Information is given about a complex polynomial f(x) whose coefficients are real numbers. Find the remaining zeros for f.
Degree 3; zeros 2, 3 - i
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It is f(x) = (x - 3 - i)(x - 3 + i) = x^2 - 6x + 10
My idea is the binomial (a-b)(a+b) = a^2 - b^2 [=(x - 3 - i)(x - 3 + i) ]
is b in IC,
then: b^2 in IR, same for a.
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