//You are given a 0-indexed integer array nums. For each index i (1 <= i <=
//nums.length - 2) the beauty of nums[i] equals: 
//
// 
// 2, if nums[j] < nums[i] < nums[k], for all 0 <= j < i and for all i < k <= 
//nums.length - 1. 
// 1, if nums[i - 1] < nums[i] < nums[i + 1], and the previous condition is not 
//satisfied. 
// 0, if none of the previous conditions holds. 
// 
//
// Return the sum of beauty of all nums[i] where 1 <= i <= nums.length - 2. 
//
// 
// Example 1: 
//
// 
//Input: nums = [1,2,3]
//Output: 2
//Explanation: For each index i in the range 1 <= i <= 1:
//- The beauty of nums[1] equals 2.
// 
//
// Example 2: 
//
// 
//Input: nums = [2,4,6,4]
//Output: 1
//Explanation: For each index i in the range 1 <= i <= 2:
//- The beauty of nums[1] equals 1.
//- The beauty of nums[2] equals 0.
// 
//
// Example 3: 
//
// 
//Input: nums = [3,2,1]
//Output: 0
//Explanation: For each index i in the range 1 <= i <= 1:
//- The beauty of nums[1] equals 0.
// 
//
// 
// Constraints: 
//
// 
// 3 <= nums.length <= 10⁵ 
// 1 <= nums[i] <= 10⁵ 
// 
// Related Topics Array 👍 191 👎 19


package leetcodeProblem.leetcode.editor.en

class SumOfBeautyInTheArray {
    fun solution() {
    }

    //below code will be used for submission to leetcode (using plugin of course)
    //leetcode submit region begin(Prohibit modification and deletion)
    class Solution {
        fun sumOfBeauties(nums: IntArray): Int {
            var sumOfBeauties = 0
            for (i in nums.indices) {

                if (nums[i - 1] < nums[i] && nums[i] < nums[i + 1]) {
                    sumOfBeauties++
                }
            }

            return 0
        }
    }
//leetcode submit region end(Prohibit modification and deletion)

}

fun main() {}
  

