Thermodynamic formula - transposition help please
I've recently decided to get back into education having been out for years....I was ok at Math's back in the day!!
I'm studying thermodynamics at HND level and have come across a formula I just can't seem to get my head around.
I have the answer from the worked example solution but can't get how he got there. any help much appreciated
Formula for calculating amount of flash steam generated from hot condensate
(mg + mf ) hf1 = mg x hg2 + mf x hf2 .....we're looking for mg - the mass of gas/steam released
the figures are as follows
(mg+mf) = 550 -- the amount of condensate supplied (mf is water content, mg is vapour content)
hf1 = 670 -- enpalthy value of condensate going in
hg2 = 2697 -- enpalthy value of steam in vessel at a different pressure
hf2 = 467 -- enpalthy of water contenet of steam in vessel
In order to remove one of the two unknown's mf which is not given = (550 - mg)
Putting into formula
550 x 670 = mg x 2697 + (550 - mg)467
it's at this point that the formula needs to be transposed for mg and I have spent ages with no success.
Thanks in advance guys.
Re: Thermodynamic formula - transposition help please