I can't give you rigorous results from an exhaustive analysis, but perhaps
a rule of thumb will suffice.
Assuming backwards crosstalk dominates, the coupled voltage between two nets
is given by:
Vb = Kb*(2tp/tr)*dVs
Vb is the coupled voltage in the backwards direction,
Kb is the backwards coupling coefficient,
tp is the propagation time across the coupled length,
tr is the signal rise time, and
dVs is the source voltage swing of the aggressor.
The ratio 2tp/tr can be viewed as the percent of the source voltage
swing available to be coupled from aggressor to victim across the
coupled length. Assuming about 6 ps/mm propagation constant across
the 3 mm body width, this ratio takes on values from 18% for 200 ps to
3.6% for 1 ns.
Values of Kb, I can only guess at, but 0.25 is a rather high coupling
coefficient. Using this value gives Vb in the range of 0.045*dVs for
200 ps risetime, down to 0.009*dVs for 1 ns.
Also, for the QSOP package, you have an additional 1.5 mm pin length
from the seating plane to the body on each side of the package. The
above does not take pin-to-pin coupling into account.
BTW, is this R-pack used as a series terminator? Do all bus signals
switch at the same time - with some time lag before stability is
required? Do the signals all propagate the same direction down
the bus? If any/all the answers to the above are yes, you could have
errorless circuit operation with some rather high levels of crosstalk.
**** To unsubscribe from si-list: send e-mail to firstname.lastname@example.org. In the BODY of message put: UNSUBSCRIBE si-list, for more help, put HELP. si-list archives are accessible at http://www.qsl.net/wb6tpu/si-list ****