Unknown since we know nothing about Event A (Team A score 0 goals) or Event B (Team B concedes 0 goals - no idea what that means).
I have 2 probabilities
p1 is the probability that team A will score 0 goals
p2 is the probability that team B will concede 0 goals
how do i combine the 2 and calculate the probability of team A scoring 0 goals into team B?
should the probability of A scoring 0 goals into team B not be the same as the probability of team B conceding 0 goals from team A?
Is it as simple as p1*p2? I thought i might need to use conditional probability to work out the intersection of p1 and p2, but it doesnt seem to look right when I do it
thanks for any help
ok i have the average number of goals that team A scores
using the poisson formula = ((lambda^k) *( e^-lambda))/k! you can work out the probability that team A scores 0 goals( where k = 0, lambda is the average number of goals scored)
I have the average number of goals that team B concedes
using the poisson formula I can work out the probability that team B concedes 0 goals.
is there any way of combining the 2 probabilities to work out the probability that team A scores no goals into team B?
not sure how else to explain it
I have no idea how sports probabilities work (what assumptions and what not goes into them), and I would imagine there would be some conditional dependence based on who Team A is playing - for example a crappy team playing a crappy team versus a good team playing a better team; so for a real world model - I do not believe you can infer that the two probabilities are independent of each other. If it was a simple model - then yea, just multiply - your probability would be a sort of "general" probability that team A scores 0 against an arbitrary team, and Team B concedes 0 goals against an arbitrary team.
That's my interpretation at the least.
(1) A score and B score
(2) A score and B do not
(3) A do not score but B do
(4) neither score
You could sum the probabilities of (3) and (4), but since some of the data is not available
you need to calculate the probability that A do not score against B
"given that" the probability of B not conceding a goal is
if p1 = the probability that A do not score
p2 = the probability of B not conceding a goal
P(p1 | p2 ) = P(p1 intersection p2) / p2
in this case though, i just end up with p1 as the answer, since (p1 intersection p2)/p2 = (p1 *p2)/p2 = p1
Im still confused as to how i get the probability that team A do not score into team B
of Team A not scoring.
That is not the probability of Team A not scoring against Team B.
The solution will involve
so the solution tried does not work.
It surely requires to be part of the solution, not cancelled.
The probability of Team A not scoring if Team B do not concede is 1.
The probability of Team B not conceding if Team A does not score is also 1
(own goals ignored).
P(AB) cannot be the multiplication of the probabilities because in this game
Team A not scoring and Team B not conceding are not 2 events.
is.... it applies to A and B playing in different games.
The probability of A not scoring against an arbitrary team
given that B did not concede against another arbitrary team
will end up giving you the probability that A do not score on average
if you use that conditional probability formula.
The events are then independent and multiplying the probabilities is feasible
to give the probability of both of 2 events happening.
In this case there is a complete overlap between A not scoring and B not conceding.
Also, if the probability of B not conceding is very small,
then the probability of A not scoring against B is much lower than
if the probability of B not conceding is very high.
ok im totally confused now
In an earlier post, you said that multiplying the probabilities was not the solution
now you are saying that it is the solution?
probability that A doesnt score into B = probability that A doesnt score * probability that B doesnt concede???