Hi I was trying to understand the geometry of Sulphur Dioxide molecule on the basis of hybridisation involved in the central atom. I found that Sulphur atom should have SP2 hybridisation. I want to know that is there any promotion of electron from 3 p-orbitals to 3d-orbitals and then forming dπ-pπ bonding? Electronic Configration of Sulphur is [Ne]3s2 3p4 ,right ? It means in ground state it would have one fully filled 3p-orbital and two half filled 3p-orbitals. And if it hybridise as such including one s and two half filled p-orbitals leading to three sp3 hybrid orbitals one of which is fully filled and two half filled hybrid orbitals form sigma bond with two oxygen atom then this will lead to completion of octet for sulphur atom but not the octet to oxygen atom , isn’t it? Then how it is possible that it undergoes hybridisation with the promotion of promotion of electrons into 3d-orbitals ? Or SO2 has conformation something like ozone which text books promotes us to think about ? If SO2 has structure like the ozone inspite of sulphur atom have accessibility to d-orbitals then why is it so ?