Objectives Functions make the basic query block more powerful, and they are used to manipulate data values. This is the first of two lessons that explore functions. It focuses on single-row character, number, and date functions, as well as those functions that convert data from one type to another (for example, conversion from character data to numeric data).
SQL Functions Functions are a very powerful feature of SQL. They can be used to do the following: Perform calculations on data Modify individual data items Manipulate output for groups of rows Format dates and numbers for display Convert column data types SQL functions sometimes take arguments and always return a value. Note: Most of the functions that are described in this lesson are specific to the Oracle version of SQL.
SQL Functions (continued) There are two types of functions: Single-row functions Multiple-row functions Single-Row Functions These functions operate on single rows only and return one result per row. There are different types of single-row functions. This lesson covers the following ones: Character Number Date Conversion General Multiple-Row Functions Functions can manipulate groups of rows to give one result per group of rows. These functions are also known as group functions (covered in a later lesson). Note: For more information and a complete list of available functions and their syntax, see Oracle SQL Reference .
Single-Row Functions Single-row functions are used to manipulate data items. They accept one or more arguments and return one value for each row that is returned by the query. An argument can be one of the following: User-supplied constant Variable value Column name Expression Features of single-row functions include: Acting on each row that is returned in the query Returning one result per row Possibly returning a data value of a different type than the one that is referenced Possibly expecting one or more arguments Can be used in SELECT , WHERE , and ORDER BY clauses; can be nested In the syntax: function_name is the name of the function arg1, arg2 is any argument to be used by the function. This can be represented by a column name or expression.
Single-Row Functions (continued) This lesson covers the following single-row functions: Character functions ccept character input and can return both character and number values Number functions Accept numeric input and return numeric values Date functions Operate on values of the DATE data type (All date functions return a value of DATE data type except the MONTHS_BETWEEN function, which returns a number.) Conversion functions Convert a value from one data type to another General functions: NVL NVL2 NULLIF COALESCE CASE DECODE
Character Functions Single-row character functions accept character data as input and can return both character and numeric values. Character functions can be divided into the following: Case-manipulation functions Character-manipulation functions Note: The functions discussed in this lesson are only some of the available functions.
Character Functions (continued)
Case-Manipulation Functions LOWER , UPPER , and INITCAP are the three case-conversion functions. LOWER Converts mixed-case or uppercase character strings to lowercase UPPER Converts mixed-case or lowercase character strings to uppercase INITCAP Converts the first letter of each word to uppercase and remaining letters to lowercase SELECT 'The job id for '||UPPER(last_name)||' is ' ||LOWER(job_id) AS &quot;EMPLOYEE DETAILS&quot; FROM employees; …
Using Case-Manipulation Functions The slide example displays the employee number, name, and department number of employee Higgins. The WHERE clause of the first SQL statement specifies the employee name as higgins . Because all the data in the EMPLOYEES table is stored in proper case, the name higgins does not find a match in the table, and no rows are selected. The WHERE clause of the second SQL statement specifies that the employee name in the EMPLOYEES table is compared to higgins , converting the LAST_NAME column to lowercase for comparison purposes. Since both names are now lowercase, a match is found and one row is selected. The WHERE clause can be rewritten in the following manner to produce the same result: ...WHERE last_name = 'Higgins' The name in the output appears as it was stored in the database. To display the name with only the first letter in uppercase, use the UPPER function in the SELECT statement. SELECT employee_id, UPPER(last_name), department_id FROM employees WHERE INITCAP(last_name) = 'Higgins';
Character-Manipulation Functions CONCAT , SUBSTR , LENGTH , INSTR , LPAD , RPAD , and TRIM are the character-manipulation functions that are covered in this lesson. CONCAT Joins values together (You are limited to using two parameters with CONCAT .) SUBSTR Extracts a string of determined length LENGTH Shows the length of a string as a numeric value INSTR Finds the numeric position of a named character LPAD Pads the character value right-justified RPAD : Pads the character value left-justified TRIM : Trims heading or trailing characters (or both) from a character string (If trim_character or trim_source is a character literal, you must enclose it in single quotation marks.) Note: You can use functions such as UPPER and LOWER with ampersand substitution. For example, use UPPER('&job_title') so that the user does not have to enter the job title in a specific case.
Using the Character-Manipulation Functions The slide example displays employee first names and last names joined together, the length of the employee last name, and the numeric position of the letter a in the employee last name for all employees who have the string REP contained in the job ID starting at the fourth position of the job ID. Example Modify the SQL statement in the slide to display the data for those employees whose last names end with the letter n . SELECT employee_id, CONCAT(first_name, last_name) NAME, LENGTH (last_name), INSTR(last_name, 'a') &quot;Contains 'a'?&quot; FROM employees WHERE SUBSTR(last_name, -1, 1) = 'n';
Number Functions Number functions accept numeric input and return numeric values. This section describes some of the number functions. Note: This list contains only some of the available number functions. For more information, see “Number Functions” in Oracle SQL Reference.
ROUND Function The ROUND function rounds the column, expression, or value to n decimal places. If the second argument is 0 or is missing, the value is rounded to zero decimal places. If the second argument is 2, the value is rounded to two decimal places. Conversely, if the second argument is –2, the value is rounded to two decimal places to the left (rounded to the nearest unit of 10). The ROUND function can also be used with date functions. You will see examples later in this lesson. DUAL Table The DUAL table is owned by the user SYS and can be accessed by all users. It contains one column, DUMMY , and one row with the value X . The DUAL table is useful when you want to return a value once only (for example, the value of a constant, pseudocolumn, or expression that is not derived from a table with user data). The DUAL table is generally used for SELECT clause syntax completeness, because both SELECT and FROM clauses are mandatory, and several calculations do not need to select from actual tables.
TRUNC Function The TRUNC function truncates the column, expression, or value to n decimal places. The TRUNC function works with arguments similar to those of the ROUND function. If the second argument is 0 or is missing, the value is truncated to zero decimal places. If the second argument is 2, the value is truncated to two decimal places. Conversely, if the second argument is – 2, the value is truncated to two decimal places to the left. If the second argument is –1, the value is truncated to one decimal place to the left. Like the ROUND function, the TRUNC function can be used with date functions.
MOD Function The MOD function finds the remainder of the first argument divided by the second argument. The slide example calculates the remainder of the salary after dividing it by 5,000 for all employees whose job ID is SA_REP. Note: The MOD function is often used to determine if a value is odd or even.
Oracle Date Format The Oracle database stores dates in an internal numeric format, representing the century, year, month, day, hours, minutes, and seconds. The default display and input format for any date is DD-MON-RR. Valid Oracle dates are between January 1, 4712 B.C., and December 31, 9999 A.D. In the example in the slide, the HIRE_DATE column output is displayed in the default format DD-MON-RR. However, dates are not stored in the database in this format. All the components of the date and time are stored. So, although a HIRE_DATE such as 17-JUN-87 is displayed as day, month, and year, there is also time and century information associated with the date. The complete data might be June 17, 1987, 5:10:43 p.m.
Oracle Date Format (continued) This data is stored internally as follows: CENTURY YEAR MONTH DAY HOUR MINUTE SECOND 19 87 06 17 17 10 43 Centuries and the Year 2000 When a record with a date column is inserted into a table, the century information is picked up from the SYSDATE function. However, when the date column is displayed on the screen, the century component is not displayed (by default). The DATE data type always stores year information as a four-digit number internally: two digits for the century and two digits for the year. For example, the Oracle database stores the year as 1987 or 2004, and not just as 87 or 04.
SYSDATE Function SYSDATE is a date function that returns the current database server date and time. You can use SYSDATE just as you would use any other column name. For example, you can display the current date by selecting SYSDATE from a table. It is customary to select SYSDATE from a dummy table called DUAL . Example Display the current date using the DUAL table. SELECT SYSDATE FROM DUAL;
Arithmetic with Dates Because the database stores dates as numbers, you can perform calculations using arithmetic operators such as addition and subtraction. You can add and subtract number constants as well as dates. You can perform the following operations:
Arithmetic with Dates (continued) The example in the slide displays the last name and the number of weeks employed for all employees in department 90. It subtracts the date on which the employee was hired from the current date ( SYSDATE ) and divides the result by 7 to calculate the number of weeks that a worker has been employed. Note: SYSDATE is a SQL function that returns the current date and time. Your results may differ from the example. If a more current date is subtracted from an older date, the difference is a negative number.
Date Functions Date functions operate on Oracle dates. All date functions return a value of DATE data type except MONTHS_BETWEEN , which returns a numeric value. MONTHS_BETWEEN( date1, date2 ) Finds the number of months between date1 and date2 . The result can be positive or negative. If date1 is later than date2 , the result is positive; if date1 is earlier than date2 , the result is negative. The noninteger part of the result represents a portion of the month. ADD_MONTHS( date, n ) Adds n number of calendar months to date . The value of n must be an integer and can be negative. NEXT_DAY( date, ' char ') Finds the date of the next specified day of the week (' char ') following date . The value of char may be a number representing a day or a character string. LAST_DAY( date ) Finds the date of the last day of the month that contains date ROUND( date [,' fmt ']) Returns date rounded to the unit that is specified by the format model fmt . If the format model fmt is omitted, date is rounded to the nearest day. TRUNC( date [, ' fmt ']) Returns date with the time portion of the day truncated to the unit that is specified by the format model fmt . If the format model fmt is omitted, date is truncated to the nearest day. This list is a subset of the available date functions. The format models are covered later in this lesson. Examples of format models are month and year.
Date Functions (continued) For example, display the employee number, hire date, number of months employed, six-month review date, first Friday after hire date, and last day of the hire month for all employees who have been employed for fewer than 70 months. SELECT employee_id, hire_date, MONTHS_BETWEEN (SYSDATE, hire_date) TENURE, ADD_MONTHS (hire_date, 6) REVIEW, NEXT_DAY (hire_date, 'FRIDAY'), LAST_DAY(hire_date) FROM employees WHERE MONTHS_BETWEEN (SYSDATE, hire_date) < 70;
Date Functions (continued) The ROUND and TRUNC functions can be used for number and date values. When used with dates, these functions round or truncate to the specified format model. Therefore, you can round dates to the nearest year or month. Example Compare the hire dates for all employees who started in 1997. Display the employee number, hire date, and start month using the ROUND and TRUNC functions. SELECT employee_id, hire_date, ROUND(hire_date, 'MONTH'), TRUNC(hire_date, 'MONTH') FROM employees WHERE hire_date LIKE '%97';
Practice 3: Overview of Part 1 Part 1 of this lesson’s practice provides a variety of exercises using different functions that are available for character, number, and date data types. For Part 1, complete questions 1 – 6 at the end of this lesson.
Conversion Functions In addition to Oracle data types, columns of tables in an Oracle database can be defined using ANSI, DB2, and SQL/DS data types. However, the Oracle server internally converts such data types to Oracle data types. In some cases, the Oracle server uses data of one data type where it expects data of a different data type. When this happens, the Oracle server can automatically convert the data to the expected data type. This data type conversion can be done implicitly by the Oracle server or explicitly by the user. Implicit data type conversions work according to the rules that are explained in the next two slides. Explicit data type conversions are done by using the conversion functions. Conversion functions convert a value from one data type to another. Generally, the form of the function names follows the convention data type TO data type . The first data type is the input data type; the second data type is the output. Note: Although implicit data type conversion is available, it is recommended that you do explicit data type conversion to ensure the reliability of your SQL statements.
Implicit Data Type Conversion The assignment succeeds if the Oracle server can convert the data type of the value used in the assignment to that of the assignment target. For example, the expression hire_date > '01-JAN-90' results in the implicit conversion from the string '01-JAN-90' to a date.
Implicit Data Type Conversion (continued) In general, the Oracle server uses the rule for expressions when a data type conversion is needed in places that are not covered by a rule for assignment conversions. For example, the expression salary = '20000' results in the implicit conversion of the string '20000' to the number 20000. Note: CHAR to NUMBER conversions succeed only if the character string represents a valid number.
Explicit Data Type Conversion SQL provides three functions to convert a value from one data type to another:
Explicit Data Type Conversion (continued)
Explicit Data Type Conversion (continued) Note: The list of functions mentioned in this lesson includes only some of the available conversion functions. For more information, see “Conversion Functions” in Oracle SQL Reference .
Displaying a Date in a Specific Format Previously, all Oracle date values were displayed in the DD-MON-YY format. You can use the TO_CHAR function to convert a date from this default format to one that you specify. Guidelines The format model must be enclosed by single quotation marks and is case-sensitive. The format model can include any valid date format element. Be sure to separate the date value from the format model by a comma. The names of days and months in the output are automatically padded with blanks. To remove padded blanks or to suppress leading zeros, use the fill mode fm element. You can format the resulting character field with the i SQL*Plus COLUMN command (covered in a later lesson). SELECT employee_id, TO_CHAR(hire_date, 'MM/YY') Month_Hired FROM employees WHERE last_name = 'Higgins';
Sample Format Elements of Valid Date Formats
Date Format Elements: Time Formats Use the formats that are listed in the following tables to display time information and literals and to change numerals to spelled numbers.
Other Formats Specifying Suffixes to Influence Number Display
Using the TO_CHAR Function with Dates The SQL statement in the slide displays the last names and hire dates for all the employees. The hire date appears as 17 June 1987. Example Modify the slide example to display the dates in a format that appears as “Seventeenth of June 1987 12:00:00 AM.” SELECT last_name, TO_CHAR(hire_date, 'fmDdspth &quot;of&quot; Month YYYY fmHH:MI:SS AM') HIREDATE FROM employees; Notice that the month follows the format model specified; in other words, the first letter is capitalized and the rest are lowercase. …
Using the TO_CHAR Function with Numbers When working with number values such as character strings, you should convert those numbers to the character data type using the TO_CHAR function, which translates a value of NUMBER data type to VARCHAR2 data type. This technique is especially useful with concatenation.
Using the TO_CHAR Function with Numbers (continued) Number Format Elements If you are converting a number to the character data type, you can use the following format elements:
Guidelines The Oracle server displays a string of number signs (#) in place of a whole number whose digits exceed the number of digits that is provided in the format model. The Oracle server rounds the stored decimal value to the number of decimal places that is provided in the format model.
Using the TO_NUMBER and TO_DATE Functions You may want to convert a character string to either a number or a date. To accomplish this task, use the TO_NUMBER or TO_DATE functions. The format model that you choose is based on the previously demonstrated format elements. The fx modifier specifies exact matching for the character argument and date format model of a TO_DATE function: Punctuation and quoted text in the character argument must exactly match (except for case) the corresponding parts of the format model. The character argument cannot have extra blanks. Without fx , Oracle ignores extra blanks. Numeric data in the character argument must have the same number of digits as the corresponding element in the format model. Without fx , numbers in the character argument can omit leading zeros.
Using the TO_NUMBER and TO_DATE Functions (continued) Example Display the name and hire date for all employees who started on May 24, 1999. Because the fx modifier is used, an exact match is required and the spaces after the word May are not recognized: SELECT last_name, hire_date FROM employees WHERE hire_date = TO_DATE('May 24, 1999', 'fxMonth DD, YYYY'); * WHERE hire_date = TO_DATE('May 24, 1999', 'fxMonth DD, YYYY') * ERROR at line 3: ORA-01858: a non-numeric character was found where a numeric was expected
RR Date Format Element The RR date format is similar to the YY element, but you can use it to specify different centuries. Use the RR date format element instead of YY so that the century of the return value varies according to the specified two-digit year and the last two digits of the current year. The table in the slide summarizes the behavior of the RR element.
Example of RR Date Format To find employees who were hired prior to 1990, the RR format can be used. Because the current year is greater than 1999, the RR format interprets the year portion of the date from 1950 to 1999. The following command, on the other hand, results in no rows being selected because the YY format interprets the year portion of the date in the current century (2090). SELECT last_name, TO_CHAR(hire_date, 'DD-Mon-yyyy') FROM employees WHERE TO_DATE(hire_date, 'DD-Mon-yy') < '01-Jan-1990'; no rows selected
Nesting Functions Single-row functions can be nested to any depth. Nested functions are evaluated from the innermost level to the outermost level. Some examples follow to show you the flexibility of these functions.
Nesting Functions (continued) The slide example displays the last names of employees in department 60. The evaluation of the SQL statement involves three steps: 1. The inner function retrieves the first eight characters of the last name. Result1 = SUBSTR (LAST_NAME, 1, 8) 2. The outer function concatenates the result with _US . Result2 = CONCAT(Result1, '_US' ) 3. The outermost function converts the results to uppercase. The entire expression becomes the column heading because no column alias was given. Example Display the date of the next Friday that is six months from the hire date. The resulting date should appear as Friday, August 13th, 1999. Order the results by hire date. SELECT TO_CHAR(NEXT_DAY(ADD_MONTHS (hire_date, 6), 'FRIDAY'), 'fmDay, Month DDth, YYYY') &quot;Next 6 Month Review&quot; FROM employees ORDER BY hire_date;
General Functions These functions work with any data type and pertain to the use of null values in the expression list. Note: For more information about the hundreds of functions available, see “Functions” in Oracle SQL Reference.
NVL Function To convert a null value to an actual value, use the NVL function. Syntax NVL ( expr1 , expr2 ) In the syntax: expr1 is the source value or expression that may contain a null expr2 is the target value for converting the null You can use the NVL function to convert any data type, but the return value is always the same as the data type of expr1 . NVL Conversions for Various Data Types
Using the NVL Function To calculate the annual compensation of all employees, you need to multiply the monthly salary by 12 and then add the commission percentage to the result: SELECT last_name, salary, commission_pct, (salary*12) + (salary*12*commission_pct) AN_SAL FROM employees; Notice that the annual compensation is calculated for only those employees who earn a commission. If any column value in an expression is null, the result is null. To calculate values for all employees, you must convert the null value to a number before applying the arithmetic operator. In the example in the slide, the NVL function is used to convert null values to zero. … …
Using the NVL2 Function The NVL2 function examines the first expression. If the first expression is not null, then the NVL2 function returns the second expression. If the first expression is null, then the third expression is returned. Syntax NVL2( expr1 , expr2, expr3 ) In the syntax: expr1 is the source value or expression that may contain null expr2 is the value that is returned if expr1 is not null expr3 is the value that is returned if expr2 is null In the example shown in the slide, the COMMISSION_PCT column is examined. If a value is detected, the second expression of SAL+COMM is returned. If the COMMISSION_PCT column holds a null value, the third expression of SAL is returned. The argument expr1 can have any data type. The arguments expr2 and expr3 can have any data types except LONG . If the data types of expr2 and expr3 are different, the Oracle server converts expr3 to the data type of expr2 before comparing them unless expr3 is a null constant. In the latter case, a data type conversion is not necessary. The data type of the return value is always the same as the data type of expr2 , unless expr2 is character data, in which case the return value’s data type is VARCHAR2 .
Using the NULLIF Function The NULLIF function compares two expressions. If they are equal, the function returns null. If they are not equal, the function returns the first expression. You cannot specify the literal NULL for the first expression. Syntax NULLIF ( expr1 , expr2 ) In the syntax: expr1 is the source value compared to expr2 expr2 is the source value compared with expr1 (If it is not equal to expr1 , expr1 is returned.) In the example shown in the slide, the length of the first name in the EMPLOYEES table is compared to the length of the last name in the EMPLOYEES table. When the lengths of the names are equal, a null value is displayed. When the lengths of the names are not equal, the length of the first name is displayed. Note: The NULLIF function is logically equivalent to the following CASE expression. The CASE expression is discussed on a subsequent page: CASE WHEN expr1 = expr 2 THEN NULL ELSE expr1 END
Using the COALESCE Function The COALESCE function returns the first non-null expression in the list. Syntax COALESCE ( expr1 , expr2, ... exprn ) In the syntax: expr1 returns this expression if it is not null expr2 returns this expression if the first expression is null and this expression is not null exprn returns this expression if the preceding expressions are null All expressions must be of the same data type.
Using the COALESCE Function (continued) In the example shown in the slide, if the MANAGER_ID value is not null, it is displayed. If the MANAGER_ID value is null, then the COMMISSION_PCT is displayed. If the MANAGER_ID and COMMISSION_PCT values are null, then the value – 1 is displayed.
Conditional Expressions Two methods used to implement conditional processing (IF-THEN-ELSE logic) in a SQL statement are the CASE expression and the DECODE function. Note: The CASE expression complies with ANSI SQL. The DECODE function is specific to Oracle syntax.
CASE Expression CASE expressions let you use IF-THEN-ELSE logic in SQL statements without having to invoke procedures. In a simple CASE expression, the Oracle server searches for the first WHEN ... THEN pair for which expr is equal to comparison_expr and returns return_expr . If none of the WHEN ... THEN pairs meet this condition, and if an ELSE clause exists, then the Oracle server returns else_expr . Otherwise, the Oracle server returns null. You cannot specify the literal NULL for all the return_expr s and the else_expr . All of the expressions ( expr , comparison_expr , and return_expr ) must be of the same data type, which can be CHAR , VARCHAR2 , NCHAR , or NVARCHAR2 .
Using the CASE Expression In the SQL statement in the slide, the value of JOB_ID is decoded. If JOB_ID is IT_PROG , the salary increase is 10%; if JOB_ID is ST_CLERK , the salary increase is 15%; if JOB_ID is SA_REP , the salary increase is 20%. For all other job roles, there is no increase in salary. The same statement can be written with the DECODE function. This is an example of a searched CASE expression. In a searched CASE expression, the search occurs from left to right until an occurrence of the listed condition is found, and then it returns the return expression. If no condition is found to be true, and if an ELSE clause exists, the return expression in the ELSE clause is returned; otherwise, NULL is returned. SELECT last_name,salary, (CASE WHEN salary<5000 THEN 'Low' WHEN salary<10000 THEN 'Medium' WHEN salary<20000 THEN 'Good' ELSE 'Excellent' END) qualified_salary FROM employees;
DECODE Function The DECODE function decodes an expression in a way similar to the IF-THEN-ELSE logic that is used in various languages. The DECODE function decodes expression after comparing it to each search value. If the expression is the same as search , result is returned. If the default value is omitted, a null value is returned where a search value does not match any of the result values.
Using the DECODE Function In the SQL statement in the slide, the value of JOB_ID is tested. If JOB_ID is IT_PROG , the salary increase is 10%; if JOB_ID is ST_CLERK , the salary increase is 15%; if JOB_ID is SA_REP , the salary increase is 20%. For all other job roles, there is no increase in salary. The same statement can be expressed in pseudocode as an IF-THEN-ELSE statement: IF job_id = 'IT_PROG' THEN salary = salary*1.10 IF job_id = 'ST_CLERK' THEN salary = salary*1.15 IF job_id = 'SA_REP' THEN salary = salary*1.20 ELSE salary = salary
Using the DECODE function (continued) This slide shows another example using the DECODE function. In this example, we determine the tax rate for each employee in department 80 based on the monthly salary. The tax rates are as follows: Monthly Salary Range Tax Rate $0.00 – 1,999.99 00% $2,000.00 – 3,999.99 09% $4,000.00 – 5,999.99 20% $6,000.00 – 7,999.99 30% $8,000.00 – 9,999.99 40% $10,000.00 – 11,999.99 42% $12,200.00 – 13,999.99 44% $14,000.00 or greater 45%
Summary Single-row functions can be nested to any level. Single-row functions can manipulate the following: Character data: LOWER , UPPER , INITCAP , CONCAT , SUBSTR , INSTR , LENGTH Number data: ROUND , TRUNC , MOD Date data: MONTHS_BETWEEN , ADD_MONTHS , NEXT_DAY , LAST_DAY , ROUND , TRUNC Remember the following: Date values can also use arithmetic operators. Conversion functions can convert character, date, and numeric values: TO_CHAR , TO_DATE , TO_NUMBER There are several functions that pertain to nulls, including NVL , NVL2 , NULLIF , and COALESCE . IF-THEN-ELSE logic can be applied within a SQL statement by using the CASE expression or the DECODE function. SYSDATE and DUAL SYSDATE is a date function that returns the current date and time. It is customary to select SYSDATE from a dummy table called DUAL .
Practice 3: Overview of Part 2 Part 2 of this lesson’s practice provides a variety of exercises using different functions that are available for character, number, and date data types. For Part 2, complete exercises 7 –14. Remember that for nested functions, the results are evaluated from the innermost function to the outermost function.
… Practice 3 Part 1 1. Write a query to display the current date. Label the column Date . 2. The HR department needs a report to display the employee number, last name, salary, and salary increased by 15.5% (expressed as a whole number) for each employee. Label the column New Salary . Place your SQL statement in a text file named lab_03_02.sql . 3. Run your query in the file lab_03_02.sql. 4. Modify your query lab_03_02.sql to add a column that subtracts the old salary from the new salary. Label the column Increase . Save the contents of the file as lab_03_04.sql . Run the revised query. …
Practice 3 (continued) 5. Write a query that displays the last name (with the first letter uppercase and all other letters lowercase) and the length of the last name for all employees whose name starts with the letters J, A, or M. Give each column an appropriate label. Sort the results by the employees’ last names. Rewrite the query so that the user is prompted to enter a letter that starts the last name. For example, if the user enters H when prompted for a letter, then the output should show all employees whose last name starts with the letter H.
Practice 3 (continued) 6. The HR department wants to find the length of employment for each employee. For each employee, display the last name and calculate the number of months between today and the date on which the employee was hired. Label the column MONTHS_WORKED . Order your results by the number of months employed. Round the number of months up to the closest whole number. Note: Your results will differ.
Practice 3 (continued) Part 2 7. Create a report that produces the following for each employee: < employee last name> earns <salary> monthly but wants <3 times salary >. Label the column Dream Salaries . If you have time, complete the following exercises: 8. Create a query to display the last name and salary for all employees. Format the salary to be 15 characters long, left-padded with the $ symbol. Label the column SALARY . … …
Practice 3 (continued) 9. Display each employee’s last name, hire date, and salary review date, which is the first Monday after six months of service. Label the column REVIEW . Format the dates to appear in the format similar to “Monday, the Thirty-First of July, 2000.” Display the last name, hire date, and day of the week on which the employee started. Label the column DAY . Order the results by the day of the week, starting with Monday. … …
Practice 3 (continued) If you want an extra challenge, complete the following exercises: 11. Create a query that displays the employees’ last names and commission amounts. If an employee does not earn commission, show “No Commission.” Label the column COMM . 12. Create a query that displays the first eight characters of the employees’ last names and indicates the amounts of their salaries with asterisks. Each asterisk signifies a thousand dollars. Sort the data in descending order of salary. Label the column EMPLOYEES_AND_THEIR_SALARIES . … …
Practice 3 (continued) 13. Using the DECODE function, write a query that displays the grade of all employees based on the value of the column JOB_ID , using the following data: Job Grade AD_PRES A ST_MAN B IT_PROG C SA_REP D ST_CLERK E None of the above 0 14. Rewrite the statement in the preceding exercise using the CASE syntax.
Display the employee number, name, and department number for employee Higgins:
SELECT employee_id, last_name, department_id FROM employees WHERE LOWER(last_name) = 'higgins'; SELECT employee_id, last_name, department_id FROM employees WHERE last_name = 'higgins'; no rows selected
BLACK and BLUE REPLACE ('JACK and JUE','J','BL') 10 LENGTH('HelloWorld') 6 INSTR('HelloWorld', 'W') *****24000 LPAD(salary,10,'*') 24000***** RPAD(salary, 10, '*') HelloWorld CONCAT('Hello', 'World') elloWorld TRIM('H' FROM 'HelloWorld') Hello SUBSTR('HelloWorld',1,5) Result Function
Using the Character-Manipulation Functions SELECT employee_id, CONCAT(first_name, last_name) NAME, job_id, LENGTH (last_name), INSTR(last_name, 'a') "Contains 'a'?" FROM employees WHERE SUBSTR(job_id, 4) = 'REP'; 2 3 1 2 1 3
Add or subtract a number to or from a date for a resultant date value.
Subtract two dates to find the number of days between those dates.
Add hours to a date by dividing the number of hours by 24.
Using Arithmetic Operators with Dates SELECT last_name, (SYSDATE-hire_date)/7 AS WEEKS FROM employees WHERE department_id = 90;
Date Functions Next day of the date specified NEXT_DAY Last day of the month LAST_DAY Round date ROUND Truncate date TRUNC Number of months between two dates MONTHS_BETWEEN Add calendar months to date ADD_MONTHS Result Function
Using Date Functions '08-SEP-95' NEXT_DAY ('01-SEP-95','FRIDAY') '28-FEB-95' LAST_DAY ('01-FEB-95') 19.6774194 MONTHS_BETWEEN ('01-SEP-95','11-JAN-94') '11-JUL-94' ADD_MONTHS ('11-JAN-94',6) Result Function
Has an fm element to remove padded blanks or suppress leading zeros
Is separated from the date value by a comma
TO_CHAR( date, ' format_model ')
Elements of the Date Format Model Three-letter abbreviation of the day of the week DY Full name of the day of the week DAY Two-digit value for month MM Full name of the month MONTH Three-letter abbreviation of the month MON Numeric day of the month DD Full year in numbers YYYY Year spelled out (in English) YEAR Result Element
These are some of the format elements that you can use with the TO_CHAR function to display a number value as a character:
TO_CHAR( number, ' format_model ') Prints a decimal point . Prints a comma as thousands indicator , Places a floating dollar sign $ Uses the floating local currency symbol L Represents a number 9 Forces a zero to be displayed 0 Result Element
RR Date Format Current Year 1995 1995 2001 2001 Specified Date 27-OCT-95 27-OCT-17 27-OCT-17 27-OCT-95 RR Format 1995 2017 2017 1995 YY Format 1995 1917 2017 2095 If two digits of the current year are: 0–49 0–49 50–99 50–99 The return date is in the current century The return date is in the century after the current one The return date is in the century before the current one The return date is in the current century If the specified two-digit year is:
Data types that can be used are date, character, and number.
Data types must match:
NVL(job_id,'No Job Yet')
Using the NVL Function SELECT last_name, salary, NVL(commission_pct, 0), (salary*12) + (salary*12*NVL(commission_pct, 0)) AN_SAL FROM employees; … 1 1 2 2
Using the NVL2 Function SELECT last_name, salary, commission_pct, NVL2(commission_pct, 'SAL+COMM', 'SAL') income FROM employees WHERE department_id IN (50, 80); 1 2 2 1
Using the NULLIF Function SELECT first_name, LENGTH(first_name) "expr1", last_name, LENGTH(last_name) "expr2", NULLIF(LENGTH(first_name), LENGTH(last_name)) result FROM employees; … 1 2 3 1 2 3
Facilitates conditional inquiries by doing the work of an IF-THEN-ELSE statement:
SELECT last_name, job_id, salary, CASE job_id WHEN 'IT_PROG' THEN 1.10*salary WHEN 'ST_CLERK' THEN 1.15*salary WHEN 'SA_REP' THEN 1.20*salary ELSE salary END "REVISED_SALARY" FROM employees; … …