Posted by ne on Wednesday, March 10, 2010 at 11:08pm.
Find the orbital speed of an ice cube in the rings of Saturn, if the mass of Saturn is 5.67 × 1026 kg and the rings
have an average radius of 100,000 km.
- Physics - FredR, Thursday, March 11, 2010 at 1:37am
Newton's law of gravitation:
F = G m1 m2 /r^2
let m2 = mass of ice cube and
s = G m1/r^2
F = s m2
s = m2/F
let V = orbital speed
centripetal acceleration = V^2/r
For an object to remain in orbit s must equal the centripetal acceleration so,
s = V^2/r
- Physics - drwls, Thursday, March 11, 2010 at 3:07am
Taking up where FredR left off,
V^2/r = G m/r^2
V^2 = G m/r
where m is the mass of Saturn.
G = 6.674*10^-11 N*m^2/kg^2
Solve for V
Answer This Question
More Related Questions
- physics - The rings of a Saturn-like planet are composed of chunks of ice that ...
- Physics - Astronomy - A hypothetical moon is orbiting Saturn in a circular orbit...
- physics - A spacecraft of mass m1 = 4673 kg with a speed v1i=5.0 ×103 m/s ...
- Physics Classical Mechanics - A spacecraft of mass m1 = 2161 kg with a speed v1i...
- Astronomy - At opposition, Saturn is observed to subtend an angular radius of 9....
- physic - A spacecraft of mass = 4673 kg with a speed 5.0 10 m/s approaches ...
- science - Are Saturn rings made of ice
- Physics180 - Tidal forces can break apart objects that orbit too close to a ...
- Physics - What is the weight of a 22.0 kg mass at the equator on the surface of ...
- science - One of Saturn's moons has an orbital distance of 1.87×100000000m. The ...