Suppose that Y is normally distributed with mean 0 and unknown variance (sigma)^2. Then (y^2)/((sigma)^2) has a X^2 distribution with 1 degree of freedom. Use the pivotal quantity (y^2)/((sigma)^2) to find a
A)95% confidence interval for sigma2.
B)95% upper confidence limit for sigma^2
C)95% lower confiidence limit for sigma^2