Having trouble with the following problem:
(2 + 2i) (3 - 4i)
I have worked out this much so far.
6 - 8i + 6i - 8i^2
6 - 2i - 8i^2
Since there is an "i" squared, do i distribute that with the preceding "8" coefficient?
Also running into a problem solving the following word problem:
"The sum of the squares of two consecutive positive odd integers is 514. What are the integers?"
I have it set up as x^2 + (x+2)^2 = 514
x^2 + x^2 + 4x + 4 = 514
2x^2 + 4x = 510
Thanks again for everyone's help!