How do I solve the following equation?
I tried the following, but apparently this is not correct, i.e. score = 0%.
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You changed 3 to root3 Why?
Let y=2^x Then 2^2x= (2^x)^2=y^2
So equation becomes y^2-3y-40=0
(y-8)(y+5)=0 y=8 0r-5
So 2^x=8 giving x=3 ( and 2^x=-5 has no solution)
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