If n represents the smaller of these two integers, which is an equation that can be used to find n? The sum of two consecutive even integers is 294.
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The sum of two consecutive even numbers is 294. If the smaller number is n, the larger number is n + 2. To determine n, solve the equation n + n + 2 = 294 for n.
Or 2n + 2 = 294
n = 146
The equation to be solved to determine n is 2n + 2 = 294
Given :- sum of the two even intefers = 294 and
The smaller of the two integer is n
The larger integer = n + 2 [ enen numbers differ by 2 ]
since sum of these two even integer = 294
That is, n + n + 2 = 294
=> 2n + 2 = 294
=> 2(n + 1) = 294
=> ( n + 1)= 294/2 = 147
=> n + 1= 147
=> n = 146 <-- Answer
Since the smaller number is "n" and the larger number is a consecutive even version, then the larger number would be "n+2"
So the equation would be
and then you simplify to get the answer...like this:
As n is the smaller of the two consective even integers, therefore the second integer is n+2.
Sum of the two numbers is n + n+2 which is also equal to 294
So the equation to be used to fine the numbers is: n+n+2 = 294
which reduces to 2n+2 =294
The required equation is 2n+2 = 294 to find n.
The above equation yields n= 146 and the two integers are 146, 148
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