]) / norm(l[0] - l[1]);\n\treturn l[0] + (l[0] - l[1])*t;\n}\n//射影 直線lを対象軸としてpと線対称にある点\npoint reflection(const Line &l, const point &p) {\n\treturn p + (projection(l, p) - p) * 2;\n}\ndouble distancePP(const point& a, const point& b) {\n\treturn sqrt(norm(a - b));\n}\ndouble distanceLP(const Line &l, const point &p) {\n\treturn abs(p - projection(l, p));\n}\ndouble distanceLL(const Line&l, const Line &m) {\n\treturn intersectLL(l, m) ? 0 : distanceLP(l, m[0]);\n}\ndouble distanceLS(const Line &l, const Line &s) {\n\tif (intersectLS(l, s))return 0;\n\treturn min(distanceLP(l, s[0]), distanceLP(l, s[1]));\n}\ndouble distanceSP(const Line &s, const point &p) {\n\tconst point r = projection(s, p);\n\tif (intersectSP(s, r))return abs(r - p);\n\treturn min(abs(s[0] - p), abs(s[1] - p));\n}\ndouble distanceSS(const Line &s, const Line &t) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\tif (intersectSS(s, t))return 0;\n\treturn min({ distanceSP(s,t[0]),distanceSP(s,t[1]),distanceSP(t,s[0]),distanceSP(t,s[1]) });\n}\npoint crosspoint(const Line &l, const Line &m) {\n\tdouble A = cross(l[1] - l[0], m[1] - m[0]);\n\tdouble B = cross(l[1] - l[0], l[1] - m[0]);\n\tif (abs(A) < EPS&&abs(B) < EPS)return m[0];//same line\n\tif (abs(A) < EPS)assert(false); // Precondition not satisfied\n\treturn m[0] + B / A * (m[1] - m[0]);\n}\ndouble dist(point &p1, point &p2) {\n\treturn abs(p1 - p2);\n}\n\n//線分同士の交点で分割して端点以外の共有点を持たないようにする\nvoid splitSegments(Lines &ls) {\n\t//端点が線分上に乗っている場合の分割\n\tfor (size_t i = 0; i < ls.size(); i++)for (size_t j = i + 1; j < ls.size(); j++) {\n\t\tfor (int k = 0; k < 2; k++) {\n\t\t\t//if(isOn(ls[i],ls[j][k])){\n\t\t\tif (intersectSP_without_endpoint(ls[i], ls[j][k])) {\n\t\t\t\tls.push_back(Line(ls[i][0], ls[j][k]));\n\t\t\t\tls[i][0] = ls[j][k];\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\t//else if(isOn(ls[j],ls[i][k])){\n\t\t\telse if (intersectSP_without_endpoint(ls[j], ls[i][k])) {\n\t\t\t\tls.push_back(Line(ls[j][0], ls[i][k]));\n\t\t\t\tls[j][0] = ls[i][k];\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\t//cerr << \"split-1\" << endl;\n\t//線分が交差している場合の分割\n\tfor (size_t i = 0; i < ls.size(); i++) {\n\t\tLine li = ls[i];\n\t\tfor (size_t j = i + 1; j < ls.size(); j++) {\n\t\t\tpoint cross_p;\n\t\t\tif(intersect(ls[i],ls[j],cross_p)){\n\t\t\t//if (intersectSS_strict(ls[i], ls[j])) {\n\t\t\t\t//point cross_p = crosspoint(ls[i], ls[j]);\n\t\t\t\tls.push_back(Line(ls[i][0], cross_p));\n\t\t\t\tls[i][0] = cross_p;\n\t\t\t\tls.push_back(Line(ls[j][0], cross_p));\n\t\t\t\tls[j][0] = cross_p;\n\t\t\t}\n\t\t}\n\t}\n}\n\n//線分の集合(split済み)を連結成分に分解する(union-find)\n\nstruct Equiv {\n\tvector<int>links;\n\t//大きさ1の同値類をn個作る\n\tEquiv(int n):links(n){\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tlinks[i] = i;\n\t\t}\n\t}\n\t//xの属する同値類の代表元を返す\n\tint find(int x) {\n\t\tint xx = links[x];\n\t\tif (xx == x)return x;\n\t\treturn links[x] = find(xx);\n\t}\n\tvoid unify(int x, int y) {\n\t\tint xx = find(x), yy = find(y);\n\t\tif (xx <= yy)links[yy] = xx;\n\t\telse links[xx] = yy;\n\t}\n};\n\ntypedef vector<Lines>vLines;\nvLines connectedComponent(const Lines &ls) {\n\tvLines ret;\n\tEquiv equiv(ls.size());\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\tfor (int j = 0; j < i; j++) {\n\t\t\tif (connectSS_with_endpoint(ls[i], ls[j])) {\n\t\t\t\tequiv.unify(i, j);\n\t\t\t}\n\t\t}\n\t}\n\t//cerr << \"connected-1\" << endl;\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\tif (equiv.find(i) == i) {\n\t\t\tLines newLs;\n\t\t\tnewLs.push_back(ls[i]);\n\t\t\tfor (int j = i + 1; j < (int)ls.size(); j++) {\n\t\t\t\tif (equiv.find(j) == i)newLs.push_back(ls[j]);\n\t\t\t}\n\t\t\tret.push_back(newLs);\n\t\t}\n\t}\n\treturn ret;\n}\n//左手法でのトレース\n//偏角でソートされた隣接点のvectorを得る\ntypedef pair<double, point>doublePoint;\ntypedef vector<doublePoint> vDoublePoint;\ntypedef map<point, vDoublePoint> adjPoint;\ntypedef vector<point>points;\n//移動前の点と隣接点のリストから移動先を決定\npoint findNext(const vDoublePoint &vdp, const point &p) {\n\tfor (int i = 0; i < (int)vdp.size() - 1; i++) {\n\t\tif (p == vdp[i].second) {\n\t\t\treturn vdp[i + 1].second;\n\t\t}\n\t}\n\treturn vdp[0].second;\n}\n//左手法でトレースして通った点の列を返す\npoints trace(const Lines &ls) {\n\tadjPoint aPoint;\n\t//隣接点(偏角付き)のリストを作成\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\taPoint[ls[i][0]].push_back(doublePoint(arg(ls[i][1] - ls[i][0]), ls[i][1]));\n\t\taPoint[ls[i][1]].push_back(doublePoint(arg(ls[i][0] - ls[i][1]), ls[i][0]));\n\t}\n\t//x座標最小の点の計算と隣接点リストのソート\n\tpoint minPoint(INT_MAX, INT_MAX);\n\tadjPoint::iterator it;\n\tfor (it = aPoint.begin(); it != aPoint.end(); ++it) {\n\t\tpoint p = it->first;\n\t\tminPoint = min(minPoint, p);\n\t\tvDoublePoint &vdp = it->second;\n\t\tsort(vdp.begin(), vdp.end());\n\t}\n\tpoints ret;\n\tret.push_back(minPoint);\n\t//最初の移動先\n\tpoint curP = aPoint[minPoint][0].second;\n\tpoint lastP = minPoint;\n\t//トレースの繰り返し\n\twhile (curP != minPoint) {\n\t\tif(DEBUG)cerr<<curP<<endl;\n\t\tret.push_back(curP);\n\t\tpoint nextP = findNext(aPoint[curP], lastP);\n\t\t//if(isSamePoint(curP,nextP))break;\n\t\tlastP = curP;\n\t\tcurP = nextP;\n\t}\n\t//開始点を最後にも追加\n\tret.push_back(minPoint);\n\treturn ret;\n}\n\nbool isInside(const points &ps) {\n\tLine l0(point(0, 0), point(51.0, 1.0 / 20000.0));\n\tint count = 0;\n\tfor (int i = 0; i < (int)ps.size() - 1; i++) {\n\t\tpoint dummy;\n\t\tLine l1(ps[i], ps[i + 1]);\n\t\tif (intersect(l0, l1,dummy))count++;\n\t}\n\treturn (count & 1) == 1;\n}\n\n\n//円\nstruct Circle {\n\tpoint p; double r;\n\tCircle(const point &p_, double r_) : p(p_), r(r_) { }\n};\n\n//凸包\nvector<point> convex_hull(vector<point> ps) {\n\tint n = ps.size(), k = 0;\n\tsort(ps.begin(), ps.end());\n\tvector<point> ch(2 * n);\n\tfor (int i = 0; i < n; ch[k++] = ps[i++]) // lower-hull\n\t\twhile (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tfor (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--]) // upper-hull\n\t\twhile (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tch.resize(k - 1);\n\treturn ch;\n}\n\n//2点を通る半径Rの円の中心\npair<point, point> get_circle_from_2points(point &p1, point &p2, double R) {\n\tdouble d = dist(p1, p2);\n\tdouble x1 = p1.real(), x2 = p2.real();\n\tdouble y1 = p1.imag(), y2 = p2.imag();\n\tif (p1.imag() == p2.imag()) {\n\t\tdouble x = (x1 + x2) / 2.0;\n\t\tdouble dy = sqrt(R - d * d / 4);\n\t\treturn { { x,y1 + dy },{ x,y1 - dy } };\n\t}\n\telse {\n\t\tdouble m = (x1 - x2) / (y2 - y1);\n\t\tdouble t = sqrt(R*R - d * d / 4);\n\t\tdouble dx = sqrt((t*t) / (m*m + 1));\n\t\tdouble dy = sqrt(t*t - dx * dx);\n\t\tdouble gx = (x1 + x2) / 2;\n\t\tdouble gy = (y1 + y2) / 2;\n\t\tif (m > EPS) {\n\t\t\treturn { { gx + dx,gy + dy },{ gx - dx,gy - dy } };\n\t\t}\n\t\telse {\n\t\t\treturn { { gx + dx,gy - dy },{ gx - dx,gy + dy } };\n\t\t}\n\t}\n}\n//長方形\nstruct Square {\n\tdouble lx, ly, rx, ry;\n\tSquare(double lx_, double ly_, double rx_, double ry_) :lx(lx_), ly(ly_), rx(rx_), ry(ry_) {};\n\tbool include(point &p) {\n\t\treturn p.real() + EPS >= lx && p.real() - EPS <= rx && p.imag() + EPS >= ly && p.imag() - EPS <= ry;\n\t}\n};\n\nstruct Polygon : public vector<point> {\n\t//0->OUT, 1->ON, 2->IN\n\tint contains(const point &p) {\n\t\tbool in = false;\n\t\tint N = this->size();\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tpoint a = this->at(i) - p;\n\t\t\tpoint b = this->at((i + 1) % N) - p;\n\t\t\tif (imag(a) > imag(b)) {\n\t\t\t\tstd::swap(a, b);\n\t\t\t}\n\t\t\tif (imag(a) <= 0 && 0 < imag(b))\n\t\t\t\tif (cross(a, b) < 0)in = !in;\n\t\t\tif (cross(a, b) == 0 && dot(a, b) <= 0)return 1;\n\t\t}\n\t\treturn in ? 2 : 0;\n\t}\n};\nclock_t START,END;\nbool trapAll() {\n\tint N; cin >> N;\n\tif (N == 0){\n\t\tEND=clock();\n\t\tdouble t=(double)(END-START)/CLOCKS_PER_SEC;\n\t\tif(DEBUG)cerr<<\"elapsed time\"<<t<<\"[sec]\"<<endl;\n\t\texit(0);\n\t}\n\tLines ls;\n\tREP(i, N) {\n\t\tdouble x1, y1, x2, y2;\n\t\tcin >> x1 >> y1 >> x2 >> y2;\n\t\tpoint p1(x1, y1);\n\t\tpoint p2(x2, y2);\n\t\tls.push_back(Line(p1, p2));\n\t}\n\tsplitSegments(ls);\n\t// for(auto l:ls){\n\t// \tcerr<<l[0]<<\" \"<<l[1]<<endl;\n\t// }\n\t//cerr << \"splitted\" << endl;\n\tvLines vls = connectedComponent(ls);\n\tfor (auto lines : vls) {\n\t\tPolygon poly;\n\t\tpoints ps= trace(lines);\n\t\tfor (auto p : ps) {\n\t\t\tpoly.push_back(p);\n\t\t}\n\t\tif (poly.contains(point(0, 0)))return true;\n\t}\n\treturn false;\n}\n\nvoid solve() {\n\tif (trapAll())cout << \"yes\" << endl;\n\telse cout << \"no\" << endl;\n\tif(DEBUG)cerr<<\"+++++++++++++\"<<endl;\n}\nsigned main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tSTART = clock();\n\twhile (true)\n\t\tsolve();\n\n}", "accuracy": 1, "time_ms": 5140, "memory_kb": 6448, "score_of_the_acc": -1.1269, "final_rank": 14 }, { "submission_id": "aoj_1247_4320281", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#pragma GCC optimize(\"unroll-loops\")\n#include\"bits/stdc++.h\"\n\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(n);i++)\n#define FOR(i,m,n) for(int i=(m);i<(n);i++)\n\nconst bool DEBUG = false;\n\nconst double EPS = 1e-8;\ntypedef complex<double> point;\nistream &operator>>(istream &is, point &p) {\n double a, b;\n is >> a >> b;\n p = point(a, b);\n return is;\n}\npoint operator*(const point&p, const double &d) {\n\treturn point(real(p)*d, imag(p)*d);\n}\nnamespace std {\n\tbool operator < (const point& a, const point& b) {\n\t\treturn real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n\t}\n}\n\n//直線or線分\nstruct Line : public vector<point> {\n\tLine(const point &a, const point &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\ntypedef vector<Line>Lines;\n\n\ndouble cross(const point& a, const point& b) {\n return real(a)*imag(b)-imag(a)*real(b);\n}\ndouble dot(const point& a, const point& b) {\n return real(a)*real(b)+imag(a)*imag(b);\n}\nint ccw(point a, point b, point c) {\n\tb =b-a; c =c - a;\n\tif (cross(b, c) > EPS) return +1; // counter clockwise\n\tif (cross(b, c) < -EPS) return -1; // clockwise\n\tif (dot(b, c) < -EPS) return +2; // c--a--b on line\n\tif (norm(b) < norm(c)) return -2; // a--b--c on line\n\treturn 0;\n}\n//交差判定\nbool intersectLL(const Line &l1, const Line &l2) {\n\treturn abs(cross(l1[1] - l1[0], l2[1] - l2[0])) > EPS || //non-parallel\n\t\tabs(cross(l1[1] - l1[0], l2[0] - l1[0])) < EPS; //same line\n}\nbool intersectLS(const Line &l, const Line &s) {\n\treturn cross(l[1] - l[0], s[0] - l[0])* // s[0] is left of l\n\t\tcross(l[1] - l[0], s[1] - l[0]) < EPS; // s[1] is right of l\n}\nbool intersectLP(const Line &l, const point &p) {\n\treturn abs(cross(l[1] - p, l[0] - p)) < EPS;\n}\n//端点に乗ってたらfalse\nbool intersectSP_without_endpoint(const Line &s, const point &p) {\n\tif (abs(s[0] - p) < EPS || abs(s[1] - p) < EPS)return false;\n\treturn abs(s[0] - p) + abs(s[1] - p) - abs(s[1] - s[0]) < EPS; //triangle inequality\n}\n\nbool intersectSP(const Line &s, const point &p) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\treturn abs(s[0] - p) + abs(s[1] - p) - abs(s[1] - s[0]) < EPS; //triangle inequality\n}\nbool connectSS(const Line &s, const Line &t) {\n\tif (intersectSP(s, t[0]) || intersectSP(s, t[1]) || intersectSP(t, s[0]) || intersectSP(t, s[1]))return true;\n\telse return false;\n}\nbool isSamePoint(const point &p1,const point &p2){\n\treturn abs(p1-p2)<EPS;\n}\nbool connectSS_with_endpoint(const Line &s,const Line &t){\n\tREP(i,2)REP(j,2){\n\t\t//if(isSamePoint(s[i],t[j]))return true;\n\t\tif(s[i]==t[j])return true;\n\t}\n\treturn false;\n}\nbool intersectSS(const Line &s, const Line &t) {\n\treturn ccw(s[0],s[1],t[0])*ccw(s[0],s[1],t[1]) <= 0 &&\n\t\tccw(t[0],t[1],s[0])*ccw(t[0],t[1],s[1]) <= 0;\n}\nbool intersectSS_strict(const Line &s, const Line &t) {\n\t//端点が線分上に乗っている場合はfalseにする\n\tif (connectSS(s, t))return false;\n\treturn ccw(s[0],s[1],t[0])*ccw(s[0],s[1],t[1]) <= 0 &&\n\t\tccw(t[0],t[1],s[0])*ccw(t[0],t[1],s[1]) <= 0;\n}\n\nbool isOn(const Line &l,const point &p){\n\tif(l[0]==p||l[1]==p)return false;\n\tpoint d=l[1]-l[0];\n\tpoint p0=(p-l[0])/d;\n\treturn p0.imag()==0.0&&0.0<p0.real()&&p0.real()<1.0;\n}\nbool intersect(const Line &l0,const Line &l1, point &p){\n\tif(connectSS_with_endpoint(l0,l1)||isOn(l0,l1[0])||isOn(l0,l1[1])||isOn(l1,l0[0])||isOn(l1,l0[1]))return false;\n\tpoint d = l0[1]-l0[0];\n\tpoint p0=(l1[0]-l0[0])/d;\n\tpoint p1=(l1[1]-l0[0])/d;\n\tif(p0.imag()*p1.imag()>=0)return false;\n\tdouble t=p0.imag()/(p0.imag()-p1.imag());\n\tdouble s=p0.real()*(1-t)+p1.real()*t;\n\tif(s<=0.0||1.0<=s)return false;\n\tp=l0[0]+d*s;\n\treturn true;\n}\n\n//距離,交点\n//射影 直線lにpから下した垂線との交点\n\npoint projection(const Line &l, const point &p) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\tdouble t = dot(p - l[0], l[0] - l[1]) / norm(l[0] - l[1]);\n\treturn l[0] + (l[0] - l[1])*t;\n}\n//射影 直線lを対象軸としてpと線対称にある点\npoint reflection(const Line &l, const point &p) {\n\treturn p + (projection(l, p) - p) * 2;\n}\ndouble distancePP(const point& a, const point& b) {\n\treturn sqrt(norm(a - b));\n}\ndouble distanceLP(const Line &l, const point &p) {\n\treturn abs(p - projection(l, p));\n}\ndouble distanceLL(const Line&l, const Line &m) {\n\treturn intersectLL(l, m) ? 0 : distanceLP(l, m[0]);\n}\ndouble distanceLS(const Line &l, const Line &s) {\n\tif (intersectLS(l, s))return 0;\n\treturn min(distanceLP(l, s[0]), distanceLP(l, s[1]));\n}\ndouble distanceSP(const Line &s, const point &p) {\n\tconst point r = projection(s, p);\n\tif (intersectSP(s, r))return abs(r - p);\n\treturn min(abs(s[0] - p), abs(s[1] - p));\n}\ndouble distanceSS(const Line &s, const Line &t) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\tif (intersectSS(s, t))return 0;\n\treturn min({ distanceSP(s,t[0]),distanceSP(s,t[1]),distanceSP(t,s[0]),distanceSP(t,s[1]) });\n}\npoint crosspoint(const Line &l, const Line &m) {\n\tdouble A = cross(l[1] - l[0], m[1] - m[0]);\n\tdouble B = cross(l[1] - l[0], l[1] - m[0]);\n\tif (abs(A) < EPS&&abs(B) < EPS)return m[0];//same line\n\tif (abs(A) < EPS)assert(false); // Precondition not satisfied\n\treturn m[0] + B / A * (m[1] - m[0]);\n}\ndouble dist(point &p1, point &p2) {\n\treturn abs(p1 - p2);\n}\n\n//線分同士の交点で分割して端点以外の共有点を持たないようにする\nvoid splitSegments(Lines &ls) {\n\t//端点が線分上に乗っている場合の分割\n\tfor (size_t i = 0; i < ls.size(); i++)for (size_t j = i + 1; j < ls.size(); j++) {\n\t\tfor (int k = 0; k < 2; k++) {\n\t\t\tif(isOn(ls[i],ls[j][k])){\n\t\t\t//if (intersectSP_without_endpoint(ls[i], ls[j][k])) {\n\t\t\t\tls.push_back(Line(ls[i][0], ls[j][k]));\n\t\t\t\tls[i][0] = ls[j][k];\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse if(isOn(ls[j],ls[i][k])){\n\t\t\t//else if (intersectSP_without_endpoint(ls[j], ls[i][k])) {\n\t\t\t\tls.push_back(Line(ls[j][0], ls[i][k]));\n\t\t\t\tls[j][0] = ls[i][k];\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\t//cerr << \"split-1\" << endl;\n\t//線分が交差している場合の分割\n\tfor (size_t i = 0; i < ls.size(); i++) {\n\t\tLine li = ls[i];\n\t\tfor (size_t j = i + 1; j < ls.size(); j++) {\n\t\t\tpoint cross_p;\n\t\t\tif(intersect(ls[i],ls[j],cross_p)){\n\t\t\t//if (intersectSS_strict(ls[i], ls[j])) {\n\t\t\t\t//point cross_p = crosspoint(ls[i], ls[j]);\n\t\t\t\tls.push_back(Line(ls[i][0], cross_p));\n\t\t\t\tls[i][0] = cross_p;\n\t\t\t\tls.push_back(Line(ls[j][0], cross_p));\n\t\t\t\tls[j][0] = cross_p;\n\t\t\t}\n\t\t}\n\t}\n}\n\n//線分の集合(split済み)を連結成分に分解する(union-find)\n\nstruct Equiv {\n\tvector<int>links;\n\t//大きさ1の同値類をn個作る\n\tEquiv(int n):links(n){\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tlinks[i] = i;\n\t\t}\n\t}\n\t//xの属する同値類の代表元を返す\n\tint find(int x) {\n\t\tint xx = links[x];\n\t\tif (xx == x)return x;\n\t\treturn links[x] = find(xx);\n\t}\n\tvoid unify(int x, int y) {\n\t\tint xx = find(x), yy = find(y);\n\t\tif (xx <= yy)links[yy] = xx;\n\t\telse links[xx] = yy;\n\t}\n};\n\ntypedef vector<Lines>vLines;\nvLines connectedComponent(const Lines &ls) {\n\tvLines ret;\n\tEquiv equiv(ls.size());\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\tfor (int j = 0; j < i; j++) {\n\t\t\tif (connectSS_with_endpoint(ls[i], ls[j])) {\n\t\t\t\tequiv.unify(i, j);\n\t\t\t}\n\t\t}\n\t}\n\t//cerr << \"connected-1\" << endl;\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\tif (equiv.find(i) == i) {\n\t\t\tLines newLs;\n\t\t\tnewLs.push_back(ls[i]);\n\t\t\tfor (int j = i + 1; j < (int)ls.size(); j++) {\n\t\t\t\tif (equiv.find(j) == i)newLs.push_back(ls[j]);\n\t\t\t}\n\t\t\tret.push_back(newLs);\n\t\t}\n\t}\n\treturn ret;\n}\n//左手法でのトレース\n//偏角でソートされた隣接点のvectorを得る\ntypedef pair<double, point>doublePoint;\ntypedef vector<doublePoint> vDoublePoint;\ntypedef map<point, vDoublePoint> adjPoint;\ntypedef vector<point>points;\n//移動前の点と隣接点のリストから移動先を決定\npoint findNext(const vDoublePoint &vdp, const point &p) {\n\tfor (int i = 0; i < (int)vdp.size() - 1; i++) {\n\t\tif (p == vdp[i].second) {\n\t\t\treturn vdp[i + 1].second;\n\t\t}\n\t}\n\treturn vdp[0].second;\n}\n//左手法でトレースして通った点の列を返す\npoints trace(const Lines &ls) {\n\tadjPoint aPoint;\n\t//隣接点(偏角付き)のリストを作成\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\taPoint[ls[i][0]].push_back(doublePoint(arg(ls[i][1] - ls[i][0]), ls[i][1]));\n\t\taPoint[ls[i][1]].push_back(doublePoint(arg(ls[i][0] - ls[i][1]), ls[i][0]));\n\t}\n\t//x座標最小の点の計算と隣接点リストのソート\n\tpoint minPoint(INT_MAX, INT_MAX);\n\tadjPoint::iterator it;\n\tfor (it = aPoint.begin(); it != aPoint.end(); ++it) {\n\t\tpoint p = it->first;\n\t\tminPoint = min(minPoint, p);\n\t\tvDoublePoint &vdp = it->second;\n\t\tsort(vdp.begin(), vdp.end());\n\t}\n\tpoints ret;\n\tret.push_back(minPoint);\n\t//最初の移動先\n\tpoint curP = aPoint[minPoint][0].second;\n\tpoint lastP = minPoint;\n\t//トレースの繰り返し\n\twhile (curP != minPoint) {\n\t\tif(DEBUG)cerr<<curP<<endl;\n\t\tret.push_back(curP);\n\t\tpoint nextP = findNext(aPoint[curP], lastP);\n\t\t//if(isSamePoint(curP,nextP))break;\n\t\tlastP = curP;\n\t\tcurP = nextP;\n\t}\n\t//開始点を最後にも追加\n\tret.push_back(minPoint);\n\treturn ret;\n}\n\nbool isInside(const points &ps) {\n\tLine l0(point(0, 0), point(51.0, 1.0 / 20000.0));\n\tint count = 0;\n\tfor (int i = 0; i < (int)ps.size() - 1; i++) {\n\t\tpoint dummy;\n\t\tLine l1(ps[i], ps[i + 1]);\n\t\tif (intersect(l0, l1,dummy))count++;\n\t}\n\treturn (count & 1) == 1;\n}\n\n\n//円\nstruct Circle {\n\tpoint p; double r;\n\tCircle(const point &p_, double r_) : p(p_), r(r_) { }\n};\n\n//凸包\nvector<point> convex_hull(vector<point> ps) {\n\tint n = ps.size(), k = 0;\n\tsort(ps.begin(), ps.end());\n\tvector<point> ch(2 * n);\n\tfor (int i = 0; i < n; ch[k++] = ps[i++]) // lower-hull\n\t\twhile (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tfor (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--]) // upper-hull\n\t\twhile (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tch.resize(k - 1);\n\treturn ch;\n}\n\n//2点を通る半径Rの円の中心\npair<point, point> get_circle_from_2points(point &p1, point &p2, double R) {\n\tdouble d = dist(p1, p2);\n\tdouble x1 = p1.real(), x2 = p2.real();\n\tdouble y1 = p1.imag(), y2 = p2.imag();\n\tif (p1.imag() == p2.imag()) {\n\t\tdouble x = (x1 + x2) / 2.0;\n\t\tdouble dy = sqrt(R - d * d / 4);\n\t\treturn { { x,y1 + dy },{ x,y1 - dy } };\n\t}\n\telse {\n\t\tdouble m = (x1 - x2) / (y2 - y1);\n\t\tdouble t = sqrt(R*R - d * d / 4);\n\t\tdouble dx = sqrt((t*t) / (m*m + 1));\n\t\tdouble dy = sqrt(t*t - dx * dx);\n\t\tdouble gx = (x1 + x2) / 2;\n\t\tdouble gy = (y1 + y2) / 2;\n\t\tif (m > EPS) {\n\t\t\treturn { { gx + dx,gy + dy },{ gx - dx,gy - dy } };\n\t\t}\n\t\telse {\n\t\t\treturn { { gx + dx,gy - dy },{ gx - dx,gy + dy } };\n\t\t}\n\t}\n}\n//長方形\nstruct Square {\n\tdouble lx, ly, rx, ry;\n\tSquare(double lx_, double ly_, double rx_, double ry_) :lx(lx_), ly(ly_), rx(rx_), ry(ry_) {};\n\tbool include(point &p) {\n\t\treturn p.real() + EPS >= lx && p.real() - EPS <= rx && p.imag() + EPS >= ly && p.imag() - EPS <= ry;\n\t}\n};\n\nstruct Polygon : public vector<point> {\n\t//0->OUT, 1->ON, 2->IN\n\tint contains(const point &p) {\n\t\tbool in = false;\n\t\tint N = this->size();\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tpoint a = this->at(i) - p;\n\t\t\tpoint b = this->at((i + 1) % N) - p;\n\t\t\tif (imag(a) > imag(b)) {\n\t\t\t\tstd::swap(a, b);\n\t\t\t}\n\t\t\tif (imag(a) <= 0 && 0 < imag(b))\n\t\t\t\tif (cross(a, b) < 0)in = !in;\n\t\t\tif (cross(a, b) == 0 && dot(a, b) <= 0)return 1;\n\t\t}\n\t\treturn in ? 2 : 0;\n\t}\n};\nclock_t START,END;\nbool trapAll() {\n\tint N; cin >> N;\n\tif (N == 0){\n\t\tEND=clock();\n\t\tdouble t=(double)(END-START)/CLOCKS_PER_SEC;\n\t\t//cerr<<\"elapsed time\"<<t<<\"[sec]\"<<endl;\n\t\texit(0);\n\t}\n\tLines ls;\n\tREP(i, N) {\n\t\tdouble x1, y1, x2, y2;\n\t\tcin >> x1 >> y1 >> x2 >> y2;\n\t\tpoint p1(x1, y1);\n\t\tpoint p2(x2, y2);\n\t\tls.push_back(Line(p1, p2));\n\t}\n\tsplitSegments(ls);\n\t// for(auto l:ls){\n\t// \tcerr<<l[0]<<\" \"<<l[1]<<endl;\n\t// }\n\t//cerr << \"splitted\" << endl;\n\tvLines vls = connectedComponent(ls);\n\tfor (auto lines : vls) {\n\t\tPolygon poly;\n\t\tpoints ps= trace(lines);\n\t\tfor (auto p : ps) {\n\t\t\tpoly.push_back(p);\n\t\t}\n\t\tif (poly.contains(point(0, 0)))return true;\n\t}\n\treturn false;\n}\n\nvoid solve() {\n\tif (trapAll())cout << \"yes\" << endl;\n\telse cout << \"no\" << endl;\n\tif(DEBUG)cerr<<\"+++++++++++++\"<<endl;\n}\nsigned main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tSTART = clock();\n\twhile (true)\n\t\tsolve();\n\n}", "accuracy": 1, "time_ms": 5150, "memory_kb": 6436, "score_of_the_acc": -1.1271, "final_rank": 15 }, { "submission_id": "aoj_1247_4320251", "code_snippet": "#include\"bits/stdc++.h\"\n\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(n);i++)\n#define FOR(i,m,n) for(int i=(m);i<(n);i++)\n\nconst double EPS = 1e-8;\ntypedef complex<double> point;\npoint operator*(const point&p, const double &d) {\n\treturn point(real(p)*d, imag(p)*d);\n}\nnamespace std {\n\tbool operator < (const point& a, const point& b) {\n\t\treturn real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n\t}\n\n\t//istream &operator>>(istream &stream, point &p) {\n\t//\tstream >> p.real >> p.imag;\n\t//\treturn stream;\n\t//}\n}\n//bool intersectLL(const Line &l1, const Line &l2);\n//bool intersectLS(const Line &l, const Line &s);\n//bool intersectLP(const Line &l, const point &p);\n//bool intersectSS(const Line &s, const Line &t);\n//bool intersectSP(const Line &s, const point &p);\n\n//直線or線分\nstruct Line : public vector<point> {\n\tLine(const point &a, const point &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\ntypedef vector<Line>Lines;\n\n\n//外積\ndouble cross(const point& a, const point& b) {\n\treturn imag(conj(a)*b);\n}\n//内積\ndouble dot(const point& a, const point& b) {\n\treturn real(conj(a)*b);\n}\nint ccw(point a, point b, point c) {\n\tb -= a; c -= a;\n\tif (cross(b, c) > 0) return +1; // counter clockwise\n\tif (cross(b, c) < 0) return -1; // clockwise\n\tif (dot(b, c) < 0) return +2; // c--a--b on line\n\tif (norm(b) < norm(c)) return -2; // a--b--c on line\n\treturn 0;\n}\n//交差判定\nbool intersectLL(const Line &l1, const Line &l2) {\n\treturn abs(cross(l1[1] - l1[0], l2[1] - l2[0])) > EPS || //non-parallel\n\t\tabs(cross(l1[1] - l1[0], l2[0] - l1[0])) < EPS; //same line\n}\nbool intersectLS(const Line &l, const Line &s) {\n\treturn cross(l[1] - l[0], s[0] - l[0])* // s[0] is left of l\n\t\tcross(l[1] - l[0], s[1] - l[0]) < EPS; // s[1] is right of l\n}\nbool intersectLP(const Line &l, const point &p) {\n\treturn abs(cross(l[1] - p, l[0] - p)) < EPS;\n}\n//端点に乗ってたらfalse\nbool intersectSP_without_endpoint(const Line &s, const point &p) {\n\tif (abs(s[0] - p) < EPS || abs(s[1] - p) < EPS)return false;\n\treturn abs(s[0] - p) + abs(s[1] - p) - abs(s[1] - s[0]) < EPS; //triangle inequality\n}\n\nbool intersectSP(const Line &s, const point &p) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\treturn abs(s[0] - p) + abs(s[1] - p) - abs(s[1] - s[0]) < EPS; //triangle inequality\n}\nbool connectSS(const Line &s, const Line &t) {\n\tif (intersectSP(s, t[0]) || intersectSP(s, t[1]) || intersectSP(t, s[0]) || intersectSP(t, s[1]))return true;\n\telse return false;\n}\nbool isSamePoint(const point &p1,const point &p2){\n\treturn abs(p1-p2)<EPS;\n}\nbool connectSS_with_endpoint(const Line &s,const Line &t){\n\tREP(i,2)REP(j,2){\n\t\t//if(isSamePoint(s[i],t[j]))return true;\n\t\tif(s[i]==t[j])return true;\n\t}\n\treturn false;\n}\nbool intersectSS(const Line &s, const Line &t) {\n\t//端点が線分上に乗っている場合はfalseにする\n\tif (connectSS(s, t))return false;\n\treturn ccw(s[0], s[1], t[0])*ccw(s[0], s[1], t[1]) <= 0 &&\n\t\tccw(t[0], t[1], s[0])*ccw(t[0], t[1], s[1]) <= 0;\n}\n\nbool isOn(const Line &l,const point &p){\n\tif(l[0]==p||l[1]==p)return false;\n\tpoint d=l[1]-l[0];\n\tpoint p0=(p-l[0])/d;\n\treturn p0.imag()==0.0&&0.0<p0.real()&&p0.real()<1.0;\n}\nbool intersect(const Line &l0,const Line &l1, point &p){\n\tif(connectSS_with_endpoint(l0,l1)||isOn(l0,l1[0])||isOn(l0,l1[1])||isOn(l1,l0[0])||isOn(l1,l0[1]))return false;\n\tpoint d = l0[1]-l0[0];\n\tpoint p0=(l1[0]-l0[0])/d;\n\tpoint p1=(l1[1]-l0[0])/d;\n\tif(p0.imag()*p1.imag()>=0)return false;\n\tdouble t=p0.imag()/(p0.imag()-p1.imag());\n\tdouble s=p0.real()*(1-t)+p1.real()*t;\n\tif(s<=0.0||1.0<=s)return false;\n\tp=l0[0]+d*s;\n\treturn true;\n}\n\n//距離,交点\n//射影 直線lにpから下した垂線との交点\n\npoint projection(const Line &l, const point &p) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\tdouble t = dot(p - l[0], l[0] - l[1]) / norm(l[0] - l[1]);\n\treturn l[0] + (l[0] - l[1])*t;\n}\n//射影 直線lを対象軸としてpと線対称にある点\npoint reflection(const Line &l, const point &p) {\n\treturn p + (projection(l, p) - p) * 2;\n}\ndouble distancePP(const point& a, const point& b) {\n\treturn sqrt(norm(a - b));\n}\ndouble distanceLP(const Line &l, const point &p) {\n\treturn abs(p - projection(l, p));\n}\ndouble distanceLL(const Line&l, const Line &m) {\n\treturn intersectLL(l, m) ? 0 : distanceLP(l, m[0]);\n}\ndouble distanceLS(const Line &l, const Line &s) {\n\tif (intersectLS(l, s))return 0;\n\treturn min(distanceLP(l, s[0]), distanceLP(l, s[1]));\n}\ndouble distanceSP(const Line &s, const point &p) {\n\tconst point r = projection(s, p);\n\tif (intersectSP(s, r))return abs(r - p);\n\treturn min(abs(s[0] - p), abs(s[1] - p));\n}\ndouble distanceSS(const Line &s, const Line &t) { //verified on 2020/04/03 https://onlinejudge.u-aizu.ac.jp/status/users/Mojumbo/submissions/1/1157/judge/4316978/C++14\n\tif (intersectSS(s, t))return 0;\n\treturn min({ distanceSP(s,t[0]),distanceSP(s,t[1]),distanceSP(t,s[0]),distanceSP(t,s[1]) });\n}\npoint crosspoint(const Line &l, const Line &m) {\n\tdouble A = cross(l[1] - l[0], m[1] - m[0]);\n\tdouble B = cross(l[1] - l[0], l[1] - m[0]);\n\tif (abs(A) < EPS&&abs(B) < EPS)return m[0];//same line\n\tif (abs(A) < EPS)assert(false); // Precondition not satisfied\n\treturn m[0] + B / A * (m[1] - m[0]);\n}\ndouble dist(point &p1, point &p2) {\n\treturn abs(p1 - p2);\n}\n\n//線分同士の交点で分割して端点以外の共有点を持たないようにする\nvoid splitSegments(Lines &ls) {\n\t//端点が線分上に乗っている場合の分割\n\tfor (size_t i = 0; i < ls.size(); i++)for (size_t j = i + 1; j < ls.size(); j++) {\n\t\tfor (int k = 0; k < 2; k++) {\n\t\t\tif(isOn(ls[i],ls[j][k])){\n\t\t\t//if (intersectSP_without_endpoint(ls[i], ls[j][k])) {\n\t\t\t\tls.push_back(Line(ls[i][0], ls[j][k]));\n\t\t\t\tls[i][0] = ls[j][k];\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse if(isOn(ls[j],ls[i][k])){\n\t\t\t//else if (intersectSP_without_endpoint(ls[j], ls[i][k])) {\n\t\t\t\tls.push_back(Line(ls[j][0], ls[i][k]));\n\t\t\t\tls[j][0] = ls[i][k];\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\t//cerr << \"split-1\" << endl;\n\t//線分が交差している場合の分割\n\tfor (size_t i = 0; i < ls.size(); i++) {\n\t\tLine li = ls[i];\n\t\tfor (size_t j = i + 1; j < ls.size(); j++) {\n\t\t\tpoint cross_p;\n\t\t\tif(intersect(ls[i],ls[j],cross_p)){\n\t\t\t//if (intersectSS(ls[i], ls[j])) {\n\t\t\t\t//point cross_p = crosspoint(ls[i], ls[j]);\n\t\t\t\tls.push_back(Line(ls[i][0], cross_p));\n\t\t\t\tls[i][0] = cross_p;\n\t\t\t\tls.push_back(Line(ls[j][0], cross_p));\n\t\t\t\tls[j][0] = cross_p;\n\t\t\t}\n\t\t}\n\t}\n}\n\n//線分の集合(split済み)を連結成分に分解する(union-find)\nstruct Equiv {\n\tvector<int>links;\n\t//大きさ1の同値類をn個作る\n\tEquiv(int n) :links(n) {\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tlinks[i] = i;\n\t\t}\n\t}\n\t//xの属する同値類の代表元を返す\n\tint find(int x) {\n\t\tint xx = links[x];\n\t\tif (xx == x)return x;\n\t\treturn links[x] = find(xx);\n\t}\n\tvoid unify(int x, int y) {\n\t\tint xx = find(x), yy = find(y);\n\t\tif (xx <= yy)links[yy] = xx;\n\t\telse links[xx] = yy;\n\t}\n};\n\ntypedef vector<Lines>vLines;\nvLines connectedComponent(const Lines &ls) {\n\tvLines ret;\n\tEquiv equiv(ls.size());\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\tfor (int j = 0; j < i; j++) {\n\t\t\tif (connectSS_with_endpoint(ls[i], ls[j])) {\n\t\t\t\tequiv.unify(i, j);\n\t\t\t}\n\t\t}\n\t}\n\t//cerr << \"connected-1\" << endl;\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\tif (equiv.find(i) == i) {\n\t\t\tLines newLs;\n\t\t\tnewLs.push_back(ls[i]);\n\t\t\tfor (int j = i + 1; j < (int)ls.size(); j++) {\n\t\t\t\tif (equiv.find(j) == i)newLs.push_back(ls[j]);\n\t\t\t}\n\t\t\tret.push_back(newLs);\n\t\t}\n\t}\n\treturn ret;\n}\n//左手法でのトレース\n//偏角でソートされた隣接点のvectorを得る\ntypedef pair<double, point>doublePoint;\ntypedef vector<doublePoint> vDoublePoint;\ntypedef map<point, vDoublePoint> adjPoint;\ntypedef vector<point>points;\n//移動前の点と隣接点のリストから移動先を決定\npoint findNext(const vDoublePoint &vdp, const point &p) {\n\tfor (int i = 0; i < (int)vdp.size() - 1; i++) {\n\t\tif (p == vdp[i].second) {\n\t\t\treturn vdp[i + 1].second;\n\t\t}\n\t}\n\treturn vdp[0].second;\n}\n//左手法でトレースして通った点の列を返す\npoints trace(const Lines &ls) {\n\tadjPoint aPoint;\n\t//隣接点(偏角付き)のリストを作成\n\tfor (int i = 0; i < (int)ls.size(); i++) {\n\t\taPoint[ls[i][0]].push_back(doublePoint(arg(ls[i][1] - ls[i][0]), ls[i][1]));\n\t\taPoint[ls[i][1]].push_back(doublePoint(arg(ls[i][0] - ls[i][1]), ls[i][0]));\n\t}\n\t//x座標最小の点の計算と隣接点リストのソート\n\tpoint minPoint(INT_MAX, INT_MAX);\n\tadjPoint::iterator it;\n\tfor (it = aPoint.begin(); it != aPoint.end(); ++it) {\n\t\tpoint p = it->first;\n\t\tminPoint = min(minPoint, p);\n\t\tvDoublePoint &vdp = it->second;\n\t\tsort(vdp.begin(), vdp.end());\n\t}\n\tpoints ret;\n\tret.push_back(minPoint);\n\t//最初の移動先\n\tpoint curP = aPoint[minPoint][0].second;\n\tpoint lastP = minPoint;\n\t//トレースの繰り返し\n\tint cnt =0;\n\twhile (curP != minPoint) {\n\t\t//cerr<<curP<<endl;\n\t\tcnt++;\n\t\tassert(cnt<1000000);\n\t\tret.push_back(curP);\n\t\tpoint nextP = findNext(aPoint[curP], lastP);\n\t\t//if(isSamePoint(curP,nextP))break;\n\t\tlastP = curP;\n\t\tcurP = nextP;\n\t}\n\t//開始点を最後にも追加\n\tret.push_back(minPoint);\n\treturn ret;\n}\n\nbool isInside(const points &ps) {\n\tLine l0(point(0, 0), point(51.0, 1.0 / 20000.0));\n\tint count = 0;\n\tfor (int i = 0; i < (int)ps.size() - 1; i++) {\n\t\tpoint dummy;\n\t\tLine l1(ps[i], ps[i + 1]);\n\t\tif (intersect(l0, l1,dummy))count++;\n\t}\n\treturn (count & 1) == 1;\n}\n\n\n//円\nstruct Circle {\n\tpoint p; double r;\n\tCircle(const point &p_, double r_) : p(p_), r(r_) { }\n};\n\n//凸包\nvector<point> convex_hull(vector<point> ps) {\n\tint n = ps.size(), k = 0;\n\tsort(ps.begin(), ps.end());\n\tvector<point> ch(2 * n);\n\tfor (int i = 0; i < n; ch[k++] = ps[i++]) // lower-hull\n\t\twhile (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tfor (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--]) // upper-hull\n\t\twhile (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tch.resize(k - 1);\n\treturn ch;\n}\n\n//2点を通る半径Rの円の中心\npair<point, point> get_circle_from_2points(point &p1, point &p2, double R) {\n\tdouble d = dist(p1, p2);\n\tdouble x1 = p1.real(), x2 = p2.real();\n\tdouble y1 = p1.imag(), y2 = p2.imag();\n\tif (p1.imag() == p2.imag()) {\n\t\tdouble x = (x1 + x2) / 2.0;\n\t\tdouble dy = sqrt(R - d * d / 4);\n\t\treturn { { x,y1 + dy },{ x,y1 - dy } };\n\t}\n\telse {\n\t\tdouble m = (x1 - x2) / (y2 - y1);\n\t\tdouble t = sqrt(R*R - d * d / 4);\n\t\tdouble dx = sqrt((t*t) / (m*m + 1));\n\t\tdouble dy = sqrt(t*t - dx * dx);\n\t\tdouble gx = (x1 + x2) / 2;\n\t\tdouble gy = (y1 + y2) / 2;\n\t\tif (m > EPS) {\n\t\t\treturn { { gx + dx,gy + dy },{ gx - dx,gy - dy } };\n\t\t}\n\t\telse {\n\t\t\treturn { { gx + dx,gy - dy },{ gx - dx,gy + dy } };\n\t\t}\n\t}\n}\n//長方形\nstruct Square {\n\tdouble lx, ly, rx, ry;\n\tSquare(double lx_, double ly_, double rx_, double ry_) :lx(lx_), ly(ly_), rx(rx_), ry(ry_) {};\n\tbool include(point &p) {\n\t\treturn p.real() + EPS >= lx && p.real() - EPS <= rx && p.imag() + EPS >= ly && p.imag() - EPS <= ry;\n\t}\n};\n\nstruct Polygon : public vector<point> {\n\t//0->OUT, 1->ON, 2->IN\n\tint contains(const point &p) {\n\t\tbool in = false;\n\t\tint N = this->size();\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tpoint a = this->at(i) - p;\n\t\t\tpoint b = this->at((i + 1) % N) - p;\n\t\t\tif (imag(a) > imag(b)) {\n\t\t\t\tstd::swap(a, b);\n\t\t\t}\n\t\t\tif (imag(a) <= 0 && 0 < imag(b))\n\t\t\t\tif (cross(a, b) < 0)in = !in;\n\t\t\tif (cross(a, b) == 0 && dot(a, b) <= 0)return 1;\n\t\t}\n\t\treturn in ? 2 : 0;\n\t}\n};\n\nbool trapAll() {\n\tint N; cin >> N;\n\tif (N == 0)exit(0);\n\tLines ls;\n\tREP(i, N) {\n\t\tdouble x1, y1, x2, y2;\n\t\tcin >> x1 >> y1 >> x2 >> y2;\n\t\tpoint p1(x1, y1);\n\t\tpoint p2(x2, y2);\n\t\tls.push_back(Line(p1, p2));\n\t}\n\tsplitSegments(ls);\n\t// for(auto l:ls){\n\t// \tcerr<<l[0]<<\" \"<<l[1]<<endl;\n\t// }\n\t//cerr << \"splitted\" << endl;\n\tvLines vls = connectedComponent(ls);\n\tfor (auto lines : vls) {\n\t\tPolygon poly;\n\t\tpoints ps= trace(lines);\n\t\tfor (auto p : ps) {\n\t\t\tpoly.push_back(p);\n\t\t}\n\t\tif (poly.contains(point(0, 0)))return true;\n\t}\n\treturn false;\n}\nvoid solve() {\n\tif (trapAll())cout << \"yes\" << endl;\n\telse cout << \"no\" << endl;\n\t//cerr<<\"+++++++++++++\"<<endl;\n}\nsigned main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\twhile (true)\n\t\tsolve();\n}", "accuracy": 1, "time_ms": 5390, "memory_kb": 6372, "score_of_the_acc": -1.1565, "final_rank": 16 }, { "submission_id": "aoj_1247_3352563", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <cmath>\n#include <queue>\n#include <vector>\n#include <utility>\n#include <set>\n//#define LOCAL\n#define maxv 205\n#define maxn 105\n#define EPS 1e-10\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\nstruct Point{\n\tdouble x,y;\n\tPoint(double x = 0.0,double y = 0.0): x(x),y(y) {}\n\tPoint operator + (Point p){\n\t\treturn Point(x + p.x,y + p.y);\n\t}\n\tPoint operator - (Point p){\n\t\treturn Point(x - p.x,y - p.y);\n\t}\n\tPoint operator * (double lambda){\n\t\treturn Point(x * lambda,y * lambda);\n\t}\n\tPoint operator / (double lambda){\n\t\treturn Point(x / lambda,y / lambda);\n\t}\n\tdouble norm(){\n\t\treturn x * x + y * y;\n\t}\n\tdouble abs_(){\n\t\treturn sqrt(norm());\n\t}\n\tdouble pol(){\n\t\treturn atan2(y,x);\n\t}\n\tbool operator == (const Point &p)const\n\t{\n\t\treturn abs(x - p.x) < EPS && abs(y - p.y) < EPS;\n\t}\n\tbool operator < (const Point &p)const\n\t{\n\t\tif(abs(x - p.x) < EPS) return y < p.y;\n\t\telse return x < p.x;\n\t}\n};\ntypedef Point Vector;\nstruct Segment{\n\tPoint p1,p2;\n\tSegment(Point p1 = Point(),Point p2 = Point()): p1(p1),p2(p2) {}\n};\nPoint front(Segment s){\n\tVector a = s.p2 - s.p1;\n\ta = a / a.abs_() * 5e-4;\n\treturn s.p2 + a;\n}\nPoint back(Segment s){\n\tVector a = s.p2 - s.p1;\n\ta = a / a.abs_() * 5e-4;\n\treturn s.p1 - a;\n}\ntypedef Segment Line;\ntypedef vector<Point> Polygon;\ndouble dot(Vector a,Vector b){ return a.x * b.x + a.y * b.y; }\ndouble det(Vector a,Vector b){ return a.x * b.y - a.y * b.x; }\nvector <int> adj[maxv];\nPoint p[maxv]; int pk;\nSegment s[maxn]; int n;\nint ccw(Point p,Segment l){\n\tif(det(l.p2 - l.p1,p - l.p1) > EPS) return 1;\n\tif(det(l.p2 - l.p1,p - l.p1) < -EPS) return -1;\n\tif(dot(l.p2 - l.p1,p - l.p1) < -EPS) return 2;\n\tif((l.p2 - l.p1).norm() < (p - l.p1).norm()) return -2;\n\treturn 0;\n}\nbool cross(Segment s1,Segment s2){\n\treturn ccw(s1.p1,s2) * ccw(s1.p2,s2) <= 0 && ccw(s2.p1,s1) * ccw(s2.p2,s1) <= 0;\n}\nbool check(Point p1,Point p2){\n\tfor(int i=1;i<=n;i++){\n\t\tif(cross(Segment(p1,p2),s[i])) return false;\n\t}\n\treturn true;\n}\nbool vis[maxv];\nvoid dfs(int u){\n\tvis[u] = true;\n\tfor(int i=0;i<(int)adj[u].size();i++){\n\t\tint v = adj[u][i];\n\t\tif(!vis[v]) dfs(v);\n\t}\n}\nint main(){\n\t#ifdef LOCAL\n\tfreopen(\"sample.in\",\"r\",stdin);\n\tfreopen(\"sample.out\",\"w\",stdout);\n\t#endif\n\twhile(~scanf(\"%d\",&n) && n){\n\t\tfor(int i=1;i<=n;i++) scanf(\"%lf%lf%lf%lf\",&s[i].p1.x,&s[i].p1.y,&s[i].p2.x,&s[i].p2.y);\n\t\tpk = 0;\n\t\tp[++pk] = Point(0,0);\n\t\tp[++pk] = Point(100,100);\n\t\tfor(int i=1;i<=n;i++){\n\t\t\tp[++pk] = front(s[i]);\n\t\t\tp[++pk] = back(s[i]);\n\t\t}\n\t\tfor(int i=1;i<=pk;i++) adj[i].clear();\n\t\tfor(int i=1;i<=pk;i++){\n\t\t\tfor(int j=i+1;j<=pk;j++){\n\t\t\t\tif(check(p[i],p[j])){\n\t\t\t\t\tadj[i].push_back(j);\n\t\t\t\t\tadj[j].push_back(i);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tmemset(vis,0,sizeof(vis));\n\t\tdfs(1);\n\t\tif(vis[2]) puts(\"no\");\n\t\telse puts(\"yes\");\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3388, "score_of_the_acc": -0.0078, "final_rank": 2 }, { "submission_id": "aoj_1247_3213715", "code_snippet": "#include <iostream>\n#include <complex>\n#include <vector>\n#include <utility>\n#include <algorithm>\nusing namespace std;\nusing P = complex<double>;\nusing L = pair<P,P>;\n#define X real()\n#define Y imag()\nconst double EPS = 1e-6, INF = 1e12;\n\ndouble dot(P &a, P &b){ return a.X*b.X + a.Y*b.Y;}\ndouble cross(P &a, P &b){ return a.X*b.Y - a.Y*b.X;}\n\nint ccw(P a, P b, P c){\n b -= a, c -= a;\n if(cross(b,c) > EPS) return 1;\n if(cross(b,c) < -EPS) return -1;\n if(dot(b,c) < EPS) return 2;\n if(norm(b) - EPS < norm(c)) return -2;\n return 0;\n}\n\nbool is_cross(L a, L b){\n P af = a.first, as = a.second, bf = b.first, bs = b.second;\n return (ccw(af,as,bs)*ccw(af,as,bf) <= 0) and (ccw(bf,bs,af)*ccw(bf,bs,as) <= 0);\n}\n\nint main(){\n int n;\n while(cin >> n, n){\n vector<L> Lines;\n for(int i = 0; i < n; ++i){\n double x, y, z, w;\n cin >> x >> y >> z >> w;\n x *= 200;\n y *= 200;\n z *= 200;\n w *= 200;\n Lines.emplace_back(P(x,y),P(z,w));\n }\n for(int i = 0; i < n; ++i){\n P d = Lines[i].second - Lines[i].first;\n d /= abs(d);\n Lines[i].second += d;\n Lines[i].first -= d;\n }\n vector< vector<int> > Adj(2*n+2, vector<int>(2*n+2,true));\n int M = 2*n + 2;\n vector<P> Points(M);\n for(int i = 0; i < n; ++i){\n Points[2*i] = Lines[i].first;\n Points[2*i+1] = Lines[i].second;\n }\n Points[2*n] = P(0,0);\n Points[2*n+1] = P(200000,200000);\n for(int i = 0; i < M; ++i){\n for(int j = 0; j < i; ++j){\n if(i == j) continue;\n if(i < 2*n and i%2 == 0 and (j-i) == 1) continue;\n for(int k = 0; k < n; ++k){\n if(is_cross(L(Points[i],Points[j]),Lines[k])){\n Adj[i][j] = false;\n Adj[j][i] = false;\n break;\n }\n }\n }\n }\n for(int k = 0; k < M; ++k){\n for(int i = 0; i < M; ++i)\n for(int j = 0; j < M; ++j)\n Adj[i][j] |= Adj[i][k]&Adj[k][j];\n }\n if(Adj[M-1][M-2]) cout << \"no\" << endl;\n else cout << \"yes\" << endl;\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3332, "score_of_the_acc": -0.0046, "final_rank": 1 }, { "submission_id": "aoj_1247_3213671", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <complex>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <array>\n#include <map>\nusing namespace std;\nconst double EPS = 1e-8;\nconst double INF = 1e12;\nconst double PI = acos(-1);\n#define EQ(n,m) (abs((n)-(m)) < EPS)\n#define X real()\n#define Y imag()\n\ntypedef complex<double> P;\ntypedef vector<P> VP;\nstruct L : array<P, 2>{\n L(const P& a, const P& b){ at(0)=a; at(1)=b; }\n L(){}\n};\n\nnamespace std{\n bool operator < (const P& a, const P& b){\n return !EQ(a.X,b.X) ? a.X<b.X : a.Y+EPS<b.Y;\n }\n bool operator == (const P& a, const P& b){\n return abs(a-b) < EPS;\n }\n}\n\ndouble dot(P a, P b){\n return (conj(a)*b).X;\n}\ndouble cross(P a, P b){\n return (conj(a)*b).Y;\n}\nint ccw(P a, P b, P c){\n b -= a;\n c -= a;\n if(cross(b,c) > EPS) return +1; //ccw\n if(cross(b,c) < -EPS) return -1; //cw\n if(dot(b,c) < -EPS) return +2; //c-a-b\n if(abs(c)-abs(b) > EPS) return -2; //a-b-c\n return 0; //a-c-b\n}\nP unit(const P &p){\n return p/abs(p);\n}\nP rotate(const P &p, double rad){\n return p *P(cos(rad), sin(rad));\n}\n\nbool intersectSS(const L& a, const L& b){\n return ( ccw(a[0],a[1],b[0]) *ccw(a[0],a[1],b[1]) <= 0 ) &&\n ( ccw(b[0],b[1],a[0]) *ccw(b[0],b[1],a[1]) <= 0 );\n}\nbool intersectSP(const L& s, const P &p){\n return abs(cross(s[0]-p, s[1]-p))<EPS && dot(s[0]-p, s[1]-p)<EPS;\n}\n\nbool isParallel(const P &a, const P &b){\n return abs(cross(a,b)) < EPS;\n}\nbool isParallel(const L &a, const L &b){\n return isParallel(a[1]-a[0], b[1]-b[0]);\n}\n\nP crosspointLL(const L &l, const L &m) {\n double A = cross(l[1]-l[0], m[1]-m[0]);\n double B = cross(l[1]-l[0], l[1]-m[0]);\n return m[0] + B/A *(m[1]-m[0]);\n}\n\ndouble getarea(const VP &poly){\n double ret = 0;\n for (int i=0; i<(int)poly.size(); i++){ \n ret += cross(poly[i], poly[(i+1)%poly.size()]);\n }\n return ret*0.5;\n}\n\nint in_poly(const P &p, const VP &poly){\n int n = poly.size();\n int ret = -1;\n for(int i=0; i<n; i++){\n P a = poly[i]-p;\n P b = poly[(i+1)%n]-p;\n if(a.Y > b.Y) swap(a,b);\n if(intersectSP(L(a,b), P(0,0))) return 0;\n if(a.Y<=0 && b.Y>0 && cross(a,b)<0) ret = -ret;\n }\n return ret;\n}\n\nint leftmostpoint(int &pidx, int &cidx, vector<int> &vec, VP &plist){\n P ptoc = plist[cidx] -plist[pidx];\n int nextidx = -1;\n double maxangle = -INF;\n for(int i=0; i<(int)vec.size(); i++){\n P cton = plist[vec[i]] -plist[cidx];\n double angle;\n if(abs(cross(ptoc, cton)) < EPS && dot(ptoc, cton) <EPS){\n angle = -PI;\n }else{\n angle = arg(cton/ ptoc);\n }\n if(angle > maxangle){\n maxangle = angle;\n nextidx = i;\n }\n }\n pidx = cidx;\n cidx = vec[nextidx];\n return nextidx;\n}\n\nvector<vector<int> > makeDualGraph(vector<vector<int> > &adj, VP &plist, vector<VP> &vlist){\n map<pair<int,int>, int> edgelist;\n vector<vector<int> > poly;\n vector<vector<bool> > used(adj.size());\n for(int i=0; i<(int)adj.size(); i++){\n used[i] = vector<bool>(adj[i].size(), false);\n }\n vlist = vector<VP>();\n \n int numarea=0;\n for(int i=0; i<(int)adj.size(); i++){\n for(int j=0; j<(int)adj[i].size(); j++){\n if(used[i][j]) continue;\n used[i][j] = true;\n vlist.push_back(VP());\n vector<int> border;\n border.push_back(i);\n vlist[numarea].push_back(plist[i]);\n int prev = i;\n int curr = adj[i][j];\n while(curr!=i){\n border.push_back(curr);\n vlist[numarea].push_back(plist[curr]);\n int idx = leftmostpoint(prev, curr, adj[curr], plist);\n used[prev][idx] = true;\n }\n poly.push_back(border);\n numarea++;\n }\n }\n \n vector<vector<int> > dual(numarea);\n for(int i=0; i<numarea; i++){\n for(int j=0; j<(int)poly[i].size(); j++){\n int a = poly[i][j];\n int b = poly[i][(j+1)%(int)poly[i].size()];\n pair<int,int> key = make_pair(min(a,b), max(a,b));\n if(edgelist.count(key) == 0){\n edgelist[key] = i;\n }else{\n dual[i].push_back(edgelist[key]);\n dual[edgelist[key]].push_back(i);\n }\n }\n }\n \n for(int i=0; i<(int)dual.size(); i++){\n sort(dual[i].begin(), dual[i].end());\n dual[i].erase(unique(dual[i].begin(), dual[i].end()), dual[i].end());\n }\n return dual;\n}\n\npair<vector<vector<int> >, VP> arrangement(const vector<L> &l){\n vector<VP> cp(l.size());\n VP plist;\n for(int i=0; i<(int)l.size(); i++){\n for(int j=i+1; j<(int)l.size(); j++){\n if(!isParallel(l[i], l[j]) && intersectSS(l[i], l[j])){\n P cpij = crosspointLL(l[i], l[j]);\n cp[i].push_back(cpij);\n cp[j].push_back(cpij);\n plist.push_back(cpij);\n }\n }\n cp[i].push_back(l[i][0]);\n cp[i].push_back(l[i][1]);\n plist.push_back(l[i][0]);\n plist.push_back(l[i][1]);\n sort(cp[i].begin(), cp[i].end());\n cp[i].erase(unique(cp[i].begin(), cp[i].end()), cp[i].end());\n }\n sort(plist.begin(), plist.end());\n plist.erase(unique(plist.begin(), plist.end()), plist.end());\n\n int n = plist.size();\n map<P, int> conv;\n for(int i=0; i<n; i++){\n conv[plist[i]] = i;\n }\n vector<vector<int> > adj(n);\n for(int i=0; i<(int)cp.size(); i++){\n for(int j=0; j<(int)cp[i].size()-1; j++){\n int jidx = conv[cp[i][j]];\n int jp1idx = conv[cp[i][j+1]];\n adj[jidx].push_back(jp1idx);\n adj[jp1idx].push_back(jidx);\n }\n }\n for(int i=0; i<n; i++){\n sort(adj[i].begin(), adj[i].end());\n adj[i].erase(unique(adj[i].begin(), adj[i].end()), adj[i].end());\n }\n return make_pair(adj, plist);\n}\n\nint main(){\n while(1){\n int n;\n cin >> n;\n if(n == 0) break;\n\n vector<L> l(n);\n for(int i=0; i<n; i++){\n double xs,ys,xt,yt;\n cin >> xs >> ys >> xt >> yt;\n l[i] = L(P(xs, ys), P(xt, yt));\n }\n\n auto ret = arrangement(l);\n auto &adj = ret.first;\n VP &plist = ret.second;\n vector<VP> vlist;\n makeDualGraph(adj, plist, vlist);\n bool ok = false;\n for(const VP &poly: vlist){\n if(getarea(poly) < EPS) continue;\n if(in_poly(P(0, 0), poly) == 1){\n ok = true;\n break;\n }\n }\n if(ok){\n cout << \"yes\" << endl;\n }else{\n cout << \"no\" << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5872, "score_of_the_acc": -0.2836, "final_rank": 3 } ]
aoj_1243_cpp
Problem D: Weather Forecast You are the God of Wind. By moving a big cloud around, you can decide the weather: it invariably rains under the cloud, and the sun shines everywhere else. But you are a benign God: your goal is to give enough rain to every field in the countryside, and sun to markets and festivals. Small humans, in their poor vocabulary, only describe this as “weather forecast”. You are in charge of a small country, called Paccimc. This country is constituted of 4 × 4 square areas, denoted by their numbers. Your cloud is of size 2 × 2, and may not cross the borders of the country. You are given the schedule of markets and festivals in each area for a period of time. On the first day of the period, it is raining in the central areas (6-7-10-11), independently of the schedule. On each of the following days, you may move your cloud by 1 or 2 squares in one of the four cardinal directions (North, West, South, and East), or leave it in the same position. Diagonal moves are not allowed. All moves occur at the beginning of the day. You should not leave an area without rain for a full week (that is, you are allowed at most 6 consecutive days without rain). You don’t have to care about rain on days outside the period you were given: i.e. you can assume it rains on the whole country the day before the period, and the day after it finishes. Input The input is a sequence of data sets, followed by a terminating line containing only a zero. A data set gives the number N of days (no more than 365) in the period on a single line, followed by N lines giving the schedule for markets and festivals. The i -th line gives the schedule for the i-th day. It is composed of 16 numbers, either 0 or 1, 0 standing for a normal day, and 1 a market or festival day. The numbers are separated by one or more spaces. Output The answer is a 0 or 1 on a single line for each data set, 1 if you can satisfy everybody, 0 if there is no way to do it. Sample Input 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 7 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 1 1 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 0 7 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 0 1 0 1 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 15 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 1 1 0 0 0 0 0 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 1 1 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 1 0 1 0 0 0 0 0 0 0 Output for the Sample Input 0 1 0 1
[ { "submission_id": "aoj_1243_10865810", "code_snippet": "#include<cstdio>\n#include<iostream>\n#include<cstring>\n#include<cmath>\n#include<cstdlib>\n#include<vector>\n#include<stack>\n#include<algorithm>\n#include<queue>\n#include<string>\n#define OK 1\n#define INF 2147483647\n#define LINF 9223372036854775807LL\n#define DINF 100000000\n#define LL long long\nusing namespace std;\ntypedef struct\n{\n\tint cnt[4][4];\n}HNode;\nvector<HNode>H[366][4][4];\nint n,map[365][4][4];\nint biao[4][4][4][2];\nconst int di[] = { 0, 0, 0, -1, -2, 0, 0, 1, 2 };\nconst int dj[] = { 0, -1, -2, 0, 0, 1, 2, 0, 0 };\nbool dfs(int cur, int ci, int cj, int cnt[4][4]);\nbool judge(int cur, int ci, int cj, int cnt[4][4]);\n\nint main()\n{\n\tint i,j,k,cnt[4][4];\n\twhile (scanf(\"%d\", &n) > 0)\n\t{\n\t\tif (n == 0) break;\n\t\tfor (k = 0; k < n; k++)\n\t\t{\n\t\t\tfor (i = 0; i < 4; i++)\n\t\t\t{\n\t\t\t\tfor (j = 0; j < 4; j++) H[k][i][j].clear();\n\t\t\t}\n\t\t}\n\t\tfor (k = 0; k < n; k++)\n\t\t{\n\t\t\tfor (i = 0; i < 4; i++)\n\t\t\t{\n\t\t\t\tfor (j = 0; j < 4; j++) scanf(\"%d\", &map[k][i][j]);\n\t\t\t}\n\t\t}\n\t\tfor (i = 0; i < 4; i++)\n\t\t{\n\t\t\tfor (j = 0; j < 4; j++) cnt[i][j] = 1;\n\t\t}\n\t\tcnt[1][1] = cnt[1][2] = cnt[2][1] = cnt[2][2] = 0;\n\t\tjudge(0, 1, 1, cnt);\n\t\tif (dfs(0, 1, 1, cnt) == true) printf(\"1\\n\");\n\t\telse printf(\"0\\n\");\n\t}\n\treturn 0;\n}\n\nbool judge(int cur, int ci, int cj, int cnt[4][4])\n{\n\tint k,j,i, len;\n\tbool flag = false;\n\tHNode e;\n\tfor (k = 0, len = H[cur][ci][cj].size(); k < len; k++)\n\t{\n\t\te = H[cur][ci][cj][k];\n\t\tflag = true;\n\t\tfor (i = 0; i < 4; i++)\n\t\t{\n\t\t\tfor (j = 0; j < 4; j++)\n\t\t\t{\n\t\t\t\tif (e.cnt[i][j] != cnt[i][j]) flag = false;\n\t\t\t}\n\t\t}\n\t\tif (flag == true) break;\n\t}\n\tif (flag == false)\n\t{\n\t\tfor (i = 0; i < 4; i++)\n\t\t{\n\t\t\tfor (j = 0; j < 4; j++) e.cnt[i][j] = cnt[i][j];\n\t\t}\n\t\tH[cur][ci][cj].push_back(e);\n\t\treturn false;\n\t}\n\telse return true;\n}\n\nbool dfs(int cur,int ci,int cj,int cnt[4][4])\n{\n\tint k,next_ci,next_cj,i,j,nextCnt[4][4];\n\tif (map[cur][ci][cj] == 1 || map[cur][ci][cj + 1] == 1 || map[cur][ci + 1][cj] == 1 || map[cur][ci + 1][cj + 1] == 1) return false;\n\tif (cur == n - 1) return true;\n\tfor (k = 0; k < 9; k++)\n\t{\n\t\tnext_ci = ci + di[k];\n\t\tnext_cj = cj + dj[k];\n\t\tif (next_ci < 0 || next_ci + 1 >= 4 || next_cj < 0 || next_cj + 1 >= 4) continue;\n\t\tmemcpy(nextCnt, cnt, sizeof(nextCnt));\n\t\tfor (i = 0; i < 4; i++)\n\t\t{\n\t\t\tfor (j = 0; j < 4; j++) nextCnt[i][j]++;\n\t\t}\n\t\tnextCnt[next_ci][next_cj] = nextCnt[next_ci][next_cj + 1] = 0;\n\t\tnextCnt[next_ci + 1][next_cj] = nextCnt[next_ci + 1][next_cj + 1] = 0;\n\t\tbool flag = true;\n\t\tfor (i = 0; i < 4; i++) //判断下雨天数\n\t\t{\n\t\t\tfor (j = 0; j < 4; j++)\n\t\t\t{\n\t\t\t\tif (nextCnt[i][j] == 7) flag = false;\n\t\t\t}\n\t\t} \n\t\tif (flag == false) continue;\n\t\tif (judge(cur + 1, next_ci, next_cj, nextCnt) == true) continue;\n\t\tif (dfs(cur + 1, next_ci, next_cj, nextCnt) == true) return true;\n \t}\n\treturn false;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 17136, "score_of_the_acc": -0.2433, "final_rank": 6 }, { "submission_id": "aoj_1243_9669450", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n/**\n * @brief template\n */\n\nint N;\nvector<int> A(N);\nvector<vector<int>> G(9);\nmap<int,bool> mp;\n\nint encode(int K, int X, int Y, int D0, int D2, int D6, int D8) {\n return K*1000000+X*100000+Y*10000+D0*1000+D2*100+D6*10+D8;\n}\n\nbool DFS(int K, int X, int Y, int D0, int D2, int D6, int D8) {\n if (K == N) return true;\n if (D0 >= 7 || D2 >= 7 || D6 >= 7 || D8 >= 7) return false;\n if ((A[K] & (1<<(X*3+Y))) == 0) return false;\n int E = encode(K,X,Y,D0,D2,D6,D8);\n if (mp.count(E)) return mp[E];\n for (int Next : G[X*3+Y]) {\n int NX = Next / 3, NY = Next % 3;\n int N0 = D0+1, N2 = D2+1, N6 = D6+1, N8 = D8+1;\n if (Next == 0) N0 = 0;\n if (Next == 2) N2 = 0;\n if (Next == 6) N6 = 0;\n if (Next == 8) N8 = 0;\n if (DFS(K+1,NX,NY,N0,N2,N6,N8)) return mp[E] = true;\n }\n return mp[E] = false;\n}\n\nint main() {\n rep(i,0,3) {\n rep(j,0,3) {\n G[i*3+j].push_back(i*3+j);\n rep(k,0,3) {\n if (i != k) G[i*3+j].push_back(k*3+j);\n if (j != k) G[i*3+j].push_back(i*3+k);\n }\n }\n }\nwhile(1) {\n mp.clear();\n cin >> N;\n if (N == 0) return 0;\n A.resize(N);\n rep(i,0,N) {\n vector<vector<int>> X(4,vector<int>(4));\n rep(j,0,4) rep(k,0,4) cin >> X[j][k];\n int B = 0;\n rep(j,0,3) {\n rep(k,0,3) {\n if (X[j][k] == 0 && X[j+1][k] == 0 && X[j][k+1] == 0 && X[j+1][k+1] == 0) B |= (1<<(j*3+k));\n }\n }\n A[i] = B;\n }\n cout << (DFS(0,1,1,1,1,1,1) ? 1 : 0) << endl;\n}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5160, "score_of_the_acc": -0.012, "final_rank": 2 }, { "submission_id": "aoj_1243_9029711", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\n} // namespace macro\n\nusing namespace macro;\n#line 3 \"A.cpp\"\n\nint solve(int n) {\n using D = array<array<int, 4>, 4>;\n vector dp(3, vector(3, set<D>()));\n\n {\n bitset<16> a; {\n vector<int> a_ = in(16);\n for(int i : rep(16)) if(a_[i]) a[i] = 1;\n }\n bitset<16> b;\n b[5] = b[6] = b[9] = b[10] = 1;\n if((a & b) == 0) {\n D s = {\n 1, 1, 1, 1,\n 1, 0, 0, 1,\n 1, 0, 0, 1,\n 1, 1, 1, 1\n };\n dp[1][1].insert(s);\n }\n }\n\n for(int _ : rep(n - 1)) {\n bitset<16> a; {\n vector<int> a_ = in(16);\n for(int i : rep(16)) if(a_[i]) a[i] = 1;\n }\n vector nt(3, vector(3, set<D>()));\n for(int ci : rep(3)) for(int cj : rep(3)) {\n for(auto [di, dj] : vector<pair<int,int>>{{-2, 0}, {0, -2}, {-1, 0}, {0, -1}, {0, 0}, {+1, 0}, {0, +1}, {+2, 0}, {0, +2}}) {\n int ni = ci + di, nj = cj + dj;\n if(not(0 <= ni and ni + 1 < 4 and 0 <= nj and nj + 1 < 4)) continue;\n bitset<16> b;\n for(int i : rep(2)) for(int j : rep(2)) b[(ni + i) * 4 + (nj + j)] = 1;\n if(not((a & b) == 0)) continue;\n for(auto s : dp[ci][cj]) {\n for(int i : rep(4)) for(int j : rep(4)) s[i][j] += 1;\n for(int i : rep(2)) for(int j : rep(2)) s[ni + i][nj + j] = 0;\n bool ok = [&] {\n for(int i : rep(4)) for(int j : rep(4)) \n if(s[i][j] >= 7) return false;\n return true;\n }();\n if(ok) nt[ni][nj].insert(s);\n }\n }\n }\n dp = move(nt);\n }\n for(int ci : rep(3)) for(int cj : rep(3)) if(not dp[ci][cj].empty()) return true;\n return false;\n}\n\nint main() {\n while(true) {\n int n = in();\n if(n == 0) return 0;\n print(solve(n));\n }\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3668, "score_of_the_acc": -0.1081, "final_rank": 5 }, { "submission_id": "aoj_1243_6718256", "code_snippet": "/**\n * author: otera\n**/\n#include<bits/stdc++.h>\nusing namespace std;\n\n// #define int long long\n\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\nusing int128_t = __int128_t;\n#define repa(i, n) for(int i = 0; i < n; ++ i)\n#define repb(i, a, b) for(int i = a; i < b; ++ i)\n#define repc(i, a, b, c) for(int i = a; i < b; i += c)\n#define overload4(a, b, c, d, e, ...) e\n#define overload3(a, b, c, d, ...) d\n#define rep(...) overload4(__VA_ARGS__, repc, repb, repa)(__VA_ARGS__)\n#define rep1a(i, n) for(int i = 0; i <= n; ++ i)\n#define rep1b(i, a, b) for(int i = a; i <= b; ++ i)\n#define rep1c(i, a, b, c) for(int i = a; i <= b; i += c)\n#define rep1(...) overload4(__VA_ARGS__, rep1c, rep1b, rep1a)(__VA_ARGS__)\n#define rev_repa(i, n) for(int i=n-1;i>=0;i--)\n#define rev_repb(i, a, b) assert(a > b);for(int i=a;i>b;i--)\n#define rev_rep(...) overload3(__VA_ARGS__, rev_repb, rev_repa)(__VA_ARGS__)\n#define rev_rep1a(i, n) for(int i=n;i>=1;i--)\n#define rev_rep1b(i, a, b) assert(a >= b);for(int i=a;i>=b;i--)\n#define rev_rep1(...) overload3(__VA_ARGS__, rev_rep1b, rev_rep1a)(__VA_ARGS__)\ntypedef pair<int, int> P;\ntypedef pair<ll, ll> LP;\n#define pb push_back\n#define pf push_front\n#define ppb pop_back\n#define ppf pop_front\n#define eb emplace_back\n#define fr first\n#define sc second\n#define all(c) c.begin(),c.end()\n#define rall(c) c.rbegin(), c.rend()\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define ub(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define Sort(a) sort(all(a))\n#define Rev(a) reverse(all(a))\n#define Uniq(a) sort(all(a));a.erase(unique(all(a)),end(a))\n#define si(c) (int)(c).size()\ninline ll popcnt(ull a){ return __builtin_popcountll(a); }\n#define kth_bit(x, k) ((x>>k)&1)\n#define unless(A) if(!(A))\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll intpow(ll a, ll b, ll m) {ll ans = 1; while(b){ if(b & 1) (ans *= a) %= m; (a *= a) %= m; b /= 2; } return ans; }\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define ULL(...) ull __VA_ARGS__;in(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__;in(__VA_ARGS__)\n#define CHR(...) char __VA_ARGS__;in(__VA_ARGS__)\n#define DBL(...) double __VA_ARGS__;in(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__;in(__VA_ARGS__)\n#define vec(type,name,...) vector<type>name(__VA_ARGS__)\n#define VEC(type,name,size) vector<type>name(size);in(name)\n#define vv(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define VV(type,name,h,w) vector<vector<type>>name(h,vector<type>(w));in(name)\n#define vvv(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\ntemplate <class T> using vc = vector<T>;\ntemplate <class T> using vvc = vector<vc<T>>;\ntemplate <class T> using vvvc = vector<vvc<T>>;\ntemplate <class T> using vvvvc = vector<vvvc<T>>;\ntemplate <class T> using pq = priority_queue<T>;\ntemplate <class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\ntemplate <class T, class U> using umap = unordered_map<T, U>;\ntemplate<class T> void scan(T& a){ cin >> a; }\ntemplate<class T> void scan(vector<T>& a){ for(auto&& i : a) scan(i); }\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){ scan(head); in(tail...); }\nvoid print(){ cout << ' '; }\ntemplate<class T> void print(const T& a){ cout << a; }\ntemplate<class T> void print(const vector<T>& a){ if(a.empty()) return; print(a[0]); for(auto i = a.begin(); ++i != a.end(); ){ cout << ' '; print(*i); } }\nint out(){ cout << '\\n'; return 0; }\ntemplate<class T> int out(const T& t){ print(t); cout << '\\n'; return 0; }\ntemplate<class Head, class... Tail> int out(const Head& head, const Tail&... tail){ print(head); cout << ' '; out(tail...); return 0; }\n#define CHOOSE(a) CHOOSE2 a\n#define CHOOSE2(a0,a1,a2,a3,a4,x,...) x\n#define debug_1(x1) cout<<#x1<<\": \"<<x1<<endl\n#define debug_2(x1,x2) cout<<#x1<<\": \"<<x1<<\", \"#x2<<\": \"<<x2<<endl\n#define debug_3(x1,x2,x3) cout<<#x1<<\": \"<<x1<<\", \"#x2<<\": \"<<x2<<\", \"#x3<<\": \"<<x3<<endl\n#define debug_4(x1,x2,x3,x4) cout<<#x1<<\": \"<<x1<<\", \"#x2<<\": \"<<x2<<\", \"#x3<<\": \"<<x3<<\", \"#x4<<\": \"<<x4<<endl\n#define debug_5(x1,x2,x3,x4,x5) cout<<#x1<<\": \"<<x1<<\", \"#x2<<\": \"<<x2<<\", \"#x3<<\": \"<<x3<<\", \"#x4<<\": \"<<x4<<\", \"#x5<<\": \"<<x5<<endl\n#ifdef DEBUG\n#define debug(...) CHOOSE((__VA_ARGS__,debug_5,debug_4,debug_3,debug_2,debug_1,~))(__VA_ARGS__)\n#define dump(...) { print(#__VA_ARGS__); print(\":\"); out(__VA_ARGS__); }\n#else\n#define debug(...)\n#define dump(...)\n#endif\n\nstruct io_setup {\n io_setup(int precision = 20) {\n ios::sync_with_stdio(false);\n cin.tie(0);\n cout << fixed << setprecision(precision);\n }\n} io_setup_ {};\n\nconst int dx[4] = {0, 1, 0, -1};\nconst int dy[4] = {1, 0, -1, 0};\n\nconst int M = 4;\nconst int D = 7;\n\nvoid solve() {\n int n;\n while(cin >> n) {\n if(n == 0) break;\n VV(int, a, n, M * M);\n vector cnt(M, array<int, M>{0, 0, 0, 0});\n bool ans = 0;\n map<tuple<int, P, vector<array<int, M>>>, bool> memo;\n auto dfs = [&](auto &&dfs, int day, int x, int y) -> void {\n if(ans) return;\n if(day == n) {\n ans = 1;\n return;\n }\n if(memo.count(make_tuple(day, P{x, y}, cnt))) return;\n memo[make_tuple(day, P{x, y}, cnt)] = 1;\n bool ok = 1;\n auto ncnt = cnt;\n rep(i, M) {\n rep(j, M) {\n if(0 <= (i - x) && (i - x) <= 1 && 0 <= (j - y) && (j - y) <= 1) {\n // rain\n if(a[day][i * M + j]) {\n ok = 0;\n break;\n }\n ncnt[i][j] = 0;\n } else {\n // not rain\n ++ ncnt[i][j];\n if(ncnt[i][j] >= 7) {\n ok = 0;\n break;\n }\n }\n }\n }\n if(!ok) {\n return;\n }\n swap(cnt, ncnt);\n rep(k, 4) {\n for(int _ = 1; _ <= 2; ++ _) {\n int nx = x + _ * dx[k], ny = y + _ * dy[k];\n if(0 <= nx && nx < 3 && 0 <= ny && ny < 3) {\n dfs(dfs, day + 1, nx, ny);\n }\n }\n }\n dfs(dfs, day + 1, x, y);\n swap(cnt, ncnt);\n };\n dfs(dfs, 0, 1, 1);\n out(ans);\n }\n}\n\nsigned main() {\n int testcase = 1;\n // in(testcase);\n while(testcase--) solve();\n return 0;\n}", "accuracy": 1, "time_ms": 720, "memory_kb": 92020, "score_of_the_acc": -1.6553, "final_rank": 20 }, { "submission_id": "aoj_1243_6654938", "code_snippet": "#include <stdio.h>\n#include <vector>\n#include <set>\nusing namespace std;\n\nint a[384][16], vis[16];\nset<vector<int>> st[384];\nvector<int> mv[16] = { {0, 1, 2, 4, 8}, {0, 1, 2, 5, 9}, {0, 1, 2, 6, 10}, {},\n {0, 4, 5, 6, 8}, {1, 4, 5, 6, 9}, {2, 4, 5, 6, 10}, {},\n {0, 4, 8, 9, 10}, {1, 5, 8, 9, 10}, {2, 6, 8, 9, 10}, {}, {}, {}, {}, {} };\n\nint main(void) {\n int n, ok;\n vector<int> v;\n while (1) {\n scanf(\"%d\", &n);\n if (n == 0) break;\n for (int i = 1; i <= n; i++) {\n for (int j = 0; j < 16; j++) {\n scanf(\"%d\", &a[i][j]);\n }\n }\n if (a[1][5] || a[1][6] || a[1][9] || a[1][10]) {\n printf(\"0\\n\");\n continue;\n }\n \n st[1].insert({ 5, -1, -1, -1, -1, -1, -1 });\n for (int i = 1; i < n; i++) {\n for (auto& j : st[i]) {\n v = j;\n for (int k = 6; k > 0; k--) v[k] = v[k - 1];\n for (int k : mv[v[1]]) {\n v[0] = k;\n if (i < 6) ok = 1;\n else {\n ok = 1;\n for (int l = 0; l < 7; l++) {\n vis[v[l]] = 1;\n vis[v[l] + 1] = 1;\n vis[v[l] + 4] = 1;\n vis[v[l] + 5] = 1;\n }\n for (int l = 0; l < 16; l++) {\n if (!vis[l]) ok = 0;\n vis[l] = 0;\n }\n }\n if (a[i + 1][v[0]] || a[i + 1][v[0] + 1] || a[i + 1][v[0] + 4] || a[i + 1][v[0] + 5]) {\n ok = 0;\n }\n if (ok) st[i + 1].insert(v);\n }\n }\n }\n\n if (st[n].size()) printf(\"1\\n\");\n else printf(\"0\\n\");\n\n for (int i = 0; i <= n; i++) st[i].clear();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 37844, "score_of_the_acc": -0.6257, "final_rank": 16 }, { "submission_id": "aoj_1243_6255081", "code_snippet": "#include <iostream>\n#include <queue>\n#include <vector>\n#include <cstring>\n\nusing namespace std;\n\nint counter[365][9][7][7][7][7];\n\nint rain[9][16] {\n {1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0},\n {0,1,1,0,0,1,1,0,0,0,0,0,0,0,0,0},\n {0,0,1,1,0,0,1,1,0,0,0,0,0,0,0,0},\n {0,0,0,0,1,1,0,0,1,1,0,0,0,0,0,0},\n {0,0,0,0,0,1,1,0,0,1,1,0,0,0,0,0},\n {0,0,0,0,0,0,1,1,0,0,1,1,0,0,0,0},\n {0,0,0,0,0,0,0,0,1,1,0,0,1,1,0,0},\n {0,0,0,0,0,0,0,0,0,1,1,0,0,1,1,0},\n {0,0,0,0,0,0,0,0,0,0,1,1,0,0,1,1},\n};\n\nint adj[9][9] {\n {1,1,1,1,0,0,1,0,0},\n {1,1,1,0,1,0,0,1,0},\n {1,1,1,0,0,1,0,0,1},\n {1,0,0,1,1,1,1,0,0},\n {0,1,0,1,1,1,0,1,0},\n {0,0,1,1,1,1,0,0,1},\n {1,0,0,1,0,0,1,1,1},\n {0,1,0,0,1,0,1,1,1},\n {0,0,1,0,0,1,1,1,1},\n};\n\nstruct X\n{\n X(int d, int p, int ul, int ll, int ur, int lr) : day{d}, pos{p}, upleft{ul}, loleft{ll}, upright{ur}, loright{lr} {}\n int day;\n int pos;\n int upleft;\n int loleft;\n int upright;\n int loright;\n};\n\nbool check_pos(int p, vector<vector<int> > &event, int day) {\n for (int i=0; i<16; ++i)\n if (rain[p][i] == 1 && event[day][i] == 1) return false;\n return true;\n}\n\nbool check_day(int a, int b, int c, int d) {\n return !(a == 7 || b == 7 || c == 7 || d == 7);\n}\n\nint solve(int day, vector<vector<int> > &event) {\n int check = 0; // クリアできるか\n queue<X> Q;\n X init(0,4,1,1,1,1);\n if (!check_pos(4, event, 0)) return 0;\n Q.push(init);\n while (!Q.empty()) {\n X pick = Q.front();\n Q.pop();\n for(int i=0; i<9; ++i) {\n if (adj[pick.pos][i] == 1) {\n X c(pick.day+1,i,pick.upleft+1,pick.loleft+1,pick.upright+1,pick.loright+1);\n if (i == 0) c.upleft = 0; else if (i == 2) c.upright = 0; else if (i == 6) c.loleft = 0; else if (i == 8) c.loright = 0;\n if (check_pos(i, event, c.day) && check_day(c.upleft, c.loleft, c.upright, c.loright)) {\n if (c.day == day-1) {\n check = 1;\n goto label;\n } else {\n if (counter[c.day][c.pos][c.upleft][c.loleft][c.upright][c.loright] == 0) {\n Q.push(c);\n counter[c.day][c.pos][c.upleft][c.loleft][c.upright][c.loright] += 1;\n }\n }\n }\n }\n }\n }\n label: ;\n return check;\n}\n\nint main() {\n int total;\n while (cin >> total && total > 0) {\n vector<vector<int> > event(total, vector<int>(16));\n for (int i=0; i<total; ++i) {\n for (int j=0; j<16; ++j) {\n cin >> event[i][j];\n }\n }\n memset(counter, 0, sizeof(counter));\n int ans = solve(total, event);\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 33992, "score_of_the_acc": -0.2705, "final_rank": 7 }, { "submission_id": "aoj_1243_6238937", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n#define rep(i, n) for (int i = 0; i < (n); i++)\n#define ALL(x) x.begin(), x.end()\n\nbool dp[370][3][3][7][7][7][7][16];\nbool a[370][4][4];\nbool ok[3][3];\n\nconst int dx[9] = {2, 1, -1, -2, 0, 0, 0, 0, 0};\nconst int dy[9] = {0, 0, 0, 0, 0, 2, 1, -1, -2};\n\nvoid solve(int N) {\n rep(i, N) rep(x, 3) rep(y, 3) rep(a1, 7) rep(a2, 7) rep(a3, 7) rep(a4, 7) rep(k, 16) dp[i][x][y][a1][a2][a3][a4][k] = false;\n rep(i, N) rep(x, 4) rep(y, 4) cin >> a[i][x][y];\n if (a[0][1][1] == true || a[0][1][2] == true || a[0][2][1] == true || a[0][2][2] == true) {\n cout << 0 << '\\n';\n return;\n }\n dp[0][1][1][1][1][1][1][0] = true;\n for (int i = 1; i < N; i++) {\n rep(cx, 3) rep(cy, 3) {\n if (a[i][cx][cy] == true || a[i][cx][cy + 1] == true || a[i][cx + 1][cy] == true || a[i][cx + 1][cy + 1] == true)\n ok[cx][cy] = false;\n else\n ok[cx][cy] = true;\n }\n rep(cx, 3) rep(cy, 3) rep(a1, 7) rep(a2, 7) rep(a3, 7) rep(a4, 7) rep(b, 16) {\n if (dp[i - 1][cx][cy][a1][a2][a3][a4][b] == false) continue;\n // 遷移\n rep(k, 9) {\n int nx = cx + dx[k], ny = cy + dy[k];\n if (!(0 <= nx && nx < 3 && 0 <= ny && ny < 3)) continue;\n if (ok[nx][ny] == false) continue;\n int na1 = a1 + 1, na2 = a2 + 1, na3 = a3 + 1, na4 = a4 + 1, nb = b;\n if (nx == 0 && ny == 0) na1 = 0, nb |= 1;\n if (nx == 0 && ny == 2) na2 = 0, nb |= 2;\n if (nx == 2 && ny == 0) na3 = 0, nb |= 4;\n if (nx == 2 && ny == 2) na4 = 0, nb |= 8;\n if (na1 > 6) continue;\n if (na2 > 6) continue;\n if (na3 > 6) continue;\n if (na4 > 6) continue;\n dp[i][nx][ny][na1][na2][na3][na4][nb] = true;\n }\n }\n }\n rep(cx, 3) rep(cy, 3) rep(a1, 7) rep(a2, 7) rep(a3, 7) rep(a4, 7) {\n if (dp[N - 1][cx][cy][a1][a2][a3][a4][15] == true) {\n cout << 1 << '\\n';\n return;\n }\n }\n cout << 0 << '\\n';\n return;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n int N;\n while (cin >> N, N) solve(N);\n return 0;\n}", "accuracy": 1, "time_ms": 490, "memory_kb": 128228, "score_of_the_acc": -1.6351, "final_rank": 19 }, { "submission_id": "aoj_1243_6128201", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <queue>\n#include <tuple>\n#include <cstring>\nusing namespace std;\n\nconst int MAX_N = 370;\nconst int AREA_NUM = 16;\nconst int dx[] = {0, 1, 0, -1, 0, 2, 0, -2, 0};\nconst int dy[] = {0, 0, -1, 0, 1, 0, -2, 0, 2};\nconst int ax[] = {0, 1, 0, 1};\nconst int ay[] = {0, 0, 1, 1};\nint cache[MAX_N][3][3][7][7][7][7];\n\nint need_sun[MAX_N][AREA_NUM];\n\nstruct State\n{\n int x;\n int y;\n int t;\n int A;\n int B;\n int C;\n int D;\n};\n\nbool check_border(int x, int y)\n{\n return ((0 <= x) && (x < 4) && (0 <= y) && (y < 4));\n}\n\nbool check_pos_and_specialday(int left_x, int top_y, int t)\n{\n int right_x = left_x + 1;\n int bottom_y = top_y + 1;\n if (check_border(left_x, top_y) &&\n check_border(right_x, bottom_y))\n return (need_sun[t][left_x + top_y * 4] == 0) &&\n (need_sun[t][left_x + bottom_y * 4] == 0) &&\n (need_sun[t][right_x + top_y * 4] == 0) &&\n (need_sun[t][right_x + bottom_y * 4] == 0);\n else\n return false;\n}\n\nbool check_dry(State state)\n{\n return state.A < 7 && state.B < 7 && state.C < 7 && state.D < 7;\n}\n\nState update_state(State state, int nx, int ny)\n{\n State new_state = {nx, ny, state.t + 1,\n state.A + 1, state.B + 1,\n state.C + 1, state.D + 1};\n int idx = 0;\n for (int i = 0; i < 4; i++)\n {\n idx = nx + ax[i] + (ny + ay[i]) * 4;\n if (idx == 0)\n new_state.A = 0;\n else if (idx == 3)\n new_state.B = 0;\n else if (idx == 12)\n new_state.C = 0;\n else if (idx == 15)\n new_state.D = 0;\n }\n return new_state;\n}\n\nint solve(int N, int sx, int sy)\n{\n int nx, ny, t;\n\n //左上のx座標・左上のy座標・何日目か・マス1の雨が降っていない期間\n queue<State> que;\n State init_state = {sx, sy, 0, 1, 1, 1, 1};\n\n bool last_day = false;\n que.push(init_state);\n while (!que.empty())\n {\n State state = que.front();\n que.pop();\n\n if (cache[state.t][state.x][state.y][state.A][state.B][state.C][state.D]++)\n continue;\n for (int i = 0; i < 9; i++)\n {\n nx = state.x + dx[i];\n ny = state.y + dy[i];\n t = state.t;\n if (t == N - 1)\n {\n last_day = true;\n break;\n }\n State new_state = update_state(state, nx, ny);\n if (check_dry(new_state) && check_pos_and_specialday(nx, ny, t + 1))\n que.push(new_state);\n }\n }\n\n if (last_day)\n return 1;\n else\n return 0;\n}\n\nint main()\n{\n int N;\n while (cin >> N)\n {\n if (N == 0)\n break;\n\n for (int i = 0; i < N; i++)\n for (int j = 0; j < AREA_NUM; j++)\n cin >> need_sun[i][j];\n\n memset(cache, 0, sizeof(cache));\n int ans = solve(N, 1, 1);\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 34656, "score_of_the_acc": -0.2893, "final_rank": 13 }, { "submission_id": "aoj_1243_6127328", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <tuple>\n#include <set>\n#include <vector>\n#include <queue>\nusing namespace std;\n\nint n;\nint cover[3][3];\nint schedule[365];\nint dx[3][3][5];\nint dy[3][3][5];\n// {四隅の連続して雨の降っていない日数、雲のx座標、雲のy座標、日付}\nusing State = tuple<int, int, int, int, int, int, int>;\nset<State> used;\n\nint solve() {\n used.clear();\n for(int i = 0; i < n; i++) {\n schedule[i] = 0;\n for(int j = 0; j < 16; j++) {\n int x; cin >> x;\n schedule[i] += x << j;\n }\n }\n // bit演算で重なりを判定\n if(cover[1][1] & schedule[0]) return 0;\n queue<State> q;\n q.push({1, 1, 1, 1, 1, 1, 0});\n while(!q.empty()) {\n auto now = q.front();\n q.pop();\n int c0 = get<0>(now), c1 = get<1>(now), c2 = get<2>(now), c3 = get<3>(now),\n x = get<4>(now), y = get<5>(now), d = get<6>(now);\n if(d == n-1) return 1;\n c0++; c1++; c2++; c3++;\n for(int i = 0; i < 5; i++) {\n int nx = x + dx[x][y][i], ny = y + dy[x][y][i];\n // markets and festivals と重なっていないか\n if((cover[nx][ny]&schedule[d+1]) == 0) {\n State nxt = make_tuple(c0, c1, c2, c3, nx, ny, d+1);\n // 雨を降らしたときの日数のリセット\n if(nx == 0 && ny == 0) {\n get<0>(nxt) = 0;\n } else if(nx == 0 && ny == 2) {\n get<1>(nxt) = 0;\n } else if(nx == 2 && ny == 0) {\n get<2>(nxt) = 0;\n } else if(nx == 2 && ny == 2) {\n get<3>(nxt) = 0;\n }\n // 雨を連続で降らせていない場所がないか\n if(!used.count(nxt) &&\n get<0>(nxt) != 7 && get<1>(nxt) != 7 &&\n get<2>(nxt) != 7 && get<3>(nxt) != 7) {\n q.push(nxt);\n used.insert(nxt);\n }\n }\n }\n }\n return 0;\n}\n\nint main() {\n // 雲の遷移、雲がカバーしている位置の前計算\n // bit演算によって位置を管理することで高速化している\n // 以下のように番号を振り、雲がいるときは cover について番号のbitを立てる\n // 0 1 2 3\n // 4 5 6 7\n // 8 9 10 11\n // 12 13 14 15\n for(int i = 0; i < 3; i++) {\n for(int j = 0; j < 3; j++) {\n for(int ii = 0; ii < 2; ii++) {\n for(int jj = 0; jj < 2; jj++) {\n cover[i][j] += 1 << ((i + ii) * 4 + (j + jj));\n }\n }\n for(int k = 1; k < 3; k++) {\n dx[i][j][k ] = (i + k) % 3 - i;\n dy[i][j][k+2] = (j + k) % 3 - j;\n }\n }\n }\n vector<int> ans;\n while(1) {\n cin >> n;\n if(n == 0) break;\n ans.push_back(solve());\n }\n for(auto &i : ans) cout << i << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 7796, "score_of_the_acc": -0.1007, "final_rank": 4 }, { "submission_id": "aoj_1243_6107405", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <tuple>\n#include <set>\n#include <vector>\n#include <queue>\nusing namespace std;\n\nint n;\nint cover[3][3];\nint schedule[365];\nint dx[3][3][5];\nint dy[3][3][5];\nusing State = tuple<int, int, int, int, int, int, int>;\nset<State> used;\n\nint solve() {\n used.clear();\n for(int i = 0; i < n; i++) {\n schedule[i] = 0;\n for(int j = 0; j < 16; j++) {\n int x; cin >> x;\n schedule[i] += x << j;\n }\n }\n if(cover[1][1] & schedule[0]) return 0;\n queue<State> q;\n q.push({1, 1, 1, 1, 1, 1, 0});\n while(!q.empty()) {\n auto now = q.front();\n q.pop();\n int c0 = get<0>(now), c1 = get<1>(now), c2 = get<2>(now), c3 = get<3>(now),\n x = get<4>(now), y = get<5>(now), d = get<6>(now);\n if(d == n-1) return 1;\n c0++; c1++; c2++; c3++;\n for(int i = 0; i < 5; i++) {\n int nx = x + dx[x][y][i], ny = y + dy[x][y][i];\n if((cover[nx][ny]&schedule[d+1]) == 0) {\n // cerr << x << \" \" << y << \" \" << nx << \" \" << ny << endl;\n State nxt = make_tuple(c0, c1, c2, c3, nx, ny, d+1);\n if(nx == 0 && ny == 0) {\n get<0>(nxt) = 0;\n } else if(nx == 0 && ny == 2) {\n get<1>(nxt) = 0;\n } else if(nx == 2 && ny == 0) {\n get<2>(nxt) = 0;\n } else if(nx == 2 && ny == 2) {\n get<3>(nxt) = 0;\n }\n if(!used.count(nxt) &&\n get<0>(nxt) != 7 && get<1>(nxt) != 7 &&\n get<2>(nxt) != 7 && get<3>(nxt) != 7) {\n q.push(nxt);\n used.insert(nxt);\n }\n }\n }\n }\n return 0;\n}\n\nint main() {\n for(int i = 0; i < 3; i++) {\n for(int j = 0; j < 3; j++) {\n for(int ii = 0; ii < 2; ii++) {\n for(int jj = 0; jj < 2; jj++) {\n cover[i][j] += 1 << ((i + ii) * 4 + (j + jj));\n }\n }\n for(int k = 1; k < 3; k++) {\n dx[i][j][k ] = (i + k) % 3 - i;\n dy[i][j][k+2] = (j + k) % 3 - j;\n }\n }\n }\n vector<int> ans;\n while(1) {\n cin >> n;\n if(n == 0) break;\n ans.push_back(solve());\n }\n for(auto &i : ans) cout << i << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 7748, "score_of_the_acc": -0.1003, "final_rank": 3 }, { "submission_id": "aoj_1243_6106653", "code_snippet": "/*\nhttps://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=1243\n\n現在の雲の左上の座標・何日目か・1,4,13,16番のセルが何日間連続で雨が降っていないかという情報を\nクラスStateで保存する。方針としては幅優先探索を可能な限り行っていき、最終日まで条件を満たしながら\n雲を動かしてけるかを確かめる。この時同じ状態を何度も探索することを防ぐために、cacheを用いている。\n\ncacheを使うことを中々思いつかず、計算時間の問題を解決するのに時間がかかった。結局1時間程\nかかってしまった。\n */\n\n#include <iostream>\n#include <algorithm>\n#include <queue>\n#include <tuple>\n#include <cstring>\nusing namespace std;\n\nconst int MAX_N = 370;\nconst int AREA_NUM = 16;\nconst int dx[] = {0, 1, 0, -1, 0, 2, 0, -2, 0};\nconst int dy[] = {0, 0, -1, 0, 1, 0, -2, 0, 2};\nconst int ax[] = {0, 1, 0, 1};\nconst int ay[] = {0, 0, 1, 1};\nint cache[MAX_N][3][3][7][7][7][7];\n\nint need_sun[MAX_N][AREA_NUM];\n\nstruct State\n{\n int x;\n int y;\n int t;\n int A;\n int B;\n int C;\n int D;\n};\n\nbool check_border(int x, int y)\n{\n return ((0 <= x) && (x < 4) && (0 <= y) && (y < 4));\n}\n\nbool check_pos_and_specialday(int left_x, int top_y, int t)\n{\n int right_x = left_x + 1;\n int bottom_y = top_y + 1;\n if (check_border(left_x, top_y) &&\n check_border(right_x, bottom_y))\n return (need_sun[t][left_x + top_y * 4] == 0) &&\n (need_sun[t][left_x + bottom_y * 4] == 0) &&\n (need_sun[t][right_x + top_y * 4] == 0) &&\n (need_sun[t][right_x + bottom_y * 4] == 0);\n else\n return false;\n}\n\nbool check_dry(State state)\n{\n return state.A < 7 && state.B < 7 && state.C < 7 && state.D < 7;\n}\n\nState update_state(State state, int nx, int ny)\n{\n State new_state = {nx, ny, state.t + 1,\n state.A + 1, state.B + 1,\n state.C + 1, state.D + 1};\n int idx = 0;\n for (int i = 0; i < 4; i++)\n {\n idx = nx + ax[i] + (ny + ay[i]) * 4;\n if (idx == 0)\n new_state.A = 0;\n else if (idx == 3)\n new_state.B = 0;\n else if (idx == 12)\n new_state.C = 0;\n else if (idx == 15)\n new_state.D = 0;\n }\n return new_state;\n}\n\nint solve(int N, int sx, int sy)\n{\n int nx, ny, t;\n\n //左上のx座標・左上のy座標・何日目か・マス1の雨が降っていない期間\n queue<State> que;\n State init_state = {sx, sy, 0, 1, 1, 1, 1};\n\n bool last_day = false;\n que.push(init_state);\n while (!que.empty())\n {\n State state = que.front();\n que.pop();\n\n if (cache[state.t][state.x][state.y][state.A][state.B][state.C][state.D]++)\n continue;\n for (int i = 0; i < 9; i++)\n {\n nx = state.x + dx[i];\n ny = state.y + dy[i];\n t = state.t;\n if (t == N - 1)\n {\n last_day = true;\n break;\n }\n State new_state = update_state(state, nx, ny);\n if (check_dry(new_state) && check_pos_and_specialday(nx, ny, t + 1))\n que.push(new_state);\n }\n }\n\n if (last_day)\n return 1;\n else\n return 0;\n}\n\nint main()\n{\n int N;\n while (cin >> N)\n {\n if (N == 0)\n break;\n\n for (int i = 0; i < N; i++)\n for (int j = 0; j < AREA_NUM; j++)\n cin >> need_sun[i][j];\n\n memset(cache, 0, sizeof(cache));\n int ans = solve(N, 1, 1);\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 34644, "score_of_the_acc": -0.2757, "final_rank": 9 }, { "submission_id": "aoj_1243_6106604", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <queue>\n#include <tuple>\n#include <cstring>\nusing namespace std;\n\nconst int MAX_N = 370;\nconst int AREA_NUM = 16;\nconst int dx[] = {0, 1, 0, -1, 0, 2, 0, -2, 0};\nconst int dy[] = {0, 0, -1, 0, 1, 0, -2, 0, 2};\nconst int ax[] = {0, 1, 0, 1};\nconst int ay[] = {0, 0, 1, 1};\nint cache[MAX_N][3][3][7][7][7][7];\n\nint need_sun[MAX_N][AREA_NUM];\n\nstruct Info\n{\n int x;\n int y;\n int t;\n int A;\n int B;\n int C;\n int D;\n};\n\nbool check_border(int x, int y)\n{\n return ((0 <= x) && (x < 4) && (0 <= y) && (y < 4));\n}\n\nbool check_pos_and_specialday(int left_x, int top_y, int t)\n{\n int right_x = left_x + 1;\n int bottom_y = top_y + 1;\n if (check_border(left_x, top_y) &&\n check_border(right_x, bottom_y))\n return (need_sun[t][left_x + top_y * 4] == 0) &&\n (need_sun[t][left_x + bottom_y * 4] == 0) &&\n (need_sun[t][right_x + top_y * 4] == 0) &&\n (need_sun[t][right_x + bottom_y * 4] == 0);\n else\n return false;\n}\n\nbool check_dry(Info info)\n{\n return info.A < 7 && info.B < 7 && info.C < 7 && info.D < 7;\n}\n\nInfo update_info(Info info, int nx, int ny)\n{\n Info new_info = {nx, ny, info.t + 1,\n info.A + 1, info.B + 1,\n info.C + 1, info.D + 1};\n int idx = 0;\n for (int i = 0; i < 4; i++)\n {\n idx = nx + ax[i] + (ny + ay[i]) * 4;\n if (idx == 0)\n new_info.A = 0;\n else if (idx == 3)\n new_info.B = 0;\n else if (idx == 12)\n new_info.C = 0;\n else if (idx == 15)\n new_info.D = 0;\n }\n return new_info;\n}\n\nint solve(int N, int sx, int sy)\n{\n int nx, ny, t;\n\n //左上のx座標・左上のy座標・何日目か・マス1の雨が降っていない期間\n queue<Info> que;\n Info init_state = {sx, sy, 0, 1, 1, 1, 1};\n\n bool last_day = false;\n que.push(init_state);\n while (!que.empty())\n {\n Info info = que.front();\n que.pop();\n\n if (cache[info.t][info.x][info.y][info.A][info.B][info.C][info.D]++)\n continue;\n for (int i = 0; i < 9; i++)\n {\n nx = info.x + dx[i];\n ny = info.y + dy[i];\n t = info.t;\n if (t == N - 1)\n {\n last_day = true;\n break;\n }\n Info new_info = update_info(info, nx, ny);\n if (check_dry(new_info) && check_pos_and_specialday(nx, ny, t + 1))\n que.push(new_info);\n }\n }\n\n if (last_day)\n return 1;\n else\n return 0;\n}\n\nint main()\n{\n int N;\n while (cin >> N)\n {\n if (N == 0)\n break;\n\n for (int i = 0; i < N; i++)\n for (int j = 0; j < AREA_NUM; j++)\n cin >> need_sun[i][j];\n\n memset(cache, 0, sizeof(cache));\n int ans = solve(N, 1, 1);\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 34656, "score_of_the_acc": -0.2893, "final_rank": 13 }, { "submission_id": "aoj_1243_6106603", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <queue>\n#include <tuple>\n#include <cstring>\nusing namespace std;\n\nconst int MAX_N = 370;\nconst int AREA_NUM = 16;\nconst int dx[] = {0, 1, 0, -1, 0, 2, 0, -2, 0};\nconst int dy[] = {0, 0, -1, 0, 1, 0, -2, 0, 2};\nconst int ax[] = {0, 1, 0, 1};\nconst int ay[] = {0, 0, 1, 1};\nint cache[MAX_N][3][3][7][7][7][7];\n\nint need_sun[MAX_N][AREA_NUM];\n\nstruct Info\n{\n int x;\n int y;\n int t;\n int A;\n int B;\n int C;\n int D;\n};\n\nbool check_border(int x, int y)\n{\n return ((0 <= x) && (x < 4) && (0 <= y) && (y < 4));\n}\n\nbool check_pos_and_specialday(int left_x, int top_y, int t)\n{\n int right_x = left_x + 1;\n int bottom_y = top_y + 1;\n if (check_border(left_x, top_y) &&\n check_border(right_x, bottom_y))\n return (need_sun[t][left_x + top_y * 4] == 0) &&\n (need_sun[t][left_x + bottom_y * 4] == 0) &&\n (need_sun[t][right_x + top_y * 4] == 0) &&\n (need_sun[t][right_x + bottom_y * 4] == 0);\n else\n return false;\n}\n\nbool check_dry(Info info)\n{\n return info.A < 7 && info.B < 7 && info.C < 7 && info.D < 7;\n}\n\nInfo update_info(Info info, int nx, int ny)\n{\n Info new_info = {nx, ny, info.t + 1,\n info.A + 1, info.B + 1,\n info.C + 1, info.D + 1};\n int idx = 0;\n for (int i = 0; i < 4; i++)\n {\n idx = nx + ax[i] + (ny + ay[i]) * 4;\n if (idx == 0)\n new_info.A = 0;\n else if (idx == 3)\n new_info.B = 0;\n else if (idx == 12)\n new_info.C = 0;\n else if (idx == 15)\n new_info.D = 0;\n }\n return new_info;\n}\n\nint solve(int N, int sx, int sy)\n{\n int nx, ny, t;\n\n //左上のx座標・左上のy座標・何日目か・マス1の雨が降っていない期間\n queue<Info> que;\n Info init_state = {sx, sy, 0, 1, 1, 1, 1};\n\n bool last_day = false;\n que.push(init_state);\n while (!que.empty())\n {\n Info info = que.front();\n que.pop();\n\n if (cache[info.t][info.x][info.y][info.A][info.B][info.C][info.D]++)\n continue;\n for (int i = 0; i < 9; i++)\n {\n nx = info.x + dx[i];\n ny = info.y + dy[i];\n t = info.t;\n if (t == N - 1)\n {\n last_day = true;\n break;\n }\n Info new_info = update_info(info, nx, ny);\n if (check_dry(new_info) && check_pos_and_specialday(nx, ny, t + 1))\n que.push(new_info);\n }\n }\n\n if (last_day)\n return 1;\n else\n return 0;\n}\n\nint main()\n{\n int N;\n while (cin >> N)\n {\n if (N == 0)\n break;\n\n for (int i = 0; i < N; i++)\n for (int j = 0; j < AREA_NUM; j++)\n cin >> need_sun[i][j];\n\n int ans = 0;\n memset(cache, 0, sizeof(cache));\n // if (check_pos_and_specialday(1, 1, 0))\n ans = solve(N, 1, 1);\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 34628, "score_of_the_acc": -0.2756, "final_rank": 8 }, { "submission_id": "aoj_1243_6106602", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <queue>\n#include <tuple>\n#include <cstring>\nusing namespace std;\n\nconst int MAX_N = 370;\nconst int AREA_NUM = 16;\nconst int dx[] = {0, 1, 0, -1, 0, 2, 0, -2, 0};\nconst int dy[] = {0, 0, -1, 0, 1, 0, -2, 0, 2};\nconst int ax[] = {0, 1, 0, 1};\nconst int ay[] = {0, 0, 1, 1};\nint cache[MAX_N][3][3][7][7][7][7];\n\nint need_sun[MAX_N][AREA_NUM];\n\nstruct Info\n{\n int x;\n int y;\n int t;\n int A;\n int B;\n int C;\n int D;\n};\n\nbool check_border(int x, int y)\n{\n return ((0 <= x) && (x < 4) && (0 <= y) && (y < 4));\n}\n\nbool check_pos_and_specialday(int left_x, int top_y, int t)\n{\n int right_x = left_x + 1;\n int bottom_y = top_y + 1;\n if (check_border(left_x, top_y) &&\n check_border(right_x, bottom_y))\n return (need_sun[t][left_x + top_y * 4] == 0) &&\n (need_sun[t][left_x + bottom_y * 4] == 0) &&\n (need_sun[t][right_x + top_y * 4] == 0) &&\n (need_sun[t][right_x + bottom_y * 4] == 0);\n else\n return false;\n}\n\nbool check_dry(Info info)\n{\n return info.A < 7 && info.B < 7 && info.C < 7 && info.D < 7;\n}\n\nInfo update_info(Info info, int nx, int ny)\n{\n Info new_info = {nx, ny, info.t + 1,\n info.A + 1, info.B + 1,\n info.C + 1, info.D + 1};\n int idx = 0;\n for (int i = 0; i < 4; i++)\n {\n idx = nx + ax[i] + (ny + ay[i]) * 4;\n if (idx == 0)\n new_info.A = 0;\n else if (idx == 3)\n new_info.B = 0;\n else if (idx == 12)\n new_info.C = 0;\n else if (idx == 15)\n new_info.D = 0;\n }\n return new_info;\n}\n\nint solve(int N, int sx, int sy)\n{\n int nx, ny, t;\n\n //左上のx座標・左上のy座標・何日目か・マス1の雨が降っていない期間\n queue<Info> que;\n Info init_state = {sx, sy, 0, 1, 1, 1, 1};\n\n bool last_day = false;\n que.push(init_state);\n while (!que.empty())\n {\n Info info = que.front();\n que.pop();\n\n if (cache[info.t][info.x][info.y][info.A][info.B][info.C][info.D]++)\n continue;\n for (int i = 0; i < 9; i++)\n {\n nx = info.x + dx[i];\n ny = info.y + dy[i];\n t = info.t;\n if (t == N - 1)\n {\n last_day = true;\n break;\n }\n Info new_info = update_info(info, nx, ny);\n if (check_dry(new_info) && check_pos_and_specialday(nx, ny, t + 1))\n que.push(new_info);\n }\n }\n\n if (last_day)\n return 1;\n else\n return 0;\n}\n\nint main()\n{\n int N;\n while (cin >> N)\n {\n if (N == 0)\n break;\n\n for (int i = 0; i < N; i++)\n for (int j = 0; j < AREA_NUM; j++)\n cin >> need_sun[i][j];\n\n int ans = 0;\n memset(cache, 0, sizeof(cache));\n if (check_pos_and_specialday(1, 1, 0))\n ans = solve(N, 1, 1);\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 34488, "score_of_the_acc": -0.288, "final_rank": 11 }, { "submission_id": "aoj_1243_6106591", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <queue>\n#include <tuple>\n#include <cstring>\nusing namespace std;\n\nconst int MAX_N = 370;\nconst int AREA_NUM = 16;\nconst int dx[] = {0, 1, 0, -1, 0, 2, 0, -2, 0};\nconst int dy[] = {0, 0, -1, 0, 1, 0, -2, 0, 2};\nconst int ax[] = {0, 1, 0, 1};\nconst int ay[] = {0, 0, 1, 1};\nint cache[MAX_N][3][3][7][7][7][7];\n\nint need_sun[MAX_N][AREA_NUM];\n\nstruct Info\n{\n int x;\n int y;\n int t;\n int A;\n int B;\n int C;\n int D;\n};\n\nbool check_border(int x, int y)\n{\n return ((0 <= x) && (x < 4) && (0 <= y) && (y < 4));\n}\n\nbool valid(int left_x, int top_y, int t)\n{\n int right_x = left_x + 1;\n int bottom_y = top_y + 1;\n if (check_border(left_x, top_y) &&\n check_border(right_x, bottom_y))\n return (need_sun[t][left_x + top_y * 4] == 0) &&\n (need_sun[t][left_x + bottom_y * 4] == 0) &&\n (need_sun[t][right_x + top_y * 4] == 0) &&\n (need_sun[t][right_x + bottom_y * 4] == 0);\n else\n return false;\n}\n\nInfo update_info(Info info, int nx, int ny)\n{\n Info new_info = {nx, ny, info.t + 1,\n info.A + 1, info.B + 1,\n info.C + 1, info.D + 1};\n int idx = 0;\n for (int i = 0; i < 4; i++)\n {\n idx = nx + ax[i] + (ny + ay[i]) * 4;\n if (idx == 0)\n new_info.A = 0;\n else if (idx == 3)\n new_info.B = 0;\n else if (idx == 12)\n new_info.C = 0;\n else if (idx == 15)\n new_info.D = 0;\n }\n return new_info;\n}\n\nbool dry_check(Info info)\n{\n return info.A < 7 && info.B < 7 && info.C < 7 && info.D < 7;\n}\n\nint solve(int N, int sx, int sy)\n{\n int nx, ny, t;\n\n //左上のx座標・左上のy座標・何日目か・マス1の雨が降っていない期間\n queue<Info> que;\n Info init_state = {sx, sy, 0, 1, 1, 1, 1};\n\n bool last_day = false;\n que.push(init_state);\n while (!que.empty())\n {\n Info info = que.front();\n que.pop();\n\n if (cache[info.t][info.x][info.y][info.A][info.B][info.C][info.D]++)\n continue;\n for (int i = 0; i < 9; i++)\n {\n nx = info.x + dx[i];\n ny = info.y + dy[i];\n t = info.t;\n if (t == N - 1)\n {\n last_day = true;\n break;\n }\n Info new_info = update_info(info, nx, ny);\n if (dry_check(new_info) && valid(nx, ny, t + 1))\n que.push(new_info);\n }\n }\n\n if (last_day)\n return 1;\n else\n return 0;\n}\n\nint main()\n{\n int N;\n while (cin >> N)\n {\n if (N == 0)\n break;\n\n for (int i = 0; i < N; i++)\n for (int j = 0; j < AREA_NUM; j++)\n cin >> need_sun[i][j];\n\n int ans = 0;\n memset(cache, 0, sizeof(cache));\n if (valid(1, 1, 0))\n ans = solve(N, 1, 1);\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 34624, "score_of_the_acc": -0.2891, "final_rank": 12 }, { "submission_id": "aoj_1243_6106589", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <queue>\n#include <tuple>\n#include <cstring>\nusing namespace std;\n\nconst int MAX_N = 370;\nconst int AREA_NUM = 16;\nconst int dx[] = {0, 1, 0, -1, 0, 2, 0, -2, 0};\nconst int dy[] = {0, 0, -1, 0, 1, 0, -2, 0, 2};\nconst int ax[] = {0, 1, 0, 1};\nconst int ay[] = {0, 0, 1, 1};\nint cache[MAX_N][3][3][7][7][7][7];\n\nint need_sun[MAX_N][AREA_NUM];\n\nstruct Info\n{\n int x;\n int y;\n int t;\n int A;\n int B;\n int C;\n int D;\n};\n\nbool check_border(int x, int y)\n{\n return ((0 <= x) && (x < 4) && (0 <= y) && (y < 4));\n}\n\nbool valid(int left_x, int top_y, int t)\n{\n int right_x = left_x + 1;\n int bottom_y = top_y + 1;\n if (check_border(left_x, top_y) &&\n check_border(right_x, bottom_y))\n return (need_sun[t][left_x + top_y * 4] == 0) &&\n (need_sun[t][left_x + bottom_y * 4] == 0) &&\n (need_sun[t][right_x + top_y * 4] == 0) &&\n (need_sun[t][right_x + bottom_y * 4] == 0);\n else\n return false;\n}\n\nInfo update_info(Info info, int nx, int ny)\n{\n Info new_info = {nx, ny, info.t + 1,\n info.A + 1, info.B + 1,\n info.C + 1, info.D + 1};\n int idx = 0;\n for (int i = 0; i < 4; i++)\n {\n idx = nx + ax[i] + (ny + ay[i]) * 4;\n if (idx == 0)\n new_info.A = 0;\n else if (idx == 3)\n new_info.B = 0;\n else if (idx == 12)\n new_info.C = 0;\n else if (idx == 15)\n new_info.D = 0;\n }\n return new_info;\n}\n\nbool dry_check(Info info)\n{\n return info.A < 7 && info.B < 7 && info.C < 7 && info.D < 7;\n}\n\nint solve(int N, int sx, int sy)\n{\n int nx, ny, t;\n\n //左上のx座標・左上のy座標・何日目か・マス1の雨が降っていない期間\n queue<Info> que;\n Info init_state = {sx, sy, 0, 1, 1, 1, 1};\n int visit[4][4];\n for (int i = 0; i < 16; i++)\n visit[i % 4][i / 4] = 0;\n\n bool last_day = false;\n que.push(init_state);\n while (!que.empty())\n {\n Info info = que.front();\n que.pop();\n\n if (cache[info.t][info.x][info.y][info.A][info.B][info.C][info.D]++)\n continue;\n\n visit[info.x][info.y] = 1;\n visit[info.x + 1][info.y] = 1;\n visit[info.x][info.y + 1] = 1;\n visit[info.x + 1][info.y + 1] = 1;\n for (int i = 0; i < 9; i++)\n {\n nx = info.x + dx[i];\n ny = info.y + dy[i];\n t = info.t;\n if (t == N - 1)\n {\n last_day = true;\n break;\n }\n Info new_info = update_info(info, nx, ny);\n if (dry_check(new_info) && valid(nx, ny, t + 1))\n que.push(new_info);\n }\n }\n\n int visited_areas = 0;\n for (int i = 0; i < 4; i++)\n for (int j = 0; j < 4; j++)\n visited_areas += visit[i][j];\n\n if (last_day && (visited_areas == 16))\n return 1;\n else\n return 0;\n}\n\nint main()\n{\n int N;\n while (cin >> N)\n {\n if (N == 0)\n break;\n\n for (int i = 0; i < N; i++)\n for (int j = 0; j < AREA_NUM; j++)\n cin >> need_sun[i][j];\n\n int ans = 0;\n memset(cache, 0, sizeof(cache));\n if (valid(1, 1, 0))\n ans = solve(N, 1, 1);\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 34416, "score_of_the_acc": -0.2874, "final_rank": 10 }, { "submission_id": "aoj_1243_6011133", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define all(A) A.begin(),A.end()\nusing vll = vector<ll>;\n#define rep(i, n) for (long long i = 0; i < (long long)(n); i++)\n\nvector<vll> Q={{1,2,5,6},{2,3,6,7},{3,4,7,8},{5,6,9,10},{6,7,10,11},{7,8,11,12},{9,10,13,14},{10,11,14,15},{11,12,15,16}};\nvector<vll> T={{0,1,2,3,6},{0,1,2,4,7},{0,1,2,5,8},{3,4,5,0,6},{3,4,5,1,7},{3,4,5,2,8},{6,7,8,0,3},{6,7,8,1,4},{6,7,8,2,5}};\nint main() {\n\twhile(1){\n\t\tll N;\n\t\tcin>>N;\n\t\tif(N==0)return 0;\n\t\tbool CD=false;\n\t\tvector<vector<vector<vector<vector<vector<bool>>>>>> DP(N+1,vector<vector<vector<vector<vector<bool>>>>>\n\t\t(7,vector<vector<vector<vector<bool>>>>(7,vector<vector<vector<bool>>>(7,vector<vector<bool>>(7,vector<bool>(9,false))))));\n\t\tDP[0][1][1][1][1][4]=true;\n\t\tvll A(16);\n\t\trep(i,16)cin>>A[i];\n\t\tif(A[5]==1||A[6]==1||A[9]==1||A[10]==1)CD=true;\n\n\t\trep(da,N-1){\n\t\t\tvll A(16);\n\t\t\trep(i,16)cin>>A[i];\n\t\t\trep(p,9){\n\t\t\t\trep(j,5){\n\t\t\t\t\tll t=T[p][j];\n\t\t\t\t\tbool C=true;\n\t\t\t\t\trep(i,4){\n\t\t\t\t\t\tif(A[Q[t][i]-1]==1)C=false;\n\t\t\t\t\t}\n\t\t\t\t\tif(C){//ここに動かせる.\n\t\t\t\t\t\tif(t==0){\n\t\t\t\t\t\t\trep(a,7)rep(b,6)rep(c,6)rep(d,6){\n\t\t\t\t\t\t\tif(DP[da][a][b][c][d][p]){\n\t\t\t\t\t\t\t\tDP[da+1][0][b+1][c+1][d+1][t]=true;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if(t==2){\n\t\t\t\t\t\t\trep(a,6)rep(b,7)rep(c,6)rep(d,6){\n\t\t\t\t\t\t\tif(DP[da][a][b][c][d][p]){\n\t\t\t\t\t\t\t\tDP[da+1][a+1][0][c+1][d+1][t]=true;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if(t==6){\n\t\t\t\t\t\t\trep(a,6)rep(b,6)rep(c,7)rep(d,6){\n\t\t\t\t\t\t\tif(DP[da][a][b][c][d][p]){\n\t\t\t\t\t\t\t\tDP[da+1][a+1][b+1][0][d+1][t]=true;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if(t==8){\n\t\t\t\t\t\t\trep(a,6)rep(b,6)rep(c,6)rep(d,7){\n\t\t\t\t\t\t\tif(DP[da][a][b][c][d][p]){\n\t\t\t\t\t\t\t\tDP[da+1][a+1][b+1][c+1][0][t]=true;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse{\n\t\t\t\t\t\t\trep(a,6)rep(b,6)rep(c,6)rep(d,6){\n\t\t\t\t\t\t\tif(DP[da][a][b][c][d][p]){\n\t\t\t\t\t\t\t\tDP[da+1][a+1][b+1][c+1][d+1][t]=true;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\n\n\n\n\n\t\t\t\t\t\t\n\n\n\n\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\n\n\n\t\tif(CD)cout<<0<<endl;\n\t\telse{\n\t\t\tbool C=false;\n\t\t\trep(a,7)rep(b,7)rep(c,7)rep(d,7)rep(p,9){\n\t\t\t\tif(DP[N-1][a][b][c][d][p])C=true;\n\t\t\t}\n\t\t\tcout<<C<<endl;\n\n\t\t}\n\t}\n\t\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 69944, "score_of_the_acc": -0.8969, "final_rank": 17 }, { "submission_id": "aoj_1243_6011099", "code_snippet": "#include<iostream>\n#include<vector>\nusing namespace std;\nint N;\nbool dp[2][9][9][9][9][9][9];\nint ok[365];\nvoid clr(int id)\n{\n\tfor(int i=0;i<9;i++)for(int j=0;j<9;j++)for(int k=0;k<9;k++)for(int l=0;l<9;l++)for(int m=0;m<9;m++)for(int n=0;n<9;n++)dp[id][i][j][k][l][m][n]=false;\n}\nint G[9];\nbool check[9][9][9][9][9][9][9];\nint main()\n{\n\tfor(int x=0;x<3;x++)for(int y=0;y<3;y++)\n\t{\n\t\tfor(int tx=0;tx<3;tx++)for(int ty=0;ty<3;ty++)\n\t\t{\n\t\t\tif(x==tx||y==ty)G[x*3+y]|=1<<tx*3+ty;\n\t\t}\n\t}\n\tfor(int a=0;a<9;a++)for(int b=0;b<9;b++)for(int c=0;c<9;c++)for(int d=0;d<9;d++)for(int e=0;e<9;e++)for(int f=0;f<9;f++)for(int g=0;g<9;g++)\n\t{\n\t\tbool ok=true;\n\t\tfor(int k:{0,2,6,8})\n\t\t{\n\t\t\tif(a-k&&b-k&&c-k&&d-k&&e-k&&f-k&&g-k)ok=false;\n\t\t}\n\t\tcheck[a][b][c][d][e][f][g]=ok;\n\t}\n\twhile(cin>>N,N)\n\t{\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tint c[4][4];\n\t\t\tfor(int j=0;j<4;j++)for(int k=0;k<4;k++)cin>>c[j][k];\n\t\t\tok[i]=0;\n\t\t\tfor(int x=0;x<3;x++)for(int y=0;y<3;y++)\n\t\t\t{\n\t\t\t\tif(!(c[x][y]||c[x][y+1]||c[x+1][y]||c[x+1][y+1]))ok[i]|=1<<x*3+y;\n\t\t\t}\n\t\t}\n\t\tif(!(ok[0]>>4&1))\n\t\t{\n\t\t\tcout<<0<<endl;\n\t\t\tcontinue;\n\t\t}\n\t\tint now=0;\n\t\tclr(now);\n\t\tdp[now][0][0][0][0][0][4]=true;\n\t\tfor(int i=1;i<N;i++)\n\t\t{\n\t\t\tint nxt=1-now;\n\t\t\tclr(nxt);\n\t\t\tfor(int a=0;a<9;a++)for(int b=0;b<9;b++)for(int c=0;c<9;c++)for(int d=0;d<9;d++)for(int e=0;e<9;e++)for(int f=0;f<9;f++)if(dp[now][a][b][c][d][e][f])\n\t\t\t{\n\t\t\t\tint to=G[f]&ok[i];\n\t\t\t\tfor(int g=0;g<9;g++)if(to>>g&1)\n\t\t\t\t{\n\t\t\t\t\tif(i>=6&&!check[a][b][c][d][e][f][g])continue;\n\t\t\t\t\tdp[nxt][b][c][d][e][f][g]=true;\n\t\t\t\t}\n\t\t\t}\n\t\t\tnow=nxt;\n\t\t}\n\t\tbool ok=false;\n\t\tfor(int a=0;a<9;a++)for(int b=0;b<9;b++)for(int c=0;c<9;c++)for(int d=0;d<9;d++)for(int e=0;e<9;e++)for(int f=0;f<9;f++)if(dp[now][a][b][c][d][e][f])ok=true;\n\t\tcout<<(ok?1:0)<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 760, "memory_kb": 9152, "score_of_the_acc": -1.044, "final_rank": 18 }, { "submission_id": "aoj_1243_6011075", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, t) for (int i = (int)(s); i < (int)(t); ++i)\n\nint N;\nvector<int> cnt;\nvector<vector<int>> sched;\nset<pair<int, vector<int>>> st;\n\nint di[4] = {0, 1, 0, -1};\nint dj[4] = {1, 0, -1, 0};\n\nbool dfs(int day, int p) {\n if (day == N) return true;\n if (st.count({day, cnt})) {\n return false;\n }\n rep(i,0,16) if (cnt[i] >= 7) return false;\n rep(i,0,16) if (sched[day][i] && cnt[i] == 0) return false;\n auto tmp = cnt;\n int i = p/4, j=p%4;\n rep(k,1,3) {\n rep(d,0,4) {\n int ni = i + k*di[d], nj = j + k*dj[d];\n if (0 <= ni && ni < 3 && 0 <= nj && nj < 3) {\n rep(x,0,16) cnt[x]++;\n cnt[4*ni+nj] = cnt[4*ni+nj+1] = cnt[4*(ni+1)+nj] = cnt[4*(ni+1)+nj+1] = 0;\n if (dfs(day+1, 4*ni+nj)) return true;\n cnt = tmp;\n }\n }\n }\n rep(x,0,16) cnt[x]++;\n cnt[4*i+j] = cnt[4*i+j+1] = cnt[4*(i+1)+j] = cnt[4*(i+1)+j+1] = 0;\n if (dfs(day+1, 4*i+j)) return true;\n cnt = tmp;\n st.insert({day, cnt});\n return false;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(15);\n\n while (1) {\n cin >> N;\n if (N==0) break;\n st.clear();\n sched.resize(N, vector<int>(16));\n rep(i,0,N) rep(j,0,16) cin >> sched[i][j];\n cnt.assign(16,1);\n cnt[5] = cnt[6] = cnt[9] = cnt[10] = 0;\n cout << dfs(0, 5) << endl;\n }\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 19552, "score_of_the_acc": -0.3032, "final_rank": 15 }, { "submission_id": "aoj_1243_5972489", "code_snippet": "#pragma region Macros\n#include <bits/stdc++.h>\nusing namespace std;\ntemplate <class T> inline bool chmax(T &a, T b) {\n if(a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <class T> inline bool chmin(T &a, T b) {\n if(a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\n#ifdef DEBUG\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << '(' << p.first << ',' << p.second << ')';\n return os;\n}\ntemplate <class T> ostream &operator<<(ostream &os, const vector<T> &v) {\n os << '{';\n for(int i = 0; i < (int)v.size(); i++) {\n if(i) { os << ','; }\n os << v[i];\n }\n os << '}';\n return os;\n}\nvoid debugg() { cerr << endl; }\ntemplate <class T, class... Args>\nvoid debugg(const T &x, const Args &... args) {\n cerr << \" \" << x;\n debugg(args...);\n}\n#define debug(...) \\\n cerr << __LINE__ << \" [\" << #__VA_ARGS__ << \"]: \", debugg(__VA_ARGS__)\n#define dump(x) cerr << __LINE__ << \" \" << #x << \" = \" << (x) << endl\n#else\n#define debug(...) (void(0))\n#define dump(x) (void(0))\n#endif\n\nstruct Setup {\n Setup() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(15);\n }\n} __Setup;\n\nusing ll = long long;\n#define OVERLOAD3(_1, _2, _3, name, ...) name\n#define ALL(v) (v).begin(), (v).end()\n#define RALL(v) (v).rbegin(), (v).rend()\n#define REP1(i, n) for(int i = 0; i < (n); i++)\n#define REP2(i, a, b) for(int i = (a); i < int(b); i++)\n#define REP(...) OVERLOAD3(__VA_ARGS__, REP2, REP1)(__VA_ARGS__)\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\nconst int INF = 1 << 30;\nconst ll LLINF = 1LL << 60;\nconstexpr int MOD = 1000000007;\nconstexpr int MOD2 = 998244353;\nconst int dx[4] = {1, 0, -1, 0};\nconst int dy[4] = {0, 1, 0, -1};\n\nvoid Case(int i) { cout << \"Case #\" << i << \": \"; }\nint popcount(int x) { return __builtin_popcount(x); }\nll popcount(ll x) { return __builtin_popcountll(x); }\n#pragma endregion Macros\n\nusing arr = array<int, 16>;\n\nbool solve() {\n int N;\n cin >> N;\n if(N == 0) return false;\n vector<arr> schedules(N);\n REP(i, N) REP(j, 16) cin >> schedules[i][j];\n\n vector<map<arr, int>> memo(16);\n arr now;\n bool ans = false;\n REP(i, 16) now[i] = 1;\n now[5] = now[6] = now[9] = now[10] = 0;\n auto dfs = [&](auto&& self, int cx, int cy, int d) -> void {\n if(ans) return;\n if(d >= N) {\n // debug(cx, cy, d);\n // REP(i, 16) cerr << now[i] << ' ';\n // cerr << endl;\n ans = true;\n return;\n }\n REP(x, 4) REP(y, 4) {\n if(now[x*4 + y] >= 7) return;\n if(now[x*4 + y] == 0 and schedules[d][x*4 + y]) return;\n }\n if(memo[cx*4 + cy].count(now) and memo[cx*4 + cy][now] >= d) return;\n // debug(cx, cy, d);\n // REP(i, 16) cerr << now[i] << ' ';\n // cerr << endl;\n memo[cx*4 + cy][now] = d;\n REP(dir, 4) REP(w, 3) {\n int nx = cx + dx[dir] * w;\n int ny = cy + dy[dir] * w;\n if(nx < 0 or nx >= 3 or ny < 0 or ny >= 3) continue;\n auto tmp = now;\n REP(x, 4) REP(y, 4) {\n if(nx <= x and x <= nx+1 and ny <= y and y <= ny+1) now[x*4 + y] = 0;\n else now[x*4 + y] += 1;\n }\n self(self, nx, ny, d+1);\n now = tmp;\n }\n };\n dfs(dfs, 1, 1, 0);\n cout << ans << '\\n';\n return true;\n}\n\nint main() {\n while(solve());\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3928, "score_of_the_acc": -0.0021, "final_rank": 1 } ]