Haven't ever been one for probability.
There are 150 options for students to choose from. Student 1 picks an option and then it is removed from the pool, Student 2 then picks and follows suit. Each option is given equal weight. What is the probability of any student obtaining their choice?
I got stuck generalizing this:
P of first student getting his or her choice: P(1) = 1
P of second student getting his or her choice: P(2) = 1 - probability of first student taking their choice = 1 - 1/150 = 149/150
at this point i wonder if i'm already heading down the wrong path... shouldn't it be more like P(2) = 148/149?
P(3) = 1 - probability of first and second student taking their choice = 1 - (1/150) - (1/149)
I'm afraid to go any further without first understanding what I'm doing... Initially I thought it would turn out to be something like the probability of drawing two aces from a deck 4|52 * 3|51 , but I'm slamming my head against the wall now. Any help would be appreciated.