When y=0, the function crosses the x-axis; these are the zeros.
So (x-2) is a zero, and so is (x+3). This implies that and
So plugging these two x values into the function, we should see that
Can you solve this system of equations?
This one follows the same idea as the previous problem. Plug these two values into the function, noting that when x=-4 and 2, f(-4)=f(2)=0. Then solve the system of equations.2.)
f(x)= 3x^4 +14x^3+px^2+qx+24 has x intercepts -4 and 2
determine the function
Solution: f(x)= 3x^4+14x^3-11x^2-70x+24
Can you take it from here?