Mathias/Everyone on the list
I am running the following query against the database:
SELECT demographic.demographic_no, demographic.first_name,
demographic.last_name, demographic.chart_no, demographic.sex,
demographic.roster_status, demographic.patient_status, demographic.phone
FROM allergies, demographic, drugs, echart, dxresearch, ichppccode WHERE
demographic.demographic_no = '1' AND demographic.last_name LIKE 'TES'
AND allergies.demographic_no = demographic.demographic_no AND
demographic.demographic_no = drugs.demographic_no AND
drugs.demographic_no = dxresearch.demographic_no AND
dxresearch.demographic_no = echart.demographicNo AND
allergies.demographic_no = echart.demographicNo AND
dxresearch.dxresearch_code = ichppccode.ichppccode
Is the string at the end from, 'AND allergies.demographic_no =
demographic.demographic_no...', the correct way to create the JOIN I
require by demographic_no on five of the tables and then a JOIN of the
dxresearch and ichppccode tables by dxresearch_code and ichppccode
respectively? Any help or pointers would be much appreciated. Thank you!
mathias fatene wrote:
>Select * from table1 T1, table2 T2, table3 T3, table4 T4, table5 T5,
> and T2.col=T3.col
> and T3.col=T4.col
> and T4.col=T5.col
> and T5.col=T6.col
> and T1.col=T6.col
>Doesn't this work ? Have you an example ?
>Hope that helps
>*This not an official mysql support answer
>From: Schalk Neethling [mailto:schalk@stripped]
>Sent: lundi 25 avril 2005 00:52
>Subject: joining six tables by mutual column
>Hope someone can give me some pointers here. I have six tables in the
>database and I need to JOIN them on a row that appears in all of the
>tables. How do I do this? I have so far done the normal 'cross-join'
>saying SELECT * FROM table1, table2, table3, table4, table5, table6
>WHERE something = something;
>I have also added STRAIGHT_JOIN to force the order but, how do I JOIN
>six tables to/by one column? I have done some google searches as well as
>looked at MySQL 2nd edition by Paul DuBois, sorry if I missed something
>here Paul, and so far I have not found an answer. Any help or pointers
>will be appreciated. Thank you.
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