I could use some help on this one. Calculate the slope of a line tangent to the curve of each of the functions for the given point .
First find the derivative ...then you want to find the slope of the tangent line at the point and the derivative evaluated at a point x has the same slope as the tangent line at that point so the slope of the tangent is
Uh I'm new to calculus so if you could kind of walk me through it a little bit more that be great.
If you haven't learned differntiation rules then we will go with the quotient difference...ok the slope of a curve is given by ..so to get the devative of before you know differentiation rules is to go through this thus the derivative of is ...so the slope at the point x is ...so the slope of the curve of at x=2 is ...so the slope of the tangent line at the point x=2 has the same slope as the curve so its slope is 4
wow lol. and im only in chapter 2. i got 7 more chapters to go tonight and tomorrow.
all that work just to get ...but I'll tell you a little trick if ...then the derivative of f(x) or f'(x) is ...so to get the derivative of x²...just multiply the coefficient by the exponent and reduce the exponent by one..so it would be