log [ 4x/(2(x-1))] = 0
10^log [ 4x/(2(x-1))] = 10^0 = 1
4x/[2(x-1))] = 1
4x = 2 x - 2
2 x = - 2
x = -1
x^2 - 4 x - 4 = 8
x^2 - 4 x - 12 = 0
then other possible solution
x^2 - 4 x -4 = -8
x^2 - 4 x + 4 = 0
(x-2)(x-2) = 0
x = 2
1. I disagree with Damon's solution.
log(4x) = log2 + log(x-1) , so x>1
log(4x) - log(x-1) = log2
log( 4x/(x-1) ) = log2
4x/(x-1) = 2
4x = 2x-2
2x = -2
x = -1 , but x > 1 or else log (4x) and log(x-1) are both undefined
thanks so much both of you!! Yah I wasn't sure about the first one but now I know how to do both!!
Answer this Question
math - Logarithm!!! Select all of the following that are true statements: (a) ...
Math Help Please - Which of the following expressions is equal to log (x sqrt-y...
Mathematics - Prove that log a, log ar, log ar^2 is an a.p. Is the following ...
Advanced Functions/ Precalculus Log - 1. Evaluate 4^(log base4 64) + 10^(log100...
Algebra 2 - how do not understand how to do this Log X + Lob (X-3) = 1 I know I ...
math(Please help) - 1) use the properties of logarithms to simplify the ...
math - write as a single logarithm: -2logbase3(1/x)+(1/3)logbase3(square root of...
TRig WIth LoGs help1!! - i have problem i can't solve and the book is no help.. ...
Math - h(x) = log (6x+5/7x-4) Find a formula for the inverse function h^-1(x) h...
Precalculus - What am I doing wrong? I keep getting 48 and its wrong... Solve ...