Logic puzzles require you to think. You will have to be logical in your reasoning.
A long time ago, candy was being sold at three prices: red candy at one for a penny, green candy at two for a penny, and blue candy at three for a penny. Some children (as many boys as girls) were given a total of seven pennies to spend on the candy. Each child received exactly the same value in candy. How many pieces of candy and what color candy did each child receive?
There must have been three boys and three girls, each of whom received two pieces of blue candy priced at three for a penny, and one piece of green candy priced at two for a penny. The total cost of the candy would be exactly 7 cents.
Oct 02, 2001
|Why could there not have been 1 boy, and|
one girl, each getting 7 pieces of
Nov 07, 2001
|or 7 boys and 7 girls each getting 1 piece of green|
Aug 29, 2002
|Or 1 boy and 1 girl each getting 3.5 cents|
worth of candy (several combinations, ranging from
3 reds and a green each to 7 greens each).
Sep 14, 2002
|@ran@ What is going on?|
Sep 14, 2002
|Why did it put @ran@ before my comment???|
Apr 18, 2006
|There are a multitude of possibilities to this teaser....|
Aug 23, 2006
|If I was them, I'd buy 7 red.|
Mar 13, 2007
|What exactly is the question for answering this teaser? |
If the question is how many combinations of candy can be purchased then then there are 8... that means 4 boys and 4 girls.
1 green 5 red
2 green 3 red
3 green 1 red
1 blue 4 red
2 blue 3 red
1 blue 1 green 2 red
1 blue 2 green
This teaser needs some attending to.
Jan 10, 2009
|How come there aren't 50 boys and 50 girls? How come there were 3 of each. This teaser needs some work, if it could somehow seggust that there were 6 children that would be good.|
Aug 17, 2012
|Why should it matter what the genders of the kids are?|
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