$(4x-5)/(3x+5) ≥ 3$
I multiply both sides by (3x+5), getting me:
$(4x-5) ≥ 3(3x+5)$
which simplifies to
$(4x-5) ≥ 9x + 15$
after solving for x, I get
$x ≤ -4$
But after testing through Wolframalpha, I am given:
$-4 ≤ x ≤ -5/3$
Which I don't really understand how they got. I tried multiplying the top side of the fraction by the denominator and then expanding the factored form, and then I rearranged everything once I had a quadratic equation, and I got $-5/3$ and $-2$ as answers, but still not what Wolframalpha got.
Would appreciate some help and insight into this.