The tens digit of a number is 3 less than the units digit. If the number is divided
by the sum of the digits. The quotient is 4 and the remainder is 3. What is
he original number?
let : x be unit digit
x - 3 be the tens digit
10(x-3) + x be the number
solve: [10(x-3) + x] / (x-3)+x = 4 + 3
please do check my representations and equation... and please correct my work..
thanks a lot
can anybody help me in representing the unknown please.