No, that would give you the tangent to the curve. The normal is perpendicular to the tangent line.b) find an equation for the normal to the curve at point where t = 1
this would just be substituting t=1 into the x, y and dy/dx equations and using (y-y1) = m(x-x1), yeah?
Your parametric equations are and .c) show that the cartesian equation of the curve can be written in the form
unsure on this
Solve each of those equations for t, set them equal, and solve for y.