Posted by ladybug on Friday, October 26, 2012 at 9:29pm.
You helped me with this question and this is what I got but my Professor says that each x and y intercept needs to have a coordinate. Where did I go wrong?? Can you help me?
(x+2)^2+(y+1)^2=25--this is where you helped me. Then I came and did the x and y intercepts. This what I got. But not a coordinate???
x-intercepts are found by setting y=0
y-intercepts are found by setting x=0
- college algebra--Please help Reiny please - Reiny, Friday, October 26, 2012 at 11:51pm
What you did is correct, but it would have been easier to do it this way:
let y = 0
(x+2)^2 + 1 = 25
(x+2)^2 = 24
x + 2 = ± √24 = ± 2√6
x = -2 ± 2√6
same way for the y-intercept
so the x-intercepts are:
(-2+2√6 , 0) and (-2 - 2√6, 0)
the y-intercepts are:
(0, 1+√21) and (0,1 - √21)
Your prof seem "picky"
By stating it as the y-intercept, you are implying that x = 0
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