[R] Kendall v MannKendall Functions
ehlers at ucalgary.ca
Tue Mar 22 09:31:52 CET 2011
On 2011-03-21 14:16, armstrwa wrote:
> I am running a correlation analysis on a temporal dataset. I was wondering
> if you would receive the same tau and p values running the function:
> MannKendall(x), where x is the dependant variable that changes with time
> as you would running:
> Kendall(d,x), where x is the exact same dataset as the x entered into
> MannKendall and d is the date on which the observation was made (assuming
> that the order is the same as the data I entered into the Kendall function).
> Can anyone elucidate this for me?
Assuming that you're referring to the (unstated) package Kendall,
a quick look at the code for MannKendall tells you that
MannKendall(x) just does Kendall(1:length(x), x).
Does that answer your question?
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