Standardize : Z=(X-μ)/σ=(Χ-12225)/795 ) and P(z)=P((X-μ)/σ)=0.900 .....check the tables...and find the answer
Hello! Can you find a right answer? Please, read first!
The manufacturer of a laser printer reports the mean number of pages a cartridge will print before it needs replacing is 12,225. The distribution of pages printed per cartridge closely follows the normal probability distribution and the standard deviation is 795 pages. The manufacturer wants to provide guidelines to potential customers as to how long they can expect a cartridge to last.
How many pages should the manufacturer advertise for each cartridge if it wants to be correct 90 percent of the time? (Round z value to 2 decimal places. Round your answer to the nearest whole number.)
I tried z= 1.28, 1.29, didn't help. I consider it as 0.50 +0.40=0.90...What z should i use?