A. Consecutive Sum Riddle
math
Theofanis has a riddle for you and if you manage to solve it, he will give you a Cypriot snack halloumi for free (Cypriot cheese).You are given an integer \(n\). You need to find two integers \(l\) and \(r\) such that \(-10^{18} \le l < r \le 10^{18}\) and \(l + (l + 1) + \ldots + (r - 1) + r = n\).
The first line contains a single integer \(t\) (\(1 \le t \le 10^4\)) — the number of test cases.The first and only line of each test case contains a single integer \(n\) (\(1 \le n \le 10^{18}\)).
For each test case, print the two integers \(l\) and \(r\) such that \(-10^{18} \le l < r \le 10^{18}\) and \(l + (l + 1) + \ldots + (r - 1) + r = n\). It can be proven that an answer always exists. If there are multiple answers, print any.
In the first test case, \(0 + 1 = 1\).In the second test case, \((-1) + 0 + 1 + 2 = 2\).In the fourth test case, \(1 + 2 + 3 = 6\).In the fifth test case, \(18 + 19 + 20 + 21 + 22 = 100\).In the sixth test case, \((-2) + (-1) + 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 = 25\).