A netmask is (in binary) composed of 2 sets of bits.
The first is made only of bits set to 1
The second is made only of bits set to 0
Bits set to 1 indicate what part of the IP address refers to the network address
Bits set to 0 indicate what part of the IP address refers to the host address
So this config :
10.0.1.34 255.255.0.0 (11111111.11111111.00000000.00000000)
means that you're the host number 1.34 in the 10.0.0.0 network
Thus in your conf there are 2 problems :
1/ IP config of interfaces :
WLAN0 : inet addr:10.0.0.1 Bcast:10.255.255.255 Mask:255.0.0.0
WLAN0.1 : inet addr:10.0.1.1 Bcast:10.255.255.255 Mask:255.0.0.0
both interfaces are in the same subnet : 10.0.0.0 255.0.0.0
they should be in different subnets : 10.0.0.0 255.255.255.0 and 10.0.1.0 255.255.255.0
2/ DHCPD config :
subnet 10.0.1.0 netmask 255.255.0.0
subnet 10.0.0.0 netmask 255.255.0.0
first that doesn't match your interfaces config (255.0.0.0) and second you've got 2 instances of the same subnet : 10.0.1.0 255.255.0.0 is included in 10.0.0.0 255.255.0.0 just like all 10.0.x.x addresses.
so, as for the interfaces, you've got to use 255.255.255.0 netmask.
I'm not sure whether I made myself clear... since the difference between your 2 subnets is in the 3rd byte of the address, the mask _MUST_ be 3 times 255 and then 0.
Remark : the default mask for 10. networks is 255.0.0.0, and the default one for 192 networks is 255.255.255.0, that's why your interfaces are configured with these masks.
But that's not a problem, you can use other masks, but, if so, then you have to specify the mask you'll use :
ifconfig eth0 192.168.0.3 will give a 192.168.0.3 255.255.255.0 config
ifconfig eth0 192.168.0.3 netmask 255.255.0.0 will overide the default mask and give a 192.168.0.3 255.255.0.0 config
Last edited by fr_laz; 05-11-2005 at 07:06 AM.