The equation of a circle is you have the point (2,2) to sub in and given it is tangent to x=1 and x=6 then the radius is half the difference of these two numbers.
find the equation of the circle that passes through the (2,2) and tangent to the line x =1 and x = 6?
What would be the best way to answer this question? can you please give me an illustration?
thank you in advance and God bless you..
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An obvious point- since x= 1 and x= 6 are parallel, the center of the circle lies on the vertical line half way between them. That immediately gives you both the x-coordinate of the center and the radius. Then use pickslides equation, with x= y=2, to find the y-coordinate of the center.